divelab/Sys2Bench huggingface dataset:
Question: On the x-y coordinate plane there is a parabola, y=x(8-x). Which of the following points is in the region that is enclosed by this parabola and the x-axis?
I. (2, 4) II. (3, 6) III. (5, 4)
Options:
A)I only
B)II only
C)III only
D)I and II
E)I, II, and III
Rationale: Since co-efficient of x^2 is negative, the parabola will be downward facing. So the parabola and the x axis will enclose some points where the y-values of the parabola are positive.
When x = 2, y = 12 lies on the parabola, so (2, 4) will be enclosed by the parabola and x axis.
When x = 3, y = 15 lies on the parabola, so (3, 6) will be enclosed by the parabola and x axis.
When x = 5, y = 15 lies on the parabola, so (5, 4) will be enclosed by the parabola and x axis.
The answer is E.
Answer: E
Question: The length of a rectangular landscape is 3times its breadth. There is a playground in it whose area is 1600 square mtr & which is 1/3rd of the total landscape. What is the length of the landscape?
Options:
A)90
B)160
C)150
D)120
E)140
Rationale: Sol. x * 3x = 3 * 2500
x = 50
Length = 3* 50= 150
C
Answer: C
Question: What annual instalment will discharge a debt of 4,200 due in 5 years at 10% simple interest?
Options:
A)500 per year
B)600 per year
C)700 per year
D)800 per year
E)None of these
Rationale: Shortcut method :
If borrowed amount be M and it is to be paid in equal instalments, then
M=na+ra/100×Y×n(n−1)/2
where Y = no. of instalments per annum
a = annual instalment
Here, M = 4200, y = 1, r = 10, n = 5, a = ?
4200 = 5a + 10a⁄100 × 5(5 - 1)⁄2
⇒ 4200 = a[5 + 1] ⇒ 6a = 4200
⇒ a = 700
Answer C
Answer: C
Question: The average age of 15 students of a class is 15 years. Out of these, the average age of 5 students is 14 years and that of the other 9 students is 16 years, The age of the 15th student is
Options:
A)11
B)66
C)18
D)16
E)12
Rationale: Explanation:
Age of the 15th student = [15 * 15 - (14 * 5 + 16 * 9)] = (225-214) = 11 years.
Answer: A
Answer: A
Question: If daily wages of a man is double to that of a woman, how many men should work for 20 days to earn Rs.14400? Given that wages for 40 women for 30 days are Rs.21600.
Options:
A)12
B)14
C)16
D)18
E)20
Rationale: Explanation :
Wages of 1 woman for 1 day = 21600/40Ã—30
Wages of 1 man for 1 day = 21600Ã—2/40Ã—30
Wages of 1 man for 20 days = 21600Ã—2Ã—20/40Ã—30
Number of men = 14400/(21600Ã—2Ã—20/40Ã—30)=144/(216Ã—40/40Ã—30)= 20
Answer : Option E
Answer: E
Question: Ram and Hari invest Rs. 18000 and 24000 respectively. If annual profit is Rs.1400 then Ram will get
Options:
A)400
B)800
C)600
D)500
E)300
Rationale: 18000:24000=3:4
then
3*1400/7=600
ANSWER:C
Answer: C
Question: Ram's age and Shyam's age are in the ratio 3 : 4. Seven years ago the ratio of their ages was 2: 3. Find the ratio of their ages five years hence?
Options:
A)26:36
B)22:33
C)26:38
D)26:33
E)26:43
Rationale: Let ages of Ramu and Shyamu be x and y respectively.
x/y = 3/4 => x = 3/4 y
Also (x - 7) / (y - 7) = 2/3
=> 3x - 21 = 2y - 14
3x = 2y + 7
But x = 3/4 y
3 * 3/4 y = 2y + 7
9y = 8y + 28 => y = 28 years
Ratio of their ages five years hence
= (21 + 5) / (28 + 5) = 26/33.
