divelab/Sys2Bench huggingface dataset:
Question: If two numbers are in the ratio 4:7. If 10 is added to both of the numbers then the ratio becomes 6:10 then find the largest number?
Options:
A)80
B)40
C)140
D)100
E)None of these
Rationale: Explanation:
4:7
4x + 10 : 7x + 10 = 6 : 10
10[4x + 10] = 6[7x + 10]
40x + 100 = 42x + 60
100 – 60 = 42x – 40x
2x = 40
X = 20
Then the first number is = 4
7x = 140
Short cut method:
a:b = 4:7
c:d = 6:10
1.Cross multiplication with both ratios
a * d ~ b * c = 4 * 10 ~ 7 * 6 = 40 ~ 42 = 2
2. If 10 is added both the number means 10 * 6 = 60 and 10 * 10 = 100,
Then 60 ~ 100 = 40
===> 2 -----> 40
===> 1 -----> 20
==> 7 -----> 140
Answer: Option C
Answer: C
Question: The price of 80 apples is equal to that of 120 oranges. The price of 60 apples and 75 oranges together is Rs.1320. The total price of 25 apples and 40 oranges is
Options:
A)Rs. 660
B)Rs. 620
C)Rs. 820
D)Rs. 780
E)Rs. 960
Rationale: Explanation :
Let the price of one apple = a and price of one orange = b
The price of 80 apples is equal to that of 120 oranges
80a = 120b
=> 2a = 3b
⇒b=2a3-----(Equation 1)
price of 60 apples and 75 oranges together is Rs.1320
=>60a + 75b = 1320
=> 4a + 5b = 88
⇒4a+5(2a)3=88(∵ Substituted the value of b from equation 1)
=> 12a + 10a = 88 × 3
=> 6a + 5a = 44 × 3
=> 11a = 44 × 3
=> a = 4 × 3 = 12
b=2a3=2×123=8
Total price of 25 apples and 40 oranges
= 25a + 40b = (25 × 12) + (40 × 8) = 300 + 320 = 620
Answer : B
Answer: B
Question: A cylinder is being filled with sand weighing 200 kg per cubic foot. The cylinder has a diameter of 1 foot and is 5 feet tall. How much sand is being used??
Options:
A)250pi kg
B)500pi kg
C)500pi^2 kg
D)1000pi kg
E)1000pi^2 kg
Rationale: Answer is A.
Volume of Cylinder = Pi*r^2 *h --------> Pi * (1/2)^2 * 5 --------> Pi * (1/4) * 5 --------> (5/4)Pi cubic feet.
1 cubic feet = 200 kg. so (5/4)Pi cubic feet = ((200*5)/4)Pi ---------> 250Pi
Regards,
Abhijit answer is A
Answer: A
Question: How many 3-digit numbers are completely divisible 6 ?
Options:
A)25
B)78
C)93
D)150
E)14
Rationale: Explanation:
3-digit number divisible by 6 are: 102, 108, 114,... , 996
This is an A.P. in which a = 102, d = 6 and l = 996
Let the number of terms be n. Then tn = 996.
a + (n - 1)d = 996
102 + (n - 1) x 6 = 996
6 x (n - 1) = 894
(n - 1) = 149
n = 150
Number of terms = 150.
D)
Answer: D
Question: Speed of a boat in standing water is 10kmph and speed of the stream is 1.5kmph. A man can rows to a place at a distance of 105km and comes back to the starting point. The total time taken by him is?
Options:
A)20.48hours
B)21.48hours
C)22.48hours
D)23.48hours
E)24.48hours
Rationale: Speed upstream = 8.5kmph
Speed downstream = 11.5kmph
Total time taken = 105/8.5 + 105/11.5 = 21.48 hours
Answer is B
Answer: B
Question: An escalator moves towards the top level at the rate of 11 ft.sec and its length is 126 feet. If a person walks on the moving escalator at the rate of 3 feet per second towards the top level, how much time does he take to cover the entire length.
Options:
A)14 sec
B)10 sec
C)12 sec
D)8 sec
E)9 sec
Rationale: Time taken to cover the entire length = tot.dist/resultant speed
= 126/ (11+3)
= 9 sec
ANSWER:E
Answer: E
Question: How many seconds will a 750 meter long train moving with a speed of 63 km/hr take to cross a man walking with a speed of 3 km/hr in the direction of the train ?
