Question: I'd like to know the number of science award that has a review score of 0.82 or that has an official website of http://www.laskerfoundation.org/awards/formerwin.htm.
Choices:
0
1
2
3
4
5
6
7
8
9
Answer: 2
SPARQL: SELECT (COUNT(DISTINCT ?e) AS ?count) WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "science award" .  { ?e <review_score> ?pv . ?pv <pred:value> "0.82" .  } UNION { ?e <official_website> ?pv . ?pv <pred:value> "http://www.laskerfoundation.org/awards/formerwin.htm" .  } }
Program:
function: FindAll
function: FilterStr
dependencies: 0
inputs: review score
0.82
function: FilterConcept
dependencies: 1
inputs: science award
function: FindAll
function: FilterStr
dependencies: 3
inputs: official website
http://www.laskerfoundation.org/awards/formerwin.htm
function: FilterConcept
dependencies: 4
inputs: science award
function: Or
dependencies: 2
5
function: Count
dependencies: 6