divelab/Sys2Bench huggingface dataset:
Question: Rory and Roxy, both house cats, love to hunt and chase insects. Since Rory only has three paws, Roxy is able to catch approximately 2.5 times more insects than Rory in one day.
After 3 days of hunting, Roxy was able to catch 23 insects. Assuming that both cats had an equal amount of hunting time, how many total insects can the two of them catch after 18 days of hunting?
Please round to the nearest whole number.
Options:
A)143
B)193
C)111
D)194
E)138
Rationale: 18 (total days) is divisible by 3 (initial data given days) 6 times,
therefore we can easily find Roxy's total for the 18 day period is 23 x 6 = 138 insects
Taking Roxy's total, we can then find Rory's total by dividing 138 by 2.5 = 55.2 insects
To find the pair's total, we add 138 + 55.2 = 193.2
This number rounded to nearest whole number is 193, answer B.
You could also divide 23 by 2.5 to get 9.2, which would be Rory's total for the first 3 days.
You could then multiply again, (23x6) + (9.2x6) = 138 + 55.2 = 193.2
Answer: B
Question: An escalator moves towards the top level at the rate of 7 ft.sec and its length is 180 feet. If a person walks on the moving escalator at the rate of 2 feet per second towards the top level, how much time does he take to cover the entire length.
Options:
A)5sec
B)25sec
C)20sec
D)15sec
E)10sec
Rationale: Explanation :
Time taken to cover the entire length = tot.dist/resultant speed = 180/ (7+2) = 20sec
Answer : C
Answer: C
Question: In a cricket team, the average of eleven players is 28 years. Out of these, the average ages of three groups of three players each are 25 years, 28 years and 38 years respectively. If in these groups, the captain and the youngest player are not included, and the captain is eleven years older than the youngest player, what is the age of the captain ?
Options:
A)23 years
B)34 years
C)35 years
D)36 years
E)37 years
Rationale: Explanation :
Let the age of youngest player be x.
Then, age of the captain = (x + 11).
=> 3*25 + 3*28 + 3*38 + x + x + 11 = 11*28.
=> 75+84+114+2x+11=308
so 2x = 24
so x = 12.
Age of the captain = (x+11)
= 23 years.
Answer : A
Answer: A
Question: Bobby bought 2 shares, and which he sold for $96 each. If he had a profit of 20% on the sale of one of the shares but a loss of 20% on the sale of the other share, then on the sale of both shares Bobby had...
Options:
A)a profit of 10
B)a profit of 8
C)a loss of 8
D)a loss of 10
E)neither a profit nor a loss
Rationale: Cost of the first stock: 96/1.2=80, so profit from it 96-80=16
Cost of the second stock: 96/0.8=120, so loss from it 96-120=-24
Overall loss 16-24=-8
Answer: C.
Answer: C
Question: In a school of 850 boys, 44% of Muslims, 28% Hindus, 10% Sikhs and the remaining of other communities. How many belonged to the other communities?
Options:
A)176
B)179
C)153
D)167
E)107
Rationale: 44 + 28 + 10 = 82%
100 – 82 = 18%
850 * 18/100 = 153
Answer: C
Answer: C
Question: A trained covered x km at 40 kmph and another 2x km at 20 kmph. Find the average speed of the train in covering the entire 3x km.
Options:
A)24 kmph
B)34 kmph
C)44 kmph
D)14 kmph
E)22 kmph
Rationale: A
24 kmph
Total time taken = x/40 + 2x/20 hours
= 5x/40 = x/8 hours
Average speed = 3x/(x/8) = 24 kmph
Answer: A
Question: Linda and Angela contract to paint a neighbor's house. Even though Linda
spends 10% more time painting the house than Angela, each receives a payment
of m dollars when the work is completed. If Angela decides to pay Linda n
dollars so that they would have received the same compensation per hour
worked, what is n in terms of m?
