Question: How many businesses are different from Chrysler established in 1925 or were not founded in 1976?
Choices:
165
166
167
168
169
170
171
172
173
174
Answer: 168
SPARQL: SELECT (COUNT(DISTINCT ?e) AS ?count) WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "business" .  { ?e_1 <different_from> ?e . ?e_1 <pred:name> "Chrysler" . ?e_1 <inception> ?pv . ?pv <pred:year> 1925 .  } UNION { ?e <inception> ?pv . ?pv <pred:year> ?v . FILTER ( ?v != 1976 ) .  } }
Program:
function: Find
inputs: Chrysler
function: FilterYear
dependencies: 0
inputs: inception
1925
=
function: Relate
dependencies: 1
inputs: different from
forward
function: FilterConcept
dependencies: 2
inputs: business
function: FindAll
function: FilterYear
dependencies: 4
inputs: inception
1976
!=
function: FilterConcept
dependencies: 5
inputs: business
function: Or
dependencies: 3
6
function: Count
dependencies: 7