divelab/Sys2Bench huggingface dataset:
Question: A family of 4 brothers and 3 sisters is to be arranged in a row, for a photograph. In how many ways can they be seated if all the sisters not together ?
Options:
A)4270
B)4820
C)4320
D)4620
E)4520
Rationale: Since the 3 sisters are inseperable, consider them as one single unit. This together with the 4 brothers make 5 persons who can be arranged among themselves in 5! ways. In everone of these permutations, the 3 sisters can be rearranged among themselves in 3!. Hence the total number of arrangement required = 5!x 3! =120x6=720. The number of arrangements of all the 7 persons without any restriction =7!= 5040 Number arrangement required =5040-720 =4320. Answer : C
Answer: C
Question: The avg weight of A,B & C is 55 kg. If D joins the group, the avg weight of the group becomes 60 kg.If another man E who weights is 3 kg more than D Replaces A, Then the avgof B,C,D&E becomes 58 kg. What is the weight of A?
Options:
A)56
B)65
C)75
D)86
E)90
Rationale: A + B + C = 3 *55 = 165
A + B + C + D = 4 * 60 = 240 ---- (i)
So, D = 75& E = 75 + 3 = 78
B + C + D +E = 58 * 4 = 232 --- (ii)
From Eq. (i) & (ii)
A-E = 240 – 232 = 8
A = E +8 = 78 + 8 = 86
Answer : D
Answer: D
Question: When a certain number X is divided by 143, the remainder is 45. Which of the following numbers, if added to X, would result in a number divisible by 16?
Options:
A)7
B)10
C)34
D)47
E)55
Rationale: So the number given is N = 143Q + 45
If this number is divided by 13, the remainder would be R[(143Q + 45)/13]
Since 143 is divisible by 13 , the product 143Q gives no remainder
This means the remainder of 45/13 should be the remainder of the entire number N
which is 6
To make it divisible by 13 , the smallest number that can be added = 16 - 6 = 10
Correct Option : B
Answer: B
Question: A clock shows the time as 9 a.m. If the minute hand gains 5 minutes every hour, how many minutes will the clock gain by 6 p.m.?
Options:
A)45 minutes
B)55 minutes
C)35 minutes
D)25 minutes
E)40 minutes
Rationale: there are 9 hours in between 9 a.m. to 6 p.m.
9*5=45 minutes.
ANSWER:A
Answer: A
Question: A rich aristocrat decided that he would give every man rs.45 and every women Rs.60.Only one nineth of the man and only one twelfth of the women collected their dues .Can u tell me how much money thath aristocrat spent if their were 3552 people in total
Options:
A)17760
B)18540
C)16320
D)14640
E)15640
Rationale: iman=45 and 1women=60 then 1/9 man=1/9*45=5 and 1/12 of women=1/12*60=5
total people 3552 =3552*5=17760
ANSWER:A
Answer: A
Question: Given that A and B are events such that
H(A)= 0.03
H(B)=0.18
H(AnB)=0.18
find H (A|B) and H(A|B)
Options:
A)1/7
B)1/5
C)1/3
D)1/2
E)1/6
Rationale: Here, A and B are events
H(A|B) = H(AnB)/H(B) = 0.18/0.18 = 1
H(A|B) = H(AnB)/H(A) = 0.18/0.03 = 1/6.
Answer is E
Answer: E
Question: 12 buckets of water fill a tank when the capacity of each bucket is 81 litres. How many buckets will be needed to fill the same tank, if the capacity of each bucket is 9 litres?
Options:
A)96
B)110
C)100
D)90
E)108
Rationale: Capacity of the tank = (12 Ã— 81) litre
Number of buckets required of capacity of each bucket is 17 litre = 12 Ã—81/9=12Ã—9=108
Answer is E
Answer: E
Question: If â€˜KARNATAKAâ€™ is coded as â€˜BAIEABABAâ€™, then â€˜BIHARâ€™ is coded as
Options:
A)BARHI
B)BHARI
C)BHIAR
D)BIHAI
E)BIHAR
Rationale: M=13,1+3=4=D
A=1=A
SIMILARLY,
B=2=B
I=9=I
H=8=H
A=1=A
R=18=1+8=9=I
SO ANS IS
BIHAI
ANSWER:D
Answer: D
Question: Of the three numbers, the first is twice as second and three times the third. The average of the three numbers is 33, and the three numbers in order are?
