divelab/Sys2Bench huggingface dataset:
Question: A woman has three blouses of different colors, four skirts of different colors, and two different pairs of shoes. She refuses to wear her pink blouse with her green skirt. How many different blouseskirt-shoe combinations could she wear?
Options:
A)8
B)12
C)22
D)17
E)18
Rationale: total ways = 3*4*2=24..
now its better to find the ways in which the pink blouse and green skirt are together and subtract from total to get the answer..
the ways in which the pink blouse and green skirt are together=1*1*2=2..
total ways =24-2=22..
ANSWER:C
Answer: C
Question: In the above number, A and B represent the tens and units digits, respectively. If the above number is divisible by 65, what is the greatest possible value of B x A?
Options:
A)0
B)10
C)15
D)20
E)30
Rationale: I also was confused when I was looking forabove number:D
As far as I understood, 65 is a factor of AB. In other words, the values of B (units digits can be 5 or 0. Better to have option for 5 in this case to havebigger result). Now let's try 65x1 (A=6, B=5 respectively we have =30). This is the greatest possible value of B x A.
IMO E.
Answer: E
Question: A trader sells 85 meters of cloth for Rs. 8925 at the profit of Rs. 15 per metre of cloth. What is the cost price of one metre of cloth?
Options:
A)Rs. 80
B)Rs. 85
C)Rs. 90
D)Rs. 95
E)None of these
Rationale: SP of 1m of cloth = 8925/85 = Rs. 105
CP of 1m of cloth = SP of 1m of cloth - profit on 1m of cloth
= Rs. 105 - Rs. 15 = Rs. 90.
ANSWER:C
Answer: C
Question: In how many different ways can the letters of the word "CLAIM" be rearrangement?
Options:
A)100
B)120
C)130
D)143
E)145
Rationale: The total number of arrangements is
5P5 = 5! = 120
B
Answer: B
Question: In what time will a train 100 m long cross an electric pole, it its speed be 144 km/hr?
Options:
A)2.5 sec
B)2.8 sec
C)8.5 sec
D)2.0 sec
E)7.5 sec
Rationale: Speed = 144 * 5/18 = 40 m/sec
Time taken = 100/40
= 2.5 sec.
Answer:A
Answer: A
Question: What command is used to create a backup configuration?
Options:
A)copy running backup
B)copy running-config startup-config
C)config mem
D)wr mem
E)wr m22
Rationale: Explanation:
The command to back up the configuration on a router is
Answer: Option B
Answer: B
Question: Find the area, diameter = 13m.
Options:
A)132.00 square meter
B)132.04 square meter
C)132.78 square meter
D)132.24 square meter
E)113.43 square meter
Rationale: Diameter = 13 meter.
Radius = diameter/2.
= 13/2.
= 6.5 meter.
Area of a circle = Ï€r2.
Here, pi (Ï€) = 3.14 meter, radius (r) = 6.5
Area of a circle = 3.14 Ã— 6.5 Ã— 6.5.
= 3.14 Ã— 42.25.
= 132.78 square meter ANSWER : C
Answer: C
Question: |x+3| – |4-x| = |8+x| How many U solutions will this equation have?
Options:
A)0
B)1
C)2
D)3
E)4
Rationale: |x| = x when x >= 0 (x is either positive or 0)
|x| = -x when x < 0 (note here that you can put the equal to sign here as well x <= 0 because if x = 0,
|0| = 0 = -0 (all are the same)
So the '=' sign can be put with x > 0 or with x < 0. We usually put it with 'x > 0' for consistency.A
Answer: A
Question: A wheel rotates 20 times every minute and moves 35 cm during each rotation. How many metres does the wheel move in one hour?
Options:
A)6 metre
B)120 metre
C)220 metre
D)1200 metre
E)420 metre
Rationale: Number of times wheel moves in 1 hour = 20 * 60 = 1200
:. Distance moves = (1200*35) cms = 42000 cms
In metres = 420 metre
ANSWER:E
Answer: E
Question: A truck covers a distance of 200 metres in 1 minute whereas a bus covers a distance of 100kms in 50minutes. The ratio of their speeds is?
