divelab/Sys2Bench huggingface dataset:
Question: A can contains a mixture of two liquids A and B in the ratio 7 : 5. When 9 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes
7 : 9. How many litres of liquid A was contained by the can initially?
Options:
A)10
B)20
C)21
D)25
E)26
Rationale: Suppose the can initially contains 7x and 5x litres of mixtures A and B respectively
Quantity of A in mixture left
= (7x - 7/12 x 9) litres = (7x - 21/4) litres.
Quantity of B in mixture left
= (5x - 5/12 x 9) litres = (5x - 15/4) litres.
(7x - 21/4) / [(5x - 15/4)+9] = 7/9 = › 28x - 21/20x + 21 = 7/9 =› 252x - 189 = 140x + 147
=› 112x = 336 =’ x = 3.
So, the can contained 21 litres of A.
Answer C
Answer: C
Question: 40 people attend a party. 11 men are single and the rest are there with their wives. There are no children in the party. In all 22 women are present. Then the number of married men at the party is ?
Options:
A)5
B)6
C)7
D)11
E)9
Rationale: Total people = number of men + number of women
40 = 7 + number of married men + 22
number of married men = 40- 22-7= 11 men
ANSWER:D
Answer: D
Question: The length of a rectangle is 2 cm more than the width of the rectangle. The perimeter of the rectangle is 20 cm. Find the length and the width of the rectangle.
Options:
A)l=2,w=9
B)l=5,w=8
C)l=6,w=4
D)l=1,w=7
E)l=2,w=3
Rationale: Let length l=x, width w=x−2and perimeter =p
∴p=2l+2w
=2x+2(x−2)
20=2x+2x−4
4x=24
x=6
l=6 cm and w=l−2=4cm
Answer is C.
Answer: C
Question: If f(x)= 5x^2- 2x+6 and g(y)= 3y-7, then g(f(x))
Options:
A)82x^2-9x+38
B)15x^2-6x+11
C)58x^2-4x+58
D)87x^2-5x+96
E)98x^2-7x+94
Rationale: g(f(x))=3(5x^2-2x+6)-7
=15x^2-6x+18-7
=15x^2-6x+11
the answer is B
Answer: B
Question: Manoj borrowed Rs.3450 from Anwar at 6% p.a. simple interest for three years. He then added some more money to the borrowed sum and lent it to Ramu for the same time at 9% p.a. simple interest. If Manoj gains Rs.824.85 by way of interest on the borrowed sum as well as his own amount from the whole transaction, then what is the sum lent by him to Ramu?
Options:
A)Rs.5625
B)Rs.5355
C)Rs.5365
D)Rs.5345
E)Rs.5395
Rationale: Let the sum lent by Manoj to Ramu be Rs.P.
Amount gained by Manoj = P. 3.9 /100 = 3450.3.6/100 = Rs.824.85
27P = 62100 = 82485
P = (82485 + 62100)/27 = 3055 + 2300 = Rs.5355
Option B
Answer: B
Question: The average age of a group of person going for picnic is 16 years. Twenty new persons with an average age of 15 years join the group on the spot due to which their average becomes 15.5 years. Find the number of persons initially going for picnic.
Options:
A)20
B)18
C)22
D)19
E)None of the above
Rationale: Let the number of persons, initially going for Picnic = x
∴ Sum of their ages = 16x
Also, 16x+15×20/x+20 = 15.5
⇒ 0.5x = 10 ⇒ x = 20 years.
Answer A
Answer: A
Question: I spend 40 hours a week (5 days) at work and like to organize my time so that I spend an equal number of hours on the two tasks I currently have. Currently, I am spending 5 hours a day on Task 1 and 3 on Task 2. How many hours a week less do I need to spend on Task 1 in order to evenly distribute my time?
Options:
A)5
B)3
C)7
D)1
E)6
Rationale: 5 x 5 = 25
25 - 5 = 20
The answer is A.
