divelab/Sys2Bench huggingface dataset:
Question: Johnson has a corporate proposal. The probability that vice-president Adams will approve the proposal is 0.3. If VP Adams approves the proposal, then the probability that vice-president Baker will approve the proposal is 0.4. If VP Adams doesn’t approve the proposal, then the probability that vice-president Baker will approve the proposal is 0.3. What is the probability that at least one of the two VPs, approves Johnson’s proposal?
Options:
A)0.12
B)0.42
C)0.28
D)0.48
E)0.72
Rationale: (1at approves * second rejects ) + (1st rejects * 2nd approves ) + (both approves )
=0.3*0.2+0.4*0.3+0.6*0.4
= 0.06+0.12+0.24
=0.42
B
Answer: B
Question: A can do a piece of work in 16 days and B can do it in 15 days and C can do it 20 days. They started the work together and A leaves after 2 days and B leaves after 4 days from the beginning. How long will work lost?
Options:
A)10 2/5
B)10 2/0
C)12 1/6
D)10 2/1
E)12 2/3
Rationale: 2/16 + 4/15 + x/20 = 1
x = 73/6 = 12 1/6 Answer: C
Answer: C
Question: If the price of a computer were reduced by 12 percent, which of the following could not be the final price of the computer? (Assume initial price to be integer in cents)
Options:
A)$844.10
B)$895.40
C)$1,053.80
D)$1,135.20
E)$1,262.80
Rationale: Let X be the initial price of computer without discount
then price (final) after discount should be=X(1-12/100)------->X(22/25)=A(say)
means X=A*(25/22).....
so initial price to be integer(As per stem) final price must be multiple of 22
if we check options all were divisible by 22 except option (A)..which is Ans.
Ans A
Answer: A
Question: Town M	Town N	Town O	Town P	Town Q	Town R ; Town A Town B Town C Town D Town E Town F In the table above, what is the least number of table entries that are needed to show the mileage between each Town and each of the other five Towns?
Options:
A)11
B)12
C)13
D)14
E)15
Rationale: Easy way to go about this problem is we have 6*6 = 36 enteries in table the least number of enteries would be (36 - 6) /2 since 6 enteries represent the distances between same points .
Alternatively this can be solved as combination problem.
Correct Answer E
Answer: E
Question: 15 buses are running between two places P and Q. In how many ways can a person go from P to Q and return by a different bus?
Options:
A)210
B)320
C)150
D)220
E)100
Rationale: we can go in any bus out of the 15 buses.
Hence He can go in 15 ways.
Since we can not come back in the same bus that he used for travelling,
we can return in 14 ways.
Total number of ways = 15 x 14 = 210
ANSWER:A
Answer: A
Question: The total number of plums that grow during each year on a certain plum tree is equal to the number of plums that grew during the previous year, less the age of the tree in years (rounded down to the nearest integer). During its 5th year, the plum tree grew 50 plums. If this trend continues, how many plums will it grow during its 6th year?
Options:
A)40
B)42
C)45
D)48
E)54
Rationale: 1st year : 0-1 (age), we take age = 0 (as the question says that we have to(rounded down to the nearest integer))
2ndyear : 1-2 (age), we take age = 1
3rd year : 2-3 (age), we take age = 2
4th year : 3-4 (age), we take age = 3
5th year : 4-5 (age), we take age = 4
6th year : 5-6 (age), we take age = 5
Thus for the 5th year = 50,
6th year = 50-5 = 45.
The correct answer is C.
Answer: C
Question: An integer n between 1 and 100, inclusive, is to be chosen at random. What is the probability that n(n+1) will be divisible by 5 ?
Options:
A)1/9
B)1/3
C)1/2
D)2/3
E)2/5
Rationale: n(n+1) to be divisible by 3 either n or n+1 must be a multiples of 3.
