divelab/Sys2Bench huggingface dataset:
Question: A certain manufacturer of cake, muffin, and bread mixes has 100 buyers, of whom 50 purchases cake mix, 40 purchase muffin mix, and 19 purchase both cake mix and muffin mix. If a buyer is to be selected at random from the 100 buyers, what is the probability that the buyer selected will be one who purchases neither cake mix nor muffin mix?
Options:
A)1/10
B)3/10
C)1/2
D)7/10
E)29/100
Rationale: C+M+B-CM-MB-CB-2CMB = 100
C - cake buyers, M - muffin and B - Bread buyers. CM,MB,CB and CMB are intersecting regions.
the question asks for people who have bought only bread mixes = B-CB-MB-2CMB has to be found out.
50 + 40 + B-CB-MB-19 -2CMB = 100
B-CB-MB-2CMB = 29
hence the probability = 29/100.
E
Answer: E
Question: If two dice are thrown together, the probability of getting an even number on one die and an odd number on the other is?
Options:
A)1/8
B)1/2
C)1/9
D)11/1
E)1/12
Rationale: The number of exhaustive outcomes is 36.
Let E be the event of getting an even number on one die and an odd number on the other. Let the event of getting either both even or both odd then = 18/36 = 1/2
P(E) = 1 - 1/2
= 1/2.
Answer:B
Answer: B
Question: Expenditures of a Company (in Lakh Rupees) per Annum Over the given Years.
Year	Item of Expenditure
Salary	Fuel and Transport	Bonus	Interest on Loans	Taxes
1998	288	98	3.00	23.4	83
1999	342	112	2.52	32.5	108
2000	324	101	3.84	41.6	74
2001	336	133	3.68	36.4	88
2002	420	142	3.96	49.4	98
The total expenditure of the company over these items during the year 2000 is?
Options:
A)Rs. 544.44 lakhs
B)Rs. 544.54 lakhs
C)Rs. 544.79 lakhs
D)Rs. 545 lakhs
E)Rs. 546 lakhs
Rationale: Total expenditure of the Company during 2000
= Rs. (324 + 101 + 3.84 + 41.6 + 74) lakhs
= Rs. 544.44 lakhs.
A)
Answer: A
Question: 3/5 of all married couples have more than one child. 2/5 of all married couples have more than 3 children. What fraction of all married couples have 2 or 3 children?
Options:
A)1/5
B)1/4
C)7/20
D)3/5
E)It cannot be determined from the given information.
Rationale: Plug in simple numbers. Take 100 couples for example.
3/5 of 100 couples have more than one child = 60 couples.
2/5 of 100 couples have more than 3 kids = 40 couples.
This implies that 40 couples are a subset of 60 couples and the complement of 60 couples within those 100 couples, which equals 20 couples have either one or no kids at all.
We need to find couples that have 2 or 3 kids, so essentially, it is 60 - 40 = 20. Fraction will be 20/100 = 1/5.
Option A
Answer: A
Question: The owner of a furniture shop charges his customer 25% more than the cost price. If a customer paid Rs. 8340 for a computer table, then what was the cost price of the computer table?
Options:
A)Rs.6672
B)Rs.6727
C)Rs.6908
D)Rs.6725
E)Rs.6728
Rationale: CP = SP * (100/(100 + profit%))
= 8340(100/125) = Rs.6672.
Answer: A
Answer: A
Question: What profit percent is made by selling an article at a certain price, if by selling at 2/3rd of that price, there would be a loss of 18%?
Options:
A)20%
B)26%
C)42%
D)27%
E)23%
Rationale: SP2 = 2/3 SP1
CP = 100
SP2 = 82
2/3 SP1 = 82
SP1 = 123
100 --- 23 => 23%
Answer: E
Answer: E
Question: If k is the sum of the digits of integer m, and m=16n, where n is an integer, which of the following must be true?
