divelab/Sys2Bench huggingface dataset:
Question: In an election contested by two parties, Party D secured 12% of the total votes more than Party R. If party R got 132,000 votes, by how many votes did it lose the election?
Options:
A)24,000
B)36,000 votes
C)168,000
D)240,000
E)300,000
Rationale: D + R = 100 ---- (1)
D - R = 12 ---- (2)
Solving (1) and (2) D = 56% and R = 44%
44% of Total = 132000
Total = 300000
D = 168000
Difference = 168000 - 132000 = 36000
Answer: B
Answer: B
Question: Factor | Percent of Respondents |
User-friendly | 56% |
Fast response time | 48% |
Bargain prices | 42% |
The table gives three factors to be considered when choosing an Internet service provider and the percent of the 1,600 respondents to a survey who cited that factor as important. If 30 percent of the respondents cited both “user-friendly” and “fast response time,” what is the maximum possible number of respondents who cited “bargain prices,” but neither “user-friendly” nor “fast response time?”
Options:
A)312
B)336
C)360
D)384
E)416
Rationale: The way I looked at is is as follows:
UserFriendly(UF) + FastResponse (FR) = 30%
UF leftover = 56 - 30 = 26%
FR leftover = 48 - 30 = 18%
Sum these = 74% (ie. 74% were either UF+FR, UF, FR)
26% leftover is the maximum number for Bargain Price
26/100 * 1600 = 26 * 16 = 416 (E).
Answer: E
Question: A man saves a certain portion of his income during a year and spends the remaining portion on his personal expenses. Next year his income increases by 40% but his savings increase by 100%. If his total expenditure in 2 years is double his expenditure in 1st year, What %age of his income in the first year did he save?
Options:
A)45%
B)40%
C)25%
D)28%
E)33.33%
Rationale: I year
Best is to give a number to his income, say 100..
and let saving be x..
so expenditure = 100-x
next year-
Income = 140
savings = 2x
expenditure = 140-2x..
Now 140-2x+100-x = 2(100-x)...
240-3x = 200-2x ................x = 40...
saving % = 40/100 * 100 = 40%
ANSWER:B
Answer: B
Question: If x is the median of the set {8/2, 11/3, 27/9, 21/5, x}, x could be
Options:
A)4
B)17/5
C)16/5
D)30/7
E)31/7
Rationale: The median is the middle number once all the numbers are arranged in increasing/decreasing order.
We see that
11/3 = 3.something,
28/9 = 3.something
21/5 = 4.something
9/2 = 4.something
So x should greater than the smallest two numbers and smaller than the greatest two numbers. We can see that x = 4 is possible. (First look at the simplest option or the middle option since options are usually arranged in increasing/decreasing order)
Answer (A)
Answer: A
Question: If a fair die is rolled three times, what is the probability that a 3 occurs on at least one roll?
Options:
A)25/36
B)125/216
C)91/216
D)11/36
E)36/216
Rationale: Thus, the probability of at least 1 roll = 1- Probability of NO 3s = 1- (5/6)(5/6)(5/6) = 1-125/216 = 91/216.
5/6 is the probability of NOT getting a 3 in any 1 roll with 5 allowed numbers (=1,2,4,5,6) out of a total of 6 possibilities.
answer:C
Answer: C
Question: Murali travelled from city A to city B at a speed of 60 kmph and from city B to city C at 40 kmph. What is the average speed of Murali from A to C given that the ratio of distances between A to B and B to C is 2 : 3?
Options:
A)kmph
B)kmph
C)kmph
D)kmph
E)kmph
Rationale: Let the distances between city A to B and B to C be 2x km and 3x km respectively.
Total time taken to cover from A to C
= (2x)/60 + (3x)/40
= (4x + 9x)/120 = 13x/120
= (2x + 3x)/(13x/120) = 46.2 kmph.
Answer: B
Answer: B
Question: Evaluate permutation
3P3
Options:
A)6
B)7
C)8
D)9
E)10
Rationale: Explanation:
nPn=n!
3P3=3∗2∗1=6
Option A
Answer: A
Question: 1000 men have provisions for 15 days. If 200 more men join them, for how many days will the provisions last now?
