divelab/Sys2Bench huggingface dataset:
Question: In the simple subtraction problem below some single digits are replaced by letters .Fined the value of 7A+5D+6CD?
Options:
A)288
B)3799
C)277
D)278
E)240
Rationale: 15 - 7 = 8 So D = 8
10 + (C -1) - 8 = 4 So C = 3
10 + (5-1) - B = 7 So B = 7
(A-1) - 1 = 6 So A = 8
7A + 5D + 6CD = 56 + 40 + 144 = 240
Answer:E
Answer: E
Question: There are 3 teams each with 6 basket players. How many combinations are there if we were to pick 2 players from the 3 teams such that no team was picked twice?
Options:
A)50
B)23
C)108
D)28
E)45
Rationale: There are altogether three arrangements, which are we can select two members each from team A and B, each from team A and C, and each from team B and C. For each arrangement, there are altogether 36 possibilities (6*6) since each team has 6 players. So there are a total of 108 possibilities (36*3). I hope this method is easier for you to understand.
Answer: C
Question: For any 8 given numbers, which of the following is always equivalent to adding the 3 numbers together and then dividing the sum by 3?
I. Ordering the 3 numbers numerically, from highest to lowest, and then selecting the middle number.
II. Dividing each of the numbers by 3 and then adding the results together.
III. Multiplying each number by 6, adding the resulting products together, and then dividing the sum by 9.
Options:
A)I only
B)II only
C)I and II only
D)II and III only
E)None of the above
Rationale: Let the 3 numbers be x, y and z.
Question: Which of the following is equivalent to (x + y + z)/3
I. Ordering the 3 numbers numerically, from highest to lowest, and then selecting the middle number. --> Not always equivalent Eg: 111 and 141
II. Dividing each of the numbers by 3 and then adding the results together. --> x/3 + y/3 + z/3 = (x + y + z)/3 --> Equivalent
III. Multiplying each number by 6, adding the resulting products together, and then dividing the sum by 9. --> (6x + 6y + 6z)/9 = 2(x + y + z)/3 --> Not equivalent
Answer: E
Answer: E
Question: A father is now three times as old as his son. Seven years back, he was four times as old as his son. The age of the son (in years) is
Options:
A)A)12
B)B)15
C)C)18
D)D)20
E)E)21
Rationale: Explanation:
Let son's age be x years. Then, father's age = (3x) years.
Seven years ago, father's age = (3x - 7) years and son's age = (x - 7) years.
So, 3x - 7 = 4 (x - 7)=> 3x - 7 = 4x - 28=> x = 21.
Answer: E
Answer: E
Question: In a group of 86 students, each student is registered for at least one of three classes – History, Math and English. Twenty-eight students are registered for History, twenty-three students are registered for Math, and forty-four students are registered for English. If only three students are registered for all three classes, how many students are registered for exactly two classes?
Options:
A)3
B)10
C)9
D)8
E)7
Rationale: A U B U C = A + B + C - AB-BC-AC + ABC
86 = 28 + 23+ 44 -AB-BC-AC +3 => AB+BC+AC = 12
Exactly Two classes = AB+BC+AC - 3ABC = 12 -3*3 = 3
Hence A
Answer: A
Question: If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is
Options:
A)50 km
B)56 km
C)70 km
D)80 km
E)90 km
Rationale: Let the actual distance travelled be x km.
Then x/10=(x+20)/14
--> 14x = 10x + 200
--> 4x = 200
--> x = 50 km.
Answer : A.
Answer: A
Question: A test paper has 10 questions each worth 4 marks. While taking the test, a student realises that he has attempted questions worth 16 marks. Assuming that whatever question he attempts is completely correct, how many more questions should he attempt so that he is able to secure 90 percent marks?
Options:
A)4
B)5
C)6
D)7
E)8
Rationale: Since the test paper has 10 questions each worth 4 marks, the maximum marks he can get is 40.