Options:
A)54,27,18
B)98,49,33
C)126,63,36
D)108,54,36
E)None of these
Rationale: Explanation :
Solution: Let A =x,
B =x/2, C = x/3.
=x + x/2 + x/3 / 3 = 33
By solving we will get x = 54.
Hence A= 54
B= 54/2= 27
C= 54/3 = 18
Answer : A
Answer: A
Question: A circular swimming pool is surrounded by a concrete wall 4ft wide. If the area of the concrete wall surrounding the pool is 11/25 that of the pool, then the radius of the pool is?
Options:
A)10ft
B)20ft
C)30ft
D)40ft
E)50ft
Rationale: Explanation:
let the radius of the pool be Rft
radius of the pool including the wall = (R+4)ft
area of the concrete wall = π[(R + 4)2 - R2] = π[(R + 4 + R)(R + 4 - R)] = 8π(R + 2) sq feet
⇒ 8π(R + 2) = 11/25πR2 ⇒ 11 R2 = 200(R + 2)
Radius of the pool R = 20ft Answer: B
Answer: B
Question: A certain musical scale has has 13 notes, each having a different frequency, measured in cycles per second. In the scale, the notes are ordered by increasing frequency, and the highest freq is twice the lowest. For each of the 12 lower freq , the ratio of a frequency to the next higher freq is a fixed constant. If the lowest freq is 440 cycles per second, then the freq of the 7th note in the scale is how many cycles/second?
Options:
A)440 * sqrt 2
B)440 *2
C)400 * sqrt 2
D)320 * sqrt 3
E)None
Rationale: let the constant be k
F1 = 440
F2 = 440k
F3 = 440 k * k = 440 * k^2
F13= 440 * k^12
we know F13 = 2 *F1 = 2 * 440 = 880
880/440 = k^12
k = twelfth root of 2
for F7...
F7 = 440 * k^6 ( as we wrote for F2 and F3)
F7 = 440 * (twelfth root of 2) ^ 6
F7 = 440 * sqrt (2)
Answer A
Answer: A
Question: How many seconds will a 500 m long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
Options:
A)22
B)30
C)88
D)266
E)121
Rationale: Speed of train relative to man = 63 - 3 = 60 km/hr.
= 60 * 5/18 = 50/3 m/sec.
Time taken to pass the man = 500 * 3/50 = 30 sec.
Answer:B:
Answer: B
Question: Peter obtained 76, 65, 82, 67 and 95 marks (out of 100) in English, Mathematics, Physics, Chemistry and Biology. What are his average marks?
Options:
A)A)87
B)B)99
C)C)68
D)D)82
E)E)75
Rationale: Average = (76 + 65 + 82 + 67 + 95)/5
= 385/5
= 77.
Answer:E
Answer: E
Question: Manoj borrowed Rs.3750 from Anwar at 6% p.a. simple interest for three years. He then added some more money to the borrowed sum and lent it to Ramu for the same time at 9% p.a. simple interest. If Manoj gains Rs.824.85 by way of interest on the borrowed sum as well as his own amount from the whole transaction, then what is the sum lent by him to Ramu?
Options:
A)22877
B)5555
C)2778
D)6787
E)1771
Rationale: Let the sum lent by Manoj to Ramu be Rs.P.
Amount gained by Manoj = P. 3.9 /100 = 3750.3.6/100 = Rs.824.85
27P = 67500 = 82485
P = (82485 + 67500)/27 = 3055 + 2500 = Rs.5555
Answer: B
Answer: B
Question: When a certain shoe store reduces the price of its best-selling style of shoe by 10 percent, the weekly sales of this style increase by 20 percent. Which of the following best describes the resulting change in the store's weekly revenue from sales of this style of shoe?
