divelab/Sys2Bench huggingface dataset:
Question: A ship sails out to a mark at the rate of 12 kmph. and sails back at the rate of 8 kmph. The average rate of sailing is ?
Options:
A)5 km/hr
B)9.6 km/hr
C)12.5 km/hr
D)25 km/hr
E)None
Rationale: Answer
Average = ( 2uv / u +v ) km/hr
= ( 2 x 12 x 8 ) / (12 +8 ) km/hr.
= 9.6 km/hr.
Correct Option: B
Answer: B
Question: John Purchased 1370 large bottles at $1.99 per bottle and 690 small bottles at $1.50 per bottle. What was the approximate average price paid per bottle?
Options:
A)$1.63
B)$1.64
C)$1.68
D)$1.72
E)$1.83
Rationale: (1370*1.99+690*1.50)/(1370+690) =~1.83
- Option (E)
Answer: E
Question: If x is the product of the positive integers from 1 to 8, inclusive, and if i, k, m, and p are positive integers such that x = 2^i * 3^k * 5^m * 7^p, then i + k + m + p =
Options:
A)4
B)7
C)8
D)11
E)12
Rationale: Given that x=8!=2^7∗3^2∗5∗7x. Hence, x=2^7∗3^2∗5^1∗7^1=2^i∗3^k∗5^m∗7p, since i, k, m, and p are positive integers, then we can equate the exponents, so we have that i=7, k=2, m=1, and p=1
Therefore, i+k+m+p=7+2+1+1=11
Answer: D.
Answer: D
Question: How many odd numbers between 10 and 800 are the squares of integers?
Options:
A)12
B)13
C)14
D)15
E)16
Rationale: The square of an odd number is an odd number:
10 < odd < 1,000
10 < odd^2 < 1,000
3.something < odd < 31.something (by taking the square root).
So, that odd number could be any odd number from 5 to 31, inclusive: 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29, and 31.
12 numbers.
Answer: A.
Answer: A
Question: Two boats are heading towards each other at constant speeds of 5 miles/hr and 23 miles/hr respectively. They begin at a distance 20 miles from each other. How far are they (in miles) one minute before they collide ?
Options:
A)1/12
B)7/12
C)1/6
D)1/3
E)1/5
Rationale: The question asks: how far apart will they be 1 minute=1/60 hours before they collide?
Since the combined rate of the boats is 5+23=25 mph then 1/60 hours before they collide they'll be rate*time=distance --> 28*1/60=7/15 miles apart.
Answer: B.
Answer: B
Question: If 9 workers can build 9 cars in 9 days, then how many days would it take 7 workers to build 7 cars?
Options:
A)6
B)7
C)8
D)9
E)10
Rationale: 9 workers can build 1 car per day on average.
1 worker can build 1/9 of a car per day.
7 workers can build 7/9 car per day.
The time required to build 7 cars is 7 / (7/9) = 9 days
The answer is D.
Answer: D
Question: If the provisions last for 30 days for 3000 men then if after 10 men are included then the remaining provisions last for how many days?
Options:
A)29.9 days
B)39.9 days
C)19.9 days
D)49.9 days
E)20.9 days
Rationale: 3000 men use for 30 days. so for 1 person = 30/3000 days = 1/100 =0.01days
for 10 ppl,its 0.1. so for 3010 ppl,its 30 - 0.1 = 29.9 days
ANSWER:A
Answer: A
Question: A box contains nine bulbs out of which 4 are defective. If four bulbs are chosen at random, find the probability that all the four bulbs are defective.
Options:
A)62/63
B)125/126
C)1/63
D)1/42
E)1/126
Rationale: Answer: Option E
Out of nine, five are good and four are defective. Required probability = â´câ‚„/â¹câ‚„ = 1/126
Answer: E
Question: Two brother X and Y appeared for an exam. The probability of selection of X is 1/7 and that of B is 2/9. Find the probability that both of them are selected.
Options:
A)2/69
B)2/60
C)2/63
D)2/29
E)2/10
Rationale: Explanation:
Let A be the event that X is selected and B is the event that Y is selected.
