divelab/Sys2Bench huggingface dataset:
Question: Five pieces of wood have an average length of 126cm and a median length of 140cm. What is the maximum possible length, in cm, of the shortest piece of wood?
Options:
A)a) 90
B)b) 105
C)c) 110
D)d) 130
E)e) 140
Rationale: B. 105
sum of all lengths of all 5 pieces of wood = 126 * 5 = 630
3rd piece (sorted in increasing length) length = 140 (median)
for sum of first 2 wood length to become max, last two should be least.
let 4th, 5th wood also have length 140 each.
total of last 3 = 140 * 3 = 420
sum of first 2 = 630 - 420 = 210
each of these 2 will have length 210/2 = 105
Aswer B
Answer: B
Question: A Vendor sells 10 clips for a rupee gaining thereby 40%. How many clips did he buy for a rupee?
Options:
A)10
B)12
C)14
D)15
E)None
Rationale: S.P of 10 Clips=Re 1
Gain= 40%.
C.P of 10 Clips=Rs(100/140)*1=Re 5/7
For Rs 5/7, Clips bought=10.
For Re 1,Clips bought=10*(7/5)=14
Answer: C
Question: If c is an even integer and c/18 is an odd integer, which of the following is NOT an even integer?
Options:
A)(c^2)/54
B)(c^2)/16
C)(c^2)/9
D)(c^2)/6
E)(c^2)/2
Rationale: since c is an even integer and c/18 is an odd integer. thus maximum power of 2 in a is one. why ?? because if the power of 2 in the expression has been 2 or greater, then the c/18 must have been an even integer. (18=2*3^2. as 18 contain only one 2 in the expression)
now, any expression in which we have 4 at the denominator will be odd. out of the given options only 16 is a multiple of 4. hence answer should be B
Answer: B
Question: Out of nine consonants and three vowels, how many words can be made so that each word contains two consonants and three vowels?
Options:
A)3180
B)3510
C)3920
D)4320
E)4750
Rationale: 9C2 x 3C3 x 5! = 4320
The answer is D.
Answer: D
Question: 7 baseball players each stand at different corners of a baseball diamond. The sides of the diamond are all of equal length. Two arrangements of baseball players are considered different only when the relative positions of the players differ. How many different ways can the baseball players arrange themselves around the diamond?
Options:
A)445
B)632
C)720
D)240
E)256
Rationale: it is like a circular arrangement.
total ways for n people to arrange in a circle is = factorial (n-1)
in this case n= 7
hence ans = 7 factorial = 720
hence C
Answer: C
Question: Eighteen years ago, a father was three times as old as his son. Now the father is only twice as old his son. Then the sum of the present ages of the son and the father is?
Options:
A)176 years
B)168 years
C)186 years
D)108 years
E)178 years
Rationale: Let the present ages of the father and son be 2x and x years respectively.
Then, (2x - 18) = 3(x - 18) => x = 36
Required sum = (2x + x)
= 108 years.
Answer:D
Answer: D
Question: If the cost price of 50 articles is equal to the selling price of 40 articles, then the gain or loss percent is?
Options:
A)20%
B)35%
C)95%
D)15%
E)25%
Rationale: Given that, cost price of 50 article is equal to selling price of 40 articles.
Let cost price of one article = Rs. 1
Selling price of 40 articles = Rs. 50
But Cost price of 40 articles = Rs. 40
Therefore, the trader made profit.\Percentage of profit = 10/40 * 100 = 25%
Answer: E
Answer: E
Question: The length of a rectangle is halved, while its breadth is tripled. What is the % change in area?
Options:
A)30%
B)40%
C)50%
D)60%
E)65%
Rationale: Let original length = x and original breadth = y.
Original area = xy.
New length =	x	.
2
New breadth = 3y.
New area = x	x 3y =	3	xy.
2	2
Increase % = 1	xy x	1	x 100	%	= 50%.
2	xy
C
Answer: C
Question: The largest 5 digit number exactly divisible by 91 is?
Options:
A)99918
B)99919
C)99921
D)99923
E)99929
Rationale: Largest 5-digit number = 99999
91) 99999 (1098
91
---
899
819
----
809
728
---
81
---
Required number = (99999 - 81)
= 99918.
Option A
Answer: A
Question: 5^100 is divided by 18 then what is the remainder?
Options:
A)10
B)11
C)13
D)15
E)16
Rationale: Here N = 18=2×32
ϕ(18)=18(1−12)(1−13) = 6
So 56 when divided by 18, remainder is 1.
