Question: Is the elevation (above sea level) greater for College Park or Holyoke?
Choices:
New Haven
Waukegan
Columbus
Franklin
Holyoke
Compton
Lansing
College Park
Oakland
Boulder
Answer: Holyoke
SPARQL: SELECT ?e WHERE { { ?e <pred:name> "College Park" .  } UNION { ?e <pred:name> "Holyoke" .  } ?e <elevation_above_sea_level> ?pv . ?pv <pred:value> ?v .  } ORDER BY DESC(?v) LIMIT 1
Program:
function: Find
inputs: College Park
function: Find
inputs: Holyoke
function: SelectBetween
dependencies: 0
1
inputs: elevation above sea level
greater