P(A) = 1/7, P(B) = 2/9.
Let C be the event that both are selected.
P(C) = P(A) × P(B) as A and B are independent events:
= (1/7) × (2/9) = 2/63
Answer: C) 2/63
Answer: C
Question: If the length, breadth and the height of a cuboid are in the ratio 6:5:4 and if the total surface area is 33300 cm2cm2, then the length , breadth and height in cms, are respectively.
Options:
A)90,85,60
B)85,75,60
C)90,75,70
D)90,75,60
E)none
Rationale: Explanation:
Let length = 6x, breadth = 5x and height =4x in cm
2(6x×5x+5x×4x+6x×4x)=33300
148x2=33300⇒x2=33300/148=225⇒x=15
Length = 90 cm, Breadth = 75 cm and Height = 60 cm
Correct Option: D
Answer: D
Question: 150 men consume 1050 kg of rice in 30 days. In how many days will 70 men consume 980 kg of rice?
Options:
A)62
B)60
C)65
D)73
E)64
Rationale: Explanation:
Rate of consumption of each man = 1050/(150 * 30) = 7/30 kg/day
Let us say 70 men take x days to consume 150 kg.
Quantity consumed by each item in x days = 7x/30 kg.
Quantity consumed by 70 men in x days = (7x/30)(70)kg
(7x/30)(70) = 980
x = (980 * 30)/490 => x = 60 days'
Answer: Option B
Answer: B
Question: In May, the grounds keeper at Spring Lake Golf Club built a circular green with an area of 81π square feet. In August, he doubled the distance from the center of the green to the edge of the green. What is the total area of the renovated green?
Options:
A)100PI
B)144PI
C)196PI
D)256PI
E)324PI
Rationale: AREA OF CIRCLE 81PI SQ FEET =PI R^2 THEREFORE R =9
NOW GREEN RADI DOUBLED I.E R =18 AREA =324 PI
E
Answer: E
Question: Reeya obtained 65, 67, 76, 80 and 95 out of 100 in different subjects, What will be the average
Options:
A)76.6
B)75
C)80
D)85
E)90
Rationale: Explanation:
(65+67+76+80+95 / 5)=76.6
Option A
Answer: A
Question: In a class, there are 30 boys who are over 160 cm tall. If these constitute three-fourths of the boys and the total number of boys is two-thirds of the total number of students in the class, what is the number of girls in the class ?
Options:
A)6
B)12
C)18
D)24
E)20
Rationale: Explanation:
Let the number of boys be x. Then, (3/4)x = 30 or x = 30 x(4/3) = 40.
If total number of students is y, then (2/3) y = 40 or y = 40 x (3/2) = 60.
Therefore Number of girls in the class = (60 - 40) = 20.
Answer: E
Answer: E
Question: How many positive integers less than 10,000 are there in which the sum of the digits equals 5?
Options:
A)31
B)51
C)56
D)62
E)93
Rationale: Basically, the question asks how many 4 digit numbers (including those in the form 0XXX, 00XX, and 000X) have digits which add up to 5. Think about the question this way: we know that there is a total of 5 to be spread among the 4 digits, we just have to determine the number of ways it can be spread.
Let X represent a sum of 1, and | represent a separator between two digits. As a result, we will have 5 X's (digits add up to the 5), and 3 |'s (3 digit separators).
So, for example:
XX|X|X|X = 2111
||XXX|XX = 0032
etc.
There are 8C3 ways to determine where to place the separators. Hence, the answer is 8C3 = 56.
ANSWER:C
Answer: C
Question: The bankerâ€™s discount of a certain sum of money is Rs. 42 and the true discount on the same sum for the same time is Rs. 36. The sum due is
Options:
A)252
B)280
C)360
D)450
E)None
Rationale: Sol.
