divelab/Sys2Bench huggingface dataset:
Question: A bag contains 15 wool scarves, exactly one of which is red and exactly one of which is green. If Deborah reaches in and draws three scarves, simultaneously and at random, what is the probability that she selects the red scarf but not the green scarf?
Options:
A)2/35
B)1/15
C)6/35
D)13/70
E)1/5
Rationale: We have 15 scarves: 1 red, 1 green and 13 other. We're asked for the probability of grabbing 3 scarves that include the 1 red but NOT the 1 green scarf.
Even though the question states that we are supposed to grab all 3 scarves simultaneously, we can still refer to them as 1st, 2nd and 3rd. There are 3 ways to get what we *want*
R = Red
O = Other
ROO
ORO
OOR
The probability of getting ROO = (1/15)(13/14)(12/13) = 2/35
The probability of getting ORO = (13/15)(1/14)(12/13) = 2/35
The probability of getting OOR = (13/15)(12/14)(1/13) = 2/35
Total ways = 2/35 + 2/35 + 2/35 = 6/35
ANSWER:C
Answer: C
Question: The probability that a card drawn from a pack of 52 cards will be a diamond or a king is
Options:
A)2/13
B)4/13
C)1/13
D)1/52
E)None
Rationale: Solution
Here, n(S) = 52.
There are 13 cards of diamond(including 1 king) and there are 3 more kings.
Let E = event of getting a diamond or a king.
Then, n(E) = (13+3)
= 16.
Therefore, P(E) = n(E)/n(S)
= 16 / 52
= 4 / 13.
Answer B
Answer: B
Question: A boat can move upstream at 25 kmph and downstream at 35 kmph, then the speed of the current is?
Options:
A)5
B)6
C)8
D)4
E)1
Rationale: US = 25
DS = 35
M = (35 - 25)/2 = 5
Answer: A
Answer: A
Question: the probability that I will sit next to Ann is 1/12.
the probability that I won't sit next to Alice is 11/12.
What is the probability that I will sit next to Alice and not next Ann?
Options:
A)1/6
B)11/12
C)11/144
D)1/12
E)1/144
Rationale: the probability that I won't sit next to Ann is 1-1/12=11/12.
the probability that I will sit next to Alice is 1-11/12 = 1/12.
Therefore the probability that I will sit next to Ann and Alice is 11/12*1/12=11/144
Answer:C
Answer: C
Question: For any integer z, the function PODD(z) is defined as the product of all odd integers between –z and z, inclusive. Which of the following numbers will not divide PODD(-15) completely?
Options:
A)3^8
B)5^5
C)7^3
D)Options B and C
E)Options A and C
Rationale: Solution 1:
Given PODD(Z) is product of all odd integers -Z to Z, so doesn't matter what the prime factors are, they will have even powers, So B and C WILL NOT divide PODD(-15) completely(!!!!, when you say completely i hope you meant without any remainder)
Solution 2:
PODD(-15) = (15.13.11.9.7.5.3)^2 and breaking down to prime factors (5.3.13.11.3.3.7.5.3)^2 = (13^2.11^2.7^2.5^4.3^8)
ANSWER:D
Answer: D
Question: A person's present age is two-fifth of the age of his mother. After 8 years, he will be one-half of the age of his mother. What is the present age of the mother?
Options:
A)25
B)30
C)35
D)40
E)45
Rationale: Let present age of the mother =5x
Then, present age of the person =2x
5x+8=2(2x+8)5x+8=4x+16x=8present age of the mother =5x=40
Answer is D.
Answer: D
Question: There are 11 stamps from which two stamps will be selected. We have five stamps which are the same as five of the stamps which could be selected. What is the probability that the two stamps selected will be different from the stamps that we have?
Options:
A)3/17
B)4/19
C)5/21
D)6/22
E)7/23
Rationale: P(first stamp is different) = 6/11
P(second stamp is different) = 5/10
P(both stamps are different) = 6/11*5/10 = 6/22
The answer is D.
