divelab/Sys2Bench huggingface dataset:
Question: The ratio of money with Ram and Gopal is 7 : 17 and that with Gopal and Krishan is 7: 17. If Ram has Rs. 490, Krishan has ?
Options:
A)Rs. 2890
B)Rs. 2330
C)Rs. 1190
D)Rs. 1620
E)Rs. 2680
Rationale: Ram : Gopal = 7 : 17 = 49 : 119
Gopal : Krishan = 7 : 17 = 119 : 289
Ram : Gopal : Krishan = 49 : 119 : 289
Ram : Krishan = 49 : 289
Thus, 49 : 289 = 490 : N
&there N = 289 x 490 / 49
= Rs. 2890
Answer :A
Answer: A
Question: A starts business with Rs.3500 and after 8 months, B joins with A as his partner. After a year, the profit is divided in the ratio 2 : 3. What is Bâ€™s contribution in the Capital ?
Options:
A)24887
B)20778
C)23788
D)15750
E)2811
Rationale: Explanation:
A invested Rs.3500 for 12 months.
Let B joined with investment x. And he invested for 12 - 8 = 4 months.
So there profit ratio = (3500 Ã— 12) : (4x) = 2 : 3
â‡’ x = 15750
Answer: D
Answer: D
Question: In what time a sum of money double itself at 5% per annum simple interest?
Options:
A)33 1/8%
B)33 1/3%
C)33 7/3%
D)32 1/3%
E)20%
Rationale: P = (P*5*R)/100
R = 20%
Answer: E
Answer: E
Question: The integer E has a tens digit of 6 and a units digit of 7. The units digit of integer y is 8. The product of E and y has a tens digit of 8. Which of the following is a possible tens digit of integer y?
Options:
A)3
B)4
C)5
D)6
E)7
Rationale: Let E be 67 and y be a8. Then the product of E and y can be written as (60+7)*(10a+8)=600a + 480+70a+56=600a+536+70a. Since 600a dose not affect on the tens digit we can ignore 600a.
So tens digit should be the unit of 3+7a. That means 3+7a =8, 18, 28, 38, 48 or 58 (since 3+7a<=3+7*9=66) --->7a=5, 15, 25, 35, 45, 55. So the only possibility is a=5.
So the answer is (C).
Answer: C
Question: If Ram and gohul can do a job in 10 days and 15 days independently, How many days would they take to complete the same job working simultaneously?
Options:
A)10
B)5
C)8
D)6
E)13
Rationale: If total work is X.
Ram working rate=X/10 per day.
Working rate of gohul=X/15 per day.
Rate of work=(X/10)+(X+15)=30X/5X=6 days
The answer is option D
Answer: D
Question: A dishonest dealer professes to sell goods at the cost price but uses a false weight and gains 25%. Find his false weight age?
Options:
A)176
B)289
C)887
D)278
E)179
Rationale: 25 = E/(1000 - E) * 100
1000 - E = 4E
1000 = 5E => E = 200
1000 - 200 = 800
Answer:C
Answer: C
Question: 12, 36, ?, 324, 972
Options:
A)108
B)125
C)215
D)312
E)368
Rationale: Series pattern
Every next element = 3 x previous element
∴ Missing term = 3 x 36 = 108 Answer : A
Answer: A
Question: Two consultants can type up a report in 12.5 hours and edit it in 7.5 hours. If Mary needs 30 hours to type the report and Jim needs 12 hours to edit it alone, how many R hours will it take if Jim types the report and Mary edits it immediately after he is done?
Options:
A)41.4
B)34.1
C)13.4
D)12.4
E)10.8
Rationale: Break down the problem into two pieces: typing and editing.
Mary needs 30 hours to type the report--> Mary's typing rate = 1/30 (rate reciprocal of time)(point 1 in theory below);
Mary and Jim can type up a report in 12.5and --> 1/30+1/x=1/12.5=2/25 (where x is the time needed for Jim to type the report alone)(point 23 in theory below)--> x=150/7;
Jim needs 12 hours to edit the report--> Jim's editing rate = 1/12;
Mary and Jim can edit a report in 7.5and --> 1/y+1/12=1/7.5=2/15 (where y is the time needed for Mary to edit the report alone) --> y=20;
How many R hours will it take if Jim types the report and Mary edits it immediately after he is done--> x+y=150/7+20=~41.4
Answer: A.
Answer: A
Question: A man saves Rs 400 at the end of each year and lends the money at 5% compound interest. How
much will it become at the end of 3 years.
