divelab/Sys2Bench huggingface dataset:
Question: Two goods trains each 720 m long are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one?
Options:
A)22 sec
B)88 sec
C)48 sec
D)18 sec
E)72 sec
Rationale: Relative speed = 45 + 30 = 75 km/hr.
75 * 5/18 = 125/6 m/sec.
Distance covered = 750 + 750 = 1500 m.
Required time = 1500 * 6/125 = 72 sec.
Answer:E
Answer: E
Question: A can do a piece of work in 10 days. He works at it for 4 days and then B finishes it in 9 days. In how many days can A and B together finish the work?
Options:
A)4 days
B)2 days
C)6 days
D)8 days
E)9 days
Rationale: C
6 days
4/10 + 9/x = 1 => x = 15
1/10 + 1/15 = 1/6 => 6 days
Answer: C
Question: 325^325/125^n
Options:
A)64
B)216
C)343
D)481
E)625
Rationale: 325^325 = 325*325*325.................325 times
and 125 = 5*5*5
also 325 = 5*5*13 (2 fives)
in 325 times 325 we have 5^(2*325) which we can write in (5^3)^216
so the answer is 216
ANSWER:B
Answer: B
Question: An amount of Rs.1,000 is to be distributed amongst P, Q, R and S such that “P” gets twice as that of “Q” and “S” gets four times as that of “R”. If “Q” and “R” are to receive equal amount, what is the difference between the amounts received by S and P?
Options:
A)2378
B)2697
C)250
D)5000
E)6971
Rationale: Explanation:
We have, P = 2Q & S = 4R
Further Q = R & P + Q + R + S = 1,000
Thus we get, 2Q + Q + Q + 4Q = 1,000
8Q = 1,000 or Q = Rs. 125
Thus, R = Rs. 125, P = 250 & S = Rs. 500
Hence, the required difference = (S – P) = (500 – 250) = Rs.250
ANSWER:C
Answer: C
Question: The sum of first 45 natural numbers is?
Options:
A)900
B)1000
C)1035
D)1040
E)1045
Rationale: et Sn =(1 + 2 + 3 + ... + 45). This is an A.P. in which a =1, d =1, n = 45.
Sn =	n	[2a + (n - 1)d]	=	45	x [2 x 1 + (45 - 1) x 1]	= 45	x 46 = (45 x 23)
2	2	2
= 45 x (20 + 3)
= 45 x 20 + 45 x 3
= 900 + 135
= 1035.
Shorcut Method:
Sn =	n(n + 1)	=	45(45 + 1)	= 1035.
2	2
C)
Answer: C
Question: A rope of which a calf is tied is increased from 12 m to 23 m, how much additional grassy ground shall it graze?
Options:
A)1218
B)1219
C)1210
D)1211
E)1212
Rationale: π (232 – 122) = 1210
Answer: C
Answer: C
Question: A bus can hold 72 passengers. If there are 12 rows of seats on the bus, how many seats are in each row?
Options:
A)4
B)8
C)10
D)6
E)12
Rationale: No. of seats = 72/12 = 6
There are 6 seats in each row
Answer : D
Answer: D
Question: In an examination, there were 2,000 candidates, out of which 900 candidates were girls and rest were Boys. If 36% of the boys and 32% of the girls passed, then the total percentage of failed candidates is?
Options:
A)35.67%
B)65.80%
C)68.57%
D)69.57%
E)none of these
Rationale: Girls = 900, Boys = 1100
Passed = ( 36% of 1100 ) + ( 32% of 900)
= 396 + 288 = 684
Failed = 2000 - 684 = 1316
Failed % = [(1316/2000) x 100]%
= 65.8%.
ANSWER:B
Answer: B
Question: For any positive integer n, the sum of the first n positive integers equals [n(n+1)]/2.
What is the sum of all the even integers between 99 and 191?