So we can write the given expression 5100=(56)16×54 = (1)16×54 = 52×52=7×7=49
Now 49 when divided by 18, remainder is 13.
C
Answer: C
Question: In Smithtown, the ratio of right-handed people to left-handed people is 3 to 1 and the ratio of men to women is 3 to 2. If the number of right-handed men is maximized, then what S percent of all the people in Smithtown are left-handed women?
Options:
A) 50%
B) 40%
C) 25%
D) 20%
E) 10%
Rationale: looking at the ratio we can take total number of people=20..
ans 5/20 or 25% C
Answer: C
Question: 60kg of an alloy A is mixed with 100 kg of alloy B. If alloy A has lead and tin in the ratio 3:2 and alloy B has tin and copper in the ratio 1:4, then the amount of tin in the new alloy is?
Options:
A)24kg
B)44kg
C)20kg
D)30kg
E)52kg
Rationale: Quantity of tin in 60kg of A = 60*2/5 = 24kg
Quantity of tin in 100kg of B = 100*1/5 = 20kg
Quantity of tin in the new alloy = 24+20 = 44kg
Answer is B
Answer: B
Question: Find the highest common factor of 36 and 84.
Options:
A)4
B)6
C)12
D)18
E)20
Rationale: 36 = 22 x 32
84 = 22 x 3 x 7
H.C.F. = 22 x 3 = 12.
Answer: Option C
Answer: C
Question: In an election between two candidates A and B, the number of valid votes received by A exceeds those received by B by 15% of the total number of votes polled. If 20% of the votes polled were invalid and a total of 5720 votes were polled, then how many valid votes did B get?
Options:
A)1859
B)2999
C)2834
D)2777
E)2991
Rationale: Let the total number of votes polled in the election be 100k.
Number of valid votes = 100k - 20% (100k) = 80k
Let the number of votes polled in favour of A and B be a and b respectively.
a - b = 15% (100k) => a = b + 15k
=> a + b = b + 15k + b
Now, 2b + 15k = 80k and hence b = 32.5k
It is given that 100k = 5720
32.5k = 32.5k/100k * 85720 = 1859
The number of valid votes polled in favour of B is 1859.
Answer: A
Answer: A
Question: People are allowed to add an apple or take an apple from a large barrel. If people are only adding apples, the barrel can be filled in 5 hours. If people only take apples, the barrel can be emptied in 15 hours. If it is desired that the barrel should be filled, from empty, exactly 6 hours after people begin adding apples at 9:30am, then at what time should people begin taking apples?
Options:
A)10:00am
B)10:45am
C)12:00pm
D)12:30pm
E)1:30pm
Rationale: In 6 hours the amount of apples added equals to 6*1/5 = 6/5 of the barrel. So, 1/5 more than necessary, which should be compensated by people taking apples. To rid 1/5 of the apples people take, it will require 15/5 = 3 hours.
Therefore, people should begin taking apples at 9:30am + 6 hours - 3 hours = 12:30pm.
Answer: D.
Answer: D
Question: A women walking at 4 Kmph reaches her office 8 minutes late. If she walks at 6 Kmph, she reaches there 8 minutes earlier. How far is the office from her house?
Options:
A)2 1/5 Km
B)3 1/5 Km
C)4 1/3 Km
D)5 Km
E)5 1/3 Km
Rationale: Formula = S1*S2/S2-S1 * T1+T2/60
= 4*6/2 * 16/6
= 24/2 * 16/60
= 8 * 2/5
= 16/5 = 3 1/5 Km
B)
Answer: B
Question: A began business with 12500 and is joined afterwards by B with 25000. When did B join, if the profits at the end of the year are divided equally?
Options:
A)8 months
B)9 months
C)10 months
D)6 months
E)None of these
Rationale: Let B join after x months of the start of the business so that B’s money is invested for (12 – x) months.
∴ Profit ratio is 12 × 12500 : (12 – x) × 25000
or 12 : 2(12 – x)
Since profit is equally divided so
12 = 2(12 – x) or x = 6. Thus B joined after 8 months.
Answer D
Answer: D
Question: At a circular table for ten will sit eight adults and two small children. The two children will sit next to each other, and the two parents of the children will sit next to the children so that there is one parent on each side of the two children. If rotating their positions around the table is not considered changing the arrangement, in how many different ways can the ten people be arranged around the table.
