divelab/Sys2Bench huggingface dataset:
Question: A can give B 60 meters start and C 120 meters start in a kilometer race. How much start can B give C in a kilometer race?
Options:
A)63.83
B)111.67
C)111.64
D)111.11
E)101.12
Rationale: A runs 1000 m while B runs 940 m and C runs 880 m.
The number of meters that C runs when B runs 1000 m,
= (1000 * 880)/940=936.17 m.
B can give C = 1000 - 936.17= 63.83 m.
Answer:A
Answer: A
Question: The length of a rectangle is two - fifths of the radius of a circle. The radius of the circle is equal to the side of the square, whose area is 900 sq.units. What is the area (in sq.units) of the rectangle if the rectangle if the breadth is 10 units?
Options:
A)120
B)99
C)88
D)72
E)12
Rationale: Given that the area of the square = 900 sq.units
=> Side of square = √900 = 30 units
The radius of the circle = side of the square = 30 units Length of the rectangle = 2/5 * 30 = 12 units
Given that breadth = 10 units
Area of the rectangle = lb = 12 * 10 = 120 sq.units
Answer: A
Answer: A
Question: Of the employees in a company, 50 % are female who have a master degree. If 20 % of the female employees do not have a master degree, what percent of the employees in the company are female?
Options:
A)60%
B)62.5%
C)63.25%
D)63.5%
E)65%
Rationale: Let E be total no. of employees and F be total no of female employees.
Question asked what is F/E X 100%?
No. of female employees with Masters = 0.5 x E (From the question)
No. of female employees without masters = 0.2 x F (From the question)
Therefore No. of female employees with masters = F - 0.2 F = 0.8 F
The 2 expressions equal each other therefore 0.8F = 0.5E; F/E = 0.5/0.8 = 62.5%
Ans: B
Answer: B
Question: Rs.1540 were divided among John, Paul & Tom in such a way that John had Rs.80 more than Paul and Tom had Rs 60 more than John . How much was Paulâ€™s share?
Options:
A)Rs.575
B)Rs.580
C)Rs.585
D)Rs.590
E)Rs.595
Rationale: Let Paul gets Rs x. Then We can say John gets Rs (x + 80 ) and Tom gets Rs ( x + 140) .
x + 80 + x + x + 140 = 1540
3x = 1320
x = 440 .
Paulâ€™s share = Rs ( 440 + 140 ) = Rs.580
B
Answer: B
Question: A bus can hold 48 passengers. If there are 12 rows of seats on the bus, how many seats are in each row?
Options:
A)2
B)1
C)8
D)6
E)4
Rationale: No. of seats = 48/12 = 4
There are 4 seats in each row
Answer : E
Answer: E
Question: If a certain sample of data has a mean of 25.0 and a standard deviation of 2.0, which of the following pairs contain two values that are each at least 2.5 standard deviations from the mean?
Options:
A)(14.0; 16.5)
B)(14.5; 21.0)
C)(14.0; 26.5)
D)(16.5; 26.0)
E)(19.0; 36.5)
Rationale: 2.5 standard deviation equals to 2.5*2=5;
2.5 standard deviations from the mean, so5 points, from the mean is the range from {mean-5} to {mean+5}, so from 20 to 30:
The correct answer choice must cover all this range: only answer choice E does this.
Answer: E.
Answer: E
Question: A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, the how old is B
Options:
A)10
B)8
C)6
D)5
E)7
Rationale: Let C's age be x years. Then, B's age = 2x years. A's age = (2x + 2) years.
(2x + 2) + 2x + x = 27
5x = 25
x = 5.
Hence, B's age = 2x = 10 years
Answer:A
Answer: A
Question: A collection of books went on sale, and 2/3 of them were sold for $4 each. If none of the 36 remaining books were sold, what was the total amount received for the books that were sold?
