divelab/Sys2Bench huggingface dataset:
Question: In a circuit board factory, all circuit boards that pass a verification process are certified. Every board that fails the verification process is indeed faulty, but 1/8 of those that pass are also faulty.
Approximately how many faulty circuit boards exist in a group of 400 circuit boards where 64 fail inspection?
Options:
A)106
B)192
C)200
D)256
E)264
Rationale: Total of 400 boards. All that fail verification are indeed faulty. So the 64 are indeed faulty. 1/8 those that pass are also faulty.
From the 400 we know 64 fail. So 336 must pass. Of these 1/8 are faulty. 336 divided by 8 gives you 42.
What one must do now is to add to the 42 which were not detected the actually detected faulty ones, namely the 64.
Total faulty: 106.
Answer: A
Answer: A
Question: A vessel contains 20 liters of a mixture of milk and water in the ratio 3:2. 10 liters of the mixture are removed and replaced with an equal quantity of pure milk. If the process is repeated once more, find the ratio of milk and water in the final mixture obtained?
Options:
A)9:1
B)9:3
C)9:3
D)5:2
E)4:1
Rationale: Milk = 3/5 * 20 = 12 liters, water = 8 liters
If 10 liters of mixture are removed, amount of milk removed = 6 liters and amount of water removed = 4 liters.
Remaining milk = 12 - 6 = 6 liters
Remaining water = 8 - 4 = 4 liters
10 liters of pure milk are added, therefore total milk = (6 + 10) = 16 liters.
The ratio of milk and water in the new mixture = 16:4 = 4:1
If the process is repeated one more time and 10 liters of the mixture are removed, then amount of milk removed = 4/5 * 10 = 8 liters.
Amount of water removed = 2 liters.
Remaining milk = (16 - 8) = 8 liters.
Remaining water = (4 -2) = 2 liters.
The required ratio of milk and water in the final mixture obtained = (8 + 10):2 = 18:2 = 9:1.
Answer:A
Answer: A
Question: kamal purchased 7kg of grapes at the rate of 70 per kg and 9 kg of mangoes at the rate of 55 per kg. How much amount did he pay to the shopkeeper?
Options:
A)A)980
B)B)1065
C)C)1070
D)D)1075
E)E)1080
Rationale: Cost of 7 kg grapes = 70 × 7 = 490.
Cost of 9 kg of mangoes = 55 × 9 = 490.
Total cost he has to pay = 490 + 490 = 980
A
Answer: A
Question: A man in a train notices that he can count 21 telephone posts in one minute. If they are known to be 50 metres apart, at what speed is the train travelling?
Options:
A)61 km/hr
B)60 km/hr
C)56 km/hr
D)63 km/hr
E)62 km/hr
Rationale: Explanation:
The man in the train notices that he can count 21 telephone posts in one minute.
Number of gaps between 21 posts are 20 and Two posts are 50 metres apart.
It means 20 x 50 meters are covered in 1 minute.
Distance = 20×50 meter = (20×50)/1000 km = 1 km
Time = 1 minute = 1/60hour
Speed = Distance/Time=1(1/60) = 60 km/hr
Answer: Option B
Answer: B
Question: 3889 + 17.952 - ? = 3854.002
Options:
A)52.95
B)49.75
C)45.97
D)47.59
E)45.79
Rationale: Let 3889 + 17.952 - x = 3854.002.
Then x = (3889 + 17.952) - 3854.002
= 3906.952 - 3854.002
= 52.95.
Answer is A
Answer: A
Question: The probability of a lottery ticket being a prized ticket is 0.2. When 4 tickets are purchased, the probability of winning a prize on atleast one ticket is ?
