divelab/Sys2Bench huggingface dataset:
Question: A bag contains 3 blue and 5 white marbles. One by one, marbles are drawn out randomly until only two are left in the bag. What is the probability C that out of the two, one is white and one is blue?
Options:
A)15/56
B)41/56
C)13/28
D)15/28
E)5/14
Rationale: The required probability C= probability of choosing 6 balls out of the total 8 in such a way that we remove 4 out of 5 white and 2 out of 3 blue balls.
Ways to select 6 out of total 8 = 8C6
Ways to select 4 out of 5 white balls = 5C4
Ways to select 2 out of 3 blue balls = 3C2
Thus the required probability = (5C4*3C2)/8C6 = 15/28.
D is thus the correct answer.
Answer: D
Question: Of 120 applicants for a job, 56 had at least 4 years' experience, 72 had degrees, and 12 had less than 4 years' experience and did not have a degree.How many of the applicants had at least 4 years' experience and a degree?
Options:
A)10
B)15
C)22
D)20
E)24
Rationale: 120 - 12 = 108
108 - 56 - 72 = -20
Then 20 are in the intersection between 4 years experience and degree.
Answer : D
Answer: D
Question: Eleven books consisting of 5 financial management, 4 marketing management and 2 system management are placed on a shelf at random order. What is the probability that the books of each kind are all together.
Options:
A)1/1155
B)1/1255
C)1/1355
D)1/1455
E)1/1555
Rationale: (Probability of an event) = (Favorable) / (Total)
The total number of ways to arrange 11 books in a row is 11!.
3 groups of books: financial management (F), marketing management (M) and system management (S), can be arranged in 3! ways: FMS, FSM, MFS, MSF, SFM, and SMF (this way all the books of each kind will be together). Now, books in F itself can be arranged in 5! ways, in M in 4! ways and in S in 2! ways. Hence, the total number of ways to arrange books so that books of each kind are together is 3!*5!*4!*2!.
P = (3!*5!*4!*2!) / 11! = 1/1155.
Answer: A
Answer: A
Question: The inverse ratio of 3: 2: 1 is?
Options:
A)2:3:8
B)4:3:6
C)2:3:2
D)2:3:6
E)2:3:1
Rationale: 1/3: 1/2: 1/1
= 2:3:6
Answer: D
Answer: D
Question: Which of the following MUST yield an integer when divided by 11?
Options:
A)The sum of eleven consecutive positive integers.
B)The square of a prime number.
C)The sum of two odd integers.
D)The product of three consecutive odd numbers.
E)The difference between a multiple of 8 and a multiple of 3.
Rationale: For option A: Let the numbers be (x-5), (x-4), (x-3), (x-2), (x-1), (x), (x+1), (x+2), (x+3), (x+4), (x+5).
Now, (x-5)+(x-4)+(x-3)+(x-2)+(x-1) + (x) + (x+1) + (x+2)+(x+3)+(x+4)+(x+5) = 11(x). Hence A is true. No need to check other answers since there can only be one correct answer.
So, Ans(A).
Answer: A
Question: A coach must choose five starters from a team of 12 players. How many different ways can the coach choose the starters ?
Options:
A)722
B)729
C)278
D)299
E)271
Rationale: Explanation:
Choose 5 starters from a team of 12 players. Order is not important.
\inline {\color{Black} 12C_{5}}= 729
Answer: B) 729
Answer: B
Question: Barbata invests $2400 in the National Bank at 5%. How much additional money must she invest at 8% so that the total annual income will be equal to 8% of her entire investment?
Options:
A)1200
B)3000
C)1000
D)3600
E)2400
Rationale: Let the additional invested amount for 8% interest be x;
Equation will be;
2400+0.05*2400+x+0.08x = 2400+x+0.08(2400+x)
0.05*2400+0.08x = 0.06x+0.08*2400
0.02x = 2400(0.08-0.05)
x = 2400*0.03/0.02 = 3600
Ans:D
Answer: D
Question: One side of the bottom layer of a triangular pyramid has 12 balls. How many are there in the whole pyramid?Note that the pyramid is equilateral and solid.
