divelab/Sys2Bench huggingface dataset:
Question: A family made a down payment of $20 and borrowed the balance on a set of encyclopedias that cost $500. The balance with interest was paid in 24 monthly payments of $25 each. The amount of interest paid was what percent of the amount borrowed?
Options:
A) 16%
B) 25%
C) 24%
D) 26%
E) 20%
Rationale: borrowings = 500-20 = 480
total pmt = 24x25 = 600
so int = 600 - 480 = 120
interest in terms of borrowing = 120/480 = 25%
Answer is B
Answer: B
Question: 20 throws of a die produces following results
SCORE -- NUMBER OF OCCURRENCES
---1-------------------4
---2-------------------3
---3-------------------5
---4-------------------2
---5-------------------2
---6-------------------4
What is the probability K that one more throw to this series will increase the mean score?
Options:
A)1/6
B)1/3
C)1/2
D)2/3
E)5/6
Rationale: I get the mean as 67/20 --> 3.35. Thus in order to raise this mean we would need a 4,5,or 6.
Thus probability K is 1/2.C
Answer: C
Question: Define e* by the equation e* = π-e. Then ((−π)*)* =
Options:
A) −2π
B) -1
C) −π
D) 2π
E) 4π
Rationale: for e* f(f(−π)) = f(π − (−π)) = f(π + π) = f(2π) = π − 2π = −π=C
Answer: C
Question: A group of 13 people plan to rent a van and agree to share equally the total cost of the rental, which is E dollars. If n of the people decide not to participate at the last minute, by how many dollars will each remaining person's share of the total cost increase?
Options:
A) E/(12 - n)
B) (12 - n)/E
C) E/[12(12-n)]
D) (12-n)E/(12n)
E) nE / [13(13-n)]
Rationale: total cost =E
no of people willing to participate initially =13
initial cost for each =E/13
when n people decided not to participate
Cost for each =E/13-n
E
Answer: E
Question: Which of the following fractions can be written as the difference of reciprocals of two consecutive integers
Options:
A)1/24
B)7/30
C)1/42
D)13/56
E)1/73
Rationale: Difference of reciprocals means 1 has to be in the numerator;
So option BD can be ignored
For option A, BE, we require to search two consecutive numbers whose product is the denominator
24 = 4 * 6 ......... Ignore
42 = 6* 7 ........ Answer
73 = 6 * 9 ................ Ignore
Answer = C
Answer: C
Question: A gardener grows cabbages in her garden that is in the shape of a square. Each cabbage takes 1 square feet of area in her garden. This year, she has increased her output by 197 cabbages as compared to last year. The shape of the area used for growing the cabbages has remained a square in both these years. How many cabbages did she produce this year?
Options:
A)9801
B)10,000
C)14,400
D)12,696
E)can not be determined
Rationale: Let the side for growing cabbages this year be X ft. Thus the area is X^2.
Let the side for growing cabbages last year be Y ft. Thus, the area was Y^2.
The area would have increased by 197 sq ft as each cabbage takes 1 sq ft space.
X^2 - Y^2 = 197
(X + Y)(X - Y) = 197
197 is a prime number and thus it will be (99+98)*(99-98).
Thus X = 99 and Y = 98
X^2 = 99^2 = 9801
The answer is A.
Answer: A
Question: A man has Rs. 440 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?
Options:
A)45
B)82.5
C)75
D)90
E)105
Rationale: Let number of notes of each denomination be x.
Then x + 5x + 10x = 440
16x = 440
x = 27.5.
Hence, total number of notes = 3x = 82.5.
Answer = B
Answer: B
Question: Seven people went to a restaurant for dinner. Six of them spent $9 each on their meals and the seventh person spent $12 more than the average expenditure of all seven people. What was the total amount of money that the seven people spent?
Options:
A)$71
B)$73
C)$75
D)$77
E)$79
Rationale: Let T be the total amount of money spent.
6*9 + (T/7 + 12) = T
66 = 6T/7
T = (7*66)/6 = 77
The answer is D.
