divelab/Sys2Bench huggingface dataset:
Question: Two pipes A and B can separately fill a tank in 2 minutes and 15 minutes respectively. Both the pipes are opened together but 4 minutes after the start the pipe A is turned off. How much time will it take to fill the tank?
Options:
A)28
B)10
C)28
D)27
E)13
Rationale: 4/12 + x/15 = 1
x = 10
Answer:B
Answer: B
Question: Tom left a job paying $75,000 per year to accept a sales job paying $45,000 per year plus 15 percent commission. If each of his sales is for $750, what is the least number of sales he must make per year if he is not to lose money because of the change?
Options:
A)40
B)200
C)266
D)267
E)600
Rationale: In order not to lose money because of the change Tom's total commission must beat least$75,000-$45,000=$30,000, so total sales must beat least$30,000/0.15=$200,000. Which means that he must makeat least$200,000/750=800/3=266.6 sales, so 267 sales.
Answer: D.
Answer: D
Question: Jean drew a gumball at random from a jar of pink and blue gumballs. Since the gumball she selected was blue and she wanted a pink one, she replaced it and drew another. The second gumball also happened to be blue and she replaced it as well. If the probability of her drawing the two blue gumballs was 16/36, what is the probability that the next one she draws will be pink?
Options:
A)1/49
B)4/7
C)3/7
D)1/3
E)40/49
Rationale: The probability of drawing a pink gumball both times is the same. The probability that she drew two blue gumballs = 16/36 = (2/3) * (2/3)
Therefore probability that the next one she draws is pink = 1/3
Option (D)
Answer: D
Question: Find the area of circle whose radius is 5m?
Options:
A)113.1
B)154
C)288
D)280
E)371
Rationale: 22/7 * 5 * 5
= 113.1
Answer:A
Answer: A
Question: SCORE INTERVAL----------------NUMBER OF SCORES
50-59-------------------------- 2
60-69--------------------------10
70-79--------------------------16
80-89--------------------------3.
90-99--------------------------8
The table above shows the distribution of test scores for a group of management trainees. Which score interval contains the median of the 39 scores?
Options:
A)22th
B)23th
C)20th( 70-79)
D)25th
E)26th
Rationale: Total scores= 2+10+16+3+8 = 39, which is odd, therefore the median is the Floor(39/2)+1 = 20 th score. And the 20th score is in the 70-79 range, because 50-69 only reference 12 scores.
D
Answer: D
Question: To fill a tank, 42 buckets of water is required. How many buckets of water will be required to fill the same tank if the capacity of the bucket is reduced to two-fifths of its present ?
Options:
A)102
B)103
C)104
D)105
E)106
Rationale: Let the capacity of 1 bucket = x.
Then, the capacity of tank = 42x.
New capacity of bucket = 2/5 x
Therefore, Required number of buckets = (42x)/(2x/5)
= (42x) x 5/2x
= 210/2
= 105
Answer is D.
Answer: D
Question: If s is a positive integer, and if the units' digit of s^2 is 4 and the units' digit of (s + 1)^2 is 1, what is the units' digit of (s + 2)^2 ?
Options:
A)	0
B)	2
C)	4
D)	6
E)	8
Rationale: A for me.
_1² = _1
_2² = _4
_3² = _9
_4² = _6
_5² = _5
_6² = _6
_7² = _9
_8² = _4
_9² = _1
_0² = _0
On the list, the only number that squared has the units digit = 4 preceding a number that squared has the units digit = 1 is the _8.
So, s = _8, that has square 4. The next square is 1 andnext nextsquare is 0.
Answer: A
Question: What is the dividend. divisor 16, the quotient is 9 and the remainder is 5?
Options:
A)A)130
B)B)134
C)C)149
D)D)158
E)E)160
Rationale: D = d * Q + R
D = 16 * 9 + 5
D = 144 + 5
D = 149
Answer C
Answer: C
Question: Of the science books in a certain supply room, 50 are on botany, 60 are on zoology, 90 are on physics. 50 are on geology, and 110 are on chemistry. If science books are removed randomly from the supply room, how many must be removed to ensure that 80 of the books removed are on the same science?
