divelab/Sys2Bench huggingface dataset:
Question: At Veridux Corporation, there are 200 employees. Of these, 90 are female, and the rest are males. There are a total of 40 managers, and the rest of the employees are associates. If there are a total of 135 male associates, how many female managers are there?
Options:
A)15
B)20
C)25
D)30
E)65
Rationale: Well, first letâ€™s take care of the â€œtotalsâ€. The numbers in the â€œtotalsâ€ row must add up. If 90 are females, the other 200 â€“ 90 = 110 must be males. Similarly, the numbers in the â€œtotalsâ€ column must add up. If 40 are managers, then the other 200 â€“ 40 = 160 must be associates.
Now, in the â€œassociateâ€ row, 135 + E = 160, which means E = 25 â€” the other 25 associates must be female.
Now, to find B, which is what the question is asking, we need only look at the sum in the â€œfemaleâ€ column: B + 25 = 90, which means B = 65. There are fifteen female managers in this company. Thus, the answer = (E).
Answer: E
Question: The average age of a class of 39 students is 15 years. If the age of the teacher be included, then the average increased by 3months. Find the age of the teacher?
Options:
A)25
B)28
C)30
D)35
E)39
Rationale: Total age of 39 persons = 39*15 = 585 years
Average age of 40 persons = 15yrs 3months = 61/4 years
Total age of 40 persons = 61/4 * 40 = 610 years
Age of the teacher = 610-585 = 25 years
Answer is A
Answer: A
Question: A beats B by 50m in a race of 500m ,then B beats by C by 25m in a race of 500m.Find the
distance by which A beats C in a race of 400?
Options:
A)55m
B)56m
C)57m
D)58m
E)59m
Rationale: A beats B in 500m race by 50m
so,for every 10 m race A beat B by 1m..
So,in 400 m race A beat B by 40m
In a case of B & C,
B beats C by 25m in 500m race..
So,B beats C by 1m in 20 m race
Now,in a 400m race B beats C by 18m..
In a 400m race,
A beats B by 40m & B beats C by 18m..
So,A beats C by 58m
ANSWER:D
Answer: D
Question: By selling 8 pencils for a rupee a man loses 60%. How many for a rupee should he sell in order to gain 60%?
Options:
A)8
B)9
C)2
D)6
E)4
Rationale: 40% --- 8
160% --- ?
40/160 * 12 = 2
Answer: C
Answer: C
Question: Find the odd man out. 14, 28, 42, 56, 60, 75, 88
Options:
A)75
B)25
C)51
D)90
E)115
Rationale: Explanation :
All except 75 are multiples of 14
Answer : Option A
Answer: A
Question: In a van there are men and goats. In all, there are 10 heads and 30 feet. How many men and how many goats are in the van?
Options:
A)5 men and 5 goats.
B)6 men and 5 goats.
C)4 men and 5 goats.
D)5 men and 6 goats.
E)5 men and 4 goats.
Rationale: 5 men and 5 goats.
Let M = men and G = Goats. We can come up with 2 equations.
M + G = 10
2M + 4G= 20
Solving the 2 equations will give 5 men and 5 goats.
Answer A
Answer: A
Question: P, Q and R have $8000 among themselves. R has two-thirds of the total amount with P and Q. Find the amount with R?
Options:
A)2400
B)2403
C)3200
D)2539
E)1930
Rationale: C
3200
Let the amount with R be $ r
r = 2/3 (total amount with P and Q)
r = 2/3(8000 - r) => 3r = 16000 - 2r
=> 5r = 16000 => r = 3200.
Answer: C
Question: Karol is three times Alice’s age but only twice as old as Betty. Alice is twelve years younger than Karol. How old is Betty?
Options:
A)6
B)9
C)12
D)18
E)24
Rationale: ans B..9..
given that K=3A=2B..AND A=K-12..
substituting the values A=6,K=18 AND B=9..
Answer: B
Question: By selling an umbrella for Rs. 500, a shop keeper gains 20%. During a clearance sale, the shopkeeper allows a discount of 10% on the marked price. His gain percent during the sale is?