Options:
A)A)(1/21)m
B)B)(1/3)m
C)C)(1/4)m
D)D)(1/5)m
E)E)(1/6)m
Rationale: let angela work for 10hrs and get 1100 rs. (m =1050)
According to question, linda works 10% more time and gets the same amount. so let linda work 11hrs and get 1050 rs.
so they do a total of 10 +11 =21 hrs of work and get 2100 rs together . The question basically asks to equalise their payment. so a total of 2100 rs is received by them and they do 21 hrs work together. average rate will be 2100/21 = 100 rs per hr. so linda should get 11*100 =1100 rs. But she got only 1050. so angela should give 50 rs to linda. answer = 50/1050 =1/21
answer A
Answer: A
Question: What percent of 13 is 13 percent of 1?
Options:
A) 0.001
B) 0.01
C) 1
D) 10
E) 101.
Rationale: 13 % of 1 = (13/100) * 1 = 13/100
To determine what percentage of 13 this is :
[13][/100*13] *100 = 1%
Ans : C
Answer: C
Question: Jean drew a gumball at random from a jar of pink and blue gumballs. Since the gumball she selected was blue and she wanted a pink one, she replaced it and drew another. The second gumball also happened to be blue and she replaced it as well. If the probability of her drawing the two blue gumballs was 16/49 what is the probability that the next one she draws will be pink?
Options:
A)1/49
B)4/7
C)3/7
D)16/49
E)40/49
Rationale: The probability of drawing a pink gumball both times is the same. The probability that she drew two blue gumballs = 16/49 = (4/7) * (4/7)
Therefore probability that the next one she draws is pink = 3/7
Option (C)
Answer: C
Question: The bus that travels from St. Louis to Chicago and back comes to St. Louis every 5 hours while the bus that travels from St. Louis to Springfield and back comes to St. Louis every 4 hours. If at 2:00 o'clock both bused arrived at St. Louis, at what time will they meet in St. Louis again?
Options:
A)16:00.
B)18:00.
C)20:00.
D)22:00.
E)24:00.
Rationale: Time taken by bus to travel from St. Louis to Chicago and back comes to St. Louis = 5 hours
Time taken by bus to travel from St. Louis to Springfield and back comes to St. Louis = 4 hours
Time taken by both buses to meet again in St. Louis will be LCM of 5 and 4 = 20
If the buses start at 2:00 o'clock from St. Louis , they will meet again in St. Louis at 22:00 hours
Answer D
Answer: D
Question: If x/y =4/3, then (x-y)/x?
Options:
A)-1/2
B)-1/4
C)1/3
D)1/2
E)1/4
Rationale: we have this law of fraction:
a/b=c/d= (a-c)/(b-d)
x/y=4/3 ---> x/4=y/3= (x-y)/(4-3)=(x-y)/(1) ---> (x-y)/x= 1/4
Answer: E
Answer: E
Question: In how many ways can a five-letter password be chosen, using the letters A, B, C, D, E, and/or F, such that at least one letter is repeated within the password?
Options:
A)420
B)576
C)900
D)936
E)1,296
Rationale: Total number of four letter passwords = 6*6*6*6= 1296 ------(1)
Total number of passwords in which no letter repeats = 6C5*5!= 6*120=720------(2)
therefore required value = (1)-(2)= 1296-720=576
B
Answer: B
Question: One-third of 1200 is what percent of 236 ?
Options:
A)169.49
B)30
C)120.32
D)125.32
E)15.152
Rationale: Answer
Let one-third of 1200 is N% of 236.
∵ 1200/3 = (N x 236)/100
∴ N = (400 x 100) / 236= 169.49
Correct Option: A
Answer: A
Question: A bank offers 5% C.I. calculated on half-yearly basis . A customer deposits Rs. 1600 each on 1st January and 1st July of a year. At the end of the year, the amount he would have gained by way of interest is?
Options:
A)299
B)121
C)298
D)390
E)387
Rationale: Amount = [1600 * (1 + 5/(2 * 100)2 + 1600 * (1 + 5/(2 * 100)]
= [1600 * 41/40(41/40 + 1)
= [(1600 * 41 * 81)/(40 * 40)] = Rs. 3321.
