divelab/Sys2Bench huggingface dataset:
Question: The difference between a positive proper fraction and its reciprocal is 9/20. The fraction is?
Options:
A)4/5
B)4/7
C)5
D)5/7
E)None
Rationale: Let the required fraction be x. Then 1 - x = 9
x 20
1 - x2 = 9
x 20
20 - 20x2 = 9x
20x2 + 9x - 20 = 0
20x2 + 25x - 16x - 20 = 0
5x(4x + 5) - 4(4x + 5) = 0
(4x + 5)(5x - 4) = 0
x = 4/5
Option A
Answer: A
Question: In a certain mathematical activity, we start with seven cards, each with a different prime number written on it. These seven cards are randomly put into three boxes in the following way: one box must get four cards, one must get two, and one gets only one. Then, for each box, we find the product of all the cards in the box, and that’s the “number” of the box. Then, we put those three numbers in order, from lowest to highest, and that is our set. How many different sets T can be created from this process?
Options:
A) 35
B) 105
C) 210
D) 420
E) 630
Rationale: T=7C4 * 3C2 = 105 Answer B.
7C4 ways to choose 4 numbers for Box 1
3C2 ways to choose 2 numbers for Box2
1 way for Box 3 .
every combination will give a different product and can be arranged least to highest only in one way .B
Answer: B
Question: If the volume of a cube is x^3 cubic units, what is the number of square units in the surface area of the cube?
Options:
A)x^2
B)x^3
C)x^6
D)6x^2
E)6x^3
Rationale: The question basically asks you to calculate the surface area of the cube.
Volume of the cube = x^3
This means each side of the cube = x
Hence area of each side = x^2
Total surfaces in a cube = 6
Total surface area = 6*x2
Correct Option: D
Answer: D
Question: If x is a positive integer, which of the following must be odd?
Options:
A)x+1
B)x^2+x
C)x^2+x+9
D)x^2−1
E)3x^2−3
Rationale: A. X+1 = can be odd or even. Since O + O =E or E + O = O
B. X^2 + X = X(X+1). Since from the above derivation we already know the term X+1 can be Odd or Even, directly substitute here. X(ODD) = Even (When X is Even) or X(EVEN) = EVEN [When X is ODD]
C. Here's the answer. Since we know the term x^2 + X can always take a EVEN number, EVEN + 9 = ODD
Hence C.
Answer: C
Question: The total marks obtained by a student in Mathematics and Physics is 60 and his score in Chemistry is 10 marks more than that in Physics. Find the average marks scored in Mathamatics and Chemistry together.
Options:
A)35
B)30
C)25
D)Data inadequate
E)None of these.
Rationale: Let the marks obtained by the student in Mathematics, Physics and Chemistry be M, P and C respectively.
Given , M + C = 60 and C - P = 10 M + C / 2 = [(M + P) + (C - P)] / 2 = (60 + 10) / 2 = 35.
ANSWER:A
Answer: A
Question: A train 325 m long passed a pole in 25 sec. How long will it take to pass a platform 900 m long?
Options:
A)76 sec
B)94 sec
C)87 sec
D)75 sec
E)96 sec
Rationale: Speed = 325/25 = 13 m/sec.
Required time = (325 + 900)/13
= 94 sec.
Answer:B
Answer: B
Question: 48% of respondents to a survey consisted of those who used both M and N and those who used neither M nor N. 41% of respondents did not use M. 38% used N. What percent of respondents used only N?
Options:
A)19.5%
B)21.5%
C)20%
D)15.5%
E)17.5%
Rationale: From the question, we can summarize the information as follows:
N Not N
M X
Not M Ans y 41
38 100
Then we can set a system of 3 equations 3 unknowns described below:
X + Y = 48
X + Ans = 38
Y + Ans = 41
Sum up all three equations to get 2X + 2Y + 2Ans = 127
Divide both sides by 2 to get X + Y + Ans = 63.5
Replace X + Y with 48 to get 48 + Ans = 63.5
Substract 48 from both sides to get Ans = 63.5 - 48 = 15.5
The answer must be D.
