divelab/Sys2Bench huggingface dataset:
Question: Present ages of Sameer and Anand are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively. What is Anand's present age in years?
Options:
A)14
B)16
C)15
D)23
E)24
Rationale: Given, the preset ratio of the ages of Sameer and Anand is 5:4
Let Age of Sameer/5 = Age of Anand/4= x
Present age of Sameer = 5x
Present age of Anand = 4x
After 3 years,
Age of Sameer woud be 5x+3
Age of Anand woud be 4x+3
So (5x+3)/(4x+3)= 119
= x = 6
Hence age of Anand will be 6X4 = 24 years. ANSWER : E
Answer: E
Question: John bought Blue and Pink recorder for pupils in his music class in the ratio of 6:4. If 40% of the Blue recorder and 60% of the pink recorder were bought at half price, how many recorders did John buy at half price?
Options:
A)48%
B)52%
C)44%
D)46%
E)47%
Rationale: let total no of Recorder bought be 100, blue recorder 60 and pink recorder 40, so recorder bought at half price for both blue and pink recorder respectively 60* 40/100=24 and 40* 60/100=24
so total 48 recorders were bought at half price out of 100 blue and pink recorders..so required % is 48%
ANSWER:A
Answer: A
Question: If I walk at 3 kmph, I miss the train by 2 min, if however, I walk at 4 kmph. I reach the station 2 min before the arrival of the train. How far do I walk to reach the station?
Options:
A)4/5 km
B)4/9
C)4/6
D)4/2
E)4/1
Rationale: x/3 – x/4 = 4/60
x = 4/5 km
Answer: A
Answer: A
Question: Of the land owned by a farmer, 90 percent was cleared for planting. Of the cleared land, 20 percent was planted with potato and 70 percent of the cleared land was planted with tomato. If the remaining 630 acres of cleared land was planted with corn, how many acres did the farmer own?
Options:
A)7000
B)6800
C)8000
D)5400
E)7100
Rationale: 20% od 90% = 18%, 70% 0f 90% = 63% so the remaining 90-18-63=9%=630 acres or 10% of 90%=9% --> 630/9*100=7000 acres Answer (A)
Answer: A
Question: A customer asks the clerk for a paintbrush and a bucket of whitewash for a total price of B dollars. If the paintbrush costs 700 cents less than twice the price of a bucket of whitewash, what is the price of half a bucket of whitewash in dollars?
Options:
A)(B + 200)/2.
B)(B + 2)/6.
C)(2B + 200)/3.
D)(B + 2)/3.
E)(B - 2)/6.
Rationale: P = 2w - 200
thus total price in cents as given should be
2w-200 +w = 100B
3w - 200 = 100 B
3w = 100 B+200
3w =b+2 (in dollars)
w/2 = (b+2)/6
Ans:C
Answer: C
Question: The Ultimate Boxwood Derby is coming up and two competitors are testing their model cars on the ultra long endurance track. Sandra launches her car, The Pink Lady, half a minute before Dee launches her car, Greased Lightning. The Pink Lady goes at 40 meters per minute and Greased Lightning goes 50 meters per minute. Where will Greased Lightning overtake The Pink Lady on this 50 meter long track?
Options:
A)At the 30 meter mark
B)At the 35 meter mark
C)At the 40 meter mark
D)At the 50 meter finish line!
E)There is not enough room, The Pink Lady will win.
Rationale: Distance covered by The Pink Lady in 1/2 minute = 20 meters
Now, 10 meters is compensated in 1 minute, therefore 20 meters will be compensated in 2 minutes.
The Pink Lady will be at the 80 meter mark in 2 minutes.
So, Greased Lightning does not have room to overtake the Pink Lady on the track.
Correct Answer: E
Answer: E
Question: TOM traveled the entire 60 miles trip. If he did the first 12 miles of at a constant rate 24 miles per hour and the remaining trip of at a constant rate 48 miles per hour, what is the his average speed, in miles per hour?
