divelab/Sys2Bench huggingface dataset:
Question: You collect balls. Suppose you start out with 7. John takes half of one more than the number of balls you have. Since his mother makes balls, Peter decides to triple your balls. How many balls do you have at the end?
Options:
A)6
B)7
C)8
D)9
E)10
Rationale: Solution
Start with 7 balls.
John takes half of one more than the number of balls you have. So John takes half of 7 + 1 which is 4,
so you're left with 7 - 4 = 3.
Peter triples the number of balls you have: 3 × 3 = 9 balls.
So you have 9 at the end.
Correct answer : D
Answer: D
Question: A circular rim 21 inches in diameter rotates the same number of inches per second as a circular rim 35 inches in diameter. If the smaller rim makes x revolutions per second, how many revolutions per minute does the larger rim makes in terms of x ?
Options:
A)48pi/x
B)75x
C)48x
D)45x
E)x/75
Rationale: Let's try the explanation. We have two wheels. One with 21pi and the other one with 35pi. They have the same speed. In the smaller wheel it's 21pi*x, which must be equal to the speed of the bigger one (35pi*a number of revolutions).They are asking that number of revolutions (but in minutes, which makes the question even harder).
Anyway, we have 21pi*x=35pi*a.
(21pi*x)/(35pi). As I said, that's in seconds. So, to convert it to minutes we multiply by 60 and we get the result, 45x.
Ans:D
Answer: D
Question: A group of men decided to do a work in 20 days, but 10 of them became absent. If the rest of the group did the work in 40 days, Find the original number of men?
Options:
A)20
B)50
C)40
D)100
E)25
Rationale: Original number of men = 10*40 / (40-20) =20
Answer is A
Answer: A
Question: Two cubes have their volumes in the ratio 1 : 27. Find the ratio of their surface areas.
Options:
A)1:9
B)2:9
C)3:9
D)5:9
E)None of them
Rationale: Let their edges be a and b. Then,
=a^3/b^3 = 1/27 (or) (a/b)^3 = (1/3)3 (or) (a/b) = (1/3).
Therefore, Ratio of their surface area = 6a^2/6b^2 = a^2/b^2 = (a/b)^2 = 1/9, i.e. 1:9.
Answer is A.
Answer: A
Question: In a normal 5-day work week, each of 12 employees produces 300 items per day-last week, 1/3 of the employees were absent from work for 2/5 of the days in the week. how many total items were produced last week?
Options:
A)18000
B)14400
C)6000
D)15600
E)16,200
Rationale: 1 employee produces 300 items per day
1/3 of the employees were absent for 2/5 days of last week.
==> 4 employees were absent for 2 days.
Items produced by them in 3 days
= 300*3*4
=3600
Items produced by other employees
=8*5*300
=12000
Total items produced = 12000+3600
=15600
ANSWER:D
Answer: D
Question: A small company employs 3 men and 5 women. If a team of 3 employees is to be randomly selected to organize the company retreat, what is the probability that the team will have exactly 2 men?
Options:
A) 5/7
B) 1/7
C) 2/7
D) 3/7
E) 1/2
Rationale: Total ways to choose 4 employees from 8 employees = 8C3
Two men = 5C2
Two women = 3C1
P = (5C2 * 3C1)/8C2 = 5/7 hence A.
Answer: A
Question: The average age of 15 students of a class is 15 years. Out of these, the average age of 5 students is 14 years and that of the other 9 students is 16 years, The age of the 15th student is
Options:
A)11
B)12
C)13
D)14
E)15
Rationale: Explanation:
Age of the 15th student = [15 * 15 - (14 * 5 + 16 * 9)] = (225-214) = 11 years. Answer: A
Answer: A
Question: If f is a number such that –2 ≤ f ≤ 2, which of the following has the largest possible absolute value?
Options:
A)3f – 1
B)x^2 + 1
C)3 – x
D)x – 3
E)x^2 – x
Rationale: Ans is A .. leads to the max value of 7 for f = -2
Answer: A
Question: In how many ways can 5 letters be posted in 3 post boxes, if any number of letters can be posted in all of the three post boxes?
