divelab/Sys2Bench huggingface dataset:
Question: In Town P, 70 percent of the population are employed, and 42 percent of the population are employed males. What percent of the employed people in Town P are females?
Options:
A)25%
B)30%
C)35%
D)40%
E)45%
Rationale: The percent of the population who are employed females is 70-42 = 28%
The percent of employed people who are female is 28% / 70% = 40%.
The answer is D.
Answer: D
Question: The ratio of boarders to day scholars at a school is 7 to 16. However, after a few new students join the initial 560 boarders, the ratio changed to 1 to 2, respectively. If no boarders became day scholars and vice versa, and no students left the school, how many boarders joined the school?
Options:
A)48
B)64
C)70
D)80
E)84
Rationale: Let day scholars be DS and boarders be B
Given B/DS = 7/16 ---> eq1
Initially B = 560 and x be new boarders joined
Then from eq1 , we get DS = 16/7*560 = 1280
Now , new ration is 560+x / DS = 1/2
560+x / 1280 = 1/2 => 1120+2x = 1280 => 2x = 160 => x = 80
ANS option D
Answer: D
Question: The value of x + x(xx) when x = 3
Options:
A)A)30
B)B) 36
C)C) 38
D)D) 36
E)E) 64
Rationale: x + x(xx)
Put the value of x = 3 in the above expression we get,
3 + 3(33)
= 3 + 3(3 Ã— 3)
= 3 + 3(9)
= 3 + 27
= 30 The answer is (A)
Answer: A
Question: On average, Machine A will produce a completed item once every 2 minutes, and Machine B will produce a completed item once every nine minutes. The number of items Machine A produces in a 24-hour period is approximately what percent greater than the number of items Machine B would produce in that same period?
Options:
A)125%
B)325%
C)350%
D)250%
E)470%
Rationale: Machine A: 1 item in 2 minutes --> 1/2 items in 1 minute;
Machine B: 1 item in 9 minutes --> 1/9 items in 1 minute.
In the same time period, Machine A produces (1/2-1/9)/(1/9)*100=~350% more items than machine B.
Answer: C.
Answer: C
Question: A restaurant meal cost $39.50 and there was no tax. If the tip was more than 10 percent but less than 15 percent of the cost of the meal, then the total amount paid must have been between
Options:
A) $44 and $46
B) $39 and $41
C) $38 and $40
D) $37 and $39
E) $36 and $37
Rationale: The total amount for the meal was between 39.5*1.1=43.45 and 39.5*1.15=45.425. Only option which covers all possible values of the meal is A.
Answer: A.
Answer: A
Question: What number is 76 more than one-fourth of itself?
Options:
A)101
B)225
C)304
D)324
E)336
Rationale: 1/4x+76= x
That means 76=3/4x
x= (76*4)/3= 304/3=101
A is the answer
Answer: A
Question: There are 3 persons Sudhir, Arvind, and Gauri. Sudhir lent cars to Arvind and Gauri as many as they had already. After some time Arvind gave as many cars to Sudhir and Gauri as many as they have. After sometime Gauri did the same thing. At the end of this transaction each one of them had 24. Find the cars each originally had.
Options:
A)Sudhir had 34 cars, Arvind had 21 cars and Gauri had 12 cars.
B)Sudhir had 38 cars, Arvind had 21 cars and Gauri had 12 cars.
C)Sudhir had 39 cars, Arvind had 21 cars and Gauri had 12 cars.
D)Sudhir had 32cars, Arvind had 21 cars and Gauri had 12 cars.
E)Sudhir had 36 cars, Arvind had 21 cars and Gauri had 12 cars.
Rationale: Sudhir Arvind Gauri
Finally 24 24 24
Before Gauri’s transaction 12 12 48
Before Arvind’s transaction 6 42 24
Before Sudhir’ s transaction 39 21 12
Answer:C
Answer: C
Question: 33 1/3% OF 390?
