divelab/Sys2Bench huggingface dataset:
Question: Andrew went to a shop and bought things worth Rs. 25, out of which 30 Paise went on sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax free items?
Options:
A)18
B)19
C)19.7
D)21
E)21.3
Rationale: Total cost of the items he purchased = Rs.25
Given that out of this Rs.25, 30 Paise is given as tax
=> Total tax incurred = 30 Paise = Rs.30/100
Let the cost of the tax free items = x
Given that tax rate = 6%
∴ (25−30/100−x)6/100 = 30/100
⇒ 6(25 −0.3 −x) = 30
⇒ (25 − 0.3 − x) = 5
⇒ x = 25 − 0.3 − 5 = 19.7
C
Answer: C
Question: B invested $4000 in a business and C invested $3000 in a business. At the end of the year they got $14000 as the profit. Find their share?
Options:
A)$8000,$6000
B)$7000,$5000
C)$6000,$4000
D)$6000,$8000
E)$5000,$6000
Rationale: B:C = 4000:3000
A:B = 4:3
A's share = 14000*4/7 = $8000
B's share = 14000*3/7 = $6000
Answer is A
Answer: A
Question: 40% of a number is more than 20% of 650 by 190. Find the number?
Options:
A)997
B)127
C)800
D)128
E)189
Rationale: (40/100) * X – (20/100) * 650 = 190
2/5 X = 320
X = 800
Answer: C
Answer: C
Question: In expressing a length 81.475 km as nearly as possible with three significant digits, find the percentage error?
Options:
A)0.075%
B)0.156%
C)0.031%
D)0.048%
E)0.152%
Rationale: Error = 81.5-81.475 = 0.028
Required percentage = (0.028/81.475)*100 = 0.031%
Answer is C
Answer: C
Question: A person can row at 9 kmph and still water. He takes 7 1/2 hours to row from A to B and back. What is the distance between A and B if the speed of the stream is 1 kmph?
Options:
A)33
B)28
C)29
D)54
E)20
Rationale: Let the distance between A and B be x km.
Total time = x/(9 + 1) + x/(9 - 1) = 7.5
=> x/10 + x/8 = 15/2 => (4x + 5x)/40 = 15/2 => x
= 33 km.
Answer:A
Answer: A
Question: Set A contains all the even numbers between 8 and 50 inclusive. Set B contains all the even numbers between 108 and 150 inclusive. What is the difference between the sum of elements of set B and the sum of the elements of set A?
Options:
A)2200
B)2550
C)5050
D)6275
E)11325
Rationale: Set A contains 8, 10, 12... 50
Set B contains 108 , 110 , 112 ... 150
Number of terms in each set = 22
Difference between corresponding terms in set A and B = 100
Difference between Sum of set B and set A = 100*22 = 2200
Answer A
Answer: A
Question: The average of 10 numbers is 23. If each number is increased by 6, what will the new average be?
Options:
A)36
B)29
C)72
D)29
E)22
Rationale: Sum of the 10 numbers = 230
If each number is increased by 6, the total increase =
6 * 10 = 60
The new sum = 230 + 60 = 290 The new average = 290/10
= 29.
Answer:B
Answer: B
Question: Little Praveen had $50.50. He spent $12.25 on sweets and gave same money to his two friends and the amount left with him is $31.25. Find how much he spent to two of his friends?
Options:
A)$ 16.65
B)$ 18.65
C)$ 19.25
D)$ 16.55
E)$ 17.65
Rationale: Praveen spent and gave to his two friends a total of
12.25 + 2x= $4.65, x is the amount spent to one friend.
Money left
50.50 -2x = $31.85. Then 2x=$18.65.
correct answer is B) $ 18.65
Answer: B
Question: There are six leopards and one sheep.
Leopard can eat sheep but since as the land is magical, the leopards who eats the sheep , turns into sheep and then can be eaten by the remaining leopard(s).
If we leave them for some time then how many sheep and leopard will be there , when we come back ?
