divelab/Sys2Bench huggingface dataset:
Question: A box contains eight bulbs out of which 4 are defective. If four bulbs are chosen at random, find the probability that exactly three bulbs are good?
Options:
A)10/35
B)11/35
C)9/35
D)8/35
E)6/35
Rationale: Required probability = (4C3 . 4C1)/8C4 = (4 * 4)/70
= 8/35
Answer:D
Answer: D
Question: Two thirds of the roads from A to B are at least 5 miles long, and 1/2 of the roads from B to C are at least 5 miles long. If you randomly pick a road from A to B and then randomly pick a road from B to C, what is the probability that at least one of the roads you pick is at least 5 miles long?
Options:
A)5/6
B)1/4
C)2/3
D)3/4
E)11/12
Rationale: So please:
Find the probability of the event thatnoneof the roads you pick will be at least 5 miles long and subtract from 1 to get the probability thatat least oneof the roads you pick will be at least 5 miles long: P=1-1/3*1/2=5/6.
Answer: A.
Answer: A
Question: I came across this problem in the GMATprep software and got it totally wrong!
A company consists of 6 senior and 4 junior staff officers. If a committee is created with 1 senior and 1 junior staff officers, how many possible committees are there?
Options:
A)12
B)44
C)56
D)24
E)200
Rationale: 6C1*4C1
=24=D
Answer: D
Question: A train 360 m long is running at a speed of 42 km/hr. In what time will it pass a bridge 140 m long?
Options:
A)40 sec
B)29 sec
C)26 sec
D)27 sec
E)43 sec
Rationale: Speed = 42 * 5/18 = 35/3 m/sec
Total distance covered = 360 + 140 = 500 m
Required time = 500 * 3/35
= 43 sec
Answer:E
Answer: E
Question: Some people are standing square. From them 32 are removed and then form a small square and
then 8 more removed. now we cannot form the square. so how many people are there at the
beginning?
Options:
A)31
B)32
C)33
D)34
E)can't be determined
Rationale: We should find the two square numbers whose difference is 32. Starting from 9,16,25,36,49,64,81,100,....
We observe 81-49=32 & 49-8=41 which is not a square.
ANSWER:E
Answer: E
Question: 28% of employees are women with fair hair. 40% of fair-haired employees are women. What percent of employees have fair hair?
Options:
A)25
B)30
C)50
D)55
E)70
Rationale: I came up with (E) 70
Think of 100 people total:
From the first fact, 28 of these are women with fair hair.
From the second fact, these 20 women make up 40% of the total fair haired population.
We can then make a ratio of 60:40 fair haired men to fair haired women.
This means that (60/40)*28 equals the number of fair haired men, which is 42 men with fair hair.
Add this 42 to the 28 women and get 70 fair haired men and women out of 100 total men and women.
70%E
Answer: E
Question: The ratio of two numbers is 3 : 4 and their H.C.F. is 4. Their L.C.M. is:
Options:
A)12
B)16
C)24
D)48
E)60
Rationale: Let the numbers be 3x and 4x. Then, their H.C.F. = x. So, x = 4.
So, the numbers 12 and 16.
L.C.M. of 12 and 16 = 48.
Answer: Option D
Answer: D
Question: Working simultaneously at their respective constant rates, machine A and B produces 20 widgets in c hours. Working alone at its constant rate, Machine A produces 20 widgets in 'a' hours.In terms of a and c, how many hours does it take Machine B, working alone at its constant rate, to produce 10 widgets
Options:
A)ac/a+c
B)2ac/a+c
C)ac/2a+2c
D)ac/2a-2c
E)ac/2c-2a
Rationale: Let the individual rates be R(a) and R(b) for machines a and b respectively. Given than combined rate is 20 widgets in c hours => 20/c
R(a) + R(b) = 20/c
Also given is the individual rate for machine a = R(a) = 20/a
Therefore, R(a) + R(b) = 20/c => 20/a + R(b) = 20/c => R(b) = 20/c - 20/a = 20(a-c)/ac = 20/(ac/(a-c)), which basically means that b produces 20 widgets in ac/a-c Hrs. We have to calculate how much does it take to produce 10 widgets. So divide the rate by 2 which gives us ac/2(a-c).