Options:
A)k is not divisible by 9
B)The sum of the digits of k is 9
C)m is a multiple of 2k
D)k is a multiple of 9
E)k is a multiple of 6
Rationale: m= 16n i.e n =1,2,3 ,4 etc or -1,-2.-3 ,-4 then m 16,32,48,64 or -16 ,-32 ,-48 ,-64 then k 7,5 12,10 or -(1+6) , -(3+2) , -(4+8) ,-(6+4)
ans A
Answer: A
Question: Ramesh purchased a refrigerator for Rs. 12500 after getting a discount of 20% on the labelled price. He spent Rs. 125 on transport and Rs. 250 on installation. At what price should it be sold so that the profit earned would be 10% if no discount was offered?
Options:
A)17603
B)17608
C)17628
D)17600
E)176023
Rationale: Price at which the TV set is bought = Rs. 12,500
Discount offered = 20%
Marked Price = 12500 * 100/80 = Rs. 15625
The total amount spent on transport and installation = 125 + 250 = Rs. 375\Total price of TV set = 15625 + 375
= Rs. 16000
The price at which the TV should be sold to get a profit of 10% if no discount was offered = 16000 * 110/100
= Rs. 17600
Answer: D
Answer: D
Question: A train covers a distance of 12 km in 10 min. If it takes 9 sec to pass a telegraph post, then the length of the train is?
Options:
A)298
B)288
C)120
D)776
E)180
Rationale: Speed = (12/10 * 60) km/hr = (72 * 5/18) m/sec = 20 m/sec.
Length of the train = 20 * 9
= 180 m.
Answer:E
Answer: E
Question: HCF and LCM two numbers are 12 and 396 respectively. If one of the numbers is 48, then the other number is?
Options:
A)99
B)66
C)132
D)264
E)364
Rationale: 12 * 396 = 48 * x
x = 99
ANSWER:A
Answer: A
Question: The length of a room is 5 m and width is 4.75 m. What is the cost of paying the floor by slabs at the rate of Rs. 900 per sq. metre.
Options:
A)21375
B)25750
C)26550
D)26750
E)25725
Rationale: Area = 5 × 4.75 sq. metre.
Cost for 1 sq. metre. = Rs. 900
Hence total cost = 5 × 4.75 × 900
= 5 × 4275 = Rs. 21375
Answer is A.
Answer: A
Question: A circular rim 28 inches in a diameter rotates the same number of inches per second as a circular rim 35 inches in diameter. If the smaller rim makes B revilutions per second, how many revilutions per minute does the larger rim makes in terms of B?
Options:
A)a) 48pi/B
B)b) 75m
C)c) 48B
D)d) 24B
E)e) B/75
Rationale: distance covered by a circular wheel per sec* = 2*pi* r * n
where n is number of revolution
So we know the smaller rim makes B rev per sec so the inches coverd SR per sec = 28 * pi* B
the problem the say SR rotates the same number of inches as the LR.
The inches covered by the LR per sec = 35 * pi*Y
So equate both u will get Y = 4/5 B
Theis is in sec we need the answer in min so 48B
answer is C
Answer: C
Question: for every correct answer 4 is awarded but for a wrong answer 2 is deducted. If there are a total of 150 questions and sukanya scores 480 how many answers of sukanya were correct?
Options:
A)110
B)120
C)130
D)140
E)150
Rationale: If x questions are correct, then
4x-2(150-x) = 480
6x= 780
x=130
so 130 questions are correct.
ANSWER:C
Answer: C
Question: The length of a rectangle is twice its breadth. If its length is decreased by 5 cm and breadth is increased by 5 cm, the area of the rectangle is increased by 75 sq.cm. What is the length of the rectangle
Options:
A)18 cm
B)16 cm
C)40 cm
D)20cm
E)28 cm
Rationale: Explanation:
Let breadth =x cm
Then, length =2x cm
Area =x×2x=2x^2 sq.cm.
New length =(2x−5) cm
New breadth =(x+5) cm
New area =(2x−5)(x+5) sq.cm.
Given that, new area = initial area +75 sq.cm.
⇒(2x−5)(x+5)=2x^2+75
⇒2x^2+10x−5x−25=2x^2+75
⇒5x−25=75
⇒5x=75+25=100
⇒x=1005=20 cm
Length =2x=2×20=40 cm
Answer: Option C
Answer: C
Question: Two vessels A and B contain milk and water mixed in the ratio 4:3 and 2:3 in what ratio must these mixtures be mixed to form new mixture containing half milk and half water?
