divelab/Sys2Bench huggingface dataset:
Question: The average marks of a class of 30 students is 40 and that of another class of 50 students is 90. Find the average marks of all the students?
Options:
A)71.25
B)52.9
C)52.1
D)52.3
E)42.5
Rationale: Sum of the marks for the class of 30 students = 30 * 40 = 1200
Sum of the marks for the class of 50 students = 50 * 90 = 4500
Sum of the marks for the class of 80 students =
1200 + 4500 = 5700
Average marks of all the students = 5700/80
= 71.25
Answer:A
Answer: A
Question: A distributor sells a product through an on-line store, which take a commission of 20% of the price set by the distributor. The distributor obtains the product from a producer at the price of $15 per item. What is the price that the buyer observers on-line if the distributor wants to maintain a 10% profit on the cost of the item?
Options:
A)18
B)21.6
C)20
D)22.5
E)27
Rationale: Producer price = $15;
The distributor wants to maintain a 20% profit on the cost of the item, thus he must get $15*1.2 = $18 after the store takes a commission of 10% of the final price --> (final price)*0.9 = $18 --> (final price) = $20.
Answer: C.
Answer: C
Question: A man wants to sell his scooter .There are two offers one at Rs12000 cash and other at a credit of Rs12880 to be paid after 8 months ,money being at 18% per annum which is better offer?
Options:
A)24277
B)12000
C)28372
D)36788
E)17881
Rationale: Explanation:
PW of Rs.12,880 due 8 months hence
= Rs\inline \fn_jvn \left [ \left ( \frac{12880\times 100}{100+(18\times \frac{8}{12})} \right ) \right ] =Rs.11500
Clearly 12000 in cash is a better offer.
Answer: B) Rs.12000
Answer: B
Question: (6!-4!)/5!=?
Options:
A)29/5
B)28/3
C)27/6
D)25/4
E)29/6
Rationale: (6!-4!)/5!
(4!*5*6-4!)/5!
4!(5*6-1)/4!*5
29/5
answer A
Answer: A
Question: A scooter costs 20,000 when it is brand new. At the end of each year, its value is only 80% of what it was at the beginning of the year. What is the value of the scooter at the end of 3 years?
Options:
A)10,240
B)12,500
C)12,800
D)12,000
E)None of these
Rationale: After first year, the value of the scooter = 16,000
After second year, the value of scooter = 12,800
After third year, the value of scooter = 10,240
Answer A
Answer: A
Question: What is the least number should be added to 1056, so the sum of the number is completely divisible by 26?
Options:
A)10
B)20
C)30
D)40
E)50
Rationale: (1056 / 26) gives remainder 16
10 + 16 = 26, So we need to add 10
A
Answer: A
Question: Average of five numbers is 27. If one number is excluded the average becomes 25. The excluded number is
Options:
A)35
B)45
C)55
D)65
E)75
Rationale: Explanation:
Number is (5*27) - (4*25) = 135-100 = 35
Option A
Answer: A
Question: In how many ways can an answer key for a quiz be written if the quiz contains 5 true-false questions followed by 3 multiple-choice questions with 4 answer choices each, if the correct answers to all true-false questions cannot be the same?
Options:
A)1220
B)1650
C)1920
D)2440
E)2860
Rationale: There are 2^5 = 32 possibilities for the true-false answers.
However we need to remove two cases for TTTTT and FFFFF.
There are 4*4*4 = 64 possibilities for the multiple choice questions.
The total number of possibilities is 30*64 = 1920.
The answer is C.
Answer: C
Question: In a certain pond, 40 fish were caught, tagged, and returned to the pond. A few days later, 40 fish were caught again, of which 2 were found to have been tagged. If the percent of tagged fish in the second catch approximates the percent of tagged fish in the pond, what is the approximate number of fish in the pond?
Options:
A) 210
B) 360
C) 520
D) 775
E) 800
Rationale: total fish = x
percentage of second catch = (2/40)*100 = 5%
so, x * 5% = 40
x = 800 ans E.