In each following group of numbers: {1, 2, 3, 4, 5}, { 6, 7, 8, 9, 10}, ..., {96, 97, 98, 99,100} there is EXACTLY 1 numbers out of 5 satisfying the above condition. For example in {1, 2, 3, 4, 5} n can be: 4 or 5. Thus, the overall probability is 2/5.
Answer: D.
Answer: E
Question: In 1990 the budgets for projects Q and V were $500,000 and $780,000, respectively. In each of the next 10 years, the budget for Q was increased by $30,000 and the budget for V was decreased by $10,000. In which year was the budget for Q equal to the budget for V ?
Options:
A) 1992
B) 1993
C) 1994
D) 1995
E) 1997
Rationale: Let the no of years it takes is x.
500+30x = 780-10x --> 40x = 280 and x=7.
Thus, it happens in 1997.
E.
Answer: E
Question: What is the average (arithmetic mean) of the numbers 16, 17, 18, 19 and 20?
Options:
A) 14.2
B) 16.5
C) 17
D) 17.5
E) 18
Rationale: {16, 17, 18, 19, 20}={18-2,18-1, 18, 18+1,18+2} --> the average = 18.
Answer: E.
Answer: E
Question: On a certain test, Bill scored 20 more points than John, but half as many points as Sue. If the sum of the scores of the three students was 200 points, how many points did Bill receive?
Options:
A)30
B)40
C)50
D)55
E)100
Rationale: consider john's points as x
so bill's points are x +20
So sue's points are 2x +40
total of all three students is 4x +60, but this total is given as 200
x = 35
so bill's points = 35 +20 = 55
correct answer option D
Answer: D
Question: which number need to add to 859622 to get a number exactly divisible by 456?
Options:
A)547896
B)243545
C)445321
D)354568
E)859622
Rationale: Dividend = Quotient * Divisor + Reminder
859622 / 456 gives quotient = 1885 and reminder = 62.
So, the next number divisible by 456 is 456 places infront of 456 * 1885
Which means 456 – 62 = 394 should be added to 859622.
E
Answer: E
Question: What is the total number of integers between 100 and 250 that are divisible by 5?
Options:
A)27
B)28
C)29
D)30
E)25
Rationale: 105, 110, 115, ..., 240,245
This is an equally spaced list; you can use the formula:
n = (largest - smallest) / ('space') + 1 = (245 - 105) / (5) + 1 = 140/5 + 1 = 28 + 1 = 29
Answer is C
Answer: C
Question: Evaluate permutation
4P4
Options:
A)22
B)23
C)24
D)25
E)None of these
Rationale: Explanation:
nPn=n!
4P4=4∗3∗2∗1=24
Option C
Answer: C
Question: The ratio between the present ages of A and B is 5:3 respectively. The ratio between A's age 4 years ago and B's age 4 years hence is 1:1. What is the ratio between A's age 4 years hence and B's age 4 years ago?
Options:
A)3:9
B)3:6
C)3:1
D)3:4
E)3:2
Rationale: Let the present ages of A and B be 5x and 3x years respectively.
Then, (5x - 4)/(3x + 4) = 1/1
2x = 8 => x = 4
Required ratio = (5x + 4):(3x - 4) = 24:8 = 3:1
Answer: C
Answer: C
Question: The ratio between the sale price and the cost price of an article is 10:7. What is the ratio between the profit and the cost price of that article?
Options:
A)2:9
B)2:5
C)3:7
D)2:0
E)2:1
Rationale: Let C.P. = Rs. 7x and S.P. = Rs. 10x.
Then, Gain = Rs. 3x
Required ratio =3x : 7x = 3:7
Answer:C
Answer: C
Question: A man purchases some eggs for Rs.500. 15% of the eggs break during transportation. What profit percentage should he take on the remaining to get an overall profit of 20%?
Options:
A)37.5
B)41.17
C)21.17
D)45.17
E)46.18
Rationale: Explanation:
The eggs remaining = 85%
CP of 85% eggs = 85x500/100 = Rs.425
Overall profit = 500 + 20% of 500 -CP of 85% eggs.
