divelab/Sys2Bench huggingface dataset:
Question: Sum Sam and Product Pete are in class when their teacher gives Sam the Sum of two numbers and Pete the product of the same two numbers (these numbers are greater than or equal to 2). They must figure out the two numbers.
Sam: I don't know what the numbers are Pete.
Pete: I knew you didn't know the numbers... But neither do I.
Sam: In that case, I do know the numbers.1
What are the numbers?
Options:
A)1-2
B)1-3
C)2-4
D)3-4
E)2-3
Rationale: Since Sam knows the sum of the numbers (x + y) he would only know the answer immediately if the sum was 4 (2 + 2) or 5 (3 + 2). Then when Pete (who knows x*y) knew that Sam didn't know the answer the product must have several numbers that add up to the sum (7 = 3 + 4, 7 = 5 + 2). When Pete doesn't know the answer at this point we know the product must have more than one pair of viable factors (12 = 3 * 4, 12 = 6 * 2). At this point Sam knows the numbers are 3 and 4 because they are the only numbers that meet these criteria.
Answer: D
Question: The value of a scooter depreciates in such a way that its value of the end of each year is 3/4 of its value of the beginning of the same year. If the initial value of the scooter is Rs.40,000, what is the value at the end of 6 years ?
Options:
A)3277
B)2977
C)7119
D)6077
E)17112
Rationale: Explanation: 40,000*(3/4)^6
Answer:C
Answer: C
Question: At the end of three years what will be the compound interest at the rate of 10% p.a. on an amount of Rs.15000?
Options:
A)4965
B)1879
C)2779
D)2672
E)2782
Rationale: A = 15000(11/10)^3
= 19965
= 15000
----------
4965
Answer: A
Answer: A
Question: The class mean score on a test was 60, and the standard deviation was 5. If Jack's score was within 2 standard deviations of the mean, what is the lowest score he could have received?
Options:
A)30
B)31
C)45
D)40
E)89
Rationale: 1 SD from the mean is ADDING and Subtrating the amount if standard deviation from the mean one time. 2 SD from the mean is ADDING and Subtracting TWICE.
1SD from the mean ranges from 65 to 55, where 65 is within SD above the mean and 55 within 1SD below the mean
2SD=5 TWICE=10 from the the mean, which is 70 to 40, where 70 is within 2 SD above the mean AND 40 is within 2 SD below the mean.
Answer = D
Answer: D
Question: The music class consists of 4 girls and 6 boys. How many ways can a group of 3 be formed if it has to include at least one boy?
Options:
A)116
B)158
C)161
D)165
E)172
Rationale: Reverse combinatorics approach is preferred method on this one
Note that at least 1 boy gives clue to using this method
All combinations - four girls = answer
All combinations is 10C3 = 120
All girls 4C3 = 4
So our answer is 120-4 = 116
Hence, answer is (A)
Answer: A
Question: A pack of baseball cards consists of 12 outfielder cards and 8 infielder cards. What is the lowest number of outfielder cards that would have to be removed from the pack so that no more than 40 percent of the pack would be outfielder cards?
Options:
A)4
B)5
C)6
D)7
E)8
Rationale: Solution: Let x be the number of outfielder cards remaining of removal.
x <= 0.4(8+x) ===> 0.6x <= 3.2 ==> x <= 5.33
S0, x = 5
So no. of cards to be removed is 12-5 = 7.
Option D
Answer: D
Question: 8500 + (1600 ÷ ?) of 1/5 = 8501
Options:
A)310
B)312
C)320
D)325
E)345
Rationale: Explanation:
=> 8500 + (1600/?) × 1/5 = 8501
=> 1600/? × 1/5 = 8501 - 8500 = 1
=> ? = 1600/5 = 320
Answer: Option C
Answer: C
Question: How many seconds will a train 100 meters long take to cross a bridge 140 meters long if the speed of the train is 36 kmph?
