divelab/Sys2Bench huggingface dataset:
Question: If the number 241 * 523 is completely divisible by 9, then the smallest whole number in place of * will b
Options:
A)4
B)5
C)1
D)8
E)9
Rationale: Sum of digits = (2 + 4 + 1 + x + 5 + 2 + 3) = (17 + x), which must be divisible by 9.
x = 1.
C)
Answer: C
Question: What is the lowest positive integer that is divisible by each of the odd integers between 17 and 23, inclusive?
Options:
A)3×17×19×21
B)5×17×19×23
C)23*21*17*19
D)7×15×19×21
E)15×17×19×21
Rationale: We should find the LCM of 17, 19, 23 and 21 = 3*7 --> LCM = 3*23*7*17*19 = 23*21*17*19.
Answer: C.
Answer: C
Question: Umesh directly went from P, to Q which is 9 feet distant. Then he turns to the right and walked 4 feet. After this he turned to the right and walked a distance which is equal from P to Q. Finally he turned to the right and walked 3 feet. How far is he now from P?
Options:
A)6 feet
B)5 feet
C)1 feet
D)0 feet
E)10 feet
Rationale: 1 feet
ANSWER:C
Answer: C
Question: Income and expenditure of a person are in the ratio 10 : 4. If the income of the person is Rs. 19000, then find his savings?
Options:
A)79754
B)87689
C)59875
D)11400
E)87648
Rationale: Let the income and the expenditure of the person be Rs. 10x and Rs. 4x respectively.
Income, 10x = 19000 => x = 1900
Savings = Income - expenditure = 10x - 4x = 6x = 6(1900)
So, savings = Rs. 11400.
Answer:D
Answer: D
Question: The average speed of a car is 1 4/5 times the avg speed of a bike. A tractor covers 575km in 23hrs. How much distance will the car cover in 4hrs if the speed of the bike is twice speed of the tractor?
Options:
A)340 km
B)480 km
C)360 km
D)450 km
E)None of these
Rationale: Sol. Average speed of a tractor = 25 km / h
The speed of a bus in an hour = 25 × 2 = 50 km
The speed of a car in an hour = 9/5 * 50 = 90 km
So, the distance covered by car in 4 h is
90 × 4 = 360 km
Ans.(C)
Answer: C
Question: There are e members in a certain department, including Michael. Two representatives are to be selected to attend a company conference. If there are 55 possible combinations in which Michael is not selected, what is the value of e?
Options:
A)11
B)12
C)15
D)18
E)22
Rationale: Combinations of two persons, in which Michael was not selected = 55
number of ways two persons can be selected from m people = m*(m-1)/2
Let m be the number of people excluding Michael, then m*(m-1) = 110 => m=11
Thus, e = m + 1(Michael) = 12
option B
Answer: B
Question: there are 15 cars and 16 trucks? which is greater15 or 16?
Options:
A)15
B)14
C)12
D)17
E)16
Rationale: E
Answer: E
Question: A rectangular grassy plot 110 m. by 65 m has a gravel path 2.5 m wide all round it on the inside. Find the cost of gravelling the path at 60 paise per sq. metre
Options:
A)s510
B)s780
C)s880
D)s480
E)s980
Rationale: area of the plot=110m*65m=7150sq.m
area of plot excluding gravel=105m*60m=6300sq.m
area of gravel =7150sq.m-6300sq.m =850sq.m
cost of building it = 850sq.m*60
= 51000p
in Rs =51000/100=Rs510
ANSWER:A
Answer: A
Question: Which of the following equivalent to (1/64)^2?
Options:
A)(0.05)^3
B)(0.06)^3
C)(0.07)^3
D)(0.08)^3
E)(0.09)^3
Rationale: (1/64)^2 = (1/4^3)^2 = (1/4)^6 = (1/16)^3 = (0.06)^3
Answer: Option B
Answer: B
Question: What is the sum of all 3 digit positive integers that can be formed using the digits 1, 4, and 7, if the digits are allowed to repeat within a number?
Options:
A)10,655
B)11,988
C)12,433
D)13,766
E)14,322
Rationale: The number of these 3-digit numbers is 3*3*3 = 27
Each digit 1, 4, and 7 will appear in the ones, tens, and hundreds place 9 times each.