Options:
A)81
B)319
C)166
D)285
E)324
Rationale: First, you can take all 50 Botany books, all 60 zoology books and all 50 geology books because you're sure to never pick 80 of them.
There are still 90 on physics and 110 on chemistry
The worst case could be that we pick 79 physics and 79 chemistry. So that the next book picked will necessary complete 80 books picked, either in physics or chemistry.
Minimum number of books picked to reach 80 in the same science should be : 50 + 60 + 50 + 79 +79 + 1 = 319
B
Answer: B
Question: A single discount equivalent to the discount series of 12%, 10% and 5% is?
Options:
A)31.67
B)31.9
C)24.67
D)24.76
E)31.1
Rationale: 100*(88/100)*(90/100)*(95/100) = 75.24
100 - 75.24 = 24.76
Answer: D
Answer: D
Question: In how many different number of ways 3 boys and 2 girls can sit on a bench?
Options:
A)700
B)710
C)120
D)720
E)740
Rationale: npn = n!
5p5 = 5 Ã— 4 Ã— 3 Ã— 2 Ã— 1 = 120
C
Answer: C
Question: A boat can travel 1.5 times the distance down the stream than up the stream in the same time. If the speed of the current is 5 KMPH, Find the speed of the boat in still water
Options:
A)5
B)10
C)15
D)20
E)25
Rationale: Simple question, messy language.
Lets say boat's speed is B and current's speed is C.
Upstream speed : B - C
Downstream speed : B + C
Distance will be the same both times. lets say D.
given : time it takes upstream = 1.5 times time it takes downstream
D/(B + C) = 1.5 * [D/(B - C)]
Solving B = 5 C
given : C is 5 KMPH
So B is 25 KMPH
E
Answer: E
Question: A fill pipe can fill 1/2 of cistern in 25 minutes. In how many minutes, it can fill 1/2 of the cistern?
Options:
A)10 min
B)15 min
C)20 min
D)25 min
E)30 min
Rationale: Required time = 25*2*1/2 = 25 minutes
Answer is D
Answer: D
Question: A photography dealer ordered 72 Model X cameras to be sold for $250 each, which represents a 20 percent markup over the dealer’s initial cost for each camera. Of the cameras ordered, 6 were never sold and were returned to the manufacturer for a refund of 50 percent of the dealer's initial cost. What was the dealer's approximate profit or loss as a percent of the dealer’s initial cost for the 72 cameras?
Options:
A)7% loss
B)13% loss
C)7% profit
D)14% profit
E)15% profit
Rationale: Total cost 72*($250/1.2)=60*250;
# of cameras sold is 72-6=66 total revenue is 66*250;
# of cameras returned is 6 total refund 6*(250/1.2)*0.5;
So, total income 66*250+ 6*(250/1.2)*0.5
The dealer's approximate profit is (66*250+ 6*(250/1.2)*0.5-60*250)/(60*250)*100=14%
Answer: D.
Answer: D
Question: The sale price sarees listed for Rs.200 after successive discount is 10% and 5% is?
Options:
A)187
B)169
C)172
D)178
E)171
Rationale: 200*(90/100)*(95/100)
= 171
Answer:E
Answer: E
Question: Four bells commence tolling together and toll at intervals of 2, 4, 6, 8 seconds respectively. In 18 minutes, how many times do they toll together ?
Options:
A)43
B)44
C)45
D)46
E)47
Rationale: LCM of 2, 4, 6, 8 is 24.
So, after each 24 seconds, they would toll together.
Hence, in 18 minutes, they would toll 18*60 seconds / 24 seconds = 45 times
But then the question says they commence tolling together. So, they basically also toll at thebeginning(0second).
