Question: Tell me the official website for the association football club that has fcvolgann (statement subscription number 78103) as a Twitter username.
Choices:
https://www.city.ac.uk/
http://www.timor-leste.gov.tl/
http://www.purchase.edu
http://www.diddy.com
http://www.ianjamescorlett.com/
http://www.northwichvics.co.uk/
http://www.wernerherzog.com
http://www.fcvolgann.ru/
https://www.erlangen.de/
http://www.valvesoftware.com/
Answer: http://www.fcvolgann.ru/
SPARQL: SELECT DISTINCT ?pv WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "association football club" . ?e <Twitter_username> ?pv_1 . ?pv_1 <pred:value> "fcvolgann" . [ <pred:fact_h> ?e ; <pred:fact_r> <Twitter_username> ; <pred:fact_t> ?pv_1 ] <number_of_subscribers> ?qpv . ?qpv <pred:unit> "1" . ?qpv <pred:value> "78103"^^xsd:double . ?e <official_website> ?pv .  }
Program:
function: FindAll
function: FilterStr
dependencies: 0
inputs: Twitter username
fcvolgann
function: QFilterNum
dependencies: 1
inputs: number of subscribers
78103
=
function: FilterConcept
dependencies: 2
inputs: association football club
function: QueryAttr
dependencies: 3
inputs: official website