divelab/Sys2Bench huggingface dataset:
Question: The average marks of a class of 30 students is 40 and that of another class of 50 students is 60. Find the average marks of all the students?
Options:
A)82.5
B)52.9
C)52.2
D)52.5
E)52.7
Rationale: Sum of the marks for the class of 30 students = 30 * 40 = 1200
Sum of the marks for the class of 50 students = 50 * 60 = 3000
Sum of the marks for the class of 80 students =
1200 + 3000 = 4200
Average marks of all the students = 4200/80 = 52.5
Answer:D
Answer: D
Question: 20 litres of mixture contains 40% alcohol and the rest water. If 8litres of water be mixed with it, the percentage of alcohol in the new mixture would be?
Options:
A)26.32%
B)35.14%
C)28.57%
D)25%
E)31.14%
Rationale: Alcohol in the 20litres of mix. = 40% of 20litres = (40*20/100) = 8litres
water in it = 20-8 = 12litres
new quantity of mix. = 20+8 = 28 litres
Quantity of alcohol in it = 8litres
Percentage of alcohol in new mix. = 8*100/28 = 50/3= 28.57%
Answer is C
Answer: C
Question: Three numbers are in the ratio 4 : 5 : 6 and their average is 25 . The largest number is:
Options:
A)28
B)30
C)36
D)42
E)45
Rationale: Explanation:
Let the numbers be 4x, 5x and 6x. Therefore,
(4x+5x+6x)/3 = 25
15x = 75
x = 5
Largest number = 6x = 30.
ANSWER B
Answer: B
Question: The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is:
Options:
A)448
B)488
C)542
D)548
E)560
Rationale: Required number = (L.C.M. of 12, 15, 20, 54) + 8
= 540 + 8
= 548.
answer :D
Answer: D
Question: Calculate the standard deviation of each data set {10,10,10,10,10}
Options:
A)8.05
B)9
C)10
D)15
E)15.5
Rationale: Standard Deviation Data set A
= √[ ( (9-10)2+(10-10)2+(11-10)2+(7-10)2+(13-10)2 )/5 ] = 2
Standard Deviation Data set B
= √[ ( (10-10)2+(10-10)2+(10-10)2+(10-10)2+(10-10)2 )/5 ] = 0
Standard Deviation Data set C
= √[ ( (1-10)2+(1-10)2+(10-10)2+(19-10)2+(19-10)2 )/5 ] = 8.05
Option A
Answer: A
Question: If x is a positive even number, then each of the following is odd EXCEPT
Options:
A)(x + 3)(x + 5)
B)x^2 + 5
C)x^2 + 6x + 9
D)3x^2 + 4
E)5(x + 3)
Rationale: lets see the choices..
A. (x + 3)(x + 5)
We have two terms with x and each is added with a odd number..
each bracket becomes odd and Odd*Odd=Odd
B. x^2 + 5
here we are adding an Odd number to even.. so E + O=O
C. x^2 + 6x + 9
here we are again adding an Odd number to even.. so E +E + O=O
D. 3x^2 + 4
here we are adding an Even number to even.. so E + E=E..
so this is our answer
E. 5(x + 3)
again O*O=O
ANSWER:D
Answer: D
Question: A rectangular box of volume x has width, depth and height in the ratio of 5:1:2 (in that order). What is the width as a function of x?
Options:
A)(4x/12)^(1/2)
B)(10x/4)^(1/2)
C)(5x)^(1/2)
D)(2x/5)^(1/2)
E)(4x/3)^(1/2)
Rationale: We are given width = 5, depth = 1, height = 2
Then Volume x = Width x Depth x Height = 5*1*2 = 10
i.e. x = 10
i.e. The correct option should result in 5 (the width) on substituting the value of x=10
Checking options with x=10
A) (4x/12)^(1/2) = (4*10/12)^(1/2) = (40/12)^(1/2) INCORRECT ANSWER
B) (10x/4)^(1/2) = (10*10/4)^(1/2) = 25^(1/2) = 5 CORRECT ANSWER
C) (5x)^(1/2) = (5*10)^(1/2) = 50^(1/2) INCORRECT ANSWER
D) (2x/5)^(1/2) = (2*10/5)^(1/2) = 4^(1/2) = 2 INCORRECT ANSWER
E) (4x/3)^(1/2) = (4*10/3)^(1/2) = 40/3^(1/2) INCORRECT ANSWER
Answer: Option B
Answer: B
Question: A man has a job, which requires him to work 8 straight days and rest on the ninth day. If he started work on Monday, find the day of the week on which he gets his 12th rest day.