Hence the answer is D
Answer: D
Question: Three cannons are firing at a target. If their individual probabilities to hit the target are 0.6, 0.7, and 0.8 respectively, what is the probability that none of the cannons will hit the target after one round of fire?
prob. that all the cannons will hit the target = .06
prob. that none of the cannons will hit = 1 - .06 = .94
Options:
A)0.006
B)0.012
C)0.024
D)0.029
E)0.904
Rationale: The probability that eachdoesn'thit is: 0.4, 0.3, and 0.2. When we have multiple independent events, we multiply the probabilities:
.4*.3*.2 = 0.024.
Option: C
Answer: C
Question: Find the smallest number that must be added to 1780 to make it a perfect square.
Options:
A)17
B)42
C)69
D)47
E)52
Rationale: 4 1780 (42
16
82	180
164
16
Number to be added = (43)2 - 1780 = 1849 - 1780 = 69.
ANSWER C
Answer: C
Question: square of 99=?
Options:
A)9001
B)9621
C)9431
D)9801
E)9601
Rationale: Square of (100-1)=10000+1-200
9801
answer D
Answer: D
Question: The ratio of the length and the breadth of a rectangle is 4 : 3 and the area of the rectangle is 6912 sq cm. Find the ratio of the breadth and the area of the rectangle?
Options:
A)1:96
B)1:76
C)1:92
D)1:28
E)1:39
Rationale: Let the length and the breadth of the rectangle be 4x cm and 3x respectively.
(4x)(3x) = 6912
12x2 = 6912
x2 = 576 = 4 * 144 = 22 * 122 (x > 0)
=> x = 2 * 12 = 24
Ratio of the breadth and the areas = 3x : 12x2 = 1 : 4x = 1: 96.
Answer: A
Answer: A
Question: The positive number a is q percent greater than the positive number b, which is z percent less than a itself. If a is increased by z percent, and the result is then decreased by q percent to produce a positive number c, which of the following could be true?
I. c > a
II. c = a
III. c < a
Options:
A)I only
B)II only
C)III only
D)I and II only
E)II and III only
Rationale: Let q = 10% then z = 100/11 %
let b = 100 then a = 110
after increasing a by z and decreasing by q we get c= 108
therefore c<a
C it is answer
Answer: C
Question: Free notebooks were distributed in a class among all the students. Each student got notebooks which were one-eighth of the number of student. If number of student been half, then each child would have received 16 notebooks in total. Find the total number of books distributed among students?
Options:
A)234
B)345
C)267
D)355
E)512
Rationale: Let suppose total number of students in class are X.
Then from the question we can conclude it that,
X∗18X=X2∗16=>X=64Total notebooks,=18X2=(18∗64∗64)=512
E
Answer: E
Question: A man performs 1/2 of the total journey by rail, 1/4 by bus and the remaining 4km on foot. His total journey is
Options:
A)18km
B)16km
C)12km
D)24km
E)25km
Rationale: Explanation:
Let the journey be x km
Then, 1x/2 + 1x/4 +4 =x
3x +16 =4x
X = 16km
Answer: Option B
Answer: B
Question: Raj invested an amount of Rs.17400 for two years. Find the rate of compound interest that will fetch him an amount of Rs.1783.50 at the end of two years?
Options:
A)7
B)6
C)8
D)5
E)4
Rationale: Let the rate of interest be R% p.a.
17400[1 + R/100]2 = 17400 + 1783.50
[1 + R/100]2 = (17400 + 1783.50)/17400
= 1 + 1025/10000 = 1 + 41/400
= 441/400 = [21/20]2
[1 + R/100] = 21/20
R/100 = 1/20
Therefore R = 5.Answer: D
Answer: D
Question: Sebastian bought a meal at a restaurant
and left a 15% tip. With the tip, he paid
exactly $35.42. How much did the meal cost without the tip?