Options:
A)1220
B)1660
C)2440
D)2880
E)3200
Rationale: Consider the two parents and two children as one unit.
Then there are six adults and one family unit.
The number of ways 7 can form a line is 7!
Around a circular table, there would be 7 rotations so we divide this number by 7.
There are 6! ways for 7 to sit around the circular table.
Then the two children have two options and the two parents have two options.
Then the total number of ways is 6!*2*2= 2880
The answer is D.
Answer: D
Question: The perimeters of two squares are 60 cm and 40 cm. Find the perimeter of a third square whose area is equal to the difference of the areas of the two squares?
Options:
A)76 cm
B)24 cm
C)88 cm
D)44.8 cm
E)34 cm
Rationale: We know perimeter of square = 4(side)
So Side of first square = 60/4 = 15 cm
Side of second square = 40/4 = 10 cm
Area of third Square = 15*15 - 10*10
= 125 cm
So side of third square = 11.2 [because area of square = side*side]
Perimeter = 4*Side = 4*11.2 = 44.8 cm
Answer:D
Answer: D
Question: Of the diplomats who attended a summit conference: 20 spoke Latin, 32 did not speak Russian and 20% of the diplomats spoke neither Latin nor Russian. If 10% of the diplomats spoke both Latin and Russian, then how many diplomats attended the conference?
Options:
A)70
B)96
C)108
D)120
E)150
Rationale: 2X2 matrix will be the easiest way to calculate this.
Text in black: given statements
Text in red: calculated values
Thus D=120 is the correct answer
Answer: D
Question: A jogger running at 9 km/hr along side a railway track is 240 m ahead of the engine of a 120 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger?
Options:
A)37
B)25
C)36
D)08
E)12
Rationale: Speed of train relative to jogger = 45 - 9 = 36 km/hr.
= 36 * 5/18 = 10 m/sec.
Distance to be covered = 240 + 120 = 360 m.
Time taken = 360/10 = 36 sec.
Answer: C
Answer: C
Question: If 0.75: x :: 5:7, then x is equal to:
Options:
A)1.05
B)1.16
C)1.2
D)1.3
E)None of these
Rationale: Explanation:
(x * 5) = (0.75 *7)
X=5.25/5 = 1.05
Answer: A
Answer: A
Question: If a man crosses a 650 m long street in 5 minutes. What is his speed?
Options:
A)7 km/hr
B)7.1 km/hr
C)7.8 km/hr
D)8 km/hr
E)8.5 km/hr
Rationale: distance = 650 meter
time = 5 minutes = 5 x 60 seconds = 300 seconds
Speed = distance/time=650/300=2.17m/s
=2.17×18/5=7.8 km/hr
C
Answer: C
Question: The salary of a typist was at first raised by 10% and then the same was reduced by 5%. If he presently draws Rs.1045.What was his original salary?
Options:
A)1000
B)970
C)765
D)654
E)780
Rationale: X * (110/100) * (95/100) = 1045
X * (11/10) * (1/100) = 11
X = 1000
ANSWER A
Answer: A
Question: Two dogsled teams raced across a 300 mile course in Wyoming. Team A finished the course in 3 fewer hours than team E. If team A's average speed was 5 mph greater than team E's, what was team E's average mph?
Options:
A)12
B)15
C)18
D)20
E)25
Rationale: This is a very specific format that has appeared in a handful of real GMAT questions, and you may wish to learn to recognize it: here we have a *fixed* distance, and we are given the difference between the times and speeds of two things that have traveled that distance. This is one of the very small number of question formats where backsolving is typically easier than solving directly, since the direct approach normally produces a quadratic equation.
Say Team E's speed was s. Then Team E's time is 300/s.
Team A's speed was then s+5, and Team A's time was then 300/(s+5).
We need to find an answer choice for s so that the time of Team A is 3 less than the time of Team E. That is, we need an answer choice so that 300/(s+5) = (300/s) - 3. You can now immediately use number properties to zero in on promising answer choices: the times in these questions will always work out to be integers, and we need to divide 300 by s, and by s+5. So we want an answer choice s which is a factor of 300, and for which s+5 is also a factor of 300. So you can rule out answers A and C immediately, since s+5 won't be a divisor of 300 in those cases (sometimes using number properties you get to the correct answer without doing any other work, but unfortunately that's not the case here). Testing the other answer choices, if you try answer D, you find the time for Team E is 15 hours, and for Team A is 12 hours, and since these differ by 3, as desired, D is correct.
