divelab/Sys2Bench huggingface dataset:
Question: P works 25% more efficiently than Q and Q works 50% more efficiently than R. To complete a certain project, P alone takes 50 days less than Q alone. If, in this project P alone works for 60 days and then Q alone works for 130 days, in how many days can R alone complete the remaining work?
Options:
A)50 days
B)83.6 days
C)100 days
D)150 days
E)80 days
Rationale: P works 25% more efficiently than Q: Something that takes Q 5 days, takes P 4 days
Q works 50% more efficiently than R: Something that takes R 7.5 days, takes Q 5 days
P alone takes 50 days less than Q: For every 4 days P works, Q has to work an extra day. Hence P alone can do it in 200 days and Q alone in 250 days and hence R alone in 380 days
P works for 60 days--> 60/200 work done => 30%
Q works for 130 days--> 130/250 work done => 52%
22% work left ... R alone will take 22% * 380 = 83.6 days
Answer is (B)
Answer: B
Question: The MegaTek Corporation is displaying its distribution of employees by department in a circle graph. The size of each sector of the graph representing a department is proportional to the percentage of total employees in that department. If the section of the circle graph representing the manufacturing department takes up 54° of the circle, what percentage of MegaTek employees are in manufacturing?
Options:
A)15%
B)25%
C)30%
D)35%
E)72%
Rationale: ANSWER:A 54° divided by 360° equals 0.15, therefore the sector is equal to 15% of the total
Answer: A
Question: What will come in place of the x in the following Number series? 18, 22, X, 46 ,78, 142
Options:
A)35
B)56
C)30
D)87
E)98
Rationale: (C)
The pattern is +4, +8, +16, +32, +64
So the missing term is = 30
Answer: C
Question: Jamshid and Irwin decided to make up their own version of basketball. In addition to being able to score 2-point baskets, they created ways to score 5-, 11-, and 13-point baskets. If at halftime the product of the point values of Irwin’s baskets was 2,420, how many 11-point baskets Q did Irwin score?
Options:
A)0
B)1
C)2
D)3
E)4
Rationale: First thing I noticed was that all these numbers are prime...
Prime factorization gives the following
Step 1:2*1210
Step 2:2*11*110
Step 4:2*11*11*10
Step 5:2*11*11*2*5
So he scored Q= 2 11-point baskets in my opinion.
Answer C
Answer: C
Question: A batsman scored 80 runs which included 2 boundaries and 2 sixes. What percent of his total score did he make by running between the wickets?
Options:
A)45%
B)500/11
C)75%
D)55%
E)35%
Rationale: Explanation :
Number of runs made by running,
=>80−(2×4+2×6).
=>80−20
=>60
Hence, the required percentage is:-
=>60/80*100
=>75%
Answer : C
Answer: C
Question: The simple Interest on a certain sum of money at the rate of 4% p.a. for 5 years is Rs. 1680. At what rate of interest the same amount of interest can be received on the same sum after 4 years ?
Options:
A)5%
B)6%
C)7%
D)8%
E)9%
Rationale: S.I. = 1680, R = 4% T = 5 years
Principal = (100 *1680)/ (5*4) = 8400
So P = 8400
Rate = (100 *1680)/ (8400 * 4) = 5%
ANSWER:A
Answer: A
Question: If x-y=8, which of the following must be true?
I. If x is negative, y must be negative
II. If x is positive, y must be positive
III. Both x and y are positive
Options:
A)I only
B)II only
C)III only
D)I and II
E)II and III
Rationale: The best way to approach such questions is to plug in values for x and y
Given: x-y=8
III. Both x and y are positive:
Let x=10 and y=2
x-y=8
But,
Let x=6 and y=-2
x-y=8
Therefore, NOT TRUE
II. If x is positive, y must be positive
Let x=10 and y=2
x-y=8
But,
Let x = 6 and y=-2
x-y=8
Therefore, NOT TRUE
I. If x is negative, y must be negative
If x is negative, for the expression x-y=8 to be true, y must be a -ve number. Otherwise, the sum of two negative numbers will yield another negative number!
