Question: How many colors comprise black or are burgundy's opposite?
Choices:
0
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9
Answer: 0
SPARQL: SELECT (COUNT(DISTINCT ?e) AS ?count) WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "color" .  { ?e_1 <has_part> ?e . ?e_1 <pred:name> "black" .  } UNION { ?e <opposite_of> ?e_1 . ?e_1 <pred:name> "burgundy" .  } }
Program:
function: Find
inputs: black
function: Relate
dependencies: 0
inputs: has part
forward
function: FilterConcept
dependencies: 1
inputs: color
function: Find
inputs: burgundy
function: Relate
dependencies: 3
inputs: opposite of
backward
function: FilterConcept
dependencies: 4
inputs: color
function: Or
dependencies: 2
5
function: Count
dependencies: 6