Answer: D
Question: Ramesh purchased a refrigerator for Rs. 12500 after getting a discount of 20% on the labelled price. He spent Rs. 125 on transport and Rs. 250 on installation. At what price should it be sold so that the profit earned would be 18% if no discount was offered?
Options:
A)17608
B)17606
C)17604
D)17600
E)18880
Rationale: Price at which the TV set is bought = Rs. 12,500
Discount offered = 20%
Marked Price = 12500 * 100/80 = Rs. 15625
The total amount spent on transport and installation = 125 + 250 = Rs. 375\Total price of TV set = 15625 + 375 = Rs. 16000
The price at whichthe TV should be sold to get a profit of 18% if no discount was offered = 16000 * 118/100 = Rs. 18880.Answer: E
Answer: E
Question: How many seconds will a train 100 meters long take to cross a bridge 150 meters long if the speed of the train is 36 kmph?
Options:
A)28 sec
B)23 sec
C)24 sec
D)25 sec
E)26 sec
Rationale: D
25 sec
D = 100 + 150 = 250
S = 36 * 5/18 = 10 mps
T = 250/10 = 25 sec
Answer: D
Question: If the S.P of Rs. 21 results in a 30% discount on the list price, What S.P would result in a 10% discount on the list price?
Options:
A)s. 23
B)s. 24
C)s. 25
D)s. 26
E)s. 27
Rationale: Let the list price be Rs. X,
70/100*x = 21, x = 21*100/70 = 30
Required S.P = 90% of Rs. 30
= 90*30/100
=27
ANSWER:E
Answer: E
Question: Look at this series: 544, 509, 474, 439,404, 369, 334, ... What number should come next?
Options:
A)206
B)299
C)306
D)507
E)404
Rationale: 299
This is a simple subtraction series. Each number is 35 less than the previous number.
B
Answer: B
Question: In how many ways can the letters of the word "SATURN" be arranged?
Options:
A)560
B)640
C)720
D)800
E)880
Rationale: The total ways of arranging the letters = 6! = 720
The answer is C.
Answer: C
Question: If TIER is written as 9163 and BRAIN is written as 23415, how is RENT coded ?
Options:
A)3653
B)3657
C)2977
D)3659
E)2711
Rationale: Explanation:
Given :
Letter : T I E R B A N
Code : 9 1 6 3 2 4 5
Thus, the code for RENT is 3659.
ANSWER:D
Answer: D
Question: An investor bought N shares of company X at $15 per share and N shares of company Y at $20 per share. If a month later the investor sold all the shares at $20 per share and made a profit of $200, then what is the value N?
Options:
A)35
B)40
C)50
D)60
E)75
Rationale: The investor made a profit of (2∗N∗20)−(15N+20N)=200. This equation simplifies to 5N=200 from where N=40.
Answer: B
Answer: B
Question: If 1488 / 1.24 = 1200, then 148.8 / 12.4 is equal to ?
Options:
A)17
B)10
C)14
D)12
E)11
Rationale: Answer
Given expression 148.8 / 12.4 = 1488 / 124
= 1488 / (1.24 x 100)
= 1200/100
=12
Correct Option: D
Answer: D
Question: Given that E and F are events such that P(E) = 0.16, P(F) = 0.4 and P(E n F) = 0.4,
find P (E|F) and P(F|E)?
Options:
A)1/4
B)1/7
C)3/7
D)4/9
E)5/11
Rationale: Here, E and F are events
P(E|F) = P(EnF)/P(F) = 0.4/0.4 = 1
P(F|E) = P(EnF)/P(E) = 0.4/0.16 = 1/4.
A)
Answer: A
Question: 2,6,30,60,130,221...tell 8th digit in series??
Options:
A)458
B)504
C)524
D)534
E)621
Rationale: in this series
T(n)=n^3+/- n
+ for odd n and - for even n
n=1 T(n)=1+1=2
n=2 T(n)=8-2=6
n=3 T(n)=27+3
n=4 T(n)=64-4=60
n=5 T(n)=125+5=130
n=6 T(n)=216-6=210
n=7 T(n)=343+7=350
n=8 T(n)=512-8=504
ANSWER:B
Answer: B
Question: The equal amounts of money are deposited in two banks each at 15% per annum for 3.5 years and 5 years respectively. If the difference between their interests is Rs.144, find the each sum?