Options:
A)$288
B)$135
C)$90
D)$60
E)$54
Rationale: Since 2/3 of the books in the collection were sold, 1/3 were not sold. The 36 unsold books represent 1/3 of the total number of books in the collection, and 2/3 of the total number of books equals 2(36) or 72. The total proceeds of the sale was 72($4) or $288. The best answer is therefore A.
Answer: A.
Answer: A
Question: The least number of four digits which is divisible by 15, 25, 40 and 75 is:
Options:
A)9000
B)9400
C)9600
D)9800
E)9700
Rationale: Greatest number of 4 digits is 9999. L.C.M of 15, 25, 40 and 75 is 600.
On dividing 9999 by 600, the remainder is 399. Required number = 9999 - 399 = 9600
ANSWER:C
Answer: C
Question: Calculate the effect changes in dimension of a rectangle will have on its area, if length is increased by 40% and its breadth is decreased by 25%?
Options:
A)5% increase
B)7% increase
C)6% increase
D)4% increase
E)3% increase
Rationale: let L and B be 100 each
100 * 100 = 10000
L increase by 40% = 140
B decrease by 25% = 75
140 * 75 = 10500
5% increase
ANSWER:A
Answer: A
Question: A and B complete a work in 30 days. A alone can do it in 40 days. If both together can do the work in how many days?
Options:
A)1.0875 days
B)0.1873 days
C)0.0673 days
D)0.0583 days
E)0.0773 days
Rationale: 1/30 + 1/40 = 0.0583 days
ANSWER:D
Answer: D
Question: A shopkeeper purchased 70 kg of potatoes for Rs. 420 and sold the whole lot at the rate of Rs. 6.50 per kg. What will be his gain percent?
Options:
A)12 4/3 %
B)18 1/4 %
C)8 1/3 %
D)6 1/3 %
E)10 2/3 %
Rationale: C
C.P. of 1 kg = 420/7 = Rs. 6
S.P. of 1 kg = Rs. 6.50
Gain % = 0.50/6 * 100 = 25/3 = 8 1/3 %
Answer: C
Question: Some of 50%-intensity red paint is replaced with 25% solution of red paint such that the new paint intensity is 30%. What fraction of the original paint was replaced?
Options:
A)1/30
B)1/5
C)2/3
D)3/4
E)4/5
Rationale: Let total paint = 1
Let amount replaced = x
50 (1-x) + 25x = 30
x = 4/5
ANSWER:E
Answer: E
Question: There are 56 lights which are functional and each is controlled by a separate On/Off switch. Two children X and Y start playing with the switches. X starts by pressing every third switch till he reaches the end. Y, thereafter, presses every fifth switch till he too reaches the end. If all switches were in Off position at the beggining, How many lights are switched On by the end of this operation?
Options:
A)18
B)19
C)17
D)15
E)16
Rationale: Editing my solution:
Number of switches = 56
Number of switches turned on by X: 3, 6, ... 54 = 18
Number of switches turned on by Y: 5, 10, ....55 = 11
Few switches are turned on by X and later turned off by Y: LCM(3,5) = 15x = 15, 30,....90 = 6.
Subtract the above 6 switches from both X and Y as they are turned off.
Number of switches that are turned on = (18- 6) + (11 - 6) = 17
Answer: C
Answer: C
Question: Sanoop bought 8 t-shirts at an average price (arithmetic mean) of Rs.526. If Sanoop returned 2 t-shirts to the retailer, and the average price of the remaining t-shirts was Rs.505, then what is the average price, of the three returned t-shirts?
Options:
A)560
B)589
C)562
D)563
E)564
Rationale: Total price of 8 t-shirts= 8*526=4208
Total price of 6 t-shirts=5*505=3030
Total price of 2 t-shirts=4208-3030=1178
Average price of 3 t-shirts=1178/2=589
Correct option Answer:B
Answer: B
Question: Thurston wrote an important seven-digit phone number on a napkin, but the last three numbers got smudged. Thurston remembers only that the last three digits contained at least one zero and at least one non-zero integer. If Thurston dials 15 phone numbers by using the readable digits followed by 15 different random combinations of three digits, each with at least one zero and at least one non-zero integer, what is the probability that he will dial the original number correctly?
