Question: Which one, Hilversum or Delft, has less area?
Choices:
Groningen
Arnhem
Rotterdam
Hilversum
Dordrecht
Amsterdam
Alkmaar
Maastricht
Leiden
Delft
Answer: Delft
SPARQL: SELECT ?e WHERE { { ?e <pred:name> "Hilversum" .  } UNION { ?e <pred:name> "Delft" .  } ?e <area> ?pv . ?pv <pred:value> ?v .  } ORDER BY ?v LIMIT 1
Program:
function: Find
inputs: Hilversum
function: Find
inputs: Delft
function: SelectBetween
dependencies: 0
1
inputs: area
less