His aim is to secure 90 % marks, this means he wants to secure 90% of 40 = 36 marks.
Out of the 36 marks, he has already attempted questions worth 16 marks, so he should attempt questions worth 36 - 16 = 20 more marks.
As every question is worth 4 marks, so to secure 20 more marks he should attempt (20/4) = 5 more questions.
Ans B
Answer: B
Question: The average age of three boys is 48 years and their ages are in proportion 2:5:5. What is the age in years of the youngest boy?
Options:
A)30
B)23
C)24
D)26
E)40
Rationale: 2x + 5x + 5x = 144
x =12
2x = 24
Answer: C
Answer: C
Question: The cash realised on selling a 14% stock is Rs.106.25, brokerage being 1/4% is
Options:
A)123
B)106
C)100
D)156
E)240
Rationale: Explanation:
Cash realised= Rs. (106.25 - 0.25)
= Rs. 106.
Answer: B
Answer: B
Question: A jogger running at 9 kmph along side a railway track is 270 metres ahead of the engine of a 120 metre long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?
Options:
A)3.6 sec
B)18 sec
C)36 sec
D)39 sec
E)None of these
Rationale: Speed of train relative to jogger
= (45 – 9) km/h = 36 km/h
= (36 × 5⁄18) m/sec = 10 m/sec
Distance to be covered = (270 + 120) m = 390 m.
∴ Time taken = (390⁄10) sec = 39 sec.
Answer D
Answer: D
Question: Find the average of all prime numbers between 80 and 100
Options:
A)88
B)60
C)80
D)89.6
E)92
Rationale: Prime numbers between 80 and 100 are 83, 89, 97
Required average = (83+ 89+ 97)/3 = 269/3 = 89.6
Answer is D
Answer: D
Question: In a birthday party, every person shakes hand with every other person. If there was a total of 28 handshakes in the party, how many persons were present in the party?
Options:
A)6
B)7
C)8
D)9
E)10
Rationale: Suppose there are nn persons present in a party and every person shakes hand with every other person. Then, total number of handshakes
= nC2=n(n−1)/2
n(n−1)=28×2n(n−1)=56
n=8
ANSWER C 8
Answer: C
Question: A train passes a man standing on the platform. If the train is 180 meters long and its speed is 72 kmph, how much time it took in doing so?
Options:
A)6 ½ sec
B)4 ½ sec
C)9 sec
D)8 sec
E)2 ½ sec
Rationale: D = 180
S = 72 * 5/18 = 20 mps
T = 180/20 = 9 sec
Answer: C
Answer: C
Question: The average age of a class of 39 students is 15 years. If the age of the teacher be included, then the average increases by3 months. Find the age of the teacher.
Options:
A)22 years
B)23 years
C)24 years
D)25 years
E)26 years
Rationale: avg of 39 student = 15 yrs
Total age of 39 students=39*15= 585 yrs
Avg age of 39 students + teacher =15+3/12=15.25 yrs
so the total age of (39 student+1 teacher) or 40 persons=
40*15.25=610 yrs
so age of teacher=610-585=25 years
ANSWER:D
Answer: D
Question: A boat running downstream covers a distance of 44 km in 8 hours while for covering the same distance upstream, it takes 10 hours. What is the speed of the boat in still water?
Options:
A)5 kmph
B)4.95 kmph
C)6 kmph
D)7 kmph
E)8 kmph
Rationale: Explanation:
Speed downstream = 44/8 = 5.5 kmph
Speed upstream = 44/10 = 4.4 kmph
Speed of the boat in still water = (5.5+4.4)/2 = 4.95 kmph
Answer: Option B
Answer: B
Question: Population of a city in 20004 was 1000000. If in 2005 there isan increment of 15% , in 2006 there is a decrements of 35 % and in 2007 there is an increment of 45%, then find the population of city atthe end of the year 2007
Options:
A)967532
B)977522
C)984424
D)997454
E)1083875
Rationale: Required population = P (1 + R1/100)(1 - R2/100)(1 + R3/100)
= P (1 + 15/100)(1 - 35/100)(1 + 45/100)
= 1083875
E
Answer: E
Question: Two numbers are in the ratio 3 : 4. If the sum of numbers is 63, find the numbers.
