Question: What is the official website of the county of Ohio whose population is equal to 125488 (the point in time of this statement is 2010-04-01)?
Choices:
http://www.co.wood.oh.us
http://www.itscomplicatedmovie.com/
http://www.kevincostner.com
http://www.curb.com
http://www.mcmaster.ca
http://www.tombrady.com/
http://www.eswfc.com/
http://www.msmnyc.edu
http://www.comune.pv.it
http://tenplay.com.au/channel-eleven/neighbours
Answer: http://www.co.wood.oh.us
SPARQL: SELECT DISTINCT ?pv WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "county of Ohio" . ?e <population> ?pv_1 . ?pv_1 <pred:unit> "1" . ?pv_1 <pred:value> "125488"^^xsd:double . [ <pred:fact_h> ?e ; <pred:fact_r> <population> ; <pred:fact_t> ?pv_1 ] <point_in_time> ?qpv . ?qpv <pred:date> "2010-04-01"^^xsd:date . ?e <official_website> ?pv .  }
Program:
function: FindAll
function: FilterNum
dependencies: 0
inputs: population
125488
=
function: QFilterDate
dependencies: 1
inputs: point in time
2010-04-01
=
function: FilterConcept
dependencies: 2
inputs: county of Ohio
function: QueryAttr
dependencies: 3
inputs: official website