divelab/Sys2Bench huggingface dataset:
Question: x =3 4 5
y= 27 36 9 then what is the relation between x and y
Options:
A)1*X)^2
B)1*X)^3
C)1*X)^4
D)1*X)^5
E)1*X)^6
Rationale: Y=(1*X)^2
9=(1*3)^2
9=9
ANSWER:A
Answer: A
Question: Mohan's salary was first increased by 20% and then decreased by 20%. If his present salary is Rs. 7200, then what was his original salary?
Options:
A)8789
B)7500
C)8392
D)8390
E)2804
Rationale: Let Mohan's salary be Rs.100.
When increased by 20%, Mohan's salary = Rs.120
Again when decreased by 20%, Mohan's salary = 120 - 24 = Rs. 96.
But present salary is Rs. 7200
for, 96 ---> 100 ; 7200 ---> ?
Required salary is 7200/96 * 100 = Rs. 7500
Answer:B
Answer: B
Question: 50% of the apartments in a certain building have windows and hardwood floors. 25% of the apartments without windows have hardwood floors. If 40% of the apartments do not have hardwood floors, what D percent of the apartments with windows have hardwood floors?
Options:
A)10
B)16 2/3
C)40
D)50
E)83 1/3
Rationale: yup you need to construct a matrix
X********| Windows'|No Windows'''| total
hardFl****'|50*****''|10*********'|60
Not hardFl*|10******|30*********'|40
Total*****|60******'|40*********'|100
so D percent of the apartments with windows have hardwood floors = 50/60 *100
= 83 1/3
so E is the answer.[/u]
Answer: E
Question: John's lottery get prize on any given day is 1/2. What is the probability that it get prize on 4 out of 7 consecutive days?
Options:
A)4/7
B)3/7
C)31/128
D)4/28
E)35/128
Rationale: using Binomial. theorem
nCr (p)^r (q)^n-r
7C4 (1/2)^4 (1/2)^r
which is 35/128
Answer is E
Answer: E
Question: How many prime numbers between 100 to 150?
Options:
A)10
B)11
C)15
D)14
E)13
Rationale: primes are of the form 6n+1 or 6n-1
Put n=25 ==> 151
for n=26 ==> 157
for n=27 , ==>163
for n=28 , ==> 167
for n =29 ==> 173
for n =30 ==> 179 and 181
for n =31 ==> no prime no.
for n= 32 ==> 191
for n =33 ==> 199
therefore total number of prime numbers = 11
Ans - B
Answer: B
Question: The ratio of a to b is 4 to 5, where a and b are positive. If x equals a increased by 25 percent of a, and m equals b decreased by 20 percent of b, what is the value of m/x?
Options:
A)2/5
B)3/4
C)4/5
D)5/4
E)3/2
Rationale: x equals a increased by 25 percent of a => x = a + 25%a = 1.25a
m equals b decreased by 20 percent of b => m = b - 20%b = 0.8b
m/x = 0.8b/1.25a
Putting the value of b/a = 5/4 we get m/x = 4/5
ANSWER:C
Answer: C
Question: 2 is what percent of 50
Options:
A)2%
B)4%
C)6%
D)8%
E)None of these
Rationale: Explanation:
2/50 * 100 = 1/25 * 100 = 4 %
Option B
Answer: B
Question: If Y = 2Z+1 where Y is an Integer then which of the following is true?
Options:
A)Y is always Odd
B)Y is always Even
C)Y is even if Z is a non integer and a multiple of 0.5
D)Y= 1
E)Y is a non multiple of 2
Rationale: C
Answer: C
Question: If 2^z is a factor of 27!, which of the following could be the value of z?
I. 22
II. 23
III. 24
Options:
A)I ​ only
B)II only
C)I​ and II
D)I, II, and III
E)None
Rationale: 27! contains all numbers from 1 to 27. To find the factor with the highest power of 2, we count the number of multiples of 2, 4, 8 and 16.
Multiples of 2 = 13
Multiples of 4 = 6
Multiples of 8 = 3
Multiples of 16 = 1
Total count = 23
The answer is C.
