Question: Regarding the tv station with the Snapchat username cbsnews and Twitter username of CBSNews, what is the number of subscribers?
Choices:
2048892
71276
1760042
139640
295112
31391
1293627
6550247
12479
113965
Answer: 6550247
SPARQL: SELECT DISTINCT ?qpv WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "television station" . ?e <Snapchat_username> ?pv_1 . ?pv_1 <pred:value> "cbsnews" . ?e <Twitter_username> ?pv . ?pv <pred:value> "CBSNews" . [ <pred:fact_h> ?e ; <pred:fact_r> <Twitter_username> ; <pred:fact_t> ?pv ] <number_of_subscribers> ?qpv .  }
Program:
function: FindAll
function: FilterStr
dependencies: 0
inputs: Snapchat username
cbsnews
function: FilterConcept
dependencies: 1
inputs: television station
function: QueryAttrQualifier
dependencies: 2
inputs: Twitter username
CBSNews
number of subscribers