Options:
A)48
B)36
C)26
D)11
E)45
Rationale: Explanation:
Here distance d = 750 mts
speed s = 63 - 3 = 60 kmph = 60 x 5/18 m/s
time t = = 45 sec.
Answer: E
Answer: E
Question: Jane started baby-sitting when she was 18 years old. Whenever she baby-sat for a child, that child was no more than half her age at the time. Jane is currently 34 years old, and she stopped baby-sitting 12 years ago. What is the current age of the oldest person for whom Jane could have baby-sat?
Options:
A)20
B)21
C)22
D)23
E)25
Rationale: Check two extreme cases:
Jane = 18, child = 9, years ago = 34-18 = 16 --> child's age now = 9+16 = 25;
Jane = 22, child = 11, years ago = 34-22 = 12 --> child's age now = 11+12 = 23.
Answer: E.
Answer: E
Question: The average of first seven prime numbers which are odd is?
Options:
A)15.5
B)15.7
C)15.2
D)15.8
E)10.7
Rationale: Sum of first 7 prime no. which are odd = 75
Average = 75/7 = 10.7
Answer:E
Answer: E
Question: A candidate got 35% of the votes polled and he lost to his rival by 2250 votes. How many votes were cast?
Options:
A)7500
B)2028
C)2775
D)5496
E)6851
Rationale: 35%-----------L
65%-----------W
------------------
30%----------2250
100%---------? => 7500
Answer:A
Answer: A
Question: John was thrice as old as Tom 6 yrs back. He will be 5/3 times as old as Tom 6 years hence. How old is Tom today?
Options:
A)10
B)11
C)12
D)14
E)15
Rationale: Sol. RMBflSk -6 = 3 (Ravi - 6) ...(j)
and Rupesh + 6 = | (Ravi + 6) ...(ii)
Solving both the equations we get,
Ravi = 12 years.
C
Answer: C
Question: It takes Avery 3 hours to build a brick wall while Tom can do it in 5 hours. If the two start working together and after an hour Avery leaves, how much time will it take Tom to complete the wall on his own?
Options:
A)100
B)110
C)120
D)130
E)140
Rationale: Avery takes 3 hours
Tom takes 2 hours
Efficiency of Avery is 1/3 units/hr
Efficiency of Tom is 1/5 units/hr
Combined efficiency of Tom and Avery is 1/3 +1/5 = 8/15 units/hr
Since they worked for 1 hour they completed 8/15 units of work and 7/15 units of work is left which is to be completed by Tom ( Since Avery left )
So Time taken by Tom to complete the remaining work will be 7/15/1/5 hours => 7/3*60 =140 minutes...
Answer will be (E)
Answer: E
Question: A restaurant meal cost $32.50 and there was no tax. If the tip was more than 10 percent but less than 15 percent of the cost of the meal, then total amount paid must have been between:
Options:
A)$40 and $42
B)$39 and $41
C)$38 and 40
D)$37 and $39
E)$36 and $38
Rationale: let tip=t
meal cost=32.50
range of tip = from 10% of 32.5 to 15% of 32.5 = 3.55 to 5.325
hence range of amount paid= 32.5+T= 36.05 to 37.825
ANSWER:E
Answer: E
Question: On what dates of April, 2001 did Wednesday fall?
Options:
A)2nd, 9th, 16th, 23rd
B)4th, 11th, 18th, 25th
C)3rd, 10th, 17th, 24th
D)1st, 8th, 15th, 22nd, 29th
E)3rd, 8th, 15th, 17th, 23rd
Rationale: Explanation:
We need to find out the day of 01-Apr-2001
01-Apr-2001 = (2000 years + period from 1-Jan-2001 to 01-Apr-2001)
We know that number of odd days in 400 years = 0
Hence the number of odd days in 2000 years = 0 (Since 2000 is a perfect multiple of 400)
Days from 1-Jan-2001 to 01-Apr-2001 = 31 (Jan) + 28 (Feb) + 31 (Mar) + 1(Apr) = 91
91 days = 13 weeks = 0 odd day
Total number of odd days = (0 + 0) = 0 odd days
0 odd day = Sunday. Hence 01-Apr-2001 is Sunday.
