divelab/Sys2Bench huggingface dataset:
Question: In a 100 m race, A can give B 10 m and C 28 m. In the same race B can give C :
Options:
A)10 m
B)15 m
C)20 m
D)30 m
E)25 m
Rationale: "A can give B 10 m".
In a 100 m race, while A starts from the starting point, B starts 10 meters ahead from the same starting point at the same time.
"A can give C 28 m"
In a 100 m race, while A starts from the starting point, C starts 28 meters ahead from the same starting point at the same time.
i.e., in a 100-10=90 m race, B can give C 28-10=18 m
In a 100 m race, B can give C18/90×100 = 20 m
Answer is C
Answer: C
Question: Find 94 ×× 97
Options:
A)93/198
B)93/12
C)93/18
D)93/10
E)93/11
Rationale: Here both numbers are less than 100. So they are deficient of - 6 and - 3 compared with 100. So
Answer:	C
Answer: C
Question: A train covers a distance of 12 km in 10 min. If it takes 6 sec to pass a telegraph post, then the length of the train is?
Options:
A)177
B)168
C)120
D)882
E)122
Rationale: Speed = (12/10 * 60) km/hr = (72 * 5/18) m/sec = 20 m/sec.
Length of the train = 20 * 6 = 120 m.Answer:C
Answer: C
Question: Torry has submitted 3/5 of his homework assignments, and he received an average grade of 75 for those assignments. If he wishes to receive an average grade of 90 for all his homework assignments, the average grade for Torry's remaining homework assignments must be what percent greater than the average grade for the assignments he has already submitted?
Options:
A)15%
B)20%
C)25%
D)33 1/3%
E)50%
Rationale: 0.6*75 + 0.4x = 90
45 + 0.4x=90
0.4x = 45
x= 112.5
112.5/75= 1.5
Ans:E
Answer: E
Question: The ratio of number of boys and girls in a school is 1:2. If there are 90 students in the school, find the number of girls in the school?
Options:
A)45
B)50
C)60
D)75
E)90
Rationale: Let the number of boys and girls be x and 2x
Total students = 100
Number of girls in the school = 2*90/3 = 60
Answer is C
Answer: C
Question: If you roll a fair-sided die twice, what is the probability of getting a double?
Options:
A)1/3
B)1/6
C)1/12
D)1/24
E)1/36
Rationale: ways you can get double - 6...as each dice showing any number from 1 to 6...
total ways = 6∗6=36.6∗6=36..
P=6/36=1/6
ANSWER: B
Answer: B
Question: What is 35% of 4/13 of 715?
Options:
A)44
B)55
C)66
D)77
E)88
Rationale: This problem can be solved easily if we just use approximation: 35% is a little over 1/3, while 4/13 is a little less than 4/12, which is 1/3. Thus, the answer is about 1/3 of 1/3 of 715, or 1/9 of 715. Since the first 1/3 is a slight underestimate and the second 1/3 is a slight overestimate, the errors will partially cancel each other out. Our estimate will be relatively accurate.
The number 715 is about 720, so (1/9)*715 will be a bit less than 80.
Keeping track not only of your current estimate, but also of the degree to which you have overestimated or underestimated , can help you pinpoint the correct answer more confidently.
The closest answer is 77, so this is the answer to choose.
The answer is D.
Answer: D
Question: Dinesh speaks truth in 3/4 cases and Abhishek lies in 1/5 cases. What is the percentage of cases in which both Dinesh and Abhishek contradict each other in stating a fact?
Options:
A)60%
B)35%
C)20%
D)15%
E)None of these
Rationale: Explanation :
D and A will contradict each other when one speaks truth and other speaks lies.
Probability of D speak truth and A lies
=>(3/4)×(1/5).
=>3/20.
Probability of A speak truth and D lies
=>(4/5)×(1/4).
=>1/5.
The two probabilities are mutually exclusive. Hence, probabilities that D and A contradict each other:
=>(3/20)+(1/5).
=>7/20.
=>0.35×100%
=>35%
Answer : B
Answer: B
Question: A man drive his car to the office at 20miles/hr.
After reaching office, he realize that its a new year holiday so he went back home at a speed of 30miles/hr.
Discounting the time spent in the stoppage what was his average speed of his journey ?
