divelab/Sys2Bench huggingface dataset:
Question: A salesmanâ€™s terms were changed from a flat commission of 5% on all his sales to a fixed salary of Rs.1000 plus 2.5% commission on all sales exceeding Rs. 4,000. If his remuneration as per new scheme was Rs. 600 more than that by the previous schema, his sales were worth?
Options:
A)Rs. 14,000
B)Rs. 12,000
C)Rs. 30,000
D)Rs. 40,000
E)Rs. 45,000
Rationale: Explanation:
[1000 + (X-4000) * (2.5/100)] - X * (5/100) = 600
X = 12000
ANSWER IS B
Answer: B
Question: A man buys s cycle for $100 and sells it at a loss of 40%. What is the selling price of the cycle?
Options:
A)$50
B)$60
C)$70
D)$80
E)$90
Rationale: S.P. = 60% of the $100 = 60/100 * 100 = $60
Answer is B
Answer: B
Question: The variables m and n are positive integers. When m is divided by 18, there is a remainder of 12, and when n is divided by 24, there is a remainder of 14. Which of the following are possible values of m + n?
I. 50
II. 68
III. 90
Options:
A)I only
B)III only
C)I and II
D)I only III
E)II and III
Rationale: m = 18k + 12 --> Values are 12, 30, 48, 66, 84
n = 24k + 14 --> Values are 14, 38, 62, 86
I. 50 --> 12 + 38 --> Possible
II. 68 --> 30 + 38--> Possible
III. 92 --> Not possible
Answer: C
Answer: C
Question: A shop sells two variants of chocolates - one that costs $3 and the other that costs $5. If the shop sold $151 chocolates on a given day, how many different combinations of (number of $3 sold, number of $5 sold) exist?
Options:
A)8
B)10
C)12
D)14
E)16
Rationale: $151 = 29*$5 + 2*$3
We can find other combinations by reducing the $5 chocolates by 3 (which is -$15)and increasing the $3 chocolates by 5 (which is +$15).
The number of $5 chocolates can be 29, 26, 23, 20,...,2 for a total of 10 combinations.
The answer is B.
Answer: B
Question: In a graduating class of 234 students, 144 took geometry and 119 took biology. What is the difference between the greatest possible number and the smallest possible number of students that could have taken both geometry and biology?
Options:
A)144
B)115
C)113
D)88
E)31
Rationale: Greatest Possible Number taken both should be 144 (As it is maximum for One)
Smallest Possible Number taken both should be given by
Total - Neither = A + B - Both
Both = A+B+Neither - Total (Neither must be 0 to minimize the both)
So 144 + 119 + 0 - 234 = 29
Greatest - Smallest is 144-29 = 115
So answer must be B. 115
Answer: B
Question: John drove for 3 hours at a rate of 50 miles per hour and for 2 hours at 60 miles per hour. What was his average speed for the whole journey?
Options:
A)The average speed is 54 miles per hour.
B)The average speed is 32 miles per hour.
C)The average speed is 44 miles per hour.
D)The average speed is 60 miles per hour.
E)The average speed is 72 miles per hour.
Rationale: Step 1: The formula for distance is
Distance = Rate × Time
Total distance = 50 × 3 + 60 × 2 = 270
Step 2: Total time = 3 + 2 = 5
Step 3: Using the formula
average speed formula
270/5 = 54
Answer(A)
Answer: A
Question: If 18 bindres bind 900 books in 10 days , How many binders will be required to bind 660 books in 12 days?
Options:
A)71
B)12
C)18
D)11
E)29
Rationale: Explanation:
Let the required no of binders be X.
Less books , Less binders (Direct Proportion)
More days, Less binders (Indirect proportion)
\inline \fn_jvn \left.\begin{matrix} Books\: 900:600\\ Days\: \: 12:10 \end{matrix}\right\}::18:x
\inline \fn_jvn \therefore \inline \fn_jvn (900\times 12\times x)=(600\times 10\times 18) \inline \fn_jvn \Leftrightarrow x= \inline \fn_jvn \frac{600\times 10\times 18}{900\times 12} = 11
Answer: D
Answer: D
Question: In a class, there are 20 boys whose average age is decreased by 2 months, when one boy aged 21 years replaced by a new boy. The age of the new boy is?
