divelab/Sys2Bench huggingface dataset:
Question: A club with a total membership of 40 has formed 3 committees, M, S and R, which have 8, 12 and 5 members respectively. If no members of committee M is on either of the other 2 committees, what is the greatest possible number of members in the club who are on none of the committees?
Options:
A)5
B)7
C)8
D)10
E)20
Rationale: As no member of committee M is on either of the other 2 committees then 40-M=40-8=32 people are on committee S, committee R or on none of the committee. We want to maximize the last group: members in the club who are on none of the committees
General rule for such kind of problems:
to maximize one quantity, minimize the others;
to minimize one quantity, maximize the others.
So we should minimize total # of people who are on committee S and committee R. Now if ALL 5 people who are the members of committee R are also the members of committee S (if R is subset of S) then total # members of committee S and committee R would be minimized and equal to 12. Which means that 32-12=20 is the greatest possible number of members in the club who are on none of the committees.
Answer: E.
Answer: E
Question: In a school with 640 students, the average age of the boys is 12 years and that of the girls is 11 years. If the average age of the school is 11 years 9 months, then the number of girls in the school is
Options:
A)160
B)200
C)250
D)350
E)None
Rationale: Sol.
Let the number of grils be x.
Then, number of boys = (640 - x).
Then, (11 3/4 × 640)
⇔ 11x + 12(640 - x) ⇔ x = 7680 - 7520 ⇔ 160.
Answer A
Answer: A
Question: The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).
Options:
A)8, 20, 28
B)16, 28, 36
C)20, 35, 45
D)None of these
E)cannot be determined
Rationale: EXPLANATION
Let their present ages be 4x, 7x and 9x years respectively.
Then, (4x – 8) + (7x – 8) + (9x – 8) = 56
20x = 80
x = 4.
Their present ages are 4x = 16 years, 7x = 28 years and 9x = 36 years respectively.
Answer B
Answer: B
Question: Tap ‘A’ can fill a water tank in 25 minutes, tap ‘B’ can fill the same tank in 40 minutes and tap ‘C’ can empty that tank in 30 minutes. If all the three taps are opened together, in how many minutes will the tank be completely filled up or emptied?
Options:
A)3 2⁄13
B)15 5⁄13
C)8 2⁄13
D)31 11⁄19
E)None of these
Rationale: Tank filled in 1 minute = 1⁄25 + 1⁄40 - 1⁄30 part
= 24+15−20/600=19/600 part
∴ tank will be filled complete in minutes
= 600⁄19 = 3111⁄19
Answer D
Answer: D
Question: A is twice as fast as B. If B alone can do a piece of work in 30 days, in what time can A and B together complete the work?
Options:
A)12
B)10
C)27
D)24
E)92
Rationale: A can do the work in 30/2 i.e., 15 days.
A and B's one day's work = 1/15 + 1/30 = (2 + 1)/30 = 1/10
So A and B together can do the work in 10 days.
Answer:B
Answer: B
Question: If x is a positive, single-digit integer such that 4/3*x, 2x, x, and x + 3, and 3x – 2 form a non-ordered list of consecutive integers, which of the following could be the median of that list?
Options:
A)3
B)4
C)5
D)6
E)8
Rationale: The big hints are thatx is a 1-digit integerAND (4/3)x, 2x, x, and x + 3, and 3x – 2 are ALLintegers
For (4/3)x to be an integer, x MUST BE A MULTIPLE OF 3. So, x can equal 3, 6, or 9.
Now let's plug each possible value of x into the terms and see which one yields a list ofconsecutive integers
When x =3, we get the following terms: (4/3)(3), 2(3),3,3+ 3, and 3(3) – 2.
When we evaluate these terms we get: 4, 6, 3, 6 and 7
Rearrange to get: 3, 4, 6, 6, 7. So, when x = 3, we getconsecutive integers.
