divelab/Sys2Bench huggingface dataset:
Question: A shipment of 1500 heads of cabbage, each of which was approximately the same size, was purchased for $600. The day the shipment arrived 1/3 of the heads were sold, each at 25% above the cost per head. The following day the rest were sold at a price equal to 5% less than the price each head sold for on the day before. What was the total gross profit on this shipment.
Options:
A)$100
B)b $115
C)c $120
D)d $125
E)e $135
Rationale: Purchase cost = 600/1500= $ 0.4
25% above the cost per head = (125/100)*0.4= $ 0.5
2/3 of the heads were sold means 1/3*1500 =500 ,Selling amount for 500 cabbage = 500 * 0.5 = $ 250
Remaining were sold at a price equal to 10% less than the price each head sold for on the day before i.e , (95/100)*0.5 = $ 0.475
Hence selling cost for the remaining cabbage = 1000 * 0.475 = $ 475
Total selling cost = 475 + 250 = $ 725
Gross profit = $ 725 - $ 600 = $ 125
Hence Answer is D
Answer: D
Question: 30 men can complete a piece of work in 18 days. In how many days will 27 men complete the same work ?
Options:
A)20
B)77
C)36
D)25
E)13
Rationale: Explanation:
Less Men, means more Days {Indirect Proportion}
Let the number of days be x
then,
27 : 30 :: 18 : x
[Please pay attention, we have written 27 : 30 rather than 30 : 27, in indirect proportion, if you get it then chain rule is clear to you :)]
{\color{Blue} x=\frac{30\times 18}{27}}
x = 20
So 20 days will be required to get work done by 27 men.
Answer: A
Answer: A
Question: QUANT 4-PACK SERIES Problem Solving Pack 4 Question 2 For every positive integer n...
For every positive integer n that is greater than 1, the function a(n) is defined to be the sum of all of the odd integers from 1 to n, inclusive. The a(n) could have any of the following units digits except…?
Options:
A)1
B)2
C)4
D)6
E)9
Rationale: For every positive integer n that is greater than 1, the function a(n) is defined to be the sum of all of the odd integers from 1 to n, inclusive. The a(n) could have any of the following units digits except…?
Used brute force on this one to calculate. Not sure if there is a quicker way.
1+3=4 C is out
1+3+....15= 81 A is out
1+3+5+7=16 D is out
1+3+5=9 E i out
Answer: B
Answer: B
Question: A towel, when bleached, lost 30% of its length and 25% of its breadth. What is the percentage decrease in area?
Options:
A)24%
B)30 %
C)44%
D)54%
E)47.5%
Rationale: percentage change in area
=(−30−25+(30×25)/100)%=−47.5%
i.e., area is decreased by 47.5%
ANSWER:E
Answer: E
Question: A computer manufacturer produces a certain electronic component at a cost of $80 per component. Shipping costs for delivering the components are $7 per unit. Further, the manufacturer has costs of $16,500 a month related to the electronic component regardless of how many it produces. If the manufacturer produces and sells 150 components a month, what is the lowest price it can sell them for such that the costs don't exceed the revenues?
Options:
A)$28
B)$82
C)$110
D)$138
E)$197
Rationale: by the question, the equation would be 150 p - 87*150 - 16500 = 0
p being the price we want to find and equation resulting zero means revenue and costs are equal so we can get the minimum price of the component.
solving the equation, we get p = $ 197. Answer E for me.
Answer: E
Question: 2 hours after a freight train leaves Delhi a passenger train leaves the same station travelling in the same direction at an average speed of 16 km/hr. After travelling 4 hrs the passenger train overtakes the freight train. The average speed of the freight train was?
Options:
A)30
B)40
C)58
D)60
E)11
Rationale: let the speed of freight train be xkm/hr
distance covered by freight train in 6 hours=distance covered by passenger train in 4 hrs
6x=16*4
x=10.66
x=11 km/hr
ANSWER:E
Answer: E
Question: A certain car traveled twice as many miles from Town A to Town B as it did from Town B to Town C. From Town A to Town B, the car averaged 12 miles per gallon, and from Town B to Town C, the car averaged 11 miles per gallon. What is the average miles per gallon that the car achieved on its trip from Town A through Town B to Town C?
