divelab/Sys2Bench huggingface dataset:
Question: The length of a rectangular floor is more than its breadth by 200%. If Rs. 324 is required to paint the floor at the rate of Rs. 3 per sq m, then what would be the length of the floor?
Options:
A)28
B)26
C)18
D)109
E)12
Rationale: Let the length and the breadth of the floor be l m and b m respectively.
l = b + 200% of b = l + 2b = 3b
Area of the floor = 324/3 = 108 sq m
l b = 108 i.e., l * l/3 = 108
l2 = 324 => l = 18.
Answer:C
Answer: C
Question: Machine C takes 2 more hours than machine B to make 20 widgets. If working together, the machines can make 25 widgets in 3 hours, how long will it take machine C to make 40 widgets?
Options:
A) 5
B) 6
C) 8
D) 10
E) 12
Rationale: i approached this one by plugging in numbers...started with C.
if 40 are made in 8 hours, then 20 are made in 4 hours. so time of C is 4, and time of B is 2.
rate together: 20/4 + 20/2 = 5+10 = 15. so in 1 hour, together make 15 widgets. in 3 hours = 45. way too much. we can eliminate right away C, B, and A - because B and C reduces the time - the total # of widgets made will be even higher.
now between D and E -> try only one ..if it doesn't work, then the other one is the answer.
i picked E:
12h to make 40 widgets, and 6 hours to make 20. this is the time of C. time of B=4 hours.
20/6 + 20/4 = 10/3 + 20/4
find LCM of 3 and 4 = 12. multiply first by 4, and second by 3:
40+60/12 = 100/12
divide by 4:
25/3
so this is the rate given.
E is the correct answer
Answer: E
Question: 50 boys and 100 girls are examined in a test; 50% of the boys and 40% of the girls pass. The percentage of the total who failed is ?
Options:
A)42.5%
B)62.1%
C)56.7%
D)39.9%
E)51.4%
Rationale: Total number of students = 50+100 = 150
Number of students passed = (50% of 50+40% of 100) = 25+40 = 65
number of failures = 85*100/150 = 56.7%
Answer is C
Answer: C
Question: What is the cost of leveling the field in the form of parallelogram at the rate of Rs.50/10 sq.metre, whose base & perpendicular distance from the other side being 54m & 24m respectively?
Options:
A)Rs. 6000
B)Rs. 6300
C)Rs. 6400
D)Rs. 6480
E)Rs. 7000
Rationale: Area of the parallelogram = Length of the base * Perpendicular height
= 54 * 24 = 1296 m.
Total cost of levelling = Rs. 6480
D
Answer: D
Question: The radius of a cone is 4 m, height 5 m. Find the curved surface area?
Options:
A)1
B)3
C)5
D)7
E)9
Rationale: Cone curved surface area = πrl = 22/7 × 4 × 5 = 440/7 = 62 6/7
Slant height (l) = √r(power2)+h(power2) = √16+9 = √25 = 5
Answer: C
Question: Product of two co-prime numbers is 117. Their L.C.M should be
Options:
A)1
B)117
C)equal to their H.C.F
D)cannot be calculated
E)None
Rationale: Solution
H.C.F of co-prime numbers is 1.
So, L.C.M	= 117/1
‹=› 117.
Answer B
Answer: B
Question: Find the C.I. on a sum of Rs.1600 for 9 months at 20% per annum, interest being compounded quarterly?
Options:
A)2888
B)2689
C)2522
D)277
E)2911
Rationale: A = 1600(21/20)3 = 2522.Answer: C
Answer: C
Question: Working alone at its constant rate, machine A produces x boxes in 10 minutes and working alone at its constant rate, machine B produces 2x boxes in 5 minutes. How many minutes does it take machines A and B, working simultaneously at their respective constant rates, to produce 4x boxes?