Answer:D
Answer: D
Question: When x is even, [x] = x/2 + 1, when x is odd [x] = 2x + 1 then [6]*[3] = ?
Options:
A)[22]
B)[44]
C)[45]
D)[28]
E)[10]
Rationale: [6]*[3]=(6/2+1)(3*2+1)
=[28].
Ans-D
Answer: D
Question: How many different pairs of numbers (s, t) such that s = 2t can be obtained if s and t are selected from the set of number {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}
Options:
A)1
B)2
C)3
D)4
E)5
Rationale: Given s=2t
t can take 0,1,2,3,4
and so s = 0,3,6,9
5 such pairs can be formed.
answer E
Answer: E
Question: The ratio W , by volume of soap to alcohol to water in a 76 litre solution is 2: 50: 100 . The solution is then altered by adding more soap, alcohol and water.After this alteration the ratio, by volume of soap to water in the solution doubles whereas the ratio, by volume of soap to water remains the same as before. What COULD BE the resulting volume.
Options:
A)79 litres
B)78 litres
C)77 litres
D)152 liters
E)304 litres
Rationale: I guess it should be
the ratio W, by volume ofsoaptowaterin the solutiondoubleswhereas the ratio, by volume ofalocoholtowaterremains thesameas before
2:50: 100 => 1 : 25 : 50. If we add all the parts, we get 76 liters
So we have 1 liters of Soap, 25 liters of Alcohol and 50 liters of Water.
Now as per the Question, Soap : Water doubles but alcohol to water remains the same.
So Soap becomes 2 liters, Alcohol remains 25 liters and Water remains at 50 liters.
Hence 77 liters - Option C)
Answer: C
Question: In a college, the ratio of the number of boys to girls is 8 : 5. If there are 300 girls, the total number of students in the college is
Options:
A)420
B)520
C)620
D)780
E)820
Rationale: Explanation:
Let the boy are 8x and Girls are 5x
=> 5x = 300
=> x = 60
Total students = 8x+5x = 13x = 13(60) = 780
Option D
Answer: D
Question: Linda spent 3/4 of her savings on furniture and the rest on a TV. If the TV cost her $220, what were her original savings?
Options:
A)$900
B)$880
C)$1000
D)$700
E)$1500
Rationale: If Linda spent 3/4 of her savings on furnitute, the rest
4 / 4 - 3 / 4 = 1 / 4 on a TV
But the TV cost her $220. So 1 / 4 of her savings is $220. So her original savings are 4 times $220 = $880
correct answer B
Answer: B
Question: How many positive integers r less than 30 have no common prime factor with 30?
Options:
A)5
B)6
C)7
D)8
E)9
Rationale: r=30=2*3*5. So, the number must be less than 30 and not have primes 2, 3, or 5.
This means that the number could be: 1, 7, 11, 13, 17, 19, 23, or 29. Total of 8 numbers.
Answer: D.
Answer: D
Question: Ayesha’s father was 38 years of age when she was born while her mother was 35 years old when her brother four years younger to her was born. What is the difference between the ages of her parents?
Options:
A)7 years
B)4 years
C)6 years
D)8 years
E)None
Rationale: EXPLANATION
Mother’s age when Ayesha’s brother was born = 35 years.
Father’s age when Ayesha’s brother was born = (38 + 4) years = 42 years.
Required difference = (42 – 35) years = 7 years.
Answer A
Answer: A
Question: What amount does Kiran get if he invests Rs.8000 at 10% p.a. compound interest for six years, compounding done annually?
Options:
A)9688
B)9687
C)9685
D)9682
E)14172
Rationale: A= P{1 + R/100}n
=> 8000{1 + 10/100}6 = Rs.14172
Answer:E
Answer: E
Question: If x > 1 and y < -2, then which of the following must be true ?
Options:
A)x/y > 1
B)x/y < -1
C)x/y < 0
D)x + y > 0
E)xy > 0
Rationale: Pick x=3, y = -3
A) x/y > 1 - Incorrect as x/y = -1
B) x/y < -1 - Incorrect as x/y = -1
C) x/y < 0 -Correct. It will hold for all values x > 2 and y < -2 as x/y = -1 < 0
D) x + y > 0 - Incorrect. x + y = 0
E) xy > 0 - Incorrect. XY = -9 which is less than zero.
