Question: How many authors do we recognize  whose ISCO occupation code is 2451 or whose ROME Occupation Code (v3) is E1102 ?
Choices:
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Answer: 2
SPARQL: SELECT (COUNT(DISTINCT ?e) AS ?count) WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "author" .  { ?e <ISCO_occupation_code> ?pv . ?pv <pred:value> "2451" .  } UNION { ?e <ROME_Occupation_Code_(v3)> ?pv . ?pv <pred:value> "E1102" .  } }
Program:
function: FindAll
function: FilterStr
dependencies: 0
inputs: ISCO occupation code
2451
function: FilterConcept
dependencies: 1
inputs: author
function: FindAll
function: FilterStr
dependencies: 3
inputs: ROME Occupation Code (v3)
E1102
function: FilterConcept
dependencies: 4
inputs: author
function: Or
dependencies: 2
5
function: Count
dependencies: 6