Answer: D
Question: Find the largest 6 digit number which is exactly divisible by 88?
Options:
A)998765
B)998907
C)999944
D)999954
E)999990
Rationale: Largest 6 digit number is 999999
After doing 999999 ÷ 88 we get remainder 55
Hence largest 6 digit number exactly divisible by 88 = 999999 - 55 = 999944
C
Answer: C
Question: A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Options:
A)120 metres
B)180 metres
C)324 metres
D)150 metres
E)170 metres
Rationale: Explanation:
Speed= 60 x	5/18	m/sec	= 50/3	m/sec.
Length of the train = (Speed x Time).
Length of the train = 50/3	x 9	m = 150 m
ANSWER IS D
Answer: D
Question: How many of the positive divisors of 600 are also multiples of 4 not including 600?
Options:
A)6
B)8
C)9
D)11
E)12
Rationale: 600 = 2^6 * 3 * 5 = (4) * 2 * 3 * 5^2
Besides (4), the exponents of 2, 3, and 5 are 1, 1, and 2.
There are (1+1)(1+1)(2+1) = 12 ways to make multiples of 4.
We must subtract 1 because one of these multiples is 600.
The answer is D.
Answer: D
Question: A bookseller has two display windows. She plans to display 4 new fiction books in the left window, and 3 new non-fiction books in the right window. Assuming she can put the four fiction books in any order, and separately, the three non-fiction books in any order, how many total configurations will there be for the two display windows?
Options:
A)24
B)72
C)144
D)336
E)420
Rationale: Explanations
1) The left window will have permutations of the 4 fiction books, so the number of possibilities for that window is
permutations = 4! = (4)(3)(2)(1) = 24
The right window will have permutations of the 3 non-fiction books, so the number of possibilities for that window is
permutations = 3! = (3)(2)(1) = 6
Any of the 24 displays of the left window could be combined with any of the 6 displays of the right window, so the total number of configurations is 24*6 = 144
Answer: C.
Answer: C
Question: How many even 4-digit integers greater than 8000 are there such that all their digits are different?
Options:
A)240
B)369
C)469
D)520
E)599
Rationale: Case 1: Numbers starting with 8 followed by EVEN number
The hundreds digit can take 4 numbers (0,2,4,6) so 4 ways
The unit digit can take remaining 3 EVEN numbers left after using 2, to be EVEN so 3 ways.
The tens digit can take remaining 7 numbers left after using 3 numbers so 7 ways
Total=4*3*7=84
Case 2: Numbers starting with 8 followed by ODD number
The hundreds digit can take 5 numbers (1,3,5,7,9) so 5 ways
The unit digit can take remaining 4 EVEN numbers (0,2,4,6) to be EVEN so 4 ways.
The tens digit can take remaining 7 numbers left after using 3 numbers so 7 ways
Total=5*4*7=140
Case 3: Numbers starting with 9 followed by EVEN number
The hundreds digit can take 5 numbers (0,2,4,6,8) so 5 ways
The unit digit can take remaining 4 EVEN numbers left after using 1, to be EVEN so 3 ways.
The tens digit can take remaining 7 numbers left after using 3 numbers so 7 ways
Total=5*3*7=105
Case 4: Numbers starting with 9 followed by ODD number
The hundreds digit can take 4 numbers (1,3,5,7) so 4 ways
The unit digit can take 5 numbers (0,2,4,6,8) to be EVEN so 5 ways.
The tens digit can take remaining 7 numbers left after using 3 numbers so 7 ways
Total=4*5*7=140
Hence 84+140+105+140=469, correct answer is C
Answer: C
Question: A marketing firm determined that, of 200 households surveyed, 80 used neither Brand K nor Brand B soap, 60 used only Brand K soap, and for every household that used both brands of soap, 3 used only Brand B soap. How many of the 200 households surveyed used both brands of soap?
Options:
A) 15
B) 20
C) 30
D) 40
E) 45
Rationale: SOLUTION FOR SOAP K AND SOAP B
(D) 40
Answer: D
Question: John deposited $10,000 to open a new savings account that earned 2 percent annual interest, compounded quarterly. If there were no other transactions in the account, what was the amount of money in John’s account 6 months after the account was opened?
