divelab/Sys2Bench huggingface dataset:
Question: FAG, GAF, HAI, IAH, ____
Options:
A)SIK
B)IKP
C)PLE
D)JAK
E)EWR
Rationale: The middle letters are static, so concentrate on the first and third letters. The series involves an alphabetical order with a reversal of the letters. The first letters are in alphabetical order: F, G, H, I , J. The second and fourth segments are reversals of the first and third segments. The missing segment begins with a new letter.
ANSWER:D
Answer: D
Question: The length of the bridge, which a train 130 meters long and travelling at 45 km/hr can cross in 30 seconds, is:
Options:
A)200 m
B)225 m
C)245 m
D)250 m
E)260 m
Rationale: Explanation:
Speed = (45 * 5/18) m/sec = (25/2) m/sec. Time = 30 sec. Let the length of bridge be x meters. Then, (130 + X)/30 = 25/2 ==> 2(130 + X) = 750 ==> X = 245 m.
ANSWER IS C
Answer: C
Question: It takes Jim two hours to wash the car and it takes Julia one hour to wash the car. Working together, how many minutes will it take them to wash the car?
Options:
A)36
B)38
C)40
D)42
E)44
Rationale: Jim can wash (1/2) of the car per hour.
Julia can wash 1 car per hour.
Together they can wash 1/2+1=3/2 cars per hour.
1 car / (3/2) cars per hour = 2/3 hours = 40 minutes.
The answer is C.
Answer: C
Question: If the cost price is 96% of selling price then what is the profit percentage.
Options:
A)7.14
B)7.41
C)4.71
D)4.17
E)None of them
Rationale: selling price=Rs100 : then cost price=Rs 96:profit =Rs 4.
Profit={(4/96)*100}%=4.17%
Answer is D.
Answer: D
Question: After spending Rs. 5000 on rent, Rs. 1500 on milk, Rs. 4500 on groceries, Rs.2500 On childrens education Rs. 2000 on petrol and Rs. 2500 on miscellaneous expenses, Mr. Kishore saved 10% of his monthly salary. How much did he save in Rs. ?
Options:
A)2160
B)2350
C)2000
D)2300
E)None of these
Rationale: Explanation :
Total Exp = 5000+1500+4500+2500+2000+2500 = 18000
Exp in % = 100-10 = 90%, 18000 = 90%
Saving = 10 % = 18000 X 10/90 = Rs. 2000
Answer : C
Answer: C
Question: The least number which should be added to 6320 so that the sum is exactly divisible by 4, 6, 7 and 9 is:
Options:
A)112
B)212
C)252
D)239
E)232
Rationale: L.C.M. of 5, 6, 4 and 3 = 252.
On dividing 6320 by 252, the remainder is 20.
Number to be added = (252 - 20) = 232. Answer: Option 'E'
Answer: E
Question: The price of commodity X increases by 45 cents every year, while the price of commodity Y increases by 20 cents every year. In 2001, the price of commodity X was $4.20 and the price of commodity Y was $6.30. In which year will the price of commodity X be 65 cents more than the price of commodity Y?
Options:
A)2010
B)2011
C)2012
D)2013
E)2014
Rationale: The price of commodity X increases 25 cents each year relative to commodity Y.
The price difference is $2.10 and commodity X needs to be 65 cents more than commodity Y.
$2.75 / 25 cents = 11 years
The answer is 2001 + 11 years = 2012.
The answer is C.
Answer: C
Question: How long does a train 120 m long running at the speed of 70 km/hr takes to cross a bridge 150 m length?
Options:
A)12.7 sec
B)13.9 sec
C)18.1 sec
D)17.1 sec
E)19.7 sec
Rationale: Speed = 70 * 5/18
= 19.4 m/sec
Total distance covered
= 120 + 150 = 270 m.
Required time = 270/19.4 '
= 13.9 sec.
Answer:B
Answer: B
Question: When running a mile during a recent track meet, Nuria was initially credited with a final time of 5 minutes, 39 seconds. Shortly after her run, officials realized that the timing mechanism malfunctioned. The stopwatch did not begin timing her until 11/25 of a minute after she began to run. If the time was otherwise correct, how long did it actually take Nuria to run the mile?