Answer: C
Question: The equal amounts of money are deposited in two banks each at 15% per annum for 3.5 years and 5 years respectively. If the difference between their interests is Rs.144, find the each sum?
Options:
A)640
B)500
C)3000
D)1000
E)2000
Rationale: (P*5*15)/100 - (P*3.5*15)/100 = 144
75P/100 â€“ 52.5P/100 = 144
22.5P = 144 * 100
=> P = Rs.640
ANSWER A
Answer: A
Question: A man can reach certain place in 50hours. If he reduces his speed by 1/10th, he goes 200km less in time. Find his speed?
Options:
A)20km/hr
B)30km/hr
C)40km/hr
D)50km/hr
E)60km/hr
Rationale: Let the speed be x km/hr
50x-50* 9/10 *x = 200
50x - 45x = 200
5x = 200
x = 40km/hr
Answer is C
Answer: C
Question: Each digit in the two-digit number G is halved to form a new two-digit number H. Which of the following numbers could be the sum of G and H?
Options:
A)153
B)150
C)143
D)141
E)89
Rationale: Let x be the original 2-digit number.
If each digit is halved, then the sum of G and H is 3x/2.
Note the sum must be a multiple of 3 and less than 150.
Of these five choices, only 141 satisfies these two conditions.
The answer is D.
Answer: D
Question: In an examination, 5% of the applicants were found ineligible and 85% of the eligible candidates belonged to the general category. If 4275 eligible candidates belonged to other categories, then how many candidates applied for the examination?
Options:
A)30,000
B)35,000
C)37,000
D)None of these
E)Cannot be determined
Rationale: Solution
Let the number of applicants be x.Number of eligible candidates	= 95% of x.
Eligible candidates of each other categories	= 15% of (95% of x).
=(15/100×95/100×x)
= 57/400×x.
Therefore, 57/400×x	= 4275
‹=› x =(4275×400 / 57)
‹=› 30000
Answer A
Answer: A
Question: The compound and the simple interests on a certain sum at the same rate of interest for two years are Rs.11730 and Rs.10200 respectively. Find the sum
Options:
A)Rs.17037
B)Rs.17000
C)Rs.17276
D)Rs.170287
E)Rs.171881
Rationale: Explanation:
The simple interest for the first year is 10200/2 is Rs.5100 and compound interest for first year also is Rs.5100. The compound interest for second year on Rs.5100 for one year
So rate of the interest = (100 * 1530)/ (5100 * 1) = 30% p.a.
So P = (100 * 10200)/ (30 * 2) = Rs.17000
Answer:B
Answer: B
Question: A sum of money at simple interest amounts to Rs. 820 in 3 years and to Rs. 854 in 4 years. The sum is:
Options:
A)647
B)718
C)654
D)847
E)976
Rationale: S.I. for 1 year = Rs. (854 - 820) = Rs. 34.
S.I. for 3 years = Rs.(34 x 3) = Rs. 102.
Principal = Rs. (820 - 102) = Rs. 718.
Answer:B
Answer: B
Question: If the sum of two positive integers is 26 and the difference of their squares is 52, what is the product of the two integers?
Options:
A)108
B)119
C)128
D)135
E)168
Rationale: Let the 2 positive numbers x and y
x+ y = 26 -- 1
x^2 - y^2 = 52
=> (x+y)(x-y)=52 -- 2
Using equation 1 in 2 , we get
=> x-y = 2 -- 3
Solving equation 1 and 3 , we get
x= 14
y= 12
Product = 14*12 = 168
Answer E
Answer: E
Question: On day one, a store sold 86 cups. On each of the next d days, the company sold 50 cups. If the average daily sales of cups over this time period (including day one) is 53 cups, what is the value of d?
Options:
A)9
B)10
C)11
D)12
E)13
Rationale: 86 + 50d = 53(d+1).
3d = 33.
d = 11.
The answer is C.