Options:
A)13
B)13.5
C)14
D)14.5
E)15.3
Rationale: Ans is B
Given d_ab = 2*d_bc
let d_ab = d and d_bc = x so d=2x
for average miles per gallon = (d+x)/((d/12)+(x/11)) = 15.3 (formula avg speed = total distance/ total time)
Answer: B
Question: If 5 less than x is 2 greater than y, then a number z that is 5 greater than x reduced by y is equal to
Options:
A)12
B)9
C)14
D)y + 9
E)y + 14
Rationale: 12 it is....nice one....
A
Answer: A
Question: An analyst will recommend a combination of 2 industrial stocks, 2 transportation stocks, and 2 utility stocks. If the analyst can choose from 5 industrial stocks, 4 transportation stocks, and 3 utility stocks, how many different combinations of 6 stocks are possible?
--
Options:
A)12
B)19
C)60
D)160
E)180
Rationale: 5C2 * 4C2 * 3C2 = 10*6*3 = 180.
Answer: E.
Answer: E
Question: A trader marked the selling price of an article at 10% above the cost price. At the time of selling, he allows certain discount and suffers a loss of 1%. He allowed a discount of :
Options:
A)10 %
B)10.5 %
C)11 %
D)12.5 %
E)None
Rationale: Sol.
Let C.P. = Rs. 100. Then, Marked Price = Rs. 110, S.P. = Rs. 99.
∴ Discount % = [11/110 * 100] % = 10%
Answer A
Answer: A
Question: Karen places a bet with Tom that she will beat Tom in a car race by 4 miles even if Karen starts 4 minutes late. Assuming that Karen drives at an average speed of 60 mph and Tom drives at an average speed of 45 mph, how many Y miles will Tom drive before Karen wins the bet?
Options:
A)15
B)18
C)21
D)24
E)27
Rationale: Let K and T be the speeds of Karen and Tom respectively.
t be the time that Karen will travel ----> t+4/60 will be the total time Tom will travel by the time the distance between Karen and Tom is 4 miles.
Thus, per the question , K(t) - T(t+4/60) = 4 ---> t = 7/15 hours
Thus the distance traveled by Tom when Karen is 4 miles ahead of him Y: T*(t+4/60) = 45 (7/15+4/60) = 24 miles. D is the correct answer.
Answer: D
Question: The price of a scooter and TV are in the ratio 7:5. If the scooter costs $100 more than the TV. then the price of the TV?
Options:
A)400
B)350
C)250
D)500
E)150
Rationale: Let the price of the scooter and TV is 7x and 5x
7x-5x = 100
x = 50
Price of TV = 7*50 = $350
Answer is B
Answer: B
Question: A grocer has a sale of Rs. 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 6900?
Options:
A)s. 4991
B)s. 5991
C)s. 6001
D)s. 6991
E)s. 7391
Rationale: total fr 5 mnths=(6435+6927+6855+7230+6562)=Rs34009.
Reqd.sale=Rs.[(6900*6)-34009]
= Rs.(41400-34009)
= Rs.7391.
ANSWER:E
Answer: E
Question: In an animal behavior experiment, 25 tagged white pigeons and 250 tagged gray pigeons were released from a laboratory. Within one week, 88 percent of the white pigeons and 80.5 percent of the gray pigeons had returned to the laboratory. What percent of the total number of pigeons returned to the laboratory?
Options:
A)80.5
B)82
C)81.5
D)85
E)81.25
Rationale: Weighted mix method is best here....
Ratio is 1:10 for 88:80.5...
So the answer required = 80.5+ (88-80.5)*1/10=80.5+7.5*1/10
80.5+0.75=81.25
E
Answer: E
Question: If four boxes of crayons contain six different colored crayons in each box, and a crayon is randomly selected from each box, what is the probability of getting at least one pair of the same colored crayons?
