Question: I want to know the number of sounds that is the origin of the name deathcore and that is named after hardcore punk.
Choices:
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Answer: 0
SPARQL: SELECT (COUNT(DISTINCT ?e) AS ?count) WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "sound" . ?e_1 <named_after> ?e . ?e_1 <pred:name> "deathcore" .  ?e <named_after> ?e_2 . ?e_2 <pred:name> "hardcore punk" .  }
Program:
function: Find
inputs: deathcore
function: Relate
dependencies: 0
inputs: named after
forward
function: FilterConcept
dependencies: 1
inputs: sound
function: Find
inputs: hardcore punk
function: Relate
dependencies: 3
inputs: named after
backward
function: FilterConcept
dependencies: 4
inputs: sound
function: And
dependencies: 2
5
function: Count
dependencies: 6