Options:
A)2:3
B)ratio 1:5
C)ratio 1:10
D)ratio 9:13
E)ratio 7:15
Rationale: Ratio of speeds = (200/60) 18/5 : 60*100/50 = 12:120 = 1:10
Answer is C
Answer: C
Question: A car traveling at a certain constant speed takes 30 seconds longer to travel 1 kilometer than it would take to travel 1 kilometer at 30 kilometers per hour. At what speed, in kilometers per hour, is the car traveling?
Options:
A)16
B)18
C)20
D)22
E)24
Rationale: 30 * T = 1 km => T = 1/30 km/h
V*(T+30/3600) = 1
V (1/30 + 30/3600) = 1
V (150/3600) = 1
V = 24 km/h
The answer is E.
Answer: E
Question: As part of a promotion designed to attract visitors, an amusement park gives out 24,600 free tickets per year. Usually, the number of tickets given away each month is constant. Due to an employee error, only 95,00 tickets were given out in the first four months of the year. How many tickets should the amusement park give out in the fifth month so that it will begin the sixth month back on its regular giveaway schedule?
Options:
A)600
B)750
C)500
D)400
E)700
Rationale: 24600/12=2050
2050*5=10250
10250-9500=750
Answer B
Answer: B
Question: A reduction of 50% in the price of apples would enable a man to obtain 80 more for Rs.55, what is reduced price per dozen?
Options:
A)1
B)3
C)4
D)7
E)10
Rationale: C
55*(50/100) = 28 --- 64
? --- 12 => Rs.4
Answer: C
Question: What percent of 30 is 80?
Options:
A)133 1⁄3
B)75
C)266.66
D)33 1⁄3
E)25
Rationale: To find out the % of 80 in 30
Do 80/30 = 266.66%
Answer C)
Answer: C
Question: Find large number from below question The difference of 2 no.'s is 1365. On dividing the larger no. by the smaller, we get 6 as quotient and the 15 as remainder?
Options:
A)1245
B)1430
C)1540
D)1600
E)1635
Rationale: Let the smaller number be x. Then larger number = (x + 1365).
x + 1365 = 6x + 15
5x = 1350
x = 270
Large number = 270+1365 = 1635
E
Answer: E
Question: 1, 2, 2, 3, 3, 3, 4, 4, 4, 4, 1, 1, 2, 2, 2, 2, 3, 3, 3, 3, 3, 3, 4, 4, 4, 4, 4, 4, 4, 4, 1, 1, 1, 2, 2, 2, 2, 2, 2, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 4....
Options:
A)7
B)6
C)3
D)4
E)1
Rationale: First if we count 1223334444. they are 10
In the next term they are 20
Next they are 30 and so on
So Using n(n+1)2×10≤2888
For n = 23 we get LHS as 2760. Remaining terms 128.
Now in the 24th term, we have 24 1's, and next 48 terms are 2's. So next 72 terms are 3's.
The 2888 term will be “3”.
Answer:B
Answer: B
Question: A car traveled 75% of the way from town A to town B at an average speed of 50 miles per hour. The car travels at an average speed of S miles per hour for the remaining part of the trip. The average speed for the entire trip was 50 miles per hour. What is S ?
Options:
A)10
B)20
C)25
D)30
E)50
Rationale: Total distance = 100 miles (easier to work with %)
75% of the distance = 75 miles
25% of the distance = 25 miles
1st part of the trip → 75/50 = 1.5
2nd part of the trip → 25/S = t
Total trip → (75+25)/50 = 1.5 + t » 100/50 = 1.5 + t » 2 = 1.5 + t » t = 0.5
Back to 2nd part of the trip formula: 25/S = 0.5 » S =50
Ans E
Answer: E
Question: The amounts of time that three secretaries worked on a special project are in the ratio of 1 to 2 to 5. If they worked a combined total of 128 hours, how many hours did the secretary who worked the longest spend on the project?