Options:
A)15%
B)12.5%
C)18%
D)11.11%
E)14%
Rationale: Marked price = Rs. 500
C.P. = 100/120 * 500 = Rs. 400
Sale price = 90% of Rs. 500 = Rs. 450
Required gain % = 50/400 * 100 =12.5%.
Answer: B
Answer: B
Question: Find (7x + 4y ) / (x-2y) if x/2y = 3/2 ?
Options:
A)6
B)8
C)7
D)5
E)none of these
Rationale: if x/2y = 3/2
2x=6y ==> x=3y
so the problem becomes
7(3y)+4y / 3y-2y
By solving this, we will get answer 25.
ANSWER:E
Answer: E
Question: A grocer has a sale of Rs 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs, 6500 ?
Options:
A)4991
B)2367
C)1976
D)1627
E)1981
Rationale: Explanation:
Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009.
Required sale = Rs.[(6500 x 6) - 34009]
= Rs. (39000 - 34009)
= Rs. 4991.
Answer: A
Answer: A
Question: What is the least multiple of 7 which leaves a remainder of 4 when divided by 6, 9, 15 and 18 ?
Options:
A)364
B)350
C)343
D)371
E)398
Rationale: LCM of 6, 9, 15 and 18 = 90
Required Number = (90k + 4) which is a multiple of 7
Put k = 1. We get number as (90 × 1) + 4 = 94. But this is not a multiple of 7
Put k = 2. We get number as (90 × 2) + 4 = 184. But this is not a multiple of 7
Put k = 3. We get number as (90 × 3) + 4 = 274. But this is not a multiple of 7
Put k = 4. We get number as (90 × 4) + 4 = 364. This is a multiple of 7
Hence 364 is the answer. Answer: Option A
Answer: A
Question: Three pipes of same capacity can fill a tank in 8 hours. If there are only two pipes of same capacity, the tank can be filled in.
Options:
A)11 hours
B)12 hours
C)15 hours
D)16 hours
E)17 hours
Rationale: The part of the tank filled by three pipes in one hour = 1/8
=> The part of the tank filled by two pipes in 1 hour = 2/3 * 1/8 = 1/12.
The tank can be filled in 12 hours.
Answer: B
Answer: B
Question: ?% of 360 = 126
Options:
A)277
B)35
C)64
D)72
E)None of these
Rationale: ?% of 360 = 126
or, ? = 126×100/360=35
Answer B
Answer: B
Question: A man drive his car to the office at 20miles/hr.
After reaching office, he realize that its a new year holiday so he went back home at a speed of 30miles/hr.
Discounting the time spent in the stoppage what was his average speed of his journey ?
Options:
A)23miles/hr
B)24miles/hr
C)25miles/hr
D)26miles/hr
E)None
Rationale: Solution:
24miles/hr (not 25miles/hr which might be guessed by many)
D : distance traveled
T1 : time of going to office
T2 : time of returning back
Y : Average Speed
D = 20 * T1
T1 = D/20
D = 30 * T2
T2 = D/30
2D = Y(T2 + T1)
2D = Y(D/20 + D/30)
2D = Y(3D/60 + 2D/60)
2D = Y(5D/60)
Y = 120D/5D
=> Y = 24
Answer B
Answer: B
Question: There are 6 periods in each working day of a school. In how many ways can one organize 5 subjects such that each subject is allowed at least one period?
Options:
A)3200
B)3600
C)2400
D)3400
E)None of these
Rationale: 5 subjects can be arranged in 6 periods in 6P5 ways.
Remaining 1 period can be arranged in 5P1 ways.
Two subjects are alike in each of the arrangement. So we need to divide by 2! to avoid overcounting.
Total number of arrangements = (6P5 x 5P1)/2! = 1800
ANSWER:E
Answer: E
Question: Each person in a group of 110 investors has investments in either equities or securities or both. Exactly 25 of the investors in equities have investments in securities, and exactly 40 of the investors in securities have investments in equities. How many have investments in equities?
