Question: what is the number of heavy metal that has famous people Rob Zombie.
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Answer: 2
SPARQL: SELECT (COUNT(DISTINCT ?e) AS ?count) WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "heavy metal" . ?e <famous_people> ?e_1 . ?e_1 <pred:name> "Rob Zombie" .   }
Program:
function: Find
inputs: Rob Zombie
function: Relate
dependencies: 0
inputs: famous people
backward
function: FilterConcept
dependencies: 1
inputs: heavy metal
function: Count
dependencies: 2