Options:
A)$28.98
B)$29.91
C)$30.15
D)$30.60
E)$30.80
Rationale: The tip is a percent increase of 15%, which is 115%. Let x equal the price before the tip.
Thus, 115% of this price equals $35.42:
1.15x = 35.42
Divide both sides by 1.15:=>x=35.42/1.15=30.80
correct answer E)$30.80
Answer: E
Question: In the city of San Durango, 50 people own cats, dogs, or rabbits. If 20 people owned cats, 30 owned dogs, 30 owned rabbits, and 20 owned exactly two of the three types of pet, how many people owned all three?
Options:
A)2
B)4
C)8
D)5
E)12
Rationale: Total = C + D + R - (CD + DR + CR) - 2CDR
50 = 20 + 30 + 30 - (20) - 2x
x = 5
So, answer will be D
Answer: D
Question: A sack of 30 marbles total contains 10 red marbles, 8 white marbles, 9 blue marbles and 3 green marbles. One marble is removed and examined at a time and placed back into the bag until a white marble is successfully removed. What is the probability that a white marble will be removed on the 2nd try or better?
Options:
A)1/3
B)3/8
C)4/9
D)7/12
E)11/15
Rationale: Favorable case = a white marble is removed in the 2nd try or later.
Unfavorable case = a white marble is removed on the first attempt.
Probability = Favorable outcomes / Total out comes
Also probability = 1-(Unfavorable outcomes / Total out comes)
Unfavorable case: probability of apple picked in first extraction = 8/30
Total Unfavorable Probability = 4/15
i.e., Favorable Probability = 1 - (4/15) = 11/15
Answer Option: E
Answer: E
Question: A jar contains 16 marbles, of which 4 are red, 3 are blue, and the rest are yellow. If 2 marbles are to be selected at random from the jar, one at a time without being replaced, what is the probability that the first marble selected will be red and the second marble selected will be blue?
Options:
A)3/64
B)1/20
C)1/16
D)1/12
E)1/8
Rationale: Note that we want the first marble selected to be red and the second marble selected to be blue.
P=4/16*3/15=1/20.
Answer: B.
Answer: B
Question: The speed at which a man can row a boat in still water is 15 kmph. If he rows downstream, where the speed of current is 3 kmph, what time will he take to cover 30 metres?
Options:
A)6
B)8
C)12
D)4
E)13
Rationale: Speed of the boat downstream = 15 + 3 = 18 kmph
= 18 * 5/18 = 5 m/s
Hence time taken to cover 60 m = 30/5 = 6 seconds.
Answer: A
Answer: A
Question: A train 440 metres long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going ?
Options:
A)5 sec
B)6 sec
C)7 sec
D)24 sec
E)None
Rationale: Solution
Speed of train relative to man =(60+6) km/hr= 66km/hr
=(66x5/18) m/sec =(55/3) m/sec
∴ Time taken to pass the man = (440 x 3/55)sec = 24 sec
Answer D
Answer: D
Question: A car runs at the speed of 55 km per hour when not serviced and runs at 90 kmph when serviced. After servicing the car covers a certain distance in 3 hours. How much time will the car take to cover the same distance when not serviced?
Options:
A)8 hours
B)6 hours
C)9 hours
D)7 hours 12 minutes
E)None
Rationale: Explanation :
Time = 90*3 / 45 = 6 hours
Answer â€“ B
Answer: B
Question: A dealer purchases 15 articles for Rs. 25 and sells 12 articles for Rs. 30. Find the profit percentage?
Options:
A)25%
B)50%
C)20%
D)5%
E)None of these
Rationale: L.C.M of 15 and 12 = 60
CP of 60 articles = Rs. 100 (25 * 4)
SP of 60 articles = Rs. 150 (30 * 5)
Profit percentage = (150 - 100)/100 * 100 = 50%
ANSWER:B
Answer: B
Question: Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is?
Options:
A)36
B)45
C)48
D)49
E)51
Rationale: Relative speed = 60 + 90 = 150 km/hr.
