divelab/Sys2Bench huggingface dataset:
Question: A certain sum amount to $1400 in 2 yrs and $2000 in five years on certain fixed simple interest. In how many yrs would the amount be $1640 had it been put at the rate of interest compounded annually?
Options:
A)4.5
B)3.5
C)3
D)2
E)1.5
Rationale: We can form equations as following:
Initial amount = P, Total amount after interest = T, Interest per year = I
T = P+I
Given T1 = P+2I = 1400T2 = P+ 5I = 2000
From this we get, P = 1000I = 200 $
Now we know that simple interest is<Compound interest ( CI = SI only after 1st year if CI is compounded annually)
consider simple interest - after 1st yer it is 200$ , after 2nd years it is 400$ and after 3rd year it is 600$.
To get a 240 $ compound interest the duration have to be > 1 year and < 2 years.
Only option fitting : Option E.
Answer: E
Question: Three numbers are in the ratio 4 : 5 : 6 and their average is 20 . The largest number is:
Options:
A)24
B)32
C)36
D)42
E)45
Rationale: Explanation:
Let the numbers be 4x, 5x and 6x. Therefore,
(4x+5x+6x)/3 = 20
15x = 60
x = 4
Largest number = 6x = 24.
ANSWER A
Answer: A
Question: P has $42 more than what Q and R together would have had if both B and C had 1/8 of what P has. How much does P have?
Options:
A)$44
B)$48
C)$52
D)$56
E)$60
Rationale: P = (2/8)*P+42
(6/8)*P=42
P=56
The answer is D.
Answer: D
Question: Carl drove from his home to the beach at an average speed of 80 kilometers per hour and returned home by the same route at an average speed of 70 kilometers per hour. If the trip home took 1/2 hour longer than the trip to the beach, how many kilometers k did Carl drive each way?
Options:
A) 350
B) 345
C) 320
D) 280
E) 240
Rationale: Let us backsolve here.
The answer option has to be divisible by 7 to give us 1/2.
Let us try k=280 km. Time taken will be 3.5 hours and 4 hours.
Hence D is the answer.
Answer: D
Question: 3/4 of 1/2 of 2/5 of 5040 = ?
Options:
A)392
B)229
C)756
D)493
E)540
Rationale: C
756
? = 5040 * (2/5) * (1/2) * (3/4) = 756
Answer: C
Question: If a2 + b2 + c2 = 250 and ab + bc + ca = 3, then a + b + c is
Options:
A)4
B)8
C)16
D)32
E)64
Rationale: by formula ,
(a + b + c)^2= a^2 + b^2 + c^2 + 2(ab + bc + ca),
since, a^2 + b^2 + c^2 = 250 and ab + bc + ca = 3,
(a + b + c)^2 = 250 + 2(3)
= 256
= 16^2
therefore: a + b + c = 16
ANSWER:C
Answer: C
Question: which of the following could be the perimeter of the triangle?If two sides of a triangle have lengths 6 and 12.
I. 30
II. 25
III. 18
Options:
A)I only
B)II only
C)II and III only
D)none
E)I, II, and III
Rationale: The length of any side of a triangle must be larger than the positive difference of the other two sides, but smaller than the sum of the other two sides.
Therefore:
(12-6) < {third side} < (12+6).
6< {third side} < 18.
Perimeter = {third side} + 6 + 18= {third side} + 24.
30< {perimeter} < 42
Answer: D.
Answer: D
Question: In what time will a railway train 120 m long moving at the rate of 70 kmph pass a telegraph post on its way?
Options:
A)3 sec
B)4 sec
C)5 sec
D)6 sec
E)7 sec
Rationale: T = 120/70 * 18/5 = 6 sec
ANSWER:D
Answer: D
Question: If n = 3^6 – 2^6 which of the following is NOT a factor of n?
Options:
A)97
B)7
C)35
D)5
E)19
Rationale: 3^6 - 2^6
= (3^3)^2 - (2^3)^2
=(3^3 + 2^3)(3^3 - 2^3)
=(27+8)(27-8)
=35*19
=7*5*19
Therefore, 97 is Not a factor of n.
