Question: How many entertainments are in the adventure genre?
Choices:
0
1
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9
Answer: 4
SPARQL: SELECT (COUNT(DISTINCT ?e) AS ?count) WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "entertainment" . ?e <genre> ?e_1 . ?e_1 <pred:name> "adventure" .   }
Program:
function: Find
inputs: adventure
function: Relate
dependencies: 0
inputs: genre
backward
function: FilterConcept
dependencies: 1
inputs: entertainment
function: Count
dependencies: 2