divelab/Sys2Bench huggingface dataset:
Question: A grocer has a sale of Rs. 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 6500?
Options:
A)4991
B)5991
C)5491
D)6991
E)6491
Rationale: Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009.
Required sale = Rs. [ (6500 x 6) - 34009 ]
= Rs. (39000 - 34009)
= Rs. 4991
Answer: Option A
Answer: A
Question: With out any halt a train travels a certain distance with an average speed of 40 km ph , and with halts it covers the same distance at an average speed of 25 kmph. When it is traveling with halts, how many minutes/per hour does the train halt on an average ?
Options:
A)48 min.
B)12min.
C)15min.
D)36min.
E)19min.
Rationale: With halt in 1 hour the train travels 60km
With out halt for traveling same distance it take 40/25 = 8/5 = 96 minutes
:. 36 minutes is the halting time per hour
ANSWER:D
Answer: D
Question: A milkman sells his milk at CP but he mixes it with water and thereby gains 25%. What is the % of water in the mixture?
Options:
A)10%
B)12%
C)20%
D)25%
E)30%
Rationale: Here Gain= 25%
error = quantity of water he mixes in the milk =x
true value = true quantity of milk = T
So the formula becomes, 25=x(T−x)×100
⇒1=x(T−x)×4⇒T−x=4x⇒T=5x
Percentage of water in the mixture
=xT×100=x5x×100=15×100=20%
C
Answer: C
Question: A person has four iron bars whose lengths are 24 m, 36 m, 48 m and 72 m respectively. This person wants to cut pieces of same length from each of four bars. What is the least number of total pieces if he is to cut without any wastage?
Options:
A)11
B)12
C)15
D)13
E)17
Rationale: C
15
24 = 12 × 2,
36 = 12 × 3,
48 = 12 × 4,
and 72 = 12 × 6
∴ HCF (24, 36, 48, 72) = 12
Total pieces = 2 + 3 + 4 + 6 = 15
Answer: C
Question: 165 liters of a mixture of milk and water contains in the ratio 3:2. How much water should now be added so that the ratio of milk and water becomes 3:4?
Options:
A)66 liters
B)32 liters
C)41 liters
D)50 liters
E)34 liters
Rationale: Milk = 3/5 * 165 = 99 liters
Water = 66 liters
99 : (66+P) = 3:4
198 + 3P = 396 => P = 66
66 liters of water are to be added for the ratio become 3:4.
Answer:A
Answer: A
Question: The present worth of Rs.338 due in 2 years at 4% per annum compound interest is
Options:
A)Rs.312.5
B)Rs.154.75
C)Rs.156.25
D)Rs.158
E)None
Rationale: Solution
Present Worth	= Rs.[338/(1+4/100)²]
= Rs.(338x25/26x25/26)
= Rs.312.5
Answer A
Answer: A
Question: How many numbers between 100 and 600 are divisible by 2, 3, and 7 together?
Options:
A)11
B)12
C)14
D)16
E)18
Rationale: Explanation:
As the division is by 2, 3, 7 together, the numbers are to be divisible by: 2*3*7 = 42
The limits are 100 and 600
The first number divisible is 42*3 = 126
To find out the last number divisible by 42 within 600:
600/42 = 14.28
Hence, 42*14 = 588 is the last number divisible by 42 within 600
Hence, total numbers divisible by 2, 3, 7 together are (14 – 2) = 12
ANSWER: B
Answer: B
Question: A 270 m long train running at the speed of 120 km/hr crosses another train running in opposite direction at the speed of 80 km/hr in 9 sec. What is the length of the other train?
Options:
A)230 m
B)240 m
C)260 m
D)320 m
E)520 m
Rationale: Relative speed = 120 + 80 = 200 km/hr.
= 200 * 5/18 = 500/9 m/sec.
Let the length of the other train be x m.
Then, (x + 270)/9 = 500/9 => x = 230.
ANSWER:A
Answer: A
Question: Which one of the given numbers is divisible by 11?