Options:
A)27 and 36.
B)25 and 30.
C)23 and 44.
D)63 and 12.
E)12 and 36.
Rationale: Sum of the terms of the ratio = 3 + 4 = 7
Sum of numbers = 63
Therefore, first number = 3/7 × 63 = 27
Second number = 4/7 × 63 = 36
Therefore, the two numbers are 27 and 36.
Answer is A
Answer: A
Question: The residents of the town Q participated in a survey to determine the number of hours per week each resident spent watching television. The distribution of the results of the survey had a mean of 21 hours and a standard deviation of 6 hours. The number of hours that Pat, a resident of town Q, watched television last week was between 1 and 2 standard deviations below the mean. Which of the following could be the number of hours that Pat watched television last week?
Options:
A)- 30
B)- 20
C)- 18
D)- 12
E)- 6
Rationale: (21-6*2)<number of hours that Pat watched television last week <(21-6*1)
=9<L<15
Only option E (12) satisfies this condition.
Answer: E
Question: The average amount with a group of seven numbers is Rs. 20. If the newly joined member has Rs. 50 with him, what was the average amount with the group before his joining the group?
Options:
A)17
B)26
C)15
D)97
E)12
Rationale: Total members in the group = 7
Average amount = Rs. 20
Total amount with them = 7 * 20
= Rs. 140
One number has Rs. 50. So, the amount with remaining 6 people
= 140 - 50 = Rs. 90
The average amount with them = 90/6
= Rs.15.
Answer:C
Answer: C
Question: A work as fast as B. If B can complete a work in 20days independently,the number of days in which A and B can together finish the work in?
Options:
A)2days
B)3days
C)4days
D)5days
E)6 2/3days
Rationale: Ratio of rates of working of A and B = 2:1
ratio of times taken = 1:2
A's 1day work = 1/10
B's 1day work = 1/20
A+B 1day work = 1/10 + 1/20 = 3/20 => 20/3 = 6 2/3
A and B can finish the work in 6 2/3days
Answer is E
Answer: E
Question: There are 10 orators A, B, C, D, E, F, G, H, I and J. In how many ways can the arrangements be made so that A always comes before B and B always comes before C.
Options:
A)10! / 3!
B)8! / 6!
C)5! x 3!
D)8! / (5! x 3!)
E)8! / (5! x 4!)
Rationale: Select any three places for A, B and C. They need no arrangement amongst themselves as A would always come before B and B would always come before C.
The remaining 7 people have to be arranged in 7 places.
Thus, 10C3 x 7! =10! / 3!
ANSWER:A
Answer: A
Question: A completes 80% of a work in 20 days. Then B also joins and A and B together finish the remaining work in 3 days. How long does it need for B if he alone completes the work?
Options:
A)37 1/2 days
B)22 days
C)31 days
D)22 days
E)25 1/2 days
Rationale: Work done by A in 20 days = 80/100 = 8/10 = 4/5
Work done by A in 1 day = (4/5) / 20 = 4/100 = 1/25 --- (1)
Work done by A and B in 3 days = 20/100 = 1/5 (Because remaining 20% is done in 3 days by A and B)
Work done by A and B in 1 day = 1/15 ---(2)
Work done by B in 1 day = 1/15 – 1/25 = 2/75
=> B can complete the work in 75/2 days = 37 ½ days
Option A
Answer: A
Question: The present average age of a family of five members is 26 years. If the present age of the youngest member in the family is ten years, then what was the average age of the family at the time of the birth of the youngest member ? (Assume no death occurred in the family since the birth of the youngest)
Options:
A)22 years
B)25 years
C)20 years
D)28 years
E)12 years
Rationale: Present total age of the members = 26(5) = 130 years.
