divelab/Sys2Bench huggingface dataset:
Question: The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is?
Options:
A)277
B)278
C)245
D)278
E)251
Rationale: Speed = [45 X 5/18] m/sec = [25/2] m/sec Time
= 30 sec Let the length of bridge be x metres. Then, (130 + x)/30
= 25/2 => 2(130 + x)
= 750 => x
= 245 m
Answer: Option C
Explanation:
Speed = [45 X 5/18] m/sec = [25/2] m/sec Time = 30 sec Let the length of bridge be x metres. Then, (130 + x)/30 = 25/2 => 2(130 + x) = 750 => x = 245 m.
Answer:C
Answer: C
Question: In a partnership between A, B and C. A's capital is Rs.5000. If his share of a profit of Rs.800 is Rs.200 and C's share is Rs.130, what is B's capital?
Options:
A)11292
B)31292
C)11392
D)11750
E)11729
Rationale: 200 + 130 = 330
800 - 330 = 470
200 ---- 5000
470 ---- ? => 11750
Answer: D
Answer: D
Question: In one hour,a boat goes 13 km along the stream and 5 km against the stream.The speed of the boat in still water (in km/hr) is :
Options:
A)3
B)5
C)8
D)9
E)10
Rationale: Solution
Speed in still water =1/2(13+5)kmph.= 9 kmph. Answer D
Answer: D
Question: {-10, -6, -5, -4, -2.5, -1, 0, 2.5, 4, 6, 7, 10}
A number is to be selected at random from the set above. What is the probability that the number selected will be a solution of the equation (x-4)(x+10)(2x-5) = 0?
Options:
A)1/12
B)1/6
C)1/4
D)1/3
E)1/2
Rationale: Roots of the equation (x-5)(x+10)(2x-5)=0 are x=4,x=-10andx=5/2=2.5. So, three solutions present in our set of 12 distinct numbers, therefore P=3/12=1/4.
Answer: C.
Answer: C
Question: A number is doubled and 9 is added. If the resultant is trebled, it becomes 69. What is that number?
Options:
A)3.5
B)6
C)8
D)7
E)4
Rationale: Let the number be x. Then,
3(2x + 9) = 69
2x = 14 => x = 7
ANSWER:D
Answer: D
Question: A shopkeeper buys two articles for Rs.1000 each and then sells them, making 75% profit on the first article and 75% loss on second article. Find the net profit or loss percent?
Options:
A)200
B)768
C)276
D)750
E)279
Rationale: Profit on first article = 75% of 1000 = 750.
This is equal to the loss he makes on the second article. That, is he makes neither profit nor loss.
Answer: D
Answer: D
Question: If the day before yesterday was Thursday, when will Sunday be?
Options:
A)Day after tomorrow
B)Tomorow
C)Two days after today
D)Today
E)none
Rationale: Explanation:
Day before yesterday was Thursday
=>Yesterday was a Friday
=> Today is a Saturday
=> Tomorrow is a Sunday
Answer: Option B
Answer: B
Question: Ms. Lily sold two properties, X and Y, for $26,000 each. She sold property X for 20 % more than she paid for it and sold property Y for 20% less than she paid for it. If expenses are disregarded , what was her total net gain or loss, if any, on the two properties ?
Options:
A)$2166.67
B)$2226.67
C)$2326.67
D)$2426.67
E)$2526.67
Rationale: There is a property to solve such questions withCommon Selling PriceandCommon %gain and loss. such cases always result in a loss and...
Total %Loss = (Common Gain% or Loss%/10)^2
Hence Here Loss% = (20/10)^2 = 4%
which means he recovered only 96% of his investment which amount to a total revenue = 26000 + 26000 = 52000
i.e. 96% of cost = 52000
therefore, 4% of cost (Loss) = $2166.67
Answer: A
Answer: A
Question: A certain basketball team played seven games and scored an average of 50 points per game. If, in the team’s first five games, it scored 45, 39, 61, 50, and 43 points, what was the average (arithmetic mean) number of points scored over the last two games?
Options:
A)65
B)81
C)82
D)56
E)Cannot be determined from the information given.
