divelab/Sys2Bench huggingface dataset:
Question: A sun is divided among X, Y and Z in such a way that for each rupee X gets, Y gets 45 paisa and Z gets 50 paisa. If the share of Y is RS. 45, what is the total amount?
Options:
A)115
B)116
C)195
D)118
E)119
Rationale: x:y:z = 100:45:50
20:9:10
9 --- 45
39 --- ? => 195
ANSWER:C
Answer: C
Question: If (260)(3,000) = (78)(1,000^c), what is the value of c?
Options:
A)5
B)4
C)3
D)2
E)1
Rationale: (260)(3,000) = (78)(100^c)
=> (260)(3,000)/78 = 100^c
=> 10,000 = 100^c
=> 100^2 = 1,000^c
Since, base is same so powers will be same too.
So, c=2
Answer will be D
Answer: D
Question: The area of an isosceles trapezoid with sides of length 5 and bases of length 7 and 13 is?
Options:
A)40
B)41
C)42
D)43
E)44
Rationale: Isosceles trapezoid indicates that if we draw perpendicular from two vertex of the smaller side, the longer side with side 13 will be divided into 3 parts= 7, 3 and 3 (Making one square and two right triangles)
For the right triangle, height will be= (5^2-3^2)^1/2= 4
And the area of trapezoid = 1/2 (B1+B2)H= 1/2*20*4= 40
A
Answer: A
Question: Anil and Suresh are working on a special assignment. Anil needs 6 hours to type 32 pages on a computer and Suresh needs 5 hours to type 40 pages. If both of them work together on two different computers, how much time is needed to type an assignment of 150 pages?
Options:
A)11 hours 15 mins
B)8 hours
C)9 hours
D)7 hours
E)6 hours
Rationale: Pages typed by Anil in 1 hour = 32/6 = 16/3
Pages typed by Suresh in 1 hour = 40/5 = 8
Pages typed by Anil and Suresh in 1 hour = 16/3 + 8 = 40/3
Time taken to type 150 pages when Anil and Suresh work together = 150 × 3 /40 = 45/4
= 11 ¼ hours = 11 hour 15 minutes
Answer is A.
Answer: A
Question: Eight persons in an organization including X and Y were to be divided in two groups of 4 members each. The total number of groups containing both X and Y is what fraction of the total number of groups which can be formed?
Options:
A)1/4
B)3/14
C)4/14
D)1/10
E)11/14
Rationale: The fraction is nothing but the probability..
Number to choose 4 out of 8= 8C4..
Number to choose X and Y and 2 from remaining 6=6C2..
prob of X and Y choosen=6C2/8C4= {6!/4!2!}/{8!/4!4!}..
6!4!4!/8!4!2!=3/2*7=3/14
Answer : B
Answer: B
Question: Henry has to secure 70% marks to clear his exam of class 6th.
He got 110 marks and failed by 100 marks.
What is the maximum marks ?
Options:
A)200
B)300
C)400
D)500
E)600
Rationale: B
300
To pass the exam ravish needs 110 + 100 = 210 marks.
=> (210/70) *100 = 300
Answer: B
Question: In which year was the difference between Jyothi's and Arun's monthly income the second highest?
Options:
A)A76
B)66
C)27
D)28
E)11
Rationale: Answer:E
Answer: E
Question: The price of 3 pants and 6 t-shirts is Rs. 750. With the same money one can buy 1 pant and 12 t-shirts. If one wants to buy 8 t-shirts, how much shall she have to pay ?
Options:
A)150
B)250
C)400
D)450
E)550
Rationale: Let the price of a pant and a t-shirt be Rs. x and Rs. y respectively.
Then, 3x + 6y = 750 .... (i)
and x + 12y = 750 .... (ii)
Divide equation (i) by 3, we get the below equation.
= x + 2y = 250. --- (iii)
Now subtract (iii) from (ii)
x + 12y = 750 (-)
x + 2y = 250
----------------
10y = 500
----------------
y= 50
cost of 8 t-shirts = 8*50 = 400
Answer : C
Answer: C
Question: Each of the integers from 0 to 8, inclusive, is written on a separate slip of blank paper and the ten slips are dropped into hat. If the slips are then drawn one at a time without replacement, how many must be drawn to ensure that the numbers on two of the slips drawn will have a sum of 9?
