divelab/Sys2Bench huggingface dataset:
Question: The speed at which a man can row a boat in still water is 15 kmph. If he rows downstream, where the speed of current is 3 kmph, what time will he take to cover 60 metres?
Options:
A)38 seconds
B)26 seconds
C)88 seconds
D)12 seconds
E)18 seconds
Rationale: Speed of the boat downstream = 15 + 3 = 18 kmph
= 18 * 5/18 = 5 m/s
Hence time taken to cover 60 m = 60/5 = 12 seconds.
Answer:D
Answer: D
Question: An amount of Rs. 100000 is invested in two types of shares. The first yields an interest of 9% p.a and the second, 11% p.a. If the total interest at the end of one year is 9 3/5 %, then the amount invested at 11% was?
Options:
A)23777
B)30000
C)29977
D)26777
E)19871
Rationale: Let the sum invested at 9% be Rs. x and that invested at 11% be Rs. (100000 - x). Then,
(x * 9 * 1)/100 + [(100000 - x) * 11 * 1]/100 = (100000 * 48/5 * 1/100)
(9x + 1100000 - 11x) = 960000
x = 70000
Sum invested at 9% = Rs. 70000
Sum invested at 11% = Rs. (100000 - 70000) = Rs. 30000.
Answer: B
Answer: B
Question: The length of the bridge, which a train 160 metres long and travelling at 45 km/hr can cross in 30 seconds, is?
Options:
A)255
B)267
C)245
D)277
E)215
Rationale: Speed = [45 X 5/18] m/sec = [25/2] m/sec Time = 30 sec Let the length of bridge be x metres. Then, (160 + x)/30 = 25/2 => 2(160 + x) = 750 => x = 215 m.
Answer:E
Answer: E
Question: What number when divided in half becomes zero ?
Options:
A)2
B)4
C)9
D)6
E)8
Rationale: E
8 is the required number.
Here, by dividing in half, we will actually chop off the digit from the middle. Then you will be left with two zeroes.
Answer: E
Question: Calculate the distance covered by 320 revolutions of a wheel of radius 28.1 cm.
Options:
A)465.2 m
B)965.2 m
C)265.2 m
D)565.2 m
E)165.2 m
Rationale: In one resolution, the distance covered by the wheel is its own circumference. Distance covered in 500 resolutions.
= 320 * 2 * 22/7 * 28.1 = 56521.14 cm = 565.2 m
ANSWER:D
Answer: D
Question: A rectangular field has to be fenced on three sides leaving a side of 2020 feet uncovered. If the area of the field is 680680 sq. feet, how many feet of fencing will be required?
Options:
A)95
B)92
C)88
D)82
E)80
Rationale: Explanation:
Area of the field =680 sq. feet.
Length of the adjacent sides are
20 feet and 680/20=34 feet.
Required length of the fencing
=20+34+34=88 feet
Answer: Option C
Answer: C
Question: A can do a piece of work in 4 hours; B and C together can do it in 3 hours, while A and C together can do it in 2 hours. How long will B alone take to do it?
Options:
A)8 hours
B)10 hours
C)12 hours
D)24 hours
E)none of the above
Rationale: A's 1 hour's work = 1/4 ;
(B + C)'s 1 hour's work = 1/3 ;
(B + C)'s 1 hour's work = 1/2
(A + B + C)'s 1 hour's work = (1/4 + 1/3) = 7/12
B's 1 hour's work = (7/12 - 1/2) = 1/12
B alone will take 12 hours to do the work.
Answer = C
Answer: C
Question: What is the sum of natural numbers between 60 and 100
Options:
A)4800
B)4860
C)5000
D)5500
E)3280
Rationale: a = first number
l = last number
Sn = n/2[a + l]
between 60 and 100 numbers = 41 => 100 - 60 = 40 + 1 = 41
Sn = 41/2 Ã— 160 = 41 Ã— 80 = 3280
Answer : E
Answer: E
Question: he total marks obtained by a student in Physics, Chemistry and Mathematics is 130 more than the marks obtained by him in Physics. What is the average mark obtained by him in Chemistry and Mathematics?