Answer: A
Question: The total of the ages of Mahesh, Suresh, Ramesh is 129 years. Ten years ago, the ratio of their ages was 2:3:4. What is the present age of Mahesh?
Options:
A)32years
B)54years
C)42years
D)35years
E)30years
Rationale: Let ages of Mahesh, Suresh, Ramesh 10years ago be 2x,3x,4x
2x+10 + 3x+10 +4x+10 = 129
x = 11
Ramesh present age = 4*11+10 = 54 years
Answer is B
Answer: B
Question: If the radius of a cylinder is doubled and height 5 times, what is the new volume of the cylinder divided by the old one?
Options:
A)8.
B)2.
C)6.
D)20.
E)10.
Rationale: let v and v' be the original and the changed volume
now
v=pir^2h
v'=pi(2r)^2(5h)
v'=20v
D) 20
Answer: D
Question: The price of a T.V. set worth Rs. 40000 is to be paid in 20 installments of Rs. 1000 each. If the rate of interest be 6% per annum, and the first installment be paid at the time of purchase, then the value of the last installment covering the interest as well will be?
Options:
A)22678
B)26699
C)26788
D)19000
E)39000
Rationale: Money paid in cash = Rs. 1000
Balance payment = (40000 - 1000) = Rs. 39000
Answer: E
Answer: E
Question: How many four-digit numbers are there such that all four digits are different and the first digit is not zero?
Options:
A)1504
B)2648
C)3720
D)5832
E)8105
Rationale: All four digits are different and first digit is not zero.
So first digit can be filled in 9 ways.
And, second digit can be filled in 9 ways.
And, third digit can be filled in 9 ways.
And, fourth digit can be filled in 8 ways.
Total ways = 9*9*9*8
= 5832
Hence option (D).
Answer: D
Question: The radius of a wheel is 16.8 cm. What is the distance covered by the wheel in making 300 resolutions?
Options:
A)754 m
B)316.512 m
C)311.512 m
D)311.518 m
E)313.512 m
Rationale: In one resolution, the distance covered by the wheel is its own circumference. Distance covered in 300 resolutions.
= 300* 2 * 22/7 * 16.8 = 31651.2 cm
= 316.512 m
Answer:B
Answer: B
Question: A train speeds past a pole in 15 seconds and a platform 120 meters long in 25 seconds. What is the length of the train (in meters)?
Options:
A)100 m
B)140 m
C)130 m
D)180 m
E)170 m
Rationale: Let the length of the train be x meters.
The speed of the train is x / 15.
Then, x + 120 = 25*(x / 15)
10x = 1800
x = 180 meters
The answer is D.
Answer: D
Question: A can be divided by 11 with no remainder. Which of the following expressions could be divided by 11 leaving a remainder of 1?
Options:
A)A-20
B)A-12
C)A-9
D)A-10
E)A-13
Rationale: since A is a multiple of 11, we could very well say A = 11K (where K is 1,2...n).
The condition here should now be
11K + 1 = <operation> such that it gives us an integer
11k +1 = A -20 => A = 11K + 21 Not divisible by 11
11K +1 = A -12 => A = 11K + 31 Not Divisible by 11
11K +1 = A -9 => A = 11K + 10 Not Divisible by 11
11K +1 = A -10 => A = 11K + 11 Divisible by 11
11K +1 = A -13 => A = 11K + 14 Not Divisible by 11
Answer therefore is A -10
ANSWER:D
Answer: D
Question: On a certain day, orangeade was made by mixing a certain amount of orange juice with an equal amount of water. On the next day, orangeade was made by mixing the same amount of orange juice with twice the amount of water. On both days, all the orangeade that was made was sold. If the revenue from selling the orangeade was the same for both days and if the orangeade was sold at $0.40 per glass on the first day, what was the price per glass on the second day?
