divelab/Sys2Bench huggingface dataset:
Question: Find the length of the wire required to go 11 times round a square field containing 27889 m2.
Options:
A)7348
B)3388
C)2667
D)8766
E)66711
Rationale: a2 = 27889 => a = 167
4a = 668
668 * 11 = 7348
Answer: A
Answer: A
Question: Mary received a 20% raise each month for three consecutive months. What was her salary after the three raises if her starting salary was $1,000 per month?
Options:
A)$1,348
B)$1,500
C)$1,631
D)$1,728
E)$1,863
Rationale: 1000 * 1.2 * 1.2 * 1.2 = 1000 * 1.728 = 1728
Answer: D
Answer: D
Question: Five drainage pipes, each draining water from a pool at the same constant rate, together can drain a certain pool in 8 days. How many additional pipes, each draining water at the same constant rate, will be needed to drain the pool in 4 days?
Options:
A) 5
B) 9
C) 10
D) 12
E) 15
Rationale: This is an inverse proportional problem......
5 pipes in 8 days; So for 4 days, it will be = 8 x 5 / 4 = 10
So, 10-5 = 5
Answer A
Answer: A
Question: A can do a work in 9 days and B can do the same work in 18 days. If they work together, in how many days will they complete the work?
Options:
A)6 days
B)7 days
C)5 days
D)3 days
E)2 days
Rationale: One day's work of A and B = 1/9 + 1/8 = (2+1)/18 = 1/6 So, the time taken to complete the work is 6 days.
Answer:A
Answer: A
Question: A can contains a mixture of liquids A and B is the ratio 7:5. When 15 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7:9. How many liter of liquid A was contained by the can initially?
Options:
A)30
B)35
C)40
D)45
E)50
Rationale: Ci*Vi = Cf*Vf
(7/12)*(V1 - 15) = (7/16)*V1
(V1 - 15)/V1 = 3/4
15 accounts for the difference of 1 on ratio scale so Initial volume = V1 = 4*15 = 60 litres.
7/12 of the initial mixture was liquid A so liquid A was (7/12)*60 = 35 litres.
Answer : B
Answer: B
Question: The compound interest on Rs. 20,000 at 8% per annum is Rs. 3,328. What is the period (in year)?
Options:
A)1 year
B)4 years
C)3 years
D)2 years
E)5 years
Rationale: Explanation:
Let the period be n years.
Amount after n years = Rs.20000 + Rs.3328 = Rs. 23328
P(1+R/100)T=23328
20000(1 + 8/100)n = 23328
20000(108/100)n = 23328
(108/100)n = 23328/20000 = 11664/10000 = (108/100)2
n = 2 years
Answer: Option D
Answer: D
Question: The ratio of three numbers is 5:3:4 and their sum is 108. The second number of the three numbers is?
Options:
A)23
B)27
C)30
D)32
E)34
Rationale: 5:3:4
Total parts = 12
12 parts --> 108
1 part ---->9
The second number of the three numbers is = 3
3 parts ----> 27
B)
Answer: B
Question: How many 7s are there in the following series which are not immediately following by 3 but immediately preceded by 8?
8 9 8 7 6 2 2 6 3 2 6 9 7 3 2 8 7 2 7 7 8 7 3 7 7 9 4
Options:
A)Nil
B)One
C)Two
D)Three
E)More than three
Rationale: 876 and 872
ANSWER:C
Answer: C
Question: Find the principal which yields a simple interest of Rs. 20 and compound interest of Rs. 30 in two years, at the same percent rate per annum?
Options:
A)s. 20
B)s. 48
C)s. 42
D)s. 20
E)s. 60
Rationale: Explanation:
SI in 2 years = Rs. 20, SI in 1 year = Rs. 10
CI in 2 years = Rs. 30
% rate per annum = [(CI – SI) / (SI in 1 year)] *100
= [(30 – 20) / 20] * 100
= 50 % p.a.
Let the principal be Rs. X
Time = T = 2 years
% rate = 50% p.a.
SI = (PRT/100)
20 = (X*50*2) / 100
X = Rs. 20
ANSWER: A
Answer: A
Question: Two trains each 250 m in length are running on the same parallel lines in opposite directions with the speed of 80 kmph and 70 kmph respectively. In what time will they cross each other completely?
