divelab/Sys2Bench huggingface dataset:
Question: Some of the people in Town L are left-handed, some are tall, some are both, and some are neither. In Town Y, three times as many people are left-handed > as are left-handed in Town L, three times as many people are tall as are tall in Town L, three times as many people are both as are both in Town L, but no one is neither. If the total number of people in Town L is four times greater than the total number of people in Town Y, which of the following could be the number of people in Town L who are neither left-handed nor tall?
Options:
A) 23
B) 39
C) 72
D) 143
E) 199
Rationale: Yes, correct answer is indeed D.
{L}={Left} + {Tall} - {Both} + {Neither};
{Y} = 3*{Left} + 3*{Tall} - 3*{Both};
Since the total number of people in Town L is four times greater than the total number of people in Town Y, then:
{Left} + {Tall} - {Both} + {Neither}=4*(3*{Left} + 3*{Tall} - 3*{Both});
{Neither}=11*({Left} + {Tall} - {Both}), which means that # of people in Town L who are neither left-handed nor tall must be a multiple of 11.
Only answer choice D, is a multiple of 11: 143=11*13.
Answer: D.
Answer: D
Question: If a and b are different positive integers and a + b = a(a + b), then which of the following must be true?
I. a = 1
II. a = 0
III. b < a
Options:
A)I only
B)II only
C)III only
D)I and II
E)I and III
Rationale: a has to equal a squared, and that only works if a is 1. There are no positive integers less than 1, so I and III are correct.
Answer : A
Answer: A
Question: A regular 10 sided area is inscribed in a circle. If A and B are adjacent vertices of the pentagon and O is the center of the circle, what is the value of ∠OAB ?
Options:
A)48 degrees
B)54 degrees
C)72 degrees
D)84 degrees
E)72 degrees
Rationale: its a regular 10 sided so divide the globe by 10.
= 360/10
=36
36 would be the angle at O.
Angles at A and B are equivalent, so
36 + 2x = 180
2x = 144
x = 72
Angles OAB and OBA will be 72 degrees each.
E
Answer: E
Question: If p is a natural number and p! ends with w trailing zeros, then the number of zeros that (5p)! ends with will be
Options:
A)a) (p+w) trailing zeros
B)b) (5p+y) trailing zeros
C)c) (5p+5y) trailing zeros
D)d) (p+5y) trailing zeros
E)e) none of them above
Rationale: Let p = 1. p! = 1! = 1, which means w= 0
(5p)! = 5! = 120, trailing zeros = 1
1 = 1 + 0 = p + w
Answer (A).
Answer: A
Question: 841, 784, 729, 676, 625, ?
Options:
A)576
B)529
C)484
D)441
E)400
Rationale: Explanation :
The pattern is 29^2, 28^2, 27^2, 26^2, 25^2, ...
So next number is 24^2 = 576
Answer : Option A
Answer: A
Question: If a,b are positive integers and a/b=67.75 which of the following could be the value of b?
Options:
A)1. 25
B)2. 26
C)4. 20
D)4. 27
E)5. 30
Rationale: Given a/b = 67.75.
this is 67 and 3/4 = 271/4
Since a and b are integers we know that whatever is the value of b, it must be divisible by 4 completely(to make a an integer)
Ans:C
Answer: C
Question: Rs.1210 were divided among A,B,C so that A : B = 5 : 4 and B : C = 9 : 10.Then,C gets :
Options:
A)Rs.340
B)Rs.400
C)Rs.450
D)Rs.475
E)None
Rationale: Solution
A : B = 5 : 4, B : C = 9 : 10 =(9x4/9) :(10x4/90 = 4 : 40/9
∴ A : B : C = 5 : 4 : 40/9 = 45 : 36 : 40 .
Sum of ratio terms =(45+36+40) = 121
∴ C’s share = Rs.(1210x40/121)= Rs. 400.
