Question: When did a country, that measured 3.3 percent inflation rate on 1st January 2012, reach the life expectancy of 79.69756 years?
Choices:
1977
2006
1837-01-01
2014-05-08
1935-12-31
1919
2009-10-16
2018-11-14
2005-04-20
1855-12-01
Answer: 2006
SPARQL: SELECT DISTINCT ?qpv WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "country" . ?e <inflation_rate> ?pv_1 . ?pv_1 <pred:unit> "percentage" . ?pv_1 <pred:value> "3.3"^^xsd:double . [ <pred:fact_h> ?e ; <pred:fact_r> <inflation_rate> ; <pred:fact_t> ?pv_1 ] <point_in_time> ?qpv_1 . ?qpv_1 <pred:date> "2012-01-01"^^xsd:date . ?e <life_expectancy> ?pv . ?pv <pred:unit> "year" . ?pv <pred:value> "79.69756"^^xsd:double . [ <pred:fact_h> ?e ; <pred:fact_r> <life_expectancy> ; <pred:fact_t> ?pv ] <point_in_time> ?qpv .  }
Program:
function: FindAll
function: FilterNum
dependencies: 0
inputs: inflation rate
3.3 percentage
=
function: QFilterDate
dependencies: 1
inputs: point in time
2012-01-01
=
function: FilterConcept
dependencies: 2
inputs: country
function: QueryAttrQualifier
dependencies: 3
inputs: life expectancy
79.69756 year
point in time