Options:
A)Rs.647
B)Rs.640
C)Rs.621
D)Rs.619
E)Rs.612
Rationale: (P*5*15)/100 - (P*3.5*15)/100 = 144
75P/100 – 52.5P/100 = 144
22.5P = 144 * 100
=> P = Rs.640
Answer:B
Answer: B
Question: A dog buys a boat for rs.132.44 and sells it for rs.263.59. Find her gain %.
Options:
A)10%
B)99.03%
C)87%
D)16%
E)94.06%
Rationale: sol. cp=rs 132.44, sp=rs 263.59
gain=rs(263.59 –132.44)=rs 131.15
so gain%={(131.15/132.44)*100}=99.03%
Answer is B.
Answer: B
Question: Out of 10 persons working on a project, 4 are graduates. If 3 are selected, what is the probability that there is at least one graduate among them?
Options:
A)5/7
B)5/3
C)5/1
D)5/6
E)5/2
Rationale: P(at least one graduate) = 1 - P(no graduates)
= 1 - ⁶C₃/¹⁰C₃ = 1 - (6 * 5 * 4)/(10 * 9 * 8)
= 5/6
Answer: D
Answer: D
Question: Evaluate 100^2 - 99^2 + 98^2 - 97^2 + 96^2 - 95^2 + ... + 2^2 - 1^2 =?
Options:
A)3043
B)5050
C)5176
D)9356
E)4890
Rationale: B
5050
You must have noticed that 50 pairs of n^2 – (n-1) ^2 exist.
n^2 – (n-1)^2 = n + (n – 1)
In such case, we may as well write 100^2 - 99^2 + 98^2 - 97^2 + 96^2 - 95^2 + ... + 2^2 - 1^2 as 100 + 99 + 98+ ... + 2 + 1 = (100 x 101)/2 = 5050
Answer: B
Question: The compound interest on $ 27,000 at 11% p.a is $ 11,000.Find out the period (in years) ?
Options:
A)2.5
B)3 1/4
C)3
D)2 3/4
E)4
Rationale: Amount = 27,000 + 11,000
= 38,000 ......... Now by using compound interest formula we get, 27,000 * (111/100)^n = 38000 ====> n == 3 1/4 years
Ans - B
Answer: B
Question: What is the units digit of (3^10)(4^13)?
Options:
A)2
B)4
C)6
D)7
E)8
Rationale: -> The ones place of (~3)^n repeats after 4 times like 39713.
The ones place of (~4)^n repeats after 2 times like 464.
Then, 3^10=3^4*2+23^2.,
4^13=4^2*6+1=4^1=~4
which is (3^10)(4^13) (3^2)(~4)=(~9)(~4)=~6. Therefore, the answer is C.
Answer: C
Question: The sector of a circle has radius of 7 cm and central angle 135o. Find its perimeter?
Options:
A)91.5 cm
B)92.2 cm
C)28.9 cm
D)30.5 cm
E)98.2 cm
Rationale: Perimeter of the sector = length of the arc + 2(radius)
= (135/360 * 2 * 22/7 * 7) + 2(7)
= 16.5 + 14 =30.5 cm
Answer:D
Answer: D
Question: If Josh, Doug, and Brad have a total of $68 between them, and Josh has two times as much money as Brad but only three-fourths as much as Doug, how much money does Brad have?
Options:
A)$10
B)$24
C)$26
D)$12
E)$36
Rationale: Josh+Doug+Brad = 68 ; Josh = 2 Brad, Josh =3/4 Doug
Josh+1/2 Josh+ 4/3 Josh = 68 (substituted the given values)
Josh = 24. 24= 3/4 Doug => Doug =32
Josh+Doug+Brad = 68
24 + 32 + Brad = 68
Brad = 12
Answer is D.
Answer: D
Question: WILLIAM has 13 ten-dollar bills, 11 five-dollar bills, and 17 one-dollar bills. If WILLIAM needs to pay exactly $128, what is the least number of bills he will need to use?
