divelab/Sys2Bench huggingface dataset:
Question: At Winson's firm's annual revenue grows twice as fast as its costs. In 2007 it operated at a $1000 loss, it broke even in 2008, and in 2009 its revenues were 44% higher than in 2007. If the firm's revenues and costs grew at a constant rate over this period, what was its profit in 2009?
Options:
A)700
B)1000
C)1300
D)1600
E)2000
Rationale: At Winson's firm's annual revenue grows twice as fast as its costs. First solve for how much revenue is increasing each year:
R2008= R2007*(1+x)
R2009= R2007*(1+x)^2=1.44*R2007
(1+x)^2 = 1.44
1+x=1.2
x=0.2 aka revenue increases 20% each year and cost increases 10% annually
Next solve for R2007and C2007:
R2007= C2007- 1000
1.2*R2007- 1.1*C2007= 0
1.2*[C2007- 1000] - 1.1*C2007= 0
0.1*C2007= 1,200
C2007= 12,000
R2007= 11,000
Finally find 2009 profits:
Profit2009= 1.44*11,000 - 1.21*12,000
Profit2009= 15,840 - 14,520
Profit2009= 1320
Answer: C
Answer: C
Question: Find the invalid no.from the following series 2,3,12,37,86,166,288
Options:
A)3
B)12
C)166
D)86
E)288
Rationale: 3-2=1
12-3=9
37-12=25
86-37=49
166-86=80(this must be 81=167-86=81)
so wrong number in the sequence is 166
difference between two sucessive numbers sequence would be
1,9,25,49,81,121(square of 1,3,5,7,9,11)
C
Answer: C
Question: A sun is divided among X, Y and Z in such a way that for each rupee X gets, Y gets 45 paisa and Z gets 50 paisa. If the share of Y is RS. 18, what is the total amount?
Options:
A)115
B)116
C)117
D)78
E)119
Rationale: x:y:z = 100:45:50
20:9:10
9 --- 18
39 --- ? => 78
ANSWER:D
Answer: D
Question: In a group of cows and hens, the number of legs are 10 more than twice the number of heads. The number of cows is :
Options:
A)5
B)6
C)7
D)10
E)12
Rationale: Let no of cows be x, no of hens be y.
So heads=x+y
Legs=4x+2y
Now, 4x+2y = 2(x+y)+ 10
2x = 10
x = 5.
ANSWER:A
Answer: A
Question: If a < b < c , which of the following must be true?
(I) a < b^2
(II) b − a < c
(III) a^2 > b^2 > c^2
Options:
A)None
B)I only
C)II only
D)III only
E)II and III
Rationale: (I) a < b^2. Not necessarily true fractions: try a=1/3 and b=1/2.
(II) b − a < c. Not necessarily true: try a=-1, b=0, and c=1.
(III) a^2 < b^2 < c^2. Not necessarily true: try a=1, b=2, and c=3.
None of the options must be true.
Answer: A.
Answer: A
Question: A company D has 45 percent of the employees are secretaries and 45 percent are salespeople. If there are 50 other employees of Company D, how many employees does Company D have?
Options:
A)500
B)162
C)180
D)152
E)250
Rationale: Let the total number of employees in the company be x
% of secretaries = 45%
% of salespeople = 45%
% of of employees other than secretaries and salespeople = 100 - 90 = 10%
But this number is given as 50
so 10% of x = 50
x = 500
Therefore there a total of 500 employees in the company D
Correct answer - A
Answer: A
Question: 3640 ÷ 14 × 16 + 340 = ?
Options:
A)0.7
B)3525
C)4480
D)None of these
E)Cannot be determined
Rationale: Solution
Given exp. = 260 × 16 + 340 = 4160 + 340 = 4500.
Answer D
Answer: D
Question: The ratio of investments of two partners is 11:12 and the ratio of their profits is 2 : 3. If A invested the money for 8 months , find for how much time B invested his money?
Options:
A)11
B)27
C)28
D)12
E)19
Rationale: Suppose A invested Rs.11 for 8 months and B invested Rs. 12 for x months.
Ratio of investments of A and B
= (11 x 8) : (12 x x)
= 88 : 12x
{88}/{12x}={2}/{3}\Rightarrow x=11
Answer:A
Answer: A
Question: To a sugar solution of 10 liters containing 50% sugar, 10 liter of water is added. The percentage of sugar in the new solution is?
