divelab/Sys2Bench huggingface dataset:
Question: Find the 100th place digit of a number forming from digits 1 to 9 without repeatation and number passes the divisibility test of 11 means difference of sum of alternative digits is 0 or divisible by 11.
Options:
A)1
B)2
C)3
D)4
E)5
Rationale: Largest no is 987652413
So digit will be 4
ANSWER:D
Answer: D
Question: n is a whole number which when divided by 4 gives 3 as remainder. What will be the remainder when 2*n is divided by 4 ?
Options:
A)8
B)2
C)6
D)7
E)1
Rationale: Explanation:
Let n=4*q + 3. Then, 2*n = 8*q + 6 = 4(2*q + 1) + 2.
Thus when 2*n is divided by 4, the reminder is 2.
Answer: B) 2
Answer: B
Question: A candidate got 30% of the votes polled and he lost to his rival by 4000 votes. How many votes were cast?
Options:
A)7500
B)2028
C)2775
D)10000
E)6851
Rationale: 30%-----------L
70%-----------W
------------------
40%----------4000
100%---------? => 10000
Answer:D
Answer: D
Question: The average of first 10 odd numbers is?
Options:
A)12
B)10
C)87
D)23
E)34
Rationale: Sum of 10 odd no.
= 100
Average = 100/10
= 10
Answer:B
Answer: B
Question: A cricketer scored 138 runs which included 12 boundaries and 2 sixes. What percent of his total score did he make by running between the wickets.
Options:
A)46.2%
B)54.54 %
C)63%
D)56.52%
E)None of these
Rationale: Explanation :
Number of runs made by running = 138 - (12 x 4 + 2 x 6)
= 138 - (60)
= 78
Now, we need to calculate 72 is what percent of 138.
=> 78/138 * 100 = 56.52 %
Answer : D
Answer: D
Question: If 36 men can do a piece of work in 25 hours, in how many hours will 15 men do it ?
Options:
A)10 hours
B)40 hours
C)20 hours
D)60 hours
E)None of them
Rationale: Let the required number of hours be x. Then,
Less men, More hours	(Indirect Proportion)
15 : 36 : : 25 : x = (15 x x) = (36 x 25) = (36 x 25)/15 = 60
Hence, 15 men can do it in 60 hours.
Answer is D.
Answer: D
Question: Calculate the value of q from the below equation: q^3âˆ’25q+5=173
Options:
A)7
B)4
C)6
D)9
E)8
Rationale: Use elimination method to find the correct option. you find that of all the options 7 is the correct value for q
Answer: A
Answer: A
Question: If 45% of z is 90% of y and y is 75% of x, what percent of x is z?
Options:
A)200
B)160
C)100
D)65
E)150
Rationale: (45/100)z = (90/100)y
and y = (75/100)x i.e. y = (3/4)x
i.e. (45/100)z = (90/100)*(3/4)x
i.e. z = (90*3)x/(45*4)
i.e. z = (1.5)x = (150/100)x
i.e. z is 150% of x
Answer: Option E
Answer: E
Question: The area of a rectangular field is equal to 200 square meters. Its perimeter is equal to 60 meters. Find the width of this rectangle.
Options:
A)5
B)10
C)15
D)20
E)25
Rationale: L * W = 200 : area , L is the length and W is the width.
2 L + 2 W = 60 : perimeter
L = 30 - w : solve for L
(30 - W) * W = 200 : substitute in the area equation
W = 10 and L = 20 :
correct answer B
Answer: B
Question: 417 x 417 + 383 x 383=?
Options:
A)320578
B)80578
C)80698
D)81268
E)None of them
Rationale: =(417)^2 + (383)^2
=(400+17)^2 + (400-17)^2
=2[(400)^2+(17)^2]
=2[160000+289]
=2 x 160289 = 320578
Answer is A
Answer: A
Question: The average weight of a group of boys is 30 kg. After a boy of weight 38 kg joins the group, the average weight of the group goes up by 1 kg. Find the number of boys in the group originally ?
Options:
A)A)4
B)B)8
C)C)6
D)D)2
E)E)7
Rationale: Let the number off boys in the group originally be x.
