divelab/Sys2Bench huggingface dataset:
Question: Salaries of Rajesh and Sunil are in the ratio of 2 : 3. If the salary of each one is increased by 4000 the new ratio becomes 40 : 57. What is Sunil’s present salary?
Options:
A)17000
B)20000
C)25500
D)Cannot be determined
E)None of these
Rationale: Let the salaries of Rajesh and Sunil be 2x and 3x respectively.
Then, 2x+4000/3x+4000=40/57
or, 114x + 228000 = 120x + 160000
or, 6x = 68000
or, 3x = 34000
Answer E
Answer: E
Question: 3 pumps, working 8 hours a day, can empty a tank in 2 days. How many hours a day must 12 pumps work to empty the tank in 1 day?
Options:
A)4
B)10
C)11
D)12
E)13
Rationale: 3 pumps take 16 hrs total (8 Hrs a day)
If 1 pump will be working then, it will need 16*3=48 hrs
1 pump need 48 Hrs
If I contribute 12 pumps then
48/12=4 hrs.
answer :A
Answer: A
Question: The sides AB, BC & CA of a triangle ABC have 3, 4 and 5 interior points respectively on them. Find the number of triangles that can be constructed using these points as vertices.
Options:
A)220.
B)205.
C)250
D)105
E)225
Rationale: different ways..
1) EASIEST approach..
lets see how many total can be made if none of the points were colliner that is NO three were in one line = 12C3 = 12!/9!3! = 220...
Due to collinear, extra triangles considered above = 3C3 + 5C3 +4C3 = 1+10+4 = 15..
total = 220-15 = 205
ANSWER:B
Answer: B
Question: A stationary engine has enough fuel to move 12 hours when its tank is 4/5 full, how much
hours will it run when the tank is 1/3 full
Options:
A)3 hours
B)4 hours
C)5 hours
D)6 hours
E)7 hours
Rationale: when engine is (4/5) full,it moves for 12 hr
so, when tank is full, it will move = 12/(4/5) = 15 hr
So, when it is 1/3 full, it will move = 15*(1/3)= 5 hours
ANSWER:C
Answer: C
Question: Miguel is 46 years old. He is 6 years older than thrice his son’s age. Find the age of his son.
Options:
A)11years
B)12years
C)13years
D)14years
E)15years
Rationale: sons age=x
46-3x=6
x=13years
ANSWER:C
Answer: C
Question: Each of the 11 letters A, H, I, M, O, T, U, V, W, X and Z appears same when looked at in a mirror. They are called symmetric letters. Other letters in the alphabet are asymmetric letters. How many two letter computer passwords can be formed (no repetition allowed) with at least one symmetric letter
Options:
A)2,145
B)6,435
C)12,100
D)2420
E)25,740
Rationale: Since we are given atleast one symmetric letter in the three letter word we can take the following cases
1. All two
2. One symmetry and other two non
4. All the two letters can be arranged in 2 ways
( 11c2+ 11c1 * 15c2) *2
( 11*10/ 2 + 11 * 15 * 14 / 2 ) * 2
2420
IMO option D is the correct answer..
OA please...will correct if I missed anything..D
Answer: D
Question: If each edge of cube increased by 50%, the percentage increase in
Options:
A)100
B)114
C)115
D)125
E)105
Rationale: 100 × (150)/100 × (150)/100 = 225 => 125%
Answer is D.
Answer: D
Question: What is the simplified result of following the steps below in order?
(1)	add 5y to 2z
(2)	multiply the sum by 3
(3)	subtract z + y from the product
Options:
A)5z + 14y
B)5x + 16y
C)5x + 5y
D)6x + 4y
E)3x + 12y
Rationale: 3(5Y+2Z) -Z-Y= 14Y+5Z
'A' is the answer
Answer: A
Question: In paper A, one student got 18 out of 70 and in paper B he got 14 out of 30. In which paper he did fare well?
