Question: When was 195530 the population of the big city that is the capital of Landgraviate of Hesse-Kassel (the end time of this statement is 1803-01-01) ?
Choices:
2002-10-23
2016-08-01
2015-12-03
2000-07-05
2010-12-31
1955-09-24
1996-12-04
1987-03-30
1911
1947
Answer: 2010-12-31
SPARQL: SELECT DISTINCT ?qpv WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "big city" . ?e <capital_of> ?e_1 . ?e_1 <pred:name> "Landgraviate of Hesse-Kassel" . [ <pred:fact_h> ?e ; <pred:fact_r> <capital_of> ; <pred:fact_t> ?e_1 ] <end_time> ?qpv_1 . ?qpv_1 <pred:date> "1803-01-01"^^xsd:date . ?e <population> ?pv . ?pv <pred:unit> "1" . ?pv <pred:value> "195530"^^xsd:double . [ <pred:fact_h> ?e ; <pred:fact_r> <population> ; <pred:fact_t> ?pv ] <point_in_time> ?qpv .  }
Program:
function: Find
inputs: Landgraviate of Hesse-Kassel
function: Relate
dependencies: 0
inputs: capital of
backward
function: QFilterDate
dependencies: 1
inputs: end time
1803-01-01
=
function: FilterConcept
dependencies: 2
inputs: big city
function: QueryAttrQualifier
dependencies: 3
inputs: population
195530
point in time