Options:
A)26
B)24
C)25
D)82
E)27
Rationale: Explanation:
D = 100 + 140 = 240
S = 36 * 5/18 = 10 mps
T = 240/10 = 24 sec
Answer: Option B
Answer: B
Question: Find the odd man out
3, 4 , 10 , 32 , 136 , 685 , 4116
Options:
A)32
B)136
C)685
D)4116
E)42
Rationale: Series N*X+X, X starts from 1,2,3..., N=3 for first iteration. New value will become N for the next iteration
3*1+1 = 4
4*2+2 = 10
10*3+3 = 33
33*4+4 = 136
136*5+5 = 685
685*6+6 = 4116
ANSWER:A
Answer: A
Question: Frank is 15 years younger then John. In 4 years John will be twice as old as Frank. How old will Frank be in four years?
Options:
A)8
B)10
C)12
D)15
E)16
Rationale: Frank is 15 years younger then John --> F+15=J;
In 5 years John will be twice as old as Frank (in 4 year John will be J+4 years old and Frank will be F+4 years old) --> J+4=2*(F+4) --> (F+15)+4=2*(F+4) --> F=11;
In 4 years Frank will be 11+4=15 years old.
Answer: D.
Answer: D
Question: Amanda has had 3 pay cuts in her salary in the past 6 months. If the first pay cut was 10%, the second pay cut was 19% and the third was 14%. What will be the percentage decrease, if the salary is decreased in a single shot?
Options:
A)17.31%
B)34.31%
C)37.31%
D)35.31%
E)31.31%
Rationale: Let Rs.100 be initial salary.
Salary After 1st decrease, 10% = 90
Salary After 2nd decrease, 19% = 72.9 i.e. reduced by 19 percent of 90
Salary After 3rd decrease, 14% = 62.694 i.e. reduced by 14 percent of 72.9
So if its decreased in single shot =
i = ( ( b - a ) /b ) * 100
=37.31%
ANSWER:C
Answer: C
Question: Rich has 3 green, 2 red and 3 blue balls in a bag. He randomly picks 5 from the bag without replacement. What is the probability R that of the 5 drawn balls, Rich has picked 1 red, 2 green, and 2 blue balls?
Options:
A)8/28
B)R=9/28
C)10/28
D)10/18
E)11/18
Rationale: (3c2*2c1*3c2)/8c5
=(3*2*3) /(8*7*6/3*2)
=18/56
=9/28
B
Answer: B
Question: Angelo and Isabella are both salespersons. In any given week, Angelo makes $590 in base salary plus 8 percent of the portion of his sales above $1,000 for that week. Isabella makes 10 percent of her total sales for any given week. For what amount of weekly sales would Angelo and Isabella earn the same amount of money?
Options:
A)23,500
B)24,500
C)25,500
D)26,500
E)27,500
Rationale: Let the weekly sales of both = x
590+(x−1000)8/100=10/100x
x = 25500
ANSWER:C
Answer: C
Question: What is the difference between the compound interest on Rs.12000 at 20% p.a. for one year when compounded yearly and half yearly?
Options:
A)Rs.126
B)Rs.120
C)Rs.127
D)Rs.197
E)Rs.122
Rationale: When compounded annually, interest
= 12000[1 + 20/100]1 - 12000 = Rs.2400
When compounded semi-annually, interest
= 12000[1 + 10/100]2 - 12000 = Rs.2520
Required difference = 2520 - 2400 = Rs.120
Answer:B
Answer: B
Question: P runs 25% faster than Q so P gives Q a twenty meter head start. If the race ends in a tie, how far (in meters) did P run in the race?
Options:
A)90
B)100
C)110
D)120
E)130
Rationale: Let D be the race distance that P ran.
Let T be the time it took to complete the race.
Let V be Q's speed.
T = D/1.25V = (D-20) / V
D=1.25D-25
0.25D=25
D=100 meters.
The answer is B.
Answer: B
Question: Two brothers took the GMAT exam, the higher score is X and the lower one is Y. If the difference between the two scores is 1/3, what is the value of Y/X ?
Options:
A)3.
B)2.