Options:
A)90
B)70
C)56
D)16
E)14
Rationale: 8x = 128
=> x = 16
Therefore the secretary who worked the longest spent 16 x 5 = 90 hours on the project
Option (A)
Answer: A
Question: Mr. Kramer, the losing candidate in a two-candidate election, received 942,568 votes, which was exactly 45 percent of all votes cast. Approximately what percent of the remaining votes would he need to have received in order to have won at least 50 percent of all the votes cast?
Options:
A)9%
B)12%
C)15%
D)17%
E)20%
Rationale: Let me try a simpler one.
Lets assume that candidate got 45% votes and total votes is 100.
Candidate won = 45
Remaining = 55
To get 50%, candidate requires 5 votes from 100 which is 5% and 5 votes from 55.
5/55= 1/11 = .09 = 9%
Which is approx 9%. Hence the answer is A.
Answer: A
Question: |14 - 5| - |8 - 12| = ?
Options:
A)3
B)2
C)1
D)5
E)4
Rationale: |14 - 5| - |8 - 12| = | 9 | - | -4 | = 9 - 4 = 5
correct answer D
Answer: D
Question: If x is the product of three consecutive positive integers, which of the following must be true?
I. x is an integer multiple of 3.
II. x is an integer multiple of 6
III. x is an integer multiple of 2
Options:
A)a) I only
B)b) II only
C)c) I and II only
D)d) I and III only
E)e) I,II and III
Rationale: The answer should be D i.e. X will be an integer and multiple of 3 and 6.
Let us take example n, n+1, n+2 as 3 three consecutive positive integers.
In a sequence of consecutive integers a number is multiple of 3 after every interval of 2 numbers i.e 3,4,5,6 Or 8,9,10,11,12
Hence in a product of 3 consecutive integers, the product is always divisible by 3.
Now, in a consecutive sequence every alternate is an even number, and when an even number is multiplied by 3 we will have 6 as one of the multiple also.
Now for a number to be a multiple of 4 we need at least 2 2's. this is only possible if the first number of three consecutive positive integers is an even number so that 3 is also even and we have 2 2's. But incase the sequence starts with odd we will have one 2 hence, the divisibility by 4 depends on the first number to be even
AnswerC
Answer: C
Question: Consider a sequence of numbers given by the expression 7 + (v - 1) * 5, where n runs from 1 to 80.What is the sum of this series ?
Options:
A)409
B)1636
C)16360
D)16000
E)15360
Rationale: terms in this sequence are 7,12,17----402
now since this is an a.p. with a common difference of 5. therefore its sum can be given as
v(a+l)/2----------------1)
v= total no. of terms =80
a= first term=7
l= last term=402
subsituting values in the expression 1 we have
80(7+402)/2
= 40(409)
=16360=C
Answer: C
Question: In a hostel, the number of students decreased by 9% and the price of food increased by 20% over the previous year. If each student consumes the same amount of food then By how much should the consumption of food be cut short by every student, so that the total cost of the food remains the same as that of the previous year?
Options:
A)19%
B)15%
C)25%
D)40%
E)8.4%
Rationale: Cost of food (C) = Food consumed per student (F) * Number of students (N) * Price of food (P)
Originally,
C = FNP
When number of students decrease by 8%, and the price of food increases by 20%,
C = F(new) * (0.91N) * (1.2P)
=> F(new) = F/(0.91*1.2)
=> F(new) = 0.915F
Therefore the new cost of food must be 91.5% of the old cost, or the cost of food must decrease by 8.4% (option E)
Answer: E
Question: 1!+2!+3!+4!+5!+..100! is divided by 24. Find the remainder?
Options:
A)5
B)8
C)9
D)11
E)13
Rationale: By applying rule 2, we divide the terms of the above expression individually, and add them to get the final remainder. But from 4! onwards all the terms leave a remainder 0 when divided by 24.