Options:
A)Thursday
B)Wednesday
C)Tuesday
D)Friday
E)None
Rationale: Explanation :
The man get his 1st rest on the ninth day,
So he will get his 12th rest on : 12x9 = 108th day
The first day is monday so 108th(15x7 + 3) day will be same as 3rd day which will be Wednesday.
Answer : B
Answer: B
Question: A vessel contains 20 liters of a mixture of milk and water in the ratio 3:2. 10 liters of the mixture are removed and replaced with an equal quantity of pure milk. If the process is repeated once more, find the ratio of milk and water in the final mixture obtained?
Options:
A)9:1
B)9:9
C)9:7
D)9:5
E)9:2
Rationale: Milk = 3/5 * 20 = 12 liters, water = 8 liters
If 10 liters of mixture are removed, amount of milk removed = 6 liters and amount of water removed = 4 liters.
Remaining milk = 12 - 6 = 6 liters
Remaining water = 8 - 4 = 4 liters
10 liters of pure milk are added, therefore total milk = (6 + 10) = 16 liters.
The ratio of milk and water in the new mixture = 16:4 = 4:1
If the process is repeated one more time and 10 liters of the mixture are removed, then amount of milk removed = 4/5 * 10 = 8 liters.
Amount of water removed = 2 liters.
Remaining milk = (16 - 8) = 8 liters.
Remaining water = (4 -2) = 2 liters.
The required ratio of milk and water in the final mixture obtained = (8 + 10):2 = 18:2 = 9:1 Answer:A
Answer: A
Question: By selling an article at Rs.800, a shopkeeper makes a profit of 25%. At what price should he sell the article so as to make a loss of 35%?
Options:
A)228
B)480
C)267
D)416
E)276
Rationale: SP = 800
Profit = 25%
CP = (SP)*[100/(100+P)]
= 800 * [100/125]
= 640
Loss = 25% = 25% of 640 = Rs.224
SP = CP - Loss = 640 - 224 = Rs.416
Answer: D
Answer: D
Question: What is the smallest positive integer x for which x3+5xx3+5x has a value more than 80?
Options:
A)2
B)3
C)4
D)5
E)6
Rationale: 4^3 + 5*4 = 64 + 20 = 84
That's pretty close to 80 already so I can cancel D and E since they'll be more than 80. B just needs to be checked just in case so...
3^3 + 5*3 = 27 + 15 = not close to 80.
Therefore, 4 (C) is the smallest positive integer x for which x^3 + 5x has a value more than 80.ANSWER:C
Answer: C
Question: The cash realised on selling a 14% stock is Rs.109.25, brokerage being 1/4% is
Options:
A)123
B)109
C)100
D)156
E)240
Rationale: Explanation:
Cash realised= Rs. (109.25 - 0.25)
= Rs. 109.
Answer: B
Answer: B
Question: X and Y invest Rs.21000 and Rs.17500 respectively in a business. At the end of the year, they make a profit of Rs.24200. What is the share of X in the profit?
Options:
A)Rs.14400
B)Rs.26400
C)Rs.12000
D)Rs.12500
E)Rs.13200
Rationale: Ratio of the investment=21000:17500=210:175
=42:35=6:5
Share of X in the profit=(24200×6)/11=
=13200
ANSWER:E
Answer: E
Question: How many terminating zeroes W does 200! have?
Options:
A) 40
B) 48
C) 49
D) 55
E) 64
Rationale: You have 40 multiples of 5, 8 of 25 and 1 of 125. This will give 49 zeros.C
Answer: C
Question: P, Q and R can do a work in 20, 30 and 60 days respectively. How many days does it need to complete the work if P does the work and he is assisted by Q and R on every third day?