Options:
A)$10,100.25
B)$10,101.50
C)$10,200.75
D)$10,201.00
E)$10,400.35
Rationale: 2 percent annual interest compounded quarterly --> 0.5% in 3 moths.
For the first 3 moths interest was 0.5% of $10,000, so $50;
For the next 3 moths interest was 0.5% of $10,000,plus0.25 earned on previous interest of $100, so $50+$0.25=$50.25;
Total interest for 6 months was $50+$50.25=$100.25, hence balance after 6 months was $10,000+ $100.25=$10,100.25.
Answer: A.
Answer: A
Question: If 3<(7-x)/3, which of the following must be true?
I. 5<x
II. |x+3|>2
III. -(x+5) is positive
Options:
A)II only
B)III only
C)I and II only
D)II and III only
E)I, II and III
Rationale: 12<7-x
x<-5
x+5<0
1.5<x...not possible
2.True.....Check for values x=-6,-7,-8....... etc
3.True.. Since x+5<0 -(x+5) will always be positive
Hence, Ans is C..
Answer: C
Question: Listed below are the mean temperatures measured in the Tokharian desert in a certain month. What is the median temperature T in that particular month?
Mean Temp (C°) No. of days
29 --------------------> 5
30 --------------------> 11
31 --------------------> 8
32 --------------------> 6
Options:
A)29
B)30
C)30.5
D)31
E)32
Rationale: to find out median===>they must be arranged in ascending order.
29 29 29...(5 times)30 30 30 30.....(11 times)31 31 31.....(8 times)32 32 32 .....(6 times)
total days=5+11+8+6=30
therefore 30 numbers ...median T will be==>mean of 15 and 16 th place temperature===>(30+30)/2=30
hence B
Answer: B
Question: Which among the following integers represents a sum of 3 consecutive even integers?
Options:
A)200
B)303
C)400
D)554
E)582
Rationale: Sum of three consecutive Even Integers must be a multiple of 2 as well as a multiple of 3 because such a sum is always 3 times the middle number (applicable to all equally spaced numbers)
Divisibility of 3: Sum of the digits of the number must be divisible by 3
Divisibility of 2: Unit digit of the number must be divisible by 2
A. 200NOT A MULTIPLE OF 3 SO RULED OUT
B. 303NOT A MULTIPLE OF 2 SO RULED OUT
C. 400NOT A MULTIPLE OF 3 SO RULED OUT
D. 554NOT A MULTIPLE OF 3 SO RULED OUT
E. 582A MULTIPLE OF BOTH 2 AND 3 SO THE CORRECT ANSWER!!!
Answer: E
Question: Find the number of terms in the series 8, 12, 16, . . .72
Options:
A)17
B)18
C)19
D)20
E)21
Rationale: SOLUTION:
a = 8
l = 72
d = 12 – 8 = 4
ANSWER IS A
Answer: A
Question: As part of her MBA program, Karen applied for three different Spring Break outreach projects, each of which selects its students by a random lottery of its applicants. If the probability of her being accepted to each individual project is 25%, what is the probability that Karen will be accepted to at least one project?
Options:
A)37/64
B)23/64
C)15/32
D)7/16
E)5/8
Rationale: Since the probability of Karen's being accepted to each individual project is 25%, the probability of her not being accepted to each project is 75%. The probability that she will be accepted to none is, therefore, (3/4)*(3/4)*(3/4)=27/64.
P(Karen will be accepted to at least one project) = 1 - (27/64) = 37/64.
The answer is A.
Answer: A
Question: AB
+BA
___
202
In the addition problem above, A and B represent digits in two different two-digit numbers. What is the sum of A and B?
Options:
A)6
B)8
C)9
D)20
E)14
Rationale: two ways to do it..
1) straight logic..
only 20 fits in..
D
Answer: D
Question: The weight of every type A widget is the same, the weight of every type B widget is the same, and the weight of every type C widget is the same. If the weight of 7 type A widgets is equal to the weight of 2 type B widgets, and the weight of 3 type B widgets is equal to the weight of 7 type C widgets. What is the ratio of the total weight of 1 type A widget and 1 type B widget, to the total weight of 1 type B widget and 1 type C widget?
Options:
A)1:2
B)3:4
C)5:6
D)7:8
E)9:10
Rationale: 3B = 7C and so B = 7C/3
7A = 2B and so A = 2B/7 = 2C/3
A+B = 2C/3 + 7C/3 = 9C/3
B+C = 7C/3 + C = 10C/3
The ratio of A+B:B+C = 9:10
The answer is E.