Options:
A)$0.15
B)$0.26
C)$0.30
D)$0.40
E)$0.45
Rationale: On the first day 1 unit of orange juice and 1 unit of water was used to make 2 units of orangeade;
On the second day 1 unit of orange juice and 2 units of water was used to make 3 units of orangeade;
So, the ratio of the amount of orangeade made on the first day to the amount of orangeade made on the second day is 2 to 3. Naturally the ratio of the # of glasses of orangeade made on the first day to the # of glasses of orangeade made on the second day is 2 to 3.
We are told thatthe revenue from selling the orangeade was the same for both daysso the revenue from 2 glasses on the first day equals to the revenue from 3 glasses on the second day.
Say the price of the glass of the orangeade on the second day was $x then 2*0.4=3*x --> x=$0.26.
Answer: B.
Answer: B
Question: Here is an ancient problem from Bhaskaracharya's Lilavati:
A beautiful maiden, with beaming eyes, asks me which is the number that. multipied by 3 then increased by thre-fourths of the product. divided by 7 diminished by 52, the square root found,addition of 8, division by 10 gives the number 2?
Well, it sounds complicated, doesn't it? No, not if you know how to go about it.
Options:
A)16
B)22
C)28
D)29
E)34
Rationale: C
28
The method of working out this problem is to reverse the whole process--multiplying 2 by 10, deducting 8,squaring the result and so on.
Answer: C
Question: The banker's gain on a sum due 6 years hence at 12% per annum is Rs. 612. What is the banker's discount?
Options:
A)1240
B)1120
C)1190
D)1462
E)None of these
Rationale: Explanation :
TD = (BG ×100)/TR = (612×100)/(6×12) = Rs. 850
BG = BD – TD
=> 612 = BD - 850
=> BD = 612 + 850 = 1462 Answer : Option D
Answer: D
Question: Two employees X and Y are paid a total of Rs. 500 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?
Options:
A)s.227
B)s.287
C)s.297
D)s.300
E)s.380
Rationale: Let the amount paid to X per week = x
and the amount paid to Y per week = y
Then x + y = 500
But x = 120% of y = 120y/100 = 12y/10
∴12y/10 + y = 500
⇒ y[12/10 + 1] = 500
⇒ 22y/10 = 500
⇒ 22y = 5000
⇒ y = 5000/22 = Rs.227.77
A)
Answer: A
Question: 800 is increased by 110%. Find the final number.
Options:
A)1200
B)1210
C)1180
D)1190
E)1680
Rationale: ExplanationFinal number = Initial number + 110%(original number) = 800+ 110%(800) = 800 + 880= 1680.Answer E
Answer: E
Question: What is the sixth digit to the right of the decimal point, in the decimal expansion of (3/10)^6?
Options:
A)	7
B)	9
C)	3
D)	6
E)	5
Rationale: Step 1 Convert fraction to decimal with two decimal places 3/10 = 0.30 then convert to scientific number = 3*10^-1
Step 2 Multiply 3^6 by 10^-6
Step 3 3 has the sequence 3, 9, 27
Answer is B
Answer: B
Question: If Rs.7500 are borrowed at C.I at the rate of 4% per annum, then after 2 years the amount to be paid is?
Options:
A)2288
B)2778
C)8297
D)8112
E)3241
Rationale: A = 7500(26/25)2 = 8112.Answer: D
Answer: D
Question: A can do a work in 15 days and B in 20 days. If they work on it together, then the number of days the whole work can be finished is:
Options:
A)7/40
B)7/60
C)40/7
D)60/7
E)50/7
Rationale: A's 1 day's work =1/15
B's 1 day's work =1/20
(A + B)'s 1 day's work =(1/15+1/20)=7/60
the whole work can be finished in 60/7days. Answer: D
Answer: D
Question: P, Q and R have $9000 among themselves. R has two-thirds of the total amount with P and Q. Find the amount with R?
Options:
A)2400
B)3600
C)3998
D)2539
E)1930
Rationale: B
3600
Let the amount with R be $ r
r = 2/3 (total amount with P and Q)
r = 2/3(9000 - r) => 3r = 18000 - 2r
=> 5r = 18000 => r = 3600.
