divelab/Sys2Bench huggingface dataset:
Question: In a candy dish the ratio of red to yellow candies is 2:5, the ratio of red to green candies is 3:8, and the ratio of yellow ot blue candies is 9:2.what is the maximum total number R of yellow and green candies combined if the maximum combined number of red and blue candies is fewer than 85?
Options:
A)144
B)189
C)234
D)279
E)309
Rationale: Given that Red is to yellow is 2:5, Red is to green is 3:8 and Yellow is to blue is 9:2.
Therefore, the total number of red, yellow, blue and green balls will be 18x, 45x, 10x and 48x respectively, where x is a constant.
If the combined number of red and blue balls is fewer than 85, i.e. max 84 balls, then the maximum number of yellow and green balls will be 279.
(10x+18x) < 85.
28x < 85, i.e. 28x <= 84 (Since number of balls cannot be in fraction). Thus, x<=3.
(45x+48x) = 93x.
Max (93x) R= 279.
Answer is D.
Answer: D
Question: How many diagonals does a polygon with 23 sides have, if one of its vertices does not connect to any diagonal?
Options:
A)201
B)159
C)179
D)189
E)209
Rationale: If I calculate it using the formulae, #diagonals = n (n-3)/2Each vertex sends of n-3 diagonals
n= 23-1 then 22*(22-3)/2 = 209
Correct Option:E
Answer: E
Question: The difference between a five digit number and the number formed by reversing its digit is not a multiple of
Options:
A)2
B)4
C)3
D)1749
E)5
Rationale: Another approach is to TEST a number.
Let's say the original number is 12345
So, the REVERSED number is 54321
The DIFFERENCE = 54321-12345 =41976
No check the answer choices
41976 is a multiple of2,3,4,1749
5 is NOT a multiple of 41976
Answer:E
Answer: E
Question: Exactly 3/7 of the people in the room are under the age of 21, and exactly 5/14 of the people in the room are over the age of 65. If the total number of the people in the room is greater than 50 and less than 100, how many people in the room are under the age of 21?
Options:
A)21
B)35
C)39
D)42
E)65
Rationale: The total number of the people in the room must be a multiple of both 7 and 14 (in order 3/7 and 5/14 of the number to be an integer), thus the total number of the people must be a multiple of LCM of 7 and 14, which is 98.
Since, the total number of the people in the room is greater than 50 and less than 100, then there are 98 people in the room.
Therefore there are 3/7*98=42 people in the room under the age of 21.
Answer: D.
Answer: D
Question: A sum of money placed at C.I. interest doubles itself in 5 years. It will amount to eight times itself at the same rate of interest in?
Options:
A)11
B)88
C)15
D)27
E)20
Rationale: P(1 + R/100)5 = 2P => (1 + R/100)5 = 2
Let P(1 + R/100)n = 8P
=> (1 + R/100)n = 8 = 23 = {(1 + R/100)5}3
=> (1 + R/100)n = (1 + R/100)15 => n = 15 Required time = 15 years.
Answer: C
Answer: C
Question: Of all the students in a certain dormitory, 1/2 are first-year students and the rest are second-year students. If 4/5 of the first-year students have not declared a major and if the fraction of second-year students who have declared a major is 1/2 times the fraction of first-year students who have declared a major, what fraction of all the students in the dormitory are second-year students who have not declared a major?
Options:
A)1/15
B)1/5
C)9/20
D)1/3
E)2/5
Rationale: tot students=x
1st year student=x/2----> non majaor=4/5(x/2)-----> maj=1/5(x/2)
2nd year student=x/2---->maj=1/2(1/5(x/2))=1/20(x)--->non major=x/2-1/20(x)=9/20(x)
hence 9/20
C
Answer: C
Question: A television manufacturer produces 600 units of a certain model each month at a cost to the manufacturer of £90 per unit and all of the produced units are sold each month. What is the minimum selling price per unit that will ensure that the monthly profit (revenue from sales minus production costs) on the sales of these units will be at least £42,000?
