divelab/Sys2Bench huggingface dataset:
Question: The ratio, by volume, of bleach to detergent to water in a certain solution is 4 : 40 : 100. The solution will be altered so that the ratio of bleach to detergent is tripled while the ratio of detergent to water is halved. If the altered solution will contain 300 liters of water, how many liters of detergent will it contain?
Options:
A)80
B)70
C)60
D)40
E)50
Rationale: B:D:W = 4:40:100
Bnew / Dnew = (1/3)*(4/40) = (1/30)
Dnew / Wnew = (1/2)*(40/100) = (1/5)
Wnew = 300
Dnew = Wnew/5 = 300/5 = 60
So, answer will be
C
Answer: C
Question: After decreasing 24% in the price of an article costs Rs.1064. Find the actual cost of an article?
Options:
A)1667
B)6789
C)1200
D)6151
E)1400
Rationale: CP* (76/100)
= 1064
CP= 14 * 100 => CP
= 1400
Answer: E
Answer: E
Question: The ratio between the sale price and the cost price of an article is 7:5. What is the ratio between the profit and the cost price of that article?
Options:
A)2 : 5
B)2 : 7
C)5 : 2
D)7 : 2
E)None
Rationale: Solution
Let C.P. = Rs. 5x and	S.P. = Rs.7x.
Then, Gain = Rs. 2x.
∴ Required ratio	= 2x : 5x
‹=›2 : 5
Answer A
Answer: A
Question: Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?
Options:
A)9
B)10
C)12
D)20
E)25
Rationale: Due to stoppages, it covers 9 km less.
Time taken to cover 9 km =(9/54 x 60) min	= 10 min
Answer:B
Answer: B
Question: What is the sum of all possible solutions to |x - 3|^2 + |x - 3| = 42 ?
Options:
A)4
B)3
C)5
D)6
E)2
Rationale: Denote |x - 3| as y: y^2 + y = 42 --> y = -7 or y = 6. Discard the first solution since y = |x - 3|, so it's an absolute value and thus cannot be negative.
y = |x - 3| = 6 --> x = 9 or x = -4. The sum = 5.
Answer: C.
Answer: C
Question: Two trains travelling in the same direction at 40 and 22 kmph completely pass off another in 1 minute. If the length of the first train is 125 m, what is the length of the second train?
Options:
A)118 m
B)128 m
C)231 m
D)175 m
E)142 m
Rationale: D
175 m
RS = 40 – 22 = 18 * 5/18 = 5 mps
T = 60 sec
D = 5 * 60 = 300 m
(-) 125
--------
175 m
Answer: D
Question: When y is divided by 288, the remainder is 44. What is the remainder when the same y is divided by 24?
Options:
A)20
B)21
C)23
D)25
E)26
Rationale: y = 288*a + 44 = (24*12)*a + 24 + 20
The answer is A.
Answer: A
Question: Tough and Tricky questions: Combinations.
The product of the digits of the four-digit number h is 30. No two digits of h are identical. How many different numbers are possible values of h?
Options:
A)24
B)30
C)36
D)42
E)54
Rationale: Answer = A= 24
Let number =abcd
Given that a*b*c*d = 30
a,b,c,d can be 1,2,3,5
Number of ways = 4*3*2 = 24
Answer: A
Question: A train sets off at 9:00 am at the speed of 70 km/h. Another train starts at 10:30 am in the same direction at the rate of 84 km/h. At what time will the second train catch the first train?
Options:
A)4:30
B)5:00
C)5:30
D)6:00
E)6:30
Rationale: In one hour and thirty minutes the first train travels 105 km.
The second train catches the first train at a rate of 84 km/h - 70 km/h = 14 km/h.
The second train will catch the first train in 105/14 = 7.5 hours, so at 6:00 pm.
The answer is D.
Answer: D
Question: Train P crosses a pole in 30 seconds and train Q crosses the same pole in one minute and 15 seconds. The length of train P is three-fourths the length of train Q. What is the ratio of the speed of train P to that of train Q?