Sum = B.D. * T.D. / B.D. - T.D. = Rs.[42 * 36 / 42 - 36] = Rs. [42 * 36 / 6] = Rs. 252
Answer A
Answer: A
Question: Kelly and Chris are moving into a new city. Both of them love books and thus packed several boxes with books. If Chris packed 60% of the total number of boxes, what was the ratio of the number of boxes Kelly packed to the number of boxes Chris packed?
Options:
A)4/3
B)2/3
C)1/3
D)3/4
E)1/4
Rationale: the ratio of the number of boxes Kelly packed to the number of boxes Chris packed = 40/60 = 2/3
ANSWER:B
Answer: B
Question: The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is?
Options:
A)298
B)270
C)245
D)267
E)239
Rationale: Speed = [45 X 5/18] m/sec = [25/2] m/sec Time = 30 sec Let the length of bridge be x metres. Then, (130 + x)/30 = 25/2 => 2(130 + x)
= 750 => x
= 245 m.
Answer:C
Answer: C
Question: a man can row 22 kmph in still water.it takes him thrice as long to row up as to row down the river.find the rate of stream
Options:
A)13 km/hr.
B)6 km/hr.
C)9 km/hr.
D)15 km/hr.
E)11 km/hr.
Rationale: Let manâ€™s rate upstream be x kmph.then ,his rate downstream=3xkmph.
So,2x=22 or x=11.
Rate upstream=11 km/hr,rate downstream=33 km/hr.
Hence,rate of stream=1/2(33-11)km/hr=11 km/hr.
Answer is E.
Answer: E
Question: The weights of three bags are in the ratio 4 : 5 : 6. If the sum of the weights of the heaviest and the lightest bag is 45 kg more than the weight of the third bag, what is the weight of the lightest bag?
Options:
A)45kg
B)38kg
C)66kg
D)36kg
E)of these
Rationale: Let the weights of the three boys be 4k, 5k and 6k respectively.
4k + 6k = 5k + 45
=> 5k = 45 => k = 9
Therefore the weight of the lightest boy
= 4k = 4(9) = 36 kg.
ANSWER:D
Answer: D
Question: P and Q can do a work in 30 days. Q and R can do the same work in 24 days and R and P in 20 days. They started the work together, but Q and R left after 4 days. How many days more will P take to finish the work?
Options:
A)10
B)36
C)18
D)20
E)22
Rationale: Let work done by P in 1 day = p,
Work done by Q in 1 day = q,
Work done by R in 1 day = r
p + q = 1/30
q + r = 1/24
r + p = 1/20
Adding all the above, 2p + 2q + 2r = 1/30 + 1/24+ 1/20 = 15/120 = 1/8
=> p + q + r = 1/16
=> Work done by P,Q and R in 1 day = 1/16
Work done by P, Q and R in 4 days = 4 × (1/16) = 4/16 = 1/4
Remaining work = 1 = 1/4 = 3/4
Work done by P in 1 day = Work done by P,Q and R in 1 day - Work done by Q and R in 1 day
= 1/16 – 1/24 = 1/48
Number of days P needs to work to complete the remaining work = (3/4) / (1/48) = 36
Option B
Answer: B
Question: If a number between 0 and 1/2 is selected at random, which of the following will the number most likely be between
Options:
A)0 and 3/20
B)3/8 and 1/2
C)1/5 and 1/4
D)1/4 and 3/10
E)3/10 and 1/2
Rationale: B. 3/8 and 1/2
Definitely not. I am always happy to explain a given question or issue if I can. However, I sometime donot put my explanation if I am answering first because I want to put others first for their explanation.
Now you have excellent explanantion byscthakur. In fact the question is asking the likelyness of or high chances/probability of having a given number. Hope you already got it.B
Answer: B
Question: If n = 2.0767 and n* is the decimal obtained by rounding n to the nearest hundredth, what is the value of n* – n?
Options:
A) -0.0053
B) -0.0003
C) 0.0007
D) 0.0047
E) 0.0033
Rationale: n*=2.08
n*-n=2.08-2.0767
0.0033
Answer: E
Answer: E
Question: Two trains, A and B, started simultaneously from opposite ends of a 125-mile route and traveled toward each other on parallel tracks. Train A, traveling at a constant rate, completed the 125-mile trip in 12 hours; Train B, traveling at a constant rate, completed the 125-mile trip in 8 hours. How many miles had train A traveled when it met train B?