The sum equals 9(111) + 9(444) + 9(777) = 11,988
The answer is B.
Answer: B
Question: If r and y are integers and (15^r + 15^(r+1))/4^y = 15^y what is the value of r?
Options:
A)2
B)3
C)4
D)5
E)Cannot be determined
Rationale: \frac{15^r( 1+ 15)}{4^y} = 15^y
(15^r . 4^2 ) / 4^y = 15^y. 4^0
15^r . 4^(2-y) = 15^y. 4^0
Equating the powers, r = y; 2-y = 0; So r = y = 2=A
Answer: A
Question: Find the odd man out:
5, 8, 20, 42, 124, 246
Options:
A)20
B)99
C)77
D)26
E)81
Rationale: Explanation:
The series is followed on the pattern of 2 alternate sequences with common formula being 2n-2 and 3n-2 respectively.
8 = 2*5-2
22 = 3*8-2
42 = 22*2-2
124 = 42*3-2
246 = 124*2-2
Hence, 20 is the odd no.
ANSWER: A
Answer: A
Question: The length of rectangle is thrice its breadth and its perimeter is 96 m, find the area of the rectangle?
Options:
A)432
B)288
C)278
D)269
E)271
Rationale: 2(3x + x) = 96
l = 36 b = 12
lb = 36 * 12 = 432
Answer:A
Answer: A
Question: Some pen bought something at loss for Rs 60.He then sold it the price of 81 and his profit was 20% of the loss.At what price did he buy the object
Options:
A)77.5
B)76.5
C)75.5
D)74.5
E)73.5
Rationale: lets Assume loss be Rs x on Rs 60
Cost Price = 60+x
He then sold it the price of 81 and his profit was 20% of the loss
60+x + 20%x = 81
Solving this x will be 17.5
Cost Price = 60 + x = 60 + 17.5 = 77.5
ANSWER:A
Answer: A
Question: In Set T, the average (arithmetic mean) equals the median W. Which of the following must be true?
I. Set T consists of evenly spaced numbers.
II. Set T consists of an odd number of terms.
III. Set T has no mode.
IV. None of the above.
Options:
A)I only
B)I and II
C)II and III
D)I, II, and III
E)IV only
Rationale: This is a very good 'trap question'.
Consider Set A= { 0,0,0,0 } Mean=Median=Mode=0- Eliminates 1,2 and 3 OR
Consider Set B= {1,2,2,3 } Mean=Median=Mode=2- Eliminates 1,2 and 3
If you think that only in 'consecutive integers' the average is equal to the median W you might fall for 'D'.
Ans: E
Answer: E
Question: A rectangular swimming pool is 8 feet by 20 feet. A deck that has uniform width surrounds the pool. The total area of the pool and deck is 540 square feet. What is the width of the deck?
Options:
A)1
B)2
C)3
D)4
E)5
Rationale: Let the width =W
Total Area of the pool and deck= (2W+8)(2W+20)
We can Test the answer choices along with unit digit method
A) 2 feet ...........12*24 has unit digit 8..........Eliminate
B) 2.5 feet.........13*25 has unit digit 5..........Eliminate
C) 3 feet............14*26 has unit digit 4...........Hold
D) 4 feet............16*28 has unit digit 8...........Eliminate
E) 5 feet............18*30 has unit digit 0...........Eliminate
Answer: E w=5
Answer: E
Question: Exactly 3/7 of the people in the room are under the age of 21, and exactly 5/8 of the people in the room are over the age of 65. If the total number of the people in the room is greater than 50 and less than 100, how many people in the room are under the age of 21?
Options:
A)24
B)35
C)39
D)60
E)65
Rationale: The total number of the people in the room must be a multiple of both 7 and 8 (in order 3/7 and 5/8 of the number to be an integer), thus the total number of the people must be a multiple of LCM of 7 and 8, which is 56.
Since, the total number of the people in the room is greater than 50 and less than 100, then there are 56 people in the room.
Therefore there are 3/7*56=24 people in the room under the age of 21.