Rs.600 – Rs.425 = Rs.175.
:. Overall profit percent = 175x100/425 = 41.17%.
Answer: Option B
Answer: B
Question: Two employees X and Y are paid a total of Rs. 550 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?
Options:
A)Rs. 150
B)Rs. 300
C)Rs. 250
D)Rs. 200
E)Rs. 220
Rationale: Explanation:
Let the amount paid to X per week =x
and the amount paid to Y per week =y
12y/10+y=550
22y/10=550
y=5500/22=500/2=250
ANSWER IS C
Answer: C
Question: How many three digit numbers X greater than 330 can be formed from the digits 1, 2, 3, 4, 5 and 6, if each digit can only be used once?
Options:
A)72
B)48
C)120
D)96
E)76
Rationale: Find the number of 3 digit numbers greater than 300, and then subtract from them the number of three digit numbers between 300 and 330 formed with the given 6 digits.
ABC three digit numbers greater than 300 - total of 4*5*4=80, because a must be greater than 2, so 4 possibilities left; B 5 remaining, and C 4 remaining possibilities to choose from.
Between 300 and 330 there are 1*2*4=8 numbers with the given property: A = 3, 1 possibility; B can be only 1 or 2 (ABC < 330), so two possibilities; C the remaining 4 possibilities after choosing A and B.
Total possible choice 80 - 8 =72=X
Answer: A.
Answer: A
Question: A goods train runs at the speed of 72 kmph and crosses a 250 m long platform in 30 seconds. What is the length of the goods train?
Options:
A)230 m
B)350 m
C)260 m
D)270 m
E)None of these
Rationale: Explanation:
Speed =[ 72 x (5/18) ]m/sec= 20 m/sec.
Time = 30 sec.
Let the length of the train be x metres.
Then,[ (x+250)/30 ]= 20
=> x + 250 = 600
=> x = 350. Answer: B
Answer: B
Question: A 180 meter long train crosses a man standing on the platform in 6 sec. What is the speed of the train?
Options:
A)107 kmph
B)138 kmph
C)121 kmph
D)108 kmph
E)103 kmph
Rationale: D
108 kmph
S = 180/6 * 18/5 = 108 kmph
Answer: D
Question: An amount at compound interest sums to Rs.17640/- in 2 years and to Rs.19404/- in 3 years at the same rate of interest. Find the rate percentage?
Options:
A)5%
B)7%
C)9%
D)10%
E)12%
Rationale: Explanation:
The difference of two successive amounts must be the simple interest in 1 year on the lower amount of money.
S.I = 19404/- - 17640/- = Rs. 1764/-
Rate of interest = (1764/17640) × (100/1)
=>10%
Answer: Option D
Answer: D
Question: How many digits 2^1000 has?
Options:
A)31
B)35
C)50
D)99
E)310
Rationale: 2^10 = 1.024 * 10^3 => 2^1000 = (1.024)^100 * 10^300
therefore 310 digits would be my best guess
E
Answer: E
Question: Two trains are running in opposite directions with the same speed. If the length of each train is 120 metres and they cross each other in 12 seconds, then the speed of each train (in km/hr) is:
Options:
A)10
B)18
C)36
D)72
E)84
Rationale: Explanation:
Let the speed of each train be x m/sec.
Then, relative speed of the two trains = 2x m/sec.
So, 2x =	(120 + 120) /12
2x = 20
x = 10.
Speed of each train = 10 m/sec = 10 x	18/5 km/hr = 36 km/hr.
ANSWER IS C
Answer: C
Question: To fill a tank, 25 buckets of water is required. How many buckets of water will be required to fill the same tank if the capacity of the bucket is reduced to 7/10 of its present?
Options:
A)61.5
B)60.5
C)63.5
D)35.71429
E)64.5
Rationale: Let capacity of 1 bucket = x
Capacity of the tank = 25x
New capacity of the bucket = 7x/10
Hence, number of buckets needed = 25x/(7x/10)=(25×10)/7=35.71429
Answer is D.