B should be the answer.
Answer: B
Question: John takes 12 hours to complete a certain job, while Bill takes only 6 hours to complete the same job. If Steve is faster than John but slower than Bill at completing the same job, then which of the following could be the time it takes the three men together, working at their constant, individual rates, to complete the job?
Options:
A)2 hours, 24 minutes
B)2 hours, 40 minutes
C)3 hours, 20 minutes
D)3 hours, 45 minutes
E)4 hours, 10 minutes
Rationale: The rate of John plus Bill is 1/12 + 1/6 = 1/4 of the job completed per hour.
If Steve worked at the same rate as John, the rate would be 1/4 + 1/12 = 1/3
The slowest possible time would be 3 hours.
If Steve worked at the same rate as Bill, the rate would be 1/4 + 1/6 = 5/12
The fastest possible time would be 12/5 hours = 2 hours, 24 minutes.
The actual time is somewhere between these two extreme points.
The answer is B.
Answer: B
Question: The number 35 is equal to the sum of the cubes of two integers. What is the product of those integers?
Options:
A)6
B)15
C)21
D)27
E)39
Rationale: 2^3 + 3^3 =35 therefore product is 2*3=6
A
Answer: A
Question: If a and b are positive integers such that a/b = 1.69, which of the following must be a divisor of a
Options:
A)10
B)12
C)11
D)13
E)14
Rationale: a/b = 1.69
a/b = 169/100
a = 169/100*b
We require to find from the available 5 options that must be a divisor of a"
This also means which of the following 5 options can divide 169 evenly
(Ignore b as its value unknown; Ignore 100 as in denominator)
Only option D = 13 best fits in
Answer = 13
ANSWER:D
Answer: D
Question: If the cost of 8kg of rice is $15. What would be the cost of 10 kg of rice?
Options:
A)15.4
B)18.75
C)20.25
D)21.56
E)22.0
Rationale: The cost of one kg of rice = 15/8=1.875
The cost of 10kg of rice = 1.875x10= $ 18.75
Answer: B
Answer: B
Question: A pipe can fill a cistern in 33 minutes. Find the time in which 1/11 part of the cistern will be filled?
Options:
A)5min
B)2min
C)3min
D)1min
E)10min
Rationale: Full cistern filled in = 33 minutes
1/11 part filled in = 33*1/11 = 3minutes
Answer is C
Answer: C
Question: A clothing store purchased a pair of pants for $81 and was selling it at a price that equaled the purchase price of the pants plus a markup that was 25 percent of the selling price. After some time a clothing store owner decided to decrease the selling price by 20 percent. What was the clothing store's gross profit on this sale?
Options:
A)$14
B)$5.4
C)$4.4
D)$1.2
E)$5.0
Rationale: Sale Price(SP) = 81 + Markup(MP)
--> Mp = SP-81
and given MP=SP/4 ( 25% is 1/4th)
so SP/4= SP-81
3SP/4= 81
SP=108
Now a discount of 20% is given so NEW SP is .8 *108 =86.4
Profit=86.4-81 =5.4$
Answer is B
Answer: B
Question: The edges of cuboid are 4 cm; 5 cm and 6 cm. Find its surface area?
Options:
A)298
B)148
C)289
D)987
E)282
Rationale: 2(4*5 + 5*6 + 4*6)
= 148
Answer:B
Answer: B
Question: In a cosmetics company , there are 5 engineers out of 20 officers. If 3 officers are picked at random, what is the probability that all are engineers.
Options:
A)3/114
B)1/114
C)1/1140
D)1/1170
E)None of these
Rationale: Explanation :
No. of engineer = 5.
No. of total non-engineer = 15.
Total no. of officers = 20 of which 3 officers are picked.
