Question: How many natural languages have a 1.5% speakers?
Choices:
0
1
2
3
4
5
6
7
8
9
Answer: 0
SPARQL: SELECT (COUNT(DISTINCT ?e) AS ?count) WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "natural language" . ?e <number_of_speakers> ?pv . ?pv <pred:unit> "percentage" . ?pv <pred:value> "1.5"^^xsd:double .  }
Program:
function: FindAll
function: FilterNum
dependencies: 0
inputs: number of speakers
1.5 percentage
=
function: FilterConcept
dependencies: 1
inputs: natural language
function: Count
dependencies: 2