Options:
A)24
B)35
C)13
D)61
E)45
Rationale: The first letter can be posted in any of the 3 post boxes. Therefore, we have 3 possibilities.
Similarly, the second, the third, the fourth and the fifth letter can each be posted in any of the 3 post boxes.
Each of the 5 letters has 3 possibilities because we can post any number of letters in all of the boxes.
Therefore, the total number of ways the 5 letters can be posted in 3 boxes is
3 * 3 * 3 * 3 * 3 = 35
Ans: B
Answer: B
Question: The length of an edge of a hollow cube open at one face is √3 metres. What is the length of the largest pole that it can accommodate?
Options:
A)2 metres
B)3 metres
C)4 metres
D)3√3metres
E)None
Rationale: Solution
Required length	= Diagonal
‹=›√3 a
‹=›(√3×√3) m
‹=›3 m.
Answer B
Answer: B
Question: The volume of cube is equal to the surface area of that cube. Then find the distance of side of the cube?
Options:
A)7
B)10
C)4
D)6
E)8
Rationale: Cube volume = a(power)3 cubic units
Surface area = 6 a(power)2 sq.units
a(power)3 = 6 a(power)2
a = 6 m
Answer is D.
Answer: D
Question: The cost price of 40 articles is the same as the selling price of x articles. If the profit is 25%, what is x?
Options:
A)26
B)28
C)30
D)32
E)34
Rationale: Let the cost price = y
The cost price of 40 articles = 40y
The selling price of x articles = 1.25y*x
1.25y*x = 40y
x = 40 / 1.25 = 32
The answer is D.
Answer: D
Question: How long does a train 120 m long running at the speed of 70 km/hr takes to cross a bridge 145 m length?
Options:
A)13.9 sec
B)12.1 sec
C)17.9 sec
D)13.9 sec
E)47.98 sec
Rationale: Speed = 70 * 5/18 = 19 m/sec
Total distance covered = 120 + 145 = 265 m.
Required time = 265/19 = 13.9 sec.
Answer:D
Answer: D
Question: If a and b are integers and a≠0 which of the following cannot equal 0?
Options:
A)ab
B)a-b
C)a+b
D)ab-b^2
E)a^2+b^2
Rationale: (A) ab
If b=0 , then ab=0
(B) a - b
If a=b , then a-b= =0
(C) a + b
If b=-a , then a+b=0
(D) ab - b^2
If a=b , then ab-b^2= 0
(E) a^2 + b^2
Can't be equal to zero .
If a=0 , then a^2 + b^2	=b^2
if a=-ve , then a^2 + b^2 not equal to 0
Answer E
Answer: E
Question: A man misses a bus by 40 minutes if he travels at 30 kmph. If he travels at 40 kmph, then also he misses the bus by 10 minutes. What is the minimum speed required to catch the bus on time?
Options:
A)11
B)45
C)66
D)72
E)32
Rationale: Let the distance to be travelled to catch the bus be x km
x/30 - x/40 = 30/60 => (4x - 3x)/120 = 1/2 => x = 60 km
By traavelling 30 kmph time taken = 60/30 = 2 hours
By taking 2 hours, he is late by 40 min. So, he has to cover 60 km in at most speed = 60/(4/3) = 45 kmph.
Answer: B
Answer: B
Question: Which of the following is NOT a factor of 10! ?
Options:
A)1440
B)625
C)160
D)80
E)50
Rationale: 625=5*5*5*5 and we dont have four 5 in 10! answer is B
Answer: B
Question: If population of certain city increases at the rate of 5%. If population in 1981 was 138915, then population in 1978 was?
Options:
A)1,20,000
B)1,20,080
C)1,20,900
D)1,29,000
E)1,20,070
Rationale: X * (105/100) * (105/100) * (105/100) = 138915
X = 138915/1.157625
X = 120000
Answer:A
Answer: A
Question: A circular mat with diameter 22 inches is placed on a square tabletop, each of whose sides is 24 inches long. Which of the following is closest to the fraction of the tabletop covered by the mat?
