divelab/Sys2Bench huggingface dataset:
Question: On a certain number line, conditions are x<Y<z<U<v. xyzuv>0 Which of the following must be true?
I xy>0
II zu>0
III uv>0
Options:
A)I only
B)II only
C)I and II
D)III only
E)II and III only
Rationale: Suppose, for the product to be greater than 0, we can two variables as -ve or four variables can be -ve.
We are given : I xy>0 II yz>0 III uv>0
case 1: x and y can be negative/positive and if they are... we get greater than 0.
case 2: we have zu , then z and u both can be negative/positive and if they are... we get greater than 0.
C
Answer: C
Question: (0.96)(power 3) - (0.1)(power 3)/ (0.96)(power 2) + 0.096 + (0.1)(power 2) is:
Options:
A)0.68
B)0.086
C)0.86
D)0.068
E)None of them
Rationale: Given expression
= (0.96) (power 3) - (0.1)(power 3) / (0.96)(power 2) + (0.96 x 0.1) + (0.1)(power 2)
= a (power 3) - b(power 3) / a(power 2) + ab + b(power 2)
= (a - b)
= (0.96 - 0.1)
= 0.86
Answer is C.
Answer: C
Question: Peta has six times as many dimes as quarters in her piggy bank. She has 21 coins in her piggy bank totaling $2.55
How many of each type of coin does she have?
Options:
A)4q & 20d
B)5q & 15d
C)3q & 18d
D)6q & 16d
E)2q & 19d
Rationale: Let x be the number of quarters. Let 6x be the number of dimes
Since one quarter equals 25 cents, x quarters equals x × 25 cents or 25x cents
Since one dime equals 10 cents, 6x dimes equals 6x × 10 cents or 60x cents
Since one 1 dollar equals 100 cents, 2.55 dollars equals 2.55 × 100 = 255 cents
Putting it all together, 25x cents + 60x cents = 255 cents
85x cents = 255 cents
85x cents / 85 cents = 255 cents / 85 cents
x = 3
6x = 6 × 3 = 18
Therefore Peta has 3 quarters and 18 dimes
correct answer is C)3q & 18d
Answer: C
Question: Two dice are thrown together. What is the probability that the sum of the number on the two faces is divided by 4 or 6
Options:
A)1/3
B)7/19
C)7/9
D)7/17
E)7/18
Rationale: Clearly n(S)=6*6=36
Let E be the event that the sum of the numbers on the two faces is divided by 4 or 6. Then
E={(1,3),(1,5),(2,2),(2,4),(2,6),(3,1),(3,3),(3,5),(4,2),(4,4),(5,1),(5,3),(6,2),(6,6)}
n(E)=14.
Hence p(e)=n(e)/n(s)=14/36=7/18
answer option E) 7/18
Answer: E
Question: The average age of M boys is ‘b’ years and of ‘n’ girls ‘c’ years. The average age of all together is?
Options:
A)(mb – nc)/ (m + n) years
B)(mb + nc)/ (m - n) years
C)(mb + nc)/ (m + n) years
D)(mb – nc)/ (m - n) years
E)(mn – mc)/ (m - n) years
Rationale: (mb + nc) / (m+ n)
Answer:C
Answer: C
Question: The average mark of the students of a class in a particular exam is 65. If 5 students whose average mark in that exam is 20 are excluded, the average mark of the remaining will be 90. Find the number of students who wrote the exam.
Options:
A)14
B)25
C)35
D)45
E)55
Rationale: Let the number of students who wrote the exam be x.
Total marks of students = 75 x.
Total marks of (x - 5) students = 90(x - 5)
65x - (5 * 20) = 90(x - 5)
350 = 25x => x = 14
ANSWER:A
Answer: A
Question: The function f is defined for all positive integers m by the following rule. f(m) is the number of positive integers each of which is less than m and has no positive factor in common with m other than 1. If q is any prime, number then f(q)=
Options:
A)q-2
B)q-1
C)(q+1)/2
D)(q-1)/2
E)2
Rationale: If not the wording the question wouldn't be as tough as it is now. The GMAT often hides some simple concept in complicated way of delivering it.