Options:
A)Revenue decreases by 10%
B)Revenue decreases by 1%
C)There is no change in revenue
D)Revenue increases by 1%
E)Revenue increases by 8%
Rationale: Old price = 10, old sales = 10 --> old revenue = 100;
New price = 9, new sales = 12 --> new revenue = 108.
Revenue increased by 8%.
Answer: E
Answer: E
Question: Find avrg speed if a man travels at speed of 16km/hr up and 30km/hr dawn at an altitude of 200m.
Options:
A)22.8
B)21.8
C)20.8
D)28.8
E)29.8
Rationale: avg speed=2*x*y/(x+y)
=2*16*30/(16+30)=20.8
ANSWER:C
Answer: C
Question: Nine coins are tossed simultaneously. In how many of the outcomes will the third coin turn up a head?
Options:
A)2^9
B)2^10
C)2^8
D)3 * 2^9
E)3 * 2^10
Rationale: Fix the third coin as H. The remaining 8 coins have 2^8 outcomes.
Ans:C
Answer: C
Question: If 8 men or 12 women can do a piece of work in 40 days, in how many days can the same work be done by 6 men and 11 women?
Options:
A)10 days
B)11 days
C)13 days
D)15 days
E)24 days
Rationale: 8men = 12women (i.e 2men = 3women)
12women 1 day work= 1/40
soln:
6men(9women)+ 11women=20women=?
1 women 1 day work =12*40= 1/480
so, 20 women work= 20/480=1/24
ans: 24 days
ANSWER:E
Answer: E
Question: The vertex of a rectangle are (1, 0), (9, 0), (1, 4) and (9, 4) respectively. If line L passes through the origin and divided the rectangle into two identical quadrilaterals, what is the slope of line L?
Options:
A)4
B)2
C)1/4
D)2/5
E)5/6
Rationale: If line L divides the rectangle into two identical quadrilaterals, then it must pass through the center (5, 2). The slope of a line passing through (0,0) and (5, 2) is 2/5.
The answer is D.
Answer: D
Question: A man sells a horse for Rs.920 and loses something, if he had sold it for Rs.980, his gain would have been double the former loss. Find the cost price of the horse?
Options:
A)287
B)279
C)267
D)860
E)940
Rationale: CP = SP + 1CP = SP - g
920 + x = 980 - 2x
3x = 60 => x
=20
CP = 920 + 20
= 940
Answer:E
Answer: E
Question: Find 103 ×× 10
Options:
A)106/19
B)108/12
C)108/19
D)108/15
E)108/11
Rationale: By taking 100 as a base we can easily get the answer for the above question within seconds.
103 is 3 more than 100 and 105 is 5 more than 100 So we will write
Add the excess of the second number to first number or excess of first number to second number as show below to get left most digits and multiply the excesses to get the right most two digits.
Note: Always remember if you get a single digit number put zero in the left two make it a two digit number to get the right most two digits.
Answer:D
Answer: D
Question: Find the area of trapezium whose parallel sides are 20 cm and 18 cm long, and the distance between them is 12 cm.
Options:
A)335 cm2
B)228 cm2
C)285 cm2
D)825 cm2
E)725 cm2
Rationale: Area of a trapezium = 1/2 (sum of parallel sides) * (perpendicular distance between them)
= 1/2 (20 + 18) * (12)
= 228 cm2
Answer: B
Answer: B
Question: A, B and C are partners in a business. Their capitals are respectively, Rs.5000, Rs.6000 and Rs.4000. A gets 30% of the total profit for managing the business. The remaining profit is divided among three in the ratio of their capitals. In the end of the year, the profit of A is Rs.200 more than the sum of the profits of B and C. Find the total profit?