Options:
A)5/12
B)2/5
C)3/2
D)3/4
E)5/8
Rationale: SO we are looking for the area of the cloth over the area of the table
Area of the Cloth = (pi)(r)^2 which is about (3)(11)(11)
Area of the Table = (24)(24)
So the quick way to estimate is looking at the fraction like this: (3/24)(121/24)
I hope this is easy to follow, so with some simplification i get (1/8)(5) = (5/8) Answer is E
Answer: E
Question: There are 28 stations between Ernakulam and Chennai. How many second class tickets have to be printed, so that a passenger can travel from one station to any other station?
Options:
A)800
B)820
C)850
D)870
E)900
Rationale: The total number of stations= 30
From 30 Stations we have to choose any two stations and the direction of travel (Ernakulam to Chennai is different from Chennai to Ernakulam) in 30P2 ways.
30P2= 30*29= 870
ANSWER:D
Answer: D
Question: The total marks obtained by a student in Physics, Chemistry and Mathematics is 150 more than the marks obtained by him in Physics. What is the average mark obtained by him in Chemistry and Mathematics?
Options:
A)75
B)267
C)299
D)266
E)21
Rationale: Let the marks obtained by the student in Physics, Chemistry and Mathematics be P, C and M respectively.
P + C + M = 150 + P
C + M = 150
Average mark obtained by the student in Chemistry and Mathematics = (C + M)/2 = 150/2 = 75.Answer: A
Answer: A
Question: If it is assumed that 60 percent of those who receive a questionnaire by mail will respond and 240 responses are needed, what is the minimum number of questionnaires that should be mailed?
Options:
A)400
B)500
C)600
D)700
E)800
Rationale: Let x be the minimum number of questionnaires to be mailed.
0.6x = 240
x = 400
The answer is A.
Answer: A
Question: How many words can be formed by using all letters of the word 'PIG' ?
Options:
A)6
B)8
C)9
D)5
E)7
Rationale: The word PIG contains 3 different letters
Required number of words = 3P3 = 3! = 3*2*1 = 6
Answer is A
Answer: A
Question: If a man can cover 12 metres in one second, how many kilometres can he cover in 3 hours 45 minutes?
Options:
A)132 km
B)167 km
C)143 km
D)162 kilometres
E)245 km
Rationale: D
12 m/s = 12 * 18/5 kmph
3 hours 45 minutes = 3 3/4 hours = 15/4 hours
Distance = speed * time = 12 * 18/5 * 15/4 km = 162 km.
Answer: D
Question: If x and y are integers such that |y + 3| ≤ 3 and 2y – 3x + 6 = 0, what is the least possible value R of the product xy?
Options:
A)	-12
B)	-3
C)	0
D)	2
E)	None of the above
Rationale: How to deal with inequalities involving absolute values? First example shows us the so callednumber case
In this case we have |y + 3| ≤ 3 which is generalized |something| ≤ some number. First we solve as if there were no absolute value brackets:
y + 3 ≤ 3
y ≤ 0
So y is 0 or negative
Second scenario - remove the absolute value brackets. Put a negative sign around the other side of the inequality,ANDflip the sign:
y + 3 >= -3
y >= -6
Therefore we have a possible range for y: -6=<y<=0
Ok, so far so good, we're half way through. What about x?
Here's the formula: 2y – 3x + 6 = 0, rewrite it as 2y + 6 = 3x.
You can say that 2y + 6 is a multiple of 3 (=3x). So all values which must be integer must also satisfy this constraint. I'm just saying that, so it's easier to evaluate all the possible numbers (-6, -3, 0). If you plug in y = 0, x will be 2 and xy = 0 as the lowest possible value R.
Hence, Answer Choice C is the one to go.
