divelab/Sys2Bench huggingface dataset:
Question: A carpenter makes 6 bunk beds every day. A military school needs to organize a place to sleep for 143 soldiers. If there are 5 carpenters working on the job, how many whole days in advance should they receive the order and start working in order to finish the right number of beds assuming that each bunk- bed is used by two soldiers?
Options:
A)3.
B)4.
C)5.
D)6.
E)7.
Rationale: I believe it is C because if 1C makes 3 beds in 1 day then:
1C's rate = 3/1
So 5c's = 3/1 * 5 = 15/1 = 15 beds in a day.
Since we have 173 soldiers who need beds and bunk beds come in pairs, 72 is the least amount of beds needed.
Time = Amount / Rate
Time = 72 / (15/1) = 72/15, simplifying we get 72/15 = 24/5 = 5.7
So, in order for the carpenters to be able to finish they need 5 whole days. At first I made the mistake of thinking how many whole days it took them to finish (as in ignore the partial day) but the prompt clarifiesdays in advance, meaning how many days would they need to finish so even if they finish early, theyusedthat day.
D
Answer: D
Question: Which of the following is not divisible by 4?
Options:
A)10236
B)21792
C)47816
D)91232
E)72034
Rationale: Divisibility rule of 4: Last two digits of the number should be divisible by 4
Option A: 10236, last two digits = 36. Divisible by 4
Option B: 21792, last two digits = 92. Divisible by 4
Option C: 47816, last two digits = 16. Divisible by 4
Option D: 91232, last two digits = 32. Divisible by 4
Option E: 72034, last two digits = 34. Not divisible by 4. Hence 72034 is not divisible by 4
Answer: E
Question: There are 15 players in a chess group, and each player plays each of the others once. Given that each game is played by two players, how many total games will be played?
Options:
A)110
B)130
C)105
D)60
E)190
Rationale: 10 players are there.
two players play one game with one another.
so 15C2=15*14/2
=105
SO OPTION C is correct
Answer: C
Question: The parameter of a square is equal to the perimeter of a rectangle of length 24 cm and breadth 16 cm. Find the circumference of a semicircle whose diameter is equal to the side of the square. (Round off your answer to two decimal places)
Options:
A)77.14 cm
B)47.14 cm
C)84.92 cm
D)94.94 cm
E)31.42 cm
Rationale: Let the side of the square be a cm.
Parameter of the rectangle = 2(24 + 16) = 80 cm Parameter of the square = 80 cm
i.e. 4a = 80
A = 20
Diameter of the semicircle = 20 cm
Circimference of the semicircle
= 1/2(∏)(20)
= 1/2(22/7)(20) = 440/14 = 31.42 cm to two decimal places
ANSWER:E
Answer: E
Question: Rohan's income doubles after every one year. If the initial income was Rs. 4 lakhs, What would be the income after 6 years?
Options:
A)Rs. 2.76 crores
B)Rs. 2.51 crores
C)Rs. 2.56 crores
D)Rs. 2.57 crores
E)Rs. 2.36 crores
Rationale: Explanation:
Income after 1 year = Rs. (4 * 21) lakhs
Income after 2 years = Rs. (4 * 2 * 2) lakhs = Rs. (4 x 22) lakhs
Income after 6 years = Rs. (4 * 26) lakhs = Rs. 256 lakhs = 2.56 crores.
ANSWER: C
Answer: C
Question: Evaluate: 6702.5 + 670.25 + 67.025 + 6.7025 + 0.67025
Options:
A)7447.14775
B)6981.59775
C)6918.59775
D)6198.59775
E)6891.59775
Rationale: 6702.5
670.25
67.025
6.7025
+ 0.67025
---------------
7447.14775
Answer is A.
Answer: A
Question: The difference of two numbers is 1365. on dividing the larger number by the smaller, we get 6 as quotient and 15 as remainder. What is the smaller number?
Options:
A)240
B)270
C)295
D)360
E)None of these
Rationale: Let the smaller number be x. Then larger number = (x+1365).
x+1365=6x+15, 5x=1350, x=270
Smaller number=270.
