divelab/Sys2Bench huggingface dataset:
Question: 469157 * 9999
Options:
A)1691100843
B)4591100843
C)4691100843
D)3691100843
E)None of these
Rationale: Explanation:
469157 * (10000 - 1)
= 4691570000 - 469157
= 4691100843
Option C
Answer: C
Question: A man goes 10 km against the current of the stream in 5 hr and goes 5 km along the stream in 1hour. How long will it take to go 5 km in stationary water?
Options:
A)1hr 30min
B)1hr 12min
C)2hr
D)2hr 15min
E)3hr
Rationale: Speed up stream = 10/5 = 2 km/hr
Speed down stream = 5/1 = 5 km/hr
Speed in still water = 1/2(2+5) = 7/2 = 3.5 km/hr
Time taken to travel 5 km in still water is = 5/7/2 = 10/7 = 1hr 12min
Answer is B
Answer: B
Question: A rectangular floor is covered by a rug except for a strip X meters wide along each of the four edge. If the floor is L meters by B meters, what is the area of the rug in square meters?
Options:
A)(L-2X)(B-2X)/2
B)2*(L-2X)(B-2X)
C)(L-2X)(B-2X)/3
D)(L-2X)(B-2X)
E)(L-2X)(B-2X)/4
Rationale: A strip of X meters is covering the inner rectangular rug for all 4 sides.
Length of inner rug = L-(2X)
breadth of inner rug= B-(2X)
Area of Rug= (L-2X)(B-2X)
Ânswer: D
Answer: D
Question: How many multiples of 4 are there between 64 and 256 ?
Options:
A)47
B)49
C)42
D)41
E)40
Rationale: It should be mentioned whether 64 and 256 are inclusive.
If 64 and 256 are inclusive, then the answer is (256-64)/4+1=49.
If 64 and 256 are NOT inclusive, then the answer is (252-68)/4+1=47.
Since OA is A, then we have NOT inclusive case.
Answer: A
Question: Of the 1000 inhabitants of a town, 60 % are males of whom 120 % are literate. If, of all the inhabitants, 25% are literate, then what percent of the females of the town are literate ?
Options:
A)32.5 %
B)32.9 %
C)92.5 %
D)38.5 %
E)37.5 %
Rationale: Explanation:
Number of males = 60% of 1000 = 600. Number of females = (1000 - 600) = 400.
Number of literates = 25% of 1000 = 250.
Number of literate males = 20% of 600 = 120.
Number of literate females = (250 - 120) = 130.
Required pecentage = (130/400 * 100 ) % = 32.5 %.
Answer: A) 32.5 %
Answer: A
Question: In a can, there is a mixture of milk and water in the ratio 4 : 5. If it is filled with an additional 8 litres of milk the can would be full and ratio of milk and water would become 6 : 5. Find the capacity of the can?
Options:
A)45
B)44
C)64
D)63
E)92
Rationale: Explanation:
Let the capacity of the can be T litres.
Quantity of milk in the mixture before adding milk = 4/9 (T - 8)
After adding milk, quantity of milk in the mixture = 6/11 T.
6T/11 - 8 = 4/9(T - 8)
10T = 792 - 352 => T = 44.
Answer: Option B
Answer: B
Question: a = 7^15 - 625^3 and a/x is an integer, where x is a positive integer greater than 1, such that it does NOT have a factor p such that 1 < p < x, then how many different values for x are possible?
Options:
A)None
B)One
C)Two
D)Three
E)Four
Rationale: This is a tricky worded question and I think the answer is should be D not C...
Here is my reason :
The stem says that x is a positive integer such that has no factor grater than 2 and less than x itself . The stem wants to say that X is a PRIME NUMBER . because any prime
Number has no factor grater than 1 and Itself .
On the other hand the stem says that X COULD get how many different number NOT MUST get different number ( this is very important issue )
AS our friends say, if we simplify Numerator more we can obtain : 5^12 ( 5^3-1) = 5^12 (124) = 5^12 (31*2*2) divided by x and we are told that this fraction is
An integer . so, X COULD Be ( not Must be) 5 , 31 ,or 2 !!! so , X could get 4 different values and answer is E....