This question for instance basically asks: how many positive integers are less than given prime number q which have no common factor with q except 1.
Well as q is a prime, all positive numbers less than q have no common factors with q (except common factor 1). So there would be q-1 such numbers (as we are looking number of integers less than q).
For example: if q=8 how many numbers are less than 8 having no common factors with 8: 1, 2, 3, 4, 5, 6, 7 --> 8-1=7.
Answer: B.
Answer: B
Question: The average age of father and his two sons is 27 years. The difference in age between the two sons is 4 years and five years ago the average age of the two sons was 12 years. What is the present age of the father?
Options:
A)34years
B)47years
C)64years
D)27years
E)37years
Rationale: The average age of father and his two sons is 27 years.
The total age of father and his two sons is 81 years.
five years ago the average age of the two sons was 12 years.
Now the average age of the two sons is 17 years.
Now the total age of the two sons is 34 years.
age of father = 81-34 =47 years
ANSWER:B
Answer: B
Question: A table is bought for Rs.940/- and sold at Rs.1040/- find the loss percentage
Options:
A)10% Loss
B)10% Gain
C)20% Loss
D)20% Gain
E)30% Gain
Rationale: Formula = (Selling price ~ Cost price)/Cost price * 100
= (1040 ~ 940)/940 = 10% gain
B
Answer: B
Question: A salesperson receives a base salary of $1000 per month and a commission of 7.5% of the selling price of each item sold above the first 50 item. If this month she sold 370 items for $150 each, what will her monthly salary be?
Options:
A)$1,500
B)$4,600
C)$2,100
D)$2,500
E)$2,800
Rationale: Ans : 1000+ 7.5 % * 150 * (370-50) = $ 4600
ANSWER:B
Answer: B
Question: In how many different ways can change be provided for a one dollar bill using pennies (1 cent), nickels (5 cents), dimes (10 cents), and quarters (25 cents), if at least one of each type of coin must be included?
Options:
A)39
B)42
C)60
D)65
E)66
Rationale: I. Case I = Four Quarters = this is impossible, because if we already have a dollar in quarters, then we cannot have any other coins. We can't have all four coins represented if we have four quarters.
Case I does not allow any ways.
II. Case II = Three Quarters (75 cents)
This allows for one dime. Two dimes would bring us up to $0.95, and we wouldn't have room for both pennies and nickels.
Subcase 1 = 3 Q, 1 D (85 cents)
1) one nickel (N) and 10 pennies (P)
2) 2 N and 5 P
Case II allows for a total of two ways.
III. Case III = Two Quarters (50 cents)
This allows for 1-4 dimes.
Subcase 1 = 2 Q, 4 D (90 cents)
(1 way) we could have 1 nickel
Subcase 2 = 2 Q, 3 D (80 cents)
(3 ways) we could have 1-3 nickels
Subcase 3 = 2 Q, 2 D (70 cents)
(5 ways) we could have 1-5 nickels
Subcase 4 = 2 Q, 1 D (60 cents)
(7 ways) we could have 1-7 nickels
Case III allows for a total of 16 ways
IV. Case IV = One Quarter (25 cents)
This allows for 1-6 dimes
Subcase 1 = 1 Q, 6 D (85 cents)
(2 ways) we could have 1-2 nickels
Subcase 2 = 1 Q, 5 D (75 cents)
(4 ways) we could have 1-4 nickels
Subcase 3 = 1 Q, 4 D (65 cents)
(6 ways) we could have 1-6 nickels
Subcase 4 = 1 Q, 3 D (55 cents)
(8 ways) we could have 1-8 nickels
Subcase 5 = 1 Q, 2 D (45 cents)
(10 ways) we could have 1-10 nickels
Subcase 6 = 1 Q, 1 D (35 cents)
(12 ways) we could have 1-12 nickels
Case IV allows for a total of 42 ways.
There's no other case, because we have to have at least one quarter and one dime. The total over the cases equals
Total = 0 + 2 + 16 + 42 =60 ways.
OA =(C)
Answer: C
Question: A library has an average of 510 visitors on Sunday and 240 on other days. The average number of visitors per day in a month of 30 days beginning with a Sunday is?