Options:
A)12.9
B)18.9
C)12.5
D)12.2
E)12.1
Rationale: :
1000*15 = 1200*x
x = 12.5
Answer: C
Answer: C
Question: A certain auto manufacturer sold 6% fewer vehicles in 2007 than in 2006. If the manufacturer sold 2.1 million vehicles in 2006, how many vehicles, to the nearest 10,000, did the manufacturer sell in 2007?
Options:
A)63,000
B)1,980,000
C)2,030,000
D)2,040,000
E)2,300,000
Rationale: Let's assume in 2006 the manufacturer sold X.
In 2007 he sold X-6/100(X)
If sales in 2006,X= 2.1 million find X-6/100(X)
(2.1 x 10^6)-6/100(2.1 x 10^6)
2100000-126000=1,974,000-----> 1,980,000(approx)
ANSWER:B
Answer: B
Question: If r is a positive integer and r^2 is divisible by 12, then the largest positive integer that must divide r ^3 is
Options:
A) 2^3
B) 2^6
C) 3^3
D) 6^3
E) 12^2
Rationale: Since r is an integer so r cannot have a 2 and sqrt 3 (because squaring this will give us a 2^2 and 3 (making the product as 12, and making r^2 as a multiple of 12))
r^2 is divisible by 12 (12 = 2*2*3), So, r should have at least one 2 and one 3 so that r^2 has a 2^2 and two 3
So, r will have a 2 and a 3. Or r will be a multiple of 6
So, largest possible integer than should divide r^3 is 6^3
So, Answer will be D
Answer: D
Question: If z is the smallest positive integer that is not prime and not a factor of 50!, what is the sum of the factors of z?
Options:
A)51
B)162
C)72
D)54
E)50!+2
Rationale: In fact 51=3*17 IS a factor of 50!.
The smallest positive integer that is NOT prime and NOT a factor of 50! is 106=2*53. The sum of the factors of 106 is 162.
Answer: B.
Answer: B
Question: A certain quantity of 70% solution is replaced with 25% solution such that the new concentration is 35%. What is the fraction of the solution that was replaced?
Options:
A)1/4
B)1/3
C)1/2
D)2/3
E)7/9
Rationale: Let's say that the total original mixture A is 100 ml
The original mixture A thus has 70 ml of alcohol out of 100 ml of solution
You want to replace some of that original mixture A with another mixture B that contains 25 ml of alcohol per 100 ml. Thus, the difference between 70 ml and 25 ml is 45 ml per 100 ml of mixture. This means that every time you replace 100 ml of the original mixture A by 100 ml of mixture B, the original alcohol concentration will decrease by 45%. The question says that the new mixture, let's call it C, must be 35% alcohol, a decrease of only 35%. Therefore, 35 out of 45 is 7/9 and E is the answer.
Answer: E
Question: If 10 litres of an oil of Rs.54 per litres be mixed with 5 litres of another oil of Rs.66 per litre then what is the rate of mixed oil per litre?
Options:
A)Rs.49.17
B)Rs.58
C)Rs.54.17
D)Rs.55.33
E)None of the above
Rationale: 54*10 = 540
66*5 = 330
870/15 = 58
ANSWER:B
Answer: B
Question: If 6x^2 + x - 12 = (ax + w)(cx + d), then |a| + |w| + |c| + |d| =
For a complete solution and more practice problems, see this blog:
http://magoosh.com/gmat/2012/algebra-on ... to-factor/
Options:
A) 10
B) 12
C) 15
D) 18
E) 20
Rationale: 6x^2+x-12 = 6x^2 + 9x -8x -12
=> 3x(2x+3) -4(2x+3)
=> (2x+3)(3x-4) = (ax+w)(cx+d)
Hence a=2, w=c=3, d=-4
So, 2+3+3+ |-4| = 2+3+3+4 = 12
Answer B.
Answer: B
Question: The average age 20 members of a committee are the same as it was 2 years ago, because an old number has been replaced by a younger number. Find how much younger is the new member than the old number?
Options:
A)18
B)99
C)77
D)40
E)12
Rationale: 20 * 2 = 40 years
Answer: D
Answer: D
Question: A man has Rs. 480 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?