Answer: E
Question: Find the principle on a certain sum of money at 5% per annum for 6 years if the amount being Rs.1120?
Options:
A)862
B)1067
C)1977
D)1056
E)1097
Rationale: 1120 = P [1 + (5*6)/100]
P= 862
Answer: A
Answer: A
Question: A, B and C shared the profit in a business in the ratio 5 : 7 : 8. They had partnered for 14 months, 4 months and 7 months respectively. What was the ratio of their investments?
Options:
A)10:12:14
B)12:24:28
C)20:22:12
D)10:49:32
E)None of these
Rationale: Explanation :
Ratio in which A,B and C shared the profit = 5 : 7 : 8
Assume that the ratio of their investment = a:b:c
Then 14a : 4b : 7c = 5 : 7 : 8
Good to go, we got the equation. Now it's a matter of time to find a, b and c
14a/4b = 5/7
=> 98a = 20b
=> b = 98a/20 = 49a/10 ---(1)
14a/7c =5/8
=> 2a/c =5/8
=> 16a = 5c
=> c = 16a/5 ---(2)
a : b : c = a : 49a/10 : 16a/5 = 1 : 49/10 : 16/5 = 10 : 49 : 32. Answer : Option D
Answer: D
Question: Sunday
Monday
Tuesday
Wednesday
Thursday
What day comes three days after the day which comes two days after the day which comes immediately after the day which comes two days after Monday?
Options:
A)Sunday
B)Monday
C)Tuesday
D)Wednesday
E)Thursday
Rationale: C
Tuesday
Answer: C
Question: A fill pipe can fill 1/2 of cistern in 15 minutes. In how many minutes, it can fill 1/2 of the cistern?
Options:
A)1 min
B)5 min
C)10 min
D)15 min
E)20 min
Rationale: Required time = 15*2*1/2 = 15 minutes
Answer is D
Answer: D
Question: 10^185 - 10^10 = Which of the following best approximates the value of the expression above?
Options:
A)10^180
B)10^185
C)10^179
D)10^170
E)10^160
Rationale: 10^185 - 10^10 =
Which of the following best approximates the value of the expression above?
Yes, answer 10^185 is correct. Note that we need approximate value of the given expression and as 10^(185) is much larger number than 10^(10) then 10^(10) is pretty much negligible in this case: 10^(185)-10^(10)=~10^(185).
Answer : B
Answer: B
Question: Replace the ? with the appropriate number
1 , 4 , 5 , 6 , 7 , 9 , 11 ?
Options:
A)488
B)123
C)234
D)100
E)589
Rationale: D
list of consecutive numbers that does not contain a 'T' in the spelling
Answer: D
Question: jim and Beth each drove from Smallville to Crown City by different routes. jim drove an an average speed of 40 miles per hour and completed the trip in 30 minutes. Beth's route was 5 miles longer, and it took her 20 minutes more than jim to complete the trip. How many miles per hour was Beth's average speed on this trip?
Options:
A) 24
B) 30
C) 48
D) 54
E) 75
Rationale: Speed = Distance/Time
Distance for jim = Speed * Time = 40 * 1/2 = 20 miles
Distance for Beth = Distance for jim +5 = 20+5 = 25 miles
Time taken by Beth = Time taken by jim + (1/3 hour) = 1/2+1/3 = 5/6
Speed of Beth = D/T = 25/(5/6) = 25*6/5 = 30 miles per hour
Hence, B is the answer.
Answer: B
Question: The ratio between the length and the breadth of a rectangular plot is 7 : 5. If the perimeter of the plot is 144 metres, what is its area?
Options:
A)1320 sq.metres
B)1260 sq.metres
C)1280 sq.metres
D)1380 sq.metres
E)None of these
Rationale: Let the length and breadth be 7x and 5x respectively.