Options:
A)3
B)4
C)5
D)6
E)7
Rationale: Answer is 6. In the worst case, you could end up drawing 0,1,2,3,4,5. th draw will result in either of 6,7,8 which would result in the numbers adding to 9.
D
Answer: D
Question: x and y are positive integers. If xy + 3x is odd, then which of the following must be even?
Options:
A)x
B)y
C)3 + y
D)xy − x
E)x^2 − y
Rationale: Given that xy + x is odd, which means x(y+3) is odd.
Product of two nos. will be odd only if both the nos. are odd.
Hence x is odd, y+3 is also odd.
y+3 is odd means y is even. Answer will be C.
Answer: C
Question: Evaluate : 2.5 + 0.0005
Options:
A)2000
B)3000
C)1000
D)5000
E)4000
Rationale: 25/0.0005 = (25*10000) / (0.0005*10000) = 25000 / 5 = 5000
Answer is D.
Answer: D
Question: The least number which when divided by 2, 3, 5 and 6 leaves a remainder 3, but when divided by 9 leaves no remainder, is
Options:
A)16
B)63
C)73
D)83
E)None of these
Rationale: Explanation:
L.C.M of 2, 3, 5, 6 = 30
therefore Required Number is of the form 30k+3.
Least value of k for which (30k+3) is divisible by 9 is k = 2
therefore Required Number = (30 x 2+3)=63. Answer: B
Answer: B
Question: Which of the following expressions CANNOT have a negative value
Options:
A)|a + b| + |a – b|
B)|a + b| – |a|
C)|2a + b| – |a + b|
D)a^2 - b^2 – 2|ab|
E)|a^3 + b^3| – a – b
Rationale: Whenever you are required to find if the equation is a perfect square or not, try to bring everything in the form of a perfect square as they are always positive.
Of the given options, only option D can be written in from of a perfect square.
|a + b| + |a – b|
This will always be positive.
Correct Option: A
Answer: A
Question: In 2008, the profits of Company N were 10 percent of revenues. In 2009, the revenues of Company N fell by 20 percent, but profits were 16 percent of revenues. The profits in 2009 were what percent of the profits in 2008?
Options:
A)80%
B)105%
C)120%
D)124.2%
E)128%
Rationale: x = profits
r= revenue
x/r = 0,1
x= 10
r=100
2009:
r=80
x/80 = 0,16 = 16/100
x= 80*16/100
x= 12.8
12.8/10 = 1,28 = 128%, Answer E
Answer: E
Question: Two identical circles intersect such that their centers and the points at which they intersect form a square of side 2 cm. What is the area of the region where the two circles intersect?
Options:
A)pi^2 - 2
B)2pi - 4
C)4 - pi
D)4 - pi/2
E)2 - pi/4
Rationale: Drawing a diagram, we see that the radius of the circle equals the side of the square.
The area of intersection is: pi*r^2/4 - (r^2-pi*r^2/4) = pi*r^2/2 - r^2 = 2pi - 4
The answer is B.
Answer: B
Question: Probability of Cristiano Ronaldo scoring a penalty is twice than the probability of missing it. In a World cup he takes 5 penalties, What is the probability of scoring 3 penalties among the 5?
a) 5 *2 *((2/3)^3 * (1/3)^2)
b) 1-((2/3)^3 * (1/3)^2)
c) 1-((2/3)^2 * (1/3)^3)
d) None of the above.
Options:
A)5 *2 *((2/3)^3 * (1/3)^2)
B)5 *2 *((2/3)^3 * (1/3)^9)
C)5 *2 *((2/3)^3 * (1/3)^7)
D)5 *2 *((2/3)^3 * (1/3)^5)
E)5 *2 *((2/3)^3 * (1/3)^1)
Rationale: Explanation:
We have to use Binomial distribution to solve this question as Ronaldo scoring penalty and not scoring penalty are Dichotomous in nature.
