divelab/Sys2Bench huggingface dataset:
Question: A man received a cheque. The amount in Rs. has been transposed for paise and vice versa. After spending Rs. 5 and 42 paise, he discovered he now had exactly 6 times the value of the correct cheque amount. What amount he should have received?
Options:
A)Rs 5.30
B)Rs 6.44
C)Rs 60.44
D)Rs 16.44
E)None of these
Rationale: Explanation :
Option 4 :- on reversal will be 44Rs 16Ps, after spending 5Rs 42Ps, remaining will be around 40rs which is not 6 times 16Rs 44Ps.
Option 3 :- on reversal will lead a smaller value. Hence we can eliminate that as well.
Option 1 :- on reversal is 30Rs 5 Paise, after spending 5Rs 42Ps, remaining will be 24Rs 63Paise, 24Rs63Ps is not 6 times 5Rs30Paise.
Option 2 on reversal is 44Rs 06 Paise, after spending 5Rs 42Ps, remaining will be 38Rs 64Ps, which is 6 times 6Rs 44Paise. Hence Rs 6.44 is the answer.
We need not even consider option 4 and option 3 as reversed number itself is not 6 times the original number. Option 1 when reversed is odd, and when even (5Rs 42Ps) is subtracted from odd, we get a odd number, and an odd number cannot be 6 times another number
Answer : B
Answer: B
Question: If an item that originally sold for A dollars was marked up by x percent and then discounted by K percent, which of the following expressions represents the final price of the item?
Options:
A)(10,000z + 100z(x – y) – xyz)/10,000
B)(A+ Ax/100) - K/100 ( A +Ax/100)
C)(100z(x – y) – xyz)/10000
D)(100z(y – x) – xyz)/10000
E)10000 /(x – y)
Rationale: value of item =A ..marked up by x% = Ax/100
total value = A +ax/100 .discounted by Y% on Total K/100 * ( A+Ax/100)
Final price =(A+ Ax/100) - K/100 ( A +Ax/100)
B
Answer: B
Question: Which of the following number will completely divide (49^15)-1?
Options:
A)8 is the number
B)6
C)22
D)12
E)14
Rationale: x^n - 1 will be divisible by x+1 only when n is even.
49^15 - 1 = (7^2)^15 - 1 = 7^30 - 1 which is divisible by 7+1 i.e. 8
Answer is A
Answer: A
Question: A and B starts a business with Rs.8000 each, and after 4 months, B withdraws half of his capital . How should they share the profits at the end of the 18 months?
Options:
A)18:11
B)18:15
C)18:19
D)18:121
E)18:112
Rationale: A invests Rs.8000 for 18 months, but B invests Rs.8000 for the first 4 months and then withdraws Rs.4000. So, the investment of B for remaining 14 months is Rs.4000 only.
A : B
8000*18 : (8000*4) + (4000*14)
14400 : 88000
A:B = 18:11.Answer:A
Answer: A
Question: 4 mat-weaves can weaves 4 mats in 4 days.At the same rate,how many mats would be woven by 8 mat-weaves in 8 days ?
Options:
A)4
B)8
C)12
D)16
E)17
Rationale: Solution
Let the required number of mats be x.
More weaves,More mats (Direct Proportion)
More days,More mats (Direct Proportion)
∴ 4 × 4 × x = 8 × 8 × 4 ⇔ x = (8x8x4)/(4x4)= 16. Answer D
Answer: D
Question: When positive integer x is divided by positive integer y, the remainder is 8. If x/y = 76.4, what is the value of y?
Options:
A)20
B)22
C)23
D)24
E)25
Rationale: When positive integer x is divided by positive integer y, the remainder is 8 --> x=qy+8;
x/y=76.4 --> x=76y+0.4y (so q above equals to 76);
0.4y=8 --> y=20.
Answer: A.
Answer: A
Question: A Bell Curve (Normal Distribution) has a mean of − 1 and a standard deviation of 1/8 . How many integer values V are within three standard deviations of the mean?
