divelab/Sys2Bench huggingface dataset:
Question: The average expenditure of a labourer for 8 months was 85 and he fell into debt. In the next 4 months by reducing his monthly expenses to 60 he not only cleared off his debt but also saved 30. His monthly income is
Options:
A)80
B)85
C)75
D)95
E)100
Rationale: Income of 8 months = (8 × 85) – debt
= 680 – debt
Income of the man for next 4 months
= 4 × 60 + debt + 30
= 270 + debt
∴ Income of 10 months = 950
Average monthly income = 950 ÷ 10 = 95
Answer D
Answer: D
Question: The three competitors in a race have to be randomly chosen from a group of three men and five women. How many different such trios contain at least one woman?
Options:
A)48
B)55
C)62
D)69
E)76
Rationale: The total number of ways to choose three runners 8C3 = 56
The number of trios with only males is 3C3 = 1
The number of trios which include at least one woman is 55.
The answer is B.
Answer: B
Question: If the length of the longest chord of a certain circle is 10, what is the radius of that certain circle?
Options:
A)2.5
B)5
C)10
D)15
E)20
Rationale: Longest chord of a circle is the diameter of the circle
diameter = 2 * radius
If diameter of the circle is given as 10 = 2 * 5
so radius of the circle = 5
correct answer - B
Answer: B
Question: In 1986 the book value of a certain car was 2/3 original price, and in 1988 its book value was 1/2 the original purchase price. By what percent did the book value for this car decrease from 1986 to 1988?
Options:
A)16 2/3%
B)25%
C)33 1/3
D)50%
E)75%
Rationale: In 1986- 200
In 1988- 150
Decrease of 50 over 200 between 86 and 88
So 25%
ANSWER:B
Answer: B
Question: The area of rectangular field is 460 square metres. If the length is 15 per cent more than the breadth ,what is the breadth of the rectangular field?
Options:
A)15 metres
B)26 metres
C)34.5 metres
D)Cannot be determined
E)None of these
Rationale: Let the breadth of the rectangular field be ‘x’ m. Then,length of the field will be
x+x×15/100=23x/20
Now, x×23x/20=460
or, 23x2 = 460 × 20
or, x2 = 20 × 20
or, x = 20 m
Answer E
Answer: E
Question: In a class, there are 20 boys whose average age is decreased by 2 months, when one boy aged 20 years replaced by a new boy. The age of the new boy is?
Options:
A)14 years 8 months
B)15 years
C)16 years 8 months
D)17 years 10 months
E)17 years
Rationale: Total decrease = (20 x 2) months
= 3 years 4 months
Age of the new boy
= 20 years - 3 years 4 months.
= 16 years 8 months.
ANSWER:C
Answer: C
Question: At a certain college, 40 percent of the total number of students are freshmen. If 50 percent of the fresh-men are enrolled in the school of liberal arts and, of these, 50 percent are psychology majors, what percent of the students at the college are freshmen psychology majors enrolled in the school of liberal arts?
Options:
A)10%
B)12%
C)14%
D)16%
E)18%
Rationale: Let's say there is a TOTAL of 100students at this college.
40 percent of the total number of students are freshmen.
# of freshmen = 40% of 100 =40
50 percent of the fresh-men are enrolled in the school of liberal arts...
Number of liberal arts freshmen = 50% of 40 = 20
...and, of these, 50 percent are psychology majors...
Number of liberal arts freshmen who are psychology majors = 50% of 20=10
What percent of the students at the college are freshmen psychology majors enrolled in the school of liberal arts?
10/100= 10%
Answer:A
Answer: A
Question: A(7, w^3) is the (x, y) coordinate of point located on the parabola Y = X^2 + 15. What is the value of w?
Options:
A)3.
B)4.
C)5.
D)6.
E)9.
Rationale: y=x^2 +15
w^3=7^2+15
w^3=64
W=4
Answer B
Answer: B
Question: Find the principal which yields a simple interest of Rs. 20 and compound interest of Rs. 24 in two years, at the same percent rate per annum?
