divelab/Sys2Bench huggingface dataset:
Question: On 8th Feb, 2005 it was Tuesday. What was the day of the week on 8th Feb, 2004?
Options:
A)Tuesday
B)Monday
C)Sunday
D)Wednesday
E)Friday
Rationale: The year 2004 is a leap year. It has 2 odd days.
The day on 8th Feb, 2004 is 2 days before the day on 8th Feb, 2005.
Hence, this day is Sunday.
Answer: Option C
Answer: C
Question: The function f is defined for all positive integers n by the following rule: f(n) is the number of positive integers each of which is less than n and has no positive factor in common with n other than 1. If p is prime, then f(p) =
Options:
A)P-1
B)P-2
C)(P+1)/2
D)(P-1)/2
E)2
Rationale: This question is wordy and confused me at first. If P is prime it's only factors are P and 1. So no number below it will have a common factor with it except 1. Therefore answer should just be P-1.
ANS = A
Answer: A
Question: Find the principle on a certain sum of money at 5% per annum for 2 2/5 years if the amount being Rs.1680?
Options:
A)1500
B)2777
C)2889
D)27670
E)2771
Rationale: 1680 = P [1 + (5*12/5)/100]
P= 1500.Answer:A
Answer: A
Question: 21 ball numbered 1 to 21. A ballis drawn and then another ball is drawn without replacement.
Options:
A)5/34
B)3/37
C)9/42
D)5/41
E)7/43
Rationale: The probability that first toy shows the even number,
=1021=1021
Since, the toy is not replaced there are now 9 even numbered toys and total 20 toys left.
Hence, probability that second toy shows the even number,
=920=920
Required probability,
=(1021)×(920)=(1021)×(920)
=9/42
C
Answer: C
Question: The area of the square formed on the diagonal of a rectangle as its side is 108 1/3 % more than the area of the rectangle. If the perimeter of the rectangle is 28 units, find the difference between the sides of the rectangle?
Options:
A)8m
B)7m
C)5m
D)2m
E)1m
Rationale: Let the sides of the rectangle be l and b respectively.
From the given data,
(√l2 + b2) = (1 + 108 1/3 %)lb
=> l2 + b2 = (1 + 325/3 * 1/100)lb
= (1 + 13/12)lb
= 25/12 lb
=> (l2 + b2)/lb = 25/12
12(l2 + b2) = 25lb
Adding 24lb on both sides
12l2 + 12b2 + 24lb = 49lb
12(l2 + b2 + 2lb) = 49lb
but 2(l + b) = 28 => l + b = 14
12(l + b)2 = 49lb
=> 12(14)2 = 49lb
=> lb = 48
Since l + b = 14, l = 8 and b = 6
l - b = 8 - 6 =2m.
Answer:D
Answer: D
Question: Find the value of 582964 x 99999 = m?
Options:
A)58210607666
B)58310607896
C)58295817036
D)58591650836
E)58310692816
Rationale: 582964 x 99999 = 582964 x (10000 - 1)
= 582964 x 100000 - 582964 x 1
= 58296400000 - 582964
= 58295817036
C
Answer: C
Question: Maddie has 4 apples, if she give 2 to mike, how many does she have left?
Options:
A)1
B)2
C)3
D)4
E)5
Rationale: 4-2=2
B. 2
Answer: B
Question: The distance of the college and home of Rajeev is 80km. One day he was late by 1 hour than the normal time to leave for the college, so he increased his speed by 4km/h and thus he reached to college at the normal time. What is the changed (or increased) speed of Rajeev?