Answer: D
Question: A printer numbers the pages of a book starting with 1 and uses 3189 digits in all. How many pages does the book have ?
Options:
A)1000
B)1074
C)1075
D)1080
E)1090
Rationale: No.of digits in 1-digit page nos=1*9=9
" " 2-digit " =2*90=180
3-digit " =3*900=2700
" " 4-digit " =3189-(9+180+2700)=300
therefore no.of 4-digit page no's=300/4=75
total no.of pages=999+75=1074
ANSWER:B
Answer: B
Question: If x = 1- 5t and y = 2t - 1, then for what value of t does x = y?
Options:
A) 5/2
B) 3/2
C) 2/3
D) 2/7
E) 0
Rationale: We are given x = 1 – 5t and y = 2t – 1, and we need to determine the value for t when x = y. We should notice that both x and y are already in terms of t. Thus, we can substitute 1 – 5t for x and 2t – 1 for y in the equation x = y. This gives us:
1 – 5t = 2t – 1
2 = 7t
2/7 = t
The answer is D.
Answer: D
Question: In the biology lab of "Jefferson" High School there are 4.32*10^6 germs, equally divided among 10,800 Petri dishes. How many germs live happily in a single dish?
Options:
A)100
B)200
C)400
D)1000
E)5000
Rationale: 4.32*10^6/ 10800==> 43.2*10^3/108==> 43200/108= 400
ANSWER:C
Answer: C
Question: A train 300 m long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 min, then the length of the tunnel is?
Options:
A)298 m
B)268 m
C)500 m
D)267 m
E)1000 m
Rationale: Speed = 78 * 5/18 = 65/3 m/sec.
Time = 1 min = 60 sec.
Let the length of the train be x meters.
Then, (300 + x)/60 = 65/3
x = 1000 m.
Answer: E
Answer: E
Question: A shop produces sarongs. The daily average production is given by 5n + 20, where n is the number of workers aside from the owner. In the first k days, 500 units are produced, and then 5 workers are added to the team. After another k days, the cumulative total is 1100. How many workers were part of the latter production run?
Options:
A)26
B)B)10
C)C)11
D)D)15
E)E)23.5
Rationale: The daily average production is given by 5n + 20- given
In the first k days, 500 units are produced
= (5n+20)K =500
k = 500/5n+20...................................1
5 workers were added = 5(n+5)+20 = 5n +45
cumulative is 1100 .. thus for the current period = 1100 -500 = 600
(5n+45)K= 600
k = 600/5n+45........................................2
equate 1 and 2
500/5n+20 = 600 /5n+45
500(5n+45) = 600(5n+20)
2500n + 22500 = 3000n + 12000
-500n = -10500
n = 21
thus n+5 = 26
hence A
Answer: A
Question: A piece of ribbon 4 yards long is used to make bows requiring 15 inches of ribbon for each. What is the maximum number of bows that can be made?
Options:
A)8
B)9
C)10
D)11
E)12
Rationale: 1 Yard = 36 inches
Total length of ribbon = 4 yards = 4*36 inches = 144
Length of ribbon needed for 1 bow = 15 inches
Max number of bows that can be made = 144 / 15
= 9.6
Answer B
Answer: B
Question: If BURNER is coded as CASOIS then how will ALIMENT be coded?
Options:
A)BKJLFMU
B)EKOLIMS
C)EMONIOU
D)BRJSFTU
E)EROSITU
Rationale: You take the next consonant or vowel in alphabetical sequence.
Watch:
b - c (next consonant in sequence)
u - a (aeiou, u cycles back to beginning, or a)
r - s
n = o
e = i (next vowel)
r = s
therefore:
a = e (next vowel)
l = m
i = o
m = n
e = i
n = o
t = u
EMONIOU
ANSWER:B
Answer: B
Question: The total of a company's assets in 1994 was 50% greater than the total in 1993, which in turn was 400% greater than the total in 1992. If the total of the company's assets in 1992 was N dollars, what were the company's assets in 1994?