Options:
A)2679
B)2976
C)2690
D)3000
E)2698
Rationale: A:B:C = 5:6:4
Let the total profit = 100 - 30 = 70
5/15 * 70 = 70/3
A share = 70/3 + 30 = 160/3
B + C share = 100 - 160/3 = 140/3
A-(B+C) = 160/3 - 140/3 = 20/3
20/3 ---- 200
100 ---- ? => 3000
Answer:D
Answer: D
Question: A company recently conducted a survey and found that 40,000 of its customers live in rural areas. If the number of customers who live in urban areas is 137 percent greater than the number of customers who live in rural areas, how many customers live in urban areas?
Options:
A)90,000
B)91,200
C)92,400
D)93,600
E)94,800
Rationale: The number of customers in urban areas is 40,000+1.37*40,000=94,800.
The answer is E.
Answer: E
Question: A dishonest dealer professes to sell goods at the cost price but uses a weight of 880 grams per kg, what is his percent?
Options:
A)15%
B)13.6%
C)65%
D)45%
E)35%
Rationale: Explanation:
880 --- 120
100 --- ? => 13.6%
Answer: B
Answer: B
Question: There are 5 marbles in a bag - 2 are orange and 3 are blue. If two marbles are pulled from the bag, what is the probability T that at least one will be orange?
Options:
A)T=7/10
B)T=3/5
C)T=2/5
D)3/10
E)1/10
Rationale: Method 1
Probability that at least one out of two marbles will be orange = 1 - Probability that both marbles are blue = 1- P(First marble is blue)* P(Second Marble is Blue) = 1- (3/5)(2/4) = 7/10
Method 2
Probability that at least one marble will be orange = P( First Marble is Orange)*P(Second Marble is Blue) + P (First Marble is Blue)*P(Second Marble is Orange) + P(First Marble is Orange) *P(Second Marble is Orange) = (2/5)*(3/4)*2 + (2/5)*(1/4) = 7/10
Method 3
Probabilty that at least one marble will be orange = 1 - Probability that both marbles are blue
= 1 - (Number of ways 2 blue marbles out of 3 can be pulled)/(Number of ways 2 marbles out of 5 can be pulled)
= 1 - 3C2/5C2
= 1-(3/10) = 7/10
Answer :A
Answer: A
Question: Judy ate 20g of chocolate on Monday, and 30g of chocolate on Tuesday. How much chocolate on average did she eat on those two days?
Options:
A)50g
B)6g
C)600g
D)25g
E)1kg
Rationale: (20g + 30g)/2 = 25g
The correct answer is D
Answer: D
Question: Sakshi can do a piece of work in 20 days. Tanya is 25% more efficient than Sakshi. The number of days taken by Tanya to do the same piece of work is?
Options:
A)65 days
B)16 days
C)15 days
D)19 days
E)20 days
Rationale: Ratio of times taken by Sakshi and Tanys = 125:100 = 5:4
Suppose Tanya takes x days to do the work.
5:4 :: 20:x => x= 16 days.
Hence, Tanya takes 16 days to complete the work.
Answer: B
Answer: B
Question: The incomes of two persons A and B are in the ratio 3:4. If each saves Rs.100 per month, the ratio of their expenditures is 1:4 . Find their incomes?
Options:
A)112.5, 158.5
B)180.5, 150
C)100, 200
D)112.5, 150
E)122.5, 150
Rationale: The incomes of A and B be 3P and 4P.
Expenditures = Income - Savings
(3P - 100) and (4P - 100)
The ratio of their expenditure = 1:4
(3P - 100):(4P - 100) = 1:4
8P = 300 => P = 37.5
Their incomes = 112.5, 150
ANSWER:D
Answer: D
Question: If Jake loses 15 pounds, he will weigh twice as much as his sister. Together they now weigh 132 pounds. What is Jake’s present weight, in pounds?
Options:
A)63
B)93
C)139
D)147
E)188
Rationale: Lets say J is the weight of Jack and S is the wt of his sister.
If he loses 15 pounds, he s twice as heavy as his sister.
J-15=2*S
Also, together they weight 132 pounds
J+S=132
solvong the 2 equation ,we get J=93 pounds !