Hence first Wednesday of Apr 2011 comes in 04th and successive Wednesdays come in 11th, 18th and 25th
Answer: Option B
Answer: B
Question: Rs 1000 is invested at 5% pa simple interest. If interest is added to principal after every 10 yr. Then we will get amount 2000 after how many year?
Options:
A)12 years.
B)13.66 years.
C)14 years.
D)16.66 years.
E)15 YEARS
Rationale: P = 1000.
R = 5%.
T = 10 years.
I = PTR/100 = (1000 * 5*10)/100 = 500.
Now,
Principal = 1000 + 500 = 1500.
A = 2000
I = 500
R = 5%
T = (100 * I)/PR = (100 * 500)/(1500 *5) = 6.66 Years.
Total Time = 10 + 6.66 = 16.66 years.
ANSWER : OPTION D
Answer: D
Question: Which of the following functions does not intersect with T = 3x^2 + 2x + 1
Options:
A)T = 3x^2 + 3x + 1
B)T = 2x^2 + 3x + 1
C)T = 3x^2 + 2x + 3
D)T = 4x^2 + 2x - 3
E)T = x^2 + 2x + 3
Rationale: Let’s find the actual intersecting point of given function and each choice T.
A. 3x^2 + 2x + 1 = 3x^2 + 3x + 1 --> x=0
B. 3x^2 + 2x + 1 = 2x^2 + 3x + 1 --> x^2 – x =0 --> x=0 or 1
C. 3x^2 + 2x + 1 = 3x^2 + 2x + 3 --> 1=3(X) --> they don’t have any intersect.
D. 3x^2 + 2x + 1 = 4x^2 + 2x - 3 --> x^2 –4=0 --> x= 2 or -2
E. 3x^2 + 2x + 1 = x^2 + 2x + 3 --> 2x^2 –2 =0 --> x= 1 or –1.
So only choice (C) has no intersecting point. The answer is (C).
Answer: C
Question: If x and y are different integers, both divisible by 6, then which is not necessarily true?
Options:
A)x^2 + y^2 is divisible by 6
B)x - y is divisible by 6
C)xy is divisible by 6
D)x + y is divisible by 6
E)x + y is divisible by 12
Rationale: Let x = 6k and let y = 6j.
Then x+y = 6(k+j) and k+j could be even or odd.
Thus 6(k+j) is not necessarily divisible by 12.
The answer is E.
Answer: E
Question: 40% of Ram's marks is equal to 20% of Rahim's marks which percent is equal to 30% of Robert's marks. If Robert's marks is 80, then find the average marks of Ram and Rahim?
Options:
A)76
B)56
C)56
D)90
E)15
Rationale: Given, 40% of Ram's marks = 20% of Rahim's marks = 30% of Robert's marks.
Given, marks of Robert = 80
30% of 80 = 30/100 * 8 = 24
Given, 40% of Ram's marks = 24.
=> Ram's marks = (24 * 100)/40 = 60
Also, 20% of Rahim's marks
= 24
=> Rahim's marks
= (24 * 100)/20 = 120
Average marks of Ram and Rahim
= (60 + 120)/2 = 90.
Answer: D
Answer: D
Question: A and B enter into partnership with capital as 7:9. At the end of 8 months, A withdraws. If they receive the profits in the ratio of 8:9 find how long B's capital was used?
Options:
A)7
B)9
C)10
D)12
E)14
Rationale: Explanation:
7 * 8 : 9 * x = 8:9 => x= 7
A)
Answer: A
Question: The average of numbers 0.64206, 0.64207, 0.64208 and 0.64209 is ?
Options:
A)0.64202
B)0.64204
C)0.642022
D)0.642075
E)None
Rationale: Answer
Average = (0.64206 + 0.64207 + 0.64208 + 0.64209)/ 4
=2.5683/ 4
=0.642075
Correct Option: D
Answer: D
Question: Pid intended to type a seven-digit number, but the two 3's he meant to type did not appear. What appeared instead was the five-digit number 52115. How many different seven-digit numbers could Pid have meant to type?
