Question: What is Zhejiang's population?
Choices:
3255944
8397804
3754786
1302161
2464459
22277541
591967
56570000
77547
57360
Answer: 56570000
SPARQL: SELECT DISTINCT ?pv WHERE { ?e <pred:name> "Zhejiang" . ?e <population> ?pv .  }
Program:
function: Find
inputs: Zhejiang
function: QueryAttr
dependencies: 0
inputs: population