Question: What is the date of birth for the human whose Munzinger IBA is 00000016903?
Choices:
1978-10-02
1958-09-22
1977-12-09
1886-05-13
1930-12-08
1966-02-05
1899-07-07
1933-02-18
1899-04-29
1632-10-20
Answer: 1899-07-07
SPARQL: SELECT DISTINCT ?pv WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "human" . ?e <Munzinger_IBA> ?pv_1 . ?pv_1 <pred:value> "00000016903" . ?e <date_of_birth> ?pv .  }
Program:
function: FindAll
function: FilterStr
dependencies: 0
inputs: Munzinger IBA
00000016903
function: FilterConcept
dependencies: 1
inputs: human
function: QueryAttr
dependencies: 2
inputs: date of birth