divelab/Sys2Bench huggingface dataset:
Question: If a 9 ton whale is divided into 2 equal large pieces and 3 equal small pieces, how much does a small piece weigh if all of the small pieces put together weigh as much as one of the large pieces?
Options:
A)1 ton
B)1 1/2 tons
C)2 tons
D)2 1/2 tons
E)3 tons
Rationale: A. Each large piece is a third of the whale. Each small piece is a third of the remaining third of the whale. One third of one third is one ninth. One ninth of nine tons is one ton, so the answer is A
Answer: A
Question: W, S, Q, M, ?
Options:
A)M
B)K
C)H
D)Y
E)S
Rationale: Explanation:
No explanation is available for this question!
ANSWER: B
Answer: B
Question: The sum of digits of a two digit number is 12,The difference between the digits is 6. Find the number
Options:
A)85
B)93
C)83
D)72
E)None
Rationale: Description :
=> x+y=12, x-y=6
Adding these 2x =18
=> x=9, y=3.
Thus the number is 93
Answer B
Answer: B
Question: The sector of a circle has radius of 35 cm and central angle 135o. Find its perimeter?
Options:
A)91.5 cm
B)11.5 cm
C)91.8 cm
D)92.5 cm
E)152.5 cm
Rationale: Perimeter of the sector = length of the arc + 2(radius)
= (135/360 * 2 * 22/7 * 35) + 2(35)
= 49.5 + 70
= 152.5 cm
Answer:E
Answer: E
Question: ax ± b = c. All problems like the following lead eventually to an equation in that simple form.
Jane spent $42 for shoes. This was $14 less than twice what she spent for a blouse. How much was the blouse?
Options:
A)28
B)26
C)24
D)22
E)20
Rationale: Every word problem has an unknown number. In this problem, it is the price of the blouse. Always let x represent the unknown number. That is, let x answer the question.
Let x, then, be how much she spent for the blouse. The problem states that "This" -- that is, $42 -- was $14 less than two times x.
Here is the equation:
2x − 14 = 42.
2x=42+14
=56.
x=56/2
= 28
The blouse cost $28.
Answer is A.
Answer: A
Question: The probability of two events A and B are0.25 and 0.30 respectively. The probability that both A and B occur is 0.15. The probability that neither A nor B occur is _________
Options:
A)0.45
B)0.4
C)0.5
D)0.05
E)0.6
Rationale: we are apply that formula..............
P(AorB)=P(A)+P(B)-P(A AND B)
=.25+.30-.15
=.40
but the probability of neither A nor B=1-.40
=0.60
ANSWER:E
Answer: E
Question: The daily high temperatures were recorded at an Antarctic weather station. If a temperature of -38.2 degrees Celsius is 2 units of standard deviation below the mean temperature, and a temperature of -22.6 degrees Celsius is 4 units of standard deviation above the mean, which of the following temperatures is 5 unit of standard deviation above the mean?
Options:
A)-35.6 degrees Celsius
B)-20.0 degrees Celsius
C)-30.4 degrees Celsius
D)-27.8 degrees Celsius
E)-25.2 degrees Celsius
Rationale: Let us suppose mean = M and SD = d.
So, we are given M - 2d = -38.2
and M + 4d = -22.6
solving both the equations, we will get M = -33 an d = 2.6
So, we need to find out M + 5d = -33 +5* 2.6 = -20. Hence, B
Answer: B
Question: How long will a car take to run round a circular field of radius 2/π metres. If car runs at the rate of 8km/hr ?
Options:
A)2.5 sec.
B)10 sec.
C)3 sec
D)2 sec
E)1.8 sec
Rationale: Speed = 8 km/hr = 8*5/18 = 20/9 m/sec
distance = 2πr=2π*2/π=4 m
time taken = 4*9/20 = 1.8 sec.
