Question: How many diseases are a risk factor of meningitis?
Choices:
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Answer: 4
SPARQL: SELECT (COUNT(DISTINCT ?e) AS ?count) WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "disease" . ?e <risk_factor> ?e_1 . ?e_1 <pred:name> "meningitis" .   }
Program:
function: Find
inputs: meningitis
function: Relate
dependencies: 0
inputs: risk factor
backward
function: FilterConcept
dependencies: 1
inputs: disease
function: Count
dependencies: 2