Answer: E
Question: 1.	How much more would Rs.16000 fetch, after two years, if it is put at 20% p.a. compound interest payable half yearly than if is put at 20% p.a. compound interest payable yearly?
Options:
A)A)Rs.4,225.60
B)B)Rs.4226.60
C)C)Rs.4,227.60
D)D)Rs.4,228.60
E)E)Rs.4,229.60
Rationale: 16000(11/10)4 - 16000(6/5)2 = 4,225.60
ANSWER:A
Answer: A
Question: The average weight of a group of boys is 30 kg. After a boy of weight 39 kg joins the group, the average weight of the group goes up by 1 kg. Find the number of boys in the group originally ?
Options:
A)A)4
B)B)8
C)C)6
D)D)2
E)E)1
Rationale: Let the number off boys in the group originally be x.
Total weight of the boys = 30x
After the boy weighing 39 kg joins the group, total weight of boys = 30x + 39
So 30x + 39 = 31(x + 1) = > x = 8.
Answer:B
Answer: B
Question: The total of the ages of Arun, Ajith, Ajay is 90 years. Ten years ago, the ratio of their ages was 1:2:3. What is the present age of Ajay?
Options:
A)40years
B)35years
C)38years
D)30years
E)42years
Rationale: Let ages of Arun, Ajith, Ajay 10years ago be x,2x,3x
x+10 + 2x+10 +3x+10 = 90
x = 10
Ramesh present age = 3*10+10 = 40 years
Answer is A
Answer: A
Question: If the number is decreased by 5 and divided by 7 the result is 7. What would be the result if 4 is subtracted and divided by 10?
Options:
A)4
B)7
C)8
D)5
E)3
Rationale: Explanation:
Let the number be x. Then,
(x - 5)/7 = 7 => x - 5 = 49
x = 54
.: (x - 4)/10 = (54 - 4)/10 = 5
Answer: Option D
Answer: D
Question: A certain sum of money at simple interest amounted Rs.934 in 8 years at 2% per annum, find the sum?
Options:
A)338
B)805
C)890
D)870
E)261
Rationale: 934 = P [1 + (8*2)/100]
P = 805
Answer:B
Answer: B
Question: A certain airline's fleet consisted of 90 type A planes at the beginning of 1980. At the end of each year, starting with 1980, the airline retired 3 of the TYPE A planes and acquired 4 new type B plans. How many years did it take before the number of type A planes left in the airline's fleet was less than 50 percent of the fleet?
Options:
A)11
B)12
C)13
D)14
E)15
Rationale: Let x be the number of years.
4x > 90 - 3x
7x > 90
x > 12 + 6/7
The answer is C.
Answer: C
Question: Reduce
803/876
to the lowest terms.
Options:
A)11/12
B)23/24
C)26/27
D)4/7
E)6/9
Rationale: Explanation:
HCF of 803 and 876 is 73, Divide both by 73, We get the answer 11/12
Option A
Answer: A
Question: Rs.705 is divided amongst A, B, C so that 3 times A's share, 5 times B's share and 4 times C's share are all equal. Find B's share?
Options:
A)177
B)150
C)180
D)716
E)616
Rationale: A+B+C = 7053A = 5B = 4C = xA:B:C = 1/3:1/5:1/4= 20:12:1512/47 * 705= Rs.180Answer: C
Answer: C
Question: When 2 + 3 = 65, 3 + 4 = 125, 4 + 5 = 205, then 5 + 6 = ?
Options:
A)285
B)305
C)315
D)350
E)245
Rationale: 2 + 3 => 2 Ã— 3 = 6 => 6 Ã— 10 + 5 = 65
3 + 4 => 3 Ã— 4 = 12 => 12 Ã— 10 + 5 = 125
4 + 5 => 4 Ã— 5 = 20 => 20 Ã— 10 + 5 = 205
Then 5 + 6 => 5 Ã— 6 = 30 => 30 Ã— 10 + 5 = 305
Answer : B
Answer: B
Question: A city with a population of 173,460 is to be divided into 9 voting districts, and no district is to have a population that is more than 10 percent greater than the population of any other district. What is the minimum possible population that the least populated district could have?