Options:
A)55
B)65
C)75
D)85
E)95
Rationale: Let the marks obtained by the student in Physics, Chemistry and Mathematics be P, C and M respectively.
P + C + M = 130 + P
C + M = 130
Average mark obtained by the student in Chemistry and Mathematics = (C + M)/2 = 130/2 = 65.
ANSWER:B
Answer: B
Question: A table is bought for Rs.400/- and sold at Rs.300/- find gain or loss percentage
Options:
A)25% loss
B)20% gain
C)20% loss
D)15% gain
E)None
Rationale: Formula = (Selling price ~ Cost price)/Cost price * 100
= (300 - 400)/400 = 25% loss
A
Answer: A
Question: Joseph Paul and his friend went for fishing.
They got six fishes without heads, nine fishes without the tail and eight fishes cut in two halves.
How many fishes did they caught ?
Options:
A)0
B)4
C)1
D)7
E)5
Rationale: A
6 without head => 0
9 without tail => 0
8 in two halves => 0 & 0
Answer: A
Question: A green lizard can travel from the green cave to the blue cave in 108 minutes; the blue lizard can travel from the blue cave to the green cave in 25% less time. If the green lizard started to travel 7.5 minutes before the blue lizard, how many minutes after the blue lizard, will the green lizard pass the middle line?
Options:
A)2.
B)3.5.
C)4.
D)5.5.
E)6.
Rationale: Time take by the green lizard to cover the distance between the caves = 108 mins
Time take by the green lizard to cover half the distance = 108/2 = 54 mins
Time take by the blue lizard to cover the distance between the caves = 108 x 3/4 =81 mins
Time take by the blue lizard to cover half the distance = 81/2 = 40.5 mins
Now the green lizard had been travelling for 7.5 mins when the blue lizard started. Therefore when the blue lizard starts to move the green lizard will have to cover 54 - 7.5 = 46.5 mins worth of distance at its current speed.
Difference in time when they both reach the mid point = 46.5 - 40.5 = 6mins.
E IS THE CORRECT ANSWER.
Answer: E
Question: If 40% of a certain number is 160, then what is 60% of that number?
Options:
A)270
B)380
C)260
D)360
E)240
Rationale: Explanation:
40% = 40*4 = 160
60% = 60*4 = 240
Answer: Option E
Answer: E
Question: Working simultaneously and independently at an identical constant rate, 6 machines of a certain type can produce a total of x units of product P in 10 days. How many of these machines, working simultaneously and independently at this constant rate, can produce a total of 5x units of product P in 6 days?
Options:
A)50
B)18
C)16
D)12
E)8
Rationale: 6 machines do x units in 10 days
we have x/10 => rate of the 6 machines
we know that we need to have 5x units in 6 days
therefore, we need to get to 5x/6 rate of the machines.
rate of one machine is x/10*1/6 = x/60.
now, we need to know how many machines need to work simultaneously, to get 5x done in 6 days.
5x/6 work needs to be done by machines that work at x/60 rate.
let's assign a constant Y for the number of machines:
(x/60)*y = 5x/6
y = 5x/6 * 60/x
cancel 6 with 60, and x with x and get -> 50. Answer choice A
Answer: A
Question: Find the least number must be subtracted from 11070 so that remaining number is divisible by 22.
Options:
A)2
B)3
C)4
D)7
E)8
Rationale: On dividing 11070 by 22 we get the remainder 4, so 4 should be subtracted. Answer is A.
Answer: A
Question: The perimeter of one face of a cube is 28 cm. Its volume will be:
Options:
A)125cm3
B)343cm3
C)250cm3
D)625cm3
E)None of these
Rationale: Explanation:
Edge of cude = 28/4 = 7 cm
Volume = a*a*a = 7*7*7 = 343 cm cube
Option B
Answer: B
Question: If a2 + b2 + c2 = 213 and ab + bc + ca = 6, then a + b + c is
Options:
A)14
B)20
C)15
D)32
E)64
Rationale: by formula ,
(a + b + c)^2= a^2 + b^2 + c^2 + 2(ab + bc + ca),
since, a^2 + b^2 + c^2 = 213 and ab + bc + ca = 6,
(a + b + c)^2 = 213 + 2(6)
= 225
= 15^2
therefore: a + b + c = 15
ANSWER:C
Answer: C
Question: Two trains, each 100 meters long, moving in opposite directions, completely pass each other in 20 seconds. If one train is moving twice as fast the other, then what is the speed of the faster train (in km/hr)?
