divelab/Sys2Bench huggingface dataset:
Question: How many two-digit numbers are there such that all two digits are different and the first digit is not zero?
Options:
A)50
B)64
C)72
D)79
E)81
Rationale: All two digits are different and first digit is not zero.
So first digit can be filled in 9 ways.
And, second digit can be filled in 8 ways.
Total ways = 9*8
= 72
Hence option (C).
Answer: C
Question: A child want to buy 5 new toys. If there are 15 toys that satisfy the child's criteria,in how many different ways can the child select the 5 new toys if the order of selection doesn't matter.
Options:
A)210
B)1365
C)3003
D)5005
E)3030
Rationale: The number of ways of choosing 5 toys out of 15 are counted by = 15C5 ways = 3003
Answer: Option C
Answer: C
Question: The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is?
Options:
A)288
B)277
C)245
D)266
E)261
Rationale: Speed = [45 X 5/18] m/sec = [25/2] m/sec Time
= 30 sec Let the length of bridge be x metres. Then, (130 + x)/30
= 25/2 => 2(130 + x)
= 750 => x = 245 m.
Answer: C
Answer: C
Question: what is the next term of this series6,10,9,15,12...?
Options:
A)9
B)20
C)11
D)12
E)15
Rationale: 3&2=6;
5*2=10;
3*3=9;
3*5=15
3*4=12
5*4=20.
ANSWER:B
Answer: B
Question: For 600 km journey it will take 8hrs, if 120 km is done by bus and the rest by car. It takes 20 minutes more, if 200 km is done by busand the rest by car. The ratio of the speed of the train to that of the cars is?
Options:
A)1 : 2
B)3 : 4
C)2:5
D)5:7
E)7:9
Rationale: Let the speed of the train be x km/hr and that of the car be y km/hr.
Then, 120 + 480 = 8 1 + 4 = 1 ....(i)
x y x y 15
And, 200 + 400 = 25 1 + 2 = 1 ....(ii)
x y 3 x y 24
Solving (i) and (ii), we get: x = 60 and y = 80.
Ratio of speeds = 60 : 80 = 3 : 4.
B
Answer: B
Question: If g(x) = ax^5 + bx^3 + 2, and g(5) = 10, then g(–5) =?
Options:
A) – 10
B) – 8
C) – 6
D) 0
E) 4
Rationale: g(5) = 10
or, 5^5 a + 5^3 b + 2 = 10
or, 5^5 a + 5^3 b = 8
g(-5) = -5^5 a - 5^3 b + 2 = - (5^5 a + 5^3 b) + 2 = - 8 + 2 = - 6 = (C)
Answer: C
Question: A 70 cm long wire is to be cut into two pieces so that one piece will be 2/5th of the other, how many centimeters will the shorter piece be?
Options:
A)21
B)20
C)17
D)12
E)18
Rationale: 1: 2/5 = 5: 2
2/7 * 70 = 20
Answer: B
Answer: B
Question: Find the number of ways of arranging the letters of the word "MATERIAL" such that all the vowels in the word are to come together?
Options:
A)1444
B)1440
C)1443
D)1432
E)1435
Rationale: In the word, "MATERIAL" there are three vowels A, I, E.
If all the vowels are together, the arrangement is MTRL'AAEI'.
Consider AAEI as one unit. The arrangement is as follows.
M T R L A A E I
The above 5 items can be arranged in 5! ways and AAEI can be arranged among themselves in 4!/2! ways.
Number of required ways of arranging the above letters = 5! * 4!/2!
= (120 * 24)/2 = 1440 ways.
Answer:B
Answer: B
Question: 12+6=792
10+2=110
1+9=9
2+7=16
11+4=??
Solve it?
Options:
A)100
B)120
C)190
D)160
E)154
Rationale: x+y=x[y+(x-1)]=x^2+xy-x
12+6=12[6+(12-1)]=792
10+2=10[2+(10-1)]=110
1+9=1[9+(1-1)]=9
2+7=2[7+(2-1)]=16
11+4=11[4+(11-1)]=154
Answer :E
Answer: E
Question: If 20 typists can type 50 letters in 30 minutes, then how many letters will 40 typists working at the same rate complete in 1 hour?