Options:
A)14 years 8 months
B)15 years
C)16 years 4 months
D)17 years 8 months
E)17 years
Rationale: Total decrease = (20 x 2) months
= 3 years 4 months
Age of the new boy
= 21 years - 3 years 4 months.
= 17 years 8 months.
ANSWER:D
Answer: D
Question: If 100 cats kill 100 mice in 100 days, then 4 cats would kill 4 mice in how many days ?
Options:
A)1 day
B)4 days
C)40 days
D)100 days
E)50 days
Rationale: as
100 cats kill 100 mice in 100 days
1 cats kill 1 mouse in 100 days
then
4 cats kill 4 mice in 100 days
ANSWER:D
Answer: D
Question: A cistern has a leak which would empty the cistern in 20 minutes. A tap is turned on which admits 4 liters a minute into the cistern, and it is emptied in 24 minutes. How many liters does the cistern hold?
Options:
A)480
B)456
C)345
D)356
E)368
Rationale: 1/x - 1/20 = -1/24
x = 120
120 * 4 = 480
Answer: A
Answer: A
Question: Reduce
803876
to the lowest terms
Options:
A)1112
B)2324
C)2627
D)47
E)None of these
Rationale: Explanation:
HCF of 803 and 876 is 73, Divide both by 73, We get the answer 11/12
Answer: Option A
Answer: A
Question: A 25 cm wide path is to be made around a circular garden having a diameter of 4 meters. Approximate area of the path is square meters is?
Options:
A)3.34
B)3.32
C)3.2
D)3.08
E)3.17
Rationale: Area of the path = Area of the outer circle - Area of the inner circle
= ∏{4/2 + 25/100}2 - ∏[4/2]2
= ∏[2.252 - 22] = ∏(0.25)(4.25) { (a2 - b2 = (a - b)(a + b) }
= (3.14)(1/4)(17/4) = 53.38/16
= 3.34 sq m
Answer: A
Answer: A
Question: Two tailors X and Y are paid a total of Rs. 550 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?
Options:
A)Rs. 200
B)Rs. 250
C)Rs. 300
D)Rs. 350
E)None
Rationale: Solution
Let the sum paid to Y per week be Rs. z.
Then, z + 120% of z = 550.
‹=›z + 120 / 100 z = 550
‹=› 11 / 5 z = 550
‹=›z = [550 x 5 / 11] = 250.
Answer B
Answer: B
Question: here are 6 periods in each working day of a school. In how many ways can one organize 5 subjects such that each subject is allowed at least one period?
Options:
A)2120
B)4123
C)3621
D)1800
E)1450
Rationale: 5 subjects can be arranged in 6 periods in 6P5 ways.
Any of the 5 subjects can be organized in the remaining period (5C1 ways).
Two subjects are alike in each of the arrangement. So we need to divide by 2! to avoid overcounting.
Total number of arrangements
= 6P5× 5C1 /2!=1800
Ans: D
Answer: D
Question: If (18^a) * 9^(3a – 1)= (2^5)(3^b) and a and b are positive integers, what is the value of a?
Options:
A)22
B)11
C)9
D)6
E)5
Rationale: (18^a) * 9^(3a – 1)= (2^5)(3^b)
= 2^a . 9^a . 9^(3a – 1) = (2^5)(3^b)
Just compare powers of 2 from both sides
Answer = 5 = E
Answer: E
Question: A dishonest dealer professes to sell his goods at Cost Price but still gets 35% profit by using a false weight. What weight does he substitute for a kilogram?
Options:
A)740 1/7 grams
B)740 20/27 grams
C)740 8/3 grams
D)740 1/3 grams
E)740 1/27 grams
Rationale: If the cost price is Rs.100, then to get a profit of 35%, the selling price should be Rs.135.
If 135kg are to be sold, and the dealer gives only 100kg, to get a profit of 35%.
How many grams he has to give instead of one kilogram(1000 gm).
135 gm ------ 100 gm
1000 gm ------ ?
