divelab/Sys2Bench huggingface dataset:
Question: The ratio of expenditure and savings is 3 : 2 . If the income increases by 15% and the savings increases by 6% , then by how much percent should his expenditure increases?
Options:
A)22
B)21
C)88
D)76
E)29
Rationale: Answer: B) 21
Answer: B
Question: Tough and Tricky questions: Exponents.
If a and b are positive integers and x = 6^a and y = 9^b, which of the following is a possible units digit of xy?
Options:
A)1
B)6
C)5
D)7
E)8
Rationale: Only Units digit of X and Y contribute to the Units digit of XY.
Finding all values of X for positive values ofa
When,
a=1; X=6
a=2; X=36
a=3; X=216........ Units digit repeat in a cycle of 6,6,6,6......
Similarly, Finding all values ofYfor positive values ofb
When,
b=1; Y=9
b=2; Y= 81
b=3; Y= 729....... Units digit repeat in cycle of 9,1,9,1....
So, possible value of Units digit of XY can be found by considering all possibilities of Units digit of X and Y
When X=6 and Y=9: Units digit of XY = 4
When X=6 and Y=1: Units digit of XY = 6
When X=6 and Y=9: Units digit of XY = 4
When X=6 and Y=1: Units digit of XY = 6
Only two possibilities for Units digit of XY i.e. 4 and 6.
Only 6 is given in answer choices, therefore answer is B
Answer: B
Question: 10 years ago, the average age of a family of 4 members was 24 years. Two children having been born (with age diference of 2 years), the present average age of the family is the same. The present age of the youngest child is :
Options:
A)1
B)2
C)3
D)4
E)5
Rationale: Explanation:
Total age of 4 members, 10 years ago = (24 x 4) years = 96 years.
Total age of 4 members now = [96 + (10 x 4)] years = 136 years.
Total age of 6 members now = (24 x 6) years = 144 years.
Sum of the ages of 2 children = (144 - 136) years = 8 years.
Let the age of the younger child be x years.
Then, age of the elder child = (X + 2)years.
So, x + (x + 2) = 8 ⇔ x = 3
Age of younger child = 3 years. Answer: C
Answer: C
Question: A boat running downstream covers a distance of 22 km in 4 hours while for covering the same distance upstream, it takes 5 hours. What is the speed of the boat in still water?
Options:
A)5 kmph
B)4.95 kmph
C)4.75 kmph
D)4.65
E)None of these
Rationale: Explanation :
Speed downstream = 22/4 = 5.5 kmph
Speed upstream = 22/5 = 4.4 kmph
Speed of the boat in still water = (5.5 + 4.4)/2 = 4.95 kmph. Answer : Option B
Answer: B
Question: he average of 15 numbers is zero. Of them, at the most, how many may be greater than zero?
Options:
A)0
B)1
C)14
D)19
E)8
Rationale: Average of 15 numbers = 0.
Sum of 15 numbers (0 x 15) = 0.
It is quite possible that 14 of these numbers may be positive and if their sum is a the 15th number is (-a).
Answer: Option C
Answer: C
Question: a vase has 2 dozens of assorted flowers of which 8 are daisies. what is the ratio of the daisies to the whole arrangement?
Options:
A)1/2
B)1/3
C)1/12
D)8/12
E)1/24
Rationale: 2 dz flowers=24; ratio of daisies to the whole flower arrangement is 8/24=1/3
ANSWER:B
Answer: B
Question: A can do a piece of work in 15 days. A does the work for 5 days only and leaves the job. B does the remaining work in 16 days.In how many days B alone can do the work?
Options:
A)5days
B)7 days
C)12 days
D)24 days
E)10 days
Rationale: Explanation:
A’s 5 day work = 5*1/15=1/3
Remaining work = 1-1/3=2/3
B completes 2/3 work in 6 days
B alone can do in x days
2/3*x=16
X=24 days
Answer: Option D
Answer: D
Question: Which of the following CAN be the least common multiple of two positive integers 10 and 15?
