divelab/Sys2Bench huggingface dataset:
Question: How long does a train 110 m long running at the speed of 72 km/hr takes to cross a bridge 136 m length?
Options:
A)82.1 sec.
B)12.3 sec
C)19.1 sec.
D)17.1 sec.
E)42.1 sec.
Rationale: Speed = 72 * 5/18 = 20 m/sec
Total distance covered = 110 + 136 = 246 m.
Required time = 246/20 = 12.3 sec.
Answer: B
Answer: B
Question: The T train leaves station A moving at a constant speed, and passes by stations B and C, in this order. It takes the T train 7 hours to reach station B, and 5 additional hours to reach station C. The distance between stations A and B is m kilometers longer than the distance between stations B and C. What is the distance between stations A and C in terms of m?
Options:
A)1.8m
B)6m
C)7m
D)9m
E)12m
Rationale: The reason it is failing for you is that you chose incorrect numbers. If the question says T it took 7 hrs to reach from A to B and 5 hrs to reach from B to C at a constant speed. It shows that distance AB and BC should be in ratio of 7/5.
If you take such numbers you can solve problem.
AB = 7, BC=5
Therefore
AB-BC = 2
But from question, AB-BC =m
=> m=2
Now total distance = AB+BC= 12
Substitute 12 to get answer in terms of m
Total distance =12 =6m
Ans B
Answer: B
Question: A and B can do a piece of work in 12 days and 16 days respectively. Both work for 3 days and then A goes away. Find how long will B take to complete the remaining work?
Options:
A)10 days
B)17 days
C)147 days
D)9 days
E)1478 days
Rationale: 3/12 + (3 + x)/16 = 1
x = 9 days
Answer: D
Answer: D
Question: A bookshop had science and art books in the ratio of 2:5. By the end of the week, 20% of both type of books were sold and 2240 books were unsold. How many art books were there at the starting?
Options:
A)1000
B)1200
C)1500
D)1600
E)2000
Rationale: science books sold = 2x × 0.2 = 0.4x
science books unsold = 2x – 0.4x = 1.6x
art books sold = 5x × 0.2 = x
art books unsold = 5x – x = 4x
total books unsold = 1.6x + 4x = 5.6x
5.6x = 2240
x = 400
2x science = 800
and 5x art books = 2000
E
Answer: E
Question: The ratio of boys to girls is 6:4.60% of the boys and 40% of girls take lunch in the canteen.What % of class takes lunch?
Options:
A)51%
B)52%
C)53%
D)54%
E)55%
Rationale: let total no of students 100, boy 60 and girl 40, so lunch taken by boy and girl respectively 60* 60/100=36 and 40* 40/100=16
so total 52 students takes lunch out of 100 students..so required % is 52%
ANSWER:B
Answer: B
Question: What is the smallest possible common multiple of three integers, all larger than 24?
Options:
A)27.
B)54.
C)25
D)19,656.
E)21,924.
Rationale: The Least common positive multiple would be for the immediate least number(s) after 24 i.e 25.
Since nowhere is it stated that the three integers must be different, the integers could be 25,25 and 25... leading to least possible positive common multiple to be 25. Answer C.
Answer: C
Question: An athlete runs 200 meters race in 48sec. His speed is?
Options:
A)20km/hr
B)15km/hr
C)30km/hr
D)25km/hr
E)40km/hr
Rationale: speed = 200/48 = 25/6 m/sec
= 25/6 * 18/5 km/hr = 15km/hr
Answer is B
Answer: B
Question: If the perimeter of a rectangular garden is 600 m, its length when its breadth is 100 m is?
Options:
A)338 m
B)778 m
C)200 m
D)276 m
E)971 m
Rationale: 2(l + 100)
= 600 => l
= 200 m
Answer:C
Answer: C
Question: The average of 11 results is 50, if the average of first six results is 49 and that of the last six is 52. Find the sixth result?
