divelab/Sys2Bench huggingface dataset:
Question: Find the area of a parallelogram with base 24 cm and height 16 cm?
Options:
A)198 cm2
B)384 cm2
C)279 cm2
D)128 cm2
E)297 cm2
Rationale: Area of a parallelogram
= base * height
= 24 * 16 = 384 cm2
Answer:B
Answer: B
Question: There are six cards in which it has two king cards. all cards are turned down and two cards are opened what is the possibility to get at least one king.
Options:
A)1/5
B)2/5
C)3/5
D)4/5
E)6/5
Rationale: POSSIBILITY TO GET AT LEAST ONE KING IS : 2C1*4C1/6C2 + 2C2/6C2 = 8/15+1/15=3/5
ANSWER:C
Answer: C
Question: In a camp,there is a meal for 120 men or 200 children.If 120 children have taken the meal,how many men will be catered to with the remaining meal ?
Options:
A)20
B)30
C)40
D)48
E)60
Rationale: Solution
There is a metal for 200 children. 120 children have taken the meal.
Remaining meal is to be catered to 80 children.
Now, 200 children = 120 men
80 children =( 120/200x80)men= 48 men. Answer D
Answer: D
Question: For an international Mathematics Olympiad, country D will send six delegates in total — two will be supervisors and four will be contestants. There are 210 ways in which the six delegates can be chosen and there are seven candidates competing for the four contestants’ places available. How many candidates are competing for the two supervisors’ slots available?
Options:
A)1
B)2
C)3
D)4
E)5
Rationale: Option A wrong as 2 supervisor need to be selected.
Going by statement: 4 contestant chosen from 7 -- 7C4 == 35
and total ways =210
Consider 2 supervisor will be chosen from : X people.
So as per question: 35*X= 210
X= 6
So by using options,
Option A already decided wrong.
Option B 2C2 will be 1 not 6.
Option C 3C2 will be 3 not 6
Option D 4C2 will be 6 correct answer
Option E 5C2 will be 10 not 6.
ANS:D
Answer: D
Question: What is the length of the longest pole which can be kept in a room 12 m long, 4 m broad and 3 m high?
Options:
A)87
B)16
C)18
D)13
E)19
Rationale: d2 = 122 + 42 + 32
= 13
Answer:D
Answer: D
Question: A train 100 m long pass a telegraph pole in 5 seconds. Find the speed of the train
Options:
A)66 km/hr
B)68.4 km/hr
C)72 km/hr
D)79.2 km/hr
E)None
Rationale: Sol.
Speed = [100/5] m/sec = [20 * 18/5] km/hr = 72 km/hr.
Answer C
Answer: C
Question: An article is bought for Rs.675 and sold for Rs.900, find the gain percent?
Options:
A)33 8/3%
B)33 1/7%
C)33 1/3%
D)33 7/3%
E)33 1/8%
Rationale: 675 ---- 225
100 ---- ? => 33 1/3%
Answer:C
Answer: C
Question: A person's present age is two-fifth of the age of his mother. After
8 years, he will be one-half of the age of his mother. What is the present age of the mother?
Options:
A)40
B)60
C)70
D)30
E)35
Rationale: Let present age = x
age of mother = 5x/2
after 8 yrs the person will be one-half of the age of his mother
(x+8) = 1/2(5x/2 + 8)
x =16
present age of mother=
5x/2 = 5*16/2 = 40
ANSWER A
Answer: A
Question: Bill has a collection of new and used trading cards that he stores in two albums. His first album contains 200 cards, 60% of which are used. If 90% of the cards in his second album are used, and 65% of all of his cards are used, what is the total number of trading cards in Billâ€™s collection?
Options:
A)290
B)260
C)240
D)156
E)254
Rationale: (60/100)*200 + (90/100)*B = (65/100)*(200+B)
B = 40
Total cards = 200+B = 240
Answer: C
Answer: C
Question: A phone manufacturer has 4 different types of phones namely: x1, x2, x3, and x4. if x2 costs 12% less than x1 and x3 costs 15% lesser than x2, and x4 costs 5% less than x3. what percent of x1's cost is x4?
