divelab/Sys2Bench huggingface dataset:
Question: What least value must be assigned to * so that the number 197*5462 is divisible by 9
Options:
A)0
B)2
C)4
D)9
E)8
Rationale: Let the missing digit be x.
Sum of digits = (1 + 9 + 7 + x + 5 + 4 + 6 +»2) = (34 + x).
For (34 + x) to be divisible by 9, x must be replaced by 2 .
Hence, the digit in place of * must be 2.
ANSWER B 2
Answer: B
Question: A bowl was filled with 120 ounces of milk, and 0.01 ounce of the milk evaporated each day during a 60-day period. What percent of the original amount of milk evaporated during this period?
Options:
A)A)0.005%
B)B)0.05%
C)C)5%
D)D)0.50%
E)E)4.2%
Rationale: Total amount of milk evaporated each day during a 60-day period = .01 * 60
= 0.6
percent of the original amount of milk evaporated during this period = (.6/120) * 100%
= 0.5 %
Answer D
Answer: D
Question: In how many ways Chief Minister and Minister be elected from a team of 12 members?
Options:
A)125
B)131
C)132
D)145
E)147
Rationale: To do this, if captain is elected first, then we have 12 ways of doing this.
For election of vice-captain, we have only 11 ways left, coz 1 way is already consumed. (Situations like this is called dependent situation. One selection depends upon other selection.)
So, the ans is 12*11 = 132 ways.
C
Answer: C
Question: Positive Integer A gives the remainder of 18 when divided by another positive Integer B. If A/B = 147.24, what is the value of B?
Options:
A)96
B)75
C)48
D)25
E)12
Rationale: .24 of B = Remainder
.24 of B = 18
B = (18*100) / 24 = 75.
B
Answer: B
Question: The average (arithmetic mean) of a normal distribution of a school's test scores is 65, and standard deviation of the distribution is 6.5. A student scoring a 77 on the exam is in what percentile of the school?
Choices
Options:
A)63rd percentile
B)68th percentile
C)84th percentile
D)96th percentile
E)98th percentile
Rationale: (78-65)/6.5 = 2 sigmas or 95.5th percentile for +-2 sigma but in our case we need only upper tail, so it's 100 - (100 - 95.5)/2 = 96th percentile
D
Answer: D
Question: A cistern which could be filled in 9 hours takes one hour more to be filled owing to a leak in its bottom. If the cistern is full in what time will the leak empty it?
Options:
A)22
B)27
C)29
D)90
E)12
Rationale: 1/9 - 1/x = 1/10
=> 90 hrs
Answer: D
Answer: D
Question: The two lines y=x and x=-8 intersect on the coordinate plane. What is the value of the area of the figure formed by the intersecting lines and the x-axis?
Options:
A)28
B)32
C)36
D)40
E)44
Rationale: The point of intersection is (-8,-8).
The triangle has a base of length 8 and a height of 8.
area = (1/2)*base*height = (1/2)*8*8 = 32
The answer is B.
Answer: B
Question: One woman and one man can build a wall together in three hours, but the woman would need the help of two girls in order to complete the same job in the same amount of time. If one man and one girl worked together, it would take them five hours to build the wall. Assuming that rates for men, women and girls remain constant, how many hours would it take one woman, one man, and one girl, working together, to build the wall?
Options:
A)5/2
B)1
C)10/7
D)12/7
E)22/7
Rationale: Solution:Let work done by man, women and girl per hour be m,w,g respectively.
Then, m+w = 1/3-->(1) , w + 2g = 1/3-->(2) and m + g =1/5-->(3).
No. of hours it would take forone woman, one man, and one girl, working together, to build the wall,n = 1/m+w+g
From (1) and (2), m=2g and from (3) g=1/15,m=2/15 and w=1/5.
So, n = 1/(2/5) = 5/2
Option, A
Answer: A
Question: In how many ways can the letters of the word WAYS be arranged in a row so that the vowels appear in alphabetic order?