Answer: D
Question: If p#q denotes the least common multiple of p and q, then E=((12#16)#(18#24)) = ?
Options:
A) 216
B) 180
C) 144
D) 108
E) 72
Rationale: There are several ways to find the Least Common Multiple of two numbers. In this case, the most efficient method is to use the Greatest Common Factor: (A * B) / (GCF AB) = LCM AB
The greatest common factor of 12 and 16 is 4. So, 12#16 = 12*16/4 = 48.
The greatest common factor of 18 and 24 is 6. So, 18#24 = 18*24/6 = 72
Finally, the greatest common factor of 48 and 72 is 24. So, E=((12#16)#(18#24)) = 48#72 = (48*72)/24 = 2*72 = 144
The correct answer is C.
Answer: C
Question: One fourth of a solution that was 15% sugar by weight was replaced by a second solution resulting in a solution that was 16 percent sugar by weight. The second solution was what percent sugar by weight?
Options:
A)34%
B)24%
C)22%
D)16%
E)8.5%
Rationale: Instead of using complex calculations and remembering formulae, why dont u directly get to weighted average.
3 parts of 15% + 1 part of x (unknown) % = 4 parts of 16%
=> x% = 64%-45% = 16%
ans D it is.
Answer: D
Question: The 41 parents participating in the Smithville PTA have been assigned to at least 1 of 3 committees: festival planning, classroom aid, and teacher relations. 21 parents are assigned to the festival planning committee, 18 parents are assigned to the classroom aid committee, and 19 parents are assigned to the teacher relations committee. If 5 parents are assigned to all 3 committees, how many parents are assigned to exactly 2 committees?
Options:
A)4
B)7
C)8
D)9
E)10
Rationale: The formula is Total = A+B+C - sum of exactly two + 2*all three + neither
21+18+19-x-2*5=41
solving for x you get 7
Answer B
Answer: B
Question: Sam deposited $12,000 to open a new savings account that earned eight percent annual interest, compounded semi-annually. If there were no other transactions in the account, what the amount of money in Sam account one year after the account was opened?
Options:
A) $13,128
B) $12,763
C) $12,968
D) $12,942
E) $12,865
Rationale: Approach #1:
8 percent annual interest compounded semi-annually --> 2.5% in 6 moths.
For the first 6 moths interest was 4% of $12,000, so $480;
For the next 6 moths interest was 4% of $12,000,plus8% earned on previous interest of $480, so $480+$8=$488;
Total interest for one year was $480+$488=$968, hence balance after one year was $12,000+ $968=$12,968.
Answer: C.
Answer: C
Question: A shopkeeper expects a gain of 22½% on his cost price. If in a week, his sale was of Rs.392, what was his profit?
Options:
A)Rs.18.20
B)Rs.70
C)Rs.72
D)Rs.88.25
E)None
Rationale: Solution
C.P	= Rs.(100/122.50x392)
= Rs.(1000/1225×392)
= Rs.320.
Therefore, Profit	= Rs.(392-320)
= Rs.72.
Answer C
Answer: C
Question: If a and y are different prime numbers less than ten, what must be true about the sum of a and y?
Options:
A)the sum is even
B)the sum is odd
C)the sum is less than ten
D)the sum is greater than ten
E)the sum is less than 13
Rationale: This has to be solved by checking for each option:
Prime numbers less that 10 = 2, 3, 5, 7
A. the sum is even
May or may not be true. a = 3, y, = 5 -> True.
a = 2, y = 3 - True
B. the sum is odd
May or may not be true. a = 3, y, = 5 -> False.
a = 2, y = 3 - True
C. the sum is less than ten
May or may not be true a= 5, y = 7, Sum = 12
a = 2, y = 3. Sum = 5
D. the sum is greater than ten
May or may not be true a= 5, y = 7, Sum = 12
a = 2, y = 3. Sum = 5
E. the sum is less than 13
This will always be true.
Maximum sum = 7 + 5 = 12.
