divelab/Sys2Bench huggingface dataset:
Question: How many 4-digit positive integers are there, where each digit is positive, and no 3 adjacent digits are same?
Options:
A)1236
B)3528
C)4096
D)4608
E)6561
Rationale: First digit.. 9 posibilities
Second digit, 8 possibilities
third digit, 7 possibilities
Fourth digit, 7 possibilities.
9*8*7*7 = 3528.
B
Answer: B
Question: The probability of a team winning a match given Matt is playing the match is 0.70. The probability of the team winning a match given Matt is not playing the match is 0.3. The probability of Matt playing any match is 0.7.
If it is known that the team has won the last match, what is the probability that Matt played the match?
Options:
A)A)0.844
B)B)0.7
C)C)0.8571
D)D)0.7531
E)E)0.8213
Rationale: Out of 100 matches:
Matt is plays in 70 and not plays in 30.
Out of 70 matches Matt plays in, team wins 0.70*70 = 49.
Out of 30 matches Matt does not play in, team wins 0.3*30 = 9.
So, out of 100 matches 49 + 9 = 58 are won.
It is known that the team has won the last match. Out of 58 matches won, Matt is in 49: 49/58 = 0.844...
Answer: A.
Answer: A
Question: In a function they are distributing noble prize. In how many ways can 3 prizes be distributed among 4 boys when No boy gets more than one prize?
Options:
A)12
B)51
C)21
D)24
E)25
Rationale: Sol. In this case, repetitions are not allowed. So, the first prize can be given in 4 ways. The second in 3 ways and the third in 2 ways. But fundamental principle, (4 x 3 x 2) ways = 24 ways
4: Or 4p = — 4:- 4X3X2X1- 24 ways
D
Answer: D
Question: The product X of two prime numbers is between 15 and 70. If one of the prime numbers is greater than 2 but less than 6 and the other is greater than 13 but less than 25, then X =
Options:
A)18
B)29
C)37
D)44
E)69
Rationale: Option BC can be ruled out as they themselves are prime numbers
18 = 2*9 = 3*6 >> Ignore
44 = 2 * 22 = 4 * 11 >> Ignore
69= 3*23 >> Answer
Answer = E
Answer: E
Question: Murali travelled from city A to city B at a speed of 70 kmph and from city B to city C at 30 kmph. What is the average speed of Murali from A to C given that the ratio of distances between A to B and B to C is 2 : 3?
Options:
A)kmph
B)kmph
C)kmph
D)kmph
E)kmph
Rationale: Let the distances between city A to B and B to C be 2x km and 3x km respectively.
Total time taken to cover from A to C
= (2x)/70 + (3x)/30
= (6x + 21x)/210 = 27x/210
= x/10 Average speed
= (2x + 3x)/(27x/210) = 38.9 kmph.
Answer: B
Answer: B
Question: The average age of a group of 10 persons was decreased by 3 years when one person, whose age was 40 years, was replaced by a new person. Find the age of the new person?
Options:
A)18
B)56
C)12
D)17
E)10
Rationale: Initial average age of the 10 persons be P.
Age of the new person Q.
Sum of the ages of the initial 10 persons = 10P
New average
= (P-3) 10(P-3)
= 10P - 40 + Q
=> Q = 10
Answer:E
Answer: E
Question: A jet plane is rising vertically with a velocity of 10 m/s. It has reached a certain height when the pilot drops a coin, which takes 4 sec to hit the ground. Assuming that there is no resistance to the motion of the coin, the height of the place and the velocity of the coin on impact with the ground are:
Options:
A)38.4 m, 28.7 m/s
B)38.4 m, 29.2 m/s
C)26.5 m, 13.5 m/s
D)26.5 m, 28.7 m/s
E)26 m
Rationale: The coin will move up with the initial velocity of 10 m/s till it comes to rest. Time taken is given by:
0=10âˆ’9.8t
â‡’t=10/9.8 sec.
