divelab/Sys2Bench huggingface dataset:
Question: Find the last 2 digits
65*29*37*63*71*87*62
Options:
A)70
B)30
C)10
D)90
E)80
Rationale: Similarly for this question,
Rof(201∗202∗203∗204∗246∗247∗248∗249)∗(201∗202∗203∗204∗246∗247∗248∗249)/100
=Rof(201∗101∗203∗204∗246∗247∗248∗249)∗(201∗202∗203∗204∗246∗247∗248∗249)/50
Note: I have left denominator as 50 since it will be easier in calculations.
=Rof[(1∗1∗3∗4∗(−4)∗(−3)∗(−2)∗(−1)]∗[(1∗2∗3∗4∗(−4)∗(−3)∗(−2)∗(−1)]/50
=Rof(12∗24∗24∗24)/50=Rof(6∗24∗24∗24)/25=Rof[6∗(−1)∗(−1)∗(−1)]/25=−6
Since remainder is coming negative, we add 25 to it.
Thus Remainder is 19. In decimal format, it is 19/25 or 0.76
Thus last two digits will be 0.76*100 = 76
[Note: Rather than calculating the decimal value first, it will be faster to combine the last two steps as follows: (19/25)*100 = 19*4 = 76. This is how I did it and it saved me valuable seconds!]
Answer should be (3).
ANSWER:C
Answer: C
Question: A thief is noticed by a policeman from a distance of 300 m. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 10 km and 11 km per hour respectively. What is the distance between them after 6 minutes?
Options:
A)150 m
B)200 m
C)170 m
D)100 m
E)250 m
Rationale: Relative speed of the thief and policeman = 11 - 10 = 1 km/hr.
Distance covered in 6 minutes = 1/60 * 6 = 1/10 km = 100 m.
Distance between the thief and policeman = 300 - 100 = 200 m
B
Answer: B
Question: The jogging track in a sports complex is 660 m in circumference. Deepak and his wife start from the same point and walk in opposite directions at 4.5 km/hr and 3.75 km/hr respectively. They will meet for the first time in?
Options:
A)5.29 min
B)5.28 min
C)5.08 min
D)4.8 min
E)5.988 min
Rationale: Clearly, the two will meet when they are 660 m apart.
To be (4.5 + 3.75) = 8.25 km apart, they take 1 hour.
To be 660 m apart, they take (100/825 * 660/1000) hrs = (660/8250 * 60) min = 4.8 min.
Answer: D
Answer: D
Question: If 30% of a number is 12.6, find the number?
Options:
A)42
B)40
C)26
D)36
E)66
Rationale: A
40
Answer: A
Question: During a trip, Francine traveled x percent of the total distance at an average speed of 100 miles per hour and the rest of the distance at an average speed of 90 miles per hour. In terms of x, what was Francineâ€™s average speed for the entire trip?
Options:
A)(180-x)/2
B)(x+60)/4
C)(300-x)/5
D)600/(115-x)
E)9,000/(100+8x)
Rationale: E....
X% traveeled at 10 mph
100-X% traveeled at 90 mph
total timt taken = x/10 +(100-x)/90 = (100+8x)/90
Total distance = x+(100-x) = 100
Av speed = Tot Dis/Time Taken which is E
Answer: E
Question: If the wheel is 14 cm then the number of revolutions to cover a distance of 1056 cm is?
Options:
A)18
B)26
C)14
D)12
E)91
Rationale: 2 * 22/7 * 14 * x = 1056 => x
= 12
Answer: D
Answer: D
Question: Find the simple interest for Rs. 2000 at 8% p/a for 2years.
Options:
A)Rs.300
B)3Rs.20
C)Rs.420
D)Rs.520
E)Rs.460
Rationale: S.I= (2000*8*2)/100
P = 320
Answer: B
Answer: B
Question: Which of the following is larger than 3/5?