In this case, the MEDIAN = 5
Since 5 is among the answer choices, we need not test the other 2 values of x (i.e., x = 6 and x = 9)
Answer:
D
Answer: D
Question: Becky sets up a hot dog stand in her busy neighborhood and purchases x pounds of hot dogs for v dollars per pound. If she has to throw away s pounds of hot dogs due to spoilage and she sells the rest of the hot dogs for d dollars per pound, which of the following represents the net profit on the sale of the hot dogs?
Options:
A)(x – s)v – sd
B)xv – (xd – sd)
C)xd – sv
D)(x – s)d – xv
E)(s – v)d – xv
Rationale: Answer D:
The amount of hotdogs she can sell is x-s. The price per pound is d, so the revenue is (x-s)d. The total costs are x time v, so the profit is (x-s)d-xv.
Answer: D
Question: From below option 50 is divisible by which one?
Options:
A)3
B)2
C)7
D)8
E)9
Rationale: 50/2 = 25
B
Answer: B
Question: The figure above shows the dimensions of a semicircular cross section of a one-way tunnel. The single traffic lane is 12 feet wide and is equidistant from the sides of the tunnel. If vehicles must clear the top of the tunnel by at least ½ foot when they are inside the traffic lane, what should be the limit U on the height of vehicles that are allowed to use the tunnel?
Options:
A)5½ ft
B)7½ ft
C)8 ½ ft
D)9½ ft
E)10 ft
Rationale: Let's label the midpoint of the circle O. Since the base of the semi-circle is 20, we know that the diameter is 20 and, accordingly, the radius is 10.
We also know that the traffic lane is 12 feet long and there's an equal amount of space on either side, so the traffic lane extends 6 feet on either side of O. Let's call the leftmost point on the base of the traffic lane A. So, the distance OA is 6.
Now draw a line straight up from A to the top of the tunnel. Let's label the point at which the line intersects the circle B. The answer to the question will, therefore, be the height AB - .5 feet (we need to leave .5 feet of clearance).
Here's the key to solving the question: if we draw a line from O to B, that line is a radius of the circle and, therefore, has length 10. We now have right triangle OAB (the right angle is at point A), with leg OA=6 and hypotenuse OB=10. We can now solve for leg AB=8 (either by applying the pythagorean theorum or by applying the 3/4/5 special right triangle ratio).
Finally: AB=8, so the correct answer U is 8 - .5 = 7.5... choose (B)!
From a strategic guessing point of view, as soon as we realize that the height of the tunnel is 10 in the middle, we should quickly eliminate (D) and (E) as too big; worse case you have a 1/3 shot at picking up the points.B
Answer: B
Question: Find the value of 18396 x 9999 = m?
Options:
A)194852714
B)183941604
C)183851704
D)183951714
E)183768244
Rationale: 18396 x 9999 = 18396 x (10000 - 1)
= 18396 x 10000 - 18396 x 1
= 183960000 - 18396
= 183941604
B
Answer: B
Question: Which of the following is closest to 10^180 – 10^10 ?
Options:
A)10^210
B)10^90
C)10^150
D)10^180
E)10^6
Rationale: 10^180 – 10^10
10^10 * (10^170 – 1)
as we know 10^2 - 1 means 100-1 and we get 99, which is approximately 100. hence (10^170 – 1) would remain as 10^170.
and 10^10 * 10^170 = 10^180. Answer is D.
Answer: D
Question: If a particular is never chosen, in how many ways can a cricketbe chosen out of 15 players?
Options:
A)289
B)334
C)364
D)356
E)346
Rationale: A particular players is never chosen, it means that 11 players are selected out of 14 players.
=> Required number of ways = 14C11
= 14!/11!x3! = 364
C
Answer: C
Question: Sasha likes to go biking on the weekends. One Saturday, she leaves home and heads east at 10 AM. She travels 12 miles per hour for three hours, then 18 miles per hour for the next two hours. She turns around to head home after a short water break, how fast does Sasha need to ride, in miles per hour, to get home at 5 PM?