Correct Option: B
Answer: B
Question: A shopkeeper buys two articles for Rs.1000 each and then sells them, making 50% profit on the first article and 50% loss on second article. Find the net profit or loss percent?
Options:
A)500
B)768
C)276
D)280
E)279
Rationale: Profit on first article = 50% of 1000 = 500.
This is equal to the loss he makes on the second article. That, is he makes neither profit nor loss.
Answer: A
Answer: A
Question: In a graduating class, the difference between the highest and lowest salaries is $100,000. The median salary is $50,000 higher than the lowest salary and the average salary is $20,000 higher than the median. What is the minimum number of students R in the class?
Options:
A)A)10
B)B)12
C)C)15
D)D)20
E)E)25
Rationale: the difference between the highest and lowest salaries is $100,000.
So there are at least 2 people - say one with salary 0 and the other with 100k. No salary will be outside this range.
Median = 50k more than lowest. So median is right in the center of lowest and highest since lowest and highest differ by 100k. In our example, median = 50k. Since there are more than 2 people, there would probably be a person at 50k.
Mean = 20k more than median so in our example, mean salary = 70k
On the number line,
0........50k (median)........100k
Mean = 70k
So there must be people more toward 100k to bring the mean up to 70k. Since we want to add minimum people, we will add people at 100k to quickly make up the right side deficit. 0 and 50k are (70k + 20k) = 90k away from 70k. 100k is 30k away from 70k. To bring the mean to 70k, we will add two people at 100k each to get:
0....50k.....100k, 100k, 100k
But when we add more people to the right of 70k, the median will shift to the right. We need to keep the median at 50k. So every time we add people to the right of 70k, we need to add people at 50k too to balance the median. 50k is 20k less than 70k while 100k is 30k more than 70k. To keep the mean same, we need to add 2 people at 100k for every 3 people we add at 50k. So if we add 3 people at 50k and 2 people at 100k, we get:
0, ... 50k, 50k, 50k, 50k, ... 100k, 100k, 100k, 100k, 100k
the median is not at 50k yet.
Add another 3 people at 50k and another 2 at 100k to get
0, 50k, 50k, 50k, 50k, 50k, 50k, 50k, 100k, 100k, 100k, 100k, 100k, 100k, 100k
Now the median is 50k and mean is 70k.
Total number of people is 15.
Answer (C)
Answer: C
Question: If 2^4, 3^3, and 13^3 are factors of the product of 1,452 and w, where w is a positive integer, what is the smallest possible value of w?
Options:
A)198
B)288
C)363
D)396
E)468
Rationale: I will go with E (pending elements to match is 2^2*3^2*13^1 = 468
Answer: E
Question: A person incurs loss for by selling a watch for Rs1140.at what price should the watch be sold to earn a 5% profit ?
Options:
A)1542
B)3645
C)7845
D)1260
E)3654
Rationale: let the new sp be Rsx.then
(100-loss%) : (1st sp)=(100+gain%) (2nd sp)
	{(100-5)/1400}={(100+5)/x}=> x={(105*1140)/95} =1260.
Ans: D
Answer: D
Question: Find the odd man out
864, 420, 200, 94, 40, 16, 6
Options:
A)420
B)200
C)16
D)94
E)6
Rationale: 6x2+4=16
16x2+8=40
40x2+12=92
92x2+16=200.. and so on. 94
ANSWER:D
Answer: D
Question: The time on a clock is 20 minutes past 5. What is the angle between the hands of the clock?
Options:
A)60 degrees
B)20 degrees
C)30 degrees
D)50 degrees
E)40 degrees
Rationale: The hour hand rotates 360 degrees in twelve hours.
The hour hand rotates 30 degrees in one hour.
The hour hand rotates 5 degrees in ten minutes.
At this time, the hour hand has rotated 160 degrees.
The minute hand rotates 360 degrees in 60 minutes, or 60 degrees in ten minutes.
At this time, the minute hand has rotated 120 degrees.
The difference is 160 - 120 = 40 degrees.