Options:
A)0
B)1
C)3
D)6
E)7
Rationale: Got the question correctly -- the second item -- [highlight]bthe list of elements in the set is required.[/highlight] is not required.
With the new information, there is only one integer value (-1) that is between (-1.375, -0.625) i.e., falls within the three 3 SD range.B
Answer: B
Question: If the number of 89n,870, where n represents the thousands digit, is a multiple of 9, then the value of n could be which of the following?
Options:
A)0
B)1
C)3
D)4
E)6
Rationale: Divisibility rule of 9: The sum of the digits must be divisible by 9
i.e 8+9+n+8+7+0 = multiple 9
or, 32 + n = multiple of 9.
If n=4, 32 + n =36,which is a multiple of 9.
Hence answer is D.
Answer: D
Question: 5% people of a village in Sri Lanka died by bombardment, 15% of the remainder left the village on account of fear. If now the population is reduced to 3443, how much was it in the beginning?
Options:
A)4264
B)2776
C)4400
D)2871
E)881
Rationale: X * (95/100) * (85/100) = 3443
X = 4264
Answer:A
Answer: A
Question: A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Options:
A)177 m
B)166 m
C)776 m
D)150 m
E)176 m
Rationale: Speed=(60 * 5/18) m/sec
= (50/3) m/sec Length of the train
= (Speed x Time)
= (50/3 * 9) m = 150 m.
Answer:D
Answer: D
Question: If r = 2^4 * 5^2 * 7 and s = 2 * 3^2 * 5, which of the following is equal to the greatest common divisor of r and s?
Options:
A)2 * 5
B)2^2 * 5
C)2^3 * 5^2
D)2*3*5*7
E)2^3 * 3^2 * 5^2 * 7
Rationale: GCD = product of prime factors raised to the least power = 2 * 5
The answer is A.
Answer: A
Question: A company produces 72000 bottles of water everyday. If a case can hold 10 bottles of water .How many cases are required by the company to hold its one day production
Options:
A)2000
B)4500
C)5000
D)7200
E)9000
Rationale: Number of bottles that can be held in a case =10
Number of cases required to hold 72000 bottles = 72000/10=7200 cases.
So the answer is D =7200
Answer: D
Question: For any integer n greater than 1, [n denotes the product of all the integers from 1 to n, inclusive. How many prime numbers are there between [6 + 2 and [6 + 6, inclusive?
Options:
A)None
B)One
C)Two
D)Three
E)Four
Rationale: Given that [n denotes the product of all the integers from 1 to n, inclusive so, [6+2=6!+2 and [6+6=6!+6.
Now, notice that we can factor out 2 our of 6!+2 so it cannot be a prime number, we can factor out 3 our of 6!+3 so it cannot be a prime number, we can factor out 4 our of 6!+4 so it cannot be a prime number, ... The same way for all numbers between 6*+2=6!+2 and 6*+6=6!+6, inclusive. Which means that there are no primes in this range.
Answer: A
Answer: A
Question: The present worth of a bill due sometime hence is Rs. 1100 and the true discount on the bill is Rs.110.Find the banker's discount and the banker’s gain?
Options:
A)Rs.111
B)Rs.120
C)Rs.121
D)Rs.125
E)None
Rationale: Solution
T.D	=	√P.W x B.G
B.G	= (T.D)² / P.W
= Rs(110x110/1100)
= Rs.11.
B.D	= (T.D + B.G)
= Rs(110+11)
= Rs.121.
Answer C
Answer: C
Question: The compound and the simple interests on a certain sum at the same rate of interest for two years are Rs.11730 and Rs.10200 respectively. Find the sum.
Options:
A)Rs.18000
B)Rs.17000
C)Rs.18500
D)Rs.17500
E)None of these.
Rationale: The simple interest for the first year is 10200/2 is Rs.5100 and compound interest for first year also is Rs.5100. The compound interest for second year on Rs.5100 for one year
So rate of the interest = (100 * 1530)/ (5100 * 1) = 30% p.a.
