divelab/Sys2Bench huggingface dataset:
Question: A train passes a station platform in 48 sec and a man standing on the platform in 40 sec. If the speed of the train is 36 km/hr. What is the length of the platform?
Options:
A)80
B)120
C)60
D)90
E)50
Rationale: Speed = 36 * 5/18 = 10 m/sec.
Length of the train = 10 * 40 = 400 m.
Let the length of the platform be x m . Then,
(x + 400)/48 = 10 => x = 80 m.
Answer: A
Answer: A
Question: How many odd, positive divisors does 520 have?
Options:
A)6
B)8
C)12
D)15
E)24
Rationale: Make a prime factorization of a number: 540=2^2*3^3*5 --> get rid of powers of 2 as they give even factors --> you'll have 3^3*5 which has (3+1)(1+1)=6 factors.
Another example: 60=2^2*3*5 it has (2+1)(1+1)(1+1)=12 factors out of which (1+1)(1+1)=4 are odd: 1, 3, 5 and 15 the same # of odd factors as 60/2^2=15 has.
Answer: A
Answer: A
Question: When positive integer k is divided by 5, the remainder is 2. When k is divided by 6, the remainder is 5. If k is less than 41, what is the remainder when k is divided by 7?
Options:
A)3
B)4
C)5
D)6
E)7
Rationale: Cant think of a straight approach but here is how I solved it:
K is divided by 5 and remainder is 2. This means k = 5n + 2 (n is an integer)
so the possible values of K = {2, 7, 12, 17, 22, 27, 32, 37} (less than 41)
Secondly, if K is divided by 6, the remainder is 5 => k= 6m + 5
so the possible value set for k = {5, 11, 17, 23, 29,35} (less than 41)
17 is the only common number in both the sets. Hence k = 17
Answer : A
Answer: A
Question: The speed of a car is 90kmph. What is the speed in metres per second.
Options:
A)25 m/s
B)40 m/s
C)35 m/s
D)28 m/s
E)27 m/s
Rationale: Explanation:
km/hr to m/sec conversion:
x km/hr = (x × 5/18) m/sec
90 × 5/18 = 25.
Answer: Option A
Answer: A
Question: If a man walks 24 Km at 8 Kmph, he will be late by 25min. if he walks 12 Kmph, how early the fixed time Will he reach?
Options:
A)30 minutes
B)25 minutes
C)40 minutes
D)35 minutes
E)20 minutes
Rationale: Time taken to cover 24 Km at the speed of 8 Kmph = 24/8 = 3 hours
Thus, right time was 2 hours 35 mintes
Now, time taken to cover 20 Km at the speed as 12 Kmph = 2 hours
Required time = 2 hours 35 minutes - 2 hours
= 35 minutes
ANSWER IS D
Answer: D
Question: In how many different ways can the letters of the word 'DETAIL' be arranged such that the vowels must occupy only the odd positions?
Options:
A)12
B)36
C)45
D)96
E)83
Rationale: The word 'DETAIL' has 6 letters which has 3 vowels (EAI) and 3 consonants(DTL)
The 3 vowels(EAI) must occupy only the odd positions. Let's mark the positions as (1) (2) (3) (4) (5) (6). Now, the 3 vowels should only occupy the 3 positions marked as (1),(3) and (5) in any order.
Hence, number of ways to arrange these vowels
= 3P3 =3!=3×2×1=6
Now we have 3 consonants(DTL) which can be arranged in the remaining 3 positions in any order. Hence, number of ways to arrange these consonants
= 3P3=3!=3×2×1=6
Total number of ways
= number of ways to arrange the vowels × number of ways to arrange the consonants
=6×6=36
Answer: B
Answer: B
Question: 10 meters of wire is available to fence off a flower bed in the form of a circular sector. What must the radius of the circle in meters be, if we wish to have a flower bed with the greatest possible surface area?
Options:
A)5/2
B)2√5
C)5
D)4√2
E)none of these
Rationale: Area of Sector, A = x/360*pi*r^2
Circumference of the sector = 10
=> x/360*2*pi*r +2r= 20
=> 2A/r+2r=10 OR 2A +2r^2=10r
=> A= r5-r^2
= r5-r^2
We will now max using derivations
i.e 5-2r=0
r=5/2
A
Answer: A
Question: The radius of the two circular fields is in the ratio 3: 5 the area of the first field is what percent less than the area of the second?
