Question: Regarding the family with the official website http://www.sachsen-coburg-gotha.de/ or that is George III of Great Britain's family.
Choices:
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Answer: 2
SPARQL: SELECT (COUNT(DISTINCT ?e) AS ?count) WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "family" .  { ?e <official_website> ?pv . ?pv <pred:value> "http://www.sachsen-coburg-gotha.de/" .  } UNION { ?e_1 <family> ?e . ?e_1 <pred:name> "George III of Great Britain" .  } }
Program:
function: FindAll
function: FilterStr
dependencies: 0
inputs: official website
http://www.sachsen-coburg-gotha.de/
function: FilterConcept
dependencies: 1
inputs: family
function: Find
inputs: George III of Great Britain
function: Relate
dependencies: 3
inputs: family
forward
function: FilterConcept
dependencies: 4
inputs: family
function: Or
dependencies: 2
5
function: Count
dependencies: 6