Options:
A)1/2
B)39/50
C)7/25
D)3/10
E)59/100
Rationale: if we want to compare two fraction number
a/b =c/d
then a*d (answer to a/b)
c*b (ans to c/d) (apply this conditions to all the options)
Therefore (3*5=15) (39*5=195)
39/5 is greater than 3/5..
ANSWER:B
Answer: B
Question: A father was as old as his son's present at the time of your birth. If the father's age is 34 years now, the son's age 5years back was?
Options:
A)10 years
B)12 years
C)14 years
D)16 years
E)20 years
Rationale: Let the son's present age be x years. Then, (34 - x) = x
2x = 34.
x = 17.
Son's age 5 years back (17 - 5) = 12 years.
B
Answer: B
Question: At a contest with 3,500 participants, 1/2 of the people are aged 18 to 22. Next year, the number of people aged 18 to 22 will increase by 1/7. After this change, what percentage of the total 3,500 people will the 18- to 22-year-olds represent?
Options:
A)33%
B)40%
C)55%
D)57.14%
E)66.14%
Rationale: I just wanted to mention a couple of things here:
* this is a pure ratio question; the number 3,500 is completely irrelevant, and you can ignore it if you like. When we increase something by 1/7, we are multiplying it by 1 + 1/7 = 8/7, so the answer here must be (1/2)*(8/7) = 4/7 = 57.14 %.
Answer : D
Answer: D
Question: Bradley owns 3b video game cartridges. If Bradleyâ€™s total is one-fourth the total owned by Andrew and triple the total owned by Charlie, how many video game cartridges do the three of them own altogether, in terms of b?
Options:
A)16/3)b
B)17/4)b
C)13/4)b
D)16b
E)7/12)b
Rationale: Step 1: Categorize the problem
This problem is testing basic algebra and equations, with an extra layer of complexity by having variables in the answer choices.
Step 2: Think like the test maker
What is the key detail or key details in the problem? The key detail to immediately recognize is that the problem gives you Andrew and Charlieâ€™s totals in relation to Bradleyâ€™s total rather than giving you Bradleyâ€™s total in relation to the other two; and then the problem asks you to solve the problem in terms of b. This means that you have to relate Andrew and Charlieâ€™s values in relation to Bradleyâ€™s total. The test maker is attempting to force you to structure the problem in the opposite way that most people are used to structuring information. By gaining this insight, it makes it easier to solve the problem.
Step 3: Solve the problem
3b = Bradleyâ€™s total
4*3b = Andrewâ€™s total
(1/3)*3b = Charlieâ€™s total
Add each total
3b + 4*3b+ (1/3)3b = 3b + 12b + b = 16b
Therefore,choose D.
Answer: D
Question: An auto assembly plant performs six functions with each frame that arrives: add axles, add wheels to the axles, install the windshield to the frame, install the instrument panel, install the steering wheel, and install the interior seating. Once those six tasks are performed, each car goes to a separate building for finishing touches. If these tasks can be arranged along a linear assembly line in any order, except that the axles must be installed before the wheels can be added, how many Y ways can the assembly line be arranged?
Options:
A)120
B)240
C)360
D)480
E)720
Rationale: C) 360
short way: there are 6C! ways to do the six tasks. Half will have wheels before axles and half will have axles before wheels. So we want Y=6C!/2 -> 720/2 = 360
Answer: C
Question: Of the 80 people in a room, 1/4 are women. If 3/4 of the people are married, what is the maximum number of women in the room who could be unmarried?
Options:
A)20
B)24
C)26
D)28
E)30
Rationale: women = 1/4 * 80 = 20
married = 3/4 * 80 = 60
unmarried = 20
max(un-married women) = 20
Answer A
Answer: A
Question: The sum of the ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?
Options:
A)4
B)5
C)6
D)7
E)9
Rationale: Let the ages of the children be x, (x + 3), (x + 6), (x + 9) and (x +12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
5x = 20 => x = 4.