Options:
A)s. 50
B)s. 48
C)s. 42
D)s. 20
E)s. 60
Rationale: Explanation:
SI in 2 years = Rs. 20, SI in 1 year = Rs. 10
CI in 2 years = Rs. 24
% rate per annum = [(CI – SI) / (SI in 1 year)] *100
= [(24 – 20) / 20] * 100
= 20 % p.a.
Let the principal be Rs. X
Time = T = 2 years
% rate = 20% p.a.
SI = (PRT/100)
20 = (X*20*2) / 100
X = Rs. 50
ANSWER: A
Answer: A
Question: A man has Rs. 512 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?
Options:
A)96
B)70
C)50
D)80
E)60
Rationale: Let number of notes of each denomination be x.
Then x + 5x + 10x = 512
16x = 512
x = 32.
Hence, total number of notes = 3x = 96.
Answer is A.
Answer: A
Question: A man is 25 years older than his son. In two years, his age will be twice the age of his son. The present age of the son is?
Options:
A)11
B)23
C)27
D)22
E)91
Rationale: Let the son's present age be x years.
Then, man's present age = (x + 25) years.
(x + 25) + 2 = 2(x + 2) x + 27 = 2x + 4 => x = 23.
Answer: B
Answer: B
Question: If it is 5:22 in the evening on a certain day, what time in the morning was it exactly 2,880,695 minutes earlier? (Assume standard time in one location.)
Options:
A)5:30
B)5:32
C)5:47
D)5:49
E)5:54
Rationale: 5:22 minus 2,880,695 must end with 7, the only answer choice which ends with 7 is C.
Answer: C.
Answer: C
Question: The probability of a team winning a match given Matt is playing the match is 0.75. The probability of the team winning a match given Matt is not playing the match is 0.6. The probability of Matt playing any match is 0.8.
If it is known that the team has won the last match, what is the probability that Matt played the match?
Options:
A)A)0.8333
B)B)0.7
C)C)0.8571
D)D)0.7531
E)E)0.8213
Rationale: Out of 100 matches:
Matt is plays in 80 and not plays in 20.
Out of 80 matches Matt plays in, team wins 0.75*80 = 60.
Out of 20 matches Matt does not play in, team wins 0.6*20 = 12.
So, out of 100 matches 60 + 12 = 72 are won.
It is known that the team has won the last match. Out of 72 matches won, Matt is in 60: 60/72 = 0.833...
Answer: A.
Answer: A
Question: A class of 4 Gangs is to be chosen from five Gangs.Each Gang contains 2 people.What is the number of different Gangs that can be chosen if two people who are in same gang to each other cannot both serve on the class?
Options:
A)840
B)960
C)60
D)720
E)1050
Rationale: Each GANG can send only one representative to the class. Let's see in how many ways we can choose 3 gangs (as there should be 3 members) out of 4 to send only one representatives to the class: 5C4=60.
But each of these 3 gangs can send two persons : 2*2*2*2=2^4=16.
Total # of ways: 5C4*2^4=960.
Answer: B.
Answer: B
Question: The sum of all the integers k such that –23 < k < 24 is
Options:
A)0
B)-43
C)-25
D)-49
E)-51
Rationale: -22------------------0-----------------23
values upto+23 cancels outwe are left with only -22-21 sum of which is - 43. hence option D.
B
Answer: B
Question: Q is as much younger than R as he is older than T. If the sum of the ages of R and T is 50 years, what is definitely the difference between R and Q's age ?
Options:
A)1 year
B)2 year
C)25 year
D)Data inadequate
E)None
Rationale: Solution
R - Q = R - T	Q = T.
Also,	R + T = 50
‹=› R + Q = 50.
So, (R - Q) cannot be determined.
Answer D
Answer: D
Question: If b does not equal zero, and ab = b/2, what is the value of a?