Answer E
Answer: E
Question: A license plate in the country Kerrania consists of four digits followed by two letters. The letters A, B, and C are used only by government vehicles while the letters D through Z are used by non-government vehicles. Kerrania's intelligence agency has recently captured a message from the country Gonzalia indicating that an electronic transmitter has been installed in a Kerrania government vehicle with a license plate starting with 79. If it takes the police 15 minutes to inspect each vehicle, what is the probability that the police will find the transmitter within three hours?
Options:
A)18/79
B)1/75
C)1/25
D)1/50
E)1/900
Rationale: If it takes 15 minutes to inspect one vehicle, the # of vehicles that can be inspected in 3 hours (180 minutes) = 180/15 = 12. Hence, for calculating the probability that the police will find the transmitter within three hours, the favorable cases = 12. Now, we need to figure out the total # of cases.
The total # of cases = Total # of such cars possible. The details given about the car is that it starts with 79, which leaves 2 more digits, both of which can be filled by all 10 numbers (0-9). In addition, we have 3 letters, each of which can be filled by any from the set {A,B,C}. Hence the total # of such cars possible = 10*10*3*3 = 900
So, the probability that the police will find the transmitter within three hours = 12/900 = 1/75. Option B
Answer: B
Question: Let y = 2g + x^2 and g = 4x + 1.
If g^2 = 289, then which of the following can be a value of 2y + 3g?
Options:
A)100
B)130
C)141
D)151
E)160
Rationale: 800score Official Solution:
First note that g can either be 17 or -17. We are going to have to use both to find all solutions before we can choose a final answer. We begin by substituting g = 17 and then g = -17. If g = 17, then x = 4. If g = -17, then x = -18/4. Since all of our solutions are whole numbers, we can dismiss -18/4. We use g = 17 and x = 4 to determine the value of y: y = 2(17) + 16 =50. Finally, we substitute the values for y and g into the last expression to determine its value : 2(50) + 3(17) = 100 + 51 = 151;the correct answer is (D).
Answer: D
Question: For any number y, y* is defined as the greatest positive even integer less than or equal to y. What is the value of 6.2 – 6.2*?
Options:
A)0.2
B)1.2
C)1.8
D)2.2
E)4.0
Rationale: Since y* is defined as the greatest positive even integer less than or equal to y, then 6.2* = 4 (the greatest positive even integer less than or equal to 6.2 is 4).
Hence, 6.2 – 6.2* = 6.2 - 4 = 2.2
Answer: D.
Answer: D
Question: A high school had 1200 students enrolled in 2003 and 1500 students in 2006. If the student population P ; grows as a linear function of time t, where t is the number of years after 2003.
a) How many students will be enrolled in the school in 2010?
Options:
A)1800
B)1900
C)1700
D)1500
E)1600
Rationale: a) The given information may be written as ordered pairs (t , P). The year 2003 correspond to t = 0 and the year 2006 corresponds to t = 3, hence the 2 ordered pairs
(0, 1200) and (3, 1500)
Since the population grows linearly with the time t, we use the two ordered pairs to find the slope m of the graph of P as follows
m = (1500 - 1200) / (6 - 3) = 100 students / year
The slope m = 100 means that the students population grows by 100 students every year. From 2003 to 2010 there are 7 years and the students population in 2010 will be
P(2010) = P(2003) + 7 * 100 = 1200 + 700 = 1900 students
Answer B
Answer: B
Question: If selling price is doubled, the profit triples. Find the profit percent.
Options:
A)200/3
B)100
C)316/3
D)120
E)None of these
Rationale: Explanation :
Let the C.P. be x and the S.P. be y
So the profit is (y - x) ---------------------------- (1)
Now, the S.P. is doubled. So the new S.P. = 2y
The new profit = (2y - x)
Given that when S.P. is doubled, profit increases 3 times
=> New profit = 3 * old profit
=> (2y - x) = 3(y - x)
=> y = 2x
So, the profit = (y - x) = (2x - x) = x
% profit = (x/x∗100)% = 100%
Answer : B
Answer: B
Question: There are 20 boys and 15 girls are present in a class. If 5 student will chosen for a competition an at least two students must be girl?