Options:
A)0.5989
B)0.5904
C)0.5929
D)0.5938
E)0.5907
Rationale: P(winning prize atleast on one ticket)
= 1 - P("Losing on all tickets")
= 1 - (0.8)4 = (1 + (0.8)2)(1 - (0.8)2)
= (1.64)(0.36) = 0.5904
Answer:B
Answer: B
Question: In what ratio must rice at Rs.30 per kg mixed with rice at Rs.10.80 per kg so that the mixture be worth Rs.10per kg Ans
Options:
A)8:7
B)8:8
C)8:3
D)8:2
E)8:1
Rationale: If 2 ingredients are mixed, then the required ratio is given by, the rule of allegation C.P of a unit quantity of cheaper (c) C.P. of a unit quantity of dearer (d)
Mean Price (m) d-m m-c  Required ratio is cheaper quantity : dearer quantity = (d-m) : (m-c) Answer with Explanation: By the rule of allegation i. C.P of 1 Kg of rice of I kind (p) = 930 ii. C.P of 1 Kg of rice of II kind (p) = 1080 iii. Mean price (p) = 1000 iv. d – m = 1080-1000 = 80 v. m – c = 1000 – 930 = 70  Required ratio = 80 : 70
= 8 : 7
Answer:A
Answer: A
Question: A car traveled 462 miles per tankful of gasoline on the highway and 336 miles per tankful of gasoline in the city. If the car traveled 12 fewer miles per gallon in the city than on the highway, how many miles per gallon did the car travel in the city?
Options:
A)14
B)16
C)21
D)22
E)32
Rationale: I treat such problems as work ones.
Work=Rate*Time
Mileage(m)=Rate(mpg)*Gallons(g)
X gallons is a full tank
{462=RX
{336=(R-12)X solve for R, R=44
44-12=32 mpg
E
Answer: E
Question: A trader marks his articles 20% more than the cost price. If he allows 20% discount, then find his gain or loss percent?
Options:
A)7
B)6
C)5
D)9
E)4
Rationale: Let CP of an article = RS. 100
MP= Rs. 120
Discount = 20%
SP = M[(100 - d%)/100] = 120(80/100) = Rs. 96
Clearly, the trader gets 4% loss.
Answer: E
Answer: E
Question: Three numbers are in the ratio 3:5:7. The largest number value is 42. Find difference between Smallest & largest number is?
Options:
A)18
B)22
C)24
D)26
E)28
Rationale: == 3:5:7
Total parts = 15
= The largest number value is 42
= The largest number is = 7
= Then 7 parts -----> 42 ( 7 * 6 = 42 )
= smallest number = 3 & Largest number = 7
= Difference between smallest number & largest number is = 7 - 3 = 4
= Then 4 parts -----> 24 (4 * 6 = 24)
C
Answer: C
Question: Salaries of Ravi and Sumit are in the ratio 2 : 3. If the salary of each is increased by Rs. 4000, the new ratio becomes 40 : 57. What is Sumit's salary?
Options:
A)32000
B)34000
C)38000
D)35000
E)36000
Rationale: Let the original salaries of Ravi and Sumit be Rs. 2x and Rs. 3x respectively.
Then,2x + 4000/3x + 4000	= 40/57
57(2x + 4000) = 40(3x + 4000)
6x = 68,000
3x = 34,000
Sumit's present salary = (3x + 4000) = Rs.(34000 + 4000) = Rs. 38,000.
ANSWER C
Answer: C
Question: Mohit sold an article for Rs. 18000. Had he offered a discount of 10% on the selling price, he would have earned a profit of 8%. What is the cost price of the article?
Options:
A)15000
B)28277
C)12002
D)28821
E)12000
Rationale: Explanation:
Let the CP be Rs. x.
Had he offered 10% discount, profit = 8%
Profit = 8/100 x and hence his SP = x + 8/100 x = Rs. 1.08x = 18000 - 10/100(18000) = 18000 - 1800 = Rs. 16200
=> 1.08x = 16200
=> x = 15000
Answer:A
Answer: A
Question: At a particular pizza shop, a pizza can be created from any combination of 2 different types of spice, 7 different types of meat, among which are pepperoni and anchovies, and 4 different types of cheese. If a customer at the shop decides to order a pizza with 1 type of spice, 2 types of cheese, and 4 types of meat but without pepperoni and anchovies together, how many possible ways to garnish the pizza are available to the customer?
