divelab/Sys2Bench huggingface dataset:
Question: January 1, 2008 is Tuesday. What day of the week lies on Jan. 1, 2009 ?
Options:
A)Monday
B)wednesday
C)Thursday
D)Sunday
E)None of these
Rationale: Solution
The year 2008 is a leap year. So, it has 2 odd day.
1st day of the year 2008 is Tuesday(Given)
so,1st day of the year 2009 is 2 days beyond Tuesday.
Hence, it will be Thursday. Answer C
Answer: C
Question: How many times are the hands of a clock at right angle in 6 hours?
Options:
A)9
B)10
C)11
D)12
E)13
Rationale: In 12 hours, they are at right angles 22 times.
In 6 hours, they are at right angles 11 times. Answer: Option C
Answer: C
Question: If Tim had lunch at $50.50 and he gave 20% tip, how much did he spend?
Options:
A)$57.45
B)$35.42
C)$60.60
D)$21.56
E)$78.45
Rationale: The tip is 20% of what he paid for lunch.
tip = 20% of 50.50 = (20/100)*50.50 = 101/100 = $10.10
Total spent
50.50 + 10.10 = $60.60
correct answer is C)$60.60
Answer: C
Question: A train running at the speed of 60 km/hr crosses a pole in 12 sec. What is the length of the train?
Options:
A)118
B)150
C)277
D)200
E)191
Rationale: Speed = 60 * 5/18 = 50/3 m/sec
Length of the train = speed * time = 50/3 * 12 = 200 m
Answer: D
Answer: D
Question: There are 100 students in a college class of which 36 are boys studying Tamil & 13 girls not studying Tamil. If there are 55 girls in all, then the probability that a boy picked up at random is not studying Tamil, is
Options:
A)1/5
B)2/3
C)3/5
D)3/7
E)4/9
Rationale: There are 55 girls and 45 boys in the college. Out of 45 boys, 36 are studying Tamil and 9 are not studying Tamil. The probability that a boy picked up at random is not studying Tamil= 9/45 = 1/5
A
Answer: A
Question: In how much time would the simple interest on a certain sum be 0.125 times the principal at 10% per annum?
Options:
A)1 1/4
B)1 1/6
C)1 1/0
D)1 1/5
E)1 5/1
Rationale: Let sum = x. Then, S.I. = 0.125x = 1/8 x, R = 10%
Time = (100 * x) / (x * 8 * 10) = 5/4 = 1 1/4 years.Answer: A
Answer: A
Question: David obtained 96, 95, 82, 97 and 95 marks (out of 100) in English, Mathematics,Physics, Chemistry and Biology What are his average marks ?
Options:
A)75
B)95
C)93
D)165
E)11
Rationale: Explanation:
Average = (96+ 95+ 82+ 97 + 95 )/ 5 = 465/5 = 93.
Answer:C
Answer: C
Question: Some of 40%-intensity red paint is replaced with 20% solution of red paint such that the new paint intensity is 20%. What fraction of the original paint was replaced?
Options:
A)2/5
B)2/3
C)1/3
D)1/2
E)1/1
Rationale: Let total paint = 1
Let amount replaced = x
40 (1-x) + 20x = 20
x = 1/1
ANSWER:E
Answer: E
Question: In what time will a railway train 60 m long moving at the rate of 36 kmph pass a telegraph post on its way?
Options:
A)6 sec
B)7 sec
C)2 sec
D)1 sec
E)5 sec
Rationale: t= 60/36* 18/5 = 6 sec
ANSWER A
Answer: A
Question: If QUESTION = DOMESTIC what will b code for RESPONSE ?
Options:
A)OMESICEM
B)HSDUISAH
C)SSIDFUGD
D)SDIFUGAU
E)UIDFGWIW
Rationale: Explanation:
Q U E S T I O N
D O M E S T I C
We can see in the word 'RESPONSE' only R and P are the letters whose code is not given, by having a look on options we can say code for R is O and code for P is S (because common in all options).
Now we can easily code the word 'RESPONSE'as 'OMESICEM'.
Answer : A
Answer: A
Question: A coin is tossed three times. What is the probability that there is at the least one tail?