Options:
A)16 km/hr
B)20 km/hr
C)24 km/hr
D)28 km/hr
E)32 km/hr
Rationale: Let the speed of the slower train be x m/s
Then, the speed of the faster train is 2x m/s
The relative speed is 3x m/s
(100 + 100)/20 = 3x
x = 10/3 m/s
So, the speed of the faster train is 20/3 = 20/3 * 18/5 = 24 km/hr
The answer is C.
Answer: C
Question: The volumes of two cones are in the ratio 1 : 10 and the radii of the cones are in the ratio of 1 : 2. What is the length of the wire?
Options:
A)2:5
B)1:5
C)3:5
D)4:5
E)6:5
Rationale: The volume of the cone = (1/3)Ï€r2h
Only radius (r) and height (h) are varying.
Hence, (1/3)Ï€ may be ignored.
V1/V2 = r12h1/r22h2 => 1/10 = (1)2h1/(2)2h2
=> h1/h2 = 2/5
i.e. h1 : h2 = 2 : 5
ANSWER A
Answer: A
Question: In a series of six consecutive even numbers, the sum of the second and sixth numbers is 24. What is the fourth number?
Options:
A)10
B)11
C)12
D)14
E)15
Rationale: Let the numbers be x, x + 2, x + 4, x + 6, x + 8 and x + 10.
Given (x + 2) + (x + 10) = 24
=> 2x + 12 = 24 => x = 6
The fourth number = x + 6 = 6 + 6 = 12.
C
Answer: C
Question: If p^2 = q^2, which of the following must be true?
Options:
A)p =q
B)p = −q
C)p = |k|
D)|p| = |q|
E)p = −|q|
Rationale: Since p^2=q^2 we have 0=p^2 – q^2 =(p-q)*(p+q). So p=q or p=-q.
So only (A) and only (B) cannot be an answer.
The choice (C) tells us that k should be greater than or equal to 0.
Similarly the choice (E) tells us that k should be less than or equal to 0.
So neither (C) nor (E) cannot be the answer.
The answer is, therefore, (D).
Answer: D
Question: In the manufacture of a certain product, 4 percent of the units produced are defective and 4 percent of the defective units are shipped for sale. What percent of the units produced are defective units that are shipped for sale?
Options:
A)0.125%
B)0.2%
C)0.16%
D)1.25%
E)2.0%
Rationale: Percent of defective produced = 4%
Percent of the defective units that are shipped for sale = 4%
Percent of units produced are defective units that are shipped for sale = (4/100)*(4/100)*100%
= (16/10000)*100%
= (16/100)%
= .16 %
Answer C
Answer: C
Question: In Township K, 1/5 of the housing units are equiped with cable Tv. If 1/10 of the housing units, including 1/4 of those that are equiped with cable tv, are equipped with videocassette recorders, what fraction of the housing units have neither cable tv nor videocassette recorders?
Options:
A)3/4
B)11/15
C)7/10
D)1/6
E)2/15
Rationale: 1/5 -- cable TV (This includes some data from video cassette recorder)
1/10 -- video cassette recorder including 1/4(equiped with cable tv) i.e. 1/4(1/5) = 1/20
therefore only video cassette recorder = 1/10 - 1/20 = 1/20
Total = 1/5+1/20+neither cable tv nor videocassette recorders
1 = 1/4 + neither cable tv nor videocassette recorders
therefore neither cable tv nor videocassette recorders = 1-1/4 = 3/4
Hence A.
Answer: A
Question: The time on a clock is 20 minutes past 7. What is the angle between the hands of the clock?