Options:
A)7 leopard and 3 sheep
B)4 leopard and 7 sheep
C)6 leopard and 4 sheep
D)5 leopard and 1 sheep
E)2 leopard and 5 sheep
Rationale: D
5 leopard and 1 sheep
since all animal are rational , once 1st leopard eats the sheep all the rest of leopard would know about this.
Answer: D
Question: At 1:00 pm, there were 10.0 grams of bacteria. The bacteria increased to x grams at 4:00 pm, and 19.6 grams at 7:00 pm. If the amount of bacteria present increased by the same fraction during each of the 3-hour periods, how many grams of bacteria were present at 4:00 pm?
Options:
A)13.7
B)14.0
C)14.3
D)14.6
E)14.9
Rationale: Let x be the factor by which the bacteria increases every three hours.
At 4:00 pm, the amount of bacteria was 10x and at 7:00 pm it was 10x^2.
10x^2 = 19.6
x^2=1.96
x=1.4
At 4:00 pm, the amount of bacteria was 10(1.4)=14 grams.
The answer is B.
Answer: B
Question: Over the course of a year, a certain microbrewery increased its beer output by 70 percent. At the same time, it decreased its total working hours by 20 percent. By what percent did this factory increase its output per hour?
Options:
A)50%
B)90%
C)112.5%
D)210%
E)212.5%
Rationale: Let's take the original output to be 100 and the new output to be 170% or 170.
Let's take the original work hours to be 100 hours and the new work hours to be 80% or 80 hours.
The old output per work hour = 100/100 hours or 1.
The new output per work hour = 170/80 or 2.125. So the resulting increase is actually new minus old or 1.125 or 112.5%.
Choice C
Answer: C
Question: If it is possible to from a word with the first, fourth, seventh and eleventh letters in the word
'SPHERVLVODS' write the second letter of thet word. Otherwise, X is the answer.?
Options:
A)T
B)E
C)R
D)HG
E)K
Rationale: The first, fourth, seventh and eleventh letters of the word 'SPHERVLVODS'
The word formed is LESS
The second letter is E.
Answer: Option 'B'
Answer: B
Question: In a camp, there is a meal for 100 men or 200 children. If 130 children have taken the meal, how many men will be catered to with remaining meal?
Options:
A)20
B)30
C)35
D)10
E)40
Rationale: There is a meal for 200 children. 130 children have taken the meal.
Remaining meal is to be catered to 70 children.
Now, 200 children 100 men.
70 children (100/200)	* 70 = 35 men
Answer is C.
Answer: C
Question: A carpenter is building a frame for a wall painting. The painting is in the shape of a rectangle. If the sides of the rectangle are in the ratio of 3:2 and the shorter side has a length of 19 inches, how many inches of framing material does the carpenter need to frame the painting?
Options:
A)12
B)22 1/2
C)37 1/2
D)50
E)25
Rationale: (19/2) ( 2+3) * 2 = 25=E
Answer: E
Question: 15 men can complete a work in 10 days while 20 boys can complete the same work in 15 days .How many days will 10 men and 10 boys together take to complete the same work
Options:
A)10 days
B)11 days
C)12 days
D)13 days
E)None of these
Rationale: Solution:
Work done by one man in one day=1/(15*10)
Work done by one boy in one day=1/(20*15)
Work done by 10 men and 10 boys in one day=10[ 1/(15*10) + 1/(20*15)]
Days taken=1/Work done by 10 men and 10 boys in one day
=10 days
Answer A
Answer: A
Question: A code is to be made by arranging 8 letters. Three of the letters used will be the letter A, two of the letters used will be the letter B, two of the letters used will be the letter C, and one of the letters used will be the letter D. If there is only one way to present each letter, how many different codes are possible?
Options:
A)42
B)210
C)420
D)840
E)6,720
Rationale: we have 8 letters out of which 3 are of one kind, 1 are of another kind..
so total ways = 8!/3!1!=6720
ans E
Answer: E
Question: If pq represents a positive two digit number, where p and q are single digit integers, which of the following cannot be true?