C)1/2.
D)1/4
E)There isn't enough data to answer the question.
Rationale: Answer is D : 1/4
X - Y = (X + Y)/3
Solving for Y/X = 1/4
Answer: D
Question: Aruna cut a cake into two halves and cuts one half into smaller pieces of equal size. Each of the small pieces is twenty grams in weight. If she has seven pieces of the cake in all with her, how heavy was the original cake ?
Options:
A)120 grams
B)140 grams
C)240 grams
D)280 grams
E)None of these
Rationale: The seven pieces consist of 6 smaller equal pieces and one half cake piece.
Weight of each small piece = 20 g.
So, total weight of the cake = [2 x (20 x6)]g= 240 g.
ANSWER:C
Answer: C
Question: Mike took 5 mock tests before appearing for the GMAT. In each mock test he scored 10 points more than the previous mock test. If he scored 750 on the GMAT and his average score for the mocks and the GMAT was 726.67, what was the difference in the score of his last mock and his GMAT score?
Options:
A)8
B)30
C)40
D)50
E)60
Rationale: One way to do this would be weighted average method..
1) let the average of 5 mocks be x...
so take it as a mix of5 quantitites of xand1 quantity of 750resulting in an average of 726.67...
By alligation/weighted average..
the difference in 750 and 726.67 is 5/6 of difference of 750 and x..
750-726.67 = 5/6 * (750-x)
750-x= 23.33*6/5=28...
so x = 722..
the last of mock test will be 722+10+10=742...
so ans = 750-742=8
A
Answer: A
Question: Lindsay can paint 1/x of a certain room in one hour. If Lindsay and Joseph, working together at their respective rates, can paint the room in three hours, what fraction of the room can Joseph paint in 20 minutes?
Options:
A)1/3x
B)x/(x-9)
C)(x-3)/9x
D)x/(x-3)
E)(x-3)/x
Rationale: Let J be Joseph's rate per hour.
1/x + J = 1/3 of a room per hour
J = 1/3 - 1/x, of a room per hour
In 20 minutes, Joseph can paint 1/3*(1/3-1/x) = 1/9-1/3x = (x-3)/9x
The answer is C.
Answer: C
Question: A and B walk around a circular track. They start at 8 a.m. from the same point in the opposite directions. A and B walk at a speed of 1 rounds per hour and 1 rounds per hour respectively. How many times shall they cross each other before 9.30 a.m. ?
Options:
A)A)5
B)B)6
C)C)8
D)D)3
E)E)9
Rationale: Relative speed = 1 + 1 = 2 rounds per hour.
So, they cross each other 2 times in an hour and 1 times in half an hour.
Hence, they cross each other 3 times before 9.30 a.m.
ANSWER:D
Answer: D
Question: In a bag there are coins of 50 paisa, 25 paisa and one rupee in the proportion 10:8:2. If there are in all Rs.90, the number of 50 paisa coins is?
Options:
A)120
B)110
C)90
D)80
E)100
Rationale: 10x 8x 2x
50 25 100
500x + 200x + 200x = 4200
900x = 9000
x = 10 => 10x = 100
Answer: E
Answer: E
Question: How much 60% of 50 is greater than 40% of 30?
Options:
A)18
B)13
C)15
D)20
E)25
Rationale: Explanation:
(60/100) * 50 â€“ (40/100) * 30
30 - 12 = 18
Answer is A
Answer: A
Question: A coin has two sides. One side has the number 1 on it and the other side has the number 2 on it. If the coin is flipped four times what is the probability that the sum of the numbers on the landing side of the coin will be greater than 6?
Options:
A)3/8
B)1/16
C)5/8
D)3/4
E)5/16
Rationale: There are 16 possible outcomes.
One outcome (2222) has a sum equal to 8.
Four outcomes (1222, 2122, 2212, 2221) have a sum equal to 7.
P(the sum is greater than 6) = 5/16
The answer is E.
Answer: E
Question: Each child has 4 crayons and 14 apples. If there are 9 children, how many crayons are there in total?