C.I. = 3321 - 3200 = Rs. 121.
Answer:B
Answer: B
Question: A certain essay consists of 13 paragraphs. Each paragraph contains at least 120 words but not more than 125 words. Which of the following could be the total number of words in the essay?
Options:
A)1440
B)1540
C)1610
D)1740
E)1840
Rationale: lets consider minimum no of words ... 13 * 120 = 1560
Lets consider maximum no of words .... 13*125= 1625
answer should be one of these two values or should lie between these two values ...
only 1 option C - 1610
Answer: C
Question: The pages of a report are numbered consecutively from 1 to 8. If the sum of the page numbers up to and including page number x of the report is equal to six less than the sum of the page numbers following page number x, then x =
Options:
A)5
B)6
C)4
D)3
E)2
Rationale: sum of the first few numbers =1+2+3+4 +5 +6 =21
sum of the last few = 7 +8 =15 page no.6 answer .B
Answer: B
Question: If nn is a positive integer and (n+1)(n+3)(n+1)(n+3) is odd, then (n+2)(n+4)(n+2)(n+4) must be a multiple of which one of the following?
Options:
A)2
B)4
C)5
D)8
E)7
Rationale: (n+1)(n+3)(n+1)(n+3) is odd only when both (n+1)(n+1) and (n+3)(n+3) are odd. This is possible only when nn is even.
Hence, n=2mn=2m, where mm is a positive integer. Then,
(n+2)(n+4)=(2m+2)(2m+4)=2(m+1)2(m+2)=4(m+1)(m+2)(n+2)(n+4)=(2m+2)(2m+4)=2(m+1)2(m+2)=4(m+1)(m+2)
=4 * (product of two consecutive positive integers, one which must be even)=4 * (product of two consecutive positive integers, one which must be even) =4 * (an even number), and this equals a number that is at least a multiple of 8=4 * (an even number), and this equals a number that is at least a multiple of 8
Hence, the answer is (D).
Answer: D
Question: A watch which gains uniformly is 2 minutes low at noon on Tuesday and is 4 min 48 sec fast at 2 p.m. on the following Tuesday. When was it correct ?
Options:
A)3 p.m. on Thursday.
B)2 p.m. on Thursday.
C)4 p.m. on Thursday.
D)2.10 p.m. on Thursday.
E)2.40 p.m. on Thursday.
Rationale: Time from 12 p.m. on Tuesday to 2 p.m. on the following Tuesday = 7 days 2 hours.
= 170 hours.
The watch gains = (2 + 4 x 4/5) min
= 34/5 min. in 170 hrs.
Now, 34/5 min are gained in 170 hrs.
Then, 2 min are gained in (170 x 5/34 x 2) hrs.
Watch is correct after 2 days 2 hrs after 12 p.m. on Tuesday, i.e., it will be correct at 2 p.m. on Thursday.
Answer B
Answer: B
Question: There are 2 sections A and B in a class, consisting of 36 and 24 students respectively. If the average weight of section A is 30kg and that of section B is 30kg, Find the average of the whole class?
Options:
A)30kg
B)37kg
C)42kg
D)55.12kg
E)29.78kg
Rationale: Total weight of 36+44 students = 36*30 + 24*30 = 1800
Average weight of the class is = 1800/60 = 30 kg
Answer is A
Answer: A
Question: A train speeds past a pole in 15 seconds and a platform 100 m long in 25 seconds. Its length is:
Options:
A)750 m
B)300 m
C)350 m
D)150 m
E)250 m
Rationale: Let the length of the train be x metres and its speed by y m/sec.
Then, x/y = 15 => y =x/15
Therefore	x + 100/25 =	x/15
=> 15(x + 100) = 25x
=> 15x + 1500 = 25x
=> 1500 = 10x
=> x = 150 m.