P(all are engineers) =
=> No. of selection with restriction / No. of selection without restriction
=> 5C3 / 20C3 .
=> 10 / 1140.
=> 1 / 114.
Answer : B
Answer: B
Question: Every year Taylor goes to the same carnival, and he attempts to shoot a basketball into a small hoop, hoping that he will win a ten-foot tall teddy bear. If the probability that Taylor does not make a basket is 8/9, what is the probability that Taylor makes exactly one basket in four tries?
Options:
A)256/729
B)170/730
C)140/730
D)184/730
E)160/743
Rationale: Probability of basket = 1/9
Probability of no basket = 8/9
Required probability= 4* (1*8*8*8/9^4)
=256/729
A is the answer
Answer: A
Question: Two cyclist start from the same places in opposite directions. One is going towards north at 18kmph and the other is going towards south 20kmph. What time will they take to be 152km apart?
Options:
A)1 1/4 hours
B)2 1/3 hours
C)4hours
D)3 3/4 hours
E)6hours
Rationale: To be (18+20) km apart, they take 1 hour
To be 152 km apart, they take 1/38 * 152 = 4 hrs
Answer is C
Answer: C
Question: BY HOW MUCH PERCENT IS FOUR-FIFTH OF 70 LESSER THAN FIVE-SEVENTH OF 112?
Options:
A)24%
B)30%
C)36%
D)42%
E)None of these
Rationale: 4/5*70=56 AND 5/7*112=80
REQUIRED PERCENTAGE-(80-56/80*100)%=(24/80*100)%=30%
CORRECT OPTIONS:B
Answer: B
Question: P, Q and R invested Rs.5500, Rs.9900 and Rs.12100 respectively, in a partnership business. Find the share of Q in profit of Rs.62500 after a year?
Options:
A)22500
B)21500
C)20500
D)19500
E)18500
Rationale: Explanation:
5500:9900:12100
5:9:11
9/25 * 62500 = 22500
A)
Answer: A
Question: Jamboree and GMAT Club Contest Starts
QUESTION #11:
How many words (with or without meaning) can be formed using all the letters of the word “SELFIE” so that the two E’s are not together?
Options:
A) 660
B) 600
C) 500
D) 300
E) 240
Rationale: The question is asking the total number of arrangements possible with the letters of the word “SELFIE” where two E’s are not together.
Arrangements when two E’s are not together = Total arrangements - Arrangements when two E’s are together
In total there are 6 letters but two are identical. so we can arrange in 6! ways. but we divide for those objects that are identical. so divide by 2!. Hence,
Total arrangements = 6!/2!
Now two E's are coupled together. Consider this couple (EE) as one letter. apart from this there are 4 more letters. so we can arrange these 5 different objects in 5! ways.
Two E's can arrange themselves in 2! ways, but we divide for those objects that are identical. so divide by 2!. so arrangement for E's would be 2!/2!.
Hence, Arrangements when two E’s are together = 5! * (2!/2!)
Arrangements when two E’s are not together = 6!/2! - 5! = 5! * ( 6/2 -1 ) = 120 * 2 = 240.
Option D is correct!
Answer: D
Question: Jane bought 300 packets of chocolate. She was able to sell 1/3 of them at a 10% profit, another 1/3 of them at zero profit and the remainder was sold at a 5% loss. Find the total profit or loss made by Jane after selling those 300 packets. A packet sold at a loss had a price of $9.
Please provide an intuitive answer if possible. Thanks!!
Options:
A)0
B)Profit of $20
C)Loss of $25
D)Profit of $50
E)Loss of $35
Rationale: A packet sold at a 10% loss had a price of $9, thus the cost of a packet is $10.
100 packets was sold at a 10% profit --> gives profit of 10*0.1*100 = $100.
100 packets was sold at a 5% loss --> gives loss of 10*0.05*100 = $50.
The overall Profit is $100 - $50 = $50.
Answer: D.
