divelab/Sys2Bench huggingface dataset:
Question: The bus that travels from St. Louis to Chicago and back comes to St. Louis every 2 hours while the bus that travels from St. Louis to Springfield and back comes to St. Louis every 5 hours. If at 06:00 o'clock both bused arrived at St. Louis, at what time will they meet in St. Louis again?
Options:
A)16:00.
B)18:00.
C)20:00.
D)22:00.
E)24:00.
Rationale: Time taken by bus to travel from St. Louis to Chicago and back comes to St. Louis = 2 hours
Time taken by bus to travel from St. Louis to Springfield and back comes to St. Louis = 5 hours
Time taken by both buses to meet again in St. Louis will be LCM of 2 and 5 = 10
If the buses start at 06:00 o'clock from St. Louis , they will meet again in St. Louis at 16:00 hours
Answer A
Answer: A
Question: A woman buys a soccer ball for rs.9.00 and sells it for rs.12.00. Find her gain %.
Options:
A)36.33%
B)9%
C)33.33%
D)24%
E)12%
Rationale: sol. cp=rs 9.00, sp=rs 12.00
gain=rs(12.00 –9.00)=rs 3.00
so gain%={(3.00/9.00)*100}=33.33%
Answer is C.
Answer: C
Question: Which of the following is equal to 3^k*5^(k-1)?
Options:
A)3*15^(k-1)
B)5*10^(k-1)
C)15^k
D)3*15^k
E)15^(2k-1)
Rationale: 3^k*5^(k-1) = 3*3^(k-1)*5^(k-1) = 3*15^(k-1)
The answer is A.
Answer: A
Question: A train running at 7/11 of its own speed reached a place in 22 hours. How much time could be saved if the train would have run at its own speed?
Options:
A)4hrs
B)6hrs
C)8hrs
D)9hrs
E)11hrs
Rationale: New speed = 7/11 of usual speed
New time = 11/7 of usual time
11/7 of usual time = 22 hrs
Usual time = 22*7/11 = 14 hrs
Time saved = 22-44 = 8 hrs
Answer is C
Answer: C
Question: Jake, Lena, Fred, John and Inna need to drive home from a corporate reception in an SUV that can seat 6 people. If only Inna or Jake can drive, how many seat allocations are possible?
Options:
A)30
B)42
C)120
D)240
E)720
Rationale: 5 people ,6 seats, only 2 can drive
if inna is in one seat remaining, 4 people can be arranged in 4p4 i.e 4! =24 ways
since any one can drive total ways = 24 *2= 48 ways
4 seats can be chosen out of remaining 5 seats in 5c4 ways = 5!/(3!*2!)= 5 ways
48*5=240
D
Answer: D
Question: Point (j,k) is on the circle represented by j^2+k^2=10, and j, k are integers. How many such points are possible?
Options:
A)0
B)2
C)4
D)6
E)8
Rationale: j^2+k^2=10 and k, k are integers means that 10 is the sum of two perfect squares.
10 is the sum of only one pair of perfect squares 1 and 9.
So, there can be 8 such points, 4 in each quadrant:
(1, 3);
(1, -3);
(-1, 3);
(-1, -3);
(3, 1);
(3, -1);
(-3, 1);
(-3, -1).
Answer: E.
Answer: E
Question: In a company with 48 employees, some part-time and some full-time, exactly (1/3) of the part-time employees and (1/4) of the full-time employees take the subway to work. What is the greatest possible number R of employees who take the subway to work?
Options:
A)12
B)13
C)14
D)15
E)16
Rationale: P/3 + F/4 = P/3 + (48-P)/4 = 12 + P/2
P/3 + F/3 = (P+F)/3 = 48/3 = 16
P/4 + F/4 = 12
P/3 + F/3 > P/3 + F/4 > P/4 + F/4
--> 16> 12 + P/12 > 12
GREATEST Possible R: 12 + p/12 = 15 --> p = 36 ( integer --> good)
15 or D is the answer
Answer: D
Question: An entrepreneurship competition requires registering teams to have 3 team members, at least one of which must be a technology co-founder. If all team members must come from the auditorium during the meet and greet event which has 4 technologists and 4 businessmen, how many possible team submissions are possible?