Options:
A)45
B)60
C)75
D)90
E)100
Rationale: Let number of notes of each denomination be x.
Then x + 5x + 10x = 480
16x = 480
x = 30.
Hence, total number of notes = 3x = 90.
Answer: Option D
Answer: D
Question: X can finish a work in 18 days. Y can finish the same work in 15 days. Yworked for 10 days and left the job. how many days does X alone need to finish the remaining work?
Options:
A)3
B)5
C)6
D)8
E)9
Rationale: Work done by X in 1 day = 1/18
Work done by Y in 1 day = 1/15
Work done by Y in 10 days = 10/15 = 2/3
Remaining work = 1 – 2/3 = 1/3
Number of days in which X can finish the remaining work = (1/3) / (1/18) = 6
C
Answer: C
Question: In traveling from a dormitory to a certain city, a student went 1/3 of the way by foot, 3/5 of the way by bus, and the remaining 2 kilometers by car. What is the distance, in kilometers, from the dormitory to the city?
Options:
A)30
B)45
C)60
D)90
E)120
Rationale: Whole trip = distance by foot + distance by bus + distance by car
x = 1/3x + 3/5x + 2
x - 1/3x - 3/5x = 2
x = 30km
Option: A
Answer: A
Question: In measuring the sides of a rectangle, one side is taken 6% in excess and other 5% in deficit. Find the error percentage in the area calculated from these measurements.
Options:
A)3.5%
B)2.4%
C)3%
D)5%
E)0.7%
Rationale: Say both sides of the rectangle are equal to 100 (so consider that we have a square). In this case the area is 100*100=10,000.
Now, the area obtained with wrong measurements would be 106*95=10,070, which is 0.7% greater than the actual area.
Answer: E.
Answer: E
Question: The number of new words that can be formed by rearranging the letters of the word 'goat' is?
Options:
A)24
B)25
C)4
D)23
E)1
Rationale: Number of words which can be formed
= 4! - 1 = 24 - 1
= 23.
Answer:D
Answer: D
Question: The product of two numbers is 168 and the sum of their squares is 289. The sum of the number is?
Options:
A)A)23
B)B)25
C)C)27
D)D)31
E)E)35
Rationale: Let the numbers be x and y.
Then, xy = 168 and x2 + y2 = 289.
(x + y)2 = x2 + y2 + 2xy = 289 + (2 x 168) = 625
x + y = 25.
Option B
Answer: B
Question: Avg cost of 2 cakes and 3 cookies is Rs.30.The avg cost of 5 cakes and 7 cookies is Rs.72. Find the total cost of 30 cakes and 30 cookies?
Options:
A)190
B)160
C)130
D)200
E)180
Rationale: Avg cost of 2 cakes and 3 cookies is Rs. 30
(2 cake + 3 cookies) 5=30
therefore 1 cake cost is 30/5=6, so 2 cake cost is 2x6=12 and 3 cookies cost is 3x6=18
Again, avg cost of 5 cakes and 7 cookies is Rs.72
(5 cake + 7 cookies) 12=72
therefore 1 cake cost is 72/12=6, so 5 cake cost is 5x6=30 and 7 cookies cost is 7x6=42
So 30 cake cost is (30/a)=180 and 30 cookies cost is (30x6)=180
ANSWER:E
Answer: E
Question: In an exam, Amar scored 64 percent, Bhavan scored 36 percent and Chetan 44 percent. The maximum score awarded in the exam is 800. Find the average mark scored by all the three boys?
Options:
A)384
B)656
C)443
D)324
E)534
Rationale: Average mark scored by all the three boys =
[64/100 (800) + 36/100 (800) + 44/100 (800)] / 3 = 384
Answer:A
Answer: A
Question: A+1/(B+1/(C+1/(D+1/E)))=1331/1000
what is the value of A*B*C*D*E ?