Options:
A)5 minutes, 17.6 seconds
B)6 minutes, 10.4 seconds
C)5 minutes, 43.56 seconds
D)5 minutes, 44.44 seconds
E)5 minutes, 21.8 seconds
Rationale: One approach:
The watch starts to work after Nuria began his running. It means the time should be greater than credited 5 minutes, 44 seconds. The only number is 6 minutes, 10.4 seconds.
Another approach:
11/25 close to 30 second when added to the 5 minutes, 44 seconds, it means it passes 6 minute.
Answer: B
Answer: B
Question: Six students are equally divided into 3 groups, then, the three groups were assigned to three different topics. How many different arrangements W are possible?
Options:
A) 30
B) 60
C) 90
D) 180
E) 540
Rationale: 90 is the number of ways you can assign 3 teams formed out of 12 people to 3 different tasks.
But now you can order the 3 tasks in 3! ways. T1 T2 T3 or T2 T1 T3.... etc etc.
I was confused between 90 and 540 but since question used the wordarrangementsdecided to go with complete arrangements W including the order of tasks.
could you explain the highlighted step... i'm getting 90 = 15 * 3!
suppose the students are numbered 1,2,3,4,5,6 and tasks are X,Y and Z
one of the 15 possible ways of forming teams is 12, 34, 56. these teams can be assigned to 3 tasks in 3! = 6 ways
X--	Y--	Z
12--	34--	56
12--	56--	34
34--	12--	56
34--	56--	12
56--	12--	34
56--	34--	12
so the answer should be 15*6 = 90
But now you can fruther decide which task you want to perform first X Y or Z..=C
Answer: C
Question: 1+2+2^2=？
Options:
A)(2^3-1)(2^3+1)
B)2^6+1
C)2^5-1
D)2^5+1
E)2^3-1
Rationale: From 1+2+2^2=1(2^6-1)/(2-1)=2^3-1, the correct answer is E.
Answer: E
Question: There are three piles of books A,B and C having 3,4,5 books respectively.These books have to be picked up and put in a shelf one by one.How many possible sequence can be formed in the shelf if a book can be picked only from top of any pile?
Options:
A)12!
B)3!*4!*5!
C)12C3*9C4
D)12^12
E)12^14
Rationale: SINCE WE SHOULD FILL ONLY FROM TOP.........12! IS NOT CORRECT
WE HAVE POSSIBILTY OF FILLING ALL 5 FROM C AND GO TO A,B 0R 1 EACH FROM EACH PILE OR 2..........SO 3!*4!*5! AND 12C3*9C4 ARE ALSO WRONG.REMAINING OPTION IS ........12^12
ANSWER:D
Answer: D
Question: If a train, travelling at a speed of 120 kmph, crosses a pole in 6 sec, then the length of train is?
Options:
A)281
B)125
C)200
D)266
E)121
Rationale: D = 120* 5/18 * 6
= 200 m
Answer: C
Answer: C
Question: 3 women and a few men participated in a chess tournament. Each player played two matches with each of the other players. If the number of matches that men played among themselves is 78 more than those they played with the women, how many more men than women participated in the tournament?
Options:
A)10
B)11
C)8
D)9
E)5
Rationale: Let x be the number of men.
Number of matches men play among themselves is 2*(xC2)
Number of matches men play with women is 2*(3x)
2*(xC2) - 2*(3x) =78
x=13
Difference between men and women is 13-3=10.
ANSWER A
Answer: A
Question: What is the remainder when 43^87 is divided by 5?
Options:
A)0
B)1
C)2
D)3
E)4
Rationale: The units digit of the exponents of 3 cycle in a group of 4: {3, 9, 7, 1}
87 has the form 4k+3 so the units digit of 43^87 is 7.
The remainder when dividing by 5 is 2.
The answer is C.
Answer: C
Question: A vessel of capacity 90 litres is fully filled with pure milk. Nine litres of milk is removed from the vessel and replaced with water. Nine litres of the solution thus formed is removed and replaced with water. Find the quantity of pure milk in the final milk solution?
