divelab/Sys2Bench huggingface dataset:
Question: TOM has 13 ten-dollar bills, 11 five-dollar bills, and 17 one-dollar bills. If TOM needs to pay exactly $128, what is the least number of bills he will need to use?
Options:
A)557
B)456
C)16
D)577
E)586585
Rationale: 128 is the total sum of money.
as we have 13 10 dollar bills so the closest we can get to 128 using the 10 dollar bills is by using 12 * 10 dollar bils
128-120 = 8
so now we need to get 8 from either 5 dollar bills or 1 dollar bills
8 - 5 (use only 1 5 dollar bill) = 3
so we can get 3 from using 3 $1 bills.
Hence 16 ( 12+1+3 )
ANSWER IS C
Answer: C
Question: Which of the following is a composite number ?
Options:
A)2
B)7
C)15
D)13
E)19
Rationale: Clearly 15 is a composite number. All others are prime. Ans : C
Answer: C
Question: What is the least value of x, So that 2x5472 is divisible by 9
Options:
A)7
B)8
C)9
D)3
E)2
Rationale: Explanation:
The sum of the digits of the number is divisible by 9.
Then the number is divisible by 9.
2 + x + 5 + 4 + 7 + 2 = 20 + x
Least value of x may be '7',
So that the total 20 + 7 = 27
is divisible by 9.
Answer: Option A
Answer: A
Question: A searchlight on top of the watchtower makes 4 revolutions per minute. What is the probability that a man appearing near the tower will stay in the dark for at least 5 seconds?
Options:
A)5/6
B)4/5
C)3/4
D)2/3
E)1/2
Rationale: The searchlight completes one revolution every 15 seconds.
The probability that the man's area will be lit up is 5/15=1/3.
The probability that he will stay in the dark is 1-1/3=2/3
The answer is D.
Answer: D
Question: What could be the range of a set consisting of odd multiples of 3?
Options:
A)21
B)24
C)35
D)62
E)70
Rationale: Range = the difference between the greatest and the smallest numbers in the sequence. Our sequence is odd and is a multiple of 7. Every number in that sequence can be represented like this: 3*(2n+1) where n is any positive integer.
Range = 3*(2m + 1) - 3*(2n + 1) = 3*2*(m-n) = 6 * (m-n).
m, n - any positive integers
The answer must be divisible by 6, which is only 24.
The correct answer is B
Answer: B
Question: Marge has 3 pumps for filling her swimming pool. When all 3 pumps work at their maximum rates, the swimming pool is filled in 56 minutes. Pump 1's maximum rate is twice the maximum rate of pump 2 and four times the maximum rate of pump 3. How long would it take Marge to fill the pool if she used only pump 3 at its maximum rate ?
Options:
A)2hrs, 48mins
B)6hrs, 32mins
C)7hrs, 12mins
D)13hrs, 4mins
E)14hrs, 24mins
Rationale: The rate of pump 1 = 4x job/minute.
The rate of pump 2 = 2x job/minute.
The rate of pump 3 = x job/minute.
Given that x+2x+4x=1/56 --> x=1/392 --> (time) = (reciprocal of rate) = 392 minutes = 6 hours and 32 minutes.
Answer: B.
Answer: B
Question: The average age of three boys is 15 years and their ages are in proportion 3:5:7. What is the age in years of the youngest boy?
Options:
A)6
B)9
C)8
D)4
E)2
Rationale: 3x + 5x + 7x = 45
x =3
3x = 9
Answer: B
Answer: B
Question: If the price has fallen by 20% what percent of its consumption be: increased so that the expenditure may be the same as before?
Options:
A)A)11%
B)B)10%
C)1/9 %
D)1/11 %
E)1/4%
Rationale: 100 – 20 = 80
80------20
100------? => 1/4%
ANSWER:E
Answer: E
Question: Fill in the sequence:
10 10 22 9 24 8 26 ?
Options:
A)1
B)3
C)5
D)7
E)9
Rationale: D
7
There are two series - 20, 22, 24, 26 and 10, 9, 8, 7.