Answer: B
Question: Ten participants are participating in a competition. In how many ways can the first three prizes be won?
Options:
A)920
B)680
C)820
D)720
E)620
Rationale: Out of 10 participants, the first three prizes can be won in,
10P3 = 10! / (10 - 3)!
= 10 x 9 x 8
= 720 ways
ANSWER:D
Answer: D
Question: Awordis defined as a sequence of three dots arranged in a row. Each dot is colored one of the three colours. How many distinct words can be formed?
Options:
A)23
B)25
C)26
D)28
E)27
Rationale: Each dot can be either one of the three, so 2 options for each dot: 3*3*3 = 27.
Answer: D.
Answer: D
Question: Amy's sells kale at x dollar per pound for the first 20 pounds and .8x for every subsequent pound. Lucia's price is x per pound for the first 14 pounds and .9x for subsequent pounds. What is the minimum number of pounds over 20 for which Amy's becomes an equal or better deal?
Options:
A)26
B)25
C)24
D)27
E)28
Rationale: For Amy's deal to be better, the cost has to be less or equal to Lucia's
Assuming 'n' is the number of pounds of kale, the equation is
20x + (n-20) (0.8x) <= 14x + (n-14)(0.9x)
Resolve it:
==> 20x + 0.8nx - 16x <= 14x + 0.9nx - 12.6x
==> 2.6x <=0.1nx
==> 26x < =nx
==> x (n-26) > = 0
as x cannot be 0,
==> n - 26 >=0
==> n > = 26
so the minimum value is 26
'A' would be the correct answer
Answer: A
Question: Country C imposes a two-tiered tax on imported cars: the first tier imposes a tax of 12% of the car's price up to a certain price level. If the car's price is higher than the first tier's level, the tax on the portion of the price that exceeds this value is 8%. If Ron imported a $14,000 imported car and ended up paying $1440 in taxes, what is the first tier's price level?
Options:
A)$1600
B)$6000
C)$6050
D)$7050
E)$8000
Rationale: Let T be the tier price, P be total price = 14000
Per the given conditions:
0.12T + 0.08(P-T) = 1440 ----> T= 8000. E is the correct answer.
Answer: E
Question: A circle circumscribes three unit circles that touch each other. What is the area of the larger circle? Note that p is the ratio of the circumference to the diameter of a circle ( 3.14159265).
Options:
A)3.14×(7+43–√3/9)
B)3.14×(7+43–√3/7)
C)3.14×(7+43–√3/6)
D)3.14×(7+43–√3/3)
E)3.14×(7+43–√3/1)
Rationale: By joining centers of 3 unit circles we will get an equilateral triangle of length 2 unit. We have to find the length of the orange line.
And center of the equilateral triangle will be the center of the big circle.
So radius of the big circle will be = (1 + Circum radius of the equilateral triagle)
Formula for Circul radius of the equilateral triangle = 23×(3–√2a)23×(32a) here 3–√2a32a is the height of the triangle. a is the side of the triangle
Circum radius of equilateral triangle = 23×3–√2×2=23–√23×32×2=23
Area of big circle will be =πr2=3.14×(1+23–√)2πr2=3.14×(1+23)2 = 3.14×(1+43–√+43)3.14×(1+43+43)
=3.14×(1+43–√+43)=3.14×(1+43+43) = 3.14×(73+43–√)3.14×(73+43)
=3.14×(7+43–√3/3)
Answer:D
Answer: D
Question: Assume all CDs are equal in time.
If 21 CDs have X hours of music, how many minutes will Y CDs have?
Options:
A)21XY/60
B)7/60XY
C)21/60XY
D)20XY/7
E)7/20XY
Rationale: 21 CDs have X hours or 60*X minutes
1 CD has time = 60*X/21 = 20X/7
Y CD time in minutes = Y*20*X/7 = 20XY/7
Hence, the answer is D.
Answer: D
Question: a survey of n people in the town of badaville found that 50% of them prefer brand A.another survey of 100 people in the town of Chotaville found that 60% prefer brand A.In total 55% of all the people surveyed prefer brand A.What is the total number of people surveyed?
