divelab/Sys2Bench huggingface dataset:
Question: In a fuel station the service costs $2.75 per car, every liter of fuel costs 0.65$. Assuming that a company owns 12 cars and that every fuel tank contains 55 liters and they are all empty, how much money total will it cost to fuel all cars?
Options:
A)320$
B)380$
C)420$
D)450$
E)462$
Rationale: 12*2.75 + 0.65*12*55 = 462 hence - E
Answer: E
Question: If a fisherman catches 203128 shrimp while out and has to evenly split the catch between 9 restaurants, how many shrimp would he have left over?
Options:
A)4
B)7
C)2
D)1
E)6
Rationale: In order to find the answer you need to find a number that is divisible by 9.
The sum of 203128 16. 9 is divisible by 9 therefore you would subtract 7. 16-7=9
There would be 7 shrimp leftover. Answer B.
Answer: B
Question: A 15% item yields 30%. The market value of the item is:
Options:
A)Rs. 45
B)Rs. 55
C)Rs. 50
D)Rs. 60
E)Rs. 65
Rationale: Let the face value of the item is Rs.100
It yields Rs.15
Market value of the stock=(15/30)*100=Rs.50
ANSWER:C
Answer: C
Question: Three-twentieths of the members of a social club are retirees who are also bridge players, Four-twentieths of the members are retirees, and one-half of the members are bridge players. If 110 of the members are neither retirees nor bridge players, what is the total number of members in the social club?
Options:
A)200
B)300
C)360
D)400
E)480
Rationale: {Total} = {Retirees} + {Bridge players} - {Both} + {Neither}
x = 4/20*x + x/2 - 3/20*x + 110
20x = 4x + 10x - 3x + 110*20 (multiply by 20)
11x = 110*20
x = 200.
Answer: A
Answer: A
Question: The radius of a semi circle is 5.2 cm then its perimeter is?
Options:
A)32.52
B)32.48
C)26.74
D)32.9
E)32.31
Rationale: 36/7 r = 5.2 = 26.74
Answer:C
Answer: C
Question: The ratio of two numbers is 3:4 and their sum is 42. The greater of the two numbers is?
Options:
A)12
B)14
C)24
D)17
E)19
Rationale: 3:4
Total parts = 7
= 7 parts --> 42 (7 Ã— 6 = 42)
= 1 part ---->6 (1 Ã— 6 = 6)
= The greater of the two number is = 4
= 4 parts ----> 24 (6 Ã— 4 = 24)
C)
Answer: C
Question: In a particular year, the month of january had exactly 4 thursdays, and 4 sundays. On which day of the week did january 1st occur in the year.
Options:
A)sunday
B)monday
C)tuesday
D)wednesday
E)friday
Rationale: series of days may be either one of two:
(i)sun-4,mon-4,tue-4,wed-4,thu-4,fri-3 or 5,sat-3 or 5
(ii)thu-4,fri-4,sat-4,sun-4,mon-3or5,tue-3or5,wed-3or5
Lets check through option,
sun=1,8,15,22,29 jan ... which is not satisfies // wrong
Mon=1,8,15,22,29 jan,,,This satisfy option(ii) with thu-4,fri-4,sat-4,sun-4,mon-5,tue-5,wed-5
ANSWER:B
Answer: B
Question: Convert the following unit:
2.4 hectares in ares
Options:
A)200 ares.
B)210 ares.
C)220 ares.
D)230 ares.
E)240 ares.
Rationale: 2.4 hectares in ares
1 hectare = 100 ares
Therefore, 2.4 hectares = 2.4 × 100 ares
= 240 ares.
ANSWER : OPTION E
Answer: E
Question: If 2 men or 3 women can reap a field in 12 days how long will 4 men and 5 women take to reap it?
Options:
A)12/16
B)11/36
C)14/24
D)18/36
E)2/24
Rationale: Explanation:
2 men reap 1/12 field in 1 day
1 man reap 1/(2 x 12)
3 women reap 1/12 field in 1 day
1 woman reap 1/(12 x 3)
4 men and 5 women reap (4/(2 x 12)+ 5/(3 x 12) =11/36 in 1 day
4 men and 5 women will reap the field in 11/36 days
Answer: Option B
Answer: B
Question: A boy has 11 trousers and 12 shirts. In how many different ways can he select a trouser and a shirt?