Options:
A)400
B)500
C)350
D)250
E)200
Rationale: No. of letters typing by 20 typists in 30 minutes = 50
No. of letters typing by 20 typists in 60 minutes = 50*2 = 100
No. of letters typing by 40 typists in 60 minutes = 100/10*40 = 400
Answer : A
Answer: A
Question: Ages of two sisters differ by 9 years. If 5 years ago, the elder one was twice as old the younger one, find their present age
Options:
A)12,28
B)14,23
C)16,32
D)18,34
E)19,32
Rationale: Explanation:
Let the age of younger sister be x,
Then elder sister's age is (x+9)
=> 2(x-5) = (x+9-5) [5 years before]
=> 2x-10 = x+4
=> x = 14.
So older sister's age is x + 9 = 23
Answer: Option B
Answer: B
Question: Analyze the number square carefully and find out what number fits in place of question mark.
35	20	14
27	12	18
6	4	?
Options:
A)6
B)12
C)24
D)36
E)8
Rationale: 20 fits in place of question mark.
This is because (number in first column) / (number in second column) * 8 = number in third column.
Here (left number / middle number) * 8 = right number
(6 / 4) * 8 = 6*2= 12
B
Answer: B
Question: If A, B and C together can finish a piece of work in 4 days. A alone in 12 days and B in 18 days, then C alone can do it in?
Options:
A)20
B)22
C)30
D)10
E)9
Rationale: C = 1/4 - 1/12 â€“ 1/18 = 1/9 => 9 days
ANSWER E
Answer: E
Question: To reach her destination, Jeanette must drive 90 miles. If she drives 5 miles every 6 minutes, how much time will it take her to reach her destination?
Options:
A)2 hours and 2 minutes
B)1 hours and 48 minutes
C)2 hours and 10 minutes
D)2 hours and 12 minutes
E)2 hours and 15 minutes
Rationale: 6 minute for 5 miles how much for 90? minutes for 1(6/5) mile multiplied by 90 miles.
6*90/5= 108> 1 hours 48 min answer is B
Answer: B
Question: If the number of 194,n70, where n represents the hundreds digit, is a multiple of 9, then the value of n could be which of the following?
Options:
A)6
B)5
C)4
D)2
E)1
Rationale: Divisibility rule of 9: The sum of the digits must be divisible by 9
i.e 1+9+4+n+7+0 = multiple of 9
or, 21 + n = multiple of 9.
If n=6, 21 + n =27,which is a multiple of 9.
Hence answer is A.
Answer: A
Question: How many two letter words are formed using the letters of the word BOOK?
Options:
A)12
B)10
C)6
D)3
E)9
Rationale: The number of letters in the given word is four.
The number of TWO letter words that can be formed using these four letters is 4P2 = 4 * 3 = 12.
Answer:A
Answer: A
Question: A gambler bought $4,000 worth of chips at a casino in denominations of $20 and $100. That evening, the gambler lost 16 chips, and then cashed in the remainder. If the number of $20 chips lost was 2 more or 2 less than the number of $100 chips lost, what is the largest amount of money that the gambler could have received back?
Options:
A)$2,040
B)$2,120
C)$1,960
D)$3,120
E)$1,400
Rationale: In order to maximize the amount of money that the gambler kept, we should maximize # of $20 chips lost and minimize # of $100 chips lost, which means that # of $20 chips lost must be 2 more than # of $100 chips lost.
So, if # of $20 chips lost is x then # of $100 chips lost should be x-2. Now, given that total # of chips lost is 16: x+x-2=16 --> x=9: 9 $20 chips were lost and 9-2=7 $100 chips were lost.
Total worth of chips lost is 9*20+7*100=$880, so the gambler kept $4,000-$880=$3,120.
