divelab/Sys2Bench huggingface dataset:
Question: Salesperson A's compensation for any week is $360 plus 6 percent of the portion of A's total sales above $2,000 for that week. Salesperson B's compensation for any week is 8 percent of A's total sales for that week. For what amount of total weekly sales would both salepeople earn the same compensation?
Options:
A)$12,000
B)$18,000
C)$15,000
D)$ 4,500
E)$4,000
Rationale: sometime, setting up an equation is an easy way to go with:
360 + 0.06 (x - 2000) = 0.08 x
x = 12000
Ans : A
Answer: A
Question: Panjali walked for 3 days. She walked 18 miles on the first day, walking 3 miles per hour. On the second day she walked for one less hour but she walked one mile per hour, faster than on the first day. On the third day she walked the same number of hours as on the first day, but at the same speed as on the second day. How many miles in total did she walk?
Options:
A)24
B)44
C)58
D)60
E)62
Rationale: Panjali walked 18 miles on the first day, walking 3 miles per hour i.e. total time of walk on Day-1 = 18/3 = 6 Hours
Second day time of walk = 6-1 = 5 hours and Speed = 3+1=4 miles per hour i.e. Distance walked on second day = 5*4 = 20 miles
Third day time of walk = 6 hours and Speed = 4 miles per hour i.e. Distance walked on second day = 6*4 = 24 miles
Total Distance travelled on three days = 18+20+24 = 62
Answer: Option E
Answer: E
Question: A sum fetched a total simple interest of 4016.25 at the rate of 9 %.p.a. in 5 years. What is the sum?
Options:
A)5768
B)8925
C)2345
D)6474
E)8723
Rationale: B
8925
Principal = (100 x 4016.25)/(9 x 5)
= 401625/45
= 8925.
Answer: B
Question: How many liters of water must be evaporated from 50 liters of a 2 percent sugar solution to get a 4 percent sugar solution?
Options:
A)20
B)25
C)30
D)35
E)40
Rationale: Let x be the amount that needs to be evaporated.
0.02(50) = 0.04(50-x)
0.04x = 2 - 1
x = 1/0.04 = 25 liters
The answer is B.
Answer: B
Question: A solution is 90% glycerin. If there are 4 gallons of the solution, how much water, in gallons must be addded to make a 75% glycerin solution
Options:
A)1.8
B)1.4
C)1.2
D)1.0
E)0.8
Rationale: In 4 gallons of the solution there are 0.9∗4=3.80 gallons of glycerin. We want to add ww gallons of water to 4 gallons of solution so that these 3.6 gallons of glycerin to be 75% of new solution: 0.9∗4=0.75(4+w) --> w=0.8
Answer: E.
Answer: E
Question: The time taken by a man to row his boat upstream is twice the time taken by him to row the same distance downstream. If the speed of the boat in still water is 18 kmph, find the speed of the stream?
Options:
A)8 kmph
B)9 kmph
C)7 kmph
D)6 kmph
E)5 kmph
Rationale: The ratio of the times taken is 2:1.
The ratio of the speed of the boat in still water to the speed of the stream = (2+1)/(2-1) = 3/1 = 3:1
Speed of the stream = 18/3 = 6 kmph.
Answer: D
Answer: D
Question: 2 oranges, 3 bananas and 4 apples cost Rs.15 . 3 oranges 2 bananas 1 apple costs Rs 10. what is the cost of 3 oranges, 3 bananas and 3 apples?
Options:
A)15
B)16
C)17
D)18
E)19
Rationale: 2o+3b+4a=15 (1)
3o+2b+1a=10 (2)
add eq (1)&(2),
5o+5b+5a=25
o+b+a=5
3o+3b+3a=15rs
ANSWER:A
Answer: A
Question: The function g(y) is defined for integers y such that if y is even, g(y) = y/2 and if y is odd, g(y) = y + 5. Given that g(g(g(g(g(y))))) = 19, how many possible values for y would satisfy this equation?