Time taken to reach the ground from the highest point:
=4âˆ’10/9.8
=29.2/9.8 sec
Velocity of coin on impact
=0+9.8Ã—(29.2/9.8)
=29.2 m/s
If 'h' is the height from which the coin dropped.
Then
29.2^2âˆ’10^2=2Ã—9.8Ã—h
â‡’h = 38.4 m
Answer : B
Answer: B
Question: A man visits a shopping mall almost every day and he walks up an up-going escalator that connects the ground and the first floor. If he walks up the escalator step by step it takes him 16 steps to reach the first floor. One day he doubles his stride length (walks up climbing two steps at a time) and it takes him 12 steps to reach the first floor.
Options:
A)15
B)16
C)47
D)48
E)49
Rationale: Let d be the distance traveled, which remains same in both the cases. if v is the speed of the man and x is the speed of elevator, in case 1 the number of steps taken is
d/v+x=16
In case 2 it is
d/2v+x=12
because now he is traveling at double the speed; eliminating d, we get x=2v; therefore d=48v; when stationery x=0, we get no. of steps as 48v/v=48.
ANSWER:D
Answer: D
Question: The product of two numbers is 168 and the sum of these two numbers is 26. What is the largest of these two numbers?
Options:
A)12
B)14
C)16
D)18
E)None of these
Rationale: Explanation:
Let the numbers be x and (26 – x) .
Therefore,
x (26 – x) = 168
x2 – 26x + 168 = 0
(x – 14) (x – 12) = 0
x = 14 or x = 12
So, the numbers are 14 and 12.
ANSWER: B
Answer: B
Question: A can run a kilometer race in 4 1/2 min while B can run same race in 5 min. How many meters start can A give B in a kilometer race, so that the race mat end in a dead heat?
Options:
A)288
B)266
C)155
D)100
E)112
Rationale: A can give B (5 min - 4 1/2 min) = 30 sec start.
The distance covered by B in 5 min = 1000 m.
Distance covered in 30 sec = (1000 * 30)/300 = 100 m.
A can give B 100m start.
Answer:D
Answer: D
Question: The value of X+3X(5X)(X)when X =2 is:
Options:
A)132
B)120
C)122
D)108
E)123
Rationale: Solution:
X+3X(5X)(X)
Put the value of X= 2 in the above expression we get,
2+ 6(2 x 5)(2)
= 2+ 6(10)(2)
= 2 + 120
=122
Answer :C
Answer: C
Question: Who is second to the right of H?
Options:
A)67
B)88
C)166
D)19
E)911
Rationale: Answer: Option B
Answer: B
Question: The banker's discount on Rs.1800 at 8% per annum is equal to the true discount on Rs.1872 for the same time at the same rate. Find the time?
Options:
A)3 months
B)4 months
C)5 months
D)6 months
E)7 months
Rationale: Solution
S.I on Rs.1800 = T.D on Rs.1872.
P.W on Rs.1872 is Rs.1800.
Rs.72 is S.I on Rs. 1800 at 8%.
Time	=(100x72 / 8x1800)
= 1/2 year
= 6 months.
Answer D
Answer: D
Question: If p+5/q is a prime integer, which of the following must be true?
1.q=5p
2.q is a prime integer
3. p+5/q is ODD.
Options:
A)None
B)1 only
C)2 only
D)1 and 2 only
E)2 and 3 only.
Rationale: I would pick up numbers and do .
i hope the question is (p+5)/q....
let p = 3 , q = 4
3+5/4 = 2 = Prime
1. q is not equal to 5p
2.q is not a prime number
3. (p+5)/q is not odd.
hence A
Answer: A
Question: A train speeds past a pole in 15 sec and a platform 120 m long in 25 sec, its length is?
Options:
A)50 m
B)180 m
C)200 m
D)300 m
E)None of these
Rationale: Let the length of the train be x m and its speed be y m/sec.
Then, x/y = 15 => y = x/15
(x + 120)/25 = x/15 => x = 180 m.
