divelab/Sys2Bench huggingface dataset:
Question: John has on his shelf three books of poetry, five novels, and two reference works. Suppose from these ten books, we were to pick two books at random. What is the probability that we pick one novel and one reference work?
Options:
A)1/2
B)2/9
C)3/10
D)7/20
E)8/45
Rationale: When we are picking two books, one novel and one reference work, we could either pick a novel first and then a reference book or pick a reference book and then a novel. Therefore the answer is 5/10*2/9 + 2/10*5/9 = 2/9.
Answer: B.
Answer: B
Question: After his first semester in college, Thomas is applying for a scholarship that has a minimum Grade Point Average (GPA) requirement of 3.5. The point values of pertinent college grades are given in the table below. If Thomas took 3 courses, each with an equal weight for GPA calculations, and received two grades of A-, one grade of B+, and one grade of B, what is the lowest grade that Thomas could receive for his fifth class to qualify for the scholarship?
Point Values of Select Grades
Grade: A | A- | B+ | B | B- | C+ | C | C-
Value: 4 | 3.7 | 3.3 | 3 | 2.7 | 2.3 | 2 | 1.7
Options:
A) A
B) B+
C) B
D) B-
E) C+
Rationale: Grade: A | A- | B+ | B | B- | C+ | C | C-
Value: 4 |3.7|3.3|3| 2.7 | 2.3 | 2 | 1.7
7.4 + 3.3 + 3 + x = 3.5 * 5
x = 17.5 - 13.7 = 3.8
Grade A is required to qualify
Answer = C+
E
Answer: E
Question: A boat M leaves shore A and at the same time boat B leaves shore B. They move across the river. They met at 500 yards away from A and after that they met 300 yards away from shore B without halting at shores. Find the distance between the shore A & B
Options:
A)1000 yards
B)1200 yards
C)1400 yards
D)1600 yards
E)1800 yards
Rationale: If X is the distance, a is speed of A and b is speed of B, then ;
500/a= (x-500)/b and (x+300)/a = (2x-300)/b , solving it, we get x=1200 yards
ANSWER:B
Answer: B
Question: A watch passes through three hands and each gains 25%. If the 3rd sells it for Rs250, what did the 1st pay for it?
Options:
A)110
B)114
C)128
D)130
E)138
Rationale: First Purchased = 250 Wes= 128
C
Answer: C
Question: The sides of a triangle are in the ratio 5: 12: 13 and its perimeter is 360 m, its area is?
Options:
A)180
B)882
C)277
D)261
E)281
Rationale: 5x + 12x + 13x = 360 => x = 12
a = 60, b = 144, c = 156
S = (60 + 144 + 156)/2 = 180
Answer: A
Answer: A
Question: Find the area of a parallelogram with base 10 cm and height 20 cm.
Options:
A)200
B)384
C)200
D)244
E)242
Rationale: Area of a parallelogram = base * height = 10 * 20 = 200 cm2
Answer: Option C
Answer: C
Question: If the number 517 * 324 is completely divisible by 3, then the smallest whole number in the place of * will be:
Options:
A)1
B)2
C)3
D)4
E)5
Rationale: B
2
Sum of digits = (5 + 1 + 7 + x + 3 + 2 + 4) = (22 + x), which must be divisible by 3.
x = 2.
Answer: B
Question: In a rectangular coordinate system, if a line passes through the points (-17,-18), (13,22) and (x,2) then what is the value of x?
Options:
A)-2
B)-1
C)0
D)1
E)2
Rationale: The slope of the line m is rise/run = 22-(-18) / 13-(-17) = 4/3
4/3 = 22-2 / 13-x
52-4x = 66-6
x = -2
The answer is A.
Answer: A
Question: A and B together can do a piece of work in 8 days. If A alone can do the same work in 12 days, then B alone can do the same work in?