Options:
A)309128
B)320000
C)251230
D)301000
E)100009
Rationale: 15 girls and 20 boys. Five students needed
It is always better to subtract the total from none in case of at least one problems.
Total ways = 35C5 = 324632
Total ways without any girl = 20C5 = 15504
Hence ways in which at least one women will be present = 324632 - 15504 = 309128
Correct option: A
Answer: A
Question: Find avrg speed if a man travels at speed of 32km/hr up and 48km/hr dawn at an altitude of 230m.
Options:
A)25.8
B)26.8
C)38.4
D)34.4
E)29.8
Rationale: avg speed=2*x*y/(x+y)
=2*32*48(32+48)=38.4
ANSWER:C
Answer: C
Question: 22 cubic centimetres of silver is drawn into a wire 1 mm in diameter. The length of the wire in metres will be :
Options:
A)84 m
B)28 m
C)120 m
D)137 m
E)None
Rationale: Sol.
Let the length of the wire b h.
Radius = 1/2 mm = 1/20 cm. Then,
22/7 * 1/20 * 1/20 * h = 22 ⇔ = [22 * 20 * 20 * 7 / 22] = 2800cm = 28 m.
Answer B
Answer: B
Question: A farmer has three different crops on his farm; cabbage, carrots, and parsnips, where 10 percent of the crops are cabbage and 35 percent are carrots. If the farm produces 650 pounds of parsnips, and the weight of all crops are evenly distributed, how many pounds of crops are produced in total?
Options:
A) 6,500 pounds
B) 2,000 pounds
C) 10 pounds
D) 1,000 pounds
E) 100 pounds
Rationale: Let the total pounds of crops be x
% of cabbage = 10%
% of carrots = 35%
% of parsnips = 100% - 45% = 65%
But this number is given as 500 pounds
so 65% of x = 650 and x = (650)(100/65)
x = 1,000
Therefore there a total of 1,000 pounds of crops.
Correct answer - D
Answer: D
Question: How many times are the hands of a clock at right angle in 2 weeks?
Options:
A)616
B)611
C)661
D)116
E)666
Rationale: In 1 day, they are at right angles 44 times.
In 14 days, they are at right angles 616 times. Answer: Option A
Answer: A
Question: The number of stamps that P and Q had were in the ratio of 7:2 respectively. After P gave Q 15 stamps, the ratio of the number of P's stamps to the number of Q's stamps was 2:1. As a result of the gift, P had how many more stamps than Q?
Options:
A)25
B)35
C)45
D)55
E)65
Rationale: P started with 7k stamps and Q started with 2k stamps.
(7k-15)/(2k+15) = 2/1
3k = 45
k = 15
P has 7(15) - 15 = 90 stamps and Q has 2(15)+15 = 45 stamps.
The answer is C.
Answer: C
Question: If the radii of umbra and penumbra cast by an object on a wall are of the ratio 2:6, what is the area of the penumbra ring around the umbra of the latter’s radius is 40 cms?
Options:
A)40288.57cm^2
B)40388.57cm^2
C)40488.57cm^2
D)40588.57cm^2
E)40688.57cm^2
Rationale: et the radius of umbra and penumbra are 2k and 6k.
Then as given radius of umbra=40cm
so 2k=40
k=20
radius of penumbra=20*6=120
area of penumbra ring around the umbra=area of penumbra-area of umbra
22/7*[(120)^2-(40)^2]
=40288.57cm^2
ANSWER:A
Answer: A
Question: A, B and C start a business each investing 20,000. After 5 months A withdrew 5000, B withdrew 4000 and C invests 6000 more. At the end of the year, a total profit of 69,900 was recorded. Find the share of B.
