divelab/Sys2Bench huggingface dataset:
Question: The ratio of the present age of Viju to that of Aju is 7:2. Four years from now, the ratio of the ages of Viju to Aju will be 5:2. What was Viju age 5 years ago ? (RBI Assistant 2015)
Options:
A)24
B)18
C)12
D)16
E)13
Rationale: Let the present age of Viju be 7x years and that of Aju be 2x years.
Then, 4 years from now
7x + 4 / 2x + 4 = 5 / 2
or 4x = 12
or x = 3
Viju present age = 7 * 3 = 21 years
Viju age 5 years ago = 21 - 5 = 16 years
answer :D
Answer: D
Question: In his room, Dumbo has three trousers. One of them is black, the second is blue, and the third is brown. In his room, he also has four shirts. One of them is black and the other 3 are white. He opens his room in the dark and picks out one shirt and one trouser pair without examining the colour. What is the likelihood that neither the shirt nor the trouser is black?
Options:
A)1/12
B)1/6
C)1/2
D)1/4
E)1/3
Rationale: Probability that trouser is not black = 2/3
Probability that shirt is not black = 3/4
Required probability = 2/3 x 3/4 = 1/2
ANSWER:C
Answer: C
Question: If y exceeds x by 20%, then x is less than y by?
Options:
A)16 2/7%
B)16 7/3%
C)16 2/3%
D)16 2/6%
E)16 1/3%
Rationale: X=100	y=120
120------20
100-------? => 16 2/3%
Answer: C
Answer: C
Question: From 6 positive numbers and 6 negative numbers, how many groups C of 4 numbers, yielding a positive product, can be formed?
Options:
A)720
B)625
C)30
D)960
E)255
Rationale: Potential combinations of 4 numbers that will yield positive product
++++ 4C6
---- 4C6
++-- 2C6*2C6
4C6 + 4C6 + 2C6*2C6
C=15 +15 + 15*15 = 255.E
Answer: E
Question: What is the 9th digit to the right of the decimal point in the decimal equivalent of 48/11?
Options:
A)3
B)5
C)6
D)4
E)2
Rationale: 48/11 = 4.3636....
36 is non-terminating repeating decimal.
The 9th digit to the right of decimal point will be 3.
Answer A
Answer: A
Question: sale of Rs 6835, Rs. 9927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs, 6800 ?
Options:
A)4966
B)6791
C)2877
D)2676
E)1881
Rationale: Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009.
Required sale = Rs.[(6800 x 6) - 34009]
= Rs. (40800 - 34009)
= Rs. 6791
Answer: B
Answer: B
Question: An amount of money is to be divided between P, Q and R in the ratio of 3:7:12. If the difference between the shares of P and Q is Rs.4400, what will be the difference between Q and R's share?
Options:
A)2788
B)5500
C)7282
D)2782
E)2729
Rationale: 4 --- 4400
5 --- ? => 5500
Answer:B
Answer: B
Question: The simple interest on a sum of money will be Rs.600 after 10 years. If the principal is trebled after 5 years what will be the total interest at the end of the tenth year?
Options:
A)2333
B)2777
C)1200
D)1987
E)1671
Rationale: P --- 10 ---- 600
P --- 5 ----- 300
3P --- 5 ----- 900
------
=> 1200
Answer:C
Answer: C
Question: Mike invested $2000 in fund A and $1000 in fund B. Over the next Three years, the money in Fund A earned a total interest of 18 percent for the three years combined and the money in fund B earned 30 percent annual interest compounded annually. Three years after Mike made these investments. Mike's investment in fund A was worth how much more than his investment in fund B?
Options:
A)1. $160
B)2. $150
C)3. $200
D)4. $183
E)5. $163
Rationale: interest on fund A will be 360. rate of interest will be 6% per annum simple interest as 18% is for 3 year. this will make investment A 2360 at the end of 3rd year.
interest on fund B will be 1197 on 30% interest compounded annually. This will make investment B 2197 at the end of 3rd year.
Difference in investment A and investment B=2360-2197=163
answer is E.
