divelab/Sys2Bench huggingface dataset:
Question: The value of a machine depreciates at the rate of 10% every year. It was purchased 3 years ago. If its present value is Rs. 8748, its purchase price was:
Options:
A)10000
B)12000
C)14000
D)16000
E)18000
Rationale: Explanation:
Purchase Price =Rs[8748 / (1- 10/100)3]=Rs.8748 x 10/9 x10/9 x10/9 = Rs.12000
ANSWER IS B
Answer: B
Question: In how many ways Chief Minister and Minister be elected from a team of 12 members?
Options:
A)128
B)130
C)132
D)143
E)135
Rationale: To do this, if captain is elected first, then we have 12 ways of doing this.
For election of vice-captain, we have only 11 ways left, coz 1 way is already consumed. (Situations like this is called dependent situation. One selection depends upon other selection.)
So, the ans is 12*11 = 132 ways.
C
Answer: C
Question: The average of 7 numbers is 20. If each number be multiplied by 5. Find the average of new set of numbers?
Options:
A)A)100
B)B)122
C)C)120
D)D)125
E)E)145
Rationale: Explanation:
Average of new numbers = 20 * 5 = 100
Answer: Option A
Answer: A
Question: A retailer buys 100 pens at the market price of 36 pens from a wholesaler, if he sells these pens giving a discount of 1%, what is the profit % ?
Options:
A)110
B)175
C)212
D)218
E)220
Rationale: let the market price of each pen be $1
then, Cost Price of 100 pens = $ 36 Selling Price of 100 pens =99% of $100=$ 99
profit %=((63*100)/36) %=175%
Answer B
Answer: B
Question: A searchlight on top of the watchtower makes 2 revolutions per minute. What is the probability that a man appearing near the tower will stay in the dark for at least 10 seconds?
Options:
A)5/6
B)3/4
C)2/3
D)1/2
E)3/5
Rationale: The searchlight completes one revolution every 30 seconds.
The probability that the man's area will be lit up is 10/30=1/3.
The probability that he will stay in the dark is 1-1/3=2/3
The answer is C.
Answer: C
Question: The units digit of (35)^(87) + (3)^(45) is:
Options:
A)2
B)8
C)6
D)9
E)0
Rationale: any power of anything ending in 5 always has a units digit of 5. So the first term has a units digit of 5.
2nd part
3^45 has a units digit of 3
Therefore, the second term has a units digit of 3.
Of course 5 + 3 = 8, so something with a units digit of 5 plus something with a units digit of 3
Answer = B
Answer: B
Question: A light has a rating of 86 watts, it is replaced with a new light that has 18% higher wattage. How many watts does the new light have?
Options:
A)105
B)95
C)80
D)60
E)101
Rationale: Final number = Initial number + 18%(original number) = 86 + 18%(86) = 86 + 15= 101.
Answer E
Answer: E
Question: The area of a square field 3136 sq m, if the length of cost of drawing barbed wire 3 m around the field at the rate of Rs.1.50 per meter. Two gates of 1 m width each are to be left for entrance. What is the total cost?
Options:
A)299
B)277
C)999
D)255
E)245
Rationale: a2 = 3136 => a = 56
56 * 4 * 3 = 672 – 6 = 666 * 1.5
= 999
Answer: C
Answer: C
Question: A theater charges $12 for seats in the orchestra and $8 for seats in the balcony. On a certain night, a total of 370 tickets were sold for a total cost of $3,320. How many more tickets were sold that night for seats in the balcony than for seats in the orchestra?
Options:
A) 90
B) 190
C) 120
D) 130
E) 220
Rationale: Orchestra Seats - a
Balcony Seats - b
a+b = 370
and 12a + 8b = 3320
Solving equations simultaneously (Multiply Equation 1 with 8 and subtract from second equation)
4a = 3320 - 8*370 = 3320 - 2960 = 360
i.e. a = 90
and b = 370-90 = 280
More seats in balcony than orchestra = b-a = 280 - 90 = 190
Answer: option B
Answer: B
Question: A boat running downstream covers a distance of 16 km in 2 hours while for covering the same distance upstream,it takes 4 hour.What is the speed of the boat in still water ?
Options:
A)4 km/hr
B)6 km/hr
C)8 km/hr
D)Data inadequate
E)None of these
Rationale: Solution
Rate downstream =(16/2) kmph = 8 kmph,Rate upstream = (16/4) kmph = 4 kmph.
