divelab/Sys2Bench huggingface dataset:
Question: Find the remainder of the division (3^15)/7.
Options:
A)7
B)6
C)15
D)8
E)2
Rationale: Find the pattern of the remainders after each power:
(3^1)/7 remainder 3
(3^2)/7 remainder 2
(3^3)/7 remainder 6
(3^4)/7 remainder 4
(3^5)/7 remainder 5
(3^6)/7 remainder 1 -->this is where the cycle ends
(3^7)/7 remainder 3 -->this is where the cycle begins again
(3^8)/7 remainder 2
Continuing the pattern to (3^15)/7 gives us a remainder of 6
Final Answer:
B) 6
Answer: B
Question: One used-car salesperson receives a commission of $ 100 plus 4 percent of $ 1,000 less than the car’s final sale price. Another car salesperson earns a straight commission of 6 percent of the car’s final sale price. What is the final sale price of a car if both salespeople would earn the same commission for selling it?
Options:
A)$ 5,000
B)$ 6,000
C)$ 8,000
D)$ 10,000
E)$ 12,000
Rationale: This question can be solved by TESTing THE ANSWERS.
We're given the pay rate of two different salespeople who sell cars:
1) A commission of $ 100 plus 4 percent of $ 1,000 less than the car’s final sale price.
2) A straight commission of 6 percent of the car’s final sale price.
We're asked for the final sale price of a car if both salespeople would earn the SAME commission for selling it?
Let's TEST Answer B: $6,000
1st salesperson = $200 + .04(6,000 - 1,000) = $200 + .04(5,000) = $200 + $200 = $400
2nd salesperson = .06(6,000) = $360
These totals are NOT the same, so we can eliminate B. Looking at the two pay 'formulas', we can see that the 2nd salesperson will make more money than the 1st when the price of the car increases to a significant level, so we need a price that is HIGHER than $6,000. Since the difference in pay is relatively small in Answer B, we're likely looking for a number that is fairly close to $6,000 though...
Let's TEST Answer B: $6,000
1st salesperson = $200 + .04(8,000 - 1,000) = $200 + .04(7,000) = $200 + $280 = $480
2nd salesperson = .06(8,000) = $480
These totals are the SAME, so this must be the answer.
Final Answer:
B
Answer: B
Question: If 4<(7-x)/3, which of the following must be true?
I. 5<x
II. |x+6|>2
III. -(x+5) is positive
Options:
A)II only
B)III only
C)I and II only
D)II and III only
E)I, II and III
Rationale: 12<7-x
x<-5
x+5<0
1.5<x...not possible
2.True.....Check for values x=-6,-7,-8....... etc
3.True.. Since x+5<0 -(x+5) will always be positive
Hence, Ans is C..
Answer: C
Question: A grocer buys apples for 100¢ per pound. If 10% of the apples goes bad and he still wants to make a 20% profit over his purchase price, what should be the sales price?
Options:
A)100¢
B)115¢
C)145¢
D)150¢
E)146.67¢
Rationale: for making calculation simple let us consider he buys 10pounds @ 100/pound=1000¢ in total .
10% apples lost...means 9 pounds left.
further he wants 20% profit on 1100 ¢
means he wants to earn 1320¢
sales price should be 1320/9=¢ 146.67
Ans E
Answer: E
Question: Certain stocks in January were 20% less than they were in February and 30% greater than they were in March. What was the percentage decrease in the stocks from February to March?
Options:
A)31%
B)45%
C)52%
D)61%
E)25%
Rationale: Let, Stock in February = 100
Then, Stock in January = 100-(20/100)*100 = 80
January = 30% greater than March = 1.3* Stock in March
i.e. Stock in March = 90 / 1.3 = 69 approximately
% Decrease from February to March = (69 - 100)*100/100 =31%approximately
Answer: Option A
Answer: A
Question: Simple interest on a certain sum at a certain annual rate of interest is 1/25 of the sum. If the numbers representing rate percent and time in years be equal, then the rate of interest is:
Options:
A)5 %
B)2 %
C)6 %
D)8 %
E)3 %
Rationale: Explanation :
Let sum = x. Then, S.I. = x/25
Let rate = R% and time = R years.
[x * R * R / 100] = x / 25? R^2 = 100/25=4
R = 2
Hence, rate of interest = 2 %.
Answer : B
Answer: B
Question: There are 900 jelly beans divided between two jars, Jar X and Jar Y. If there are 500 fewer jelly beans in jar X than three times the number of beans in jar Y, how many beans are in jar X?
