divelab/Sys2Bench huggingface dataset:
Question: consider the sequence 1,-2,3,-4,5,-6........what is the average of first 200 terms of sequence?
Options:
A)-1
B)-0.5
C)0
D)0.5
E)1
Rationale: 1-2+3-4+5-6....................+199-200
= (1-2)+(3-4)+(5-6)....................+(199-200)
= -1-1-1......................(100 terms)
= -100
so, average= (-100)/200= -0.5
ANSWER:B
Answer: B
Question: How many factors of 270 are odd numbers greater than 1?
Options:
A)3
B)4
C)5
D)6
E)9
Rationale: prime factors of 810 are 2^1,3^4,5^1
total divisors = (power if a prime factor+1)
total no. of odd factors(3,5,) = (4+1)(1+1) =10
since we need odd divisors other than 1 =>10-1 =9 odd divisors
E is the answer
Answer: E
Question: If 28% of a number exceeds 18% of it by 7.2, then find the number?
Options:
A)50
B)34
C)55
D)60
E)90
Rationale: Use the elimination method to find the correct option.
Of all the options only 90 fits
28% of 90 = 25.2
18% of 90 = 16.2
25.2 - 16.2 = 7.2
Required number is 90.
ANSWER:E
Answer: E
Question: If z = 4p, where p is a prime number greater than 2, how many different positive even divisors does z have, including z ?
Options:
A) Two
B) Three
C) Four
D) Six
E) Eight
Rationale: z=4p
since z = 4p thenevendivisors are:
4p/4p= 1
4p/2p= 2
4p/4= p
4p/2= 2p
so the answer is (C)
Answer: C
Question: A and B undertake to do a piece of work for Rs 600. A alone can do it in 6 days while B alone can do it in 8 days. With the help of C, they can finish it in 3 days, Find the share of each?
Options:
A)300, 225, 75
B)200, 225, 80
C)400, 300, 100
D)500, 300, 100
E)None of these
Rationale: C’s one day’s work = (1/3) - (1/6 + 1/8) = 1/24
Therefore, A : B : C = Ratio of their one day’s work = 1/6 : 1/8 : 1/24 = 4 : 3 : 1.
A’s share = Rs (600 x 4/8) = 300
B’s share = Rs (600 x 3/8) = 225
C’s share = Rs[600 - (300 + 225)] = Rs 75
ANSWER:A
Answer: A
Question: The cash realised on selling a 14% stock is Rs.109.25, brokerage being 1/4% is?
Options:
A)366
B)106
C)102
D)109
E)122
Rationale: Cash realised= Rs. (109.25 - 0.25)
= Rs. 109.
Answer: D
Answer: D
Question: When p is divided by 9, the remainder is 4. All of the following are possible values of p, except for which of the following?
Options:
A)13
B)31
C)49
D)55
E)67
Rationale: If a number is divisible by 9, the sum of its digits must be divisible by 9. --> If a number leaves a remainder 4 when divided by 9 the sum of its digits must be 4.
55
Answer: D
Answer: D
Question: Zaya purchase 13 jars in a store then she returned 10 jars to store .Now how many jars she had?
Options:
A)A)5
B)B)11
C)C)19
D)D)3
E)E)4
Rationale: 13-10=3. Answer is D
Answer: D
Question: Indu gave Bindu Rs.4375 on compound interest for 2 years at 4% per annum. How much loss would Indu has suffered had she given it to Bindu for 2 years at 4% per annum simple interest?
Options:
A)s.10
B)s.7
C)s.5
D)s.3
E)s.4
Rationale: 4375 = D(100/4)2
D = 7
ANSWER:B
Answer: B
Question: The number of defects in the first five cars to come through a new production line are 8, 7, 10, 4, and 6, respectively. If the sixth car through the production line has either 3, 7, or 12 defects, for which of theses values does the mean number of defects per car for the first six cars equal the median?