Options:
A)120ways
B)138ways
C)140ways
D)132ways
E)150ways
Rationale: The boy can select one trouser in 11 ways.
The boy can select one shirt in 12 ways.
The number of ways in which he can select one trouser and one shirt is 11 * 12
= 132 ways.
Answer: D
Answer: D
Question: If y = 30p, and p is prime, what is the greatest common factor of y and 12p, in terms of p?
Options:
A)p
B)5p
C)6p
D)7p
E)p^2
Rationale: Y=30p
other number is 12p
then GCF(30p,12P)=6P; C is the correct answer
Answer: C
Question: In a mixture of milk and water, the proportion of milk by weight was 80%. If, in a 180 gm mixture, 36 gms of pure milk is added, what would be the percentage of milk in the mixture formed?
Options:
A)73.33%
B)93.33%
C)23.33%
D)33.33%
E)83.33%
Rationale: Explanation:
Percentage of milk in the mixture formed = [80/100 (180) + 36] / (180 + 36) * 100% = (144 + 36)/216 * 100% = 5/6 * 100% = 83.33%.
Answer: E
Answer: E
Question: The unit digit in the product (445 * 534 * 999 * 234) is:
Options:
A)2
B)0
C)6
D)5
E)1
Rationale: Explanation:
Unit digit in the given product = Unit Digit in (5*4*9*4) = 0
ANSWER: B
Answer: B
Question: A pair of articles was bought for $360 at a discount of 10%. What must be the marked price of each of the article?
Options:
A)$200
B)$500
C)$350
D)$400
E)$600
Rationale: S.P. of each of the article = 360/2 = $180
Let M.P = $x
90% of x = 360
x = 180*100/90 =$200
Answer is A
Answer: A
Question: Of the 400 employees in a certain company, 25 percent will be relocated to City X and the remaining 75 percent will be relocated to City Y. However, 40 percent of the employees prefer City Y and 60 percent prefer City X. What is the highest possible number of employees who will be relocated to the city they prefer?
Options:
A) 65
B) 100
C) 115
D) 130
E) 260
Rationale: 240 prefer X (Group 1);
160 prefer Y (Group 2).
City Y needs 300 people: letall 160 who prefer Y (entire Group 2) be relocated there, the rest 140 will be those who prefer X from Group 1;
City X needs 100 people: 240-140=100 from Group 1 will be relocated to X, which they prefer.
So, the highest possible number of employees who will be relocated to the city they prefer is 160+100=260.
Answer: E.
Answer: E
Question: Jim bought edging to go around a circular garden with a radius of 5 feet. Later he decided to
double the diameter of the garden. How many more feet of edging must he buy?
Options:
A)28.84' additional edging
B)48.84' additional edging
C)31.40' additional edging
D)18.84' additional edging
E)58.84' additional edging
Rationale: circumference of small garden = 2 x 3.14 x 5 = 31.40'
double of the circumference of small garden = 2 x 31.40' = 62.80'
More feet to be buy = 62.80 - 31.40 = 31.40
Answer : C
Answer: C
Question: The difference between the local value and the face value of 7 in the numeral 32675149 is
Options:
A)75142
B)64851
C)5149
D)69993
E)None of these
Rationale: (Local value of 7) - (Face value of 7) = (70000 - 7) = 69993
Answer: Option D
Answer: D
Question: The average age of boys in a class is 16 years and that of the girls is 15 years. What is the average age for the whole class?
Options:
A)15
B)16
C)15.5
D)Insufficient Data
E)17
Rationale: Explanation:
We do not have the number of boys and girls. Hence we cannot find out the answer.
Answer: Option D
Answer: D
Question: A and B start a business with investments of Rs. 5000 and Rs. 4500 respectively. After 4 months, A takes out half of his capital. After two more months, B takes out one-third of his capital while C joins them with a capital of Rs. 7000. At the end of a year, they earn a profit of Rs. 5080. Find the share of each member in the profit.