Options:
A)10
B)16
C)21
D)24
E)27
Rationale: Should be 21.
Pid intended to type a seven-digit number there are two possibilities for placing 2 3s .
case 1: two 3s were missed consecutively. i.e. he typed 33 and it came blank on screen.
-5-2-1-1-5- in this arrangement we can fit 33 in 6 ways . (Six dashes, each dash represent one possible place for placing 33)
case 2: two 3s are not together, i.e. they have one or more digits between them .
-5-2-1-1-5- , in this arrangement
if we place first 3 at first dash i.e. 35-2-1-1-5- then the other 3 can fit into 5 places.
if we place first 3 at second dash i.e. -532-1-1-5- then the other 3 can fit into 4 places.
if we place first 3 at third dash i.e. -5-231-1-5- then the other 3 can fit into 3 places.
if we place first 3 at fourth dash i.e. -5-2-131-5- then the other 3 can fit into 2 places.
if we place first 3 at Fifth dash i.e. -5-2-1-135- then the other 3 can fit into 1 place.
so total 15 ways.
case 2 + case 1 = 6+ 15 = 21 ways
Answer C
Answer: C
Question: In a class, there are 18 boys who are over 160 cm tall. If these constitute three-fourths of the boys and the total number of boys is two-thirds of the total number of students in the class, what is the number of girls in the class ?
Options:
A)6
B)12
C)18
D)19
E)22
Rationale: In a class, there are 18 boys who are over 160 cm tall. If these constitute three-fourths of the boys , then total no of boys = 18*4/3 = 24 boys.
the total number of boys (24)is two-thirds of the total number of students in the class, then total students = 24*3/2= 36
no. of girls = 36-24=12
ANSWER:B
Answer: B
Question: 0.04 x 0.0162 is equal to:
Options:
A)6.48 x 10(power -4)
B)6.48 x 10(power -3)
C)9.48 x 10(power -4)
D)5.48 x 10(power -4)
E)6.08 x 10(power -4)
Rationale: 4 x 162 = 648. Sum of decimal places = 6.
So, 0.04 x 0.0162 = 0.000648 = 6.48 x 10(power -4)
Answer is A.
Answer: A
Question: The speed of a boat in still water is 80kmph and the speed of the current is 20kmph. Find the speed downstream and upstream?
Options:
A)22 kmph
B)40 kmph
C)60 kmph
D)15 kmph
E)23 kmph
Rationale: Speed downstream = 80 + 20 = 100 kmph
Speed upstream = 80 - 20 = 60 kmph
Answer:C
Answer: C
Question: At a certain supplier, a machine of type A costs $30,000 and a machine of type B costs $70,000. Each machine can be purchased by making a 20 percent down payment and repaying the remainder of the cost and the finance charges over a period of time. If the finance charges are equal to 40 percent of the remainder of the cost, how much less would 2 machines of type A cost than 1 machine of type B under this arrangement?
Options:
A)$10,000
B)$11,200
C)$12,000
D)$12,800
E)$13,200
Rationale: Total Cost of 2 Machines of Type A
= 20% of (Cost of 2 machine A) + remainder + 40 % remainder
= 20% of 30000 + (30000 - 20% of 30000) + 40% of (40000 - 20% of 30000)
= 79200
Total Cost of 1 Machine of Type B
= 20% of (Cost of 1 machine B) + remainder + 40 % remainder
= 20% of 70000 + (70000 - 20% of 70000) + 40% of (50000 - 20% of 70000)
= 92400
Diff = 92400 - 79200 = 13200
Hence, E.
Answer: E
Question: What is the total number of integers between 20 and 70 that are divisible by 2?
Options:
A)19
B)25
C)24
D)26
E)20
Rationale: 22, 24, 26, ..., 56,58
This is an equally spaced list; you can use the formula:
n = (largest - smallest) / ('space') + 1 = (70 - 22) / (2) + 1 = 48/2 + 1 = 24 + 1 = 25
Answer is B
Answer: B
Question: The second of two numbers is two less than three times the first. Find the numbers if there sum is
82.