Present age of the youngest member = 10 years
Present total age of the remaining four members = 130 -10 = 120 years
Their average age at the time of the birth of the youngest member = [120 - (4 * 10)] / 4 = 30 - 10 = 20 years.
Answer: C
Answer: C
Question: 8597 - ? = 7429 - 4358
Options:
A)3567
B)6424
C)6835
D)5526
E)None of these
Rationale: D
7429-4358=3071
Let 8597 - x = 3071
Then, x = 8597 - 3071 = 5526
Answer: D
Question: In an increasing sequence of 8 consecutive integers, the sum of the last 4 integers is 822. What is the sum of the first 4 integers in the sequence?
Options:
A)800
B)808
C)806
D)802
E)804
Rationale: Solution:
In solving this problem we must first remember that when we have 8 consecutive integers we can display them in terms of just 1 variable. Thus, we have the following:
Integer 1: x
Integer 2: x + 1
Integer 3: x + 2
Integer 4: x + 3
Integer 5: x + 4
Integer 6: x + 5
Integer 7: x + 6
Integer 8: x + 7
We are given that the sum of the first 4 integers is 570. This means that:
x+7+ x+6 + x+5 + x+4 = 822
4x + 22 = 822
4x = 800
x = 200
The sum of the last 4 integers can be expressed and simplified as:
x+ x+1 + x+2+ x+3 = 4x + 6
Substituting 141 for x yields:
(4)(200) + 6 = 806
Answer: C
Answer: C
Question: A lemonade stand sold only small and large cups of lemonade on Tuesday. 3/5 of the cups sold were small and the rest were large. If the large cups were sold for 11/5 as much as the small cups, what fraction of Tuesday's total revenue was from the sale of large cups?
Options:
A)(a) 7/16
B)(b) 7/15
C)(c) 10/21
D)(d) 22/37
E)(e) 1/2
Rationale: A simpler way i guess would be to think that in total 5 cups were sold. Out of which 3 are small and 2 are large. Now let the small ones cost $5. so the large ones would cost $11.
So,
3*5=15 and 2*11=22.
Total revenue was 15+22=37
and Large cup sales as found above is 22
Therefore answer is 22/37
D
Answer: D
Question: Find the area of the quadrilateral of one of its diagonals is 40 cm and its off sets 11 cm and 9 cm?
Options:
A)100 cm2
B)150 cm2
C)333 cm2
D)400 cm2
E)750 cm2
Rationale: 1/2 * 40(11 + 9)
= 400 cm2
Answer: D
Answer: D
Question: The mean of 50 observations was 36. It was found later that an observation 48 was wrongly taken as 23. The corrected new mean is
Options:
A)35.2
B)36.1
C)36.5
D)39.1
E)None
Rationale: Sol.
Therefore correct sum
= ( 36 × 50 + 48 – 23)
= 1825.
Therefore correct mean
= 1825 / 50
= 36.5.
Answer C
Answer: C
Question: The length of a rectangular plot is thrice its breadth. If the area of the rectangular plot is 867 sq m, then what is the breadth of the rectangular plot?
Options:
A)76 m
B)17 m
C)88 m
D)55 m
E)44 m
Rationale: Let the breadth of the plot be b m.
Length of the plot = 3 b m
(3b)(b) = 867
3b2 = 867
b2 = 289 = 172 (b > 0)
b = 17 m.
Answer:B
Answer: B
Question: In seven given numbers,the average of first four numbers is 4 and that of last four numbers is also 4. if the average of these seven numbers is 3, the fourth number is?