Success + Failure = 1
2x + x = 1
So x = 1/3
Probability of scoring a penalty = p = 2/3 and Not scoring it = q = 1/3
Probability of scoring exactly 'r' of 'n' trials = P(x=r)=nCr.pr.qn−rP(x=r)=nCr.pr.qn−r
P(x=3)=5C3.(23)3.(13)5−3P(x=3)=5C3.(23)3.(13)5−3
= 10.(23)3.(13)210.(23)3.(13)2
Answer:A
Answer: A
Question: The sum of two numbers is 66. How much should be added to the sum for it to be exactly divisible by 9 leaving 0 as the reminder?
Options:
A)6
B)7
C)8
D)9
E)1
Rationale: The sum is 66 .Adding 6 to 66 = 66+6=72.
72 is exactly divisible by 9 leaving 0 as the reminder=8. So the answer is A=6
Answer: A
Question: A completes a work in 6 days and B complete the same work in 12 days. If both of them work together, then the number of days required to complete the work will be?
Options:
A)4 days
B)11 days
C)21 days
D)22 days
E)24 days
Rationale: If A can complete a work in x days and B can complete the same work in y days, then, both
of them together can complete the work in x y/ x+ y days
Therefore, here, the required number of days = 6 Ã— 12/ 18 = 4 days.
Option 'A'
Answer: A
Question: In May, the grounds keeper at Spring Lake Golf Club built a circular green with an area of 64π square feet. In August, he doubled the distance from the center of the green to the edge of the green. What is the total area of the renovated green?
Options:
A)100PI
B)144PI
C)196PI
D)256PI
E)78
Rationale: AREA OF CIRCLE 64PI SQ FEET =PI R^2 THEREFORE R =8
NOW GREEN RADI DOUBLED I.E R =16 AREA =256 PI
D
Answer: D
Question: A can do a piece of work in 18 days, B in 27 days, C in 36 days. They start worked together . But only C work till the completion of work. A leaves 4 days and B leaves 6 days before the completion of work. In how many days work be completed?
Options:
A)12
B)15
C)14
D)13
E)11
Rationale: Explanation:
Let the work be completed in x days
(x-4)days of A + (x-6)days of B + x days of C = 1
=>x-4/18 + x-6/27 + x/36 = 1
=> 13 x-48 /108 =1
x=12
Total time = 12 days
ANSWER IS A
Answer: A
Question: A goods train runs at the speed of 72 km/hr and crosses a 280 m long platform in 26 sec. What is the length of the goods train?
Options:
A)278
B)166
C)151
D)240
E)109
Rationale: Speed = 72 * 5/18 = 20 m/sec.
Time = 26 sec.
Let the length of the train be x meters.
Then, (x + 280)/26 = 20
x = 240 m.
Answer:D
Answer: D
Question: If x and y are different prime numbers, each greater than 4, which of the following must be true?
I. x+y is an even integer
II. xy is an odd integer
III. (x/y) is not an integer
Options:
A)III only
B)I,II and III
C)I only
D)II only
E)I,II only
Rationale: This question tests your knowledge about the effect of addition and multiplication on odd and even numbers:
Even + Even = Even
Odd + Even = Odd
Odd + Odd = Even
Even * Even = Even
Odd * Even = Even
Odd * Odd = Odd
Given: x and y are different prime numbers, both greater than 4
Statement I: x+y is an even integer
Since x and y are prime numbers greater than 4, they will be odd
Therefore sum will be even.
Correct
Statement II: xy is an odd integer
Since x and y are prime numbers greater than 4, they will be odd
Therefore multiplication will be odd.
Correct
Statement III: (x/y) is not an integer
Since x and y are prime integers, therefore they will not have any common factor apart from 1
Hence (x/y) will not be an integer
Correct
Hence all three statements I, II and III are correct
Answer : B
Answer: B
Question: The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?
Options:
A)4 years
B)8years
C)10 years
D)12 years
E)None of these
Rationale: Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
5x = 20
x = 4.
Age of the youngest child = x = 4 years.
