divelab/Sys2Bench huggingface dataset:
Question: On Saturday morning, Malachi will begin a camping vacation and he will return home at the end of the first day on which it rains. If on the first three days of the vacation the probability of rain on each day is 0.6, what is the probability that Malachi will return home at the end of the day on the following Monday?
Options:
A)0.096
B)0.128
C)0.488
D)0.512
E)0.64
Rationale: Re-phrasing the question:
What is the probability of: Saturday: No rain, Sunday: No rain, Monday: Rain
Probablity of rain = 0.6
Therefore, probability of no rain = 0.4
0.4*0.4*0.6 = 0.096
Hence A
Answer: A
Question: A school having five classes only have student strength of 10, 10, 20, 20 and 40 respectively. The pass percentages of these classes are 20%, 30%, 60%, 90% and 100% respectively. What is the pass percentage for the entire school?
Options:
A)56%
B)75%
C)34%
D)66%
E)46%
Rationale: 20% of 10+30% of 10+60% of 20+90% of 20+100% of 40
=2+3+12+18+40 =
now 75 of 100
= 75%
ANSWER:B
Answer: B
Question: A sum of money becomes double itself in 8 years at simple interest. How many times will it become 10 years at the same rate?
Options:
A)2 1/4
B)3 1/4
C)4 1/2
D)5
E)7
Rationale: P ---- 2P ---- 8 years
2 1/4 P ---- 10 years
ANSWER A
Answer: A
Question: 63.2 is what percent of 867?
Options:
A)6.9
B)8.99
C)7.29
D)7.98
E)9.21
Rationale: We assume that 867 is 100%
assume 'x' is value we looking for
here,
867 = 100% and
x% = 63.2
therefore,
100/x = 867/63.2
100/x = 13.71
x = 7.29
C
Answer: C
Question: If x > y^4 > z^5, which of the following statements could be true? I. x>y>z II. x>z III.y=z
Options:
A)I,II only
B)III only
C)II only
D)I only
E)II,III only
Rationale: Answer : A
Answer: A
Question: What is the sum of 59 consecutive integers from -29 inclusive, in a increasing order?
Options:
A)-29
B)29
C)-30
D)0
E)60
Rationale: From -29 to -1 --> 29 nos.
zero --> 1 number
from +1 to +29 --> 29 nos.
When we add up nos. from -29 to +29 sum will be zero for total 59 nos.
Sum of these 59 nos. = 0.
D is the answer.
Answer: D
Question: In how many ways can a group of 5 men and women be made out of a total of 7 men and 3 women?
Options:
A)64
B)75
C)45
D)63
E)25
Rationale: Required number of ways=7c5 x 3c2
=7c2 x 3c1
=63
ANS: D
Answer: D
Question: At a certain committee meeting only associate professors and assistant professors are present. Each associate professor has brought 2 pencils and 1 chart to the meeting, while each assistant professor has brought 1 pencil and 2 charts. If a total of 10 pencils and 11 charts have been brought to the meeting, how many people are present?
Options:
A)6
B)7
C)8
D)9
E)10
Rationale: Say there are 'A' associate professors. So we have 2A pencils and A charts.
Say there are 'B' assistant professors. So we have B pencils and 2B charts.
Total pencils are 10 so 2A + B = 10
Total charts are 11 so A + 2B = 11
Add both: 3A + 3B = 21 so A + B = 7
Total number of people = 7
ANSWER:B
Answer: B
Question: What approximate value should come in place of the question mark(?) in the following equation?
6.39 × 15.266 + 115.8 of 2⁄5 = ?
Options:
A)145
B)165
C)180
D)130
E)135
Rationale: ? = 6.39 × 15.266 + 115.8 of 2⁄5
≈ 6.50 × 15 + 115 × 0.4 = 97.50 + 46 ≈ 145
Answer A
Answer: A
Question: A girl purchased “m” number of pens of type “A” at the unit price of “Rs. x” each, “n” number of pens of type “B” at the unit price of “Rs. y” each and “p” number of pens of type “C” at the unit price of “Rs. z” each. Which of the following represents the average price of all the pens taken together?