Options:
A)6
B)35
C)300
D)450
E)740
Rationale: Number of possible ways to select 1 type of spice = 2c1 = 2
Number of possible ways to select 2 types of cheese = 4c2 = 6
(Here we can pick our answer as D- 450 since it is the only answer that is divisible by 3*6= 18 , but most likely on the GMAT there will be more another answer that will be divisible by 18 )
Number of possible ways to select 4 types of meat but without pepperoni and anchovies together
= Total number of ways without any restriction - Total number of ways in which pepperoni and anchovies together
= 7c4 - 5c2
=35 - 10
=25
Possible ways to garnish the pizza are available to the customer = 2*6 * 25
=300
Answer C
Answer: C
Question: Ten percent of Ram's monthly salary is equal to eight percent of Shyam's monthly salary. Shyam's monthly salary is twice Abhinav's monthly salary. If Abhinav's annual salary is Rs. 1.92 lakhs, find Ram's monthly salary?
Options:
A)Rs.25638
B)Rs.25638
C)Rs.25600
D)Rs.25624
E)Rs.25602
Rationale: Let the monthly salaries of Ram and Shyam be Rs. r and Rs. s respectively.
10/100 r = 8/100 s
r = 4/5 s
Monthly salary of Abhinav = (1.92 lakhs)/12 = Rs. 0.16 lakhs
s = 2(0.16 lakhs) = 0.32 lakhs
r = 4/5(0.32 lakhs) = Rs.25600
Answer:C
Answer: C
Question: A person travels equal distances with speeds of 3 km/hr, 4 km/hr and 5 km/hr and takes a total time of 47 minutes. The total distance is?
Options:
A)2
B)3
C)4
D)5
E)6
Rationale: Explanation:
Let the total distance be 3x km.
Then, x/3 + x/4 + x/5 = 47/60
47x/60 = 47/60 => x = 1.
Total distance = 3 * 1 = 3 km.
ANSWER IS B
Answer: B
Question: A sock drawer contains seven socks, each one a different solid color. The colors of the socks are black,red, orange, yellow, green, blue, indigo, and violet. A person reaches into the drawer, pulls out two socks, and puts a single sock on each foot. If each sock can fit either the left or the right foot, and if it matters whether a particular sock is on the left or the right foot, how many different sock fashion combinations could the person make from the eight socks?
Options:
A)12
B)15
C)21
D)36
E)56
Rationale: It's a question of permutation since order matters here ....
It can be deduced to-
8P2 = 8!/6! = 8*7 = 56 .........Answer is - E
Answer: E
Question: Aman started a business investing Rs. 70,000. Rakhi joined him after six months with an amount of Rs. 1,05,000 and Sagar joined them with Rs. 1.4 lakhs after another six months. The amount of profit earned should be distributed in what ratio among Aman, Rakhi and Sagar respectively, 3 years after Aman started the business?
Options:
A)2:35:16
B)2:15:16
C)2:15:77
D)2:15:98
E)2:15:23
Rationale: Aman : Rakhi : Sagar = (70000 * 36) : (105000 * 30) : (140000 * 24)
= 12:15:16
Answer: B
Answer: B
Question: If a man can cover 16 metres in one second, how many kilometres can he cover in 3 hours 45 minutes?
Options:
A)180km
B)190km
C)200km
D)210km
E)216km
Rationale: 16 m/s = 16 * 18/5 kmph
3 hours 45 minutes = 3 3/4 hours = 15/4 hours
Distance = speed * time = 16 * 18/5 * 15/4 km = 216 km.
Answer:E
Answer: E
Question: Rs.590 is divided amongst A, B, C so that 5 times A's share, six times B's share and eight times C's share are all equal. Find C's share?
Options:
A)Rs.157
B)Rs.150
C)Rs.176
D)Rs.165
E)Rs.156
Rationale: A+B+C = 590
5A = 6B = 8C = x
A:B:C = 1/5:1/6:1/8
= 24:20:15
15/59 * 590 = Rs.150
Answer:B
Answer: B
Question: The remainder when E=1+3+3^2+3^3+..........+3^200 is divided 13.
Options:
A)12
B)7
C)0
D)5
E)3
Rationale: E=1+3+3^2+3^3+..................+3^200
Is a Geometric progression having common ratio as '3' and number of terms as '201'.