Age of youngest child = x = 4 years.Answer: A
Answer: A
Question: A shopkeeper buys two articles for Rs.1000 each and then sells them, making 20% profit on the first article and 20% loss on second article. Find the net profit or loss percent?
Options:
A)200
B)99
C)88
D)77
E)112
Rationale: Profit on first article = 20% of 1000 = 200.
This is equal to the loss he makes on the second article. That, is he makes neither profit nor loss.
Answer:A
Answer: A
Question: David mixed 20 kg of butter at Rs. 200 per kg with 30 kg butter at the rate of Rs. 100 per kg. At what price per kg should he sell the mixture to make a profit of 40% in the transaction?
Options:
A)Rs. 96
B)Rs. 196
C)Rs. 296
D)Rs. 190
E)Rs. 195
Rationale: Cost of Butter = 20*200+ 30*100 /50 =7000/50 = 140
40% of 140 = 56
S.P. should be = 140+56 = Rs. 196/ kg
Answer : B
Answer: B
Question: A pump can fill a tank with water in 2 hours. Because of a leak, it took 2 2/3 hours to fill the tank. The leak can drain all the water of the tank in
Options:
A)6 hours
B)8 hours
C)9 hours
D)10 hours
E)12 hours
Rationale: Explanation:
Solution 1
The pump can fill the tank in 2 hour. But, because of the leak, it took 2 2/3 hours to fill the tank.
i.e., the additional water filled by the pump in 2/3 hour is emptied by the leak in 2 2/3 = 8/3 hours.
Therefore, the water filled by pump in 2 bour can be emptied by the leak in 8/3 X 3 = 8 hours.
i.e., The leak can drain all the water of the tank in 8 hours.
ANSWER IS B
Answer: B
Question: When Ravi was 8 years old, his father was 31 years old,. Now his father is twice Ravi's age. How old is Ravi now?
Options:
A)45 yrs
B)46 yrs
C)47 yrs
D)48 yrs
E)49 yrs
Rationale: When Ravi was 8 years old, his father was 31 years old,.
Means father's age is 23 years more than Ravi.
Now his father is twice Ravi's age.
It means difference between their ages is equal to present age of Ravi.
So Ravi's present age = 23 years. and father's age = 2*23 = 46 yrs
ANSWER:B
Answer: B
Question: A no.when divided by 223 gives a remainder 43, what remainder will beobtained by dividingthe same no.17?
Options:
A)2
B)7
C)9
D)11
E)15
Rationale: 223 + 43 = 266/17 = 11 (Remainder)
D
Answer: D
Question: Dhoni spends $250 buying his favorite dolls. If he buys only small Barbie dolls, which are $5 cheaper than the large Barbie dolls, he could buy 25 more dolls than if he were to buy only large Barbie dolls. How much does a large Barbie doll cost?
Options:
A)$10.5
B)$10
C)$11
D)$12
E)$13
Rationale: A is not an integer. So we start with B.
If large doll costs $10, then he can buy 250/10 = 25 large dolls and 250/5 =50 small dolls.
Difference is 25, which is we wanted.
Answer B.
Answer: B
Question: A certain car's price decreased by 2.5% (from the original price) each year from 1996 to 2002, during that time the owner of the car invested in a new carburetor and a new audio system for the car, which increased car's price by $2,500. If the price of the car in 1996 was $22,000, what is the car's price in 2002?
Options:
A)$18,400
B)$19,500
C)$20,200
D)$20,400
E)$21,200
Rationale: Price in 96 = 22000
Price decrease each year = 2.5/100*22000 = 550
Price in 97 = 22000 - 550
Price in 98 = 22000 - 2*550
Price in 99 = 22000 - 3*550
Price in 00 = 22000 - 4*550
Price in 01 = 22000 - 5*550
Price in 02 = 22000 - 6*550 = 18700
Investment in the car = 2500
Net price of the car in 02 = 18700 + 2500 = $21200
Correct Option: E
Answer: E
Question: If 2 men or 3 women can reap a field in 5 days how long will 5 men and 6 women take to reap it?
