divelab/Sys2Bench huggingface dataset:
Question: Two trains 120 m and 190 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is?
Options:
A)10.9 sec
B)11.6 sec
C)10.6 sec
D)10.8 sec
E)20.8 sec
Rationale: Relative speed = 60 + 40 = 100 km/hr.
= 100 * 5/18 = 250/9 m/sec.
Distance covered in crossing each other = 120 + 190 = 310 m.
Required time = 310 * 9/250 = 11.6
= 11.6 sec.
Answer: B
Answer: B
Question: Ravi and Kumar are working on an assignment. Ravi takes 6 hours to type 32 pages on a computer, while Kumar takes 5 hours to type 40 pages. How much time will they take, working together on two different computers to type an assignment of 110 pages?
Options:
A)7 hours 15 minutes
B)8 hours 15 minutes
C)7 hours 30 minutes
D)8 hours 30 minutes
E)8 HOURS 15 MINUTES
Rationale: Number of pages typed by Ravi in 1 hour = 32/6 = 16/3 .
Number of pages typed by Kumar in 1 hour = 40/5 = 8.
Number of pages typed by both in 1 hour = ( 16/3 + 8 ) = 40/3 .
Therefore Time taken by both to type 110 pages = ( 110 x 3/40 ) hours
= 8 hours 15 minutes. ANSWER : E
Answer: E
Question: If a car had traveled 20 kmh faster than it actually did, the trip would have lasted 30 minutes less. If the car went exactly 60 km, at what speed did it travel?
Options:
A)35 kmh
B)40 kmh
C)50 kmh
D)60 kmh
E)65 kmh
Rationale: Time = Distance/Speed
Difference in time = 1/2 hrs
60/x - 60/(x + 20) = 1/2
Substitute the value of x from the options. --> x = 40 --> 60/40 - 60/60 = 3/2 - 1 = 1/2
Answer: B
Answer: B
Question: SCORE INTERVAL----------------NUMBER OF SCORES
50-59-------------------------- 8
60-69--------------------------10
70-79--------------------------16
80-89--------------------------27
90-99--------------------------18
The table above shows the distribution of test scores for a group of management trainees. Which score interval contains the median of the 79 scores?
Options:
A)39th (80-89)
B)40th
C)34th
D)37th
E)35th
Rationale: Total scores= 8+10+16+27+18 = 79, which is odd, therefore the median is the Floor(79/2)+1 = 39th score. And the 39th score is in the 80-89 range, because 50-79 only reference 34 scores.
A
Answer: A
Question: A bag contains 2 yellow, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue?
Options:
A)1/2
B)10/21
C)9/11
D)7/11
E)11/15
Rationale: Total number of balls = 2 + 3 + 2 = 7
Let S be the sample space.
n(S) = Total number of ways of drawing 2 balls out of 7 = 7C2
Let E = Event of drawing 2 balls , none of them is blue.
n(E) = Number of ways of drawing 2 balls , none of them is blue
= Number of ways of drawing 2 balls from the total 5 (=7-2) balls = 5C2
(∵ There are two blue balls in the total 7 balls. Total number of non-blue balls = 7 - 2 = 5)
P(E) = n(E)/n(S)
=5C2 / 7C2
= (5×42×1)/(7×62×1)
=(5×4)/(7×6)
=10/21
Ans- B
Answer: B
Question: The population of a bacteria colony doubles every day. If it was started 5 days ago with 2 bacteria and each bacteria lives for 12 days, how large is the colony today?
Options:
A)512
B)768
C)64
D)2048
E)4096
Rationale: 2^5(2) = 2^6 = 64
The answer is C
Answer: C
Question: In one hour a boat goes 22 km long the stream and 12 km against the stream.The speed of the boat in still water is?
Options:
A)17
B)18
C)16
D)15
E)11
Rationale: Speed in still water A = ½ ( 22+12) km/hr A= 17 kmph
Answer: A
Answer: A
Question: A vessel of capacity 2 litre has 30% of alcohol and another vessel of capacity 6 litre had 45% alcohol. The total liquid of 8 litre was poured out in a vessel of capacity 10 litre and thus the rest part of the vessel was filled with the water. What is the new concentration of Mixture?
