Question: Which has fewer people, Oxford or Shrewsbury?
Choices:
Shrewsbury
Aylesbury
Bedford
Warwick
Reading
Northampton
Oxford
Guildford
Ipswich
Maidstone
Answer: Shrewsbury
SPARQL: SELECT ?e WHERE { { ?e <pred:name> "Oxford" .  } UNION { ?e <pred:name> "Shrewsbury" .  } ?e <population> ?pv . ?pv <pred:value> ?v .  } ORDER BY ?v LIMIT 1
Program:
function: Find
inputs: Oxford
function: Find
inputs: Shrewsbury
function: SelectBetween
dependencies: 0
1
inputs: population
less