Options:
A)5.5N
B)7.5N
C)9.5N
D)11.5N
E)13.5N
Rationale: In 1992, the company's assets were N.
In 1993, the company's assets were N + 4N = 5N.
In 1994, the company's assets were 5N + 2.5N = 7.5N.
The answer is B.
Answer: B
Question: If the set S is composed of the following numbers {99, 100, 100, 105, 106, 112, 127}, which of the following is largest?
Options:
A)The average (arithmetic mean) of set S
B)The median of set S
C)The mode of set S
D)The range of set S
E)The standard deviation of set S
Rationale: A) 99, 100, 100, 105, 106, 112, 127 = 749 and its mean is 749/7 = 107.
B) The list is of 7 numbers and median is 105.
C) Mode is number of repetition of a number in the list , here it is 100.
D) Range = Max value - min value = 127 -99 = 28.
E) SD = square root of (sum of ( mean of series - number)^2 ) / n =>< 100
IMO option A is correct answer..
Answer: A
Question: What is the dividend. divisor 13, the quotient is 17 and the remainder is 1
Options:
A)222
B)224
C)226
D)228
E)230
Rationale: A = d * Q + R
A = 13 * 17 + 1
A = 221 + 1
A = 222
Answer: A
Question: if the price of a book is first decreased by 15% and then increased by 10%, then the net change in the price will be :
Options:
A)10
B)388
C)6.5
D)29
E)22
Rationale: Explanation:
Let the original price be Rs. 100.
Decreased by 15% = 85
Then increased 10% on Rs 85 = 85 + 8.5 = 93.5
Net change in price = 100 - 93.5 = 6.5
Answer : C
Answer: C
Question: A truck covers a distance of 360 km at a certain speed in 8 hours. How much time would a car take at an average speed which is 18 kmph more than that of the speed of the truck to cover a distance which is 14 km more than that travelled by the truck ?
Options:
A)6 hours
B)5 hours
C)7 hours
D)8 hours
E)None
Rationale: Explanation :
Speed of the truck = Distance/time = 360/8 = 45 kmph
Now, speed of car = (speed of truck + 18) kmph = (45 + 18) = 63 kmph
Distance travelled by car = 360 + 81 = 441 km
Time taken by car = Distance/Speed = 441/63 = 8 hours.
Answer – D
Answer: D
Question: A car crosses a 600m long bridge in 5 mins. What is the speed of car in km per hr?
Options:
A)7 km/hr
B)7.2 km/hr
C)7.5 km/hr
D)8 km/hr
E)8.5 km/hr
Rationale: Speed = 600 m/sec.
5 x 60
= 2 m/sec.
Converting m/sec to km/hr (see important formulas section)
= 2 x 18 km/hr
5
= 7.2 km/hr
B
Answer: B
Question: A can contains a mixture of liquids A and B is the ratio 7:5. When 12 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7:9. How many liter of liquid A was contained by the can initially?
Options:
A)25
B)27
C)29
D)28
E)31
Rationale: Ci*Vi = Cf*Vf
(7/12)*(V1 - 12) = (7/16)*V1
(V1 - 12)/V1 = 3/4
12 accounts for the difference of 1 on ratio scale so Initial volume = V1 = 4*12 = 48 litres.
7/12 of the initial mixture was liquid A so liquid A was (7/12)*48 = 28 litres.
Answer : D
Answer: D
Question: 10% of the inhabitants of village having died of cholera.,a panic set in , during which 25% of the remaining inhabitants left the village. The population is then reduced to 4050. Find the number of original inhabitants.
Options:
A)600
B)6500
C)6000
D)6500
E)7000
Rationale: Let the total number of orginal inhabitants be x.
((75/100))*(90/100)*x)=4050  (27/40)*x=4050
x=((4050*40)/27)=6000.
ANSWER C 6000
Answer: C
Question: John found that the average of 15 numbers is 40. If 12 is added to each number then the mean of number is?