Options:
A)A - Rs. 1600, B - Rs. 1800, C - Rs. 1680
B)A - Rs. 1680, B - Rs. 1600, C - Rs. 1800
C)A - R,s. 1800, B - Rs. 1500, C - Rs. 1780
D)A - Rs. 1400, B - Rs. 1900, C - Rs. 1780
E)None of these
Rationale: Explanation:
A:B:CA:B:C =(5000Ã—4+2500Ã—8)=(5000Ã—4+2500Ã—8) :(4500Ã—6+3000Ã—6):(4500Ã—6+3000Ã—6) :(7000Ã—6):(7000Ã—6)
=40000:45000:42000=40000:45000:42000 =40:45:42=40:45:42.
A's share = Rs. 5080Ã—401275080Ã—40127 = Rs. 1600.
B's share = Rs. 5080Ã—451275080Ã—45127 = Rs. 1800.
C's share = Rs. 5080Ã—421275080Ã—42127 = Rs. 1680.
ANSWER IS A
Answer: A
Question: Four different objects 1,2,3,4 are distributed at random in four places marked 1,2,3,4. What is the probability that none of the objects occupy the place corresponding to its number?
Options:
A)17/24
B)3/8
C)1/2
D)5/8
E)5/3
Rationale: Explanation :
Let a particular number (say) number 2 occupies position 1.
Then all possible arrangement are given as:
=>(2,1,3,4), (2,1,4,3), (2,3,4,1), (2,4,1,4), (2,4,1,3), (2,4,3,1).
Out of these six, three (2,1,3,4), (2,3,1,4), (2,4,3,1) are not acceptable because numbers 3 and 4 occupy the correct positions.
Hence, the required probability = 3/6 = 1/2.
Answer : C
Answer: C
Question: Of the families in City X in 1991, 60 percent owned a personal computer. The number of families in City X owning a computer in 1993 was 20 percent greater than it was in 1991, and the total number of families in City X was 9 percent greater in 1993 than it was in 1991. what percent of the families in City X owned a personal computer in 1993?
Options:
A)59%
B)55%
C)63%
D)66%
E)68%
Rationale: Say a 100 families existed in 1991 then the number of families owning a computer in 1991 - 60
Number of families owning computer in 1993 = 60 * 120/100 = 72
Number of families in 1993 = 109
The percentage = 72/109 * 100 = 66%.
ANSWER:D
Answer: D
Question: A person purchased a TV set for Rs. 16000 and a DVD player for Rs. 6250. He sold both the items together for Rs. 35600
. What percentage of profit did he make?
Options:
A)80%
B)49%
C)40%
D)60%
E)90%
Rationale: The total CP = Rs. 16000 + Rs. 6250
= Rs. 22250 and SP = Rs. 35600
Profit(%) = (35600 - 22250)/22250 * 100
= 60%
Answer:D
Answer: D
Question: John had a stock of 1200 books in his bookshop. He sold 75 on Monday, 50 on Tuesday, 64 on Wednesday, 78 on Thursday and 135 on Friday. What percentage of the books were not sold?
Options:
A)36.5%
B)46.5%
C)66.5%
D)76.5%
E)96.5%
Rationale: Let N be the total number of books sold. Hence
N = 75 + 50 + 64 + 78 + 135 = 402
Let M be the books NOT sold
M = 1200 - N = 1200 - 402 = 798
Percentage
Books not sold / total number of books = 798/1200 = 0.665 = 66.5%
correct answer C
Answer: C
Question: A and B can do a piece of work in 7 days. With the help of C they finish the work in 4 days. C alone can do that piece of work in?
Options:
A)33
B)9 1/3
C)30
D)88
E)11
Rationale: C = 1/4 â€“ 1/7 = 3/28 => 28/3 = 9 1/3 days
Answer: B
Answer: B
Question: A committee of three students has to be formed. There are six candidates: Jane, Joan, Paul, Stuart, and Jessica. If Paul and Stuart refuse to be in the committee together and Jane refuses to be in the committee without Paul, how many committees are possible?