Options:
A)187
B)279
C)280
D)285
E)262
Rationale: Since the month begins with a Sunday, so there will be five Sundays in the month.
Required average
= [(510 * 5) + (240 * 25)]/30 = 8550/30 = 285.
Answer:D
Answer: D
Question: In aquarium A there are 2 yellow fish and 2 green ones, in aquarium B there are 3 yellow fish and 4 green ones. An aquarium is chosen at random, what is the probability of picking up a green fish out of aquarium A?
Options:
A)1/2.
B)3/5.
C)1/4.
D)1/3.
E)2/3.
Rationale: Probability of picking up one aquarium out of two= 1/2
probability of picking 1 green fish from aquarium A= 2/4=1/2
Hence the desired probability= 1/2*1/2= 1/4
C is the answer
Answer: C
Question: What is the smallest no. which must be added to 3245613 so as to obtain a sum which is divisible by 11?
Options:
A)1
B)2
C)4
D)9
E)3
Rationale: For divisibility by 11, the difference of sums of digits at even and odd places must be either zero or divisible by 11.
For 3245613 , Difference =(3+4+6+3) -(2+5+1)=16-8=8.
The units digit is at odd place. So we add 3 to the number
=> 3245613+3= 3245616
Now , (3+4+6+6) -(2+5+1)=19-8=11 =>11 is a multiple of 11 and hence 3245616 is also divisible by 11
E
Answer: E
Question: 4,7,15,31,35,19,11,?
Options:
A)5
B)6
C)7
D)8
E)9
Rationale: Find the diff between each digits:
7-4=3
15-7=8
31-15=16
35-31=4
19-35=-16
11-19=-8
i.e. it shows a series 3,8,16,4,-16,-8,-3
that means next digit would be 8.
ANSWER:D
Answer: D
Question: What will be the cost of gardening 1 meter boundary around a rectangular plot having perimeter of 340 meters at the rate of Rs. 10 per square meter ?
Options:
A)Rs. 3430
B)Rs. 3440
C)Rs. 3450
D)Rs. 3460
E)Rs. 3490
Rationale: Explanation:
In this question, we are having perimeter.
We know Perimeter = 2(l+b), right
So,
2(l+b) = 340
As we have to make 1 meter boundary around this, so
Area of boundary = ((l+2)+(b+2)-lb)
= 2(l+b)+4 = 340+4 = 344
So required cost will be = 344 * 10 = 3440
Answer: Option B
Answer: B
Question: TOM traveled the entire 80 miles trip. If he did the first 30 miles of at a constant rate 30 miles per hour and the remaining trip of at a constant rate 50 miles per hour, what is the his average speed, in miles per hour?
Options:
A)55 mph
B)50 mph
C)40 mph
D)60 mph
E)70 mph
Rationale: avg speed = total distance/ total time = (d1+d2)/(t1+t2) = (30+50) / ((30/30)+(50/50)) = 80/2=40mph
C
Answer: C
Question: Find the odd man out.10, 25, 45, 50, 66, 70, 80
Options:
A)45
B)50
C)66
D)70
E)80
Rationale: Each of the numbers except 66 is multiple of 5.
ANSWER :C
Answer: C
Question: The cost of the paint is rs.36.50 per kg. if 1kg of paint covers 16sq.ft, how much will it cost to paint outside of a cube having 8 feet each side
Options:
A)Rs.962
B)Rs.672
C)Rs.546
D)Rs.876
E)None of these
Rationale: Explanation:
surface area of a cube= 6 x 82 = 384sq.ft
quantity of paint required=(384/16)=24kg
cost of painting= 36.5 x 24 = Rs.876
Answer: D
Answer: D
Question: In a division sum, the remainder is 5 and the divisor is 3 times the quotient and is obtained by adding 3 to the thrice of the remainder. The dividend is:
Options:
A)72
B)76
C)100
D)113
E)112
Rationale: Diver = (5*3)+3 = 18
3* Quotient = 18
Quotient = 6
Dividend = (Divisor * Quotient) + Remainder
Dividend = (18* 6) + 5 = 113
D
Answer: D
Question: Let Tn be the number of all possible triangles formed by joining vertices of an n-sided regular polygon. If Tn+1−Tn=10Tn+1−Tn=10, then the value of n is
Options:
A)5
B)6
C)7
D)8
E)10
Rationale: We are given that Tn+1−Tn=C3n+1−C3n=10 --> C3n+1−C3n=(n+1)!/3!(n−2)!−n!3!(n−3)!=10 --> (n−1)n(n+1)/6−(n−2)(n−1)n/6=10 (n−1)n=20 --> n=5n=5.