Options:
A)3 minutes
B)4 minutes
C)5 minutes
D)6 minutes
E)8 minutes
Rationale: Rate = Work / Time
Given Rate of Machine A = X / 10 min
Machine B Produces 2x boxes in 5 min hence , Machine B produces 4x boxes in 10 min .
Rate of Machine B = 4x / 10
we need tofind the combined time that machines A and B, working simultaneouslytakeat their respective constant rates
let's first find the combined Rate of Machine A and B
Rate of Machine A = X / 10 min + Rate of Machine B = 4x / 10 = 5X/10
Now combine Time = combine work needs to be done / Combine Rate = 4x/5x * 10 = 8 Min
Ans: E
Answer: E
Question: A 600 meter long train crosses a signal post in 40 seconds. How long will it take to cross a 5.4 kilometer long bridge, at the same speed?
Options:
A)4 min
B)2 min
C)8 min
D)6 min
E)3 min
Rationale: S = 600/40 = 15 mps
S =5400/15 = 360 sec = 6 min.Answer:D
Answer: D
Question: The average of 6 observations is 15. A new observation is included and the new average is decreased by 1. The seventh observation is?
Options:
A)1
B)8
C)5
D)6
E)7
Rationale: Let seventh observation = X.
Then, according to the question we have
=> (90 + X) / 7 = 14
=> X = 8
Hence, the seventh observation is 8
ANSWER:B
Answer: B
Question: A man saves 20% of his monthly salary. If an account of dearness of things he is to increase his monthly expenses by 20%, he is only able to save Rs. 200 per month. What is his monthly salary?
Options:
A)6000
B)5000
C)5500
D)4000
E)3500
Rationale: Income = Rs. 100
Expenditure = Rs. 80
Savings = Rs. 20
Present Expenditure 80*(20/100) = Rs. 96
Present Savings = 100 â€“ 96 =Rs. 4
100 ------ 4
? --------- 200 => 5000
ANSWER B
Answer: B
Question: A bag contains 12 white and 18 black balls.Two balls are drawn in succession without replacement. What is the probability that first is white and second is black?
Options:
A)36/145
B)29/145
C)18/145
D)20/145
E)15/145
Rationale: The probability that first ball is white=12C1/30C1=12/30=2/5
Since.the balls is not replaced; hence the number of balls left in bag=29.
Hence the probability of second ball is black is 18C1/29C1=18/29
Required probability =(2/5)*(18/29)=36/145
The answer is option A
Answer: A
Question: With a uniform speed a car covers the distance in 8 hours. Had the speed been increased by 4 km/hr, the same distance could have been covered in 7 1/2 hours. What is the distance covered?
Options:
A)400 km
B)480 km
C)490 km
D)380 km
E)330 km
Rationale: B
480 km
Let the distance be x km. Then,
x/(7 1/2) - x/8 = 4
2x/15 - x/8 = 4 => x = 480 km.
Answer: B
Question: The average monthly salary of 20 employees in an organisation is Rs. 1700. If the manager's salary is added, then the average salary increases by Rs. 100. What is the manager's monthly salary ?
Options:
A)3800
B)3890
C)88798
D)2789
E)2891
Rationale: Explanation:
Manager's monthly salary Rs. (1800 * 21 - 1700 * 20) = Rs. 3800.
Answer: A) 3800
Answer: A
Question: What profit percent is made by selling an article at a certain price, if by selling at 2/3rd of that price, there would be a loss of 20%?
Options:
A)20%
B)70%
C)29%
D)50%
E)24%
Rationale: SP2 = 2/3 SP1
CP = 100
SP2 = 80
2/3 SP1 = 80
SP1 = 120
100 --- 20 => 20%
Answer:A
Answer: A
Question: Each year for 4 years, a farmer increased the number of trees in a certain orchard by 1/4 of the number of trees in the orchard of the preceding year. If all of the trees thrived and there were 1250 trees in the orchard at the end of 4 year period, how many trees were in the orchard at the beginning of the 4 year period.
