Question: What number of dynasties are part of House of Savoy ?
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Answer: 0
SPARQL: SELECT (COUNT(DISTINCT ?e) AS ?count) WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "dynasty" . ?e <part_of> ?e_1 . ?e_1 <pred:name> "House of Savoy" .   }
Program:
function: Find
inputs: House of Savoy
function: Relate
dependencies: 0
inputs: part of
backward
function: FilterConcept
dependencies: 1
inputs: dynasty
function: Count
dependencies: 2