Options:
A)2/24
B)6/18
C)2/22
D)5/12
E)9/10
Rationale: Explanation:
2 men reap 2/5 field in 1 day
1 man reap 1/(2 x 5)
3 women reap 1/43 field in 1 day
1 woman reap 1/(5 x 3)
5 men and 6 women reap (5/(2 x 5)+ 6/(3 x 5)) =9/10 in 1 day
5 men and 6 women will reap the field in 9/10 days
Answer: Option E
Answer: E
Question: Calculate the ratio between x and y if 25% of x equal to 40% of y?
Options:
A)5 : 8
B)5 : 9
C)5 : 7
D)5 : 6
E)5 : 4
Rationale: Explanation:
25 x = 40 y
x: y = 25 : 40 = 5 : 8
Answer:A
Answer: A
Question: Ayesha's father was 40 years of age when she was born while her mother was 32 years old when her brother six years younger to her was born. What is the difference between the ages of her parents?
Options:
A)6
B)14
C)5
D)1
E)2
Rationale: Mother's age when Ayesha's brother was born = 32 years.
Father's age when Ayesha's brother was born = (40 + 6) years = 46 years.
Required difference = (46 - 32) years = 14 years.
Answer:B
Answer: B
Question: 150 125 60 120 95 60 70 ? ?
Options:
A)25 15
B)25 85
C)35 25
D)60 60
E)20 75
Rationale: 150-25=125
again 60
125-25=120
120-25=95
again 60
95-25=70
70-25=55
again 60
then answer is 60 ,60
ANSWER:D
Answer: D
Question: Sales price is $91, gross profit is 160% of cost, what is the value of gross profit?
Options:
A)32
B)33
C)39
D)40
E)56
Rationale: Cost + Profit = Sales
Cost + (160/100)Cost = 91
Cost = 35
Profit = 91 - 35 = 56
Answer (E)
Answer: E
Question: There are 9 baskets with pebbles in it.Every basket have pebbles weighing 1gm except one which has pebbles weighing 2gm.There is a weighing machine. Use the weighing machine only once and find which basket have pebbles that weigh 2gm?
Options:
A)9th
B)8th
C)6th
D)4th
E)5th
Rationale: Take 1 pebble form 1st basket, 2 from 2nd, 3 from 3rd,...9 from the 9th basket and weigh them. If all the baskets contained 1gm pebbles the weight would have been 45 [ 1+2+3+..9 = 45]
Since 1 of the basket contains 2 gm pebbles the weight will be more than 45.
Subtract 45 from the weight to get the basket number.
ie
if the weight is 49
49 - 45 = 4
4th basket
ANSWER:D
Answer: D
Question: The five sides of a pentagon have lengths of 2, 3, 4, 5 and 6 inches. one pentagons are considered different only when the positions of the side lengths are different relative to each others. What is the total number of different possible pentagons that could be drawn using these five side lengths ?
Options:
A) 5
B) 12
C) 24
D) 32
E) 120
Rationale: CONCEPT: The number of ways to arrange n elements around a circular Manner is (n-1)!.
But the number of ways to arrange n elements in circular manner where the arrangement can be flipped around (e.g. Necklace, Garland, Bracelet) = (n-1)!/2.
The pentagon in the problem above can be flipped over (Clockwise Arrangement of Sides = Counter-clockwise arrangement), the number of distinct ways to arrange the 5 sides = (5-1)!/2 = 5.
Answer: option A
Answer: A
Question: Positive integer y is 50 percent of 50 percent of positive integer x, and y percent of x equals 4. What is the value of x?
Options:
A)40
B)100
C)200
D)400
E)600
Rationale: y = 0.5*0.5*x = x/4
y%*x = 4
(y/100)*x = 4
(x/400)*x = 4
x^2 = 4*400
x = 40
The answer is A.
