Question: Is Indianapolis or Bradenton the bigger of the two, in terms of area?
Choices:
New Haven
Compton
Boulder
Waukegan
Franklin
Lansing
Columbus
Oakland
Indianapolis
Greenville
Answer: Indianapolis
SPARQL: SELECT ?e WHERE { { ?e <pred:name> "Indianapolis" .  } UNION { ?e <pred:name> "Bradenton" .  } ?e <area> ?pv . ?pv <pred:value> ?v .  } ORDER BY DESC(?v) LIMIT 1
Program:
function: Find
inputs: Indianapolis
function: Find
inputs: Bradenton
function: SelectBetween
dependencies: 0
1
inputs: area
greater