Options:
A)60 km/h
B)10 km/h
C)60 km/h
D)20 km/h
E)90 km/h
Rationale: Explanation:
Let the normal speed be x km/h, then
x = 16 km/h
(x + 4) = 20 km/h
Therefore increased speed = 20 km/h
Answer: D
Answer: D
Question: loga(ab)=x then logb(ab) is
Options:
A)x/x-1
B)x/x+1
C)x(x-1)
D)x(x+1)
E)x+1
Rationale: loga(ab)=x
log(ab)/log(a)=x
log(b)/log(a)=x-1
log(a)/log(b)=1/x-1
1+log(a)/log(b) = 1+ 1/x-1
logb(ab) = x/x-1
ANSWER A
Answer: A
Question: The greatest possible length which can be used to measure exactly the length 9m, 4m 90cm, 11 m 20 cm is
Options:
A)15 cm
B)25 cm
C)10 cm
D)12 cm
E)43 cm
Rationale: Explanation:
Required Length = H.C.F of 900 cm, 490 cm and 1120 c
= 10 cm. Answer: C
Answer: C
Question: For any positive number x, the function [x] denotes the greatest integer less than or equal to x. For example, [1] = 1, [1.367] = 1 and [1.999] = 1. If k is a positive integer such that k^2 is divisible by 45 and 80, what is the units digit of k^3/4000 ?
Options:
A)0
B)1
C)27
D)54
E)Cannot be determined
Rationale: Factorization of 45 = 3*3*5
Factorization of 80 = 5 * 2^4
Means the smallest value of K is \sqrt{3^2*5*2^4}=3*5*2^2
K^3=3^3*5^3*2^6*X=3^3*2*4000*X where X can be any integer
K^3/4000=3^3*2*X=54X which obviously has different units digit depending on X
ANSWER:D
Answer: D
Question: A 2-year certificate of deposit is purchased for W dollars. If the certificate earns interest at a n annual rate of 6 percent compound quarterly, which of the following represents the value, in dollars, of the certificate at the end of 2 years?
Options:
A)k(1.06)^2
B)k(1.06)^8
C)k(1.015)^2
D)W(1.015)^8
E)k(1.03)^4
Rationale: Annual Rate of interest= 6%
Quaterly rate of interest= 6/4% = 1.5%
Now, periods of compounding in 2 years= 8 (8 quarters)
Thus W(1.015)^8
Answer: D
Answer: D
Question: If difference between compound interest and simple interest on a sum at 10% P.a. for 2 years is Rs.65 then sum is
Options:
A)s.5000
B)s.6500
C)s.5800
D)s.6000
E)s.6200
Rationale: p(r/100)^2=C.I-S.I
P(10/100)^2=65
6500
ANSWER:B
Answer: B
Question: Find the number of zeroes in the expression 15*32*25*22*40*75*98*112*125
Options:
A)9
B)8
C)7
D)6
E)5
Rationale: Maximum power of 5 in the above expression can be calculated like this. Count all the powers of 5 in the above expression. So number of zeroes are 9.
Answer: A
Answer: A
Question: A trader marks his books 10% more than the cost price. If he allows 20% discount, then find his gain or loss percent?
Options:
A)2% profit
B)12% loss
C)4% loss
D)No profit No loss
E)None of these
Rationale: Let CP of an book = 100
MP of an book = 110
Discount 20 % on 110 = 22
SP of the book = 110 - 22 = 88
LOSS = 12%
Answer : B
Answer: B
Question: A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If four marbles are picked at random, what is the probability that none is blue?
Options:
A)33/67
B)33/91
C)33/19
D)33/18
E)33/91
Rationale: Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles. When four marbles are picked at random, then the probability that none is blue is
= ¹²C₄/¹⁵C₄
= (12 * 11 * 10 * 9)/(15 * 14 * 13 * 12)
= 33/91
Answer: B
Answer: B
Question: Robin is traveling from one end of a forest to the other. In order to find her way back, she is leaving morsels of bread in the following pattern: 2 morsels of wheat, 3 morsels of white, and 1 morsel of rye. The pattern repeats after she leaves the morsel of rye. If Robin drops 1994 morsels of bread, what are the last 3 morsels of bread that she drops?
Options:
A)R,w,w
B)wheat − wheat − white
C)white − rye − wheat
D)white − white − white
E)white − white − rye
Rationale: Q is nothing BUT asking about remainder..
total morsels thrown before the pattern is repeated = 2+3+1 = 6..
so REMAINDER when 1994 is div by 6..
1992 is EVEN and also div by 3, so remainder is 2..