So, total tolls together = 45+1 = 46
Answer C
Answer: C
Question: 16 business executives and 7 chairmen meet at a conference. If each business executive shakes the hand of every other business executive and every chairman once, and each chairman shakes the hand of each of the business executives but not the other chairmen, how many handshakes would take place?
Options:
A)144
B)131
C)232
D)90
E)45
Rationale: there are 16 business exec and in each handshake 2 business execs are involved.
hence 16C2=120
Also, each of 16 exec will shake hand with every 7 other chairmen for total of 112 handshake.
total=120+112=232
ANS: C
Answer: C
Question: WHAT WILL BE THE VALUE OF
log e(e(e....)^1/2)^1/2)^1/2).....log base is e?
Options:
A)0
B)1
C)2
D)3
E)4
Rationale: e(e(e....)^1/2)^1/2)^1/2 = e ^ (1/2 + 1/4 + 1/8 +....)
it is in G.P(Geometric progression) then sum to infinite terms = (a)/(1-r)
(1/2 + 1/4 + 1/8 +....) = (1/2)/(1-1/2) = 1
so e ^ 1
log(e^1) base e = 1
ANSWER:B
Answer: B
Question: The average age of 40 students is 8 years. If the age of teacher is also included , then their average age increases by half a year. What is the age of the teacher?
Options:
A)45 years
B)48.5 years
C)28.5 years
D)26.5 years
E)29.5 years
Rationale: Exp. Total age of 40 students = 40*8 = 320
Let the age of the the teacher be x, Then (320+x)/41 = 8+1/2 =8 ½.
320+x =17/2*41 =697/2 = 348.5, x =348.5-320 = 28.5
Answer: C
Answer: C
Question: A, B and C have Rs.300 between them, A and C together have Rs.200 and B and C Rs.350. How much does C have?
Options:
A)A)250
B)B)249
C)C)248
D)D)247
E)E)246
Rationale: A+B+C = 300
A+C = 200
B+C = 350
--------------
A+B+2C = 550
A+B+C = 300
----------------
C = 250
Answer:A
Answer: A
Question: Of the 200 stamps in a collection, 90 are foreign and 50 are more than 10 years old. If 20 stamps are both foreign and more than 10 years old, how many stamps are neither foreign nor more than 10 years old?
Options:
A)30
B)80
C)100
D)130
E)150
Rationale: 20 stamps are both foreign and more than 10 years old.
70 stamps are foreign only.
30 stamps are 10 years old only.
The number of remaining stamps is 200 - (20+70+30) = 80
The answer is B.
Answer: B
Question: If 4 (P's Capital ) = 6 ( Q's Capital ) = 10 ( R's Capital ) , then out of the total profit of Rs 4960 , R will receive
Options:
A)600
B)700
C)800
D)960
E)None of these
Rationale: Explanation :
Let P's capital = p, Q's capital = q and R's capital = r
Then
4p = 6q = 10r
=> 2p = 3q = 5r
=>q = 2p/3
r = 2p/5
P : Q : R = p : 2p/3 : 2p/5
= 15 : 10 : 6
R's share = 4960 * (6/31) = 160*6 = 960. Answer : Option D
Answer: D
Question: The number of livestock in a farm at the beginning of year 2000 was 140,000. During the year, the number increased by p%. During the next year 2001, there was a famine and the number decreased by q%. A census at the end of year 2001 revealed that the number of livestock in the farm was 140,000. Which of the following expressions is correct?
Options:
A)There is no relation between p and q
B)q > p
C)p = q
D)With the exception of 1 instance, p will be equal to q
E)p > q
Rationale: Number plugging in will be best strategy for this question.
Let p = 5%,
Per the question 100000(1.05)(1-q/100) = 100000 ---> q = 4.7%. Thus p > q and hence E is the correct answer.
Answer: E
Question: A and B can together finish a work in 10days. They worked together for 5days and then B left. After another 5days, A finished the remaining work. In how many days A alone can finish the job?