Options:
A)22
B)65
C)12
D)36
E)10
Rationale: 4*9=36.Answer is D.
Answer: D
Question: A taxi charges w dollars for the first two miles and c cents per quarter mile for every mile after the first two. Which equation describes cost of a taxi ride of n miles in dollars.
Options:
A)wn – c/8(100)
B)cw + 4n-8/200
C)w + (4cn-8c)/100
D)w + 100cn/4
E)4cw(n-2) – 100
Rationale: This is about as complicated as these types of problems come, but it is essentially the same as any problem which has an initial cost which is added to a dependent additional cost. Looking at the problem, we notice that the cost w is added to the mile dependent cost, which is some combination of the other terms listed in the problem. With just that knowledge we can eliminate all but two of the answer choices! Choices (A), (B), and (E) either do some strange calculation with the initial cost w, or subtract the additional cost from w. Both of these circumstances would be next to impossible if there is an initial cost being added to another cost. Thus, we only have to choose between choice (C) and choice (D). We can easily find the right answer by plugging in real numbers and checking which choice yields a correct answer. We can also see that answer choice (D) seems to be multiplying the cost in cents by 100, which, if the trip was 6 miles and the charge per mile was 25 cents, would make the taxi cost an additional $3750! This seems impossible, and leaves only the correct answer choice, (C).
Answer: C
Question: A starts business with Rs. 3500 and after 5 months, B joins with A as his partner. After a year, the profit is divided in the ratio 2 : 3. What is B's contribution in the capital?
Options:
A)Rs. 7500
B)Rs. 8000
C)Rs. 8500
D)Rs. 9000
E)None of these
Rationale: Explanation:
Let B's capital be Rs. x.
Then,(3500x 12 / 7 )=2/3
14x = 126000
x = 9000.
Answer is D
Answer: D
Question: A train running at a speed of 36 kmph crosses an electric pole in 12 seconds. In how much time will it cross a 330 m long platform?
Options:
A)37 min
B)55 min
C)47 min
D)67 min
E)45 min
Rationale: E
45 min
Let the length of the train be x m.
When a train crosses an electric pole, the distance covered is its own length.
So, x = 12 * 36 * 5 /18 m = 120 m.
Time taken to cross the platform = (120 +330)/ 36 * 5/18 = 45 min.
Answer: E
Question: Find the fourth proportion to 5,10,15
Options:
A)10
B)20
C)42
D)36
E)30
Rationale: Explanation:
5:10 :: 15:x
=> 5/10= 15/x
=> x = 15*10/5
=> x = 30
Answer:E
Answer: E
Question: In a carton containing a dozen mirrors is dropped, which of the following cannot be the ratio of broken mirrors to unbroken mirrors?
Options:
A)2 : 1
B)3 : 1
C)3 : 2
D)7 : 5
E)None
Rationale: Sol.
For dividing 12 into two whole numbers, the sum of the ratio terms must be a factor of 12. So, they cannot be in the ratio 3 : 2.
Answer C
Answer: C
Question: 7, 26, 63, 124, 215, 342, (....)
Options:
A)481
B)511
C)421
D)391
E)515
Rationale: The series is (23 - 1), (33 - 1), (43 - 1), (53 - 1), (63 - 1), (73 - 1), ...
Hence, next number is (83 - 1) = 511
Answer is B
Answer: B
Question: For any positive integer n, the sum of the first n positive integers equals n(n+1)/2. What is the sum x of all the even integers between 99 and 301?
Options:
A)10,100
B)20,200
C)22,650
D)40,200
E)45,150
Rationale: I would solve it in a different way.
First of all, total number of even integers between 99 and 301 are, (301-99)/2 = 202/2=101
Average = (301+99)/2 = 400/2 = 200
Sum x= Average*total count = 200*101 = 20,200
Answer is B
Answer: B
Question: A boat covers a certain distance downstream in 1 hour, while it comes back in 11⁄2 hours. If the speed of the stream be 3 kmph, what is the speed of the boat in still water?
