divelab/Sys2Bench huggingface dataset:
Question: If A speaks the truth 75% of the times, B speaks the truth 60% of the times. What is the probability that they tell the truth at the same time
Options:
A)0.49
B)0.48
C)0.45
D)0.482
E)0.411
Rationale: Explanation:
Probability that A speaks truth is 75/100 = 0.75
Probability that B speaks truth is 60/100 = 0.6
Since both A and B are independent of each other
So probability of A intersection B is P(A) × P(B) =0.75 × 0.6 = 0.45
Answer: C
Answer: C
Question: The salary of Mr. X is 30% more than that of Mr. Y . Find what percent of Mr. Y’s salary is less than Mr. X’s?
Options:
A)23 1/8%
B)23 7/3%
C)23 1/3%
D)23 1/3%
E)53 3/3%
Rationale: y=100	x=130
130---------30
100---------? => 23 1/3%
Answer:C
Answer: C
Question: A bag of potatoes weighs 50 lbs divided by half of its weight. How much does the bag of potatoes weight?
Options:
A)20 lb
B)30 lb
C)10 lb
D)15 lb
E)5 lb
Rationale: Sol.
50÷5 = 10.
Answer : C
Answer: C
Question: If xy > 0, which of the following must be negative?
Options:
A)-x/y
B)xy
C)x/y
D)2xy
E)2x/y
Rationale: - / + = -
Answer : A
Answer: A
Question: The length of the bridge, which a train 140 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
Options:
A)200 m
B)235 m
C)245 m
D)250 m
E)270 m
Rationale: Let the length of the bridge:L
The equation now is L+140/12.5m/s(45km/hr or12.5m/s)=30
Solving, L =235m
ANSWER:B
Answer: B
Question: Which is a better investment 5% stock at 412 or 3 3/2 stock at 360?
Options:
A)5% stock at 412
B)Both are equally good
C)Cannot be compared, as the total amount of investment is not given
D)None
E)3 3/2 stock at 360
Rationale: Let investment in each case be Rs. (412 x 360).
Income in 1st case = Rs.5 x 412 x 360/412	= Rs. 1800.
Income in 2nd case = Rs.9 x 412 x 360/(2*117)	= Rs. 5704.6
Clearly, 3 3/2 stock at 360 is better.
ANSWER:E
Answer: E
Question: A, B and C started a business with capitals of Rs. 8000, Rs. 10000 and Rs. 12000 respectively. At the end of the year, the profit share of B is Rs. 1900. The difference between the profit shares of A and C is?
Options:
A)288
B)760
C)155
D)600
E)441
Rationale: Ratio of investments of A, B and C is 8000 : 10000 : 12000 = 4 : 5 : 6
And also given that, profit share of B is Rs. 1900
=> 5 parts out of 15 parts is Rs. 1900
Now, required difference is 6 - 4 = 2 parts
Required difference = 2/5 (1900) = Rs. 760
Answer:B
Answer: B
Question: 66 cubic centimetres of silver is drawn into a wire 1 mm in diameter. The length if the wire in meters will be:
Options:
A)76 m
B)80 m
C)84 m
D)88 m
E)90 m
Rationale: Explanation:
Let the length of the wire be h
Radius=1/2mm=1/20cm
πr2h=66
(22/7)*(1/20)*(1/20)*h=66
=>h=(66∗20∗20∗7) / 22
=8400cm
=84m
ANSWER IS C
Answer: C
Question: 4 professors and 6 students are being considered for membership on a supervisory committee which must consist of 3 people. If the committee has to include at least 1 professor, how many ways can this committee be formed?
Options:
A)36
B)60
C)72
D)80
E)100
Rationale: combinations:
1 professor 2 students
students: 6 x 5 / 2 = 15
15*4 = 60
2 professors 1 student
4 x 3 / 2 = 6
6*6 = 36
3 professors
4/1 = 4
60 + 36 + 4 = 100
ANS:E
Answer: E
Question: A,B,C together can do a work in 8 days. A alone can do the work in 30 days and B alone can do the same work in 20 days. Find in what time C alone can do that work?