Options:
A)52
B)100
C)162
D)198
E)202
Rationale: We have 3 scenarios here:
1) 1 tech2 businessmen: 4C1 x 4C2 =24
2) 2 tech1 businessman: 4C2 x 4C1 = 24
3) 3 tech0 businessmen: 4C3 = 4
Total:24+24+4 = 52
Answer: A
Answer: A
Question: Dan can fill Q cans of water in 7 minutes. If there are R cans of water in one gallon, how many gallons can Dan fill in 42 minutes?
Options:
A)6QR
B)6R/Q
C)6Q/R
D)7Q/R
E)7R/Q
Rationale: Dan can fill this number of cans in 42 minutes: (42/7)Q = 6Q.
One can is 1/R gallons.
Dan can fill 6Q*(1/R) = 6Q/R gallons of water in 42 minutes.
The answer is C.
Answer: C
Question: Running at the same constant rate, 15 identical machines can produce a total of 45 bags per minute. At this rate, how many bags could 150 such machines produce in 8 minutes?
Options:
A) 9,00
B) 1,800
C) 2,700
D) 3,600
E) 4,800
Rationale: Let's take the approach that uses the answer choices to eliminate wasted time.
45/15 = 3 bags per minute per machine. 150 machines = 450 per minute. 8 minutes worth = 3600 bags.
Looking at the answers it is clear...we can only choose (D).
THE CORRECT ANSWER IS D.
Answer: D
Question: Given that N=a^3*b^4*c^5 where a, b and c are distinct prime numbers, what is the smallest number with which N should be multiplied such that it becomes a perfect square, a perfect cube as well as a perfect fifth power?
Options:
A)a^3*b^4*c^5
B)a^5*b^4*c^3
C)a^2*b^3*c^5
D)a^7*b^6*c^5
E)a^27*b^26*c^25
Rationale: The powers of a, b and c have to be divisible by 2, 3 and 5 for N to be a perfect square, perfect cube and perfect 5th power.
LCM of 2, 3 and 5 is 30
The smallest integer N = (a^30)(b^30)(c^30)
Answer: E
Answer: E
Question: According to the directions on a packet of smoothie mix, 1 3-ounce packet of smoothie mix is to be combined with 12 ounces of water to make a smoothie. How many 3-ounce packets of smoothie mix are required to prepare 120 12-ounce smoothies?
Options:
A) 120
B) 150
C) 180
D) 240
E) 600
Rationale: This question wasn't particularly grueling, but I think it's the first where I had the opportunity to solve it via theory andinspectionthat many on this board suggest as strategy on the GMAT. It actually came to me by accident. Basically, if we thought that the 3 packets of powder were included in the 12 ounces of water, that would mean we would need 150 packets of smoothie mix (along with 12(150) ounces of water for a total of 150 packets. However, we know, after a more careful reading of the stimulus, that the 3 ounces are NOT included in the 12 ounces. As such, the answer has to be LESS than 150 packets, since 150 would be too much powder considering you already have 150(12) ounces of water and need less packets than water to make a smoothie. As such, the only answer less than 150 is 120, A. Does this make sense? Or am I way off base?
D
Answer: D
Question: Find the cost of fencing around a circular field of diameter 22 m at the rate of Rs.3 a meter?
Options:
A)288
B)132
C)772
D)207.3
E)261
Rationale: 2 * 22/7 * 11 = 69.1
69.1 * 3 = Rs.207.3
Answer: D
Answer: D
Question: In a sequence, each term is obtained by adding 5 to the preceding one. If the sum of the first 20 terms is equal to 350, what is the result of the addition of the first 30 terms?