Options:
A)14 kmph
B)15 kmph
C)13 kmph
D)12 kmph
E)None of these
Rationale: Explanation :
Let the speed of the water in still water = x
Given that speed of the stream = 3 kmph
Speed downstream = (x+3) kmph
Speed upstream = (x-3) kmph
He travels a certain distance downstream in 1 hour and come back in 11⁄2 hour.
ie, distance travelled downstream in 1 hour = distance travelled upstream in 11⁄2 hour
since distance = speed × time, we have
(x+3) × 1 = (x−3)(3/2)
=> 2(x + 3) = 3(x-3)
=> 2x + 6 = 3x - 9
=> x = 6+9 = 15 kmph. Answer : Option B
Answer: B
Question: Find the area of the quadrilateral of one of its diagonals is 20 cm and its off sets 9 cm and 6 cm?
Options:
A)128
B)150
C)887
D)279
E)771
Rationale: 1/2 * 20(9 + 6) = 150 cm2
Answer: B
Answer: B
Question: In a division sum, the divisor is ten times the quotient and five times the remainder. If the remainder is 100, the dividend is:
Options:
A)A)5322
B)B)5330
C)C)25100
D)D)53400
E)E)53420
Rationale: Divisor = (5 * 100) = 500
= 10 * Quotient = Divisor
=> Quotient = 500/10 = 50
Dividend = (Divisor * Quotient) + Remainder
Dividend = (500 * 50) + 100 = 25100.
C
Answer: C
Question: The length of the bridge, which a train 140 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
Options:
A)235
B)240
C)245
D)250
E)260
Rationale: Speed = [45 X 5/18] m/sec = [25/2] m/sec Time = 30 sec Let the length of bridge be x metres. Then, (140 + x)/30 = 25/2 => 2(140 + x) = 750 => x = 235 m.
Answer: Option A
Answer: A
Question: The ages of 2 persons differ by 35 years. If 10 years ago the elder one be 6 times as old as the younger one, find the present age of elder person.
Options:
A)30
B)48.5
C)52
D)50
E)55
Rationale: age of the younger person = x
age of the elder person = x+35
6(x-10) = x+35-10
x= 15
age of elder person = 15+35=50
Answer is D
Answer: D
Question: A painting crew painted 80 houses. They painted the first y houses at a rate of x houses per week. Then more painters arrived and everyone worked together to paint the remaining houses at a rate of 6.25x houses per week. How many weeks did it take to paint all 80 houses, in terms of x and y?
Options:
A)(320 - y)/(5x)
B)(y +190)/(5x)
C)5(80 - y)/(4x)
D)(y + 400)/(4x)
E)(4y + 320)/(5x)
Rationale: Ans B
Plug some numbers
Let y = 40 houses and x = 20
then they painted 20 houses per week
as painters were added to the group , the rate of the group increased to 6.25 x => 6.25 * 20 = 125 houses per week
total time they took = (40/20) + (40/125) = 2.3 weeks
Putting the values of x and y in equation B
(y +190)/(5x) = (40+190)/5*20 = 230/100 = 2.3
Answer: B
Question: What is the next number of the following sequence
2, 12, 4, 24, 8, 48, (...)
Options:
A)10
B)12
C)16
D)20
E)22
Rationale: The series is
2*6=12
12/3=4
4*6=24
24/3=8
8*6=48
48/3=16
ANSWER: C
Answer: C
Question: A committee has 5 men and 6 women. What are the number of ways of selecting 2 men and 3 women from the given committee?
Options:
A)188
B)200
C)277
D)266
E)121
Rationale: The number of ways to select two men and three women = ⁵C₂ * ⁶C₃
= (5 *4 )/(2 * 1) * (6 * 5 * 4)/(3 * 2)
= 200
Answer: B
Answer: B
Question: 15% of 75 is the same as vx% of 450.find x.
