divelab/Sys2Bench huggingface dataset:
Question: A 2member committee comprising of one male & one female member is to be constitute out of 5 males and 3females. Among st the females. Ms.A refuses to be a member of the committee in which Mr.B is taken as the member. In how many different ways can the committee be constituted ?
Options:
A)10
B)14
C)16
D)18
E)21
Rationale: 5C1 * 3C1 -1
= 15-1
= 14
B
Answer: B
Question: The speed of a boat in still water in 42 km/hr and the rate of current is 8 km/hr. The distance travelled downstream in 44 minutes is:
Options:
A)86.6 km
B)46.6 km
C)36.6 km
D)35.6 km
E)26.6 km
Rationale: Speed downstream = (42 + 8) = 50 kmph
Time = 44 minutes =44/60 hour = 11/15 hour
Distance travelled = Time × speed =11/15×50 = 36.6 km
ANSWER:C
Answer: C
Question: In a graduating class of 232 students, 144 took geometry and 119 took biology. What is the difference between the greatest possible number P and the smallest possible number of students that could have taken both geometry and biology?
Options:
A)144
B)119
C)113
D)88
E)31
Rationale: OFFICIAL SOLUTION:
First of all, notice that since 144 took geometry and 119 took biology, then the number of students who took both geometry and biology cannot be greater than 119.
{Total} = {geometry} + {biology} - {both} + {neither};
232 = 144 + 119 - {both} + {neither};
{both} = 31 + {neither}.
{both} is minimized when {neither} is 0. In this case {both} = 31.
The greatest possible number of students P that could have taken both geometry and biology, is 119.
Thus, the answer is 119 - 31 = 88.
Answer: D.
Answer: D
Question: If R and S are non-zero integers, and R/S > 1, then which of the following must be true?
Options:
A)R > S
B)2R > S
C)R^2< S^2
D)R^3 < S^3
E)RS > S
Rationale: E
Answer: E
Question: A completes a work in 20 days B in 60 days C in 45 days. All three persons working together on a project got a profit of Rs.26000 what is the profit of B?
Options:
A)4878
B)4675
C)4817
D)4818
E)4875
Rationale: We know that profits must be shared as the ratio of their efficiencies. But efficiencies are inversely proportional to the days. So efficiencies of A : B : C = 1/20 : 1/60 : 1/45 = 9 : 3 : 4
So B share in the total profit = 316×26000316×26000 = Rs.4875
Answer:E
Answer: E
Question: The fourth proportional to 28, 14 and 18 is?
Options:
A)2
B)6
C)7
D)8
E)9
Rationale: (14*18)/28 = 9
Answer: E
Answer: E
Question: Anand and Deepak started a business investing Rs. 40,000 and Rs. 35,000 respectively. Out of a total profit of Rs. 13,800, Deepak's share is?
Options:
A)2777
B)2888
C)6440
D)2882
E)2781
Rationale: Ratio of their shares =40000 : 35000 = 8:7
Deepak's share = 13800 * 7/15 = Rs. 6440.
Answer: C
Answer: C
Question: Oranges are bought at 7 for Rs.2. At what rate per hundred must they be sold to gain 33%?
Options:
A)27
B)38
C)39
D)44
E)55
Rationale: 7 oranges bought for rs 2
1 orange cost =2/7
therefore for 100 oranges =100*(2/7)
gain =33%
200/7+(33/100)*200/7=rate per hundred he want to sell
ans :38
ANSWER:B
Answer: B
Question: A metal company's old machine makes bolts at a constant rate of 100 bolts per hour. The company's new machine makes bolts at a constant rate of 150 bolts per hour. If both machines start at the same time and continue making bolts simultaneously, how many minutes will it take the two machines to make a total of 350 bolts?
