divelab/Sys2Bench huggingface dataset:
Question: Two trains leave the same train station at 6:00 am and 7:15 am and they travel at 100 kph and 125 kph respectively. How many kilometers from the train station will the two trains be together?
Options:
A)525
B)550
C)575
D)600
E)625
Rationale: At 7:15, the first train is 125 km ahead.
The second train gains 25 km each hour.
The time it takes the second train to catch the first train is 125 / 25 = 5 hours.
In this time, the second train travels 5*125=625 km.
The answer is E.
Answer: E
Question: David mixed 10 kg of ghee at Rs. 200 per kg with 30 kg ghee at the rate of Rs. 100 per kg. At what price per kg should he sell the mixture to make a profit of 10% in the transaction?
Options:
A)Rs. 187.50
B)Rs. 147.50
C)Rs. 137.50
D)Rs. 127.50
E)Rs. 107.50
Rationale: Cost of Ghee = 10*200+ 30*100 /40 =5000/40 = 125
10% of 125 = 12.50
S.P. should be = 125+12.5= Rs. 137.50/ kg
Answer : C
Answer: C
Question: An athlete runs 200 metres race in 24 seconds. His speed is :
Options:
A)20 km/hr
B)24 km/hr
C)28.5 km/hr
D)30 km/hr
E)None of these
Rationale: Speed = 200/24 m/sec=25/3 m/sec=(25/3*18/5)km/hr=30 km/hr.
Correct Option: D
Answer: D
Question: On a sum of money, simple interest for 2 years is Rs 660 and compound interest is Rs 696.30, the
rate of interest being the same in both cases.
Options:
A)8%
B)9%
C)10%
D)11%
E)None of these
Rationale: Explanation:
Difference between C.I and S.I for 2 years = 36.30
S.I. for one year = 330.
S.I. on Rs 330 for one year = 36.30
So R% = \frac{100*36.30}{330*1} = 11%
Answer: D
Answer: D
Question: Three pipes of same capacity can fill a tank in 8 hours. If there are only two pipes of same capacity, the tank can be filled in.
Options:
A)16
B)12
C)18
D)15
E)19
Rationale: Explanation:
The part of the tank filled by three pipes in one hour = 1/8
=> The part of the tank filled by two pipes in 1 hour = 2/3 * 1/8 = 1/12.
The tank can be filled in 12 hours.
Answer:B
Answer: B
Question: What is the place value of 4 in the numeral 4259
Options:
A)4000
B)3000
C)2000
D)1000
E)5000
Rationale: 4* 1000 = 4000
ANSWER A
Answer: A
Question: The equation of line q is y = 4/3*x - 100. What is the smallest possible distance in the xy-plane from the point with coordinates (0, 0) to any point on line q?
Options:
A)48
B)50
C)60
D)75
E)100
Rationale: This can be solve in two steps and without any complex calculation.
Given : equation of line q as y=(4/3)x -100. So the line intercept the axes at (0,-100) and (75,0).
This can be considered a right angle triangle with right angle at (0,0) . So Base=100 , Height=75 and Hypotenuse =125 (By Pythagoras triplet)
So a perpendicular from the (0,0) to hypotenuse will be the answer.
Area of triangle= 0.5*100*75=0.5*125* x
=> x=60;
SO answer is 60=C
Answer: C
Question: A sum of money at simple interest amounts to Rs. 815 in 3 years and to Rs. 854 in 4 years. The sum is:
Options:
A)500
B)698
C)780
D)910
E)None
Rationale: Sol.
S.I. for 1 year = Rs. (854 - 815) = Rs. 39.
S.I. for 3 years = Rs. (39 * 3) = Rs. 117.
∴ Principal = Rs. (815 - 117) = Rs. 698
Answer B
Answer: B
Question: What is the next number in 0, 1, 1, 3, 1, 3, 1, 3, 5?
Options:
A)1
B)2
C)3
D)4
E)5
Rationale: C
1
As the series is 0, 1, 1, 3, 1, 3, 1, 3, 5....