Then, P = 2(7x + 5x) = 144 ⇒ x = 6
Area = 7 × 6 × 5 × 6 = 1260 sq.m.
Answer B
Answer: B
Question: If f is a function defined for all k by f(k) = k^(2/3)/16, what is f(8 k) in terms of f(k)?
Options:
A)1/8 f(k)
B)5/8 f(k)
C)4 f(k)
D)10 f(k)
E)32 f(k)
Rationale: f(k) = (k^(2/3)) /16
f(8 k) = (8 k)^( 2/3)/16 = 4 k^(2/3)/16 = 4 * (k^(2/3)/16) =4 f(k).
So answer is C.
Answer: C
Question: A train ,135 meters long travels at a speed of 45 km/hr crosses a bridge in 30 seconds. The length of the bridge is
Options:
A)270 m
B)245 m
C)235 m
D)220 m
E)240 m
Rationale: Explanation:
Assume the length of the bridge = x meter
Total distance covered = 135+x meter
total time taken = 30s
speed = Total distance covered /total time taken = (135+x)/30 m/s
=> 45 Ã— (10/36) = (135+x)/30
=> 45 Ã— 10 Ã— 30 /36 = 135+x
=> 45 Ã— 10 Ã— 10 / 12 = 135+x
=> 15 Ã— 10 Ã— 10 / 4 = 135+x
=> 15 Ã— 25 = 135+x = 375
=> x = 375-135 =240
Answer: Option E
Answer: E
Question: Cathy's Catering business is catering a party. She is delivering food that is 1/6 sandwiches, 1/4 salads, 1/6 chips, 1/8 deserts, 1/8 snacks, and the rest drinks. If Cathy dropped the deserts on the way to the party and decides to stop and buy more snacks to make up for it, by doubling the snacks, what proportion of the food is snacks now?
Options:
A)5/29
B)1/8
C)5/16
D)1/2
E)1/4
Rationale: Sandwiches = 1/6 = 4/24
Salads = 1/4 = 6/24
Chips = 1/6 = 4/24
Deserts = 1/8 = 3/24
Snacks = 1/8 = 3/24
Drinks = 1 - (20/24) = 4/24
Now: Deserts = 0/24
If Snacks doubled => (2)(3/24) = 6/24; then, total = 24
and 6 is now snacks => proportion = 6/24.
Answer: E
Answer: E
Question: A number when divided by 100 leaves 11 as a remainder. What will be the remainder if the number is divided by 11?
Options:
A)11
B)1
C)2
D)3
E)21
Rationale: Let 100+11=111
111 divided evenly by eleven leaves a remainder of one.
Correct answer is B.
Answer: B
Question: The profit earned by selling an article for Rs. 832 is equal to the loss incurred when the same article is sold for Rs. 448. What should be the sale price for making 50% profit?
Options:
A)220
B)230
C)960
D)780
E)400
Rationale: C
C.P. = Rs. x.
Then, 832 - x = x - 448
2x = 1280 => x = 640
Required S.P. = 150% of Rs. 640 = 150/100 * 640 = Rs. 960.
Answer: C
Question: At a certain college there are twice as many history majors as English majors and three times as many history majors as mathematics majors. What is the ratio of the number of english majors to the number of mathematics majors?
Options:
A)6 to 1
B)2 to 3
C)3 to 2
D)1 to 5
E)1 to 6
Rationale: This is how I translated the question:
At a certain college there are twice as many english majors as history majors
H = 2E
and three times as many english majors as mathematics majors.
H = 3M
What is the ratio of the number of history majors to the number of mathematics majors?
What is E:M?
Just set E equal to each other to get the ratio in terms of E and M.
2E = 3M
E/M = 3/2
The answer is 3:2
Answer : C
Answer: C
Question: Choose the missing terms out of the given alternatives.
AZ, BY, CX, DW, EV ?
Options:
A)EF
B)GH
C)ED
D)FU
E)KN
Rationale: D
FU
The first letter moves one step forward. The second letter moves one step backward.
