divelab/Sys2Bench huggingface dataset:
Question: The average weight of 7 person's increases by 6.2 kg when a new person comes in place of one of them weighing 76 kg. What might be the weight of the new person?
Options:
A)160 kg
B)175 kg
C)180.7 kg
D)119.4 kg
E)190.8 kg
Rationale: Total weight increased = (7 x 6.2) kg = 43.4 kg.
Weight of new person = (76 + 43.4) kg = 119.4 kg
Option D
Answer: D
Question: Sides of a rectangular park are in the ratio 3: 2 and its area is 3750 sq m, the cost of fencing it at 50 ps per meter is?
Options:
A)288
B)277
C)298
D)125
E)272
Rationale: 3x * 2x = 3750 => x = 25
2(75 + 50) = 250 m
250 * 1/2 = Rs.125.Answer:C
Answer: C
Question: A boatman can row 96 km downstream in 8 hr. If the speed of the current is 4 km/hr, then find in what time he will be able to cover 8 km upstream ?
Options:
A)1.5 hrs
B)1 hrs
C)2.5 hrs
D)2 hrs
E)3 hrs
Rationale: Explanation:
Speed in downstream = 96/8 = 12 kmph
Speed of current = 4 km/hr
Speed of the boatman in still water = 12 â€“ 4 = 8 kmph
Speed in upstream = 8 â€“ 4 = 4 kmph
Time taken to cover 8 km upstream = 8/4 = 2 hours.
ANSWER IS D
Answer: D
Question: How many integer values T are there for x such that 1 < 3x + 5 < 17?
Options:
A)Two
B)Three
C)Four
D)Five
E)Six
Rationale: 1 < 3x + 5 < 17
=> -4 < 3x < 12
=> -4/3 < x < 4
x can take integer values T -1,0 , 1 , 2 , 3
Answer D
Answer: D
Question: In a kilometer race, A beats B by 80 meters or 10 seconds. What time does A take to complete the race?
Options:
A)199 sec
B)190 sec
C)726 sec
D)127 sec
E)115 sec
Rationale: Time taken by B run 1000 meters
= (1000 * 10)/80 = 125 sec.
Time taken by A = 125 - 10
= 115 sec.
Answer: E
Answer: E
Question: What is the maximum number of pieces of birthday cake of size 5” by 5” that can be cut from a cake 15” by 15”?
Options:
A)5
B)10
C)16
D)20
E)9
Rationale: The prompt is essentially asking for the maximum number of 5 x 5 squares that can be cut from a larger 15 by 15 square. Since each 'row' and each 'column' of the larger square can be sub-divided into 3 'pieces' each, we have (3)(3) = 9 total smaller squares (at maximum).
E
Answer: E
Question: The average of marks obtained by 120 boys was 36. If the average of marks of passed boys was 39 and that of failed boys was 15, the number of boys who passed the examination is?
Options:
A)105
B)110
C)120
D)130
E)140
Rationale: Let the number of boys who passed = X.
Then, 39 x X + 15 x (120 - X) = 120 x 36
24X = 4320 - 1800
=> X = 2520/24
X = 105.
Hence, the number of boys passed = 105.
ANSWER:A
Answer: A
Question: A bike covers a certain distance at the speed of 66km/h in 8 hrs. If the bike was to cover the same distance in approximately 6 hrs, at what approximate speed should the bike travel?
Options:
A)85 km/h
B)85.34 km/h
C)87.67 km/h
D)90.25 km/h
E)88 km/h
Rationale: Ans.(E)
Sol. Total distance = 66 × 8 = 528 km
Now speed = 528/6 = 88 km/h
Answer: E
Question: The distance light travels in one year is approximately 5,860,000,000,000 miles. The distance light travels in 100 years is
Options:
A)A) 587 × 108 miles
B)B) 587 × 1010 miles
C)C) 587 × 10-10 miles
D)D) 586 × 1012 miles
E)E) 587 × 10-12 miles
Rationale: The distance of the light travels in 100 years is:
5,860,000,000,000 × 100 miles.