I. 3
II. 7
III. 12
Options:
A)I only
B)II only
C)III only
D)I and III only
E)I, II, and III
Rationale: C
for 7 we will have mean as 7.16(approx) and median as 7 but for 3 we will have mean and median = 6.5 and for 12 we will have median and mean =8
Answer: C
Question: Two dogsled teams raced across a 300 mile course in Wyoming. Team A finished the course in 3 fewer hours than team Q. If team A's average speed was 5 mph greater than team Q's, what was team Q's average mph?
Options:
A)12
B)15
C)18
D)20
E)25
Rationale: This is a very specific format that has appeared in a handful of real GMAT questions, and you may wish to learn to recognize it: here we have a *fixed* distance, and we are given the difference between the times and speeds of two things that have traveled that distance. This is one of the very small number of question formats where backsolving is typically easier than solving directly, since the direct approach normally produces a quadratic equation.
Say Team Q's speed was s. Then Team Q's time is 300/s.
Team A's speed was then s+5, and Team A's time was then 300/(s+5).
We need to find an answer choice for s so that the time of Team A is 3 less than the time of Team Q. That is, we need an answer choice so that 300/(s+5) = (300/s) - 3. You can now immediately use number properties to zero in on promising answer choices: the times in these questions will always work out to be integers, and we need to divide 300 by s, and by s+5. So we want an answer choice s which is a factor of 300, and for which s+5 is also a factor of 300. So you can rule out answers A and C immediately, since s+5 won't be a divisor of 300 in those cases (sometimes using number properties you get to the correct answer without doing any other work, but unfortunately that's not the case here). Testing the other answer choices, if you try answer D, you find the time for Team Q is 15 hours, and for Team A is 12 hours, and since these differ by 3, as desired, D is correct.
Answer: D
Question: A triangle has two angles with ratio of 4:3, and the third angle is the sum of the first two. Find the smallest angle of the triangle in degrees.
Options:
A)130/11
B)270/7
C)270/11
D)310/7
E)35
Rationale: The angles are 4x, 3x, and (4x+3x) = 7x for some value x
the three angles of a triangle add up to 180, so
4x+3x+7x=180
14x=180
x=180/14
x=90/7
the smallest angle is 3x = 3*(90/7) = 270/7
B
Answer: B
Question: Alice, Benjamin, and Carol each try independently to win a carnival game. If their individual probabilities for success are 2/5, 3/8, and 2/7, respectively, what is the probability that exactly two of the three players will win but one will lose?
Options:
A)3/140
B)1/280
C)3/280
D)4/56
E)77/280
Rationale: P = P(A wins, B wins, C loses) + P(A wins, B loses, C wins) + P(A loses, B wins, C wins) = 2/5*3/8*5/7 + 2/5*5/8*2/7 + 3/5*3/8*2/7 = 77/280.
Answer: E.
Answer: E
Question: The average of seven numbers is 18. The average of first three numbers is 14 and the average of last three numbers is 19. What is the middle number?
Options:
A)19
B)22
C)27
D)29
E)31
Rationale: The total of seven numbers = 7X18 = 126
The total of first 3 and last 3 numbers is = 3 X 14+3 X 19 = 99
So, the middle number is (126 - 99 ) = 27
C)
Answer: C
Question: Bag A contains red, white and blue marbles such that the red to white marble ratio is 1:3 and the white to blue marble ratio is 2:3. Bag B contains red and white marbles in the ratio of 1:4. Together, the two bags contain 36 white marbles. How many red marbles could be in bag A?
Options:
A)1
B)3
C)4
D)6
E)8
Rationale: 6 is the answer.
Bag A-
R:W:B = 2:6:9
Let W in bag A be 6K
Bab B -
R:W = 1:4
Let W in bag B be 4P
W = 36 = 6K+4P
=> K =4, P=3
Total Red's in bag A will be 2K = 8
E
Answer: E
Question: Sum of the squares of three numbers is 314 and the sum of their products taken two at a time is 131. Find the sum?