It can clearly be observed that the sequence given is about the no of composite numbers between any two consecutive prime number.
That means all the no excluding the primes.
The series continues as 0, 1, 1, 3, 1, 3, 1, 3, 5,1,5,3,1,5,5,5,1,5.....
The answer to this question is 1
Answer: A
Question: A candidate got 35% of the votes polled and he lost to his rival by 2250 votes. How many votes were cast?
Options:
A)7500
B)2776
C)8767
D)1997
E)6991
Rationale: 35%-----------L
65%-----------W
------------------
30%----------2250
100%---------? => 7500
Answer: A
Answer: A
Question: A man buys 1kg of sandalwood and 1kg of teakwood. He sells one for 10% profit and other for 10% loss. What is total profit/loss percentage?
Options:
A)1% loss
B)2% loss
C)3% loss
D)4% loss
E)5% loss
Rationale: if x is both the profit and loss % then it must be loss of x^2/100;
so 10*10/100=1;
1% loss
ANSWER:A
Answer: A
Question: A number has exactly 32 factors out of which 4 are not composite. Product of these 4 factors (which are not composite) is 30. How many such numbers W are possible?
Options:
A)2
B)4
C)6
D)3
E)Not possible
Rationale: Firstly , we should note that 1 is NEITHER a prime nor a composite number.The first composite number is 4.Thus, when the problem states that there are 4 factors that are not composite, these nos are 1,2,3,5. Thus, the given number = 2^a*3^b*5^c. Also, (a+1)*(b+1)*(c+1) = 32. We can break down 32 into 3 integers as : 2*2*8 or 4*4*2
Also, the only possible combinations for a,b,c are : 3,3,1 OR 1,1,7. Thus, each combination has 3 possible orders and we have a total W of 6 possibilities.
C.
Answer: C
Question: The average age of 39 students in a group is 14 years. When teacher's age is included to it, the average increases by one. What is the teacher's age in years ?
Options:
A)35 years
B)45 years
C)51 years
D)54 years
E)None of these
Rationale: Explanation:
Age of the teacher = (40 * 15 - 39 * 14) years = 54 years. Answer: D
Answer: D
Question: Jordan and Morgan appeared at an examination. Jordan secured 9 marks more than Morgan and his marks was 56% of the sum of their marks. The marks obtained by them are:
Options:
A)39,30
B)39,30
C)42,33
D)43,34
E)None of these
Rationale: Explanation :
Let their marks be (x + 9) and x.
Then, x + 9 =0.56 (x + 9 + x)
=>25(x + 9) = 14(2x + 9)
=>3x = 99
=>x = 33
So, their marks are 42 and 33.
Answer : C
Answer: C
Question: Anil does a work in 90 days, Bittu in 40 days and Chintu in 12 days. They work one after another for a day each, starting with Anil followed by Bittu and then by Chintu. If the total wages received are Rs 360 and Anil, Bittu, Chintu share them in the ratio of the work done, find their respective individual wages.
Options:
A)Rs 40, Rs 60 and Rs 260
B)Rs 36, Rs 81 and Rs 243
C)Rs 42, Rs 86 and Rs 232
D)Rs 38, Rs 88 and Rs 234
E)none of these
Rationale: Let the total work done be 360 units.
Therefore, work done by Anil, Bittu and Chintu in single day are 4 units, 9 units and 30 units respectively.
Each of them working for 9 days Anil and Bittu will be able to complete 4 units and 9 units of their work on the 9th day but Chintu
will be doing remaining 3 units of work.
Hence, individual work done by them to complete the whole work is 36 units, 81 units and 243 units till the end of 9th day for each of them.
Thus, respective wages on the basis of work done is Rs 36, Rs 81 and Rs 243 respectively for Anil, Bittu and Chintu.
ANSWER:B
Answer: B
Question: A train 270 m long, running with a speed of 108 km / hr will pass a tree in
Options:
A)12 sec
B)9 sec
C)16 sec
D)20 sec
E)None
Rationale: Sol.
Speed = (108 x 5/18) m/sec.
= 30 m / sec.
