divelab/Sys2Bench huggingface dataset:
Question: 3 cooks have to make 80 burgers. They are known to make 20 pieces every minute working together.The 1st cook began workin alone and made 20 pieces having worked for sometime more than 3 mins.The remaining part of the work was done by second and 3rd cook working together.It took a total of 8 minutes to complete the 80 burgers.How many minutes would it take the 1st cook alone to cook 160 burgers?
Options:
A)16 minutes
B)24 mins
C)32 mins
D)40 mins
E)30 mins
Rationale: Denote by A, B, C the rates of the three cooks in units of burgers/minute.
A + B + C = 20.
Let t be the time in minutes it took the first cook A to make the 20 burgers. So, A*t = 20, and we know that t > 3.
We need to find 8t, as 160 burgers will be made by A in 8 times more than making 20 burgers.
We already know that 8t > 8*3 = 24, so we can eliminate answers (A) and (B).
In addition, (B + C)(8 - t) = 60, or (20 - A)(8 - t) = 60.
Since 20 - A < 20 and 8 - t < 5, looking for integer solutions, we find the only acceptable solution 20 - A = 15 and 8 - t = 4, so t = 4.
I am assuming integer numbers for the solutions based on the answer choices.
Anyway, testing the answer choices, only (C) is a solution.
Therefore, A will make 160 burgers in 8*4 = 32 minutes.
Answer C
Answer: C
Question: A person travels equal distances with speeds of 3 km/hr, 4 km/hr and 5 km/hr and takes a total time of 47 minutes. The total distance is?
Options:
A)1
B)3
C)4
D)45
E)4
Rationale: Let the total distance be 3x km.
Then, x/3 + x/4 + x/5 = 47/60
47x/60 = 47/60 => x = 1.
Total distance = 3 * 1 = 3 km.
Answer:B
Answer: B
Question: X starts a business with Rs.45000. Y joins in the business after 3 months with Rs.30000. What will be the ratio in which they should share the profit at the end of the year?
Options:
A)1:2
B)2:1
C)1:3
D)3:1
E)None of these
Rationale: Explanation :
Ratio in which they should share the profit
= Ratio of the investments multiplied by the time period
= 45000 * 12: 30000 * 9
= 45 * 12: 30 * 9
= 3*12: 2 * 9
= 2:1. Answer : Option B
Answer: B
Question: An engineer undertakes a project to build a road 10 km long in 300 days and employs 30 men for the purpose. After 100 days, he finds only 2 km of the road has been completed. Find the (approximate) number of extra men he must employ to finish the work in time.
Options:
A)20
B)25
C)30
D)35
E)40
Rationale: 30 workers working already
Let x be the total men required to finish the task in next 200 days
2 km done hence remaining is 8 km
Also, work has to be completed in next 200 days (300 - 100 = 200)
We know that, proportion of men to distance is direct proportion
and, proportion of men to days is inverse proportion
Hence, X = (30 * 8 * 100) / (2 *200)
thus, X = 60
Thus, more men needed to finish the task = 60-30=30
Answer : C
Answer: C
Question: What is the least number of square tiles required to pave the floor of a room 11 m 50cm long and 1m 50 cm broad?
Options:
A)724
B)804
C)69
D)844
E)None
Rationale: Solution
Length of largest tile = H.C.F. of 1150cm & 150cm = 50cm.
Area of each tile = (50 x 50)cm2
∴ Required number of tiles	= [1150x150/50x50]
= 69.
Answer C
Answer: C
Question: Mrs. Evans gave a test to her freshmen economics class, which has 29 students enrolled and 24 of them answered question 1 correctly. If 22 answered question 2 correctly and 5 did not take the test then how many answered both questions correctly?
Options:
A)18
B)19
C)22
D)20
E)19
Rationale: Total number of enrolled students = 29
Number of students who did not take test = 5
Hence, number of students who took test = 29 - 5 = 24
Number of students who answered Q2 correctly =24, therefore, all students who took test answered Q2 correctly.