Options:
A)50%
B)60%
C)40%
D)64%
E)55%
Rationale: Explanation:
r = 3 πr2 = 9
r = 5 πr2 = 25
25 π – 16 π
100 ---- ? => 64%
ANSWER IS D
Answer: D
Question: 4, 6, 12, 14, 28, 30, .. ?
Options:
A)20
B)40
C)no=60
D)80
E)100
Rationale: C
60
The given sequence is a combination of two series 4, 12, 28, .... and 6, 14, 30, .... The pattern is +8, +16, +32. So, the missing number = (28 + 32) = 60
Answer: C
Question: A bag contains 11 wool scarves, exactly one of which is red and exactly one of which is green. If Deborah reaches in and draws three scarves, simultaneously and at random, what is the probability that she selects the red scarf but not the green scarf?
Options:
A)8/19
B)10/33
C)12/55
D)15/67
E)20/83
Rationale: Total possible ways to choose three scarves is 11C3 = 165
We need to choose the red scarf and two of 9 other scarves (not the green scarf).
The number of successful possibilities is 9C2 = 36
P(red scarf but not green scarf) = 36/165 = 12/55
The answer is C.
Answer: C
Question: Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is?
Options:
A)15
B)17
C)19
D)21
E)26
Rationale: Let the three integers be x, x + 2 and x + 4.
Then, 3x = 2(x + 4) + 3 x = 11.
Third integer = x + 4 = 15.
Option A
Answer: A
Question: How many two digit numbers are there such that the product of their digits after reducing it to the smallest form is a prime number? for example if we take 98 then 9*8=72, 72=7*2=14, 14=1*4=4. Consider only 4 prime numbers (2,3,5,7)
Options:
A)27
B)28
C)18
D)99
E)01
Rationale: Explanation:
2 = 12 or 21 So 1×2, 2×1, 3×4, 4×3, 2×6, 6×2, 3×7, 7×3
3 = 13 or 31 So 1×3, 3×1
5 = 15, 51 So 1×5, 5×1, 3×5, 5×3, 7×5, 5×7
7 = 17 or 71 So 1×7, 7×1
15 = 3×5 = 5×3
So total 18 numbers = 12,13,15,17,21,26,31,34,35,37,43,51,53,57,62,71,73,75
Answer:C
Answer: C
Question: A is a working partner and B is a sleeping partner in the business. A puts in Rs.15000 and B Rs.25000, A receives 10% of the profit for managing the business the rest being divided in proportion of their capitals. Out of a total profit of Rs.9600, money received by A is?
Options:
A)2888
B)2669
C)2997
D)4200
E)2877
Rationale: 15:25 => 3:5
9600*10/100 = 960
9600 - 960 = 8640
8640*3/8 = 3240 + 960
= 4200.Answer: D
Answer: D
Question: Beginning in Town A, Biker Bob rides his bike 30 miles west, 6 miles north, 15 miles east, and then 18 miles north, to Town B. How far apart are Town A and Town B? (Ignore the curvature of the earth.)
Options:
A)27 miles
B)25 miles
C)24 miles
D)28.3 miles
E)23 miles
Rationale: Using Pythagoras we have one side i,e total distance traveled in north direction = 18+6=24m
other being the base ie distance traveled west- distance traveled eat=30-15=15 m
now this third side or the distance between town A and Town B=24^2+ 15^2=sq root 801=28.3m
Answer : D
Answer: D
Question: P and Q invested in a business. The profit earned was divided in the ratio 4 : 5. If P invested Rs 52000, the amount invested by Q is
Options:
A)30000
B)50000
C)40000
D)20000
E)65000
Rationale: Let the amount invested by Q = q
52000:q=4:5
⇒52000×5=4q
⇒q=(52000×5)/4=65000
Answer is E.
Answer: E
Question: If the price of an article went up by 60%, then by what percent should it be brought down to bring it back to its original price?
