divelab/Sys2Bench huggingface dataset:
Question: The cost of 16 packets of salt,each weighing 900 grams is Rs. 28.What will be the cost of 27 packets,if each packet weight 1 kg ?
Options:
A)Rs.52.50
B)Rs.56
C)Rs.58.50
D)Rs.64.75
E)None of these
Rationale: Solution
Let the required cost be Rs. x. Then,
More packets, More cost (Direct Proportion)
More weight, More cost (Direct Proportion)
∴ (16 × 900 × x) = (27 × 1000 × 28) ⇔ x =(27x1000x28)/16x900=105/2=52.50 .Answer A
Answer: A
Question: On the independence day, bananas were be equally distributed among the children in a school so that each child would get two bananas. On the particular day 330 children were absent and as a result each child got two extra bananas. Find the actual number of children in the school?
Options:
A)237
B)287
C)197
D)660
E)720
Rationale: Explanation:
Let the number of children in the school be x. Since each child gets 2 bananas, total number of bananas = 2x.
2x/(x - 330) = 2 + 2(extra)
=> 2x - 660 = x => x = 660.
Answer: D
Answer: D
Question: A boat goes 100 km downstream in 10 hours, and 75 m upstream in 15 hours. The speed of the stream is?
Options:
A)22 1/2 kmph
B)2 2 1/8 kmph
C)2 2 1/0 kmph
D)2 2 1/2 kmph
E)2 2 2/2 kmph
Rationale: 100 --- 10 DS = 10
? ---- 1
75 ---- 15 US = 5
? ----- 1 S = (10 - 5)/2
= 2 2 1/2 kmph
Answer: D
Answer: D
Question: What is the units digit of (44^4)(33^5)(21^6)?
Options:
A)0
B)2
C)4
D)6
E)8
Rationale: The units digit of 44^4 is the units digit of 4^4 which is 6.
The units digit of 33^5 is the units digit of 3^5 which is 3.
The units digit of 21^6 is the units digit of 1^6 which is 1.
The units digit of 6*3*1 is 8.
The answer is E.
Answer: E
Question: In a 8*8 chess board, what is the total number of squares refer model?
Options:
A)201
B)202
C)203
D)204
E)205
Rationale: 1x1 8 8 64
2x2 7 7 49
3x3 6 6 36
4x4 5 5 25
5x5 4 4 16
6x6 3 3 9
7x7 2 2 4
8x8 1 1 1
total 204
ANSWER:D
Answer: D
Question: A, B and C are entered into a partnership. A invested Rs.6500 for 6 months, B invested Rs.8400 for 5 months and C invested for Rs.10000 for 3 months. A is a working partner and gets 5% of the total profit for the same. Find the share of C in a total profit of Rs.7400.
Options:
A)1900
B)1750
C)10300
D)8600
E)8000
Rationale: 65 * 6 : 84 * 5 : 100 * 3
26:28:20
C share = 74000 * 95/100 = 7030 * 20/74 => 1900
ANSWER A
Answer: A
Question: At a small company, 61 percent of the employees are women, and 60 percent of the employees are married. If 2/3 of the men are single, what fraction of the women are married?
Options:
A)5/16
B)1/3
C)9/20
D)47/61
E)5/7
Rationale: Lets take total employees are 100.
Given that,Total Women= 61 and Total Married = 60.
Total Men = 100 - 61 = 39 and Single men = 2/3*39 = 26.
Married men = total men - single men = 39 - 26 = 13.
Married women= Total married - Married men = 60 - 13 = 47.
Fraction of women are married = Married women / Total Women = 47 / 61 = 5/7. ANS D
Answer: D
Question: The perimeter of a semi circle is 144 cm then the radius is?
Options:
A)88
B)28
C)61
D)86
E)21
Rationale: 36/7 r = 144
=> r = 28
Answer:B
Answer: B
Question: There are 45 apples and 40 oranges in stock and packs are to be filled with equal number of same type of fruits such that minimum number of packs are used. There are 20 places on the shelf to display fruits so what will be the number of empty places to display fruits?
