divelab/Sys2Bench huggingface dataset:
Question: The radius of a circular wheel is 1.75 m, how many revolutions will it make in traveling 1 km?
Options:
A)1000
B)1988
C)1998
D)2789
E)2677
Rationale: 2 * 22/7 * 1.75 * x
= 11000
x = 1000
Answer: A
Answer: A
Question: Fresh grapes contain 90% by weight while dried grapes contain 20% water by weight. What is the weight of dry grapes available from 10 kg of fresh grapes?
Options:
A)2 kg
B)2.4 kg
C)2.5 kg
D)1.250 kg
E)none of these
Rationale: The weight of non-water in 10 kg of fresh grapes (which is 100-90=10% of whole weight) will be the same as the weight of non-water in x kg of dried grapes (which is 100-20=80% of whole weight), so 10âˆ—0.1=xâˆ—0.8--> x=1.25
Answer: D
Answer: D
Question: he population of a city is 140,000. If it increases at the rate of 6% per annum, then what will be its population 2 years hence?
Options:
A)1797787
B)1597723
C)159776
D)159728
E)157304
Rationale: Population after n years = P [1 + (R/100)]2
Population after 2 years = 140000 * [1 + 6/100]2 = (160000 x 53/50 x 53/50) = 157304
ANSWER: E
Answer: E
Question: The sum of four consecutive odd numbers is equal to the sum of 3 consecutive even numbers. Given that the middle term of the even numbers is greater than 101 and lesser than 212, how many such sequences can be formed?
Options:
A)27
B)17
C)25
D)33
E)50
Rationale: Four consecutive odd numbers: k-2, k, k+2, k+4
Three consecutive even numbers: n-2, n, n+2
k-2+k+k+2+k+4=n-2+n+n+2
4k+4=3n
4(k+1)=3n
k+1=(3/4)n
k=(3/4)n-1
All n's that's divisible by 4 will have an integral k. So, we need to find out how many such n's are available within given range:
We know,
101<n<212
104<=n<=208
Count=(208-104)/4+1=104/4+1=26+1=27
Ans: 27.
Answer: A
Question: The average monthly salary of laborers and supervisors in a factory is Rs.1250 per month; where as the average monthly salary of 6 supervisors is Rs.2450. If the average monthly salary of the laborers is Rs.950 find the number of laborers?
Options:
A)11
B)42
C)77
D)88
E)12
Rationale: 5x 6x 2x
50 25 100
250x + 150x + 200x = 4200
600x = 4200
x = 7 => 6x = 42
Answer:B
Answer: B
Question: 7,23,55,109,191,__
Options:
A)304
B)305
C)306
D)307
E)308
Rationale: 7= 2^3-1^2
23= 3^3-2^2
55= 4^3-3^2
....
..191= 6^3 - 5^2 = 216-25
next number = 7^3-6^2= 343 -36= 307
ANSWER:D
Answer: D
Question: The Smiley Pie Eating team won 30% of the first contests they entered. An amazingly winning streak increased their average to 50%. How many consecutive contests must they have won to have achieved this average?
Options:
A)30
B)20
C)10
D)25
E)35
Rationale: Explanation: Let's set up an equation to find the solution. Total number of contest won to start was 30% of 75 = 22.5. Then, an amazing winning streak increases the percentage to 50%. Let x represent the unknown number of consecutive winning contests. Therefore, the total number of contests entered is (75+x). The total contests won is (22.5+x). With a 50% increase in the total contests won, we end up with a solution equation of 50% * (75+x)+22.5+x. Next, let's get rid of the percent sign and rewrite, then solve the equation. 50/100 * (75+x)=22.5+x
1/2 * (75+x)=22.5+x
2[ 1/2 * (75+x)]=2(22.5+x)
1 * (75+x)=45+2x
75+x=45+2x
(75-45)+x=(45-45)+2x
30+x=2x
(30+x =2x)/x
30=x
Answer: A
Answer: A
Question: A teacher grades students’ tests by subtracting twice the number of incorrect responses from the number of correct responses. If Student A answers each of the 100 questions on her test and receives a score of 73, how many questions did Student A answer correctly?