Options:
A)4450
B)5560
C)6670
D)7780
E)8890
Rationale: 100 + 102 +...+ 190 = 46*100 + (2+4...+90) = 46*100 + 2(1+2+...+45) =
46*100 + 2(45)(46)/2 = 145*46 = 6670
The answer is C.
Answer: C
Question: If s is a number such that –2 ≤ s ≤ 2, which of the following has the largest possible absolute value?
Options:
A)3s – 1
B)x^2 + 1
C)3 – x
D)x – 3
E)x^2 – x
Rationale: Ans is A .. leads to the max value of 7 for s = -2
Answer: A
Question: Each child has 4 pencils and 13 Skittles. If there are 8 children, how many pencils are there in total?
Options:
A)16
B)12
C)18
D)22
E)32
Rationale: 4*8=32.Answer is E.
Answer: E
Question: A portion of the 80% solution of chemicals was replaced with an equal amount of 20% solution of chemicals. As a result, 50% solution of chemicals resulted. What part of the original solution was replaced?
Options:
A)1/3
B)1/2
C)1/4
D)1/5
E)1/6
Rationale: This is a weighted average question. Say x% of the solution was replaced --> equate the amount of chemicals: 0.8(1-x)+0.2*x=0.5 --> x=1/2.
Answer: B.
Answer: B
Question: Replace the question mark with the correct number in the series
60 40 40 43 20 46 0 49 ?
Options:
A)-20
B)50
C)40
D)-10
E)-30
Rationale: A
-20
Its a alternate series riddle
60 40 20 0 (?)
40 43 46 49 (+3)
Answer: A
Question: 108.	Triangle A’s base is 9% greater than the base of triangle B, and A’s height is 9% less than the height of triangle B. The area of triangle A is what percent less or more than the area of triangle B?
Options:
A) 9 % less
B) 1 % less
C) Equal to each other
D) 1.3 % more
E) 9 % more
Rationale: Wish the question specified that we are talking about corresponding height.
Base of A = 10/9 * Base of B
Height of A = 8/9 * Height of B
Area of A = (1/2) * Base of A * Height of A = 10/9 * 8/9 * Area of B = 80/81 * Area of B
Area of A is 1.3% more than the area of B.
Answer (D)
Answer: D
Question: Find the missing in the series: 70, 56, 45, 41,___
Options:
A)22
B)287
C)2679
D)276
E)2771
Rationale: Answer:D
Answer: D
Question: If S and T are positive integers, and the remainder obtained when S is divided by T is the same as the remainder obtained when T is divided by S, which of the following is a possible value of ST?
Options:
A) 64
B) 55
C) 42
D) 36
E) 24
Rationale: I am not too sure on this. I guess it is possible only when S and T are both same. If they are both same, ST must be a perfect square.
64 is a perfect square.
Ans:A
Answer: A
Question: All the six members of a family A, B, C, D, E and F are travelling together. B is the son of C but C is not the mother of B. A and C are a married couple. E is the brother of C. D is the daughter of A. F is the brother of B. Who is the mother of B ?
Options:
A)C
B)V
C)R
D)A
E)T
Rationale: Explanation:
B is the son of C but C is not the mother of B means C is the father of B. A is marned to C means A is the mother of B. F is brother of B means F is son of A and C. D is daughter of A means D is daughter of A and C
Clearly. A is the mother of B.
Answer: D
Answer: D
Question: A cubical block of metal weighs 3 pounds. How much will another cube of the same metal weigh if its sides are twice as long?
Options:
A)48
B)32
C)24
D)18
E)12
Rationale: For example our cube have a side 1 meter, so we have 1 cubical meter in this cube
and this cubical meter weigth 3 pounds
If we take cube with side 2 meters we will have 8 cubical meters in this cube
8 meters * 3 pounds = 24 pounds
So answer is C
And similar but more theoretical approach:
if we have sides a and b than they have equal ration with their areas:
a/b = a^2/b^2
and they have equal ration with their volumes:
a/b = a^3/b^3
we have two sides 1/2 so their volume will be in ratio 1/8
weight of one cube * volume of another cube
3 * 8 = 24
So answer is C
Answer: C
Question: If a, b, t are integers, 33 = abt, and a < b < t, what is the smallest possible value of a?
