divelab/Sys2Bench huggingface dataset:
Question: As a treat for her two children, a mother runs to the freezer in which she has three cherry ice pops, four orange ice pops, and four lemon ice pops. She chooses two at random to bring outside to the children, but realizes as she runs out the door that she cannot bring them different flavors without one being jealous of the other and getting even more upset. What is the probability that she has to return to the freezer to make sure that they each receive the same flavor?
Options:
A)3/5
B)5/7
C)8/11
D)11/15
E)13/20
Rationale: P(2 cherry) = 3/11 * 2/10 = 6/110
P(2 orange) = 4/11 * 3/10 = 12/110
P(2 lemon) = 4/11 * 3/10 = 12/110
P(2 of the same flavor) = 30/110
P(2 different flavors) = 1 - 30/110 = 80/110 = 8/11
The answer is C.
Answer: C
Question: If x and y are positive integers such that (3x + 7y) is a multiple of 11, then which of the followings are divisible by 11?
Options:
A)4x + 6y
B)4x - 9y
C)4x + 6y
D)9x + 4y
E)8x + 4y
Rationale: By hit and trial method, we get x=5 and y=1 such that 3x + 7y = 15 + 7 = 22 is a multiple of 11.
Then
(4x + 6y) = (4 × 5 + 6 × 1) = 26 which is not divisible by 11
(x + y + 4) = (5 + 1 + 4) = 10 which is not divisible by 11
(9x + 4y) = (9 × 5 + 4 × 1) = 49 which is not divisible by 11
(4x - 9y) = (4 × 5 - 9 × 1) = 20 - 9 = 11 which is divisible by 11
Answer is B
Answer: B
Question: If the sum of a number and its square is 272, What is the number?
Options:
A)16
B)77
C)25
D)87
E)171
Rationale: Explanation:
Let the integer be x.
Then, x + x2 = 272
x2 + x - 272 = 0
(x + 17) (x – 16) = 0
x = 16
ANSWER: A
Answer: A
Question: If x and y are positive integers such that y is a multiple of 5 and 3x + 8y = 700, then x must be a multiple of which of the following?
Options:
A)3.
B)6.
C)7.
D)8.
E)10.
Rationale: If y is a multiple of 5, then 8y is also a multiple of 5.
3x = 700 - 8y
700 - 8y is even and it is a multiple of 5.
Thus x must also be even and a multiple of 5.
Therefore x must be a multiple of 10.
The answer is E.
Answer: E
Question: A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If three marbles are picked at random, what is the probability that they are all blue?
Options:
A)1/455
B)1/452
C)1/459
D)1/455
E)1/451
Rationale: Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles.
Probability that all the three marbles picked at random are blue = 3C3/15C3
= (1 * 3 * 2 * 1)/(15 * 14 * 13)
= 1/455
Answer: A
Answer: A
Question: The compound ratio of 2/3, 6/7, 1/5 and 1/8 is given by?
Options:
A)7/98
B)1/48
C)1/98
D)3/350
E)1/68
Rationale: 2/3 * 6/7 * 1/5 * 1/8 = 12/1400 = 3/350
ANSWER:D
Answer: D
Question: The Malibu Country Club needs to drain its pool for refinishing. The hose they use to drain it can remove 60 cubic feet of water per minute. If the pool is 60 feet wide by 100 feet long by 10 feet deep and is currently at 80% capacity, how long will it take to drain the pool?
Options:
A)1000
B)1400
C)1200
D)800
E)1000
Rationale: volume of pool = 60*100*10 cu.ft , 80% full = 60*100*10*0.8 cu.ft water is available to drain.
draining capacity =60 cu.ft /min therefore time taken = 60*100*10*0.8/ 60 min= 800 min
D
Answer: D
Question: Rs.1210 were divided among 3 person P, Q, R so that P:Q=5:4 and Q: R=9:10. Then R gets the amount?
Options:
A)Rs.300
B)Rs.400
C)Rs.480
D)Rs.500
E)Rs.520
Rationale: P : Q = 5 : 4, Q : R = 9 : 10 = ( 9 x 4 / 9 ) : ( 10 x 4 / 9 ) = 4 : 40 / 9.
