divelab/Sys2Bench huggingface dataset:
Question: A train 175 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
Options:
A)49
B)50
C)12
D)13
E)68
Rationale: Speed of the train relative to man = (175/10) m/sec = (35/2) m/sec. [(35/2) * (18/5)] km/hr = 63 km/hr. Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr. x - 5 = 63 ==> x = 68 km/hr.
Answer: Option E
Answer: E
Question: The radius of a circle is increased by 1%. Find how much % does its area increases?
Options:
A)2.07%
B)2.71%
C)2.05%
D)2.01%
E)2.02%
Rationale: r = 100 r = 101
r2 = 10000 r2 = 10201
10000 ---- 201
100 ---- ? => 2.01%
Answer: D
Answer: D
Question: A person takes 5hrs 45 min in walking to a place and riding back. He would have gained 6 hrs by riding both ways. The time he would take to walk both ways is?
Options:
A)5 hours 45 min
B)5 hours 55 min
C)6 hours 45 min
D)11 hours 45 min
E)12 hours
Rationale: ----------------------------------------------------------------
Solution 1
----------------------------------------------------------------
Given that time taken for riding both ways will be 6 hours lesser than
the time needed for waking one way and riding back
From this, we can understand that
time needed for riding one way = time needed for waking one way - 6 hours
Given that time taken in walking one way and riding back = 5 hours 45 min
Hence The time he would take to walk both ways = 5 hours 45 min + 6 hours = 11 hours 45 min
D
Answer: D
Question: For any integer k greater than 1, the symbol k* denotes the product of all the fractions of the form 1/t, where t is an integer between 1 and k, inclusive. What is the value of 3*/5* ?
Options:
A)5
B)5/4
C)4/5
D)1/4
E)1/5
Rationale: When dealing with 'Symbolism' questions, it often helps to 'play with' the Symbol for a few moments before you attempt to answer the question that's asked. By understanding how the Symbol 'works', you should be able to do the latter calculations faster.
Here, we're told that K* is the PRODUCT of all the fractions of the form 1/T, where T is an integer between 1 and K, inclusive.
Based on this definition....
IF....
K = 2
K* = (1/1)(1/2) = 1/2
IF....
K = 3
K* = (1/1)(1/2)(1/3) = 1/6
We're asked to find the value of 5*/4*
Now that we know how the Symbol 'works', solving this problem shouldn't be too difficult. You can actually choose to do the math in a couple of different ways....
5* = (1/1)(1/2)(1/3)(1/4)(1/5)
Don't calculate this just yet though....since we're dividing by 4*, many of those fractions will 'cancel out.'
4* = (1/1)(1/2)(1/3)(1/4)
We're looking for the value of:
(1/1)(1/2)(1/3)(1/4)(1/5) / (1/1)(1/2)(1/3)(1/4)
Since the first four fraction in the numerator and denominator cancel out, we're left with just one fraction:
5/3
B
Answer: B
Question: The owner of a furniture shop charges his customer 24% more than the cost price. If a customer paid Rs. 8339 for a computer table, then what was the cost price of the computer table?
Options:
A)2789
B)2772
C)1991
D)6725
E)2099
Rationale: CP = SP * (100/(100 + profit%))
= 8339(100/124) = Rs. 6725.
Answer: D
Answer: D
Question: If two negative numbers are multiplied the product is 150. If the lesser of the two is 35 less than triple the greater number, what is the greater number?
Options:
A)-14
B)-13
C)-17
D)-12
E)-15
Rationale: Test the options. The options give you the greater number. Start from the middle option.
(C) - 17
Triple of -17 is -51 and 35 less is -16.
-16 * -17 = 272 (Not correct)
...
(E) - 15
Triple of 15 is -45 and 35 less is -10.
-10 * -15 = 150
Correct
Answer (E)
Answer: E
Question: The length of a rectangle is two - fifths of the radius of a circle. The radius of the circle is equal to the side of the square, whose area is 1225 sq.units. What is the area (in sq.units) of the rectangle if the rectangle if the breadth is 12 units?
Options:
A)140 sq.units
B)170 sq.units
C)190 sq.units
D)168 sq.units
E)149 sq.units
Rationale: Explanation:
Given that the area of the square = 1225 sq.units
=> Side of square = √1225 = 35 units
The radius of the circle = side of the square = 35 units Length of the rectangle = 2/5 * 35 = 14 units
Given that breadth = 12 units
Area of the rectangle = lb = 14 * 12 = 168 sq.units
Answer: Option D
Answer: D
Question: 66 cubic centimetres of silver is drawn into a wire 1 mm in diameter. The length of the wire in metres will be:
Options:
A)66
B)84
C)80
D)72
E)68
Rationale: Let the length of the wire be h.
