divelab/Sys2Bench huggingface dataset:
Question: In how many ways can a teacher write an answer key for a mini-quiz that contains 3 true-false questions followed by 2 multiples-choice questions with 4 answer choices each, if the correct answers to all true-false questions cannot be the same?
Options:
A)88
B)90
C)96
D)98
E)102
Rationale: 2 multiples-choice questions can be answered in = 4 x 4 = 16 ways
3 true-false questions can be answered in = 2x2x2 = 8 ways
But out of the 8 ways, 2 ways [(True-True-True) (False-False-False)]will contain same answers
Thus 3 true-false questions can be answered in = 2x2x2 = 6 ways
Total ways to answer the quiz = 16 x 6 = 96
Answer C
Answer: C
Question: Helen went to the stationers and bought things worth Euro 25, out of which 30 paise went on sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax free items?
Options:
A)Euro 16.70
B)Euro 15.70
C)Euro 13.70
D)Euro 18.70
E)Euro 19.70
Rationale: E
Euro 19.70
Let the amount taxable purchases be Euro x.
Then, 6% of x = 30/100
x = (30/100 x 100/6) = 5.
Cost of tax free items = Euro [25 - (5 + 0.30)] = Euro 19.70
Answer: E
Question: Complete the series
1,-3, -7, -11, -15, -19... ...
Options:
A)-4
B)0
C)3
D)-2
E)-23
Rationale: In the above series clearly we know we can get the next term by subtract 4 from the previous term so the answer is Option E) -23
Answer: E
Question: Of the 3,600 employees of Company X, 1/3 are clerical. If the clerical staff were to be reduced by 1/3, what percent of the total number of the remaining employees would then be clerical?
Options:
A)25%
B)22.2%
C)20%
D)12.5%
E)11.1%
Rationale: Let's see, the way I did it was
1/3 are clerical out of 3600 so 1200 are clerical
1200 reduced by 1/3 is 1200*1/3
so it reduced 400 people , so there is 800 clerical people left
but since 400 people left, it also reduced from the total of 3600 so there are 3200 people total
since 800 clerical left / 3200 people total
you get (A) 25%
Answer: A
Question: If x and y are odd integers, which of the following must always be a non-integer
Options:
A)xy
B)y/x
C)x/y
D)-x^2y
E)xy/4
Rationale: as X and Y are odd, multiplication of x and y would result in odd integer
(Odd Integer)/2 will always be non integer
E
Answer: E
Question: A shopkeeper sells 20% of his stock at 10% profit ans sells the remaining at a loss of 5%. He incurred an overall loss of Rs. 250. Find the total worth of the stock?
Options:
A)12500
B)20000
C)20289
D)20027
E)20026
Rationale: Let the total worth of the stock be Rs. x.
The SP of 20% of the stock = 1/5 * x * 1.1 = 11x/50
The SP of 80% of the stock = 4/5 * x * 0.95 = 19x/25 = 38x/50
Total SP = 11x/50 + 38x/50 = 49x/50
Overall loss = x - 49x/50 = x/50
x/50 = 250 => x = 12500
Answer: A
Answer: A
Question: |-2| (|-25|-|5|)= ??
Source: Preparation Material MBA Center
Options:
A)40
B)–60
C)60
D)75
E)100
Rationale: Absolute value will turn negatives into their positive 'equivalents', and will leave positives unchanged, so |-2| = 2, |-25| = 25, and |5| = 5. Getting rid of our absolute values we have:
|-2| (|-25|-|5|) = (2) (25 - 5) = 2*20 = 40
Answer: A
Question: What is the minimum number of square marbles required to tile a floor of length 3 metres 39 cm and width 1 metres 13 cm?
Options:
A)176
B)187
C)540
D)748
E)3
Rationale: The marbles used to tile the floor are square marbles.
Therefore, the length of the marble=width of the marble.the length of the marble=width of the marble.
