divelab/Sys2Bench huggingface dataset:
Question: A set of numbers has the property that for any number t in the set,t+3 is in the set. If -2 is in the set, which of the following must also be in the set? I. -3 II. 1 III. 4
Options:
A)I,III only
B)III only
C)II only
D)II,III only
E)I only
Rationale: question is asking for must be there elements.
According to the question if t is there t+3 must be there.
if -2 is the starting element the sequence is as follows.
S ={-2,1,4,7,10....}
if -2 is not the starting element the sequence is as follows
S = {...-5,-2,1,4,7,10...}
By observing the above two sequences we can say that 1,4 must be there in set S.
Answer : D
Answer: D
Question: If a:b = 2:3 and b:c = 4:3, then find a:b:c
Options:
A)8:12:9
B)2:3:8
C)2:3:9
D)2:3:12
E)None of these
Rationale: Explanation:
a:b=2:3
b:c=4:3=(4∗3/4:3∗3/4)
=3:9/4
a:b:c=2:3:9/4
=8:12:9
Option A
Answer: A
Question: If the L.C.M of two numbers is 660 and their product is 18480, find the H.C.F of the numbers.
Options:
A)50
B)30
C)125
D)25
E)None of these
Rationale: H.C.F = (Product of the numbers) / (Their L.C.M) = 18480/660 = 28.
ANSWER:E
Answer: E
Question: The current of a stream runs at the rate of 4 kmph. A boat goes 6 km and back to the starting point in 2 hours, then find the speed of the boat in still water?
Options:
A)4
B)5
C)8
D)9
E)6
Rationale: S = 4
M = x
DS = x + 4
US = x - 4
6/(x + 4) + 6/(x - 4) = 2
x = 8
Answer: C
Answer: C
Question: The average of 6 no.'s is 5.40. The average of 2 of them is 5.2, while the average of the other 2 is 5.80. What is the average of the remaining 2 no's?
Options:
A)5.2
B)2.6
C)3.6
D)4.5
E)4.6
Rationale: Sum of the remaining two numbers = (5.40 * 6) - [(5.2 * 2) + (5.8 * 2)]
= 32.40 - (10.4+ 11.6) = 32.40 - 22.0 = 10.40.
Required average = (10.4 / 2) = 5.2
Answer : A
Answer: A
Question: The simple Interest on a certain sum of money at the rate of 4% p.a. for 5 years is Rs. 1680. At what rate of interest the same amount of interest can be received on the same sum after 4 years ?
Options:
A)5%
B)6%
C)8%
D)4%
E)7%
Rationale: S.I. = 1680, R = 4% T = 5 years
Principal = (100 *1680)/ (5*4) = 8400
So P = 8400
Rate = (100 *1680)/ (8400 * 4) = 5%
ANSWER:A
Answer: A
Question: The average of first 20 prime numbers is?
Options:
A)9.5
B)8.6
C)9.3
D)9.6
E)9.8
Rationale: Explanation:
Average = (2+3+5+7+11+13+17+19/8 = 77/8= 9.6(Approx)
Answer is D
Answer: D
Question: At 1:00 PM, Train X departed from Station A on the road to Station B. At 1:30 PM, Train Y departed Station B on the same road for Station A. If Station A and Station B are p miles apart, Train X’s speed is r miles per hour, and Train Y’s speed is s miles per hour, how many hours after 1:40 PM, in terms of p, r, and s, do the two trains pass each other?
Options:
A)0.5 + (p - 0.5s)/(r + s)
B)(p - 0.5s)/(r + s)
C)0.5 + (p - 0.5r)/r
D)(p - 0.5r)/(r + s)
E)0.5 + (p - 0.5r)/(r + s)
Rationale: The distance A is going to cover between 1:00 and 1:30
= .5r
now the distance between the two trains = (p-.5r)
the relative velocity = (r-(-s)) = r+s
From 1:30, time is going to take when they meet = (p-.5r)/(r+s)
so the ans is .5+((p-.5r)/(r+s)) [.5 is added for the time from 1:00 to 1:30]
ans is C
Answer: C
Question: A work crew of 7 Men takes 10 days to complete one-half of a job. If 8 men are then added to the crew and the men continue to work at the same rate, how many days will it take the enlarged crew to do the rest of the job?