The answer is E.
Answer: E
Question: Working simultaneously and independently at an identical constant rate, 6 machines of a certain type can produce a total of x units of product P in 5 days. How many of these machines, working simultaneously and independently at this constant rate, can produce a total of 4x units of product P in 10 days?
Options:
A)9
B)10
C)12
D)14
E)18
Rationale: The rate of 6 machines is rate=job/time=x/5 units per day --> the rate of 1 machine 1/6*(x/5)=x/30 units per day;
Now, again as {time}*{combined rate}={job done}
then 10*(m*x/30)=4x --> m=12.
Answer: C.
Answer: C
Question: A person's present age is two-fifth of the age of his mother. After 6 years, he will be one - half of the age of his mother. How old is the mother at present ?
Options:
A)A)25
B)B)40
C)C)32
D)D)45
E)E)30
Rationale: Let the mother's present age be x years
Then the person's present age = 2x/5
(2x/5)+6 = 1/2(x+6)
2(2x+30) = 5 (x+6)
x = 30
Answer is E
Answer: E
Question: A salt manufacturing company produced a total of 5000 tonnes of salt in January of a particular year. Starting from February its production increased by 100 tonnes every month over the previous months until the end of the year. Find its average monthly production for that year?
Options:
A)5520
B)2789
C)5550
D)2889
E)2788
Rationale: Total production of salt by the company in that year = 5000 + 5100 + 5200 + .... + 6100 = 66600.
Average monthly production of salt for that year = 66600/12 = 5550.
Answer: C
Answer: C
Question: The positive integers a and b leave remainders of 2 and 3, respectively, when divided by 6. a > b.
What is the remainder when a – b is divided by 6?
Options:
A)4
B)3
C)5
D)2
E)1
Rationale: Let's test out some values of m and n that satisfy the given information.
a leaves are remainder of 2 when divided by 6
So, a COULD equal 8
b leaves are remainder of 3 when divided by 6
So, b COULD equal 3
What is the remainder when a – b is divided by 6?
So, a - b = 8 - 3 = 5, and when we divide 5 by 6, we get 0 with remainder 5
Answer: C
Answer: C
Question: What percent is 120 of 70?
Options:
A)133 1/3 %
B)134 1/3 %
C)135 1/3 %
D)140 1/3 %
E)171 3/7 %
Rationale: 120/70 = 12/7
12/7 × 100 = 1200/7 = 171 3/7 %
E
Answer: E
Question: Given that f(x) = x×f(x - 1) for any natural number x. If f(x + 2) = 20*f(x), then what is the value of x?
Options:
A)5
B)6
C)7
D)8
E)98
Rationale: Given:f(x) = x××f(x - 1) ....(a)
and f(x + 2) = 20××f(x) ....(b)
Substitute x = x + 1 in (a)
Then, f(x + 1) = (x + 1)××f(x) .........(c)
Substitute x = x + 2 in (a)
Then, f(x + 2) = (x + 2)××f(x + 1) ......(d)
From (b), 20××f(x) = f(x + 2) = (x + 2)××f(x + 1)= (x + 2)(x + 1)××f(x)
⇒⇒ 20××f(x) = (x + 2) (x + 1)××(f(x)
Cancelling f(x) on both sides and upon simplification we get
or x2x2+ 3x - 18 = 0
or (x + 6)(x - 3) = 0
or x = -6 or 3. Hence the answer is option (e).
Answer:B
Answer: B
Question: In 1995 a total of 250 earthquakes occurred worldwide, some but not all of which occurred in Asia. If 100 of these earthquakes occurred in Asia, which of the following represents the ratio of the number of earthquakes that occurred in Asia to the number that did NOT occur in Asia?
Options:
A)2/3
B)1/3
C)1/4
D)3/4
E)5/8
Rationale: We're given a couple of facts to work with:
1) There were a total of 250 earthquakes
2) Of those earthquakes, 100 of them occurred in Asia
We're asked for the ratio of the number of earthquakes that occurred IN ASIA to the number of earthquakes that DID NOT occur in Asia.
