divelab/Sys2Bench huggingface dataset:
Question: Which is a better investment 9% stock at 580 or 6 2/5 stock at 312?
Options:
A)9% stock at 580
B)Both are equally good
C)6 2/5 stock at 312
D)None
E)Cannot be compared, as the total amount of investment is not given
Rationale: Let investment in each case be Rs. (580 x 312).
Income in 1st case = Rs. 9 x 580 x 312/580= Rs. 2808.
Income in 2nd case = Rs.32 x 580 x 312/(5*312)= Rs. 3712
Clearly, 6 2/5 stock at 312 is better.
ANSWER:C
Answer: C
Question: There are two circles of different radii. The are of a square is 784 sq cm and its side is twice the radius of the larger circle. The radius of the larger circle is seven - third that of the smaller circle. Find the circumference of the smaller circle.
Options:
A)165∏ cm
B)65∏ cm
C)12∏ cm
D)14∏ cm
E)16∏ cm
Rationale: Let the radii of the larger and the smaller circles be l cm and s cm respectively. Let the side of the square be a cm.
a2 = 784 = (4)(196) = (22).(142)
a = (2)(14) = 28
a = 2l, l = a/2 = 14
l = (7/3)s
Therefore s = (3/7)(l) = 6 Circumference of the smaller circle = 2∏s = 12∏ cm.
Answer: C
Answer: C
Question: An urn contains 6 black and 2 white balls. Two balls are drawn from the urn one after the other
without replacement. What is the probability that both drawn balls are black?
Options:
A)1/5
B)3/7
C)2/5
D)3/5
E)15/28
Rationale: Let E and F denote respectively the events that first and second ball drawn
are black. We have to find P(E n F) or P (EF).
Now P(E) = P (black ball in first draw) = 6/8
Also given that the first ball drawn is black, i.e., event E has occurred, now there are 5 black balls and eight white balls left in the urn. Therefore, the probability that the second ball drawn is black, given that the ball in the first draw is black, is nothing but the conditional probability of F given that E has occurred.
That is P(F|E) = 5/7
By multiplication rule of probability, we have
P (E n F) = P(E) P(F|E)
= 6/8× 5/7 = 15/28
E
Answer: E
Question: What number has a 15:1 ratio to the number 10?
Options:
A)130
B)100
C)200
D)150
E)120
Rationale: 15:1 = x: 10
x = 10*15
x=150
ANSWER:D
Answer: D
Question: If you select two cards from a pile of cards numbered 1 to 10, what is the probability that the sum of the numbers is less than 6?
Options:
A)1/45
B)2/45
C)4/45
D)2/15
E)1/5
Rationale: The number of ways to choose two cards is 10C2=45.
There are 4 ways, {1,2},{1,3}, {1,4} and {2,3}, to get a sum less than 6.
P(sum less than 6)=4/45
The answer is C.
Answer: C
Question: Siddharth wants to borrow Rs.7000 at rate of interest 6% p.a. at S.I and lend the same amount at C.I at same rate of interest for two years. What would be his income in the above transaction?
Options:
A)s.21.60
B)s.21.68
C)s.25.2
D)s.21.98
E)s.21.29
Rationale: Amount of money Siddharth borrowed at S.I at 6% p.a. for two years = Rs.7,000
He lend the same amount for C.I at 6% p.a. for two years.
=> Siddharth's income = C.I - S.I
= p[1 + r/ 100]n - p - pnr/100
= p{ [1 + r/ 100]2 - 1 - nr/100
= 7,000{ [1 + 6/100]2 - 1 - 12/100}
= 7,000 {(1.06)2- 1 - 0.12} = 7,000(1.1236 - 1 - 0.12)
= 7,000 (0.0036) = 7 * 3.6
= Rs.25.2
Answer: C
Answer: C
Question: On Thursday Mabel handled 90 transactions. Anthony handled 10% more transactions than Mabel, Cal handled 2/3rds of the transactions that Anthony handled, and Jade handled 16 more transactions than Cal. How much transactions did Jade handled?
