divelab/Sys2Bench huggingface dataset:
Question: 2/5 of the fish in an aquarium are red and 1/4 of the fish are brown. 1/4 of the red fish and 2/5 of the brown fish are male. If the rest of the fish in the aquarium are female, what is the probability that a fish randomly picked from the aquarium is male?
Options:
A)1/4
B)1/5
C)1/10
D)1/12
E)1/20
Rationale: 1/4*2/5 + 2/5*1/4 = 1/5
The answer is B.
Answer: B
Question: If x is the product of three consecutive positive integers, which of the following must be true?
I. x is an integer multiple of 5.
II. x is an integer multiple of 3
III. x is an integer multiple of 6
Options:
A)a) I only
B)b) II only
C)c) I and II only
D)d) I and III only
E)e)II and III only
Rationale: The answer should be D i.e. X will be an integer and multiple of 3 and 6.
Let us take example n, n+1, n+2 as 3 three consecutive positive integers.
In a sequence of consecutive integers a number is multiple of 3 after every interval of 2 numbers i.e 3,4,5,6 Or 8,9,10,11,12
Hence in a product of 3 consecutive integers, the product is always divisible by 3.
Now, in a consecutive sequence every alternate is an even number, and when an even number is multiplied by 3 we will have 6 as one of the multiple also.
Now for a number to be a multiple of 4 we need at least 2 2's. this is only possible if the first number of three consecutive positive integers is an even number so that 3 is also even and we have 2 2's. But incase the sequence starts with odd we will have one 2 hence, the divisibility by 4 depends on the first number to be even
Answer E
Answer: E
Question: In a partnership between A, B and C. A's capital is Rs.5000. If his share of a profit of Rs.800 is Rs.300 and C's share is Rs.130, what is B's capital?
Options:
A)19878
B)12798
C)6166
D)11750
E)22073
Rationale: 300 + 130 = 430
800 - 430 = 370
300 ---- 5000
370 ---- ? => 6166
Answer: C
Answer: C
Question: If 10/b + 20/b + 30/b is an integer, which of the following must also be an integer?
Options:
A)20/b
B)b/16
C)60/b
D)4b
E)4+b
Rationale: If 10/b + 20/b + 30/b; then (10+20+30)/b is also integer.
i.e. 60/b is an integer.
Answer is C
Answer: C
Question: The president of a country and 2 other dignitaries are scheduled to sit in a row on the 3 chairs represented above. If the president must sit in the center chair, how many different seating arrangements are possible for the 3 people?
Options:
A) 4
B) 5
C) 20
D) 24
E) 2
Rationale: IMO E
Given that one chair is taken, i think the remaining 2 dignitaries can be arranged 2!. That is 2*1=2.
Answer: E
Question: There are 7 people and 7 chairs. In how many different ways people can occupy the chairs?
Options:
A)5040
B)4500
C)3400
D)6766
E)120
Rationale: number of ways =7! = 5040
Answer is A
Answer: A
Question: What is the next number in the sequence below?
1 4 9 16 25 36 __ ?
Options:
A)45
B)46
C)47
D)48
E)49
Rationale: as the series of numbers are squares of numbers
1^2=1
2^2=4
3^2=9
and so on
therefore 7^2=49
ANSWER:E
Answer: E
Question: The compound ratio of 1:2, 2:5 and 3:10?
Options:
A)1:2
B)1:5
C)3:5
D)1:50
E)3:50
Rationale: 1/2 * 2/5 * 3/10 = 3/503:50Answer: E
Answer: E
Question: A machine P can print one lakh books in 8 hours, machine Q can print the same number of books in 10 hours while machine R can print them in 12 hours. All the machines are started at 9 a.m. while machine P is closed at 11 a.m. and the remaining two machines complete the work. Approximately at what time will the work be finished?
