Question: What is the time point of the city with a population equaling 1088000 and Glaswegian as its demonym?
Choices:
1994-02-15
2007-12-01
2003-08-01
1955-02-01
1951
1931-01-01
1831
1994-06-16
2015-01-22
1867-12-03
Answer: 1931-01-01
SPARQL: SELECT DISTINCT ?qpv WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "city" . ?e <demonym> ?pv_1 . ?pv_1 <pred:value> "Glaswegian" . ?e <population> ?pv . ?pv <pred:unit> "1" . ?pv <pred:value> "1088000"^^xsd:double . [ <pred:fact_h> ?e ; <pred:fact_r> <population> ; <pred:fact_t> ?pv ] <point_in_time> ?qpv .  }
Program:
function: FindAll
function: FilterStr
dependencies: 0
inputs: demonym
Glaswegian
function: FilterConcept
dependencies: 1
inputs: city
function: QueryAttrQualifier
dependencies: 2
inputs: population
1088000
point in time