Answer B
Answer: B
Question: The compound ratio of 2/3, 6/7, 4/3 and 1/8 is given by?
Options:
A)2/21
B)1/48
C)1/98
D)1/96
E)1/68
Rationale: 2/3 * 6/7 * 4/3 * 1/8 = 48/504 = 2/21
ANSWER:A
Answer: A
Question: if p is number greater than 99 ,e is the probability of divisiblity of any even whole number p, and O is the probablity of any odd whole number divisible by p , w is probablity of any whole number divisible by p.
Options:
A)w=2e
B)e=w/2
C)o=w/2
D)either (b) or (c)
E)none
Rationale: for eg any even whole number take e=2,
any odd whole number take o=3,
any whole number take w=6
for eg the number which is divisible by 2,3,6 is=642
so take option c;
o=w/2 which means 3=6/2 ->3=3;
ANSWER:C
Answer: C
Question: In how many ways can the letters D, I, G, I be arranged so that the two I's are not next to each other?
Options:
A)36
B)48
C)72
D)6
E)128
Rationale: 1 D
2 I
1 G
1 T
Number of ways these letters can be arranged = 4!/2! (2! to account 2 same Is) = 12
Consider 2 Is as 1 entity and thus the number of arrangements for (II)DG = 3! =6
Total allowed cases = 12-6 =6
D is the correct answer.
Answer: D
Question: If December 3rd, 1999 is a Friday, what day is January 4th, 2000?
Options:
A)Tuesday
B)Wednesday
C)Friday
D)Saturday
E)Sunday
Rationale: There is difference of 32 days from Dec. 3rd 1999 to Jan. 4th 2000.
32/7 has a remainder of 4.
Jan. 4th is: Friday + 4 days = Tuesday
The answer is A.
Answer: A
Question: There are 14 players in a chess group, and each player plays each of the others once. Given that each game is played by two players, how many total games will be played?
Options:
A)91
B)30
C)45
D)60
E)90
Rationale: 10 players are there.
two players play one game with one another.
so 14C2=14*13/2
=91
SO OPTION A is correct
Answer: A
Question: A bullet train leaves Kyoto for Tokyo traveling 240 miles per hour at 12 noon. Ten minutes later, a train leaves Tokyo for Kyoto traveling 160 miles per hour. If Tokyo and Kyoto are 360 miles apart, at what time will the trains pass each other?
Options:
A)12:58pm
B)12:49pm
C)12:55pm
D)1:00pm
E)1:05pm
Rationale: Train A: going from K to T
Train B: going from T to K
First I calculated how far Train A will have travelled by the time Train B starts at 12:10:
10 minutes at 240 mph
1/6*240=40miles
They have 360-40=320 miles to travel to meet each other.
I found the combined rate of the two trains
Rate(A) + Rate(B) = 400mph
Divide Distance/Rate to find total time each will travel:
320/400>>> 48 Minutes to meet
12:10+48 minutes = 12:58 or Answer A
Answer: A
Question: How many four-digit integers exist such that all their digits are odd?
Options:
A)80
B)100
C)120
D)125
E)625
Rationale: so last digit can be filled in 5 ways- 1,3,5,7,9
there are 5 possibilities. The answer is 5∗5*5*5=625
The correct answer is E
Answer: E
Question: How many numbers between 11 and 90 are divisible by 7?
Options:
A)7
B)10
C)11
D)12
E)13
Rationale: The required numbers are 14,21,28,...........,84.
This is an A.P with a=14,d=7.
Let it contain n terms
then T =84=a+(n-1)d
=14+(n-1)7
=7+7n
7n=77 =>n=11.
ANSWER C 11
Answer: C
Question: Noelle walks from point A to point B at an average speed of 6 kilometers per hour. At what speed, in kilometers per hour, must Noelle walk from point B to point A so that her average speed for the entire trip is 7 kilometers per hour?
