divelab/Sys2Bench huggingface dataset:
Question: How long does a train 165 meters long running at the rate of 90 kmph take to cross a bridge 660 meters in length?
Options:
A)33
B)72
C)55
D)82
E)62
Rationale: Explanation:
T = (660 + 165)/90 * 18/5
T = 33
Answer: Option A
Answer: A
Question: A man can row upstream at 3km/hr and down stream at 13km/hr find mans rate in still water ?
Options:
A)2km/hr
B)4km/hr
C)6km/hr
D)8km/hr
E)10km/hr
Rationale: :	given upstream(u) =3km/hr
down stream (v)= 13km/hr rate in still water =1/2(u+v)=1/2(3+13)=8km/hr Answer is (D):8
Answer: D
Question: How many seconds will a 800 m long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
Options:
A)22
B)48
C)99
D)77
E)12
Rationale: Speed of train relative to man = 63 - 3 = 60 km/hr.
= 60 * 5/18 = 50/3 m/sec.
Time taken to pass the man = 800 * 3/50 = 48 sec.
Answer: B
Answer: B
Question: xy=1 then what is (6^(x+y)^2) / (6^(x-y)^2)
Options:
A)1296
B)4
C)8
D)16
E)32
Rationale: (x+y)^2 - (x-y)^2
(x+y+x-y)(x+y-x+y)
(2x)(2y)
4xy
4
6^4 = 1296
Answer A
Answer: A
Question: There are 10 stations between Trichy and Chennai. How many second class tickets have to be printed, so that a passenger can travel from any station to any other station?
Options:
A)133
B)132
C)134
D)135
E)136
Rationale: The total number of stations = 12
From 12 stations we have to choose any two stations and the direction of travel (i.e.,Trichy to Chennai is different from Chennai to Trichy) in 12P2 ways.
12P2= 12 * 11 = 132
ANSWER: B
Answer: B
Question: The residents of Town X participated in a survey to determine the number of hours per week each resident spent watching television. The distribution of the results of the survey had a mean of 18 hours and a standard deviation of 6 hours. The number of hours that Pat, a resident of Town X, watched television last week was between 1 and 2 standard deviations below the mean. Which of the following could be the number of hours that Pat watched television last week?
Options:
A)30
B)9
C)18
D)12
E)6
Rationale: Given: mean=18 and SD=6.
The number of hours that Pat watched television was between 1 and 2 standard deviations below the mean: 1 SD below the mean ismean-1*SD=12and 2 SD below the mean ismean-2*SD=6, so the number of hours that Pat watched television was between 6 and 12hours.
Answer: B
Answer: B
Question: If @ is a binary operation defined as the difference between an integer n and the product of n and 5, then what is the largest positive integer n such that the outcome of the binary operation of n is less than 14?
Options:
A)1
B)2
C)3
D)4
E)5
Rationale: @(n) = 5n - n
We need to find the largest positive integer such that 5n - n < 14.
Then 4n < 14 and n < 3.5.
The largest possible integer is n = 3.
The answer is C.
Answer: C
Question: The tax on a commodity is diminished by 20% and its consumption increased by 15%. The effect on revenue is?
Options:
A)6%
B)8%
C)9%
D)2%
E)1%
Rationale: 100 * 100 = 10000
80 * 115 = 9200
-----------
10000-----------800
100-----------? => 8% decrease
Answer: B
Answer: B
Question: A bird shooter was asked how many birds he had in the bag. He replied that there were all sparrows but six, all pigeons but six, and all ducks but six. How many birds he had in the bag in all?
Options:
A)9
B)18
C)27
D)36
E)42
Rationale: Explanation:
There were all sparrows but six' means that six birds were not sparrows but only pigeons and ducks.
Similarly, number of sparrows + number of ducks = 6 and number of sparrows + number of pigeons = 6.
This is possible when there are 3 sparrows, 3 pigeons and 3 ducks i.e. 9 birds in all.