Options:
A) 25
B) 37.5
C) 40
D) 45.5
E) 50
Rationale: As the ratio of the rates of A and B is 8 to 12 then the distance covered at the time of the meeting (so after traveling the same time interval) would also be in that ratio, which means that A would cover 8/(8+12)=8/20 of 125 miles: 125*8/20=50 miles.
Answer: E.
Answer: E
Question: If A(k)=(k+2)^k, and k=0, what is the value of A(A(A(k)))/(18^15)?
Options:
A)1
B)18
C)16
D)6
E)9
Rationale: A(A(A(0)))=A(A(2))=A(16)=18^16
18^16/18^15 = 18
Thus, the answer is B.
Answer: B
Question: If one person completes a journey in 10 hrs. He travels 1st half of the journey at the rate of 21 km/hr and 2nd half at therate of 24 km/hr. Find the total journey in km.
Options:
A)210 km
B)216 km
C)224 km
D)230 km
E)232 km
Rationale: distance = speed x time
Let time taken to travel the first half = x hr
then time taken to travel the second half = (10 - x) hr
Distance covered in the the first half = 21x
Distance covered in the the second half = 24(10 - x)
But distance covered in the the first half = Distance covered in the the second half
=> 21x = 24(10 - x)
=> 21x = 240 - 24x
=> 45x = 240
=> 9x = 48
=> 3x = 16
⇒x=163Hence Distance covered in the the first half = 21x=21×163=7×16=112 kmTotal distance = 2×112=224 km
C
Answer: C
Question: 17+18=35. How many such 2 consecutive numbers are there less than 200 when added gives a sum which is divisible by 5?
Options:
A)80
B)40
C)50
D)60
E)20
Rationale: since 2+3=5 & 7+8=15
any combination with these no be will give u desirable result...
so total no in 100 will be 20 & that's why in 200,it will be 40
ANSWER:B
Answer: B
Question: When a commodity is sold for $34.80, there is a loss of 2%. what is the cost price of the commodity?
Options:
A)$46.40
B)$48
C)$42.60
D)$43.45
E)$52.60
Rationale: s.p. = $34.80
loss = 2%
c.p. = 100*34.80/75 = $46.40
correct option is A
Answer: A
Question: Two fractions 1/3 and 2/3 are given to you. Can you find a fraction that lies one third on the way between them?
Options:
A)10/15
B)13/19
C)11/32
D)12/27
E)15/30
Rationale: D
12/27
This is really simple if you know the concept. You just have to increase the fraction by multiplying with a number. In that way, you will increase the numerator and you will be able to find the required fraction. Here, we are multiplying the numerator and denominator of both the numbers with 9. Now if you simplify, the number will remain the same and thus dont think we changed the fraction.
1/3 * 9/9 = 9/27
2/3 * 9/9 = 18/27
Its easy to find the one third fraction on the way now i.e. 12/27.
Answer: D
Question: Three seventh of a number is 12 more than 40% of that number. What will be the 20% of that number?
Options:
A)A)148
B)B)210
C)C)42
D)D)248
E)E)258
Rationale: 3/7 x – 40/100 x = 12
x = 35 * 12
35 * 12 * 20/100 = 84/2 = 42
ANSWER:C
Answer: C
Question: The prices of tea and coffee per kg were the same in june. In july the price of coffee shot up by 20% and that of tea dropped by 20%. if in july , a mixture containing equal quantities of tea and coffee costs 80/kg. how much did a kg of coffee cost in june ?
Options:
A)50
B)60
C)80
D)100
E)120
Rationale: Let the price of tea and coffee be x per kg in June.
Price of tea in July = 1.2x
Price of coffee in July = 0.8x .
In July the price of 1/2 kg (800gm) of tea and 1/2 kg (800gm) of coffee (equal quantities) = 80
1.2x(1/2) + 0.8x(1/2) = 80
=> x =80
Thus proved...option C.