Options:
A)12
B)30
C)17
D)18
E)50
Rationale: LCM of 10 & 15 is 30
Answer : B
Answer: B
Question: What is the compound interest paid on a sum of Rs.6000 for the period of 2 years at 10% per annum.
Options:
A)1260
B)1320
C)1200
D)1250
E)None of these
Rationale: Solution= Interest % for 1st year= 10
Interest % for 2nd year= 10+ 10% of 10= 10+ 10 *10/100=11
Total % of interest= 10 + 11=21
Total interest = 21 % 6000 = 6000 * (21/100)= 1260
Answer A
Answer: A
Question: W is the set of the first n positive odd numbers, where n is a positive integer. Given that n > k, where k is also a positive integer, x is the maximum value of the sum of k distinct members of W, and y is the minimum value of the sum of k distinct members of W, what is x + y?
Options:
A) kn
B) kn + k^2
C) kn + 2k^2
D) 2kn – k^2
E) 2kn
Rationale: Probably the easiest way to solve this question would be to assume some values for n and k.
Say n=3, so W, the set of the first n positive odd numbers would be: W={1, 3, 5};
Say k=1, so X, the maximum value of the sum of K distinct members of W would simply be 5. Similarly, Y, the minimum value of the sum of K distinct members of W would simply be 1.
X+Y=5+1=6.
Now, substitute n=3 and k=1 in the options provided to see which one yields 6. Only asnwer choice E fits: 2kn=2*3*1=6.
Answer: E.
Answer: E
Question: A train 250 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 150 m long?
Options:
A)45 sec
B)42 sec
C)32sec
D)48 sec
E)25 sec
Rationale: total length= 250+150=400
speed=45km/h=(45*5)/18= 25/2m/s
time=(400*2)/25=32 sec.
ANSWER:C
Answer: C
Question: How many unique positive odd integers less than 100 are equal to the product of a positive multiple of 5 and an odd number?
Options:
A)4
B)10
C)11
D)12
E)15
Rationale: The Question basically asks how many positive odd integers less than 100 are odd multiples of 5
So we have 5,15,25,35,45,55,65,75,85,95
=10
Ans B
Answer: B
Question: In a mixed college 160 students are there in one class. Out of this 160 students 1/2 students are girls. How many boys are there ?
Options:
A)A)40
B)B)60
C)C)80
D)D)120
E)E)140
Rationale: Total Number of Students :160
Total Girls : 160*1/2=80
Total Boys : 160-80 = 80
Answer is C
Answer: C
Question: A sum of Rs. 1700 has been divided among A, B and C such that A gets of what B gets and B gets of what C gets. B’s share is:
Options:
A)Rs. 120
B)Rs. 160
C)Rs. 240
D)Rs. 300
E)None
Rationale: EXPLANATION
Let C’s share = Rs. x
Then, B’s share = Rs. x/4 , A’s share = Rs. (2/3 x x/4 ) = Rs. x/6
=x/6 + x/4 + x = 1700
=> 17x/12 = 1700
=> 1700 x 12/ 17 = Rs.1200
Hence, B’s share = Rs. (1200/4) = Rs. 300.
Answer D
Answer: D
Question: How many 6 digit positive integers exist such that no two consecutive digits are the same?
Options:
A)10*9*8*7*6*5
B)9*8*7*6*5*4
C)9*9*8*7*6*5
D)9*9*8^4
E)9^6
Rationale: no two consecutive integers are same, so the digit is in the form of XY XY XY
so leftmost digit can be any digit but 0. we can choose in 9 ways. next digit can be chosen in 9 ways, remaining each digit can be chosen in 9 ways.
total digits are 9∗9∗9∗9∗9∗9=9^6
Ans. E
Answer: E
Question: Two cars were driven by W and B. They were 580 miles apart when they started driving towards each other.W's car had traveled at a speed of 20 miles per hour, 4 hours per day for 5 days when it had met B's car. If B had driven 3 hours per day for 5 days, what was B's speed in miles per hour?