Options:
A)3
B)4
C)7
D)11
E)12
Rationale: let 7 numbers are a,b,c,d,e,f,g.
given avg of first 4 nums are 4...i.e (a+b+c+d)/4=4
a+b+c+d=16
given avg of last 4 nums are also 4..i.e.(d+e+f+g)/4=4
d+e+f+g=16
e+f+g=16-d
given avg of 7 nums are 3....i.e (a+b+c+d+e+f+g)/7=3
a+b+c+d+e+f+g=21
16+16-d=21
d=32-21
d=11
ANSWER:D
Answer: D
Question: Which of the following fractions R has a decimal equivalent that is a terminating decimal?
Options:
A)10/189
B)15/196
C)16/225
D)25/144
E)39/128
Rationale: The fraction R will terminate if and only if the denominator has prime divisors only 2 and 5 or both.
A. 10/189 = 10/(3*3*3*7) Non-term.
B. 15/196 = 15/(2*2*7*7) Non-term.
C. 16/225 = 16/(5*5*3*3) Non-term.
D. 25/144 = 25/(2*2*2*7) Non-term.
E. 39/128 = 39/(2^7) Terminatingbecause only 2 in denominator.
Answer: E
Question: A code is to be made by arranging 7 letters. Three of the letters used will be the letter A, two of the letters used will be the letter B, one of the letters used will be the letter C, and one of the letters used will be the letter D. If there is only one way to present each letter, how many different codes are possible?
Options:
A)42
B)210
C)420
D)840
E)5,040
Rationale: we have 7 letters out of which 3 are of one kind, 2 are of another kind..
so total ways = 7!/3!2!=420
ans C
Answer: C
Question: How many times are the hands of a clock at right angle in a day?
Options:
A)44
B)21
C)22
D)41
E)40
Rationale: A
44
In 12 hours, they are at right angles 22 times.
In 24 hours, they are at right angles 44 times.
Answer: A
Question: An amount of Rs.1638 was divided among A, B and C, in the ratio 1/2 : 1/3 : 1/4. Find the share of A?
Options:
A)656
B)456
C)756
D)745
E)720
Rationale: Let the shares of A, B and C be a, b and c respectively.
a : b : c = 1/2 : 1/3 : 1/4
Let us express each term with a common denominator which is the last number divisible by the denominators of each term i.e., 12.
a : b : c = 6/12 : 4/12 : 3/12 = 6 : 4 : 3.
Share of A = 6/13 * 1638 = Rs. 756
Answer: C
Answer: C
Question: Find the total number of distinct vehicle numbers that can be formed using two letters followed by two numbers. Letters need to be distinct.
Options:
A)60000
B)65000
C)70000
D)75000
E)None
Rationale: Solution:
Out of 26 alphabets two distinct letters can be chosen in 26P2 ways.
Coming to numbers part, there are 10 ways (any number from 0 to 9 can be chosen) to choose the first digit and similarly another 10 ways to choose the second digit.
Hence, there are totally 10 *10 = 100 ways.
Combined with letters there are,
26P2 *100 = 65000 ways to choose vehicle numbers.
Answer: Option B
Answer: B
Question: If a letter is picked randomly from the alphabet, what are the odds of it being in the first 10 letters or being a vowel (a, e, i, o, u, y)?
Options:
A)6/13
B)1/2
C)15/26
D)11/26
E)8/13
Rationale: P(10á´œV) = P(10) + P(V) - P(10âˆ©V), where 10 denotes the first ten letters, and V denotes a vowel.
P(10á´œV) = 10/26 + 6/26 - 3/26
= 1/2
Answer: B
Answer: B
Question: Seed mixture X is 40% ryegrass and 60% bluegrass by weight; seed mixture Y is 25% ryegrass and 75% fescue. If a mixture of X and Y contains 31% ryegrass, what percent of the weight of the mixture is from mixture X?
Options:
A)20%
B)30%
C)40%
D)50%
E)60%
Rationale: 31% is 6%-points above 25% and 9%-points below 40%.
Thus the ratio of mixture Y to mixture X is 3:2.
The percent of mixture X is 2/5 = 40%.
The answer is C.