Options:
A)7:6
B)7:1
C)7:5
D)7:2
E)7:8
Rationale: Answer with Explanation: Step (i): Let C.P. of 1 liter milk be Re.1 Ratio of mixture in A = 4:3  Milk in 1 litre mixture in A = 4/7 lit,  C.P of 1 litre mix of A = Rs. 4/7 Ratio of mix in B = 2:3  Milk in 1 litre mixture in B = 2/5 lit,  C.P of 1 litre mix of B = Rs. 2/5 Ratio of new mixture = 1:1  Milk in 1 litre mixture = 1/2 lit,  C.P of 1 litre mix = Rs. ½ (Mean price = re. ½ ) Step (ii) By the rule of alligation C.P. of 1 lit mix. In A (d) C.P. of 1 lit mix. In B (c) 4/7 2/5
Mean Price (m)
m-c (1/2 – 2/5) = 1/10 1/2 d-m (4/7 – 1/2) = 1/14
Required Ratio = 1/14 : 1/10 = 7 : 5
Answer:C
Answer: C
Question: In how many ways can three consonants and two vowels be selected from the letters of the word "TRIANGLE"?
Options:
A)28 ways
B)35 ways
C)67 ways
D)23 ways
E)30 ways
Rationale: The word contains five consonants. Three vowels, three consonants can be selected from five consonants in ⁵C₃ ways, two vowels can be selected from three vowels in ³C₂ ways.
3 consonants and 2 vowels can be selected in ⁵C₂ . ³C₂ ways i.e., 10 * 3
=30 ways.
Answer:E
Answer: E
Question: A man sells an article at a profit of 25%. If he had bought it at 20% less and sold it for Rs.14.70 less, he would have gained 30%. Find the cost of the article.
Options:
A)30
B)40
C)50
D)60
E)70
Rationale: Let C.P=100
Gain=25%
S.P=125
Supposed C.P=80
Gain=30%
S.P=(130*80)/100=104
Diff=(125-104)=21
Diff 21 when C.P=100
then Diff 14.70 when C.P=(100*14.70)/21=70
ANSWER:E
Answer: E
Question: In how many ways Chief Minister and Minister be elected from a team of 14 members?
Options:
A)162 ways
B)192 ways
C)182 ways
D)172 ways
E)152 ways
Rationale: To do this, if captain is elected first, then we have 14 ways of doing this.
For election of vice-captain, we have only 13 ways left, Bcoz 1 way is already consumed. (Situations like this is called dependent situation. One selection depends upon other selection.)
So, the ans is 14*13= 182 ways.
C
Answer: C
Question: y selling 12 pencils for a rupee a man loses 20%. How many for a rupee should he sell in order to gain 20%?
Options:
A)8
B)9
C)7
D)5
E)4
Rationale: 80% --- 12
120% --- ?
80/120 * 12 = 8
Answer: A
Answer: A
Question: The sum of the ages of 5 children born at the intervals of 4 years each is 50 years. what is the age of the eldest child ?
Options:
A)15
B)8
C)18
D)None of these
E)Cannot be determined
Rationale: Explanation:
Let x = the youngest child. Each of the other four children will then be x+4, x+8, x+12, x+16.
We know that the sum of their ages is 50 .
so, x+(x+4)+(x+8)+(x+12)+(x+16) = 50
x= 2
The youngest child is 2 years old.
Age of eldest child is = 2+16 = 18
Answer: C
Answer: C
Question: (64 - 12)2 + 4 x 64 x 12 = ?
Options:
A)5246
B)4406
C)5126
D)5776
E)None of these
Rationale: Explanation :
Here, the given statement is like (a - b)2 + 4ab where a= 64 and b = 12
(a - b)2 + 4ab = (a2 - 2ab + b2) + 4ab = a2 + 2ab + b2 = (a + b)2
Hence (64 - 12)2 + 4 x 64 x 12 = (64 + 12)2 = 762 = 5776. Answer : Option D
Answer: D
Question: The forth proportional to 10,8,15 is?
