divelab/Sys2Bench huggingface dataset:
Question: If the two-digit integers P and N are positive and have the same digits, but in reverse order, which of the following CANNOT be the sum of P and N?
Options:
A)181
B)165
C)121
D)99
E)44
Rationale: Since the question asks for the answer that CANNOT be the sum of P and N, and the answers are numbers, we can use a combination of TESTing VALUES and TESTing THE ANSWERS to eliminate the possible values and find the answer to the question.
We're told that P and N are two-digit positive integers and have the SAME DIGITS but in REVERSE ORDER. We're asked which of the 5 answers CANNOT be the SUM of P and N.
Let's start with the 'easiest' answer first:
44. Can we get to 44 in the manner described?
Yes, if the numbers are 13 and 31.....13+31 = 44. Eliminate Answer E
Now let's work through the rest of the list....
Can we get to 99 in the manner described?
Yes, there are several ways to do it. For example, if the numbers are 18 and 81.....18+81 = 99. Eliminate Answer D
Can we get to 121 in the manner described?
Yes, there are several ways to do it. For example, if the numbers are 38 and 83.....38+83 = 121. Eliminate Answer C
Can we get to 165 in the manner described?
Yes, there are a couple of ways to do it. For example, if the numbers are 78 and 87.....78+87 = 165. Eliminate Answer B
There's only one answer left....
A
Answer: A
Question: a school has 9 English 7 history and 6 geography teachers each teacher can teach 2 subjects max what is he minimum number of teachers required
Options:
A)7
B)8
C)9
D)10
E)11
Rationale: Total subjects = 9+7+6=22
Max subjects by 1 teacher = 2
So, min of teachers required = 22/2 = 11
ANSWER:E
Answer: E
Question: If f(a)=a^2, what is the value of (f(a+b)−f(b))/b ?
Options:
A)2a+a^2
B)b
C)2a
D)2a + b
E)2b - a
Rationale: start with f(a+b) before start calculations: f(a+b)=(a+b)^2= a^2+2ab+b^2
a^2+2ab+b^2 - b^2/b = (simplify a^2)
2ab+a^2/b = (cancel b's)
= 2a+a^2
Ans : A
Answer: A
Question: A can run 22.5 m while B runs 25 m. In a kilometre race B beats A by:
Options:
A)120 meter
B)300 meter
C)100 meter
D)200 meter
E)500 meter
Rationale: when B runs 25 m, A runs 22.5 m
=> When B runs 1000 metre, A runs 22.5/25 x 1000 = 900m.
=> When B runs 1 kilometre, A runs 900 m
Hence, in a kilometre race, B beats A by
ANSWER:C
(1 kilometre - 900 metre) = (1000 metre - 900 metre) = 100 metre
Answer: C
Question: The sum of the present ages of two persons A and B is 54. If the age of A is twice that of B, find the sum of their ages 5 years hence?
Options:
A)50
B)64
C)70
D)80
E)90
Rationale: A + B = 54, A = 2B
2B + B = 54 => B = 18 then A = 36.
5 years, their ages will be 41 and 23.
Sum of their ages = 41 + 23 = 64.
ANSWER:B
Answer: B
Question: If 7800 / 3.25 = 2400, then 780.0 / 32.5 is equal to ?
Options:
A)21
B)28
C)26
D)25
E)24
Rationale: Answer
Given expression 780.0 / 32.5 = 7800 / 325
= 7800 / (3.25 x 100)
= 2400 / 100
=24
Correct Option: E
Answer: E
Question: A and B walk around a circular track. A and B walk at a speed of 2 rounds per hour and 3 rounds per hour respectively. If they start at 8 a.m. from the same point in opposite directions, how many times shall they cross each other before 9.30 a.m.?