Options:
A)4823718
B)8423718
C)8432718
D)4238718
E)4852718
Rationale: Explanation:
4238718 = (4+3+7+8) – (2+8+1) = 11
So, the given number is divisible by 11
Answer:D
Answer: D
Question: If a certain toy store's revenue in November was 3/5 of its revenue in December and its revenue in January was 1/6 of its revenue in November, then the store's revenue in December was how many times the average (arithmetic mean) of its revenues in November and January?
Options:
A)3/2
B)5/4
C)10/3
D)20/7
E)25/9
Rationale: N = 3D/5
J = N/6 = D/10
The average of November and January is (N+J)/2 = 7D/10 / 2 = 7D/20
D is 20/7 times the average of November and January.
The answer is D.
Answer: D
Question: Divide Rs.32000 in the ratio 3:7?
Options:
A)12000, 20000
B)9600, 22400
C)12000, 20007
D)12000, 20006
E)12000, 20001
Rationale: 3/10 * 32000 = 9600
7/8 * 32000 = 22400
Answer: B
Answer: B
Question: The three digits of a number add up to 17. The number is divisible by 5. The leftmost digit is double the middle digit. What is the product of the three digits?
Options:
A)160
B)72
C)78
D)88
E)125
Rationale: Say the three-digit number is abc.
The leftmost digit is double the middle digit --> a=2b;
The number is divisible by 5 --> c is either 0 or 5;
The three digits of a number add up to 17 --> a+b+c=17
So, either a+b+c=2b+b+0=17 or a+b+c=2b+b+5=17. The first equation does not give an integer value of b, so it's not the case. From the second we get that b=4 --> a=8 and c=5 --> a*b*c=160.
Answer: A.
Answer: A
Question: Peter's One tap, working alone at its maximum constant rate, can fill a certain sink in 220 seconds. A second tap, working alone at its maximum constant rate, can fill the same sink in 224 seconds. If both taps work together at their respective maximum constant rates, the time it will take to fill the sink is closest to
Options:
A)111 seconds
B)130 seconds
C)177 seconds
D)200 seconds
E)270 seconds
Rationale: Tap 1 : 220 secs
Tap 2 : 224 secs
Considering the average of these 2 taps : 222 secs.
So 1 tap can fill the tank in 222 secs, so 2 taps can fill the tank in 222/2 = 111 secs.
Closest answer is A.
Answer: A
Question: A father said to his son, "I was as old as you are at the present at the time of your birth". If the father's age is 52 years now, the son's age five years back was?
Options:
A)18years
B)19years
C)20years
D)21years
E)21years
Rationale: Let the son's present age be x years. Then, (52 - x) = x
2x = 52.
x = 26.
Son's age 5 years back (26 - 5) = 21 years.
D)
Answer: D
Question: A college has classes from 10:00 AM until 2:00 PM. In this duration, there are five periods. If 5 minutes are provided between each period to leave one class and enter the next class, how many minutes long is each period?
Options:
A)38 min
B)41 min
C)40 min
D)42 min
E)44 min
Rationale: The total time is 240 minutes.
There are four breaks of five minutes between the classes for a total of 20 minutes.
The total class time is 220 minutes.
220 / 5 classes = 44 minutes per class
The answer is E.
Answer: E
Question: Lokesh started a business with Rs.30,000 and Ramesh joined him afterwards with Rs.30,000. If profits of both are same after one year then for how many months did Ramesh invest his money?
Options:
A)9 months
B)8 months
C)6 months
D)5 months
E)12 months
Rationale: let us assume ramesh has joined after "X" moths.
It has been told that profit is same
Therfore 30,000*12=30,000*X
X=12 months
ANSWER:E
Answer: E
Question: A boat goes 100 km downstream in 10 hours, and 75 m upstream in 15 hours. The speed of the stream is?