Options:
A)65
B)80
C)120
D)180
E)190
Rationale: Explanation :
The investors can be categorized into three groups:
(1) Those who have investments in equities only.
(2) Those who have investments in securities only.
(3) Those who have investments in both equities and securities.
Let x, y, and z denote the number of people in the respective categories. Since the total number of investors is 110, we have :-
=>x+y+z=110 ------------- (1).
Also,
The number of people with investments in equities is x+z and
The number of people with investments in securities is y+z.
Since exactly 25% of the investors in equities have investments in securities, we have the equation
=>(25/100)×(x+z)=z.
=>(25/100)×x=75z/100.
=>x=3z. -------------- (2)
Since exactly 40% of the investors in securities have investments in equities, we have the equation
=>(40/100)×(y+z)=z.
=>(y+z)=5z/2.
=>y=3z/2. -----------------(3)
Substituting equations (2) and (3) into equation (1) gives:-
=>3z+(3z/2)+z=110.
=>11z/2=110.
=>z=110×2/11=20.
Hence, the number of people with investments in equities is:
=>x+z=3z+z=3×20+20=60+20= 80.
Answer : B
Answer: B
Question: A shirt goes on sale for 50% of its original price. One week later, the sale price is marked down 10%. The final price is what percent of the original price?
Options:
A)72%
B)70%
C)52%
D)50%
E)45%
Rationale: Just assume original price is 100.
Sale price = 50
Then it is marked down by 10% = 50-5=45.
Hence it is 45% od the original price. Hence answer is E.
Answer: E
Question: If the price of an article went up by 50%, then by what percent should it be brought down to bring it back to its original price?
Options:
A)16 2/3%
B)16 4/3%
C)33 1/3%
D)16 6/3%
E)16 2/3%
Rationale: Let the price of the article be Rs. 100.
50% of 100 = 50.
New price
= 100 + 50 = Rs. 150
Required percentage
= (150 - 100)/150 * 100
= 50/150 * 100
= 100/3
= 33 1/3%.
Answer:C
Answer: C
Question: A bus takes 3 hours to cover a distance of 500 Km. how much should the speed in Kmph be maintained to cover the same direction in 5/3th of the previous time?
Options:
A)75 Kmph
B)100 Kmph
C)90 Kmph
D)65 Kmph
E)70 Kmph
Rationale: Time = 3
Distance = 500
5/3 of 3 hours = 3 * 5/3 = 5 Hours
Required speed = 500/5 = 100 Kmph
B
Answer: B
Question: Two trains having equal lengths, take 10 seconds and 15 seconds respectively to cross a post. If the length of each train is 120 meters, in what time (in seconds) will they cross each other when traveling in opposite direction?
Options:
A)10
B)11
C)12
D)13
E)14
Rationale: speed of train1 = 120/10 = 12 m/s
speed of train2 = 120/15 = 8 m/s
if they travel in opposite direction, relative speed = 12+8 = 20 m/s
distance covered = 120+120 = 240 m
time = distance/speed = 240/20 = 12 s
Answer is C.
Answer: C
Question: An ore contains 25% of an alloy that has 90% iron. Other than this, in remaining 75% of the ore ,there is no iron. How many kgs of the ore are needed to obtain 60 kg. of pure iron.?
Options:
A)266.69
B)266.67
C)266.66
D)263.66
E)266.61
Rationale: Explanation:
Let us take 100x kgs of ore. Now it contains 25x kgs of alloy and it contains 90% (25x) kgs of iron.
90% (25x) = 60 kg ⇒ x = 60×10090×12560×10090×125 = 8383
So iron ore required = 100 × 8383 = 266.66
Answer: D
Answer: D
Question: The mean of a data set is equal to 10 and its standard deviation is equal to 1. If we add 5 to each data value, then the mean and standard deviation become
Options:
A)mean = 15 , standard deviation = 6
B)mean = 10 , standard deviation = 6
C)mean = 15 , standard deviation = 1
D)mean = 10 , standard deviation = 1
E)None
Rationale: Solution
Since 5 is added to all data values, the mean will also increase by 5 and becomes 15. But the standard deviation which measure the "distance" between the mean and the data values does not change.