Options:
A)16days
B)20.8days
C)24days
D)28.5days
E)32.4days
Rationale: The required answer is = 8*30*20 / 30*20-8(30+20)
= 4800/200 = 24days
Answer is C
Answer: C
Question: Find the value of 72519 x 9999 = m?
Options:
A)345466221
B)345455672
C)353456678
D)725117481
E)789545233
Rationale: 72519 x 9999 = 72519 x (10000 - 1)
= 72519 x 10000 - 72519 x 1
= 725190000 - 72519
= 725117481
D
Answer: D
Question: The compound interest on $ 30,000 at 7% per annum is $4347. The period (in years) is:
Options:
A)2
B)21/2
C)3
D)4
E)5
Rationale: Amt = $(30000+4347) = $34347
let the time be n yrs then 30000(1+7/100)^n=34347
(107/100)^n=34347/30000=(107/100)^2
n = 2 yrs
ANSWER A
Answer: A
Question: It is known that no more than 8 children will be attending a party. What is the smallest number of cookies that must be brought to the party so that each child receives the same number of cookies?
Options:
A)35
B)105
C)180
D)210
E)840
Rationale: The question states that there are no more than 8 children in the party. Thus, the possibility is that there could be 1, 2, 3, 4, 5, 6,7 or 8 children.
If you assume answer as 35 and there are 3 children, you may not distribute be able to distribute cookies equally.
similarly if there were 105 cookies, and 2 children, cookies cannot be distributed equally.
or if there were 210 cookies, and 4 children, cookies cannot be distributed equally.
Thus, the question asks for a number of cookies which can be distributed to any number of children (from 1 to 8).
And therefore the smallest number of cookies would be lcm of (1, 2, 3, 4, 5, 6, 7,8), i.e., 840.
Answer (E)
Answer: E
Question: A, B and C rents a pasture for Rs.435. A put in 12 horses for 8 months, B 16 horses for 9 months and 18 horses for 6 months. How much should C pay?
Options:
A)120
B)227
C)268
D)198
E)176
Rationale: 12*8 :16*9 = 18*6
8: 12: 9
8/29 * 435 = 120
Answer:A
Answer: A
Question: Of all the students in a certain dormitory, 1/2 are first-year students and the rest are second-year students. If 4/5 of the first-year students have not declared a major and if the fraction of second-year students who have declared a major is 1 times the fraction of first-year students who have declared a major, what fraction of all the students in the dormitory are second-year students who have not declared a major?
Options:
A)1/15
B)1/5
C)4/15
D)1/3
E)2/5
Rationale: tot students=x
1st year student=x/2----> non majaor=4/5(x/2)-----> maj=1/5(x/2)
2nd year student=x/2---->maj=1(1/5(x/2))=1/10(x)--->non major=x/2-1/10(x)=2/5(x)
hence 2/5
E
Answer: E
Question: Mother is aged thrice than her daughter Silvia. After 8 years, he would be 2(1/2) times of Silvia’s age. After 8 years, how many times would she be of Silvia’s age?
Options:
A)2 years
B)4 years
C)3 years
D)5 years
E)6 years
Rationale: A
2 years
Let Silvia’s current age is A years.
Then, mom’s current age = (A + 3A) years = 4A years.
(4A + 8) = (5/2) (A + 8)
=> 8A + 16 = 5A + 40
=> 3A = 24
A = 8
Needed ratio = { (4A + 16)/(A+16) }
= 48/24
= 2
Answer: A
Question: One fish tank is half full. After adding 10 gallons the tank is 7/8 of the tank. Calculate the capacity of the fish tank.
Options:
A)80/3 gallons
B)90/3 gallons
C)70/3 gallons
D)60/3 gallons
E)50/3 gallons
Rationale: If x is capacity of full tank, then
x*(7/8-1/2) =10
x*3/8=10
x= 80/3 gallons
ANSWER:A
Answer: A
Question: Raji,Lakshmi and Priya enter into partnership. Raji invests some money at the beginning, Lakshmi invests double the amount after 6 months, and Priya invests thrice the amount after 8 months. If the annual gain be Rs.12000. Priya's share is?