(1000 * 100)/135 = 740 20/27 grams.
Answer:B
Answer: B
Question: If the probability of rain on any given day in Chicago during the summer is 20%, independent of what happens on any other day, what is the probability of having exactly 3 rainy days from July 4 through July 7 inclusive?
Options:
A)2/25
B)3/125
C)7/125
D)12/625
E)16/625
Rationale: One possible case is: rainy-rainy-rainy-not rainy.
The probability of this case is 1/5*1/5*1/5*4/5 = 4/625
The number of possible cases is 4C3 = 4.
P(exactly 3 rainy days) = 4*4/625 = 16/625
The answer is E.
Answer: E
Question: Vishal invested 10% more than Trishul. Trishul invested 10% less than Raghu. If the total sum of their investments is Rs. 5780, how much amount did Raghu invest ?
Options:
A)1287
B)2887
C)2000
D)1129
E)1192
Rationale: Let money invested by Raghu = Rs. x
Money invested by Trishul = 9/10 x = 0.9x
Money invested by Vishal = 9/10x * 110/100 = 0.99x
Also, x+0.9x+0.99x = 5780
= x= 5780/2.89 = 2000
Therefore, amount invested by Raghu is Rs. 2000.
Answer: C
Answer: C
Question: P beats Q by 125 meter in a kilometer race. Find Q's speed if P's speed is 32 meter/sec.
Options:
A)21 meter/sec
B)7 meter/sec
C)14 meter/sec
D)18 meter/sec
E)28 meter/sec
Rationale: P's speed = 32 m/s
P's distance = 1000m (as it is a km race)
t = 1000/32 = 31.25 sec
Q's distance = 1000-125= 875m
Q's time to complete this distance is also 62.5 sec.
Q's speed = dist/time = 875/31.25 = 28 m/s
Hence E is the answer.
Answer: E
Question: Pipes A and B can fill a cistern in 8 and 24 minutes respectively. They are opened an alternate minutes. Find how many minutes, the cistern shall be full?
Options:
A)11
B)12
C)99
D)75
E)72
Rationale: 1/8 + 1/24 = 1/6
6 * 2 = 12
Answer: B
Answer: B
Question: x =1 2 3
y= 4 5 18 then what is the relation between x and y
Options:
A)1*X)^1
B)1*X)^6
C)1*X)^7
D)1*X)^4
E)1*X)^2
Rationale: Y=(1*X)^2
4=(1*2)^2
4=4
ANSWER:E
Answer: E
Question: The area of a parallelogram is 128sq m and its altitude is twice the corresponding base. Then the length of the base is?
Options:
A)8
B)9
C)6
D)5
E)1
Rationale: 2x * x = 128 => x
= 8
Answer:A
Answer: A
Question: The average weight of a group of boys is 30 kg. After a boy of weight 35 kg joins the group, the average weight of the group goes up by 1 kg. Find the number of boys in the group originally ?
Options:
A)4
B)7
C)6
D)8
E)6
Rationale: Let the number off boys in the group originally be x.
Total weight of the boys = 30x
After the boy weighing 35 kg joins the group, total weight of boys = 30x + 35
So 30x + 35 + 31(x + 1) = > x = 4.
Answer:A
Answer: A
Question: a, b, c, d, and e are five consecutive numbers in increasing order of size. Deleting one of the five
numbers from the set decreased the sum of the remaining numbers in the set by 20%. Which one of
the following numbers E was deleted?
Options:
A) a
B) b
C) c
D) d
E) e
Rationale: a+b+c+d+e => 1+2+3+4+5=15
20%*15= 3 =>C
Answer: C
Question: A can do a piece of work in 30 days. He works at it for 5 days and then B finishes it in 20 days. In what time can A and B together it ?
Options:
A)15 1/3 days
B)13 1/3 days
C)19 1/3 days
D)11 1/3 days
E)12 1/3 days
Rationale: B
13 1/3 days
5/30 + 20/x = 1
x = 24
1/30 + 1/24 = 3/40
40/3 = 13 1/3 days
Answer: B
Question: A boat running downstream covers a distance of 16 km in 2 hours while for covering the same distance upstream,it takes 4 hours.What is the speed of the boat in still water ?