Answer: C
Question: A train covers a distance of 100km in 1 hour. If its speed is decreased by 30km/hr, the time taken by the car to cover the same distance will be?
Options:
A)1hr
B)1hr 25min
C)50min
D)1hr 30min
E)1hr 45min
Rationale: Speed = 100/1 = 100km/hr
New speed = 100-30 = 70 km/hr
Time taken = 100/70 = 1hr 25min
Answer is B
Answer: B
Question: In a flower shop there were 5 flowers in each bouquet. If the seller has doubled the number of flowers in each bouquet then the new average of flowers in each bouque is
Options:
A)12
B)3
C)8
D)10
E)None of these
Rationale: Answer
Now required average
= old average x Multiplicand
= 5 x 2 = 10
Correct Option: D
Answer: D
Question: (A% of B + B% of A) is equal to ?
Options:
A)A% of B
B)B% of A
C)2% of AB
D)AB% of 3
E)None
Rationale: Answer
A% of B + B% of A =AB/100 + AB/100
= 2AB/100 = 2% of AB
Correct Option: C
Answer: C
Question: A train running at 50 km/hr takes 9 seconds to pass a platform. Next, it takes 6 seconds to pass a man walking at 5 km/hr in the same direction. Find the length of the train and that of the platform.
Options:
A)a) 75m50m
B)b) 100m50m
C)c) 50m45m
D)d) 100/3 m200/3
E)e) none of these
Rationale: A train running at 50 km/hr takes 9 seconds to pass a platform. Next, it takes 6 seconds to pass a man walking at 5 km/hr in the same direction. Find the length of the train and that of the platform.
Distance = Speed*time
It's probably best to convert to meters so we can find the length of the platform.
Distance = 50000 meters/h * 9 seconds*(1/60*60)
Distance =(50000*18 / [3600] ) = 125m
I'm not sure how we take the length of the train into account (if we do at all) to solve this problem. For example, If we were measuring by the time the very front of the train passed one end of the platform to the time the very front of the train passed the other end, the result would be different than if we counted when the very front of the train passed one end of the platform to the time the back side of the train passed the end.
As for the problem involving the man, the man is moving forward at a speed of 5km/h while the train is moving forward at a speed of 50km/h. Therefore, the train is moving past the man at a total speed of 45km/h.
distance = speed * time
distance = 45km/h * 12 seconds
distance (length of train) = 75 m
We know the length of the train is roughly 75m and the distance covered passing the platform was 125m. However, The platform isn't 125m long - it is 125m minus the length of the train long (or so I think) which is 125-75 or roughly 50m. Both of these answers are in A so I think that is the right answer. I am still having a bit of trouble conceptualizing why we have to subtract out the length of the train, however.
ANSWER: A) a) 75m50m
Answer: A
Question: Ravi's salary was reduced by 25%. Percentage increase to be effected to bring salary to original level =
Options:
A)33.38 %
B)33.33 %
C)83.33 %
D)33.35 %
E)34.33 %
Rationale: Explanation:
Let the Salary be 100.
Salary was reduced by 25%. So present salary = 75.
Percentage has to be increased in order to get Original level = 2575×1002575×100 = 33.33 %
Answer: B
Answer: B
Question: If p and q are positive integers, and 3 is not a factor of q, then q may be which of the following?
Options:
A)(p−1)·p·(p+1)
B)(p−3)·(p−1)·(p+1)
C)(p−2)·p·(p+2)
D)(p−1)·p·(p+2)
E)(p−3)·(p+1)·(p+2)
Rationale: Plugged in values :
let p=5
A. (p−1)·p·(p+1) --> divisible by 3
B. (p−3)·(p−1)·(p+1) --> divisible by 3
C. (p−2)·p·(p+2) --> divisible by 3
D. (p−1)·p·(p+2) --> not divisible. Hence the answer.
Answer: D
Question: If 7 (A's capital) = 8 (B's capital) = 10 (C's capital). Then the ratio of their capitals is?
