Question: Which area is smaller, Los Angeles or Omaha?
Choices:
Boulder
Greenville
Los Angeles
New Haven
Omaha
Waukegan
Oakland
Franklin
Columbus
Lansing
Answer: Omaha
SPARQL: SELECT ?e WHERE { { ?e <pred:name> "Los Angeles" .  } UNION { ?e <pred:name> "Omaha" .  } ?e <area> ?pv . ?pv <pred:value> ?v .  } ORDER BY ?v LIMIT 1
Program:
function: Find
inputs: Los Angeles
function: Find
inputs: Omaha
function: SelectBetween
dependencies: 0
1
inputs: area
less