Options:
A)4 km/hr
B)6 km/hr
C)8 km/hr
D)Data inadequate
E)None of these
Rationale: Solution
Rate downstream =(16/2) kmph = 8 kmph, Rate upstream =(16/4) = 4 kmph.
∴ Speed in still water =1/2(8+4) kmph = 6 kmph. Answer B
Answer: B
Question: During the second quarter of 1984, a total of 2,976,000 domestic cars were sold. If this was 24% greater than the number sold during the first quarter of 1984, how many were sold during the first quarter ?
Options:
A)714,240
B)2,261,760
C)2,400,000
D)3,690,240
E)3,915,790
Rationale: Let number of cars sold in 1st quarter = x
Number of cars sold in 2nd quarter = 24% greater than the number sold during the first quarter = (1 + 24/100)x = 1.24 x
1.24 x = 2,976,000
=> x = 2,400,000
So, answer will be C
Answer: C
Question: The two trains of lengths 400 m, 600 m respectively, running at same directions. The faster train can cross the slower train in 180 sec, the speed of the slower train is 48 km. then find the speed of the faster train?
Options:
A)66 Kmph
B)68 Kmph
C)86 Kmph
D)99 Kmph
E)55 Kmph
Rationale: Length of the two trains = 600m + 400m
Speed of the first train = X
Speed of the second train= 48 Kmph
1000/X - 48 = 180
1000/x - 48 * 5/18 = 180
50 = 9X - 120
X = 68 Kmph .Answer: B
Answer: B
Question: Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 4 seconds. What is the length of the fast train ?
Options:
A)22 2/9
B)28 7/9
C)29 7/9
D)30 7/9
E)None of these
Rationale: Explanation:
As Trains are moving in same direction,
So, Relative Speed = 40-20 = 20 kmph
= 20*(5/18) = 50/9 m/sec
Length of Train= Speed * Time
Length=50/9âˆ—4
=200/9
=22 2/9
Option A
Answer: A
Question: A pool can be filled in 4 hours and drained in 5 hours. The valve that fills the pool was opened at 1:00 pm and some time later the drain that empties the pool was also opened. If the pool was filled by 9:00 pm and not earlier, when was the drain opened?
Options:
A)at 2:00 pm
B)at 2:30 pm
C)at 3:00 pm
D)at 3:30 pm
E)at 4:00 pm
Rationale: The filling rate is 1/4 and the draining rate is 1/5.
The combined rate of filling and draining is 1/4 - 1/5 = 1/20.
Let x be the number of hours before the drain was opened.
x/4 + (8-x)/20 = 1
5x + 8 - x = 20
4x = 12
x = 3
The answer is 4:00 pm.
The answer is E.
Answer: E
Question: A man engaged a servant on the condition that he would pay him Rs.900 and a uniform after 1year service. He served onlyfor 9 months and received uniform & Rs.650, find the price of the uniform?
Options:
A)Rs.90
B)Rs.100
C)Rs.150
D)Rs.190
E)Rs.200
Rationale: 9/12 = 3/4 * 900 = 675
650
-------------
25
1/4 -------- 25
1 --------- ? => Rs.100
B
Answer: B
Question: 9 friends bought a franchise for 500,000 dollars. If they all have to pay the same amount and none of them have bills smaller than $1, how much money would they have to pay?
Options:
A)500,003
B)500,001
C)500,004
D)500,000
E)500,005
Rationale: In order to divide the sum in 9 parts, the amount must be divisible by 9
Divisibility rule of 9: The sum of the digits must be divisible by 9
Sum of digits of 500,000 = 5 and 9 is divisible by 9.
Hence, we need to add 4 to this number for it to be divisible by 9
Correct Option: C
Answer: C
Question: The ratio of the number of ladies to gents at a party was 1:2 but when 2 ladies and 2 gents left, the ratio became 1:3. How many people were at the party originally?
Options:
A)18
B)17
C)12
D)19
E)11
Rationale: x, 2x
(x-2):(2x-2) = 1:3
3x-6 = 2x-2
x = 4
x+2x = 3x
=> 3*4 = 12
Answer: C
Answer: C
Question: What number should replace the question mark?
