divelab/Sys2Bench huggingface dataset:
Question: Two trains A and B starting from two points and travelling in opposite directions, reach their destinations 9 hours and 4 hours respectively after meeting each other. If the train A travels at 100kmph, find the rate at which the train B runs.
Options:
A)40
B)60
C)120
D)80
E)150
Rationale: If two objects A and B start simultaneously from opposite points and, after meeting, reach their destinations in ‘a’ and ‘b’ hours respectively (i.e. A takes ‘a hrs’ to travel from the meeting point to his destination and B takes ‘b hrs’ to travel from the meeting point to his destination), then the ratio of their speeds is given by:
Sa/Sb = √(b/a)
i.e. Ratio of speeds is given by the square root of the inverse ratio of time taken.
Sa/Sb = √(4/9) = 2/3
This gives us that the ratio of the speed of A : speed of B as 2:3.
Since speed of A is 80 kmph, speed of B must be 100*(3/2) = 1520 kmph
E
Answer: E
Question: If the average marks of three batches of 55, 60 and 45 students respectively is 30, 55, 60, then the average marks of all the students is:
Options:
A)53.33
B)54.68
C)55
D)47.81
E)None of these
Rationale: Explanation:
Required average = (55 × 30 + 60 × 55 + 45 × 60/55 + 60 + 45)
= (1650 + 3300 + 2700/160)
= 7650/160
= 47.81
Answer: D
Answer: D
Question: Machine A takes 100 hours to complete a certain job and starts that job at 7AM. After two hour of working alone, machine A is joined by machine B and together they complete the job at 6PM. How long would it have taken machine B to complete the jobif it had worked alone for the entire job?
Options:
A)10.11
B)9.99
C)11.1
D)44.11
E)1.01
Rationale: Let us assume total job = 100 units
A finishes 100 units in 100 hrs(given)
Hence A (working rate)= 1 units /hr
Now Given that A works for 2 hr( so 2 units done) then A and B finish total work in 15 hours. Hence A and B finish 98 units in 9 hours. Of these 1x9=9 units were done by A. Hence B did 89units in 9 hours.
Hence B(working rate)= 89/9 units /hr
Hence B takes 100x9/89 = 10.11 hours to complete the job.
Answer A.
Answer: A
Question: An amount of Rs. 3000 becomes Rs. 3600 in four years at simple interest. If the rate of interest was 1% more, then what was be the total amount?
Options:
A)Rs.3776
B)Rs.3729
C)Rs.3720
D)Rs.3778
E)Rs.3992
Rationale: A = P(1 + TR/100)
=> 3600 = 3000[1 + (4 * R)/100] => R = 5%
Now R = 6%
=> A = 3000[1 + (4 * 6)/100]
= Rs.3720.
Answer: C
Answer: C
Question: Find the area of circle whose radius is 7m?
Options:
A)187
B)154
C)177
D)288
E)298
Rationale: 22/7 * 7 * 7
= 154
Answer:B
Answer: B
Question: A certain board game has a row of squares numbered 1 to 100. If a game piece is placed on a random square and then moved 5 consecutive spaces in a random direction, what is the probability the piece ends no more than 5 spaces from the square numbered 49?
Options:
A)15%
B)8%
C)11%
D)12%
E)13%
Rationale: No more than 5 spaces from 49 means in the rangefrom 49-5=44 to 49+5=54, inclusive. Total numbers in this range 54-44+1=11, the probability favorable/total=11/100
Answer: C
Answer: C
Question: There are 8 women and 7 men in a certain club. If the club is to select a committee of 2 women and 2 men, how many different such committees are possible?
Options:
A)332
B)450
C)362
D)476
E)588
Rationale: 8C2 * 7C2 = 28*21 = 588
The answer is E.
Answer: E
Question: The average marks of 30 students are 45 but after checking there are two mistakes found. After adjustment if a student got 45 more markes and other student got 15 less marks, then What will be the adjusted average?
Options:
A)45
B)44
C)47
D)46
E)None of these
Rationale: Answer
Total number of all students of the class = 30 x 45 = 1350
∴ New average after adjustment = (1350 - 45 + 15)/30 = 1320/30 = 44
Correct Option: B
Answer: B
Question: Suppose there are 4 books on fairy tales, 5 novels and 3 plays. They have to be arranged so that the books on fairy tales are together, novels are together and plays are together, but we no longer require that they should be in a specific order. In how many ways can this be done?