Options:
A)80
B)90
C)110
D)120
E)130
Rationale: 33 1/3 % = 1/3
1/3 × 390 = 130
E)
Answer: E
Question: 4 people are sitting in a 4 seat row watching a football game. At halftime they all get up. When they return, they each randomly sit down on one of the 6 chairs. What is the likelihood that none of the 4 end up sitting in the same chair that they sat in during the first half?
Options:
A)3/24
B)9/24
C)15/24
D)18/24
E)3/4
Rationale: Originally seated A B C D
now when after they get up and when they sit back again .
1st- A has option to sit on 3 seats ( apart from his previous seat . thus he now sits on B's seat.)
2nd- Similarly B has option to sit on 3 seats ( because A has already occupied B's previous seat, thus B sits on a's seat.)
3rd- Now C has only 1 option to sit on D's seat . and similarly D also has one option to sit on C's seat.)
hence total favourable outcomes 3*3*2*1*1*1=18
and total possible outcomes =4!=24
probability of the favourable outcome= 3/4. E
Answer: E
Question: Cindy has her eye on a sundress but thinks it is too expensive. It goes on sale for 15% less than the original price. Before Cindy can buy the dress, however, the store raises the new price by 25%. If the dress cost $71.4 after it went on sale for 15% off, what is the difference between the original price and the final price?
Options:
A)$5.625
B)$1.00
C)$3.40
D)$5.25
E)$6.80
Rationale: 0.85*{Original Price} = $71.4 --> {Original Price} = $84.
{Final Price} = $71.4*1.25 = $89.25.
The difference = $89.25 - $84 = $5.25
Answer: D.
Answer: D
Question: In how many ways can 2 men & 4 women can be made from a gang of 4 men & 7 women ?
Options:
A)100
B)41
C)45
D)78
E)89
Rationale: Explanation:
4C2 * 7C4 = 41
B
Answer: B
Question: Mr. Thomas invested an amount of 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be 3508, what was the amount invested in Scheme B?
Options:
A)4800
B)6500
C)2280
D)3400
E)3490
Rationale: B
6500
Let the sum invested in Scheme A be x and that in Scheme B be (13900 - x).
Then, (x x 14 x 2)/100 + ((13900 - x) x 11 x 2)/100 = 3508
28x - 22x = 350800 - (13900 x 22)
6x = 45000
x = 7500.
So, sum invested in Scheme B = (13900 - 7500) = 6400.
Answer: B
Question: Joe has a bunch of change in his pocket? Which of the following choices is the correct amount of change?
Options:
A)75 cents
B)85 cents
C)29 cents
D)39 cents
E)51 cents
Rationale: 29 is the only prime number, so answer C is the correct answer.
Answer: C
Question: How much interest can a person get on Rs. 8600 at 17.5% p.a. simple interest for a period of two years and six months?
Options:
A)3587.58
B)3587.59
C)3587.5
D)3762.5
E)3587.56
Rationale: I = (8600 * 2.5 * 17.5)/100 = (8600 * 5 * 35)/(100 * 2 * 2) = Rs. 3762.50.Answer: D
Answer: D
Question: A shirt goes on sale for 80% of its original price. One week later, the sale price is marked down 20%. The final price is what percent of the original price?
Options:
A)72%
B)70%
C)52%
D)64%
E)28%
Rationale: Just assume original price is 100.
Sale price = 80
Then it is marked down by 20% = 80-16=64.
Hence it is 64% od the original price. Hence answer is D.
Answer: D
Question: Excluding stoppages, the speed of a train is 54 kmph and including stoppages it is 36 kmph. Of how many minutes does the train stop per hour?
Options:
A)20
B)17
C)15
D)18
E)12
Rationale: T = 18/54 * 60
= 20
Answer: A
Answer: A
Question: Insert the missing number. 12, 25, 49, 99, 197, 395, (...)
Options:
A)789
B)1579
C)12
D)23
E)28
Rationale: Each number is twice the previous one with 1 added or subtracted alternatively. Missing Number is 789
Answer is A
Answer: A
Question: If 3 persons can do 3 times of a particular work in 3 days, then, 7 persons can do 7 times of that work in
Options:
A)6 days
B)2 days
C)3 days
D)5 days
E)4 days
Rationale: That is, 1 person can do one time of the work in 3 days.
