divelab/Sys2Bench huggingface dataset:
Question: The least number of complete years in which a sum of money put out at 20% C.I. will be more than doubled is?
Options:
A)5
B)4
C)7
D)1
E)2
Rationale: P(1 + 20/100)n > 2P or (6/5)n > 2
Now, (6/5 * 6/5 * 6/5 * 6/5) > 2. So, n
= 4 years.
Answer:B
Answer: B
Question: Given that there are 11 cricket players per team, how many ways can you select 10 cricket players from 2 teams if no more than 7 players can be selected from each team?
Options:
A)108900
B)457845
C)145256
D)356586
E)213444
Rationale: Now from each group we have to select 5 persons only: 11C7 * 11C7= 330 * 330 = 108900
Total ways=108900 ways.
Answer A
Answer: A
Question: A, B and C can do a work in 8 days, 8 days and 12 days respectively. In how many days can all three of them working together, complete the work?
Options:
A)3
B)2 2/8
C)2 2/0
D)2 2/2
E)2 2/1
Rationale: Work done by all three of them in one day = 1/8 + 1/8 + 1/12 = 1/3
The number of days required = 3 days.
Answer:A
Answer: A
Question: A boat goes 100 km downstream in 10 hours, and 75 m upstream in 15 hours. The speed of the stream is?
Options:
A)22 1/9
B)22 1/7
C)22 1/1
D)22 1/2
E)32 1/2
Rationale: 100 --- 10 DS = 10
? ---- 1
75 ---- 15 US = 5
? ----- 1 S = (10 - 5)/2
= 22 1/2 kmph.Answer:D
Answer: D
Question: Two stations A and B are 110 km apart on a straight line. One train starts from A at 2 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?
Options:
A)15 a.m
B)10 a.m
C)12 a.m
D)02 a.m
E)05 a.m
Rationale: Suppose they meet x hours after 2 a.m.
Distance covered by A in x hours = 20x km.
Distance covered by B in (x - 1) hours = 25(x - 1) km.
Therefore 20x + 25(x - 1) = 110
45x = 135
x = 3.
So, they meet at 5 a.m.
Answer:E
Answer: E
Question: If the average (arithmetic mean) of five consecutive negative integers is 4k – 1, what is the difference between the greatest and least of the five integers?
Options:
A)4K
B)4k^2 -4k
C)4-4k
D)4
E)4k+4
Rationale: (n-2 + n - 1 + n + n + 1 + n + 2)/5 = 4k - 1
=> n = 20k - 5
Greatest = n + 2 = 20k - 5 + 2 = 20k - 3
Least = n - 2 = 20k - 5 - 2
=> Difference = 20k - 3 - (20k - 7)
= 4
Answer - D
Answer: D
Question: How long does a train 120 meters long running at the rate of 54 kmph take to cross a bridge 660 meters in length?
Options:
A)33
B)72
C)52
D)82
E)62
Rationale: Explanation:
T = (660 + 120)/54 * 18/5
T = 52
Answer: Option C
Answer: C
Question: There are a total of 10 students in Mr. Schmidt's gym class. Over the course of a badminton unit, each of the 10 students will compete exactly once against every other student in the class. How many total games of badminton will be played?
Options:
A)48
B)47
C)45
D)41
E)46
Rationale: there are 10 students , if each play with all other members .
then total games can be calculated as 9+8....+1 = 45.
alternate approach is to choose 2 distinct out of 10 = 10c2 = 45
Answer is C.
Answer: C
Question: What is x if x + 5y = 24 and y = 2?
Options:
A)1
B)3
C)5
D)7
E)14
Rationale: Substitute y by 2 in x + 5y = 24
x + 5(2) = 24
x + 10 = 24
If we substitute x by 14 in x + 10 = 24, we have 14 + 10 = 24. Hence
x = 14 correct answer E
Answer: E
Question: In a race of 400 m, A can beat B by 40 m and C by 20 m. In how many meter race, C will beat B by 50m ?
