divelab/Sys2Bench huggingface dataset:
Question: On a scale that measures the intensity of a certain phenomenon, a reading of a+1 corresponds to an intensity that is 10 times the intensity corresponding to a reading of a. On that scale, the intensity corresponding to a reading of 8 is how many times as great as the intensity corresponding to a reading of 3?
Options:
A) 5
B) 50
C) 10^5
D) 5^10
E) 8^10 - 3^10
Rationale: To solve this problem we need to examine the information in the first sentence. We are told that “a reading of a + 1 corresponds to an intensity that is 10 times the intensity corresponding to a reading of a.”
Let’s practice this idea with some real numbers. Let’s say a is 2. This means that a + 1 = 3. With the information we were given we can say that a reading of 3 is ten times as great as the intensity of a reading of 2.
Furthermore, we can say that a reading of 4 is actually 10 x 10 = 10^2 times as great as the intensity of a reading of 2.
Increasing one more unit, we can say that a reading of 5 is 10 x 10 x 10 = 10^3 times as great as the intensity of a reading of 2.
We have found a pattern, which can be applied to the problem presented in the stem:
3 is “one” unit away from 2, and thus a reading of 3 is 10^1 times as great as the intensity of a reading of 2.
4 is “two” units away from 2, and thus a reading of 4 is 10^2 times as great as the intensity of a reading of 2.
5 is “three” units away from 2, and thus a reading of 5 is 10^3 times as great as the intensity of a measure of 2.
We can use this pattern to easily answer the question. Here we are being asked for the number of times the intensity corresponding to a reading of 8 is as great as the intensity corresponding to a reading of 3. Because 8 is 5 units greater than 3, a reading of 8 is 10^5 times as great as the intensity corresponding to a reading of 3.
Answer C.
Answer: C
Question: Two family reunions are happening at the same hotel, the Oates reunion and the Yellow reunion. All 100 guests at the hotel attend at least one of the reunions. If 42 people attend the Oates reunion and 65 people attend the Yellow reunion, how many people attend both reunions?
Options:
A) 2
B) 7
C) 10
D) 16
E) 22
Rationale: No of people in Oates reunion=42
No of people in Yellow reunion=65
Attending both=x
All guests attend at least one.
Therefore, 100=42+65-(Both)
Both=7
Answer B
Answer: B
Question: Harriet planned to complete a certain task on Wednesday, January 1, but because of illness the completion date was postponed 45 days. On which day of the week in February was the task completed?
Options:
A)Tuesday
B)Wednesday
C)Saturday
D)Sunday
E)Monday
Rationale: This type of story problem is essentially just about a repeating pattern and a 'remainder.'
We're told that Harriet planned to complete a certain task on WEDNESDAY, January 1, but because of illness the completion date was postponed 45 DAYS. We're asked on what day of the week the task was actually completed on.
Since the task was supposed to be completed on a Wednesday....
A 1 day postponement would be Thursday
A 2 day postponement would be Friday
A 3 day postponement would be Saturday
A 4 day postponement would be Sunday
A 5 day postponement would be Monday
A 6 day postponement would be Tuesday
A 7 day postponement would be Wednesday
A 8 day postponement would be Thursday
Etc.
So this question is ultimately asking how many 'groups of 7' are there, and how many 'leftover days' are there, when you postpone 45 days.
45/7 = 6 remainder 3
This means that there are 6 full weeks AND 3 extra days after a Wednesday....Thus, the task was completed on a Saturday.
C
Answer: C
Question: If abc = ab^3 = 180 where a, b and c are positive integers, what is the value of `c’?
Options:
A)0
B)1
C)2
D)3
E)4
Rationale: abc = a(b^3) = 180
on solving abc = a(b^3) we get c = b^2
and for a(b^3) = 180 , there is only one possibility a = 180 and b = 1 so c = 1^2 = 1
ANSWER:B
Answer: B
Question: Find the number of ways in which 8064 can be resolved as the product of two factors?
Options:
A)22
B)24
C)21
D)20
E)19
Rationale: Solution:
Total number of ways in which 8064 can be resolved as the product of two factors is 24 as below:
(1,8064), (2,4032), (3,2688), (4,2016), (6,1344), (7,1152),(8,1008), (9,896), (12,672), (14,576), (16,504), (18,448), (21,884), (24,336), (28,288), (32,252), (36,224), (42,192), (48,168), (56,144), (63,128), (68,126), (72,112), (84,96).
