divelab/Sys2Bench huggingface dataset:
Question: X can do a piece of work in 40days. He works at it for 8days and then Y finished it in 32 days. How long will Y take to complete the work?
Options:
A)10
B)40
C)15
D)18
E)20
Rationale: Work done by X in 8days = 8*1/40 = 1/5
Remaining work = 1 - 1/5 = 4/5
4/5 work is done by Y in 32 days
Whole work will be done by Y in 32*5/4 = 40 days
Answer is B
Answer: B
Question: A train 150 m long running at 72 kmph crosses a platform in 25 sec. What is the length of the platform?
Options:
A)288
B)236
C)350
D)299
E)266
Rationale: D = 72 * 5/18 = 25 = 500 – 150 = 299.Answer:C
Answer: C
Question: 8, 24, 12, 36, 18, 54, (....)
Options:
A)27
B)68
C)107
D)108
E)28
Rationale: 8 × 3 = 24
24 ÷ 2 = 12
12 × 3 = 36
36 ÷ 2 = 18
18 × 3 = 54
54 ÷ 2 = 27
Answer is A
Answer: A
Question: Mixture of milk & water has been kept in two separate bowl. Ratio of milk to water in one of the bowls is 5 : 1 and that in the other bowl 7 : 2. In what ratio the mixtures of these 2 bowl should be added together so that the quantity of milk in the new mixture may become 80%?
Options:
A)2:3
B)3:5
C)4:5
D)5:7
E)6:11
Rationale: Lett. mixtures of the two containers be added together in the ratio of x
= = [ixoox l00%
Since the percentage quantity ofmilk in the new mixture is SO% — so% (45x + 42y) x 5 4 x 54(x y) 225x 210y 216.3E+216y
9x=6y
x:y=2:3
A
Answer: A
Question: If Q is a negative integer, which of the following must be a negative integer?
Options:
A)Q + 1
B)Q/2+3
C)Q^4
D)Q – y
E)Q^11
Rationale: We need to check each option here:
A. Q + 1
This will depend on the value of Q. Nothing can be said
B. Q/2+3
This will depend on the value of Q. Nothing can be said
C. Q^4
This will always be positive. Even powers of negative numbers are positive and odd powers are negative
D. Q – y
This will depend on the value of Q. Nothing can be said
E. Q^11
This will always be negative. Even powers of negative numbers are positive and odd powers are negative
Correct Option: E
Answer: E
Question: When tossed, a certain coin has equal probability of landing on either side. If the coin is tossed 3 times, what is the probability that it will land on the same side each time?
Options:
A)1/8
B)1/4
C)1/3
D)3/8
E)1/2
Rationale: Winning scenario is if we'll have either three tails (TTT) or three heads (HHH): 1/2*1/2*1/2+1/2*1/2*1/2=1/4.
Answer: B.
Answer: B
Question: Samantha's investment portfolio consists of three stocks: an airline, a bank, and a computer company. In the month of February, the price of the airline's stock rose by 10%, that of the bank decreased by 10% and that of the computer company also decreased by 15%, but the overall value of her portfolio increased. If Samantha owns equal amounts of all three stocks, which of the following could be the initial prices of the three stocks in the order airline, bank, and computer company respectively?
Options:
A)$55, $85, $40
B)$65, $60, $60
C)$85, $55, $45
D)$85, $25, $20
E)$25, $60, $70
Rationale: Since Samantha owns equal amounts of stocks, the 10% increase alone should set off the 10% and 15% decrease in each of the other two stocks. i.e The stock which increased should have a substantially higher value than the two stocks which decreased. Between B and C, C is obviously the safer bet and is the right answer.
Answer is C.
Answer: C
Question: A customer pays 70 dollars for a coffee maker after a discount of 20 dollars
What is the original price of the coffe maker?
Options:
A)A)$50
B)B)$60
C)C)$70
D)D)$80
E)E)$90
Rationale: Let x be the original price.
x - 20 = 70
x - 20 + 20 = 70 + 20
x + 0 = 90
x = 90
correct answer is E)$90
Answer: E
Question: 27 men working 8 hours per day dig 30 m deep. How many extra men should be put to dig to a depth of 50 m working 6 hours per day?