Options:
A)6.75
B)7
C)7.25
D)7.5
E)8.4
Rationale: Let's suppose that speed while returning was xkm/h
Since the distance is same, we can apply the formula of avg speed
Avg speed= 2S1S2/S1+S2
7= 2*6*x/6+x
x= 8.4
E is the answer
Answer: E
Question: 0.014×0.014= ?
Options:
A)0.000196
B)0.00196
C)19.6
D)196
E)NONE
Rationale: Solution
Sum of decimals places= 6.
14×14	= 196.
= s0.014×0.014
= 0.000196
Answer A
Answer: A
Question: The salaries of A,B,C are in the ratio 2 : 3 : 5. If the increments of 15%, 10% and 20% are allowed respectively in their salaries, then what will be the new ratio of their salaries?
Options:
A)3 : 3 : 10
B)10 : 11 : 20
C)23 : 33 : 60
D)Cannot be determined
E)None of these
Rationale: Let A = 2k, B = 3k and C = 5k.
A’s new salary = 115⁄100 of 2k = (115⁄100 × 2k) = 23⁄10k
B’s new salary = 110⁄100 of 3k = (110⁄100 × 3k) = 33⁄10k
C’s new salary = 120⁄100 of 5k = (120⁄100 × 5k) = 6k
∴ New ratio = 23k⁄10 : 33k⁄10 : 6k = 23 : 33 : 60
Answer C
Answer: C
Question: A man can row upstream at 25 kmph and downstream at 39 kmph, and then find the speed of the man in still water?
Options:
A)86
B)67
C)30
D)15
E)32
Rationale: US = 25
DS = 39
M = (39 + 25)/2
= 32
Answer: E
Answer: E
Question: Two employees X and Y are paid a total of Rs. 550 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?
Options:
A)Rs.150
B)Rs.180
C)Rs.200
D)Rs.220
E)Rs.250
Rationale: Let the amount paid to X per week = x
and the amount paid to Y per week = y
Then x + y = 550
But x = 120% of y = 120y/100 = 12y/10
∴12y/10 + y = 550
⇒ y[12/10 + 1] = 550
⇒ 22y/10 = 550
⇒ 22y = 5500
⇒ y = 5500/22 = 500/2 = Rs.250
E)
Answer: E
Question: A work which could be finished in 9 days was finished 3 days earlier after 10 more men joined. The number of men employed was?
Options:
A)22
B)20
C)88
D)71
E)11
Rationale: x ------- 9
(x + 10) ---- 6
x * 9 = (x + 10)6
x = 20
\Answer: B
Answer: B
Question: How many different positive integers exist between 10^2 and 10^3, the sum of whose digits is equal to 2?
Options:
A)3
B)5
C)6
D)7
E)8
Rationale: 101
110
200
total no. is 3
A
Answer: A
Question: what is the distance between two parallel chords of length 32 cm and 24 cm in a circle of radius 20 cm ?
Options:
A)1 or 7
B)3 or 21
C)4 or 28
D)2 or 14
E)2 or 15
Rationale: since the chord length=2sqrrt(r^2-d^2)
chord length=32,r=20 then we get d=12
chord length=24,r=20 then we get d=16
then we add/subtract we get 4 or 28
ANSWER:C
Answer: C
Question: Can you find the last number in the number sequence given below?
10 : 10 : 20 : 45 : 110 : 300 : ?
Options:
A)nine hundred thirty
B)870
C)450
D)330
E)220
Rationale: A
New number = Last number * multiplication factor (increased by 0.5 every time) + sum factor (increased by 5 every time)
10
10 * 0.5 + 5 => 10
10 * 1.0 + 10 => 20
20 * 1.5 + 15 => 45
45 * 2.0 + 20 => 110
110 * 2.5 + 25 => 300
300 * 3.0 + 30 => 930 , desired answer
Answer: A
Question: Two persons start running simultaneously around a circular track of length 700 m from the same point at speeds of 15 km/hr and 25 km/hr. When will they meet for the first time any where on the track if they are moving in opposite directions?