Options:
A)15
B)12
C)18
D)20
E)24
Rationale: Let the fourth proportional to 10,8,15 be x
then 10:8::15:x
10x = 8*15
x = 12
Answer is B
Answer: B
Question: In an examination a pupil's average marks were 63 per paper. If he had obtained 20 more marks for his Geography paper and 2 more marks for his History paper, his average per paper would have been 65. How many papers were there in the examination?
Options:
A)176
B)9
C)87
D)11
E)16
Rationale: Let the number of papers be x. Then,
63x + 20 + 2 = 65x
= 2x = 22
= x = 11.
Answer:D
Answer: D
Question: Two trains are moving in the same direction at 72 kmph and 36 kmph. The faster train crosses a man in the slower train in 48 seconds. Find the length of the faster train?
Options:
A)270
B)288
C)266
D)299
E)480
Rationale: Relative speed = (72 - 36) * 5/18 = 2 * 5 = 10 mps.
Distance covered in 27 sec = 48 * 10 = 480 m.
The length of the faster train = 480 m.
Answer: E
Answer: E
Question: A person bought 110 glass bowls at a rate of Rs. 10 per bowl. He sold 100 of them at Rs. 14 and the remaining broke. What is the percentage gain for A?
Options:
A)40
B)300/11
C)243/7
D)279/11
E)279/8
Rationale: CP=110*10=1100 and SP=100*14=1400
Gain %= 100*(1400-1100)/1100= 300/11
ANSWER:B
Answer: B
Question: A, B and C started a shop by investing Rs. 27,000, Rs. 72,000 and Rs. 81,000 respectively. At the end of the year, the profits were distributed among them. If C’s share of profit be Rs. 36,000, then the total profit was :
Options:
A)30,000
B)60,000
C)80,000
D)120,000
E)None
Rationale: Sol.
A : B : C = 27000 : 72000 : 81000 = 3: 8 : 9. so, C’s share : Total Profit = 9 : 20.
Let the total profit be Rs. x. Then, 9/20 = 36000/x or x
= 36000 * 20 / 9 = 80000.
Answer C
Answer: C
Question: The jogging track in a sports complex is 1040 m in circumference. Kapil and his wife start from the same point and walk in opposite directions at 7.5 km/hr and 3.7 km/hr respectively. They will meet for the first time in?
Options:
A)3.12 min
B)3.74 min
C)4.25 min
D)4.90 min
E)5.57 min
Rationale: Clearly, the two will meet when they are1040 m apart.
To be (7.5 + 3.7) = 11.2 km apart, they take 1 hour. THat is 60 minutes.
To be 1040m apart, they take
= (1040/11200 * 60) min
= 5.57 min.
Answer: E
Answer: E
Question: A shopkeeper sells three items P, Q and R and incurs a loss of 21, 11 and 10respectively. The overall loss percentage on selling P and Q items is 14.33 and that of Qand R items is 10.4. Find the overall loss percentage on selling the three items?
Options:
A)15%
B)12.16%
C)13.4%
D)20.2%
E)None of these
Rationale: Explanation :
Let the costs of the items P, Q and R are Rs p, Rs q and Rs r respectively.
And, S.P pf the items P, Q and R are 0.79p, 0.89p and 0.9r respectively.
Overall loss percentage of the 1st two items = 14.33%
=>(0.21p+0.11q)/(p+q)=0.1433
=>p/q=1/2.
Overall loss percentage of the 2nd and 3rd item =10.4%
=>(0.11q+0.1r)/(q+r)=0.104.
=>q/r=2/3.
Therefore, the overall loss percentage is :
=>(0.21p+0.11q+0.1r)x100/(p+q+r).
=>(1(0.21)+2(0.11)+3(0.1))x100/(1+2+3).
=>0.1216×100.
=>12.16%.
Answer : B
Answer: B
Question: Three hundred multiples of seven are chosen at random, and 450 multiples of eight are chosen at random. Approximately what percentage of the 750 selected numbers are odd?
