divelab/Sys2Bench huggingface dataset:
Question: There stand nine temples in a row in a holy place. All the nine temples have 100 steps climb. A fellow devotee comes to visit the temples. He drops a Re. 1 coin while climbing each of the 100 steps up. Then he offers half of the money he has in his pocket to the god. After that, he again drops Re. 1 coin while climbing down each of the 100 steps of the temple.
If he repeats the same process at each temple, he is left with no money after climbing down the ninth temple. Can you find out the total money he had with him initially?
Options:
A)143700
B)146900
C)376190
D)248117
E)127690
Rationale: B
146900
Whenever you face such type of questions, it is wise to begin from the last thing. Here in this question the last thing will be the 9th temple. He climbed down 100 steps and thus you know, he had Rs. 100 before beginning climbing down. Thus, he must have offered Rs. 100 to the god in that temple too (he offered half of the total amount). Also, he must have dropped Rs. 100 while climbing the steps of the ninth temple. This means that he had Rs. 300 before he begand climbing the steps of the ninth temple.
Now, we will calculate in the similar manner for each of the temples backwards.
Before the devotee climbed the eight temple: (300+100)*2 + 100 = 900
Before the devotee climbed the seventh temple: (900+100)*2 + 100 = 2100
Before the devotee climbed the Sixth temple: (2100+100)*2 + 100 = 4300
Before the devotee climbed the fifth temple: (4300+100)*2 + 100 = 8900
Before the devotee climbed the fourth temple: (8900+100)*2 + 100 = 18100
Before the devotee climbed the third temple: (18100+100)*2 + 100 = 36,500
Before the devotee climbed the second temple: (36500+100)*2 + 100 = 73300
Before the devotee climbed the first temple: (73300+100)*2 + 100 = 146900
Therefore, the devotee had Rs. 146900 with him initially.
Answer: B
Question: The average of first 20 natural numbers is?
Options:
A)10.5
B)11.4
C)5.3
D)5.9
E)5.1
Rationale: Sum of 20 natural no. = 420/2 = 210
Average = 210/20 = 10.5
Answer:A
Answer: A
Question: a dog have birth to 12 puppies, 2 female and 10 male. what is the ratio of the female puppies to the male?
Options:
A)1/5
B)1/6
C)1/10
D)2/12
E)1/8
Rationale: If female is 2 and male is 10, then 1/5.
so ratio of female to male is = 2/10 = 1/5
ANSWER:A
Answer: A
Question: A small water pump would take 3 hours to fill an empty tank. A larger pump would take 3/4 hour to fill the same tank. How many hours would it take both pumps, working at their respective constant rates, to fill the empty tank if they began pumping at the same time?
Options:
A)3/4
B)3/5
C)5/7
D)1/2
E)4/5
Rationale: Rate of the small pump is 1/3 tank/hour
Rate of the larger pump is 1/(3/4) or 4/3 tank/hour;
Combined rate of the two pumps is 1/3+4/3=5/3 tank/hour, together they will fill the empty tank in 1/(5/3)) = 3/5 hours (time=job/rate).
Answer: B
Answer: B
Question: P is five times as old as Q, and Q is six years older than R. If R is z years old, what is P’s age in terms of z?
Options:
A)5z + 6
B)5z − 30
C)5z + 30
D)(z + 6)/5
E)(z − 6)/5
Rationale: P = 5Q
Q = R+6 = z+6
P = 5(z+6) = 5z + 30
The answer is C.
Answer: C
Question: A wire in the form of a circle of radius 3.5 m is bent in the form of a rectangule, whose length and breadth are in the ratio of 6 : 5. What is the area of the rectangle?
Options:
A)54 cm2
B)30 cm2
C)17 cm2
D)26 cm2
E)98 cm2
Rationale: The circumference of the circle is equal to the permeter of the rectangle.
Let l = 6x and b = 5x 2(6x + 5x) = 2 * 22/7 * 3.5
=> x = 1
Therefore l = 6 cm and b = 5 cm Area of the rectangle
= 6 * 5
= 30 cm2
Answer: B
Answer: B
Question: R=(429)^2 * 237 * (1243)^3 is thrice of ?