Options:
A)26 sec
B)28 sec
C)12 sec
D)77 sec
E)66 sec
Rationale: D = 250 m + 250 m = 500 m
RS = 80 + 70 = 150 * 5/18 = 125/3
T = 500 * 3/125 = 12 sec
Answer: C
Answer: C
Question: If the function Q is defined by the formula Q = 5w/(4m(z^2)), by what factor will Q be multiplied if w is quadrupled, m is doubled, and z is tripled?
Options:
A)1/9
B)2/9
C)4/9
D)3/9
E)2/27
Rationale: We just need to find the factor thats all,
w -> quadrupled -> 4w
m-> doubled -> 2m
z-> tripled -> 3Z
Hence, Z^2 = 9Z^2
W is in numerator, and m*z in denominator.
Hence,
Additional factor being introduced = 4/2*9
=4/18 = 2/9 = B
Answer: B
Question: Three partners A,B & C invested total Rs. 1,15,000. After one year one olhem gets a profit of Rs.6000, second gets Rs. 10,000 and third gets Rs. 14000 then how much amount did B invested?
Options:
A)Rs.10,000
B)Rs.40,000
C)Rs.20,000
D)Rs.50,000
E)none
Rationale: 3:5:7 is thr ratio's of their profits
(5/15)*115000
ans is 38333.3
ANSWER:E
Answer: E
Question: (74 + 75 + 76 + 77 + ..... + 149 + 150) = ?
Options:
A)8624
B)8634
C)8654
D)8644
E)8677
Rationale: Explanation:
Sum of first n natural numbers
= (1 + 2 + 3 + ..... + n) = n(n+1)/2
(74 + 75 + 76 + .....+ 150)
=(1 + 2 + .... + 73 + 74 + 75 + .....+ 150) - (1 + 2 + .... + 73)
=(1/2 x 150 x 151) - (1/2 x 73 x 74)
= 11325 - 2701 = 8624
Answer: Option A
Answer: A
Question: Rectangular tile each of size 45cm by 50cm must be laid horizontally on a rectangular floor of size 250cm by 180cm,such that the tiles do not overlap and they are placed with edges jutting against each other on all edges. A tile can be placed in any orientation so long as its edges are parallel to the edges of floor. No tile should overshoot any edge of the floor. The maximum number of tiles that can be accommodated on the floor is:
Options:
A)35
B)40
C)25
D)18
E)20
Rationale: Area of tile = 45*50 = 2250
Area of floor = 250*180 = 45000
No of tiles = 45000/2250 = 20
So, the no of tile =20
ANSWER:E
Answer: E
Question: The speeds of three motor bikes are in the ratio 12 : 4 : 6. The ratio between the time taken by them to travel the same distance is :
Options:
A)1 : 3 : 5
B)1 : 4 : 2
C)1 : 2 : 2
D)1 : 3 : 3
E)1 : 3 : 2
Rationale: Ratio of time taken :
1/12 :1/4 : 1/6 = 1 : 3 : 2
ANSWER:E
Answer: E
Question: Vijay bought 160 shirts at the rate of Rs. 245 per shirt. The transport expenditure was Rs. 1400. He paid an octroi at the rate of Rs. 1.75 per shirt and labour charges were Rs. 320. What should be the selling price of one shirt, if he wants a profit of 20%?
Options:
A)Rs. 258
B)Rs. 270
C)Rs. 277.5
D)Rs. 309
E)None of these
Rationale: Total CP per shirt = 245 + 1400/160 + 1.75 + 320/160 = Rs. 257.5
SP = CP[(100 + profit%)/100]
= 257.5 * [(100 + 20)/100] = Rs. 309.
ANSWER:D
Answer: D
Question: John has on his shelf one books of poetry, seven novels, and two reference works. Suppose from these ten books, we were to pick two books at random. What is the probability that we pick one novel and one reference work?
Options:
A)1/2
B)2/5
C)3/10
D)7/20
E)14/45
Rationale: When we are picking two books, one novel and one reference work, we could either pick a novel first and then a reference book or pick a reference book and then a novel. Therefore the answer is 7/10*2/9 + 2/10*7/9 = 14/45.
