Question: Does Seattle or Wheaton have less elevation (above sea level)?
Choices:
Columbus
Lansing
New Haven
Oakland
Seattle
Boulder
Waukegan
Greenville
Compton
Wheaton
Answer: Seattle
SPARQL: SELECT ?e WHERE { { ?e <pred:name> "Seattle" .  } UNION { ?e <pred:name> "Wheaton" .  } ?e <elevation_above_sea_level> ?pv . ?pv <pred:value> ?v .  } ORDER BY ?v LIMIT 1
Program:
function: Find
inputs: Seattle
function: Find
inputs: Wheaton
function: SelectBetween
dependencies: 0
1
inputs: elevation above sea level
less