Question: What is the Munzinger IBA for the person winning a Primetime Emmy Award for Outstanding Lead Actor in a Miniseries or a Movie in the year 1963?
Choices:
00000010898
00000014118
00000020432
00000018279
00000020599
00000014615
00000002285
00000008306
00000022142
00000005263
Answer: 00000005263
SPARQL: SELECT DISTINCT ?pv WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "human" . ?e_1 <winner> ?e . ?e_1 <pred:name> "Primetime Emmy Award for Outstanding Lead Actor in a Miniseries or a Movie" .  [ <pred:fact_h> ?e_1 ; <pred:fact_r> <winner> ; <pred:fact_t> ?e ] <point_in_time> ?qpv . ?qpv <pred:year> 1963 . ?e <Munzinger_IBA> ?pv .  }
Program:
function: Find
inputs: Primetime Emmy Award for Outstanding Lead Actor in a Miniseries or a Movie
function: Relate
dependencies: 0
inputs: winner
forward
function: QFilterYear
dependencies: 1
inputs: point in time
1963
=
function: FilterConcept
dependencies: 2
inputs: human
function: QueryAttr
dependencies: 3
inputs: Munzinger IBA