Options:
A)103680
B)113689
C)125569
D)136690
E)None
Rationale: Explanation :
First, we consider the books on fairy tales, novels and plays as single objects.
These three objects can be arranged in 3!=6 ways.
Let us fix one of these 6 arrangements.
This may give us a specific order, say, novels -> fairy tales -> plays.
Given this order, the books on the same subject can be arranged as follows.
The 4 books on fairy tales can be arranged among themselves in 4!=24 ways.
The 5 novels can be arranged in 5!=120 ways.
The 3 plays can be arranged in 3!=6 ways.
For a given order, the books can be arranged in 24*120*6=17280 ways.
Therefore, for all the 6 possible orders the books can be arranged in 6*17280= 103680 ways.
Answer : A
Answer: A
Question: If five machines working at the same rate can do 3/4 of a job in 30 minutes, how many minutes would it take two machines working at the same rate to do 3/5 of the job?
Options:
A)45
B)60
C)75
D)80
E)100
Rationale: using the std formula
m1d1h1/w1=m2d2h2/w2
substituting the values we have
5*1/2*4/3=2*5/3*x (converted 30 min into hours =1/2)
10/3=10/3*x
x=1 hour
so 60 minutes
ANSWER:B
Answer: B
Question: In two alloys, copper and tin are related in the ratios of 4:1 and 1:3. 10kg of Ist alloy, 16 kg of 2nd alloy and some pure copper melted together. An alloy obtained in which the ratio of copper and tin was 3:2. Find the weight of the new alloy.
Options:
A)34kg
B)35kg
C)36kg
D)30kg
E)32kg
Rationale: suppose x kg of pure copper is melted with 10kg of Ist alloy and 16 kg of 2nd alloy , then
Pure cooper in new alloy = 10*4/5 + 16*1/4 +x = 12+x kg
Pure tin in new alloy = 10*1/5+ 16*3/4 = 14 kg
As per given condition
(12+x)/14 = 3/2
24+2x= 42
x=9 kg
Total weight of new alloy = 10+16+9=35 kg
ANSWER:B
Answer: B
Question: The least common multiple of positive integer f and 3-digit integer n is 690. If n is not divisible by 3 and f is not divisible by 2, what is the value of n?
Options:
A)115
B)230
C)460
D)575
E)690
Rationale: The LCM of n and f is 690 = 2*3*5*23.
f is not divisible by 2, thus 2 goes to n
n is not divisible by 3, thus 3 goes to f.
From above:
n must be divisible by 2 and not divisible by 3: n = 2*... In order n to be a 3-digit number it must take all other primes too: n = 2*5*23 = 230.
Answer: B.
Answer: B
Question: x/2y = 2a,then 2x/x-2ay=?
Options:
A)4
B)8
C)16
D)2
E)6
Rationale: x/2y=2a,
Then x = 4ay,
Now, 2x/x-2ay = (2*4ay)/(4ay-2ay) = 8ay/2ay = 4
ANSWER:A
Answer: A
Question: Which no. need to add to 859622 to get a no. exactly divisible by 456?
Options:
A)546577
B)674645
C)566578
D)465766
E)859622
Rationale: Dividend = Quotient * Divisor + Reminder
859622 / 456 gives quotient = 1885 and reminder = 62.
So, the next number divisible by 456 is 456 places infront of 456 * 1885
Which means 456 – 62 = 394 should be added to 859622.
E
Answer: E
Question: If population of certain city increases at the rate of 5%. If population in 1981 was 231525, then population in 1978 was?
Options:
A)120000
B)228788
C)266891
D)267689
E)200000
Rationale: X * (105/100) * (105/100) * (105/100) = 232525
X = 231525/1.157625
X = 200000
Answer:E
Answer: E
Question: In how many different ways can 5 identical blue pants and 5 identical red pants be shared among 10 children such that each child receives a pant?
Options:
A)628800
B)4628800
C)2628800
D)3628800
E)1628800
Rationale: GGG RRR
Therefore total number of ways is
6! but there are two groups of 3 identical things.
Therefore total number of "different" ways is
10!/ (5!) (5!) = 3628800 ANS:D
Answer: D
Question: During a trip on an expressway, Don drove a total of x miles. His average speed on a certain 5-mile section of the expressway was 20 miles per hour, and his average speed for the remainder of the trip was 60 miles per hour. His travel time for the x-mile trip was what percent greater than it would have been if he had traveled at a constant rate of 60 miles per hour for the entire trip?