Options:
A)42
B)52
C)62
D)72
E)82
Rationale: Mabel handled 90 transactions
Anthony handled 10% more transactions than Mabel
Anthony = 90 + 90 × 10%
= 90 + 90 × 0.10
= 90 + 9
= 99
Cal handled 2/3rds of the transactions than Anthony handled
Cal = 2/3 × 99
= 66
Jade handled 16 more transactions than Cal.
Jade = 66 + 16
= 82
Jade handled = 82 transactions.
Answer: E
Question: Consider the word ROTOR. Whichever way you read it, from left to right or from right to left, you get the same word. Such a word is known as palindrome. Find the maximum possible number of 5-letter palindromes
Options:
A)1700
B)7570
C)1576
D)17576
E)500
Rationale: The first letter from the right can be chosen in 26 ways because there are 26 alphabets.
Having chosen this, the second letter can be chosen in 26 ways.
=> The first two letters can be chosen in 26Ã—26=67626Ã—26=676 ways
Having chosen the first two letters, the third letter can be chosen in 26 ways.
=> All the three letters can be chosen in 676Ã—26=17576676Ã—26=17576 ways.
It implies that the maximum possible number of five letter palindromes is 17576 because the fourth letter is the same as the second letter and the fifth letter is the same as the first letter.
ANSWER D
Answer: D
Question: The distance from Springville to Franklin is 400 Km. Travelling at 120 Km/h from Springville to Franklin, Teresa arrives two hours faster than her return trip, which took five hours. What speed was Teresa travelling on the return trip?
Options:
A)50 Km/h
B)55 Km/h
C)62 Km/h
D)72 Km/h
E)80 Km/h
Rationale: distance=speed*time
d1=s1t1
d2=s2t2
The distance from point A to point B is the same for each trip so,
d1=d2 and
t1=3
t2=5
thus,
s1t1=s2t2
120(3)=s2(5)
s2=72 Km/h
Answer: D
Answer: D
Question: What least number should be added to 1054, so that the sum is completely divisible by 23
Options:
A)A)4
B)B)1
C)C)2
D)D)3
E)E)5
Rationale: Explanation:
(1054 / 23) gives remainder 19
19 + 4 = 23, So we need to add 4
Answer: Option A
Answer: A
Question: What is the remainder when you divide 2^200+1 by 7?
Options:
A)1
B)2
C)3
D)4
E)5
Rationale: answer is E. this is very similar to the 32^32^32+1 divided by 7 question.
Answer: E
Question: 3,8,24,48,120,?
Options:
A)166
B)167
C)168
D)198
E)178
Rationale: 2^2 =(4) -1 =3
3^2=(9) -1 =8
5^2 =(25) -1 =24
7^2 =(49) -1 =48
11^2 =(121) -1 =120
So, next
13^2 =(169) -1=168
ANSWER:C
Answer: C
Question: If the population of a certain country increases at the rate of one person every 15 seconds, by how many persons does the population increase in 55 minutes?
Options:
A)80
B)100
C)150
D)180
E)220
Rationale: Since the population increases at the rate of 1 person every 15 seconds, it increases by 4 people every 60 seconds, that is, by 4 people every minute. Thus, in 55 minutes the population increases by 55 x 4 = 220 people.
Answer. E.
Answer: E
Question: P persons have decided to rent a van to tour while on holidays. The price of the van is x dollars and each person is to pay an equal share. If D persons cancel their trip thus failing to pay their share, which of the following represents the additional number of dollars per person that each remaining person must pay in order to still rent the van?
Options:
A)Dx
B)x/(P −D)
C)Dx/(P −D)
D)Dx/(P(P −D))
E)x/(P(P −D))
Rationale: Share per person =x/p
When D person left, share per person = x/(p-D)
So the additional share per person is =x/(D-p) - x/p = (px-Dx+px)/p(D-p)=Dx/p(D-p)
Answer D
Answer: D
Question: What percent of a day is 6 hours?