Options:
A)11 : 30 am
B)12 noon
C)12 : 30 pm
D)1 pm
E)None of these
Rationale: (P + Q + R)’s 1 hour’s work = (1⁄8 + 1⁄10 + 1⁄12) = 37⁄120
Work done by P, Q and R in 2 hours = (37⁄120 × 2) = 37⁄60
Remaining work = (1 - 37⁄60) = 23⁄60
(Q + R)’s 1 hour’s work = (1⁄10 + 1⁄12) = 11⁄60
Now, 11⁄60 work is done by Q and R in 1 hour.
So, 23⁄60 work will be done by Q and R in
(60⁄11 × 23⁄60) = 23⁄11 hours ≈ 2 hours.
So, the work will be finished approximately 2 hours after 11 a.m., i.e., around 1 p.m.
Answer D
Answer: D
Question: Given the following equation 25% of 2475 + 20% of 2115 = x, Find the approximate value should come in place of the x.
Options:
A)1046
B)1048
C)1049
D)1047
E)1040
Rationale: x = 25% of 2475 + 20% of 2115
x = 25/100*2475 + 20/100*2115
x = 1041.75
≈ 1040
Answer E
Answer: E
Question: A circle and a rectangle have the same perimeter. The sides of the rectangle are 18 cm and 26 cm. What is the area of the circle ?
Options:
A)88 cm2
B)154 cm2
C)1250 cm2
D)616 cm2
E)None of these
Rationale: Perimeter of the circle = 2πr = 2(18 + 26)
⇒ 2 × 22⁄7 × r = 88 ⇒ r = 14
∴ Area of the circle
= πr2 = 22⁄7 × 14 × 14 = 616 cm2
Answer D
Answer: D
Question: A sum of money at simple interest amounts to Rs. 815 in 3 years and to Rs. 854 in 4 years. The sum is:
Options:
A)Rs. 650
B)Rs. 690
C)Rs. 698
D)Rs. 700
E)None of these
Rationale: Explanation :
S.I. for 1 year = Rs. (854 - 815) = Rs. 39.
S.I. for 3 years = Rs.(39 x 3) = Rs. 117.
Principal = Rs. (815 - 117) = Rs. 698.
Answer : C
Answer: C
Question: Find the number of factors R of 180 that are in the form (4*k + 2), where k is a non-negative integer?
Options:
A)1
B)2
C)3
D)4
E)R=6
Rationale: As for the question, the most straightforward way is to list out the factors (this is fine for this question as 180 is a relatively small number). Number of factors of 180 R (=2^2*3^2*5) = 18. So listing the factors gives us:
1, 180
2, 90
3, 60
4, 45
5, 36
6, 30
9, 20
10, 18
12, 15
As the question asks us about the factors of the form 4k+2 ---> eliminate all ODD factors. You are now left with
2,4,6,10,12,18,20,30,36,60,90,180
For the form 4k+2, the first few values are 2, 6, 10, 14, 18, 22, 26, 30 ... already giving you 5 factors (=2,6,10,18,30). You can stop here and mark 6 (6th one = 90) as the correct answer as 5 is not given.
For checking any particular factor whether they conform to the form 4k+2---> do the following
4k+2 = 36 ---> 4k = 34 --> this will NOT give you an integer value for k ---> reject. Proceed with others until you find all the values asked.
E is thus the correct answer.
Answer: E
Question: A bus leaves Santa Barbara at 8:00 a.m. traveling east at 80 miles per hour. At 3:00 p.m. a plane leaves Santa Barbara traveling east at 360 miles per hour. At what time will the plane overtake the bus?
Options:
A)5:00 p.m.
B)6:00 p.m.
C)4:00 p.m.
D)5:30 p.m.
E)4:30 p.m.
Rationale: At 3:00pm, the bus is 560 miles ahead of plane
The plane travels at 360 mph, which gains 250 mph on bus
560/280= 4/3 hours = 120 minutes
3:00 + 2:00 = 5:00
The plane will overtake bus at 5:00pm
Answer:A
Answer: A
Question: Mary charges $8.50 per hour to clean a house. If she works 25 hours, how much
does she earn in one week?