Options:
A)7-19
B)8-20
C)10-16
D)15-9
E)21-61
Rationale: We are looking for two numbers.
#1 - x
#2 - 3x â€“ 2
The sum is 82. #1 + #2 = 82
Substituting x + 3x â€“ 2 = 82
4x â€“ 2 = 82
4x = 84
x = 21
The first number is 21, the second number is two less than three times 21 or 61.
correct answer E
Answer: E
Question: A room 4 m 47 cm long and 7m 77 cm broad is to be paved with square tiles. Find the least number of square tiles required to cover the floor.
Options:
A)38636
B)38640
C)38647
D)38591
E)38675
Rationale: Explanation:
Area of the room = (447 x 777) cm2.
Size of largest square tile = H.C.F. of 447 cm and 777 cm = 3 cm.
Area of 1 tile = (3 x 3) cm2.
Number of tiles required =(447×777)/(3×3)=38591
Answer: Option D
Answer: D
Question: A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
Options:
A)16
B)14
C)15
D)18
E)13
Rationale: A's 2 day's work= (1/20)*2=1/10
(A + B + C)'s 1 day's work =(1/20+1/30+1/60) = 6/60 =1/10
Work done in 3 days = (1/10+1/10) = 1/5
Now,	1/5 work is done in 3 days.
Whole work will be done in (3 x 5) = 15 days.
ANSWER:C
Answer: C
Question: A certain number of donkeys and an equal number of men are going to a village. Half of the men are on their donkey's back while the remaining are walking along leading their donkeys. If the number of legs walking on the ground is 70. How many donkeys are there?
Options:
A)218
B)277
C)299
D)267
E)11
Rationale: Answer:B
Answer: B
Question: Two numbers are respectively 20% and 25% more than a third number. The percentage that is first of the second is?
Options:
A)33
B)71
C)96
D)55
E)77
Rationale: I II III
120 125 100
125----------120
100-----------? => 96%
\Answer:C
Answer: C
Question: A certain research group plans to create computer models of x% of a list of 10,000 bacterial species known to inhabit the human body. After a budget cut, the group finds it must reduce this selection by (x − 7)%. In terms of x, how many species of bacteria will the group be able to model?
Options:
A)x*x – 5x
B)(x)*(107 – x)
C)(100)(105 – x)
D)(100)(95 – x)
E)(x-5)/100
Rationale: Initial: (x/100)*10000 = 100x (bacterial species)
After reduce BY (x - 7)%, the percentage of bacterial species = 1 - (x - 7)% = 1 - (x - 7)/100 = (107 - x)/100
Note: Difference between reduce to[means: the remain] and reduce by[means: the remain = 1 -reduce by]
So, the number of bacterial species after reducing: 100x*(107 - x)/100 = (x)*(107 - x)
Ans is B.
Answer: B
Question: In each of the following questions a number series is given with one term missing. Choose the correct alternative that will continue the same pattern and fill in the blank spaces.
2, 7, ?, 23, 34, 47
Options:
A)31
B)14
C)36
D)31
E)33
Rationale: B
14
The given sequence is +5, +7, +9, ——
ie. 2+ 5 = 7, 7 + 7 = 14, 14 + 9 = 23
Answer: B
Question: Mid intended to type a seven-digit number, but the two 3's he meant to type did not appear. What appeared instead was the five-digit number 52115. How many different seven-digit numbers could Mid have meant to type?
Options:
A)10
B)16
C)21
D)24
E)27
Rationale: Should be 21.
Mid intended to type a seven-digit number there are two possibilities for placing 2 3s .
case 1: two 3s were missed consecutively. i.e. he typed 33 and it came blank on screen.
-5-2-1-1-5- in this arrangement we can fit 33 in 6 ways . (Six dashes, each dash represent one possible place for placing 33)
case 2: two 3s are not together, i.e. they have one or more digits between them .