∴ Speed in still water =1/2(8+4) kmph = 6 kmph. Answer B
Answer: B
Question: The batting average of a particular batsman is 60 runs in 46 innings. If the difference in his highest and lowest score is 190 runs and his average excluding these two innings is 58 runs, find his highest score.
Options:
A)179
B)367
C)269
D)177
E)199
Rationale: Explanation:
Total runs scored by the batsman = 60*46 = 2760 runs
Now excluding the two innings the runs scored = 58*44 = 2552 runs
Hence the runs scored in the two innings = 2760 â€“ 2552 = 208 runs.
Let the highest score be x, hence the lowest score = x â€“ 190
x + (x - 190) = 208
2x = 398
x = 199 runs
ANSWER: E
Answer: E
Question: An article is bought for Rs.600 and sold for Rs.500, find the loss percent?
Options:
A)16 6/3%
B)16 2/8%
C)16 3/3%
D)16 2/3%
E)16 2/6%
Rationale: 600 ---- 100
100 ---- ? => 16 2/3%
Answer: D
Answer: D
Question: A cube of side one meter length is cut into small cubes of side 10 cm each. How many such small cubes can be obtained?
Options:
A)1017
B)1029
C)1000
D)1028
E)1026
Rationale: Along one edge, the number of small cubes that can be cut
= 100/10 = 10
Along each edge 10 cubes can be cut. (Along length, breadth and height). Total number of small cubes that can be cut = 10 * 10 * 10 = 1000
Answer: C
Answer: C
Question: Beginning in Town A, Biker Bob rides his bike 12 miles west, 6 miles north, 4 miles east, and then 12 miles north, to Town B. How far apart are Town A and Town B? (Ignore the curvature of the earth.)
Options:
A)18.97 miles
B)20 miles
C)22 miles
D)23 miles
E)25 miles
Rationale: Using Pythagoras we have one side i,e total distance traveled in north direction = 12+6=18m
other being the base ie distance traveled west- distance traveled eat=12- 6= 6 m
now this third side or the distance between town A and Town B=18^2+ 6^2=sq root 360=18.97 mile
Answer : A
Answer: A
Question: The height of a triangle is decreased by 15% and its base increased by 50%. Its area will
Options:
A)decrease by 12.5%
B)increase by 12.5%
C)decrease by 25%
D)Increase by 27.5%
E)None of these
Rationale: Explanation :
Let the initial height be 100 and the base be 200 units.
âˆ´ Area = 1/2 x 100 x 200 = 10000 sq units
Now, height = 85 units and base = 300 units
âˆ´ New area = 1/2 x 85 x 300 = 12750
âˆ´ Area is increased by (12750 - 10000)/10000 x 100
= 27.5%
Answer : Option D
Answer: D
Question: The X&co having such a sales structure out of their whole sales 70% of the customers are corporate companies out of these 20% of them are related to banking sector and 60% of the corporate companies related to banking sector having their head quarters in USA. If total sales of the company X&co is 100 cr then, what is sales amount of corporate companies related to banking sector having their head quarters in USA?
Options:
A)8.5
B)7.0
C)6.3
D)3.6
E)8.4
Rationale: total amount of sales =100 cr; out of these 70% are corporate companies = 70 cr; out of these 20% are related to banking sector = 14 cr ; 60% of the corporate companies related to banking sector having their head quarters in USA = 8.4 cr.
Answer: E
Question: A cubical block of metal weighs 6 pounds. How much will another cube of the same metal weigh if its sides are twice as long?
Options:
A)48
B)99
C)266
D)28
E)17
Rationale: Explanation:
If you double the sides of a cube, the ratio of the surface areas of the old and new cubes will be 1: 4. The ratio of the volumes of the old and new cubes will be 1: 8.
Weight is proportional to volume. So, If the first weighs 6 pounds, the second weighs 6x8 pounds =48.
Answer: A) 48
Answer: A
Question: Which of the following Equation is NOT equivalent to 25x^2 = y^2 - 25?Which of the following Equation is NOT equivalent to 25x^2 = y^2 - 4?
Options:
A)25x^2 + 4 = y^2
B)75x^2 = 3y^2 - 12
C)5x = y - 5
D)25x^2 = (y + 2)(y - 2)
E)x^2 = (y^2 - 4)/25
Rationale: 1) Take the original equation and try to manipulate it so that it becomes 4 of the 5 answers
2) Take each answer choice and see if you can manipulate it to make it into the original equation.
With Answer D, we have...
5X = Y - 5
If we square both sides, we end up with....