Options:
A)20
B)25
C)26
D)28
E)24
Rationale: (a + b + c)2 = a2 + b2 + c2 + 2(ab +bc + ca) = 314 + 2* 131
a + b + c = √576 = 24
E
Answer: E
Question: Of the 3,600 employees of Company X, 1/6 are clerical. If the clerical staff were to be reduced by 1/4, what percent of the total number of the remaining employees would then be clerical?
Options:
A) 13%
B) 22.2%
C) 20%
D) 12.5%
E) 11.1%
Rationale: Welcome, just post the question and the choices
Let's see, the way I did it was
1/6 are clerical out of 3600 so 600 are clerical
600 reduced by 1/4 is 1200*1/4
so it reduced 150 people , so there is 450 clerical people left
but since 150 people left, it also reduced from the total of 3600 so there are 3450 people total
since 450 clerical left / 3450 people total
you get (A) 13%
Answer : A
Answer: A
Question: Birla company plans to assign identification numbers to its employees. Each number is to consist of four different digits from 0 to 9, inclusive, except that the first digit cannot be 0. How many different identification numbers are possible?
Options:
A) 3,024
B) 4,536
C) 5,040
D) 9,000
E) 10,000
Rationale: Birla company plans to assign identification numbers to its employees.The first digit can take 9 values from 1 to 9 inclusive;
The second digit can also take 9 values (9 digits minus the one we used for the first digit plus 0);
The third digit can take 8 values;
The fourth digit can take 7 values.
Total = 9*9*8*7 = something with the units digit if 6.
Answer: B.
Answer: B
Question: The duplicate ratio of 3:4 is?
Options:
A)9:19
B)9:13
C)9:16
D)9:12
E)9:11
Rationale: 32: 42 = 9:16
Answer: C
Answer: C
Question: The owner of a furniture shop charges his customer 24% more than the cost price. If a customer paid Rs. 8463 for a computer table, then what was the cost price of the computer table?
Options:
A)6825
B)2977
C)2871
D)6725
E)2981
Rationale: Explanation:
CP = SP * (100/(100 + profit%))
= 8463(100/124) = Rs. 6825.
Answer: A
Answer: A
Question: A watch was sold at a loss of 10%. If it was sold for Rs.140 more, there would have been a gain of 4%. What is the cost price?
Options:
A)1000
B)2777
C)2667
D)2908
E)2712
Rationale: 90%
104%
--------
14% ---- 140
100% ---- ? => Rs.1000
Answer: A
Answer: A
Question: Allay's internet provider offers unlimited traffic which costs $0.5 per day charged off at 12 a.m. The service is discontinued when client's debt exceeds $5. If today in the morning Allay makes a payment of $7, for how many days, including today, will she be connected to the internet without any additional payments, given her initial balance was $0?
Options:
A) 15
B) 24
C) 25
D) 26
E) 13
Rationale: day 0- payment of $7 is made in the morning (after 12 am midnight)
day 1 onwards(after 12 am midnight) internet service will begin and will run for 7*2=14 days i.e. at the end of day 15 balance will be zero.
now Allay can still use the internet till her debt reaches $5 which means total of 5*2=10 days.
now the question states for how many days, including today, will she be connected to the internet without any additional paymentsi.e. we will have to include day0 also in our final answer. therefore total no. of days =1+14+10=25=C
Answer: C
Question: A and B start a business with Rs.6000 and Rs.8000 respectively. Hoe should they share their profits at the end of one year?
Options:
A)3:4
B)3:6
C)3:1
D)3:2
E)3:0
Rationale: They should share the profits in the ratio of their investments.
The ratio of the investments made by A and B =
6000 : 8000 => 3:4 .
Answer:A
Answer: A
Question: Given that E and F are events such that P(E) = 0.16, P(F) = 0.4 and P(E n F) = 0.4,
find P (E|F) and P(F|E)
Options:
A)1/4
B)2/5
C)2/7
D)3/7
E)3/11
Rationale: Here, E and F are events
P(E|F) = P(EnF)/P(F) = 0.4/0.4 = 1
P(F|E) = P(EnF)/P(E) = 0.4/0.16 = 1/4.