Answer: D
Answer: D
Question: A garrison of 400 men had a provision for 31 days. After 28 days 280 persons re-enforcement leave the garrison. Find the number of days for which the remaining ration will be sufficient?
Options:
A)16 days
B)34 days
C)10 days
D)16 days
E)15 days
Rationale: 400 --- 31
400 --- 3
120 --- ?
400*3 = 120*x => x
=10 days
Answer: C
Answer: C
Question: The temperature of a certain cup of coffee 2 minutes after it was poured was 120 degrees Fahrenheit. If the temperature F of the coffee t minutes after it was poured can be determined by the formula F = 120*2^(-at) + 60, where F is in degrees Fahrenheit and a is a constant. Then the temperature of the coffee 30 minutes after it was poured was how many degrees Fahrenheit?
Options:
A)65
B)60.003662
C)80.2
D)85
E)90
Rationale: First, we have to find a.
We know that after t=2 minutes the temperature F=120 degrees.
Hence:
120 = 120*(2^-2a)+60
60 = 120*(2^-2a)
60/120 = 2^-2a
1/2 = 2^-2a
2^-1 = 2^-2a
-1 = -2a
1/2 = a
Now we need to find F after t=30 minutes:
F = 120*(2^-1/2*30)+60
F = 120* (2^-15) +60
F = 120* (1/2^15) +60
F = 120*1/32768 +60
F = 0.003662+60 = 60.003662
Answer B!
Answer: B
Question: Statement: Put thechild in school at the age of 5. Assumptions: At that age the child reaches appropriate level of development and is ready to learn. The schools do not admit children after 6years of age.
Options:
A)Only assumption I is implicit
B)Only assumption II is implicit
C)Either I or II is implicit
D)Neither I nor II is implicit
E)Both I and II are implicit
Rationale: Since the statement talks of putting the child in school at the age of 5, it means that the child is mentally prepared for the same at this age. So, I is implicit. But nothing about admission after 6 years of age is mentioned in the statement. So, II is not implicit.
A
Answer: A
Question: A number when divided by 5 gives a number which is 8 more than the remainder obtained on dividing the same number by 34. Such a least possible number M is
Options:
A)74
B)M=75
C)M=175
D)M=680
E)690
Rationale: I solved this question by plugging in numbers from the answer choices.
A.) 74
Starting with answer choice A, I immediately eliminated it because 74 is not even divisible by 5.
B.) 75
I divide 75/5 and get 15 as an answer. I divide 75/34 and get a remainder of 7.
15-7 = 8 so I know the correct answer isB
Answer: B
Question: On what dates of April, 2001 did Wednesday fall?
Options:
A)1st, 8th, 15th, 22nd, 29th
B)2nd, 9th, 16th, 23rd, 30th
C)3rd, 10th, 17th, 24th
D)4th, 11th, 18th, 25th
E)None of these
Rationale: EXPLANATION
We shall find the day on 1st April, 2001.
1st April, 2001 = (2000 years + Period from 1.1.2001 to 1.4.2001)
Odd days in 1600 years = 0
Odd days in 400 years = 0
Jan. Feb. March April
(31 + 28 + 31 + 1) = 91 days 0 odd days.
Total number of odd days = (0 + 0 + 0) = 0
On 1st April, 2001 it was Sunday.
In April, 2001 Wednesday falls on 4th, 11th, 18th and 25th.
Answer D
Answer: D
Question: At a supermarket, John spent 1/2 of his money on fresh fruits and vegetables, 1/3 on meat products, and 1/10 on bakery products. If he spent the remaining $8 on candy, how much did John spend at the supermarket?
Options:
A) $60
B) $80
C) $90
D) $120
E) $180
Rationale: Let's let T = total number of dollars spent at the supermarket. With this variable we can set up an equation and determine T.
We are given that John spent 1/2 of his money on fresh fruits and vegetables, or (1/2)T, 1/3 on meat products, or (1/3)T, and 1/10 on bakery products, or (1/10)T. We are also given that he spent the remaining $8 on candy. Since we know where all his money was allocated, we can sum these values together and set the sum to T. So we have:
(1/2)T + (1/3)T + (1/10)T + 8 = T
To get rid of the fractions we can multiply the entire equation by 30, and we obtain:
15T + 10T + 3T + 240 = 30T
28T + 240 = 30T
240 = 2T
T = 120
John spent $90 at the supermarket.
