divelab/Sys2Bench huggingface dataset:
Question: The length of rectangle is thrice its breadth and its perimeter is 104 m, find the area of the rectangle?
Options:
A)507 sq m
B)356 sq m
C)452 sq m
D)428 sq m
E)525 sq m
Rationale: 2(3x + x) = 104
l = 39 b = 13
lb = 39 * 13 = 507
ANSWER:A
Answer: A
Question: Two trains are running in opposite directions with the same speed. If the length of each train is 180 m and they cross each other in 12 sec, then the speed of each train is?
Options:
A)54
B)26
C)36
D)99
E)27
Rationale: Let the speed of each train be x m/sec.
Then, relative speed of the two trains = 2x m/sec.
So, 2x = (180 + 180)/12 => x = 15
Speed of each train = 15 m/sec.
= 15 * 18/5 =54 km/hr.
Answer: A
Answer: A
Question: Which of the following numbers has more than two distinct prime factors?
Options:
A)385
B)422
C)425
D)471
E)500
Rationale: 385=5*7*11
422=2*211
425=5^2*17
471=3*157
500=2^2 * 5^3
385 has 3 distinct prime factors
Answer A
Answer: A
Question: A certain lab experiments with white and brown mice only. In one experiment, 2/3 of the mice are white. If there are 7 brown mice in the experiment, how many mice in total are in the experiment?
Options:
A)39
B)33
C)26
D)21
E)10
Rationale: Let total number of mice = M
Number of white mice = 2/3 M
Number of brown mice = 1/3 M = 7
=> M = 21
Answer D
Answer: D
Question: If 2x + 3y = 37; 2y + z = 19 and x + 2z = 29, what is the value of x + y + z ?
Options:
A)18
B)32
C)25
D)22
E)None of these
Rationale: On solving equation we get
x = 11, y = 5, z = 9
Answer C
Answer: C
Question: A train passes a station platform in 36 seconds and a man standing on the platform in 23 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Options:
A)37
B)240
C)288
D)195
E)211
Rationale: Speed = (54 * 5/18) m/sec = 15 m/sec. Length of the train = (15 x 23)m = 345 m. Let the length of the platform be x meters. Then, (x + 345)/36 = 15 ==> x + 345 = 540 ==> x = 195 m.Answer: D
Answer: D
Question: The dimensions of a room are 25 feet * 15 feet * 12 feet. What is the cost of white washing the four walls of the room at Rs. 2 per square feet if there is one door of dimensions 6 feet * 3 feet and three windows of dimensions 4 feet * 3 feet each?
Options:
A)s.4528
B)s.1812
C)s.4527
D)s.4530
E)s.4521
Rationale: Area of the four walls = 2h(l + b)
Since there are doors and windows, area of the walls
= 2 * 12 (15 + 25) - (6 * 3) - 3(4 * 3)
= 906 sq.ft.
Total cost = 906 * 2
= Rs.1812
Answer:B
Answer: B
Question: Large, medium and small ships are used to bring water. 4 large ships carry as much water as 7 small ships; 3 medium ships carry as much water as 2 large ships and 1 small ship. If 15 large, 7 medium and 14 small ships, each made 36 journeys to bring a certain quantity of water , then in how many journeys will 12 large, 14 medium and 21 small ships bring the same quantity of water?
Options:
A)29 journeys
B)30
C)20
D)50
E)55
Rationale: Explanation :
Here, Large, Medium and Small ships are denoted by the symbol L, M and S.
Now, according to the question,
4L = 7S. ------(i)
3M = 2L + S. ------(ii)
Using above equations, the ratios of the capacity of the Large, Medium and Small ships are :-
7: 6 : 4.
Let, the number of journeys required be x. Since, quantity of water remains the same, so :-
=((15×7+7×6+14×4)36) = x (12×7+14×6+21×4).
=>((15×7+7×6+14×4)36) / (12×7+14×6+21×4)= x
=>x=7308/252
=>x=29.