Answer: D
Question: If 2|2 –a| = 5, what is the sum of all the possible values for a ?
Options:
A)1/2
B)2
C)5/2
D)4
E)5
Rationale: if a<2, then 2-a=5/2; a=-1/2
if a>2 , then a-2=5/2; a=9/2
9/2-1/2=8/2=4=D
Answer: D
Question: Carol and Blake invested 12000 and 24000, respectively in a business. Carol manages the business and for this he receives 9% of the profit while the rest is divided in proportion to their capitals. Find the share of Carol in a profit of 4000.
Options:
A)2573.3
B)1573.3
C)1565.3
D)2473.3
E)6573.3
Rationale: The Carol gets for managing
= 9% of Rs. 4000 = 360
Remaining profit = 4000 â€“ 360 = 3640
This is to be divided in the ratio 12000 :24000=12: 24=1:2.
Share of Carol = 1/3 of 3640 = 1213.3
â‡’ Total share of Carol = 360 + 1213.3 = 1573.3.
Answer B
Answer: B
Question: 6th March, 2005 is Monday, what was the day of the week on 6th March, 2004?
Options:
A)Friday
B)Saturday
C)Wednesday
D)Sunday
E)None of these
Rationale: Explanation :
Number of days from 6th March, 2004 to 5th March 2005 = 365 days
(Though Feb 2004 has 29 days as it is a leap year, it will not come in the required period)
365 days = 1 odd day
Given that 6th March, 2005 is Monday
Hence 6th March, 2004 = (Monday - 1 odd day) = Sunday
Answer : Option D
Answer: D
Question: To deliver an order on time, a company has to make 25 parts a day. After making 25 parts per day for 3 days, the company started to produce 5 more parts per day, and by the last day of work 100 more parts than planned were produced. Find how many parts the company made and how many days this took.
Options:
A)375
B)475
C)575
D)675
E)775
Rationale: Let x be the number of days the company worked. Then 25x is the number of parts they planned to make. At the new production rate they made:
3⋅25+(x−3)⋅30=75+30(x−3)
Therefore: 25x=75+30(x−3)−100
25x=75+30x−90−100
190−75=30x−25
115=5x
x=23
So the company worked 23 days and they made 23⋅25+100=675 pieces.
correct answer D
Answer: D
Question: Number of ways in which the letters of word PARDENS can be arranged with vowels in alphabetical order, is
Options:
A)360
B)240
C)2520
D)480
E)None of these
Rationale: Solution
Order of vowels of fixed
âˆ´ required number of ways are 7!/2!.
Answer C
Answer: C
Question: A man, a woman and a boy can complete a job in 3, 4 and 12 days respectively. How many boys must assist 1 man and 1 woman to complete the job in 1/4 of a day?
Options:
A)22
B)77
C)26
D)41
E)66
Rationale: (1 man + 1 woman)'s 1 day work = (1/3 + 1/4) = 7/12 Work done by 1 man and 1 woman in 1/4 day = (7/12 * 1/4) = 7/48
Remaining work = (1 - 7/48) = 41/48
Work done by 1 boy in 1/4 day = ( 1/12 * 1/4) = 1/48
Number of boys required = 41/48 * 41 = 41.
Answer: D
Answer: D
Question: A shopkeeper sold an article at $1200 and gained a 20% profit. What was the cost price?
Options:
A)$1000
B)$1020
C)$1040
D)$1060
E)$1080
Rationale: Let x be the cost price.
1.2x = 1200
x = 1200/1.2 = 1000
The answer is A.
Answer: A
Question: 10 books are placed at random in a shelf. The probability that a pair of books will always be together is ?
Options:
A)1/8
B)1/4
C)1/5
D)1/9
E)1/1
Rationale: 10 books can be rearranged in 10! ways consider the two books taken as a pair then number of favourable ways of getting these two books together is 9! 2!
Required probability = 1/5
Answer:C
Answer: C
Question: A and B invests Rs.8000 and Rs.12000 in a business. After 4 months, A withdraws half of his capital and 2 months later, B withdraws one-third of his capital. In what ratio should they share the profits at the end of the year?