Options:
A)33
B)66
C)88
D)100
E)281
Rationale: (27 * 8)/30 = (x * 6)/50 => x =60
60 – 27 = 33
Answer: A
Answer: A
Question: We run a business that rents out canoes and kayaks. A canoe rental costs $15 per day, and a kayak rental costs $18 dollars per day. One day, our business rents out 3 canoes for every 2 kayaks and receives a total of $405 in revenue. How many more canoes than kayaks were rented out?
Options:
A)5
B)6
C)7
D)8
E)9
Rationale: Let x be the number of canoes.
Then 2x/3 is the number of kayaks.
15x+(2x/3)*18=405
15x+12x=405
27x=405
x=15 (canoes)
2x/3=10 (kayaks)
There were 15-10 = 5 more canoes rented out.
The answer is A.
Answer: A
Question: The present age of a father is 3 years more than three times the age of his son.Three years hence,father as age will be 10 years more than twice the age of the son.Find the present age of the father.
Options:
A)88
B)77
C)33
D)44
E)55
Rationale: Explanation:
Let the present age be 'x' years. Then father's present age is 3x+3 years. Three years hence (3x+3)+3=2(x+3)+10 x=10 Hence father's present age = 3x+3 =[ (3 x 10) + 3] = 33 years.
Answer: C
Answer: C
Question: What amount does Kiran get if he invests Rs. 18000 at 15% p.a. simple interest for two years?
Options:
A)29893
B)27773
C)29989
D)28800
E)23400
Rationale: Simple interest = (18000 * 2 * 15)/100 = Rs. 5400
Amount = P + I = 18000 + 5400 = Rs. 23400
Answer: E
Answer: E
Question: An article is bought for Rs.600 and sold for Rs.500, find the loss percent?
Options:
A)16 2/8%
B)16 6/3%
C)76 2/3%
D)16 2/3%
E)96 2/3%
Rationale: 600 ---- 100
100 ---- ? => 16 2/3%
Answer: D
Answer: D
Question: A family made a down payment of $100
and borrowed the balance on a set of
encyclopedias that cost $400. The
balance with interest was paid in 20
monthly payments of $17.2 each and a
final payment of $3. The amount of
interest paid was what percent of the
amount borrowed?
Options:
A) 6%
B) 12%
C) 14%
D) 15.6%
E) 20%
Rationale: interest paid = 17.2*20+3 - 300=47
% off the balance = (47/300) * 100 = 15.67%
Answer is D.
Answer: D
Question: During a trip, Francine traveled x percent of the total distance at an average speed of 30 miles per hour and the rest of the distance at an average speed of 60 miles per hour. In terms of x, what was Francine's average speed for the entire trip?
Options:
A)(180-x)/2
B)(x+60)/4
C)4800/x+100
D)600/(115-x)
E)12,000/(x+200)
Rationale: total distance =100 ;total time = T
t1 = x/30 t2 = 100-x /60
T =t1+t2 = x/30 + 100-x/60 = (60x + 3000- 30x)/1800
= (30x+3000)/1800
= x +100 / 60
av speed = 100*60/x+100 = 4800/x+100
C
Answer: C
Question: A train 1000 m long passed a pole in 20 sec. How long will it take to pass a platform 500 m long?
Options:
A)22
B)24
C)26
D)28
E)30
Rationale: Speed = 1000/20 = 50 m/sec.
Required time = (1000 + 500)/50
= 30 sec.
Answer:E
Answer: E
Question: The average of five results is 48 and that of the first four is 45. The fifth result is?
Options:
A)50
B)60
C)70
D)80
E)90
Rationale: 5 * 48 – 4 * 45 = 60
ANSWER:B
Answer: B
Question: In what time will a train 150 m long cross an electric pole, it its speed be 144 km/hr?
Options:
A)2.5 sec
B)4.25 sec
C)3.75 sec
D)12.5 sec
E)6 sec
Rationale: Speed = 144 * 5/18 = 40 m/sec
Time taken = 150/40 = 3.75 sec.