So, number of students who answered Q1 correctly, also answered Q2 correctly = 22.
Number of students who answered both Q1 & Q2 correctly = 22.
ANSWER:C
Answer: C
Question: If x is an odd negative integer and y is an even integer, which of the following statements must be true?
I. (3x + 2y) is negative integer
II. (xy)^2 is negative integer
III. (y^2 - x) is negative integer
Options:
A)None of these
B)I Only
C)II only
D)IIIonly
E)I,II only
Rationale: I. It is true if x > y
II. It is always positive
III. It is not true
Answer : A
Answer: A
Question: How many positive even integers less than 100 contain digits 3 or 7?
Options:
A)16
B)17
C)18
D)10
E)20
Rationale: Two digit numbers:
3 at tens place: 30,32,34,36,38
7 at tens place: 70,72,74,76,78
If 3 and 7 is at units place, the number cant be even
Total:5+5= 10
Answer D
Answer: D
Question: A school has only four classes that contain 10, 20, 30 and 40 students respectively. The pass percentage of these classes are 20%, 30%, 60% and 100% respectively. Find the pass % of the entire school.
Options:
A)56%
B)76%
C)34%
D)66%
E)None of these
Rationale: Solution: The number of pass candidates are 2+6+18+40 = 66 out of total 100.
Hence,
Pass pecentage = 66%.
Answer: Option D
Answer: D
Question: Today is Jack's birthday. One year, from today he will be twice as old as he was 13 years ago. How old is Jack today ?
Options:
A)23 years
B)24 years
C)25 years
D)26 years
E)27 years
Rationale: let Jack's age=xx+1=2(x-13)x=27ANSWER:E
Answer: E
Question: Peter brought a scooter for a certain sum of money. He spent 10% of the cost on repairs and sold the scooter for a profit of $ 1100. How much did he spend on repairs if he made a profit of 20%?
Options:
A)100
B)200
C)300
D)400
E)500
Rationale: E
500
Let the C.P. be $ x. Then, 20% of x = 1100
20/100 * x = 1100 => x = 5500
C.P. = $ 5500, expenditure on repairs = 10%
Actual price = $ (100 * 5500)/110 = $ 5000
Expenditures on repairs = (5500 - 5000) = $ 500.
Answer: E
Question: Find the odd man out
4, 16, 25, 36, 42, 64
Options:
A)36
B)25
C)42
D)95
E)4
Rationale: 2^2 = 4
4^2 = 16
5^2 = 25
6^2 = 36
7^2 = 49
8^2 = 64
ANSWER:C
Answer: C
Question: The average weight of a group of boys is 30 kg. After a boy of weight 33 kg joins the group, the average weight of the group goes up by 1 kg. Find the number of boys in the group originally ?
Options:
A)4
B)8
C)5
D)2
E)9
Rationale: Let the number off boys in the group originally be x.
Total weight of the boys = 30x
After the boy weighing 33 kg joins the group, total weight of boys = 30x + 33
So 30x + 33 + 31(x + 1) = > x = 2.
Answer: D
Answer: D
Question: A man can swim in still water at 4.5 km/h, but takes twice as long to swim upstream than downstream. The speed of the stream is?
Options:
A)1.3
B)1.2
C)1.9
D)1.5
E)1.1
Rationale: M = 4.5
S = x
DS = 4.5 + x
US = 4.5 + x
4.5 + x = (4.5 - x)2
4.5 + x = 9 -2x
3x = 4.5
x = 1.5
Answer:D
Answer: D
Question: Which of the following lines has x-intercept and y-intercept that are integers Q?
Options:
A)y=3x+1
B)y=√x+1
C)y=-2/x
D)y=x^2-1
E)xy=1
Rationale: Values that satisfy y=x^2-1 are (x,y)=(-1,0),(1,0),(0,-1). Hence, they are all integers Q and the correct answer is D.
Answer: D
Question: if a^2+b^2=177and ab=54 then find the value of a+b/a-b?
