Question: What is the official website of the television channel with Twitter username TELETOON which has 8817 subscribers?
Choices:
http://www.dianakrall.com
http://www.blizzard.com
http://www.ozzy.com/
http://www.sydbarrett.com
http://www.teletoon.com/en/
http://www.yesisthenewno.com/
http://www.channel4.com/hollyoaks
https://www.montrealalouettes.com
http://www.legallyblonde.com/
http://www.law.stanford.edu/
Answer: http://www.teletoon.com/en/
SPARQL: SELECT DISTINCT ?pv WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "television channel" . ?e <Twitter_username> ?pv_1 . ?pv_1 <pred:value> "TELETOON" . [ <pred:fact_h> ?e ; <pred:fact_r> <Twitter_username> ; <pred:fact_t> ?pv_1 ] <number_of_subscribers> ?qpv . ?qpv <pred:unit> "1" . ?qpv <pred:value> "8817"^^xsd:double . ?e <official_website> ?pv .  }
Program:
function: FindAll
function: FilterStr
dependencies: 0
inputs: Twitter username
TELETOON
function: QFilterNum
dependencies: 1
inputs: number of subscribers
8817
=
function: FilterConcept
dependencies: 2
inputs: television channel
function: QueryAttr
dependencies: 3
inputs: official website