Answer: Option A
Answer: A
Question: If equation |x/4| + |y/4| =2.5 encloses a certain region on the coordinate plane, what is the area of this region?
Options:
A)20
B)50
C)100
D)400
E)200
Rationale: The equation can be reduced to intercept form as |x/10| + |y/10| = 1, so these are lines in four quadrants with x and y intercept as 10, so it is a rhombus with diagonals of 20 each and hence area = 1/2*d1*d2 = 1/2*20*20 = 200. Answer E.
Answer: E
Question: The jogging track in a sports complex is 726 m in circumference. Deepak and his wife start from the same point and walk in opposite directions at 4.5 km/hr and 3.75 km/hr respectively. They will meet for the first time in?
Options:
A)4.28 min
B)3.28 min
C)5.28 min
D)6.28 min
E)7.28 min
Rationale: C
5.28 min
Clearly, the two will meet when they are 726 m apart.
To be (4.5 + 3.75) = 8.25 km apart, they take 1 hour.
To be 726 m apart, they take (100/825 * 726/1000) hrs = (242/2750 * 60) min = 5.28 min.
Answer: C
Question: An amount of Rs. 3000 becomes Rs. 3600 in four years at simple interest. If the rate of interest was 1% more, then what was be the total amount?
Options:
A)3720
B)3520
C)3456
D)3285
E)3900
Rationale: A = P(1 + TR/100)
=> 3600 = 3000[1 + (4 * R)/100] => R = 5%
Now R = 6%
=> A = 3000[1 + (4 * 6)/100] = Rs. 3720.
ANSWER A
Answer: A
Question: Six years ago, P was half of Q's age. If the ratio of their present ages is 3:4 what will be the total of their present ages?
Options:
A)33
B)67
C)29
D)21
E)35
Rationale: Let present age of P and Q be 3x3x and 4x4x respectively.
Six years ago, P was half of Q's age
â‡’(3xâˆ’6)=1/2(4xâˆ’6)
â‡’6xâˆ’12=4xâˆ’6
â‡’2x=6
â‡’x=3
Total of their present ages
=3x+4x=7x=7Ã—3=21
D
Answer: D
Question: Matt and Peter can do together a piece of work in 20 days. After they have worked together for 12 days peter stops and Peter completes the remaining work in 10 days. In how many days Matt complete the work separately.
Options:
A)28
B)27
C)26
D)25
E)29
Rationale: Together they complete the job in 20 days means they complete 12/20 of the job after 12 days.
Peter completes the remaining (8/20) of the job in 10 days which means that the whole job(1) can be completed in X days.
<=> 8/20->10 <=> X=10/(8/20)=25
D
Answer: D
Question: A train which is 180m long which is having a speed of 62kph is passing a guy who is walking in the same direction of trains motion with a speed of 3kph. How long it will take the train to pass the guy(in seconds)?
Options:
A)9.38
B)10.98
C)11.32
D)14.25
E)15.16
Rationale: Relative speed of train with respect to guy=62-3=59kph=16.39m/s
Time taken by the train to pass the guy=180/16.39=10.98s
Answer:B
Answer: B
Question: A truck covers a distance of 200 metres in 1 minute whereas a bus covers a distance of 100kms in 50minutes. The ratio of their speeds is?
Options:
A)2:3
B)1:5
C)1:10
D)9:13
E)7:15
Rationale: Ratio of speeds = (200/60) 18/5 : 60*100/50 = 12:120 = 1:10
Answer is C
Answer: C
Question: A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?
Options:
A)2
B)3 METRE
C)5
D)6
E)7
Rationale: Area of the park = (60 x 40) m2 = 2400 m2.
Area of the lawn = 2109 m2.
Area of the crossroads = (2400 - 2109) m2 = 291 m2.
Let the width of the road be x metres. Then,
60x + 40x - x2 = 291
x2 - 100x + 291 = 0
(x - 97)(x - 3) = 0
x = 3.
