divelab/Sys2Bench huggingface dataset:
Question: To save money, Arkadelphia Cream Cheese will reduce each dimension of its rectangular box container (which is entirely full of cream cheese) by 75%, and reduce the price it charges its consumers by 75% as well. By what percentage does this increase the price-per-cubic-inch that each consumer will pay for cream cheese?
Options:
A)1. No change
B)2. 50%
C)3. 100%
D)4. 300%
E)5. 1500%
Rationale: L = 20: B = 10: H= 10 of initial box and Price = 100$
Therefore Price / cubic inch = 100 / (20*10*10) =0.05
Now, when dimensions are reduced by 75% and price also reduced by 75%
L = 5; B=2.5; H=2.5 and Price = 25$
Therefore price / cubic inch = 25 / (5*2.5*2.5) =0.8
Percentage change = (0.8 - 0.05) *100/ 0.05 = 1500%
Answer is E
Answer: E
Question: A bag contains 4 white balls, 4 black balls, and 3 red balls. One by one, three balls are drawn out without replacement. What is the probability that the third ball is red?
Options:
A)1/2
B)1/4
C)3/11
D)5/16
E)2/7
Rationale: The probability for each ball to be drawn third is equal.
Then the probability a red ball is drawn third is 3/11.
The answer is C.
Answer: C
Question: Mahesh can do a piece of work in 40days. He works at it for 20days and then Rajesh finished it in 30days. How long will Y take to complete the work?
Options:
A)45
B)25
C)37
D)41
E)60
Rationale: Work done by Mahesh in 60days = 20*1/40 = 1/2
Remaining work = 1 - 1/2 = 1/2
1/2 work is done by Rajesh in 30days
Whole work will be done by Rajesh is 30*2 = 60days
Answer is E
Answer: E
Question: Larry, Michael, and Jack have five donuts to share. If any one of the men can be given any whole number of donuts from 0 to 5, in how many different ways can the donuts be distributed?
Options:
A) 21
B) 42
C) 120
D) 504
E) 5040
Rationale: Larry, Michael, and Jack have five donuts to share. to get the answer, see how can we get sum5with 3 numbers.
1) 0,0,5 = 3 combinations or 3! /2!
2) 0,1,4 = 6 combinations or 3!
similarly
3) 0,2,3 = 6 combinations
4) 1,1,3 = 3 combination
5) 2,2,1 = 3 combination
total =21=A
Answer: A
Question: X and Y started a business by investing Rs.36000 and Rs.42000 respectively after 4 months Z joined in the business with an investment of Rs.48000, then find share of Z in the profit of Rs.13750 ?
Options:
A)3200
B)4000
C)3250
D)3825
E)3985
Rationale: Ratio of investment, as investments is for different time.
Investment x Number of units of time.
Ratio of investments X : Y : Z = 36000 : 42000 : 48000 => 6 : 7 : 8.
X = 6 x 12 Months = 72, Y = 7 x 12 = 84, Z = 8 X 8 = 64 => 18 : 21 : 16.
Ratio of investments => X : Y : Z = 18 : 21 : 16.
Investment Ratio = Profit sharing Ratio.
Z = 13750 × 16/55 = Rs.4000.
Share of Z in the profit is Rs.4000.
Option B
Answer: B
Question: The present ages of three persons in proportions 4 : 1 : 3. Eight years ago, the sum of their ages was 56. Find their present ages (in years).
Options:
A)8, 20, 28
B)16, 28, 36
C)16, 28, 35
D)40, 10, 30
E)16, 28, 33
Rationale: Let their present ages be 4x, x and 3x years respectively.
Then, (4x - 8) + (x - 8) + (3x - 8) = 56
8x = 80
x = 10.
Their present ages are 4x = 40 years, 1x = 10 years and 3x = 30 years respectively.
Answer:D
Answer: D
Question: If set A={4,4,4,....,n times} , set B={3,3,3,3....m times} and set C={11,11,11...k time} , then in terms of m,n and k , how many possible subsets from sets A,B, and C can be created ?