Options:
A)89.1%
B)77.8%
C)60.7%
D)80.4%
E)71.06%
Rationale: Let the cost of x1 be $100
x2 costs 12% less than x1=$100-$12--88(cost of x2)
x3 costs 15% lesser than x2--$88-13.2--74.8(cost of x3)
x4 costs 5% less than x3--74.8-3.74--71.06(cost of x4)
therefore --71.06*100/100
Answer is E
Answer: E
Question: If two 2-digit positive integers have their respective tens digits exchanged, the difference between the pair of integers changes by 4. What is the greatest possible difference between the original pair of integers?
Options:
A)76
B)80
C)82
D)90
E)94
Rationale: For maximizing most of 2 digit integer questions, you will have numbers closes to 90s and 10s.
Start with 10 and 99 you see that the differences are 89 (=99-10) and 71 (=90-19) giving you a change of 89-71=18, a lot more than 4.
Next check with 15 and 99, you get 84 (=99-15) and 76 (=95-19), you get 84-76=8. Thus the difference has been decreasing.
Finally check with 99 and 17, you get 82 (=99-17) and 78 (=97-19), giving you 82-78 = 4 . This is the answer.
Thus, the maximum difference is 99-17=82. C is the correct answer.
Answer: C
Question: find cp when sp =Rs 40.60 : gain=16%
Options:
A)Rs 55
B)Rs 36
C)Rs 47
D)Rs 30
E)Rs 35
Rationale: cp=Rs{(100/116)*40.60}=Rs 35
Answer is E.
Answer: E
Question: An error 2% in excess is made while measuring the side of a square. What is the percentage of error in the calculated area of the square?
Options:
A)3.07
B)2.3
C)3.2
D)4.04
E)5.92
Rationale: D
4.04
Percentage error in calculated area
=(2+2+(2×2/100))%=4.04
Answer: D
Question: Find the day of the week on 16th july, 1776.
Options:
A)Sunday
B)Monday
C)Tuesday
D)Wednesday
E)Wednesd21
Rationale: Explanation:
Split the year 1775 + 16th july 1776
Till 1600 years no odd days.
1601 to 1700 = 5 odd days
1701 to 1775 = 75 + 18 = 93 = 2 odd days. (75 years has 93 odd days (∵∵ 18 leap + 57 non leap years)
upto 15th july 1776 = 31 + 29 + 31 + 30 + 31 + 30 + 15 = 197 = 1 odd day.
Total odd days = 5 + 2 + 1 = 8 = 1 odd day.
So one day after Monday. That is Tuesday.
Answer: C
Answer: C
Question: A train 125 m long passes a man, running at 12 km/hr in the same direction in which the train is going, in 10 sec. The speed of the train is?
Options:
A)37 km/hr
B)50 km/hr
C)36 km/hr
D)57 km/hr
E)87 km/hr
Rationale: Speed of the train relative to man = 125/10 = 25/2 m/sec.
= 25/2 * 18/5 = 45 km/hr
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 12 = 45 => x = 57 km/hr.
Answer:D
Answer: D
Question: Rs.2600 is divided into two parts such that if one part be put out at 5% simple interest and the other at 6%, the yearly annual income may be Rs.140. How much was lent at 5%?
Options:
A)1600
B)1700
C)1800
D)1900
E)2000
Rationale: (x*5*1)/100 + [(2600 - x)*6*1]/100 = 140
X = 1600
ANSWER:A
Answer: A
Question: The value of (.02)2 + (0.52)2 + (0.035)2/ (0.002)2 + (0.052)2 + (0.0035)2
Options:
A)100
B)1000
C).001
D).0001
E).01
Rationale: (.02)2 + (0.52)2 + (0.035)2 / (0.002)2 + (0.052)2 + (0.0035)2
= a2+b2+c2 / ( a /10) 2+ ( b/10) 2 + ( c/10) 2
where a= .02, b= .52, c= .035
= 100(a2+b2+c2) / a2+b2+c2 = 100
ANSWER:A
Answer: A
Question: There are 2 sections A and B in a class, consisting of 30and 20 students respectively. If the average weight of section A is 40kg and that of section B is 35kg, Find the average of the whole class?