Options:
A)60 degrees
B)100 degrees
C)80 degrees
D)50 degrees
E)120 degrees
Rationale: The hour hand rotates 360 degrees in twelve hours.
The hour hand rotates 30 degrees in one hour.
The hour hand rotates 5 degrees in ten minutes.
At this time, the hour hand has rotated 220 degrees.
The minute hand rotates 360 degrees in 60 minutes, or 60 degrees in ten minutes.
At this time, the minute hand has rotated 120 degrees.
The difference is 220 - 120 = 100 degrees.
The answer is B.
Answer: B
Question: The least number which when divided by 5, 6 , 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is:
Options:
A)1677
B)1683
C)2523
D)3363
E)3478
Rationale: L.C.M. of 5, 6, 7, 8 = 840.
Required number is of the form 840k + 3
Least value of k for which (840k + 3) is divisible by 9 is k = 2.
Required number = (840 x 2 + 3) = 1683. Answer: Option B
Answer: B
Question: On a summer camp, 25% of the campers paid $110 each, 35% paid $80 each and the rest paid $65 each. What percentage of the total amount paid came from the campers who paid $80?
Options:
A)18%
B)21%
C)33.35
D)33.3%
E)37.5%
Rationale: let the total no of campers be 100
total amount = (25*110)+(35*80)+(40*65) = 2750+2800+2600= $8150
required percentage = (2800/8150)*100=33.35%
C
Answer: C
Question: If there are 8 pairs of twins, and a committee will be formed with 3 members. In how many ways this committee formed in a way that no siblings in a group?
Options:
A)32
B)24
C)56
D)448
E)540
Rationale: Firstly, there are 8 ways to choose 3 groups from the 4 groups. Hence 8C3.
Next, with the 3 groups chosen, there are 2^3 choices of choosing either one of the siblings.
Hence, the total number of ways are 8C3 * (2^3) = 448
D
Answer: D
Question: The length of rectangle is thrice its breadth and its perimeter is 80 m, find the area of the rectangle?
Options:
A)432 sq m
B)356 sq m
C)300 sq m
D)428 sq m
E)525 sq m
Rationale: 2(3x + x) = 80
l = 30 b = 10
lb = 30 * 10 = 300
ANSWER:C
Answer: C
Question: If wy + z = w(y + z), which of the following must be true?
Options:
A) x = 0 and z = 0
B) w = 1 and y = 1
C) w = 1 and z = 0
D) w = 1 or y = 0
E) w = 1 or z = 0
Rationale: wy + z = wy + wz
z = wz
case 1: z not= 0, w = z/z = 1
case 2: z = 0, 0 = w0 = 0
Combining 2 cases: w = 1 or z =0
E. is the answer.
Answer: E
Question: The sum of present age of Abe and the age before 7 years is 37. Find the present age of Abe. What will be his age after 7 years?
Options:
A)25
B)26
C)27
D)28
E)29
Rationale: Present age = x
Before 7yrs, y=x-7
After 7yrs, z=x+7
By the qn,
x+(x-7)=37
2x-7=37
2x=37+7
x=44/2
x=22
z=x+7
=22+7
=29
ANSWER:E
Answer: E
Question: . In a certain city, 60 percent of the registered voters are Democrats and the rest are Republicans. In a mayoral race, if 65 percent of the registered voters who are Democrats and 20 percent of the registered voters who are Republicans are expected to vote for Candidate A, what percent of the registered voters are expected to vote for Candidate A ?
Options:
A) 50%
B) 47%
C) 54%
D) 55%
E) 57%
Rationale: Registered voters = 100
D = 60
R = 40
65% of D ( 60) = 39
20% of R ( 40 ) = 8
Total voter% of registered voters = 47 / 100
47% Ans B
Answer: B
Question: Two pipes P and Q can fill a cistern in 12 and 15 minutes respectively. Both are opened together, but at the end of 3 minutes the first is turned off. How much longer will the cistern take to fill?