Options:
A) 84
B) 72
C) 120
D) 144
E) 180
Rationale: Old Machine
100 bolts in 60 mins
so,
5/3 bolts in 1 min
New Machine
150 bolts in 60 mins
so,
5/2 bolts in 1 min
together,
5/3 + 5/2 =
25/6 bolts in 1 min
so, for 350 bolts
350 * 6 / 25 = 84 mins
Ans A
Answer: A
Question: The events A and B are independent, the probability that event A occurs is greater than 0, and the probability that event A occurs is twice the probability that event B occurs. The probability that at least one of events A and B occurs is 18 times the probability that both events A and B occur. What is the probability that event A occurs?
Options:
A)12/112
B)6/81
C)11/61
D)12/33
E)3/19
Rationale: Let us say probability of A occuring is a.
Let us say probability of B occuring is b.
a = 2b
Probability (either A or B or both) = 8 times Probability (A and B)
a*(1-b) + b*(1-a) + ab = 18*ab
Substituting a=2b in the second equation:
2b*(1-b) + b*(1-2b) + 2b*b = 18*2b*b
3b-2b^2 = 36b^2
3b = 38b^2
b = 3/38
So, a = 2b = 6/38=3/19
THE CORRECT ANSWER IS E.
Answer: E
Question: A math teacher has 25 cards, each of which is in the shape of a geometric figure. Half of the cards are rectangles, and a third of the cards are rhombuses. If 8 cards are squares, what is the maximum possible number of cards that re circles.
Options:
A)8
B)10
C)11
D)12
E)13
Rationale: a square is a special kind of rhombus (sides are perpendicular)
a square is a special kind of rectangles (sides with same length)
Among the 25 cards with have:
15 rectangles
10 rhombus
8 squares
Among the 15 rectangles, there could be 8 special ones (with sides of same length) that are squares. That lets at least 7 rectangles that are not square.
Among the 10 rectangles, there could be 8 special ones (with sides perpendicular) that are squares. That lets at least 2 rhombus that are not square.
We have 8 squares.
So the minimum different cards that represent a square, a rhombus or a rectangle is 2 + 7 + 8 = 17
Which means that the maximum number of circles that you could have is 25 - 17 = 8
Answer (A)
Answer: A
Question: If x and y are positive integers greater than 1 such that x – y and x/y are both even integers, which of the following numbers must be non-prime integers?
I. x
II. x + y
III. y/x
Options:
A)I only
B)II only
C)III only
D)I and II
E)I ,II and III
Rationale: Ans:
from the conditions given to us we get x>y and the min value of y can be 2 , therefore x will be a multiple of 4 so both I and ii will always be non-prime but iii will not be an integer. Answer (D).
Answer: D
Question: The radius of a wheel is 22.4 cm. What is the distance covered by the wheel in making 500 resolutions.
Options:
A)288
B)704
C)777
D)662
E)288
Rationale: In one resolution, the distance covered by the wheel is its own circumference. Distance covered in 500 resolutions.
= 500 * 2 * 22/7 * 22.4 = 70400 cm = 704 m
Answer:B
Answer: B
Question: A train running at the speed of 60 km/hr crosses a pole in 9 sec. What is the length of the train?
Options:
A)120 m
B)190 m
C)115 m
D)110 m
E)150 m
Rationale: Speed = 60 * 5/18 = 50/3 m/sec
Length of the train = speed * time = 50/3 * 9 = 150 m
Answer: E
Answer: E
Question: Nine carpenters can individually complete a particular task in 3, 4, 5, and 7 hours, respectively. What is the maximum fraction of the task that can be completed in forty-five minutes if eight of the carpenters work together at their respective rates ?
Options:
A)11/15
B)3/5
C)11/30
D)47/135
E)5/9
Rationale: Farmer A, B, C, and D
A's rate: 1/3 job/hour
B's rate: 1/4 job/hour
C's rate: 1/5 job/hour
D's rate: 1/7 job/hour
By intuition we know that the three fastest farmers are A B and C.
As such
(1/3 + 1/4 + 1/5)*(8/9) = ?