Options:
A)17
B)18
C)19
D)20
E)21
Rationale: She travels 12*2 + 18*2 = 60 miles east in 4 hours, taking a short rest at 2 PM
She needs to travel at (60 miles) / (5 PM - 2PM) = 60 miles / 3 hours = 20 miles per hour
Correct answer: D
Answer: D
Question: The price of a VCR is marked at Rs. 12,000. If successive discounts of 15%, 10% and 5% be allowed, then at what price does a customer buy it?
Options:
A)8729
B)8721
C)2772
D)9927
E)2388
Rationale: Actual price = 95% of 90% of 85% of Rs. 12000
= 95/100 * 90/100 * 85/100 * 12000
= Rs. 8721.
Answer: B
Answer: B
Question: A reduction of 40% in the price of bananas would enable a man to obtain 64 more for Rs.40, what is reduced price per dozen?
Options:
A)1
B)7
C)3
D)8
E)5
Rationale: 40*(40/100) = 16 --- 64
? --- 12 => Rs.3
Answer: D
Answer: D
Question: Product of two natural numbers is 3. Then, the sum of reciprocals of their squares is
Options:
A)10/9
B)1/289
C)290/90
D)290/19
E)None of these
Rationale: Explanation:
If the numbers are a, b, then ab = 3,
as 3 is a prime number, so a = 1, b = 3.
1/a2+1/b2=1/1(2)+1/3(2)
=10/9
Option A
Answer: A
Question: Four hundred multiples of seven are chosen at random, and 100 multiples of eight are chosen at random. Approximately what percentage of the 500 selected numbers are odd?
Options:
A)20%
B)25%
C)40%
D)50%
E)80%
Rationale: About half the multiples of seven will be odd while all the multiples of eight are even.
The percentage of odd numbers is about (1/2)(400) / 500 = 40%
The answer is C.
Answer: C
Question: A trader sells 40 metres of cloth for Rs.8200 at a profit of Rs.35 per metre of cloth. How much profit will the trder earn on 40 metres of cloth?
Options:
A)Rs.950
B)Rs.1500
C)Rs.1000
D)Rs.1400
E)None of these
Rationale: Explanation:
SP of 1 metre cloth = 8200/40 = Rs.205.
CP of 1 metre cloth = Rs.205 – 35 = Rs.170
CP on 40 metres = 170 x 40 = Rs.6800
Profit earned on 40 metres cloth = Rs.8200 – Rs.6800 = Rs.1400.
Answer: Option D
Answer: D
Question: How many 3-digit even numbers are possible such that if one of the digits is 5, the next/succeeding digit to it should be 1?
Options:
A)5
B)305
C)365
D)405
E)495
Rationale: 510, 512, 514, 516, and 518, so total 5. Hence Option A.
Answer: A
Question: Ramu was facing East. He walked 4 km forward and then after turning to his right walked 6
km. Again he turned to his right and walked 7 km. After this he turned back. Which direction
was he facing at the time?
Options:
A)East
B)North
C)South
D)West
E)none
Rationale: First he is in east direction...n then he moved forward 4km, and then he turned to right means he is now in south direction n he moved forwrd 6km towards south n again he turned right ... Here now he is in west direction...in question they mention what his position facing towards when he turned back.... He is now in east
ANSWER:A
Answer: A
Question: If $6000 was invested at an annual interest rate of 5.6% compounded annually, which of the following represents the amount the investment was worth after 3 years?
Options:
A)6000 (1.056)(3)
B)6000 (3+1.056)
C)6000 (1+3(0.056))
D)6000 (1+(0.056)^3)
E)6000 (1.056)^3
Rationale: the formula is CI=P(1+r/100)^t
in this case i think E is the ans 6000 (1.056)^3
Answer: E
Question: A person bought an article and sold it at a loss of 10%. If he had bought it for 20% less and sold it for Rs.75 less, he could have gained 25%. What is the cost price?