Options:
A)58
B)56
C)51
D)52
E)59
Rationale: 1 to 11 = 11 * 50 = 550
1 to 6 = 6 * 49 = 294
6 to 11 = 6 * 52 = 312
6th = 294 + 312 – 550
= 56
Answer: B
Answer: B
Question: In how many different number of ways 6 men and 3 women can sit on a shopa which can accommodate persons?
Options:
A)200
B)230
C)504
D)250
E)260
Rationale: 9p3 = 9 Ã— 8 Ã— 7 = 504
C
Answer: C
Question: A train passes a man standing on the platform. If the train is 210 meters long and its speed is 72 kmph, how much time it took in doing so?
Options:
A)10 ½ sec
B)4 ½ sec
C)9 ½ sec
D)8 ½ sec
E)2 ½ sec
Rationale: D = 210
S = 72 * 5/18 = 20 mps
T = 210/20 = 10 ½ sec
Answer: A
Answer: A
Question: A cricketer scored 134 runs which included 12 boundaries and 2 sixes. What percent of his total score did he make by running between the wickets.
Options:
A)55.22%
B)54.54 %
C)63%
D)70%
E)None of these
Rationale: Explanation :
Number of runs made by running = 134 - (12 x 4 + 2 x 6)
= 134 - (60)
= 74
Now, we need to calculate 72 is what percent of 134.
=> 74/134 * 100 = 55.22 %
Answer : A
Answer: A
Question: Points A, B, and C lie, in that order, on a straight railroad track. The distance from point A to point B is twice the distance from point B to point C. A train traveled from point A to point C without stopping. The train's average speed when traveling from point A to point B was 200 miles per hour and the train's average speed when traveling from point B to point C was 150 miles per hour. What was the train's average speed, in miles per hour, when traveling from point A to point C?
Options:
A)150
B)200
C)180
D)190
E)250
Rationale: Average speed = distance/time
Because we are looking for average speed we can pick a distance for the variable d.
Speed A-B = 200
Speed B-C = 150
Average Speed = total distance/total rate
rate = distance/time
A====================B==========C
If A-B is twice the length of B-C then let A-B = 2d and let B-C = d
Average speed = 3d/(2d/200) + (d/150)
3d/(6d/600) + (4d/600)
3d/(10d/600)
1800d/10d
Average speed = 180
ANSWER: C
Answer: C
Question: 72,90, 80,85,90,105,105,130,130,130
The list consists of the times in seconds that it took each of the 10 school children to run a distance of 400 mts . If the standard deviation of the 10 running times is 22.4, rounded to the nearest tenth of a second, how many of the 10 running times are more than 1 standard deviation below the mean of the 10 running times.
Options:
A)1
B)2
C)3
D)4
E)5
Rationale: How many of the 10 running times are more than one SD below the meanmeans how many data points from given 10 are less thanmean-1SD.
We are given that SD=22.4, so we should find mean --> mean=100 --> there are only 1 data points below 100-22.4=77.6, namely 72 .
Answer: A.
Answer: A
Question: In a 300 m race A beats B by 22.5 m or 6 seconds. B's time over the course is:
Options:
A)80 sec
B)86 sec
C)76 sec
D)49 sec
E)50 sec
Rationale: B runs 300 m in(6*2/45*300)sec=80 sec
ANSWER A
Answer: A
Question: 1+2+2^2+2^3+2^4+2^5+2^6=？
Options:
A)(2^3-1)(2^3+1)
B)2^6+1
C)2^7-1
D)2^5+1
E)2^5-2
Rationale: From 1+2+2^2+2^3+2^4+2^5+2^6=1(2^7-1)/(2-1)=2^7-1, the correct answer is C.
Answer: C
Question: There are two examinations rooms A and B. If 10 students are sent from A to B, then the number of students in each room is the same. If 20 candidates are sent from B to A, then the number of students in A is double the number of students in B. The number of students in room A is?
Options:
A)60
B)70
C)80
D)90
E)100
Rationale: Let the number of students in rooms A and B be x and y respectively.
