divelab/Sys2Bench huggingface dataset:
Question: A salesman`s commission is 5% on all sales upto Rs.10,000 and 4% on all sales exceeding this.He remits Rs.31,100 to his parent company after deducing his commission . Find the total sales.
Options:
A)32500
B)33400
C)44000
D)40000
E)45000
Rationale: Let his total sales be Rs.x.Now(Total sales) – (Commission )=Rs.31,100
x-[(5% of 10000 + 4% of (x-10000)]=31,100
x-[((5/100)*10000 + (4/100)*(x-10000)]=31,100
x-500-((x-10000)/25)=31,100
x-(x/25)=31200  24x/25=31200x=[(31200*25)/24)=32,500.
Total sales=Rs.32,500
ANSWER A
Answer: A
Question: What is the remainder when 263251 is divided by 9?
Options:
A)8
B)3
C)6
D)1
E)9
Rationale: If the sum of the digits of a number is divisible by 9, the number will be divisible by 9.
2 + 6 + 3 + 2 + 5 + 1 = 19
The nearest multiple of 9 is 18.
19 - 18 = 1.
ANSWER:D
Answer: D
Question: A set of numbers has the property that for any number x in the set, x+4 is also in the set. If -4 is in the set, which of the following must also be in the set
1. 0
2. -8
3. 8
Options:
A)1 only
B)2 only
C)1 and 2 only
D)2 and 3 only
E)1,2 and 3
Rationale: If X is in the set than X+ 4 is also in the set
If -4 in the set than
-4+4= 0 is also in the set
Since + 4 is Present, 4 + 4= 8 Is also present in the set .
Therefore Ans C
Answer: C
Question: A began business with Rs.45000 and was joined afterwards by B with Rs.5400. When did B join if the profits at the end of the year were divided in the ratio of 2:1?
Options:
A)7
B)8
C)9
D)6
E)5
Rationale: 45*12 : 54*x = 2: 1
x = 5
12 -5 = 7.Answer: A
Answer: A
Question: If 40% of a number is greater than 80% of 5 by 2, what is the number?
Options:
A)3
B)15
C)20
D)2
E)5
Rationale: Explanation:
40/100 * x - 80/100 * 5 = 2
40/100 * x - 4 = 2
40/100 * x = 6
x = 6 * 100 / 40
x = 15
Answer: Option B
Answer: B
Question: If a coin is flipped, the probability that the coin will land tails is 1/2. If the coin is flipped 5 times, what is the probability that it will land tails up on the first 2 flips and not on the last 3 flips?
Options:
A)3/5
B)1/32
C)1/5
D)1/4
E)1/2
Rationale: (1/2) * (1/2) * (1/2) * (1/2) * (1/2) = 1/32 Answer: B
Answer: B
Question: If a is a positive integer then 4^(2a) + (64^a)/(2^(2a)) =
Options:
A)0
B)16^16
C)8^15
D)2 × 16^a
E)18^a
Rationale: 4^(2a) + 64^a/ 2^(2a) = 16^a + 36^a/4^a = 16^a + (64/4)^a = 16^a + 16^a = 2 × 16^a
Answer : D
Answer: D
Question: There are 5 locks and 5 keys and each of the 5 keys matches each of the 5 locks. What is the minimum and the maximum trial numbers of attempts needed to confirm that each of the 5 keys matches each of the 5 locks?
Options:
A)5,15
B)4,15
C)5,10
D)4,10
E)5,20
Rationale: the actual number of tries that we need to "unlock" all the lockers, and got into the trap 5-15.
of course, if we do not need to unlock the lockers, but just simply to check..
minimum # of attempts is 4.
maximum is 10,
ANS:D
Answer: D
Question: A and B starts a business with Rs.8000 each, and after 4 months, B withdraws half of his capital . How should they share the profits at the end of the 19 months?
Options:
A)18:11
B)18:15
C)18:19
D)18:121
E)19:11
Rationale: A invests Rs.8000 for 19 months, but B invests Rs.8000 for the first 4 months and then withdraws Rs.4000. So, the investment of B for remaining 14 months is Rs.4000 only.
A : B
8000*19 : (8000*4) + (4000*14)
152000 : 88000
A:B = 19:11.Answer:E
Answer: E
Question: In the set of positive integers from 1 to 60, what is the sum of all the odd multiples of 5?