Options:
A)35kg
B)37kg
C)42kg
D)38kg
E)29.78kg
Rationale: Total weight of 36+44 students = 30*40 + 20*35 = 1900
Average weight of the class is = 1900/50 = 38 kg
Answer is D
Answer: D
Question: In Arun's opinion, his weight is greater than 61 kg but leas than 72 kg. His brother does not agree with Arun and he thinks that Arun's weight is greater than 60 kg but less than 70 kg. His mother's view is that his weight cannot be greater than 64 kg. If all of them are correct in their estimation, what is the average of diferent probable weights of Arun ?
Options:
A)86.5 kg
B)62.5 kg
C)46.5 kg
D)26.5 kg
E)16.5 kg
Rationale: Let Arun's weight be X kg.
According to Arun, 61 < X < 72.
According to Arun's brother, 60 < X < 70.
According to Arun's mother, X < 64.
The values satisfying all the above conditions are 62 and 63.
Required average = (62 + 63) / 2 = 62.5 kg
Answer: B
Answer: B
Question: When a merchant imported a certain item, he paid a 9 percent import tax on the portion of the total value of the item in excess of $1,000. If the amount of the import tax that the merchant paid was $67.50, what was the total value of the item?
Options:
A)$1,150
B)$1,450
C)$1,750
D)$2,150
E)$2,450
Rationale: Let x be the value in excess of $1,000.
0.09x = 67.5
x = $750
The total value was $750 + $1,000 = $1,750.
The answer is C.
Answer: C
Question: The present age of a father is 4 years more than three times the age of his son. Three years hence, father's age will be 10 years more than twice the age of the son. Find the present age of the father.
Options:
A)30
B)38
C)29
D)40
E)48
Rationale: if the present age be x years.
father's will be (3x+4)years..
so, (3x+4+3)=2(x+3)+10
or, x=9
so the fathers present age =(3x+3)=(3*9+3)years =30years..
ANSWER : OPTION A
Answer: A
Question: A man can row upstream at 10kmph and downstream at 20kmph. Find man's rate in still water ?
Options:
A)5km/hr
B)15km/hr
C)10km/hr
D)20km/hr
E)7.5km/hr
Rationale: Rate in still water = 1/2 (10+20) = 15km/hr
Answer is B
Answer: B
Question: The difference between a number and its two-fifth is 510. What is 30% of that number?
Options:
A)253
B)255
C)252
D)251
E)254
Rationale: Let the number be x. Then,
x - 2/5 x = 510
x = (510 * 5)/3 = 850
30% of 850 = 255.
Answer:B
Answer: B
Question: By selling an article at Rs.1000, a shopkeeper makes a profit of 25%. At what price should he sell the article so as to make a loss of 25%?
Options:
A)s.600
B)s.480
C)s.500
D)s.450
E)s.550
Rationale: SP = 1000
Profit = 25%
CP = (SP)*[100/(100+P)]
= 1000 * [100/125]
= 800
Loss = 25% = 25% of 800 = Rs.200
SP = CP - Loss = 800 - 200 = Rs.600
ANSWER:A
Answer: A
Question: Out of first 40 natural numbers, one number is selected at random. The probability that it is either an even number or a prime number is -.
Options:
A)1/2
B)16/19
C)4/5
D)31/40
E)3/5
Rationale: n(S) = 40
n(Even no) = 20 = n(E)
n(Prime no) = 12 = n(P)
P(EᴜP) = 20/40 + 12/40 - 1/40 = 31/40
ANSWER:D
Answer: D
Question: If it is 6:27 in the evening on a certain day, what time in the morning was it exactly 2,861,997 minutes earlier? (Assume standard time in one location.)
Options:
A)6:35
B)6:30
C)6:27
D)6:24
E)6:21
Rationale: 6:27 minus 2,861,997 in any way must end with 0.
The only answer choice which ends with 0 is B.
The answer is B.
Answer: B
Question: Jacob is now 12 years younger than Michael. If 3 years from now Michael will be twice as old as Jacob, how old will Jacob be in 4 years?
