Question: Among the film that is a derivative work of Mission: Impossible which has run for 48 minute, Which is expensive?
Choices:
Pleasantville
Mission: Impossible II
Mission: Impossible III
The Towering Inferno
A Prairie Home Companion
Curse of the Golden Flower
Training Day
Rebecca
Talk to Her
The Fifth Element
Answer: Mission: Impossible III
SPARQL: SELECT ?e WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "film" . ?e_1 <derivative_work> ?e . ?e_1 <pred:name> "Mission: Impossible" . ?e_1 <duration> ?pv_1 . ?pv_1 <pred:unit> "minute" . ?pv_1 <pred:value> "48"^^xsd:double . ?e <cost> ?pv . ?pv <pred:value> ?v .  } ORDER BY DESC(?v) LIMIT 1
Program:
function: Find
inputs: Mission: Impossible
function: FilterNum
dependencies: 0
inputs: duration
48 minute
=
function: Relate
dependencies: 1
inputs: derivative work
forward
function: FilterConcept
dependencies: 2
inputs: film
function: SelectAmong
dependencies: 3
inputs: cost
largest