Options:
A)72.8 litres
B)72.9 litres
C)74.9 litres
D)72.4 litres
E)72.7 litres
Rationale: Let the initial quantity of milk in vessel be T litres.
Let us say y litres of the mixture is taken out and replaced by water for n times, alternatively.
Quantity of milk finally in the vessel is then given by [(T - y)/T]n * T
For the given problem, T = 90, y = 9 and n = 2.
Hence, quantity of milk finally in the vessel
= [(90 - 9)/90]2 (90) = 72.9 litres.
Answer:B
Answer: B
Question: Convert the 13/36 m/s into kilometers per hour?
Options:
A)1.7
B)1.5
C)1.3
D)1.1
E)1.2
Rationale: 13/36 m/s = 13/36 * 18/5 = 13/10
= 1.3 kmph.
Answer: C
Answer: C
Question: Two letters from the word MYANTKAR are selected at random. What is the probability that at least one of the selected letters is a consonant?
Options:
A)27/28
B)25/28
C)29/28
D)32/28
E)42/28
Rationale: There are 6 consonants and 2 vowels in MYANTKAR .
probability that at least one of the selected letters is a consonant = 1 - (Probability of both vowels)
Probability of both vowels = 2C2/8C2 = 1/28
So,Answer is 1 - 1/28 = 27/28
Answer : A
Answer: A
Question: If 6 (A's capital) = 8 (B's capital) = 10 (C's capital). Then the ratio of their capitals is?
Options:
A)20:15:17
B)20:15:19
C)20:15:12
D)20:15:18
E)20:15:23
Rationale: 6A = 8B = 10 C
A:B:C = 1/6:1/8:1/10
= 20:15:12
Answer: C
Answer: C
Question: At the rate of 6%p.a SI, a sum of Rs. 2500 will earn how much interest by the end of 5 years?
Options:
A)750
B)650
C)250
D)980
E)950
Rationale: 2500--->5 * 6%= 30%(2500) =750Ans A
Answer: A
Question: If n is a prime number greater than 5, what is the remainder when n^2 is divided by 23?
Options:
A)0
B)1
C)2
D)3
E)5
Rationale: There are several algebraic ways to solve this question including the one under the spoiler. But the easiest way is as follows:since we can not have two correct answersjust pick a prime greater than 5, square it and see what would be the remainder upon division of it by 23.
n=5 --> n^2=49 --> remainder upon division 49 by 23 is 3.
Answer: D.
Answer: D
Question: If the compound interest on a certain sum for 2 years in Rs. 80.80 and the simple interest Rs. 80; then the rate of interest per annum is
Options:
A)2%
B)1%
C)3%
D)4%
E)5%
Rationale: Explanation:
Let the sum be P and Rate of Interest be R% per annum
Simple Interest on Rs.P for 2 years = 80
PRT/100 = 80
(PR × 2)/100 = 80
PR/50 = 80
PR = 4000 - -- (equation 1)
Compound Interest = P(1 + R/100)T - P
= P(1 + R/100)2 - P
= P[(1 + R/100)2 - 1] = P[(1 + 2R/100 + R2/10000) - 1] = P(2R/100 + R2/10000)
= 2PR/100 + PR2/10000
= 2PR/100 + (PR × R)/10000
= [2 × 4000]/100 + (4000 × R)/10000 ( substituted the value of PR from equation 1)
= 80 + 0.4R
Given that compound interest = Rs.80.80
=> 80 + 0.4R = 80.80
=> 0.4R = 0.80
=> R = 0.80/0.4 = 2%
Answer: Option A
Answer: A
Question: In how many ways can a group of 5 men and 2 women be made out of a total of 7 men and 3 women?
Options:
A)63
B)93
C)103
D)83
E)135
Rationale: Required number of ways = (7C5 x 3C2) = (7C2 x 3C1) =	(7 x 6/2 x 1) x 3= 63.
Answer : A.
Answer: A
Question: A train moves past a post and a platform 264 m long in 8 seconds and 20 seconds respectively. What is the speed of the train?