Then, x - 10 = y + 10 x - y = 20 .... (i)
and x + 20 = 2(y - 20) x - 2y = -60 .... (ii)
Solving (i) and (ii) we get: x = 100 , y = 80.
The required answer A = 100.
E)
Answer: E
Question: Mr. Babu ison tour and he has Rs. 360 for his expenses. If he exceeds his tour by 4 days. he must cut down his daily expenses by Rs. 3.For how many days is Mr. babu on tour?
Options:
A)20
B)30
C)40
D)90
E)20
Rationale: Suppose Mr. babu is on tour for x days . Then, 360/x-360/x+4
=1/x-1/x+4=1/120
x(x+4)=4x120=480
(x+24)(x-20)=0
x=20
ANSWER: A
Answer: A
Question: A train passes a station platform in 36 sec and a man standing on the platform in 20 sec. If the speed of the train is 54 km/hr. What is the length of the platform?
Options:
A)615 m
B)240 m
C)168 m
D)197 m
E)691 m
Rationale: Speed = 54 * 5/18 = 15 m/sec.
Length of the train = 15 * 20 = 300 m.
Let the length of the platform be x m . Then,
(x + 300)/36 = 15 => x
= 240 m
Answer: B
Answer: B
Question: Jonah drove the first half of a 200-mile trip in x hours and the second half in y hours. Which of the following is equal to Jonah’s average speed, in miles per hour, for the entire trip?
Options:
A)100/(x + y)
B)200/(x + y)
C)25/x + 25/y
D)50/x + 50/y
E)100/x + 100/y
Rationale: Time taken by Jonah to cover first half i.e 100 miles of a 200 mile trip = x
time taken by Jonah to cover the second half i.e 100 miles of a 200 mile trip = y
Total time taken by Jonah = x+y
Jonah's average speed for the entire trip =total distance /total time
=200/(x+y)
Answer B
Answer: B
Question: If the length & width of a rectangle is decreased by 50% & then again increase the new length & width by 40%. Calculate the percentage difference between the area of New Rectangle & Original Rectangle.
Options:
A)50%
B)51%
C)52%
D)53%
E)54%
Rationale: let length is l, width is w so area is wl
after decreament l is i/2 ,w is w/2
again inc by 40% so l is 7l/10 ,w is 7w/10 so area is 49wl/100
percentage change is wl-49wl/100=51wl/100
so 51%
ANSWER:B
Answer: B
Question: 40% of a number is more than 20% of 650 by 190. Find the number?
Options:
A)288
B)278
C)800
D)267
E)121
Rationale: (40/100) * X – (20/100) * 650 = 190
2/5 X = 320
X = 800
Answer:C
Answer: C
Question: Sheila works 8 hours per day on Monday, Wednesday and Friday, and 6 hours per day on Tuesday and Thursday. She does not work on Saturday and Sunday. She earns $360 per week. How much does she earn in dollars per hour?
Options:
A)2
B)8
C)9
D)10
E)2
Rationale: Explanation:
Total hours worked = 8 x 3 + 6 x 2 = 36
Total earned = 360. Hourly wage = 360 / 36 = 10
Answer: D
Answer: D
Question: The average monthly income of P and Q is Rs. 5050. The average monthly income of Q and R is Rs. 6250 and the average monthly income of P and R is Rs. 5200. The monthly income of P is:
Options:
A)4000
B)5000
C)6000
D)7000
E)None of these
Rationale: Explanation:
Let P, Q and R represent their respective monthly incomes. Then, we have:
P + Q = (5050 x 2) = 10100 …. (i)
Q + R = (6250 x 2) = 12500 …. (ii)
P + R = (5200 x 2) = 10400 …. (iii)
Adding (i), (ii) and (iii), we get: 2(P + Q + R) = 33000 or P + Q + R = 16500 …. (iv)
Subtracting (ii) from (iv), we get P = 4000.
P’s monthly income = Rs. 4000.
Answer A
Answer: A
Question: A shipment of 8 television sets contains 2 black-and-white sets and 5 color sets. If 2 television sets are to be chosen at random from this shipment, what is the probability that at least 1 of the 2 sets chosen will be a black-and-white set?