Options:
A)20 days
B)16 days
C)24 days
D)28 days
E)32 days
Rationale: Explanation:
B = 1/8 – 1/2 = 1/24 => 24 days
Answer: C
Answer: C
Question: Of 30 applicants for a job, 14 had at least 4 years of exper, 18 had degrees, and 3 had less than 4 years exper and did not have a degree, how many applicants had at least 4 years exper and a degree?
Options:
A)a)14
B)b)13
C)c)9
D)d)7
E)e)5
Rationale: Answer is E. Here is how:
The quickest way is to setup a matrix and work through the given values in the question.
For all such problems, set up a matrix with number of columns and rows corresponding to the divisions mentioned in the question stem.
Degrees and Experience
> 4 yrs Exp< 4 yrs ExpTotal
Degree5Required Value1318Given
No Degree9312
Total14Given1630 Given answer is E
Answer: E
Question: Set A: {1, 3, 4, 6, 10, 12, 15}
If three numbers are randomly selected from set A without replacement, what is the probability that the sum of the three numbers is divisible by 3?
Options:
A)3/14
B)2/7
C)9/14
D)5/7
E)4/35
Rationale: using probability you can solve: 4/7*3/6*2/5=4/35.
Ans E
Answer: E
Question: If n is an integer and 5^n > 40,000,000,000, what is the least possible value of n?
Options:
A)16
B)8
C)9
D)10
E)11
Rationale: When you seperate the 40000000000 into factors of 5 and 2 you get - > 10^10 x 2^2 = 5^10 x 2^12
2 to the ^ 8 = 4096 so its4096 x 5^10
that means 5^10 x 5^x must be greater
5^x > 4096
5^1=5
5^2=25
5^3= 125
5^6= 15625 - > so x must be at least 6
5^(10+6)= 5^16
A
Answer: A
Question: By selling a house for Rs.45000, it was found that 1/8 of the outlay was gained, what ought the selling to price to have been in order to have lost 8 p.c?
Options:
A)28000
B)36800
C)37000
D)38000
E)40000
Rationale: Option B
Explanation:
CP + CP/8 = 45000
CP = 40000
SP = 40000*(92/100) = 36800
Option B
Answer: B
Question: Jason flips a coin three times. What is the probability Q that the coin will land on the same side in all three tosses?
Options:
A)1/16
B)1/8
C)1/4
D)1/3
E)1/2
Rationale: Total outcome is 2^3=8
Favorable cases HHH or TTT
Therefore, probability Q is 2/8 or 1/4=C
Answer: C
Question: A man can row with a speed of 20 kmph in still water. If the stream flows at 30 kmph, then the speed in downstream is?
Options:
A)27
B)41
C)20
D)50
E)60
Rationale: M = 20
S = 30
DS = 30+ 20 = 50
Answer:D
Answer: D
Question: The largest 4 digit number exactly divisible by 88 is:
Options:
A)9944
B)9768
C)9988
D)8888
E)None of these
Rationale: Explanation:
Largest 4-digit number = 9999
88) 9999 (113
88
----
119
88
----
319
264
---
55
---
Required number = (9999 - 55)
= 9944.
ANSWER IS A
Answer: A
Question: The batting average of a particular batsman is 61 runs in 46 innings. If the difference in his highest and lowest score is 150 runs and his average excluding these two innings is 58 runs, find his highest score.
Options:
A)179
B)202
C)210
D)223
E)229
Rationale: Explanation:
Total runs scored by the batsman = 61*46 = 2806 runs
Now excluding the two innings the runs scored = 58*44 = 2552 runs
Hence the runs scored in the two innings = 2806 – 2552 = 254 runs.
Let the highest score be x, hence the lowest score = x – 150
x + (x - 150) = 254
2x = 404
x = 202 runs
ANSWER B
Answer: B
Question: A contest will consist of n questions, each of which is to be answered wither "True" or "False". Anyone who answers all n questions correctly will be a winner. What is the least value of n for which the probability is less than 1/1000 that a person who randomly guesses the answer to each question will be a winner?
