Question: Which website belongs to the person with 19689877 subscribers to his Twitter username, AlejandroSanz?
Choices:
http://www.wellingtoncollege.org.uk/
http://www.shirleyjones.com/
http://www.incheonutd.com/
http://www.anneheche.com/
http://www.bodyguardsandassassins.com/eng/page.htm
http://web.archive.org/web/20130401204339/http://www.fox.com/fringe/
https://en.fc-zenit.ru/
http://www.theyoungvictoriamovie.com/
http://www.alejandrosanz.com
http://www.frankvincent.com
Answer: http://www.alejandrosanz.com
SPARQL: SELECT DISTINCT ?pv WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "human" . ?e <Twitter_username> ?pv_1 . ?pv_1 <pred:value> "AlejandroSanz" . [ <pred:fact_h> ?e ; <pred:fact_r> <Twitter_username> ; <pred:fact_t> ?pv_1 ] <number_of_subscribers> ?qpv . ?qpv <pred:unit> "1" . ?qpv <pred:value> "19689877"^^xsd:double . ?e <official_website> ?pv .  }
Program:
function: FindAll
function: FilterStr
dependencies: 0
inputs: Twitter username
AlejandroSanz
function: QFilterNum
dependencies: 1
inputs: number of subscribers
19689877
=
function: FilterConcept
dependencies: 2
inputs: human
function: QueryAttr
dependencies: 3
inputs: official website