Answer : A
Answer: A
Question: A mixed doubles tennis game is to be played between two teams. There are four married couples. No team is to consist of a husband and his wife. What is the maximum number of games that can be played.
Options:
A)12
B)21
C)36
D)42
E)46
Rationale: Let's denote the four couples by (A,a), (B,b), (C,c), and (D,d) where A,B,C,D are the husbands and a,b,c,d are the wives.
For a games, let's choose first the husbands. We have 4C2=4*3/2=6 possibilities. Now we know that the final number of games will be a multiple of 6, so we are down to two choices, C and D.
Once husbands were chosen, say A and B, let's count how many possibilities we have to choose their partners under the given restrictions.
We can choose a and b and we have to pair them as (A,b) and (B,a) - 1 possibility.
We can choose one of the wives, a or b, but we have to pair her with the other husband and in addition, we have to choose another partner for the second husband.
This we can do in 2*2 = 4 ways, as there are two possibilities to choose from a and b, then we have 2 possibilities to choose the other wife, c or d - 4 possibilities
Finally, we can choose the other two wives, c and d, and we have two possibilities to team them up with the men, (A,c), (B,d) or (A,d), (B,c) - 2 possibilities.
In conclusion, for every pair of husbands, we have 1 + 4 + 2 = 7 possibilities to choose their partners for the game.
Total number of possibilities 6 * 7 = 42.
Answer D.
Answer: D
Question: A triangle has a perimeter 14. The two shorter sides have integer lengths equal to x and x + 1. Which of the following could be the length of the other side?
Options:
A)6
B)7
C)8
D)9
E)5
Rationale: The SHORTER sides have integral lengths equal to x and x + 1
Let the longest side be 'a'
So, a + x + (x +1) = 14
a + 2x = 13.......eqn (1)
We know that the sum of the lengths of the shorter sides has to be more than the length of the longer one. i.e 2x+1> a
a =6
A
Answer: A
Question: If a mixture is 1⁄2 alcohol by volume and 3⁄2 water by volume, what is the ratio of the volume of alcohol to the volume of water in this mixture?
Options:
A)3⁄7
B)4⁄7
C)3⁄4
D)4⁄3
E)7⁄4
Rationale: Should be a sub-600 level Q..
volume= {1/2}/{3/2}=1/3
C
Answer: C
Question: David has d books, which is 3 times as many as Jeff and 3/2 as many as Paula. How many books do the three of them have altogether, in terms of d?
Options:
A) 2*d
B) 7/3*d
C) 10/3*d
D) 7/2*d
E) 9/2*d
Rationale: Although we could plug in a real value for d, the problem can be just as easily solved by setting up equations. However, let’s start by defining some variables. Since we are given that David has d books, we can use variable d to represent how many books David has.
number of books David has = d
number of books Jeff has = j
number of books Paula has = p
We are given that David has 3 times as many books as Jeff. We can now express this in an equation.
d = 3j
d/3 = j
We are also given that David has ½ as many books as Paula. We can also express this in an equation.
d = (3/2)p
2d/3 = p
Notice that we immediately solved forj in terms of d and p in terms of d. Getting j and p in terms of d is useful when setting up our final expression. We need to determine, in terms of d, the sum of the number of books for David, Jeff, and Paula. Thus, we have:
d + d/3 + 2d/3
=2d
The answer is A
Answer: A
Question: What comes next in the series?
16 72 38 94 50 __
Options:
A)11
B)25
C)17
D)19
E)16
Rationale: E
16
Each number reverses the previous number and adds 1 to each digit. Thus, in the first two terms, 16 reversed is 61, which then changes to 72. In the penultimate term, 50 reversed becomes 05, which in turn becomes 16 - by adding 1 to each digit.