Options:
A)16 seconds
B)28 seconds
C)49 seconds
D)57 seconds
E)63 seconds
Rationale: Time taken to meet for the first time anywhere on the track
= length of the track / relative speed
= 700 / (15 + 25)5/18 = 700* 18 / 40 * 5
= 63 seconds.
Answer:E
Answer: E
Question: A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If three marbles are drawn what is the probability that one is yellow and two are red?
Options:
A)12/489
B)12/452
C)12/455
D)12/429
E)12/292
Rationale: Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles.
When three marbles are drawn, the probability that one is yellow and two are red
= (²C₁)(⁴C₂)/¹⁵C₃
= (2 * 4 * 3 * 3 * 2)/(1 * 2 * 15 * 14 * 13)
= 12/455
Answer: C
Answer: C
Question: A sum of money placed at C.I. interest doubles itself in 5 years. It will amount to eight times itself at the same rate of interest in?
Options:
A)7 years
B)10 years
C)15 years
D)20 years
E)25 years
Rationale: P(1 + R/100)5 = 2P => (1 + R/100)5 = 2
Let P(1 + R/100)n = 8P
=> (1 + R/100)n = 8 = 23 = {(1 + R/100)5}3
=> (1 + R/100)n = (1 + R/100)15 => n = 15 Required time = 15 years.
ANSWER:C
Answer: C
Question: A man buys a cycle for Rs.1400 and sells it at a loss of 18%. What is the selling price of the cycle?
Options:
A)Rs.1148
B)Rs.1160
C)Rs.1190
D)Rs.1202
E)NONE
Rationale: Solution
S.P	= 82% of Rs.1400
= Rs.(82/100×1400)
Rs.1148.
Answer A
Answer: A
Question: The length of the longest rod that can fit in a cubical room of 4 m side is?
Options:
A)3:8
B)3:1
C)3:0
D)3:2
E)3:5
Rationale: 3:1
Answer:B
Answer: B
Question: The ratio of men to women in the Snyder community choir is 4 to 3. The ratio of men to women in the Leigh community choir is 5 to 6. If the two choirs merged, the ratio of men to women in the combined choir would be 22 to 27. If Snyder has 4 more men and 6 more women than Leigh, how many women are in the Snyder choir?
Options:
A)27
B)25
C)31
D)32
E)34
Rationale: This question has a number of patterns in it that we can take advantage of. We can also TEST THE ANSWERS (but we can actually eliminate most of the answer choices rather quickly.
We're told that the ratio of the Men to Women in the Snyder choir is 4 to 3, so the number of men MUST be a multiple of 4 and the number of women MUST be a multiple of 3 The question asks how many WOMEN are in the SNYDER choir, so the answer MUST be a multiple of 3. We can eliminate Answers B,C, D and E (since they're NOT multiples of 3
Answer A
Answer: A
Question: Jadeja rented a power tool from a rental shop. The rent for the tool was $13 for the first hour and $8 for each additional hour. If Jadeja paid a total of $133, excluding sales tax, to rent the tool, for how many hours did she rent it?
Options:
A)14
B)19
C)16
D)13
E)12
Rationale: 13 + 8n = 133
n = 15
Total time = n+1 hrs = 15+1 hrs = 16 hrs
Answer : C
Answer: C
Question: Arjun started a business with Rs. 40,000 and is joined afterwards by Anoop with Rs.80, 000. After how many months did Anoop join if the profits at the end of the year are divided equally?
Options:
A)3
B)4
C)5
D)6
E)7
Rationale: Suppose Anoop joined after 3 months.
Then, 40000 * 12 = 80000 * (12 – x)
=> x = 6.