Answer: D
Question: The average of 10 numbers is calculated as 23. It is discovered later on that while calculating the average, one number namely 36 was wrongly read as 26. The correct average is?
Options:
A)A)16
B)B)18
C)C)19
D)D)22
E)E)24
Rationale: Explanation:
10 * 23 + 36 – 26 = 240=>240/10 = 24
E)
Answer: E
Question: If it is 7:03 in the evening on a certain day, what time in the morning was it exactly 1,440,706 minutes earlier? (Assume standard time in one location.)
Options:
A)7:09
B)7:11
C)7:17
D)7:22
E)7:34
Rationale: 7:03 minus 1,440,706 must end with 7, the only answer choice which ends with 7 is C.
Answer: C.
Answer: C
Question: If the selling price of 8 articles is same as the cost price of 12 articles. Find the gain or loss percentage?
Options:
A)30% gain
B)30% loss
C)50% gain
D)50% loss
E)60% loss
Rationale: Explanation:
Let the C.P of each article be Re 1. Then,
S.P of 8 articles = C.P of 12 articles = Rs. 12/-
Now, C.P of 8 articles = Rs. 8/-, S.p of 8 articles = Rs 12/-
Gain = Rs ( 12 - 10 ) = Rs 4/-.
Gain% = ( 4/8 * 100 ) % = 50% Gain
Answer: Option C
Answer: C
Question: A train started from station 'A' and proceeded towards station 'B' at a speed of 48 Km/hr. Forty-five minutes later another train started from station 'B' and proceeded towards station 'A' at 50 Km/hr. If the distance between the two stations is 232 Km, at what distance from station 'A' will the trains meet?
Options:
A)160KM
B)108KM
C)132KM
D)144KM
E)134KM
Rationale: Train A started 45 min ago,by the time train B started,
It means Distance covered by the Train A in 45 min is 48*45/60=36km covered,
now remaining distance=196km
since they are moving towards each other relative speed=48+50=98kmph
and time=196/98=2hrs
In 2hrs trainAcovered 96km distance and 36 km already covered
=>96=36=132km
Hence,132 km from station A, trains meet eachother.
ANSWER:C
Answer: C
Question: Find the coordinates
of the midpoint of the line segment joining the points
A(–3,2) and B(7,8)
Options:
A)(2,5)
B)(1,5)
C)(2,4)
D)(3,5)
E)(4,5)
Rationale: mid point of A(x1,y1) and B(x2,y2) can be calculated by
(x1+y1/2,x2+y2/2) hence ((-3+7)/2,(2+8)/2)=(2,5)
ANSWER:A
Answer: A
Question: A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 sec. The speed of the train is?
Options:
A)225 km/hr
B)50 km/hr
C)99 km/hr
D)88 km/hr
E)66 km/hr
Rationale: Speed of the train relative to man = 125/10 = 25/2 m/sec.
= 25/2 * 18/5 = 45 km/hr
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45 => x = 50 km/hr.
Answer: B
Answer: B
Question: A grocery store priced a gallon of milk at 25% above the wholesale price of $4. If a customer comes in with a coupon for 5% off milk, how much does that customer pay?
Options:
A)$4.95
B)$4.75
C)$5.05
D)$4.50
E)$5.25
Rationale: Wholesale cost of milk = $4
Milk was priced at 25% above $4 = $5
% discount given by coupon = 5%
Customer paid = .95 * 5 = $4.75
Answer B
Answer: B
Question: What sum of money will produce Rs.70 as simple interest in 4 years at 3 1/2 percent?
Options:
A)289
B)500
C)188
D)666
E)155
Rationale: 70 = (P*4*7/2)/100
P = 500
Answer:B
Answer: B
Question: If x and y are even integers, which of the following is an odd integer?