Answer: C
Question: A cube is divided into 512 identical cubelets. Each cut is made parallel to some surface of the cube. But before doing that, the cube is painted with green on one set of opposite faces, red on another set of opposite faces, and blue on the third set of opposite faces. How many cubelets are painted with exactly one colour?
Options:
A)216
B)264
C)296
D)312
E)324
Rationale: Each face of the cube has 8 x 8 = 64 cubelets.
On each face, only the interior cubelets are painted one colour.
On each side, 6 x 6 = 36 cubelets are painted one colour.
Since the cube has six sides, the number of cubes with one colour is 6*36 = 216
The answer is A.
Answer: A
Question: The population of a town is 10000. It increases annually at the rate of 30% p.a. What will be its population after 2 years?
Options:
A)14000
B)14400
C)14500
D)14600
E)16900
Rationale: Formula :
10000 × 130/100 × 130/100 = 16900
Answer : E
Answer: E
Question: John has $2500 in his bank account that earns 10% interest every year. How much will be in John's bank account after one year?
Options:
A)$2600
B)$3000
C)$2250
D)$2750
E)$3500
Rationale: Final number = Initial number + 20%(original number) = 2500 + 10%(2500) = 2500 + 250 = 2750.
Answer D
Answer: D
Question: Mary works in a restaurant a maximum of 45 hours. For the first 20 hours, she is paid $8 per hour. For each overtime hour, she is paid at a rate which is 25% higher than her regular rate. How much Mary can earn in a week?
Options:
A)300
B)420
C)410
D)320
E)400
Rationale: Mary receives $8(20)=$160 for the first 20 hours.
For the 25 overtime hours, she receives $8(0.25) +$8 = $10 per hour, that is $10(25)=$250.
The total amount is $160+$250 = $410
Answer C 410.
Answer: C
Question: What is the probability W of randomly selecting an arrangement of the letters of the wordMEDITERRANEANin which the first letter is E and the last letter is R?
Options:
A)1/13
B)1/20
C)1/26
D)1/50
E)1/100
Rationale: Why do you calculate the total combinations and everything, it is much easier to calculate as follows:
3/13 * 1 * 1 * 1 * 1 ..... * 2/12 = 6/156 = 1/26
This is because 3/13 = Probability that first letter will be E and 2/12 = probability that thefirstletter will be R. Between everything else cuts down to 1*1*1... e.g. probability W of the second letter is 11/11 = 1, > we do not care what's in between.C
Answer: C
Question: A sum of Rs 12,500 amounts to Rs. 15,500 in the 4 years at the rate of simple interest. Find the rate percent
Options:
A)6 %
B)7 %
C)8 %
D)9 %
E)10 %
Rationale: Explanation:
S.I.=P∗R∗T/100=>R=S.I.∗100/P∗T
So, S.I = 15500 - 12500 = 3000.
=>R=3000∗100/12500∗4=6%
Option A
Answer: A
Question: Chlorination is used in industry for the purification of water; 1gm solution of chlorine will remove half of the germs in 1 liter of water. If water containing less than 0.09% of germs is considered clean, what is the minimum amount of chlorine required to purify 150 liter of water containing 0.3 liter of harmful substances?
Options:
A)1
B)2
C)3
D)4
E)5
Rationale: Assuming that it's SUPPOSED to state "0.3" liters of harmful substances, here's how you can answer this question.
First, we have to figure out what .09% of 150 liters is...
1% = .01
.1% = .001
.09% = .0009
So, .0009(150) = .135 liters
We need enough doses of chlorine to get the 0.3 liters down to LESS than .135 liters. Each "dose" of chlorine will remove HALF of the harmful substances...
Start = 0.3 liters
After 1st dose = .15 liters
After 2nd dose = .075 liters
We're now below the .135 liters that we need to be less than.
Final Answer:B
Answer: B
Question: A luxury liner, Queen Marry II, is transporting several cats as well as the crew (sailors, a cook, and one-legged captain) to a nearby port. Altogether, these passengers have 14 heads and 41 legs. How many cats does the ship host?