Options:
A)31%.
B)71%.
C)49%.
D)33%.
E)51%.
Rationale: 30% of 2 litres = 0.6 litres
45% of 6 litres = 2.7 litres
Therefore, total quantity of alcohol is 3.3 litres.
This mixture is in a 10 litre vessel. Hence, the concentration of alcohol in this 10 litre vessel is 33%
D
Answer: D
Question: On an xy-graph, three corners of a
parallelogram are located at (3, 3), (4, – 4),
and (–2, –1). Which of the following points
could be the remaining corner?
Options:
A)(8, 0)
B)(8, –1)
C)(–1, 9)
D)(–3, 6)
E)(–5, 7)
Rationale: A good way to begin is to draw a picture showing the three points given, including
possible places where a fourth point would form a parallelogram. Here’s what your
picture may look like:
y
A
B
C
(4, –4)
(–2, –1)
(3, 3)
x
This figure shows three possible points for the remaining corner of the parallelogram: A, B,
and C. To find the exact coordinates of these three additional points, choose any of the
given points and count up and over (or down and over) to a second given point. Then,
starting from the third given point, count the same number of steps up and over (or down
and over) and label the point where you end up.
By this method, you find that A = (–3, 6), B = (9, 0), and C = (–1, –8). Only point A is listed
as an answer.
correct answer A)(8, 0)
Answer: A
Question: If 9 parallel lines in a plane is intersected by a family of another 8 parallel lines, how many parallelograms are there in the network thus formed?
Options:
A)80
B)63
C)120
D)1008
E)1260
Rationale: parallelogram can formed by 2 horizontal and 2 vertical lines
for horizontal 9c2
for vertical 8c2
total parallelogram is 9 c2*8c2=36*28
=1008
ANSWER:D
Answer: D
Question: If the prime factorization of the integer q can be expressed as a^2xb^xc^3x−1, where a, b, c, and x are distinct positive integers, which of the following could be the total number of factors of q?
Options:
A)3j + 4, where j is a positive integer
B)5k + 5, where k is a positive integer
C)6l + 2, where l is a positive integer
D)9m + 7, where m is a positive integer
E)10n + 1, where n is a positive integer
Rationale: Straight forward question if you know the formula for number of factors of an integer q=ax∗by∗czq=ax∗by∗cz , where x,y,z≥0 x,y,z≥0 and are integers = (x+1)(y+1)(z+1) including 1 and integer q.
Now given, q= a^2xb^xc^3x−1, thus based on the above formula, the number of factors of q including 1 and q = (2x+1)(x+1)(3x-1+1) = 3x(2x+1)(x+1). So we know that the number will be of the form 3x(2x+1)(x+1) , will be an integer and will be true for ALL X. Thus substitute x=1, we get number of factors = 3*3*2 =18 (this eliminates A, as 3 is a factor of 18 and thus can not leave 4 or (4-3=1) as the remainder. Similarly, eliminate C and D).
Now substitute x=2, we get number of factors = 6*5*3 = 90 and this eliminates E as 10 is a factor of 90 and will leave a remainder of 0. Thus B is the only remaining answer choice
ANSWER:B
.
Answer: B
Question: Which of the following is closest to 10^140 – 10^30 ?
Options:
A)10^210
B)10^140
C)10^150
D)10^90
E)10^6
Rationale: 10^140 – 10^30
10^30 * (10^110 – 1)
as we know 10^2 - 1 means 100-1 and we get 99, which is approximately 100. hence (10^110 – 1) would remain as 10^110.
and 10^30 * 10^110 = 10^140. Answer is B.
Answer: B
Question: A windmill is taking advantage of strong air currents in order to produce electrical energy. On a typical day the wind speed is around 20 mph and in that speed the windmill produces 500 kw/h (kilowatts per hour). On a stormy day a windmill produces 20% more energy. How much kw/h can three windmills produce in two hours on a stormy day?