So, P : Q : R = 5 : 4 : 40 /9 = 45 : 36 : 40
Sum of ratio terms is = ( 45 + 36 + 40 ) =121.
R share of amount is Rs (1210 x 40 / 121) = Rs.400.
B
Answer: B
Question: If 40 men can make 30 boxes in 20 days, How many more men are needed to make 60 boxes in 25 days?
Options:
A)28
B)24
C)22
D)26
E)28
Rationale: Explanation :
Given that 40 men can make 30 boxes in 20 days
Let x more men are needed to make 60 boxes in 25 days
Then (40 + x) men can make 60 boxes in 25 days
More boxes, more men(direct proportion)
More days, less men(indirect proportion)
Hence we can write as
⇒ 30 × 25 × (40 + x) = 60 × 20 × 40
⇒ 25 × (40 + x) = 2 × 20 × 40
⇒ 5 × (40 + x) = 2 × 4 × 40
⇒ (40 + x) = 2 × 4 × 8 = 64
⇒ x = 64 − 40 = 24. Answer : Option B
Answer: B
Question: What is the ratio between perimeters of two squares one having 3 times the diagonal then the other?
Options:
A)4:8
B)1:4
C)6:2
D)3:1
E)1:3
Rationale: d = 3d d = d
a√2 = 3d a√2 = d
a = 3d/√2 a = d/√2 => 3: 1
ANSWER:B
Answer: B
Question: 10 play kabadi, 30 play kho kho only, 5 play both gmaes. Then how many in total?
Options:
A)30
B)35
C)38
D)40
E)45
Rationale: 10 play kabadi =>n(A)=10,
5 play both gmaes.=> n(AnB)=5
30 play kho kho only,=>n(B)=n(B only)+n(AnB)=30+5=35
Total => n(AUB)= n(A)+n(B)-n(AnB)
= 10+35-5
= 40
ANSWER:D
Answer: D
Question: A train running at the speed of 300 km/hr crosses a pole in 15 seconds. What is the length of the train?
Options:
A)1200 m
B)1250 m
C)1300 m
D)1350 m
E)1450 m
Rationale: Speed=(300 * 5/18) m/sec
= (250/3) m/sec Length of the train
= (Speed x Time)
= (250/3 * 15) m = 1250 m.
Answer:B
Answer: B
Question: A superhero flies at an incredible rate of 1000 kilometers per minute. What is her speed in miles per hour? [1km = 0.6 miles]
Options:
A)6000
B)36000
C)60000
D)600
E)3600
Rationale: To calculate the equivalent of miles in a kilometer
0.6 kilometers= 1 mile
1000 kilometers = (0.6)*1000 = 600 miles
Speed in miles per minute = 600 = 600
1 hour = 60 minutes
Speed in miles per hour = 600 * 60 = 36,000
Correct Answer - B
Answer: B
Question: Tickets numbered 1 to 30 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5?
Options:
A)2/15
B)7/15
C)10/30
D)7/30
E)8/30
Rationale: Here, the sample space S = (1, 2, 3, 4, 5, ...,29, 30).
Let E = the event of getting a multiple of 3 or 5.
E = (3, 6, 9, 12, 15, 18, 5, 10, 20, 21, 24, 25, 27, 30)
P(E) = n(E) / n(S) = 14/30 = 7/15
ANSWER:B
Answer: B
Question: A train 125 m long passes a man, running at 15 km/hr in the same direction in which the train is going, in 10 sec. The speed of the train is?
Options:
A)60 km/hr
B)50 km/hr
C)36 km/hr
D)26 km/hr
E)87 km/hr
Rationale: Speed of the train relative to man = 125/10 = 25/2 m/sec.
= 25/2 * 18/5 = 45 km/hr
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 15 = 45 => x = 60 km/hr.
Answer:A
Answer: A
Question: In Jonathan's pen there are 300 sheep's. 5/6 of the sheep's are white, 2/3 of the sheep's have soft wool. What can't be the number of white sheep's that also have soft wool in the pen?