ANSWER:A
Answer: A
Question: A certain sum of money at simple interest amounted Rs.645 in 12 years at 5% per annum, find the sum?
Options:
A)403
B)410
C)500
D)340
E)455
Rationale: 645 = P [1 + (12*5)/100]
P = 403
Answer: A
Answer: A
Question: The ages of two persons differ by 16 years. 6 years ago, the elder one was 3 times as old as the younger one. What are their present ages of the elder person
Options:
A)22
B)66
C)77
D)30
E)88
Rationale: Let's take the present age of the elder person = x
and the present age of the younger person = x – 16
(x – 6) = 3 (x-16-6)
=> x – 6 = 3x – 66
=> 2x = 60
=> x = 60/2 = 30
Answer: D
Answer: D
Question: There are 11 women and 8 men in a certain club. If the club is to select a committee of 2 women and 2 men, how many different such committees are possible?
Options:
A)120
B)720
C)1,540
D)1,520
E)1,980
Rationale: Answer is E. Can somebody tell me what answer I may have found if I had added the 11C2 and 8C2 (55+28=83)?
I'm guessing that would've been the number of 2-member committees which had men and women separately. Is that right?
C
Answer: C
Question: a and b are positive integers less than or equal to 9. If a and b are assembled into the six-digit number abab, which of the following must be a factor of abab?
Options:
A)3
B)4
C)5
D)6
E)none of the above
Rationale: 4848 when divided by 3 gives the result 1212
CONCEPT: Rule of Divisibility of 4 isIf sum of the digits of the Number is divisible by 4 then the number will be divisible by 2
SUm of the digits of No. 4848 is 27 which is divisible by 4 hence the Number 4848 will be divisible by 4
B
Answer: B
Question: An alloy of copper and zinc contains copper and zinc in the ratio 3 : 5. Another alloy of copper and zinc contains copper and zinc in the ratio 6 : 2. In what ratio should the two alloys be mixed so that the resultant alloy contains equal proportions of copper and zinc?
Options:
A)1:2
B)2:2
C)2:5
D)2:6
E)2:7
Rationale: Let Alloy_1 be x units, and let Alloy_2 be y units.
So, fraction of copper in Alloy_1 = 3x/8, and fraction of zinc in Alloy_1 = 5x/8.
Similarly, fraction of copper in Alloy_2 = 6y/8, and fraction of zinc in Alloy_2 = 2y/8.
Mixing them, we get
copper = 3x/8 +6y/8; zinc = 5x/8 + 2y/8.
So, 3x+6y = 5x+2y
-> 2x = 4y
-> x/y = 2/4 = 1/2
So, they must be mixed in the ratio 1 : 2
Answer : A
Answer: A
Question: By selling 15 pencils for a rupee a man loses 25%. How many for a rupee should he sell in order to gain 25%?
Options:
A)8
B)9
C)7
D)6
E)4
Rationale: 75% --- 15
125% --- ?
75/125 * 15 = 9
Answer: B
Answer: B
Question: Find the value of 3/11 × [(1 + 1/3) (1 + 1/4) …………. (1 + 1/120)] is
Options:
A)11
B)13
C)15
D)17
E)19
Rationale: 3/11 × [(1 + 1/3) (1 + 1/4) ....... (1 + 1/120)]
3/11 × [4/3 + 5/4 × ........ 121/120]
3/11 × 4/3 × 5/4 × .... 121/120
121/11 = 11.
A)
Answer: A
Question: A sum of Rs. 2900 amounts to Rs. 3422 in 3 years. Had the rate of interest be 5% higher then what would the sum amount in the same time period?
Options:
A)Rs. 4465
B)Rs. 3683
C)Rs. 3596
D)Rs. 3857
E)None of these
Rationale: 3422=2900+(2900*R*3/100)
R=6
If R is 5 more.
Then R=11
Sum=2900+(2900*11*3/100)
Sum=3857
ANSWER:D
Answer: D
Question: A school bus travels from Veldhoven to Roosendaal. There are four children in the bus. Each child has four backpacks with him. There are four dogs sitting in each backpack. Every dog has four puppies with her. All these dogs have four legs, with four toes at each leg.