Options:
A)286
B)364
C)504
D)164
E)165
Rationale: As there are 12 balls along one side, it means that there are 12 layers of balls. The top most layer has 1 ball. The second layer has 3 (1+2) balls. The third layer has 6 (1+2+3) balls. The fourth layer has 10 (1+2+3+4) balls. The fifth layer has 15 (1+2+3+4+5) balls. Similarly, there are 21, 28, 36, 45, 55, 66 and 78 balls in the remaining layers.
Hence, the total number of balls are
= 1 + 3 + 6 + 10 + 15 + 21 +28 + 36 + 45 + 55 + 66 + 78
= 364 balls
ANSWER:B
Answer: B
Question: Marcella has 25 pairs of shoes. If she loses 9 individual shoes, what is the greatest number of matching pairs she could have left?
Options:
A)21
B)20
C)19
D)16
E)15
Rationale: greatest number of paired shoes means greatest number of lost pairs
9 shoes have 4 pairs and 1 extra shoes of a pair .so a otal of 5 pairs she loses
leftover pair=20
ANSWER:B
Answer: B
Question: A welder received an order to make a 1 million liter cube-shaped tank. If he has only 4x2 meter sheets of metal that can be cut, how many metal sheets will be required for this order Y? (1 cubic meter = 1,000 liters)
Options:
A)92
B)90
C)82
D)78
E)75
Rationale: I get 75. A cube with 1 million liters cube would be a cube with the dimensions of 100*100*100. 4*2 covers 8 sq liters so 100/8 = 12.5.
Y=12.5*6 = 75.E
Answer: E
Question: A merchant can buy goods at the rate of Rs. 20 per good. The particular good is part of an overall collection and the value is linked to the number of items that are already on the market. So, the merchant sells the first good for Rs. 2, second one for Rs. 4, third for Rs. 6…and so on. If he wants to make an overall profit of at least 40%, what is the minimum number of goods he should sell?
Options:
A)24
B)18
C)27
D)32
E)34
Rationale: DETAILED SOLUTION
Let us assume he buys n goods.
Total CP = 20n
Total SP = 2 + 4 + 6 + 8 ….n terms
Total SP should be at least 40% more than total CP
2 + 4 + 6 + 8 ….n terms ≥ 1.4 * 20 n
2 (1 + 2 + 3 + ….n terms) ≥ 28n
n(n + 1) ≥ 28n
n2 + n ≥ 28n
n2 - 27n ≥ 0
n ≥ 27
He should sell a minimum of 27 goods.
Answer Choice (C)
Answer: C
Question: 65% of x = 20% of 747.50. Find the value of x?
Options:
A)100
B)230
C)150
D)180
E)199
Rationale: 65% of x = 20% of 747.50
Then, 65/100 * x = 20/100 * 7475/10
x = 230
Answer is B
Answer: B
Question: The sum of two numbers is 528 and their H.C.F is 33. The number of pairs of numbers satisfying the above conditions is:
Options:
A)4
B)5
C)6
D)6
E)1
Rationale: Let the required numbers be 33a and 33b.
Then, 33a + 33b = 528 => a + b = 16.
Now, co-primes with sum 16 are (1, 15), (3, 13), (5, 11) and (7, 9).
Required numbers are (33 * 1, 33 * 15), (33 * 3, 33 * 13), (33 * 5, 33 * 11), (33 * 7, 33 * 9).
The number of such pairs is 4.
Answer:A
Answer: A
Question: The population of a bacteria culture doubles every 2 minutes. Approximately how many minutes will it take for the population to grow from 1,000 to 200,000 bacteria
Options:
A)10
B)12
C)14
D)16
E)18
Rationale: The question basically asks how many minutes it takes for a population to increase by factor 200 (200,000 / 1,000 = 200).