Options:
A)-33
B)-3
C)1
D)3
E)11
Rationale: Given : a * b * t = 33.
33 is a Positive Odd number.Side Note:Thus, all 3 numbers will be odd.
Prime factorization will also give you numbers. 1, 3, 11. The 3 numbers will be combination of these 3 numbers with possible variation in sign(+/-).
We could have any 2 digits as negative. --> negative * negative * positive. We have negative values in answer option, so eliminate C, D and E from answer choices.
-33 * -1 * 1 = 33.
Correct answer is A
Answer: A
Question: For what value of x will the function f(x) = -3(x - 10)(x - 4) have a maximum value? Find the maximum value.
Options:
A)9
B)18
C)27
D)36
E)45
Rationale: f(x) = -3(x - 10)(x - 4) = -3x2*square* + 42x - 120 : expand and obtain a quadratic function
h = -b/2a = -42/-6 = 7 : h is the value of x for which f has a maximum value
f(h) = f(7) = 27 : maximum value of f.
correct answer C
Answer: C
Question: Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is ?
Options:
A)1 : 1
B)2 : 1
C)2 : 3
D)3 : 2
E)1 : 2
Rationale: Let the speeds of the two trains be x m/sec and y m/sec respectively.
Then, length of the first train = 27 x meters, and
length of the second train = 17 y meters.
(27 x + 17 y) / (x + y) = 23
=> 27 x + 17 y = 23 x + 23 y
=> 4 x = 6 y
=> x/y = 3/2.
Answer : D
Answer: D
Question: The ratio between the speeds of two trains is 5: 6 If the second train runs 540 kms in 6 hours, then the speed of the first train is
Options:
A)90 km/h
B)60 km/h
C)45 km/h
D)80 km/h
E)75km/h
Rationale: E
75 km/h
Answer: E
Question: If -1 < h < 3, which of the following has the greatest value?
Options:
A)a) 1-h
B)b) 1+h
C)c) 1+h^2
D)d) 1-1/h
E)e) 1-1/(h^2)
Rationale: easiest way of solving this would be to substitute a value.
lets say h= - 1/2
a) 3/2
b) 1/2
c) 5/4
d) 3
e) - 3
the value you chose is wrong . h cannot be 0.9 as -1<h<0. if you chose -0.9 answer will still be D.
Answer is B.
Answer: B
Question: A hiker walking at a constant rate of 4 kilometers per hour is passed by a cyclist travelling in the same direction along the same path at a constant rate of 18 kilometers per hour. The cyclist stops and waits for the hiker 5 minutes after passing her while the hiker continues to walk at her constant rate. How many minutes must the cyclist wait until the hiker catches up?
Options:
A)7.5
B)12.5
C)17.5
D)22.5
E)27.5
Rationale: In 5 minutes, the cyclist travels a distance of (5/60)*18 = 1.5 km.
The time it takes the hiker to complete this distance is 1.5/4 hours = 22.5 minutes
The cyclist needs to wait 22.5 - 5 = 17.5 minutes
The answer is C.
Answer: C
Question: A bag holds 4 red marbles and 4 green marbles. If you removed two randomly selected marbles from the bag, without replacement, what is the probability that both would be red?
Options:
A)1/7
B)1/5
C)3/14
D)2/7
E)1/2
Rationale: probability of selecting first red marble = 4/8
probability of selecting second red marble without replacement = 3/7
final probability = 4/8 * 3/7 = 3/14
The correct answer is C.
Answer: C
Question: If goods be purchased for $840 and one-fourth be sold at a loss of 20% at what gain percent should the remainder be sold so as to gain 20% on the whole transaction?