Thus, there were 150 earthquakes that DID NOT occur in Asia....
The answer to the question is 100/150 = 2/3
Answer : A
Answer: A
Question: A shop owner sells 25mtr of cloth and gains SP of 10 mtrs. Find the gain %?
Options:
A)30%
B)40%
C)50%
D)66.67%
E)70%
Rationale: Here, selling price of 10 m cloth is obtained as profit.
Profit of 10 m cloth = (S.P. of 25 m cloth) – (C.P. of 25 m cloth)
Selling price of 15 m cloth = Selling Price of 25 m of cloth
Let cost of each metre be Rs. 100.
Therefore, cost price of 15 m cloth = Rs. 1500 and S.P. of 15 m cloth = Rs. Rs. 2500
Profit% = 10/15 × 100 =66.67%
Profit of 66.67% was made by the merchant.
D
Answer: D
Question: Evaluate 28% of 550 + 45% of 280
Options:
A)232
B)242
C)252
D)262
E)280
Rationale: Explanation:
= (28/100) * 550 + (45/100) * 280
= 154 + 126 = 280
Answer: Option E
Answer: E
Question: A batsman makes a score of 64 runs in the 16th innings and thus increased his average by 3. Find his average after the 16th inning?
Options:
A)22
B)299
C)277
D)19
E)77
Rationale: Let the average after the 16th inning be P.
So, the average after the 15th inning will be (P-3) Hence, 15(P-30) + 64 = 16P => P = 19.Answer:D
Answer: D
Question: Bookman purchased 30 copies of a new book released recently, 10 of which are hardback and sold for $20 each, and rest are paperback and sold for $10 each. If 14 copies were sold and the total value of the remaining books was 240, how many paperback copies were sold?
Options:
A)8
B)12
C)6
D)4
E)5
Rationale: The bookman had 10 hardback ad 30-10=20 paperback copies;
14 copies were sold, hence 30-14=16 copies were left. Let # of paperback copies left be p then 10p+20(16-p)=240 --> 10 p=80 --> p=8
# of paperback copies sold is 20-8=12
Answer: B
Answer: B
Question: Michael cashed a check for $1,240 and received only $10 and $50 bills in return. During the course of a day, he used 15 bills and then lost the rest of the money. If the number of $10 bills used was either one more or one less than the number of $50 bills used, what is the minimum possible amount of money that was lost?
Options:
A) $830
B) $800
C) $770
D) $730
E) $700
Rationale: 1. 15 bills spent
2. Number of $10 bills is one more or one less than number of $50 bills.
So, 2 choices
1. 7*10 + 8*50 = $470
2. 8*10 + 7*50 = $430
Least money lost implies most money spent. i.e $470
Therefore, lost money = 1240 - 470 = 770.
Answer C
Answer: C
Question: What is the equation of a circle of radius 5 units centered at (3, 2)?
Options:
A)x^2 + y^2 + 6x – 4y = 23
B)x^2 + y^2 - 6x + 4y = 23
C)x^2 + y^2 + 6x + 4y = 23
D)x^2 + y^2 - 6x – 4y = - 12
E)x^2 + y^2 - 6x – 4y = 12
Rationale: the equation of a circle with center at (a,b) and radius R is (X-a)^2+(Y-b)^2=R^2
=> answer = (X-3)^2+(Y-2)^2=5^2
solving,,we get the equation in answer choice E.
Answer: E
Question: If the weight of 12 meters long rod is 12.2 kg. What is the weight of 6 meters long rod ?
Options:
A)7.2 kg.
B)10.8 kg.
C)12.4 kg.
D)6.1 kg
E)None
Rationale: Answer
∵Weight of 12 m long rod = 12.2 kg
∴ Weight of 1 m long rod = 12.2 / 12 kg
∴ Weight of 6 m long rod = 12.2 x 6 / 12
= 6.1 kg
Option: D
Answer: D
Question: Convert the 13/36 m/s into kilometers per hour?