Options:
A)$612.50
B)$112.50
C)$212.50
D)$412.50
E)$312.50
Rationale: Multiply 25 hours x $8.50 =
Answer: $212.50
correct answer C
Answer: C
Question: A train passes a station platform in 36 seconds and a man standing on the platform in 24 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Options:
A)180
B)240
C)288
D)267
E)211
Rationale: Speed = (54 * 5/18) m/sec = 15 m/sec. Length of the train = (15 x 24)m = 360 m. Let the length of the platform be x meters. Then, (x + 360)/36 = 15 ==> x + 360 = 540 ==> x = 180 m.Answer: A
Answer: A
Question: There are 8 books in a shelf that consist of 3 paperback books and 5 hardback books. If 3 books are selected at random without replacement, how many different combinations are there that at least one paperback book is selected?
Options:
A)40
B)46
C)50
D)55
E)60
Rationale: 8C3 [Select any four] -5C3 [Select all hard backs] = 46
B
Answer: B
Question: The difference of the areas of two squares drawn on two line segments of different lengths is 32 sq	.cm. Find the length of the greater line segment if one is longer than the other by 2cm.
Options:
A)6 cm
B)7 cm
C)9 cm
D)11 cm
E)None
Rationale: Solution
Let the lengths of the line segments be x cm and (x + 2) cm.
Then (x+2)2 - x2 = 32
<=> x2+4x+4-x2 = 32
<=> 4x = 28
Therefore x = 7.
Length of longer line segment	= (7 + 2) cm
= 9 cm.
Answer C
Answer: C
Question: John makes $50 a week from his job. He earns a raise andnow makes $90 a week. What is the % increase?
Options:
A)15%
B)16.66%
C)17.8%
D)80%
E)21%
Rationale: Increase = (40/50)*100 = (4/5)*100 = 80%.
D
Answer: D
Question: You collect balls. Suppose you start out with 16. Mike gives you another 17 balls. How many balls do you have at the end?
Options:
A)33
B)34
C)35
D)36
E)37
Rationale: Solution
Start with 16 balls.
Mike gives you 17 balls: 16 + 17 = 33 balls.
So you have 33 at the end.
Correct answer: A
Answer: A
Question: In your classes you counted 120 hands. How many students were at the class?
Options:
A)60
B)61
C)85
D)86
E)88
Rationale: Total number of hands = 120
We have 2 hands.
To find how many students were at the class, divide the total number of hands by the number of hands we have.
We get, divide 120 by 2
220 ÷ 2 = 60
Therefore, there were 60 students at the class.
ANSWER IS A
Answer: A
Question: In a certain candy store, 22% of the customers are caught sampling the candy and are charged a small fine, but 10% of the customers who sample the candy are not caught. What is the total percent of all customers who sample candy?
Options:
A)22%
B)23%
C)24.4%
D)25%
E)34%
Rationale: Since 10% of the customers who sample the candyare notcaught, then 90% of the customers who sample the candyarecaught:
{% of customers who sample candy}*0.90 = 0.22;
{% of customers who sample candy} = 0.25.
Answer: C.
Answer: C
Question: Find the area of the quadrilateral of one of its diagonals is 26 cm and its off sets 9 cm and 6 cm?
Options:
A)188 cm2
B)150 cm2
C)168 cm2
D)195 cm2
E)987 cm2
Rationale: 1/2 * 26(9 + 6)
= 195 cm2
Answer: D
Answer: D
Question: A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?
Options:
A)2
B)3.5
C)3
D)4
E)5
Rationale: Area of the park = (60 x 40) m2 = 2400 m2.
Area of the lawn = 2109 m2.
Area of the crossroads = (2400 - 2109) m2 = 291 m2.
Let the width of the road be x metres. Then,
60x + 40x - x2 = 291
x2 - 100x + 291 = 0
(x - 97)(x - 3) = 0
x = 3.
