Question: When did Suiza had a life expectancy of 80.18049 years?
Choices:
1928
2014-10-31
1948-08-01
2001
1915-01-01
1753
1086
2018-01-01
2009-01-14
1829-01-01
Answer: 2001
SPARQL: SELECT DISTINCT ?qpv WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "sovereign state" . ?e <demonym> ?pv_1 . ?pv_1 <pred:value> "suiza" . ?e <life_expectancy> ?pv . ?pv <pred:unit> "year" . ?pv <pred:value> "80.18049"^^xsd:double . [ <pred:fact_h> ?e ; <pred:fact_r> <life_expectancy> ; <pred:fact_t> ?pv ] <point_in_time> ?qpv .  }
Program:
function: FindAll
function: FilterStr
dependencies: 0
inputs: demonym
suiza
function: FilterConcept
dependencies: 1
inputs: sovereign state
function: QueryAttrQualifier
dependencies: 2
inputs: life expectancy
80.18049 year
point in time