divelab/Sys2Bench huggingface dataset:
Question: What percent is 100 gm of 1 kg?
Options:
A)25%
B)40%
C)10%
D)8%
E)12%
Rationale: 1 kg = 1000 gm
100/1000 × 100 = 10000/1000
=10 %
Answer is C
Answer: C
Question: If a man lost 4% by selling oranges at the rate of 12 a rupee at how many a rupee must he sell them to gain 44%?
Options:
A)9
B)8
C)7
D)5
E)2
Rationale: 96% ---- 12
144% ---- ?
96/144 * 12 = 8
Answer: B
Answer: B
Question: A certain car dealership sells economy cars, luxury cars, and sport utility vehicles. The ratio of economy to luxury cars is 3:1. The ratio of economy cars to sport utility vehicles is 4:3. What is the ratio of luxury cars to sport utility vehicles?
Options:
A)9:8
B)4:9
C)3:2
D)2:3
E)1:2
Rationale: The ratio of economy to luxury cars is 3:1 --> E:L = 3:1 = 12:4.
The ratio of economy cars to sport utility vehicles is 4:3 --> E:S = 4:3 = 12:9.
Thus, L:S = 4:9.
Answer: B.
Answer: B
Question: When 1/10 percent of 4,000 is subtracted from 1/10 of 4,000, the difference is
Options:
A) 0
B) 50
C) 396
D) 495
E) 500
Rationale: We can break this problem into two parts:
1) What is 1/10 percent of 4,000?
2) What is 1/10 of 4,000?
To calculate 1/10 percent of 4,000 we must first remember to DIVIDE 1/10 BY 100.
So we have: (1/10)/(100)
To divide a number by 100 means to multiply it by 1/100, so we have:
1/10 x 1/100 = 1/1,000
Thus, 1/10 percent of 4,000 = 1/1,000 x 4,000 = 4.
Now let's concentrate on part 2. We need to calculate 1/10 of 4,000. To do this we simply multiply 1/10 by 4,000.
1/10 x 4,000 = 400
The answer to part 1 is 4, and the answer to part 2 is 400. Their difference is 400 – 4= 396.
Answer C.
Answer: C
Question: There are a cities. What is the number of airlines that connected 2 different cities (airline from city A to city B is different with airline from city B to city A)?
Options:
A)n(n-1)
B)n(n+1)
C)a(a-1)
D)n(n+1)/2
E)n2
Rationale: First of all, the possible number of airlines is a. Then, the possible number of airlines departing from one city to another becomes (a-1). Hence, the answer is a(a-1), which makes C
Answer: C
Question: A man rows his boat 110 km downstream and 90 km upstream, taking 3 hours each time. Find the speed of the stream?
Options:
A)6
B)5
C)7.5
D)3.5
E)2.5
Rationale: Speed downstream = d/t = 110/(3) = 37 kmph
Speed upstream = d/t = 90/(3) = 30 kmph
The speed of the stream = (37 - 30)/2 = 3.5 kmph
Answer:D
Answer: D
Question: On a game show, a contestant spins four different wheels; each wheel is numbered 1 to 3. What is the probability that the contestant will spin all tens?
Options:
A)87
B)28
C)1/81
D)693
E)8/27
Rationale: All 3s:
1st wheel = 3 = 1/3
2nd wheel = 3 = 1/3
3rd wheel = 3 = 1/3
4th wheel = 3 = 1/3
(1/3)(1/3)(1/3)(1/3) = 1/81
Answer: C
Answer: C
Question: A merchant has 100 lbs of sugar, part of which he sells at 5% profit and the rest at 17% profit. He gains 10 % on the whole. Find how much is sold at 5% profit?