Options:
A)£110
B)£120
C)£140
D)£160
E)£180
Rationale: Explanation:
Let's say x is the amount that the manufacturer sells each unit for, then the profit per unit can be expressed as x-90. We also know that 600 units have been produced and that the total profit has to be at least £42,000.
600(x-90)≥42,000
x-90≥70
x≥160
Answer: Option D
Answer: D
Question: Find out the wrong number in the given sequence of numbers.
1, 2, 6, 15, 31, 55
Options:
A)55
B)6
C)15
D)31
E)91
Rationale: 1(result) + (1*1) = 2.
2(result) + (2*2) = 6.
6(result) + (3*3) = 15.
15(result) + (4*4) = 31.
31(result) + (5*5) = 56.
Now we are getting 56 not 55.. So 55 is the wrong number of the given.
answer : A
Answer: A
Question: The distance between A&B is 1540km. A person is traveling from A to B at 100km/hr started at 6AM and another person is traveling from B to A at 120km/hr and started at same time. Then at what time they meet together.
Options:
A)11AM
B)1PM
C)3PM
D)10AM
E)9AM
Rationale: Let x hours be they will meet together
distance covered by 1st person+distance covered by 2nd person = 1540km
100x+120x = 1540
x= 7 hr
They will meet = 6AM +7hr = 1PM
Answer is B
Answer: B
Question: Favid has d books, which is 3 times as many as Jeff and 1/2 as many as Paula. How many books do the three of them have altogether, in terms of d?
Options:
A) 5/6*d
B) 7/3*d
C) 10/3*d
D) 7/2*d
E) 9/2*d
Rationale: Favid has d books;
Jeff has d/3 books;
Paula has 2d books;
Total = d+d/3+2d=10d/3.
Answer: C.
Answer: C
Question: find the next term 2,5,26...
Options:
A)27
B)45
C)455
D)555
E)677
Rationale: 2
2*2+1=5
5*5+1=26
26*26+1=677
ans=677
ANSWER:E
Answer: E
Question: A man walking at a rate of 10km/hr crosses a bridge in 12 minutes. The length of the bridge is?
Options:
A)2000
B)1492
C)1667
D)1254
E)1112
Rationale: Speed = 10*5/18 = 50/18 m/sec
Distance covered in 10minutes = 50/18 *12 *60 = 2000 m
Answer is A
Answer: A
Question: Which of the following CANNOT be the least common multiple of two positive integers x and y
Options:
A)xy
B)x
C)y
D)x + y
E)x - y^2
Rationale: The least common multiple of two positive integers cannot be less than either of them. Therefore, since x - y^2 is less than x, it cannot be the LCM of a x and y.
Answer: E
Answer: E
Question: Look at this series: 3, 4, 7, 8, 11, 12, ... What number should come next?
Options:
A)15
B)14
C)17
D)12
E)19
Rationale: This alternating addition series begins with 3; then 1 is added to give 4; then 3 is added to give 7; then 1 is added, and so on.
ANSWER A
Answer: A
Question: Which of the following numbers is not prime?
Options:
A)50+70
B)150 -23
C)100+67
D)156-7
E)103+36
Rationale: 10 can be factored out of both 50 and 70. -->50+70= 10*(5+7). The correct answer is A.
Answer: A
Question: Ram can finish a puzzle in 3 hours and Shyam can do the same in 2 hours. Both of them finish the puzzle and get 15 candies. What is Ram’s share?
Options:
A)6
B)7
C)5
D)8
E)9
Rationale: Explanation:
The question is based on efficiency to do work.
Ram can finish a puzzle in 3 hours. Shyam can finish the puzzle in 2 hours.
=>In one hour Ram can finish 1/3rd of a puzzle
=>In one hour Shyam can finish half the puzzle
A total of 15 candies are to be shared amongst both of them
Hence Ram’s share must be = ((Work done by Ram in 1 hour)/(Work done by Shyam in one hour)+(Work done by Ram in hour))*15
=> 1/3/((1/2)+(1/3))*15
=> (1/3/(5/6))*15
=> 6/15*(15)
=>6 candies
ANSWER: A
Answer: A
Question: The cost of 10 packets of sugar, each weighing 900 grams is Rs. 28. What will be the cost of 27 packets, if each packet weighs 1 kg?