Options:
A)3
B)4
C)5
D)6
E)7
Rationale: k is the integer that represents the number of fruit in a pack
ak= 45 --> k = 45/a
bk= 40 --> k = 40/b
45/a = 40/b --> 9b = 8a and then min (a+b) = 17
20 -17 = 3 empty shelf places
ANSWER: A
Answer: A
Question: A man can row upstream at 34 kmph and downstream at 48 kmph, and then find the speed of the man in still water?
Options:
A)29
B)92
C)41
D)32
E)23
Rationale: US = 34
DS = 48
M = (48 + 34)/2 = 41
Answer:C
Answer: C
Question: A and B can separately do apiece of work in 20 and 15 days respectively. They worked together for 6 days, after which B was replaced by C. If -the work was finished in next 4 days, then the number of days in which C alone could do the work will be
Options:
A)60
B)40
C)35
D)30
E)65
Rationale: A and Bs one day work= 1/20+1/15=7/60
A and Bs six day work=(7/60)*6=7/10
remaining work=1-7/10=3/10
A and Cs 4 day work=(A and Cs 1 day work)*4= (1/20+1/x)*4=3/10 (remaining work)
x=40
Cs one day work=40
ANSWER:B
Answer: B
Question: If x < y < z and y-x > 3, where x is an even integer and y and z are odd integers, what is the least possible value of z - x?
Options:
A)7
B)6
C)8
D)9
E)10
Rationale: We have:
1) x<y<z
2) y-x>3
3) x=2k (x is an even number)
4) y=2n+1 (y is an odd number)
5) z=2p+1 (z is an odd number)
6) z-x=? least value
z-x=2p+1-2k=2p-2k+1=2(p-k)+1 - that means that z-x must be an ODD number.
we are asked to find the least value, so we have to pick the least numbers
since y is odd and x is even, y-x must be odd. since y-x>3, the least value for y-x must be 5, the least value for x must be 2, and, thus, the least possible value for y must be 7 (y-2=5, y=7)
2<7<z, since z is odd, the least possible value for z is 9
z-x=9-2=7
Answer A
Answer: A
Question: How long does a train 110 m long running at the speed of 54 km/hr takes to cross a bridge 132 m length?
Options:
A)12.9 sec
B)12.1 sec
C)17.9 sec
D)16.13 sec
E)14.9 sec
Rationale: Speed = 54 * 5/18 = 15 m/sec
Total distance covered = 110 + 132 = 242 m.
Required time = 242/15 = 16.13 sec.
Answer: D
Answer: D
Question: If in a cricket one day match, there were no wide balls, no wides, no extras and no overthrows.
What is the maximum number of runs that a batsman can score in 40 overs in an ideal case scenario?
Options:
A)1652
B)1651
C)1653
D)1323
E)None
Rationale: Solution:
1323
Explanation:
For an ideal case, the batsman will hit a six on each ball. But if he hits six on the last ball of the over, the strike will change in the next over. Thus, the best he can do in the last ball is run 3 runs so that he retains the strike even in the next over. Thus the total runs that he can score in each over:
6 * 5 + 3 = 33
But this will have to go like it only till the 39th over. In the 40th over, he can hit a six in the last ball as well as that will be the last ball of his destination.
Thus runs for the 40th over will be 6 * 6 = 36.
Hence the maximum runs = 33 * 39 + 36 = 1323
Answer D
Answer: D
Question: In a box of 12 pens, a total of 4 are defective. If a customer buys 3 pens selected at random from the box, what is the probability that neither pen will be defective?