Since Sum to n terms in GP = a(r^n-1)/(r-1)
where a=First term and r =common ration
Hence,
1*(3^201 -1 )/(3-1)
Rem of (3^201-1)/2 divided by 13
3^201 -1 /26
WKT, 3^3 = 27 = 26+1
{(26+1)^67 - 1}/26
{1-1}/26
=>0.C
Answer: C
Question: Cara leaves her home and walks toward Don's house. Two hours later, Don leaves his home and walks toward Cara's house. The distance between their homes is 45 kilometers, Cara's walking speed is 6 km/h, and Don's walking speed is 5 km/h. How many kilometers will Cara walk before she meets Don?
Options:
A)26
B)27
C)28
D)29
E)30
Rationale: Cara walks 12 km in the first two hours so there are 33 km remaining.
When Don starts walking, they complete a total of 11 km per hour.
They will meet three hours after Don starts walking.
Since Cara walks for 5 hours, she walks 30 km.
The answer is E.
Answer: E
Question: 3,10,29,66,__
Options:
A)125
B)165
C)145
D)127
E)112
Rationale: 3=1*1*1+2
10=2*2*2+2
29=3*3*3+2
66=4*4*4+2
Similarly 5*5*5+2=127
ANSWER:D
Answer: D
Question: If a, b and c are even integers, which of the following could be the value of a^2 + b^2 + c^2?
Options:
A)a)36
B)b)38
C)c)42
D)d)46
E)e)50
Rationale: a, b and c are even integers which means that, supposing that x, y and z are integers, then a=2x, b=2y and c=2z
Therefore we have: a^2+b^2+c^2=2^2*x^2+2^2*y+2^2*z=4x^2+4y^2+4z^2=4(x^2+y^2+z^2).
Which means that the total a^2+b^2+c^2 must be divisible by 4.
The only choice which is divisible by 4 is: A)
36=4^2+4^2+2^2
Answer: A.
Answer: A
Question: If 6000209× 6111209× K^20 is divisible by 3, which of the following could be the value of K?
Options:
A)6000209
B)6111209
C)6123309
D)6111109
E)6111309
Rationale: The first two terms are not divisible by 3, so we need the third term to be divisible by 3. The only way that (k^2) is going to be a multiple of 3 is if k is a multiple of 3. Therefore, we need the single answer that is a multiple of 3.
Answer =(E)
Answer: E
Question: A boy has nine trousers and 12 shirts. In how many different ways can he select a trouser and a shirt?
Options:
A)189
B)829
C)108
D)829
E)823
Rationale: The boy can select one trouser in nine ways.
The boy can select one shirt in 12 ways.
The number of ways in which he can select one trouser and one shirt is 9 * 12 = 108 ways.
Answer:D
Answer: D
Question: A customer pays 60 dollars for a coffee maker after a discount of 20 dollars
What is the original price of the coffe maker?
Options:
A)A)$50
B)B)$60
C)C)$70
D)D)$80
E)E)$90
Rationale: Let x be the original price.
x - 20 = 60
x - 20 + 20 = 60 + 20
x + 0 = 80
x = 80
correct answer is D)$80
Answer: D
Question: In a shop apple, orange, mango and pomegranate are sold. Average price of them is Rs.100 per kg. Apple, orange, mango are sold for Rs.100, Rs.90, Rs.80 per kg respectively. Therefore what is price of pomegranate?
Options:
A)Rs. 100
B)Rs. 90
C)Rs. 130
D)Rs. 120
E)Rs. 110
Rationale: EXPLANATION
Total price for apple, orange & mango = Rs. (100 + 90 + 80) = Rs. 270.
Pomegranate price = Rs. [ (100 x 4) – 270 ]
= Rs. (400 – 270)
= Rs. 130.
Answer C
Answer: C
Question: If a 3-number code is formed of the integers from 1 to 15 inclusively, and each of the numbers in the code is different, how many possible codes are there?
Options:
A)2400
B)2510
C)2620
D)2730
E)2840
Rationale: 15*14*13=2730
The answer is D.