Options:
A)52
B)45
C)65
D)78
E)64
Rationale: (x+x1+...x14)/15 = 40
52
Option A
Answer: A
Question: Two numbers are respectively 20% and 60% more than a third number. The percentage that is first of the second is?
Options:
A)34%
B)68%
C)51%
D)75%
E)83%
Rationale: I II III
120 160 100
160----------120
100-----------? => 75%
Answer:D
Answer: D
Question: If a train runs at 40 kmph ,it reach its destination late by 11 minutes but if it runs at 50kmph it is late by 5 minutes only . the correct time for a train to complete its journey is?
let the correct time to complete the journey be x min
distance covered in(x+11)min. at 40 kmph
distance covered in(x+5)min. at 50 kmph
(x+11)/60*40=(x+5)/60*50
x=19min
Options:
A)19 min
B)19hrs
C)52min
D)126min
E)52min
Rationale: let the correct time to complete the journey be x min
distance covered in(x+11)min. at 40 kmph
distance covered in(x+5)min. at 50 kmph
(x+11)/60*40=(x+5)/60*50
x=19min
Answer(A)
Answer: A
Question: The traffic lights at 3 different roads change after every 14 sec, 72 sec, 108 sec respectively. If they all change simultaneously at 9:15 AM then at what time will they again change simultaneously.
Options:
A)9:22:12
B)9:42:15
C)10:15:24
D)9:40:12
E)10:01:20
Rationale: LCM of 14,72,108 = 1512 = 25mnts 12sec
The lines will change every 25m 12sec
The light will change again after 9:15 AM is = 9:15+0:25:12 = 9:40:12
Answer is D
Answer: D
Question: How many positive 5-digit integers have the odd sum Q of their digits?
Options:
A)9*10^2
B)9*10^3
C)10^4
D)45*10^3
E)9*10^4
Rationale: We are looking at numbers between 10000 and 99999 both inclusive.
There are 90000 numbers.
Now for
10000 : sum of digits is odd;
10001 :sum of digits is even;
10002 : sum of digits is odd ; so on and so forth. So every alternate number is such that the sum of digit is odd.
(Exception for the above statement :
When it is 10009 the sum is even and for 10010 again the sum is even; But if you look at 10019 :sum is odd; 10020 : sum is odd
and this pattern continues so basically the number of odd sum of digits and even sum of digits are equal)
This means exactly half of the numbers will have odd sum Q of their digits. i.e 45000
Answer :D
Answer: D
Question: How many inches are in 2000 millimeters? (round your answer to the nearest hundredth of of an inch).
Options:
A)48.74 inches
B)58.74 inches
C)78.74 inches
D)28.74 inches
E)88.74 inches
Rationale: One inch is the same as 25.4 mm. Let x inches be the same as 1000 mm
x = 1 inch * 2000 mm / 25.4 mm = 78.74 inches
correct answer C
Answer: C
Question: What is the sum of all 3 digit numbers that leave a remainder of '2' when divided by 4?
Options:
A)123,750
B)164,850
C)164,749
D)149,700
E)156,720
Rationale: Find the number , Upon Sum of 3 Digits of a number Gives a Reminder 2 when it is Divided by 4
Seeing the Options After Dividing and Finding the Reminder of 2
My Answer was A
Answer: A
Question: A bag contains 3 white balls, 3 black balls & 2 red balls. One by one three balls are drawn out without replacement. What is the probability that the third ball is red?