Options:
A)p+q =9
B)(p)(q)=9
C)p-q = 9
D)q-p= 9
E)p/q = 9
Rationale: (A) pq = 45 or 63 or 27
(B) pq = 33 or 19
(C) 90
(D) impossible
(E) pq = 91
(D) is impossible because 09 is not a valid two digit number --- if there's a zero in the ten's place, that's just 9, a single digit number. Therefore, no valid two digit number would satisfy (D).
ans D
Answer: D
Question: Two pipes can fill a tank in 18 minutes and 20 minutes. An outlet pipe can empty the tank in 45 minutes. If all the pipes are opened when the tank is empty, then how many minutes will it take to fill the tank?
Options:
A)1/15
B)1/16
C)1/11
D)1/10
E)1/12
Rationale: Part of the filled by all the three pipes in one minute
= 1/18 + 1/21 - 1/45 = 1/12
So, the tank becomes full in 12 minutes.
Answer:E
Answer: E
Question: Roy was suffering from severe headaches. He went to see his doctor and the doctor gave him five tablets asking him to take one tablet every 15 minutes.
How much time will it take Roy to consume all the five tablets?
Options:
A)60 minutes
B)65 minutes
C)50 minutes
D)45 minutes
E)55 minutes
Rationale: A
60 minutes
Roy will be able to consume all the five tablets in an hour.
Tablet 1 will be taken in 0 min.
Tablet 2 will be taken in 15 min.
Tablet 3 will be taken in 30 min.
Tablet 4 will be taken in 45 min.
Tablet 5 will be taken in 60 min.
Answer: A
Question: A single discount equivalent to the discount series of 20%, 10% and 5% is?
Options:
A)31.9
B)31.1
C)31.6
D)31.2
E)31.5
Rationale: :
100*(80/100)*(90/100)*(95/100) = 68.4
100 - 68.4 = 31.6
Answer: C
Answer: C
Question: Eight mobsters have arrived at the theater for the premiere of the film “Goodbuddies.” One of the mobsters, Frankie, is an informer, and he's afraid that another member of his crew, Joey, is on to him. Frankie, wanting to keep Joey in his sights, insists upon standing behind Joey in line at the concession stand, though not necessarily right behind him. How many ways can the six arrange themselves in line such that Frankie’s requirement is satisfied?
Options:
A)20160
B)2400
C)12000
D)36002
E)7200
Rationale: Arrangement of 8=8!. In half of the cases Frankie will be behind Joey and in half of the cases Joey will be behind Frankie (as probability doesn't favor any of them). So, the needed arrangement is 8!/2=20160.
Answer: A
Answer: A
Question: Line Q has the equation 5y – 3x = 90. If Line S is perpendicular to Q, has an integer for its y-intercept, and intersects Q in the second quadrant, then how many possible Line S’s exist? (Note: Intersections on one of the axes do not count.)
Options:
A)58
B)61
C)64
D)67
E)70
Rationale: 5y - 3x = 90 and so y = 3x/5 + 18
When x = 0, then y = 18.
When y = 0, then x = -30
The slope is 3/5, so the slope of line S is -5/3.
Through the point (-30, 0), 0 = -5(-30)/3 + c
The y-intercept is c = -50.
Thus the perpendicular line S can have y-intercepts from -49 up to 17.
The number of possible lines is 49 + 17 + 1 = 67
The answer is D.
Answer: D
Question: If there is an equal probability of a child being born a boy or a girl, what is the probability that a couple who have 5 children have two children of the same sex and one of the opposite sex?
Options:
A)1/3
B)2/3
C)1/4
D)5/16
E)3/5
Rationale: No of ways of selecting a gender - 2C1
No of ways of selecting any 2 children out of 5 = 5C2
Total possible outcomes - 2^5 (each child can be either a girl or a boy)
Probability=2C1*5C2/2^5= 2*5/2*2*2*2*2=10/32=5/16
Ans=D
Answer: D
Question: If r and y are different prime numbers less than ten, what must be true about the sum of r and y?