Options:
A)70 lbs
B)40 lbs
C)30 lbs
D)58 lbs
E)60 lbs
Rationale: These types ofweighted averagequestions can be solved in a variety of ways, so you can choose whichever method you find easiest/fastest. Here's another variation on the Weighted Average Formula:
A = # of pounds sold at 5% profit
B = # of pounds sold at 17% profit
A+B = 100 pounds
(.05A + .17B)/(A+B) = .10
.05A + .17B = .1A + .1B
.07B = .05A
7B = 5A
7/5 = A/B
So, for every 7 pounds of A, we have 5 pounds of B.
With 100 pounds total, we have 58 pounds of A and 42 pounds of B.
Option D
Answer: D
Question: If Bill can buy 3 pairs of jeans and 2 shirts for $69 or 2 pairs of jeans and 3 shirts for $66, how much does one shirt cost?
Options:
A)$10
B)$12
C)$13.20
D)$15
E)$16.80
Rationale: Let the price of one shirt be ss and of jeans be j:
3j+2s=69
2j+3s=66
Subtracting the second from the first gives: j−s=3or j=s+3 Plug j in either of the equations and solve for s, which is $12
Answer: B	.
Answer: B
Question: A new savings account offers 4 percent annual interest compounded every 6 months. What would be the total balance in an account after 1 year, if the initial amount in the account were $6000?
Options:
A)$80.00
B)$84.40
C)$360.00
D)$6,242.40
E)$6,365.40
Rationale: The interest is compounded every 6 months. To calculate interest, you must take the principal and multiply it by the interest and the length of time (using the unit used in the interest, typically years). At the end of the first 6 months the interest earned is $6,000(.04) (1/2) = $120. (Note: the 6 months are “1/2” in the equation since 4% is a yearly rate, not a bi-yearly one).
Since the interest is compounded, the second six months of the year are not earning interest on just the original $6,000, but on the interest as well, so they are actually earning interest on $6,120. The interest earned during the final 6 months of the year is $6,120(.04)(1/2) = $122.4. Therefore, the total balance is the original amount ($6000) + $120 + $122.40 = $6,242.40.
The correct answer is D.
Answer: D
Question: A cricket player whose bowling average was 20.5 runs per wicket, takes 5 wicket for 52 runs in a match. Due to this his average decreases by 0.5. What will be the number of wickets taken by him till the last match?
Options:
A)64
B)72
C)101
D)111
E)128
Rationale: Average = Total Runs / Total wickets
Total runs after last match = 20.5w + 52
Total wickets after last match = w + 5
(20.5w + 52) / (w + 5) = 20.5 - 0.5 = 20
w = 96
so total wickets aftr last match = w+5 = 101
ANSWER:C
Answer: C
Question: A work can be finished in 30 days by twenty women. The same work can be finished in fifteen days by 10 men. The ratio between the capacity of a man and a woman is
Options:
A)1:3
B)4:1
C)2:3
D)2:1
E)2:4
Rationale: Work done by 20 women in 1 day = 1/30
Work done by 1 woman in 1 day = 1/(30×20)
Work done by 10 men in 1 day = 1/15
Work done by 1 man in 1 day = 1/(15×10)
Ratio of the capacity of a man and woman =1/(15×10) : 1/(30×20) = 1/150 : 1/600
= 1/1 :1/4 = 4:1
Option B
Answer: B
Question: The length of the bridge, which a train 500 metres long and travelling at 42 km/hr can cross in 60 seconds, is?
Options:
A)100 m
B)200 m
C)300 m
D)250 m
E)350 m
Rationale: Speed = [42 X 5/18] m/sec = [35/3]m/sec
Time = 30 sec Let the length of bridge be x metres. Then, (130 + x)/60
35/3 = (130 + x)/60
500+x=700
=>x=200 m
Answer:B
Answer: B
Question: There are five people who can build five houses in just five days. Increase the amount of people to 100. How long would it take these 100 people to build 100 houses?
Options:
A)2 days
B)3 days
C)4 days
D)5 days
E)1 days
Rationale: It will take 5 days for 100 people to build 100 houses.
1 person can build 1 house in 5 days. So, 100 people can build 100 houses in 5 days.