Answer: A
Question: Tom, working alone, can paint a room in 6 hours. Peter and John, working independently, can paint the same room in 3 hours and 5 hours, respectively. Tom starts painting the room and works on his own for one hour. He is then joined by Peter and they work together for an hour. Finally, John joins them and the three of them work together to finish the room, each one working at his respective rate. What fraction of the whole job was done by Peter?
Options:
A)19/35
B)23/42
C)27/55
D)31/63
E)35/74
Rationale: Tom paints 1/6 of the room in the first hour.
Tom and Peter paint 1/6+1/3 = 1/2 of the room in the next hour for a total of 4/6.
The three people then paint the remaining 2/6 in a time of (2/6) / (21/30) = 10/21 hours
Peter worked for 31/21 hours so he painted 31/21 * 1/3 = 31/63 of the room.
The answer is D.
Answer: D
Question: Kelly and Jody packed boxes with books. If Jody packed 60% of the total number of boxes, what was the ratio of the number of boxes Kelly packed to the number that Jody packed?
Options:
A)1 to 6
B)1 to 4
C)2 to 5
D)3 to 5
E)2 to 3
Rationale: Explanation:
If Jody packed 60% of the boxes then Kelly packed 40%. The ratio of the number of boxes Kelly packed to the number Jody packed is thus 40%/60%=2/3
Answer: Option E
Answer: E
Question: Six persons in an organization including A and B were to be divided in two groups of 3 members each. The total number of groups containing both A and B is what fraction of the total number of groups which can be formed?
Options:
A)3/10
B)1/70
C)3/14
D)1/10
E)11/14
Rationale: The fraction is nothing but the probability..
Number to choose 3 out of 6= 6C3
Number to choose A and B and 2 from remaining 4=4C2..
prob of A and B choosen=4C2/6C3=3/10
Answer : A
Answer: A
Question: A rectangular block 15cm by 30cm by 75cm is cut into an exact number of equal cubes. Find the least possible number of cubes?
Options:
A)6
B)40
C)15
D)10
E)22
Rationale: Volume of the block = 15*30*75 = 33750 cm^3
Side of the largest cube = H.C.F of 15,30,75 = 15cm
Volume of the cube = 15*15*15 = 3375 cm^3
Number of cubes = 33750/3375 = 10
Answer is D
Answer: D
Question: The ratio between the speeds of two trains is 7 : 10. If the second train runs 400 kms in 8 hours, then the speed of the first train is
Options:
A)35 km/h
B)60 km/h
C)45 km/h
D)50km/h
E)30 km/h
Rationale: A
35 km/h
Answer: A
Question: The length of each side of square A is increased by 100 percent to make square B. If the length of the side of square B is increased by 40 percent to make square C, by what percent is the area of square C greater than the sum of the areas of squares A and B?
Options:
A)75.00%
B)56.80%
C)110%
D)150%
E)180%
Rationale: Let length of each side of square A be 10
Area of A = 10^2 = 100
Since , length of each side of square A is increased by 100 percent to make square B
length of each side of square B = 2*10 = 20
Area of B = 20^2 = 400
Since , length of the side of square B is increased by 40 percent to make square C
length of each side of square C= 1.4*20 = 28
Area of C= 28^2 = 784
Difference in areas of C and cummulative areas of A and B = 784 -(400+100) = 284
percent is the area of square C greater than the sum of the areas of squares A and B = (284/500) * 100 % = 56.80%
Answer B
Answer: B
Question: In a certain large company, the ratio of college graduates with a graduate degree to non-college graduates is 1:8, and ratio of college graduates without a graduate degree to non-college graduates is 2:3. If one picks a random college graduate at this large company, what is the probability R this college graduate has a graduate degree?
Options:
A)1/11
B)1/12
C)1/13
D)3/19
E)3/43
Rationale: In believe the answer is D. Please see below for explanation.