Options:
A)2
B)3
C)3 1/3
D)4
E)4 2/3
Rationale: Suppose 1 man can do work in X days..
so 7 men will do in ..
7/X=1/10*1/2 as half job is done
X=140
now 8 more are added then
15/140=1/2*1/d for remaining half job
d=4 2/3 Number of days
E
Answer: E
Question: If the annual interest on a principal is 25%, how many years before the amount is double?
Options:
A)2
B)3
C)7
D)4
E)5
Rationale: P = (P*25*R)/100
R = 4%
Answer: D
Answer: D
Question: A 10-by-4 inch piece of paper is used to form the lateral surface of a cylinder. If the entire piece of paper is used to make the lateral surface, which of the following must be true of the two possible cylinders that can be formed?
Options:
A)The volume of the cylinder with height 10 is 40/pi cubic inches greater than the volume of the cylinder with height 6.
B)The volume of the cylinder with height 4 is 40/pi cubic inches greater than the volume of the cylinder with height 10.
C)The volume of the cylinder with height 10 is 40pi cubic inches greater than the volume of the cylinder with height 6.
D)The volume of the cylinder with height 4 is 40pi cubic inches greater than the volume of the cylinder with height 10.
E)The volume of the cylinder with height 4 is 240/pi cubic inches greater than the volume of the cylinder with height 10.
Rationale: Pretty straightforward. Plug in the values to compute the volume of the cylinder. Keep in mind 4 and 10 are the circumference of the base and not the radius. B is the right answer.
Answer: B
Question: How many positive integers less than 300 are there such that they are multiples of 17 or multiples of 16?
Options:
A)31
B)32
C)33
D)34
E)35
Rationale: 300/17 = 17 (plus remainder) so there are 17 multiples of 17
300/16 = 18 (plus remainder) so there are 18 multiples of 16
We need to subtract 1 because 17*16 is a multiple of both so it was counted twice.
The total is 17+18-1 = 34
The answer is D.
Answer: D
Question: What is the unit’s digit of 7^8?
Options:
A)1
B)2
C)3
D)4
E)5
Rationale: 7^1=7
7^2=49
7^3=343
7^4=1(last digit)
7^5=7(last digit) and the cycle repeats after every 4 powers
Therefore, last digit of 7^8=1
Answer A
Answer: A
Question: A certain experimental mathematics program was tried out in 2 classes in each of 38 elementary schools and involved 44 teachers. Each of the classes had 1 teacher and each of the teachers taught at least 1, but not more than 3, of the classes. If the number of teachers who taught 3 classes is n, then the least and greatest possible values of n, respectively, are
Options:
A)0 and 13
B)0 and 14
C)0 and 16
D)1 and 9
E)2 and 8
Rationale: One may notice that greatest possible values differ in each answer choice in contrast to the least values, which repeat.
To find out the greatest value you should count the total classes (38*2=76), then subtract the total #of teachers since we know from the question that each teacher taught at least one class (76-44=32). Thus we get a number of the available extra-classes for teachers, and all that we need is just to count how many teachers could take 2 more classes, which is 32/2 = 16. So the greatest possible value of the # of teachers who had 3 classes is 16.
Only answer C has this option.
Answer: C
Question: A student traveled 25 percent of the distance of the trip alone, continued another 40 miles with a friend, and then finished the last half of the trip alone. How many miles long was the trip?
Options:
A)120
B)140
C)160
D)180
E)200
Rationale: Let x be the total length of the trip.
0.25x + 40 miles + 0.5x = x
40 miles = 0.25x
x = 160 miles
The answer is C.
Answer: C
Question: X alone can do a piece of work in 15 days and Y alone can do it in 10 days. X and Y undertook to do it for Rs. 720. With the help of Z they finished it in 5 days. How much is paid to Z?