Options:
A)55
B)60
C)73
D)82
E)91
Rationale: let the number of correct responses be x
then the number of incorrect responses =100-x
according to question
x-2(100-x)=73 (subtracting twice of incorrect from correct)
3x=273
x=91
ANSWER:E
Answer: E
Question: There are 4 people of different heights standing in order of increasing height. The difference is 2 inches between the first person and the second person, and also between the second person and the third person. The difference between the third person and the fourth person is 6 inches and the average height is 75. How tall is the fourth person?
Options:
A)73
B)75
C)77
D)79
E)81
Rationale: Let x be the height of the first person.
Then the heights are x, x+2, x+4, and x+10.
4x+16 = 4(75) = 300
x = 71 and the fourth person has a height of 71+10 = 81 inches
The answer is E.
Answer: E
Question: If a boat goes 7 km upstream in 42 minutes and the speed of the stream is 3 kmph, then the speed of the boat in still water is
Options:
A)4.2 Km /hr
B)9 Km /hr
C)13 Km /hr
D)21 Km /hr
E)None
Rationale: Solution
Rate upstream	= (7/42x60)kmph
= 10 kmph.
Speed upstream	= 3 kmph.
Let speed in still water be x km/hr. Then,
speed upstream = (x - 3) Km/hr.
∴ x - 3 = 10 or
‹=›x = 13 Km/hr
Answer C
Answer: C
Question: What is the diffference between the place value of 2 in the numeral 7229?
Options:
A)150
B)160
C)180
D)190
E)200
Rationale: Option 'C'
200 - 20 = 180
Answer: C
Question: A boy wants to go abroad by boat and return by flight. He has a choice of 4 different boat to go and 5 flight to return. In how many ways, can the boy perform his journey?
Options:
A)20
B)40
C)45
D)60
E)70
Rationale: Ans.(A)
Sol. Number of choices to go by ship = 4 Number of choices to return by airline = 5 From, fundamental principle, total number of ways of performing the journey = 4 x 5 = 20 ways
Answer: A
Question: If each digit in the set of A = {1,2,3,4,5,6,7} is exactly used once, in how many ways can the digits be arranged such that the 2 and 5 are not adjacent?
Options:
A)7!
B)5*6!
C)7! - 6!
D)7! - 2!
E)7! / 2!
Rationale: The answer should be the (total arrangements) - (arrangements when 2 and 5 are adjacent).
The number of ways to arrange 7 units is 7!
If we think of 2 and 5 as one single unit, the number of arrangements is 6!
Note that 2 and 5 can have two arrangements, so we multiply by 2 to get 2*6!
The total number of valid arrangements is 7! - 2*6! = 7*6! - 2*6! = 5*6!
The answer is B.
Answer: B
Question: In a division sum, the quotient is 36, the divisor 85 and the remainder 26, find the dividend?
Options:
A)3066
B)3586
C)3086
D)3968
E)3286
Rationale: Explanation:
36 * 85 + 26 = 3086
Answer : C
Answer: C
Question: An airplane flies against the wind from A to B in 8 hours. The same airplane returns from B to A, in the same direction as the wind, in 7 hours. Find the ratio of the speed of the airplane (in still air) to the speed of the wind.
Options:
A)15
B)25
C)35
D)45
E)55
Rationale: Let x = speed of airplane in still air, y = speed of wind and D the distance between A and B. Find the ratio x / y
Against the wind: D = 8(x - y), with the wind: D = 7(x + y)
8x - 8y = 7x + 7y, hence x / y = 15
correct answer is A) 15
Answer: A
Question: The area of a square land is A square feet and the perimeter is p feet. If 5A=10p+45, what is the perimeter of the land, in feet?
Options:
A)18
B)56
C)40
D)36
E)64
Rationale: You can also solve this via using the given numbers in the answer choices!