Options:
A)15:8
B)12:0
C)13:9
D)14:2
E)13:0
Rationale: Given that train P crosses a pole in 30 seconds and train Q crosses the same pole in one minute and 15 seconds.
Let the length of train P be LP and that of train Q be LQ
given that LP = 3/4 LQ
As the train P and Q crosses the pole in 30 seconds and 75 seconds respectively,
=> Speed of train P = VP = LP/30
Speed of train Q = VQ = LQ/75
LP = 3/4 LQ
=> VP = 3/4 LQ/(30) = LQ/40
Ratio of their speeds = VP : VQ
= LQ/40 : LQ/75 => 1/40 : 1/75 = 15 : 8
Answer:A
Answer: A
Question: A salesmanâ€™s terms were changed from a flat commission of 5% on all his sales to a fixed salary of Rs.1000 plus 2.5% commission on all sales exceeding Rs. 4,000. If his remuneration as per new scheme was Rs. 700 more than that by the previous schema, his sales were worth?
Options:
A)s. 8,000
B)s. 9,000
C)s. 20,000
D)s.10,000
E)s. 50,000
Rationale: [1000 + (X-4000) * (2.5/100)] - X * (5/100) = 700
X = 8000
ANSWER A
Answer: A
Question: Water boils at 212°F or 100°C and ice melts at 32°F or 0°C . If the temperature of a pot of water is 50°C, what is the temperature of the pot of water in °F?
Options:
A)101°F
B)108°F
C)116°F
D)122°F
E)127°F
Rationale: Let F and C denote the temperature in Fahrenheit and Celsius respectively.
(F - 32) /(212 - 32) = (C - 0)/(100 - 0)
F = 9C/5 + 32
F = 9(50)/5 + 32 = 122°F
The answer is D.
Answer: D
Question: When x + p is divided by p + 1, the quotient is n and there is no remainder. Which of the following must be the value of x?
Options:
A)n(p +1)
B)n(p − 1)
C)p(n + 1)
D)p(n - 1) + n
E)n(p + 1) (p − 1)
Rationale: Given in question (x+p)/p+1= n
=> x+p= n(p+1)
=>x= np+n-p
or x= np-p+n
Now we are good to check the options
x= p(n-1) + n
Answer D
Answer: D
Question: A train speeds past a pole in 15 sec and a platform 120 m long in 25 sec, its length is?
Options:
A)100
B)150
C)160
D)170
E)180
Rationale: Let the length of the train be x m and its speed be y m/sec.
Then, x/y = 15 => y = x/15
(x + 120)/25 = x/15 => x = 180 m.
Answer: Option E
Answer: E
Question: Zinc and copper are melted together in the ratio 9 : 11. What is the weight of melted mixture, if 35.1 kg of zinc has been consumed in it?
Options:
A)78 kg
B)60 kg
C)64 kg
D)70 kg
E)None
Rationale: Sol.
For 9 kg Zinc, mixture melted = (9+11) kg.
For 35.1 kg Zinc, mixture, melted = [20/9 x 35.1] kg
= 78 kg.
Answer A
Answer: A
Question: An accurate clock shows 8 o'clock in the morning. Through how many degrees will the hour hand rotate
when the clock shows 2 o'clock in the afternoon?
Options:
A)180 degrees
B)190 degrees
C)200 degrees
D)280 degrees
E)None
Rationale: Angle traced by the hour hand in 6 hours = ( 360/12 * 11/3 )degrees
=180 degrees
A
Answer: A
Question: A work could be completed in 100days by x workers. However, due to the absence of 10workers, it was completed in 110days. The original no.of workers was:
Options:
A)100
B)120
C)110
D)130
E)140
Rationale: sax Letlheo g alnumberofworkers hex
x workers can do the wor - 100 days
(x — 10) workers can do the work in 110 days
4 100x 1u1x— 10)
1100 Q x 110
C
Answer: C
Question: There are 300 giraffes at a large zoo. The number of giraffes is 3 times the number of all the other animals combined. How many more giraffes are there than non giraffes animals at the zoo?