47/135 or (D)
Answer: D
Question: A train speeds past a pole in 15 sec and a platform 110 m long in 25 sec, its length is?
Options:
A)100
B)150
C)160
D)165
E)180
Rationale: Let the length of the train be x m and its speed be y m/sec.
Then, x/y = 15 => y = x/15
(x + 110)/25 = x/15 => x = 165 m.
Answer: Option D
Answer: D
Question: An order was placed for the supply of a carper whose length and breadth were in the ratio of 3 : 2. Subsequently, the dimensions of the carpet were altered such that its length and breadth were in the ratio 7 : 3 but were was no change in its parameter. Find the ratio of the areas of the carpets in both the cases.
Options:
A)8:8
B)8:7
C)8:2
D)8:1
E)8:9
Rationale: Let the length and breadth of the carpet in the first case be 3x units and 2x units respectively.
Let the dimensions of the carpet in the second case be 7y, 3y units respectively.
From the data,.
2(3x + 2x) = 2(7y + 3y)
=> 5x = 10y
=> x = 2y
Required ratio of the areas of the carpet in both the cases
= 3x * 2x : 7y : 3y
= 6x2 : 21y2
= 6 * (2y)2 : 21y2
= 6 * 4y2 : 21y2
= 8 :7
Answer:B
Answer: B
Question: Sneha went to the stationers and bought things worth Rs. 50, out of which 50 paise went on sales tax on taxable purchases. If the tax rate was 5%. then what was the cost of the tax free items?
Options:
A)Rs. 39.60
B)Rs. 39.50
C)Rs. 39.80
D)Rs. 49.50
E)Rs. 49.75
Rationale: Solution
Let the amount of taxable purchases be Rs.x.
Then, 5% of x	= 50/100
x ‹=› (50/100×100/5)
= 10
Cost of tax free items	= Rs.[50 - (10 + 0.50)]
= Rs. 39.50
Answer B
Answer: B
Question: How Many 7â€™s are there in the following sequence which are immediately preceded by 6 but not immediately followed by 4?
6 7 4 2 7 4 9 3 6 7 1 9 4 7 2 9 6 7 1 3 6 7 4 3 6
Options:
A)1
B)2
C)3
D)4
E)None
Rationale: Answer: B . 2
Answer: B
Question: If 31/198 = 0.1565, what is the 97nd digit to the right of the decimal point of the fraction?
Options:
A)1
B)2
C)6
D)7
E)9
Rationale: we are not concerned what 31/198 means..
we have to look at the decimal..
0.1565 means 0.1565656....
so leaving girst and second digit to the right of decimal, all ODD numbered are 6 and all EVEn numbered are 5..
here 97 is ODD, so ans is 6
C
Answer: C
Question: The instructions state that Cheryl needs 4/9 square yards of one type of material and 2/3 square yards of another type of material for a project. She buys exactly that amount. After finishing the project, however, she has 6/12 square yards left that she did not use. What is the total amount of square yards of material Cheryl used?
Options:
A)1/12
B)1/9
C)2/3
D)1 1/9
E)4/9
Rationale: total bought = 4/9+2/3
left part 6/12--->2/3
so used part 4/9+2/3-2/3=4/9
Ans E
Answer: E
Question: A drink vendor has 10 liters of Maaza, 144 liters of Pepsi and 368 liters of Sprite. He wants to pack them in cans, so that each can contains the same number of liters of a drink, and doesn't want to mix any two drinks in a can. What is the least number of cans required?
Options:
A)135
B)261
C)422
D)430
E)438
Rationale: The number of liters in each can = HCF of 10, 144 and 368 = 2 liters.
Number of cans of Maaza = 10/2 = 5
Number of cans of Pepsi = 144/2 = 72
Number of cans of Sprite = 368/2 = 184
The total number of cans required = 5 + 72 + 184 = 261 cans.
ANSWER:B
Answer: B
Question: What will be the difference in simple and compound interest on 5000 after three years at the rate of 10 percent per annum?