Options:
A)20,000
B)21,200
C)28,200
D)20,500
E)None of these
Rationale: Ratio of the capitals of A, B and C
= 20000 × 5 + 15000 × 7 : 20000 × 5 + 16000 × 7 : 20000 × 5 + 26000 × 7
= 205000 : 212000 : 282000 = 205 : 212 : 282.
B’s share = (69900 × 212⁄699) = 21200;
Answer C
Answer: C
Question: There are 36 carpenters in a crew. On a certain day, 29 were present. What percent showed up for work? (round to the nearest tenth)
Options:
A)50.6%
B)60.6%
C)70.6%
D)80.6%
E)90.6%
Rationale: x/100=29/36
Multiply the opposites:
29 x 100 = 2900
Divide by the remaining number:
80.55/2900.00
80.6%
correct answer D
Answer: D
Question: In a 100 m race, A runs at 8km per hour. If A gives B a start of 6 m and still him by 15 seconds, what is the speed of B ?
Options:
A)5.56 km/hr.
B)5.06 km/hr.
C)5.64 km/hr.
D)6.76 km/hr.
E)5.72 km/hr.
Rationale: Time taken by A to cover 100 m =(60 X 60 / 8000)	x 100 sec = 45 sec.
B covers (100 - 6) m = 94m in (45 + 15) sec = 60 sec.
B's speed = (94 x 60 x 60)/(60 x 1000)km/hr = 5.64 km/hr.
Answer is C
Answer: C
Question: A can finish a work in 10 days and B can do same work in half the time taken by A. then working together, what part of same work they can finish in a day?
Options:
A)1/5
B)1/6
C)1/7
D)3/10
E)None of these
Rationale: Explanation:
Please note in this question, we need to answer part of work for a day rather than complete work. It was worth mentioning here because many do mistake at this point in hurry to solve the question
So lets solve now,
A's 1 day work = 1/10
B's 1 day work = 1/5 [because B take half the time than A]
(A+B)'s one day work =
(1/10+1/5)=3/10
So in one day 3/10 work will be done
Answer: D
Answer: D
Question: Two persons start running simultaneously around a circular track of length 500 m from the same point at speeds of 15 km/hr and 25 km/hr. When will they meet for the first time any where on the track if they are moving in opposite directions?
Options:
A)16 seconds
B)18 seconds
C)19 seconds
D)27 seconds
E)45 seconds
Rationale: Time taken to meet for the first time anywhere on the track
= length of the track / relative speed
= 500 / (15 + 25)5/18 =500* 18 / 40 * 5
= 45 seconds.
Answer:E
Answer: E
Question: The average (arithmetic mean) of four different positive integers is 12. If the first of these integers in 3 times the second integer and the second integer is 2 less than the third integer, what is the least possible value of the fourth integer?
Options:
A)5
B)4
C)3
D)2
E)1
Rationale: Let the second integer be x and the fourth be a.
Then [3x + x + (x+2) + a]/4 = 12
=> 5x + 2 + a = 48
=> 5x + a = 48
=> a = 48 - 5x
From the above equation we can see that a is minimum when x is maximum, provided both are positive
The maximum value that x can take in the above equation while still keeping a positive is x=9
This gives us a= 48 - 45 = 3
Therefore the minimum value that the fourth integer can have is 3. Option C.
Answer: C
Question: In the country of Celebria, the Q-score of a politician is computed from the following formula:
Q=(41ab^2c^3)/d2, in which the variables a, b, c, and d represent various perceived attributes of the politician, all of which are measured with positive numbers. Mayor Flower’s Q-score is 150% higher than that of Councilor Plant; moreover, the values of a, b, and c are 60% higher, 40% higher, and 20% lower, respectively, for Mayor Flower than for Councilor Plant. By approximately what percent higher or lower than the value of d for Councilor Plant is the corresponding value for Mayor Flower?
Options:
A)56% higher
B)25% higher
C)8% lower
D)20% lower
E)36% lower
Rationale: Let's say M stands for Mayor and P stands for councilor
Then as per given information -
Qm = 2.5*Qp
Am = 1.6 Ap
Bm = 1.4 Bp
Cm = 0.8 Cp
and let
Dm = X* Dp
On substituting these values and solving for X we get X ~ 0.8 ....