(5X)^2 = (Y-5)^2
(5X)(5X) = (Y-5)(Y-5)
25X^2 = Y^2 - 10Y + 25
This is NOT a match for the original equation, so it's the answer that is NOT equivalent. C
Answer: C
Question: In how many different ways can pennies (1 cent), nickels (5 cents), dimes (10 cents), and quarters (25 cents) be combined for a total of $1.10 (110 cents), if at least one of each type of coin must be included?
Options:
A)36
B)51
C)70
D)87
E)101
Rationale: I. Case I = Four Quarters = this is impossible, because if we already have a dollar in quarters, then we either have to have one dime or nickels & pennies. We can't have all four coins represented if we have four quarters.
II. Case II = Three Quarters (75 cents)
This allows for two or one dime. Three dimes would bring us up to $1.05, and we wouldn't have room for both pennies & nickels.
Subcase 1 = 3Q, 2 D (95 cents)
Here, we could have have
1) two nickles
2) one nickle
(Notice that once the number of Q & D & N are determined, the number of pennies is fixed and doesn't have to be considered.
Subcase 2 = 3Q, 1 D (85 cents)
Here we could have
3) 4 nickles
4) 3 nickles
5) 2 nickles
6) 1 nickle
Case II allows for a total of six cases.
III. Case III = Two Quarters (50 cents)
This allows for 1-5 dimes.
Subcase 1 = 2Q, 5 D = we could have 1 nickle (1 case)
Subcase 2 = 2Q, 4 D = we could have 1-3 nickles (3 cases)
Subcase 3 = 2Q, 3 D = we could have 1-5 nickles (5 cases)
Subcase 4 = 2Q, 2 D = we could have 1-7 nickles (7 cases)
Subcase 5 = 2Q, 1 D = we could have 1-9 nickles (9 cases)
Case III allows for a total of 25 cases
IV. Case IV = One Quarter (25 cents)
This allows for 1-7 dimes
Subcase 1 = 1 Q, 7D = we could have 1-2 nickles (2 cases)
Subcase 2 = 1 Q, 6D = we could have 1-4 nickles (4 cases)
Subcase 3 = 1 Q, 5D = we could have 1-6 nickles (6 cases)
Subcase 4 = 1 Q, 4D = we could have 1-8 nickles (8 cases)
Subcase 5 = 1 Q, 3D = we could have 1-10 nickles (10 cases)
Subcase 6 = 1 Q, 2D = we could have 1-12 nickles (12 cases)
Subcase 7 = 1 Q, 1D = we could have 1-14 nickles (14 cases)
Case IV allows for a total of 56 cases.
There's no other case, because we have to have at least one quarter. The total over the cases equals
Total = 6 + 25 + 56 = 87
ANSWER:D
Answer: D
Question: What comes next?
120, 60, 40, 30, 24, ?
Options:
A)10
B)20
C)25
D)28
E)30
Rationale: Factors of 120 are arranging in descending order.
So, next would be 20
Final series is like : 120, 60, 40, 30, 24, 20
ANSWER:B
Answer: B
Question: In a friendship gang Andrew has 8 gang, in how many ways can he invite one or more of the gang to his house?
Options:
A)230
B)255
C)259
D)265
E)270
Rationale: Andrew can select one or more than one of his 8 gang.
=> Required number of ways = 28 – 1= 255.
B
Answer: B
Question: 2598 Successive discounts of 20% and 15% are equal to a single discount of
Options:
A)30%
B)32%
C)34%
D)35%
E)36%
Rationale: Successive discounts of 20% and 15% are equal to a single discount of 32 %.
As final value after discount is 0.8*0.85 = 0.68 of original value.
so discount is 0.32 of original value. means 32%.
ANSWER:B
Answer: B
Question: The duplicate ratio of 4:5 is?
Options:
A)1:2
B)1:4
C)1:8
D)1:18
E)16:25
Rationale: 4^2: 5^2 = 16:25
ANSWER:E
Answer: E
Question: Seven children — A, B, C, D, E, F, and G — are going to sit in seven chairs in a row. Child A has to sit next to both BG, with these two children immediately adjacent to here on either side. The other four children can sit in any order in any of the remaining seats. How many possible configurations R are there for the children?
Options:
A)240
B)480
C)720
D)1440
E)3600
Rationale: MAGOOSHOFFICIAL SOLUTION:
First, we will consider the restricted elements — children ABG have to be in three seats in a row. How many “three in a row” seats are there in a row of seven seats?