As we have to use whole number of marbles, the side of the square should a factor of both 3 m 39 cm and 1m 13. And it should be the highest factor of 3 m 39 cm and 1m 13.
3 m 39 cm = 339 cm and 1 m 13 cm = 113 cm.
The HCF of 339 and 113 = 113.
Hence, the side of the square is 113.
The number of such square marbles required,
=339×113/113×113
=3 marbles
Option(E)
Answer: E
Question: complete the numerical series with the correct number
5+3+3=151527
9+2+4=183652
8+6+5=484082
5+4+6=203046
9+5+4= ?
Options:
A)453676
B)454586
C)454585
D)454386
E)444586
Rationale: 9+5+4= 453676
Answer : A
Answer: A
Question: An analysis of the monthly incentives received by 5 salesmen : The mean and median of the incentives is $7000. The only mode among the observations is $12,000. Incentives paid to each salesman were in full thousands. What is the difference X between the highest and the lowest incentive received by the 5 salesmen in the month?
Options:
A)$4000
B)$5000
C)$9000
D)$11,000
E)$13,000
Rationale: Break down the question in to steps:
Step #1: incentives received by 5 salesmen -->abcde
Step #2: mean and median of the incentives is $7000: via number properties --> total incentives = 7,000 * 5 = 35, 000ab7,000de
Step #3: only mode among the observations is $12,000: mode is the value that appears most often in a set of data. Therefore 12,000 must occur more then once and since 12,000 is larger than the mean (7,000) the most it can occur is twice in our list. If we place the numbers in ascending order we haveab7,00012,00012,000
Step #4: What is the difference between the highest and the lowest incentive:
- The total paid has to equal mean * # of numbers = 7,000 * 5 = 35 000.
- The three values we have so far (12,000 12,000 and 7, 000) equal 31,000.
- Therefore the first two numbers( ab) must equal 4, 000
- There is only one mode which is 12,000, therefore 4,000 must be equal to a set of two numbers that are not the and a < b
if a = 1,000 b = 3,000 --> difference X between the highest and the lowest incentive = 12,000 - 1,000 =11, 000
no other options for a or b to fit the criteria
Final List:1,0003,0007,00012,00012,000
Answer D
Answer: D
Question: The rates of simple interest in two banks A and B are in the ratio 5 : 4. A person wants to deposit his total savings in two banks in such a way that he received equal half-yearly interest from both. He should deposit the savings in banks A and B in the ratio.
Options:
A)2 : 5
B)4 : 5
C)5 : 2
D)5 : 4
E)None of these
Rationale: Let the savings be X and Y and the rates of simple interest be 5x and 4x respectively.
Then, X × 5x × 1⁄2 × 1⁄100 = Y × 4x × 1⁄2 × 1⁄100 or X⁄Y = 4⁄5
i.e., X : Y = 4 : 5.
Answer B
Answer: B
Question: Revenues were recorded for Store A and Store B over a period of three months. In the first month, Store A's revenues were $60,000 higher than Store B's revenues. In the second month, Store A's revenues were $9,000 higher than Store B's revenues. If Store A's average (arithmetic mean) monthly revenue for the three months was $4,000 greater than Store B's average monthly revenue, then Store B's revenue in the third month was how much greater than Store A's revenue?
Options:
A) $14,000
B) $15,000
C) $42,000
D) $46,000
E) $57,000
Rationale: Answer: CIt may be tempting to come up with a lot of variables, one each for each month's revenue for each company. However, focus on the differences. In the first month, the difference was +60 in favor of A. (Note that we can drop the thousands since every number in the question is in terms of thousands.) In the second, the difference was +9 in favor of A. The average was +4 in favor of A. With these numbers, use the average formula to find the third month (T):
(60 + 9 + T)/3 = 4
69 + T = 12
T = -57
Since positive numbers indicate a difference in favor of A, negative numbers are in favor of B. -57 represents a $57,000 advantage in favor of Store B. Choice (E) is correct.
