divelab/Sys2Bench huggingface dataset:
Question: A sum of money place at compound interest doubles itself in 6 years. In how many years will it amount to eight times itself?
Options:
A)15 years
B)11 years
C)12 years
D)18 years
E)19 years
Rationale: 100 ---- 200 ---- 6
400 ---- 6
800 ---- 6
------
18 years
Answer: D
Answer: D
Question: lets say that the average (arithmetic mean) of seven numbers is 12.2
If the sum of four of these numbers is 42.8, what is the average of the other 3 numbers?
Options:
A)(a) 12.4
B)(b) 14.2
C)(c) 16.8
D)(d) 18.6
E)(e) 19.2
Rationale: We're told that the average of 7 numbers is 12.2
(Sum of numbers)/7 = 12.2
Sum of numbers = (12.2)(7) = 85.4
Next, we're told that the sum of 4 (of the 7) numbers is 42.8
From this information, we can calculate the sum of the OTHER 3 numbers:
85.4 - 42.8 = 42.6
The question asks for the AVERAGE of the OTHER 3 numbers....
42.6/3 = 14.2
B
Answer: B
Question: There are 680 students in a school. The ratio of boys and girls in this school is 3:5. Find the total of girls & boys are there in this school?
Options:
A)425
B)345
C)375
D)380
E)400
Rationale: In order to obtain a ratio of boys to girls equal to 3:5, the number of boys has to be written as 3 x and the number of girls as 5 x where x is a common factor to the number of girls and the number of boys. The total number of boys and girls is 680. Hence
3x + 5x = 680
Solve for x
8x = 680
x = 85
Number of boys
3x = 3 × 85 = 255
Number of girls
5x = 5 × 85 = 425
A
Answer: A
Question: A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If three marbles are picked at random, what is the probability that they are all blue?
Options:
A)fraction of 1/455
B)1/451
C)1/457
D)1/459
E)1/452
Rationale: Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles.
Probability that all the three marbles picked at random are blue = 3C3/15C3
= (1 * 3 * 2 * 1)/(15 * 14 * 13)
= 1/455
Answer: A
Answer: A
Question: If each side of a square is increased by 25%, find the percentage change in its area?
Options:
A)52.25%
B)42.55%
C)56.25%
D)36.55%
E)26.55%
Rationale: let each side of the square be a , then area = a x a
New side = 125a / 100 = 5a / 4
New area =(5a x 5a) / (4 x 4) = (25a²/16)
increased area== (25a²/16) - a²
Increase %= [(9a²/16 ) x (1/a² ) x 100]% = 56.25%
ANSWER : C
Answer: C
Question: A sun is divided among X, Y and Z in such a way that for each rupee X gets, Y gets 45 paisa and Z gets 50 paisa. If the share of Y is RS. 27, what is the total amount?
Options:
A)115
B)116
C)117
D)118
E)119
Rationale: x:y:z = 100:45:50
20:9:10
9 --- 27
39 --- ? => 117
ANSWER:C
Answer: C
Question: Two trains of length 100 meters and 200 meters are 660 meters apart. They are moving towards each other on parallel tracks, at speeds of 90 km/h and 108 km/h. After how many seconds will the trains meet?
Options:
A)12
B)14
C)16
D)18
E)20
Rationale: The speeds are 90000/3600 = 25 m/s and 108000/3600 = 30 m/s
The relative speed is 55 m/s.
time = 660 / 55 = 12 seconds
The answer is A.
Answer: A
Question: In a mixture 60 litres, the ratio of milk and water 2 : 1. If this ratio is to be 1 : 2, then the quanity of water to be further added is:
Options:
A)20 litres
B)30 litres
C)40 litres
D)60 litres
E)none
Rationale: Quantity of milk = (60 * 2/3)litres = 40 litres.
Quantity of water in it = (60- 40) litres = 20 litres.
New ratio = 1 : 2
Let quantity of water to be added further be x litres.
Then, milk : water = (40 / (20+x))
Now, (40 / (20+x)) = 1/2
20 + x = 80
x = 60.