Last 3 of morsels are 1992-1993-1994
so he uses the last of morsel of pattern in 1992 two of the first morsels of the pattern in 1993 and 1994, and the pattern is w, w, W, W, W, R..
ans R-w-w
A
Answer: A
Question: George went to the supermarket with a red and a green bag and bought 10 carrots and 6 radishes. On the way back he divided the vegetables between the two bags in such a way that no bag was left empty. What is the maximum number of ways in which he can divide the vegetables between the two bags?
Options:
A)60
B)120
C)600
D)2^16
E)2^16 - 2
Rationale: Each carrot or radish can go into either red or green bag. So for Each vegetable there are 2 ways they can end up.
Like that for 16( 10 carrot + 6 raddish) there are 2^16 ways. But this includes the cases where all the 16 are in either red or green bag.
So answer is 2^16-2.
ANSWER:E
Answer: E
Question: A rectangular of certain dimensions is chopped off from one corner of a larger rectangle as shown. AB = 8 cm and BC = 4 cm. The perimeter of the figure ABCPQRA (in cm) is :
Options:
A)24
B)28
C)36
D)48
E)None of these
Rationale: Solution
Required perimeter = (AB + BC +CP + PQ + QR + RA)
= AB + BC + (CP + QR) + (PQ + RA)
= AB + BC + AB + BC = 2(AB + BC)
= [2(8 + 4 )] cm = 24 cm. Answer A
Answer: A
Question: Sally has a gold credit card with a certain spending limit, and a platinum card with twice the spending limit of the gold card. Currently, she has a balance on her gold card that is 1/3 of the spending limit on that card, and she has a balance on her platinum card that is 1/8 of the spending limit on that card. If Sally transfers the entire balance on her gold card to her platinum card, what portion of her limit on the platinum card will remain unspent?
Options:
A)11/30
B)29/60
C)17/24
D)19/30
E)11/15
Rationale: Let s assume the platinum card spending limit =x
Gold card spending limit will be =x/2
balance on gold card is =x/2*1/3=x/6
Platinum card unspent limit is= x-1/8x=7/8x
So if gold card balance is transferred then the rest unspent will be
7/8x-x/6=17/24x
So the ans is C
Answer: C
Question: At a certain laboratory, chemical substance are identified by an unordered combination of three different colors. If no chemical may be assigned the same three colors as any other, what is the maximum number of substances that can be identified using seven colors?
Options:
A)21
B)35
C)105
D)135
E)210
Rationale: Combinations = N!/[K!(N-K)!] where N is the total number of items and K is the size of the subgroup
Here, we have 7 colors and we're choosing combinations of 3. Plugging those values in, we get...
7!/(3!4!) = (7)(6)(5)/(3)(2)(1) = (7)(5) = 35 combinations of 3 colors.
Final Answer:B
Answer: B
Question: A sum of money at simple interest amounts to Rs. 840 in 3 years and to Rs. 854 in 4 years. The sum is:
Options:
A)647
B)798
C)654
D)847
E)976
Rationale: S.I. for 1 year = Rs. (854 - 840) = Rs. 14.
S.I. for 3 years = Rs.(14 x 3) = Rs. 42.
Principal = Rs. (840 - 42) = Rs. 798.
Answer:B
Answer: B
Question: A hardware store purchased tools at 1/4 of their list price and sold them for 75% of the list price. What is his percent gain?
Options:
A)75
B)125
C)200
D)225
E)300
Rationale: Cost = 1/4 List Price = .25*LSale = .75 List Price = .75*LGain Ratio = (Sale - Cost) / Cost = (.75*L - .25*L) / .25*L = .5*L / .25*L = 2.0Gain Percent = 100 * Gain Ratio = 100 * 2.0 = 200% = Answer C
Answer: C
Question: A football coach must choose 5 freshers from a team of 11 players. How many different ways can the coach choose the freshers?
Options:
A)462
B)650
C)729
D)800
E)890
Rationale: Choose 5 starters from a team of 11 players. Order is not important.
\inline {\color{Black} 11C_{5}}=462
A
Answer: A
Question: The banker's gain on a sum due 6 years hence at 12% per annum is Rs. 756. What is the banker's discount?