Of course you need to be aware of the basic properties as outlined by the other posts above (a = x^2 and p = 4x)
Starting with B you will notice that x=14 is way too big for your area (14^2) and will not satisfy: 5A=10p+45 or A=2p+9
--> Eliminate B and E
Now pick D (its either too big, then its A, or too small then you know its C or it is B itsself)
And picking D indeed solves the problem! (36/4 --> 9; a= 9^2 = 81 and 81=2x36+9)
Answer: D
Question: If 2 tic equals 3 tacs and 2 tacs equal 7 tocs, what is the ratio of one tic to one toc?
Options:
A)15/2
B)6/5
C)21/4
D)3/10
E)1/15
Rationale: 2Tic=3*Tac and 2*Tac=7*Toc;
4*Tic=6*Tac and 6*Tac=21*Toc --> 4*Tic=21*Toc --> Tic/Toc=21/4.
Answer: C.
Answer: C
Question: A train moves at average speed of 60kmph reaches its destination on time.what its average speed becomes 50kmph , then it reaches its destination 15 late. find the length of the journey?
Options:
A)4.86km
B)2.5km
C)6.86km
D)5.867km
E)3.25km
Rationale: Difference between timings=15 min=1/4hr
let the length of the journey be x km.
then x/50-x/60=1/4
x/10=1/4
x=2.5km
Answer (B)
Answer: B
Question: Find the numbers which are in the ratio 3 : 2 : 4 such that the sum of the first and the second added to the difference of the third and the second is 21 ?
Options:
A)3,3,3
B)4,4,3
C)4,5,3
D)9, 6, 12
E)2,4,4
Rationale: Let the numbers be a, b and c.
Given that a, b and c are in the ratio 3 : 2 : 4.
let, a = 3x, b = 2x and c = 4x
Given, (a+b) + (c - b) = 21
= > a + b + c - b = 21 = > a + c = 21
= > 3x + 4x = 21 = >7x = 21 = > x = 3
a , b , c are 3x, 2x, 4x.
a, b, c are 9 , 6 , 12.
Answer:D
Answer: D
Question: In each series, look for the degree and direction of change between the numbers. In other words, do the numbers increase or decrease, and by how much
Look at this series: 80, 10, 70, 15, 60, ... What number should come next?
Options:
A)30
B)40
C)20
D)50
E)60
Rationale: C
20
This is an alternating addition and subtraction series. In the first pattern, 10 is subtracted from each number to arrive at the next. In the second, 5 is added to each number to arrive at the next.
Answer: C
Question: At 6′o a clock ticks 6 times. The time between first and last ticks is 40 seconds. How long does it tick at 12′o clock
Options:
A)47
B)88
C)28
D)66
E)11
Rationale: Explanation:
For ticking 6 times, there are 5 intervals.
Each interval has time duration of 40/5 = 8 secs
At 12 o'clock, there are 11 intervals,
So total time for 11 intervals = 11 × 8 = 88 secs.
Answer: B
Answer: B
Question: Distance between two stations A and B is 1108 km. A train covers the journey from A to B at 84 km per hour and returns back to A with a uniform speed of 56km per hour. Find the average speed of train during the whole journey.
Options:
A)60 km/hr
B)30.5 km/hr
C)57 km/hr
D)67.2 km/hr
E)None of these
Rationale: Explanation :
Average speed = (2xy)/(x+y) km/hr
= (28456)/(84+56) km/hr
= (28456)/140 km/hr
= 67.2 km/hr.
Answer : D
Answer: D
Question: If A:B = 2:3, B:C = 4:5 and C:D = 6:7, then find the value of A:B:C:D
Options:
A)15:24:30:35
B)16:24:30:35
C)17:24:30:35
D)18:24:30:35
E)NONE OF THE ABOVE
Rationale: Explanation:
A:B=2:3
B:C=4:5=(4∗3/4:5∗3/4)=3:15/4
C:D=6:7=(6∗15/24:7∗15/24)=15/4:35/8
A:B:C:D=2:3:15/4:35/8=16:24:30:35=8:12:9
ANSWER IS B
Answer: B
Question: A telephone number contains 10 digit, including a 3-digit area code. Bob remembers the area code and the next 5 digits of the number. He also remembers that the remaining digits are not 0, 1, 2, 6, or 7. If Bob tries to find the number by guessing the remaining digits at random, the probability that he will be able to find the correct number in at most 2 attempts is closest to which of the following ?