Options:
A)Rs 662
B)Rs 1232.01
C)Rs 1324.05
D)Rs 1662.05
E)None of these
Rationale: Explanation:
=[400(21/20×21/20×21/20)+400(21/20×21/20)+400(21/20)]= 1324.05
Answer: C
Answer: C
Question: Z is a set of positive numbers. The median of Z is greater than the mean of Z. Which of the following W must be true?
I. At least 50% of the numbers in Z are smaller than the median.
II. Less than 50% of the numbers in Z are greater than the median.
III. The median of Z is greater than the average of the largest and smallest numbers in Z.
Options:
A)I only
B)II only
C)III only
D)I and III only
E)W=None of the above
Rationale: Condition 3 can be invalidated by: (1, 3, 4, 5)--median is equal to average of 1 and 5 and average is greater than 3.
Then, don't conditions 1 and 2 have to occur simultaneously? I reasoned this based on the word... maybe that's incorrect.
Even if not, we can rule them both out. So, E.
Answer: E
Question: To apply for the position of photographer at a local magazine, a photographer needs to include three or four photos in an envelope accompanying the application. If the photographer has pre-selected six photos representative of her work, how many choices does she have to provide the photos for the magazine?
Options:
A)35
B)36
C)40
D)42
E)45
Rationale: 6C3 + 6C4 = 20 + 15 = 35
The answer is A.
Answer: A
Question: A can run a kilometer race in 4 1/2 min while B can run same race in 5 min. How many meters start can A give B in a kilometer race, so that the race mat end in a dead heat?
Options:
A)200 m
B)700 m
C)800 m
D)100 metre
E)1300 m
Rationale: Explanation:
A can give B (5 min - 4 1/2 min) = 30 sec start.
The distance covered by B in 5 min = 1000 m.
Distance covered in 30 sec = (1000 * 30)/300 = 100 m.
A can give B 100m start.
Answer:D
Answer: D
Question: John bought 2 shares and sold them for $98 each. If he had a profit of 20% on the sale of one of the shares but a loss of 20% on the sale of the other share, then on the sale of both shares John had
Options:
A) a profit of $10
B) a profit of $8
C) a loss of $4
D) a loss of $10
E) neither a profit nor a loss
Rationale: $ Profit of the share sold at 20% profit =
120-98
20-?
$18 profit on the sale of 1 share.
$ Loss of the share sold at 20% loss=
80-98
20-?
$22 loss on the sale of 1 share.
18-22=Loss of $4
Answer: C
Answer: C
Question: If each participant of a chess tournament plays exactly one game with each of the remaining participants, then 253 games will be played during the tournament. What is the number of participants?
Options:
A)21
B)22
C)23
D)24
E)25
Rationale: Let n be the number of participants.
The number of games is nC2 = n*(n-1) / 2 = 253
n*(n-1) = 506 = 23*22 (trial and error)
The answer is C.
Answer: C
Question: A credit card number has 6 digits (between 1 to 9 inclusive). The first two digits are 12 in that order, the third digit is bigger than 6, the fourth digit is divisible by 2, and the fifth digit is 3 times the sixth. How many different credit card numbers are possible?
Options:
A)18
B)24
C)36
D)48
E)72
Rationale: The first two digits are fixed.
The third digit can be 7, 8, or 9 so there are 3 choices.
The fourth digit can be 2, 4, 6, or 8 so there are 4 choices.
The fifth digit depends entirely on the sixth digit.
The sixth digit can be 1, 2, or 3 so there are 3 choices.
The number of possibilities is 3*4*3 = 36
The answer is C.
Answer: C
Question: 1+ 1+ 1+ 2 × 1^2 + 2 × 1^1+ 2 × 1^4 + 2 × 1^5 + 2 × 1^6 + 2 × 1^7 =
Options:
A) 1^7
B) 1^8
C) 1^14
D) 1^28
E) 3^30
Rationale: We have the sum of 9 terms. Now, if all terms were equal to the largest term 2*1^7 we would have: sum=9*(2*1^7)=2*1^9=~1^10, so the actual sum is less than 1^10 and more than 1^7 (option A) as the last term is already more than that. So the answer is clearly B.
Answer: B.
Answer: B
Question: On a test, students receive 6 points for each correct answer and are penalized by losing 2 points for each incorrect answer. There are 6 questions on the test and each question has 4 answer options, A, B, C, and D. It is known that 5 of the questions have option B as the correct answer and one question has option C as the correct answer. If a student marks B for the first 3 questions and C for the last 3 questions, what is the minimum possible score that student can receive?