Rationale: Avg points for total of 7 games = 50
So A+B+C+D+E+F+G/7=50
and A+B+C+D+E+F+G = 350
Given A+B+C+D+E = 238
So F+G = 112
So average (arithmetic mean) number of points scored over the last two games is 112/2 = 56
Correct answer is D) 56
Answer: D
Question: In the graph below, no axes or origin is shown. If point B's coordinates are (11,3), which of the following coordinates would most likely be A's?
Options:
A)(17, -2)
B)(10, 6)
C)(6, 8)
D)(-10, 3)
E)(-2, -17)
Rationale: wherever be the axis as per question y coordinate of point A will be greater than 3 and X coordinate will be lower than 10.
D rules..
Answer: D
Question: A student travels from his house to school at 12 km/hr and reaches school 2 hours late. The next day he travels 20 km/hr and reaches school 1 hour early. What is the distance between his house and the school?
Options:
A)90
B)100
C)110
D)120
E)130
Rationale: Let x be the distance from his house to the school.
x/12 = x/20 + 3
5x = 3x + 180
2x = 180
x = 90 km
The answer is A.
Answer: A
Question: In how many ways can 6 people be seated at a round table if one of those seated cannot sit next to 2 of the other 5?
Options:
A)720
B)120
C)108
D)84
E)48
Rationale: 6 People in a round table can be seated in (6 - 1) ! ways = 120.
Now we need to subtract the number of cases when one of those is sitting next to 2 of the other 5.
We can consider as if 5 people are sitting in a row because it is round table.
Again consider 3 people, those who can not sit together, as a single unit â€“
So the possible arrangements among remaining people 5 â€“ 3 + 1 Unit are = 3 !
And the 3 people unit can arrange among themselves in 3 ! ways.
So the possible cases when one of those is sitting next to 2 of the other 5 = 3 ! * 3 ! = 36
Total possible cases = 120 -36 = 84 ANS:D
Answer: D
Question: 64 is divided into two parts in such a way that seventh part of first and ninth part of second are equal. Find the smallest part?
Options:
A)66
B)26
C)42
D)28
E)11
Rationale: x/7 = y/9 => x:y = 7:9
7/16 * 64 = 28
Answer: D
Answer: D
Question: A 300 meter long train crosses a platform in 39 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform?
Options:
A)150 m
B)200 m
C)350 m
D)400 m
E)300 m
Rationale: Speed = [300 / 18] m/sec = 50/3 m/sec.
Let the length of the platform be x meters.
Then, x + 300 / 39 = 50/3
3(x + 300) = 1950 è x = 350m.
ANSWER:C
Answer: C
Question: There are 8 pairs of socks and 2 socks are worn from that such that the pair of socks worn are not of the same pair. what is the number of pair that can be formed.
Options:
A)53
B)54
C)55
D)56
E)57
Rationale: First of all you should remember that there is a difference in left and right sock.
now no. of way to select any of the sock = 8
and for second = 7
so total methods = 8*7 = 56
ANSWER:D
Answer: D
Question: Arjun started a business with Rs. 10,000 and is joined afterwards by Anoop with Rs.40, 000. After how many months did Anoop join if the profits at the end of the year are divided equally?
Options:
A)3
B)4
C)5
D)6
E)9
Rationale: Suppose Anoop joined after 3 months.
Then, 10000 * 12 = 40000 * (12 – x)
=> x = 9.
ANSWER:E
Answer: E
Question: Of the diplomats who attended a summit conference: 20 spoke Spanish, 32 did not speak Russian and 20% of the diplomats spoke neither Spanish nor Russian. If 10% of the diplomats spoke both Spanish and Russian, then how many diplomats attended the conference?
Options:
A)70
B)96
C)108
D)120
E)150
Rationale: 2X2 matrix will be the easiest way to calculate this.
Text in black: given statements
Text in red: calculated values
Thus D=120 is the correct answer
Answer: D
Question: If |x^2 − 42| = x, which of the following could be the value of x?
Options:
A)–7
B)–6
C)2
D)6
E)14
Rationale: The LHS is not negative, so the RHS is also not negative. Thus x >= 0.
First, let's assume that x^2-42 is negative.