Options:
A)the sum is even
B)the sum is odd
C)the sum is less than ten
D)the sum is greater than ten
E)the sum is less than 13
Rationale: This has to be solved by checking for each option:
Prime numbers less that 10 = 2, 3, 5, 7
A. the sum is even
May or may not be true. r = 3, y, = 5 -> True.
r = 2, y = 3 - True
B. the sum is odd
May or may not be true. r = 3, y, = 5 -> False.
r = 2, y = 3 - True
C. the sum is less than ten
May or may not be true r= 5, y = 7, Sum = 12
r = 2, y = 3. Sum = 5
D. the sum is greater than ten
May or may not be true r= 5, y = 7, Sum = 12
r = 2, y = 3. Sum = 5
E. the sum is less than 13
This will always be true.
Maximum sum = 7 + 5 = 12.
This is always less than 13.
Correct Option: E
Answer: E
Question: The total circumference of two circles is 25. If the first circle has a circumference that is exactly twice the circumference of the second circle, then what is the approximate sum of their two radii?
Options:
A)5.7
B)6.0
C)4.0
D)9.7
E)18.0
Rationale: Let r= Radius of smaller circle. Let R = Radius of larger circle
Therefore:
2πr + 2πR = 25
where 2r = R
Thus:
2πr + 4πr = 25
6πr = 25
r = approx 1.33
πR + 2Rπ = 25
3πR = 25
R = approx 2.65
r + R = approx 3.98 = 4.0
Answer : C
Answer: C
Question: The salary of a person was reduced by 14%. By what percent should his reduced salary be raised so as to bring it at par with his original salary?
Options:
A)10%
B)16.3%
C)13.7%
D)15.1%
E)12.3%
Rationale: Let the original salary be $100
New salary = $86
Increase on 86=14
Increase on 100 = 14/86* 100 = 16.3%
Answer is B
Answer: B
Question: A and B can complete a work in 30days and 15day. They started doing the work together but after 5days B had to leave and A alone completed the remaining work. The whole work was completed in?
Options:
A)10days
B)12days
C)20days
D)18days
E)25days
Rationale: A+B 1day work = 1/30 + 1/15 = 1/10
Work done by A and B in 10days = 1/10 * 5 = 1/2
Remaining work = 1-1/2 = 1/2
Now 1/30 work is done by A in 1day
1/2 work will be done by A in 30*1/2 = 15days
Total time taken = 15+5 = 20days
Answer is C
Answer: C
Question: Let a1, a2, . . . , ar be r not necessarily distinct positive integers such that
(x + a1)(x + a2) · · · (x + ar) = xr + 230xr−1 + · · · + 2007,
where each missing term on the right has degree between 1 and r − 2
inclusive. What is the value of r ?
Options:
A)4
B)12
C)63
D)669
E)2007
Rationale: The conditions imply a1 + a2 + · · · + ar = 230 and a1a2 · · · ar = 2007. One checks that
2007 = 32 · 223, where 223 is prime. We deduce that some aj is 223, two aj’s are 3, and the
remaining aj’s are 1. Since their sum is 230 = 223 + 3 + 3 + 1, we obtain r = 4.
correct answer A
Answer: A
Question: In a school with 652 students, the average age of the boys is 12 years and that of the girls is 11 years. If the average age of the school is 11 years 9 months, then the number of girls in the school is
Options:
A)150
B)200
C)250
D)163
E)None
Rationale: Sol.
Let the number of grils be x.
Then, number of boys = (652 - x).
Then, (11 3/4 × 652)
⇔ 11x + 12(652 - x) ⇔ x = 7824 - 7661 ⇔ 163.
Answer D
Answer: D
Question: Find the annual income derived by investing $ 6800 in 30% stock at 136.
Options:
A)550
B)1500
C)250
D)1300
E)400
Rationale: By investing $ 136, income obtained = $ 30.