Options:
A)8
B)9
C)10
D)11
E)12
Rationale: 1. At 20mph for 4 hours a day, then driver W was traveling 80 miles per day. When W met with B, W had already traveled 400 miles.
2. This means that driver B had traveled 580-400 = 180 miles upon meeting up with W. B traveled a total of 3 x 5 = 15 hours (3hrs/day for 5 days). 180 miles / 15 hours = 12mph
3. Answer E!
Answer: E
Question: Two employees X and Y are paid a total of Rs. 550 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?
Options:
A)Rs.180
B)Rs.200
C)Rs.250
D)Rs.280
E)Rs.300
Rationale: Let the amount paid to X per week = x
and the amount paid to Y per week = y
Then x + y = 550
But x = 120% of y = 120y/100 = 12y/10
∴12y/10 + y = 550
⇒ y[12/10 + 1] = 550
⇒ 22y/10 = 550
⇒ 22y = 5500
⇒ y = 5500/22 = 500/2 = Rs.250
Option 'C'
Answer: C
Question: There are 9 players in a chess group, and each player plays each of the others once. Given that each game is played by two players, how many total games will be played?
Options:
A)10
B)30
C)36
D)60
E)90
Rationale: 9 players are there.
two players play one game with one another.
so 9C2=9x8/2=36
SO OPTION C is correct
Answer: C
Question: By selling 150 apples, a fruit-seller gains the selling price of 30 apples. Find the gain percent?
Options:
A)30%
B)58%
C)25%
D)60%
E)12%
Rationale: Option C
Explanation:
SP = CP + g
150 SP = 150 CP + 30 SP
120 SP = 150 CP
120 --- 30 CP
100 --- ? => 25%
Answer: C
Question: A 150 meter long train crosses a man standing on the platform in 3 sec. What is the speed of the train?
Options:
A)176 kmph
B)108 kmph
C)176 kmph
D)134 kmph
E)180 kmph
Rationale: S = 150/3 * 18/5
= 180 kmph
Answer: E
Answer: E
Question: The radius of a wheel is 22.4 cm. What is the distance covered by the wheel in making 1500 resolutions?
Options:
A)2187 m
B)2112 m
C)2179 m
D)2127 m
E)2197 m
Rationale: In one resolution, the distance covered by the wheel is its own circumference. Distance covered in 1500 resolutions.
= 1500 * 2 * 22/7 * 22.4
= 211200 cm
= 2112 m
Answer:B
Answer: B
Question: In an election between two candidates, the first candidate got 60% of the votes and the second candidate got 480 votes. What was the total number of votes?
Options:
A)900
B)1200
C)1500
D)1800
E)2100
Rationale: Let V be the total number of votes.
0.4V = 480
V = 1200
The answer is B.
Answer: B
Question: Two tains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 120 metres, in what time (in seconds) will they cross each other travelling in opposite direction?
Options:
A)12
B)14
C)16
D)20
E)18
Rationale: Sol.
Speed of the first train = [120 / 10] m/sec = 12 m/sec.
Speed of the second train = [120 / 15] m/sec = 8 m/sec.
Relative speed = (12 + 8) = m/sec = 20 m/sec.
∴ Required time = (120 + 120) / 20 secc = 12 sec.
Answer A
Answer: A
Question: A trader sells 85 meters of cloth for Rs. 8925 at the profit of Rs. 20 per metre of cloth. What is the cost price of one metre of cloth?
Options:
A)21
B)28
C)90
D)85
E)11
Rationale: Explanation:
SP of 1m of cloth = 8925/85 = Rs. 105
CP of 1m of cloth = SP of 1m of cloth - profit on 1m of cloth
= Rs. 105 - Rs. 20 = Rs. 85.
Answer: D
Answer: D
Question: A can run a kilometer race in 4 1/2 min while B can run same race in 5 min. How many meters start can A give B in a kilometer race, so that the race mat end in a dead heat?
Options:
A)150 m
B)125 m
C)130 m
D)100 m
E)120 m
Rationale: A can give B (5 min - 4 1/2 min) = 30 sec start.