Answer: A.
Answer: A
Question: A telephone number contains 10 digit, including a 3-digit area code. Bob remembers the area code and the next 5 digits of the number. He also remembers that the remaining digits are not 0, 1, 6, or 7. If Bob tries to find the number by guessing the remaining digits at random, the probability that he will be able to find the correct number in at most 2 attempts is closest to which of the following?
Options:
A)1/6
B)1/9
C)1/18
D)1/24
E)1/36
Rationale: There are 6*6 = 36 possibilities.
Bob has 2 chances so the probability is 2/36 = 1/18.
The answer is C.
Answer: C
Question: If in a kindergarten class, there are five children 3 feet 4 inches tall (indicated by notation 3'4"), two children 4'3" tall and thirteen children 2'9" tall, which of the following is the median height of the children?
Options:
A)2'9"
B)2'6"
C)3'3"
D)3'4"
E)4'3
Rationale: Total number of children in class = 20
so median must be between 10th and 11th child when they are arranged in ascending order.
When arranged in ascending order 5th and 6th child will have the height of 3'4"
so required median height = (2'9"+2'9")/2 = 2'6"
Ans:Option A
Answer: A
Question: A reduction of 20% in the price of salt enables a lady to obtain 10kgs more for Rs.100, find the original price per kg?
Options:
A)2 3/2
B)2 2/3
C)2.5
D)3
E)3.5
Rationale: 100*(20/100) = 20 --- 10
? --- 1 => Rs.2
100 --- 80
? --- 2 => Rs.2.5
Answer: C
Answer: C
Question: Change 1/8 = 8-1 to logarithmic notation.
Options:
A)log(8)8
B)log7
C)log(5)8
D)log 5
E)None of these
Rationale: Solution:
1/8 = 8-1 = log88
Answer is A
Answer: A
Question: Eighteen years ago, a father was three times as old as his son. Now the father is only twice as old his son. Then the sum of the present ages of the son and the father is:
Options:
A)54
B)72
C)105
D)108
E)118
Rationale: Let the present ages of the father and son be 2x and x years respectively.
Then, (2x - 18) = 3(x - 18) => x = 36
Required sum = (2x + x) = 108 years.
ANSWER:D
Answer: D
Question: One lady has 2 children, one of her child is boy, what is the probability of having both are boys
Options:
A)1/2
B)1/3
C)1/4
D)1/5
E)3/4
Rationale: n(S)=one of her child is boy out of 2 children=BB,BG=2
n(E)=both are boys=BB=1
so p=n(E)/n(s)=1/2
ANSWER:A
Answer: A
Question: If the product 48^64 × 9x2 is divisible by 12, then what is the value of x?
Options:
A)1
B)2
C)3
D)4
E)5
Rationale: 4864 × 9a2 is divisible by 12
=> 4864 × 9a2 is divisible by 3
and 4864 × 9a2 is divisible by 4
4864 is divisible by 4 because number formed by the last two digits is 64 which is divisible by 4. Hence 4864 × 9a2 will also be divisible by 4
4864 is not divisible by 3 (because 4 + 8 + 6 + 4 = 22 which is not divisible by 3). Hence 9a2 must be divisible by 3 because 48^64 × 9x2 is divisible by 3
=> 9 + x + 2 is divisible by 3
=> 11 + a is divisible by 3
Hence a can be 1 or 4 or 7 such that 11 + a is divisible by 3
So, from the given choices, 1 is the answer.
A
Answer: A
Question: Sterling Silver is 92.5% pure silver. How many grams of Sterling Silver must be mixed to a 90% Silver alloy to obtain a 500g of a 91% Silver alloy?
Options:
A)200
B)300
C)400
D)500
E)600
Rationale: Let x and y be the weights, in grams, of sterling silver and of the 90% alloy to make the 500 grams at 91%. Hence
x + y =500
The number of grams of pure silver in x plus the number of grams of pure silver in y is equal to the number of grams of pure silver in the 500 grams. The pure silver is given in percentage forms. Hence
92.5% x + 90% y = 91% 500
Substitute y by 500 - x in the last equation to write
92.5% x + 90% (500 - x) = 91% 500
Simplify and solve
92.5 x + 45000 - 90 x = 45500
x = 200 grams.