Quantity of water to be added = 60 litres.
Answer = D
Answer: D
Question: How many integers between 324,805 and 458,705 have tens digit 2 and units digit 3?
Options:
A)1,352
B)1,359
C)1,329
D)1,349
E)1,348
Rationale: There is one number in hundred with 2 in the tens digit and 3 in the units digit: 23, 123, 223, 323, ...
The difference between 324,700 and 458,600 is 458,600-324,700=134,900 - one number per each hundred gives 133,900/100=1,349 numbers.
Answer: D.
Answer: D
Question: A certain list consists of 21 different numbers. If n is in the list and n is 3 times the average (arithmetic mean) of the other 20 numbers in the list, then n is what fraction of the sum of the 21 numbers in the list?
Options:
A)1/20
B)1/6
C)1/5
D)4/21
E)3/23
Rationale: series : a1, a2....a20,n
sum of a1+a2+...+a20 = 20*x (x = average)
so, n = 3*x
Hence, a1+a2+..+a20+n = 23x
So, the fraction asked = 3x/23x =3/23
Answer E
Answer: E
Question: Two trains 121 meters and 165 meters in length respectively are running in opposite directions, one at the rate of 80 km and the other at the rate of 65 kmph. In what time will they be completely clear of each other from the moment they meet?
Options:
A)7.16
B)7.16
C)7.12
D)7.15
E)7.11
Rationale: T = (121 + 165)/ (80 + 65) * 18/5
T = 7.15
Answer: D
Answer: D
Question: The H.C.F. of two numbers is 15 and the other two factors of their L.C.M. are 11 and 15. The larger of the two numbers is:
Options:
A)225
B)300
C)299
D)322
E)345
Rationale: the numbers are (15 x 11) and (15 x 15).
Larger number = (15 x 15) = 225.
ANSWER :A
Answer: A
Question: Computer completes the first iteration in 10 seconds and then the following iterations are completed in 7 seconds as constants are already loaded. What is the maximum number of completed iterations under 5 minutes?
Options:
A)41
B)42
C)43
D)44
E)45
Rationale: b must be an integer as it is the number of completed iterations at a rate of 7sec/iteration
10 + 7b =5*60
7b = 290
b= 41
The total number of iterations --> 41+1 = 42 and
43rd iteration will be completed at 304seconds which is above 5 minutes
ANSWER: B
Answer: B
Question: Mr. Karan borrowed a certain amount at 6% per annum simple interest for 9 years. After 9 years, he returned Rs. 8110/-. Find out the amount that he borrowed.
Options:
A)Rs. 5266
B)Rs. 5269
C)Rs. 5228
D)Rs. 5218
E)Rs. 52192
Rationale: Explanation:
Let us assume Mr. Karan borrowed amount is Rs. A. (the principal)
By formula of simple interest, S.I. = PRT / 100
Where P = The principal, R = Rate of interest as a %, T = Time in years
S.I. = (P * 6 * 9)/100 = 54 P/100
Amount = Principal + S.I.
8110 = P + (54P/100)
8110 = (100P + 54P)/100
8110 = 154P/100
P = (8110 * 100)/154 = Rs. 5266.233
ANSWER: A
Answer: A
Question: In a class of 54 students, 12 enrolled for both English and German. 22 enrolled for German. If the students of the class enrolled for at least one of the two subjects, then how many students enrolled for only English and not German?
Options:
A)30
B)10
C)18
D)28
E)32
Rationale: Total=English+German-Both+Neither --> 54=English+22-12+0 --> English=44 --> Only English=English-Both=44-12=32.
Answer: E.
Answer: E
Question: A boat can travel 1.5 times the distance down the stream than up the stream in the same time. If the speed of the current is 2 KMPH, Find the speed of the boat in still water
Options:
A)5
B)10
C)15
D)20
E)25
Rationale: Simple question, messy language.
Lets say boat's speed is B and current's speed is C.