Options:
A)20%
B)25%
C)40%
D)50%
E)80%
Rationale: About half the multiples of seven will be odd while all the multiples of eight are even.
The percentage of odd numbers is about (1/2)(300) / 750 = 20%
The answer is A.
Answer: A
Question: mixture contains alcohol and water in the ratio 4 : 3. If 6 liters of water is added to the mixture, the ratio becomes 4: 5. Find the quantity of alcohol in the given mixture.
Options:
A)10
B)6.8
C)27
D)22
E)29
Rationale: Let the quantity of alcohol and water be 4x litres and 3x litres respectively
24x = 4(3x+5)
12x = 20
x = 1.7
Quantity of alcohol = (4 x 1.7) litres = 6.8 litres.
Answer: B
Answer: B
Question: Two goods trains each 500 m long are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one?
Options:
A)14 sec
B)87 sec
C)48 sec
D)17 sec
E)16 sec
Rationale: Relative speed = 45 + 30 = 75 km/hr.
75 * 5/18 = 125/6 m/sec.
Distance covered = 500 + 500 = 1000 m.
Required time = 1000 * 6/125 = 48 sec.
Answer:C
Answer: C
Question: A certain no. when divided by 65 leaves a remainder 25, what is the remainder if the same no.be divided by 15?
Options:
A)2
B)4
C)6
D)8
E)9
Rationale: Explanation:
65 + 25 = 90/15 = 6 (Remainder)
C
Answer: C
Question: Kateys mom has $137 to pay 12 kids to clean up her backyard. How much more money does she need to be able to pay each of the 12 kids $12?
Options:
A)8
B)7
C)9
D)11
E)4
Rationale: 12*12=144, not 137.
144-137=7
Kateys mom needs 7 more dollars to be able to pay each kid $12
Therefore B is correct
Answer: B
Question: A car averages 35 miles per hour for the first 4 hours of a trip and averages 53 miles per hour for each additional hour of travel time. If the average speed for the entire trip is 50 miles per hour, how many hours long is the trip?
Options:
A)16
B)18
C)20
D)22
E)24
Rationale: Let T be the total time of the trip.
35*4 + 53(T-4) = 50T
3T = 212-140
T = 24
The answer is E.
Answer: E
Question: How many liters of a 40% iodine solution need to be mixed with 35 liters of a 20% iodine solution to create a 32% iodine solution?
Options:
A)35
B)49
C)100
D)102
E)140
Rationale: Solution 1:
Assume the iodine solution to be mixed = x lts.
Iodine = 0.4x lts, Water = 0.6x lts.
Solution 2: 35 liters of a 20% iodine solution
Iodine = 7 lts, Water = 28 lts.
Total iodine = 0.4x + 7
Total water = 0.6x + 28
The resultant is a 35% idoine solution.
Hence (0.4x + 7) / (x + 35) = 32/100
40x + 700 = 32x + 1120
8x = 820
x = 102 lts
Correct Option: D
Answer: D
Question: For which of the following “n” is the number 2^74 +2^2058+2^2n is a perfect square?
Options:
A)22777
B)2686
C)8667
D)2020
E)99771
Rationale: 2^74 +2^2058+2^2n = K2K2
2^74 +2^2058+2^2n = (237)2+22058+(2n)2(237)2+22058+(2n)2
We try to write this expression as (a+b)2=a2+2ab+b2(a+b)2=a2+2ab+b2
Now a = 237237, 2ab = 2205822058 and b = 2n2n
Substituting the value of a in 2ab, we get b = 2020
Ans: D
Answer: D
Question: A teacher will pick a group of 5 students from a group of 9 students that includes Bart Lisa and john. If one of all the possible 5-student groups is picked at random, what is the probability of picking a group that includes john Bart and Lisa?