Options:
A)7/8
B)6/7
C)1/7
D)3/7
E)1/31
Rationale: Let P(T) be the probability of getting least one tail when the coin is tossed three times.
= There is not even a single tail.
i.e. all the outcomes are heads.
= 1/8 ; P(T) = 1 - 1/8
= 7/8
Answer: A
Answer: A
Question: A can do a job in 16 days, B can do same job in 12 days. With the help of C they did the job in 4 days. C alone can do the same job in how many days ?
Options:
A)6 1/2days
B)7 1/2days
C)8 3/5days
D)9 3/5days
E)10 1/2 days
Rationale: Explanation:
In this question we having, A's work, B's work and A+B+C work. We need to calculate C's work.
We can do it by,
(A+B+C)'s work - (A's work + B's work).
Let's solve it now:
C's 1 day work =
1/4−(1/16+1/12)=(1/4−7/48)=5/48
So C can alone finish the job in 48/5 days,
Which is =
9 3/5days
Option D
Answer: D
Question: If x^3 > y^2 = z, which of the statements could be true?
I. x < y < z
II. x < z < y
III. y < x < z
Options:
A)I only
B)III only
C)I and II only
D)II and III only
E)I, II and III
Rationale: Given : x^3 > y^2 = z
I. x < y < z is not true for x=3, y=2, z=4
II. x < z < y is not true for x=3, y=2, z=4
III. y < x < z is true for x=3, y=2, z=4 i.e. Answers can only be Options E
Answer: option B
Answer: B
Question: Two trains of equal length are running on parallel lines in the same directions at 46km/hr. and 36km/hr. The faster trains pass the slower train in 108 seconds. The length of each train is:
Options:
A)82m
B)50m
C)72m
D)150m
E)None of these
Rationale: Explanation:
The relative speed of train is 46-36 = 10 Km/hr = (10 X 5) / 18 = 25/9 m/s10×518=259m/s
In 108 secs the total distance traveled is 108x25/9 = 300 m.
Therefore the length of each train is = 300/2 = 150 m.
Answer D
Answer: D
Question: A train starts full of passengers at the first station it drops 1/3 of the passengers and takes 280 more at the second station it drops one half the new total and takes twelve more. On arriving at the third station it is found to have 248 passengers. Find the no of passengers in the beginning?
Options:
A)292
B)180
C)192
D)144
E)168
Rationale: Let no of passengers in the beginning be X
After first station no passengers=(X-X/3)+280=2X/3 +280
After second station no passengers =1/2(2X/3+280)+12
1/2(2X/3+280)+12=248
2X/3+280=2*236 = 472 - 280 = 192
2X/3=192
X=288. So the answer is option C) 192.
Answer: C
Question: The total marks obtained by a student in Physics, Chemistry and Mathematics is 150 more than the marks obtained by him in Physics. What is the average mark obtained by him in Chemistry and Mathematics?
Options:
A)75
B)65
C)29
D)26
E)12
Rationale: Let the marks obtained by the student in Physics, Chemistry and Mathematics be P, C and M respectively.
P + C + M = 150 + P
C + M = 150
Average mark obtained by the student in Chemistry and Mathematics
= (C + M)/2 = 150/2
= 75.
Answer:A
Answer: A
Question: 20/25 = 4/5 . which method did you use to determine whether this proportion is true or false?
Options:
A)true
B)neutral
C)false
D)not sure
E)none
Rationale: 20/25= 4/5 cross multiplication: 20 * 5= 100, 4 * 25 =100,
we see that 100 are not equal to 100. so there is proportion. corrcet answer: (A)
Answer: A
Question: 1, 4, 9, 16, 25, ?
Options:
A)35
B)36
C)48
D)49
E)50
Rationale: The sequence is a series of squares, 12, 22, 32, 42, 52....
Answer : B.