Options:
A)513
B)512
C)517
D)519
E)521
Rationale: Trees increase by 1/4 the number of trees in preceding year. Hence, correct answer must be divisible by 4. Based on divisibility rules, if last 2 digits are divisible by 4 then the number is divisible by 4. Thus, we can eliminate A, C, D,E The answer to be B
Again, trees increase by 1/4 the number of trees in preceding year. Hence, the number of trees increase by 5/4 times the number of trees the preceding year.
If x = initial number of trees = 512
Year 1 = 5/4x
Year 2 = (5/4)(5/4)x
Year 3 = (5/4)(5/4)(5/4)x
Year 4 = (5/4)(5/4)(5/4)(5/4)x
Only for Answer D: (5/4)(5/4)(5/4)(5/4) 512 = 1250
Hence, correct answer = B
Answer: B
Question: In a forest 170 deer were caught, tagged with electronic markers, then released. A week later, 50 deer were captured in the same forest. Of these 50 deer, it was found that 5 had been tagged with the electronic markers. If the percentage of tagged deer in the second sample approximates the percentage of tagged deer in the forest, and if no deer had either left or entered the forest over the preceding week, what is the approximate number of deer in the forest?
Options:
A)150
B)750
C)1,250
D)1,700
E)2,500
Rationale: The percentage of tagged deer in the second sample = 5/50*100=10%.
So, 170 tagged deers comprise 10% of total # of deers --> total # of deers = 170*10 = 1,700.
Answer: D.
Answer: D
Question: Fresh grapes contain 60% water by weight and raisins obtained by drying fresh grapes contain 25% water by weight. How many kgs of fresh grapes are needed to get 20kgs of raisins?
Options:
A)75 kgs
B)64kgs
C)37.5 kgs
D)65 kgs
E)70 kgs
Rationale: The weight of non-water in 20 kg of dried grapes (which is 100-25=75% of whole weight) will be the same as the weight of non-water in x kg of fresh grapes (which is 100-60=40% of whole weight),
so 20*0.75 = x*0.4
--> x = 37.5.
Answer: C
Answer: C
Question: In a school 50% of the students are younger than 10, 1/20 are 10 years old and 1/10 are older than 10 but younger than 12, the remaining 70 students are 12 years or older. How many students are 10 years old?
Options:
A)20
B)40
C)10
D)39
E)48
Rationale: Let us write the fraction for each group of students
Group A: younger than 10: 50% = 50/100 = 1/2
Group B: 10 years old: 1/20
Group C: older that 10 but younger than 12: 1/10
Group D: 12 years or older: 70 students
The fraction for group A, B and C together is given by
1 / 2 + 1 / 20 + 1 / 10 = 10 / 20 + 1 / 20 + 2 / 20 , common denominator
= 13 / 20 , add numerators
The fraction for group D is given by
20 / 20 - 13 / 20 = 7 / 20 and corresponds to 70 students
If X is the total number of students, then
7 / 20 of X = 70
or (7 / 20) * X = 70
Solve for X
X = 70 * (20 / 7) = 200
Students who are 10 years old have a fraction of 1 / 20 of the total X and their number is equal to
(1 / 20) of 200 = 10 students
correct answer C
Answer: C
Question: Two employees X and Y are paid a total of Rs. 550 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?
Options:
A)250
B)100
C)150
D)300
E)200
Rationale: Let amount paid to X per week = x
and the amount paid Y per week = y
x=120% of y = 120y/100 = 12y/10
22y/10=550
y=250
ANSWER A
Answer: A
Question: X and Y are integers, X is even and negative, Y is odd and positive. Which of the following could be false?
1. (X + Y) is an odd number.
2. Y^(X + Y) is an integer.
3. X^Y is a negative number.
Options:
A)2 only.
B)3 only.
C)1 and 3 only.
D)2 and 3 only.