Options:
A)1000m
B)1200m
C)800m
D)950m
E)600m
Rationale: Explanation:
A:B = 400 : 360
A:C = 400 : 380
=>B:C = 360:380 = 18:19
When C covers 380 m , B Covers 360 m
When C covers x m , B Covers
=> x - 50 m
18x/19 = x - 50
x = 950 m
Answer: D
Answer: D
Question: The population of a town increases 22% and 25% respectively in two consecutive years. After the growth the present population of the town is 1220. Then what is the population of the town 2 years ago?
Options:
A)A)600
B)B)700
C)C)800
D)D)900
E)E)1000
Rationale: Explanation:
Formula: (After =100 denominator
Ago = 100 numerator)
1220 * 100/122 * 100/125 = 800
Answer: Option C
Answer: C
Question: Find large number from below question The difference of two numbers is 1365. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder
Options:
A)1245
B)1435
C)2345
D)3543
E)1635
Rationale: Let the smaller number be x. Then larger number = (x + 1365).
x + 1365 = 6x + 15
5x = 1350
x = 270
Large number = 270+1365 = 1635
E
Answer: E
Question: During a trip on an expressway, Kon drove a total of x miles. His average speed on a certain 5-mile section of the expressway was 30 miles per hour, and his average speed for the remainder of the trip was 60 miles per hour. His travel time for the x-mile trip was what percent greater than it would have been if he had traveled at a constant rate of 60 miles per hour for the entire trip?
Options:
A)8.5%
B)50%
C)x/12%
D)60/x%
E)500/x%
Rationale: so Kon drove (x-5) miles at 60mph and 5 miles at 30mph:
(x-5)/60 + (10/60) = (X+5)/60 - current time to drive the whole distance
if the entire trip @60mph than time = x/60
so to get percent [(X+5)/60 ]/[x/60] x100
=(x+5)/x *100
=100+500/x
so increase of 500/x%[/u]=E
Answer: E
Question: If 30!/10! is written as the product of consecutive integers, the largest of which is 30, what is the smallest of the integers?
Options:
A)1
B)3
C)7
D)11
E)20
Rationale: 30!/10!=30∗29∗28...........11∗10!/10!
Smallest integer = 11
Answer = D
Answer: D
Question: How many 3-digit integers between 100 and 200 have a digit that is the average (arithmetic mean) of the other 2 digits?
Options:
A)1
B)7
C)9
D)11
E)19
Rationale: Since the number is between 100 and 200, the hundreds digit has to be 1.
And since the answer choices are small enough, it won't hurt just to write them out. 102, 111, 120, 123, 132, 135, 147, 153, 159, 174, 195.
Answer D
Answer: D
Question: A sells a bicycle to B at a profit of 20%. B sells it to C at a profit of 25%. If C pays Rs. 225 for it, the cost price of the bicycle for A is
Options:
A)627
B)297
C)127
D)150
E)181
Rationale: Explanation:
125% of 120% of A = 225
125/100 * 120/100 * A = 225
A = 225 * 2/3 = 150.
Answer: D
Answer: D
Question: Ramu bought an old car for Rs. 40000. He spent Rs. 13000 on repairs and sold it for Rs. 64900. What is his profit percent?
Options:
A)12%
B)16%
C)18%
D)82%
E)22.45%
Rationale: Total CP = Rs. 40000 + Rs. 13000 = Rs. 53000 and SP
= Rs. 64900
Profit(%) = (64900 - 53000)/53000 * 100
= 22.45%
Answer:E
Answer: E
Question: If x, y, and z are positive integers and x = 4y = 7z, then the least possible value of x - y - z is
Options:
A)33
B)17
C)49
D)16
E)23
Rationale: x - y - z = x - x/4 - x/7
= (28 - 7 - 4 )x/28 = 17x/28
17 is not divisible by 28(it's a prime #), so for least value, x = 28
Answer - B
Answer: B
Question: If 3 persons can do 3 times of a particular work in 3 days, then, 7 persons can do 7 times of that work in
?