Options:
A)33605 * 31960 * (1243)^2
B)33654 * 538219 * (1243)^2
C)33891 * 533247 * (1243)^2
D)34122 * 532004 * (1243)^2
E)34606 * 534572 * (1243)^2
Rationale: R=(429)^2*237*(1243)^3 is an odd number.
Among answer choices only C is an odd number, (so thrice C also will be an odd number).
Answer: C.
Answer: C
Question: The area of the square formed on the diagonal of a rectangle as its side is 108 1/3 % more than the area of the rectangle. If the perimeter of the rectangle is 28 units, find the difference between the sides of the rectangle?
Options:
A)5
B)4
C)7
D)2
E)1
Rationale: Let the sides of the rectangle be l and b respectively.
From the given data,
(√l2 + b2) = (1 + 108 1/3 %)lb
=> l2 + b2 = (1 + 325/3 * 1/100)lb
= (1 + 13/12)lb
= 25/12 lb
=> (l2 + b2)/lb = 25/12
12(l2 + b2) = 25lb
Adding 24lb on both sides
12l2 + 12b2 + 24lb = 49lb
12(l2 + b2 + 2lb) = 49lb
but 2(l + b) = 28 => l + b = 14
12(l + b)2 = 49lb
=> 12(14)2 = 49lb
=> lb = 48
Since l + b = 14, l = 8 and b = 6
l - b = 8 - 6 = 2m.Answer: D
Answer: D
Question: Expenditures of a Company (in Lakh Rupees) per Annum Over the given Years.
Year	Item of Expenditure
Salary	Transport and Fuel	Bonus	Interest on Loans	Taxes
1998	288	98	3.00	23.4	83
1999	342	112	2.52	32.5	108
2000	324	101	3.84	41.6	74
2001	336	133	3.68	36.4	88
2002	420	142	3.96	49.4	98
The total amount spent for transport by the company during the given period is approximately what percent of the total amount of salary paid during this period?
Options:
A)A)0.5%
B)B)1.24%
C)C)1%
D)D)3%
E)E)4%
Rationale: Required percentage
=	(288 + 342 + 324 + 336 + 420)
=	[	17	x 100	]	%
1710
~= 1%.
Answer : C
Answer: C
Question: The length of the bridge, which a train 150 metres long and travelling at 45 km/hr can cross in 30 seconds, is?
Options:
A)76 m
B)178 m
C)225 m
D)187 m
E)176 m
Rationale: Speed = [45 X 5/18] m/sec
= [25/2] m/sec Time = 30 sec Let the length of bridge be x metres. Then, (150 + x)/30 = 25/2
=> 2(150 + x)= 750 => x = 225 m.
Answer: C
Answer: C
Question: If a two-digit positive integer has its digits reversed, the resulting integer differs from the original by 36. By how much do the two digits differ?
Options:
A)3
B)4
C)5
D)6
E)7
Rationale: we are given that if the integer N has its digits reversed the resulting integer differs from the original by 25. First let’s express the reversed number in a similar fashion to the way in which we expressed the original integer.
10B + A = reversed integer
Since we know the resulting integer differs from the original by 27 we can say:
10B + A – (10A + B) = 36
10B + A – 10A – B = 36
9B – 9A = 36
B – A = 4
Since B is the tens digit and A is the units digit, we can say that the digits differ by 4.
The answer is B.
Answer: B
Question: Eighty percent of the lights at Hotel California are on at 8 p.m. a certain evening. However, forty percent of the lights that are supposed to be off are actually on and ten percent of the lights that are supposed to be on are actually off. What percent X of the lights that are on are supposed to be off?
Options:
A)22(2/9)%
B)16(2/3)%
C)11(1/9)%
D)10%
E)5%
Rationale: Is the Answer D.
let me try..