Options:
A)0.25
B)0.15
C)0.35
D)0.45
E)0.4
Rationale: Favorable outcomes :
WWR -> P(WWR)= 3/8 * 2/7 * 2/6 = 12/336
WRR -> P(WRR)= 3/8 * 2/7 * 1/6 = 6/336
RWR -> P(RWR)= 2/8 * 3/7 * 1/6 = 6/336
BBR -> P(BBR)= 3/8 * 2/7 * 2/6 = 12/336
BRR -> P(BRR)= 3/8 * 2/7 * 1/7 = 6/336
RBR -> P(RBR)= 2/8 * 3/7 * 1/6 = 6/336
WBR -> P(WBR)= 3/8 * 3/7 * 2/6 = 18/336
BWR -> P(BWR)= 3/8 * 3/7 * 2/6 = 18/336
So, P(Total) = 84/336 = 1/4 = 0.25
Answer is A
Answer: A
Question: If x is an integer such that 0 < x < 12, 1 < x < 15, 10 > x > 5, 11 > x > 8, and x + 2 < 12, then x is
Options:
A)3
B)5
C)7
D)9
E)11
Rationale: 0 < x < 12,
1 < x < 15,
-5 < x < 10
8< x < 11
x<10
From above: 8 < x < 10 --> x = 9.
Answer: D.
Answer: D
Question: At an elementary school, 60% of the faculty members are women and 60% of the faculty members are married. If 3/4 of the men are single, what fraction of the men are married?
Options:
A)3/4
B)2/5
C)4/5
D)2/3
E)1/4
Rationale: --------------------M------W--------Total
Marrried---------10-----50---------60
Not married-----30-----10---------40
Total-------------40-----60--------100
need married man/total man, so 10/40=1/4
E
Answer: E
Question: If the Average of 10 consecutive integers is 24.5 then the 10th integer is :-
Options:
A)15
B)20
C)23
D)29
E)25
Rationale: The average falls between the 5th and 6th integers,
integer 5 = 24, integer 6 = 25.
Counting up to the tenth integer
we get 29.
ANSWER:D
Answer: D
Question: In a certain company, the ratio of the number of managers to the number of non-managers in any department must always be greater than 7 : 37. In the company, what is the maximum number of non-managers in a department that has 9 managers?
Options:
A)44
B)45
C)46
D)47
E)48
Rationale: 9/7 * 37 = 47.6
The answer is D.
Answer: D
Question: A certain list of 300 test scores has an arithmetic mean of 74 and a standard deviation of d, where d is positive. Which of the following two test scores, when added to the list, must result in a list of 302 test scores with a standard deviation less than d?
Options:
A) 75 and 80
B) 80 and 85
C) 74 and 74
D) 75 and 75
E) 70 and 80
Rationale: Ans: C
Deviation means spreading of the numbers from one median point value..
as the set is already established and we need to add only two numbers, this means we can only add numbers which are closer to the median to reduce the deviation.
so 74 and 74 are the most close numbers and they will increase the number of elements in the set without changing the median value.
C
Answer: C
Question: A cube has a volume of 125 cubic feet. If a similar cube is twice as long, twice as wide, and twice as high, then the volume, in cubic feet of such cube is?
Options:
A)24
B)48
C)64
D)80
E)1000
Rationale: Volume = 125 = side^3
i.e. Side of Cube = 5
New Cube has dimensions 10, 10, and 10 as all sides are twice of teh side of first cube
Volume = 10*10*10 = 1000 square feet
Answer: option E
Answer: E
Question: If m is a positive integer greater than 1, what is the sum of the multiples of m from m to m^2, inclusive?
Options:
A) m(m + 1)(m-1)
B) m^2(m + 1)/2
C) m^2(m-1)
D) (x^3 + 2x)/2
E) x(x-1)^2
Rationale: Ans :- B=m^2(m + 1)/2
I substituted 3 in all answer choices.
Option B and C were both satisfying the condition.
So i substituted 4 instead of 3 in all answer choices,
Only B option satisfied.
Answer: B
Question: A can do a piece of work in 15 days. A does the work for 5 days only and leaves the job. B does the remaining work in 6 days.In how many days B alone can do the work?
Options:
A)5days
B)7 days
C)12 days
D)9 days
E)10 days
Rationale: Explanation:
A’s 5 day work = 5*1/15=1/3
Remaining work = 1-1/3=2/3
B completes 2/3 work in 6 days
B alone can do in x days
2/3*x=6
X=9 days
Answer: Option D
Answer: D
Question: If f(b)=b^2 and b is a positive integer, which of the following CANNOT be the value of f(f(b))?
