Question: I need to know the word that has official website http://www.worldfantasy.org/awards/ and that is a list of people.
Choices:
Grammy Award for Best Reggae Album
Cannes Film Festival Award for Best Actor
Independent Spirit Award for Best Female Lead
Golden Globe Award for Best Animated Feature Film
World Fantasy Award for Life Achievement
World Fantasy Award for Best Anthology
World Fantasy Award for Best Novel
Grammy Award for Best Metal Performance
NBA Rookie of the Year Award
Grammy Award for Best Male Pop Vocal Performance
Answer: World Fantasy Award for Life Achievement
SPARQL: SELECT DISTINCT ?e WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "award" . ?e <official_website> ?pv . ?pv <pred:value> "http://www.worldfantasy.org/awards/" . ?e <is_a_list_of> ?e_1 . ?e_1 <pred:name> "human" .  }
Program:
function: FindAll
function: FilterStr
dependencies: 0
inputs: official website
http://www.worldfantasy.org/awards/
function: FilterConcept
dependencies: 1
inputs: award
function: Find
inputs: human
function: Relate
dependencies: 3
inputs: is a list of
backward
function: FilterConcept
dependencies: 4
inputs: award
function: And
dependencies: 2
5
function: What
dependencies: 6