Options:
A)1240
B)1120
C)1190
D)1806
E)None of these
Rationale: Explanation :
TD = (BG ×100)/TR = (756×100)/(6×12) = Rs. 1050
BG = BD – TD
=> 756 = BD - 1050
=> BD = 1050+ 756 = 1806 Answer : Option D
Answer: D
Question: The smallest number when increased by " 1 " is exactly divisible by 2, 8, 24, 36 is:
Options:
A)71
B)70
C)72
D)73
E)36
Rationale: LCM = 72
72 - 1 = 71
ANSWER:A
Answer: A
Question: A house wife saved $5 in buying an item on sale. If she spent $48 for the item, approximately how much percent she saved in the transaction?
Options:
A)8%
B)9%
C)10%
D)11%
E)12%
Rationale: Actual price = 48+5 = $53
Saving = 5/48 * 100 = 100/11 = 10% approximately
Answer is C
Answer: C
Question: Income and expenditure of a person are in the ratio 4 : 3. If the income of the person is Rs. 20000, then find his savings?
Options:
A)Rs.3600
B)Rs.3603
C)Rs.3639
D)Rs.3632
E)Rs.5000
Rationale: Let the income and the expenditure of the person be Rs. 4x and Rs. 3x respectively.
Income, 4x = 20000 => x = 5000
Savings = Income - expenditure = 4x - 3x = x
So, savings = Rs.5000
Answer: E
Answer: E
Question: There are 640 students in a school. The ratio of boys and girls in this school is 3:5. Find the total of girls & boys are there in this school?
Options:
A)320
B)345
C)375
D)380
E)400
Rationale: In order to obtain a ratio of boys to girls equal to 3:5, the number of boys has to be written as 3 x and the number of girls as 5 x where x is a common factor to the number of girls and the number of boys. The total number of boys and girls is 640. Hence
3x + 5x = 640
Solve for x
8x = 640
x = 80
Number of boys
3x = 3 × 80 = 240
Number of girls
5x = 5 × 80 = 400
E
Answer: E
Question: Which of the following numbers is the largest?
Options:
A)10000-100
B)2-10000
C)1000-1000
D)5-4000
E)3-2000
Rationale: The choices are a little easier to compare written this way:
(a) (104)100 = 10400 (b) (210)1000 > (103)1000 = 103000 (c) (103)1000 = 103000
(d) (54)1000 < (103)1000 = 103000 (e) (32)1000 < 101000
The answer is clear
correct answer B
Answer: B
Question: Find out the C.I on Rs.5000 at 4% p.a. compound half-yearly for 1 1/2 years
Options:
A)306.09
B)306.07
C)306.04
D)306.03
E)306.01
Rationale: A = 5000(51/50)3
= 5306.04
5000
-----------
306.04
Answer:C
Answer: C
Question: A certain sum of money at simple interest amounted Rs.640 in 10 years at 3% per annum, find the sum?
Options:
A)442.3
B)492.3
C)592.3
D)402.3
E)472.3
Rationale: 640 = P [1 + (10*3)/100]
P = 492.30
ANSWER:B
Answer: B
Question: By selling an article at Rs.800, a shopkeeper makes a profit of 25%. At what price should he sell the article so as to make a loss of 30%?
Options:
A)s.429
B)s.480
C)s.429
D)s.488
E)s.419
Rationale: SP = 800
Profit = 25%
CP = (SP)*[100/(100+P)]
= 800 * [100/125]
= 640
Loss = 30% = 30% of 640 = Rs.192
SP = CP - Loss = 640 - 192
= Rs.448
Answer:D
Answer: D
Question: Of the following, which is greater than 1/2 ?
Indicate ALL such fractions
Options:
A)4/9
B)4/7
C)4/3
D)4/2
E)4/6
Rationale: One way to deal with fractions is to convert them all to decimals.
In this case all you would need to do is to see which is greater than 0.5.
Otherwise to see which is greater than ½, double the numerator and see if the result is greater than the denominator. In B doubling the numerator gives us 8, which is bigger than 7.