Answer: E
Question: 23, 29, 31, 37, 41, 43, (...)
Options:
A)53
B)47
C)48
D)59
E)45
Rationale: Explanation :
All are prime numbers in their order, starting from 23
Hence, next number is 47
Answer : Option B
Answer: B
Question: Of the total amount that Jill spent on a shopping trip, excluding taxes, she spent 50 percent on clothing, 10 percent on food, and 40 percent on other items. If Jill paid a 4 percent tax on the clothing, no tax on the food, and an 8 percent tax on all other items, then the total tax that she paid was what percent of the total amount that she spent, excluding taxes?
Options:
A) 2.8%
B) 3.6%
C) 4.4%
D) 5.2%
E) 6.0%
Rationale: Let amount spent by Jill = 100
Clothing=50, Food=10, others=40
Tax on clothing= 2
Tax on others=3.2
Percentage= 5.2/100 =5.2%
Answer: D
Answer: D
Question: If an object travels at 8 feet per second, how many feet does it travel in forty five minutes?
Options:
A)18000
B)24000
C)21600
D)18000
E)22000
Rationale: If an object travels at 8 feet per second it covers 8x60 feet in one minute, and 8x60x45 feet in forty five minutes.
Answer = 21600 Answer:C
Answer: C
Question: Find the average of the first 23 natural numbers?
Options:
A)8
B)9
C)10
D)11
E)12
Rationale: Average of the first 'n' natural numbers = (n + 1)/2
We get (23 + 1)/2 = 12
ANSWER:E
Answer: E
Question: A family pays $800 per year for an insurance plan that pays 80 percent of the first $1,000 in expenses and 100 percent of all medical expenses thereafter. In any given year, the total amount paid by the family will equal the amount paid by the plan when the family's medical expenses total which of the following?
Options:
A)$1,000
B)$1,200
C)$1,400
D)$1,800
E)$2,200
Rationale: The family pays $800 per year for the plan, plus (100 percent minus 80 percent) or 20 percent of the first $1,000 in medical expenses, while the insurance company pays 80 percent of the first $1,000, or $800. It must pay an additional $200 to match what the family pays out. Since the $200 comes after the first $1,000 in expenses, it must represent 100 percent of additional expenses. Therefore, there must have been $1,000 plus $200 or $1,200 in medical expenses altogether.
B. $1,200
Answer: B
Question: A factory that employs 1000 assembly line workers pays each of these workers $5 per hour for the first 40 hours worked during a week and 1½ times that rate for hours worked in excess of 40. What was the total payroll for the assembly-line workers for a week in which 30 percent of them worked 15 hours, 50 percent worked 40 hours, and the rest worked 50 hours?
Options:
A) $180,000
B) $185,000
C) $190,000
D) $177,500
E) $205,000
Rationale: 30% of 1000 = 300 worked for 15 hours
Payment @ 5/hr
Total Payment = 300*15*5 = 22500
50 % of 1000 = 500 worked for 40 hours
Payment @ 5/hr
Total payment = 500*40*5 = 100000
Remaining 200 worked for 50 Hours
Payment for first 40 Hours @ 5 /hr
Payment = 200*40*5 = 40000
Payment for next 10 hr @ 7.5/hr
Payment = 200 * 10 * 7.5 = 15000
Total Payment = 22500+100000 + 40000 +15000 = 1775000
Hence , answer is D
Answer: D
Question: What is the sum of all remainders obtained when the first 100 natural numbers are divided by 7?
Options:
A)397
B)401
C)403
D)405
E)306
Rationale: A positive integer can give only the following 9 remainders when divided by 9: 1, 2, 3, 4, 5, 6, 7, 8, and 0.
1 divided by 9 gives the remainder of 1;
2 divided by 9 gives the remainder of 2;
...
8 divided by 9 gives the remainder of 8;
9 divided by 9 gives the remainder of 0.
We'll have 11 such blocks, since 99/9=11. The last will be:
91 divided by 9 gives the remainder of 1;
92 divided by 9 gives the remainder of 2;
...
