Question: TMNT is the title of what number of entertainment?
Choices:
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Answer: 1
SPARQL: SELECT (COUNT(DISTINCT ?e) AS ?count) WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "entertainment" . ?e <title> ?pv . ?pv <pred:value> "TMNT" .  }
Program:
function: FindAll
function: FilterStr
dependencies: 0
inputs: title
TMNT
function: FilterConcept
dependencies: 1
inputs: entertainment
function: Count
dependencies: 2