So P = (100 * 10200)/ (30 * 2) = Rs.17000
ANSWER:B
Answer: B
Question: The marks obtained by Polly and Sandy are in the ratio 4:5 and those obtained by Sandy and Willy are in the ratio of 5:2. The marks obtained by Polly and Willy are in the ratio of...?
Options:
A)2:1
B)3:2
C)4:3
D)5:4
E)6:5
Rationale: Polly : Sandy = 4:5
Sandy : Willy = 5:2
Polly : Sandy : Willy = 4:5:2
Polly : Willy = 4:2 = 2:1
The answer is A.
Answer: A
Question: A bus trip of 550 miles would have taken 1 hour less if the average speed V for the trip had been greater by 5 miles per hour. What was the average speed V, in miles per hour, for the trip?
Options:
A)40
B)45
C)50
D)55
E)60
Rationale: The time is the distance/speed. The time difference is 1 hour.
550/V - 550/(V+5) = 1
550(V+5) - 550V = (V)(V+5)
2750 = (V)(V+5)
50*55 = (V)(V+5)
V = 50 mph
The answer is C.
Answer: C
Question: If q is an integer greater than 6, which of the following must be divisible by 3?
Options:
A)Q(Q+1)(Q-4)
B)N(N+2)(N-1)
C)N(N+3)(N-5)
D)N(N+4)(N-2)
E)N(N+5)(N-6)
Rationale: Now take Q = 3k , Q = 3k+1 Q = 3k+2..put in all the choices. If by putting all the values of Q we get it is divisible by 3, then it is correct answer choice.
A is correct. It will hardy take 10 sec per choice as we have to consider only 3k+1 and 3k+2.
Answer: A
Question: In a race of 1000 m, A can beat by 100 m, in a race of 800m, B can beat C by 100m. By how many meters will A beat C in a race of 600 m?
Options:
A)122.9 m
B)127.5 m.
C)122.2 m
D)222.9 m
E)12289 m
Rationale: When A runs 1000 m, B runs 900 m and when B runs 800 m, C runs 700 m.
When B runs 900 m, distance that C runs = (900 * 700)/800
= 6300/8
= 787.5 m.
In a race of 1000 m, A beats C by (1000 - 787.5) = 212.5 m to C.
In a race of 600 m, the number of meters by which A beats C = (600 * 212.5)/1000
= 127.5 m.
Answer:B
Answer: B
Question: How many integers are between 7 and 120/9, inclusive?
Options:
A)5
B)6
C)7
D)9
E)10
Rationale: 120/9 = 13.xx
We are not concerned about the exact value of 120/9 as we just need the integers.
The different integers between 7 and 120/9 would be 7, 8, 9, 10, 11, 12,13
Total number of integers = 7
Option C
Answer: C
Question: The salary of a worker is first increased by 15% and afterwards reduced by 15%. What is the net change in the worker's salary?
Options:
A)5.25% increase
B)5.25% decrease
C)2.25% increase
D)2.25% decrease
E)no change
Rationale: Let x be the original salary.
The final salary is 0.85(1.15x) = 0.9775x
The answer is D.
Answer: D
Question: In x-y plane, there is a right triangle ABC (∠B=90o). If the length of AC is 25 and the slope of line segment AC is 4/3, what is the length of AB?
Options:
A)12
B)18
C)20
D)28
E)40
Rationale: Slope = Change in Vertical Direction/Change in Horizontal Direction = 4/3
Change in Vertical Direction = 4x = AB
Change in Horizontal Direction = 3x = BC
AB^2 + BC^2 = 25^2
16x^2 + 9x^2 = 625
25x^2 = 625
x^2 = 25
x = 5
Therefore AB = 5*4 = 20
Answer: C
Answer: C
Question: An express traveled at an average speed of 120 km/hr, stopping for 3 min after every 90 kn. How long did it take to reach its destination 600 km from the starting point?
Options:
A)5 hrs 21 min
B)4 hrs 21 min
C)6 hrs 41 min
D)5 hrs 15 min
E)4 hrs 34 min
Rationale: D
6 hrs 21 min
Time taken to cover 600 km = 600/120 = 5 hrs.