Options:
A)46.6
B)46.9
C)46.7
D)46.2
E)46.1
Rationale: Find the percentages. Paper A = 18/70 x 100 = 25.7
Paper B = 14/30 x 100 = 46.6
Answer:A
Answer: A
Question: A parallelogram has a base that is four time the size of it's height. The total area of this parallelogram is 2,304 Sq ft. What is the height of the parallelogram?
Options:
A)19
B)23
C)24
D)16
E)17
Rationale: 4x * x = 2304 => x
= 24
Answer: C
Answer: C
Question: A certain number X when divided by 233 leaves a remainder of 87. Which of the following can be subtracted from X to make X divisible by 91?
Options:
A)17
B)27
C)37
D)47
E)57
Rationale: Least possible value of the number is 233 + 87 = 320
Further it is given the number must be divisible by 91 .
320/91 = Gives remainder as 47
So, 47 must be subtracted from the number , answer is (D)
Answer: D
Question: A train 360 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 140 m long?
Options:
A)40 sec
B)42 sec
C)45 sec
D)48 sec
E)50 sec
Rationale: Explanation:
Formula for converting from km/hr to m/s: X km/hr =(X x 5/8)m/s.
Therefore, Speed =(45 x5/18)m/sec	=	25/2 m/sec.
Total distance to be covered = (360 + 140) m = 500 m.
Formula for finding Time =(Distance/Speed)
Required time =(500x 2 / 25)sec	= 40 sec.
ANSWER IS A
Answer: A
Question: S is a set containing 7 different positive odd primes. T is a set containing 8 different numbers, all of which are members of S. Which of the following statements CANNOT be true?
Options:
A) The median of S is prime.
B) The median of T is prime
C) The median of S is equal to the median of T.
D) The sum of the terms in S is prime.
E) The sum of the terms in T is prime.
Rationale: Here is my explanation. The question states:S is a set containing 9 different positive odd primes. T is a set containing 8 different numbers, all of which are members of S. Which of the following statements CANNOT be true?
(A) The median of S is prime.
Thismust be true. If there are an odd number of members of a set, then the median is a member of the set: it's the middle number, when all the numbers are ranked from smallest to biggest. Every number in S is a positive odd prime, so the median is one of them, and is prime.
(B) The median of T is prime.
Thismay or may not be true. If a set has an even number of members, the median is average of the two numbers in the middle, when ranked from smallest to biggest. The average of two odd numberscould beeven (average of 71 and 73 is 72), and hence not prime, or itcould beodd (the average of 71 and 79 is 75). For particularly well chosen odd numbers, the average can be not only odd but also prime -- for example, the average of 89 and 113 is 101, another prime number. If the two middle numbers of T were 89 and 113, the median would be 101, a prime number.
(C) The median of S is equal to the median of T.
Under most configurations for S and T, this wouldn't happen. If you weren't trying to make it happen, it would be unlikely to happen by chance. BUT, if the number dropped going from from S to T was the median of S (say, 101), and if the two middle numbers of T happen to have an average of that number that was dropped (for example, if the two numbers were 89 and 113), then the medians would be equal. In other words, the three middle numbers of S would have to be {. . ., 89, 101, 133, . . .}, and when 101 is dropped in going to T, the median of two would be the average of 89113, which happens to be 101. It's an exceptional case, but itcouldbe true.
(D) The sum of the terms in S is prime.
Thismay or may not be true. The sum of 9 odd numbermustbe an odd number. That odd numbercould beprime. For example, the sum of the first nine odd prime numbers {3, 5, 11, 13, 17, 19, 23, 29} is 127, which is prime. If you drop 3 and include the next prime, 31, the set {5, 11, 13, 17, 19, 23, 29, 31} has a sum of 155, which is clearly not prime.
(E) The sum of the terms in T is prime.