0) we are told the following ratios
CGD - College Graduate with Degree
NCG - Non College Graduate
CGN - College Graduate no Degree
CGD NCG CGN
1 8
3 2
In order to make CGD and CGN comparable we need to find the least common multiple of 8 and 3 and that is 24 multiplying the first ratio by 3 and the second ratio by 8 we get
CGD NCG CGN
3 24 16
If one picks a random college graduate at this large company, what is the probability this college graduate has a graduate degree?
Nr of CGD = 3
Nr of CG = 3+ 16 = 19
Probability R of CGD / (CG) -> 3/19
Answer D
Answer: D
Question: How many three letter words are formed using the letters of the word TIME?
Options:
A)25
B)29
C)25
D)24
E)23
Rationale: The number of letters in the given word is four.
The number of three letter words that can be formed using these four letters is 4P3
= 4 * 3 * 2
= 24.
Answer: D
Answer: D
Question: 3034−(1002÷20.04)=?
Options:
A)1964
B)1984
C)2964
D)2984
E)None of these
Rationale: Explanation:
=3034−(1002/2004×100)
=3034−50=2984
Option D
Answer: D
Question: If A's height is 20% less than that of B, how much percent B's height is more than that of A?
Options:
A)66.66%
B)66.68%
C)66.766%
D)86.66%
E)25%
Rationale: Excess of B's height over A's = [(20/(100 - 20)] x 100%
= 25%
Answer: E)
Answer: E
Question: A train 50 m long is running at the speed of 30 km / hr. Find the time taken by it to pass a man standing near the railway line in seconds
Options:
A)5 sec
B)6 sec
C)7 sec
D)8 sec
E)3 sec
Rationale: Explanation:
Speed of the train = (60 x 5/18m / sec = 50/3 m/ sec.
Distance moved in passing the standing man = 100 m.
Required time taken = 50/(50/3) = (50 Ã—(3/50)) sec =3 sec
Answer: Option E
Answer: E
Question: Replace the ? by the correct Mathematics symbol to make the expression true
18 ? 12 ? 4 ? 5 = 59
Options:
A)18 ÷ 12 x 4 - 5 = 59
B)18 + 12 ÷ 4 - 5 = 59
C)18 x 12 + 4 - 5 = 59
D)18 x 12 ÷ 4 + 5 = 59
E)18 x 12 ÷ 4 - 5 = 59
Rationale: D
Answer: D
Question: (x + 5) is a factor in x^2 - mx - 40. What is the value of m?
Options:
A)1
B)2
C)4
D)3
E)5
Rationale: I solved the second degree equation and found it like this:
x^2 - mx - 40 = 0
(x-8)(x+5) = 0
x=8 or x= -5
Substituting both values for x in the equation we find:
x^2 - mx -40
=> (-5)^2 - m(-5) = 40
=> 25+ 5m= 40
=> 5m = 40-25=15
=> m = 3
And with 8, using a similar process we end up with:
(8)^2 - m(8) =40
-8m = 40-64= -24
m=3
Ao,ANS D
Answer: D
Question: Braun invested a certain sum of money at 8% p.a. simple interest for 'n' years. At the end of 'n' years, Braun got back 2 times his original investment. What is the value of n?
Options:
A)50 years
B)25 years
C)12 years 6 months
D)37 years 6 months
E)40 years
Rationale: Explanatory Answer
Let us say Braun invested $100.
Then, at the end of 'n' years he would have got back $200.
Therefore, the Simple Interest earned = 200 - 100 = $100.
We know that Simple Interest = (Principal * number of years * rate of interest) / 100
Substituting the values in the above equation we get 100 = (100 * n * 8) / 100
Or 8n = 100
Or n = 12.5years.
correct choice is (C)
Answer: C
Question: What percent is 120 of 60?
Options:
A)133 1/3 %
B)134 1/3 %
C)200 %
D)140 1/3 %
E)143 1/3 %
Rationale: 120/60 = 2/1
2 × 100 = 200 %
C
Answer: C
Question: A 300 m long train crosses a platform in 39 sec while it crosses a signal pole in 18 sec. What is the length of the platform?