Radius =1/2mm=1/20cm.	Then,
(22/7)x (1/20) x (1/20) x h = 66.
h = (66 x 20 x 20 x 7)/22 = 8400 cm = 84 m.
ANSWER B
Answer: B
Question: Mixture of milk & water has been kept in two separate bowl. Ratio of milk to water in one of the bowls is 5 : 1 and that in the other bowl 7 : 2. In what ratio the mixtures of these 2 bowl should be added together so that the quantity of milk in the new mixture may become 80%?
Options:
A)2:3
B)1:3
C)2:5
D)3:7
E)4:5
Rationale: Lett. mixtures of the two containers be added together in the ratio of x
= = [ixoox l00%
Since the percentage quantity ofmilk in the new mixture is SO% — so% (45x + 42y) x 5 4 x 54(x y) 225x 210y 216.3E+216y
9x=6y
x:y=2:3
A
Answer: A
Question: The sale price sarees listed for Rs.390 after successive discount is 15% and 25% is?
Options:
A)298
B)237
C)248
D)876
E)291
Rationale: 390*(85/100)*(75/100)
= 248
Answer: C
Answer: C
Question: In a market there are men and horses. In all, there are 22 heads and 66 feet. How many men and how many horses are in the market?
Options:
A)8 men and 14 horses.
B)7 men and 14 horses.
C)6 men and 14 horses.
D)5 men and 14 horses.
E)11 men and 11 horses.
Rationale: 11 men and 11 horses.
Let M = men and H = horses. We can come up with 2 equations.
M + H = 22
2M + 4H= 66
Solving the 2 equations will give 11 men and 11 horses.
Answer E
Answer: E
Question: A train met with an accident 80km away from station A. It completed the remaining journey at 5/6th of the original speed and reached station B 1hr 12mins late. Had the accident taken place 60km further, it would have been only 1hr late. what was the original speed of the train?
Options:
A)60 km/hr
B)55 km/hr
C)65 km/hr
D)80 km/hr
E)48 km/hr
Rationale: let the original speed be 6x. A/q, traveling 80 km at 5/6th of original speed costs him 12 minutes etc
80/5x =80/6x +12/60 -> x =10 , 8x= 80.
Ans D
Answer: D
Question: An investor deposited $10,000 to open a new savings account that earned 12 percent annual interest, compounded quarterly. If there were no other transactions in the account, what was the amount of money in the account 6 months after the account was opened?
Options:
A)$10,300
B)$10,303
C)$10,600
D)$10,609
E)$10,900
Rationale: The amount in the account after 6 months is 1.03*1.03($10,000) = $10,609.
The answer is D.
Answer: D
Question: In a deck of cards there are 52 cards numbered from 1 to 13. There are 6 cards of each number in the deck. If you insert 12 more cards with the number 10 on them and you shuffle the deck really good, what is the probability to pull out a card with a number 10 on it?
Options:
A)1/4.
B)4/17.
C)5/29.
D)4/13.
E)9/32
Rationale: 6+12 tens/52+12 total cards=18/64=9/32
E
Answer: E
Question: A coin is tossed twice if the coin shows head it is tossed again but if it shows a tail then a die is tossed. If 8 possible outcomes are equally likely. Find the probability that the die shows a number greater than 4, if it is known that the first throw of the coin results in a tail
Options:
A)2/4
B)1/3
C)2/3
D)3/6
E)1/4
Rationale: Sample space S = { HH, HT, T1, T2, T3, T4, T5, T6 }
Let A be the event that the die shows a number greater than 4 and B be the event that the first throw of the coin results in a tail then,
A = { T5, T6 }
B = { T1, T2, T3, T4, T5, T6 }
Required probability = ( 2/8)/(6/8)=1/3
ANSWER:B
Answer: B
Question: The average of six results is 15 and that of the first five is 13. The sixth result is?
Options:
A)20
B)25
C)15
D)22
E)18
Rationale: 6 * 15 â€“ 5 * 13 = 25
Answer: B
Answer: B
Question: The average of 10 numbers is 40.2. Later it is found that two numbers have been wrongly copied. The first is 18 greater than the actual number and the second number added is 13 instead of 31. Find the correct average.