A)
Answer: A
Question: Ten years ago, Kumar was thrice as old as Sailesh was but 10 years hence, he will be only twice as old. Find Kumar’s present age.
Options:
A)60 years
B)80 years
C)70 years
D)76 years
E)86 years
Rationale: Let Kumar’s present age be x years and Sailesh’s present age be y years.
Then, according to the first condition,
x - 10 = 3(y - 10) or, x - 3y = - 20 ..(1)
Now. Kumar’s age after 10 years = (x + 10) years
Sailesh’s age after 10 years = (y + 10)
(x + 10) = 2 (y + 10) or, x - 2y = 10 ..(2)
Solving (1) and (2), we get x = 70 and y = 30
Kumar’s age = 70 years and Sailesh’s age = 30 years.
ANSWER:C
Answer: C
Question: A cargo ship carrying four kinds of items, doohickies, geegaws, widgets, and yamyams, arrives at the port. Each item weighs 2, 11, 5, and 7 pounds, respectively, and each item is weighed as it is unloaded. If, in the middle of the unloading process, the product of the individual weights of the unloaded items equals 1,043,504,000 pounds, how many widgets have been unloaded?
Options:
A)2
B)3
C)4
D)625
E)208,700,800
Rationale: We need to know the number of widgets (which weigh 5 pounds each). The number of times that 5 divides the number is related to the number of times that 10 divides the number.
When we divide 1,043,504,000 by 1000, we get 1,043,504,000 = 1,043,504 * 5^3 *2^3.
1,043,504 is not divisible by 5, thus there are 3 widgets.
The answer is B.
Answer: B
Question: The digit in units place of the product 81 x 82 x ..... x 89 is
Options:
A)0
B)2
C)6
D)8
E)9
Rationale: Sol.
Required digit = unit digit in (1 x 2 x 3 x 4 x 5 x 6 x 7 x 8 x 9) = 0.
Answer A
Answer: A
Question: In how many different ways can the letters of the word 'DETAIL' be arranged in such a way that the vowels occupy only the odd positions?
Options:
A)32
B)48
C)36
D)60
E)120
Rationale: 3 vowels can be arranged in odd positions in 6 ways
and
3 consonants can be arranged in even positions in 6 ways.
so total 6*6= 36 ways
ANSWER:C
Answer: C
Question: If a particular is never chosen, in how many ways can a cricketbe chosen out of 15 players?
Options:
A)234
B)256
C)364
D)378
E)398
Rationale: A particular players is never chosen, it means that 11 players are selected out of 14 players.
=> Required number of ways = 14C11
= 14!/11!x3! = 364
C
Answer: C
Question: 80% of the population of a village is 23040. The total population of the village is ?
Options:
A)28800
B)24000
C)24936
D)25640
E)None
Rationale: Answer
∵ 80% of P = 23040
∴ P = (23040 x 100) / 80 = 28800
Correct Option: A
Answer: A
Question: If A,B,C are three integers and AB+C is even ; which of the following must be true? A)C is even B)B is even C)AB is Odd
Options:
A)None of the above
B)I only
C)II only
D)III only
E)I,II only
Rationale: If AB is Odd then C will not even. O+E = O
If B is even AB is even always. But If C is Odd E+O = O
None of the above are true.
Answer : A
Answer: A
Question: 21 ball numbered 1 to 21. A ballis drawn and then another ball is drawn without replacement.
Options:
A)2/17
B)3/37
C)9/42
D)8/97
E)12/31
Rationale: The probability that first toy shows the even number,
=1021=1021
Since, the toy is not replaced there are now 9 even numbered toys and total 20 toys left.
Hence, probability that second toy shows the even number,
=920=920
Required probability,
=(1021)×(920)=(1021)×(920)
=9/42
C
Answer: C
Question: If x > 0.3, which of the following could be the value of x?