Options:
A)5
B)6
C)7
D)8
E)9
Rationale: Explanation:
Relative speed = Speed of A + Speed of B (∴ they walk in opposite directions)
=2+3=5 rounds per hour
Therefore, they cross each other 5 times in 1 hour and 2 times in 12 hour
Time duration from 8 a.m. to 9.30 a.m. =1.5 hour
Hence they cross each other 7 times before 9.30 a.m.
ANSWER IS C
Answer: C
Question: Sam’s car was fined when he gave Joe and Peter a ride, so they decided to help Sam pay the fine. Joe paid $10 more than 1/4 of the fine and Peter paid $10 less than 1/3 of the fine, leaving pay $25 less than 1/2 the fine to complete the payment. What fraction of the fine did Sam pay?
Options:
A)$120
B)$125
C)$130
D)$135
E)$140
Rationale: Call the fine F. Joe paid (1/4)F + 4 and Peter paid (1/3)F – 4, leaving (1/2)F – 5 left. If we add those three up, they should add up to F.
F = [(1/4)F + 10] + [(1/3)F – 10] + [(1/2)F – 25]
F = (1/4)F + (1/3)F + (1/2)F – 25
Multiply all terms by 12 to clear the fractions.
12F = 3F + 4F + 6F – 300
12F = 13 F – 300
–F = – 300
F = 300
Well, if the fine cost $300, then Sam paid the part not covered by Joe or Peter. Half the fine is $150, and Sam paid $25 less than this: $125
Answer = B
Answer: B
Question: Mary built a model ship. She spent 10 hours constructing the ship and 5 hours painting it, for what fraction of the total time did she spend painting the ship?
Options:
A)1/3
B)1/5
C)1/4
D)2/3
E)1/2
Rationale: We don't need to get into calculations for solving this question. We can use the concept of weighted averages.
The average time for the entire project is 15 hours; so, she spent a lesser duration of time painting the ship than constructing it.
5---(5---5)
This shows that you can divide the entire project into 3 equal parts. Thus, 1/3 of the journey was spent painting.
Answer: A
Answer: A
Question: A and B participate in a seven-person footrace on the basketball court during All-Star Weekend. If all seven contestants finish (including Charles Barkley) and there are no ties, how many different arrangements of finishes are there in which A defeats B ?
Options:
A) 5040
B) 2520
C) 720
D) 120
E) 42
Rationale: PRINCETON REVIEW OFFICIAL SOLUTION:
A beats B? Carmelo beats B? No one said anything about specific results, especially not on a question that includes so many people.
Many questions on the GMAT can be overwhelming in appearance so first thing…Relax. This question looks nasty, but it’s pretty straightforward, requiring two things: the basic first calculation and then some additional work to solve the problem. It would be extremely painful to try to calculate this whole question in one fell swoop. So don’t.
Calculate out all possibilities first to get your bearings. That is, how many different arrangements, period? Since the order of arrangement again matters, this is another permutation. And since we’re placing all seven runners, this calculation is…
7 x 6 x 5 x 4 x 3 x 2 x 1, cash and prizes worth 5040 arrangements.
Now, what to do? Again, some nice deep breathing to control your nerves – relax and think. These 5040 arrangements are a comprehensive list; every possible seven-person order of finish has been counted. So, we have accounted for every time A beats B AND every time LeBron beats Carmelo. Doesn’t it make sense that, for every time Carmelo beats LeBron, there is exactly one other instance in which LeBron beats Carmelo? Or more simply, doesn’t it make sense that, if these 5040 represents everything, that Carmelo beats LeBron exactly 50% of the time and vice versa?
The thought takes time. You need to have the presence to recognize that grinding your way in, around, and through this question could take roughly forever. Stepping back and recognizing that this is simply a 50/50 proposition and applying that thought to the 5040 you cranked out gives you 2520. The answer is B.