A
Answer: A
Question: Timothy leaves home for school, riding his bicycle at a rate of 9 miles per hour. Fifteen minutes after he leaves, his mother sees Timothy’s math homework lying on his bed and immediately leaves home to bring it to him. If his mother drives at 30 miles per hour, how far (in terms of miles) must she drive before she reaches Timothy?
I think is a 700 level problem but I tag it as 600/700, let me know. Either way I hope in an explanationThanks
Options:
A)1/3
B)3
C)4
D)45/14
E)12
Rationale: In 15 mins, Timothy travels=9/4 miles.
Now, let his mother takes x hours to reach him, traveling at 30mph.
So, 30x=9x+9/4
x=3/28 hrs.
Thus, the distance traveled by his mother to reach= 30*3/28=45/14 miles. Ans D
Answer: D
Question: The average age of students of a class is 15.8 years. The average age of boys in the class is 16.3 years and that of the girls is 15.4 years. The ration of the number of boys to the number of girls in the class is:
Options:
A)2:5
B)2:3
C)2:4
D)4:5
E)2:9
Rationale: Let the ratio be k : 1. Then,
k * 16.3 + 1 * 15.4 = (k + 1) * 15.8
= (16.3 - 15.8)k = (15.8 - 15.4)
= k = 0.4/0.5 = 4/5
Required ratio = 4/5 : 1 = 4:5.
Answer:D
Answer: D
Question: 3 candidates in an election and received 2500, 5000 and 20000 votes respectively. What % of the total votes did the winningcandidate got in that election?
Options:
A)72.72%
B)50%
C)57.57%
D)60%
E)65%
Rationale: Total number of votes polled = (2500 + 5000 + 20000) = 27500
So, Required percentage = 20000/27500 * 100 = 72.72%
A
Answer: A
Question: The volume of a cube is 729 cc. Find its surface.
Options:
A)864
B)444
C)456
D)486
E)422
Rationale: a3 = 729 => a = 96a2 = 6 * 9 * 9 = 486Answer: D
Answer: D
Question: If (x/y)=(6/5), find the value (x^2+y^2)/(x^2-y^2)
Options:
A)61/11
B)51/11
C)41/11
D)21/11
E)None of them
Rationale: = (x^2+y^2)/(x^2-y^2) = ( x^2 /y^2+ 1)/ ( x^2 /y^2-1) = [(6/5)^2+1] / [(6/5)^2-1]
= [(36/25)+1] / [(36/25)-1] = (61*25)/(25*11) = 61/11
Answer is A.
Answer: A
Question: Find the sum and number of divisors of 544 excluding 1 and 544.
Options:
A)587
B)588
C)589
D)590
E)591
Rationale: if N = p^a * q^b *r^c *...
total no. of factors of N = (a+1)*(b+1)*(c+1)*... &
sum of all of the factors of N =(1+p+p^2+...+p^a)*(1+q+..+q^b)*(1+r+r^2+...+r^c)
544 = 2^5 * 17
number of divisors of 544 excluding 1 and 544 = (5+1)*(1+1) - 2 = 10
sum of divisors of 544 excluding 1 and 544 = (1+2+2^2+2^3+2^4+2^5)*(1+17)-1-544
= 589
ANSWER:C
Answer: C
Question: The sale price of an article including the sales tax is $ 616. The rate of sales tax is 10%. If the shopkeeper has made a profit of 12%, then the cost price of the article is:
Options:
A)$700
B)$800
C)$500
D)$300
E)$400
Rationale: C
$500
110% of S.P. = 616
S.P. = (616 * 100)/110 = $ 560
C.P = (110 * 560)/112 = $ 500
Answer: C
Question: A is 1.5 times as fast as B. A alone can do the work in 20 days. If A and B working together , in how many days will the work be completed?