Now you know that every two minutes the population doubles, i.e. is multiplied by 2. So the equation becomes:
2^x >= 200, where x represents the number of times the population doubles. A lot of people remember that 2^10 = 1,024. Hence, 2^8 = 256, i.e. the population has to double 8 times.
Since it takes the population 2 minutes to double once it takes 8*2 minutes = 16 minutes to double 8 times.
Thus, solution D = 16 is correct.
Answer: D
Question: A train 240 m long passed a pole in 24 sec. How long will it take to pass a platform 500 m long?
Options:
A)65sec
B)70sec
C)74sec
D)80sec
E)85sec
Rationale: Speed = 240/24 = 10 m/sec.
Required time = (240 + 500)/10 = 74 sec.
Answer:C
Answer: C
Question: The average temperature of a city in the first four days of a month was 36°. The average for the 2nd, 3rd, 4th and 5th day was 38°. If the temperature of the 1st and 5th day were in the ratio 4 : 5, then what is the temperature on the fifth day ?
Options:
A)40°
B)49°
C)43°
D)41°
E)42°
Rationale: Explanation:
The temperature for first 4 days = 4 * 36 = 144
The temperature for last 4 days = 4 * 38 = 152
The difference between the temperatures is (152 – 144) = 8
The ratio of temperature between first and fifth day is 4 : 5
The temperature on fifth day is 5*8 = 40
ANSWER: A
Answer: A
Question: A bird shooter was asked how many birds he had in the bag. He replied that there were all sparrows but six, all pigeons but six, and all ducks but six. How many birds he had in the bag in all?
Options:
A)9
B)18
C)27
D)36
E)34
Rationale: all sparrows bt six i.e. those six can b 3 pigeons and 3 ducks,
similarly the other 2 conditions will apply..
ANSWER:A
Answer: A
Question: Find the number which multiplied by 15 is increased by 196.
Options:
A)14
B)20
C)26
D)28
E)27
Rationale: Let the number be x. Then,
15x - x = 196
x = 14
ANSWER:A
Answer: A
Question: When Tom works alone he chops 2 lb. salad in 3 minutes, and when Tammy works alone she chops 3 lb. salad in 2 minutes. They start working together, and after some time finish chopping 65 lb. of salad. Of those 80 lb., the salad quantity chopped by Tom is what percent lesser than the quantifying chopped by Tammy?.
Options:
A)44%
B)100%
C)105%
D)225%
E)125%
Rationale: Tom chops 4 lbs in 6 minutes
Tammy chops 9 lbs in 6 minutes
So in the same amount of time, Tom chops 125% less than Tammy, since 9 is 125% greater than 4. So 125% is the answer.
Note that the actual time doesn't matter. If you multiply the time each work by x, you'll multiply the work each does by x, and 9x is still 125% greater than 4x.
Ans:E
Answer: E
Question: If a randomly selected non-negative single digit integer is added to {2, 3, 4, 8}. What is the probability that the median of the set will increase but the range still remains the same?
Options:
A)0.2
B)0.3
C)0.4
D)0.5
E)0.6
Rationale: We are selecting from non-negative single digit integers, so from {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}. These 10 digits represent the total number of outcomes.
Hence, the total number of outcomes is 10.
We need to find the probability that the median of the set will increase but the range still remains the same.
The median of the set is (3 + 4)/2 = 3.5, thus the number selected must be 4 or greater.
For the range to remain the same, the number must be between 2 and 8 inclusive.
To satisfy both conditions, the number selected must be 4, 5, 6, 7, or 8.
The probability is 5/10 = 0.5
The answer is D.
Answer: D
Question: In a survey conducted to find out the readership of three Newspapers A,B and C, it was found that the number of newspaper A is at least 20 and at most 40. The number of people who read newspaper B is at least 50 and at most 70. The number of people who read newspaper C is at least 70 and at most 83. It was also found that 5 people read all three newspapers. Find the minimum number of people who read both A and B but not C.