Options:
A)10
B)15
C)20
D)5
E)30
Rationale: A+B 5days work = 5*1/10 = 1/2
Remaining work = 1-1/2 = 1/2
1/2 work is done by A in 5days
whole work will be done by A in 5*2 = 10days
Answer is A
Answer: A
Question: Four hundred students at College Q study a foreign language. Of these, 190 of those students study French, and 260 study Spanish. If at least 105 students who study a foreign language at College Q study neither French nor Spanish, then the number of students who study Spanish but not French could be any number from
Options:
A)10 to 40
B)40 to 100
C)60 to 100
D)60 to 105
E)70 to 110
Rationale: 190 students study French
210 students do not study French
260 students study Spanish
140 students do not study Spanish
105 students study neither French nor Spanish
210-140=70
210-105=90
D. 60 to 105
Answer: D
Question: 40% of x is greater than 1/3rd of x by 110.what is x?
Options:
A)1100
B)2100
C)1300
D)1650
E)1400
Rationale: 4x/10-x/3=110
1x/15=110
x=1650
ANSWER:D
Answer: D
Question: Evaluate :log3 27
Options:
A)3
B)4
C)5
D)6
E)7
Rationale: Solution
log3 27	= n
=3n
=27
=33
n‹=›3.
Answer A
Answer: A
Question: The average weight of 4 person's increases by 1.5 kg when a new person comes in place of one of them weighing 95 kg. What might be the weight of the new person?
Options:
A)101 kg
B)103.4 kg
C)105 kg
D)Data inadequate
E)None of these
Rationale: Total weight increased = (4 x 1.5) kg = 6 kg.
Weight of new person = (95 + 6) kg = 101 kg.
Answer: Option A
Answer: A
Question: Anne has pouches of grain that she wants to divide between the different areas of the petting zoo. Unfortunately, Anne's pouches of grain don't divide evenly. It turns out that in order for the pouches of grain to divide evenly, Anne will have to purchase two additional pouches of grain, and not visit two of the petting zoo areas. Which of the following can describe the initial number of grain pouches, and the initial number of areas in the petting zoo (in the order areas of the petting zoo; pouches of grain)?
Options:
A)20; 5.
B)16; 5.
C)12; 4
D)30; 4
E)21; 7
Rationale: Option B) Initially 16 petting zoo areas, then decreased to 14 petting zoo areas; and Initially 5 pouches of grain, then icreased to 7 pouces of grain fits the requirement.
14 / 7 = 2 pouches of grain per petting zoo area
Answer: B
Question: A group of tourists wants to visit at least three of the four cities A, B, C, and D. How many travel itineraries can they make? All cities are connected to one another and please note that visiting the same cities in a different order counts as a different itinerary.
Options:
A)24
B)36
C)48
D)60
E)64
Rationale: The number of ways to choose three cities is 4C3=4.
The number of itineraries for each group of 3 cities is 3!.
So the number of itineraries to three cities is 4*3!=24.
The number of ways to choose four cities is 4C4=1.
The number of itineraries for the group of 4 cities is 4!.
So the number of itineraries to four cities is 4!=24.
The total number of itineraries is 24+24=48.
The answer is C.
Answer: C
Question: 2/3rd of the boys and 3/4th of the girls of a school participate in a function. If the no.of participating students is 550, out of which 150 are girls, what is the total no.of students in the school?
Options:
A)620
B)780
C)800
D)880
E)900
Rationale: Let total number of boys be x and total number of girls be y. y=400=>x = 600and^= I50=>y = 200 Now, x + y = 800
C
Answer: C
Question: The owner of a furniture shop charges his customer 20% more than the cost price. If a customer paid Rs. 3000 for a computer table, then what was the cost price of the computer table?
Options:
A)2500
B)2772
C)1991
D)6725
E)2099
Rationale: CP = SP * (100/(100 + profit%))
= 3000(100/120) = Rs. 2500.
Answer: A
Answer: A
Question: If f(x) =6* (x^4 - 1)/(x^2), what is f(1/x) in terms of f(x)?