Options:
A)1/7
B)1/4
C)9/14
D)11/28
E)13/28
Rationale: I get 9/14, which is not in the answer choices.
the probability of getting at least one b/w TV is 1-(the probability of getting 2 color TVs)
1-C(5,2)/C(8/2)=18/28=9/14
C
Answer: C
Question: Raj invested an amount of Rs.17400 for two years. Find the rate of compound interest that will fetch him an amount of Rs.1783.50 at the end of two years?
Options:
A)9
B)8
C)7
D)5
E)3
Rationale: Let the rate of interest be R% p.a.
17400[1 + R/100]2 = 17400 + 1783.50
[1 + R/100]2 = (17400 + 1783.50)/17400
= 1 + 1025/10000 = 1 + 41/400
= 441/400 = [21/20]2
[1 + R/100] = 21/20
R/100 = 1/20
Therefore R = 5
Answer:D
Answer: D
Question: In a two digit number, the digit in the units place is six times the digit in ten's place and sum of the digits is equal to 7. What is the number?
Options:
A)16
B)28
C)32
D)36
E)38
Rationale: Solution
Let the ten digits be x. Then,units digit=6x
Therefore x + 6x = 7
‹=›7x = 7
‹=›x= 1.
So, ten's digit = 1, unit's digit = 6.
Hence, the required number is 16.
Answer A
Answer: A
Question: The Pinedale bus line travels at an average speed of 60 km/h, and has stops every 5 minutes along its route. Yahya wants to go from his house to the Pinedale Mall, which is 10 stops away. How far away, in kilometers, is Pinedale Mall away from Yahya's house?
Options:
A)20 km
B)30 km
C)40 km
D)50 km
E)60 km
Rationale: Number of stops in an hour: 60/5 = 12
Distance between stops: 60/12 = 5 km
Distance between Yahya's house and Pinedale Mall: 5 x 10 = 50 km
IMO, correct answer is "D."
Answer: D
Question: On a test consisting of 30 questions. No. of wrong answers is 50% less than number of right answers. Each answer was either right or wrong. What is the ratio of right answers to wrong answers?
Options:
A)1 : 3
B)1 : 5
C)2 : 1
D)3 : 1
E)4 : 5
Rationale: Sol. Let the number of wrong answer - x and number of right answer = 30-x x = 50/100 of (30-x) x = 10
Required ratio = 20 : 10 = 2 : 1
C
Answer: C
Question: If each edge of cube increased by 10%, the percentage increase in
Options:
A)21
B)22
C)25
D)19
E)15
Rationale: 100 × (110)/100 × (110)/100 = 121 => 21%
Answer is A.
Answer: A
Question: 12, 14, x, 10
The median of the list of positive integers above is 11. Which of the following could be the average (arithmetic mean) of the list?
Options:
A)3
B)5.5
C)11
D)7
E)7.5
Rationale: GivenThe median of the list of positive integers above is 11
So arranging the numbers from lowest to highest, avg of 2 middle terms needs to be 11
so the sequence will be x 10 12 14
Lets say x = 8, which gives us mean = sum/4 = 11
C is correct
Answer: C
Question: Two cars are 15 kms apart. One is turning at a speed of 50kmph and the other at 40kmph . How much time will it take for the two cars to meet?
Options:
A)12min
B)10min
C)14min
D)15min
E)16min
Rationale: if they are moving in same direction then solution will be
(50-40)*t=15
ans=1.5hours
if they are moving in opposite direction then ans
(50+40)*t=15
ans=1/6 hours=10min
ANSWER:B
Answer: B
Question: When positive integer m is divided by positive integer x, the reminder is 7 and when positive integer n is divided by positive integer y, the reminder is 11. Which of the following W is a possible value for x + y?
