Question: Does Wheeling or Hartford have more area?
Choices:
Wheeling
Columbus
New Haven
Lansing
Boulder
Waukegan
Greenville
Compton
Franklin
Hartford
Answer: Hartford
SPARQL: SELECT ?e WHERE { { ?e <pred:name> "Wheeling" .  } UNION { ?e <pred:name> "Hartford" .  } ?e <area> ?pv . ?pv <pred:value> ?v .  } ORDER BY DESC(?v) LIMIT 1
Program:
function: Find
inputs: Wheeling
function: Find
inputs: Hartford
function: SelectBetween
dependencies: 0
1
inputs: area
greater