Answer: D
Answer: D
Question: The table below shows the enrollment in various classes at a certain college.
Class | Number of Students
Biology | 58
Physics | 35
Calculus | 40
Although no student is enrolled in all three classes, 15 are enrolled in both Biology and Physics, 10 are enrolled in both Biology and Calculus, and 12 are enrolled in both Physics and Calculus. How many different students are in the three classes?
Options:
A)51
B)88
C)90
D)96
E)162
Rationale: No. of total students = no of students of biology + no of students of physics but not biology + no of students of calculus but not biology and physics
No. of total students = 58 + (35-15) + (40-10-12) = 58+20+18 = 96
Hence, Answer will be D.
Answer: D
Question: How many words can be formed by using all the letters of the word “DAUGHTER” so that vowels always come together & vowels are never together?
Options:
A)2310
B)4510
C)5231
D)2351
E)4320
Rationale: Given word contains 8 different letters
When the vowels AUE are always together we may suppose
them to form an entity ,treated as one letter
then the letter to be arranged are DAHTR(AUE)
these 6 letters can be arranged in 6p6 = 6!
= 720 ways
The vowels in the group (AUE) may be arranged in 3! = 6 ways
Required number of words = 760 * 6 =4320
Ans: E
Answer: E
Question: How many possible ways are there to select 3 stocks at random from 7 stocks?
Options:
A)26
B)29
C)32
D)35
E)38
Rationale: 7C3 = 35
The answer is D.
Answer: D
Question: If Raj walks at 12.5 km/hr instead of 10 km/hr, he would have walked 6 km more. The actual distance traveled by him during this period is?
Options:
A)10
B)11
C)12
D)13
E)24
Rationale: Let the actual distance traveled is 'x' km
Then by given conditions, we have
x/10 = (x+6)/12.5
12.5x = 10x + 60
x = 24 km
Ans- E
Answer: E
Question: If the population of a certain country increases at the rate of one person every 30 seconds, by how many persons does the population increase in 10 minutes?
Options:
A)20
B)30
C)15
D)10
E)80
Rationale: Answer = 2 * 10 = 20
Answer = A
Answer: A
Question: Length of a rectangular plot is 20 mtr more than its breadth. If the cost of fencin gthe plot at 26.50 per meter is Rs. 5300, what is the length of the plot in mtr?
Options:
A)45 m
B)60 m
C)57 m
D)69 m
E)78 m
Rationale: Let breadth = x metres.
Then, length = (x + 20) metres.
Perimeter = 5300 m = 200 m.
26.50
2[(x + 20) + x] = 200
2x + 20 = 100
2x = 80
x = 40.
Hence, length = x + 20 = 60 m
B
Answer: B
Question: The maximum number of students among them 1230 pens and 920 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is:
Options:
A)91
B)10
C)1001
D)1911
E)None of these
Rationale: Explanation:
Required number of students = H.C.F of 1230 and 920 = 10. Answer: B
Answer: B
Question: A train traveling at 100 kmph overtakes a motorbike traveling at 64 kmph in 85 seconds. What is the length of the train in meters?
Options:
A)400 meters
B)1111 meters
C)160 meters
D)850 meters
E)None of these
Rationale: Train overtakes a bike means that we are talking about total length of the train. (train's head is close to bike when it started and its tail crosses the bike when it overtakes the bike)
Relative speed= 100-64= 36Km/h = 36000 m/h
time= 85 seconds
Distance= speed*time
36000* 85/3600= 850 meters.
D is the answer.
Answer: D
Question: The ratio of the incomes of Lakshmi and Latha is 5:4 and the ratio of their expenditure is 4:3. If at the end of the year, each saves $6000 then the income of Lakshmi is?