ANSWER:C
Answer: C
Question: A train 800 m long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 min, then the length of the tunnel is?
Options:
A)298 m
B)268 m
C)500 m
D)267 m
E)181 m
Rationale: Speed = 78 * 5/18 = 65/3 m/sec.
Time = 1 min = 60 sec.
Let the length of the train be x meters.
Then, (800 + x)/60 = 65/3
x = 500 m.
Answer: C
Answer: C
Question: A room is 6 meters 24 centimeters in length and 4 meters 32 centimeters in Width. Find the least number of square tiles of equal size required to cover the entire floor of the room.
Options:
A)107
B)117
C)127
D)137
E)147
Rationale: Let us calculate both the length and width of the room in centimeters.
Length = 6 meters and 24 centimeters = 624 cm
width = 4 meters and 32 centimeters = 432 cm
As we want the least number of square tiles required, it means the length of each square tile should be as large as possible.Further,the length of each square tile should be a factor of both the length and width of the room.
Hence, the length of each square tile will be equal to the HCF of the length and width of the room = HCF of 624 and 432 = 48
Thus, the number of square tiles required = (624 x 432 ) / (48 x 48) = 13 x 9 = 117
Answer: B
Answer: B
Question: If xy = 5 and x^2 + y^2 = 15, then x/y + y/x =
Options:
A)5
B)3 1/7
C)5 1/3
D)7
E)60
Rationale: We can make simplifying of question and get it in view: (x^2 + y^2) / xy and as we know the meaning of this parts:
x^2 + y^2 = 15
xy = 5
we can calculate the answer 15/5 -> 5 so answer is A
Answer: A
Question: Missing number in the series
4 9 20 43 90 185 376 759?
Options:
A)1750
B)1850
C)1900
D)1950
E)1526
Rationale: 4*2+1=9
9*2+2=20
20*2+3=43
43*2+4=90
90*2+5=185
185*2+6=376
376*2+7=759
759*2+8=1526
ANSWER:E
Answer: E
Question: A certain school principal must choose 5 students to attend a field trip out of a group of 12 students. In addition, out of the 5 chosen students, the principal must select a note-taker and a treasurer. How many different ways are there for the principal to select the 5 students and then select the treasurer and the note-taker?
Options:
A)1,260
B)2,520
C)15,840
D)6,020
E)10,080
Rationale: 5 students can be selected out of 12 students in 12C5 ways.
out of the remaining 5 students,Note taker can be chosen in 5 ways.
Finally only 4 students remain from which we can choose a treasurer in 4 ways.
Total number of ways = 792 * 5 *4 = 15840
correct answer - C
Answer: C
Question: In doing a division of a question with zero remainder, a candidate took 12 as divisor instead of 21. The quotient obtained by him was 35. The correct quotient is
Options:
A)0
B)12
C)13
D)20
E)None
Rationale: Sol.
Dividend = (12 x 35) = 420.
Now, dividend = 420 and divisor = 21.
∴ Correct quotient = 420 / 21 = 20.
Answer D
Answer: D
Question: In how many different ways can 7 identical green shirts and 7 identical red shirts be distributed among 14 children such that each child receives a shirt?
Options:
A)87178291200
B)871782912
C)8717829
D)871782
E)87178
Rationale: GGG RRR
Therefore total number of ways is
14! but there are two groups of 3 identical things.
Therefore total number of "different" ways is
14!/ (7!) (7!) = 20 ANS:A
Answer: A
Question: A store sells five different kinds of shirts. If we want to buy two different kinds of shirts, how many possible combinations of two shirts can we buy?
Options:
A)6
B)8
C)10
D)12
E)14
Rationale: 5C2=10.
The answer is C.
Answer: C
Question: The sale price sarees listed for Rs.400 after successive discount is 10% and 5% is?
Options:
A)228
B)277
C)342
D)291
E)112
Rationale: 400*(90/100)*(95/100) = 342
Answer: C
Answer: C
Question: In a group of 800 people, 1/5 play at least one instrument, 32 play two or more. What is the probability that one student play exactly one instrument?
Options:
A)2/125
B)4/25
C)C)2/25
D)3/25
E)1/5
Rationale: P(playing 2 or more instruments) = 32/800 = 1/25.