Options:
A)8.5%
B)50%
C)x/12%
D)60/x%
E)400/x%
Rationale: Say x = 5 miles (so no remainder of the trip).
Time to cover x = 5 miles at 20 miles per hour = (time) = (distance)/(rate) = 5/20 = 1/4 hours = 10 minutes.
Time to cover x = 5 miles at 60 miles per hour = (time) = (distance)/(rate) = 5/60 = 1/12 hours = 5 minutes.
(Or simply, half rate will result in doubling the time.)
So, we can see that the time to cover x = 5 miles at 30 miles per hour (10 minutes) is 100% greater than the time to cover x = 5 miles at 60 miles per hour (5 minutes).
Now, plug x = 4 miles into the answer choices to see which one yields 100%. Only answer E works.
Answer: E.
Answer: E
Question: Every student in a room is either a junior or a senior. There is at least one junior and at least one senior in the room. If 1/3 of the juniors is equal to 4/3 of the seniors, what fraction of the students in the room are juniors?
Options:
A)3/20
B)1/3
C)5/2
D)2/7
E)4/5
Rationale: Let total number of juniors= J
total number of seniors =S
(1/3) J = (4/3) S
=> S = 1/4 J
Total number of students = J+S = (5/4) J
Fraction of the students in the room are juniors = J/(J+S) = J/[(5/4) J]
=4/5
Answer E
Answer: E
Question: The sale price of an article including the sales tax is Rs. 616. The rate of sales tax is 10%. If the shopkeeper has made a profit of 12%, then the cost price of the article is
Options:
A)Rs. 500
B)Rs. 515
C)Rs. 550
D)Rs. 600
E)None
Rationale: Solution
110% of S.P. = 616	‹=› S.P.=(616x100/110).
‹=› Rs. 560.
C.P.	‹=› Rs.(100/112 x 560)
‹=› Rs. 500.
Answer A
Answer: A
Question: k = 2^n + 3, where n is an integer greater than 1. If k is divisible by 9, which of the following MUST be divisible by 9?
Options:
A)2^n - 6
B)2^n - 2
C)2^n
D)2^n + 4
E)2^n + 5
Rationale: Given: k, M and N are integers
If k is a divisor of both N and M, then k is a divisor of N+M (and N–M and M–N)
We're told that 9 is a divisor of 2^n + 3
We also know that 9 is a divisor of9.
So, applying the above rule, 9 is a divisor of 2^n + 3 +9, and 9 is a divisor of 2^n + 3 -9= 2^n-6
A
Answer: A
Question: If a new town has 100 residents, and the population doubles every 10 years, what will be its population after 75 years?
Options:
A)6034 residents
B)9051 residents
C)12068 residents
D)15075 residents
E)18102 residents
Rationale: 100*2^(75/10)=100*2^7.5=100*181.02=18102
The answer is E.
Answer: E
Question: The average (arithmetic mean) of 4 positive integers is 50. If the average of 2 of these integers is 35, what is the greatest possible value that one of the other 2 integers can have?
Options:
A)55
B)65
C)100
D)109
E)129
Rationale: a + b + c + d = 200
a + b = 70
c + d = 130
Greatest possible = 129 (Just less than 1)
Answer = E
Answer: E
Question: A rectangular floor measures 2 by 3 meters. There are 5 white, 5 black, and 5 red parquet blocks available. Each block measures 1 by 1 meter. In how many different colors h patterns can be floor be parqueted?
Options:
A) 104
B) 213
C) 3^5
D) 705
E) 726
Rationale: Total number of squares we need to fill = 6
Number of colors we have h= 3
Therefore, total number of patterns = 3*3*3*3*3*3 = 729
However, this is considering that we can have a case in which all tiles are the same color. Since we are given that the quantity of each tile is 5 and the number of tiles required is 6, we know that this case cannot be possible. Therefore we must subtract the cases in which all tiles will be of the same color (3 cases since there are 3 colors).
Thus our answer should be :729 - 3 = 726
Answer : E
Answer: E
Question: For a group of n people, k of whom are of the same sex, the (n-k)/n expression yields an index for a certain phenomenon in group dynamics for members of that sex. For a group that consists of 20 people, 5 of whom are females, by how much does the index for the females exceed the index for the males in the group?