Answer: E
Question: 81,162,49,98,25,50,56
Options:
A)112
B)127
C)129
D)128
E)131
Rationale: 81*2=162
49*2=98
25*2=50
56*2=112
ANSWER:A
Answer: A
Question: A 2member committee comprising of one male & one female member is to be constitute out of 5 males and 3females. Among st the females. Ms.A refuses to be a member of the committee in which Mr.B is taken as the member. In how many different ways can the committee be constituted ?
Options:
A)12
B)14
C)12
D)17
E)20
Rationale: 5C1 * 3C1 -1
= 15-1
= 14
B
Answer: B
Question: By selling a house for Rs.45000, it was found that 1/8 of the outlay was gained, what ought the selling to price to have been in order to have lost 5 p.c?
Options:
A)28000
B)29000
C)38000
D)40000
E)42000
Rationale: CP + CP/8 = 45000
CP = 40000
SP = 40000*(95/100) = 38000
C
Answer: C
Question: Suppose 7 students are staying in a hall in a hostel and they are allotted 7 beds. Among them, Parvin does not want a bed next to Anju because Anju snores. Then, in how many ways can you allot the beds?
Options:
A)2399
B)2887
C)3600
D)2882
E)2791
Rationale: Explanation:
Let the beds be numbered 1 to 7.Case 1 : Suppose Anju is allotted bed number 1.
Then, Parvin cannot be allotted bed number 2.
So Parvin can be allotted a bed in 5 ways.
After alloting a bed to Parvin, the remaining 5 students can be allotted beds in 5! ways.
So, in this case the beds can be allotted in 5´5!ways = 600 ways.
Case 2 : Anju is allotted bed number 7.
Then, Parvin cannot be allotted bed number 6
As in Case 1, the beds can be allotted in 600 ways.
Case 3 : Anju is allotted one of the beds numbered 2,3,4,5 or 6.
Parvin cannot be allotted the beds on the right hand side and left hand side of Anju’s bed. For example, if Anju is allotted bed number 2, beds numbered 1 or 3 cannot be allotted to Parvin.
Therefore, Parvin can be allotted a bed in 4 ways in all these cases.
After allotting a bed to Parvin, the other 5 can be allotted a bed in 5! ways.
Therefore, in each of these cases, the beds can be allotted in 4´ 5! = 480 ways.
The beds can be allotted in (2x 600 + 5 x 480)ways = (1200 + 2400)ways = 3600 ways
Answer: C) 3600
Answer: C
Question: A man covers a certain distance F in a train. If the train moved 4km/hr faster, it would take 30 min less. If it moved 2km/hr slower, it would take 20 mins more. Find the distance?
Options:
A)200 km
B)50 km
C)20 km
D)60 km
E)80 km
Rationale: Not really. When you solve the 2 equation above, you get,
6T-4/3 = 5R/6 from simplifying equation 1
4T-2=R/2 from simplifying equation 2
You can now multiply equation 2 by 5 to get
5(4T-2=R/2 ) = 20T-10=5R/2 and then subtract this new equation from equation 1 to get T=3, followed by R=20 to give you distance F= R*T=20*3=60 km.D
Answer: D
Question: Find the compound interest on $50000 in 2years at 4% per annum, the interest being compounded half-yearly?
Options:
A)$645.56
B)$4121.60
C)$954.26
D)$745.69
E)$1020.45
Rationale: Principle = $50000
Rate = 2% half yearly = 4 half years
Amount = 50000*(1 + 2/100)^4 = 50000 * 51/50 * 51/50 * 51/50 * 51/50
= $54121.60
C.I. = 54121.60-50000 = $4121.60
Answer is B
Answer: B
Question: Rajesh can finish 1/5 of his home work in 30 minutes. Seema can finish 3/7 of
her homework in one hour and Ramya can finish 3/4 of her homework in
two and a half hours. If all of them start their home work at 12.00 PM and can
go to play as soon as they all finish their homework. When can they start to
play, if they take a break at 3.00 PM for 30 minutes?