B)
Answer: B
Question: The product X of two prime numbers is between 17 and 100. If one of the prime numbers is greater than 2 but less than 6 and the other is greater than 13 but less than 25, then X =
Options:
A)18
B)29
C)37
D)44
E)95
Rationale: Option BC can be ruled out as they themselves are prime numbers
18 = 2*9 = 3*6 >> Ignore
44 = 2 * 22 = 4 * 11 >> Ignore
51 = 5*19 >> Answer
Answer = E
Answer: E
Question: A can do a particular work in 6 days . B can do the same work in 8 days. A and B signed to do it for Rs. 3200. They completed the work in 3 days with the help of C. How much is to be paid to C?
Options:
A)Rs. 380
B)Rs. 600
C)Rs. 420
D)Rs. 400
E)Rs. 450
Rationale: Explanation :
Amount of work A can do in 1 day = 1/6
Amount of work B can do in 1 day = 1/8
Amount of work A + B can do in 1 day = 1/6 + 1/8 = 7/24
Amount of work A + B + C can do = 1/3
Amount of work C can do in 1 day = 1/3 - 7/24 = 1/24
work A can do in 1 day: work B can do in 1 day: work C can do in 1 day
= 1/6 : 1/8 : 1/24 = 4 : 3 : 1
Amount to be paid to C = 3200 Ã— (1/8) = 400
Answer IS D
Answer: D
Question: 15.06 * 0.0001 = ?
Options:
A)15060000
B)0.001506
C)0.01506
D)0.1506
E)None of these
Rationale: Explanation:
Clearly after decimal 6 digits should be there.
Option B
Answer: B
Question: Running at the same constant rate, 6 identical machines can produce a total of 270 bottles per minute. At this rate, how many bottles could 10 such machines produce in 4 minutes?
Options:
A)648
B)1800
C)2700
D)10800
E)948
Rationale: Let the required number of bottles be x.
More machines, More bottles (Direct Proportion)
More minutes, More bottles (Direct Proportion)
Machines 6	:	10 :: 270 : x
Time (in minutes) 1	:	4
Therefore, 6 x 1 x x = 10 x 4 x 270
=> x =(10 x 4 x 270) / (6)
=> x = 1800.
Correct answer is B.
Answer: B
Question: A 300 m long train crosses a platform in 33 sec while it crosses a signal pole in 18 sec. What is the length of the platform?
Options:
A)288
B)350
C)889
D)276
E)250
Rationale: Speed = 300/18 = 50/3 m/sec.
Let the length of the platform be x meters.
Then, (x + 300)/33 = 50/3
3x + 900 = 1650 => x = 250 m.
Answer:E
Answer: E
Question: Mr. Jones sold two pipes at $1.20 each. Based on the cost, his profit one was 20% and his loss on the other was 20%. On the sale of the pipes, he
Options:
A)broke even
B)lost 4 cents
C)gained 4 cents
D)lost 10 cents
E)gained 10 cents
Rationale: Solution:
20 % profit on $ 1.20
= $ 20/100 × 1.20
= $ 0.20 × 1.20
= $ 0.24
Similarly, 20 % loss on $ 1.20
= $ 20/100 × 1.20
= $ 0.20 × 1.20
= $ 0.24
Therefore, in one pipe his profit is $ 0.24 and in the other pipe his loss is $ 0.24.
Since both profit and loss amount is same so, it’s broke even.
Answer: (a)
Answer: A
Question: The ratio of two quantities is 2 to 5. If each of the quantities is increased by 7, what is the ratio of these two new quantities?
Options:
A)2/5
B)5/8
C)7/13
D)22/25
E)It cannot be determined from the information given.
Rationale: Correct Answer: E
Let x and y be the two quantities such that x/y = 2/5. There is no algebraic operation that can be used to increase x and y each by 3 and determine what happens to the ratio 2/5.
For example, if x = 2 and y = 5, then (x+7)/(y+7) = (2+7)/(5+7) = 9/12 =3/4. However, if x = 4 and y = 10 (which would still set x/y = 2/5), then (x+3)/(y+3) = (4+7)/(10+7) = 11/17. The ratio of the two new quantities cannot be uniquely determined from the information given, and the correct answer is (E).