Options:
A)5/97
B)3/41
C)7/41
D)5/42
E)2/21
Rationale: Probability = Favorable Outcomes / Total Outcomes
Total Outcomes= Total No. of ways of Picking Group of 5 out of 9 = 9C5 = 9! / (5! * 4!) = 126
Favorable Outcomes= Total No. of ways of Picking Group of 5 out of 9 such that J, B and L are always in the group (i.e. we only have to pick remaining 2 out of remaining 6 as J, B and L must be there is group) = 6C2 = 15
Hence,Probability=15/126=5/42
Answer: Option D
Answer: D
Question: Which of these must the factor F of the product of four consecutive even integers:-
1) 48
2) 64
3) 96
4) 192
5) 80
Options:
A)1,2 only
B)F=2,3 only
C)F=1,2,3 only
D)F=1,2,3,4 only
E)All of them
Rationale: Let the four variables be a< b< c< d.
Assume a worst case scenario where the a equal to a prime number (hence odd).
therefore
a = divisible by 1
b = a + 1 (divisible by 2)
c = a + 3 (divisible by 3)
d = a + 4 (divisible by 4)
therefore
each answer choice must be divisible by 2 x 3 x 4 = 24
only 80 is not divisible. Therefore answer = D
Answer: D
Question: If x is to be chosen at random from the set {5,6,7,8} and y is to be chosen at random from the set {1,2,3}, what`s the probability that xy will be even?
Options:
A)1/6
B)1/3
C)2/3
D)1/2
E)5/6
Rationale: The product to be even either one or both must be even, so:
P(x=even OR y=even)=P(x=even)+P(y=even)-P(x=even AND y=even)=2/4+1/3-2/4*1/3=2/3;
Or: P(xy=even)=1-P(xy=odd)=1-2/4*2/3=2/3, so basically we find the probability of the product to be odd (which happens when both x and y are odd) and subtract it from 1.
Answer: C.
Answer: C
Question: A candidate who gets 30% of the marks fails by 30 marks. But another candidate who gets 45% marks gets 15 marks more than necessary for passing. Find the number of marks for passing?
Options:
A)100 Marks
B)200 Marks
C)280 Marks
D)371 Marks
E)120 Marks
Rationale: 30% ------------ 30
45% ------------ 15
----------------------
15% ------------- 45
30% -------------- ?
90 + 30 = 120 Marks
Answer:E
Answer: E
Question: A ladder learning against a wall makes an angle of 60° with the ground. If the length of the ladder is 19 m, find the distance of the foot of the ladder from the wall.
Options:
A)9 m
B)9.5 m
C)10.5 m
D)12 m
E)None
Rationale: Let AB be the wall and BC be the ladder.
Then, < ABC	= 60°
and, BC	= 19 m.;
AC = x metres
AC/BC	= cos 60°
= x / 19
=1 / 2
x= 19/2
= 9.5 m.
Answer B
Answer: B
Question: A family made a down payment of $75 and borrowed the balance on a set of encyclopedias that cost $300. The balance with interest was paid in 23 monthly payments of $12 each and a final payment of $3. The amount of interest paid was what percent of the amount borrowed?
Options:
A) 23%
B) 20%
C) 25%
D) 26%
E) 24%
Rationale: borrowings = 300-75 = 225
total pmt = 23x12 + 3 = 279
so int = 279 - 225 = 54
interest in terms of borrowing = 54/225 = 24%
Answer is D
Answer: D
Question: The average of 9 observations was 4, that of the 1st of 5 being 10 and that of the last 5 being 8. What was the 5th observation?
Options:
A)54
B)12
C)15
D)17
E)18
Rationale: Explanation:
1 to 9 = 9 * 4 = 36
1 to 5 = 5 * 10 = 50
5 to 9 = 5 * 8 = 40
5th = 50 + 40 = 90 – 36 = 54
Option A
Answer: A
Question: What is the square root of 225?
Options:
A)6
B)9
C)12
D)45
E)15
Rationale: 15X15 = 225
ANSWER E
Answer: E
Question: The average of 11 results is 55, if the average of first six results is 49 and that of the last six is 52. Find the sixth result?
Options:
A)A)46
B)B)1
C)C)66
D)D)76
E)E)74
Rationale: 1 to 11 = 11 * 55 = 605
1 to 6 = 6 * 49 = 294
6 to 11 = 6 * 52 = 312
6th = 294 + 312 –605= 1
Answer:B
Answer: B
Question: Total number of men, women and children working in a factory is 18. They earn Rs. 4000 in a day. If the sum of the wages of all men, all women and all children is in ratio of 18: 10: 12 and if the wages of an individual man, woman and child is in ratio 6: 5: 3, then how much a woman earn in a day?