Options:
A)180
B)185
C)190
D)160
E)165
Rationale: 1 - 60
5 - 15 - 25 - 35 - 45 are valid multiples of 5. Add them
5+15+25+35+45+55 =180
A
Answer: A
Question: Two bus tickets from city A to B and three tickets from city A to C cost Rs. 154 but three tickets from city A to B and two tickets from city A to C cost Rs. 146. What are the fares for cities B and C from A ?
Options:
A)s. 4, Rs. 23
B)s. 13, Rs. 17
C)s. 15, Rs. 14
D)s. 17, Rs. 13
E)s. 26, Rs. 34
Rationale: If fares for cities B and C from A are x and y respectively, then
2x+3y=154 or 6x+9y= 462
3x+2y =146 or 6x+4y= 292
subtracting
5y = 170
y= Rs 34
Hence E. Rs. 26, Rs. 34
ANSWER:E
Answer: E
Question: If the difference between the length and breadth of a rectangle is 23 m and its perimeter is 206 m, what is its area?
Options:
A)2520
B)2510
C)2525
D)2025
E)2020
Rationale: l-b=23...(1)
perimeter = 206
2(l=b)= 206
l+b = 103...(2)
(1)+(2)
2l=23+103=126
l =126/2=63 metre
Substituting the value of l in (1), we get
63-b=23
b=63-23=40 metre
area=lb=63Ã—40 =2520 m2
ANSWER:A
Answer: A
Question: If Yury has been writing programming code for 11 hours at a rate of 5 lines of code per 20 seconds, how many lines of code has he written?
Options:
A)126(10^2)
B)126(10^3)
C)12.6(10^5)
D)1.26(10^7)
E)99(10^2)
Rationale: 5 LINES IN 20 SECONDS
SO FOR 1 MINUTE ( 5 X 3 = 15 LINES )
I HOUR = 60 MINUTES
15 X 60 = 900 LINES IN AN HOUR
11 HOURS = 900 X 11 = 99(10^2)
ANSWER E
Answer: E
Question: The sum of five numbers is 750. The average of the first two numbers is 75 and the third number is 130. Find the average of the two numbers?
Options:
A)220
B)225
C)230
D)235
E)240
Rationale: Let the five numbers be P, Q, R, S and T.
=> P + Q + R + S + T = 750.
(P + Q)/2 = 75 and R = 130
P + Q = 150 and R = 130
P + Q + R = 280
S + T = 750 - (P + Q + R) = 470
Average of the last two numbers
= (S + T)/2 = 235
Answer:D
Answer: D
Question: The number of sequences in which 7 players can throw a ball, so that the youngest player may not be the last is?
Options:
A)4389
B)8369
C)4320
D)4356
E)3537
Rationale: x Not younger_______ ↑
The last ball can be thrown by any of the remaining 6 players. The first 6 players can throw the ball in ⁶P₆ ways.
The required number of ways = 6(6!) = 4320
Answer:C
Answer: C
Question: If Jake loses 8 pounds, he will weigh twice as much as his sister Kendra. Together they now weigh 287 pounds. What is Jake’s present weight, in pounds?
Options:
A)178
B)182
C)186
D)190
E)194
Rationale: J + K = 287 and so K = 287 - J
J - 8 = 2K
J - 8 = 2(287-J)
3J = 582
J = 194
The answer is E.
Answer: E
Question: A number x is mistakenly divided by 10 instead of being multiplied by 10. what is the percentage error in the result?
Options:
A)-99%
B)-100%
C)+99%
D)+100%
E)None
Rationale: Solution: Actual result = 10x
By mistake it has been divided by 10 = x /10
% change = [10x -(10 /x) /10x] *100 = 99
= - 99%.
Since, actual value is greater than the wrong value.
Alternatively,
Let, x = 10
Actual result = 10 * 10 = 100
wrong result = 10 /10 = 1.
Change = (1 -100) = -99
% change = -99%.
Answer: Option A
Answer: A
Question: A man buys an item at Rs. 1200 and sells it at the loss of 20 percent. Then what is the selling price of
that item
Options:
A)Rs. 660
B)Rs. 760
C)Rs. 860
D)Rs. 960
E)None of these
Rationale: Explanation:
Here always remember, when ever x% loss,
it means S.P. = (100 - x)% of C.P
when ever x% profit,
it means S.P. = (100 + x)% of C.P
So here will be (100 - x)% of C.P.