Options:
A)3600.
B)4860.
C)5780.
D)5760.
E)6380.
Rationale: Efficiency per machine = 500 watt/hr
Efficiency due to increase in wind speed = 500*120% => 600 watt/hr
Production by each machine in 2 hours is 600*2 => 1200 watt
Production by 3 machines => 1200 watt * 3 = 3600 watt
Answer will be (A)
Answer: A
Question: There are 60 people and 3 clubs M, S, and Z in a company. 16 people joined M, 18 people joined S and 11 people joined Z. If the members of M did not join any other club, at most, how many people of the company did not
join any club?
Options:
A)22
B)23
C)24
D)25
E)26
Rationale: Answer E.
key is 'atmost' here.
so 16 people joined M.
18 people joined S and 11 people joined Z. to get maximum people who did not join any club, 11 people who joined Z are among 18 people who joined S.
so 18+16 = 34
60-34 = 26
Answer: E
Question: P cando a work in 15 days and Q cando the same work in 20 days. If they can work together for 4 days, what is the fraction of work left?
Options:
A)1/15
B)2/15
C)8/15
D)9/15
E)11/15
Rationale: Amount of work P can do in 1 day = 1/15
Amount of work Q can do in 1 day = 1/20
Amount of work P and Q can do in 1 day = 1/15 + 1/20 = 7/60
Amount of work P and Q can together do in 4 days = 4 × (7/60) = 7/15
Fraction of work left = 1 – 7/15= 8/15
C
Answer: C
Question: In how many years will a sum of money doubles itself at 12% per annum on simple interest?
Options:
A)15%
B)20%
C)10%
D)8%
E)22%
Rationale: P = (P*12*R)/100
R = 8%
Answer:D
Answer: D
Question: If x is an integer, find the minimum value of x such that 0.00001154111 x 10^x exceeds 1000.
Options:
A)7
B)1
C)8
D)6
E)5
Rationale: Considering from the left if the decimal point is shifted by 8 places to the right, the number
becomes 1154.111. Therefore, 0.00001154111 x 10x exceeds 1000 when x has a minimum value of 8.
ANSWER:C
Answer: C
Question: Find the surface area of a 8 cm x 4 cm x 2 cm brick.
Options:
A)136 cu cm
B)112 cu cm
C)164 cu cm
D)180 cu cm
E)None
Rationale: Sol.
Surface area = [2(8 x 4 + 4 x 2 + 8 x 2)]
= (2 x 56)
= 112 cu cm
Answer B
Answer: B
Question: A man has some hens and cows. If the number of heads be 48 and the number of feet equals 140, then the number of hens will be:
Options:
A)43
B)26
C)33
D)21
E)28
Rationale: B
26
Let the number of hens be x and the number of cows be y.
Then, x + y = 48 .... (i)
and 2x + 4y = 140 x + 2y = 70 .... (ii)
Solving (i) and (ii) we get: x = 26, y = 22.
The required answer = 26.
Answer: B
Question: What is the average of two tenths and five thousandths
Options:
A)0.2022
B)0.3325
C)0.1025
D)0.2012
E)0.2114
Rationale: Explanation:
two tenths = 0.2
Five thousandths = 0.005
The average is (0.2 + 0.005)/2 = 0.1025
Answer: C
Answer: C
Question: A train 110 meters long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?
Options:
A)8 sec
B)6 sec
C)2 sec
D)9 sec
E)3 sec
Rationale: Speed of train relative to man
= (60 + 6) km/hr
= 66 km/hr
[66 * 5/18] m/sec
= [55/3] m/sec.
Time taken to pass the man
= [110 * 3/55] sec
= 6 sec
Answer: B
Answer: B
Question: A bag contains five white and four red balls. Two balls are picked at random from the bag. What is the probability that they both are different color?
Options:
A)5/8
B)5/9
C)5/2
D)5/1
E)5/0
Rationale: Explanation:
Two balls can be picked from nine balls in ways.
We select one white ball and one red ball from five white balls and four red balls. This can be done ways.
