divelab/Sys2Bench huggingface dataset:
Question: This topic is locked. If you want to discuss this question please re-post it in the respective forum.
Matt and Peter can do together a piece of work in 20 days. After they have worked together for 12 days Matt stops and Peter completes the remaining work in 14 days. In how many days Peter complete the work separately.
Options:
A)26 days
B)27 days
C)23 days
D)35 days
E)24 days
Rationale: Together they complete the job in 20 days means they complete 12/20 of the job after 12 days.
Peter completes the remaining (8/20) of the job in 14 days which means that the whole job(1) can be completed in X days.
<=> 8/20->14 <=> X=14/(8/20)=35Thus the answer is D.
Answer: D
Question: The average weight of 6 person's increases by 4.5 kg when a new person comes in place of one of them weighing 75 kg. What might be the weight of the new person?
Options:
A)160 kg
B)175 kg
C)180 kg
D)102 kg
E)190 kg
Rationale: Total weight increased = (6 x 4.5) kg = 27 kg.
Weight of new person = (75 + 27) kg = 102 kg
Option D
Answer: D
Question: If Aug 15th,2012 falls on Thursday then June 11th,2013 falls on which day ?
Options:
A)monday
B)saturday
C)friday
D)wednesday
E)sunday
Rationale: First,we count the number of odd days for the left over days in the given period.
Here,given period is 15.8.2012 to 11.6.2013
Aug Sept Oct Nov Dec Jan Feb Mar Apr May Jun
16 30 31 30 31 31 28 31 30 31 11(left days)
2 + 2 + 3 + 2 + 3 + 3 + 0 + 3 + 2 + 3 + 4 (odd days) = 6 odd days
So,given day Thursday + 6 = Wednesday is the required result.
Answer: D) Wednesday
Answer: D
Question: -88 × 39 + 312 = ?
Options:
A)-3200
B)3120
C)-3120
D)3200
E)3208
Rationale: -88 × 39 + 312 = -88 × (40-1) + 312
= -88 × 40 + 88 + 312
= -3520 + 88 + 312
= -3120
Answer is C
Answer: C
Question: Rob traveled a distance of 30 km, covering the first 10 km in x minutes, the next 10 km in y minutes and the last 10 km in z minutes. If he totally took 3y minutes to cover the whole distance, then which of the following cannot be true? Assume x , y and z are different.
Options:
A)z=3x
B)x=3z
C)y=2x
D)x=2y
E)y=3x
Rationale: Rob Travelled for x,y and for z min.
Total Time : x + y + z
Which is equal to : 3y
Equating both sides we get
x+y+z = 3y
=> x+z =2y ........ Eqn 1
Looking out at options
D Says x =2y
Using it in Eqn 1
2y + z = 2y
=> Z = 0 mins, Which I guess is not possible.
The Ans isD
Answer: D
Question: A certain cube floating in a bucket of water has between 75 and 85 percent of its volume below the surface of the water. If between 9 and 16 cubic centimeters of the cube's volume is above the surface of the water, then the length of a side of the cube is approximately
Options:
A)4
B)5
C)7
D)8
E)9
Rationale: If sides are 7, vol=7^3=343
75%= 257.25, 85%=291.55
so vol above water, between 85.75 and 51.45 -->too big
If side are 4, vol = 64
75%=48, 85%=54.4
vol above water between 16 and 9.6
So 4 should be the answer.
Check option C,
If sides are 5, vol = 125
75%= 93.75, .85%=106.25
vol above water between 18.75-31.25
(Sides are 4 cubic centimeters)
A
Answer: A
Question: An inspector rejects 0.08% of the meters as defective. How many will be examine to project ?
Options:
A)5500
B)7500
C)3500
D)2500
E)4500
Rationale: Let the number of meters to be examined be x.
Then, 0.08% of x =2
[(8/100)*(1/100)*x] = 2
x = [(2*100*100)/8] = 2500.
Answer is D.
Answer: D
Question: In how many ways can the letters of the word, ‘LANGUAGE’ be arranged in such a way that the vowels always come together?