Options:
A)A)1/8
B)B)1/4
C)C)1/3
D)D)1/2
E)of the above
Rationale: Explanation:
To solve for a, divide both sides of the equation by b: ab = b/2
(ab)/b = (b/2)/b
a = (b/2)*1/b
a = 1/2
Answer: (D).
Answer: D
Question: If grapes are 92% water and raisins are 20% water, then how much did a quantity of raisins, which currently weighs 10 pounds, weigh when all the raisins were grapes? (Assume that the only difference between their raisin-weight and their grape-weight is water that evaporated during their transformation.)
Options:
A)25 pounds
B)46 pounds
C)92 pounds
D)100 pounds
E)146 pounds
Rationale: Since only water evaporates, then the weight of pulp (non-water) in grapes and raisins is the same. Thus 0.08*{weight of grapes}=0.8*{weight of raisins} --> 0.08x = 0.8*10 --> x = 100.
Answer: D.
Answer: D
Question: Find large number from below question The difference of two no.'s is 1365. On dividing the larger no. by the smaller, we get 6 as quotient and the 15 as remainder?
Options:
A)1456
B)1563
C)1546
D)1643
E)1635
Rationale: Let the smaller number be x. Then larger number = (x + 1365).
x + 1365 = 6x + 15
5x = 1350
x = 270
Large number = 270+1365 = 1635
E
Answer: E
Question: Excluding stoppages, the speed of a bus is 40 kmph and including stoppages, it is 30 kmph. For how many minutes does the bus stop per hour?
Options:
A)10 min
B)12 min
C)18 min
D)15 min
E)20 min
Rationale: Due to stoppages, it covers 10 km less.
Time taken to cover 10 km = (10/40 x 60) min = 15 min
Answer : D
Answer: D
Question: If the difference between compound interest (interest compounded yearly)and simple interest on a sum for 2 years at 10% p.a. is Rs.150 then sum is
Options:
A)Rs.12,000
B)Rs.15,000
C)Rs.13,000
D)Rs.10,000
E)Rs.14,000
Rationale: compund interest = p[1+r/100]^t-p
CI = p[21/100]
simple interest = ptr/100
SI = p[20/100]
difference p[21/100]-p[20/100] = 150
p=15,000
ANSWER:B
Answer: B
Question: Jessica can text 85 words per minute, while Maurice can text 25 words per minute. An abridged English translation of Tolstoy’s War and Peace contains 410,400 words. Working together, how many days will it take Jessica and Maurice to text the entire abridged translation of War and Peace?
Options:
A)0.3
B)1.3
C)3
D)2.6
E)11.3
Rationale: Since the answer choices are reasonably spaced out, we can approximate and save time
Combined words per day = 110*60*24
410400/158400 will be closest to only 2.6
So, Answer should be D.
Answer: D
Question: If the sides of a cube are in the ratio 5:3. What is the ratio of their diagonals?
Options:
A)5:9
B)9:3
C)5:4
D)3:5
E)5:3
Rationale: Explanation:
Diagonal of a Cube=a√3 where a is side
a1:a2 = 5:3
d1:d2 = 5:3 where√3 cancelled both side
ANSWER:E
Answer: E
Question: If f(1, 3) = 10 and f(1, 4) = 17, what is the value of f(1, 5)?
Options:
A)107
B)127
C)147
D)None of these
E)26
Rationale: Solution:
The function f(a, b) = a3 + b2
f(1, 3) therefore is = 10 and
f(1, 4) = 13 + 62 =17.
Therefore, f(1, 5) = 1 + 25 = 26
Answer E
Answer: E
Question: A and B can do a piece of work in 18 days; Band C can do it in 24 days A and C can do it in 36 days. In how many days will A, Band C finish it together?
Options:
A)14
B)16
C)19
D)18
E)20
Rationale: (A + B)'s 1 day's work = (1/18) (B + C)'s 1 day's work = (1/24)
and (A + C)'s 1 day's work = (1/36)
Adding, we get: 2 (A + B + C)'s 1 day's work =¬(1/18 + 1/24 + 1/36)
=9/72 =1/8
(A +B + C)'s 1 day's work =1/16
Thus, A, Band C together can finish the work in 16 days.
