Question: Of republics with a rate of total fertility exceeding 5.2, which takes up the least area?
Choices:
Eritrea
Sudan
Tanzania
Somalia
Sierra Leone
Niger
Uganda
Malawi
Liberia
Rwanda
Answer: Rwanda
SPARQL: SELECT ?e WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "republic" . ?e <total_fertility_rate> ?pv_1 . ?pv_1 <pred:unit> "1" . ?pv_1 <pred:value> ?v_1 . FILTER ( ?v_1 > "5.2"^^xsd:double ) . ?e <area> ?pv . ?pv <pred:value> ?v .  } ORDER BY ?v LIMIT 1
Program:
function: FindAll
function: FilterNum
dependencies: 0
inputs: total fertility rate
5.2
>
function: FilterConcept
dependencies: 1
inputs: republic
function: SelectAmong
dependencies: 2
inputs: area
smallest