Question: In how many entertainment works have appeared Miles "Tails" Prower?
Choices:
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9
Answer: 2
SPARQL: SELECT (COUNT(DISTINCT ?e) AS ?count) WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "entertainment" . ?e_1 <present_in_work> ?e . ?e_1 <pred:name> "Miles \"Tails\" Prower" .   }
Program:
function: Find
inputs: Miles "Tails" Prower
function: Relate
dependencies: 0
inputs: present in work
forward
function: FilterConcept
dependencies: 1
inputs: entertainment
function: Count
dependencies: 2