98 divided by 9 gives the remainder of 8;
99 divided by 9 gives the remainder of 0.
The last number, 100, gives the remainder of 1 when divided by 9, thus the sum of all remainders will be:
11(1+2+3+4+5+6+7+8+0)+1=306.
Answer: E.
Answer: E
Question: A = {2, 3, 4, 5}
B = {4, 5, 6, 7, 8}
Two integers will be randomly selected from the sets above, one integer from set A and one integer from set B. What is the probability J that the sum of the two integers will equal 9 ?
Options:
A) 0.15
B) 0.20
C) 0.25
D) 0.30
E) 0.33
Rationale: Rearrange the first set:
A = {5,4,3,2}
B = {4,5,6,7, 8}
As you can see numbers in each column (the numbers of the same color) give the sum of 9. So there are 4 such pares possible, total # of pairs is 4*5=20. J=favorable/total=4/20=0.2.
Answer: B.
Or: we can select ANY number from set A (4/4=1) but in this case we must select its matching pair from set B (the number of the same color) and since there are only one matching pair of this particular number in B then the probability of this is 1/5. So, overall: J=1*1/5.
Answer: B.
Answer: B
Question: Two cars cover the same distance at the speed of 40 and 24 kmps respectively. Find the distance traveled by them if the slower car takes 2 hour more than the faster car?
Options:
A)278
B)480
C)960
D)278
E)261
Rationale: 40(x + 2) = 24x
X = 8
60 * 8 = 480 km
Answer:B
Answer: B
Question: A certain sum of money is divided among A, B and C so that for each Rs. A has, B has 65 paisa and C 40 paisa. If C's share is Rs.40, find the sum of money?
Options:
A)298
B)207
C)238
D)205
E)293
Rationale: A:B:C = 100:65:40
= 20:13:8
8 ---- 40
41 ---- ? => Rs.205
Answer:D
Answer: D
Question: In a renowned city, the average birth rate is 8 people every two seconds and the death rate is 6 people every two seconds. Estimate the size of the population net increase that occurs in one day.
Options:
A)32,300
B)172,800
C)468,830
D)86,400
E)259,200
Rationale: Every 2 seconds, 2 persons are added (8-6). Every second 1 persons are added.
In a day 24hrs = 24 * 60 Minutes = 24 * 60 * 60 = 86400 seconds.
86400 * 1 = 86400
Option D
Answer: D
Question: A and B started a business with initial investments in the ratio 4 : 3, after some months B withdrawn his investment, and their share in the annual profits were in the ratio 8 : 7. Then how long B was in the business ?
Options:
A)6 months
B)8 months
C)9 months
D)5 months
E)14 months
Rationale: Let Sumit in the business for ‘a’ months.
Investment Ratio Amit to Sumith = 4 : 3.
Profit sharing ratio = 8 : 7.
Amit is in the business for 12 months.
Then Sumit in the business for
(4 × 12) / (3 × a) = 8 / 7 => 24a = 336 or
a = 336 / 24 = 14 or 14 months
Option E
Answer: E
Question: A, B and C can do a piece of work in 24, 30 and 40 days respectively. They start the work together but C leaves 4 days before the completion of the work. In how many days is the work done?
Options:
A)33 days
B)77 days
C)99 days
D)11 days
E)18 days
Rationale: x/24 + x/30 + x/40 = 1
x = 11 days
Answer: D
Answer: D
Question: In how many of ways can 4 balls be placed in 4 tins if any number of balls can be placed in any tin?
Options:
A) 5C4
B) 5P4
C) 54
D) 4^4
E) 5^5
Rationale: Now, each of the 4 different balls has 4 choices (4 tins to go to), so total # of distribution is 4*4*4*4=4^4.
Answer: D.
Answer: D
Question: 5^4 + 5^4 + 5^4 + 5^4 =
Options:
A)5^5
B)5^6
C)4^8
D)4^9
E)4^12
Rationale: Hi shakticnb,
Certain Quant questions on the GMAT are just about 'organizing' the information in a specific way. If you find yourself getting confused by a prompt, think about how you might change the way that the information is presented to you.