Answer: E
Question: Johnny bought six peanut butter cans at an average price (arithmetic mean) of 38.0¢. If Johnny returned two cans to the retailer, and the average price of the remaining cans was 31¢, then what is the average price, in cents, of the two returned peanut butter cans?
Options:
A)5.5
B)11
C)52
D)66
E)67.5
Rationale: Total price of six cans = 6*38.0 = 228
Total price of 4 cans = 4*31 = 124
Total rice of two cans = 228 - 124 = 104
Average price of two cans = 104/2 = 52 c
Another way to do it is this:
Assume that the four leftover cans were of 31c each. The avg was 38c initially because the two cans were 38c each and were providing another 7c of cost to other 4 cans.
So cost of the two cans = 2*38 + 4*7 = 104
Avg cost of the two cans = 104/2 = 52c
Answer (C)
Answer: C
Question: A boy goes to his school from his house at a speed of 3 km/hr and returns at a speed of 2 km/hr. If he takes 5 hours in going and coming. the distance between his house and school is :
Options:
A)4.5 km
B)5.5 km
C)6 km
D)7 km
E)None
Rationale: Sol.
Average speed = [2*3*2 / 3+2] km/hr = 12/5 km/hr.
Distance travelled = [12/5 * 5] km = 12 km.
∴ Distance between house and school = [12/2] km = 6 km.
Answer C
Answer: C
Question: An analyst will recommend a combination of 2 industrial stocks, 2 transportation stocks, and 1 utility stocks. If the analyst can choose from 6 industrial stocks, 5 transportation stocks, and 3 utility stocks, how many different combinations of 5 stocks are possible?
Options:
A)12
B)460
C)60
D)450
E)720
Rationale: 6C2 * 5C2 * 3C1 = 15*10*3 = 450.
Answer: D
Answer: D
Question: The sum of three numbers is 98. If the ratio of the first to second is 2 :3 and that of the second to the third is 5 : 8, then the second number is:
Options:
A)30
B)40
C)20
D)10
E)60
Rationale: A: B = 2:3 and B:C = 5:8
=>(5*3/5):(8*3/5)
=>3:24/5
A:B:C = 2:3:24/5 = 10:15:24
B= 30
ANSWER A
Answer: A
Question: A certain bacteria colony doubles in size every day for 22 days, at which point it reaches the limit of its habitat and can no longer grow. If two bacteria colonies start growing simultaneously, how many days will it take them to reach the habitat’s limit?
Options:
A)6.33
B)7.5
C)21
D)15
E)19
Rationale: If there is one bacteria colony, then it will reach the limit of its habitat in 20 days.
If there are two bacteria colonies, then in order to reach the limit of habitat they would need to double one time less than in case with one colony. Thus colonies need to double 21 times.
Answer: C.
Similar questions to practice:
Hope it helps.
Answer: C
Question: A and B go around a circular track of length 1200 m on a cycle at speeds of 36 kmph and 54 kmph. After how much time will they meet for the first time at the starting point?
Options:
A)240 sec
B)165 sec
C)186 sec
D)167 sec
E)168 sec
Rationale: Time taken to meet for the first time at the starting point
= LCM { length of the track / speed of A , length of the track / speed of B}
= LCM { 1200/ (36 * 5/18) , 1200/ (54 * 5 /18) }
= LCM (120, 80)
=240 sec.
Answer:A
Answer: A
Question: David mixed 10 kg of ghee at Rs. 200 per kg with 30 kg ghee at the rate of Rs. 100 per kg. At what price per kg should he sell the mixture to make a profit of 10% in the transaction?
Options:
A)Rs. 110
B)Rs. 120
C)Rs. 130
D)Rs. 150
E)Rs. 160
Rationale: Cost of Ghee = 10*200+ 30*100 /40 =5000/40 = 125
20% of 125 = 25
S.P. should be = 125+25= Rs. 150/ kg
Answer : D
Answer: D
Question: How many three digits number greater than 600 can be formed using the digits 4,5,6,7,8?