Answer: D
Answer: D
Question: What is the difference between the place values of two 2's in the numeral 58232
Options:
A)202
B)200
C)198
D)120
E)220
Rationale: Required difference = 200-2 = 198
Answer is C
Answer: C
Question: Excluding the stoppages, the speed of a bus is 48 km/hr and including the stoppages the speed of the bus is 24 km/hr. For how many minutes does the bus stop per hour?
Options:
A)30min
B)10 min
C)12 min
D)20 min
E)18 min
Rationale: Speed of the bus without stoppage=48 km/hr
Speed of the bus with stoppage=24 km/hr
Difference in speed=24 km/hr
so,the time taken in the stoppages = time taken to cover 24 km=(24/48)hr = 1/2 hr =30 min
ANSWER:A
Answer: A
Question: Find large number from below question The difference of two numbers is 1385. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder
Options:
A)1234
B)1265
C)1350
D)1467
E)1659
Rationale: Let the smaller number be x. Then larger number = (x + 1385).
x + 1385 = 6x + 15
5x = 1370
x = 274
Large number = 274+1385 = 1659
E
Answer: E
Question: A PERSON WENT TO A SHOP AND ASKED FOR CHANGE FOR 1.15 PAISE. BUT HE SAID THAT HE COULD NOT ONLY GIVE CHANGE FOR ONE RUPEE. BUT ALSO FOR 50P, 25P, 10P AND 5P. WHAT WERE THE COINS HE HAD
Options:
A)1.15
B)1.25
C)1.35
D)1.45
E)1.85
Rationale: 50p-1, 25p-2, 10p-1, 5p-1
thus total= 1.15
ANSWER:A
Answer: A
Question: Two trains of equal are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 sec. The length of each train is?
Options:
A)50
B)45
C)48
D)55
E)51
Rationale: Let the length of each train be x m.
Then, distance covered = 2x m.
Relative speed = 46 - 36 = 10 km/hr.
= 10 * 5/18 = 25/9 m/sec.
2x/36 = 25/9 => x = 50.
Answer: Option A
Answer: A
Question: A cube has a volume of 216 cubic feet. If a similar cube is twice as long, twice as wide, and twice as high, then the volume, in cubic feet of such cube is?
Options:
A)24
B)1728
C)64
D)80
E)100
Rationale: Volume = 216 = side^3
i.e. Side of Cube = 6
New Cube has dimensions 12, 12, and 12 as all sides are twice of teh side of first cube
Volume = 12*12*12 = 1728 square feet
Answer: option B
Answer: B
Question: The year next to 1991 having the same calendar as that of 1990 is –
Options:
A)1998
B)2001
C)2002
D)2003
E)None of these
Rationale: We go on counting the odd days from 1991 onward still the sum is divisible by 7. The number of such days are 14 upto the year 2001. So, the calender for 1991 will be repeated in the year 2002.
Answer C
Answer: C
Question: What is the probability of rolling a total of 6 with a single roll of two fair six-sided dice, each with the distinct numbers 1 through 6 on each side?
Options:
A)1/12
B)5/36
C)2/7
D)1/3
E)1/2
Rationale: Totalsample spacefrom two fair six-sided dice is 36.
There are six possible ways to be 6 i.e. (1+5), (2+4), (3+3), (4+2), (5+1)
So, total probability is 5/36.
Answer is B.
Answer: B
Question: The population of a town is 8000. It decreases annually at the rate of 30% p.a. What will be its population after 2 years?
Options:
A)3920
B)5120
C)5200
D)5400
E)5500
Rationale: Formula :
( After =100 denominator
Ago = 100 numerator)
8000 Ã— 70/100 Ã— 70/100 = 3920
Answer : A
Answer: A
Question: How many even number in the range between 10 to 100 inclusive are not divisible by 3
Options:
A)15
B)30
C)31
D)33
E)46
Rationale: We have to find the number of terms that are divisible by 2 but not by 6( as the question asks for the even numbers only which are not divisible by 3)
For 2,
10,12,14...100
using AP formula, we can say 100 = 10 + (n-1) *2
or n=46.