Answer C
Answer: C
Question: A room of 5 m 44 cm long and 3 m 74 cm broad is to be paved with square tiles. Find the least number of square tiles required to cover the floor.
Options:
A)136
B)146
C)166
D)176
E)216
Rationale: area of the room = 544 * 374 sq cm
size of largest square tile = H.C.F of 544 cm and 374 cm= 34 cm
area of 1 tile = 34*34 sq cm
no. of tiles required = (544*374) / (34 * 34) = 176
answer :D
Answer: D
Question: Sandeep's age after six years will be three-seventh of his father's age. Ten years ago the ratio of their ages was 1:5. What is Sandeep's father's age at present?
Options:
A)50
B)40
C)30
D)60
E)70
Rationale: Let the age of Sandeep and his father before 10 years be x and 5x respectively.
Given that Sandeep's age after six years will be three-seventh of his father's age
⇒x+16=37(5x+16)⇒7x+112=15x+48⇒8x=64⇒x=8
Sandeep's father's present age
=5x+10=5×8+10=50
Answer is A.
Answer: A
Question: The final exam of a particular class makes up 40% of the final grade, and Moe is failing the class with an average (arithmetic mean) of 45% just before taking the final exam. What grade does Moe need on his final exam in order to receive the passing grade average of 60% for the class?
Options:
A)75%
B)82.5%
C)85%
D)90%
E)92.5%
Rationale: Lets Assume that total marks are 100.
Final exam weightage : 40
Rest of the exams : 60
Percentage scored by Moe out of 60 = 45%
Hence, Total marks obtained out of 60 = 45% of 60 = 27
Marks required in the final exam to get 60% in end = 60(marks) - 27 = 33 marks
i.e. 33 marks required out of 40 = 82.5 marks required out of 100 in final exam
ANS: 82.5 % (B)
Answer: B
Question: The U.S. Defense Department has decided that the Pentagon is an obsolete building and that it must be replaced with an upgraded version: the Hexagon. The Secretary of Defense wants a building that is exactly 70 feet high and 200 feet on a side, and that has a hexagonal bull's-eye cutout in the center (somewhat like the current one) that is 45 feet on a side. What will be the volume of the new building in cubic feet?
Options:
A)3,937,500 cubic feet
B)15,750 cubic feet
C)6,906,336 cubic feet
D)15,750√3 cubic feet
E)3,937,500√3 cubic feet
Rationale: Volume of the Hexagon with side 200 and height 70 = Area * height
= 6*(sqrt(3)/4)(200^2)(70)
Volume of the center bull's eye that is similar in shape of a hexagon but side 45
= 6 * (sqrt(3)/4)(45^2)*70
Volume of the building = 6*(sqrt(3)/4)(200^2)(70) - 6 * (sqrt(3)/4)(45^2)*70=6,906,336
Answer is C
Answer: C
Question: -64*29+468=?
Options:
A)1430
B)1302
C)-2801
D)-1388
E)None of these
Rationale: => -64*(30-1)+468;
=> -(64*30)+64+468;
=> -1920+532=-1388.
Correct Option: D
Answer: D
Question: If a man walks to his office at ¾ of his usual rate, he reaches office 1/3 of an hour late than usual. What is his usual time to reach office?
Options:
A)1 hour
B)4 hour
C)2 hour
D)7 hour
E)9 hour
Rationale: Speed Ratio = 1:3/4 = 4:3
Time Ratio = 3:4
1 -------- 1/3
3 --------- ? è 1 hour
Answer: A
Answer: A
Question: On Saturday, Will ran 15 miles. Morgan ran 60% of the distance Will ran. Jackie ran 1/3 more distance than Morgan did, and Denilo ran 1 less mile than Jackie. How many miles did Denilo run?