What is the total number of toes in the bus?
Options:
A)4789
B)5170
C)4902
D)4490
E)5538
Rationale: B
5170
The total number of toes is 5170.
The puppies: 4 children × 4 backpacks × 4 dogs × 4 puppies × 4 legs × 4 toes = 4096
Plus the dogs: 4 children × 4 backpacks × 4 dogs × 4 legs × 4 toes = 1024
Plus the children: 4 children × 2 legs × 5 toes = 40
Plus the driver of the school bus: 2 legs × 5 toes = 10
4096+1024+40+10 = 5170
This gives the following total number of toes: 5170
Answer: B
Question: An oblong piece of ground measures 19m 2.5dm by 12m 5dm. From the centre of each side a path 2m wide goes across to the centre of the opposite side. Find the cost of paving these paths at the rate of rs.1.32 per sq m?
Options:
A)Rs. 43.6
B)Rs. 78.65
C)Rs 54.75
D)Rs. 344
E)Rs. 34.4
Rationale: Area of path horizontal=20*192.5=3850 dm^2
Area of path vertical=20*125=2500 dm^2
Since center path is covered twice so total area=(3850+2500)-(20*20)=5950 dm^2
total cost=1.32*59.5 m^2=78.54
ANSWER:B
Answer: B
Question: x and y are positive integers. When x is divided by 17, the remainder is 3, and when x is divided by 19, the remainder is 1. When y is divided by 14, the remainder is 5, and when y is divided by 21, the remainder is 12. What is the least possible value of y - x?
Options:
A)15
B)13
C)11
D)14
E)18
Rationale: When x is divided by 17, the remainder is 3: So, the possible values of x are: 3, 20, 37,54 , etc.
When x is divided by 19, the remainder is 1: So, the possible values of x are: 1,20... STOP. Since both lists include 20, the smallest possible value of x is 20.
When y is divided by 14, the remainder is 5: So, the possible values of y are: 5, 19, 33,47 etc.
When y is divided by 21, the remainder is 12: So, the possible values of y are: 12, 33, ...STOP. Since both lists include 33, the smallest possible value of y is 33
Since the smallest possible values of x and y are 20 and 33 respectively, the smallest possible value of y - x is 13. So,B is the correct answer to the original question.
Answer: B
Question: Insert the missing number
100,91,....,76,70
Options:
A)82
B)83
C)84
D)81
E)80
Rationale: Missing number: 83
Answer: B
Answer: B
Question: 1/(√2-1)=?
Options:
A)9+4√5
B)9-4√5
C)√2+1
D)9-2√5
E)4+9√5
Rationale: This question requires us to rationalize (fix) the denominator.
For more on this technique, seehttps://www.gmatprepnow.com/module/gmat ... video/1044
Given: 1/(√2-1)
Multiply top and bottom by the CONJUGATE of √2-1, which is √2+1
So, 1/(√2-1) = (1)(√2+1)/(√2-1)(√2+1)
= (√2+1)/(1)
= √2+1
=
C
Answer: C
Question: what will be the next number in the following series??
4,18,...,100,180,294
Options:
A)32
B)36
C)40
D)44
E)48
Rationale: 2x2x1=4;
3x3x2=18;
4x4x3=48;
5x5x4=100;
6x6x5=180;
7x7x6=294;
so answer is 48.
ANSWER:E
Answer: E
Question: Two machines, Y and Z, work at constant rates producing identical items. Machine Y produces 13 items in the same time Machine Z produces 14 items. If machine Y takes 28 minutes to produce a batch of items, how many minutes does it take for machine Z to produce the same number of items?
Options:
A)26
B)9
C)9 1/2
D)12
E)13 1/2
Rationale: rate z/rate y=14/13
time z/time y=13/14
(13/14)*28=26 minutes
A
Answer: A
Question: A sequence consists of 16 consecutive even integers written in increasing order. The sum of the first 8 of these even integers is 472. What is the sum of the last 8 of the even integers?