Options:
A)23miles
B)25miles
C)22miles
D)24miles
E)26miles
Rationale: D
24miles/hr (not 25miles/hr which might be guessed by many)
D : distance traveled
T1 : time of going to office
T2 : time of returning back
Y : Average Speed
D = 20 * T1
T1 = D/20
D = 30 * T2
T2 = D/30
2D = Y(T2 + T1)
2D = Y(D/20 + D/30)
2D = Y(3D/60 + 2D/60)
2D = Y(5D/60)
Y = 120D/5D
=> Y = 24
Answer: D
Question: The average (arithmetic mean) of 22, 33, and 53 is 8 less than the average of 30, 56, and x. What is x?
Options:
A)42
B)44
C)46
D)48
E)50
Rationale: The average of 22, 33, and 53 is 108/3 = 36.
The average of 30, 56 and x is 44.
Then 30 + 56 + x = 132.
x = 46.
The answer is C.
Answer: C
Question: Abby and Bobby type at constant rates of 80 words per minute and 60 words per minute, respectively. Bobby begins typing before Abby and has typed 600 words when Abby begins typing at 1:30 pm. If they continue typing at their respective rates, at what time will Abby have typed exactly 300 more words than Bobby?
Options:
A)1:40 PM
B)1:50 PM
C)2:00 PM
D)2:15 PM
E)2:20 PM
Rationale: Say time needed for Abby to type 200 more words than Bobby is t. In that time she would type 80t words and Bobby would type 60t words.
Now, total words typed by Bobby would be 600+60t and we want that number to be 200 less than 80t: 600+60t=80t-300 --> t=45.
1:30 PM + 45 minutes = 2:15 PM.
Answer: D.
Answer: D
Question: Three runners E, B and C run a race, with runner E finishing 12m ahead of runner B and 18m ahead of runner C, while runner B finishes 8m ahead of runner C. Each runner travels entire distance at a constant speed. What was the length of the race?
Options:
A)36m
B)48m
C)60m
D)72m
E)84m
Rationale: Let distance of race be x mtrs. Then when E finishes x m , B has run (x- 12)mtrs and C has run x-18 mtrs. so at this point B is 6 m ahead of C. Now to finish race b needs to run another 12 m, so he runs another 12 m. when B finishes race he is 8 m ahead of C. so last 12 m B has run, C has run 10 m.
as speeds are constant, we have equation,
x-12/ x-18 = 12/10 > x = 48.
Answer B
Answer: B
Question: A man saves 20% of his monthly salary. If an account of dearness of things he is to increase his monthly expenses by 20%, he is only able to save Rs. 260 per month. What is his monthly salary?
Options:
A)5000
B)2999
C)2878
D)2990
E)6500
Rationale: Income = Rs. 100
Expenditure = Rs. 80
Savings = Rs. 20
Present Expenditure 80*(20/100) = Rs. 96
Present Savings = 100 â€“ 96 =Rs. 4
100 ------ 4
? --------- 260 => 6500
Answer: E
Answer: E
Question: letters in the word ABUSER are permuted in all possible ways and arranged in alphabetical order then find the word at position 49 in the permuted alphabetical order?
Options:
A)KASJJHJ
B)DGUJKL
C)ARBESU
D)ILUGUO
E)HDIWWD
Rationale: Ans: The best way to solve this problems is Just ask how many words starts with A. If we fix A, then the remaining letters can be arranged in 5! ways = 120. So the asked word must start with A.
Arrange all the given letters in alphabetical order. ABERSU
Let us find all the words start with AB. AB**** = 4!= 24 ways
Now we find all the words start wit AE. AE****= 4!= 24 ways
So next word start with AR and remaining letters are BESU
Answer:C
Answer: C
Question: If 1/12 of the passengers on a ship are from North America, 1/4 are Europeans, 2/9 are from Africa, 1/6 are from Asia and the remaining 50 people are citizens of other continents, then how many passengers are on board the ship?
Options:
A)120
B)140
C)150
D)160
E)180
Rationale: 1/12 + 1/4 + 2/9 + 1/6 = (3+9+8+6)/36 = 13/18
Let x be the number of passengers on the ship.
50 = (5/18)x
x = 180
The answer is E.
Answer: E
Question: If it takes 6 identical printing presses exactly 4 hours E to print 5,000 newspapers, how long would it take 3 of these presses to print 3,000 newspapers?
Options:
A)3 hours, 20 minutes
B)4 hours, 20 minutes
C)4 hours, 48 minutes
D)5 hours, 48 minutes
E)6 hours, 50 minutes
Rationale: 6 presses - 5,000 newspapers - 4 hours ;
3 presses - 2,500 newspapers - 4 hours ;
3 presses - 3,000 newspapers - 4 hours + 1/5*4 hours = 4 hours, 48 minutes (since 2,500+1/5*2,500=3,000) = E.