Time taken = (270 x 1/30) sec = 9 sec
Answer B
Answer: B
Question: The no.of seats in a cinema hall is decreased by 5%, the price on the ticket also 5%. What is the effect on the revenue collected..??
Options:
A)-10%
B)+2.5%
C)-9.75%
D)+10.5%
E)+11.5%
Rationale: this can be esily solved by assuming
assume 100 seats n 100/- per seat
total revenue if all seats full-10000
now reduced by 5%
seats-95 price per seat-95
95x95=9025
therefore
loss=(975/10000)100 = 9.75%
ANSWER:C
Answer: C
Question: By selling 12 pencils for a rupee a man loses 20%. How many for a rupee should he sell in order to gain 20%?
Options:
A)8
B)9
C)7
D)5
E)2
Rationale: 80% --- 12
120% --- ?
80/120 * 12 = 8
Answer: A
Answer: A
Question: 26th January, 1996 was a Friday. What day of the week lies on 27th January, 1997?
Options:
A)Saturday
B)Sunday
C)Monday
D)Thursday
E)Friday
Rationale: SOLUTION :
The year 1996 was a leap year. Hence, it adds 3 odd days. As 26th January, 1996 was a Friday, 26th January, 1997 was a Sunday.
ANSWER IS C
Answer: C
Question: ((a+b)/c)/2
In the expression above, a, b, and c are different numbers and each is one of the numbers 2, 3, or 5. What is the least possible value of the expression?
Options:
A)2/10
B)5/10
C)10/5
D)7/6
E)6/7
Rationale: ((a+b)/c)/2
= (a+b)/2c
The expression will have the least value when numerator (a+b) is the smallest.
=(2+3)/2*5
=5/10
Answer B
Answer: B
Question: A person took some amount with some interest for 7 years, but increase the interest for 1%, he paid Rs.700/- extra, then how much amount he took?
Options:
A)Rs.5500/-
B)Rs.6000/-
C)Rs.4000/-
D)Rs.7000/-
E)None of these
Rationale: Explanation:7 years = Rs.700/-year = 700/7Rate of Interest = 1%100/1% × 700/7 = Rs.1000/-P = Rs.1000/- Answer: Option E
Answer: E
Question: X, Y, and Z are different prime numbers. The product X^3*Y^2*Z^1 is divisible by how many different positive numbers?
Options:
A)24
B)30
C)36
D)42
E)48
Rationale: The exponents of X^3*Y^2*Z^1 are 3, 2, and 1.
The number of factors is (3+1)(2+1)(1+1) = 24
The answer is A.
Answer: A
Question: A machine puts c caps on bottles in m minutes. How many W hours will it take to put caps on b bottles?
Options:
A)60bm/c
B)W=bm/60c
C)bc/60m
D)60b/cm
E)b/60cm
Rationale: The machine puts c caps in m minutes or c caps in m/60 hours.
Rate = c/m/60 = 60c/m.
To put b caps the machine CCwill take:-
Time = Work/Rate
T = b/60c/m = bm/60c
Answer is B.
Answer: B
Question: The number of the members of a club is more than 50 and less than 80. When 5 people sit at a table, other people exactly divided to 8-people groups (8 people sit at a table) or 7-people groups (7 people sit at a table). If the members are divided to 9-people groups, how many people will be left?
Options:
A)4
B)5
C)6
D)7
E)8
Rationale: The number of members is 7k+5 = 8j+5
The only number in this range which satisfies this is 61.
61/9 = 6(9) + 7
The answer is D.
Answer: D
Question: A certain company consists of 5 managers and 8 non-managers. How many different teams of 3 employees can be formed in which at least one member of the team is a manager and at least one member of the team is not a manager? (Two groups are considered different if at least one group member is different)
Options:
A)84
B)108
C)135
D)220
E)990
Rationale: Total # of teams of 3 possible is 13C3=286
# of teams with only managers or only non-managers is: 5C3+8C3=10+56=66;
# of teams of 3 with at least one manager or at least one non-manager is: 286-66=220.
ANSWER:D
Answer: D
Question: A hat company ships its hats, individually wrapped, in 8-inch by 10-inch by 12-inch boxes. Each hat is valued at $7.50. If the company’s latest order required a truck with at least 288,000 cubic inches of storage space in which to ship the hats in their boxes, what was the minimum value of the order?