Options:
A)1/9
B)10/243
C)1/18
D)10/271
E)1/1000000
Rationale: If the last three digits have 1 zero (XX0), the total # of numbers possible is 9*9*3 (multiply by 3 since XX0 can be arranged in 3 ways: XX0, X0X, or 0XX).
If the last three digits have 2 zeros (X00), the total # of numbers possible is 9*3 (multiply by 3 since X00 can be arranged in 3 ways: X00, 00X, or X0X).
P = 15/(9*9*3+9*3) = 1/18.
Answer: C.
Answer: C
Question: If six boys sit in a row, then what is the probability that three particular boys are always together is?
Options:
A)1/5
B)1/4
C)1/3
D)1/7
E)2/5
Rationale: Six boys can be arranged in a row in 6! ways.
Treat the three boys to sit together as one unit then there 4 boys and they can be arranged in 4! ways.
Again 3 boys can be arranged among them selves in 3! ways.
Favorable outcomes = 3!4!
Required probability = 3!4!/6! = 1/5
A
Answer: A
Question: A sum of Rs. 2665 is lent into two parts so that the interest on the first part for 8 years at 3% per annum may be equal to the interest on the second part for 3 years at 5% per annum. Find the second sum?
Options:
A)1686
B)1640
C)6829
D)2780
E)2790
Rationale: (x*8*3)/100 = ((2665 - x)*3*5)/100
24x/100 = 39975/100 - 15x/100
39x = 39975 => x = 1025
Second sum = 2665 – 1025 = 1640
Answer: B
Answer: B
Question: How many meters of carpet 50cm, wide will be required to cover the floor of a room 30m * 20m?
Options:
A)1000
B)1050
C)1100
D)1200
E)1300
Rationale: 50/100 * x = 30 * 20 => x = 1200
ANSWER:D
Answer: D
Question: All of the students of the Music High School are in the band, the orchestra, or both. 90 percent of the students are in only one group. There are 91 students in the band. If 60 percent of the students are in the band only, how many students are in the orchestra only?
Options:
A)30
B)33
C)36
D)39
E)42
Rationale: 60% of students are in the band only, so 30% of students are in the orchestra only.
Since 10% of students are in both, then 70% of students are in the band which is 91 students.
The number of students in the orchestra is (30/70)*91 = 39.
The answer is D.
Answer: D
Question: Yesterday it took Robert 3 hours to drive from City A to City B. Today it took Robert 2.5 hours to drive back from City В to City A along the same route. If he had saved 30 minutes in both trips, the speed for the round trip would be 80 miles per hour. What is the distance between city A and city B?
Options:
A) 90
B) 180
C) 150
D) 240
E) 300
Rationale: 2d/80 = 4.5 ( because time = 3 + 2.5 - 1 hrs)
=> d = 180
Answer - B
Answer: B
Question: Six students are equally divided into 3 groups, then, the three groups were assigned to three different topics. How many different arrangements E are possible?
Options:
A) 30
B) 60
C) 90
D) 180
E) 540
Rationale: 90 is the number of ways you can assign 3 teams formed out of 12 people to 3 different tasks.
But now you can order the 3 tasks in 3! ways. T1 T2 T3 or T2 T1 T3.... etc etc.
I was confused between 90 and 540 but since question used the wordarrangementsdecided to go with complete arrangements E including the order of tasks.
could you explain the highlighted step... i'm getting 90 = 15 * 3!
suppose the students are numbered 1,2,3,4,5,6 and tasks are X,Y and Z
one of the 15 possible ways of forming teams is 12, 34, 56. these teams can be assigned to 3 tasks in 3! = 6 ways
X--	Y--	Z
12--	34--	56
12--	56--	34
34--	12--	56
34--	56--	12
56--	12--	34
56--	34--	12
so the answer should be 15*6 = 90
But now you can fruther decide which task you want to perform first X Y or Z..C
Answer: C
Question: The difference between the place values of two fives in the numerical 86510529 is
Options:
A)0
B)4905
C)49050
D)490500
E)None of them
Rationale: Required difference = (500000-500)
=490500.