Options:
A)510
B)520
C)530
D)540
E)550
Rationale: X+Y=900 so Y=900-X
X=3Y-500
X=3(900-X)-500
4X=2200
X=550
The answer is E.
Answer: E
Question: The average number of printing error per page in a book of 512 pages is 4. If the total number of printing error in the first 302 pages is 1,208, the average number of printing errors per page in the remaining pages is
Options:
A)0
B)4
C)840
D)90
E)None of the above
Rationale: Remaining pages = 512 – 302 = 210
Let average printing error in remaining pages = x
Then, 1208+210×x/512=4
⇒ 210x = 840 ⇒ x = 4
Answer B
Answer: B
Question: I take a four-digit number and subtract from it the sum of its digits. In the result I strike off one of the digits and the remaining three digits of the result are 2, 4 and 6 (not necessarily in that order). Find the digit struck off by me.
Options:
A)6
B)7
C)8
D)9
E)10
Rationale: Sol:
Let us assume the four digit number as wxyz. Then in base system 10 it can written as 1000w + 100x + 10y + z. Now given that,
wxyz = 1000w + 100x + 10y + z - (w + x + y + z) = 999w + 99x + 9y which is a multiple of 9
Hence the sum of digits must be a multiple of 9.
Hence 2 + 4 + 6 + x is equal to either 9, 18, 27 ...
But if the sum is equal to 9 then x is negative number. Therefore x = 6.
Answer A
Answer: A
Question: In each of the following numbers, what should be the missing digit in the indicated place such that the number is a multiple of 11?
945678_
Options:
A)3
B)2
C)8
D)7
E)6
Rationale: Divisibility of 11: If the difference of the sum of the digits at odd places and the sum of the digits at even places of a number is zero or a multiple of 11, then that number is divisible by 11.
As per divisibility rule of 11, difference = (x + 21) - 18 = x + 3
=> x + 3 = 11 => x = 8
ANSWER:C
Answer: C
Question: Mr. LISA invested in Fund X and Fund Y. The total amount she invested, in both funds combined, was $200,000. In one year, Fund X paid 41% and Fund Y paid 14%. The interest earned in Fund Y was exactly $200 greater than the interest earned in Fund X. How much did Ms. Tom invest in Fund X?
Options:
A)60,545.56
B)570,545.56
C)50,545.45
D)80,545.23
E)90,545.78
Rationale: X+Y=200,000
0.14Y=0.41A+200
Take away decimals first: 14Y+41X+20,000
Isolate first equation to solve for X (your goal): Y=200,000-Y
Plug in for B:
14(200,000-X)=41X+20,000
2,800,000-14X=41X+20,000
2,780,000=55X
2,780,000/55=X
X=50,545.45=Answer Choice C
Answer: C
Question: There are three secretaries who work for four departments. If each of the four departments have one report to be typed out, and the reports are randomly assigned to a secretary, what is the probability W that all three secretary are assigned at least one report?
Options:
A)8/9
B)64/81
C)4/9
D)16/81
E)5/9
Rationale: I got the same answer: Here's my reasoning
First Report you have 3 choices
Second Report you have 2 choices
Third Report you have 1 choice
Fourth report 3 choices again
Then total number of ways is: 3*2*1*3=3^2*2
This is not correct. You have assumed that the 4th report must go to someone who already has a report. There is no such constraint. You can easily give the 1st and 2nd reports to secretary 1, 3rd report to secretary 2 and 4th report to secretary 3. But you have ignored all such cases.
The number of ways of ensuring at least one report goes to each secretary is 4C2 (select 2 reports out of 4 which go to the same person)*3C1 (select the person who must type 2 reports)*2! (since you have 2 reports left which you must distribute to the 2 remaining people such that each person gets one) = 36
Required probability W= 36/81.C
Answer: C
Question: A watch which gains uniformly is 2 minutes low at noon on Monday and is 4 min. 48 sec fast at 2 p.m. on the following Monday. When was it correct?
Options:
A)2 p.m. on Tuesday
B)2 p.m. on Wednesday
C)3 p.m. on Thursday
D)1 p.m. on Friday
E)8 p.m. on Friday
Rationale: Time from 12 p.m. on Monday to 2 p.m. on the following Monday = 7 days 2 hours = 170 hours.
The watch gains 2 + 4*4/5	min.	or	34/5	min. in 170 hrs.
Now,	34/5	min. are gained in 170 hrs.
2 min. are gained in 170 x	5/34	x 2	hrs	= 50 hrs.