This is always less than 13.
Correct Option: E
Answer: E
Question: If a^2 is divisible by 240 what is the least possible value of integer a?
Options:
A)120
B)30
C)90
D)60
E)12
Rationale: 240 can be written as (2^4)*3*5.
For a^2 to be divisible by 240 it should contain at least 2^4 and 3 and 5 in its factors. We can leave out option E because 12 doesnt have 5 as one of its factor. Now if we check for option B, 30 can be written as 2*3*5, hence 30^ 2 will have 2 as the maximum power of 2, so we can leave out this option too.
Option D is the right answer if we follow the same method as we followed for other two previous options.
60 = (2^2)*3*5; 60^2 = (2^4)*(3^2)*(5^2). So it shows that 60^2 is divisible by 240 and hence the answer.
Answer : D
Answer: D
Question: Simran started a software business by investing Rs. 50,000. After six months, Nanda joined her with a capital of Rs. 80,000. After 3 years, they earned a profit of Rs. 420. What was Simran share in the profit?
Options:
A)s 180
B)s 100
C)s 120
D)s 190
E)s 290
Rationale: Simran : Nanda = (50000 x 36) : (80000 x 30) = 3 : 4.
Simran's share = Rs.420 x	3/7	= Rs. 180.
ANSWER :A
Answer: A
Question: The salaries of A and B together amount to $4000. A spends 95% of his salary and B, 85% of his. If now, their savings are the same, what is A's salary?
Options:
A)$1000
B)$1250
C)$2500
D)$3000
E)$1200
Rationale: Let A's salary is x
B's salary = 4000-x
(100-95)% of x = (100-85)% of (4000-x)
x = $3000
Answer is D
Answer: D
Question: Albert is 2 times Mary’s age but only 4 times as old as Betty. Mary is 16 years younger than Albert. How old is Betty?
Options:
A)8
B)12
C)10
D)15
E)18
Rationale: given that A=2M=4B..AND M=A-16..
substituting the values M=16,A=32 AND B=8..
Answer is A
Answer: A
Question: A chair is bought for Rs.900/- and sold at Rs.810/- find the loss percentage
Options:
A)10%
B)15%
C)20%
D)25%
E)30%
Rationale: Formula = (Selling price ~ Cost price)/Cost price * 100
= (810 ~ 900)/900 = 10% Loss
A
Answer: A
Question: Fresh grapes contain 70% water by weight and raisins obtained by drying fresh grapes contain 25% water by weight. How many kgs of fresh grapes are needed to get 30kgs of raisins?
Options:
A)75 kgs
B)64kgs
C)72 kgs
D)65 kgs
E)70 kgs
Rationale: The weight of non-water in 30 kg of dried grapes (which is 100-25=75% of whole weight) will be the same as the weight of non-water in x kg of fresh grapes (which is 100-70=30% of whole weight),
so 30*0.75 = x*0.3
--> x = 75.
Answer: A.
Answer: A
Question: Mother is aged 3times more than her daughter Rose. After 8 years, she would be two and a 1/2times of Rose's age. After further 8 years, how many times would he be of Rose's age?
Options:
A)1
B)2
C)4
D)5
E)6
Rationale: Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
(4x + 8) = 5 (x + 8)
2
8x + 16 = 5x + 40
3x = 24
x = 8.
Hence, required ratio = (4x + 16)/(x + 16) = 48/24= 2.
B
Answer: B
Question: If 5 less than x is 1 greater than y, then a number z that is 5 greater than x reduced by y is equal to
Options:
A)4
B)9
C)14
D)11
E)y + 14
Rationale: 11 it is....nice one....
D
Answer: D
Question: In how many different ways can 5 females and 5 males form a circle such that the males and the females alternate?
Options:
A)1400
B)2800
C)1200
D)3000
E)4012
Rationale: circle 5 males can be arranged in 4!
gvn that the males and females alternate then 5 places for females
=> female arranged in 5 !
tot no of ways = 4! * 5 ! = 24 * 120 = 2880
ANSWER B
Answer: B
Question: Ratio between Rahul and Deepak is 4:3, After 2 Years Rahul age will be 26 years. What is Deepak present age.