Options:
A)100
B)200.
C)190.
D)180.
E)160.
Rationale: ..................................White Sheep...........not- white sheep
Softwool............................................................................ 2/3×300 =200
Not soft wool ......................................................................300-200=100
................................5/6 ×300= 250...........300-250=50..........Total = 300
As per the matrix it's obvious that the number of white sheep with Soft Wool cannot be 100. As this would lead to a value of 100 for black sheep with soft wool, an impossible consequence as per the matrix.
Therefore A is the correct answer.
Answer: A
Question: The initial price of an article is Rs.2000 which increases 30% increse in its price in the first year,a 20% decrease in the second year and a 10% increase in the next year. What is the final price of the article ?
Options:
A)Rs.1748
B)Rs.1948
C)Rs.1848
D)Rs.2048
E)Rs.2148
Rationale: The initial price of the article, four years age is Rs. 2000 in the 1st year, price of the article = 2000 + 600 = Rs. 2600. In the 2nd year, price = 2600 - 20% of 2600 = 2200- 520 = Rs. 1680.
In the 3rd year, price = 1680+ 10% of 1680 = 1680 + 168= Rs.1848.
Required price = Rs.1848
Answer:C
Answer: C
Question: A certain truck uses 18 gallons of diesel fuel in traveling 240 miles. In order for the truck to travel the same distance using 10 gallons of diesel fuel, by how many miles per gallon must the truck’s fuel mileage be increased?
Options:
A)8
B)9
C)12
D)15
E)27
Rationale: There are two sets 18G1 gallons and 10G2 gallons details given.
18 gallons covering 240 miles
Then 1 G1 is used to cover 15 miles.
Now for 10 G2 covering 240 miles.
then 1 G2 is used to cover 24 miles.
There must 24 - 15 = 9 miles per gallon increment is needed for 10 gallons to improve the mileage to cover 240 miles.
IMO B is correct answer.
Answer: B
Question: A fast food company plans to build 4 new restaurants. If there are 12 sites that satisfy the company's criteria for location of new restaurant, in how many different ways can company select the 4 sites needed for the new restaurant if the order of selection doesn't matter.
Options:
A)48
B)288
C)495
D)990
E)11880
Rationale: The number of ways of choosing 4 sites out of 12 are counted by = 12C4 ways = 495
Answer: Option C
Answer: C
Question: The average mark of a class of twenty students is 64. If three students whose marks are 32,28 and 34 are removed , then find the approximate average mark of the remaining students of the class.
Options:
A)71
B)74
C)57
D)70
E)80
Rationale: Exp. Total mark of 20 students = 64*20 = 1280,
Total mark after the removal of 3 students = 1280 –(32 +28+34 )
= 1280 – 94 = 1186
Approximate average mark = 1186/(20-3) = 1186/ 17 = 70
Answer: D
Answer: D
Question: A manufacturer is using glass as the surface for the multi-touch screen of its smartphone. The glass on the manufactured phone has a 8% probability of not passing quality control tests. The quality control manager bundles the smartphone in groups of 10. If that bundle has any smartphone that does not pass the quality control test, the entire bundle of 10 is rejected.
What is the probability that a smartphone bundle that will be rejected by quality control?
Options:
A) 0.25
B) .05^10
C) 1-0.92^10
D) 1-0.05^10
E) 0.95^10
Rationale: Find the probability of the opposite event and subtract from 1.
The opposite event is that bundle will NOT be rejected by quality control, which will happen if all 10 phones pass the test, so P(all 10 phones pass test)=0.92^10.
P(at least one phone do not pass the test)=1- P(all 10 phones pass test)=1-0.92^10.
Answer: C.
Answer: C
Question: Find the value of y from given equation: (12)^3 x 6^4 ÷ 432 = y?
Options:
A)2568
B)3468
C)4500
D)4876
E)5184
Rationale: Given Exp. = (12)3 x 64 = (12)3 x 64 = (12)2 x 62 = (72)2 = 5184
432 12 x 62
E
Answer: E
Question: {(481 + 426)2 - 4 x 481 x 426} = ?