Answer: B
Question: If f1(x)=f(x)=12xf1(x)=f(x)=12x and fn(x)=f(fn−1(x)fn(x)=f(fn−1(x), then find f5(x)+f10(x)f5(x)+f10(x) where x = 1
Options:
A)3/9
B)3/2
C)3/1
D)3/3
E)3/4
Rationale: f(x) = 12x12x and f(f(x)) = f(12x)f(12x) = 12(12x)12(12x) = x
Similarly f3(x)=f(f2(x))=f(x)=12xf3(x)=f(f2(x))=f(x)=12x and f4(x)=f(f3(x))=f(12x)=12×12x=xf4(x)=f(f3(x))=f(12x)=12×12x=x
Hence fn(x)=12xfn(x)=12x for n = odd and fn(x)=xfn(x)=x for n = even
f5(x)+f10(x)=12x+xf5(x)+f10(x)=12x+x
If x = 1, ⇒12×1+1=3/2
Answer:B
Answer: B
Question: A shopkeeper labels the price of articles 20% above the cost price. If he allows 31.20 off on a bill of 312, find his profit per cent on the article?
Options:
A)8
B)12 1⁄3
C)11 2⁄3
D)8 1⁄3
E)None of these
Rationale: Let the CP = 100 Marked price = 120
Discount = 312⁄31.2 × 1⁄100 = 10% = 12
SP = 120 – 12 = 108 Profit% = 108 – 100 = 8%
Answer A
Answer: A
Question: A building contractor employs 20 male, 15 female and 5 child workers. To a male worker he pays Rs.25 per day, to a female worker Rs.20 per day and a child worker Rs.8 per day. The average wage per day paid by the contractor is?
Options:
A)22
B)21
C)77
D)88
E)66
Rationale: 20 15 5
25 20 8
500 + 300 + 40 = 840/40 = 21
Answer: B
Answer: B
Question: 3x^2-6x+3 = 0 Find the above equation find the value of x
Options:
A)0
B)1
C)3
D)4
E)5
Rationale: a = 3, b = -6, c = 3
x1,2 = (6 ± √( (-6)2 - 4×3×3)) / (2×3) = (6 ± √(36-36)) / 6 = (6 ± 0) / 6
x1 = x2 = 1
B
Answer: B
Question: A man rows his boat 85 km downstream and 45 km upstream, taking 2 1/2 hours each time. Find the speed of the stream?
Options:
A)7 kmph
B)9 kmph
C)3 kmph
D)8 kmph
E)2 kmph
Rationale: Speed downstream = d/t = 85/(2 1/2) = 34 kmph
Speed upstream = d/t = 45/(2 1/2) = 18 kmph
The speed of the stream = (34 - 18)/2 = 8 kmph.Answer: D
Answer: D
Question: There are two groups of students in the sixth grade. There are 45 students in group A, and 55 students in group B. If, on a particular day, 20% of the students in group A forget their homework, and 40% of the students in group B forget their homework, then what percentage of the sixth graders forgot their homework?
Options:
A)23%
B)25%
C)29%
D)31%
E)36%
Rationale: Number of students in group A = 45
students who forget homework in group A = 20 % of 45 = 9 students
Number of students in group B = 55
students who forget homework in group B = 40 % of 55 = 22 students
Total number of students = 45 + 55 = 100
students who forgot homework = 9 + 22 = 31 students
percentage of students who forget homework = 31/100 * 100 = 31%
Answer: D
Answer: D
Question: Seven men and seven women have to sit around a circular table so that no 2 women are together. In how many different ways can this be done?
Options:
A)6!*7!
B)136!*7!
C)356!*7!
D)366!*7!
E)566!*7!
Rationale: Yes, the solution given above is correct. Think of it this way:
There are 7 men: Mr. A, Mr. B .....
and 7 women: Ms. A, Ms. B ....
14 seats around a circular table.
You seat the 7 women such that no two of them are together so they occupy 7 non-adjacent places in 6! ways. For the first woman who sits, each seat is identical. Once she sits, each seat becomes unique and when the next woman sits, she sits in a position relative to the first woman (e.g. 1 seat away on left, 3 seats away on right etc)
The 7 men have 7 unique seats to occupy. Each of the 7 seats are unique because they have a fixed relative position (e.g. between Ms. A and Ms. B or between Ms. C and Ms. B etc...). So the men can sit in 7! ways.
