Question: http://www.razzies.com/ is the official website of what number of Golden Raspberry Awards?
Choices:
8
9
10
11
12
13
14
15
16
17
Answer: 11
SPARQL: SELECT (COUNT(DISTINCT ?e) AS ?count) WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "Golden Raspberry Awards" . ?e <official_website> ?pv . ?pv <pred:value> "http://www.razzies.com/" .  }
Program:
function: FindAll
function: FilterStr
dependencies: 0
inputs: official website
http://www.razzies.com/
function: FilterConcept
dependencies: 1
inputs: Golden Raspberry Awards
function: Count
dependencies: 2