C)
Answer: C
Question: A diet contains 400 grams of a mixture of two foods, food X and food Y. Food X contains 10 percent protein and food Y contains 15 percent protein. If a diet provides exactly 50 grams of protein daily, how many grams of food X are in the mixture?
Options:
A)120
B)140
C)150
D)160
E)200
Rationale: Let x be the number of grams of food X in the mixture.
0.1x + 0.15(400-x) = 50
0.05x = 10
x = 200
The answer is E.
Answer: E
Question: he number of sequences in which 5 players can throw a ball, so that the youngest player may not be the last is?
Options:
A)96
B)12
C)50
D)42
E)18
Rationale: x Not younger_______ ↑
The last ball can be thrown by any of the remaining 4 players. The first 4 players can throw the ball in 4P4 ways.
The required number of ways = 4(4!) = 4320
Answer:A
Answer: A
Question: The ratio of numbers is 3:4 and their H.C.F is 4. Their L.C.M is?
Options:
A)23
B)77
C)88
D)48
E)11
Rationale: Let the numbers be 3x and 4x.
Then their H.C.F = x. So, x = 4.
So, the numbers are 12 and 16.
L.C.M of 12 and 16 = 48.
Answer:D
Answer: D
Question: In an election, candidate Smith won 52% of the total vote in Counties A and B. He won 61% of the vote in County A. If the ratio of people who voted in County A to County B is 3:1, what percent of the vote did candidate Smith win in County B ?
Options:
A)25%
B)27%
C)34%
D)43%
E)49%
Rationale: Let total votes in County A = 3x.
Let total votes in County B = x.
Hence total votes in Count A & B together = 4x
Given that, 0.52(4x) = 0.61(3x) + n(x)
So, 2.08x = 1.83x + nx
So, n = 0.25 = 25%
Hence option A
Answer: A
Question: A square mirror has exactly half the area of the rectangular wall on which it is hung. If each side of the mirror is 34 inches and the width of the wall is 54 inches, what is the length of the wall, in inches?
Options:
A) 22.8
B) 33.8
C) 42.8
D) 63.8
E) 56.8
Rationale: Since the mirror is 42 inches in all sides, it must be a square. Area of a square is A=a^2; 34^2=1156.Area of rectangle is double of that 2 *1156=2312.Now A=lw and we need find w so A/l=w ; 2312/54= 42.8 Answer!
Answer is C
Answer: C
Question: A man can hit a target once in 4 shots. If he fires 4 shots in succession, what is the probability that he will hit his target?
Options:
A)564/123
B)646/458
C)456/847
D)175/256
E)256/175
Rationale: The man will hit the target if he hits it once or twice or thrice or all four times in the four shots that he takes.
So, the only possibility when the man will not hit the target is when he fails to hit the target in even one of the four shots that he takes.
The event of not hitting the target even once is the complement of the event of hitting the target at least once.
The probability that he will not hit the target in any given shot = 1 – 1/4 = ¾
Therefore, the probability that he will not hit the target in any of the four shots =3/4*3/4*3/4*3/4=81/256
The probability that he will hit the target at least in one of the four shots=1-81/256
=175/256
Ans: D
Answer: D
Question: In a certain zoo, the ratio of horses to penguins is 5 to 11. If there are 80 more penguins than horses at the zoo, how many horses are there?
Options:
A)24
B)36
C)66
D)72
E)132
Rationale: 5/11 = x / x+80
5*80 = 6x
x=66
C. 66
Answer: C
Question: A watch was sold at a loss of 10%. If it was sold for Rs.190 more, there would have been a gain of 4%. What is the cost price?
Options:
A)s.1000
B)s.1009
C)s.1007
D)s.1357.1
E)s.1002
Rationale: Explanation:
90%
104%
--------
14% ---- 190
100% ---- ? => Rs.1357.1
Answer:D
Answer: D
Question: The C.P of 10 pens is equal to the S.P of 20 pens. Find his gain % or loss%?