Answer: B
Answer: B
Question: In how many different ways can the letters of the word "POLICE" be rearrangement?
Options:
A)710
B)725
C)720
D)770
E)722
Rationale: Option 'C'
The total number of arrangements is
6P6 = 6! = 720
Answer: C
Question: What is the units digit of 16^83 × 13^82 × 11^87?
Options:
A)4
B)5
C)6
D)7
E)8
Rationale: To find : the units digit of 17^83 × 13^82 × 11^87
Let's reduce the clutter and simplify the product
(7^83) (3^82) (1^87)
7 has a cyclicity of 4 : the last digit of any positive power of 7 repeats itself after every 4th power
so 7^5 has the same last digit as 7^1, 7^9, 7^13
Thus , 7^83 has the same last digit as 7^3, 7^7, 7^11 i.e.3
3 has a cyclicity of 4 : exactly the same routine as above
Thus , 3^82 has the same last digit as 3^2, 3^6, 3^10 i.e.9
Any power of 1 will result in1as the last digit
So, product of our last digits = 3 x 9 x 1 = 27....last digit is 6
Correct Option : C
Answer: C
Question: Sandhiya purchased a briefcase with an additional 10% discount on the reduced price after deducting 20% on the labelled price. If the labelled price was Rs. 1400, at which price did she purchase the briefcase?
Options:
A)Rs. 980
B)Rs. 999
C)Rs. 1008
D)Rs. 1120
E)None
Rationale: Solution
C.P. 90% of 80% of Rs. 1400	= Rs.(90/100x80/100x1400)
‹=›Rs. 1008.
Answer C
Answer: C
Question: A wire can be bent in the form of a circle of radius 56cm. If it is bent in the form of a square, then its area will be
Options:
A)7744
B)2388
C)3778
D)2992
E)2888
Rationale: Explanation:
length of wire = {\color{Blue}2 \Pi r}= 2 *(22/7 )*56 = 352 cm
side of the square = 352/4 = 88cm
area of the square = 88*88 = 7744sq cm
Answer: A) 7744
Answer: A
Question: The average of runs of a cricket player of 20 innings was 32. How many runs must he make in his next innings so as to increase his average of runs by 3 ?
Options:
A)95
B)106
C)122
D)116
E)122
Rationale: Average = total runs / no.of innings = 32
So, total = Average x no.of innings = 32 * 20 = 640
Now increase in avg = 4 runs. So, new avg = 32+3 = 35 runs
Total runs = new avg x new no. of innings = 35 * 21 = 735
Runs made in the 11th inning = 735-640 = 95
ANSWER:A
Answer: A
Question: If 36 men can do a piece of work in 25 hours, in how many hours will 13 men
do it ?
Options:
A)65 hours
B)69 hours
C)30 hours
D)62 hours
E)66 hours
Rationale: Let the required number of hours be x. Then,
Less men, More hours	(Indirect Proportion)
13 : 36 : : 25 : x	(13 x x) = (36 x 25)	(36 x 25)/13= 69
Hence, 15 men can do it in 60 hours.
Answer is B.
Answer: B
Question: If one of the followings is the product of the two 3-digit integers 8L7 and 6K9 (K and L denote the tens digit of the respective integers), then that product must be
Options:
A)511,913
B) 478,823
C) 531,875
D) 538,424
E) 569,114
Rationale: To know the unit digit you can multiply both digit number: 7 x 9 = 63
This eliminates C, D, and E, because the number must end with a 3
To know the answer you can multiply both the thousand digit giving 8 x 6 = 48 so the number must be bigger than 480.000.
So the answer is A
Answer: A
Question: The total of 344 of 20 paise and 25 paise make a sum of Rs. 71. The no of 20 paise coins is
Options:
A)238
B)277
C)278
D)200
E)300
Rationale: Explanation:
Let the number of 20 paise coins be x. Then the no of 25 paise coins = (344 - x).
0.20 * (x) + 0.25 (344 - x) = 71 => x = 300..