Options:
A)16 2/3%
B)37 1/2%
C)16 7/3%
D)16 6/3%
E)16 2/3%
Rationale: Let the price of the article be Rs. 100.
60% of 100 = 60.
New price
= 100 + 60 = Rs. 160
Required percentage
= (160 - 100)/160 * 100
= 60/160 * 100
= 75/2
= 37 1/2%.
Answer:B
Answer: B
Question: What profit percent is made by selling an article at a certain price, if by selling at 2/3rd of that price, there would be a loss of 20%?
Options:
A)20%
B)25%
C)70%
D)28%
E)30%
Rationale: SP2 = 2/3 SP1
CP = 100
SP2 = 80
2/3 SP1 = 80
SP1 = 120
100 --- 20 => 20%
Answer:A
Answer: A
Question: A train 110 meters long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?
Options:
A)5
B)6
C)7
D)8
E)5
Rationale: Speed of train relative to man = (60 + 6) km/hr = 66 km/hr
[66 * 5/18] m/sec = [55/3] m/sec.
Time taken to pass the man = [110 * 3/55] sec = 6 sec
Answer: B
Answer: B
Question: The ratio of Ajay’s and Balu’s ages is 4: 5. If the difference between the present age of Balu and the age of Ajay 5 years hence is 3 years, then what is the total of present ages of Ajay and Balu?
Options:
A)68 years
B)72 years
C)76 years
D)64 years
E)74 years
Rationale: Let us consider Ajay as A and Balu as B.
Given A/B = 4/5
And B - (A + 5) = 3
B - A = 8
B = 8 + A
Now, A/(8 + A) = 4/5
A = 32 years
Therefore B = 40 years.
A + B = 72 years
ANSWER:B
Answer: B
Question: If a and b are each greater than x and y, which of the following must be true?
I. ab < xy
II.a + b > x + y
III. |a| + |b| > |x| + |y|
Options:
A)I only
B)II only
C)I and II
D)I and III
E)I, II and III
Rationale: I. a + b > x + y. Since a and b are each greater than x and y, then the sum of a and b will also be greater than the sum of x and y.
II. ab > xy. Not necessarily true, consider a = b = 0 and x = y = -1 --> ab = 0 < 1 = xy.
III. |a| + |b| > |x| + |y|. Not necessarily true, consider a = b = 0 and x = y = -1 --> |a| + |b| = 0 < 2 = |x| + |y|.
Answer: B.
Answer: B
Question: How many even integers n, such that 20<=n<=240 are of the form 3k+4, where k is any natural number?
Options:
A)31
B)33
C)35
D)37
E)39
Rationale: The first number is 22 = 16+6(1).
We can continue adding 6 to make a list: 22, 28, 34,...
The last number is 238 = 16+6(37)
There are 37 numbers in the list.
The answer is D.
Answer: D
Question: In a certain pond, 50 fish were caught, tagged, and returned to the pond. A few days later, 50 fish were caught again, of which 4 were found to have been tagged. If the percent of tagged fish in the second catch approximates the percent of tagged fish in the pond, what is the approximate number of fish in the pond?
Options:
A) 400
B) 625
C) 1,250
D) 2,500
E) 10,000
Rationale: total fish = x
percentage of second catch = (4/50)*100 = 8%
so, x * 8% = 50
x = 625 ans. B
Answer: B
Question: The probability that A speaks truth is 3/5 and that of B speaking truth is 3/7. What is the probability that they agree in stating the same fact?
Options:
A)17/35
B)17/39
C)17/36
D)17/33
E)17/32
Rationale: If both agree stating the same fact, either both of them speak truth of both speak false.
Probability = 3/5 * 3/7 + 2/5 * 4/7
= 9/35 + 8/35 = 17/35
Answer: A
Answer: A
Question: Two trains 125 meters and 165 meters in length respectively are running in opposite directions, one at the rate of 80 km and the other at the rate of 65 kmph. In what time will they be completely clear of each other from the moment they meet?