Options:
A)Rs. 360
B)Rs. 120
C)Rs. 240
D)Rs. 300
E)None
Rationale: Solution:
In one day X can finish 1/15th of the work.
In one day Y can finish 1/10th of the work.
Let us say that in one day Z can finish 1/Zth of the work.
When all the three work together in one day they can finish 1/15 + 1/10 + 1/Z = 1/5th of the work.
Therefore, 1/Z = 1/30.
Ratio of their efficiencies = 1/15: 1/10: 1/30 = 2: 3: 1.Therefore Z receives 1/6th of the total money.
According to their efficiencies money is divided as 240: 360: 120.
Hence, the share of Z = Rs. 120.
Answer B
Answer: B
Question: What is the are of an equilateral triangle of side 8 cm?
Options:
A)11√3
B)12√3
C)16√3
D)15√3
E)18√3
Rationale: Area of an equilateral triangle = √3/4 S2
If S = 8, Area of triangle = √3/4 * 8 * 8
= 16√3 cm2;
Answer:C
Answer: C
Question: In the xy-plane, a triangle has vertices (0,0), (4,0) and (4,8). If a point (a,b) is selected at random from the triangular region, What is the probability that a-b>0?
Options:
A)1/5
B)1/3
C)1/2
D)2/3
E)4/5
Rationale: The area of the right triangle is (1/2)*4*8 = 16.
Only the points (a,b) below the line y=x satisfy a - b > 0.
The part of the triangle which is below the line y=x has an area of (1/2)(4)(4) = 8.
P(a - b > 0) = 8/16 = 1/2
The answer is C.
Answer: C
Question: If a trader sold two cars each at Rs. 325475 and gains 12% on the first and loses 12% on the second, then his profit or loss percent on the whole is?
Options:
A)1.44%
B)2.45%
C)7.44%
D)8.44%
E)2.44%
Rationale: Explanation:
SP of each car is Rs. 325475, he gains 12% on first car and losses 12% on second car.
In this case, there will be loss and percentage of loss is given by = [(profit%)(loss%)]/100 = (12)(12)/100 % = 1.44%
Answer: A
Answer: A
Question: There are three places P, Q and R such that 3 roads connects P and Q and 4 roads connects Q and R. In how many ways can one travel from P to R?
Options:
A)12
B)23
C)28
D)80
E)84
Rationale: The number of ways in which one can travel from P to R = 3 × 4 = 12
Answer is A
Answer: A
Question: If the average (arithmetic mean) of a and b is 40 and the average of b and c is 60, what is the value of c − a?
Options:
A)25
B)40
C)90
D)140
E)It cannot be determined from the information given.
Rationale: -(a + b = 80)
b + c=120
c-a=40
B. 40
Answer: B
Question: Calculate the L.C.M of 2/5, 4/ 7, 3/7, 6/13 is :
Options:
A)15
B)14
C)13
D)12
E)11
Rationale: Required L.C.M =L.C.M. of 2, 4, 3, 6/H.C.F. of 5, 7, 7, 13 =12/1=12
Answer is D
Answer: D
Question: A and B invests Rs.3000 and Rs.4000 respectively in a business. If A doubles his capital after 6 months. In what ratio should A and B divide that year's profit?
Options:
A)9:9
B)9:8
C)9:3
D)9:1
E)9:2
Rationale: (3*6 + 6*6): (4*12)
54:48 => 9:8
Answer: B
Answer: B
Question: Calculate the speed of a boat in still water (in km/hr) if in one hour, the boat goes at 13 km/hr downstream and 4 km/hr upstream.
Options:
A)4.5 kmph
B)9.5 kmph
C)7.5 kmph
D)8.5 kmph
E)5.5 kmph
Rationale: Speed in still water = (13 + 4)1/2 kmph = 8.5 kmph.
answer :D
Answer: D
Question: a number divided by 84 leaves remainder 57 what is the remainder when same number divided by 12
Options:
A)7
B)8
C)9
D)10
E)11
Rationale: add 84+57=141
now 141divided by 12 so we get 9 as reaminder
ANSWER:C
Answer: C
Question: Rajan borrowed Rs.4000 at 5% p.a compound interest. After 2 years, he repaid Rs.2210 and after 2 more year, the balance with interest. What was the total amount that he paid as interest?