Options:
A)a) k(n+m+mn)+ k
B)b) (1+n+m+mn)(k+1)
C)c) k^2(mn+n/m)
D)d) kmn(k+m+n)
E)e) None of the above.
Rationale: a) how many 2's are included?
b) how many 3's are included?
and
c) how many 11's are included?
For the number of 2, we could have zero 2's, or one 2, or two 2's, all the way up to n 2's. That's (n + 1) possibilities for the 2's. Similarly, (m + 1) possibilities for the 3's and (k + 1) possibilities for the 11's. We simply multiply these three numbers.
NOTICE that one set, the set that includes no 2's, no 3's, and no 11's, is included. This is known in mathematics as thenull set, sometimes called the empty set, a set with no members. Technically, this is a subset of every possible set, but that's a technical detail of set theory that goes well beyond what the GMAT would expect students to know. Even the the calculation is not that difficult, some of the technical aspects of this question are not in line with the GMAT's expectations.
The number of subsets is (m + 1)(n + 1)(k + 1). The answer is not given in that form. Instead, the first two factors have been FOILed together:
(mn + m + n + 1)(k + 1).
Mike
B
Answer: B
Question: How many paying stones, each measuring 2 1/2 m * 2 m are required to pave a rectangular court yard 60 m long and 16 1/2 m board?
Options:
A)99
B)18
C)16
D)198
E)15
Rationale: 60 * 33/2 = 5/2 * 2 * x => x
= 198
Answer:D
Answer: D
Question: John has 10pairs of dark blue socks and 10pairs of black socks. He keeps them all in the same bag. If he picks out 3socks at random, then what is the probability thathe will get a matching pair?
Options:
A)1
B)3
C)5
D)6
E)9
Rationale: If he draws any combination of 3 socks he will definitely have the matching pair of either colour.
A
Answer: A
Question: A dishonest dealer professes to sell his goods at Cost Price but still gets 15% profit by using a false weight. What weight does he substitute for a kilogram?
Options:
A)869 1/7 grams
B)869 13/23 grams
C)869 8/3 grams
D)869 1/3 grams
E)832 1/23 grams
Rationale: If the cost price is Rs.100, then to get a profit of 15%, the selling price should be Rs.115.
If 115kg are to be sold, and the dealer gives only 100kg, to get a profit of 15%.
How many grams he has to give instead of one kilogram(1000 gm).
115 gm ------ 100 gm
1000 gm ------ ?
(1000 * 100)/115 = 869 13/23 grams.
Answer:B
Answer: B
Question: If the radius of a circle is decreased 10%, what happens to the area?
Options:
A)10% decrease
B)19% decrease
C)36% decrease
D)40% decrease
E)50% decrease
Rationale: Area of Square = Pi* radius^2
New Radius = 0.9 * old radius
so new area = (0.9)^2 old area => 0.81 of old area =>81% old area
Ans : B
Answer: B
Question: Two passenger trains start at the same hour in the day from two different stations and move towards each other at the rate of 22 kmph and 21 kmph respectively. When they meet, it is found that one train has traveled 60 km more than the other one. The distance between the two stations is?
Options:
A)288
B)516
C)877
D)278
E)178
Rationale: 1h ----- 5
? ------ 60
12 h
RS = 22 + 21 = 43
T = 12
D = 43 * 12 = 516
Answer: B
Answer: B
Question: On a 20 mile course, Pat bicycled at an average rate of 30 miles per hour for the first 12 minutes and without a break, ran the rest of the distance at an average rate of 8 miles per hour. How many minutes did Pat take to cover the entire course?
Options:
A)75
B)105
C)117
D)150
E)162
Rationale: At an average rate of 30 miles per hour in 12 minute (1/5 hours) Pat covers (distance) = (time) * (rate) = 1/5*30 = 6 miles, thus she should cover the remaining distance of 20 - 6 = 14 miles at an average rate of 8 miles per hour.