Options:
A)17,400
B)17,500
C)17,600
D)17,700
E)17,800
Rationale: The minimum possible population occurs when all the other districts have a population that is 10% greater than the least populated district.
Let p be the population of the least populated district.
Then 173,460 = p + 8(1.1)p
9.8p=173,460
p = 17,700
The answer is D.
Answer: D
Question: Find the area of circle whose radius is 7m?
Options:
A)138
B)154
C)288
D)280
E)371
Rationale: 22/7 * 7 * 7
= 154
Answer:B
Answer: B
Question: A cube of edge 7 cm is cut into cubes each of edge 1 cm. The ratio of the total surface area of one of the small cubes to that of the large cube is equal to:
Options:
A)1:25
B)1:49
C)1:52
D)1:522
E)None
Rationale: Sol.
Required ratio = 6 * 1 * 1 / 6 * 7 * 7 = 1/49 = 1:49.
Answer B
Answer: B
Question: An art gallery has only paintings and sculptures. Currently, 1/3 of the pieces of art are displayed, and 1/6 of the pieces on display are sculptures. If 1/3 of the pieces not on display are paintings, and 800 sculptures are not on display, how many pieces of art does the gallery have?
Options:
A)360
B)1800
C)540
D)640
E)720
Rationale: Too many words and redundant info there.
(i) 1/3 of the pieces of art are displayed, hence2/3 of the pieces of art are NOT displayed.
(ii) 1/6 of the pieces on display are sculptures, hence 5/6 of the pieces on display are paintings.
(iii) 1/3 of the pieces NOT on display are paintings, hence2/3 of the pieces NOT on display are sculptures.
800 sculptures are not on display, so according to (iii) 2/3*{not on display} = 800 --> {not on display} = 1200.
According to (i) 2/3*{total} = 1200 --> {total} = 1800.
Answer: B.
Answer: B
Question: (8^16)+(16^13)+(4^20) = ?
Options:
A)(4)*(2^29+1)
B)(6)*(2^48)
C)(9)*(2^49)
D)(28)*(2^53)
E)2^148
Rationale: I think you are assuming that (X^Y) + (X^Z) is = (X^Y+Z) which is not true, as it only applies to multiplication. Rather it would have to be (X^Y)(X^Z) = (X^YZ)
So when you simplify down to 2^48 + 2^52 + 2^48 you cannot just add exponents.
Here's how my brain works with this one,
Step 1: Recognize a common base.
(8^16) + (16^13) + (4^24) = ((2^2)^16) + ((2^4)^13) + ((2^2)^24) = (2^48) + (2^52) + (2^48)
Step 2: Recognize the factor and pull out of the equation.
= (2^48)(1 + (2^4) + 1)
= (2^48)(1 + 16 + 1)
= (2^48)(18)
Step 3: Recognize this is not an answer and adapt.
(2^48)(18) = (2^48)(2)(9) = (2^48)(6)
Answer is B.
Answer: B
Question: If A lends Rs.1500 to B at 10% per annum and B lends the same sum to C at 11.5% per annum then the gain of B in a period of 3 years is?
Options:
A)112.5
B)122.5
C)132.5
D)67.5
E)212.5
Rationale: (1500*1.5*3)/100 => 67.5
ANSWER:D
Answer: D
Question: If the price of a computer were reduced by 16 percent, which of the following could not be the final price of the computer? (Assume initial price to be integer in cents)
Options:
A)$844.10
B)$896.70
C)$1,056.30
D)$1,136.10
E)$1,264.20
Rationale: Let X be the initial price of computer without discount
then price (final) after discount should be=X(1-16/100)------->X(21/25)=A(say)
means X=A*(25/21).....
so initial price to be integer(As per stem) final price must be multiple of 21(3 or 7)
if we check options all were divisible by 3 except option (A)
Answer: A
Answer: A
Question: the average of four consecutive even numbers is 27. find the largest of these numbers?