Answer: D
Question: If the compound interest on a certain sum of money for 6 years at 10% per annum be Rs. 993, what would be the simple interest?
Options:
A)Rs. 880
B)Rs. 890
C)Rs. 1800
D)Rs. 900
E)None
Rationale: Let P = Principal
A - Amount
We have a = P(1 + R/100)3 and CI = A - P
ATQ 993 = P(1 + R/100)3 - P
? P = 3000/-
Now SI @ 10% on 3000/- for 6 yrs = (3000 x 10 x 6)/100
= 1800/-
Answer: C.
Answer: C
Question: Which of the following is a possible length for side AB of triangle ABC if AC = 4 and BC = 10?
I. 6
II. 9 √3
III. 11.5
Options:
A)I only
B)II only
C)III only
D)II and III
E)I, II, and III
Rationale: (10-4) < AB < (10+4)
The answer is C.
Answer: C
Question: Two dice are rolled together. What is the probability of getting two numbers whose product is even?
Options:
A)2
B)3/4
C)1/4
D)7/4
E)9/4
Rationale: Total number of outcomes possible=36
probability of getting two numbers whose product is even=27
P(E) =27/36=3/4
ANSWER:B
Answer: B
Question: John went to a shop and bought things worth Rs. 25, out of which 30 Paise went on sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax free items?
Options:
A)17
B)18
C)19.7
D)21
E)27
Rationale: Total cost of the items he purchased = Rs.25
Given that out of this Rs.25, 30 Paise is given as tax
=> Total tax incurred = 30 Paise = Rs.30/100
Let the cost of the tax free items = x
Given that tax rate = 6%
∴ (25−30/100−x)6/100 = 30/100
⇒ 6(25 −0.3 −x) = 30
⇒ (25 − 0.3 − x) = 5
⇒ x = 25 − 0.3 − 5 = 19.7
C)
Answer: C
Question: Simple interest on a certain sum is 22.5 over 10 of the sum. Find the rate per cent and time, if both are equal.
Options:
A)8% and 8 years
B)15% and 15 years
C)10% and 10 years
D)12 % and 12 years
E)None of these
Rationale: 22.5â„10 P = PÃ—RÃ—R/100
â‡’ R2 = 2250â„10 â‡’ 225 => R = 15%
Also, time = 15 years
Answer B
Answer: B
Question: What is the square root of 83,521?
Options:
A)476
B)489
C)289
D)511
E)311
Rationale: 1) Checking the last digits in the answer options A, C, E are out since last digit of the square is known to be 1.
2) C = 489^2 and E = 511^2
C = (300-11)^2 and E = (300 + 11)^2
Since we need the answer less than 90000 => E is out.
Thus we have C as the ans.
Answer: C
Question: If (A+B) = 4, (B+C) = 5 and (C+D) = 3, what is the value of (A+D)?
Options:
A)16.
B)8.
C)7.
D)2.
E)-2.
Rationale: Given A+B = 4
B+C = 5
C+D = 3
(A+B)-(B+C)+(C+D)=(A+D)
=>4 - 5+3 = 2.
Option D...
Answer: D
Question: Look at this series: 7, 10, 8, 11, 9, 12, 10, 13, ... What number should come next?
Options:
A)10
B)11
C)12
D)13
E)14
Rationale: This is a simple alternating addition and subtraction series. In the first pattern, 3 is added; in the second, 2 is subtracted.
The answer is B.
Answer: B
Question: Two pipes A and B can fill a tank in 20 and 30 minutes respectively. If both the pipes are used together, then how long it will take to fill the tank ?
Options:
A)10 mins
B)12 mins
C)15 mins
D)20 mins
E)30 mins
Rationale: Explanation:
In this type of questions we first get the filling in 1 minute for both pipes then we will add them to get the result, as
Part filled by A in 1 min = 1/20
Part filled by B in 1 min = 1/30
Part filled by (A+B) in 1 min = 1/20 + 1/30
= 1/12
So both pipes can fill the tank in 12 mins.