Options:
A)3
B)4
C)5
D)6
E)8
Rationale: Let's try a different problem with your approach. There are five people: A, B, C, D, E. Need to chose 3 for a committee. A and B cannot be chosen together. B and C cannot be chosen together. How many options?
Your approach: total 10 options, 5c3.
Now, assume the wrong scenario where A and B are chosen together. There are three such scenarios. (A and B are chosen, just need one more person.) So we have to subtract the three wrong options. Similarly, there are three wrong scenarios where B and C are chosen together.
This gives us 10-3-3=4 as the answer.
Yet this answer is wrong. There are five possibilities: ACD, ACE, ADE, BDE, CDE.
D
Answer: D
Question: The simple interest on Rs. 10 for 4 months at the rate of 3 paise per rupeeper month is
Options:
A)1.2
B)1.4
C)2.25
D)3.21
E)None
Rationale: Sol.
S.I. = Rs. [10 * 3/100 * 4] = Rs. 1.20
Answer A
Answer: A
Question: If n is a positive integer, which of the following is a possible value of |36 - 5n|?
Options:
A)7
B)14
C)12
D)15
E)20
Rationale: When 36>5n, then |36- 5n| = 71- 5n = (36-5n) + 1 = {multiple of 5} + 1
When 36<=5n, then |36- 5n| = -(71- 5n) = (36-70) - 1 = {multiple of 5} - 1
So, the correct answer must be 1 greater or 1 less than a multiple of 5. Only B fits.
Answer: B
Answer: B
Question: TOM traveled the entire 50 miles trip. If he did the first 15 miles of at a constant rate 20 miles per hour and the remaining trip of at a constant rate 45 miles per hour, what is the his average speed, in miles per hour?
Options:
A)60.40mph
B)60.20mph
C)55.32mph
D)65.50mph
E)70.25mph
Rationale: avg speed = total distance/ total time = (d1+d2)/(t1+t2) = (15+35) / ((15/20)+(35/45)) = 50*180/149 = 60.40mph
A
Answer: A
Question: Two trains 140 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is?
Options:
A)10
B)11
C)12
D)10.8
E)16
Rationale: Relative speed = 60 + 40 = 100 km/hr.
= 100 * 5/18 = 250/9 m/sec.
Distance covered in crossing each other = 140 + 160 = 300 m.
Required time = 300 * 9/250 = 54/5 = 10.8 sec.
Answer: Option D
Answer: D
Question: John makes $50 a week from his job. He earns a raise and now makes $80 a week. What is the % increase?
Options:
A)16%
B)16.66%
C)17.9%
D)18.12%
E)60%
Rationale: Increase = (30/50)*100 = (3/5)*100 = 60%.
E
Answer: E
Question: The salary of a person was reduced by 50%. By what percent should his reduced salary be raised so as to bring it at par with his original salary?
Options:
A)20%
B)25%
C)50%
D)75%
E)100%
Rationale: Let the original salary be $100
New salary = $50
Increase on 50 = 50
increase on 100 = 50/50 *100 = 100%(APPROXIMATELY)
Answer is E
Answer: E
Question: A train traveled the first d miles of its journey it an average speed of 60 miles per hour, the next d miles of its journey at an average speed of y miles per hour, and the final d miles of its journey at an average speed of 160 miles per hour. If the train’s average speed over the total distance was 90 miles per hour, what is the value of y?
Options:
A) 68
B) 84
C) 90
D) 110
E) 135
Rationale: Average speed=Total distance traveled /Total time taken
3d/d/60+d/y+d/160=90
Solving for d and y,
15y=11y+480
4y=440
y=110
Answer D
Answer: D
Question: The size of a television screen is given as the length of the screen's diagonal. If the screens were flat, then the area of a square 20-inch screen would be how many square inches greater than the area of a square 18-inch screen?