Total 6!*7! ways.
ANS:A
Answer: A
Question: Find the odd man out
4, 9,16, 36, 64, 144
Options:
A)144
B)16
C)9
D)36
E)4
Rationale: 9 is square of 3 which is odd number where as all others are squares of even numbers.
ANSWER:C
Answer: C
Question: 3 friends A, B, C went for week end party to McDonald’s restaurant and there they measure there weights in some order In 7 rounds. A, B, C, AB, BC, AC, ABC. Final round measure is 140kg then find the average weight of all the 7 rounds?
Options:
A)98.5 kgs
B)80 kgs
C)76.5 kgs
D)67.5 kgs
E)58.2 kgs
Rationale: Average weight = [(a + b + c + (a+b) + (b+c) + (c+a)+(a+b+c)] / 7 = 4 (a+b+c) /7 = 4 x 140/7 = 80 kgs
Answer:B
Answer: B
Question: Let C be defined as the sum of all prime numbers between 0 and 30. What is C/3
Options:
A)155
B)129
C)61
D)47
E)43
Rationale: Prime numbers between 0 and 30 - 2 , 3 , 5 , 7, 11 , 13 , 17 , 19 , 23 , 29
Sum,C = 129
C/3 = 43
Answer E
Answer: E
Question: A shopkeeper sells his goods at cost price but uses a faulty meter that weighs 950 grams. Find the profit percent.
Options:
A)100/18%
B)100/17%
C)100/16%
D)100/19%
E)100/13%
Rationale: Explanation:
(100 + g) / (100 + x) = True measure / Faulty measure
x = 0
true measure = 1000
faulty measure = 950
100 + g / 100 + 0 = 1000 / 950
100+g = 20/19*100
g = 100/19 %
ANSWER: D
Answer: D
Question: What distance will be covered by a bus moving at 36 kmph in 30 seconds?
Options:
A)287
B)600
C)289
D)300
E)207
Rationale: 36 kmph = 36 * 5/18
= 10 mps
D = Speed * time = 10 * 30
= 300 m.
Answer:D
Answer: D
Question: Rs.8000 become Rs.11256 in a certain interval of time at the rate of 5% per annum of C.I. Find the time?
Options:
A)6 YEARS
B)7
C)5
D)3
E)4
Rationale: Explanation:
11256 = 8000(21/20)N
(21/20)7 = (21/20)N => N = 7
Answer: Option B
Answer: B
Question: In N is a positive integer less than 200, and 14N/60 is an integer, then N has how many different positive prime factors?
Options:
A)2
B)3
C)5
D)6
E)8
Rationale: 14n/60 must be an integer. => 7n/30 must be an integer. Hence n must be a multiple of 2*3*5.
=> n has 3 different prime integers and cannot have more than 3 different prime integers because 2*3*5*7=210 > 200 ANSWER:B
Answer: B
Question: The length of rectangle is thrice its breadth and its perimeter is 96 m, find the area of the rectangle?
Options:
A)432
B)672
C)278
D)266
E)261
Rationale: 2(3x + x) = 96
l = 36 b = 12
lb = 36 * 12 = 432
Answer: A
Answer: A
Question: Month	Average Price
per Dozen
April $1.26
May $1.20
June $1.08
The table above shows the average (arithmetic mean) price per dozen of the large grade A eggs sold in a General store during three successive months. If 2/3 as many dozen were sold in April as in May, and twice as many were sold in June as in April, what was the average price per dozen of the eggs sold over the three-month period?
Options:
A)1.4
B)1.3
C)1.2
D)1.1
E)1.16
Rationale: Say x dozen eggs were sold in May.
Then 2x/3 dozen eggs were sold in April and 2*2x/3=4x/3 dozen eggs were sold in May.
Total x+2x/3+4x/3=3x dozen eggs were sold in three months.
Total sales: 2x/3*1.26+x*1.2+4x/3*1.08=$3.48x. The average price per dozen 3.48x/3x=$1.16.