Therefore, TRUE
Ans: 'A'
Answer: A
Question: 4 people are sitting in a 4 seat row watching a football game. At halftime they all get up. When they return, they each randomly sit down on one of the 5 chairs. What is the likelihood that none of the 4 end up sitting in the same chair that they sat in during the first half?
Options:
A)3/24
B)3/4
C)15/24
D)18/24
E)21/24
Rationale: Originally seated A B C D
now when after they get up and when they sit back again .
1st- A has option to sit on 3 seats ( apart from his previous seat . thus he now sits on B's seat.)
2nd- Similarly B has option to sit on 3 seats ( because A has already occupied B's previous seat, thus B sits on a's seat.)
3rd- Now C has only 1 option to sit on D's seat . and similarly D also has one option to sit on C's seat.)
hence total favourable outcomes 3*3*2*1*1=18
and total possible outcomes =4!=24
probability of the favourable outcome= 3/4. B
Answer: B
Question: Find compound interest on Rs. 7500 at 4% per year for 2 years, compounded annually.
Options:
A)812
B)712
C)412
D)512
E)612
Rationale: Amount = Rs [7500*(1+(4/100)2] = Rs (7500 * (26/25) * (26/25)) = Rs. 8112.
therefore, Compound Interest = Rs. (8112 - 7500) = Rs. 612.
Answer is E.
Answer: E
Question: For any integer n greater than 1, n* denotes the product of all the integers from 1 to n, inclusive. How many prime numbers R are there between 6* + 2 and 6* + 6, inclusive?
Options:
A)None
B)One
C)Two
D)Three
E)Four
Rationale: Given that n* denotes the product of all the integers from 1 to n, inclusive so, 6*+2=6!+2 and 6*+6=6!+6.
Now, notice that we can factor out 2 our of 6!+2 so it cannot be a prime number, we can factor out 3 our of 6!+3 so it cannot be a prime number, we can factor out 4 our of 6!+4 so it cannot be a prime number, ... The same way for all numbers between 6*+2=6!+2 and 6*+6=6!+6, inclusive. Which means that there are no primes R in this range.
Answer: A.
Answer: A
Question: The simple interest on a sum of money will be Rs.800 after 10 years. If the principal is trebled after 5 years what will be the total interest at the end of the tenth year?
Options:
A)2261
B)1600
C)1200
D)2699
E)2771
Rationale: P --- 10 ---- 800
P --- 5 ----- 400
3P --- 5 ----- 1200
------
=> 1600
Answer: B
Answer: B
Question: If y is the smallest positive integer such that 630 multiplied by y is the square of an integer, then y must be
Options:
A)20
B)50
C)60
D)70
E)140
Rationale: 630 = 2*3^2*5*7
To be perfect square, we need to multiply by at least 2*5*7 = 70.
The answer is D.
Answer: D
Question: If 15 students in a class average 80% on an English exam and 10 students average 90% on the same exam, what is the average in percent for all 25 students?
Options:
A)83%
B)83 1⁄2%
C)84%
D)85%
E)86 2⁄3%
Rationale: The average percentage = (15 x 80% + 10 x 90%)/25
= (15 x 80% + 10x 80% + 10x10%) / 25 ......(as 90% = 10% + 80% )
=(25x80% + 10x10%)/25
= 80% + 10x10%/25
= 80% + 4%
= 84%
ANSWER:C
Answer: C
Question: A shopkeeper first raises the price of Jewellery by x% then he decreases the new price by x%. After such up down cycle, the price of a Jewellery decreased by Rs. 21025. After a second up down cycle the Jewellery was sold for Rs. 484416. What was the original price of the jewellery.2
Options:
A)Rs. 5,26,000
B)Rs. 6,00,625
C)Rs. 525625
D)Rs. 5,00,000
E)None of these
Rationale: Solution: Let the initial price = Rs. 10000P
price after first increment = 10000P + 100xP.
price after first decrement = 10000P + 100xP - (100Px+Px2) = 10000P - Px2.