For 6,
12,18,...96
using AP formula, we can say 96 = 12 + (n-1) *6
or n=15.
Hence, only divisible by 2 but not 3 = 46-15 = 31. hence, Answer C
Answer: C
Question: What is the total number of D integers between 100 and 200 that are divisible by 3?
Options:
A) 33
B) 32
C) 31
D) 30
E) 29
Rationale: yes there is a different way of arriving at that answer ....
u can also use airthmetic progression to get the answer
since the first term to be divisble by 3 is 102 ..take that as A .. the starting no
and since 198 is the last digit to be divisible by 3 take that as N ...
since the difference is 3 take that as D
no u have to find what term is 198 take that as nth term
the formula for that is N = A + (n-1) * d
198 = 102 +(n-1) * 3
from this u get n =33
Answer: A
Question: In a class of 32 students, 12 enrolled for both English and German. 22 enrolled for German. If the students of the class enrolled for at least one of the two subjects, then how many students enrolled for only English and not German?
Options:
A)30
B)10
C)18
D)28
E)32
Rationale: Total=English+German-Both+Neither --> 40=English+22-12+0 --> English=22 --> Only English=English-Both=22-12=10.
Answer: B.
Answer: B
Question: If n is a positive integer, then n(n+1)(n+2) is +ve and
Options:
A)divisible by 4 whenever n is even
B)divisible by 3 only when n is odd
C)odd whenever n is odd
D)even only when n is odd
E)even only when n is even
Rationale: n*(n+1)*(n+2)= +ve even integer divisible by 4 ( e.g 3,4,&5)
A
Answer: A
Question: If a card is drawn from a well shuffled pack of cards, the probability of drawing a spade or a king is
Options:
A)19/52
B)17/52
C)5/13
D)4/13
E)9/26
Rationale: P(SᴜK) = P(S) + P(K) - P(S∩K), where S denotes spade and K denotes king.
P(SᴜK) = 13/52 + 4/52 - 1/52 = 4/13
ANSWER:D
Answer: D
Question: If Jan 1, 2006 was a Wednesday, What was the day of the week Jan 1, 2010?
Options:
A)Friday
B)Thursday
C)Tuesday
D)Saturday
E)Monday
Rationale: Explanation :
Given that Jan 1 2006 was a Wednesday
Number of odd days in the period 2006-2009
= 3 normal years + 1 leap year
= 3 x 1 + 1 x 2 = 5 (note that we have taken the complete year 2006 because the period in 2006 is from 01-Jan-2006 to 31-Dec-2006, which is the whole year 2006. Then the complete years 2007, 2008 and 2009 are also involved)
Hence Jan 1 2010 = (Wednesday + 5 odd days) = Monday.. Answer : Option E
Answer: E
Question: In a division sum, the divisor is ten times the quotient and five times the remainder. If the remainder is 46, the dividend is:
Options:
A)5322
B)5330
C)5336
D)5340
E)5342
Rationale: Divisor = (5 * 46) = 230
= 10 * Quotient = Divisor
=> Quotient = 230/10 = 23
Dividend = (Divisor * Quotient) + Remainder
Dividend = (230 * 23) + 46 = 5336.
C
Answer: C
Question: A rectangular lawn of length 200m by 120m has two roads running along its center, one along the length and the other along the width. If the width of the roads is 5m what is the area R covered by the two roads?
Options:
A)400
B)1550
C)1575
D)1600
E)1625
Rationale: Area Covered by Road Along the Length = 5*200 = 1000 Square Meter
Area Covered by Road Along the Width = 5*120 = 600 Square Meter
Common Area in both Roads (where the roads intersect) = Square with Side 5 meter = 5*5 = 25
Total Area of the Roads R = 1000+600-25 = 1575
Answer: option C
Answer: C
Question: A person walks a distance of 18 kms at a particular speed. For the next 30 kms he increases his speed by 2 kmph. Had he walked the entire distance at 3 kmph more than his initial speed, he would have reached 4 hours earlier. Find his initial speed.