Answer: A.
Or: one additional point gives 10 more triangles, so when we add one point there are 10 different pairs of points which make triangles with that additional point --> C2n=10--> (n−1)n=20 --> n=5
Answer: A.
Answer: A
Question: A firm has 4 senior partners and 6 junior partners. How many different groups W of 3 partners can be formed in which at least one member of the group is a senior partner. (2 groups are considered different if at least one group member is different)
Options:
A)48
B)100
C)120
D)288
E)600
Rationale: What seems to work as well, though its tougher to come up with this solution:
(10*9*8) * 2/3 + (10*9*4)*1/3 = 600. Divided by all possible permutations (=3!) yields 100.
Explanation: For the first spot you have 10 possible canditates, for the 2nd 9. For the 3rd spot you need to differentiate if a senior partner has been picked for one of the first 2 spots or not. If yes, then you can pick one of the 8 remaining guys, so 10*9*8. If no senior partner has been picked yet, you need 10*9*4.
Now you need to weight the 2 cases with the corresponding probabilities: probability of no senior partner being picked in the first 2 draws = 6/10*5/9=1/3, so you weight 10*9*4 with 1/3. For the complementary case (senior partner was picked in the first 2 draws) you just take the complementary prob (1-1/3)= 2/3 and weight 10*9*8 with it.
Now you just need to divide the answer (600) by the number of different positions (=3!) and get W=600/6=100.B
Answer: B
Question: If the value of a piece of land decreases by 10% while the new tax rate on the land represent 110% of the original tax rate, what is the effect on the taxes?
Options:
A)a - taxes increase by 10%
B)b- taxes increase by 1%
C)c- there is no change in taxes
D)d- taxes decrease by 1%
E)c- taxes decrease by 10%
Rationale: Cansider the value of land = 100, Original tax rate 10%, hence tax value = 100*10% = 10.
Decreased value of land = 90, New tax rate = 110% of 10 = 11%, hence tax value = 90*11% = 9.9
10-9.9 = decrease by 1%.
Answer D.
Answer: D
Question: If John takes 15 minutes to eat x raisins, how many seconds will it take him to eat z raisins, assuming he continues to eat at the same rate?
Options:
A)900xz
B)15z/x
C)900x/z
D)15x/z
E)900z/x
Rationale: It will take (z/x)(15) minutes which is (z/x)(15)(60) seconds = 900z/x seconds.
The answer is E.
Answer: E
Question: The sum of all the integers k such that –21 < k < 24 is
Options:
A)0
B)-2
C)-25
D)-39
E)-51
Rationale: -20------------------0-----------------23
values upto+23 cancels outwe are left with only -20-19 sum of which is - 39. hence option D.
D
Answer: D
Question: In a recent survey at a local deli, it was observed that 3 out of 5 customers bought a bagel and 5 out of 7 customers bought a coffee. Some customers bought both. If 4 customers are selected, what are the chances that at least 1 customer bought a coffee and a bagel?
Options:
A)27/343
B)3/7
C)27/125
D)271/340
E)9/125
Rationale: Let us take 7*5=35 as the total number of customers. So 7*3=21 customers bought a bagel and 5*5=25 customers bought a coffee.
chances that at least 1 customer bought a coffee and a bagel = 1 - chances that no customer bought a coffee and a bagel
chances that no customer bought a coffee and a bagel= 24/35*23/34*22/33*21/32=69/340
chances that at least 1 customer bought a coffee and a bagel= 1 - 69/340 = 271/340
D
Answer: D
Question: A boat can move upstream at 25 kmph and downstream at 30 kmph, then the speed of the current is?