Options:
A)3 days
B)7 days
C)9 days
D)11 days
E)15 days
Rationale: That is, 1 person can do one time of the work in 3 days.
Therefore, 7 persons can do 7 times work in the same 3 days itself.
Option 'A'
Answer: A
Question: Insert the missing number. 2, 7, 10, 22, 18, 37, 26
Options:
A)42
B)32
C)52
D)62
E)50
Rationale: There are two series here
2, 10, 18, 26, ... (Increase by 8)
7, 22, 37, ... (Increase by 15)
Hence, next term is 37+15 = 52
Answer is C.
Answer: C
Question: What is the total number of positive integers that are less than 800 and that have no positive factor in common with 800 other than 1?
Options:
A)200
B)320
C)480
D)500
E)600
Rationale: Since 800=2^5*5^2 then a number can not have 2 and/or 5 as a factor.
The odd numbers do not have 2 as a factor and there are 400 odd numbers from 1 to 800.
We then need to eliminate the 80 numbers that end with 5, that is 5, 15, 25,...,795.
There are a total of 400 - 80 = 320 such numbers between 1 and 800.
The answer is B.
Answer: B
Question: Eighteen years ago, a father was three times as old as his son. Now the father is only twice as old as his son. Then the sum of the present ages of the son and the father is
Options:
A)54.
B)72
C)105
D)108
E)None
Rationale: Solution
Let the present ages of Father and Son be 2x years and x years respectively.
Then	(2x-18)=3(x-18)
2x-18=3x-54
x=54-18
x=36.
Required sum	= (2x+x)
=3x
=3x36
=108 years.
Answer D
Answer: D
Question: The length of a rectangle is two - fifths of the radius of a circle. The radius of the circle is equal to the side of the square, whose area is 900 sq.units. What is the area (in sq.units) of the rectangle if the rectangle if the breadth is 10 units?
Options:
A)140 sq.units
B)120 sq.units
C)187 sq.units
D)607 sq.units
E)815 sq.units
Rationale: Given that the area of the square = 900 sq.units
=> Side of square = √900 = 30 units
The radius of the circle = side of the square = 30 units
Length of the rectangle = 2/5 * 30 = 12 units
Given that breadth = 10 units
Area of the rectangle = lb = 12 * 10 = 120 sq.units
Answer: B
Answer: B
Question: Twenty-four men can complete a work in sixteen days. Thirty-two women can complete the same work in twenty-four days. Sixteen men and sixteen women started working and worked for twelve days. How many more men are to be added to complete the remaining work in 2 days?
Options:
A)48
B)24
C)36
D)16
E)None of the above
Rationale: 24 men complete the work in 16 days
∴ 16 men complete (16⁄24 × 12⁄16) = 1⁄2 part of work in 12 days
32 women complete the work in 24 days
∴ 16 women complete 16⁄32 × 14⁄24) = 7⁄24 part of work in (12 + 2 ) = 14 days
So, the remaining part of the work which is done by sixteen men + sixteen women and the reqd additional no. of men in 2 days
= 1 - (1⁄2 + 7⁄24) = 1⁄2 - 7⁄24 = 5⁄24 (part)
Now, in 2 days 5⁄24 part of the work is done by
24 × 16⁄2 × 5⁄24 = 40 men
Hence, the reqd. additional no. of men
= 40 – 16 = 24 men.
Answer B
Answer: B
Question: In a shop, the cost of 4 shirts, 4 pairs of trousers and 2 hats is $560. The cost of 9 shirts, 9 pairs of trousers and 6 hats is $1,290. What is the total cost of 1 shirt, 1 pair of trousers and 1 hat?
Options:
A)$150
B)$545
C)$214
D)$332
E)$199
Rationale: Let x be the price of one shirt, y be the price of one pair of trousers and z be the price of one hat.
4x + 4y + 2z = 560 :
9x + 9y + 6z = 1,290
3x + 3y + 2z = 430 : divide all terms of equation C by 3
x + y = 130 : subtract equation D from equation B
3(x + y) + 2z = 430 : equation D with factored terms.