Options:
A)3 kms/hr
B)2 kms/hr
C)4 kms/hr
D)5 kms/hr
E)None of these
Rationale: let x be the initial speed , then
18/x+30/x+2=12 , we get 12 from 3*4=12
by solving we get x=1,-3
ANSWER:E
Answer: E
Question: A 300 meter long train crosses a platform in 39 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform?
Options:
A)99
B)289
C)350
D)882
E)281
Rationale: Speed = [300 / 18] m/sec = 50/3 m/sec.
Let the length of the platform be x meters.
Then, x + 300 / 39 = 50/3
3(x + 300) = 1950 è x = 350m.
Answer: C
Answer: C
Question: There are 180 doctors and nurses at a hospital. If the ratio of doctors to nurses is 2 to 3, how many nurses are at the hospital?
Options:
A)100
B)104
C)108
D)112
E)116
Rationale: The number of nurses at the hospital is (3/5)*180=108.
The answer is C.
Answer: C
Question: A person travels from P to Q a speed of 40 km/hr and returns by increasing his speed by 50%. What is his average speed for both the trips?
Options:
A)48 km/hr
B)40 km/hr
C)44 km/hr
D)38 km/hr
E)52 km/hr
Rationale: A
48 km/hr
Speed on return trip = 150% of 40 = 60 km/hr.
Average speed = (2 * 40 * 60)/(40 + 60) = 48 km/hr.
Answer: A
Question: A leak in the bottom of a tank can empty the full tank in 8 hours. An inlet pipe fills water at the rate of 6 litres a minute. When the tank is full, the inlet is opened and due to the leak, the tank is empty in 12 hours. How many litres does the cistern hold?
Options:
A)7580
B)7960
C)8290
D)8640
E)None
Rationale: Solution
Work done by the inlet in 1 hour	= (1/8 - 1/12)
= 1/24.
Work done by the inlet in 1 min.	= (1/24 × 1/60)
= 1/1440.
Volume of 1/1440 part = 6 litres.
Therefore, Volume of whole	= (1440×6)
‹=› 8640 litres.
Answer D
Answer: D
Question: A company wants to spend equal amounts of money for the purchase of two types of computer printers costing $300 and $200 per unit, respectively. What is the fewest number of computer printers that the company can purchase?
Options:
A)3
B)5
C)7
D)9
E)11
Rationale: The smallest amount that the company can spend is the LCM of 300 and 200, which is 600 for each, which is total 1200.
The number of 1st type of computers which costing $300 = 600/300 = 2.
The number of 2nd type of computers which costing $200 = 600/200 = 3.
Total = 2+3 = 5
Answer is B.
Answer: B
Question: Ravi can do a piece of work in 28 days while Prakash can do it in 40 days. In how many days will they finish it together?
Options:
A)16 1/17 days
B)17 1/8 days
C)16 8/17 days
D)17 7/17 days
E)18 1/17 days
Rationale: 1/28 + 1/40 = 17/280
280/17= 16 8/17 days
Answer: C
Answer: C
Question: The cost price of a Rs.100 stock at 4 discount, when brokerage is % is :
Options:
A)96.2
B)96.2
C)96.25
D)76.2
E)96.19
Rationale: Explanation:
CP. = = Rs.96.25
Answer: C) Rs.96.25
Answer: C
Question: In what ratio must a grocer mix two varieties of pulses costing Rs. 15 and Rs. 20 per kg respectively so as to get a mixture worth Rs. 16.50 kg?
Options:
A)4:7
B)3:7
C)4:3
D)7:3
E)2:3
Rationale: Cost of 1 kg pulses of 1st kind=Rs. 15
Cost of 1 kg pulses of 2nd kind=Rs. 20
Mean Price=Rs. 16.50
Cost of 1 kg pulses of 1st kind - Mean Price=15-16.50=Rs 1.50
Cost of 1 kg pulses of 2nd kind - Mean Price=20-16.50=Rs 3.50
Required rate = 3.50 : 1.50 = 7 : 3.