Therefore, 7 persons can do 7 times work in the same 3 days itself.
C
Answer: C
Question: If Rs. 510 be divided among A, B, C in such a way that A gets 2/3 of what B gets and B gets 1/4 of what C gets, then their shares are respectively?
Options:
A)Rs.300
B)Rs.360
C)Rs.389
D)Rs.368
E)Rs.323
Rationale: (A = 2/3 B and B = 1/4 C) = A/B = 2/3 and B/C = 1/4
A:B = 2:3 and B:C = 1:4 = 3:12
A:B:C = 2:3:12
A;s share = 510 * 2/17 = Rs. 60
B's share = 510 * 3/17 = Rs. 90
C's share = 510 * 12/17 =Rs.360.
Answer:B
Answer: B
Question: A money lender finds that due to a fall in the annual rate of interest from 8% to 7 3/4 % his yearly income diminishes by Rs. 63.50, his capital is?
Options:
A)24,602
B)28,888
C)24,600
D)24,628
E)24,400
Rationale: Let the capital be Rs. x. Then,
(x * 8 * 1)/100 - (x * 31/4 * 1/100) = 63.50
32x - 31x = 6350 * 4
x = 25,400.
Answer: E
Answer: E
Question: When running a mile during a recent track meet, Nuria was initially credited with a final time of 6 minutes, 44 seconds. Shortly after her run, officials realized that the timing mechanism malfunctioned. The stopwatch did not begin timing her until 11/25 of a minute after she began to run. If the time was otherwise correct, how long did it actually take Nuria to run the mile?
Options:
A)5 minutes, 17.6 seconds
B)5 minutes, 21.8 seconds
C)5 minutes, 43.56 seconds
D)5 minutes, 44.44 seconds
E)7 minutes, 10.4 seconds
Rationale: One approach:
The watch starts to work after Nuria began his running. It means the time should be greater than credited 6 minutes, 44 seconds. The only number is 7 minutes, 10.4 seconds.
Another approach:
11/25 close to 30 second when added to the 6 minutes, 44 seconds, it means it passes 7 minute.
Answer: E
Answer: E
Question: A cycle is bought for Rs.900 and sold for Rs.1440, find the gain percent?
Options:
A)39%
B)20%
C)23%
D)74%
E)60%
Rationale: 900 ---- 540
100 ---- ? =>
60%
Answer:E
Answer: E
Question: IF A fair coin with sides marked heads and tails is to be tossed eight times. What is the probability that the coin will land tails side up more than five times?
Options:
A)A)37/256
B)B)56/256
C)C)65/256
D)D)70/256
E)E)81/256
Rationale: More than 5 times tails = 6times +7times+8times = 8C6 + 8C7 + 8C8 = 37
- - - - - - - -
2 2 2 2 2 2 2 2
2^8 times total events and 37 events where tails side up .
So probability = 37/2^8 = 37/256 (Answer A)
Answer: A
Question: If rupee one produces rupees nine over a period of 40 years, find the rate of simple interest?
Options:
A)22 1/6 %
B)22 8/2 %
C)25 1/2 %
D)22 1/2 %
E)22 5/2 %
Rationale: 9 = (1*40*R)/100
R = 22 1/2 %
Answer: D
Answer: D
Question: If a = (1/2)b and c = 5a, then which of the following represents the average (arithmetic mean) of a, b, and c, in terms of a ?
Options:
A) (8/3)a
B) (11/3)a
C) 4a
D) (4 1/7)a
E) (7 1/4)a
Rationale: Official Answer: A
The average of the three variables isa + b + c/3. However, we need to solve in terms of a, which means we must convert b and c into something in terms of a.
Were told that a =1/2b, which is equivalent to b = 2a. We can plug that in and simplify the average to:a + 2a + c/3
We also know that c = 5a, which we can plug directly into the average expression:
a + 2a + 5a/3
= 8a/3 = (8/3)a, choiceA.