Options:
A)40.2
B)40.4
C)40.6
D)40.8
E)None of the above
Rationale: Sum of 10 numbers = 402
Corrected sum of 10 numbers
= 402 – 13 + 31 – 18 = 402
Hence, new average = 402⁄10 = 40.2
Answer A
Answer: A
Question: The numbers in which of the following pairs do NOT have a pair of distinct prime divisors in common ?
Options:
A)10 and 20
B)12 and 18
C)24 and 32
D)21 and 63
E)22 and 88
Rationale: 32 has only one prime 2 (32=2^5) in its prime factorization, so it can not have a PAIR of distinct prime divisors in common with ANY of the numbers.
Answer: C.
Answer: C
Question: The difference between the value of a number increased by 12.5% and the value of the original number decreased by 25% is 30. What is the original number E?
Options:
A)60
B)80
C)40
D)120
E)160
Rationale: (1 + 1/8)x - (1 - 1/4)x = 30
(9/8)x - (3/4)x = 30
x = 80=E
Answer: B
Answer: B
Question: There are 16 teams in the hockey league, and each team faces all the other teams 10 times each. How many games are played in the season?
Options:
A)750
B)900
C)1050
D)1200
E)1350
Rationale: The number of ways to choose two teams is 16C2 = 16*15/2 = 120
The total number of games in the season is 10*120 = 1200.
The answer is D.
Answer: D
Question: Out of the five integral numbers C is the average of A and D. B is greater than C and less than D.Also B is the average of A and E . The middle most number in the sequence ?
Options:
A)A
B)B
C)C
D)D
E)E
Rationale: D _ C _ A --------(1)
D > B > C --------(2)
from (1) and (2)
D > B > C > A ---------(3)
Again E _ B _ A
But B > A, from (3)
So E > D > B > C > A [ Since B is the average of E and A so it is eqidistant from both E and A]
Answer: B
Answer: B
Question: At what rate percent per annum will the simple interest on a sum of money be 4/5 of the amount in 10 years?
Options:
A)4%
B)7%
C)8%
D)3%
E)1%
Rationale: Let sum = x. Then, S.I. =4x/5, Time
= 10 years.
Rate = (100 * 4x) / (x * 5 * 10)
= 8%
Answer: C
Answer: C
Question: Three pipes A,B and C are attached to a tank.A and B can fill it in 20 and 30 minutes respectively while C can empty it in 15 minutes.If A,B and C are kept open successively for 1 minute each, how soon will the tank be filled?
Options:
A)165 min
B)166 min
C)167 min
D)168 min
E)169 min
Rationale: the term successively and NOT SIMULTANEOUSLY.AT THE END OF 3 mts, i/60 part of the tank is filled.we have to consider a three-minute block starting from 3 mts, 6 mts,9 mts....etc upto 177 mts. at the end of 165 mts,55/60 part of the tank was filled. at the end of the next suceessive minutes,i.e, 166,167th minute, the part filled is 5/60.so 55/60+5/60. this means the whole tank is filled at the end of 167 th minute.
ANSWER:C
Answer: C
Question: A certain club has exactly 5 new members at the end of its first week. Every subsequent week, each of the previous week's new members (and only these members) brings exactly L new members into the club. If y is the number of new members brought into the club during the twelfth week, which of the following could be y?
Options:
A) 5^1/12
B) 3^11 * 5^11
C) 3^12 * 5^12
D) 3^11 * 5^12
E) 60^12
Rationale: At the end of the first week, there are 5 new members;
At the end of the second week, there are 5L new members (since each 5 new members from the previous week brings L new members);
At the end of the third week, there are 5L^2 new members (since each 5L new members from the previous week brings L new members);
...
At the end of the twelfth week, there are 5L^11 new members (since each 5L^10 new members from the previous week brings L new members).
We are given that 5L^11=y. Out of the answers only D yields integer value for L: 5L^11=3^11 * 5^12 --> L=3*5=15.
Answer: D.
Answer: D
Question: a' and 'b' are positive integers such that their LCM is 20 and their HCF is 1. What is the addition between the maximum and minimum possible values of 'a - b'?
Options:
A)0
B)12
C)24
D)26
E)18
Rationale: possible values of a and b can be 5,4; 4,5 and 1,20; 20,1
maximum possible value for a-b is 20-1=19
minimum possible value for a-b is 1-20=-19
19-19=0 ans is A
Answer: A
Question: A train running at the speed of 60 km/hr crosses a pole in 9 sec. What is the length of the train?