3*130 + 2z = 430
z = 20 : solve for z
x + y + z = 130 + 20 = $150
correct answer A
Answer: A
Question: If Ryan has 20% more notebook than justin.and Ryan have 18 notebook then Justin have how many notebooks?
Options:
A)16
B)14
C)12
D)15
E)10
Rationale: lets Justin have x notebook.
(18-x)*100/x=20
1800-100x=20x
120x=1800
x=1800/120
x=15
answer D
Answer: D
Question: In a recent survey at a local deli, it was observed that 3 out of 5 customers bought a bagel and 5 out of 7 customers bought a coffee. Some customers bought both. If 6 customers are selected, what are the chances that at least 1 customer bought a coffee and a bagel?
Options:
A)27/343
B)3/7
C)27/125
D)776/965
E)9/125
Rationale: Let us take 7*5=35 as the total number of customers. So 7*3=21 customers bought a bagel and 5*5=25 customers bought a coffee.
chances that at least 1 customer bought a coffee and a bagel = 1 - chances that no customer bought a coffee and a bagel
chances that no customer bought a coffee and a bagel= 24/35*23/34*22/33*21/32*20/31*19/30=189/965
chances that at least 1 customer bought a coffee and a bagel= 1 -189/965 = 776/965
Answer D.
Answer: D
Question: A can do a piece of work in 10 days, B in 15 days. They work for 5 days. The rest of work finished by C in 2 days. If they get Rs 1500 for the whole work, the daily wages of B and C are?
Options:
A)275
B)250
C)225
D)300
E)335
Rationale: Part of work done by A = 5/10 = 1/2
Part of work done by B = 1/3
Part of work done by C = (1- (1/2 + 1/3)) = 1/6
A’s share : B’s share : C’s share = 1/2 : 1/3 : 1/6 = 3 : 2 : 1.
A’s share = (3/6) x 1500 = 750
B’s share = (2/6) x 1500 = 500
C’s share = (1/6) x 1500 = 250
A’s daily wages = 750/5 = 150/-
B’s daily wages = 500/5 = 100/-
C’s daily wages = 250/2 = 125/-
Daily wages of B & C = 100 + 125 = 225/-
ANSWER:C
Answer: C
Question: A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If two marbles are picked at random, what is the probability that they are either blue or yellow?
Options:
A)2/29
B)2/20
C)2/21
D)2/28
E)2/23
Rationale: Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles. Probability that both marbles are blue = ³C₂/¹⁵C₂ = (3 * 2)/(15 * 14) = 1/35
Probability that both are yellow = ²C₂/¹⁵C₂
= (2 * 1)/(15 * 14) = 1/105
Probability that one blue and other is yellow
= (³C₁ * ²C₁)/¹⁵C₂ = (2 * 3 * 2)/(15 * 14)
= 2/35
Required probability = 1/35 + 1/105 + 2/35
= 3/35 + 1/105 = 1/35(3 + 1/3)
= 10/(3 * 35)
= 2/21
Answer:C
Answer: C
Question: A rectangular field is to be fenced on three sides leaving a side of 80 feet uncovered.If the area of the field is 680 sq.ft, how many feet of fencing will be required?
Options:
A)44ft
B)97ft
C)22ft
D)11ft
E)66ft
Rationale: Given that length and area, so we can find the breadth.
Length x Breadth = Area
80 x Breadth = 680
Breadth = 8.5 feet
Area to be fenced = 2B + L = 2 (8.5) + 80 = 97 feet
Answer: B) 97ft
Answer: B
Question: How many 8 ′ s are there in the given sequence which are not immediately preceded by 09 and not immediately followed by 90?
9 0 8 0 9 0 9 8 9 0 8 9 0 8 0 9 8 9 0 9 8 0 9 8 9 0 8 9 0
Options:
A)3
B)1
C)2
D)More than 3
E)None of these
Rationale: the given logic is executed 3 times for 8's occuring at 2nd eight,5th eight and 7th eight in the sequence.
ANSWER:A
Answer: A
Question: The factorial expression 11!/2! is not divisible by which of the following integers?