So the remainder = 1 + 2 + 6 + 0 + 0....... = 9
C
Answer: C
Question: The positive integers x and y leave remainders of 2 and 3, respectively, when divided by 6. x > y. What is the remainder when x– y is divided by 6?
Options:
A)4
B)2
C)1
D)5
E)3
Rationale: Let's test out some values of p and q that satisfy the given information.
x leaves are remainder of 2 when divided by 6
So, x COULD equal 8
y leaves are remainder of 3 when divided by 6
So, y COULD equal 3
What is the remainder when x – y is divided by 6?
So, x - y = 8 - 3 = 5, and when we divide 5 by 6, we get 0 with remainder 5
Answer: D
Answer: D
Question: If equation |x/2| + |y/2| = 1 encloses a certain region on the coordinate plane, what is the area of this region?
Options:
A)8
B)50
C)100
D)200
E)400
Rationale: The equation can be reduced to intercept form as |x/2| + |y/2| = 1, so these are lines in four quadrants with x and y intercept as 2, so it is a rhombus with diagonals of 4 each and hence area = 1/2*d1*d2 = 1/2*4*4= 8. Answer A.
Answer: A
Question: The average of 5 numbers is 6.8. If one of the numbers is multiplied by a factor of 4, the average of the numbers increases to 9.2. What number is multiplied by 4?
Options:
A) 1.5
B) 3.0
C) 3.9
D) 4.0
E) 6.0
Rationale: The average of 5 numbers is 6.8
The sum of 5 numbers will be 6.8 x 5 = 34
The average of 5 number after one of the number is multiplied by 4 is 9.2
The sum of the numbers will now be 9.2 x 5 = 46
So the sum has increased by 46-34 = 12
Let the number multiplied by 4 be n
Then,
4n = n+12
or 3n = 12
or n = 4
Answer:- D
Answer: D
Question: If the true discount on a certain sum due 6 months hence at 15% is Rs. 120, what is the banker’s discount on the same sum for the same time and at the same rate?
Options:
A)100
B)115
C)120
D)129
E)None
Rationale: Sol.
B.G. = S.I. on T.D. = Rs. [120 * 15 * 1/2 * 1/100] = Rs. 9.
∴ (B.D.) - (T.D.) = Rs.9.
∴ B.D. = Rs. (120 + 9) = Rs. 129
Answer D
Answer: D
Question: A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 32, then how old is B?
Options:
A)17 years
B)19 years
C)29 years
D)10 years
E)12 years
Rationale: Let C's age be x years.
Then, B's age = 2x years.
A's age = (2x + 2) years.
(2x + 2) + 2x + x = 32
5x = 30 => x = 6
Hence, B's age = 2x = 12 years.
Answer: E
Answer: E
Question: In the first 12 overs of a cricket game, the run rate was only 4.5. What should be the run rate in the remaining 38 overs to reach the target of 360 runs?
Options:
A)9.55
B)6.25
C)6.75
D)8.05
E)7.25
Rationale: Required run rate = 360 - (4.5 x 12)	/38	=	306/38 = 8.05 Option D
Answer: D
Question: The S.I. on a certain sum of money for 3 years at 8% per annum is half the C.I. on Rs. 4000 for 2 years at 10% per annum. The sum placed on S.I. is?
Options:
A)288
B)276
C)1750
D)2887
E)2991
Rationale: C.I. = [4000 * (1 + 10/100)2 - 4000]
= (4000 * 11/10 * 11/10 - 4000) = Rs. 840.
Sum = (420 * 100)/(3 * 8) = Rs. 1750.Answer: C
Answer: C
Question: Alyssa and her six cousins went to a party. There are sixteen pieces of
pizza for them to eat.
Is there any
pizza left over?