200 grams of Sterling Silver is needed to make the 91% alloy.
Answer A
Answer: A
Question: Walking with 4/5 of my usual speed, I miss the bus by 6 minutes. What is my usual time?
Options:
A)16 min
B)26 min
C)34 min
D)24 min
E)12 min
Rationale: Speed Ratio = 1:4/5 = 5:4Time Ratio
= 4:5 1 -------- 6 4 --------- ? è 24
Answer: D
Answer: D
Question: A 300 m long train crosses a platform in 33 sec while it crosses a signal pole in 18 sec. What is the length of the platform?
Options:
A)286 m
B)250 m
C)277 m
D)278 m
E)267 m
Rationale: Speed = 300/18 = 50/3 m/sec.
Let the length of the platform be x meters.
Then, (x + 300)/33 = 50/3
=> x = 250 m.
Answer:B
Answer: B
Question: A train running at the speed of 72 km/hr crosses a pole in 9 seconds. Find the length of the train?
Options:
A)150 meter
B)299 meter
C)666 meter
D)155 meter
E)180 meter
Rationale: Speed = 72*(5/18) m/sec = 20 m/sec
Length of Train (Distance) = Speed * Time
(20) * 9
= 180 meter
Answer: E
Answer: E
Question: A 240 m long train running at the speed of 120 km/hr crosses another train running in opposite direction at the speed of 80 km/hr in 9 sec. What is the length of the other train?
Options:
A)230
B)260
C)267
D)256
E)298
Rationale: Relative speed = 120 + 80 = 200 km/hr.
= 200 * 5/18 = 500/9 m/sec.
Let the length of the other train be x m.
Then, (x + 240)/9 = 500/9 => x = 260.
Answer: B
Answer: B
Question: If an article is sold at 19% profit instead of 12% profit, then the profit would be Rs. 105 more. What is the cost price?
Options:
A)2278
B)388
C)1500
D)2776
E)8811
Rationale: Let the cost price of an article be Rs. x.
(19% of x) - (12% of x) = 105
19x/100 - 12x/100 = 105 => 7x = 105 * 100
=> x = 1500
Cost price = Rs. 1500
Answer:C
Answer: C
Question: If 8 men do a work in 80 days, in how many days will 20 men do it?
Options:
A)18 days
B)32 days
C)42 days
D)48 days
E)44 days
Rationale: 8 * 80 = 20 * x
x = 32 days
ANSWER:B
Answer: B
Question: A train 160 m long passes a man,running at 6 kmph in the direction opposite to that of the train,in 6 seconds.The speed of the train is
Options:
A)54 kmph
B)60 kmph
C)66 kmph
D)72 kmph
E)90 kmph
Rationale: speed of train relative to man: 160/6 * 18/5 km/hr
= 96 km/hr
let speed of train= x
therefore x+6 = 96
x= 96-6
x=90 km/hr
ANSWER:E
Answer: E
Question: The angle between the minute hand and the hour hand of a clock when the time is 12.30, is
Options:
A)35°
B)65°
C)45°
D)195°
E)95°
Rationale: Angle between hands of a clock
When the minute hand is behind the hour hand, the angle between the two hands at M minutes past H 'o clock
=30(H−M/5)+M/2 degree
When the minute hand is ahead of the hour hand, the angle between the two hands at M minutes past H 'o clock
=30(M/5−H)−M/2 degree
Here H = 12, M = 30 and minute hand is behind the hour hand.
Hence the angle
=30(H−M/5)+M/2
=30(12−30/5)+30/2
=30(12−6)+15
=30×6+15 =195°
Answer is D.
Answer: D
Question: A credit card number has 6 digits (between 1 to 9). The first two digits are 12 in that order, the third digit is bigger than 5, the forth is divisible by 3 and the fifth digit is 3 times the sixth. How many different credit card numbers exist?
Options:
A)27
B)72
C)36
D)112
E)422
Rationale: {1}{2}{greater than 5}{divisible by 3}{3x}{x}:
The third digit can take 4 values:6, 7, 8, or 9.