Options:
A)567
B)11
C)22
D)46
E)16
Rationale: 128 is the total sum of money.
as we have 13 10 dollar bills so the closest we can get to 128 using the 10 dollar bills is by using 12 * 10 dollar bils
128-120 = 8
so now we need to get 8 from either 5 dollar bills or 1 dollar bills
8 - 5 (use only 1 5 dollar bill) = 3
so we can get 3 from using 3 $1 bills.
Hence 16 ( 12+1+3 )
ANSWER IS E
Answer: E
Question: A train 200 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is?
Options:
A)28
B)50
C)77
D)22
E)12
Rationale: Speed of the train relative to man = (200/10) m/sec = (20) m/sec. [(20) * (18/5)] km/hr = 72 km/hr. Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr. x - 5 = 72 ==> x
= 77 km/hr.Answer:C
Answer: C
Question: A train 280 m long, running with a speed of 63 km/hr will pass a tree in?
Options:
A)21 sec
B)16 sec
C)71 sec
D)18 sec
E)28 sec
Rationale: Speed = 63 * 5/18 = 35/2 m/sec
Time taken = 280 * 2/35
= 16 sec
Answer: B
Answer: B
Question: Lines y=4√5·x−2 and y=3√5·x−1 intersect at what height above the x axis?
Options:
A)0
B)2√5
C)2
D)3√5
E)12√5
Rationale: Solve two equations for y
y=4√5·x−2
y=3√5·x−1
Set the two equations equal to each other and solve for x
4√5·x−2=3√5·x−1
√5·x = 1
x = 1/√5
Plug x = 1/√5 into any one of the original equations to find the y value (height above x axis) where the two lines intersect
y=4√5·x−2
y=4√5·(1/√5)−2
y=4·1 - 2
y = 4 - 2
y = 2
Final answer:
C) 2
Answer: C
Question: 12 men take 18 days to complete a job whereas 12 women in 18 days can complete 1â„4 of the same job. How many days will 10 men and 8 women together take to complete the same job?
Options:
A)6
B)13 1â„2
C)18
D)Data inadequate
E)None of these
Rationale: 12 M Ã— 18 = 12 W Ã— 18 Ã— 4â„1
\ w = 1/4 M
10M + 8W = 10M + 8 Ã— 1â„4M = 12 M
\12 men can complete the same work
in 12Ã—18/12=18days
Answer C
Answer: C
Question: find value for x from below equation?
x + 1 = -3
Options:
A)-2
B)-4
C)-1
D)-5
E)1
Rationale: 1. Subtract 1 from both sides:
x + 1 - 1 = -3 - 1
2. Simplify both sides:
x = -4
B
Answer: B
Question: Out of 15 consecutive numbers, 2 are chosen at random. The probability that they are both odds or both primes is
Options:
A)10/17
B)10/19
C)46/105
D)11/15
E)Cannot be determined
Rationale: There is no definite formula for finding prime numbers among 15 consecutive numbers. Hence the probability cannot be determined.
ANSWER:E
Answer: E
Question: Walking 7/6 of his usual rate, a boy reaches his school 4 min early. Find his usual time to reach the school?
Options:
A)11
B)15
C)16
D)28
E)19
Rationale: Speed Ratio = 1:7/6 = 6:7
Time Ratio = 7:6
1 -------- 7
4 --------- ? è 28 m
Answer: D
Answer: D
Question: The difference between the compound interest and simple interest on a certain sum of money at 5% per annum for 2 years is 45. Then the original sum is?
Options:
A)Rs.16500/-
B)Rs.17000/-
C)Rs.18000/-
D)Rs.19000/-
E)Rs.20000/-
Rationale: For 2 years = (1002D)/R2
= (1002 × 45)/(5 × 5) = (10000 × 45)/25 = Rs.18000/-
C
Answer: C
Question: Reena took a loan of Rs. 2000 with simple interest for as many years as the rate of interest. If she paid Rs. 720 as interest at the end of the loan period, what was the rate of interest?
Options:
A)6
B)7
C)8
D)9
E)10
Rationale: Let rate = R% and time = R years.