ANSWER:B
Answer: B
Question: The mean of 50 observations was 41. It was found later that an observation 48 was wrongly taken as 23. The corrected new mean is
Options:
A)35.2
B)36.1
C)36.5
D)41.5
E)None
Rationale: Sol.
Therefore correct sum
= ( 41 × 50 + 48 – 23)
= 2075.
Therefore correct mean
= 2075 / 50
= 41.5.
Answer D
Answer: D
Question: A letter lock consists of three rings each marked with five different letters. The number of distinct unsuccessful attempts to open the lock is at the most?
Options:
A)176
B)124
C)215
D)197
E)172
Rationale: Since each ring consists of five different letters, the total number of attempts possible with the three rings is
= 5 * 5*5 = 125. Of these attempts, one of them is a successful attempt.
Maximum number of unsuccessful attempts
= 125 - 1 = 124.
Answer: B
Answer: B
Question: A student gets 70% in one subject, 80% in the other. To get an overall of 75% how much should get in third subject.
Options:
A)75%
B)25%
C)45%
D)55%
E)65%
Rationale: A student gets 70% in one subject, 80% in the other.
Average of 2 subjects is 75% , if they have equal weightage.
To get an overall of 75% , he should get 75 % in third subject to maintain same % age..if they have equal weightage.
ANSWER:A
Answer: A
Question: A clothing store sells t-shirts arranged on display such that each of the five different colors of t-shirts, orange, green, red, blue, and purple are consecutive in a repeating pattern. If six consecutively displayed t-shirts are purchased, what is the probability that two of the t-shirts are purple?
Options:
A)2/5
B)1/25
C)1/5
D)3/4
E)1/20
Rationale: After orange, green, red, blue, and purple, the next t-shirt can be of any given five colours, therefore we have total five possibilites, out of which we need purple i.e. 1 therefore prob is 1/5. Correct answer is C.
Answer: C
Question: The price of a certain car this year is $18,000, which is 25 percent greater than the cost of the car last year. What was the price of the car last year?
Options:
A)$14,000
B)$14,200
C)$14,400
D)$14,600
E)$14,800
Rationale: The price of the car last year was $18,000/1.25=$14,400
The answer is C.
Answer: C
Question: Mary decided to save a certain amount of her monthly salary each month and her salary was unchanged from month to month. If Mary's savings by the end of the year from these monthly savings were SIX times the amount she spent per month, what should be the fraction of her salary that she spent each month?
Options:
A)1/2
B)3/4
C)1/3
D)2/3
E)1
Rationale: Saving = S, Expenditure = E, Income = I
At the end of 12months; 12S=6E=6(I-S)
=> 18S = 6I => Savings = 1/3 I
Hence Expenditure = 1-(1/3) = 2/3
Answer (D)
Answer: D
Question: A can do a work in 16 days and B can do it in 8 days. In how many days A and B can do the work?
Options:
A)20 days
B)5 1/3 days
C)6 days
D)8 days
E)7 days
Rationale: Explanation:
A's 1day's work = 1/16
B's 1day's work = 1/8
They work together = 1/16 + 1/8 = 3/16 = 16/3 = 5 1/3days
Answer: Option B
Answer: B
Question: Nine persons went to a hotel for taking their meals 8 of them spent Rs.12 each on their meals and the ninth spent Rs.8 more than the average expenditure of all the nine.What was the total money spent by them?
Options:
A)Rs.118
B)Rs.117
C)Rs.116
D)Rs.115
E)Rs.114
Rationale: Let the average expenditure of all nine be Rs.x
Then 12*8+(x+8)=9x or 8x=104 or x=13.
Total money spent = 9x=Rs.(9*13)=Rs.117.
Option B
Answer: B
Question: Reeya obtained 55, 67, 76, 82 and 55 out of 100 in different subjects, What will be the average
Options:
A)70
B)75
C)67
D)85
E)90
Rationale: Explanation:
(55+67+76+82+55 / 5)=67
Option C
Answer: C
Question: A can do a piece of work in 15 days and B in 20 days. They began the work together but 5 days before the completion of the work, A leaves. The work was completed in?