Answer: C
Question: The L.C.M. of 2 numbers is 72. The numbers are in the ratio 2:3. Find their sum?
Options:
A)36
B)40
C)48
D)60
E)56
Rationale: Let the numbers be 2x and 3x
L.C.M. = 6x
6x = 72
x = 12
The numbers are = 24 and 36
Required sum = 24+36= 60
Answer is D
Answer: D
Question: The salary of a typist was at first raised by 10% and then the same was reduced by 5%. If he presently draws Rs.4180.What was his original salary?
Options:
A)2277
B)2999
C)4000
D)2651
E)1971
Rationale: X * (110/100) * (95/100) = 4180
X * (11/10) * (1/100) = 44
X = 4000
Answer: C
Answer: C
Question: How many terms are there in 2, 4, 8, 16,..., 256?
Options:
A)14
B)11
C)12
D)10
E)8
Rationale: 2, 4, 8, 16, ..., 256 is a G.P with a =2
and r =4/2 =2
Let the number of terms be n. Then
2 x 2 ^n-1 = 256
or 2^n-1 =128 = 2^7
Thus n - 1 =7
n= 8
ANSWER:E
Answer: E
Question: X can finish a work in 36 days. Y can finish the same work in 24 days. Y worked for 12 days and left the job. how many days does X alone need to finish the remaining work?
Options:
A)12
B)13
C)16
D)17
E)18
Rationale: Work done by X in 1 day = 1/36
Work done by Y in 1 day = 1/24
Work done by Y in 12 days = 12/24 = 1/2
Remaining work = 1 – 1/2 = 1/2
Number of days in which X can finish the remaining work = (1/2) / (1/36) = 18
E
Answer: E
Question: A number, x is chosen at random from the set of positive integers less than 10. What is the probability that (8/x) > x?
Options:
A) 1/5
B) 2/8
C) 1/3
D) 2/3
E) 7/9
Rationale: Number x has to be chosen from numbers 1-9
(8/x) > x
=> 8 > x^2
=>x^2 - 8 < 0
x can have 2 values only 1 , 2
Therefore , probability = 2 / 8
Answer B
Answer: B
Question: 20 is added to a certain number, the sum is multiplied by 2, the product is divided by 2 and 2 is subtracted from the quotient. The remainder left is half of 88. What is the number?
Options:
A)21
B)20
C)26
D)30
E)45
Rationale: Let number is X.
When 20 added to it,
= (X+20)
2 multiplied to sum,
= 2 *(X +20)
Now,
= [{2 *(X +20)} /2]
And,
= [{2 *(X +20)} /2] - 2
According to question,
[{2 *(X +20)} /2] - 2 = half of 88
[(2X + 40) /2) = 44 +2
2X + 40 = 46 * 2
X + 20 = 46
X = 46 - 20
X = 26
So, required number is: 26.
ANSWER : C
Answer: C
Question: ten family members: 5 grandchildren (3 brothers and 2 sisters) and their 5 grandparents are to be seated around a circular table. How many different seating arrangements are possible so that 2 sisters are seated between any two of the three brothers?
Options:
A)120
B)480
C)1440
D)2880
E)8640
Rationale: Answer: E.
Answer: E
Question: In a certificate by mistake a candidate gave his height as 25% more than actual height. In the interview panel, he clarified that his height was 5feet 5 nches. Find the % correction made by the candidate from his stated height to his actual height?
Options:
A)10
B)20
C)30
D)40
E)50
Rationale: His height was = 5 feet 5 inch = 5 + 60 = 65 inch. Required % correction =65*(1.25-1)* 100 = 20
B
Answer: B
Question: If 18 is 15 percent of 25 percent of a certain number, what is the number?
Options:
A)9
B)36
C)480
D)81
E)400
Rationale: Let the certain number be x.
=> (15/100)*(25/100)*x = 18;
=> x=480;
Ans is (C).