=(2000xRxR)/100 =720
=20Rsquare =720
R Square = 720/20 =36
R= 6
ANSWER :A
Answer: A
Question: How many seconds will a 900 metre long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
Options:
A)25
B)30
C)40
D)45
E)54
Rationale: Relative speed of the train=63-3=60kmph=60*5/18=50/3 m/sec
t=900*3/50=54sec
ANSWER:E
Answer: E
Question: In three annual examinations, of which the aggregate marks of each was 500, a student secured
average marks 45% and 55% in the first and the second yearly examinations respectively. To secure 70% average total marks, it is necessary for him in third yearly examination to secure marks :
Options:
A)300
B)350
C)400
D)450
E)550
Rationale: total marks:1500 for three exams
70% of 1500=1050
first exam marks=45% of 500=225
second exam marks=55% of 500=275
let X be the third exam marks
225 + 275 + X =1050
X=550
ANSWER:E
Answer: E
Question: In a division sum, the remainder is 0. As student mistook the divisor by 12 instead of 21 and obtained 35 as quotient. What is the correct quotient ?
Options:
A)0
B)12
C)13
D)20
E)25
Rationale: 12*35=420
420%21=20
ANSWER:D
Answer: D
Question: A fruit seller had some Mangoes. He sells 50% oranges and still has 500 Mangoes. How many Mangoes he had originally?
Options:
A)800
B)850
C)900
D)1000
E)1050
Rationale: He sells 50% of oranges and still there are 500 oranges remaining.
= 50% of oranges = 500
Total oranges x (50/100)= 500
= Total oranges =500×100/50=1000
answer :D
Answer: D
Question: n is a positive integer and k is the product of all integers from 1 to n inclusive. If k is a multiple of 1600, then what is the smallest possible value of n?
Options:
A)6
B)8
C)10
D)12
E)15
Rationale: 1600=2^6*5^2
2^6 means that n must be at least 8. That is, we need 2, 2*2, 6, and 2*2*2.
5^2 means that n must be at least 10. That is, We need 5 and 10.
The answer is C.
Answer: C
Question: Analyze the number square carefully and find out what number fits in place of question mark.
35	20	14
27	12	18
5	2	?
Options:
A)19
B)23
C)21
D)22
E)20
Rationale: E
20 fits in place of question mark.
This is because (number in first column) / (number in second column) * 8 = number in third column.
Here (left number / middle number) * 8 = right number
E.g. (35 / 20) * 8 = (7/4) * 8 = 7 x 2 = 14
The same process can be used to find out the missing digit.
Answer: E
Question: A business school club, Friends of Foam, is throwing a party at a local bar. Of the business school students at the bar, 40% are first year students and 60% are second year students. Of the first year students, 50% are drinking beer, 30% are drinking mixed drinks, and 20% are drinking both. Of the second year students, 30% are drinking beer, 30% are drinking mixed drinks, and 20% are drinking both. A business school student is chosen at random. If the student is drinking beer, what is the probability that he or she is also drinking mixed drinks?
Options:
A)2/5
B)4/7
C)10/19
D)7/24
E)7/10
Rationale: Suppose there are 100 students
Group A : 40% = 40 students
50% drink beer = 20
30% mixed = 12
20% both = 8
Group B 60% = 60
30% beer= 18
30% mixed = 18
20% both= 12
now we need both ( beer + mixed = both)
probability = total beer drinker = 20+18 =38 and both = 20
thus 20/38 = 10/19
Hence C
Answer: C
Question: From a bunch of eight keys, three particular keys have to be used to open a combination lock, such that the second key can be used only after the first key and the third key can be used only after the second key. What are the chances of opening the lock in a random selection of three keys?
Options:
A)1/120
B)1/180
C)1/336
D)1/480
E)1/720
Rationale: The probability is 1/8*1/7*1/6 = 1/336.
The answer is C.
Answer: C
Question: A warehouse had a square floor with area 10,000 sq.meters. A rectangular addition was built along one entire side of the warehouse that increased the floor by one-half as much as the original floor. How many meters did the addition extend beyond the original buildings ?