The distance covered by B in 5 min = 1000 m.
Distance covered in 30 sec = (1000 * 30)/300 = 100 m.
A can give B 100m start.
ANSWER:D
Answer: D
Question: Janet invited her Boy and Girl friends to her party at the ratio of 3:7. If 30% of the Boys and 70% of the Girls will be coming for the party from Texas, How many Janet invited friends will be coming from Texas.
Options:
A)62%
B)52%
C)57%
D)56%
E)58%
Rationale: let total no of Janet invited friends be 100, boys 30 and girls 70, so total number of Janet's invited guests coming from Texas for both Boys and Girls respectively 30* 30/100=9 and 70* 70/100=49
so total 58 of Janet's invited guest out of the 100 invited guests will be coming from Texas..so required % is 58%
ANSWER:E
Answer: E
Question: In how many different number of ways 5 boys and 2 girls can sit on a shopa which can accommodate persons?
Options:
A)180
B)190
C)200
D)210
E)220
Rationale: Option 'D'
7p3 = 7 × 6 × 5 = 210
Answer: D
Question: Liam is pulled over for speeding just as he is arriving at work.He explains to the police officer that he could not afford to be late today, and has arrived at work only four minutes before he is to start. The officer explains that if Liam had driven 5mph slower for his whole commute, he would have arrived at work exactly on time. If Liam's commute is 60 miles long,how fast was he actually driving?(Assume that Liam drove at a constant speed for the duration of his commute.)
Options:
A)50 mph
B)45 mph
C)48 mph
D)52 mph
E)70 mph
Rationale: Let t be the number of hours he would need to reach office on time.
when he is driving with over speed, he reached office 4 min earlier! so the equation for this is s(t - 4/60) = 60
where s is the speed and 30 is the distance.
if he decreases his speed by 5mph then he would have reached his office on time: (s-5)t = 60
if you solve above equations, you will arrive at t = 2/3 hr and s = 70mph
therefore answer is E
Answer: E
Question: If a train, travelling at a speed of 90 kmph, crosses a pole in 5 sec, then the length of train is?
Options:
A)288
B)125
C)88
D)76
E)232
Rationale: D = 90 * 5/18 * 5 = 125 m
Answer: B
Answer: B
Question: 5, 7, 11, 18, 33, (...)
Options:
A)22
B)35
C)27
D)63
E)25
Rationale: Explanation :
5
5 × 2 - 3 = 7
7 × 2 - 3 = 11
11 × 2 - 3 = 18
18 × 2 - 3 = 33
33 × 2 - 3 = 63
Answer : Option D
Answer: D
Question: A and B can together finish a work 30 days. They worked together for 20 days and then B left. After another 20 days, A finished the remaining work. In how many days A alone can finish the work?
Options:
A)10 days.
B)30 days.
C)60 days.
D)20 days.
E)50 days.
Rationale: (A + B)'s 20 day's work =(1/30 x 20)	=2/3	.
Remaining work =(1 -2/3)=1/3.
Now,	1/3	work is done by A in 20 days.
Therefore, the whole work will be done by A in (20 x 3) = 60 days.
Answer: Option C
Answer: C
Question: The ratio 2:10 expressed as percent equals to
Options:
A)50 %
B)30 %
C)25 %
D)20 %
E)90%
Rationale: Explanation:
Actually it means 2 is what percent of 10, which can be calculated as,
(2/10)*100 = 2* 10 = 20
Answer: Option D
Answer: D
Question: An error 2% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is
Options:
A)4.04%
B)4.14%
C)4.23%
D)4.26%
E)4.5%
Rationale: 100 cm is read as 102 cm.
A1 = (100 x 100) cm2 and A2 (102 x 102) cm2.
(A2 - A1) = [(102)2 - (100)2]
= (102 + 100) x (102 - 100)
= 404 cm2.
Percentage error = 404	x 100	%	=
100 x 100
A)
Answer: A
Question: If Dinesh is 1/3rd the age of his father Kiran now, and was 1/4th the age of his father 5 years ago, then how old will his father Kiran be 5 years from now?