Options:
A)155
B)42
C)62
D)20
E)None of these
Rationale: For 3 years:
Diff.=Sum×(rate)2(300+rate)/(100)3
= 5000×10×10×310/100×100×100 = 155
Answer A
Answer: A
Question: 2.01 Ã— 0.001 = ?
Options:
A)0.201
B)0.000201
C)2.01
D)0.0201
E)0.00201
Rationale: 2.01 Ã— 0.001 = ?
or,? = 0.00201
Answer E
Answer: E
Question: How many such letter-pairs are there in the word MONKEY having same no. of letters left between them as they have in the series?
Options:
A)3
B)4
C)1
D)5
E)6
Rationale: only 1
i.e (n,o)
ANSWER:C
Answer: C
Question: 21 ball numbered 1 to 21. A ballis drawn and then another ball is drawn without replacement?
Options:
A)9/31
B)8/45
C)9/42
D)8/111
E)9/113
Rationale: The probability that first toy shows the even number,
=1021=1021
Since, the toy is not replaced there are now 9 even numbered toys and total 20 toys left.
Hence, probability that second toy shows the even number,
=920=920
Required probability,
=(1021)×(920)=(1021)×(920)
=9/42
C
Answer: C
Question: List R contains five numbers that have an average value of 70. If the median of the numbers in the list is equal to the mean and the largest number is equal to 20 more than two times the smallest number, what is the smallest possible value in the list?
Options:
A)28
B)31
C)34
D)37
E)40
Rationale: The middle number is 70.
Let the smallest number be x. Then the largest number is 2x+20.
To make x as small as possible, let's make the remaining numbers as large as possible.
So the second largest = the largest = 2x+20.
The second smallest should be equal to the median.
The numbers are x, 70, 70, 2x+20, 2x+20.
x + 70 + 70 + 2x + 20 + 2x + 20 = 5*70 = 350
5x = 170
x = 34
The answer is C.
Answer: C
Question: If a rectangular room measures 11 meters by 6 meters by 4 meters, what is the volume of the room in cubic centimeters? (1 meter=100 centimeters)
Options:
A)24,000
B)240,000
C)2,400,000
D)24,000,000
E)264,000,000
Rationale: E. 264,000,000
11*100*6*100*4*100 = 264,000,000
Answer: E
Question: The number of arrangements that can be made with the letters of the word MEADOWS so that the vowels occupy the even places?
Options:
A)122
B)134
C)144
D)156
E)176
Rationale: Explanation:
The word MEADOWS has 7 letters of which 3 are vowels.
-V-V-V-
As the vowels have to occupy even places, they can be arranged in the 3 even places in 3! i.e., 6 ways. While the consonants can be arranged among themselves in the remaining 4 places in 4! i.e., 24 ways.
Hence the total ways are 24 * 6 = 144.
C)
Answer: C
Question: Molly can do a task in 10 days while Sandy can do the task in 30 days. How many days will it take to complete the task if both work together?
Options:
A)4.5
B)6
C)7.5
D)8
E)8.5
Rationale: Each day, Molly can do 1/10 of the task.
Each day, Sandy can do 1/30 of the task.
Each day, they can do 1/10 + 1/30 = 2/15 of the task.
The task will be completed in 15/2 = 7.5 days.
The answer is C.
Answer: C
Question: Simplify: 72519 x 9999
Options:
A)725142989
B)725117481.
C)725117482
D)725111748
E)725117899
Rationale: 72519 x 9999 = 72519 x (10000 - 1)
= 72519 x 10000 - 72519 x 1
= 725190000 - 72519
= 725117481.
Answer is B
Answer: B
Question: If p/q = 3/7 , then 2p+q= ?
Options:
A)12
B)14
C)13
D)15
E)16
Rationale: let p=3, q=7 then 2*3+7=13
so 2p+q=13.