Options:
A)1100
B)1175
C)1270
D)1275
E)1280
Rationale: a is first term and d = 5 since the preceding number is always greater than the previous one..
Now 20th term is a+19(5).
Sum of n terms is n/2(first term + last term)and here we have to get sum of 20 terms , we get 20/2 ( a + a+95) = 350 ( given sum of 20 terms is 300)
=> 10(2a+95) = 350
=> 2a+95 = 35
=> a = -30
Now to get sum of first 30 terms , we need to get 30th term value i.e. -30+29(5) = 115.
Sum of first 30 terms = 30/2( -30 + 115) =1275 .
Hence option D is correct answer..
Answer: D
Question: Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 25 seconds. The ratio of their speeds is?
Options:
A)3/1
B)4/1
C)3/3
D)3/5
E)5/2
Rationale: Let the speeds of the two trains be x m/sec and y m/sec respectively. Then, length of the first train
= 27 x meters, and length of the second train
= 17 y meters. (27 x + 17 y) / (x + y) = 25 ==> 27 x + 17 y = 25 x + 25 y
==> 2 x = 8 y ==> x/y
= 4/1.
Answer:B
Answer: B
Question: The price of lunch for 15 people was $210.00, including a 15 percent gratuity for service. What was the average price per person, EXCLUDING the gratuity?
Options:
A) $11.73
B) $12.72
C) $13.80
D) $14.00
E) $15.87
Rationale: Take the initial price before the gratuity is 100
The gratuity is calculated on the final price, so as we assumed the final bill before adding gratuity is 100 so gratuity is 15% of 100 is 15 so the total price of meals is 115 so the given amount i.e 210 is for 115 then we have to calculate for 100
for 115 210
for 100 x
so by cross multiplication we get 115x=100*210 => x=100*210/110 by simplifying we get x as 190.90 which is the price of lunch before gratuity so the gratuity is 19.10 so
as the question ask the average price person excluding gratuity is 190.90/15=12.72 so our answer is B)
Answer: B
Question: Solve for x
if (log2)(1-x/2)=x-2.
Options:
A)1
B)2
C)3
D)4
E)5
Rationale: (log2)(1-x/2)=x-2
or,log2-(x/2)log2=x-2
or,2log2-xlog2=2x-4
or,log4+4=2x+xlog2
or,4.60=2.3x i.e.x=2.
ANSWER:B
Answer: B
Question: A man buys an article and sells it at a profit of 20%. If he had bought it at 20% less and sold it for Rs.85 less, he could have gained 25%. What is the cost price?
Options:
A)s.370
B)s.375
C)s.425
D)s.350
E)s.300
Rationale: CP1 = 100 SP1 = 120
CP2 = 80 SP2 = 80 * (125/100) = 100
20 ----- 100
85 ----- ? => 425
ANSWER:C
Answer: C
Question: In a certain company, a third of the workers do not have a retirement plan. 10% of the workers who do not have a retirement plan are women, and 40% of the workers who do have a retirement plan are men. If 120 of the workers of that company are men, how many of the workers are women?
Options:
A)80
B)95
C)105
D)120
E)91
Rationale: 20% of the workerswithoutretirement plan are women, this means 80% of the workerswithoutretirement plan are men right? Makes 100% = no retirement plan.
Then 40% of those wo have a retirement plan are men, which means 60% of those who have a retirement plan are women. These percentages are always refering to the subgroupsRetirement plan = YesandNo Retirement Plan.
Make the total workers equal x and work from there and it should be fine > x/3 have no retirement plan at all. I struggled with the question a lot, it was hard for me although usually I have no problems with sets questions like this. I believe it must be a 700+ question.
Yes, you are right. I read the question incorrectly! I glazed overnotfor some reason.
If20% of the workers who do not have a retirement plan are women,80% who do not have retirement plan are men. Also 40% who do have retirement plan are men. Since 1/3 do not have retirement plan and 2/3 do have, it becomes a simple weighted average question.