Options:
A)5
B)6
C)7
D)8
E)9
Rationale: sa's +co +ca +cats = 14. sa's + 1 +1 +cats =14 or sa's +cats =12.
sa's(2) +2 +1 +cats*4 =41 sa's*2 +cats*4 = 38 or sa's +cats*2 =19 or 12-cats +cat*2 =19
then cats =7
C
Answer: C
Question: Two pipes A and B can fill a tank in 4 and 5 hours respectively. If they are turned up alternately for one hour each, the time taken to fill the tank is?
Options:
A)4 hrs 54 min
B)4 hrs 24 min
C)4 hrs 14 min
D)4 hrs 34 min
E)4 hrs 04 min
Rationale: 1/4 + 1/5 = 9/20
20/9 = 2 2/9
9/20 * 2 = 9/10 ---- 4 hours
WR = 1 - 9/10 = 1/10
1 h ---- 1/4
? ----- 1/10
2/5 * 60 = 24 = 4 hrs 24 min
Answer:B
Answer: B
Question: What is the lowest possible common multiple of 2 distinct integers, each greater than 140?
Options:
A)141
B)142
C)282
D)141*141
E)141*142
Rationale: The least common multiple of two numbers greater than 140 is 2(141) = 282, where the two distinct integers are 141 and 282.
The answer is C.
Answer: C
Question: if i earn a profit 50$ in a day and I have 9 employees . After keeping 10 percent profit for me, and distribute remianing money equally among my employees then how much each employee would get?
Options:
A)$3
B)$7
C)$1
D)$5
E)$9
Rationale: Since I earned $50 sp 10 percent would be 5$ and 45$ would remain. Dividing 45 by 9, each employee would get 5$ each and hince option D is correct.
Answer: D
Question: A box contains six bulbs out of which 4 are defective. If four bulbs are chosen at random, find the probability that atleast one bulb is good.
Options:
A)125/167
B)14/15
C)125/126
D)125/186
E)125/128
Rationale: Required probability
= 1 - 1/15
= 14/15
Answer: B
Answer: B
Question: One day a car rental agency rented 3/4 of its cars, including 3/5 of its cars with CD players. If 3/5 of its cars have CD players, what percent of the cars that were not rented had CD players?
Options:
A)29/30
B)24/25
C)19/20
D)14/15
E)9/10
Rationale: The cars with CD players which were not rented is (2/5)(3/5) = 6/25 of all the cars.
The cars which were not rented is 1/4 of all the cars.
The percent of non-rented cars which had CD players is (6/25) / (1/4) = 24/25
The answer is B.
Answer: B
Question: In a certain sequence, the first term is 3, and each successive term is 1 more than the reciprocal of the term that immediately precedes it. What is the fifth term in this sequence?
Options:
A)13/8
B)21/13
C)8/5
D)5/8
E)18/11
Rationale: let five terms in the sequence be a,b,c,d,e
a=3
b= 1+1/3=4/3
c=1+3/4= 7/4
d= 1+4/7 = 11/7
e= 1+7/11 = 18/11
hence answer should be E.
Answer: E
Question: A sock drawer contains 6 socks, each one a different solid color. The colors of the socks are red, orange, yellow, green, indigo, and violet. If a person reaches into the drawer and pulls out two socks, how many different color combinations are possible in the selected pair of socks?
Options:
A)12
B)15
C)21
D)36
E)42
Rationale: Since the order in which we select the socks does not matter, we can use combinations.
We can select 2 socks from 6 socks in 6C2 ways.
6C2 = 15
Answer : B
Answer: B
Question: Mrs. Napier has 23 stickers to give to 9 students for a reward. How many
stickers will each student get? Will there be any stickers left over?
Options:
A)2-5
B)2-4
C)2-6
D)2-3
E)2-8
Rationale: 23/9 = 2 R 5 Mrs. Napier will give each student 2 stickers and there
will be 5 left over.
correct answer A
Answer: A
Question: A rectangular garden is 12m by 5m, what is its area?