Answer D
Answer: D
Question: In the arithmetic sequence t1, t2, t3, ..., tn, t1=23 and tn= tn-1 - 3 for each n > 1. What is the value of n when tn = -7?
Options:
A)-1
B)7
C)10
D)11
E)20
Rationale: We know that t1 = 23
So, using the given formula we have:
t1=(t1-1) -3 =23
t0 - 3 = 23
t0= 26
The same way we find that t2= 20
It seems that the sequence goes like this:
t0 = 26
t1 = 23
t2 = 20
t3 = 17
t4 = 14
t5 = 11
t6 = 8
t7 = 5
t8 = 2
t9 = -1
t10 = -4
t11 = -7
So, ourANS is D.
Answer: D
Question: The annual budget of a certain college is to be shown on a circle graph. If the size of each sector of the graph is to be proportional to the amount of the budget it represents, how many degrees of the circle should be used to represent an item that is 25 percent of the budget?
Options:
A) 15 °
B) 36 °
C) 54 °
D) 90 °
E) 150 °
Rationale: 100 percent = 360 degrees
25 percent = 360*25/100 = 90 degrees
Answer is D.
Answer: D
Question: The dimensions of a room are 25 feet * 15 feet * 12 feet. What is the cost of white washing the four walls of the room at Rs. 5 per square feet if there is one door of dimensions 6 feet * 3 feet and three windows of dimensions 4 feet * 3 feet each?
Options:
A)8939
B)8383
C)8389
D)4530
E)9392
Rationale: Explanation:
Area of the four walls = 2h(l + b)
Since there are doors and windows, area of the walls = 2 * 12 (15 + 25) - (6 * 3) - 3(4 * 3) = 906 sq.ft.
Total cost = 906 * 5 = Rs. 4530
Answer: Option D
Answer: D
Question: A small company reduced its faculty by approximately 15 percent to 195 employees. What was the original number of employees?
Options:
A)A)182
B)B)208
C)C)220
D)D)229
E)E)302
Rationale: If x is the original number of employees, then after 15% reduction in employees number is .85x
but we are given .85x = 195
x = 229
So the original number of employees is 229
Correct Answer - D
Answer: D
Question: A vendor buys 10 t-shirts at an average price of $14 per t-shirt. He then buys 15 more t-shirts at an average price of $11 per t-shirt. What is the average price Q per t-shirt that the vendor paid for these purchases?
Options:
A)$12.20
B)$12.50
C)$12.55
D)$12.70
E)$13.00
Rationale: Correct Answer: A
Explanation: The relevant formula for this problem is Average Q= (Sum)/(Number of Terms). Another way to look at the formula is Sum = Average x Number of Terms. For the first purchase, the vendor's sum (total cost) was $140, since 14 x 10 = 140. For the second purchase, the vendor's cost was $165, since 11 x 15 = 165. The grand sum is then $140 + $165, which equals $305. The total number of shirts purchased was 25, so to get the average price per shirt, we divide 305 by 25, which equals $12.20. As a result, the correct answer is A.
NOTE: A relative understanding of weighted average offers a shortcut to this problem. Because the true average of 11 and 14 is 12.5, but the vendor sells more shirts at the lower price than at the higher price, the weighted average must be less than $12.50; only answer choice A is a possibility.
Answer: A
Question: A grocer buys apples for 65¢ per pound. If 10% of the apples goes bad and he still wants to make a 20% profit over his purchase price, what should be the sales price?
Options:
A)90.50¢
B)70.70¢
C)80.00¢
D)95.00¢
E)86.67¢
Rationale: for making calculation simple let us consider he buys 10pounds @ 65/pound=650¢ in total .
10% apples lost...means 9 pounds left.
further he wants 20% profit on 650 ¢
means he wants to earn 780¢
sales price should be 780/9==¢ 86.67
Ans E
Answer: E
Question: Two men A and B start from place X walking at 4 ½ kmph and 5 ¾ kmph respectively. How many km apart they are at the end of 4 ½ hours if they are walking in the same direction?