Then, the probability of playing exactly one instrument is given by:
P(playing 1 or more instruments) - P(playing 2 or more instruments) = 1/5 - 1/25 = 4/25.
Answer B.
Answer: B
Question: A bank pays interest to its customers on the last day of the year. The interest paid to a customer
is calculated as 10% of the average monthly balance maintained by the customer. John is a
customer at the bank. On the last day, when the interest was accumulated into his account, his
bank balance doubled to $5080. What is the average monthly balance maintained by John in his
account during the year?
Options:
A) 2840
B) 5680
C) 6840
D) 25400
E) 28400
Rationale: bank balance is doubled with accumulation of interest tp 5080..
this means INTEREST is 5080/2=2540 for entire year..
although since interest is 10% of avg MONthly balance, it becomes 25400..
D
Answer: D
Question: Compound interest of Rs.2000 at 10% per annum for 1 1/2years will be (interest compounded half yearly).
Options:
A)Rs.473
B)Rs.374
C)Rs.495
D)Rs.315
E)None of the above
Rationale: 10% interest per annum will be 5% interest half yearly for 3 terms( 1 1/2 years)
So compound interest=2000[1+(5/100)]^3 - 2000=2000[(21/20)^3 -1]
=2000(9261-8000)/8000
=2*1261/8
=315
ANSWER:D
Answer: D
Question: he total marks obtained by a student in Physics, Chemistry and Mathematics is 170 more than the marks obtained by him in Physics. What is the average mark obtained by him in Chemistry and Mathematics?
Options:
A)55
B)65
C)75
D)85
E)95
Rationale: Let the marks obtained by the student in Physics, Chemistry and Mathematics be P, C and M respectively.
P + C + M = 170 + P
C + M = 170
Average mark obtained by the student in Chemistry and Mathematics = (C + M)/2 = 170/2 = 85.
ANSWER:D
Answer: D
Question: There are two sections Y and Z of a class, consisting of 288 and 352 students respectively. If the average weight of sections Y is 320 kg and that of sections Z is 280 kg. Find the average weight of the whole class
Options:
A)297.5
B)298.0
C)298.5
D)299.0
E)None
Rationale: Solution
Total weight of(288+352)Students	= (288x320+352x280)Kg
= 1,90,720 kg.
Average weight of the whole class	= (190720 / 640)
= 298.00.
Answer B
Answer: B
Question: In how many ways letters of the word RSCUPERATE be arranged?
Options:
A)275788
B)287578
C)4357809
D)437479
E)302400
Rationale: RESUPERATE has 10 letters, out of which E repeated 3 times, R repeated 2 times. Hence total ways = 10! / (3!*2!) = 302400 ways
E
Answer: E
Question: Of the 100 athletes at a soccer club, 40 play defense and 68 play midfield. If at least 20 of the athletes play neither midfield nor defense, the number of athletes that play both midfield and defense could be any number between
Options:
A)10 to 20
B)10 to 40
C)28 to 40
D)30 to 70
E)40 to 70
Rationale: First of all notice that since only 40 athletes play defense, then the number of athletes that play both midfield and defense cannot possibly be greater than 40.Eliminate D and E.
{Total} = {defense} + {midfield} - {both} + {neither}
100 = 40 + 68 - {both} + {neither}
{both} = {neither} + 8.
Since the least value of {neither} is given to be 20, then the least value of {both} is 20+8=28.Eliminate A and B.
Answer: C.
Answer: C
Question: A group of n students can be divided into equal groups of 4 with 1 student left over or equal groups of 5 with 4 students left over. What is the sum of the two smallest possible values of n?
Options:
A)30
B)34
C)38
D)42
E)46
Rationale: n = 4k+1 = 5j+4
Let's start at 1 = 4(0)+1 and keep adding 4 until we find a number in the form 5j+4.
1, 5, 9 = 5(1)+ 4
The next such number is 9 + 4*5 = 29.
9+29 = 38
The answer is C.