Cavg = (90*1 + 40*2)/3 = 170/3% are men
Total = 120*300/170 = 211
No. of women = 211 - 120 = 91
E
Answer: E
Question: Rs 50000 is divided into two parts One part is given to a person with 10% interest and another part is given to a person with 20 % interest. At the end of first year he gets profit 7000 Find money given by 10%?
Options:
A)30000
B)40000
C)50000
D)60000
E)70000
Rationale: let first parrt is x and second part is y then x+y=50000----------eq1
total profit=profit on x +profit on y
7000=(x*10*1)/100 + (y*20*1)/100
70000=x+2y-----------------------------------eq2
70000=50000+y
so y=20000 then x =50000-20000=30000
first part =30000
ANSWER:A
Answer: A
Question: Out of first 20 natural numbers, one number is selected at random. The probability that it is either an even number or a prime number is?
Options:
A)17/65
B)17/29
C)17/21
D)17/20
E)17/212
Rationale: n(S) = 20
n(Even no) = 10 = n(E)
n(Prime no) = 8 = n(P)
P(EᴜP) = 10/20 + 8/20 - 1/20 = 17/20.Answer:D
Answer: D
Question: Two years ago, Arthur gave each of his five children 20 percent of his fortune to invest in any way they saw Fit. In the first year, three of the children, Alice, Bob, and Carol, each earned a profit of 50 percent on their Investments, while two of the children, Dave and Errol, lost 40 percent on their investments. In the second Year, Alice and Bob each earned a 10 percent profit, Carol lost 60 percent, Dave earned 75 percent in profit, And Errol lost all the money he had remaining. What percentage of Arthur's fortune currently remains?
Options:
A)93%
B)97%
C)100%
D)107%
E)99%
Rationale: Say Arthur's fortune was $100. Then:
A = 20*1.5*1.1 = 33
B = 20*1.5*1.1 = 33
C = 20*1.5*0.4 = 12
D = 20*0.6*1.75 = 21
E = 0
Total 33 + 33 + 12 + 21 = 99.
Answer: E.
Answer: E
Question: A dishonest grocer professes to sell pure butter at cost price, but he mixes it with adulterated fat and thereby gains 15%. Find the percentage of adulterated fat in the mixture assuming that adulterated fat is freely available?
Options:
A)20%
B)25%
C)33.33%
D)40%
E)15%
Rationale: Say 100g pure butter costs $100
But; $100 is his 25% profit because he just used 80gram pure butter.
80g would have costed him $80 and he sold it for $100 by adding 20g of freely available fat. $100 is 1.15(85)
so;
total weight=100g
fat=15g
15%
E
Answer: E
Question: Jack and Jill are marathon runners. Jack can finish a marathon (40 km) in 4.5 hours and Jill can run a marathon in 4.0 hours.What is the ratio of their average running speed? (Jack: Jill)
Options:
A)14/15
B)15/14
C)8/9
D)5/4
E)Cannot be determined
Rationale: Average Speed of Jack =Distance/ Time
= 40 /(9/2) = 80/9
Average Speed of Jill = 40/(4.0) = 10
Ratio of Average speed of Jack to Jill = (80/9)/10 = 8/9
Answer C
Answer: C
Question: A train sets off at 2 p.m. at the speed of 60 kmph. Another train starts at 3:30 p.m. in the same direction at the rate of 70 kmph. At what time the trains will meet?
Options:
A)0.37 p.m
B)0.20 p.m
C)0.30 a.m.
D)0.38 p.m
E)0.10 p.m
Rationale: D = 60 * 1 Â½ = 90 km
RS = 70 â€“60 = 10
T = 90/10 = 9 h
3.30 + 9 h = 0.30 a.m.