Options:
A)20 years
B)45 years
C)40 years
D)50 years
E)None of these
Rationale: Let the present age of Dinesh and his father be ’x’ and ’y ’respectively. Then
x = 1/3y
(x - 5) = 1/4(y - 5)
y = 45 years
Hence required age = (y + 5) = 50 years
ANSWER:D
Answer: D
Question: In the graduating class of a certain college, 48 percent of the students are male and 52 percent are female. In this class 40 percent of the male and 50 percent of the female students are 25 years old or older. If one student in the class is randomly selected, approximately what is the probability that he or she will be less than 25 years old?
Options:
A)A)0.9
B)B)0.5
C)C)0.45
D)D)0.3
E)E)0.25
Rationale: Percent of students who are 25 years old or older is 0.4*48+0.5*52=~45, so percent of people who are less than 25 years old is 100-45=55.
Answer: B.
Answer: B
Question: The average of 11 numbers is 10.9. If the average of first six is 10.5 and that of the last six is 11.4 the sixth number is?
Options:
A)11.9
B)14.2
C)11.9
D)11.5
E)11.2
Rationale: 1 to 11 = 11 * 10.9 = 119.9
1 to 6 = 6 * 10.5 = 63
6 to 11 = 6 * 11.4 = 68.4
63 + 68.4 = 131.4 – 119.9 = 11.5
6th number = 11.5
Answer:D
Answer: D
Question: In a contest, a bowl contains 8 keys, one of which will open a treasure chest and Seven of which will not. If a contestant selects the key that opens the treasure chest, she wins the contents of that chest. If Kiran is allowed to draw two keys, simultaneously and at random, from the bowl as the first contestant, what is the probability that he wins the prize?
Options:
A)1/4
B)1/2
C)1/3
D)1/5
E)1/6
Rationale: The total possibilities existing while withdrawing two keys are: 8C2 = 28
For Kiran to win, 7 combinations exist assuming Key 1 to unlock the treasure E.g(1,2), (1,3)....(1,7)
P = 7/28= 1/4
Option A
Answer: A
Question: Convert the 15/36 m/s into kilometers per hour?
Options:
A)3.5 kmph.
B)2.5 kmph.
C)1.2 kmph.
D)1.5 kmph.
E)1.9 kmph.
Rationale: 15/36 m/s = 13/36 * 18/5 = 15/10 = 1.5 kmph.
ANSWER:D
Answer: D
Question: If xerox paper costs 5 cents a sheet and a buyer gets 10% discount on all xerox paper one buys after the first 2000 papers and 20% discount after first 10000 papers, how much will it cost to buy 35000 sheets of xerox paper?
Options:
A)$1250
B)$1060
C)$1450
D)$900
E)$1000
Rationale: 30 sec approach - solve it using approximation
35000 sheet at full price, 5 cent = 1750
35000 sheet at max discount price, 4 cent = 1400
Your ans got to be between these two.
Ans C it is.
Answer: C
Question: The price of lunch for 13 people was $207 including a 15% gratuity for service. What was the average price per person, EXCLUDING the gratuity?
Options:
A)11.73
B)12
C)13.85
D)14
E)15.87
Rationale: Clearly C is the answer
I used POE here
Lets consider option (C)
13*13.85= 180 now 180(115/100)=207
=> possible ANSWER IMO C
Answer: C
Question: The daytime telephone rate between two cities is 50 cents for the first 3 minutes and c cents for each additional minute. The total charge is reduced 60 percent on calls made after 10:00 P.M. The cost, in dollars, of a 35-minute call made at 10:30 P.M. between these two cities is:
Options:
A) 0.4(0.60) + 35c
B) 0.4(0.50 + 0.32c)
C) 0.4(0.60 + 9c)
D) 0.6(0.60 + 32c)
E) 0.6(0.60 + 0.35c)
Rationale: For first three minutes = 50 cents
Remaining minutes = 35 -3 = 32
charge for 32 minutes = 32c
total cost (if the call was made in daytime) = 0.50 + 32c
60% chargereducedon night calls => 40% charge
=>0.4(0.50 + 32c)
Hence, Answer is B
Answer: B
Question: In Kiran's opinion, his weight is greater than 65 kg but less than 72 kg. His brother does not agree with Kiran and he thinks that Kiran's weight is greater than 60 kg but less than 70 kg. His mother's view is that his weight cannot be greater than 68 kg. If all are them are correct in their estimation, what is the average of different probable weights of Kiran?