= 150 * 5/18 = 125/3 m/sec.
Distance covered = 1.10 + 0.9 = 2 km = 2000 m.
Required time = 2000 * 3/125 = 48 sec.
ANSWER:C
Answer: C
Question: 5 points are marked on a straight line and another 6 points are marked on a second straight line with no points in common. How many triangles can be constructed with vertices from among the above points?
Options:
A)21
B)91
C)135
D)196
E)364
Rationale: Solution: select 2 from 5 and one from 6 + select 2 from 6 and 1 from 5
6C2*5C1 + 5C2*6C1
= 135
Answer : C
Answer: C
Question: 6/[(1/0.03) + (1/0.37)] = ?
Options:
A)0.004
B)0.16666
C)2.775
D)3.6036
E)36.036
Rationale: Approximate.
1/.03 = 100/3 = 33
1/.37 = 100/37 = 3
Denominator becomes 33 + 3 = 36
6/36 = .16666
Answer (B)
Answer: B
Question: The length of a rectangular plot is 10 meters more than its width. If the cost of fencing the plot at $15.50 per meter is $744, what is the length of the plot in meters?
Options:
A)11
B)13
C)15
D)17
E)19
Rationale: perimeter = 2L + 2W = 2L + 2(L-10) = 4L - 20
cost of fencing = (4L - 20) * 15.50 = 62L - 310 = 744
62L = 1054
L = 17 meters
The answer is D.
Answer: D
Question: In a hotel we can order two types of varieties, but we can make 9 more varieties in home. One can choose the four varieties with two from hotel as must. Find how many ways one can order.
Options:
A)14
B)15
C)36
D)28
E)29
Rationale: 2c2*9c2=36ways
ANSWER:C
Answer: C
Question: mr. depak has $439,774 in his bank account. What is the least amount of money (in whole number of dollars) that he must add to his account if he wants to split this money evenly among her six best friends?
Options:
Options:
A)$1
B)$2
C)$3
D)$4
E)$6
Rationale: To find the least amount deepak should add to his saving account to split the money evenly among his 6 best friends,
he needs to make the total divisible by 6
Simply add the individual digits of the total = 4+3+9+7+7+4 = 34
If you add 2 , the number is divisible by 6 (34+ 2)
Correct Option : B
Answer: B
Question: A straight line has a slope of 1/2 and a y-intercept of -2. On this line, what is the x-coordinate of the point whose y-coordinate is 10?
Options:
A)(8)
B)(12)
C)(13)
D)(16)
E)(24)
Rationale: For the point intercept form of a line y=mx+b ; m is the slope and (b=y when x=0)
Slope=y2−y1/ x2−x1
we are given slope =1/2
y intercept is always equal to b when x = 0 (therefore at origin we can always write any (x,y) pair as (0,b)
y intercept hence (b) is given -2
now we have got all the values that we want to calculate slope
1/2=10−(−2)/x−0
1/2=10+2/x==>1/2=12/x==>x=24
CORRECT ANSWER IS E
Answer: E
Question: A hiker walking at a constant rate of 4 kilometers per hour is passed by a cyclist travelling in the same direction along the same path at a constant rate of 30 kilometers per hour. The cyclist stops and waits for the hiker 5 minutes after passing her while the hiker continues to walk at her constant rate. How many minutes must the cyclist wait until the hiker catches up?
Options:
A)7.5
B)15
C)17.5
D)25
E)32.5
Rationale: In 5 minutes, the cyclist travels a distance of (5/60)*30 = 2.5 km.
The time it takes the hiker to complete this distance is 2.5/4 hours = 37.5 minutes
The cyclist needs to wait 37.5 - 5 = 32.5 minutes
The answer is E.