Options:
A)10 days
B)14 days
C)15 days
D)9 days
E)5 days
Rationale: Explanation :
Amount of work P can do in 1 day = 1/20
Amount of work Q can do in 1 day = 1/30
Amount of work R can do in 1 day = 1/60
P is working alone and every third day Q and R is helping him
Work completed in every three days = 2 × (1/20) + (1/20 + 1/30 + 1/60) = 1/5
So work completed in 15 days = 5 × 1/5 = 1
Ie, the work will be done in 15 days
Answer :C
Answer: C
Question: 30 buckets of water fill a tank when the capacity of each bucket is 13.5 litres. How many buckets will be required to fill the same tank if the capacity of each bucket is 9 litres?
Options:
A)30
B)32
C)45
D)Data inadequate
E)None of these
Rationale: Capacity of the tank = 30 Ã— 13.5= 405 litres
When the capacity of each bucket = 9 litres, then the required no. of buckets
=405â„9 = 45
Answer C
Answer: C
Question: Surekha started a business investing Rs.25,000 in 1999. In 2000, he invested an additional amount of Rs. 10,000 and Rajesh joined him with an amount of Rs. 35,000. In 2001, Surekha invested another additional amount of Rs.10,000 and Jay joined them with an amount of Rs.35,000. What will be Rajesh's share in the profit of Rs.1,20,000 earned at the end of 3 years from the start of the business in 1999?
Options:
A)Rs 40000
B)Rs 50000
C)Rs 70000
D)Rs 75000
E)None
Rationale: Surekha:Rajesh:Jay= (25000×12+35000×12+45000×12):(35000×24) : (35000×12) = 1260000 : 840000 : 420000 = 3 : 2 : 1. Rajesh's share =Rs.(120000×2/6) = Rs.40000.
Answer A
Answer: A
Question: A boy rides his bicycle 10 km at an average speed of 12 km/hr and again travels 12 km at an average speed of 10 km/hr. His average speed for the entire trip is approximately?
Options:
A)10.7 km/hr
B)10.8 km/hr
C)17.8 km/hr
D)10.5 km/hr
E)30.8 km/hr
Rationale: Total distance traveled = 10 + 12 = 22 km /hr.
Total time taken = 10/12 + 12/10 = 61/30 hrs.
Average speed = 22 * 30/61 = 10.8 km/hr.
Answer:B
Answer: B
Question: A man can row at 5 kmph in still water. If the velocity of current is 1 kmph and it takes him 1 hour to row to a place and come back, how far is the place?
Options:
A)2.4 km
B)2.9 km
C)3.4 km
D)4.4 km
E)5.6 km
Rationale: Explanation:
Speed in still water = 5 kmph
Speed of the current = 1 kmph
Speed downstream = (5+1) = 6 kmph
Speed upstream = (5-1) = 4 kmph
Let the required distance be x km
Total time taken = 1 hour
⇒ x/6+x/4=1
⇒2x+3x=12
⇒5x=12
⇒x=2.4 km
Answer: Option A
Answer: A
Question: On Monday, Lou drives his vehicle with 27-inch tires, averaging x miles per hour. On Tuesday, Lou switches the tires on his vehicle to 30-inch tires yet drives to work at the same average speed as on Monday. What is the percent change from Monday to Tuesday in the average number of revolutions that Lou's tires make per second?
Options:
A)Decrease by 14.3%
B)Decrease by 10%
C)Increase by 14.3%
D)Increase by 12.5%
E)Cannot be determined with the given information.
Rationale: 270 the LCM
On Tuesday 270/30 =9
On Monday 270/27 = 10
Therefore, 9-10/10 = -10% decrease
Answer is B
Answer: B
Question: If x = a!, which of these following values of a is the least possible value (in this list) for which the last 10 digits of the integer x will all be zero?
Options:
A)16
B)27
C)38
D)44
E)63
Rationale: 2*5 will give one 0 at the end. We need 2^10*5^10 to get 10 zeroes at the end.
There are many 2's, so we need to find the first 10 appearances of 5.
These multiples of 5 are: 5, 10, 15, 20, 5*5, 30, 35, 40, 45...which gives us 10.
To have at least 10 zeroes at the end, a => 45.
The answer is E.
Answer: E
Question: Two persons A and B can complete a piece of work in 30 days and 45 days respectively. If they work together, what part of the work will be completed in 3 days?