Options:
A)√0.005
B)√0.0005
C)√0.3
D)√0.006
E)√0.007
Rationale: Answer : C
Answer: C
Question: Find the simple interest on $10000 at 5% per annum for 12 months?
Options:
A)$410
B)$500
C)$650
D)$710
E)$1000
Rationale: P = $10000
R = 5%
T = 12/12 YEARS = 1 YEAR
S.I. = P*R*T/100 = 10000*5*1/100 = $500
Answer is B
Answer: B
Question: A 600 meter long train crosses a signal post in 50 seconds. How long will it take to cross a 3 kilometer long bridge, at the same speed?
Options:
A)4 min
B)2 min
C)8 min
D)9 min
E)5 min
Rationale: S = 600/50 = 12 mps
S = 3600/12 = 300 sec = 5 min
Answer: E
Answer: E
Question: How much is 80% of 40 is greater than 4/5 of 25?
Options:
A)29
B)776
C)66
D)12
E)99
Rationale: (80/100) * 40 – (4/5) * 25
32 - 20 = 12
Answer: D
Answer: D
Question: The average of non zero number and its square is 5 times the number. The number is?
Options:
A)5
B)7
C)9
D)10
E)12
Rationale: Let the number be x
(x+x^2)/2 = 5x
x^2 - 9x = 0
x(x-9) = 0
x = 0 or x = 9
So the number is 9
Answer is C
Answer: C
Question: Carolina has 1 nickel and 5 pennies in her pocket. If she pulls 2 coins out of her pocket simultaneously and randomly, what is the probability that she will be holding exactly 6 cents?
Options:
A)1/3
B)4/15
C)5/6
D)6/10
E)2/15
Rationale: The probability is equal to the number of desired choices divided by the total number of possibilities.
Probability = Favorable/Total
Total = 6C2 = 6*5/2 = 15
Favorable:
Pick 1 penny out of 5 pennies
AND
Pick the 1 nickel
5C1*1C1 = 5*1 = 5
P = 5/15 = 1/3
When you use combination method, it is picking all possible cases and the order doesn't matter. Whereas, upon choosing probability method to solve, order matters.
Thus,
Total Probability:
Probability of choosing a penny first AND Probability of choosing the nickel
OR
Probability of choosing the nickel first AND Probability of choosing a penny
Answer: A
Answer: A
Question: A pipe can fill a cistern in 20 minutes whereas the cistern when fill can be emptied by a leak in 30 minutes. When both pipes are opened, find when the cistern will be full?
Options:
A)17 minutes
B)87 minutes
C)60 minutes
D)27 minutes
E)11 minutes
Rationale: 1/20 - 1/30 = 1/60
60 minutes
Answer:C
Answer: C
Question: The average marks obtained by 120 candidates in a certain examinationis 35.if the average marks of passed candidate is 39 and that of the failed candidates is 15,what is the no. of candidates who passed the examination?
Options:
A)880
B)100
C)110
D)109
E)107
Rationale: Let No. of passed candidates are x
So, x * 39 + (120 – x) 15= 120 * 35
x = 100
B
Answer: B
Question: The cost of an article is decreased by 15%. If the original cost is $80, find the decrease cost.
Options:
A)33
B)11
C)68
D)36
E)91
Rationale: Original cost = $80
Decrease in it = 15% of $80
= 15/100 × 80
= 1200/100
= $12
Therefore, decrease cost = $80 - $12 = $68
Answer:C
Answer: C
Question: If the average (arithmetic mean) of x + 1, x + 3, and x + 5 is 0, then x =
Options:
A)–4
B)–3
C)–2
D)–1
E)0
Rationale: (x+1 + x+3 + x+5)/3 = 0
=>3x + 9 = 0
=>x = -3
Answer B
Answer: B
Question: Which of the following is a prime number
Options:
A)13
B)14
C)15
D)16
E)18
Rationale: Clearly, 13 is a prime number.
Option A
Answer: A
Question: Find the area of trapezium whose parallel sides are 20 cm and 18 cm long, and the distance between them is 14 cm.