Options:
A)2
B)4
C)16
D)38
E)40
Rationale: Pythogoras will help here!
let the sides be x and diagonal be d
Then d ^2 = 2x^2
and
Area = x^2
Now plug in the given diagonal values to find x values
and then subtract the areas
Ans will be 20^2/2 - 18^2 /2 = 76 /2 = 38
Ans D.
Answer: D
Question: how many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9, which are divisible by 5 and none of the digits is repeated?
Options:
A)5
B)10
C)15
D)20
E)25
Rationale: Since each desired number is divisible by 5, so we must have 5 at the unit place. So, there is 1 way of doing it.
The tens place can now be filled by any of the remaining 5 digits (2, 3, 6, 7, 9). So, there are 5 ways of filling the tens place.
The hundreds place can now be filled by any of the remaining 4 digits. So, there are 4 ways of filling it.
Required number of numbers = (1 x 5 x 4) = 20.
ANSWER D 20
Answer: D
Question: Two cars are 500 cm apart. each is moving forward for 100 cm at a velocity of 50 cm/s and receding back for 50 cm at 25cm/s at what time they will collide with each other.
Options:
A)11 sec
B)14 sec
C)12 sec
D)13 sec
E)15 sec
Rationale: each car is moving forward for 100 cm with velocity 50cm/s
so time to cover 100cm is=100/50=2 sec
again receding back for 50 cm at 25cm/s velocity
so time to cover 50 cm is=50/25=2 sec
actually they individually cover (100-50)=50 cm in (2+2)=4 sec
so in 12 sec they together cover (150+150)=300 cm
and after that both move 100 cm in 2 sec
so after (12+2)=14 sec they cover (300+200)=500cm
so they collide after 14 sec
ANSWER:B
Answer: B
Question: What is the % change in the area of a rectangle when its length increases by 30% and its width decreases by30%?
Options:
A)0%
B)20% increase
C)20% decrease
D)9% decrease
E)Insufficient data
Rationale: (13/10)*(7/10) =91/100 of original area
91/100 is a 9% decrease from 100/100 ->D
Answer: D
Question: Find the area of the quadrilateral of one of its diagonals is 20 cm and its off sets 9 cm and 6 cm?
Options:
A)150 cm2
B)196 cm2
C)189 cm2
D)146 cm2
E)161 cm2
Rationale: 1/2 * 20(9 + 6)
= 150 cm2
Answer:A
Answer: A
Question: If the cost of 12 apples is $20. What would be the cost of 20 apples?
Options:
A)25.5
B)29.36
C)33.33
D)35.56
E)38.24
Rationale: The cost of one apple=20/12=1.67
The cost of twenty apples= 1.67x20= $ 33.33
Answer: B
Answer: B
Question: Income and expenditure of a person are in the ratio 10 : 8. If the income of the person is Rs. 10000, then find his savings?
Options:
A)2003
B)2002
C)2000
D)2001
E)2004
Rationale: Let the income and the expenditure of the person be Rs. 10x and Rs. 8x respectively.
Income, 10x = 10000 => x = 1000
Savings = Income - expenditure = 10x - 8x = 2x = 2(1000)
So, savings = Rs. 2000.
Answer:C
Answer: C
Question: The banker's gain on a bill due 1 year hence at 10% per annum is Rs. 20. What is the true discount?
Options:
A)Rs. 200
B)Rs. 100
C)Rs. 150
D)Rs. 250
E)None of these
Rationale: Explanation :
TD = (BG ×100)/TR = (20×100)/(1×10) = Rs. 200 Answer : Option A
Answer: A
Question: The first train leaves the station at 6:00 am with a speed of 60 km/hr. The second train leaves at 7:00 am, in the same direction from the same station, with a speed of 75 km/hr. What time will the second train catch the first train?
Options:
A)10:00 am
B)11:00 am
C)12:00 noon
D)1:00 pm
E)2:00 pm
Rationale: In sixty minutes, the first train travels 60 km.
The second train catches the first train with a relative speed of 15 km/h.
The second train will catch the first train in 4 hours.
The second train will catch the first train at 11:00 am.
The answer is B.
