Question: What is the start date that 2602:300::/24 is the IPv6 routing prefix of the agent whose IPv4 routing prefix is 70.128.0.0/12 (starting in the year 2005)?
Choices:
1774-09-05
1988-01-01
2008-10-30
1992-09-03
1793-07-22
2010-03-14
1700
2011-06-17
2011-10-05
1999-09-14
Answer: 2011-06-17
SPARQL: SELECT DISTINCT ?qpv WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "agent" . ?e <IPv4_routing_prefix> ?pv_1 . ?pv_1 <pred:value> "70.128.0.0/12" . [ <pred:fact_h> ?e ; <pred:fact_r> <IPv4_routing_prefix> ; <pred:fact_t> ?pv_1 ] <start_time> ?qpv_1 . ?qpv_1 <pred:year> 2005 . ?e <IPv6_routing_prefix> ?pv . ?pv <pred:value> "2602:300::/24" . [ <pred:fact_h> ?e ; <pred:fact_r> <IPv6_routing_prefix> ; <pred:fact_t> ?pv ] <start_time> ?qpv .  }
Program:
function: FindAll
function: FilterStr
dependencies: 0
inputs: IPv4 routing prefix
70.128.0.0/12
function: QFilterYear
dependencies: 1
inputs: start time
2005
=
function: FilterConcept
dependencies: 2
inputs: agent
function: QueryAttrQualifier
dependencies: 3
inputs: IPv6 routing prefix
2602:300::/24
start time