Options:
A)400
B)360
C)300
D)290
E)200
Rationale: Answer is D.
Total giraffes= 300 = 3 * Other Animals (X)
or X = 10.
So, Difference in giraffes and X = 300-10 = 290.
Answer: D
Question: Find the ratio in which rice at Rs.7.20 a kg be mixed with rice at Rs.5.80 a kg to produce a mixture worth Rs.6.30 a kg?
Options:
A)5 : 9
B)2 : 3
C)3 : 4
D)4 : 5
E)None of these
Rationale: Solution
Required ratio = 50 : 90 = 5 : 9
Answer A
Answer: A
Question: A customers identification code consists of a vowel followed by a 3-digit number greater than 200. Exactly 2 of the 3 digits in the code should be identical. How many different codes is it possible to form?
Options:
A)211
B)216
C)1075
D)1080
E)2160
Rationale: A customers identification code will be of the type -,-,-,-
first digit can be selected from any of the 5 vowels in 5C1 ways
now for the remaining three digit lets consider the following two cases
case 1: when the number is greater than 200 but less than 300
number will be of the type 2,_,_. now suppose repeating number is same as first digit number i.e. 2. and the third number is one of the remaining 9 numbers (we are rejecting 2 here, because it will result in 222, which is not acceptable as per the given condition). thus these two number can arrange themselves in two blank spaces in 2! ways. hence total number of numbers in which repeating digit is same as the first digit = 1.9.2! =18
now, suppose that repeating number is different than first digit. thus possible case in this case are 8 as listed below:
211
233
244
255
266
277
288
299
here again we have rejected 200( because number must be greater than 200) and 222 ( exactly two repeating digits are allowed)
thus total possible cases are 18 + 8 =26
case 2: number ranging from 300 to 999
here for first digit we have 7 cases (3,4,5,6,7,8,9)
now if the repeating number is same as the first number then we will have 18 cases ( same reasoning as mentioned in the previous case)
if the repeating number is different than first digit number then we will have 9 cases ( because here number ending with two zeros are allowed)
hence total number of ways = 7(18+9) = 189
thus different number of codes = 5(189+26) = 1075
hence C
Answer: C
Question: A bowl of fruit contains 12 apples and 23 oranges. How many oranges must be removed so that 60% of the pieces of fruit in the bowl will be apples?
Options:
A) 3
B) 6
C) 15
D) 17
E) 20
Rationale: Number of apples = 14
number of oranges = 23
let number of oranges that must be removed so that 60% of pieces of fruit in bowl will be apples = x
Total number of fruits after x oranges are removed = 12+(23-x) = 35-x
12/(35-x) = 6/10
=>20 = 35-x
=>x= 15
Answer C
Answer: C
Question: The sum of a number and its reciprocal is one-fifth of 26. What is the sum of that number and its square.
Options:
A)3
B)4
C)5
D)6
E)7
Rationale: Explanation:
Let the number be x. Then,
x + 1/x = 26/5
=> (x2 + 1)/x = 26/5
=> 5x2 - 26x + 5 = -0
=> (x - 5)(5x - 1) = 0
=> x = 5 or 1/5
Answer: Option C
Answer: C
Question: X and Y can do a piece of work in 20 days and 12 days respectively. X started the work alone and then after 4 days Y joined him till the completion of the work. How long did the work last?
Options:
A)3 days.
B)4 days.
C)9 days.
D)8 days.
E)10 days.
Rationale: Work done by X in 4 days =1/20	x 4=	1/5.
Remaining work =1 -	1/5=	4/5.
(X + Y)'s 1 day's work =1/20+1/12=8/60=2/15.
Now,	2/15	work is done by X and Y in 1 day.
So,	4/5 work will be done by X and Y in	15/2	x 4/5= 6 days.
Hence, total time taken = (6 + 4) days = 10 days.
Answer: Option E
Answer: E
Question: The average marks scored by Ganesh in English, Science, Mathematics and History is less than 20 from that scored by him in English, History, Geography and Mathematics. What is the difference of marks in Science and Geography scored by him?