Options:
A)180
B)200
C)220
D)240
E)260
Rationale: badavilla=50% from 100
chotavilla=60% from 100
total=110 from 200
55% of 200 is also 110
so total number of survey is 200
ANSWER:B
Answer: B
Question: Which of the following is closest in value to (9^12)-(9^2)?
Options:
A)9^9
B)9^8
C)9^7
D)9^12
E)9^5
Rationale: 9^12 is much larger number than 9^2 and as we need approximate value then it's pretty much negligible in this case, so: (9^12)-(9^2) = ~9^9.
Answer: D.
Similar questions to practice:
Hope it helps.
Answer: D
Question: A company pays 12.5% dividend to its investors. If an investor buys Rs.60 shares and gets 25% on investment, at what price did the investor buy the shares?
Options:
A)25
B)66
C)30
D)19
E)01
Rationale: Explanation:
Dividend on 1 share = (12.5 * 60)/100 = Rs.7.5
Rs.25 is income on an investment of Rs.100
Rs.7.5 is income on an investment of Rs. (7.5 * 100)/25 = Rs.30
ANSWER: C
Answer: C
Question: A train passes a platform in 36 seconds. The same train passes a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, The length of the platform is
Options:
A)280 meter
B)240 meter
C)200 meter
D)260 meter
E)None of these
Rationale: Explanation:
Speed of the train = 54 km/hr = (54×10)/36 m/s = 15 m/s
Length of the train = speed × time taken to cross the man = 15×20 = 300 m
Let the length of the platform = L
Time taken to cross the platform = (300+L)/15
=> (300+L)/15 = 36
=> 300+L = 15×36 = 540
=> L = 540-300 = 240 meter
Answer: Option B
Answer: B
Question: Can you find the missing number in the sequence given below?
11 15 19 12 16 ? 13 17 21 14 18 22
Options:
A)20
B)21
C)22
D)23
E)24
Rationale: Solution:
20
Explanation :
The sequence is given in the puzzle is :
11 15 19 12 16 ? 13 17 21 14 18 22
Let's break the given series as below:
11 15 19
12 16 ?
13 17 21
14 18 22
Now read the number from left hand side from top to bottom as :
So the number that will replace '?' is 20.
Answer A
Answer: A
Question: If a population of women in a town is 50% of men . What is the population of men as a % of population of women ?
Options:
A)200%
B)100%
C)50%
D)65%
E)110%
Rationale: We're told that the number of Women in a town is equal to 50% of the number of Men in that town.
IF....
Men = 10
Women = 5
We're asked for the number of Men, as a percentage of the number of Women.
M/W = 10/5 = 2 = 200%
Answer is A
Answer: A
Question: A pipe X is 30 meters and 45% longer than another pipe Y. find the length of the pipe Y.
Options:
A)20.12
B)20.68
C)20
D)20.5
E)None of these
Rationale: Explanation :
Length of pipe X = 30 meter
Given that pipe X is 45% longer than Y
Let the length of pipe Y = y
Then, Length of pipe X =y×(100+45)/100
⇒ 30 = y × (145/100) => y = 30×100/145=6×100/29=600/29=20.68
Answer : Option B
Answer: B
Question: The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:
Options:
A)4.5%
B)4%
C)5%
D)6%
E)5.5%
Rationale: Increase in 10 years = (262500 - 175000) = 87500.
Increase% =(87500/175000)x 100% = 50%.
Required average =50/10% = 5%.
Answer:C
Answer: C
Question: If population of certain city increases at the rate of 5%. If population in 1981 was 324135, then population in 1978 was?