Options:
A)25%
B)30%
C)15%
D)20%
E)18%
Rationale: Quantity of sugar = 50*10/100 = 5kg
New percentage = 5/20 * 100 = 25%
Answer is A
Answer: A
Question: Three runners W, B and C run a race, with runner W finishing 12m ahead of runner B and 18m ahead of runner C, while runner B finishes 8m ahead of runner C. Each runner travels entire distance at a constant speed. What was the length of the race?
Options:
A)36m
B)48m
C)60m
D)72m
E)84m
Rationale: Let distance of race be x mtrs. Then when W finishes x m , B has run (x- 12)mtrs and C has run x-18 mtrs. so at this point B is 6 m ahead of C. Now to finish race b needs to run another 12 m, so he runs another 12 m. when B finishes race he is 8 m ahead of C. so last 12 m B has run, C has run 10 m.
as speeds are constant, we have equation,
x-12/ x-18 = 12/10 > x = 48.
Answer B
Answer: B
Question: the value of (1+.1+.01+.001) is:
Options:
A)1.001
B)1.011
C)1.003
D)1.111
E)None of them
Rationale: 1.0
0.1
0.01
0.001
-------
1.111
Answer is D
Answer: D
Question: If m and n are positive integers, and m=2n and k=5m, then -
Options:
A)3m is a factor of k/2.
B)2m is a factor of k.
C)m/2 is a factor of k.
D)k is a factor of m.
E)k is a factor of m/2.
Rationale: m=2n --> m is even.
k=5m --> m is factor of k, thus m/2 = integer must also be a factor of k.
Answer: C.
Answer: C
Question: One out of every 500 light bulbs are defected. If 5 out of every 10 defected light bulbs have a broken glass and there are 20 broken glass light bulbs in the shipment, how many light bulbs total are there in the shipment?
Options:
A)2,000
B)5,000
C)10,000
D)20,000
E)52,000
Rationale: out of 500 only 1 bulb is defective.So for 10 defective bulbs, we must have 5000 bulbs
Now out of these 10 bulbs, 5 bulbs, have broken glass
i.e 5 broken glass out of 5000 bulbs
20 broken glass will be from 20000 bulbs
Answer is D
Answer: D
Question: How much is 70% of 40 is greater than 4/5 of 25?
Options:
A)12
B)27
C)18
D)12
E)8
Rationale: (70/100) * 40 â€“ (4/5) * 25
28- 20 = 8
Answer:E
Answer: E
Question: If a sample of data has mean of 21 and SD of 3, which of the following values is more than 2.5 SDs from the mean?
Options:
A)a. 12
B)b. 13.5
C)c. 17
D)d. 23.5
E)e. 26.5
Rationale: Value ismore than 2.5SDfrom the mean means that the distance between the mean and the value must be more than 2.5SD=7.5. So the value either <21-7.5=13.5 or >21+7.5=28.5.
Answer: A.
Answer: A
Question: Two numbers are less than a third number by 40% and 47% respectively. How much per cent is the second number less than the first ?
Options:
A)95%
B)88%
C)85%
D)90%
E)none of these
Rationale: Here, x = 40 and y = 47
Therefore second number
= [[(100 - y)/(100 - x )] x 100 ]% of first number
= [[(100 - 47)/(100 - 40 )] x 100 ]% of first number
i.e, 88.3% of the first.
ANSWER:B
Answer: B
Question: A restaurant meal cost $37.50 and there was no tax. If the tip was more than 10 percent but less than 15 percent of the cost of the meal, then the total amount paid must have been between
Options:
A) $40 and $42
B) $42 and $44
C) $38 and $40
D) $37 and $39
E) $36 and $37
Rationale: The total amount for the meal was between 37.5*1.1=41.25 and 37.5*1.15=43.125. Only option which covers all possible values of the meal is B.
Answer: B.
Answer: B
Question: The number of stamps that Kaye and Alberto had were in the ration of 5:3 respectively. After Kaye gave Alberto 12 of her stamps, the ration of the number of Kaye had to the number of Alberto had was 8:6. As a result of the gift, Kaye had how many more stamps than Alberto?