= 80% of 1200
= 80/100 * 1200
= 960
Answer: D
Answer: D
Question: 10 books are placed at random in a shelf. The probability that a pair of books will always be together is?
Options:
A)1/7
B)1/9
C)1/5
D)1/8
E)1/2
Rationale: 10 books can be rearranged in 10! ways consider the two books taken as a pair then number of favourable ways of getting these two books together is 9! 2!
Required probability = 1/5
Answer: C
Answer: C
Question: An automobile parts supplier charges $25 per package of gaskets. When a customer orders more than 10 packages of gaskets, the supplier charges 4/5 the price for each package in excess of 10. During a certain week, the supplier sold 60 packages of gaskets. If 25 percent of the gaskets went to Company X, 15 percent to Company Y, and the rest to Company Z, what was the total amount, in dollars, that the parts supplier received in payment for the gaskets?
Options:
A)1305
B)1545
C)1375
D)1345
E)1455
Rationale: $25 per packet of gasket in case a customer orders less than 10
in case a customer orders > 10 price per gasket = 25*4/5=20
a certain week the supplier sold 60 gasket
1.he sold 25 % of the gaskets to X = 15 gaskets = 25*10 + 20 *5 = 250 + 100 = 350
2.he sold 15 % of the gaskets to Y = 9 gaskets = 25*9= 225
3.he sold remaining 60% to z =36 gaskets = 25*10 =250 + 20*26=770
thus ,total money earned
350+225+770 = 1345
Answer is D
Answer: D
Question: Cost is expressed by the formula tb^4. If b is doubled, the new cost is what percent T of the original cost?
Options:
A)T=200
B)T=600
C)T=800
D)T=1600
E)T=50
Rationale: Original Cost C1=t1*b1^4
New Cost C2=t2*b2^4....only b is doubled so t2=t1 and b2=2b1
C2=t2*(2b1)^4
=16(t1 * b1^4)
=16C1
16 times C1=>1600% of C1
Ans D=1600
Answer: D
Question: Find the value of 72519 x 9999 = m?
Options:
A)234567745
B)674225565
C)570909643
D)725117481
E)768965324
Rationale: 72519 x 9999 = 72519 x (10000 - 1)
= 72519 x 10000 - 72519 x 1
= 725190000 - 72519
= 725117481
D
Answer: D
Question: A is twice as good a workman as B and together they complete a work in 12 days. In how many days A alone can do the work?
Options:
A)32
B)33
C)34
D)35
E)36
Rationale: A’s one day’s work : B’s one day’s work= 2:1
(A+B)’s one day’s work= 1/12
B’s one day’s work= 1/12 *1/3 = 1/36
B alone can do the work in 36 days
ANSWER:E
Answer: E
Question: In how many ways can a group of 4 men and 2 women be made out of a total of 6 men and 4 women?
Options:
A)63
B)67
C)70
D)90
E)80
Rationale: We need to select 4 men from 6 men and 2 women from 4 women. Number of ways to do this= 6C4 × 4C290D)
Answer: D
Question: What will come in place of the x in the following Number series? 11, 14, 19, 22, 27, 30, x
Options:
A)29
B)31
C)23
D)35
E)39
Rationale: (D)
The pattern is + 3, + 5, + 3, + 5, …………
So the missing term is = 30 + 5 = 35.
Answer: D
Question: what is the angle between the hands of a clock when time is 10:20?
Options:
A)90deg
B)75deg
C)45deg
D)15deg
E)30deg
Rationale: Angle between two hands =
20h - 11/2 m = 20*10 - 20*11/2 = 200 - 110 = 90deg
ANSWER:A
Answer: A
Question: Two hoses are pouring water into an empty pool. Hose 1 alone would fill up the pool in 6 hours. Hose 2 alone would fill up the pool in 5 hours. How long would it take for both hoses to fill up two-thirds of the pool?