Options:
A)5
B)4
C)3
D)2
E)1
Rationale: 16/7 = 2 R 2 Each girl will get 2 pieces of pizza and there will be 2
pieces left over.
correct answer D
Answer: D
Question: A change-making machine contains one-rupee, two-rupee and five-rupee coins. The total number of coins is 300. The amount is Rs. 960. If the numbers of one-rupee coins and two-rupee coins are interchanged, the value comes down by Rs. 40. The total number of five-rupee coins is
Options:
A)100
B)140
C)60
D)150
E)None of these
Rationale: Explanation :
Let the number of 5 rupee , 2 rupee and 1 rupee coins be x, y and z respectively.
x + y + z = 300.
5x + 2y + z = 960 .......(i)
5x - y + 2z = 920 ......(ii)
On subtracting (ii) from (i) we get,
y - z = 40.
And, x + 2y = 340.
Using the options,
if x= 140, y= 100 and z= 60, this satisfies all the given conditions.
Answer : B
Answer: B
Question: The ratio between the present ages of A and B is 5:3 respectively. The ratio between A's age 4 years ago and B's age 4 years hence is 1:1. What is the ratio between A's age 4 years hence and B's age 4 years ago?
Options:
A)3:1
B)2:3
C)4:3
D)5:4
E)2:4
Rationale: Let the present ages of A and B be 5x and 3x years respectively.
Then, (5x - 4)/(3x + 4) = 1/1
2x = 8 => x = 4
Required ratio = (5x + 4):(3x - 4) = 24:8 = 3:1
ANSWER A
Answer: A
Question: How many positive integers less than 50 have a reminder 2 when divided by 7?
Options:
A)3
B)4
C)5
D)6
E)7
Rationale: take the multiples of 7 and add 2
0X7+2=2 ....6X7+2=44
there are 7 numbers
answer E
Answer: E
Question: Find 80 / ? = ? / 20
Options:
A)40
B)400
C)800
D)1600
E)None
Rationale: Answer
Let 80/y = y/20
Then, y 2 = 80 x 20 = 1600
∴ y = √1600 = 40.
Option: A
Answer: A
Question: Alex deposited x dollars into a new account that earned 5 percent annual interest, compounded annually. One year later Alex deposited an additional x dollars into the account. If there were no other transactions and if the account contained w dollars at the end of two years, which of the following expresses x in terms of w ?
Options:
A)w/(1+1.08)
B)w/(1.08+1.16)
C)w/(1.16+1.24)
D)w/(1.05+1.05^2)
E)w/(1.08^2+1.08^2)
Rationale: Account at the end of the first year would be 1.05x dollars. At this time x dollars was deposited, hence the account at the beginning of the second year would be (1.05x+x) dollars. Account at the end of the second year would be (1.05x+x)*1.05=w --> x(1.05^2+1.05)=w --> x=w/(1.05+1.05^2).
Answer: D.
Answer: D
Question: Peter invested an amount of Rs. 12,000 at the rate of 10% p.a simple interest and another amount at the rate of 20% p.a. simple interest. The total interest earned at the end of one year on the total amount invested became 14% p.a. Find the total amount invested?
Options:
A)Rs.20,000
B)Rs.20,028
C)Rs.20,298
D)Rs.20,029
E)Rs.20,291
Rationale: Let the second amount be Rs. x. Then,
(12000 * 10 * 1)/100 + (x * 20 * 1)/100 = [(12000 + x) * 14 * 1] / 100
120000 + 20x = 16800 + 14x
x = 8000
Total investment = 12000 + 8000
=Rs.20,000.
Answer:A
Answer: A
Question: If log 2, log (2x -1) and log (2x + 3) are in A.P, then x is equal to ____
Options:
A)5/2
B)log(2)5
C)log(3)2
D)3/2
E)None of these
Rationale: Explanatory Answer
Because log 2, log (2x -1) and log (2x + 3) are in an AP
2 log (2x - 1) = log 2 + log (2x + 3)
Using the power rule of log, we can write 2 log (2x - 1) = log (2x - 1)2
Therefore, we can write the equation as log (2x - 1)2 = log 2 + log (2x + 3)
Using product rule, we can write the right hand side of the equation as follows:
log 2 + log (2x + 3) = log 2 (2x + 3)
The modified equation after applying the power rule and the product rule of logarthims is log (2x - 1)2 = log 2 (2x + 3)
Removing logarithm on both sides of the equation, we get
(2x - 1)2 = 2 (2x + 3)
Or 22x - 2*2x + 1 = 2 * 2x + 6
Or 22x - 4 * 2x - 5 = 0
Let y = 2x
So, the equation can be written as y2 - 4y - 5 = 0
Factorzing, we get (y - 5)(y + 1) = 0.