Options:
A)7 km/h
B)5 km/h
C)3 km/h
D)2 (1/2) km/h
E)None
Rationale: 100 --- 10 DS = 10
? ---- 1
75 ---- 15 US = 5
? ----- 1 S = (10 - 5)/2
= 2 2 ½ kmph
ANSWER:D
Answer: D
Question: The average of first six multiples of 3 is
Options:
A)10.5
B)6
C)9
D)12
E)15
Rationale: Solution
Average	= 3(1+2+3+4+5+6) / 6
= 63 / 6.
= 10.5.
Answer A
Answer: A
Question: x varies inversely as square of y. Given that y = 2 for x = 1. The value of x for y = 6 will be equal to?
Options:
A)1/6
B)1/3
C)1/0
D)1/9
E)1/5
Rationale: Given x = k/y2, where k is a constant.
Now, y = 2 and x = 1 gives k = 4.
x = 4/y2 => x = 4/62, when
y = 6 => x = 4/36 = 1/9.
Answer:D
Answer: D
Question: What is the approximate value of b in the following equation?
18% of 4514 + 25% of 3415 = b
Options:
A)1620
B)1670
C)1680
D)1690
E)1630
Rationale: b = 18% of 4514 + 25% of 3415
b = 18/100* 4514 + 25/100* 3415
b = 1666.27
≈ 1670
Answer B
Answer: B
Question: A certain sum amounts to Rs.1725 in 3 years and Rs.1875 in 5 years. Find the rate % per annum?
Options:
A)3%
B)5%
C)6%
D)4%
E)2%
Rationale: 3 --- 1725
5 --- 1875
--------------
2 --- 150
N = 1 I = 75 R = ?
P = 1725 - 225 = 1500
75 = (1500*1*R)/100
R = 5%
Answer :B
Answer: B
Question: John bought a shirt on sale for 25% off the original price and another 25 % off the discounted price. If the final price was $16, what was the price before the first discount?
Options:
A)$18.44
B)$28.44
C)$48.44
D)$58.44
E)$38.44
Rationale: let x be the price before the first discount. The price after the first discount is
x - 25%x (price after first discount)
A second discount of 25% of the discounted price after which the final price is 16
(x - 25%x) - 25%(x - 25%x) = 16
Solve for x
x = $28.44
correct answer B
Answer: B
Question: When the positive integer x is divided by the positive integer y, the quotient is 3 and the remainder is z. When z is divided by y, the remainder is 2. Which of the following could be the value of x?
I. 5
II. 8
III. 32
Options:
A)I only
B)II only
C)III only
D)I and II only
E)I, II and III
Rationale: When x is divided by y, the quotient is 3 and the remainder is z: x=3y+z, where 0≤z<y (the remainder must be less than the divisor).
When z is divided by y, the remainder is 2: when divisor (y in our case) is more than dividend (z in our case), then the reminder equals to the dividend (for example, 2 divided by 5 gives the remainder of 2). Therefore, z=2 and 2<y.
So, we have that x=3y+2 and 2<y. This implies that the least value of x is x=3∗3+2=11: x cannot be 5 or 8.
Could x be 32? Yes. If y=10, then x=3∗10+2=32.
Answer: C.
Answer: C
Question: The C.P of 15 books is equal to the S.P of 18 books. Find his gain% or loss%?
Options:
A)16 2/3% loss
B)16 2/9% loss
C)16 2/2% loss
D)16 2/3% loss
E)16 3/9% loss
Rationale: 15 CP = 18 SP
18 --- 3 CP loss
100 --- ? => 16 2/3% loss
Answer: A
Answer: A
Question: Consider the following game, in which a referee picks a random integer between 1 and 100.
One after the other, each of three players tries to guess the number the referee picked. Each
player announces his or her guess before the next player guesses. Each guess has to be different
from the previous guesses. The winner is the player who comes closest to the referee’s
number without exceeding it. (It is possible for none of the players to win.)
Suppose that Player 1 guesses 24, and that Player 3 will guess a number that gives her/him the
best chance of winning. What number should Player 2 guess to maximize his/her chances of
winning?