Options:
A)5 kmph
B)7 kmph
C)8 kmph
D)9 kmph
E)2.5 kmph
Rationale: US = 25
DS = 30
M = (30 - 25)/2 = 2.5
Answer:E
Answer: E
Question: The average monthly salary of 20 employees in an organisation is Rs. 1500. If the manager's salary is added, then the average salary increases by Rs. 100. What is the manager's monthly salary ?
Options:
A)Rs.6003
B)Rs.6029
C)Rs.1288
D)Rs.6108
E)Rs.6011
Rationale: Explanation:
Manager's monthly salary Rs. (1600 * 21 - 1500 * 20) = Rs.6003.
Answer: A
Answer: A
Question: If 2^2n + 2^2n + 2^2n + 2^2n = 4^22, then n =
Options:
A)3
B)6
C)12
D)23
E)21
Rationale: 2^2n + 2^2n + 2^2n + 2^2n = 4^22
=> 4 x 2^2n = 4^22 = 2^44
=> 2^2 x 2^2n = 2^44
=> 2^(2n+2) = 2^44
=> 2n+2 = 44=> n =21
So. Answer will be E.
Answer: E
Question: If the selling price of 100 articles is equal to the cost price of 40 articles, then the loss or gain percent is:
Options:
A)25%
B)40%
C)60%
D)65%
E)50%
Rationale: Let C.P. of each article be Re. 1.
Then, C.P. of 100 articles = Rs. 100;
S.P. of 100 articles = Rs. 40.
Loss % = 60/100 * 100 = 60%
ANSWER:C
Answer: C
Question: At 15:00 there were 20 students in the computer lab. At 15:03 and every three minutes after that, 3 students entered the lab. If at 15:10 and every ten minutes after that 9 students left the lab, how many students were in the computer lab at 15:44 ?
Options:
A)7
B)14
C)25
D)27
E)30
Rationale: Initial no of students + 3 * (1 + No of possible 3 minute intervals between 15:03 and 15:44) -
8 *(1 + No of possible 10 minute intervals between 15:10 and 15:44)
20 + 3*14 -8 * 4 = 25
C
Answer: C
Question: A man bought 20 shares of Rs. 50 at 5 discount, the rate of dividend being 13. The rate of interest obtained is:
Options:
A)27%
B)87%
C)15%
D)66%
E)88%
Rationale: Investment = Rs. [20 x (50 - 5)] = Rs. 900.
Face value = Rs. (50 x 20) = Rs. 1000.
Dividend = Rs. 27	x	1000 = Rs. 135.
2	100
Interest obtained = 135	x 100	%	= 15%
900
View Answer Discuss in Forum
Answer: C
Answer: C
Question: w,x,y,z is an arithmetic sequence, which of the following options also qualifies as an arithmetiv sequence?
I. w-6,x-6,y-6,z-6
II. 5w,2x,3y,5z
III. 5w,5x,5y,5z
Options:
A)II and III
B)III only
C)I and III
D)I and II
E)II only
Rationale: lets look at the three choices...
I. w-6,x-6,y-6,z-6
since the difference is constant, it is an arithmetic sequence...
II. 5w,2x,3y,5z
since the difference is not constant, it is not an arithmetic sequence
III. 5w,5x,5y,5z
since the difference is constant it is an arithmetic sequence...
Answer is A)
Answer: A
Question: 3 candidates in an election and received 1036, 4636 and 11628 votes respectively. What % of the total votes did the winning candidate gotin that election?
Options:
A)40%
B)55%
C)57%
D)60%
E)67.2%
Rationale: Total number of votes polled = (1036 + 4636 + 11628) = 17300
So, Required percentage = 11628/17300 * 100 = 67.2%
E
Answer: E
Question: In the standard formulation of a flavored drink the ratio by volume of flavoring to corn syrup to water is 1 : 12 : 30. In the sport formulation, the ratio of flavoring to corn syrup is three times as great as in the standard formulation, and the ratio of flavoring to water is half that of the standard formulation. If a large bottle of the sport formulation contains 6 ounces of corn syrup, how many ounces of water does it contain?