Options:
A)5
B)15
C)6
D)3
E)7
Rationale: (a+b)^2=a^2+b^2+2ab=117+2*24=225
a+b=15
(a-b)^2=a^2+b^2-2ab=117-2*54
a-b=3
a+b/a-b=15/3=5
Option A
Answer: A
Question: A bag contains 50 p, 25 P and 10 p coins in the ratio 5: 9: 4, amounting to
Rs. 206. Find the number of coins of each type.
Options:
A)165
B)174
C)160
D)163
E)135
Rationale: Let the number of 50 p, 25 P and 10 p coins be 5x, 9x and 4x respectively.
(5x/2)+( 9x/ 4)+(4x/10)=20650x + 45x + 8x = 41201O3x = 4120 x=40.
Number of 50 p coins = (5 x 40) = 200; Number of 25 p coins = (9 x 40) = 360;
Number of 10 p coins = (4 x 40) = 160.
ANSWER C 160
Answer: C
Question: The average of 10 numbers is 23. If each number is increased by 4, what will the new average be?
Options:
A)17
B)27
C)19
D)16
E)87
Rationale: Sum of the 10 numbers = 230
If each number is increased by 4, the total increase =
4 * 10 = 40
The new sum = 230 + 40 = 270 The new average = 270/10 = 27.
Answer:B
Answer: B
Question: Each of the integers from 0 to 9, inclusive, is written on a separate slip of blank paper and the ten slips are dropped into a hat. If 5 of the slips are the drawn, without replacement, what is the probability that all 5 have a even number written on it?
Options:
A)1/252
B)1/10
C)1/8
D)1/2
E)5/9
Rationale: Key is that there is no replacement, so each successive choice will become more skewed towards picking a neg (i.e. the pool of positives decreases, while the pool of negatives stay the same)
P(+ on 1st pick) = 5/10
P(+ on 2nd pick) = 4/9
P(+ on 3rd pick) = 3/8
P(+ on 4rd pick) = 2/7
P(+ on 5rd pick) = 1/6
5/10*4/9*3/8*2/7*1/6=1/252
A
Answer: A
Question: The ratio of the volumes of two cubes is 729 : 1331. What is the ratio of their total surface areas?
Options:
A)81 : 121
B)81 : 128
C)81 : 120
D)81 : 125
E)81 : 122
Rationale: Ratio of the sides = 3√729 : 3√1331 = 9 : 11
Ratio of surface areas = 92 : 112 = 81 : 121
Answer: A
Answer: A
Question: Foodmart customers regularly buy at least one of the following products: milk, chicken, or apples. 60% of shoppers buy milk, 50% buy chicken, and 35% buy apples. If 15% of the customers buy all 3 products, what percentage of Foodmart customers purchase exactly 2 of the products listed above?
Options:
A)5%
B)10%
C)15%
D)25%
E)30%
Rationale: 60-(x+15+z) + 50-(x+15+y) + 35-(z+15+y) + x + +y + z +15 = 100
where x = people who bought MilkChicken
y = people who bought chickenApples
z= people who bought Milk and Apples
x+y+z= the number of people who bought just exactly two products.
Hence solving the above equation we get,
115 -(x+y+z) = 100
Thus, x+y+z= 15
Answer: C
Answer: C
Question: Ayesha’s father was 38 years of age when she was born while her mother was 34 years old when her brother four years younger to her was born. What is the difference between the ages of her parents?
Options:
A)2 years
B)4 years
C)6 years
D)8 years
E)None
Rationale: EXPLANATION
Mother’s age when Ayesha’s brother was born = 34 years.
Father’s age when Ayesha’s brother was born = (38 + 4) years = 42 years.
Required difference = (42 – 34) years = 8 years.
Answer D
Answer: D
Question: The ratio of boarders to day students at a school was originally 2 to 5. However, after a number of new boarders join the initial 60 boarders, the ratio changed to 1 to 2. If no boarders became day students and vice versa, and no students left the school, how many new boarders joined the school?
Options:
A)12
B)15
C)20
D)24
E)30
Rationale: Let x be the number of new boarders.