Answer: Option B
Answer: B
Question: In a certain sequence of numbers, a1, a2, a3, ..., an, the average (arithmetic mean) of the first m consecutive terms starting with a1 is m, for any positive integer m. If a1=1, what is a15?
Options:
A)100
B)55
C)29
D)19
E)1
Rationale: As stated above, (a1+a2+a3......+a15)/15=15
therefore a1+a2+a3.......a15=225 (1)
using the same logic, we got a1+a2+a3..........+a14=196 (2)
(2)-(1) we got a15=29
C
Answer: C
Question: The bankers discount of a certain sum of money is Rs. 144 and the true discount on the same sum for the same time is Rs. 120. The sum due is:
Options:
A)715
B)716
C)718
D)720
E)722
Rationale: Sum = (B.D*T.D)/(B.D-T.D)
(144*120)/144-120;
720
ANSWER: D
Answer: D
Question: If the length is increased by 25%, by what percent the width of a rectangle should be decreased so as to keep the area same.
Options:
A)25%
B)20%
C)30%
D)10%
E)15%
Rationale: SOLUTION :
Let the original length be l and the width be b
Therefore, the area = l*b
Now, as the length is increased by 25%, the new length is (1.25*l) and let the new width be x.
As the area is same, 1.25*l*x = l*b
x = b/1.25 = 0.8b
Therefore, the width is to be decreased by 20%.
ANSWER IS B
Answer: B
Question: A man can row 5 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and black. How far is the place?
Options:
A)2.25
B)2.35
C)2.45
D)2.55
E)2.65
Rationale: M = 5
S = 1.2
DS = 5 + 1.2 = 6.2
US = 5 - 1.2 = 3.8
x/6.2 + x/3.8 = 1
x = 2.35.Answer: B
Answer: B
Question: 38 69 22 43 31 47 13 82
Which of the following numbers is greater than three fourths of the numbers but less than one fourth of the numbers in the list above?
Options:
A)56
B)69
C)70
D)71
E)73
Rationale: Arrange the numbers in ascending order:
13, 22, 31, 38, 43, 47, 69, 82 (Just cross check the count to ensure that you didn't miss anything)
How many numbers do we see?
8, alright.
What's (1/4)8?
2.
What's (3/4)8?
6.
We're asked to find a number that are greater than 6 numbers in the list AND smaller than the remaining two.
13, 22, 31, 38, 43, 47, 69, 82
13, 22, 31, 38, 43, 47: Find a number greater than any of these numbers.
69, 82: Find a number smaller than any of these numbers.
Only 56 fits the description.
Ans:A
Answer: A
Question: Arun and Tarun can do a work in 10 days.After 4 days tarun went to his village.How many days are required to complete the remaining work by Arun alone.Arun can do the work alone in 70 days.
Options:
A)16 days.
B)17 days.
C)18 days.
D)19 days.
E)42 days.
Rationale: They together completed 4/10 work in 4 days.
balance 6/10 work will be completed by Arun alone in 70*6/10 = 42 days.
ANSWER:E
Answer: E
Question: A car gets 40 kilometers per gallon of gasoline. How many gallons of gasoline would the car need to travel 180 kilometers?
Options:
A)8.5 gallons
B)7.5 gallons
C)6.5 gallons
D)5.5 gallons
E)4.5 gallons
Rationale: Each 40 kilometers, 1 gallon is needed. We need to know how many 40 kilometers are there in 180 kilometers?
180 / 40 = 4.5 * 1 gallon = 4.5 gallons correct answer E
Answer: E
Question: A lemonade stand sold only small and large cups of lemonade on Tuesday. 2/5 of the cups sold were small and the rest were large. If the large cups were sold for 7/6 as much as the small cups, what fraction of Tuesday's total revenue was from the sale of large cups?
Options:
A)7/11
B)7/15
C)10/21
D)17/35
E)1/2
Rationale: Let the total # of cups be 10.
# of small cups sold 2/5*10=4;
# of large cups sold 10-4=6;
Let the price of small cup be $6, then the price of larges cup would be 7/6*6=$7;
Revenue from small cups: 4*$6=$24;
Revenue from large cups cups: 6*$7=$42;
Fraction of total revenue from large cups: 42/(42+24)=7/11.
