Question: What is the official website of a person with Twitter username Jeff_Daniels (the subscription number of this statement is 283349)?
Choices:
https://www.gillinghamfootballclub.com/
http://www.berlin2009.org/1-1-home.html
http://www.gotha.de
https://www.warnerbros.com/unknown
http://www.burnley.gov.uk/
http://www.officialrobertvaughn.com
http://disney.go.com/disneypictures/olddogs/
http://www.transy.edu
http://www.usafa.af.mil
https://www.jeffdaniels.com
Answer: https://www.jeffdaniels.com
SPARQL: SELECT DISTINCT ?pv WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "human" . ?e <Twitter_username> ?pv_1 . ?pv_1 <pred:value> "Jeff_Daniels" . [ <pred:fact_h> ?e ; <pred:fact_r> <Twitter_username> ; <pred:fact_t> ?pv_1 ] <number_of_subscribers> ?qpv . ?qpv <pred:unit> "1" . ?qpv <pred:value> "283349"^^xsd:double . ?e <official_website> ?pv .  }
Program:
function: FindAll
function: FilterStr
dependencies: 0
inputs: Twitter username
Jeff_Daniels
function: QFilterNum
dependencies: 1
inputs: number of subscribers
283349
=
function: FilterConcept
dependencies: 2
inputs: human
function: QueryAttr
dependencies: 3
inputs: official website