The ratio changed from 2:5 = 4:10 up to 1:2 = 5:10.
60 / (60+x) = 4/5
x = 15
The answer is B.
Answer: B
Question: Julie put half of her savings in a savings account that pays an annual simple interest and half in a savings account that pays an annual compound interest. After two years she earned $100 and $105 from the simple interest account and the compound interest account respectively. If the interest rates for both accounts were the same, what was the amount of Julie's initial savings?
Options:
A)600
B)720
C)1000
D)1200
E)1440
Rationale: $100 for 2 years = $50 per year.
Extra $5 yearned with the compound interest is the percent yearned on percent. So, $5 is yearned on $50, which means that the interest = 10%.
This on the other hand means that half of the savings = 50*10 = $500. Twice of that = $1,000.
Answer: C.
Answer: C
Question: The cost price of a radio is Rs.1500 and it was sold for Rs.1305, find the loss %?
Options:
A)13%
B)16%
C)17%
D)78%
E)28%
Rationale: 1500 ---- 195
100 ---- ? => 13%
Answer:A
Answer: A
Question: Solve below question 2x + 1 = -19
Options:
A)-8
B)-9
C)9
D)8
E)-10
Rationale: 2x + 1 = -19
x = -10
E
Answer: E
Question: Tom invested Rs. 15000 @ 8% per annum for two years. If the interest is compounded half-yearly, then the amount received by Tom at the end of the year will be?
Options:
A)17,546.75
B)17,547.40
C)17,547.88
D)17,548.32
E)17,548.80
Rationale: P = Rs. 15000; R = 8% p.a. = 4% per half-year; T = 2 years = 4 half-year
Amount = [15000 * (1 + 4/100)4]
= (15000 * (1.04)4) = Rs. 17547.88
Answer: C
Answer: C
Question: A certain scholarship committee awarded scholarships in the amounts of $1250, $2500 and $4000. The Committee awarded twice as many $2500 scholarships as $4000 and it awarded three times as many $1250 scholarships as $2500 scholarships. If the total of $45000 was awarded in $1250 scholarships, how many $4000 scholarships were awarded?
Options:
A)5
B)6
C)9
D)10
E)15
Rationale: Since the starting point is given as the $4000 scholarship,
Assume $4000 scholarships to be x
By the given information, $2500 scholarships = 2x
and $1250 scholarships = 6x
Gievn: Total $1250 scholarships = $45000
6x*1250 = 45000
Solve for x = 6
Option B
Answer: B
Question: There are 9 points marked on the circumference of a circle. How many hexagons can be formed by connecting 6 points of the 9 points?
Options:
A)84
B)86
C)88
D)90
E)92
Rationale: 9C6=84
The answer is A.
Answer: A
Question: To prepare cake of type A, it requires 4 eggs. While to prepare cake of type B, it requires 6 eggs. If there are 30 eggs available, and at least one cake of each type needs to be prepared, maximum how many cakes can be prepared of type B?
Options:
A)1
B)2
C)3
D)4
E)5
Rationale: If a number of type A cakes are prepared, and b number of type B cakes are prepared. Based on total number of eggs used, 4a + 6b = 30.
=> 6b = 30 - 4a
=> b = 5 - (4/6)a = 5 - (2/3)a
To maximize b, we have to minimize a, and a has to be a multiple of 3. Also, since at least one cake of each type is to be prepared, a >= 1.
=> a = 3.
b = 5 - (2/3)3 = 3.
Answer: C
Answer: C
Question: A jogger running at 9 km/hr along side a railway track is 240 m ahead of the engine of a 120 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger?
Options:
A)16
B)11
C)36
D)17
E)12
Rationale: Speed of train relative to jogger = 45 - 9 = 36 km/hr.
= 36 * 5/18 = 10 m/sec.
Distance to be covered = 240 + 120 = 360 m.
Time taken = 360/10 = 36 sec.