Options:
A)$26000
B)$20000
C)$23000
D)$25000
E)$22000
Rationale: Let the income of Lakshmi and Latha be $5x and $4x
Let their expenditures be $4y and $3y
5x-4y = 6000-------1)
4x-3y = 6000-------2)
From 1) and 2)
x = 6000
Lakshmi's income = 5x = 5*5000 = $25000
Answer is D
Answer: D
Question: If daily wages of a man is four times to that of a woman, how many men should work for 20 days to earn Rs.14400? Given that wages for 40 women for 30 days are Rs.21600.
Options:
A)10
B)14
C)16
D)18
E)20
Rationale: Explanation :
Wages of 1 woman for 1 day = 21600/40Ã—30
Wages of 1 man for 1 day = 21600Ã—4/40Ã—30
Wages of 1 man for 20 days = 21600Ã—4Ã—20/40Ã—30
Number of men = 14400/(21600Ã—4Ã—20/40Ã—30)=144/(216Ã—80/40Ã—30)=10
Answer : Option A
Answer: A
Question: One half of a two digit number exceeds its one third by 7. What is the sum of the digits of the number?
Options:
A)A)3
B)B)5
C)C)7
D)D)9
E)E)10
Rationale: x/2 – x/3 = 7 => x =46
4 + 6 = 10
ANSWER:E
Answer: E
Question: Doug, who runs track for his high school,
was challenged to a race by his younger
brother, Matt. Matt started running first,
and Doug didn’t start running until Matt
had finished a quarter-mile lap on the
school track. Doug passed Matt as they
both finished their sixth lap. If both boys
ran at a constant speed, with Doug running
2 miles an hour faster than Matt, what was
Matt’s speed?
Options:
A)10.5 miles per hour
B)10 miles per hour
C)9 miles per hour
D)8 miles per hour
E)7.5 miles per hour
Rationale: Doug runs 2 miles an hour faster than Matt, so let Matt’s speed equal x miles per hour.
Then Doug’s speed equals x + 2 miles per hour. Each lap is one-quarter of a mile, so Doug
runs 1.5 miles in the time it takes Matt to run 1.25 miles. Place this information in a chart:
DOUGH RATE:x-2 TIME:1.5/1 DISTANCE:1.5
MATT RATE:X TIME:1.25/X DISTANCE:1.25
The two boys took the same amount of time from the time Doug started, so make an
equation by setting the two times in the chart equal to each other, and then solve for x:
1.5/X+2=1.25/X
1.5X=1.25(X+2)
1.5X=1.25X+2.5
0.25X=2.5
X=10
So Matt ran at 10 miles per hour.
correct answer B)10 miles per hour
Answer: B
Question: A person plans to start a business with x% of a list of 10,000 products in his inventory. Next year after a business loss, the person wants to reduce the list by (x − 4)%. In terms of x, how many products will be in the inventory?
Options:
A)x*x – 4x
B)(x)(104 – x)
C)(100)(104 – x)
D)(100)(96 – x)
E)(x-4)/100
Rationale: Based on the answer choices and the question, this question begs the use of x=4 as a sample number.
Initial = 4%*10000 = 400
Reduction = 4-4=0%, so no math required here to calculate the reduction; just make sure that you can calculate 400 in your answer.
A. x*x – 4x = 0; No
B. (x)(104 – x) = 400; Winner!
C. (100)(104 – x) > 400; No
D. (100)(96 – x) > 400; No
E. (x-4)/100 = 0; No
B
Answer: B
Question: A grocer has 400 pounds of coffee in stock, 20 percent of which is decaffeinated. If the grocer buys another 100 pounds of coffee of which 60 percent is decaffeinated, what percent, by weight, of the grocer’s stock of coffee is decaffeinated?
Options:
A)28%
B)30%
C)32%
D)34%
E)40%
Rationale: 1. 20% of 400=80 pounds of decaffeinated coffee
2. 60% of 100=60 pounds of decaffeinated coffee
3. Wt have 140 pounds of decaffeinated out of 500 pounds, that means 140/500*100%=28%.
The correct answer is A.