Options:
A)7 km
B)6 km
C)5 5/8 km
D)9 km
E)5 km
Rationale: RS = 5 ¾ - 4 ½ = 1 ¼
T = 4 ½ h.
D = 5/4 * 9/2 = 45/8
= 5 5/8 km
Answer:C
Answer: C
Question: How many prime numbers between 100 to 150?
Options:
A)11
B)10
C)13
D)12
E)15
Rationale: primes are of the form 6n+1 or 6n-1
Put n=17
6n+1=6*17+1=103
for n=17
6n-1=6*17-1=101
for n=18 , ==>107 and 109
for n=19 , ==> 113
for n =20 ==> no prime no.
for n =21 ==> 127
for n =22 ==> 131
for n=23 ==> 137 AND 139
for n =24 ==> no prime number
for n= 25 ==> 149
therefore total number of prime numbers = 10
Ans - B
Answer: B
Question: If 1 > 1 - ab > 0, which of the following must be true?
I. a/b > 0
I. ab < 1
III. a/b < 1
Options:
A)I only
B)II only
C)III only
D)I and II only
E)I and III only
Rationale: MANHATTAN GMATOFFICIAL SOLUTION:
You can manipulate the original compound inequality as follows, making sure to perform each manipulation on every term:
1 > 1 - ab > 0
0 > -a b > -1 Subtract 1 from all three terms.
0 < ab < 1 Multiply all three terms by -1 and flip the inequality signs.
Therefore you know that 0 < ab < 1. This tells you that ab is positive, so a/b must be positive (a and b have the same sign). Therefore, I must be true. However, you do not know whether a/b < 1, so II is not necessarily true. But you do know that ab must be less than 1, so III must be true.
Therefore, the correct answer is (D).
Answer: D
Question: A and B start a business with Rs.6000 and Rs.8000 respectively. Hoe should they share their profits at the end of one year?
Options:
A)3:4
B)3:2
C)3:9
D)3:8
E)3:1
Rationale: They should share the profits in the ratio of their investments.
The ratio of the investments made by A and B =
6000 : 8000 => 3:4
Answer: B
Answer: B
Question: A 150 m long train crosses a platform in 39 sec while it crosses a signal pole in 18 sec. What is the length of the platform?
Options:
A)300
B)175
C)360
D)370
E)380
Rationale: Speed = 150/18 = 25/3 m/sec.
Let the length of the platform be x meters.
Then, (x + 150)/39 = 25/3
=> x = 325 m.
L=325-150 =175 m
Answer: Option B
Answer: B
Question: A book is bought for $60 and sold for $75. What is the profit in percentage?
Options:
A)12
B)15
C)20
D)25
E)30
Rationale: 75/60 = 1.25
The answer is D.
Answer: D
Question: On one side of a coin there is the number 0 and on the other side the number 1. What is the probability that the sum of three coin tosses will be 2?
Options:
A)1/8.
B)1/2.
C)1/5.
D)3/8.
E)1/3.
Rationale: Assume the coin is unbiased.
Possible sums from 3 tosses = 0,1,2,3
O and 3 are possible in only 1 case each. (0,0,0 or 1,1,1)
1 is possible in 3C1 = 3 cases. (1,0,0; 0,1,0 or 0,0,1) or
similarly, 2 is possible in 3C2=3 cases (1,0,1; 1,1,0; 0,1,1)
So answer will be 3/8. Answer :Option D.
Answer: D
Question: As a bicycle salesperson, Norman earns a fixed salary of $20 per week plus $6 per bicycle for the first six bicycles he sells, $12 per bicycle for the next six bicycles he sells, and $18 per bicycle for every bicycle sold after the first 12. This week, Norman earned more than twice as much as he did last week. If he sold k bicycles last week and y bicycles this week, which of the following statements must be true?