Answer:C
Answer: C
Question: If X = 2 + 1/(1+1/(1-1/2))then the value of 4x+7/3
Options:
A)12 2/3
B)15 2/3
C)18 2/3
D)11 2/3
E)17 2/3
Rationale: X = 2 + 1/(1+1/(1-1/2))
= 2 + 1/(1+2)
= 2 + 1/3
X = 7/3 ==> 4X + 7/3 => 4(7/3) + 7/3
=> 28/3 + 7/3
=> 35/3
=> 11 2/3.
Answer is D.
Answer: D
Question: A thief goes away with a SANTRO car at a speed of 30 kmph. The theft has been discovered after half an hour and the owner sets off in a bike at 60 kmph when will the owner over take the thief from the start?
Options:
A)1 hours
B)2 hours
C)2/3 hours
D)1/3 hours
E)2/5 hours
Rationale: -----------30--------------------|
60 30
D = 30
RS = 60 â€“ 30 = 30
T = 30/30 = 1 hours
ANSWER:A
Answer: A
Question: The ratio of two quantities is 10 : 7. If each of the quantities is increased by 2, their ratio changes to 15:11 then the greatest number is?
Options:
A)10
B)12
C)15
D)16
E)20
Rationale: Let the numbers be 10x and 7x
Then 10x+2 / 7x+2 = 15/11
110x+22 = 105x+30
5x = 8
x = 1.6
Greatest number = 10*1.6 = 16
Answer is D
Answer: D
Question: The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is:
Options:
A)74
B)94
C)184
D)364
E)512
Rationale: L.C.M. of 6, 9, 15 and 18 is 90.
Let required number be 90k + 4, which is multiple of 7.
Least value of k for which (90k + 4) is divisible by 7 is k = 4.
Required number = (90 x 4) + 4 = 364.
Answer: Option D
Answer: D
Question: If x^2 + 9/x^2 = 22, what is the value of x - 3/x
Options:
A)36
B)25
C)9
D)5
E)4
Rationale: To find : x-3/x. Let it be t.
=> x-3/x = t
=> (x^2 + 9/x^2) - 2*x*3/x = t^2 (Squaring both sides).
=> (22) - 2*3 = 16
=> t^2 = 16. Thus t=4 or t=-4.
Answer E
Answer: E
Question: College T has 1000 students. Of the 300 students majoring in one or more of the sciences,150 are majoring in Chemistry and 180 are majoring in Biology. If at least 60 of the students are not majoring in either Chemistry or Biology, then the number of students majoring in both Chemistry and Biology could be any number from?
Options:
A)110 to 150
B)60 to 150
C)30 to 150
D)60 to 140
E)70 to 130
Rationale: Total = Chemistry + Biology - Both + Neither
300 = 150 + 180 - Both + N
We know that N (Neither) must be at least 30, so set N=30 and solve:
300 = 150 + 180 - Both + 60
300 = 330 - Both
Both = 30
Even if you're not sure whether 150 is the highest or lowest Both could possibly be, it doesn't matter, because you know it's a boundary point of the range,
Both can not be greater than 150, because even if every chemistry major was also a biology major, there are only 130 chemistry majors total. C the solution.
Answer: C
Question: A certain class of students is being divided into teams. The class can either be divided into 18 teams with an equal number of players on each team or 24 teams with an equal number of players on each team. What is the lowest possible number of students in the class?
Options:
A)6
B)36
C)48
D)60
E)72
Rationale: Prime factorization of 18 = 2*3^2
Prime factorization of 24 = 2^3 *3
LCM of the given numbers = 2^3 *3^2
=72
Answer E
Answer: E
Question: Sukhbir is taller than Randhir but not as tall as Ajit. If Manoj is taller than Nitin, who is shorter than Ajit, then who among them is the shortest?
Options:
A)Nitin
B)Sukhbir
C)Manoj
D)Data inadequate
E)None of these
Rationale: Data Inadequate. As No relation is given among Randhir and Nitin.
ANSWER:D
Answer: D
Question: Students are in clubs as follows: Science-20, Drama-30, and Band-12. No student is in all three clubs, but 8 are in both Science and Drama, 6 are in both Science and Band, and 4 are in Drama and Band.