Options:
A)2500
B)3500
C)4500
D)2800
E)4000
Rationale: x* 12 : 2x* 6: 3x* 4
1:1:1
1/3 * 12000 = 4000
Answer: E
Answer: E
Question: Present ages of X and Y are in the ratio 5:6 respectively. Seven years hence this ratio will become 6:7 respectively. What is X's present age in years?
Options:
A)35 years
B)77 years
C)55 years
D)44 years
E)33 years
Rationale: Let the present ages of X and Y be 5x and 6x years respectively.
Then, (5x + 7)/(6x + 7) = 6/7
7(5x + 7) = 6(6x + 7) => x = 7
X's present age = 5x = 35 years.Answer: A
Answer: A
Question: In how many different number of ways a Committee of 3person of can be selected from 4boys and 3girls such that at least 1 girl is included in the committe
Options:
A)30
B)29
C)31
D)17
E)85
Rationale: 1G 2B 2G 1B 3G
=(3C1*4C2)+(3C2*4C1)+3C3
=(3*6)+(3*4)+1
=18+12+1=31
Total 4M 3W
7C3=35
4C3=4
At least one girl = total - with out girl
At least one girl =35-4=31
C)
Answer: C
Question: The area of a parallelogram is 1764sq m and its base is nine times size of the corresponding altitude. Then the length of the base is?
Options:
A)21
B)9
C)11
D)14
E)7
Rationale: 9x * x = 1764 => x
= 14
Answer: D
Answer: D
Question: In order to fence a square Manish fixed 48 poles. If the distance between two poles, is 3 metres then what will be the area of the square so formed?
Options:
A)Cannot be determined
B)2600 cm2
C)2500 cm2
D)1296 cm2
E)None of these
Rationale: Let the side of the square be x m.
∴ Perimeter of the square = 48 × 3 = 4x ∴ x = 36 m
∴ Area = (36)2 = 1296 m2
Answer D
Answer: D
Question: After decreasing 20% in the price of an article costs Rs.200. Find the actual cost of an article?
Options:
A)280
B)250
C)260
D)270
E)300
Rationale: CP* (80/100) = 200
CP= 2.5* 100 => CP = 250
Answer: B
Answer: B
Question: During a certain two-week period, 76 percent of the movies rented from a video store were comedies, and of the remaining movies rented, there were 5 times as many dramas as action movies. If no other movies were rented during that two-week period and there were A action movies rented, then how many comedies, in terms of A, were rented during that two-week period?
Options:
A)16A
B)19A
C)17A
D)18A
E)20A
Rationale: Total movies = 100.
Comedies = 76.
Action + Drama = 24. Since there were 5 times as many dramas as action movies, then Action + 5*Action = 24 --> Action = A = 4.
Comedies = 76 = 19A.
Answer: B.
Answer: B
Question: A store sells branded shirts for $20 each and unbranded shirts $16 each. On every branded shirt, the store makes a profit of $6 while on every unbranded shirt it makes a profit of $4. If on a given day the store's sales amounted to $960, which of the following cannot be the profit made on that day?
Options:
A)$264
B)$268
C)$270
D)$272
E)$276
Rationale: $270 is the only option that does not satisfy a combination of integer number sales of branded and unbranded shirts sales. Answer: C
Answer: C
Question: A fruitseller sells mangoes at the rate of Rs.9 per kg and thereby loses 20%.At what price per kg,he should have sold them to make a profit of 5% ?
Options:
A)Rs.11.81
B)Rs.12
C)Rs.12.25
D)Rs.12.31
E)None
Rationale: Solution
80 : 9 = 105 : x or x =(9x105/80) = 11.81.
Hence, S.P. per kg. = Rs.11.81.
Answer A
Answer: A
Question: A motorcyclist goes from Bombay to Pune, a distance of 192 kms at an average of 32 kmph speed. Another man starts from Bombay by car 2 ½ hours after the first, and reaches Pune ½ hour earlier. What is the ratio of the speed of the motorcycle and the car?