Thismust be false. The sum of eight odd numbers must be an even number. Only 2 is prime, and all other even numbers are not. Therefore, the sum of eight odd prime numbers will be an even number bigger than two, and absolutely cannot be prime.
A
Answer: A
Question: Two trains of length 100 m and 200 m are 100 m apart. They start moving towards each other on parallel tracks, at speeds 108 kmph and 72 kmph. In how much time will the trains cross each other?
Options:
A)8
B)7
C)9
D)2
E)1
Rationale: Relative speed = (108 + 72)* 5/18 = 50 mps.
The time required = d/s = (100 + 100 + 200)/50
= 400/50 = 8 sec.
Answer:A
Answer: A
Question: What is the probability of getting a number less than 4 when a die is rolled?
Options:
A)1/3
B)1/4
C)1/5
D)1/6
E)1/2
Rationale: Total number of outcomes possible when a die is rolled = 6 (âˆµ any one face out of the 6 faces)n(S) =6
E = Getting a no less than 4 = {1,2,3}
hence n(E) = 3
P(E) = n(E)/n(S) = 1/2
ANSWER E
Answer: E
Question: A train 110 m long is running with a speed of 60 km/hr. In what time will it pass a man who is running at 6 km/hr in the direction opposite to that in which the train is going?
Options:
A)5
B)6
C)7
D)8
E)9
Rationale: Speed of train relative to man = 60 + 6 = 66 km/hr.
= 66 * 5/18 = 55/3 m/sec.
Time taken to pass the men = 110 * 3/55 = 6 sec.
Answer: Option B
Answer: B
Question: Which of the following correctly lists the data sets in order of least to greatest standard deviation?
I. 56, 56, 56, 56, 56, 56
II. 5, 7, 16, 18, 25, 32
III. 6,7,8,9,10,11,12
Options:
A)I, II, III
B)I, III, II
C)II, I, III
D)I, III, II
E)III, II, I
Rationale: out of three given sets,
I has all numbers same, so it has zero standard deviation hence it is Least
only answer choices C and E have I in least position.
Out of I ans III
III has consecutive numbers , hence all are closedly spaced hence std deviation will be less
while in II,numbers are spread widely hence std deviation should be more than III
hence order should be I, III,II
IMO D
Answer: D
Question: A certain sum of money is divided among A, B and C so that for each Rs. A has, B has 65 paisa and C 40 paisa. If C's share is Rs.24, find the sum of money?
Options:
A)288
B)262
C)72
D)123
E)267
Rationale: A:B:C = 100:65:40
= 20:13:8
8 ---- 24
41 ---- ? => Rs.123
Answer: D
Answer: D
Question: A company has two types of machines, type R and type S. Operating at a constant rate, a machine of type R does a certain job in 10 hrs and a machine of type S does the same job in 5 hours. If the company used the same number of each type of machine to do the job in 2 hours, how many machines of type R were used?
Options:
A)A)3
B)B)4
C)C)6
D)D)9
E)E)12
Rationale: Rate of machine R =1/10
Rate of machine S =1/5
since same no of machines used for R and S to do the same work in 2 hrs
So collective rate needed to finish the work in 2 hrs= 1/2
Let the no of machine be x
So, x/10 +x/5 =1/2
3x/10=1/2
x=30/5=6
So no of machine R is 6
Answer C
Answer: C
Question: What is the units digit of 18! + 2 ?
Options:
A)1
B)2
C)3
D)4
E)5
Rationale: Any number above 4!, such as 5!, 6!, etc... are always multiples of 10, so their units digit is 0.
The units digit of 18! + 2 is 2.
The answer is B.
Answer: B
Question: A and B can finish a work in 14 days while A alone can do the same work in 24 days. In how many days B alone will complete the work?