Options:
A)12
B)13
C)11
D)15
E)10
Rationale: C
11
Will ran 15 miles.
Morgan ran 60% of the distance that Will did.
Morgan= 15 x .6
=9
Jackie ran 1/3 more distance than Morgan.
Morgan = 9 + (9 x 1/3)
= 9 + 3
= 12
Denilo ran one less mile than Jackie.
Denilo= 12-1
=11
Denilo ran 11 miles.
The correct answer is C.
Answer: C
Question: The two trains of lengths 400 m, 600 m respectively, running at same directions. The faster train can cross the slower train in 180 sec, the speed of the slower train is 48 km. then find the speed of the faster train?
Options:
A)66 Kmph
B)68 Kmph
C)88 Kmph
D)55 Kmph
E)44 Kmph
Rationale: Length of the two trains = 600m + 400m
Speed of the first train = X
Speed of the second train= 48 Kmph
1000/X - 48 = 180
1000/x - 48 * 5/18 = 180
50 = 9X - 120
X = 68 Kmph
Answer: B
Answer: B
Question: How high shall you count before you make use of the letter A?
Options:
A)1000
B)1200
C)1120
D)1800
E)1300
Rationale: A
1000
Answer: A
Question: Calculate how many seconds it will take for 4 bells to toll together again, given that they begin to toll together respectively at the intervals of 9, 12, 15 and 18 seconds?
Options:
A)186
B)130
C)180
D)181
E)120
Rationale: LCM of 9, 12, 15 and 18 is
180
LCM=180
ANSWER:C
Answer: C
Question: A shopping mall give 40% sale on T-shirts and increase 25% price of pants. The cost price of pants and T-shirts are 1500 and 400 respectively. Overall they makes a?
Options:
A)200
B)250
C)300
D)215
E)180
Rationale: Let the SP of the pants and T-shirts be Rs. p and Rs. t respectively.
p = 1500(1 + 25/100) = 1500 + 375
t = 400(1 - 40/100) = 400 - 160
Total SP - Total CP = p + t - (1500 + 400) = 375 - 160 = Rs. 215
As this is positive, an overall profit of Rs. 500 was made.
Answer: D
Answer: D
Question: Find the odd man out
1, 3, 7, 11, 15, 18, 21
Options:
A)3
B)7
C)18
D)21
E)1
Rationale: The 18 is the only even number in the series.
ANSWER:C
Answer: C
Question: Six friends go to see a comedy at the local movie theater and sit in a particular row together. If Grady and Howard are among those 6 friends but can never sit next to each other, how many 6-person seating arrangements are possible?
Options:
A)360
B)420
C)480
D)600
E)720
Rationale: Ways to arrange 6 people in a row = 6! = 720
From this we want to subtract all the arrangements where Grady and Howard are next to each other. If we consider Grady and Howard one unit (GH), then the number of arrangements of the GH unit and the 4 other friends is 5! And the number of arrangements of G and H within the GH unit are 2 (GH or HG). So the total number of arrangements of the 6 friends with Grady and Howard together are 5!*2
Number of permutations where Grady and Howard are not seated next to each other = 6! - 5!*2 = 720-120*2 = 480
Answer: C
Answer: C
Question: A boat can travel with a speed of 42 km/hr in still water. If the speed of the stream is 10 km/hr, find the time taken by the boat to go 70 km downstream
Options:
A)1 hour 40 min
B)2 hour 40 min
C)1 hour 21 min
D)1 hour 30 min
E)1 hour 50 min
Rationale: Speed of the boat in still water = 42 km/hr
speed of the stream = 10 km/hr
Speed downstream = (42+10) = 52 km/hr
Distance travelled downstream = 70 km
Time taken =distance/speed
=70/52
= 1.35 hours
= 1 hour 21 min.