Options:
A)5/12 hours
B)5/8 hours
C)20/11 hours
D)12/7 hours
E)12/5 hours
Rationale: Hose 1 would fill the pool alone in 6 hours
i.e. 1 Hour work of Hose 1 = 1/6
Hose 2 would fill the pool alone in 5 hours
i.e. 1 Hour work of Hose 2 = 1/5
i.e. 1 Hour work of Hose1 and Hose2 together = (1/6)+(1/5) = (11/30)
i.e. (11/30) work can be finished by Hose1 and Hose2 together in 1 hour
i.e. (2/3) work can be finished by Hose1 and Hose2 together in 1*(30/11)*(2/3) = 20/11hour
Answer: Option C
Answer: C
Question: The difference between the simple interest and the compound interest (compounded yearly)earned on a sum of money at the end of four years at the rate of 10 percent per annum is Rs.256.40. Find the sum.
Options:
A)Rs.6,000
B)Rs.4,000
C)Rs.5,000
D)Rs.4500
E)Rs.5500
Rationale: SI=(P*10*4)/100= 4p/10
CI=P(1+10/100)^4-P =4641P/100
CI-SI=
4641P/100-4P/100=256.40
P=4000
ANSWER:B
Answer: B
Question: The cash realised on selling a 14% stock is Rs.105.25, brokerage being 1/4% is?
Options:
A)366
B)106
C)102
D)105
E)122
Rationale: Cash realised= Rs. (105.25 - 0.25)
= Rs. 106.
Answer: D
Answer: D
Question: Tom began driving from home on a trip averaging 30 miles per hour. How many miles per hour must Carla drive on average to catch up to him in exactly 3 hours if she leaves 30 minutes after Tom?
Options:
A)35
B)55
C)39
D)40
E)60
Rationale: Carla starts 30 minutes later and it takes 3 hr for carla to meet Tom
So Tom total time travelled = 3hr + 30 minutes
Tom distance = 30 * (3 1/2) = 105
so carla need to travle 105 to meet Tom in 3 hrs
speed of carla = 105/3 = 35 miles per hour
Answer is A
Answer: A
Question: The simple interest on Rs.12000 at a certain rate of interest in five years is Rs.7200. Find the compound interest on the same amount for five years at the same rate of interest?
Options:
A)3052.83
B)3052.22
C)3052.08
D)3052.8
E)3052.13
Rationale: R = 100 I / PT
=> R = (100 * 7200)/ (12000 * 5) = 12%
CI = P{ [1 + R /100]n - 1}
= 12000 { [ 1 + 12 / 100]2 - 1}
= Rs.3052.80
Answer: D
Answer: D
Question: The smallest number which when added to 4, the sum is exactly divisible by 24, 36, 48 and 60 is:
Options:
A)327
B)716
C)256
D)299
E)111
Rationale: nation: 2 24 36 48 60 2 12 18 24 30 3 6 9 12 15 2 2 3 4 5 1 3 2 5 ∴ LCM of 24, 36, 48, 60 = 2 × 2 × 3 × 2 × 3 × 2 × 5 = 720. ∴ Required number = 716
Answer:B
Answer: B
Question: The sum of the first 50 positive even integers is 2550. What is the sum R of even integers from 102 to 200 inclusive?
Options:
A)5100
B)7550
C)10100
D)15500
E)20100
Rationale: My solution is:
First 50 even integers:
2
4
6
8
<...>
Integers from 102 to 200
102
104
106
108
<...>
We notice that each integer from the second set is 100 more than the respective integer in the first set. Since we have 50 even integers from 102 to 200, then:
R=2550+(100*50)=7550.B
Answer: B
Question: A train moves fast a telegraph post and a bridge 264 m long in 8 sec and 26 sec respectively. What is the speed of the train?
Options:
A)89
B)23
C)52.8
D)79.2
E)67
Rationale: Let the length of the train be x m and its speed be y m/sec.
Then, x/y = 8 => x = 8y
(x + 264)/26 = y
y = 14.67
Speed = 14.67 m/sec = 14.67 * 18/5 = 52.8 km/hr.
Answer: Option C
Answer: C
Question: If Susan takes 10 seconds to run y yards, how many minutes will it take her to run x yards at the same rate?
Options:
A)xy/10
B)10x/(60y)
C)60xy/10
D)xy/540
E)540x/y
Rationale: The answer is B.
She runs x yards in 10x/y seconds =10x/60y minutes.
Answer: B
Question: For how many values of M, is |||M - 5| -10| -5| = 2?