Answer: C
Answer: C
Question: In a certain math department, students are required to enroll in either Calculus or Trigonometry, each of which is offered in beginner and advanced courses. The number of students enrolled in Trigonometry is 50% greater than the number of students enrolled in Calculus, and 90% of Calculus students are enrolled in the beginner course. If 4/5 of students are in the beginner courses, and one student is selected at random, what is the probability that an advanced Trigonometry student is selected?
Options:
A)12%
B)16%
C)20%
D)24%
E)40%
Rationale: Let x be the number of students in calculus.
Then the number of students in trigonometry is 1.5x
The number of students on beginner calculus is 0.9x
The number of students in beginner trigonometry is 4/5*(2.5x) - 0.9x = 1.1x
The number of students in advanced trigonometry is 0.4x
The percentage in advanced trigonometry is 0.4x / 2.5x = 16%
The answer is B.
Answer: B
Question: A father said to his son, "I was as old as you are at present at the time of your birth." If the father's age is 38 years now, the son's age seven years back was?
Options:
A)12yr
B)15yr
C)20yr
D)25yr
E)30yr
Rationale: Let the son's present age be x years
Then, 38-x = x
x = 19
Son's age 7 years back = 19-7 = 12 years
Answer is A
Answer: A
Question: A store owner estimates that the average price of type A products will increase by 35% next year and that the price of type B products will increase by 20% next year. This year, the total amount aid for type A products was $3500 and the total price paid for type B products was $6300. According to the store owner's estimate, and assuming the number of products purchased next year remains the same as that of this year, how much will be spent for both products next year?
Options:
A)$14,755
B)$15,325
C)$16,000
D)$12,285
E)$17,155
Rationale: cost of type A products next year = 1.35 * 3500 = 4725
cost of type B products next year = 1.2 * 6300 = 7560
total 4725 + 7560 = 12285
ANSWER:D
Answer: D
Question: Of 70 players on a football team, 52 are throwers. The rest of the team is divided so one third are left- handed and the rest are right handed. Assuming that all throwers are right handed, how many right- handed players are there total?
Options:
A)54
B)59
C)63
D)64
E)92
Rationale: Total = 70
Thrower = 52
Rest = 70 - 52 = 18
Left Handed = 18/3 = 6
Right handed = 12
If all Thrower are right handed then total right handed is 52 + 12 = 64
so D. 64 is the right answer
Answer: D
Question: If a(a + 2) = 35 and b(b + 2) = 35, where a ≠ b, then a + b =
Options:
A)-5
B)-6
C)-7
D)-2
E)-10
Rationale: i.e. if a = 5 then b = -7
or if a = -7 then b = 5
But in each case a+b = 5-7 = -2
Answer: D
Answer: D
Question: Two trains run in opposite directions on a circular track. Train A travels at a rate of 4π miles per hour and Train B runs at a rate of 6π miles per hour. If the track has a radius of 6 miles and the trains both start from Point W at the same time, how long, in hours, after the trains depart will they again meet at Point W?
Options:
A)3
B)6
C)9
D)18
E)22
Rationale: I don't agree with your solutions, first. And second the answer choices don't seem to contain the right answer.
My solution is as follows, and I ask anyone to correct me if I am wrong.
Solution 1
Let the distance covered by train A be X, thus that covered by the train B will be 12*3.14-X
dA = X dB = 12*3.14 - X
Times taken by A and B are
tA= X/4*3.14 , tB = (12*3.14 - X)/6*3.14 (ii)
Since they have been traveling for the same period of time, then
X/4*3.14 = (12*3.14 - X)/6*3.14
X/2 =(12*3.14 -X)/3
3X = 2(12*3.14 -X)
5X = 24*3.14
X = 24*3.14/5
Plugging that in either equation of (ii) yields t = 6/5
Solution 2
We add the speed of A and B: totalSpeed W= 4*3.14 + 6*3.14 = 10*3.14
Total distance covered = 12*3.14
t ime = distance / speed = 12*3.14/10*3.14 = 6/5.
tA =( X/4*3.14) =(24*3.14/5)/4*3.14 = 6/5=B
Answer: B
Question: In what time will a train 100 m long cross an electric pole, it its speed be 90 km/hr?