Answer: E
Question: A car travels at a speed of 55 miles per hour. How far will it travel in 5 hours?
Options:
A)425 miles
B)625 miles
C)325 miles
D)225 miles
E)275 miles
Rationale: During each hour, the car travels 55 miles. For 5 hours it will travel
55 + 55 + 55 + 55 + 55 = 5 *55 = 275 miles correct answer E
Answer: E
Question: Two cars P and Q start at the same time from A and B which are 120 km apart. If the two cars travel in opposite directions, they meet after one hour and if they travel in same direction (from A towards B), then P meets Q after 6 hours. What is the speed of car P?
Options:
A)75 km/hr
B)71 km/hr
C)72 km/hr
D)70 km/hr
E)78 km/hr
Rationale: D
70 km/hr
Let their speed be x km/hr and y km/he respectively.
Then, 120/(x + y) = 1 => x + y = 120 --- (i)
Now, when they move in same direction:
(Distance traveled by P in 6 hrs) - (Distance traveled by Q in 6 hrs) = 120 km
6x - 6y = 120 => x - y = 20 --- (ii)
Sloving (i) and (ii), we get x = 70, y = 50
P's speed = 70 km/hr.
Answer: D
Question: In the floor of a particular kitchen owned by an abstract artist, each row of tiles to the right of the first row contains two fewer tiles than the row directly to its left. If there are nine rows in all and a total of 270 tiles in the floor, how many tiles does the leftmost row contain?
Options:
A)38
B)56
C)60
D)64
E)68
Rationale: This question can be solved in a variety of ways: with algebra, by TESTing THE ANSWERS and by using a great Number Property shortcut involving consecutive integers.
We're given a few facts to work with:
1) There are 9 rows of tiles.
2) When going from 'left to right', each row contains TWO FEWER tiles than the one next to it.
3) There are a total of 270 tiles
We're asked how many tiles the left-most most row holds (meaning the one with the MOST tiles).
To start, 270 is divisible by 9, so we can figure out the AVERAGE number of tiles per row. That is 270/9 = 30. Since we're dealing with a set of 9 consecutive integers that differ by 2 each, we know that the '5th row' will have 30 tiles (the average). Then we just have to 'add 2s' until we get to the first row...
30 +2 +2 +2 +2 = 38.
Final Answer:
A
Answer: A
Question: The ratio of 2 numbers is 3:7 and their H.C.F. is 12. Their L.C.M. is ?
Options:
A)20
B)24
C)252
D)136
E)160
Rationale: Let the numbers be 3x and 7x
Their H.C.F. = 3
so the numbers are 3*12 , 7*12 = 36,84
L.C.M. = 252
Answer is C
Answer: C
Question: Given that 4.21 x 10(power 4), Which of the following options is equal to it?
Options:
A)72100
B)42100
C)42200
D)32100
E)41100
Rationale: = 4.21 x 10(power 4)
= 4.21 x 10000
= 42100.
Answer is B.
Answer: B
Question: A group consists of 4 men, 6 women and 5 children. In how many ways can 2 men , 3 women and 1 child selected from the given group?
Options:
A)450
B)600
C)390
D)830
E)984
Rationale: Two men, three women and one child can be selected in ⁴C₂ * ⁶C₃ * ⁵C₁ ways
= (4 * 3)/(2 * 1) * (6 * 5 * 4)/(3 * 2) * 5
= 600 ways.
Answer:B
Answer: B
Question: A man starts walking at 3 pm . he walks at a speed of 4 km/hr on level ground and at a speed of 3 km/hr on uphill , 6 km/hr downhill and then 4 km/hr on level ground to reach home at 9 pm. What is the distance covered on one way?