Options:
A)20mph
B)24mph
C)30mph
D)40mph
E)42mph
Rationale: avg speed = total distance/ total time = (d1+d2)/(t1+t2) = (12+48) / ((12/24)+(48/48)) = 60*2/3 = 40mph
D
Answer: D
Question: Find the number of square tiles to cover the floor of a room measuring 4 m * 9 m leaving 0.25 m space around the room. A side of square tile is given to be 25 cms?
Options:
A)299
B)476
C)277
D)268
E)982
Rationale: 3 1/2 * 8 1/2 = 1/4 * 1/4 * x => x
= 476
Answer:B
Answer: B
Question: If a train, travelling at a speed of 80 kmph, crosses a pole in 5 sec, then the length of train is?
Options:
A)110.111 m
B)121.111 m
C)111.11 m
D)141.111 m
E)181.111 m
Rationale: D = 80 * 5/18 * 5 = 111.11 m
ANSWER:C
Answer: C
Question: For each hour of production, a certain factory requires 1 assembly line worker for every 25 units to be produced in that hour. The factory also requires 8 managers regardless of the number of units to be produced. Which of the following expressions represents the total number of assembly line workers and managers that this factory requires to produce 50N in one hour, where N is a positive integer?
Options:
A)12 + 50N
B)12 + 2N
C)8 + 2N
D)37N
E)25
Rationale: 25 units = 1 worker;
50N units = 50N/25 = 2N workers.
So, the answer is 2N workers plus 8 managers.
Answer: C.
Answer: C
Question: A company organized a recruiting process for 3 vacant positions of assistant manager for its product launches. The company's efforts yielded 15 eligible candidates. How many sets of 3 candidates can the company choose to fill the 3 assistant manager positions?
Options:
A) 2,060
B) 1,320
C) 455
D) 315
E) 220
Rationale: 15*14*13/3*2*1 = 455
C
Answer: C
Question: A single discount equivalent to the discount series of 30%, 10% and 8% is?
Options:
A)31.8
B)42.04
C)31.6
D)31.2
E)31.9
Rationale: Explanation:
100*(70/100)*(90/100)*(92/100) = 57.96
100 - 57.96 = 42.04
Answer: B
Answer: B
Question: A rectangular box of volume V has width, depth and height in the ratio of 2:1:3 (in that order). What is the height as a function of V?
Options:
A)(V/2)^(1/3)
B)(2V/6)^(1/3)
C)(9V/2)^(1/3)
D)(4V/3)^(1/3)
E)(4V/2)^(1/3)
Rationale: We are given width = 2, depth = 1, height = 3.
Then Volume V = Width x Depth x Height = 2*1*3 = 6
i.e. V = 6
The correct option should result in 3 (the height) on substituting the value of V=6.
Checking options with V=6:
A) (V/2)^(1/3) = (6/2)^(1/3) = 3^(1/3) INCORRECT ANSWER
B) (2V/6)^(1/3) = (12/6)^(1/3) = 2^(1/3) INCORRECT ANSWER
C) (9V/2)^(1/3) = (54/2)^(1/3) = 3 CORRECT ANSWER
D) (4V/3)^(1/3) = (24/3)^(1/3) = 8^(1/3) = 2 INCORRECT ANSWER
E) (4V/2)^(1/3) = (24/2)^(1/3) = 12^(1/3) INCORRECT ANSWER
Answer: Option C
Answer: C
Question: In expressing a length 810472 km as nearly as possible with three significant digits , find the percentage error.
Options:
A)0.34%
B)0.304%
C)30.4%
D)0.034%
E)3.40%
Rationale: Error = (81.5 – 81.472)km = 0.028.
Required percentage = [(0.028/81.472)*100]% = 0.034%.