Options:
A)xy +3
B)x(y − 2)
C)x(x + 5)
D)3x + 4y
E)(x + 2)(y + 1)
Rationale: If a and b are even integers, then:
A. xy + 3: even + odd = odd
B. x(y− 2): even(even) = even
C. x(x+ 5): even(odd) = even
D. 3x + 4y: even + even = even
E. (x + 2)(y + 1): (even)(odd) = even
Answer is A
Answer: A
Question: If a number N is chosen at random from the set of two-digit integers whose digits are both prime numbers, what is the probability W that N is divisible by 3?
Options:
A)1/3
B)¼
C)9/25
D)5/16
E)0
Rationale: Prime digits are: 2, 3, 5, 7
Total number of 2 digit #s with both digits prime are: 4*4 = 16
out of these numbers divisible by 3 = 33, 27, 57, 72 and 75. I had to find the numbers manually using the 4 numbers above.
=> prob = 5/16.
Ans D. Took me 3:20 mins.
Answer: D
Question: In 2008, the profits of Company N were 10 percent of revenues. In 2009, the revenues of Company N fell by 20 percent, but profits were 10 percent of revenues. The profits in 2009 were what percent of the profits in 2008?
Options:
A)80%
B)105%
C)120%
D)124.2%
E)138%
Rationale: x = profits
r= revenue
x/r = 0,1
x= 10
r=100
2009:
r=80
x/80 = 0,10 = 10/100
x= 80*10/100
x= 8
8/10 = 0.8 = 800%, Answer A
Answer: A
Question: An order was placed for the supply of a carpet whose breadth was 6 m and length was 1.44 times the breadth. What be the cost of a carpet whose length and breadth are 40% more and 25% more respectively than the first carpet. Given that the ratio of carpet is Rs. 45 per sq m?
Options:
A)4882.40
B)8082.40
C)4002.40
D)4082.40
E)9082.40
Rationale: Explanation:
Length of the first carpet = (1.44)(6) = 8.64 cm
Area of the second carpet = 8.64(1 + 40/100) 6 (1 + 25/100)
= 51.84(1.4)(5/4) sq m = (12.96)(7) sq m
Cost of the second carpet = (45)(12.96 * 7) = 315 (13 - 0.04) = 4095 - 12.6 = Rs. 4082.40
Answer: Option D
Answer: D
Question: A cistern can be filled by a tap in 4 hours while it can be emptied by another tap in 7 hours. If both the taps are opened simultaneously, then after how much time will the cistern get filled?
Options:
A)9.5
B)9.4
C)9.3
D)9.2
E)9.1
Rationale: Net part filled in 1 hour = (1/4 - 1/7) = 3/28
The cistern will be filled in 28/3 hrs i.e., 9.3 hrs.Answer: C
Answer: C
Question: A dishonest person wants to make a profit on the selling of milk. He would like to mix water (costing nothing) with milk costing 33 $ per litre so as to make a profit of 70% on cost when he sells the resulting milk and water mixture for 36$. In what ratio should he mix the water and milk?
Options:
A)1:120
B)67:120
C)67:8
D)8:120
E)1:2
Rationale: First of all, let's consider 1 liter of the stuff he is going to sell --- naive customers think it's pure milk, but we know it's some milk-water mixture. He is going to sell this liter of milk-water for $36.
This $36 should be a 20% increase over cost. Here, we need to think about percentage increases as multipliers.
Using multipliers
(cost)*1.70 = $36
cost = 36/1.7= 360/12 = $30
If he wants a 70% increase over cost on the sale of one liter of his milk-water, the cost has to be $21.17
Well, a liter of milk costs $33, so if he is going to use just $30 of milk in his mixture, that's 21.17/33 = 120/187 of a liter. If milk is 120/87 of the liter, then water is 67/187 of the liter, and the ratio of water to milk is 67:120. Answer choice(B)
Answer: B
Question: The cost C, in dollars, to remove p percent of a certain pollutant from a pond is estimated by using the formula C = 100,000p/(100 - p). According to this estimate, how much more would it cost to remove 90 percent of the pollutant from the pond than it would cost to remove 60 percent of the pollutant?