Options:
A)4:30pm
B)5:30pm
C)6:30pm
D)4:00pm
E)3:50pm
Rationale: rajesh can finish his work in 2.5 hr,
ramya can finish her work in 2.4 hr
seema can finish in 3.3 hr
so 3:50 pm they can go to play
ANSWER:E
Answer: E
Question: The perimeter of a semi circle is 162 cm then the radius is?
Options:
A)31.5
B)28
C)98
D)37
E)13
Rationale: 36/7 r = 162
=> r
= 31.5
Answer: A
Answer: A
Question: A train covers a distance of 12 km in 10 minutes. If it takes 9 seconds to pass a telegraph post, then the length of the train is
Options:
A)100m
B)120m
C)140m
D)160m
E)180cm
Rationale: Explanation:
Speed =12/10x 60 km/hr = 72 x5/18m/sec = 20 m/sec.
Length of the train = (Speed x Time) = (20 x 9) m = 180 m
Answer: Option E
Answer: E
Question: By selling 32 cucumber in a dollar, a man loses 40%. How many cucumber must he sell in a dollar to gain 20% profit?
Options:
A)16
B)18
C)20
D)25
E)28
Rationale: This is a question that is much easier than it first appears. If you work with the percents directly, you can solve it very quickly. If the man sells 32 cucumber for a dollar, he loses 40%. That means he is at 60% of his cost (100% - 40% = 60%). We are trying to figure out how many cucumber he has to sell in order to make a 20% profit, or be at 120% (100% + 20% = 120%). 120% is double 60%, meaning that we simply cut the number of cucumber in half to double our returns (from 60% to 120%), yielding 32/2 = 16 cucumber, or answer choice A.
Answer: A
Question: One pump drains one-half of a pond in 5 hours, and then a second pump starts draining the pond. The two pumps working together finish emptying the pond in one-half hour. How long would it take the second pump to drain the pond if it had to do the job alone?
Options:
A)1 hour
B)1.2 hour
C)3 hours
D)5 hours
E)1.1 hours
Rationale: The tricky part here, I believed is one half hour = 1/2. Then everything would be easy.
We have the 1st pump working rate/hour = 1/2 : 5 = 1/10
Working rate of 2 pumps: 1/2 : 1/2 = 1.
Working rate of 2nd pump: 1 -1/10 = 9/10 --> Time taken for the 2nd pump to finish: 1 : 9/10 = 10/9 = 1.1 hours.
E
Answer: E
Question: V is the volume of a cylinder; the radius of the cylinder is 3.4. The height of the cylinder is 450% more than the radius. Which of the following is true?
Options:
A)700 < V < 900
B)300 < V < 500
C)500 < V < 700
D)100 < V < 300
E)900 < V < 1100
Rationale: As we see the answers are in form of range we can use approximation
Volume of cylinder is πr^2h
Given π= 22/7 and r = 3.4 so r^2 ~ 12 and h = 5.5 * 3.4 ~ 19
So 22/7 * 12 * 19 ~ 717
so answer should be
A. 700 < V < 900
Answer : A
Answer: A
Question: Two pipes A and B can fill a tank in 8 hours and 16 hours respectively. If both pipes are opened simultaneously, how much time will be taken to fill the tank?
Options:
A)5 hours 20 min
B)5 hours 49 min
C)3 hours 50 min
D)3 hours 22 min
E)3 hours 42 min
Rationale: Explanation:
Part filled by A in 1 hour = 1/8
Part filled by B in 1 hour = 1/16
Part filled by (A + B) in 1 hour = ( 1/8 + 1/16) = (3/16)
Time taken to fill the tank is (16/3) = 16/3*60 = 320 mins = 5 hrs 20 mins
ANSWER A
Answer: A
Question: Cost is expressed by the formula tb^4. If b is doubled, the new cost W is what percent of the original cost?