Options:
A)120000
B)120029
C)187899
D)178968
E)280000
Rationale: X * (105/100) * (105/100) * (105/100) = 324185
X = 324185/1.157625
X = 280000
Answer:E
Answer: E
Question: The sum of the non-prime numbers between 30 and 40, non-inclusive, is
Options:
A)202
B)217
C)232
D)247
E)262
Rationale: sum of consecutive integers from 31 to 39, inclusive ====> (A1 + An)/2 * # of terms = (31 + 39)/2 * 9 = 35 *9 = 315
sum of non-prime numbers b/w 30 and 40, non inclusive ===> 315 - 68 (i.e., 31 + 37, being the prime #s in the range) =247
Answer: D
Answer: D
Question: How many digits will be there to the right of the decimal point in the product of 89.635 and .02218?
Options:
A)5
B)6
C)7
D)8
E)9
Rationale: Explanation :
Sum of decimal places = 3 + 5 = 8
The last digit to the extreme right is zero (Since 5 x 8 = 40)
Hence, there will be 7 significant digits to the right of the decimal point. Answer : Option C
Answer: C
Question: A dishonest grocer professes to sell pure butter at cost price, but he mixes it with adulterated fat and thereby gains 45%. Find the percentage of adulterated fat in the mixture assuming that adulterated fat is freely available?
Options:
A)20%
B)25%
C)33.33%
D)40%
E)35%
Rationale: Say 100g pure butter costs $100
But; $100 is his 25% profit because he just used 80gram pure butter.
80g would have costed him $80 and he sold it for $100 by adding 20g of freely available fat. $100 is 1.45(65)
so;
total weight=100g
fat=35g
35%
E
Answer: E
Question: John bought 9.25m of cloth for $434.75. Find the cost price per metre.
Options:
A)46
B)47
C)58
D)56
E)54
Rationale: Cloth bought by John = 9.25 m
Cost of 9.25 m = $434.75
Cost per metre = 434.75 ÷ 9.25
The cost of the cloth per metre = $ 47
Answers: B
Answer: B
Question: Two MBA admissions committees are to be formed randomly from 6 second year MBAs with 3 members each. What is the probability V that Jane will be on the same committee as Albert?
Options:
A) 12%
B) 20%
C) 33%
D) 40%
E) 50%
Rationale: Total number of ways to choose 3 member committee - 6C3=(6!/3!3!)=20
No. of ways Albert n Jane are in same committee:- (4C1 * 2)= 8
Probability V= (8/20) *100 =40%.
+1 for me.. :D
Answer: D
Question: All the water in container A which was filled to its brim was poured into two containers B and C. The quantity of water in container B was 62.5% less than the capacity of container A. If 152 liters was now transferred from C to B, then both the containers would have equal quantities of water. What was the initial quantity of water in container A?
Options:
A)1289
B)1198
C)281
D)1216
E)282
Rationale: Explanation:
B has 62.5% or (5/8) of the water in A. Therefore, let the quantity of water in container A(initially) be 8k.
Quantity of water in B = 8k - 5k = 3k.
Quantity of water in container C = 8k - 3k = 5k
Container: A B C
Quantity of water: 8k 3k 5k
It is given that if 152 liters was transferred from container C to container B, then both the containers would have equal quantities of water.
5k - 152 = 3k + 152 => 2k = 304 => k = 152
The initial quantity of water in A = 8k = 8 * 152 = 1216 liters.
Answer: Option D
Answer: D
Question: Evaluate: 17 + sqrt(- 7 + 10Ã—6Ã·5) =?
Options:
A)40
B)42
C)44
D)46
E)48
Rationale: According to order of operations, inner brackets first where 10x6Ã·5 is first calculated since it has a multiplication and a division.
10x6Ã·5 = 60Ã·5 = 12
Hence
17 + sqrt(- 7 + 10Ã—6Ã·5) = 17+ sqrt(-7+ 12)
= 17 + sqrt(5) = 17 + 25 = 42
correct answer B)42
Answer: B
Question: A starts a business with Rs.40,000. After 2 months, B joined him with Rs.60,000. C joined them after some more time with Rs.1,20,000. At the end of the year, out of a total profit of Rs.3,75,000, C gets Rs.1,50,000 as his share. How many months after B joined the business, did C join?