Options:
A)33 1/3 days
B)35 2/3 days
C)33 2/3 days
D)31 2/3 days
E)32 2/3 days
Rationale: B = 1/14 – 1/24 = 5/168
=> 168/5 days
=>33 2/3 days
ANSWER:C
Answer: C
Question: A company has two types of machines, type R and type S. Operating at a constant rate a machine of R does a certain job in 36 hours and a machine of type S does the job in 12 hours. If the company used the same number of each type of machine to do job in 12 hours,how many machine R were used?
Options:
A)3
B)4
C)6
D)9/2
E)12
Rationale: yes there is a typo in the question, I got the same ques on my GMAT PREP last week, and the questions goes as:
A company has two types of machines,type R and type S.Operating at a constant rate a machine of R does a certain job in 36 hours and a machine of type S does the job in 12 hours .If the company used the same number of each type of machine to do job in2 hours,how many machine R were used?
So for a job to be done in 2 hours R = 1/2
R_a(Rate of Machine R) = 1/36
R_s(Rate of Machine S) = 1/12
Lets say x machines are used to attain the desired rate, thus
x/36+x/12 = 1/2 (Desired R =1/2 i.e. to complete the job in 2 hours)
(x+3x)/36 = 1/2
4x/36 = 1/2
x = 9/2.
QA = 9/2 (ANSWER D)
Answer: D
Question: Subtracting 10% from X is the same as multiplying X by what number?
Options:
A)97%
B)90%
C)80%
D)98%
E)20%
Rationale: X - (10/100) X = X * ?
? = 90%
Answer: B
Answer: B
Question: A bag contains 6 red, 5 blue and 2 green balls. If 2 balls are picked at random, what is the probability that both are red?
Options:
A)2/13
B)3/17
C)5/26
D)5/21
E)7/15
Rationale: P(Both are red),
=6C213C2=6C213C2
=5/26
C
Answer: C
Question: How many words, with or without meaning, can be formed using all letters of the word SHARP using each letter exactly once?
Options:
A)90
B)100
C)110
D)120
E)130
Rationale: The Word SHARP has exactly 5 letters which are all different.
Therefore the number of words that can be formed = Number of permutations of 5 letters taken all at a time.
= P (5, 5) = 5!
= 5 x 4 x 3 x 2 × 1
= 120
ANSWER:D
Answer: D
Question: In a college the ratio of the numbers of boys to the girls is 8:5. If there are 210 girls, the total number of students in the college is?
Options:
A)562
B)356
C)452
D)416
E)546
Rationale: Let the number of boys and girls be 8x and 5x
Then , 5x = 210
x= 42
Total number of students = 13x = 13*42 = 546
Answer is E
Answer: E
Question: Which one of the following is a composite number?
Options:
A)31
B)61
C)71
D)73
E)55
Rationale: 55 is divisible by 5,11,55. So, it a composite number.
E
Answer: E
Question: Akash leaves Chennai at 6am & reaches Bangalore at 10am. Prakash leaves Hyderabad at 8 am and reaches Chennai at 11:30 am. At what time do they cross each other?
Options:
A)5 : 54am
B)6 : 56am
C)8 : 56am
D)9 : 56am
E)10 : 26am
Rationale: Time taken by Akash = 4 h
Time taken by Prakash = 3.5 h
For your convenience take the product of times taken by both as a distance.
Then the distance = 14km
Since, Akash covers half of the distance in 2 hours(i.e at 8 am)
Now, the rest half (i.e 7 km) will be coverd by both prakash and akash
Time taken by them = 7/7.5 = 56 min
Thus , they will cross each other at 8 : 56am.
C
Answer: C
Question: A sock drawer contains seven socks, each one a different solid color. The colors of the socks are red, orange, yellow, green, blue, indigo, and violet. If a person reaches into the drawer and pulls out two socks, how many different color combinations are possible in the selected pair of socks?
Options:
A)12
B)15
C)21
D)36
E)42
Rationale: Since here order of socks is not important then we'll have 7C2 i.e. 21 combinations.
If order is important then we would have got 42 socks...
ANS option C is correct answer..