ANSWER D 0.034%
Answer: D
Question: The ages of two persons differ by 16 years. 6 years ago, the elder one was 3 times as old as the younger one. What are their present ages of the elder person
Options:
A)15
B)20
C)25
D)30
E)28%
Rationale: Explanation:
Let's take the present age of the elder person = x
and the present age of the younger person = x – 16
(x – 6) = 3 (x-16-6)
=> x – 6 = 3x – 66
=> 2x = 60
=> x = 60/2 = 30
Option D
Answer: D
Question: Out of a total of 1,000 employees at a certain corporation, 52 percent are female and 40 percent of these females work in research. If 65 percent of the total number of employees work in research, how many male employees do NOT work in research?
Options:
A) 520
B) 480
C) 392
D) 208
E) 38
Rationale: total number of female employees =52% =520
female employees working in research =(2/5)*520=208
Total no of employees working in research =65% =650
Total male employees =48%=480
male employees working in research =650-208=442
male employees not working in research =480-442=38
Answer E
Answer: E
Question: A shopkeeper sold an article offering a discount of 5% and earned a profit of 19.7%. What would have been the percentage of profit earned if no discount was offered?
Options:
A)60%
B)26%
C)30%
D)56%
E)73%
Rationale: Let C.P. be Rs. 100.
Then, S.P. = Rs. 19.70
Let marked price be Rs. x. Then, 95/100 x = 119.70
x = 11970/95 = Rs. 126
Now, S.P. = Rs. 126, C.P. = Rs. 100
Profit % = 26%.
Answer: B
Answer: B
Question: If the speed of X meters per minute is equivalent to the speed of Y kilometers per hour, what is Y in terms of X? (1 kilometer=1000 meters)
Options:
A)15x/18
B)6x/5
C)18x/5
D)0.06x
E)3600000x
Rationale: x=1000y/60
y = 0.06x
Answer : D
Answer: D
Question: If a number p is prime, and 2p+1 = q, where q is also prime, then the decimal expansion of 1/q will produce a decimal with q-1 digits. If this method produces a decimal with 166 digits, what is the units digit of the product of p and q
Options:
A)1
B)3
C)5
D)7
E)9
Rationale: 3/7 = 0.428571... (a repeating pattern one digit long)
B
Answer: B
Question: Two trains travel in opposite directions at 36 kmph and 45 kmph and a man sitting in slower train passes the faster train in 10 seconds. The length of the faster train is
Options:
A)225 m
B)100 m
C)120 m
D)180 m
E)None
Rationale: Solution
Relative Speed	= (36 + 45) km/hr
= (81 x 5/18) m/sec
= (45/2) m/sec
Length of the train	= (45 / 2 x 10) m
= 225 m.
Answer A
Answer: A
Question: The simple interest on Rs.11000 at a certain rate of interest in five years is Rs.7200. Find the compound interest on the same amount for two years at the same rate of interest.
Options:
A)3068.82
B)3052.89
C)3052.85
D)3068.51
E)3068.81
Rationale: R = 100 I / PT
=> R = (100 * 7200)/ (11000 * 5) = 13.09%
CI = P{ [1 + R /100]n - 1}
= 11000 { [ 1 + 13.09 / 100]^2 - 1} = Rs.3068.51
Answer:D
Answer: D
Question: Running at the same rate, 8 identical machines can produce 560 paperclips a minute. At this rate, how many paperclips could 15 machines produce in 6 minutes?
Options:
A)1344
B)6300
C)8400
D)50400
E)67200
Rationale: 8 machines produce 560 in 1 min
8 machines produce 560* 6 in 6 min
15 machine produce 560*6*(15/8) in 6 minutes
560*6*15/8=6300 answer is B.
Answer: B
Question: In a factory, there are 90% technicians and 10% non-technicians. If the 90% of the technicians and 10% of non-technicians are permanent employees, then the percentage of workers who are temporary is?
Options:
A)62%
B)57%
C)52%
D)82%
E)42%
Rationale: Total = 100
T= 90 NT= 10
90*(10/100)=910*(90/100)=9
9 + 9 = 18=> 100 - 18 = 82%
Answer:D
Answer: D
Question: A mixture contains milk and water in the ratio 5:2. On adding 10 liters of water, the ratio of milk to water becomes 5:3. The quantity of milk in the original mixture is?