Options:
A)67
B)68
C)69
D)70
E)71
Rationale: Let Kiran's weight = x. Then
According to Kiran, 65 < x < 72 ----(equation 1)
According to brother, 60 < x < 70 ----(equation 2)
According to mother, x ≤ 68 ----(equation 3)
Given that equation 1,equation 2 and equation 3 are correct. By combining these equations,we can write as
65<x≤68
i.e., x = 66 or 67 or 68
Average of different probable weights of Kiran = (66+67+68)/3=67
Answer is A.
Answer: A
Question: X and Y invest Rs.21000 and Rs.17500 respectively in a business. At the end of the year, they make a profit of Rs.26400. What is the share of X in the profit?
Options:
A)14400
B)26400
C)12000
D)12500
E)14500
Rationale: Explanation:
Ratio of the investment
=21000:17500=210:175
=42:35=6:5
Share of X in the profit
=2400 x 6/11
=2400×6=14400
Answer: Option A
Answer: A
Question: Working together, printer A and printer B would finish the task in 24 minutes. Printer A alone would finish the task in 60 minutes. How many pages does the task contain if printer B prints 10 pages a minute more than printer A ?
Options:
A)600
B)800
C)1000
D)1200
E)1500
Rationale: Answer: D.
Answer: D
Question: Find the roots of quadratic equation: 2x2 + 5x + 2 = 0?
Options:
A)-2, -1/2
B)4, -1
C)4, 1
D)-2, 5/2
E)None of these
Rationale: 2x2 + 4x + x + 2 = 0
2x(x + 2) + 1(x + 2) = 0
(x + 2)(2x + 1) = 0 => x = -2, -1/2
ANSWER:A
Answer: A
Question: The difference between a positive proper fraction and its reciprocal is 9/20. The fraction is:
Options:
A)3/5
B)3/10
C)4/5
D)5/4
E)6/4
Rationale: Let the required fraction be x. Then,
1/x - x = 9/20
20x2 + 9x - 20 = 0
20x2 + 25x - 16x - 20 = 0
5x(4x + 5) -4(4x + 5) = 0
(4x + 5)(5x - 4) = 0
x = 4/5
ANSWER:C
Answer: C
Question: If the mean of a data set is 75 and the standard deviation is 10, what is the range of scores that fall within one standard deviation of the mean?
Options:
A)65, 80}
B)65, 90}
C)65, 70}
D)65, 80}
E)65, 85}
Rationale: score ranges between 85 and 65, where 85 is within one Standard deviation above the mean and 65 is within one standard deviation below the mean
Answer is E
Answer: E
Question: What percent of 60 is 80?
Options:
A)133 1⁄3
B)75
C)60
D)33 1⁄3
E)25
Rationale: % of 60 is 80?
= 80/60 = 4/3 = 133.33%
Thus A is the correct answer.
Answer: A
Question: A can do a piece of work in 30 days. He works at it for 5 days and then B finishes it in 20 days. In what time can A and B together it?
Options:
A)13 1/8 days
B)13 1/3 days
C)83 1/3 days
D)13 8/3 days
E)19 1/3 days
Rationale: 5/30 + 20/x = 1
x = 24
1/30 + 1/24 = 3/40
40/3 = 13 1/3 days
Answer: B
Answer: B
Question: Some man have some apples with him.He gave half of the apples and half an apple.This gets repeated for 4 time.After that he has no more apple with him.How many number of apples were there initially?
