Question: How many albums are different from Barney's Version?
Choices:
0
1
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9
Answer: 0
SPARQL: SELECT (COUNT(DISTINCT ?e) AS ?count) WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "album" . ?e_1 <different_from> ?e . ?e_1 <pred:name> "Barney's Version" .   }
Program:
function: Find
inputs: Barney's Version
function: Relate
dependencies: 0
inputs: different from
forward
function: FilterConcept
dependencies: 1
inputs: album
function: Count
dependencies: 2