Options:
A)79.0
B)79.2
C)79.5
D)79.7
E)79.6
Rationale: Let x is the length of the train and v is the speed
Time taken to move the post = 8 s
=> x/v = 8
=> x = 8v --- (1)
Time taken to cross the platform 264 m long = 20 s
(x+264)/v = 20
=> x + 264 = 20v ---(2)
Substituting equation 1 in equation 2, we get
8v +264 = 20v
=> v = 264/12 = 22 m/s
= 22×36/10 km/hr = 79.2 km/hr
Answer is B.
Answer: B
Question: Find the remainder when 10,000 is divided by 84
Options:
A)4
B)1
C)6
D)7
E)8
Rationale: Answer:A
Answer: A
Question: The difference of 2 digit number & the number obtained by interchanging the digits is 36. What is the difference the sum and the number if the ratio between the digits of the number is 1:2 ?
Options:
A)7
B)8
C)9
D)10
E)11
Rationale: Let the number be xy.
Given xy – yx = 36.
This means the number is greater is than the number got on reversing the digits.
This shows that the ten’s digit x > unit digit y.
Also given ratio between digits is 1 : 2 => x = 2y
(10x + y) – (10y +x) = 36 => x – y = 4 => 2y – y =4.
Hence, (x + y) – (x – y) = 3y – y = 2y = 8
B
Answer: B
Question: xy=1 then what is (4^(x+y)^2) / (4^(x-y)^2)
Options:
A)256
B)4
C)8
D)16
E)32
Rationale: (x+y)^2 - (x-y)^2
(x+y+x-y)(x+y-x+y)
(2x)(2y)
4xy
4
4^4 = 256
Answer A
Answer: A
Question: A certain galaxy is known to comprise approximately 4 x 10^12 stars. Of every 50 million of these stars, one is larger in mass than our sun. Approximately how many stars in this galaxy are larger than the sun?
Options:
A)800
B)1,250
C)8,000
D)12,000
E)80,000
Rationale: 4*10^12
50 mln = 5*10^7
we divide 10^12 by 10^7 and we get (10^5)*4 = 400,000 and divide by 5. the result is 80,000
E
Answer: E
Question: If a book is sold at 5% profit instead of 5% loss, it would have brought Rs 13 more. Find out the cost price of the book
Options:
A)75
B)72
C)130
D)70
E)80
Rationale: Let C.P. of the book be Rs. ’X’
Given, 1.05 X - 0.95X = 13
=> 0.1 X = 13 = 13/0.1 = Rs 130
ANSWER:C
Answer: C
Question: If the number of students in each of three groups are in the ratio 8:9:10, and also the number of students in each group is a multiple of 5. then the following statements are true.
I. The product of number of students of each group is divisible by both 2 and 3.
II. The product of number of students of each group is divisible by 125
III. The product of number of students of each group is divisible by 125, 2 and 3
Options:
A)I
B)II
C)III
D)All of the above
E)None of the above
Rationale: The product of consecutive positive integers are divisible by both 2 and 3.
Since the number of students in each group is divisible by 5, the product will be divisible by 125
Hence statement III is correct.
Answer:D
Answer: D
Question: Kavi spends 50% of his monthly salary on food and saves 80% of the remaining amount. If his monthly salary is Rs.19,000, how much money does he save every month ?
Options:
A)Rs.2000
B)Rs.600
C)Rs.8000
D)Rs. 3800
E)Rs.1200
Rationale: Explanation:
Kavi's monthly income = Rs.19,000
He spends 50% on food.
The total money spent on food = 50/100 * 19000 = Rs. 9500
Now, his monthly remaining income = Rs.19000 – Rs.9500 = Rs. 9500
Out of Rs. 9500, he saves 40%.
Amount saved = 40/100 * 9500 = Rs. 3800
ANSWER:D
Answer: D
Question: I. a3 - 405 = 324,
II. b2 - 72 = 9 to solve both the equations to find the values of a and b?
Options:
A)a > b
B)a ≥ b
C)a < b
D)a ≤ b
E)a = b or the relationship between a and b cannot be established.