Answer: D
Question: A player holds 13 cards of four suits, of which seven are black and six are red. There are twice as many diamonds as spades and twice as many hearts as diamonds. How many clubs does he hold ?
Options:
A)4
B)5
C)6
D)7
E)8
Rationale: D=2S
H=2D =4S
C+S+2S+4S=13;C+7S=13
2S+4S=6S =6
S=1
C=6
ANSWER:C
Answer: C
Question: Mangala completes a piece of work in 10 days, Raju completes the same work in 12 days. If both of them work together, then the number of days required to complete the work is?
Options:
A)5.5 days
B)6.5 days
C)7.5 days
D)8.5 days
E)9.5 days
Rationale: If A can complete a work in x days and B can complete the same work in y days, then, both
of them together can complete the work in x y/ x+ y days.
That is, the required No. of days = 10 Ã— 12/22 = 5.5 days.
A)
Answer: A
Question: Two bullet trains of equal lengths take 8 seconds and 15 seconds respectively to cross a telegraph post. If the length of each bullet train be 120 metres, in what time (in seconds) will they cross each other travelling in opposite direction?
Options:
A)13 sec.
B)10.4 sec.
C)12 sec.
D)17 sec.
E)19 sec.
Rationale: Speed of the first bullet train = 120/8 m/sec = 15 m/sec.
Speed of the second bullet train = 120/15 m/sec = 8 m/sec.
Relative speed = (15 + 8) = 23 m/sec.
Required time = (120 + 120)/23 sec = 10.4 sec.
B
Answer: B
Question: Two machines, Y and Z, work at constant rates producing identical items. Machine Y produces 30 items in the same time Machine Z produces 38 items. If machine Y takes 19 minutes to produce a batch of items, how many minutes does it take for machine Z to produce the same number of items?
Options:
A)6
B)9
C)9 1/2
D)15
E)13 1/2
Rationale: rate z/rate y=38/30
time z/time y=30/38
30/38*19= 15 minutes
D
Answer: D
Question: If the annual increase in the population of a town is 10% and the present number of people is 15000, what will the population be in 2 years?
Options:
A)12100
B)15240
C)18150
D)18452
E)19002
Rationale: The required population is = 15000 (1 + 10/100)^2
= 15000 * 11/10 * 11/10
= 18150
Answer is C
Answer: C
Question: Machine A and machine B are each used to manufacture 550 sprockets. It takes machine A 10 hours longer to produce 550 sprockets than machine B. Machine B produces 10 percent more sprockets per hour than machine A. How many sprockets per hour does machine A produces?
Options:
A)6
B)5
C)7
D)8
E)9
Rationale: Machine B: Takes x hours to produce 550 sprockets
Machine A: Takes (x+10) hours to produce 550 sprockets
Machine B: In 1 hour, B makes 550/x sprockets
Machine A: In 1 hour, A makes 550/(x+10) sprockets
Equating:
1.1(550/(x+10)) = 550/x
605/(x+10) = 550/x
605x = 550x+5500
55x = 5500
x = 100
A makes 550/(110) = 5 sprockets per hour
Answer : B
Answer: B
Question: R and S start walking each other at 10 AM at the speeds of 3 km/h and 4 km/h respectively. They were initially 17.5 km apart. At what time do they meet?
Options:
A)2 : 30 PM
B)11 : 30 AM
C)1 : 30 PM
D)12 : 30 PM
E)None of these
Rationale: Let after t hours they meet then,
3t + 4t = 17.5 ⇒ t = 25
∴ Time = 10 am + 2.5 h = 12 : 30 am
Answer D
Answer: D
Question: 3 buffaloes eat as much as 4 cows or 2 oxen. At a farm, there are 15 buffaloes, 8 oxen, and 24 cows. The fodder for these cattle is available for 24 days. If 60 more cows and 30 more buffaloes are brought in, how many days will the fodder last?
Options:
A)6
B)9
C)12
D)15
E)18
Rationale: 2 oxen = 3 buffaloes = 4 cows
Also: 15 buffaloes + 8 oxen + 24 cows
= 10 oxen + 8 oxen + 12 oxen = 30 oxen
There is enough fodder for 1 oxen for 30*24 days.