Options:
A)Rs 52.50
B)Rs 56
C)Rs 58.50
D)Rs 84
E)None of these
Rationale: Explanation :
Let the required cost be Rs. x. Then,
More packets, More cost (Direct Proportion)
More weight, More cost (Direct Proportion)
Packets 10 : 27
Weight 900 : 1000 :: 28 : x
(10 x 900 x x) = (27 x 1000 x 28)
x = (27 x 1000 x 28) /10 x 900
= 84
Answer D
Answer: D
Question: Rs.3080 were divided among Jonathan, Kevin & Dawson in such a way that John had Rs.160 more than Kevin and Dawson had Rs 120 more than John . How much was Kevinâ€™s share?
Options:
A)Rs.1120
B)Rs.1130
C)Rs.1140
D)Rs.1150
E)Rs.1160
Rationale: Let Kevin gets Rs x. Then We can say Jonathan gets Rs (x + 160 ) and Dawson gets Rs ( x + 280) .
x + 160 + x + x + 280 = 3080
3x = 2640
x = 880 .
Kevinâ€™s share = Rs ( 880+280 ) = Rs.1160
E
Answer: E
Question: A furniture store bought chairs for 60% of their list price and sold them for 10% off the list price. What is their percent gain?
Options:
A)25
B)50
C)60
D)75
E)110
Rationale: Cost = 60% of List Price = .6*LSale = (100-10)% of List Price = .9*LGain Ratio = (Sale - Cost) / Cost = (.9*L - .6*L) / .6*L = .3*L / .6*L = 0.50Gain Percent = 100 * Gain Ratio = 100 * 0.5 = 50% = Answer B
Answer: B
Question: The area of a square garden is A square feet and the perimeter is p feet. If a=2p+26.25, what is the perimeter of the garden, in feet?
Options:
A)28
B)36
C)40
D)42
E)64
Rationale: Perimeter of square = P
Side of square = P/4
Area of Square = (P^2)/16 =A
Given that A = 2P + 26.25
(P^2)/16 = 2P + 26.25
P^2 = 32P + 420
P^2 -32P -420 = 0
P^2 -42P +10 P -420 = 0
P(P-42)+10(P+42) = 0
(P-42)(P+10) = 0
P = 42 or- 10
Discarding negative value , P = 42
Answer is D
Answer: D
Question: What is the greatest integer m for which the number 20!/10^m is an integer?
Options:
A)3
B)4
C)5
D)6
E)7
Rationale: 10^m = 2^m*5^m.
Let's figure out how many 5's are in the prime factorization of 20!
The multiples of 5 are: 5, 10, 15, 20.
Thus 5^4 will divide 20! but 5^5 will not.
Clearly 2^4 will divide 20!
So m=4 is the largest possible integer.
The answer is B.
Answer: B
Question: Tough and Tricky questions: Word Problems.
A salesman's income consists of commission and base salary. His weekly income totals over the past 5 weeks have been $406, $413, $420, $436 and $395. What must his average (arithmetic mean) income over the next five weeks be to decrease his average weekly income to $400 over the 10-week period?
Options:
A)$385
B)$356
C)$367
D)$376
E)$386
Rationale: OFFICIAL SOLUTION:
(E) First, we need to add up the wages over the past 5 weeks: $406 + $413 + $420 + $436 + $395 = $2070.
To average $400 over 10 weeks, the salesman would need to earn: $400 × 10 = $4000.
Subtract $2070 from $4000 to determine how much he would need to earn, in total, over the next 5 weeks to average $400 for the 10 weeks: $4000 – $2070 = $1930.
Dividing $1930 by 5 will give us the amount he needs to earn on average over the next 5 weeks: $1930/5 = $386.
The correct answer is choice (E).
Answer: E
Question: What is the square root of 16, divided by 2?