Options:
A) 0.05
B) 0.0625
C) 0.5
D) 0.25
E) 0.6
Rationale: Index for females = (20-5)/20 = 3/4 = 0.75
Index for males = (20-15/20 = 1/4 = 0.25
Index for females exceeds males by 0.75 - 0.25 = 0.5
Answer: C
Answer: C
Question: 10 men working 6 hrs per day manufacture 200 shoes in 18 days. How many hours a day must 15 men work to manufacture the same 200 shoes in 12 days?
Options:
A)6
B)10
C)12
D)15
E)17
Rationale: Explanation :
Solution: Let the required number of hours be x.
More men, less hours per day (Indirect proportion)
Less days, more working hours per day (Indirect proportion)
men 15 : 10
} : : 6 : x
days 12 : 18
.'. 15*12*x = 10*18*6
=> x = 10*18*6/(15*12)
=> x = 6
Answer : A
Answer: A
Question: A bullet train 200 m long is running with a speed of 69 kmph. In what time will it pass a man who is running at 3 kmph in the direction opposite to that in which the bullet train is going?
Options:
A)10 sec
B)15 sec
C)12 sec
D)11 sec
E)16 sec
Rationale: A
10 sec
Speed of the bullet train relative to man = (69 + 3) kmph
= 72 *5/18 m/sec = 60/3 m/sec.
Time taken by the bullet train to cross the man = Time taken by it to cover 200 m at (60/3) m / sec
= (200*3/60) sec = 10 sec
Answer: A
Question: A box contains four silver coins, of which two coins have heads on both their faces, one coin has tail on both its faces and the fourth coin is a normal one. A coin is picked at random and then tossed. If head is the outcome of the toss, then find the probability that the other face (hidden face) of the coin tossed is also a head.
Options:
A)1/5
B)2/5
C)3/5
D)4/5
E)3/4
Rationale: There are four ways (2 heads in one two-headed coin and 2 heads in the other two-headed coin)
How many ways can you get heads from this entire set of coins? There are five ways (four as identified above and one from the normal coin)
Therefore probability = 4/5
Option D
Answer: D
Question: The average weight of a group of boys is 30 kg. After a boy of weight 33 kg joins the group, the average weight of the group goes up by 1 kg. Find the number of boys in the group originally ?
Options:
A)4
B)5
C)2
D)7
E)8
Rationale: Let the number off boys in the group originally be x.
Total weight of the boys = 30x
After the boy weighing 33 kg joins the group, total weight of boys = 30x + 33
So 30x + 33 = 31(x + 1) = > x = 2.
Answer: C
Answer: C
Question: If a is a positive integer, and if the units digit of a^2 is 9 and the units digit of (a+1)^2 is 4, what is the units G digit of (a+2)^2?
Options:
A)1
B)3
C)5
D)6
E)C. 14
Rationale: I also got A. By punching in numers:
G...7^2=...9
...8^2=...4
...9^2=...1.A
Answer: A
Question: A train 275 metres long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going ?
Options:
A)5 sec
B)6 sec
C)15 sec
D)10 sec
E)None
Rationale: Solution
Speed of train relative to man =(60+6) km/hr= 66km/hr
=(66x5/18) m/sec =(55/3) m/sec
∴ Time taken to pass the man = (275x3/55)sec = 15 sec
Answer C
Answer: C
Question: Rose and Marry each have a bag of marbles, each of which contains 4 blue marbles, 10 red marbles, and 6 white marbles. If Rose and Marry each select one marble from their respective bags, what is the probability that either Rose or Marry select a red marble?
Options:
A)3/7
B)3/4
C)1/4
D)1/8
E)1/16
Rationale: Probability that either selects a red marble,P(Either) = 1- probability that neither selects a red marble, P(Neither)
Probability that Marry selects non red = 10c1 / 20c1 = 1/2
Probability that Rose selects non red = 10c1 / 20c1 = 1/2
=> P(Either)=1- (1/2*1/2) = 1-1/4= 3/4.
Answer B.
Answer: B
Question: First bunch of bananas has (1/4) again as many bananas as a second bunch. If the second bunch has 3 bananas less than the first bunch, then the number of bananas in the first bunch is
Options:
A)9
B)10
C)12
D)15
E)17
Rationale: x is the no.of banana's in second bunch
first bunh banan's will be x+(1/4)x= x*5/4
If the second bunch has 3 bananas less than the first bunch
X*5/4 = x+3, X=12,
First bunch bannana's will be 15
ANSWER:D
Answer: D
Question: The difference between a two-digit number and the number obtained by interchanging the positions of its digits is 54. What is the difference between the two digits of that number?