Options:
A)(mx + ny + pz) / (m + n + p)
B)(mA + nB + pC) / (m + n + p)
C)(mA + nB + pC) / (A + B + C)
D)(mx + ny + pz) / (A +B + C)
E)None of these
Rationale: Explanation:
(mx + ny + pz) / (m + n + p)
Required Average = Total Price / Total number = (mx + ny + pz) / (m + n + p)
ANSWER: A
Answer: A
Question: By selling an umbrella for Rs. 200, a shop keeper gains 50%. During a clearance sale, the shopkeeper allows a discount of 10% on the marked price. His gain percent during the sale is?
Options:
A)20
B)25
C)15
D)10
E)5
Rationale: Marked price = Rs. 200
C.P. = 100/150 * 200 = Rs. 200
Sale price = 90% of Rs. 200 = Rs. 180
Required gain % = 50/200 * 100 = 25%.
Answer:B
Answer: B
Question: List K consists of 12 consecutive integers. If -5 is the least integer in list K, what is the range of the positive integers in list K?
Options:
A)5
B)6
C)7
D)11
E)12
Rationale: Answer = A= 5
If least = -5, then largest = 6
Range = 6 - 1 = 5
Answer: A
Question: The radius of the wheel of a bus is 250 cms and the speed of the bus is 66 km/h, then the r.p.m. (revolutions per minutes)of the wheel is
Options:
A)70
B)125
C)300
D)500
E)None of these
Rationale: Radius of the wheel of bus = 250 cm. Then,
circumference of wheel = 2Ï€r = 500Ï€ = 1571.43440 cm
Distance covered by bus in 1 minute
= 66â„60 Ã— 1000 Ã— 100 cms
Distance covered by one revolution of wheel
= circumference of wheel
= 1571.45 cm
âˆ´ Revolutions per minute = 6600000/60Ã—1571.43 = 70
Answer A
Answer: A
Question: Two numbers are respectively 20% and 50% more than a third number. The ratio of the two
numbers is
Options:
A)2:5
B)3:5
C)4:5
D)6:5
E)None of these
Rationale: Explanation:
Let the third number be x.
First Number (120/100)*x = 6x/5
Second Number (150/100)*x = 3x/2
Ratio = 6x/5:3x/2
=> 4:5
Answer: C
Answer: C
Question: If d=(10^10)-47, what is the sum of all the digit of d?
Options:
A)40
B)45
C)50
D)55
E)80
Rationale: Start small and check for any pattern:
10^2 - 47 = 53 -> number of digits = power of 10; number of 9s = (power of 10) - 2; 53 is the last 2 digits
10^3 - 47 = 953 -> number of digits = power of 10; number of 9s = (power of 10) - 2; 53 is the last 2 digits
...extrapolate
10^10 - 47 -> number of digits = 10; number of 9s = 8; 53 will be the last 2 digits
d = 9*8 + 5 + 3 = 80.
Answer (E).
Answer: E
Question: The average weight of a group of boys is 30 kg. After a boy of weight 36 kg joins the group, the average weight of the group goes up by 1 kg. Find the number of boys in the group originally ?
Options:
A)A)5
B)B)8
C)C)6
D)D)2
E)E)1
Rationale: Let the number off boys in the group originally be x.
Total weight of the boys = 30x
After the boy weighing 36 kg joins the group, total weight of boys = 30x + 36
So 30x + 36 = 31(x + 1) = > x = 5.
Answer:A
Answer: A
Question: 80 is what percent of 40?
.
Options:
A)0.2%
B)2%
C)200%
D)20%
E)500%
Rationale: 80= x*40/100
x = 200%
Ans; C
Answer: C
Question: 9 years ago I was five times as old as my eldest son. Today I am 3 times his age. How old am I now?
Options:
A)34
B)44
C)54
D)64
E)74
Rationale: x-9=5(y-9)
& x=3y
x-9=5x/3-45
x=54
ANSWER:C
Answer: C
Question: A certain university will select 1 of 7 candidates eligible to fill a position in the mathematics department and 2 of 7 candidates eligible to fill 2 identical positions in the computer science department. If none of the candidates is eligible for a position in both departments, how many different sets of 3 candidates are there to fill the 3 positions?
