Question: What has less area, Lakewood or Evanston?
Choices:
New Haven
Columbus
Greenville
Evanston
Compton
Boulder
Lansing
Lakewood
Franklin
Waukegan
Answer: Lakewood
SPARQL: SELECT ?e WHERE { { ?e <pred:name> "Lakewood" .  } UNION { ?e <pred:name> "Evanston" .  } ?e <area> ?pv . ?pv <pred:value> ?v .  } ORDER BY ?v LIMIT 1
Program:
function: Find
inputs: Lakewood
function: Find
inputs: Evanston
function: SelectBetween
dependencies: 0
1
inputs: area
less