ANSWER B 16
Answer: B
Question: How many common two-digit whole numbers are there which gives a remainder of 2 when divided by 9 and gives a remainder of 5 when divided by 8?
Options:
A)Five
B)Three
C)One
D)Two
E)Four
Rationale: Answer = C) One
Two digit numbers giving remainder 2 when divided by 9 = 11, 20, 29, 38, 47, 56, 65, 74, 83, 92
Two digit numbers giving remainder 5 when divided by 8 = 13, 21, 29, 37, 45, 53, 61, 69, 77, 85, 93
Common Numbers = 29 = 1
Answer: C
Question: As a treat for her two crying children, a mother runs to the freezer in which she has two cherry ice pops, four orange ice pops, and four lemon-lime ice pops. If she chooses two at random to bring outside to the children, but realizes as she runs out the door that she cannot bring them different flavors without one invariably being jealous of the other and getting even more upset, what is the probability that she has to return to the freezer to make sure that they each receive the same flavor?
Options:
A)1/9
B)1/6
C)5/18
D)4/45
E)5/6
Rationale: Probability of not getting the same flavor ->
Favorable -> Cherry - orange [ 2C1 * 4C1 [or simply 2*4 ] or Cherry - lemon [ 2*4] or orange - lemon [4*4]
Prob = (2*4 + 2*4 + 4*4 ) / 9C2 = 32/360 = 4/45
Answer -> D
Answer: D
Question: Alex takes a loan of $6,000 to buy a used truck at the rate of 8 % simple Interest.Calculate the annual interest to be paid for the loan amount.
Options:
A)680
B)700
C)720
D)480
E)420
Rationale: From the details given in the problem Principle = P = $6,000 and R = 8% or 0.08 expressed as a decimal.
As the annual Interest is to be calculated, the time period T =1.
Plugging these values in the simple Interest formula,
I = P x T x R
= 6,000 x 1 x 0.08
= 480.00
Annual Interest to be paid = $480
answer :D
Answer: D
Question: If the diameter of circle R is 60% of the diameter of circle S, the area of circle R is what percent of the area of circle S?
Options:
A)50%
B)46%
C)36%
D)26%
E)38%
Rationale: Let diameter of circle R , dr = 60
and diameter of circle S , ds = 100
Radius of circle R , Rr = 30
Radius of circle S , Rs = 50
Area of circle R/ Area of circle S = (pi * Rr ^2 ) /( pi * Rs^2 )
= (30/50)^2 = (6/10)^2
=36%
Answer :C
Answer: C
Question: Find the number of square tiles to cover the floor of a room measuring 6.5 m * 8.5 m leaving 0.25 m space around the room. A side of square tile is given to be 25 cms?
Options:
A)768
B)476
C)429
D)428
E)413
Rationale: Floor area to be covered by tiles = 6 * 8 = 48
tiles area = 0.25 * 0.25 =0.0625
No. of tiles = 48/0.0625 = 768
Answer : A
Answer: A
Question: k = 2^n + 6, where n is an integer greater than 1. If k is divisible by 9, which of the following MUST be divisible by 9?
Options:
A)2^n - 8
B)2^n - 2
C)2^n-3
D)2^n + 4
E)2^n + 5
Rationale: Given: k, M and N are integers
If k is a divisor of both N and M, then k is a divisor of N+M (and N–M and M–N)
We're told that 9 is a divisor of 2^n + 6
We also know that 9 is a divisor of9.
So, applying the abov erule, 9 is a divisor of 2^n + 6 +9, and 9 is a divisor of 2^n + 6 -9 =2^n-3
C
Answer: C
Question: A train speeds past a pole in 15 seconds and a platfrom 100 m long in 25 seconds. Its length is :
Options:
A)100 m
B)125 m
C)130 m
D)150 m
E)None
Rationale: Sol.