So, y = 5 or y = -1
So, 2x = 5 or 2x = -1
2x cannot be negative. S, 2x = 5
If 2x = 5, expressed in terms of a log, it becomes x = log(2)5
Answer B
Answer: B
Question: How many hours are there in 660 minutes?
Options:
A)60 hours
B)6 hours
C)30 hours
D)11 hours
E)10 hours
Rationale: Solution:
Number of minutes in 1 hour = 60 minutes
So
Just divide 660 by 60
660 Ã· 60 = 11, so there are 11 hours in 660 minutes
Option D
Answer: D
Question: Amar takes as much time in running 12 meters as a car takes in covering 45 meters. What will be the distance covered by Amar during the time the car covers 1.4 km?
Options:
A)700 m
B)500 m
C)373 m
D)356 m
E)640 m
Rationale: Distance covered by Amar
= 12/45 (1.4km)
= 4/15(1400) = 373 m
Answer: C
Answer: C
Question: How many prime numbers Z exist such that 90 < Z < 106 and n is a factor of 99999919?
Options:
A)1. Zero
B)2. One
C)3. Two
D)4. Three
E)5. More than three
Rationale: I found that considering the constraint..Z is a prime num in between 90 to 106 not inclusive , only 3 numbers (91,97 and 101) are present but those numbers are not the factors of the number mentioned....Therefore, i doubt the answer.C
Answer: C
Question: The average age 9 members of a committee are the same as it was 2 years ago, because an old number has been replaced by a younger number. Find how much younger is the new member than the old number?
Options:
A)18
B)12
C)27
D)21
E)28
Rationale: 9 * 2 = 18 years
ANSWER A
Answer: A
Question: In a small dairy farm, 40 cows eat 20 bags of grass in 40 days. In how many days one cow will eat one bag of grass?
Options:
A)40
B)80
C)60
D)50
E)90
Rationale: Assume that in a days, one cow will eat one bag of grass.
More cows, less days (Indirect proportion)
More bags, more days (direct proportion)
Hence we can write as (cows)40:1
::x:40
(bags)1:20
⇒40×1×40=1×20×x
⇒x=80
ANSWER:B
Answer: B
Question: Each year, a cyber café charges its customers a base rate of $25, with an additional $0.30 per visit for the first 50 visits, and $0.10 for every visit after that. How much does the cyber café charge a customer for a year in which 72 visits are made?
Options:
A)36.6
B)42.2
C)47.8
D)51.1
E)53.6
Rationale: Explanation:
The café charges $25 + $0.30(first 50) + $0.10(additional after 50). For 72 visits there are 50 visits with an additional 22 visits.
$25 + $0.30(50) + $0.10(22)
=$25 +$15 + $2.20
=$42.20
Answer is (B).
Answer: B
Question: In a group of 6 boys and 3 girls, four children are to be selected. In how many different ways can they be selected such that at least one girl is included?
Options:
A)105
B)111
C)117
D)123
E)129
Rationale: The total number of ways to choose 4 children is 9C4 = 126
The number of ways to choose only boys is 6C4 = 15
The number of groups which include at least one girl is 111.
The answer is B.
Answer: B
Question: Find the average increase rate, if increase in the population in the first year is 30% and that in the second year is 40%.
Options:
A)41
B)56
C)40
D)38
E)39
Rationale: Solution: Let 100 be the original population.
1st year's population increased = 30%
So, Population after first year = (100 +30% of 100) = 130. Population in second year increases by 40%, then Population
= (130 +40% of 130) = 182.
