Question: How many professions does Steven Berkoff hold?
Choices:
0
1
2
3
4
5
6
7
8
9
Answer: 0
SPARQL: SELECT (COUNT(DISTINCT ?e) AS ?count) WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "profession" . ?e <officeholder> ?e_1 . ?e_1 <pred:name> "Steven Berkoff" .   }
Program:
function: Find
inputs: Steven Berkoff
function: Relate
dependencies: 0
inputs: officeholder
backward
function: FilterConcept
dependencies: 1
inputs: profession
function: Count
dependencies: 2