Answer: E.
Answer: E
Question: Three pipes A, B and C can fill a tank in 6 hours. After working at it together for 2 hours. C is closed A and B can fill the remaining par in 7 hours. The number of hours taken by C alone to fill the tank is?
Options:
A)76
B)55
C)14
D)33
E)99
Rationale: Part filled in 2 hours = 2/6 = 1/3.
Remaining part = 1 - 1/3 = 2/3
(A + B)'s 1 hour work = 2/21
C's 1 hour work = [(A + B + C)'s 1 hour work - (A + B)'s 1 hour work]
= (1/6 - 2/21) = 1/14
C alone can fill the tank in 14 hours.Answer:C
Answer: C
Question: A man cheats while buying as well as while selling. While buying he takes 11% more than what he pays for and while selling he gives 20% less than what he claims to. Find the profit percent, if he sells at 9.09% below the cost price of the claimed weight.
Options:
A)19.81%
B)20%
C)37.5%
D)25%
E)42.86%
Rationale: There is a one step calculation method too. It requires more thought but is faster.
The man takes 11% more than what he pays for. So if he claims to take 100 pounds, he pays $100 but he actually takes 111 pounds for which he will take from the customer $111. Hence, in effect, there is a 11% mark up.
While selling, he sells 30% less. This means, he claims to sell 100 pounds and gets $100 but actually sells only 70 pounds and should have got only $70 for it. So this is again a mark up of $30 on $70.
But he also sells at 9.09% less i.e. gives a discount of 1/11.
(1 + m1%)(1 + m2%)(1 - d%) = (1 + p%)
11/10 * 10/7 * 10/11 = (1 + p%)
profit % = 42.86%E
Answer: E
Question: The volume of a wall, 5 times as high as it is broad and 8 times as long as it is high, is 12.8 cu. meters. Find the breadth of the wall.
Options:
A)40
B)29
C)28
D)27
E)12
Rationale: Explanation:
Let the breadth of the wall be x metres.
Then, Height = 5x metres and Length = 40x metres.
x * 5x * 40x = 12.8
=>\inline \fn_jvn x^3=\frac{12.8}{200}=\frac{128}{2000}=\frac{64}{1000}
=>\inline \fn_jvn x=\frac{4}{10}m
=>\inline \fn_jvn x=\frac{4}{10}\times 100=40cm
Answer: A) 40cm
Answer: A
Question: There are 5,280 feet in 1 mile and 10 inches in one foot. How many inches are in a mile?
Options:
A)5,280 - 12
B)5,280/12
C)12(5,280)
D)12^2(5,280)
E)10*5,280
Rationale: 1 feet = 10 inches
1 mile = 5280 feet
1 mile = 5280*10 inches
Ans: E
Answer: E
Question: What is the remainder when 5990990900032 is divided by 32 ?
Options:
A)16
B)8
C)0
D)2
E)3
Rationale: Though i was unaware of the divisibility test for 32 but i guessed the pattern!!
divisibility rule for 4- last two digits must be divisible by 4
divisibility rule for 8- last three digits must be divisible by 8
similarly, divisibility rule for 32 - last five digits must be divisible by 32
Hence, Ans C
Answer: C
Question: A dishonest dealer professes to sell goods at the cost price but uses a weight of 800 grams per kg, what is his percent?
Options:
A)25%
B)25%
C)29%
D)55%
E)45%
Rationale: 800 --- 200
100 --- ? => 25%
Answer: B
Answer: B
Question: if integer N has p factors ; how many factors will 8N have ?
Options:
A)p
B)2p
C)P+1
D)2p+1
E)Cannot be determined
Rationale: Case 1:
Let N = 6 => 2 x 3 (prime factorization) => p = 4;
8N = 48 => No. of factors = 10; (p+6)
Case 2:
Let N = 7 => 3^2 (prime factorization) => p = 2;
8N = 56 => no of factors = 8; (4p)
For different N different results are observed. So, shouldn't E be the right answer?