Options:
A)-4
B)-1
C)0
D)1
E)4
Rationale: For the minimum possible score, let us take the worst case scenario
Suppose, he gets all of the last 3 qs wrong whose correct answer options are B and one of the first 3 qs wrong whose correct option is C
In that case, he will get only 2 out of the first 3 qs right.
Therefore, minimum possible score=(6*2)-(4*2)=4
Answer E
Answer: E
Question: Tough and Tricky questions: Word Problems.
It takes Sarah 20 minutes to do one oil change, and it takes Alice 12 minutes. If Sarah and Alice both begin doing oil changes at exactly 9:00 a.m. without pausing, when is the first time at which they will finish changing the oil of a car simultaneously?
Options:
A)10:00 a.m.
B)10:42 a.m.
C)12:00 a.m.
D)1:00 p.m.
E)2:00 p.m.
Rationale: LCM of 1220
12 = 2 * 2 * 3
20 = 2 * 2 * 5
LCM = 2 * 2 * 3 * 5 = 60 = 1 hour
1000AM
A
Answer: A
Question: The length of the bridge, which a train 130 m long and traveling at 45 km/hr can cross in 30 sec is?
Options:
A)188
B)166
C)245
D)777
E)765
Rationale: Speed = 45 * 5/18 = 25/2 m/sec.
Time = 30 sec
Let the length of bridge be x meters.
Then, (130 + x)/30 = 25/2
x = 245 m.
Answer: C
Answer: C
Question: A firm has 4 senior partners and 6 junior partners. How many different groups of 3 partners can be formed in which at least one member of the group is a senior partner. (2 groups are considered different if at least one group member is different)
Options:
A)48
B)100
C)120
D)288
E)600
Rationale: Total no of groups of 3 members (including junior and senior) = 10C3
Total no of groups of 3 members (only juniors) = 6C3
Total no of groups of 3 members (at least 1 senior) = 10C3 - 6C3 = 120 - 20 =100
ans:B
Answer: B
Question: Three 6 faced dice are thrown together. The probability that all the three show the same number on them is -
Options:
A)1/216
B)1/36
C)5/9
D)5/12
E)1/4
Rationale: Answer: Option B
It all 3 numbers have to be same basically we want triplets. 111, 222, 333, 444, 555 and 666. Those are six in number. Further the three dice can fall in 6 * 6 * 6 = 216 ways.
Hence the probability is 6/216 = 1/36
Answer: B
Question: 10 solid colored balls in a box, including 1 Green and 1 Yellow. If 3 of the balls in the box are chosen at random, without replacement, what is the probability that the 3 balls chosen will include the Green ball but not the yellow ball.
Options:
A)1/6
B)7/30
C)1/4
D)3/10
E)4/15
Rationale: But we ARE told that there is is only 1 green ball and only 1 yellow ball in the box, becausethere are 10 solid colored balls in a box,including 1 Green and 1 Yellowmeans exactly that. How else?
Would it make ANY sense if there were for example 2 green balls and we were told thatthere are 10 solid colored balls in a box,including 1 Green and 1 Yellow?
Hmm.. yeah, that does make sense. I'm a non-native English speaker so I tend to over-analyze simple things. In this case, since the wordonlywas missing i.e. there are 10 solid colored balls in a box, includingexactly/only1 Green and 1 Yellow . But yeah, in retrospect this is a Quant question not a Verbal SCThanks for the explanation answer is B
Answer: B
Question: Three persons invested Rs.9000 in a joint business. The second person invested Rs.1000 more than the first and the third Rs.1000 more than second. After two years, they gained Rs.5400. How much third person will get?
Options:
A)3526
B)1256
C)2186
D)2286
E)2400
Rationale: Explanation:
First persons investment = x
Second persons investment = x + 1000
Third persons investments = x + 2000
x + x + 1000 + x + 2000 = 9000
3x = 6000
x = 2000
Ratio = 2000 : 3000 : 4000
2:3:4
4/9 * 54000 = 2400
Answer: E
Answer: E
Question: A 1.5 by 2 rectangle is inscribed in circle. What is the circumference of the circle?
Options:
A)2.5π
B)3π
C)3.5π
D)4π
E)5.5π
Rationale: The diagonal of the rectangle will be the diameter of the circle.
and perimeter= 2*pi*r
Ans: A
Answer: A
Question: A man takes 5hr 45min in walking to certain place and riding back. He would have gained 2hrs by riding both ways. The time he would take to walk both ways is?