Answer:D
Answer: D
Question: What sum of money will produce Rs.900 as simple interest in 4 years at 9/2 percent?
Options:
A)80000
B)100000
C)90000
D)85000
E)70000
Rationale: 900 = (P*4*9/2)/100
P = 8000
Answer: A
Answer: A
Question: The average age of 2 boys is 25 years and their ages are in the proportion 3:5:7. The age of the youngest boy is?
Options:
A)10years
B)15years
C)20years
D)25years
E)18years
Rationale: Total age of 2 boys = 25*2 = 50
ratio of their ages = 3:5:7
Age of the youngest = 50*3/15 = 10 years
Answer is A
Answer: A
Question: What is the decimal equivalent of (1/4)^4?
Options:
A)0.0039
B)0.0625
C)0.16
D)0.25
E)0.5
Rationale: (1/4)^4 = 1/256 = 0.0039
Answer : A
Answer: A
Question: In ΔPQS above, if PQ =7 and PS = 8, then
Options:
A) 9/4
B) 12/5
C) 56/9
D) 15/4
E)20/3
Rationale: there are two ways to calculate area of PQS. area remains same, so both are equal.
7*8/2 = PR*9/2
PR = 56/9
C
Answer: C
Question: If 11 lions can kill 11 deers in 11 minutes how long will it take 100 lions to kill 100 deers?
Options:
A)1 minutes
B)11 minute
C)100 minutes
D)10000 minutes
E)1000 minutes
Rationale: we can try the logic of time and work,our work is to kill the deers so 11(lions)*11(min)/11(deers)=100(lions)*x(min)/100(deers)hence answer is x=11
ANSWER:B
Answer: B
Question: Helen went to the stationers and bought things worth Euro 35, out of which 30 paise went on sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax free items?
Options:
A)Euro 15
B)Euro 15.7
C)Euro 19.7
D)Euro 29.7
E)None
Rationale: Explanation: Let the amount taxable purchases be Euro x.
Then, 6% of x = 30/100
x = (30/100 x 100/6) = 5.
Cost of tax free items = Euro [35 - (5 + 0.30)] = Euro 29.70
Answer: Option D
Answer: D
Question: If Josh, Doug, and Brad have a total of $72 between them, and Josh has three times as much money as Brad but only three-fourths as much as Doug, how much money does Doug have?
Options:
A)$8
B)$9
C)$27
D)$32
E)$36
Rationale: josh+Doug+Brad = 72 ; Josh = 3 brad, Josh =3/4 doug
Josh+1/3 Josh+ 4/3 Josh = 72 (substituted the given values)
Josh = 27. 27= 3/4 doug => doug =36
ANSWER:E
Answer: E
Question: A thief is noticed by a policeman from a distance of 200 m. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 10 km and 11 km per hour respectively. What is the distance between them after 6 minutes?
Options:
A)100 m
B)150 m
C)500 m
D)200 m
E)175 m
Rationale: Relative speed of the thief and policeman = 11 - 10 = 1 km/hr.
Distance covered in 6 minutes = 1/60 * 6 = 1/10 km = 100 m.
Distance between the thief and policeman = 200 - 100 = 100 m.
ANSWER A
Answer: A
Question: A box contains 100 balls, numbered from 1 to 100. If three balls are selected at random and with replacement from the box, what is the probability G that the sum of the three numbers on the balls selected from the box will be odd?
Options:
A)1/4
B)3/8
C)1/2
D)5/8
E)3/4
Rationale: The sum of the three numbers on the balls selected from the box to be odd one should select either three odd numbered balls (Odd+Odd+Odd=Odd) or two even numbered balls and one odd numbered ball (Even+Even+Odd=Odd);
P(OOO)=(1/2)^3;
P(EEO)=3*(1/2)^2*1/2=3/8 (you should multiply by 3 as the scenario of two even numbered balls and one odd numbered ball can occur in 3 different ways: EEO, EOE, or OEE);
So finally G=1/8+3/8=1/2.
Answer: C.
Answer: C