Total weight of the boys = 30x
After the boy weighing 38 kg joins the group, total weight of boys = 30x + 38
So 30x + 38 = 31(x + 1) = > x = 7.
Answer:E
Answer: E
Question: Operation # is defined as: a # b = 4a^2 + 4b^2 + 8ab for all non-negative integers. What is the value of (a + b) + 5, when a # b = 100?
Options:
A)5
B)8
C)10
D)13
E)17
Rationale: OFFICIAL SOLUTION:
(B) We know that a # b = 100 and a # b = 4a² + 4b² + 8ab. So
4a² + 4b² + 8ab = 100
We can see that 4a² + 4b² + 8ab is a well-known formula for (2a + 2b)². Therefore
(2a + 2b)² = 100.
(2a + 2b) is non-negative number, since both a and b are non-negative numbers. So we can conclude that 2(a + b) = 10. (a + b) + 5 = 10/2 + 5 = 10.
The correct answer is C.
Answer: C
Question: If the median of a list of numbers is m, the first quartile of the list is the median of the numbers in the list that are less than m. What is the first quartile of the list of numbers 42, 24, 30, 28, 26, 19, 33 and 35 ?
Options:
A)33
B)28
C)27
D)25
E)23
Rationale: It is given that a quartile is the middle number of all numbers less than median..
so lets arrange the number in ascending order- 42, 24, 30, 28, 26, 19, 33 and 35
19, 24, 26, 28, 30 , 33, 35, 42...
numbers less than median are 19, 24, 26, 28..
the median of these numbers = center of 24 and 26 = 25
D
Answer: D
Question: A vessel of capacity 90 litres is fully filled with pure oil. Nine litres of oil is removed from the vessel and replaced with water. Nine litres of the solution thus formed is removed and replaced with water. Find the quantity of pure oil in the final oil solution?
Options:
A)83.9 litres
B)54.9 litres
C)37.9 litres
D)72.9 litres
E)27.9 litres
Rationale: D
72.9 litres
Let the initial quantity of oil in vessel be T litres.
Let us say y litres of the mixture is taken out and replaced by water for n times, alternatively.
Quantity of oil finally in the vessel is then given by [(T - y)/T]n * T
For the given problem, T = 90, y = 9 and n = 2.
Hence, quantity of oil finally in the vessel
= [(90 - 9)/90]2 (90) = 72.9 litres.
Answer: D
Question: A set of football matches is to be organized in a "round-robin" fashion, i.e., every
participating team plays a match against every other team once and only once. If 21
matches are totally played, how many teams participated?
Options:
A)4
B)5
C)6
D)7
E)8
Rationale: 2 ways to solve this problem..
summation(x)=n(n-1)/2
n(n-1)/2=21;
n^2-n-42=0
factors : 7,-6
Ans : 7
ANSWER:D
Answer: D
Question: If each letter in the English alphabet is assigned an even number such as A = 2, B = 4 and so on, then what will be the total value of the letters in the word LEAD?
Options:
A)42
B)40
C)46
D)44
E)48
Rationale: GIven the Condition:
L=24,E=10, A=2 and D=8
Hence the addition is 44
ANSWER:D
Answer: D
Question: What is the unit digit in the product (3^65 x 6^59 x 7^71)?
Options:
A)4
B)8
C)6
D)2
E)1
Rationale: Unit digit in 3^4 = 1 Unit digit in (3^4)16 = 1
Unit digit in 3^65 = Unit digit in [ (3^4)16 x 3 ] = (1 x 3) = 3
Unit digit in 6^59 = 6
Unit digit in 7^4 ==> Unit digit in (7^4)17 is 1.
Unit digit in 7^71 = Unit digit in [(7^4)17 x 7^3] = (1 x 3) = 3.
Required digit = Unit digit in (3 x 6 x 3) = 4.
Answer A)4.
Answer: A
Question: Divide $300 among A,B in the ratio 1:2. How many $ that A get?