Options:
A)841
B)842
C)843
D)844
E)846
Rationale: A+1/(B+1/(C+1/(D+1/E)))=1331/1000 = 1 + 331/1000 => A = 1
1/(B+1/(C+1/(D+1/E))) = 331/1000
or, B+1/(C+1/(D+1/E)) = 1000/331 = 3 + 7/331 => B = 3
1/(C+1/(D+1/E)) = 7/331
=> C+1/(D+1/E) = 331/7 = 47 + 2/7 => C = 47
1/(D+1/E) = 2/7
=> D + 1/E = 7/2 = 3 + 1/2 =>> D = 3, E = 2
finally,
A=1
B=3
C=47
D=3
E=2
A*B*C*D*E = 1*3*47*3*2 = 846
ANSWER:E
Answer: E
Question: In Solution P, the proportion of water to alcohol is 5:2. In Solution Q, the proportion of water to alcohol is 3:2. If the two solutions are combined, what is the concentration of alcohol in the new solution if the original solutions were mixed in equal amounts?
Options:
A)25%
B)28%
C)31%
D)34%
E)37%
Rationale: Let V be the total volume of the new solution.
The amount of alcohol added from Solution P is (2/7)*V/2=(1/7)*V
The amount of alcohol added from Solution Q is (2/5)*V/2=(1/5)*V
The total amount of alcohol in the new solution is (1/7+1/5)*V=(12/35)*V
The alcohol concentration is 12/35=34% (approximately)
The answer is D.
Answer: D
Question: At 1:00 pm, a truck left city P and headed toward City Q at a constant speed of 38 km/h. One hour later, a car left City Q and headed toward City P along the same road at a constant speed of 42 km/h. If the distance between City P and City Q is 378 km, at what time will the truck and the car meet each other?
Options:
A)5:30
B)5:45
C)6:00
D)6:15
E)6:30
Rationale: At 2:00 pm, the truck and the car are 340 km apart.
The truck and the car complete a distance of 80 km each hour.
The time it takes to meet is 340/80 = 4.25 hours.
They will meet at 6:15 pm.
The answer is D.
Answer: D
Question: If 5a= 3125, then the value of 5(a-3) is
Options:
A)25
B)50
C)250
D)300
E)None
Rationale: Sol.
5a = 3125 = 5a = 55
a = 5.
5(1-3) = 5(5-3) = 5(2) = 25.
Answer A
Answer: A
Question: Find the ratio in which rice at Rs. 7.00 a kg be mixed with rice at Rs. 5.70 a kg to produce a mixture worth Rs. 6.30 a kg
Options:
A)6:7
B)2:3
C)2:1
D)2:2
E)2:8
Rationale: By the rule of alligation:
Cost of 1 kg rice of 1st kind Cost of 1 kg rice of 2nd kind
Required ratio = 60 : 70 = 6 : 7
Answer: A
Answer: A
Question: How many numbers greater than a thousand can be made using the following digits without repetition: 1, 0, 3, 4, and 5:
Options:
A)96^2
B)96*2 IS ANSWER
C)576
D)24^2
E)24*96
Rationale: We have 5 digits: {0, 1, 3, 4, 5}
We can have 4-digit OR 5-digit numbers greater than 1,000.
# of 4-digit numbers greater than 1,000 = 4*4*3*2 = 96. The first digit can take 4 values: 1, 3, 4, or 5. So, any value but 0, since in this case a number will no longer be a 4-digit and becomes 3-digit. The second digit can take 4 values (5 values minus 1 we already used for the first digit), ...
# of 5-digit numbers greater than 1,000 = 4*4*3*2*1 = 96.
Total: 96+96=2*96.
Answer: B.
Answer: B
Question: Which of the following equations represents a line that is perpendicular to y=1/3*x+2?
Options:
A)y−2x=8
B)2x+4y=10
C)3y+6x=12
D)4y−8x=16
E)5x−10y=20
Rationale: For two lines to be perpendicular, the product of slopes should be equal to -1.
Slope of line 1 = 1/2
Slope of the line perpendicular to line 1 must be -2. Option C can be rewritten as y = -2x + 4 --> Slope = -2
Answer: D
Answer: D
Question: What is the remainder when 2676 * 1487 * 4459 is divided by 12
Options:
A)3
B)8
C)12
D)9
E)27
Rationale: 2679/12==> Remainder=3
1487/12==> Remainder=11
4459/12==> Remainder=7
=3*11*7=231/12==> Remainder=3
Answer: A
Answer: A
Question: Walking at 4/5 of his usual speed a man is 10 mins too late. find his usual time.