ANSWER:C
Answer: C
Question: 3 candidates in an election and received 1136, 7636 and 11628 votes respectively. What % of the total votes did the winningcandidate got in that election?
Options:
A)34%
B)54%
C)57%
D)78%
E)87%
Rationale: Total number of votes polled = (1136 + 7636 + 11628) = 20400
So, Required percentage = 11628/20400 * 100 = 57%
C
Answer: C
Question: Find large number from below question The difference of 2 no's is 1365. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder
Options:
A)1236
B)1356
C)1470
D)1556
E)1635
Rationale: Let the smaller number be x. Then larger number = (x + 1365).
x + 1365 = 6x + 15
5x = 1350
x = 270
Large number = 270+1365 = 1635
E
Answer: E
Question: A bus leaves the stop 30 minutes before the scheduled time. The driver decreases its speed by 30km/hr. At the next bus stop 180 km away, the bus reached on time. Find the original speed of the bus?
Options:
A)110km/hr
B)120km/hr
C)130km/hr
D)140km/hr
E)None of these
Rationale: Explanation :
Distance = 180km, actual speed = x and actual time = t
180 = x*t
180 = (x – 30)*(t +1/2)
Solve both equation, we will get x = 120km/hr
Answer – B
Answer: B
Question: The tax on a commodity is diminished by 12% and its consumption increased by 10%. The effect on revenue is?
Options:
A)8
B)6
C)3
D)5
E)4
Rationale: 100 * 100 = 10000
88 * 110 = 9680
-----------
10000-----------320
100-----------? => 3% decrease
Answer:C
Answer: C
Question: An escalator moves towards the top level at the rate of 12 ft.sec and its length is 196 feet. If a person walks on the moving escalator at the rate of 2 feet per second towards the top level, how much time does he take to cover the entire length.
Options:
A)14 sec
B)10 sec
C)12 sec
D)8 sec
E)9 sec
Rationale: Time taken to cover the entire length = tot.dist/resultant speed
= 196/ (12+2)
= 14sec
ANSWER:A
Answer: A
Question: James took a 3-hour bike ride. In the second hour he travlled 12 miles, which was 20 percent farther than he traveled the first hour. If he traveled 25 percent farther in the third hour than he did in the second hour, how many miles did jose travel during the entire ride?
Options:
A)54.0
B)54.9
C)55.5
D)37.0
E)63.0
Rationale: Let the distance travelled in the first hour be x. Thus, 1.2x = 12 , x = 10. Now, the distance travelled in the 3rd hour = 12+1/4âˆ—12=15
Therefore 12+15+ 10 = 37
ANSWER:D
Answer: D
Question: What is the value of 3x^2 − 1.8x + 0.3 for x = 0.6?
Options:
A)−0.3
B)0
C)0.3
D)1.08
E)2.46
Rationale: 3x^2-1.8x+0.3 for x=0.6
=3(0.6*0.6)-3*0.6*(0.6)+0.3
=0+0.3
=0.3
ANSWER:C
Answer: C
Question: A person X working alone can complete a work in 6 days. A person Y completes the same amount of work in 10 days, and a person Z when working alone can complete the same amount of work in 30 days. All three people work together for 2 days but then X and Y leave. How many more days does Z need to complete the work after X and Y leave?
Options:
A)9
B)10
C)11
D)12
E)13
Rationale: The fraction of work completed in two days is 2/6 + 2/10 + 2/30 = 18/30
The fraction of work remaining is 1 - 18/30 = 12/30
The number of days required for Z is 12 days.
The answer is D.
Answer: D
Question: A man can row with a speed of 23 kmph in still water. If the stream flows at 14 kmph, then the speed in downstream is?
Options:
A)37
B)23
C)20
D)28
E)12
Rationale: M = 23
S =14
DS = 23 + 14 = 37
Answer: A
Answer: A
Question: Rs. 6000 is lent out in two parts. One part is lent at 7% p.a simple interest and the other is lent at 10% p.a simple interest. The total interest at the end of one year was Rs. 450. Find the ratio of the amounts lent at the lower rate and higher rate of interest?