Answer: D
Question: A certain restaurant offers 6 different salads, 4 different main courses, and 6 different desserts. If customers choose one salad, one main course, and two different desserts for their meal, how many different meals are possible?
Options:
A)240
B)280
C)320
D)360
E)400
Rationale: The number of possible choices for desserts is 6C2 = 15
The number of possible meals is 6*4*15 = 360
The answer is D.
Answer: D
Question: When positive integer X is divided by positive integer Y, the remainder is 3. If X/Y = 96.12, what is the value of Y?
Options:
A)96
B)75
C)48
D)25
E)12
Rationale: When positive integer x is divided by positive integer y, the remainder is 3 --> x=qy+3;
x/y=96.12 --> x=96y+0.12y (so q above equals to 96);
0.12y=3 --> y=25.
Answer: D.
Answer: D
Question: 24 men working at 8 hours a day can finish a work in 10 days. Working at the rate of 10 hours a day, the number of men required to finish the same work in 6 days is?
Options:
A)30
B)32
C)34
D)36
E)38
Rationale: Using Using the chain rule,
M1 x T1 = M2 x T2
Therefore, 24 x 8 x 10 = 10 x X x 6
X= 32
Hence, the number of men required to finish the work = 32.
ANSWER:B
Answer: B
Question: A driver would have reduced the time it took to drive from home to the store by 1/3 if the average speed had been increased by 21 miles per hour. What was the actual average speed, in miles per hour, when the driver drove from home to the store?
Options:
A)36
B)42
C)45
D)48
E)51
Rationale: Let R be the original speed and let T be the original time.
Since the distance remains the same (we're just changing the rate and time), any increase in rate or time is met with a decrease in the other term. Decreasing the time by 1/3 would give us:
D = (R)(T) = (2T/3)(x*R)
x = 3/2 since (2T/3)(3R/2) = (R)(T) = D
3R/2 = R + 21
R/2 = 21
R= 42
The answer is B.
Answer: B
Question: Train P crosses a pole in 30 seconds and train Q crosses the same pole in one minute and 15 seconds. The length of train P is three-fourths the length of train Q. What is the ratio of the speed of train P to that of train Q?
Options:
A)15:8
B)15:7
C)15:1
D)15:3
E)15:2
Rationale: Given that train P crosses a pole in 30 seconds and train Q crosses the same pole in one minute and 15 seconds.
Let the length of train P be LP and that of train Q be LQ
given that LP = 3/4 LQ
As the train P and Q crosses the pole in 30 seconds and 75 seconds respectively,
=> Speed of train P = VP = LP/30
Speed of train Q = VQ = LQ/75
LP = 3/4 LQ
=> VP = 3/4 LQ/(30) = LQ/40
Ratio of their speeds = VP : VQ
= LQ/40 : LQ/75 => 1/40 : 1/75 = 15:8
Answer:A
Answer: A
Question: Three interviewers, A, B, and C are interviewing 30 applicants. Only with three interviewers' admission can an applicant be admitted. If interviewer A admitted 10 applicants, B admitted 12 applicants, and C admitted 15 applicants, at least how many applicants get the admission?
Options:
A) 6
B) 2
C) 0
D) 8
E) 12
Rationale: If A admitted 10 are overlapping with B admission of 12 But C does not overlap with anybody.
Then no student will get nod from all the 3.
Hence 0 student will get admission.
Answer : C
Answer: C
Question: How long does a train 110 m long running at the speed of 72 km/hr takes to cross a bridge 112 m length?
Options:
A)82.1 sec
B)12.1 sec
C)16.1 sec
D)11.1 sec
E)12.15sec
Rationale: Speed = 72 * 5/18 = 20 m/sec
Total distance covered = 110 + 112 = 222 m.
Required time = 222/20 = 11.1 sec.
Answer:D
Answer: D
Question: If p^2 – 13p + 40 = x, and p is a positive integer between 1 and 10, inclusive, what is the probability that x < 0?