Options:
A)80
B)50
C)60
D)Data inadequate
E)None of these
Rationale: E+H+G+M/4âˆ’E+S+M+H/4=20
â‡’ G - S = 80
Answer A
Answer: A
Question: At the opening of a trading day at a certain stock exchange, the price per share of stock K was $10. If the price per share of stock K was $15 at the closing of the day, what was the percent increase in the price per share of stock K for that day?
Options:
A)1.4%
B)50%
C)11.1%
D)12.5%
E)23.6%
Rationale: Opening = 10
Closing = 15
Rise in price = 5
So, percent increase = 5/10 * 100 = 50%
Answer : B
Answer: B
Question: If the cost price of 50 articles is equal to the selling price of 40 articles, then the gain or loss percent is?
Options:
A)27%
B)65%
C)285%
D)245%
E)25%
Rationale: Given that, cost price of 50 article is equal to selling price of 40 articles.
Let cost price of one article = Rs. 1
Selling price of 40 articles = Rs. 50
But Cost price of 40 articles = Rs. 40
Therefore, the trader made profit.\Percentage of profit = 10/40 * 100 = 25%.Answer:E
Answer: E
Question: A train covers a distance of 20 km in 10 minutes. If its speed is decreased by 10 km/hr, the time taken by it to cover the same distance will be?
Options:
A)20min 15sec
B)11min 30sec
C)15min 20sec
D)12min 10sec
E)9min 30sec
Rationale: Speed = 20*60/10 = 120 km/hr
new speed = 120-10 = 110 km/hr
time taken = 20/110 = 60*2/11 = 11 min 30 sec
Answer is B
Answer: B
Question: At an international conference, “Yellow” world countries and “Blue” world countries are the only participants. The ratio of “Yellow” world participants to “Blue” world participants is 3:2. If one-third of “Yellow” world participants are left-handed and two-thirds of “Blue” world participants are left-handed, then what is the fraction of the participants who are left-handed?
Options:
A)7
B)7/15
C)5/8
D)9/2
E)4/6
Rationale: Yellow: Blue = 3:2
Let Yellow = 3x and Blue = 2x
1/3 of Yellow are left handed => 1/3 * 3x = 3x/3 Yellow left handed
2/3 of Blue are left handed => 2/3 *2x = 4x/3 blue left handed
fraction of participants who are left handed = total left handed/ total participants = (yellow left handed + blue left handed)/total participants = (3x/3 + 4x/3)/(3x+2x) = (7x/15x) = 7/15
Answer : B
Answer: B
Question: A salesman gets commission on total sales at 9%. If the sale is exceeded Rs.10,000 he gets an additional commission as bonus of 3% on the excess of sales over Rs.10,000. If he gets total commission of Rs.1380, then the bonus he received is:
Options:
A)22
B)120
C)388
D)377
E)272
Rationale: Explanation:
Commission up to 10000 = \inline 10000\times \frac{9}{100} = 900
Again after 10000,
Commission : Bonus
9 : 3
\inline \Rightarrow 3x : x
\therefore Bonus = \inline (1380-900)\times \frac{1}{4}= Rs.120
Answer: B) Rs.120
Answer: B
Question: I. l-14, l, l, l, l+14
II. b, b+1, b+2, b+3, b+4
III. c, c, c, c, c
The data sets I, II, and III above are ordered from greatest standard deviation to least standard deviation in which of the following?
Options:
A)I, II, III
B)I, III, II
C)II, III, I
D)III, I, II
E)III, II, I
Rationale: S.D is a non-negative entity. Also, for a given set with all the elements same, the S.D is Zero(It is zero even if there is only one element in the set too). From the given sets, we can see that the last set has a standard deviation of zero. Also, because the other sets can not have all the terms equal for any values of l or b, thus the S.D for the third set(III) has to be the minimum. Select the option which has III in the end.
A.
Answer: A
Question: Sonika deposited Rs.8000 which amounted to Rs.9200 after 3 years at simple interest. Had the interest been 3% more. She would get how much?