Options:
A)28
B)27
C)299
D)277
E)150
Rationale: Speed = 60 * 5/18 = 50/3 m/sec
Length of the train = speed * time = 50/3 * 9
= 150 m
Answer: E
Answer: E
Question: A book club rented the party room of a local restaurant to meet and discuss its current novel over dinner. The total charge, including food and service, was $ 950. If each member of the club paid at least $ 42, then what is the greatest possible number of members in the club?
Options:
A)19
B)20
C)21
D)25
E)23
Rationale: Given: Each person spends $42.
By looking at the options, we see that if there were 20 members, each person will spend atleast $42.
Hence the greatest number of members = 22.6. Option E
Answer: E
Question: what is the value of (4)^-6 ?
Options:
A)1/1008
B)1/6400
C)1/6550
D)1/6660
E)1/4096
Rationale: 4^-6= 1/(4)^6= 1/4096
ANSWER:E
Answer: E
Question: Set B consists of the following unique integers: -2, 17, 3, n, 2, 15, -3, and -27; which of the following could be the median of set B?
Options:
A)6
B)4
C)1
D)7
E)76
Rationale: Whenever a question asks you to deal with the MEDIAN of a group of numbers, you MUST put the numbers in order from least to greatest (or at the very least,group offthe numbers so that you can restrict the potential value of the median).
Here, we have 8 values (one of the values is the variable N). We're told that the values are UNIQUE, so N CANNOT be any of the other 7 values listed. We're asked which of the following answers COULD be the median, so if we determine that one of the answer choices is a POSSIBLE median, then we can stop working....
Since the group includes 8 values, the median will be the AVERAGE of the 4th and 5th values...
Putting the 7 numbers in order, we have:
-27, -3, -2, 2, 3, 15, 17
This means that the2will either be the 4th term or the 5th term (depending on the value of N).
IF....
N is REALLY BIG, then the 4th and 5th terms will be 2 and 3, so the median will = 2.5
N is REALLY SMALL, then the 4th and 5th terms will be -2 and 2, so the median will = 0
Neither of those answers is among the choices though, so N must be something relativelycloseto 2.....
IF....
N = 0, then the 4th and 5th terms will be 0 and 2, so the median will = 1. That answer IS among the choices, so we're done.
C
Answer: C
Question: A baker filled with a measuring cup with a cup water. He poured 1/2 of the water into the batter, and then spilled 1/8 of the water on the floor. How much water will the baker needed to add what is left in the cup to have 50% more than what he started with?
Options:
A)1/8 cup
B)3/8 cup
C)1/4 cup
D)1/2 cup
E)9/8 cup
Rationale: 3/4 is the original water in cup .half in batter.So left is 3/8 out which 1/8 is spilled out.So again left with 2/8.
so 50% more than what he started was = 8/8+1/2*(3/4)=11/8
Amount of water needed to add = 11/8 - 2/8=9/8
ANSWER:E
Answer: E
Question: One thief entered a cave where he found a pile of diamonds. At first he thought of taking all. But listening to his conscience he thought of taking only half of them. But while returning he picked up two more from the pile. After that Second thief entered the cave and bagged half of remaining diamonds and picked up two more while returning. Later third thief entered and did the same. Even the fourth thief did the same. When the fifth thief entered he found only one diamond in the cave. How many diamonds are there in the cave at first.
Options:
A)74
B)75
C)76
D)77
E)78
Rationale: When 5th thief entered-1 diamond
When 4th thief entered -(1+2)*2=6 diamonds
When 3rd thief entered -(6+2)*2=16 diamonds
When 2nd thief entered -(16+2)*2=36 diamonds
When 1st thief entered -(36+2)*2=76 diamonds
ANSWER:C
Answer: C
Question: If 11.25 m of a uniform steel rod weighs 42.75 kg. what will be the weight of 8 m of the same rod?
Options:
A)22.8 kg
B)25.6 kg
C)28 kg
D)30.4 kg
E)None of these
Rationale: Explanation :
Let the required weight be x kg. Then, Less length, Less weight (Direct Proportion)
=> 11.25 : 8 :: 42.75 : x
=> 11.25 x x = 8 x 42.75
=> x = (8 x 42.75) / 11.25
=> x = 30.4
Answer : D
Answer: D
Question: A set of 13 different integers has median of 25 and a range of 25. What is greatest possible integer that could be in this set?