Options:
A)7.16
B)7.16
C)7.12
D)7.15
E)7.2
Rationale: T = (125 + 165)/ (80 + 65) * 18/5
T = 7.2
Answer: E
Answer: E
Question: If Rs. 510 be divided among A, B, C in such a way that A gets 2/3 of what B gets and B gets 1/4 of what C gets, then their shares are respectively:
Options:
A)Rs. 60, Rs. 90, Rs. 389
B)Rs. 60, Rs. 90, Rs. 360
C)Rs. 60, Rs. 90, Rs. 368
D)Rs. 60, Rs. 90, Rs. 329
E)Rs. 60, Rs. 30, Rs. 329
Rationale: (A = 2/3 B and B = 1/4 C) = A/B = 2/3 and B/C = 1/4
A:B = 2:3 and B:C = 1:4 = 3:12
A:B:C = 2:3:12
A;s share = 510 * 2/17 = Rs. 60
B's share = 510 * 3/17 = Rs. 90
C's share = 510 * 12/17 = Rs. 360.
Answer:B
Answer: B
Question: A sum of money is put out at compound interest for 2 years at 20%. It would fetch Rs.482 more if the interest were payable half-yearly, then it were pay able yearly. Find the sum.
Options:
A)2200
B)1897
C)8799
D)2000
E)2782
Rationale: P(11/10)4 - P(6/5)2 = 482
P = 2000
Answer: D
Answer: D
Question: Find the area of circle whose radius is 70m?
Options:
A)28866
B)23456
C)76766
D)16866
E)15400
Rationale: 22/7 * 70 * 70
= 15400
Answer: E
Answer: E
Question: What is the least number which should be added to 2697 so that the sum is exactly divisible by 5, 6, 4, and 3?
Options:
A)3
B)11
C)19
D)27
E)35
Rationale: L.C.M. of 5, 6, 4 and 3 = 60.
When dividing 2697 by 60, the remainder is 57.
The number to be added = 60 - 57 = 3.
The answer is A.
Answer: A
Question: A can do a piece of work in 15 days and B alone can do it in 10 days. B works at it for 5 days and then leaves. A alone can finish the remaining work in
Options:
A)5days
B)6days
C)7.5days
D)8.5days
E)9days
Rationale: Explanation:
B's 5 days work =
1/10∗5=1/2
Remaining work =1−1/2=1/2
A can finish work =15∗1/2=7.5days
Option C
Answer: C
Question: If the range of the set of numbers {140, 90, 135, 110, 170, 145, x, 123, 136} is 110, which of the following could be x?
Options:
A)40
B)50
C)60
D)70
E)80
Rationale: The range of the other 8 numbers is 170-90 = 80, so x must be either the smallest number or the largest number in the set.
Then x = 170-110 = 60 or x = 90+110 = 200
The answer is C.
Answer: C
Question: Due to construction, the speed limit along an 8-mile section of highway is reduced from 55 miles per hour to 35 miles per hour. Approximately how many minutes more will it take to travel along this section of highway at the new speed limit than it would have taken at the old speed limit ?
Options:
A)5
B)8
C)10
D)15
E)24
Rationale: Let t1 is time taken @ 55 mph
t1 = 8/55
Let t2 is time taken @ 35 mph
t2 = 8/35
Difference in time = 8/35 - 8/55 = 8 * 20 / (35 * 55) hr = 160 * 60 / (35 * 55) mins = 4.7 = 5 (approx) mins
ANSWER:A
Answer: A
Question: A train 300 m long passed a pole in 10 sec. How long will it take to pass a platform 600 m long?
Options:
A)80
B)90
C)100
D)110
E)120
Rationale: Speed = 300/10 = 30 m/sec.
Required time = (300 + 600)/10
= 90 sec.
Answer:B
Answer: B
Question: If i equals the sum of the even integers from 2 to 200, inclusive, and k equals the sum of the even integers from 20 to 200, inclusive, what is the value of i - k?