Options:
A)81 mins
B)64 mins
C)52 mins
D)40 mins
E)None
Rationale: speed=s,time=t,
4/5s*(t+10)=st
t=40
ANSWER:D
Answer: D
Question: If P represents the product of the first 12 positive integers, which of the following must be true?
I. P is an odd number
II. P is a multiple of 26
III. P is a multiple of 17
Options:
A)I only
B)II only
C)III only
D)None of the above
E)All of the above
Rationale: Answer = B) II only
Answer: B
Question: There are 7 stores in town that had a total of 21 visitors on a particular day. However, only 11 people went shopping that day; some people visited more than one store. If 7 people visited exactly two stores each, and everyone visited at least one store, what is the largest number of stores anyone could have visited?
Options:
A)6
B)8
C)4
D)9
E)2
Rationale: 7 people visited 2 stores each for 14 visits.
To maximize the number of stores that one person visited, let's assume that 3 people visited 1 store each. The number of remaining visits is 21 - 14 - 3 = 4, which is the maximum that one person could have visited.
The answer is C.
Answer: C
Question: A certain sum becomes Rs. 20720 in four years and 24080 in six years at simple interest. Find sum and rate of interest?
Options:
A)28%
B)12%
C)72%
D)82%
E)13%
Rationale: Let the interest for one year be x.
As amount = Principal + Interest, we have
P + 4x = 20720 --- (1) ; P + 6x = 24080 --- (2)
Solving the equations (1) and (2), we can get
P = Rs. 14000 and x = Rs. 1680
Interest for one year on Rs. 14000 is Rs. 1680
So, R = (100 * 1680)/(14000 * 1) = 12% p.a.
Answer:B
Answer: B
Question: A certain car uses one gallon of gasoline every 40 miles when it travels on highway, and one gallon of gasoline every 20 miles when it travels in the city. When a car travels 4 miles on highway and 4 additional miles in the city, it uses what percent more gasoline than if it travels 8 miles on the highway?
Options:
A)15%
B)20%
C)22.5%
D)25%
E)50%
Rationale: 4 miles on the highway = 4/40 gallons;
4 miles in the city = 4/20 gallons;
Total = 4/40 + 4/20 = 3/10 gallons.
8 miles on the highway = 8/40 gallons .
The % change = (3/10 - 8/40)/(8/40) = 1/2 = 0.50.
Answer: E.
Answer: E
Question: The ratio of two quantities is 5 to 6. If each of the quantities is increased by 2, what is the ratio of these two new quantities?
Options:
A)It cannot be determined from the information given.
B)5/14
C)6/15
D)7/16
E)8/17
Rationale: let the actual ratio be 5k/6k, increase numerator and denominator by 2=> 5k+2/6k+2
Until the value of k is unknown we can not determine the actual ratio.
OR
let the actual be 3/4. After increasing 2 => 5/6
let the actual be 6/8. After increasing 2 => 8/10
Therefore without actual quantities we cannot determine the actual ratio.
Answer : A
Answer: A
Question: A train is 360 meter long is running at a speed of 45 km/hour. In what time will it pass a bridge of 140 meter length?
Options:
A)22
B)28
C)40
D)27
E)12
Rationale: Speed = 45 Km/hr = 45*(5/18) m/sec = 25/2 m/sec
Total distance = 360+140 = 500 meter
Time = Distance/speed
= 500 * (2/25) = 40 seconds.
Answer: C:
Answer: C
Question: The circumferences of two circles are 264 meters and 352 meters. Find the difference between the areas of the larger and the smaller circles?
Options:
A)2312 sq m
B)2871 sq m
C)4312 sq m
D)1566 sq m
E)7177 sq m
Rationale: Let the radii of the smaller and the larger circles be s m and l m respectively.