ANSWER:C
Answer: C
Question: A can do a certain work in the same time in which B and C together can do it. If A and B together could do it in 10 days and C alone in 50 days, then B alone could do it in:
Options:
A)15 days
B)20 days
C)25 days
D)30 days
E)35 days
Rationale: Explanation:
(A + B)'s 1 day's work =1/10
C's 1 day's work =1/50
(A + B + C)'s 1 day's work =1/10+1/50=6/50=3/25.. (i)
A's 1 day's work = (B + C)'s 1 day's work .... (ii)
From (i) and (ii), we get: 2 x (A's 1 day's work) =3/25
A's 1 day's work =	3/50
B's 1 day's work=1/10-3/50=2/50=1/25
So, B alone could do the work in 25 days.
ANSWER IS C
Answer: C
Question: A train is 360 meter long is running at a speed of 45 km/hour. In what time will it pass a bridge of 140 meter length?
Options:
A)10 sec
B)20 sec
C)15 sec
D)40 sec
E)45 sec
Rationale: speed = 45*6/18 = 25/2
tot dist = 360+140 = 500
time = d/s
=500*2/25 = 40 sec
ANSWER D
Answer: D
Question: Helen went to the stationers and bought things worth Euro 40, out of which 30 paise went on sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax free items?
Options:
A)Euro 15
B)Euro 15.7
C)Euro 19.7
D)Euro 34.7
E)None
Rationale: Explanation: Let the amount taxable purchases be Euro x.
Then, 6% of x = 30/100
x = (30/100 x 100/6) = 5.
Cost of tax free items = Euro [40 - (5 + 0.30)] = Euro 34.70
Answer: Option D
Answer: D
Question: city A to city B, Andrew drove for 1 hour at 50 mph and for 3 hours at 60 mph. What was the average speed for the whole trip?
Options:
A)56
B)57.5
C)58
D)58.13
E)59.4
Rationale: The total distance is 1×50+3×60=2301×50+3×60=230. And the total time is 4 hours. Hence,
Average Speed=(Total DistanceTotal Time)=2304=57.5
B
Answer: B
Question: If w, x, and y are consecutive odd positive integers and w < x < y, which of the following could be equal to w - x - y ?
Options:
A)-7
B)-2
C)-1
D)0
E)3
Rationale: Since W, X and Y are CONSECUTIVE ODD POSITIVE INTEGERS and W < X < Y, we can start with the easiest set of values that comes to mind:
W = 1
X = 3
Y = 5
The question asks for what COULD be the value of W - X - Y.
In this case, the value would be...
1 - 3 - 5 = -7
-7 IS among the answer choices, so we're done.
A
Answer: A
Question: Two cars start from the opposite places of a main road, 150 km apart. First car runs for 25 km and takes a right turn and then runs 15 km. It then turns left and then runs for another 25 km and then takes the direction back to reach the main road. In the mean time, due to minor break down the other car has run only 35 km along the main road. What would be the distance between two cars at this point?
Options:
A)65
B)38
C)20
D)28
E)21
Rationale: Answer: A) 65 km
Answer: A
Question: Stock / Number of shares
V ------------ 68
W ---------- 112
X ------------ 56
Y ------------ 94
Z ------------ 45
The table shows the number of shares of each of the 5 stocks owned by Mr Sami. If Mr. Sami was to sell 20 shares of Stock X and buy 23 shares of stock Y, what would be the increase in the range of the numbers of shares of the 5 stocks owned by Mr. Sami?
Options:
A)4
B)6
C)9
D)14
E)20
Rationale: Based on the original number of shares, the range would be: 112 - 45 = 67
However, the prompt tells us that two of the values in the table are going to change. After the changes, the values will be:
V 68
W 112
X 36
Y 117
Z 45
Now the range is 117 - 36 = 81
The INCREASE in the range requires us to compare thenewrange to theoldrange: 81 - 67 = 14
D
Answer: D
Question: A basket of 1430 apples is divided equally among a group of apple lovers. If 45 people join the group, each apple lover would receive 9 apples less. How many apples F did each person get before 45 people joined the feast?
Options:
A)20.
B)21.
C)22.
D)23.