Upstream speed : B - C
Downstream speed : B + C
Distance will be the same both times. lets say D.
given : time it takes upstream = 1.5 times time it takes downstream
D/(B + C) = 1.5 * [D/(B - C)]
Solving B = 5 C
given : C is 2 KMPH
So B is 10 KMPH
B
Answer: B
Question: What profit percent is made by selling an article at a certain price, if by selling at 3/4rd of that price, there would be a loss of 20%?
Options:
A)20%
B)29%
C)7%
D)27%
E)28%
Rationale: SP2 = 3/4 SP1
CP = 100
SP2 = 80
3/4 SP1 = 80
SP1 = 107
100 --- 107 => 7%
Answer: C
Answer: C
Question: Mary passed a certain gas station on a highway while traveling west at a constant speed of 40 miles per hour. Then, 15 minutes later, Paul passed the same gas station while traveling west at a constant speed of 50 miles per hour. If both drivers maintained their speeds and both remained on the highway for at least 2 hours, how long after he passed the gas station did Paul catch up with Mary?
Options:
A)1/2
B)1
C)3/4
D)2
E)3
Rationale: d = rt
M: r = 40mph, t = t + 1/4hr
d = 40 (t + 1/4)
P: r = 50, t = t
d = 50t
since they went the same distance:
40t + 40/4 = 50t
10t = 10
t = 1 hr,
B
Answer: B
Question: A courtyard is 18 meter long and 16 meter board is to be paved with bricks of dimensions 20 cm by 10 cm. The total number of bricks required is?
Options:
A)22877
B)27778
C)20000
D)27999
E)14400
Rationale: Number of bricks =Courtyard area/1 brick area
=(1800×1600/20×10)=14400
Answer: E
Answer: E
Question: 1.A committee that includes 6 members is about to be divided into 2 subcommittees with 3 members each. On what percent of the possible subcommittees that Michael is a member of is David also a member
Options:
A)A.10%
B)B.20%
C)C.25%
D)D.46%
E)E.50%
Rationale: A,B, C is too low so I eliminated those answers, E was too high of a number, so I chose D as my final answer.D
Answer: D
Question: A train running at the speed of 60 km/hr crosses a pole in 6 seconds. What is the length of the train?
Options:
A)187 m
B)278 m
C)876 m
D)150 m
E)100 m
Rationale: Speed=(60 * 5/18) m/sec = (50/3) m/sec Length of the train
= (Speed x Time)
= (50/3 * 6) m
= 100 m.
Answer: E
Answer: E
Question: What is the greatest integer that will always evenly divide the sum of seven consecutive integers?
Options:
A)2
B)3
C)4
D)7
E)12
Rationale: Let the three consecutive even integers be x , x + 7 , x+14 , x+21 , x+28 , x+35, x+42
Sum = x + x + 7 + x + 14 + x + 21 + x + 28 + x + 35 + x + 42
= 7x+147 = 7(x+21)
Therefore , 7 will always be a factor .
Answer D
Answer: D
Question: If the sides of a cube are in the ratio 7:3. What is the ratio of their diagonals?
Options:
A)9:4
B)8:4
C)7:4
D)7:3
E)6:4
Rationale: Explanation:
Diagonal of a Cube=a√3 where a is side
a1:a2 = 7:3
d1:d2 = 7:3 where√3 cancelled both side
ANSWER:D
Answer: D
Question: If the LCM and HCF of 12 and another number is 60 and 3 respectively. Find the other number ?
Options:
A)17
B)12
C)15
D)13
E)11
Rationale: HCF x LCM = Product of Numbers
3 x 60 = 12 x the other number
other number = (3 x 60) / 12
other number = 15
ANSWER : C
Answer: C
Question: A train running at the speed of 180 km/hr crosses a pole in 36 seconds. What is the length of the train?
Options:
A)450 m
B)500 m
C)550 m
D)600 m
E)650 m
Rationale: Speed=(180 * 5/18) m/sec
= (50/3) m/sec Length of the train
= (Speed x Time)
= (50/3 * 36) m = 600 m.