Watch is correct 2 days 2 hrs. after 12 p.m. on Monday i.e., it will be correct at 2 p.m. on Wednesday.
Answer:B
Answer: B
Question: Reeya obtained 50, 60, 70, 80 and 80 out of 100 in different subjects, What will be the average
Options:
A)70
B)75
C)80
D)85
E)68
Rationale: Explanation:
(50+60+70+80+80 / 5)=68
Option E
Answer: E
Question: An alchemist discovered that the formula expressing the correct proportions needed to turn ordinary metal into gold is G = 3/2M + 15, where G is the number of gold bars and M is the number of metal bars. If a metal bar weighs twice as much as a gold bar, how many metal bars will yield an equal weight of gold
Options:
A)a.	A - 10
B)b.	B - 15
C)c.	C – 22.5
D)d.	D – 40
E)e.	E – 67.5
Rationale: A --- 30/2 + 15 = 30 --- CORRECT
B --- 45/2 + 15 = not an integer --- wrong
C --- 22.5(3/2) + 15 = not an integer --- wrong
D --- 120/2+15 = 75 --- wrong
This is one of those problems that will probably be easiest to solve by plugging in numbers. The algebra is do-able, but it's not worth the effort (in my opinion). I was able to solve it in under 30 seconds total with this method.
A
Answer: A
Question: Find the smallest number which should be multiplied with 520 to make it a perfect square.
Options:
A)30
B)120
C)55
D)35
E)None of these
Rationale: 520 = 26 * 20 = 2 * 13 * 22 * 5 = 23 * 13 * 5
Required smallest number = 2 * 13 * 5 = 130
130 is the smallest number which should be multiplied with 520 to make it a perfect square.
ANSWER:E
Answer: E
Question: What is the 4 digit number in which the 1st digit is 1/3 of the second, the 3rd is the sum of the 1st and 2nd, and the last is three times the 2nd?
Options:
A)1200
B)1245
C)1349
D)1450
E)1530
Rationale: First digit is 1/3 second digit => The numbers can be 1 & 3, 2& 6, 3 & 9.
First + second = third => we can eliminate 3 & 9 since 3 + 9 = 12.
Last is 3 times the second => we can eliminate option 2 & 6 since 3 * 6 = 18.
Hence the number is 1349
C
Answer: C
Question: In an exam, Amar scored 64 percent, Bhavan scored 36 percent and Chetan 44 percent. The maximum score awarded in the exam is 900. Find the average mark scored by all the three boys?
Options:
A)384
B)432
C)207
D)269
E)208
Rationale: Average mark scored by all the three boys =
[64/100 (900) + 36/100 (900) + 44/100 (900)] / 3
= 432
Answer: B
Answer: B
Question: In the rectangular coordinate system, what is the x-intercept of a line passing through (10, 3) and (−6, −5)?
Options:
A)4
B)2
C)0
D)−2
E)−4
Rationale: First, solve for the slope, m:
m = (y2 - y1)/(x2 - x1) = (-5 - 3)/(-6 - 10) = -8/-16 or 1/2
Then you can re-write the equation as y = (1/2)x + b and plug in one of the points to find b, the y intercept. Using point (10, 3): 3 = (1/2)(10) + b, which can be simplified to 3 = 5 + b. Solve for b and you get b = -2.
The equation now reads: y = (1/2)x - 2.
To find the x intercept, plug in 0 for y: 0 = (1/2)x - 2, which simplifies to 2 = (1/2)x. From this, we can see that the x intercept = 4.
Answer is A.
Answer: A
Question: Three men sit at a table. One dollar is placed in front of each of them. When a buzzer sounds, the first man to touch the money in front of him keeps the money that is in front of him, while the other two receive nothing. If none of the three men touches the money in front of them, then the amount of money doubles for the next round. After seven rounds of this activity, what is the maximum amount of money that any one man could receive?
Options:
A)$4
B)$5
C)$10
D)$15
E)$64
Rationale: The Optimized scenario
After 1st Round - $1. Let nobody touches the amount will double in next round.
After 2nd Round - $2. Let nobody touches the amount will double in next round.
After 3rd Round - $4. Let nobody touches the amount will double in next round.
After 4th Round - $8. Let nobody touchesthe amount will double in next round.
After 5th Round - $16. Let nobody touches the amount will double in next round.
After 6th Round - $32. Let Man A touches it and get$32
After 7th Round - $32. Let the same Man A touches it and get another$32.
So, after 7th round, the maximum amount a man receives is $64.