= 586,000,000,000,000 miles.
= 586 × 1012 miles.
The answer is (D)
Answer: D
Question: The difference between the simple interest received from two different sources on Rs.1900 for 3 years is Rs.13.50. The difference between their rates of interest is
Options:
A)0.13%
B)0.23%
C)0.33%
D)0.43%
E)0.53%
Rationale: (1900xR1x3)/100-(100xR2x3)/100 =13.50
5700(R1-R2)=1350
R1-R2 = 1350/5700=0.23%
answer : B
Answer: B
Question: In August,a cricket team that played 120 matches won 24% of the games it played.After a continuous winning streak,this team raised its average to 52%.How many matches did the team win to attain this average?
Options:
A)40
B)52
C)68
D)70
E)98
Rationale: let the no of matches played more=x
so,
(120+x)*52/100=28.8+x
by solving we get x=70
ANSWER:D
Answer: D
Question: Three candidates contested an election and received 1136, 7636 and 12000 votes respectively. What percentage of the total votes did the winning candidate get?
Options:
A)46%
B)58%
C)74%
D)63%
E)68%
Rationale: B
12000/(1136 + 7636 + 12000) = 58%.
Answer: B
Question: How many numbers from 29 to 79 are exactly divisible by 11?
Options:
A)4
B)6
C)8
D)5
E)7
Rationale: Numbers=(79/11)-(29/11)
=7-2
=5 numbers
Option D is answer
Answer: D
Question: John bought 2 shares and sold them for $97 each. If he had a profit of 20% on the sale of one of the shares but a loss of 20% on the sale of the other share, then on the sale of both shares John had
Options:
A) a profit of $10
B) a profit of $8
C) a loss of $6
D) a loss of $10
E) neither a profit nor a loss
Rationale: $ Profit of the share sold at 20% profit =
120-97
20-?
$17 profit on the sale of 1 share.
$ Loss of the share sold at 20% loss=
80-97
20-?
$24 loss on the sale of 1 share.
17-23=Loss of $6
Answer: C
Answer: C
Question: If 4 (A's capital) = 6 (B's capital) = 10 (C's capital), then out of a profit of Rs. 31, C will receive
Options:
A)6
B)5
C)8
D)10
E)12
Rationale: Explanation:
Let 4A = 6B = 1OC = k. Then, A = k/4, B = k/6, and C =k/10 .
A : B :C = k/4 : k/6 : k/10 = 15 : 10 : 6.
Hence, C's share (31 * 6/31) = Rs, 6.
Answer: A) Rs.6
Answer: A
Question: There are 3 teams each with 8 basket players. How many combinations are there if we were to pick 2 players from the 3 teams such that no team was picked twice?
Options:
A)50
B)23
C)192
D)28
E)45
Rationale: There are altogether three arrangements, which are we can select two members each from team A and B, each from team A and C, and each from team B and C. For each arrangement, there are altogether 64 possibilities (8*8) since each team has 8 players. So there are a total of 192 possibilities (64*3). I hope this method is easier for you to understand.
Answer: C
Question: What is the smallest positive integer x such that 80-x is the cube of a positive integer
Options:
A)16
B)12
C)47
D)9
E)12
Rationale: Given 80-x is a perfect cube
so we will take 64= 4*4*4
80-x = 64
x =80-64 = 16
correct option is A
Answer: A
Question: A river 2m deep and 45 m wide is flowing at the rate of 3 kmph the amount of water that runs into the sea per minute is?
Options:
A)4500
B)3889
C)2777
D)1299
E)2791
Rationale: (3000 * 2 * 5)/60
= 4500 M3
Answer: A
Answer: A
Question: A dealer offers a cash discount of 20%. Further, a customer bargains and receives 20 articles for the price of 15 articles. The dealer still makes a profit of 20%. How much percent T above the cost price were his articles marked?