Options:
A)1/6
B)2/55
C)14/55
D)12/55
E)3/4
Rationale: Method- 1
There are 9 fine pieces of pen and 4 defective in a lot of 12 pens
i.e. Probability of first pen NOT being defective = (8/12)
i.e. Probability of Second pen NOT being defective = (7/11)
i.e. Probability of third pen NOT being defective = (6/10)
Probability of Both pen being NON-defective = (8/12)*(7/11)*(6/10) = 14/55
Answer: option C
Answer: C
Question: A lent Rs. 5000 to B for 2 years and Rs. 3000 to C for 4 years on simple interest at the same rate of interest and received Rs. 2640 in all from both of them as interest. The rate of interest per annum is?
Options:
A)16%
B)12%
C)74%
D)10%
E)45%
Rationale: Let the rate be R% p.a. Then,
(5000 * R * 2)/100 + (3000 * R * 4)/100 = 2640
100 R + 120 R = 2640
R = 12%
Answer:B
Answer: B
Question: Bob finishes the first half of an exam in one-seventh the time it takes him to finish the second half. If the whole exam takes him an hour, how many minutes does he spend on the first half of the exam?
Options:
A)15
B)24
C)27
D)36
E)40
Rationale: Many times, it is easiest to think of problems like this conceptually (as opposed to formulaically). Conceptually, if the first half of the exam takes 1/7's the time of the second half (7/7's), we can see that the hour the entire exam took to finish can be broken down into fifth's. (Another way to look at this problem is via ratio's - first half is 1:8 and the second half is 7:8). With each eighth of an hour being 7.5 minutes (60/8), the first half of the exam would have taken 15 minutes. Correct answer is A.
Answer: A
Question: Of the students at a certain high school, 90 percent took a course in algebra or geometry and 18 percent took courses in both. If the percent of students who took a course in algebra was 2 times the percent of students who took a course in geometry, what percent of the students took a course in algebra but not geometry?
Options:
A)72%
B)70%
C)65%
D)60%
E)54%
Rationale: You can also just use the formula
n(A or B) = n(A) + n(B) - n(A and B)
90 = 2X + X - 18
X = 36
2X = 72
This is the number of people who took algebra including those who took both. To get the number of people who took only algebra, 72 - 18 = 54%
Answer (E)
Answer: E
Question: If the sides of a triangle are 30 cm, 28 cm and 14 cm, what is its area?
Options:
A)196 cm2
B)187 cm2
C)178 cm2
D)189 cm2
E)176 cm2
Rationale: The triangle with sides 30 cm, 28 cm and 14 cm is right angled, where the hypotenuse is 30 cm.
Area of the triangle
= 1/2 * 28 * 14
= 196 cm2
Answer: A
Answer: A
Question: If -4 < x < 7 and -7 < y < 3, which of the following specifies all the possible values of xy?
Options:
A)-42 < xy < 21
B)-42 < xy < 24
C)-49 < xy < 28
D)-24 < xy < 21
E)-24 < xy < 24
Rationale: The least value of xy is a bit more than 7*(-7)=-49 and the largest value of xy is a bit less than (-4)*(-7)=28.
Therefore -49 < xy < 28.
Answer: C.
Answer: C
Question: One cutting machine cuts 100 metal bars in 30 minutes.Another machine does the same job in 30 seconds.What time will it take if both machines are put on the same work ?
Options:
A)25.0 seconds
B)29.5 seconds
C)30.0 seconds
D)30.5 seconds
E)30.7 seconds
Rationale: By guess it is clear that the time taken will be less than 30 seconds and very near to it. Therefore, answer 29.5 seconds will be correct. Answer-B
Answer: B
Question: Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 7 sec. What is the length of the fast train?
Options:
A)38 7/6 m
B)38 7/4 m
C)38 8/9 m
D)38 7/9 m
E)38 7/7 m
Rationale: Relative speed = (40 - 20) = 20 km/hr.
= 20 * 5/ 18 = 50/9 m/sec.
Length of faster train = 50/9 * 7 = 350/9 = 38 8/9 m.Answer:C
Answer: C
Question: Sum of two numbers is 15. Two times of the first exceeds by 5 from the three times of the other. Then the numbers will be?