E
Answer: E
Question: If A : B= 1 : 2 and B : C = 3 : 4, then A : B : C is:
Options:
A)9:6:4
B)1:2:3
C)3:6:9
D)12:25:87
E)3:5:7
Rationale: A:B=1:2, B:C=3:4, A:B:C=3Ã—3:3Ã—2:1Ã—4
â‡’ 9:6:4
Answer: A.
Answer: A
Question: A college has classes from 10:00 AM until 1:55 PM. In this duration, there are five periods. If 5 minutes are provided between each period to leave one class and enter the next class, how many minutes long is each period?
Options:
A)38 min
B)41 min
C)40 min
D)42 min
E)43 min
Rationale: The total time is 235 minutes.
There are four breaks of five minutes between the classes for a total of 20 minutes.
The total class time is 215 minutes.
215 / 5 classes = 43 minutes per class
The answer is E.
Answer: E
Question: The average expenditure of a labourer for 6 months was 85 and he fell into debt. In the next 4 months by reducing his monthly expenses to 60 he not only cleared off his debt but also saved 30. His monthly income is
Options:
A)70
B)72
C)75
D)78
E)None of the above
Rationale: Income of 6 months = (6 × 85) – debt
= 510 – debt
Income of the man for next 4 months
= 4 × 60 + debt + 30
= 270 + debt
∴ Income of 10 months = 780
Average monthly income = 780 ÷ 10 = 78
Answer D
Answer: D
Question: Which of the following is always odd?
Options:
A)Sum of two odd numbers
B)Diff. of two odd numbers
C)Prod. of two odd numbers
D)none of these
E)Cannot be determined
Rationale: Solution
Product of two numbers is always odd.
Answer C
Answer: C
Question: Statement: Concerns have risen about air pollution in Indian cities. A recent report by the World Health Organization (WHO) states that of the 20 most polluted cities in the world, 13 are in India.
Action:
I. Pollution committee should immediately take certain measures to control the pollution levels in India.
II. Licenses of polluting industries should be cancelled and owners should be put behind the bars.
Options:
A)Only I follows
B)Only II follows
C)Either I or II follows
D)Neither I nor II follows
E)Both I and II follow
Rationale: Explanation: Only one follows. The given statement describes the problem and the actions mention the solutions for the same. Second option is to be avoided because it is a negative and harsh approach. As listed in tips and tricks section also Options which are negative in nature and provide harsh solutions should be avoided.
ANSWER IS A
Answer: A
Question: There are 7 red cups and 5 blue cups on a shelf. If 4 cups are selected at random from the shelf, what is the probability that all 4 cups selected are blue cups?
Options:
A)1/80
B)1/88
C)1/90
D)1/95
E)1/99
Rationale: The number of ways of choosing 4 cups from the shelf is 12C4 = 495.
The number of ways of choosing 4 blue cups is 5C4 = 5.
P(4 blue cups) = 5/495=1/99.
The answer is E.
Answer: E
Question: What is the area of a triangle with the following vertices L(1, 3), M(3, 1), and N(3, 5) ?
Options:
A)3
B)4
C)5
D)6
E)7
Rationale: There is a direct formula to calculate the are of a triangle based on coordinates of its vertices and one could use it to solve this problem.
Though if you make a diagram minimum simple calculations will be needed:
Answer: B.
Answer: B
Question: John weighs twice as much as Susan. Susan's weight is 60% of Sam's weight. Mark weighs 50% of Lynn's weight. Lynn weighs 150% of John's weight. Which of these 5 people weighs the least?
Options:
A)John
B)Susan
C)Sam
D)Mark
E)Lynn
Rationale: John weighs twice as much as Susan --> J=2S --> John cannot weigh the least;
Susan's weight is 60% of Sam's weight --> S=0.6*Sam --> Sam cannot weigh the least;
Mark weighs 50% of Lynn's weight --> M=0.5*L --> Lynn cannot weigh the least;
Lynn weighs 150% of John's weight --> L=1.9*J --> John cannot weigh the least (we already know that);
As you can see the answer is either Susan (S) or Mark (M). To compare their weights we should express their weights in regards of the same person: M=0.5*L=0.5*(1.5*J)=0.75*J and from J=2S, S=0.5*J --> Susan weights the least: Susan's weight is 50% of that of John and Mark's weight ismore than 50%of that of John.