Answer: E
Question: A fraction bears the same ratio to 1/27 as 3/7 does to 5/9. The fraction is?
Options:
A)1/24
B)1/35
C)1/34
D)1/37
E)1/23
Rationale: Let the fraction be x. Then,
x:1/27 = 3/7 : 5/9
x × 5/9 = 1/27 × 3/7
x × 5/9 = 1/9 × 1/7
x × 5/9 = 1/63
x × 5 = 9/63
5x = 1/7 = 1/35
B
Answer: B
Question: The set S consists of 5 numbers: {1,2,3,4,5}. If all possible subsets including the null set are created and one subset is chosen at random, what is the probability that the subset has 4 or 5 as its largest number?
Options:
A)1/2
B)2/3
C)3/4
D)5/8
E)11/16
Rationale: The set S has 2^5 = 32 subsets.
The number 5 is in half of these subsets.
Thus 5 is the largest number in 16 subsets of S.
Of the remaining 16 subsets, 4 is an element in 8 of them.
Thus 4 is the largest number in 8 subsets of S.
The probability that 4 or 5 is the largest number is 24/32 = 3/4.
The answer is C.
Answer: C
Question: What will be 50 percent of a number whose 200 percent is 90 ?
Options:
A)144
B)72
C)22.5
D)None of these
E)Cannot be determined
Rationale: Answer
∵ 200% of N = 90
⇒ N = (90 x 100) / 200 = 45
∴ 50% of N = (50 x 45) / 100 = 22.5
Correct Option: C
Answer: C
Question: The difference between the local value and the face value of 6 in the numeral 85475641 is
Options:
A)459
B)954
C)594
D)584
E)458
Rationale: Explanation:
(Local value of 6) - (Face value of 6) = (600 - 6) = 594
C)
Answer: C
Question: A gambler bought $3,000 worth of chips at a casino in denominations of $30 and $100. That evening, the gambler lost 16 chips, and then cashed in the remainder. If the number of $30 chips lost was 2 more or 2 less than the number of $100 chips lost, what is the largest amount of money that the gambler could have received back?
Options:
A)$2,040
B)$2,120
C)$1,960
D)$1,920
E)$2,030
Rationale: In order to maximize the amount of money that the gambler kept, we should maximize # of $30 chips lost and minimize # of $100 chips lost, which means that # of $30 chips lost must be 2 more than # of $100 chips lost.
So, if # of $30 chips lost is x then # of $100 chips lost should be x-2. Now, given that total # of chips lost is 16: x+x-2=16 --> x=9: 9 $30 chips were lost and 9-2=7 $100 chips were lost.
Total worth of chips lost is 9*30+7*100=$970, so the gambler kept $3,000-$970=$2,030.
Answer: E
Answer: E
Question: In a regular week, there are 5 working days and for each day, the working hours are 8. A man gets Rs. 2.40 per hour for regular work and Rs. 3.20 per hours for overtime. If he earns Rs. 432 in 4 weeks, then how many hours does he work for ?
A.	160
B.	175
C.	180
D.	195
Explanation:
Options:
A)160
B)175
C)180
D)185
E)195
Rationale: Suppose the man works overtime for x hours.
Now, working hours in 4 weeks = (5 x 8 x 4) = 160.
160 x 2.40 + x x 3.20 = 432
3.20x = 432 - 384 = 48
x = 15.
Hence, total hours of work = (160 + 15) = 175.
Answer: Option B
Answer: B
Question: When positive integer s is divided by 6, the remainder is 1. Which of the following must be true?
I. s is a prime number
II. s is odd
III. s is divisible by 7
Options:
A)I only
B)II only
C)III only
D)I and II only
E)II and III only
Rationale: s=6q+1
Examine II) put q=0,1,2,3....... we have s=1,7,13,...25 so s must be odd
Examine III) 14/6 has reminder 249/7 has reminder 1 so not always true
Examine I) s= 7 true but while 2 is prime, it does not give reminder 1
Answer: B
Answer: B
Question: If a carpenter completes 3/8th of his work in 6 days, then how many more days will he require completing his remaining work?
Options:
A)10
B)12
C)6
D)16
E)18
Rationale: Explanation:
As 3/8th of the work is completed, the work remaining is 5/8th of the total.
(3/8):6::(5/8):x
x = 6*(5/8)/(3/8)
x = 10
ANSWER A
Answer: A