Answer is D
Answer: D
Question: The velocity of a falling object in a vacuum is directly proportional to the amount of time the object has been falling. If after 5 seconds an object is falling at a speed of 90 miles per hour, how fast will it be falling after 18 seconds?
Options:
A)18 miles per hour
B)90 miles per hour
C)216 miles per hour
D)324 miles per hour
E)5400 miles per hour
Rationale: Since Velocity is proportional to Time
Velocity =k*Timewhere k is the constant of proportionality
Time= 5 seconds
Velocity = 5k = 90 miles per Hour
i.e. k = 18
i.e. The relation between Velocity and Time becomes
Velocity =18*Time
Time= 18 seconds
Velocity = 18*18 = 324 miles per hour
Answer: Option D
Answer: D
Question: A cement mixture is composed of 3 elements. By weight, 1/2 of the mixture is sand, 1/5 of the mixture is water, and the remaining 15 pounds of the mixture is gravel. What is the weight of the entire mixture in pounds?
Options:
A)30
B)40
C)50
D)60
E)80
Rationale: Let the total weight be x.
Sand content= (1/2)x
Water content= (1/5)x
Gravel=x-(1/2)x-(1/5)x=(3/10)x=15
x=50
Then answer will be C=50
Answer: C
Question: The speed of a boat in upstream is 30 kmph and the speed of the boat downstream is 70 kmph. Find the speed of the boat in still water and the speed of the stream?
Options:
A)10 kmph
B)20 kmph
C)12 kmph
D)97 kmph
E)15 kmph
Rationale: Speed of the boat in still water
= (30+70)/2
= 50 kmph. Speed of the stream
= (70-30)/2
= 20 kmph.
Answer: B
Answer: B
Question: Between 1980 and 1990 a small town's population increased from 10000 to 12500. Between 1990 and 2000 its population increased from 12500 to 14500. By what percent did the rate of population growth decrease from the period 1980-1990 to the period 1990-2000?
Options:
A)20%
B)24%
C)28%
D)32%
E)36%
Rationale: Solution:
This is a percent decrease problem. We will use the formula: percent change = (new – old)/old x 100 to calculate the final answer.
We first set up the ratios of population growth to initial population for the two periods. The first ratio will be for the period 1980-1990, and the second ratio will be for the period 1990-2000. Because the populations are in hundreds, we do not have to express all the trailing zeros in our ratios.
1980-1990
growth/initial population = 2500/10000 = 1/4
1990-2000
growth/initial population = 2000/12500 = 4/25
Because each ratio is not an easy number to use, we can simplify each one by multiplying each by the LCM of the two denominators, which is 100. Keep in mind that we are able to do this only because our answer choices are expressed in percents.
1980-1990
growth/initial population = (1/4) x 100 = 25
1990-2000
growth/initial population = (4/25) x 100 = 16
We can plug 25 and 16 into our percent change formula:
(new – old)/old x 100
[(16 – 25)/25] x 100
-9/25 x 100
At this point we can stop and consider the answer choices. -9/25 x 100 is -36, so the decrease is by 36%.
Answer E.
Answer: E
Question: Simplify: 244 x 301
Options:
A)73144
B)73143
C)73200
D)72956
E)73444
Rationale: 244 x 301 = 244 x (300 + 1)
= 73200 + 244
=73444
Answer is E
Answer: E
Question: What is the ratio between perimeters of two squares one having 3 times the diagonal then the other?
Options:
A)3: 4
B)3: 9
C)3: 2
D)3: 1
E)3: 3
Rationale: d = 3d d = d
a√2 = 3d a√2 = d
a = 3d/√2 a = d/√2 => 3: 1
Answer: D
Answer: D
Question: 14, 23, 32, 41, 50, 59, …
In the sequence above, each term is 9 more than the previous term. What is the 41st term Z of the sequence?