Hence it is lower by 20%
Ans - D
Answer: D
Question: What is 985*985?
Options:
A) 954,169
B) 964,219
C) 964,549
D) 965,019
E) 970,225
Rationale: if you take a base of 1000 then 985 is 15 less than 1000
to get the product of 985 x 985 write like this
985- 15( as 15 less than base1000)
985- 15
now 15 x 15 = 225
and 985-15 = 970
so 985 x 985 = 970225 ... (bingo the answer is E . you can even have a shortcut ...... 15 x 15 = 225 ... only answer choice has last three digits as 225.. so no need to calculate 985-15 . after you get 15 x 15 you can straight way pick answer choice E.
Answer: E
Question: Eleven bags are bought for Rs.1000 and sold at 10 for Rs.1100. What is the gain or loss in percentage?
Options:
A)29%
B)21%
C)23%
D)28%
E)27%
Rationale: Explanation:
As selling price is Rs.1100 for 10 bags, each bag is sold at Rs.110.
Hence, the profit is Rs.100 after selling 10 bags plus the selling price of 1 bag = 100 + 110 = Rs.210.
%profit = 210/1000 *100
= 21%
ANSWER: B
Answer: B
Question: The prices of tea and coffee per kg were the same in june. In july the price of coffee shot up by 20% and that of tea dropped by 20%. if in july , a mixture containing equal quantities of tea and coffee costs 90/kg. how much did a kg of coffee cost in june ?
Options:
A)50
B)60
C)80
D)90
E)120
Rationale: Let the price of tea and coffee be x per kg in June.
Price of tea in July = 1.2x
Price of coffee in July = 0.8x .
In July the price of 1/2 kg (900gm) of tea and 1/2 kg (900gm) of coffee (equal quantities) = 90
1.2x(1/2) + 0.8x(1/2) = 90
=> x =90
Thus proved...option D.
Answer: D
Question: A man can row his boat with the stream at 30 km/h and against the stream in 14 km/h. The man's rate is?
Options:
A)1 kmph
B)4 kmph
C)5 kmph
D)7 kmph
E)8 kmph
Rationale: DS = 30
US = 14
S = ?
S = (30 - 14)/2 = 8 kmph
Answer: E
Answer: E
Question: If an object travels at five feet per second, how many feet does it travel in one hour?
Options:
A)30
B)300
C)720
D)1800
E)18000
Rationale: object travels 5 feet in 1 seconds
so speed = 5 ft/second
there are 60 * 60 = 3600 seconds in a hour
so time = 3600 seconds
according to formula distance = speed * time
so object will travel 5 * 3600 = 18000 feet in a hour
so distance = 18000 feet
correct answer - E
Answer: E
Question: The maximum gap between two successive leap year is?
Options:
A)2
B)8
C)9
D)6
E)5
Rationale: Explanation:
This can be illustrated with an example.
Ex: 1896 is a leap year.The next leap year comes in 1904 (1900 is not a leap year).
Answer: B) 8
Answer: B
Question: What is the greatest integer that will always evenly divide the sum of four consecutive integers?
Options:
A)2
B)3
C)4
D)6
E)12
Rationale: Let the three consecutive even integers be x , x + 4 , x+8 , x+12
Sum = x + x + 4 + x + 8 + x + 12
= 4x+24 = 4(x+6)
Therefore , 4 will always be a factor .
Answer C
Answer: C
Question: For any function Fn(x)=Fn−1(F(x))Fn(x)=Fn−1(F(x)) if for n > 1 also g(x) = 1/x, h(x) = x−−√x and k(x) = x2x2 then what is the value of g(h3(k2(x)))?