Options:
A)Rs. 120
B)Rs. 150
C)Rs. 250
D)Rs. 400
E)None of these
Rationale: Solution: Ratio of number of men, women and children,
= (18/6): (10/5):(12/3) = 3:2:4
Total (Men +Women +Children) = 18
3X +2X +4X = 18
9X = 18
X = 2
Hence, number of women = 2X = 2*2 = 4
Share of all women = (10*4000)/40 = Rs. 1000 [18+10+12 =40]
Thus, share of each woman = 1000/4 = Rs. 250.
Answer: Option C
Answer: C
Question: A man swims downstream 30 km and upstream 20 km taking 5 hours each time, what is the speed of the man in still water?
Options:
A)7
B)8
C)2
D)5
E)4
Rationale: 30 --- 5 DS = 6
? ---- 1
20 ---- 5 US = 4
? ---- 1 M = ?
M = (6 + 4)/2 = 5
Answer:D
Answer: D
Question: A computer store offers employees a 30% discount off the retail price. If the store purchased a computer from the manufacturer for $1500 dollars and marked up the price 30% to the final retail price, how much would an employee save if he purchased the computer at the employee discount (30% off retail price) as opposed to the final retail price.
Options:
A)525
B)545
C)565
D)575
E)585
Rationale: Cost price=1500
Profit=30% =30% of 1500=450
selling price=CP+ Profit
SP=1950
a Discount of 30% to employees means 30% off on 1950
so 30% of 1950= 585
Ans E
Answer: E
Question: What will be the ratio between the area of a rectangle and the area of a triangle with one of the sides of the rectangle as base and a vertex on the opposite side of the rectangle ?
Options:
A)1:1
B)1:2
C)2:3
D)2:1
E)None of these
Rationale: Explanation:
As far as questions of Area or Volume and Surface area are concerned, it is all about formulas and very little logic. So its a sincere advice to get all formulas remembered before solving these questions.
Lets solve this,
Area of rectangle =l∗b
Area of triangle =1/2l∗b
Ratio =l∗b:1/2l∗b
=1:1/2
=2:1
Option D
Answer: D
Question: The average age of three boys is 20 years and their ages are in proportion 3:5:7. What is the age in years of the youngest boy?
Options:
A)6
B)9
C)8
D)4
E)12
Rationale: 3x + 5x + 7x = 60
x =4
3x = 12
Answer:E
Answer: E
Question: the average age of 56 employees in a company is 35. An employee aged 60 is retired and a fresher of age 20 is taken in. What is the new age average of employees?
Options:
A)25.45
B)32.26
C)33.13
D)34.28
E)35.55
Rationale: The sum of age of the employees when the age average is 35 = 35x56 =1960
The sum of ages of the employees of new group= (1960-60)+20 = 1920
The average age of the new group= 1920/56 = 34.28
Answer: D
Answer: D
Question: A part-time employee whose hourly wage was decreased by 20 percent decided to increase the number of hours worked per week so that the employee's total income did not change. By what percent R should the number of hours worked be increased?
Options:
A)12.5%
B)20%
C)25%
D)50%
E)100%
Rationale: Correct Answer: C
Solution: C. We can set up equations for income before and after the wage reduction. Initially, the employee earns W wage and works H hours per week. After the reduction, the employee earns .8W wage and works X hours. By setting these equations equal to each other, we can determine the increase in hours worked: WH = .8WX (divide both sides by .8W) 1.25H = X We know that the new number of hours worked R will be 25% greater than the original number. The answer is C.
Answer: C
Question: The average age of 6 boys is 25 years and their ages are in the proportion 3:5:7. The age of the youngest boy is?
Options:
A)10years
B)15years
C)20years
D)25years
E)30years
Rationale: Total age of 6 boys = 25*6 = 150
ratio of their ages = 3:5:7
Age of the youngest = 150*3/15 = 30 years
Answer is E
Answer: E