Question: How many business people usually have Lisa Gerrard as a property?
Choices:
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Answer: 0
SPARQL: SELECT (COUNT(DISTINCT ?e) AS ?count) WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "businessperson" . ?e <properties_for_this_type> ?e_1 . ?e_1 <pred:name> "Lisa Gerrard" .   }
Program:
function: Find
inputs: Lisa Gerrard
function: Relate
dependencies: 0
inputs: properties for this type
backward
function: FilterConcept
dependencies: 1
inputs: businessperson
function: Count
dependencies: 2