Question: Per this statement with a 2011-07-11 start time, what's the name of the movie with an exploitation visa number of 130375?
Choices:
The Last Picture Show
Six Degrees of Separation
The Cell
Green Lantern
Gigi
Colorado
Stranger than Fiction
Pirates of the Caribbean: Dead Man's Chest
Hamlet
Rich Man, Poor Man
Answer: Green Lantern
SPARQL: SELECT DISTINCT ?pv WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "film" . ?e <exploitation_visa_number> ?pv_1 . ?pv_1 <pred:value> "130375" . [ <pred:fact_h> ?e ; <pred:fact_r> <exploitation_visa_number> ; <pred:fact_t> ?pv_1 ] <start_time> ?qpv . ?qpv <pred:date> "2011-07-11"^^xsd:date . ?e <title> ?pv .  }
Program:
function: FindAll
function: FilterStr
dependencies: 0
inputs: exploitation visa number
130375
function: QFilterDate
dependencies: 1
inputs: start time
2011-07-11
=
function: FilterConcept
dependencies: 2
inputs: film
function: QueryAttr
dependencies: 3
inputs: title