Options:
A)10
B)20
C)50
D)100
E)500
Rationale: as L*B=10000 ie for square L=B=100m
THEN,
IF A RECTANGULAR ADDITIONALLY WAS BUILT ALONG ONE ENTIRE SIDE IT ENSURES THAT ONE SIDE MUST BE REMAIN SAME AS THE SQUARE
HENCE EQUATION BECOMES
(100+X)100=10000+(1/2)*10000
(100+X)100=15000
X=50
ANSWER:C
Answer: C
Question: A 425 meter long train crosses a platform in 55 seconds while it crosses a signal pole in 40 seconds. What is the length of the platform?
Options:
A)155.68
B)160
C)159.38
D)180
E)175
Rationale: Speed = [425 / 40 m/sec = 42.5/4 m/sec.
Let the length of the platform be x meters.
Then, x + 425 / 55= 42.5/4
4(x + 425) = 2337.5 è x =159.38 m. Answer: C
Answer: C
Question: In a certain city, 60 percent of the registered voters are Democrats and the rest are Republicans. In a mayoral race, if 85 percent of the registered voters who are Democrats and 20 percent of the registered voters who are Republicans are expected to vote for Candidate A, what percent of the registered voters are expected to vote for Candidate A ?
Options:
A)50%
B)59%
C)54%
D)55%
E)57%
Rationale: Say there are total of 100 registered voters in that city. Thus 60 are Democrats and 40 are Republicans.
60*0.85=51 Democrats are expected to vote for Candidate A;
40*0.20=8 Republicans are expected to vote for Candidate A.
Thus total of 51+8=59 registered voters are expected to vote for Candidate A, which is 59% of the total number of registered voters.
Answer: B.
Answer: B
Question: Find the principle on a certain sum of money at 5% per annum for 2 2/5 years if the amount being Rs.1008?
Options:
A)900
B)2217
C)2889
D)2777
E)2991
Rationale: 1008 = P [1 + (5*12/5)/100]
P= 900
Answer: A
Answer: A
Question: A textile manufacturing firm employees 56 looms. It makes fabrics for a branded company. The aggregate sales value of the output of the 56 looms is Rs 5,00,000 and the monthly manufacturing expenses is Rs 1,50,000. Assume that each loom contributes equally to the sales and manufacturing expenses are evenly spread over the number of looms. Monthly establishment charges are Rs 75000. If one loom breaks down and remains idle for one month, the decrease in profit is:
Options:
A)13000
B)6250
C)10000
D)5000
E)None of these
Rationale: Explanation :
Profit = 5,00,000âˆ’(1,50,000+75,000) =Rs. 2,75,000.
Since, such loom contributes equally to sales and manufacturing expenses.
But the monthly charges are fixed at Rs 75,000.
If one loan breaks down sales and expenses will decrease.
New profit :-
=>500000Ã—(55/56)âˆ’150000Ã—(55/56)âˆ’75000.
=>Rs 2,68,750
Decrease in profit
=>2,75,000âˆ’2,68,750
=>Rs. 6,250
Answer : B
Answer: B
Question: Which of the following is closer to (3!+2!)-(3!-2!)?
Options:
A)0
B)1
C)2
D)3
E)4
Rationale: 3!+2!)-(3!-2!)=6+2-6+2
= 4
Answer: E
Answer: E
Question: A is twice as good a work man as B and together they finish a piece of work in 14 days.The number of days taken by A alone to finish the work is :
Options:
A)11
B)21
C)28
D)42
E)None of these
Rationale: Solution
(A’s 1 day’s work): (B’s 1 day’s work)= 2 : 1.
(A + B)'s 1 day’s work = 1/14
Divide 1/14 in the ratio 2 : 1.
∴ A’s 1 day’s work = (1/14 x2/3)= 1/21
Hence,A alone can finish the work in 21 days.
Answer B
Answer: B
Question: A certain machine produces 550 units of product P per hour. Working continuously at this constant rate, this machine will produce how many units of product P in 5 days?
Options:
A)7,000
B)24,000
C)66,000
D)100,000
E)168,000
Rationale: Since 5 days consist of 24*5 hours the total is 120 hours.