100, 93, 79, 53, ?.
Options:
A)30
B)36
C)32
D)41
E)44
Rationale: A
30
The sequence progresses –7, –14, –21, –28.
Answer: A
Question: There are 14 balls in a jar: 8 red, 3 blue and 3 green. If a single ball is drawn from the jar, what is the probability of that it is either blue or red?
Options:
A)1/12
B)11/14
C)1/2
D)2/3
E)3/4
Rationale: Blue + Red =11
Total number of balls is 8+3+3=14
So the answer is 11/14=11/14
Answer B
Answer: B
Question: Jill, who lives in City C, plans to visit 7 different cities, M, L, P, I, Y, B and S. She plans to visit each city exactly once and return to City C after the 7 visits. She can visit the cities in any order. In how many different orders can she visit the 7 cities?
Options:
A) 3000
B) 5040
C) 8000
D) 9000
E) 12000
Rationale: 7! = 5040 =B
Answer: B
Question: 12 : 21 :: 31 :?
Options:
A)13
B)14
C)30
D)31
E)40
Rationale: Ans 13
Reverse of 31
ANSWER:A
Answer: A
Question: A man divides $8600 Among 5 Sons, 4 Daughters and 2 Nephews. If each daughter receives four times as much as each nephews and each son receives five times as much as each nephews, how much does each daughter receive?
Options:
A)$200
B)$1000
C)$800
D)$1200
E)$400
Rationale: Let the share of each nephews be $X.
Then, share of each daughter=$4X, share of each son= $5X.
So, 5*5X+4*4X+2*X=8600
25X+16X+2X=8600
43X=8600, X=200.
Daughter receives four times of nephew so 4 * 200 = 800.
So Each Daughter receives $800. answer is option C) $800.
Answer: C
Question: There are three boats B1, B2 and B3 working together they carry 60 people in each trip. One day an early morning B1 carried 50 people in few trips alone. When it stopped carrying the passengers B2 and B3 started carrying the people together. It took a total of 10 trips to carry 300 people by B1, B2 and B3. It is known that each day on an average 300 people cross the river using only one of the 3 boats B1, B2 and B3. How many trips it would take to B1, to carry 150 passengers alone?
Options:
A)15
B)30
C)25
D)10
E)15
Rationale: Explanation:
Combined efficiency of all the three boats = 60 passenger/trip
Now, consider option(a)
15 trips and 150 passengers means efficiency of B1 = 10p/t
which means in carrying 50 passengers B1 must has taken 5 trips. So the rest trips equal to 5 (10-5 = 5) in which B2 and B3 together carried remaining 250 (300 - 50 = 250) Passengers.
Therefore the efficiency of B2 and B3 = 250/5 = 50 p/t
Since, the combined efficiency of B1, B2 and B3 is 60. Which is same as given in the first statement hence option(a) is correct
Answer: A
Answer: A
Question: If x and y are integers and xy = 660, x or y must be divisible by which of the following numbers?
Options:
A)4
B)5
C)6
D)20
E)30
Rationale: xy = 660 = 2 * 2 * 3 * 5 * 11
One of x or y must be divisible by 5.
The answer is B.
Answer: B
Question: Lovely shop runs a sale on goldfish and platys. If one customer buys 13 goldfish and 12 platys for $5.60, and another buys 14 goldfish and 21 platys for $8.05, what is the ratio of the price of goldfish to platys?
Options:
A)0.8
B)0.75
C)c) 8/9
D)5/7
E)6/8
Rationale: The approach of plugging in the numbers is a fine approach. But, in this case, the answer was the first option and thus, by plugging in a number in the ration given, we arrived at the answer quickly!
However, what if the correct ratio was option D or C?
In any case, the algebraic solution isn't that complex if you realize a key concept:
The number 7 can be factored out of the second equation!
Here's the working:Lovely shop runs a sale on goldfish and platys.