Options:
A)5
B)10
C)50
D)100
E)1000
Rationale: (1/2)^n < 1/1000
(1/2)^n < (1/2)^3*(1/5)^3
Because 1/5 ~ (1/2)^2
n > 3 + 3*2 = 9
ANSWER: B
Answer: B
Question: The cross-section of a cannel is a trapezium in shape. If the cannel is 12 m wide at the top and 5 m wide at the bottom and the area of cross-section is 344 sq m, the depth of cannel is?
Options:
A)39
B)28
C)27
D)40
E)71
Rationale: 1/2 * d (12 + 5) = 344
d = 40
Answer: D
Answer: D
Question: Two vessels A and B contain milk and water mixed in the ratio 8:5 and 5:2 res. The ratio in which these two mixtures be mixed to get a new mixture containing milk and a water in the ratio 9:4?
Options:
A)2:8
B)2:1
C)2:2
D)2:3`
E)2:7
Rationale: Step (i) : Let C.P. of milk be Re.1 Given ratio of mixture in A = 8:5  Milk in 1 lit mixture in A = 8/13 lit  C.P of 1 lit mixture in A = Rs. 8/13 Ratio of Mixture in B = 5:2  milk in 1 litre mixture in B – 5/7 lit  C.P of 1 lit mixture in B = Rs. 5/7 Ratio of new mixture = 9:4  milk in 1 lit mixture = 9/13 C.P of 1 lit mixture = Rs/ 9/13 (Mean price) Step (ii) : By the rule of allegation, i. C.P of 1 liter of mixture in A =8/13 ii. C.P of 1 liter of mixture in B = 5/7 iii. Mean price (p) = 9/13 iv. d – m = 9/13 – 5-7 = 2/91 v. m – c = 9/13 – 8/13 = 1/13  Required ratio = 2/91 : 1/13 = 2:7
Answer:E
Answer: E
Question: Free notebooks were distributed equally among children of a class. The number of notebooks each child got was one-eighth of the number of children. Had the number of children been half, each child would have got 16 notebooks. How many notebooks were distributed in all?
Options:
A)432
B)640
C)256
D)512
E)None of these
Rationale: In case I: Let the no. of children = x.
Hence, total no. of notebooks distributed
1⁄8x.x or x2⁄8.......(i)
In case II: no.of children = x⁄2
Now, the total no. of notebooks
= 16 × x⁄2 .......(ii)
Comparing (i) & (ii), we get
x2⁄8 = 8x
or, x = 64
Hence, total no. of notebooks
= 64×64/8=512
Answer D
Answer: D
Question: If n is a 27-digit positive integer, all of whose digits are the same, which of the following must be true?
I. n is divisible by 3
II. n is divisible by 9
III. n is divisible by 27
Options:
A)I only
B)I and II only
C)I and III only
D)II and III only
E)I, II and III
Rationale: Rule for divisibility by 3: The sum of the digits of the number should be multiple of 3
Rule for divisibility by 9: The sum of the nos digits of the number should be divisible by 9 or the number should be divisible by 3 two times.
Rules for divisibility by 27: The sum of the digits should a multiple of 27
Consider no 11111111...27 times = The sum 27*1=27----> divisbible by 3,9 and 27
consider number to be 222....27 times, then sum of the no. 27*2=54 divisible by 3,9 and 27
So why so because when you sum the numbers either you can add the digits 27 times or multiply the digit *27..
Note that since 27 is divisible by 27,9 and 3 and thus the sum of the nos will be divisible by all the nos.
Answer is E
Answer: E
Question: The height of a triangle is decreased by 25% and its base increased by 50%. Its area will
Options:
A)decrease by 12.5%
B)increase by 12.5%
C)decrease by 25%
D)Increase by 25%
E)None of these
Rationale: Explanation :
Let the initial height be 100 and the base be 200 units.
∴ Area = 1/2 x 100 x 200 = 1000sq units
Now, height = 75 units and base = 300 units
∴ New area = 1/2 x 75 x 300 = 11250
∴ Area is increased by (11250 - 10000)/10000 x 10
= 12.5%
Answer : Option B
Answer: B
Question: How much is 80% of 40 is greater than 4/5 of 25?
