Question: Which has fewer people, Wheaton or Sandusky?
Choices:
Lansing
Boulder
Wheaton
Greenville
Sandusky
Columbus
Compton
Waukegan
New Haven
Franklin
Answer: Sandusky
SPARQL: SELECT ?e WHERE { { ?e <pred:name> "Wheaton" .  } UNION { ?e <pred:name> "Sandusky" .  } ?e <population> ?pv . ?pv <pred:value> ?v .  } ORDER BY ?v LIMIT 1
Program:
function: Find
inputs: Wheaton
function: Find
inputs: Sandusky
function: SelectBetween
dependencies: 0
1
inputs: population
less