Answer: B
Question: The area of a square field is A square feet and the perimeter is p feet. If 6A=6(2p+9), what is the perimeter of the field, in feet? (Here A=a^2)
Options:
A)28
B)36
C)40
D)56
E)84
Rationale: You can also solve this via using the given numbers in the answer choices!
Of course you need to be aware of the basic properties as outlined by the other posts above (a = x^2 and p = 4x)
Starting with D you will notice that x=14 is way too big for your area (14^2) and will not satisfy: 6A=6(2p+9) or a=2p+9
--> Eliminate D and E
Now pick B (its either too big, then its A, or too small then you know its C or it is B itsself)
And picking B indeed solves the problem! (36/4 --> 9; a= 9^2 = 81 and 81=2x36+9)
Answer: B
Question: A is two years older than B who is twice as old as C.If the total of the ages of A,B nd C be 27,then how old is B ?
Options:
A)7
B)8
C)9
D)10
E)11
Rationale: Solution
Let C's age be x years .Then,B's age =2x years.A's age =(2x +2) years.
∴ (2x +2) +2x + x =27 ⇔ 5x =25 ⇔ x =5.
Hence,B's age =2x = 10 years. Answer D
Answer: D
Question: if 12401 is divided by any no. then quotient is 76 and remainder is 13.what is divisor?
Options:
A)154
B)124
C)153
D)163
E)183
Rationale: divisor=(dividend-remainder)/quotient=(12401-13)/76=12388/76=163
divisor = 163
answer D
Answer: D
Question: Find the value of x from the below equation:
x^2−7x+10=0
Options:
A)5 or 2
B)3 or 5
C)3 or 7
D)4 or 6
E)None
Rationale: Here we need to find out a and b such that a + b = -7 and ab = +10
a = -5 and b = -2 satisfies the above condition.
Hence
x^2−7x+10=(x−5)(x−2)
x2−7x+10=(x−5)(x−2)
x^2−7x+10
=0
⇒(x−5)(x−2)
=0
x2−7x+10=0⇒(x−5)(x−2)=0
Step 3: Equate each factor to 0 and solve the equations
(x−5)(x−2)
=0
⇒(x−5)
=0or (x−2)=0
⇒x= 5 or 2
A
Answer: A
Question: A train 360 m long runs with a speed of 45 km/hr. What time will it take to pass a platform of 390 m long?
Options:
A)38 sec
B)35 sec
C)44 sec
D)40 sec
E)60 sec
Rationale: Explanation:
Speed = 45 km/hr = 45×(10/36) m/s
= 150/12 = 50/4 = 25/2 m/s
Total distance = length of the train + length of the platform
= 360 + 390 = 750 meter
Time taken to cross the platform = 750/(25/2) = 750×2/25 = 60 seconds
Answer: Option E
Answer: E
Question: A jar of 180 marbles is divided equally among a group of marble-players today. If 2 people joined the group in the future, each person would receive 1 marble less. How many people are there in the group today?
Options:
A)16
B)18
C)20
D)22
E)24
Rationale: 180 = 18*10 = 20*9
There are 18 people in the group today.
The answer is B.
Answer: B
Question: A bicyclist's wheel has a circumference of 9 meters. if the bicyclist covers 180 meters in 5 hours at a constant speed, how many rotations does the wheel make per hour at that speed?
Options:
A)2
B)3
C)4
D)5
E)6
Rationale: The bicyclist covers y meters in t hrs. So he covers y/t meters in one hour.
To cover y/t meters, the bicycle's wheel went round and round that is, multiple times, the wheel completed one circumference on the road. How many times did it complete one full rotation. Since the circumference is x, the number of times it completes the circumference is y/xt.=180/9*5=4
Answer (C)
Answer: C
Question: If a particular is never chosen, in how many ways can a cricketbe chosen out of 15 players?
Options:
A)239
B)259
C)364
D)370
E)372
Rationale: A particular players is never chosen, it means that 11 players are selected out of 14 players.
=> Required number of ways = 14C11
= 14!/11!x3! = 364
C
Answer: C
Question: Which of the following leads to the correct mathematical solution for the number of ways that the letters of the word APPLE could be arranged to create a five-letter code?