Options:
A)W=200
B)W=600
C)W=800
D)W=1600
E)W=50
Rationale: Original Cost W, C1=t1*b1^4
New Cost C2=t2*b2^4....only b is doubled so t2=t1 and b2=2b1
C2=t2*(2b1) ^4
=16(t1*b1^4)
=16C1
16 times C1=>1600% of C1
Ans D=1600
Answer: D
Question: Bob invested $3000 in fund A and $1000 in fund B. Over the next two years, the money in Fund A earned a total interest of 12 percent for the two years combined and the money in fund B earned 30 percent annual interest compounded annually. Two years after bob made these investments. Bob's investment in fund A was worth how much more than his investment in fund B?
Options:
A)1. $1500
B)2. $1550
C)3. $1600
D)4. $1670
E)5. $1700
Rationale: interest on fund A will be 360. rate of interest will be 6% per annum simple interest as 12% is for 2 year. this will make investment A 360 at the end of 2nd year.
interest on fund B will be 690 on 30% interest compounded annually. This will make investment B 1690 at the end of 2nd year.
Difference in investment A and investment B=3360-1690=1670
answer is D.
Answer: D
Question: A number is increased by 70 % and then decreased by 70 %. Find the net increase or decrease per cent.
Options:
A)49%
B)18%
C)17%
D)13%
E)16%
Rationale: Let the number be 100.
Increase in the number = 70 % = 70 % of 100
= (70/100 Ã— 100)
= 70
Therefore, increased number = 100 + 70 = 170
This number is decreased by 70 %
Therefore, decrease in number = 70 % of 170
= (70/100 Ã— 170)
= 11900/100
= 119
Therefore, new number = 170 - 119 = 51
Thus, net decreases = 100 - 51 = 49
Hence, net percentage decrease = (49/100 Ã— 100) %
= (4900/100) %
= 49 %
Answer:A
Answer: A
Question: Present age of a father is 3 years more than 3 times theage of his son. 3 years hence, father's age will be 10 years more than twice the age of the son. What is father's present age?
Options:
A)28
B)29
C)33
D)36
E)39
Rationale: Let the present age the son =x
Then, present age of the father =3x+3
Given that, three years hence, father's age will be 10 years more than twice the age of the son
⇒(3x+3+3)=2(x+3)+10⇒x=10
Father's present age
=3x+3=3×10+3=33
C
Answer: C
Question: If the average of 10,11,12,13,14,15,16,17,18 and x is 23, what is the value of x?
Options:
A)90
B)89
C)123
D)x=104
E)110
Rationale: Given (10+11+12+13+14+ 15+16+17+18+x)/10=23
126+x/10= 23
126+x=230
x=230-126
x=104
Answer is D
Answer: D
Question: If log5 x = 2, what is √x?
Options:
A)5
B)3√2
C)2√3
D)5√3
E)3√5
Rationale: E. Plug the values into the distance formula:
DISTANCE=√(x2-xi)2*square*+(y2-y1)2*square*=√(1-(-2)2*square*+(-2-4)2*square*
Simplify:
=√32*sq*+62*sq*=√9+36=√45=3√5
correct answer E)3√5
Answer: E
Question: A box contains 12 apples, 11 of which are red. An apple is drawn from the box and its color is noted before it is eaten. This is done a total of n times, and the probability that a red apple is drawn each time is less than 0.5. What is the smallest possible value of n?
Options:
A)3
B)4
C)5
D)6
E)7
Rationale: P(choosing a red apple 7 times in a row) = 11/12*10/11*9/10*8/9*7/8*6/7*5/6 = 5/12 < 0.5
The answer is E.
Answer: E
Question: If i equals the sum of the even integers from 2 to 224, inclusive, and k equals the sum of the even integers from 8 to 80, inclusive, what is the value of i - k?