E)1, 2 and 3.
Rationale: Statement I is TRUE
Statement II is not TRUE
Statement III is TRUE
Answer : C
Answer: C
Question: The speed of a boat in still water is 60kmph and the speed of the current is 20kmph. Find the speed downstream and upstream?
Options:
A)17 kmph
B)40 kmph
C)18 kmph
D)13kmph
E)19 kmph
Rationale: Speed downstream = 60 + 20 = 80 kmph
Speed upstream = 60 - 20
= 40 kmph
Answer:B
Answer: B
Question: A shopkeeper sells an article for Rs. 200 with a loss of Rs. 20 %. Find the cost price of the article.
Options:
A)220
B)250
C)280
D)260
E)275
Rationale: Explanation:
Hint:
Cost Price =	100/(100-Loss%)*S.P.
We are given that,
S.P. = Rs. 200 and loss = 20
Cost Price =	100/(100-20)*200
Cost Price =	100/80*200
Cost Price = Rs. 250
ANSWER IS B
Answer: B
Question: A city had 300 migrants in the year 2000. Since then, The number of migrants in a countrythe city has doubled every 3 years. If there were 300 migrants in the country in the year 2000, What was the increase in the population of migrants during the period from 2009 to 2012?
Options:
A)1200
B)2400
C)4800
D)6800
E)8400
Rationale: The population will increase in the following order:
2000: 300
2003: 600
2006: 1200
2009: 2400
2012: 4800
Difference between 2009 and 2012 = 2400
Option B
Answer: B
Question: To save money, Arkadelphia Cream Cheese will reduce each dimension of its rectangular box container (which is entirely full of cream cheese) by 20%, and reduce the price it charges its consumers by 20% as well. By what percentage does this increase the price-per-cubic-inch that each consumer will pay for cream cheese?
Options:
A)1. No change
B)2. 56.25%
C)3. 100%
D)4. 300%
E)5. 400%
Rationale: Let,
L = 20: B = 10: H= 10 of initial box and Price = 50$
Therefore Price / cubic inch = 50 / (20*10*10) =0.025
Now, when dimensions are reduced by 50% and price also reduced by 50%
L = 16; B=8; H=8 and Price = 40$
Therefore price / cubic inch = 40 / (16*8*8) =0.039
Percentage change = (0.039 - 0.025) *100/ 0.025 = 56.25%
Answer is B
Answer: B
Question: If n=3*4*p where p is a prime number greater than 3,how many different positive non-prime divisors does n have, excluding 1 and n?
Options:
A)Six
B)Seven
C)Eight
D)Nine
E)Ten
Rationale: n=3∗2^2∗p
Number of divisors = 2 * 3 * 2 = 12
The 12 divisors includes 1, n, 3, 2 and p
Number of different non prime divisors excluding 1 and n = 12 - 5 = 7
Answer: B
Answer: B
Question: The least number which should be added to 1789 so that the sum is exactly divisible by 5, 6, 4 and 3 is?
Options:
A)1
B)11
C)21
D)31
E)41
Rationale: L.C.M. of 5, 6, 4 and 3 = 60.
On dividing 1789 by 60, the remainder is 49.
Number to be added = (60 - 49) = 11
B)
Answer: B
Question: 16 boys or 24 girls can construct the wall in 6 days. the number of days that 16 boys and 12 girls Will take to construct?
Options:
A)7 days
B)4 days
C)6 days
D)8 days
E)9 days
Rationale: Explanation:
16 boys =24 girls, 1 boy = 24/16 girls
1 boy = 6/4 girls
16 boys + 12 girls = 16 Ã— 6/4 + 12 = 24+ 12 = 36 girls
4 days to complete the work
Answer: Option B
Answer: B
Question: What will be the ratio of simple interest earned by certain amount at the same rate of interest for 25 years and that for 40 years?