Options:
A)100%
B)80%
C)75%
D)66+2/3%
E)50%
Rationale: Good question...2:11 min
Marked Price (M) = Cost Price (C) + Mark up...(EQN. A)
Selling price = 20% Discount over M = 0.8*M
Given that, a customer bargains and receives 20 articles for the price of 15 articles-->*afurther loss of 25%to the dealer--> BUT aNET PROFIT of 20%over cost price (C)
0.75* 0.8 * M =1.2 * C
Hence, M/C = 2/1 = 200%=T
From Eqn. A , (C + Mark up)/C = 200% -->Mark up / C = 100%
Ans. A
Answer: A
Question: Given a Number 123456, from this number put any three values in numerator and remaining three are in denominator. So how many values you can make from this number less than 1/5.
Options:
A)2
B)6
C)7
D)87
E)81
Rationale: Explanation:
If the given value is 120, then denominator should be slightly greater than 600. If for 130, it is 650. So if we take numerator as 132, then denominator should be greater than 660 which is not possible as we have only 5 and 4 available. So numerator is less than 130. The following numbers are possible.
123/654, 123/645, 124/635, 124/653, 125/634, 125/643.
Answer:D
Answer: D
Question: A trader sells 85 meters of cloth for Rs. 8925 at the profit of Rs. 15 per metre of cloth. What is the cost price of one metre of cloth?
Options:
A)21
B)28
C)90
D)26
E)11
Rationale: Explanation:
SP of 1m of cloth = 8925/85 = Rs. 105
CP of 1m of cloth = SP of 1m of cloth - profit on 1m of cloth
= Rs. 105 - Rs. 15 = Rs. 90.
Answer: C
Answer: C
Question: 10 camels cost as much as 24 horses, 16 horses cost as much as 4 oxen and 6 oxen as much as 4 elephants. If the cost of 10 elephants is Rs.130000, find the cost of a camel?
Options:
A)s.9800
B)s.3800
C)s.9800
D)s.5200
E)s.6880
Rationale: Cost of the camel = P
10 camels = 24 horses
16 horses = 4 oxen
6 oxen = 4 elephants
10 elephants = Rs.130000
P = Rs.[(24 * 4 * 4 * 130000)/(10 * 16 * 6 * 10)]
P = Rs.(49920000/9600) => P = Rs.5200
Answer:D
Answer: D
Question: If (1/5)^m * (1/4)^2 = 1/((10)^4), then m =
Options:
A)4
B)5
C)6
D)3
E)2
Rationale: 1/5^m *1/4^2= 1/ 2^4*5^4
2^4*5^4/2^4 =5^m or 5^4 =5^m
therefore m=4
A
Answer: A
Question: How many 1's are there preceded by 2 but not followed by 7?
5 9 3 2 1 7 4 2 6 9 7 4 2 1 3 2 8 7 4 1 3 8 3 2 5 6 7 4 3 9 5 8 2 0 1 8 7 4 6 3
Options:
A)4
B)5
C)6
D)1
E)9
Rationale: 2 1 3
Only at these places 1 is preceded by 2 but not followed by 7
Answer: D
Answer: D
Question: What least number must be added to 1056, so that the sum is completely divisible by 23 ?
Options:
A)2
B)3
C)18
D)21
E)None of these
Rationale: 23) 1056 (45
92
---
136
115
---
21
---
Required number = (23 - 21)
= 2.
Answer: A
Answer: A
Question: A certain car dealership offers its newest model in ten exterior and ten interior colors. If the seven interior colors are identical to the seven exterior colors, and the dealership sells every pair of colors except those that would result in a car with an identically colored interior and exterior, how many different color combinations are possible?
Options:
A)45
B)81
C)90
D)10!/2!
E)10!
Rationale: I lined up the 10 different colours for Exterion and Interior like this:
E: A B C D E F G H I J
I: A B C D E F G H I J
I calculated the number of combinations: 10*10= 100 combinations.
But, from these 100 we need to delete sth: the same colours.
There are 10 possible pairs of coulours that will be the same. So, I deleted these 10 pairs from 100, resulting in 45.