Options:
A)50/625
B)2/625
C)4/625
D)25/625
E)75/625
Rationale: I think most of the answers are missing a point. Let me try to put it across:
Total number of possible numbers are : 5x5 = 25
Correct number =1
Case 1: When he gets it right in first attempt: P(E1) = 1/25
Case 2: He gets 1st attempt wrong and second right:
When he gets it wrong then the probability of getting wrong is 24/25.
Now there are 24 cases with him and he chooses the right one this time.
Probability of right case is 1/24
Thus, P(E2) = 24/25 x 1/24
=1/25
Probability of getting it right in at most two cases = P(E1) + P(E2)
= 1/25 + 1/25
= 2/25
= 50/625
Option (A) is therefore right as most of you mentioned but the method employed was wrong.
Answer: A
Question: There are 10 teams in a soccer league and each team plays each of the other teams once. How many games will be played in total?
Options:
A)33
B)36
C)39
D)42
E)45
Rationale: 10C2=45
The answer is E.
Answer: E
Question: A train running at 25 km/hr takes 60 seconds to pass a platform. Next, it takes 12 seconds to pass a man walking at 5 km/hr in the same direction. Find the length of the train and that of the platform.
Options:
A)a) 200/3m175/3m
B)b) 30m190m
C)c) 50m45m
D)d) 100/3 m200/3
E)e) none of these
Rationale: Hi Math gurus correct me if I am wrong. I wondered i reached the answer mentioned here i.e 100m and 25m
lets solve it
To find out length of train the train, which is must cover the static point of the man as well as the distance covered the man during 12 sec.
The man covered the distance during 12sec is 5*5/60*12=5m so the train covered a distance in 12 sec= 25*5/60*12=25
so the length of the train(Lt) is 5+25=30m
Now crossing the platform means length of train+length of platform(Lt+p)= 60*25*5/60=125m Now the length of platform (Lp) is= 125-30=95m
So answer is 30m and 95m Must beBeven though its mentioned 30m and 190m thinking so typo mistake...........
Answer: B
Question: 50 square stone slabs of equal size were needed to cover a floor area of 98 sq.m. Find the length of each stone slab?
Options:
A)140cm
B)767cm
C)88cm
D)666cm
E)776cm
Rationale: Area of each slab
=98/50m2=1.96m2
Length of each slab √1.96=1.4m=140cm
Answer: A
Question: In a 100 m race, A runs at 8km per hour. If A gives B a start of 5 m and still him by 15 seconds, what is the speed of B ?
Options:
A)5.56 km/hr.
B)5.06 km/hr.
C)5.70 km/hr.
D)6.76 km/hr.
E)5.72 km/hr.
Rationale: Time taken by A to cover 100 m =(60 X 60 / 8000)	x 100 sec = 45 sec.
B covers (100 - 5) m = 95 m in (45 + 15) sec = 60 sec.
B's speed = (95 x 60 x 60)/(60 x 1000)km/hr = 5.7 km/hr.
Answer is C
Answer: C
Question: Three 6 faced dice are thrown together. The probability that no two dice show the same number on them is ?
Options:
A)5/7
B)5/9
C)5/5
D)5/3
E)2/9
Rationale: No two dice show same number would mean all the three faces should show different numbers. The first can fall in any one of the six ways. The second die can show a different number in five ways. The third should show a number that is different from the first and second. This can happen in four ways.
Thus 6 * 5 * 4 = 120 favourable cases.
The total cases are 6 * 6 * 6 = 216.
The probability = 120/216 = 5/9.
Answer:B
Answer: B
Question: What is the difference between the local values of 3 in the number 53403?
