Question: About the disease with the DiseasesDB identifier of 7728, and 31479 cases, tell me it's time point
Choices:
1944-09-13
2000-04-09
2016-01-15
1832-01-01
2012-02-12
1665-09-28
1999-12-01
2013
1992
2002-07-03
Answer: 2013
SPARQL: SELECT DISTINCT ?qpv WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "disease" . ?e <DiseasesDB> ?pv_1 . ?pv_1 <pred:value> "7728" . ?e <number_of_cases> ?pv . ?pv <pred:unit> "1" . ?pv <pred:value> "31479"^^xsd:double . [ <pred:fact_h> ?e ; <pred:fact_r> <number_of_cases> ; <pred:fact_t> ?pv ] <point_in_time> ?qpv .  }
Program:
function: FindAll
function: FilterStr
dependencies: 0
inputs: DiseasesDB
7728
function: FilterConcept
dependencies: 1
inputs: disease
function: QueryAttrQualifier
dependencies: 2
inputs: number of cases
31479
point in time