Here, for example, we're asked for....
5^4 + 5^4 + 5^4 + 5^4 =
Now, the GMAT doesn't really expect us to calculate this sum (but we could if we had to), but we are expected to find a way to organize this information... If, instead of all of those exponents, we had...
X + X + X + X =
What would the sum be?
Clearly, it would be 4(X) = 4X.....since we're just combining 'like' terms. Take that same idea with this prompt and you have...
5^4 + 5^4 + 5^4 + 5^4 =
5(5^4)
This can be re-written as...
(5^1)(5^4)
...and now we can use exponent rules; since we're MULTIPLYING 'bases' that are the same, we ADD the exponents...
(5^1)(5^4) = 5^5
Final Answer:
A
Answer: A
Question: A train is moving at the speed of 80 km/hr. What is its speed in metres per second?
Options:
A)22 2/9 m/s
B)22 8/9 m/s
C)22 2/7 m/s
D)22 2/5 m/s
E)22 3/9 m/s
Rationale: Speed = 80 km/hr = 80×518 m/s = 40×59 m/s = 2009 m/s = 22 2/9 m/s
Answer : A
Answer: A
Question: The length of a side of a hexagon is 2 inches. What is the perimeter?
Options:
A)11
B)12
C)13
D)14
E)15
Rationale: Hexagon. It means 6 equal sides.
p = 2 + 2 + 2 + 2 + 2 + 2 = 4 + 4 + 4 = 8 + 4 = 12 inches
Answer B
Answer: B
Question: Find the constant k so that : -x2 - (k + 7)x - 8 = -(x - 2)(x - 4)
Options:
A)-11
B)-12
C)-13
D)-14
E)-15
Rationale: -x2 - (k + 7)x - 8 = -(x - 2)(x - 4) : given
-x2 - (k + 7)x - 8 = -x2 + 6x - 8
-(k + 7) = 6 : two polynomials are equal if their corresponding coefficients are equal.
k = -13 : solve the above for k
correct answer C
Answer: C
Question: Find out the square of a number which when doubled exceeds its one seventh by 13 ?
Options:
A)16
B)49
C)19
D)26
E)17
Rationale: A
Let the number be p, then the square will be p^2
According to question:
2p = (p/7) + 13
=> 14p = p +91
=> p = 7
p^2 = 7^2 = 49.
Answer : B
Answer: B
Question: The average of a set of five distinct integers is 350. If each number is less than 2,000, and the median of the set is the greatest possible value, what is the sum of the two smallest numbers?
Options:
A)-4,244
B)-3,997
C)-3,494
D)-3,194
E)The answer cannot be determined from the information given
Rationale: Sum of the set = 350*5=1750 Each number is less than 2000 and median of the set is the greatest possible value.
Therefore last 3 numbers can be 1999,1998 and 1997. Their sum=5994.
Therefore sum of two smallest numbers= 1750-5994= -4244
Answer=A
Answer: A
Question: What will come in place of the x in the following Number series? 11, 14, 19, 22, 27, 30, 35, 38, 43, 46, 51 x
Options:
A)29
B)31
C)23
D)54
E)59
Rationale: (D)
The pattern is + 3, + 5, + 3, + 5, …………
So the missing term is = 51 + 3 = 54.
Answer: D
Question: In the biology lab of "Jefferson" High School there are 1.08*10^6 germs, equally divided among 10,800 Petri dishes. How many germs live happily in a single dish?
Options:
A)100
B)200
C)500
D)1000
E)5000
Rationale: 1.08*10^6/ 10800==> 10.8*10^3/108==> 10800/108= 100
ANSWER:A
Answer: A
Question: Two employees A and B are paid a total of Rs. 550 per week by their employer. If A is paid 120 percent of the sum paid to B, how much is B paid per week?