Now, total decrement,
Px2 = 21025 .............. (1)
price after second increment,
10000P - Px2 + 100xP - Px3/100
price after second increment,
10000P - P2 + 100xP - P3/100 - 100xP + Px3/100 - Px2 + Px4/10000
= 10000P -2Px2+Px2/10000 = 484416 ............... (2)
on solving equation equn (1) and (2), We get
x = 20.
substituting back we get,
P = 52.5625
Therefore
Answer: Option C
Answer: C
Question: The average monthly income of A and B is Rs. 5050. The average monthly income of B and C is Rs. 6250 and the average monthly income of A and C is Rs. 5200. What is the monthly income of A?
Options:
A)1000
B)1500
C)2000
D)3000
E)4000
Rationale: Let monthly income of A = a
monthly income of B = b
monthly income of C = c
a + b = 2 × 5050 .... (Equation 1)
b + c = 2 × 6250 .... (Equation 2)
a + c = 2 × 5200 .... (Equation 3)
(Equation 1) + (Equation 3) - (Equation 2)
=> a + b + a + c - (b + c) = (2 × 5050) + (2 × 5200) - (2 × 6250)
=> 2a = 2(5050 + 5200 - 6250)
=> a = 4000
i.e., Monthly income of A = 4000
Answer is E.
Answer: E
Question: An ice cream store received shipments of ingredients on Tuesday and Wednesday. Tuesday's shipment had 6 different packages, with an average (arithmetic mean) of 9 and 2/3 pounds. Wednesday's shipment included 7 packages, weighing an average of 9 and 3/7 pounds. What was the average package weight, in pounds, of the shipments received on both days?
Options:
A)9 and 6/7 pounds
B)10 and 1/10 pounds
C)10 and 2/5 pounds
D)11 pounds
E)124/13 pounds
Rationale: Solution: Average weight = Total weight/number of packages. The total weight on Tuesday was 6 * (9 and 2/3 pounds), or 58 pounds. The total weight on Wednesday was 7 * (9 and 3/7 pounds), or 66 pounds. The sum of the weights for both days is 66 + 58, or 124 pounds. The average is 124 pounds/13 packages.
Correct answer: E
Answer: E
Question: If w/x = 2/3 and w/y = 6/15, then (x + y)/y =
Options:
A)4/5
B)6/5
C)7/5
D)8/5
E)9/5
Rationale: W/X = 2/3=>x=3/2w and W/Y = 6/15=>y=15/6w
(X+Y)/Y = (3/2w+15/6w)/15/6w = 4w/(15/6W) = 8/5
Correct Option: D
Answer: D
Question: How many unique positive odd integers less than 110 are equal to the product of a positive multiple of 5 and an odd number?
Options:
A)4
B)6
C)11
D)12
E)15
Rationale: The Question basically asks how many positive odd integers less than 110 are odd multiples of 5
So we have 5,15,25,35,45,.. and 105
=11
Ans C
Answer: C
Question: A cycle is bought for Rs.670 and sold for Rs.780, find the gain percent?
Options:
A)70%
B)20%
C)16%
D)19%
E)80%
Rationale: Explanation:
670 ---- 110
100 ---- ? => 16%
Answer: C
Answer: C
Question: John paid a sum of money for purchasing 30 pens, which he recovered in full when he sold 20 of them. What was his percentage of profit or loss per pen?
Options:
A)50%
B)60%
C)40%
D)30%
E)45%
Rationale: A
50%
If the sum he paid whilst purchasing 30 pens = A,
Then the Cost Price of each pen = A/30.
Since the amount he got whilst selling 20 pens is also = A
Then the Selling Price of each pen = A/20.
Since Selling Price > Cost Price, he made a profit.
Profit per pen = Selling Price - Cost Price = A/20 - A/30 = A/60.
Profit percentage per pen = Profit per pen / Cost per pen x 100 = (A/60) / (A/30) x 100 = 50%
Answer: A
Question: A swimmer can swim in still water at 4 km/h. If the speed of the water current is 2 km/h, how many hours will the swimmer take to swim against the current for 3 km?
Options:
A)1.5
B)1.75
C)2.0
D)2.25
E)2.5
Rationale: The swimmer can swim against the current at a speed of 4-2 = 2 km/h.