60 cows + 30 buffaloes = 30 oxen + 20 oxen = 50 oxen
The new total is equal to 80 oxen instead of 30 oxen.
30*24 / 80 oxen = 9 days
The answer is B.
Answer: B
Question: Tom and Linda stand at point A. Linda begins to walk in a straight line away from Tom at a constant rate of 3 miles per hour. One hour later, Tom begins to jog in a straight line in the exact opposite direction at a constant rate of 8 miles per hour. If both Tom and Linda travel indefinitely, what is the positive difference, in minutes, between the amount of time it takes Tom to cover half of the distance that Linda has covered and the amount of time it takes Tom to cover twice the distance that Linda has covered?
Options:
A)60
B)72
C)84
D)96
E)108
Rationale: D is the answer....
D = TS where D=distance, T=Time and S=Speed
To travel half distance, (2+3T) = 8T ==> T = 2/5 ==> 24 minutes
To travel double distance, 2(2+3T) = 8T ==> 2 ==> 120 minutes
Difference, 96 minutes
D
Answer: D
Question: The area of a sector of a circle of radius 5 cm formed by an arc of length 4 cm is?
Options:
A)8.78
B)8.67
C)8.75
D)10
E)8.28
Rationale: (5 * 4)/2
= 10
Answer:D
Answer: D
Question: A merchant gets a 5% discount on each meter of fabric he buys after the first 2,000 meters and a 7% discount on every meter after the next 1,500 meters. The price, before discount, of one meter of fabric is $2, what is the total amount of money the merchant spends on 5,500 meters of fabric?
Options:
A)$7,360
B)$8,540
C)$9,720
D)$10,570
E)$11,680
Rationale: For first 2000 meters he does not get any discount.
The price is 2*2000 = $4000
For next 1500 meters, he gets a 5% discount.
The price is 1.9*1500 = $2850
For the next 1500 meters, he gets a 7% discount.
The price is 1.86*2000 = $3720
The total price is $4000 + $2850 + $3720 = $10,570
The answer is D.
Answer: D
Question: Find (7x + 2y ) / (x-2y) if x/2y = 3/2 ?
Options:
A)23
B)25
C)26
D)27
E)29
Rationale: x/2y=3/2
=>x=6y/2=3y
=>(7x+2y)/(x-2y)=((7*(3y))+2y)/(3y-2y)
=>23y/y=23
ANSWER:A
Answer: A
Question: If A can finish a work in 12 days and B can finish same work in 15 days.then they together can finish that work in how many days?
Options:
A)15
B)12
C)20/3
D)8
E)10/3
Rationale: A work in 1 hour=1/12,B work in 1 hour=1/15
[A+B] work in 1 hour=[1/12+1/15] = 3/20
Time take by both to finish the work=20/3hour
Answer C
Answer: C
Question: Convert the following units:
(a) 60 cm² in mm²
Options:
A)600 mm²
B)1600 mm²
C)6000 mm²
D)600 mm²
E)6600 mm²
Rationale: 60 cm² in mm²
1 cm = 10 mm
1 cm² = 100 mm²
Therefore, 60 cm² = 60 × 100 mm²
= 6000 mm²
ANSWER : OPTION C
Answer: C
Question: The ratio between the perimeter and the width of a rectangle is 5 : 1. If the area of the rectangle is 294 sq. cm, what is the length of the rectangle?
Options:
A)15 cm
B)18 cm
C)21 cm
D)24 cm
E)27 cm
Rationale: 2L+2W = 5W
L = 3W/2
W*L = 294
3W^2/2 = 294
W^2 = 196
W = 14
L = 3(14)/2 = 21
The answer is C.
Answer: C
Question: A and B ran, at their respective constant rates, a race of 480 m. In the first heat, A gives B a head start of 48 m and beats him by 1/10th of a minute. In the second heat, A gives B a head start of 144 m and is beaten by 1/30th of a minute. What is B’s speed in m/s?
Options:
A)12
B)14
C)16
D)18
E)20
Rationale: Let x be the speed of B.