Options:
A)20
B)30
C)40
D)32
E)90
Rationale: C
K1 = 5x
A1 = 3x
K2 = 5x - 12
A2 = 3x + 12
K2/A2 = 8/6
(5x-12)/(3x+12) = 8/6
6*(5x-12) = 8*(3x+12)
30x - 72 = 24x + 96
6x = 168
x = 28
K2 = 5*28 - 12 = 128
A2 = 3*28 + 12= 96
K2 - A2 = 32
Answer : D
Answer: D
Question: Two goods trains each 500 m long are running in opposite directions on parallel tracks. Their speeds are 60 km/hr and 90 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one?
Options:
A)48
B)93
C)24
D)23
E)12
Rationale: Relative speed = 60 + 90 = 150 km/hr.
150 * 5/18 = 125/3 m/sec.
Distance covered = 500 + 500 = 1000 m.
Required time = 1000 * 3/125 = 24 sec.
Answer:C
Answer: C
Question: Colin has an app on his phone that generates a random integer betwen 1 and 10. He generates
10 random numbers and computes the sum. Compute the number of distinct possible sums
Colin can end up with.
Options:
A)41
B)32
C)75
D)91
E)82
Rationale: The maximum possible sum is 10 * 10 = 100. The minimum possible sum is 10.
Hence, there are 100 - 10 + 1 = 91 possible sums
correct answer D
Answer: D
Question: One man traveled a distance of 61 km in 9hrs. He traveled partly on footat 4 km/hr and partly on bicycle ta 9 km/hr. The distance traveled on foot is?
Options:
A)8 km
B)12 km
C)16 km
D)18 km
E)20 km
Rationale: Let the distance travelled on foot be x km.
Then, distance travelled on bicycle = (61 -x) km.
So, x + (61 -x) = 9
4 9
9x + 4(61 -x) = 9 x 36
5x = 80
x = 16 km.
C
Answer: C
Question: An express traveled at an average speed of 100 km/hr, stopping for 4 min after every 75 km. How long did it take to reach its destination 150 km from the starting point ?
Options:
A)8 hrs 29 min
B)6 hrs 28 min
C)2 hrs 28 min
D)6 hrs 28 min
E)1 hr 34 min
Rationale: Explanation:
Time taken to cover 150 km = 150/100 = 1 hr 30 mins
Number of stoppages = 150/75 - 1 = 1
Total time of stoppages = 4 x 1 = 4 min
Hence, total time taken = 1 hr 34 min.
Answer: E
Answer: E
Question: How many quarters are equal to 7 dollars?
Options:
A)1
B)28
C)12
D)9
E)7
Rationale: 7 * 4 = 28 quarters
Answer : B
Answer: B
Question: If w is three times larger than n , and if 2n+3 is 20% of 25, what is the value of ?
Options:
A)1
B)2
C)3
D)6
E)12
Rationale: Then the wordings of question are misleading. Moreover, it'd also be a bad way to convey w=4n, if it really wanted to convey so.
From other questions that I have seen, proper wordings could be:
If w is three times as large as n
OR simply,
If w is three times n.C
Answer: C
Question: What is the next number in this sequence: 39, 52, 65, 78, 91 ?
Options:
A)107
B)112
C)104
D)99
E)109
Rationale: By subtracting each number from the one after it, we can determine that the numbers are all multiples of 13. By adding 13 to the last number, you get the answer.
91 + 13 = 104
Answer: C
Answer: C
Question: If x and y are perfect squares, then which two of the following is not necessarily a perfect square?
Options:
A)x^2
B)xy
C)4x
D)x+y
E)x^5
Rationale: If x=y=1^2=1, then each option but C is a perfect square, therefore C is NOT necessarily a perfect square.
Answer: C.
Answer: C
Question: If 4x + 22x-1 = 3x+(1/2) = 3x - (1/2)
Options:
A)1/2
B)3/2
C)5/2
D)2
E)7/2
Rationale: 4x+4x/2 = 3x/√3 + 3x.√3
=> 4x.3/2 = 3x.4/√3
=> (4/3)x = 8/(3√3)
=> [4/3]x = [4/3]3/2
=> x = 3/2
ANSWER:B
Answer: B
Question: A farm has chickens, cows and sheep. There are six times the number of chickens and cows than sheep. If there are more cows than chickens or sheep, and together, cows and chickens have a total of 100 feet and heads, how many sheep live at the farm?