Options:
A)9
B)2
C)122
D)6
E)1
Rationale: Square root is a number times itself
Square root of 16=4, 4/2=2
(B)2
Answer: B
Question: One-sixth of the light switches produced by a certain factory are defective. Four-fifths of the defective switches are rejected and 1/15 of the non defective switches are rejected by mistake. If all the switches not rejected are sold, what percent of the switches sold by the factory are defective?
Options:
A)1.8%
B)2.9%
C)4.1%
D)5.6%
E)6.4%
Rationale: 1/6 of the switches are defective.
The defective switches that are not rejected are 1/5*1/6 = 1/30 = 3/90 of all switches.
The non defective switches that are sold are 5/6*14/15 = 70/90 of all switches.
The percent of switches sold that are defective is 3/73 which is about 4.1%.
The answer is C.
Answer: C
Question: If 5 spiders make 5 webs in 5 days, then 1 spider will make 1 web in how many days?
Options:
A)7
B)6
C)5
D)4
E)3
Rationale: Let the required number days be x.
Less spiders, More days (Indirect Proportion)
Less webs, Less days (Direct Proportion)
spiders 1:5
Webs 5:1
1 x 5 x x = 5 x 1 x 5
=> x= 5
Answer is C
Answer: C
Question: P and Q can do a work in 30 days. Q and R can do the same work in 24 days and R and P in 20 days. They started the work together, but Q and R left after 6 days. How many days more will P take to finish the work?
Options:
A)30
B)15
C)18
D)20
E)22
Rationale: Let work done by P in 1 day = p,
Work done by Q in 1 day = q,
Work done by R in 1 day = r
p + q = 1/30
q + r = 1/24
r + p = 1/20
Adding all the above, 2p + 2q + 2r = 1/30 + 1/24+ 1/20 = 15/120 = 1/8
=> p + q + r = 1/16
=> Work done by P,Q and R in 1 day = 1/16
Work done by P, Q and R in 6 days = 6 × (1/16) = 6/16 = 3/8
Remaining work = 1 = 3/8 = 5/8
Work done by P in 1 day = Work done by P,Q and R in 1 day - Work done by Q and R in 1 day
= 1/16 – 1/24 = 1/48
Number of days P needs to work to complete the remaining work = (5/8) / (1/48) = 30
Option A
Answer: A
Question: If p and q are positive integers each greater than 1, and 17(p+1)=28(q+1), what is the least possible value of p+q?
Options:
A)36
B)42
C)44
D)43
E)none
Rationale: 17(p+1)=29(q+1) --> (p+1)/(q+1) = 28/17 --> the least positive value of p+1 is 28, so the least value of p is 27 and the least positive value of q+1 is 17, so the least value of q is 16 --> the least value of p+q is 27+16=43.
Answer: D
Answer: D
Question: An article is bought for Rs.1000 and sold for Rs.1100, find the gain percent?
Options:
A)33 1/7%
B)10%
C)33 1/3%
D)38 1/3%
E)33 2/3%
Rationale: 1000 ---- 100
100 ---- ? => 10%
Answer:B
Answer: B
Question: By selling a watch for Rs.800/-, a man loses 20% what is that watch cost price?
Options:
A)s. 600/-
B)s. 700/-
C)s. 800/-
D)s. 850/-
E)s. 1000/-
Rationale: 80 % ------> 800 (80 * 10 = 640)
100 % ------>1000 (100 * 10 = 1000)
Cost price = Rs. 1000/-
E)
Answer: E
Question: 85% of a number is added to 24, the result is the same number. Find the number?
Options:
A)257
B)267
C)187
D)160
E)122
Rationale: (85/100) * X + 24 = X
3X = 480
X = 160
Answer:D
Answer: D
Question: A dealer offers a cash discount of 20% and still makes a profit of 20%, when he further allows 16 articles to a dozen to a particularly sticky bargainer. How much percent above the cost price were his wares listed?
Options:
A)100%
B)80%
C)75%
D)66(2/3)%
E)NOne
Rationale: Solution: Let the CP of the article be Rs. x, since he earns a profit of 20%, hence SP= X + 20% of X = 1.2x.