Answer: B.
Answer: B
Question: If a man buys 20 lollipops for $90 and sold them for $2 dollars determine his loss.
Options:
A)$ 50
B)$ 58
C)$ 52
D)$ 60
E)$ 12
Rationale: Cost of 20 lollipops = $90
Sold each lollipop for $2
So he sold 20 lollipops for $(20 × 2) = $40
Loss = $(90 – 40) = $50
Therefore, loss = $ 50.
Answer:A
Answer: A
Question: A man buys an article for $100. and sells it for $120. Find the gain percent?
Options:
A)10%
B)15%
C)25%
D)20%
E)30%
Rationale: C.P. = $100
S.P. = $120
Gain = $20
Gain% = 20/100 *100 = 20%
Answer is D
Answer: D
Question: In order to obtain an income of Rs. 650 from 10% stock at Rs. 96, one must make an investment of:
Options:
A)Rs. 3100
B)Rs. 6240
C)Rs. 6500
D)Rs. 9600
E)Rs. 9000
Rationale: Explanation:
To obtain Rs. 10, investment = Rs. 96.
To obtain Rs. 650, investment = Rs. 96	/10 *650=Rs. 6240.
ANSWER IS B
Answer: B
Question: A car covers a distance of 624 km in 3 hours. Find its speed?
Options:
A)104 kmph
B)194 kmph
C)208 kmph
D)174 kmph
E)101 kmph
Rationale: 624/3
=208 kmph
Answer:C
Answer: C
Question: In a village there are 150 men and 90 women in present time.if in next year population will be P=(a^2 +b^2)^1/2 , and in every year men are reduces 4%.what is population of after 2 year.
Options:
A)140
B)141
C)142
D)143
E)147
Rationale: next year total population=[150^2+90^2]^.5=174.92=175
man decreased by 4% so total man =150*.96=144
women will be= 175-144=31
so population after two years= [135^2+31^2]^.5=147.30=147
so population after two year= 147
ANSWER:E
Answer: E
Question: Arjun and Sajal are friends . each has some money. If Arun gives Rs. 30 to Sajal, the Sajal will have twice the money left with Arjun. But, if Sajal gives Rs. 10 to Arjun, the Arjun will have thrice as much as is left with Sajal. How much money does Sajal have?
Options:
A)Rs 34
B)Rs 35
C)Rs 36
D)Rs 37
E)Rs 38
Rationale: If arun had x rs , and sejal had y rs, then
2*(x-30) = y+30 or 2x-60= y+30 or y= 2x-90
and
x+10 = 3*(y-10)= 3*(2x-90-10)=6x-300
or
5x=310
x= 310/5 = 62 Rs with Arjun
y= 2x-90 = Rs 34 with Sajal
ANSWER:A
Answer: A
Question: If x^2 – 3x = 18, then one possible value of x – 4 =
Options:
A)-9
B)-5
C)-3
D)-1
E)2
Rationale: x^2 – 3x = 18
i.e. x^2 – 3x - 18 = 0
i.e. x^2 –6x + 3x - 18 = 0
i.e. (x-6)(x+3) = 0
i.e. x = 6 or -3
i.e. x-4 = 6-4 or -3-4
i.e. x-4 = 2 or -7
Answer: Option E
Answer: E
Question: In a class, there are 24 boys who are over 160 cm tall. If these constitute three-fourths of the boys and the total number of boys is two-thirds of the total number of students in the class, what is the number of girls in the class ?
Options:
A)6
B)12
C)18
D)16
E)26
Rationale: Explanation:
Let the number of boys be x. Then, (3/4)x = 24 or x = 24 x(4/3) = 32.
If total number of students is y, then (2/3) y = 32 or y = 32 x (3/2) = 48.
Therefore Number of girls in the class = (48 - 32) = 16.
Answer: D
Answer: D
Question: In a certain company 20% of the men and 40% of the women attended the annual company picnic.If 30% of all the employees are men .What % of all the employee went to the picnic?