Options:
A)635.5
B)635.57
C)635.51
D)635.59
E)635.54
Rationale: 4000
200 ---- I
200
10 ---- II
---------------
4410
2210
--------
2000
110 ---- III
110
5.50 ---- IV
-----------
2425.50
2210
-----------
4635.50
4000
----------
635.50
Answer:A
Answer: A
Question: A contractor undertakes to built a walls in 50 days. He employs 60 peoples for the same. However after 25 days he finds that only 40% of the work is complete. How many more man need to be employed to complete the work in time?
Options:
A)25
B)90
C)35
D)20
E)None of these
Rationale: 60 men complete 0.4 work in 25 days.
Applying the work rule, m1 × d1 × w2 = m2 × d2 × w1
we have,
60 × 25 × 0.6 = m2 × 25 × 0.4
or m2 = 60×25×0.6/25×0.4 = 90 men
AnswerB
Answer: B
Question: Fox jeans regularly sell for $15 a pair and Pony jeans regularly sell for $18 a pair. During a sale these regular unit prices are discounted at different rates so that a total of $3 is saved by purchasing 5 pairs of jeans: 3 pairs of Fox jeans and 2 pairs of Pony jeans. If the sum of the two discounts rates is 18 percent, what is the discount rate on Pony jeans?
Options:
A)9%
B)56.6%
C)11%
D)12%
E)15%
Rationale: You know that Fox jeans costs $15, and Pony jeans costs $18, you also know that 3 pairs of Fox jeans and 2 pairs of Pony jeans were purchased. So
3(15) = 45 - Fox
2(18) = 36 - Pony
The total discount discount is $3 and you are asked to find the percent discount of pony jeans,
so 45(18 - X)/100 + 36(X)/100 = 3 or 45*18 -45*x + 36*x =3*100 or 9x = -3*100 +45*18
x= 510/9 = 56.6%
B
Answer: B
Question: Find the compound ratio of (2:5), (6:11) and (11:2) is
Options:
A)3:2
B)2:1
C)1:2
D)6:5
E)2:3
Rationale: Required ratio = 2/5 * 6/11 * 11/2 = 2/1 = 6:5
Answer is D
Answer: D
Question: If two-third of a bucket is filled in 6 minute then the time taken to fill the bucket completely will be .
Options:
A)90 seconds
B)70 seconds
C)60 seconds
D)9 minutes
E)120 seconds
Rationale: 2/3 filled in 6 mint
1/3 filled in 3 mint
thn 2/3+1/3=6 + 3 = 9 minutes
ANSWER:D
Answer: D
Question: In a queue if 30 children were made to stand in a column, 16 columns could be formed. If 24 children were made to stand in a column, how many columns could be formed?
Options:
A)10
B)20
C)25
D)36
E)40
Rationale: Sol. Required number = 16 *^30 = 20
B
Answer: B
Question: A jogger running at 9 km/hr along side a railway track is 240 m ahead of the engine of a 120 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger?
Options:
A)88
B)27
C)36
D)88
E)12
Rationale: Speed of train relative to jogger = 45 - 9 = 36 km/hr.
= 36 * 5/18 = 10 m/sec.
Distance to be covered = 240 + 120 = 360 m.
Time taken = 360/10 = 36 sec.
Answer: C
Answer: C
Question: [(7 * 9) + (2 * 12) + 3]/[(12 * 3) + (81/9)] = ?
Options:
A)4
B)60
C)1.75
D)4.5
E)None of these
Rationale: Explanation:
[(7 * 9) + (2 * 12) + 3]/[(12 * 3) + (81/9)] = (63 + 24 + 3)/(36 + 9) = 90/45 = 2
ANSWER IS E
Answer: E
Question: Two family reunions are happening at the same hotel, the Dates reunion and the Hall reunion. All 50 guests at the hotel attend at least one of the reunions. If 50 people attend the Dates reunion and 60 people attend the Hall reunion, how many people attend both reunions?