I. y > 2k
II. y > k
III. y > 3
Options:
A)I only
B)II only
C)I and II
D)II and III
E)I, II, and III
Rationale: This is kind of like doing your taxes, lets summarize the data in terms of bike sales and salary -
0 Bikes - $20
6 Bikes - $56
12 Bikes - $128
More than 12 bikes - 128 + 18*(k-12) where k is the total number of bikes sold (when k>12). K = cycles sold last week
KS = Salary last week.
Y = cycles sole this week
YS = Salary this week.
given YS>2KS
lets test all statements with K=0;
KS = 20
YS >40
True when Y = 4
satisfies all the statements but we can only be sure of iii as Y will only increase from here. So iii must be true. Eliminate A,B,C
lets test all statements with K=1;
KS = 26
YS>52
True when Y=6
Still satisfies all the statements - Nothing achieved
lets test all statements with K=6;
KS = 56
YS>112
True when Y = 11
This proves statement i wrong, hence eliminate E so we are left with
Answer D
Answer: D
Question: A company decreased the price of its main product by 20%. Subsequently, the number of units sold increased such that the total revenue remained unchanged. What was the ratio of the percent increase in the units sold to the percent decrease of the original price for this product?
Options:
A)3.0
B)7.0
C)5.0
D)2.0
E)1.0
Rationale: For the total revenue to remain the same when the price is one fifth, the number of products sold must five times. Therefore increase in the number of products sold is 100%
=> The required ratio = 100%/20% = 5.0
Answer : C
Answer: C
Question: In a LAB experiment, a 100 ml compound of element X and element Y needs to be increased to 120 ml by adding some quantity of element X, and some quantity of element Y. If the original compound contains 30% of element X, how much (in ml) of element Y must be added so that element X will be exactly one third of the resulting mixture ?
Options:
A)40 ml
B)100/3 ml
C)20 ml
D)20/3 ml
E)10 ml
Rationale: There are 0.3*100=30 ml of element X in the initial solution.
We need X to be 1/3rd of 120 ml in the resulting solution, so 40 ml. Thus out of 20 ml of solution added, 10 must be X (in order it to become 40 ml) ans the remaining 10 must be Y.
Answer: E
Answer: E
Question: Train A left Centerville Station, heading toward Dale City Station, at 3: 00 p.m. Train B left Dale City Station, heading toward Centerville Station, at 4: 20 p.m. on the same day. The trains rode on straight tracks that were parallel to each other. If Train A traveled at a constant speed of 30 miles per hour and Train B traveled at a constant speed of 10 miles per hour, and the distance between the Centerville Station and Dale City Station is 90 miles, when did the trains pass each other?
Options:
A)4: 45 p.m.
B)5: 00 p.m.
C)6: 20 p.m.
D)5: 35 p.m.
E)6: 00 p.m.
Rationale: the distance travelled by the train A in first 20 minutes will be 10.
The distance which will be remaining is 80.
Now both trains are running in opposite direction.Their speed will be added so 40.
Time at which they will meet =80/40=2
time of train B will be 4:20 +2=6:20
Hence answer is C.Hope i am correct
Answer: C
Question: A computer store offers employees a 30% discount off the retail price. If the store purchased a computer from the manufacturer for $900 dollars and marked up the price 30% to the final retail price, how much would an employee save if he purchased the computer at the employee discount (30% off retail price) as opposed to the final retail price.
Options:
A)352
B)356
C)358
D)362
E)365
Rationale: Cost price=900
Profit=30% =30% of 900=270
selling price=CP+ Profit
SP=1170
a Discount of 30% to employees means 30% off on 1170
so 30% of 1170= 351
Ans A
Answer: A
Question: A certain bridge is 2,024 feet long. Approximately how many minutes does it take to cross this bridge at a constant speed of 10 miles per hour? (1 mile = 5,280 feet)
Options:
A) 1
B) 2
C) 4
D) 6
E) 7
Rationale: Distance: 2024 feet. This is (2024/5280) miles = 0.38 miles
Speed: 10 miles per hour
Time: (Distance / Speed) (0.38/10) {This will come in Hours}. Multiply by 60 to get answer in minutes. It is 2.28 minutes.