Options:
A)1/10
B)2/5
C)1/5
D)3/5
E)3/10
Rationale: (p-5)(p-8) = x
p = 6 or 7 for this to be true, so
2/10 = 1/5
Ans :C
Answer: C
Question: One side of a rectangular field is 4 m and its length along diagonal is 5 m. What is the area of the field?
Options:
A)13√8
B)13√2
C)13√4
D)13√2
E)13√1
Rationale: 4a = 48 4a = 20
a = 12 a = 5
a2 = 144 a2 = 25
Combined area = a2 = 169 => a = 13
d = 13√2.Answer: B
Answer: B
Question: A credit card company has a cash back option for their customers which is based on the annual amount that they charge on their credit cards. The customer receives 1.5% cash on their first $5000 of purchase, 2.5% on the next $5000 of purchase and a 3% on cash back on portion that exceeds $10,000. If a customer receives a cash back of 2.2% on their total annual charges made on the credit card, then what was the customer's annual charge?
Options:
A)$12,500
B)$15,000
C)$17,500
D)$20,000
E)$22,500
Rationale: The customer receives $75 for the first $5000.
The customer receives $125 for the next $5000.
Let x be the total amount of the customer's annual charge.
$200 + 0.03(x-10,000)=0.022x
0.008x=100
x=12,500
The answer is A.
Answer: A
Question: The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ Rs. 26.50 per metre is Rs. 4240, what is the length of the plot in metres?
Options:
A)20
B)200
C)50
D)400
E)140
Rationale: Let length of plot = L meters, then breadth = L - 20 meters
and perimeter = 2[L + L - 20] = [4L - 40] meters
[4L - 40] * 26.50 = 4240
[4L - 40] = 4240 / 26.50 = 160
4L = 200
L = 200/4= 50 meters. Answer: C
Answer: C
Question: Positive integer x has z factors; 3x has 3 factors; Which of the following values can z take?
I. 1
II. 2
III. 3
Options:
A)I or II
B)I only holds
C)II only holds
D)II or III
E)I or III
Rationale: Squares have odd number of factors.The square which is a multiple of 3 is 9.
3 has factors 1,3 .
Therefore 2 factors
Answer C
Answer: C
Question: A certain number of men can do a work in 65 days working 6 hours a day. If the number of men are decreased by one-fourth, then for how many hours per day should they work in order to complete the work in 40 days?
Options:
A)17
B)14
C)16
D)13
E)11
Rationale: D
13
Let the number of men initially be x. we have M1 D1 H1= M2 D2 H2
So, x * 65 * 6 = (3x)/4 * 40 * h2
=> h2 = (65 * 6 * 4)/(3 * 40) = 13.
Answer: D
Question: How many positive three-digit integers have an odd digit in both the tens and units place?
Options:
A)25
B)225
C)250
D)450
E)500
Rationale: 1. Make empty spaces and try to fill up the empty spaces one by one
2. If a condition is given, you always find the condition space and fill the condition space first.
Here we need to form a 3 digit number given 2 conditions that the tens and units digit are odd. the digits we can use here are all the digits from 0 to 9 and since nothing is mentioned about the digits being repeated or not, we always consider the with repetition case.
So making 3 empty spaces _ Odd Odd.
The total number of ways of filling the units digit is 5, since we can use any one out of 1,3,5,7 and 9. Similarly the total number of ways of filling the tens digit is 5. Now since the digits can be repeated and we need to have a 3 digit number, we can fill the hundreds digit in 9 ways, since we can use any one out of 1,2,3,4,5,6,7,8,9. We cannot use 0 since we need a 3 digit number.
So the answer here will be 9 * 5 * 5 = 225 ANS:B
Answer: B
Question: In a garden, there are 10 rows and 12 columns of mango trees. The distance between the two trees is 2 metres and a distance of two metres is left from all sides of the boundary of the garden. What is the length of the garden?
Options:
A)22
B)24
C)26
D)28
E)30
Rationale: Between the 12 mango trees, there are 11 gaps and each gap has 2 meter length
Also, 2 meter is left from all sides of the boundary of the garden.