Answer: C
Question: Q and R are two-digit positive integers that have the same digits but in reverse order. If the positive difference between Q and R is less than 60, what is the greatest possible value of Q minus R?
Options:
A)52
B)54
C)55
D)56
E)58
Rationale: A two-digit integer "ab" can be expressed algebraically as 10a+b.
Q-R=(10a+b)-(10b+a)=9(a-b)<60.
The greatest multiple of 9 which is less than 60 is 54.
The answer is B.
Answer: B
Question: A man can row 6 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and black. What is the total distance traveled by the man?
Options:
A)5.77
B)5.79
C)5.76
D)5.75
E)5.71
Rationale: M = 6
S = 1.2
DS = 7.2
US = 4.8
x/7.2 + x/4.8 = 1
x = 2.88
D = 2.88 * 2 = 5.76
Answer:C
Answer: C
Question: A sum of Rs. 725 is lent in the beginning of a year at a certain rate of interest. After 8 months, a sum of Rs. 362.50 more is lent but at the rate twice the former. At the end of the year, Rs. 33.50 is earned as interest from both the loans. What was the original rate of interest?
Options:
A)3.46%
B)4.2%
C)4.5%
D)5%
E)None of these
Rationale: Explanation :
Let the sum of Rs.725 is lent out at rate R% for 1 year
Then, at the end of 8 months, ad additional sum of 362.50 more is lent out at rate 2R% for remaining 4 months(1/3 year)
Total Simple Interest = 33.50
=>725×R×1/100+362.50×2R×1/3/100=33.50
=>725×R×1/100+362.50×2R/300=33.50
=>725R/100+725R300=33.50
=>725R(1/100+1/300)=33.50
=>725R(4/300)=33.50
=>725R×4=10050
=>725R=2512.5
=>145R=502.5
=>R=502.5/145
=3.46%
Answer : Option A
Answer: A
Question: If p^2 – 13p + 40 = d, and p is a positive integer between 1 and 10, inclusive, what is the probability that d < 0?
Options:
A)1/10
B)1/5
C)2/5
D)3/5
E)3/10
Rationale: p2 – 13p + 40 = d
so (p – 8)(p – 5) = d
For q to be negative, the expressions (p – 8) and (p – 5) must have opposite signs. Which integers on the number line will yield opposite signs for the expressions (p – 8) and (p – 5)? Those integers in the range 5 < p < 8 (notice 5 and 8 are not included because they would both yield a value of zero and zero is a nonnegative integer). That means that there are only two integer values for p, 6 and 7, that would yield a negative q. With a total of 10 possible p values, only 2 yield a negative q, so the probability is 2/10 or 1/5.
The correct answer is B.
Answer: B
Question: is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 42, then how old is B?
Options:
A)16
B)8
C)9
D)10
E)11
Rationale: Let C's age be x years.
Then, B's age = 2x years.
A's age = (2x + 2) years.
(2x + 2) + 2x + x = 42
5x = 40 => x = 8
Hence, B's age = 2x = 16 years.
ANSWER:A
Answer: A
Question: There are 3 men, 8 women, they are standing in a row for a photoshoot, in how many ways they can be arranged if no 2 men can stand together.
Options:
A)9P3 * 8!
B)9P3 * 7!
C)9P3 * 6!
D)9P3 * 5!
E)8P3 * 8!
Rationale: There is restriction on the number of Men, so consideration of problem shall be done by fixing position of Women
_W_W_W_W_W_W_W_W_
In those blank spaces 3 Men can be arranged among 9 positions so that it satisfies the above condition.
No. of ways= 9P3 * 8!
ANSWER:A
Answer: A
Question: Find the missing in the series: 70, 58, 47, 37,___
Options:
A)28
B)287
C)2679
D)2767
E)2771
Rationale: Answer:A
Answer: A
Question: A competition requires teams to attempt 10 long jumps and 5 high jumps. Each successful long jump is worth the same number of points, and each successful high jump is worth the same number of points. Team A completed all 15 jumps, receiving 20 points. Team B succeeded in only 8 long jumps and 2 high jumps, earning 10 points. Team C missed 2 long jumps and successfully completed all the high jumps. How many points did Team C score?