Options:
A)5
B)8
C)10
D)4
E)17
Rationale: Chicken - ch
Cows - C
Sheep -S
ch+C=6S
C> ch and c>s
Each cow has 4 legs and 1 head
Each chicken has 2 legs and 1 head
So 5c+3ch=100 (sum of legs and head)
There are 2 possible solutions to this equation
c=11 and ch=9 or
c=14 and ch=10
Since from first equation where ch+c=6s
The sum of ch and c should be divisbile by 6. 20 is not so the only possible solution is c=14 and ch=10. So s=4
Answer : D
Answer: D
Question: The length of a rectangle is increased by 25% and its breadth is decreased by 20%. What is the effect on its area?
Options:
A)10000
B)10020
C)10208
D)10029
E)10182
Rationale: 100 * 100
= 10000
125 * 80
= 10000
Answer:A
Answer: A
Question: Solve This
6 + 7 = 12
8 + 9 = 16
5 + 6 = 10
7 + 8 = 14
Then, 9 + 10 = ??
Options:
A)11
B)12
C)13
D)14
E)18
Rationale: 18
ANSWER:E
Answer: E
Question: 9.009/1.001
Options:
A)0.009
B)0.09
C)0.9
D)9
E)90
Rationale: Answer is 9, move the decimal forward three places for both numerator and denominator or just multiply both by a thousand. The result is 9009/1001= 9
Answer D
Answer: D
Question: If t>0.9, which of the following options can be the value of t?
Options:
A)0.9^2
B)√(0.9)
C)0.09
D)0.9
E)0.9^3
Rationale: Lets take a few examples
When .2 is squared it gives .04
when .5 is squared it gives .25
When .9 is squared it gives .81
So raising a fraction to its power of 2 or 3 only reduces the value of the fraction
This is because
.2 = 2/10
.2^2= 4/100
.2^3=8/1000
Since the denominator gets an extra 0 each time u increase the power , it is going to drag the value down
But if you just think about the opposite case :
Then we can see , if squaring a fraction diminish its value, then taking the square root of it will again increase its value
that is √(0.04) will give you back 0.2
so √(0.04) > 0.04
so obviously diminishing the power will appreciate the value
So t √(0.9) > 0.9
Hence Correct Answer is (B)
Answer: B
Question: Cheese, bologna, and peanut butter sandwiches were made for a picnic in a ratio of 5 to 7 to 8. If a total of 160 sandwiches were made, how many bologna sandwiches
were made?
Options:
A)15
B)30
C)38
D)42
E)56
Rationale: For deciding such task we should calculate all parts 5 + 7 + 8 = 20 parts
and we should calculate how many sandwiches holds 1 part:
160 / 20 = 8 sandwiches in one part
For bologna we have 8 parts so:
7 * 8 = 56
Answer is E
Answer: E
Question: A store has 10 bottles of juice, including 5 bottles of apple juice. In the evening, 6 bottles of juice are sold one by one. What is the probability of selling 3 bottles of apple juice among the 6 bottles? Assume that every bottle has an equal chance of being bought.
Options:
A)4/9
B)6/11
C)8/15
D)10/21
E)12/25
Rationale: The total number of ways to sell 6 bottles from 10 is 10C6 = 210.
The number of ways to sell 3 bottles of apple juice is 5C3*5C3 = 10*10 = 100
P(selling 3 bottles of apple juice) = 100/210 = 10/21
The answer is D.
Answer: D
Question: The length of the bridge, which a train 140 meters long and travelling at 45 km/hr can cross in 30 seconds, is?
Options:
A)388
B)267
C)235
D)288
E)261
Rationale: Speed = (45 * 5/18) m/sec = (25/2) m/sec. Time = 30 sec. Let the length of bridge be x meters. Then, (140 + X)/30 = 25/2 ==> X = 235 m.
Answer: C
Answer: C
Question: For any positive integer n, the sum of the first n positive integers equals [n(n+1)]/2.
What is the sum of all the even integers between 99 and 201?