Answer: C.
Answer: C
Question: A fast food hotel sells chicken in orders of 6, 9, and 20.
What is the largest number of pieces of chicken you cannot order from this hotel ?
Options:
A)A)23
B)B)33
C)C)43
D)D)53
E)E)63
Rationale: 43.
After 6 all numbers divisible by 3 can be ordered (because they can all be expressed as a sum of 6's and 9's). After 26, all numbers divisible by three when subtracted by 20 can be obtained. After 46, all numbers divisible by three when subtracted by 40 can be obtained. After 46, all numbers fit into one of these 3 categories, so all numbers can be obtained. 43 is the last number that doesn't fall into one of these categories (44 = 20 + 6 * 4, 45 = 6 * 6 + 9). answer is C
Answer: C
Question: A person walks at a speed of 4 km/hr and runs at a speed of 8 km/hr. How many hours will the person require to cover a distance of 8 km, if the person completes half of the distance by walking and the other half by running?
Options:
A)0.5
B)1.5
C)2.5
D)3.5
E)4.5
Rationale: time = 4/4 + 4/8 = 12/8 = 1.5 hours
The answer is B.
Answer: B
Question: How many positive integers less than 200 are there such that they are multiples of 13 or multiples of 12?
Options:
A)28
B)29
C)30
D)31
E)32
Rationale: Total Multiples of 13: 15 (First multiple:13, last multiple:195)
Total Multiples of 12:16 (First multiple: 12,Last multiple: 192)
Multiple of 12 and 13: 1 (156)
15+16-1=30
ANSWER:C
Answer: C
Question: Find the sum of all odd numbers upto 100.
Options:
A)2200
B)2900
C)2700
D)2500
E)2800
Rationale: The given numbers are 1, 3, 5, 7, ..., 99.
This is an A.P. with a = 1 and d = 2.
Let it contain n terms. Then,
1 + (n - 1) x 2 = 99 or n = 50.
Therefore, Required sum = n/2 (first term + last term)
= 50/2 (1 + 99) = 2500.
Answer is D.
Answer: D
Question: A and B can together finish a work in 40days. They worked together for 10days and then B left. After another 9days, A finished the remaining work. In how many days A alone can finish the job?
Options:
A)12
B)25
C)60
D)30
E)20
Rationale: A+B 10days work = 10*1/40 = 1/4
Remaining work = 1-1/4 = 3/4
3/4 work is done by A in 9 days
whole work will be done by A in 9*4/3 = 12 days
Answer is A
Answer: A
Question: The sum of the squares of three consecutive natural number is 2030. What is the middle number?
Options:
A)25
B)26
C)27
D)28
E)29
Rationale: Let the numbers be x, x+1 and x+2
X2+(x+1)2+(x+2)2=2030
3x2+6x-2025=0
(x+27)(x-25)=0
X=25
The middle number is 26
ANSWER B 26
Answer: B
Question: A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 47, then how old is B?
Options:
A)17 years
B)19 years
C)18 years
D)10 years
E)12 years
Rationale: Let C's age be x years.
Then, B's age = 2x years.
A's age = (2x + 2) years.
(2x + 2) + 2x + x = 47
5x = 45 => x = 9
Hence, B's age = 2x = 18 years.
Answer: C
Answer: C
Question: In a mixture of 60 liters, the ratio of milk and water is 4:1. What amount of water must be added to make the ratio of milk and water as 1:4?
Options:
A)60 liters
B)42 liters
C)68 liters
D)65 liters
E)62 liters
Rationale: 4:1 --- 60
1:4
2:8
---------------
5
5 ----------- 60
5 ----------- ? => 60 liters
ANSWER:A
Answer: A
Question: At a local appliance manufacturing facility, the workers received a 10% hourly pay raise due to extraordinary performance. If one worker decided to reduce the number of hours that he worked so that his overall pay would remain unchanged, by approximately what percent would he reduce the number of hours that he worked?
Options:
A)83%
B)80%
C)20%
D)17%
E)9%
Rationale: Let's say he works usually 10 hours and earns 100 per hour.
10 * 100 = 1000
10 * 110 = 1100 (this are the new earnings after the raise)
To figure out how much he needs to work with the new salary in order to earn the original 1000:
1000/110= 9.09
So he can reduce his work by 0.91 hours. Which is >9%.