ANSWER:D
Answer: D
Question: For how many integers pair (x,y) satisfies the result
(1/x)+((1/y)=1/11
Options:
A)a) 12
B)b) 6
C)c) 10
D)d) 14
E)e) 32
Rationale: It seems that the accepted answer is wrong, according to WolframAlpha. The answer should be 26, which isn't even listed as a selectable answer.
D
Answer: D
Question: Each student is given a five-character identification code. The first three characters are selected from the numbers 0 to 9 inclusive, and the last two characters are selected from the 26 letters of the alphabet. If characters may be repeated and the same characters used in a different order constitute a different code, how many different identification codes can be generated following these rules?
Options:
A)652,000
B)665,000
C)676,000
D)683,000
E)694,000
Rationale: The number of possible codes is 10*10*10*26*26=26,000.
The answer is C.
Answer: C
Question: 1600 men have provisions for 28 days in the temple. If after 4 days, 400 men leave the temple, how long will the food last now?
Options:
A)11
B)99
C)32
D)44
E)66
Rationale: 1600 ---- 28 days
1600 ---- 24
1200 ---- ?
1600*24 = 1200*x
x = 32 days
Answer: C
Answer: C
Question: 5 tables and 10 chairs were sold for 20000.15%gain for table,10%loss on chair.overall profit rs 750.the cp of table is
Options:
A)840
B)1940
C)2040
D)2140
E)3240
Rationale: let cost of table is X and chair is Y.
sold price is 20000 and profit is 750 .
so cost for both is 19250.
then
first eq is 5X+10Y=19250
second eq is 5*(115/100)X + 10* (90/100)Y =20000
solve both eqations , then get X=2140
ANSWER:D
Answer: D
Question: The H.C.F. of two numbers is 30 and the other two factors of their L.C.M. are 10 and 15. The larger of the two numbers is:
Options:
A)350
B)250
C)450
D)500
E)620
Rationale: Explanation:
Clearly, the numbers are (30 x 10) and (30 x 15).
{\color{Blue} \therefore } Larger number = (30 x 15) = 450.
Answer: C) 450
Answer: C
Question: On average, the boys in the class have 12 erasers and the girls have 26 erasers. If the overall class average is 18 erasers, what is the ratio of boys to girls in the class?
Options:
A)2/1
B)3/2
C)4/3
D)5/4
E)6/5
Rationale: (26G + 12B) / (G+B) = 18
26G + 12B = 18(G+B)
8G=6B
B/G = 4/3
The answer is C.
Answer: C
Question: A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of this son is
Options:
A)15
B)20
C)18
D)24
E)22
Rationale: son age is x then father age x+24
2(x+2)=(x+24+2)
2x+4=x+26
x=22 yrs
ANSWER E
Answer: E
Question: In a question on division with zero remainder, a candidate took 12 as divisor instead of 21. The quotient obtained by him was 35. The correct quotient is?
Options:
A)20
B)24
C)28
D)29
E)30
Rationale: Number = (35 * 12) = 420
Correct quotient = 420/21 = 20
A)
Answer: A
Question: Which of the options is a two-digit number, which has a unit's digit that exceeds its ten's digit by 6 and the product of the given number and the sum of its digits is equal to 136.
Options:
A)82
B)93
C)39
D)28
E)17
Rationale: Using the elimination method the option that fits this description is 17
7-1 = 3 (unit's digit that exceeds its ten's digit by 3)
17*8 = 136 (the product of the given number and the sum of its digits is equal to 175)
answer :E
Answer: E
Question: For what range of values of 'x' will the inequality 15x - 2/x > 1?
Options:
A)x > 0.4
B)x < 1/3
C)-1/3 < x < 0.4, x > 15/2
D)-1/3 < x and x< 0, x > 2/5
E)x < -1/3 and x > 2/5
Rationale: In Case 1 where x > 0, I agree. I calculated x > (-1/3) and x > 2/5, and because x > 0, it must be x > 2/5.