Options:
A)$960
B)$1,350
C)$1,725
D)$2,050
E)$2,250
Rationale: Total Volume is 288000
Given LBH = 8*10*12.
the number of hats inside it = 288000/10 * 8 * 12 = 300.
price of each hat is 7.5 $ then total value is 300 * 7.5 = 2250.
Answer: option E is correct answer..
Answer: E
Question: 385, 462, 572, 396, 428, 671, 264
Options:
A)385
B)428
C)671
D)264
E)None of these
Rationale: Solution
In each number except 428,the middle digit is the sum of the other two. Answer B
Answer: B
Question: 8k8
+ k88
--------
1,6w6
If k and w represent non-zero digits within the integers above, what is w?
Options:
A)6
B)7
C)8
D)9
E)17
Rationale: 8k8
k88
--------
16w6
Trial and error or just plug-in method might be the shortest way to solve this problem. Though you can narrow down the possible values of k to just two: 7 and 8 --> 8**+7**=16** or 8**+8**=16** (k can not be less than 7 or 9, as the result won't be 16**). After that it's easy to get that k=7 and w=6.
Answer: A.
Answer: A
Question: If in a race of 110m, A covers the distance in 20 seconds and B in 25 seconds, then A beats B by:
Options:
A)20m
B)16m
C)11m
D)22m
E)15m
Rationale: Explanation:
The difference in the timing of A and B is 5 seconds. Hence, A beats B by 5 seconds.
The distance covered by B in 5 seconds = (110 * 5) / 25 = 22m
Hence, A beats B by 22m.
ANSWER D
Answer: D
Question: Marcella has 20 pairs of shoes. If she loses 9 individual shoes, what is the greatest number of matching pairs she could have left?
Options:
A)21
B)20
C)19
D)16
E)15
Rationale: Marcella has 20 pairs of shoes and loses 9 shoes.
To minimize the loss of identical pairs of shoes we want Marcella to lose as many identical pairs as possible. This would yield 4 identical pairs and 1 additional shoe (destroying 5 pairs of shoes).
The 20 pairs of shoes minus the 5 'destroyed' pairs yields 15 pairs that still fulfill the requirements.
Answer: E
Answer: E
Question: Tabby is training for a triathlon. She swims at a speed of 1 mile per hour. She runs at a speed of 8 miles per hour. She wants to figure out her average speed for these two events. What is the correct answer for her?
Options:
A)8 mph
B)5.25 mph
C)3.5 mph
D)4.5 mph
E)0.5 mph
Rationale: (1 mph +8 mph)/2 = 4.5 mph
Correct option is: D
Answer: D
Question: Excluding stoppages, the speed of a bus is 62 kmph and including stoppages, it is 56 kmph. For how many minutes does the bus stop per hour?
Options:
A)70 min
B)16 min
C)7 min
D)6 min
E)40 min
Rationale: D
10 min
Due to stoppages, it covers 6 km less.
Time taken to cover 6 km = (6/62 x 60) min = 6 min
Answer: D
Question: A warehouse is labeling computer inventory with 4-digit codes. Each code is to consist of four digits between the numbers 0 and 8. The manager is debating whether to allow any 4-digit codes to have leading zero's before a non-zero number is used. If not allowed, then numbers like0025cannot be used.
The manager wants to measure the magnitude of the number of 4-digit code possibilities that are lost if he disallows the use of leading zero's. How many such codes would be lost?
Options:
A)981
B)2000
C)1011
D)1101
E)1110
Rationale: The number of codes possible if leading zero is allowed = 10*10*10*10=10^4
The number of codes possible if leading zero is NOT allowed = 8*10*10*10=9*10^3
The difference = 10^4 - 8*10^3 = 10^3(10-8) = 2*10^3.