-(x^2 - 42) = x
x^2 + x - 42 = 0
(x+7)(x-6) = 0
x = 6 or x = -7 (However, x can not be negative.)
Then x = 6 is a possible value for x.
The answer is D.
Answer: D
Question: If 4 (P's Capital ) = 6 ( Q's Capital ) = 10 ( R's Capital ) , then out of the total profit of Rs 4650 , R will receive
Options:
A)600
B)700
C)800
D)900
E)None of these
Rationale: Explanation :
Let P's capital = p, Q's capital = q and R's capital = r
Then
4p = 6q = 10r
=> 2p = 3q = 5r
=>q = 2p/3
r = 2p/5
P : Q : R = p : 2p/3 : 2p/5
= 15 : 10 : 6
R's share = 4650 * (6/31) = 150*6 = 900. Answer : Option D
Answer: D
Question: What is the rate of simple interest?
I. The total interest earned was Rs. 4000.
II. The sum was invested for 4 years.
Options:
A)I alone sufficient while II alone not sufficient to answer
B)II alone sufficient while I alone not sufficient to answer
C)Either I or II alone sufficient to answer
D)Both I and II are not sufficient to answer
E)Both I and II are necessary to answer
Rationale: Explanation:
We know that, R =( 100 xS. I / P x T )
Now, I gives, S.I. = Rs. 4000.
II gives, T = 4 years.
But, P is unknown. So, we cannot find R.
So, given data is insufficient to get R.
answer is (D).
Answer: D
Question: Solve This
6 + 7 = 12
8 + 9 = 16
5 + 6 = 10
7 + 8 = 14
Then, 9 + 9 = ??
Options:
A)11
B)12
C)17
D)14
E)18
Rationale: 17
ANSWER:C
Answer: C
Question: A box contains THIRTEEN bulbs out of which 6 are defective. If FIVE bulbs are chosen at random, find the probability that atleast one bulb is good
Options:
A)455/451
B)428/421
C)427/429
D)456/489
E)423/127
Rationale: Required probability = 1-6C5/13C5 = 1 - 2/429 = 427/429.Answer:C
Answer: C
Question: A is twice as good a workman as B and they took 11 days together to do the work B alone can do it in.
Options:
A)17 days
B)12 days
C)29 days
D)25 days
E)33 days
Rationale: WC = 2:1
2x + x = 1/11
x = 1/33 => 33 days
ANSWER:E
Answer: E
Question: A pump can fill a tank with water in 2 hours. Because of a leak, it took 2 1/7 hours to fill the tank. The leak can drain all the water of the tank in?
Options:
A)17 hr
B)19 hr
C)10 hr
D)24 hr
E)30 hr
Rationale: Work done by the tank in 1 hour
= (1/2 -2 1/7)
= 1/30 Leak will empty the tank in 30 hrs.
Answer:E
Answer: E
Question: Two trains having equal lengths, take 10 seconds and 15 seconds respectively to cross a post. If the length of each train is 120 meters, in what time (in seconds) will they cross each other when traveling in opposite direction?
Options:
A)22
B)38
C)12
D)99
E)73
Rationale: Explanation:
Speed of train 1 = = 12 m/sec
Speed of train 2 = = 8 m/sec
if they travel in opposite direction, relative speed = 12 + 8 = 20 m/sec
distance covered = 120 + 120 = 240 m
time = distance/speed = 240/20 = 12 sec
Answer: C) 12
Answer: C
Question: An illiterate retailer marks all its goods at 50% above the cost price and thinking that he will still make 25% profit, offers a discount of 25% on the market price. What is the actual profit on the sales?
Options:
A)0.125
B)26.5%
C)27.8%
D)None of the above
E)Cannot be determined
Rationale: Explanation :
Let C.P =Rs 100.then, marked price =Rs100
S.P=75% of Rs 150= Rs 112.50
Hence, gain%=12.50%
Answer : A
Answer: A
Question: If the perimeter of a rectangular garden is 680 m, its length when its breadth is 82 m is?