Options:
A)40
B)48
C)52
D)56
E)70
Rationale: milk:water = 5:2
5x : 2x + 10 = 5 : 3
3[5x] = 5[2x + 10]
15x = 10x + 50
15x - 10x = 50
x = 10
The quantity of milk in the original mixture is = 5 : 2 = 5 + 2 = 7
7x = 70
E
Answer: E
Question: At his usual rowing rate, Rahul can travel 12 miles downstream in a certain river in 6 hr less than it takes him to travel the same distance upstream. But if he could double his usual rowing rate for this 24 miles round trip, the downstream 12 miles would then take only 1 hr less than the upstream 12 miles. What is the speed of the current in miles per hour?
Options:
A)7/3
B)4/3
C)5/3
D)8/3
E)None of these
Rationale: Explanation :
Let x be rate of rahul , and y be the rate of current in mph.
=> [12/ (x-y)] - [12 / (x+y)] = 6.
=> y = ( x2 - y2 ) / 4. ..................(i)
When Rahul doubles his rowing rate, then we have :-
=> 12/( 2x-y) - 12/( 2x+y) = 1.
=> 2y / (4x2 - y2) = 1/12.
=> y = (4x2 - y2) / 24. ..................(ii)
Hence, from (i) and (ii), we have 2x2 = 5y2 .
Putting, x2 = 5y2 / 2 in (i), we get
=> y = (3/2)y2 / 4 .
=> y = 8/3.
Answer : D
Answer: D
Question: A man can row downstream at 18 kmph and upstream at 10 kmph. Find the speed of the man in still water and the speed of stream respectively?
Options:
A)2
B)4
C)8
D)4
E)7
Rationale: Let the speed of the man in still water and speed of stream be x kmph and y kmph respectively.
Given x + y = 18 --- (1)
and x - y = 10 --- (2)
From (1) & (2) 2x = 28 => x = 14, y = 4.
Answer:D
Answer: D
Question: The fraction 101 27/100000 in decimal for is:
Options:
A)101.27
B)101.00027
C)101.0027
D)101.027
E)None of them
Rationale: 101 27/100000
= 101 + 27/ 100000
= 101 + .00027
= 101.00027
Answer is B.
Answer: B
Question: If exactly 7 guests drank only one of the two types of drinks, how many guests drank both types of drinks?
Options:
A)5
B)6
C)7
D)4
E)2
Rationale: Say x guests drank both drinks.
(7 - x) + (4 - x) = 7 --> x = 2.
Answer: E.
Answer: E
Question: Sara is younger than Robert by 8 years. If their ages are in the respective ratio of 3:5, how old is Sara?
Options:
A)8
B)10
C)12
D)15
E)20
Rationale: Let Robert's age be x years
Then Sara's age = x-8 years
(x-8)/x = 3/5
x = 20
Sara's age = x-8 = 12 years
Answer is C
Answer: C
Question: A car covers a distance of 520 km in 4 hours. Find its speed?
Options:
A)104
B)130
C)298
D)269
E)213
Rationale: 520/4 = 130 kmph
Answer:B
Answer: B
Question: A student travels from his house to school at 10 km/hr and reaches school 2 hours late. The next day he travels 16 km/hr and reaches school 1 hour early. What is the distance between his house and the school?
Options:
A)70
B)75
C)80
D)85
E)90
Rationale: Let x be the distance from his house to the school.
x/10 = x/16 + 3
8x = 5x + 240
3x = 240
x = 80 km
The answer is C.
Answer: C
Question: A sum fetched a total simple interest of Rs. 4016.25 at the rate of 5% p.a. in 5 years. What is the sum?
Options:
A)12021
B)14520
C)16065
D)18925
E)12887
Rationale: Principal = (100 * 4016.25) / (5 * 5)
= Rs.16065.