Mind here, that the 10 do not result in 20 colours, because 1 pair is one unit that is not allowed. So, 10 units are not allowed (surprised that 80 wasn't among the answer options to confuse test takers...).
A
Answer: A
Question: In a group of 25 factory workers, 17 have brown eyes. Six of the women do not have brown eyes. How many of the 11 men have brown eyes.
Options:
A)10
B)9
C)8
D)7
E)4
Rationale: Total number of worker (M+W): 25
No. of men (M): 11 (Inferred fromHow many of the 11 men)
No. of women (W): 14
Total no. of workers who have brown eyes (B): 17
No. of women who do not have brown eyes: 6
Therefore, no. of women who have brown eyes: W - 6 = 14 - 6 = 8
Remaining 9 are men. (B - 8= 17 - 8= 9)
So 9 out of 11 men have brown eyes.
B
Answer: B
Question: The ratio of two numbers is 3:4 and their sum is 28. The greater of the two numbers is?
Options:
A)8
B)10
C)16
D)18
E)22
Rationale: 3:4
Total parts = 7
= 7 parts --> 28 (7 × 4 = 28)
= 1 part ---->4 (1 × 4 = 4)
= The greater of the two number is = 4
= 4 parts ----> 16 (4 × 4 = 16)
C
Answer: C
Question: If Q is a positive integer, which of the following must be odd?
Options:
A)Q+1
B)Q^2+Q
C)Q^2+Q+1
D)x^2−1
E)3x^2−3
Rationale: A. Q+1 = can be odd or even. Since O + O =E or E + O = O
B. Q^2 + Q = Q(Q+1). Since from the above derivation we already know the term Q+1 can be Odd or Even, directly substitute here. Q(ODD) = Even (When Q is Even) or Q(EVEN) = EVEN [When Q is ODD]
C. Here's the answer. Since we know the term Q^2 + Q can always take a EVEN number, EVEN + 1 = ODD
Hence C.
Answer: C
Question: Set S consists of all prime numbers less than 10. If two numbers are chosen from et S at random, what is the probability that the product of these numbers will be greater than the product of the numbers which were not chosen?
Options:
A)1/3
B)2/3
C)1/2
D)7/10
E)4/5
Rationale: Prime integers below 10: 2, 3, 5, 7
Total outcomes: Number of ways you can choose 2 from 4 = 4C2=6pairs4C2=6pairs
No. of ways for Event: Pairs that will have products greater than product of pairs not selected i.e. (3,5), (3,7), (5,7) =3pairs=3pairs
Probability = number of ways/Total outcomes =3/6=1/2=3/6=1/2
Hence choice(C) is correct.
Answer: C
Question: A paint store mixes 3/4 pint of red paint and 2/3 pint of white paint to make a new paint color called Perfect Pink. How many pints of red paint would be needed to make 36 pints of Perfect Pink paint?
Options:
A)9
B)16
C)19
D)25 1/3
E)28 1/2
Rationale: 3/4 pint is required to make 3/4 + 2/3 = 17/12 pint of perfect pink
so 17/12 pint requires 3/4 pint of red..
1 pint will require 3/4 * 12/17=9/17..
36 pints will require 9/17 * 36= 19 pints..
C
Answer: C
Question: How many combinations of three letters taken from letters (b, b, c, c, d,d) are possible?
Options:
A)12
B)13
C)5
D)6
E)7
Rationale: So 3C3 for bcd - 1 choice
2 more for dd(b,c )
2 more for bb(d,c )
2 more for cc(d,b )
total 7
Ans :E
Answer: E
Question: There are 6 more women than there are men on a local co-ed softball team. If there are a total of 16 players on the team, what is the ratio of men to women?
Options:
A)10/16
B)6/16
C)4/16
D)6/10
E)5/11
Rationale: w = m+6
w+m = 16
m+6+m = 16
2m = 10
m = 5
w = 11
ratio:5:11
Ans: E
Answer: E
Question: A quantity of tea is sold at Rs. 5.75 per kilogram. The total gain by selling the tea at this rate is Rs. 60. Find the quantity of tea being sold if a profit of 15% is made on the deal.
