Subject: Chemistry — Coordination Compounds
Question: The total number of possible isomers for
$\left\lbrack Pt\left( NH_{3} \right)_{4}Cl_{2} \right\rbrack Br_{2}$ is
\_\_\_\_\_\_\_\_\_.
Answer: (6)
Solution: Total number of isomer of complex
$\left\lbrack Pt\left( NH_{3} \right)_{4}Cl_{2} \right\rbrack Br_{2}$
\(1\) Cis -
$\left\lbrack Pt\left( NH_{3} \right)_{4}Cl_{2} \right\rbrack Br_{2}$
(2) Trans -
$\left\lbrack Pt\left( NH_{3} \right)_{4}Cl_{2} \right\rbrack Br_{2},$
[IMAGE] Cis form Trans form
\(3\) Cis -
$\left\lbrack Pt\left( NH_{3} \right)_{4}BrCl \right\rbrack ClBr$ (4)
Trans -
$\left\lbrack Pt\left( NH_{3} \right)_{4}BrCl \right\rbrack ClBr$
[IMAGE] Cis form Trans form
\(5\) Cis -
$\left\lbrack Pt\left( NH_{3} \right)_{4}Br_{2} \right\rbrack Cl_{2}$
(6) Trans -
$\left\lbrack Pt\left( NH_{3} \right)_{4}Br_{2} \right\rbrack Cl_{2}$
[IMAGE]