Options:
A)5:8
B)7:5
C)3:8
D)Data inadequate
E)None of these
Rationale: Let the principal be P and rate of interest be R%.
∴ Required Ratio = [(P×R×25/100) /(P×R×40/100)]=25PR/40PR=25/40=5:8
Answer A
Answer: A
Question: Shipment --- No. of Defective Chips/shipment --- Total Chips in shipment
S1 ---------------------- 2 ------------------------------------------ 5,000
S2 ---------------------- 4 ------------------- ---------------------- 12,000
S3 ---------------------- 2 ------------------------------------------ 15,000
S4 ---------------------- 4 ------------------------------------------ 16,000
A computer chip manufacturer expects the ratio of the number of defective chips to the total number of chips in all future shipments to equal the corresponding ratio for shipments S1, S2, S3, and S4 combined, as shown in the table above. What’s the expected number of defective chips in a shipment of 60,000 chips?
Options:
A)14
B)20
C)22
D)24
E)15
Rationale: for a total of 51000 chips (adding S1,S2,S3,S4) total number of defective chips is 17 ((adding defective chips of S1,S2,S3,S4) so ratio is 12/48000 or 1 every 4000 chips.
Keeping this ratio constant for 60000 chips number of defective chips will be (1/4000) * 60000 = 15
E
Answer: E
Question: A and B walk around a circular track. They start at 8 a.m. from the same point in the opposite directions. A and B walk at a speed of 2 rounds per hour and 3 rounds per hour respectively. How many times shall they cross each other before 11.00 a.m. ?
Options:
A)15
B)12
C)10
D)12
E)8
Rationale: A
15
Relative speed = 2 + 3 = 5 rounds per hour.
So, they cross each other 5 times in an hour and 2 times in half an hour.
Hence, they cross each other 15 times before 11.00 a.m.
Answer: A
Question: A person was asked to state his age in years. His reply was, "Take my age three years hence, multiply it by 3 and then subtract three times my age three years ago and you will know how old I am." What was the age of the person?
Options:
A)18 years
B)12 years
C)5 years
D)9 years
E)21 years
Rationale: Answer: Option A
Let the present age of the person be x years.
Then, 3(x + 3) - 3(x - 3) = x
3x + 9 - 3x + 9 = x => x = 18
Answer: A
Question: A construction company wants to number new houses using digit plates only. If the company puts an order for 912 plates, how many houses are to be given numbers? (The numbers of houses are consecutive and the number of the first house is 1).
Options:
A)320
B)350
C)340
D)360
E)400
Rationale: You know that the answer is going to be three digits, and it's easy to figure out how many 1 and 2 digit numbers (9 and 90), so the real question is how many 3 digit number are there?
99+(912-9-90*2)/3=340
Answer : C
Answer: C
Question: The compound interest on $ 30,000 at 7% p.a is $. 4347.Find out the period (in years) ?
Options:
A)1
B)1.5
C)2
D)2.5
E)3
Rationale: Amount = 30,000 + 4347
= 34347 ......... Now by using compound interest formula we get, 30,000 * (107/100)^n = 34347 ====> n = 2 years Ans - C
Answer: C
Question: A company has two types of machines, type R and type S. Operating at a constant rate, a machine of type R does a certain job in 50 hrs and a machine of type S does the same job in 20 hours. If the company used the same number of each type of machine to do the job in 5 hours, how many machines of type R were used?
Options:
A)18/7
B)16/7
C)15/7
D)22/7
E)20/7
Rationale: Rate of machine R =1/50
Rate of machine S =1/20
since same no of machines used for R and S to do the same work in 5 hrs
So collective rate needed to finish the work in 5 hrs= 1/5
Let the no of machine be x
So, x/50 +x/20 =1/5
(2x+5x)/100=1/5
7x=20
x=20/7
So no of machine R is 20/7
Answer E
Answer: E
Question: In 2 Kg mixture of copper and aluminium, 30% is copper. How much aluminium powder should be added to the mixture so that the proportion of copper becomes 20%
Options:
A)800 gm
B)600 gm
C)1200 gm
D)900 gm
E)1000 gm
Rationale: Mixture = 2 kg = 2000g.