Options:
A) $300,000
B) $100,000
C) $50,000
D) $10,000
E) $5,000
Rationale: To remove 90% of pollutant
C= 100,000(90)/(100-90) = 900,000
To remove 60% of pollutant
C' = 100,000(60)/(100-60) = 600,000
Difference = C - C' = 300,000
Answer - A
Answer: A
Question: A classroom has equal number of boys and girls. FIVE girls left to play kho-kho, leaving twice as many boys as girls in the classroom. What was the total number of girls and boys present initially?
Options:
A)16
B)24
C)32
D)48
E)20
Rationale: after 5 girls left remaining 5 girls
now boys 10 are twice as many as remaining girls.
initially boys=10 and girls=10.
ANSWER:E
Answer: E
Question: Without stoppages a train travels a certain distance with an average speed of 120 kmph and with stoppages it covers the same distance with an average speed of 90 kmph. What is the time in minutes per hour for which train stops?
Options:
A)5 min/hr
B)6 min/hr
C)12 min/hr
D)16 min/hr
E)15 min/hr
Rationale: Pick a smart number for the distance. lets say LCM 360
Without = 360/120 = 3 hours
With = 360/90= 4 hours
So in a trip of 4 hours, 1 hour is spent in stoppages
Hence, 60/4 = 15 min/hr on stoppages
Answer : E
Answer: E
Question: A number is increased by 60 % and then decreased by 60 %. Find the net increase or decrease per cent.
Options:
A)19%
B)18%
C)27%
D)33%
E)36%
Rationale: Let the number be 100.
Increase in the number = 60 % = 60 % of 100
= (60/100 Ã— 100)
= 60
Therefore, increased number = 100 + 60 = 160
This number is decreased by 60 %
Therefore, decrease in number = 60 % of 160
= (60/100 Ã— 160)
= 9600/100
= 96
Therefore, new number = 160 - 96 = 64
Thus, net decreases = 100 - 64 = 36
Hence, net percentage decrease = (36/100 Ã— 100) %
= (3600/100) %
= 36 %
Answer:E
Answer: E
Question: A fruit seller sells mangoes at the rate of Rs.13 per kg and thereby loses 25%. At what price per kg, he should have sold them to make a profit of 15%?
Options:
A)Rs.11.81
B)Rs.19.93
C)Rs.12.25
D)Rs.12.31
E)None
Rationale: Solution
75 : 13 = 115 : x
x= (13Ã—115/75)
= Rs.19.93
Hence, S.p per Kg	= Rs.19.93
Answer B
Answer: B
Question: Beverley rode 5 1/4 miles in 1 hours and 30 minutes. What was her average rate of speed in miles per hour?
Options:
A)3
B)3 1/4
C)3 1/2
D)3 3/4
E)4
Rationale: D = 5(1/4) = 21/4
T = 1(1/2) = 3/2 = 6/4
S = D/T = 3 3/4
Answer = D
Answer: D
Question: In a class of 50 students, 20 play SNOOKER, 15 play Cricket and 11 play Football. 7 play both SNOOKER and Cricket, 4 play Cricket and Football and 5 play SNOOKER and football. If 18 students do not play any of these given sports, how many students play exactly two of these sports?
Options:
A)10
B)12
C)34
D)45
E)566
Rationale: Notice that7 play both SNOOKER and Cricket does not mean that out of those 7, some does not play Football too. The same for Cricket/Football and SNOOKER/Football.
[color=#ffff00]{Total}={SNOOKER}+{Cricket}+{Football}-{HC+CH+HF}+{All three}+{Neither}For more check ADVANCED OVERLAPPING SETS PROBLEMS
[/color]
50=20+15+11-(7+4+5)+{All three}+18 --> {All three}=2;
Those who play ONLY SNOOKER and Cricket are 7-2=5;
Those who play ONLY Cricket and Football are 4-2=2;
Those who play ONLY SNOOKER and Football are 5-2=3;
Hence, 5+2+3=10 students play exactly two of these sports.
Answer: A.
Answer: A
Question: How many numbers from 2 to 8 are exactly divisible by 2?
