Question: When did Puerto Rico (the one whose population is 2718000) have a total fertility rate of 1.6528?
Choices:
2014-04-10
1576-01-01
2009
2005-06-19
2015-05-06
2002-02-13
1995-02-20
1946
2017-11-24
2017-01-05
Answer: 2009
SPARQL: SELECT DISTINCT ?qpv WHERE { ?e <pred:name> "Puerto Rico" . ?e <population> ?pv_1 . ?pv_1 <pred:unit> "1" . ?pv_1 <pred:value> "2718000"^^xsd:double . ?e <total_fertility_rate> ?pv . ?pv <pred:unit> "1" . ?pv <pred:value> "1.6528"^^xsd:double . [ <pred:fact_h> ?e ; <pred:fact_r> <total_fertility_rate> ; <pred:fact_t> ?pv ] <point_in_time> ?qpv .  }
Program:
function: Find
inputs: Puerto Rico
function: FilterNum
dependencies: 0
inputs: population
2718000
=
function: QueryAttrQualifier
dependencies: 1
inputs: total fertility rate
1.6528
point in time