The fourth digit can take 3 values: 3, 6, or 9.
The fifth and sixth digits can take 3 values: 31, 62, or 93.
Total = 4*3*3 = 36.
Answer: C.
Answer: C
Question: The taxi charges in a city comprise of a fixed charge, together with the charge of the distance covered. For a journey of 16 km, the charges paid are Rs. 156 and for a journey of 24 km, the charges paid are Rs. 204. What will a person have to pay for travelling a distance of 30 km?
Options:
A)Rs. 236
B)Rs. 240
C)Rs. 248
D)Rs. 252
E)Rs. 352
Rationale: For a journey of 16 km, the charges paid are Rs. 156 and for a journey of 24 km, the charges paid are Rs. 204.
Additional charges for 8 kms = 204-156 = 48 Rs
additional charge/km= 48/8 = Rs 6
additional charge for 6 kms = 6*6 = Rs 36.
total charges for 30 kms = 204 +36 = Rs 240
ANSWER:B
Answer: B
Question: A boatman goes 3 km against the current of the stream in 1 hour and goes 1 km along the current in 10 minutes. How long will it take to go 5 km in stationary water?
Options:
A)40 minutes
B)1 hour 7 min
C)1 hour 15 min
D)1 hour 30 min
E)1 hour 10 min
Rationale: speed (upstream) =3/1 = 3 kmhr
speed (downstream)=1/(10/60)= 6 kmhr
speed in still water = 1/2 (3+6) = 4.5 kmhr
time taken in stationary = 5/4.5 = 1 hrs 7 min
ANSWER:B
Answer: B
Question: In a mens hostel, there were 95 students. To accommodate 30 more students the average is decreased by rupees 5. But total expenditure increased by Rs.500. Find the total expenditure of the hostel now ?
Options:
A)Rs.4680
B)Rs.4287
C)Rs.4129
D)Rs.4112
E)Rs.4101
Rationale: Explanation:
Let the expenditure on the 95 students be 'x'
Then,
95x + 500 = 120(x â€“ 5)
95x + 500 = 120x - 600
120x - 95x = 1100
25x = 1100
=> x = 44
Therefore, total expenditure of the hostel becomes
95 x 44 + 500 = 4680.
Answer: A
Answer: A
Question: For the set {2, 2, 3, 3, 4, 4, 5, 5,7,7 x}, which of the following values of x will most increase the standard deviation?
Options:
A)1
B)2
C)3
D)(-3.2)^2
E)5
Rationale: Standard Deviation Step 1, as pointed out by others, is to find out the mean = 4.2
Step 2, For each number: subtract the Mean and square the result =
(1-4.2)^2=(-3.2)^2
(2-4.2)^2=(-2.2)^2
(3-4.2)^2 =(-1.2)^2
(4-4.2)^2=(.2)^2
(5-4.2)^2=(.8)^2
Clearly (1-3.5)^2=(-3.2)^2 will give you the greatest value among all the other options.
Hence D
Answer: D
Question: The population of a town is 186800. If it increase at the rate of 7% per annum. What will be its population for 2years hence?
Options:
A)200000
B)215600
C)194582
D)213867
E)215460
Rationale: population after 2years = 186800*(1+ 7/100)^2 = 213867
Answer is D
Answer: D
Question: 0,2,6,12,20, ____
Options:
A)25
B)28
C)30
D)26
E)35
Rationale: 0,2,6,12,20, .....
1*1-1=0
2*2-2=2
3*3-3=6
4*4-4=12
5*5-5=20
So 6*6-6=30
ANSWER:C
Answer: C
Question: In the city of San Durango, 60 people own cats, dogs, or rabbits. If 30 people owned cats, 40 owned dogs, 14 owned rabbits, and 12 owned exactly two of the three types of pet, how many people owned all three?
Options:
A)2
B)4
C)6
D)12
E)32
Rationale: You are considering a case when cat dogs and rabbit are not exactly equal to 12 .
The solution shall be 60=30+40+14-12-2x
and hence x shall be 6.
Answer C
Answer: C
Question: If the area of a square with sides of length 3 centimeters is equal to the area of a rectangle with a width of 4 centimeters, what is the length of the rectangle, in centimeters?