Answer: C
Question: if the average of 6 consecutive number is 27, then the largest of the number is?
Options:
A)27.5
B)28.5
C)29
D)29.5
E)30
Rationale: x+x+1+x+2+x+3+x+4+x+5/6=27
6x+15=162
x=24.5
x+5=29.5
ANSWER:D
Answer: D
Question: Rs.1200 divided among P, Q and R. P gets half of the total amount received by Q and R. Q gets one-third of the total amount received by P and R. Find the amount received by R ?
Options:
A)Rs. 1100
B)Rs. 500
C)Rs. 1200
D)Rs. 700
E)None of these
Rationale: Explanation:
Let the amounts to be received by P, Q and R be p, q and r.
p + q + r = 1200
p = 1/2 (q + r) => 2p = q + r
Adding 'p' both sides, 3p = p + q + r = 1200
=> p = Rs.400
q = 1/3 (p + r) => 3q = p + r
Adding 'q' both sides, 4q = p + q + r = 1200
=> q = Rs.300
r = 1200 - (p + q) => r = Rs.500.
ANSWER IS B
Answer: B
Question: For any a and b that satisfy |a – b| = b – a and a > 0, then |a + 5| + |-b| + |b – a| + |ab| =
Options:
A)a-b
B)2a-2b
C)2a-2b-5
D)ab + 2b + 5
E)a-b-5
Rationale: Observation-1: |a – b| = b – a
which is possible only when signs of a and b are Same
Since Given a > 0
so we figure out that a and b are both positive
Observation-2: |a – b| must be Non-Negative and so should be the value of b-a which is possible only when absolute value of b is greater than or equal to absolute value of a
Now you may choose the values of a and b based on above observations
e.g. b = 5 and a=1 and check the value of given functions and options
|a + 5| + |-b| + |b – a| + |ab| = |1 + 5| + |-5| + |5 – 1| + |1*5| = 20
ab + 2b + 5= 1*5+10+5=20
all other options are not equal to 20
Answer : D
Answer: D
Question: In a can, there is a mixture of milk and water in the ratio 1 : 5. If it is filled with an additional 2 litres of milk the can would be full and ratio of milk and water would become 2 : 5. Find the capacity of the can?
Options:
A)14
B)44
C)48
D)50
E)56
Rationale: Let the capacity of the can be T litres.
Quantity of milk in the mixture before adding milk = 1/6 (T - 2)
After adding milk, quantity of milk in the mixture = 2/7 T.
2T/7 - 2 = 1/6(T - 2)
5T = 84 - 14 => T = 14.
Answer:A
Answer: A
Question: A, B and C started a business with capitals of Rs. 8000, Rs. 10000 and Rs. 12000 respectively. At the end of the year, the profit share of B is Rs. 1500. The difference between the profit shares of A and C is?
Options:
A)621
B)276
C)236
D)600
E)211
Rationale: Explanation:
Ratio of investments of A, B and C is 8000 : 10000 : 12000 = 4 : 5 : 6
And also given that, profit share of B is Rs. 1500
=> 5 parts out of 15 parts is Rs. 1500
Now, required difference is 6 - 4 = 2 parts
Required difference = 2/5 (1500) = Rs. 600
Answer: D
Answer: D
Question: Gold is 19 times as heavy as water and copper 9 times as heavy as water. The ratio in which these two metals be mixed so that the mixture is 15 times as heavy as water is:
Options:
A)1 : 2
B)2 : 3
C)3 : 2
D)19: 135
E)None of these
Rationale: Explanation:
This question can be solved using weighted average formula. If two quantities of weights m, n have concentrations x, y are mixed then, final concentration = mx+ny/m+n
Take 1 unit of gold and x units of copper.
1×19+x×9/1+x=15⇒19+9x=15+15x
⇒x=2/3
So they are to be mixed in the ratio 1 : x = 1:2/3 or 3 : 2
Correct Option: C
Answer: C
Question: A began a business with Rs. 85,000. He was joined afterwards by B with Ks. 42,500. For how much period does B join, if the profits at the end of the year are divided in the ratio of 3 : 1 ?