Options:
A)9920
B)96288
C)26667
D)1662
E)2882
Rationale: (8000*3*3)/100 = 720
9200
--------
9920
Answer:A
Answer: A
Question: Ajay can walk 7km in 1 hour. In how many hours he can walk 80km?
Options:
A)5hrs
B)11.4hrs
C)15.5hrs
D)20.4hrs
E)30hrs
Rationale: 1 hour he walk 8km
he walk 80km in = 80/7* 1 = 11.4hours
Answer is B
Answer: B
Question: Emily cut two circles from a sheet of colored paper measuring 8” by 12”. One circle had a
radius of 3 inches and the other had a radius of 2.5 inches. How many square inches of paper are
left over?
Options:
A)48.11 sq. in.
B)58.11 sq. in.
C)68.11 sq. in.
D)78.11 sq. in.
E)88.11 sq. in.
Rationale: 8 x 12 = 96 sq. in. area of paper
3.14(3)2 = 28.26 sq. in. area of one circle
3.14(2.5)2 = 19.625 or 19.63 sq. in. rounded
area of other circle
28.26 + 19.63 = 47.89 sq. in. used for circles
96 - 47.89 = 48.11 sq. in. left over
correct answer A
Answer: A
Question: A candidate got 35% of the votes polled and he lost to his rival by 2250 votes. How many votes were cast?
Options:
A)7500
B)5000
C)6000
D)3500
E)4000
Rationale: Explanation:
35%-----------L
65%-----------W
------------------
30%----------2250
100%---------? => 7500
ANSWER IS A
Answer: A
Question: A man can row 4.5 km/hr in still water. It takes him twice as long to row upstream as to row downstream. What is the rate of the current ?
Options:
A)1.9
B)1.7
C)1.2
D)1.5
E)1.1
Rationale: Speed of boat in still water (b) = 4.5 km/hr. Speed of boat with stream (Down Stream), D = b + u Speed of boat against stream (Up stream), U = b – u It is given upstream time is twice to that of down stream. ⇒ Downstream speed is twice to that of upstream. So b + u = 2(b – u) ⇒ u =b/3 = 1.5 km/hr.
Answer: D
Answer: D
Question: Two friends A and B are running up hill and then to get down! length of road is 440 yards. A on his return journey met B going up at 20 yards from top, A has finished the race 5 minutes earlier than B, then how much time A had taken to complete the race.
Options:
A)50 minutes
B)52.5 minutes
C)55 minutes
D)54.5 minutes
E)None of these
Rationale: Explanation :
When A travels 460m (=440+20),
B travels 420m (=440-20). So, ratio of speed = 460:420
= 23:21.
Let A's speed be 23x, and that of B's be 21x.
=> 23x = ((2 * 440) / t) which implies 23t = 880/x;
=> 21x = ((2 * 440) / (t+5)) which implies 21(t+5) = 880/x.
From these two equations, 23t = 21(t+5). Solving, t = 52.5
Hence (B) is the correct answer.
Answer : B
Answer: B
Question: The speed of a boat in upstream is 20 kmph and the speed of the boat downstream is 80 kmph. Find the speed of the boat in still water and the speed of the stream?
Options:
A)10 kmph
B)11 kmph
C)16 kmph
D)30 kmph
E)19 kmph
Rationale: Speed of the boat in still water = (20+80)/2 = 50 kmph. Speed of the stream = (80-20)/2 = 30 kmph.Answer: D
Answer: D
Question: Two trains 140 m and 180 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is?
Options:
A)17.9 sec
B)11.52 sec
C)27.7 sec
D)10.8 sec
E)17.8 sec
Rationale: Relative speed = 60 + 40 = 100 km/hr.
= 100 * 5/18 = 250/9 m/sec.
Distance covered in crossing each other = 140 + 180 = 320 m.
Required time = 320 * 9/250 = 11.52 sec.
Answer: B
Answer: B
Question: A lady bought five books namely A,B,C,D,E to distribute her 6 children. How many ways she can distribute books?