Answer:D
Answer: D
Question: Alok ordered 16 chapatis, 5 plates of rice, 7 plates of mixed vegetable and 6 ice-cream cups. The cost of each chapati is Rs.6, that of each plate of rice is Rs.45 and that of mixed vegetable is Rs.70. The amount that Alok paid the cashier was Rs.961. Find the cost of each ice-cream cup?
Options:
A)25
B)76
C)29
D)12
E)20
Rationale: Explanation:
Let the cost of each ice-cream cup be Rs.x
16(6) + 5(45) + 7(70) + 6(x) = 961
96 + 225 + 490 + 6x = 961
6x = 150 => x = 25.
Answer:A
Answer: A
Question: x, y and z are consecutive positive integers such that x < y < z; which of the following must be true?
1. yz is even
2. (z-x)(y-x+1) = 4
3. xy is odd
Options:
A)I only
B)I , II only
C)III only
D)I and II only
E)I, II, and III
Rationale: Since x, y and z are consecutive integers such that x < y < z, we can say x = y-1 and Z = y+1
Statement 1 yz =y*(y+1) ..if one is odd then other will be even and vice versa ..true
Statement 2 can be simplified if we write everything in terms of y as ((y+1)-(y-1))*(y-(y-1)+1) = 2*2 = 4 So, always true
Statement 3 talks about xy Since x and y are consecutive integers one of them is odd and other is even so product would always be even and hence not true.
So, I and II are always true and hence answer is
B
Answer: B
Question: A producer of tea blends two varieties of tea from two tea gardens one costing Rs 18 per kg and another Rs 20 per kg in the ratio 5 : 3. If he sells the blended variety at Rs 26 per kg, then his gain percent is
Options:
A)12%
B)39%
C)14%
D)15%
E)16%
Rationale: Explanation:
Suppose he bought 5 kg and 3 kg of tea.
Cost Price = Rs. (5 x 18 + 3 x 20) = Rs. 150.
Selling price = Rs. (8 x 26) = Rs. 208.
Profit = 208 - 150 = 58
So, Profit % = (58/150) * 100 = 39%
Option B
Answer: B
Question: The ratio of the volumes of two cubes is 125 : 512. What is the ratio of their total surface areas?
Options:
A)81 : 121
B)25 : 64
C)729 : 1331
D)27 : 121
E)None of these
Rationale: Ratio of the sides = Â³âˆš125 : Â³âˆš512 = 5 : 8
Ratio of surface areas = 5^2 : 8^2 = 25 : 64
ANSWER: B
Answer: B
Question: If â€˜MADURAIâ€™ is coded as â€˜DADCIAIâ€™, then â€˜DELHIâ€™ is coded as
Options:
A)DEHIE
B)DDEHI
C)EDDIH
D)DECHI
E)CHIDE
Rationale: M=13,1+3=4=D
A=1=A
SIMILARLY,
M=13=1+3=4=D
D=4=D
E=5=E
L=12=1+2=C
H=8=H
I=9=I
SO ANS IS
DECHI
ANSWER:D
Answer: D
Question: Find the circumference and area of radius 7 cm.
Options:
A)124 cm²
B)144 cm²
C)154 cm²
D)184 cm²
E)194 cm²
Rationale: Area of circle = πr²
= 22/7 × 7 × 7 cm²
= 154 cm²
ANSWER:C
Answer: C
Question: Two trains are running in opposite directions with the same speed. If the length of each train is 120 m and they cross each other in 12 sec, then the speed of each train is?
Options:
A)22
B)88
C)36
D)77
E)81
Rationale: Let the speed of each train be x m/sec.
Then, relative speed of the two trains = 2x m/sec.
So, 2x = (120 + 120)/12 => x = 10
Speed of each train = 10 m/sec.
= 10 * 18/5 =- 36 km/hr.
Answer:C
Answer: C
Question: If x^2+(1/x^2)=2, x^4+(1/x^4)=?
Options:
A)10
B)2
C)12
D)14
E)15
Rationale: -> x^4+(1/x^4)=(x^2)^2+(1/x^2)^2=(x^2+1/x^2)^2-2x^2(1/x^2)=2^2-2=2.