Options:
A)45
B)50
C)55
D)60
E)90
Rationale: F:C:W
1:12:30
Sport version:
F:C
3:12
F:W
1:60
OR 3:180
So C:F:W = 12:3:180
C/W = 12/180 = 3 ounces/x ounces
x = 6*180/12 = 90 ounces of water
E
Answer: E
Question: At what rate percent on simple interest will a sum of money double itself in 30 years?
Options:
A)3 1/3%
B)3 1/7%
C)3 9/3%
D)3 5/3%
E)3 3/3%
Rationale: P = (P*30*R)/100
R = 3 1/3%
Answer: A
Answer: A
Question: An empty fuel tank with a capacity of 208 gallons was filled partially with fuel A and then to capacity with fuel B. Fuel A contains 12% ethanol by volume and fuel B contains 16% ethanol by volume. If the full fuel tank contains 30 gallons of ethanol, how many gallons of fuel A were added?
Options:
A)160
B)150
C)82
D)80
E)50
Rationale: Say there are A gallons of fuel A in the tank, then there would be 208-A gallons of fuel B.
The amount of ethanol in A gallons of fuel A is 0.12A;
The amount of ethanol in 208-A gallons of fuel B is 0.16(208-A);
Since the total amount of ethanol is 30 gallons then 0.12A+0.16(208-A)=30 --> A=82.
Answer: C.
Answer: C
Question: What is the greatest value of m such that 4^m is a factor of 27! ?
Options:
A)5
B)7
C)6
D)8
E)4
Rationale: Pretty simple, really.
If m = 8, then 4m = 32, which is 16x2, both of which are included in 27!
Since 8 is the largest number here, its the answer.
Answer is D
Answer: D
Question: A can do a job in 18 days and B can do it in 30 days. A and B working together will finish twice the amount of work in ------- days?
Options:
A)21 ½ days
B)22 ½ days
C)23 ½ days
D)12 ½ days
E)none of these
Rationale: 1/18 + 1/30 = 8/90 = 4/45
45/4 = 11 ¼ *2 = 22 ½ days
ANSWER:B
Answer: B
Question: A, B and C invests Rs.2000, Rs.3000 and Rs.4000 in a business. After one year A removed his money; B and C continued the business for one more year. If the net profit after 2 years be Rs.3200, then A's share in the profit is?
Options:
A)288
B)2778
C)299
D)400
E)287
Rationale: 2*12 : 3*12 : 4*24
1: 3: 4
1/8 * 3200 = 400
27. A and B start a busin. Answer: D
Answer: D
Question: Which of the following fractions is greater than 3 /4 and less than 5 / 6 ?
Options:
A)4/8
B)4/5
C)4/6
D)4/1
E)4/4
Rationale: Explanation:
3 /4 = 0.75, 5/6 = 0.833, 1/2 = .5, 2/3 = 0.66, 4/5 = 0.8, 9/10 = 0.9.
clearly 0.8 lies between 0.75 and .833.
4/5 lies between 3/4 and 5/6..
Answer: B) 4 / 5
Answer: B
Question: Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. What are the marks obtained by them?
Options:
A)42, 33
B)43, 33
C)42, 38
D)43, 39
E)50, 43
Rationale: Let the marks secured by them be x and (x + 9)
Then sum of their marks = x + (x + 9) = 2x + 9
Given that (x + 9) was 56% of the sum of their marks
=>(x+9) = 56/100(2x+9)
=>(x+9) = 14/25(2x+9)
=> 25x + 225 = 28x + 126
=> 3x = 99
=> x = 33
Then (x + 9) = 33 + 9 = 42
Hence their marks are 33 and 42
A)
Answer: A
Question: The average weight of a class of 20 boys was calculated to be 58.4 kgs and it was later found that one weight was misread as 56 kg instead of 65 kg. What is the correct weight?