Let the light which are supposed to be OFF = SO
Let the light which are supposed to be ON = SN
Let the light which are ACTUALLY OFF = AO
Let the light which are ACTUALLY ON = AN
Let the total no. of lights be 100,
So ACTUALLY ON lights = 80
And ACTUALLY OFF lights = 20
Also given >> forty percent of the lights that are supposed to off are actually on >>> (40/100)*SO are ACTUALLY ON
it means >>> (60/100)*SO are ACTUALLY OFF
Also given >> ten percent of the lights that are supposed to be on are actually off >>> (10/100)*SN are ACTUALLY OFF
it means >>> (90/100)*SN are ACTUALLY ON
So, Total ACTUALLY ON lights = (40/100)*SO + (90/100)*SN = 80
and Total ACTUALLY OFF lights = (60/100)*SO + (10/100)*SN = 80
From here we get SO = 20
we need to find: What percent of the lights that are on are supposed to be off >>> So light ACTUALLY ON are 80 and light which are ACTUALLY ON, which are supposed to be OFF = (40/100)*SO = 8.
So (8/80)*100 X= 10%.D
Answer: D
Question: What is the lowest possible common multiple of 2 distinct integers, each greater than 145?
Options:
A)146
B)147
C)292
D)146*146
E)146*147
Rationale: The least common multiple of two numbers greater than 145 is 2(146) = 292, where the two distinct integers are 146 and 292.
The answer is C.
Answer: C
Question: Anand and Deepak started a business investing Rs. 500 and Rs. 600 respectively. Out of a total profit of Rs. 420. Deepak's share is?
Options:
A)s. 220.01
B)s. 450.20
C)s. 845.01
D)s. 320.01
E)s. 229.09
Rationale: Ratio of their shares = 500 : 600 = 5 : 6
Deepak's share = Rs. (420* 6/11) = Rs. 229.09 ANSWER "E
Answer: E
Question: The numerator of a fraction is increased by 200% and denominator is increased by 250% the resultant fraction is 3/14. What is the original fraction?
Options:
A)1/2
B)3/4
C)1/4
D)1/8
E)3/8
Rationale: if the original fraction is x/y then after increasing numerator by 200% and denomenator by 250% new fraction will become 3x/3.5y
3x/3.5y = 3/14 => x/y = 1/4 , Hence original fraction is 1/4
ANSWER:C
Answer: C
Question: 300 is what percent of 40?
.
Options:
A)0.2%
B)2%
C)5%
D)20%
E)750%
Rationale: 300= x*40/100
x = 750%
Ans; E
Answer: E
Question: The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is:
Options:
A)504
B)536
C)544
D)548
E)568
Rationale: Required number = (L.C.M. of 12, 15, 20, 54) + 8
= 540 + 8
= 548.
Answer: Option D
Answer: D
Question: The length of the rectangular field is double its width. Inside the field there is square shaped pond 8m long. If the area of the pond is 1/18 of the area of the field. What is the length of the field?
Options:
A)23
B)32
C)34
D)43
E)48
Rationale: Explanation:
A/18 = 8 * 8 => A = 8 * 8 * 18
x * 2x = 8 * 8 * 18
x = 24 => 2x = 48
Answer: Option E
Answer: E
Question: Which of the following does NOT have a decimal equivalent that is a terminating decimal?
Options:
A)1/2^25
B)5^3/2^7
C)3^8/6^10
D)3^9/6^7
E)6^8/10^10
Rationale: For a fraction to have terminating decimal, it must either have only 2 and/or 5 in the denominator. All other values in the denominator leads to non terminating decimal values
Hence,
1. A has 2 in the denominator, Hence it is terminating
2. B is also terminating
3. 3^8/(6^10) can be written as 3^8/ (2^10 * 3^10) => 1/(2^10 * 3^2). There is 3 in the denominator. Hence it is non terminating decimal
4. 3^9/(2^7 * 3^7) => 3^2/2^7. Hence Terminating
5. Has both 2 & 5 in the denominator. Hence Terminating.
Option C
Answer: C
Question: In Company J, the total monthly payroll for the 15 factory workers is $30,000 and the total monthly payroll for the 30 office workers is $75,000. By how much does the average (arithmetic mean) monthly salary of an office worker exceed that of a factory worker in this company?
Options:
A)$450
B)$500
C)$600
D)$650
E)$750
Rationale: The average monthly salary of a factory worker is: $30,000 / 15 = $2000.
The average monthly salary of an office worker is: $75,000 / 30 = $2500.