Options:
A)3025
B)4200
C)3060
D)3210
E)None of these
Rationale: Explanation :
Here, the given statement is like (a + b)2 - 4ab where a= 481 and b = 426
(a + b)2 - 4ab = (a2 + 2ab + b2) - 4ab = a2 - 2ab + b2 = (a - b)2
Hence {(481 + 426)2 - 4 x 481 x 426} = (481 - 426)2 = 552 = 3025. Answer : Option A
Answer: A
Question: Indu gave Bindu Rs.625 on compound interest for 2 years at 4% per annum. How much loss would Indu has suffered had she given it to Bindu for 2 years at 4% per annum simple interest?
Options:
A)1
B)2
C)7
D)4
E)9
Rationale: 625 = D(100/4)2
D = 1
Answer:A
Answer: A
Question: Magnabulk Corp sells boxes holding x magnets each. The boxes are shipped in crates, each holding b boxes. What is the price charged per magnet, in cents, if Magnabulk charges m dollars for each crate?
Options:
A)100bx/m
B)bx/m
C)bx/(100m)
D)m/(bx)
E)100m/(bx)
Rationale: We're given some facts to work with:
1) Magnabulk Corp sells boxes holding X magnets each.
2) The boxes are shipped in crates, each holding B boxes.
3) Magnabulk charges M DOLLARS for each crate
We're asked for the price charged per magnet, in CENTS....
IF....
X = 2
B = 3
M = 12
(2 magnets per crate)(3 crates) = 6 magnets
$12 for 6 magnets = $2 per magnet = 200 cents per magnet
So we're looking for an answer that equals 200 when X=2, B=3 and M=12. There's only one answer that matches...
Answer is E
Answer: E
Question: in how many ways u can form a group of 11 members from 5 men and 11 women if the men member not more than 3?
Options:
A)2256 ways
B)2356
C)3456
D)4456
E)1554
Rationale: we need team members=11 such that there should not be more than 3 men
so the conditions are (3M,8W),(2M,9W),(1M,10W)
Now, no. of ways=11c11+5c3*11c8+5c2*11c9+5c1*11c10=2256
ANSWER:A
Answer: A
Question: A person was fined for exceeding the speed limit by 10 km/hr.Another person was also fined for exceeding the same speed limit by twice the same.If the second person was traveling at a speed of 35 km/hr,find the speed limit.
Options:
A)487
B)15
C)76
D)29
E)12
Rationale: If x is speed limit,
Speed of first person = x + 10
Speed of 2nd person = x + 20
But speed of 2nd person = 35 kmph
x + 20 = 35
x = 15 kmph.
so speed limit is 15 kmph option D
Answer:	B
Answer: B
Question: The total age of A and B is 11 years more than the total age of B and C. C is how many year younger than A
Options:
A)11
B)12
C)13
D)14
E)15
Rationale: Explanation:
Given that A+B = 11 + B + C
=> A ? C = 11 + B ? B = 11
=> C is younger than A by 11 years
Answer: Option A
Answer: A
Question: 3-3*5+2=
Options:
A)A)2
B)B)-10
C)C)-18
D)D)-17
E)of the above
Rationale: 3-3*5+2 = 5-15 = -10...
so the answer is -10... B
Answer: B
Question: In the Hillside summer camp there are 60 children. 90% of the children are boys and the rest are girls. The camp administrator decided to make the number of girls only 5% of the total number of children in the camp. How many more boys must she bring to make that happen?
Options:
A)50.
B)45.
C)40.
D)60.
E)25.
Rationale: Given there are 60 students , 90% of 60 = 54 boys and remaining 6 girls.
Now here 90% are Boys and 10% are Girls.
Now question is asking about how many boys do we need to add, to make the girls percentage to 5 or 5%..
If we add 60 to existing 54 then the count will be 114and the girls number will be 6 as it.
Now boys are 95% and girls are 5%. ( out of 120 students = 114 boys + 6 girls ).