Answer: Option B
Answer: B
Question: How many paying stones, each measuring 4 m * 2 m are required to pave a rectangular court yard 40 m long and 20 m board?
Options:
A)99
B)18
C)100
D)17
E)12
Rationale: 40 * 20 = 4 * 2 * x => x
= 100
Answer: C
Answer: C
Question: 4000 was divided into two parts such a way that when first part was invested at 3% and the second at 5%, the whole annual interest from both the investments is Rs.144, how much was put at 3%?
Options:
A)2277
B)2882
C)2800
D)2677
E)2211
Rationale: (x*3*1)/100 + [(4000 - x)*5*1]/100 = 144
3x/100 + 200 – 5x/100 = 144
2x/100 = 56 è x = 2800
Answer: C
Answer: C
Question: A shop produces sarongs. The daily average production is given by 5n + 20, where n is the number of workers aside from the owner. In the first k days, 500 units are produced, and then 5 workers are added to the team. After another k days, the cumulative total is 900. How many workers were part of the latter production run?
Options:
A)A)6
B)B)10
C)C)11
D)D)15
E)E)34
Rationale: The daily average production is given by 5n + 20- given
In the first k days, 500 units are produced
= (5n+20)K =500
k = 500/5n+20...................................1
5 workers were added = 5(n+5)+20 = 5n +45
cumulative is 900 .. thus for the current period = 900 -500 = 400
(5n+45)K= 400
k = 400/5n+45........................................2
equate 1 and 2
500/5n+20 = 400 /5n+45
500(5n+45) = 400(5n+20)
25n + 225 = 20n + 80
5n =145
n = 29
thus n+5 = 34
hence E
Answer: E
Question: An amount at compound interest sums to Rs.17640/- in 2 years and to Rs.18522/- in 3 years at the same rate of interest. Find the rate percentage?
Options:
A)5%
B)6%
C)7%
D)8%
E)9%
Rationale: The difference of two successive amounts must be the simple interest in 1 year on
the lower amount of money.
S.I = 18522/- - 17640/- = Rs. 882/-
Rate of interest = (882/17640) × (100/1) => 8820/1764 = 5%
Principal = Amount/(1 + R/100)n
= 17640/(1 + 5/100)2
= 17640/(21/20 × 21/20)
= 17640/(1.05 × 1.05)
= 17640/1.1025
= 16000
Thus the principal is Rs.16000/- and the rate of interest is 5%
A
Answer: A
Question: An urn contains g green marbles and b blue marbles. If 3 green marbles and 4 blue marbles are added, and then one marble is selected at random from the urn, what is the probability that a blue marble will be drawn?
Options:
A)b/(b+g)
B)(b+5)/(g+3)
C)(b+5)/(b+g+8)
D)(b+4)/(b+g+7)
E)b/(b+g+5)
Rationale: no of fav outcomes i.e. blue MArbles = b+4
Total no of outcomes i.e. total Marbles = (b+4)+(g+3)= b+g+7
probability = (b+4) /(b+g+7)
Answer D
Answer: D
Question: A, B and C are partners. A receives 2/3 of profits, B and C dividing the remainder equally. A's income is increased by Rs.300 when the rate to profit rises from 5 to 7 percent. Find the Capital of C?
Options:
A)3377
B)2899
C)3750
D)2778
E)1991
Rationale: A:B:C = 2/3:1/6:1/6 = 4:1:1
x * 2/100 * 2/3 = 300
C's capital = 22500*1/6 = 3750
Answer: C
Answer: C
Question: Walking at 5/6th of its usual speed a cab is 6mnts late. Find its usual time to cover the journey?
Options:
A)25m
B)30m
C)32m
D)50m
E)62m
Rationale: New speed = 5/6th of usual speed
New time = 6/5th of usual time
6/5 UT - UT = 6m
UT/5 = 6m
UT = 30m
Answer is B
Answer: B
Question: A certain auto manufacturer sold 4% fewer vehicles in 2007 than in 2006. If the manufacturer sold 2.1 million vehicles in 2006, how many vehicles, to the nearest 10,000, did the manufacturer sell in 2007?
Options:
A)63,000
B)2,000,000
C)2,030,000
D)2,040,000
E)2,300,000
Rationale: Let's assume in 2006 he has sold X. Therefore in 2007 he should have sold 97/100×X.
97/100×2100=2037
-->2,037,000 sold in 2007. When rounded to the nearest 10,000 :
2,000,000
B
Answer: B
Question: If (12z)/(5 - 6x/y) = 4z then which of the following is true?