Answer: C
Question: Henrikh lives x blocks from his office. It takes him 1 minute per block to walk to
work and 20 seconds per block to ride his bicycle to work. If it takes him exactly
16 minutes more to walk to work than to ride his bicycle, then x equals
Options:
A)4
B)7
C)10
D)15
E)24
Rationale: The best way would be...
Per km, he takes 40 secs extra if he walks
So he will take 16 mins or 16*60 secs in 16*60/40 =24 km
ANSWER:E
Answer: E
Question: Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is
Options:
A)12
B)13
C)15
D)17
E)18
Rationale: Explanation:
Let the three integers be x, x+2 and x+4.
Then, 3x = 2(x+4)+3,
x= 11
Therefore, third integer x+4 = 15
Answer: Option C
Answer: C
Question: A bag contains 23 purple jellybeans, 12 green jellybeans, and 15 yellow jellybeans; these jellybeans are the only items in the bag. If a person picks a jellybean at random out of the bag, what is the probability that the jellybean will be purple?
Options:
A)15%
B)20%
C)25%
D)30%
E)46%
Rationale: p = 23 , g=12 , y=15
total = 50
p(purple)=(23/50)*100 = 46% . Ans = E
Answer: E
Question: In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
Options:
A)6.25
B)7.25
C)7.75
D)7.35
E)8.25
Rationale: Runs scored in the first 10 overs = 10 × 3.2 = 32
Total runs = 282
Remaining runs to be scored = 282 - 32 = 250
Remaining overs = 40
Run rate needed = 25040=6.25
ANSWER:A
Answer: A
Question: 85 litres of diesel is required to travel 600 km using a 800 cc engine. If the volume of diesel required to cover a distance varies directly as the capacity of the engine, then how many litres of diesel is required to travel 800 km using 1200 cc engine?
Options:
A)80 litres
B)90 litres
C)120 litres
D)170 litres
E)None of these
Rationale: Explanatory Answer
To cover a distance of 800 kms using a 800 cc engine, the amount of diesel required = 800/600*85= 113.33 litres.
However, the vehicle uses a 1200 cc engine and the question states that the amount of diesel required varies directly as the engine capacity.
i.e., for instance, if the capacity of engine doubles, the diesel requirement will double too.
Therefore, with a 1200 cc engine, quantity of diesel required = 1200/800*113.33 = 170 litres.
Answer D
Answer: D
Question: How many ways can 5 friends be arranged around a circular dinner table?
Options:
A)A)24
B)B)48
C)C)96
D)D)120
E)E)720
Rationale: The number of arrangements of n distinct objects in a row is given by n!n!.
The number of arrangements of n distinct objects in a circle is given by (n−1)!(n−1)!.
The difference between placement in a row and that in a circle is following: if we shift all object by one position, we will get different arrangement in a row but the same relative arrangement in a circle. So, for the number of circular arrangements of n objects we have:
n!n=(n−1)!n!n=(n−1)!.
So, the answer is (5 - 1)! = 4! = 24.
Answer: A.
Answer: A
Question: (A% of 3B + B% of A) is equal to ?
Options:
A)A% of B
B)B% of A
C)4% of AB
D)AB% of 3
E)None
Rationale: Answer
A% of 3B + B% of A =3AB/100 + AB/100
= 4AB/100 = 4% of AB
Correct Option: C
Answer: C
Question: A certain sum of money doubles itself in 10 years in how much many years will it trible itself at the same rate?
Options:
A)20 years
B)28 years
C)24 years
D)27 years
E)57 years
Rationale: 100 ---- 100 --- 10
100 --- 10
--------------------
300 ---- 20 years
Answer:A
Answer: A
Question: In a group of cows and chickens, the number of legs was 12 more than twice the number of heads. The number of cows was:
Options:
A)6
B)7
C)10
D)12
E)14
Rationale: Let the number of cows be x and their legs be 4x.
Let the number of chicken be y and their legs be 2x.
Total number of legs = 4x + 2y.
Total number of heads = x + y.
The number of legs was 12 more than twice the number of heads.
