Question: Which area is smaller, Evansville or Steubenville?
Choices:
Compton
Boulder
Columbus
Steubenville
Evansville
Lansing
Franklin
Oakland
Greenville
New Haven
Answer: Steubenville
SPARQL: SELECT ?e WHERE { { ?e <pred:name> "Evansville" .  } UNION { ?e <pred:name> "Steubenville" .  } ?e <area> ?pv . ?pv <pred:value> ?v .  } ORDER BY ?v LIMIT 1
Program:
function: Find
inputs: Evansville
function: Find
inputs: Steubenville
function: SelectBetween
dependencies: 0
1
inputs: area
less