Options:
A)12
B)66
C)77
D)88
E)91
Rationale: lets us consider t1 = time taken on level road. t2 = uphill. t3 = down hill; the distance traveled uphill and down hill same so t2*3 = 6*t3; => t2 = 2t3;---> (1) total time = 2*t1 + t2 + t3 = 6 hours ---> (2) 2t1+3t3 = 6 -->(3) total distance = 2*(4t1) + 3*t2+ 6*t3 ---> (4) substitute (1) in (4) 8t1 + 12t3 => 4(2t1+3t3) then from (3) the total distance will become 4*6= 24 => one way distance = 12km
Answer: A
Answer: A
Question: The length of the bridge, which a train 135 m long and traveling at 45 km/hr can cross in 30 sec is?
Options:
A)235
B)240
C)245
D)250
E)255
Rationale: Speed = 45 * 5/18 = 25/2 m/sec.
Time = 30 sec
Let the length of bridge be x meters.
Then, (135 + x)/30 = 25/2
x = 240 m.
Answer: Option B
Answer: B
Question: How many integers Q are prime numbers in the range 200 < Q < 220?
Options:
A) 1
B) 2
C) 3
D) 4
E) 5
Rationale: My friend, every single odd number greater than can be written either as 4Q+1 or as 4Q+3. If you divide any odd number by 4, you will get a remainder of either 1 or 3. That's not a rule unique to prime numbers at all.
The 6Q+1 or 6Q-1 rule is basically every odd number that is not divisible by three, so it narrows the search a little.
Here's how I thought about the problem. First, eliminate all the even numbers and the odd multiples of 5 in that range. That leaves us with:
{201, 203, 207, 209, 211, 213, 217, 219}
Eliminate the four multiples of 3. Notice that 21 is a multiple of 3, so 210 is also a multiple of 3. If we add or subtract 3 or 9, we get more multiples of three. When we eliminate those, we are left with.
{203, 209, 211, 217}
Now, notice that a cool thing about this range is that 210 is also a multiple 7 (again, because 21 is a multiple of 7). This means that
210 - 7 = 203
210 + 7 = 217
Those two numbers are also multiples of 7, so eliminate them from the list. Now, we are left with
{209, 211}.
We've already checked all the prime numbers less than 10, so we know that neither of these numbers is divisible by anything less than 10. We have to check 11 now. We know that 22 is a multiple of 11, so 220 is also a multiple of 11. This means that
220 - 11 = 209
is also a multiple of 11. We can eliminate this from the list also.
That leaves us with just 211. There's no zero option in the question, so this must be a prime number.
Answer = (A)
Answer: A
Question: If the cost price of 12 pens is equal to the selling price of 8 pens, the gain percent is:
Options:
A)80%
B)90%
C)50%
D)40%
E)10%
Rationale: Explanation:
Let C.P. of each pen be Re. 1.
Then, C.P. of 8 pens = Rs. 8; S.P. of 8 pens = Rs. 12.
Gain % = 4/8 * 100 = 50%
Answer:C
Answer: C
Question: A trader sold an article at a loss of 5% but when he increased the selling price by Rs.65 he gained 3.33% on the cost price. If he sells the same article at Rs. 936, what is the profit percentage?
Options:
A)23
B)22
C)20
D)28
E)11
Rationale: Explanation:
103.33 CP- 0.95 CP = 65
inline \Rightarrow CP = Rs. 780
profit (%) = \inline \frac{936-780}{780}\times 100 = 20%
Answer: C) 20%
Answer: C
Question: Machine A produces pencils at a constant rate of 9000 pencils per hour, and machine B produces pencils at a constant rate of 7000 pencils per hour. If the two machines to gather must produce 100,000 pencils and if each machine can operate for at most 8 hours, what is the least amount of time W, in hours, that machine B must operate?
Options:
A)4
B)4 2/3
C)5 1/3
D)6
E)6 1/4
Rationale: Machine A produces pencils at a constant rate of 9,000 pencils per hour, and machine B produces pencils at a constant rate of 7,000 pencils per hour. If the two machines together must produce 100,000 pencils and if each machine can operate for at most 8 hours, what is the least amount of time W, in hours, that machine B must operate?
a) 4
b) 4 and 2/3
c) 5 and 1/3
d) 6
e) 6 and 1/4
To minimize the time that machine B must operate we must maximize the time machine A can operate, so make it operate 8 hours. In 8 hours machine A will produce 8*9,000=72,000 pencils, so 100,000-72,000=28,000 pencils are left to produce, which can be produced by machine B in 28,000/7,000=4 hours.