Options:
A)600
B)700
C)720
D)750
E)780
Rationale: In the word ‘LANGUAGE’ we treat the vowels AUAE as one letter. Thus, we have LNGG (AUAE).
This we have 5 letters of which G occurs 2 times and the rest are different.
Number of ways arranging these letters= 5!/2! =5*4*3= 60
Now, 4 letters of which A occurs 2 times and the rest are different, can be arranged in 4!/2!
= 4*3=12.
Therefore, Required number of ways= 60*12= 720
ANSWER: C
Answer: C
Question: Out of 15 consecutive numbers, 2 are chosen at random. The probability that they are both odds or both primes is?
Options:
A)1/1
B)1/7
C)1/8
D)1/3
E)1/2
Rationale: A leap year has 52 weeks and two days
Total number of cases = 7
Number of favourable cases = 1
i.e., {Saturday, Sunday}
Required Probability = 1/7
Answer:B
Answer: B
Question: What is the difference between the compound interest on Rs.12000 at 20% p.a. for one year when compounded yearly and half yearly?
Options:
A)337
B)120
C)266
D)287
E)612
Rationale: When compounded annually, interest
= 12000[1 + 20/100]1 - 12000 = Rs.2400
When compounded semi-annually, interest
= 12000[1 + 10/100]2 - 12000 = Rs.2520
Required difference = 2520 - 2400 = Rs.120
Answer:B
Answer: B
Question: Compound interest earned on a sum for the second and the third years are Rs.2500 and Rs.2625 respectively. Find the rate of interest?
Options:
A)10% p.a.
B)5% p.a.
C)15% p.a.
D)12.5% p.a.
E)None of these.
Rationale: Rs.2625 - 2500 = Rs.125 is the interest on Rs.2500 for one year.
Rate of interest = (125/2500) * 100 = 5% p.a
ANSWER:B
Answer: B
Question: The two trains of lengths 400 m, 600 m respectively, running at same directions. The faster train can cross the slower train in 180 sec, the speed of the slower train is 48 km. then find the speed of the faster train?
Options:
A)60
B)68
C)67
D)69
E)54
Rationale: Length of the two trains = 600m + 400m
Speed of the first train = X
Speed of the second train= 48 Kmph
1000/X - 48 = 180
1000/x - 48 * 5/18 = 180
50 = 9X - 120
X = 68 Kmph
Answer: Option B
Answer: B
Question: Jimmy has 18% more cookies than Janice. What percentage of cookies should Jimmy give to Janice so that both Jimmy and Janice have the same number of cookies?
Options:
A)7.6%
B)8.5%
C)9%
D)11%
E)12.2%
Rationale: An easy way to solve this question is by number plugging. Assume Janice has 100 cookies then Jimmy has 118 cookies. Now, for both Jimmy and Janice to have equal amounts of cookies we should give Janice 9 of Jimmy's cookies, which is 9/118=~7.6% of Jimmy's cookies.
Answer: A.
Answer: A
Question: The greatest common factor of 16 and the positive integer n is 4, and the greatest common factor of n and 45 is 3. Which of the following could be the greatest common factor of n and 60?
Options:
A)3
B)30
C)40
D)42
E)70
Rationale: Greatest common factor n and 16 is 4 = 2*2 * 2*2
Greatest common factor n and 45 is 3 = 3*3 *5
Greatest common factor n and 60 is = 2*3*5 =30
Answer: B.
Answer: B
Question: Rajan mixed 24 kg of butter at Rs. 200 per kg with 36 kg butter at the rate of Rs. 150 per kg. At what price per kg should he sell the mixture to make a profit of 40% in the transaction?
Options:
A)Rs.129
B)Rs.120
C)Rs.238
D)Rs.178
E)Rs.126
Rationale: CP per kg of mixture = [24*200) + 36*150)]/(24 + 36)
= Rs. 10200/60 =Rs. 170
SP = Rs.170 + 170*40/100
= Rs.170+68
= Rs.238
Answer:C
Answer: C
Question: How many 3 – digit number can be formed from the digit 2, 3, 5, 6, 7 and 9, which are divisible by 5 and none of the digits is repeated?