Options:
A)10
B)99
C)9
D)88
E)90
Rationale: Use following formulae for such problems:
Sum of evenly spaced integers = (# of integers)*(mean of integers)
# of integers = [(last - first)/2] + 1
Mean of integers = (last + first)/2
In above problem:
# of integers = [(200 - 2)/2] + 1= 100 and [(200-20)/2]+ 1 = 91
Mean of integers = (200 + 2)/2 = 101 and (200 + 20)/2 = 110
Sum of integers = (100*101) = 10100 and (91*110) = 10010
Thus their difference i - k = 10100 - 10010 = 90
ANSWER:E
Answer: E
Question: If xy = 6 and x^2 + y^2 = 12, then x/y + y/x =
Options:
A)2
B)3 1/7
C)5 1/3
D)7
E)60
Rationale: We can make simplifying of question and get it in view: (x^2 + y^2) / xy and as we know the meaning of this parts:
x^2 + y^2 = 12
xy = 6
we can calculate the answer 12/6 -> 2 so answer is A
Answer: A
Question: The length of the longest tape in cm which can be used to measure exactly, the length 7m; 3m 85cm; and 12m 95cm is:
Options:
A)37
B)35
C)34
D)36
E)38
Rationale: The three lengths in cm are 700, 385 & 1295.
HCF of 700, 385 & 1295 is 35.
Hence, the answer is 35 cm.
ANSWER:B
Answer: B
Question: A boat can move upstream at 32 kmph and downstream at 30 kmph, then the speed of the current is?
Options:
A)5
B)9
C)1
D)9
E)5
Rationale: US = 32
DS = 30
M = (32 - 30)/2 = 1
Answer: C
Answer: C
Question: Calculate Ronald's average score in an exam if he obtained the following marks 51, 57, 68, 60 and 78 out of 100 in different subjects.
Options:
A)69.8
B)67.8
C)62.8
D)61.8
E)60.8
Rationale: Explanation:
(51+57+68+60+78)/5=62.8
Answer: Option C
Answer: C
Question: How many two-digit whole numbers yield a remainder of 1 when divided by 20 and also yield a remainder of 1 when divided by 5?
Options:
A)None
B)One
C)Two
D)Three
E)Four
Rationale: The possible number N can be written as follow:
N = Multiple of LCM(20,5) + 1st such number
N = 20x + 1
Possible values = 1, 21, 41, 61,81
Answer : 4 such 2 digit number. E.
Answer: E
Question: What is the greatest positive integer x such that 2^x is a factor of 8^10?
Options:
A)5
B)9
C)10
D)20
E)30
Rationale: 8^10 = (2^3)^10 = 2^30
ANSWER:E
Answer: E
Question: If A is 25% greater than B then how much percentage is B smaller than A?
Options:
A)20%
B)30%
C)40%
D)50%
E)60%
Rationale: X = 125
Y = 100
X-Y/X × 100 = 25/125 × 100 = 20 % smaller smaller than X
A)
Answer: A
Question: If a = 105 and a^3 = 21 × 25 × 45 × d, what is the value of d?
Options:
A)35
B)42
C)45
D)49
E)54
Rationale: a=105 = 3* 5 *7
a^3 = 21 × 25 × 45 × d
=> a^3 = (7*3) x (5*5) x ( 3^2 * 5) x d
=> a^3 = 3^3 * 5^3 * 7 x d
=>( 3* 5 *7) ^3 = 3^3 * 5^3 * 7 x d
d = 7^2 = 49
Answer D
Answer: D
Question: A can do a piece of work in 12 days. He worked for 15 days and then B completed the remaining work in 10 days. Both of them together will finish it in?
Options:
A)12 1/2 days
B)12 6/2 days
C)12 1/6 days
D)17 1/2 days
E)12 1/8 days
Rationale: 15/25 + 10/x = 1 => x = 25
1/25 + 1/25 = 2/25
25/2 = 12 1/2 days
Answer:A
Answer: A
Question: The average weight of 5 students decreases by 4 kg when one of them weighing 92 kg is replaced by a new student. The weight of the student is
Options:
A)62 kg
B)60 kg
C)70 kg
D)72 kg
E)None of these
Rationale: Explanation :
Let the weight of student be x kg.
Given, Difference in average weight = 4 kg
=> (92-x)/5 = 4
=> x = 72
Answer : D
Answer: D
Question: A Shopkeeper divides an ice-cream brick in two halves, then cut one of the halves into several smaller portions of equal size. Each of the smaller portions weights 12 grams. The shopkeeper now has a total of 5 portions. How heavy was the original brick?