Options:
A)35 1/3%
B)30 2/3%
C)33 1/3%
D)38 1/2%
E)40 1/3%
Rationale: C
33 1/3%
1/4 CP = 210 SP = 21*(80/100) = 168
SP = 840*(120/100) = 1008
1008 - 168 = 840
3/4 SP = 630
Gain = 210
630 --- 210
100 --- ? => 33 1/3%
Answer: C
Question: Two pipes A and B can fill a cistern in 37 1/2 minutes and 45 minutes respectively. Both pipes are opened. The cistern will be filled in just half an hour, if the pipe B is turned off after?
Options:
A)7 min
B)9 min
C)4 min
D)9 min
E)1 min
Rationale: Let B be turned off after x minutes. Then, part filled by (A + B) in x min + part filled by A in (30 - x) min = 1.
x(2/75 + 1/45) + (30- x) 2/75 = 1
11x + 180 - 6x = 225 => x = 9
Answer:B
Answer: B
Question: A 9% stock yields 8%.The market value of the stock is :
Options:
A)Rs. 72
B)Rs. 92
C)Rs. 112.50
D)Rs. 116.50
E)None of these
Rationale: solution
To obtain Rs. 8, investment = Rs. 100.
To obtain Rs. 9, investment = Rs.(100/8X9)= Rs. 112.50
∴ Market value of Rs. 100 stock = Rs.112.50
Answer C
Answer: C
Question: A whale goes on a feeding frenzy that lasts for 9 hours. For the first hour he catches and eats x kilos of plankton. In every hour after the first, it consumes 3 kilos of plankton more than it consumed in the previous hour. If by the end of the frenzy the whale will have consumed a whopping accumulated total 450 kilos of plankton, how many kilos did he consume on the sixth hour?
Options:
A)38
B)47
C)50
D)53
E)62
Rationale: Suppose food eaten in first hour : x
The AP is : x, x+3, x+6, .... [Number of terms 'n' = 9]
Therefore,
9/2[2 x + (9-1)*3] = 450.
Solving for x, x = 38.
Now, 6th term will be : x + (6-1)*d = 38 + 5*3 = 53.
Hence D !!
Answer: D
Question: There is a 10% chance that Tigers will not win at all during the whole season. There is a 10% chance that Federer will not play at all in the whole season. What is the greatest possible probability that the Tigers will win and Federer will play during the season?
Options:
A)A)55%
B)B)60%
C)C)70%
D)D)72%
E)E)90%
Rationale: There is a 10% chance that Tigers will not win at all during the whole season
We can infer that there is 90% chance Tigers will win .
Similarly There is a 10% chance that Federer will not play at all in the whole season
We can also infer that there is 90% chance that Federer will play.
Answer E
Answer: E
Question: A man whose speed is 6 kmph in still water rows to a certain upstream point and back to the starting point in a river which flows at 1.5 kmph, find his average speed for the total journey?
Options:
A)7
B)5.6
C)6
D)9
E)3
Rationale: M = 6.0
S = 1.5
DS = 7.5
US = 4.5
AS = (2 * 7.5 * 4.5) /12 = 5.6
Answer:B
Answer: B
Question: A and B can do a work in 8 days, B and C can do the same work in 12 days. A, B and C together can finish it in 6 days. A and C together will do it in?
Options:
A)8
B)4
C)6
D)12
E)10
Rationale: (A + B + C)'s 1 day work = 1/6;
(A + B)'s 1 day work = 1/8
(B + C)'s 1 day work = 1/12
(A + C)'s 1 day work = (2 * 1/6) - (1/8 + 1/12)
= (1/3 - 5/24) = 1/8
So, A and C together will do the work in 8 days.
ANSWER A
Answer: A
Question: The contents of a bag of marbles consist of 12 green marbles and 20 blue marbles. How many blue marbles must be removed so that 40% of the marbles in the bag will be green?
Options:
A)0
B)1
C)2
D)3
E)4
Rationale: We can use simple arithmetic to solve this problem by testing our answers.
Lets test B:
If we only remove 1 blue marble:
12 green marbles and 19 blue marbles for a total of 31 marbles
12/31=37.5% not quite our answer.