Answer: E
Question: Tim came second in Math. When his mother asked him how much he had scored, he answered that he got the sum of the first 9 even numbers. His mother immediately worked out the answer. How much had he scored in Math?
Options:
A)80
B)90
C)30
D)70
E)60
Rationale: B
90
Sum = (n x n) + n
Hence, 9 x 9 = 81 + 9 = 90
Answer: B
Question: A, B and C start a business, each investing Rs. 30,000/-. After 4 months A withdrew Rs. 10,000/-, B Rs. 6,000/- and C invested Rs 8000/- more. At the end of the year, a total profit of Rs. 69,000/-was recorded. What is the share of B?
Options:
A)Rs. 25000/-
B)Rs. 21,600/-
C)Rs. 21,000/-
D)Rs. 21,200/-
E)None of these
Rationale: Explanation:
A : B : C = (30000 * 4 + 10000 * 8) : (30000 * 4 + 6000 * 8) : (30000 * 4 + 8000 * 8)
(120000 + 80000) : (120000 + 48000) : (120000 + 64000)
= 200000 : 168000 : 184000
A : B : C = 25 : 21 : 23
B’s Share = Rs. (69000 * 21/69) = 1000 * 21 = Rs. 21,000/-
Answer: Option C
Answer: C
Question: If the cost price of 72 articles is equal to the selling price of 60 articles, then what is the percent profit?
Options:
A)10%
B)15%
C)20%
D)25%
E)30%
Rationale: Let x be the cost price of one article.
Let y be the selling price of one article.
60y = 72x
y = 1.2x
The answer is C.
Answer: C
Question: In 1999, there are 28 days in February and there are 365 days in the year. In 2000, there are 29 days in February and there are 366 days in the year. If the date March 20, 1999 is a Wednesday, then which one of the following would the date March 20, 2000 be?
Options:
A)Friday
B)Tuesday
C)Monday
D)Sunday
E)Saturday
Rationale: From the information given, March 20, 2000 is 366 days after March 20, 1999.
366 days = 52 weeks and 2 more days. Therefore if March 20, 1999 is a Wednesday, then March 20, 2000 is Wednesday + 2 days = Friday
Answer: A
Answer: A
Question: The list price of an article is Rs.69. A customer pays Rs.56.16 for it. He was given two successive discounts, one of them being 10%. The other discount is?
Options:
A)9.33%
B)9.44%
C)9.45%
D)9.56%
E)9.67%
Rationale: 69*(90/100)*((100-x)/100) = 56.16
x = 9.56%
ANSWER:D
Answer: D
Question: The ratio of the volumes of two cubes is 729 : 2197. What is the ratio of their total surface areas?
Options:
A)81 : 169
B)81 : 122
C)81 : 124
D)81 : 126
E)81 : 129
Rationale: Ratio of the sides = 3√729 : 3√2197 = 9 : 13
Ratio of surface areas = 9^2 : 13^2 = 81 : 169
Answer: Option A
Answer: A
Question: Country X taxes each of its citizens an amount equal to 14 percent of the first $40,000 of income, plus 20 percent of all income in excess of $40,000. If a citizen of Country X is taxed a total of $8,000, what is her income?
Options:
A)$40,000
B)$52,000
C)$64,000
D)$66,667
E)$80,000
Rationale: Equation is correct, so math must be a problem.
0.14*40,000+0.2*(x-40,000)=8,000 --> 5,600+0.2x-8,000=8,000 --> 0.2x=10,400 --> x=52,000.
Answer: B.
Answer: B
Question: What is the smallest positive integer x such that 507+x is the cube of a positive integer?
Options:
A)15
B)5
C)50
D)2
E)4
Rationale: Given 507+x is a perfect cube
so we will take 512 = 8*8*8
507+x = 512
x = 512-507 = 5
correct option is B
Answer: B
Question: There are two shelves A and B.The number of books in shelf A is 50 more than in shelf B..Then 20 books are removed from each shelf..Then the number of books in shelf A is twice the number of books in shelf..what are the number of books in shelf A originally?