Options:
A)12 square meters
B)5 square meters
C)44 square meters
D)60 square meters
E)22 square meters
Rationale: Area of a Rectangle: A = w × h
D) 60 square meters
Answer: D
Question: How many ways are there to award a gold, silver and bronze medal to 11 contending teams?
Options:
A)11 x 10 × 9
B)10!/(3!7!)
C)10!/3!
D)360
E)300
Rationale: we clearly know that there can be only one winning team which deserves the gold medal. we can do the selection in 11 ways
if gold medal is given to 1 of the teams then only possible 10 teams can be considered for silver medal. we can do selection in 10 ways
similarly if gold and silver medals are awarded then only remaining 9 teams can be considered for a bronze medal. we can do the selection in 9 ways
Total number of ways to select the 3 possible medal winners = 11*10 * 9
Correct answer - A
Answer: A
Question: If the true discount on s sum due 2 years hence at 14% per annum be Rs. 140, the sum due is:
Options:
A)s. 768
B)s. 640
C)s. 1960
D)s. 2400
E)s. 2800
Rationale: td=pw*r*t/100 so 140=pw*14*2/100 so pw=500
sum=pw+td..
sum=500+140=640
ANSWER:B
Answer: B
Question: Souju's age is 131% of what it was 10 years ago, but 80 2/3% of what it will be after 10 years. What is her present age?
Options:
A)46 years
B)27 years
C)36 years
D)42 years
E)54 years
Rationale: Let the age before 10 years =x. Then,
131x/100=x+10
â‡’131x=100x+1000
â‡’x=1000/31=32
Present age =x+10=32+10=42
ANSWER:D
Answer: D
Question: By selling 175 apples, a shopkeeper gains the price of 25 apples. His gain per cent is
Options:
A)18.66%
B)17.66%
C)16.66%
D)15.66%
E)14.66%
Rationale: Suppose S.P of 175 apples = Rs 175
Therefore, Gain = Rs 25 => C.P = Rs 150
Gain % = 25/150 x 100 = 16.66%
Gain = 16.66%
ANSWER:C
Answer: C
Question: Exactly 5% of the reporters for a certain wire service cover local politics in Country X. If 30% of the reporters who cover politics for the wire service do not cover local politics in Country X, what percent of the reporters for the wire service do not cover politics?
Options:
A) 20%
B) 42%
C) 44%
D) 92%
E) 90%
Rationale: You are correct. People who cover local politics are a subset of people who cover politics.
30% of reporters who cover politics do not cover local politics so 70% DO cover local politics.
Reporters covering local politics= 70% of reporters covering politics= 5% of all reporters
Reporters covering politics/All Reporters = 5/70 = 1/14
Reporters not covering politics/All Reporters = 13/14 = 92%=D
Answer: D
Question: If k is an integer and 2 < k < 7, for how many different values of k is there a triangle with sides of lengths 3, 6, and k?
Options:
A)0
B)1
C)2
D)3
E)4
Rationale: (6-3) < k < (6+3)
3 < k < 9
Thus k = 4, 5, 6, 7, 8
Since 2 < k < 7, then k can be 4, 5, or 6.
The answer is D.
Answer: D
Question: Worker A takes 8 hours to do a job. Worker B takes 10 hours to do the same job. How long it take both A & B, working together but independently, to do the same job?
Options:
A)40 days
B)40/9 days
C)39/9 days
D)30/9 days
E)60/9 days
Rationale: B
40/9 days
A's one hour work = 1/8.
B's one hour work = 1/10.
(A+B)'s one hour work = 1/8+1/10 = 9/40.
Both A & B can finish the work in 40/9 days
Answer: B
Question: A grocer has a sale of Rs. 4435, Rs. 4927, Rs. 4855, Rs. 5230 and Rs. 4562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 4500?
Options:
A)s. 1991
B)s. 2991
C)s. 3991
D)s. 4991
E)s. 5991
Rationale: Explanation:
Total sale for 5 months = Rs. (4435 + 4927 + 4855 + 5230 + 4562) = Rs. 24009.