13x + 12y = 5.60 <<<<< Equation 1
14x + 21y = 8.05 <<<<< Equation 2
2x + 3y = 1.15 [Factor Out 7 from equation 2] <<<<< Equation 3
8x + 12y = 4.6 [Multiply Equation 3 with 4]
5x = 1.0 [Equation 1 - Equation 2]
x = 0.2
3y = 1.15 - 0.4 = 0.75 [Substitute for x in Equation 1]
y = 0.25
x/y = 0.2/0.25 = 20/25 = 4/5 = 0.8 [Answer A]
The whole thing must have taken me about 45 s :D
Answer: D
Question: How many solutions does the equation
sin(x) sin(2x) sin(3x) · · · sin(11x) sin(12x) = 0
have in the interval (0,π] ?
Options:
A)11
B)12
C)24
D)46
E)68
Rationale: If x is a solution of the equation, then lx = k for some integers k and l with 1 _<l_<12. Thus
x = k
lπ. Since we want x to be in (0;π], the number of solutions equals the number of fractions in
(0,1] with numerator an integer, and denominator a positive integer _<12. Since we want to avoid
counting the same solution twice (for example 2π/=3 = 4π/6), we need to count only fractions in
lowest terms. Let φ(n) be the number of fractions in lowest terms in (0,1] with denominator n.
Then φ(1) = 1, φ(2) = 1,φ(3) = 2, φ(4) = 2,φ(5) = 4, φ(6) = 2,φ(7) = 6, φ(8) = 4,
φ(9) = 6, φ(10) = 4,φ(11) = 10, and φ'(12) = 4. Adding the above values of φ we get that the
number of solutions is 46.
correct answer D
Answer: D
Question: Six bells commence tolling together and toll at intervals of 2, 4, 6, 8 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together ?
Options:
A)4
B)10
C)15
D)16
E)None
Rationale: L.C.M. of 2, 4, 6, 8, 10, 12 is 120.
So, the bells will toll together after every 120 seconds(2 minutes).
In 30 minutes, they will toll together 30/2 + 1= 16 times
Answer D
Answer: D
Question: A bag of n peanuts can be divided into 9 smaller bags with 6 peanuts left over. Another bag of m peanuts can be divided into 12 smaller bags with 4 peanuts left over. Which of the following is the remainder when nm is divided by 12?
Options:
A)4
B)3
C)2
D)1
E)0
Rationale: n = 9x + 6
m = 12y + 4
nm = (9x + 6)*(12y + 4) = 108xy + 36x + 72y + 24
Remainder of nm/12 = (108xy + 36x + 72y + 24)/12
Observe that the all four terms are a multiple of 12
Hence mn/12 will have no remainder
Correct Option: E
Answer: E
Question: The probability of Sam passing the exam is 1/4. The probability of Sam passing the exam and Michael passing the driving test is 1/2. What is the probability of Michael passing his driving test?
Options:
A)1/24.
B)2.
C)1/3.
D)2/3.
E)2/5
Rationale: 1/4 *1/m= 1/2 , 1/m = 2
Answer B
Answer: B
Question: If $0.90 is the commission for sales of $3,000, what percent of the sales amount is the commission?
Options:
A)3%
B)0.3%
C)0.03%
D)0.003%
E)0.0003%
Rationale: % of sales amount of commission
= (Commission/Total Value) *100
= (0.9/3000) * 100
= 0.03%
The answer is C.
Answer: C
Question: What annual instalment will discharge a debt of Rs 1092 due in 3 years at 12% simple interest?
Options:
A)325
B)234
C)998
D)277
E)991
Rationale: Let each instalment be Rs.x .
1st year = [x + (x * 12 * 2)/100]
2nd year = [ x + (x *12 * 1)/100]
3rd year = x
Then, [x + (x * 12 * 2)/100] + [ x + (x *12 * 1)/100] + x =1092
3x + ( 24x/100 ) + ( 12x/100 ) = 1092
336x =109200
x = 325
Each instalment = Rs. 325
Answer: A) Rs.325
Answer: A
Question: A company has 15 managers and 75 associates. The 15 managers have an average salary of $210,000. The 75 associates have an average salary of $30,000. What is the average salary for the company?