Options:
A)Rs.250
B)Rs.229
C)Rs.220
D)Rs.127
E)Rs.221
Rationale: CP1 = 100 SP1 = 90
CP2 = 80 SP2 = 80 * (140/100) = 112
22 ----- 100
55 ----- ? => Rs.250
Answer: A
Answer: A
Question: If in a box of dimensions 6 m * 5 m * 4 m smaller boxes of dimensions 60 cm * 50 cm * 40 cm are kept in it, then what will be the maximum number of the small boxes that can be kept in it?
Options:
A)3388
B)1000
C)2799
D)2787
E)9771
Rationale: 6 * 5 * 4 = 60/100 * 50/100 * 40/100 * x
1 = 1/10 * 1/10 * 1/10 * x => x = 1000
Answer: B
Answer: B
Question: A company has 15 managers and 75 associates. The 15 managers have an average salary of $180,000. The 75 associates have an average salary of $30,000. What is the average salary for the company?
Options:
A)$35,000
B)$45,000
C)$55,000
D)$65,000
E)$75,000
Rationale: Another method is to get ratios
Say 30000=a and
We know the # of people are in 1:5 ratio
Average=(6a*1+a*5)/6= 11a/6=55000
Answer is C. $55,000
Answer: C
Question: If,
1 * 3 * 5 = 16
3 * 5 * 7 = 38
Then find,
15 * 17 * 19 =?
Options:
A)89
B)49
C)68
D)38
E)338
Rationale: E
338
(19 * 17) + 15 = 338
Answer: E
Question: Find the highest value of 'a' so that 36500a is divisible by 8.
Options:
A)9
B)8
C)0
D)2
E)1
Rationale: Explanation:
Given, number is divisible by 8 only if 'a' is divisible by 8 or is 0.
.: Highest value of a is '8'.
Answer: Option B
Answer: B
Question: A certain number of men can do a work in 60days. If there were 8 men less it could be finished in 10days more. How many men are there?
Options:
A)56
B)42
C)60
D)45
E)36
Rationale: The original number of men = 8(60+10)/10 = 56men
Answer is A
Answer: A
Question: If a and b are odd integers, which of the following is an even integer?
Options:
A)2(a-b)+ab
B)2(a-b)+a
C)2(a-b)+b
D)2(a-b)+ab+a
E)2(a-b)+4a+b
Rationale: 2(a-b)+ab+a=even+odd+odd=even
The answer is D.
Answer: D
Question: Two taps can separately fill a cistern 8 minutes and 12 minutes respectively and when the waste pipe is open, they can together fill it in 18 minutes. The waste pipe can empty the full cistern in?
Options:
A)7
B)8
C)6.5
D)9
E)5
Rationale: 1/8 + 1/12 - 1/x = 1/18
x = 72/11 = 6.5
Answer: C
Answer: C
Question: Given that E and F are events such that P(E) = 0.16, P(F) = 0.4 and P(E n F) = 0.4,
find P (E|F) and P(F|E)
Options:
A)1/4
B)1/7
C)1/9
D)1/11
E)1/13
Rationale: Here, E and F are events
P(E|F) = P(EnF)/P(F) = 0.4/0.4 = 1
P(F|E) = P(EnF)/P(E) = 0.4/0.16 = 1/4.
A)
Answer: A
Question: The owner of a furniture shop charges his customer 24% more than the cost price. If a customer paid Rs. 8339 for a computer table, then what was the cost price of the computer table?
Options:
A)6727
B)6887
C)6728
D)6725
E)2871
Rationale: :
CP = SP * (100/(100 + profit%))
= 8339(100/124) = Rs. 6725.
Answer: D
Answer: D
Question: An investment W gained an interest payment of $250 each month when the annual interest rate was 8%, how much more should we invest annually if we want to gain 12% more per month with a new annual interest rate of 7.5% ?