Options:
A)5
B)10
C)15
D)20
E)25
Rationale: Solution
Since each desired number is divisible by 5, so we must have 5 at the unit place. So, there is 1 way of doing it.
Tens place can be filled by any of the remaining 5 numbers.
So, there are 5 ways of filling the tens place.
The hundreds place can now be filled by any of the reaming 4 digits. so, there are 4 ways of filling it.
So, Required number of numbers = (1 × 5 × 4) = 20 . Answer D
Answer: D
Question: Last year the price per share of Stock X increased by k percent and the earnings per share of Stock X increased by m percent, where k is greater than m. By what percent did the ratio of price per share to earnings per share increase, in terms of k and m?
Options:
A)k/m %
B)(k-m) %
C)[100(k-m)]/(100+k) %
D)[100(k-m)]/(100+m) %
E)[100(k-m)]/(100+k+m) %
Rationale: If old price per share = X, old Earnings per share = Y
=> Old ratio = X/Y
New price per share = X(100+k)/100, new Earnings per share = Y(100+m)/100
=>New ratio = X(100+K)/[(100+m)(Y)]
Increase in the ratios after simplifying comes to [100(k-m)]/(100+m) %
ANSWER:D
Answer: D
Question: Jamboree and GMAT Club Contest Starts
QUESTION #10:
How many words (with or without meaning)Y can be formed using all the letters of the word “SELFIE” so that the two E’s are not together?
Options:
A) 660
B) 600
C) 500
D) 300
E) 240
Rationale: In general, repetitions are taken care of by dividing the permutation by the factorial of the number of objects that are identical. in this case,Y if you think logically, A,B,C,D options are not divisible by 6!. 6 is total number of letters in the word SELFIE. Only option E is divisible by 6!. So correct answer is E that is 240
Answer: E
Question: A car is running at a speed of 80kmph. What distance will it cover in 20sec?
Options:
A)100m
B)440m
C)180m
D)200m
E)250m
Rationale: Speed = 80kmph = 80*5/18 = 22 m/s
Distance covered in 20sec = 22*10 = 440m
Answer is B
Answer: B
Question: In what time will a train 120 m long cross an electric pole, it its speed be 121 km/hr?
Options:
A)2.5
B)2.7
C)2.9
D)3.6
E)2.1
Rationale: Speed = 121 * 5/18 = 33.6 m/sec
Time taken = 120/33.6
= 3.6 sec.
Answer: D
Answer: D
Question: Average of money that group of 4 friends pay for rent each month is $800.After one persons rent is increased by 20% the new mean is $870.What was original rent of friend whose rent is increased?
Options:
A)800
B)1400
C)1000
D)1100
E)1200
Rationale: 0.2X = 4(870-800)
0.2X = 280
X = 1400
Answer B
Answer: B
Question: Find the 25% of Rs. 800.
Options:
A)s. 50
B)s. 200
C)s. 100
D)s. 80
E)s. 60
Rationale: Explanation :
25% of 800
=> 25/100 *800 = Rs. 200
Answer : B
Answer: B
Question: Find out the square of a number which when doubled exceeds its quarter by 7 ?
Options:
A)16
B)25
C)19
D)26
E)17
Rationale: A
Let the number be p, then the square will be p^2
According to question:
2p = (p/4) + 7
=> 8p = p + 28
=> p = 4
p^2 = 4^2 = 16.
Answer: A
Question: In order to fence a square Manish fixed 48 poles. If the distance between two poles, is 6 metres then what will be the area of the square so formed?
Options:
A)Cannot be determined
B)2600 cm2
C)5184 cm2
D)3025 cm2
E)None of these
Rationale: Let the side of the square be x m.
∴ Perimeter of the square = 48 × 6 = 4x ∴ x = 72 m
∴ Area = (72)2 = 5184 m2
Answer C
Answer: C
Question: A certain car dealership sells economy cars, luxury cars, and sport utility vehicles. The ratio of economy to luxury cars is 5:4. The ratio of economy cars to sport utility vehicles is 3:2. What is the ratio of luxury cars to sport utility vehicles?