Write the equation:
(480-48)/x (time of B for first heat) - 6 (seconds, time B lost to A first heat) = TIME OF A (in both heats A runs with constant rate, so the time for first and second heats are the same)=(480-144)/x (time of B for second heat) + 2 (seconds, time B won to A second heat)
(480-48)/x-6=(480-144)/x+2
x=12
Answer: A.
Answer: A
Question: a factory produce certain no of car a day finds that increase in production efficiency by 12 1/2% then they produce 20 cars per day.how many cars produced in a day when their efficiency is 20% less
Options:
A)12
B)13
C)14
D)15
E)16
Rationale: et effi. is x
x+(25x/1000=20
or, x=18(apprx)
now, x-(20% of x)= 18-(20% of 18)=14
ANSWER:C
Answer: C
Question: The equation relates the values (R - 3)/28 = (S + 8)/35 of two linked currencies, where R is the value in dollars of one currency and S is the value in dollars of the other currency. Which of the following equations can be used to convert dollar values from the R currency to the S currency?
Options:
A)S = (5R - 47)/4
B)S = (4R + 47)/5
C)S = (5R + 17)/4
D)S = (4R - 17)/5
E)S = 5R/4 - 12
Rationale: R - 3)/28 = (S + 8)/35
(R - 3)/4 = (S + 8)/5
5(R - 3)/4 = s+8.
5R-47/4 = S
Option A.
Answer: A
Question: Simple interest on a certain sum at a certain annual rate of interest is 1/3 of the sum. If the numbers representing Time is three times the Rate percent , then the Rate is:
Options:
A)1 1/3 %.
B)2 1/3 %.
C)3 1/3 %.
D)4 1/3 %.
E)5 1/3 %.
Rationale: Explanation :
Let sum = x. Then, S.I. = x/3
Let N =3R
[x * 3R * R / 100] = x/3? R^2 = 100/9
R = 10/3 = 3 1/3%.
Hence, Rate = 3 1/3 %.
Answer : C
Answer: C
Question: The third smallest prime number is?
Options:
A)67
B)71
C)79
D)83
E)89
Rationale: The third smallest prime number is 79.
C)
Answer: C
Question: One out of every 2000 computer chips is defective. If 2 out of every 30 defective chips have defective processors and there are 30 defective processors in the first batch, how many computer chips are there in the first batch?
Options:
A)450
B)900
C)90,000
D)450,000
E)900,000
Rationale: (D) Read the whole question to get the feel of what they are asking you to find. Then start with the smallest amount and work your way outwards. We are told that two out of every 30 defective chips have a defective processor. Let x be the total number of defective processors in the batch. Because we know 2 out of every 30 defective chips will have defective processors, and the total number of defective processors in the batch is 30, we can write out an equation: (2/30)x = 30. This can be simplified to (1/15)x = 30. Multiplying each side by 15, we arrive at x = 450. This tells us that there are 450 defective chips in the whole batch. Because we know that 1 out of every 1000 chips is defective, we can set up a proportion. If 1 out of every 2000 chips is defective, then 450 out of y chips would be defective, where y is the total number of chips in the batch. This can be set up as an equation as follows: 1/2000 = 450/y. Solve for y and you will get the total number of chips in the batch: 900,000.
The answer is (E).
Answer: E
Question: In what ratio should two varieties of sugar of Rs.18 per kg and Rs.24 kg be mixed together to get a mixture whose cost is Rs.20 per kg?
Options:
A)1:3
B)3:1
C)1:2
D)2:1
E)3:4
Rationale: Explanation:
=4:2=2:1
ANSWER IS D
Answer: D
Question: Mary has a monthly salary of $1200. She spends $280 per month on food. What percent of her monthly salary does she spend on food?
Options:
A)22%
B)23%
C)24%
D)25%
E)26%
Rationale: Solution to Problem 2:
The part of her salary that is spent on food is $280 out of her monthly salary of $1200
percent = part / whole = 280 / 1200 = 0.23 (rounded to 2 decimal places)
Multiply and divide 0.23 by 100 to convert in percent
percent = 0.23 * 100 / 100 = 23 / 100 = 23%
Answer B
Answer: B
Question: If X = the product of four distinct prime numbers, how many factors does X have besides 1 and itself?