Options:
A)14
B)18
C)20
D)22
E)24
Rationale: Explanation:
Present age is 4x and 3x,
=> 4x + 2 = 26 => x = 6
So Deepak age is = 3(6) = 18
Option B
Answer: B
Question: A and B invest money in the ratio 8:9 and they has loss of Rs.6900 at the end of year. what is the share of loss of B?
Options:
A)Rs.1600
B)Rs.1500
C)Rs.1400
D)Rs.1300
E)None of the above
Rationale: et ratio of A and B be 8x & 9x
so net loss = 8x+9x= 6800
x=400
A=3x=3(400)=1200
B= 4x=4(400)=1600
so, B= 1600
ANSWER:A
Answer: A
Question: Two bullet train s 140 m and 190 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time (in seconds) which they take to cross each other, is:
Options:
A)15.8 sec.
B)12.8 sec.
C)11.88 sec.
D)10.8 sec.
E)08.8 sec.
Rationale: Relative speed = (60 + 40) km/hr = 100x5/18 = 250/9 m/ sec.
Distance covered in crossing each other = (140 + 190) m = 330 m.
Required time = 330x9/250 = 54/5 = 11.88 sec.
ANSWER C
Answer: C
Question: A $77.95 lawn chair was sold for $59.95 at a special sale. By approximately what percent was the price decreased?
Options:
A)15%
B)23%
C)25%
D)60%
E)80%
Rationale: Listed selling price of chair = 77.95 $
Discounted selling price of chair = 59.95 $
Discount = 77.95 - 59.95 = 18 $
% decrease in price of chair = (18/77.95) * 100% = 23 % approx
Answer B
Answer: B
Question: In a drawer of shirts 8 are blue, 6 are green and 4 are magenta. If Mason draws 2 shirts at random, what is the probability W at least one of the shirts he draws will be blue?
Options:
A)25/153
B)28/153
C)5/17
D)4/9
E)W=12/17
Rationale: P(at least one blue) = 1- P(0 blue) = 1 - 10/18*9/17 =W= 12/17.
Answer: E.
Answer: E
Question: In a garment industry, 12 men working 8 hours per day complete a piece of work in 10 days. To complete the same work in 8 days, working 5 hours a day, the number of men required is:
Options:
A)24
B)5
C)6
D)8
E)9
Rationale: Explanation :
Let the required number of men be x.
Less days, More men (Indirect Proportion)
More working hrs per day, Less men (Indirect Proportion)
Days 8 : 10
Working Hrs 5 : 8 :: 12 : x
=> 8 x 5 x x = 10 x 8 x 12
=> x = 10 x 8 x 12 / (8 x 5)
=> x = 24
Answer : A
Answer: A
Question: The perimeter of a square is 72 m. Find the area of the square.
Options:
A)161 mÂ².
B)324 mÂ².
C)166 mÂ².
D)169 mÂ².
E)273 mÂ².
Rationale: Perimeter of square = 72 m
But perimeter of square = 4 Ã— side
Therefore, 4 Ã— side = 72 m
Therefore, side= 72/4 m = 18m
Now, the area of the square = (side Ã— side)
Therefore, area of the square = 18 Ã— 18 mÂ² = 324 mÂ².
ANSWER : OPTION B
Answer: B
Question: The cross-section of a cannel is a trapezium in shape. If the cannel is 10 m wide at the top and 6 m wide at the bottom and the area of cross-section is 640 sq m, the depth of cannel is?
Options:
A)39
B)28
C)27
D)80
E)71
Rationale: 1/2 * d (10 + 6) = 640
d = 80
Answer: D
Answer: D
Question: 14, 35, 56, 63, 91, 126
In the sequence above, each term is related with the others. Which of the following could not be a term in the sequence?