It is given that he incurs loss by selling 16 articles at the cost of 12 articles [loss = (16-12)/16 = 25%]
His selling price = SP - 25% of SP = SP*0.75;
Hence, SP*0.75 = 1.2X.
Or, SP = (1.2*x/0.75) = 1.6X.
This SP is arrived after giving a discount of 20% on MP.
Let MP = Y.
Y - 20% of Y = SP
0.80Y = 1.6X.
Y = 2X.
It means that the article has been marked 100% above the cost price. Or Marked Price was twice of cost price.
Answer: Option A
Answer: A
Question: At present, the ratio between the ages of Shekhar and Shobha is 4:3. After 6 years, Shekhar's age will be 26 years. Find out the age of Shobha at present?
Options:
A)10
B)12
C)14
D)15
E)20
Rationale: After 6 years, Shekhar's age will be 26 years
Therefore, Present age of Shekhar =26−6=20
Let present age of Shobha =x
Then,
20x=43x=20×34=15
Answer is D.
Answer: D
Question: The length of a train and that of a platform are equal. If with a speed of 90 k/hr, the train crosses the platform in one minute, then the length of the train (in meters) is?
Options:
A)177
B)156
C)199
D)750
E)155
Rationale: Speed = [90 * 5/18] m/sec = 25 m/sec; Time = 1 min. = 60 sec.
Let the length of the train and that of the platform be x meters.
Then, 2x/60 = 25 è x = 25 * 60 / 2 = 750
Answer:D
Answer: D
Question: P can complete a work in 12 days working 8 hours a day. Q can complete the same work in 8 days working 10 hours a day. If both P and Q work together, working 8 hours a day, in how many days can they complete the work?
Options:
A)5
B)5 3/5
C)5 5/7
D)6
E)None
Rationale: P can complete the work in (12 x 8) hrs. = 96 hrs.
Q can complete the work in (8 x 10) hrs. = 80 hrs.
P's1 hour's work =	1	and Q's 1 hour's work =	1	.
96	80
(P + Q)'s 1 hour's work = 1	+	1 =	11	.
96	80	480
So, both P and Q will finish the work in 480 hrs.
11
Number of days of 8 hours each = 480	x	1 =	60	days = 5	5	days.
11	8	11	11
Option C
Answer: C
Question: A train 280 m long, running with a speed of 63 km/hr will pass a tree in?
Options:
A)21
B)16
C)18
D)12
E)112
Rationale: Speed = 63 * 5/18 = 35/2 m/sec
Time taken = 280 * 2/35 = 16 sec.Answer: B
Answer: B
Question: Let a be a positive integer. If e is divisible by 2^a and e is also divisible by 3^(2a), then it is possible that e is NOT divisible by
Options:
A)6
B)3 × 2^a
C)2 × 3^(2a)
D)6^a
E)6^(2a)
Rationale: Since, e is divisible by 2^a and 3^(2a), it must be divisible by 6. As least value of a = 1
Only for E, 6^(2a) doesn't satisfy, if a = 1 and e=18, it is not divisible by 6^2 (i.e 36)
Hence answer is E
Answer: E
Question: If 0.20: x : : 4 : 2, then x is equal to
Options:
A)0.2
B)0.3
C)0.1
D)0.5
E)None
Rationale: Sol.
(x×4) = (0.20×2) ⇒ x = 0.4/4 = 0.1.
Answer C
Answer: C
Question: Today Mary’s father is four times as old as Mary. Ten years ago, he was 14 times as old. How old is Mary today?
Options:
A)7
B)9
C)11
D)13
E)15
Rationale: Dad's age = 4M
14*(M-10) = 4M-10
10M = 130
M = 13
The answer is D.
Answer: D
Question: A father is two times as old as his daughter. 2 decades ago, the age of the father was 12 times the age of the daughter. The current age of the father is
Options:
A)44 years
B)43 years
C)42 years
D)48 years
E)49 years
Rationale: A
44 years
Let daughter’s age = A.