Rationale: a3 = 729 => a = 9
b2 = 81 => b = ± 9
a ≥ b
ANSWER:B
Answer: B
Question: The area of sector of a circle whose radius is 12 metro and whose angle at the center is 30° is?
Options:
A)35m2
B)36m2
C)37m2
D)38m2
E)40m2
Rationale: 30/360 * 22/7 * 12 * 12
= 37 m2
Answer:C
Answer: C
Question: Mohan purchased 15 kgs of rice at the rate of Rs.26 per kg and 10 kgs of pulses at the rate of Rs.26 per kg. Whaat is the total amount that he paid to the shopkeeper?
Options:
A)A)Rs.598
B)B)Rs.594
C)C)Rs.596
D)D)Rs.550
E)None of these
Rationale: Explanation:
Price of 15 kgs of rice at Rs.26/kg = 15x26 = Rs.390
Price of 10 kgs of pulses at Rs.26/kg = 10x26 = Rs.260
Therefore, Total amount = Rs.390+Rs.260 = Rs.550
Answer: Option D
Answer: D
Question: Mary charges $8.50 per hour to clean a house. If she works 22 hours, how much
does she earn in one week?
Options:
A)$687.00
B)$112.50
C)$187.00
D)$487.50
E)$387.50
Rationale: Multiply 22 hours x $8.50 =
Answer: $187.00
correct answer C
Answer: C
Question: In a class of students, 1/2 of the number of girls is equal to 1/5 of the total number of students. What is the ratio of boys to girls in the class?
Options:
A)1/2
B)3/2
C)1/3
D)2/3
E)4/3
Rationale: (1/2)G=(1/5)(B+G)
5G=2B+2G
3G=2B
B/G=3/2.
The answer is B.
Answer: B
Question: There were totally 100 men.84 are married.75 have T.V, 85 have radio,70 have A.C. How many men have T.V, radio, A.C and also married?
Options:
A)11
B)12
C)13
D)14
E)15
Rationale: 100-(100-84)-(100-75)-(100-85)-(100-70)
= 100-16-25-15-30
=100-86
=14
ANSWER:D
Answer: D
Question: What will be in unit's place digit of 3 to the power 34.
Options:
A)1
B)6
C)3
D)0
E)9
Rationale: as the unit place digit of 3 to the power of 1 is 3, to the power of 2 is 9.to the power of 3 is 7 ,to the power of 4 is 1 and it'll be repeated again in the same order.... so the unit place digit of 3 to the power of 34 is 9..
ANSWER:E
Answer: E
Question: Jalal weighs twice as much as Meena. Meena's weight is 60% of Bahar's weight. Dolly weighs 50% of Laila's weight. Laila weighs 19% of Jalal's weight. Who among these 5 persons weighs the least?
Options:
A)Bahar
B)Dolly
C)Jalal
D)Laila
E)Meena
Rationale: Let Jalal weigh 100 kg.
Then Meena = 50 kg, Bahar = 83.33 kg, Laila = 19 kg, Dolly = 9.5 kg
Therefore clearly Dolly is the lightest.
ANSWER:B
Answer: B
Question: Solve x2 – 7x = 0
Options:
A)0,7
B)1,7
C)2,7
D)3,7
E)4,7
Rationale: This quadratic factors easily: Copyright © Elizabeth Stapel 2002-2011 All Rights Reserved
x2 – 7x = 0
x(x – 7) = 0
x = 0 or x – 7 = 0
x = 0 or x = 7
The solution is x = 0, 7
ANSWER A 0,7
Answer: A
Question: How many 3-letter words with or without meaning, can be formed out of the letters of the word, 'LOGAR', if repetition of letters is not allowed?
Options:
A)690
B)60
C)740
D)760
E)780
Rationale: The word 'LOGAR' has 5 different letters.
Hence, the number of 3-letter words(with or without meaning) formed by using these letters
= 5P3
=
5
×
4
×
3
=
60
Option B
Answer: B
Question: A train running at the speed of 56 km/hr crosses a pole in 9 sec. What is the length of the train?