By investing $ 6800, income obtained = $ [(30/136)*6800] = $ 1500.
Answer B.
Answer: B
Question: A sum of money at simple interest amounts to $ 680 in 3 years and to $710 in 4 years. The sum is:
Options:
A)$153
B)$698
C)$590
D)$549
E)$675
Rationale: C
$590
S.I. for 1 year = $(710- 680) = $30.
S.I. for 3 years = $(30 x 3) = $90.
Principal = $(680 - 90) = $590.
Answer: C
Question: Which number can we add to 987654 to get a number exactly divisible by 456?
Options:
A)18
B)24
C)30
D)36
E)42
Rationale: 987654 / 456 = 2165 with a remainder of 414.
We need to add 456 - 414 = 42
The answer is E.
Answer: E
Question: A car covers a distance of 984 km in 6 ½ hours. Find its speed?
Options:
A)104 kmph
B)187 kmph
C)164 kmph
D)175 kmph
E)106 kmph
Rationale: 984/6
= 164 kmph
Answer: C
Answer: C
Question: A straight line is formed using two points A(3,3) and B(6,6). Another point P(x,y) lies between A and B such that AP/BP = 9. What are the coordinates of P?
Options:
A)(57/10, 57/10)
B)(3/10, 3/10)
C)(63/10, 63/10)
D)(27/10, 27/10)
E)(9/10, 9/10)
Rationale: The equation of the straight line is y = x, so the x- and y-coordinates of P are the same.
x = 3 + (6-3)*(9/10) = 3 + 27/10 = 57/10 = y
The answer is A.
Answer: A
Question: At a certain fruit stand, the price of each apple is 40 cents and the price of each orange is 60 cents. Mary selects a total of 10 apples and oranges from the fruit stand, and the average (arithmetic mean) price of the 10 pieces of fruit is 48 cents. How many oranges must Mary put back so that the average price of the pieces of fruit that she keeps is 45 cents?
Options:
A)1
B)2
C)3
D)4
E)5
Rationale: Let number of Apples = A
number of oranges = B
A+B=10 --- 1
.48 =(.4A + .6 B)/10
=> 48 = 4A + 6B ----2
Solving 1 and 2, we get
A= 6
B= 4
Let the number of oranges put back = C
45*(10-c) = 40*6 + 60(4-C)
=> C= 2
Answer B
Answer: B
Question: If the average (arithmetic mean) of five consecutive negative integers is 10k – 1, what is the difference between the greatest and least of the five integers?
Options:
A)4K
B)4k^2 -4k
C)4-4k
D)4
E)4k+4
Rationale: (n-2 + n - 1 + n + n + 1 + n + 2)/5 = 10k - 1
=> n = 50k - 5
Greatest = n + 2 = 50k - 5 + 2 = 50k - 3
Least = n - 2 = 50k - 5 - 2
=> Difference = 50k - 3 - (50k - 7)
= 4
Answer - D
Answer: D
Question: In some code, letters, a, b, c, d and e represent numbers 2, 4, 5, 6 and 10. However, we don’t know which letter represent which number.
Consider the following relationships:
i. a + c = e
ii. b – d = d
iii. e + a = b
Options:
A)b = 4, d = 2
B)a = 4, e = 6
C)b = 6, e = 2
D)a = 4, c = 6
E)None
Rationale: Explanation :
From the given equations, we see that , b=10 and d=5.
Now 'a' and 'c' must be 4 and 2 respectively.
So, e = 6.
Answer : B
Answer: B
Question: The cost price of a radio is Rs.2400 and it was sold for Rs.2100, find the loss %?
Options:
A)12.5%
B)11%
C)13%
D)15%
E)12.8%
Rationale: 2400 ---- 300
100 ---- ? => 12.5%
Answer:A
Answer: A
Question: 6 men and 8 women can complete a work in 10 days. 26 men and 48 women can finish the same work in 2 days. 15 men and 20 women can do the same work in - days.