Answer: E) 300
Answer: E
Question: If a = 105 and a^3 = 21 × 25 × 45 × z, what is the value of z?
Options:
A)35
B)42
C)45
D)49
E)54
Rationale: a=105 = 3* 5 *7
a^3 = 21 × 25 × 45 × z
=> a^3 = (7*3) x (5*5) x ( 3^2 * 5) x z
=> a^3 = 3^3 * 5^3 * 7 x z
=>( 3* 5 *7) ^3 = 3^3 * 5^3 * 7 x z
z = 7^2 = 49
Answer D
Answer: D
Question: Two trains each 250 m in length are running on the same parallel lines in opposite directions with the speed of 80 kmph and 60 kmph respectively. In what time will they cross each other completely?
Options:
A)15 sec
B)19 sec
C)12 sec
D)12.9 sec
E)11 sec
Rationale: Explanation:
D = 250 m + 250 m = 500 m
RS = 80 + 60 = 140 * 5/18 = 350/9
T = 500 * 9/350 = 12.9 sec
Answer: Option D
Answer: D
Question: Which number is the odd one out ?
9654 4832 5945 7642 7963 8216 3649
Options:
A)3649
B)9654
C)5945
D)7963
E)8216
Rationale: The product of first two digits in a number equals the last two digits, except in 3649. Hence, it is the odd one.
The answer is 3649.
ANSWER:A
Answer: A
Question: 60% of a number is added to 120, the result is the same number. Find the number?
Options:
A)300
B)388
C)776
D)2991
E)212
Rationale: (60/100) * X + 120 = X
2X = 600
X = 300
Answer: A
Answer: A
Question: How many of the following numbers are divisible by 132 ?
264, 396, 462, 792, 968, 2178, 5184, 6336
Options:
A)4
B)5
C)6
D)7
E)3
Rationale: Explanation:
132 = 4 x 3 x 11
So, if the number divisible by all the three number 4, 3 and 11, then the number is divisible by 132 also.
264 -> 11,3,4 (/)
396 ->11,3,4 (/)
462 ->11,3 (X)
792 ->11,3,4 (/)
968 ->11,4 (X)
2178 ->11,3 (X)
5184 -> 3,4 (X)
6336 ->11,3,4 (/)
Therefore the following numbers are divisible by 132 : 264, 396, 792 and 6336.
Required number of number = 4.
ANSWER IS A
Answer: A
Question: In a particular state, 70% of the counties received some rain on Monday, and 55% of the counties received some rain on Tuesday. No rain fell either day in 35% of the counties in the state. What percent of the counties received some rain on Monday and Tuesday?
Options:
A)20%
B)40%
C)50%
D)60%
E)70%
Rationale: 70 + 55 + 35 = 160%
The number is 60% above 100% because 60% of the counties were counted twice.
The answer is D.
Answer: D
Question: Insert the missing number.
2, 6, 12, 20, 30, 42, 56,72, 90, 110 (....)
Options:
A)22
B)132
C)72
D)66
E)19
Rationale: Explanation:
The pattern is 1 x 2, 2 x 3, 3 x 4, 4 x 5, 5 x 6, 6 x 7, 7 x 8,8 x 9, 9 x 10,10 x 11.
So, the next number is 11 x 12 = 132.
Answer: B) 132
Answer: B
Question: Given that 29a031 × 342 = 100900b02 where a and b denote two missing
digits, what is the value of a + b ?
Options:
A)7
B)8
C)9
D)10
E)11
Rationale: Recall the tests for divisibility by 9 and by 11. Since 342 is divisible by 9, the number
100900b02 is as well. So b has to be 6. But then 100900b02 is divisible by 11. Since 342 is
not divisible by 11, we deduce 29a031 must be divisible by 11. So a has to be 5, and a + b = 11.
correct answer E
Answer: E
Question: If 0.75 : x : : 5 : 8, then x is equal to
Options:
A)1.12
B)1.25
C)1.20
D)1.3
E)None
Rationale: Sol.
(x×5) = (0.75×8) ⇒ x = 6/5 = 1.20.
