Question: When was the population of Newburgh 28866?
Choices:
2006-10-25
2018-12-13
1918-12-31
1593
2012-02-01
1949-03-24
1495-01-01
2010-01-01
1790-01-01
1562
Answer: 2010-01-01
SPARQL: SELECT DISTINCT ?qpv WHERE { ?e <pred:name> "Newburgh" . ?e <population> ?pv . ?pv <pred:unit> "1" . ?pv <pred:value> "28866"^^xsd:double . [ <pred:fact_h> ?e ; <pred:fact_r> <population> ; <pred:fact_t> ?pv ] <point_in_time> ?qpv .  }
Program:
function: Find
inputs: Newburgh
function: QueryAttrQualifier
dependencies: 0
inputs: population
28866
point in time