Options:
A)7 hr 45 min
B)7 hr 15 min
C)6 hr 45 min
D)6 hr 15 min
E)7 hr 10 min
Rationale: Let x be the speed of walked
Let y be the speed of ride
Let D be the distance
Then D/x + D/y = 23/4 hr -------------------(1)
D/y + D/y = 23/4 – 2 hr
D/y = 15/8 ----------------------------------(2)
substitute 2 in 1
D/x + 15/8 = 23/4
D/x = 23/4 -15/8 =46-15/8 =31/8
Time taken for walk one way is 31/8 hr
time taken to walk to and fro is 2*31/8 = 31/4 hr
=7 hr 45 min
Answer : A.
Answer: A
Question: A man covered a certain distance at some speed. If he had moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. What is the distance in km?
Options:
A)36
B)38
C)40
D)42
E)45
Rationale: Explanation:
speed=2v1v2/v1−v2
=2×3×23−2=12 km/H=hr
distance =vt1(1+v/v1)
=12×40/60(1+12/3)=40 km
ANSWER IS C
Answer: C
Question: The purchase price of an article is $48. In order to include 30% of cost for overhead and to provide $12 of net profit, the markup should be
Options:
A)15%
B)25%
C)35%
D)40%
E)55%
Rationale: Cost price of article = 48$
% of overhead cost = 30
Net profit = 12 $
We need to calculate % markup
Net profit as % of cost price = (12/48)*100 = 25%
Total markup should be = 25 + 30 = 55%
Answer E
Answer: E
Question: A particular store purchased a stock of turtleneck sweaters and marked up its cost by 20%. During the New Year season, it further marked up its prices by 25% of the original retail price. In February, the store then offered a discount of 10%. What was its profit on the items sold in February?
Options:
A)27.5%
B)30%
C)35%
D)37.5%
E)40%
Rationale: Assume the total price = 100x
Price after 20% markup = 120x
Price after 25%further markup = 1.25*120x = 150x
Price after the discount = 0.9*150x = 135x
Hence total profit = 35%
Option C
Answer: C
Question: A and B walk around a circular track. A and B walk at a speed of 2 rounds per hour and 3 rounds per hour respectively. If they start at 8 a.m. from the same point in opposite directions, how many times shall they cross each other before 9.30 a.m.?
Options:
A)9.39 am
B)9.80 am
C)9.30 am
D)9.32 am
E)5.30 am
Rationale: Relative speed = Speed of A + Speed of B (∴ they walk in opposite directions)
= 2 + 3 = 5 rounds per hour
=> They cross each other 5 times in 1 hour and 2 times in 1/2 hour
Time duration from 8 am to 9.30 am = 1.5 hour
Hence they cross each other 7 times before 9.30 am
Answer : C
Answer: C
Question: George's drawer has 10 loose black socks, 15 loose blue socks, and 8 loose white socks. If George takes socks out of the drawer at random, how many would he need to take out to be sure that he had at least two matching pairs of socks in two different colors?
Options:
A)3
B)6
C)9
D)15
E)18
Rationale: The worst case scenario is choosing 15 blue socks. Then he would need 3 more socks to be sure of a matching pair of black socks or white socks.
The answer is E.
Answer: E
Question: If q<0, which of the following must be true?
Options:
A)–100 < q < 100
B)q ≤ –1
C)q ≤ 1
D)q^2 ≥ 1/4
E)–100 < q < 0
Rationale: q is a negative number.
A. –100 < q < 100q can be a negative number less than -100
B. q ≤ –1q can be a fraction, in which case it would be greater than -1
C. q ≤ 1must be true since 1 is positive and q is negative
D. q^2 ≥ 1/4not true if m is a negative fraction like -1/5
E. –100 < q < 0q can be a negative number less than -100=C
Answer: C
Question: How many days will there be from 26th January,1996 to 15th May,1996(both days included)?
Options:
A)102
B)103
C)111
D)120
E)121
Rationale: Explanation:
Number of days from 26-Jan-1996 to 15-May-1996 (both days included)
= 6(Jan) + 29(Feb) + 31 (Mar) + 30(Apr)+ 15(May) = 111
Answer: Option C
Answer: C
Question: The greatest possible length which can be used to measure exactly the length 10m, 10m 80cm, 10 m 90 cm is
Options:
A)15 cm
B)25 cm
C)35 cm
D)10 cm
E)43 cm
Rationale: Explanation:
Required Length = H.C.F of 1000 cm, 1080 cm and 1090 c
= 10 cm. Answer: D
Answer: D
Question: In an elaction between two candidates, 10% of votes are were declares invalid. First candidate got 1800 votes which were 60% of the total valid votes . The total number of votes enrolled in that election was?