Options:
A)1
B)5
C)7
D)8
E)11
Rationale: Let me define terms:
in g(y) = R
y is argument, R is result, g() is function,
in g(g(g(g(g(y))))), g1 is inner most, g5 is outermost for identification.
From definition of function g, we can deduce that:
If Result is even then two possibilities for argument = 1 Even 1 Odd
If Result is odd then one possibility for argument = 1 Even
Since final result = 19 = Odd
Possibilities:
g1:1 Even
g2: 1*(Even,Odd ) =1 Even 1 Odd
g3: 1*(Even,Odd) + 1 Even =2 Even 1 Odd
g4: 2*(Even, Odd) + 1 Even =3 Even 2 Odd
g5: 3*(Even, Odd) + 2 Even =5 Even 3 Odd = Total 8
Ans D it is!
Answer: D
Question: After his first semester in college, Thomas is applying for a scholarship that has a minimum Grade Point Average (GPA) requirement of 3.5. The point values of pertinent college grades are given in the table below. If Thomas took 2 courses, each with an equal weight for GPA calculations, and received two grades of A-, one grade of B+, and one grade of B, what is the lowest grade that Thomas could receive for his fifth class to qualify for the scholarship?
Point Values of Select Grades
Grade: A | A- | B+ | B | B- | C+ | C | C-
Value: 4 | 3.7 | 3.3 | 3 | 2.7 | 2.3 | 2 | 1.7
Options:
A) A
B) B+
C) B
D) B-
E) C+
Rationale: Grade: A | A- | B+ | B | B- | C+ | C | C-
Value: 4 |3.7|3.3|3| 2.7 | 2.3 | 2 | 1.7
7.4 + 3.3 + 3 + x = 3.5 * 5
x = 17.5 - 13.7 = 3.8
Grade A is required to qualify
Answer = B-
D
Answer: D
Question: A train starts full of passengers at the first station it drops 1/3 of the passengers and takes 280 more at the second station it drops one half the new total and takes twelve more. On arriving at the third station it is found to have 242 passengers. Find the no of passengers in the beginning?
Options:
A)292
B)270
C)192
D)144
E)168
Rationale: Let no of passengers in the beginning be X
After first station no passengers=(X-X/3)+280=2X/3 +280
After second station no passengers =1/2(2X/3+280)+12
1/2(2X/3+280)+12=242
2X/3+280=2*230 = 460 - 280 = 180
2X/3=180
X=270. So the answer is option B) 270.
Answer: B
Question: A meeting has to be conducted with 4 managers. Find the number of ways in which the managers be selected from among 7 managers, if 2 managers will not attend the meeting together?
Options:
A)25
B)20
C)35
D)36
E)38
Rationale: we can either choose all 4 people from 5 manager who have no problems or choose 3 from the 5 and 1 from the 2 managers who have a problem sitting together
so 5C4 + (5C3 * 2C1)
this is 5 + 20=25
Answer : A
Answer: A
Question: On taking delivery of a consignment of eggs the market stall owner was furious to find that several were cracked. In fact, on counting them up in order to assess the damage he found that 72 were cracked, which was 12 per cent of the total consignment. How many eggs in total were in the consignment?
Options:
A)500
B)600
C)700
D)800
E)900
Rationale: Sol.
= 72 ÷ 12 × 100
= 600.
Answer :B
Answer: B
Question: The radius of the two circular fields is in the ratio 3: 5 the area of the first field is what percent less than the area of the second?
Options:
A)67%
B)62%
C)24%
D)64%
E)66%
Rationale: r = 3 πr2 = 9
r = 5 πr2 = 25
25 π – 16 π
100 ---- ? => 64%
Answer: D
Answer: D
Question: There is a sequence such that each term is positive integer and each digit of the terms in the sequence has 3 to be ordered, what is the value W of 100th term?
Options:
A)126
B)192
C)232
D)252
E)342
Rationale: (1~99) 19, (100~199)  19, (200~299) 19. The 100th term should be 100-(19+19+19)=43th number. Hence, the correct answer W is 342. The correct answer is E.