Required sale = Rs. [ (4500 x 6) â€“ 24009 ]
= Rs. (27000 â€“ 24009)
= Rs. 2991.
Answer B
Answer: B
Question: A straight line in the xy-plane has a slope of 2 and a y-intercept of 2. On this line, what is the x-coordinate of the point whose y-coordinate is 480 ?
Options:
A)249
B)498
C)239
D)823
E)1,002
Rationale: slope of 2 and a y-intercept of 2
y-coordinate is 480
y = 2x + 2
478 = 2x
x = 239
Answer:
C. 239
Answer: C
Question: 3^4+3^4+3^4=?
Options:
A)a) 3^3
B)b) 3^4
C)c) 3^5
D)d) 3^6
E)e) 3^15
Rationale: The correct answer is C 3^5
3^5 = 3^4+3^4+3^4
Answer: C
Question: A man can row a boat at 20 kmph in still water. If the speed of the stream is 8 kmph, what is the time taken to row a distance of 60 km downstream?
Options:
A)30/16 hours
B)80/13 hours
C)30/73 hours
D)15/7 hours
E)50/13 hours
Rationale: Speed downstream = 20 + 8 = 28 kmph.
Time required to cover 60 km downstream
= d/s = 60/28
= 15/7 hours.
Answer:D
Answer: D
Question: There are 25 Kids in a classroom. 12 Kids are wearing socks and 8 are wearing Shoes. 6 Kids are wearing both.
How many are Bare Feet ?
Options:
A)10
B)20
C)40
D)50
E)11
Rationale: 12 kids wear socks
8 kids wear shoes
6 wear both.
12 â€“ 6 = 6 (wear only socks)
8 â€“ 6 = 2 (wear only shoes)
6 (wear both)
hence, 25 -14 = 11
11 kids are with bare feet.
E
Answer: E
Question: A train 108 m long moving at a speed of 50 km/hr crosses a train 112 m long coming from opposite direction in 6 seconds. The speed of the second train is:
Options:
A)48 km/hr
B)54 km/hr
C)66 km/hr
D)82 km/hr
E)85 km/hr
Rationale: Explanation:
Let the speed of the second train be x km/hr.
Relative speed	= (x + 50) km/hr
=(x + 50) x 5/18 m/sec
=250 + 5x	/18 m/sec
Distance covered = (108 + 112) = 220 m.
220/ [(250+5x)	/18]=6
250 + 5x = 660
x = 82 km/hr.
ANSWER IS D
Answer: D
Question: A trained covered x km at 30 kmph and another 2x km at 20 kmph. Find the average speed of the train in covering the entire 3x km.
Options:
A)20kmph
B)22.5kmph
C)25kmph
D)30kmph
E)35kmph
Rationale: Total time taken = x/30 + 2x/20 hours
= 8x/60 = 2x/15 hours
Average speed = 3x/(2x/15)
= 22.5 kmph
Answer:B
Answer: B
Question: If each side of a square is increased by 25%, find the percentage change in its area.
Options:
A)26.5%
B)36.25%
C)46.25%
D)56.25%
E)66.25%
Rationale: Let each side of the square be a. Then, area = a2.
New side =(125a/100) =(5a/4). New area = (5a/4) 2=(25a2)/16.
Increase in area = ((25 a2)/16)-a2=(9a2)/16.
Increase% = [((9a2)/16)*(1/a2)*100] % = 56.25%.
ANSWER D 56.25%
Answer: D
Question: In a camp, there is a meal for 120 men or 200 children. If 150 children have taken the meal, how many men will be catered to with remaining meal?
Options:
A)20
B)30
C)40
D)50
E)60
Rationale: Here given 120 men = 200 children
therefore 1 child = 3/5 of Man------ step I
Now given that the food was consumed by 150 children
From step I we get 150 children =90 Men ( 1 child = 3/5 Man ie , 150 X 3/5 = 90)
So the food is for (120-90) men = 30 Men
ANSWER:B
Answer: B