Options:
A)160
B)220
C)150
D)120
E)180
Rationale: three letters can be arranged in 1! ways.
only one combination AEI is required.
4 letters can be arranged in 4! ways.
D
Answer: D
Question: 5358 x 61 = ?
Options:
A)326838
B)323758
C)323298
D)273258
E)327382
Rationale: A
5358 x 61 = 5358 x (60 + 1)
= 5358 x 60 + 5358 x 1
= 321480 + 5358
= 326838.
Answer: A
Question: In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
Options:
A)6.25
B)5.5
C)7.4
D)5
E)5.2
Rationale: Runs scored in the first 10 overs = 10 × 3.2 = 32
Total runs = 282
Remaining runs to be scored = 282 - 32 = 250
Remaining overs = 40
Run rate needed = 250/40=6.25
ANSWER:A
Answer: A
Question: If Sn is the sum of the first n terms of a certain sequence and if Sn = n(n+3) for all positive integers n, what is the third term of the sequence?
Options:
A)3
B)4
C)6
D)8
E)9
Rationale: Tn = nth term
T1 = 1st term
T2 = 2nd term
and so on...
Sn = Sum of first n terms of the sequence
Sn = 1st term + 2nd term + 3rd term + ... + nth term
Sn = T1 + T2 + T3 + ....Tn
You are given here thatSn is the SUM of first n terms...So you have
Sn = T1 + T2 + T3 + ....Tn = n(n+1)
So S1 = T1
S2 = T1 + T2
S3 = T1 + T2 + T3
and so on
S1 = T1 = 1*(1+1) = 2
S2 = T1 + T2 = 2 + T2 = 2*(2+1) = 6
So T2 = 4
S3 = T1 + T2 + T3 = 2 + 4 + T3 = 3*(3+1) = 12
So T3 = 8
(This is what we wanted)
The third term is 8.
D
Answer: D
Question: On the independence day, bananas were be equally distributed among the children in a school so that each child would get two bananas. On the particular day 130 children were absent and as a result each child got two extra bananas. Find the actual number of children in the school?
Options:
A)260
B)620
C)500
D)520
E)720
Rationale: Let the number of children in the school be x. Since each child gets 2 bananas, total number of bananas = 2x.
2x/(x - 130) = 2 + 2(extra)
=> 2x - 260 = x => x = 260.
ANSWER:A
Answer: A
Question: A school has received 60% of the amount it needs for a new building by receiving a donation of $300 each from people already solicited. People already solicited represent 40% of the people from whom the school will solicit donations. How much average contribution is requited from the remaining targeted people to complete the fund raising exercise?
Options:
A)$200
B)$177.78
C)$100
D)$277.78
E)$377.78
Rationale: Let the amount school needs = X
Let total people school plans to solicit = T
School has received 60 % of X => (3/5) X
People already solicited = 40% of T => (2/5) T
Now, as per the information given in the question :
(3/5)X = $400 . (2/5) . T --------------------------- 1
Remaning Amount is 40 % i.e ( 2/5 ) X ------because school has already received 60%
And the remaining people are 60 % i.e (3/5) .T -----because 40% of the people are already solicited
So, average contribution required from the remaining targeted people is
(2/5) X = (Amount required) . (3/5) . T ----------------------------------- 2
Divide eqn 1 by eqn 2
Amount required = $177.78
B
Answer: B
Question: The star running back on our football team got most of his total yardage
running. The rest was catching passes. He caught passes for 60 yards.
His total yardage was 150 yards. The running back for the other team
got 200 yards. How many yards did the star running back on our football
team get running?
Options:
A)50 yards
B)60 yards
C)70 yards
D)80 yards
E)90 yards
Rationale: .The other team is extra information. 150 – 60 = 90
He got 90 yards running.
correct answer E
Answer: E
Question: 25 people are there, they are shaking hands together, how many hand shakes possible, if they are in pair of cyclic sequence.