Options:
A)67.4kg
B)57.75kg
C)58.85kg
D)49.4kg
E)None of these
Rationale: Actual total weight is (20 Ã— 58.4 - 56 + 65) = 1177 Kgs
Actual average weight is 1177/20 = 58.85kgs
ANSWER IS C
Answer: C
Question: By selling 12 pencils for a rupee a man loses 20%. How many for a rupee should he sell in order to gain 20%?
Options:
A)8
B)76
C)17
D)7
E)77
Rationale: 80% --- 12
120% --- ?
80/120 * 12 = 8
Answer: A
Answer: A
Question: A train crosses a pole in 10 sec and a 200m long platform in 20 sec. What is the length of the train?
Options:
A)100m
B)200m
C)250m
D)300m
E)350m
Rationale: Let the length of train be x meter and speed be y m/sec
Therefore, time taken to cross the pole = x/y sec
and time taken to cross the platform = ( Length of train + Length of platform) / speed of train
Therefore x/y = 10
And, (x+200) / y = 20
⇒ 10y + 200 = 20 y
∴ speed of train, y = 20 m/sec
And length of rain = x = 10y = 200m ANSWER : B
Answer: B
Question: Three candidates contested in an election and received 3136, 7636, 11628 votes respectively. What is the percentage of the total votes did the winning candidate get?
Options:
A)45%
B)49%
C)52%
D)51%
E)62%
Rationale: Total number of votes polled = 3136+7636+11628 = 22400
Required percentage = 11628*100/22400 = 52%
Answer is C
Answer: C
Question: For every $20 that a billionaire spends, a millionaire spends the equivalent of 20 cents. For every $4 that a millionaire spends, a yuppie spends the equivalent of $2. The ratio of money spent by a yuppie, millionaire, and billionaire can be expressed as
Options:
A)1 :2 : 200
B)1 : 4 : 100
C)20 : 4 : 1
D)100 : 4 : 1
E)400 : 4 : 1
Rationale: millionaire 20 cents = 1/5 dollar ..therefore 1 dollar M = 100 dollar of B
therefore 4 dollar M = 400 dollar of B also 2 dollar Y
Y:M:B = 2:4:400
= 1:2:200
A
Answer: A
Question: Ajay and Vijay have some marbles with them. Ajay told Vijay "if you give me 'x' marbles, both of us will have equal number of marbles". Vijay then told Ajay "if you give me twice as many marbles, I will have 30 more marbles than you would". Find 'x'?
Options:
A)7
B)5
C)6
D)4
E)3
Rationale: If Vijay gives 'x' marbles to Ajay then Vijay and Ajay would have V - x and A + x marbles.
V - x = A + x --- (1)
If Ajay gives 2x marbles to Vijay then Ajay and Vijay would have A - 2x and V + 2x marbles.
V + 2x - (A - 2x) = 30 => V - A + 4x = 30 --- (2)
From (1) we have V - A = 2x
Substituting V - A = 2x in (2)
6x = 30 => x = 5.
Answer: B
Answer: B
Question: The average age of students of a class is 15.8 years. The average age of boys in the class is 16.3 years and that of the girls is 15.4 years. The ration of the number of boys to the number of girls in the class is?
Options:
A)2:6
B)2:3
C)4:5
D)2:1
E)2:4
Rationale: Let the ratio be k : 1. Then,
k * 16.3 + 1 * 15.4 = (k + 1) * 15.8
= (16.3 - 15.8)k = (15.8 - 15.4)
= k = 0.4/0.5 = 4/5
Required ratio = 4/5 : 1 = 4:5.
Answer:C
Answer: C
Question: A person lent a certain sum of money at 4% per annum at simple interest and in 8 years the interest amounted to Rs.340 less than the sum lent. What was the sum lent?
Options:
A)228
B)278
C)289
D)500
E)821
Rationale: P - 340 = (P*4*8)/100
P = 500
Answer: D
Answer: D
Question: By how much is 12% of 24.2 more than 10% of 14.2 ?
Options:
A)0.1484
B)14.84
C)1.484
D)2.762
E)None
Rationale: Answer
Required difference = (12 x 24.2) / 100 - (10 x 14.2) / 100
= 2.904 -1.42
= 1.484.
Correct Option: C
Answer: C