Answer: E
Question: The value of 489.1375 x 0.0483 x 1.956/0.0873 x 92.581 x 99.749 is closest to:
Options:
A)0.48
B)5.8
C)0.58
D)0.058
E)0.0058
Rationale: = 489.1375 x 0.0483 x 1.956/0.0873 x 92.581 x 99.749
= 489 x 0.05 x 2/0.09 x 93 x 100
= 489/9 x 93 x 10
= 163/279 x 1/10
= 0.58/10
= 0.058 (or) 0.06.
Answer is D.
Answer: D
Question: The ratio of cats to dogs to birds to fish is 3:4:5:6. There are no other types of animals in the pet store. which of the following cannot be the total number of animals in the store?
Options:
A)36
B)54
C)72
D)90
E)101
Rationale: The parts add up to 3 + 4 + 5 + 6 = 18, so we know that any possible number of total answers must be a multiple of 18. All five answer choices are multiples of 18:
(A) 36 = 18*2
(B) 54 = 18*3
(C) 72 = 18*4
(D) 90 = 18*5
(E) 101 = not a multiple of 18
ans is E
Answer: E
Question: . Mr.P and Mr.Q can build a wall in 10 days; Mr.Q & Mr.R can take 14 days to build the same wall; and Mr.P and Mr.R can do it in 8 days. Who among them will take more time when they work alone?
Options:
A)8.8
B)8.7
C)1.3
D)8.6
E)8.5
Rationale: Answer: b
Explanation:
Let the total work be 280 units.
Now P and Q capacity per day = 280/10 = 28 units.
Q and R capacity per day =280/14 = 20 units
P and R capacity per day = 280/8 = 25 units.
Adding all the three,
2(P + Q + R) = 73 ⇒ P + Q + R = 36.5 units.
We are asked to find who will take maximum time. So the capacity is minimum. R capacity is minimum as (P + Q + R) - (P + R) = 36.5 - 28 = 8.5.
Answer:E
Answer: E
Question: If the cost price of 81 chocolates is equal to the selling price of 45 chocolates, the gain percent is :
Options:
A)80%
B)85%
C)82%
D)70%
E)75%
Rationale: Explanation :
Solution: Let C.P. of each chocolate be Re. 1. then, C.P. of 45 chocolates = Rs. 45;
S.P. of 45 chocolates =Rs. 81.
.'. Gain% = 36*100/45 = 80%
Answer : A
Answer: A
Question: In the xy-coordinate system, line k passes through points (-6m, 0) and (0, 3m). Which of the following is a possible equation of line k?
Options:
A)y = -2*x + 3m
B)y = 1/2*x - 6m
C)y = 3x + 3m
D)y = 1/2*x + 3m
E)y = -1/3*x - 6m
Rationale: The slope of the line is 3m/6m=1/2.
The y-intercept is 3m.
the equation of the line is: y = 1/2*x +3m
The answer is D.
Answer: D
Question: Look at this series: 1875000,375000,75000, ... What number should come next?
Options:
A)17
B)25000
C)15
D)18
E)8
Rationale: 25000
This is a simple division series. Each number is divided by 5.
ANSER B
Answer: B
Question: A and B started a business with their capitals Rs. 3000 and 9,000 respectively. Annual profit will be distributed between them in the ratio
Options:
A)2:7
B)1:9
C)1:3
D)2:3
E)1:5
Rationale: 3,000:9,000
Ans. 1:3
ANSWER:C
Answer: C
Question: In how many a committee of 5 members can be selected from 6men 5 ladies consisting of 3 men and 2 ladies
Options:
A)451
B)125
C)200
D)362
E)168
Rationale: (3 men out of 6) and (2 ladies out of 5) are to be chosen
Required number of ways
=(6C3 * 5C2)
= 200
Ans: C
Answer: C
Question: An empty wooden vessel weighs 8% of its total weight when filled with paint. If the weight of a partially filled vessel is one half that of a completely filled vessel, what fraction of the vessel is filled.
Options:
A)3/7
B)5/9
C)1/24
D)4/9
E)2/5
Rationale: An empty wooden vessel weighs 8% of its total weight when filled with paint:
Vessel = 0.08(Vessel + Paint);
8V = V + P (so the weight of completely filled vessel is 8V)
P = 7V (so the weight of the paint when the vessels is completely filled is 7V).