Answer E
Answer: E
Question: The profit earned by selling an article for 812 is equal to the loss incurred when the same article is sold for 448. What should be the sale price of the article for making 50 per cent profit?
Options:
A)960
B)1060
C)1,200
D)945
E)None of these
Rationale: Let the profit or loss be x
and 812 – x = 448 + x or, x = 364⁄2 = 182
\ Cost price of the article = 812 – x = 448 + x = 630
\ SP of the article = 630 × 150⁄100 = 945
Answer D
Answer: D
Question: What will be the difference between simple and compound interest at 10% per annum on a sum of Rs. 1000 after 4 years?
Options:
A)64.19
B)64.12
C)62.1
D)64.1
E)64.11
Rationale: S.I. = (1000 * 10 * 4)/100 = Rs. 400
C.I. = [1000 * (1 + 10/100)4 - 1000] = Rs. 464.10 Difference = (464.10 - 400) = Rs. 64.10
Answer: D
Answer: D
Question: In a certain game, you perform three tasks. You flip a coin, and success would be heads. You roll a single die, and success would be a three. You pick a card from a full playing-card deck, and success would be picking a spades card. If exactly one of these three tasks is successful, then you win the game. What is the probability of winning?
Options:
A)11/16
B)15/32
C)14/36
D)17/56
E)23/48
Rationale: The answer is E
Probability of just one enent will be happining
So, Probability heads=1/2
Probability number 3 =1/6
Probability picking a spades card =1/4
so, Probability win by getting tails= 1/2*5/6*3/4 = 15/48
Probability win by getting number 6 = 1/2*1/6*3/4 = 3/48
Probability win by picking a spades card =1/2*5/6*1/4=5/48
Probability wining= 15/48+3/48+5/48 =23/48
Answer: E
Question: For a recipe for triple berry pie calls for cups of strawberries, raspberries, and blueberries in a ratio of 1:2:3. How many total cups of fruit will you need to make the pie?
Options:
A)2
B)3
C)4
D)5
E)6
Rationale: The ratio 1:2:3 represents 1 cup strawberries: 2 cups raspberries: 3 cups blueberries.
1+2+3 = 6
6 cups will be used for the pie.
The answer is E
Answer: E
Question: Mahesh can do a piece of work in 30days. He works at it for 20days and then Rajesh finished it in 30days. How long will Y take to complete the work?
Options:
A)90
B)25
C)37
D)41
E)30
Rationale: Work done by Mahesh in 30days = 20*1/30 = 2/3
Remaining work = 1 - 2/3 = 1/3
1/3 work is done by Rajesh in 30days
Whole work will be done by Rajesh is 30*3 = 90days
Answer is A
Answer: A
Question: After M students took a test, the average score was 72%. If the test has 50 questions, what is the least number of questions that the next student has to get right to bring the average score up to 75%?
Options:
A)1.5M + 36
B)72 - 1.5M
C)1.5M + 37.5
D)0.75 + 1.5M
E)1.5M + 0.72
Rationale: The total number of correct answers for M students is (0.72)*50*M=36*M
For an average of 75%: (total correct answers) / (M+1) = 0.75*50=37.5
Let x be the number of correct answers for the next student.
(x + 36M) / M+1 = 37.5
x + 36M= 37.5M+37.5
x = 1.5M + 37.5
The answer is C.
Answer: C
Question: By selling 80 pens, a trader gains the cost of 20 pens. Find his gain percentage?
Options:
A)25%
B)30%
C)35%
D)40%
E)50%
Rationale: Let the CP of each pen be Rs. 1.
CP of 80 pens = Rs. 80
Profit = Cost of 20 pens = Rs. 20
Profit% = 20/80 * 100 = 25%
Answer:A
Answer: A
Question: A train travels from station A to station B. If the train leaves station A and makes 75 km/hr, it arrives at station B 48 minutes ahead of scheduled. If it made 50 km/hr, then by the scheduled time of arrival it would still have 40 km more to go to station B. Find:
A) The distance between the two stations;
B) The time it takes the train to travel from A to B according to the schedule;
C) The speed of the train when it's on schedule.
Options:
A)34
B)27
C)26
D)28
E)60
Rationale: Let xx be the scheduled time for the trip from A to B. Then the distance between A and B can be found in two ways. On one hand, this distance equals 75(x−4860)75(x−4860) km. On the other hand, it is 50x+4050x+40 km. So we get the equation:
75(x−4860)=50x+4075(x−4860)=50x+40
x=4x=4 hr is the scheduled travel time. The distance between the two stations is 50⋅4+40=24050⋅4+40=240 km. Then the speed the train must keep to be on schedule is 2404=602404=60 km/hr.
