Question: When did Djibouti (the one whose life expectancy is 56.992 year) have a total fertility rate of 4.472?
Choices:
1828
2012-02-26
2013-04-13
1859-01-01
1931
1866
1991-12-25
2007-03-14
2000
2006-12-18
Answer: 2000
SPARQL: SELECT DISTINCT ?qpv WHERE { ?e <pred:name> "Djibouti" . ?e <life_expectancy> ?pv_1 . ?pv_1 <pred:unit> "year" . ?pv_1 <pred:value> "56.992"^^xsd:double . ?e <total_fertility_rate> ?pv . ?pv <pred:unit> "1" . ?pv <pred:value> "4.472"^^xsd:double . [ <pred:fact_h> ?e ; <pred:fact_r> <total_fertility_rate> ; <pred:fact_t> ?pv ] <point_in_time> ?qpv .  }
Program:
function: Find
inputs: Djibouti
function: FilterNum
dependencies: 0
inputs: life expectancy
56.992 year
=
function: QueryAttrQualifier
dependencies: 1
inputs: total fertility rate
4.472
point in time