Therefore, 2 × (x + y) + 14 = 4x + 2y.
or, 2x + 2y + 12 = 4x + 2y.
or, 2x + 12 = 4x [subtracting 2y from both sides].
or, 12 = 4x – 2x [subtracting 2x from both sides].
or, 12 = 2x.
or, x = 6 [dividing by 2 on both sides].
Therefore, the number of cows = 6.
Correct Answer:A)6
Answer: A
Question: A certain factory produces buttons and buckles at a uniform weight. If the total weight of 2 buttons and 2 buckles is one third of 11 buckles and 3 buttons, then the weight of 3 buttons and 3 buckles is how many times that of 5 buckles and 6 buttons?
Options:
A)7/15.
B)4/9.
C)6/11.
D)5/9.
E)8/15.
Rationale: 2buttons + 2buckles = 1/3(11buckles + 3buttons)
6buttons + 6buckles = 11buckles + 3buttons
3buttons = 5buckles
Weight of 3buttons and 3buckles = 5buckles + 3buckles = 8buckles
Weight of 6buttons and 5buckles = 10buckles + 5buckles = 15buckles
(3buttons and 2buckles) = x * (6buttons and 5buckles)
8 = x*15
x = 8/15
Answer: E
Answer: E
Question: Express a speed of 180 kmph in meters per second?
Options:
A)10 mps
B)05 mps
C)50 mps
D)12 mps
E)11 mps
Rationale: C
50 mps
180 * 5/18 = 50 mps
Answer: C
Question: Hammers and wrenches are manufactured at a uniform weight per hammer and a uniform weight per wrench. If the total weight of 3 hammers and 4 wrenches is one-third that of 10 hammers and 5 wrenches, then the total weight of one wrench is how many times that of one hammer?
Options:
A)1/2
B)2/3
C)1
D)3/2
E)1/7
Rationale: x be the weight of a hammer and y be the weight of a wrench.
(3x+4y)=1/3*(10x+5y)
3(3x+4y)=(10x+5y)
9x+12y=10x+5y
7y=x
y=x/7
Ans - E
Answer: E
Question: In a bowl, the no. of marbles gets doubled after every minute. if the bowl gets filled after two hours of such process, how long do you think it will take for it to be half filled?
Options:
A)1 hr 48 mins
B)1 hr 39 mins
C)1 hr 49 mins
D)1hr 59 mis
E)1 hr 58 mins
Rationale: Correct Answer : D
If you go backward , if the no. of marbles gets doubled after every minute and after two hours. it is filled completely. one minute ago it would be half.
Answer: D
Question: In a games hour 4 different types of players came to the ground? cricket 18, hockey 15, football 21, softball 15. In these 4 people play both cricket and hockey, 3people play both softball and football. 5 people play both cricket and football. How many people play only cricket?
Options:
A)11
B)9
C)5
D)3
E)9
Rationale: people play only cricket = total players in cricket- both cricket and football- both cricket and hockey.
people play only cricket = 18-4-5 = 9
Answer is B
Answer: B
Question: The average weight of A,B,C is 45 Kg. The avg wgt of A & B be 40Kg & that of B,C be 43Kg. Find the wgt of B.
Options:
A)36kg
B)84kg
C)31kg
D)45kg
E)12kg
Rationale: Sol. Let A,B,c represent their individual wgts.
Then,
A+B+C=(45*3)Kg=135Kg
A+B=(40*2)Kg=80Kg & B+C=(43*2)Kg=86Kg
B=(A+B)+(B+C)-(A+B+C)
=(80+86-135)Kg
=31Kg.
Ans: B
Answer: B
Question: Each of the positive integers a, b, and c is a three-digit integer. If each of the digits 0 through 8 appears in one of these three integers, what is the maximum possible value of the sum of a, b, and c?
Options:
A)2233
B)2774
C)2223
D)2345
E)2135
Rationale: According to the stem we should use the digits 0 through 7 to construct 3 three-digit integers, so that their sum is as large as possible.
To maximize the sum, maximize the hundreds digits of a, b, and c, so make them 8, 7, and 6.
Next, minimize tens digits. Make them 5, 4, and 3.