Options:
A) 3
B) 7
C) 15
D) 21
E) 13
Rationale: Jacob=x years, Mike=x+12 years
3 years from now,
2(x+3)=x+15
2x+6=x+15
x=9
x+4=13 years
Answer E
Answer: E
Question: Eighteen years ago, a father was three times as old as his son. Now the father is only twice as old his son. Then the sum of the present ages of the son and the father is:
Options:
A)108
B)75
C)80
D)110
E)101
Rationale: Let the present ages of the father and son be 2x and x years respectively.
Then, (2x - 18) = 3(x - 18) => x = 36
Required sum = (2x + x) = 108 years.
ANSWER A
Answer: A
Question: In a 50-mile trip, the first 10 miles were completed at 50 mph. If the average speed for the whole trip was 60 mph, what was the average speed in the last 40 miles?
Options:
A)1200/19 mph
B)1100/19 mph
C)1000/17 mph
D)900/17 mph
E)800/17 mph
Rationale: The time to complete the first 10 miles was (10 miles / 50 mph) = (1/5) hours.
The time to complete the whole trip was (50 miles / 60 mph) = (5/6) hours.
The time to complete the last 40 miles was (5/6) - (1/5) = (19/30) hours.
The average speed in the last 40 miles was (40 miles / (19/30) hours) = 1200/19 mph.
The answer is A.
Answer: A
Question: The digital sum of a number is the sum of its digits. For how many of the positive integers 24-140 inclusive is the digital sum a multiple of 7?
Options:
A)7
B)8
C)14
D)15
E)20
Rationale: is there other way than just listing?
25
34
43
52
59
61
68
70
77
86
95
106
115
124
133
15 ways..
D
Answer: D
Question: 0.03 x 0.35=?
Options:
A)3.15e-05
B)0.000315
C)0.105
D)0.0105
E)0.00105
Rationale: 3 x 35 = 105
Sum of decimal places =4
Therefore, 0.03 x 0.35 = 0.0105
Answer is D.
Answer: D
Question: If x is 20 percent greater than 80, then x =
Options:
A)68
B)70.4
C)96
D)105.6
E)108
Rationale: X is 20% greater than 80 means X is 1.2 times 80 (in other words 80 + 20/100 * 80 = 1.2 * 80)
Therefore, X = 1.2 * 80 = 96.00
ANSWER:C
Answer: C
Question: h, b, c, and d are positive integers. If the remainder is 9 when h is divided by b, and the remainder is 5 when c is divided by d, which of the following is NOT a possible value for b + d?
Options:
A) 20
B) 19
C) 18
D) 16
E) 15
Rationale: When h is divided by b remainder is 9 that means b is greater than or equals to 10, similarly d is greater than or equals to 6.
b + d cannot be 15, hence E is the answer.
Answer: E
Question: The average of first 15 natural numbers is?
Options:
A)7
B)8
C)9
D)10
E)11
Rationale: Sum of 15 natural no. = 240/2 = 120
Average = 120/15 = 8
Answer:B
Answer: B
Question: Evaluate: 30 - 12÷3×2 = ?
Options:
A)20
B)22
C)24
D)26
E)28
Rationale: According to order of operations, 12÷3×2 (division and multiplication) is done first from left to right
12÷3×2 = 4 × 2 = 8
Hence
30 - 12÷3×2 = 30 - 8 = 22
correct answer B)22
Answer: B
Question: the sum of 5th and 21th term of A.P. is equal to the sum of 8th , 15th and 13 th term . find the term which is 0
Options:
A)11
B)10
C)12
D)13
E)14
Rationale: t5 + t21 = t8 + t15 + t13
=> a+4d + a+20d = a+7d + a+14d + a+12d
=> a + 9d = 0
=> t10 = 0 i.e. 10th term is zero.
ANSWER: B
Answer: B
Question: A began business with Rs.45000 and was joined afterwards by B with Rs.5400. When did B join if the profits at the end of the year were divided in the ratio of 2:1?
Options:
A)6
B)5
C)7
D)4
E)1
Rationale: 45*12 : 54*x = 2: 1
x = 5
12 -5 = 7
Answer: C
Answer: C
Question: In a sports club with 30 members, 17 play badminton and 19 play tennis and 3 do not play either. How many members play both badminton and tennis?