Options:
A)85
B)65
C)75
D)25
E)15
Rationale: Clearly repetition of digits allowed. Also the hundredths place of the 3-digit number can be filled in by6,7,8 in 3 ways. Each of the ten's, one's place can be filled in 5 ways. Hence the total number of required numbers = 3*5*5 =75 Answer : C
Answer: C
Question: A solution of X pounds of water and sugar is boiled until 20% of the water content evaporates. Originally y% of sugar was present in the solution. After evaporation, what percentage of the solution is sugar?
Options:
A)100y/(1-y)
B)80y/(1-y)
C)75y/(1-y)
D)100y/(80-0.2y)
E)100y/(80+0.2y)
Rationale: Assume values when the options have a variable.
Say, x is 100 pounds. Say y% is 50% i.e. the solution had 50 pounds of sugar and 50 pounds of water.
20% water evaporates so 20/100 * 50 = 10 pounds of water evaporates leaving 40 pounds of water.
%age of sugar solution = 50/(50+40) * 100 = 55%
Put y = 50 in the options. Options (A), (B) and (C) make no sense since they will have a negative denominator. Option (E) gives 55% when you put y = 50.
Answer (E)
Answer: E
Question: Average weight of 10 people increased by 2 kg when one person of 45 kg is replaced by a new
man. Then weight of the new man is
Options:
A)50
B)55
C)60
D)65
E)70
Rationale: Explanation:
Total weight increased is 2 * 10 = 20.
So weight of new person is 45+20 = 65
Answer: Option D
Answer: D
Question: If the third day of the month is Monday, Which of the following will be the fifth day from 21st of that month?
Options:
A)Tuesday
B)Monday
C)Wednesday
D)Thursday
E)None of these
Rationale: 3rd dy is monday----so----1st day must be saturdy
1-8-15-22 are all saturdy..ok
so 21 will be friday so,
from firdy 5th day will be wednesday
ANSWER:C
Answer: C
Question: The compound ratio of 5:6, 3:2 and 4:5?
Options:
A)1:8
B)1:0
C)1:7
D)1:1
E)1:6
Rationale: 5/6 * 3/2 * 4/5 = 1/1
1:1
Answer: D
Answer: D
Question: $700 is divided amongst A,B and C so that A may get 2/3 as much as B and C together, B may get 6/9 as much as A and C together, then the share of A is
Options:
A)$100
B)$150
C)$125
D)$280
E)$250
Rationale: A:(B+C) = 2:3
A's share = 700*2/5 = $280
Answer is D
Answer: D
Question: If x = 7p and y = 5p + 1, then for what value of p, x is equal to y ?
Options:
A)1
B)0.5
C)2
D)-1
E)0
Rationale: Explanation:
x = y <=> 7p = 5p + 1 <=> 2q = 1 <=> p = 0.5
Answer: B
Answer: B
Question: A part of certain sum of money is invested at 9% per annum and the rest at 21% per annum, if the interest earned in each case for the same period is equal, then ratio of the sums invested is?
Options:
A)4:2
B)4:8
C)7:3
D)4:0
E)4:9
Rationale: 21:9
= 7:3
Answer: C
Answer: C
Question: There are 27 different three-digit integers that can be formed using only the digits 3, 4 and 5. If all 27 of the integers were listed, what would their sum be?
Options:
A)11,888
B)11,988
C)12,088
D)12,188
E)12,288
Rationale: There must be nine 3's in the hundreds place, nine 3's in the tens place, and nine 3's in the units place. This is also true for the 4's and 5's. Then the sum is:
9(333+444+555)=9*(1332)=11,988.
The answer is B.
Answer: B
Question: Rs. 800 becomes Rs. 956 in 3 years at a rate of S.I. If the rate of interest is increased by 4%, what amount will Rs. 800 become in 3 years?
Options:
A)2288
B)2677
C)1052
D)2872
E)18711
Rationale: S.I. = (956 - 800) = Rs. 156.