Options:
A)A)2
B)B)4
C)C)5
D)D)7
E)E)8
Rationale: 2/2 = 1 and 8/2 = 4
4- 1 = 3
3 + 1 = 4 Numbers.
Answer : B
Answer: B
Question: If set A={2,2,2,....,n times} , set B={3,3,3,3....m times} and set C={13,13,13...k time} , then in terms of m,n and k , how many possible subsets from sets A,B, and C can be created ?
Options:
A)a) k(n+m+mn)+ k
B)b) (1+n+m+mn)(k+1)
C)c) k^2(mn+n/m)
D)d) kmn(k+m+n)
E)e) None of the above.
Rationale: a) how many 2's are included?
b) how many 3's are included?
and
c) how many 11's are included?
For the number of 2, we could have zero 2's, or one 2, or two 2's, all the way up to n 2's. That's (n + 1) possibilities for the 2's. Similarly, (m + 1) possibilities for the 3's and (k + 1) possibilities for the 11's. We simply multiply these three numbers.
NOTICE that one set, the set that includes no 2's, no 3's, and no 11's, is included. This is known in mathematics as thenull set, sometimes called the empty set, a set with no members. Technically, this is a subset of every possible set, but that's a technical detail of set theory that goes well beyond what the GMAT would expect students to know. Even the the calculation is not that difficult, some of the technical aspects of this question are not in line with the GMAT's expectations.
The number of subsets is (m + 1)(n + 1)(k + 1). The answer is not given in that form. Instead, the first two factors have been FOILed together:
(mn + m + n + 1)(k + 1).
Mike
B
Answer: B
Question: A train running at the speed of 60 km/hr crosses a pole in 9 seconds. Find the length of the train?
Options:
A)150
B)872
C)287
D)288
E)212
Rationale: Speed = 60*(5/18) m/sec = 50/3 m/sec
Length of Train (Distance) = Speed * Time
(50/3) * 9 = 150 meter
Answer:A
Answer: A
Question: Cecilia, Robbie, and Briony all bought stamps. The number of stamps Cecilia purchased was equal to a single digit. The number of stamps only one of them purchased was divisible by 7. The number of stamps one of them bought was an even number. Which of the following could represent the numbers of stamps each purchased?
Options:
A)3, 8, 24
B)7, 9, 17
C)6, 9, 12
D)5, 15, 18
E)9, 10, 13
Rationale: I didnt get your point on eliminating D.
The number of stamps only one purchased was divisible by 7.Could that not be Cecilia with 9 stamps.
I choose this and marked D.
Answer: D
Question: The profit earned by selling an article for $ 832 is equal to the loss incurred when the same article is sold for $ 448. What should be the sale price for making 45% profit?
Options:
A)$480
B)$450
C)$928
D)$870
E)$660
Rationale: Let C.P. = $ x.
Then, 832 - x = x - 448
2x = 1280 => x = 640
Required S.P. = 145% of $ 640 = $ 928.
C
Answer: C
Question: If the sides of a cube are in the ratio 9:5. What is the ratio of their diagonals?
Options:
A)9:5
B)16:9
C)4:
D)3:4
E)3:8
Rationale: Explanation:
Diagonal of a Cube=a√3 where a is side
a1:a2 = 9:5
d1:d2 = 9:5 where√3 cancelled both side
ANSWER:A
Answer: A
Question: Both Robert and Alice leave from the same location at 8:00 a.m. driving in the same direction, but in separate cars. Robert drives 60 miles per hour while Alice drives 80 miles per hour. After 6 hours, Alice’s car stops. At what time will Robert’s car reach Alice’s car?
Options:
A)1 p.m.
B)3 p.m.
C)4 p.m.
D)8 p.m.
E)9 p.m.
Rationale: 8:00 am so 6 hours later is 2:00 pm
In six hours, Robert will have driven 6*60 = 360 miles
In six hours, Alive will have driven 6*80 = 480 miles
So Robert needs 480-360 = 120 miles do catch Alice up.