Options:
A)5!
B)5! − (2!)
C)5! − (3! × 2!)
D)5!/(2!)
E)6!/( 2!)
Rationale: APPLE - five letters can be arranged in 5! ways
since 'P' repeats 2 times , we need to divide the 5! ways by 2! to adjust repetition.
5!/(2!)
Ans. D) 5!/(2!)
Answer: D
Question: The cost price of an book is 64% of the marked price. Calculate the gain percent after allowing a discount of 12%?
Options:
A)33%
B)28.02%
C)37.5%
D)30.5%
E)22%
Rationale: C
37.5%
Let marked price = $100.
Then, C.P. = $64, S.P. = $88
Gain % = 24/64 * 100 = 37.5%.
Answer: C
Question: If x^2 − 2x − 15 = (x + r)( x + s) for all values of x, and if r and s are constants, then which of the following is a possible value of 2(r − s)?
Options:
A)8
B)16
C)− 2
D)− 3
E)− 5
Rationale: We know that given ax^2 + bx + c = 0, Sum of the roots = -b/a and product of the roots = c/a.
The roots here are -r and -s.
-r - s = -(-2)/1 = r + s = -2
(-r)*(-s) = -15/1 = rs
So one of r and s is -5 and the other is 3. So 2(r - s) could be 16 or -16.
Answer (B)
Answer: B
Question: The length of rectangle is thrice its breadth and its perimeter is 72 m, find the area of the rectangle?
Options:
A)432
B)376
C)299
D)324
E)111
Rationale: 2(3x + x) = 72
l = 36 b = 9
lb = 36 * 9
= 324
D
Answer: D
Question: Tom, working alone, can paint a room in 12 hours. Peter and John, working independently, can paint the same room in 6 hours and 2 hours, respectively. Tom starts painting the room and works on his own for two hour. He is then joined by Peter and they work together for two hour. Finally, John joins them and the three of them work together to finish the room, each one working at his respective rate. What fraction of the whole job was done by Peter?
Options:
A)5/3
B)1/3
C)7/3
D)4/9
E)3/5
Rationale: Let the time when all three were working together be t hours. Then:
Tom worked for t+4 hour and has done 1/12*(t+4) part of the job;
Peter worked for t+2 hour and has done 1/6*(t+2) part of the job;
John worked for t hours and has done 1/2*t part of the job:
1/12*(t+4)+1/6*(t+2)+1/2*t=1 --> multiply by 12 --> (t+4)+(2t+2)+6t=12 --> t=2/3;
Hence Peter has done 1/6*(2/3+2)=1/6 *8/3=8/18=4/9
Answer: D
Answer: D
Question: A cistern has a leak which would empty the cistern in 20 minutes. A tap is turned on which admits 5 liters a minute into the cistern, and it is emptied in 24 minutes. How many liters does the cistern hold?
Options:
A)480
B)487
C)481
D)729
E)600
Rationale: 1/x - 1/20 = -1/24
x = 120
120 * 5 = 480
Answer:E
Answer: E
Question: Rs.1500 is divided into two parts such that if one part is invested at 6% and the other at 5% the whole annual interest from both the sum is Rs.85. How much was lent at 5%?
Options:
A)298
B)287
C)202
D)500
E)279
Rationale: (x*5*1)/100 + [(1500 - x)*6*1]/100 = 85
5x/100 + 90 – 6x/100 = 85
x/100 = 5
=> x =500
Answer:D
Answer: D
Question: If both 7^2 and 3^4 are factors of the number a*4^3*6^2*13^11, then what is the smallest possible value of a?
Options:
A)120
B)256
C)343
D)441
E)512
Rationale: The number a must include at least 3^2*7^2 = 441
The answer is D.
Answer: D
Question: The average of first twelve prime numbers which are odd is?
Options:
A)15.5
B)19.7
C)15.2
D)15.8
E)15.1
Rationale: Sum of first 12 prime no. which are odd = 236
Average = 236/12 = 19.7
Answer:B
Answer: B