Answer:C
Answer: C
Question: A sequence consists of 16 consecutive even integers written in increasing order. The sum of the first 8 of these even integers is 504. What is the sum of the last 8 of the even integers?
Options:
A)608
B)614
C)620
D)626
E)632
Rationale: The sum of the first 8 numbers is: x + (x+2) +...+ (x+14) = 504
The sum of the next 8 numbers is: (x+16) + (x+2+16) +...+ (x+14+16) =
504 + 8(16) = 504 + 128 = 632
The answer is E.
Answer: E
Question: At an international conference, “Red” world countries and “Blue” world countries are the only participants. The ratio of “Red” world participants to “Blue” world participants is 2:1. If one-third of “Red” world participants are left-handed and two-thirds of “Blue” world participants are left-handed, then what is the fraction of the participants who are left-handed?
Options:
A)2/3
B)4/5
C)6/2
D)5/2
E)4/9
Rationale: Red: Blue = 2:1
Let Red = 2x and Blue = 1x
1/3 of Red are left handed => 1/3 * 2x = 2x/3 Red left handed
2/3 of Blue are left handed => 2/3 *1x = 2x/3 blue left handed
fraction of participants who are left handed = total left handed/ total participants = (red left handed + blue left handed)/total participants = (2x/3 + 2x/3)/(2x+1x) = 4/9
Answer : E
Answer: E
Question: If cement, gravel and sand are to be mixed in 7:10:13 and 11 tons of cement is available how many tons of mixture can be produced assuming that sufficient gravel and sand is readily available.
Options:
A)35 7/8
B)36
C)34 2/7
D)47 1/7
E)34 6/7
Rationale: Cement:Gravel:Sand = 7:10:13 --> total of 7+10+13 = 30 parts.
If we use 11 tons of cement, then we'll get 11/7*30 = 47 1/7 tons of mixture.
Answer: D.
Answer: D
Question: If a man crosses a 600 m long street in 5 minutes. What is his speed?
Options:
A)7 km/hr
B)7.1 km/hr
C)7.2 km/hr
D)8 km/hr
E)8.5 km/hr
Rationale: distance = 600 meter
time = 5 minutes = 5 x 60 seconds = 300 seconds
Speed = distancetime=600300=2m/s=2×185 km/hr=365 km/hr=7.2 km/hr
C
Answer: C
Question: 3^7+3^7+3^7=?
Options:
A)a) 81^2
B)b) 81^4
C)c) 81^5
D)d) 81^6
E)e) 81^15
Rationale: The correct answer is A 81^2
Answer: A
Question: Mohit sold an article for Rs . 18000. Had he offered a discount of 10% on the selling price, he would have earned a profit of 8%. What is the cost price of the article?
Options:
A)Rs.15000
B)15002
C)26879
D)26992
E)12681
Rationale: Let the CP be Rs. x.
Had he offered 10% discount, profit = 8%
Profit = 8/100 x and hence his SP = x + 8/100 x
= Rs. 1.08x = 18000 - 10/100(18000)
= 18000 - 1800 = Rs. 16200
=> 1.08x = 16200
=> x = 15000
Answer: A
Answer: A
Question: Nr Books bought Nr of People
5 7
6 3
7 3
8 2
What is the median of books bought per person?
Options:
A)a) 2
B)b) 4
C)c) 6
D)d) 8
E)e) 18
Rationale: 5,5,5,5,5,5,5,6,6,6,7,7,7,8,8
so you will observer that the median of the list is 6.
Ans C
Answer: C
Question: A customer bought a product at the shop. However, the shopkeeper increased the price of the product by 20% so that the customer could not buy the required amount of the product. The customer managed to buy only 80% of the required amount. What is the difference in the amount of money that the customer paid for the second purchase compared to the first purchase?
Options:
A)10%
B)8%
C)6%
D)4%
E)2%
Rationale: Let x be the amount of money paid for the first purchase.