Answer: A
Question: In how many ways can 4 arts and 5 science students be arranged in a row so that the arts and the science students are placed alternately?
Options:
A)2880
B)1850
C)3260
D)5200
E)360*120
Rationale: The four art students can be arranged in those 4 A-slots in 4! = 24 ways.
The five science students can be arranged in those 5 S-slots in 5! =120 ways.
Total arrangements = 24 *120 = 2880
Answer =(A)
Answer: A
Question: In a recent survey 40% houses contained two or more people. Of those houses containing only one person 25% were having only a male. What is the percentage of all houses which contain exactly one female and no males?
Options:
A)75
B)40
C)15
D)Cannot be determined
E)None of these
Rationale: Houses containing only one person = 100 – 40 = 60%
Houses containing only a male = 60 × 25⁄100 = 15%
∴ Houses containing only one female = 60 – 15 = 45%
Answer E
Answer: E
Question: What is the next number of the following sequence
1,3,4,5,6,7,1,9,16,25,36,...
Options:
A)14
B)15
C)16
D)17
E)49
Rationale: (1, 3 ,4, 5, 6, 7) (1, 9, 16, 25, 36, x)
square of 1st group gives 2nd group
1^2 = 1
3^2 = 9
4^2 = 16
5^2 =25
6^2 =36
7^2 = 49
ANSWER:E
Answer: E
Question: A certain list consists of 21 different numbers. If n is in the list and n is 6 times the average (arithmetic mean) of the other 20 numbers in the list, then n is what fraction of the sum of the 21 numbers in the list?
Options:
A)1/20
B)1/6
C)1/5
D)3/13
E)5/21
Rationale: series : a1, a2....a20,n
sum of a1+a2+...+a20 = 20*x (x = average)
so, n = 6*x
Hence, a1+a2+..+a20+n = 26x
So, the fraction asked = 6x/26x = 6/26=3/13
D
Answer: D
Question: S = { 1,2,3,5,6}
T = { 2,3,6,7 }
what is the probability that x chosen from S and y chosen from T will result x*y = even
Options:
A)2/7
B)3/8
C)7/10
D)10/7
E)3/8
Rationale: p: the probability that x*y is even, then p=1-p(x*y is odd)
p(x*y odd)=p(x odd)*p(y odd)=3/5*2/4=3/10
And p=1-3/10=7/10.
Option: C
Answer: C
Question: What percentage of numbers from 1 to 70 have 1 or 9 in the unit's digit?
Options:
A)1
B)14
C)20
D)21
E)30
Rationale: Clearly, the numbers which have 1 or 9 in the unit's digit, have squares that end in the digit 1. Such numbers from 1 to 70 are 1, 9, 11, 19, 21, 29, 31, 39, 41, 49, 51, 59, 61, 69.
Number of such number =14
Required percentage =(14x 100)/70% = 20%.
Answer :C
Answer: C
Question: Three different containers contain 496 litres, 403 litres and 713 litres of mixture of milk and water respectively. What is the biggest measure can measure all the different quantities exactly ?
Options:
A)29 litres
B)31 litres
C)35 litres
D)19 litres
E)26 litres
Rationale: M1 = 496 litres
M2 = 403 litres
M3 = 713 litres
Required measurement = H.C.F. of M1,M2,M3 = 31 litres
Answer is B
Answer: B
Question: A train running at the speed of 60 km/hr crosses a pole in 15 seconds. Find the length of the train?
Options:
A)250 meter
B)876 meter
C)167 meter
D)719 meter
E)169 meter
Rationale: Speed = 60*(5/18) m/sec = 50/3 m/sec
Length of Train (Distance) = Speed * Time
(50/3) * 15
= 250 meter
Answer: A
Answer: A
Question: In a race with 30 runners where 4 trophies will be given to the top 6 runners (the trophies are distinct: first place, second place, etc), how many ways can this be done?