Copper = 30% of 2000 = 600g.
To make copper 20% of mixture, we should need to mix 1000g of Aluminum.
As,
2000 + 1000 = 3000g mixture.
And 20% of 3000 = 600g.
ANSWER : B
Answer: B
Question: In an election between two candidates, 75% of the voters cast thierthier votes, out of which 2% of the votes were declared invalid. A candidate got 9261 votes which were 75% of the total valid votes. Find the total number of votes enrolled in that election.
Options:
A)15000
B)15500
C)16800
D)17500
E)18000
Rationale: Let the number of votes enrolled be x. Then ,
Number of votes cast =75% of x. Valid votes = 98% of (75% of x).
75% of (98% of (75%of x)) =9261.
[(75/100)*(98/100)*(75/100)*x] =9261.
X = [(9261*100*100*100)/(75*98*75)] =16800.
ANSWER C
Answer: C
Question: For any positive integer n, the sum of the first n positive integers equals n(n+1)/2. What is the sum of all the even integers between 1 and 100?
Options:
A)1250
B)1530
C)2120
D)2540
E)2550
Rationale: Average of the set: (largest+smallest)/2=(100+2)/2=51;
# of terms: (largest-smallest)/2+1=(100-2)/2+1=50
The sum = 51*50= 2550
Answer: E
Answer: E
Question: How much time will it take for an amount of Rs. 450 to yield Rs. 81 as interest at 4.5% per annum of simple interest?
Options:
A)3.5 years
B)4years
C)4.5years
D)5years
E)None of these
Rationale: Explanation:
Time = (100 x 81)/(450 x 4.5) years
= 4 years.
Answer: B
Answer: B
Question: A certain company expects quarterly earnings of $0.80 per share of stock, half of which will be distributed as dividends to shareholders while the rest will be used for research and development. If earnings are greater than expected , shareholders will receive an additional $0.04 per share for each additional $0.10 of per share earnings. If quarterly earnings are $1.10 per share, what will be the dividend paid to a person who owns 500 shares of the company's stock?
Options:
A)$260
B)$96
C)$26
D)$120
E)$240
Rationale: EPS Actual> EPS expected.
each gets and additional .12 per share.
Thus .52*500 --> $260
answer is A
Answer: A
Question: If the radius of a circle is decreased by 50%, find the percentage decrease in its area.
Options:
A)25 %
B)50 %
C)75 %
D)95 %
E)None of them
Rationale: Let original radius = R. New radius =(50/100) R = (R/2)
Original area=22/7( R )2= and new area=  ((R/2))2= ( ( R )2)/4
Decrease in area =((3(22/7) (R )2 )/4 X (1/(22/7)( R)2) X 100) % = 75%
Answer is C.
Answer: C
Question: I sold a book at a profit of 10%. Had I sold it for $90 more, 15% would have been gained. Find the cost price?
Options:
A)$1800
B)$2500
C)$3000
D)$3120
E)$1540
Rationale: 115% of cost - 110% of cost = $90
5% of cost = $90
cost = 90*100/5 = $1800
Answer is A
Answer: A
Question: A, B, C and D enter into partnership. A subscribes 1/3 of the capital B 1/4, C 1/5 and D the rest. How much share did A get in a profit of Rs.2460?
Options:
A)12211
B)22777
C)29777
D)14000
E)21689
Rationale: 25*12: 30*12: 35*8
15:18:14
14/47 * 47000 = 14000
Answer:D
Answer: D
Question: Mr. Evans will states that each of his children will receive an equal share of his estate and that his grandchildren will split a portion of the estate that is equal to the share received by each of his children. If Mr. Evans has 2 children and 6 grandchildren, then approximately what percentage of Mr. Evans estate will each grandchild receive?