Options:
A)4 months
B)5 months
C)6 months
D)8 months
E)9 months
Rationale: Suppose B joined for x months . Then, ( 85000 * 12 )/(42500 * x) = 3. or x = (85000 * 12) / (42500 * 3) = 8.
So, B joined for 8 months.ANSWER D
Answer: D
Question: The length of the bridge, which a train 160 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
Options:
A)200 m
B)215 m
C)245 m
D)250 m
E)270 m
Rationale: Let the length of the bridge:L
The equation now is L+160/12.5m/s(45km/hr or12.5m/s)=30
Solving, L =215m
ANSWER:B
Answer: B
Question: In 1950, John was 4 times as old as Tom. In 1955, Richard was 3 times as old as Tom. In which year was John twice as old as Tom?
Options:
A) 1960
B) 1970
C) 1972
D) 1975
E) 1980
Rationale: In 1950: Jo = 4 To-------------- eq1
In 1955: Jo +5 = 3(To+5)---------eq2
Thus in 1950, solving eq1 and eq2
Jo = 10 , Jo =40
Now for each year we can calculate:
1960: Jo = 50 , To=20
1965: Jo = 55, To=25
1970: Ri= 60, Ro = 30
Thus Ans:B
Answer: B
Question: In the standard formulation of a flavored drink the ratio by volume of flavoring to corn syrup to water is 1 : 12 : 30. In the sport formulation, the ratio of flavoring to corn syrup is three times as great as in the standard formulation, and the ratio of flavoring to water is half that of the standard formulation. If a large bottle of thesportformulation contains 5 ounces of corn syrup, how many ounces of water does it contain?
Options:
A)15
B)30
C)45
D)75
E)90
Rationale: Standard:
Fl: Corn S: Water = 1:12:30
Sport:
Fl: Corn S: Water = 3:12:180
This simplifies to 1:4:60
If the large bottle has a capacity of x ounces, then
4x / 65 = 5.
So, x = 325 / 4 ounces.
Water = (60 / 65) * (325 / 4) = 60 * 3 / 4 = 75 ounces.
Ans D
Answer: D
Question: Alice has 3 times the number of stamps that Doris does and Jane has 7 stamps more than Doris does. If Alice, Doris, and Jane each increase their number of stamps by 4, which of the following must be true after each person increases her number of stamps?
Alice has more stamps than Jane.
Jane has 3 more stamps than Doris.
The sum of the numbers of stamps that Alice and Doris have is a multiple of 4.
Options:
A)None
B)III only
C)I and III only
D)II and III only
E)I, II, and III
Rationale: Let Alice, Doris and jane have A, D and J stamps initially.
We know that
A =3D
and
J=d+7
After addition of 4 stamps they'll have A+4, D+4, and J+4 stamps respectively.
Lets analyze each statements:
Alice has more stamps than Jane.
this can be written as
A+4 > J+4
=> 3D+4 > D+7+4
=>D >7/3
It may not be true for many values of D.. D could very well be equal to 1,2 etc for which D<7/3. Not correct.
Jane has 3 more stamps than Doris.
this can be written as
J+4 = (D+4)+3
=> D+7+4 = D+4+3
Clealy not correct for any value of D.
The sum of the numbers of stamps that Alice and Doris have is a multiple of 4.
(A+4)+(D+4) = 4k, where k is any integer
=> 3D+4+D+4 =4k
=> 4D+8 = 4K
=> 4(D+2) = 4K
or K = D+2 .. clearly possible for any value of D. Hence Correct.
Hence Ans B. Only iii is correct.
Answer: B
Question: What is the thousandths digit in the decimal equivalent of 43/5000?