Options:
A)$9,360
B)$9,100
C)$8,250
D)$7,300
E)$7,150
Rationale: Answer is D : 7,300
An investment W gained an interest payment of $250 each month when the annual interest rate was 8%,Interest per annum with 8% interest rate is = 250* 12 = Principal * Interest Rate(8/100)
This gives Principal as 37,500$
For an revised interest of 12% more and new interest rate of 7.5% , ie. 250* 12 * 1.12 = Principal * Interest Rate (7.5/100)
This gives the new Principal as 44,800.
The question is how much more should we invest, so 44,800 - 37,500 = 7,300.D
Answer: D
Question: A car owner buys petrol at Rs 7.50, Rs. 8 and Rs. 8.50 per litre for three successive years. What approximately is the average cost per litre of petrol if he spends Rs. 4000 each year ?
Options:
A)8.98
B)7.98
C)6.98
D)4.98
E)2.98
Rationale: Explanation:
Total quantity of petrol consumed in 3 years = liters
= liters
= liters
Total amount spent = Rs. (3 x 4000) = Rs. 12000.
Average cost = Rs. = Rs. 7.98.
Answer: B
Answer: B
Question: Arun borrowed a sum for 4 years on S.I. at 12%. The total interest paid was Rs. 360. Find the Principal.
Options:
A)120
B)360
C)480
D)560
E)750
Rationale: P=100×SI/RT=100×360/12×4
=100×30/4
=25×30
=750
Option E
Answer: E
Question: A and B can do a piece of work in 45 days and 40 days respectively. They began to do the work together but A leaves after some days and then B completed the remaining work in 23 days. The number of days after which A left the work was
Options:
A)5 days
B)6 days
C)7 days
D)9 days
E)8 days
Rationale: does the job in 40 days = 1/40
A & B together completes the job = ?
After A leaves, B completes the remaining job in 23 days.
i.e B's part of job in 23days = 23/40
Remaining part 17/40 is done by A & B together in x no.of days.
i.e (x/45) + (x/40) = 17/40
=> x = 9 days
ANSWER:D
Answer: D
Question: The ratio of the radius of two circles is 1: 3, and then the ratio of their areas is?
Options:
A)1: 5
B)1: 0
C)1: 9
D)1: 4
E)1: 2
Rationale: r1: r2 = 1: 3
Πr12: Πr22
r12: r22 = 1: 9
Answer: C
Answer: C
Question: A group of four girls and three boys have tickets for seven adjacent seats in one row of a theater. If the three girls will not sit in three adjacent seats, how many possible different seating arrangements are there for these 7 theatre-goers?
Options:
A)7! – 2!3!2!
B)7! – 4!3!
C)7 × 2!3!2!
D)2!3!2!
E)7! – 5!3!
Rationale: There are 3 boys and 4 girls , we want to calculate the seating arrangements if three boys do not sit together, like MMM.
Let's calculate the # of arrangements when they SIT together and subtract from total # of arrangements of these 7 persons without restriction. Thus we'll get the # of arrangements asked in the question.
1. Total # of arrangements of 7 is 7!.
2. # of arrangements when 3 girls are seated together, like GGG;
Among themselves these 3 boys can sit in 3! # of ways,
Now consider these 3 boys as one unit like this {GGG}. We'll have total of 5 units: {GGG}{G}{B}{B}{B}. The # of arrangements of these 5 units is 5!.
Hence total # of arrangements when 3 men sit together is: 3!5!.
# of arrangements when 3 boys do not sit together would be: 7!-3!5!.
Answer: E.
Answer: E
Question: Jose is uploading a file to the internet for a college project. The file weighs 160 megabytes. If Jose's internet speed for uploading tops 8 megabytes per minute, how long will it take until the upload is completed?
Options:
A)1 hour
B)45 minutes
C)20 minutes
D)5 minutes
E)1 hour and 10 minutes
Rationale: Answer is (C). Jose calculates that if the files weighs 160 megabytes, and his internet uploads at 8 megabytes per minute, it would take 20 minutes to upload as 160 divided by 8 megabytes per minute equals 20.
Answer: C
Question: If c is 14% of a and 40% of b, what percent of a is b?