Options:
A)10
B)11
C)12
D)13
E)14
Rationale: Let's take the four primes: 2, 3, 5 and 7 --> each of the 4 primes will be a factor of the product
All the possible combinations of the four primes will be factors (10 possible combinations):
2x3
2x5
2x7
3x5
3x7
5x7
2x3x5
2x3x7
2x5x7
3x5x7
Thus, in total there are 10 + 4 = 14 factors.
ANSWER:E
Answer: E
Question: What should come in place of the question mark (?) in the following equation?
12400 + 6899 = 610+ ?
Options:
A)12345
B)56894
C)18689
D)23478
E)94561
Rationale: 12400 + 6899 = 610+ ?
12400 + 6899 – 610 = 18689
Answer C
Answer: C
Question: A person can row at 9 kmph and still water. He takes 8 1/2 hours to row from A to B and back. What is the distance between A and B if the speed of the stream is 1 kmph?
Options:
A)60 km
B)87 km
C)38 km
D)67 km
E)20 km
Rationale: Let the distance between A and B be x km.
Total time = x/(9 + 1) + x/(9 - 1) = 8.5
=> x/10 + x/8 = 17/2 => (4x + 5x)/40 = 17/2 => x
= 38 km.
Answer:C
Answer: C
Question: The compound interest accrued on an amount of Rs.44000 at the end of two years is Rs.1193.60. What would be the simple interest accrued on the same amount at the same rate in the same period?
Options:
A)Rs.10176
B)Rs.10287
C)Rs.10560
D)Rs.10227
E)Rs.11827
Rationale: Explanation:
Let the rate of interest be R% p.a.
4400{[1 + R/100]2 - 1} = 11193.60
[1 + R/100]2 = (44000 + 11193.60)/44000
[1 + R/100]2 = 1 + 2544/1000 = 1 + 159/625
[1 + R/100]2 = 784/625 = (28/25)2
1 + R/100 = 28/25
R/100 = 3/25
Therefore R = 12 SI on Rs.44000 at 12% p.a. for two years = 44000(2)(12)/100
=Rs.10560
Answer: C
Answer: C
Question: A test has 120 questions. Each question has 5 options, but only 1 option is correct. If test-takers mark the correct option, they are awarded 1 point. However, if an answer is incorrectly marked, the test-taker loses 0.25 points. No points are awarded or deducted if a question is not attempted. A certain group of test-takers attempted different numbers of questions, but each test-taker still received the same net score of 40. What is the maximum possible number of such test-takers?
Options:
A)11
B)13
C)15
D)17
E)19
Rationale: A correct answers get you 1 point, an incorrect answer gets you MINUS 1/4 point and a skipped question gets you 0 points. Since there are 200 total questions, there are a variety of ways to get a total of 40 points.
Let C be the number of correct answers and let I be the number of incorrect answers.
To get 40 points, a test taker must have at least 40 correct answers. Then C=> 40.
For every correct question above 40, the test taker has 4 incorrect answers.
Then, the I = 4*(C - 40).
Also, I + C <= 120. Thus 5C <= 280 and so C <= 56.
Then 40 <= C <= 56 and C can have 17 possible values.
The answer is D.
Answer: D
Question: A man can reach certain place in 50hours. If he reduces his speed by 1/10th, he goes 400km less in time. Find his speed?
Options:
A)20km/hr
B)30km/hr
C)40km/hr
D)80km/hr
E)60km/hr
Rationale: Let the speed be x km/hr
50x-50* 9/10 *x = 400
50x - 45x = 400
5x = 400
x = 80km/hr
Answer is D
Answer: D
Question: A shopkeeper loses 15%,if an article is sold for Rs. 102. What should be the selling price of the article to gain 20%?
Options:
A)Rs.147
B)Rs.148
C)Rs.144
D)Rs.129
E)Rs.112
Rationale: Given that SP = Rs. 102 and loss = 15%
CP = [100(SP)]/(100 - l%) = (100 * 102)/85 = 20 * 6
= Rs. 120.
