Question: What number of genres have a website that is http://www.cbs.com/shows/the_twilight_zone or a start time later than 1959?
Choices:
0
1
2
3
4
5
6
7
8
9
Answer: 1
SPARQL: SELECT (COUNT(DISTINCT ?e) AS ?count) WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "genre" .  { ?e <official_website> ?pv . ?pv <pred:value> "http://www.cbs.com/shows/the_twilight_zone/" .  } UNION { ?e <start_time> ?pv . ?pv <pred:year> ?v . FILTER ( ?v > 1959 ) .  } }
Program:
function: FindAll
function: FilterStr
dependencies: 0
inputs: official website
http://www.cbs.com/shows/the_twilight_zone/
function: FilterConcept
dependencies: 1
inputs: genre
function: FindAll
function: FilterYear
dependencies: 3
inputs: start time
1959
>
function: FilterConcept
dependencies: 4
inputs: genre
function: Or
dependencies: 2
5
function: Count
dependencies: 6