E)24.
Rationale: Before solving it algebraically, let us prime factorize 1430 = 2*5*11*13.
Since number of apples per person * total persons F= 1430, the answer should be a factor of 1430. Only C is. And that's your answer.C
Answer: C
Question: If X,Y is 22%,30% smaller than Z then how much percentage is Y greater than X?
Options:
A)10 10/39%
B)13%
C)13 1/2%
D)14%
E)15%
Rationale: X = 78 %
Y = 70 %
Z = 100 %
X-Y/X × 100 = 8/78 × 100 = 10 10/39% greater than X
A)
Answer: A
Question: A merchant purchased a jacket for $150 and then determined a selling price that equaled the purchase price of the jacket plus a markup that was 25 percent of the selling price. During a sale, the merchant discounted the selling price by 20 percent and sold the jacket. What was the merchant’s gross profit on this sale?
Options:
A)$0
B)$3
C)$4
D)$10
E)$15
Rationale: Let selling price = x
So, x = 150 + 25x/100
Calculating above, x = 200
Selling price =200
20% Discount on Selling price = 160
So, profit = 160-150 = 10 Answer = D
Answer: D
Question: There are 200 female managers in a certain company. Find the total number Y of female employees in the company, if 2/5 of all the employees are managers and 2/5 of all male employees are managers.
Options:
A)300
B)Y=400
C)Y=500
D)Y=600
E)None of these
Rationale: {Managers} = {Female Managers} + {Male Managers};
We are told that the total number of managers in the company is 2/5 of all the employees , thus{Managers} = 2/5 (M + F), where M and F are number of female and male employees, respectively.
Also, we know that 2/5 of all male employees are managers:{Male Managers} = 2/5 * Mas well as there are total of 200 female managers:{Female Managers} = 200;
Thus:2/5 (M + F) = 200 + 2/5 * M-->F = 500.
Answer: C.
Answer: C
Question: The number of meters in MB is equal to the square root of the number of centimeters in MB. What is the length of MB (1 meter=100 centimeters)?
Options:
A)100 meters
B)10 meters
C)100 centimeters
D)10 centimeter
E)1 centimeter
Rationale: I'd plug in the options for this question.
Check option A: if the number of meters in MB is 100, then the number of centimeters is 100*100. The square root of 100*100 is 100: 100 = 100.
Answer: A.
Answer: A
Question: On a summer camp, 25% of the campers paid $100 each, 35% paid $80 each and the rest paid $65 each. What percentage of the total amount paid came from the campers who paid $80?
Options:
A)18%
B)21%
C)26%
D)35.44%
E)37.5%
Rationale: let the total no of campers be 100
total amount = (25*100)+(35*80)+(40*65) = 2500+2800+2600= $7900
required percentage = (28/79)*100 = 400/12 = 100/3 =35.44%
D
Answer: D
Question: The average of 6 no.'s is 4.60. The average of 2 of them is 3.4, while the average of the other 2 is 3.8. What is the average of the remaining 2 no's?
Options:
A)2.3
B)6.6
C)3.6
D)4.5
E)4.6
Rationale: Sum of the remaining two numbers = (4.6 * 6) - [(3.4 * 2) + (3.8 * 2)]
= 27.60 - (6.8 + 7.6) = 27.60 - 14.40 = 13.20.
Required average = (13.2 / 2) = 6.6.
Answer : B
Answer: B
Question: A and B together can do a work in 6 days. If A alone can do it in 10 days. In how many days can B alone do it?
Options:
A)10
B)15
C)77
D)55
E)21
Rationale: 1/6 – 1/10 = 1/15
=> 15
Answer: B
Answer: B
Question: A = {1, 2, 3} and B = {4, 5, 6}.Find A-B
Options:
A){2,8,4}
B){1,3,5}
C){1,2,3}
D){5,10,15}
E){8,9,10}
Rationale: A = {1, 2, 3}
B = {4, 5, 6}
correct answer :A - B = {1, 2, 3}
C
Answer: C