(Those ls are mods)
Options:
A) 0
B) 2
C) 4
D) 8
E) More than 8
Rationale: I think its 8
|||M-5|-10|-5| =2
let |M-5| = a which makes above
||a-10|-5| =2
let |a-10| = b which makes
|b-5| = 2
now for the above b can take 3, 7
for every b =3 a can have 13, 7
and for b = 7 a can have 17 and 3
so 'a' has four solutions 13, 7, 17 and 3
for a = 13; x has 18 or -8 thus has 2 for every combination hence 4x2 = 8
answer D
Answer: D
Question: Rakesh travelled 1800 kilometre by air which formed 3/5 of the total journey. He travels 1/4 of the trip by car and the remaining trip by train. Find the distance travelled by train.
Options:
A)350
B)450
C)550
D)650
E)None of these
Rationale: Explanation :
3/5 of D = 1800. So D = 3000 km,
so distance travelled by train = 3000 – 1800 – 1/4 of 3000 = 450
Answer – B
Answer: B
Question: If a(a - 6) = 27 and b(b - 6) = 27, where a ≠ b, then a + b =
Options:
A) −48
B) −2
C) 6
D) 46
E) 48
Rationale: i.e. if a =-3 then b = 9
or if a = 9 then b =-3
But in each case a+b = -3+9 = 6
Answer: option C
Answer: C
Question: The average age of the mother and her six children is 12 years which is reduced by 5 years if the age
of the mother is excluded. How old is the mother
Options:
A)40
B)41
C)42
D)43
E)44
Rationale: Answer: Option C
Answer: C
Question: At present, the ratio between the ages of Arun and Deepak is 4:3. After 6 years, Arun's age will be 34 years. What is the age of Deepak at present?
Options:
A)77 years
B)15 years
C)21 years
D)88 years
E)55 years
Rationale: Let the present ages of Arun and Deepak be 4x and 3x years respectively.
Then, 4x + 6 = 34 => x = 7
Deepak's age = 3x = 21 years.
Answer: C
Answer: C
Question: Audrey 4 hours to complete a certain job. Ferris can do the same job in 3hours. Audrey and Ferris decided to collaborate on the job, working at their respective rates. While Audrey worked continuously, Ferris took 2 breaks of equal length. If the two completed the job together in 2 hours, how many minutes long was each of Ferris’ breaks ?
Options:
A)5
B)15
C)17
D)20
E)25
Rationale: Audery and Ferris collective Work rate:
1/4 + 1/3 = 7/12
Collective work Time = 12/7 = 1.7 Hrs
Job Was actually done in = 2 (Includes breaks)
Breaks = Actual time taken - Collective work time
= 2 - 1.7
= .3 Hrs = 1/2
so ferrais took 2 breaks
=.3/2=.15 hrs = 15 m
so Answer is B) 15 mins
Answer: B
Question: Write 860,000,000,000 in scientific notation.
Options:
A)8.6 * 10^11
B)800.900 * 10^11
C)8.900 * 10^11
D)80.9000* 10^11
E)08.900 * 10^11
Rationale: a * 10 n , where a is a real number such that 1 * |a| < 10 and n is an integer.
860,000,000,000 = 8.6* 100,000,000,000 = 8.6 * 10 11**
correct answer A
Answer: A
Question: A person buys an article at Rs.500. At what price should he sell the article so as to make a profit of 40%?
Options:
A)700
B)882
C)772
D)652
E)271
Rationale: Cost price = Rs.500
profit = 40% of 500 = Rs.200
Selling price = Cost price + Profit
= 500 + 200 = 700
Answer:A
Answer: A
Question: A women purchased 3 towels @ Rs.100 each, 5 towels @ Rs.150 each and two towels at a certain rate which is now slipped off from his memory. But she remembers that the average price of the towels was Rs.170. Find the unknown rate of two towels?
Options:
A)A)400
B)B)650
C)C)500
D)D)550
E)E)600
Rationale: 10 * 170 = 1700
3 * 100 + 5 * 150 = 1050
1700 – 1050 = 650
B
Answer: B
Question: The simple interest on Rs.12000 at a certain rate of interest in five years is Rs.7200. Find the compound interest on the same amount for five years at the same rate of interest.