The time it will take is 3/2 = 1.5 hours.
The answer is A.
Answer: A
Question: Bradley owns b video game cartridges. If Bradley’s total is one-half the total owned by James and four times the total owned by Charlie, how many video game cartridges do the three of them own altogether, in terms of b?
Options:
A)(16/3)b
B)(17/4)b
C)(13/4)b
D)(19/12)b
E)(7/12)b
Rationale: b = Bradley’s total
2b = James’s total
(1/4)b = Charlie’s total
Add each total
b + 2b+ (1/4)b = 3b + (1/4)b = = (13/4b)
Answer : C
Answer: C
Question: If n is a prime number greater than 19, what is the remainder when n^2 is divided by 12 ?
Options:
A)0
B)1
C)2
D)3
E)5
Rationale: There are several algebraic ways to solve this question, but the easiest way is as follows:since we cannot have two correct answers just pick a prime greater than 19, square it and see what would be the remainder upon division of it by 12.
n=23 --> n^2=529 --> remainder upon division 529 by 12 is 1.
Answer: B.
Answer: B
Question: Four of the five parts numbered (a) ,(b) ,(c) (d) and (e) in the following equation are exactly equal. Which of the parts is not equal to the other four? The number of that part is the answer.
Options:
A)2a2 – ab + 3b2
B)(a – b)(2a – 3b) + 4ab
C)(a – b)2 + (a2 + ab + 2b2)
D)(a + b)2 + (a2 + 2b2 – 3ab)
E)(a + b)(a – b) + (2a2 – ab + 4b2)
Rationale: The other parts are equal to 34.
Answer E
Answer: E
Question: David obtained 76, 65, 82, 67 and 85 marks (out of 100) in English, Mathematics,Physics, Chemistry and Biology What are his average marks ?
Options:
A)75
B)37
C)26
D)97
E)27
Rationale: Average = (76 + 65 + 82 + 67 + 85 )/ 5 = 375/5
= 75.
Answer: A
Answer: A
Question: If 6th March, 2005 is Monday, what was the day of the week on 6th March, 2004?
Options:
A)Saturday
B)Sunday
C)Monday
D)Friday
E)Thursday
Rationale: The year 2004 is a leap year. So, it has 2 odd days.
But, Feb 2004 not included because we are calculating from March 2004 to March 2005.
So it has 1 odd day only.
The day on 6th March, 2005 will be 1 day beyond the day on 6th March, 2004.
Given that, 6th March, 2005 is Monday.
6th March, 2004 is Sunday (1 day before to 6th March, 2005).
Answer is B.
Answer: B
Question: Sum of two number is 50 & sum of three reciprocal is 1/12 so find these two numbers
Options:
A)30 & 29
B)30 & 26
C)30 & 24
D)30 & 22
E)30 & 20
Rationale: Sol : x+y = 50 .....(1) x=50-y ....(2)
1x+1y=1121x+1y=112 ⇒y+xxy=112⇒12(y+x)=xy⇒y+xxy=112⇒12(y+x)=xy ...(3)
put (2) in (4)
⇒⇒ 12(y+50-y)=(50-y)y
⇒⇒ 12y+600-12y=50y-y2y2
⇒⇒ y2y2-50y+600=0
⇒⇒ y2y2-30y-20y+600=0
⇒⇒ y(y-30)-20(y-30)=0
⇒⇒ (y-20) (y-30)=0
y=20 or y=30
if y=20 then x = 30
or y=30 then x = 20
two numbers are 30 & 20
Answer:E
Answer: E
Question: John is going with 7 friends on a trip to Paris for spring break. Airfare and hotel costs a total of $5600.00 for the group of 8 friends. How much does each person have to pay for their hotel and airfare?
Options:
A)$500
B)$600
C)$650
D)$680
E)$700
Rationale: Answer= E
The total cost of the trip ($5600.00) divided by 8 equals $700.00.
Answer: E
Question: A can do a piece of work in 6days, and B can do it in 5days. If C, who can do the work in 12days, joins them, how long will they take to complete the work?