Options:
A)2.5
B)2.9
C)4 sec
D)2.8
E)2.1
Rationale: Speed = 90 * 5/18 = 25 m/sec
Time taken = 100/25
= 4 sec.
Answer:C
Answer: C
Question: The total circumference of two circles is 80. If the first circle has a circumference that is exactly twice the circumference of the second circle, then what is the approximate sum of their two radii?
Options:
A)5.7
B)6.0
C)10.6
D)9.7
E)18.0
Rationale: Let r= Radius of smaller circle. Let R = Radius of larger circle
Therefore:
2πr + 2πR = 80
where 2r = R
Thus:
2πr + 4πr = 80
6πr = 80
r = approx 4.2
πR + 2Rπ = 80
3πR = 80
R = approx 8.4
r + R = approx 10.6
Answer is C
Answer: C
Question: Which of the following equations has a root in common with x^2−3x+2=0 ?
Options:
A)x^2-2x+1=0
B)x^2-2x-1=0
C)x^2-x+1=0
D)x^2-3x+3=0
E)x^2-7x=0
Rationale: If we carefully look at the given equation we can arrange it in the following manner:
(x-1)(x-2)= 0
so the two roots are 1 and 2.
Now put 1 and 2 in given equations. The equation in which one of them gives value 0, that will be our answer.
(A) putting 1: we get 0. This is the equation.
We are lucky. No need to check other options.
A is the answer.
Answer: A
Question: Three different containers contain 496 litres, 403 litres and 713 litres of mixtures of milk and water respectively. What biggest measure can measure all the different quantities exactly ?
Options:
A)30 litres
B)31 litres
C)32 litres
D)33 litres
E)34 litres
Rationale: 403)713(1
403
---------
310)403(1
310
----------
93)310(3
279
--------
31)93(3
93
-------
X
so answer is 31 litres......
ANSWER:B
Answer: B
Question: Find the missing number. 1, 4, 9, 16, 25, 36, 49, (....)
Options:
A)64
B)54
C)56
D)81
E)85
Rationale: Explanation :
The series is 1^2, 2^2, 3^2, 4^2, 5^2, 6^2, 7^2,
Hence, next term = 8^2 = 64
Answer : Option A
Answer: A
Question: A rabbit on a controlled diet is fed daily 300 grams of a mixture of two foods, food X and food Y. Food X contains 10% protein and food Y contains 15% protein. If the rabbit's diet provides exactly 36 grams of protein daily, how many grams of food X are in the mixture.
Options:
A)120
B)140
C)150
D)160
E)180
Rationale: Let x be the amount of food X.
0.1x + 0.15(300-x) = 36
0.05x = 9
x = 180
The answer is E.
Answer: E
Question: When positive integer m is divided by positive integer x, the reminder is 7 and when positive integer n is divided by positive integer y, the reminder is 11. Which of the following E is a possible value for x + y?
I. 18
II. 19
III. 20
Options:
A)I only
B)II only
C)E=III only
D)II and III only
E)None
Rationale: TIP FOR SUCH QUESTIONS:Make Algebraic Equation in the beginning to understand how to proceed further. Then Start thinking the possible values of variables asked about
i.e.When positive integer m is divided by positive integer x, the reminder is 7can be understood as
m = ax +7which means thevalue of x must be greater than 7as the remainder 7 is possible only when the Divisor is bigger than the Remainder 7
i.e. Min Value of x = 8
AND
i.e.When positive integer n is divided by positive integer y, the reminder is 11can be understood as
n = by +11which means thevalue of y must be greater than 11as the remainder 11 is possible only when the Divisor is bigger than the Remainder 11
i.e. Min Value of y = 12
i.e. Minimum Value of x+y = 8+12 = 20
Hence III only can be True
Answer: Option
C
Answer: C
Question: 96% of the population of a village is 23040. The total population of the village is?