Options:
A)5 : 1
B)5 : 7
C)5 : 5
D)5 : 9
E)5 : 3
Rationale: Let the amount lent at 7% be Rs. x
Amount lent at 10% is Rs. (6000 - x)
Total interest for one year on the two sums lent
= 7/100 x + 10/100 (6000 - x) = 600 - 3x/100
=> 600 - 3/100 x = 450 => x = 5000
Amount lent at 10% = 1000
Required ratio = 5000 : 1000 = 5 : 1
Answer: A
Answer: A
Question: An alloy weighing 20 ounces is 70 percent gold. How many ounces of pure gold must be added to create an alloy that is 90 percent gold?
Options:
A)6
B)9
C)12
D)76
E)48
Rationale: In 24 ounces, gold is 20 * (70/100) = 14 ounces. Now we add x ounces of pure gold to make it 90% gold.
So 14 + x = (24 + x)* 90/100 => x =76.
Answer is D.
Answer: D
Question: A room is 8 meters 16 centimeters in length and 4 meters 32 centimeters in Width. Find the least number of square tiles of equal size required to cover the entire floor of the room.
Options:
A)107
B)153
C)178
D)198
E)165
Rationale: Let us calculate both the length and width of the room in centimeters.
Length = 8 meters and 16 centimeters = 816 cm
width = 4 meters and 32 centimeters = 432 cm
As we want the least number of square tiles required, it means the length of each square tile should be as large as possible.Further,the length of each square tile should be a factor of both the length and width of the room.
Hence, the length of each square tile will be equal to the HCF of the length and width of the room = HCF of 816 and 432 = 48
Thus, the number of square tiles required = (816 x 432 ) / (48 x 48) = 17 x 9 = 153
Answer: B
Answer: B
Question: A cistern 8 m long and 6 m wide contains water up to a depth of 1 m 25 cm. The total area of the wet surface is:
Options:
A)80 m2
B)50 m2
C)83 m2
D)86 m2
E)55 m2
Rationale: Area of the wet surface	= [2(lb + bh + lh) - lb]
= 2(bh + lh) + lb
= [2 (6 x 1.25 + 8 x 1.25) + 8 x 6] m2
= 83 m2.
answer :C
Answer: C
Question: Rani bought more apples than oranges. She sells apples at ₹23 apiece and makes 15% profit. She sells oranges at ₹10 apiece and makes 25% profit. If she gets ₹653 after selling all the apples and oranges, find her profit percentage C.
Options:
A)16.8%
B)17.4%
C)17.9%
D)18.5%
E)19.1%
Rationale: Given: Selling price of an Apple = 23 --> Cost price = 23/1.15 = 20
Selling price of an orange = 10 --> Cost price = 10/1.25 = 8
A > O
23*(A) + 10*(O) = 653
653 - 23*(A) has to be divisible by 10 --> Units digit has to be 0
Values of A can be 1, 11, 21, 31, .... --> 1 cannot be the value
Between 11 and 21, If A = 11, O = 30 --> Not possible
If A = 21, O = 17 --> Possible
Cost price = 20*21 + 8*17 = 420 + 136 = 556
Profit = 653 - 556 = 97
Profit% C= (97/556)*100 = 17.4%
Answer: B
Answer: B
Question: All the water in container A which was filled to its brim was poured into two containers B and C. The quantity of water in container B was 62.5% less than the capacity of container A. If 148 liters was now transferred from C to B, then both the containers would have equal quantities of water. What was the initial quantity of water in container A?
Options:
A)7184 liters
B)8184 liters
C)6184 liters
D)1184 liters
E)1183 liter
Rationale: Explanation:
B has 62.5% or (5/8) of the water in A. Therefore, let the quantity of water in container A(initially) be 8k.
Quantity of water in B = 8k - 5k = 3k.