Options:
A)4
B)5
C)6
D)8
E)9
Rationale: Sol.
Let the ten’s digit be x and unit’s digit be y,
Then, (10x + y) - (10y + x) = 54 ⇔ 9 (x - y) = 54
⇔ x - y = 6
Answer C
Answer: C
Question: In the game of Dubblefud, red chips, blue chips and green chips are each worth 2, 4 and 5 points respectively. In a certain selection of chips, the product of the point values of the chips is 16,000. If the number of blue chips in this selection doubles the number of green chips, how many red chips are in the selection?
Options:
A)1
B)2
C)3
D)4
E)5
Rationale: this is equivalent to :-
2x * 4y * 5z = 16000
y/2= z (given)
2x * 4y * 5y/2= 16000
2x * y^2 = 16000/10
2x * y^2 = 1600
now from options given we will figure out which number will divide 800 and gives us a perfect square :-
which gives us x=2 as
2* 2* y^2 =1600
y^2 = 400
y =20
Number of red chips = 2 hence B
Answer: B
Question: Sneh's age is 1/6th of her father's age. Sneh's father's age will be twice of Vimal's age after 10 years. If Vimal's eighth birthday was celebrated two years before, what is Sneh's present age?
Options:
A)24 years
B)30 years
C)6 2/3 years
D)32 years
E)None of these
Rationale: Vimal's age after 10 years = (8+2+10)years
= 20 years.
Sneh's father age after 10 years = 40 years (Twice than Vimal's age after 10yr)
Sneh's father Present age = 30 years (40yrs -10yrs)
Therefore Sneh's age	= (1/6 * 30)years
= 5 years.
ANSWER:E
Answer: E
Question: Jack and Jill work at a hospital with 2 other workers. For an internal review, 2 of the 4 workers will be randomly chosen to be interviewed. What is the probability that Jack and Jill will both be chosen?
Options:
A) 1/3
B) 1/6
C) 1/15
D) 3/8
E) 2/3
Rationale: 1/4C2=1/6.
Answer: B.
Answer: B
Question: Tom, who has 50 math questions, will get 6 points per question if he chooses a correct answer. If he chooses a wrong answer to a question or skips one, he will lose 2 points per question. Then, which of the following can be the score if he solves all the 50 questions?
Options:
A)192
B)193
C)194
D)195
E)196
Rationale: Let x be the correctly answered questions. y be the wrongly answered/ skipped ones.
We have x + y = 50;
Score = 6x-2y
2x+2y = 100; 6x-2y = Score;
==> 8x = 100+Score;
check for answer choices where 100+Score is divisible by 8
Choice (E) 196 fits the equation !
Answer: E
Question: . A boy has eight trousers and 10 shirts. In how many different ways can he select a trouser and a shirt?
Options:
A)80
B)87
C)90
D)120
E)140
Rationale: Explanation:
The boy can select one trouser in eight ways.
The boy can select one shirt in 10 ways.
The number of ways in which he can select one trouser and one shirt is 8 * 10 = 80 ways.
Answer: Option A
Answer: A
Question: If the product of 4 integers is negative, at most how many of the integers can be negative?
Options:
A)2
B)3
C)4
D)5
E)6
Rationale: The product of 4 integers is negative
Thus an odd number of integers need to be negative to have a negative product
We are asked at most how many are required.
So, the highest odd integer before 6,i.e. 3
Correct Option : B
Answer: B
Question: The Carson family will purchase three used cars. There are two models of cars available, Model A and Model B, each of which is available in seven colors: blue, black, red, and green. How many different combinations of three cars can the Carsons select if all the cars are to be different colors?
Options:
A)24
B)32
C)48
D)254
E)192
Rationale: I have no idea how you got 8C8, 7C6 and 4C1.
I could have understood 8C1*6C1*4C1 (I have explained why this doesn't work in the post above)
The best way to solve it is by first selecting 3 colors out of the given 4 in 4C3 ways. (say, you got black, red and green)
Now for each color, you have 2 choices - model A or B
So you select a model in 2 ways.
No of ways of selecting the 3 cars = 7C3 * 2 * 2 * 2 = 254
Well, my logic was
The number of ways of selecting r objects from n different objects is nCr.