So at 60 mph, he will need 2 hours
2:00 pm + 2 hours = 4:00 pm
ANS : C
Answer: C
Question: X percents of the rooms are suits, Y percent of the rooms are painted light blue. Which of the following best represents the least percentage of the light blue painted suits?
Options:
A)X-Y
B)Y-X +100
C)100X-Y
D)X+Y-100
E)100-XY
Rationale: Using the simple formula
100 = X + Y - BOTH - > Here X = % of Suits , Y = % of light blue painted rooms and BOTH = % of suits painted in light blue colour
So now, BOTH = X+Y -100 and now you can manipulate the value of X and Y to get the max and minimum values.
Hence Answer D
Answer: D
Question: If a - b = 5 and a2 + b2 = 29, find the value of ab.
Options:
A)6
B)8
C)10
D)11
E)2
Rationale: 2ab = (a2 + b2) - (a - b)2
= 29 - 25 = 4
ab = 2.
Answer: E
Answer: E
Question: In a store, the profit is 320% of the cost. If the cost increases by 25% but the SP remainsconstant, approximately what %of the sp is the profit?
Options:
A)30%
B)70%
C)80%
D)90%
E)100%
Rationale: Let C.P. = Rs. 100. Then, profit = Rs. 320, S.P. = Rs. 420
New C.P. = 125% of Rs. 100 = Rs. 125.
New S.P. = Rs. 420
Profit = 420 - 125 = Rs. 295
Required percentage = 295/420 * 100 = 1475/21 = 70%
B
Answer: B
Question: ashok and pyarelal invested money together in a business and share a capital of ashok is 1/9 of that of pyarelal.if the incur a loss of Rs 1000 then loss of pyarelal?
Options:
A)600
B)700
C)800
D)900
E)1000
Rationale: Let the capital of Pyarelal be x, then capital of Ashok=x/9
So ratio of investment of Pyarelal and Ashok = x : x/9 =9x : x
Hence out of the total loss of 1000, loss of Pyarelal= 1000*9x/10x=900
ANSWER:D
Answer: D
Question: A and B start from Opladen and Cologne respectively at the same time and travel towards each other at constant speeds along the same route. After meeting at a point between Opladen and Cologne, A and B proceed to their destinations of Cologne and Opladen respectively. A reaches Cologne 40 minutes after the two meet and B reaches Opladen 70 minutes after their meeting. How long did A take to cover the distance between Opladen and Cologne?
Options:
A)1 hour
B)1 hour 10 minutes
C)2 hours 30 minutes
D)1 hour 20 minutes
E)2 hours 10 minutes
Rationale: v1 and V2 are speeds.
v1.t /70 = v2
v2.t/40 = v1
v1/v2 = 7/4
which train A would 70. 4/7 mins to cover the same distance
40 + 40 = 80 mins (ANS D)
Answer: D
Question: The ratio R, by volume of soap to alcohol to water in a 76 litre solution is 2: 50: 100 . The solution is then altered by adding more soap, alcohol and water.After this alteration the ratio, by volume of soap to water in the solution doubles whereas the ratio, by volume of soap to water remains the same as before. What COULD BE the resulting volume.
Options:
A)79 litres
B)78 litres
C)77 litres
D)152 liters
E)304 litres
Rationale: I guess it should be
the ratio R, by volume ofsoaptowaterin the solutiondoubleswhereas the ratio, by volume ofalocoholtowaterremains thesameas before
2:50: 100 => 1 : 25 : 50. If we add all the parts, we get 76 liters
So we have 1 liters of Soap, 25 liters of Alcohol and 50 liters of Water.
Now as per the Question, Soap : Water doubles but alcohol to water remains the same.
So Soap becomes 2 liters, Alcohol remains 25 liters and Water remains at 50 liters.
Hence 77 liters - Option C)
Answer: C
Question: Three people took GMAT practice tests in which the minimum and maximum possible scores are 200 and 800, respectively. They each took a test 3 times, and no one scored below 400 or over 700. If the individual ranges of the three people's scores in those 3 practice tests were 40, 70 and 100, what is the difference between the maximum and minimum possible ranges of all their scores put together.