Lets test C:
If we remove 2 blue marbles:
12 green marbles and 18 blue marbles for a total of 30 marbles
12/30=40%
C is our answer!
Answer: C
Question: What will come in place of the x in the following Number series? 25, 100, 400, X, 6400
Options:
A)6400
B)6900
C)1600
D)7500
E)7900
Rationale: (C)
25 x 4 = 100, 100 x 4 = 400, 400 x 4 = 1600, 1600 x 4 = 6400.
Answer: C
Question: A boat goes 150 km downstream in 10 hours, and 75 m upstream in 15 hours. The speed of the stream is?
Options:
A)22 1/7
B)22 1/4
C)22 1/2
D)22 1/1
E)5
Rationale: 150 --- 10 DS = 15
? ---- 1
75 ---- 15 US = 5
? ----- 1 S = (15 - 5)/2
= 5 kmp Answer: E
Answer: E
Question: From a pack of cards two cards are drawn one after the other, with replacement. The probability that the first is a red card and the second is a king is -.
Options:
A)1/26
B)3/52
C)15/26
D)11/26
E)1/13
Rationale: Explanation:
Let E1 be the event of drawing a red card.
Let E2 be the event of drawing a king .
P(E1 ∩ E2) = P(E1) . P(E2)
(As E1 and E2 are independent)
= 1/2 * 1/13 = 1/26
ANSWER IS A
Answer: A
Question: (7/10^2)*(8/10^2)*(6/10^2)=?
Options:
A)0.000336
B)0.336
C)0.0336
D)0.00337
E)0.00336
Rationale: 7/10^2=0.07
8/10^2=0.08
6/10^2=0.06
=0.07*0.08*0.06 multiply the whole number (i.e) 7*8*6=336
Move the place depend upon the decimal places (i.e) 0.000336
Option A is answer
Answer: A
Question: How many multiples of 10 are there between 100 and 10000 (both are inclusive)?
Options:
A)456
B)789
C)991
D)1020
E)1100
Rationale: the answer is (10000-100)/10+1=991
Answer is C
Answer: C
Question: A man can row upstream at 7 kmph and downstream at 10kmph.find man’s rate in still water and the rate of current.
Options:
A)1.5 km/hr
B)1 km/hr
C)1.5 km/min
D)0.5 km/hr
E)1.75 km/hr
Rationale: Rate in still water=1/2(10+7)km/hr=8.5 km/hr.
Rate of current=1/2(10-7)km/hr=1.5 km/hr.
Answer is A.
Answer: A
Question: A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 15 seconds. The speed of the train is?
Options:
A)35
B)50
C)88
D)22
E)12
Rationale: Speed of the train relative to man = (125/15) m/sec = (25/3) m/sec. [(25/3) * (18/5)] km/hr = 30 km/hr. Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr. x - 5 = 30 ==> x
= 35 km/hr.Answer:A
Answer: A
Question: 11 persons are sittingin a row. how many ways can 11 persons be arranged in a row such that 3 persons should always be together?
Options:
A)7!×2!
B)10!×1!
C)9!×3!
D)8!×2!
E)6!×3!
Rationale: Given that three particular persons should always be together. Hence, just group these three persons together and consider as a single person.
Therefore we can take total number of persons as 9. These 9 persons can be arranged in 9! ways.
We had grouped three persons together. These three persons can be arranged among themselves in 3! ways.
Hence, required number of ways
=9!×3!
C
Answer: C
Question: The no. of gift pack bought by Dexter is 1 more than the price, in rupees, of each gift pack. The amount of Rs.380 which Dexter had, fell short of the required amount. What is theamount by which he might have fallen short.
Options:
A)30
B)40
C)50
D)70
E)80
Rationale: Let the price of gift pack be 'aa'
Then number of packs bought =a+1=a+1
Hence total cost is a(a+1)a(a+1)
It is given that 380<a(a+1)380<a(a+1)
If a=19a=19, the total cost =19×20=380=19×20=380
Dexter would not have fallen short, If:
a=20a=20, a(a+1)=420a(a+1)=420
So he would have fallen short by Rs 40.