Options:
A)1
B)81
C)200
D)256
E)625
Rationale: f(b)=b^2
f(f(b)) = (b^2)^2 = b^4
Therefore f(f(b)) will be numbers that are 4th power of other numbers.
Checking the options:
1 = 1^$
81 = 3^4
200. This cannot be written as the 4th power of any number
256 = 4^4
625 = 5^4
Answer: C
Answer: C
Question: I walk a certain distance and ride back taking a total time of 37 minutes. I could walk both ways in 55 minutes. How long would it take me to ride both ways?
Options:
A)12 mins
B)10 mins
C)19 mins
D)15 mins
E)20 mins
Rationale: Let the distance be x km. Then,
( Time taken to walk x km) + (time taken to ride x km) =37 min.
( Time taken to walk 2x km ) + ( time taken to ride 2x km )= 74 min.
But, the time taken to walk 2x km = 55 min.
Time taken to ride 2x km = (74-55)min =19 min.
Ans: C
Answer: C
Question: An investor receives a total combined return of 10% on his two different investments. On his $10,000 investment he receives a return of 6%. What is the return on his $20,000 investment?
Options:
A)7.25%
B)12%
C)8%
D)8.5%
E)9%
Rationale: 0.06 * 10000 + 20000x = 0.10(30000)
solving for x give x = 12%
option B
Answer: B
Question: Drum X is 1/2 full of oil and drum Y, which has twice the capacity of drum X, is 1/2 full of oil. If all of the oil in drum X is poured into drum Y, then drum Y will be filled to what capacity?
Options:
A)2/3
B)3/4
C)4/5
D)5/6
E)7/8
Rationale: (1/2)X = (1/4)Y
(1/4)Y + (1/2)Y = (3/4)Y
The answer is B.
Answer: B
Question: Thomas's age and Matt's age are in the ratio 2:3. Two years ago the ratio of their ages was 1:2. Find the ratio of their ages four years hence?
Options:
A)1:2
B)2:3
C)3:4
D)4:5
E)5:6
Rationale: Let ages of Thomas and Matt be x and y respectively.
x/y = 2/3 => x = 2/3 y
(x- 2)/(y - 2) = 1/2
=> 2x - 4 = y - 2 => 2x = y + 2
But x = 2/3 y
2 * 2/3 y = y + 2
4y = 3y + 6 => y = 6years
=> x = 4 years
Ratio of their ages five years hence, (4 +4)/(6 + 4) = 8/10. => 4:5
Answer:D
Answer: D
Question: The function f is defined for all positive integers u by the following rule. f(u) is the number of positive integers each of which is less than u and has no positive factor in common with u other than 1. If s is any prime, number then f(s)=
Options:
A)2
B)s-2
C)(s+1)/2
D)(s-1)/2
E)S-1
Rationale: If not the wording the question wouldn't be as tough as it is now. The GMAT often hides some simple concept in complicated way of delivering it.
This question for instance basically asks: how many positive integers are less than given prime number s which have no common factor with s except 1.
Well as s is a prime, all positive numbers less than s have no common factors with s (except common factor 1). So there would be s-1 such numbers (as we are looking number of integers less than s).
For example: if s=4 how many numbers are less than 4 having no common factors with 4: 1, 2, 3, 4,--> 4-1=3.
Answer: E.
Answer: E
Question: The charge for a single room at Hotel P is 30 percent less than the charge for a single room at Hotel R and 10 percent less than the charge for a single room at Hotel G. The charge for a single room at Hotel R is what percent greater than the charge for a single room at Hotel G ?
Options:
A)28%
B)20%
C)40%
D)50%
E)150%
Rationale: Let rate in R = 100x
then P = 70x
G = 100y
P = 90y
Thus
70 x=90y
or x = 1.28 y
Ans R = 128y
so increase = 28%
Answer: A
Answer: A
Question: Two stations P and Q are 290 km apart on a straight track. One train starts from P at 7 a.m. and travels towards Q at 20 kmph. Another train starts from Q at 8 a.m. and travels towards P at a speed of 25 kmph. At what time will they meet?