Options:
A)23
B)22
C)12
D)24
E)25
Rationale: A can finish 1 work in 20 days
B can finish 1/1.5 work in 20 days - since A is 1.5 faster than B
This means
B can finish 1 work in 20*1.5 days = 30 days
Now using the awesome GMAT formula when two machines work together they can finish the job in = AB/ (A+B) = 20*30/(20+30) = 20*30/50 = 12 days
So answer is C
Answer: C
Question: A marble statue is being carved by a sculptor. In the first week 35% is cut away, in the second week 20% of the remainder is cut away and in the third week 25% of the remainder is cut away and polished to produce the final statue. The weight of the final statue is 48.75 lbs. What was the weight of the original piece of marble?
Options:
A)134
B)167
C)125
D)113
E)111
Rationale: C
lb : reverse the calculations:
So 48.75 ÷ 0.75 = 65,
65 ÷ 0.8 = 81.25 and
81.25 ÷ 0.65 = 125.
Answer: C
Question: It takes 30 days to fill a laboratory dish with bacteria. If the size of the bacteria doubles each day, how long did it take for the bacteria to fill one quarter of the dish?
Options:
A)10 days
B)14 days
C)24 days
D)28 days
E)29 days
Rationale: The bacteria doubles each day, so after 29 days, the dish was half full.
After 28 days, the dish was one quarter full.
The answer is D.
Answer: D
Question: If log x + log y = log (x+y), then,
Options:
A)x=y
B)xy=1
C)y= (x-1)/x
D)y=x/(x-1)
E)y=1/(x-1)
Rationale: log x + log y = log (x+y)
=> log (x+y) = log (xy)
=> x+y = xy => y(x-1) = x
=> y= x/(x-1)
ANSWER:D
Answer: D
Question: From the sale of sleeping bags, a retailer made a gross profit of 16% of the wholesale cost. If each sleeping bag was sold for $28, what was the wholesale cost per bag?
Options:
A)3.0
B)3.36
C)24.13
D)25.0
E)31.36
Rationale: Cost price * 1.16 = Selling price --> Cost price * 1.16 = $28 --> Cost price = $24.13.
Answer: C.
Answer: C
Question: In a colony of 70 residents, the ratio of the number of men and women is 4 : 3. Among the women, the ratio of the educated to the uneducated is 1 : 4. If the ratio of the number of educated to uneducated persons is 8 : 27, then find the ratio of the number of educated to uneducated men in the colony?
Options:
A)1:6
B)1:1
C)1:8
D)1:9
E)1:3
Rationale: Number of men in the colony = 4/7 * 70 = 40.
Number of women in the colony = 3/7 * 70 = 40.
Number educated women in the colony = 1/5 * 30 = 6.
Number of uneducated women in the colony = 4/5 * 50 = 24.
Number of educated persons in the colony = 8 /35 * 70 = 16.
As 6 females are educated, remaining 10 educated persons must be men.
Number of uneducated men in the colony = 40 - 10 = 30.
Number of educated men and uneducated men are in the ratio 10 : 30 i.e., 1:3.
Answer:E
Answer: E
Question: What is the smallest number which when diminished by 24, is divisible 5, 10, 15 and 20?
Options:
A)276
B)84
C)88
D)90
E)342
Rationale: Required Number
= (LCM of 5, 10, 15 and 20) + 24
= 60 + 24 = 84
Option B
Answer: B
Question: If 35 people play hockey and 10 people play both football and hockey and if 10 people play hockey and cricket and 5 people play all three games then the number of people playing hockey alone is?
Options:
A)10
B)15
C)20
D)25
E)30
Rationale: hockey =35 (given)
hockey , cricket , football = 5(given)
hockey , cricket = 10(given)
hockey , football = 10(given)
only hockey = 35 - 5(h,c,f)-5(h,c (10-5)) -5(h,f(10-5))=35-5-5-5=20
ANSWER:C
Answer: C
Question: A man cycles round the boundary of a rectangular park at the rate of 12 kmph and completes one full round in 8 minutes. If the ratio between the length and breadth of the park be 3:2, then its area is:
Options:
A)1536m2
B)15360m2
C)153600m2
D)163600m2
E)None of these
Rationale: Perimeter= Distance covered in 8 min
= (12000/60 *8)m= 1600m
Let, length= 3x meters and breadth= 2x meters
Then, 2(3x+2x)= 1600 or x= 160
Therefore, length= 480 m and breadth= 320m
Therefore, area= (480*320)m2 = 153600 m2
ANSWER:C
Answer: C
Question: At a circular table for twelve will sit ten adults and two small children. The two children will sit next to each other, and the two parents of the children will sit next to the children so that there is one parent on each side of the two children. If rotating their positions around the table is not considered changing the arrangement, in how many different ways can the twelve people be arranged around the table.