Thus, the answer is B.
Answer: B
Question: How many integers between 2000 and 3000 that have distinct digits and increase from left to right ?
Options:
A)10
B)20
C)60
D)120
E)600
Rationale: Since the numbers must be distinct and increasing from left to right,
The only arrangements we could come-up with are:
245_ --> 4
246_ --> 3
247_ --> 2
248_ --> 1
256_ --> 3
257_ --> 2
258_ --> 1
267_ --> 2
268_ --> 1
Number of integers =20
B
Answer: B
Question: How many positive integers less than 600 can be formed using the numbers 1, 2, 3, 5 and 6 for the digits?
Options:
A) 48
B) 130
C) 66
D) 68
E) 84
Rationale: Notice that we can find the number of 2 and 3 digit numbers by just assuming the first digit can also be zero:
0 1 1
1 2 2
2 3 3
3 5 5
5 6 6
Number of possibilities = 5*5*5 = 125.
Then, just add up the number of 1 digits numbers = 5, so total is 125+5 = 130.
Answer: B
Answer: B
Question: After an ice began to melt out from the freezer, in the first hour lost 3/4, in the second hour lost 3/4 of its remaining. If after two hours, the volume is 0.25 cubic inches, what is the original volume of the cubic ice, in cubic inches?
Options:
A)2.5
B)3.0
C)4.0
D)6.5
E)8.0
Rationale: Let initial volume of ice be = x
Ice Remaining after 1 hour = x - 0.75x = 0.25x
Ice Remaining after 2 hour = (1/4)x - (3/4 * 1/4 * x) = (1/16)x
(1/16)x = 0.25
x = 4
Alternate solution: Try to backsolve.
Initial volume = 4
After one hour --> (1/4)4 = 1
After two hours --> (1/4)1 = 0.25
Answer: C
Answer: C
Question: The speed of a boat in still water is 55kmph and the speed of the current is 20kmph. Find the speed downstream and upstream?
Options:
A)80,70 kmph
B)80,40 kmph
C)75,35 kmph
D)80,80 kmph
E)84,40 kmph
Rationale: Speed downstream = 55 + 20
= 75 kmph
Speed upstream = 55 - 20
= 35 kmph
Answer: C
Answer: C
Question: If y ≠ 3 and 2r/y is a prime integer greater than 2, which of the following must be true?
I. r = y
II. y = 1
III. r and y are prime integers.
Options:
A) None
B) I only
C) II only
D) III only
E) I and II
Rationale: Note that we are asked which of the following MUST be true, not COULD be true. For such kind of questions if you can prove that a statement is NOT true for one particular set of numbers, it will mean that this statement is not always true and hence not a correct answer.
So we should try to make the listed statements not true for some r and y (which satisfy y≠3 and 2r/y=prime>2).
I. r = y --> not necessarily true: r=3 and y=2 (2r/y=3=prime>2);
II. y=1 --> not necessarily true: r=3 and y=2 (2r/y=3=prime>2);
III. r and y are prime integers --> not necessarily true: r=10 and y=4 (2r/y=5=prime>2).
Answer: A.
Answer: A
Question: ABCD is a square. E,F,G,H is the midpoint of the sides of square. J and K is the midpoint of the sides HG and FG . L is a point on sides EF such that LF= 1/3 EF. Find the ratio of area of triangle JKL to the area of square ABCD.
Options:
A)5: 46
B)5: 44
C)4: 48
D)5: 48
E)5: 4
Rationale: ratio = 5: 48
ANSWER:D
Answer: D
Question: sowdharya had 90 currency notes in all, some of which are of Rs 95 denomination and the remaining of Rs 45 denomination. The total amount of all these currency notes was Rs. 5000. How much amount (in Rs) did she have in the denomination of Rs 45?
Options:
A)75
B)72
C)71
D)76
E)73
Rationale: Let the number of 45-rupee notes = x
Then, the number of 95-rupee notes = (90 – x)
45x + 95(90 – x) = 5000 : x = 71
ANSWER:C
Answer: C
Question: Find the constant b so that the three points A(2 , 3), B(4 , 7) and C(8 , b) are collinear (i.e. on the same line).