Options:
A)286 m
B)899 m
C)200 m
D)166 m
E)258 m
Rationale: 2(l + 82) = 680 => l
= 258 m
Answer: E
Answer: E
Question: A number when divided by 5, gives 45 as quotient and 0 as remainder. What will be the remainder when dividing the same number by 10
Options:
A)A)5
B)B)3
C)C)4
D)D)6
E)E)7
Rationale: Explanation:
P ÷ 5 = 45
=> P = 45 * 5 = 225
P / 10 =225 / 10 = 22, remainder = 5
Answer: Option A
Answer: A
Question: The toll T, in dollars, for a truck using a certain bridge is given by the formula T = 0.50 + 0.50( x − 2), where x is the number of axles on the truck. What is the toll for an 18-wheel truck that has 2 wheels on its front axle and 4 wheels on each of its other axles?
Options:
A) $ 2.00
B) $ 3.00
C) $ 3.50
D) $ 4.00
E) $ 5.00
Rationale: Number of wheels in truck = 18
Number of wheels on its front axle =2
number of wheels remaining = 16
number of axles remaining axles = 16/4 = 4
Total number of axles = 5
T = 0.50 + 0.50( x − 2)
= 0.50 + .5*3
= 0.5 +1.5 = 2 $
Answer A
Answer: A
Question: The circumference of the front wheel of a cart is 40 ft long and that of the back wheel is 48 ft long. What is the distance travelled by the cart, when the front wheel has done five more revolutions than the rear wheel?
Options:
A)1200 ft
B)800 ft
C)900 ft
D)1000 ft
E)1500 ft
Rationale: total distance - x
x/40 - x/48 = 5
x = 1200 ft
ANSWER A
Answer: A
Question: The captain of a cricket team of 11 members is 26 years old and the wicket keeper is 11 years older. If the ages of these two are excluded, the average age of the remaining players is one year less than the average age of the whole team. What is the average age of the team?
Options:
A)23 years
B)24 years
C)25 years
D)26 years
E)27 years
Rationale: EXPLANATION
Let the average age of the whole team by x years.
11x â€“ (26 + 40) = 9(x -1)
11x â€“ 9x = 54
2x = 54
x = 27.
So, average age of the team is 27 years.
Answer E
Answer: E
Question: Difference between a two-digit number and the number obtained by interchanging the two digits is 36, what is the difference between two numbers
Options:
A)2
B)4
C)8
D)12
E)14
Rationale: Explanation:
Let the ten digit be x, unit digit is y.
Then (10x + y) - (10y + x) = 36
=> 9x - 9y = 36
=> x - y = 4.
Option B
Answer: B
Question: By selling 50 meters of cloth. I gain the selling price of 15 meters. Find the gain percent?
Options:
A)42 6/8%
B)42 6/7%
C)42 4/7%
D)42 9/7%
E)42 6/7%
Rationale: SP = CP + g
50 SP = 50 CP + 15 SP
35 SP = 50 CP
35 --- 15 CP gain
100 --- ? => 42 6/7%
Answer: B
Answer: B
Question: In a BCCI meeting there are 14 people. All shake hands with each other once. How many handshakes will be there altogether?
Options:
A)28
B)13
C)14
D)19
E)18
Rationale: There will be n-1 handshakes as A person will shake hands with all the other members.
=14-1=13
Answer:B
Answer: B
Question: 40% of Ram's marks is equal to 20% of Rahim's marks which percent is equal to 30% of Robert's marks. If Robert's marks is 80, then find the average marks of Ram and Rahim?
Options:
A)93
B)77
C)68
D)90
E)62
Rationale: Given, 40% of Ram's marks = 20% of Rahim's marks = 30% of Robert's marks.
Given, marks of Robert = 80
30% of 80 = 30/100 * 8 = 24
Given, 40% of Ram's marks = 24.
=> Ram's marks = (24 * 100)/40 = 60
Also, 20% of Rahim's marks = 24
=> Rahim's marks = (24 * 100)/20 = 120
Average marks of Ram and Rahim = (60 + 120)/2 = 90.
Answer:D
Answer: D
Question: In a shower, 4 cm of rain falls. The volume of water that falls on 1.5 hectares of ground is:
Options:
A)75 cu. m
B)600 cu. m
C)750 cu. m
D)6000 cu. m
E)7.50 cu. m
Rationale: 1 hectare = 10000 sq mtr
The volume of water that falls on 1.5 hectares of ground = 0.04*1.5*10000 = 600 cub mtr .