Options:
A)1
B)2.5
C)3
D)4
E)5
Rationale: 15%of 75=11.25
450*x/100=11.25
x=2.5
ANSWER:B
Answer: B
Question: In a set of numbers from 100 to 1000 inclusive, how many integers are odd and do not contain the digit 9?
Options:
A)180
B)196
C)288
D)286
E)324
Rationale: We have to find the total number of 3-digit odd numbers not having 9 as a digit.
Units digits will be among 1,3,7,5
Tenth digits will be among 0,1,2,3,4,6,7,8,5
Hundredth digits will be among 1,2,3,4,6,7,8,5
So total numbers = 4*9*8 =288
Answer : C
Answer: C
Question: Can you deduce the pattern and find the next number in the series?
13, 24, 35, 46, __?
Options:
A)59
B)65
C)54
D)25
E)57
Rationale: Solution:
57
Explanation:
11+2=13
22+2=24
33+2=35
44=2=46
55+2=57
Answer E
Answer: E
Question: What is the perimeter of a triangle with sides 7 and 5 that has the maximum possible area?
Options:
A)12 + √7
B)12 + 4√7
C)12 + √47
D)12 + 4√47
E)12 + √74
Rationale: We can maximize the area of the triangle by making these two sides the base and the height of a right angle triangle. Then the third side is the hypotenuse with a length of √(49+25) = √74
The perimeter is 12 + √74
The answer is E.
Answer: E
Question: A cistern is filled by a tap in 8 1/2 hours. Due to leak in the bottom of the cistern, it takes half an hour longer to fill the cistern. If the cistern is full how many hours will it take the leak to empty it?
Options:
A)133
B)143
C)153
D)163
E)173
Rationale: filling rate - leak rate = net rate
1/8.5 - leak rate = 1/9
leak rate = 2/17 - 1/9 = 1/153
The answer is C.
Answer: C
Question: If x + y = 11 and x – y = 3, then x^2 - y^2 =
Options:
A)-4
B)4
C)10
D)33
E)40
Rationale: The fastest approach has already been shown. Here's one more option.
Given:
x + y = 11
x – y = 3
Add the two equations to get: 2x = 14, which means x = 7
If x = 7, we can plug that value into either equation, to conclude that y = 4
If x = 7 and y = 4, then x² - y² = 33
Answer: D
Answer: D
Question: During a particular baseball game, the probability of a team's pitcher throwing a strike on each throw is 2/5. What is the least number of times that the pitcher should pitch the ball that will increase the probability of getting a strike at least once to more than 50%.
Options:
A)3
B)2
C)1
D)4
E)5
Rationale: Rule of Subtraction: P(A) = 1 - P(A')
Rule of Multiplication: P(A ∩ B) = P(A) P(B)
The probability that the pitcher throws a strike at least once in 2 guesses is 1- (3/5)^2 = 1 - 9/25 = 16/25 > 50%.
Answer: B
Answer: B
Question: In a box of 12 pens, a total of 6 are defective. If a customer buys 2 pens selected at random from the box, what is the probability that neither pen will be defective?
Options:
A)1/6
B)5/22
C)6/11
D)9/16
E)3/4
Rationale: Method- 1
There are 9 fine pieces of pen and 6 defective in a lot of 12 pens
i.e. Probability of first pen NOT being defective = (6/12)
i.e. Probability of Second pen NOT being defective = (5/11) [11 pen remaining with 5 defective remaining considering that first was defective]
Probability of Both pen being NON-defective = (6/12)*(5/11) = 5/22
Answer: option B
Answer: B
Question: A train 125 m long passes a man, running at 15 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is?
Options:
A)60
B)50
C)28
D)26
E)29
Rationale: Speed of the train relative to man = (125/10) m/sec = (25/2) m/sec. [(25/2) * (18/5)] km/hr = 45 km/hr. Let the speed of the train be x km/hr. Then, relative speed = (x - 15) km/hr. x - 15 = 45 ==> x = 60 km/hr
Answer: A
Answer: A
Question: What is the probability of rolling two normal six-sided dice and getting exactly one six?