Options:
A)1
B)25
C)62
D)63
E)64
Rationale: First of all, observe that it always gives the third player the best chances to win if
[s]he guesses the lowest number in some range which the other players left open. Thus, if you
choose 63, this narrows the third player’s choices down to 1, 25, and 64. Guessing 25 gives
a range of 38 numbers (25 through 62 inclusive) which win for the third player if the referee
picked one of them, while a choice of 64 would only give 37 favorable numbers, and a choice
of 1 only gives 23 favorable numbers.
Note that 63 gives you 38 favorable numbers also (63 through 100 inclusive) so this way you
and the third player both have a 38% chance of winning, while the first player only has a 24%
chance.
The other four given answers do not give you such a good result. Answer (e), 64, still makes
25 the best choice for the third player, but cuts your chances down to 37% while raising the
third player’s to 39%. Answer (a), 1, is even worse than (e) because it only gives 23 chances
for you. Answer (c), 62, would give the third player 63 as the best guess, (38% versus 37%
if 25 is guessed instead) drastically reducing your winning chances to 1%. You would get the
same baleful result if you guessed 25 [answer (b)], because then the obvious best guess for
the third player is 26.
correct answer D
Answer: D
Question: The average monthly salary of 20 employees in an organisation is Rs. 1700. If the manager's salary is added, then the average salary increases by Rs. 100. What is the manager's monthly salary ?
Options:
A)Rs.6003
B)Rs.3800
C)Rs.1288
D)Rs.6108
E)Rs.6011
Rationale: Explanation:
Manager's monthly salary Rs. (1800 * 21 - 1700 * 20) = Rs.3800.
Answer: B
Answer: B
Question: Out of 40 applicants to a law school, 15 majored in political science, 20 had a grade point average higher than 3.0, and 10 did not major in political science and had a GPA equal to or lower than 3.0. How many W applicants majored in political science and had a GPA higher than 3.0?
Options:
A)5
B)10
C)15
D)25
E)35
Rationale: Total applicants = 40
Political science = 15 and Non political science = 40 - 15 = 25
GPA > 3.0 = 20 and GPA <= 3.0 = 20
10 Non political science students had GPA <= 3.0 --> 15 Non political science students had GPA > 3.0
GPA > 3.0 in political science = Total - (GPA > 3.0 in non political science) W= 20 - 15 = 5
Answer: A
Answer: A
Question: A certain bridge is 4,424 feet long. Approximately how many minutes does it take to cross this bridge at a constant speed of 10 miles per hour? (1 mile = 5,280 feet)
Options:
A) 1
B) 2
C) 4
D) 5
E) 7
Rationale: Distance: 4424 feet. This is (4424/5280) miles = 0.84 miles
Speed: 10 miles per hour
Time: (Distance / Speed) (0.84/10) {This will come in Hours}. Multiply by 60 to get answer in minutes. It is 5.04 minutes.
Answer to be 5 minutes.
ANS D
Answer: D
Question: A train 900 m long passed a pole in 9 sec. How long will it take to pass a platform 800 m long?
Options:
A)17
B)18
C)19
D)20
E)21
Rationale: Speed = 900/9
= 100 m/sec.
Required time
= (900 + 800)/100
= 17 sec.
Answer:A
Answer: A
Question: Two pipes can fill a tank in 18 minutes and 60 minutes. An outlet pipe can empty the tank in 45 minutes. If all the pipes are opened when the tank is empty, then how many minutes will it take to fill the tank?
Options:
A)1/15
B)1/16
C)1/20
D)1/10
E)1/12
Rationale: Part of the filled by all the three pipes in one minute
= 1/18 + 1/60 - 1/45 = 1/20
So, the tank becomes full in 20 minutes.