Options:
A)6, 9
B)10, 5
C)7, 8
D)9, 6
E)1,5
Rationale: Explanation:
x + y = 15
2x – 3y = 5
x = 10 y = 5
ANSWER IS B
Answer: B
Question: Suppose that f(x) is a function such that for every real number x,i)f(x)+f(1-x) = 10 and (ii) f(1+x) = 3+f(x). Then f(x)+f(-x)
must equal
Options:
A)7
B)9
C)10
D)11
E)12
Rationale: Since (ii) holds for every real number x, it will remain valid if we replace x with
-x. Therefore, f(1-x) = 3+f(-x). Now, from (i), 10 = f(x)+f(1-x) = f(x)+3+f(-x)
so that f(x) + f(-x) = 10-3 = 7. (Observe that f(x) = 3x + 4 satisfies the conditions
in the problem.)
correct answer A
Answer: A
Question: Two trains of length 100 m and 200 m are 100 m apart. They start moving towards each other on parallel tracks, at speeds 54 kmph and 72 kmph. After how much time will the trains meet?
Options:
A)20/7
B)20/5
C)20/9
D)20/21
E)20/8
Rationale: They are moving in opposite directions, relative speed is equal to the sum of their speeds.
Relative speed = (54 + 72)*5/18 = 7*5 = 35 mps.
The time required = d/s = 100/35 = 20/7 sec.
Answer:A:
Answer: A
Question: At an upscale fast-food restaurant, Shin can buy 3 burgers, 7 shakes, and one cola for $110. At the same place it would cost $164.50 for 4 burgers, 10 shakes, and one cola. How much would it cost for a meal of one burger, one shake, and one cola?
Options:
A)$1
B)$27
C)$31
D)$41
E)It cannot be determined
Rationale: let's suppose that the price of a burger is BB, of a shake - SS and that of a cola is CC. We can then construct these equations:
3B+7S+C=110
4B+10S+C=164.5
Subtracting the first equation from the second gives us B+3S=54.5
Now if we subtract the new equation two times from first or 3 times from second we will get B+S+C=11. In any case, there is no necessity to know each item's price, just the sum.
Answer: A
Answer: A
Question: A discount electronics store normally sells all merchandise at a discount of 5 percent to 45 percent off the suggested retail price. If, during a special sale, an additional 2 percent were to be deducted from the discount price, what would be the lowest possible price of an item costing $400 before any discount?
Options:
A)$215.00
B)$200.00
C)$215.80
D)$182.00
E)$215.60
Rationale: Original price : 400$
Max first discount = -45%
Thus : 400âˆ—(1âˆ’45/100)=220
Second discount on the discounted price = -2%
Thus : 220âˆ—(1âˆ’2/100)=215.60
Answer E
Answer: E
Question: On the independence day, bananas were be equally distributed among the children in a school so that each child would get two bananas. On the particular day 370 children were absent and as a result each child got two extra bananas. Find the actual number of children in the school?
Options:
A)237
B)287
C)197
D)740
E)720
Rationale: Explanation:
Let the number of children in the school be x. Since each child gets 2 bananas, total number of bananas = 2x.
2x/(x - 370) = 2 + 2(extra)
=> 2x - 740 = x => x = 740.
Answer: D
Answer: D
Question: Coconuts were purchased at 150 per hundred and sold at 2 per coconut. If 2000 coconuts were sold, what was the total profit made?
Options:
A)500
B)1000
C)1500
D)2000
E)None of these
Rationale: C.P. for one coconut = 150⁄100 = 3⁄2
S.P. for one coconut = 2
Profit on one coconut = 2 - 3⁄2 = 1⁄2
∴ Profit on 2000 coconut = 1⁄2 × 2000 = 1000
Answer B
Answer: B
Question: In a division sum, the remainder is 4 and the divisor is 3 times the quotient and is obtained by adding 2 to the thrice of the remainder. The dividend is:
Options:
A)53
B)58
C)51
D)60
E)62
Rationale: Diver = (4*3)+2 = 14
4* Quotient = 14
Quotient = 3.5
Dividend = (Divisor * Quotient) + Remainder
Dividend = ( 14 * 3.5) + 4 = 53
A
Answer: A
Question: 85 kg of a mixture containing milk and water in the ratio 27:7. How much more water is to be added to get a new mixture containing milk and water in the ratio 3:1?