Answer (E)
Answer: E
Question: Which one the following fractions has the exact division of Five?
Options:
A)1889/5
B)1998/5
C)2007/5
D)2000/5
E)2016/5
Rationale: Numerator for all option is 5. In the numerator value, if the last digit is either 0 or 5, then it is exact division of 5. So Option (D) 2000, last digit is 0 is exactly divisible by 5. Answer (D).
Answer: D
Question: A new home buyer pays 4% annual interest on her first mortgage and 9% annual interest on her second mortgage. If she borrowed a total of $325,000, 80% of which was in the first mortgage, what is her approximate monthly interest payment?
Options:
A)$1,354
B)$1,733
C)$3,466
D)$13,333
E)$20,796
Rationale: 0.04x + 0.09y = 325000 [1]
0.04x = 0.80 * 325000 = 260000 [2]
260000 + 0.09y = 325000 --> 0.09y = 65000 [3]
260000 / 12 = 21666.67 [4]
65000 / 12 = 5416.667[5]
Adding [4,5] we get: 27083.33 [6]
Dividing [6] / 2 to get an average we get 1.354,ANS A
Answer: A
Question: The true discount on a bill due 9 months hence at 16% per annum is Rs. 153.The amount of the bill is
Options:
A)Rs. 1386
B)Rs. 1764
C)Rs. 1275
D)Rs. 2268
E)None of these
Rationale: Solution
32.5
Let P.W. be Rs. x.Then,S.I. on Rs.x at 16% for 9 months =Rs.153.
∴ x 16 x9/ 12x 1/100}= 153 or x = 1275.
∴ P.W. = Rs. 1275.
Answer C
Answer: C
Question: From a box containing 10 orange balls and 6 yellow balls, a child takes out two balls simultaneously and at random. What is the probability that he picks one ball of each color?
Options:
A) 1/8
B) 1/30
C) 1/16
D) 1/4
E) 1/2
Rationale: We are told that we have 16 balls, 10 orange and 6 yellow. The balls are drawn simultaneous and randomly, B1 and B2, in different colors. There are two acceptable outcomes: 1) B1 is orange and B2 is yellow; 2) B1 is yellow and B2 is orange. Let's go: 1) B1 = (10/16)(6/15)= 1/4 chance of this happening. 2) B2 = (6/16)(10/15) = 1/4 chance of this happening. Then: (1/4)+(1/4)= 1/2, chance of getting the result that you wanted. Answer E.
Answer: E
Question: Exactly 3/7 of the people in the room are under the age of 21, and exactly 5/9 of the people in the room are over the age of 65. If the total number of the people in the room is greater than 50 and less than 100, how many people in the room are under the age of 21?
Options:
A)27
B)35
C)39
D)60
E)65
Rationale: The total number of the people in the room must be a multiple of both 7 and 9 (in order 3/7 and 5/9 of the number to be an integer), thus the total number of the people must be a multiple of LCM of 7 and 9, which is 63.
Since, the total number of the people in the room is greater than 50 and less than 100, then there are 91 people in the room.
Therefore there are 3/7*63=27 people in the room under the age of 21.
Answer: A.
Answer: A
Question: If k and w are the dimensions of a rectangle that has area 48, and if k and w are integers such that k > w, what is the total number of possible values of k?
Options:
A) Four
B) Three
C) Two
D) Five
E) Six
Rationale: kw=48=48*1=24*2=16*3=12*4 --> k can take 4 values.
Answer: A
Answer: A
Question: A certain Social Security recipient will receive an annual benefit of $12,000 provided he has annual earnings of $9,360 or less, but the benefit will be reduced by $1 for every $3 of annual earnings over $9,360. What amount of total annual earnings would result in a 40 percent reduction in the recipient's annual Social Security benefit? (Assume Social Security benefits are not counted as part of annual earnings.)
Options:
A)$15,360
B)$17,360
C)$18,000
D)$21,360
E)$30,960
Rationale: For every $3 earn above $9360, the recipient loses $1 of benefit.
OR
For every $1 loss in the benefit, the recipient earns $3 above $9360
If earning is; 9360+3x
Benefit = 12000-x
Or the vice versa
If benefit is 12000-x, the earning becomes 9360+3x
He lost 40% of the benefit;
Benefit Received= 12000-0.4*12000 = 12000-4800
x=7200
Earning becomes 9360+3x=9360+3*7200=30960
Ans:E
Answer: E
Question: The captain of a cricket team of 11 members is 26 years old and the wicket keeper is 3 years older. If the ages of these two are excluded, the average age of the remaining players is one year less than the average age of the whole team. What is the average age of the team?