Options:
A)$50
B)$500
C)$150
D)$250
E)$100
Rationale: Sum of ratio terms = 1+2 = 3
A = 300*1/3 = $100
Answer is E
Answer: E
Question: A man can row
9 1/3
kmph in still water and finds that it takes him thrice as much time to row up than as to row, down the same distance in the river. The speed of the current is.
Options:
A)3 2/3kmph
B)4 2/3kmph
C)5 2/3kmph
D)6 2/3kmph
E)None of these
Rationale: Explanation:
Friends first we should analyse quickly that what we need to calculate and what values we require to get it.
So here we need to get speed of current, for that we will need speed downstream and speed upstream, because we know
Speed of current = 1/2(a-b) [important]
Let the speed upstream = x kmph
Then speed downstream is = 3x kmph [as per question]
speed in still water = 1/2(a+b)
=>1/2(3x+x)
=>2x as per question we know,
2x=9 1/3
=>2x=28/3
=>x=14/3
So,
Speed upstream = 14/3 km/hr, Speed downstream 14 km/hr.
Speed of the current
=1/2[14−14/3]
=14/3=4 2/3kmph
Option B
Answer: B
Question: A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered.If the area of the field is 800 sq.ft, how many feet of fencing will be required ?
Options:
A)100feet
B)120feet
C)150feet
D)180feet
E)186feet
Rationale: Explanation:
We are given with length and area, so we can find the breadth.
as Length * Breadth = Area
=> 20 * Breadth = 800
=> Breadth = 40 feet
Area to be fenced = 2B + L = 2*40 + 20
= 100 feet
Answer: Option A
Answer: A
Question: A certain league has four divisions. The respective divisions had 9, 10, 11, and 12 teams qualify for the playoffs. Each division held its own double-elimination tournament -- where a team is eliminated from the tournament upon losing two games -- in order to determine its champion. The four division champions then played in a single-elimination tournament -- where a team is eliminated upon losing one game -- in order to determine the overall league champion. Assuming that there were no ties and no forfeits, what is the maximum number of games that could have been played in order to determine the overall league champion?
Options:
A)79
B)83
C)85
D)87
E)88
Rationale: Consider 4 teams.
Max possible games if a team is eliminated after 2 loses = 3 + 2 = 5
Similarly, if 5 teams are there,
Max possible games = 4 + 3 = 7.
So going forth we can play 15,17,19,21 max possible games for 9,10,11,12 teams respectively.
Adding them up gives 72. Now there are two teams left in each group still. So four more games to give a winner in each team.
So 72+ 4 = 76.
Now of the four teams we can have max 3 games if its a knock out round.
So 76 + 3 = 79.
Answer A = 79.
Answer: A
Question: For the symbol, m”n=n^2−m for all values of m and n. What is the value of 6”3?
Options:
A)5
B)3
C)2
D)1
E)0
Rationale: 6”3= 9 - 6=3
Answer: B
Answer: B
Question: A brick measures 20 cm * 10 cm * 7.5 cm how many bricks will be required for a wall 25 m * 2 m * 0.75 m?
Options:
A)33381
B)27991
C)92211
D)25000
E)27821
Rationale: 25 * 2 * 0.75 = 20/100 * 10/100 * 7.5/100 * x
25 = 1/100 * x => x = 25000
Answer: D
Answer: D
Question: Find the number of zeroes in the expression 15*32*25*22*40*75*98*112*125
Options:
A)12
B)9
C)14
D)7
E)8
Rationale: (3*5)*(2*2*2*2*2)*(5*5)*(2*11)*(2*2*2*2*5)*(5*5*3)*(2*7*7)*(2*2*2*2*7)*(5*5*5)
there are 9 (5*2) pairs which gives zero
so.no of zeros 9
ANSWER:B
Answer: B
Question: 1904 x 1904 = ?
Options:
A)3623216
B)3624216
C)3624316
D)3625116
E)3625216
Rationale: 1904 x 1904 = (1904)2
= (1900 + 4)2
= (1900)2 + (4)2 + (2 x 1900 x 4)
= 3610000 + 16 + 15200.
= 3625216.