Options:
A)116,120
B)124,480
C)132,720
D)142,240
E)161,280
Rationale: Consider the two parents and two children as one unit.
Then there are eight adults and one family unit.
The number of ways 9 can form a line is 9!
Around a circular table, there would be 9 rotations so we divide this number by 9.
There are 8! ways for 9 to sit around the circular table.
Then the two children have two options and the two parents have two options.
Then the total number of ways is 8!*2*2= 161,280
The answer is E.
Answer: E
Question: The present ages of three persons in proportions 2 : 8 : 6. Eight years ago, the sum of their ages was 56. Find their present ages (in years).
Options:
A)10, 40, 30
B)16, 28, 36
C)16, 28, 35
D)16, 28, 34
E)16, 28, 33
Rationale: Let their present ages be 2x, 8x and 6x years respectively.
Then, (2x - 8) + (8x - 8) + (6x - 8) = 56
16x = 80
x = 5.
Their present ages are 2x = 10 years, 8x = 40 years and 6x = 30 years respectively.
Answer:A
Answer: A
Question: There are 20 poles with a constant distance between each pole. A car takes 26 second to reach the 12th pole. How much will it take to reach the last pole.
Options:
A)44.4543
B)44.9091
C)44.95128
D)44.91288
E)44.91222
Rationale: Assuming the car starts at the first pole.
To reach the 12th pole, the car need to travel 11 poles (the first pole doesn't count, as the car is already there).
11 poles 26 seconds
1 pole (26/11) seconds
To reach the last (20th) pole, the car needs to travel 19 poles.
19 pole 19 x (26/11) seconds
= 44.9091 seconds
Answer:B
Answer: B
Question: If x is a positive integer, and two sides of a certain triangle have lengths x and y respectively, where x is greater than y, which of the following could be the length of the third side of the triangle?
I. AB < x + y
II. AB > x - y
III. AB < y - x
Options:
A)I only
B)II only
C)I and II only
D)II and III only
E)I, II and III
Rationale: Let the third side of triangle be AB
Triangle rule states that:
Difference of other 2 sides < any side < sum of other two sides
So x - y < AB < x + y
I. AB < x + y ; could be a possible value.
II. AB > x - y ; could be a possible value.
III. AB < y - x ; could not be a possible value.
Answer: C
Answer: C
Question: A train covers a distance of 100km in 1 hour. If its speed is decreased by 12km/hr, the time taken by the car to cover the same distance will be?
Options:
A)1hr
B)1hr 8min
C)50min
D)1hr 30min
E)1hr 45min
Rationale: Speed = 100/1 = 100km/hr
New speed = 100-12 = 88 km/hr
Time taken = 100/88 = 1hr 8min
Answer is B
Answer: B
Question: Jane makes toy bears. When she works with an assistant, she makes 60 percent more bears per week and works 10 percent fewer hours each week. Having an assistant increases Jane’s output of toy bears per hour by what percent?
Options:
A)70%
B)80%
C)100%
D)180%
E)200%
Rationale: We can use fractional equivalents here to solve the problem
80% = 4/5; this means that in 1st case if she prepares 5 bears, in 2nd case she prepares 9 bears
10% = 1/10; this means that in 1st case if she needs 10 hours, in 2nd case she needs 9 hours
Now we come to productivity
Based on above fractional values the productivity in 1st case is 0.5 bears / hour and in the 2nd case it is 1 bear / hour
Hence the productivity is double with the assistant i.e. the increase in productivity is 70%
A
Answer: A
Question: A certain car dealership sells economy cars, luxury cars, and sport utility vehicles. The ratio of economy to luxury cars is 3:4. The ratio of economy cars to sport utility vehicles is 4:3. What is the ratio of luxury cars to sport utility vehicles?