Options:
A)6540
B)7650
C)8760
D)9870
E)10,980
Rationale: 100 + 102 +...+ 200 = 51*100 + (2+4...+100) = 51*100 + 2(1+2+...+50) =
51*100 + 2(50)(51)/2 = 150*51 = 7650
The answer is B.
Answer: B
Question: What is the solution of the equations x - y = 0.9 and 11(x + y)-1 = 2 ?
Options:
A)x = 3.2, y = 2.3
B)x = 1, y = 0.1
C)x = 2, y = 1.1
D)x = 1.2, y = 0.3
E)None
Rationale: Answer
x - y = 0.9 ...(i)
and 11(x + y)-1=2
⇒ 11/ (x + y) = 2
⇒ 2(x + y) =11
⇒ x + y = 11/2 ...(ii)
On solving Eqs.(i) and (ii),we get
x = 3.2
and y = 2.3
Correct Option: A
Answer: A
Question: Two varieties of wheat - A and B costing Rs. 9 per kg and Rs. 15 per kg were mixed in the ratio 3 : 7. If 5 kg of the mixture is sold at 25% profit, find the profit made?
Options:
A)Rs. 13.50
B)Rs. 14.50
C)Rs. 15.50
D)Rs. 16.50
E)None of these
Rationale: Let the quantities of A and B mixed be 3x kg and 7x kg.
Cost of 3x kg of A = 9(3x) = Rs. 27x
Cost of 7x kg of B = 15(7x) = Rs. 105x
Cost of 10x kg of the mixture = 27x + 105x = Rs. 132x
Cost of 5 kg of the mixture = 132x/10x (5) = Rs. 66
Profit made in selling 5 kg of the mixture = 25/100 (cost of 5 kg of the mixture) = 25/100 * 66 = Rs. 16.50
ANSWER:D
Answer: D
Question: A certain college's enrollment at the beginning of 1992 was 20 percent greater than it was at the beginning of 1991, and its enrollment at the beginning of 1993 was 10 percent greater than it was at the beginning of 1992. The college's enrollment at the beginning of 1993 was what percent greater than its enrollment at the beginning of 1991 ?
Options:
A)17.5%
B)24%
C)30%
D)32%
E)38%
Rationale: Suppose enrollment in 1991 was 100
Then enrollment in 1992 will be 120
And enrollment in 1993 will be 120*1.10=132
Increase in 1993 from 1991 = 132-100= 32
Answer : D
Answer: D
Question: At what rate of annual simple interest,a certain sum will amount to four times in 15 year?
Options:
A)15%
B)17.5%
C)20%
D)25%
E)35%
Rationale: r=?
t=15 yrs
SI=p*r*t/100
Amount = SI+p = 4p
(p*r*15/100)+p = 4p
p(15r/100 + 1) = 4p
15r + 100 = 400
15r = 300
r = 20%
ANSWER:C
Answer: C
Question: At what angle the hands of a clock are inclined at 15 minutes past 5?
Options:
A)67.9
B)67.5
C)67.2
D)67.1
E)67.92
Rationale: Answer: B) 67.5 degrees
Answer: B
Question: The area of a parallelogram is 147 sq m and its base is thrice the corresponding height. Then the length of the base is?
Options:
A)14m
B)29m
C)49m
D)7
E)none
Rationale: b*h=147 b*h=147=>b^2=49m.b=7 Answer: (D)
Answer: D
Question: Albert buys 4 horses and 9 goats for $ 13,400. If he sells the horses at 10% profit and the goats at 20% profit, then he earns a total profit of $ 1880. The cost of a horse is:
Options:
A)$ 3000
B)$ 6000
C)$ 2000
D)$ 8000
E)$ 7000
Rationale: C
$ 2000
Let C.P. of each horse be $ x and C.P. of each cow be $ y.
Then, 4x + 9y = 13400 -- (i)
And, 10% of 4x + 20% of 9y = 1880
2/5 x + 9/5 y = 1880 => 2x + 9y = 9400 -- (ii)
Solving (i) and (ii), we get : x = 2000 and y = 600.
Cost price of each horse = $ 2000.
Answer: C
Question: Free notebooks were distributed in a class among all the students. Each student got notebooks which were one-eighth of the number of student. If number of student been half, then each child would have received 16 notebooks in total. Find the total number of books distributed among students?
