Question: How many Academy Awards ceremony has http://www.oscar.com as their official website or 31 as edition number?
Choices:
3
4
5
6
7
8
9
10
11
12
Answer: 4
SPARQL: SELECT (COUNT(DISTINCT ?e) AS ?count) WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "Academy Awards ceremony" .  { ?e <official_website> ?pv . ?pv <pred:value> "http://www.oscar.com" .  } UNION { ?e <edition_number> ?pv . ?pv <pred:value> "31" .  } }
Program:
function: FindAll
function: FilterStr
dependencies: 0
inputs: official website
http://www.oscar.com
function: FilterConcept
dependencies: 1
inputs: Academy Awards ceremony
function: FindAll
function: FilterStr
dependencies: 3
inputs: edition number
31
function: FilterConcept
dependencies: 4
inputs: Academy Awards ceremony
function: Or
dependencies: 2
5
function: Count
dependencies: 6