Options:
A)32
B)37
C)40
D)43
E)41
Rationale: The correct answer is E.
A set of 13 different integers has median of 25 and a range of 25. What is greatest possible integer that could be in this set?
Given 15 different integers, lets say
n1, n2, n3, n4, n5, n6, n7, n8, n9, n10, n11, n12, n13, n14, n15
Also given median is 25 i.e. n8 = 25
n1, n2, n3, n4, n5, n6, n7, 25, n9, n10, n11, n12, n13, n14, n15
As each integer is different we need to find the maximum values for all those numbers before the median.
the maximum value n7 can have is one less then the median i.e. 24, similarly n6 will be one less than 24 i.e. 23 ... using this process the values for all number before the median would be..
18, 19, 20, 21, 22, 23, 24, 25, n9, n10, n11, n12, n13, n14, n15
Also given the range is 25 i.e. n15 - n1 (18) = 23
The maximum value n15 can have is 23+ n1 (18) = 41
E
Answer: E
Question: Of the 10 temporary employees in a certain company, 4 will be hired as permanent employees. If 5 of the 12 temporary employees are women, how many of the possible groups of 4 employees consist of 3 women and one man?
Options:
A)22
B)50
C)56
D)70
E)105
Rationale: another approach :
one scenario : [WWWM]
now we have 5 ways for the first women , 4 ways for the 2nd women and , 3 ways for the third women.
and 5 ways to select one man
so 5*4*3*5 = 300
now the three women are same so combinations with win them are irrelevant the 3 women can we arranged in 3! ways
hence 300/3!= 300/6=50
B
Answer: B
Question: I had a certain amount of candies with me. I gave half of them with one more to my first son. Then, I gave the remaining half with one more to the younger son. Now I was left with just one candy.
How much candies did I have in the beginning?
Options:
A)10
B)15
C)22
D)25
E)12
Rationale: A
I had 10 candies in the beginning.
Explanation:
Let us take and solve this problem in the reverse direction.
At the end, I was left with 1 candy. Let me take the extra one candy back from my younger son. Now since I gave him half of what I had, we must be having the same number of candies. I have 2, which means he also have 2. This implies that I was left with 4 candies after I gave some to the elder son.
Let me take back the extra candy from my elder son now. Now I have 5 candies. Since I gave him half of what I had, he must be having 5 candies as well. Thus, I had 10 candies in the beginning.
Answer: A
Question: Two employees X and Y are paid a total of Rs. 550 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?
Options:
A)Rs.250
B)Rs.280
C)Rs.290
D)Rs.299
E)Rs.300
Rationale: Let the amount paid to X per week = x
and the amount paid to Y per week = y
Then x + y = 550
But x = 120% of y = 120y/100 = 12y/10
∴12y/10 + y = 550
⇒ y[12/10 + 1] = 550
⇒ 22y/10 = 550
⇒ 22y = 5500
⇒ y = 5500/22 = 500/2 = Rs.250
A
Answer: A
Question: Three numbers are in the ratio 3:4:5 and their L.C.M. is 1800. Their H.C.F is?
Options:
A)20
B)30
C)40
D)50
E)60
Rationale: Let the numbers be 3x,4x and 5x
their L.C.M. = 60x
60x = 1800
x = 30
The numbers are 3*30 , 4*30 , 5*30
Hence required H.C.F. = 30
Answer is B
Answer: B
Question: There are some pigeons and hares in a zoo. If heads are counted, there are 200. If legs are counted, there are 880. The number of hares in the zoo is?
Options:
A)90
B)99
C)77
D)66
E)240
Rationale: 200*2 = 400
880
-----
480
1----2
?----480 = 240
Answer:E
Answer: E
Question: A and B complete a work in 3 days. A alone can do it in 9 days. If both together can do the work in how many days?
Options:
A)3.75 days
B)4.75 days
C)3.25 days
D)3.15 days
E)2.75 days
Rationale: 1/3 + 1/9 = 4/9
9/4 = 4.75 days
Answer: B
Answer: B
Question: There are 11 cans in the refrigerator. 6 of them are red and 5 of them are blue. In how many ways we can remove 8 cans so that at least one red and at least one blue cans to remain the refrigerator.