Use the remaining digits (2, 1, and 0) for units digits.
So, a would be 852, b would be 741 and c would be 630.
741 + 852 + 630 = 2223.
Answer: C.
Answer: C
Question: In a certain city , there are two football teams , 65 percent of the people prefer team (A) and the rest prefer team (B),
Team (A) is going to play against team (C) from another city. If 80 percent of people who prefer team (A) are going to attend the match , and 20 percent of the people who prefer team (B) are going to attend the match , what percent of city's people are going to attend the match ?
Options:
A) 45%
B) 59%
C) 60%
D) 61%
E) 68%
Rationale: say the population of the city is 100 person , so there are 65 persons prefer team (A) and 35 persons prefer team(B) .
65*0.8=52 person who prefer team (A) are going to attend the match
35*0.2=7 person who prefer team (B) are going to attend the match
Thus total of 52+7=59 persons are going to attend the match , which is 59 percent of population.
answer: B
Answer: B
Question: Two trains, one from P to Q and the other from Q to P, start simultaneously. After they meet, the trains reach their destinations after 25 hours and 16 hours respectively. The ratio of their speeds is
Options:
A)4:1
B)4:2
C)4:5
D)4:3
E)4:6
Rationale: Ratio of their speeds = Speed of first train : Speed of second train
= √16−−√25
= 4:5
Answer is C
Answer: C
Question: In an election between two candidates first candidate got 60% of votes polled and second Candidate got 250 votes. The total number of votes polled was?
Options:
A)votes
B)votes
C)votes
D)votes
E)votes
Rationale: Total = 100 %,
First person got 60%
second person got remaining 40 % of votes.
than 40 % = 250
40% = 40×7 = 250
100% =100×7 =700 votes
A)
Answer: A
Question: In a rectangular coordinate system, what is the area of a rhombus whose vertices have the coordinates (0, 3.5), (8, 0), (0, -3.5), (-8, 0)?
Options:
A)56
B)88
C)112
D)116
E)120
Rationale: Area of rhombus= 1/2* D1 *D2
Length of 1st diagonal = 8+8= 16
Length of 2nd diagonal= 3.5+3.5= 7
Area= 1/2*16*7= 56
A is the answer
Answer: A
Question: The value of Underrot 130pi/4 + Underrot 1 is most nearly equal to which of the following integers? (Please refer to the picture below for the exact version of the question)
Options:
A)108
B)114
C)125
D)120
E)103
Rationale: Under root (130pi/4) ~ 102
Under root (1) = 1
Hence, 102+1 = 103 is the approx answer. E is the correct answer.
Answer: E
Question: A train crosses a platform of 100 m in 15 sec, same train crosses another platform of length 250 m in 20 sec. then find the length of the train?
Options:
A)150
B)88
C)77
D)62
E)350
Rationale: Length of the train be â€˜Xâ€™
X + 100/15 = X + 250/20
4X + 400 = 3X + 750
X = 350m
Answer: E
Answer: E
Question: What is the 20th digit to the right of the decimal point in the decimal expansion of 1/37?
Options:
A) 0
B) 2
C) 4
D) 7
E) 9
Rationale: 1/37=0.027027... So, we have a repeating cycle of 027. Every third digit (2nd, 4th, 6th, ...) to the right of the decimal point is alternating by 2, 0, 7 thus 20th digit is 2.
Answer: B.
Answer: B
Question: In a six-sided polygon XQRSTV ∠X measures 48° less than the average (arithmetic mean) of the remaining five angles. What does ∠X equal to, in degrees?
Options:
A) 72
B) 80
C) 88
D) 96
E) 104
Rationale: The sum of interior angle in a polygon is (n-2)*180
so for a six sided figure, (6-2)*180 = 720
let the A.M of the other 5 angles be 'm'
--> m*5 + ∠X = 720, we know ∠X=m-48
--> m*5 + m - 48 = 720, solving we get m=128
hence ∠X= 128-48 = 80
Ans B.
Answer: B
Question: X starts a business with Rs.45000. Y joins in the business after 3 months with Rs.30000. What will be the ratio in which they should share the profit at the end of the year?