Options:
A)3:5
B)4:5
C)2:5
D)2:4
E)2:7
Rationale: T = 160/32 = 5 h
T = 5 - 3 = 2
Time Ratio = 5:2
Speed Ratio = 2:5
ANSWER:C
Answer: C
Question: A shipment of 1500 heads of cabbage, each of which was approximately the same size was purchased for $600.The day the shipment arrived 2/3 of the heads were sold, each at 25% above the cost per head.The following day the rest were sold at a price per head equal to 10% less than the price each head sold for the day before.what was the gross profit E on this shipment?
Options:
A)a) $100
B)b) $115
C)c) $125
D)d) $130
E)e) $135
Rationale: I recommend one should use fractions to solve this one rather than converting it into decimals
Sol:
1500 heads -> $600
1 head -> $600/1500
1 head -> $(2/5)
25% more of (2/5) -> 125/100 * 2/5 = $(1/2)
He sold 2/3*1500 = 1000 heads for $(1/2) per head
Total revenue by selling 1000 heads = 1000 * 1/2 = $500
Heads left: 500
Cost per head: 90% of the previous price: 90/100 * 1/2 = $(9/20)
Total revenue by selling 500 heads = 9/20 * 500 = 225
Total revenue after selling 1500 cabbage heads - 225+500 = $725
Money spent on the purchase: $600
Profit E= 725-600 = $125
Ans:C
Answer: C
Question: The sum of first five prime numbers is:
Options:
A)28
B)72
C)55
D)33
E)58
Rationale: A
Required sum = (2 + 3 + 5 + 7 + 11) = 28.
Note: 1 is not a prime number.
Definition: A prime number (or a prime) is a natural number that has exactly two distinct natural number divisors: 1 and itself.
Answer: A
Question: The circumference of a circle is equal to 72 pi. Find the radius of this circle.
Options:
A)35
B)36
C)37
D)38
E)39
Rationale: The circumference of a circle is given by
C = 2 pi r, where r is the radius of the circle.
Substitute C by 72 pi to obtain the equation
72 pi = 2 pi r
Simplify and solve for r to obtain
r = 36
Answer B
Answer: B
Question: There are three numbers. 5/7th of the first number is equal to 48% of the second number. The second number is 1/9th of the third number. If the third number is 1125, then find 25% of the first number?
Options:
A)16
B)18
C)12
D)21
E)10
Rationale: Let the first number and the second number be F and S respectively.
5/2 F = 48/100 S ----> (1)
S = 1/9 * 1125 = 125
(1) => 5/7 F = 48/100 * 125
=> F = 84
25% of F = 1/4 * 84 = 21.
Answer: D
Answer: D
Question: A rectangular field has to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 680 sq. feet, how many feet of fencing will be required?
Options:
A)80
B)82
C)84
D)88
E)86
Rationale: Area of the field =680 sq. feet.
Length of the adjacent sides are
20 feet and 68020=34 feet.
Required length of the fencing
=20+34+34=88 feet
Answer is D.
Answer: D
Question: Anil purchases two books for Rs.100. He sells first at loss of 5% and second al 20% profit. If he gets Overall profit of 5% then what is cost of first book?
Options:
A)Rs.45
B)Rs.60
C)Rs.55
D)Rs.58
E)Rs.56
Rationale: If cost of first book=x then second book=100-x
According to given condition x*(95/100) + (100-x)*(120/100) =100*(105/100) or
0.95x +120 -1.2x=105
x=60
ANSWER:B
Answer: B
Question: A group of boy scouts and girls scouts is going on a rafting trip. 80% of the scouts arrived with signed permission slips. If 40% of the scouts were boy scouts and 75% of the boy scouts arrived with signed permission slips, then what percentage of the girl scouts arrived with signed permission slips? Round to the nearest percent.
Options:
A)79
B)81
C)82
D)83
E)85
Rationale: 40% were boy scouts so 60% (100-40=60) were girl scouts.
