Question: What award's Alexa rank is higher than 35 as of the year 2018?
Choices:
The New York Times Company
NBCUniversal
Primetime Emmy Award for Outstanding Animated Program
Primetime Emmy Award for Outstanding Comedy Series
Harland and Wolff
Primetime Emmy Award for Outstanding Supporting Actress in a Miniseries or a Movie
Primetime Emmy Award for Outstanding Writing for a Drama Series
Primetime Emmy Award for Outstanding Writing for a Comedy Series
The New York Times
Primetime Emmy Award for Outstanding Lead Actress in a Comedy Series
Answer: Primetime Emmy Award for Outstanding Animated Program
SPARQL: SELECT DISTINCT ?e WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "award" . ?e <Alexa_rank> ?pv . ?pv <pred:unit> "1" . ?pv <pred:value> ?v . FILTER ( ?v > "35"^^xsd:double ) . [ <pred:fact_h> ?e ; <pred:fact_r> <Alexa_rank> ; <pred:fact_t> ?pv ] <point_in_time> ?qpv . ?qpv <pred:year> 2018 .  }
Program:
function: FindAll
function: FilterNum
dependencies: 0
inputs: Alexa rank
35
>
function: QFilterYear
dependencies: 1
inputs: point in time
2018
=
function: FilterConcept
dependencies: 2
inputs: award
function: What
dependencies: 3