Question: Which website represents the person who has 13150 followers for her Twitter username, OliviadAbo ?
Choices:
http://www.corkcoco.ie/
http://www.mammootty.com/
http://www.thehungergamesmovie.com/
http://www.cookingvinyl.com/
https://www.metallica.com/releases/albums/release-4213.html
http://www.bath.ac.uk/
http://www.themummy.com/
http://www.oliviadabo.net
http://www.theconstantgardener.com/
http://www.ontarioliberal.ca/fr/Default.aspx
Answer: http://www.oliviadabo.net
SPARQL: SELECT DISTINCT ?pv WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "human" . ?e <Twitter_username> ?pv_1 . ?pv_1 <pred:value> "OliviadAbo" . [ <pred:fact_h> ?e ; <pred:fact_r> <Twitter_username> ; <pred:fact_t> ?pv_1 ] <number_of_subscribers> ?qpv . ?qpv <pred:unit> "1" . ?qpv <pred:value> "13150"^^xsd:double . ?e <official_website> ?pv .  }
Program:
function: FindAll
function: FilterStr
dependencies: 0
inputs: Twitter username
OliviadAbo
function: QFilterNum
dependencies: 1
inputs: number of subscribers
13150
=
function: FilterConcept
dependencies: 2
inputs: human
function: QueryAttr
dependencies: 3
inputs: official website