Options:
A)11 3/5
B)11 3/0
C)11 3/3
D)11 3/7
E)11 3/2
Rationale: (x – 5)/15 + x/20 = 1
x = 11 3/7 days
Answer: D
Answer: D
Question: Cara took out a charge account at the General Store and agreed to pay 5% simple annual interest. If she charges $54 on her account in January, how much will she owe a year later, assuming she does not make any additional charges or payments?
Options:
A)$55.70
B)$56.20
C)$56.70
D)$57.20
E)$57.70
Rationale: 1.05*$54=$56.70
The answer is C.
Answer: C
Question: A Martian bat flies at 60 yards per second from its nest to a dry lake. When it arrives there, it immediately continues at 45 yards per second to a nearby cave. If the distance between the lake and the cave is half the distance between the nest and the lake, what is the average speed, in yards per second, of the bat during the whole flight?
Options:
A)36
B)40
C)42
D)54
E)65
Rationale: Distance from nest to lake = d, Speed = 60, Time = d/60
Distance from lake to cave = d/2, Speed = 45, Time = d/90
Average speed = (d + d/2)/(d/60 + d/90) = (3/2)/(1/36) = 54
Answer: D
Answer: D
Question: 12.1212 + 17.0005 – 9.1102 = ?
Options:
A)200.01
B)20.011
C)20.0115.
D)20.1
E)0.002
Rationale: Solution
Given expression = (12.1212 + 17.0005) - 9.1102 = (29.1217 - 9.1102) = 20.0115. Answer C
Answer: C
Question: Find large number from below question The difference of two numbers is 1365. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder
Options:
A)1120
B)1239
C)1300
D)1456
E)1635
Rationale: Let the smaller number be x. Then larger number = (x + 1365).
x + 1365 = 6x + 15
5x = 1350
x = 270
Large number = 270+1365 = 1635
E
Answer: E
Question: Two trains each 250 m in length are running on the same parallel lines in opposite directions with the speed of 80 kmph and 70 kmph respectively. In what time will they cross each other completely?
Options:
A)22 sec
B)27 sec
C)12 sec
D)19 sec
E)10 sec
Rationale: D = 250 m + 250 m = 500 m
RS = 80 + 70 = 150 * 5/18 = 125/3
T = 500 * 3/125 = 12 sec
Answer: C
Answer: C
Question: In What proportion must flour at $0.8 per pound be mixed with flour at $0.9 per pound so that the mixture costs $0.845 per pound?
Options:
A)1:3
B)1:2
C)1:1
D)2:1
E)5:4
Rationale: Using weighted average method:
Let x be the proportion in which the $0.8 per pound flour is mixed with $0.9 per pound flour.
Thus 0.8*x + 0.9*(1-x) = 0.845
0.9 – 0.1x = 0.845
x = 0.55
Thus ratio of both flours is 5:4
E
Answer: E
Question: In a particular state, 60% of the counties received some rain on Monday, and 65% of the counties received some rain on Tuesday. No rain fell either day in 25% of the counties in the state. What percent of the counties received some rain on Monday and Tuesday?
Options:
A)12.5%
B)40%
C)50%
D)60%
E)67.5%
Rationale: 60 + 65 + 25 = 150%
The number is 50% above 100% because 50% of the counties were counted twice.
The answer is C.
Answer: C
Question: A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Options:
A)380
B)384
C)356
D)324
E)314
Rationale: Speed = (54 * 5/18) m/sec = 15 m/sec. Length of the train = (15 x 20)m = 300 m. Let the length of the platform be x meters. Then, (x + 300)/36 = 15 ==> x + 300 = 540 ==> x = 240 m.
Answer: Option B
Answer: B
Question: The sum of 9 hours 25 minutes and 4 hours 35 minutes is approximately what percent of a day?