Options:
A)9:8
B)8:9
C)3:2
D)2:3
E)16:9
Rationale: The ratio of economy to luxury cars is 3:4 --> E:L = 3:4 = 12:16.
The ratio of economy cars to sport utility vehicles is 4:3 --> E:S = 4:3 = 12:9.
Thus, L:S = 16:9.
Answer: E.
Answer: E
Question: If a certain number X is divided by 82, the reminder is 5. what is the reminder when X+17 is divided by 41?
Options:
A)3
B)5
C)6
D)22
E)18
Rationale: X can be written as 82K + 5 or X = 5,87,169,etc.
X + 17 = 82K + 5+17= 82K +22 or X + 17 = 22,104, 186 etc.
When divided by 41, we will get the remainder 22.
D
Answer: D
Question: When p is divided by 9, the remainder is 4. All of the following are possible values of p, except for which of the following?
Options:
A)13
B)31
C)49
D)54
E)67
Rationale: If a number is divisible by 9, the sum of its digits must be divisible by 9. --> If a number leaves a remainder 4 when divided by 9 the sum of its digits must be 4.
54
Answer: D
Answer: D
Question: A man covers a certain distance A in a train. If the train moved 4km/hr faster, it would take 30 min less. If it moved 2km/hr slower, it would take 20 mins more. Find the distance?
Options:
A)200 km
B)50 km
C)20 km
D)60 km
E)80 km
Rationale: Not really. When you solve the 2 equation above, you get,
6T-4/3 = 5R/6 from simplifying equation 1
4T-2=R/2 from simplifying equation 2
You can now multiply equation 2 by 5 to get
5(4T-2=R/2 ) = 20T-10=5R/2 and then subtract this new equation from equation 1 to get T=3, followed by R=20 to give you distance A= R*T=20*3=60 km.D
Answer: D
Question: The present worth of a sum due sometimes hence is Rs.5760 and the banker's gain is Rs.10. What is the true discount?
Options:
A)Rs. 480
B)Rs. 420
C)Rs. 120
D)Rs. 240
E)None of these
Rationale: TD = √PW × BG
=√5760×10
=√57600
= Rs. 240
ANSWER:D
Answer: D
Question: How much time will take for an amount of Rs. 150 to yield Rs. 81 as interest at 4.5% per annum of simple interest?
Options:
A)7
B)4
C)5
D)12
E)2
Rationale: Time = (100 * 81) / (150 * 4.5) = 12 years'
Answer:D
Answer: D
Question: A can do a piece of work in 30 days. He works at it for 5 days and then B finishes it in 20 days. In what time can A and B together it?
Options:
A)13 1/7 days
B)13 1/3 days
C)13 2/3 days
D)13 1/7 days
E)13 3/3 days
Rationale: 5/30 + 20/x = 1
x = 24
1/30 + 1/24 = 3/40
40/3 = 13 1/3 days
Answer:B
Answer: B
Question: The price for a loaf of bread in April was $1.14, in May the price was $1.35, and in June the price was $1.05. If 2/3 as much bread was sold in April as in May, and twice as much was sold in June as in April, what was the average price for a loaf of bread sold during the three-month period?
Options:
A)$1.13
B)$1.14
C)$1.15
D)$1.16
E)$1.17
Rationale: Let x be the number of loaves sold in May.
Then 2x/3 loaves were sold in April and 4x/3 loaves were sold in June.
The average price was (2x/3)(114) + 135x + (4x/3)(105) / (2x/3 + x + 4x/3) =
(76 + 135 + 140) / (3) = 351/3 = $1.17
The answer is E.
Answer: E
Question: ¹⁵/₇₁, ⁴¹/₇₁, ⁶²/₇₁ etc. are like/unlike fractions
Options:
A)unlike fraction
B)like fraction
C)both
D)none
E)Can't determined
Rationale: Fractions having the same denominators are called like fractions.
denominators of all fractions are 71 so like fraction
ANSWER :B
Answer: B
Question: The Pinedale bus line travels at an average speed of 60 km/h, and has stops every 5 minutes along its route. Yahya wants to go from his house to the Pinedale Mall, which is 7 stops away. How far away, in kilometers, is Pinedale Mall away from Yahya's house?