Options:
A)2x = 3y
B)3x = 2y
C)x = 3y
D)3x = y
E)2x = y
Rationale: (12z)/(5 - 6x/y) = 4z
=> 12zy/(5y - 6x) = 4z
=> 3y/(5y -6x) = 1
=> 3y = 5y - 6x
=> -2y = -6x
=> y = 3x
Hence Ans is D
Answer: D
Question: The sum and the product of two numbers are 25 and 144 respectively, the difference of the number is?
Options:
A)1
B)6
C)7
D)8
E)2
Rationale: Explanation:
x + y = 25
xy = 144
(x- y)2 = (x + y)2 â€“ 4xy
(x- y)2 = 625 â€“ 576 => (x â€“ y) = 7
Answer: C
Answer: C
Question: 76 is divided into two parts in such a way that seventh part of first and ninth part of second are equal. Find the smallest part?
Options:
A)13.25
B)38.25
C)33.25
D)34.25
E)31.25
Rationale: x/7 = y/9 => x:y = 7:9
7/16 * 76 = 33.25
ANSWER:C
Answer: C
Question: A, B and C enter into a partnership and their shares are in the ratio 1/2 : 1/3 : 1/4. After 2 months, A withdraws half of his capital and after 10 months, a profit of Rs. 378 is divided among them. What is B's share ?
Options:
A)144
B)377
C)377
D)288
E)271
Rationale: Explanation:
Ratio of initial investments = 1/2 : 1/3 : 1/4 = 6 : 4 : 3.
Let their initial investments be 6x, 2x and 3x respectively.
A : B : C = (6x * 2 + 3x * 10) : (4x * 12) : (3x * 12) = 42 : 48 : 36 = 7 : 8 : 6.
B's share = Rs. (378 * 8/21) = Rs. 144.
Answer: A) 144
Answer: A
Question: Of the 50 researchers in a workgroup, 50 percent will be assigned to Team A and the remaining 50 percent to Team B. However, 70 percent of the researchers prefer Team A and 30 percent prefer Team B. What is the lowest possible number of researchers who will NOT be assigned to the team they prefer?
Options:
A) 15
B) 17
C) 10
D) 25
E) 30
Rationale: I solved it by assuming 100 people and then dividing my answer in two to save time on calculations. (percentage equals number of people) In that case
50 will be in team A
50 will be in team B
The larger diff is
70 want team A so diff is 70-50=20. At least 20 people will NOT get their wish, so for 50 researchers the same number is 10.
Answer choice C
Answer: C
Question: John had a stock of 1200 books in his bookshop. He sold 75 on Monday, 50 on Tuesday, 64 on Wednesday, 78 on Thursday and 135 on Friday. What percentage of the books were not sold?
Options:
A)66.5%
B)96.5%
C)56.5%
D)46.5%
E)26.5%
Rationale: Let N be the total number of books sold. Hence
N = 75 + 50 + 64 + 78 + 135 = 402
Let M be the books NOT sold
M = 1200 - N = 1200 - 402 = 798
Percentage
Books not sold / total number of books = 798/1200 = 0.665 = 66.5%
correct answer A
Answer: A
Question: In a class,9 students like to play Basketball and 8 like to play Cricket. 6 students like to play on both Basketball and Cricket. How many students like to play Basketball or Cricket or both?
Options:
A)12
B)11
C)16
D)18
E)22
Rationale: Draw a Venn Diagram yourself !
B + C - BC = Number of students that play either Basketball or Cricket
9 +8 - 6 = 11
B)
Answer: B
Question: What will be the cost of building a fence around a square plot with area equal to 289 sq ft, if the price per foot of building the fence is Rs. 58?
Options:
A)3944
B)5667
C)5525
D)2466
E)2665
Rationale: Let the side of the square plot be a ft.
a2 = 289 => a = 17
Length of the fence = Perimeter of the plot = 4a = 68 ft.
Cost of building the fence = 68 * 58 = Rs. 3944.
Answer: Option A
Answer: A
Question: Three years ago the average age of a family of six members was 19 years. A boy have been born, the average age of the family is the same today. What is the age of the boy?
Options:
A)5
B)6
C)2
D)3
E)1
Rationale: 6 * 22 = 132
7 * 19 = 133
--------------
1
ANSWER E
Answer: E
Question: Lakshmi has $100 in her piggy bank. How much will she have in her bank 15 weeks from now if she puts $1 in the bank next week, $2 two weeks from now, $3 three weeks from now, and continues to increase the amount that she puts in by $1 each week?