Options:
A)80kg.
B)90kg.
C)70kg.
D)60kg.
E)50kg.
Rationale: say total cost price of tea is x.
then total profit at a rate of 15% is=(15x/100)
according to question,
15x/100=60
so x=400
c.p of the tea is 400.so total selling price will be=(400+60)=460
so the quantity of the tea will be=(460/5.75)=80kg.
ANSWER:A
Answer: A
Question: Last year, sales at Company Dopler were 10% greater in February than in January, 5% less in March than in Feb, 5% greater in April than in March, 10% less in May than in April, and 10% greater in June than in May. In which month were sales closest to Jan?
Options:
A)Feb
B)April
C)Mar
D)May
E)June
Rationale: Jan = $100
10% greater in February than in January ---> Feb = $110
10% less in March than in Feb ---> Mar = $99
5% greater in April than in March ---> Apr = $103.95
10% less in May than in April ---> May $93.55
10% greater in June than in May --->Jun = $102.90
Answer : C
Answer: C
Question: A watch passes through three hands and each person gains 25%. If the third person sells it for $375, what did the first person pay for it?
Options:
A)$184
B)$188
C)$192
D)$196
E)$200
Rationale: 1.25*1.25*1.25 * original price = 375
(5/4)^3 * original price = 375
original price = 64*375 / 125 = $192
The answer is C.
Answer: C
Question: A train 280 m long, running with a speed of 63 km/hr will pass a tree in?
Options:
A)17 sec
B)16 sec
C)18 sec
D)14 sec
E)12 sec
Rationale: Speed = 63 * 5/18
= 35/2 m/sec
Time taken = 280 * 2/35
= 16 sec
Answer: B
Answer: B
Question: What approximate value should come in the place of question mark(?) in the following equation?
98.98 ÷ 11.03 + 7.014 × 15.99 = (?)2
Options:
A)131
B)144
C)12
D)121
E)11
Rationale: 98.98 ÷ 11.03 + 7.014 × 15.99 = (?)2
Suppose ? = x
Then 99 ÷ 11 + 7 × 16 + ≈ 121
(taking approximate value)
∴ x = 11
Answer E
Answer: E
Question: The value of a machine depreciates at 24% per annum. If its present value is $1,50,000, at what price should it be sold after two years such that a profit of $24,000 is made?
Options:
A)$250640
B)$430640
C)$120640
D)$110640
E)$150640
Rationale: The value of the machine after two years = 0.76 * 0.76 * 1,50,000 = $86,640
SP such that a profit of $24,000 is made = 86,640 + 24,000 = $1,10,640
D
Answer: D
Question: You and your friend are playing Russian Roulette. Of course, the gun is filled with fake pellets. Three bullets are placed inside three consecutive chambers. The cylinder is then spun once. It won't be spun again.
As per the rules, the gun will be passed from one person to other until a pellet is shot. If you want to win this game, would you go first or second ?
Options:
A)1st
B)3rd
C)4th
D)2nd
E)5th
Rationale: D
2nd
When the cylinder is spun for the first and last time, the following six outcomes are possible:
First:
First chamber is fired first. The first player loses.
Second:
Second chamber is fired first. The first player loses.
Third:
Third chamber is fired first. The first player loses.
Fourth:
Fourth chamber is fired first. The second player loses. (First shot, player 1, chamber 4 empty. Second shot player 2, chamber 5, empty. Third shot player 1, chamber 6 empty. Fourth shot player 2, chamber 1 not empty.)
Fifth:
Fifth chamber is fired first. The first player loses. (First shot, player 1, chamber 5 empty. Second shot player 2, chamber 6, empty. Third shot player 1, chamber 1 not empty.)