Options:
A)2/5
B)1/6
C)1/4
D)1/9
E)2/6
Rationale: B
1/6
A's one day's work = 1/30
B's one day's work = 1/45
(A + B)'s one day's work = 1/30 + 1/45 = 1/18
The part of the work completed in 3 days = 3 (1/18) = 1/6.
Answer: B
Question: At a certain company, each employee has a salary grade s that is at least 1 and at most 5. Each employee receives an hourly wage p, in dollars, determined by the formula p = 9.50 + 0.25(s – 1). An employee with a salary grade of 4 receives how many more dollars per hour than an employee with a salary grade of 1?
Options:
A)$0.75
B)$1.00
C)$1.25
D)$1.50
E)$1.75
Rationale: Salary grade of 4 is p(4)=9.50+0.25(4–1)=9.50+0.25*3;
Salary grade of 1 is p(1)=9.50 + 0.25(1–1)=9.50;
p(4)-p(1)=9.50+0.25*4-9.50=0.75.
Answer: A.
Answer: A
Question: A goods train runs at the speed of 72 km/hr and crosses a 250 m long platform in 26 sec. What is the length of the goods train?
Options:
A)337
B)278
C)287
D)270
E)191
Rationale: Speed = 72 * 5/18 = 20 m/sec.
Time = 26 sec.
Let the length of the train be x meters.
Then, (x + 250)/26 = 20
x = 270 m.
Answer: D
Answer: D
Question: Take a marker and start from a corner of a cube. How many edges you can trace if you dont move the marker twice anywhere and never remove it? (You can move the marker only on the corner and edges)
Options:
A)7
B)8
C)9
D)10
E)11
Rationale: we can trace 9 edeges
ANSWER:C
Answer: C
Question: X and Y invest Rs.21000 and Rs.17500 respectively in a business. At the end of the year, they make a profit of Rs.26400. What is the share of X in the profit?
Options:
A)Rs 14400
B)Rs 26400
C)Rs 12000
D)Rs 12500
E)Rs 13000
Rationale: Ratio of the investment
=21000:17500=210:175 = 42:35 = 6:5
26400*6/11=2400*6 =14400
ANSWER A
Answer: A
Question: An article is bought for Rs.675 and sold for Rs.900, find the gain percent?
Options:
A)33 1/8%
B)33 3/3%
C)33 1/3%
D)32 1/3%
E)33 5/3%
Rationale: 675 ---- 225
100 ---- ? => 33 1/3%
Answer:C
Answer: C
Question: Two cups X and Y contain coffee and water combined in the ratio 8:5 and 5:2 correspondingly. What is the ratio in these 2 combinations be combined to get a new combination has coffee and a water in the ratio of 9:4?
Options:
A)2:5
B)2:3
C)2:7
D)2:9
E)None of these
Rationale: Explanation :
i) : If C.P. of coffee be Re.1
Given ratio of combination in X= 8:5
Coffee in 1 cup combination in X = (8/13)cups
C.P of 1 cup combination in X= Rs. 8/13
Therefore, The ratio of Combination in Y = 5:2
Coffee in 1 cup combination in Y – (5/7) cups
C.P of 1 cup combination in B = Rs. 5/7
Ratio of new combination = 9:4
milk in 1 cup combination = 9/13
C.P of 1 cup combination = Rs/ 9/13 (Mean price)
ii) : By the rule of allegation,
i. C.P of 1 cup of combination in X =8/13
ii. C.P of 1 cup of combination in Y = 5/7
iii. Mean price (p) = 9/13
iv. d – m = 9/13 – 5-7 = 2/91
v. m – c = 9/13 – 8/13 = 1/13
Needed ratio = 2/91 : 1/13 = 2:7
Answer : C
Answer: C
Question: A seller uses 840gm in place of 1kg to sell his goods. Find his actual % profit or loss, when he sells his article his article on 4% gain on cost price?
Options:
A)23 17/21%
B)25%
C)27 25/37%
D)30%
E)32%
Rationale: Selling price of 840gm = 100+4 = $104
Profit = 104-84 = $20
% of profit = 20*100/84 = 23 17/21 %
Answer is A
Answer: A
Question: Write 840,000,000,000 in scientific notation.
Options:
A)8.4 * 10^11
B)800.900 * 10^11
C)8.900 * 10^11
D)80.9000* 10^11
E)08.900 * 10^11
Rationale: a * 10 n , where a is a real number such that 1 * |a| < 10 and n is an integer.