Options:
A)96grams
B)97grams
C)98grams
D)99grams
E)95grams
Rationale: Since there are 5 portions, 4 small portions of equal size and one half of original ice-cream brick.
1 small portion = 12 grams
4 small portion = 4*12 = 48grams
Therefore weight of original ice-cream brick = 48*2 = 96grams
ANSWER:A
Answer: A
Question: HCF of
22×32×52,24×34×53×11
is
Options:
A)24×34×53
B)24×34×53×11
C)22×32×52
D)2×3×5
E)None of these
Rationale: Explanation:
As in HCF we will choose the minimum common factors among the given.. So answer will be third
option
Answer: Option C
Answer: C
Question: What is the average (arithmetic mean) of all the multiples of ten from 10 to 200 inclusive?
Options:
A)90
B)95
C)100
D)105
E)110
Rationale: 10 and 190 inclusive would mean there are 19 terms.
No need to add up all the terms and further divide by 20 since the terms are evenly spaced in ascending order from 10, 20, 30........200
The middle term is the average which is the tenth term = 110
E is the answer.
Answer: E
Question: Find the area of circle whose radius is 7m?
Options:
A)124 sq m
B)154 sq m
C)145 sq m
D)167 sq m
E)180 sq m
Rationale: r = 7
Area of Circle =∏r2
= (22/7)(7)(7)
= 154 sq m.Answer: B
Answer: B
Question: What is the number of integers from 1 to 1000 (inclusive) that are divisible by neither 11 nor by 34?
Options:
A)884
B)890
C)892
D)910
E)945
Rationale: Normally, I would use the method used by Bunuel. It's the most accurate. But if you are looking for a speedy solution, you can use another method which will sometimes give you an estimate. Looking at the options (most of them are spread out), I wont mind trying it. (Mind you, the method is accurate here since the numbers start from 1.)
In 1000 consecutive numbers, number of multiples of 11 = 1000/11 = 90 (Ignore decimals)
In 1000 consecutive numbers, number of multiples of 35 = 1000/35 = 28
Number of multiples of 11*35 i.e. 385 = 1000/385 = 2
Number of integers from 1 to 1000 that are divisible by neither 11 nor by 35 = 1000 - (90 + 28 - 2) {Using the concept of sets here) = 890
Think: Why did I say the method is approximate in some cases?
Think what happens if the given range is 11 to 1010 both inclusive (again 1000 numbers)
What is the number of multiples in this case?
B
Answer: B
Question: The length of a rectangle is two - fifths of the radius of a circle. The radius of the circle is equal to the side of the square, whose area is 5625 sq.units. What is the area (in sq.units) of the rectangle if the rectangle if the breadth is 10 units?
Options:
A)140 sq.units
B)300 sq.units
C)367sq.units
D)178sq.units
E)176sq.units
Rationale: Given that the area of the square = 5625 sq.units
=> Side of square = √5625 = 75units
The radius of the circle = side of the square = 75 units Length of the rectangle = 2/5 * 75 = 30 units
Given that breadth = 10 units
Area of the rectangle = lb = 30 * 10 = 300 sq.units
Answer:B
Answer: B
Question: What is the probability that a 5 person committee chosen at random from a group consisting of 6 men, 7 women, and 5 children contains exactly 1 woman?
Options:
A)55/204
B)77/832
C)11/77
D)308/1411
E)22/832
Rationale: Total possible selections = 5 out of 18 group members = 18C5
Favorable selections = 1 out of 7 women and 4 out of 11 (= 6 men + 5 children) = 7C1 * 11C4
Thus the required probability = 7C1*11C4 / 18C5 = 55/204. Thus A is the correct answer.
Answer: A
Question: Baker Tom is storing cake boxes in cartons that measure 25 inches by 42 inches by 60 inches. If the measurement of each cake box is 8 inches by 7 inches by 5 inches, then what is the maximum number of cake boxes that can be placed in each carton?
Options:
A)330
B)300
C)252
D)225
E)210
Rationale: Baker Tom is storing cake boxes in cartons The dimensions of the carton are 25x 42x 60and those of each cake box are 8x 7x 5.
