Question: What disease's incidence is more than 2.8 cases per 100000 person-years (the location of this statement is Earth) and DiseasesDB identifier is 9510?
Choices:
pedophilia
pancreatic cancer
diarrhea
peritonitis
amyotrophic lateral sclerosis
attention deficit hyperactivity disorder
gastroesophageal reflux disease
Crohn's disease
prostate cancer
bubonic plague
Answer: pancreatic cancer
SPARQL: SELECT DISTINCT ?e WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "disease" . ?e <incidence> ?pv . ?pv <pred:unit> "cases per 100000 person-years" . ?pv <pred:value> ?v . FILTER ( ?v > "2.8"^^xsd:double ) . [ <pred:fact_h> ?e ; <pred:fact_r> <incidence> ; <pred:fact_t> ?pv ] <location> ?qpv . ?qpv <pred:value> "Earth" . ?e <DiseasesDB> ?pv_1 . ?pv_1 <pred:value> "9510" .  }
Program:
function: FindAll
function: FilterNum
dependencies: 0
inputs: incidence
2.8 cases per 100000 person-years
>
function: QFilterStr
dependencies: 1
inputs: location
Earth
function: FilterConcept
dependencies: 2
inputs: disease
function: FindAll
function: FilterStr
dependencies: 4
inputs: DiseasesDB
9510
function: FilterConcept
dependencies: 5
inputs: disease
function: And
dependencies: 3
6
function: What
dependencies: 7