Options:
A)10 am
B)12 am
C)10.30 am
D)12.30 pm
E)2 pm
Rationale: Assume both trains meet after x hours after 7 am
Distance covered by train starting from P in x hours = 20x km
Distance covered by train starting from Q in (x-1) hours = 25(x-1)
Total distance = 290
=> 20x + 25(x-1) = 290
=> 45x = 315
=> x= 7
Means, they meet after 7 hours after 7 am, ie, they meet at 2 pm
Answer is E.
Answer: E
Question: In an exam, A scored 75 percent, B scored 25 percent and C scored 32 percent. The maximum score awarded in the exam is 500. Find the average mark scored by all the three candidates?
Options:
A)190
B)200
C)210
D)220
E)230
Rationale: Average mark scored by all the three boys
= [75/100 (500) + 25/100 (500) + 32/100 (500)] / 3
= 220
Answer: D
Answer: D
Question: It is well known that a triangle’s area is √(p(p-a)(p-b)(p-c)),
when p=(a+b+c)/2, such that a, b, c are the lengths of sides of the triangle. If the triangle has 300, 300, and 300 as the side’s lengths, what is the triangle’s area?
Options:
A)34,200
B)36,200
C)38,200
D)42,200
E)38,971
Rationale: It is well known that a triangle’s area is √(p(p-a)(p-b)(p-c)),
when p=(a+b+c)/2,
-> P=(300+300+300)/2=450, area=√(450(450-300)(450-300)(450-300))=38,971. Therefore, the answer is E.
Answer: E
Question: In a kilometer race, A beats B by 40 meters or 10 seconds. What time does A take to complete the race?
Options:
A)290 sec
B)190 sec
C)199 sec
D)192 sec
E)240 sec
Rationale: Time taken by B run 1000 meters
= (1000 * 10)/40 = 250 sec.
Time taken by A = 250 - 10 = 240 sec.
Answer: E
Answer: E
Question: A candidate appearing for an examination has to secure 52% marks to pass paper I. But he secured only 45 marks and failed by 35 marks. What is the maximum mark for paper I?
Options:
A)110
B)154
C)130
D)140
E)150
Rationale: he secured 45 marks nd fail by 35 marks so
total marks for pass the examinatn=80
let toal marks x
x*52/100=80
x=154
ANSWER:B
Answer: B
Question: A certain kind of necklace is made from 9 green, 6 white, and 3 orange beads. What is the maximum number of these necklaces that can be made from 45 beads of each color ?
Options:
A)7
B)8
C)5
D)6
E)2
Rationale: Atleast 9 green breads are needed to make a necklace, so irrespective of the combinations of white and orange beads, the number of necklaces that can be formed will be
45/9 =5
Answer:- C
Answer: C
Question: A factory that employs 1000 assembly line workers pays each of these workers $5 per hour for the first 40 hours worked during a week and 1½ times that rate for hours worked in excess of 40. What was the total payroll for the assembly-line workers for a week in which 30 percent of them worked 10 hours, 50 percent worked 40 hours, and the rest worked 50 hours?
Options:
A) $180,000
B) $185,000
C) $170,000
D) $200,000
E) $205,000
Rationale: 30% of 1000 = 300 worked for 20 hours
Payment @ 5/hr
Total Payment = 300*10*5 = 15000
50 % of 1000 = 500 worked for 40 hours
Payment @ 5/hr
Total payment = 500*40*5 = 100000
Remaining 200 worked for 50 Hours
Payment for first 40 Hours @ 5 /hr
Payment = 200*40*5 = 40000
Payment for next 10 hr @ 7.5/hr
Payment = 200 * 10 * 7.5 = 15000
Total Payment = 15000+100000 + 40000 +15000 = 170000
Hence , answer is C
Answer: C