Options:
A)24
B)25
C)44
D)48
E)50
Rationale: n for cyclic hand shake and n-1 for linear handshake.
so here no of hand shake is 25.
ANSWER:B
Answer: B
Question: A man complete a journey in 10 hours. He travels first half of the journey at the rate of 21 km/hr and second half at the rate of 26 km/hr. Find the total journey in km.
Options:
A)220 km
B)224 km
C)230 km
D)200 km
E)234 km
Rationale: 0.5x/10 + 0.5x/10 = 20
--> x/10 + x/10 = 40
--> 2x = 10x40
--> x = (10x40)/2 =200 km.
Answer : D.
Answer: D
Question: A researcher computed the mean, the median, and the standard deviation for a set of performance scores. If18 were to be added to each score, which of these three statistics would change?
Options:
A)The mean only
B)The median only
C)The mean and the median
D)The standard deviation only
E)The mean and the standard deviation
Rationale: The correct answer is C.
Answer: C
Question: In how many ways can you line up 7 people in a row if one of them, Stephen, cannot be in the middle or at the either end?
Options:
A)2,880
B)92
C)1,100
D)2,990
E)3,200
Rationale: Since Stephen cannot be placed in the middle or at either end (3 spots), then he can choose 4 spots to sit. The remaining 6 apples can be placed in in 6! ways. Thus the # of arrangements is 4*6! = 2,880.
Answer: A.
Answer: A
Question: Arun borrowed a sum for 4 years on S.I. at 12%. The total interest paid was Rs. 360. Find the Principal.
Options:
A)Rs.700
B)Rs.650
C)Rs.800
D)Rs.750
E)Rs.850
Rationale: Explanation :
P=100×SI/RT
=100×360/12×4
=100×30/4
=25×30
=750
Answer : Option D
Answer: D
Question: 14 men and 3 boys finish a job in 7 days, 14 men and 14 boys finish it in 6 days. 13 men and 13 boys shall finish it in how many days?
Options:
A)18
B)07
C)12
D)19
E)12
Rationale: 14 M + 3 B ----- 7 days
14 M + 14 B ------- 6 days
13 M + 13 B -------?
196 M + 42 B = 182 M +182 B
14 M = 140 B => 1 M = 10 B
140 B + 3 B = 143 B ---- 7 days
130 B + 13 B = 143 B -----? => 7 days
Answer: B
Answer: B
Question: Jim wishes to buy 3 gifts that cost 23 dollars, 9 dollars, and 12 dollars. He has 1/4 of the money
he needs. How much more money must he earn in order to buy the gifts?
Options:
A)$57
B)$47
C)$33
D)$17
E)$27
Rationale: $23 + $9 + $12 = $44 needed
1/4 x $44 = $11 on hand
$44 - $11 = $33 to earn
correct answer C
Answer: C
Question: A tank is filled in 5 hours by three pipes A, B and C. The pipe C is twice as fast as B and B is twice as fast as A. How much time will pipe A alone take to fill the tank?
Options:
A)77 hrs
B)81 hrs
C)35 hrs
D)17 hrs
E)19 hrs
Rationale: Suppose pipe A alone takes x hours to fill the tank.
Then, pipes B and C will take x/2 and x/4 hours respectively to fill the tank.
1/x + 2/x + 4/x = 1/5
7/x = 1/5 => x = 35 hrs.
Answer: C
Answer: C
Question: 25 is subtracted from 75% of a number, the result is 50. Find the number?
Options:
A)150
B)75
C)125
D)95
E)100
Rationale: (75/100) * X â€“ 25 = 50
7.5X = 750
X = 100
Answer:E
Answer: E
Question: What is 92% of 3/4?
Options:
A)6.9
B)69.0
C)0.6845
D)0.6859
E)0.69
Rationale: Soln:-
120% = 12/10
5/8 * 12/10 = 60/80 = 6/8 = 3/4
=0.69
Answer: E.