Answer: B
Question: Half of 3 percent written as decimal is
Options:
A)5
B)0.5
C)0.05
D)0.015
E)None of these
Rationale: Explanation:
It will be 1/2(3%) = 1/2(3/100) = 3/200 = 0.015
Answer: Option D
Answer: D
Question: Jane and Thomas are among the 6 people from which a committee of 3 people is to be selected. How many different possible committees of 3 people can be selected from these 6 people if at least one of either Jane or Thomas is to be selected?
Options:
A)12
B)14
C)16
D)18
E)20
Rationale: The total number of ways to choose 3 people from 6 is 6C3 = 20.
The number of committees without Jane or Thomas is 4C3 = 4.
There are 20-4 = 16 possible committees which include Jane and/or Thomas.
The answer is C.
Answer: C
Question: In a class of 37 students 26 play football and play 20 long tennis, if 17 play above, many play neither?
Options:
A)6
B)8
C)10
D)12
E)14
Rationale: 26 + 20 - 17 = 29
37 - 29 = 8 play neither
Answer is B
Answer: B
Question: What is the area of square field whose side of length 25 m?
Options:
A)225 sq m
B)186 sq m
C)586 sq m
D)287 sq m
E)625 sq m
Rationale: 25 * 25
= 625 sq m
Answer: E
Answer: E
Question: P can do a work in the same time in which Q and R together can do it. If P and Q work together, the work can be completed in 10 days. R alone needs 35 days to complete the same work. then Q alone can do it in
Options:
A)20
B)22
C)25
D)28
E)30
Rationale: Work done by P and Q in 1 day = 1/10
Work done by R in 1 day = 1/35
Work done by P, Q and R in 1 day = 1/10 + 1/35 =9/70
But Work done by P in 1 day = Work done by Q and R in 1 day . Hence the above equation can be written as Work done by P in 1 day Ã— 2 = 9/70
=> Work done by P in 1 day = 9/140
=> Work done by Q and R in 1 day = 9/140
Hence work done by Q in 1 day = 9/140â€“ 1/35 = 1/28
So Q alone can do the work in 28 days
Answer is D.
Answer: D
Question: 6 + 12 + 18 + 5 x 6^2 + 5 x 6^3 + 5 x 6^4 + 5 x 6^5 + 5 x 6^6 =
Options:
A) 6^7
B) 6^10
C) 6^12
D) 6^16
E) 6^18
Rationale: Let's see that 6 + 12 + 18 is 36 or 6^2, then: 6^2 + 5 x 6^2 becomes 6 x 6^2 that is 6^3. So we follow with the next element: 6^3 + 5 x 6^3 is equal to 6 x 6^3 that is 6^4. Then is assumed right before 5 x 6^6: 6^6 + 5 x 6^6 becomes 6 x 6^6 that is 6^7. Thus, the correct answer is the option A, 6^7.
Answer: A
Question: A car takes 6 hours to cover a distance of 180 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time?
Options:
A)50 Kmph
B)20 Kmph
C)65 Kmph
D)70 Kmph
E)None
Rationale: Time = 6
Distence = 180
3/2 of 6 hours = 6 * 3/2 = 9 Hours
Required speed = 180/9 = 60 Kmph
B)
Answer: B
Question: How many positive integers less than 70 have a reminder 01 when divided by 3?
Options:
A)13
B)24
C)35
D)16
E)17
Rationale: 1 also gives the remainder of 1 when divided by 3. So, there are total of 24 numbers.
Answer: B.
Answer: B
Question: A plane flies 720 km with the wind and 630 km against the wind in the same length of time. If the speed of the wind is 15 km/h, what is the speed of the plane in still air?
Options:
A)205 km/h
B)215 km/h
C)225 km/h
D)235 km/h
E)245 km/h
Rationale: The speed of the plane in still air = x km/h
The speed of the wind is 15 km/h
Speed with the wind = (x + 15) km/h
Speed against the wind = (x â€“ 15) km/h
Time = Distance/ Speed
720 / (x+15) = 630 / (x-15)
720(x-15) = 630(x+15)
72x - 1080 = 63x + 945
9x = 2025
x = 225
Therefore, the speed of the plane in still air is 225 km/h.