Options:
A)13/18
B)5/18
C)1/2
D)2/3
E)1/6
Rationale: AT LEAST one pair of matching crayons.
First solve for NO matching crayons:
1st box = any color = 6/6
2nd box = not a match to the first = 5/6
3rd box = not a match to the 1st or 2nd = 4/6
4th box = not a match to the 1st or 2nd or 3rd = 3/6
(6/6)(5/6)(4/6)(3/6) =
(1)(5/6)(2/3)(1/2) =
10/36
10/36 is the probability of NO matching crayons, so...
1 - 10/36 = 26/36 = the probability of getting at least one matching pair of crayons.
26/36 = 13/18
Answer: A
Answer: A
Question: A certain quantity is measured on two different scales, the R scale and the S scale, that are related linearly. Measurements on the R scale of 6 and 24 correspond to the measurements on the S scale of 30 and 60 respectively. What measurement on the R scale corresponds to a measurement of 75 on the S scale?
Options:
A)30
B)33
C)36
D)39
E)42
Rationale: A change of +18 on the R scale is a change of +30 on the S scale.
R = (18/30)*S + K = 3S/5 + K
6 = 3(30)/5 + K
K = -12
R = 3S/5 - 12
R = 3(75)/5 - 12 = 45-12 = 33
The answer is B.
Answer: B
Question: John invested $ 30000 at 7% per annum, He got 34347 after some period, The interest was calculated compoundly. Find the period?
Options:
A)2 Years
B)2 1/2 Years
C)3 Years
D)4 Years
E)3 1/2 Years
Rationale: P(1+(R/100))power of n
so
=30000(1+(7/100))power of n = 34347
=(107/100)Power of n=34347/30000
To simplify 34347/30000
We get 11449/10000
This is in the form of (107/100) power of 2
so The value of n is 2
Answer is 2 years
Answer: A
Question: The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is:
Options:
A)35 years
B)40 years
C)50 years
D)45 years
E)None of these
Rationale: Sum of the present ages of husband, wife and child = (27 x 3 + 3 x 3) years = 90 years.
Sum of the present ages of wife and child = (20 x 2 + 5 x 2) years = 50 years.
Husband's present age = (90 - 50) years = 40 years.
Answer: Option B
Answer: B
Question: A call center has two teams. Each member of Team A was able to process 2/5 calls as compared to each member of Team B. If Team A has 5/8 as many number of call center agents as Team B, what fraction of the total calls was processed by Team B?
Options:
A)3/2
B)3/4
C)4/5
D)1/2
E)1/5
Rationale: Let team B has 8 agents, so team A has 5 agents
Let each agent of team B picked up 5 calls, so total calls by team B = 40
So, each agent in Team A picked up 2 calls, so total calls for team A = 10
Fraction for team B = 40/(40+10) = 4/5 = Answer = C
Answer: C
Question: A grocer has 400 pounds of coffee in stock, 30 percent of which is decaffeinated. If the grocer buys another 100 pounds of coffee of which 60 percent is decaffeinated, what percent, by weight, of the grocer’s stock of coffee is decaffeinated?
Options:
A)28%
B)30%
C)36%
D)36%
E)40%
Rationale: 1. 30% of 400=120 pounds of decaffeinated coffee
2. 60% of 100=60 pounds of decaffeinated coffee
3. Wt have 180 pounds of decaffeinated out of 500 pounds, that means 180/500*100%=36%. The correct answer is D.
Answer: D
Question: A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, the how old is B?
Let C's age be x years. Then, B's age = 2x years. A's age = (2x + 2) years.
(2x + 2) + 2x + x = 27
5x = 25
x = 5.
Hence, B's age = 2x = 10 years.
Options:
A)7
B)8
C)9
D)10
E)11
Rationale: Let C's age be x years. Then, B's age = 2x years. A's age = (2x + 2) years.
(2x + 2) + 2x + x = 27
5x = 25
x = 5.
Hence, B's age = 2x = 10 years.