Options:
A)5
B)10
C)15
D)20
E)25
Rationale: The slope of the line through A and B must be equal to the slope of the line through B and C.
(7 - 3)/(4- 2) = (b - 7)/(8 - 4)
solve the above for b to find b = 15.
correct answer C)15
Answer: C
Question: A bag contains 7 green and 8 white balls. If two balls are drawn simultaneously, the probability that both are of the same colour is?
Options:
A)7/19
B)7/12
C)7/97
D)7/29
E)7/15
Rationale: Drawing two balls of same color from seven green balls can be done in ⁷C₂ ways.
Similarly from eight white balls two can be drawn in ⁸C₂ ways.
P = ⁷C₂/¹⁵C₂ + ⁸C₂/¹⁵C₂
= 7/15
Answer: E
Answer: E
Question: The music class consists of 5 girls and 7 boys. How many ways can a group of 3 be formed if it has to include at least one boy?
Options:
A)155
B)158
C)161
D)165
E)210
Rationale: Reverse combinatorics approach is preferred method on this one
Note that at least 1 boy gives clue to using this method
All combinations - five girls = answer
All combinations is 12C3 = 220
All girls 5C3 = 10
So our answer is 220-10=210
Hence, answer is (E)
Answer: E
Question: If x^6 > x^9 > x^11, which of the following could be the value of x?
Options:
A)-1/5
B)52
C)6
D)3
E)-4.7
Rationale: x^6 > x^9 > x^11
1)Here we have an even power of a variable (x) that is greater than both a larger odd power of the variable x and a smaller odd power of the variable x.
This can be possible only if the base is negative; therefore, the variable, x, must be a negative number.
2) Now if the variable x is negative, the higher power results in a smaller number if x<-1, and a higher power results in a larger number if 0>x>-1.
With this information, we know that x is a negative number less than -1; therefore, E (-4.7) is the only option.
Answer: E
Question: A feed store sells two varieties of birdseed: Brand A, which is 60% millet and 40% sunflower, and Brand B, which is 65% millet and 35% safflower. If a customer purchases a mix of the two types of birdseed that is 50% millet, what percent of the mix is Brand A?
Options:
A)40%
B)60%
C)50 %
D)45 %
E)55 %
Rationale: Yes there is a simple method :
Consider the following method
Brand A : 60% millet and 40% sunflower
Brand B : 65% millet and 35% safflower
Mix : 50% millet
Here the weighted average is 50%,
Now Brand A has 60% millet, which is 10% more than the weighted average of mix = + 0.10 A --------------- I
Similarly, Brand B has 65 % millet, which is 15 % more than the weighted average of mix = + 0.15 B ------------ II
Now, both Brand A and Brand B are combined to give a 50% mix containing millet, so equate I and II
implies, 0.10 A = 0.15 B
Therefore A/B = 0.15/0.10 = 3/2
A : B : (A + B) = 3 : 2 : (3+2) = 3 : 2 : 5
We have to find, percent of the mix is Brand A i.e. A : (A + B) = 3 : 5 = (3 / 5) * 100 = 60 %
Here is a pictorial representation :
Brand A= 60%------------------------10% or 0.10 above average, A times-----------------Total above = + 0.10 A
----------------------------------------------------------------------------------------Average = 50% or 0.50
Brand B = 65 %--------------------------15% or 0.15 above average, B times-----------------Total above = + 0.15 B
Since the amount below the average has to equal the average above the average; therefore,
0.10 A = 0.15 B
A/B = 3/2
A:B: Total = 3:2:5
Therefore
A/Total = 3:5 = 60 %
Answer: B
Answer: B
Question: In an institute, 60% of the students are boys and the rest are girls. Further 15% of the boys and 7.5% of the girls are getting a fee waiver. If the number of those getting a fee waiver is 90, find the total number of students getting 50% concessions if it is given that 50% of those not getting a fee waiver are eligible to get half fee concession?