Options:
A)22
B)67
C)88
D)12
E)66
Rationale: (80/100) * 40 – (4/5) * 25
32 - 20 = 12
Answer: D
Answer: D
Question: If p^2 – 12p + 36 = q, and p is a positive integer between 1 and 10, inclusive, what is the probability that q < 0?
Options:
A)1/10
B)1/5
C)2/5
D)3/5
E)3/10
Rationale: (p-4)(p-8) = q
p = 5 ,6 or 7 for this to be true, so
3/10
Ans :E
Answer: E
Question: A and B can do a work in 5 days and 10 days respectively. A starts the work and B joins him after 4 days. In how many days can they complete the remaining work?
Options:
A)6 days
B)2/3 days
C)8 days
D)3 days
E)9 days
Rationale: Work done by A in 4 days = 4/5
Remaining work = 1/5
Work done by both A and B in one day = 1/5 + 1/10 = 3/10
Remaining work = 1/5 * 10/3 = 2/3 days.
Answer: B
Answer: B
Question: 1
11
21
1211
111221
??????
Options:
A)312211
B)312212
C)312221
D)312222
E)311211
Rationale: 1
11
111 as 21
1211
1112111 as 111221
11112211 as 312211
ans 312211
ANSWER:A
Answer: A
Question: Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is?
Options:
A)40
B)41
C)48
D)67
E)45
Rationale: Relative speed = 60 + 90 = 150 km/hr.
= 150 * 5/18 = 125/3 m/sec.
Distance covered = 1.10 + 0.9 = 2 km = 2000 m.
Required time = 2000 * 3/125 = 48 sec.
Answer: Option C
Answer: C
Question: If population of certain city increases at the rate of 5%. If population in 1981 was 138915, then population in 1978 was?
Options:
A)120000
B)27778
C)27779
D)27767
E)29087
Rationale: X * (105/100) * (105/100) * (105/100) = 138915
X = 138915/1.157625
X = 120000
Answer: A
Answer: A
Question: Six cards numbered from 1 to 6 are placed in an empty bowl. First one card is drawn and then put back into the bowl; then a second card is drawn. If the cards are drawn at random and if the sum of the numbers on the cards is 6, what is the probability that one of the two cards drawn is numbered 3 ?
Options:
A)1/3
B)1/2
C)1/5
D)3/5
E)4/5
Rationale: (5,1) (1,5) (4,2) (2,4) (3,3) – only 5 possible scenarios for sum to be 6. One from this 5 has already happened.
From this five cases, only in one we have 3. So, the probability is 1 chances out of 5 that the one that occurred had 3: P=1/5.
Answer: C.
Answer: C
Question: A train 300 m long is running at a speed of 68 kmph. How long does it take to pass a man who is running at 8 kmph in the same direction as the train?
Options:
A)5 sec
B)9 sec
C)12 sec
D)15 sec
E)18 sec
Rationale: Speed of the train relative to man = (68 - 8) kmph
= (60* 5/18) m/sec = (50/3)m/sec
Time taken by the train to cross the man
= Time taken by It to cover 300 m at 50/3 m / sec
= 300 *3/ 50 sec = 18sec
Answer : E
Answer: E
Question: Three independent strategies A, B and C have been initiated for cost cutting in a company producing respectively 40%, 40% and 10% savings. Assuming that they operate independently, what is the net saving achieved?
Options:
A)56%
B)67.6%
C)62.2%
D)68%
E)61%
Rationale: If initial cost is Rs 100, then
Final cost will be 100*0.6*0.6*0.9 = Rs. 32.4
savings = 100-32.4=67.6
so 67.6%
ANSWER:B
Answer: B
Question: There are two names given JOHNSON and JONES. If one letter is picked from both simultaneously at random, then find the probability that the letter is same?
Options:
A)24/35
B)17/35
C)8/25
D)6/35
E)1/25
Rationale: This question can also be solved by using 'brute force' - you just have to 'map out' the possibilities.