Let the length of the train be x metres and its speed be y m/sec.
They, x / y = 15 ⇒ y = x/15
∴ x + 100 / 25 = x / 15 ⇔ x = 150 m.
Answer D
Answer: D
Question: A bag contains five white and four red balls. Two balls are picked at random from the bag. What is the probability that they both are different color?
Options:
A)5/1
B)5/9
C)5/5
D)5/3
E)5/2
Rationale: Two balls can be picked from nine balls in ⁹C₂ ways.
We select one white ball and one red ball from five white balls and four red balls. This can be done ⁵C₁ . ⁴C₁ ways.
The required probability
= (5 * 4)/⁹C₂
= 20/36
= 5/9
Answer:B
Answer: B
Question: Raju, Rahim, Rajesh together can do a work in 5 days. Raju alone can do the work in 10 days and Rahim alone can do the same work in 20 days. Find in what time Rajesh alone can do that work?
Options:
A)10days
B)15days
C)20days
D)30days
E)18days
Rationale: The required answer is = 5*10*20 / 10*20-5(10+20)
= 1000/50 = 20days
Answer is C
Answer: C
Question: A certain list consists of 21 different numbers. If n is in the list and n is 4 times the average(arithmetic mean) of the other 20 numbers in the list, then n is what fraction E of the sum of the 21 numbers in the list?
Options:
A) 1/20
B) 1/6
C) 1/5
D) 4/21
E) 5/21
Rationale: This is how I used to calculate which I think works pretty well:
if you let the average of the 20 other numbers equal a, can you write this equation for sum of the list (S)
n + 20a = S
the question tells us that
n = 4a
plug this back into the first equation and you get that the sum is 24a
4a + 20a = 24a
therefore fraction E of n to the total would be
4a/24a or 1/6
answer B
Answer: B
Question: What is 15 percent of 68?
Options:
A)7.6
B)8.7
C)9.1
D)10.2
E)11.6
Rationale: (15/100) * 68 = 10.2
The answer is D.
Answer: D
Question: The wages earned by Robin is 50% more than that earned by Erica. The wages earned by Charles is 60% more than that earned by Erica. How much percent is the wages earned by Charles more than that earned by Robin?
Options:
A)18.75%
B)23%
C)30%
D)50%
E)7%
Rationale: Let wage of Erica = 10
Wage of Robin = 1.5*10 = 15
Wage of Charles = 1.6 *10 = 16
Percentage by which wage earned by Charles is more than that earned by Robin = (16-15)/15 * 100%
= 1/15 * 100%
=7%
Answer E
Answer: E
Question: What is 92% of 3/5?
Options:
A)0.552
B)69.0
C)0.6845
D)0.6859
E)0.69
Rationale: 92%*(3/5)=0.92*0.6=0.552
Answer :A
Answer: A
Question: The area of a rectangular plot is 460 square metres. If the length is 15% more than the breadth, what is the breadth of the plot?
Options:
A)14 metres
B)20 metres
C)18 metres
D)16 metres
E)17 metres
Rationale: Explanation:
length =115% of breadth.
length×breadth =460 m2
⇒ 115% of breadth×breadth =460 m2
⇒ 115/100× breadth×breadth =460 m2
⇒ breadth×breadth =400 m2
⇒ breadth =20 m
Answer: Option B
Answer: B
Question: There are 13 South American countries, Anncy has won a ticket to fly from Denver to one South American country and then directly to another South American Country before returning home to Denver again. Assuming there are four airports in each country, how many flights paths can Anncy choose from?
Options:
A)13.12.11.10.4.4.
B)13.12.11.10.4
C)13.12.4.4.
D)13.12.4
E)13.13.13.13
Rationale: flights paths can Anncy choose from There are 13 ways to chose the first destination,
then, 12 ways to chose next destination, with option of 4 airports (13x4)
then, to return he has 4 options to chose the airports
Thus, 13*12*4*4 ways.