Answer: A.
Answer: A
Question: A clock loses 5 min for every hour and another gains 5 min for every hour. If they are set correct at 10 am on Monday then when will they be 12 hrs apart ?
Options:
A)10 am on Thursday
B)10 am on Friday
C)10 am on Saturday
D)None of the above
E)Cannot be determined
Rationale: Explanation :
For every hour watch A loses 5 min and watch B gains 5 min.
So for every hour they will differ by 10 min.
For 12 hrs (720 min) difference between them the time required = 720 / 10 = 72 hrs
So they will be 12 hrs apart after 3 days i.e., at 10 am on Thursday.
Answer : A
Answer: A
Question: Find the number of shares that can be bought for Rs.8200 if the market value is Rs.25 each with brokerage being 2.5%.
Options:
A)237
B)320
C)177
D)166
E)111
Rationale: Explanation:
Cost of each share = (25 + 2.5% of 25) = Rs.25.625
Therefore, number of shares = 8200/25.625 = 320
ANSWER:B
Answer: B
Question: The bankerâ€™s gain on a sum due 3 years hence at 12% per annum is Rs. 90. The bankerâ€™s discount is
Options:
A)Rs.340
B)Rs.840
C)Rs.1020
D)Rs.760
E)None
Rationale: Solution
T.D	=(B.G x 100 / R x T)
= Rs.(90x100/12 x 3)
= Rs.250.
B.D
=Rs(250+ 90)
= Rs.340.
Answer A
Answer: A
Question: What is the value of 18^2 + 19^2 + 20^2 + 21^2 + 22^2 ?
Options:
A)2010
B)2012
C)2016
D)2028
E)2058
Rationale: This is what I did, all the nos are close to 20, and squared, so 20^2 plus there are 5 numbers, so (20)^2 x 5 =2000,
now squaring the last digits of each no individually comes up to (4+1+0+1+4) = 10.
when you add the 2 up it gives you a (2000+10) =2010,
Answer is A
Answer: A
Question: If the price of 23 toys is 276, then what will the price of 12 toys ?
Options:
A)144
B)148
C)156
D)186
E)176
Rationale: Explanation:
Less toys, Less Price (Direct Proportion)
So, let the price be Rs. x
then,
23:12::276:x=>x=276∗12 /23
=>x=144
So price of 12 toys will be Rs. 144
Option A
Answer: A
Question: If a man buys 60 lollipops for $150 and sold them for $2 dollars each determine his loss.
Options:
A)$ 28
B)$ 35
C)$ 52
D)$ 30
E)$ 12
Rationale: Cost of 60 lollipops = $150
Sold each lollipop for $2
So he sold 20 lollipops for $(60 × 2) = $120
Loss = $(150 – 120) = $30
Therefore, loss = $ 30.
Answer:D
Answer: D
Question: Let f(x,y) be defined as the remainder when (x–y)! is divided by x. If x=50, what is the maximum value of y for which f(x,y)=0?
Options:
A)35
B)36
C)40
D)42
E)45
Rationale: The question is finding y such that (50-y)! is a multiple of 50. That means we need to have 2*5^2 in (50-y)!
10! is the smallest factorial number with 2*5^2 as a factor.
50-y = 10
y = 40
The answer is C.
Answer: C
Question: The speed of a car is 90 km in the first hour and 60 km in the second hour. What is the average speed of the car?
Options:
A)76 kmph
B)75 kmph
C)87 kmph
D)56 kmph
E)86 kmph
Rationale: S = (90 + 60)/2
= 75 kmph
Answer: B
Answer: B
Question: Two trains, each 100 meters long, moving in opposite directions, completely pass each other in 12 seconds. If one train is moving twice as fast the other, then what is the speed of the faster train (in km/hr)?