To get 20% profit, New SP = [(100 + p%)CP]/100
= (120 * 120)/100
= Rs.144
Answer:C
Answer: C
Question: The sum of the ages of 5 children born at the intervals of 3 year each is 60 year. what is the age of the eldest child ?
Options:
A)4 year
B)18 year
C)10 year
D)None of these
E)9 year
Rationale: Solution
let the ages of the children be x,(x + 3),(x + 6),(x + 9) and (x + 12) year.
then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 60 â‡” 5 x = 30 â‡” x= 6.
âˆ´ Age of the eldest child = x +12= 6 +12 =18 years. Answer B
Answer: B
Question: There are 35 students in a hostel. If the no. of students increases by 7, the expenses of the mess increase by Rs.42/day while the average expenditure per head diminishes by Rs1. Find the original expenditure of the mess?
Options:
A)Rs. 34
B)Rs. 39
C)Rs. 42
D)Rs. 48
E)Rs. 49
Rationale: Suppose the average join the mess , total expenditure = 35x + 42
Now, the average expenditure = (35x + 42)/ (35 + 7) = x – 1
or, 35x + 42 = 42x – 42
or, x = 12
Thus the original expenditure of the mess = 35 x 12 = Rs. 42
C
Answer: C
Question: Total number of people attending a party is 600. 70% of the men are wearing black shirt and rest are wearing red. If 60% of the total people are women then how many men are wearing red shirts?
Options:
A)168
B)72
C)56
D)170
E)60
Rationale: Number of woman in the party = 0.60*600 = 360
number of men in the party = 600-360 = 240
% of men wearing red shirts = 100-70 = 30%
number of men wearing red shirt = 0.30*240 = 72. B is the correct answer
Answer: B
Question: Find the odd man out
253, 136, 352, 327, 631, 244
Options:
A)327
B)136
C)352
D)631
E)531
Rationale: The sum all three digits comes to 10 except 327
ANSWER:A
Answer: A
Question: The average weight of 10 men is increased by 2 ½ kg when one of the men who weighs 58 kg is replaced by a new man. What is the weight of the new man?
Options:
A) 80 kg
B) 83 kg
C) 70 kg
D) 75 kg
E) 85 kg
Rationale: Since the average has increased by 2.5 kg, the weight of the man who stepped in must be equal to 58+10x2.5
58+25=83 Kg
Ans: 'B'
Answer: B
Question: The speeds of 3 trains in the ratio 3:9:12. The ratio between time taken by them to travel the same distance is?
Options:
A)12:4:3
B)1:2:3
C)4:8:9
D)6:5:2
E)4:8:7
Rationale: Ratio of time taken is = 1/3 : 1/9 : 1/12 = 12:4:3
Answer is A
Answer: A
Question: Ram has passed his exam of 5 subject in 85% of marks. He has gotten 90, 75, 98 and 72 marks in four subjects. Therefore what is his marks in the fifth subject?
Options:
A)75
B)85
C)95
D)90
E)84
Rationale: EXPLANATION
Total marks of 4 subjects = (90 + 75 + 98 + 72 ) = 335
Marks of 5th subject = [ (85 x 5) – 335 ]
= (425 – 335)
= 90.
Answer D
Answer: D
Question: A grocer has a sale of Rs. 2500, Rs. 6500, Rs. 9855, Rs. 7230 and Rs. 7000 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 7500?
Options:
A)s. 49180
B)s. 49910
C)s. 11915
D)s 6997
E)s. 5000
Rationale: Total sale for 5 months = Rs. (2500 + 6500 + 9855 + 7230 + 7000 ) = Rs. 33085.
Required sale = Rs. [ (7500 x 6) -33085]
= Rs. (45000 - 33085)
= Rs. 11915.
C
Answer: C
Question: The cost price of 16 articles is equal to the selling price of 11 articles. Find the profit percent?