Answer: Option D
Answer: D
Question: A reduction of 10% in the price of rice enables a man to obtain 2 kgs more for Rs.1000, what is the reduced price for kg?
Options:
A)Rs.40
B)Rs.44
C)Rs.46
D)Rs.48
E)Rs.50
Rationale: Explanation:
1000*(10/100) = 100 ---- 2
? ---- 1 => Rs.50
Answer: E
Answer: E
Question: A, B and C can do a work in 4 days, 8 days and 12 days respectively. In how many days can all three of them working together, complete the work?
Options:
A)2 9/11 days
B)5 2/11 days
C)2 1/11 days
D)3 2/11 days
E)2 2/11 days
Rationale: Work done by all three of them in one day = 1/4+ 1/8 + 1/12 = 11/24.
The number of days required = 24/11 = 2 2/11 days.
ANSWER:E
Answer: E
Question: A monkey start climbing up a tree 20ft tall.Each hour it hops 3 ft and slips back 2ft.How much time would it take the monkey to reach the top.
Options:
A)15 hrs
B)18 hrs
C)19 hrs
D)17 hrs
E)16 hrs
Rationale: if monkey hops 3ft and slips back 2ft in a hour, it means the monkey hops (3ft-2ft)= 1ft/hr.
similarly in 17hrs it wil be 17ft.
Bt since the height of the tree is 20ft, so if the monkey hops up the tree in the next hr i.e 18th hr then it reaches at the top of the tree.
hence it takes 18 hrs for monkey to reach at the top
ANSWER:B
Answer: B
Question: A and B walk around a circular track. They start at 8 a.m. from the same point in the opposite directions. A and B walk at a speed of 2 rounds per hour and 2 rounds per hour respectively. How many times shall they cross each other before 9.30 a.m. ?
Options:
A)A)5
B)B)61
C)C)8
D)D)6
E)E)9
Rationale: Relative speed = 2 + 2 = 4 rounds per hour.
So, they cross each other 4 times in an hour and 2 times in half an hour.
Hence, they cross each other 6 times before 9.30 a.m.
ANSWER:D
Answer: D
Question: How many digits are in the number 50^8 × 8^3 × 11?
Options:
A)18
B)20
C)19
D)22
E)17
Rationale: Whenever you are asked to find the number of digits, try to bring the number in multiples of 10. This way, we can wasily calculate the umber of 0's through the powers of 10
50^8 × 8^3 × 11 = (5^2*2)^8*2^9*11 = 5^16*2^17*11 = 2*11*10^16 = 22*10^16
Hence we would have 16 trailing 0's and the three digits from 22
Total digits = 2 + 16 = 18
Correct Option: A
Answer: A
Question: If the average (arithmetic mean) of a and b is 140, and the average of b and c is 100, what is the value of a − c?
Options:
A)−220
B)−100
C)100
D)135
E)80
Rationale: a+b = 280
b+c = 200
a-c = 80.
IMO option E.
Answer: E
Question: If [x] is the greatest integer less than or equal to x, what is the value of [-6.2]+[-3.4]+[12.7] ?
Options:
A) -1
B) 0
C) 1
D) 2
E) 3
Rationale: You are asked what the closest lesser integer value to [x] is.
[-6.2] = -7.0
[-3.4] = -4.0
[12.7] = 12.0
Therefore , answer is: -7.0 -4.0 + 12.0 = -1.0
Option A.
Answer: A
Question: Pipe P can drain the liquid from a tank in 1/4 the time that it takes pipe Q to drain it and in 2/3 the time that it takes pipe R to do it. If all 3 pipes operating simultaneously but independently are used to drain liquid from the tank, then pipe Q drains what portion of the liquid from the tank?
Options:
A)9/29
B)3/23
C)3/8
D)17/29
E)3/4
Rationale: Suppose Q can drain in 1 hr. So, rQ = 1/1 = 1
So, rP = 1/[(1/4)rQ] = 4
Also, rP = rR/(2/3) => 4 = rR/(2/3) => rR = 8/3
Let H is the time it takes to drain by running all 3 pipes simultaneously
So combined rate = rC = 1/H = 1 + 4 + 8/3 = 23/3 = 1/(3/23)
Thus running simultaneously, Pipe Q will drain 3/23 of the liquid.