Answer: C
Question: Each digit in the two-digit number G is halved to form a new two-digit number H. Which of the following could be the sum of G and H
Options:
A)153
B)150
C)137
D)120
E)89
Rationale: let the number be x, now x is halved => x/2..the question asks what is x?
x(number) + x/2 (half of that number) = something
=> 3x/2 = something
=> x = 2 (something) / 3
so the answer choice must be divisible by 3
eliminate C, E right away
check the rest
D satisfies
3x/ 2 = 120
=> x = 86
Verify. 80 + 40= 120
Answer is D
Answer: D
Question: In how many seconds will a train 150 meters long pass an oak tree, if the speed of the train is 54 km/hr?
Options:
A)6
B)8
C)10
D)12
E)14
Rationale: speed = 54 * 5/18 = 15 m/s
time = 150/15 = 10 seconds
The answer is C.
Answer: C
Question: A committee has 5 men and 4 women. What are the number of ways of selecting 2 men and 3 women from the given committee?
Options:
A)127
B)40
C)882
D)272
E)323
Rationale: The number of ways to select two men and three women
= ⁵C₂ * 4C₃
= (5 *4 )/(2 * 1) * (4 * 3 * 2)/(3 * 2)
= 40
Answer: B
Answer: B
Question: What do you get if you add 9 to 311 four times?
Options:
A)305
B)310
C)327
D)320
E)309
Rationale: D
320 , 320 , 320 , 320
Answer: D
Question: Mary's income is 60% more Than Tim's income and Tim's income is 50% less than Juan's income.What % of Juan's income is Mary's income.
Options:
A)124%
B)B.120%
C)96%
D)80%
E)64%
Rationale: Even I got 96%
J = 100
T = 100*0.5 = 50
M = 50*1.6 = 80
If Mary's income is x percent of J
M = J*x/100
x = M*100/J = 80*100/100 = 80
Ans:D
Answer: D
Question: What is the value of x^2yz − xyz^2, if x = 2, y = 1, and z =2?
Options:
A) 20
B) 24
C) 0
D) 32
E) 48
Rationale: 4*1*2-(2*1*4)
=8+8 = 0
Ans: C
Answer: C
Question: Find the missing figures: 0.25% of ? = 0.04
Options:
A)16
B)20
C)17
D)12
E)18
Rationale: Let 0.25% of x = 0.04. Then , 0.25*x/100 = 0.04
X= [(0.04*100)/0.25] = 16.
Answer is A.
Answer: A
Question: The maximum number of girls among them 2923 bags and 3239 eyeliners can be distributed in such a way that each student gets the same number of bags and eyeliners.
Options:
A)80
B)79
C)78
D)81
E)82
Rationale: Max no of girls=HCF of 2923 and 3239= 79
ANSWER:B
Answer: B
Question: When ticket sales began, Pat was the nth customer in line for a ticket, and customers purchased their tickets at the rate of z customers per minute. Of the following, which best approximates the time, in minutes, that Pat had to wait in line from the moment ticket sales began?
Options:
A)(n - 1) z
B)n + z –1
C)n/(z-1)
D)z/(n-1)
E)(n-1)/z
Rationale: E. (n - 1) / z
Answer: E
Question: When n is divided by 19, the remainder is 6 . When n is divided by 11, the quotient is equal to Z, and the remainder is equal to 6. Z must be divisible by which of the following numbers?
Options:
A)3
B)7
C)10
D)13
E)nineteen
Rationale: N = 19 q + 6
N = 11 z + 6
Equating
19 Q + 6 = 11z+6
11z=19q
11z/19 = q
since q is an integer Z must be divisible by 19.
ANSWER:E
Answer: E
Question: Which of the following functions does not intersect with Q = 3x^2 + 2x + 1
Options:
A)Q= 3x^2 + 3x + 1
B)Q = 2x^2 + 3x + 1
C)Q = 3x^2 + 2x + 3
D)Q = 4x^2 + 2x - 3
E)Q = x^2 + 2x + 3
Rationale: Let’s find the actual intersecting point of given function and each choice Q
A. 3x^2 + 2x + 1 = 3x^2 + 3x + 1 --> x=0
B. 3x^2 + 2x + 1 = 2x^2 + 3x + 1 --> x^2 – x =0 --> x=0 or 1
C. 3x^2 + 2x + 1 = 3x^2 + 2x + 3 --> 1=3(X) --> they don’t have any intersect.
D. 3x^2 + 2x + 1 = 4x^2 + 2x - 3 --> x^2 –4=0 --> x= 2 or -2
E. 3x^2 + 2x + 1 = x^2 + 2x + 3 --> 2x^2 –2 =0 --> x= 1 or –1.
So only choice (C) has no intersecting point. The answer is (C).
