Question: How many Netherlands provinces whose demonym is Groninger?
Choices:
1
2
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10
Answer: 1
SPARQL: SELECT (COUNT(DISTINCT ?e) AS ?count) WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "province of the Netherlands" . ?e <demonym> ?pv . ?pv <pred:value> "Groninger" .  }
Program:
function: FindAll
function: FilterStr
dependencies: 0
inputs: demonym
Groninger
function: FilterConcept
dependencies: 1
inputs: province of the Netherlands
function: Count
dependencies: 2