The answer is C.
Answer: C
Question: Amar takes as much time in running 18 meters as a car takes in covering 48 meters. What will be the distance covered by Amar during the time the car covers 1.6 km?
Options:
A)328
B)288
C)2800
D)600
E)713
Rationale: Distance covered by Amar = 18/4.8 (1.6km)
= 3/8(1600)
= 600 m
Answer:D
Answer: D
Question: The sum of the digits of a two digit number is 7. When the digits are reversed then the number is decreased by 9. Then find the number
Options:
A)43
B)34
C)44
D)35
E)33
Rationale: Let the original no be 10x+y
Sum of the digits x+y=7
When the digits are reversed then it is 10y+x
Since it is decreased by 9 it is written as (10y+x)-(10x+y)=9 solving this we get y=4
Substitute in x+y=7 we get x=3
so the number is 34 correct ans is B
Answer: B
Question: Craig had 200 apples. He lost 20 apples and sold 43 apples. A customer returned one apple. How many apples did he have left?
Options:
A)137
B)138
C)135
D)140
E)139
Rationale: For lost, use negative. For gain, use positive.
200+-20+-43+1
correct answer is B)138
Answer: B
Question: The value of x is to be randomly selected from the integers from 1 to 8, inclusive, and then substituted into the equation y = x^2 - 4x + 3. What is the probability that the value of y will be negative?
Options:
A)1/4
B)1/8
C)1/2
D)3/8
E)5/8
Rationale: y will only be negative for x=2.
(We can check the values from 1 to 8 to be certain.)
P(y is negative) = 1/8
The answer is B.
Answer: B
Question: A man buy a book in Rs50 & sale it Rs70. What is the rate of profit ???
Options:
A)10%
B)40%
C)30%
D)25%
E)28%
Rationale: cp=50
sp=70
profit=70-50=20
%=20/50*100=40%
ANSWER:B
Answer: B
Question: John starts his journey from A to B and Tom starts his journey from B to A at the same time.After passing each other they complete their journeys in 3 1/3 and 4 4/5 hours respectively.Find the speed of Tom if John traveled at 12 miles/hr.
Options:
A)a) 8.33 m/hr
B)b) 9 m/hr
C)c) 10 m/hr
D)d) 20 m/hr
E)e)16.66 m/hr
Rationale: Your calculations look perfect, but I think they answer a different question from the one the question designer intended. I don't find the wording of this question to be good at all, but I'm pretty sure what they mean is this: from the point in time at which John and Tom meet, it takes a *further* 3 1/3 hours for John to complete his journey, and a *further* 4 4/5 hours for Tom to complete his journey. So if it takes them t hours to meet, John will end up traveling for a total of t + 10/3 hours, and Tom a total of t + 24/5 hours. That's a more difficult problem than the one you solved. I don't have time to write up a solution at the moment, but I can later if that would be helpful.
C)
Answer: C
Question: find the number, difference between number and its 3/5 is 50.
Options:
A)120
B)123
C)124
D)125
E)126
Rationale: Explanation:
Let the number = x,
Then, x-(3/5)x = 50,
=> (2/5)x = 50 => 2x = 50*5,
=> x = 125
Answer: Option D
Answer: D
Question: A four digit number is such that the product of all of its digits is 126. The sum of all the digits is equal to the 2 digit number formed by using thousands digit and tens digit (Thousand digit in tens place & ten digit in units place) which in turn is equal to 19. Then difference of units and thousand place of the number is, given that this difference is positive.
Options:
A)1692
B)1792
C)1795
D)1892
E)1992
Rationale: the number is 1792.
Let the number be represented as 1000x+100y+10z+t
acc to ques,
xyzt=126
x + y + z + t = 10x + z = 19
so, number in thousands and tens place are 1 and 9 respectively.
the remaining factor is 14 which is 7*2
So the number is 1792.