B
Answer: B
Question: The average of the two-digit numbers, which remain the same when the digits interchange their positions, is?
Options:
A)22
B)89
C)55
D)38
E)13
Rationale: Average = (11 + 22 + 33 + 44 + 55 + 66 + 77 + 88 + 99)/9
= [(11 + 99) + (22 + 88) + (33 + 77) + (44 + 66) + 55]/9
= [(4 * 110) + 55]/9 = 495/9
= 55.
Answer:C
Answer: C
Question: Salaries of Ram and Sham are in the ratio of 4 : 5. If the salary of each is increased by Rs. 5000, then the new ratio becomes 50 : 60. What is Sham's present salary?
Options:
A)Rs. 20,000
B)Rs. 25,000
C)Rs. 30,000
D)Rs. 35,000
E)Rs. 40,000
Rationale: EXPLANATION:
Assume original salaries of Ram and Sham as 4x and 5x respectively.
Therefore,
(4x + 5000)/(5x +5000)	=	50 /60
60 (4x + 5000) = 50 (5x + 5000)
10 x = 50,000
5x = 25, 000
Sham's present salary = 5x + 5000 = 25,000 + 5000
Sham's present salary = Rs. 30,000
ANSWER IS C
Answer: C
Question: If a 10 percent deposit that has been paid toward the purchase of a certain product is $140, how much more remains to be paid?
Options:
A)$880
B)$990
C)$1,000
D)$1,100
E)$1,260
Rationale: 10/100P = 140 >> p= 140*100/10 = 1400
1400 - 140 = 1260
ANSWER:E
Answer: E
Question: How many different positive integers exist between 10^5 and 10^6, the sum of whose digits is equal to 2?
Options:
A)6
B)7
C)5
D)8
E)18
Rationale: So, the numbers should be from 100,000 to 1,000,000
The following two cases are possible for the sum of the digits to be 2:
1. Two 1's and the rest are 0's:
100,001
100,010
100,100
101,000
110,000
5numbers.
2. One 2 and the rest are 0's:
200,000
1 number.
Total = 6 numbers.
Answer: A
Answer: A
Question: A train passes a station platform in 45 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Options:
A)180 m
B)240 m
C)260 m
D)280 m
E)375 m
Rationale: Speed = 54 x 5/18 = 15 m/s
Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
Then, (x + 300)/45 = 15
--> x + 300 = 675
x = 375m.
Answer : E.
Answer: E
Question: A present value of a machine is $128000. Its value depletiation rate is 25% per annum then find the machine value after 3 years?
Options:
A)$54000
B)$48000
C)$36520
D)$32450
E)$42500
Rationale: P= $128000
R = 25%
T = 3 years
Machine value after 3years = P/(1-R/100)^T
=128000*3/4 * 3/4 * 3/4
=$54000
Answer is A
Answer: A
Question: In a race of 1000 m, A can beat by 100 m, in a race of 800m, B can beat C by 100m. By how many meters will A beat C in a race of 600 m?
Options:
A)187.5 m
B)127.5 m
C)127.3 m
D)122.5 m
E)197.3 m
Rationale: When A runs 1000 m, B runs 900 m and when B runs 800 m, C runs 700 m.
When B runs 900 m, distance that C runs = (900 * 700)/800 = 6300/8
= 787.5 m.
In a race of 1000 m, A beats C by (1000 - 787.5) = 212.5 m to C.
In a race of 600 m, the number of meters by which A beats C
= (600 * 212.5)/1000
= 127.5 m.
Answer:B
Answer: B
Question: A parking space have 10 different slots. 10 cars has to arrange in 8 slots. But there are exactly 4 cars between 6 specified cars. In how many ways cars can be arranged?
Options:
A)17280
B)65000
C)1500
D)1640
E)1440
Rationale: we arranged 2 specified cars in 4 slots = 4!
remaining 6 cars in 6 slots = 6!
number of ways = 4!*6! = 17280
correct option is A
Answer: A
Question: There are 10 women and 15 men in an office. In how many ways a team of a man and a woman can be selected?