The difference in average salary is: $2500 - $2000 = $500.
The answer is B.
Answer: B
Question: The length of the room is 5m and width is 5m. Find the cost of paving the floor by slabs at the rate of Rs.200 per sq meter?
Options:
A)2000
B)3000
C)4000
D)3500
E)5000
Rationale: l=5m w=5m
area of the floor = 5x 5 = 25 sq m
cost of paving = 200 x 25= Rs. 5000
Answer: E
Answer: E
Question: There are two numbers. If 50% of the first number is added to the second number, then the second number increases to its five-fourth. Find the ratio of the first number to the second number?
Options:
A)A)1/2
B)B)5/8
C)C)6
D)D)6/7
E)E)7
Rationale: Let the two numbers be x and y.
50/100 * x + y = 5/4y
=> 1/2 x = 1/4 y => x/y = 1/2
A)
Answer: A
Question: A family with 1 mother, 1 father, and 3 children sit in a car with 2 front seats and 3 back seats. If the mother drives with a child in the front, and the father sits in the back with the other two children, how many seating arrangements are possible?
Options:
A)3
B)4
C)6
D)12
E)18
Rationale: In the front seat we have 3 possibilities of children. (C1 or C2 or C3)
In the back seat we have (2!*1)*3 = 6 possibilities ( C1,C2,F / C2,C1,F / C1,F,C2 / C2,F,C1 / F,C1,C2 / F,C2,C1 -> IF C3 is in front seat)
So, 6*3 = 18 (try to figure out to change the possibilities of sitting back the C3 child in the place of C1 or C2 and do the 6 possibilities again and again).
Or, another way to see:
Looking into the back seat:
( C1,C2,F / C2,C1,F / C1,F,C2 / C2,F,C1 / F,C1,C2 / F,C2,C1) = 6
or +
( C3,C2,F / C2,C3,F / C3,F,C2 / C2,F,C3 / F,C3,C2 / F,C2,C3) = 6
or +
( C1,C3,F / C3,C1,F / C1,F,C3 / C3,F,C1 / F,C1,C3 / F,C3,C1) = 6
-------
ANS : E :18
Answer: E
Question: A technical support team of 6 agents is chosen from 9 senior-level agents and 5 junior-level agents. The team must have at least 2 seniors and at least 3 juniors. How many ways can this team be created?
Options:
A)140
B)320
C)1015
D)1020
E)2204
Rationale: Solution: We have two possibilities 2S 4J or 3S 3J
(9C2)(5C4)+(9C3)(5C3)=700
D) 1020
Answer: D
Question: The least number of complete years in which a sum of money put out at 20% compound interest will be more than doubled is:
Options:
A)3
B)4
C)5
D)6
E)None of these
Rationale: Explanation:
P(1 + 20/100)n >2P => (6/5)n >2
Now,(6/5 x 6/5 x 6/5 x	6/5	)>2
So, n = 4 years.
ANSWER IS B
Answer: B
Question: How many figures are required to number the pages the pages of a book containing 223 pages?
Options:
A)372
B)661
C)561
D)467
E)761
Rationale: 1 to 9 = 9 * 1 = 9
10 to 99 = 90 * 2 = 180
100 to 223 = 124 * 3 = 372
-----------
561
ANSWER:C
Answer: C
Question: Find L.C.M of 852 and 1491
Options:
A)5964
B)5664
C)4964
D)4664
E)5555
Rationale: 852) 1491 (1
852
639) 852 (1
639
213) 639 (3
639
0
H.C.F of 852 and 1491 is 213
: . L.C.M = 852*1491/213 = 5964
Answer is A.
Answer: A
Question: In a set of numbers from 100 to 1000 inclusive, how many integers are odd and do not contain the digit 3?
Options:
A)180
B)288
C)286
D)284
E)324
Rationale: We have to find the total number of 3-digit odd numbers not having 3 as a digit.
Units digits will be among 1,5,7,9
Tenth digits will be among 0,1,2,5,4,6,7,8,9
Hundredth digits will be among 1,2,5,4,6,7,8,9
So total numbers = 4*9*8 =288
Answer : B
Answer: B
Question: By selling an umbrella for Rs. 300, a shop keeper gains 10%. During a clearance sale, the shopkeeper allows a discount of 5% on the marked price. His gain percent during the sale is?