Answer: E
Question: Two vessels P and Q contain 62.5% and 87.5% of alcohol respectively. If 2 litres from vessel P is mixed with 4 litres from vessel Q, the ratio of alcohol and water in the resulting mixture is?
Options:
A)19:4
B)19:2
C)19:8
D)19:5
E)19:6
Rationale: Explanation:
Quantity of alcohol in vessel P = 62.5/100 * 2 = 5/4 litres
Quantity of alcohol in vessel Q = 87.5/100 * 4 = 7/2 litres
Quantity of alcohol in the mixture formed = 5/4 + 7/2 = 19/4 = 4.75 litres
As 6 litres of mixture is formed, ratio of alcohol and water in the mixture formed = 4.75 : 1.25 = 19 : 5.
Answer: Option D
Answer: D
Question: Kunal bought a suitcase with 15% discount on the labelled price. He said the suitcase for Rs.2880 with 20% profit on the labelled price. At what price did he buy the suitcase?
Options:
A)Rs.2040
B)Rs.2400
C)Rs.2604
D)Rs.2640
E)None
Rationale: Solution
Let the labelled price be Rs.x. Then, 120% of x = 2880
Therefore	x=(2880×100/120)
= 2400.
C.P = 85% of Rs.2400	= Rs(85/100x2400)
=Rs.2040.
Answer A
Answer: A
Question: The owner of a furniture shop charges his customer 24% more than the cost price. If a customer paid Rs. 8215 for a computer table, then what was the cost price of the computer table?
Options:
A)6727
B)6887
C)6728
D)6625
E)2871
Rationale: :
CP = SP * (100/(100 + profit%))
= 8215(100/124) = Rs. 6625.
Answer: D
Answer: D
Question: How many of the positive factors of 36 are not factors of 72
Options:
A)0
B)3
C)4
D)5
E)1
Rationale: Factors of 36 - 1,2,3,4,6,9,12,18,36,
factors of 72 - 1,2,3,4,6,8,9,12,18,24,36,72,
Comparing both, we have no factors of 36 which are not factors of 72 - 0
Answer(A)
Answer: A
Question: A, B and C rent a pasture. A puts 10 oxen for 7 months, B puts 12 oxen for 5 months and C puts 15 oxen for 3 months for grazing. If the rent of the pasture is Rs. 245, how much must C pay as his share of rent?
Options:
A)45
B)50
C)55
D)63
E)none
Rationale: Sol.
A : B : C = 10 * 7 : 12 * 5 : 15 * 3 = 70 : 60 : 45 = 14 : 12 : 9.
âˆ´ Câ€™s rent = Rs. [245 * 9/35] = Rs. 63.
Answer D
Answer: D
Question: Find the missing figures :
?% of 25 = 20125
Options:
A)8.5
B)6.5
C)8.7
D)7.7
E)4.5
Rationale: (i)	Let x% of 25 = 2.125. Then , (x/100)*25 = 2.125
X = (2.125 * 4) = 8.5
Answer is A.
Answer: A
Question: Simplify: 250 x 250 - 100 x 100
Options:
A)761200
B)761400
C)52500
D)761500
E)None of them
Rationale: (250)^2 - (100)^2 = (250 + 100) (250 - 100) = 350 x 150 = 52500.
Answer is C.
Answer: C
Question: A trader has 70 kg of rice, a part of which he sells at 14% profit and rest at 6% loss. On the whole his loss is 4% . What is the quantity sold at 14% profit and that at 6% loss?
Options:
A)7 and 63 kg
B)10 and 40 kg
C)15 and 35 kg
D)20 and 30 kg
E)40 and 30 kg
Rationale: Alligation Method
I PART II PART
14 (x1) -6 (x2)
\ /
x
/ \
(x2-x) (x-x1)
2 18
1 9
Ratio of quantities sold at 14% profit and 6% loss = 1: 9
Quantity sold at 14% profit = 70/1+9 *1 = 7 kg
Quantity sold at 6% loss = 70/1+9 *9 = 63 kg
ANSWER:A
Answer: A
Question: A person can swim in still water at 4 km/h. If the speed of water 2 km/h, how many hours will the man take to swim back against the current for 6km?