Options:
A)12%
B)12.5%
C)25%
D)11.3%
E)None of these
Rationale: Explanation :
Solution: required percentage = (6/100 * 24) = 25%
Answer : C
Answer: C
Question: If a(n) is to be entered following the rule [a(n)^2 - 1] then what are the next three entries.
Options:
A)0,-1,0
B)2,3,4
C)1,2,3
D)0,-1,2
E)0,-1,1
Rationale: It only satisfies the rule, when a(n) = -1,0,1
ANSWER:A
Answer: A
Question: John has purchased an item on sale for $25.00. A few days later John sees the price is now $32.00. By what percentage of the price John paid has the price risen?
Options:
A)5
B)7
C)15
D)20
E)28
Rationale: C.P.=25.00
N.P.=32.00
markup%=(N.P.-C.P.)/C.P.*100=(32-25)/25*100=28%
ANSWER:E
Answer: E
Question: Bob wants to run a mile in the same time as his sister. If Bob’s time for a mile is currently 10 minutes 30 seconds and his sister’s time is currently 9 minutes 36 seconds, by what percent does Bob need to improve his time in order run a mile in the same time as his sister?
Options:
A)3%
B)5%
C)9%
D)10%
E)12%
Rationale: Bob's time = 630 secs.
His sis' time = 576 secs.
Percent increase needed = (630-576/630) * 100 = 54/640 * 100 = 9%. Ans (C).
Answer: C
Question: Of 45 applicants for a job, 28 had at least 5 years of prior work experience, 24 had advanced degrees, and 20 had at least 5 years of prior work experience and advanced degrees. How many of the applicants had neither 5 years of prior work experience nor advanced degrees?
Options:
A)9
B)13
C)18
D)20
E)23
Rationale: Had advanced degrees and 5 years work experience: 20
Only had 5 years work experience: 28-20 = 8
Only had advanced degrees: 24-20 = 4
45-20-8-4=13
Answer: B
Answer: B
Question: In a 200-mile trip, the first 50 miles were completed at 40 mph. If the average speed for the whole trip was 50 mph, what was the average speed in the last 150 miles?
Options:
A)592/11 mph
B)594/11 mph
C)596/11 mph
D)598/11 mph
E)600/11 mph
Rationale: The time to complete the first 50 miles was (50 miles / 40 mph) = (5/4) hours.
The time to complete the whole trip was (200 miles / 50 mph) = (4) hours.
The time to complete the last 150 miles was (4) - (5/4) = (11/4) hours.
The average speed in the last 150 miles was (150 miles / (11/4) hours) = 600/11 mph.
The answer is E.
Answer: E
Question: A grocer has a sale of Rs. 800, Rs. 900, Rs. 1000, Rs. 700 and Rs. 800 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 850?
Options:
A)s. 440
B)s. 850
C)s. 450
D)s. 900
E)s. 950
Rationale: Total sale for 5 months = Rs. (800 + 900 + 1000+ 700 + 800) = Rs. 4200
Required sale = Rs. [ (850 x 6) - 4200 ]
= Rs. (5100- 4200)
= Rs. 900.
Option D
Answer: D
Question: In baseball, the batting average is defined as the ratio of a player’s hits to at bats. If a player had anywhere from 6 to 8 at bats in a recent game and had anywhere from 6 to 7 hits in the same game, the player’s actual batting average for that game could fall anywhere between
Options:
A)0.25 and 1.00
B)0.50 and 0.75
C)0.70 and 1.25
D)0.33 and 0.50
E)0.50 and 0.66
Rationale: Average Range = Hits to Bats i.e 6/8 to 7/6 = 0.75 to 1.16
Answer: C
Answer: C
Question: How many odd factors does 160 have?
Options:
A) 2
B) 4
C) 5
D) 6
E) 8
Rationale: Start with the prime factorization: 160 = 2*5
For odd factors, we put aside the factor of two, and look at the other prime factors.
set of exponents = {1}
plus 1 to each = {2}
product = 2
Therefore, there are 2 odd factors of 160.
Answer: A.