To cover 14 miles at an average rate of 8 miles per hour Pat needs (time) = (distance)/(rate) = 14/8 = 1.75 hours = 105 minutes.
Therefore Pat needs total of 12 + 105 = 117 minutes to cover the entire course.
Answer: C.
Answer: C
Question: To fill a tank, 25 buckets of water is required. How many buckets of water will be required to fill the same tank if the capacity of the bucket is reduced to 1/5 of its present?
Options:
A)61.5
B)60.5
C)63.5
D)62.5
E)125
Rationale: Let capacity of 1 bucket = x
Capacity of the tank = 25x
New capacity of the bucket = 1x/5
Hence, number of buckets needed = 25x/(1x/5)=(25×5)/1=125
Answer is E.
Answer: E
Question: Murali travelled from city A to city B at a speed of 40 kmph and from city B to city C at 60 kmph. What is the average speed of Murali from A to C given that the ratio of distances between A to B and B to C is 2 : 3?
A. 48 kmph
Options:
A)33
B)50
C)28
D)27
E)16
Rationale: Let the distances between city A to B and B to C be 2x km and 3x km respectively.
Total time taken to cover from A to C
= (2x)/40 + (3x)/60 = (6x + 6x)/120 = 12x/120 = x/10 Average speed = (2x + 3x)/(x/10) = 50 kmph.
Answer: B
Answer: B
Question: A rectangular grass field is 75 m * 40 m, it has a path of 2.5 m wide all round it on the outside. Find the area of the path and the cost of constructing it at Rs.2 per sq m?
Options:
A)s.1350
B)s.1327
C)s.1200
D)s.1397
E)s.1927
Rationale: Area = (l + b +2d) 2d
= (75 + 40 +2.5 * 2) 2*2.5 => 600
600 * 2 = Rs.1200
Answer: C
Answer: C
Question: Chris age after 14years will be 5 times his age 5years back. what is the present age of Chris?
Options:
A)A)20
B)B)25
C)C)15
D)D)22
E)E)11
Rationale: Chris present age= x
after 14years = x+14
5years back = x-5
x+14= 5(x-5)
x=11
Answer is E
Answer: E
Question: John and David were each given X dollars in advance for each day they were expected to perform at a community festival. John eventually performed on all 30 days of the festival, while David performed on 5 fewer days than John performed. If David gives John y dollars of her advance payment so that they would have each received the same daily rate, what was John paid in advance, in terms of Y?
Options:
A)11Y
B)15Y
C)13Y
D)10Y
E)5Y
Rationale: Both of them were given X $ each
David to adjust Y $ in advance to John
So David now has (X-Y)$ and John has (X+Y) $ such that their daily rate becomes same
So Rate of David= Rate of John
Also , David works for 25 days and John works for full 30 days
(X-Y) / 25 = (X+Y) / 30
Solving 30x-30y=25x+25y =>5x=55y => x=55/5y
X= 11Y
Answer : A
Answer: A
Question: When x is divided by y, the quotient is z with remainder f. Which of the following is equal to f?
Options:
A)yz – x
B)y/x−z
C)x – y – z
D)x – yz
E)zx – y
Rationale: (x/y)=z(+f)
(18/8)=2(+2)
x-yz
which is 18-(8*2)=2
Answer is D
Answer: D
Question: At the first meeting of the amputees’ support group, there were
93 fewer handshakes than there would have been if everyone
had at least one arm and shook hands once with everyone else.
The people with less than one arm made up 1/11 of the group.
How many of them were there?
Options:
A)2
B)3
C)4
D)5
E)6
Rationale: perfect example to use the units digit to get the answer quick.
let's assume the answer is A, then (22*21)/2 - (20*19)/2 = 93?
we can actually ignore the second part (after the minus) of the equation because it will always end with a units digit of 0.
the first part will have a units digit of 1 --> (units digit of 2 * units digit of 1) / 2
for the rest
B) (33*32) / 2 --> (units digit 3 * units digit 2) / 2 = 3 (success)
C) (44*43) / 2 --> (units digit 4 * units digit 3) / 2 = 6 (fail)
D) (55*54) / 2 --> (units digit 5 * units digit 4) / 2 = 0 (fail)
E) (66*65) / 2 --> (units digit 6 * units digit 5) / 2 = 0 (fail)
Interesting approach, but I don't think the unit digit is correct for B, D and E. The even number will become half and that reduced number should be used to get the unit digit.