Options:
A)9 1/4 min
B)11 1/4 min
C)7 1/4 min
D)8 1/2 min
E)9 1/2 min
Rationale: 3/12 + x/15 = 1
x= 11 1/4
ANSWER:B
Answer: B
Question: A furniture manufacturer has two machines, but only one can be used at a time. Machine F is utilized during the first shift and Machine B during the second shift, while both work half of the third shift. If Machine F can do the job in 12 days working two shifts and Machine B can do the job in 15 days working two shifts, how many days will it take to do the job with the current work schedule?
Options:
A)14
B)13
C)11
D)9
E)7
Rationale: 'Approximately' could actually make such a question ambiguous. Not this one though but a similar question with the answer as 9.2 days. You round off 8.89 days as 9 days and everything is fine in this question. What do you do when you get 9.2 days? Do you need 9 days or 10 days? Can you round off 9.2 as 9 even though that is what you do with numbers? No, because in 9 days your work is not over. You do need 10 days.
To finish a work say Machine F you need to work full 9 days and a part of the 10th day. If I ask you how many days do you need to complete the work, will you say 9 or 10? You will say 10 even if you don't use the 10th day fully=D
Answer: D
Question: There are 30 children in a classroom, each student will get 1 dozen pencils and 2 dozen erasers, there are 6 teachers. how many pencils will each teacher have to give out to each student?
Options:
A)6
B)4
C)3
D)2
E)5
Rationale: Each student is supposed to get 12 pencils and there are 6 teachers. 6 x 2 is 12. With each teacher giving out 2 pencils to each student, each student will then get 12 pencils like they are supposed to. The answer is D.
Answer: D
Question: In a certain pond, 50 fish were caught, tagged, and returned to the pond. A few days later, 50 fish were caught again, of which 2 were found to have been tagged. If the percent of tagged fish in the second catch approximates the percent of tagged fish in the pond, what is the approximate number of fish in the pond?
Options:
A)400
B)625
C)1,250
D)2,500
E)10,000
Rationale: total fish = x
percentage of second catch = (2/50)*100 = 4%
so, x * 4% = 50
x = 1250
ANSWER:C
Answer: C
Question: There are, in a certain league, 20 teams, and each team face another team for a total of 4 times. How many games are played in the season?
Options:
A)450
B)760
C)110
D)180
E)400
Rationale: By using the formula, t[n(n - 1) / 2], where t = no. of games between two teams and n = total no. of teams, we get: 760
Option B.
Answer: B
Question: The average price of 10 oranges is Rs. 12 while the average price of 8 of these oranges is Rs. 11.75. Of the remaining two oranges, if the price of one orange is 40% more than the price of the other, what is the price of each of these two oranges?
Options:
A)Rs 5, Rs 7.50
B)Rs 8, Rs 12
C)Rs 10, Rs 16
D)Rs 10.8, Rs 15.2
E)None of these
Rationale: Explanation :
Total price of the two oranges = Rs. [(12 x 10) (11.75 x 8)]
= Rs. (120 - 94) = Rs. 26.
Let the price of one orange be Rs. x.
Then, the price of other orange = Rs. (x + 40% of x) = Rs. x + x2/5 = Rs. 7x/5
So, x + 7x/5 = 26
12x = 130
x = 10.8
The prices of the two oranges are Rs. 10.8 and Rs. 15.2
Answer : D
Answer: D
Question: On a map, 2 inches represent 30 miles. How many miles approximately is the distance if you measured 38 centimeters assuming that 1-inch is 2.54 centimeters?
Options:
A)226
B)228
C)230
D)224
E)232
Rationale: 1 inch = 2.54 cm
2 inch = 2.54 * 2 cm
5.08 cm = 30 miles
38 cms = 30/5.08*38 = 224 miles
Answer : D
Answer: D
Question: A and B together have Rs. 1210. If 4/15 of A's amount is equal to 2/5 of B's amount, how much amount does B have?
Options:
A)Rs. 460
B)Rs. 484
C)Rs. 550
D)Rs. 664
E)Rs. 764
Rationale: Explanation:
4/15A=2/5B
A=(2/5X15/4)B
A/B=3/2
A:B=3:2
B's share = Rs.(1210X2/5)= Rs. 484.