This is the minimum amount by which he may have fallen short.
B)
Answer: B
Question: The average age of 30 students in a class is 15 years. If the age of teacher is also included, the average becomes 16 years, find the age of the teacher.
Options:
A)46
B)55
C)43
D)39
E)54
Rationale: Explanation:
If teacher's age is 15 years, there is no change in the average. But teacher has contributed 1 year to all the students along with maintaining his age at 16.
Age of teacher = Average age of all + Total increase in age
= 16 + (1 x 30 ) = 46 years
Answer:A
Answer: A
Question: In a certain office 1/3 of the workers are women ½ of the women are married and 1/3 of the married women have children if ¾ of the men are married and 2/3 of the married men have children what part of workers are without children?
Options:
A)11/18
B)12/18
C)13/18
D)10/18
E)None of them
Rationale: Let the total no of workers be x
No of women =x/3
No of men =x-(x/3)=2x/3
No of women having children =1/3 of ½ ofx/3=x/18
No of men having children=2/3 of ¾ of2x/3=x/3
No of workers having children = x/8 +x/3=7x/18
Workers having no children=x-7x/18=11x/18=11/18 of all wprkers
Answer is A.
Answer: A
Question: A group of hikers is planning a trip that will take them up a mountain using one route and back down using another route. They plan to travel down the mountain at a rate of one and a half times the rate they will use on the way up, but the time each route will take is the same. If they will go up the mountain at a rate of 5 miles per day and it will take them two days, how many miles long is the route down the mountain?
Options:
A)4
B)6
C)8
D)12
E)15
Rationale: On the way down, the rate is 1.5*5 = 7.5 miles per day.
The distance of the route down the mountain is 2*7.5 = 15 miles.
The answer is E.
Answer: E
Question: Working alone, printers X, Y, and Z can do a certain printing job, consisting of a large number of pages, in 16, 12, and 8 hours, respectively. What is the ratio of the time it takes printer X to do the job, working alone at its rate, to the time it takes printers Y and Z to do the job, working together at their individual rates?
Options:
A)5/2
B)7/4
C)8/5
D)10/3
E)12/5
Rationale: The time it takes printer X is 16 hours.
The combined rate of Y and Z is 1/12 + 1/8 = 5/24
The time it takes Y and Z is 24/5
The ratio of times is 16 / (24/5) = 5*16/24 = 10/3
The answer is D.
Answer: D
Question: A can do a job in 18 days and B can do it in 30 days. A and B working together will finish twice the amount of work in days?
Options:
A)22 1/6
B)22 1/2
C)22 1/0
D)22 1/9
E)22 1/1
Rationale: 1/18 + 1/30 = 8/90 = 4/45
45/4 = 11 1/4 *2 = 22 1/2 days
Answer: B
Answer: B
Question: The length of a room is 5.5 m and width is 3.75 m. What is the cost of paying the floor by slabs at the rate of $800 per sq. metre.
Options:
A)$12500
B)$13500
C)$16500
D)$14500
E)$18500
Rationale: C
$16500
Area =5.5×3.75 sq. metre.
Cost for 1 sq. metre. = $800
Hence, total cost
=5.5×3.75×800=5.5×3000= $16500
Answer: C
Question: On Thursday Mabel handled 90 transactions. Anthony handled 10% more transactions than Mabel, Cal handled 2/3rds of the transactions that Anthony handled, and Jade handled 15 more transactions than Cal. How much transactions did Jade handled?
Options:
A)80
B)81
C)82
D)83
E)84
Rationale: Solution:
Mabel handled 90 transactions
Anthony handled 10% more transactions than Mabel
Anthony = 90 + 90 × 10%
= 90 + 90 × 0.10
= 90 + 9
= 99
Cal handled 2/3rds of the transactions than Anthony handled
Cal = 2/3 × 99
= 66
Jade handled 15 more transactions than Cal.