ANSWER:B
Answer: B
Question: One fourth of a solution that was 10 percent sugar by weight was replaced by a second solution resulting in a solution that was 16 percent sugar by weight. The second solution was what percent sugar by weight ?
Options:
A)34%
B)24%
C)22%
D)18%
E)8.5%
Rationale: Let the original solution be 100 ml
It had 10ml of sugar
1/4 of this solution is removed
sugar remaining = 7.5 ML
25 ml of x% solution is added.
New volume of sugar = 7.5+25*x/100
Since resulting solution is 16% sugar by weight, volume of sugar = 16ml
equating the 2
x=(16-7.5)*4
=34
ANSWER:A
Answer: A
Question: What do you get if you add 5 to 500 five times?
Options:
A)305
B)510
C)320
D)505
E)509
Rationale: D
505 , 505 , 505 , 505 , 505
Answer: D
Question: A man spends 10% of his income in house rent, 20% of the rest on his childrenâ€™s education, 25% of the rest miscellaneous causes. If he now posses Rs. 1944 then his income is?
Options:
A)3600
B)5500
C)5000
D)4000
E)2000
Rationale: X * (90/100) * (80/100) * (75/100) = 1944
X * 0.9 * 0.8 * 0.75
X = 1944/0.54
X = 3600
ANSWER A
Answer: A
Question: A sum of Rs.4800 is invested at a compound interest for three years, the rate of interest being 10% p.a., 20% p.a. and 25% p.a. for the 1st, 2nd and the 3rd years respectively. Find the interest received at the end of the three years.
Options:
A)Rs.3128
B)Rs.3120
C)Rs.3122
D)Rs.3121
E)Rs.3122
Rationale: Explanation:
Let A be the amount received at the end of the three years.
A = 4800[1 + 10/100][1 + 20/100][1 + 25/100]
A = (4800 * 11 * 6 * 5)/(10 * 5 * 4)
A = Rs.7920
So the interest = 7920 - 4800 = Rs.3120
Answer: B
Answer: B
Question: P and Q began business with Rs.6000 and Rs.9000 after 4 months, P withdraws Rs.2000 and B advances Rs.3000 more.
At the end of the year, their profits amounted to Rs.1175 find the share of Q.
Options:
A)800
B)625
C)825
D)725
E)850
Rationale: (6*4 + 4*8):(9*4 + 12*8)
14 : 33
33/47 * 1175 = 825.Answer:C
Answer: C
Question: If C is the temperature in degrees Celsins and F is the temperature in degrees Fahrenheit, then the relationship between temperatures on the two scales is expressed by the equation 9C=5(F-32). On a day when the temperature extremes recorded at two different cities differed by 55 degrees on the Fahrenheit scale, by how many degrees did the temperature extremes differ on the Celsius scale?
Options:
A)a) 65/9
B)b) 13
C)c) 28
D)d) 45
E)e) 81
Rationale: The relationship is 9/5 - 32, so approximately half of difference in Celsius (the -32 part won't be used in this case).
Just looking at the answer choices you can pick C which is the only number near half of 55. The other answer choices are too far apart so no need to calculate.
Answer: C
Question: If 20 ounces of a strong vinegar solution are diluted with 40 ounces of water to form a five-percent vinegar solution, what was the concentration of the original solution?
Options:
A)8%
B)10%
C)12%
D)15%
E)18%
Rationale: Let x be the concentration of the original solution.
20x = 0.05(60)
x = 0.15
The answer is D.
Answer: D
Question: A basket has 6 apples and 4 oranges. Three fruits are picked at random. What is the probability that at least 2 apples are picked?
Options:
A)1/2
B)1/3
C)2/3
D)2/5
E)3/5
Rationale: The total possible choices are 10C3 = 120
The ways to choose 3 apples: 6C3 = 20
The ways to choose 2 apples: 6C2 * 4C1 = 60
P(at least 2 apples) = 80/120 = 2/3
The answer is C.