Options:
A)33%
B)34%
C)35%
D)36%
E)37%
Rationale: total men in company 30% means total women in company 70%(assume total people in company 100%)
no of men employees attended picnic=30x(20/100)=6
no of women employees attended picnic=70x(40/100)=28
total percentage of employees attended the picnic=6+28=34%
ANSWER:B
Answer: B
Question: If |x| = 4x - 2, then x = ?
Options:
A)1
B)2
C)1 and 1/2
D)-1/2
E)-1
Rationale: Answer:
Approach:
Substituted option A i.e x=2. Inequality satisfied.
B
Answer: B
Question: How many even 4-digit numbers can be formed, so that the numbers are divisible by 4 and no two digits are repeated?
Options:
A)336
B)784
C)1120
D)1804
E)1936
Rationale: Number is divisible by 4 if the last two digits form a number divisible by 4.
Therefore last two digits can be:
00;
04;
08;
12
16;
...
96.
Basically multiples of 4 in the range 0-96, inclusive. Multiples of 4 in a range 0-96, inclusive are last multiple in the range − first multiple in the range4+1=25last multiple in the range − first multiple in the range4+1=25
But 3 numbers out of these 25 are not formed with distinct digits: 00, 44, and 88. Hence the numbers we are looking for can have only 22 endings.
If there is 0 in the ending (04, 08, 20, 40, 60, 80 - total 6 such numbers), then the first and second digit can take 8 and 7 choices each = 56 choices total. As there are 6 numbers with 0 in ending, hence total 6*56=336.
If there is no 0 in the ending (total 22 - 6 with zero = 16 such numbers), then the first digit can take 7 choices (10 - 2 digits in the ending and zero, so total 3 digits = 7, as 4-digit number can not start with zero) and the second digit can take 7 choices too (10 digits - 3 digits we've already used) = 7*7=49 choices total. As there are 16 numbers without zero in ending, hence total 16*49=784.
TOTAL: 336+784=1120
Answer: C.
Answer: C
Question: A retailer bought a coat at wholesale and marked it up 90% to its initial price of $76. By how many more dollars does he need to increase the price to achieve a 100% markup?
Options:
A)2
B)4
C)6
D)8
E)10
Rationale: Let x be the wholesale price.
Then 1.9x= 76 and x = 76/1.9 = 40.
To achieve a 100% markup, the price needs to be $80.
The retailer needs to increase the price by $4 more.
The answer is B.
Answer: B
Question: If an object travels at ten feet per second, how many feet does it travel in two hours?
Options:
A)60000
B)30000
C)18000
D)72000
E)22200
Rationale: If an object travels at 10 feet per second it covers 10x60 feet in one minute, and 10x60x2x60 feet in two hour.
Answer = 72000 Answer: D
Answer: D
Question: what is the least number. which should be added to 0.0568 to make it a perfect square?
Options:
A)0.0004
B)0.0009
C)0.0002
D)0.0003
E)0.0008
Rationale: 0.0568+0.0008=0.0576
(0.24)^2
ANSWER:E
Answer: E
Question: If M and N are positive integers and M = 15N - 1, what is the remainder when M is divided by 5?
Options:
A)0
B)1
C)2
D)3
E)4
Rationale: This question asks what IS...(the answer), so we know that the answer will be consistent. As such, we can TEST VALUES to quickly get the solution.
We're told that M and N are POSITIVE INTEGERS and M = 15N - 1. We're asked for the REMAINDER when M is divided by 5.
IF....
N = 1
M = 14
14/5 = 2 remainder 4
Final Answer:
E
Answer: E
Question: The average temperature of Monday, Tuesday, Wednesday and Thursday was 38∘ and that of Tuesday, Wednesday, Thursday and Friday was 40∘. If the temperature on Monday was 30∘, the temperature of Friday was :
Options:
A)40∘
B)39∘
C)38∘
D)30∘
E)None of these
Rationale: Explanation:
M+T+W+Th=(4×38)=152
Monday temparature is 30. So T+W+Th=(152-30)=122
T+W+Th+F=(4×40)=160
F = (160-122)=38∘
Correct Option: C
Answer: C