Answer:C
Answer: C
Question: In a city, the streets are aligned in a grid, where the east-west roads are called 1st Rd, 2nd Rd, 3rd Rd, etc, increasing in number as one moves northward. The north-south roads are called 1st Ave, 2nd Ave, 3rd Ave, etc, increasing in number as one moves eastward. If Bill needs to walk from the corner of 2nd Rd and 3rd Ave to the corner of 9th Rd and 6th Ave in the shortest possible time, how many different routes could he take?
Options:
A)90
B)120
C)150
D)180
E)210
Rationale: Bills needs to walk 7 blocks north and 3 blocks east.
One possible solution is NNNNNNNEEE.
There are 10C7 = 120 possible solutions.
The answer is B.
Answer: B
Question: It takes printer A 4 more minutes more than printer B to print 40 pages. Working together, the two printers can print 50 pages in 6 minutes. How long will it take Printer A to print 60 pages?
Options:
A)12
B)18
C)20
D)24
E)30
Rationale: If it takes 4 more minutes for A to print 40 pages than it takes B,
it takes 5 more minutes for A to print 50 pages than it takes B.
Thus if b is the number of minutes than B takes to print 50 pages,
we can write:
1/b+1/(b+5)=1/6 (since in 1 minute, they print 1/6th of the 50 page job)
6(2b+5)=b(b+5)
b^2-7b-30=0
(b-10)(b+3)=0
b=10
Thus it takes A 15 minutes to print 50 pages and 15*60/50=18 minutes to print 60 pages (ANSWER B)
Answer: B
Question: In a 2000 m race, A beats B by 100 meters or 15 seconds. Find the speed of B?
Options:
A)10m/s
B)2m/s
C)5m/s
D)6.7m/s
E)3m/s
Rationale: Since A beats B by 100 m or 15 seconds,
it implies that B covers 100 m in 15 seconds.
Hence speed of B = 100/15 = 6.7 m/s.
Answer: D
Answer: D
Question: The probability that event A occurs is 0.4, and the probability that event B occurs is 0.45. If the probability that either event A or event B occurs is 0.6, what is the probability that event B and event B will occur?
Options:
A)0.25
B)0.15
C)0.45
D)0.5
E)0.55
Rationale: P(A or B) = P (A) + P(B) - p(a n b)
0.6= 0.4 + p(a n b) + 0.45
P(B) = 0.25
Ans : A
Answer: A
Question: A 480 m long train is running at a speed of 55 Km/hr. It crossed a platform of length 620 m in ?
Options:
A)41.1 sec
B)72 sec
C)31.8 sec
D)50.4 sec
E)none of the above
Rationale: Speed = 55 Km/hr
(to convert km/hr in to M/s)
= 55 x 5/18 M/s
Distance = 480 m + 620 m ( If questions is about train crossing a post you need to consider only the length of Train, )
= 1100 m
Time = Distance / Speed
= 1100 x 18 / (5 x 55)
= 72 sec
Ans is :B
Answer: B
Question: At a certain supplier, a machine of type A costs $20,000 and a machine of type B costs $60,000. Each machine can be purchased by making a 20 percent down payment and repaying the remainder of the cost and the finance charges over a period of time. If the finance charges are equal to 40 percent of the remainder of the cost, how much less would 2 machines of type A cost than 1 machine of type B under this arrangement?
Options:
A)$10,000
B)$11,200
C)$12,000
D)$12,800
E)$26,400
Rationale: Total Cost of 2 Machines of Type A
= 20% of (Cost of 2 machine A) + remainder + 40 % remainder
= 20% of 40000 + (40000 - 20% of 40000) + 40% of (40000 - 20% of 40000)
= 52800
Total Cost of 1 Machine of Type B
= 20% of (Cost of 1 machine B) + remainder + 40 % remainder
= 20% of 60000 + (60000 - 20% of 60000) + 40% of (60000 - 20% of 60000)
= 79200
Diff = 79200 - 52800 =26400
Hence, E.
Answer: E
Question: A train is 360 meter long is running at a speed of 54 km/hour. In what time will it pass a bridge of 140 meter length?