IMO option D is correct.
Answer: D
Question: If n is a positive integer, what is the remainder when (7^(4n+3))(3^n) is divided by 10?
Options:
A)1
B)2
C)4
D)6
E)8
Rationale: This one took me bout 3 1/2 min. Just testin numbers and what not.
First notice that n is positive. Save time by noticing thatI worked out one solution where n=0 only to find that thats not an option :p.
1-7 stands for ^1 thru 7
1: 7*1=7
2: 7*7=9
3: 7*9=3
4: 7*3=1
5: 7*1=7
6: 7*7=9
7: 7*9=3
Pattern repeats every @ 5. Notice every ^4 or multiple of 4 is always going to be 1. This is just for future notice for similar problems.
so 7^4n+3 ---> if n=1 then its ((7^7)*6))/10 which can say is going to be 3*8--> 18/10 --> R=8
Now from here if id double check just to make sure.
7^4(2)+3*6^2 ---> 7^11*36 or we can just say again 7^11*6 (b/c we are only interested in the units digit).
Since ^12 is going to be 1 that means ^11 is going to be 3 (as taken from our pattern)
so again 3*6=18/10 ---> R =2
B or J in this problem.
Answer: B
Question: When 6 + 2 = 85, 8 + 3 = 115, 7 + 5 = 125, then 5 + 8 = ?
Options:
A)145
B)185
C)245
D)135
E)140
Rationale: 6 + 2 => 6 + 2 = 8 => 8 Ã— 10 + 5 = 85
8 + 3 => 8 + 3 = 11 => 11 Ã— 10 + 5 = 115
7 + 5 => 7 + 5 = 12 => 12 Ã— 10 + 5 = 125
Then 5 + 8 => 5 + 8 = 13 => 13 Ã— 10 + 5 = 135
Answer : D
Answer: D
Question: A honey bee flies for 10 seconds, from a daisy to a rose. It immediately continues to a poppy, flying for 6 additional seconds. The distance the bee passed, flying from the daisy to the rose is 8 meters longer than the distance it passed flying from the rose to the poppy. The bee flies to the poppy at 3 meters per second faster than her speed flying to the rose. The bee flies how many meters per second from the daisy to the rose?
Options:
A)2.6
B)5.6
C)6.3
D)8
E)10
Rationale: Let the speed be 's' and let the distance between rose and poppy be 'x'
The problem boils down to:
Rose to Poppy: s+3=x/6 ------- 1
Daisy to Rose: s=(x+8)/10------ 2
so from 1 we can re write x as x=6s+18
substitute the value of x in 2 gives us s=2.6 m/s
A
Answer: A
Question: How many of the following numbers are divisible by 3 but not by 9 ?
2133, 2343, 3474, 4131, 5286, 5340, 6336, 7347, 8115, 9276
Options:
A)5
B)6
C)7
D)8
E)None of these
Rationale: Explanation:
Marking (/) those which are are divisible by 3 by not by 9 and the others by (X), by taking the sum of digits, we get:s
2133 -> 9 (X)
2343 -> 12 (/)
3474 -> 18 (X)
4131 -> 9 (X)
5286 ->21 (/)
5340 -> 12 (/)
6336 -> 18 (X)
7347 -> 21 (/)
8115 -> 15 (/)
9276 -> 24 (/)
Required number of numbers = 6.
ANSWER IS B
Answer: B
Question: For all numbers c and d, the operation @ is defined by c@d = c^2 - cd. If xy ≠ 0, then which of the following can be equal to zero?
I. x@y
II. (xy)@y
III. x@(x + y)
Options:
A)II
B)I and II
C)I and III
D)II and III
E)All of the above
Rationale: c@d = c^2 - cd=c(c-d).... so c@d will be zero if c=d or c=0.. but a cannot be equal to 0.. as per Q, x and y can take any int value except 0...
now lets look at the choices..
when x=y, it will be 0... so ok...
when we put xy=y, it is possible when x=1 and y any integer... so ok again
when we put x=x+y.... only possibility when y=0 and it is given x and y cannot be 0....so not possible
only l and ll possible
answer: B
Answer: B
Question: Have a look at the formula P = nRT/V.
if R is doubled, T is doubled and V is quadrupled, by what factor does P change.
