Question: Which one has a bigger area, Champaign or Henderson.
Choices:
Columbus
Champaign
New Haven
Oakland
Compton
Waukegan
Boulder
Lansing
Franklin
Henderson
Answer: Henderson
SPARQL: SELECT ?e WHERE { { ?e <pred:name> "Henderson" .  } UNION { ?e <pred:name> "Champaign" .  } ?e <area> ?pv . ?pv <pred:value> ?v .  } ORDER BY DESC(?v) LIMIT 1
Program:
function: Find
inputs: Henderson
function: Find
inputs: Champaign
function: SelectBetween
dependencies: 0
1
inputs: area
greater