Question: Which Munzinger IBA corresponds to the individual winner of the 1992 British Academy Television Award for Best Actress?
Choices:
00000019175
00000023937
00000002798
00000023182
00000022131
00000021076
00000005680
00000021766
00000011428
00000020780
Answer: 00000023937
SPARQL: SELECT DISTINCT ?pv WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "human" . ?e_1 <winner> ?e . ?e_1 <pred:name> "British Academy Television Award for Best Actress" .  [ <pred:fact_h> ?e_1 ; <pred:fact_r> <winner> ; <pred:fact_t> ?e ] <point_in_time> ?qpv . ?qpv <pred:year> 1992 . ?e <Munzinger_IBA> ?pv .  }
Program:
function: Find
inputs: British Academy Television Award for Best Actress
function: Relate
dependencies: 0
inputs: winner
forward
function: QFilterYear
dependencies: 1
inputs: point in time
1992
=
function: FilterConcept
dependencies: 2
inputs: human
function: QueryAttr
dependencies: 3
inputs: Munzinger IBA