B) (33*32) / 2 --> (units digit 3 * units digit 6) = 8
D) (55*54) / 2 --> (units digit 5 * units digit 7) = 5
E) (66*65) / 2 --> (units digit 3 * units digit 5) = 5
answer is B
Answer: B
Question: Find the value of (1-(1/3))(1-(1/4))(1-(1/5))….(1-(1/100)).
Options:
A)1/50
B)3/50
C)4/50
D)6/50
E)9/50
Rationale: Answer is A.
Answer: A
Question: Find the missing number:
6 13 25 51 101 ?
Options:
A)201
B)202
C)203
D)204
E)205
Rationale: C
203
6x2+1=13
13x2-1=25
25x2+1=51
51x2-1=101
101x2+1=203
Answer: C
Question: There are 6 people in the elevator. Their average weight is 150 lbs. Another person enters the elevator, and increases the average weight to 151 lbs. What is the weight of the 7th person.
Options:
A)157
B)168
C)189
D)190
E)200
Rationale: Solution
Average of 7 people after the last one enters = 151 .
âˆ´ Required weight = (7x151)-(6x150)
= 1057- 900
= 157.
Answer A
Answer: A
Question: Simplify: (7+2) – (5+3+1)-1.
Options:
A)-1
B)–2
C)1
D)2
E)0
Rationale: Solution:
(7+2) – (5+3+1)-1
=9-5-3+1-1
=9-8+1-1
=2-1
=1
Answer: (C)
Answer: C
Question: A man has some hens and cows. If the number of heads be 48 and the number of feet equals 140, then the number of hens will be:
Options:
A)26
B)25
C)23
D)22
E)20
Rationale: Let the number of hens be x and the number of cows be y.
Then, x + y = 48 .... (i)
and 2x + 4y = 140
x + 2y = 70 .... (ii)
Solving (i) and (ii) we get: x = 26, y = 22.
The required answer = 26.
Answer is A.
Answer: A
Question: By mixing two brands of tea and selling the mixture at the rate of Rs. 177 per kg. a shopkeeper makes a profit of 18%. If to every 2 kg of one brand costing Rs. 200 per kg, 3 kg of the other brand is added, then how much per kg does the other brand cost?
Options:
A)Rs.116.69
B)Rs.116.60
C)Rs.116.62
D)Rs.116.66
E)Rs.116.61
Rationale: Let the cost of the brand be Rs. X per kg.
C.P. of 5 kg = (2 * 200 + 3 * x) = Rs. (400 + 3x)
S.P of 5 kg = Rs. (5 * 177) = Rs. 885
[885 - (400 + 3x)]/(400 + 3x) * 100 = 18
24250 - 150x = 3600 + 27x
177x = 20650 => x = 116 2/3
So, cost of the other brand = Rs.116.66.
Answer: D
Answer: D
Question: For my anniversary, I decided to surprise my wife. Since she is a voracious reader, I decided to collect a lot of books for her. On the first day of the month, I bought one book, on the second, I bought two and on the third, I bought three. This process went on till the anniversary and on the day, I had 253 books with me to gift her.
Can you calculate, on which day is our anniversary?
Options:
A)31
B)28
C)23
D)33
E)22
Rationale: E
22rd day
1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20 + 21 + 22 = 253
Thus our anniversary falls on the 22rd day of the month.
You can apply other formulas to shorten the process but that is the simplest way to do it.
Answer: E
Question: Out of a classroom of 6 boys and 4 girls the teacher picks a president for the student board, a vice president and a secretary.
What is the probability that only girls will be elected?