Options:
A)9000 votes
B)10000 votes
C)11000 votes
D)12000 votes
E)13000 votes
Rationale: 100 % - 10 % = 90 %
54%-36%=18%
18% ------> 1800 ( 18 × 100 = 1800)
100% -------> 10000 votes (100 × 100 = 10000)
B)
Answer: B
Question: Adam borrowed some money at the rate of 6% p.a. for the first two years, at the rate of 9% p.a. for the next three years, and at the rate of 14% p.a. for the period beyond four years. If he pays a total interest of 11,600 at the end of nine years, how much money did he borrow?
Options:
A)10,210
B)12,210
C)14,210
D)16,210
E)16,410
Rationale: Let the sum borrowed be x. Then,
(x×6×21/00)+(x×9×3/100)+(x×14×4/100)= 11600
⇒ (3⁄25x + 27⁄100x + 14⁄25x) = 11400 ⇒ 95⁄100x = 11600
⇒ x = (11600×100/95)= 12210
Hence, sum borrowed = 12,210
Answer B
Answer: B
Question: A fair sided dice labeled 1 to 6 is tossed 2 times. What is the probability the sum of the 2 throws is 5?
Options:
A)1/6
B)7/216
C)4/36
D)9/216
E)11/216
Rationale: The total possible number of combination if the dice is thrown 2 times is 36.
There are 4 possible outcomes that the sum of the number is 5 which is (2+3)(3+2)(1+4) and (4+1)
Answer: C
Answer: C
Question: A car traveled 75% of the way from Town A to Town B at an average speed of 75 mph. The car traveled at an average speed of v mph for the remaining part of the trip. The average speed for the entire trip was 50 mph. What is v in mph?
Options:
A)30
B)35
C)25
D)40
E)45
Rationale: Assume total distance = 100miles
Time taken for 75 miles = 75/75 = 1 hour
Time taken for the rest of the 25 miles = 25/v hours.
Average speed = 50
Therefore the total time needed = 2 hours.
2 = 1 + 25/v
Hence v = 25 mph
Answer : C
Answer: C
Question: A box contains either blue or red flags. The total number of flags in the box is an even number. A group of children are asked to pick up two flags each. If all the flags are used up in the process such that 60% of the children have blue flags, and 45% have red flags, what percentage of children have flags of both the colors?
Options:
A)5%
B)10%
C)15%
D)20%
E)It can not be determined
Rationale: Solution: let the total number of flags be 100(even number)
let the total number of 'blue' flags alone be 'a'
let the total number of 'red' flags alone be 'b'
let the total number of 'both' flags be 'c'
We have given,
total number of blue flags = 60% = 60 = a+c
total number of red flags=45%=45=b+c
total number of flags = a+b+c=100 (since all the flag have been utilized)
So, substituting for c in the third equation, we have,
60-c+c+45-c=100
c=5
Option A.
Answer: A
Question: A plane was originally flying at an altitude of x feet when it ascended 2,000 feet and then descended 5,000 feet. If the plane's altitude after these two changes was 1/5 its original altitude, then the solution of which of the following equations gives the plane's original altitude, in feet ?
Options:
A)x + 2000 = 1/3*(x - 3000)
B)1/3*(x - 3000) = x
C)x + 3000 = 1/3*x
D)x - 7000 = 1/3*x
E)x - 3000 = 1/5*x
Rationale: Plane's original altitude = x
Plane's new altitude after ascending 2000 ft = x+2000
Plane's new altitude after descending 5000 ft from previous altitude = x+2000-5000 = x-3000
So, after two changes plane is at 1/5 its original altitude => x-3000 = x/5
Answer (E)
Answer: E
Question: A train 400 m long can cross an electric pole in 20 sec and then find the speed of the train?
Options:
A)987
B)271
C)72
D)27
E)28
Rationale: Length = Speed * time
Speed = L/T
S = 400/20
S = 20 M/Sec
Speed= 20*18/5 (To convert M/Sec in to Kmph multiply by 18/5)
Speed = 72 Kmph
Answer:C
Answer: C
Question: An inspector rejects 0.08% of the meters as defective. How many will be examine to project ?