Options:
A)10
B)20
C)30
D)40
E)50
Rationale: Sol: let the numbers be x,x+2,x+4 andx+6. then,
(x+(x+2)+(x+4)+(x+6))/4) = 27
(4x+12)/4 = 27
x+3=27  x=24.
Therefore the largest number=(x+6)=24+6=30.
ANSWER: C
Answer: C
Question: In a 1000 m race, A beats B by 250 meters or 25 seconds. Find the speed of B?
Options:
A)10
B)9
C)7
D)5
E)2
Rationale: Since A beats B by 250 m or 25 seconds, i
t implies that B covers 250 m in 25 seconds.
Hence speed of B = 250/25 = 10 m/s.
Answer: A
Answer: A
Question: How many cuboids of length 5 m, width 2 m and height 3 m can be farmed from a cuboid of 18 m length, 15 m width and 2 m height.
Options:
A)10
B)12
C)15
D)16
E)18
Rationale: (18 Ã— 15 Ã— 12)/(5 Ã— 3 Ã— 2) = 18
Answer is E.
Answer: E
Question: A certain number of men can finish a piece of work in 100 days. If there were 10 men less, it would take 10 days more for the work to be finished. How many men were there originally?
Options:
A)120
B)105
C)115
D)110
E)140
Rationale: Originally let there be x men.
Less men, More days (Indirect Proportion)
therefore (x-10) : x :: 100 :110
=(x-10)x 110-x(100)
= 10x= 1100
x= 110
Answer is D.
Answer: D
Question: A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 680 sq. feet, how many feet of fencing will be required ?
Options:
A)34
B)40
C)68
D)88
E)None of these
Rationale: Solution
We have : l = 20 ft and lb = 680 sq. ft. So, b = 34 ft.
∴ Length of fencing = (l + 2b) = (20 + 68) ft = 88 ft. Answer D
Answer: D
Question: An investment yields an interest payment of $234 each month. If the simple annual interest rate is 9%, what is the amount of the investment?
Options:
A)$28,300
B)$30,400
C)$31,300
D)$31,200
E)$35,100
Rationale: Let the principal amount = P
Simple annual interest = 9%
Simple monthly interest = (9/12) = (3/4)%
(3/4)*(P/100) = 234
=>P = (234 *4 * 10^2 )/3
= 78*4*10^2
= 312 * 10^2=31200
Answer D
Answer: D
Question: The organizers of a week-long fair have hired exactly eight security guards to patrol the fairgrounds at night for the duration of the event. Exactly three guards are assigned to patrol the grounds every night, with no guard assigned consecutive nights. If the fair begins on a Monday, how many different groups of 3 guards will be available to patrol the fairgrounds on the following Saturday night?
Options:
A)6
B)8
C)10
D)12
E)14
Rationale: For any given day, only the guards patrolling on the previous day won't be available. So, 3 guards who patrolled on Friday won't be available. We are thus left with 5 guards.
To choose 3 out of 5, we will have 5C3 = 10 different groups.
The answer is C.
Answer: C
Question: What is the sum of all digits for the number 10^25 - 58?
Options:
A)197
B)201
C)205
D)209
E)213
Rationale: 10^25 is a 26-digit number: 1 followed by 25 zeros.
10^25 - 58 is a 25-digit number: 23 9's and 42 at the end.
The sum of the digits is 23*9+4+2=213.
The answer is E.
Answer: E
Question: When positive integer x is divided by positive integer y, the remainder is 9. If x/y = 96.15, what is the value of y?
Options:
A)96
B)60
C)48
D)25
E)12
Rationale: Guys, one more simple funda.
5/2= 2.5
now .5 x2 =1 is the remainder
25/4 = 6.25
now .25x4=1 is the remainder
32/5=6.4
now.4x5 = 2 is the remainder
given x/y = 96.15 and remainder is 9
So .15 X y = 9
hence y= 60
Ans B
Answer: B
Question: If $64 amount to $ 83.20 in 2 years. what will $ 86 amount to in 4 years at the same rate percent per annum?