The required probability = (5 * 4) = 20/36 = 5/9
Answer:B
Answer: B
Question: A water tank is one-third full.Pipe A can fill a tank in 10 minutes and pipe B can empty it in 6 minutes.If both the pipes are open,how long will it take to empty or fill the tank completely?
Options:
A)6 min.to empty
B)9 min.to empty
C)5 min.to empty
D)4 min.to empty
E)7 min.to empty
Rationale: Explanation:
Clearly,pipe B is faster than pipe A and so,the tank will be emptied.
part to be emptied = 1/3
part emptied by (A+B) in 1 minute=(1/6-1/10)=1/15
so, the tank will be emptied in 5 min
Answer: C
Answer: C
Question: Ram professes to sell his goods at the cost price but he made use of 900 grms instead of a kg, what is the gain percent?
Options:
A)11 1/5%
B)11 8/9%
C)11 1/9%
D)13 1/9%
E)11 4/9%
Rationale: 900 --- 100
100 --- ? => 11 1/9%
Answer:C
Answer: C
Question: If an apple orchard has 10,000 apples on its trees, and every day half of the apples on the trees are harvested, how many will still be on the trees after 4 days?
Options:
A)500 apples
B)625 apples
C)1000 apples
D)1250 apples
E)1500 apples
Rationale: 10000/(2^4)=10000/16=625
The answer is B.
Answer: B
Question: A motorcyclist goes from Bombay to Pune, a distance of 192 kms at an average of 32 kmph speed. Another man starts from Bombay by car 2 ½ hours after the first, and reaches Pune ½ hour earlier. What is the ratio of the speed of the motorcycle and the car?
Options:
A)1:2
B)1:5
C)1:4
D)1:1
E)1:8
Rationale: T = 192/32 = 6 h
T = 6 - 3 = 3
Time Ratio = 6:3 = 2:1
Speed Ratio = 1:2
Answer: A
Answer: A
Question: Dacid obtained 96, 95, 82, 87 and 92 marks (out of 100) in English, Mathematics, Physics, Chemistry and Biology. What are his average marks?
Options:
A)67
B)26
C)87
D)26
E)90
Rationale: Average
= (96+95+82+87+92)/5
= 452/5 = 90.
Answer: E
Answer: E
Question: The sum of ages of Aswin ,Sachin and Sumesh is 93 years.10 years ago ratio of their age was 2:3:4.what is the present age of sachin.
Options:
A)19
B)21
C)31
D)41
E)51
Rationale: Solution:Sum of the present ages of Aswin ,Sachin and Sumesh=93
Sum of the ages of Aswin ,Sachin and Sumesh 10 years ago=93- 10*3=63
Age of sachin 10 years ago=(3/(2+3+4)) * 63 = 21.
Present age of Sachin=21+10=31
Answer C
Answer: C
Question: After giving a discount of rs.50 the shopkeeper still gets a profit of 20%,if the cost price is rs.180.find the markup %?
Options:
A)0.5
B)0.6
C)0.48
D)0.65
E)0.45
Rationale: cost price=180
s.p=180*120/100=216
disc=50
so...mark price=216+50=266......
mark up%=266-180/180=86/180=.48 or 48%
ANSWER:C
Answer: C
Question: Rocky is 22 and his brother Ronnie is 25 years old. How many years ago was the ratio of their ages 2:5 ?
Options:
A)20 years
B)2 years
C)10 years
D)22 years
E)24 years
Rationale: let be x years ago....
so, (22-x)/(25-x)=2/5........solve it.
x=20years
ANSWER:A
Answer: A
Question: If the operation # is defined for all a and b by the equation a@b =(a*b)-1, then 2#(3#1) =
Options:
A)4
B)2
C)3
D)1
E)5
Rationale: work within the parenthesis first so solve (3#1) first
(3#1)=(3*1)-1=2
now take 2 plug back into equation and solve the rest
(2#2)=(2*2)-1=3
so 3 is the answer....this question is merely testing order of operations
remember PEMDAS
Option C is answer
Answer: C
Question: A ballet instructor has decided to divide her next class into equal groups. Unfortunately, the number of students doesn't divide equally by the group size that she wanted. It turns out that in order for the groups to be equal, she must increase her group size by one and cut three children from the roster. Which of the following can describe the initial number of students in the class and the instructor's initial group size (in the order Students; group size)?