Options:
A)3
B)5
C)6
D)7
E)None of these
Rationale: 11!/2! => 11 x 10 x 9 x 8x7x6x5x4x3
(A) 3 Can divide 3,12 or 9
(B) 5 Can divide 10
(C) 6 Can divide 12
(D) 7 can divide 7, 21, 42
Hence answer will be (E)
Answer: E
Question: A product when sold with 10% rebate on the listed price gave a profit of Rs.70. What was its cost price?
Options:
A)Rs. 200
B)Rs. 250
C)Rs. 300
D)Cannot be determined
E)None
Rationale: Solution
Since the marked price is not given, so the cost price cannot be determined.
Answer D
Answer: D
Question: The cash difference between the selling prices of an book at a profit of 12% and 20% is $3. The ratio of the two selling prices is:
Options:
A)55:23
B)52:33
C)52:53
D)45:53
E)14:15
Rationale: Let C.P. of the book be $x.
Then, required ratio = 112% of x / 120% of x
= 112/120 = 14/15 = 14:15
E
Answer: E
Question: Find the result of equation of the ellipse whose foci are at (0 , -5) and (0 , 5) and the length of its major axis is 14.
Options:
A)5
B)4
C)3
D)2
E)1
Rationale: From the coordinates of the foci, c = 5 and the major axis is the y axis. From the length of the major axis, we obtain a = 7. Also b 2 = a 2 - c 2 = 24.
The equation of the ellipse is given by
x 2 / 24 + y 2 / 49 = 1
correct answer is E) 1
Answer: E
Question: The average of first 10 natural numbers is?
Options:
A)5.7
B)5.5
C)5.6
D)5.4
E)5.2
Rationale: Sum of 10 natural no. = 110/2 = 55
Average = 55/10 = 5.5
Answer: B
Answer: B
Question: If 18 bindres bind 900 books in 10 days , How many binders will be required to bind 660 books in 12 days?
Options:
A)17
B)77
C)12
D)11
E)91
Rationale: Explanation:
Let the required no of binders be X.
Less books , Less binders (Direct Proportion)
More days, Less binders (Indirect proportion)
\inline \fn_jvn \left.\begin{matrix} Books\: 900:600\\ Days\: \: 12:10 \end{matrix}\right\}::18:x
\inline \fn_jvn \therefore \inline \fn_jvn (900\times 12\times x)=(600\times 10\times 18) \inline \fn_jvn \Leftrightarrow x= \inline \fn_jvn \frac{600\times 10\times 18}{900\times 12} = 11
Answer: D
Answer: D
Question: In the line xy plane line m has the equation y = 3x - 3, then the line m passes through which of the following points?
Options:
A)(3, 1)
B)(3, 4)
C)(4, 2)
D)(6, 9)
E)(6, 15)
Rationale: Yes it is y=3x-8....extremely sorry for mistake....
IF that's the case then answer is E
y=3x-8
15=3X6-3
15=18-3
15=15 (satisfied)
Answer: E
Question: How many Books each of Volume 100 meter cube can be packed into a crate of volume 3000 meter cube?
Options:
A)50
B)cannot be determined
C)150
D)300
E)350
Rationale: Gud question with a simple concept.
In geo if we want to insert one shape into another we need to know the dimensions of the two shapes.
In above with volume given , we can come up with different shapes, so we cant know the answer
For ex :3000 m3 can be 300*10 or 30*100 or just 3000*1 we don't know , so we cant calculate
Answer : B
Answer: B
Question: The average of 6 observations is 16. A new observation is included and the new average is decreased by 1. The seventh observation is?
Options:
A)1
B)3
C)9
D)6
E)7
Rationale: Let seventh observation = X.
Then, according to the question we have
=> (96 + X) / 7 = 15
=> X = 9
Hence, the seventh observation is 9.
ANSWER:C
Answer: C
Question: A zoo has an average of 510 visitors on Sundays and 480 on Saturday, 210 on other days and Wednesday is holiday. The average number of visitors in a month of 30 days starting with Saturday is
Options:
A)252
B)268
C)277
D)295
E)310
Rationale: Number of saturdays and sundays in that month is 5 and number of wednesdays in that month is 4.
