Question: How many diseases have a medical condition of the person with the Muzinger IBA of 00000009660?
Choices:
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Answer: 1
SPARQL: SELECT (COUNT(DISTINCT ?e) AS ?count) WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "disease" . ?e_1 <medical_condition> ?e . ?e_1 <pred:instance_of> ?c_1 . ?c_1 <pred:name> "human" . ?e_1 <Munzinger_IBA> ?pv . ?pv <pred:value> "00000009660" .   }
Program:
function: FindAll
function: FilterStr
dependencies: 0
inputs: Munzinger IBA
00000009660
function: FilterConcept
dependencies: 1
inputs: human
function: Relate
dependencies: 2
inputs: medical condition
forward
function: FilterConcept
dependencies: 3
inputs: disease
function: Count
dependencies: 4