Options:
A)12
B)13
C)15
D)18
E)19
Rationale: From Team A: 10x+5y = 20
From Team B: 8x+2y=10
Solve using whatever method you choose (i.e. substitution or elimination) --> x = 1/2 & y = 3
Team C: 8(1/2) + 5(3) = 19
Answer is E
Answer: E
Question: Find the odd man out. 1, 8, 27, 64, 125, 196, 216, 343
Options:
A)64
B)196
C)216
D)1
E)343
Rationale: The pattern is 1^3, 2^3, 3^3, 4^3, 5^3, 6^3, 7^3.
196 is not a perfect cube
Answer is B
Answer: B
Question: The difference between the compound interest and simple interest at the ratio of 10% per annum at the end of two years is Rs. 496.20. If the compound interest is compounded every six months, what is the sum ?
Options:
A)Rs. 24000
B)Rs. 30000
C)Rs. 32000
D)Rs. 36000
E)None of these
Rationale: Explanation :
[x (1 + 5/100)4 - x] - (x x 10 x 2)/100 = 496.20
x (0.21550625 - 0.2) = 496.2
∴ x = 496.20/0.01550625 = 32000
Answer : Option C
Answer: C
Question: Joan and Karl each bought a sofa and the sum of their purchases was $600. If twice of what Joan paid was $90 more than what Karl paid, what did Joan pay for her sofa?
Options:
A)$190
B)$210
C)$230
D)$250
E)$270
Rationale: J+K=600 so K=600-J
2J=K+90
2J=(600-J)+90
3J=690
J=230
The answer is C.
Answer: C
Question: P can do a certain work in 10 days. Q is 60% more efficient than P. How many days does Q alone take to do the same job?
Options:
A)6.25
B)6.75
C)7.5
D)7.75
E)8.25
Rationale: Each day, P can do 1/10 of the work.
Each day, Q can do 1.6/10 of the work = 16/100 of the work
The time taken by B alone to complete the total work is 100/16 = 6.25 days.
The answer is A.
Answer: A
Question: Find the simple interest on Rs 18 000 at 18% per annum for the period from 12th November 2016 to 16th December 2016.
Options:
A)Rs. 201.8
B)Rs. 1301.8
C)Rs. 341.8
D)Rs. 531.8
E)Rs. 401.8
Rationale: Explanation:
One thing which is tricky in this question is to calculate the number of days.
Always remember that the day on which money is deposited is not counted while the day on which
money is withdrawn is counted.
So lets calculate the number of days now,
Time = (18+16) days = 34/365 years
P = 18 000
R = 18%
S.I. = =18 000Ã—18Ã—34/(365*100)=301.8
Answer: C
Answer: C
Question: Each week, Harry is paid x dollars per hour for the first 18 hours and 1.5x dollars for each additional hour worked that week. Each week, James is paid x dollars per per hour for the first 40 hours and 2x dollars for each additional hour worked that week. Last week James worked a total of 41 hours If Harry and James were paid the same amount last week, how many hours did Harry work last week ?
Options:
A)34
B)36
C)37
D)38
E)39
Rationale: 42x=18x+1.5x(H-18)
==> 42=18+1.5(H-18)
==> H-18 = 24/1.5=16 ==> H = 34
Answer is A
Answer: A
Question: A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Options:
A)488
B)200
C)289
D)150
E)822
Rationale: Speed=(60 * 5/18) m/sec = (50/3) m/sec Length of the train = (Speed x Time) = (50/3 * 9) m = 150 m.Answer:D
Answer: D
Question: A grocer has a sale of Rs. 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 6500?
Options:
A)4991
B)5000
C)4800
D)5500
E)6000
Rationale: Let the sale in the sixth month = x
=>6435+6927+6855+7230+6562+x/6 = 6500
6435+6927+6855+7230+6562+x=6*6500
x=39000
x=39000-34009 = 4991
ANSWER A
Answer: A