Options:
A)42
B)70
C)147
D)165
E)315
Rationale: Ans: 147
7C1 * 7C2
Answer C)
Answer: C
Question: How many days will there be from 26th January,1996 to 15th May,1996(both days included)?
Options:
A)102
B)103
C)111
D)120
E)201
Rationale: Explanation :
Number of days from 26-Jan-1996 to 15-May-1996 (both days included)
= 6(Jan) + 29(Feb) + 31 (Mar) + 30(Apr)+ 15(May) = 111
Answer : Option C
Answer: C
Question: 2^(20) + 2^(21) + 2^(22) + ... + 2^(49) + 2^(50) =
Options:
A)2^20(2^(21)-1)
B)2^20(2^(31)-1)
C)2^20(2^(28)-1)
D)2^21(2^(21)-1)
E)2^21(2^(25)-1)
Rationale: 2^(20) + 2^(21) + 2^(22) + ... + 2^(49) + 2^(50) =
2^(20)*(1+2+4+...+2^(30)) =
2^(20)*(2^(31) - 1)
The answer is B.
Answer: B
Question: A company bought for its 5 offices 2 computers of brand N and 3 computers of brand M. In how many ways could computers be distributed among the offices if each office can have only 1 computer.
Options:
A)1
B)10
C)25
D)29
E)31
Rationale: This problem has to do withcombinations. Here's the general idea: if you have a set of n elements, and you are going to choose r of them (r < n), then the number of combinations of size r one could choose from this total set of n is:
# of combinations = nCr = (n!)/[(r!)((n-r)!)]
where n! is the factorial symbol, which means the product of every integer from n down to 1. BTW, nCr is readn choose r.
In this problem, let's consider first the three computers of brand M. How many ways can three computer be distributed to seven offices?
# of combinations = 5C3 = 10
There are 10 different ways to distribute three computers to 7 offices. (The massive amount of cancelling that occurred there is very much typical of what happens in the nCr formula.)
One we have distributed those three M computers, we have to distribute 2 N computers to the remaining four offices. How many ways can two computer be distributed to four offices?
# of combinations = 2C2 = 1
For each of the 10 configurations of distributing the M computers, we have 1 ways of distributing the N computers to the remaining offices. Thus, the total number of configurations is 10*1 = 10. Answer choice =B
Answer: B
Question: A sum of Rs. 12,500 amounts to Rs. 15,500 in 4 years at the rate of simple interest .What is the rate of interest ?
Options:
A)3%
B)4%
C)5%
D)6%
E)7%
Rationale: Solution
S.I. = Rs. (15500 - 12500) = Rs. 3000.
Rate =(100x3000/12500x4) = 6 %.
Answer D
Answer: D
Question: Carl drove from his home to the beach at an average speed of 80 kilometers per hour and returned home by the same route at an average speed of 70 kilometers per hour. If the trip home took 1/2 hour longer than the trip to the beach, how many kilometers o did Carl drive each way?
Options:
A) 350
B) 345
C) 320
D) 280
E) 240
Rationale: Let us backsolve here.
The answer option has to be divisible by 7 to give us 1/2.
Let us try o=280 km. Time taken will be 3.5 hours and 4 hours.
Hence D is the answer.
Answer: D
Question: Convert 0.35 in to a vulgar fraction ?
Options:
A)18/50
B)16/50
C)7/20
D)19/50
E)None
Rationale: Answer
0.35 = 35/100 = 7/20
Correct Option: C
Answer: C
Question: A train speeds past a pole in 20 seconds and a platform 100 m long in 25 seconds. Its length is?
Options:
A)188 m
B)876 m
C)251 m
D)150 m
E)400 m
Rationale: Let the length of the train be x meters and its speed be y m/sec.
They, x / y = 20 => y = x/20
x + 100 / 25 = x / 20
x = 400 m.