Options:
A)23 year
B)24 years
C)25 years
D)30 years
E)None
Rationale: Sol.
Let the average age of the whole team be x years.
∴ 11 x - (26 + 29) = 9 (x - 1)
⇔ 11x - 9x = 46
⇔ 2x = 46
⇔ x = 23.
So, average age of the team is 23 years.
Answer A
Answer: A
Question: On dividing a number by 5, we get 3 as remainder. What will the remainder when the square of the this number is divided by 5 ?
Options:
A)0
B)1
C)2
D)4
E)6
Rationale: Let the number be x and on dividing x by 5, we get k as quotient and 3 as remainder.
x = 5k + 3
x2 = (5k + 3)2
= (25k2 + 30k + 9)
= 5(5k2 + 6k + 1) + 4
On dividing x2 by 5, we get 4 as remainder.
Answer: D
Answer: D
Question: A tradesman by means of his false balance defrauds to the extent of 1%? in buying goods as well as by selling the goods. What percent does he gain on his outlay?
Options:
A)2%
B)77%
C)44%
D)16%
E)47%
Rationale: g% = 1 + 1 + (1*1)/100
= 2%
Answer: A
Answer: A
Question: Train A leaves the station traveling at 30 miles per hour. Two hours later train В leaves the same station traveling in the same direction at 42 miles per hour. How many miles from the station was train A overtaken by train B?
Options:
A)150
B)170
C)190
D)210
E)230
Rationale: After two hours, Train A is ahead by 60 miles.
Train B can catch up at a rate of 12 miles per hour.
The time to catch up is 60/12 = 5 hours.
In 5 hours, train A travels another 30*5 = 150 miles for a total of 210 miles.
The answer is D.
Answer: D
Question: Running at the same constant rate, 6 identical machines can produce a total of 270 bottles per minute. At this rate, how many bottles could 5 such machines produce in 4 minutes?
Options:
A) 900
B) 1,800
C) 2,700
D) 10,800
E) 64,800
Rationale: 6 machines produce 270 bottles per minute;
1 machine produces 270/6=45 bottles per minute;
5 machines produce 45*5=225 bottles per minute;
In 4 minutes 10 machines produce 225*4=900 bottles.
Answer: A.
Answer: A
Question: Two trains are moving at 50 kmph and 70 kmph in opposite directions. Their lengths are 170 m and 100 m respectively. The time they will take to pass each other completely is?
Options:
A)3 sec
B)8 sec
C)9 sec
D)5 sec
E)7 sec
Rationale: 70 + 50 = 120 * 5/18 = 100/3 mps
D = 170 + 100 = 270 m
T = 270 * 3/100 = 8 sec
ANSWER:B
Answer: B
Question: A two-digit number is such that the product of the digits is 8. When 18 is added to the number, then the digits are reversed. The number is:
Options:
A)2
B)15
C)18
D)7
E)12
Rationale: Let the ten's and unit digit be x and 8/x respectively.
Then,(10x + 8/x) + 18 = 10 x 8/x	+ x
10x2 + 8 + 18x = 80 + x2
9x2 + 18x - 72 = 0
x2 + 2x - 8 = 0
(x + 4)(x - 2) = 0
x = 2.
Answer:A
Answer: A
Question: A, B, C subscribe Rs. 50,000 for a business. If A subscribes Rs. 4000 more than B and B Rs. 5000 more than C, out of a total profit of Rs. 40,000, what will be the amount A receives?
Options:
A)14700
B)14500
C)16800
D)14300
E)14000
Rationale: Total amount invested = 50000
Assume that investment of C =x.
Then investment of B =5000+x,
Investment of A =4000+5000+x=9000+x
x+5000+x+9000+x=50000
⇒3x+14000=50000
⇒3x=50000–14000=36000
⇒x=36000/3=12000
Investment of C =x=12000
Investment of B =5000+x=17000
Investment of A =9000+x=21000
Ratio of the investment of A, B and C
=21000:17000:12000
=21:17:12
Share of A = Total profit ×21/50
=40000×21/50=16,800
Answer is C
Answer: C
Question: A factory producing tennis balls stores them in either big boxes, 25 balls per box, or small boxes, 20 balls per box. If 153 freshly manufactured balls are to be stored, what is the least number of balls that can be left unboxed?
Options:
A)2
B)1
C)3
D)5
E)4
Rationale: We have to work with multiples of 20 and 25.
