Question: Was Beijing's population not 8600 in 2015?
Choices:
yes
no
unknown
unknown
unknown
unknown
unknown
unknown
unknown
unknown
Answer: yes
SPARQL: ASK { ?e <pred:name> "Beijing" . ?e <population> ?pv . ?pv <pred:unit> "1" . ?pv <pred:value> ?v . FILTER ( ?v != "8600"^^xsd:double ) . [ <pred:fact_h> ?e ; <pred:fact_r> <population> ; <pred:fact_t> ?pv ] <point_in_time> ?qpv . ?qpv <pred:year> 2015 .  }
Program:
function: Find
inputs: Beijing
function: QueryAttrUnderCondition
dependencies: 0
inputs: population
point in time
2015
function: VerifyNum
dependencies: 1
inputs: 8600
!=