divelab/Sys2Bench huggingface dataset:
Question: Tough and Tricky questions: Exponents.
If a and b are positive integers and x = 8^a and y = 7^b, which of the following is a possible units digit of xy?
Options:
A)1, 4
B)4, 1, 2
C)5, 8
D)2, 4, 6 and 8
E)8, 6
Rationale: Only Units digit of X and Y contribute to the Units digit of XY.
Finding all values ofXfor positive values ofa
When,
a=1; X=8
a=2; X=64
a=3; X=512
a=4; X=2048........ Units digit repeat in a cycle of 8,4,2,8......
Similarly, Finding all values ofYfor positive values ofb
When,
b=1; Y=7
b=2; Y= 49
b=3; Y= 343
b=4; Y=2041
b=5; Y=16807....... Units digit repeat in cycle of 7,9,3,1,7,9,3....
So, possible value of Units digit of XY can be found by considering all possibilities of Units digit of X and Y
When X=8 and Y=7: Units digit of XY = 56
When X=8 and Y=9: Units digit of XY = 72
When X=8 and Y=3: Units digit of XY = 24
When X=4 and Y=7: Units digit of XY = 28
When X=4 and Y=9: Units digit of XY = 36
When X=4 and Y=3: Units digit of XY = 12
When X=2 and Y=7: Units digit of XY = 14
When X=2 and Y=9: Units digit of XY = 18
When X=2 and Y=3: Units digit of XY = 6
Only four possibilities for Units digit of XY i.e. 2, 4, 6 and 8
therefore answer is D
Answer: D
Question: In a consumer survey, 82% of those surveyed liked at least one of three products: 1, 2, and 3. 45% of those asked liked product 1, 30% liked product 2, and 20% liked product 3. If 4% of the people in the survey liked all three of the products, what percentage of the survey participants liked more than one of the three products?
Options:
A)9
B)11
C)13
D)15
E)17
Rationale: 45 + 30 + 20 = 95
The number 95 includes some people counted twice and some people counted three times.
95 - 82 = 13, and this number represents people counted twice or three times.
4% of the people are counted two extra times.
The percentage of people counted one extra time is 13 - 4(2) = 5.
The percentage of people who liked more than one product is 4% + 5% = 9%.
The answer is A.
Answer: A
Question: How many words can be formed by using all the letters of the word, 'ALLAHABAD' ?
Options:
A)3780
B)1890
C)7560
D)2520
E)5420
Rationale: The word 'ALLAHABAD' contains 9 letters, namely 4A, 2L, 1H, 1B and 1D.
Requisite number of words =9!/(4!)(2!)(1!)(1!)(1!) =7560
Answer is C
Answer: C
Question: What will come in place of the x in the following Number series? 12, 38, 116, 350, 1052, x
Options:
A)2546
B)2753
C)2864
D)2975
E)3158
Rationale: 12
12 × 3 + 2 = 38
38 × 3 + 2 = 116
116 × 3 + 2 = 350
350 × 3 + 2 = 1052
1052 × 3 + 2 = 3158
E
Answer: E
Question: Kavi had a stock of 600 bags in his bookshop. He sold 25 on Monday, 70 on Tuesday, 100 on Wednesday, 110 on Thursday and 145 on Friday. What percentage of the bags were not sold?
Options:
A)10%
B)25%
C)64%
D)42%
E)17%
Rationale: Let N be the total number of bags sold. Hence
N = 25 + 70 + 100 +110 + 145 = 450
Let M be the bags NOT sold
M = 600 - N = 600 - 450 = 150
Percentage
Bags not sold / total number of bags = 150/600= 0.25 = 25%
correct answer B
Answer: B
Question: Mr. Karthik drives to work at an average speed of 48 km/hr. Time taken to cover the first 60% of the distance is 20 minutes more than the time taken to cover the remaining distance. Then how far is his office ?
Options:
A)23
B)98
C)28
D)80
E)19
Rationale: Explanation:
Let the total distance be 'x' km.
Time taken to cover remaining 40% of x distance is
But given time taken to cover first 60% of x distance is
\Rightarrow
\small \Rightarrow x=80 km.
Answer: D
Answer: D
Question: The number of arrangements that can be made with the letters of the word PETER so that the vowels occupy the even places?
Options:
A)14
B)18
C)12
D)15
E)11
Rationale: The word PETER has 5 letters of which 2 are vowels.
-V-V-V-
As the vowels have to occupy even places, they can be arranged in the 2 even places in 2! i.e., 2 ways. While the consonants can be arranged among themselves in the remaining 3 places in 3! i.e., 6 ways.
