Question: Regarding the TV station http://www.imbc.com, with official website, http://www.imbc.com, and the Twitter username with NBC, tell me the number of subscribers.
Choices:
25066
93151
845463
652801
332574
21273808
1035941
1389
1227103
55009
Answer: 1035941
SPARQL: SELECT DISTINCT ?qpv WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "television station" . ?e <official_website> ?pv_1 . ?pv_1 <pred:value> "http://www.imbc.com" . ?e <Twitter_username> ?pv . ?pv <pred:value> "withMBC" . [ <pred:fact_h> ?e ; <pred:fact_r> <Twitter_username> ; <pred:fact_t> ?pv ] <number_of_subscribers> ?qpv .  }
Program:
function: FindAll
function: FilterStr
dependencies: 0
inputs: official website
http://www.imbc.com
function: FilterConcept
dependencies: 1
inputs: television station
function: QueryAttrQualifier
dependencies: 2
inputs: Twitter username
withMBC
number of subscribers