Options:
A)7
B)8
C)9
D)10
E)11
Rationale: Let x play both badminton and tennis so 17-x play only badminton and 19-x play only tennis. 2 play none and there are total 30 students. hence,
(17-x)+(19-x)+x+3=30
39-2x+x=30
39-x=30
x=9
So 9 members play both badminton and tennis.
C
Answer: C
Question: In an election between two candidates, 75 % of the voters cast their votes, out of which 2% of the
votes were declared invalid. A candidate got 9261 votes which were 75% of the total valid votes. Find the
total number of votes
Options:
A)16800
B)15800
C)16700
D)15700
E)None of these
Rationale: Explanation:
Let the total number of votes enrolled are x.
Number of votes cast = 75% of x
Valid votes = 98% of 75% of x
Now, as 9261 is the 75% of valid casted votes so,
75% of 98% of 75% of x = 9261 [imporant]
=>75×98×75×x100×100×100=9261=>x=16800
Answer: Option A
Answer: A
Question: In a basket 7 apples are available. Jack wants to take 5 apples.In how many ways to choose apples?
Options:
A)21
B)12
C)22
D)30
E)35
Rationale: There are 7C5 possible ways to choose apples
7C5=7!/5!*2!=7*6*5!/5!*2*1
=21 ways
Ans:option A
Answer: A
Question: Two numbers N and 14 have LCM = 56 and GCF = 10. Find N.
Options:
A)24
B)40
C)44
D)54
E)64
Rationale: The product of two integers is equal to the product of their LCM and GCF. Hence.
14 × N = 56 × 10
N = 56 × 10 / 14 = 40
correct answer B
Answer: B
Question: The operationis defined for all integers a and b by the equation ab = (a - 1)(b - 1). If x15 = 98, what is the value of x ?
Options:
A)8
B)7
C)10
D)11
E)12
Rationale: ab = (a - 1)(b - 1)
x15 = (x-1)(15-1) = 98 --> x-1=7 --> x=8
Answer: A.
Answer: A
Question: The price of a certain car this year is $ 42,000, which is 25 percent greater than the cost of the car last year. What was the price of the car last year?
Options:
A)$27,000
B)$28,000
C)$31,500
D)$33,600
E)$34,500
Rationale: 125% of Cost of car last year = $42000
1.25 of Cost of car last year = $42000
i.e. Cost of car last year = $42000/1.25 = $33600
Answer: option D
Answer: D
Question: Find the odd man out
3, 8, 15, 24, 34, 48, 63
Options:
A)15
B)24
C)34
D)48
E)58
Rationale: difference between numbers are 5, 7, 9, 11, 13, 15
3+5=8
8+7=15
15+9=24
24+11=35
35+13=48
48+15=63
ANSWER:C
Answer: C
Question: By selling 12 pencils for a rupee a man loses 20%. How many for a rupee should he sell in order to gain 20%?
Options:
A)8
B)9
C)10
D)89
E)81
Rationale: 80% --- 12
120% --- ?
80/120 * 12 = 8
Answer: A
Answer: A
Question: How long does a train 110 m long running at the speed of 72 km/hr takes to cross a bridge 132 m length?
Options:
A)9.8 sec
B)12.1 sec
C)12.42 sec
D)14.3 sec
E)9.2 sec
Rationale: Speed = 72 * 5/18 = 20 m/sec
Total distance covered = 110 + 132 = 242 m.
Required time = 242/20 = 12.1 sec.
ANSWER:B
Answer: B
Question: When x divided by 288, the remainder is 47. Find the remainder when the same x is divided by 24?
Options:
A)20
B)21
C)23
D)26
E)29
Rationale: 23
Option C
Answer: C
Question: What is the last digit in(7^95 - 3^58)?
Options:
A)5
B)6
C)4
D)9
E)5.5
Rationale: Explanation:
Unit digit in 795 = Unit digit in [(74)23 x 73]
= Unit digit in [(Unit digit in(2401))23 x (343)]
= Unit digit in (123 x 343)
= Unit digit in (343)
= 3
Unit digit in 358 = Unit digit in [(34)14 x 32]
= Unit digit in [Unit digit in (81)14 x 32]
= Unit digit in [(1)14 x 32]
= Unit digit in (1 x 9)
= Unit digit in (9)
= 9
Unit digit in (795 - 358) = Unit digit in (343 - 9) = Unit digit in (334) = 4.