Answer: B.
Similar questions to practice:
Hope it helps.
Answer: B
Question: A factory has 500 workers, 20 percent of whom are women. If 50 additional workers are to be hired and all of the present workers remain, how many of the additional workers must be women in order to raise the percent of women employees to 20 percent?
Options:
A) 3
B) 10
C) 25
D) 30
E) 35
Rationale: Currently the factory has 0.20*500=100 women.
After 50 additional workers are hired, there will be total of 550 workers and we need 0.2*550=110 of them to be women, so we need 110-100=10 more women.
Answer: B.
Answer: B
Question: In a certain province in Italy there are 15 cities. If a single road segment connects only two cities, how many road segments are required in order to connect the cities so that each city is connected to all other cities with a single road segment?
Options:
A)30
B)105
C)330
D)14!
E)15!
Rationale: Method-1:
Italy Total Cities = 15 and each city should be connected with every other city
So Total Roads required to connect 1st City with other 14 cities = 14
Now 1st City is connected with all other cities so,
So Total Roads required to connect 2nd City with 13 cities (Other than 1st) = 13
Now 1st and 2nd Cities are connected with all other cities so,
So Total Roads required to connect 3rd City with 12 cities (Other than 1st, and 2nd) = 12
......and so on...
Total Roads required = 14 + 13 + 12 + 11 + 10 + 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 = 105=B
Answer: B
Question: If a number between 1 and 60 (inclusively) is chosen randomly, what are the odds that it is divisible by 5 or 8?
Options:
A)1/4
B)7/30
C)17/60
D)3/10
E)4/15
Rationale: P(5á´œ8) = P(5) + P(8) - P(5âˆ©8), where S denotes divisible by 5 and 8 denotes divisible by 8.
P(5á´œ8) = 12/60 + 7/60 - 1/60
= 3/10
Answer: D
Answer: D
Question: Sreenivas sells a table to Shiva at 10% profit and Shiva sells it to Mahesh at 10% loss. At what price did Sreenivas purchase the table if Mahesh paid Rs. 3168?
Options:
A)2277
B)3200
C)2200
D)2766
E)2998
Rationale: Let the cost price of table for Sreenivas be Rs. x and given that, cost price of table for Mahesh = Rs. 3168.
=> (90%) of (110%) of x = Rs. 3168.
=> (90/100)(110/100)x = 3168
=> x = (3168 * 100)/(9 * 11)
=> x = Rs. 3200
Answer: B
Answer: B
Question: P starts a business with Rs. 4,000. After 4 months, Q joins with P as his partner.
After a year, the profit is divided in the ratio 2 : 3. Q's contribution in the capital is ?
Options:
A)Rs. 7,000
B)Rs. 11,000
C)Rs. 8,000
D)Rs. 10,000
E)Rs. 9,000
Rationale: Solution: Let's Q's capital is x.
P : Q = (4,000 * 12): (x : 8) = 2 : 3 .
So Q's share = (4000 * 12/8x) = 2/3
=> x = (4000 * 12 * 3)/(2 * 8) =Rs. 9,000
Answer: Option E
Answer: E
Question: The average (arithmetic mean) of all scores on a certain algebra test was 90. If the average of the 8 male students’ grades was 85, and the average of the female students’ grades was 92, how many female students took the test?
Options:
A)8
B)9
C)10
D)11
E)20
Rationale: Total Marks of male = M
Total Marks of female = F
Number of males = 8
Number of females = f
Given: (M+F)/(8+f) = 90 -------------1
Also given, M/8 = 85 Thus M = 680 ---------2
Also, F/f = 92 thus F = 92 F - --------3
Put 2 and 3 in 1: we get
(680+92f)/(8+f) = 90
solving this we get f = 20
Ans: E
Answer: E
Question: Let T be the set of integers { 3, 11, 19, 27, ..., 451, 459, 467 } and S be a subset of T such that the sum of no two elements of S is 470. The maximum possible number of elements in S is
Options:
A)32
B)28
C)29
D)30
E)None of these
Rationale: Explanation :
At first, let's find the number fo integers in the given series.