Options:
A)140 m
B)786 m
C)566 m
D)546 m
E)445 m
Rationale: Speed = 56 * 5/18 = 140/9 m/sec
Length of the train = speed * time = 140/9 * 9
= 140 m
Answer: A
Answer: A
Question: If w and t are positive integers, wt + w + t cannot be
Options:
A)5
B)6
C)7
D)8
E)9
Rationale: Let wt + t + w = x
Add 1 on both sides:
wt + t + w + 1 = x + 1
t(w + 1) + w + 1 = x + 1
(w + 1)(t + 1) = x + 1
Minimum value of (w + 1) = 2
Minimum value of (t + 1) = 2
Hence x + 1 cannot be prime
Substitute x from the given options: 6 + 1 = 7 --> prime --> wt + t + s cannot be 6
Answer: B
Answer: B
Question: A mobile battery in 1 hour charges to 20 percent.How much time (in minute) will it require more to charge to 30 percent.
Options:
A)145
B)90
C)175
D)160
E)130
Rationale: 1 hr =20 percent.Thus 15 min=5 percent .Now to charge 30 percent 90 min.Answer:B
Answer: B
Question: If the average (arithmetic mean) of 18 consecutive odd integers is 414, then the least of these integers is
Options:
A)a) 497
B)b) 518
C)c) 519
D)d) 521
E)e) 525
Rationale: A very helpful rule to know in arithmetic is the rule that in evenly spaced sets, average = median. Because the average will equal the median in these sets, then we quickly know that the median of this set of consecutive odd integer numbers is 414.
There are 18 numbers in the set, and in a set with an even number of terms the median is just the average of the two most median terms (here the 9th and 10th numbers in the set). This means that numbers 9 and 10 in this set are 413 and 415. Because we know that number 9 is 413, we know that the smallest number is 8 odd numbers below this, which means that it is 8*2 = 16 below this (every odd number is every other number). Therefore 413-16 = 397, answer choice A
Answer: A
Question: A car started running at a speed of 38 km/hr and the speed of the car was increased by 2 km/hr at the end of every hour. Find the total distance covered by the car in the first 10 hours of the journey.
Options:
A)47 km
B)76 km
C)25 km
D)15 km
E)30 km
Rationale: A
47 km
The total distance covered by the car in the first 10 hours = 38 + 40 + 42 + 44 + 46 + 48 + 50 + 52 + 54 + 56= sum of 10 terms in AP whose first term is 30 and last term is 56 = 10/2 [38 + 56] = 470 km.
Answer: A
Question: H.C.F. of 513, 1134 and 1215 is
Options:
A)27
B)21
C)76
D)42
E)33
Rationale: H.C.F. of 513, 1134 and 1215 = 3 × 3 × 3 = 27
Answer: Option A
Answer: A
Question: On Saturday morning, Malachi will begin a camping vacation and he will return home at the end of the first day on which it rains. If on the first three days of the vacation the probability of rain on each day is 0.3, what is the probability that Malachi will return home at the end of the day on the following Monday?
Options:
A)0.008
B)0.147
C)0.488
D)0.512
E)0.64
Rationale: Re-phrasing the question:
What is the probability of: Saturday: No rain, Sunday: No rain, Monday: Rain
Probablity of rain = 0.3
Therefore, probability of no rain = 0.7
0.7*0.7*0.3 = 0.147
Hence B
Answer: B
Question: If 10 men can make 200 tables working for 15 days at the rate of 8 hr per day, how many tables can 5 men make working for 10 days at the rate of 6 hr a day?A
Options:
A)150
B)50
C)250
D)100
E)120
Rationale: formula
men* days * workinghour / work
so m1*d1*t1/ w1 = m2*d2*t2 / w2
= 50
ANSWER:B
Answer: B
Question: A and B together can do a work in6 days. If A alone can do it in 42 days. In how many days can B alone do it?
Options:
A)11
B)7
C)8
D)20
E)25
Rationale: B
7
1/6 â€“ 1/42 = 1/7 => 7
Answer: B
Question: A cistern can be filled by a tap in 7 hours while it can be emptied by another tap in 9 hours. If both the taps are opened simultaneously, then after how much time will the cistern get filled ?