Options:
A)32:99
B)82:31
C)8:15
D)34:89
E)35:21
Rationale: A : B
(8000*4)+(4000*8) : (12000*6)+(9000*6)
64000 : 120000
8 : 15
Answer:C
Answer: C
Question: How many different possible arrangements S can be obtained from the letters G, M, A, T, I, I, and T, such that there is at least one character between both I's?
Options:
A)360
B)720
C)900
D)1800
E)5040
Rationale: Total ways for arranging without restriction = 7!/ (2!2!) { 2! is becoz of two T's and other 2! for two I's)
Restriction : atleast one character between I's = Possible ways - both I's together i.e.o character between I's
_ _ _ _ _ (I I)
Both I's Together = 6! (Assuming 2 I's as one unit) /2!(for 2 T's) * 2! (No of arrangements of 2 I's)/2! (for 2 I's)
=6!/2!
Therefore ans S= 7!/ (2!2!) -6!/2! = 900
HENCE C.
Answer: C
Question: The average age of a group of 10 persons was decreased by 3 years when one person, whose age was 48 years, was replaced by a new person. Find the age of the new person?
Options:
A)18
B)56
C)12
D)17
E)14
Rationale: Initial average age of the 10 persons be P.
Age of the new person Q.
Sum of the ages of the initial 10 persons = 10P
New average
= (P-3) 10(P-3)
= 10P - 48 + Q
=> Q = 18
Answer:A
Answer: A
Question: A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If four marbles are picked at random, what is the probability that none is blue?
Options:
A)33/96
B)33/91
C)33/93
D)13/91
E)33/99
Rationale: Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles. When four marbles are picked at random, then the probability that none is blue is = (12 * 11 * 10 * 9)/(15 * 14 * 13 * 12) = 33/91.Answer: B
Answer: B
Question: Find the invalid no.from the following series 15, 16, 33, 105, 424, 2124, 12756
Options:
A)16
B)33
C)105
D)424
E)2124
Rationale: 2nd term = (1st term) * 1 + 1 = 15 *1 + 1 = 16.
3rd term = (2nd term) * 2 + 2 = 16 * 2 + 2 = 34
4th term = (3th term) *3 + 3 = 34 * 3 + 3 = 105
5th term = (4th term) * 4 + 4 = 105 * 4 + 4 = 424
6th term = (5th term) * 5 + 5 = 424 * 5 + 5 = 2125
3th term should 34 instead of 33.
B
Answer: B
Question: A shopkeeper sold two radio sets for 792 each, gaining 10% on one, and losing 10% on the other. Then he
Options:
A)neither gains nor loses
B)gains 1%
C)loses 1%
D)gains 5%
E)None of these
Rationale: Sol.(c) When selling price of two articles is same and
% gain = % loss
then there will be always loss.
and overall % loss = (10)2⁄100% = 1%. Answer C
Answer: C
Question: If x and y are numbers such that (x+5)(y-5)=0, what is the smallest possible value of x^2 + y^2
Options:
A)0
B)4
C)9
D)25
E)16
Rationale: From (x+5)(y-5)=0 it follows that either x=-5 or y=5. Thus either x^2=25 or y^2=25.
Now, if x^2=8125, then the least value of y^2 is 0, so the least value of x^2 + y^2 = 25 + 0 = 25.
Similarly if y^2=25, then the least value of x^2 is 0, so the least value of x^2 + y^2 = 0 + 25 = 25.
Answer: D.
Answer: D
Question: In how many different ways can the letters of the word ‘GEOMETRY’ be arranged so that the vowels always come together?
Options:
A)4323
B)2797
C)4320
D)2997
E)0811
Rationale: Explanation:
There are in all 8 letters in the given word of which 3 are vowels. As the vowels should always be together, considering the 3 vowels as one letter, there are in all 6
letters which can be arranged in 6! ways = 720
Also the 3 vowels can be arranged in 3! ways = 6
Total number of arrangements = 720*6 = 4320
ANSWER:C
Answer: C
Question: if(x-10)(y-5)(z-2)=1000 then what is the least value of x+y+z? if x,y,z are all integer no.