2∏s = 264 and 2∏l = 352
s = 264/2∏ and l = 352/2∏
Difference between the areas = ∏l2 - ∏s2
= ∏{1762/∏2 - 1322/∏2}
= 1762/∏ - 1322/∏
= (176 - 132)(176 + 132)/∏
= (44)(308)/(22/7) = (2)(308)(7) = 4312 sq m
Answer:C
Answer: C
Question: A company D has 30 percent of the employees are secretaries and 45 percent are salespeople. If there are 50 other employees of Company D, how many employees does Company D have?
Options:
A)200
B)162
C)180
D)152
E)250
Rationale: Let the total number of employees in the company be x
% of secretaries = 30%
% of salespeople = 45%
% of of employees other than secretaries and salespeople = 100 - 75 = 25%
But this number is given as 50
so 25% of x = 50
x = 200
Therefore there a total of 200 employees in the company D
Correct answer - A
Answer: A
Question: Which of the following numbers has only one prime factor?
Options:
A)16
B)19
C)22
D)30
E)32
Rationale: 16=2^4
19=19
22=2*11
30=2*3*5
32=2^5
19 has 1 distinct prime factor
Answer B
Answer: B
Question: The average (arithmetic mean) of seven numbers is 12.2
If the sum of four of these numbers is 42.8, what is the average of the other 3 numbers?
Options:
A)(a) 12.4
B)(b) 14.2
C)(c) 16.8
D)(d) 18.6
E)(e) 19.2
Rationale: We're told that the average of 7 numbers is 12.2
(Sum of numbers)/7 = 12.2
Sum of numbers = (12.2)(7) = 85.4
Next, we're told that the sum of 4 (of the 7) numbers is 42.8
From this information, we can calculate the sum of the OTHER 3 numbers:
85.4 - 42.8 = 42.6
The question asks for the AVERAGE of the OTHER 3 numbers....
42.6/3 = 14.2
B
Answer: B
Question: The average of ten numbers is 7. If each number is multiplied by 12 ,then the average of new set of numbers is :
Options:
A)22
B)29
C)27
D)84
E)19
Rationale: The avg will be = 12×7= 84
Answer:	D
Answer: D
Question: The prices of tea and coffee per kg were the same in May. In july the price of coffee shot up by 20% and that of tea dropped by 20%. if in july , a mixture containing equal quantities of tea and coffee costs 50/kg. how much did a kg of coffee cost in june ?
Options:
A)50
B)45
C)40
D)32
E)28
Rationale: Let the price of tea and coffee be x per kg in June.
Price of tea in July = 1.2x
Price of coffee in July = 0.8x .
In July the price of 1/2 kg (500gm) of tea and 1/2 kg (500gm) of coffee (equal quantities) = 50
1.2x(1/2) + 0.8x(1/2) = 50
=> x =50
A
Answer: A
Question: How many prime factors in 25^10 * 36^10 * 20^10 ?
Options:
A)90
B)80
C)70
D)60
E)50
Rationale: 25^10 * 36^10 * 20^10
=(5*5)^10 * (2*2*3*3)^10 * (2*2*5)^10
=(5^10 * 5^10) * (2^10 * 2^10 * 3^10 * 3^10) * (2^10 * 2^10 * 5^10)
=5^30 * 2^40 * 3^20
number of distinct prime factors = 3
number of prime factors = 30+40+20 = 90 ANSWER:A
Answer: A
Question: The greatest common factor of two positive integers is F. The least common multiple of these two integers is Y. If one of the integers is Z, what is the other?
Options:
A)FY⁄Z
B)XZ + YZ
C)X⁄Z + Y
D)X + Y⁄Z
E)X + Z⁄Y
Rationale: Say other integer is W
Formula
GCF(WZ)*LCM(WZ) = W*Z
F*Y = W*Z
So W= FY/Z
Answer A
Answer: A
Question: Two trains each 180 m in length are running on the same parallel lines in opposite directions with the speed of each 80 kmph. In what time will they cross each other completely?
Options:
A)7.8 sec
B)8.1 sec
C)8.3 sec
D)8.2 sec
E)8.4 sec
Rationale: D = 180m + 180m = 360m * 1/1000 = 0.36 kms
RS = 80 + 80 = 160 kmph
T = (0.36/160) * 3600 = 8.1 sec
ANSWER:B
Answer: B
Question: The original price of a camera was displayed as a whole dollar amount. After adding sales tax of 20 percent, the final price was also a whole dollar amount. Which of the following could be the final price of the camera?
