Question: What is the official website of the person who weighs 112 kilograms?
Choices:
http://www.dafc.co.uk/
http://www.gocolumbiamo.com
http://www.aquitaine.fr/
http://www.waynecounty.com
http://corporate.wwe.com/who-we-are/leadership#vincent-k-mcmahon
https://uwaterloo.ca/
http://www.mtv.com/ontv/vma
https://www.clubsportingcristal.pe/
http://www.robschneider.com/
http://www.law.gwu.edu/
Answer: http://corporate.wwe.com/who-we-are/leadership#vincent-k-mcmahon
SPARQL: SELECT DISTINCT ?pv WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "human" . ?e <mass> ?pv_1 . ?pv_1 <pred:unit> "kilogram" . ?pv_1 <pred:value> "112"^^xsd:double . ?e <official_website> ?pv .  }
Program:
function: FindAll
function: FilterNum
dependencies: 0
inputs: mass
112 kilogram
=
function: FilterConcept
dependencies: 1
inputs: human
function: QueryAttr
dependencies: 2
inputs: official website