X X X _ _ _ _
_ X X X _ _ _
_ _ X X X _ _
_ _ _ X X X _
_ _ _ _ X X X
There are five different “three in a row” locations for these three children. Now, for any given triplet of seats, we know A has to be in the middle, so the children could be seated B-A-G or G-A-B — just those two orders. This means the total number of configurations for these three children is 5*2 = 10.
Now, consider the non-restricted elements, the other four. Once ABG are seated, the remaining four children can be seated in any order among the remaining four seats — that’s a permutation of the 4 items —- 4P4 = 4! = 24. For any single configuration of ABG, there are 24 ways that the other children could be seated in the remaining seats.
Finally, we’ll combine with the Fundamental Counting Principle. We have 10 ways for the first three, and 24 ways for the remaining four. That’s a total number of configurations R of 24*10 = 240.
Answer = A
Answer: A
Question: Length of a rectangular plot is 20 mtr more than its breadth. If the cost of fencin gthe plot at 26.50 per meter is Rs. 5300, what is the length of the plot in mtr?
Options:
A)46 m
B)60 m
C)58 m
D)78 m
E)80 m
Rationale: Let breadth = x metres.
Then, length = (x + 20) metres.
Perimeter = 5300 m = 200 m.
26.50
2[(x + 20) + x] = 200
2x + 20 = 100
2x = 80
x = 40.
Hence, length = x + 20 = 60 m
B
Answer: B
Question: When running a mile during a recent track meet, Nuria was initially credited with a final time of 4 minutes, 44 seconds. Shortly after her run, officials realized that the timing mechanism malfunctioned. The stopwatch did not begin timing her until 11/25 of a minute after she began to run. If the time was otherwise correct, how long did it actually take Nuria to run the mile?
Options:
A)5 minutes, 17.6 seconds
B)5 minutes, 21.8 seconds
C)5 minutes, 43.56 seconds
D)5 minutes, 10.4 seconds
E)5 minutes, 44.44 seconds
Rationale: One approach:
The watch starts to work after Nuria began his running. It means the time should be greater than credited 4 minutes, 44 seconds. The only number is 5 minutes, 10.4 seconds.
Another approach:
11/25 close to 30 second when added to the 4 minutes, 44 seconds, it means it passes 5 minute.
Answer: D
Answer: D
Question: What number has a 3:4 ratio to the number 400?
Options:
A)130
B)100
C)200
D)300
E)120
Rationale: 3:4 = x: 200
4x = 3*400
x=300
ANSWER:D
Answer: D
Question: My brother is 4 years elder to me. My father was 28 years of age when my sister was born while my mother was 26 years of age when I was born. If my sister was 5 years of age of when my brother was born, then, what was the age of my father and mother respectively when my brother was born?
Options:
A)32 yrs, 23 yrs
B)32 yrs, 29 yrs
C)35 yrs, 29 yrs
D)35 yrs, 22 yrs
E)none
Rationale: Sol.
Clearly, my brother was born 5 years before I was born and 4 years after my sister was born.
So, father's age when brother was born = (28 + 4) = 32 years.
mother's age when was born = (26 - 4) years = 22 years.
Answer D
Answer: D
Question: Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 9 hours and 36 hours respectively. The ratio of their speeds is?
Options:
A)4:5
B)4:3
C)4:4
D)4:9
E)6:3
Rationale: Let us name the trains A and B.
Then, (A's speed) : (B's speed)
= √b : √a = √36 : √9 = 6:3
Answer:E
Answer: E
Question: AMOUNT OF BACTERIA PRESENT
Time Amount
1:00 P.M. 12.0 grams
4:00 P.M. x grams
7:00 P.M. 16.4 grams
Data for a certain biology experiment are given in the table above. If the amount of bacteria present increased by the same fraction during each of the two 3-hour periods shown, how many grams of bacteria were present at 4:00 P.M.?
Options:
A)12.0
B)14.0
C)14.2
D)12.3
E)14.4
Rationale: The question says that bacteria increased by same fraction, not by same amount in 2 intervals of 3 hours.
Let X represent the amount of bacteria present at 4:00 PM. Since the fractional increase must remain constant from 1 to 4pm as it is from 4pm to 7pm:
Fractional increase from 1 PM to 4 PM = X / 12.0
Fractional increase from 4 PM to 7 PM = 16.4 / X
X \ 12 = 16.4 \ X
X^2 = 16.4 * 12
X = 14
answer : B
Answer: B
Question: The length of a rectangle is halved while its width is also halved. What is the % change in area?