Options:
A)8^8 ways
B)8^9 ways
C)6^4 ways
D)8^7 ways
E)8^6 ways
Rationale: 6 people can be prized with 4 distinct prizes in 6^4 ways
ANSWER:C
Answer: C
Question: A student read 40 pages per day on average in a 10 days period. How many pages must the student read on the next day to increase the average to 45 pages per day?
Options:
A)10
B)25
C)45
D)55
E)95
Rationale: Solution
Average of 11 days = 45 .
âˆ´ Required average= (11x45)-(10x40)
= 495- 400
= 95.
Answer E
Answer: E
Question: If the area of a square with sides of length 3 centimeters is equal to the area of a rectangle with a width of 3 centimeters, what is the length of the rectangle, in centimeters?
Options:
A)3
B)8
C)12
D)16
E)18
Rationale: Let length of rectangle = L
3^2 = L*3
=> L = 9/3 = 3
Answer A
Answer: A
Question: A certain league has three divisions. The respective divisions had 8, 10, and 11 teams qualify for the playoffs. Each division held its own double-elimination tournament -- where a team is eliminated from the tournament upon losing two games -- in order to determine its champion. The four division champions then played in a single-elimination tournament -- where a team is eliminated upon losing one game -- in order to determine the overall league champion. Assuming that there were no ties and no forfeits, what is the maximum number of games that could have been played in order to determine the overall league champion?
Options:
A) 51
B) 52
C) 54
D) 56
E) 57
Rationale: Overall, there can be 57 minuses. Tus, it is E.
Answer: E
Question: Some times small town drivers can be very rude. One taxi driver I had the occasion to travel with was particularly lacking in courtesy, and so I asked for his number.
The driver gave me a sardonical smile and said. 'Well, if you divide my number by 2, 3, 4, 5 or 6 you will find there is always 1 remaining. But if you divide it by 11 there is no remainder. Do you want to know something more? There is no other cabby in this town with a lower number than---who can say the same.,' and he drove off, while I stood there completely baffled.
What was the man's number?
Options:
A)121
B)143
C)165
D)133
E)117
Rationale: A
The driver's number was 121.
Answer: A
Question: If a tap could fill entire tank in 18 hrs due to leakage, then in how much time
tank can be emptied by leakage if tap can fill entire tank in 14 hrs without leakage
Options:
A)12hrs
B)63hrs
C)36hrs
D)48hrs
E)52hrs
Rationale: time take to fill[withleakage] =18hrs so workdone in 1hr=1/18
time tkae to fill[without leakage]=14hrs so workdone in 1hr=1/14
if u subtract both u'll get time taken by leakage to empty...
1/18-1/14=2/126 = 1/63 so 63hrs
ANSWER:B
Answer: B
Question: What will come in place of the x in the following Number series? 11, 14, 19, 22, 27, 30,35,38 x
Options:
A)23
B)26
C)36
D)35
E)43
Rationale: (E)
The pattern is + 3, + 5, + 3, + 5, …………
So the missing term is = 38 + 5 = 43.
Answer: E
Question: A camera lens filter kit containing 5 filters sells for $67.50. If the filters are purchased individually, 2 of them are priced at $7.45 each, 2 at $10.05 each, 1 at $14.50. The amount saved by purchasing the kit is what percent of the total price of the 5 filters purchased individually?
Options:
A)25.66%
B)26.66%
C)27.66%
D)28.66%
E)29.66%
Rationale: Cost of kit = $67.50
If filters are purchased individually - $7.45*2 + $10.05*2 + $14.50 = $49.50
Amount saved = $67.50 - $49.50 = $18
Required %age = ($18/$67.50)*100 = 26.66%
So, the correct answer is B.
Answer: B
Question: The equation (M )/63 = (p )/21 relates two temperature scales, where M is the number of degrees on one scale and P is the number of degrees on the other scale. Which of the following equations can be used to convert temperatures from the P scale to the M scale?