We have 8 options and can select either of the 8 as the first - 8C8
One car is gone and one becomes a forbidden choice so we have 7 options and need to select either of the 6 as the first - 7C6
Two cars are gone and two becomes a forbidden choice so we have 6 options and need to select either of the 4 as the first - 6C4
D
Answer: D
Question: Pavan travelled for 11 hours. He covered the first half of the distance at 30 kmph and remaining half of the distance at 25 kmph. Find the distance travelled by Pavan?
Options:
A)388
B)266
C)288
D)300
E)371
Rationale: Let the distance travelled be x km.
Total time = (x/2)/30 + (x/2)/25 = 11 => x/60 + x/50 = 11 => (5x + 6x)/300 = 11 => x = 300 km
Answer: D
Answer: D
Question: Two taps can separately fill a cistern 10 minutes and 15 minutes respectively and when the waste pipe is open, they can together fill it in 18 minutes. The waste pipe can empty the full cistern in?
Options:
A)7
B)6
C)8
D)9
E)5
Rationale: 1/10 + 1/15 - 1/x = 1/18
x = 9
Answer:D
Answer: D
Question: A certain list of 200 test scores has an average (arithmetic mean) of 90 and a standard deviation of d, where d is positive. Which of the following two test scores, when added to the list, must result in a list of 202 test scores with a standard deviation less than d ?
Options:
A) 80 and 80
B) 80 and 85
C) 90 and 90
D) 85 and 85
E) 85 and 90
Rationale: The standard deviation of a set shows how much variation there is from the mean, how widespread a given set is. So, a low standard deviation indicates that the data points tend to be very close to the mean, whereas high standard deviation indicates that the data are spread out over a large range of values.
So when we add numbers, which are far from the mean we are stretching the set making SD bigger and when we add numbers which are close to the mean we are shrinking the set making SD smaller.
According to the aboveadding two numbers which are closest to the mean will shrink the set most, thus decreasing SD by the greatest amount.
Closest to the mean are 90 and 90 (actually these numbers equal to the mean) thus adding them will definitely shrink the set, thus decreasing SD most.
Answer: C.
Answer: C
Question: A bag contains 7 green and 8 white balls. If two balls are drawn simultaneously, the probability that both are of the same colour is
Options:
A)7/16
B)7/12
C)7/19
D)7/12
E)7/15
Rationale: Drawing two balls of same color from seven green balls can be done in ⁷C₂ ways.
Similarly from eight white balls two can be drawn in ⁸C₂ ways.
P = ⁷C₂/¹⁵C₂ + ⁸C₂/¹⁵C₂
= 7/15
Answer:E
Answer: E
Question: Mr. Smith calculated the average of 10 three digit numbers. But due to a mistake he reversed the digits of a number and thus his average increased by 69.3. The difference between the unit digit and hundreds digit of that number is :
Options:
A)3
B)4
C)5
D)6
E)7
Rationale: Since the average increased by 69.3 and there were a total of 10 numbers, it means the incorrect number was 693 greater than the correct number.
Say, the correct number was abc (where a, b and c are the digits of the 3 digit number)
Then the incorrect number was cba.
100c + 10b + a - (100a + 10b + c) = 693
99c - 99a = 99(c - a) = 693
693 = 99*7 = 99(c - a)
So c - a = 7
Answer (E)
Answer: E
Question: Mac has £ 3 more than Ken, but then Ken wins on the horses and trebles his money, so that he now has £ 2 more than the original amount of money that the two boys had between them. How much money did Mac and Ken have between them before Ken's win ?
Options:
A)22
B)27
C)13
D)55
E)11
Rationale: Let money with Ken = x. Then, money with Mac = x + £ 3.
Now, 3x = (x + x + £ 3) + £ 2 x = £ 5.
Therefore Total money with Mac and Ken = 2x + £ 3 = £ 13.
Answer: C
Answer: C
Question: How long does a train 150 m long traveling at 60 kmph takes to cross a bridge of 170 m in length?
Options:
A)16.5
B)19.2
C)16.4
D)16.8
E)16.1
Rationale: D = 150 + 170 = 320 m
S = 60 * 5/18 = 50/3
T = 320 * 3/50 = 19.2 sec
Answer: B
Answer: B
Question: Find the average of all the numbers between 6 and 34 which are divisible by 5.
Options:
A)22
B)20
C)288
D)277
E)21
Rationale: Average = (10 + 15 + 20 + 25 + 30)/5 = 100/5 = 20.
Answer: B
Answer: B