Rate = (100 * 156) / (800 * 3) = 6 1/2 %
Now rate = (6 1/2 + 4) = 10 1/2 %
New S.I. = (800 * 21/2 * 3/100) = Rs. 252
New amount = (800 + 252) = Rs. 1052.
Answer:C
Answer: C
Question: If the cost price of 60 boxes is equal to the selling price of 50 boxes, the gain percent is
Options:
A)5
B)10
C)15
D)20
E)25
Rationale: Let C.P. of each box be Re. 1.
Then, C.P. of 50 boxes = Rs. 50; S.P. of 50 boxes = Rs. 60.
Gain % = 10/50 * 100 = 20%
Answer:D
Answer: D
Question: Let S be the set of all positive integers that, when divided by 8, have a remainder of 5. What is the 75th number in this set?
Options:
A) 597
B) 608
C) 613
D) 616
E) 621
Rationale: The set S = {5, 13, 21, 29, ..................... }
1st Number = 8 * 0 + 5 = 5
2nd Number = 8 * 1 + 5 = 13
3rd Number = 8 * 2 + 5 = 21
75th Number = 8 * (75-1) + 5 = 597
Answer = A
Answer: A
Question: A sum of money is divided among A, B, C & D in the ratio 3:5:8:9 respectively. If the share of D Rs.1872 more than the share of A, then what is the total amount of money of B & C together?
Options:
A)3000
B)4056
C)5000
D)5400
E)5600
Rationale: Sol. Share of B + C = -3 x (5 + 8) = Rs. 4056
B
Answer: B
Question: A, B, C, D and E are ve
consecutive odd numbers The sum of A and C is 146. What is
the value of E?
Options:
A)75
B)81
C)71
D)79
E)None of these
Rationale: A + C = 146
⇒ A + A + 4 = 146
⇒ A =146-4/2=71
∴ E = A + 8 = 71 + 8 = 79
Answer D
Answer: D
Question: Rs.1200 divided among P, Q and R. P gets half of the total amount received by Q and R. Q gets one-third of the total amount received by P and R. Find the amount received by R?
Options:
A)338
B)500
C)279
D)1277
E)198
Rationale: Let the amounts to be received by P, Q and R be p, q and r.
p + q + r = 1200
p = 1/2 (q + r) => 2p = q + r
Adding 'p' both sides, 3p = p + q + r = 1200
=> p = Rs.400
q = 1/3 (p + r) => 3q = p + r
Adding 'q' both sides, 4q = p + q + r = 1200
=> q = Rs.300
r = 1200 - (p + q) => r = Rs.500.
Answer: B
Answer: B
Question: In a question on division with zero remainder, a candidate took 12 as divisor instead of 36. The quotient obtained by him was 30. The correct quotient is?
Options:
A)A)10
B)B)24
C)C)28
D)D)29
E)E)30
Rationale: Number = (30 * 12) = 360
Correct quotient = 360/36 = 10
A)
Answer: A
Question: A seller of used cars has 12 cars to sell and each of his clients selected 4 cars that he liked most. If each car was selected exactly thrice, how many clients visited the garage?
Options:
A)9
B)10
C)12
D)14
E)16
Rationale: IfNo caris selected more than once then the number of clients = 12/4 = 3
But since every car is being selected three times so No. of Clients must be thrice as well =3*3 = 9
Answer: option A
Answer: A
Question: Find the least number must be subtracted from 724946 so that remaining no.is divisible by 10?
Options:
A)0
B)2
C)4
D)6
E)8
Rationale: On dividing 724946 by 10 we get the remainder 6, so 6 should be subtracted
D
Answer: D
Question: How many 4's are there preceded by 7 but not followed by 3?