Options:
A)loss 16 2/8%
B)loss 50%
C)loss 16 2/3%
D)loss 18 2/3%
E)loss 16 25%
Rationale: 10 CP = 20 SP
20 --- 10 CP loss
100 --- ? => 50% loss
Answer:B
Answer: B
Question: A man has Rs. 160 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?
Options:
A)30
B)60
C)75
D)90
E)105
Rationale: Answer : A
Let number of notes of each denomination be x.
Then, x + 5x + 10x = 160
16x = 160
x = 10.
Hence, total number of notes = 3x = 30.
Answer: A
Question: Sarah is driving to the airport. After driving at 50 miles per hour for one hour, she realizes that if she continues at that same average rate she will be an hour late for her flight. She then travels 100 miles per hour for the rest of the trip, and arrives 30 minutes before her flight departs. How many miles did she drive in all?
Options:
A)140
B)175
C)200
D)245
E)280
Rationale: After driving at 50 miles per hourfor one hour, this distance left to cover is d-50. Say this distance is x miles.
Now, we know that the difference in time between covering this distance at 50 miles per hour and 100 miles per hour is 1+ 1/2 = 3/2 hours.
So, we have that x/50 - x/100 = 3/2 --> 2x/100 - x/100 = 3/2 --> x/100 = 3/2 --> x = 150
Total distance = x + 50 = 200 miles.
Answer: C.
Answer: C
Question: If v equals the sum of the odd integers from 5 to 505, inclusive, and q equals the sum of the odd integers from 3 to 303, inclusive, what is the value of v - q?
Options:
A)1616
B)153007
C)40902
D)1147612
E)50503
Rationale: Use following formulae for such problems:
Sum of evenly spaced integers = (# of integers)*(mean of integers)
# of integers = [(last - first)/2] + 1
Mean of integers = (last + first)/2
In above problem:
# of integers = [(505 - 5)/2] + 1= 251 and [(303-3)/2]+ 1 = 151
Mean of integers = (505 + 5)/2 = 255 and (303 + 3)/2 = 153
Sum of integers = (251*255) = 64005 and (151*153) = 23103
Thus their difference (v - q) = 40902
ANSWER:C
Answer: C
Question: The compound ratio of 5:7, 3:2 and 4:5?
Options:
A)1:7
B)6:5
C)6:7
D)4:7
E)6:9
Rationale: 5/7 * 3/2 * 4/5 = 6/7
6:7
ANSWER:C
Answer: C
Question: A computer wholesaler sells eight different computers and each is priced differently. If the wholesaler chooses three computers for display at a trade show, what is the probability (all things being equal) that the two most expensive computers will be among the three chosen for display?
Options:
A)15/56
B)3/28
C)1/28
D)1/56
E)1/168
Rationale: Since, two of the choices are prefixed, we are free to choose 1 from the rest of the 6 avilable. so 6C1 is the numerator.
Total no of ways we can choose 3 from 8 is 8c3, which is the denominator.
So, the probability: 6c1/8c3= 3/28 ans is B.
Answer: B
Question: In how many ways, a committee of 5 members can be selected from 6 men and 5 ladies, consisting of 3 men and 2 ladies?
Options:
A)150
B)180
C)200
D)310
E)250
Rationale: (3 men out 6) and (2 ladies out of 5) are to be chosen
Required number of ways = 6C3*5C2 = 200
Answer is C
Answer: C
Question: Jerry and Michelle play a card game. In the beginning of the game they have an equal number of cards. Each player, at her turn, gives the other a third of her cards. Michelle plays first, giving Jerry a third of her cards. Jerry plays next, and Michelle follows. Then the game ends. Jerry ended up with 28 more cards than Michelle. How many cards did each player have originally?
Options:
A)51
B)52
C)53
D)54
E)56
Rationale: GameMichelle Jerry
Initially 54 54 assume
After game 1 36 72
After game 2 60 48
After game 3 40 68
Now Merry has 28 cards more than Michelle. This option gives us exactly what number of cards they had initially.