Options:
A)$127.40
B)$124.70
C)$114.80
D)$137.60
E)$117.40
Rationale: First, Simple interest formula is
S.I=PNR/100 Here P=$64, T=2 years and S.I=$19.20 (i.e 83.20-64)
R=((100x19.20)/(64x2))%=15%
Now P=$86, T=4 years, R=15%
so S.I=86x4x15/100=$137.60
Answer is D
Answer: D
Question: A certain bus driver is paid a regular rate of $15 per hour for any number of hours that does not exceed 40 hours per week. For any overtime hours worked in excess of 40 hours per week, the bus driver is paid a rate that is 75% higher than his regular rate. If last week the bus driver earned $982 in total compensation, how many total hours did he work that week?
Options:
A)56
B)40
C)44
D)48
E)52
Rationale: For 40 hrs = 40*15=600
Excess = 982-600=382
For extra hours =.75(15)=11.25+16=27.25
Number of extra hrs =382/27.25=14
Total hrs =40+14=56
Answer A 56
Answer: A
Question: The volume of a solid is given by the formula V = ab^2.
If a is doubled and b tripled, by what factor does the volume (V) increase?
Options:
A)3
B)6
C)9
D)18
E)12
Rationale: We have,
V = ab^2
After doubling a and tripling b, we have:
V = (2a)*(3b)^2
V = 2a*9b^2
V = 18ab^2
Initially V = ab^2. Now, V = 18ab^2.
Therefore, V increases by a factor of 18.
Answer = D =18
Answer: D
Question: A number is doubled and 5 is added. If the resultant is trebled, it becomes 129. What is that number?
Options:
A)12
B)29
C)27
D)19
E)99
Rationale: Explanation:
Let the number be x.
Therefore,
3(2x + 5) = 129
6x + 15 = 129
6x =114
x = 19
ANSWER:D
Answer: D
Question: A train running at the speed of 60 km/hr crosses a pole in 6 seconds. Find the length of the train?
Options:
A)100 meter
B)170 meter
C)156 meter
D)168 meter
E)154 meter
Rationale: Speed = 60*(5/18) m/sec
= 50/3 m/sec
Length of Train (Distance)
= Speed * Time
(50/3) * 6
= 100 meter
Answer:A
Answer: A
Question: A committee is composed of w women and m men. If 2 women and 2 men are added to the committee, and if one person is selected at random from the enlarged committee, then the probability that a woman is selected can be represented by
Options:
A)w/m
B)w/(w+m)
C)(w+2)/(m+2)
D)(w+2)/(w+m+2)
E)(w+2)/(w+m+4)
Rationale: The number of women is w+2.
The total number of people is w+m+4.
P(a woman is selected) = (w+2) / (w+m+4)
The answer is E.
Answer: E
Question: In a group of 72 students, each student is registered for at least one of three classes – History, Math and English. Twenty-five students are registered for History, twenty-five students are registered for Math, and thirty-four students are registered for English. If only three students are registered for all three classes, how many students are registered for exactly two classes?
Options:
A)13
B)10
C)9
D)8
E)6
Rationale: A U B U C = A + B + C - AB-BC-AC + ABC
72 = 25 + 25+ 34 -AB-BC-AC +3 => AB+BC+AC = 15
Exactly Two classes = AB+BC+AC - 3ABC = 15 -3*3 = 6
Hence E
Answer: E
Question: EASY,INC recently conducted a survey and found that 60,000 of its customers live in rural areas. if the number of it customers who live in urban areas is 200 percents grater than the numbers of customers who live in rural areas, how many of EASY,INC customers live in urban areas ?
Options:
A)200,000
B)180,000
C)360,000
D)480,000
E)540.0
Rationale: Let's say that we have a starting value of X...
100% of X = X
100% MORE than X = X + X = 2X
200% MORE than X = X + 2X = 3X
300% MORE than X = X + 3X = 4X
Etc.