Options:
A)4
B)8
C)12
D)3
E)18
Rationale: Let length of rectangle = L
3^2 = L*4
=> L = 9/4 = 3
Answer D
Answer: D
Question: In a hostel there were 100 students. To accommodate 20 more students the average is decreased by rupees 5. But total expenditure increased by Rs.400. Find the total expenditure of the hostel now?
Options:
A)5429
B)2897
C)5400
D)2689
E)2781
Rationale: 100x + 400 = 12(x – 5)
x = 50
100 * 50 + 400 = 5400
Answer:C
Answer: C
Question: The digital sum of a number is the sum of its digits. For how many of the positive integers 24-80 inclusive is the digital sum a multiple of 7?
Options:
A)7
B)9
C)14
D)16
E)20
Rationale: is there other way than just listing?
25
34
43
52
59
61
68
70
77
9 ways..
B
Answer: B
Question: The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?
Options:
A)8 years
B)16 years
C)4 years
D)18 years
E)12 years
Rationale: Let the age of first child be x years.
since all the children got birth in interval of 3 years so the age of 2nd,3rd,4th and 5th child would be x-3 , (x-3)-3 ,((x-3)-3)-3 ,(((x-3)-3)-3)-3 respectively,
also the sum of ages of all children is 50,
= x+(x-3)+(x-6)+(x-9)+(x-12)=50
=5x-30=50
=5x=80
=x=16
so the age of youngest child would be 16-12 = 4 years. ANSWER : C
Answer: C
Question: Jamboree and GMAT Club Contest Starts
QUESTION #20:
How many words (with or without meaning) can be formed using all the letters of the word “SELFIE” so that the two E’s are not together?
Options:
A) 660
B) 600
C) 500
D) 300
E) 240
Rationale: The question is asking the total number of arrangements possible with the letters of the word “SELFIE” where two E’s are not together.
Arrangements when two E’s are not together = Total arrangements - Arrangements when two E’s are together
In total there are 6 letters but two are identical. so we can arrange in 6! ways. but we divide for those objects that are identical. so divide by 2!. Hence,
Total arrangements = 6!/2!
Now two E's are coupled together. Consider this couple (EE) as one letter. apart from this there are 4 more letters. so we can arrange these 5 different objects in 5! ways.
Two E's can arrange themselves in 2! ways, but we divide for those objects that are identical. so divide by 2!. so arrangement for E's would be 2!/2!.
Hence, Arrangements when two E’s are together = 5! * (2!/2!)
Arrangements when two E’s are not together = 6!/2! - 5! = 5! * ( 6/2 -1 ) = 120 * 2 = 240.
Option B is correct!
Answer: B
Question: Which of the following lines has x-intercept and y-intercept that are integers W?
Options:
A)y=3x+1
B)y=√x+1
C)y=-2/x
D)y=x^2-1
E)xy=1
Rationale: Values that satisfy y=x^2-1 are (x,y)=(-1,0),(1,0),(0,-1). Hence, they are all integers W and the correct answer is D.
Answer: D
Question: A no.when divided by 224 gives a remainder 43, what remainder will beobtained by dividingthe same no.17?
Options:
A)2
B)7
C)9
D)11
E)12
Rationale: 224 + 43 = 267/17 = 12 (Remainder)
E
Answer: E
Question: In X game of billiards, X can give Y 20 points in 60 and he can give Z 30 points in 60. How many points can Y give Z in X game of 80?
Options:
A)30
B)20
C)25
D)40
E)50
Rationale: X scores 60 while Y score 40 and Z scores 30.
The number of points that Z scores when Y scores 80 = (80 * 30)/40 = 60.
In X game of 100 points, Y gives (80 - 60) = 20 points to C.
B
Answer: B
Question: Stella buys an advertising agency for rs.16,000,000 and sells it for rs.20,000,000. Find her gain %.
Options:
A)9%
B)20%
C)14%
D)87%
E)25%
Rationale: sol. cp=rs16,000,000, sp=rs 20,000,000
gain=rs(20,000,000 –16,000,000)=rs4,000,000
so gain%={(4,000,000/16,000,000)*100}=25%
Answer is E.