So the answer is D
Answer: D
Question: Find the value o f 72519 x 9999 = m?
Options:
A)434539873
B)355797990
C)435453490
D)m=725117481
E)873430134
Rationale: 72519 x 9999 = 72519 x (10000 - 1)
= 72519 x 10000 - 72519 x 1
= 725190000 - 72519
= 725117481
D
Answer: D
Question: If a certain number is divisible by 12 and 10, it is NOT necessarily divisible by which of the following?
Options:
A)4
B)6
C)15
D)20
E)24
Rationale: If a certain number is divisible by 12 and 10, it is NOT necessarily divisible by which of the following?
let the certain number be 60, which is both divisible by 12 and 10.
60/24 = 5/2
ANSWER:E
Answer: E
Question: Each Machine of type X has 3 steel parts and 2 chrome parts. Each machine of type Y has 4 steel parts and 7 chrome parts. If a certain group of type X and type Y machines has a total of 20 steel parts and 22 chrome parts, how many machines are in the group
Options:
A)2
B)3
C)6
D)8
E)9
Rationale: Look at the below representation of the problem:
Steel Chrome total
X 3 2 20 >>no. of type X machines=20/5=4
Y 4 7 22 >>no. of type Y machines=22/11=2
So the answer is 6 i.e C.
Answer: C
Question: The average age of students in section A of 115 students is 15 years and the average age of students in section B of 120 students is 22 years. Find the average age of students in both sections taken together?
Options:
A)26 years
B)30years
C)18years
D)25years
E)20years
Rationale: The required average = (115*15+120*22)/115+120 = 18 years
Answer is C
Answer: C
Question: The average of 10 numbers is calculated as 15. It is discovered later on that while calculating the average, one number namely 36 was wrongly read as 26. The correct average is?
Options:
A)29
B)8
C)16
D)99
E)12
Rationale: 10 * 15 + 36 – 26 = 160/10
= 16
Answer: C
Answer: C
Question: Find the value of (2 − 1/3) (1 − 1/4)(1 − 1/5)……… (1 − 1/99)(1 − 1/100)
Options:
A)1/20
B)1/21
C)1/45
D)1/43
E)1/23
Rationale: (2 − 1/3) (1 − 1/4)(1 − 1/5)..... (1 − 1/99)(1 − 1/100)
5/3 × 3/4 × 4/5 × ....... 98/99 × 99/100 = 5/100 = 1/20
A
Answer: A
Question: A man desired to get into his work building, however he had forgotten his code.
However, he did recollect five pieces of information
-> Sum of 5th number and 3rd number is 14.
-> Difference of 4th and 2nd number is 1.
-> The 1st number is one less than twice the 2nd number.
->The 2nd number and the 3rd number equals 10.
->The sum of all digits is 30.
Crack the code ?
Options:
A)54658
B)74658
C)84658
D)14658
E)34658
Rationale: B
74658
* 8 + 6 =14
* 5 - 4 = 1
* 7 = 2*4 - 1
* 4 + 6 = 10
* 7+4+6+5+8 = 30
Answer: B
Question: In how many ways can the letters of the word, ‘KEYBOARD’ be arranged in such a way that the vowels always come together?
Options:
A)4250
B)4520
C)4320
D)4230
E)4530
Rationale: In the word ‘KEYBOARD’ we treat the vowels EOA as one letter. Thus, we have KYBRD (EOA).
Thus we have 6 letters can be arranged in 6! = 720 ways
The vowels (EOA) can be arranged among themselves in 3! = 6 ways
Therefore, Required number of ways= (720*6)= 4320
ANSWER:C
Answer: C
Question: If a certain sample of data has a mean of 21.0 and the value 42.0 is more than 2.5 standard deviations from the mean, which of the following could be the standard deviation of the sample
Options:
A)8.3
B)7.3
C)7.5
D)6.5
E)6.2
Rationale: 42.0 is more than 2.5 standard deviations from 21 --> 42 > 21 + 2.5*{SD} --> 2.5*{SD} < 21 --> {SD} < 8.4. Only option A offers the standard deviation less than 8.4.