Options:
A)A)1
B)B)2
C)C)3
D)D)0
E)E)5
Rationale: I wish I could draw a diagram to show you but by giving you number A and B, it might help a little.
A and B and C is 5 - that means A and B is at least 5. This seems trivial given the value intervals of A and B but definitely helps to think through how to minimize A and B but not C
A and B but not C = |A|-|B| - 5
So i would pick A=25 and B =50 to minimize the value to a 0. (ANS D)
Answer: D
Question: 6% of customers that enter a store on any given day must not pay tax. If 1000 people shop every day, how many people pay taxes in the store every week
Options:
A)6500
B)6580
C)7200
D)7120
E)6800
Rationale: 6% of customers do not pay taxes.
6/100 * 1000 customers do not pay taxes.
6/100 * 1000 = 60
Therefore 1000 - 60 customers do pay taxes.
1000 - 60 = 940
940 * 7 days per week = 6580
B)
Answer: B
Question: A taxi owner buys diesel at Rs.8.50, Rs. 9 and Rs. 9.50 per litre for three successive years. What approximately is the average cost per litre of diesel if he spends Rs. 5000 each year?
Options:
A)7.98
B)8.98
C)9.98
D)6.98
E)8.12
Rationale: Total Cost = 5000 × 3=15000
Total diesel used = 5000/8.50 + 5000/9 +5000/9.50
=588+555+527
=1670
Average cost per litre of diesel=15000/1670
=8.98
ANSWER:B
Answer: B
Question: With the wind, an airplane travels 1120 miles in seven hours. Against the wind, it takes eight hours. Find the rate of the plane in still air and the velocity of the wind.
Options:
A)10 kmph
B)11 kmph
C)12 kmph
D)13 kmph
E)14 kmph
Rationale: 1120 miles in seven hrs that means up speed is 1120/7=160.
for against the wind 1120 miles in 8 hrs so down speed 1120/8=140.
now plain speed in still air=1/2(160+140)=150 kmph
wind speed=1/2(160-140)=10 kmph
ANSWER:A
Answer: A
Question: x = 13.165
y = 7.496
z = 11.557
The number A is obtained by first rounding the values of x, y, and z to the hundredths place and then adding the resulting values. The number B is obtained by first adding the values of x, y, and z and then rounding the sum to the hundredths place. What is the value of A – B?
Options:
A)0.01
B)0.02
C)0.03
D)0.1
E)0.2
Rationale: Rounding off the values:
x = 13.17
y = 7.50
z = 11.56
A = 13.17 + 7.50 + 11.56= 32.23
x + y + z = 13.165 + 7.496 + 11.557 = 32.206
B = 32.21
A - B = 0.02
Option B
Answer: B
Question: If a 3-number code is formed of the integers from 1 to 14 inclusively, and each of the numbers in the code is different, how many possible codes are there?
Options:
A)1744
B)1854
C)1964
D)2074
E)2184
Rationale: 14*13*12=2184
The answer is E.
Answer: E
Question: If a car travels a distance of 300 km in 8 hours, partly at a speed of 40 kmh-1 and partly at 30 kmh-1, what is the distance it travelled at the speed of 40 kmh-1?
Options:
A)200 km
B)210 km
C)220 km
D)240 km
E)250 km
Rationale: let the distance travelled at 40 kmph=x km
distance travelled at 30 kmph =300-x km
x/40 + (300-x)/30 = 8
x = 240
ANSWER:D
Answer: D
Question: If the length of the longest chord of a certain circle is 18, what is the radius of that certain circle?
