Question: Among the news whose number of episodes is greater than 700, which has the largest number of episodes?
Choices:
Good Morning America
The Colbert Report
Orange
Today
Napoleonic Wars
Second Intifada
manufacturing
FreeBSD
Western Desert Campaign
Android
Answer: Good Morning America
SPARQL: SELECT ?e WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "news" . ?e <number_of_episodes> ?pv_1 . ?pv_1 <pred:unit> "1" . ?pv_1 <pred:value> ?v_1 . FILTER ( ?v_1 > "700"^^xsd:double ) . ?e <number_of_episodes> ?pv . ?pv <pred:value> ?v .  } ORDER BY DESC(?v) LIMIT 1
Program:
function: FindAll
function: FilterNum
dependencies: 0
inputs: number of episodes
700
>
function: FilterConcept
dependencies: 1
inputs: news
function: SelectAmong
dependencies: 2
inputs: number of episodes
largest