I. 18
II. 19
III. 20
Options:
A)I only
B)II only
C)W=III only
D)II and III only
E)None
Rationale: TIP FOR SUCH QUESTIONS:Make Algebraic Equation in the beginning to understand how to proceed further. Then Start thinking the possible values of variables asked about
i.e.When positive integer m is divided by positive integer x, the reminder is 7can be understood as
m = ax +7which means thevalue of x must be greater than 7as the remainder 7 is possible only when the Divisor is bigger than the Remainder 7
i.e. Min Value of x = 8
AND
i.e.When positive integer n is divided by positive integer y, the reminder is 11can be understood as
n = by +11which means thevalue of y must be greater than 11as the remainder 11 is possible only when the Divisor is bigger than the Remainder 11
i.e. Min Value of y = 12
i.e. Minimum Value of x+y = 8+12 = 20
Hence III only can be True
Answer: Option
C
Answer: C
Question: If A : B : C = 2 : 3 : 4, then A⁄B : B⁄C : C⁄A is equal to :
Options:
A)4 : 9 : 16
B)8 : 9 : 12
C)8 : 9 : 16
D)8 : 9 : 24
E)None of these
Rationale: Let A = 2x, B = 3x and C = 4x. Then,
A⁄B = 2x⁄3x = 2⁄3, B⁄C = 3x⁄4x = 3⁄4 and C⁄A = 4x⁄2x = 2⁄1
⇒ A⁄B : B⁄C : C⁄A = 2⁄3 : 3⁄4 : 2⁄1 = 8 : 9 : 24
Answer D
Answer: D
Question: Rob has 8 toy trucks. He gives 3 trucks to his best friend as a gift. How many trucks does Rob have left?
Options:
A)5
B)20
C)2
D)5
E)8
Rationale: A. 5
Answer: A
Question: A car during its journey travels 30 minutes at a speed of 30 kmph, another 30 minutes at a speed of 60 kmph, and 1 hours at a speed of 80 kmph.The average speed of the car is
Options:
A)63.07 kmph
B)64 kmph
C)62.5 kmph
D)64.02 kmph
E)None of these
Rationale: First car travels 30 min at speed of 30 kmph
distance = 30 x 1/2 = 15 m
Then car travels 30 min at a speed of 60 kmph
distance = 30 min at speed of 60 kmph
distance = 60 x 1/2 = 30 m
at last it travels 1 hours at speed of 80 kmph
distance = 80 x 1 = 80 m
Total distance = 15 + 30 + 80 = 125
Total time= 1/2 + 1/2 + 1 = 2
Average speed of the car = 125/2 = 62.5
ANSWER:C
Answer: C
Question: The area of a rectangle is equal to the area of right-angles triangle. What is the length of the rectangle?
I.	The base of the triangle is 40 cm.
II.	The height of the triangle is 50 cm.
Options:
A)I alone sufficient while II alone not sufficient to answer
B)II alone sufficient while I alone not sufficient to answer
C)Either I or II alone sufficient to answer
D)Both I and II are not sufficient to answer
E)Both I and II are necessary to answer
Rationale: EXPLANATION
Given: Area of rectangle = Area of a right-angles triangle.
⇒l x b =1-div-1/2x B x H
II gives, H = 50 cm.I gives, B = 40 cm.
Thus, to find l, we need b also, which is not given.
Given data is not sufficient to give the answer.
answer is (D).
Answer: D
Question: Chirag was conducting an experiment in which the average of 11 observation came to be 90. Average of first five observation was 87, and that of the last five was 84. What was the measure of the 6th observation?
Options:
A)165
B)125
C)145
D)135
E)None of these
Rationale: Explanation :
11 * 90 - 5 * 87 - 5 * 84 = 900 - 435 - 420 = 135.
Answer : D
Answer: D
Question: During the break of a football match, the coach will make 3 substitutions. If the team consists of 16 players among which there are 2 forwards, what is the probability that none of the forwards will be substituted?