Answer: E
Answer: E
Question: A shopkeeper labeled the price of his articles so as to earn a profit of 20% on the cost price. He then sold the articles by offering a discount of 10% on the labeled price. What is the actual percent profit earned in the deal?
Options:
A)18%
B)20%
C)17%
D)19%
E)None of these
Rationale: Explanation:
Let the CP of the article = Rs.100.
Then labeled price = Rs.120.
SP = Rs.120- 10% of 120 = Rs.120-13 = Rs.118.
Gain = Rs.118 â€“ Rs.100 = Rs.18
Therefore, gain/profit percent = 18%.
Answer: Option D
Answer: D
Question: One night 16 percent of the female officers on a police force were on duty. If 160 police officers were on duty that night and half of these were female officers, how many female officers were on the police force?
Options:
A)500
B)650
C)800
D)950
E)1100
Rationale: Let x be the number of female police officers on the police force.
The number of female police officers on duty was 80.
0.16x = 80
x = 500
The answer is A.
Answer: A
Question: If 5% more is gained by selling an book for $ 350 than by selling it for $ 340, the cost of the book is:
Options:
A)160
B)210
C)200
D)227
E)220
Rationale: C
200
Let C.P. be $ x.
Then, 5% of x = 350 - 340 = 10
x/20 = 10 => x = 200
Answer: C
Question: A librarian has a set of twelve books, including four different books about Abraham Lincoln. The librarian wants to put the twelve books on a shelf with the four Lincoln books next to each other, somewhere on the shelf among the other eight books. How many different arrangements of the twelve books are possible?
Options:
A)(12!)/(4!)
B)(4!)(8!)
C)(4!)(9!)
D)(4!)(12!)
E)(4!)(8!)(12!)
Rationale: You can club the four Lincoln books as one, which leaves us with eight other books plus this one to think about. So, these nine items can be arranged in 9! ways, and since the four books can be moved around among themselves with each combination giving us a new overall combination, we have an additional 4! ways. Therefore, the answer would be 9!*4!, which is C.
Answer: C
Question: A trader bought a car at 20% discount on its original price. He sold it at a 40% increase on the price he bought it. What percent of profit did he make on the original price?
Options:
A)17%
B)17%
C)12%
D)82%
E)92%
Rationale: Original price = 100
CP = 80
S = 80*(140/100) = 112
100 - 112 = 12%
Answer: C
Answer: C
Question: Tickets to a certain concert sell for $20 each. The first 10 people to show up at the ticket booth received a 40% discount, and the next 20 received a 15% discount. If 52 people bought tickets to the concert, what was the total revenue from ticket sales?
Options:
A)$600
B)$740
C)$850
D)$900
E)$1,140
Rationale: Price of 1 ticket = 20$
Revenue generated from sales of first 10 tickets = 10 * (60/100 * 20 )
= 10 * 12 = 120
Revenue generated from sales of next 20 tickets = 20 *(85/100 * 20 )
=20*17 = 340
Revenue generated from sales of last 22 tickets = 20 * 22
= 440
Revenue generated from sales of 52 tickets = 120 + 340 + 440
= 900 $
Answer D
Answer: D
Question: In one year, the population, of a village increased by 10% and in the next year, it decreased by 10%. If at the end of 2nd year, the population was 7920, what was it in the beginning?
Options:
A)8019
B)8000
C)8279
D)2797
E)2927
Rationale: x*110/100 * 90/100 = 7920
X*0.99=7920
X=7920/0.99
=> 8000
Answer: B
Answer: B
Question: There are 350 zebras at a large zoo near city. The number of zebras is 5 times the number of all the other animals combined. How many more zebras are there than non zebra animals at the zoo?
Options:
A)500
B)420
C)340
D)280
E)200
Rationale: Answer is D.
Total zebras= 350 = 5 * Other Animals (X)
or X = 70.
So, Difference in zebras and X = 350-70 = 280.
Answer: D
Question: A pair of articles was bought for Rs. 37.40 at a discount of 15%. What must be the marked price of each of the articles ?