Options:
A)1/30
B)4/30
C)5/30
D)7/30
E)8/30
Rationale: GBB (girl,boy,boy)
GGB (girl,girl,boy)
GGG (girl,girl,girl)
the probability of GGG is already known - 1/30.
ANS:A
Answer: A
Question: The owner of a cell phone shop charges his customer 23% more than the cost price. If a customer paid Rs.8,517 for a cell phone, then what was the cost price of the cell phone?
Options:
A)Rs.5,845
B)Rs.6,750
C)Rs.5,700
D)Rs.6,925
E)None of these
Rationale: Explanation:
123% of CP =SP
Therefore, CP = Rs.8,517x100/123 = Rs.6925
Answer: Option D
Answer: D
Question: The average expenditure of a labourer for 3 months was 85 and he fell into debt. In the next 4 months by reducing his monthly expenses to 60 he not only cleared off his debt but also saved 30. His monthly income is
Options:
A)70.2
B)50.1
C)75.2
D)78.4
E)52.5
Rationale: Income of 3 months = (3 × 85) – debt
= 255 – debt
Income of the man for next 4 months
= 4 × 60 + debt + 30
= 270 + debt
∴ Income of 10 months = 525
Average monthly income = 525 ÷ 10 = 52.5
Answer E
Answer: E
Question: If a+b+c=21, what is the total number of non-negative integral solutions?
Options:
A)223
B)233
C)240
D)243
E)253
Rationale: Think of it is a problem of diving 21 items to three people A, B & C which may or may not receive an item.
So simply use Combination here as (n-r+1) C (r-1) i.e.
(21+3-1) C (3-1) => 23 C 2 == > 253 solutions.
ANSWER:E
Answer: E
Question: If the sum of a number and its square is 72, what is the number?
Options:
A)15
B)26
C)8
D)91
E)none of these
Rationale: Let the number be x. Then,
x + x2 = 72
(x + 9)(x - 8) = 0
x = 8
ANSWER:C
Answer: C
Question: A number when divided successively by 4 and 5 leaves remainder 1 and 4 respectively. When it is successively divided by 5 and 4, then the respective remainders will be?
Options:
A)0
B)1
C)2
D)3
E)4
Rationale: Trying to get back the number first.
5x+4
4*[5x+4] + 1
so number is 20x +17
now divide it successively by 5 and then 4
(20x + 17)/ 5 = 2 remainder and 4x + 3is number left
now divide it by 4 we will get 3 remainder
ANSWER:D
Answer: D
Question: Diesel costs Rs.4 per lit and petrol costs 6.23 per litre. If the price of diesel rise by 10% a month and the price of petrol is unchanged.How many months will it take until a litre of Diesel costs more than a litre of petrol.
Options:
A)9 months
B)5 months
C)6 months
D)3 months
E)2 months
Rationale: Explanation :
=>In the First Month the price of the diesel would be 4*110/100 = 4.4
=>In the Second Month the price of the diesel would be 4.4*110/100 = 4.84
=>In the Third Month the price of the diesel would be 4.84*110/100 = 5.324
=>In the fourth Month the price of the diesel would be 5.324*110/100 = 5.85
=>In the fifth Month the price of the diesel would be 5.85*110/100 = 6.44 which is higher than the price of petrol
Answer : B
Answer: B
Question: A trader sold an article on a certain price with 20% profit. If he sold double of previous selling price then find its profit %
Options:
A)140%
B)120%
C)100%
D)90%
E)80%
Rationale: let cost price = 100%
selling price = 120%
new s.p. = 240%
p% = 240-100 = 140%
Answer is A
Answer: A
Question: Efrida and Frazer who live 12 miles apart, meet at a restaurant that is directly north of Efrida's home and directly east of Frazer's home. If the restaurant is two miles closer to Efrida's home, than to Frazer's home, how many miles is the restaurant from Frazer's home?
Options:
A)6
B)7
C)8
D)10
E)11
Rationale: It's a simple geometry problem. Look at the diagram below:
Answer: D.