Answer: A
Answer: A
Question: There r 3 boys & 4 girls; Howmany ways they r arranged such that boys should be always together ?
Options:
A)120ways
B)220ways
C)420ways
D)720ways
E)520ways
Rationale: By kept 3boys together(1) and arranging 4 girls with them
5! = 5*4*3*2*1 = 120ways. (i.e., 4+1 =5)
Possible arrangements of 3 boys in following ways
3! = 3*2*1 = 6ways
Now, arrange all with the boys together
120*6 = 720ways
ANSWER:D
Answer: D
Question: Five machines, each working at the same constant rate, together can complete a certain job in 20 days. How many additional machines, each working at the same constant rate, will be needed to complete the job in 10 days?
Options:
A)4
B)6
C)8
D)5
E)10
Rationale: Rate of one machine = 1 job / (20*5) days
let X = number of machines needed to complete the job in 10 days
1/(5*20) * 10 * X = 1 job
X = 10
10-5= 5
ANSWER: D
Answer: D
Question: Jeya decided to save a certain amount of her monthly salary each month and her salary was unchanged from month to month. If Jeya's savings by the end of the year from these monthly savings were two times the amount she spent per month, what should be the fraction of her salary that she spent each month?
Options:
A)5/7
B)6/7
C)9/7
D)5/7
E)4/7
Rationale: Let Jeya's monthly savings = S
Jeya's monthly pay = P
Jeya's monthly expenditure = P-S
Jeya's savings by the end of the year from these monthly savings were two times the amount she spent per month
12S = 2*(P-S)
=>6S = P-S
=> P = 7S
Jeya's monthly expenditure = P-S = 7S-S = 6S
fraction of her salary that Jeya spent each month = 6S / 7S=P-S/P = 6/7. Answer is B
Answer: B
Question: Two trains are moving in the same direction at 72 kmph and 36 kmph. The faster train crosses a man in the slower train in 27 seconds. Find the length of the faster train?
Options:
A)270 m
B)280 m
C)279 m
D)282 m
E)279 m
Rationale: Relative speed = (72 - 36) * 5/18 = 2 * 5 = 10 mps.
Distance covered in 27 sec
= 27 * 10 = 270 m.
The length of the faster train
= 270 m.
Answer: A
Answer: A
Question: Simran started a software business by investing Rs. 50,000. After six months, Nanda joined her with a capital of Rs. 80,000. After 3 years, they earned a profit of Rs. 24,500. What was Simran's share in the profit?
Options:
A)2888
B)27798
C)27766
D)29971
E)10500
Rationale: Simran : Nanda = (50000 * 36) : (80000 * 30) = 3:4
Simran's share = 24500 * 3/7
= Rs. 10500
Answer: E
Answer: E
Question: 7 people average age is 30. youngest person age is 5. find average of the people when youngest was born.
Options:
A)23
B)24
C)25
D)26
E)27
Rationale: average age of people =30
so have total age =210
before 7 years we have to deduct each person age by seven years 210-35=161
so average age would be 175/7=25
ANSWER:C
Answer: C
Question: Cars M and N are approaching each other on the same highway. Car M is moving at 45 mph northbound and Car N is moving at 55 mph southbound. At 2:00 pm, they are approaching each other and 190 miles apart. Eventually they pass each other. At what clock time are they moving away from each other and 35 miles apart?
Options:
A) 3:30 pm
B) 3:45 pm
C) 4:00 pm
D) 4:15 pm
E) 4:30 pm
Rationale: Total distance, which should be covered by both cars is 190+35=225 miles.
Let t be the time so the equation will be 45t+55t=225 thus,
t=2.25 hours
Answer: D
Answer: D