The weight of a partially filled vessel is one half that of a completely filled vessel:
V + P' = 1/2*8V;
P' = 3V (so the weight of the paint when the vessels is partially filled is 3V).
What fraction of the vessel is filled?
So, we need to find the ratio of the weight of the paint when the vessel iscompletely filledto the weight of the paint when the vessel ispartially filled:
P'/P = 3V/7V = 3/7.
Answer: A.
Answer: A
Question: Seven children — A, B, C, D, E, F, and G — are going to sit in seven chairs in a row. The children C & F have to sit next to each other, and the others can sit in any order in any remaining chairs. How many possible configurations are there for the children?
Options:
A)600
B)720
C)1440
D)4320
E)4800
Rationale: for such questions , we can treat both as one then total person=6..
these 6 can be arranged in 6! ways.. but within these 6 , one consists of two people who can be arranged in 2 ways CF or FC.. so ans =6!*2=1440
ans C
Answer: C
Question: In a stack of cards, 7 cards are blue and the rest are red. If 2 cards are to be chosen at random from the stack without replacement, the probability that the cards chosen will both be blue is 4/5. What is the number of cards in the stack?
Options:
A)8
B)11
C)12
D)15
E)18
Rationale: This question can be solved by TESTing THE ANSWERS.
We're told that we have 7 blue cards and an unknown number of red cards. We're also told that if 2 cards are to be chosen at random from the stack WITHOUT replacement, then the probability that the cards chosen will BOTH be BLUE is 4/5. We're asked for the TOTAL number of cards.
Normally, when TESTing THE ANSWERS,
Answer A: 8 total cards
With 8 total cards, and 7 blue cards, the probability of pulling two blue cards is...
(7/8)(6/7) = 42/56
Since 4/5 = 0.75, this is clearly the answer.
A
Answer: A
Question: How many numbers with 1 different digits can be formed using only the odd digits?
Options:
A)10
B)20
C)4
D)60
E)120
Rationale: Odd digits are 2, 4, 6, 8.
We want 3 different digits.
First digit can be chosen in 4 ways.
Total ways = 4
= 4
Hence option (C).
Answer: C
Question: A Man can row upstream at 55kmph and downward stream at 47 kmph. Find Man's rate of the current
Options:
A)87km/hr
B)20km/hr
C)65km/hr
D)2.8km/hr
E)4km/hr
Rationale: Rate of the current=1/2(55-47)km/hr
=4km/hr
correct option is :E
Answer: E
Question: A bag contains 5 white balls, 4 black balls, and 3 red balls. One by one, three balls are drawn out without replacement. What is the probability that the third ball is red?
Options:
A)1/2
B)1/4
C)3/8
D)5/16
E)2/5
Rationale: The probability for each ball to be drawn third is equal.
Then the probability a red ball is drawn third is 3/12 = 1/4.
The answer is B.
Answer: B
Question: a ladder is 100 m long and distance between bottom of the ladder and wall is 60m.what is the maximum size of the cube that can be placed between the wall and the ladder.
Options:
A)40
B)45
C)50
D)55
E)60
Rationale: side of the cube is 40m
AB-WALL
BC- DISTANCE BETWEEN WALL AND LADDER FOOT=60m
AC-LADDER=100m
SO AB=SQ.RT (AC^2-BC^2)=80m
Area of triangle ABC=1/2*b*h=2400 sq. m
lasrgest possible square will be of area 1600sq. m
so side =40m
ANSWER:A
Answer: A
Question: 5 and 15 are the first two terms in a geometric sequence. What is the arithmetic difference between the 9th term and the 7th term?
Options:
A)3*5^2
B)5* 3^13 - 5 * 3^11
C)40 * 3^7
D)40 * 3^10
E)3^12 - 3^10
Rationale: Common ratio = 15/5 =3
7th term = 5*3^7
9th term = 5*3^9
Difference = 5 * (3^9 - 3^7)
= 5 * 3^7 *(3^2 - 1)
= 5 * 3^7 * 8
= 40 * 3^7....