Options:
A)10kg
B)7kg
C)5kg
D)9kg
E)3kg
Rationale: Milk in 85kg of mix = 85*27/34 = 135/2 kg
Water in it= 85-135/2 = 35/2 kg
Let x kg of water be added to it.
(135/2)/(35/2 + x) = 3/1
x=5kg
Answer is C
Answer: C
Question: A factory has a fixed cost of $45,000 a month, and a cost of $2.5 for every item produced. If the selling price of a single item is $5.5, what is the number of items must be sold monthly for the factory to cover its cost exactly?
Options:
A)9,000
B)15,000
C)18,000
D)22,500
E)27,000
Rationale: selling price - Cost price = 3 so per unit profit =3
cost to recover =45000
no of items required = 45000/3 = 15000
Ans B
Answer: B
Question: The quantities S and T are positive and are related by the equation S=K/T, where k is a constant. If the value of S increases by 60 percent, then the value of T decreases by what percent?
Options:
A)25%
B)33 ¹/₃%
C)50%
D)66 ²/₃%
E)75%
Rationale: We can assign numbers:
lets say S = 2, K = 6 (constant) and T = 3 (so that S=K/T)
Now increasing S by 50% gives S=4, K remains constant, so T = 2 (6/2=3)
decrease in T= 1, percent decrease in T = (1/4)*100 = 25%
Answer A
Answer: A
Question: The length of the bridge, which a train 150 metres long and travelling at 45 km/hr can cross in 30 seconds, is?
Options:
A)10 m
B)16 m
C)245 m
D)19 m
E)225 m
Rationale: Speed = [45 X 5/18] m/sec = [25/2] m/sec Time = 30 sec Let the length of bridge be x metres. Then, (150 + x)/30
= 25/2 => 2(150 + x) = 750 => x
= 225 m.
Answer: E
Answer: E
Question: A, B and C rents a pasture for Rs.899. A put in 12 horses for 8 months, B 16 horses for 9 months and 18 horses for 6 months. How much should C pay?
Options:
A)270
B)279
C)267
D)255
E)552
Rationale: 12*8 :16*9 = 18*6
8: 12: 9
9/29 * 899 = 279
Answer: B
Answer: B
Question: Two cars start at the same time from opposite ends of a highway that is 500 miles long. One car is riding at 40 mph and the second car is riding at 60 mph. How long after they begin will they meet?
Options:
A)1
B)2
C)3
D)4
E)5
Rationale: As cars are moving in opposite directions their speeds will be added. So their relative speeds: 60+40 = 100 mph
Total distance to be covered = 500 miles.
Time taken would be: 500 miles/100 mph = 5 hours
E is the answer.
Answer: E
Question: In a hotel we can order two types of varieties, but we can make 5 more varieties in home. One can choose the four varieties with two from hotel as must. Find how many ways one can order.
Options:
A)14
B)10
C)56
D)28
E)29
Rationale: 2c2*5c2=10ways
ANSWER:B
Answer: B
Question: The denominator of a fraction is 1 less than twice the numerator. If the numerator and denominator are both increased by 1, the fraction becomes 3/5. Find the fraction?
Options:
A)2/3
B)3/5
C)4/7
D)5/9
E)None of these
Rationale: Let the numerator and denominator of the fraction be 'n' and 'd' respectively.
d = 2n - 1
(n + 1)/(d + 1) = 3/5
5n + 5 = 3d + 3
5n + 5 = 3(2n - 1) + 3 => n = 5
d = 2n - 1 => d = 9
Hence the fraction is : 5/9
ANSWER:D
Answer: D
Question: The difference between compound and simple interest on a certain sum of money for 3 years at 6 2/3% p.a is Rs.184. Find the sum?