Answer: A
Question: A girl has exactly 5 quarters, 8 dimes, and 10 nickels in her pocket. If she withdraws a number of these coins at random, how many coins would she have to withdraw to ensure that she has at least a 50 percent chance of withdrawing at least one quarter?
Options:
A)2
B)3
C)4
D)5
E)6
Rationale: When the probability of NOT drawing a quarter is 50% or less, then the probability of drawing a quarter is at least 50%.
P(not drawing a quarter with 2 coins) = 18/23 * 17/22 = 153/253 > 50%
P(not drawing a quarter with 3 coins) = 153/253 * 16/21 = 816/1771 < 50%
The answer is B.
Answer: B
Question: Consider two postmen A and B respectively. A is young and can deliver 20 parcels in 3 hours while B is older than A and can deliver only 15 parcels in 4 hours. If the total number of parcels to deliver is 60, how long they will take working together.
Options:
A)121/12 hours
B)144/36 hours
C)144/25 hours
D)121/25 hours
E)141/25 hours
Rationale: work done by 1st = 20/3 , work done by 2nd = 15/4 (here work is work/hour)
total work done together = 20/3+15/4 =125/12
time to do 60 unit work(ie, parcels)= 60*12/125 = 144/25
ANSWER:C
Answer: C
Question: One boy forgot the lastdigit of a 7 digit telephone no. If he randomly dialthe final 3 digits after correctly dialing the 1st four, then what is the chance of dialing the correct no.?
Options:
A)2/995
B)1/998
C)1/1000
D)1/1100
E)1/1200
Rationale: it is given that last 3 digits are randomly dialed
Then, each of the digit can be selected out of 10 digits in 10 ways. Hence, required probability
= 1/(10)3 = 1/1000
C
Answer: C
Question: Oil cans x and y are right circular cylinders and the height and radius of y are each 4 times those of x. If the oil in can x filled to capacity sells for $2, how much does the oil in y sell for if y is only half filled?
Options:
A)$60
B)$52
C)$63
D)$64
E)$68
Rationale: formula for vol of a cyl is PI*r^2*h
so Vy = 64*Vy
y when half filled will cost 32 times x so ans is D
Answer: D
Question: For 600 km journey it will take 8hrs, if 120 km is done by bus and the rest by car. It takes 20 minutes more, if 200 km is done by busand the rest by car. The ratio of the speed of the train to that of the cars is?
Options:
A)1 : 2
B)3 : 4
C)3 : 5
D)5 : 7
E)1 : 5
Rationale: Let the speed of the train be x km/hr and that of the car be y km/hr.
Then, 120 + 480 = 8 1 + 4 = 1 ....(i)
x y x y 15
And, 200 + 400 = 25 1 + 2 = 1 ....(ii)
x y 3 x y 24
Solving (i) and (ii), we get: x = 60 and y = 80.
Ratio of speeds = 60 : 80 = 3 : 4
B
Answer: B
Question: The average age of 31 students in a group is 16 years. when teacher's age is included to it, the average increases by one.What is the teacher's age in years?
Options:
A)31
B)36
C)48
D)45
E)57
Rationale: age of the teacher=(32*17-31*16)
=48 years.
ANSWER:C
Answer: C
Question: A plane flies 440 km with the wind and 360 km against the wind in the same length of time. If the speed of the wind is 20 km/h, what is the speed of the plane in still air?
Options:
A)160 km/h
B)170 km/h
C)180 km/h
D)190 km/h
E)200 km/h
Rationale: The speed of the plane in still air = x km/h
The speed of the wind is 20 km/h
Speed with the wind = (x + 20) km/h
Speed against the wind = (x â€“ 20) km/h
Time = Distance/ Speed
440 / (x+20) = 360 / (x-20)
440(x-20) = 360(x+20)
44x - 880 = 36x + 720
8x = 1600
x = 200
Therefore, the speed of the plane in still air is 200 km/h.
The answer is E.
Answer: E
Question: present ages of A and B are in the ratio of 5:3 respectively. 4 years hence, the ratio of their ages will become 11:9 respectively . what A's age after 3 years?