Options:
A)335 cm2
B)885 cm2
C)285 cm2
D)825 cm2
E)266 cm2
Rationale: Area of a trapezium = 1/2 (sum of parallel sides) * (perpendicular distance between them)
= 1/2 (20 + 18) * (14)
= 266 cm2
Answer: E
Answer: E
Question: The current of a stream at 1 kmph. A motor boat goes 35 km upstream and back to the starting point in 12 hours. The speed of the motor boat in still water is?
Options:
A)6
B)7
C)8
D)9
E)2
Rationale: S = 1
M = x
DS = x + 1
US = x - 1
35/(x + 1) + 35/(x - 1) = 12
x = 6
Answer:A
Answer: A
Question: The price of lunch for 15 people was $207.00, including a 15 percent gratuity for service. What was the average price per person, EXCLUDING the gratuity?
Options:
A)$11.73
B)$12.00
C)$13.80
D)$14.00
E)$15.87
Rationale: If the amount spent excluding the gratuity was x, then x(1.15) = 207
=> x = 207/1.15 = 180
Then the average price per person = 180/15 = 12
Option (B)
Answer: B
Question: Divide Rs. 2379 into 3 parts so that their amounts after 2, 3 and 4 years respectively may be equal, the rate of interest being 5% per annum at simple interest. The first part is?
Options:
A)239
B)77
C)998
D)828
E)972
Rationale: Let the parts be x, y and [2379 - (x + y)]
x + (x * 2 * 5/100) = y + (y * 3 * 5/100) = z + (z * 4 * 5/100)
11x/10 = 23y/20 = 6z/5 = k
x = 10k/11, y = 20k/23, z = 5k/6
But x + y + z = 2379
10k/11 + 20k/23 + 5k/6 = 2379
k = (2379 * 11 * 23 * 6)/3965 = (3 * 11 * 23 * 6)/5
x = [10/11 * (3 * 11 * 23 * 6)/5] = 828
Hence, the first part is Rs. 828.
Answer: D
Answer: D
Question: A man has Rs. 512 in the denominations of one-rupee notes, five-rupee notes and ten rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has?
Options:
A)45
B)60
C)75
D)90
E)96
Rationale: Let number of notes of each denomination be x.
Then x + 5x + 10x = 512
16x = 512
x = 32.
Hence, total number of notes = 3x = 96
Answer: Option E
Answer: E
Question: A and B’s salaries together amount to Rs. 2,000. A spends 95% of his salary and B spends 85% of his. If now their savings are the same, what is A’s salary?
Options:
A)1888
B)2676
C)1297
D)1500
E)1678
Rationale: (5/100) A = (15/100) B
A = 3B
A + B = 2000
4B = 2000 => B = 500
A = 1500
Answer: D
Answer: D
Question: If (x^2 + x - 8)/2 ≤ x + 1, then x could be represented by which of the following?
Options:
A)− 4 ≤ x ≤ − 3
B)− 4 ≤ x ≤ 3
C)− 3 ≤ x ≤ 4
D)− 3 ≤ x ≤ 3
E)3 ≤ x ≤ 4
Rationale: IMO C is correct answer
solving through eqautions
x^2 +x-8<= 2x+2
(x+3)(x-4)<=0
Answer: C
Question: Average of five numbers is 12, and the sum of three of the numbers is 39, what is the average of the other 2 numbers?
Options:
A)9.5
B)8.5
C)7.5
D)11.5
E)10.5
Rationale: Let the five numbers be a, b, c, d, e. Then their average is (a+b+c+d+e)/5=12a+b+c=39(39+d+e)/5=1239+d+e=60d+e=21average=21/2=10.5Ans E
Answer: E
Question: A cube with its sides numbered 1 through 6 is rolled twice, first landing on a and then landing on b. If any roll of the cube yields an equal chance of landing on any of the numbers 1 through 6, what is the probability E that a + b is prime?