-5-2-1-1-5- , in this arrangement
if we place first 3 at first dash i.e. 35-2-1-1-5- then the other 3 can fit into 5 places.
if we place first 3 at second dash i.e. -532-1-1-5- then the other 3 can fit into 4 places.
if we place first 3 at third dash i.e. -5-231-1-5- then the other 3 can fit into 3 places.
if we place first 3 at fourth dash i.e. -5-2-131-5- then the other 3 can fit into 2 places.
if we place first 3 at Fifth dash i.e. -5-2-1-135- then the other 3 can fit into 1 place.
so total 15 ways.
case 2 + case 1 = 6+ 15 = 21 ways
Answer C
Answer: C
Question: The workforce of Company Samsung is 60% female. The company hired 20 additional male workers, and as a result, the percent of female workers dropped to 50%.How many employees did the company have after hiring the additional male workers?
Options:
A)180
B)170
C)160
D)150
E)145
Rationale: let x be the total worker then 0.6x =female worker and 0.4x is male worker then 20 male worker added
06x/(0.4x +20) = 50/100 or 60x = 50*( 0.4x+100) = 20x+ 5000 or 40x = 5000 , x = 125
total worker = 125+20= 145
E
Answer: E
Question: A computer was sold at a loss of 20%. If it was sold for Rs.3200 more, there would have been a gain of 12%. What is the cost price?
Options:
A)Rs.12000
B)Rs. 8000
C)Rs.10000
D)Rs. 20000
E)Rs. 11000
Rationale: 80%
112%
--------
32% ---- 3200
100% ---- ? => Rs.10000
Answer:C
Answer: C
Question: Sum of the squares of three numbers is 138 and the sum of their products taken two at a time is 131. Find the sum?
Options:
A)20
B)22
C)24
D)26
E)28
Rationale: (a + b + c)2 = a2 + b2 + c2 + 2(ab +bc + ca) = 138 + 2* 131
a + b + c = √400 = 20
A
Answer: A
Question: Given two fair dice, what is the probability W that the sum of their numbers is 4 if exactly one die shows a 3?
Options:
A)a) 2/11
B)b) 1/18
C)c) 3/11
D)d) 2/39
E)e) 1/5
Rationale: If exactly one die shows 3, there are 10 such combinations (given that we have 2 fair dice).
1:3, 2:3, 4:3, 5:3, 6:3,
3:1, 3:2, 3:4, 3:5, 3:6
The sum of numbers would be 4 for two events: 1:3, 3:1.the probability W that the sum of their numbers is 4 if exactly one die shows a 3
2/11 would be the answer if 'at least one of the die shows a 3'.A
Answer: A
Question: If a is a positive integer, which of the following could NOT be the square of a?
Options:
A) 5,008,644
B) 5,004,169
C) 4,999,696
D) 4,995,225
E) 4,990,752
Rationale: A number ending with 2 can never be a perfect square.
Units digit of a perfect square must be:
1,4,9,6,5
Answer E)
Answer: E
Question: If a tire rotates at 400 revolutions per minute when the car is traveling 96km/h, what is the circumference of the tire?
Options:
A)2
B)1
C)4
D)3
E)5
Rationale: 400 rev / minute = 400 * 60 rev / 60 minutes
= 24,000 rev / hour
24,000 * C = 96,000 m : C is the circumference
C = 4 meters
correct answer C
Answer: C
Question: An design manager has 10patterns of chairs & 7patterns of tables. In how many ways can he make a pair of table & chair?
Options:
A)70
B)40
C)80
D)90
E)100
Rationale: He has has ten patterns of chairs and eight patterns of tables
Hence, A chair can be arranged in 10 ways and
A table can be arranged in 7 ways
Hence one chair and one table can be arranged in 10 x 7 ways = 70 ways
A
Answer: A
Question: A, B and C invested Rs.6300, Rs.4200 and Rs.10500 respectively, in a partnership business. Find the share of A in profit of Rs.12100 after a year?
Options:
A)3630
B)2879
C)289
D)279
E)2928
Rationale: 6300:4200:10500
3:2:5
3/10 * 12100 = 3630
Answer:A
Answer: A
Question: Two brothers were expected to return here on the same day. Rajat returned 3 days earlier but Rohit returned 4 days later. If Rajat returned on Tuesday, what was the expected day when both the brothers were to return home and when did Rohit Return?
Options:
A)Wednesday, Sunday
B)Thursday, Monday
C)Friday, Tuesday
D)Monday, Friday
E)none
Rationale: Rajat returned on Tuesday -i.e. 3 days earlier
so actual day to return home is Friday.