Then father’s age = 2A
12 (A – 20) = (2A – 20)
10A = 220
A = 22
Father’s current age = 44 years.
Answer: A
Question: John,Anny, Markov, David and Philip line up at a theatre ticket window. In how many ways can they arrange themselves so that philip is second in line from the window?
Options:
A)a 24
B)b 12
C)c 9
D)d 6
E)e 3
Rationale: A
Philip's position is fixed. Now we need to arrange all others around philip.
There are 4x3x2x1= 24 ways to arrange four people.
Answer: A
Question: A bat is bought for Rs.430 and sold at a gain of 20% find its selling price
Options:
A)s.430/-
B)s.480/-
C)s.400/-
D)s.516/-
E)s.616/-
Rationale: 100 % ------> 430
120 % ------> 430*120/100
Selling price = Rs.516
D
Answer: D
Question: Average of all prime numbers between 30 to 50
Options:
A)37
B)37.8
C)39
D)39.8
E)None of these
Rationale: Explanation:
Prime numbers between 30 and 50 are:
31, 37, 41, 43, 47
Average of prime numbers between 30 to 50 will be
(31+37+41+43+475)=1995=39.8
Answer: Option D
Answer: D
Question: Water tax is increased by 40% but its consumption is decreased by 40%. The increase or decrease in the expenditure is?
Options:
A)16% decrease
B)16% increase
C)8% decrease
D)8% increase
E)None of these
Rationale: Since Tax x Consumption = Expenditure .
Therefore, Net % change in expenditure
= ( x + y + xy/100) %
= [40 - 40 + (40 x - 40)/100]% or -16%.
Therefore, expenditure decreased by 16%.
ANSWER:A
Answer: A
Question: The speed of light is approximately 93 * 10^5 miles per second. This approximate speed is how many miles per hour?
Options:
A) 3,35 * 10^8
B)70 * 10^7
C) 11 * 10^8
D) 16 * 10^8
E) 70 * 10^8
Rationale: The easiest way to answer this question is by POE, it does not require any calculation (answered in 30seconds). In one hour there are 3600 seconds, therefore speed in miles/hour will be.
(.93*10^5)*3600 = (.93*10^5)*(3.6*10^3) = some number*10^8...
The key is realizing that thesome numberhas to be bigger thatn .93(because .93*3.6), and the only answer that fits that is A
Answer: A
Question: A man can row upstream at 25 kmph and downstream at 35 kmph, and then find the speed of the man in still water?
Options:
A)30 kmph
B)10 kmph
C)5 kmph
D)25 kmph
E)30 kmph
Rationale: Explanation:
US = 25
DS = 35
M = (35 + 25)/2 = 30 kmph
Answer: A
Answer: A
Question: Bernice's income is 70 percent more than Cathy's income, and Cathy's income is 65 percent less than Camilla's income. What percent of Camilla's income is Bernice's income?
Options:
A)54.5%
B)52.5%
C)59.5%
D)51.5%
E)55.5%
Rationale: Camilla's income = 100 (assume);
Cathy's income = 35 (65 percent less than Camilla's income);
Bernice's income = 59.5 (70 percent more than Cathy's income).
Thus, Bernice's income (59.5) is 59.5% of Camilla's income (100).
Answer: C
Answer: C
Question: A popular website requires users to create a password consisting of the digits {1,2,3,4,5,6,7,8}. If no digit may be repeated and each password must be at least 7 digits long, how many passwords are possible?
Options:
A)7! + 8!
B)2 x 8!
C)7! x 8!
D)15!
E)16!
Rationale: If we choose the 8 different digits then they can be arranged in 8! ways.
The number of possible 7-digit passwords is 8*...*2 = 8!
The total number of passwords is 8! + 8! = 2*8!
The answer is B.