Total number of visitors=(510x5)+(480x5)+((20-4)x210)=8310
Average visitor per day= 8310/30 = 277
Answer: C
Answer: C
Question: If the GCD of two numbers (not equal, both integers, greater than 1) is 2, then which of the following can be true?
A. They are prime.
B. They are consecutive.
C. They do not have a common prime factor.
D. They have a common factor other than 2.
Options:
A)Only A
B)Only B
C)Only C
D)Only D
E)A, B, C, and D
Rationale: The GCD of two numbers (not equal, both integers, greater than 1) is 2 means that they don't share factors other than 1 and 2.
This also means that both numbers are even ( divisible by 2.)
A. They are not prime. 2 is the only even number that is prime, so one number can be prime but the other number cannot be.
B. They are not consecutive. With two consecutive numbers, one will be even and one will be odd.
C. They have a common prime factor. The question defines the numbers as having a GCD of 2, which is prime.
D. They have a common factor other than 2. Both numbers have common factors of 2 and 1. For example:
The factors of 4 are 1 and 2, the factors of 6 are 1, 2, and 3.
Therefore, (D) is the only correct answer.
Answer: D
Question: A, B, C and D enter into partnership. A subscribes 1/3 of the capital B 1/4, C 1/5 and D the rest. How much share did A get in a profit of Rs.2490 ?
Options:
A)Rs. 820
B)Rs. 830
C)Rs. 840
D)Rs. 850
E)Rs. 890
Rationale: Explanation:
Let the total amount in the partnership be 'x'.
Then A's share = x/3
B's share = x/4
C's share = x/5
D's share = x - (x/3 + x/4 +x/5) = 13x/60
A : B : C : D = x/3 : x/4 : x/5 : 13x/60 = 20 : 15 : 12 : 13
A's share in the profit of Rs. 2490 = 20 (2490/60) = Rs. 830.
ANSWER IS B
Answer: B
Question: In Mrs. Susna's class, 1/4 of her students are getting an A, 1/2 are getting a B, 1/8 are getting a C, 1/12 are getting a D, and 1/24 are getting a F. What fraction of Mrs. Susna's class getting a passing grade of C or higher.
Options:
A)5/6
B)3/4
C)7/8
D)1/8
E)1/2
Rationale: If Mrs. Susna's class has 24 students, the number of students receiving As, Bs, or Cs, are 6, 12, and 3 respectively. That means 21/24 of her students are receiving passing grades or 7/8. (Answer:C)
Answer: C
Question: A, B and C shared the profit in a business in the ratio 5 : 7 : 8. They had partnered for 14 months, 8 months and 7 months respectively. What was the ratio of their investments?
Options:
A)20:64:49
B)49:20:64
C)64:20:49
D)64:49:20
E)20:49:64
Rationale: Ratio in which A,B and C shared the profit =5:7:8
Assume that the ratio of their investments =a:b:c
⇒14a:8b:7c=5:7:8⋯(A)
From (A),
14a:8b=5:7
⇒14a×7=8b×5
⇒7a×7=4b×5
⇒b=49a/20⋯(1)
From (A),
14a:7c=5:8
⇒(14a)×8=(7c)×5
⇒(2a)×8=c×5
⇒c=16a/5⋯(2)
a:b:c=a:49a/20:16a/5
=1:49/20:16/5
=20:49:64
Answer is E.
Answer: E
Question: Find the probability that a number selected from numbers 1, 2, 3,...,45 is a prime number, when each of the given numbers is equally likely to be selected?
Options:
A)10/45
B)14/45
C)8/45
D)3/45
E)7/45
Rationale: Let X be the event of selecting a prime number.
X = {2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41,43}
n(X) = 14,
n(S) = 45
Hence, the required probability is 14/45.