Options:
A) 64%
B) 56%
C) 58%
D) 48%
E) 72%
Rationale: Since the question is asking for an approximate percentage
9:25+4:35 = 14 hours
% of day = 14*100/24 = 7*100/25 ~ 58%
Answer is C.
Answer: C
Question: 8, 24, 12, 36, 18, 54, (....)
Options:
A)27
B)68
C)108
D)72
E)75
Rationale: Explanation :
8 × 3 = 24
24 ÷ 2 = 12
12 × 3 = 36
36 ÷ 2 = 18
18 × 3 = 54
54 ÷ 2 = 27
Answer : Option A
Answer: A
Question: A train 108 m long is moving at a speed of 50 km/hr . It crosses a train 112 m long coming from opposite direction in 6 seconds. What is the speed of the second train?
Options:
A)81km/hr
B)80km/hr
C)82km/hr
D)85km/hr
E)84km/hr
Rationale: Total distance = 108+112 = 220 m
Time = 6s
Relative speed = distance/time = 220/6 m/s = 110/3 m/s
= (110/3) × (18/5) km/hr = 132 km/hr
=> 50 + speed of second train = 132 km/hr
=> Speed of second train = 132-50 = 82 km/hr
Answer is C.
Answer: C
Question: The marching band is made up of 140 musicians. The band wants to form a rectangular formation with A people in a row and B people in a column. If the number of people in a row is more than 4 and less than 35, how many different combinations of rectangular shapes are possible?
Options:
A)3
B)4
C)5
D)6
E)7
Rationale: firstly factors of 140 = 1, 2, 4, 5, 7, 10, 14, 20, 28, 35, 70, 140
the question says each row will have musicians more than 4 and less than 35,
therefore, we should be interested in the factors between 4 and 35 (noninclusive)
5(in each row) * 28(number of columns) =140, similarly
7 * 20
10 * 14
14 * 10
20 * 7
28 * 5
total possibilities = 6
option D
Answer: D
Question: The average of 20, 40 and 150 is twice the average of 10, 30, and which of the following ?
Options:
A)1)10
B)2)30
C)3)65
D)4)90
E)5)180
Rationale: 20 40 150 = 150+60 = 210/3 = 70.
70/2 = 35
10 30 x = 40+x/3 should be smaller than 35
cross multiply 35*3-40 = 65
C
Answer: C
Question: A committee has 5 men and 6 women. What are the number of ways of selecting 2 men and 3 women from the given committee?
Options:
A)170
B)200
C)626
D)207
E)227
Rationale: The number of ways to select two men and three women = ⁵C₂ * ⁶C₃
= (5 *4 )/(2 * 1) * (6 * 5 * 4)/(3 * 2)
= 200
Answer:B
Answer: B
Question: At a party, everyone shook hands with everybody else. There were 66 handshakes. How many people were at the party?
Options:
A)14
B)18
C)11
D)17
E)12
Rationale: In general, with n+1 people, the number of handshakes is the sum of the first n consecutive numbers: 1+2+3+ ... + n.
Since this sum is n(n+1)/2, we need to solve the equation n(n+1)/2 = 66.
This is the quadratic equation n2+ n -132 = 0. Solving for n, we obtain 11 as the answer and deduce that there were 12 people at the party.
correct answer is E)12
Answer: E
Question: If the perimeter of a rectangular garden is 600 m, its length when its breadth is 100 m is?
Options:
A)228
B)288
C)200
D)288
E)111
Rationale: 2(l + 100) = 600 => l = 200 m
Answer: C
Answer: C
Question: A fellow borrowed a certain sum of money at 4% per annum at simple interest and in 4 years the interest amounted to Rs.1260 less than the sum lent. What was the sum lent?
Options:
A)1050
B)1220
C)1500
D)1060
E)1110
Rationale: P - 1260 = (P*4*4)/100
P = 1500
Answer: C
Answer: C
Question: On the first day of her vacation, Louisa traveled 250 miles. On the second day, traveling at the same average speed, she traveled 350 miles. If the 250-mile trip took 3 hours less than the 350-mile trip, what was the average speed, in miles per hour?