Options:
A) 2.5%
B) 15%
C) 25%
D) 35%
E) 250%
Rationale: Answer = D
14a/100 = 40b/100
b = 14a/40 = 35a/100 = 35%
Answer: D
Question: Using all the letters of the word "TEN", how many words can be formed, which begin with N and end with A?
Options:
A)1
B)6
C)8
D)9
E)2
Rationale: There are five letters in the given word.
Consider 3 blanks ....
The first blank and last blank must be filled with T and N all the remaining three blanks can be filled with the remaining 1 letters in 1! ways.
The number of words = 1! = 1.
Answer: A
Answer: A
Question: Jo's collection contains US, Indian and British stamps. If the ratio of US to Indian stamps is 5 to 3 and the ratio of Indian to British stamps is 5 to 1, what is the ratio of US to British stamps?
Options:
A)5 : 1
B)10 : 5
C)15 : 2
D)20 : 2
E)25 : 2
Rationale: U/I = 5/3
I/B = 5/1
Since I is multiple of both 2 (as per first ratio) and 5 (as per second ratio) so let's assume that I = 10
i.e. Multiplying teh first ratio by 5 and second ration by 2 in each numerator and denominator
then, U : I : B = 25 : 15 : 2
i.e. U : B = 25 : 2
Answer: Option E
Answer: E
Question: What no. should be subtracted from x^3+4x^2−7x+12x^3+4x^2−7x+12, if it is to be perfectly divisible by x+3x+3?
Options:
A)40
B)42
C)45
D)46
E)49
Rationale: According to remainder theorem when dfracf(x)x+adfracf(x)x+a, then the remainder is f(−a)f(−a).
In this case, as x+3x+3 divides x3+4x2−7x+12–kx3+4x2−7x+12–k perfectly (kk being the number to be subtracted), the remainder is 0 when the value of xx is substituted by -3.
i.e., (−3)3+4(−3)2−7(−3)+12−k=0(−3)3+4(−3)2−7(−3)+12−k=0
or −27+36+21+12=k−27+36+21+12=k
or k=k= 42
B
Answer: B
Question: A city had 800 migrants in the year 2000. Since then, The number of migrants in a countrythe city has doubled every 2 years. If there were 800 migrants in the country in the year 2000, What was the increase in the population of migrants during the period from 2006 to 2008?
Options:
A)2800
B)4400
C)5400
D)6400
E)8800
Rationale: The population will increase in the following order:
2000: 800
2002: 1600
2004: 3200
2006: 6400
2008: 12800
Difference between 2006 and 2008 = 6400
Option D
Answer: D
Question: On a map, 3 centimeters represents 33 kilometers. Two cities 209 kilometers apart would be separated on the map by how many centimeters?
Options:
A)19
B)7
C)13
D)110
E)180
Rationale: 1 centimeter represents 11 kilometers ( 33/3 )
X=209/11= 19
Answer: A
Answer: A
Question: The average of 25 result is 18.The average of 1st 12 of them is 14 & that of last 12 is 17.Find the 13th result.
Options:
A)57
B)48
C)36
D)78
E)52
Rationale: Clearly 13th result=(sum of 25 results)-(sum of 24 results)
=(18*25)-(14*12)+(17*12)
=450-(168+204)
=450-372
=78.
Ans: D
Answer: D
Question: The distance that light travels in one year is approximately 5,870,000,000,000 miles. The distance light travels in 10 years is:
Options:
A)111 × 1827 miles
B)999× 1238 miles
C)346 × 1012 miles
D)247 × 1012 miles
E)587 × 10^11 miles
Rationale: The distance of the light travels in 10 years is:
5,870,000,000,000 × 10 miles.
= 58,700,000,000,000 miles.
= 587 × 10^11 miles.
Answer :E
Answer: E
Question: A 20% stock yielding 10% is quoted at :
Options:
A)83.33
B)110
C)200
D)120
E)160
Rationale: Solution
To earn Rs. 10, money invested = Rs. 100.