Options:
A)6^3
B)5^6
C)6^5
D)6^6
E)3^6
Rationale: 6*6*6*6*6
6^5
ANSWER:C
Answer: C
Question: Evaluate: 50 - 12÷2×2 =
Options:
A)A)36
B)B)38
C)C)40
D)D)42
E)E)44
Rationale: According to order of operations, 12÷2×2 (division and multiplication) is done first from left to right
12÷2×2 = 6 × 2 = 12
Hence
50 - 12÷6×2 = 50 - 12 = 38
correct answer is B) 38
Answer: B
Question: A man can row 30 km downstream and 20 km upstream in 4 hours. He can row 45 km downstream and 40 km upstream in 7 hours. Find the speed of man in still water?
Options:
A)12.6
B)82.5
C)12.4
D)12.5
E)12.0
Rationale: Let the speed of the man in still water be a kmph and let the speed of the stream be b kmph.
Now 30/(a + b) + 20/(a - b) = 4 and 45/(a + b) + 40/(a - b) = 7
Solving the equation, the speed of man in still water is 12.5 kmph.
Answer: D
Answer: D
Question: A and B entered into a partnership investing Rs.25000 and Rs.30000 respectively. After 4 months C also joined the business with an investment of Rs.35000. What is the share of C in an annual profit of Rs.47000?
Options:
A)22277
B)29977
C)267676
D)14000
E)18811
Rationale: 25*12: 30*12: 35*8
15:18:14
14/47 * 47000 = 14000
Answer: D
Answer: D
Question: A certain car increased its average speed by 5 miles per hour in each successive 5-minute interval after the first interval. If in the first 5-minute interval its average speed was 38 miles per hour, how many miles did the car travel in the third 5-minute interval?
Options:
A)1.0
B)1.5
C)2.0
D)2.5
E)4.0
Rationale: In the third time interval the average speed of the car was 38+5+5=30 miles per hour;
In 5 minutes (1/12 hour) at that speed car would travel 48*1/12=4 miles.
Answer: E.
Answer: E
Question: In a simultaneous throw of 2 dice what is the probability of getting a total of 4?
Options:
A)1/2
B)1/4
C)2/9
D)1/12
E)3/13
Rationale: n(S) = 6*6 = 36
E = {(1,3),(2,2),(3,1)}
Probability = 3/36 = 1/12
Answer is D
Answer: D
Question: A leak in the bottom of a tank can empty the full tank in 6 hours. An inlet pipe fills water at the rate of 4 liters per minute. When the tank is full in inlet is opened and due to the leak the tank is empties in 8 hours. The capacity of the tank is?
Options:
A)5760
B)5860
C)5240
D)5890
E)6000
Rationale: 1/x - 1/6 = -1/8
x = 24 hrs
24 * 60 * 4 = 5760
ANSWER A
Answer: A
Question: Midas has boxes in three sizes: large, medium, and small. He puts 11 large boxes on a table. He leaves some of these boxes empty, and in all the other boxes he puts 8 medium boxes. He leaves some of these medium boxes empty, and in all the other medium boxes he puts 8 (empty) small boxes. Now, 102 of all the boxes on the table are empty.
How many boxes has Midas used in total?
Options:
A)113
B)114
C)115
D)116
E)117
Rationale: By keeping 8 boxes in a single box, the total number of empty boxes increases by 8-1 = 7.
let x the number of times that 8 boxes have been kept in a box
now we know that 11 + 7x = 102
by solving we have x=13
finally 11 + 13 × 8 = 115
therefore totally 115 boxes have been used
ANSWER:C
Answer: C
Question: How many three-digit numbers are divisible by 6 in all?
Options:
A)149
B)150
C)151
D)166
E)None
Rationale: Solution
Required numbers are 102,018,114,....996.
This is an A.P with a = 102,
d= 6.
Let the number of its terms be n. Then	a+(n - 1)d
‹=›102+(n - 1)×6 = 996
‹=›n=150.
Answer B
Answer: B
Question: How many keystrokes are needed to type the numbers from 1 to 100?