Options:
A)210
B)220
C)230
D)240
E)250
Rationale: The dollar deposits are in an A.P.
1,2,3,4...15with common difference 1
Sum of the terms is n(n+1) / 2
i.e 15* (15+1) /2
= 15* 16/2 = 120
Total deposit therefore with Chiu-Lihas is 100 + 120= 220$
Answer: B
Question: If the average (arithmetic mean) of 5 positive temperatures is x degrees Fahrenheit, then the sum C of the 3 greatest of these temperatures, in degrees Fahrenheit, could be
Options:
A)6x
B)C=4x
C)C=5x/3
D)C=3x/2
E)3x/5
Rationale: OA please. Yeah so 5x is the sum of the 5, then I guess 4x could be the answer (B)
But what about C,D,E? Any ideas why these could be wrong?
Note that we have 5 positive temperatures.
Next, as the average is x then the sum of the temperatures is 5x and as all the temperatures are positive then the sum of the 3 greatest must be more than (or equal to) 3x (as the average of the 3 greatest must be at least x) and less than 5x: 3x<SUM<5x --> only option B fits.
Answer: B.
Answer: B
Question: A lighting store is stocked with 410 fixtures. Some of the fixtures are floor lamps and the rest are table lamps. If 5% of the floor lamps and 30% of the table lamps are imported, what is the smallest possible number of imported lamps stocked at the store?
Options:
A)3
B)10
C)13
D)20
E)23
Rationale: F + T = 410
Now, expression for the no. of imported items = 0.05F+0.3T
=> 0.05F+0.3(410-F)=123-0.25F
=>F has to be a multiple of 4
to minimize the expression, we have to maximize F
Max value of F can only be 400, as anything beyond this (404 or 408) will give a fractional value of the no. of imported Ts
Hence, minimum no. of imported stuff = 123-400/4 = 23
ANSWER:E
Answer: E
Question: I have a fruit basket with only apples, pears and oranges. I have as many apples in grams as pears in hectograms, and I have as many apples in hectograms and oranges in kilograms. I have a total of 60 kilograms of fruit. How many oranges in kilograms do I have?
Options:
A)5 kilograms
B)20 kilograms
C)10 kilograms
D)15 kilograms
E)50 kilograms
Rationale: Let o be the oranges’ weight in kilograms. If p is the weight of pears in kilograms, then pears are p10 hectograms. If a is apples’ weight in kilograms, then apples’ is a1000 grams. Thus,a1000 = p10Since apples is a10 hectograms,a10 = oSince apples, pears and oranges together are 60 kilograms,a + p + o = 60The above system of 3 equations in 3 unknowns (a, p and o) can be solved as follows:o / 10 +10o + o = 60 oro + 100o + 10o = 600 oro = 600 / 111 = 5 yearsAnswer = A
Answer: A
Question: A carpenter constructed a rectangular sandbox with a capacity of 10 cubic feet. If the carpenter made instead a sandbox which was twice as long, twice as wide and twice as high as the original, what would the capacity be of the new larger sandbox?
Options:
A)20
B)40
C)60
D)80
E)100
Rationale: Explanation:
When all the dimensions of a three dimensional object are in fact doubled, then the capacity increases by a factor of 2x2x2=2^3=8. Thus the capacity of the new sandbox is 8x10=80 cubic feet.
Answer: Option D
Answer: D
Question: A farmer spent $35 on feed for chickens and goats. He spent 40% money on chicken feed, which he bought at a 60% discount off the full price, and spent the rest on goat feed, which he bought at full price. If the farmer had paid full price for both the chicken feed and the goat feed, what amount would he have spent on the chicken feed and goat feed combined?
Options:
A)$37.80
B)$38.50
C)$39.20
D)$39.50
E)$51
Rationale: A farmer spent 40% money on chicken feed, so he spent 0.4*$35=$14 on chicken feed, thus he spent the remaining 35-14=$21 on goat feed.
Now, since he bought chicken feed at a 20% discount then the original price of it was x*0.4=$14 --> x=$35.
Therefore if the farmer had paid full price for both the chicken feed and the goat feed, then he would he have spent 35+21=$51.
Answer: E.
Answer: E
Question: don and his wife each receive an 8 percent annual raise. if don receives a raise rs.800 and his wife receives a raise of rs. 840, what is the difference between their annual income after their raises?