Options:
A)9:8
B)8:9
C)6:5
D)2:3
E)1:2
Rationale: The ratio of economy to luxury cars is 5:4 --> E:L = 5:4 = 15:12.
The ratio of economy cars to sport utility vehicles is 3:2 --> E:S = 3:2 = 15:10.
Thus, L:S = 12:10 = 6:5.
Answer: C.
Answer: C
Question: The game of blackjack is played with a deck consisting of 13 cards (one of each of the numbers 2-10, one jack, one queen, one king, and one of ace) in each of four suits: clubs, diamonds, hearts, and spades.
In a game of blackjack, if your first card is a spade, what are the odds that it is a queen?
Options:
A)5/13
B)1/26
C)1/52
D)1/4
E)1/13
Rationale: The question should ask about the probability not the odds.
There are 13 spades, the probability that the spade we already have is a queen is therefore 1/13.
Answer:E.
Answer: E
Question: A machine can finish a work in 15days and 2nd machine can finish the work in 30days. 2nd machine worked for 10days and left the job. In how many days, A alone can finish the remaining work?
Options:
A)5days
B)6days
C)10days
D)12days
E)15days
Rationale: 2nd machine 10days work = 1/30*10 = 1/3
Remaining work = 1 - 1/3 = 2/3
now 1/15 work is done by 1st machine in 1day
2/3 work is done by 1 machine in 15*2/3 = 10days.
Answer is C
Answer: C
Question: If each interior angle of a regular polygon is 144o, the it is
Options:
A)Octagon
B)Decagon
C)Dodecagon
D)Pentagon
E)None of these
Rationale: Decagon, then each ext angle = 180-44=36 deg .
sum of all ext angles = 360 deg .
Then total ext angles = 360/36 =10 means 10 sides of polygon.
ANSWER:C
Answer: C
Question: The average age of a group of 5 members is 20 years. Two years later, a new member joins the group. The average age of the group becomes 21 years. What is the age of the new member ?
Options:
A)16 years
B)21 years
C)22 years
D)23 years
E)24 years
Rationale: The average age of the 5 members is 20 years
=> The sum of the ages of the 5 members is 20*5 = 100 years
Once the new member joins, the average age becomes 21 years.
Let the age of the new member be x.
Then (110+x)/6 = 21
=> x = 16 years
Answer A
Answer: A
Question: A reduction of 40% in the price of bananas would enable a man to obtain 64 more for Rs.40, what is reduced price per dozen?
Options:
A)1
B)2
C)4
D)3
E)5
Rationale: 40*(40/100) = 16 --- 64
? --- 12 => Rs.3
Answer: D
Answer: D
Question: If x is an integer, then x(x - 1)(x - k) must be evenly divisible by three when k is any of the following values except
Options:
A)-4
B)-8
C)-1
D)2
E)5
Rationale: if we put k=-1 we get:
X(x-1)(X+1) rearrange:(x-1)X(X+1)
so it looks like a sequenc,
if we assume that X =2 and put number from the answer then we get:
(x – 1)x(x – k)
k=5 =1.2.-3
k=2 =1.2.0
k=-1 =1.2.3
k=-4 =1.2.6
but when we put
k=-8 =1.2.10 not satisfied
so,the answer is B
Answer: B
Question: The LCM of three numbers is four times their GCF. Which of the following must be true of the numbers?
I. At least o ne of the numbers is odd.
II. Two of the three numbers must be same.
III. At least one number is the same as GCF.
Options:
A)only
B)option II only
C)and III only
D)and II only
E)I and III only
Rationale: Consider the following set: {2, 4, 8}.
GCF = 2.
LCM = 8 = 4*2.
The set discards options I and II. Only B fits.
Answer: B.