Answer: C
Question: In a ratio which is equal to 3:4, if the antecedent is 12, then the consequent is?
Options:
A)12
B)16
C)20
D)22
E)25
Rationale: We have 3/4 = 12/x
3x = 48
x = 16
consequent = 16
Answer is B
Answer: B
Question: There are two positive numbers in the ratio 5:8. If the larger number exceeds the smaller by 27, then find the smaller number?
Options:
A)25
B)66
C)45
D)88
E)44
Rationale: Let the two positive numbers be 5x and 8x respectively.
8x - 5x = 27
3x = 27 => x = 9
=> Smaller number = 5x = 45.
Answer: C
Answer: C
Question: Gordon buys 5 dolls for his 5 nieces. The gifts include two identical S beach dolls, one E, one G, one T doll. If the youngest niece doesn't want the G doll, in how many different ways can he give the gifts
Options:
A)24
B)48
C)72
D)96
E)120
Rationale: Total # of ways to distribute SSEGT among 5 sisters (without restriction) is 5!2!=605!2!=60;
The # of ways when the youngest niece gets G is: 4!2!=124!2!=12 (give G to youngest and then distribute SSET among 4 sisters).
So, # of ways when youngest niece doesn't get G is: 60−12=4860−12=48.
Answer: 48.
ANSWER:B
Answer: B
Question: There are two tanks a and b. A drains water with 6L/m and b drains water with 8L/m. A starts drain water at 9:00 and after 2 minute, b starts draining of water. At what time, both with have same level.
Options:
A)9:12
B)9:10
C)9:08
D)9:04
E)9:06
Rationale: 9:01 --- 6 L
9:02 --- 12 L
from 9:03 onwards --------18,24,30,36,42,48,54,60
B =>
from 9:03 onwards -------- 8,16,24,32,40,48,56,64
at 9:08 both A & B have same level (48 L)
ANSWER:C
Answer: C
Question: Q is the set of the first n positive odd numbers, where n is a positive integer. Given that n > k, where k is also a positive integer, x is the maximum value of the sum of k distinct members of Q, and y is the minimum value of the sum of k distinct members of Q, what is x + y?
Options:
A) kn
B) kn + k^2
C) kn + 2k^2
D) 2kn – k^2
E) 2kn
Rationale: Probably the easiest way to solve this question would be to assume some values for n and k.
Say n=3, so Q, the set of the first n positive odd numbers would be: Q={1, 3, 5};
Say k=1, so X, the maximum value of the sum of K distinct members of Q would simply be 5. Similarly, Y, the minimum value of the sum of K distinct members of Q would simply be 1.
X+Y=5+1=6.
Now, substitute n=3 and k=1 in the options provided to see which one yields 6. Only asnwer choice E fits: 2kn=2*3*1=6.
Answer: E.
Answer: E
Question: In an examination 35% of the students passed and 481 failed. How many students appeared for the examination?
Options:
A)A)540
B)B)400
C)C)700
D)D)740
E)E)840
Rationale: Let the number of students appeared be x
then, 65% of x = 481
65x/100 = 481
x = 481*100/65 = 740
Answer is D
Answer: D
Question: In right triangle ABC, AC is the hypotenuse. If AC is 35 and AB + BC = 55, what is the area of the triangle ABC?
Options:
A)225
B)450
C)25√2
D)200
E)200√2
Rationale: Square AB + BC = 55:
(AB)^2 + 2*AB*BC + (BC)^2 = 3025. Since (AC)^2 = (AB)^2 + (BC)^2 = 35^2 = 1225, then (AB)^2 + 2*AB*BC + (BC)^2 = 1225 + 2*AB*BC = 3025.
1225 + 2*AB*BC = 3025.
AB*BC = 900.
The area = 1/2*AB*BC = 450.
Answer: B.
Answer: B
Question: Due to construction, the speed limit along an 6-mile section of highway is reduced from 55 miles per hour to 35 miles per hour. Approximately how many minutes more will it take to travel along this section of highway at the new speed limit than it would have taken at the old speed limit ?