Options:
A)20%
B)17%
C)5.5%
D)3.3%
E)2.8%
Rationale: 33.33/6=5.5
Answer : C
Answer: C
Question: Four circular cardboard pieces, each of radius 7cm are placed in such a way that each piece touches two other pieces. The area of the space encosed by the four pieces is
Four circular cardboard pieces, each of radius 7cm are placed in such a way that each piece touches two other pieces. The area of the space encosed by the four pieces is
Options:
A)3
B)87
C)42
D)767
E)27
Rationale: Explanation:
required area = 14*14 - (4 * 1/4 * 22/7 * 7 *7) sq cm
= 196 - 154 = 42 sq cm.
Answer: C) 42
Answer: C
Question: If 23 lines are drawn in a plane such that no two of them are parallel and no three are concurrent, then in how many points do they intersect?
Options:
A)176
B)253
C)342
D)458
E)560
Rationale: If two lines are not parallel, then they will intersect in exactly one point. Lines can be extended infinitely on both ends so somewhere they will intersect with each other if they are not parallel. We are also given that no three lines are concurrent. This means that no three lines intersect at the same point. So every pair of two lines we select will have a unique point of intersection which they will not share with any third line.
The number of ways to select 2 lines from 23 lines is 23C2 = 253
The answer is B.
Answer: B
Question: Farmer Charlie has a chicken farm. On a certain day, Charlie calculates in how many days he will run out of chicken-food. He notices that if he would sell 75 of his chickens, he could feed the remaining chickens twenty days longer with the chicken-food he has, and that if he would buy 100 extra chickens, he would run out of chicken-food fifteen days earlier.
One chicken lays two eggs in three days. How many eggs do three chickens lay in nine days?
Options:
A)11
B)17
C)18
D)20
E)23
Rationale: C
18
1 chicken lays 2 eggs in 3 days, so 3 chickens lay 3×2=6 eggs in 3 days. In 9 days, these 3 chickens lay 3 times as much eggs as in 3 days. Conclusion: three chickens lay 3×6=18 eggs in nine days.
Answer: C
Question: In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is:
Options:
A)1hour
B)2hour
C)3hour
D)4hour
E)5hour
Rationale: Let the duration of the flight be x hours
Then 600/x - 600/x (1/2) = 200
= 600/x - 1200/2x+1 =200
=x(2x+1) =3
=2xsquare + x -3 = 0
=(2x+3)(x-1) = 0
= x= 1 hr ( neglecting the -ve value of x)
Answer: Option A
Answer: A
Question: Two numbers are in the ratio 3 : 4. If their L.C.M. is 72. what is sum of the numbers?
Options:
A)42
B)56
C)76
D)84
E)85
Rationale: Explanation:
Let the numbers be 3x and 4x
LCM of 3x and 4x = 12x (Since LCM of 3 and 4 is 12. Hence LCM of 3x and 4x is 12x)
Given that LCM of 3x and 4x is 72
=> 12x = 72
=> x = 72/12 = 6
Sum of the numbers
= 3x + 4x
= 7x
= 7 x 6 = 42
Answer: Option A
Answer: A
Question: Youseff lives x blocks from his office. It takes him 1 minute per block to walk to work and 20 seconds per block to ride his bike to work. It is takes him exactly 14 minutes more to walk to work than to ride his bike to work, then x equals?
Options:
A)4
B)7
C)10
D)15
E)21
Rationale: Please follow posting guidelines, link is in my signatures.
As for your question, x/60 = blocks/time/block = block^2/time . This is not what you want. You are given x blocks and 60 seconds PER BLOCK. Thus you need to put it as 60*x to give you units of seconds as you are equating this to 840(which is TIME in seconds.).
Thus the correct equation is : 60*x-20*x=840 ----> 40x=840-> x = 21.
option E
Answer: E