Options:
A)55
B)25
C)150
D)28
E)None of these
Rationale: Number of ways in which a team of a man and a woman can be selected
= 15 × 10 = 150
Answer is C
Answer: C
Question: In what time will a railway train 60 m long moving at the rate of 72 kmph pass a telegraph post on its way?
Options:
A)8 sec
B)3 sec
C)2 sec
D)6 sec
E)9 sec
Rationale: T = 60/72 * 18/5
= 3 sec
Answer:B
Answer: B
Question: A retailer bought a machine at a wholesale price of $90 and later on sold it after a 10% discount of the retail price. If the retailer made a profit equivalent to 20% of the whole price, what is the retail price of the machine?
Options:
A)81
B)100
C)120
D)135
E)160
Rationale: My solution: Wholesale Price= 90
Retail Price, be = x
He provides 10 % discount on Retail price= x-10 x/100
This Retail price = 20 % profit on Wholesale price
x-10 x/100 = 90+ 1/5(90)
x=120;
ANSWER:C
Answer: C
Question: Last year Manfred received 26 paychecks. Each of his first 6 paychecks was $750; each of his remaining paychecks was $50 more than each of his first 6 paychecks. To the nearest dollar, what was the average (arithmetic mean) amount of his pay checks for the year?
Options:
A) $752
B) $755
C) $765
D) $788
E) $775
Rationale: = (750*6+ 800 *20)/26
= 788
Answer is D.
Posted from my mobile device
Answer: D
Question: In the reading room of a library, there are 24 reading spots. Each reading spot consists of a round table with 9 chairs placed around it. There are some readers such that in each occupied reading spot there are different numbers of readers. If in all there are 36 readers, how many reading spots do not have even a single reader?
Options:
A)8
B)16
C)15
D)14
E)9
Rationale: 1+2+3+4+5+6+7+8 = 36
so, 8 spots are occupied by users
24-8 = 16,
ANSWER:B
Answer: B
Question: A rope of which a calf is tied is increased from 12 m to 23 m, how much additional grassy ground shall it graze?
Options:
A)2989
B)2789
C)1210
D)1288
E)1211
Rationale: π (232 – 122)
= 1210
Answer: C
Answer: C
Question: What could be the range of a set consisting of odd multiples of 5?
Options:
A)21
B)24
C)35
D)62
E)60
Rationale: Range = the difference between the greatest and the smallest numbers in the sequence. Our sequence is odd and is a multiple of 7. Every number in that sequence can be represented like this: 5*(2n+1) where n is any positive integer.
Range = 5*(2m + 1) - 5*(2n + 1) = 5*2*(m-n) = 10 * (m-n).
m, n - any positive integers
The answer must be divisible by 10, which is only 60.
The correct answer is E.
Answer: E
Question: Mr. Wayne bungee jumps from the top of a building straight to the ground at a constant speed. 3 seconds after he starts plummeting he passes the 20th floor. 15 seconds after he starts plummeting he passes the 5th floor. Each floor is 3.4 meters high. What is Mr. Wayne's speed in meters per second?
Options:
A)3
B)3.75
C)4
D)4.25
E)5
Rationale: IMO: D
15 Floors * 3.4 Meter/Floor = 51 Meters
Time= 12 sec
Rate * 12 = 51
Rate= 51/12
=4.25
Answer D
Answer: D
Question: If there is exactly one root of the equation ax^2 + x + b, where a and b are positive constants, what is b in terms of a?
Options:
A)1/4a
B)a
C)3a/2
D)a^2/2
E)a^2/4
Rationale: one root for a quadratic equation ax^2+bx+c is possible only when b^2 = 4ac ---1
Here
c= b
b = 1
substituting these values in 1, we have
1^2 = 4ab => b =1/4a
Answer is A.
Answer: A
Question: A shopkeeper sells 400 metres of cloth for Rs. 18000 at a loss of Rs.5 per metre. Find his cost price for one metre of cloth?