Options:
A)70
B)80
C)100
D)140
E)200
Rationale: According to the information in the question the maximum range would be between 400 and 700(300). The minimum range would be the greatest range for any one individual, which is listed in the problem as 100. So the difference between these would be 300-100 or 200.
Answer:E
Answer: E
Question: A dishonest dealer uses a scale of 80 cm instead of a metre scale and claims to sell at cost price. His profit is
Options:
A)9%
B)10%
C)25%
D)None of these
E)Cannot be determined
Rationale: Solution
Gain%	= (20 / 80 x 100)%
= 25%
Answer C
Answer: C
Question: If an amount of Rs 15,487 is divided equally among
76 students, approximately how much amount will
each student get?
Options:
A)Rs 206
B)Rs 210
C)Rs 204
D)Rs 218
E)None
Rationale: Amount received by each student = 15487/76 ≈ Rs
204
Answer C
Answer: C
Question: If 89/99 = 0.898, what is the 83rd digit to the right of the decimal point of the fraction?
Options:
A)5
B)2
C)8
D)7
E)9
Rationale: we are not concerned what 89/99 means..
we have to look at the decimal..
0.898 means 0.898989....
so right of decimal, all ODD numbered are 8 and all EVEn numbered are 9..
here 83 is ODD, so ans is 8
Answer is C
Answer: C
Question: There is a swimming match that is single elimination meaning that after one loss the team is out. There are 50 swimmers in this match. How many matches are swam?
Options:
A)25
B)50
C)49
D)15
E)10
Rationale: C
The number of matches always adds up to one less than the number of matches in a single elimination tournament. You may calculate it any way. Therefore, 49 races were swam.
Answer: C
Question: A boy has nine trousers and 12 shirts. In how many different ways can he select a trouser and a shirt?
Options:
A)238 ways
B)287 ways
C)266 ways
D)108 ways
E)121 ways
Rationale: Explanation:
The boy can select one trouser in nine ways.
The boy can select one shirt in 12 ways.
The number of ways in which he can select one trouser and one shirt is 9 * 12 = 108 ways.
Answer: D
Answer: D
Question: If A lends Rs. 3500 to B at 10% p.a. and B lends the same sum to C at 11.5% p.a., then the gain of B (in
Rs.) in a period of 3 years is
Options:
A)Rs. 154.50
B)Rs. 155.50
C)Rs. 156.50
D)Rs. 157.50
E)None of these
Rationale: Explanation:
We need to calculate the profit of B.
It will be,
SI on the rate B lends - SI on the rate B gets
Gain of B=157.50=3500×11.5×3100−3500×10×3100
Answer: D
Answer: D
Question: A train 200 m long is running at a speed of 68 kmph. How long does it take to pass a man who is running at 8 kmph in the same direction as the train?
Options:
A)5 sec
B)9 sec
C)12 sec
D)18 sec
E)15 sec
Rationale: Answer : C.
Speed of the train relative to man = (68 - 8) kmph
= (60* 5/18) m/sec = (50/3)m/sec
Time taken by the train to cross the man
= Time taken by It to cover 200 m at 50/3 m / sec = 200 *3/ 50 sec = 12sec
Answer: C
Question: If c = (1/10)a and b = 5c, then which of the following represents the result of a^2+b^2+c^2 in terms of c
Options:
A)25c^2
B)56c^3
C)52c
D)126c^2
E)110c^2
Rationale: a = 10c and b =5c.
a^2+b^2+c^2 = (10c)^2+(5c)^2+c^2 = 126c^2.
Answer is D
Answer: D
Question: Due to 10% decrease in the price of sugar and John can buy 4kg more sugar in Rs100 , then find the CP of sugar?
Options:
A)s. 1(2/9)
B)s. 2(7/9)
C)s. 2(1/9)
D)s. 3(2/7)
E)s. 4(2/9)
Rationale: Here r = 10 % ,x = 100 and A = 4 kg
Actual price of sugar = 10*100/((100-10 )*4) = Rs. 2(7/9)
B
Answer: B