Hence the total ways are 6 * 2 = 18.
Answer:B
Answer: B
Question: What is the sum of the different positive prime factors of 720?
Options:
A)5
B)10
C)15
D)17
E)21
Rationale: Prime factorization of 720
=72 * 10
=6*12 * 10
=2*3 * 2*6 * 2*5
=2*3 * 2 * 2*3 * 2*5
=2^4 * 3^2 * 5
Sum of the different positive prime factors of 720 = 2+3+5
=10
Answer B
Answer: B
Question: If the two-digit integers A and B are positive and have the same digits, but in reverse order, which of the following could be the sum of A and B?
Options:
A)29
B)30
C)31
D)32
E)33
Rationale: A two-digit number "cd" can be expressed algebraically as 10c+d.
The sum of A + B = (10c+d)+(10d+c)=11(c+d).
The only answer that is a multiple of 11 is 33.
The answer is E.
Answer: E
Question: College T has 1000 students. Of the 250 students majoring in one or more of the sciences,140 are majoring in Chemistry and 170 are majoring in Biology. If at least 50 of the students are not majoring in either Chemistry or Biology, then the number of students majoring in both Chemistry and Biology could be any number from?
Options:
A)110 to 150
B)110 to 140
C)110 to 130
D)120
E)130
Rationale: Total = Chemistry + Biology - Both + Neither
250 = 140 + 170 - Both + N
We know that N (Neither) must be at least 30, so set N=30 and solve:
250 = 140 + 170 - Both + 50
250 = 360 - Both
Both = 110
Even if you're not sure whether 110 is the highest or lowest Both could possibly be, it doesn't matter, because you know it's a boundary point of the range,
Both can not be greater than 140, because even if every chemistry major was also a biology major, there are only 140 chemistry majors total. B the solution.
Answer: B
Question: A tank has both an inlet pipe and an outlet pipe. Working alone, the inlet pipe can fill up the tank in 5 hours. Working alone, the outlet pipe can empty out the tank in 10 hours. If it is desired that the tank should be filled, from empty, exactly 8 hours after the inlet pipe is turned on at 9:30am, then at what time should the outlet pipe be opened ?
Options:
A)11:30am
B)10:30am
C)9:30am
D)8:30am
E)7:30am
Rationale: In 8 hours the inlet pipe will pump in water equal to 8*1/5 = 8/5 of the pool. So, 3/5 more than necessary, which should be compensated by the outlet pipe. To pump out 3/5 of the water the outlet pipe needs 30/5 = 6 hours.
Therefore, the outlet pipe should be opened at 9:30am + 8 hours - 6 hours = 11:30am.
Answer: A
Answer: A
Question: If I walk at 3 kmph, I miss the train by 2 min, if however, I walk at 4 kmph. I reach the station 2 min before the arrival of the train. How far do I walk to reach the station?
Options:
A)4/5 km
B)2/3 km
C)8/2 km
D)1/3 km
E)9/6 km
Rationale: x/3 – x/4 = 4/60
x = 4/5 km
Answer:A
Answer: A
Question: Question: What is the remainder when R=(1!)!^3 + (2!)^3 + (3!)^3 + … + (432!)^3 is divided by 144?
Options:
A) 0
B) 25
C) 49
D) 81
E) 100
Rationale: 144 =12 *12
(1!)^3=1
2!=2, therefore (2!)^3=2*2*2=8
3!=6, therefore (3!)^3=6*6*6=216
4!=24 therefore (4!)^3= 24*24*24 which is completely divisible by 144
thus from 4! onwards each term will be divisible by 144 and will leave the remainder of 0
now the remainder when R=(1!)^3 + (2!)^3 + (3!)^3 + … + (432!)^3 is divided by 144 is same as, when 1+8+216 =225 is divided by 144
now remainder when 225 is divided by 144 is 81. hence answer should be D
Answer: D
Question: Alex deposited x dollars into a new account that earned 9 percent annual interest, compounded annually. One year later Alex deposited an additional x dollars into the account. If there were no other transactions and if the account contained w dollars at the end of two years, which of the following expresses x in terms of w ?
Options:
A)w/(1+1.08)
B)w/(1.08+1.16)
C)w/(1.16+1.24)
D)w/(1.09+1.09^2)
E)w/(1.08^2+1.08^2)
Rationale: Account at the end of the first year would be 1.09x dollars. At this time x dollars was deposited, hence the account at the beginning of the second year would be (1.09x+x) dollars. Account at the end of the second year would be (1.09x+x)*1.09=w --> x(1.09^2+1.09)=w --> x=w/(1.09+1.09^2).
