Question: How many musicians share the profession of Steven Van Zandt?
Choices:
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Answer: 1
SPARQL: SELECT (COUNT(DISTINCT ?e) AS ?count) WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "musician" . ?e_1 <occupation> ?e . ?e_1 <pred:name> "Steven Van Zandt" .   }
Program:
function: Find
inputs: Steven Van Zandt
function: Relate
dependencies: 0
inputs: occupation
forward
function: FilterConcept
dependencies: 1
inputs: musician
function: Count
dependencies: 2