Options:
A)4.5 hrs
B)5 hrs
C)6.5 hrs
D)17.2 hrs
E)31.5 hrs
Rationale: Net part filled in 1 hour= 1/7 -1/9= 2/63
Therefore the cistern will be filled in 63/2 hours or 31.5 hours.
ANSWER:E
Answer: E
Question: A technician makes a round-trip to and from a certain service center by the same route. If the technician completes the drive to the center and then completes 80 percent of the drive from the center, what percent of the round-trip has the technician completed?
Options:
A)5%
B)75%
C)25%
D)40%
E)50%
Rationale: The complete round trip consists of driving to the service center and then back home again.
So, once the technician drives to the service center he/she has already competed 50% of the entire trip.
Since the technician completes a portion of the trip back home,the correct answer must be greater than 50%
Only one answer choice works.
Answer:
B
Answer: B
Question: A shop sells chocolates at re.1 each. U can exchange 3 wrappers for 1 chocolate. If u have Rs.100, how many chocolates can you totally get?
Options:
A)147
B)148
C)149
D)145
E)141
Rationale: for 100 rupees we will get 100 chocolates
then for 3 wrappers we will get 1 chocolate so 100/3==33 chocolates and we left with one more wraper the 33+1=34 ...34/3=11...one more wrapper so 12/3=4 ..4/3=1 and one more wrapper so finally...100+33+11+4+1=149
ANSWER:C
Answer: C
Question: A trader bought a car at 20% discount on its original price. He sold it at a 50% increase on the price he bought it. What percent of profit did he make on the original price?
Options:
A)A)10%
B)B)12%
C)C)14%
D)D)20%
E)E)22%
Rationale: Original price = 100
CP = 80
S = 80*(150/100) = 120
100 - 120 = 20%
D)
Answer: D
Question: In a colony of 70 residents, the ratio of the number of men and women is 4:3. Among the women, the ratio of the educated to the uneducated is 1:4. If the ratio of the number of education to uneducated persons is 8:27, then find the ratio of the number of educated and uneducated men in the colony?
Options:
A)1:9
B)1:6
C)1:3
D)1:1
E)1:3
Rationale: Number of men in the colony = 4/7 (70) = 40
Number of women in the colony = 3/7 (70) = 30
Number of educated women in the colony = 1/5 (30) = 6
Number of uneducated women in the colony = 4/5 (30) = 24
Number of educated persons in the colony = 8/35 (70) = 16
As 6 females are educated, remaining 10 educated persons must be men.
Number of uneducated men in the colony = 40 - 10 = 30
Number of educated men and uneducated men are in the ratio 10:30 => 1:3
Answer: E
Answer: E
Question: If rupee one produces rupees nine over a period of 25 years, find the rate of simple interest?
Options:
A)22 1/7 %
B)36 %
C)22 1/8 %
D)22 1/2 %
E)22 1/2 %
Rationale: 9 = (1*25*R)/100
R = 36 %
Answer:B
Answer: B
Question: Sripad has scored average of 64 marks in three objects. In no subjects has he secured less than 58 marks. He has secured more marks in Maths than other two subjects. What could be his maximum score in Maths ?
Options:
A)79
B)28
C)76
D)27
E)21
Rationale: Assuming Sripad has scored the least marks in subject other than science,
Then the marks he could secure in other two are 58 each.
Since the average mark of all the 3 subject is 64.
i.e (58+58+x)/3 = 64
116 + x = 192
x = 76 marks.
Therefore, the maximum marks he can score in maths is 76.
Answer: C
Answer: C
Question: Roses can be purchased individually for $7.30, one dozen for $36, or two dozen for $50. What is the greatest number of roses that can be purchased for $680?
Options:
A) 156
B) 162
C) 316
D) 324
E) 325
Rationale: Buy as many $50 deals as possible. We can by 650/50=13 two dozen roses, thus total of 13*24 = 312 roses.
We are left with 680 - 650 = $30. We can buy 30/7.3 = ~4 roses for that amount.
Total = 312 + 4 = 316.
Answer: C.
Answer: C