ANSWER IS B
Answer: B
Question: A Sum at compound interest amounts to Rs.7500 in 2 years and to Rs.9000 in 3 years then rate per annum is
Options:
A)11%
B)12%
C)15%
D)20%
E)22%
Rationale: 1500/7500 *100=20%
ANSWER:D
Answer: D
Question: Four circular cardboard pieces, each of radius 7cm are placed in such a way that each piece touches two other pieces. The area of the space encosed by the four pieces is
Options:
A)12
B)32
C)42
D)52
E)58
Rationale: required area = 14*14 - (4 * 1/4 * 22/7 * 7 *7) sq cm
= 196 - 154 = 42 sq cm. Answer: C
Answer: C
Question: If the price of an article went up by 15%, then by what percent should it be brought down to bring it back to its original price?
Options:
A)17.39%
B)2/8%
C)2/1%
D)1/3%
E)2/7%
Rationale: Let the price of the article be Rs. 100.
15% of 100 = 15
New price = 100 + 15 = Rs. 115
Required percentage = (115 - 100)/115 * 100
= 20/115 * 100 = 17.39 %.
Answer:A
Answer: A
Question: What percent of 17 is 17 percent of 1?
Options:
A) 0.001
B) 0.01
C) 0.1
D) 14
E) 1
Rationale: 17 % of 1 = (17/100) * 1 = 17/100
To determine what percentage of 17 this is :
[17][/100*17] *100 = 1%
Ans : E
Answer: E
Question: Find k if 24 / k = 4.
Options:
A)6
B)7
C)8
D)4
E)3
Rationale: Since 24 /k = 4 and 24/ 6 = 4, then
k = 6 correct answer A
Answer: A
Question: Average of first five multiples of 3 is
Options:
A)9
B)11
C)13
D)15
E)16
Rationale: Explanation:
Average=3(1+2+3+4+5)5=455=
Answer: Option A
Answer: A
Question: Find a sum for 1st 4 prime number's?
Options:
A)25
B)17
C)30
D)34
E)36
Rationale: Required sum = (2 + 3 + 5 + 7 ) = 17
Note: 1 is not a prime number
Option B
Answer: B
Question: The speed at which a man can row a boat in still water is 15 kmph. If he rows downstream, where the speed of current is 3 kmph, what time will he take to cover 60 metres?
Options:
A)18
B)17
C)17
D)12
E)13
Rationale: Speed of the boat downstream = 15 + 3 = 18 kmph
= 18 * 5/18 = 5 m/s
Hence time taken to cover 60 m = 60/5 = 12 seconds.
Answer: D
Answer: D
Question: The population of a city increases by 7% per year but due to migration it decrease by 1% per years. What will be the percentage increase in population in 3 years?
Options:
A)9%
B)9.10%
C)27%
D)12%
E)None of these
Rationale: Actual increase in population=6%
Let, earlier population=100 then the population after 3 years
=100(1+6/100)^3=119.1016
∴Required percentage=9.1016%
ANSWER:B
Answer: B
Question: A baker makes chocolate cookies and peanut cookies. His recipes allow him to make chocolate cookie in batches of 5 and peanut cookies in batches of 6. If he makes exactly 94 cookies, what is the minimum number of chocolate chip cookies he makes?
Options:
A)7
B)14
C)21
D)28
E)40
Rationale: 5C+6P=94
We need to maximize P to minimize C so that the eq is also satisfied
Try substitution for CP to solve so that eqn is satisfied
The least value of C for which equation gets satisfied is 5
i.e. 5*8+6*9=40+54=94
Hence E is the answer
Answer: E
Question: A bag contains 9 wool scarves, exactly one of which is red and exactly one of which is green. If Deborah reaches in and draws three scarves, simultaneously and at random, what is the probability that she selects the red scarf but not the green scarf?
Options:
A)1/4
B)2/9
C)3/11
D)4/19
E)5/26
Rationale: Total possible ways to choose three scarves is 9C3 = 84
We need to choose the red scarf and two of 7 other scarves (not the green scarf).