Answer: D
Question: A contractor undertakes to complete the construction of a tunnel 720 meters long in 240 days and employs 50 men for the purpose. After 120 days, he finds that only 240 meters of the tunnel is complete. How many more men should be employ in order to complete the work in time?
Options:
A)75 men
B)80 men
C)70 men
D)60 men
E)50 men
Rationale: In 120days, only 240m of the tunnel is constructed by 50 men.
The remaining 120days, 480m of the tunnel can be constructed by 120 men.
Additional number of men required = 120 - 50 = 70 men.
ANSWER:C
Answer: C
Question: If 9 - 4/X = 7 + 8/X, then X =
Options:
A)15
B)6
C)1
D)5
E)12
Rationale: We're given the equation 9 - 4/X = 7 + 8/X. We're asked for the value of X.
The common-denominator of these 4 numbers is X, so we have to multiple 2 of the numbers to give them that denominator...
9X - 4X/X = 7X + 8X/X
We can then eliminate that denominator, which gives us....
9X - 4 = 7X + 8
12 = 2X
Both 2X and 12 have a common denominator of 2, so we divide both sides by 2 for our final answer...
6 = X
B
Answer: B
Question: A person travelled from his house to office at 35km/hr and office to house at 65km/hr. Then find the average speed?
Options:
A)30km/hr
B)45.5km/hr
C)48km/hr
D)50.5km/hr
E)62km/hr
Rationale: Average speed = (2*35*65)/(35+65)= 45.5km/hrAnswer is B
Answer: B
Question: Two trains of equal length are running on parallel lines in the same directions at 46km/hr. and 36km/hr. The faster trains pass the slower train in 18 seconds. The length of each train is:
Options:
A)25m
B)50m
C)72m
D)80m
E)None of these
Rationale: Explanation:
The relative speed of train is 46-36 = 10 Km/hr = (10 X 5) / 18 = 25/9 m/s10×518=259m/s
In 18 secs the total distance traveled is 18x25/9 = 50 m.
Therefore the length of each train is = 50/2 = 25 m.
Answer A
Answer: A
Question: Find large no. from below question The difference of two numbers is 1365. On dividing the larger number by the smaller, we get 6 as quotient and the 5 as remainder
Options:
A)1637
B)1456
C)1567
D)1678
E)1635
Rationale: Let the smaller number be x. Then larger number = (x + 1365).
x + 1365 = 6x + 5
5x = 1360
x = 272
Large number = 272+1365 = 1637
A
Answer: A
Question: How much interest can a person get on Rs. 8200 at 17.5% p.a. simple interest for a period of two years and six months?
Options:
A)3000
B)4000.75
C)3587.5
D)3500
E)5020.75
Rationale: I = (8200 * 2.5 * 17.5)/100 = (8200 * 5 * 35)/(100 * 2 * 2) = Rs. 3587.50
ANSWER C
Answer: C
Question: Mohit sold an article for Rs. 18000. Had he offered a discount of 10% on the selling price, he would have earned a profit of 8%. What is the cost price of the article?
Options:
A)15000
B)15002
C)26879
D)26992
E)12681
Rationale: Let the CP be Rs. x.
Had he offered 10% discount, profit = 8%
Profit = 8/100 x and hence his SP = x + 8/100 x
= Rs. 1.08x = 18000 - 10/100(18000)
= 18000 - 1800 = Rs. 16200
=> 1.08x = 16200
=> x = 15000
Answer: A
Answer: A
Question: The average age of 8 men increases by 2 years when two women are included in place of two men of ages 20 and 24 years. Find the average age of the women?
Options:
A)27
B)21
C)30
D)27
E)176
Rationale: 20 + 24 + 8 * 2
= 60/2
= 30
Answer:C
Answer: C
Question: In a certain growth fund, 3/5 of the investment capital is invested in stocks, and of that portion, 1/3 is invested in preferred stocks. If the mutual fund has $849,000 invested in preferred stocks, what is the total amount of money invested in the fund?