The final population become 182 which was originally at 100. It means there is 82% increment in the population in 2 years
So, Average increment = 82/2 = 41%.
Mind Calculation Method:
Increase in population is given by,
100==30%↑==>130==40%↑==> 182.
Hence, average increase = 82/2 = 41%
Answer: Option A
Answer: A
Question: Torry has submitted 2/5 of his homework assignments, and he received an average grade of 75 for those assignments. If he wishes to receive an average grade of 96 for all his homework assignments, the average grade for Torry's remaining homework assignments must be what percent greater than the average grade for the assignments he has already submitted?
Options:
A)15%
B)20%
C)25%
D)46 2/3%
E)40%
Rationale: 0.4*75 + 0.6x = 96
30 + 0.6x=96
0.6x = 66
x= 110
110/75= 1.4666...
Ans:D
Answer: D
Question: If two numbers are in the ratio 2:3. If 10 is added to both of the numbers then the ratio becomes 5:7 then find the largest number?
Options:
A)30
B)34
C)38
D)40
E)42
Rationale: 2:3
2x + 10 : 3x + 10 = 5 : 7
7[2x + 10] = 5[3x + 10]
14x + 70 = 15x + 50
15x - 14x = 70 - 50
x = 20
Then the first number is = 2
2x = 40
D
Answer: D
Question: We invested a total of $1,000. We invested one part of the money at 4% and the rest of the money at 6%. The total investment with interest at the end of the year was $1,046. How much money did we invest at 4%?
Options:
A)$600
B)$650
C)$700
D)$750
E)$800
Rationale: Let x be the money invested at 4%.
1.04x+1.06(1000-x)=1046.
0.02x=1060-1046.
0.02x=14.
2x=1400.
x=700.
The answer is C.
Answer: C
Question: A train leaves Delhi at 9 a.m. at a speed of 30 kmph. Another train leaves at 3 p.m. at a speed of 40 kmph on the same day and in the same direction. How far from Delhi, will the two trains meet?
Options:
A)229
B)288
C)600
D)720
E)121
Rationale: D = 30 * 6 = 180
RS = 40 – 30 = 10
T = 180/10 = 18
D = 40 * 18 = 720 km
Answer: D
Answer: D
Question: If x represents the sum of the interior angles of a regular octagon and y represents the sum of the interior angles of a regular pentagon, then the difference between x and y is equal to the sum of the interior angles of what geometric shape?
Options:
A)Triangle
B)Square
C)Rhombus
D)Trapezoid
E)Pentagon
Rationale: Sum of angles of octagon = 180*(8-2) = 1080 => using formula sum of angles of polygon = 180*(n-2) where n is the number of sides in a polygon
Sum of angles in Pentagon = 180*(5-2) =540
Difference = 1080 - 540 = 540 => Pentagon
hence (E).
Answer: E
Question: What is the ratio whose term differ by 40 and the measure of which is 2/7?
Options:
A)32:23
B)16:56
C)71:85
D)32:39
E)41:52
Rationale: Let the ratio be x:(x+40)
Then, x/(x+40) = 2/7
x=16
required ratio = 16:56
Answer is B
Answer: B
Question: Baby Isabel plays with blocks. Each block is 3.9 inches tall. She has a collection of 32 blocks. If she could stack all of the blocks up one on top of the other, how many inches tall would her tower of blocks be?
Options:
A)67"
B)124.8"
C)106"
D)120"
E)151.7"
Rationale: 3.9"*32=124.8". Answer is B.
Answer: B
Question: When y divided by 288, the remainder is 47. Find the remainder when the same y is divided by 24?
Options:
A)20
B)21
C)23
D)25
E)26
Rationale: 23
Option C
Answer: C
Question: Find the greatest number that will divide 256, 193 and 210 leaving 6, 18 and 100 as remainders respectively
Options:
A)19
B)25
C)23
D)20
E)26
Rationale: Explanation:
Answer will be HCF of (256-6, 193-18, 210-10)
HCF of (250, 175, 200) = 25
Option B
Answer: B