Options:
A)$222
B)$209
C)$211
D)$220
E)$215
Rationale: Final price = (1+20/100) * Original Price
= 1.20 * Original Price
From options given only 222 is divisible by 1.20 as it is stated OP is whole dollar amount.
Hence A
Answer: A
Question: The C.P of 10 pens is equal to the S.P of 12 pens. Find his gain % or loss%?
Options:
A)66 3/3%
B)16 2/3%
C)16 4/3%
D)76 2/3%
E)66 2/3%
Rationale: Explanation:
10 CP = 12 SP
12 --- 2 CP loss
100 --- ? => 16 2/3%
Answer: C
Answer: C
Question: Dean Winchester has got a long wooden stock of size 60 feet, he need to cut small stock of size 1 feet long using his axe.
He takes 5 minutes to cut one small stock (1 feet), how long will he take to make 60 such small stocks?
Options:
A)296 minutes.
B)297 minutes.
C)295 minutes.
D)294 minutes.
E)None
Rationale: Solution:
295 minutes.
When he cut 59 stocks, the 60th stock will remain.
59 * 5 = 295 minutes.
Answer C
Answer: C
Question: If each edge of cube increased by 20%, the percentage increase in
Options:
A)42
B)44
C)48
D)45
E)47
Rationale: 100 × (120)/100 × (120)/100 = 144 => 44%
Answer is B.
Answer: B
Question: A total of 550 players participated in a single tennis knock out tournament. What is the total number of matches played in the tournament? (Knockout means if a player loses, he is out of the tournament). No match ends in a tie.
Options:
A)511
B)512
C)549
D)255
E)1023
Rationale: There are 550 players, only 1 person wins, 549 players lose. in order to lose, you must have lost a game.
549 games.
Ans- C
Answer: C
Question: O(x) represents the least odd integer greater than x, whereas o(x) represents the greatest odd integer less than x. Likewise, E(x) represents the least even integer greater than x, whereas e(x) represents the greatest even integer less than x. According to these definitions, the value of O(11.6) + E(–10.4) + o(–9.2) + e(9.5) is:
Options:
A)-3
B)-1
C)0
D)1
E)3
Rationale: O(11.6) + E(–10.4) + o(–9.2) + e(9.5) = 13 + (-10) + (-11) + 8 = 0
The answer is C.
Answer: C
Question: After M students took a test, the average score was 66%. If the test has 50 questions, what is the least number of questions that the next student has to get right to bring the average score up to 68%?
Options:
A)2M-34
B)M+34
C)0.66M+0.68
D)0.33M+34
E)3M-33
Rationale: The total number of correct answers for M students is (0.66)*50*M=33*M
For an average of 68%: (total correct answers) / (M+1) = 0.68*50=34
Let x be the number of correct answers for the next student.
(x + 33M) / M+1 = 34
x + 33M= 34M+34
x = M + 34
The answer is B.
Answer: B
Question: The number of people at Ovations Bar in the hour from 12 p.m. to 1 p.m. was 25% greater than the number of people there from 11 a.m. to 12 p.m. The number of the people at the bar from 11 a.m. to 12 p.m. was 25% less than the number there from 10 a.m. to 11 a.m. If 135 people were at the bar from 11 a.m. to 1 p.m., which of the following is the number of people in the bar from 10 a.m. to 11 a.m.?
Options:
A)10
B)20
C)30
D)40
E)80
Rationale: No of people from 10 - 11 is x
No of people from 11 - 12 is 3x/4
No of people from 12 to 1 is (5/4)(3x/4)
Given that 3x/4 + (5/4)(3x/4) = 27x/16 = 135
Then x = 80
E
Answer: E
Question: Express a speed of 54 kmph in meters per second?
Options:
A)10 mps
B)18 mps
C)15 mps
D)17 mps
E)12 mps
Rationale: 54 * 5/18
= 15 mps
Answer:C
Answer: C