Options:
A)7
B)8
C)9
D)10
E)11
Rationale: (x-10)(y-5)(z-2)=1000
put x=0
y=-5
z=12
then
(0-10)(-5-5)(12-2)=1000
(-10)(-10)(10)=1000
1000=1000
ANSWER:A
Answer: A
Question: In a 4 person race, medals are awarded to the fastest 3 runners. The first-place runner receives a gold medal, the second-place runner receives a silver medal, and the third-place runner receives a bronze medal. In the event of a tie, the tied runners receive the same color medal. (For example, if there is a two-way tie for first-place, the top two runners receive gold medals, the next-fastest runner receives a silver medal, and no bronze medal is awarded). Assuming that exactly three medals are awarded, and that the three medal winners stand together with their medals to form a victory circle, how many S different victory circles are possible?
Options:
A)24
B)52
C)96
D)144
E)648
Rationale: Possible scenarios are:
1. Gold/Silver/Bronze/No medal (no ties) - 4!=24;
2. Gold/Gold/Silver/No medal - 4!/2!=12;
3. Gold/Silver/Silver/No medal - 4!/2!=12;
4. Gold/Gold/Gold/No medal - 4!/3!=4.
Total: 24+12+12+4=52
Answer: B.
Answer: B
Question: Jim and Reneeh will play one game of Rock, Paper, Scissors. In this game, each will select and show a hand sign for one of the three items. Rock beats Scissors, Scissors beat Paper, and Paper beats Rock. Assuming that both Jim and Reneeh have an equal chance of choosing any one of the hand signs, what is the probability that Jim will win?
Options:
A)5/6
B)2/3
C)1/2
D)5/12
E)1/3
Rationale: 1/3
probability of jim winning is basically the sum of three probabilities:
probability of jim picking rock and reneeh picking scissors = 1/3*1/3 = 1/9
probability of jim picking scissors and reneeh picking paper = 1/3*1/3=1/9
probability of jim picking paper and reneeh picking rock = 1/3*1/3=1/9
1/9 + 1/9 + 1/9 = 3/9 = 1/3=E
Answer: E
Question: In a cinema hall for the matinee show which started at 2.30 pm and ended at 5.30 pm the vehicle parking lot had only three wheelers (auto rickshaws) and four wheelers. Today the wheels of the vehicles parked was counted and found to be 240. What could be the number of three wheelers parked therein ?
Options:
A)10
B)48
C)37
D)97
E)12
Rationale: 3X + 4y = 240
by substitute through options 48 is correct
Answer: B
Answer: B
Question: How many cubes of 3cm edge can be cut out of a cube of 18cm edge
Options:
A)36
B)232
C)216
D)455
E)363
Rationale: number of cubes=(18 x 18 x 18) / (3 x 3 x 3) = 216
Answer: C
Answer: C
Question: A = {2, 3, 5, 7, 11}
B = {2, 4, 6, 13}
Two integers will be randomly selected from sets A and B, one integer from set A and one from set B, and then multiplied together. How many different products can be obtained?
Options:
A)15
B)16
C)19
D)20
E)36
Rationale: This would be the generic strategy:
Step 1: Find out the number of products you get.
5 distinct numbers in set A and 4 distinct in set B so number of products = 5*4 = 20
Step 2: Remove the products that appear more than once.
Notice that 5, 7, 11 and 13 are primes and none of their multiples are in either set. So ignore them. We just need to focus on 2 and 3 of set A and 2, 4 and 6 of set B.
2, 3
2, 4, 6
The only product repeated when you take a number from each set is 12. (3*4 and 2*6) Rest all are distinct.
Answer = 20 - 1 = 19
ANSWER:C
Answer: C
Question: Bruce purchased 7kg of grapes at the rate of 70 per kg and 9 kg of mangoes at the rate of 55 per kg. How much amount did he pay to the shopkeeper?