A
Answer: A.
Answer: A
Question: If Scott has earned y dollars by working 7 days a week at a constant daily rate for w weeks, which of the following represents his daily wage?
Options:
A)3yw
B)3w/y
C)w/(7y)
D)yw/7
E)y/(7w)
Rationale: Scott total earning = y
No days he worked = 7
Rate = w
Daily wage = total / (Rate * days)
E is correct answer...
Answer: E
Question: A sum of money place at compound interest doubles itself in 4 years. In how many years will it amount to eight times itself?
Options:
A)22
B)18
C)12
D)88
E)29
Rationale: 100 ---- 200 ---- 4
400 ---- 4
800 ---- 4
------
12 years
Answer: C
Answer: C
Question: 7128+1252=1202+X
Options:
A)7158
B)7149
C)7145
D)7128
E)7178
Rationale: X=1278+1252-1202
X=7128+50
X=7178
CORRECT ANSWER : E
Answer: E
Question: A room of 5m 44cm long and 3m 74cm broad is to be paved with squre tiles. Find the least number of squre tiles required to cover the floor?
Options:
A)178
B)128
C)127
D)176
E)171
Rationale: area of the room = 544 * 374 sq cm
size of largest square tile = H.C.F of 544cm and 374cm= 34cm
area of 1 tile = 34*34 sq cm
no. of tiles required = (544*374) / (34 * 34) = 176
Answer: D
Answer: D
Question: The cost price of 30 articles is the same as the selling price of x articles. If the profit is 25%, what is x?
Options:
A)18
B)20
C)22
D)24
E)26
Rationale: Let the cost price = y
The cost price of 30 articles = 30y
The selling price of x articles = 1.25y*x
1.25y*x = 30y
x = 30 / 1.25 = 24
The answer is D.
Answer: D
Question: By selling 66 bags, a shopkeeper gains the price of 33 bags. His gain per cent is
Options:
A)91%
B)100%
C)95%
D)98%
E)93%
Rationale: Suppose S.P of 66 bags = Rs 66
Therefore, Gain = Rs 33 => C.P = Rs 33
Gain % = 33/33 x 100 = 100%
Gain = 100%
ANSWER:B
Answer: B
Question: A trader cheats both his supplier and customer by using faulty weights. When he buys from the supplier, he takes 30% more than the indicated weight. When he sells to his customer, he gives the customer a weight such that 40% of that is added to the weight, the weight claimed by the trader is obtained. If he charges the cost price of the weight that he claims, find his profit percentage.
Options:
A)28%
B)82%
C)24.33%
D)29.109%
E)78%
Rationale: Anyways, one can infer that he 'steals' 30% from suppliers and then charges 40% extra to customers
So basically 1.3 * 1.4 = 1.82
Given that 1 is start point, we get 21% more
Hence answer is B
Answer: B
Question: Two pipes A and B can fill a cistern in 20 and 30 minutes respectively, and a third pipe C can empty it in 40 minutes. How long will it take to fill the cistern if all the three are opened at the same time?
Options:
A)17 1/5
B)17 1/8
C)17 1/7
D)17 1/1
E)17 1/2
Rationale: 1/20 + 1/30 - 1/40 = 7/120
120/7 = 17 1/7
Answer:C
Answer: C
Question: If two dice are thrown together, the probability of getting an even number on one die and an odd number on the other is?
Options:
A)1/5
B)1/2
C)1/9
D)1/3
E)1/4
Rationale: The number of exhaustive outcomes is 36.
Let E be the event of getting an even number on one die and an odd number on the other. Let the event of getting either both even or both odd then = 18/36 = 1/2
P(E) = 1 - 1/2 = 1/2.
Answer:B
Answer: B
Question: In a class, the average age of 35 boys is 15 years and the average of 25 girls is 10 years. what is the average age of the whole class?
Options:
A)12 Years
B)12.3 Years
C)12.9 Years
D)13 Years
E)15 Years
Rationale: Total age of 60 students
(35X 15+25 X 10) = 775
Average = 775/60 = 12.9 Years
C
Answer: C