Options:
A)40:15:15
B)40:25:18
C)40:35:28
D)40:25:24
E)40:45:11
Rationale: 7A = 8B = 10 C
A:B:C = 1/7:1/8:1/10
= 40:35:28
Answer: C
Answer: C
Question: What least number must be added to 686, so that the sum is completely divisible by 5 ?
Options:
A)2
B)3
C)5
D)4
E)6
Rationale: If we divide 686 by 5 remainder is 1
5 - 1 =4
Answer : D
Answer: D
Question: Dividing by 3⁄6 and then multiplying by 5⁄6 is the same as dividing by what number?
Options:
A)31⁄5
B)16⁄5
C)20⁄9
D)9⁄20
E)5⁄3
Rationale: say X/3/6*5/6 = x*6/3*5/6 = x*5/3
E
Answer: E
Question: If a fair 6-sided die is rolled three times, what is the probability that exactly one 3 is rolled?
Options:
A)25/216
B)50/216
C)25/72
D)25/36
E)5/6
Rationale: Total ways in which a 6-sided die can be rolled three times = 6*6*6 = 216
To get exactly one 3, there are three ways:
A 3 on the first roll and non 3 on other two rolls. This can be done in 1*5*5 = 25 ways.
The 3 could be on the second or third roll too. So total favorable cases = 25*3 = 75
Required Probability = 75/216 = 25/72
Answer (C)
Answer: C
Question: The cost to park a car in a certain parking garage is $9.00 for up to 2 hours of parking and $1.75 for each hour in excess of 2 hours. What is the average (arithmetic mean) cost per hour to park a car in the parking garage for 9 hours?
Options:
A) $1.09
B) $1.67
C) $2.25
D) $2.36
E) $2.50
Rationale: Total cost of parking for 9 hours = 9$ for the first 2 hours and then 1.75 for (9-2) hours = 9+7*1.75 = 21.25
Thus the AVERAGE parking price = 21.25/9 = 2.36 $
D is the correct answer.
Answer: D
Question: A bag has 4 blue, 3 yellow and 2 green balls. The balls of the same color are identical. In how many ways can a child picks ball(s) out of the bag? He could even decide to pick ZERO balls.
Options:
A)60
B)1260
C)24
D)120
E)9
Rationale: With the blue ball there are 5 scenarios-->
0 blue ball being selected
1 blue ball being selected
2 blue ball being selected
3 blue ball being selected
4 blue ball being selected
And for each of these cases there is only one possibilty as they are identical.
So there are 5 ways to select the blue ball
Same is the case with 3 yellow (for which we have 4 possibilties) and 2 green balls(we have 3 possibilties)
so in total 5*4*3 = 60 possibilties..
ANS:A
Answer: A
Question: If it is true that x > -2 and x < 9, which of the following must be true?
Options:
A)x > 2
B)x < -9
C)x < 2
D)-9 < x < 2
E)none of the above.
Rationale: the range is -2 < x < 9
A. x > 2 - no because x can be between -2 < x < 2
B. x < -9 - no because the values of x are always >-9
C. x < 2 - no because x can be between 2 < x < 9
D. -9 < x < 2 - no because x can be between 2 < x < 9
E. none of the above.
Answer: E
Answer: E
Question: Roshan is 5 years younger than Raj and they have an age ratio 3:4 respectively. How old is Roshan?
Options:
A)10
B)15
C)18
D)24
E)25
Rationale: Let the age of Roshan be x.( x/x+5)=3/4
on cross multiplication and solving we get x=15
Answer: B
Answer: B
Question: If A, B and C together can finish a piece of work in 6 days. A alone in 12 days and B in 18 days, then C alone can do it in?
Options:
A)1
B)7
C)8
D)9
E)36
Rationale: C = 1/6 - 1/12 – 1/18 = 1/36 => 36 days'
Answer: E
Answer: E