Question: Which has a lesser area, Jacksonville or Visalia?
Choices:
Lansing
Boulder
Jacksonville
Franklin
Waukegan
Compton
Oakland
Visalia
New Haven
Columbus
Answer: Visalia
SPARQL: SELECT ?e WHERE { { ?e <pred:name> "Jacksonville" .  } UNION { ?e <pred:name> "Visalia" .  } ?e <area> ?pv . ?pv <pred:value> ?v .  } ORDER BY ?v LIMIT 1
Program:
function: Find
inputs: Jacksonville
function: Find
inputs: Visalia
function: SelectBetween
dependencies: 0
1
inputs: area
less