Answer: B
Question: In baseball, the batting average is defined as the ratio of a player’s hits to at bats. If a player had anywhere from 6 to 9 at bats in a recent game and had anywhere from 4 to 5hits in the same game, the player’s actual batting average for that game could fall anywhere between
Options:
A)0.25 and 1.50
B)0.25 and 0.75
C)0.30 and 1.00
D)0.30 and 0.50
E)0.56 and 0.66
Rationale: Average Range = Hits to Bats i.e 4/9 to 5/6 = 0.44 to 0.83
Answer: C
Answer: C
Question: Q, B, C are three consecutive positive integers (Q>B>C). What is the value of the expression 2Q +B +3C?
Options:
A)6A+7.
B)5A+1.
C)5A-1.
D)6A-5.
E)6Q-7.
Rationale: => Q+Q+(Q-1)+3(Q-2)
Ans E. 6Q-7.
Answer: E
Question: At the end of a business conference the 18 people present all shake hands with each other once. How many handshakes will there be altogether ?
Options:
A)20
B)45
C)153
D)90
E)95
Rationale: number of handshakes = 18C2= 18*17/2 = 153
ANSWER:C
Answer: C
Question: If the sum of three consecutive even numbers is 24 more than the average of these numbers, then the largest of these numbers is?
Options:
A)10
B)12
C)14
D)16
E)17
Rationale: Explanation:
Let the smallest of these number be x. The other two numbers are (x + 2) and (x + 4).
x + (x + 2) + (x + 4) = (X + (X+2) + (x+4)) / 3 + 24
3x + 3*(x + 2) + 3*(x + 4) = x + (x + 2) + (x + 4) + 72
9x + 18 = 3x + 78
6x = 60
x = 10
Therefore, the largest number is 14.
ANSWER C
Answer: C
Question: Aaron will jog from home at 6 miles per hour and then walk back home by the same route at 12 miles per hour. How many miles from home can Aaron jog so that he spends a total of 3 hours jogging and walking?
Options:
A)12
B)14
C)16
D)15
E)11
Rationale: xyt/(x+y)
x= 6, y=12 t= 3
6*12*3/6+12 = 12
Answer : A
Answer: A
Question: How many digits are there to the right of the decimal point in the product of .32546 and 75.21 ?
Options:
A)7
B)6
C)8
D)2
E)9
Rationale: Product of is .32546 and 75.21 is 24.4778466.
Therefore number of digits to right of decimal point is 7
Answer is A.
Answer: A
Question: Paul is going with 5 friends on a trip to Rome for spring break. Airfare and hotel costs a total of $3600.00 for the group of 6 friends. How much does each person have to pay for their hotel and airfare?
Options:
A)$400
B)$500
C)$600
D)$660
E)$680
Rationale: Answer= C
The total cost of the trip ($3600.00) divided by 6 equals $600.00.
Answer: C
Question: The sum of the present ages of two persons A and B is 60. If the age of A is twice that of B, find the sum of their ages 5 years hence?
Options:
A)58
B)59
C)62
D)70
E)74
Rationale: Explanation:
A + B = 60, A = 2B
2B + B = 60 => B = 20 then A = 40.
5 years, their ages will be 45 and 25.
Sum of their ages = 45 + 25 = 70.
D)
Answer: D
Question: A man can row 30 km downstream and 20 km upstream in 4 hours. He can row 45 km downstream and 40 km upstream in 7 hours. Find the speed of man in still water?
Options:
A)12.2
B)12.9
C)12.6
D)12.5
E)12.3
Rationale: Let the speed of the man in still water be a kmph and let the speed of the stream be b kmph.
Now 30/(a + b) + 20/(a - b) = 4 and 45/(a + b) + 40/(a - b) = 7
Solving the equation, the speed of man in still water is 12.5 kmph.
Answer: D
Answer: D
Question: In a sequence of 40 numbers, each term, except for the first one, is 7 less than the previous term. If the greatest term in the sequence is 279, what is the smallest term in the sequence?
Options:
A)2
B)-2
C)0
D)8
E)6
Rationale: Which term is the greatest? The first or the last? It is given to you that every term is 7 less than the previous term. Hence as you go on, your terms keep becoming smaller and smaller. The first term is the greatest term.
An = 279 + (40 - 1)*(-7)
An = 279 - 273 = 6
E
Answer: E