Options:
A)30
B)31
C)32
D)33
E)34
Rationale: some apples=x
he gave half of an apples and half of an apple and reaming he have are x/2-1/2
It is repeated four times
2nd time x/4-1/2-1/2
3d time x/8-1/2-1/2-1/2
4th time x/16-1/2-1/2-1/2-1/2=0
x/16-2=0
x=32
ANSWER:C
Answer: C
Question: If the cost price of 50 articles is equal to the selling price of 30 articles, then the gain or loss percent is?
Options:
A)22
B)65
C)78
D)66.67
E)25
Rationale: Given that, cost price of 50 article is equal to selling price of 30 articles.
Let cost price of one article = Rs. 1
Selling price of 30 articles = Rs. 50
But Cost price of 30 articles = Rs. 30
Therefore, the trader made profit.\Percentage of profit = 20/30 * 100 = 66.67%
Answer:D
Answer: D
Question: Pumps A, B, and C operate at their respective constant rates. Pumps A and B, operating simultaneously, can fill a certain tank in 1 hours; pumps A and C, operating simultaneously, can fill the tank in 1 hours; and pumps B and C, operating simultaneously, can fill the tank in 2 hours. How many hours does it take pumps A, B, and C, operating simultaneously, to fill the tank.
Options:
A)1/3
B)1/2
C)1/4
D)1
E)5/6
Rationale: A+B =1 ; A+C =1 ,B+C =2 ; ADD THEN 2*(A+B+C) = 4
A+B+C = 2 HRS
B
Answer: B
Question: Kira's seafood restaurant gets a delivery of fresh seafood every day, 7 days per week, and her delivery company charges her dollars per delivery plus cents per item delivered. If lst week Sarah's seafood restaurant had an average of x items per day delivered, then which of the following is the total cost, in dollars, of last week's deliveries ?
Options:
A)7cdx/100
B)d + 7cx/100
C)7d + xc/100
D)7d + 7xc/100
E)7cdx
Rationale: Answer is D.
Answer: D
Question: Torry has submitted 2/5 of his homework assignments, and he received an average grade of 75 for those assignments. If he wishes to receive an average grade of 120 for all his homework assignments, the average grade for Torry's remaining homework assignments must be what percent greater than the average grade for the assignments he has already submitted?
Options:
A)100%
B)20%
C)25%
D)33 1/3%
E)40%
Rationale: 0.4*75 + 0.6x = 120
30 + 0.6x=120
0.6x = 90
x= 150
150/75=2
Ans:A
Answer: A
Question: The average of 15 result is 60. Average of the first 10 of them is 10 and that of the last 10 is 80. Find the 8th result?
Options:
A)35
B)200
C)150
D)250
E)300
Rationale: Sum of all the 13 results = 15 * 60 = 900
Sum of the first 7 of them = 10 * 10 = 100
Sum of the last 7 of them = 10 * 80 = 800
So, the 8th number = 900 + 100 - 800 = 200.
B
Answer: B
Question: Lilly has 10 fish and Rosy has 11 fish. In total, how many fish do they have in all?
Options:
A)19
B)20
C)21
D)22
E)23
Rationale: 10+11=21
The answer is C.
Answer: C
Question: Ten years ago, P was half of Q's age. If the ratio of their present ages is
3:4, what will be the total of their present ages?
Options:
A)45
B)40
C)35
D)30
E)38
Rationale: Let present age P and Q be 3x 4x respectively
Ten years ago, P was half of Q's age
(3x-10) = 1/2 (4x-10)
2x = 10
x=5
Total of their present ages = 3x+4x = 7x = 7 * 5 = 35
ANSWER C
Answer: C
Question: The effective annual rate of interest corresponding to a nominal rate of 12% per annum payable half-yearly is?
Options:
A)16.06%
B)16.07%
C)12.36%
D)6.09%
E)6.19%
Rationale: Amount of Rs. 100 for 1 year when compounded half-yearly = [100 * (1 + 6/100)2] = Rs. 112.36 Effective rate = (112.36 - 100) = 12.36%
ANSWER:C
Answer: C