The nameJohnsonhas 7 letters and the nameJoneshas 5 letters, so there are (7)(5) = 35 possible pairings of letters that can occur.
Of those 35, the pairings that include the SAME letter both times are:
J and J
1st O and O
1st N and N
S and S
2nd O and O
2nd N and N
Total: 6
So the probability that the two randomly selected letters will match is 6/35.
D
Answer: D
Question: the age of man is three time the sum of the age of his two sons. Five years hence, his age will be double of the sum of the ages of his sons. the father’s present age is :
Options:
A)40 year
B)45 year
C)50 year
D)55 year
E)65 year
Rationale: Solution
Let the sum of present ages of the two sons be x years.
Then, father's present age = 3x years.
∴ (3x + 5) = 2 (x + 10) ⇔ 3x + 5 = 2x + 20 ⇔ x = 15.
Hence, father's present age = 45 years. Answer B
Answer: B
Question: In a mixture of 60 liters, the ratio of milk and water is 2:1. What amount of water must be added to make the ratio of milk and water as 1:2?
Options:
A)76 liters
B)16 liters
C)60 liters
D)16 liters
E)86 liters
Rationale: 2:1 --- 60
1:2
2:4
---------------
3
3 ----------- 60
3 ----------- ? => 60 liters
Answer: C
Answer: C
Question: The S.I. on a certain sum of money for 3 years at 8% per annum is half the C.I. on Rs. 4000 for 2 years at 10% per annum. The sum placed on S.I. is?
Options:
A)Rs.1718
B)Rs.1729
C)Rs.1750
D)Rs.1724
E)Rs.1723
Rationale: C.I. = [4000 * (1 + 10/100)2 - 4000]
= (4000 * 11/10 * 11/10 - 4000) = Rs. 840.
Sum = (420 * 100)/(3 * 8) = Rs.1750
Answer:C
Answer: C
Question: Three workers have a productivity ratio of 1 to 2 to 4. All three workers are working on a job for 4 hours. At the beginning of the 5th hour, the slowest worker takes a break. The slowest worker comes back to work at the beginning of the 9th hour and begins working again. The job is done in ten hours. What was the ratio of the work performed by the fastest worker as compared to the slowest?
Options:
A)12 to 1
B)6 to 1
C)5 to 1
D)20 to 3
E)1 to 5
Rationale: The fastest worker who does 4 units of job worked for all 10 hours, so he did 4*10=40 units of job;
The slowest worker who does 1 unit of job worked for only 4+2=6 hours (first 4 hours and last 2 hours), so he did 1*6=6 units of job;
The ratio thus is 40 to 6, or 20 to 3.
Answer: D
Answer: D
Question: In a hostel there were 100 students. To accommodate 10 more students the average is decreased by rupees 5. But total expenditure increased by Rs.400. Find the total expenditure of the hostel now?
Options:
A)A)Rs.5800
B)B)Rs.9900
C)C)Rs.5400
D)D)Rs.5900
E)E)Rs.5430
Rationale: 100x + 400
= 110(x – 5)
x = 95
100 * 95 + 400
= 9900
Answer:B
Answer: B
Question: A person incurs 5% loss by selling a watch for $1140. At what price should the watch be sold to earn 5% profit?
Options:
A)$1260
B)$1200
C)$1150
D)$1320
E)$1290
Rationale: Let the new S.P. = x
then (100-loss%): (1st S.P.) = (100+gain%): (2nd S.P.)
(100-5)/1140 = (100+5)/x
x=105*1140/95 = 1260
new price = $1260
correct option is A
Answer: A
Question: An escalator moves towards the top level at the rate of 15 ft.sec and its length is 200 feet. If a person walks on the moving escalator at the rate of 5 feet per second towards the top level, how much time does he take to cover the entire length.