Options:
A)5.56%
B)2%
C)8%
D)3%
E)4%
Rationale: Marked price = Rs. 300
C.P. = 100/110 * 300 = Rs. 270
Sale price = 95% of Rs. 300 = Rs. 285
Required gain % = 15/270 * 100 =5.56%.
Answer: A
Answer: A
Question: 3/4 of 1/2 of 2/5 of 5020 = ?
Options:
A)392
B)229
C)753
D)493
E)540
Rationale: C
753
? = 5020 * (2/5) * (1/2) * (3/4) = 753
Answer: C
Question: Solve(0.76 × 0.76 × 0.76 − 0.008)/(0.76 × 0.76 + 0.76 × 0.2 + 0.04)
Options:
A)0.56
B)0.62
C)0.5
D)0.48
E)0.52
Rationale: 0.56
Option 'A'
Answer: A
Question: The average of runs of a cricket player of 10 innings was 18. How many runs must he make in his next innings so as to increase his average of runs by 4?
Options:
A)87
B)16
C)62
D)76
E)17
Rationale: Average after 11 innings = 22
Required number of runs
= (33* 11) - (18* 10) = 242 - 180
= 62.
Answer: C
Answer: C
Question: If the wheel is 14 cm then the number of revolutions to cover a distance of 3520 cm is?
Options:
A)22
B)28
C)17
D)12
E)40
Rationale: 2 * 22/7 * 14 * x = 3520 => x = 40
Answer: E
Answer: E
Question: A certain car dealership sells economy cars, luxury cars, and sport utility vehicles. The ratio of economy to luxury cars is 5:3. The ratio of economy cars to sport utility vehicles is 4:3. What is the ratio of luxury cars to sport utility vehicles?
Options:
A)12:15
B)8:9
C)3:2
D)2:3
E)1:2
Rationale: The ratio of economy to luxury cars is 5:3 --> E:L = 5:3 = 20:12.
The ratio of economy cars to sport utility vehicles is 4:3 --> E:S = 4:3 = 20:15.
Thus, L:S = 12:15.
Answer: A.
Answer: A
Question: Graph G has a line of symmetry of x = –2. Graph G passes through the point (3, 3). What is the x-coordinate of another point that must have a y-coordinate of 3?
Options:
A) –8
B) –7
C) –5
D) –4
E) 2
Rationale: Line of symmetry is X=-2; one point is (3,3)
Right side distance =2+3(distance from origin) = 5; therefore Left side distance should be same from line of symmetry =5;
therefore left side co-ordinate=5+ 2(distance from origin) = 7; as the X coordinate is in 2nd quadrant hence -7
Therefore answer is B
Answer: B
Question: The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 44 kg, then the weight of B is:
Options:
A)31 kg
B)32 kg
C)33 kg
D)34 kg
E)None of these
Rationale: Explanation:
Let A, B, C represent their respective weights. Then, we have:
A + B + C = (45 x 3) = 135 …. (i)
A + B = (40 x 2) = 80 …. (ii)
B + C = (44 x 2) = 88 ….(iii)
Adding (ii) and (iii), we get: A + 2B + C = 168 …. (iv)
Subtracting (i) from (iv), we get : B = 33.
B’s weight = 33 kg.
Answer: C
Answer: C
Question: A rectangular-shaped carpet that measures x feet by y feet is priced at $46. What is the cost of the carpet, in dollars per square yard? (1 square yard = 9 square feet)
Options:
A)xy/360
B)9xy/40
C)40xy/9
D)414xy
E)414/(xy)
Rationale: The area of the carpet in feet is xy.
The area in square yards is xy / 9.
The price per square yard is 46 / (xy/9) = 414/(xy).
The answer is E.
Answer: E
Question: Find the L.C.M of 16,24,36,54
Options:
A)528
B)432
C)528
D)456
E)741
Rationale: The l.c.m of 16,24,36,54=2^4*3^3=432
Answer(B)
Answer: B
Question: A man wears socks of two colours - Black and brown. He has altogether 20 black socks and 20 brown socks in a drawer. Supposing he has to take out the socks in the dark, how many must he take out to be sure that he has a matching pair ?