Options:
A)Rs.12000
B)Rs.14200
C)Rs.17520
D)Rs.13500
E)Rs.14500
Rationale: P = (184*106) / [6 2/3 * 6 2/3 *(300*6 2/3)]
P = 13500
ANSWER:D
Answer: D
Question: All the water in container A which was filled to its brim was poured into two containers B and C. The quantity of water in container B was 62.5% less than the capacity of container A. If 153 liters was now transferred from C to B, then both the containers would have equal quantities of water. What was the initial quantity of water in container A?
Options:
A)1289
B)1198
C)281
D)1224
E)282
Rationale: Explanation:
B has 62.5% or (5/8) of the water in A. Therefore, let the quantity of water in container A(initially) be 8k.
Quantity of water in B = 8k - 5k = 3k.
Quantity of water in container C = 8k - 3k = 5k
Container: A B C
Quantity of water: 8k 3k 5k
It is given that if 153 liters was transferred from container C to container B, then both the containers would have equal quantities of water.
5k - 153 = 3k + 153 => 2k = 306 => k = 153
The initial quantity of water in A = 8k = 8 * 153 = 1224 liters.
Answer: Option D
Answer: D
Question: Consider the following sets:
L = {3, 4, 5, 5, 6, 7},
M = {2, 2, 2, 8, 8, 8},
N = {15, 15, 15, 15, 15, 15},
Rank those three sets from least standard deviation to greatest standard deviation.
Options:
A)L, M, N
B)M, L, N
C)M, N, L
D)N, L, M
E)N, M, L
Rationale: Now we have to compare the standard deviations of Set L and Set M. In Set L, the mean is clearly 5: two of the entries equal 5, so they have a deviation from the mean of zero, and no entry is more than two units from the mean. By contrast, in Set M, the mean is also 5, and here, every number is 3 units away from the mean, so the standard deviation of M is 3. No number in Set L is as much as 3 units away from the mean, so whatever the standard deviation of L is, it absolutely must be less than 3. That means, Set L has the second largest standard deviation, and Set M has the largest of the three. N, L, M in increasing order. Answer = D.
Answer: D
Question: If two boys starting from same point, walking in the opposite directions with 4km/hr and 2km/hr as average speeds respectively. Then the distance between them after 6 hours is?
Options:
A)32
B)33
C)34
D)35
E)36
Rationale: Explanation:
Total distance = Distance traveled by person A+ Distance traveled by person B
= (4Ã— 6) + (2Ã— 6)
= 24+ 12
= 36 Km
Answer:E
Answer: E
Question: What number has a 5:1 ratio to the number 9?
Options:
A)45
B)50
C)88
D)52
E)12
Rationale: 5:1 = x: 9
x = 45
Answer: A
Answer: A
Question: Find the odd man out. 362, 482, 551, 263, 344, 284
Options:
A)362
B)482
C)551
D)344
E)None of these
Rationale: Explanation :
In all numbers except 344, the product of first and third digits is the middle digit. Answer : Option D
Answer: D
Question: The radius of a wheel is 22.4 cm. What is the distance covered by the wheel in making 650 resolutions?
Options:
A)724 m
B)704 m
C)915.2 m
D)278 m
E)927 m
Rationale: In one resolution, the distance covered by the wheel is its own circumference. Distance covered in 650 resolutions.
= 650 * 2 * 22/7 * 22.4 = 91520 cm
= 915.2 m
Answer:C
Answer: C
Question: A certain sum of money doubles itself in 10 years in how much many years will it trible itself at the same rate?
Options:
A)20
B)15
C)17
D)18
E)25
Rationale: 100 ---- 100 --- 10
100 --- 10
--------------
300 ---- 20 years
ANSWER A
Answer: A
Question: During a sale of 20% on everything in a store, a kid is successful in convincing the store manager to give him 20 candies for the discounted price of 10 candies. The store still makes a profit of 12% on this sale. What is the mark up percentage on each candy?