Answer:E
Answer: E
Question: In an examination, a pupil’s average marks were 63 per paper. If he had obtained 20 more marks for his Geography paper and 2 more marks for his history paper, his average per paper would have been 65. How many papers were there in the examination?
Options:
A)8
B)9
C)10
D)11
E)12
Rationale: Solution
Let the number pf papers be x.
Then, 63x + 20+2=65x
65x-63x=22
2x = 22
x = 11.
Answer D
Answer: D
Question: Maddie has 18 apples, if she give 12 to mike, how many does she have left?
Options:
A)1
B)6
C)3
D)4
E)5
Rationale: 18-12=6
B. 6
Answer: B
Question: At a garage sale, all of the items were sold at different prices. If the price of a radio sold at the garage sale was both the 18th highest price and the 25th lowest price among the prices of the items sold, how many items were sold at the garage sale?
Options:
A)41
B)42
C)43
D)44
E)45
Rationale: There were 17 items sold at a higher price than the radio and 24 items sold at a lower price than the radio. Including the radio, there were 17 + 24 + 1 = 42 items sold.
The answer is B.
Answer: B
Question: Two numbers are in the ratio of 5:7. If 25 be subtracted from each, they are in the ratio of 35:59. Find the numbers?
Options:
A)60,85
B)60,61
C)60,18
D)60,84
E)60,15
Rationale: =(5x-25):(7x-25) = 35:59
x = 12 => 60,84
Answer: D
Answer: D
Question: In a game of billiards, A can give B 20 points in 60 and he can give C 30 points in 60. How many points can B give C in a game of 130?
Options:
A)15
B)77
C)55
D)18
E)12
Rationale: A scores 60 while B score 40 and C scores 30.
The number of points that C scores when B scores 100 = (100 * 30)/40 = 25 * 3 = 75.
In a game of 100 points, B gives (130 - 75) = 55 points to C.
Answer:C
Answer: C
Question: How many of the following numbers are divisible by 14 ?
264, 396, 462, 792, 968, 2178, 5184, 6336
Options:
A)3
B)4
C)5
D)6
E)1
Rationale: By using your calculator you can calculate that the following numbers are divisible by 14 : 462.
Required number of number = 1.
E
Answer: E
Question: What is the least number of square tiles required to pave the floor of a room 50 m 00 cm long and 11m 25 cm broad?
Options:
A)724
B)804
C)814
D)9000
E)None
Rationale: Solution
Length of largest tile = H.C.F. of 5000cm & 1125cm = 25cm.
Area of each tile = (25 x 25)cm2
∴ Required number of tiles	= [5000x1125/25x25]
= 9000.
Answer D
Answer: D
Question: Karen places a bet with Tom that she will beat Tom in a car race by 4 miles even if Karen starts 4 minutes late. Assuming that Karen drives at an average speed of 60 mph and Tom drives at an average speed of 45 mph, how many Q miles will Tom drive before Karen wins the bet?
Options:
A)15
B)18
C)21
D)24
E)27
Rationale: Let K and T be the speeds of Karen and Tom respectively.
t be the time that Karen will travel ----> t+4/60 will be the total time Tom will travel by the time the distance between Karen and Tom is 4 miles.
Thus, per the question , K(t) - T(t+4/60) = 4 ---> t = 7/15 hours
Thus the distance traveled by Tom when Karen is 4 miles ahead of him : T*(t+4/60) = 45 (7/15+4/60) Q= 24 miles. D is the correct answer.
Answer: D
Question: In Arun's opinion, his weight is greater than 65 kg but less than 72 kg. His brother doest not agree with Arun and he thinks that Arun's weight is greater than 60 kg but less than 70 kg. His mother's view is that his weight cannot be greater than 68 kg. If all are them are correct in their estimation, what is the average of different probable weights of Arun?
Options:
A)67 kg
B)68 kg
C)69 kg
D)Data inadequate
E)None of these
Rationale: Explanation:
Let Arun's weight by X kg.
According to Arun, 65 < X < 72
According to Arun's brother, 60 < X < 70.
According to Arun's mother, X <= 68
The values satisfying all the above conditions are 66, 67 and 68.
Required average = 66 + 67 + 68/ 3 = 201	/ 3	= 67 kg.