Options:
A)11028
B)14172
C)14284
D)14015
E)14397
Rationale: Use following formulae for such problems:
Sum of evenly spaced integers = (# of integers)*(mean of integers)
# of integers = [(last - first)/2] + 1
Mean of integers = (last + first)/2
In above problem:
# of integers = [(224 - 2)/2] + 1= 112 and [(80-8)/2]+ 1 = 37
Mean of integers = (224 + 2)/2 = 113 and (80 + 8)/2 = 44
Sum of integers = (112*113) = 12656 and (37*44) = 1628
Thus their difference (i - k) = 12656 - 1628 = 11028
ANSWER:A
Answer: A
Question: A, B and C are entered into a partnership. A invested Rs.6500 for 6 months, B invested Rs.8400 for 5 months and C invested for Rs.10000 for 3 months. A is a working partner and gets 5% of the total profit for the same. Find the share of C in a total profit of Rs.7400.
Options:
A)1909
B)1900
C)1908
D)1901
E)1902
Rationale: 65 * 6 : 84 * 5 : 100 * 3
26:28:20
C share = 74000 * 95/100 = 7030 * 20/74 => 1900
Answer: B
Answer: B
Question: A can finish a piece of work in 5 days. B can do it in 10 days. They work together for two days and then A goes away. In how many days will B finish the work?
Options:
A)4 days
B)8 days
C)12 days
D)9 days
E)3 days
Rationale: 2/5 + (2 + x)/10
= 1 => x
= 4 days
Answer: A
Answer: A
Question: A palindrome is a number which reads the same when read forward as it it does when read backward. So, how many 5 digit palindromes are there?
Options:
A)720
B)800
C)890
D)900
E)950
Rationale: 5 digit palindrome would look like this : abcba.abcba.
Thus, the first digit can be filled in 9 ways(1-9), the second digit can be filled in 10 ways (0-9) and the 3rd digit can again be filled in 10 ways. The last 2 digits would just mirror the already selected digit. Thus, the no of ways : 9*10*10*1*1 = 900.
ANSWER:D.
Answer: D
Question: The side of a square is increased by 25% then how much % does its area increases?
Options:
A)56.75 %
B)56.25 %
C)56.75 %
D)57.25 %
E)56.22 %
Rationale: a = 100 a2 = 10000
a = 125 a2 = 15625
----------------
10000 --------- 5625
100 -------? => 56.25 %
Answer:B
Answer: B
Question: The cost of 3 kg of sugar is $15. What will the cost of 8 kg of sugar be?
Options:
A)20
B)40
C)80
D)160
E)180
Rationale: 3 kg costs $15
1 kg costs $5
8 kg costs $40
The answer is B.
Answer: B
Question: In how many different number of ways 10 boys and 3 girls can sit on a shopa which can accommodate 3 persons?
Options:
A)1800
B)1716
C)1617
D)2000
E)None
Rationale: Option 'B'
13p3 = 13x12x11= 1716
Answer: B
Question: Tough and Tricky questions: Combinations.
Three contestants representing four different countries advance to the finals of a fencing championship. Assuming all competitors have an equal chance of winning, how many possibilities are there with respect to how a first-place and second-place medal can be awarded?
Options:
A)6
B)9
C)12
D)16
E)24
Rationale: Four contestants representing four different countries advance to the finals of a fencing championship. Assuming all competitors have an equal chance of winning, how many possibilities are there with respect to how a first-place and second-place medal can be awarded?
We have 2 slots to be filled using 3 contestants:3 options for slot1*3 option for slot2
= 3* 3
= 9
Ans. B) 9
Answer: B
Question: Double of Quarter of 5 percent written as a decimal is :
Options:
A)0.003
B)0.0005
C)0.025
D)0.005
E)None of these
Rationale: Explanation :
Solution: (2)*(1/4)*5% = 0.025
Answer : C
Answer: C
Question: When positive integer k is divided by 5, the remainder is 2. When k is divided by 6, the remainder is 5. If k is less than 42, what is the remainder when k is divided by 7?