The number of successful possibilities is 7C2 = 21
P(red scarf but not green scarf) = 21/84 = 1/4
The answer is A.
Answer: A
Question: A car takes 6 hours to cover a distance of 540 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time?
Options:
A)50 Kmph
B)45 Kmph
C)54 Kmph
D)56 Kmph
E)60 Kmph
Rationale: Time = 6
Distence = 540
3/2 of 6 hours = 6 * 3/2 = 9 Hours
Required speed = 540/9 = 60 Kmph
E
Answer: E
Question: 4 Women & 6 men have to be seated in a row given that no two women can sit together. How many different arrangements are there.
Options:
A)6! x 7P4
B)6! x 9P4
C)6! x 5P4
D)6! x 3P4
E)6! x 2P4
Rationale: Let us first sit all the 6 men in 6 positions in 6! ways. Now there are 7 gaps between them in which 4 women can sit in 7P47P4 ways.
So total ways are 6! x 7P4
Answer:A
Answer: A
Question: n the youth summer village there are 150 people, 75 of them are not working, 50 of them have families and 100 of them like to sing in the shower. What is the largest possible number of people in the village, which are working, that don't have families and that are singing in the shower?
Options:
A)25.
B)50.
C)75
D)100
E)150
Rationale: total =150
not working =75
having family=50
like to sing in shower = 100
working=150-75=75
not having family = 150-50=100
like to sing in shower = 100
largest possible number is the lowest possible among the above
ANSWER:C
Answer: C
Question: A metallic sheet is of rectangular shape with dimensions 46 m x 36 m. From each of its corners, a square is cut off so as to make an open box. If the length of the square is 8 m, the volume of the box (in m3) is:
Options:
A)4830
B)5120
C)6420
D)4800
E)8960
Rationale: l = (46 - 16)m = 30 m,
b = (36 -16)m = 20 m,
h = 8 m.
Volume of the box = (30 x 20 x 8) m3 = 4800 m3.
Answer: Option D
Answer: D
Question: A and B started a partnership business investing some amount in the ratio of 3 : 5. C joined then after six months with an amount equal to that of B. In what proportion should the profit at the end of one year be distributed among A, B and C?
Options:
A)3 : 5 : 2
B)3 : 5 : 5
C)6 : 10 : 5
D)6 : 11 : 2
E)Data inadequate
Rationale: Let the initial investments of A and B be 3x and 5x.
A : B : C = (3x x 12) : (5x x 12) : (5x x 6) = 36 : 60 : 30 = 6 : 10 : 5.
Answer:C
Answer: C
Question: Truck X is 13 miles ahead of Truck Y, which is traveling the same direction along the same route as Truck X. If Truck X is traveling at an average speed of 47 miles per hour and Truck Y is traveling at an average speed of 53 miles per hour, how long will it take Truck Y to overtake and drive 5 miles ahead of Truck X?
Options:
A)2 hours
B)2 hours 20 minutes
C)2 hours 30 minutes
D)2 hours 45 minutes
E)3 hours
Rationale: Relative speed = 53-47 = 6 miles per hour
Dist required = 13+5 = 18 miles
Time taken to overtake = 18/6 = 3 hours.
E is the answer.
Answer: E
Question: The G.C.D. of 1.08, 0.36 and 0.6 is?
Options:
A)0.03
B)0.9
C)0.18
D)0.12
E)none of these
Rationale: Given numbers are 1.08,0.36 and 0.60.
H.C.F of 108, 36 and 60 is 12
H.C.F of given numbers=0.12.
Correct Options:D
Answer: D
Question: Statement : A man must be wise to be a good wrangler. Good wranglers are talkative and boring.
Conclusions :
I. All the wise persons are boring.
II. All the wise persons are wranglers.
Options:
A)Only conclusion I follows
B)Only conclusion II follows
C)Either I or II follows
D)Neither I nor II follows
E)Both I and II follow
Rationale: Explanation:
Neither I nor II follows.
D)
Answer: D