Answer: E
Question: J and M were each paid x dollars in advance to do a certain job together. J worked on the job for 8 hours and M worked for 2 hours less than J. If M gave J y dollars of her payment so that they would have received the same hourly wage, what was the dollar amount, in terms of y, that J was paid in advance?
Options:
A)a)4y
B)b)5y
C)c)6y
D)d)7y
E)e)9y
Rationale: J and M were both paid x dollars
If M gave Y dollars from her X to J then at the end
J will have X+Y dollars
M will have X- Y dollars
Now since the hourly wages have to be same then
Hourly wage of J = (X+Y) / 8 (Since J worked for 8 hrs)
Hourly wage of M = (X-Y) / 6 (Since M worked 2 hrs less than J)
Equating both
(X+Y)/8=(X-Y)/6
on simplifying X=7Y
Answer D
Answer: D
Question: My grandson is about as many days as my son in weeks, and my grandson is as many months as I am in years. My grandson, my son and I together are 120 years. Can you tell me my age in years ?
Options:
A)56
B)72
C)68
D)91
E)85
Rationale: Let m be my age in years. If s is my son's age in years, then my son is 52s weeks old. If g is my grandson's age in years, then my grandson is 365g days old. Thus,
365g = 52s.
Since my grandson is 12g months old,
12g = m.
Since my grandson, my son and I together are 120 years,
g + s + m = 120.
The above system of 3 equations in 3 unknowns (g, s and m) can be solved as follows.
m / 12 + 365 m / (52 x 12) + m = 120 or
52 m + 365 m + 624 m = 624 x 120 or
m = 624 x 120 / 1041 = 72.
So, I am 72 years old.
correct answer is B)72
Answer: B
Question: A certain truck uses 18 gallons of diesel fuel in traveling 250 miles. In order for the truck to travel the same distance using 10 gallons of diesel fuel, by how many miles per gallon must the truck’s fuel mileage be increased?
Options:
A)8
B)10
C)12
D)15
E)27
Rationale: There are two sets 18G1 gallons and 10G2 gallons details given.
18 gallons covering 250 miles
Then 1 G1 is used to cover 15 miles.
Now for 10 G2 covering 2750 miles.
then 1 G2 is used to cover 25 miles.
There must 25- 15 = 10 miles per gallon increment is needed for 10 gallons to improve the mileage to cover 270 miles.
IMO B is correct answer.
Answer: B
Question: If all the sides of a right triangle increase in length by 5%, then by what percentage does the area of the triangle increase?
Options:
A)10.25%
B)20.50%
C)25.75%
D)30.25%
E)35.50%
Rationale: Let B be the base and H be the height of the original triangle.
The original area is (1/2)BH.
The area of the expanded triangle is (1/2)(1.05B)(1.05H) = (1.05)(1.05)(1/2)BH = 1.1025(1/2)BH
The answer is A.
Answer: A
Question: A certain junior class has 1,000 students and a certain senior class has 800 students. Among these students, there are 40 siblings pairs, each consisting of 1 junior and 1 senior. If 1 student is to be selected at random from each class, what is the probability that the 2 students selected at will be a sibling pair?
Options:
A)3/40,000
B)1/3,600
C)1/20,000
D)1/60
E)1/15
Rationale: Total number of ways of choosing one student from each group is = 800 * 1000
Number of cases in which a sibling pair will be got is = 40
Thus the probability that the 2 students selected will be a sibling pair is
= 40 /(800 * 1000)
= 1/20,000
C
Answer: C
Question: The product of all the prime numbers less than 15 is closest to which of the following powers of 10?
Options:
A)10^9
B)10^8
C)10^7
D)10^6
E)10^5
Rationale: OA: E
Answer: E
Question: A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Options:
A)140 m
B)150 m
C)160 m
D)240 m
E)None
Rationale: Sol.
Speed = [60 * 5/18] m/sec = [50/3] m/sec.
Length of the train = (Speed * Time) = [50/3 * 9] m = 150m.