Using permutations:
If the solution had written 13P1 instead of 13C1 it won't matter. As per the definition - making arrangements of the combinations gives permutations.
Since there are no arrangement for 1 item, permutationscombinations are equal.C
Answer: C
Question: Starting with 0, a mathematician labels every non-negative integer as one of five types: alpha, beta, gamma, delta, or epsilon, in that repeating order as the integers increase. For instance, the integer 8 is labeled delta. What is the label on an integer that is the sum of an alpha raised to the seventh power and an epsilon raised to the seventh power?
Options:
A)alpha
B)beta
C)gamma
D)delta
E)epsilon
Rationale: Let the alpha be 5k and let the epsilon be 5j+4.
(5k)^7 + (5j+4)^7 which has the form 5k+4, which is an epsilon.
The answer is E.
Answer: E
Question: A man opens a shop. He buys water bottles for 50 cents each, fruit for 25 cents each, and snacks for a dollar each. He wants to start a bundle of selling a bottle a water, 3 snacks and 2 fruits for D dollars. Every 5th bundle sold will be sold for 2 dollars and a complimentary snack at the owner's expense. What should he charge at least to not lose any money?
Options:
A)4.6
B)3.0
C)4.1
D)3.2
E)2.9
Rationale: W=0.50
F = 0.25
S = 1.00
B= W+2F+3S = 4.00 they pay, he pays 4, net loss 0
fifth bundle = 2 they pay, he pays 5, net loss 3 dollars
3/5 = 60 cents.
Charging 60 more cents on each bundle will be safe.
answer: A
Answer: A
Question: The marked price of a book is 20% more than the cost price. After the book is sold, the vendor realizes that he had wrongly raised the cost price by a margin of 25%. If the marked price of the book is Rs.30, what is the original cost price of the book?
Options:
A)Rs.30
B)Rs.25
C)Rs.45
D)Rs.20
E)Rs.10
Rationale: Let the incorrect cost price be C1 and let the original cost price be C2.
Marked price of book is Rs.30. It is 20% more than C1.
Therefore, (120/100) X C1 = 30
Or C1 = 25.
C1 is more than C2 margin of 25%.
Or C1 = (125/100)C2
Therefore, C2 = (100/125) x 25 = Rs 20
ANSWER:D
Answer: D
Question: A bat is bought for Rs.400 and sold at a gain of 10% find its selling price?
Options:
A)s.460/-
B)s.480/-
C)s.500/-
D)s.520/-
E)s.440/-
Rationale: 100 % ------> 400 (100 * 4 = 400)
110 % ------> 440 (120 * 4 = 440)
Selling price = Rs.440/-
Option 'E'
Answer: E
Question: (700 + 200) Ã— 4 Ã— (4 + 2) = ?
Options:
A)24500
B)21600
C)36600
D)22400
E)12500
Rationale: (700 + 200) Ã— 4 Ã— (4 + 2) = ?
or, ? =900 Ã— 4 Ã— 6 = 21600
Answer B
Answer: B
Question: Two water pumps, working simultaneously at their respective constant rates, took exactly 5 hours to fill a swimming pool. If the constant rate of one pump was 1.5 times the constant rate of the other, how many hours would it have taken the faster pump to fill the pool if it had worked alone at its constant rate?
Options:
A)5/3
B)16/3
C)17/3
D)22/3
E)25/3
Rationale: Let the rate of the slow pump be x. Then the rate of the fast pump is 1.5x.
(x+1.5x)*5 = 2.5x*5 = 12.5x, which is the capacity of the whole pool.
Working alone:
1.5x*Time = 12.5x
Time = 12.5/1.5 = 125/15 = 25/3 hours
The answer is E.
Answer: E
Question: The population of bacteria culture doubles every 2 minutes.approximately how many minutes will it take for the population to grow from 1000 to 500,000 bacteria?