Jade = 66 + 15
= 81
Jade handled = 81 transactions.
Answer: B
Answer: B
Question: If the numbers 1 to 100 are written on 100 pieces of paper, (one on each) and one piece is picked at random, then What is the probability that the number drawn is neither prime nor composite?
Options:
A)1/50
B)1/25
C)1/100
D)1
E)2
Rationale: There are 25 primes, 74 composite numbers from 1 to 100. The number
which is neither prime nor composite is 1.
Therefore, required probability = 1/100.
ANSWER:C
Answer: C
Question: Two trains are running in opposite directions with the same speed. If the length of each train is 300 metres and they cross each other in 12 seconds, then the speed of each train (in km/hr) is:
Options:
A)31 km/hr.
B)32 km/hr.
C)60 km/hr.
D)35 km/hr.
E)90 km/hr.
Rationale: Let the speed of each train be x m/sec.
Then, relative speed of the two trains = 2x m/sec.
So, 2x = (300 + 300)/12
2x = 50
x = 25.
Speed of each train = 25 m/sec = 25 x 18/5 km/hr = 90 km/hr.
answer :E
Answer: E
Question: Uncle Bruce is baking chocolate chip cookies. He has 50 ounces of dough (with no chocolate) and 40 ounces of chocolate. How much chocolate is left over if he uses all the dough but only wants the cookies to consist of 30% chocolate?
Options:
A)22.86
B)23.86
C)25
D)26
E)27
Rationale: First, you must find the total weight of the mixture given that 80% of it will be dough.
70%*Total = 40 => (7/10)Total=40 => Total=400/7 => Total=57.14 oz,
From there, you must find 30% of the total 57.14 oz of the mixture.
30%*Total => (3/10)(57.14)= 17.14 oz choclate used,
Not forgetting that the question asks how much chocolate is left over we must subtract the chocolate used from the initial chocolate. 40-17.14 = 22.86 oz chocolate left over.
Answer : A
Answer: A
Question: A sun is divided among X, Y and Z in such a way that for each rupee X gets, Y gets 45 paisa and Z gets 30 paisa. If the share of Y is RS. 27, what is the total amount?
Options:
A)109
B)105
C)129
D)119
E)113
Rationale: x:y:z = 100:45:30
20:9:6
9 --- 27
35 --- ? => 105
Answer:B
Answer: B
Question: In how many ways can a cricket 15 be chosen out of a batch of 20 players?
Options:
A)12500
B)18250
C)13250
D)15504
E)14520
Rationale: Required number of ways = 20C15 = 20C (20-15) = 20C5
20C5 = (20*19*18*17*16)/(5*4*3*2*1) = 15504
Answer is D
Answer: D
Question: The price of commodity X increases by 30 cents every year, while the price of commodity Y increases by 20 cents every year. If in 2001, the price of commodity X was $4.20 and the price of commodity Y was $4.40, in which year will commodity X cost 90 cents more than the commodity Y?
Options:
A)2010
B)2011
C)2012
D)2013
E)2014
Rationale: The cost of commodity X increases by 10 cents per year relative to commodity Y.
The price of X must gain 20 + 90 = $1.10 cents on commodity Y, which will take 11 years.
The answer is C.
Answer: C
Question: A small pool filled only with water will require an additional 300 gallons of water in order to be filled to 70% of its capacity. If pumping in these additional 300 gallons of water will increase the amount of water in the pool by 30%, what is the total capacity of the pool in gallons?
Options:
A)1000
B)1250
C)1300
D)1600
E)1857.14
Rationale: 300 gallons of water increases capacity by 30% that means
30% is 300 gallons, so 100% would be = 300*100/30= 1000 gallons
Now 1000 +300 gallons is 70% capacity of tank.
so 100% capacity would be= 1300 *100/70= 1857.14
E is the answer
Answer: E