Options:
A)f(x)
B)-f(x)
C)1/f(x)
D)-1/f(x)
E)-6*f(x)
Rationale: f(1/x) =6* ((1/x)^4 - 1) / ((1/x)^2)
= 6*((1/x^4) - 1) / (1/x^2)
= 6*((1-x^4)/(x^4)) / (1/x^2)
= 6*(1-x^4)/(x^2)
= - 6*( (x^4) -1) / (x^2)
= -6f(x)
Answer is E.
Answer: E
Question: Mangoes, Oranges and Apples in a fruit shop are in the ratio of 10: 2 : 3. If there are 120 Mangoes, the number of Apples in the shop is:.
Options:
A)36
B)42
C)72
D)400
E)56
Rationale: Explanation :
Let Mangoes = 10x, Oranges = 2x & Apples = 3x. Now, 10x = 120 hence x = 12.
Number of Apples = 3x = 36.
Answer : A
Answer: A
Question: The average age of a group of 10 persons was decreased by 3 years when one person, whose age was 42 years, was replaced by a new person. Find the age of the new person?
Options:
A)11
B)19
C)12
D)17
E)14
Rationale: Initial average age of the 10 persons be P.
Age of the new person Q.
Sum of the ages of the initial 10 persons = 10P
New average = (P-3) 10(P-3) = 10P - 42 + Q => Q
= 12
Answer: C
Answer: C
Question: There are 3 classes having 20, 24 and 30 students respectively having average marks in
an examination as 20,25 and 30 respectively. The three classes are represented by A, B and C and you have the following information about the three classes.
a. In class A highest score is 22 and lowest score is 18
b. In class B highest score is 31 and lowest score is 23
c. In class C highest score is 33 and lowest score is 26.
Options:
A)can't be determined in both cases
B)definite decrease in both cases
C)definite increase in both cases
D)will remain constant in both cases
E)will remain constant in both cases21
Rationale: Ans: B
Explanation:
Class A average is 20. And their range is 18 to 22
Class B average is 25. And their range is 23 to 31
Class A average is 30. And their range is 26 to 33
If 5 students transferred from A to B, A's average cannot be determined but B's average comes down as the highest score of A is less than lowest score of B.
If 5 students transferred from B to C, C's average cannot be determined the B's range fo marks and C's range of marks are overlapping.
Answer:A
Answer: A
Question: The price of a jewel, passing through three hands, rises on the whole by 65%. If the first and second sellers earned 20% and 25% profit respectively, find the percentage profit earned by the third seller.
Options:
A)10%
B)22%
C)18%
D)12%
E)15%
Rationale: Let the original price of the jewel be Rs. P and let the profit earned by the third seller
be x%.
Then, ( 100 +x )% of 125% of 120% of P = 165% of p
[ ( 100+x )/100*125/100*120/100* P ] = [ 165/100* P ]
( 100 + X ) = 165*100*100/125*120 = 110,
X = 10%.
ANSWER:A
Answer: A
Question: A ship sails out to a mark at the rate of 19 kmph. and sails back at the rate of 13 kmph. The average rate of sailing is ?
Options:
A)15 km/hr
B)12 km/hr
C)12.5 km/hr
D)25 km/hr
E)None
Rationale: Answer
Average = ( 2uv / u +v ) km/hr
= ( 2 x 19 x 13 ) / (19 +13 ) km/hr.
= 15 km/hr.
Correct Option: A
Answer: A
Question: Two goods trains each 500 m long are running in opposite directions on parallel tracks. Their speeds are 30 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one?
Options:
A)12 sec
B)24 sec
C)48 sec
D)60 sec
E)62 sec
Rationale: Relative speed = 30 + 30 = 60 km/hr.
60 * 5/18 = 50/3 m/sec.
Distance covered = 500 + 500 = 1000 m.
Required time = 1000 * 3/50 = 60 sec.
ANSWER:D
Answer: D
Question: If x is positive integer,y is negative integer, and 3x + 2y = 13, which of the following could be the value of x ?