Options:
A)2days
B)3.5days
C)2.2days
D)4days
E)5.7days
Rationale: A,B, and C do the work in = 6*5*12/6*5+5*12+6*12 = 360/162= 2.2 days
Answer is C
Answer: C
Question: A and B can finish a work in 16 days while A alone can do the same work in 24 days. In how many days B alone will complete the work?
Options:
A)35 days
B)48 days
C)64 days
D)24 days
E)36 days
Rationale: B
48 days
B = 1/16 – 1/24 = 1/48 => 48 days
Answer: B
Question: Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is?
Options:
A)22
B)287
C)48
D)277
E)21
Rationale: Relative speed = 60 + 90 = 150 km/hr.
= 150 * 5/18 = 125/3 m/sec.
Distance covered = 1.10 + 0.9 = 2 km = 2000 m.
Required time = 2000 * 3/125 = 48 sec.
Answer: C
Answer: C
Question: How many integers n are there such that 1< 5n +5 < 60?
Options:
A)5
B)7
C)11
D)13
E)12
Rationale: Solution:
1< 5n + 5 < 60 is a compound inequality. Compound inequalities often need to be manipulated, and we can use the rules of algebra that we already know, to do this. Just as with equations, whatever we do to one part of a compound inequality, we must do to all parts of the compound inequality. Let’s first isolate n within the inequality.
1< 5n + 5 < 60
We first subtract 5 from all three parts of the inequality, and we obtain:
-4 < 5n < 55
Next, we divide both sides of the inequality by 5 and we get:
-4/5 < n < 11
The integers that are greater than -4/5 and less than 4 are 0, 1, 2, and 3. Thus, there are 4 integers that satisfy the inequality 1 < 5n + 5 < 25.
The answer is C.
Answer: C
Question: A house wife saved $4 in buying an item on sale. If she spent $28 for the item, approximately how much percent she saved in the transaction?
Options:
A)8%
B)13%
C)10%
D)11%
E)12%
Rationale: Actual price = 28+4 = $32
Saving = 4/32 * 100 = 13% approximately
Answer is B
Answer: B
Question: From 6 positive numbers and 6 negative numbers, how many groups F of 4 numbers, yielding a positive product, can be formed?
Options:
A)720
B)625
C)30
D)960
E)255
Rationale: Potential combinations of 4 numbers that will yield positive product
++++ 4C6
---- 4C6
++-- 2C6*2C6
4C6 + 4C6 + 2C6*2C6
F=15 +15 + 15*15 = 255=E
Answer: E
Question: If the first and second letters in the word DEPRESSION' were interchanged, also the third and the fourth letters, the fifth and the sixth letters and so on, which of the following would be the seventh letter from the right ?
Options:
A)H
B)K
C)I
D)P
E)U
Rationale: Explanation:
The new letter sequence is EDRPSEISNO
The seventh letter from the right is P
Answer: D) P
Answer: D
Question: One fourth of one third of two fifth of a number is 17. What will be 40% of that number
Options:
A)140
B)204
C)180
D)200
E)250
Rationale: Explanation:
(1/4) * (1/3) * (2/5) * x = 17 then x = 17 * 30 = 510
40% of 510 = 204
Answer: Option B
Answer: B
Question: If p and q are positive integers and q ≠ 1, then pq(q −5) is
Options:
A)pq^2+5pq
B)pq^2+pq
C)pq^2-pq
D)pq^2-5pq
E)pq^2
Rationale: pq(q-5) = pq^2-5pq
Answer : D
Answer: D
Question: All the water in container A which was filled to its brim was poured into two containers B and C. The quantity of water in container B was 62.5% less than the capacity of container A. If 148 liters was now transferred from C to B, then both the containers would have equal quantities of water. What was the initial quantity of water in container A?
Options:
A)1184
B)1151
C)1126
D)1130
E)1254
Rationale: B has 62.5% or (5/8) of the water in A. Therefore, let the quantity of water in container A(initially) be 8k.
Quantity of water in B = 8k - 5k = 3k.
Quantity of water in container C = 8k - 3k = 5k
Container: A B C
Quantity of water: 8k 3k 5k
It is given that if 148 liters was transferred from container C to container B, then both the containers would have equal quantities of water.