Options:
A)Rs15
B)Rs 20
C)Rs 22
D)Rs 25
E)None of these
Rationale: Explanation:
As question states that rate was of pair of articles,
So rate of One article = 37.40/2 = Rs. 18.70
Let Marked price = Rs X
then 85% of X = 18.70
=> X = 1870/85 = 22
Option C
Answer: C
Question: A monkey climbs 30 feet at the beginning of each hour and rests for a while when he slips back 20 feet before he again starts climbing in the beginning of the next hour. If he begins his ascent at 7.00 a.m., at what time will he first touch a flag at 120 feet from the ground?
Options:
A)4 p.m.
B)5 p.m.
C)6 p.m.
D)7 p.m.
E)None of these
Rationale: Explanation:
Net ascent of the monkey in 1 hour = (30 - 20) feet = 10 feet.
So, the monkey ascends 90 feet in 9 hours i.e. till 4 p.m.
Clearly, in the next 1 hour i.e. till 5 p.m. the monkey ascends remaining 30 feet to touch the flag.
Answer:B
Answer: B
Question: An express train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the express train is 54 km/hr, what is the length of the platform?
Options:
A)m
B)m
C)m
D)m
E)of these
Rationale: Speed = (54 * 5/18) m/sec = 15 m/sec. Length of the train = (15 x 20)m = 300 m. Let the length of the platform be x meters. Then, (x + 300)/36 = 15 ==> x + 300 = 540 ==> x = 240 m.
ANSWER:B
Answer: B
Question: Given that √12 = 3.464 and √120 = 10.95, find the value of √1.2 + √1200 + √0.012.
Options:
A)32.164
B)35.844
C)36.164
D)37.304
E)None of these
Rationale: Explanation:
Given exp. = √1.2 +√1200 +√0.0120 = √120/100 +√12*100 + √120/10000
= (√120)/10 + √12 * 10 + (√120)/100 = 10.95/10 + 3.464 * 10 + 10.95/100
= 1.095 + 34.64 + 0.1095
= 35.8445
ANSWER B
Answer: B
Question: X, Y, and Z are consecutive numbers and X > Y > Z. Also, X + 3Y + 3Z = 5Y + 6. What is the value of Z?
Options:
A)2
B)3
C)4
D)5
E)6
Rationale: If X, Y, and Z are consecutive numbers and X > Y > Z, then Y = Z+1 and X = Z+2.
X + 3Y + 3Z = 5Y + 6
Z+2+3Z+3+3Z = 5Z+5+6
2Z = 6
Z = 3
The answer is B.
Answer: B
Question: Excluding the stoppages, the speed of a bus is 64 km/hr and including the stoppages the speed o the bus is 48km/hr. For how many minutes does the bus stop per hour?
Options:
A)22
B)15
C)77
D)28
E)91
Rationale: Answer: B) 15 minutes
Answer: B
Question: A group of medical interns at Bohemus Medical School want to go on dates. There are 4 girls and 4 guys. Assuming girls go on dates with guys, how many possible ways can these 8 medical interns date each other?
Options:
A)A)16
B)B)18
C)C)20
D)D)22
E)E)24
Rationale: 1st girl can go with 4 guys
2nd girl can go with remaining 3
3rd girl can go with remaining 2 and so on
so the total ways are 4!= 24
E should be the answer
Answer: E
Question: A, B, C subscribe Rs. 50,000 for a business, A Subscribes Rs. 4000 more than B and B Rs. 5000 more than C. Out of a total profit of Rs. 70,000, C receives :
Options:
A)14700
B)16800
C)37798
D)13777
E)14778
Rationale: Explanation:
Let C = x. Then, B = x + 5000 and A = x + 5000 + 4000 = x + 9000.
So, x + x + 5000 + x + 9000 = 50000 <=> 3x = 36000 <=>
x = 12000.
A : B : C = 21000 : 17000 : 12000 = 21 : 17 : 12.
C's share = Rs. (70000 * 12/50 ) = Rs. 16800.
Answer: B)
Answer: B
Question: A seller of used cars has 15 cars to sell and each of his clients selected 3 cars that he liked most. If each car was selected exactly thrice, how many clients visited the garage?