Here, we're told that 60,000 customers live in rural areas and the number who live in urban areas is 200% GREATER than the number who live in rural areas. That means that the number who are in urban areas is 3 times the number in rural areas...
3(60,000) = 180,000
Final Answer:B
Answer: B
Question: Evaluate: |7 - 8(3 - 12)| - |5 - 11| = ?
Options:
A)40
B)50
C)73
D)70
E)80
Rationale: According to order of operations, inner brackets first. Hence
|7 - 8(3 - 12)| - |5 - 11| = |7 - 8*(-9)| - |5 - 11|
According to order of operations, multiplication within absolute value signs (which may be considered as brackets when it comes to order of operations) next. Hence
= |7 + 72| - |5 - 11|
= |79| - |-6|
= 79 - 6 = 73
correct answer C)73
Answer: C
Question: A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 680 sq. feet, how many feet of fencing will be required?
Options:
A)34
B)40
C)68
D)88
E)None
Rationale: EXPLANATION
We have: l = 20 ft and lb = 680 sq. ft.
So, b = 34 ft.
Length of fencing = (l + 2b) = (20 + 68) ft = 88 ft.
Answer D
Answer: D
Question: In a set of three numbers,the difference between the largest and the second largest numbers is added to the smallest number.The average of the largest,second largest and the new number formed exceeds the average of the original three numbers by 16.The largest number exceeds the second largest number by how much ?
Options:
A)5
B)10
C)30
D)15
E)60
Rationale: Let the numbers in increasing order be A<B<C...
since the new number(N) increase the average of new set of numbers by 5 after replacing the smallest number,A,
the new number,N, exceeds the smallest,A, by 3*5=15 orN=15+A..(1)
and what is the new number,N,----C-B (diff in the largest and second largest)+A...(2)...
from (1)(2) C-B=15
Answer:D
Answer: D
Question: Murari and Madan Started a business with investments of Rs. 13000 and Rs. 52000. After 5 months Arun joins with a capital of Rs. 52000. At the end of a year they got a profit of Rs. 14250. Find the share of Arun.
Options:
A)Rs. 3650
B)Rs. 5250
C)Rs. 6750
D)Rs. 2250
E)None of these
Rationale: Explanation:
Rs. 5250
Answer: Option B
Answer: B
Question: The speed of a subway train is represented by the equation z=s^2+2s for all situations where 0≤s≤7, where z is the rate of speed in kilometers per hour and s is the time in seconds from the moment the train starts moving. In kilometers per hour, how much faster is the subway train moving after 7 seconds than it was moving after 5 seconds?
Options:
A)4
B)28
C)15
D)48
E)63
Rationale: Given: z=s^2+2s for 0≤s≤7
z(5) = 5^2 + 2*5 = 35
z(7) = 7^2 + 2*7 = 63
Therefore z(7) - z(3) = 63 - 35 = 28 km/hr
Option B
Answer: B
Question: Two numbers N and 12 have LCM = 42 and GCF = 6. Find N.
Options:
A)35
B)56
C)21
D)87
E)24
Rationale: The product of two integers is equal to the product of their LCM and GCF. Hence.
12* N = 42 * 6
N = 42*6 / 12 = 21 correct answer C
Answer: C
Question: My brother is 4 years elder to me. My father was 28 years of age when my sister was born while my mother was 26 years of age when I was born. If my sister was 4 years of age of when my brother was born, then, what was the age of my father and mother respectively when my brother was born?
Options:
A)32 yrs, 23 yrs
B)32 yrs, 29 yrs
C)32 yrs, 22 yrs
D)35 yrs, 33 yrs
E)none
Rationale: Sol.
Clearly, my brother was born 4 years before I was born and 4 years after my sister was born.
So, father's age when brother was born = (28 + 4) = 32 years.
mother's age when was born = (26 - 4) years = 22 years.
Answer C
Answer: C
Question: A single discount equivalent to the discount series of 20%, 30% and 5% is?