Options:
A)5
B)3
C)6
D)7
E)10
Rationale: Cant think of a straight approach but here is how I solved it:
K is divided by 5 and remainder is 2. This means k = 5n + 2 (n is an integer)
so the possible values of K = {2, 7, 12, 17, 22, 27, 32, 37} (less than 42)
Secondly, if K is divided by 6, the remainder is 5 => k= 6m + 5
so the possible value set for k = {5, 11, 17, 23, 29,35,41} (less than 42)
17 is the only common number in both the sets. Hence k = 17
Answer : B
Answer: B
Question: What number times (1⁄4)^2 will give the value of 4^3?
Options:
A)4
B)16
C)64
D)256
E)1024
Rationale: x*(1/4)^2 = 4^3
x = 4^2*4^3 = 4^5 = 1024
The answer is E.
Answer: E
Question: A dishonest dealer professes to sell goods at the cost price but uses a weight of 990 grams per kg, what is his percent?
Options:
A)1.01%
B)25%
C)22%
D)29%
E)45%
Rationale: 990 --- 10
100 --- ? => 1.01%
Answer:A
Answer: A
Question: 2/5 of the fish in an aquarium are red and 1/4 of the fish are brown. 1/2 of the red fish and 2/5 of the brown fish are male. If the rest of the fish in the aquarium are female, what is the probability that a fish randomly picked from the aquarium is male?
Options:
A)1/3
B)2/5
C)3/10
D)3/20
E)7/20
Rationale: 1/2*2/5 + 2/5*1/4 = 3/10
The answer is C.
Answer: C
Question: Five equal cubes, each of side 5 cm, are placed adjacent to each other. The volume of the new solid formed will be
Options:
A)125 cm3
B)625 cm3
C)15525cm3
D)1225cm3
E)None
Rationale: Solution
The new solid formed is a cuboid of length 25 cm, breadth 5 cm and height 5 cm
∴Volume = (25x5x5)cm3
‹=›625cm3
Answer B
Answer: B
Question: 7 men, 5 women and 8 children were given as assignment of distributing 2000 books to students in a school over a period of 3 days. All of them distributed books on the 1st day. One of the 2nd day 2 women and 3 children remained absent and on the 3rd day 3 men and 5 children remained absent. If the ratio of the no. of books distributed in a day by a man, a woman & a child was 5 : 4 : 2 respectively, a total of approximately how many books were distributed on the second day?
Options:
A)450
B)500
C)560
D)650
E)700
Rationale: Sol. Let the books distributed by man, a woman and a child be 5x, 4x and 2x respectively.
∴ No. of books distributed in 1st day
= 7×5x+5×4x+8×2x=71x
No. of books distributed in 1Ind day
=7×5x+3×4x+5×2x=57x
And no. of books distributed in IIIrd day
=4×5x+5×4x+3×2x=46x
71x + 57x + 46x = 2000, x = 2000/174
57x=2000/174×57=650
D
Answer: D
Question: What percent is 300 gm of 1 kg?
Options:
A)25%
B)40%
C)30%
D)8%
E)12%
Rationale: 1 kg = 1000 gm
300/1000 Ã— 100 = 30000/1000
=30 %
Answer is C
Answer: C
Question: Pipe A can fill a tank in 5 hr, pipe B in 10hr and pipe C in 30hr. If all the pipes are open in how many hours will tank be filled?
Options:
A)1hr
B)2hr
C)3hr
D)4hr
E)5hr
Rationale: Part filled by (A+B+C) in 1hour = 1/5 + 1/10 + 1/30 = 1/3
All the 3 pipes together will fill the tank in 3hours
Answer is C
Answer: C
Question: The average weight of a class of 24 students is 35 kg. if the weight of the teacher be included, the average rises by 400 g. the weight of the teacher is
Options:
A)45 kg
B)50 kg
C)53 kg
D)55 kg
E)None of these
Rationale: Solution
Weight of the teacher = (35.4 × 25 - 35 × 24) kg = 45 kg. Answer A
Answer: A