In Case 2 where x < 0, I don't understand why you say that the range must be x > -1/3 and x < 0, since the values that satisfy the inequality 15x^2 - x - 2 < 0show that x < -1/3 and x < 2/5.
I have the same doubt. Shouldn't the answer be D?
____________
The answer IS D.
Answer: D
Question: Selling 1 kilogram of mangoes for Rs. 500, a shop keeper gains 5%. During an seasonal time, the shopkeeper allows a discount of 5% on the marked price. His gain/loss percent during the sale is?
Options:
A)0.1%
B)2%
C)0.2%
D)5%
E)10%
Rationale: Explanation:
Marked price = Rs. 500
C.P. = 100/105 * 500 = Rs. 476.19
Sale price = 95% of Rs. 500 = Rs. 475
Required LOSS % = .119/476.19 * 100 = 0.2%.
Answer: C
Answer: C
Question: A and B’s salaries together amount to Rs. 2,000. A spends 95% of his salary and B spends 85% of his. If now their savings are the same, what is A’s salary?
Options:
A)2999
B)2669
C)2600
D)1500
E)1267
Rationale: (5/100) A = (15/100) B
A = 3B
A + B = 2000
4B = 2000 => B = 500
A = 1500
Answer: D
Answer: D
Question: Eight fencers participate in a fencing championship. Assuming all competitors have an equal chance of winning, how many possibilities are there with respect to how a first-place and second-place medal can be awarded?
Options:
A)52
B)56
C)60
D)64
E)72
Rationale: 8*7 = 56
The answer is B.
Answer: B
Question: A group of 36 students are visiting an amusement park. The tickets are $6 for an individual or $30 for a group up to 10 people. What is the minimum amount the group has to pay?
Options:
A)$520.
B)$320.
C)$220.
D)$420.
E)$120.
Rationale: There are 2 options to buy tickets for 36 students.
• Option 1: 3 group tickets + 6 single tickets.
The cost for option 1 is $30 × 3 + $6 × 6 = $126.
• Option 2: 4 group tickets
The cost for option 2 is $30 × 4 = $120.
The option 2 is cheaper. Therefore, the minimum amount the group has to pay is $120.
correct answer E
Answer: E
Question: If points X and Y are two distinct points in the coordinate plane, which of the following can have more than one possible value?
Options:
A)The circumference of a circle with diameter XY.
B)The area of a square with diagonal XY.
C)The perimeter of a right isosceles triangle with a leg XY.
D)The area of a circle with chord XY.
E)The area of an equilateral triangle with base XY.
Rationale: All other options will have distinct values.
ANSWER:C
Answer: C
Question: Sheila works 8 hours per day on Monday, Wednesday and Friday, and 6 hours per day on Tuesday and Thursday. She does not work on Saturday and Sunday. She earns $252 per week. How much does she earn in dollars per hour?
Options:
A)11
B)10
C)9
D)8
E)7
Rationale: Let Sheila earn x dollars per hour
So, on Monday, Wednesday and Friday , she earns 8x each
And, on Tuesday and Thursday, she earns 6x each
In total , over the week she should earn, 3(8x) + 2(6x) = 36x
She earns $252 per week
36x =252
x =7
Correct Option :E
Answer: E
Question: Two trains 140 m and 150 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is?
Options:
A)10.9 sec
B)13.8 sec
C)53.8 sec
D)10.44 sec
E)10.4 sec
Rationale: Relative speed = 60 + 40 = 100 km/hr.
= 100 * 5/18 = 250/9 m/sec.
Distance covered in crossing each other = 140 + 150 = 290 m.
Required time = 290 * 9/250 = 10.44 sec.
Answer: D:
Answer: D
Question: The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is:
Options:
A)504
B)536
C)544
D)548
E)586
Rationale: Required number = (L.C.M. of 12, 15, 20, 54) + 8
= 540 + 8
= 548.
Answer: Option D
Answer: D
Question: A take twice as much time as B or thrice as much time to finish a piece of work. Working together, they can finish the work in 4 days. B can do the work alone in?