Options:
A)5sec
B)10sec
C)20sec
D)15sec
E)25sec
Rationale: Explanation :
Time taken to cover the entire length = tot.dist/resultant speed = 200/ (15+5) = 10sec
Answer : B
Answer: B
Question: There are 7 red shoes & 3 green shoes . If two of red shoes are drawn what is the probability of getting red shoes
Options:
A)1/13
B)1/14
C)1/15
D)7/15
E)7/16
Rationale: taking 2 red shoe the probablity is 7C2
from 10 shoes probablity of taking 2 red shoe is 7C2/10C2=7/15
ANSWER:D
Answer: D
Question: A shipment of 230 smartphones contains 84 that are defective. If a customer buys two smartphones at random from the shipment, what is the approximate probability that both phones are defective?
Options:
A)1/250
B)1/84
C)1/11
D)9/68
E)1/3
Rationale: Probability of chosing one defective phone from a lot of 230 which ontains 84 defective phones is = (84/230)
Probability of chosing one defective phone from a lot of 229(we already picked one) which ontains 83(we already picked one) defective phones is = (83/229)
Combined probability of series of events = product of the probabilities = (84/230)*(83/229)
84/230 is close to (23/63) and (83/229)= (29/80)
so answer is (23/63)*(29/80) = (9/68)
So, answer will be D
Answer: D
Question: John and Jane went out for a dinner and they ordered the same dish. Both used a 10% discount coupon. John paid a 15% tip over the original price of the dish, while Jane paid the tip over the discounted price for the coupon. If John paid $0.54 more than Jane, what was the original price of the dish?
Options:
A) 24
B) 34.8
C) 36
D) 42
E) 84
Rationale: The difference between the amounts John paid and Jane paid is the deference between 15% of p and 15% of 0.9p:
0.15p - 0.15*0.9p = 0.54 --> 15p - 13.5p = 54 --> p = 36.
Answer: C.
Answer: C
Question: A man buys an article and sells it at a profit of 20%. If he had bought it at 20% less and sold it for Rs.75 less, he could have gained 25%. What is the cost price?
Options:
A)372
B)375
C)278
D)267
E)288
Rationale: CP1 = 100 SP1 = 120
CP2 = 80 SP2 = 80 * (125/100) = 100
20 ----- 100
75 ----- ? => 375
Answer:B
Answer: B
Question: Mixture A is 25 percent milk, and mixture B is 65 percent milk. If the two are poured together to create a 4-gallon mixture that contains 40 percent milk, approximately how many gallons of mixture A are in the mixture?
Options:
A)1.5
B)1.75
C)2.85
D)2.5
E)3.0
Rationale: (65-40)/(40-25) = Qa/Qb
25/15 = Qa/Qb
5/3 = Qa/Qb
Qa = (5/7) * 4 = 20/7 = 2.85 approx
Answer : C
Answer: C
Question: In a particular course, only two grades are given all semester: the midterm exam, which counts for 25% of the semester grade, and the final exam, which counts for the remainder. Lindsey's semester grade was 88%. If the highest possible score on either exam is 100%, what is the lowest possible score K that Lindsey could have received on her midterm exam?
Options:
A)52%
B)64%
C)72%
D)76%
E)80%
Rationale: If the midterm counts for 25% of the total grade, then the final exam must count for the remaining 75%, meaning that in this weighted average problem the final is weighted 3 times as much as the midterm. Using the weighted average mapping strategy, then, and maximizing her final exam score so that you minimize her midterm score, you have:
100-------------88----------------------------x
And you know that the ratio is 3:1. Since the final exam score of 100 is weighted heavier, then the difference of 12 between 100 and 88 is the1part of the ratio, meaning that 3(12) is the 3 portion. That equals 36, so the midterm score (x) is 36 less than the weighted average of 88. 88 - 36 = 52, sothe correct answer is 52%.
Answer: A
Question: There are 11 dozen mangoes in a box. If there are 16
such boxes, how many mangoes are there in all the
boxes together?
Options:
A)2112
B)3096
C)6192
D)628
E)None
Rationale: Number of mangoes = 11 dozens
= 11 × 12 = 132
∴ Number of mangoes in 16 boxes
= 16 × 132 = 2112
Answer A
Answer: A
Question: The total marks obtained by a student in Mathematics and Physics is 60 and his score in Chemistry is 20 marks more than that in Physics. Find the average marks scored in Mathamatics and Chemistry together.