Options:
A)P
B)2P
C)4P
D)3P
E)7P
Rationale: M/63 =(P)/21
M = (P)*63/21
=(P)*3 =3P
D
Answer: D
Question: what is the unit digit in [(6273)^1793x(625)^317x(341)^491]?
Options:
A)0
B)2
C)3
D)5
E)None of them
Rationale: Unit digit in (6374)^1793=Unit digit in (4)^1793
=Unit digit in [(4^2)^896 x 4]
=Unit digit in (6x4)=4
Unit digit in (625)^317=Unit digit in (5)^317=5
Unit digit in (341)^491=Unit digit in (1)^491=1
Required digit = Unit digit in (4x5x1)=0
Answer is 0
Answer: A
Question: A and B start a business with Rs.6000 and Rs.8000 respectively. Hoe should they share their profits at the end of one year?
Options:
A)1:2
B)3:4
C)2:5
D)3:7
E)2:1
Rationale: They should share the profits in the ratio of their investments.
The ratio of the investments made by A and B =
6000 : 8000 => 3:4
ANSWER:B
Answer: B
Question: Andrew has a certain number of coins in his pocket. He has three times as many dimes as quarters and six times as many nickels as dimes. A nickel is worth $0.05, a dime is worth $0.10 and a quarter is worth $0.5. If he has a total of $10.15, then which of the following represents the number of dimes in Andrew’s pocket?
Options:
A)9
B)10
C)16
D)20
E)18
Rationale: E.
Let number of quarters be q. Therefore , dimes are 3q and nickels are 18q.
Total value = 18q(.05) + 3q(0.1) + .5q =1.7q
Given total value = 10.15
therefore, 1.7q=10.15 or q=6
Number of dimes = 3q or 18
Answer : E
Answer: E
Question: A sum was put at simple interest at certain rate for 3 years. Had it been put at 1% higher rate it would have fetched Rs. 66 more. The sum is: A. Rs. 2,400 B. Rs. 2,100 C. Rs. 2,200 D.Rs. 2,480
Options:
A)2000
B)2100
C)2200
D)2300
E)2400
Rationale: 1 percent for 3 years= 66
1 percent for 1 year = 22
=> 100 percent = 2200
ANSWER:C
Answer: C
Question: A property decreases in value every year at the rate of 6 1/4% of its value at the beginning of the year its value at the end of 3 years was Rs.21093. Find its value at the beginning of the first year?
Options:
A)25600.24
B)25600.27
C)25600.28
D)25600.21
E)25600.29
Rationale: 6 1/4% = 1/16
x *15/16 * 15/16 * 15/16 = 21093
x = 25600.24
Answer:A
Answer: A
Question: When working alone, painter W can paint a room in 2 hours, and working alone, painter X can paint the same room in e hours. When the two painters work together and independently, they can paint the room in 3/4 of an hour. What is the value of e?
Options:
A)3/4
B)1[1/5]
C)1[2/5]
D)1[3/4]
E)2
Rationale: Rate*Time=Work
Let Painter W's rate be W and Painter X's rate be X
R*T = Work
W * 2 = 1 (If the work done is same throughout the question then the work done can be taken as 1) => W = 1/2
X * e = 1 => X = 1/e
When they both work together then their rates get added up
Combined Rate = (W+X)
R*T = Work
(W+X) * 3/4 = 1
=> W+X = 4/3
=> 1/2 + 1/e = 4/3
=> 1/e = (8-3)/6 = 5/6
=> e = 6/5 = 1[1/5]
Answer B
Answer: B
Question: A new apartment complex purchased 60 toilets and 20 shower heads. If the price of a toilet is three times the price of a shower head, what percent of the total cost was the cost of all the shower heads?
Options:
A)13
B)297
C)26
D)19
E)10
Rationale: Explanation:
Let the cost of shower head is x. Then the cost of the toilet = 3x.
Total cost of 60 toilets and 20 shower heads = 60 × 3x + 20 × x = 200x
So shower heads cost as a percentage of total cost = 20x20x20x20x × 100 = 10%
Answer:E
Answer: E
Question: The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is:
Options:
A)28
B)32
C)40
D)53
E)54
Rationale: Let the numbers be 2x and 3x.