Options:
A)Rs.150
B)Rs.220
C)Rs.250
D)Rs.300
E)Rs.310
Rationale: Let the amount paid to A per week = x
and the amount paid to B per week = y
Then x + y = 550
But x = 120% of y = 120y/100 = 12y/10
∴12y/10 + y = 550
⇒ y[12/10 + 1] = 550
⇒ 22y/10 = 550
⇒ 22y = 5500
⇒ y = 5500/22 = 500/2 = Rs.250
C)
Answer: C
Question: P is three times as fast as Q and working together, they can complete a work in 15 days. In how many days can Q alone complete the work?
Options:
A)16 days
B)17 days
C)19 days
D)14 days
E)20 days
Rationale: P = 3Q
P + Q = 3Q + Q = 4Q
These 4Q people can do the work in 15 days, which means Q can do the work in 60 days.
Hence, P can do the work in 20 days.
Answer:E
Answer: E
Question: A sum of Rs. 1360 has been divided among A, B and C such that A gets 2/3 of what B gets and B gets 1/4 of what C gets. B's share is:
Options:
A)Rs.120
B)Rs. 160
C)Rs.240
D)Rs.300
E)Rs.500
Rationale: Let C's share = Rs. x
Then, B's share = Rs. x/4; A's share = Rs.2/3 * x/4= Rs. x/6
Therefore x/6 + x/4 + x = 1360
17x/12 = 1360
x= 1360*12/17= Rs.960
Hence, B's share= Rs.960/4= Rs.240
ANSWER:C
Answer: C
Question: Four times the first of the three consecutive even integers is 7 more than thrice the second. The third integer is
Options:
A)9
B)11
C)13
D)17
E)15
Rationale: Solution
Let the three integers be x, x+2, x+4 4x = 7 + 3(x+2) x = 13 Third integer is x+4 = 13+4 = 17.
Answer D
Answer: D
Question: Running at the same rate, 8 identical machines can produce 560 paperclips a minute. At this rate, how many paperclips could 18 machines produce in 6 minutes?
Options:
A)1344
B)3360
C)7560
D)50400
E)67200
Rationale: 8 machines produce 560 in 1 min
8 machines produce 560* 6 in 6 min
18 machine produce 560*6*(18/8) in 6 minutes
560*6*18/8=7560 answer is C.
Answer: C
Question: A train is moving at a speed of 45km/hr and its length is 500m. Find the time taken by it to pass a man standing near the railway line?
Options:
A)30sec
B)45sec
C)40sec
D)29sec
E)52sec
Rationale: Speed of the train = 45*5/18 = 25/2 m/sec
Distance moved in passing the standing man = 500m
Required time taken = 500/(25/2) = 40sec
Answer is C
Answer: C
Question: John completes a piece of work in 10 days, Jerry completes the same work in 40 days. If both of them work together, then the number of days required to complete the work is?
Options:
A)4 days
B)8 days
C)10 days
D)12 days
E)13 days
Rationale: If A can complete a work in x days and B can complete the same work in y days, then, both
of them together can complete the work in x y/ x+ y days.
That is, the required No. of days = 10 × 40/50 = 8 days.
B)
Answer: B
Question: How many pairs t, t+1) have one or more prime factors common, where t is an integer and 2 ≤ t ≤9 ?
Options:
A)0
B)1
C)2
D)3
E)4
Rationale: t and t+1 are consecutive integers.
Two consecutive integers are co-prime, which means that they don't share ANY common factor but 1. For example 20 and 21 are consecutive integers, thus only common factor they share is 1.
Answer: A.
Answer: A
Question: In a certain Parallelogram the degree measure of one angle exceeds that of the other by 50 what is the degree measure of the smaller angle?
Options:
A)65
B)80
C)85
D)90
E)95
Rationale: In a parallelogram opposite angles are equal and the angles at each side are supplementary to each other (supplementary angles are two angles that add up to 180°).
Given: x+(x+50)=180 --> x=65.
Answer: A.
Answer: A
Question: Rani worked in the Private company. At the time of Interview officer told her to give Salary Rs. 15000/- per month & Also 2-3 % to be increased in every month. she have taken 2-3 leaves. After one month she got Rs. 13950/- then How much amount increased to her? What is the percentage value?