Options:
A)360
B)365
C)369
D)374
E)383
Rationale: First term , a= 14
Common difference , d = 9
nth term , tn = a + (n-1)d
41st term Z, t41 = a+ 40*d = 14 + 40*9 = 374
Answer D
Answer: D
Question: A set of football matches is to be organized in a "round-robin" fashion, i.e., every
participating team plays a match against every other team once and only once. If 3
matches are totally played, how many teams participated?
Options:
A)4
B)5
C)6
D)7
E)3
Rationale: 2 ways to solve this problem..
summation(x)=n(n-1)/2
n(n-1)/2=3;
n^2-n-6=0
Ans : 3
ANSWER:E
Answer: E
Question: Evaluate: 45678 * 8*4*8 = ?
Options:
A)730848
B)705265
C)730846
D)730596
E)731848
Rationale: According to order of operations, 8?4?8 (division and multiplication) is done first from left to right
8/4 = 2* 8 = 16
Hence
45678 * 8*4*8 = 45678 * 16 = 730848
correct answer A
Answer: A
Question: Twenty percent of the skiers that tried out for the ski patrol were selected. Of those that were not selected, 15 skiers were CPR certified and 25 were not. How many skiers tried out for the ski patrol?
Options:
A)40
B)50
C)60
D)70
E)80
Rationale: Not Selected = 80%
If total is x.
Then 0.8x=15+25=40
x=50
Hence answer is B.
Answer: B
Question: Raman mixed 24 kg of butter at Rs. 150 per kg with 36 kg butter at the rate of Rs. 125 per kg. At what price per kg should he sell the mixture to make a profit of 40% in the transaction?
Options:
A)Rs.129
B)Rs.198
C)Rs.189
D)Rs.128
E)Rs.129
Rationale: CP per kg of mixture = [24(150) + 36(125)]/(24 + 36) = Rs. 135
SP = CP[(100 + profit%)/100]
= 135 * [(100 + 40)/100]
= Rs.189.
Answer:C
Answer: C
Question: A part of certain sum of money is invested at 10% per annum and the rest at 16% per annum, if the interest earned in each case for the same period is equal, then ratio of the sums invested is?
Options:
A)8:5
B)4:9
C)4:3
D)4:1
E)4:2
Rationale: 16:10
= 8:5
Answer: A
Answer: A
Question: The area of the maximum size of the circle described from the 10 inch square?
Options:
A)75.5 sq inch
B)76.5 sq inch
C)77.5 sq inch
D)78.5 sq inch
E)79.5 sq inch
Rationale: 10 inch square means sides of sq are 10inch
then circle is within square so diameter would be 10 inch maximum and radius is 5inch
so area of the circle is = pi*r*r=3.14*5*5=78.5 sq inch
ANSWER:D
Answer: D
Question: What approximate value will come in place of the question mark(?) in the below question?
(47% of 1442 - 36% of 1412) + 63 = ?
Options:
A)237
B)278
C)278
D)252
E)271
Rationale: Explanation:
Since there are 5 cups of each kind,prepared with milk or tea leaves added first,are identical hence,total number of different people ways of presenting the cups to the expert is 10!/(5! x 5!)= 252
Answer: D) 252
Answer: D
Question: Three numbers are in the ratio 4 : 5 : 6 and their average is 30 . The largest number is:
Options:
A)33
B)77
C)36
D)18
E)16
Rationale: Explanation:
Let the numbers be 4x, 5x and 6x. Therefore,
(4x+5x+6x)/3 = 30
15x = 90
x = 6
Largest number = 6x = 36.
ANSWER:C
Answer: C
Question: The average weight of a class of 24 students is 35 kg. If the weight of the teacher be included, the average rises by 400 g. The weight of the teacher is
Options:
A)45 kg
B)75kg
C)25kg
D)35 kg
E)55 kg
Rationale: Explanation:
Weight of the teacher = (35.4 x 25 - 35 x 24) kg = 45 kg.