Options:
A)40
B)460
C)500
D)540
E)150
Rationale: Don salary 8% = 800 ; Therefore, 100% = 10000
His wife salary 8% = 840; Therefore, 100% = 10500
After raise 8%,
Don salary = 10000 + 800 = 10800
And his wife salary = 10500+ 840 = 11340
Difference = 11340 - 10800 = 540
ANSWER:D
Answer: D
Question: A is faster than B. A and B each walk 24 km. The sum of their speeds is 7 km/hr and the sum of times taken by them is 14 hours. Then, A's speed is equal to?
Options:
A)2 km/hr
B)3 km/hr
C)4 km/hr
D)7 km/hr
E)8 km/hr
Rationale: B
Let A's speed = x km/hr. Then, B's speed = (7 - x) km/ hr.
So, 24/x + 24/(7 - x) = 14
x2 - 98x + 168 = 0
(x - 3)(x - 4) = 0 => x = 3 or 4.
Since, A is faster than B, so A's speed = 4 km/hr and B's speed = 3 km/hr.
Answer: B
Question: Natasha climbs up a hill, and descends along the same way she went up. It takes her 4 hours to reach the top and 2 hours to come back down. If her average speed along the whole journey is 4 kilometers per hour, what was her average speed (in kilometers per hour) while climbing to the top?
Options:
A)2
B)2.5
C)3
D)3.25
E)3.5
Rationale: Let the distance to the top be x, so the total distance traveled by Natasha is 2x.
The total time is 4 + 2 = 6 hours
The average speed = total distance/total time taken = 2x/6 = x/3
The average speed of the complete journey is 4 km/hour
x/3 = 4
x = 12 km
The average speed while climbing = distance/time = 12/4 = 3 km/h
The answer is C.
Answer: C
Question: In an election between two candidates, 10% of votes are were declares invalid. First candidate got 5400 votes which were 60% of the total valid votes . The total number of votes enrolled in that election was:
Options:
A)9000
B)98000
C)30000
D)11000
E)12000
Rationale: 100 % - 10 % = 90 %
54%-36%=18%
18% ------> 5400 ( 18 × 300 = 5400)
100% -------> 30000 votes (100 × 300 = 30000)
C
Answer: C
Question: John is facing very difficult financial times and can only pay the interest on a $10,000 loan he has taken. The bank charges him a quarterly compound rate of 10%. What is the approximate interest he pays annually?
Options:
A)4000
B)9500
C)2500
D)2000
E)4500
Rationale: An easy way too attempt this is by approximation:
For the first quarter, he pays 10% of 10,000 which is $1000.
So for the four quarters in the year, he will approximately play 1000*4=4000 over the entire year.
Because of compound interest it will be more than 4000. Approx. option E is correct.
Answer :E
Answer: E
Question: If n = 3^8 – 2^6 which of the following is NOT a factor of n?
Options:
A)89
B)65
C)73
D)89
E)1
Rationale: 3^8 - 2^6
= (3^4)^2 - (2^3)^2
=(3^4 + 2^3)(3^4 - 2^3)
=(81+8)(81-8)
=89*73
Therefore, 65 is Not a factor of n.
B
Answer: B
Question: A trader mixes 80 kg of tea at 15 per kg with 20 kg of tea at cost price of 20 per kg. In order to earn a profit of 40%, what should be the sale price of the mixed tea?
Options:
A)22.4
B)22
C)20
D)19.2
E)None of these
Rationale: C.P. of mixture = 80×15+20×20 /80+20=16
∴ S.P. = (100+40)/100×16=22.4
Answer A
Answer: A
Question: A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If four marbles are picked at random, what is the probability that none is blue?
Options:
A)1/16
B)12/14
C)33/91
D)8/22
E)9/36
Rationale: Explanation:
Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles. When four marbles are picked at random, then the probability that none is blue is = Â¹Â²Câ‚„/Â¹âµCâ‚„
= (12 * 11 * 10 * 9)/(15 * 14 * 13 * 12) = 33/91
Answer: C
Answer: C
Question: A rectangular floor that measures 24 meters by 64 meters is to be covered with carpet squares that each measure 8 meters by 8 meters. If the carpet squares cost $24 apiece, what is the total cost for the number of carpet squares needed to cover the floor?