Options:
A)3052.89
B)3052.86
C)3092.8
D)3052.8
E)3052.81
Rationale: R = 100 I / PT
=> R = (100 * 7200)/ (12000 * 5) = 12%
CI = P{ [1 + R /100]n - 1}
= 12000 { [ 1 + 12 / 100]2 - 1} = Rs.3052.80.Answer: D
Answer: D
Question: If the radius of a circle is increased by 12%, then the area of the circle
Options:
A)decreases by 25.44%
B)increases by 25.44%
C)no change in area
D)decreases by 12%
E)none
Rationale: A1=pi(100)^2
A2=pi(112)^2
so (A2-A1)/A1*100=25.44
ANSWER:B
Answer: B
Question: Which of the following is the Highest Common Factor of 121, 99 and 77?
Options:
A)8
B)10
C)6
D)14
E)11
Rationale: the Highest Common Factor is 11Ans is :E
Answer: E
Question: A certain car can travel 40 minutes on a gallon of gasoline at 60 miles per hour. If the car had started with a full tank and had 8 gallons of gasoline left in its tank at the end, then what percent of the tank was used to travel 120 miles at 60 mph?
Options:
A)15%
B)20%
C)27.27%
D)30%
E)40%
Rationale: Let, Tank capacity = T gallon
Used Fuel = (T-8) gallons
Distance Travelled (@60 miles/hr) = 80 miles
Distance travelled in 1 gallon = Distance travelled in 40 mins (@60 miles/hr) = (60/60)*40 = 40 miles
Fuel used to travel 120 miles = (120/40) = 3 gallon
i.e. Used fuel = (T-8) = 3 gallon
i.e. T = 10 Gallons
i.e. Used Fuel = (3/11)*100 =27,27%
C
Answer: C
Question: Two trains of equal lengths take 10 sec and 15 sec respectively to cross a telegraph post. If the length of each train be 120 m, in what time will they cross other travelling in opposite direction?
Options:
A)65 sec
B)12 sec
C)77 sec
D)44 sec
E)11 sec
Rationale: Speed of the first train = 120/10 = 12 m/sec.
Speed of the second train = 120/5 = 8 m/sec.
Relative speed = 12 + 8 = 20 m/sec.
Required time = (120 + 120)/20 = 12 sec.
Answer: B
Answer: B
Question: John and Tony began business with Rs.12000 and Rs.14000 after 8 months, John withdraws Rs.2000 and Tony withdraws Rs.4000. At the end of the year, their profits amounted to Rs.4500 find the share of Tony.
Options:
A)2375
B)2325
C)2300
D)3375
E)3300
Rationale: (12*8 + 10*4):(14*8 + 10*4)
17:19
19/36 * 4500 = 2375. Answer: A
Answer: A
Question: If y is the smallest positive integer such that 7,700 multiplied by y is the square of an integer, then y must be
Options:
A)29
B)58
C)63
D)74
E)77
Rationale: 7700= 5*5*2*2*7*11, so we need one 7 and one 11 to make it a square of a number. so 7*11= 77
Ans: E
Answer: E
Question: A completes a work in 3 days and B complete the same work in 6 days. If both of them work together, then the number of days required to complete the work will be?
Options:
A)2 days
B)11 days
C)21 days
D)22 days
E)24 days
Rationale: If A can complete a work in x days and B can complete the same work in y days, then, both
of them together can complete the work in x y/ x+ y days
Therefore, here, the required number of days = 3 Ã— 6/ 9 = 2 days.
Option 'A'
Answer: A
Question: The average age of 10 members of a committee is the same as it was 4 years ago, because an old member has been replaced by a young member. Find how much younger is the new member?
Options:
A)40
B)50
C)60
D)70
E)80
Rationale: Let the members be Old Having age O + other 9 having ages x and New one having age Y
Sum of their ages = (Y + 9 × x) and average = (Y + 9 × x)/10
Before 4 years sum was (O + 9 x – 10 × 4) and average = (O + 9 x – 10 × 4) /10
equating, Y + 9 x = O + 9x – 40
Y = O – 40
Younger is 40 years younger than Old one.
ANSWER:A
Answer: A
Question: By selling 12 pencils for a rupee a man loses 20%. How many for a rupee should he sell in order to gain 20%?
Options:
A)8
B)7
C)6
D)5
E)1
Rationale: Explanation:
80% --- 12
120% --- ?
80/120 * 12 = 8
Answer: A
Answer: A
Question: To asphalt 1km road, 30 men spent 12 days working 8 hours per day. How many days, 20 men will spend to asphalt a road of 2km working 10 hours a day?