Options:
A)1
B)2
C)3
D)4
E)5
Rationale: Given,
P = nRT/V
Here, R and T are doubled and V is quadrupled. Applying these conditions we have,
P = n*(2R)*(2T)/(4V)
P = 4nRT/4V
P = nRT/V
Intially, P = nRT/V. After changing R, T & V, P = nRT/V.
Therefore, P changes by a factor of 1.
Answer = A =1
Answer: A
Question: John walking at 4 Kmph reaches his office 8 minutes late. If he walks at 6 Kmph, he reaches there 7 minutes earlier. How far is the office from his house?
Options:
A)3 Km
B)3 1/5 Km
C)4 1/5 Km
D)5 1/5 Km
E)None
Rationale: Formula = S1*S2/S2-S1 * T1+T2/60
= 4*6/2 * 15/6
= 24/2 * 15/60
= 15/5 = 3 Km
A
Answer: A
Question: One fill pipe A is 3 times faster than second fill pipe B and takes 10 minutes less time to fill a cistern than B takes. Find when the cistern will be full if fill pipe B is only opened.
Options:
A)20 min
B)18 min
C)15 min
D)10 min
E)None of these
Rationale: Let B can fill the cistern in x min. Then,
then A can fill the cistern in x⁄3 min
Given x - x⁄3 = 10 ⇒ x = 15 min
Answer C
Answer: C
Question: Thurston wrote an important seven-digit phone number on a napkin, but the last three numbers got smudged. Thurston remembers only that the last three digits contained at least one zero and at least one non-zero integer. If Thurston dials 40 phone numbers by using the readable digits followed by 40 different random combinations of three digits, each with at least one zero and at least one non-zero integer, what is the probability that he will dial the original number correctly?
Options:
A)1/9
B)10/243
C)4/27
D)10/271
E)1/1000000
Rationale: If the last three digits have 1 zero (XX0), the total # of numbers possible is 9*9*3 (multiply by 3 since XX0 can be arranged in 3 ways: XX0, X0X, or 0XX).
If the last three digits have 2 zeros (X00), the total # of numbers possible is 9*3 (multiply by 3 since X00 can be arranged in 3 ways: X00, 00X, or X0X).
P = 40/(9*9*3+9*3) = 4/27.
Answer: C.
Answer: C
Question: What is the least integer greater than 0+0.5?
Options:
A)–2
B)–1
C)0
D)1
E)2
Rationale: This question is just about doing careful Arithmetic and remembering what makes a numberbiggerorsmallercompared to another number.
First, let's take care of the Arithmetic:
(0) + (0.5) = 0.5
On a number line, since we're ADDING +.5 to a number, the total moves to the RIGHT (so we're moving from 0 to 0.5).
Next, the question asks for the LEAST integer that is GREATER than 0.5
Again, we can use a number line. Numbers become greater as you move to the RIGHT. The first INTEGER to the right of 0.5 is 1.
Final Answer:
D
Answer: D
Question: Mathematics, physics, and chemistry books are stored on a library shelf that can accommodate 25 books. Currently, 20% of the shelf spots remain empty. There are twice as many mathematics books as physics books and the number of physics books is 4 greater than that of the chemistry books. Ricardo selects 1 book at random from the shelf, reads it in the library, and then returns it to the shelf. Then he again chooses 1 book at random from the shelf and checks it out in order to read at home. What is the probability Ricardo reads 1 book on mathematics and 1 on chemistry?
Options:
A)3%
B)6%
C)12percent
D)20%
E)24%
Rationale: Shelf can accomodate 25 books but 20% of it is empty so there are in all 20 books.