Options:
A)2.5
B)9
C)10
D)15
E)20
Rationale: Longest chord of a circle is the diameter of the circle
diameter = 2 * radius
If diameter of the circle is given as 18 = 2 * 9
so radius of the circle = 9
correct answer - B
Answer: B
Question: Nick took a bus from home to market, that travels at 80 kmph. While walking back at 8 kmph,
halfway through, he suddenly realized he was getting late and he cycled back the remaining distance in 60 kmph. Find the average speed.
Options:
A)49.5 kmph
B)49.0 kmph
C)48.5 kmph
D)48.0 kmph
E)none of these
Rationale: Let the distance be 2x(one way)
Time taken by bus = 2x/80, by walking =x/8, by cycling = x/60 hours
:. Average speed = Total Distance/Total time
= 8x / x/40 + x/8 + x/60
= 8 *60 / 1.5+7.5+1
= 12.0
ANSWER:D
Answer: D
Question: At the faculty of Aerospace Engineering, 310 students study Random-processing methods, 232 students study Scramjet rocket engines and 112 students study them both. If every student in the faculty has to study one of the two subjects, how many students are there in the faculty of Aerospace Engineering?
Options:
A)430
B)432
C)440
D)442
E)446
Rationale: 310 + 232 - 112 (since 112 is counted twice )= 430
A is the answer
Answer: A
Question: In a particular course, only two grades are given all semester: the midterm exam, which counts for 25% of the semester grade, and the final exam, which counts for the remainder. Lindsey's semester grade was 88%. If the highest possible score on either exam is 100%, what is the lowest possible A score that Lindsey could have received on her midterm exam?
Options:
A)52%
B)64%
C)72%
D)76%
E)80%
Rationale: If the midterm counts for 25% of the total grade, then the final exam must count for the remaining 75%, meaning that in this weighted average problem the final is weighted 3 times as much as the midterm. Using the weighted average mapping strategy, then, and maximizing her final exam score so that you minimize her midterm score, you have:
100-------------88----------------------------x
And you know that the ratio is 3:1. Since the final exam score of 100 is weighted heavier, then the difference of 12 between 100 and 88 is the1part of the ratio, meaning that 3(12) is the 3 portion. That equals 36, so the midterm score (x) is 36 less than the weighted average of 88. 88 - 36 = 52, sothe correct answer is 52%.
Answer: A
Question: The length of the bridge, which a train 130 meters long and travelling at 45 km/hr can cross in 30 seconds, is?
Options:
A)176 m
B)189 m
C)245 m
D)189 m
E)197 m
Rationale: Speed = (45 * 5/18) m/sec
= (25/2) m/sec. Time
= 30 sec. Let the length of bridge be x meters. Then, (130 + X)/30 = 25/2 ==> 2(130 + X)
= 750 ==> X = 245 m.
Answer:C
Answer: C
Question: The rate of a certain chemical reaction is directly proportional to the square of the concentration of chemical A present and inversely proportional to the concentration of chemical B present. If the concentration of chemical B is increased by 40%, which of the following is closest to the percent change in the concentration of chemical A required to keep the reaction rate unchanged?
Options:
A)100% decrease
B)50% decrease
C)40% decrease
D)40% increase
E)50% increase
Rationale: The rate of reaction is invesrsly proportional to the concentration of chemical B present. It used to have B=1 . Now that B is increased by 40%. So the new equation would be 2B=(1/2). In order for the rate of reaction to still be 1, we need to change the concentration of A to yield a 2. It used to be A^2=1, now the new equation should be (sqrt(2)*A)^2=2. The change in the concentration of A can be calculated as (sqrt(2) -1)/1 or approximately 40% increase. Answer B.
Answer: B
Question: Jill works as a waitress at the local diner where she earns an hourly wage of $8.00 per hour and a standard tip rate of 30% of the cost of the orders she serves. If she worked four 12-hour shifts this week and averaged $40 in orders per hour, how much did Jill earn this week?
Options:
A)1120
B)300
C)320
D)350
E)400
Rationale: Jill earns 8 dollars/hour and the hourly tip is (3/10)*40.