Options:
A)327
B)350
C)276
D)287
E)261
Rationale: Speed = 300/18 = 50/3 m/sec.
Let the length of the platform be x meters.
Then, (x + 300)/39 = 50/3
3x + 900 = 1950 => x = 350 m.
Answer: B
Answer: B
Question: If six thousand six hundred and six dollar is written as $6,606, then write eleven thousand eleven hundred and eleven dollars.
Options:
A)$12,118
B)$12,119
C)$12,110
D)$12,115
E)$12,111
Rationale: E
$12,111
Answer: E
Question: If x > y and y > z, which of the following represents the greatest number W?
Options:
A) x − z
B) x − y
C) y − x
D) z − y
E) z − x
Rationale: Because x>y>z
thus W=x- z wil lbe greatest
Ans: A
Answer: A
Question: A certain car can travel 40 minutes on a gallon of gasoline at 50 miles per hour. If the car had started with a full tank and had 8 gallons of gasoline left in its tank at the end, then what percent of the tank was used to travel 80 miles at 60 mph?
Options:
A)15%
B)20%
C)25%
D)30%
E)40%
Rationale: Let, Tank capacity = T gallon
Used Fuel = (T-8) gallons
Distance Travelled (@50 miles/hr) = 80 miles
Distance travelled in 1 gallon = Distance travelled in 40 mins (@50 miles/hr) = (50/50)*40 = 40 miles
Fuel used to travel 80 miles = (80/40) = 2 gallon
i.e. Used fuel = (T-8) = 2 gallon
i.e. T = 10 Gallons
i.e. Used Fuel = (2/10)*100 =20%
B
Answer: B
Question: If 40% of a number is equal to two-third of another number, what is the ratio of first number to the second number.
Options:
A)2:5
B)2:7
C)5:7
D)5:3
E)None of these
Rationale: Explanation:
Let the first number is A and second number is B.
As per question
40/100A=2/3B
A/B=2/3∗100/40
A/B=5/3
=>A:B=5:3
Option D
Answer: D
Question: A, B and C can do a piece of work in 24 days, 30 days and 40 days respectively. They began the work together but C left 6 days before the completion of the work. In how many days was the work completed?
Options:
A)12 days
B)16 days
C)18 days
D)11.5 days
E)38 days
Rationale: One day work of A, B and C = 1/24 + 1/30 + 1/40 = 1/10 Work done by A and B together in the last 6 days = 6*(1/24 + 1/30) = 9/20
Remaining work = 11/20
The number of days required for this initial work = 5.5 days.
The total number of days required = 6 + 5.5 = 11.5 days.Answer: D
Answer: D
Question: In the infinite sequence 10, 15, 20, 25, 30, . . . , where each term is 5 greater than the previous term, the 32th term is
Options:
A)183
B)178
C)165
D)139
E)179
Rationale: T(n) = a + (n-1) d
Here d =5, a=10, n=32
Solving we get T(n) = 165.
Answer: C
Answer: C
Question: 6.2 is what percent of 1000?
Options:
A)62%
B)6.2%
C)0.62%
D)0.062%
E)0.0062%
Rationale: 10% of 1000 is 100.
6.2 is way less than 100 (10% of 1000).So it cannot be 62% of 1000. eliminate option a
1% of 1000 is 10.
6.2 is less than 10. So it cant be 6.2%.eliminate option b
(0.5%) i.e. half of 1% of 1000 is 5.
but 6.2 is greater than 5..
So it has to be greater than 0.5%...hence answer is 0.62%,
ANSWER:C
Answer: C
Question: What will be the reminder when (27^27+27) is divided by 28?
Options:
A)92
B)43
C)71
D)26
E)31
Rationale: (x^n+1) will be divisible by (x+1) only when n is odd;
(27^27+1) will be divisible by (27+1);
(27^27+1)+26 when divided by 28 will give 26 as remainder.
Correct Option : D
Answer: D