Options:
A)3
B)20
C)39
D)45
E)None of these
Rationale: Explanation:
Since there are socks of only two colours, so two out of any three socks must always be of the same colour.
Answer: A
Answer: A
Question: A coin is tossed live times. What is the probability that there is at the least one tail?
Options:
A)31/32
B)31/39
C)31/31
D)61/32
E)32/39
Rationale: Explanation:
Let P(T) be the probability of getting least one tail when the coin is tossed five times.
= There is not even a single tail.
i.e. all the outcomes are heads.
= 1/32 ; P(T) = 1 - 1/32 = 31/32
Answer:A
Answer: A
Question: A standard Veggiematik machine can chop 36 carrots in 4 minutes. How many carrots can 6 standard Veggiematik machines chop in 6 minutes?
Options:
A)36
B)54
C)108
D)216
E)324
Rationale: Direct Relationship:-
1 standard Veggiematik machine - 36 Carrots - 4 minutes,
1 standard Veggiematik machine - 9 Carrots - 1 minute,
Now
6 standard Veggiematik machine - ? Carrots - 6 minutes,
Hence = 9X6X6 =324 Carrots
Answer E
Answer: E
Question: In Township K, 1/5 of the housing units are equiped with cable Tv. If 1/15 of the housing units, including 1/3 of those that are equiped with cable tv, are equipped with videocassette recorders, what fraction of the housing units have neither cable tv nor videocassette recorders?
Options:
A)23/30
B)11/15
C)7/10
D)4/5
E)2/15
Rationale: 1/5 -- cable TV (This includes some data from video cassette recorder)
1/15 -- video cassette recorder including 1/3(equiped with cable tv) i.e. 1/3(1/5) = 1/15
therefore only video cassette recorder = 1/15 - 1/15 = 0
Total = 1/5+0+neither cable tv nor videocassette recorders
1 = 1/5 + neither cable tv nor videocassette recorders
therefore neither cable tv nor videocassette recorders = 1-1/5 = 4/5
Hence D.
Answer: D
Question: Harry started a 7-mile hike with a full 9-cup canteen of water and finished the hike in 2 hours with 3 cup of water remaining in the canteen. If the canteen leaked at the rate of 1 cup per hour and Harry drank 2 cups of water during the last mile, how many cups did he drink per mile during the first 6 miles of the hike?
Options:
A)1/6
B)2/6
C)3/6
D)4/6
E)5/6
Rationale: No of cups leaked during the trip = 2 cups.
No of cups Harry drank = 6 cups.
No of cups harry drank during the first 6 miles = 4.
drink / mile = 4/6
Answer D
Answer: D
Question: If a cloth merchant sells ‘a’ metres of cloth for Rs.x, then what is the selling price of ‘b’ metres of cloth?
Options:
A)Rs.(b*x)
B)Rs.{(b*x)/a}
C)Rs.{(a*b)/x}
D)None of these
E)Cannot be determined
Rationale: Explanation:
Cost of ‘a’ metres of cloth = Rs.x. Therefore, each metre of cloth costs Rs. (x/a).
The cost of ‘b’ metres of cloth = Rs. b*(x/a) = Rs. {(b*x)/a}
ANSWER B
Answer: B
Question: In how many different ways can three letters be posted from seven different postboxes assuming no two letters can be posted from the same postbox?
Options:
A)110
B)210
C)310
D)410
E)510
Rationale: First letter could be sent from ANY of the seven postboxes - 7 (7 options);
Second letter could be sent from the SIX postboxes left - 6 (6 options);
Third letter could be sent from the FIVE postboxes left - 5 (5 options);
Total # of ways =7*6*5=210
ANSWER:B
Answer: B
Question: A boat can travel with a speed of 12 km/hr in still water. If the speed of the stream is 4 km/hr, find the time taken by the boat to go 68 km downstream.