Options:
A)588
B)594
C)600
D)606
E)612
Rationale: The sum of the first 8 numbers is: x + (x+2) +...+ (x+14) = 472
The sum of the next 8 numbers is: (x+16) + (x+2+16) +...+ (x+14+16) =
472 + 8(16) = 472 + 128 = 600
The answer is C.
Answer: C
Question: Last year, a certain public transportation system sold an average (arithmetic mean) of 41,000 tickets per day on weekdays (Monday through Friday) and an average of 15,000 tickets per day on Saturday and Sunday. Which of the following is closest to the total number of tickets sold last year?
Options:
A)1 million
B)1.25 million
C)10 million
D)12.2 million
E)125 million
Rationale: If you type that into the calculator, it results in 12.3 mil
[D], 12.2 mil, is the correct answer... see 2 posts above for quick approx method
Answer: D
Question: The sum of all the integers s such that -26 < s < 24 is
Options:
A)0
B)-2
C)-25
D)-49
E)-51
Rationale: Easy one -
-25, -24, -23,-22,...... -1,0, 1, 2...., 22, 23
Cancel everyhitng and we're left with - -25 and -24 s= -49.
D is the answer.
Answer: D
Question: If (x – 2)^2 = 144, which of the following could be the value of 2x?
Options:
A)–26
B)–22
C)–11
D)12
E)-20
Rationale: You can also get to the answer by backsolving using answer choices
Starting with x = -10
(x – 2)^2 = 144
(-10– 2)^2 = 144 =====> (-12)^2 = 144 Bingo, Clearly, among the answer choices only -10 will result in 144 in the equation so x must be -10,
Then 2x = 2 * -10 = -20
Answer: E
Answer: E
Question: 3 workers transfer a tool weighing 120kg in 12 seconds. How many men are required to transfer it in 9 seconds?
Options:
A)4
B)5
C)6
D)7
E)8
Rationale: We have, M1D1H1 = M2D2H2
3*120*12 = M2*120*9
M2 = 3*120*12/120*9 = 4
ANSWER:A
Answer: A
Question: A batch of cookies was divided amomg 6 tins: 2/3 of all the cookies were placed in either the blue or the green tin, and the rest were placed in the red tin. If 1/4 of all the cookies were placed in the blue tin, what fraction of the cookies that were placed in the other tins were placed in the green tin
Options:
A)15/2
B)9/4
C)5/9
D)5/7
E)9/7
Rationale: This will help reduce the number of variables you have to deal with:
G + B = 2/3
R = 1/6
B = 1/4
We can solve for G which is 5/12
What fraction (let it equal X) of the cookies that were placed in the other tins were placed in the green tin?
So..
X*(G+R)=G
X*(5/12 + 1/6) = 5/12
X = 5/7
ANSWER: D
Answer: D
Question: Each child has 12 crayons and 24 apples. If there are 18 children, how many crayons are there in total?
Options:
A)220
B)65
C)216
D)219
E)230
Rationale: 12*18=216.Answer is C.
Answer: C
Question: A bag is bought for Rs.400 and sold at a gain of 35% find its selling price
Options:
A)A)Rs.460/-
B)B)Rs.470/-
C)C)Rs.480/-
D)D)Rs.500/-
E)E)Rs.520/-
Rationale: 100 % ------> 400 (100 * 4 = 400)
135 % ------> 540 (135 * 4 = 540)
Selling price = Rs.540
Answer : E
Answer: E
Question: If x and y are different prime numbers, each greater than 8, which of the following must be true? I. x+y is an even integer II. xy is an odd integer III. (x/y) is not an integer
Options:
A)I,II only
B)I,III only
C)II,III only
D)I,II and III
E)II only
Rationale: Given: x and y are different prime numbers, both greater than 8
Statement I: x+y is an even integer
Since x and y are prime numbers greater than 8, they will be odd
Therefore sum will be even.
Correct
Statement II: xy is an odd integer
Since x and y are prime numbers greater than 8, they will be odd
Therefore multiplication will be odd.