Options:
A)20 km
B)35 km
C)40 km
D)50 km
E)60 km
Rationale: Number of stops in an hour: 60/5 = 12
Distance between stops: 60/12 = 5 km
Distance between Yahya's house and Pinedale Mall: 5 x 7 = 35 km
IMO, correct answer is "B."
Answer: B
Question: 12 different biology books and 8 different chemistry books lie on a shelf. In how many ways can a student pick 2 books of each type?
Options:
A)80
B)160
C)720
D)1600
E)1848
Rationale: No. of ways of picking 2 biology books(from 12 books) = 12C2 = (12*11)/2 = 66
No. of ways of picking 2 chemistry books(from 8 books) = 8c2 = (8*7)/2 = 28
Total ways of picking 2 books of each type = 66*28 =1848
(Option E)
Answer: E
Question: If the average (arithmetic mean) of five consecutive negative integers is 2k – 1, what is the difference Q between the greatest and least of the five integers?
Options:
A)4K
B)4k^2 -4k
C)4-4k
D)4
E)4k+4
Rationale: (n-2 + n - 1 + n + n + 1 + n + 2)/5 = 2k - 1
=> n = 10k - 5
Greatest = n + 2 = 10k - 5 + 2 = 10k - 3
Least = n - 2 = 10k - 5 - 2
=> Difference Q= 10k - 3 - (10k - 7)
= 4
Answer - D
Answer: D
Question: There are 5 boys and 3 girls. In how many ways can they be seated in a row so that all the three girls do not sit together?
Options:
A)24000
B)36000
C)54200
D)32560
E)45100
Rationale: Total number of persons = 5+3 = 8
they can be seated in a row in 8! ways
Treat 3 girls as 1 so we have 6 people can be arranged in 6! ways
Three girls can be arranged among themselves in 3! ways
Required number of ways = 8!-6!*3! = 36000
Answer is B
Answer: B
Question: Adams's internet provider offers unlimited traffic which costs $0.5 per day charged off at 12 a.m. The service is discontinued when client's debt exceeds $5. If today in the morning Adams makes a payment of $7, for how many days, including today, will she be connected to the internet without any additional payments, given her initial balance was $0?
Options:
A) 15
B) 24
C) 25
D) 26
E) 13
Rationale: day 0- payment of $7 is made in the morning (after 12 am midnight)
day 1 onwards(after 12 am midnight) internet service will begin and will run for 7*2=14 days i.e. at the end of day 15 balance will be zero.
now Adams can still use the internet till her debt reaches $5 which means total of 5*2=10 days.
now the question states for how many days, including today, will she be connected to the internet without any additional paymentsi.e. we will have to include day0 also in our final answer. therefore total no. of days =1+14+10=25=C
Answer: C
Question: subash can copy 50 pages in 10 hrs.subash and prakash together can copy 300 pages in 40 hours.in how much time prakash can copy 18 pages.
Options:
A)8
B)10
C)2
D)14
E)16
Rationale: subhas 's 1 hr copy page=50/10=5 page
(subhas+prakash)'s 1 hr copy page=300/40=7.5 page
from above prakash's 1 hr copy page= 2.5 page
so time taken in 30 page's copy =(5/2.5)=2 hrs
ANSWER:C
Answer: C
Question: If cost of sugar increases by 10%. How much percent consumption of sugar should be decreased in order to keep expenditure fixed?
Options:
A)22%
B)50%
C)20%
D)9.1%
E)30%
Rationale: 100
110
-----
110 ----- 10
100 ------ ? => 9.1%
Answer: D
Answer: D
Question: The volumes of two cones are in the ratio 1 : 10 and the radii of the cones are in the ratio of 1 : 2. What is the length of the wire?
Options:
A)2:5
B)2:7
C)2:2
D)2:1
E)2:9
Rationale: The volume of the cone = (1/3)πr2h
Only radius (r) and height (h) are varying.