Options:
A)1:2
B)2:1
C)1:3
D)3:1
E)1:1
Rationale: Explanation:
Ratio in which they should share the profit
= Ratio of the investments multiplied by the time period
=45000×12:30000×9
=45×12:30×9
=3×12:2×9
=2:1
Answer: Option B
Answer: B
Question: In how much time will a train of length 100 m, moving at 36 kmph cross an electric pole?
Options:
A)34 sec
B)11 sec
C)12 sec
D)10 sec
E)15 sec
Rationale: Convert kmph to mps. 36 kmph = 36 * 5/18 = 10 mps.
The distance to be covered is equal to the length of the train.
Required time t = d/s = 100/10 = 10 sec.
Answer:D
Answer: D
Question: 150 men consume 1050 kg of rice in 30 days. In how many days will 70 men consume 980 kg of rice?
Options:
A)16
B)60
C)66
D)52
E)51
Rationale: Rate of consumption of each man = 1050/(150 * 30) = 7/30 kg/day
Let us say 70 men take x days to consume 150 kg.
Quantity consumed by each item in x days = 7x/30 kg.
Quantity consumed by 70 men in x days = (7x/30)(70)kg
(7x/30)(70) = 980
x = (980 * 30)/490 => x = 60 days
Answer:B
Answer: B
Question: A group of hikers is planning a trip that will take them up a mountain using one route and back down using another route. They plan to travel down the mountain at a rate of one and a half times the rate they will use on the way up, but the time each route will take is the same. If they will go up the mountain at a rate of 4 miles per day and it will take them two days, how many miles long is the route down the mountain?
Options:
A)4
B)6
C)8
D)12
E)16
Rationale: D = S*T
Given condition is for UP the mountain hikers takes 4 miles per day and total 2 days... miles = 8 miles...
For DOWN speed they take = 3/2(4) = 6 miles per day and for the same 2 days... miles = 12 miles..
Answer: option D is correct answer
Answer: D
Question: The ratio of three numbers is 3:4:7 and their product is 18144. The numbers are
Options:
A)9,12,21
B)15,20,25
C)18,24,42
D)24,15,17
E)30,12,7
Rationale: Let the numbers be 3x, 4x and 7x
3x x 4x x 7x=18144
X3=216
X=6
The numbers are 18,24,42
ANSWER C 18,24,42
Answer: C
Question: If the radius of a circle is increased by 30% then the area is increased by:
Options:
A)44%
B)69%
C)144%
D)40%
E)None of the above
Rationale: initially A=pi*r2
now R2=130/100r
then area=Pi*(130R/100)2
area=169R/100
that is area increases from 100 to 169=increase in area=69%
ANSWER:B
Answer: B
Question: Angelina walked 1200 meters from her home to the grocery at a constant speed. She then walked 480 meters to the gym at double the speed. She spent 40 seconds less on her way from the grocery to the gym than on her way from home to the grocery. What was Angelina's speed, in meters per second, from the grocery to the gym?
Options:
A)12
B)23
C)34
D)48
E)52
Rationale: let the speed be X...
so time taken from home to grocery= 1200/x..
the speed to gym = 2x..
so time taken = 480/2x=240/x..
its given 1200/x-240/x=40..
960/x=40..
x=24m/secs..
so grocery to gym=2*24=48m/s...
D
Answer: D
Question: A set of pictures of butterflies contains 10 pictures. Jim bought 3 of the pictures. If 2 pictures are to be picked out from the 10 pictures, what is the probability that both pictures are not those that were already bought by Jim?
Options:
A)14/15
B)3/5
C)6/13
D)7/15
E)7/10
Rationale: Probability of first pick not one of the Jim's picture is = 7/10 (except for 3 which Jim purchased)
Probability of second pick not one of the Jim's picture is = 6/9
Total = 7/10∗6/9=7/15
Answer is D
Option D
Answer: D
Question: What least number must be added to 1096, so that the sum is completely divisible by 23 ?