5 9 3 2 1 7 4 2 6 9 7 4 6 1 3 2 8 7 4 1 3 8 3 2 5 6 7 4 3 9 5 8 2 0 1 8 7 4 6 3
Options:
A)4
B)6
C)3
D)5
E)None
Rationale: Answer: A) 4
Answer: A
Question: Two trains each 250 m in length are running on the same parallel lines in opposite directions with the speed of 80 kmph and 70 kmph respectively. In what time will they cross each other completely?
Options:
A)66 sec
B)88 sec
C)12 sec
D)87 sec
E)55 sec
Rationale: D = 250 m + 250 m = 500 m
RS = 80 + 70 = 150 * 5/18 = 125/3
T = 500 * 3/125 = 12 sec
Answer: C
Answer: C
Question: A drawer contains socks. When two socks are drawn at random, the
probability that both are red is 5/14. Which of the following can be
the number of socks in the drawer?
Options:
A)5
B)6
C)7
D)8
E)9
Rationale: If there are n socks, r of which are red, in the drawer, then the probability that
two chosen together at random are red is
r/n *
r - 1/n - 1
=
5/14
Therefore, r(r - 1) = 5k and n(n- 1) = 14k for some positive integer k. Since 14 must
divide n(n - 1), the only choices given which need be considered are n = 7 and n = 8. If
n = 7, then n(n -1) = 14k implies k = 3 but then r(r - 1) = 5k = 15 is an impossibility.
If n = 8, we get k = 4 and r = 5, a valid possiblity. Therefore, the answer is n = 8.
correct answer D
Answer: D
Question: A train 100 meters long completely crosses a 300 meters long bridge in 45 seconds. What is the speed of the train is?
Options:
A)12
B)15
C)18
D)7
E)32
Rationale: Explanation:
speed= Distance/ Time
S = (100 + 300)/45 = 400/45 * 18/5 = 32.
Answer: E
Answer: E
Question: How many four-digit integers exist such that all their digits are even?
Options:
A)80
B)100
C)120
D)125
E)500
Rationale: 0 is also an even integer
so last digit can be filled in 5 ways- 0,2,4,6,8
for both second and third digit there are 5 possibilities-
5 X 5 X 5 X 5 = 625
_______________
The first digit can be any of the four: 2, 4, 6, or 8. For both second, third and four digits, there are 5 possibilities. The answer is 4∗5∗5*5=500.
The correct answer is E
Answer: E
Question: A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 47, the how old is B?
Options:
A)10 years
B)12 years
C)14 years
D)18 years
E)16 years
Rationale: Let C's age be x years. Then, B's age = 2x years. A's age = (2x + 2) years.
(2x + 2) + 2x + x = 47
5x = 45
x = 9.
Hence, B's age = 2x = 19 years.
D)
Answer: D
Question: If Re.5 amounts to Rs.20 over a period of 3 years. What is the rate of simple interest?
Options:
A)80%
B)90%
C)100%
D)110%
E)115%
Rationale: 15 = (5*3*R)/100
R = 100%
Answer:C
Answer: C
Question: A mixture of 70 liters of wine and water contains 10% water. How much water must be added to make water 12 ½% of the total mixture?
Options:
A)12 liters
B)10 liters
C)4 liters
D)2 liters
E)3 liters
Rationale: 70 * (10/100) = 7
Wine Water
87 1/2% 12 1/2%
87 1/2% ------- 63
12 1/2% -------? => 9-7=2
ANSWER:D
Answer: D
Question: A machine puts c caps on bottles in n minutes. How many hours will it take to put caps on b bottles?
Options:
A)60bn/c
B)bc/60n
C)bn/60c
D)60b/cn
E)b/60cn
Rationale: A machine puts c caps on bottles in m minutes.
So, the machine puts 1 cap in n/c minutes
To put caps on b bottles, the machine will take bn/c minutes
In order to calculate the no. of hours taken , divide the product by 60.
So, our answer is bn/60c
Answer : C
Answer: C
Question: The cost price of 13 articles is equal to the selling price of 11 articles. Find the profit percent?