Options:
A)25%
B)30%
C)50%
D)65%
E)75%
Rationale: The original area is L*W
The new area is 0.5L*0.5W = 0.25*L*W = L*W - 0.75*L*W
The area decreased by 75%.
The answer is E.
Answer: E
Question: In a rare coin collection, all coins are either pure gold or pure silver, and there is initially one gold coin for every three silver coins. With the addition of 10 more gold coins to the collection, the ratio of gold coins to silver coins is 1 to 2. Based on this information, how many total coins are there now in this collection (after the acquisition)?
Options:
A)40
B)50
C)60
D)80
E)90
Rationale: Let's call g = # of gold coins and s = # of silver coins
Initially 3g = s and after the acquisition 2(g+10) = s
Let's solve the simultaneous equations by subtracting the second expression form the first expression: 3g-2g+20 = 0, yields g = 20.
After the acquisition we have 30 gold coins and double that in silver coins (60). A total of 90 coins.
ANSWER:E
Answer: E
Question: Two trains travelling in the same direction at 50.8 and 14.8 kmph completely pass off another in 45 sec.. If the length of the first train is 112 m, what is the length of the second train?
Options:
A)338 m
B)287 m
C)450 m
D)383 m
E)833 m
Rationale: RS = 50.8 â€“ 14.8= 36* 5/18 =10 mps
T = 45 sec
D = 10* 45= 450 m
112
--------
338 m
Answer: A
Answer: A
Question: A survey of n people in the town of Eros found that 50% of them preferred Brand A. Another survey of 150 people in the town of Angie found that 60% preferred Brand A. In total, 55% of all the people surveyed together preferred Brand A. What is the total number of people surveyed?
Options:
A)50
B)100
C)150
D)300
E)250
Rationale: It is simply a weighted average question. Since the given average of 50% and 60% is 55% (right in the middle), it means the number of people surveyed in Eros (n) is same as the number of people surveyed in Angie.
So n = 150
Total = 150 + 150 = 300
Answer (D)
Answer: D
Question: What is the are of an equilateral triangle of side 16 cm?
Options:
A)63√6 cm2
B)64√4 cm2
C)64√3 cm2
D)62√3 cm2
E)14√3 cm2
Rationale: Area of an equilateral triangle
= √3/4 S2
If S = 16, Area of triangle
= √3/4 * 16 * 16
= 64√3 cm2;
Answer:D
Answer: D
Question: The length of a train and that of a platform are equal. If with a speed of 90 k/hr, the train crosses the platform in one minute, then the length of the train (in meters) is?
Options:
A)288
B)277
C)208
D)750
E)287
Rationale: Speed = [90 * 5/18] m/sec = 25 m/sec; Time = 1 min. = 60 sec.
Let the length of the train and that of the platform be x meters.
Then, 2x/60 = 25 è x = 25 * 60 / 2 = 750
Answer:D
Answer: D
Question: A train speeds past a pole in 15 seconds and speeds past a platform 100 meters long in 25 seconds. Its length in meters is :
Options:
A)60m
B)70m
C)100m
D)120m
E)150m
Rationale: Let the length of the train be X metres and its speed be Y metres/sec.
Then X/Y=15
Y= X/15
X+100/25
Now,(x+100) /25
=X/15
X=150m
ANSWER : E
Answer: E
Question: If the sides of a cube are in the ratio 4:3. What is the ratio of their diagonals?
Options:
A)4:3
B)4:0
C)3:3
D)4:6
E)4:7
Rationale: a1:a2 = 4:3
d1:d2 = 4:3
Answer: A
Answer: A
Question: A family consists of grandparents, parents and three grand children. The average age of the grandparents is 67 years, that of the parents is 40 years and that of the grandchildren is 6 years. What is the average age of the family?
Options:
A)28 4â„7 years
B)31 5â„7 years
C)33 1â„7 years
D)27 1â„2 years
E)None of these
Rationale: Required average = (67Ã—2+40Ã—2+6Ã—3/2+2+3)
=232/7
= 33 1â„7 years
Answer C
Answer: C
Question: 80% of the population of a village is 64000. The total population of the village is?
Options:
A)26799
B)24000
C)80000
D)29973
E)12312
Rationale: X * (80/100) = 64000
X = 800 * 100
X = 80000
Answer: C
Answer: C
Question: In the xy-plane, a line has slope 5 and x-intercept 3. What is the y-intercept of the line?
Options:
A)-15
B)-3
C)0
D)3
E)9
Rationale: Let the line be represented by a general equation y=mx+b, where m = slope (5) and b=y intercept. We are also given the value of x-intercept 3.