# of boy scouts with permission slips signed + # of girl scouts with permission slips signed = total # with permission slip signed
(75% of 40% of the total going) + (?% of 60% of the total going) = 80% of the total going
We can let the "total going" = 100 arbitrarily since we only care about the percent (of girl scouts w/ permission signed)
.75*.40*100 + x*.60*100 = .80*100
30 + x*60 = 80
60x=50
x=50/60
x=.833333
converting this to a percent, we have 83%
D
Answer: D
Question: Ifaequals the sum of the even integers from 2 to 20, inclusive, andbequals the sum of the odd integers from 1 to 19, inclusive, what is the value of a + b ?
Options:
A)110
B)100
C)190
D)200
E)210
Rationale: Answer is 10
Yes! there is really a faster way to solve it.
Sum of consecutive odd or even integers = (no. of odd or even ints) * (first int + last int) / 2
Here A = sum of even ints from 2 to 20, inclusive
number of even ints = 10,
first int + last int = 2+20 = 22
A = 10*22 / 2 = 110
B = sum of odd ints from 1 to 19, inclusive
number of odd ints = 10,
first int + last int = 1+19 = 20
A = 10*20 / 2 = 100
A+B = 110 + 100 = 210
Ans :E
Answer: E
Question: We bought 85 hats at the store. Blue hats cost $6 and green hats cost $7. The total price was $540. How many green hats did we buy?
Options:
A)A)36
B)B)30
C)C)40
D)D)42
E)E)44
Rationale: Let B be the number of blue hats and let G be the number of green hats.
B+G=85.
B=85-G.
6B+7G=540.
6(85-G)+7G=540.
510-6G+7G=540.
G=540-510=30.
The answer is B.
Answer: B
Question: If a man can cover 12 metres in one second, how many kilometres can he cover in 3 hours 45 minutes?
Options:
A)157
B)162
C)882
D)155
E)101
Rationale: 12 m/s = 12 * 18/5 kmph
3 hours 45 minutes = 3 3/4 hours = 15/4 hours
Distance = speed * time = 12 * 18/5 * 15/4 km
= 162 km.
Answer: B
Answer: B
Question: The price of a certain house this year is $140,000, which is 25 percent greater than the cost of the house last year. What was the price of the house last year?
Options:
A)$112,000
B)$114,000
C)$116,000
D)$118,000
E)$120,000
Rationale: The price of the house last year was $140,000/1.25=$112,000
The answer is A.
Answer: A
Question: The ratio between x and y is 8/3; x is multiplied by x and y is multiplied by y , what is the ratio between the new values of x and y?
Options:
A)8/3
B)3/8
C)1
D)64/9
E)It Cannot Be Determined
Rationale: Ratio = 7k/9k = 7/9, 14/18, etc.
x is multiplied by x and y is multiplied by y --> (7k*7k)/(9k*9k) = 49k^2 / 81k^2 =49/81 =7/9
Answer: A
Answer: A
Question: A function g(n), where n is an integer, is defined as the product of all integers from 1 to n. How many of the followings must be a prime number?
g(7) + 2; g(7) + 3; g(7) + 4; and g(7) + 5?
Options:
A)1
B)2
C)3
D)4
E)none
Rationale: g(7) is the product of all integers from 1 to 7, so g(7) = 7!
Thus g(7) is a multiple of all the integers from 1 to 7.
Then g(7) is a multiple of 2, 3, 4, and 5.
2 divides g(7)+2
3 divides g(7)+3
4 divides g(7)+4
5 divides g(7)+5
The answer is E.
Answer: E
Question: Three unbased coins are tossed. the probability of getting at least two head is ?
Options:
A)1/4
B)1/2
C)3/4
D)2/3
E)2/5
Rationale: S={TTT,TTH,THT,HTT,THH,HTH,HHT,HHH}
E be the event of getting at least two head is {THH,HTH,HHT,HHH}
P(E)=n(E)/n(S)=4/8=1/2
Answer(B)
Answer: B
Question: The distance light travels in one year is approximately 5,890,000,000,000 miles. The distance light travels in 100 years is
Options:
A)A) 587 × 108 miles
B)B) 587 × 1010 miles
C)C) 587 × 10-10 miles
D)D) 589 × 1012 miles
E)E) 587 × 10-12 miles
Rationale: The distance of the light travels in 100 years is:
5,890,000,000,000 × 100 miles.