Options:
A) 4
B) 8
C) 10
D) 15
E) 24
Rationale: 6/35 - 6/55 = 6/5 * ( 11 - 7)/77
= 6/5 * 4/77 * 60 min
= 6 * 12 * 4/77
= 288/77 ~ 3.7
Answer - A
Answer: A
Question: In how many different orders can the people Alice, Benjamin, Charlene, David, Elaine, Frederick, Gale, and Harold be standing on line if each of Alice, Benjamin, Charlene must be on the line before each of Elaine, Gale, and Harold?
Options:
A)1,008
B)2016
C)1,512
D)2,018
E)2,268
Rationale: Place D and F first: 8 options for D, 7 options for F
We are left with 6 empty places. A, B and C must take first 3 places and F, G, H must take the remaining three. A, B and C can be arranged in their places in 3! ways. The same for E, G, and H.
Total = 8*7*3!*3! = 2,016.
Answer: B
Answer: B
Question: A room is 30 m long and 24 m broad. If the sum of the areas of the floor and the ceiling is equal to the sum of the areas of four walls, the volume of the hall is:
Options:
A)9.6 m3
B)96 m3
C)960 m3
D)9600 m3
E)96000 m3
Rationale: Let the height be H
2(30+24) x H – 2(30-24)
H=(2(30x24))/(2(30+24)) = (30x24)/54 = 40/3 m
Volume = 30x24x40/3 = 9600 m3
answer :D
Answer: D
Question: If the cost price of 60 articles is equal to the selling price of 40 articles, then what is the percent profit?
Options:
A)30%
B)40%
C)50%
D)60%
E)70%
Rationale: Let x be the cost price of one article.
Let y be the selling price of one article.
40y = 60x
y = 1.5x
The answer is C.
Answer: C
Question: The average of 50 numbers is 30. If two numbers, 35 and 40 are discarded, then the average of the remaining numbers is nearly
Options:
A)28.32
B)28.78
C)29.27
D)29.68
E)None
Rationale: Solution
Sum of 50 numbers	= 30 x 50
= 1500.
Sum of remaining 48 numbers	= 1500 - (35+40)
= 1425.
∴ Required average	= (1425 / 48)
= 475 / 16.
= 29.68.
Answer D
Answer: D
Question: In a partnership between A, B and C. A's capital is Rs.5000. If his share of a profit of Rs.900 is Rs.200 and C's share is Rs.130, what is B's capital?
Options:
A)19878
B)14250
C)26908
D)11750
E)22073
Rationale: 200 + 130 = 330
900 - 330 = 570
200 ---- 5000
570 ---- ? => 14250
Answer: B
Answer: B
Question: The value of 5 in the number 357.21 is
Options:
A)5 ones
B)5 twenty
C)5 tens
D)5 hundreds
E)none of the above
Rationale: Ans is C
The number 357.21 consists of: 3 hundreds, 5 tens, 7 ones, 2 tenths and 1 hundredth =>the value of 5 in 357.21	is 5 tens
Answer: C
Question: A WORKS TWICE AS FAST AS B. IF B CAN COMPLETE A WORK IN 6 DAYS INDEPENDENTLY, THE NUMBER OF DAYS IN WHICH A AND B CAN TOGETHER FINISH THE WORK IS:
Options:
A)3/4 DAYS
B)2/1 DAYS
C)4/3 DAYS
D)3/2 DAYS
E)1/2 DAYS
Rationale: RATIO OF RATES OF WORKING OF A AND B = 2:1. SO, RATIO OF TIME TAKEN = 1:2
A'S 1 DAY'S WORK = 1/3, B'S 1 DAY'S WORK = 1/6
(A+B)'S 1 DAY'S WORK = (1/3+1/6)=1/2=1/2
SO, A AND B TOGETHER CAN FINISH THE WORK IN 1/2 DAYS.
CORRECT OPTION: E
Answer: E
Question: 325,244,180,131 ?
Options:
A)42
B)43
C)44
D)40
E)95
Rationale: 325 - 244 = 81 = 9^2
244 - 180 = 64 = 8^2
180 - 131 = 49 = 7^2
so we can write
131 - x = 36 = 6^2 , where x is the next number
x = 131 - 36 = 95
so the next number will be 95
ANSWER:E
Answer: E