E)
Answer: E
Question: A fraudulent dairy guy declares to market his dairy at price range but he combined it with water and therefore benefits 25%. The percentage of water in the combination is:
Options:
A)20%
B)30%
C)50%
D)35%
E)60%
Rationale: Explanation :
-> If Capability Price of 1 L of milk = Rs.1
And S.Price of 1 L of combination = Rs.1
Benefits = 20%
Capability Price of 1 L of combination =[ (100 / 100+25)*1 ]
= Rs. 100/125 = Rs. 4/5
-> From the rule of allegation
i. Capability Price of 1 L of water = 0
ii. Capability Price of 1 L of milk = 1
iii. (p) = 4/5
iv. d – m = 1 – 4/5 = 1/5
v. m – c = 4/5 – 0 = 4/5
Ratio of milk to water = 4/5 : 1/5 = 4:1
% of water in the combination = (1/5 x 100)% = 20%
Answer : A
Answer: A
Question: On Monday Joshua sold 90 phones, Rob sold 30% more phones than Joshua, Prerna sold 11 more phones than Rob, and Declan sold 3/4 of what Prerna sold. How many phones did Declan sell?
Options:
A)111
B)75
C)29
D)128
E)96
Rationale: E
96
Joshua sold 90 phones.
Rob sold 30 % more phones than Joshua
Rob = 90 + 90 × 30%
= 90 + 90 × 0.30
= 90 + 27
= 117
Prerna sold 11 more phones than Rob
Prerna = 117 + 11
= 128
Declan sold 3/4 of what Prerna sold.
Declan= 128 x 3/4
=96
Declan sold 96 phones.
The correct answer is E.
Answer: E
Question: Today John is twice as old as Sam and Sam is 3 years younger than Mike. If John, Sam, and Mike are all alive 4 years from today, which of the following must be true on that day. I. John is twice as old as Sam II. Sam is 3 years younger than Mike III. John is older than Mike
Options:
A)I, III
B)I
C)II
D)I,II & III
E)III
Rationale: Say Mike age is 10
Sam age is 7
John age is 14
After 4 years
Mike age is 14
Sam age is 11
John age is 28
i.e ) after 4 years
Sam is 3 years younger than Mike
John is twice as old as Sam
John is older than Mike
Answer : D
Answer: D
Question: Kate and Danny each have $10. Together, they flip a fair coin 5 times. Every time the coin lands on heads, Kate gives Danny $1. Every time the coin lands on tails, Danny gives Kate $1. After the five coin flips, what is the probability W that Kate has more than $10 but less than $15?
Options:
A)5/16
B)1/2
C)12/30
D)W=15/32
E)W=3/8
Rationale: For 21 heads Kate will end up with < $10 and we want her to win. Therefore, only possibilities W are 3 or 4 heads.
I made an educated guess and it worked fine.
Ans- 'D'
MGMAT's anagram helped here as well.
HHHHT = 5!/4!*1! = 5
HHHTT = 5!/3!*2! = 10
Total acceptable cases = 15
Total cases = 32
P = 15/32.D
Answer: D
Question: Find unit digit of{(6374)^1793 x (625)^317 x (341)^491}.
Options:
A)5
B)15
C)0
D)20
E)69
Rationale: Explanation:
Unit digit of 6374 is 4.
Unit digit of 625 is 5.
Unit digit of 341 is 1.
Just multiply 4*5*1 = 20
So unit digit of 20 is 0.
Answer C.
Answer: C
Question: The ratio by weight, measured in pounds, of books to clothes to electronics in a suitcase initially stands at 5:4:2. Someone removes 7 pounds of clothing from the suitcase, thereby doubling the ratio of books to clothes. How many pounds do the electronics in the suitcase weigh?
Options:
A)6
B)7
C)8
D)9
E)10
Rationale: The weights of the items in the suitcase are 5k, 4k, and 2k.
If removing 7 pounds of clothes doubles the ratio of books to clothes, then 7 pounds represents half the weight of the clothes.
2k = 7 pounds and then k = 3.5 pounds.
The electronics weigh 2(3.5) = 7 pounds.