Options:
A)35
B)77
C)28
D)50
E)22
Rationale: Explanation:
SP per metre = 18000/400 = Rs. 45 Loss per metre = Rs. 5 CP per metre
= 45 + 5
= Rs. 50
Answer: D
Answer: D
Question: How many of the following numbers are divisible by 132 ? 264, 396, 462, 792, 968, 2178, 5184, 6336
Options:
A)4
B)3
C)6
D)8
E)9
Rationale: Explanation :
Here 3, 4 and 11 are pairwise co-prime numbers. 132 = 3 × 4 × 11 . Also 3,4 and 11 are
factors of 132. Hence
if a number is divisible by 3, 4 and 11, the number will be divisible by their product 132 also.
If a number is not divisible by 3 or 4 or 11, it is not divisible by 132
You must learn Divisibility Rules to say whether a given number is divisible by another number
without actually performing the division.
further.
264 is divisible by 3, 4 and 11 => 264 is divisible by 132
396 is divisible by 3, 4 and 11 => 396 is divisible by 132
462 is divisible by 3 and 11, but not divisible by 4 => 462 is not divisible by 132
792 is divisible by 3, 4 and 11 => 792 is divisible by 132
968 is divisible by 4 and 11, but not divisible by 3 => 968 is not divisible by 132
2178 is divisible by 3 and 11, but not divisible by 4 => 2178 is not divisible by 132
5184 is divisible by 3 and 4, but not divisible by 11 => 5184 is not divisible by 132
6336 is divisible by 3, 4 and 11 => 6336 is divisible by 132
Hence, only 264, 396 ,792 and 6336 are divisible by 132. So the answer is 4. Answer : Option A
Answer: A
Question: A train 110 metres long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train in going?
Options:
A)5 sec
B)7 sec
C)6 sec
D)10 sec
E)none
Rationale: speed of train relative to man=(60+6)km/hr=66 km/ hr.
(66*5/18)m/sec.
(55/3)m/sec.
Time taken to pass the man=(110*3/55)sec=6 sec.
Answer: C
Answer: C
Question: Henry eats X scones in X percent of the time it takes Rachel to eat Y scones. If Rachel eats four scones in ten minutes, then the number of minutes it takes Henry to eat 2 scones must be equal to which of the following?
Options:
A)Y/20
B)200/Y
C)100Y/(15X)
D)XY/250
E)Y/(5X)
Rationale: Rachel eats 4 scones/10 minutes = 2/5 scones per minute
The time for Rachel to eat 1 scone is 5/2 minutes.
The time for Rachel to eat Y scones is 5Y/2 minutes.
The time for Henry to eat X scones is 5YX/200 minutes.
The time for Henry to eat 1 scone is 5Y/200 minutes.
The time for Henry to eat 2 scones is 10Y/200 = Y/20 minutes.
The answer is A.
Answer: A
Question: In what ratio must water be mixed with milk costing Rs.12 per litre in order to get a mixture worth of
Rs.8 per litre?
Options:
A)1 : 3
B)2 : 2
C)1 : 2
D)3 : 1
E)3 : 2
Rationale: Explanation :
By the rule of alligation, we have
Cost Price of 1 litre of water Cost Price of 1 litre of milk
0 12
Mean Price
8
12-8=4 8-0=8
Required Ratio = 4 : 8 = 1 : 2
Answer : Option C
Answer: C
Question: A person took some amount with some interest for 3 years, but increase the interest for 1%, he paid Rs.120/- extra, then how much amount he took?
Options:
A)s.5500/-
B)s.6000/-
C)s.4000/-
D)s.7000/-
E)s.8000/-
Rationale: Explanation:
3 years = Rs.120/-
year = 120/3
Rate of Interest = 1%
100/1% × 120/3 = Rs.4000/-
P = Rs.4000/-
Answer: Option C
Answer: C
Question: If 60 percent of 500 is 50 percent of x, then x=?
Options:
A)600
B)620
C)650
D)700
E)720
Rationale: 0.6 * 500 = 0.5 * x
x = 6/5 * 500 = 600
Answer: A