So, Answer C
Answer: C
Question: The sector of a circle has radius of 21 cm and central angle 130o. Find its perimeter?
Options:
A)91.5 cm
B)89.6 cm
C)91.8 cm
D)92.5 cm
E)99.5 cm
Rationale: Perimeter of the sector = length of the arc + 2(radius)
= (130/360 * 2 * 22/7 * 21) + 2(21)
= 47.6 + 42
= 89.6 cm
Answer:B
Answer: B
Question: In a camp, there is a meal for 110 men or 180 children. If 145 children have taken the meal, how many men will be catered to with remaining meal?
Options:
A)20
B)30
C)50
D)21
E)40
Rationale: There is a meal for 180 children. 145 children have taken the meal.
Remaining meal is to be catered to 35 children.
Now, 180 children 110 men.
35 children (110/180)	* 35 = 21 men
Answer is D.
Answer: D
Question: Find the odd man out. 23, 27, 36, 52, 77, 111, 162
Options:
A)162
B)111
C)52
D)27
E)23
Rationale: Explanation :
23 + 22 = 27
27 + 32 = 36
36 + 42 = 52
52 + 52 = 77
77 + 62 = 113
113 + 72 = 162
Hence, 113 should have come in place of 111
Answer : Option B
Answer: B
Question: A watch was sold at a loss of 10%. If it was sold for Rs.225 more, there would have been a gain of 5%. What is the cost price?
Options:
A)1000
B)1500
C)2778
D)2788
E)2991
Rationale: 90%
105%
--------
15% ---- 225
100% ---- ? => Rs.1500
Answer:B
Answer: B
Question: A train 100 m long crosses a platform 125 m long in 2 sec; find the speed of the train?
Options:
A)36
B)405
C)200
D)302
E)404
Rationale: D = 100 + 125 = 225
T = 2
S = 225/2 * 18/5 = 405 kmph
Answer: B
Answer: B
Question: If x is an integer, then x(x - 1)(x - m) must be evenly divisible by three when m is any of the following values EXCEPT
Options:
A)-4
B)-2
C)-1
D)2
E)5
Rationale: here's another approach
x(x - 1)(x - m)
all three are consecutive, so the product MUST be a multiple of 3
we don't know the value of k just yet ... so let's extend the series ... the extension itself reveals the answers
..(x-5)..(x-2)(x-1)x(x+1)..(x+4)..
we can see the possible values of m too from the series
m = 2 OR 2+3n [25]
m= -1 OR -1+3n [-1-4]
B i.e. -2 does not fit in any value of m
so B it is
Answer: B
Question: A train 400 m long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 min, then the length of the tunnel is?
Options:
A)298 m
B)500 m
C)900 m
D)967 m
E)1181 m
Rationale: Speed = 78 * 5/18 = 65/3 m/sec.
Time = 1 min = 60 sec.
Let the length of the train be x meters.
Then, (400 + x)/60 = 65/3
x = 900 m.
Answer: C
Answer: C
Question: sale of Rs 6835, Rs. 9927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs, 7000 ?
Options:
A)4966
B)2477
C)2877
D)7991
E)8881
Rationale: Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009.
Required sale = Rs.[(6500 x 6) - 34009]
= Rs. (42000 - 34009)
= Rs. 7991
Answer: D
Answer: D
Question: What is 990*990?
Options:
A) 974,169
B) 974,219
C) 974,549
D) 980,100
E) 985,369
Rationale: if you take a base of 1000 then 990 is 10 less than 1000
to get the product of 990 x 990 write like this
990- 10( as 10 less than base1000)
990- 10
now 10 x 10 = 100
and 990-10 = 980
so 990 x 990 = 980100 ... (bingo the answer is D . you can even have a shortcut ...... 10 x 10 = 100... only answer choice has last three digits as 100.. so no need to calculate 990-10 . after you get 10 x 10 you can straight way pick answer choice D.
Answer: D
Question: An ore contains 25% of an alloy that has 90% iron. Other than this, in the remaining 75% of the ore, there is no iron. How many kilograms of the ore are needed to obtain 60 kg of pure iron?