Options:
A)31.9
B)31.7
C)46.8
D)31.5
E)31.1
Rationale: 100*(80/100)*(70/100)*(95/100) = 53.2
100 - 53.2 = 46.8
Answer:C
Answer: C
Question: A 300 meter long train crosses a platform in 39 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform.
Options:
A)310 meter
B)335 meter
C)345 meter
D)350 meter
E)375 meter
Rationale: Explanation:
Speed = Distance/time = 300/18 = 50/3 m/sec
Let the length of the platform be x meters
then
Distance=Speedâˆ—Timex+300=50/3 X 39
=>3(x+300)=1950=>x=350 meters
ANSWER IS D
Answer: D
Question: A train , having a length of 385 meter is running at a speed of 60 kmph. In what time, it will pass a man who is running at 6 kmph in the direction opposite to that of the train
Options:
A)10 sec
B)8 sec
C)6 sec
D)4 sec
E)21 sec
Rationale: Explanation:
Distance = 385 m
Relative speed = 60+6 = 66 kmph (Since both the train and the man are in moving in opposite direction)
= 66×10/36 mps = 110/6 mps
Time = distance/speed = 385/(110/6) = 21 s
Answer: Option E
Answer: E
Question: 3x + y = 21 , and x + 3y = 1. Find the value of 2x + 2y
Options:
A)20
B)18
C)16
D)11
E)5
Rationale: Add these two equations
4x + 4y = 22
Divide by 2 ( to Get 2x + 2y)
Answer will be D. 11
Answer: D
Question: What is the dividend. divisor 17, the quotient is 9 and the remainder is 5?
Options:
A)140
B)143
C)144
D)158
E)160
Rationale: D = d * Q + R
D = 17 * 9 + 5
D = 153 + 5
D = 158
Answer: D
Question: John tossed a fair coin 3 times. What is the probability that the coin landed heads up exactly twice?
Options:
A)0.125
B)0.175
C)0.275
D)0.375
E)0.475
Rationale: The probability is exactly same as the cion landed tail up once. That is 3*(1/2)^3 = 3/8 =0.375.
The answer is, therefore, (D).
Answer: D
Question: A starts business with Rs. 3500 and after 5 months, B joins with A as his partner. After a year, the profit is divided in the ratio 2 : 3. What is B's contribution in the capital?
Options:
A)Rs. 7500
B)Rs. 8000
C)Rs. 8500
D)Rs. 9000
E)Rs. 9500
Rationale: A invests 3500 Rs for 12 months (Why 12 - because profit is given of 1 year) in the ratio of 2.
B invests X Rs for 7 months (Why 7 - because B joins A after 5 months and profit is given of 1 year) in the ratio of 3.
3500*12+X*7 = 2/3.
42000+7X = 2/3.
7X = 3/2*42000.
X = 9000.
ANSWER D
Answer: D
Question: 20 people can write 50 book in 15 days working 8 hour a day.then in how many day 200 can be written by 60 people?
Options:
A)200
B)100
C)50
D)70
E)25
Rationale: work per day epr hour per person= 50/(15*8*20) // eq-1
people= 60; let suppose day=p; per day work for 8 hours
acc. to condition
work per day epr hour per person= 200/(p*8*60) // eq-2
eq-1==eq-2;
p= 100
ANSWER:B
Answer: B
Question: Sandy can do a job in 21 days and Molly can do the same job in 42 days. If they work together, in how many days will they complete the job?
Options:
A)8
B)10
C)12
D)14
E)16
Rationale: Sandy can do 1/21 of the job each day.
Molly can do 1/42 of the job each day.
The combined rate is 1/21 + 1/42 = 1/14 of the job each day.
The job will take 14 days.
The answer is D.
Answer: D
Question: The least number which when increased by 4 each divisible by each one of 22, 32, 36 and 54 is :
Options:
A)427
B)859
C)860
D)4320
E)None of these
Rationale: Solution
Required number = (L.C.M. of 24, 32, 36, 54) - 4 = 864 - 4 = 860. Answer C
Answer: C