Question: When did have a population of 126319 people?
Choices:
2012-07-01
1970-11-01
1086
2009-03-01
1991
1712-01-01
2001-03-25
2004-12-20
1890-01-01
1939-01-01
Answer: 2012-07-01
SPARQL: SELECT DISTINCT ?qpv WHERE { ?e <pred:name> "Hunterdon County" . ?e <population> ?pv . ?pv <pred:unit> "1" . ?pv <pred:value> "126319"^^xsd:double . [ <pred:fact_h> ?e ; <pred:fact_r> <population> ; <pred:fact_t> ?pv ] <point_in_time> ?qpv .  }
Program:
function: Find
inputs: Hunterdon County
function: QueryAttrQualifier
dependencies: 0
inputs: population
126319
point in time