Question: When did  David Brown (the one whose date of birth is 1889-07-26) become a member of the Tottenham Hotspur F.C.?
Choices:
2008
1992-07-17
1971-01-25
1885
1896-01-04
2011-04-03
2005-04-15
1960-05-01
1958-10-07
1909
Answer: 1909
SPARQL: SELECT DISTINCT ?qpv WHERE { ?e_1 <pred:name> "David Brown" . ?e_1 <date_of_birth> ?pv . ?pv <pred:date> "1889-07-26"^^xsd:date . ?e_2 <pred:name> "Tottenham Hotspur F.C." . ?e_1 <member_of_sports_team> ?e_2 . [ <pred:fact_h> ?e_1 ; <pred:fact_r> <member_of_sports_team> ; <pred:fact_t> ?e_2 ] <start_time> ?qpv .  }
Program:
function: Find
inputs: David Brown
function: FilterDate
dependencies: 0
inputs: date of birth
1889-07-26
=
function: Find
inputs: Tottenham Hotspur F.C.
function: QueryRelationQualifier
dependencies: 1
2
inputs: member of sports team
start time