Options:
A)28.8
B)30
C)32
D)34
E)36
Rationale: Man-hours required to asphalt 1 km road=30*12*8=2880
Man-hours required to asphalt 2 km road=2880*2=5760
Man-hours available per day=20*10=200
Therefore number of days=5760/200=28.8 days
Ans=A
Answer: A
Question: Kiran is younger than Bineesh by 7 years and their ages are in the respective ratio of 7:9. How old is Kiran?
Options:
A)22.5
B)24.5
C)23.5
D)25.5
E)26.5
Rationale: Let age of Kiran and Bineesh be 7x and 9x respectively
7x=9x−7x=72=3.5
Kiran's age =7x=7×3.5=24.5
Answer is B.
Answer: B
Question: A can do a piece of work in 12 days. He worked for 15 days and then B completed the remaining work in 10 days. Both of them together will finish it in.
Options:
A)12 1/2 days
B)10 1/2 days
C)12 1/3 days
D)10 1/3 days
E)11 1/2 days
Rationale: Explanation:
15/25 + 10/x = 1 => x = 25
1/25 + 1/25 = 2/25
25/2 = 12 1/2 days
Answer A
Answer: A
Question: A man took loan from a bank at the rate of 5% p.a. S.I. After 13 years he had to pay Rs. 1300 interest only for the period. The principal amount borrowed by him was?
Options:
A)1750
B)4000
C)3500
D)2000
E)1000
Rationale: Principal = (100 * 1300) / (5 * 13)
= Rs.2000
Answer: D
Answer: D
Question: If A:B = 1/5: 1/3 B:C = 1/2:1/3 then A:B:C?
Options:
A)9:6:6
B)9:6:8
C)9:6:2
D)9:6:4
E)9:15:10
Rationale: A:B = 1/5:1/3 = 3:5
B:C = 1/2:1/3 = 3:2
--------------------
A:B:C = 9:15:10
Answer:E
Answer: E
Question: When x is even, [x] = x/2 + 1, when x is odd [x] = 2x + 1 then [7]*[8] = ?
Options:
A)[22]
B)[44]
C)[75]
D)[88]
E)[90]
Rationale: [7]*[8]=(7*2+1)(8/2+1)
=[75].
Ans -C
Answer: C
Question: there are two cubes with ratio between volume is 125:64. then what is the value of length of each cube?
Options:
A)25:16
B)16:25
C)4:5
D)5:4
E)150:96
Rationale: given
6a12:a22=150:96
then a12:a22=25:16
a1:a2=5:4
so the answer is D
Answer: D
Question: A lemonade stand sold only small and large cups of lemonade on Tuesday. 3/5 of the cups sold were small and the rest were large. If the large cups were sold for 7/24 as much as the small cups, what fraction of Tuesday's total revenue was from the sale of large cups?
Options:
A)(a) 7/16
B)(b) 7/15
C)(c) 10/21
D)(d) 17/35
E)(e) 7/43
Rationale: This problem is very good example how easy and quick plug-in method might be.
Let the total # of cups be 10.
# of small cups sold 3/5*10=6;
# of large cups sold 10-6=4;
Let the price of small cup be $6, then the price of larges cup would be 7/24*6=$7/4;
Revenue from small cups: 6*$6=$36;
Revenue from large cups cups: 4*$7/4=$7;
Fraction of total revenue from large cups: 7/(36+7)=7/43.
Answer:E.
Answer: E
Question: Mark purchases a dozen items for $240.00. If Mark sells each item for $30.00 what is his markup%?
Options:
A)10
B)50
C)75
D)100
E)125
Rationale: C.P.=240/12=20
S.P.=30
markup%=((S.P.-C.P.)/C.P.)*100=((30-20)/20)*100=50%
ANSWER:B
Answer: B
Question: If a particular player is always chosen, in how many ways can a cricket-be chosen out of 15 players?
Options:
A)1100
B)1134
C)1240
D)1340
E)1365
Rationale: A particular player is always chosen, it means that 10 players are selected out of the remaining 14 players.
=. Required number of ways = 14C10 = 14C4
= 14!/4!x19! = 1365
E
Answer: E
Question: 45 x ? = 40% of 900
Options:
A)16.2
B)4
C)5
D)500
E)8
Rationale: Answer
Let 45 x A = (40 x 900)/100
∴ A = (40 x 9)/45 = 8
Correct Option: E
Answer: E