Question: http://www.sweeneytoddmovie.com/ is the official website of which Critics' Choice Movie Award?
Choices:
0
1
2
3
4
5
6
7
8
9
Answer: 3
SPARQL: SELECT (COUNT(DISTINCT ?e) AS ?count) WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "Critics' Choice Movie Award" . ?e_1 <nominated_for> ?e . ?e_1 <pred:instance_of> ?c_1 . ?c_1 <pred:name> "visual artwork" . ?e_1 <official_website> ?pv . ?pv <pred:value> "http://www.sweeneytoddmovie.com/" .   }
Program:
function: FindAll
function: FilterStr
dependencies: 0
inputs: official website
http://www.sweeneytoddmovie.com/
function: FilterConcept
dependencies: 1
inputs: visual artwork
function: Relate
dependencies: 2
inputs: nominated for
forward
function: FilterConcept
dependencies: 3
inputs: Critics' Choice Movie Award
function: Count
dependencies: 4