Answer: D.
Answer: D
Question: The diagonals of the two squares are in the ratio of 2:5 find the ratio of their area .
Options:
A)5:89
B)7:96
C)4:25
D)5:84
E)8:96
Rationale: Let the diagonals of the square be 2x and 5x respectively .
ratio of their areas =1/2(2x)^2:1/2(5x)
= 4x^2:25x^2=4:25
Answer(C)
Answer: C
Question: A worker's daily wage is increased by 50% and the new wage is $30 per day. What was the worker's daily wage before the increase?
Options:
A)$15
B)$18
C)$20
D)$22
E)$25
Rationale: Let x be the daily wage before the increase.
1.5x = $30
x = $20
The answer is C.
Answer: C
Question: If six persons sit in a row, then the probability that three particular persons are always together is ?
Options:
A)1/3
B)1/9
C)1/5
D)1/7
E)1/1
Rationale: Six persons can be arranged in a row in 6! ways. Treat the three persons to sit together as one unit then there four persons and they can be arranged in 4! ways. Again three persons can be arranged among them selves in 3! ways. Favourable outcomes = 3!4! Required probability = 3!4!/6! = 1/5
Answer:C
Answer: C
Question: Find the amount on Rs.5000 in 2 years, the rate of interest being 2% per first year and 3% for the second year?
Options:
A)3377
B)2678
C)5460
D)1976
E)5253
Rationale: 5000 * 102/100 * 103/100 => 5253
Answer: E
Answer: E
Question: A certain characteristic in a large population has a distribution that is symmetric about the mean m. If 84 percent of the distribution lies within one standard deviation d of the mean, what percent of the distribution is less than m + d ?
Options:
A) 16%
B) 32%
C) 48%
D) 84%
E) 92%
Rationale: This is easiest to solve with a bell-curve histogram. m here is equal to µ in the Gaussian normal distribution and thus m = 50% of the total population.
So, if 84% is one st.Dev, then on either side of m we have 84/2 =42%. So, 84% are to the right and left of m (= 50%). In other words, our value m + d = 50 + 42 = 92% goingfrom the mean m, to the right of the distributionin the bell shaped histogram.. This means that 92% of the values are below m + d.
Like I said, doing it on a bell-curve histogram is much easier to fullygethow this works, or you could apply GMAT percentile jargon/theory to it
E
Answer: E
Question: A theater charges $12 for seats in the orchestra and $8 for seats in the balcony. On a certain night, a total of 355 tickets were sold for a total cost of $3,320. How many more tickets were sold that night for seats in the balcony than for seats in the orchestra?
Options:
A) 90
B) 115
C) 120
D) 130
E) 220
Rationale: Orchestra Seats - a
Balcony Seats - b
a+b = 355
and 12a + 8b = 3320
Solving equations simultaneously (Multiply Equation 1 with 8 and subtract from second equation)
4a = 3320 - 8*355 = 3320 - 2840 = 480
i.e. a = 120
and b = 355-120 = 235
More seats in balcony than orchestra = b-a = 235 - 120 = 115
Answer: option B
Answer: B
Question: A, B and C are entered into a partnership. A invested Rs.6500 for 6 months, B invested Rs.8400 for 5 months and C invested for Rs.10000 for 3 months. A is a working partner and gets 5% of the total profit for the same. Find the share of C in a total profit of Rs.7400.
Options:
A)2997
B)1900
C)2887
D)2898
E)27912
Rationale: 65 * 6 : 84 * 5 : 100 * 3
26:28:20
C share = 74000 * 95/100 = 7030 * 20/74 => 1900.Answer: B
Answer: B
Question: he population of a city is 120,000. If it increases at the rate of 6% per annum, then what will be its population 2 years hence?
Options:
A)137787
B)134832
C)139776
D)139728
E)139718
Rationale: Population after n years = P [1 + (R/100)]2
Population after 2 years = 120000 * [1 + 6/100]2 = (120000 x 53/50 x 53/50) = 134832
ANSWER: B
Answer: B
Question: The largest 4 digit number exactly divisible by 88 is?
Options:
A)9934
B)9938
C)9940
D)9942
E)9944
Rationale: Largest 4-digit number = 9999
88) 9999 (113
88
----
119
88
----
319
264
---
55
---
Required number = (9999 - 55)
= 9944.