Options:
A)2992
B)2997
C)2877
D)2077
E)1211
Rationale: Explanation:
3000 â€“ 3 = 2997
Answer:B
Answer: B
Question: The average marks of a Suresh in 10 papers are 80. If the highest and the lowest scores are not considered, the average is 81. If his highest score is 92, find the lowest?
Options:
A)55
B)60
C)62
D)52
E)Cannot be determined
Rationale: Total marks of 10 papers = 80 x 10 = 800
Total marks of 8 papers = 81 x 8 = 648
Total marks of two papers = (800 - 648) = 152
If highest total is 92, then the lowest total is
(152 - 92) = 60.
ANSWER:B
Answer: B
Question: If a number between 0 and 1/2 is selected at random, which of the following will the number most likely be between
Options:
A)0 and 3/20
B)3/20 and 1/5
C)1/5 and 1/4
D)1/4 and 3/10
E)3/11 and 1/2
Rationale: E. 3/11 and 1/2
Definitely not. I am always happy to explain a given question or issue if I can. However, I sometime donot put my explanation if I am answering first because I want to put others first for their explanation.
Now you have excellent explanantion byscthakur. In fact the question is asking the likelyness of or high chances/probability of having a given number. Hope you already got it. E
Answer: E
Question: X and Y invest Rs.21000 and Rs.15000 respectively in a business. At the end of the year, they make a profit of Rs.25500. What is the share of X in the profit?
Options:
A)Rs.14400
B)Rs.26400
C)Rs.12000
D)Rs.12500
E)Rs.14875
Rationale: Ratio of the investment=21000:15000=7:5
Share of X in the profit=(25500×7)/12=14875
ANSWER:E
Answer: E
Question: Bill made a profit of 10% by selling a product. If he had purchased that product for 10% less and sold it at a profit of 30%, he would have received $ 70 more. What was his original selling price?
Options:
A) $770
B) $660
C) $700
D) $1100
E) $840
Rationale: Let the original purchase price be X
So original selling price at 10% profit = 1.1X
If product is purchased at 10% less of original = 0.9X
Profit of 30% on this price = 1.3(0.9X)
He would have received $70 more in second scenario => 1.3(0.9X) - 1.1X = 70
=> 0.07X = 70
=> X = $1000
Original purchase price = $1000
Hence, original selling price (at 10% of profit) = 1.1(1000) = $1100
Option D
Answer: D
Question: How many 6 digits no can be formed using 0,1,2,3,5,7 without repeatation?
Options:
A)500
B)600
C)700
D)800
E)900
Rationale: no. of words with all nos. is 6!
no. of words with 0 in 1st position is 5!
required no. 6!-5!=600
ANSWER:B
Answer: B
Question: John had a stock of 1200 books in his bookshop. He sold 75 on Monday, 50 on Tuesday, 64 on Wednesday, 78 on Thursday and 135 on Friday. What percentage of the books were not sold?
Options:
A)26.5%
B)36.5%
C)46.5%
D)56.5%
E)66.5%
Rationale: Let N be the total number of books sold. Hence
N = 75 + 50 + 64 + 78 + 135 = 402
Let M be the books NOT sold
M = 1200 - N = 1200 - 402 = 798
Percentage
Books not sold / total number of books = 798/1200 = 0.665 = 66.5%
correct answer E
Answer: E
Question: When Professor Wang looked at the rosters for this term's classes, she saw that the roster for her economics class (E) had 20 names, the roster for her marketing class (M) had 28, and the roster for her statistics class (S) had 18. When she compared the rosters, she saw that E and M had 9 names in common, E and S had 7, and M and S had 10. She also saw that 4 names were on all 3 rosters. If the rosters for Professor Wang's 3 classes are combined with no student's name listed more than once, how many names will be on the combined roster?
Options:
A)30
B)44
C)42
D)46
E)50
Rationale: Total # of students 20+28+18-(9+7+10)+4=44.
Answer: B.
Answer: B
Question: The combined salaries of three brothers is $270,000. Mr. Big earns twice what Mr. Small earns, and Mr. Middle earns 1 1/2 times what Mr. Small earns. What is the smallest salary of the three brothers?