Hence, length of the garden = (11 Ã— 2) + 2 + 2 = 26 meter
Answer is C.
Answer: C
Question: On a map, 4.5 inches represent 45 miles. How many miles approximately is the distance if you measured 254 centimeters assuming that 1-inch is 2.54 centimeters?
Options:
A)1000
B)1100
C)1200
D)1250
E)1300
Rationale: 1 inch = 2.54 cm
4.5 inch = 2.54 * 4.5 cm
11.43 cm = 45 miles
254 cms = 45/11.43*254= 1000 miles
Answer : A
Answer: A
Question: The average age of a class of 32 students is 12 yrs. if the teacher's age is also included, the average increases by one year. Find the age of the teacher
Options:
A)45 Years
B)46 Years
C)49 Years
D)52 Years
E)54 Years
Rationale: Total age of students is 32X12 = 384 Years Total age inclusive of teacher = 33X (12+1) = 429 So, Teacher's age is 429-384= 45 Yrs There is a shortcut for these type of problems Teacher's age is 12+(33X1) = 45 Years Answer : A
Answer: A
Question: In how many ways a committee, consisting of 5 men and 6 women can be formed from 8 men and 10 women?
Options:
A)524
B)1024
C)15247
D)11760
E)11470
Rationale: Required number of ways	= (8C5 x 10C6)
= (8C3 x 10C4)
= 11760.
ANSWER D 11760
Answer: D
Question: Find a sum for first 5 prime no's?
Options:
A)23
B)28
C)26
D)27
E)29
Rationale: Required sum = (2 + 3 + 5 + 7 + 11) = 28.
Note: 1 is not a prime number.
B
Answer: B
Question: A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 37, the how old is B?
A.	7
B.	8
C.	9
D.	10
Explanation:
Options:
A)5
B)7
C)9
D)10
E)14
Rationale: Let C's age be x years. Then, B's age = 2x years. A's age = (2x + 2) years.
(2x + 2) + 2x + x = 37
5x = 35
x = 7.
Hence, B's age = 2x = 14 years.
Answer: Option E
Answer: E
Question: 800 students took the test on English and Maths. 35% students failed in english and 45% failed in maths. 40% of those who passed in maths also passed in english, then how many students failed in both ?
Options:
A)a) 162
B)b) 138
C)c) 16
D)d) 38
E)e) 12
Rationale: Passed in english = 65%
Passed in maths = 55%
Passed in both = 40% of 55% = 2/5 * (55%) = 22%
Passed in (English + Maths - Both + Neither) = 100%
65 + 55 - 22 + Neither = 100
Neither = 100 - 98 = 2% = 0.02 * 800 = 16
Answer: C
Answer: C
Question: A person was asked to state his age in years. His reply was , "Take my age 4 years hence, multiply it by 4 and subtract 4 times my age 4 years ago and you will know how old I am." What was the age of the person ?
Options:
A)18
B)32
C)27
D)26
E)19
Rationale: Explanation:
Let the present age of person be x years.
Then, 4(x + 4) - 4(x - 4 ) = x <=> (4x + 16) - (4x - 16) = x <=> x = 32..
Answer: B
Answer: B
Question: A, B, C subscribe Rs. 50,000 for a business. If A subscribes Rs. 4000 more than B and B Rs. 5000 more than C, out of a total profit of Rs. 39,000, what will be the amount A receives?
Options:
A)14700
B)14500
C)14900
D)16380
E)14000
Rationale: Total amount invested = 50000
Assume that investment of C =x.
Then investment of B =5000+x,
Investment of A =4000+5000+x=9000+x
x+5000+x+9000+x=50000
⇒3x+14000=50000
⇒3x=50000–14000=36000
⇒x=36000/3=12000
Investment of C =x=12000
Investment of B =5000+x=17000
Investment of A =9000+x=21000
Ratio of the investment of A, B and C
=21000:17000:12000
=21:17:12
Share of A = Total profit ×21/50
=39000×21/50=16380
Answer is D
Answer: D