ANSWER:B
Answer: B
Question: In a group of hats consisting of only blue hats, green hats, and purple hats, the ratio of blue hats to green hats to purple hats is 7:4:12. If there are a total of 115 hats in this group, how many of these hats are not blue?
Options:
A)28
B)42
C)48
D)80
E)76
Rationale: Since the hats Blue, Green and Purple are in ratio of 7:4:12...The total no. of balls will be
7x+4x+12x=115 or 23x=115...here 7x,4x and 12x represent hats of each type
23x=115 so x=5...Blue hats =7*5=35...Not blue will be 115-35=80.
Ans D
Answer: D
Question: In country Z, 10% of the people do not have a university diploma but have the job of their choice, and 15% of the people who do not have the job of their choice have a university diploma. If 40% of the people have the job of their choice, what percent of the people have a university diploma?
Options:
A)39%
B)45%
C)55%
D)65%
E)75%
Rationale: Setting up a matrix is how I solve this one.
Diploma No Diploma Totals
Job of Choice w/Diploma
Job of Choice w/o Diploma = 10%
Job of Choice Total = 40%
Not Job of Choice with Diploma =.15X
Not Job of Choice w/o Diploma= .85X
Total Not Job of Choice = X
Total with Diploma
Total without Diploma
Total citizen = 100
If 40% of people have their job of choice, then 60% of people do NOT have their job of choice. 15% of 60% = 9%. We can also see that 30% of the people have their job of choice and a diploma (40%-10%=30%). 30% + 9% = 39%. Therefore 39% of the people in Country Z have a diploma.
Ans A
Answer: A
Question: if a person has to divide equally $13011 among all his 12 people then how much minimum should he keep with himself so that he divides equally among all 12 people in whole numbers?
Options:
A)$1
B)$2
C)$3
D)$4
E)$9
Rationale: He would need to keep $ 3 to himself so he can give $ 1084 to all 12 people so option C is correct one
Answer: C
Question: if 50% of (x-y) = 40% of (x+y) then what percent of x is y?
Options:
A)2.5%
B)11%
C)5%
D)15%
E)25%
Rationale: 50% of (x-y)=40% of(x+y)
(50/100)(x-y)=(40/100)(x+y)
5(x-y)=4(x+y)
x=9y
x=9y
therefore required percentage
=((y/x) X 100)% = ((y/9y) X 100) =11%
Answer is B.
Answer: B
Question: After replacing an old member by a new member, it was found that the average age of eight members of a club is the same as it was two years ago.What is the difference between the ages of the replaced and the new member?
Options:
A)2 years
B)4 years
C)8 years
D)16 years
E)None of these
Rationale: Explanation :
Age decreased = (8 x 2) years
16 years
So, required difference =16 years.
Answer : D
Answer: D
Question: Nine coins are tossed simultaneously. In how many of the outcomes will the first coin turn up a head?
Options:
A)2^8
B)2^10
C)3 * 2^8
D)3 * 2^9
E)3 * 2^10
Rationale: Fix the first coin as H. The remaining8 coins have 2^8 outcomes.
Ans:A
Answer: A
Question: In how many W ways can the letters of the word JUPITER be arranged in a row so that the vowels appear in alphabetic order?
Options:
A) 736
B) 768
C) 792
D) 840
E) 876
Rationale: three letters can be arranged in 3! ways.
only one combination EIU is required.
7 letters can be arranged in 7! ways.
thus W=7!/ 3! * 1 = 840.
D
Answer: D
Question: A 600 meter long train crosses a signal post in 30 seconds. How long will it take to cross a 3 kilometer long bridge, at the same speed?
Options:
A)4 min
B)2 min
C)8 min
D)3 min
E)5 min
Rationale: S = 600/30 = 20 mps
S = 3600/20 = 180 sec = 4 min
Answer: D
Answer: D
Question: A student writes a computer program that generates a sequence of numbers a1, a2, a3, ... such that a1=a2=1 and ak=a(k-1)*4+1 for 2<k<n. If n=15, find a5.