The answer is B.
Answer: B
Question: A woman has two blouses of different colors, three skirts of different colors, and two different pairs of shoes. She refuses to wear her pink blouse with her green skirt. How many different blouseskirt-shoe combinations could she wear?
Options:
A)8
B)10
C)16
D)17
E)18
Rationale: total ways = 2*3*2=12..
now its better to find the ways in which the pink blose and green skirty are together and subtract from total to get the answer..
the ways in which the pink blose and green skirty are together=1*1*2=2..
total ways =12-2=10..
B
Answer: B
Question: A hollow iron pipe is 21 cm long and its external diameter is 8 cm. If the thickness of the pipe is 1 cm and iron weighs 8 g/cm^3, then the weight of the pipe is:
Options:
A)3.6 kg
B)3.696 kg
C)36 kg
D)36.9 kg
E)3.06 kg
Rationale: External radius = 4 cm,
Internal radius = 3 cm.
Volume of iron=(22/7	x [(4)^2 - (3)^2] x 21) cm^3
(22/7x 7 x 1 x 21)cm^3
462 cm^3.
Weight of iron = (462 x 8) gm = 3696 gm = 3.696 kg.
ANSWER B
Answer: B
Question: A train passes a station platform in 34 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Options:
A)228
B)210
C)188
D)266
E)281
Rationale: The speed of the train is 54 * 5/18 m/s = 15 m/s
The length of the train is 15 x 20 = 300 m
platform + 300 = 15 * 34
platform = 510 - 300 = 210
The answer is B.
Answer: B
Question: One computer can upload 120 megabytes worth of data in 6 seconds. Two computers, including this one, working together, can upload 1300 megabytes worth of data in 42 seconds. How long would it take for the second computer, working on its own, to upload 120 megabytes of data?
Options:
A) 6
B) 7
C) 9.13
D) 11
E) 13
Rationale: Since the first computer can upload 120 megabytes worth of data in 6 seconds then in 6*7=42 seconds it can upload 7*120=840 megabytes worth of data, hence the second compute in 42 seconds uploads 1300-840=460 megabytes worth of data. The second computer can upload 120 megabytes of data in 9.13 seconds.
Answer: C.
Answer: C
Question: How many two-digit numbers yield a remainder of 1 when divided by both 6 and 15?
Options:
A)0
B)1
C)2
D)3
E)4
Rationale: Easier to start with numbers that are of the form 15p+1 ---> 16,31,46,61,76,91.
Out of these 2 (31,61) are also of the form 6q+1. Thus 2 is the answer. C is the correct answer.
Answer: C
Question: At a small company, 76 percent of the employees are women, and 60 percent of the employees are married. If 2/3 of the men are single, what fraction of the women are married?
Options:
A)13/19
B)1/3
C)9/20
D)7/10
E)5/7
Rationale: Lets take total employees are 100.
Given that,Total Women= 76 and Total Married = 60.
Total Men = 100 - 76 = 24 and Single men = 2/3*24 = 16.
Married men = total men - single men = 24 - 16 = 8.
Married women= Total married - Married men = 60 - 8 = 52.
Fraction of women are married = Married women / Total Women = 52 / 76 = 13/19. ANS A
Answer: A
Question: If CD represents a positive two digit number, where C and D are single digit integers, which of the following cannot be true?
Options:
A)C+D =9
B)(C)(D)=9
C)C-D = 9
D)D-C= 9
E)C/D = 9
Rationale: (A) CD = 45 or 63 or 27
(B) CD = 33 or 19
(C) 90
(D) impossible
(E) CD = 91
(D) is impossible because 09 is not a valid two digit number --- if there's a zero in the ten's place, that's just 9, a single digit number. Therefore, no valid two digit number would satisfy (D).
ans D
Answer: D
Question: 8^100 is divisible by 17. Find the remainder for this?
Options:
A)10
B)12
C)16
D)17
E)19
Rationale: This is an extremely difficult problem to solve with out Fermat's little theorem. By applying Fermat's little theorem , We know that 816 when divided by 17, the remainder is 1.