Options:
A)31
B)33.33
C)35
D)37
E)39.33
Rationale: (time)*(rate) = (distance)-->(rate) = (distance)/(time)--> given:(rate) = 250/t = 350/(t+3)-->5/t = 7/(t+3)-->5t+15=7t ---->2t= 15 . t= 7.5 ---->(rate ) = 250/7.5 = 33.33
Answer: B
Answer: B
Question: A certain bakery baked a batch of 470 cookies one day. Of those, 320 contained nuts, 230 contained chocolate chips, and 85 contained neither nuts nor chocolate chips. What is the fewest possible number of cookies with both chocolate chips and nuts that would need to be added to that batch so that cookies with both nuts and chocolate chips represented more than 3/5 of all the cookies in the batch?
Options:
A)166
B)293
C)413
D)438
E)511
Rationale: Cookies which have both nuts and chocolate chips = 165
Let fewest possible number of cookies with both chocolate chips and nuts that would need to be added to that
batch so that cookies with both nuts and chocolate chips represented more than 3/5 of all the cookies in the batch = x
(165+x)/(470+x) = 6/10
=>1650 + 10x = 2820 + 6x
=> 4x = 1170
=> x = 292.5
Therefore x = 293
Answer B
Answer: B
Question: An amount of money is to be divided between M, N and O in the ratio of 3:7:12. If the difference between the shares of M and N is Rs.2000, what will be the difference between N and O's share?
Options:
A)1266
B)3000
C)2866
D)2500
E)2678
Rationale: 7-3= 4= 2000
12-7 = 5 = 2000/4*5 = 2500
Answer : D
Answer: D
Question: The ratio of three numbers is 3:4:5 and the sum of their squares is 1250. The sum of the numbers is:
Options:
A)20
B)40
C)60
D)80
E)100
Rationale: Let the numbers be 3x, 4x and 5x
Then, 9x2+16x2+25x2=1250
50x2=1250
X=5
Sum of numbers= 3x+4x+5x=12x=60
ANSWER C
Answer: C
Question: The width of a rectangular hall is ½ of its length. If the area of the hall is 450 sq.m, what is the difference between its length and breadth?
Options:
A)8m
B)10m
C)12m
D)15m
E)17m
Rationale: Let the length of the hall be x m
Breadth of the hall = 1x/2 m
Area of the hall = Length * Breadth
450 = x * 1x/2
x² = 900
x =30
Difference between the length and breadth of the hall = x - 1x/2 = x/2
=30/2 = 15m
ANSWER:D
Answer: D
Question: What percent of the different arrangements of the letters of the word AGAHUS are those in which the vowels appear together?
Options:
A)30%
B)25%
C)20%
D)40%
E)25%
Rationale: let's determine the number of total possibilities in arranging the letters. There are six spaces, so the total number of arrangements is 6!, or 360.
Next, we need to figure out how to determine the number of ways that we can arrange the 3 vowels together - simply place them together (as in AAU) and call that a single place.
Next, we must determine the number of ways to arrange the now 4 units (i.e., AAU, B, C, S). Like above, there are 4 units and 4 places so the number of arrangements is 4!, or 24.
Finally, we need to account for the number of ways we can arrange AAU. We can either write out each unique iteration (AAU, AUA and UAA) or calculate as 3!/2! and get 3.
Putting this all together, we get the number of ways to arrange the letters so that the vowels are together is 4! x 3 ==> 72
the number of total arrangements of all the letters is 6! ==> 360
72/360 = 1/5, or 20% Correct answer is C
Answer: C
Question: An engineer designed a ball so that when it was dropped, it rose with each bounce exactly one-half as high as it had fallen. The engineer dropped the ball from a 16-meter platform and caught it after it had traveled 46.5 meters. How many times did the ball bounce?