Sixth:
Sixth chamber is fired first. The second player loses. (First shot, player 1, chamber 6 empty. Second shot, player 2, chamber 1, not empty)
Thus, if you analyze, you will find that the second player has a 4/6 chance of winning. Therefore if you want to win the game, going second gives you better shot at it.
Answer: D
Question: If the first half of the English alphabet is reversed and then next portion of English alphabet is reversed so as 'A' takes the portion of 'M' and 'N' takes the portion of 'z' then which letter will be 6th to the left of 17th letter to the right of 7th leter from the left?
Options:
A)Y
B)V
C)J
D)G
E)K
Rationale: Explanation:
6th to the left of 17th letter to the right of 7th letter from the left = 6th to the left of (17+7 =) 24th letter from the left = (24-6 =) 18th letter from the left.
Thus, we have to count from the left and we have to find out 18th letter from the left that falls into the second section of English alphabet.
Here, both the first half and the second half of the English alphabet have been reversed and we have to count from the left end, then the required letter can be found out using the formula given below. Suppose , the first and the second reversed sections of the English alphabet are and respectively.Then,
The required letter =
Therefore, The required letter = 26 + 13 + 1 - 18 = 22 = V
Answer: B
Answer: B
Question: Sum of the numbers from 1 to 45 is
Options:
A)1789
B)1035
C)1025
D)1009
E)None of these
Rationale: Explanation: Sum of first n natural numbers = 1 + 2 + 3 + ..... n = n(n+1)/2
Substitute n = 45.
So S20=45Ã—46/2=1035
Correct Option: B
Answer: B
Question: Maxwell leaves his home and walks toward Brad's house at the same time that Brad leaves his home and runs toward Maxwell's house. If the distance between their homes is 60 kilometers, Maxwell's walking speed is 4 km/h, and Brad's running speed is 6 km/h, what is the distance traveled by Brad?
Options:
A)16
B)36
C)20
D)24
E)30
Rationale: Time taken = Total Distance / Relative Speed
Total Distance = 60 kms
Relative Speed (Opposite side) (As they are moving towards each other speed would be added ) = 6+ 4 = 10 kms/hr
Time taken = 60 / 10 = 6 hrs
Distance traveled by Brad = Brad's speed * time taken = 6 * 6 = 36 kms... Answer - B
Answer: B
Question: Two brother X and Y appeared for an exam. The probability of selection of X is 1/7 and that of B is 2/5. Find the probability that both of them are selected.
Options:
A)2/69
B)2/60
C)2/63
D)2/35
E)2/38
Rationale: Explanation:
Let A be the event that X is selected and B is the event that Y is selected.
P(A) = 1/7, P(B) = 2/5.
Let C be the event that both are selected.
P(C) = P(A) Ã— P(B) as A and B are independent events:
= (1/7) Ã— (2/5) = 2/35
Answer: D) 2/35
Answer: D
Question: In a division, a student took 42 as divisor instead of 36. his answer was 24 . The correct answer is-
Options:
A)42
B)32
C)48
D)28
E)38
Rationale: X/42 = 24.
X = 24 *42.
So correct answer would be,
(24 *42) /36 = 38.
ANSWER : E
Answer: E
Question: An woman swims downstream 81 km and upstream 36 km taking 9 hours each time; what is the speed of the current?
Options:
A)0.5
B)1.5
C)2.5
D)3.5
E)4.5
Rationale: 81 --- 9 DS = 9
? ---- 1
36 ---- 9 US = 4
? ---- 1 S = ?
S = (9 - 4)/2 = 2.5
Answer:C
Answer: C
Question: A train speeds past a pole in 15 sec and a platform 140 m long in 25 sec, its length is?
Options:
A)50 m
B)150 m
C)210 m
D)300 m
E)None of these
Rationale: Let the length of the train be x m and its speed be y m/sec.
Then, x/y = 15 => y = x/15
(x + 140)/25 = x/15 => x = 210 m.
ANSWER:C
Answer: C
Question: The average of six number is 3.99. The average of two of them is 3.4, while the average of the other two is 3.85. what is the average of the remaining two number ?