Options:
A)8
B)10
C)12
D)14
E)15
Rationale: IfNo caris selected more than once then the number of clients = 15/3 =5
But since every car is being selected three times so No. of Clients must be thrice as well = 5*3 = 15
Answer: option E
Answer: E
Question: Faiza has 14 purses, she gives 3 purse as gift. Now how many purse did she have ?
Options:
A)2
B)5
C)11
D)9
E)4
Rationale: 14-3=11. Answer is C
Answer: C
Question: At a certain stage of a soccer tournament, the score ratio of teams A, B and C was 3:4:5. Eventually, the score ratio of A to B has doubled while the score ratio of A to C has halved. If the final score of team C was 40, what was the final score W of team B?
Options:
A)1)8
B)2)10
C)3)20
D)4)40
E)5)80
Rationale: A to B = 3 : 4
So, on doubling we get 6 : 4
A to C = 3 : 5
So, on halving we get 1.5 : 5 or 3 : 10 or 6 : 20
So final ratio = 6 : 4 : 20.
If 20x = 40
4x = 8
Hence, answer is A
Answer: A
Question: In how many different ways can the letter of the word 'LEADING ' be arranged in such a way that the vowels always come together?
Options:
A)147
B)963
C)720
D)789
E)852
Rationale: It has 7 different letters.
when the vowels EAI are always together, they can be supposed to form one letter.
then we have to arrange the letter LDNG (EAI)
now 4 letters can be arranged in 5!=120 ways
the vowels EAI can be arranged amoung themselves in 3!= 6 ways
required number of ways =120*6=720
Answer(C)
Answer: C
Question: In covering a distance of 42 km, A takes 2 hours more than B. If A doubles his speed, then he would take 1 hour less than B. A's speed is:
Options:
A)5 km/h
B)7 km/h
C)10 km/h
D)15 km/h
E)25 km/h
Rationale: Let A's speed be X km/hr.
Then, 42/x - 42/2x = 3
6x = 42
x = 7 km/hr.
Answer : B.
Answer: B
Question: If m is an integer such that (-2)^2m=2^(18-m) then m=?
Options:
A)4
B)5
C)6
D)7
E)8
Rationale: 2m = 18-m
3m = 18
m = 6
The answer is C.
Answer: C
Question: A and B undertake to do a piece of work for Rs. 1200. A alone can do it in 6 days while B alone can do it in 8 days. With the help of C, they finish it in 3 days. Find the share of A.
Options:
A)500
B)600
C)750
D)800
E)None of them
Rationale: C's 1 day's work = 1/3-(1/6+1/8)=24
A : B : C = Ratio of their 1 day's work = 1/6:1/8:1/24= 4 : 3 : 1.
A’s share = Rs. (1200 *4/8) = Rs.600, B's share = Rs. (1200 *3/8) = Rs. 450
C's share = Rs. [1200 - (300 + 225») = Rs. 150.
Answer is B
Answer: B
Question: Dacid obtained 86, 85, 92, 87 and 95 marks (out of 100) in English, Mathematics, Physics, Chemistry and Biology. What are his average marks?
Options:
A)67
B)26
C)89
D)26
E)75
Rationale: Average
= (86+ 85+ 92+ 87+95)/5
= 445/5 = 89.
Answer: C
Answer: C
Question: When positive integer n is divided by 5, the remainder is 1. When n is divided by 7, the remainder is 3. What is the smallest positive integer k such that k+n is a multiple of 34?
Options:
A)3
B)4
C)12
D)32
E)35
Rationale: n = 5p + 1 = 6,11,16,21,26,31
n = 7q + 3 = 3,10,17,24,31
=>n = 34m + 31
To get this, we need to take LCM of co-efficients of p and q and first common number in series.
So we need to add 3 more to make it
34m + 34
Answer - A
Answer: A
Question: Sixty men complete a work in 25 days. One man starts working it at and thereafter one more man joins him every day. In how many
days the work will be completed?
