Question: Which website belongs to the band with 20707 followers of its Twitter username, goldfingermusic ?
Choices:
http://www.jamiefoxxmusic.com/
http://www.brooklyn.cuny.edu
http://www.cityoforange.org
https://www.newport.gov.uk
http://www.adelaide.sa.gov.au
http://www.goldfingermusic.com
http://www.pamtillis.com/
http://www.howardstern.com
http://aja.disney.com/cinderella
http://www.haroldlloyd.com/
Answer: http://www.goldfingermusic.com
SPARQL: SELECT DISTINCT ?pv WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "band" . ?e <Twitter_username> ?pv_1 . ?pv_1 <pred:value> "goldfingermusic" . [ <pred:fact_h> ?e ; <pred:fact_r> <Twitter_username> ; <pred:fact_t> ?pv_1 ] <number_of_subscribers> ?qpv . ?qpv <pred:unit> "1" . ?qpv <pred:value> "20707"^^xsd:double . ?e <official_website> ?pv .  }
Program:
function: FindAll
function: FilterStr
dependencies: 0
inputs: Twitter username
goldfingermusic
function: QFilterNum
dependencies: 1
inputs: number of subscribers
20707
=
function: FilterConcept
dependencies: 2
inputs: band
function: QueryAttr
dependencies: 3
inputs: official website