840,000,000,000 = 8.4* 100,000,000,000 = 8.4 * 10 11**
correct answer A
Answer: A
Question: The product of all the prime numbers less than 20 is closest to which of the following powers of 20 ?
Options:
A) 10^9
B) 10^8
C) 10^7
D) 10^6
E) 10^5
Rationale: 2*3*5*7*11*13*17*19
2*19*3*17*5*13*7*11
38*51*65*77
By approximation
40*50*70*70
2000*4900
By approximation
2000*5000
10,000,000
C
Answer: C
Question: Tough and Tricky questions: Distance/Rate.
On a reconnaissance mission, a state-of-the-art nuclear powered submarine traveled 300 miles to reposition itself in the proximity of an aircraft carrier. This journey would have taken 1.5 hour less if the submarine had traveled 10 miles per hour faster. What was the average speed, in miles per hour, for the actual journey?
Options:
A)20
B)40
C)60
D)80
E)100
Rationale: Say, if speed is 60, 300/40 = 7.5 hrs and 300/50 = 6 hrs (a reduction of 1.5 hr -> Correct answer)
Answer (B)
Answer: B
Question: A merchant sells an item at a 20% discount, but still makes a gross profit of 20 percent of the cost. What percent W of the cost would the gross profit on the item have been if it had been sold without the discount?
Options:
A)20%
B)40%
C)50%
D)60%
E)75%
Rationale: Let the Market Price of the product is MP.
Let the Original Cost Price of the product is CP.
Selling Price (Discounted Price) = 100%of MP - 20%MP
= 80% of MP. ---------------- (1)
Profit made by selling at discounted price = 20% of CP -------------- (2)
Apply the formula:
Profit W= Selling Price - Original Cost Price
=> 20% of CP = 80% of MP - 100% CP
=> MP = 120CP/80 = 3/2 (CP)
Now if Product is sold without any discount, then,
Profit = Selling Price (without discount) - Original Cost Price
= Market Price - Original Cost Price
= MP - CP
= 3/2 CP - CP
= 1/2 CP
=50%of CP
Thus, Answer should beC.
Answer: C
Question: The expression 10^12−120 is divisible by all of the following integers EXCEPT
Options:
A)7
B)3
C)4
D)8
E)11
Rationale: Yeah. I agree this question has two answers which are (B) and (E). If 10 is power to odd number and equal or more than 5, then the answer choice (A) is correct.
Answer: A
Question: The public library has exactly 2 floors. It has 1/3 as many shelves on its 2nd floor as it does on its 1st. If the second floor has 5/6 as many books per shelf as the first floor, what fraction of the library's books are on the first floor?
Options:
A)1/4
B)5/14
C)5/9
D)9/14
E)18/23
Rationale: Let x be the no of shelves and y be the no of books per shelf on first floor.
Now no of shelves on 2nd floor = (1/3)*x
no of books per shelf on 2nd floor = (5/6) * y
So total no books on first floor = xy and total no of books on 2nd floor = (1/3)*x*(5/6)*y = (5/18)*xy
fraction of library books on first floor = (xy)/(xy + (5/18)*xy)
=1 / (1+(5/18))
=18/23
So E
Answer: E
Question: Seller selling an apple for Rs.19, a Seller loses 1/6th of what it costs him. The CP of the apple is?
Options:
A)10
B)12
C)20
D)18
E)21
Rationale: SP=19Loss=CP20Loss=CP−SP=CP−19⇒CP20=CP−19⇒19 CP20=19⇒CP20=1⇒CP=20
C
Answer: C
Question: Ifaequals the sum of the even integers from 2 to 60, inclusive, andbequals the sum of the odd integers from 1 to 59, inclusive, what is the value of a - b ?
Options:
A)1
B)10
C)30
D)20
E)21
Rationale: This is a solution from Beatthegmat:
even numbers:
(60-2)/2 + 1 = 30 even integers.
(60+2)/2 = 31 is the average of the even set.
sum = avg*(#of elements) = 31*30 = 930 = a
odd numbers:
(59-1)/2 + 1 = 30 odd integers.
