Question: What is the elevation above sea level of the U.S. city that is the capital of Weber County?
Choices:
614 foot
193 metre
257 metre
318 metre
332 metre
170 metre
866 foot
299 metre
1310 metre
76 metre
Answer: 1310 metre
SPARQL: SELECT DISTINCT ?pv WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "city of the United States" . ?e_1 <capital> ?e . ?e_1 <pred:name> "Weber County" .  ?e <elevation_above_sea_level> ?pv .  }
Program:
function: Find
inputs: Weber County
function: Relate
dependencies: 0
inputs: capital
forward
function: FilterConcept
dependencies: 1
inputs: city of the United States
function: QueryAttr
dependencies: 2
inputs: elevation above sea level