Options:
A)9
B)10
C)12
D)13
E)4
Rationale: Use answer options to solve this problem -
Put x= 9
3x+2y=13
3(9)+2y=13
27+2y=13
2y=13-27;2y=-14
y=-7(y is negative integer)
Answer will be (A)
Answer: A
Question: Some of the workers at a hedge fund are analysts; the others are not analysts. There are a total of 2x/3 analysts at the hedge fund. A total of x hedge fund workers have an MBA. Furthermore, x/3 analysts have an MBA, y/4 of the hedge fund workers are neither analysts nor have an MBA, and 70 workers are not analysts. If there are y total workers at the hedge fund, x is equal to which of the following?
Options:
A)45
B)50
C)63
D)75
E)80
Rationale: AnalystsNot AnalystsTotal
MBAx/32x/3x
No MBAy/4
Total2x/350y
We are asked for the value of x.
From the table: 2x/3 = y - 70
y - 70 + (y/4) = 70
5y/4 = 140
y = 112
2x/3 = 112 - 70 = 42
x = 126/2 = 63
Answer: C
Answer: C
Question: Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is:
Options:
A)4
B)6
C)5
D)7
E)9
Rationale: N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305)
= H.C.F. of 3360, 2240 and 5600 = 1120.
Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4
Answer: Option A
Answer: A
Question: If the true discount on a sum due 3 years hence at 14% per annum be Rs. 168, the sum due is:
Options:
A)698
B)768
C)1430
D)1980
E)None
Rationale: Sol.
P.W. = 100 * T.D./R * T = 100 * 168 / 14 * 2 = 600.
∴ Sum = (P.W. + T.D.) = Rs. (600 + 168) = Rs. 768.
Answer B
Answer: B
Question: William earned $9.50 an hour. He worked 40 hours one week and received a bonus
of $75.00. How much did he earn that week?
Options:
A)$455.00
B)$555.00
C)$655.00
D)$755.00
E)$855.00
Rationale: Multiply $9.50 x 40 = $380.00
Add bonus $75.00 + $380.00= $455.00
$380.00
+ 75.00
$455.00
correct answer A
Answer: A
Question: Find the unit's digit in the product 2467 153 * 34172?
Options:
A)1
B)3
C)2
D)5
E)7
Rationale: Unit's digit in the given product=Unit's digit in 7 153 * 172
Now 7 4 gives unit digit 1
7 152 gives unit digit 1
7 153 gives 1*7=7.Also 172 gives 1
Hence unit's digit in the product =7*1=7.
Option A
Answer: A
Question: Find the surface area of a 10cm*4cm*3cm brick.
Options:
A)154 cm square
B)156 cm square
C)160 cm square
D)164 cm square
E)None of these
Rationale: Explanation:
Surface area of a cuboid = 2(lb+bh+hl) cm square
So,
Surface area of a brick = 2(10*4+4*3+3*10) cm square
= 2(82) cm square = 164 cm square
Option D
Answer: D
Question: The banker's discount on a sum of money for 3 years is Rs. 1116. The true discount on the same sum for 4 years is Rs. 1200. What is the rate per cent?
Options:
A)8%
B)12%
C)10%
D)6%
E)7%
Rationale: Explanation :
BD for 3 years = Rs. 1116
BD for 4 years = 11163 × 4 = Rs. 1488
TD for 4 years = Rs. 1200
F = BD × TD(BD – TD) = (1488 × 1200)/(1488–1200) = (1488×1200)/288
= (124 × 1200)/24 = (124 × 100)/2 = 62 × 100 = Rs. 6200
=> Rs.1488 is the simple interest on Rs. 6200 for 4 years
⇒ 1488 = (6200 × 4 × R)/100
⇒ R = (1488 × 100)/(6200 × 4)
= (372 × 100)/6200 = 372/62 = 6% Answer : Option D
Answer: D
Question: If the average (arithmetic mean) of a and b is 100, and c – a = 120, what is the average of b and c?