Options:
A)3
B)6
C)9
D)7
E)2
Rationale: M = 4
S = 2
US = 4 - 2 = 2
D = 6
T = 6/2 = 3
Answer:A
Answer: A
Question: The average age of 8 men increases by 2 years when two women are included in place of two men of ages 20 and 24 years. Find the average age of the women?
Options:
A)16
B)20
C)24
D)28
E)30
Rationale: Explanation:
20 + 24 + 8 * 2 = 60/2 = 30
E
Answer: E
Question: P is a prime number. If 6p is between 15 and 95, which of the following J can be a value of 7p + 2?
Options:
A)15
B)J=79
C)121
D)65
E)21
Rationale: [3,5,7,11,13] are prime numbers that fits this equation 15< 6X <95. Afterwards subtract 2 from all the answer n see if it's divisible by 7. Therefore A and E are out. Leaves out with B C D.
B =11
C =17
D = 9
Only 11 is the set of prime numbers that fit between 15 and 95. Therefore 79 is the answer.B
Answer: B
Question: In a lottery there are 100 prizes and 300 blanks. A lottery is drawn at random. What is the probability of getting a prize?
Options:
A)1/2
B)5/400
C)1/5
D)1/3
E)1/4
Rationale: total draws = prizes+blanks= 100+300=400
probability of getting a prize = 100/400 = 1/4
correct option is E
Answer: E
Question: A man buys Rs. 56 shares paying 9% dividend. The man wants to have an interest of 12% on his money. The market value of each share is:
Options:
A)s. 12
B)s. 15
C)s. 18
D)s. 21
E)s. 42
Rationale: Dividend on Rs. 56 = Rs.	9/100	x 56 =Rs.	5.04	.
Rs. 12 is an income on Rs. 100.
Rs.	5.04	is an income on Rs.100/12 x 5.04	= Rs. 42.
Answer: Option E
Answer: E
Question: An analyst will recommend a combination of 3 industrial stocks, 2 transportation stocks, and 2 utility stocks. If the analyst can choose from 5 industrial stocks, 4 transportation stocks, and 4 utility stocks, how many different combinations of 7 stocks are possible?
--
Options:
A)12
B)19
C)360
D)580
E)720
Rationale: 5C3 * 4C2 * 4C2 = 10*6*6 = 360.
Answer: C.
Answer: C
Question: A can run 160 metre in 28 seconds and B in 32 seconds. By what distance A beat B?
Options:
A)38 metre
B)28 metre
C)20 metre
D)15 metre
E)28 metre
Rationale: Clearly, A beats B by 4 seconds
Now find out how much B will run in these 4 seconds
Speed of B = Distance/Time taken by B=160/32=5 m/s
Distance covered by B in 4 seconds = Speed Ã— time =5Ã—4=20 metre
i.e., A beat B by 20 metre
Answer is C
Answer: C
Question: A train running at the speed of 30 km/hr crosses a pole in 6 sec. What is the length of the train?
Options:
A)20 m
B)70 m
C)50 m
D)Cannot be determined
E)None of these
Rationale: Speed = 30 * 5/18 = 25/3 m/sec
Length of the train = speed * time = 25/3 * 6 = 50 m
ANSWER:C
Answer: C
Question: x, y, a, and b are positive integers of Q. When x is divided by y, the remainder is 6. When a is divided by b, the remainder is 9. Which of the following is NOT a possible value for y + b?
Options:
A)24
B)21
C)20
D)17
E)15
Rationale: x, y, a, and b are positive integers of Q. When x is divided by y, the remainder is 6. When a is divided by b, the remainder is 9. Answer: E.