Options:
A)1
B)8
C)7
D)6
E)12
Rationale: Given Fn(x)=Fn−1(F(x));Fn(x)=Fn−1(F(x)); g(x) = 1/x; h(x) = x−−√x; k(x) = x−−√x
Then, k(k(x)) = (x2)2=x4(x2)2=x4
And, h3(k2(x))=h(h(h(k2(x))))=h(h(x2))=h(x)=x−−√.h3(k2(x))=h(h(h(k2(x))))=h(h(x2))=h(x)=x.
And, g(h3(k2(x)))=g(x−−√)=1/x−−√.g(h3(k2(x)))=g(x)=1/x.
Hence answer is option (A).
Answer: A
Question: Which of the following must be subtracted from 2^526 so that the resulting integer will be a multiple of 3?
Options:
A)1
B)2
C)3
D)5
E)6
Rationale: 2^12 is definitely NOT a multiple of 3 as 2^12 will only have 2s in it.
Coming back to the question,
2^1 leaves a remainder of 2 when divided by 3
2^2 leaves a remainder of 1 when divided by 3
2^3 leaves a remainder of 2 when divided by 3
2^4 leaves a remainder of 1 when divided by 3... etc. and the cyclicity continues.
Thus, 2^526 will leave a remainder of 1 when divided by 3. Thus you must subtract 1 from 2^526 to make it divisible by 3.
A is thus the correct answer.
Answer: A
Question: A man has some hens and cows. If the number of heads be 48 and the number of feet equals 140, then the number of hens will be:
Options:
A)22
B)23
C)24
D)25
E)26
Rationale: Let the number of hens be x and the number of cows be y.
Then, x + y = 48 .... (i)
and 2x + 4y = 140 x + 2y = 70 .... (ii)
Solving (i) and (ii) we get: x = 26, y = 22.
The required answer = 26.
Option E
Answer: E
Question: In an election between two candidates, the winner has a margin of 10% of the votes polled. If 3000 people change their mind and vote for the loser, the loser would have won by a margin of 10% of the votes polled. Find the total number of votes polled in the election?
Options:
A)23000
B)22000
C)20000
D)25000
E)30000
Rationale: Winner - Looser
55% - 45%
If 3000 people change their mind and vote for the loser:
Winner - Looser
45% - 55%
Thus 3,000 people compose 10% of all voters, which means that the total number of votes is 30,000.
Answer: E.
Answer: E
Question: 28 buckets of water fill a tank when the capacity of each bucket is 13.5 litres. How many buckets will be required to fill the same tank if the capacity of each bucket is 9 litres?
Options:
A)30
B)42
C)60
D)Data inadequate
E)None of these
Rationale: Capacity of the tank = 28 Ã— 13.5= 378 litres
When the capacity of each bucket = 9 litres, then the required no. of buckets
= 378â„9 = 42
Answer B
Answer: B
Question: What is the are of an equilateral triangle of side 16 cm?
Options:
A)64√6 cm2
B)84√3 cm2
C)64√9 cm2
D)64√3 cm2
E)66√3 cm2
Rationale: Area of an equilateral triangle = √3/4 S2
If S = 16, Area of triangle = √3/4 * 16 * 16
= 64√3 cm2;
Answer: D
Answer: D
Question: There is a plane contains 32 points.all the 32 points have equal distance from point x. which of the following is true .
Options:
A)ll 32 points lie in circle
B)the distance from x to all 32 points is less than the distance between each other c. both a and b
C)both a and b
D)32
E)242
Rationale: Option 3
X must be the center of the circle and 32 points are on the circumference. So Option A is correct
Number of diagnols of a regular polygon = n(n−3)2n(n−3)2
So for a polygon of 32 sides, Number of diagnols = 464. Now the minimum distance between any two points = 2πr32=1156r2πr32=1156r
Now total lengh of all the distances from 32 points = 2πr2πr + Sum of the lengths of all the 464 diagnols.