Answer C
Answer: C
Question: There are 14 slate rocks, 20 pumice rocks, and 10 granite rocks randomly distributed in a certain field. If 2 rocks are chosen at random and without replacement, what is the probability that both rocks will be slate rocks?
Options:
A)1/5
B)11/22
C)81/724
D)91/946
E)101/987
Rationale: 14/44*13/43 = 91/946
The answer is D.
Answer: D
Question: What Should come in place of the question mark in the following number series ?
Q. 5 8 10 12 16 (?)
Options:
A)15
B)18
C)17
D)21
E)23
Rationale: Explanation :
The series is 5, and 5 + odd prime numbers 5 + 3 = 8, 5 + 5 = 10, 5 + 7 = 12, 5+ 11 = 16, 5 + 13 = 18
Answer : Option B
Answer: B
Question: A furniture dealer purchased a desk for $180 and then set the selling price equal to the purchase price plus a markup that was 40% of the selling price. If the dealer sold the desk at the selling price, what was the amount of the dealer's gross profit from the purchase and the sale of the desk?
Options:
A)$40
B)$60
C)$80
D)$120
E)$100
Rationale: Purchase price = 180
Selling price = x
180 + 0.4*x = x
0.6*x = 180
x = 300
Profit = 300 - 180 = 120
ANSWER:D
Answer: D
Question: Some pens are divided among A, B, C and D. A gets twice the number of pens that B gets. C gets the same number of pens as D gets. If A gets 25 pens more than D and the ratio of the number of pens that B and C get is 2:3, then find the number of pens that D gets?
Options:
A)45 pens
B)65 pens
C)75 pens
D)95 pens
E)14 pens
Rationale: Let the number of pens that A, B, C and D get be a, b, c and d respectively.
a:b = 2:1
a = c + 25
b:c = 2:3
a:b:c:d = 4:2:3:3
a, d get 4p, 3p pens
=> 4p - 3p = 25 => p = 25
=> D gets 3p = 3 * 25 = 75 pens.
Answer: C
Answer: C
Question: A thief goes away with a SANTRO car at a speed of 40 kmph. The theft has been discovered after half an hour and the owner sets off in a bike at 50 kmph when will the owner over take the thief from the start?
Options:
A)2 hours
B)8 hours
C)6 hours
D)1 hours
E)9 hours
Rationale: |-----------20--------------------|
50 40
D = 20
RS = 50 – 40 = 10
T = 20/10 = 2 hours
Answer:A
Answer: A
Question: The game of blackjack is played with a deck consisting of 13 cards (one of each of the numbers 2-10, one jack, one queen, one king, and one of ace) in each of four suits: clubs, diamonds, hearts, and spades.
In a game of blackjack, if your first card is a spade, what are the odds that it is a jack?
Options:
A)1/52
B)1/13
C)5/13
D)1/4
E)1/26
Rationale: The question should ask about the probability not the odds.
There are 13 spades, the probability that the spade we already have is a jack is therefore 1/13.
Answer: B.
Answer: B
Question: A certain store sold pens for $0.35 each and pencils for $0.25 each. If a customer purchased both pens and pencils from the store for a total of $3.50, what total number of pens and pencils did the customer purchase?
Options:
A)8
B)9
C)10
D)11
E)12
Rationale: Answer: Algebraically, the question looks like this: 2.5 = 0.35x + 0.25y There are six possible numbers of pens that fit that requirement:
1 pen: $0.35
2 pens: $0.70
3 pens: $1.05
4 pens: $1.40
5 pens: $1.75 balance can fetch 7 pencils for $0.25 each. That's 5 pens and 7 pencils for a total of 12 pens and pencils. Choice (E) is correct.
Answer: E
Question: The length of a rectangular plot is thrice its breadth. If the area of the rectangular plot is 2028 sq m, then what is the breadth of the rectangular plot?
Options:
A)11
B)17
C)26
D)101
E)1322
Rationale: Let the breadth of the plot be b m.
Length of the plot = 3 b m
(3b)(b) = 2028
3b2 = 2028
b2 = 676 = 26 (b > 0)
b = 26 m.
Answer: C
Answer: C