Answer: B
Question: The length of a rectangle is two - fifths of the radius of a circle. The radius of the circle is equal to the side of the square, whose area is 1225 sq.units. What is the area (in sq.units) of the rectangle if the rectangle if the breadth is 10 units?
Options:
A)140
B)99
C)88
D)72
E)12
Rationale: Given that the area of the square = 1225 sq.units
=> Side of square = √1225 = 35 units
The radius of the circle = side of the square = 35 units Length of the rectangle = 2/5 * 35 = 14 units
Given that breadth = 10 units
Area of the rectangle = lb = 14 * 10 = 140 sq.units
Answer: A
Answer: A
Question: Mr. loyd wants to fence his Square shaped land of 120Sqft each side.If a pole is laid every 10ft how many poles do he need?
Options:
A)20
B)30
C)48
D)50
E)60
Rationale: If each side is 120 feet..then total perimeter is 120*4=480
poles every 10 feet hence no of poles= 480/10=48
ANSWER:C
Answer: C
Question: A sum of money deposited at compound interest (compounded yearly) amounts to $4200 in 2 years and to $4494 in 3 years. What is the interest rate?
Options:
A)3%
B)5%
C)7%
D)9%
E)11%
Rationale: 4494 - 4200 = 294
294 / 4200 = 0.07 = 7%
The answer is C.
Answer: C
Question: The length of a rectangular plot is thrice its breadth. If the area of the rectangular plot is 675 sq m, then what is the breadth of the rectangular plot?
Options:
A)11
B)15
C)18
D)101
E)1322
Rationale: Let the breadth of the plot be b m.
Length of the plot = 3 b m
(3b)(b) = 675
3b2 = 675
b2 = 225 = 15 (b > 0)
b = 15 m.
Answer: B
Answer: B
Question: The sum an integer N and its reciprocal is equal to 78/15. What is the value of N?
Options:
A)9
B)8
C)7
D)6
E)5
Rationale: Write equation in N as follows
N + 1/N = 78/15
Multiply all terms by N, obtain a quadratic equation and solve to obtain N = 5
correct answer E
Answer: E
Question: In one hour, a boat goes 11 km/hr along the stream and 5 km/hr against the stream. The speed of the boat in still water (in km/hr) is:
Options:
A)3 km/hr
B)4 km/hr
C)5 km/hr
D)6 km/hr
E)8 km/hr
Rationale: Upstream relative speed is u + v=11km/hr
Downstream speed is u-v = 5
Where u = speed of boat in still water and v is speed of stream
Then adding two equations u+v + u-v =11+5
2u=16
Finally, u=8.
ANSWER : E
Answer: E
Question: 5% people of a village in Sri Lanka died by bombardment, 15% of the remainder left the village on account of fear. If now the population is reduced to 3553, how much was it in the beginning?
Options:
A)4402
B)4418
C)4400
D)4418
E)4412
Rationale: X * (95/100) * (85/100) = 3553
X = 4400
Answer: C
Answer: C
Question: Two airplanes take off from one airfield at noon. One flies due east at 201 miles per hour while the other flies directly northeast at 283 miles per hour. Approximately how many miles apart are the airplanes at 2 p.m.?
Options:
A)166
B)332
C)400
D)402
E)566
Rationale: D
In two hours:
the plane flying East will be 402 miles away from airport.
the other plane will be 566 miles away from airport.
566/402 = ~1.4 = ~sqrt(2)
This means that planes formed a right isocheles triangle => sides of such triangles relate as 1:1:sqrt(2) => the planes are 402 miles apart. D
Answer: D
Question: A dishonest shopkeeper professes to sell pulses at the cost price, but he uses a false weight of 950gm. for a kg.His gain is …%.
Options:
A)5.26%
B)5.36%
C)4.26%
D)6.26%
E)7.26%
Rationale: His percentage gain is 100*50/950 as he is gaining 50 units for his purchase of 950 units.
so 5.26%.
ANSWER:A
Answer: A
Question: Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 16 hours and 9 hours respectively. The ratio of their speeds is?
Options:
A)4:5
B)4:3
C)4:4
D)4:9
E)3:4
Rationale: Let us name the trains A and B.