Sum of the lengths of x to all the 32 points = 32 radius = 32r
But the 464 diagnols have 16 diameters connecting 2 oposite points connecting via center. So Sum of the lengths of distances from point to point is clearly greater than sum of the length from x to all 32 ponts. Option B is correct
Answer:C
Answer: C
Question: In a can, there is a mixture of milk and water in the ratio 4 : 5. If it is filled with an additional 8 litres of milk the can would be full and ratio of milk and water would become 6 : 5. Find the capacity of the can?
Options:
A)40
B)44
C)48
D)52
E)None of these
Rationale: Let the capacity of the can be T litres.
Quantity of milk in the mixture before adding milk = 4/9 (T - 8)
After adding milk, quantity of milk in the mixture = 6/11 T.
6T/11 - 8 = 4/9(T - 8)
10T = 792 - 352 => T = 44.
ANSWER:B
Answer: B
Question: John purchased some shirts and trousers for $1100. He paid $550 less for the shirts than he did for the trousers. If he bought 5 shirts and the cost of a shirt is $20 less than that of a trouser, how many trousers did he buy?
Options:
A)4
B)5
C)6
D)7
E)11
Rationale: Given that the total purchase of two items cost 1100.
So the average purchase of one item will cost 1100/2 = 550.
Its given as total shirt cost 100$ less. Hence Total Shirt cost = 550 - 275 and Total trouser cost = 300 + 275
5 shirts = 275$ ==> One shirt = 55$
One trouser = 55 + 20 = 75$
Total trousers = 825 / 75 = 11.
E
Answer: E
Question: If X:Y is 1:5 and Y:Z is 5:7 then X:Z is equal to
Options:
A)1:6
B)1:5
C)1:4
D)1:7
E)1:3
Rationale: The two ratios given are having the same number 5 for Y in both the ratios.
Hence- X:Y = 1:5 Y:Z = 5:7
=> X:Z = 1:7
Answer D
Answer: D
Question: If two integers x,y (x>y) are selected from -5 to 5 (inclusive), how many cases are there?
Options:
A)55
B)60
C)65
D)70
E)75
Rationale: There are 11 integers from -5 to 5 inclusive.
11C2 = 55.
The answer is A.
Answer: A
Question: If 100 microns = 1 decimeter, and 1,000angstroms = 1 decimeter, how many angstroms equal 1 micron?
Options:
A)1.0e-05
B)0.0001
C)10
D)10,000
E)100,000
Rationale: 100 microns = 1 decimeter
1,000 angstroms = 1 decimeter
100 microns = 1,000 angstroms
1 micron = 1,000/100 = 10
Answer : C
Answer: C
Question: A special municipal payroll tax charges not tax on a payroll less than $200,000 and only 0.1% on a company’s payroll above $200,000. If Belfried Industries paid $400 in this special municipal payroll tax, then they must have had a payroll of?
Options:
A)$180,000
B)$202,000
C)$220,000
D)$400,000
E)$600,000
Rationale: ANSWER : E , ( with different approach) :
The 400 paid is 0.1% of the additional amount above 200,000. Let it be X
Now 0.1% of X = 400
Therefore X= 400,000
Total = 200,000 + X= 600,000
Answer: E
Question: A military camp has a food reserve for 250 personnel for 40 days. If after 15 days 50 more personnel are added to the camp, find the number of days the reserve will last for?
Options:
A)20
B)36
C)25
D)42
E)49
Rationale: Explanation:
As the camp has a reserve for 250 personnel that can last for 40 days, after 10 days the reserve left for 250 personnel is for 30 days. Now 50 more personnel are added
in the camp.
Hence, the food reserve for 300 personnel will last for:
250:300::x:30 ……..(it is an indirect proportion as less men means more days)
x = (250*30)/300
x = 25 days
ANSWER C
Answer: C
Question: A man can row with a speed of 15 kmph in still water. If the stream flows at 4 kmph, then the speed in downstream is?
Options:
A)33
B)77
C)20
D)19
E)71
Rationale: M = 15
S = 4
DS = 15 + 4 = 19
Answer: D
Answer: D