Thus answer = B.
Answer: B
Question: Find the sum which will yield an interest of Rs.910 in 2 1/2 years at 7% p/a simple interest.
Options:
A)Rs.3200
B)Rs.4200
C)Rs.6200
D)Rs.5200
E)Rs.7200
Rationale: 70 = (P*4*7/2)/100
P = (910x100x2)/(5x7)=Rs.5200
Answer: D
Answer: D
Question: John has taken four (4) tests that have an average of 81. In order to bring his course grade up to a ‘B’, he will need to have a final average of 87. What will he need to average on his final two tests to achieve this grade?
Options:
A)87
B)90
C)92
D)94
E)99
Rationale: 87-81=6*4=24 points
2*87=174
174+24=198 points to be scored in the 2 tests.
Avg of 2 tests = 198/2=99
Answer: E
Traditional Method:
Total scored till now 81*4=324
Total score to avg 87 in 6 tests = 87*6=522
Total to be scored on 2 tests = 522-324=198
Avg on 2 tests = 198/2 = 99
Answer E
Answer: E
Question: The H.C.F. of two numbers is 59 and the other two factors of their L.C.M. are 13 and 16. The larger of the two numbers is:
Options:
A)678
B)944
C)456
D)323
E)899
Rationale: :	Explanation:
Clearly, the numbers are (59 x 13) and (59 x 16).
{\color{Blue} \therefore } Larger number = (59 x 16) = 944.
Answer: B)944
Answer: B
Question: In the first M games of a team's season, the ratio of the team's wins to its losses was 1:2. In the subsequent N games, the ratio of the team´s wins to losses was 1:4. If M:N = 4:5, what was the ratio of the team's wins to its losses for all M+N games?
Options:
A)7:20
B)9:23
C)11:27
D)23:54
E)31:77
Rationale: M = 4/9 of total games
N = 5/9 of total games
Wins = 1/3*4/9 + 1/5*5/9 = 4/27 + 3/27 = 7/27
Losses = 1 - 7/27 = 20/27
The ratio of wins to losses is 7:20.
The answer is A.
Answer: A
Question: A number when divided successively by 4 and 5 leaves remainders 1 and 4 respectively. When it is successively divided by 5 and 4, then the respective remainders will be
Options:
A)1,2
B)2,3
C)3,7
D)2,7
E)8,7
Rationale: 4 | x y = (5 x 1 + 4) = 9
--------
5 | y -1 x = (4 x y + 1) = (4 x 9 + 1) = 37
--------
| 1 -4
Now, 37 when divided successively by 5 and 4, we get
5 | 37
---------
4 | 7 - 2
---------
| 1 - 3
Respective remainders are 2 and 3.
Correct Option is B
Answer: B
Question: Which of the following is equal to 10^-(-3)^3?
Options:
A)1/(10^30)
B)1/(10^28)
C)1/(10^29)
D)1/(10^27)
E)1/(10^25)
Rationale: 10^-(-3)^3 => 10^-(-3^3) => 10^-(27) = 1/(10^27)
Answer : D
Answer: D
Question: 3 men or 6 women can do a piece of work in 24 days. In how many days will 12 men and 8 women do the same work?
Options:
A)15/9 days
B)9/2 days
C)18/4 days
D)11/4 days
E)35/4 days
Rationale: 3M = 6W ---- 24 days
12M + 8W -----?
24W + 8 W = 32W ---?
6W ---- 24 32 -----?
6 * 24 = 32 * x => x = 9/2 days
Answer:B
Answer: B
Question: In what time will Rs.5000 lent at 3% per annum on simple interest earn as much interest as Rs.5000 will earn in 5 years at 4% per annum on simple interest?