Options:
A)5
B)6
C)7
D)8
E)9
Rationale: Going down = 16 m
Going Up = 8 --> Total = 24
Going down = 8 --> Total = 32
Going Up = 4 --> Total = 36
Going down = 4 --> Total = 40
Going up = 2 --> Total = 42
Going down = 2 --> Total = 44
Going up = 1 --> Total = 45
Going down = 1 --> Total = 46
Going up = 0.5 --> Total = 46.5 (Caught)
No of going downs = 5 ..
ANSWER:A
Answer: A
Question: A club wants to mix 15 pounds of candy worth $8.00 per pound with candy worth $5.00 per pound to reduce the cost of the mixture to $6.00 per pound. How many pounds of the $5.00 per pound candy should be used?
Options:
A)20
B)30
C)40
D)50
E)60
Rationale: Let number of pounds of 5$ candy to be used be w
6 = (15*8 + 5*w)/(15 +w)
=>90 + 6w = 120 + 5w
=> w = 30
Answer B
Answer: B
Question: A batsman of a cricket has a certain average for 10 innings. In the eleventh inning, he scored 108 runs, thereby increasing his average by 6 runs. His new average is:
Options:
A)48 runs
B)52 runs
C)55 runs
D)60 runs
E)None of these
Rationale: Explanation :
Let average for 10 innings be x. Then, (10x + 108)/11 = x + 6
11x + 66 = 10x + 108
x = 42
New average = (x + 6) = 48 runs.
Answer : A
Answer: A
Question: A man goes to shopkeeper and says that if u give me as much as i have ,i will spend Rs.10/- on ur shop. shopkeeper agrees and man moves to another shopkeeper ans asked same. at 3rd shop after all the transaction, he was left with no money. find the initial amount with the man
Options:
A)5.75
B)6.75
C)7.75
D)8.75
E)9.75
Rationale: man has Rs.x
he leaves-
1st shop wid Rs.(2x-10)
2nd shop wid Rs.[2(2x-10)-10]
3rd shop wid Rs.{2[2(2x-10)-10]-10}=0(since he has no money left)
so solving the eqn x=8.75
ANSWER:D
Answer: D
Question: If a person walks at 15 km/hr instead of 5 km/hr, he would have walked 20 km more. The actual distance traveled by him is?
Options:
A)50 km
B)76 km
C)18 km
D)10 km
E)97 km
Rationale: Let the actual distance traveled be x km. Then,
x/5 = (x + 20)/15
10x - 100 =>x = 10 km.
Answer: D
Answer: D
Question: The present age of a father is 3 years more than three times the age of his son. Five years hence, father's age will be 10 years more than twice the age of the son. Find the present age of the father.
Options:
A)33
B)38
C)27
D)40
E)48
Rationale: if the present age be x years.
father's will be (3x+3)years..
so, (3x+3+5)=2(x+3)+10
or, x=8
so the fathers present age =(3x+3)=(3*8+3)years =27 years..
ANSWER : OPTION C
Answer: C
Question: What percent of the month of April is 20 days?
Options:
A)75%
B)66,66%
C)60%
D)64,5%
E)70%
Rationale: Explanation :
Total days in the month of April = 30
Required percentage = (20/30) Ã— 100 = 66,66%
Answer : Option B
Answer: B
Question: If P represents the product of the first 14 positive integers, then P is NOT a multiple of
Options:
A)99
B)84
C)72
D)65
E)34
Rationale: Answer is E.
Since prime factor of 57 is 2x17. 17 is a prime number and not part of the first 14 positive integers.
A) 9 x 11
B) 12 x 7
C) 12 x 6
D) 13 x 5
E) 2 x 17
Answer: E
Question: 5 men are equal to as many women as are equal to 8 boys. All of them earn Rs.60 only. Menâ€™s wages are?
Options:
A)6Rs
B)7Rs
C)8Rs
D)4Rs
E)1Rs
Rationale: 5M = xW = 8B
5M + xW + 8B ----- 60 Rs.
5M + 5M + 5M ----- 60 Rs.
15M ------ 60 Rs. => 1M = 4Rs.
Answer:D
Answer: D