The second time, the customer paid 0.8(1.2x)=0.96x.
The difference is 4%.
The answer is D.
Answer: D
Question: For a certain exam,a score of 58 was 2 standard deviations below mean and a score of 98 was 3 standard deviations above mean.What was the standard deviation for the exam?
Options:
A)7
B)6
C)8
D)0
E)2
Rationale: Mean-2SD=58
Mean+3SD=98
By solving above equation we get,
SD (absolute value)=8
Ans. C
Answer: C
Question: A committee has 5 men and 5 women. What are the number of ways of selecting 2 men and 3 women from the given committee?
Options:
A)127
B)100
C)882
D)272
E)323
Rationale: The number of ways to select two men and three women
= ⁵C₂ * 5C₃
= (5 *4 )/(2 * 1) * (5 * 4 * 3)/(3 * 2)
= 100
Answer: B
Answer: B
Question: The G.C.D of 1.08, 0.36 and 1.5 is
Options:
A)0.06
B)0.1
C)0.18
D)0.11
E)0.12
Rationale: Explanation:
Given numbers are 1.08 , 0.36 and 1.5
H.C.F of 108, 36 and 150 is 6[because G.C.D is nothing but H.C.F]
therefore H.C.F of given numbers = 0.06
Answer: A
Answer: A
Question: Company X sells a selection of products at various price points. Listed below are unit sales made for one particular day. How many unit sales on that day were greater than the mean sale price but less than the median sale price?
$50, $50, $97, $97, $97, $120, $155, $155, $199, $199, $219
Options:
A)0
B)1
C)2
D)3
E)4
Rationale: Taking the prices of products in ascending order(already arranged)
$50, $50, $97, $97, $97, $120, $125, $155, $199, $199, $219
we see that median value is the 6th value as there in total 11 values given
Arithmetic mean = total/number of entries = 1408/11 =128
We are asked to find how many unit sales on that day were greater than the mean sale price but less than the median sale price
as we can clearly see that there is one value between $120 and $128, answer is 1 unit
Correct Answer - B
Answer: B
Question: The average of 2,7,6 and x is 5 and the average of 18,1,6,x and y is 10. What is the value of y ?
Options:
A)5
B)10
C)20
D)30
E)40
Rationale: Answer C
Solution
We have :(2+7+6+X/4) = 5 or 15+x = 20 or x=5
Also, (18+1+6+X+Y/5) = 10 or 25+5+y = 50 or y=20. Answer C
Answer: C
Question: A bookseller has two display windows. She plans to display 4 new fiction books in the left window, and 5 new non-fiction books in the right window. Assuming she can put the five fiction books in any order, and separately, the three non-fiction books in any order, how many total configurations will there be for the two display windows?
Options:
A)2400
B)720
C)2880
D)336
E)420
Rationale: Two displays books could be arranged n! # of total arrangements are combinations multiplied together,
4!*5! =24*120=2880
Answer is C
Answer: C
Question: The larger of two negative consecutive even integers 2t and 2(t-1) is multiplied by 6 and then added to the smaller of the two original integers. Which of the following represents this operation?
Options:
A)6t-2
B)8t-2
C)14t-2
D)3
E)-2-4t^2
Rationale: larger of 2t-2, 2t (when they are negative) is 2t. the smallest of 2t and 2t-2 when they are positive is 2t-2.
therefore 6* 2t + 2t-2 = 14t-2.
option C.
Answer: C
Question: Number of ways in which the letters of word PARTI can be arranged with vowels in alphabetical order, is
Options:
A)60
B)240
C)120
D)480
E)None of these
Rationale: Solution
Order of vowels of fixed
âˆ´ required number of ways are 5!/2!.
Answer A
Answer: A
Question: Each shelf of a bookcase contained 11 books. If the librarian took out 33 books and rearranged the remaining books so that all shelves but the last one contained 7 books and that last shelf contained 2 books, how many shelves does the bookcase have?