Options:
A)29992
B)24000
C)26892
D)29991
E)29878
Rationale: X * (96/100) = 23040
X = 240 * 100
X = 24000
Answer: B
Answer: B
Question: The average age of 15 students of a class is 16 years. Out of these, the average age of 5 students is 14 years and that of the other 10 students is 16 years. Tee age of the 15th student is?
Options:
A)18years
B)16years
C)14years
D)12years
E)10years
Rationale: Age of the 15th student
=[15 * 16 - (14 * 5 + 16 * 10)]
= (240 - 230) = 10 years.
Answer:E
Answer: E
Question: The length of a train and that of a platform are equal. If with a speed of 108 k/hr, the train crosses the platform in one minute, then the length of the train (in meters) is?
Options:
A)752
B)799
C)719
D)750
E)900
Rationale: Speed = [108 * 5/18] m/sec = 30 m/sec; Time = 1 min. = 60 sec.
Let the length of the train and that of the platform be x meters.
Then, 2x/60 = 30 Ã¨ x = 30 * 60 / 2 = 900
Answer: E
Answer: E
Question: We made a down payment of $100 and borrowed the balance on a new piano which cost $1000. The balance with interest was paid in 23 monthly payments of $40 each and a final payment of $70. The amount of interest paid was what percent of the amount borrowed?
Options:
A)6%
B)7%
C)8%
D)9%
E)10%
Rationale: We borrowed $900.
To pay back this loan, we paid 23*$40 + $70=$990.
The interest was $990-$900=$90.
The percentage was $90/$900=0.1=10%.
The answer is E.
Answer: E
Question: A thief is noticed by a policeman from a distance of 200 m. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 10 km and 11 km per hour respectively. What is the distance between them after 6 minutes?
Options:
A)100 m
B)200 m
C)600 m
D)800 m
E)400 m
Rationale: Explanation:
Relative speed of the thief and policeman = (11 â€“ 10) km/hr = 1 km/hr
Distance covered in 6 minutes = {\color{Blue} \left ( \frac{1}{60}\times 6 \right )} km = {\color{Blue} \frac{1}{10}} km = 100 m
{\color{Blue} \therefore } Distance between the thief and policeman = (200 â€“ 100) m = 100 m.
Answer: A
Answer: A
Question: P is a prime number. If 6p is between 15 and 95, which of the following W can be a value of 7p + 2?
Options:
A)W=15
B)W=79
C)121
D)65
E)21
Rationale: [3,5,7,11,13] are prime numbers that fits this equation 15< 6X <95. Afterwards subtract 2 from all the answer n see if it's divisible by 7. Therefore A and E are out. Leaves out with B C D.
B =11
C =17
D = 9
Only 11 is the set of prime numbers that fit between 15 and 95. Therefore 79 is the answer.B
Answer: B
Question: David has s pairs of shoes, which is 1/4 as many as Mary and twice as many as Jones. In terms of s, how many pairs of shoes do the three of them have combined?
Options:
A)9/2*s
B)7/2*s
C)3s
D)11/2*s
E)5/2*s
Rationale: == s +4s + s/2 ==> 5s + 1/2 s = 11/2*s
Ans .D
Answer: D
Question: 2224 × 9997 = ?
Options:
A)22244428
B)22255538
C)22233328
D)22266628
E)22233327
Rationale: C
22233328
2224 × 9997 = 2224 × (10000-3)
= 2224 × 10000 - 2224 × 3
= 22240000 - 6672
= 22233328
Answer: C
Question: If Finn was 15 months old one year ago, how old was he, in months, x months ago?
Options:
A)x − 30
B)x − 12
C)18 − x
D)27 − x
E)30 − x
Rationale: Age Today = 15 months + 12 months (1year) = 27 months
X months ago- Today's Age - X = 27 - X
Ans- D
Answer: D