Options:
A)82; 5.
B)54; 9.
C)27; 4.
D)15; 6.
E)35; 7.
Rationale: Option E) Initially 35 students then reduced to 32 students; and Initially a group size of 7 increased to a group size of 8 fits the requirement.
32 / 8 = 4 groups of students
Answer: E
Question: Evaluate 25% of 450 + 45% of 250
Options:
A)225
B)242
C)252
D)262
E)272
Rationale: Explanation:
= (25/100) * 450 + (45/100) * 250
= 225
Option A
Answer: A
Question: xy=1 then what is (7^(x+y)^2) / (7^(x-y)^2)
Options:
A)2401
B)4
C)8
D)16
E)32
Rationale: (x+y)^2 - (x-y)^2
(x+y+x-y)(x+y-x+y)
(2x)(2y)
4xy
4
7^4 = 2401
Answer A
Answer: A
Question: A fruit salad mixture consists of apples, peaches, and grapes. There are 2 times as many pounds of apples as grapes and 3 times as many pounds of peaches as grapes. If a mixture that has an average (arithmetic mean) of 9 pounds per fruit, how many more pounds of apples than grapes does the mixture have?
Options:
A)15
B)12
C)9
D)6
E)3
Rationale: A+P+G= 9*2
A=2G
P=3G
3G+2G+G= 9*2
G= 9*2/6= 3
A= 3*2=6
Difference = 6-3=3
'E' is the answer
Answer: E
Question: If an amount of Rs.142136 is distributed equally amongst 163 persons, how much amount would each person get?
Options:
A)Rs.862
B)Rs.872
C)Rs.882
D)Rs.892
E)None of these
Rationale: Explanation:
Amount each person would get = Rs.142136/163 = Rs.872
Answer: Option B
Answer: B
Question: There are 12 teachers in a school. If the average age of the teachers is 36, what will be the new average age if a 30 year old teacher joins the school?
Options:
A)35.54
B)34.52
C)32.3
D)35
E)34.44
Rationale: (sum of the 12 ages)/12 = 36
sum of the 12 ages = 432
new sum = 432+30 = 462
new average = 462/13 = 35.54
ans: A
Answer: A
Question: How many numbers from 10 to 100000 are exactly divisible by 9?
Options:
A)900
B)11110
C)1100
D)1200
E)1400
Rationale: 10/9 = 1 and 100000/9 =11111 ==> 11111 - 1 = 11110.
Answer : B
Answer: B
Question: A student committee that must consists of 3 members is to be formed from a pool of 9 candidates. How many different committees are possible
Options:
A)5
B)8
C)40
D)56
E)84
Rationale: Out of 9 people, any 3 can be selected for a committee. So 9c3=84 is the answer.
E
Answer: E
Question: 2 men and 4 women are lined up in a row. What is the number of cases where they stand with each other in turn? (The number of cases in which men (or women) do not stand next to each other)
Options:
A)12
B)15
C)18
D)21
E)48
Rationale: The list should be WMWMW. Hence, from women 4! And men 2!, we get (4!)(2!)=48. Therefore, the correct answer is E.
Answer: E
Question: The average of all odd numbers up to 200 is
Options:
A)50
B)100
C)120
D)75
E)80
Rationale: The numbers are 1,3,5,7,--------,197,199
Average = (199-1)/2 + 1 = 100
Answer is B
Answer: B
Question: A rectangular swimming pool is 10 feet by 12 feet. A deck that has uniform width surrounds the pool. The total area of the pool and deck is 360 square feet. What is the width of the deck?