Hence, (1/3)π may be ignored.
V1/V2 = r12h1/r22h2 => 1/10 = (1)2h1/(2)2h2
=> h1/h2 = 2/5
i.e. h1 : h2 = 2 : 5
Answer: A
Answer: A
Question: What annual installment will discharge a debt of Rs. 1260 due in 3 years at 12% simple interest?
Options:
A)315
B)345
C)325
D)375
E)None of them
Rationale: Let each Installment be Rs. x
Then, ( x+ ((x*12*1)/100)) + (x+ ((x*12*2)/100) ) + x = 1260
=((28x/25) + (31x/25) + x) = 1260 ïƒ› (28x+31x+25x)=(1260*25)
x= (1260*25)/84 = Rs.375.
Therefore,	Each installment = Rs. 375.
Answer is D.
Answer: D
Question: (7.5 × 7.5 + 37.5 + 2.5 × 2.5) is equal to :
Options:
A)30
B)60
C)80
D)100
E)None of these
Rationale: Solution
Given expression = (7.5 × 7.5 + 2 × 7.5 × 2.5 + 2.5 × 2.5)
=(a 2 + 2ab + b 2) = (a + b)2 = (7.5 + 2.5)2 = 102 = 100 . Answer D
Answer: D
Question: x = y - (20/y), where x and y are both > 0. If the value of y is doubled in the equation above, the value of x will
Options:
A)decrease
B)stay the same
C)increase four fold
D)double
E)triples
Rationale: Alternate approach
Plug in some values of y > 0
Let y = 10
So, x = y - (20/y)
Or, x = 10 - (20/10) =8
Let y = 20
So, x = y - (20/y)
Or, x = 20 - (20/20) =19
So, x increases from 8 to 19
Hence the number increases 2.2 times, thus the correct answer will be (D)
Answer: D
Question: The area of a square is equal to five times the area of a rectangle of dimensions 25 cm * 5 cm. What is the perimeter of the square?
Options:
A)100
B)800
C)500
D)600
E)700
Rationale: Area of the square = s * s = 5(25 * 5)
=> s = 25 cm
Perimeter of the square = 4 * 25 = 100 cm.
Answer: Option A
Answer: A
Question: If 75 percent of a class answered the first question on a certain test correctly, 45 percent answered the second question on the test correctly, and 20 percent answered neither of the questions correctly, what percent answered both correctly?
Options:
A)10%
B)(8) 40%
C)30%
D)50%
E)65%
Rationale: I didn't understand how to connect 20 percent with the whole equation.
Why 20 is out of the percentile diagram (circles) but inside of 100?
20% appeared in the exam; however did not answer Question AQuestion B correctly
So they are out of the two circles, however as they have appeared in the exam, they have to be taken into consideration for calculation purpose
I am doing it this way:
Suppose the total class size is 100, then 20 percent of the class answered incorrectly and rest 80 percent answered correctly in question 1 or 2 or both.
Now,
100 - [(75 - x) + x + (45 - x)] = 20 .......... values are in percent
x = 20 - 100 + 120
x = 40
Ans: B
Answer: B
Question: A sum of money deposited at C.I. amounts to Rs.9000 in 10 years and to Rs.9990 in 11 years. Find the rate percent?
Options:
A)9%
B)10%
C)11%
D)12%
E)13%
Rationale: 9000 --- 990
100 --- ? => 11%
Answer: C
Answer: C
Question: In a kilometer race, A beats B by 25 meters or 10 seconds. What time does A take to complete the race?
Options:
A)180 sec
B)190 sec
C)290 sec
D)490 sec
E)390 sec
Rationale: Time taken by B run 1000 meters = (1000 * 10)/25
= 400 sec.
Time taken by A = 400 - 10
= 390 sec.
Answer:E
Answer: E
Question: What is the most powerful tool used by the Reserve Bank of India to control inflation?
Options:
A)FDS
B)Reduce interest rates
C)Raise interest rates
D)Raise current supply
E)Reduce current supply
Rationale: Explanation:
No explanation is available for this question!
ANSWER:C
Answer: C