Options:
A)19
B)12
C)11
D)24
E)114
Rationale: Suppose A, B and C take x, x/2 and x/3 respectively to finish the work.
Then, (1/x + 2/x + 3/x) = 1/4
6/x = 1/4 => x = 24
So, B takes 12 hours to finish the work.
Answer: D
Answer: D
Question: What is the ratio of y to x if (x + 3y) / ( x - y) = 5/4?
Options:
A)-15/4
B)-5/3
C)1/17
D)3/5
E)15/1
Rationale: Solving for y/x gives, 1/17 (C)
Answer: C
Question: Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 1.15 km respectively. The time taken by the slower train to cross the faster train in seconds is?
Options:
A)65 sec
B)54 sec
C)48 sec
D)33 sec
E)12 sec
Rationale: Relative speed = 60 + 90 = 150 km/hr.
= 150 * 5/18 = 125/3 m/sec.
Distance covered = 1.10 + 1.15 = 2.25 km = 2250 m.
Required time = 2250 * 3/125
= 54 sec.
Answer:B
Answer: B
Question: The distance from the x-axis to point P is half the distance from the y-axis to point P. If the coordinates of P are (x,-5), how many units is P from the y-axis?
Options:
A)2.5
B)5
C)7.5
D)10
E)12
Rationale: The x-axis is 5 units from the point P.
Thus the y-axis is 10 units from the point P.
The answer is D.
Answer: D
Question: Evaluate:60 - 12*3*2 =?
Options:
A)42
B)52
C)62
D)72
E)82
Rationale: According to order of operations, 12?3?2 (division and multiplication) is done first from left to right
12**2 = 4* 2 = 8
Hence
60 - 12*3*2 = 60 - 8 = 52
correct answer B
Answer: B
Question: Jackson purchased a refrigerator and a mobile phone for $15000 and $8000 respectively. He sold the refrigerator at a loss of 4 percent and the mobile phone at a profit of 10 percent. Overall he make a.
Options:
A)profit of Rs. 200
B)profit of Rs. 100
C)loss of Rs. 100
D)loss of Rs. 200
E)None of these
Rationale: A
profit of Rs. 200
Let the SP of the refrigerator and the mobile phone be $ r and $ m respectively.
r = 15000(1 - 4/100) = 15000 - 600
m = 8000(1 + 10/100) = 8000 + 800
Total SP - Total CP = r + m - (15000 + 8000) = -600 + 800 = $200
As this is positive, an overall profit of $200 was made.
Answer: A
Question: 81 men working 8 hours per day dig 30 m deep. How many extra men should be put to dig to a depth of 50 m working 6 hours per day?
Options:
A)A)99
B)B)77
C)C)66
D)D)55
E)E)88
Rationale: (81 * 8)/30
= (x * 6)/50
=> x =180
180 – 81
= 99
Answer:A
Answer: A
Question: There are 15 members in a family. it takes 180 days for a women to complete the work, however man completes in 120 days. They take 17days to complete the work if men work on alternate days and women work every third day. if all of them started together on the 1st day, then how many women are there in the family
Options:
A)1
B)2
C)3 women
D)4
E)5
Rationale: Let the number of men be m and so the number of women = 15-m
Out of 17 days, men and women work together on 1,4,7,10,13,16th days (Total of 6 days) from the start.
Men work on alternate days, that is 1,3,5,7,9,11,13,15,17th days (Total of 9 days).
Let the total work be 360 units (LCM of 180 and 120).
1 man does 360/120 = 3 units per day
1 woman does 360/180 = 2 units per day
Based on above facts,
Total work by men + women in these 17 days = 360 units
m*9*3 + (15-m)*6*2 = 360,
27m + 180 -12m = 360, Solving m=12.
Num of men = 12 and number of women = 15-12 = 3
ANSWER:C
Answer: C