Options:
A)2
B)1
C)3
D)5
E)8
Rationale: 1096/23 = 47.6--
that is 23 * 47 = 1081
Now,
1096- 1081 = 15
To get completely divided by 23 add 8 to 1096
Ans -E
Answer: E
Question: The sum of the present ages of two persons A and B is 45. If the age of A is twice that of B, find the sum of their ages 5 years hence?
Options:
A)55
B)60
C)70
D)80
E)90
Rationale: A + B = 45, A = 2B
2B + B = 45 => B = 15 then A = 30.
5 years, their ages will be 35 and 20.
Sum of their ages = 35 + 20 = 55.
ANSWER:A
Answer: A
Question: How many 4-letter words with or without meaning, can be formed out of the letters of the word, ‘LOGARITHMS’, if repetition of letters is not allowed?
Options:
A)40
B)400
C)5040
D)2520
E)None of these
Rationale: Solution
'LOGARITHM' contain 10 different letters.
Required number of words = Number of Arrangement of 10 letters, taking 4 at a time
= 10 P 4 = (10 × 9 × 7) = 5040 . Answer C
Answer: C
Question: The average monthly income of A and B is Rs. 4050. The average monthly income of B and C is Rs. 5250 and the average monthly income of A and C is Rs. 4200. What is the monthly income of A?
Options:
A)2000
B)2500
C)3000
D)3500
E)4000
Rationale: Let monthly income of A = x
monthly income of B = y
monthly income of C = z
x + y = 2 × 4050 .... (Equation 1)
y + z = 2 × 5250 .... (Equation 2)
z + x = 2 × 4200 .... (Equation 3)
(Equation 1) + (Equation 3) - (Equation 2)
=> x +y + x + z - (y + z) = (2 × 4050) + (2 × 4200) - (2 × 5250)
=> 2x = 2(4050 + 4200 - 5250)
=> x = 3000
i.e., Monthly income of A = 3000
ANSWER:C
Answer: C
Question: Which of the following is a divisible by 3 number ?
Options:
A)10000
B)20000
C)30000
D)40000
E)50000
Rationale: Explanation :
C is divisible by 3 with out integers.
Answer : Option C
Answer: C
Question: If 11 persons meet at a reunion and each person shakes hands exactly once with each of the others, what is the total number of handshakes?
Options:
A) 10•9•8•7•6•5•4•3•2•1
B) 10•10
C) 55
D) 45
E) 36
Rationale: We got #11 people who shake each other's hands once ==> a pair of 2
11!/9!2! = 11*10 / 2*1 = 55.
Hence answer C.
Answer: C
Question: A zinc-copper alloy with 5 kg of pure zinc would contain 90% of zinc. The alloy with 3 kg of 90% zinc alloy contains 84% of zinc. Calculate the weight and percentage of zinc in the zinc-copper alloy.
Options:
A)2.4 kg or 80%
B)1.4 kg or 88%
C)4.3 kg or 60%
D)7.4 kg or 18%
E)1.4 kg or 60%
Rationale: Right Answer Explanation:
x : 5
y : 100
90
10 : 90 – y
(90-y)/5 = 10/x = ………..(1)
In the second case,
x 3
y 90
84
6 84-y
Therefore (84-y)/3 = 6/x ………..(2)
Dividing (1) and (2)
=
810 – 9y = 2100 – 25y
16y = 1290
y = 80.625
x = 50/(90-80.625) = 50/9.375 = 5.33 kg
Quantity of zinc in x = 80.625% of x
= 0.80625 5.33
= 4.3 kg
Weight and percentage of zinc is 4.3 kg or 80.625%
C
Answer: C
Question: If the charge of staying in a student youth hostel $18.00/day for the first week, and $12.00/day for each additional week, How much does it cost to stay for 23 days?
Options:
A)$318
B)$289
C)$282
D)$274
E)$286
Rationale: Total number of days of stay = 23
Charge of staying in first week = 18*7 = 126 $
Charge of staying for additional days =(23-7)*12 = 16*12 = 192 $
Total charge =126 +192 = 318$
Answer A
Answer: A