Theory : y intercept represents the point on the line where the x=0, and x intercept represents the point on the line where the y=0.
Putting these values in the equation : 0 = 5*3 + b => b = -15. Hence A.
Answer: A
Question: The greatest number by which the product of four consecutive multiples of 3 is always divisible is
Options:
A)54
B)76
C)152
D)162
E)None of these
Rationale: Solution
Required number	= Product of first three multiplies of 3
= (3 Ã— 6 Ã— 9x12)= 1944.
Answer E
Answer: E
Question: What is the greatest prime factor of 1+2+3+。。。+60?
Options:
A)59
B)61
C)31
D)37
E)41
Rationale: find the sum from direct formula = n(n+1)/2 = 60(60+1)/2 = 30*61...
61 is a PRIME number, so ans is 61..
B is the answer
Answer: B
Question: Three dice are rolled. The number of possible outcomes in which at least one dice shows 5 is
Options:
A)215
B)36
C)125
D)91
E)None of these
Rationale: Required number of possible outcomes
= Total number of possible outcomes – Number of possible outcomes in which 5 does not appear on any dice. (hence 5 possibilities in each throw)
= 6(3) – 5(3) = 216 – 125 = 91
Answer D
Answer: D
Question: S is the set of all fractions defined by the formula n/(n + 1), where n is a positive integer less than 20. What is the product V of all the fractions that are in S?
Options:
A)1) 1/20
B)2) 1/21
C)3) 1/2
D)4) 19/40
E)5) 19/20
Rationale: 1/2 * 2/3 * 3/4 * ... 19/20
= 1/20
Answer - A
Answer: A
Question: A trader has 50 kg of pulses, part of which he sells at 14% profit and rest at 6% loss. On the whole his loss is 4%. How much quantity is sold at 14% profit and that at 6% loss?
Options:
A)5 kg, 45 kg
B)15 kg, 35 kg
C)10kg, 40 kg
D)None of these
E)Cannot be determined
Rationale: Solution:
ratio of quantity sold at 14% profit and 6% loss,
= 2:18 = 1:9
Hence, pulses sold at 14% profit,
= (50*1)/10 = 5 kg
At 6% Wheat sold at loss = 45 kg.
Answer: Option A
Answer: A
Question: A,B and C can do a piece of work in 6,8 and 12 days respectively. In how many days would all of them complete the same job together?
Options:
A)5 2/3 days.
B)3 2/3 days.
C)2 2/3 days.
D)4 2/3 days.
E)1 2/3 days.
Rationale: Explanation:
A,B and C can do the work in 6,8 and 12 days respectively. Therefore,
part done by A in 1 day =1/6
part done by B in 1 day = 1/8
part done by C in 1 day = 1/12
part done by A,B and C in 1 day = 1/6+1/8+1/12
=9/24
Net job can be done by A,B,C together in 1 day =24/9 =2 2/3 days.
Answer: Option C
Answer: C
Question: A football team plays games only against the other five teams in its league and always in the following order: Smith, Jones, Glen, Fader, and Gary . If the team’s final game of the season is against Fader, which of the following could be the number of games in the team’s schedule?
Options:
A)18
B)52
C)24
D)72
E)81
Rationale: IMO 'C' is the answer.
Matches will be in multiples of 5x+4. The answer that satisfies this condition is C
Answer: C
Question: If a monkey can climb 6 meter & slip down 3 meter in alternate minutes, than how much time can be taken by the monkey to climb up to a height of 60 meter.
Options:
A)36 min
B)37 min
C)38 min
D)39 min
E)32 min
Rationale: In 1st min it climb 6m and in 2nd min it slips 3m,
so it final displacement is 3m in 2min.
now for 51m it has taken 34 min.
in 35 min it goes to 57m.
in 36 min come down to 54 m.
in 37 min it goes to 60
ANSWER:B
Answer: B
Question: Kiran travels from A to B by car and returns from B to A by cycle in 7 hours. If he travels both ways by car he saves 3 hours. What is the time taken to cover both ways by cycle?
Options:
A)10 hours
B)17 hours
C)19 hours
D)16 hours
E)27 hours
Rationale: Let the time taken to cover from A to B in car and cycle be x hours and y hours respectively.
x + y = 7 --- (1) ; 2x = 4 --- (2)
solving both the equations, we get y = 5
So, time taken to cover both ways by cycle = 2y hours = 10 hours.
Answer: A
Answer: A