Options:
A)18 2/16
B)18 2/11
C)18 2/16
D)18 2/14
E)18 3/11
Rationale: 13 CP = 11 SP
11 --- 2 CP
100 --- ? =>18 2/11%
Answer:B
Answer: B
Question: A certain artist is selling five paintings for the following prices: $7,000, $8,000, $9,000, $23,000, and $25,000. If the price of the most expensive painting is increased $3,000, which of the following statements best describes the change in the mean and the median of the paintings?
Options:
A) The mean and the median will remain unchanged.
B) The mean will remain unchanged but the median will increase.
C) The mean will increase but the median will remain unchanged.
D) The mean and the median will increase by the same amount.
E) The mean and the median will increase by different amounts.
Rationale: Old set = {7000, 8000, 9000, 23000, 25000}.
New set = {7000, 8000, 9000, 23000, 28000} --> the median (middle term) will remain the same and the mean will increase.
Answer: C.
Answer: C
Question: A bike covers a certain distance at the speed of 77km/h in 7 hrs. If the bike was to cover the same distance in approximately 11 hrs, at what approximate speed should the bike travel?
Options:
A)53 km/h
B)52 km/h
C)51 km/h
D)50 km/h
E)49 km/h
Rationale: Ans.(E)
Sol. Total distance = 77 × 7 = 539 km
Now speed = 539/11 = 49km/h
Answer: E
Question: Triangle STV has sides ST = TV = 26, and SV = 20. What is the area?
Options:
A)160
B)180
C)200
D)220
E)240
Rationale: Let the base B of the triangle be SV = 20. Then we need to find the height H.
H^2 = 26^2 - 10^2 = 576 and then H = 24.
The area is (1/2)*B*H = 10*24 = 240
The answer is E.
Answer: E
Question: 10 friends are living in 10 different flats of an apartment. Each of them was allotted a parking spot to park their cars in the ground floor. But they used to park their cars randomly in any of the 10 parking spots. In how many ways can they park their cars so that exactly 8 people park their cars in the spots allotted to them?
Options:
A)35
B)40
C)45
D)50
E)55
Rationale: 10C8 = 45
The remaining 2 people in each case will be parked in each other's parking spots.
The answer is C.
Answer: C
Question: Three partners A,B,C invested 360000rs.,378000rs. and 414000rs.in a business.at the end of one year,there is profit of 64000rs.then calculate the profit share of C.
Options:
A)24000
B)23000
C)28000
D)2750
E)2880
Rationale: ratio of A,B,C investment=360000:378000:414000=20:21:23.
total profit=64000 rs.
share of C=[64000×23/64]=23000 rs.
answer B
Answer: B
Question: In three years, Janice will be three times as old as her daughter. Six years ago, her age was her daughter’s age squared. How old is Janice?
Options:
A)18
B)36
C)40
D)42
E)45
Rationale: Let Jane's age be J and daughters' age be D...
Given J + 3 = 3(D + 3 ) => J - 6 = 3D -> Eq1.
Given J-6 = (D-6)^2 --> Eq 2..
sub J-6 value in eq 2... 3D = D^2 - 12D + 36.
0 = D^2 - 15D + 36 => D = 12 or D = 3.
When D = 12 we get from eq 1... J+3 = 45 => J =42..
When D = 3 ..we get from eq 1.. J+3 = 18 => J = 15...
In the above options only 42 exits..
Answer: option D is correct answer..
Answer: D
Question: Michele invests 200 of her money in a mutual fund that quickly goes sour, losing 25% of its value each day for a week. Which of the following COULD BE be the value of Michele’s investment at the close-of-business any day that week?
Options:
A)$0.00
B)$133.00
C)$26.69
D)$1575.00
E)$10000.00
Rationale: Suppose she invests n$ in the starting then in the subesequent days the money left after the day will be
n/2, n/4, n/8, n/16, n/32
So, answer will be C
Answer: C