Options:
A)85
B)87
C)89
D)93
E)95
Rationale: a1=1
a2=1
a3=1*4+1=5
a4=5*4+1=21
a5=21*4+1=84+1=85
85
Answer: A
Question: The original price of a car was $30,000. Because the car owner thought he could get more money for the car, he set a new price by increasing the original price of the car by 10%. After a week, the car had not sold, so the owner discounted the new price by 10%, and the car was finally sold. What price was the car sold for?
Options:
A)$29,660
B)$29,680
C)$29,700
D)$29,720
E)$29,740
Rationale: The car was sold for (0.9)(1.1)($30,000)=$29,700.
The answer is C.
Answer: C
Question: The average marks in mathematics scored by the pupils of a school at the public examination were 39. If four of these pupils who actually scored 5, 12, 15 and 19 marks at the examination had not been sent up, the average marks for the school would have been 44. Find the number of pupils sent up for examination from the school?
Options:
A)12
B)25
C)28
D)245
E)21
Rationale: 39x = 5 + 12 + 15 + 19 + (x – 4)44
x = 25
Answer: B
Answer: B
Question: Six children — A, B, C, D, E, F, and G — are going to sit in seven chairs in a row. Children AB must sit next to each other, and child C must be somewhere to the right of AB. How many possible configurations are there for the children?
Options:
A)600
B)720
C)1440
D)4320
E)4800
Rationale: A, B, C, D, E, F, G- seven children, of which AB must sit next to each other. Considering them as one X (A, B), we have X, C, D, E, F, G. These can be arranged in 6! ways. But A,B can arrange themselves in 2! ways. So a total of 6!*2! ways = 1440. Since in exactly half of them, C will be to the right of AB, and exactly half, C will be to the left of AB, therefore 1440/2 = 600.
A is the right answer.
Answer: A
Question: A, B, C, D and E are 5 consecutive points on a straight line. If BC = 3CD, DE = 7, AB = 5 and AC = 11, what is the length of AE?
Options:
A)18
B)19
C)20
D)21
E)22
Rationale: AC = 11 and AB = 5, so BC = 6.
BC = 3CD so CD = 2.
The length of AE is AB+BC+CD+DE = 5+6+2+7 = 20
The answer is C.
Answer: C
Question: You hold some gold in a vault as an investment. Over the past year the price of gold increases by 52%. In order to keep your gold in the vault, you must pay 6% of the total value of the gold per year. What percentage has the value of your holdings changed by over the past year.
Options:
A)42.88$
B)43%
C)45%
D)45.5%
E)46.3%
Rationale: (100%+52%)*(100%-6%) = 152*0.94 = 142.88% an increase of 42.88%
Your gold holdings have increased in value by 42.88%.
The Answer is A
Answer: A
Question: In how many ways can you seat 4 people on a bench if one of them, Rohit, does not want to sit on the middle seat or at either end?
Options:
A)720
B)1720
C)2880
D)6
E)10080
Rationale: Since Rohit does not want to sit on the middle seat or at either end (3 chairs), then he can choose 1 chairs to sit. The remaining 3 people can sit in 3! ways. Thus the # of arrangements is 1*3! = 6.
Answer: D.
Answer: D
Question: 5/8 of the population of the country of Venezia lives in Montague Province, while the rest lives in Capulet Province. In the upcoming election, 80% of Montague residents support Romeo, while 70% of Capulet residents support Juliet; each resident of Venezia supports exactly one of these two candidates. Rounded if necessary to the nearest percent, the probability that a Juliet supporter chosen at random resides in Capulet is
Options:
A)28%
B)41%
C)45%
D)72%
E)68%
Rationale: Total population = 80 (assume).
5/8*80=50 people from Montague.