ANSWER:B
Answer: B
Question: If log 27= 1.431, then the value of log 9 is:
Options:
A)0.934
B)0.945
C)0.954
D)0.958
E)0.959
Rationale: log 27 = 1.431 => log 33 = 1.431
=> 3 log 3= 1.431 => log 3 = 0.477
Therefore, log 9 = log 32 = 2 log 3 = (2*0.477) = 0.954
ANSWER:C
Answer: C
Question: If (2^16)(25^S) = 5(10^m) what is the value of m ?
Options:
A)7
B)8
C)15
D)16
E)23
Rationale: given
2^16 * 25^s = 5 * 10^2
=> 2^16 * 5^(2s) = 2^m * 5^(m+1)
Ans D
on comparing the power of 2 => m=16
Answer: D
Question: What least number must be subtracted from 42398 so that remaining no.is divisible by 15
Options:
A)3
B)5
C)6
D)8
E)9
Rationale: Explanation:
On dividing 42398 by 15 we get the remainder 8, so 8 should be subtracted
Option D
Answer: D
Question: A tourist purchased a total of $2,500 worth of traveler’s checks in $10 and $50 denominations, During the trip the tourist cashed 7 checks and then lost all of the rest. If the number of $10 checks cashed was one more or one less than the number of $50 checks cashed, what is the minimum possible value of the checks that were lost?
Options:
A)$1,430
B)$1,310
C)$1,290
D)$2,270
E)$2,150
Rationale: Let the number of $10 checks cashed beT
Let the number of $50 checks cashed beF
7 checks cashed;
T+F=7
Now; T can be F+1 OR T can be F-1
Let's check both conditions;
T=F+1
T+F=7
F+1+F=7
2F=6
F=3
T=4
Value cashed = 3*50+4*10=150+40=$190
Let's check the other condition as well;
T=F-1
T+F=7
F-1+F=7
2F=8
F=4
T=3
Value cashed = 4*50+3*10=200+30=$230
The more money he cashes, the less loss he incurs. Thus, we must consider the latter case.
Value cashed = $230
Value lost = 2500-230 = $2270
Ans:D
Answer: D
Question: The seating chart of an airplane shows 30 rows of seats. Each row has 3 seats on each side of the center aisle, and one of the seats on each side is a window saet. The view from the window seats in 6 of the rows is obscured by the wings of the airplane. If the first person to be assigned a seat is assigned a window seat and thw window seat is assigned randomly, what is the probability that the person will get a seat with an unobscured view?
Options:
A)1/6
B)1/3
C)2/3
D)5/6
E)4/5
Rationale: priyalr
6 seats per row, think of a boeing 737. We have 30 rows, therefore window 30 seats one one side and 30 window seats on the other, totaling 60 window seats on the whole plane.
the view of the window of 6 rows is blocked. two wings, therefore 12 window seats are blocked.
Total window seats = 60
Total blocked window seats = 12
Total unblocked seats = 48
We know that a window seat was given, therefore probability for not window seat is 48/60 =4/5
ANS E
Answer: E
Question: A stock trader originally bought 300 shares of stock from a company at a total cost of m dollars. If each share was sold at 80% above the original cost per share of stock, then interns of m for how many dollars was each share sold?
Options:
A)a) 2m/300
B)b) 9m/1500
C)c) m/200
D)d) m/300 + 50
E)e) 350/m
Rationale: Let Cost of 300 shares be $ 3000
So, Cost of 1 shares be $ 10 =>m/300
Selling price per share = (100+80)/100 * m/300
Or, Selling price per share = 9/5 * m/300 => 9m/1500
Hence answer will be (B)
Answer: B
Question: A person can row at 9 kmph and still water. He takes 4 1/2 hours to row from A to B and back. What is the distance between A and B if the speed of the stream is 1 kmph?
Options:
A)33
B)77
C)26
D)28
E)20
Rationale: Let the distance between A and B be x km.
Total time = x/(9 + 1) + x/(9 - 1) = 4.5
=> x/10 + x/8 = 9/2 => (4x + 5x)/40 = 9/2 => x = 20 km.
Answer: E
Answer: E