Options:
A)36 km/hr
B)40 km/hr
C)44 km/hr
D)48 km/hr
E)52 km/hr
Rationale: Let the speed of the slower train be x m/s
Then, the speed of the faster train is 2x m/s
The relative speed is 3x m/s
(100 + 100)/12 = 3x
x = 50/9
So, the speed of the faster train is 100/9 = 100/9 * 18/5 = 40 km/hr
The answer is B.
Answer: B
Question: In a school of 700 students, 45% wear blue shirts, 23% wear red shirts, 15% wear green shirts, and the remaining students wear other colors. How many students wear other colors (not blue, not red, not green)?
Options:
A)109
B)119
C)129
D)139
E)149
Rationale: 45 + 23 + 15 = 83%
100 – 83 = 17%
700 * 17/100 = 119
The answer is B.
Answer: B
Question: How many multiples of 7 are there between 21 and 343, inclusive ?
Options:
A)48
B)47
C)46
D)45
E)44
Rationale: 7 * 3 = 21
7 * 49 = 343
Total multiples = (49-3) + 1 = 47
Include 21 and 343 = 47
Answer is B
Answer: B
Question: Rs. 7800 is divided into three parts A, B and C. How much A is more than C if their ratio is 1/2:1/3:1/4?
Options:
A)1878
B)1878
C)1999
D)1800
E)1900
Rationale: 1/2:1/3:1/4
= 6:4:3
3/13*7800
= 1800
Answer: D
Answer: D
Question: Two numbers are in the ratio 1:2, if 7 is added to both, their ratio changes to 3:5. The greatest number is
Options:
A)28
B)30
C)32
D)36
E)40
Rationale: Let the numbers be x and 2x
Then, (x+7)/(2x+7)=3/5
X=14
There fore answer is 28
ANSWER A
Answer: A
Question: If P/2 = Q/3 = R/4 then find P:Q:R
Options:
A)1:2:3
B)2:5:7
C)6:4:9
D)5:7:2
E)2:3:4
Rationale: Let P/2 = Q/3 = R/4 = K
P = 2K
Q = 3K
R = 4K
P:Q:R = 2:3:4
Answer is E
Answer: E
Question: A train 125 m long passes a man, running at 3 km/hr in the same direction in which the train is going, in 10 sec. The speed of the train is?
Options:
A)40
B)50
C)60
D)79
E)48
Rationale: Speed of the train relative to man = 125/10 = 25/2 m/sec.
= 25/2 * 18/5 = 45 km/hr
Let the speed of the train be x km/hr. Then, relative speed = (x - 3) km/hr.
x - 3 = 45 => x = 48 km/hr.
Answer: Option E
Answer: E
Question: Rs.1500 is divided into two parts such that if one part is invested at 6% and the other at 5% the whole annual interest from both the sum is Rs.85. How much was lent at 5% ?
Options:
A)500
B)287
C)288
D)122
E)101
Rationale: Let the lent at 5% be 'A'
(A x 5 x 1)/100 + [(1500 - A)x 6 x 1]/100 = 85
5A/100 + 90 – 6A/100 = 85
A/100 = 5
=> A = 500
Answer: A
Answer: A
Question: If a continuous cable 10 meters long was marked off at intervals of 1/5 meter and also 1/8 meter, and then if the cable were cut at each mark, how many different size length of cable would result?
Options:
A)1
B)2
C)3
D)4
E)5
Rationale: In this particular example length (10 meter) is just extraneous information.
The location of the marks for 1/3 meter would be 8/40, 16/40, 24/40, 32/40, 40/40, etc...
The location of the marks for 1/8 meter would be 5/40, 10/40, 15/40, 20/40, 25/40, 30/40, 35/40, 40/40, etc...
The distances between marks are 5/40, 3/40, 2/40, 1/40, and 4/40.
The answer is E.
Answer: E