Question: How many families include the House of Habsburg as a member and have the official website http://www.sachsen-coburg-gotha.de/?
Choices:
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Answer: 0
SPARQL: SELECT (COUNT(DISTINCT ?e) AS ?count) WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "family" . ?e <has_part> ?e_1 . ?e_1 <pred:name> "House of Habsburg" .  ?e <official_website> ?pv . ?pv <pred:value> "http://www.sachsen-coburg-gotha.de/" .  }
Program:
function: Find
inputs: House of Habsburg
function: Relate
dependencies: 0
inputs: has part
backward
function: FilterConcept
dependencies: 1
inputs: family
function: FindAll
function: FilterStr
dependencies: 3
inputs: official website
http://www.sachsen-coburg-gotha.de/
function: FilterConcept
dependencies: 4
inputs: family
function: And
dependencies: 2
5
function: Count
dependencies: 6