Question: What is the elevation (above sea level) of the city of the United States that is the capital of Dakota County ?
Choices:
416 metre
294.7 metre
222 metre
10 metre
380 metre
409.4 metre
1524 metre
305 metre
334 metre
0 foot
Answer: 222 metre
SPARQL: SELECT DISTINCT ?pv WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "city of the United States" . ?e <capital_of> ?e_1 . ?e_1 <pred:name> "Dakota County" .  ?e <elevation_above_sea_level> ?pv .  }
Program:
function: Find
inputs: Dakota County
function: Relate
dependencies: 0
inputs: capital of
backward
function: FilterConcept
dependencies: 1
inputs: city of the United States
function: QueryAttr
dependencies: 2
inputs: elevation above sea level