Answer: C
Question: A bike covers a certain distance at the speed of 64km/h in 8 hrs. If the bike was to cover the same distance in approximately 6 hrs, at what approximate speed should the bike travel?
Options:
A)80 km/h
B)85.34 km/h
C)90.14 km/h
D)91.24 km/h
E)92 km/h
Rationale: Ans.(B)
Sol. Total distance = 64 × 8 = 512 km
Now speed = 512/6 = 85.34 km/h
Answer: B
Question: The five sides of a pentagon have lengths of 2, 3, 4, 5 and 6 inches. Four pentagons are considered different only when the positions of the side lengths are different relative to each others. What is the total number of different possible pentagons that could be drawn using these five side lengths ?
Options:
A) 5
B) 12
C) 24
D) 32
E) 120
Rationale: CONCEPT: The number of ways to arrange n elements around a circular Manner is (n-1)!.
But the number of ways to arrange n elements in circular manner where the arrangement can be flipped around (e.g. Necklace, Garland, Bracelet) = (n-1)!/2.
The pentagon in the problem above can be flipped over (Clockwise Arrangement of Sides = Counter-clockwise arrangement), the number of distinct ways to arrange the 5 sides = (5-1)!/2 = 5.
Answer: option A
Answer: A
Question: 4 men or 6 women can do a piece of work in 20 days. In how many days will 12 men and 8 women do the same work?
Options:
A)12/9 days
B)60/13 days
C)82/8 days
D)22/76 days
E)22/2 days
Rationale: 4M = 6W ---- 20 days
12M + 8W -----?
18W + 8 W = 26W ---?
6W ---- 20 26 -----?
6 * 20 = 26 * x => x = 60/13 days
Answer:B
Answer: B
Question: A shopkeeper sells two articles at Rs.1000 each, making a profit of 20% on the first article and a loss of 20% on the second article. Find the net profit or loss that he makes?
Options:
A)3%
B)8%
C)9%
D)4%
E)24%
Rationale: SP of first article = 1000
Profit = 20%
CP = (SP)*[100/(100+P)] = 5000/6 = 2500/3
SP of second article = 1000
Loss = 20%
CP = (SP)*[100/(100-L)] = 5000/4 = 1250
Total SP = 2000
Total CP = 2500/3 + 1250 = 6250/3
CP is more than SP, he makes a loss.
Loss = CP-SP = (6250/3)- 2000 = 250/3
Loss Percent = [(250/3)/(6250/3)]*100
=0.04 * 100
= 4%
Answer: D
Answer: D
Question: A thief is spotted by a policeman from a distance of 200 meters. When the policeman starts the chase, the thief also starts running. If the speed of the thief be 8km/hr and that of the policeman 10 km/hr, how far the thief will have run before he is overtaken?
Options:
A)350m
B)200m
C)400m
D)800m
E)None of them
Rationale: Relative speed of the policeman = (10-8) km/hr =2 km/hr.
Time taken by police man to cover
(200m/1000) x 1/2 hr = 1/10 hr.
In 1/10 hrs, the thief covers a distance of 8 x 1/10 km = 4/5 km = 800 m
Answer is D.
Answer: D
Question: Two men A and B start from place X walking at 4 ½ kmph and 5 ¾ kmph respectively. How many km apart they are at the end of 3 ½ hours if they are walking in the same direction?
Options:
A)4 3/6
B)4 3/9
C)4 3/8
D)4 3/4
E)4 3/1
Rationale: RS = 5 3/4 - 4 1/2 = 1 1/4
T = 3 1/2 h.