Answer: E
Question: Last week David spent 40 percent of his wages on recreation. This week, his wages are 5 percent less than last weekʼs wages and he spent 50 percent of his wages on recreation. The amount he spends on recreation this week is what percent of the amount he spent on recreation last week
Options:
A)118.75%
B)128.75%
C)116.75%
D)117.75%
E)114.75%
Rationale: Say David's wages last week were $100, so he spent 0.40*100=$40 on recreation;
This week's wages is 0.95*100=$95, so he spends 0.5*95=$47.5 on recreation;
47.5/40=1.1875, hence the amount he spends on recreation this week is 118.75% of the amount he spent on recreation last week: 40*1.1875=47.5
Answer: A
Answer: A
Question: The arithmetic mean of the scores of a group of students in a test was 72. The brightest 20% of them secured a mean score of 80 and the dullest 25% a mean score of 31. The mean score of remaining 55% is?
Options:
A)A)81.40
B)B)81.70
C)C)87.72
D)D)81.10
E)E)81.29
Rationale: Let the required means score be x. Then,
20 * 80 + 25 * 31 + 55 * x = 72 * 100
= 1600 + 775 + 55x = 7200
= 55x = 4825
= x = 565/11 =87.72
Answer:C
Answer: C
Question: A telephone number contains 10 digit, including a 3-digit area code. Bob remembers the area code and the next 5 digits of the number. He also remembers that the remaining digits are not 0, 1, 2, 5, 6, or 7. If Bob tries to find the number by guessing the remaining digits at random, the probability that he will be able to find the correct number in at most 2 attempts is closest to which of the following?
Options:
A)1/2
B)1/4
C)1/8
D)1/16
E)1/32
Rationale: There are 4*4 = 16 possibilities.
Bob has 2 chances so the probability is 2/16 = 1/8.
The answer is C.
Answer: C
Question: In a maths test, students were asked to find 5/16 of a certain number. One of the students by mistake found 5/6th of that number and his answer was 150 more than the correct answer. Find the number.
Options:
A)125
B)288
C)384
D)400
E)500
Rationale: Explanation:
Let the number be x.
5*x/6 = 5*x/16 + 150
25*x/48 = 150
x = 288
ANSWER B
Answer: B
Question: A grocer has a sale of Rs. 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 6500?
Options:
A)Rs. 1991
B)Rs. 2991
C)Rs. 3991
D)Rs. 4991
E)Rs. 5991
Rationale: Explanation:
Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009.
Required sale = Rs. [ (6500 x 6) – 34009 ]
= Rs. (39000 – 34009)
= Rs. 4991.
Answer D
Answer: D
Question: If C.P. of 28 books is equal to S.P of 30 books , then your gain or loss is ?
Options:
A)23 1/3 gain %
B)30 10/23 loss %
C)6.67 loss %
D)30 1/3 loss %
E)40 1/3 loss %
Rationale: Say the cost price of 28 books is $28 so $1 for a book.
The cost of 30 books would be $30, and the selling price of 30 books would be 28$, hence the loss = ($30 - $28)/$30 = ~6.67%.
Answer: C.
Answer: C
Question: Equal weights of two alloys containing tin, copper and lead in the ratio 1:2:3 and 4:5:3 are melted and mixed together. What is the ratio of tin, copper and lead in the resultant alloy?
Options:
A)41:81:37
B)3:9:8
C)1:2:2
D)6:4: 9
E)4:8:9
Rationale: Let the weight of the two alloys be w each
Required ratio =
(1w/6 +4w/12): ( 2w/6 +5w/12 ): (3w/6+3w/12)
= 6w/12 : 4w/12 : 9w/12
= 6:4: 9
ANSWER:D
Answer: D
Question: A 270 m long train running at the speed of 120 km/hr crosses another train running in opposite direction at the speed of 80 km/hr in 9 sec. What is the length of the other train?
Options:
A)230
B)99
C)88
D)65
E)44
Rationale: Relative speed = 120 + 80 = 200 km/hr.
= 200 * 5/18 = 500/9 m/sec.
Let the length of the other train be x m.
Then, (x + 270)/9 = 500/9 => x = 230.
Answer: A
Answer: A
Question: A letter lock consists of three rings each marked with five different letters. The number of distinct unsuccessful attempts to open the lock is at the most?