Since every hour the machine produces 550 units of product P the total product during 120 hours is 120*550=66,000.
Correct Option : C
Answer: C
Question: If a certain number X is divided by 82, the reminder is 5. what is the reminder when X+13 is divided by 41?
Options:
A)3
B)18
C)6
D)16
E)5
Rationale: X can be written as 82K + 5 or X = 5,87,169,etc.
X + 13 = 82K + 5+13= 82K +18 or X + 13 = 18,100, 182 etc.
When divided by 41, we will get the remainder 18.
B
Answer: B
Question: If the simple interest on a sum of money for 2 years at 5% per annum is Rs.50, what is the compound interest on the same at the same rate and for the same time?
Options:
A)Rs. 52
B)Rs. 51.25
C)Rs. 54.25
D)Rs. 60
E)Rs. 70
Rationale: Simple interest for 2 years = Rs.50 ie. For 1 years Rs. 25. . In the first year the S.I and C.I are
same ie.Rs. 25. So in the 2nd year in C.I calculated for 1 years interest also. So in second years for
Rs.25 interest is 25*5/100 = 1.25 . So total C.P = 51.25.
ANSWER:B
Answer: B
Question: If x^2 – 2y^2 = 2xy, then (x + y)^2 =
Options:
A)x^2
B)2x^2-y^2
C)4xy
D)2y^2
E)– y^2
Rationale: (x+y)^2 = x^2 + y^2 + 2xy = x^2 + y^2+ x^2-2y^2 = 2x^2-y^2
Correct option : B
Answer: B
Question: Stalin gets on the elevator at the 11th floor of a building and rides up at a rate of 57 floors per minute. At the same time Jose gets on an elevator on the 51st floor of the same building and rides down at a rate of 63 floors per minute. If they continue traveling at these rates, at which floor will their paths cross?
Options:
A)19
B)28
C)34
D)32
E)30
Rationale: Steve gets on the elevator at the 11th floor of a building and rides up at a rate of 57 floors per minute. At the same time Joyce gets on an elevator on the 51st floor of the same building and rides down at a rate of 63 floors per minute. If they continue traveling at these rates, at which floor will their paths cross?
40 floors/120 floors per minute=1/3 minutes
11+57/3=30
51-63/3=30
Answer : E
Answer: E
Question: A contractor hires 100 men to finish a job in 50 days. After 40 days, n men leave. After some more days, the contractor hires 2n more men to complete the job on time. For how many days did these 2n men work?
Options:
A)20
B)18
C)16
D)12
E)5
Rationale: Step1: Find Each day what % of work is finished ; it requires 50 days to complete which means each day 1/50= 2% work will be completed.
Step 2 : After 40 Days = 40* 2= 80% of work is finished. remaining is 20% ( which means if same 100 men were about to complete the job they would have required 10 more days)
Step3: Let us assume all people have left job. therefore contractor hires 2n people. initially it was taking 10 days to compete for n people. at present 2n people are present to finish job. hence 5 more days.
E
Answer: E
Question: Each Machine of type A has 2 steel parts and 3 chrome parts. Each machine of type B has 3 steel parts and 5 chrome parts. If a certain group of type A and type B machines has a total of 40 steel parts and 32 chrome parts, how many machines are in the group
Options:
A)12
B)13
C)14
D)15
E)16
Rationale: Look at the below representation of the problem:
Steel Chrome total
A 2 3 40 >>no. of type A machines=40/5=8
B 3 5 32 >>no. of type B machines=32/8=4
So the answer is 12 i.e A.
Hope its clear .
Answer: A
Question: A and B started business in partnership investing Rs. 20,000 and Rs. 15,000 respectively. After six months, C joined them with Rs. 20,000. What will be B's share in the total profit of Rs. 25,000 earned at the end of 2 years from the starting of the business?
Options:
A)7500
B)2878
C)2662
D)2992
E)2772
Rationale: A:B:C = (20000 * 24) : (15000 * 24) : (20000 * 18) = 4:3:3
B's share = 25000 * 3/10 = Rs. 7500.
Answer: A
Answer: A