D = 5/4 * 7/2 = 35/8 = 4 3/8 km
Answer: C
Answer: C
Question: The ratio of the number of boys and girls in a college is 7 : 8. If the percentage increase in the number of boys and girls be 20% and 10% respectively, what will be the new ratio?
Options:
A)8 : 9
B)21 : 22
C)17 : 18
D)12 : 20
E)Cannot be determined
Rationale: Originally, let the number of boys and girls in the college be 7x and 8x respectively.
Their increased number is (120% of 7x) and (110% of 8x).
(120/100 x 7x)	and	(110/100 x 8x)
42x/5 and 44x/5
The required ratio = (42x/5 : 44x/5)= 21 : 22.
ANSWER B
Answer: B
Question: A, B and C started a business with capitals of Rs. 8000, Rs. 10000 and Rs. 12000 respectively. At the end of the year, the profit share of B is Rs. 1500. The difference between the profit shares of A and C is?
Options:
A)277
B)266
C)299
D)600
E)261
Rationale: Ratio of investments of A, B and C is 8000 : 10000 : 12000 = 4 : 5 : 6
And also given that, profit share of B is Rs. 1500
=> 5 parts out of 15 parts is Rs. 1500
Now, required difference is 6 - 4 = 2 parts
Required difference = 2/5 (1500) = Rs. 600
Answer: D
Answer: D
Question: What is the perimeter of a square with area 4p^2/16 ?
Options:
A)3p/4
B)3p^2/4
C)2p
D)3p^2
E)4p/3
Rationale: Area of square, (side)^2 = (2p/4)^2
Therefore side of the square = 2p/4
Perimeter of square = 4*side = 4* (2p/4) = 2p
Answer is C.
Answer: C
Question: In a store, the profit is 320% of the cost. If the cost increases by 25% but the SP remains constant, approximatelywhat %of the sp is the profit?
Options:
A)50%
B)70%
C)80%
D)90%
E)110%
Rationale: Let C.P. = Rs. 100. Then, profit = Rs. 320, S.P. = Rs. 420
New C.P. = 125% of Rs. 100 = Rs. 125.
New S.P. = Rs. 420
Profit = 420 - 125 = Rs. 295
Required percentage = 295/420 * 100 = 1475/21 = 70%
B
Answer: B
Question: If Rs.7500 are borrowed at C.I at the rate of 4% per annum, then after 2 years the amount to be paid is?
Options:
A)2868
B)1718
C)1689
D)8112
E)1718
Rationale: A = 7500(26/25)2
= 8112
Answer:D
Answer: D
Question: The cost of 20 pens and 12 pencils is Rs.400 and the cost of 6 pens and 4 pencils is Rs.100. Find the cost of each pen?
Options:
A)Rs.50
B)Rs.100
C)Rs.150
D)Rs.25
E)Rs.125
Rationale: 20p + 12q = 400 --- (1)
6p + 4q = 100
8p + 8q = 192 --- (2)
(1) - (2) => 8p = 160
=> p = 50
ANSWER:A
Answer: A
Question: In a shop, 40% socks are white and rest are black. 60% socks are made of cotton and rest are made of wool. 25% white socks are made of cotton and 20 of the black socks are made of wool. How many black socks X are made of cotton?
Options:
A)100
B)80
C)60
D)50
E)25
Rationale: I'll prefer to solve this with plug n play method.
As we know, White Cotton socks are only 25% and Total Cotton socks is 60% - Hence Black Cotton socks X has to be [highlight]HIGH[/highlight]number. Thats why we've to pick high number... say 100 or 80.
100 fits perfectly after relevant calculations. Hence answer A.
Answer: A
Question: For which of the following functions f is f(b) = f(1-b) for all b?
Options:
A)f (x) = 1 - x
B)f (b) = 1 - b^2
C)f (b) = b^2 - (1 - b)^2
D)f (b) = b^2*(1 - b)^2
E)f (x) = x/(1 - x)
Rationale: I remember seeing this problem in a GMATprep test. I think choice D should be F(b)=(b^2) (1-b)^2. If that is true then substituting (1-b) for will give us the same function back and the answer choice is D, where the function is multiplicative
Answer: D