Number of stoppages = 600/90 - 1 = 5
Total time of stoppages = 3 * 5 = 15 min
Hence, total time taken = 5 hrs 15 min.
Answer: D
Question: The set X = {10,11,12,13}. The set Y = {2,3,4,5}. We will randomly choose one element x from set X and one element y from set Y. What is the probability that x / y will be an integer?
Options:
A)9/16
B)7/16
C)5/16
D)5/8
E)3/8
Rationale: The total number of x and y pairs is 4*4=16.
There are five pairs such that x / y is an integer.
The probability that x / y is an integer is 5/16.
The answer is C.
Answer: C
Question: A passenger sitting near the window in a train moving at 45 km/h, noticed that it took 3 sec. for the oncoming train to pass by. What was the speed of the oncoming train if the length of the oncoming train was 75 metres?
Options:
A)a)50km/h
B)b)52km/h
C)c)45km/h
D)d)60km/h
E)e)70km/h
Rationale: im getting A
3 secs to pass a 75 mts train , therefore speed = 25 meters/sec
to convert m/s to km/hrs multiply by 3.6
25*3.6 = 90
so its 90-45 = 45 .
C
Answer: C
Question: How much time will it take for an amount of Rs. 450 to yield Rs. 81 as interest at 4.5% per annum of simple interest?
Options:
A)3.5 years
B)4 years
C)4.5 years
D)5 years
E)5.5 years
Rationale: Time = (100 x 81)/(450 x 4.5) = 4 years.
Answer: Option B
Answer: B
Question: Find last two digits of the following expression (201*202*203*204*246*247*248*249)^2
Options:
A)33Q76
B)76
C)20
D)27
E)200
Rationale: To find the last two digits of a product take the last two digits in each number and multiply. 01*02*03......48*49 (use onscreen calculator)
this gives 76. So 762762 = 576 So last two digits are 76
Answer:B
Answer: B
Question: In a garden, there are 10 rows and 12 columns of mango trees. The distance between the two trees is 2 metres and a distance of four metre is left from all sides of the boundary of the garden. What is the length of the garden?
Options:
A)22
B)24
C)26
D)28
E)30
Rationale: Between the 12 mango trees, there are 11 gaps and each gap has 2 meter length
Also, 4 meter is left from all sides of the boundary of the garden.
Hence, length of the garden = (11 Ã— 2) + 4 + 4 = 30 meter
Answer is E.
Answer: E
Question: A work can be finished in 16 days by 30 women. The same work can be finished in 10 days by sixteen men. The ratio between the capacity of a man and a woman is
Options:
A)3:1
B)4:3
C)2:3
D)2:1
E)2:4
Rationale: Work done by 30 women in 1 day = 1/16
Work done by 1 woman in 1 day = 1/(16×30)
Work done by 16 men in 1 day = 1/10
Work done by 1 man in 1 day = 1/(10×16)
Ratio of the capacity of a man and woman =1/(10×16) : 1/(16×30) = 1/10 : 1/30
= 1/1 :1/3 = 3:1
Option A
Answer: A
Question: If a, b, c and d are positive integers and a/b < c/d, which of the following must be true?
I. (a+c)/(b+d) < c/d
II. (a+c)/(b+d) < a/b
III. (a+c)/(b+d) = a/b +c/d
Options:
A)None
B)I only
C)II only
D)I and II
E)I and III
Rationale: If a, b, c and d are positive integers and a/b < c/d, which of the following must be true?
Since the numbers are positive we can safely cross-multiply. So, we are given that ad<bcad<bc.
I. a+cb+d<cda+cb+d<cd = ad+cd<bc+cd
ad+cd<bc+cd= cdcd cancels out: ad<bc. This is given to be true.
II. a+cb+d<aba+cb+d<ab = ab+bc<ab+adab+bc<ab+ad= ab
ab cancels out: bc<ad bc<ad. Opposite what is given, thus this option is not true.
