Question: When was Framingham's population at 68,318?
Choices:
2010-01-01
1990
2004-04-14
2006-11-01
1959-12-01
1999-05-19
2001-08-22
1951-03-29
2017-11-23
1750
Answer: 2010-01-01
SPARQL: SELECT DISTINCT ?qpv WHERE { ?e <pred:name> "Framingham" . ?e <population> ?pv . ?pv <pred:unit> "1" . ?pv <pred:value> "68318"^^xsd:double . [ <pred:fact_h> ?e ; <pred:fact_r> <population> ; <pred:fact_t> ?pv ] <point_in_time> ?qpv .  }
Program:
function: Find
inputs: Framingham
function: QueryAttrQualifier
dependencies: 0
inputs: population
68318
point in time