Options:
A) 2
B) 5
C) 10
D) 16
E) 60
Rationale: No of people in Dates reunion=50
No of people in Hall reunion=60
Attending both=x
All guests attend at least one.
Therefore, 50=50+60-(Both)
Both=60
Answer E
Answer: E
Question: What will be the cost of building a fence around a square plot with area equal to 81 sq ft, if the price per foot of building the fence is Rs. 58?
Options:
A)2088
B)2882
C)2999
D)2667
E)2121
Rationale: Let the side of the square plot be a ft.
a2 = 81 => a = 9
Length of the fence = Perimeter of the plot = 4a = 36 ft.
Cost of building the fence = 36 * 58 = Rs. 2088.
Answer: A
Answer: A
Question: fill in ht blank:(a) the point with ___ (0,0) is called origin of a rectangular coordinate system,(b) to find the y-intercept of a line, we let ___ equal 0 and solve for ___; to find x- intercept , we let ____ equal 0 and solve for___
Options:
A)(a) the point with line (0,0) is called origin of a rectangular coordinate system, (b) to find the y-intercept of a line, we let x equal 0 and solve for y ; to find x- intercept , we let y equal 0 and solve for y
B)(a) the point with coordinates (0,0) is called origin of a rectangular coordinate system, (b) to find the y-intercept of a line, we let x equal 0 and solve for y ; to find x- intercept , we let y equal 0 and solve for x
C)(a) the point with axis (0,0) is called origin of a rectangular coordinate system, (b) to find the y-intercept of a line, we let z equal 0 and solve for x ; to find x- intercept , we let x equal 0 and solve for y
D)(a) the point with xyz (0,0) is called origin of a rectangular coordinate system, (b) to find the y-intercept of a line, we let x equal 0 and solve for y ; to find x- intercept , we let y equal 0 and solve for x
E)none of the above
Rationale: (a) the point with coordinates (0,0) is called origin of a rectangular coordinate system, (b) to find the y-intercept of a line, we let x equal 0 and solve for y ; to find x- intercept , we let y equal 0 and solve for xcorrect answer (B)
Answer: B
Question: Six years ago, the ratio of the ages of Kunal and Sagar was 6:5, Four years hence, the ratio of their ages will be 11:10. What is Sagar age at present
Options:
A)22
B)17
C)15
D)16
E)12
Rationale: Let six years ago the age of Kunal and Sagar are 6x and 5x resp.
then,
=>(6x+6)+4(5x+6)+4=1110
=>(6x+6)+4(5x+6)+4=1110
<=>10(6x+10)=11(5x+10)
<=>10(6x+10)=11(5x+10)
<=>5x=10=>x=2
<=>5x=10=>x=2
So Sagar age is (5x+6) = 16
Answer: D
Answer: D
Question: A can complete a project in 20 days and B can complete the same project in 20 days. If A and B start working on the project together and A quits 10 days before the project is completed, in how many days will the project be completed?
Options:
A)18 days
B)27 days
C)26.67 days
D)16 days
E)15 days
Rationale: Let X = the number of days taken to complete the project.
The amount of work done by A is (x-10) * (1/20).
The amount of work done by B is (x) * (1/30).
(1/20)*(x-10) + (1/20)*(x) = 1
(x/20) + (x/20) - (10/20) = 1
x/10 = 3/2
x = 15
Therefore, the answer is E: 15.
Answer: E
Question: The positive numbers w, x, y, and z are such that x is 40 percent greater than y, y is 20 percent greater than z, and w is 20 percent less than x. What percent greater than z is w ?