Options:
A)300-1%
B)400- 2%
C)405 -3%
D)2150- 5%
E)500 - 3%
Rationale: Rani's Total Salary : 15000/-
Leave Days : 3days
3 days salary : 1500/-
Salary after leaves : 15000-1500 = 13500/-
Amount received : 13905/-
Difference amount = received amount- payable amount
ie, 13905 - 13500 = 405/-
Percentage value = 405/13500*100 = 3%
Answer is (C)
Answer: C
Question: The ratio of the number of boys and girls in a college is 7:8. If the percentage increase in the number of boys and girls be 20% and 10% respectively. What will be the new ratio?
Options:
A)21:29
B)21:31
C)21:22
D)21:31
E)21:12
Rationale: Originally, let the number of boys and girls in the college be 7x and 8x respectively.
Their increased number is (120% of 7x) and (110% of 8x).
i.e., (120/100 * 7x) and (110/100 * 8x)
i.e., 42x/5 and 44x/5
Required ratio = 42x/5 : 44x/5 = 21:22
Answer: C
Answer: C
Question: A taxi leaves Point A 4 hours after a bus left the same spot. The bus is traveling 30 mph slower than the taxi. Find the speed of the taxi, if it overtakes the bus in two hours.
Options:
A)40
B)42
C)45
D)48
E)49
Rationale: Let the speed of bus be v - 30, speed of taxi be v
The bus travelled a total of 6 hrs and taxi a total of 2 hrs.
Hence 6 * (v-30) = 2v
6v - 180 = 2v
4v = 180
v = 45 mph
C
Answer: C
Question: 72 67 66 61 60 ...?
Options:
A)52
B)53
C)54
D)55
E)56
Rationale: Sequence = 72 67 66 61 60 55
There is 2 series :
1st series = 72 66 60 (decreasing by 6)
2nd series = 67 61 55 (decreasing by 6)
ANSWER:D
Answer: D
Question: John makes $60 a week from his job. He earns a raise andnow makes $68 a week. What is the % increase?
Options:
A)16.12%
B)16.66%
C)16.56%
D)17.66%
E)13.33%
Rationale: Increase = (8/60)*100 = (2/15)*100 = 13.33%.
E
Answer: E
Question: If -4 < x < 8 and -6 < y < 3, which of the following specifies all the possible values of xy?
Options:
A)-42 < xy < 21
B)-48< xy < 24
C)-28 < xy < 18
D)-24 < xy < 21
E)-24 < xy < 24
Rationale: The least value of xy is a bit more than 8*(-6)=-48 and the largest value of xy is a bit less than (-4)*(-6)=24.
Therefore -48 < xy < 24.
Answer: B.
Answer: B
Question: The average age of 3 children in a family is 20% of the average age of the father and the eldest child. The total age of the mother and the youngest child is 39 years. If the father's age is 26 years. What is the age of the second child?
Options:
A)15 years
B)16 years
C)18 years
D)Cannot be determined
E)None
Rationale: Solution
Since the total or average age of all the family members is not given, the given data is inadequate. So, the age of second child cannot be determined.
Answer D
Answer: D
Question: 5n + 2 > 17 and 7n - 5 < 44; n must be between which numbers?
Options:
A)1 and 8
B)2 and 6
C)0 and 9
D)3 and 7
E)2 and 9
Rationale: 5n > 15 --> n > 3
7n < 49 --> n < 7
3 < n < 7
Answer: D
Answer: D
Question: Anand and Deepak started a business investing Rs. 22,500 and Rs.35,000 respectively. Out of a total profit of Rs.13,800, Deepak’s share is _____
Options:
A)5400
B)3797
C)27877
D)2772
E)9911
Rationale: Explanation:
Ratio of their investments = 22500 : 35000 = 9 : 14
So Deepak' s share = 923923 × 13800 = Rs.5,400
Answer: A
Answer: A
Question: What is the greatest value of positive integer x such that 2^x is a factor of 100^50?