Options:
A) 45,000
B) 60,000
C) 55,000
D) 30,000
E) 40,000
Rationale: Mr. Small = x;
Mr. Middle = 3/2*x;
Mr. Big = 2x.
x + 3/2*x + 2x = 270 --> x=60
Answer: B
Answer: B
Question: If Jake loses 29 pounds, he will weigh twice as much as his sister. Together they now weigh 99 pounds. What is Jake's present weight, in pounds?
Options:
A) 69
B) 135
C) 139
D) 147
E) 188
Rationale: J = Jake’s current weight, in pounds
S = Sister’s current weight, in pounds
We are told that “If Jake loses 8 pounds, he will weigh twice as much as his sister.We put this into an equation:
J – 29 = 2S
J = 2S + 29 (Equation 1)
Next, we are told that “Together they now weigh 89 pounds.” We can also put this into an equation.
J + S = 89 (Equation 2)
To solve this equation, we can substitute 2S + 8 from Equation 1 for the variable J in Equation 2:
2S + 29 = 89-S
3S = 60
S = 20
J + 20 = 89
J = 69
Answer: A
Answer: A
Question: The value of x + x(xx) when x = 1 is:
Options:
A)5
B)8
C)2
D)1
E)4
Rationale: x + x(xx)
Put the value of x = 1 in the above expression we get,
=1 + 1(1)
= 1 + 1(1)
= 1 + 1
= 2 CORRECT ANSWER : C
Answer: C
Question: If a student loses 6 kilograms, he will weigh twice as much as his sister. Together they now weigh 132 kilograms. What is the student's present weight in kilograms?
Options:
A)82
B)84
C)86
D)88
E)90
Rationale: Let x be the weight of the sister.
Then the student's weight is 2x+6.
x + (2x+6) = 132
3x = 126
x = 42 kg
Then the student's weight is 90 kg.
The answer is E.
Answer: E
Question: What profit percent is made by selling an article at a certain price, if by selling at 2/3rd of that price, there would be a loss of 30%?
Options:
A)5%
B)29%
C)10%
D)80%
E)90%
Rationale: SP2 = 2/3 SP1
CP = 100
SP2 = 70
2/3 SP1 = 70
SP1 = 105
100 --- 5 => 5%
Answer: A
Answer: A
Question: A sum of Rs.312 was divided among 100 boys and girls in such
a way that each boy gets Rs.3.60 and each girl Rs.2.40.
Options:
A)45
B)49
C)52
D)60
E)74
Rationale: Let number of boys = x
Then number of girls = (100-x)
3.60x +2.40(100-x) = 312 ¡ê 1.2x
= 312 - 240
= 72 ¡ê x = 60
answer :D
Answer: D
Question: How many integers are divisible by 3 between 20! and 20! + 20 inclusive?
Options:
A)6
B)7
C)8
D)9
E)10
Rationale: B - 7
20! is divisible by 3
There are 6 numbers between 10! and 10!+20 that are divisible by 3.
Hence 7
Answer: B
Question: The average age 8 members of a committee are the same as it was 2 years ago, because an old number has been replaced by a younger number. Find how much younger is the new member than the old number?
Options:
A)14 years
B)16 years
C)18 years
D)12 years
E)11 years
Rationale: 2 * 2
= 16
Answer:B
Answer: B
Question: If an object travels 200 feet in 2 seconds, what is the object's approximate speed in miles per hour? (Note: 1 mile = 5280 feet)
Options:
A)68
B)54
C)21
D)48
E)22
Rationale: 1 mile = 5280 feet
=> 1 feet = 1/5280 miles
If the object travels 200 feet in 2 sec
then it travels 200/2 * 60 * 60 feet in 1 hour (1 hr = 60 min * 60 sec)
= 3600 * 100 feet in 1 hour
= 360000 feet in 1 hr
= 360000/5280 miles in 1 hour
= 36000/528 miles/hr ~ 68 miles/hr
Answer - A
Answer: A
Question: A part of certain sum of money is invested at 9% per annum and the rest at 12% per annum, if the interest earned in each case for the same period is equal, then ratio of the sums invested is?