Options:
A) 21/55
B) 18/44
C) 3/20
D) 28/44
E) 36/55
Rationale: Required probability = no. of favorable outcome/ total no. of outcomes
out of 16 players any 3 can be selected in 16C3 ways
after removing 2 forwards any 3 players can be selected from the remaining 9 players in 9C3 ways
thus required probability = 9C3/16C3 =3/20
Answer: C
Question: In a primary school, the ratio of the number of girls to boys is 5 : 8. If there are 160 girls, the total number of students in the college is:
Options:
A)100
B)250
C)260
D)300
E)350
Rationale: Let the number of girls and boys be 5x and 8x.
Total number of students = 13x = 13 x 32 = 416.
Answer : D
Answer: D
Question: A box contains seven bulbs out of which 5 are defective. If five bulbs are chosen at random, find the probability that all the five bulbs are defective?
Options:
A)1/12
B)1/21
C)1/19
D)1/13
E)1/16
Rationale: Out of seven, two are good and five are defective. Required probability
= 5C5/7C5
= 1/21
Answer:B
Answer: B
Question: A dealership needs to fill the empty lot with cars. If separated into to 5 rows, 6 rows, or 7 rows, no cars will be left over. What is the least number of cars needed?
Options:
A)103
B)98
C)265
D)33
E)210
Rationale: To solve you need to find the LCM. LCM (5,6,7)=210. Each row would need 210 cars wether there were 5, 6, or 7 rows. Answer E.
Answer: E
Question: X and Y invested in a business. They earned some profit which they divided in the ratio of 1 : 2. If X invested Rs.20,000. the amount invested by Y is
Options:
A)Rs.45,000
B)Rs.40,000
C)Rs.60,000
D)Rs.80,000
E)None
Rationale: Solution
Suppose Y invested Rs.y
Then,	20000 /y = 1 / 2
â€¹=â€º y=(20000Ã—2 / 1).
â€¹=â€º y=40000.
Answer B
Answer: B
Question: A reduction of 20% in the price of oil enables a house wife to obtain 5kgs more for Rs.800, what is the reduced price for kg?
Options:
A)s.42
B)s.46
C)s.40
D)s.41
E)s.32
Rationale: 800*(20/100) = 160 ---- 5
? ---- 1 => Rs.32
Answer: E
Answer: E
Question: If c + xy = c and x is not equal to 0, which of the following must be true?
Options:
A)x=0
B)x+y=0
C)y=0
D)x<0
E)x=c
Rationale: c + xy = c --> xy=0. Since x is not equal to 0, thus y = 0.
Answer: C.
Answer: C
Question: There are 8 people and 3 tables. In how many ways people can occupy the tables?
Options:
A)336
B)840
C)560
D)740
E)800
Rationale: total people = 8
total tables = 3
1st can be occupy in 8ways
2nd can be occupy in 7ways
3rd can be occupy in 6ways
total number of ways = 8*7*6 = 336 ways
correct option is A
Answer: A
Question: A bottle contains a certain solution. In the bottled solution, the ratio of water to soap is 3:4, and the ratio of soap to salt is five times this ratio. The solution is poured into an open container, and after some time, the ratio of water to soap in the open container is halved by water evaporation. At that time, what is the ratio of water to salt in the solution?
Options:
A)9:32
B)9:30
C)32:9
D)19:32
E)18:30
Rationale: Water:soap = 3:4
Soap:Salt=15:20
=> For 15 soap, salt = 20
=> For 4 Soap, salt = (20/15)*4 = 80/15=16/3
So, water:soap:salt = 3:4:16/3= 9:12:16
After open container, water:soap:salt =4.5:12:16
So, water:salt = 4.5:16 = 9:32
ANSWER:A
Answer: A
Question: Convert the 13/54 m/s into kilometers per hour?
Options:
A)1.7
B)1.5
C)0.86
D)1.1
E)1.2
Rationale: 13/54 m/s = 13/54 * 18/5 = 13/15
= 0.86 kmph.
Answer: C
Answer: C
Question: What is the next number of the following sequence
8, 24, 12, 36, 18, 54, (....)