Options:
A)460
B)490
C)493
D)455
E)445
Rationale: Answer: E
Answer: E
Question: What is the probability, to 3 decimal places, that at least two people in a room share the same birthday if there are eleven people in the room? (Assume nobody was born on a leap year)
Options:
A)0.027
B)0.03
C)0.076
D)0.141
E)0.271
Rationale: First, find the probability that nobody has the same birthday: 364/365 * 363/365 * 362/365 * ... * 356/365 * 355/365 = 0.859. Then the correct answer is 1 - 0.859 = 0.141, so the correct answer is D
Answer: D
Question: The average of first 10 natural numbers is?
Options:
A)5.7
B)5.5
C)5.4
D)5.2
E)5.9
Rationale: Sum of 10 natural no. = 110/2
= 55
Average = 55/10
=5.5
Answer: B
Answer: B
Question: A farmer is planting a row consisting of 4 unique apple trees and 5 unique orange trees. How many ways are there for the farmer to plant the trees such that no apple tree is adjacent to another apple tree and no orange tree is adjacent to another orange tree?
Options:
A)512
B)5760
C)1,024
D)1,152
E)10,080
Rationale: 2 possible arrangements are possible
AOAOAOAO
OAOAOAOA
2 unique type of trees are present consisting of 4 trees each
4 apple trees can be arranged in 4! ways
4 orange trees can be arranged in 4! ways
as 2 arrangements are possible
total arrangements = 2 *4! * 5! = 5760
correct answer option B
Answer: B
Question: A tap can fill a tank in 6 hours. After half the tank is filled three more similar taps are opened. What is the total time taken to fill the tank completely?
Options:
A)3 hrs 48 min
B)3 hrs 45 min
C)3 hrs 85 min
D)3 hrs 75 min
E)3 hrs 25 min
Rationale: Time taken by one tap to fill the tank = 3 hrs.
Part filled by the taps in 1 hour = 4 * 1/6 = 2/3
Remaining part = 1 - 1/2 = 1/2
2/3 : 1/2 :: 1 : x
x = 1/2 * 1 * 3/2 = 3/4 hrs. i.e., 45 min
So, total time taken = 3 hrs 45 min.
Answer: B
Answer: B
Question: A man can row 7 ½ kmph in still water.if in a river running at 1.5 km/hr an hour,it takes him 50 minutes to row to a place and back,how far off is the place?
Options:
A)1.5 km
B)1 km
C)2.5km
D)2 km
E)3 km
Rationale: Speed downstream =(7.5+1.5)km/hr=9 km/hr;
Speed upstream=(7.5-1.5)kmph=6kmph.
Let the required distance be x km.then,
x/9+x/6=50/60.
2x+3x=(5/6*18)
5x=15
x=3.
Hence,the required distance is 3km.
Answer is E.
Answer: E
Question: In an election between two candidates, the winner has a margin of 10% of the votes polled. If 4000 people change their mind and vote for the loser, the loser would have won by a margin of 10% of the votes polled. Find the total number of votes polled in the election?
Options:
A)16000
B)10000
C)40000
D)12000
E)5000
Rationale: Winner - Looser
55% - 45%
If 4000 people change their mind and vote for the loser:
Winner - Looser
45% - 55%
Thus 4,000 people compose 25% of all voters, which means that the total number of votes is
40,000
Answer: C
Answer: C
Question: A father said to his son, "I was as old as you are at the present at the time of your birth". If the father's age is 48 years now, the son's age five years back was:
Options:
A)A)14
B)B)67
C)C)19
D)D)89
E)E)34
Rationale: Let the son's present age be x years. Then, (48 - x) = x
2x = 48.
x = 24.
Son's age 5 years back (24 - 5) = 19 years.
Answer:C
Answer: C
Question: What is the probability for a family with four children to have a girl and three boys (assuming the probability of having a boy or a girl is equal)?
Options:
A)1/2
B)1/3
C)1/4
D)1/8
E)1/16
Rationale: One possible case is: girl - boy - boy - boy
The probability of this is 1/2*1/2*1/2*1/2 = 1/16
There are 4C3 = 4 such cases so we should multiply by 4.
P(one girl and three boys) = 4/16 = 1/4
The answer is C.
Answer: C
Question: Tom opened a shop investing Rs.3000. Jose joined him 2 months later, investing Rs.4000. They earned a profit of Rs.4230 after completion of one year. What will be Jose's share of profit?
Options:
A)2000
B)2200
C)2309
D)2350
E)3250
Rationale: SoL = ~s- So Anju’s share = [5/9] x 4230 = 2350
D
Answer: D