Answer B
Answer: B
Question: John has both apples and bananas. The ratio of apples to bananas is 2 to 5. If there are 6 more bananas than apples, how many bananas are there?
Options:
A)8
B)10
C)12
D)14
E)16
Rationale: Let B be the number of bananas, and A be the number of apples.
Since the ratio of A to B is 2 to 5, that means that A = 2/5B.
We also know that A = B-6. Therefore we can substitute:
B-6 = 2/5B
Now we can solve for B:
If we isolate B, we see that:
3/5B = 6
And so
B = 10
Answer: B
Question: If the cost of x metres of wire is d rupees, then what is the cost of y metres of wire at the same rate?
Options:
A)Rs. (ydS
B)s.	(xy/d)
C)Rs. (xd)
D)Rs. (yd/x)
E)Rs. (yd)
Rationale: Explanation:
Cost of x metres = Rs. d.
Cost of 1 metre=Rs.(d/x)
Cost of y metres=Rs.[(d/x).y]=Rs.(yd/x)
Answer: D
Answer: D
Question: John's Bank's saving amount is decreased 20% due to loan payment and current balance is Rs.24000. Find the actual balance before deduction?
Options:
A)8000
B)8500
C)9000
D)9500
E)30000
Rationale: 20% decreased
80% Balance = 24000
100% = 24000/80*100 = 30000
Answer : E
Answer: E
Question: A company, Chauncy Co., has an annual travel budget of $60,000. The accounting department estimates that transportation expenses will increase 5 percent in the coming year, and nontransportation travel expenses will increase by 15 percent in the coming year. Last year, Chauncy Co. spent $19,500 on transportation-related expenses, and $35,000 on nontransportation travel expenses. If the annual travel budget does not increase this year, and if the accounting department’s estimates are correct, how far over the annual travel budget will expenses be this year?
Options:
A)Expenses will not go over the budget.
B)$725
C)$4,225
D)$5,725
E)$60,725
Rationale: annual travel budget of $60,000
Let, Transportation expenses = T = 19500
and Non-Transportation expenses = N=35000
i.e. Increased Transportation expenses = 1.05T = 20475
and Increased Non-Transportation expenses = 1.15N = 40250
Total Expense = 20475+40250 = 60725
Expense over Budget = Budget - expense = 60000-60725 = 725
Answer: Option B
Answer: B
Question: A man bets on no. 16 on a roulette wheel 14 times and losses each time. On the 15th span he does a quick calculation and finds out that the no. 12 had appeared twice in the 14 spans and is therefore, unable to decide whether to bet on 16 or 12 in the 15th span. Which will give him the best chance and what are the odds of winning on the bet that he takes?
Options:
A)32:2
B)35:1
C)33:4
D)36:23
E)35:27
Rationale: Each of the span is an independent event and the outcome of the 15th span will not depend on the outcome of the earlier spans.
Either ;35:1
B)
Answer: B
Question: If abc = 1 , cde = 0 , and xyu = 0, which of the following must be zero?
Options:
A)E
B)D
C)C
D)B
E)A
Rationale: abc = 1 which means neither a / b/ c is 0
c x de = 0 , we know c is not 0 from above hence either d or e must be 0.
d x a x c = 0, we know from first expression that a and c are not 0 hence d =0.
OPTION B
Answer: B
Question: The dimensions of an open box are 52, 40 and 29 cms. Its thickness is 2 cms. If 1 cm3 of metal used in the box weighs 0.5 gms, the weight of the box is?
Options:
A)6.882 kg
B)6.932 kg
C)8.832 kg
D)6.832 kg
E)3.832 kg
Rationale: 52 * 40 * 29 = 60320
48 * 36 * 27 = 46650
------------
13664
13664 * 1/2 = 6832 => 6.832 kg
Answer: D
Answer: D
Question: The perimeter of a triangle is 32 cm and the inradius of the triangle is 2.5 cm. What is the area of the triangle?
Options:
A)76
B)88
C)66
D)55
E)40
Rationale: Area of a triangle = r * s
Where r is the in radius and s is the semi perimeter of the triangle.
