Question: How many musicians have the same occupation as Roy Haynes or have a ROME Occupation Code (v3) of L1101?
Choices:
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Answer: 2
SPARQL: SELECT (COUNT(DISTINCT ?e) AS ?count) WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "musician" .  { ?e_1 <occupation> ?e . ?e_1 <pred:name> "Roy Haynes" .  } UNION { ?e <ROME_Occupation_Code_(v3)> ?pv . ?pv <pred:value> "L1101" .  } }
Program:
function: Find
inputs: Roy Haynes
function: Relate
dependencies: 0
inputs: occupation
forward
function: FilterConcept
dependencies: 1
inputs: musician
function: FindAll
function: FilterStr
dependencies: 3
inputs: ROME Occupation Code (v3)
L1101
function: FilterConcept
dependencies: 4
inputs: musician
function: Or
dependencies: 2
5
function: Count
dependencies: 6