Options:
A)0
B)1
C)3
D)5
E)8
Rationale: 43/5000 = 43 /(5*10^3)
= (43/5) *10^-3
=8.6 * 10^-3
=.0086
Thousandths digit = 8
Answer E
Answer: E
Question: Eesha bought two varities of rice costing 50Rs per kg and 60 Rs per kg and mixed them in some ratio.Then she sold that mixture at 70 Rs per kg making a profit of 20 % What was the ratio of the micxture?
Options:
A)1 : 9
B)1 by 5
C)1 : 7
D)1 : 3
E)1 : 1
Rationale: Selling price of the mixture = 70 and profit = 20%
Cost price of the mixture = 70×100120=70×5670×100120=70×56
By applying alligation rule:
So ratio = 60−1753:1753−5060−1753:1753−50 = 1 : 5
Answer:B
Answer: B
Question: A train covers a distance of 12 km in 10 min. If it takes 6 sec to pass a telegraph post, then the length of the train is?
Options:
A)999
B)279
C)120 metre
D)99
E)21
Rationale: Speed = (12/10 * 60) km/hr = (72 * 5/18) m/ sec = 20 m/sec.
Length of the train = 20 * 6
= 120 m.
Answer: C
Answer: C
Question: A certain experimental mathematics program was tried out in 2 classes in each of 34 elementary schools and involved 40 teachers. Each of the classes had 1 teacher and each of the teachers taught at least 1, but not more than 3, of the classes. If the number of teachers who taught 3 classes is n, then the least and greatest possible values of n, respectively, are
Options:
A)0 and 13
B)0 and 14
C)1 and 10
D)1 and 9
E)2 and 8
Rationale: One may notice that greatest possible values differ in each answer choice in contrast to the least values, which repeat.
To find out the greatest value you should count the total classes (34*2=68), then subtract the total #of teachers since we know from the question that each teacher taught at least one class (68-40=28). Thus we get a number of the available extra-classes for teachers, and all that we need is just to count how many teachers could take 2 more classes, which is 28/2 = 14. So the greatest possible value of the # of teachers who had 3 classes is 14.
Only answer B has this option.
Answer: B
Question: In a pair of fractions, fractions A is twice the fraction B and the product of two fractions is 2/25. What is the value of fraction A?
Options:
A)1/5
B)1/25
C)2/5
D)3/5
E)Data inadequate
Rationale: a=2b
ab=2/25
2b*b=2/25
b^2=1/25
b=1/5
a=2/5
ANSWER:C
Answer: C
Question: A boat running downstream covers a distance of 22 km in 4 hours while for covering the same distance upstream, it takes 5 hours. What is the speed of the boat in still water?
Options:
A)5 kmph
B)4 kmph
C)4.75 kmph
D)4.95 kmph
E)4.65 kmph
Rationale: Speed Downstream = 22/4 = 5.5 kmph
Speed Upstream = 22/5 =4.4 kmph
Speed of the boat in still water = 5.5+4.4/2=4.95 kmph
Answer : Option D
Answer: D
Question: What is the least number of squares tiles required to pave the floor of a room 15 m 17 cm long and 9 m 2 cm broad?
Options:
A)814 tiles
B)800
C)100
D)200
E)456
Rationale: Length of largest tile = H.C.F. of 1517 cm and 902 cm = 41 cm.
Area of each tile = (41 x 41) cm2.
Required number of tiles = (1517 x 902)/41 x 41 = 814.
Answer:A
Answer: A
Question: The product X of two prime numbers is between 17 and 55. If one of the prime numbers is greater than 2 but less than 6 and the other is greater than 13 but less than 25, then X =
Options:
A)18
B)29
C)37
D)44
E)51
Rationale: Option B & C can be ruled out as they themselves are prime numbers
18 = 2*9 = 3*6 >> Ignore
44 = 2 * 22 = 4 * 11 >> Ignore
51 = 3*17 >> Answer
Answer E
Answer: E