Question: Which has a lesser number of episodes, Lost, season 3 or Cranford?
Choices:
The Wire, season 5
Monster House
The Wire, season 1
Cold War
Cranford
variety
The Wire, season 3
The Larry Sanders Show
Lost, season 3
Peter Pan
Answer: Cranford
SPARQL: SELECT ?e WHERE { { ?e <pred:name> "Lost, season 3" .  } UNION { ?e <pred:name> "Cranford" .  } ?e <number_of_episodes> ?pv . ?pv <pred:value> ?v .  } ORDER BY ?v LIMIT 1
Program:
function: Find
inputs: Lost, season 3
function: Find
inputs: Cranford
function: SelectBetween
dependencies: 0
1
inputs: number of episodes
less