Options:
A) 100%
B) 80%
C) 75%
D) 66+2/3%
E) 55%
Rationale: Hi Akhil, I can share the way I solved it..
Let's say Marked price = M
So, there's a discount of 20% on M So, new S.P. = 80% of M
Now, the child convinces the owner to sell 20 candies for the price of 14 candies .
Let's say each candy after discount is 1$. So, S.P. of 20 candies = 20$. THe child bought it for 14 $ So, he got a discount of 6/20 *100 = 30%
So, the latest S.P. = 70% of 80% of M = 0.7* 0.8 M
Now, we are given that the shopkeeper still makes a profit of 12%. So we have ,
0.7 * 0.8 * M = 1.12 C.P
So, we get, M= 2 C.P.
i.e. Marked price was kept 100% above C.P.
B
Answer: B
Question: The diagonal of a rectangle is 41 cm and its area is 20 sq. cm. The perimeter of the rectangle must be:
Options:
A)18
B)19
C)20
D)21
E)46
Rationale: l2 + b2 = 41.
Also, lb = 20.
(l + b)2 = (l2 + b2) + 2lb = 41 + 40 = 81
(l + b) = 9.
Perimeter = 2(l + b) = 18 cm.
Answer:A
Answer: A
Question: The triplicate ratio of 3:5 is?
Options:
A)27:125
B)1:62
C)1:34
D)3:64
E)5:64
Rationale: 3^3: 5^3 = 27:125
ANSWER:A
Answer: A
Question: A bag marked at $80 is sold for $68. The rate of discount is?
Options:
A)10%
B)15%
C)20%
D)25%
E)30%
Rationale: Rate of discount = 12/80 * 100 = 15%
Answer is B
Answer: B
Question: A certain sum of money at simple interest amounted Rs.780 in 5 years at 4% per annum, find the sum?
Options:
A)337
B)268
C)198
D)650
E)168
Rationale: 780 = P [1 + (5*4)/100]
P = 650'
Answer:D
Answer: D
Question: In a certain game of shooting the points in each round for the first,second,third and fourth position were 10,5,2,1 . No other points were given. Daniel participated in several rounds in the competition and the product of his score was 1000. In How many Rounds did he participate?
Options:
A)100
B)50
C)Cannot be determined
D)105
E)25
Rationale: Correct answer is C because we are given that there won't be any points awarded for rounds other than 1st four position.
Thus, it may happen that he played 150 rounds out of only 70 rounds were there in which he was awarded some points.
Answer: C
Question: A train passes a station platform in 30 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Options:
A)150 m
B)240 m
C)260 m
D)280 m
E)380 m
Rationale: Speed = 54 x 5/18 = 15 m/s
Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
Then, (x + 300)/30 = 15
--> x + 300 = 450
x = 150m.
Answer : A.
Answer: A
Question: In the xy-plane, a triangle has vertices (0,0), (4,0) and (4,10). If a point (a,b) is selected at random from the triangular region, What is the probability that a-b>0?
Options:
A)1/5
B)1/3
C)1/2
D)2/3
E)2/5
Rationale: The area of the right triangle is (1/2)*4*10 = 20.
Only the points (a,b) below the line y=x satisfy a - b > 0.
The part of the triangle which is below the line y=x has an area of (1/2)(4)(4) = 8.
P(a - b > 0) = 8/20 = 2/5
The answer is E.
Answer: E
Question: Baby Isabel plays with blocks. Each block is 4.5 inches tall. She has a collection of 33 blocks. If she could stack all of the blocks up one on top of the other, how many inches tall would her tower of blocks be?
Options:
A)67.19"
B)90.9"
C)106.34"
D)120.5"
E)148.5"
Rationale: 4.5"*33=148.5". Answer is E.
Answer: E