Quantity of water in container C = 8k - 3k = 5k
Container: A B C
Quantity of water: 8k 3k 5k
It is given that if 148 liters was transferred from container C to container B, then both the containers would have equal quantities of water.
5k - 148 = 3k + 148 => 2k = 296 => k = 148
The initial quantity of water in A = 8k = 8 * 148 = 1184 liters.
Answer: D
Answer: D
Question: Six persons in an organization including X and Y were to be divided in two groups of 3 members each. The total number of groups containing both X and Y is what fraction of the total number of groups which can be formed?
Options:
A)1/4
B)1/70
C)3/14
D)3/10
E)11/14
Rationale: The fraction is nothing but the probability..
Number to choose 3 out of 6= 6C3
Number to choose X and Y and 2 from remaining 4=4C2..
prob of A and B choosen=4C2/6C3=3/10
Answer : D
Answer: D
Question: Boy sells a book for Rs.450 he gets a loss of 10%, find CP of the book?
Options:
A)Rs.400
B)Rs.450
C)Rs.500
D)Rs.600
E)Rs.650
Rationale: Find cost price
Let C.P. of book = x and S.P. = Rs. 450
S.P. of book = C.P. – (10% of C.P.)
S.P. = x – (0.10x)
450 = 0.9 x
x i.e cost price = Rs.500
C
Answer: C
Question: If the consumer price index for a sample of goods and services purchased in Dallas rose from 100 at the end of 1967 to x at the end of 1985, what was the average R (arithmetic mean) annual increase in the index over this period?
Options:
A) (x + 100)/18
B) x/18
C) (100 − x)/18
D) (x − 100)/18
E) 100x/18
Rationale: CPI in end of 1967 = 100
CPI in end of 1985 = x
Number of years = 18
Average annual increase in CPI R= (x-100)/18
Answer D
Answer: D
Question: In a lottery, there are 10 prizes and 25 blanks. A lottery is drawn at random. What is the probability of getting a prize?
Options:
A)5/6
B)2/7
C)2/8
D)9/2
E)8/9
Rationale: P (getting a prize) =10/(10 + 25) = 10/35 = 2/7	.
Answer:B
Answer: B
Question: The total age of A and B is 15 years more than the total age of B and C. C is how many years younger than A ?
Options:
A)12
B)27
C)15
D)18
E)11
Rationale: (A+B) - (B+C) = 15
A - C = 15.
C is younger than A by 15 years.
Answer: C
Answer: C
Question: Simran started a software business by investing Rs. 50,000. After six months, Nanda joined her with a capital of Rs. 80,000. After 3 years, they earned a profit of Rs. 14000. What was Simran's share in the profit?
Options:
A)Rs. 9423
B)Rs. 10,250
C)Rs. 12,500
D)Rs. 6000
E)None of these
Rationale: Simran : Nanda = (50000 * 36) : (80000 * 30) = 3:4
Simran's share = 14000 * 3/7 = Rs. 6000
ANSWER:D
Answer: D
Question: If x+y=260, x-y=200, for integers of x and y, y=?
Options:
A)200
B)230
C)50
D)115
E)150
Rationale: x+y = 260
x-y = 200
2x = 60
x = 30
y = 230
Answer is B
Answer: B
Question: The average age of a husband and a wife is 28 years when they were married ten years ago but now the average age of the husband, wife and child is 27 years(the child was born during the interval). What is the present age of the child?
Options:
A)2 years
B)5 years
C)9 years
D)4 years
E)1 years
Rationale: 38 * 2 = 76
27 * 3 = 81
-----------
5 years
Answer:B
Answer: B
Question: A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of this son is
Options:
A)21 years
B)22 years
C)23 years
D)24 years
E)26 years
Rationale: Explanation:
Let's Son age is x, then Father age is x+24.
=> 2(x+2) = (x+24+2)
=> 2x+4 = x+26
=> x = 22 years
Option B
Answer: B