Options:
A)15.2%
B)16.0%
C)20.0%
D)23.2%
E)24.8%
Rationale: My strategy is same as theDobermanbut instead take z=100, which makes life a bit easy. As:
z=100
y=120 (20% greater than z)
z=144(20% greater than y)
Now calculate w 20% less than z = 144*80/100= 115.2
Now by just looking, relation between w and z:
w-z/z*100 = 23.2 - Answer D
Answer: D
Question: Ashok secured average of 72 marks in 6 subjects. If the average of marks in 5 subjects is 74, how many marks did he secure in the 6th subject?
Options:
A)62
B)74
C)78
D)80
E)None of these
Rationale: Explanation:
Number of subjects = 6
Average of marks in 6 subjects = 72
Therefore total marks in 6 subjects = 72 * 6 = 432
Now, No. of subjects = 5
Total marks in 5 subjects = 74 * 5 = 370
Therefore marks in 6th subject = 432 – 370 = 62
ANSWER A
Answer: A
Question: A cube has a volume of 64 cubic feet. If a similar cube is twice as long, twice as wide, and twice as high, then the volume, in cubic feet of such cube is?
Options:
A)24
B)48
C)64
D)80
E)512
Rationale: Volume = 64 = side^3
i.e. Side of Cube = 4
New Cube has dimensions 8, 8, and 8 as all sides are twice of teh side of first cube
Volume = 8*8*8 = 512 square feet
Answer: option E
Answer: E
Question: John traveled 80% of the way from Yellow-town to Green-fields by train at an average speed of 80 miles per hour. The rest of the way John traveled by car at an average speed of v miles per hour. If the average speed for the entire trip was 50 miles per hour, what is v in miles per hour?
Options:
A)20
B)40
C)50
D)55
E)70
Rationale: HiBunuel
THe question seems incorrect. it should not be 80% at the speed of 80. However if it's 20% at the speed of 80, Answer comes out 55.
The question is correct. Here's the explanation:
Let distance be D. We can find the total timeequate it, which comes as:
0.8D / 80 + 0.2D / v = D / 50 => v = 20 (Option A).
Answer: A
Question: If a person moves 15km straight and turns right and moves 15km straight then how much distance he needs to walk to reach starting point?
Options:
A)20.2
B)21.2
C)23.2
D)24.2
E)26.2
Rationale: person will move along right angled traingle whose smaller sides are 15 km
& 15 km
reqd distance= hypotenuse of triangle = √(15^2+15^2)= 15√2 = 21.2 km
ANSWER:B
Answer: B
Question: The profit earned by selling an article for $ 832 is equal to the loss incurred when the same article is sold for $ 448. What should be the sale price for making 30% profit?
Options:
A)$480
B)$450
C)$960
D)$832
E)$660
Rationale: Let C.P. = $ x.
Then, 832 - x = x - 448
2x = 1280 => x = 640
Required S.P. = 130% of $ 640 = $ 832.
D
Answer: D
Question: Tomeka is playing a dice game. If she rolls the same number on her second roll as she rolls on her first, she wins. Each roll is with two, fair, six-sided dice. If Tomeka rolled a seven on her first roll, what is the probability that she will win on her second roll?
Options:
A)1/4
B)1/5
C)1/6
D)1/9
E)1/12
Rationale: There are 6 ways to roll a seven: 1 and 6, 6 and 1, 2 and 5, 5 and 2, 3 and 4, 4 and 3.
There are 6*6=36 ways to roll two six-sided dice.
Thus the probability of winning by rolling a seven on the second roll given a seven on the first roll is 6/36 = 1/6
C
Answer: C
Question: 2/3rd of the boys and 3/4th of the girls of a school participate in a function. If the no.of participating students is 550, out of which 150 are girls, what is the total no.of students in the school?
Options:
A)300
B)400
C)800
D)900
E)1000
Rationale: Let total number of boys be x and total number of girls be y. y=400=>x = 600and^= I50=>y = 200 Now, x + y = 800
C
Answer: C
Question: If 8 persons meet at a reunion and each person shakes hands exactly once with each of the others, what is the total number of handshakes?