Options:
A)1/36
B)1/6
C)5/18
D)11/36
E)1/3
Rationale: Possible pairs having exactly one six are (1,6), (2,6),(3,6),(4,6),(5,6),(6,1)...(6,5) = 10 pairs
Total number of possible pairs = 6*6 = 36
Therefore, probability of getting exactly one six = 1036=5181036=518
Answer: C
Answer: C
Question: A man walking at the rate of 5 km/hr crosses a bridge in 15 minutes. What is the length of the bridge (in metres)?
Options:
A)1250
B)1280
C)1320
D)1340
E)1450
Rationale: Explanation:
Speed = 5 km/hr
Time = 15 minutes = 1/4 hour
Length of the bridge = Distance Travelled by the man = Speed × Time = 5×1/4 km
= 5 × 1/4 × 1000 metre=1250 metre
Answer: Option A
Answer: A
Question: How many positive integers, from 2 to 100, inclusive, are not divisible by even integers greater than 1?
Options:
A)5
B)6
C)8
D)10
E)50
Rationale: The no will be of the form 2^n to achieve this. Since any other form will have odd no in the prime factorization.
Hence we need to find solution of n for equation - 1< 2^n < 101.
2^6 = 64, 2^7 - 128
Hence n can take values from 1 to 6.
Hence Ans- (B) 6
Answer: B
Question: How long does a train 110 m long running at the speed of 72 km/hr takes to cross a bridge 132 m length?
Options:
A)12.9 sec
B)12.1 sec
C)17.9 sec
D)37.9 sec
E)12.8 sec
Rationale: Speed = 72 * 5/18 = 20 m/sec
Total distance covered = 110 + 132 = 242 m.
Required time = 242/20
= 12.1 sec.
Answer: B
Answer: B
Question: Jerry, an electrician, worked 7 months out of the year. What percent
of the year did he work? (round answer to the nearest hundredth)
What percent 12 is 7? 12 months = 1 year
Options:
A)58.33%
B)68.33%
C)78.33%
D)88.33%
E)98.33%
Rationale: 1. Multiply the opposites
7 x 100 = 700
100=7/12
Divide by the remaining number
58.33
12)58.33/700.00
58.33% (rounded to hundredth)
correct answer A
Answer: A
Question: For any positive integer n, the sum of the first n positive integers equals n(n+1)/2. What is the sum of all the even integers between 99 and 181?
Options:
A)3820
B)5740
C)6580
D)7360
E)9200
Rationale: 100 + 102 + ... + 180 =
100*41 + (2+4+...+80) =
100*41 + 2*(1+2+...+40) =
100*41 + 2(40)(41)/2 =
100*41 + 40*41 = 140(41) = 5740
The answer is B.
Answer: B
Question: The value of a stock is X dollars. On Sunday the stock's value grew by third of its value, but on Monday its value dropped to a third of its new value. What is the stock's value at the end of Monday?
Options:
A)X.
B)X/2.
C)2X/3.
D)X/3.
E)4X/9.
Rationale: Stock value= X
AT sunday end= x+X/3= 4X/3=1.3X
On monday the value drop to 1/3rd of its value on sunday
1.3x/3= 4X/9
E is the answer
Answer: E
Question: If a sum of money doubles itself in 15 years at simple interest, the ratepercent per annum is
Options:
A)12
B)12.5
C)6.67
D)13.5
E)14
Rationale: Explanation:
Let sum = x then Simple Interest = x
Rate = (100 * x) / (x * 15) = 6.67
Option C
Answer: C
Question: If the diagonal of a rectangle is 17cm long and its perimeter is 46 cm. Find the area of the rectangle.
Options:
A)110
B)120
C)130
D)140
E)150
Rationale: Explanation:
let length = x and breadth = y then
2(x+y) = 46 => x+y = 23
x²+y² = 17² = 289
now (x+y)² = 23²
=>x²+y²+2xy= 529
289+ 2xy = 529
=> xy = 120
area =xy=120 sq. cm Answer: B
Answer: B