Answer to be 2 minutes.
ANS B
Answer: B
Question: By walking at 3/4th of his usual speed, a man reaches office 10 minutes later than usual. What is his usual time?
Options:
A)30min
B)50min
C)65min
D)60min
E)70min
Rationale: let T be the usual time.
time spent=4T/3
therefore, 4T/3=T+10
4T=3T+30...therefor T=30min
ANSWER:A
Answer: A
Question: A can do a piece of work in 6 hours; B and C together can do it in 4 hours, which A and C together can do it in 3 hours. How long will B alone take to do it?
Options:
A)8hours
B)6hours
C)14hours
D)12hours
E)5hours
Rationale: A's 1 hour work = 1/6;
(B + C)'s 1 hour work = 1/4;
(A + C)'s 1 hour work = 1/3
(A + B + C)'s 1 hour work = (1/4 + 1/6) = 5/12
B's 1 hour work = (5/12 - 1/3) = 1/12
B alone will take 12 hours to do the work.
Answer:D
Answer: D
Question: The size of a television screen is given as the length of the screen's diagonal. If the screens were flat, then the area of a square 21-inch screen would be how many square inches greater than the area of a square 17-inch screen?
Options:
A)2
B)4
C)16
D)38
E)76
Rationale: Pythogoras will help here!
let the sides be x and diagonal be d
Then d ^2 = 2x^2
and
Area = x^2
Now plug in the given diagonal values to find x values
and then subtract the areas
Ans will be 21^2/2 - 17^2 /2 = 152 /2 = 76
Ans E.
Answer: E
Question: The speed of a boat in upstream is 40 kmph and the speed of the boat downstream is 70 kmph. Find the speed of the boat in still water and the speed of the stream?
Options:
A)70,10 kmph
B)55,15 kmph
C)70,70 kmph
D)78,10 kmph
E)70,12 kmph
Rationale: Speed of the boat in still water
= (40+70)/2
= 55 kmph. Speed of the stream
= (70-40)/2
= 15 kmph.
Answer:B
Answer: B
Question: Which of the following equations has real roots ?
Options:
A)3x2 + 4x + 5 = 0
B)x2 + x + 4 = 0
C)(x - 1)(2x - 5) = 0
D)2x2 - 3x + 4 = 0
E)None of these
Rationale: Sol.(c) Roots of a quadratic equation
ax2 + bx + c = 0 are real if b2 - 4ac ≥ 0
Let us work with options as follows.
Option (a) : 3x2 + 4x + 5 = 0
b2 - 4ac = 42 - 4(3)(5) = -44 < 0.
Thus, roots are not real.
(b) : x2 + x + 4 = 0
b2 - 4ac = 12 - 4(1)(4) = 1 - 16 = -15 < 0. Thus, roots are not real. (c) :(x –1) (2x – 5) = 0 => 22 - 7x + 5 = 0
b2 - 4ac = (-7)2 - 4(2)(5) = 49 - 40 = 9 > 0.
Thus roots are real.
or x = 1 and x = 5/2 > 0; Thus, equation has real roots.
(d) : 2x2 - 3x + 4 = 0
b2 - 4ac = (-3)2 - 4(2)(4) = 9 - 32 = -23 < 0.
Thus, roots are not real. Hence, option (c) is correct.
Answer C
Answer: C
Question: The length of a rectangular plot is thrice its breadth. If the area of the rectangular plot is 867 sq m, then what is the breadth of the rectangular plot?
Options:
A)12
B)17
C)10
D)12
E)19
Rationale: Let the breadth of the plot be b m.
Length of the plot = 3 b m
(3b)(b) = 867
3b2 = 867
b2 = 289 = 172 (b > 0)
b = 17 m.
Answer:B
Answer: B
Question: If the numerator of a fraction R is tripled, and the denominator of a fraction is doubled, the resulting fraction will reflect an increase of what percent?