Answer: A
Question: A father was as old as his son's present at the time of your birth. If the father's age is 38 years now, the son's age 5years back was?
Options:
A)10 years
B)12 years
C)14 years
D)15 years
E)16 years
Rationale: Let the son's present age be x years. Then, (38 - x) = x
2x = 38.
x = 19.
Son's age 5 years back (19 - 5) = 14 years.
C
Answer: C
Question: If n is an integer and n^4 is divisible by 32, which of the following could be the remainder when n is divided by 32?
Options:
A)2
B)4
C)5
D)6
E)10
Rationale: Given:
n^4/32 = int
n^4/2^5 = int
1/2(n/2)^4 = int
try n= int = 2,4,6,8... because n/2 must be an integer
n=2 wont work because 1/2(n/2)^4 needs to be an integer.
n=4, result = 1/2 (2)^4 = 8, so the remainder of n/32 = remainder of 8/32 = 8 (not an option)
n=8, result = 1/2(8/2)^4 = 1/2(4)^4 = 1/2x16x16= 16x8, so the remainder of n/32 = remainder of 16x8/32 = 4 (option B)
Answer: B
Question: The average monthly salary of 20 employees in an organisation is Rs. 1500. If the manager's salary is added, then the average salary increases by Rs. 100. What is the manager's monthly salary?
Options:
A)2000
B)3000
C)3600
D)4800
E)4000
Rationale: Manager's monthly salary
= Rs. (1600 * 21 - 1500 * 20) = Rs. 3600
ANSWER C
Answer: C
Question: n is a whole number which when divided by 4 gives 3 as remainder. What will be the remainder when 2n is divided by 4 ?
Options:
A)2
B)4
C)7
D)9
E)11
Rationale: Let n = 4q + 3. Then 2n = 8q + 6 = 4(2q + 1 ) + 2.
Thus, when 2n is divided by 4, the remainder is 2.
Option A
Answer: A
Question: Find the value for m?
19(m + n) + 17 = 19(-m + n) - 59
Options:
A)0
B)-1
C)1
D)2
E)-2
Rationale: 19m + 19n + 17 = -19m + 19n - 59
38m= -76 => m = -2
E
Answer: E
Question: In what time will a train 300 m long cross an electric pole, it its speed be 144 km/hr?
Options:
A)2.5 sec
B)9.7 sec
C)3.5 sec
D)2.9 sec
E)7.5 sec
Rationale: Speed = 144 * 5/18 = 40 m/sec
Time taken = 300/40
= 7.5 sec.
Answer: E
Answer: E
Question: 24 = 3a + 5b
3 > |–a|
If ‘a’ and ‘b’ are both integers, then what is the highest possible values of ‘b’ that can be used to solve the above equation.
Options:
A)2
B)3
C)4
D)5
E)6
Rationale: Let us understand the meaning of 5 > |-a|
1) when we write |-x| this means the same as |x|.
2) Mod is very easy concept if you solve mod question by considering as a distance. when a mod is written as |x-(a)| = b, this means the distance from point 'a' (both side left and right of 'a' on number line) is b. |x-(a)| < b means the distance is between the two extreme distance(left and right side of 'a' on number line, considering the max distance is 'b' from 'a' - as per this scenario.....hence the value of 'a' must be between these two extremes. |x-(a)| > b means the distance is greater than the distance of 'b'..i.e the value of a could be anywhere more than 'b'.
Now come to the question. First its given|-a| < 3 ==> |a| < 3 ===> |a-0| < 3 ==> the distance from zero is less than 3. So the point ‘a’ will be -2,-1,0,1,2 as distance from 0 to these values is less than 3.
Now, lets move to equation 3a + 5b = 24 ==> b = (24 – (3 * a))/5. According to question, b is an integer, hence to make ‘b’ integer (24 – (3*a)) must be divisible by 5. Now remove the value which can’t make (24-(3*a)) divisible by 5 from the possible values of a. It will remain is -2. With only one value of ‘a’ we can have only one value of ‘b’ and that is b = (24 – 3 *(-2))/5 ==> b = (24 + 6)/5 ==> b = 6. Hence the highest value that b can take is 6 and the answer is E (value 6).