Area of triangle = 2.5 * 32/2 = 40 cm2
Answer:E
Answer: E
Question: The radius of a semi circle is 6.83 cm then its perimeter is?
Options:
A)32.52
B)32.47
C)34.97
D)32.92
E)32.33
Rationale: 36/7 r = 6.3 = 34.97
Answer:C
Answer: C
Question: There are 8 men and 10 women and you need to form a committee of 5 men and 6 women. In how many ways can the committee be formed?
Options:
A)10240
B)11
C)11760
D)812
E)None of these
Rationale: We need to select 5 men from 8 men and 6 women from 10 women
Number of ways to do this
= 8C5 × 10C6
= 8C3 × 10C4 [∵ nCr = nC(n-r)]
=(8×7×6 / 3×2×1) (10×9×8×7 / 4×3×2×1)
=56×210=11760
Answer : C
Answer: C
Question: There are 36 students in a certain geometry class. If one third of the students are boys and three fourths of the boys are under six feet tall, how many boys in the class are under six feet tall?
Options:
A)9
B)12
C)18
D)24
E)27
Rationale: Total Students = 36
One third of the students are boys = 1/3*36 = 12
Three fourths of the boys are under six feet tall = 3/4*12 = 9 ...
Therefore Number of boys in the class under six feet tall = 9 ... Answer A....
Alternatively... Number of boys in the class under six feet tall = 3/4 of 1/3 of Total Students = 3/4*1/3*36 = 9...
Answer A
Answer: A
Question: Nil and Ethan are brothers. They left their home
at the same time and drove to the same beach.
Nil drove at a speed of 40 miles per hour. Ethan
drove at a speed of 20 miles per hour. Nil
arrived at the beach 0.5 hour earlier than Ethan.
What is the distance between their home and the
beach?
Options:
A)30 miles
B)40 miles
C)50 miles
D)60 miles
E)70 miles
Rationale: Every hour, Nil gets ahead of Ethan 40 - 20 =
20 miles. When Nil arrived at the beach, Ethan
is only 20 × 0.5 = 10 miles behind. That tells us
they only drove 1 hour when Nil arrived at the
beach.
The distance between their home and the beach
is
Nil’s speed × Nil’s time
= 40 × 1 = 40 miles.
correct answer B
Answer: B
Question: A goods train runs at the speed of 72 km/hr and crosses a 250 m long platform in 26 sec. What is the length of the goods train?
Options:
A)287 m
B)278 m
C)276 m
D)270 m
E)268 m
Rationale: Speed = 72 * 5/18 = 20 m/sec.
Time = 26 sec.
Let the length of the train be x meters.
Then, (x + 250)/26 = 20
x = 270 m.
Answer:D
Answer: D
Question: Rs. 1300 is divided into three parts A, B and C. How much A is more than C if their ratio is 1/8:1/3:1/4?
Options:
A)Rs.224
B)Rs.216
C)Rs.100
D)Rs.300
E)Rs.400
Rationale: 1/8:1/3:1/4 = 4:8:6
3/18*1300 = 216
ANSWER:B
Answer: B
Question: 8 men can do a piece of work in 12 days. 4 women can do it in 48 days and 10 children can do it in 24 days. In how many days can 6 men, 4 women and 10 children together complete the piece of work?
Options:
A)5 days
B)15 days
C)28 days
D)8 days
E)7 days
Rationale: Explanation:
1 man’s 1 day’s work = 1/8 × 12 = 1/96
6 men’s 1 day’s work = 1 × 6/96 =1/16
1 woman’s 1 day’s work = 1/192
4 women’s 1 day’s work = 1/192 × 4 = 1/48
1 child’s 1 day’s work = 1/240
10 children’s 1 day’s work = 1/24
Therefore, (6 men + 4 women + 10 children)’s 1 day’s work = 1/16 + 1/48 + 1/24
= 1/8
The required No. of days = 8 days
Answer: Option D
Answer: D
Question: The time taken by a man to row his boat upstream is twice the time taken by him to row the same distance downstream. If the speed of the boat in still water is 51 kmph, find the speed of the stream?