Then, (A's speed) : (B's speed)
= √b : √a = √9 : √16 = 3:4
Answer:E
Answer: E
Question: A man can swim in still water at 4 km/h, but takes twice as long to swim upstream than downstream. The speed of the stream is?
Options:
A)1.3
B)7.5
C)2.25
D)1.5
E)4
Rationale: M = 4
S = x
DS = 4 + x
US = 4 - x
4 + x = (4 - x)2
4 + x = 8 -2x
3x = 4
x = 1.3
ANSWER:A
Answer: A
Question: A train speeds past a pole in 15 seconds and a plaƞorm 100 meter long in 25 seconds. What is length
of the train ?
Options:
A)140 meter
B)145 meter
C)150 meter
D)155 meter
E)None of these
Rationale: Explanation:
Let the length of the train is x meter and Speed of the train is y meter/second
Then x/y = 15 [because distance/speed = Ɵme]
=> y = 15/x
=>x+10025=x15x=150 meters
So length of the train is 150 meters
Answer: C
Answer: C
Question: To celebrate a colleague's retirement, the T coworkers in an office agreed to share equally the cost of a catered lunch. If the lunch costs a total of K dollars and S of the coworkers fail to pay their share, which of the following represents the additional amount, in dollars, that each of the remaining coworkers would have to contribute so that the cost of the lunch is completely paid?
Options:
A)K/T
B)K/(T-S)
C)SK/(T-S)
D)SK/T(T-S)
E)K(T-S)/T
Rationale: Since no absolute values are given in the question we can replace the given parameters with assumed numbers,
Let Total colleagues be 100 (T)
Let total contribution be 900 (K) (point to note is that its total cost not per person)
Those who dont pay are S (30)
Per person cost = K/T = 900/100 = 9
So cost for those who failed to pay = (K/T) * S = SK/T = 30*9=270
The equation for people who would bear the total cost after S people fail = (T-S)=70
There fore the solution is (SK/T)/ (T-S) = SK/T(T-S) = 270/70
Answer D
Hope this helps !!!
Answer: D
Question: Every year an amount increases by 1/8th of itself. How much will it be after two years if its present value is Rs.3200?
Options:
A)8100
B)3388
C)7767
D)4050
E)2288
Rationale: 3200* 9/8 * 9/8
= 4050
Answer: D
Answer: D
Question: From a group of 3 boys and 3 men, four are to be randomly selected. What is the probability that equal numbers of boys and men will be selected?
Options:
A)1/5
B)3/5
C)4/5
D)2/5
E)6/10
Rationale: Using the first example, here is the probability of THAT EXACT sequence occurring:
BBMM = (3/6)(2/5)(3/4)(2/3) = 36/360 = 1/10
Each of the other 5 options will yield the exact SAME probability....
eg
BMBM = (3/6)(3/5)(2/4)(2/3) = 36/360 = 1/10
So we have 6 different options that each produce a 1/10 chance of occurring.
6(1/10) = 6/10 = 3/5
Final Answer:
B
Answer: B
Question: Mohan purchased 17 kgs of rice at the rate of Rs.26 per kg and 8 kgs of pulses at the rate of Rs.26 per kg. Whaat is the total amount that he paid to the shopkeeper?
Options:
A)A)Rs.598
B)B)Rs.594
C)C)Rs.650
D)D)Rs.595
E)E)of these
Rationale: Explanation:
Price of 17 kgs of rice at Rs.26/kg = 17x26 = Rs.442
Price of 8 kgs of pulses at Rs.26/kg = 8x26 = Rs.208
Therefore, Total amount = Rs.442+Rs.208 = Rs.650.
