Question: What place has less area, Huntsville or Poughkeepsie?
Choices:
Columbus
Boulder
New Haven
Compton
Poughkeepsie
Greenville
Franklin
Lansing
Oakland
Waukegan
Answer: Poughkeepsie
SPARQL: SELECT ?e WHERE { { ?e <pred:name> "Huntsville" .  } UNION { ?e <pred:name> "Poughkeepsie" .  } ?e <area> ?pv . ?pv <pred:value> ?v .  } ORDER BY ?v LIMIT 1
Program:
function: Find
inputs: Huntsville
function: Find
inputs: Poughkeepsie
function: SelectBetween
dependencies: 0
1
inputs: area
less