So divide 100 by 16 and find the remainder. Remainder = 4
Therefore, 100 = (16 × 6) + 4
Now this problem can be written as 810017 = 816×6+417 = (816)6×8417
Now this problem simply boils down to (1)6×8417 = 8417
84 = 82×82, we need to find the remainder when 64 × 64 is divisible by 17. Or 13 × 13 = 169. When 169 is divided by 17, remainder is 16.
C
Answer: C
Question: The speed of a boat in upstream is 60 kmph and the speed of the boat downstream is 80 kmph. Find the speed of the boat in still water and the speed of the stream?
Options:
A)10 kmph
B)22 kmph
C)77 kmph
D)66 kmph
E)99 kmph
Rationale: Speed of the boat in still water = (60+80)/2 = 70 kmph. Speed of the stream
= (80-60)/2
= 10 kmph.
Answer:A
Answer: A
Question: A single letter is selected at random from the word 'SIM'. The probability that it is a vowel is..??
Options:
A)2/11
B)3/11
C)4/11
D)1/3
E)1
Rationale: total vowels = 1, total number of letters = 3
so probability = 1/3
ANSWER:D
Answer: D
Question: In year Y imported machine tools accounted for 25 percent of total machine - tool sales in the United States, and Japanese imports accounted for 55 percent of the sales of imported machine tools. If the total sales of machine tools imported Japan that year was x billion dollars, then the total sales of all machine tools in the United States was how many billion dollars?
Options:
A)9X/80
B)13X/20
C)80/9X
D)20X/13
E)80X/11
Rationale: IMT = 0.25T
JI = 0.55 IMT
0.55 IMT = $x b
IMT = $x/(0.55) b
T = 4*IMT = 4x/0.55 = 4x*100/55 = 80x/11
Ans: "E"
Answer: E
Question: In 2000, a town had 1300 males and 1400 females. In 2015, the same town had 56500 males and 60000 females. By approximately what percent did the ratio of males to females increase from 2000 to 2015.
Options:
A)0.4%
B)0.7%
C)0.9%
D)1.1%
E)1.4%
Rationale: 2000: males/females = 1300/1400 =3900/4200
2015: males/females = 56500/60000 =3955/4200
ASIDE: It's useful to write both ratios with the same denominator. This allows us to IGNORE the denominator and focus solely on the numerators.
So, our ratio went from 3900/4200 to 3955/4200
Ignoring the denominators, we went from 3900 to 3955
The percent change = 100(difference in values)/(original value)
= (100)(3955-3900)/3900
= (100)(55)/3900)
= (100)(0.0141)
≈ 1.41...
Answer: E
Answer: E
Question: A train 600 meters long is running with a speed of 50 kmph. The time taken by it to cross a tunnel 170 meters long is?
Options:
A)287 sec
B)288 sec
C)55 sec
D)16 sec
E)17 sec
Rationale: D = 600 + 170 = 770
S = 50 * 5/18 = 14 mps
T = 770/14 = 55 sec
Answer: C
Answer: C
Question: Which one the following fractions has the smallest value?
Options:
A)123/847
B)123/849
C)123/874
D)123/877
E)246/1700
Rationale: Among (A) , (B) , (C) & (D)
(D) is the smallest...
Now compare (D) Vs (E)
(D) 123/877 ~ 14%
(E) 246/1700 ~ 14.47%
So (D) < (E)
Hence correct answer must be (D)
Answer: D
Question: If a is a positive integer, then 5^a+1^a =?
Options:
A)Cannot be determined
B)1+(5^a)
C)2a
D)2a^(a + 1)
E)None
Rationale: 5^a+1^a=5^a+1
Answer is option B
Answer: B
Question: If P gets 25% more than Q, then by what percent does Q get less than P?
Options:
A)60%
B)22%
C)12%
D)20%
E)13%
Rationale: Let Q get 1 unit.
25% of 1 unit = 1/4 = 0.25
P gets (1 + 0.25) i.e., 1.25 units.