Options:
A)100
B)115
C)130
D)120
E)140
Rationale: consider the books in B is x,then A has x+50,now 20 books are removed from both A&B then A has x+30,B has x-20,now books in A will be twice of books in shelf B
so x+30=2(x-20) solve this eq gives x=70 so initially A has 120 books
ANSWER:D
Answer: D
Question: Calculate the share of Y , if Rs. 690 is divided among X, Y and Z in the ratio 5 : 7 : 11?
Options:
A)190
B)160
C)120
D)151
E)150
Rationale: 5 + 7 + 11 =23
690/23=30
so Y's share=5*30
=150
ANSWER:E
Answer: E
Question: If 60 percent of 600 is 50 percent of x, then x=?
Options:
A)600
B)720
C)820
D)800
E)920
Rationale: 0.6 * 600 = 0.5 * x
x = 6/5 * 600 = 720
Answer: B
Question: One train is traveling 45 kmph and other is at 10 meters a second. Ratio of the speed of the two trains is?
Options:
A)5:4
B)5:9
C)5:6
D)5:1
E)5:7
Rationale: 45 * 5/18 = 10
25:20 => 5:4
Answer: A
Answer: A
Question: The current of a stream runs at the rate of 3 kmph. A boat goes 6 km and back to the starting point in 2 hours, then find the speed of the boat in still water?
Options:
A)A)7.24
B)B)2
C)C)8.5
D)D)6.67
E)E)3
Rationale: S = 3
M = x
DS = x + 3
US = x - 3
6/(x + 3) + 6/(x - 3) = 2
x = 7.24
Answer:A
Answer: A
Question: Fresh grapes contain 80% by weight while dried grapes contain 20% water by weight. What is the weight of dry grapes available from 40 kg of fresh grapes?
Options:
A)10 kg
B)12 kg
C)15 kg
D)16 kg
E)20 kg
Rationale: From the question we know: 40kg * 80% = 32kg of water in the fresh grapes
40kg - 32kg of water = 8kg of non-water mass
We are looking for the weight of the dry grapes (X).
Since the question tells us that 20% of the weight of the dry graps is water and we know that 8kg is non-water mass we can set up the following equation:
X = 1/5(X) + 8kg
4/5(X) = 8kg
X = 10 kg
Answer- A
Answer: A
Question: The water from one outlet, flowing at a constant rate, can fill a swimming pool in 16 hours. The water from a second outlet, flowing at a constant rate, can fill the same pool in 12 hours. If both outlets are used at the same time, approximately what is the number of hours required to fill the pool?
Options:
A) 0.22
B) 0.31
C) 2.50
D) 3.21
E) 6.85
Rationale: Always remember RT=W i.e Rate*Time = Work
Also remember that rate can be added or subtracted. For e.g if A do a work in 2 day and B do a work in 2 day.
They both of them together will do a work in 1 day.
So now your question first determine both outlets rate.
1st outlet rate = 1/16 (R=W/T here W=1 work, T = 16hrs)
2nd outlet rate = 1/12 (R=W/T here W=1 work, T = 12hrs)
Both of them working together rate = 1st outlet rate + 2nd outlet rate = 1/16+1/12 = 7/48
again apply the formula RT=W
T = W/R = 1/7/48 = 48/7 =6.85
Answer is E.
Answer: E
Question: In how many ways can the letters of the word RECPECT be arranged?
Options:
A)2580
B)2500
C)2000
D)2520
E)3420
Rationale: RECPECT has 7 words, but E is repeated two times. Thus ways = 7! / 2! = 2520 ways
C
Answer: C
Question: Janet has to pay back her bank loan over 8 months following the below sequence.
$50, $55, $65, $80, $85, $95, $110, ?
How much will she pay back on the eigthmonth?
Options:
A)$115
B)$145
C)$135
D)$125
E)$130
Rationale: The sequence progresses +5, +10, +15 repeated; The amount to pay back on the 8th Month is $115
Ans A
Answer: A
Question: Can you find the missing number in the sequence?