Options:
A)8 × 7 × 6 × 5 × 4 × 3 × 2 × 1
B)8 × 7 × 6 × 5 × 4 × 3 × 2 × 1
C)8 × 9
D)28
E)45
Rationale: 1st person will have 7 handshakes, 2nd will have 6, ....7th will have 1 and 8th will have 0
= 7+6+5+4+3+2+1 = 28
if we generalize this: if there are n people then there will be n(n-1)/2 handshakes.
Ans.D)
Answer: D
Question: If x and y are positive integers such that x/y = 6.8, which of the following numbers could be y?
Options:
A)1
B)3
C)2
D)6
E)10
Rationale: With the given information, we are trying to find the value of y.
To achieve this we must convert the given decimal to a fraction and reduce it to it's lowest integer form.
Take the decimal x/y = 6.8 and because it's in the tens decimal place, put the given value (x/y = 6.8/1) and multiply it by 10.
Take the resulting fraction (x/y = 68/10) and reduce it to it's lowest form.
Both of the numbers are divisible by 2.
The result is x/y = 34/5.
Thus y = 5.
The correct answer is C.
Answer: C
Question: If two dice are thrown together, the probability of getting an even number on one die and an odd number on the other is?
Options:
A)1/8
B)1/2
C)1/1
D)1/6
E)1/3
Rationale: The number of exhaustive outcomes is 36.
Let E be the event of getting an even number on one die and an odd number on the other. Let the event of getting either both even or both odd then = 18/36 = 1/2
P(E) = 1 - 1/2
= 1/2.
Answer:B
Answer: B
Question: A shopkeeper sells a TV set for 16560 at 10 % discount on its marked price and earns 15 % profit. If no discount is offered, then what will be his present per cent profit?
Options:
A)27 7⁄9
B)22 7⁄9
C)25 7⁄9
D)Data inadequate
E)None of these
Rationale: Original selling price of TV set
=16560×100/90 = 18400
Cost price of the TV = 16560×100/115 = 14400
at no discount, % profit will be
= (18400−14400)×100/14400 = 27 7/9
Answer A
Answer: A
Question: Old women said no of days of my grand daughter = no of months my daughters is?
And my age in no of years is= no of weeks of my grand daughter . sum of their ages is 115. Find d old women age?
Options:
A)71.7 years
B)72.7 years
C)73.7 years
D)74.7 years
E)75.7 years
Rationale: age of grand daughter is d days d/365 years
and age of daughter is d months d/12yrs
and age of old women is d/7 years
d/7 + d/12 + d/365 = 115years
4380d +2555d + 84d = 115*365*12*7
7019d = 3525900
d = 3525900/7019 = 502
age of old women is 502/7 =71.7 years
ANSWER:A
Answer: A
Question: The ratio by weight, measured in pounds, of books to clothes to electronics in a suitcase initially stands at 7:4:3. Someone removes 8 pounds of clothing from the suitcase, thereby doubling the ratio of books to clothes. How many pounds do the electronics in the suitcase weigh?
Options:
A)6
B)8
C)10
D)12
E)14
Rationale: The weights of the items in the suitcase are 7k, 4k, and 3k.
If removing 8 pounds of clothes doubles the ratio of books to clothes, then 8 pounds represents half the weight of the clothes.
2k = 8 pounds and then k = 4 pounds.
The electronics weigh 3(4) = 12 pounds.
The answer is D.
Answer: D
Question: 1, 0.5, 0.25, 0.125, 0.0625, ?
Options:
A)0.015625
B)0.03125
C)0.0078125
D)None of these
E)0.025874
Rationale: Explanation :
Divide by 2 to get the next term
Answer : Option B
Answer: B
Question: A and B can together complete a piece of work in 4 days. If A alone can complete the same work in 12
days, in how many days can B alone complete that work ?
Options:
A)4 days
B)5 days
C)6 days
D)7 days
E)None of these
Rationale: Explanation:
(A+B)'s 1 day work = 1/4
A's 1 day work = 1/12
B's 1 day work =
(14−112)=3−112=16
So B alone can complete the work in 6 days
Answer: C
Answer: C