Options:
A)5.3 kmph
B)2.3 kmph
C)3.3 kmph
D)1.3 kmph
E)4.3 kmph
Rationale: D
1.3 kmph
13/36 m/s = 13/36 * 18/5 = 13/10 = 1.3 kmph.
Answer: D
Question: In western Europe, Z bicycles were sold in each of the years 1990 and 1993. The bicycle producers of Western Europe had a 42 percent share of this market in 1990 and a 33 percent share in 1993. Which of the following represents the decrease in the annual number of bicycles produced and sold in Western Europe from 1990 to 1993?
Options:
A)9% of (x/100)
B)14% of (x/100)
C)75% of (x/100)
D)9% of Z
E)14% of x
Rationale: Moreover is't question actually asking the the difference between the {(Quantity Produced + Quantity Sold ) Z in 1990 - (Quantity Produced + Quantity Sold ) in 1993}
Though the Quantity sold in both the years is same it actually boils down to (Quantity Produced in 1990 ) in (Quantity Produced in 1993)=D
Answer: D
Question: If population of certain city increases at the rate of 5%. If population in 1981 was 138915, then population in 1978 was?
Options:
A)120000
B)228788
C)266891
D)267689
E)127791
Rationale: X * (105/100) * (105/100) * (105/100) = 138915
X = 138915/1.157625
X = 120000
Answer:A
Answer: A
Question: Consider a set S given as {11,22,33,44,55,66,77,88,99} . If each element of the data set is multiplied by -7 then by what factors will the Mean,Variance and Standard Deviation respectively change ?
Options:
A)-7,-7,-7
B)-7,7,7
C)1,1,1
D)-7,49,7
E)7,7,49
Rationale: Mean: If all values are multiplied by -7 then their sum will also be multiplied by -7 so Mean will also get -7
Variance:
Variance is equal to (Sum of (Square of (the difference between mean and individual values))/Total number of values
When we multiply all the values by -7 then the difference between the mean and the individual values also gets multiplied by -7 and the square of that difference becomes 49. So, the variance gets multiplied by a factor of 49
SD:
Standard Deviation is the square root of variance so sqrt(49)=7. So SD gets multiplied by a factor of 7.
So, answer will be D.
Answer: D
Question: A driver took a trip consisting of three segments at three different speeds. The driver drove a distance of (5D) at a speed of (2V), then a distance of (7D) at a speed of (3V), then a distance of D at a speed of (6V). In terms of D and V, what was the total time of the trip?
Options:
A)3D/V
B)4D/V
C)5D/V
D)6D/V
E)7D/V
Rationale: The total time of the trip was:
5D/2V + 7D/3V + D/6V =
30D/12V + 28D/12V + 2D/12V =
60D/12V = 5D/V
The answer is C.
Answer: C
Question: The speed of a boat in upstream is 60 kmph and the speed of the boat downstream is 80 kmph. Find the speed of the boat in still water and the speed of the stream?
Options:
A)10
B)88
C)676
D)99
E)12
Rationale: Speed of the boat in still water = (60+80)/2 = 70 kmph. Speed of the stream
= (80-60)/2 = 10 kmph.
Answer: A
Answer: A
Question: Robin is traveling from one end of a forest to the other. In order to find her way back, she is leaving morsels of bread in the following pattern: 2 morsels of wheat, 3 morsels of MAZE, and 1 morsel of rye. The pattern repeats after she leaves the morsel of rye. If Robin drops 2,000 morsels of bread, what are the last 3 morsels of bread that she drops?
Options:
A)rye − wheat − wheat
B)wheat − wheat − white
C)RYE- w-w
D)white − white − white
E)white − white − rye
Rationale: Q is nothing BUT asking about remainder..
total morsels thrown before the pattern is repeated = 2+3+1 = 6..
so REMAINDER when 2000 is div by 6..
1998 is EVEN and also div by 3, so remainder is 2..
Last 3 of morsels are 1998-1999-2000
so he uses the last of morsel of pattern in 1998 two of the first morsels of the pattern in 1999 and 2000, and the pattern is w, w, M,M, M, RY..
ans RY-w-w
C
Answer: C
Question: If the sales tax reduced from 3 1/2 % to 3 1/3%, then what difference does it make to a person who purchases an article with market price of Rs. 8400 ?