= 589,000,000,000,000 miles.
= 589 × 1012 miles.
The answer is (D)
Answer: D
Question: Adding 35% of x to x is equivalent to multiplying x by which of the following?
Options:
A)12.5
B)1.05
C)1.35
D)1.2
E)1.25
Rationale: 135x/100= 1.35*x
ANSWER:C
Answer: C
Question: A, B, C rent a pasture. A puts 10 oxen for 7 months, B puts 12 oxen for 5 months and C puts 15 oxen for 3 months for grazing. If the rent of the pasture is Rs. 175, how much must C pay as his share of rent?
Options:
A)Rs. 45
B)Rs. 50
C)Rs. 55
D)Rs. 60
E)None
Rationale: Solution: A : B : C = (10 * 7) : (12 * 5) : (15 * 3) = 70 : 60 : 45 = 14 : 12 : 9.
C's rent = Rs.(175 * 9/35) = Rs. 45.
Answer: Option A
Answer: A
Question: A company has two models of computers, model X and model Y. Operating at a constant rate, a model X computer can complete a certain task in 60 minutes and a model Y computer can complete the same task in 30 minutes. If the company used the same number of each model of computer to complete the task in 1 minute, how many model X computers were used?
Options:
A)18
B)16
C)15
D)17
E)20
Rationale: Let's say 1 work is processing 60 gb of data.
Model X : 1 gb per min
Model Y : 2 gb per min
Working together, 1 X and 1 Y = 3 gb per min
So, 20 times as many computers would work at 60 gb per min.
So no. of X =20
Answer is E
Answer: E
Question: A set M contains element all even number between 1 and 23 and all odd numbers 24 and 100. if all the elements of the set multiplied than how many trailing 0 , resulting number will contains?
Options:
A)10
B)12
C)9
D)8
E)7
Rationale: m={10,20 } &{25,35,45,55,65,75,85,95}
in set m number of 5 is 12.
ANSWER:B
Answer: B
Question: If the ratio of boys to girls in a class is B and the ratio of girls to boys is G; then 3 (B + G) is ?
Options:
A)Equal to 3
B)Less than 3
C)More than 3
D)Less than 1/3
E)none of these
Rationale: Let number of boys = x
Let number of girls = y
Therefore x/y = B and y/x = G
3(B + G) = 3[(x/y) + (y/x)] = 3[(x2 + y2)/xy] > 3
ANSWER:C
Answer: C
Question: Two trains 200m and 160m long run at the speed of 68kmph and 40kmph in opposite directions in parallel tracks. The time which they take to cross each other is?
Options:
A)5.6sec
B)8.9sec
C)10.8sec
D)12 sec
E)15sec
Rationale: Relative speed = 68+40 = 108kmph * 5/18 = 30 m/s
Distance covered in crossing each other = 200+160 = 360m
Required time = 360*1/30 = 12 sec
Answer is D
Answer: D
Question: Anne bought doughnuts for a class breakfast party. She bought 12 chocolate doughnuts, 12 coconut doughnuts, and 10 jam-filled doughnuts. How many doughnuts did Anne buy in all?
Options:
A)25
B)34
C)39
D)21
E)11
Rationale: Add the numbers of doughnuts.
12 + 12 + 10 =34.
Answer is B.
Answer: B
Question: A is half good a work man as B and together they finish a job in 14 days. In how many days working alone B finish the job?
Options:
A)22
B)21
C)77
D)99
E)12
Rationale: WC = 1:2
2x + x = 1/14 => x = 1/42
2x = 1/21 => 21 days
Answer: B
Answer: B
Question: The mass of 1 cubic meter of a substance is 400 kilograms under certain conditions. What is the volume, in cubic centimeters, of 1 gram of this substance under these conditions? (1 kilogram = 1,000 grams and 1 cubic meter = 1,000,000 cubic centimeters)
Options:
A)0.8
B)1.25
C)8.0
D)2.5
E)80.0
Rationale: Density is mass divided by volume. So density of the given substance will be mass/volume=400kg/1m^3=400 kg/m^3 or 1g/2.5cm^3=0.4 g/cm^3.