To earn Rs. 20, money invested = Rs.(100/10X20) = Rs. 200.
âˆ´ Market value of Rs. 100 stock =Rs. 200
Answer C
Answer: C
Question: The rate of inflation was 1000%. Then what will be the cost of an article, which costs 6 units of currency now, 2 years from now?
Options:
A)666
B)626
C)547
D)726
E)None of these
Rationale: Explanation :
Let x be initial cost .
1000 % increase => x + (1000/100)x = 11x.
1st yr = 6 * 11 = 66
2nd year = 66 * 11 = 726.
Answer : D
Answer: D
Question: What is the perimeter of a regular polygon with sides of length 15 cm and internal angles measuring 130° each?
Options:
A)108 cm
B)118 cm
C)120 cm
D)132 cm
E)144 cm
Rationale: Sum of all interior angles is given by:
180(n-2) = n is number of sides
180(n-2) = 130*n
from here
n = 7.2
So perimeter becomes 15*7.2= 108
Answer: A
Answer: A
Question: 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, (...)
Options:
A)53
B)67
C)48
D)59
E)45
Rationale: Explanation :
All are prime numbers in their order, starting from 23
Hence, next number is 67
Answer : B
Answer: B
Question: Mike weighs twice as much as Mary. Mike's weight is 150% of Michelle's weight. Alan weighs 20% more than Charlie. Charlie weighs 160% of Mary's weight. Which of these 5 people weighs the highest?
Options:
A)Mary
B)Mike
C)Michelle
D)Alan
E)Charlie
Rationale: Mary < Michelle < Mike
Charlie < Alan
Let x be Mary's weight.
Mike's weight is 2x and Alan's weight is 1.2*1.6x = 1.92x.
The answer is B.
Answer: B
Question: The diameter of the driving wheel of a bus in 140 cm. How many revolutions per minute must the wheel make in order to keep a speed of 11 kmph?
Options:
A)21.23
B)52.85
C)23.26
D)41.67
E)25.15
Rationale: distance covered in 1 min=(66*1000)/60=183.33cm
circumference of the wheel=(2*(22/7)*.70)=4.4m
no of revolution per min=183.33/4.4=41.67
ANSWER:D
Answer: D
Question: Anil invested a sum of money at a certain rate of simple interest for a period of five years. Had he invested the sum for a period of nine years for the same rate, the total intrest earned by him would have been sixty percent more than the earlier interest amount. Find the rate of interest p.a.
Options:
A)6%
B)9%
C)12.5%
D)Cannot be determined
E)None of these
Rationale: Let the sum be Rs.P. Let the rate of interest be R% p.a.
(P)(9)(R)/100 = [1 + 6/100][ (P)(5)(R) /100] = 1.6{5PR/100]
9PR/100 = 9PR/100 which is anyway true.
R cannot be found.
ANSWER:D
Answer: D
Question: Two trains of equal are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 sec. The length of each train is?
Options:
A)50
B)88
C)77
D)66
E)45
Rationale: Let the length of each train be x m.
Then, distance covered = 2x m.
Relative speed = 46 - 36 = 10 km/hr.
= 10 * 5/18 = 25/9 m/sec.
2x/36 = 25/9 => x = 50.
Answer: A
Answer: A
Question: Which of the following is closer to √0.8+√0.1?
Options:
A)0.5
B)0.7
C)0.9
D)1.1
E)1.2
Rationale: √0.8+√0.1=approximately √0.81+√0.09=0.9+0.3=1.2. Hence, the correct answer is E.
Answer: E
Question: In an office, 60 percent of the workers have at least 5 years of service, and a total of 16 workers have at least 10 years of service. If 90 percent of the workers have fewer than 10 years of service, how many of the workers have at least 5 but fewer than 10 years of service?
Options:
A) 96
B) 64
C) 50
D) 144
E) 160
Rationale: (10/100)Workers = 16 = > number of workers = 160
(60/100)*Workers = x+16 = > x = 96
Answer A
Answer: A