Options:
A) $200
B) $576
C) $480
D) $960
E) $1,920
Rationale: The width of the rectangular floor(24 m) is a multiple of one side of the square(8 m), and the length of the floor(64 m) is also a multiple of the side of the square. So the number of carpets to cover the floor is (24/8)*(64/8)=24.
The total cost is 24*24=$576.
The answer is, therefore, B.
Answer: B
Question: a dealer buys 4 varieties of wheat costing rs. 18,rs.20,rs.22 and rs.24 per kg in the ratio 2:1:3:4 and mixes all the four varieties and sells at 50% profit. What is the selling price per kg of wheat?
Options:
A)30.5
B)31.8
C)32.0
D)32.7
E)34.0
Rationale: CP = 18*2+20*1+22*3+24*4 = 218
SP = 1.5*218=327
Total no.of kgs=2+1+3+4=10
SP per kg=327/10=32.70
ANSWER:D
Answer: D
Question: . In digging a pond 17 m * 20 m * 4 m the volumes of the soil extracted will be?
Options:
A)3323
B)1360
C)2877
D)2992
E)7111
Rationale: 17 * 20 * 4 = 1360
Answer: B
Answer: B
Question: Luke and Seth started out to visit Uncle Arnie. After driving 50 miles, they saw a restaurant, and
Luke wanted to stop for lunch. Seth wanted to look for something better, so they drove on for 8
miles before giving up and going back to the restaurant. After eating they traveled on for 26 more
miles from the restaurant. Seth saw a sign for a classic car museum, which they decided to visit.
The museum was 6 miles from their route. After returning to the main road, they drove for another 40
miles and arrived at Uncle Arnie’s house.How many miles did they drive on the way there?
Options:
A)444 miles
B)344 miles
C)244 miles
D)144 miles
E)644 miles
Rationale: Use a drawing to show their travels.
The distances don’t have to be to sc
50 + 26 + 40 = 116 miles from house to house
50 + 8 + 8 = 66 miles past restaurant and back
66 + 26 = 92 miles to museum turnoff
92 + 6 + 6 = 104 miles back to main route
104 + 40 = 144 miles total driven
correct answer D
Answer: D
Question: A particular library has 75 books in a special collection, all of which were in the library at the beginning of the month. These book are occasionally loaned out through an inter-library program. If, by the end of the month, 80 percent of books that were loaned out are returned and there are 64 books in the special collection at that time, how many books of the special collection were loaned out during that month?
Options:
A)20
B)30
C)35
D)40
E)55
Rationale: there are 11 books less(75-64) which represents 20% of the loaned books (100-80)
So total loaned out books = 55
Answer E
Answer: E
Question: Dexter and Prexter are competing with each other in a friendly community competition in a pool of 50 m length and the race is for 1000 m. Dexter crosses 50 m in 2 min and Prexter in 3 min 15 sec. Each time they meet/cross each other, they do handshake's. How many such handshake's will happen if they start from the same end at the same time?
Options:
A)17
B)18
C)19
D)20
E)22
Rationale: Explanation :
When Dexter completes second round, they do handshake once.
Now for every round which Dexter completes, there will be one hand shake as the ratio of speed is 13:8.
D and P will meet at the pool end only after D completes 26 rounds.
In the 20th round, D finish the race and the total handshake's will be:
20−1= 19.
Answer : C
Answer: C
Question: The speed of a train is 70 kmph excluding stoppages and including stoppages it is 63 kmph. Of how many minutes does the train stop per hour?
Options:
A)3
B)6
C)7
D)9
E)14
Rationale: Explanation:
T = 7/70 * 60 = 6
Answer: Option B
Answer: B
Question: A fort had provision of food for 150 men for 45 days. After 15 days, 25 men left the fort. The number of days for which the remaining food will last, is:
Options:
A)36
B)37 1/4
C)42
D)54
E)48
Rationale: After 15 days : 150 men had food for 30 days.
Suppose 125 men had food for x days.
Now, Less men, More days (Indirect Proportion)
Therefore 125 : 150 :: 30 : x <=> 125 x x = 150 x 30
=> x =150 x 30/125
=> x = 36.
Correct answer is A
Answer: A
Question: 70,54,45,41 ?
Options:
A)42
B)43
C)44
D)40
E)39
Rationale: 70 - 54 = 16 = 4^2
54 - 45 = 09 = 3^2
45-41 = 04 =2^2
so we can write
41 - x = 01 = 1^1 , where x is the next number
x = 41 - 1 = 40
so the next number will be 40
ANSWER:D
Answer: D