Options:
A)22
B)52
C)24
D)55
E)65
Rationale: 1 mens 1 day work =1/1500
1/1500(1+2+3+........n)=1(as total work=1)
We need to find n it cannot be greater than 60
Here the answer is 55(approx)
ANSWER:D
Answer: D
Question: If the mean of numbers 28, x, 42, 78 and 104 is 90, then what is the mean of 128, 255, 511, 1023 and x?
Options:
A)395
B)275
C)355
D)423
E)365
Rationale: The mean of numbers 28, x, 42, 78 and 104 is 62: 28+x+42+78+104=90*5 --> x=198;
So, the mean of 128, 255, 511, 1023 and x is (128+255+511+1023+198)/5=423.
Answer:D.
Answer: D
Question: The difference between the compound interest compounded annually and simple interest for 2 years at 20% per annum is Rs.288. Find the principal?
Options:
A)2277
B)2667
C)3600
D)7200
E)1811
Rationale: P = 288(100/5)^2 => P = 7200
Answer: D
Answer: D
Question: The area of one square is x^2 + 8x + 16 and the area of another square is 4x^2 − 20x + 25. If the sum of the perimeters of both squares is 44, what is the value of x?
Options:
A)2
B)4
C)6
D)8
E)10
Rationale: The areas are (x+4)^2 and (2x-5)^2.
The lengths of the sides are x+4 and 2x-5.
If we add the two perimeters:
4(x+4) + 4(2x-5) = 44
12x = 48
x = 4
The answer is B.
Answer: B
Question: A watch was sold at a loss of 10%. If it was sold for Rs.200 more, there would have been a gain of 4%. What is the cost price?
Options:
A)1000
B)1429
C)1977
D)2778
E)2711
Rationale: 90%
104%
--------
14% ---- 200
100% ---- ? => Rs.1429
Answer: B
Answer: B
Question: The average of 21 numbers is 25. The average of first ten numbers is 18 and the average of last ten numbers is 32. What is the middle number?
Options:
A)195
B)175
C)184
D)201
E)188
Rationale: The total of 21 numbers = 21X25 = 525
The total of first 10 and last 10 numbers is = 10 X 14+10 X 19 = 330
So, the middle number is (525 - 330 ) = 195
A
Answer: A
Question: A committee of two people is to be chosen from 5 married couples. What is the number of different committees that can be chosen if two people who are married to each other cannot both serve on the committee?
Options:
A)16
B)24
C)26
D)40
E)32
Rationale: One of the approaches:
Each couple can send only onerepresentativeto the committee. Let's see in how many ways we can choose 2 couples (as there should be 2 members) out of 5 to send only onerepresentativesto the committee: 5C2=10.
But each of these 2 couples can send two persons (husband or wife): 2*2=2^2=4.
Total # of ways: 5C2*2^2=40.
Answer: D.
Answer: D
Question: A sum of money amounts to Rs.9800 after 5 years and Rs.12005 after 8 years at the same rate of simple interest. The rate of interest per annum is
Options:
A)15%
B)12%
C)8%
D)7%
E)5%
Rationale: Explanation :
Simple Interest for 3 years = (Rs.12005 - Rs.9800) = Rs.2205
Simple Interest for 5 years = 22053×5=Rs.3675
Principal(P) = (Rs.9800 - Rs.3675) = Rs.6125
R = 100×SI/PT
=100×3675/6125×5
=12%
Answer : Option B
Answer: B
Question: In 30 years, A will be twice as old as B was 30 years ago. If A is now 5 years older than B, the present age of B is?
Options:
A)85yrs
B)95yrs
C)93yrs
D)82yrs
E)90yrs
Rationale: Let B's present age = x years
Then A's present age = x+5 years
x+5+30 = 2(x-30)
x + 35 = 2x - 60
x = 95years
Answer is B
Answer: B
Question: John Purchased 1375 large bottles at $1.75 per bottle and 690 small bottles at $1.35 per bottle. What was the approximate average price paid per bottle?
Options:
A)$1.62
B)$1.64
C)$1.68
D)$1.72
E)$1.76
Rationale: (1375*1.75+690*1.35)/(1375+690) =~1.62
Option (A)
Answer: A