III. a+cb+d=ab+cda+cb+d=ab+cd. From I we already know that a+cb+d<cda+cb+d<cd, thus when we add a positive value (abab) to (cdcd)we make the right hand side even bigger.Thus a+cb+d=ab+cda+cb+d=ab+cd cannot be true.
Answer: B.
Answer: B
Question: For a road work, a contractor was given a deadline to complete the work in 25 days. Hence, he employed a certain number of workers to accomplish the job. But from the very first day 9 workers were absent and the remaining workers could finish the work in 40 days. What number of workers did the contractor hired in the beginning?
Options:
A)20
B)30
C)24
D)16
E)19
Rationale: Explanation :
Let the number of workers initially hired be x.
Hence, x workers can complete the work in 25 days and (x-9) workers can complete the work in 40 days.
Now, the number of men and the amount of work are in direct proportion and number of men and number of days in indirect proportion.
x*25 = (x 9)*40
25x = 40x 360
15x = 360
x = 24
Answer : C
Answer: C
Question: A particular library has 150 books in a special collection, all of which were in the library at the beginning of the month. These book are occasionally loaned out through an inter-library program. If, by the end of the month, 65 percent of books that were loaned out are returned and there are 108 books in the special collection at that time, how many books of the special collection were loaned out during that month?
Options:
A)40
B)60
C)80
D)100
E)120
Rationale: The total number of books is 150.
Let x be the number of books which were loaned out.
65% of books that were loaned out are returned.
35% of books that were loaned out are NOT returned.
Now, there are 108 books, thus the number of un-returned books is 150-108 = 42 books.
0.35x = 42
x = 120
The answer is E.
Answer: E
Question: It rained on exactly 7 of the days during Jane's summer holiday trip. On
each day that it rained, it rained either in the morning or the afternoon
but not both. There were exactly 5 afternoons when it did not rain and
exactly 6 mornings when it did not rain. How many days did the trip
last?
Options:
A)7
B)8
C)9
D)10
E)11
Rationale: Let M be the number of days it rained in the morning; A - the number of
days it rained in the afternoon; and let N be the number of days when it did not rain.
We have M + A = 7 (days when it rained); M + N = 5 (afternoons when it did not
rain); and A + N = 6 (mornings when it did not rain). Adding the equations we get
2(M + A + N) = 18, M + A + N = 9.
correct answer C
Answer: C
Question: The median annual household income in a certain community of 21 households is $50,000. If the mean income of a household increases by 10% per year over the next 2 years, what will the median Q income in the community be in 2 years?
Options:
A) $50,000
B) $60,000
C) $60,500
D) $65,000
E) Cannot be determined
Rationale: Answer is E, because there are different numbers in the set and we are not sure which side of the numbers in the set will be increased so the mean Q is increase by 10%. It could be the case that small number of higher end incomes increased a little or many low end incomes increased - it cannot be identified.
Answer: E
Question: An investor can sell her MicroTron stock for 36$ per share and her Dynaco stock for 44$ per share, If she sells 300 shares altogether, some of each stock, at an average price per share of 40$, how many shares of Dynaco stock has she sold?
Options:
A)52
B)75
C)92
D)136
E)150
Rationale: w1/w2 = (A2 - Aavg)/(Aavg - A1) = (44 - 40)/(40 - 36) = 4/4 = 1/1 = Number of MicroTron stocks/Number of Dynaco stocks
So for every 1 MicroTron stock, she sold 1 Dynaco stock.
So out of 300 total stocks, (1/1)th i.e. 300/2 = 150 must be Dynaco stock.
Answer (E)
Answer: E
Question: The simple form of the ratio 2/3:2/5 is?
Options:
A)5:6
B)5:1
C)5:7
D)5:3
E)1:3
Rationale: 2/3 : 2/5 = 10:6
=5:3
Answer:D
Answer: D
Question: A box contains 4 red chips and 5 blue chips. If two chips are selected at random without replacement, what is the probability that the chips are different colors?
