Question: When did Hereford have a population of 63024?
Choices:
1603-12-16
1792
1806-01-01
2001-08-22
2014-08-14
1968-12-01
2011-10-31
1992-01-08
2018-03-31
2016
Answer: 2016
SPARQL: SELECT DISTINCT ?qpv WHERE { ?e <pred:name> "Hereford" . ?e <population> ?pv . ?pv <pred:unit> "1" . ?pv <pred:value> "63024"^^xsd:double . [ <pred:fact_h> ?e ; <pred:fact_r> <population> ; <pred:fact_t> ?pv ] <point_in_time> ?qpv .  }
Program:
function: Find
inputs: Hereford
function: QueryAttrQualifier
dependencies: 0
inputs: population
63024
point in time