Options:
A)4 days
B)6 days
C)2 days
D)8 days
E)10 days
Rationale: Explanation :
Let work done by 1 man in 1 day = m and work done by 1 woman in 1 day = b
Work done by 6 men and 8 women in 1 day = 1/10
=> 6m + 8b = 1/10
=> 60m + 80b = 1 --- (1)
Work done by 26 men and 48 women in 1 day = 1/2
=> 26m + 48b = Â½
=> 52m + 96b = 1--- (2)
Solving equation 1 and equation 2. We get m = 1/100 and b = 1/200
Work done by 15 men and 20 women in 1 day
= 15/100 + 20/200 =1/4
=> Time taken by 15 men and 20 women in doing the work = 4 days
Answer IS A
Answer: A
Question: A fruit shop on its opening in a day, had 400 mangoes and 600 oranges. If 57 percent of the mangoes and 42 percent of the oranges got sold during the day, what percent of the total number of planted fruits were sold ?
Options:
A) 45.5%
B) 46.5%
C) 48.0%
D) 49.5%
E) 51.0%
Rationale: 57% of 400 mangoes sold, hence 0.47*200 = 228 sold.
42% of 600 oranges sold, hence 0.42*600 = 252 sold.
Thus (germinated)/(total) = (228 + 252)/(400 + 600) = 480/1000 = 48% fruits sold.
Answer: C.
Answer: C
Question: Walking 7/6 of his usual rate, a boy reaches his school 6 min early. Find his usual time to reach the school?
Options:
A)22
B)28
C)99
D)42
E)66
Rationale: Speed Ratio = 1:7/6 = 6:7
Time Ratio = 7:6
1 -------- 7
6 --------- ?
=42 m
Answer:D
Answer: D
Question: Which of the following statements is definitely true , if A is the brother of B and C. Q is B's son and R is A's father.
Options:
A)A is B's son
B)A is C's son
C)A is B's nephew
D)A is B's niece
E)A is Q's uncle
Rationale: Explanation:
A, B, C are brothers, so since Q is B's son, A is his uncle
Answer E
Answer: E
Question: A shopkeeper sold an article for Rs 2524.36. Approximately what was his profit percent if the cost price of the article was Rs 2400
Options:
A)4%
B)5%
C)6%
D)7%
E)8%
Rationale: Explanation:
Gain % = (125.36*100/2400) = 5.2 % = 5% approx
Option B
Answer: B
Question: Sheela deposits Rs. 3800 in bank savings account. If this is 32% of her monthly income. What is her monthly income in?
Options:
A)22000
B)20000
C)11875
D)12340
E)None of these
Rationale: Explanation :
32% of income = Rs. 3800
100% of income = 3800 X 100/32 = Rs. 11875
Answer : C
Answer: C
Question: How many prime numbers between 1 and 100 are factors of 210?
Options:
A)5
B)4
C)3
D)2
E)1
Rationale: factor of 210= 2*3*5*7--- 4 prime numbers
B
Answer: B
Question: Line m lies in the xy-plane. The y-intercept of line m is -2, and line m passes through the midpoint of the line segment whose endpoints are (2, 8) and (8,-2). What is the slope of line m?
Options:
A)-2
B)-1
C)0
D)1
E)2
Rationale: The midpoint of (2,8) and (8,-2) is (5,3).
The slope of a line through (0,-2) and (5,3) is (3-(-2))/(5-0) = 5/5 = 1
The answer is D.
Answer: D
Question: If n is a 36-digit positive integer, all of whose digits are the same, which of the following must be true?
I. n is divisible by 3
II. n is divisible by 9
III. n is divisible by 36
Options:
A)I only
B)I and II only
C)I ,II and III only
D)II and III only
E)III
Rationale: Rule for divisibility by 3: The sum of the digits of the number should be multiple of 3
Rule for divisibility by 9: The sum of the nos digits of the number should be divisible by 9 or the number should be divisible by 3 two times.