C
Answer: C
Question: David works at a science lab that conducts experiments on bacteria. The population of the bacteria multiplies at a constant rate, and his job is to notate the population of a certain group of bacteria each hour. At 1 p.m. on a certain day, he noted that the population was 500 and then he left the lab. He returned in time to take a reading at 4 p.m., by which point the population had grown to 13,500. Now he has to fill in the missing data for 2 p.m. and 3 p.m. What was the population at 3 p.m.?
Options:
A)6500
B)3500
C)2500
D)4500
E)2000
Rationale: let the rate be x, then population of the bacteria after each hour can be given as 500,500x, 500(x^2), 500(x^3)
now population at 4pm =13,500
thus we have 500(x^3) = 13,500 =27
thus x=3
therefore population at 3pm = 500(9) = 4,500
Answer : D
Answer: D
Question: Find the roots of quadratic equation: x2 + x - 42 = 0?
Options:
A)-6, 7
B)-8, 7
C)14, -3
D)-7, 6
E)3, -14
Rationale: x2 + 7x - 6x + 42 = 0
x(x + 7) - 6(x + 7) = 0
(x + 7)(x - 6) = 0 => x = -7, 6
ANSWER:D
Answer: D
Question: There is a certain relation between two given words on one side of : : and one word is given on another side of : : while another word is to be found from the given alternatives, having the same relation with this word as the given pair has.
Options:
A)Landslides
B)Strains
C)Resistances
D)Volcanoes
E)Volcanoe1
Rationale: Explanation:
Seismography is an instrument to measure the intensity of an earthquake.
Similarly, taseometer is an instrument to measure strains.
Answer: B) Strains
Answer: B
Question: Shreyas bought an article and sold it for 115% of its cost price. What was the cost price of the article, if Shreyas sold it for Rs.33750/-?
Options:
A)Rs.24600
B)Rs.29348
C)Rs.24250/-
D)Rs.23200
E)None of these
Rationale: Explanation:
115% of CP = Rs.33750
:. CP = Rs.33750x100/115 = Rs.29348.
Answer: Option B
Answer: B
Question: Suresh and Ramesh started a business investing Rs. 24,000 and Rs. 40,000 respectively. Out of total profit of Rs. 18,000, what is Suresh's share?
Options:
A)s. 6750
B)s. 7750
C)s. 8750
D)s. 9372
E)s. 9750
Rationale: Explanation:
Ratio of Suresh and Ramesh's share = 24,000 : 40,000 = 3 : 5
Suresh's share = Rs. (18000 x 3 / 8) = Rs. 6750
ANSWER: A
Answer: A
Question: How many zeroes are there at the end of the number N, if N = 80! + 160! ?
Options:
A)15
B)19
C)23
D)27
E)31
Rationale: The number of zeroes at the end of 80! will be less than the number of zeroes at the end of 160!
Hence it is sufficient to calculate the number of zeroes at the end of 80!
The number of zeroes = [80/5] + [80/25] + [80/125] = 16 + 3 + 0 = 19
The answer is B.
Answer: B
Question: If goods be purchased for Rs.840 and one-fourth be sold at a loss of 20% at what gain percent should the remainder be sold so as to gain 20% on the whole transaction?
Options:
A)33 1/6%
B)33 7/3%
C)33 1/3%
D)33 1/5%
E)33 2/3%
Rationale: 1/4 CP = 210 SP = 21*(80/100) = 168
SP = 840*(120/100) = 1008
1008 - 168 = 840
3/4 SP = 630
Gain = 210
630 --- 210
100 --- ? => 33 1/3%
Answer: C
Answer: C
Question: If the digits 33 in the decimal 0.00033 repeat indefinitely, what is the value of (10^5-10^3)(0.00033)?
Options:
A)0.33
B)33
C)0.033
D)0.0033
E)3.3e-05
Rationale: 99*0.33=32.67 approx. 33
Answer : B
Answer: B