3/8*80=30 people from Capulet.
0.2*50=10 people from Montague support Juliet.
0.7*30=21 people from Capulet support Juliet.
The probability that a Juliet supporter chosen at random resides in Capulet is 21/(10+21)=~68.
Answer: E
Answer: E
Question: A sum of Rs. 395 was divided among A, B, and C in such a way that B gets 25% more than A and 20% more than C. What is the share of A?
Options:
A)Rs.195
B)Rs.180
C)Rs. 98
D)Rs. 120
E)Rs. 130
Rationale: Let each one’s share is A,B and C respectively, then
B =125A/100 = 120C/100
A =100B/125 =4/5B, C = 100B/120 = 5/6B
4/5B +B +5/6B =395, 79B/30 =395, B =395*30/79 =150
A = 4*150/5 = 120
ANSWER:D
Answer: D
Question: Let us say that a table tennis tournament was going on with knock out terms which means the one who loses the match is out of the tournament. 50 players took part in that tournament.
How many matches were played?
Options:
A)99 matches.
B)88 matches.
C)49 matches.
D)66 matches.
E)55 matches.
Rationale: Solution:
49 matches.
The number of matches will always sum up to one less than the number of players in a knock out tournament. You may calculate it in any manner. Thus 49 matches were played.
Answer C
Answer: C
Question: Two cars start at the same time from A and B which are 120 km apart. If the two cars travel in opposite direction they meet after one hour and if they travel in same direction ( from A towards B) then A meets B after 6 hours. What is the speed of the car starting from A?
Options:
A)70 kmph
B)120 kmph
C)60 kmph
D)Data Inadequate
E)None of these
Rationale: Let, speed of car from A towards B = x km/hr
Let, speed of car from B towards A = y km/hr
Two cars start at same time which 120km apart = x + y = 120-----(i)
Travel in same direction, A meets B after 6hr = 6x-6y = 120-----(ii)
By Solving equation (i) and (ii), we get
12x = 840
x = 840/12
x = 70km/hr
Substituting x value in eqn (i) or (ii), we get
y = 50km/hr
So, speed of car starting from 70kmph.
ANSWER:A
Answer: A
Question: The profit obtained by selling an article for Rs. 57 is the same as the loss obtained by selling it for Rs. 43. What is the cost price of the article?
Options:
A)Rs. 40
B)Rs. 50
C)Rs. 49
D)Rs. 59
E)None of these
Rationale: S.P 1- C.P = C.P – S.P 2
57 - C.P = C.P - 43
2 C.P = 57 + 43;
C.P = 100/2 = 50
ANSWER:B
Answer: B
Question: Ram professes to sell his goods at the cost price but he made use of 925 grms instead of a kg, what is the gain percent?
Options:
A)2 9/13%
B)7 9/13%
C)3 9/13%
D)4 9/13%
E)5 9/13%
Rationale: 925 --- 75
75 --- ? =>
=75/925 *100= 7 9/13%
Answer: B
Answer: B
Question: Two men Amar and Bhuvan have the ratio of their monthly incomes as 6 : 5. The ratio of their monthly expenditures is 3 : 2. If Bhuvan saves one-fourth of his income, find the ratio of their monthly savings?
A. 3 : 5
Options:
A)3:9
B)3:10
C)3:21
D)3:12
E)3:14
Rationale: Let the monthly incomes of Amar and Bhuvan be 6x and 5x respectively.
Let the monthly expenditure of Amar and Bhuvan be 3y and 2y respectively.
Savings of Bhuvan every month = 1/4(5x)
= (His income) - (His expenditure) = 5x - 2y.
=> 5x = 20x - 8y => y = 15x/8.
Ratio of savings of Amar and Bhuvan
= 6x - 3y : 1/4(5x) = 6x - 3(15x/8) : 5x/4 = 3x/8 : 5x/4
= 3 : 10.
Answer: Option B
Answer: B