Options:
A)1/2
B)5/9
C)7/12
D)2/3
E)7/10
Rationale: Total selection ways: 9C2=9!/5!4!=36
Selecting one blue chip out of two: 5C1=5!/4!1!=5
Selecting one red chip out of four: 4C1=4!/1!3!=4
Thus, (5C1*4C1)/9C2=(5*4)/36=20/36=5/9=B
Answer: B
Question: Walking at 8KMPH From Point R to Point railway station, mike will miss the train by 5 minutes. If he walks at 10KMPH he will reach the station by 5 minutes early.What is the distance between Point R to Railway station?
Options:
A)A)9KM
B)B)6.66KM
C)C)7.25KM
D)D)12.40KM
E)E)13KM
Rationale: Since time differences given are in minutes so let's convert speed in Km per minute
8 kmph = 8/60 km per minute = (2/15) km per minute
10 kmph = 10/60 km per minute = (1/6) km per minute
Let, Time of train to depart from station = t minutes
Distance between Point R and Railway Station = Speed*Time = (2/15)*(t+5)
Distance between Point R and Railway Station = Speed*Time = (1/6)*(t-5)
i.e. (2/15)*(t+5) = (1/6)*(t-5)
i.e. 12t+60 = 15t - 75
i.e. 3t = 135
i.e. t = 45 minutes
i.e. Distance = (1/6)*(t-5) = (1/6)*(45-5) = 40/6 = 20/3 Km = 6.66 Km
Answer: Option B
Answer: B
Question: A shop sells bicycles and tricycles. In total there are 10 cycles (cycles include both bicycles and tricycles) and 23 wheels. Determine how many of each there are, if a bicycle has two wheels and a tricycle has three wheels.
Options:
A)b=7,t=3
B)b=5,t=3
C)b=8,t=2
D)b=2,t=5
E)b=6,t=4
Rationale: Let b be the number of bicycles and let t be the number of tricycles.
Set up the equations
b+t=10............(1)
2b+3t=23............(2)
Let b be the number of bicycles and let t be the number of tricycles.
Set up the equations
b+t=8............(1)
2b+3t=19............(2)
Rearrange equation (1) and substitute into equation (2)
2b+30-3b=23
-b=-7
b=7
Calculate the number of tricycles t
t=10−b
=10−7
=3
There are 3 tricycles and 7 bicycles.
Answer is A.
Answer: A
Question: 12 buckets of water fill a tank when the capacity of each tank is 13.5 litres. How many buckets will be needed to fill the same tank, if the capacity of each bucket is 9 litres?
Options:
A)8
B)15
C)16
D)18
E)None
Rationale: Solution
Capacity of the tank	= (12×13.5) litres
= 162 litres.
Capacity of each bucket	= 9 litres.
Number of buckets needed	= (162/9)
‹=› 18.
Answer D
Answer: D
Question: On average, the boys in the class have 20 pencils and the girls have 38 pencils. If the overall class average is 30 pencils, what is the ratio of boys to girls in the class?
Options:
A)1/2
B)2/3
C)3/4
D)4/5
E)5/6
Rationale: (38G + 20B) / (G+B) = 30
38G + 20B = 30(G+B)
8G=10B
B/G = 4/5
The answer is D.
Answer: D
Question: What is the ratio of 12 minute to 1 hour ?
Options:
A)1/4
B)3/4
C)1/5
D)2/2
E)3/1
Rationale: C
1/5
Answer: C
Question: Tough and Tricky questions: Work/Rate Problems.
If it takes 70 workers 3 hours to disassemble the exhibition rides at a small amusement park, how many hours would it take 20 workers to do this same job?
Options:
A)40/3
B)10.5
C)7
D)7/3
E)9/7
Rationale: 70 Workers = 3 hours then,
1 Worker = 3*70 Hours
20 Workers = (3*70) /(20) = 10.5 Answer. B
Answer: B
Question: The moon revolves around the earth at a speed of approximately 1.02 kilometers per second. This approximate speed is how many kilometers per hour?