ANSWER IS A
Answer: A
Question: There are 27 different three-digit integers that can be formed using only the digits 1, 3, and 4. If all 27 of the integers were listed, what would their sum be?
Options:
A)7592
B)7692
C)7792
D)7892
E)7992
Rationale: There must be nine 1's in the hundreds place, nine 1's in the tens place, and nine 1's in the units place. This is also true for the 3's and 4's. Then the sum is:
9(111+333+444)=9*(888)=7992.
The answer is E.
Answer: E
Question: Mary's income is 500 dollars per week. How much does she makes every year?
Options:
A)1000 dollars
B)12000 dollars
C)4000 dollars
D)5000 dollars
E)26000 dollars
Rationale: Solution:
1 year = 52 weeks.
Mary's one week's income = 500 dollars
Thus, 500 Ã— 52 = 26,000 dollars
Option E
Answer: E
Question: Q is as much younger than R as he is older than T. If the sum of the ages of R and T is 50 years, what is definitely the difference between R and Q's age?
Options:
A)23
B)28
C)25
D)19
E)11
Rationale: Explanation:
Given
R – Q = Q – T and R + T = 50 which gives Q = 25
As the difference between R & Q and Q & T is same
So Answer is 25 years
Answer: C
Answer: C
Question: In the floor of a particular kitchen owned by an abstract artist, each row of tiles to the right of the first row contains two fewer tiles than the row directly to its left. If there are nine rows in all and a total of 360 tiles in the floor, how many tiles does the leftmost row contain?
Options:
A)48
B)56
C)60
D)64
E)68
Rationale: This question can be solved in a variety of ways: with algebra, by TESTing THE ANSWERS and by using a great Number Property shortcut involving consecutive integers.
We're given a few facts to work with:
1) There are 9 rows of tiles.
2) When going from 'left to right', each row contains TWO FEWER tiles than the one next to it.
3) There are a total of 360 tiles
We're asked how many tiles the left-most most row holds (meaning the one with the MOST tiles).
To start, 360 is divisible by 9, so we can figure out the AVERAGE number of tiles per row. That is 360/9 = 48. Since we're dealing with a set of 9 consecutive integers that differ by 2 each, we know that the '5th row' will have 48 tiles (the average). Then we just have to 'add 2s' until we get to the first row...
40 +2 +2 +2 +2 = 48.
Final Answer:
A
Answer: A
Question: When Q is divided by W, the quotient is R and the remainder is X. Which of the following expressions is equal to X?
Options:
A)RW + Q
B)RW - Q
C)Q/R
D)QW - R
E)Q - RW
Rationale: Q/W = R + X/W
Q -RW = X
Amswer: E
Answer: E
Question: A and B invests Rs.3000 and Rs.4500 respectively in a business. If A doubles his capital after 6 months. In what ratio should A and B divide that year's profit?
Options:
A)6:8
B)9:8
C)7:9
D)9:5
E)1:1
Rationale: (3*6 + 6*6): (4.5*12)
54:54 => 1:1
Answer: E
Answer: E
Question: Mr.Jones gave 40% of the money he had to his wife. he also gave 20% of the remaining amount to his 3 sons. half of the amount now left was spent on miscellaneous items and the remaining amount of Rs.12000 was deposited in the bank. how much money did Mr.jones have initially?
Options:
A)100000
B)12000
C)15000
D)13000
E)65000
Rationale: Let the initial amount with Mr.Jones be Rs.x
Then, (1/2)[100-(3*20)]% of x=12000
 (1/2)*(40/100)*(60/100)*x=12000
x=((12000*25)/3)=100000
ANSWER A
Answer: A
Question: On a schoolâ€™s Annual day sweets were to be equally distributed amongst 112 children. But on that particular day, 32 children were absent. Thus the remaining children got 6 extra sweets. How many sweets was each child originally supposed to get ?
Options:
A)28
B)27
C)11
D)15
E)19
Rationale: Explanation:
Let 'K' be the total number of sweets.
Given total number of students = 112
If sweets are distributed among 112 children,
Let number of sweets each student gets = 'L'
=> K/112 = L ....(1)
But on that day students absent = 32 => remaining = 112 - 32 = 80
Then, each student gets '6' sweets extra.
=> K/80 = L + 6 ....(2)
from (1) K = 112L substitute in (2), we get
112L = 80L + 480
32L = 480
L = 15
Therefore, 15 sweets were each student originally supposed to get.
Answer: D
Answer: D