Options:
A)65 seconds
B)33.33 seconds
C)40 seconds
D)97 seconds
E)26 seconds
Rationale: Speed = 54 Km/hr = 54*(5/18) m/sec = 15 m/sec
Total distance = 360+140 = 500 meter
Time = Distance/speed
= 500 * (1/15)
= 33.33 seconds
Answer:B
Answer: B
Question: A and B together have $100. If 3/10 of A's amount is equal to 1/5 of B's amount, how much amount does B have?
Options:
A)$60
B)$55
C)$42
D)$31
E)$100
Rationale: 3/10 A = 1/5 B
A = 1/5 * 10/3 B
A = 2/3 B
A/B = 2/3
A:B = 2:3
B's share = 100*3/5 = $60
Answer is A
Answer: A
Question: Donovan took a math test and got 35 correct and 14 incorrect answers.
What was the percentage of correct answers? (Round to the nearest
hundredth)
Options:
A)57.78%
B)67.78%
C)71.43%
D)47.78%
E)97.78%
Rationale: 35 correct our of 49 total (35+14)
35/49
correct answer C
Answer: C
Question: In how many different ways can the letters of the word 'OPTICAL' be arranged so that the vowels always come together?
Options:
A)610
B)720
C)825
D)920
E)650
Rationale: Explanation:
The word 'OPTICAL' has 7 letters. It has the vowels 'O','I','A' in it and these 3 vowels should always come together. Hence these three vowels can be grouped and considered as a single letter. That is, PTCL(OIA).
Hence we can assume total letters as 5 and all these letters are different.
Number of ways to arrange these letters
=5!=5Ã—4Ã—3Ã—2Ã—1=120=5!=5Ã—4Ã—3Ã—2Ã—1=120
All the 3 vowels (OIA) are different
Number of ways to arrange these vowels among themselves
=3!=3Ã—2Ã—1=6=3!=3Ã—2Ã—1=6
Hence, required number of ways
=120Ã—6=720
ANSWER IS B
Answer: B
Question: A deer runs k miles in n hours. How many miles will it run in x hours at the same rate?
Options:
A)knx
B)k⁄n
C)kx⁄2n
D)kx⁄n
E)kn⁄x
Rationale: Given Speed = k/n
To Find distance in x hours with same speed
Distance = speed * time
Distance = k/n*x = kx/n
Answer D
Answer: D
Question: The length of the rectangular field is double its width. Inside the field there is square shaped pond 8m long. If the area of the pond is 1/50 of the area of the field. What is the length of the field?
Options:
A)73
B)32
C)34
D)43
E)80
Rationale: Explanation:
A/50 = 8 * 8 => A = 8 * 8 * 50
x * 2x = 8 * 8 * 50
x = 40 => 2x = 80
Answer: Option E
Answer: E
Question: If the average of 8 digits is 20 and the average of 5 of them is 12, calculate the average of the remaining 3 numbers?
Options:
A)13.3
B)38.3
C)35.3
D)31.3
E)33.3
Rationale: Explanation:
Total of the 8 digits - 8*20 = 160
Total of the 5 digits - 5*12 = 60
Total of the remaining 3 digits - 160-60 = 100
average of the remaining 3 numbers = 100/3 = 33.3
ANSWER: E
Answer: E
Question: The average weight of 10 men is increased by 1 ½ kg when one of the men who weighs 60 kg is replaced by a new man. What is the weight of the new man?
Options:
A) 80 kg
B) 83 kg
C) 70 kg
D) 75 kg
E) 85 kg
Rationale: Since the average has increased by 1.5 kg, the weight of the man who stepped in must be equal to 60+10x1.5
60+15=75 Kg
Ans: 'D'
Answer: D
Question: Charlene's annual bonus is calculated in the following manner: Charlene receives 20 percent of her first $11,000 in sales and 30 percent of her sales in excess of $11,000. If Charlene received a bonus of $8,500, what were her annual sales?
Options:
A)$ 20,000
B)$ 22,000
C)$ 24,666
D)$ 26,000
E)$ 28,000
Rationale: Let x be the total sales in $.