E)
Answer: E
Question: Three seventh of a number is 12 more than 40% of that number. What will be the 90% of that number?
Options:
A)A)148
B)B)210
C)C)189
D)D)248
E)E)258
Rationale: 3/7 x – 40/100 x = 12
x = 35 * 12
35 * 12 * 90/100 = 378/2 = 189
ANSWER:C
Answer: C
Question: Bob finishes the first half of an exam in one-fifth the time it takes him to finish the second half. If the whole exam takes him an hour, how many minutes does he spend on the first half of the exam?
Options:
A)20
B)24
C)27
D)36
E)40
Rationale: Many times, it is easiest to think of problems like this conceptually (as opposed to formulaically). Conceptually, if the first half of the exam takes 1/5's the time of the second half (6/6's), we can see that the hour the entire exam took to finish can be broken down into sixth's. (Another way to look at this problem is via ratio's - first half is 1:6 and the second half is 5:6). With each sixth of an hour being 10 minutes (60/6), the first half of the exam would have taken 20 minutes. Correct answer is A.
Answer: A
Question: Josh and Dan have a 12 apples each. Together they flip a coin 6 times. For every heads, Josh receives an apple from Dan, and for every tails Dan receives an apple from Josh. After the coin has been flipped 6 times, what is the probability that Josh has more than 12 apples but fewer than 18?
Options:
A)1/64
B)15/64
C)21/64
D)21/32
E)5/6
Rationale: minimum number of times to win is 4 to have more than 12 apples .
coz: if he wins 3 times => he gets 3 apples and give 3 apples ; no change
so he needs to win 4 times OR 5 times
Not 6 times because ,
if he wins 6 times => he gets 6 apples and he will have 18 apples
Now number of ways to win 4 times out of 6 times 6C4
Now number of ways to win 5 times out of 6 times 6C5
Total number of ways 2626 ways
Probability =(6C4) + (6C5)/2^6
=21/64
Answer :C
Answer: C
Question: If 4x+y+z=800, 2x-y-z=40,3x+y-z = 12 for integers of x,y and z, find z =?
Options:
A)250
B)464
C)525
D)256
E)324
Rationale: 4x+y+z = 800----------1)
2x-y-z = 40-------------2)
3x+y-z = 12 ------------3)
from 1) and 2)
6x = 840
x = 140 substitute in 1) and 3)
560+y+z = 800
y+z = 240-------4)
420+y-z = 12
y-z = -408-------5)
from 4) and 5)
2z = 648
z = 324
Answer is E
Answer: E
Question: Bruce and Bhishma are running on a circular track of length 600m. Speed of Bruce is 30 m/s and that of Bhishma is 20 m/s .They start fro the same point at the same time in the same direction. When will they meet again for the first time?
Options:
A)30
B)40
C)50
D)60
E)80
Rationale: Actually Arjun has to make a lead of 600 m, because when Arjun will be 600m ahead of Bhishma, they will be together again as a person when completes the total length it starts retracing he same path and thus Arjun and Bhishma can be together again.
Since , they make a difference of 10 m in 1 second. so, he will create 600m difference in 60 second.
D
Answer: D
Question: 20 marbles were pulled out of a bag of only white marbles, painted black, and then put back in. Then, another 20 marbles were pulled out, of which 1 was black, afterwhich they were all returned to the bag. If the percentage of black marbles pulled out the second time represents their percentage in the bag, how many marbles in total does the bag currently hold?
Options:
A)40
B)200
C)380
D)400
E)3200
Rationale: We know that there are 20 black marbles in the bag and this number represent 1/20 th of the number of all marbles in the bag, thus there are total of 20*20=400 marbles.
Answer: D.
Answer: D
Question: In an engineering class that contained 100 students, the final exam consisted of 2 questions. Three fifths of the students answered the first question correctly. If four fifths of the remainder answered the second question correctly, how many students answered both questions incorrectly?
Options:
A)4
B)6
C)8
D)12
E)24
Rationale: 1st Question : Three fifths of the students answered the first question correctly - so 3/5âˆ—100=60
2nd Question : four fifths of the remainder answered the second question correctly so 4/5âˆ—(100âˆ’60)=4/5âˆ—40=32
total students who answered at least one Q correct =60+32=92
so students who answered BOTH incorrectly = 100âˆ’92=8
ANSWER:C
Answer: C
Question: How many multiples of 5 are there between 0 and 358?