Options:
A)5
B)6
C)7
D)8
E)9
Rationale: Let x be the number of shelves.
11x - 33 = 7(x-1) + 2
4x = 28
x = 7
The answer is C.
Answer: C
Question: If 60 percent of the members of a certain organization are women and 6/8 of the members of the organization are married men, which of the following statements concerning the membership must be true? I. The number of women in the organization is greater than the number of married men in the organization. II. The number of women in the organization is greater than the number of unmarried men in the organization. III. The number of married men in the organization is greater than the number of unmarried men in the organization.
Options:
A)II
B)III
C)I, II
D)I
E)II, III
Rationale: 6/10 (60%) of the members are women and 6/8 of the members are married men. Let the total numbers of members is 80 (the LCM of 10 and 8). Then there are:
6/10*80 = 48 women;
80 - 48= 32 men;
6/8*32 = 24 married men;
32 - 24 = 8 unmarried men.
So, option I,II is true.
Answer: C
Answer: C
Question: The price of pulses has fallen by 20%. How many quintals can be bought for the same amount which was sufficient to buy 18 quintals at the higher price?
Options:
A)20
B)22.5
C)25
D)30
E)32.5
Rationale: 80% of original price can buy = 18 quintals.
Therefore, he can buy ( 18 x 100 )/ 80 = 22.5 quintals at the lower price.
ANSWER:B
Answer: B
Question: There are 6 boxes numbered 1, 2,3,4,5 and 6. Each box is to be filled up either with a red or a green ball in such a way that at least 1 box contains a green ball & the boxes containing green balls are consecutively numbered. The total no. of ways in which this can be done is?
Options:
A)18
B)19
C)21
D)23
E)25
Rationale: If only one of the boxes has a green ball, it can be any of the 6 boxes. So, this can be achieved in 6 ways.
If two of the boxes have green balls and then there are 5 consecutive sets of 2 boxes. 12, 23, 34, 45, 56.
Similarly, if 3 of the boxes have green balls, there will be 4 options.
If 4 boxes have green balls, there will be 3 options.
If 5 boxes have green balls, then there will be 2 options.
If all 6 boxes have green balls, then there will be just 1 options.
Total number of options = 6 + 5 + 4 + 3 + 2 + 1 = 21
C
Answer: C
Question: A, B and C enter into a partnership by investing $11000, $15000 and $23000 respectively. At the end of 8 months, B receives $3315 as his share. Find the share of A.
Options:
A)$1865
B)$2087
C)$2217
D)$2431
E)$2662
Rationale: The ratio of capital of A, B and C = 11000 : 15000 : 23000 = 11 : 15 : 23
A's share = (11/15)*3315 = $2431
The answer is D.
Answer: D
Question: A cubical tank is filled with water to a level of 2 feet. If the water in the tank occupies 50 cubic feet, to what fraction of its capacity is the tank filled with water?
Options:
A)1/3
B)2/3
C)3/4
D)2/5
E)5/6
Rationale: The volume of water in the tank is H*L*B = 50 cubic feet.
Since H = 2, then L*B = 25 and L = B = 5.
Since the tank is cubical, the capacity of the tank is 5*5*5 = 125.
The ratio of the water in the tank to the capacity is 50/125 = 2/5
The answer is D.
Answer: D
Question: 5 is added to a certain number, the sum is multiplied by 7, the product is divided by 5 and 5 is subtracted from the quotient. The remainder left is half of 66. What is the number?
Options:
A)21
B)20
C)22
D)30
E)45
Rationale: Let number is X.
When 5 added to it,
= (X+5)
7 multiplied to sum,
= 7 *(X +5)
Now,
= [{7 *(X +5)} /5]
And,
= [{7 *(X +5)} /5] - 5
According to question,
[{7 *(X +10)} /5] - 5 = half of 66
[(7X + 35) /5) = 33 +5
7X + 35 = 38 *5
X = 155/7
X = 22.14=22
So, required number is: 22.
ANSWER : C
Answer: C