Options:
A)77
B)88
C)14
D)12
E)17
Rationale: The ratio of the times taken is 2:1.
The ratio of the speed of the boat in still water to the speed of the stream = (2+1)/(2-1) = 3/1 = 3:1
Speed of the stream = 51/3 = 17 kmph.
Answer:E
Answer: E
Question: How many digits are in the number 50^8 × 8^3 × 11^2 x 10^4?
Options:
A)22
B)20
C)19
D)18
E)17
Rationale: Whenever you are asked to find the number of digits, try to bring the number in multiples of 10. This way, we can wasily calculate the umber of 0's through the powers of 10
50^8 × 8^3 × 11^2 x 10^4 = (5^2*2)^8*2^9*11^2 *10^4= 5^16*2^17*11^2*10^4 = 2*11^2*10^16*10^4 = 242*10^16 x 10^4
Hence we would have 16 trailing 0's and the three digits from 242
Total digits = 3 + 20 = 23
Correct Option: D
Answer: D
Question: David was born 5 years after his father's marriage. His mother is 4 years younger than his father but 20 years older than David who is 8 years old. At what age did the father get married ?
Options:
A)19 years
B)20 years
C)21 years
D)18 years
E)17 years
Rationale: Explanation:
David's present age = 8 years.
His mother's present age = (20 + 8) years = 28 years.
His father's present age = (28 + 4) years = 32 years.
His father's age at the time of David's birth = (32 - 8) years = 24 years.
Therefore David's father's age at the time of marriage = (24 - 5) years = 19 years.
Answer: A
Answer: A
Question: A boy multiplied 987 by a certain number and obtained 559981 as his answer. If in the answer both 98 are wrong and the other digits are correct , then the correct answer would be :
Options:
A)288889
B)556677
C)555681
D)267788
E)268811
Rationale: Explanation:
987 = 3 * 7 * 47.
So, the required number must be divisible by each one of 3, 7, 47
553681 => (Sum of digits = 28, not divisible by 3)
555181 => (Sum of digits = 25, not divisible by 3)
555681 is divisible by each one of 3, 7, 47.
Answer: C) 555681
Answer: C
Question: In a hotel we can order two types of varieties, but we can make 8 more varieties in home. One can choose the four varieties with two from hotel as must. Find how many ways one can order.
Options:
A)14
B)15
C)56
D)28
E)29
Rationale: 2c2*8c2=28ways
ANSWER:D
Answer: D
Question: Find the C.I. on a sum of Rs.1600 for 9 months at 20% per annum, interest being compounded quarterly?
Options:
A)3377
B)2889
C)2522
D)2678
E)7111
Rationale: A = 1600(21/20)3 = 2522
Answer: C
Answer: C
Question: The spherical ball of lead 3 cm in diameter is melted and recast into 3 spherical balls. The diameters of two of these are 1 1/2 cm and 2 cm respectively. The diameter of third ball is?
Options:
A)2.8
B)2.5
C)2.2
D)2.0
E)2.1
Rationale: 4/3 π * 3 * 3 * 3 = 4/3 π[(3/2)3 + 23 + r3]
r = 1.25
d = 2.5
Answer:B
Answer: B
Question: In climbing a round pole of 80 meters height, a monkey climbs 5 meters in a minute and slips 2
meters in the alternate minute. To get to the top of the pole, the monkey would take :
Options:
A)51 minutes
B)54 minutes
C)58 minutes
D)61 minutes
E)63 minutes
Rationale: a monkey climbs 5 meters in one min & slips 2m in other min.
therefore the monkey reach 3meters in 2min
3m=2min
25*3m=25*2min - >75m=50min
hence the remaining 5m jumps the monkey in 1min to reach original height
so 51 min
ANSWER:A
Answer: A