=> Tn = a + (n - 1) d.
=> 467 = 3 + (n - 1) 8.
=> 464/8 = n - 1.
=> 58 + 1 = n. i.e n = 59.
If we closely observe the given set 3 + 467 = 11 + 459 = .... = 470.
The total number of elements in the given set = 59.
This means that we have 59/2 i.e 29 pairs of values that add to 470, and one lone number (235) that has no other number to pair up with.
So, We have 29 prohibited number pairs: (3 and 467), (11 and 459), (19 and 451), . . .
We can take 1 number from each of these pairs, so we can have 29 numbers in set S.
PLUS we can have the lone number 235.
So, set S can have a maximum of 29+1 i.e 30 numbers.
Answer : D
Answer: D
Question: What is the place value of 7 in the numeral 2734?
Options:
A)600
B)650
C)700
D)750
E)770
Rationale: Option 'C'
7 * 100 = 700
Answer: C
Question: what is the remainder when 50! is divided by 16^8??
Options:
A)0
B)1
C)2
D)3
E)4
Rationale: 16 raise to 8=2 raise to 32, now highest power of 2 divisible by 50! Is 25+12+6+3+1=47
Since 2 raise to 47 is divisible, 2 raise to 32 also will be divisible
ANSWER:A
Answer: A
Question: 765.765 - ? + 46.82 = 437.785
Options:
A)A)374.80
B)B)752.804
C)C)714.642
D)D)629.906
E)of these
Rationale: Explanation:
374.80
Answer: Option A
Answer: A
Question: In 10 years, A will be twice as old5as B was 10 years ago. If A is now 12 years older than B, the present age of B is
Options:
A)35
B)37
C)39
D)41
E)42
Rationale: Explanation:
Let B's age = x years.
Then, As age = (x+ 12) years.
(x+12+10)=2(x—10)
hence x=42.
Present age of B = 42 years
Answer: Option E
Answer: E
Question: There are 14 teams in a soccer league and each team plays each of the other teams once. How many games will be played in total?
Options:
A)87
B)91
C)95
D)99
E)103
Rationale: 14C2=91
The answer is B.
Answer: B
Question: With both inlets open, a water tank will be filled with water in 42 minutes. The first inlet alone would fill the tank in 2 hours. If in every minutes the second inlet admits 50 cubic meters of water than the first, what is the capacity of the tank ?
Options:
A)7,000
B)10,500
C)11,750
D)12,000
E)13,000
Rationale: The work Done by Inlet A and B together in 1 min = 1/42
The work Done by Inlet A (First Inlet) in 1 min = 1/120
The work Done by Inlet B (Second Inlet) in 1 min = (1/42)- (1/120) =1/65
DIfference of Work done by B and A = B - A = 50 Cubic meter
i.e. (1/65)- (1/120) = 50 Cubic meter
= 7000 Cubic Meter
Answer: option A
Answer: A
Question: How long will it take for a sum of money to grow from Rs.1250 to Rs.10,000, if it is invested at 12.5% p.a simple interest?
Options:
A)8 years
B)64 years
C)72 years
D)56 years
E)None
Rationale: Solution:
Simple interest is given by the formula SI = (pnr/100), where p is the principal, n is the number of years for which it is invested, r is the rate of interest per annum
In this case, Rs. 1250 has become Rs.10,000.
Therefore, the interest earned = 10,000 – 1250 = 8750.
8750 = [(1250*n*12.5)/100]
=> n = 700 / 12.5 = 56 years.
Answer D
Answer: D
Question: A Jon's company that sells only cars and trucks reported that revenues from car sales in 1997 were down 11 percent from 1996 and revenues from truck sales were up 7 percent from 1996. If total revenues from car sales and truck sales in 1997 were up 1 percent from 1996, what is the ratio of revenue from car sales in 1996 to revenue from truck sales in 1996?