Answer: Option C
Answer: C
Question: The operation # is defined for all nonzero w and y by w#y = w + w/y. If a>0, then 1#(1#a) =
Options:
A)a
B)a+1
C)a/(a+1)
D)(a+2)/(a+1)
E)(2a+1)/(a+1)
Rationale: w#y = w + w/y. If a>0, then 1#(1#a) =
You can see that a stands for y and 1 stands for w. I like to work with numbers so I did w=1 a=2 and a=y so y=2
1#a= 1+(1/2)=1.5 so now a is 1.5 --> 1+(1/1.5)=1 2/3 = 5/3
So now you can check by filling in a, which is 2:
A. a --> 2
B. a+1 --> 2+1=3
C. a/(a+1)-->2/(2+1)=2/3
D. (a+2)/(a+1)-->(2+2)/(2+1)=4/3
E. (2a+1)/(a+1)-->(2*2+1)/(2+1)=5/3
So E is the answer.
Answer: E
Question: A man borrowed some amount, after 3 years he paid Rs.10,400/- with 10% interest, then how much Amount he borrowed?
Options:
A)Rs.6000/-
B)Rs.6500/-
C)Rs.7000/-
D)Rs.7200/-
E)Rs.8000/-
Rationale: principal P = ?
Rate of interest R = 10%
Time T = 3 years
Accumulated Amount A = Rs.10400/-
A = P + I
A = P + PTR/100
A = P(1+ TR/100)
Rs.10400/- = P [1 + 3*10/100]
Rs.10400/- = P [1/1 + 3/10]
Rs.10400/- = P [10+3/10] = P[13/10]
Rs.10400/- = P * 13/10
==> P = Rs.104000/13
==> P = Rs.8000/-
E
Answer: E
Question: The boys ordered several pizzas for the weekend. When the first evening was over, the
following amounts of pizza were left over: 1/4 of the pepperoni pizza, 1/2 of the cheese pizza,
3/4 of the mushroom pizza and 1/4 of the supreme pizza. The next morning, each boy ate the
equivalent of 1/4 of a pizza for breakfast. If that finished the pizza, how many boys were there?
Options:
A)5
B)6
C)7
D)8
E)9
Rationale: 1/4 + 1/2 + 3/4 + 1/4 =
1/4 + 2/4 + 3/4 + 1/4 = 7/4 or 1 3/4 pizza left over
7/4 ÷ 1/4 = 7/4 x 4/1 = 7 boys
correct answer C
Answer: C
Question: Let f(x) = x^2 + bx + c. If f(1) = 0 and f(-6) = 0, then f(x) crosses the y-axis at what y-coordinate?
Options:
A)-6
B)-1
C)0
D)1
E)6
Rationale: When x = 1 and when x = -6, the expression f(x) = x² + bx + c equals 0.
Then f(x) = (x-1)(x+6)
f(0) = -6
The answer is A.
Answer: A
Question: Given that s/t < 1, and both s and t are positive integers, which one of the following must be greater than 1?
Options:
A)s/t^2
B)s^2/t
C)s^2/t^2
D)t/s
E)√(s/t)
Rationale: Since s/t is a fraction t must always be > 1
Given -
Which one of the following must be greater than 1
We can get the result one only when the denominator in s/t ( Which is less than 1 ) becomes numerator..
Among the given options only (D) has the required characteristic we are looking for...
Hence answer will be (D)
Answer: D
Question: Selling an kite for Rs. 30, a shop keeper gains 15%. During a clearance sale, the shopkeeper allows a discount of 10% on the marked price. His gain percent during the sale is?
Options:
A)3.5%
B)10%
C)11%
D)15%
E)20%
Rationale: Explanation:
Marked price = Rs. 30
C.P. = 100/115 * 30 = Rs. 26.08
Sale price = 90% of Rs. 30 = Rs. 27
Required gain % = 0.92/26.08 * 100 = 3.5%.
Answer: A
Answer: A
Question: The sum of the ages of 5 children born at the intervals of 2 years each is 50 years. what is the age of the youngest child ?
Options:
A)6
B)18
C)10
D)99
E)38
Rationale: Let x = the youngest child. Each of the other four children will then be x+2, x+4, x+6, x+8.
We know that the sum of their ages is 50 .
so, x+(x+2)+(x+4)+(x+6)+(x+8) = 50
therefore The youngest child is 6 years old
Answer: A
Answer: A