To maximize number of boxes try and fit maximum into the base of the box. If you take the base as 25x 42and fit 5 x 6 boxes of 5x 7, then the total number of boxes is 5 x 6 x integer(60/8) = 5 x 6 x 7 = 210.
Alternatively you could try taking the base as 60x 42and fit 12 x 6 boxes of 5x 7, then the total number of boxes is 12 x 6 x integer(25/8) = 12 x 6 x 3 = 216. But since that is not an answer option, I go with (E) 210.
Answer: E
Question: A man buys a cycle for Rs. 1400 and sells it at a loss of 15%. What is the selling price of the cycle?
Options:
A)Rs. 1090
B)Rs. 1160
C)Rs. 1190
D)Rs. 1202
E)Rs. 1502
Rationale: S.P. = 85% of Rs. 1400 = Rs. 85/100	x 1400 = Rs. 1190
Answer: Option C
Answer: C
Question: The original price of a camera was displayed as a whole dollar amount. After adding sales tax of 5 percent, the final price was also a whole dollar amount. Which of the following could be the final price of the camera?
Options:
A)$107
B)$109
C)$106
D)$111
E)$105
Rationale: Final price = (1+5/100) * Original Price
= 1.05 * Original Price
From options given only 105 is divisible by 1.05 as it is stated OP is whole dollar amount.
Hence E
Answer: E
Question: Three candidates contested an election and received 936, 7636 and 19628 votes respectively. What percentage of the total votes did the winning candidate got
Options:
A)55%
B)56%
C)57%
D)58%
E)69.6%
Rationale: Explanation:
Total number of votes polled = (936 + 7636 + 19628) = 28200
So, Required percentage = 19628/28200 * 100 = 69.6%
Answer: Option E
Answer: E
Question: Company A has 13 employees, 8 of whom belong to the union. If 5 people work any one shift, and the union contract specifies that at least 5 union members work each shift, then how many different combinations of employees might work any given shift?
Options:
A)56
B)231
C)336
D)350
E)406
Rationale: Looks easy: -- 8C5*5C1 + 8C5 -- 336 (C).
Answer: C
Question: P can do piece of work in 30 days while Q alone can do it in 40 days. In how many days can P and Q working together do it?
Options:
A)17 1/7
B)18 1/7
C)20 1/7
D)22 1/7
E)24 2/7
Rationale: P DAYS WORK = 1/30
Q ONE DAY WORK = 1/40
(P+Q) ONE DAY = 1/30 + 1/40 = 7/120
A AND B FINISH WORK = 17 1/7 DAYS
ANSWER A
Answer: A
Question: If 1535/1038 = a +1/[b+1/{c+(d+1/e)}]. Find a*b*c*d*e?
Options:
A)165/2
B)175/2
C)178/3
D)187 by 2
E)197/2
Rationale: by expanding 1535/1038 make form like a+1/[b+1/{c+(d+1/e)}
=1+(497/1038) now a=1
=1+{1/(1038/497)}
=1+{1/(2+42/497)}
=1+{1/ (2+1/(497/42)} now b= 2 similarly expand
c=11 d= 1 e=34/8
finally a*b *b*c*d*e
1*2*11*1*34/8
187/2
ANSWER:D
Answer: D
Question: In how many different number of ways 4 boys and 1 girls can sit on a bench?
Options:
A)120
B)730
C)740
D)750
E)800
Rationale: npn = n!
5p5 = 5 × 4 × 3 × 2 × 1 = 120
A
Answer: A
Question: An automobile financier claims to be lending money at simple interest, but he includes the interest every six months for calculating the principal. If he is charging an interest of 10%, the effective rate of interest becomes:
Options:
A)10%
B)10.25%
C)10.5%
D)11 %
E)None of these
Rationale: Let the sum be Rs. 100. Then,
S.I. for first 6 months = Rs.((100 x 10 x 1)/(100 x 2))	= Rs. 5
S.I. for last 6 months = Rs.((105 x 10 x 1)/	(100 x 2))= Rs. 5.25
So, amount at the end of 1 year = Rs. (100 + 5 + 5.25) = Rs. 110.25
Effective rate = (110.25 - 100) = 10.25%
Answer : B
Answer: B