7 12 37 ? 9142
Options:
A)1262
B)2189
C)1132
D)1214
E)3256
Rationale: A
1262
Sequence is based on formula:
Next = (1st Number)^2 - (2nd number)
7 12 37 ? 9142
7^2 - 12 = 37
12^2 - 37 = 107
37^2 - 107 = 1262 (Answer)
102^2 - 1262 = 9142
Answer: A
Question: In a multiple choice test comprising 5 Questions, each with 4 choices, what is the probability of a student getting 3 or more questions correct? Each question has only one correct answer and the student is equally likely to choose any of the four choices.
Options:
A)24/256
B)53/512
C)105/512
D)459/512
E)47/256
Rationale: Probability for choosing correct answer is 1/4 and incorrect answer is 3/4
For 3 correct answers,
C(5,3)*(1/4)^3*(3/4)^2=90/(4^5)
For 4 correct answers,
C(5,4)*(1/4)^4*(3/4)^1=15/(4^5)
For 5 correct answers,
C(5,5)*(1/4)^5*(3/4)^0=1/(4^5)
So total probability
=106/1024
=53/512
Ans B
Answer: B
Question: The average price of three items of furniture is Rs. 30000. If their prices are in the ratio 3:5:7, the price of the cheapest item is?
Options:
A)2379
B)2889
C)9288
D)9000
E)6000
Rationale: Let their prices be 3x, 5x and 7x.
Then, 3x + 5x + 7x = (15000 * 3) or x = 2000.
Cost of cheapest item = 3x = Rs. 6000.
Answer: E
Answer: E
Question: There are 10 women and 8 men in a certain club. If the club is to select a committee of 2 women and 2 men, how many different such committees are possible?
Options:
A)1040
B)1260
C)1480
D)1620
E)1850
Rationale: 10C2 * 8C2 = 45*28 = 1260
The answer is B.
Answer: B
Question: Given that 0 < a < b < c < d, which of the following the largest ?
Options:
A)(c+d) / (a+b)
B)(c+d) / (a+c)
C)(c+d) / (a+q)
D)(c+d) / (a+o)
E)(c+d) / (a+f)
Rationale: Explanation: Take a = 1, b = 2, c = 3, d = 4. option A is clearly true.
Sol: A
Answer: A
Question: if a@b = a * b^(1/2) then 2@25 = ?
self made
Options:
A)2
B)6
C)10
D)8
E)4
Rationale: 2* (25)^1/2= 2*5= 10
C is the answer
Answer: C
Question: At a tanning salon, customers are charged $10 for their first visit in a calendar month and $7 for each visit after that in the same calendar month. In the last calendar month, 100 customers visited the salon, of which 30 made a second visit, and 10 made a third visit. All other customers made only one visit. If those visits were the only source of revenue for the salon, what was the revenue for the last calendar month at the salon?
Options:
A)$1220
B)$1280
C)$1300
D)$1340
E)$1880
Rationale: I get B. This question seems too straightforward for 600+. Am I missing something?
100 first-time visits --> 100(10) = $1000
30 + 10 = 40 subsequent visits --> 40(7) = $280
Total revenue: 1000+ 280 = $1280
The answer is B.
Answer: B
Question: The radius of a wheel is 22.4 cm. What is the distance covered by the wheel in making 1250 resolutions?
Options:
A)1277 m
B)1760 m
C)1278 m
D)1288 m
E)1378V
Rationale: In one resolution, the distance covered by the wheel is its own circumference. Distance covered in 1250 resolutions.
= 1250 * 2 * 22/7 * 22.4 = 176000 cm
= 1760 m
Answer: B
Answer: B
Question: The average height of 35 boys in a class was calculated as 183cm. It has later found that the height of one of the boys in the class was wrongly written as 166 cm whereas his actual height was 106 cm. Find the actual average height of the boys in the class (Round off your answer to two decimal places?
Options:
A)187.89 cm
B)181.29 cm
C)123.98 cm
D)149.98 cm
E)146.89 cm
Rationale: Calculated average height of 35 boys = 183 cm.
Wrong total height of 35 boys = 183 * 35 cm. This was as a result of an actual height of 106 cm being wrongly written as 166 cm. Correct total height of 35 boys = 183 cm - (166 cm - 106 cm)/35
= 183 cm - 60 /35 cm
= 183 cm - 1.71 cm = 181.29 cm.