Options:
A)A)985
B)B)1050
C)C)1055
D)D)1065
E)E)1075
Rationale: Cost of 7 kg grapes = 70 × 7 = 490.
Cost of 9 kg of mangoes = 55 × 9 = 495.
Total cost he has to pay = 490 + 495 = 985
A
Answer: A
Question: If the reciprocals of two consecutive positive integers are added together, what is the sum in terms of the greater integer p?
Options:
A)(2p-1)/(p^3- p)
B)(2p-1)/(p^4- p)
C)(2p-1)/(p^2- p)
D)(2p-1)/(p^2- 2p)
E)(2p-4)/(p^2- 3p)
Rationale: Let two consecutive positive integers be p and p-1 (Greater integer is p)
So,
(1/p) + [1/(p-1)]
= (2p-1)/p(p-1)
=(2p-1)/(p^2- p)
Answer : C
Answer: C
Question: Two interconnected, circular gears travel at the same circumferential rate. If Gear A has a diameter of 20 centimeters and Gear B has a diameter of 50 centimeters, what is the ratio of the number of revolutions that Gear A makes per minute to the number of revolutions that Gear B makes per minute?
Options:
A)3:5
B)9:25
C)5:2
D)25:9
E)Cannot be determined from the information provided
Rationale: Same circumferential rate means that a point on both the gears would take same time to come back to the same position again.
Hence in other words, time taken by the point to cover the circumference of gear A = time take by point to cover the circumference of gear B
Time A = 2*pi*25/Speed A
Time B = 2*pi*10/Speed B
Since the times are same,
50pi/Speed A = 20pi/Speed B
SpeedA/Speed B = 50pi/30pi = 5/2
Correct Option: C
Answer: C
Question: If the price of a certain computer increased 30 percent from d dollars to 351 dollars, then 3d =
Options:
A)540
B)570
C)619
D)649
E)710
Rationale: Before Price increase Price = d
After 30% Price increase Price = d+(30/100)*D = 1.3d = 351 (Given)
i.e. d = 351/1.3 = $270
i.e. 3d = 3*270 = 710
Answer: option E
Answer: E
Question: The ratio of the ages of Anil and his son at present is 7 : 3. Six years hence, the ratio of the ages of the Anil's wife and the son will be 2 : 1. Find the ratio of the present ages of Anil and his wife?
Options:
A)270
B)266
C)209
D)298
E)277
Rationale: 12*8 :16*9 = 18*6
8: 12: 9
9/29 * 870 = 270
Answer: A
Answer: A
Question: Income and expenditure of a person are in the ratio 9 : 8. If the income of the person is Rs. 36000, then find his savings?
Options:
A)2000
B)3000
C)4000
D)5000
E)6000
Rationale: Let the income and the expenditure of the person be Rs. 9x and Rs. 7x respectively.
Income, 9x = 36000
=> x = 4000
Savings = Income - expenditure
= 9x - 8x = x
So, savings =Rs.4000.
Answer: C
Answer: C
Question: A and B started a business in partnership investing Rs. 20,000 and Rs. 15,000 respectively. After six months, C joined them with Rs. 20,000. What will be B's share in total profit of Rs. 25,000 earned at the end of 2 years from the starting of the business?
Options:
A)Rs. 7500
B)Rs. 9000
C)Rs. 9500
D)Rs. 10,000
E)None
Rationale: Solution: A : B : C = (20,000 * 24) : (15,000 * 24) : (20,000 * 18) = 4 : 3 : 3.
So B's share = Rs. (25000 * 3/10) = Rs. 7,500.
Answer: Option A
Answer: A
Question: If n is a positive integer and the product of all integers from 1 to n, inclusive, is a multiple of 650, what is the least possible value of n?
Options:
A)10
B)11
C)12
D)13
E)14
Rationale: 650 = 2 * 5 * 5 * 13
so the least value forNcan be 13.
D
Answer: D