Question: When was the population of Ohio 11613423 ?
Choices:
2016-01-05
2004-11-01
1964-10-01
2015-01-01
1995-11-21
1871-01-01
1986-09-06
1995-09-01
1610
2015-03-15
Answer: 2015-01-01
SPARQL: SELECT DISTINCT ?qpv WHERE { ?e <pred:name> "Ohio" . ?e <population> ?pv . ?pv <pred:unit> "1" . ?pv <pred:value> "11613423"^^xsd:double . [ <pred:fact_h> ?e ; <pred:fact_r> <population> ; <pred:fact_t> ?pv ] <point_in_time> ?qpv .  }
Program:
function: Find
inputs: Ohio
function: QueryAttrQualifier
dependencies: 0
inputs: population
11613423
point in time