Options:
A)102
B)150
C)192
D)208
E)225
Rationale: There are 9 one-digit numbers from 1 to 9.
There are 90 two-digit numbers from 10 to 99.
We need 3 keystrokes for the number 100.
9 + 90(2) + 3 = 192
The answer is C.
Answer: C
Question: The perimeter of a semi circle is 144 cm then the radius is?
Options:
A)25 cm
B)28 cm
C)30 cm
D)35 cm
E)40 cm
Rationale: Explanation:
36/7 r = 144 => r = 28
ANSWER IS B
Answer: B
Question: If p is the product of the integers from 1 to 30, inclusive, what is the greatest integer k for which 3^k is a factor of p?
Options:
A)10
B)12
C)14
D)16
E)18
Rationale: No need to actually find the product of 1 to 30. Just look at the numbers that have factors of 3.
3 = 3
6 = 3 * 2
9 = 3 * 3
12 = 3 * 2 * 2
15 = 3 * 5
18 = 3 * 3 * 2
21 = 3 * 7
24 = 3 * 2 * 2 * 2
27 = 3 * 3 * 3
30 = 3 * 2 * 5
There are 14 3's, so the largest factor of p for 3k is 3*14
ANSWER:C
Answer: C
Question: At a special sale, 12 tickets can be purchased for the price of 3 tickets. If 12 tickets are purchased at the sale, the amount saved will be What percent of the original price of the 12 tickets?
Options:
A)20%
B)33.3%
C)40%
D)50%
E)75%
Rationale: let the price of a ticket be Rs.100, so 3 tickets cost 300 & 12 tickets cost 1200
12 tickets purchased at price of 3 tickets ie., for 300, so amount saved s Rs.900,
% of 5 tickets = (900 /1200)*100 =75 %
ANSWER:E
Answer: E
Question: The length of minute hand of a clock is 5.6 cm. What is the area covered by this in 10 minutes
Options:
A)15.27
B)16.27
C)17.27
D)16.41
E)19.27
Rationale: area of circle is pi*r^2
but in 10 minutes area covered is (10/60)*360=60 degree
so formula is pi*r^2*(angle/360)=3.14*(5.6^2)*(60/360)=16.41 cm^2
ANSWER:D
Answer: D
Question: From 2005 to 2015 the world's population grew by 11.27%, and from 2005 to 2010 the world's population grew by 6.20%. What was the percentage growth in the world's population from 2010 to 2015?
Options:
A) 5%
B) 6%
C) 2%
D) 2.5%
E) 5.5%
Rationale: Let the world's population in 2005 = x; then,
for 2005-2010, the population equation is x + 0.0620x = 1.0620x,
for 2005-2015, the population equation is x + 0.1127x = 1.1127x;
so, the growth from 2010 to 2015 = (1.1127x - 1.060x)/(1.062x) = 0.05 (rounded). Thus, the answer is 5%.
Answer is A
Answer: A
Question: The radius of the two circular fields is in the ratio 3: 5 the area of the first field is what percent less than the area of the second?
Options:
A)50%
B)60%
C)40%
D)64%
E)75%
Rationale: Explanation:
r = 3 Ï€r2 = 9
r = 5 Ï€r2 = 25
25 Ï€ â€“ 16 Ï€
100 ---- ? => 64%
ANSWER IS D
Answer: D
Question: If the L.C.M of two numbers is 560 and their product is 42000, find the H.C.F of the numbers.
Options:
A)50
B)30
C)75
D)25
E)None of these
Rationale: H.C.F = (Product of the numbers) / (Their L.C.M) = 42000/560 = 75.
ANSWER:C
Answer: C
Question: The sum of present age of Abe and the age before 7 years is 29. Find the present age of Abe. What will be his age after 7 years?
Options:
A)25
B)26
C)27
D)28
E)29
Rationale: Present age = x
Before 7yrs, y=x-7
After 7yrs, z=x+7
By the qn,
x+(x-7)=29
2x-7=29
2x=29+7
x=36/2
x=18
z=x+7
=18+7
=25
ANSWER:A
Answer: A