Options:
A)Rs.10
B)Rs.12
C)Rs.14
D)Rs.16
E)Rs.18
Rationale: Required difference = [3 ½ % of Rs.8400] – [3 1/3 % of Rs.8400]
= [(7/20-(10/3)]% of Rs.8400 =1/6 % of Rs.8400
= Rs. [(1/6)8(1/100)*8400] = Rs. 14.
Option C
Answer: C
Question: A 3-digit number 4a3 is added to another 3-digit number 984 to give a 4-digit number 13b7, which is divisible by 11. Then, (a + b) = ?
Options:
A)8
B)10
C)7
D)26
E)38
Rationale: Explanation:
4 a 3 |
9 8 4 } ==> a + 8 = b ==> b - a = 8
13 b 7 |
Also, 13 b7 is divisible by 11 =>(7 + 3) - (b + 1) = (9 - b)
=>(9 - b) = 0
b = 9
(b = 9 and a = 1) => (a + b) = 10.
B
Answer: B
Question: In how many ways can a committee consisting of 4 men and 5 women be formed from a group of 7 men and 10 women?
Options:
A)7C4 10C5
B)4C7 5C10
C)7C5 9C4
D)9C4 7C5
E)NONE
Rationale: Group consisting of 7 men and 10 women
4 men can be selected from 7 men in 7C4 ways
5 women can be selected from 10 women in 10C5 ways
Therefore, Total number of ways= 7C4 10C5
ANSWER:A
Answer: A
Question: 1/2,16,4,15,3,56,_ ?
Options:
A)28/3
B)27/3
C)26/3
D)25/3
E)24/3
Rationale: take alternative no. 1/2, 4,3
16/4=4
15/5 = 3
56/6 =28/3
hence ans is 28/3
ANSWER:A
Answer: A
Question: On 8th Dec, 2007 Saturday falls. What day of the week was it on 8th Dec, 2006?
Options:
A)Saturday
B)Friday
C)Monday
D)Tuesday
E)Sunday
Rationale: The year 2006 is an ordinary year. So, it has 1 odd day.
So, the day on 8th Dec, 2007 will be 1 day beyond the day on 8th Dec, 2006.
But, 8th Dec, 2007 is Saturday
So, 8th Dec, 2006 is Friday. Answer: B
Answer: B
Question: A train after traveling for 50km meets with an accident and then proceeds at 3/4 of its former speed and arrives at its destination 35 minutes late . Had the accident occurred 24 km farther, it would have reached the destination only 25 minutes late. What is the speed W of the train.
Options:
A)a) 45
B)b) 33
C)c) 48
D)d) 55
E)e) 61
Rationale: Let y be the balance distance to be covered and x be the former speed.
A train after traveling for 50km meets with an accident and then proceeds at 3/4 of its former speed and arrives at its destination 35 minutes late
so, y/(3x/4) - y/x = 35/60
4y/3x - y/x = 7/12
y/x(4/3-1)=7/12
y/x*1/3=7/12
y/x=7/4
4y-7x=0 ........ 1
Had the accident occurred 24 km farther, it would have reached the destination only 25 minutes late
so, (y-24)/(3x/4) - (y-24)/x = 25/60
4(y-24)/3x - (y-24)/x = 5/12
(y-24)/x (4/3-1) = 5/12
(y-24)/x *1/3 = 5/12
(y-24)*12 = 3x*5
(y-24)*4 = 5x
4y-5x = 96 ....... 2
eq2 - eq1
2x=96
x=48=W
Ans = C
Answer: C
Question: The C.P of 15 books is equal to the S.P of 19 books. Find his gain% or loss%?