Answer: B
Answer: B
Question: A sum of Rs. 2743 is lent into two parts so that the interest on the first part for 8 years at 3% per annum may be equal to the interest on the second part for 3 years at 5% per annum. Find the second sum?
Options:
A)1642
B)1640
C)1632
D)1688
E)6386
Rationale: (x*8*3)/100 = ((2743 - x)*3*5)/100
24x/100 = 41145/100 - 15x/100
39x = 41145 => x = 1055
Second sum = 2743 – 1055
=1688
Answer:D
Answer: D
Question: A bank offers 5% compound interest calculated on half-yearly basis. A customer deposits $ 1600 each on 1stJanuary and 1st July of a year. At the end of the year, the amount he would have gained by way of interest is:
Options:
A)$120
B)$121
C)$122
D)$123
E)$124
Rationale: Amount	= $ 1600 x 1 +	5 2	+ 1600 x 1 +	5
2 x 100 2 x 100
= $ 1600 x	41	x	41	+ 1600 x	41
40 40 40
= $ 1600 x	41 41	+ 1
40 40
= $ 1600 x 41 x 81
40 x 40
= $ 3321.
C.I. = $. (3321 - 3200) = $ 121
ANSWER : B $ 121
Answer: B
Question: India has a run rate of 3.2 in the first 10 overs. What should be the run rate in remaining 40 overs to win a game of 282 runs?
Options:
A)6.25
B)6.27
C)6.22
D)6.21
E)6.20
Rationale: Explanation:
Runs scored in first 10 overs:
=> Rate*Overs= 3.2*10 = 32 runs
=> Required runs = 282-32 = 250
=> Left overs= 40
Required rate = runs/overs
= 250/40
= 6.25
=> 6.25 runs per over is needed to win the game.
ANSWER: A
Answer: A
Question: In how many ways can 21 books on English and 19 books on Hindi be placed in a row on a shelf so that two books on Hindi may not be together?
Options:
A)1540
B)2314
C)5420
D)1240
E)4512
Rationale: We must place all these books as under:
XEXEX….XEX
There are 21 books on English, 19 books on Hindi
19 places out of 22 can be chosen 22C19=22C3=1540 ways
ANS: A
Answer: A
Question: Two trains A and B starting from two points and travelling in opposite directions, reach their destinations 9 hours and 4 hours respectively after meeting each other. If the train A travels at 110kmph, find the rate at which the train B runs.
Options:
A)40
B)165
C)120
D)80
E)100
Rationale: If two objects A and B start simultaneously from opposite points and, after meeting, reach their destinations in ‘a’ and ‘b’ hours respectively (i.e. A takes ‘a hrs’ to travel from the meeting point to his destination and B takes ‘b hrs’ to travel from the meeting point to his destination), then the ratio of their speeds is given by:
Sa/Sb = √(b/a)
i.e. Ratio of speeds is given by the square root of the inverse ratio of time taken.
Sa/Sb = √(4/9) = 2/3
This gives us that the ratio of the speed of A : speed of B as 2:3.
Since speed of A is 110 kmph, speed of B must be 110*(3/2) = 165 kmph
Answer B
Answer: B
Question: Rs. 800 becomes Rs. 956 in 3 years at a certain rate of simple interest.If the rate of interest is increased by 4% ,What amount will Rs. 800 become in 3 years ?
Options:
A)Rs. 1020.80
B)Rs. 1025
C)Rs. 1052
D)Data inadequate
E)None of these
Rationale: Solution
S.I. = Rs.(956-800 )=Rs.156
Rate = (100x156/800x3) = 6 1/2%
New rate = (6 1/2 +4)% = 10 1/2%
New S.I. = Rs.(800 x21/2x3/100) Rs. 252.
∴ New amount = Rs.(800+252)= Rs. 1052.
Answer C
Answer: C
Question: A sum of money is put out at compound interest for 2 years at 20%. It would fetch Rs.482 more if the interest were payable half-yearly, then it were pay able yearly. Find the sum.
Options:
A)3377
B)6886
C)2788
D)2000
E)28712
Rationale: P(11/10)4 - P(6/5)2 = 482
P = 2000
Answer:D
Answer: D