Answer: E
Question: Two dice are rolled. What is the probability the sum will be greater than 8?
Options:
A)2/9.
B)1/12.
C)5/36.
D)7/36.
E)1/5.
Rationale: Combinations possible: (6,6) , (5,6) , (6,5) , (4,6), (6,4) , (5,5) , (5,4), (4,5) = 8
Total combinations possible: 6*6=36
Answer = 8/36 = 2/9 Option A.
Answer: A
Question: The length and breadth of a room are 8 m and 6 m respectively. A cat runs along all the four walls and finally along a diagonal order to catch a rat. How much total distance is covered by the cat?
Options:
A)22
B)88
C)38
D)99
E)11
Rationale: Answer: C) 38
Answer: C
Question: A bag of potatoes weighs 12 lbs divided by half of its weight. How much does the bag of potatoes weight?
Options:
A)20 lb
B)18 lb
C)12 lb
D)15 lb
E)5 lb
Rationale: Sol.
12÷1 = 12.
Answer : C
Answer: C
Question: The difference between simple and compound interests annually on a particular sum of money for 2 years at 4% per annum is Rs. 1. What is the sum?
Options:
A)600
B)625
C)650
D)675
E)700
Rationale: sum consider as x
CI = (x(1+4/100)^2-x) = 676/625x-x
=>51/625x
SI = x*4*2/100 = 2x/25
51x/625 - 2x/25 = 1
x= 625
ANSWER B
Answer: B
Question: If the length of a certain rectangle is decreased by 4 cm and the width is increased by 3 cm, a square with the same area as the original rectangle would result. Find the perimeter of the original rectangle.
Options:
A)33
B)38
C)77
D)50
E)29
Rationale: Explanation:
Let x and y be the length and breadth of the rectangle respectively.
Then, x - 4 = y + 3 or x - y = 7 ----(i)
Area of the rectangle =xy; Area of the square = (x - 4) (y + 3)
(x - 4) (y + 3) =xy <=> 3x - 4y = 12 ----(ii)
Solving (i) and (ii), we get x = 16 and y = 9.
Perimeter of the rectangle = 2 (x + y) = [2 (16 + 9)] cm = 50 cm.
Answer: D) 50
Answer: D
Question: A man starts walking at 3 pm, He walks at a speed of 4 km/hr on level ground and at a speed of 3 km/hr on uphill, 6 km/hr downhill and then 4 km/hr on level ground to reach home at 9 pm. What is the distance covered on one way?
Options:
A)8
B)9
C)10
D)11
E)12
Rationale: if x km is level ground and y km is hill road, then
x/4 + y/3 +y/6+x/4= 6
6(x+y)=72
x+y=12 km
so one side distance is 12 kms.
ANSWER:E
Answer: E
Question: The average of six numbers is 3.95. The average of two of them is 3.4, while the average of the other two is 3.85. What is the average of the remaining two numbers?
Options:
A)4.5
B)4.6
C)4.7
D)4.8
E)4.9
Rationale: Sum of the remaining two numbers
= (3.95 × 6) – [(3.4 × 2) + (3.85 × 2)]
= 23.70 – (6.8 + 7.7)
= 23.70 – 14.5 = 9.20
∴ Required average = (9.2⁄2) = 4.6
Answer B
Answer: B
Question: What day of the week was 1 January 1901
Options:
A)Monday
B)Tuesday
C)Saturday
D)Friday
E)None of these
Rationale: Explanation :
1 Jan 1901 = (1900 years + 1-Jan-1901)
We know that number of odd days in 400 years = 0
Hence the number of odd days in 1600 years = 0 (Since 1600 is a perfect multiple of 400)
Number of odd days in the period 1601-1900
= Number of odd days in 300 years
= 5 x 3 = 15 = 1
(As we can reduce perfect multiples of 7 from odd days without affecting anything)
1-Jan-1901 = 1 odd day
Total number of odd days = (0 + 1 + 1) = 2
2 odd days = Tuesday
Hence 1 January 1901 is Tuesday.
Answer : Option B
Answer: B