Options:
A)402
B)259
C)322
D)686
E)847
Rationale: Simplifying the question into easier words we just need to find which of the numbers is not divisible by 7
clearly the answer is 402 because if we divide 402 by 7 we get a remainder of 57.42
Correct answer - A
Answer: A
Question: Two pipes can fill a tank in 30 and 12 hours, while third pipe will make the tank empty in 20 hours. If all three pipes operate simultaneously. In how many hours the tank will be filled ?
Options:
A)5 Hours
B)7 Hours
C)8 Hours
D)9 Hours
E)15 Hours
Rationale: In 1 hour it fill 1/30 + 1/12 - 1/20 = 1/15
So fill tank fill up in 15 Hours
ANSWER:E
Answer: E
Question: 9log9(4) = ?
Options:
A)1
B)2
C)3
D)4
E)5
Rationale: Exponential and log functions are inverse of each other. Hence
aloga(x) = x , for all x real and positive.
and therefore
9log9(4) = 4
correct answer D
Answer: D
Question: The probability of Sam passing the exam is 1/4. The probability of Sam passing the exam and Michael passing the driving test is 1/8. What is the probability of Michael passing his driving test?
Options:
A)1/24.
B)1/2.
C)1/3.
D)2/3.
E)2/5
Rationale: 1/4 *1/m= 1/8 , 1/m = 1/2
Answer B
Answer: B
Question: A, B, K start from the same place and travel in the same direction at speeds of 30km/hr, 40km/hr, 60km/hr respectively. B starts three hours after A. If B and K overtake A at the same instant, how many hours after A did K start?
Options:
A)3
B)4.5
C)6
D)d) 5.5
E)e) 5
Rationale: The table you made doesn't make sense to me. All three meet at the same point means the distance they cover is the same.
We know their rates are 30, 40 and 60.
Say the time taken by B is T hrs. Then A takes 3+T hrs. And we need to find the time taken by K.
Distance covered by A = Distance covered by B
30*(3+T) = 40*T
T = 9 hrs
Distance covered by B = Distance covered by K
40*T = 60*Time taken by K
Time taken by K = 40*9/60 = 6 hrs
Time taken by A = 3+T = 3+9 = 12 hrs
Time taken by K = 6 hrs
So K starts 12-6 = 6 hrs after A. (answer C)
Answer: C
Question: Steve traveled the first 2 hours of his journey at 40 mph and the last 2 hours of his journey at 80 mph. What is his average speed of travel for the entire journey?
Options:
A)53.33 mph
B)56.67 mph
C)60 mph
D)64 mph
E)66.67 mph
Rationale: Average Speed = Total distance/ Total time = (40 * 2 + 80 * 2)/(2 + 2) = 240/4 = 60
Answer: C
Answer: C
Question: The present age of a father is 3 years more than five times the age of his son. Three years hence, father's age will be 17 years more than thrice the age of the son. Find the present age of the father.
Options:
A)33
B)38
C)29
D)40
E)53
Rationale: if the present age be x years.
father's will be (5x+3)years..
so, (5x+3+3)=3(x+3)+17
or, x=10
so the fathers present age =(5x+3)=(5*10+3)years =53years..
ANSWER : OPTION E
Answer: E
Question: A large tank can filled by A and B in 30 minutes and 45 minutes respectively. How many minutes will it take to fill the tanker from empty state if B is used for half the time and A and B fill it together for the other half?
Options:
A)30min
B)20min
C)25min
D)40min
E)45min
Rationale: Part filled by A+B in 1 minute = 1/30 + 1/45 = 1/45
Suppose the tank is filled in x minutes
Then, x/2(1/45 + 1/45) = 1
x/2 * 2/45 = 1
x = 45 min
Answer is E
Answer: E
Question: What percent of 40 is 80?
Options:
A)133 1⁄3
B)75
C)200
D)33 1⁄3
E)25
Rationale: To find out the % of 80 in 40
Do 80/40 = 200%
Answer C)
Answer: C