Options:
A)456
B)480
C)499
D)501
E)512
Rationale: Let suppose total number of students in class are X.
Then from the question we can conclude it that,
X∗18X=X2∗16=>X=64Total notebooks,=18X2=(18∗64∗64)=512
E
Answer: E
Question: The sum of three numbers is 98. If the ratio of the first to the second is 2:3. And that of the second to the third is 5:8, then the second number is:
Options:
A)17
B)30
C)87
D)27
E)82
Rationale: Let the three parts A, B, C.
Then, A:B = 2:3 and B:C = 5:8
= (5 * 3/5) : (8 * 3/5) = 3:24/5
A:B:C = 2:3:24/5
= 10:15:24 => B = 98 * 15/49 = 30.
Answer:B
Answer: B
Question: When tossing two coins once, what is the probability of heads on both the coins?
Options:
A)2/7
B)3/5
C)2/6
D)1/4
E)1/47
Rationale: Explanation :
Total number of outcomes possible when a coin is tossed = 2
Hence, total number of outcomes possible when two coins are tossed, n(S) = 2 × 2 = 4
E = event of getting heads on both the coins = {HH}
Hence, n(E) = 1
P(E)=n(E)/n(S)=1/4
D
Answer: D
Question: A train is 360 meter long is running at a speed of 60 km/hour. In what time will it pass a bridge of 140 meter length?
Options:
A)87
B)69
C)30
D)72
E)21
Rationale: Speed = 60 Km/hr = 60*(5/18) m/sec = 50/3 m/sec
Total distance = 360+140 = 500 meter
Time = Distance/speed
= 500 * (3/50) = 30 seconds
Answer: C
Answer: C
Question: The average of 13 numbers is 60. Average of the first 7 of them is 56 and that of the last 7 is 61. Find the 8th number?
Options:
A)39
B)83
C)45
D)53
E)64
Rationale: Sum of all the 13 numbers = 13 * 60 = 780
Sum of the first 7 of them = 7 * 56 = 392
Sum of the last 7 of them = 7 * 61 = 427
So, the 8th number = 427 + 392 - 780 = 39.
Answer:A
Answer: A
Question: five children, Arya, Betsy, Chen, Daniel, Emily, are to be seated in a single row of six chairs. If Betsy cannot sit next to Emily, how many different arrangements of the six children are possible?
Options:
A)240
B)480
C)540
D)72
E)840
Rationale: Since it is more time consuming and error prone to find ways Betsy and E not sitting together, It is better we find ways in which they will be together and then subtract from total ways..
total ways = 5!..
ways B and E will be sitting together..
take both B and E as one, then these two together with other 3 can sit in 4! ways ...
Also B and E can sit within themselves in 2! ways..
so the answer required = 5!-2*4!=72..
D
Answer: D
Question: A standard Veggiematik machine can chop 36 carrots in 4 minutes. How many carrots can 6 standard Veggiematik machines chop in 3 minutes?
Options:
A)36
B)54
C)162
D)216
E)324
Rationale: Direct Relationship:-
1 standard Veggiematik machine - 36 Carrots - 4 minutes,
1 standard Veggiematik machine - 9 Carrots - 1 minute,
Now
6 standard Veggiematik machine - ? Carrots - 3 minutes,
Hence = 9X6X3 =324 Carrots
Answer C
Answer: C
Question: The current of a stream runs at the rate of 4 kmph. A boat goes 6 km and back to the starting point in 2 hours, then find the speed of the boat in still water?
Options:
A)9
B)4
C)8
D)5
E)3
Rationale: S = 4
M = x
DS = x + 4
US = x - 4
6/(x + 4) + 6/(x - 4) = 2
x = 8
Answer:C
Answer: C
Question: If A is thrice as fast as B and together can do a work in 15 days. In how many days A alone can do the work?
Options:
A)36
B)20
C)28
D)54
E)45
Rationale: A’s one day’s work= 1/X
B’s one day’s work= 1/3x
A + B’s one day’s work= 1/x + 1/3x = 1/15
= 3+1/3x = 4/3x = 1/15
x = 15*4/3 = 20
ANSWER:B
Answer: B
Question: a, b, c, d, and e are five consecutive numbers in increasing order of size. Deleting one of the five
numbers from the set decreased the sum of the remaining numbers in the set by 20%. Which one of
the following numbers Q was deleted?