Options:
A)4.5
B)4.6
C)4.72
D)4.8
E)None of these
Rationale: solution:
Sum of the remaining two numbers = (3.99 × 6) - [(3.4 × 2) + (3.85 ×2)]
=23.94 -(6.8 + 7.7) = 23.94 - 14.5 = 9.44.
∴ Required average =9.44/2 = 4.72 Answer C
Answer: C
Question: 50 men can complete a work in 65 days.Five days after started the work, 20 men left the group. In how many days can the remaining work be completed?
Options:
A)277
B)268
C)260
D)276
E)100
Rationale: After 5 days, the following situation prevails.
50 men can complete the work in 60 days.
30 men can complete the work in ? days.
M1 D1 = M2 D2
=> 50 * 60 = 30 * D2
=> D2 = (50 * 60)/30 = 100 days.
Answer: E
Answer: E
Question: In how many ways can an answer key for a quiz be written if the quiz contains 3 true-false questions followed by 3 multiple-choice questions with 4 answer choices each, if the correct answers to all true-false questions cannot be the same?
Options:
A)164
B)224
C)280
D)384
E)476
Rationale: There are 2^3 = 8 possibilities for the true-false answers.
However we need to remove two cases for TTT and FFF.
There are 4*4*4 = 64 possibilities for the multiple choice questions.
The total number of possibilities is 6*64 = 384.
The answer is D.
Answer: D
Question: How many of the following numbers are divisible by 132 ?
264, 396, 462, 792, 968, 2178, 5184, 6336
Options:
A)4
B)5
C)6
D)7
E)8
Rationale: 132 = 4 x 3 x 11
So, if the number divisible by all the three number 4, 3 and 11, then the number is divisible by 132 also.
264 -> 11,3,4 (/)
396 -> 11,3,4 (/)
462 -> 11,3 (X)
792 -> 11,3,4 (/)
968 -> 11,4 (X)
2178 -> 11,3 (X)
5184 -> 3,4 (X)
6336 -> 11,3,4 (/)
Therefore the following numbers are divisible by 132 : 264, 396, 792 and 6336.
Required number of number = 4.
Answer:A
Answer: A
Question: Merry and Mich play a card game. In the beginning of the game they have an equal number of cards. Each player, at her turn, gives the other a third of her cards. Mich plays first, giving Merry a third of her cards. Merry plays next, and Mich follows. Then the game ends. Merry ended up with 14 more cards than Mich. How many cards did each player have originally?
Options:
A)60
B)58
C)56
D)55
E)54
Rationale: Game Mich Merry
Initially 54 54 assume
After game 1 36 72
After game 2 60 48
After game 3 40 68
Now Merry has 28 cards more than Mich. This option gives us exactly what number of cards they had initially.
So the answer is E
Answer: E
Question: On dividing 172 by a number, the quotient is 10 and the remainder is 2. Find the divisor.
Options:
A)9
B)11
C)13
D)15
E)17
Rationale: d = (D-R)/Q
= (172 - 2)/10
= 170/10 = 17
E
Answer: E
Question: 10^190 - 10^9 = Which of the following best approximates the value of the expression above?
Options:
A)10^170
B)10^180
C)10^160
D)10^181
E)10^190
Rationale: 10^190 - 10^9 =
Which of the following best approximates the value of the expression above?
Yes, answer 10^190 is correct. Note that we need approximate value of the given expression and as 10^(190) is much larger number than 10^(9) then 10^(9) is pretty much negligible in this case: 10^(190)-10^(9)=~10^(190).
Answer : E
Answer: E
Question: If 5 cars park in 5 parking place.there are 3 red colour car,1 blue and 1 green then how many ways we can arrange the cars differently
Options:
A)10
B)20
C)30
D)40
E)50
Rationale: total car=5
place =5
means cars are place any 5 position means its 5!=120
but 3 cars r red and 1 blue and 1 green
then its arrange 3!,1!,1!
so,
=120/6*1*1
=20
ANSWER:B
Answer: B