Options:
A)4.25 hr
B)5.25 hr
C)8.25 hr
D)2.25 hr
E)2.50 hr
Rationale: speed of boat in still water = 12 km/hr
speed of the stream = 4 km/hr
Speed downstream = (12+4) = 16 km/hr
Time taken to travel 68 km downstream = 68⁄16 = 17⁄4 = 4.25 hours
Answer is A
Answer: A
Question: what is a percent of b divided by b percent of a?
(a) a (b) b (c) 1 (d) 10 (d) 100
Options:
A)1
B)7
C)19
D)2
E)3
Rationale: a percent of b : (a/100) * b
b percent of a : (b/100) * a
a percent of b divided by b percent of a : ((a / 100 )*b) / (b/100) * a )) = 1
Answer:A
Answer: A
Question: At what time between 5.30 and 6 will the hands of a clock be at right angles?
Options:
A)40 min. past 5
B)42 min. past 5
C)43 4/11 min past 5
D)43 7/11 min. past 5
E)None
Rationale: Sol.
At 5 o’clock, the hands are 24 min. spaces apart.
To be at right angles and that too between 5.30 and 6, the minute hand hasto gain (25 + 15) = 40 min. spaces.
55 min. spaces are gained in 60 min.
40 min. spaces are gained in [60/55 * 40] min. = 43 7/11 min.
∴ Required time = 43 7/11 min. past 5.
Answer D
Answer: D
Question: Pipe A can fill a tank in 15 minutes and pipe B cam empty it in 24 minutes. If both the pipes are opened together after how many minutes should pipe B be closed, so that the tank is filled in 30 minutes?
Options:
A)18
B)27
C)98
D)27
E)24
Rationale: Let the pipe B be closed after x minutes.
30/15 - x/24 = 1 => x/24 = 30/15 - 1 = 1
=> x = 1* 24
= 24.
Answer:E
Answer: E
Question: A box contains four light out of which 2 are defective. If two light are chosen at random, find the probability that all the two light are defective?
Options:
A)2/7
B)3/8
C)1/9
D)3/7
E)1/6
Rationale: Out of nine light , five are good and four are defective.
Required probability = 2C2/4C2 = 1/6
E
Answer: E
Question: a car runs 10,000 miles using 5 tyres interchangably. to have equal wornout by all tyres, how many miles each tyre should have run?
Options:
A)7000 miles
B)8000 miles
C)9000 miles
D)6000 miles
E)5000 miles
Rationale: simply 10000*4/5=8000
or
take a,b,c,d,e are tyres then each tyre travells 8000 miles first car runs with
a,b,c,d for 2000 miles
b,c,d,e for 2000 miles
a,c,d,e for 2000 miles
a,b,d,e for 2000 miles
a,b,c,e for 2000 miles
so total distance travelled is 10000 miles and each tyre travells 8000 miles
ANSWER:B
Answer: B
Question: The rate of Interest on a sum of money is 9% p.a. for the first 3 years, 4% p.a. for the next 4 years, and 5% for the period beyond 7 years. If the S.I, Occured on the sum for the total period of 8 years is Rs. 540/-, the sum is
Options:
A)1,125
B)2,000
C)2,100
D)2,250
E)2,540
Rationale: Explanation:
I1 = (P x 3 x 9)/100 = 10P/37
I2 = (P x 4 x 4)/100 = 4P/25
I3 = (P x 1 x 5)/100 = P/20
10P/37 + 4P/25 + P/20 = 540
12P/25 = 540
P = 1125
Answer: Option A
Answer: A
Question: In an examination, a student scores 4 marks for every correct answer and loses 1 mark for every wrong answer. If he attempts all 60 questions and secures 140 marks, the no of questions he attempts correctly is :
Options:
A)A)35
B)B)38
C)C)90
D)D)88
E)E)40
Rationale: Let the number of correct answers be X.
Number of incorrect answers = (60 – X).
4x – (60 – x) = 140
=> 5x = 200
=> x = 40
Answer:E
Answer: E
Question: If there are 4 peanuts in a box and Mary puts 8 more peanuts inside, how many peanuts are in the box?
Options:
A)8
B)9
C)10
D)11
E)12
Rationale: 8+4=12
correct answer is E)12
Answer: E