Options:
A)7
B)2
C)3
D)4
E)6
Rationale: Let the width =W
Total Area of the pool and deck= (2W+10)(2W+12)
We can Test the answer choices along with unit digit method
A) 2 feet ...........14*16 has unit digit 4..........Eliminate
B) 2.5 feet.........15*17 has unit digit 5..........Eliminate
C) 3 feet............16*18 has unit digit 8...........eliminate
D) 4 feet............18*20 has unit digit 0...........hold
E) 5 feet............20*22 has unit digit 0...........Eliminate ( bigger size)
Answer:D w=4
Answer: D
Question: A day-trader plans to invest a total of $23,400 into 15 separate investments. If each investment requires a minimum deposit of $1,400, then which of the following is the maximum amount that she could put into any one investment?
Options:
A)$2,200
B)$3,000
C)$3,500
D)$3,800
E)$3,900
Rationale: We can also just keep track of theHUNDREDS DIGITS(since the hundreds digit is different for each answer choice).
Total of 14 minimized investments = (14)(1400) = $???600
The 15th investment + $???600 = $23,400
So, theHUNDREDS DIGITSof the 15th investment must be 8
Answer: D
Answer: D
Question: 16, 23, 19, 19, 22, 15, 25, ?
What number should replace the question mark?
Options:
A)13
B)11
C)16
D)18
E)19
Rationale: B
11
There are two alternate sequences: +3 and â€“4;
Answer: B
Question: The sum of two consecutive number is 49. Which is the larger number?
Options:
A)42
B)43
C)25
D)45
E)46
Rationale: Let consecutive number be x, x+1
Therefore sum of the consecutive number is x + x+1=49
2x+1=49
2x=48
x=24
Therefore larger number is x+1=25
ANSWER:C
Answer: C
Question: If 0 < a < b and k = (4a + 3b)/b , which of the following must be true?
Options:
A)k < 2
B)k < 7
C)k > 19
D)k > 9
E)k > 11
Rationale: Please follow posting guidelines (link in my signature) especially writing the correct topic title. Also do mention the source of the question if you select the tag:Source-Other Please Specify.
As for your question, it is very simple and straightforward with number plug in.
Assume a=1 and b=2 as a < b, you get k = (4+6)/2 =5. This eliminates all but option B , making it the correct answer.
Answer: B
Question: the sum of 2nd and 19th term of A.P. is equal to the sum of 8th , 15th and 12 th term . find the term which is 0
Options:
A)11th
B)12th
C)13th
D)14th
E)15th
Rationale: t2 + t19 = t8 + t15 + t12
=> a+d + a+18d = a+7d + a+14d + a+11d
=> a + 13d = 0
=> t14 = 0 i.e. 14th term is zero.
ANSWER:D
Answer: D
Question: How many kg of sugar costing Rs. 9/kg must be mixed with 27kg of sugar costing Rs. 7/ kg so that there may be a gain of 10% the mixture at Rs. 9.24 per kg?
Options:
A)52
B)55
C)57
D)60
E)63
Rationale: Selling Price(SP) of 1 kg mixture= Rs. 9.24
Profit = 10%
Cost Price(CP) of 1 kg mixture =100(100+Profit%)×SP
=100(100+10)×9.24=100110×9.24=92.411= Rs.8.4
By rule of alligation,
CP of 1 kg sugar of 1st kind CP of 1 kg sugar of 2nd kind
Rs. 9 Rs. 7
Mean Price
Rs.8.4
8.4 - 7 = 1.4 9 - 8.4 = 0.6
i.e., to get a cost price of 8.4, the sugars of kind1 and kind2 should be mixed in the ratio 1.4 : 0.6 = 14 : 6 = 7 : 3
Suppose x
kg of kind1 sugar is mixed with 27 kg of kind2 sugar.
then x : 27 = 7 : 3
⇒3x=27×7⇒x=9×7=63
E
Answer: E
Question: A chair is bought for Rs.600/- and sold at a loss of 5% find its selling price
Options:
A)s.570/-
B)s.550/-
C)s.560/-
D)s.590/-
E)s.580/-
Rationale: 100 % ------> 600 (100 * 6 = 600)
95 % ------> 540 (95 * 6 = 570)
Selling price = Rs.540/-
A)
Answer: A
Question: A can do a certain job in 12 days. B is 60% more efficient than A. How many days does B alone take to do the same job?