Rules for divisibility by 36: The sum of the digits should a multiple of 36
Consider no 11111111...36 times = The sum 36*1=36----> divisbible by 3,9 and 36
consider number to be 222....36 times, then sum of the no. 36*2=72 divisibly by 3,9 and 36
So why so because when you sum the numbers either you can add the digits 36 times or multiply the digit *36..
Note that since 36 is divisble by 36,9 and 3 and thus the sum of the nos will be divisible by all the nos.
Ans is C
Answer: C
Question: The second largest prime number is?
Options:
A)1
B)2
C)3
D)4
E)5
Rationale: The second largest prime number is 3.
C)
Answer: C
Question: If there are 4 peanuts in a box and Mary puts 2 more peanuts inside, how many peanuts are in the box?
Options:
A)8
B)9
C)6
D)11
E)12
Rationale: 2+4=6
correct answer is C)6
Answer: C
Question: Two-third of a positive number and 16/216 of its reciprocal are equal. The number is:
Options:
A)5/12
B)12/5
C)1/3
D)144/25
E)146/25
Rationale: Let the number be x. Then,
2/3 x = 16/216 * 1/x
x2 = 16/216 * 3/2 = 16/144 = 1/9
x = 1/3
ANSWER:C
Answer: C
Question: A certain car increased its average speed by 5 miles per hour in each successive 5-minute interval after the first interval. If in the first 5-minute interval its average speed was 26 miles per hour, how many miles did the car travel in the third 5-minute interval?
Options:
A)1.0
B)1.5
C)2.0
D)2.5
E)3.0
Rationale: In the third time interval the average speed of the car was 22+5+5=36 miles per hour;
In 5 minutes (1/12 hour) at that speed car would travel 36*1/12=3 miles.
Answer: E.
Answer: E
Question: A certain business produced x rakes each month form November through February and shipped x/2 rakes at the beginning of each month from March through October. The business paid no storage costs for the rakes from November through February, but it paid storage costs of $0.50 per rake each month from March through October for the rakes that had not been shipped. In terms of x, what was the total storage cost, in dollars, that the business paid for the rakes for the 12 months form November through October?
Options:
A)0.40x
B)1.20x
C)1.40x
D)1.60x
E)3.20x
Rationale: because we have a total of 4X
Also from Mar- Oct the rakes will be deducted by 1/8 X
so
In Apr they pay for the storage 0.5 * 4X * 7/8
In May they pay for the storage 0.5 * 4X * 6/8
In Jun they pay for the storage 0.5 * 4X * 5/8
In Jul they pay for the storage 0.5 * 4X * 4/8
In Aug they pay for the storage 0.5 * 4X * 3/8
In Sep they pay for the storage 0.5 * 4X * 2/8
In Oct they pay for the storage 0.5 * 4X * 1/8
total = 0.5 * 4X * 1/8 * [ 1+2+3+4+5+6+7]
= 0.5 * X/2 * (28)
= 7.0X
D
Answer: D
Question: There are 27 bicycles and 10 tricycles in the storage area at Stanley's flat building. Each bicycle has 2 wheels and each tricycle has 3 wheels. How many wheels are there in all?
Options:
A)84
B)67
C)39
D)21
E)11
Rationale: Step 1: Find the number of bicycle wheels.
2 × 27 = 54
Step 2: Find the number of tricycle wheels.
3 × 10 = 30
Step 3: Find the total number of wheels.
54 + 30 = 84
There are 84 wheels in all.
Answer is A.
Answer: A
Question: A grocer has a sale of Rs. 5400, Rs. 9000, Rs. 6300, Rs. 7200 and Rs.4500 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 5600?
Options:
A)s. 1200
B)s. 5400
C)s. 5400
D)s. 4999
E)s. 5000
Rationale: Total sale for 5 months = Rs. (5400 + 9000 + 6300+ 7200 + 4500) = Rs. 32400.
Required sale = Rs. [ (5600 x 6) - 32400 ]
= Rs. (33600 - 32400)
= Rs.1200.
Option A
Answer: A