Options:
A)150
B)140
C)160
D)170
E)180
Rationale: a+b/2 = 100
=> a+b = 200
a = c - 120...sub this value
c-120+b = 200
=>c+b = 320
=>c+b/2 = 160
Answer : C
Answer: C
Question: In the x-y plane, the area of the region bounded by the graph of |x+y| + |x-y| = 8 is
Options:
A)8
B)12
C)256
D)20
E)24
Rationale: I've never seen such kind of question in GMAT before.
OK there can be 4 cases:
|x+y| + |x-y| = 8
A. x+y+x-y = 8 --> x=4
B. x+y-x+y = 8 --> y=4
C. -x-y +x-y= 8 --> y=-4
D. -x-y-x+y=8 --> x=-4
The area bounded by 4 graphs x=4, x=-4, y=4, y=-4 will be square with the side of 4 so the area will be 16*16=256
Answer: C
Answer: C
Question: A bowl has only 7 apples and 7 bananas. If one piece of fruit is selected from the bowl at random, and a second piece is selected from the bowl without replacing the first, what is the probability that both pieces of fruit chosen are apples?
Options:
A)1/10
B)1/5
C)2/9
D)2/5
E)3/13
Rationale: 7/14 * 6/13
=3/13
E. 3/13
Answer: E
Question: There are 7 players in a bowling team with an average weight of 121 Kg. If two new players join the team, one weighs 110 Kg and the second weighs 60 Kg, what will be the new average weight?
Options:
A)115 Kg.
B)118 Kg.
C)113 Kg.
D)110 Kg.
E)112 Kg.
Rationale: The New average will be= (121*7+110+60)/9= 113 kgs
C is the answer
Answer: C
Question: Can you find next number in tricky mathematical series below?
111 , 113 , 117 , 119 , 123 , 137 ?
Options:
A)151
B)161
C)171
D)131
E)121
Rationale: Solution:
151 (131+20)
Explanation:
1st 7 prime numbers post 100 are
101 , 103 , 107 , 109 , 113 , 127 , 131
...Adding 20 to numbers
121 , 123 , 127 , 129 , 133 , 147 , 151
Answer A
Answer: A
Question: A and B working separately can do a piece of work in 9 and 12 days respectively, If they work for a day alternately, A beginning, in how many days, the work will be completed?
Options:
A)9 days
B)11 days
C)8 days
D)10 1/4 days
E)None of them
Rationale: (A + B)'s 2 days' work =(1/9+1/12)=7/36
Work done in 5 pairs of days =(5*7/36)=35/36
Remaining work =(1-35/36)=1/36
On 11th day, it is A’s turn. 1/9 work is done by him in 1 day.
1/36 work is done by him in(9*1/36)=1/4 day
Total time taken = (10 + 1/4) days = 10 1/4days.
Answer is D.
Answer: D
Question: There are two numbers. If 30% of the first number is added to the second number, then the second number increases to its six-fifth. What is the ratio of the first number to the second number?
Options:
A)1 : 4
B)4 : 5
C)3 : 5
D)5 : 8
E)2 : 3
Rationale: Let the two numbers be x and y.
(3/10) * x + y = (6/5) * y
(3/10) * x = (1/5) * y
x/y = 10/15 = 2/3
The answer is E.
Answer: E
Question: If q is an odd integer, which of the following must also be odd?
Options:
A)6q + 4
B)q + q
C)3q + 3
D)2q + q
E)q^2 + 1
Rationale: Things to keep in mind:
Odd + odd = even
Odd + even = odd
Odd*odd = odd
Odd*even = even
On checking each option
A. 6q + 4
6q = even, 6q + 4 = even + even = even.
B. q + q
Odd + odd = even. This will be even
C. 3q + 3
3q = odd, 3q + 3 = odd + odd = even
D. 2q + q
2q = even, 2q +q = even + odd = odd
E. q^2 + 1
q^2 = odd, q^2 + 1 = odd + odd = even
Correct option: D
Answer: D