Options:
A)4 months
B)5 months
C)6 months
D)7 months
E)8 months
Rationale: Explanation:
Assume that C was there in the business for x months
A:B:C
=40000×12:60000×10:120000 × x
=40×12:60×10:120x
=40:5×10:10 x
=8:10:2x
=4:5:x
C's share =375000 x/ 9+x=375000 x/9+x
⇒375000 x/9+x=150000
⇒375x9+x=150
⇒15x=6(9+x)
⇒5x=18+2x
⇒3x=18
⇒x=6
It means C was there in the business for 6 months. Given that B joined the business after 2 months. Hence C joined 4 months after B joined.
Answer: Option A
Answer: A
Question: If air is called green , green is called blue, blue is called sky, sky is called yellow, yellow is called water and water is called pink, then what is the color of clear sky ?
Options:
A)Blue
B)Sky
C)Water
D)Yellow
E)Black
Rationale: Explanation:
The colour of clear sky is 'blue' and as given, 'blue' is called 'sky'.
So, the colour of clear sky is 'sky'.
Answer: B
Answer: B
Question: A 25% stock yielding 20% is quoted at:
Options:
A)s. 83.33
B)s. 110
C)s. 112
D)s. 125
E)s. 140
Rationale: Income of Rs 20 on investment of Rs 100
Income of Rs 25 on investment of ?
= (25*100)/20=125
ANSWER:D
Answer: D
Question: If a, b, and c are consecutive positive integers and a < b < c, which of the following must be true?
I. c - a = 2
II. abc is an even integer.
III. (a + b + c)/3 is an decimal.
Options:
A) I only
B) II only
C) I and II only
D) II and III only
E) I, II, and III
Rationale: Since a, b, and c are consecutive positive integers and a < b < c, then c = a + 2, from which it follows that c - a = 2. So, I is true.
Next, out of 3 consecutive integers at least 1 must be even, thus abc=even. II is true.
Finally, since b = a + 1, and c = a + 2, then (a + b + c)/3 = (a + a + 1 + a + 2)/3 = a + 1 = integer. III is false.
Answer: C
Answer: C
Question: A table is bought for Rs.200/- and sold at Rs.150/- find gain or loss percentage
Options:
A)15% loss
B)20% loss
C)25% loss
D)30% loss
E)None
Rationale: Formula = (Selling price ~ Cost price)/Cost price * 100
= (150 - 200)/200 = 25% loss
C
Answer: C
Question: In Plutarch Enterprises, 60% of the employees are marketers, 30% are engineers, and the rest are managers. Marketers make an average salary of $50,000 a year, and engineers make an average of $80,000. What is the average salary for managers if the average for all employees is also $80,000?
Options:
A)$80,000
B)$130,000
C)$260,000
D)$290,000
E)$320,000
Rationale: For sake of ease, let's say there are 10 employees:6 marketers, 3 engineers, and 1 manager.
Average company salary * Number of employees = Total company salary
>>> $80,000 * 10 = $800,000
Subtract the combined salaries for the marketers (6 * $50,000) and the engineers (3 * $80,000)
>>> $800,000 - $300,000 - $240,000 = $260,000.
The correct answer is C.
Answer: C
Question: What will come in place of the x in the following Number series? 18, X, 30, 46 ,78, 142
Options:
A)35
B)56
C)22
D)87
E)98
Rationale: (C)
The pattern is +4, +8, +16, +32, +64
So the missing term is = 22.
Answer: C
Question: Three pipes, A, B, & C are attached to a tank. A & B can fill it in 20 & 30 minutes respectively while C can empty it in 15 minutes. If A, B & C are kept open successively for 1 minute each, how soon will the tank be filled?
Options:
A)2 hours
B)4 hours
C)3 hours
D)5 hours
E)6 hours
Rationale: in three minute 1/20+1/30-1/15=1/60 part is filled
3 min--------1/60 parts
x min--------- 1 part(full)
x=180 min =3 hours
ANSWER:C
Answer: C