Options:
A) a
B) b
C) c
D) d
E) e
Rationale: a+b+c+d+e => 1+2+3+4+5=15
Q=20%*15= 3 =>C
Answer: C
Question: A sells a Cricket Bat to B at a profit of 20%. B sells it to C at a profit of 25%. If C pays $222 for it, the cost price of the Cricket Bat for A is:
Options:
A)150
B)148
C)130
D)160
E)210
Rationale: 125% of 120% of A = 222
125/100 * 120/100 * A = 222
A = 222 * 2/3 = 148.
ANSWER B
Answer: B
Question: Sally has a gold credit card with a certain spending limit, and a platinum card with twice the spending limit of the gold card. Currently, she has a balance on her gold card that is 1/3 of the spending limit on that card, and she has a balance on her platinum card that is 1/9 of the spending limit on that card. If Sally transfers the entire balance on her gold card to her platinum card, what portion of her limit on the platinum card will remain unspent?
Options:
A)11/30
B)29/60
C)17/30
D)13/18
E)11/15
Rationale: Let s assume the platinum card spending limit =x
Gold card spending limit will be =x/2
balance on gold card is =x/2*1/3=x/6
Platinum card unspent limit is= x-1/9x=8/9x
So if gold card balance is transferred then the rest unspent will be
8/9x-x/6=13/18x
So the ans is D
Answer: D
Question: The membership of a committee consists of 3 English teachers, 4 Mathematics teachers, and 2 Social Studies teachers. If 2 committee members are to be selected at random to write the committee’s report, what is the probability that the two members selected will both be social teachers?
Options:
A)2/3
B)1/12
C)2/9
D)1/2
E)1/24
Rationale: Probability of first member an English teacher = 3/9
Probability of second member an English teacher = 2/8
Probability of both being english teacher = 3/9 x 2/8 =1/12 (B)
Answer: B
Question: 32 % of 1500 is
Options:
A)480
B)440
C)370
D)415
E)435
Rationale: 1 % of 1500 is = 1532 % of 1500 is = 32*15 = 480Answer : A
Answer: A
Question: If 4 men can colour 48 m long cloth in 2 days, then 6 men can colour 36 m long cloth in
Options:
A)1 day
B)2 days
C)4 days
D)3 days
E)None
Rationale: The length of cloth painted by one man in one day = 48 / 4 × 2 = 6 m
No. of days required to paint 36 m cloth by 6 men = 36/ 6 × 6 = 1 day.
Option 'A'
Answer: A
Question: A cyclist covers a distnce of 750 m in 2 min 30 sec. What is the speed in km/hr of the cyclist?
Options:
A)28 km/hr
B)18 km/hr
C)20 km/hr
D)22 km/hr
E)24 km/hr
Rationale: Speed = { 750 } m/sec =5 m/sec = { 5 * 18 } km/hr =18km/hr
ANSWER B
Answer: B
Question: A person sold a horse at a gain of 15%. Had he bought it for 25% less and sold it for Rs. 600 less, he would have made a profit of 32%. The cost price of the horse was:
Options:
A)Rs. 3,750
B)Rs. 3,250
C)Rs. 2,750
D)Rs. 2,250
E)None
Rationale: Solution: Let the original CP = Rs. X.
Hence, SP= X + 15% of X = 115X/100 = Rs. 23X/20.
New, CP = X - 25% of X = 75X/100 = 3X/4.
New SP = 3X/4 + 32% of 3X/4 = Rs. 99X/100.
According to the question,
(23x/20)-(99x/100)= 600
Or, (115x-99x)/100 = 600
16x = 600*100
X = 600*100/16 = Rs. 3750.
Answer: Option A
Answer: A
Question: pipes P and Q would fill a cistern 18 and 24 minutes respectively. Both pipes being opened, find when the first pipe must be turned off so that the cistern may be just filled in 12 minutes?
Options:
A)8
B)9
C)2
D)7
E)5
Rationale: x/18 + 12/24 = 1
x = 9
Answer: B
Answer: B