Options:
A)277
B)269
C)124
D)145
E)123
Rationale: Since each ring consists of five different letters, the total number of attempts possible with the three rings is
= 5*5*5 = 125. Of these attempts, one of them is a successful attempt.
Maximum number of unsuccessful attempts = 125 - 1
= 124.
Answer:C
Answer: C
Question: A man can row 2 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and black. What is the total distance traveled by the man?
Options:
A)1.8
B)1.9
C)1.2
D)1.7
E)1.3
Rationale: M = 2
S = 1.2
DS = 2.4
US = 0.8
x/1.2 + x/0.8 = 1
x = 0.6
D = 0.6 * 2 = 1.2
Answer:C
Answer: C
Question: What is the area of square field whose side of length 10 m?
Options:
A)100
B)662
C)772
D)882
E)21
Rationale: 10 * 10
= 100 sq m
Answer:A
Answer: A
Question: If k is the greatest positive integer such that 3^k is a divisor of 15! then k =
Options:
A)3
B)4
C)5
D)6
E)7
Rationale: For solving this type of tasks we can use such approach
15 / 3 = 5
15 / 3^2 = 1 and remainder
and 3^3 is more than 15 so we stop on second exponent
5 + 1 = 6
so maximum value of k = 6
And answer is D
Answer: D
Question: P is able to do a piece of work in 20 days and Q can do the same work in 10 days. If they can work together for 2 days, what is the fraction of work left?
Options:
A)5/10
B)9/10
C)7/10
D)6/10
E)4/10
Rationale: Explanation :
Amount of work P can do in 1 day = 1/20
Amount of work Q can do in 1 day = 1/10
Amount of work P and Q can do in 1 day = 1/20+ 1/10 = 3/20
Amount of work P and Q can together do in 2 days = 2 × (3/20) =3/10
Fraction of work left = 1 – 3/10= 7/10
Answer : Option C
Answer: C
Question: A retailer sells 6 shirts. The first 2 he sells for $40 and $50. If the retailer wishes to sell the 6 shirts for an overall average price of over $50, what must be the minimum average price of the remaining 4 shirts?
Options:
A)$37.00
B)$40.00
C)$45.50
D)$48.00
E)$52.50
Rationale: First 2 shirts are sold for $40 and $50=$90.
To get average price of $50,total sale should be 6*$50=$300
So remaining 4 shirts to be sold for $300-$90=$210
Answer should be 210/4=$52.50 that is E
Answer: E
Question: Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 6 seconds. What is the length of the fast train ?
Options:
A)33 1/3
B)28 7/9
C)29 7/9
D)30 7/9
E)None of these
Rationale: Explanation:
As Trains are moving in same direction,
So, Relative Speed = 40-20 = 20 kmph
= 20*(5/18) = 50/9 m/sec
Length of Train= Speed * Time
Length=50/9âˆ—6
=300/9
=33 1/3
Option A
Answer: A
Question: If the simple interest on $2000 increase by $40,when the time increase by 4 years. Find the rate percent per annum.
Options:
A)1.2%
B)0.5%
C)0.7%
D)0.9%
E)0.3%
Rationale: Applying the above formula, we have
40=2000*r*4/100
r=40*100/2000*4=0.5%.
Answer is B
Answer: B
Question: Three pipes of same capacity can fill a tank in 8 hours. If there are only two pipes of same capacity, the tank can be filled in?
Options:
A)76 hours
B)12 hours
C)15 hours
D)17 hours
E)16 hours
Rationale: The part of the tank filled by three pipes in one hour
= 1/8
=> The part of the tank filled by two pipes in 1 hour
= 2/3 * 1/8 = 1/12.
The tank can be filled in 12 hours.
Answer:B
Answer: B
Question: A fruit vendor purchased 20 dozens of bananas at Rs. 15 per dozen. But one-fourth of the bananas were rotten and had to be thrown away. He sold two-third of the remaining bananas at Rs. 22.50 per dozen. At what price per dozen should he sell the remaining bananas to make neither a profit nor a loss?
Options:
A)29
B)15
C)27
D)21
E)12
Rationale: CP of 20 dozen of bananas = 15 * 20 = Rs. 300
Number of bananas which are rotten = 1/4 * 20 = 5 dozen.
