Question: When did the sovereign state whose life expectancy is 76.786 years have a population of 2602573?
Choices:
2016-11-12
1979
2001-03-25
1921-01-01
30000000
2014-06-26
2014-02-22
2018-11-27
1961-04-17
1825-12-01
Answer: 1979
SPARQL: SELECT DISTINCT ?qpv WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "sovereign state" . ?e <life_expectancy> ?pv_1 . ?pv_1 <pred:unit> "year" . ?pv_1 <pred:value> "76.786"^^xsd:double . ?e <population> ?pv . ?pv <pred:unit> "1" . ?pv <pred:value> "2602573"^^xsd:double . [ <pred:fact_h> ?e ; <pred:fact_r> <population> ; <pred:fact_t> ?pv ] <point_in_time> ?qpv .  }
Program:
function: FindAll
function: FilterNum
dependencies: 0
inputs: life expectancy
76.786 year
=
function: FilterConcept
dependencies: 1
inputs: sovereign state
function: QueryAttrQualifier
dependencies: 2
inputs: population
2602573
point in time