Options:
A)10
B)12
C)14
D)18
E)20
Rationale: 2000^1,2000^2,2000^3,2000^4.......2000^9
population increases in this sequence
taking 9*2=18
ANSWER:D
Answer: D
Question: Using all the letters of the word "SATURDAY", how many different words can be formed?
Options:
A)A)7
B)B)8
C)C)8!
D)D)7!
E)E)3
Rationale: Explanation:
Total number of letters = 8
Using these letters the number of 8 letters words formed is ⁸P₈ = 8!.
Answer: Option C
Answer: C
Question: The true discount on a bill due 9 months hence at 16% per annum is Rs. 270. The amount of the bill is
Options:
A)2200
B)2520
C)2600
D)3354
E)None of these
Rationale: Explanation:
Let P.W. be Rs.x.
Then, S.I. on Rs. x at 16% for 9 months = Rs. 270.
x Ã— 16 Ã— (9/12) Ã— (1/100) = 270 or x = 2250.
P.W. = Rs. 2250
Sum due = P.W. + T.D. = Rs.(2250
270) = Rs. 2520
Answer: B
Answer: B
Question: 1/3 of certain journey is covered at the rate of 25kmph,one-fourth at the rate of 30kmph and the rest at 50 kmph.Find the avg speed for the whole journey.
Options:
A)45 kmph
B)44.35 kmph
C)33.333 kmph
D)39.57 kmph
E)43.766 kmph
Rationale: Average speed = total distance / total time
LCM = 3, 4 = 12
Average speed = 12 / (1/3*12*1/25 + ¼ * 12*1/30 +5/50)
= 12/ (4/25 + 3/30+ 5/30
= 150*12/54 = 33.333 kmph
C
Answer: C
Question: Thomas's salary and Matt's salary are in the ratio 1:2. If both get an increment of Rs. 4000 their salaries would be in the ratio of 7:12. Find Thomas's salary as of now?
Options:
A)5000
B)10000
C)15000
D)20000
E)25000
Rationale: Let salaries of Thomas and Matt be x and y respectively.
x/y = 1/2 => x = 1/2 y
(x+4000)/(y+4000) = 7/12
=> 12x + 48000 = 7y+28000=> 12x = 7y-20000
But x = 1/2 y
6y = 7y-20000
y = 20000
x = 10000
Thomas salary is Rs.10000
Answer:B
Answer: B
Question: In how many different ways can the letters of the word VALUES be arranged in such a way that the vowels occupy only the odd positions?
Options:
A)120
B)36
C)48
D)32
E)72
Rationale: The 3 vowels can be arranged in three odd places in 3! ways.
Similarly, the 3 consonants can be arranged in three even places in 3! ways.
The total number of arrangements in which vowels occupy odd positions = 3! Ã— 3! = 6 Ã— 6 = 36
The answer is B.
Answer: B
Question: 2, 3, 5, 16, 231, ?
Options:
A)62005
B)52120
C)422
D)53105
E)56200
Rationale: Explanation :
2
3
32 - 22 = 5
52 - 32 = 16
162 - 52 = 231
2312 - 162 = 53105
Answer : Option D
Answer: D
Question: In a certain city each of 28 primary schools is represented by a colored flag. Each flag consists of either a single color or a pair of two different colors. If each school has a different flag, what is the minimum number of colors needed for the flags. (Assume that the order of colors in a pair on a flag does not matter.)
Options:
A)7
B)9
C)8
D)10
E)5
Rationale: A.7:
if we have 7 colors we can choose pairs in 7C2 ways = 21 and single color flags are 7. Therefore total number of flags = 28.
ANS A.
Answer: A
Question: The sides of a square region, measured to the nearest centimeter, are 7 centimeters long. The least possible value of the actual area of the square region is
Options:
A)42.25 sq cm
B)45.25 sq cm
C)43.25 sq cm
D)50.25 sq cm
E)52.25 sq cm
Rationale: Though there might be some technicalities concerning the termnearest(as 6.5 is equidistant from both 6 and 7) the answer still should be A: 6.5^2=42.25.
Answer: A
Answer: A