Options:
A)$35,000
B)$45,000
C)$55,000
D)$60,000
E)$75,000
Rationale: Another method is to get ratios
Say 30000=a and
We know the # of people are in 1:5 ratio
Average=(7a*1+a*5)/6= 12a/6=2a=60000
Answer is D. $60,000
Answer: D
Question: If 10 gallons of grape juice are added to 40 gallons of a mixture, which contains 10 percent grape juice then what percent of the resulting mixture is grape juice?
Options:
A)14%
B)25%
C)28%
D)34%
E)50%
Rationale: Mixture contains 4 gallons of grape juice out of 40 gallons
After addition: 14 gallons of grape juice out of 50 gallons ==> 28%
Answer C
Answer: C
Question: What will be the compound interest on Rs. 45000 after 3 years at the rate of 12 % per annum
Options:
A)Rs 18221.76
B)Rs 18123.30
C)Rs 18123.40
D)Rs 18123.50
E)None of these
Rationale: Explanation:
(45000×(1+12/100)3)
=>45000×28/25×28/25×28/25
=>63221.76
So Compound interest will be 63221.76 - 45000
= Rs 18221.76
Option A
Answer: A
Question: A certain auto manufacturer sold 3% fewer vehicles in 2007 than in 2006. If the manufacturer sold 2.6 million vehicles in 2006, how many vehicles, to the nearest 1,000, did the manufacturer sell in 2007?
Options:
A)63,000
B)2,000,000
C)2,030,000
D)2,040,000
E)2,300,000
Rationale: Let's assume in 2006 he has sold X. Therefore in 2007 he should have sold 97/100×X.
97/100×2100=2037
-->2,037,000 sold in 2007. When rounded to the nearest 10,000 :
63,000
A
Answer: A
Question: If xy = 5 and x^2 + y^2 = 14, then x/y + y/x =
Options:
A)2 4/5
B)3 1/7
C)5 1/3
D)7
E)60
Rationale: x/y+y/x=(x^2+y^2)/xy =substitute given we get 14/5=2 4/5
answer A
Answer: A
Question: Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:
Options:
A)9
B)11
C)13
D)15
E)12
Rationale: Let the three integers be x, x + 2 and x + 4.
Then, 3x = 2(x + 4) + 3 x = 11.
Third integer = x + 4 = 15.
Answer: D
Answer: D
Question: Kiran travels from A to B by car and returns from B to A by cycle in 7 hours. If he travels both ways by car he saves 3 hours. What is the time taken to cover both ways by cycle?
Options:
A)10
B)99
C)88
D)77
E)66
Rationale: Let the time taken to cover from A to B in car and cycle be x hours and y hours respectively.
x + y = 7 --- (1) ; 2x = 4 --- (2)
solving both the equations, we get y = 5
So, time taken to cover both ways by cycle = 2y hours = 10 hours.
Answer: A
Answer: A
Question: The area of a rectangle is 460 square metres. If the length is 15% more than the breadth, what is the breadth of the rectangular field?
Options:
A)20
B)27
C)26
D)188
E)11
Rationale: Explanation:
Let breadth=x meters.
Then,Length = meters
Given that,
=> x = 20
Breadth = 20
Answer: A) 20 m
Answer: A
Question: A man's speed with the current is 15 km/hr and the speed of the current is 2.5 km/hr. The man's speed against the current is?
Options:
A)10
B)20
C)50
D)30
E)40
Rationale: Man's speed with the current = 15 km/hr
=> speed of the man + speed of the current = 15 km/hr
speed of the current is 2.5 km/hr
Hence, speed of the man = 15 - 2.5 = 12.5 km/hr
man's speed against the current = speed of the man - speed of the current
= 12.5 - 2.5 = 10 km/hr
Answer is A.
Answer: A
Question: A, B, C together started a business. A invested Rs.6000 for 5 months B invested Rs.3600 for 6 months and C Rs.7500 for 3 months. If they get a total profit of Rs.7410. Find the share of A?
Options:
A)7219
B)3000
C)2799
D)2797
E)2788
Rationale: 60*5:36*6:75*3
100: 72: 75
100/247 * 7410
= 3000
Answer: B
Answer: B