Options:
A)27
B)108
C)68
D)72
E)62
Rationale: The series is
8*3=24
24/2=12
12*3=36
36/2=18
18*3=54
54/2=27
ANSWER:A
Answer: A
Question: The H.C.F. and L.C.M. of two numbers are 13 and 5040 respectively If one of the numbers is 144, find the other number
Options:
A)400
B)256
C)120
D)455
E)None of these
Rationale: Explanation:
Solve this question by using below formula.
Product of 2 numbers = product of their HCF and LCM
144 * x = 13 * 5040
x = (13*5040)/144 = 455
Option D
Answer: D
Question: On a certain transatlantic crossing, 30 percent of a ship's passengers held round-trip tickets and also took their cars aboard the ship. If 60 percent of the passengers with round-trip tickets did not take their cars aboard the ship, what percent of the ship's passengers held round-trip tickets?
Options:
A)33 1/3%
B)75%
C)50%
D)60%
E)66 2/3%
Rationale: On a certain transatlantic crossing, 20 percent of a ship’s passengers held round-trip tickets and also took their cars abroad the ship. If 60 percent of the passengers with round-trip tickets did not take their cars abroad the ship, what percent of the ship’s passengers held round-trip tickets?
Solution: Let total number of passengers be 100
According to Q stem 40% of passengers who had round-trip tics have taken cars - let number of passengers with round trip be X then
40% of X = 30 => X= 75.
Answer B
Answer: B
Question: In how many different number of ways 3 boys and 4 girls can sit on a bench such that girls always sit together.
Options:
A)A)720
B)B)576
C)C)740
D)D)780
E)E)790
Rationale: 576
Option 'B'
Answer: B
Question: Which of the following options is the possible total number of people in a hall given that the number of people is a multiple of both 8 and 22.?
Options:
A)88
B)56
C)64
D)72
E)80
Rationale: the number of people are a multiple of both 8 and 22, so it must be divisible by 8 and 22.
using the elimination method look for a number that is both divisible by 8 and 22,
of all the options only 88 is divisible by 8 and 22.
[ 88/8=11 and 88/22=3]
answer :A
Answer: A
Question: A tank contains 10,000 gallons of a solution that is 5 percent sodium chloride by volume. If 5,500 gallons of water evaporate from the tank, the remaining solution will be approximately what percent sodium chloride?
Options:
A) 1.25%
B) 3.75%
C) 6.25%
D) 6.67%
E) 11.11%
Rationale: The remaining solution will be approximately what percent sodium chloride?means:what percent of the remaining solution is sodium chloride. Now, since the remaining solution is 10,000-5,500=4,500 gallons and sodium chloride is 500 gallons (5% of initial solution of 10,000 gallons) then sodium chloride is 500/4,500*100=~11.11% of the remaining solution of 4,500 gallons.
Answer: E.
Answer: E
Question: When average age of 22 members are 0, how many members greater than 0?
Options:
A)17
B)21
C)22
D)24
E)25
Rationale: Average of 22 numbers = 0.
Sum of 22 numbers (0 x 22) = 0.
It is quite possible that 21 of these numbers may be positive and if their sum is a then 22nd number is (-a)
Answer is 21 (B)
Answer: B
Question: A team has to design a flag. The team has five yellow strips of cloth and six green strips of cloth that they must use as is to make the flag. How many different flags can the team design with the materials at hand?
Options:
A)120
B)144
C)256
D)462
E)600
Rationale: The # of permutations of total 5+6=11 strips where 5 are identical yellow and 6 are identical green is 11!/(5!*6!)=462 (note that they must use all the materials at hand, also I guess that the strips must be either only vertical or only horizontal).
Answer: D.
Answer: D
Question: If the number 52,1n8, where n represents the tens digit, is a multiple of 3, then the value of n could be which of the following?
Options:
A)6
B)5
C)3
D)1
E)0
Rationale: The sum of the digits 5 + 2 + 1 + n + 8 must be a multiple of 3
16 + n must be a multiple of 3
substituting the numbers n must = 5
Answer B
Answer: B