Options:
A) 1:2
B) 4:5
C) 1:1
D) 3:2
E) 5:3
Rationale: A Jon's company that sells only cars and trucks reported that revenues from car sales in 1997 were down 11 percent from 1996 and revenues from truck sales were up 7 percent from 1996.1996- x----- y------- x+y
1997- x1---- y1-- x1+y1
x1= a*x .....(P)
y1= 1.07*y...(Q)
x1+y1/x+y = 1.01
solve using P and Q and find x/y
Answer: A
Question: A car moves at 98 km/hr. What is the speed of the car in meters per second ?
Options:
A)20 2/9m sec
B)22 2/9m sec
C)24 2/9m sec
D)27 2/9m sec
E)28 2/9m sec
Rationale: Explanation:
Speed=(98∗5/18)m/sec
=245/9 m/sec
=27 2/9msec
Option D
Answer: D
Question: By selling a bat for Rs. 640/- a man loses 20% what is that bat cost price
Options:
A)Rs.800/-
B)Rs.820/
C)Rs.840/
D)Rs.860/
E)Rs.870/
Rationale: Explanation:
80 % ------> 640 (80 * 8 = 640)
100 % ------>800 (100 * 8 = 800)
Cost price = Rs.800/-
Answer: Option A
Answer: A
Question: The perimeter of a square is 28 cm. What is the perimeter of a circle whose radius is equal to the side of the square?(in cm)
Options:
A)14
B)28
C)42
D)44
E)56
Rationale: Side of the square=28/4=7
Diameter of the circle=7x2=14
Perimeter of the circle= Ï€xD=(22/7)x14 = 44cm
Answer: D
Answer: D
Question: How many zeros does 100! end with?
Options:
A)20
B)24
C)25
D)30
E)32
Rationale: According to above 100! has 100/5+100/25=20+4=24 trailing zeros.
Answer: B.
Answer: B
Question: E = {2, 3, 4, 5}
B = {4, 5, 6, 7, 8}
Two integers will be randomly selected from the sets above, one integer from set E and one integer from set B. What is the probability that the sum of the two integers will equal 9 ?
Options:
A) 0.15
B) 0.20
C) 0.25
D) 0.30
E) 0.33
Rationale: The total number of pairs E,B possible is 4*5=20. Out of these 20 pairs only 4 sum up to 9: (2, 7); (3, 6), (4, 5) and (5, 4). The probability thus is 4/20=0.2.
Answer: B.
Answer: B
Question: In how many years will a sum of money doubles itself at 25% per annum on simple interest?
Options:
A)8%
B)2%
C)3%
D)4%
E)5%
Rationale: P = (P*25*R)/100
R = 4%
ANSWER:D
Answer: D
Question: A,B,C together can do a work in 30 days. A alone can do the work in 80 days and B alone can do the same work in 100 days. Find in what time C alone can do that work?
Options:
A)75days
B)85.65days
C)88.50days
D)92.31days
E)96days
Rationale: The required answer is = 30*80*100 / 80*100-30(80+100)
= 240000/2600 = 92.31days
Answer is D
Answer: D
Question: An unbiased die is tossed. Find the probability of getting a multiple of 5
Options:
A)A)1/3
B)B)2/5
C)C)1/6
D)D)2/3
E)E)3/7
Rationale: Here S = {1,2,3,4,5,6}
E = event of getting a multiple of 5
E = {5}
P(E) = 1/6
Answer is C
Answer: C
Question: What will come in place of the question mark (?) in the following questions?
22% of ? + 166.64 = 340
Options:
A)790
B)548
C)888
D)788
E)980
Rationale: D
788
(?*22)/100 = 340 - 166.64 = 173.36
? = (173.36 * 100)/22
? = 788
Answer: D
Question: Mangala completes a piece of work in 12 days, Raju completes the same work in 36 days. If both of them work together, then the number of days required to complete the work is?
Options:
A)5 days
B)6 days
C)7 days
D)8 days
E)9 days
Rationale: If A can complete a work in x days and B can complete the same work in y days, then, both
of them together can complete the work in x y/ x+ y days.
That is, the required No. of days = 12 Ã— 36/48 = 9 days.
E)
Answer: E