Options:
A)$1,974,000
B)$2,538,000
C)$3,264,000
D)$3,826,000
E)$4,245,000
Rationale: Portion invested in preferred stock = 3/5 * 1/3 = 1/5
1/5 of fund = 849---
Fund = 5 * 849---
Here, we can avoid the math and simply look at 5 * 9 -> 45. Only option E has 45 in it.
Answer (E).
Answer: E
Question: The average of first five multiples of 3 is?
Options:
A)6
B)8
C)9
D)5
E)7
Rationale: Average = 3(1 + 2 + 3 + 4 + 5)/5
= 45/5
= 9.
Answer:B
Answer: B
Question: A bowl of fruit contains 14 apples and 23 oranges. How many oranges must be removed so that 70% of the pieces of fruit in the bowl will be apples?
Options:
A)3
B)6
C)14
D)17
E)20
Rationale: Number of apples = 14
number of oranges = 23
let number of oranges that must be removed so that 70% of pieces of fruit in bowl will be apples = x
Total number of fruits after x oranges are removed = 14+(23-x) = 37-x
14/(37-x) = 7/10
=>20 = 37-x
=>x= 17
Answer D
Answer: D
Question: The milk level in a rectangular box measuring 58 feet by 25 feet is to be lowered by 6 inches. How many gallons of milk must be removed? (1 cu ft = 7.5 gallons)
Options:
A)100
B)250
C)750
D)5437.5
E)5635.5
Rationale: 6 inches = 1/2 feet (there are 12 inches in a foot.), so 58*25*1/2=725 feet^3 of milk must be removed, which equals to 725*7.5=5437.5 gallons.
Answer: D.
Answer: D
Question: According to the directions on a can of frozen orange juice concentrate, 1 can of concentrate is to be mixed with 3 cans of water to make an orange juice. How many 12 ounce cans of concentrate are required to prepare 200 6-ounce servings of orange juice.
Options:
A)25
B)34
C)50
D)67
E)100
Rationale: A =25
1 oz concentrate + 3 oz ofwater = 4 oz jucie
300 oz concentrate +900 oz of waer = 1200 oz juice
no of cans==300/12=25
Ratio of juice to water ===> 1:3
total 200*6 ounces
12 ounce juice cans ==> 1200/12 == 100*1/4 (ratio of jiuce to total) == 25
Answer: A
Question: The profit earned by selling an article for Rs. 832 is equal to the loss incurred when the same article is sold for Rs. 448. What should be the sale price for making 70% profit?
Options:
A)220
B)1088
C)960
D)780
E)400
Rationale: C.P. = Rs. x.
Then, 832 - x = x - 448
2x = 1280 => x = 640
Required S.P. = 170% of Rs. 640 = 170/100 * 640 = Rs. 1088.
B
Answer: B
Question: A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 390 sq. feet, how many feet of fencing will be required?
Options:
A)34
B)59
C)68
D)88
E)92
Rationale: Given that length and area, so we can find the breadth.
Length x Breadth = Area
20 x Breadth = 390
Breadth = 19.5 feet
Area to be fenced = 2B + L = 2 (19.5) + 20 = 59 feet answer : B
Answer: B
Question: Find the largest number of four digits which is exactly divisible by 27,18,12,15
Options:
A)9700
B)9710
C)9720
D)9730
E)9740
Rationale: Explanation:
LCM of 27-18-12-15 is 540.
After dividing 9999 by 540 we get 279 remainder.
So answer will be 9999-279 = 9720
Option C
Answer: C
Question: If x and y are integers and x=50y + 69, which of the following must be odd?
Options:
A)xy
B)x + y
C)x + 2y
D)3x-1
E)3x+1
Rationale: x = 50y + 69, since y is integer, 50y will always be even hence 50y + 69 will be odd hence x = odd
you don't know whether Y is even or odd, so you need to try.
A: odd * even = even ; odd*odd= odd ->not true
B: odd + odd = even ; odd+even = odd -> not true
C: odd + 2*odd = odd ; odd + 2*even = odd -> TRUE, stop here.
Answer C
Answer: C