Options:
A)48 2/91%
B)45 5/11%
C)48 9/11%
D)48 2/91%
E)42 2/11%
Rationale: 16 CP = 11 SP
11 --- 2 CP
100 --- ? =>45 5/11%
Answer:B
Answer: B
Question: Pat, Kate, and Mark charged a total of 144 hours to a certain project. If Pat charged twice as much time to the project as Kate and 1/3 as much time as Mark, how many more hours did Mark charge to the project than Kate?
Options:
A)18
B)80
C)72
D)90
E)108
Rationale: 80
all u do is do
2:1:6=>2x+x+6x=144=>x= 16
32:16:96
96-16=80
Answer B
Answer: B
Question: How many number of weights do u need to weigh 31 kg of rice if u have only one 1kg weights stone ?
Options:
A)30
B)31
C)5
D)4
E)3
Rationale: first measure 1kg rice by 1 kg weight
then use this 2kg (1kg rice+ 1 kg weight) to measure 2kg rice
now combine this to get 3kg rice + 1 kg weight to measure 4 kg rice
add this newly measure 4kg + 3kg + 1kg weight to measure 8 kg
add this 8kg+ 4kg + 3kg + 1kg weight to measure 16 kg rice
now combining all u get 31 kg rice + 1 kg weight
so the answer is 5
ANSWER:C
Answer: C
Question: If tuesday falls on 4th of month, then which day will fall three days after the 24th ?
Options:
A)SUNDAY
B)tuesday
C)monday
D)thursday
E)friday
Rationale: Explanation:
The 4th day is tuesday, then 11, 18, 25th also tuesdays
Then 3 days after 24th is 27th, which is thursday
Answer: D) thursday
Answer: D
Question: If the sum of two numbers is 42 and their product is 437, then find the
absolute difference between the numbers.
Options:
A)2
B)4
C)3
D)1
E)0
Rationale: Let the numbers be x and y. Then, x + y = 42 and xy = 437
x - y = sqrt[(x + y)2 - 4xy] = sqrt[(42)2 - 4 x 437 ] = sqrt[1764 – 1748] = sqrt[16] = 4.
Required difference = 4.
Answer is B.
Answer: B
Question: A student got 74% in math and 84% in history. To get an overall average of 75%, how much should the student get in the third subject?
Options:
A)61%
B)63%
C)65%
D)67%
E)69%
Rationale: 74 + 84 + x = 3*75
x = 67
The answer is D.
Answer: D
Question: In one hour, a boat goes 11 km along the stream and 7 km against the stream. the sped of the boat in still water (in km/hr) is :
Options:
A)3
B)5
C)8
D)9
E)10
Rationale: Solution
Speed in still water= 1/2(11+7) km/hr= 9kmph. Answer D
Answer: D
Question: The current birth rate per ten thousand is 620, whereas corresponding death rate is 110 per ten thousand. The net growth rate in terms of population increase in percent is given by
Options:
A)6.5
B)4.5
C)5.5
D)5.2
E)5.1
Rationale: Sol.
Net growth on 1000 = (620 - 110) =510.
Net growth on 100 = (510/10000 Ã— 100)% = 5.1%.
Answer: E
Answer: E
Question: The cash difference between the selling prices of an article at a profit of 4% and 6% is Rs. 3. The ratio of the two selling prices is:
Options:
A)51:52
B)52:53
C)51:53
D)52:55
E)53:54
Rationale: Explanation:
Let C.P. of the article be Rs. x.
Then, required ratio = 104% of x / 106% of x
= 104/106 = 52/53 = 52:53
ANSWER IS B
Answer: B
Question: Find the odd man out. 1, 4, 9, 16, 25, 37, 49, 64, 81
Options:
A)16
B)25
C)37
D)49
E)81
Rationale: Explanation :
Each of the given numbers except 37 is a perfect square
Answer : Option C
Answer: C
Question: A father said to his son, "I was as old as you are at the present at the time of your birth". If the father's age is 38 years now, the son's age five years back was:
Options:
A)14 years
B)19 years
C)33years
D)38 years
E)3 years
Rationale: Let the son's present age be x years. Then, (38 - x) = x
2x = 38.
x = 19.
Son's age 5 years back (19 - 5) = 14 years.
ANSWER:A
Answer: A