Correct
Statement III: (x/y) is not an integer
Since x and y are prime integers, therefore they will not have any common factor apart from 1
Hence (x/y) will not be an integer
Correct
Hence all three statements I, II and III are correct
Answer : D
Answer: D
Question: In an examination, 25% of total students failed in Hindi, 35% failed in English and 40% in both. The percentage of these who passed in both the subjects is :
Options:
A)10%
B)20%
C)60%
D)80%
E)50%
Rationale: pass percentage = 100 - (25+35-40) = 100-20 = 80
ANSWER:D
Answer: D
Question: Ramesh starting from a fixed point goes 15 km towards North and then after turning to his right he goes 15 km. then he goes 10, 15 and 15 metres after turning to his left each time. How far is he from his starting point?
Options:
A)8 km
B)9 km
C)10 km
D)11 km
E)12 km
Rationale: he will be 10 km. away from his starting point.
ANSWER:C
Answer: C
Question: Copper is 7 times as heavy as water and gold is 13 times as heavy as water. In what ratio should these be mixed to get an alloy 11 times as heavy as water ?
Options:
A)2 : 1
B)1 : 2
C)2 : 3
D)3 : 2
E)3 : 1
Rationale: Explanation :
Solution: C = 7W and G = 13W.
Let 1 gm of copper be mixed with x gm of gold to get (1+x)gm of alloy.
(1gm copper)+(xgm gold) = (x+1)gm of alloy.
=>7W+13W*x = (x+1)*11W
=> 7+13x = 11(x+1)
=> 2x = 4 => x = 2.
.'. Ratio of copper and gold = 1 : 2
Answer : B
Answer: B
Question: A train running at the speed of 60 km/hr crosses a pole in 12 seconds. What is the length of the train?
Options:
A)200 metres
B)180 metres
C)324 metres
D)228 metres
E)150 metres
Rationale: Speed= 60 x	5/18	m/sec	= 50/3	m/sec.
Length of the train = (Speed x Time).
Length of the train = 50/3	x 9	m = 200 m.
Option A
Answer: A
Question: The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 43 kg, what is the weight of B?
Options:
A)31 kg
B)28 1/2 kg
C)32 kg
D)30 1/2 kg
E)32 kg
Rationale: Explanation:
Let the weight of A, B and C are a,b and c respectively.
Average weight of A,B and C = 45
a + b + c = 45 × 3 = 135 --- equation(1)
Average weight of A and B = 40
a + b = 40 × 2 = 80 --- equation(2)
Average weight of B and C = 43
b + c = 43 × 2 = 86 --- equation(3)
equation(2) + equation(3) - equation(1)
=> a + b + b + c - (a + b + c) = 80 + 86 - 135
=> b = 80 + 86 -135 = 166 - 135 = 31
Weight of B = 31 Kg
Answer: Option A
Answer: A
Question: A milk man sells the milk at the cost price but he mixes the water in it and thus he gains 9.09%. The quantity of water in the mixture of 1 liter is?
Options:
A)83.33 ml
B)12.33 ml
C)77.33 ml
D)22.33 ml
E)18.33 ml
Rationale: Profit (%) = 9.09 % = \inline \frac{1}{11}
Since the ratio of water and milk is 1 : 11,
Therefore the ratio of water is to mixture = 1:12
Thus the quantity of water in mixture of 1 liter =
{1}/{12} = 83.33 ml
Answer: A
Answer: A
Question: Three years ago the average age of a class of six members was 23 years. A boy have been added, the average age of the class is the same today. What is the age of the boy?
Options:
A)A)1
B)B)2
C)C)3
D)D)4
E)E)5
Rationale: 6 * 26 = 156
7 * 23 = 161
`5
E
Answer: E
Question: A train 220 m long is running with a speed of 90 km/hr. In what time will it pass a bus that is running with a speed of 60 km/hr in the direction opposite to that in which the train is going?
Options:
A)4.37
B)5.28
C)6.75
D)8
E)3.1
Rationale: Speed of train relative to bus = 90 + 60 = 150 km/hr.
= 150 * 5/18 = 125/3 m/sec.
Time taken to pass the bus = 220 * 3/125
= 5.28 sec.
Answer: B
Answer: B