Options:
A)16 1⁄6%
B)25%
C)33 1⁄3%
D)50%
E)66 2⁄3%
Rationale: This question can be dealt with conceptually or by TESTing VALUES.
We're told that the numerator of a fraction R is tripled and the denominator of that same fraction is doubled. We're asked for the resulting increase, in percentage terms, of that fraction.
Let's TEST 2/1
If we triple the numerator and double the denominator, we end up with....
(2x3)/(1x2) = 6/2 = 3
Since we're increasing 2 to 3, we're increasing that fraction by (3-2)/2 = 1/2 of itself = 50%
D
Answer: D
Question: Mangala completes a piece of work in 30 days, Raju completes the same work in 40 days. If both of them work together, then the number of days required to complete the work is
Options:
A)4 days
B)6 days
C)8 days
D)17.14 days
E)11 days
Rationale: If A can complete a work in x days and B can complete the same work in y days, then, both
of them together can complete the work in x y/ x+ y days.
That is, the required No. of days = 30 × 40/70 = 17.14 days.
Answer : D
Answer: D
Question: There are 2 printers installed to print some pages. If you have to find out how many pages will the printers print at 35°C when one printer’s work is directly proportional and the others printer work is inversely proportional to the temperature and the total work done at 15°C is 20 pages and that done on 20°C is 25 pages?
Options:
A)40 pages
B)41.2 pages
C)40.7 pages
D)43.2 pages
E)39.7 pages
Rationale: If 1st Printer works directly proportional to the temperature with constant K1 and
2nd printer works inversely proportional to the temperature with constant K2, then
Pages printed at particular temperature= T1*K1 + K2/T2 ----(i)
15K1+ (K2/15) = 20 ----(ii) &
20K1+ (K2/20) = 25 ----(iii)
On solving (ii) & (iii), K1=8/7 ,K2=300/7
From (i), Total pages printed at 35°C = (35*8/7) + [300/(7*35)] =40 + (60/49)= 41.22
ANSWER:B
Answer: B
Question: In what time a sum of money double itself at 3% per annum simple interest?
Options:
A)33 1/8%
B)33 1/3%
C)33 7/3%
D)32 1/3%
E)23 1/3%
Rationale: P = (P*3*R)/100
R = 33 1/3%
Answer: B
Answer: B
Question: In a contest, a bowl contains 16 keys, only one of which will open a treasure chest. If a contestant selects the key that opens the treasure chest, she wins the contents of that chest. If Anna is allowed to draw two keys, simultaneously and at random, from the bowl as the first contestant, what is the probability that she wins the prize?
Options:
A)15/256
B)3/32
C)1/16
D)1/8
E)1/32
Rationale: P(not winning) = 15/16*14/15 = 7/8
P(winning) = 1 - 7/8 = 1/8
The answer is D.
Answer: D
Question: The sum of two numbers is 35. Their difference is 5. The bigger number is
Options:
A)20
B)25
C)30
D)35
E)45
Rationale: X + Y = 35
X - Y = 5
Adding 2X = 40 ==> X = 20 and Y = 35 - 20 = 15
Bigger number is X = 20
Answer A.
Answer: A
Question: Population of a city in 20004 was 1000000. If in 2005 there isan increment of 15% , in 2006 there is a decrements of 35 % and in 2007 there is an increment of 45%, then find the population of city atthe end of the year 2007
Options:
A)976374
B)979923
C)980241
D)2356677
E)1083875
Rationale: Required population = P (1 + R1/100)(1 - R2/100)(1 + R3/100)
= P (1 + 15/100)(1 - 35/100)(1 + 45/100)
= 1083875
E
Answer: E
Question: If a: b = 7: 5, b: c = 9: 11, find a: b: c?
Options:
A)63: 14: 55
B)63: 45: 55
C)14: 14: 15
D)7: 14: 15
E)None of these
Rationale: Explanation:
a: b = 7: 5
b: c = 9: 11
a: b: c = 63: 45: 55
Answer is B
Answer: B