Answer: A
Answer: A
Question: Bob bikes to school every day at a steady rate of x miles per hour. On a particular day, Bob had a flat tire exactly halfway to school. He immediately started walking to school at a steady pace of y miles per hour. He arrived at school exactly t hours after leaving his home. How many miles is it from the school to Bob's home?
Options:
A)(x + y) / t
B)2(x + t) / xy
C)2xyt / (x + y)
D)2(x + y + t) / xy
E)x(y + t) + y(x + t)
Rationale: Say the distance to school is 10 miles, x=5 miles per hour and y=1 miles per hour, then:
Time Bob spent biking would be 5/5=1 hour, and time he s pent walking would be 5/1=5 hours, so t=1+5=6 hours.
Now, plug x=5, y=1, and t=6 into the answer choices to see which one yields the distance of 10 miles. Only answer choice C fits.
Answer: C.
Answer: C
Question: Which of the following numbers is between 1⁄4 and 1⁄5?
Options:
A).45
B).35
C).29
D).22
E).15
Rationale: 1/4 = .25
1/5 = .2
The only number between these two is 0.22.
The answer is D.
Answer: D
Question: A train 240 m in length crosses a telegraph post in 16 seconds. The speed of the train is?
Options:
A)16 kmph
B)88 kmph
C)54 kmph
D)18 kmph
E)19 kmph
Rationale: S = 240/16 * 18/5
= 54 kmph
Answer: C
Answer: C
Question: A survey of employers found that during 1993 employment costs rose 3.5 percent, where employment costs consist of salary costs and fringe-benefit costs. If salary costs rose 3 percent and fringe-benefit costs rose 8.5 percent during 1993, then fringe-benefit costs represented what percent of employment costs at the beginning of 1993 ?
Options:
A) 16.5%
B) 9%
C) 35%
D) 55%
E) 65%
Rationale: The amount by which employment costs rose is equal to 0.035(salary costs + fringe benefit costs);
On the other hand the amount by which employment costs rose is equal to 0.03*salary costs + 0.085*fringe benefit costs;
So, 35(S+F) = 30S+85F --> S = 10F --> F/S = 1/10 --> F/(S+F) = 1/(1+10) = 1/11 = 0.09.
Answer: B.
Answer: B
Question: The value of C+5C(7C)(5CC)when C= 7 is:
Options:
A)420754
B)420777
C)420170
D)420175
E)420715
Rationale: Solution:
C+5C(7C)(5CC)
Put the value of C= 7 in the above expression we get,
7+ 35(7 x 7)(5x7 x 7)
= 7+ 35(49)(5 Ã— 49)
= 7 + 420175
=420175
Answer : D
Answer: D
Question: A walks around a circular field at the rate of one round per hour while B runs around it at the rate of six rounds per hour. They start in the same direction from the same point at 7.30 a.m. They shall first cross each other at?
Options:
A)7.42 am
B)7.45 am
C)8.30 am
D)9.45 am
E)10.00 am
Rationale: Since A and B move in the same direction along the circle, so they will first meet each other when there is a difference of one round between the two.
Relative speed of A and B = 6 - 1 = 5 rounds per hour.
Time taken to complete one round at this speed = 1/5 hr = 12 min.
ANSWER A
Answer: A
Question: A basket of 1430 apples is divided equally among a group of apple lovers. If 45 people join the group, each apple lover would receive 9 apples less. How many apples did each person get before 45 people joined the feast?
Options:
A)20.
B)21
C)22
D)23
E)24
Rationale: if 1430 is divisible by anyone of the answer choices.
A.1430/20 = 143/2
B 1430/21 = 1430/21
C 1430/22 = 65
If 1430 apple was divided among 65 people, each would have received 22.
After addition of 45 people the answer should be 13. 1430/110 = 13.
