Question: Which has fewer people, Compton or Steubenville?
Choices:
Oakland
Franklin
Compton
Lansing
Columbus
Steubenville
Greenville
Waukegan
New Britain
Boulder
Answer: Steubenville
SPARQL: SELECT ?e WHERE { { ?e <pred:name> "Compton" .  } UNION { ?e <pred:name> "Steubenville" .  } ?e <population> ?pv . ?pv <pred:value> ?v .  } ORDER BY ?v LIMIT 1
Program:
function: Find
inputs: Compton
function: Find
inputs: Steubenville
function: SelectBetween
dependencies: 0
1
inputs: population
less