Options:
A)70
B)80
C)90
D)100
E)120
Rationale: Put in simple words, we need to find the highest power of 2 in 100^50
100 = 2^2*5^2
Therefore 100^50 = (2^2*5^2)^50 = 2^100*5^100
Answer : D
Answer: D
Question: A swimmer can swim in still water at 4 km/h. If the speed of the water current is 2 km/h, how many hours will the swimmer take to swim against the current for 8 km?
Options:
A)1
B)2
C)3
D)4
E)5
Rationale: The swimmer can swim against the current at a speed of 4-2 = 2 km/h.
The time it will take is 8/2 = 4 hours.
The answer is D.
Answer: D
Question: The total of the ages of Jayant, Prem and Saransh is 75 years. Ten years ago, the ratio of their ages was 2 : 3 : 4. What is the present age of Saransh?
Options:
A)30 years
B)32 years
C)34 years
D)38 years
E)None
Rationale: Solution
Let the ages of Jayant, Prem and Saransh 10 years ago be 2x, 3x and 4x years respectively. Then,
(2x + 10)+(3x + 10)+(4x + 10)	= 75.
‹=›9x = 45
x = 5.
∴ Saransh's present age = 4x + 10 = 30 years.
Answer A
Answer: A
Question: How many ways are there to award a gold and bronze medal to 10 contending teams?
Options:
A)10 × 9
B)10!/(3!7!)
C)10!/3!
D)360
E)300
Rationale: we clearly know that there can be only one winning team which deserves the gold medal. we can do the selection in 10 ways
if gold medal is given to 1 of the teams then only possible 9 teams can be considered for bronze medal. we can do selection in 9 ways
Total number of ways to select the 3 possible medal winners = 10 * 9
Correct answer - A
Answer: A
Question: At what price must an article costing Rs.47.50 be marked in order that after deducting 5% from the list price. It may be sold at a profit of 25% on the cost price?
Options:
A)Rs.62.50
B)Rs.72.50
C)Rs.75.00
D)Rs.80.00
E)Rs.85.00
Rationale: CP = 47.50
SP = 47.50*(125/100) = 59.375
MP*(95/100) = 59.375
MP = 62.5
ANSWER:A
Answer: A
Question: What is the value of: 3^8 + 3^10 ?
Options:
A) 7(3^8)
B) 10(3^8)
C) 3^18
D) 3^80
E) 6^18
Rationale: 3^8 + 3^10 = 3^8 (1 + 3^2) = 3^8 (1 + 9) = 10 (3^8), Answer B.
Answer: B
Question: How many 3 digit odd numbers do not use any digit more than once
Options:
A)1720
B)216
C)224
D)2460
E)280
Rationale: The Way i solved it is
A B C ( hundreds, tens, units
)C can be 1 3 5 7 9 ( any of the 5 digits )
A can be anything except (D or 0) so 8 possibilitie
B can be anything execpt ( A D C ) so 7 possibilities
total ways are 7 * 8 * 5 = 280
Ans : E
Answer: E
Question: A number was divided successively in order by 4,5,6 the remainder was respectively 2,3,4 the numbers are?
Options:
A)1
B)2
C)3
D)4
E)8
Rationale: let x=6q+3
then x^2=(6q+3)^2=6(6q^2+6q+1)+3
thus the remainder is 3
The Answer is(C)
Answer: C
Question: one father gave 10 cents to one son and 15 cents to another son so now what is the time
Options:
A)Quarter to 1
B)Quarter to 2
C)Quarter to 3
D)2
E)1
Rationale: 10+15 = 25 cents .. one quarter given to two sons.
Quarter to 2
ANSWER:B
Answer: B
Question: P and Q invested in a business. The profit earned was divided in the ratio 2 : 3. If P invested Rs 40000, the amount invested by Q is
Options:
A)Rs. 40000
B)Rs. 50000
C)Rs. 60000
D)Rs. 70000
E)None
Rationale: Solution: Let the amount invested by Q = q.
40000 : q = 2 : 3.
=> 40000/q = 2/3.
=> q = 40000 * (3/2) = Rs. 60000.
Answer: Option C
Answer: C