C is the answer.
Answer: C
Question: In a coded language
If
tomato = 3
apple = 2
math = 1
then
mathematics = ?
Options:
A)1
B)2
C)3
D)4
E)5
Rationale: mathematics=4
because no. of vowels in mathematics=4
ANSWER:D
Answer: D
Question: Mike needs 30% to pass. If he scored 212 marks and falls short by 22 marks, what was the maximum marks he could have got?
Options:
A)343
B)777
C)780
D)867
E)232
Rationale: If Mike had scored 22 marks more, he could have scored 30%
Therefore, Mike required 212 + 22 = 234 marks
Let the maximum marks be m.
Then 30 % of m = 234
(30/100) × m = 234
m = (234 × 100)/30
m = 23400/30
m = 780
Answer:C
Answer: C
Question: Latha travels from A to B a distance of 1000 miles in 10 hours. He returns to A in 5 hours. Find his average speed?
Options:
A)100mph
B)125.98mph
C)156.15mph
D)133.3mph
E)110.5mph
Rationale: Speed from A to B = 1000/10 = 100 mph
Speed from B to A = 1000/5 = 200 mph
Average speed = 2*100*200 / 300 = 133.3mph
Answer is D
Answer: D
Question: A man bought 20 shares of Rs. 50 at 5 discount, the rate of dividend being 4 %. The rate of interest obtained is
Options:
A)5%
B)5.28%
C)5.30%
D)5.50%
E)6%
Rationale: Shares = 20 shares
50 at 5 discount
rate divident 4%
req ===> 5.28%
ANSWER B
Answer: B
Question: Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is
45 kmph. For how many minutes does the bus stop per hour?
Options:
A)12
B)11
C)10
D)9
E)20
Rationale: SPEED OF THE BUS EXCLUDING STOPPAGES = 54 KMPH
SPEED OF THE BUS INCLUDING STOPPAGES = 45 KMPH
LOSS IN SPEED INCLUDING STOPPAGES = 54-45 = 9 KMPH
IN HOUR BUS COVERS 9 KM LESS DUE TO STOPPAGES
HENCE DISTANCE/SPEED = 9/54 = 1/6 HR = 60/6 MIN = 10 MIN
ANSWER C
Answer: C
Question: A rectangular garden is to be twice as long as it is wide. If 180 yards of fencing, including the gate, will completely enclose the garden, what will be the length of the garden, in yards?
Options:
A)60
B)70
C)80
D)90
E)100
Rationale: ALTERNATE APPROACH
Backsolving ( Using answer options to reach the correct answer ) can work wonders here if one is fast in calculations.
Given Perimeter is 180
So, 2 ( L + B ) = 180
Or, L + B = 90
Now use the answer options ( Given Length ; Breath will be half the length)
(A) 60
L = 60 ; B = 30
L + b = 90
(B) 70
L = 70 ; B = 35
L + b = 105
(C) 80
L = 80; B = 40
L + b = 120
(D) 90
L = 90; B = 45
L + b = 135
(E) 100
L = 100; B = 50
L + b = 150
Thus you see no, need of any calculations, U can reach the correct option only by checking options ; correct answer will be (A)
Answer: A
Question: 653Ã—1001=?
Options:
A)649011
B)540041
C)654321
D)653001
E)643001
Rationale: 653Ã—(1000+1)
653000+1
653001
answer D
Answer: D
Question: Total 90 cows 30 cow gives each 2 liter milk 30 cow gives each 3/4 liter milk 30 cow gives each 1/4 liter milk this is split into 3 son per each 30 cows & 30 liter milk how?
Options:
A)10
B)12
C)15
D)16
E)30
Rationale: 30 cow 2 liter each =60 liter
30 cow 3/4 liter each= 3/4=0.75*30=22.5
30 cow 1/4 liter each = 1/4=0.25*30=7.5
add 60+22.5+7.5=90
milk split into 3 son each 30 liter then 90/3=30
ANSWER:E
Answer: E