Difference = (1.25 - 1) = 0.25
Required percentage = 0.25/1.25 * 100 = 1/5 * 100 = 20%
Answer: C
Answer: C
Question: The present population of a town is 2000. Population increase rate is 20% p.a. Find the population of town after 1 years?
Options:
A)1000
B)2400
C)1500
D)1600
E)1250
Rationale: P = 2000
R = 20%
Required population of town = P(1 + R/100)^T
= 2000(1 + 20/100)
= 2000(6/5)
= 2400
Answer is B
Answer: B
Question: A straight fence is to be constructed from posts 6 inches wide and separated by lengths of chain 5 feet long. If a certain fence begins and ends with a post, which of the following could be the length of the fence in feet? (12 inches = 1 foot).
Options:
A)17
B)88
C)266
D)2777
E)88
Rationale: Explanation:
The fence will consist of one more post than there are chains. (e.g. P-c-P-c-P).
Therefore, a total length has to be a multiple of the length of the chain plus one post (5.5) plus one post extra.We have length = (5.5n + 0.5), where n can be any positive whole number. If n= 3, length =17
Answer: A) 17
Answer: A
Question: The toll T, in dollars, for a truck using a certain bridge is given by the formula T =3.50 + 0.50( x − 2), where x is the number of axles on the truck. What is the toll for an 18-wheel truck that has 2 wheels on its front axle and 4 wheels on each of its other axles?
Options:
A) $ 2.50
B) $ 3.00
C) $ 3.50
D) $ 4.00
E) $ 5.00
Rationale: Number of wheels in truck = 18
Number of wheels on its front axle =2
number of wheels remaining = 16
number of axles remaining axles = 16/4 = 4
Total number of axles = 5
T = 3.50 + 0.50( x − 2)
= 3.50 + .5*3
= 3.5 +1.5 = 5 $
Answer E
Answer: E
Question: If Yury has been writing programming code for 15 hours at a rate of 5 lines of code per 20 seconds, how many lines of code has he written?
Options:
A)126(10^2)
B)135(10^2)
C)12.6(10^5)
D)1.26(10^7)
E).126(10^9)
Rationale: 5 LINES IN 20 SECONDS
SO FOR 1 MINUTE ( 5 X 3 = 15 LINES )
I HOUR = 60 MINUTES
15 X 60 = 900 LINES IN AN HOUR
15 HOURS = 900 X 15 = 135(10^2)
ANSWER B
Answer: B
Question: A sum of money at simple interest amounts ti $2240 in 2 years and to $ 2600 in 5 years. What is the principal amount?
Options:
A)$1520
B)$1880
C)$2120
D)$2000
E)$1980
Rationale: S.I for 3 years = $ (2600-2240) = $ 360
S.I for 2 years = $ ((360/3) x 2) = $ 240
Principal =$ (2240-240) = $ 2000
Answer is D
Answer: D
Question: A no. when divided by the sum of 555 and 445 gives 2times their difference as quotient & 30 as remainder. Find the no. is?
Options:
A)124345
B)234545
C)165767
D)144656
E)220030
Rationale: (555 + 445) * 2 * 110 + 30 = 220000 + 30 = 220030
E
Answer: E
Question: By selling an shirt for $300, a shop keeper gains 20%. During a clearance sale, the shopkeeper allows a discount of 10% on the marked price. His gain percent during the sale is:
Options:
A)2
B)14
C)8%
D)12
E)10
Rationale: C
8%
Marked price = $300
C.P. = 100/120 * 300 = $250
Sale price = 90% of $300 = $270
Required gain % = 20/250 * 100 = 8%.
Answer: C
Question: An author received $0.80 in royalties for each of the first 100,000 copies of her book sold, and $0.50 in royalties for each additional copy sold. If she received a total of $260,000 in royalties, how many copies of her book were sold?
Options:
A)130,000
B)300,000
C)380,000
D)400,000
E)460,000
Rationale: Total royalties for first 100.000 books = .8*100,000= 80,000
Total royalties for the rest of the books = 260,000-80,000 = 180,000
Remaining books = 180,000/0.5 = 360,000
Total books = 360,000+100,000 = 460,000 Answer E
Answer: E