Options:
A)40
B)26
C)27
D)28
E)22
Rationale: Let the marks obtained by the student in Mathematics, Physics and Chemistry be M, P and C respectively.
Given , M + C = 60 and C - P = 20 M + C / 2 = [(M + P) + (C - P)] / 2 = (60 + 20) / 2 = 40.Answer:a
Answer: A
Question: A shipment of 250 smartphones contains 67 that are defective. If a customer buys two smartphones at random from the shipment, what is the approximate probability that both phones are defective?
Options:
A)1/250
B)1/14
C)1/11
D)1/9
E)1/3
Rationale: Probability of chosing one defective phone from a lot of 250 which ontains 67 defective phones is = (67/250)
Probability of chosing one defective phone from a lot of 249(we already picked one) which ontains 66(we already picked one) defective phones is = (66/249)
Combined probability of series of events = product of the probabilities = (67/250)*(66/249)
67/250 is close to (26/97) and (66/249)= (22/83)
so answer is (26/97)*(22/83) = (1/14)
So, answer will be B
Answer: B
Question: If x+y=24, x-y=40, for integers of x and y, x=?
Options:
A)20
B)23
C)25
D)32
E)42
Rationale: x+y = 24
x-y = 40
2x = 64
x = 32
Answer is D
Answer: D
Question: A man spend 1/5 of his salary on food , 1/10 of his salary on house rent and 3/5 salary on clothes. he still has $14000 left with him. find salary..
Options:
A)$10400
B)$14000
C)$144000
D)$1800
E)$140000
Rationale: [1/(x1 / y1 + x2/y2 + x3/y3)] * Total amount= Balance amount
[1-(1/5 + 1/10 + 3/5)} * total salary= $14000, = [1-9/10] * Total salary = $14000, Total salary = $14000*10 = $140000, correct answer (E)
Answer: E
Question: Sides of a rectangular park are in the ratio 3: 2 and its area is 3750 sq m, the cost of fencing it at 90 ps per meter is?
Options:
A)287
B)369
C)225
D)279
E)361
Rationale: 3x * 2x = 3750 => x = 25
2(75 + 50) = 250 m
250 * 0.9
= Rs.225
Answer:C
Answer: C
Question: A bag contains 50 P, 25 P and 10 P coins in the ratio 5: 9: 4, amounting to Rs. 206. Find the number of coins of each type respectively.
Options:
A)360, 160, 200
B)160, 360, 200
C)200, 360,160
D)200,160,300
E)300,260,100
Rationale: let ratio be x.
Hence no. of coins be 5x ,9x , 4x respectively
Now given total amount = Rs.206
=> (.50)(5x) + (.25)(9x) + (.10)(4x) = 206
we get x = 40
=> No. of 50p coins = 200
=> No. of 25p coins = 360
=> No. of 10p coins = 160
Answer:C
Answer: C
Question: There is a total of 100 marbles in a box, each of which is red, green, blue, or white. If one marble is drawn from the box at random, the probability that it will be white is 1/4 and the probability that it will be green is 1/5. What is the probability that the marble will be either red or blue?
Options:
A)2/3
B)3/5
C)7/10
D)9/20
E)11/20
Rationale: P(red or blue) = 1 - P(white) - P(green) = 20/20 -5/20 - 4/20 = 11/20
The answer is E.
Answer: E
Question: A car is traveling 75 kilometers per hour. How many meters does the car travel in one minute?
Options:
A)1,250 meters / minute
B)1,760 meters / minute
C)1,443 meters / minute
D)1,980 meters / minute
E)1,667 meters / minute
Rationale: Convert hour into minutes ( 1 hour = 60 minutes) and kilometers into meters (1 km = 1000 m) and simplify
75 kilometers per hour = 75 km/hr
= (75 × 1000 meters) / (60 minutes) = 1,250 meters / minute
correct answer A
Answer: A