Options:
A)54
B)75
C)76
D)71
E)58
Rationale: 5 * 1 = 5
5 * 71 = 355
Total number of multiples = (71 + 1)
= 72
Answer D
Answer: D
Question: Sachin is older than Rahul by 7 years. If the ratio of their ages is 11:9, find the age of Sachin
Options:
A)24.5
B)24.8
C)38.5
D)24.88
E)24.19
Rationale: Explanation:
If Rahul age is x, then Sachin age is x + 7,
so,
9x + 63 = 11x
2x = 63
x = 31.5
So Sachin age is 31.5 + 7 = 38.5
Answer: C) 38.5
Answer: C
Question: A certain company has budgeted $1320 for entertainment expenses for the year, divided into 12 equal monthly allocations. If by the end of the third month, the total amount spent on entertainment was $300, how much was the company under budget or over budget?
Options:
A)$60 under budget
B)$30 under budget
C)$30 over budget
D)$60 over budget
E)$180 over budget
Rationale: The budget for 3 months is (3/12)*$1320 = $330
The company is $30 under budget.
The answer is B.
Answer: B
Question: If Rs.460 amount to Rs.540 in 4 years, what will it amount to in 6 years at the same rate % per annum?
Options:
A)Rs.575
B)Rs.595
C)Rs.590
D)Rs.580
E)Rs.585
Rationale: 80 = (460*4*R)/100
R = 4.34%
I = (460*6*4.34)/100 = 120
460 + 120 = 580
ANSWER:D
Answer: D
Question: A, B and C invested Rs.6300, Rs.4200 and Rs.10500 respectively, in a partnership business. Find the share of A in profit of Rs.12200 after a year?
Options:
A)3660
B)2881
C)2887
D)9977
E)2212
Rationale: 6300:4200:10500
3:2:5
3/10 * 12200 = 3660.Answer: A
Answer: A
Question: When N is divided by T, the quotient is S and the remainder is Q. Which of the following expressions is equal to N?
Options:
A)ST
B)S + V
C)ST + Q
D)T(S+V)
E)T(S – V)
Rationale: Using the rule dividend = Quotient * divisor + remainder =>ST + Q C is correct
Answer: C
Question: In how many ways can 5 boysand 2 girls be arranged at a table if 2 girls are never together?
Options:
A)235
B)256
C)260
D)350
E)480
Rationale: Total ways of arranging 7 person in a circle = 6! = 720 ways
If we consider two women as one, then we have 5+1=6 persons. Arranging these six persons in circle will take = 5! = 120 ways
And two women can arrange themselves in 2! ways
Total ways in which two women sit together in circle = 5!*2! = 240 ways
Total ways in which two women doesn’t sit together in circle = 6! - 5!*2! = 720 - 240 = 480 ways
E
Answer: E
Question: If n divided by 3 has a remainder of 2, what is the remainder when 2 times n is divided by 3?
Options:
A)1
B)2
C)3
D)5
E)0
Rationale: As per question => N=3P+2 for some integer p
hence 2N => 6Q + 4 => remainder => 1 for some integer Q
hence A
Answer: A
Question: Population of a city in 2004 was 1000000. If in 2005 there is an increment of 25% , in 2006 there is a decrements of 35 % and in 2007 there is an increment of 45%, then find the population of city at the end of the year 2007
Options:
A)967532
B)977522
C)984424
D)997454
E)1178125
Rationale: Required population = P (1 + R1/100)(1 - R2/100)(1 + R3/100)
= P (1 + 25/100)(1 - 35/100)(1 + 45/100)
= 1178125
E
Answer: E
Question: If among 5 children there are 2 siblings, in how many ways can the children be seated in a row so that the siblings do not sit together?
A. 38
B. 46
C. 72
D. 86
E. 102
Options:
A)38
B)46
C)72
D)86
E)102
Rationale: Without limitations, 5 children can be seated in 5!=120 ways. Find the number of ways to seat the 5 children so that the siblings DO sit together. The siblings can be regarded as one unit so there are 4! combinations. But within this unit the siblings can sit in two different ways. So the number of ways to seat the 5 children so that the siblings DO sit together is 4!∗2=48. Thus, the number of combinations in which the siblings DO NOT sit together is 120 - 48 = 72.
Answer: C
Answer: C
Question: In February Wilson’s earnings were 40 percent of his family’s total income. In March Wilson earned 25 percent less than in February. If the rest of his family’s income was the same in both months, then, in March, Wilson’s earnings were approximately what percent S of his family’s total income?
