Question: When did the state of India whose rural population is greater than 420000, and whose male population is 9093476, have a female population of 13103873?
Choices:
2011-01-01
1843-12-03
1900-12-31
2008-08-06
2010-06-07
1888-12-01
1874
2005-05-18
1350-01-01
2015-03-01
Answer: 2011-01-01
SPARQL: SELECT DISTINCT ?qpv WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "state of India" . ?e <rural_population> ?pv_1 . ?pv_1 <pred:unit> "1" . ?pv_1 <pred:value> ?v_1 . FILTER ( ?v_1 > "420000"^^xsd:double ) . [ <pred:fact_h> ?e ; <pred:fact_r> <rural_population> ; <pred:fact_t> ?pv_1 ] <male_population> ?qpv_1 . ?qpv_1 <pred:unit> "1" . ?qpv_1 <pred:value> "9093476"^^xsd:double . ?e <female_population> ?pv . ?pv <pred:unit> "1" . ?pv <pred:value> "13103873"^^xsd:double . [ <pred:fact_h> ?e ; <pred:fact_r> <female_population> ; <pred:fact_t> ?pv ] <point_in_time> ?qpv .  }
Program:
function: FindAll
function: FilterNum
dependencies: 0
inputs: rural population
420000
>
function: QFilterNum
dependencies: 1
inputs: male population
9093476
=
function: FilterConcept
dependencies: 2
inputs: state of India
function: QueryAttrQualifier
dependencies: 3
inputs: female population
13103873
point in time