Options:
A)16 2/3% loss
B)16 2/8% loss
C)21 1/19% loss
D)36 2/3% loss
E)56 2/3% loss
Rationale: 15 CP = 19 SP
19 --- 4 CP loss
100 --- ? => 21 1/19% loss
Answer:C
Answer: C
Question: The cost of registration at a professional association meeting was $50 per person; a lunch for registrants only was available for an additional $22 per person. If the number of registrants who paid for lunch was 20 more than the number who did not, and if receipts for registration and lunch totaled $50,240, how many people paid just for registration at the meeting?
Options:
A)700
B)800
C)1,300
D)1,500
E)400
Rationale: Hope this might be useful to you.
Let the number of people who have opted only to register = x
Now since the registration cost is 50$ per person, the total amount sums to = 50x $
As per the information given in the question, the number of registrants who paid for lunch was 20 more than the number who did not. That means, total number of people who registered and paid for lunch = 20 + x.
For the people who registered for lunch the cost is 50 $ (for the event registration) + 22 $ (for lunch) = 72 $.
Total amount in this case sums to = 72(20 + x) = 1440 + 72x
Now, total amount received was 50240.
Thus, from the above data,
50x + 1440 + 72x = 50240
122x = 50240 - 1440
122x = 48800
x = 400.
Hence the correct Ans is E
Answer: E
Question: Find the ratio in which rice at Rs.10.0 a kg be mixed with rice at Rs.5.70 a kg to produce a mixture worth Rs.6.30 a kg?
Options:
A)1 : 3
B)2 : 3
C)3 : 5
D)4 : 5
E)None of these
Rationale: Solution
Required ratio = 60 : 100 = 3 : 5
Answer C
Answer: C
Question: A trader mixes 26 kg of rice at Rs. 20 per kg with 30 kg of rice of other variety at Rs. 36 per kg and sells the mixture at Rs. 38 per kg. His profit percent is:
Options:
A)No profit, no loss
B)5%
C)33%
D)10%
E)None of these
Rationale: Explanation :
C.P. of 56 kg rice = (26 * 20 + 30 * 36) Rs. = (520 + 1080) Rs. = 1600 Rs.
S.P. of 56 kg rice = (56 * 38) Rs. = 2128 Rs.
Profit % = (2128−1600/1600∗100)% = 33%
Answer : C
Answer: C
Question: If 75 percent of a class answered the first question on a certain test correctly, 35 percent answered the second question on the test correctly, and 20 percent answered neither of the questions correctly, what percent answered both correctly?
Options:
A) 10%
B)(8) 20%
C) 30%
D) 50%
E) 65%
Rationale: {Total} = {First} + {Second} - {Both} + {Neither}
100% = 75% + 35% - {Both} + 20% --> {Both} = 30%.
Answer: C
Answer: C
Question: A father is 30 years older than his son, however he will be only thrice as old as the son after 5 years, what is the father's present age ?
Options:
A)40 yrs
B)30 yrs
C)50 yrs
D)60 yrs
E)None of the above
Rationale: After 5 years . if ages are F and S , then
F=3S where F = S+30
F= 3*(F-30) = 3F-90
2F = 90
F =45
so present age = 45-5= 40 years
ANSWER:A
Answer: A
Question: If a and b are integers and (2^a)(3^b) is a factor of 90^40, what is the largest possible value of ab?
Options:
A)2a
B)5a
C)20a
D)40a
E)80a
Rationale: (2^a)(3^b) is a factor of 90^40
We need to find the largest possible value of ab.
We know that 90 = 2^1*5^1*3^2
Therefore 90^40 will have 2 powers of 3 in it.
Hence in (2^a)(3^b), b has to 2
Therefore value of ab = 2a
Correct Option: A
Answer: A
Question: Find out the wrong number in the given sequence of numbers.
1, 2, 6, 15, 31, 56, 93
Options:
A)2
B)6
C)15
D)93
E)91
Rationale: 1(result) + (1*1) = 2.
2(result) + (2*2) = 6.
6(result) + (3*3) = 15.
15(result) + (4*4) = 31.
31(result) + (5*5) = 56.
56(result) + (6*6) = 92.
Now we are getting 92 not 93.. So 93 is the wrong number of the given.
answer : D
Answer: D