Options:
A)25
B)21
C)28
D)24
E)35
Rationale: A and B be 5x years and 3x years respectively
(5x+4)/(3x+4)=11/9
9(5x+4)=11(4x+4), 45x+36=44x+44
x=8, therefore A's present age : 3x=24 years
A's age after 4 year = 24+4 = 28
correct answer(B)
Answer: B
Question: Paint needs to be thinned to a ratio of 2 parts paint to 1.5 parts water. The painter has by mistake added water so that he has 6 litres of paint which is half water and half paint. What must he add to make the proportions of the mixture correct?
Options:
A)1 litre paint
B)1 litre water
C)Â½ litre water and one litre paint
D)Â½ litre paint and one litre water
E)None of these
Rationale: Explanation:
At the moment the paint is 3 liters of paint and 3 liters of water. We need to add to this to make the new ratio 2 liters paint to 1.5 liters water. As this is equivalent to 4 : 3 we can see that we have the right amount of water, and just need 1 liter of paint to make it correct.
Answer: A
Answer: A
Question: A certain university will select 1 of 7 candidates eligible to fill a position in the mathematics department and 2 of 12 candidates eligible to fill 2 identical positions in the computer science department. If none of the candidates is eligible for a position in both departments, how many different sets of 3 candidates are there to fill the 3 positions?
Options:
A)42
B)70
C)140
D)165
E)462
Rationale: Ans: 462
7C1 * 12C2
Answer E)
Answer: E
Question: Seven children — A, B, C, D, E, F, and G — are going to sit in seven chairs in a row. Child A has to sit next to both B & G, with these two children immediately adjacent to Child A on either side. The other four children can sit in any order in any of the remaining seats. How many possible configurations are there for the children?
Options:
A)240
B)480
C)720
D)1440
E)3600
Rationale: First we can imagine the trio ABG as one item to arrange along with four other items: C , D, E, F.
This can be done in 5! = 120 ways
However the trio can be arranged in 2 ways: BAG or GAB.
So, total number of ways to sit the seven children is equal to 2*120 = 240 (option A)
Answer: A
Question: Coffee worth amount Rs. 126 per kg are mixed with third variety in the ratio 1: 1 : 2. If the mixture is worth Rs. 153 per kg, the price of the third variety per kg
Options:
A)175.5
B)200.5
C)125.5
D)225.5
E)250.5
Rationale: x==>153/22.50 = 1 => x - 153 = 22.50 => x=175.50.
ANSWER A
Answer: A
Question: Rice weighing 33/4 pounds was divided equally and placed in 4 containers. How many ounces of rice were in each container? (Note that 1 pound = 16 ounces)
Options:
A)27
B)30
C)33
D)36
E)39
Rationale: 33/4 ÷ 4 = 33/16 pounds in each container
33/16 pounds * 16 ounces / pound = 33 ounces in each container
The answer is C.
Answer: C
Question: Wednesday occurred on 15th September 2010. What was the day of the week on 15th September 2009?
Options:
A)Monday
B)Friday
C)Wednesday
D)Tuesday
E)Sunday
Rationale: 1 odd day in the year 2009
So, the day on 15th September 2010 will be one day beyond the day on 15th September 2009
But, 15th September 2010 is Wednesday
On 15th September 2009, it was Tuesday
Answer: D
Answer: D
Question: On a certain test, Bill scored 20 more points than John, but half as many points as Sue. If the sum of the scores of the three students was 120 points, how many points did Bill receive?
Options:
A)35
B)40
C)50
D)80
E)100
Rationale: consider john's points as x
so bill's points are x +20
So sue's points are 2x +40
total of all three students is 4x +60, but this total is given as 120
x = 15
so bill's points = 15 +20 = 35
correct answer option A
Answer: A
Question: Train A traveling at 60 km/hr leaves Mumbai for Delhi at 6 P.M. Train B traveling at 90 km/hr also
leaves Mumbai for Delhi at 9 P.M. Train C leaves Delhi for Mumbai at 9 P.M. If all three trains meet at the same time between Mumbai and Delhi, what is the speed of Train C if the distance between Delhi and Mumbai is 1260 kms?
