Question: Which has less of an elevation above sea level, Hilversum or Delft?
Choices:
Amsterdam
Maastricht
Alkmaar
Leiden
Groningen
Delft
Arnhem
Hilversum
Nijmegen
Dordrecht
Answer: Delft
SPARQL: SELECT ?e WHERE { { ?e <pred:name> "Hilversum" .  } UNION { ?e <pred:name> "Delft" .  } ?e <elevation_above_sea_level> ?pv . ?pv <pred:value> ?v .  } ORDER BY ?v LIMIT 1
Program:
function: Find
inputs: Hilversum
function: Find
inputs: Delft
function: SelectBetween
dependencies: 0
1
inputs: elevation above sea level
less