(59+1)/2 = 30 is the average of the odd set.
sum = avg*(#of elements) = 30*30 = 900 = b
a-b = 930 - 900 = 30. Answer : C
Answer: C
Question: The value of (1/log3 60 + 1/log4 60 + 1/log5 60) is:
Options:
A)0
B)1
C)5
D)60
E)2
Rationale: log60 3 + log60 4 + log60 5 + log60 (3*4*5)
= log60 60 = 1
ANSWER:B
Answer: B
Question: Rich has 3 green, 2 red and 3 blue balls in a bag. He randomly picks 5 from the bag without replacement. What is the probability W that of the 5 drawn balls, Rich has picked 1 red, 2 green, and 2 blue balls?
Options:
A)8/28
B)W=9/28
C)W=10/28
D)10/18
E)11/18
Rationale: (3c2 *2c1*3c2)/8c5
=(3*2*3)/(8*7*6/3*2)
=18/56
=9/28
B
Answer: B
Question: Eight years ago, Ajay's age was 4/3 times that of Vijay. Eight years hence, Ajay's age will be 6/5 times that of Vijay. What is the present age of Ajay?
Options:
A)30 years
B)40 years
C)32 years
D)48 years
E)None of these
Rationale: Let the present ages of Ajay and Vijay be 'A' and 'V' years respectively.
A - 8 = 4/3 (V - 8) and A + 8 = 6/5 (V + 8)
3/4(A - 8) = V - 8 and 5/6(A + 8) = V + 8
V = 3/4 (A - 8) + 8 = 5/6 (A + 8) - 8
=> 3/4 A - 6 + 8 = 5/6 A + 20/3 - 8
=> 10 - 20/3 = 10/12 A - 9/12 A
=> 10/3 = A/12 => A = 40.
ANSWER:B
Answer: B
Question: A, B and C start a business each investing 20,000. After 6 months A withdrew 5000, B withdrew 4000 and C invests 6000 more. At the end of the year, a total profit of 67,600 was recorded. Find the share of B.
Options:
A)20,000
B)21,200
C)21,600
D)20,500
E)None of these
Rationale: Ratio of the capitals of A, B and C
= 20000 Ã— 6 + 15000 Ã— 6 : 20000 Ã— 6 + 16000 Ã—6 : 20000 Ã— 6 + 26000 Ã— 6
= 210000 : 216000 : 250000 = 210 : 216 : 250
Bâ€™s share = (67600 Ã— 216â„676) = 21600
Answer C
Answer: C
Question: In a fuel station the service costs $1.75 per car, every liter of fuel costs 0.65$. Assuming that a company owns 12 cars and that every fuel tank contains 45 liters and they are all empty, how much money total will it cost to fuel all cars?
Options:
A)320$
B)372$
C)420$
D)450$
E)480$
Rationale: Total Cost = ( 1.75*12 ) + ( 0.65 * 12 * 45 ) = 21 + 351 => 372
Hence answer will be (B) 372
Answer: B
Question: The point A and point B is 30 miles apart, the point B and point C is 25 miles apart. A car travels from point A to point B in 30 min and point B to point C in 40 min. What is the average speed of the car?
Options:
A)34.15
B)40.35
C)47.14
D)50.12
E)56.66
Rationale: Average speed=Total distance covered/Total time taken
=55miles/70min
=0.79miles/min
=47.14 miles/hour
Answer: C
Answer: C
Question: The L.C.M of two numbers is 2310 and their H.C.F is 30. If one number is 385 the Other is
Options:
A)180
B)300
C)270
D)250
E)350
Rationale: The other number
= L.C.M * H.C.F/given number
= 2310*30/385 = 180
Answer is A.
Answer: A
Question: If n is a positive integer, which of the following is a possible value of |46 - 5n| ?
Options:
A)7
B)2
C)11
D)15
E)20
Rationale: When 46>5n, then |46- 5n| = 46- 5n = (45-5n) + 1 = {multiple of 5} + 1
When 46<=5n, then |46- 5n| = -(46- 5n) = (5n-45) - 1 = {multiple of 5} - 1
So, the correct answer must be 1 greater or 1 less than a multiple of 5. Only C fits.
Answer: C
Answer: C
Question: The length of a train and that of a platform are equal. If with a speed of 54 k/hr, the train crosses the platform in one minute, then the length of the train (in meters) is?