Options:
A)6 2/3
B)6 1/6
C)6 1/3
D)6 1/2
E)6 1/5
Rationale: (5000*3*R)/100 = (5000*5*4)/100
R = 6 2/3
Answer: A
Answer: A
Question: Jack takes a loan of $120,000 with 12% annual interest: the interest is paid once, at the end of the year. Jill takes a loan of $120,000 with 12% annual interest, compounding monthly at the end of each month. At the end of one full year, compared to Jack's loan interest, approximately how much more does Jill have to repay?
Options:
A)Zero
B)$81.90
C)$8190.03
D)$819.00
E)$8.19
Rationale: Jack's interest= $120,000*0.12 = $14400 or $1,200 each month.
Jills’s interest, 12%/12 = 1% each month:
For the 1st month = $120,000*0.01 = $1,200;
For the 2nd month = $1,200 + 1% of 1,200 = $1,212, so we would have interest earned on interest (very small amount);
For the 3rd month = $1,212 + 1% of 1,212 = ~$1,224;
For the 4th month = $1,224 + 1% of 1,224 = ~$1,236;
...
For the 12th month = $1,320 + 1% of 1,320 = ~$1,332.
The difference between Jack's interest and Jill’s interest = ~(12 + 24 + ... + 132) = $792.
Answer: D.
Answer: D
Question: shopkeeper buys two articles for Rs.1000 each and then sells them, making 20% profit on the first article and 20% loss on second article. Find the net profit or loss percent?
Options:
A)8%
B)9%
C)3%
D)4%
E)2%
Rationale: SP of first article = 1000
Profit = 20%
CP = (SP)*[100/(100+P)] = 5000/6 = 2500/3
SP of second article = 1000
Loss = 20%
CP = (SP)*[100/(100-L)] = 5000/4 = 1250
Total SP = 2000
Total CP = 2500/3 + 1250 = 6250/3
CP is more than SP, he makes a loss.
Loss = CP-SP = (6250/3)- 2000 = 250/3
Loss Percent = [(250/3)/(6250/3)]*100
=0.04 * 100 = 4%
Answer:D
Answer: D
Question: In a certain pond, 50 fish were caught, tagged, and returned to the pond. A few days later, 50 fish were caught again, of which 2 were found to have been tagged. If the percent of tagged fish in the second catch approximates the percent of tagged fish in the pond, what is the approximate number of fish in the pond?
Options:
A)400
B)625
C)1250
D)2500
E)10000
Rationale: This is a rather straight forward ratio problem.
1. 50 fish tagged
2. 2 out of the 50 fish caught were tagged thus 2/50
2/50=50/x
thus, x=1250
Think of the analogy: 2 fish is to 50 Fish as 50 fish is to ...?
You've tagged 50 fish and you need to find what that comprises as a percentage of the total fish population - we have that information with the ratio of the second catch
ANSWER C
Answer: C
Question: A group of two women and three men have tickets for seven adjacent seats in one row of a theatre. If the three men will not sit in three adjacent seats, how many possible different seating arrangements are there for these 7 theatre-goers?
Options:
A) 7! – 2!3!2!
B) 7! – 4!3!
C) 5! – 3!3!
D) 7 × 2!3!2!
E) 2!3!2!
Rationale: 5 people can sit in 5! different ways. But because 3 men cannot sit together, we take them as a unit.
This unit of men, among themselves can sit in 3! ways.
Hence, 5! - 3!.
This unit of men along with 2 women can sit in 3! different ways which also needs to be eliminated.
Hence 5! - 3!3!
C
Answer: C
Question: The product of two numbers is 2028 and their H.C.F is 13. The number of such pairs is?
Options:
A)7
B)2
C)3
D)4
E)9
Rationale: Let the numbers be 13a and 13b.
Then, 13a * 13b = 2028 => ab = 12.
Now, co-primes with product 12 are (1, 12) and (3, 4).
So, the required numbers are (13 * 1, 13 * 12) and (13 * 3, 13 * 4).
Clearly, there are 2 such pairs.
Answer: B
Answer: B
Question: A train covers a distance of 12 km in 10 min. If it takes 6 sec to pass a telegraph post, then the length of the train is?