How many different students are in at least one of the three clubs?
Options:
A)36
B)38
C)42
D)44
E)48
Rationale: Total students = S + D + B - (sum of 2-group overlaps) + (all three)
Total students = 20 + 30 + 12 - (6 + 8 + 4) + 0 = 44 students.answer is D
Answer: D
Question: Find the odd man out.
8, 20, 14, 21, 16, 28, 32
Options:
A)16
B)21
C)8
D)28
E)14
Rationale: Explanation:
Each of the numbers except 21 is a even numbers.
Answer: B) 21
Answer: B
Question: Find the odd man out. 21, 28, 35, 42, 49, 51, 56
Options:
A)21
B)28
C)35
D)42
E)51
Rationale: All numbers except 51 are multiples of 7
Answer is E
Answer: E
Question: A man invests some money partly in 9% stock at 96 and partly in 12% stock at 120. To obtain equal dividends from both, he must invest the money in the ratio:
Options:
A)3:4
B)3:5
C)4:5
D)16:15
E)12:13
Rationale: For an income of $1 in 9% stock at 96, investment =$(96/9)=32/3
For an income of $1 in 12% stock at 120, investment =$(120/12)
=$10
Ratio of investment=32/3:10
=16:15
Option D
Answer: D
Question: In an election between two candidates A and B, the number of valid votes received by A exceeds those received by B by 15% of the total number of votes polled. If 20% of the votes polled were invalid and a total of 4720 votes were polled, then how many valid votes did B get?
Options:
A)1534
B)2999
C)2834
D)2777
E)2991
Rationale: Let the total number of votes polled in the election be 100k.
Number of valid votes = 100k - 20% (100k) = 80k
Let the number of votes polled in favour of A and B be a and b respectively.
a - b = 15% (100k) => a = b + 15k
=> a + b = b + 15k + b
Now, 2b + 15k = 80k and hence b = 32.5k
It is given that 100k = 4720
32.5k = 32.5k/100k * 4720 = 1534
The number of valid votes polled in favour of B is 1534.
Answer: A
Answer: A
Question: The average of 20 numbers is zero. Of them, at the most, how many may be greater than zero?
Options:
A)22
B)28
C)29
D)20
E)21
Rationale: Average of 20 numbers = 0
Sum of 20 numbers = (0 * 20) = 0
It is quite possible that 19 of these numbers may be positive and if their sum is a, then 20th number is (-a).
Answer: D
Answer: D
Question: A man invested an amount of Rs.8000 in a fixed deposit scheme for 2 years at compound interest of 5% per annum. How much amount will Albert get on maturity of the fixed deposit ?
Options:
A)Rs.8600
B)Rs.8620
C)Rs.8820
D)Rs. 8840
E)Rs. 8940
Rationale: Amount = 8000 *1+(5/100)2
= 8000 *21/20 * 21/20
= Rs.8820
ANSWER:C
Answer: C
Question: At the wholesale store you can buy an 8-pack of hot dogs for $1.55, a 20-pack for $3.05, and a 250-pack for $22.95. What is the greatest number of hot dogs you can buy at this store with $211?
Options:
A)1,108
B)2,100
C)2,108
D)2,124
E)2,180
Rationale: I think it should be E.
I can buy 8 250-pack for Rs 22.95*8 = $183.60
Now, I can buy 9 20-pack for 3.05*9 = $15.25
Now, I am left with only $1.15. I cannot but anything with this.
Hence Total Hotdogs = 250*8 + 20*9 = 2180
Answer: E
Question: Fresh grapes contain 90% by weight while dried grapes contain 20% water by weight. What is the weight of dry grapes available from 5 kg of fresh grapes?
Options:
A)2 kg
B)2.4 kg
C)2.5 kg
D)10 kg
E)0.625
Rationale: The weight of non-water in 5 kg of fresh grapes (which is 100-90=10% of whole weight) will be the same as the weight of non-water in x kg of dried grapes (which is 100-20=80% of whole weight), so 5âˆ—0.1=xâˆ—0.8--> x=0.625
Answer: E.