Then, their L.C.M. = 6x.
So, 6x = 48 or x = 8.
The numbers are 16 and 24.
Hence, required sum = (16 + 24) = 40.
Answer: Option C
Answer: C
Question: In a division sum, the divisor is ten times the quotient and five times the remainder. If the remainder is 48, the dividend is?
Options:
A)5808
B)5825
C)5830
D)5835
E)5836
Rationale: Divisor = (5 * 48) = 240
= 10 * Quotient = Divisor
=> Quotient = 240/10 = 24
Dividend = (Divisor * Quotient) + Remainder
Dividend = (240 * 24) + 48 = 5808
A
Answer: A
Question: Point (e,f) is on the circle represented by e^2+f^2=10, and e, f are integers. How many such points are possible?
Options:
A)0
B)2
C)4
D)6
E)8
Rationale: e^2+f^2=10 and e, f are integers means that 10 is the sum of two perfect squares.
10 is the sum of only one pair of perfect squares 1 and 9.
So, there can be 8 such points, 4 in each quadrant:
(1, 3);
(1, -3);
(-1, 3);
(-1, -3);
(3, 1);
(3, -1);
(-3, 1);
(-3, -1).
Answer: E.
Answer: E
Question: In a graduating class, 40 percent of the students are male. In this class, 40 percent of the male students and 20 percent of the female students are 25 years old or older. If one student in the class is randomly selected, approximately what is the probability that he or she will be less than 25 years old?
Options:
A)0.9
B)0.72
C)0.45
D)0.35
E)0.28
Rationale: Let x be the total number of students.
The number students who are younger than 25 is 0.6*0.4x+0.8*0.6x = 0.72x
The answer is B.
Answer: B
Question: What will come in place of the x in the following Number series? 2, 2, 4, 12, 48, 240, x
Options:
A)2560
B)960
C)1440
D)480
E)540
Rationale: There is one series here
(the multiply by number increases by 1 to get the next number)
2 x 1 = 2
2 x 2 = 4
4 x 3 = 12
12 x 4 = 48......
Hence: 240 x 6= 1440
C is the correct choice
Answer: C
Question: Two good train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km / hr and 30 km /hr respectively. Find the time taken by the slower train to pass the driver of the faster one.
Options:
A)12 sec
B)24 sec
C)48 sec
D)60 sec
E)None
Rationale: Sol.
Relative Speed = (45 + 30) km / hr
= (75 x 5 / 18) m/sec
= (125/6) m/sec.
Distance covered = (500 + 500) m = 1000 m.
Required time = (1000 x 6 / 125) sec = 48 sec.
Answer C
Answer: C
Question: 2x + y = 14
|y| <= 14
For how many ordered pairs (x , y) that are solutions of the system above are x and y both integers?
Options:
A)7
B)12
C)13
D)14
E)15
Rationale: Hi - The questions says |y| <=14 so the values of y will range from 0 to 14. So the values of y will be 0,1,2,3,4,5,6,7,8,9,10,11,12,13,14. So 15 (E) is the answer. remember sign doesn't matter for y as y will always be positive.
Answer: E
Question: Due to 10% decrease in the price of sugar and John can buy 5kg more sugar in Rs.100, then find the CP of sugar?
Options:
A)Rs. 1(1/9)
B)Rs. 2(2/9)
C)Rs. 2(2/7)
D)Rs. 2
E)Rs. 3(1/9)
Rationale: Here r = 10 % ,x = 100 and A = 5 kg
Actual price of sugar = 10*100/((100-10 )*5) = Rs. 2(2/9)
B
Answer: B
Question: A 70 cm long wire is to be cut into two pieces so that one piece will be 2/5th of the other, how many centimeters will the shorter piece be?
Options:
A)12
B)20
C)88
D)77
E)14
Rationale: 1: 2/5 = 5: 2
2/7 * 70 = 20
Answer: B
Answer: B