Options:
A) 15%
B) 17%
C) 24%
D) 30%
E) 33%
Rationale: Lets suppose the Total Family income in Feb = 100x
Wilson's earning in Feb = 40% of 100x = 40x
Earnings of remaining family in Feb = 100x - 40x = 60x
Wilson's earning in March = 75% of Wilson's Feb earnings = 75% of 40x = 30x
Earnings of remaining family in March = Earnings of remaining family in Feb = 60x
Thus Wilson's earning as % of Total family income in March S= 30x/ (30+60)x = 30x/90x = 33.33%
Thus Answer is E
Answer: E
Question: If the seller selling his goods with the profit of 200 and profit percentage of the good is 50%, then what is the Cost price of that goods.
Options:
A)200
B)300
C)400
D)500
E)600
Rationale: Explanation:
Profit = 200
Profit% = 50% = (Profit/C.P)*100
C.P = (200*100) / 50 = 400. Answer: C
Answer: C
Question: A bag contains 64 balls of eight different colours. There are eight of each colour (including red). What is the least number you would have to pick, without looking, to be sure of selecting 3 red balls?
Options:
A)59
B)33
C)52
D)68
E)80
Rationale: A
59
The first 56 balls could be of all colours except red. This would leave 8 balls, all of which are red. so any three chosen would be red.
Answer: A
Question: In a school of 300 boys, 44% of Muslims, 28% Hindus, 10% Sikhs and the remaining of other communities. How many belonged to the other communities?
Options:
A)54
B)63
C)70
D)42
E)31
Rationale: 44 + 28 + 10 = 82%
100 – 82 = 18%
300 * 18/100 = 54
ANSWER:A
Answer: A
Question: What percent of 50 is 80?
Options:
A)133 1⁄3
B)75
C)160
D)33 1⁄3
E)25
Rationale: To find out the % of 80 in 50
Do 80/50 = 160%
Answer C)
Answer: C
Question: A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If three marbles are picked at random, what is the probability that they are all blue?
Options:
A)1/455
B)1/459
C)1/458
D)1/451
E)1/451
Rationale: Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles.
Probability that all the three marbles picked at random are blue = ³C₃/¹⁵C₃ = (1 * 3 * 2 * 1)/(15 * 14 * 13) = 1/455
Answer:A
Answer: A
Question: A, B, C hired a car for Rs. 520 and used it for 7, 8 and 11 hours respectively. Hire charges paid by B were?
Options:
A)127
B)160
C)287
D)237
E)111
Rationale: A : B : C = 7 : 8 : 11.
Hire charges paid by B = Rs. (520 * 8/26) = Rs. 160.
Answer: B
Answer: B
Question: A train running at certain speed crosses a stationary engine in 20 seconds. To find out the speed of the train, which of the following information is necessary:
Options:
A)Only the length of the train
B)Only the length of the engine
C)Either the length of the train or the length of the engine.
D)Both the length of the train and the length of the engine.
E)none of these
Rationale: Explanation:
Since the sum of the length of the train and the length of the engine is needed, so both the lengths must be known.
Correct Option : D
Answer: D
Question: what is the compound interest on rs:50,000 for 4 months at the rate of 5% per annum
Options:
A)1058.24
B)2006.24
C)838.55
D)848.55
E)858.55
Rationale: it is monthly compound
rate=5/12% per month
50000*(1+5/1200)^4-50000=838.55
ANSWER:C
Answer: C
Question: Diana picked a number of pears, each of which she sold, canned, or poached. If she canned 60 percent more than she poached, and she poached 50 percent less than she sold. If there were a total of 115 pears, then how many pears did she sell?
Options:
A)41
B)44
C)47
D)50
E)53
Rationale: Let x be the amount of pears that she sold.
Then she poached 0.5x.
Then she canned 1.6*0.5x=0.8x.
The total amount of pears is x+0.5x+0.8x=2.3x
The fraction of pears that she sold is 1/2.3=10/23.
The number of pears she sold is (10/23)*115=50.
The answer is D.
Answer: D
Question: Find a number such that when 15 is subtracted from 7 times the number, the result is 10 more than twice the number.
Options:
A)1
B)3
C)5
D)7
E)9
Rationale: 7x-15=10+2x
7x-2x=25
x=5
ANSWER:C
Answer: C
Question: A and B together can do a work in 6 days. If A alone can do it in 15 days. In how many days can B alone do it?
Options:
A)10
B)99
C)77
D)55
E)21
Rationale: 1/6 – 1/15 = 1/10
=> 10
Answer: A
Answer: A