Answer: E
Question: Find the number of shares that can be bought for Rs.8800 if the market value is Rs.20 each with brokerage being 2.5%.
Options:
A)429.3
B)270
C)177
D)166
E)111
Rationale: Explanation:
Cost of each share = (20 + 2.5% of 20) = Rs.20.5
Therefore, number of shares = 8800/20.5 = 429.3
ANSWER:A
Answer: A
Question: A fast food restaurant sells chicken in orders of 6, 9, and 20.
What is the largest number of pieces of chicken you cannot order from this restaurant?
Options:
A)23
B)33
C)43
D)53
E)63
Rationale: 43.
After 6 all numbers divisible by 3 can be ordered (because they can all be expressed as a sum of 6's and 9's). After 26, all numbers divisible by three when subtracted by 20 can be obtained. After 46, all numbers divisible by three when subtracted by 40 can be obtained. After 46, all numbers fit into one of these 3 categories, so all numbers can be obtained. 43 is the last number that doesn't fall into one of these categories (44 = 20 + 6 * 4, 45 = 6 * 6 + 9).
Answer: C
Question: A hat company ships its hats, individually wrapped, in 8-inch by 10-inch by 12-inch boxes. Each hat is valued at $7.50. If the company’s latest order required a truck with at least 384,000 cubic inches of storage space in which to ship the hats in their boxes, what was the minimum value of the order?
Options:
A)$3,000
B)$1,350
C)$1,725
D)$2,050
E)$2,250
Rationale: Number of boxes= Total volume/volume of one box= 384,000/ (8*10*12)= 400
One box costs 7.50, so 400 box will cost= 400*7.5= 3000
A is the answer
Answer: A
Question: Free notebooks were distributed in a class among all the students. Each student got notebooks which were one-eighth of the number of student. If number of student been half, then each child would have received 16 notebooks in total. Find the total number of books distributed among students?
Options:
A)435
B)456
C)467
D)489
E)512
Rationale: Let suppose total number of students in class are X.
Then from the question we can conclude it that,
X∗18X=X2∗16=>X=64Total notebooks,=18X2=(18∗64∗64)=512
E
Answer: E
Question: A dealer purchases 15 articles for Rs. 25 and sells 12 articles for Rs. 30. Find the profit percentage?
Options:
A)60%
B)50%
C)80%
D)70%
E)53%
Rationale: L.C.M of 15 and 12 = 60
CP of 60 articles = Rs. 100 (25 * 4)
SP of 60 articles = Rs. 150 (30 * 5)
Profit percentage = (150 - 100)/100 * 100
= 50%
Answer: B
Answer: B
Question: Two pipes can separately fill a tank in 20 and 30 hours respectively. Both the pipes are opened to fill the tank but when the tank is full, a leak develops in the tank through which one-third of water supplied by both the pipes goes out. What is the total time taken to fill the tank?
Options:
A)18 hrs
B)16 hrs
C)15 hrs
D)12 hrs
E)10 hrs
Rationale: Explanation:
1/20 + 1/30 = 1/12
1 + 1/3 = 4/3
1 --- 12
4/3 --- ?
4/3 * 12 = 16 hrs
ANSWER IS B
Answer: B
Question: A & B started one company. They invest Rs. 1,00,000/- each. They deposit the money to Bank. Bank give 1% interest per month. After 2 years B left from company and asked A to return the money with interest. A says it will take time to release the FD and he assure B to give the money withinterest @0.5%. B Agreed this. What is the profit of A?
Options:
A)48000
B)12000
C)36000
D)24000
E)30000
Rationale: Total Investment : 100000/-*2=200000/-
Interest rate @ 1%= 200000*1%*12*2= 48000/-
Total : 248000/-
Interest to B : 100000/-*0.5%*12*2 = 12000/-
Paid to B : 100000/- + 12000/- = 112000/-
profit of A : 36000/-
Answer is C
Answer: C