Options:
A)250 kg
B)275 kg
C)300 kg
D)266.66 kg
E)None
Rationale: Solution: Let there is 100 kg of ore.
25% ore contains 90% off Iron that means 25 kg contains;
25*90/100 = 22.5 kg Iron.
22.5 kg Iron contains 100 kg of ore.
Then, 1 kg of iron contains = 25/100 kg ore;
Hence, 60 kg iron contains = 100*60/22.5 = 266.66 kg ore.
Answer: Option D
Answer: D
Question: The probability of rain showers in Barcelona on any given day is 0.2. What is the probability that it will rain on exactly one out of three straight days in Barcelona?
Options:
A)0.144
B)0.072
C)0.432
D)0.72
E)0.384
Rationale: IMO This is just for first day! It can rain on 2nd day or 3 rd day (and not rain on other days) in 3 consecutive days!
Hence,
0.2*0.8*0.8 + 0.8*0.2*0.8 + 0.8*0.8*0.2 = 0.384
Option - E
Answer: E
Question: A man purchased 3 blankets @ Rs.100 each, 6 blankets @ Rs.150 each and two blankets at a certain rate which is now slipped off from his memory. But he remembers that the average price of the blankets was Rs.150. Find the unknown rate of two blankets?
Options:
A)A)300
B)B)350
C)C)450
D)D)470
E)E)500
Rationale: Explanation:
10 * 150 = 1500
3 * 100 + 6* 150 = 1200
1500 – 1200 =300
A
Answer: A
Question: In how many different number of ways 5 men and 2 women can sit on a shopa which can accommodate persons?
Options:
A)210
B)220
C)240
D)250
E)270
Rationale: 7p3 = 7 × 6 × 5 = 210
A)
Answer: A
Question: What is the compound interest paid on a sum of Rs.700 for the period of 2 years at 10% per annum.
Options:
A)130
B)620
C)147
D)120
E)None of these
Rationale: Solution= Interest % for 1st year= 10
Interest % for 2nd year= 10+ 10% of 10= 10+ 10 *10/100=11
Total % of interest= 10 + 11=21
Total interest = 21 % 700 = 700 * (21/100)= 147
Answer C
Answer: C
Question: Of the 80 electronics components that a factory must manufacture, 60 percent would be most e¢ ciently manufactured by Machine A and the remaining 40 percent would be most efficiently manufactured by Machine B, though either machine could manufacture any of the 80 components. If 60 percent of the components were manufactured by Machine A and the remainder were manufactured by Machine B, what is thehighest possible number of components that were manufactured by the machine that would manufacture them the most efficiently?
Options:
A)80
B) 32
C) 33
D) 35
E) 36
Rationale: A can manufacture 60 % of 80 efficiently, which is 48.
B can manufacure 40 % of 80 efficiently, which is 32.
Now 60 % of 80 are produced by A. This means 48 parts. Since A can produce 48 efficiently, all 48 are produced efficiently. Rest (32) is produced by B, which can produce max. 32 parts efficiently.
Hence parts that were produced efficiently = 32+48 = 80. (A).
Answer: A
Question: Raja purchased a refrigerator for Rs. 12500 after getting a discount of 20% on the labelled price. He spent Rs. 125 on transport and Rs. 250 on installation. At what price should it be sold so that the profit earned would be 10% if no discount was offered?
Options:
A)68980
B)46898
C)56849
D)17600
E)21349
Rationale: D
Price at which the TV set is bought = Rs. 12,500
Discount offered = 20%
Marked Price = 12500 * 100/80 = Rs. 15625
The total amount spent on transport and installation = 125 + 250 = Rs. 375\Total price of TV set = 15625 + 375 = Rs. 16000
The price at which the TV should be sold to get a profit of 10% if no discount was offered = 16000 * 110/100 = Rs. 17600
Answer: D
Question: The edges of a cuboid are respectively 3cm, 4cm and 12 cm. Find the length of the diagonal of cuboid.
Options:
A)9: 8
B)9: 5
C)9: 1
D)9: 2
E)9: 4
Rationale: a1 : a2 = 3 : 1
6 a12 : 6 a22 = 9: 1
Answer:C
Answer: C