First, we must know the limits of this multiples, so:
152/25= 6....so the max is 6
152/20=7...so the max is 7
153-150 =3 ( 6 big box )
Answer : C
Answer: C
Question: 90 litres of diesel is required to travel 600 km using a 800 cc engine. If the volume of diesel required to cover a distance varies directly as the capacity of the engine, then how many litres of diesel is required to travel 800 km using 1200 cc engine?
Options:
A)80 litres
B)90 litres
C)120 litres
D)180 litres
E)None of these
Rationale: Explanatory Answer
To cover a distance of 800 kms using a 800 cc engine, the amount of diesel required = 800/600*90 = 120 litres.
However, the vehicle uses a 1200 cc engine and the question states that the amount of diesel required varies directly as the engine capacity.
i.e., for instance, if the capacity of engine doubles, the diesel requirement will double too.
Therefore, with a 1200 cc engine, quantity of diesel required = 1200/800*120 = 180 litres.
Answer D
Answer: D
Question: Two trains of length 100 m and 200 m are 250 m apart. They start moving towards each other on parallel tracks, at speeds 54 kmph and 72 kmph. After how much time will the trains meet?
Options:
A)50/7 sec
B)32/3 sec
C)20/7 sec
D)32/3 sec
E)53/2 sec
Rationale: They are moving in opposite directions, relative speed is equal to the sum of their speeds.
Relative speed = (54 + 72)*5/18 = 7*5 = 35 mps.
The time required = d/s = 250/35 = 50/7 sec.
Answer:A
Answer: A
Question: There are 6 couples. If they will sit 12 chairs in a row such that each couple sits side by side, how many possible cases are there?
Options:
A)120
B)240
C)1,200
D)46080
E)3,840
Rationale: Tie the couples. Then we have 6 persons that have to be arranged in 6 places. 6! ways.
Now the couples can change position with each other. 2! ways.
6! * (2!)^6=720 *64 = 46080
Answer is D.
Answer: D
Question: A, B and C can do a piece of work in 30 days, 30 days and 40 days respectively. They began the work together but C left 4 days before the completion of the work. In how many days was the work completed?
Options:
A)12 days
B)16 days
C)18 days
D)11 days
E)38 days
Rationale: One day work of A, B and C = 1/30 + 1/30 + 1/40 = 1/11Work done by A and B together in the last 4 days = 4*(1/30 + 1/30) = 4/15
Remaining work = 11/15
The number of days required for this initial work = 8 days.
The total number of days required = 4 + 8 = 12 days.
Answer:A
Answer: A
Question: The maximum number of students among them 640 pens and 520 pencils can be distributed in such a way that each student get the same number of pens and same number of pencils?
Options:
A)40
B)45
C)50
D)55
E)60
Rationale: number of pens = 640
number of pencils = 520
Required number of students = H.C.F. of 640 and 520= 40
Answer is A
Answer: A
Question: Ram professes to sell his goods at the cost price but he made use of 950 grms instead of a kg, what is the gain percent?
Options:
A)5.26%
B)11 7/7%
C)11 1/9%
D)71 1/9%
E)11 1/2%
Rationale: 950 --- 50
100 --- ? => 5.26%
Answer:A
Answer: A
Question: Simple interest on a sum at 5% per annum for 2 years is Rs.90. The C.I. on the same sum for the same period is?
Options:
A)81.6
B)91.5
C)81.2
D)81.3
E)81.1
Rationale: SI = 45 + 45
CI = 45 + 45 + 1.5 = 91.5
Answer: B
Answer: B
Question: A piece of ribbon is cut from a role that can now make 189 more pieces and an additional piece of 30mm. If the full role after the piece was cut is 600mm, what is the length of the ribbon that was cut?
Options:
A)25
B)270
C)12
D)3
E)30
Rationale: r as the length of the ribbon cut.
(189*r) +r + 30=600.
(190*r) +30=600
(190*r)=600-30 solves to (190*r)/270= 570/190
r equates to 3mm.
Answer is D.
Answer: D
Question: There is an increase of 30% in the production of milk chocolates in Amul Dairy in one month. If now it is 6,500 milk chocolates per month, what was it one month ago?
Options:
A)5,000 chocolates
B)9000 chocolates
C)8000 chocolates
D)7000 chocolates
E)None of these
Rationale: Let one month ago, production be x chocolates.
Then, 130 % of x = 6500
⇒ x = 6500×100/130=5000 chocolates
Answer A
Answer: A