Options:
A)360
B)280
C)320
D)330
E)350
Rationale: Solution: Let us assume there are 100 students in the institute.
Then, number of boys = 60
And, number of girls = 40
Further, 15% of boys get fee waiver = 9 boys
7.5 % of girls get fee waiver = 3 girls
Total = 12 students who gets fee waiver
But, here given 90 students are getting fee waiver. So we compare
12 = 90
So, 1 = 90/12 = 7.5
Now number of students who are not getting fee waiver = 51 boys and 37 girls.
50% concession = 25.5 boys and 18.5 girls (i.e. total 44).
Hence, required students = 44*7.5 = 330.
Answer: Option D
Answer: D
Question: The parameter of a square is double the perimeter of a rectangle. The area of the rectangle is 480 sq cm. Find the area of the square.
Options:
A)200
B)345
C)255
D)Cannot be determined
E)342
Rationale: Let the side of the square be a cm. Let the length and the breadth of the rectangle be l cm and b cm respectively.
4a = 2(l + b)
2a = l + b
l . b = 480
We cannot find ( l + b) only with the help of l . b. Therefore a cannot be found .
Area of the square cannot be found.
Answer: Option D
Answer: D
Question: Find the value of 72519 x 9999 = m?
Options:
A)673223454
B)695546788
C)634899013
D)725117481
E)734576909
Rationale: 72519 x 9999 = 72519 x (10000 - 1)
= 72519 x 10000 - 72519 x 1
= 725190000 - 72519
= 725117481
D
Answer: D
Question: Find the area of trapezium whose parallel sides are 30 cm and 12 cm long, and the distance between them is 16 cm?
Options:
A)288 cm2
B)277 cm2
C)285 cm2
D)336 cm2
E)340 cm2
Rationale: Area of a trapezium = 1/2 (sum of parallel sides) * (perpendicular distance between them)
= 1/2 (30 + 12) * (16)
= 336 cm2
Answer: D
Answer: D
Question: A sum of money invested for a certain number of years at 8% p.a. simple interest grows to Rs.180. The same sum of money invested for the same number of years at 4% p.a. simple interest grows to Rs.120 only. For how many years was the sum invested?
Options:
A)25
B)37
C)36
D)29
E)21
Rationale: Explanation:
From the information provided we know that,
Principal + 8% p.a. interest on principal for n years = 180 …….. (1)
Principal + 4% p.a. interest on principal for n years = 120 ……… (2)
Subtracting equation (2) from equation (1), we get
4% p.a. interest on principal for n years = Rs.60.
Now, we can substitute this value in equation (2),
i.e Principal + 60 = 120
= Principal = Rs.60.
We know that SI = , where p is the principal, n the number of years and r the rate percent of interest.
In equation (2), p = Rs.60, r = 4% p.a. and the simple interest = Rs.60.
Therefore, 60 =(60*n*4)/100
=> n = 100/4 = 25 years.
Answer: A) 25years
Answer: A
Question: The first term of an arithmetic progression is 3 and the 10 th term is 21. Find 15 th and 22 nd terms.
Options:
A)21,35
B)31,45
C)30,46
D)29,40
E)39,40
Rationale: Exp. a = 3, T 10 = a +9d =21, 3 +9d = 21, d =18/9 = 2
T 15 = a + 14d =3 +14*2 = 31, T22 = a + 21d = 3+ 21*2 = 45
ANSWER:B
Answer: B
Question: Look at this series: 1.25, 7.5, ____, 270, 1620, ... What number should fill the blank?
Options:
A)50
B)65
C)45
D)55
E)40
Rationale: This is a simple multiplication series. Each number is 6 times greater than the previous number.
Answer: C
Answer: C
Question: Six bells commence tolling together and toll at intervals of 2, 4, 6, 8 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together?
Options:
A)4
B)10
C)15
D)16
E)17
Rationale: L.C.M of 2,4,6,8,10,12 is 120. i.e after each 2 min they will toll together.So in 30 min they will toll 15 times.As they have initially tolled once,The answer will be 15+1=16.
ANSWER:D
Answer: D