If no of Chem books = x, number of Physics book = x+4, number of Math books = 2(x+4)
x + x+4 + 2(x+4) = 4x + 12 = 20
x = 2
Chem books = 2, Phy books = 6, Math books = 12
Probability of picking a Math book = 12/20
Probability of picking a Chem book = 2/20
Total Probability = Pick Math first and then Chem + Pick Chem first and then Math
= (12/20) * (2/20) + (2/20) * (12/20) = 12/100 = 12%
Answer: C
Question: A train covers a certain distance at a speed of 200kmph in 4 hours. To cover the same distance in 1 3/4 hours, it must travel at a speed of
Options:
A)400km/hr
B)457km/hr
C)450km/hr
D)650km/hr
E)750km/hr
Rationale: Explanation:
Distance = 200Ã—4 = 800km
Required speed = (800Ã— 4/7) = 457km/hr
Answer: Option B
Answer: B
Question: Two bus tickets from city A to B and three tickets from city A to C cost Rs. 308 but three tickets from city A to B and two tickets from city A to C cost Rs. 292. What are the fares for cities B and C from A ?
Options:
A)s. 4, Rs. 23
B)s. 8.2, Rs. 97.2
C)s. 15, Rs. 14
D)s. 17, Rs. 13
E)s. 17, Rs. 15
Rationale: If fares for cities B and C from A are x and y respectively, then
2x+3y=308 or 6x+9y= 924
3x+2y =292 or 6x+4y= 438
subtracting
5y =486
y= Rs 97.2
Hence B. Rs. 8.2, Rs. 97.2
ANSWER:B
Answer: B
Question: A total of 3000 chocolates were distributed among 120 boys and girls such that each boy received 2 chocolates and each girl received 3 chocolates. Find the respective number of boys and girls?
Options:
A)22,99
B)60,60
C)40,88
D)30,40
E)40,30
Rationale: Let the number of boys be x.
Number of girls is 120 - x.
Total number of chocolates received by boys and girls = 2x + 3(120 - x) = 300
=> 360 - x = 300 => x = 60.
So, the number of boys or girls is 60.
Answer:B
Answer: B
Question: What is the next number of the following sequence.
8, 8, 6, 2,.... ?
Options:
A)-4
B)-5
C)-6
D)-7
E)-8
Rationale: 8-(2*0) = 8
8-(2*1) = 6
6-(2*2) = 2
2-(2*3) = -4
ANSWER:A
Answer: A
Question: A train 500 m long passes a man, running at 9 km/hr in the same direction in which the train is going, in 20seconds. The speed of the train is:
Options:
A)105
B)95
C)90
D)99
E)100
Rationale: Speed of the train relative to man =500/20 m/sec
=25m/sec.
=25x18/5km/hr
= 90 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 9) km/hr.
x - 9= 90 =99 km/hr.
Answer:D
Answer: D
Question: How many ways are there for 3 males and 4 females to sit (around a circular table) if no male should sit next to a male (and no female next to female) and Mary wants to sit with her back on the wall?
Options:
A)6
B)36
C)72
D)100
E)720
Rationale: So Mary has her own chair, fixed position. Other 3 females around the table can sit in 3! ways: the first to the left of Mary and the second to the right or vise-versa. Now, if 3 males will sit between them then no two female or two male will sit next to each other (female-male-female-male-female-male). But these males on their spots can also sit in different ways, namely in 3! different ways, so total 3!*3!=36.
Answer B.
Answer: B
Question: Think of a number, divide it by 6 and add 5 to it. The result is 17. What is the number thought of?
Options:
A)24
B)72
C)297
D)267
E)29
Rationale: Explanation :
17-5 = 12
12 x 6 = 72
Answer : B
Answer: B
Question: The distance from City A to City B is 180 miles. While driving from City A to City B, Bob drives at a constant speed of 40 miles per hour. Alice leaves City A 30 minutes after Bob. What is the minimum constant speed in miles per hour that Alice must exceed in order to arrive in City B before Bob?
Options:
A)45
B)48
C)50
D)52
E)54
Rationale: The time it takes Bob to drive to City B is 180 / 40 = 4.5 hours.
Alice needs to take less than 4 hours for the trip.
Alice needs to exceed a constant speed of 180 / 4 = 45 miles per hour.
The answer is A.
Answer: A