Options:
A)60
B)61.2
C)62.5
D)3,600
E)3,672
Rationale: moon revolves around the earth at a speed of 1.02kilometers per second.
one hour equal to 60 minutes.
one minute equals to 60 seconds. so one hour equals to 3600 seconds.
so one hour, speed= 1.02*3600=3672 kilometers per hour.
Option E is correct
Answer: E
Question: Monica planned her birthday party. She prepared 5 muffins for each of her guests and kept aside two additional muffins in case someone will want extra. After the party, it turned out that one of the guests didn't come but every one of the guests that did come ate six muffins and 7 muffins remained. How many guests did Monica plan on?
Options:
A)3.
B)4.
C)1.
D)6.
E)7.
Rationale: 5N +2 = 7 + 6(N-1)
Solving N= 1
Hence C
Answer: C
Question: A man rows his boat 72 km downstream and 30 km upstream, taking 3 hours each time. Find the speed of the stream?
Options:
A)6 kmph
B)5 kmph
C)2 kmph
D)8 kmph
E)7 kmph
Rationale: Speed downstream = d/t = 72/(3) = 24 kmph
Speed upstream = d/t = 30/(3) = 10 kmph
The speed of the stream = (24 - 10)/2 = 7 kmph
Answer:E
Answer: E
Question: A and B enter into a partnership with respective capitals of Rs. 20,000 and Rs. 40,000. At the end of the year, the total profit is Rs. 39,000. If A receives Rs. 15,000 as both his salary and profit, then what is his salary?
Options:
A)Rs. 2000
B)Rs. 4000
C)Rs. 3500
D)Rs. 3000
E)None of these
Rationale: Explanation:
A's capital : B 's capital
20000 : 40000 = 1 : 2
Since, the time period is fixed, the profit is distributed in the ratio of capital 1 : 2
Profit of A = (1/3) * 39,000 = Rs. 13,000
Salary of A = Rs. (15000 – 13000) = Rs. 2000
ANSWER: A
Answer: A
Question: Jack and Jill work at a hospital with 4 other workers. For an internal review, 2 of the 6 workers will be randomly chosen to be interviewed. What is the probability that Jack and Jill will both be chosen?
Options:
A)1/3
B)1/4
C)1/15
D)3/8
E)2/3
Rationale: Total number of ways to choose 2 out of 6 workers= 6!/2!4!= 15
Number of ways to choose both jack and jill= 1
probability= 1/15
C should be the answer
Answer: C
Question: A man can row 6 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and black. What is the total distance traveled by the man?
Options:
A)5.77 km
B)5.98 km
C)5.76 km
D)5.96 km
E)5.12 km
Rationale: Explanation:
M = 6
S = 1.2
DS = 7.2
US = 4.8
x/7.2 + x/4.8 = 1
x = 2.88
D = 2.88 * 2 = 5.76
Answer: Option C
Answer: C
Question: How long does a train 110 m long running at the speed of 72 km/hr takes to cross a bridge 132 m length?
Options:
A)120
B)121.1
C)13
D)156
E)148
Rationale: Speed = 72 * 5/18 = 20 m/sec
Total distance covered = 110 + 132 = 242 m.
Required time = 242/20 = 12.1 sec.
Answer: Option B
Answer: B
Question: The sum of ages of 5 children born 2 years different each is 50 yrs. What is the age of the Elder child?
Options:
A)8
B)14
C)16
D)17
E)18
Rationale: Let the ages of children be x, (x + 2), (x + 4), (x + 6) and (x + 8) years.
Then, x + (x + 2) + (x + 4) + (x + 6) + (x + 8) = 50
5x = 30
x = 6
x+8= 6+8= 14
Answer : B
Answer: B
Question: If x and y are prime numbers, which of the following CANNOT be ( x + Y )?
Options:
A)5
B)23
C)13
D)16
E)3
Rationale: All answer choices but B are odd. In order odd number to be the sum of two prime numbers one must be even, so 2, and another odd.
Now, 23=2+21. Since 21 is not a prime then 23 cannot be written as the sum of two prime numbers.
Answer: B
Answer: B