Options:
A)227
B)299
C)450
D)750
E)211
Rationale: Speed = [54 * 5/18] m/sec = 15 m/sec; Time = 1 min. = 60 sec.
Let the length of the train and that of the platform be x meters.
Then, 2x/60 = 15 è x = 15 * 60 / 2 = 450
Answer: C
Answer: C
Question: Sum of three numbers 286, If the first number be twice then second and third number be one third of the first, then the second number is
Options:
A)A)70
B)B)71
C)C)78
D)D)73
E)E)74
Rationale: Explanation:
Let the second number is x, then first is 2x, and third is 1/3(2x)
=>2x+x+2x/3=286
<=>11x/3=286
=>x=78
Answer: Option C
Answer: C
Question: Rony walks along Sunrise Boulevard daily. He starts walking at 07:00 from block 10 and walks to block 90 where he turns around and walks back to block 70, where he stops at 07:20. The blocks along the boulevard are numbered sequentially (1,2,3), and each block measures 35 meters. What is Rony's speed in meters per minute?
Options:
A)108
B)175
C)198
D)216
E)252
Rationale: Total distance from 10 to 90 =80 + from 90 to 70 =20
So the dist is 100×35(per block dist)
Speed = 3500mts/20min =175m/min
B is the answer
Answer: B
Question: Rs.1200 is divided so that 5 times the first share, 10 times the 2nd share and fifteen times third share amount to the same. What is the value of the second share?
Options:
A)s525
B)s527
C)s598
D)s400
E)s500
Rationale: A+B+C = 1200
5A = 10B = 15C = x
A:B:C = 1/5:1/10:1/15 =3:2:1
2/6 * 1200 =Rs 400
Answer:D
Answer: D
Question: Mohit sold an article for $12000. Had he offered a discount of 10% on the selling price, he would have earned a profit of 8%. What is the cost price of the article?
Options:
A)16000
B)25000
C)10000
D)18000
E)17000
Rationale: Let the CP be $x.
Had he offered 10% discount, profit = 8%
Profit = 8/100 x and hence his SP = x + 8/100 x = $1.08x = 12000 - 10/100(12000) = 12000 - 1200 = $10800
=> 1.08x = 10800
=> x = 10000
C
Answer: C
Question: A cab driver 5 days income was $250, $400, $750, $400 , $500. Then his average income is?
Options:
A)$440
B)$450
C)$460
D)$470
E)$480
Rationale: avg = sum of observations/number of observations
avg income=(250+400+750+400+500)/5 = 460
Answer is C
Answer: C
Question: The average weight of 25 persons sitting in a boat had some value. A new person added to them whose weight was 46 kg only. Due to his arrival, the average weight of all the persons decreased by 5 kg. Find the average weight of first 25 persons?
Options:
A)175
B)116
C)197
D)176
E)267
Rationale: 25x + 46
= 26(x – 5)
x = 176
Answer:D
Answer: D
Question: What is the next number of the following sequence.
3, 10, 13, 20, 23, 30,
Options:
A)28
B)29
C)30
D)33
E)36
Rationale: 3
3+7=10
10+3=13
13+7=20
20+3=23
23+7=30
30+3=33
ANSWER:D
Answer: D
Question: A regular square is inscribed in a circle. If A and B are adjacent vertices of the pentagon and O is the center of the circle, what is the value of ∠OAB ?
Options:
A)45 degrees
B)54 degrees
C)72 degrees
D)84 degrees
E)108 degrees
Rationale: its a regular square so divide the globe by 4.
= 360/4
= 90
90 would be the angle at O.
Angles at A and B are equivalent, so
90 + 2x = 180
2x = 90
x =45
Angles OAB and OBA will be 45 degrees each.
A
Answer: A
Question: 5 noun, 4 verbs and 3 adjectives are written on blackboard.we can form sentence by choosing 1 from each available set without caring it makes sense or not.what is the number of ways of doing this??
Options:
A)360
B)430
C)510
D)540
E)630
Rationale: we have to choose one from each set. 1 from 5 nouns and 1 from 4 verbs and 1 from 3 adjectives.
then we have to arrange 3 different sets in 3! ways.
so,
5c1*4c1*3c1*3!=360
ANSWER:A
Answer: A