Next, ask yourself if 400,000 g is equivalent to 1,000,000 cubic centimeters then 1 g is equivalent to how many cubic centimeters? --> 1 g - 1,000,000/400,000 = 10/4 = 2.5 cubic centimeters.
Answer is D
Answer: D
Question: A, B and C play a cricket match. The ratio of the runs scored by them in the match is A:B =2:3 and B:C = 2:5. If the total runs scored by all of them are 75, the runs scored by B are?
Options:
A)20.23
B)18
C)30.93
D)20.93
E)10.93
Rationale: A:B = 2:3
B:C = 2:5
A:B:C =4:6:15
6/25 * 75 = 18
ANSWER:B
Answer: B
Question: Every year an amount increases by 1/8th of itself. How much will it be after two years if its present value is Rs.32000?
Options:
A)81000
B)33888
C)77678
D)200988
E)40500
Rationale: 32000* 9/8 * 9/8
= 40500
Answer: E
Answer: E
Question: When 5% is lost in grinding wheat, a country has to import 20 million bags; but when only 2% is lost, it has to import only 15 million bags. Find the quantity of wheat, which grows in the country?
Options:
A)166 2/9
B)166 2/5
C)166 2/8
D)166 2/3
E)166 2/1
Rationale: 5% - 2% = 3%
3% ---- 5
100% ---- ?
=> 166 2/3
Answer:D
Answer: D
Question: Two pipes A and B can fill a cistern in 20 and 30 minutes respectively, and a third pipe C can empty it in 60 minutes. How long will it take to fill the cistern if all the three are opened at the same time?
Options:
A)15 min
B)15 1/7 min
C)17 1/7 min
D)7 1/7 min
E)7 2/7 min
Rationale: 1/20 + 1/30 - 1/60 = 4/60
60/4 = 15
ANSWER:A
Answer: A
Question: A goods train runs at a speed of 72 kmph and crosses a 260 m long platform in 26 seconds.What is the length of the goods train?
Options:
A)230 m
B)240 m
C)260 m
D)270 m
E)250 m
Rationale: s=260+x/t
72*5/18=260+x/26
x=260
ANSWER:C
Answer: C
Question: Along a yard 225 metres long, 26 trees are palnted at equal distances, one tree being at each end of the yard. What is the distance between two consecutive trees
Options:
A)8
B)9
C)10
D)11
E)12
Rationale: Explanation:
26 trees have 25 gaps between them,
Required distance (225/25) = 10
Option B
Answer: B
Question: Three printing presses, W, S, and T, working together at their respective constant rates, can do a certain printing job in 4 hours. S and T, working together at their respective constant rates, can do the same job in 5 hours. How many hours would it take W, working alone at its constant rate, to do the same job?
Options:
A)8
B)10
C)12
D)15
E)20
Rationale: =1/4-1/5=1/20
W can do 1/20 job in 1 hour
W can do the whole job in 20 hours=E
Answer: E
Question: An urn contains 5 red, 6 blue and 8 green balls. 3 balls are randomly selected from the urn, find the probability that the drawn ball are 2 blue and 1 red?
Options:
A)25/323
B)21/969
C)28/989
D)74/879
E)23/589
Rationale: Sample space = no. of ways 3 balls were drawn from urn = 19C3 = 969
No. ways 2 blue balls and 1 red were drawn from bag = 6C2 * 5C1 = 75
Probability = 75 / 969 =25/323
Ans - A
Answer: A
Question: If the SI on a certain sum of money is 4/25 of the sum and the rate per cent equals the number yrs, then the rate of interest/annum is?
Options:
A)4%
B)55
C)6%
D)7%
E)9%
Rationale: Sol Let the prmcipal be Rs. x
Then the simple interest (1)
Let the me ofinterestp 3 be 1%,
than tune m : ryears
max! max
pm
‘X:5
4%
A
Answer: A