Options:
A)110km/hr
B)120km/hr
C)130km/hr
D)140km/hr
E)150km/hr
Rationale: let time taken by train b is t hrs to meet train A
so let the train A and B meets at distance x
As the distance will be same so
time taken by train A is t+3
so 60*(t+3)=90*t
so t = 6hrs
now distance covered by train A is 90*6=540
And the remaining distance will be covered by train c to meet = 1260-540=720
so speed of train c is 720/6=120km/hr
ANSWER:B
Answer: B
Question: The dimensions of a rectangular solid are 4 inches, 6 inches, and 8 inches. If a cube, a side of which is equal to one of the dimensions of the rectangular solid, is placed entirely within thespherejust large enough to hold the cube, what the ratio of the volume of the cube to the volume within thespherethat is not occupied by the cube?
Options:
A) 10:17
B) 2:5
C) 5:16
D) 25:7
E) 2:3
Rationale: Answer: E.
Answer: E
Question: A restaurant spends one quarter of its monthly budget for rent and quarter of the rest for food and beverages. What percentage of the budget does the restaurant spend for food and beverages?
Options:
A)23.5%
B)32.5%
C)35%
D)18.75%
E)20%
Rationale: Spend on rent = 1/4
Spend on food and beverage= 1/4 of remaining = 1/4*3/4= 3/16
so 3/16= 18.75%
D is the answer
Answer: D
Question: Read the following three equations:
5 ~ 4 ~ 3 ~ 9 = 4215
6 ~ 9 ~ 2 ~ 6 = 3816
4 ~ 7 ~ 3 ~ 3 = 1122
Now based on the rule that has been used, solve the following equation:
8 ~ 2 ~ 7 ~ 4 = ____
Options:
A)3412
B)2910
C)2940
D)3749
E)4470
Rationale: A
3412
3412
The rule that is being followed here is
P ~ Q ~ R ~ S = [first digit of (P * S)] [last digit of (Q * R)] [first digit of (Q * R)] [last digit of (P * S)]
Using the same rule in the incomplete equation,
8 ~ 2 ~ 7 ~ 4 = [first digit of (8 * 4)] [last digit of (2 * 7)] [first digit of (2 * 7)] [last digit of (8 * 4)]
= 2418
Thus 3412 is the missing number.
Answer: A
Question: A retailer buys 40 pens at the marked price of 35 pens from a wholesaler. If he sells these pens giving a discount of 1%, what is the profit percent?
Options:
A)12 %
B)10 %
C)15 %
D)16 %
E)None
Rationale: Sol.
Let the marked price of each pen be Re. 1.
Then, C.P. of 40 pens = Rs. 36. S.P. of 40 pens = 99% of Rs. 40 = Rs. 39.60.
∴ Profit% = [3.60/36 * 100]% = 10%.
Answer B
Answer: B
Question: Positive integer n leaves a remainder of 4 after division by 5 and a remainder of 3 after division by 5. If n is greater than 30, what is the remainder that n leaves after division by 30?
Options:
A)3
B)12
C)18
D)22
E)28
Rationale: The theory says:
if a # x is devided by y and leave the positive # r as the remainder then it can also leave negative # (r-y) as the remainder.
e.g:
9 when devided by 5 leves the remainder 4 : 9=5*1+4
it can also leave the remainder 4-5 = -1 : 9=5*2 -1
back to the original qtn:
n leaves a remainder of 4 after division by 6 and a remainder of 3 after division by 5
==> n leaves a remainder of -2 (i.e. 4-6) after division by 6 and a remainder of -2 (i.e. 3-5) after division by 5
==> n when devided by 5 and 6 leaves the same remainder -2.
what is n?