Answer: E
Question: Two taps can separately fill a cistern 10 minutes and 15 minutes respectively and when the waste pipe is open, they can together fill it in 15 minutes. The waste pipe can empty the full cistern in?
Options:
A)10 min
B)7 min
C)5 min
D)9 min
E)4 min
Rationale: 1/10 + 1/15 - 1/x
= 1/10
x = 10
Answer: A
Answer: A
Question: A trader purchased two colour televisions for a total of Rs. 35000. He sold one colour television at 30% profit and the other 40% profit. Find the difference in the cost prices of the two televisions if he made an overall profit of 32%?
Options:
A)Rs.21000
B)Rs.21028
C)Rs.21098
D)Rs.21021
E)Rs.21007
Rationale: Let the cost prices of the colour television sold at 30% profit and 40% profit be Rs. x and Rs. (35000 - x) respectively.
Total selling price of televisions = x + 30/100 x + (35000 - x) + 40/100 (35000 - x)
=> 130/100 x + 140/100 (35000 - x) = 35000 + 32/100 (35000)
x = 28000
35000 - x = 7000
Difference in the cost prices of televisions = Rs.21000
Answer:A
Answer: A
Question: In August,a cricket team that played 120 matches won 28% of the games it played.After a continuous winning streak,this team raised its average to 52%.How many matches did the team win to attain this average?
Options:
A)40
B)52
C)60
D)80
E)98
Rationale: let the no of matches played more=x
so,
(120+x)*52/100=33.6+x
by solving we get x=60
ANSWER:C
Answer: C
Question: If 13 lions can kill 13 deers in 13 minutes how long will it take 100 lions to kill 100 deers?
Options:
A)1 minutes
B)13 minute
C)100 minutes
D)10000 minutes
E)1000 minutes
Rationale: we can try the logic of time and work,our work is to kill the deers so 13(lions)*13(min)/13(deers)=100(lions)*x(min)/100(deers)hence answer is x=13
ANSWER:B
Answer: B
Question: In a class, the average age of 30 boys is 13 years and the average of 20 girls is 12 years. what is the average age of the whole class?
Options:
A)12 Years
B)12.3 Years
C)12.6 Years
D)13 Years
E)15 Years
Rationale: Total age of 50 students
(30X 13+20 X 12) = 630
Average = 630/50 = 12.6 Years
C
Answer: C
Question: How many positive three-digit integers are divisible by both 3 and 5?
Options:
A)50
B)60
C)65
D)70
E)80
Rationale: A number to be divisible by both 3 and 5 should be divisible by the least common multiple of 3 and 5 so by 15.
Multiples of 15 between 100 and 999, inclusive is
(last-first)/multiple+1=(990-105)/15+1=59+1=60
Answer: B.
Answer: B
Question: Abel can complete a work in 10 days, Ben in 12 days and Carla in 15 days. All of them began the work together, but Abel had to leave after 3 days and Ben 4 days before the completion of the work. How long did the work last?
Options:
A)6 8/9
B)7
C)8
D)9
E)10
Rationale: Abel in the 3 days that he worked completed 3/10 of the job = 7/10 remains
Then if Ben had to leave 4 days before the completion, this means that Carla had to work alone for these 4 days in which she completed 4/15 of the job.
Now together, Ben and Carla completed the job in (1/12 + 1/15)(t) = 13/30
3/20 (t) = 13/30 ---> t = 26/9=2 8/9
Therefore, these 2 8/9 days worked plus the 4 days that Carla had to work by herself add to 6 8/9 days
Answer: A
Answer: A
Question: How many times are the hands of a clock at right angle in a day?
Options:
A)22
B)24
C)44
D)34
E)38
Rationale: In 12 hours, they are at right angles 22 times.
In 24 hours, they are at right angles 44 times.
Answer: Option C
Answer: C