Options:
A)7 1/2 days
B)8 days
C)5 days
D)9 days
E)None of them
Rationale: Ratio of times taken by A and B = 160 : 100 = 8 : 5.
Suppose B alone takes x days to do the job.
Then, 8 : 5 :: 12 : x = 8x = 5 x 12 =x = 7 1/2 days.
Answer is A.
Answer: A
Question: At a constant Rate of flow, it takes 120 minutes to fill a swimming pool if a large hose is used and 180 minutes if a small hose is Used. At these constant rates, how many minutes will it take to fill the pool when both hoses are used simultaneously?
Options:
A)52
B)54
C)56
D)58
E)72
Rationale: time taken to fill the pool by Large Hose =120 minutes =L or 1/L=1/120 similarly 1/S=1/180
simultaneously it will take 1/L+1/S=1/120+1/180=5/360=72 minutes
Answer : E
Answer: E
Question: In a certain business school class, p students are accounting majors, q students are finance majors, r students are marketing majors, and s students are strategy majors. If pqrs = 1365, and if 1< p < q < r < s, how many students in the class are strategy majors?
Options:
A)3
B)5
C)8
D)11
E)13
Rationale: pqrs = 1365 = 3 * 5 * 7 * 13
Since 1< p < q < r < s, the number of students who are strategy majors is s = 13.
The answer is E.
Answer: E
Question: Due to 10% decrease in the price of sugar and John can buy 5kg more sugar in Rs100 , then find the CP of sugar?
Options:
A)Rs. 3(2/9)
B)Rs. 2(2/9)
C)Rs. 2(1/9)
D)Rs. 2(2/7)
E)Rs. 2(3/7)
Rationale: Here r = 10 % ,x = 100 and A = 5 kg
Actual price of sugar = 10*100/((100-10 )*5) = Rs. 2(2/9)
B
Answer: B
Question: Sudhir started a business with Rs.60,000 and after 8 months Ravi joined him with Rs.60,000. If they get a profit of Rs.28000 then ratio of their shares will be
Options:
A)3:1
B)2:3
C)4:3
D)3:4
E)3:5
Rationale: 60000*12:60000*(12-8)
=720000 :240000
=3:1
ANSWER:A
Answer: A
Question: If A> 0 and A is divisible by the product of the first nine positive integers, all of the following must be factors of A except
Options:
A)35
B)40
C)63
D)315
E)704
Rationale: A is divisible by 9!,which is 1*2*3*4*5*6*7*8*9
A=(9!) * some number
A. 35 = 5*7 so will divide A
B. 40 =5*8 so will divide A
C. 63 =9*7 so will divide A
D. 315 =5*7*9 so will divide A
E. 704 =8*8*11 This will not divide A
Ans E
Answer: E
Question: How many minutes does Aditya take to cover a distance of 400 m, if he runs at a speed of 20 km/hr
Options:
A)115min
B)215min
C)315min
D)415min
E)None of these
Rationale: ExplanaƟon:
We know that,
Time=DistanceSpeedSpeed=20 km/hr=20
∗
518m/sec=509m/sec Time =(400
∗
950)=72sec=115min
Answer: OpƟon A
Answer: A
Question: A train has a length of 150 metres. It is passing a man who is moving at 2 km/hr in the same direction of the train, in 3 seconds. Find out the speed of the train.
Options:
A)152 km/hr
B)178 km/hr
C)182 km/hr
D)172 km/hr
E)142 km/hr
Rationale: Length of the train = 150 m
Speed of the man =2 km/hr
Relative speed = 153/3=50 m/s
=50Ã—18/5=180 km/hr
Relative speed = Speed of train - Speed of the man (as both are moving in the same direction).
Therefore,Speed of the train = Relative speed + Speed of the man=180+2=182 km/hr
ANSWER:C
Answer: C