SP of two-third of remaining bananas = (2/3 * 15) * 22.5 = Rs. 225
SP of remaining 5 dozens of bananas to make no profit and no loss =(300 - 225) = Rs. 75.
SP of 1 dozen bananas = 75/5
= Rs.15.
Answer:B
Answer: B
Question: Score Interval Number of Scores
50-59 2
60-69 10
70-79 16
80-89 20
90-99 18
The table shows a distribution of test scores. Which score interval contains the median of the 66 scores?
Options:
A)a) 60-69
B)b) 70-79
C)c) 80-89
D)d) 90-99
E)e) Cannot determine.
Rationale: 33th person
80-89 C
Answer: C
Question: A certain investment grows at an annual interest rate of 8%, compounded quarterly. Which of the following equations can be solved to find the number of years, x, that it would take for the investment to increase by a factor of 16?
Options:
A)16 = 1.02^(x/4)
B)2 = 1.02^x
C)16 = 1.08^(4x)
D)2 = 1.02^(x/4)
E)1/16 = 1.02^(4x)
Rationale: Now we can take the fourth root of both sides of the equation. (i.e.the equivalent of taking the square root twice) We will only consider the positive root because a negative 2 doesn't make sense here.
161/4 = [(1.02)^(4x)]^(1/4)
2 = (1.02)^x
The correct answer is B."
Answer: B
Question: Anand and Deepak started a business investing Rs. 22,500 and Rs. 35,000 respectively. Out of a total profit of Rs. 16,100, Deepak's share is:?
Options:
A)s.8467
B)s.8428
C)s.8400
D)s.9800
E)s.8420
Rationale: Ratio of their shares
= 22500 : 35000
= 9:14
Deepak's share
= 16100 * 14/23
= Rs.9800.
Answer:D
Answer: D
Question: 12008 - 50 ÷ 10.00 = ?
Options:
A)1195
B)120
C)12000
D)12003
E)None
Rationale: Answer
Given expression = 12008 - 50 ÷ 10.00
= 12008- 5
= 12003
Correct Option: D
Answer: D
Question: How many 9 digit numbers are possible by using the digits 1,2,3,4,5 which are divisible by 4 if the repetition is allowed?
Options:
A)56
B)57
C)55
D)59
E)58
Rationale: _ _ _ _ _ _ _ _ _ (9 digit number)
Digits that can be used = 1, 2, 3, 4 and 5
For a number to divisible by 4, the last two digits have to be divisible by 4
So, the units digit cannot be 1, 3 or 5
If the units digit is 2, only 12, 32 adn 52 are acceptable as the last two digits
If the units digit is 4, only 24 and 44 are acceptable as the last two digits.
So, total 5 cases for the last two digits.
Now, the first 7 digits of the 9 digit number can be filled in 57 ways as each place can be filled by 1, 2, 3, 4 or 5.
So, desired answer = 57*5 = 58
ANSWER:E
Answer: E
Question: On a business trip, 30 percent of 60 sales representatives will be given accommodations at Hotel XYZ and the remaining 70 percent will be given accommodations at Hotel ABC. However, 30 percent of the sales representatives prefer to stay at Hotel XYZ and 70 percent prefer to stay at Hotel ABC. What is the highest possible number of sales representatives NOT given accommodations at the hotel they prefer?
Options:
A)28
B)32
C)36
D)40
E)44
Rationale: 18 people stay in XYZ and 42 people stay in ABC.
18 people prefer XYZ and 42 people prefer ABC.
Let's put all 18 people who prefer XYZ in hotel ABC.
Then 18 people who prefer ABC will stay in XYZ.
The highest possible number who are not given their preference is 18+18=36.
The answer is C.
Answer: C
Question: A no.when divided by 221 gives a remainder 43, what remainder will beobtained by dividing the same number19?
Options:
A)3
B)6
C)9
D)11
E)15
Rationale: 221 + 43 = 264/17 = 9 (Remainder)
C
Answer: C