5k - 148 = 3k + 148 => 2k = 296 => k = 148
The initial quantity of water in A = 8k = 8 * 148 = 1184 liters.
ANSWER A
Answer: A
Question: A car covers a distance of 840 km in 6 ½ hours. Find its speed?
Options:
A)104 kmph
B)187 kmph
C)164 kmph
D)140 kmph
E)106 kmph
Rationale: 840/6
= 140 kmph
Answer: D
Answer: D
Question: The diagonals of a rhombus are 14 cm and 20 cm. Find its area?
Options:
A)329
B)140
C)150
D)238
E)31
Rationale: 1/2 * 14 * 20 = 140
Answer: B
Answer: B
Question: If the average (arithmetic mean) of a list of numbers is 12 and the standard deviation of that list of numbers is 1.3, then which of the following numbers is more than two standard deviations from the mean?
I. 14.5
II. 15.3
III. 9.5
Options:
A)I only
B)I and II only
C)II only
D)III only
E)I and III only
Rationale: Mean = 12
SD = 1.3
2 SD above mean = 12+2*1.3 = 14.6
2 SD below mean = 12-2*1.3 = 9.4
14.5 and 9.5 lies in the range of 2SD from mean
Answer: Option C
Answer: C
Question: Drum X is 1/2 full of oil and drum Y, which has twice the capacity of drum X, is 1/5 full of oil. If all of the oil in drum X is poured into drum Y, then drum Y will be filled to what capacity?
Options:
A)3/10
B)7/10
C)9/10
D)9/20
E)13/20
Rationale: (1/2)X = (1/4)Y
(1/4)Y + (1/5)Y = (9/20)Y
The answer is D.
Answer: D
Question: A passenger sitting near the window in a train moving at 50 km/h, noticed that it took 3 sec. for the oncoming train to pass by. What was the speed of the oncoming train if the length of the oncoming train was 75 metres?
Options:
A)a)50km/h
B)b)52km/h
C)c)56km/h
D)d)60km/h
E)e)40km/h
Rationale: im getting A
3 secs to pass a 75 mts train , therefore speed = 25 meters/sec
to convert m/s to km/hrs multiply by 3.6
25*3.6 = 90
so its 90-50 = 40 .
E
Answer: E
Question: An unbiased die is tossed .find the probability of getting a multiple of 3
Options:
A)1/3
B)5/3
C)2/3
D)7/3
E)3/7
Rationale: . Here S={1,2,3,4,5,6}
Let E be the event of getting the multiple of 3
then ,E={3,6}
P(E)=n(E)/n(S)=2/6=1/3
Option: A
Answer: A
Question: 4, 6, 9, 13.50, 20.25, (...)
Options:
A)60
B)60.75
C)58
D)31.528
E)30.375
Rationale: 4
(4Ã—3)Ã· 2 = 6
(6Ã—3)Ã· 2 = 9
(9Ã—3)Ã· 2 = 13.50
(13.50Ã—3)Ã· 2 = 20.25
(40.5Ã—3)Ã· 2 = 30.375
Answer is E
Answer: E
Question: A money lender lends Rs.2000 for six months at 20% p.a. rate. It the interest is reckoned quarterly than find the amount given after time limit?
Options:
A)2205
B)8786
C)8275
D)2872
E)2282
Rationale: A = 2000(21/20)2 = 2205
Answer:A
Answer: A
Question: A man invested Rs. 1552 in a stock at 97 to obtain an income of Rs. 140. The dividend from the stock is :
Options:
A)7.5 %
B)8.75 %
C)9.7 %
D)None of these
E)Cannot be determined
Rationale: Solution
By investing Rs. 1552,income = Rs. 140.
By investing Rs. 97, income = Rs. (140/1552x97)= Rs.8.75
âˆ´ Dividend = 8.75%.
Answer B
Answer: B
Question: A train 100 m long crosses a platform 125 m long in 15 sec; find the speed of the train?