Options:
A)276 m
B)256 m
C)120 m
D)216 m
E)268 m
Rationale: Speed = (12/10 * 60) km/hr
= (72 * 5/18) m/sec = 20 m/sec.
Length of the train = 20 * 6
= 120 m.
Answer:C
Answer: C
Question: The 19th of September 1987 was a Saturday. If 1988 was a leap-year, what day of the week was the 24th of September 1990?
Options:
A)Monday
B)Tuesday
C)Wednesday
D)Thursday
E)Friday
Rationale: 19th September
1987: Saturday
1988: Monday (due to leap year)
1989: Tuesday
1990: Wednesday
Hence 24th September was a Monday.
The answer is A.
Answer: A
Question: A man invested Rs. 1552 in a stock at 97 to obtain an income of Rs. 128. The dividend from the stock is :
Options:
A)7.5 %
B)8 %
C)9.7 %
D)None of these
E)Cannot be determined
Rationale: Solution
By investing Rs. 1552,income = Rs. 128.
By investing Rs. 97, income = Rs. (128/1552x97) =Rs.8
∴ Dividend = 8%.
Answer B
Answer: B
Question: If a man were to sell his chair for Rs. 720, he would lose 25%. To gain 25% he should sell it for:
Options:
A)Rs. 1,200
B)Rs. 1,000
C)Rs. 960
D)Rs. 900
E)None
Rationale: Solution: Let the Cost price of the Chair is X.
SP = X - 25% of X
720 = 0.75X
X = 960.
CP = Rs. 960.
So, To gain 25%, SP would be
= 960 + 25% of 960 =Rs. 1200.
Short-cut
CP of chair = (100/75)*720 = Rs. 960;
To gain 25%, SP = (125/100)*960 = Rs. 1200.
Answer: Option A
Answer: A
Question: The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is?
Options:
A)288
B)298
C)245
D)200
E)212
Rationale: Speed = [45 X 5/18] m/sec = [25/2] m/sec Time = 30 sec Let the length of bridge be x metres. Then, (130 + x)/30 = 25/2 => 2(130 + x) = 750 => x = 245 m. Answer: C
Answer: C
Question: A and B invests Rs.10000 each, A investing for 4 months and B investing for all the 12 months in the year. If the total profit at the end of the year is Rs.4000, find their shares?
Options:
A)1000,3500
B)1000,3000
C)1000,2000
D)1000,5000
E)1000,2500
Rationale: The ratio of their profits A:B = 4:12 =1:3
Share of A in the total profit = 1/4 * 4000 = Rs.1000
Share of B in the total profit = 3/4 * 4000 = Rs.3000
Answer:B
Answer: B
Question: The average age of 8 men increases by 2 years when two women are included in place of two men of ages 20 and 28 years. Find the average age of the women?
Options:
A)87
B)98
C)32
D)28
E)37
Rationale: 20 + 28 + 8 * 2
= 64/2
= 32
Answer:C
Answer: C
Question: Each of the following equations has at least one solution EXCEPT C. Is it true?
Options:
A)2* -a = (–2)*a
B)2*a = (–2)*-a
C)-2*a = -2-a
D)(–2)a = –2a
E)(–2)-a = –2-a
Rationale: If we put a = 1 then
A. -2
B. 2
D. -2
E. -3
Answer : C
Answer: C
Question: A sum of money lent at compound interest for 2 years at 20% per annum would fetch Rs.482 more, if the interest was payable half yearly than if it was payable annually . The sum is
Options:
A)200000
B)20000
C)200029
D)288778
E)277789
Rationale: Explanation:
Let sum=Rs.x
C.I. when compounded half yearly =
C.I. when compounded annually =
=> x=20000
Answer: B) 20000
Answer: B
Question: One-third less than 15% of 180 is equal to:
Options:
A)18
B)30
C)35
D)40
E)45
Rationale: Lots of ways to tackle this.
15% of 180 =27
1/3 of 27= 9
So, 1/3less than 27 is equal to 27- 9 = 18
Answer: A
Answer: A