Options:
A)1000
B)1500
C)2000
D)2300
E)2500
Rationale: Let the number of meters to be examined be x.
Then, 0.08% of x =2
[(8/100)*(1/100)*x] = 2
x = [(2*100*100)/8] = 2500.
answer E 2500
Answer: E
Question: In a division, divident is 686, divisior is 36 and quotient is 19. Find the remainder.
Options:
A)A)4
B)B)3
C)C)2
D)D)5
E)E)6
Rationale: Explanation:
686 = 36 x 19 + r
686= 684 + r
r = 686 - 684 = 2
Answer: Option C
Answer: C
Question: When x + p is divided by p , the quotient is n and there is no remainder. Which of the following must be the value of x?
Options:
A)p(n - 1)
B)n(p − 1)
C)p(n + 1) + 2n
D)p(n - 1) + 2n
E)n(p + 1) (p − 1)
Rationale: Given in question (x+p)/p= n
=> x+p= np
=>x= np-p
Now we are good to check the options
x= p(n-1)
Answer A
Answer: A
Question: John buys 100 shares of par value Rs. 10 each, of a company, which pays an annual dividend of 12% at such a price that he gets 10% on his investment. Find the market value of a share.
Options:
A)12
B)4
C)5
D)6
E)8
Rationale: Face value of each share = Rs.10
Total dividend received by John = 100Ã—10Ã—12/100 = Rs.120
Let market value of 100 shares = Rs.x
xÃ—10/100=120
x = 1200
ie, Market value of 100 shares = Rs.1200
Hence, Market value of each share = Rs.12
Answer is A
Answer: A
Question: The price of 10 chairs is equal to that of 4 tables. The price of 15 chairs and 2 tables together is Rs. 4000. The total price of 12 chairs and 3 tables is:
Options:
A)Rs. 3500
B)Rs. 3600
C)Rs. 3900
D)Rs. 4000
E)Rs. 4100
Rationale: Let the cost of a chair and that of a table be Rs. x and Rs. y respectively.
Then, 10x = 4y or y = 5 x.
2
15x + 2y = 4000
15x + 2 x 5 x = 4000
2
20x = 4000
x = 200.
So, y = 5 x 200 = 500.
2
Hence, the cost of 12 chairs and 3 tables = 12x + 3y
= Rs. (2400 + 1500)
= Rs. 3900.
C
Answer: C
Question: Two numbers are in the ratio of 2:3 . if 4 is added in both numbers the ratio becomes 5:7. Find the difference between numbers.
Options:
A)8
B)6
C)4
D)2
E)10
Rationale: We're told that two numbers are in the ratio of 2:3. Thus, the two numbers could be...
2 and 3
4 and 6
6 and 9
8 and 12
10 and 15
Etc.
We're told that ADDING 4 to each number changes the ratio of the numbers to 5:7. We're asked for the DIFFERENCE between the original numbers.
Since adding 4 makes the first number a multiple of 5, this limits the possibilities....
2+4 = 6 NOT POSSIBLE
4+4 = 8 NOT POSSIBLE
6+4 = 10 This IS possible...Using this example, we would have...
6 and 9, after adding 4 to each, becomes10 and 13...this is NOT a ratio of 5 to 7 though (even though it's pretty close), so we have to keep looking....
The next value that becomes a multiple of 5 when you add 4 to it is...16...
16 + 4 = 20
With16 and 24, after adding 4 to each, we have20 and 28.This IS a ratio of 5 to 7, so we have our pair of original numbers.
The difference between them is 8.
Final Answer:
A
Answer: A
Question: Calculate the time it will take for a full tank of water to become completely empty due to a leak given that the tank could be filled in 10 hours, but due to the leak in its bottom it takes 11 hours to be filled ?
Options:
A)90 hours
B)80 hours
C)50 hours
D)120 hours
E)110 hours
Rationale: Part filled without leak in 1 hour = 1/10
Part filled with leak in 1 hour = 1/11
Work done by leak in 1 hour
=1/10âˆ’1/11=110 hours
Answer:E
Answer: E
Question: The cost price of an article is Rs. 100. To gain 50% after allowing a 50% discount, the market price of the article is :
Options:
A)Rs. 200
B)Rs. 400
C)Rs. 350
D)Rs. 300
E)Rs. 380
Rationale: discount id always on MP.... so let M.P be x.....
nd S.P is 100 + (50% of 100)= 150
so (50/100)*x = 150
on solving x= 300
ANSWER:D
Answer: D