Options:
A)52 kmph
B)14 kmph
C)54 kmph
D)58 kmph
E)24 kmph
Rationale: D = 100 + 125 = 225
T = 15
S = 225/15 * 18/5 = 54 kmph
Answer: C
Answer: C
Question: A train passes a station platform in 36 sec and a man standing on the platform in 23 sec. If the speed of the train is 54 km/hr. What is the length of the platform?
Options:
A)767 m
B)240 m
C)195 m
D)176 m
E)186 m
Rationale: Speed = 54 * 5/18 = 15 m/sec.
Length of the train = 15 * 23 = 345 m.
Let the length of the platform be x m . Then,
(x + 345)/36 = 15 => x = 195 m.
Answer:C
Answer: C
Question: A jewelry store purchased a pair of earrings for $240 and was selling it at a price that equaled the purchase price of the earrings plus a markup that was 25 percent of the selling price. After some time a jewelry store owner decided to decrease the selling price by 20 percent. What was the jewelry store's gross profit on this sale?
Options:
A)$14
B)$2
C)$10
D)$16
E)$18
Rationale: Sale Price(SP) = 240 + Markup(MP)
--> Mp = SP-240
and given MP=SP/4 ( 25% is 1/4th)
so SP/4= SP-240
3SP/4= 240
SP=320
Now a discount of 20% is given so NEW SP is .8 *320 =256
Profit=256-240 =16
Answer is D
Answer: D
Question: The difference between a 8 digit number and the number formed by reversing its digit is not a multiple of
Options:
A)3
B)5
C)296297
D)888891
E)2666673
Rationale: Another approach is to TEST a number.
Let's say the original number is 12000002
So, the REVERSED number is 20000021
The DIFFERENCE = 20000021-12000002 = 8000019
No check the answer choices
8000019 is a multiple of 3,296297,888891,2666673
5 is NOT a multiple of 8000019
Answer ; B
Answer: B
Question: Nitin borrowed some money at the rate of 6% p.a. for the first three years,9% p.a. for the next five years and 13% p.a. for the period beyond eight years.If the total interest paid by him at the end of eleven years is Rs. 8160,how much money did he borrow ?
Options:
A)Rs. 8000
B)Rs. 10,000
C)Rs. 12,000
D)Data inadequate
E)None
Rationale: Solution
22.21
Let the sum be Rs. x.Then,
(X x6 x 3/100)+ (X x 9 x 5/100)+ (X x 13 x 3/100) 8160
18 x + 45x + 39x (8160x100)= 816000 x = 8000.
Answer A
Answer: A
Question: How many multiples of 4 are there between 20 and 196 ?
Options:
A)45
B)42
C)52
D)43
E)51
Rationale: It should be mentioned whether 20 and 196 are inclusive.
If 20 and 196 are inclusive, then the answer is (196-20)/4+1=45.
If 20 and 196 are NOT inclusive, then the answer is (192-24)/4+1=43.
Since OA is D, then we have NOT inclusive case.
Answer: D
Question: A bag contains five white and four red balls. Two balls are picked at random from the bag. What is the probability that they both are different color?
Options:
A)5/8
B)5/9
C)5/6
D)5/3
E)5/1
Rationale: Two balls can be picked from nine balls in ⁹C₂ ways.
We select one white ball and one red ball from five white balls and four red balls. This can be done ⁵ ways.
The required probability = (5 * 4) = 20/36 = 5/9
Answer: B
Answer: B
Question: A coin is tossed 8 times. What is the probability of getting exactly 7 heads?
Options:
A)1/8
B)1/16
C)1/32
D)1/64
E)1/128
Rationale: The number of possible outcomes is 2^8 = 256
There are 8 ways to get exactly 7 heads.
P(exactly 7 heads) = 8/256 = 1/32
The answer is C.
Answer: C
Question: In an election between two candidates, 20% of votes are were declares invalid. First candidate got 480 votes which were 60% of the total valid votes . The total number of votes enrolled in that election was
Options:
A)2000 votes
B)3000 votes
C)3500 votes
D)3600 votes
E)3700 votes
Rationale: (100%-20%=80%
48%-32%=16%
16% = 16×30 = 480
100% =100×30 =3000 votes)
B
Answer: B