Options:
A) 0
B) 1/12
C) 5/12
D) 7/18
E) 4/9
Rationale: Total # of outcomes is 6*6=36;
Favorable outcomes:
a-b --> prime
1-1 --> 2;
1-2 --> 3;
2-1 --> 3;
1-4 --> 5;
4-1 --> 5;
2-3 --> 5;
3-2 --> 5;
1-6 --> 7;
6-1 --> 7;
2-5 --> 7;
5-2 --> 7;
3-4 --> 7;
4-3 --> 7;
6-5 --> 11;
5-6 --> 11.
Total of 15 favorable outcomes
E=15/36.
Answer: C.
Answer: C
Question: During a special promotion, a certain filling station is offering a 10 percent discount on gas purchased after the first 10 gallons. If Kim purchased 20 gallons of gas, and Isabella purchased 25 gallons of gas, then Isabella‟s total per-gallon discount is what percent of Kim‟s total per-gallon discount?
Options:
A)80%
B)100%
C)116.7%
D)120%
E)140%
Rationale: Kim purchased 20 gallons of gas. She paid for 10 + 0.9*10 = 19 gallons, so the overall discount she got was 1/20 = 5%.
Isabella purchased 25 gallons of gas. She paid for 10 + 0.9*15 = 23.5 gallons, so the overall discount she got was 1.5/25 = 6%.
6 is 6/5*100 = 120% of 5.
Answer: D.
Answer: D
Question: In a queue if 30 children were made to stand in a column, 16 columns could be formed. If 24 children were made to stand in a column, how many columns could be formed?
Options:
A)15
B)20
C)22
D)26
E)29
Rationale: Sol. Required number = 16 *^30 = 20
B
Answer: B
Question: A boat having a length 3 m and breadth 2 m is floating on a lake. The boat sinks by 1 cm when a man gets into it. The mass of the man is :
Options:
A)50 kg
B)60 kg
C)70 kg
D)80 kg
E)None of these
Rationale: Explanation:
In this type of question, first we will calculate the volume of water displaces then will multiply with the density of water.
Volume of water displaced = 3*2*0.01 = 0.06 m cube
Mass of Man = Volume of water displaced * Density of water
= 0.06 * 1000 = 60 kg
Option B
Answer: B
Question: X and Y run a 300m race,where X beats Y by 30m. To do a favor to Y, X starts 30m behind the starting line in a second 100m race. Both run at the same previous speed. Which of the following is true?
Options:
A)X Beats Y by 2m
B)X Beats Y by 0.5 m
C)X Beats Y by 4 m
D)Y Beats X by 10m
E)X Beats Y by 3 m
Rationale: Let's suppose that the speed of X is 30m/s and that the speed of Y is 27m/s.
So, in the first race, the results are the following:
X crosses the finish line in 10s. In other words, X has run 300m in 10 s.
In 10s, Y has run 270 meters.
Therefore, there is the difference of 30 meters mentioned in the question.
Now, let's review the second race.
In 11 seconds, X can complete the 300 meters race. We have to remember that X is 30 meters behind the starting line.
But in 11 seconds, Y has covered (270+27) =297 meters. Also, it is important to notice that in 11 seconds Y cannot arrive to the finish line.
So, 300 - 297 = 3 meter
Answer: E
Answer: E
Question: A boat goes 100 km downstream in 10 hours, and 60 km upstream in 15 hours. The speed of the stream is?
Options:
A)3km/h
B)4km/h
C)6km/h
D)(1/2) km/h
E)E)None
Rationale: 100 --- 10 DS = 10
? ---- 1
60 ---- 15 US = 4
? ----- 1 S = (10 - 4)/2
= 3 kmph
ANSWER:A
Answer: A
Question: In a urban village of india named "owlna" , 70% people have refrigerator , 75% people have television , 80% people got computers and 80% got Air-conditionor. how many people(minimum) got all these luxury.
Options:
A)23%
B)17%
C)11%
D)10%
E)15%
Rationale: D
10%
100 - [ (100-85)+(100-80)+(100-75) +(100-70)]
=100-(15+20+25+30)
=100-90
Answer: D