Jill thus earns 8*14+14*12 per day(or 8(14)+12(14)=20(14)=280).
Jill has worked for 4 days -> 280*4=1120.
This matches answer choice A.
Answer: A
Question: Which number is a factor of 20?
Options:
A)3
B)4
C)7
D)18
E)9
Rationale: A whole number that divides exactly into another whole number is called a factor
20/5 =4
answer B
Answer: B
Question: A and B play a series of 5 games in badminton. A's chance of winning s single game against B is 2/3. Find the chance that A wins exactly 3 games.
Options:
A)64/81
B)35/128
C)80/243
D)None of these
E)cannot be determined
Rationale: Explanation :
Here, each game is a trial and A's winning the game is a success. All games are independent , so, using the binomial distribution.
P(X) = nCx px(1 - p)n-x.
Where, x= wins exactly 3 games
=> x = 3.
p= 2/3, 1-p=1/3, n=5.
P(3) = 5C3 (2/3)3(1/3)2 .
=> 10 x (2(3)/3(5)).
=> 80/243.
Answer : C
Answer: C
Question: 852.68 âˆ’ 4.5 + 108.94 = ? âˆ’ 2132.54
Options:
A)6078.58
B)5225.9
C)6078.54
D)6088.58
E)None
Rationale: Option 'C'
Answer: C
Question: A bag contains 6 red balls, 5 green balls and 6 white balls. A ball is drawn at
random from the box. What is the probability that the ball drawn is either red or green?
Options:
A)2/5
B)3/5
C)11/17
D)7/15
E)8/15
Rationale: Total number of balls = (6 + 5 + 6) = 17.
Therefore, n(S) = 17.
Let E1 = event of drawing a red ball.
and E2 = event of drawing a green ball.
Then, E1 n E2 = f.
P (E1 n E2) = P(E1) + P(E2) = (6/17 + 5/17) = 11/17.
ANSWER:C
Answer: C
Question: A train 240 m long passed a pole in 24 sec. How long will it take to pass a platform 650 m long?
Options:
A)99 sec
B)89 sec
C)54 sec
D)27 sec
E)22 sec
Rationale: Speed = 240/24 = 10 m/sec.
Required time = (240 + 650)/10
= 89 sec.
Answer: B
Answer: B
Question: What will be the cost of building a fence around a square plot with area equal to 49 sq ft, if the price per foot of building the fence is Rs. 58?
Options:
A)3944
B)1624
C)2999
D)2667
E)2121
Rationale: Let the side of the square plot be a ft.
a2 = 49=> a = 7
Length of the fence = Perimeter of the plot = 4a = 28 ft.
Cost of building the fence = 28 * 58 = Rs. 1624.
Answer: B
Answer: B
Question: A standard Veggiematik machine can chop 36 carrots in 4 minutes. How many carrots can 6 standard Veggiematik machines chop in 8 minutes?
Options:
A)36
B)54
C)108
D)216
E)432
Rationale: ONE Veggiematik machine can chop 36 carrots in 4 minutes
So, ONE Veggiematik machine can chop (1.5)(36) carrots in (1.5)(4) minutes
In other words, ONE Veggiematik machine can chop 54 carrots in8minutes
So,SIXVeggiematik machines can chop (8)(54) carrots in6minutes
In other words, SIX Veggiematik machines can chop 432 carrots in8minutes
Answer: E
Question: Two numbers are in the ratio of 5:8. If 30 be subtracted from each, they are in the ratio of 5:9. Find the numbers?
Options:
A)122,195
B)121,199
C)120,192
D)102,192
E)126,109
Rationale: (5x-30):(8x-30) = 5:9
x = 24=> 120,192
Answer: C
Answer: C
Question: A cistern of 475 litres is completely filled using pipes A and B, with Pipe A being open for 5 more hours than pipe B. If we are to interchange the operating hours of the two pipes than pipe A would have pumped half the water as much as pipe B, then find the time for which pipe B was open. Also, given that if the two pipes were open simultaneously the tank would fill in 19 hours.