LCM (5,6)-2 = 30-2 = 28
CHECK: 28 when devided by 6 leaves the remainder 4 and when devided by 5 leaves the remainder 3
However, the qtn says n > 30
so what is the nex #, > 28, that can give the said remainders when devided by 6 and 5
nothing but 28 + (some multiple of 6 and 5) as thissome multiple of 6 and 5will not give any remainder when devided by 5 or 6 but 28 will give the required remainders.
hence n could be anything that is in the form 28 + (some multiple of 6 and 5)
observe thatsome multiple of 6 and 5is always a multiple of 30 as LCM (5,6) = 30.
hence when n (i.e. 28 + some multiple of 6 and 5) is devided by 30 gives the remainder 22.
D
Answer: D
Question: In a school of 850 boys, 44% of Muslims, 28% Hindus, 10% Sikhs and the remaining of other communities. How many belonged to the other communities?
Options:
A)173
B)163
C)153
D)143
E)133
Rationale: 44 + 28 + 10 = 82%
100 – 82 = 18%
850 * 18/100 = 153
ANSWER:C
Answer: C
Question: Calculate the share of Y , if Rs. 2880 is divided among X, Y and Z in the ratio 3 : 5 : 8?
Options:
A)540
B)520
C)140
D)560
E)240
Rationale: 3 + 5 + 8 =16
2880/16=180
so Y's share=3*180
=540
ANSWER:A
Answer: A
Question: (2^x) (30^3) = (2^3) (3^3) (4^3) (5^3)
In the above equation, what is the value of x?
Options:
A)10
B)5
C)8
D)7
E)6
Rationale: E
6
Explanation:
(2^x)(30^3) = (2^3) (3^3) (4^3) (5^3)
(2^x)(30^3) = (120^3)
(2^x) = (120^3)/ (30^3)
(2^x) = (4^3)
(2^x) = 64
ln(2^x) = ln(64)
x ln(2) = ln(64)
x = ln(64)/ln(2)
x = 6
Thus x = 6.
Answer: E
Question: A man took some money for borrowed, for 3 years the total will be Rs.5500 and 5 years it will be Rs.6500/-. Then how much amount he borrowed?
Options:
A)s.4000/-
B)s.4500/-
C)s.4770/-
D)s.4800/-
E)s.4820/-
Rationale: 3 years --------> Rs.5500/-
5 years --------> Rs.6500/-
~ ~
------------------------------
2 years ---------> Rs.1000/-
1 year ----------> Rs.500/-
3years * Rs.500/- = Rs.1500/-
P = Rs.5500/- - Rs.1500/- = Rs.4000/-
P = Rs.4000/-
A
Answer: A
Question: List I: 11, 13, 15, 19 List II: x,11, 13, 15, 19
Options:
A)10
B)12
C)11
D)13
E)14
Rationale: List I has even number of terms, thus its median is the average of two middle terms (when arranged in ascending/descending order), so median=(13+15)/2=14
List II has odd number of terms, thus its median is the middle term (when arranged in ascending/descending order). As no other number in the list equal to 14, then x=14.
Answer: E
Answer: E
Question: Round off the given number to nearest hundreds
2785
Options:
A)2700
B)3000
C)2900
D)2800
E)3100
Rationale: the given number is 2785
its tens digit is 8. so replace each of the tens and ones digit by 0 and increase the hundreds digit by 1 to get the rounded off number to the nearest hundred.
correct answer (D)
Answer: D
Question: A gardener wants to plant flowers in his garden. He has 16 flowers. He has 10 flower pots. 2 flower pots are in the first row . 5 are in the second row and remaining 3 in the last row. He has 3 roses and the roses must be put only in the first row. The roses should not be kept anywhere else. The other flowers can be put in any pot. How many different groupings are possible?
Options:
A)216216
B)2006
C)3008
D)8007
E)2734
Rationale: 3C2 Select 3 Roses for first row
13C5 Select 5 flowers for second row from 13 flowers ( Since 3 roses cannot be used. 16-3 = 13)
8C3 Select 3 flowers for the last row from 8 flowers( Since 3 are roses which can be put in first row only and we have used 5 flowers for second row. 16-3-5 = 8)
Number of selection = 3C2 * 13C5 * 8C3 = 216216
Ans : A
Answer: A