For the 1st 11,000 you get 20% ---> 0.2*11000 = 2200$
For the remaining (x-11000) $, you get 30% ---> 0.3*(x-11000)
Thus, 0.3*(x-11000) + 2200 = 8500 ----> x= 24,666 $
C is thus the correct answer.
Answer: C
Question: If four coins are tossed, the probability of getting two heads and two tails is?
Options:
A)3/8
B)3/6
C)3/9
D)3/1
E)3/4
Rationale: Since four coins are tossed, sample space = 24
Getting two heads and two tails can happen in six ways.
n(E) = six ways
p(E) = 6/24 = 3/8
Answer:A
Answer: A
Question: Three-fifth of a two digit number exceeds its one fifth by 6. What is the sum of the digits of the number?
Options:
A)6
B)9
C)11
D)12
E)15
Rationale: Explanation:
3x/5 – x/5 = 6 => x =15
1 + 5 = 6
A)
Answer: A
Question: In a restaurant, the profit is 160% of the cost. If the cost increases by 12% but the selling price remains constant, approximately what percentage of the selling price is the profit?
Options:
A)30%
B)57%
C)90%
D)100%
E)None of these
Rationale: Explanation :
Let C.P.= Rs. 100. Then, Profit = Rs. 160, S.P. = Rs. 260.
New C.P. = 112% of Rs. 100 = Rs. 112
New S.P. = Rs. 260.
Profit = Rs. (260 - 112) = Rs. 148.
Required percentage = (148 /260 *100) % = 57 % appox
Answer : B
Answer: B
Question: An investor purchased 100 shares of stock X at 6 1/8 dollars per share and sold them all a year later at 30 dollars per share. If the investor paid a 2 percent brokerage fee on both the total purchase price and the total selling price, which of the following is closest to the investor's percent gain on this investment?
Options:
A)92%
B)240%
C)280%
D)395%
E)380%
Rationale: If the purchase price was 6$ per share then the investor would have made a profit of 400%.
Since the purchase price is slightly more than 6$ the profit would be slightly less than 400%.
Also a 2% brokerage is negligible and it brings down the profit percentage only by a small value. Approximation is very useful to solve these kind of problems as the answer choices are far apart.
Answer: D
Answer: D
Question: A certain jacket was marked down 20% the first week and another 20% the next week. What percent of the regular price was the final cost of the jacket after the two markdowns?
Options:
A)30%
B)36%
C)40%
D)60%
E)64%
Rationale: This is a case of successive discounts.
Effective discount = -a -b + ab/100
Effective Discount = -20 - 20 + 400/100 = -36%
Final cost = 100 - 36 = 64% of the initial cost
ANSWER:E
Answer: E
Question: A dishonest dealer professes to sell his goods at Cost Price but still gets 20% profit by using a false weight. What weight does he substitute for a kilogram?
Options:
A)223 1/3 grams.
B)833 1/3 grams.
C)2873 1/3 grams.
D)273 1/3 grams.
E)832 1/3 grams.
Rationale: Explanation:
If the cost price is Rs.100, then to get a profit of 20%, the selling price should be Rs.120.
If 120kg are to be sold, and the dealer gives only 100kg, to get a profit of 20%.
How many grams he has to give instead of one kilogram(1000 gm).
120 gm ------ 100 gm
1000 gm ------ ?
(1000 * 100)/120 = 2500/3 = 833 1/3 grams.
Answer:B
Answer: B
Question: Of 100 apples in a tree, 30 percent are green. How many red apples must be picked in order to bring the number of green apples up to 50 percent of the apples in the tree?
Options:
A)40
B)50
C)30
D)70
E)20
Rationale: Now, there are 30 green apples (30% of 100) and 100-30=70 red apples in the tree. We need there to be 30 green apples and 30 red apples, in this case there will be 50% green apples and 50% red apples.
Therefore 70-30=40 red apples must be picked.
Answer: A.
Answer: A