Options:
A)10 h
B)14 h
C)16 h
D)20 h
E)24 h
Rationale: DETAILED SOLUTION
The 475 litres is filled in 19 hours by the two pipes when they are opened simultaneously.
Therefore, rate of water flow by A and B,
A + B = 47519 = 25 litres/hour………….(1)
Let pipe B was opened for t hours
Then, pipe A was opened for t + 5 hours
A x (t+5) + B x t = 475
(A + B) x t + 5A = 475
25t + 5A = 475
=) 5t + A = 95
Now, using option analysis
a) t = 10 =) 5 x 10 + A = 95 =) A = 45 (not possible from (1))
b) t = 14 =) 5 x 14 + A = 95 =) A = 25 (not possible from (1) as B can’t be zero)
c) t = 16 =) 5 x 16 + A = 95 =) A = 15
CORRECT ANSWER C
Answer: C
Question: Ram professes to sell his goods at the cost price but he made use of 800 grms instead of a kg, what is the gain percent?
Options:
A)11 1/7%
B)11 7/7%
C)11 1/9%
D)71 1/9%
E)25%
Rationale: 800 --- 200
100 --- ? => 25%
Answer:E
Answer: E
Question: How many three letter words are formed using the letters of the word TIME?
Options:
A)66
B)57
C)88
D)24
E)21
Rationale: The number of letters in the given word is four.
The number of three letter words that can be formed using these four letters is 4P3
= 4 * 3 * 2 = 24.
Answer: D
Answer: D
Question: A tradesman by means of his false balance defrauds to the extent of 15%? in buying goods as well as by selling the goods. What percent does he gain on his outlay?
Options:
A)44%
B)48%
C)32%
D)45%
E)34%
Rationale: g% = 15 + 15 + (15*15)/100
= 32%
Answer: C
Answer: C
Question: Rachel and Sarah started out to visit Grandma. They drove for 50 miles and stopped to rest
before driving for 30 more miles. They decided to go back 10 miles to a restaurant they had seen.
After leaving the restaurant, they drove 80 more miles to Grandma’s house. How many miles did the
girls drive on the way to Grandma’s house?
Options:
A)150 miles
B)160 miles
C)170 miles
D)180 miles
E)200 miles
Rationale: 50 + 30 = 80 to turn around
80 + 10 = 90 backtrack to restaurant
90 + 80 = 170 miles is total distance driven
correct answer C
Answer: C
Question: 20 beavers, working together in a constant pace, can build a dam in 3 hours. How many hours C will it take 12 beavers that work at the same pace, to build the same dam?
Options:
A)2.
B)4.
C)C=5.
D)C=6.
E)8.
Rationale: C. 5 hrs
If there were 10 beavers it qould have taken double C= 6hrs.. so closest to that option is 5.
Answer: C
Question: The number x of cars sold each week varies with the price y in dollars according to the equation x = 800,000 – 50y. What would be the total weekly revenue R, in dollars, from the sale of cars priced at $ 15,000?
Options:
A)50,000
B)750,000
C)850,000
D)7,500,000
E)R=750,000,000
Rationale: number of cars sold = x=800000-50y
y= 15000
x=800000-750000=50000
revenue from 50000 cars=15000*50000=750000000 E
Answer: E
Question: In an examination, 300 students appeared. Out of these students; 26 % got first division, 54 % got second division and the remaining just passed. Assuming that no student failed; find the number of students who just passed.
Options:
A)33
B)37
C)54
D)60
E)01
Rationale: The number of students with first division = 26 % of 300 = 26/100 × 300 = 7800/100 = 78
And, the number of students with second division = 54 % of 300
= 54/100 × 300
=16200/100
= 162
Therefore, the number of students who just passed = 300 – (78 + 162) = 60
Answer:D
Answer: D