Question: What does Another Year have to do with Imelda Staunton?
Choices:
production company
performer
military rank
permanent resident of
penalty
cast member
color
occupant
allegiance
architectural style
Answer: cast member
SPARQL: SELECT DISTINCT ?p WHERE { ?e_1 <pred:name> "Another Year" . ?e_2 <pred:name> "Imelda Staunton" . ?e_1 ?p ?e_2 .  }
Program:
function: Find
inputs: Another Year
function: Find
inputs: Imelda Staunton
function: QueryRelation
dependencies: 0
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