Options:
A)1:5
B)2:3
C)4:9
D)4:3
E)6:2
Rationale: Explanation:
12:9
= 4:3
Answer: D
Answer: D
Question: In a throw of dice what is the probability of geÆ«ng number greater than 3
Options:
A)1/2
B)1/3
C)1/5
D)1/6
E)None of these
Rationale: Explanation:
Number greater than 3 is 4, 5, 6, so only 3 number
Total cases of dice = [1,2,3,4,5,6]
So probability = 3/6 = 1/2
Answer: A
Answer: A
Question: A, B and C completed a piece of work, A worked for 6 days, B for 9 days and C for 4 days. Their daily wages were in the ratio of 3:4:5. Find the daily wages of C, if their total earning was Rs.1406?
Options:
A)s.109
B)s.108
C)s.100
D)s.95
E)s.102
Rationale: 3x 4x 5x
6 9 4
18x + 36x + 20x = 1406
74x = 1406 => x = 19
5x = 95 Rs.
Answer:D
Answer: D
Question: The value of x + x(xx) when x = 4 is:
Options:
A)8
B)10
C)64
D)14
E)16
Rationale: x + x(xx)
Put the value of x = 4 in the above expression we get,
4 + 4(4*4)
= 4 + 64
= 68
ANSWER : C
Answer: C
Question: A man traveled a total distance of 1800 km. He traveled one-third of the whole trip by plane and the distance traveled by train is two-thirds of the distance traveled by bus. If he traveled by train, plane and bus, how many kilometers did he travel by bus?
Options:
A)660
B)680
C)720
D)760
E)800
Rationale: total distance traveled = 1800 km.
distance traveled by plane = 600 km.
distance traveled by bus = x
distance traveled by train = 2x/3
x + 2x/3 + 600 = 1800
5x/3 = 1200
x = 720 km
The answer is C.
Answer: C
Question: Find the average of first 40 natural numbers.
Options:
A)20.5
B)18
C)19.5
D)19
E)17
Rationale: Exp. Sum of first n natural numbers = n( n+1)/2
So, sum of first 40 natural numbers = 40*41/2 = 820
Required average =820/40 =20.5
Answer:A
Answer: A
Question: The lenght of a room is 5.5 m and width is 4 m. Find the cost of paving the floor by slabs at the rate of Rs. 950 per sq. metre.
Options:
A)s. 20,550
B)s. 15,600
C)s. 20,900
D)s. 17,600
E)s. 17,900
Rationale: Area of the floor = (5.5 Ã— 4) m2 = 22 m2.
Cost of paving = Rs. (950 Ã— 22) = Rs. 20900
Answer: Option C
Answer: C
Question: Employees of a certain company are each to receive a unique 8-digit identification code consisting of the digits 0, 1, 2, 3, 4, 5, 6, and 7 such that no digit is used more than once in any given code. In valid codes, the second digit in the code is exactly twice the first digit. How many valid codes are there?
Options:
A)1220
B)1840
C)2160
D)2480
E)2760
Rationale: There are 6! ways to make codes starting with 12.
There are 6! ways to make codes starting with 24.
There are 6! ways to make codes starting with 36.
The number of codes is 3*6! = 2160.
The answer is C.
Answer: C
Question: A train 140m long is running at 60kmph. In how much time will it pass a platform 260m long?
Options:
A)15 seconds
B)24 seconds
C)28 seconds
D)30 seconds
E)35 seconds
Rationale: Distance travelled = 140 + 260m = 400m
Speed = 60 * 5/8 = 50/3m
Time = 400 * 3/50 = 24 Second
Answer : B
Answer: B
Question: If (2^13)(25^S) = 5(10^m) what is the value of m ?
Options:
A)7
B)13
C)15
D)16
E)23
Rationale: given
2^13 * 25^s = 5 * 10^2
=> 2^13 * 5^(2s) = 2^m * 5^(m+1)
Ans B
on comparing the power of 2 => m=13
Answer: B