Rohit returned after days so Tuesday.
ANSWER:C
Answer: C
Question: The flow of water through a drainage pipe was monitored for a 3-hour period. In the second hour, the rate of flow was 36 gallons per hour, which was 50 percent faster than the rate of flow for the first hour. If 25 percent more water flowed through the pipe in the third hour than it did in the second, how many gallons of water flowed through the pipe during the entire three hours?
Options:
A)106.25
B)105.5
C)105.75
D)106
E)105.0
Rationale: Rate of flow of water in second hour = 36 gallons per hour
Rate of flow of water in first hour = 36/(3/2) = 24 gallons per hour
Rate of flow of water in third hour = (125/100)* 36 = (5/4) * 36 = 45 gallons per hour
Number of gallons of water that flowed through the pipe during the entire 3 hours = 24+36+45 = 105 gallons
Answer E
Answer: E
Question: How many seconds will a 700 meter long train moving with a speed of 63 km/hr take to cross a man walking with a speed of 3 km/hr in the direction of the train ?
Options:
A)48
B)36
C)42
D)11
E)18
Rationale: Explanation:
Here distance d = 700 mts
speed s = 63 - 3 = 60 kmph = 60 x 5/18 m/s
time t = = 42 sec.
Answer: C
Answer: C
Question: Suppose five circles, each 4 inches in diameter, are cut from a rectangular strip of paper 12 inches
long. If the least amount of paper is to be wasted, what is the width of the paper strip?
a=sqrt(3)
Options:
A) 5
B) 4 +2a
C) 8
D) 4(1+ a)
E) not enough information
Rationale: Also if we dont go by 30:60:90 rule, we can arrive at the length of by pythagoras theorem.
(AC)^2 + (BC)^2 = AB^2
(AC)^2 + 2^2 = 4^2
AC = 2 root b.
so the width of paper = 2 + 2 + 2 root 3 --> 4 + 2 root 3.
which is B.
Answer: B
Question: In how many ways the letters of the word RAIMBON be arranged?
Options:
A)4540
B)4740
C)5040
D)6432
E)7794
Rationale: Total ways of arranging the letters = 7! = 5040 ways.
C)
Answer: C
Question: A women purchased 3 towels @ Rs.100 each, 5 towels @ Rs.150 each and two towels at a certain rate which is now slipped off from his memory. But she remembers that the average price of the towels was Rs.165. Find the unknown rate of two towels?
Options:
A)A)400
B)B)450
C)C)500
D)D)550
E)E)600
Rationale: 10 * 150 = 1650
3 * 100 + 5 * 150 = 1050
1650 – 1050 = 600
E
Answer: E
Question: Sides of a rectangular park are in the ratio 3: 2 and its area is 3750 sq m, the cost of fencing it at 80 ps per meter is?
Options:
A)287
B)369
C)125
D)200
E)361
Rationale: 3x * 2x = 3750 => x = 25
2(75 + 50) = 250 m
250 * 0.80
= Rs.200
Answer:D
Answer: D
Question: The length of a rectangle is two - fifths of the radius of a circle. The radius of the circle is equal to the side of the square, whose area is 1225 sq.units. What is the area (in sq.units) of the rectangle if the rectangle if the breadth is 13 units?
Options:
A)140 sq.units
B)170 sq.units
C)190 sq.units
D)940 sq.units
E)182 sq.units
Rationale: Explanation:
Given that the area of the square = 1225 sq.units
=> Side of square = √1225 = 35 units
The radius of the circle = side of the square = 35 units Length of the rectangle = 2/5 * 35 = 14 units
Given that breadth = 10 units
Area of the rectangle = lb = 14 * 13 = 182 sq.units
Answer: Option E
Answer: E
Question: The cost price of 13 articles is equal to the selling price of 11 articles. Find the profit percent?
Options:
A)78 2/11%
B)18 2/11%
C)88 2/11%
D)58 2/11%
E)68 2/11%
Rationale: Explanation:
13 CP = 11 SP
11 --- 2 CP
100 --- ? =>18 2/11%
Answer:B
Answer: B