divelab/Sys2Bench huggingface dataset:
Question: Two trains start from same place at same time at right angles to each other. Their speeds are 36km/hr and 48km/hr respectively. After 30 seconds the distance between them will be ?
Options:
A)270 mts
B)190 mts
C)100 mts
D)500 mts
E)110 mts
Rationale: Explanation:
Using pythagarous theorem,
distance travelled by first train = 36x5/18x30 = 300m
distance travelled by second train = 48x5/18x30 = 400m
so distance between them =âˆš( 90000 + 160000) = âˆš250000 = 500mts.
Answer: D
Answer: D
Question: 261 ÷ ? × 15 + 270 = 405
Options:
A)24
B)25
C)36
D)39
E)43
Rationale: Explanation:
261 ÷ ? × 15 = 405 - 270 = 135
(261 × 15)/? = 135
? = (261 × 15)/135 = 39
Answer: Option D
Answer: D
Question: Paul sells encyclopedias door-to-door. He earns $150 on every paycheck, regardless of how many sets he sells. In addition, he earns commission as follows:
Commission Sales
10% $0.00 - $10,000.00
5% $10,000.01 --->
He does not earn double commission.That is, if his sales are $12,000, he earns 10% on the first $10,000 and 5% on the remaining $2,000.
His largest paycheck of the year was $1,320. What were his sales for that pay period?
Options:
A)13,400
B)14,800
C)16,400
D)15,800
E)19,600
Rationale: His pay check was $1320.
Out of this, $150 was his fixed salary so the total commission he earned was $1320 - $150 = $1170
He earns 10% on the sales of first $10,000 which gives a commission of $1000.
He earns 5% on every subsequent dollar. Since he earns another $170, he must have had sales of another 170*(100/5) = 3400
So his total sales must have been $10,000 + $3400 = $13,400
A
Answer: A
Question: The length of a rectangle is increased by 25% and its breadth is decreased by 20%. What is the effect on its area?
Options:
A)10000
B)18999
C)16990
D)16007
E)16991
Rationale: 100 * 100 = 10000
125 * 80 = 10000
Answer:A
Answer: A
Question: A not-so-good clockmaker has four clocks on display in the window. Clock #1 loses 35 minutes every hour. Clock #2 gains 15 minutes every hour relative to Clock #1 (i.e., as Clock #1 moves from 12:00 to 1:00, Clock #2 moves from 12:00 to 1:15). Clock #3 loses 20 minutes every hour relative to Clock #2. Finally, Clock #4 gains 20 minutes every hour relative to Clock #3. If the clockmaker resets all four clocks to the correct time at 12 noon, what time will Clock #4 display after 6 actual hours (when it is actually 6:00 pm that same day)?
Options:
A)5:00
B)5:34
C)5:42
D)6:00
E)6:24
Rationale: C1 loses 15 minutes every hour. So after 60 minutes have passed, C1 displays that 60-15 = 45 minutes have passed.
C2 gains 15 minutes for every 60 minutes displayed on C1. Thus, the time displayed on C2 is 75/60 = 5/4 the time displayed on C1. So after 60 minutes have passed, C2 displays the passing of (5/4 * 45) minutes.
C3 loses 20 minutes for every 60 minutes displayed on C2. Thus, the time displayed on C3 is 40/60 = 2/3 the time displayed on C2. So after 60 minutes have passed, C3 displays the passing of (2/3 * 5/4 * 45) minutes.
C4 gains 20 minutes for every 60 minutes displayed on C3. Thus, the time displayed on C4 is 80/60 = 4/3 the time displayed on clock 3. So after 60 minutes have passed, C4 displays the passing of 4/3 * 2/3 * 5/4 * 45 = 50 minutes.
C4 loses 10 minutes every hour.
In 6 hours, C4 will lose 6*10 = 60 minutes = 1 hour.
Since the correct time after 6 hours will be 6pm, C4 will show a time of 6-1 = 6:24pm.
The correct answer is E.
Answer: E
Question: How many two-digit numbers yield a remainder of 2 when divided by both 7 and 16?
Options:
A)0
B)1
C)2
D)3
E)4
Rationale: Easier to start with numbers that are of the form 16p+2 ---> 18,34,50,66,82,98.
Out of these no number is also of the form 7q+2. Thus 0 is the answer. A is the correct answer.
Answer: A
Question: A shopkeeper sold an article offering a discount of 5% and earned a profit of 18.75%. What would have been the percentage of profit earned if no discount was offered?
Options:
A)60%
B)23%
C)25%
D)56%
E)73%
Rationale: Let C.P. be Rs. 100.
Then, S.P. = Rs. 118.75
Let marked price be Rs. x. Then, 95/100 x = 118.75
x = 11875/95 = Rs. 125
Now, S.P. = Rs. 125, C.P. = Rs. 100
Profit % = 25%.
Answer: C
Answer: C
Question: An article was sold after a discount of 20% and therewas a gain of 20%. If the profit madeon it was Rs.6 less thanthe discount offered on it, find its SP?
Options:
A)Rs. 22
B)Rs. 65
C)Rs. 70
D)Rs. 72
E)Rs. 90
Rationale: Let CP = Rs. 100x
SP = Rs. 120x
MP = 120x/80 * 100 = Rs. 150x
D = Rs. 150x - Rs. 120x = Rs. 30x
D - P = 30x - 20x = Rs. 6, 10x = Rs. 6
120x = 120/10 * 6 = Rs. 72
C
Answer: C
Question: A thief is noticed by a policeman from a distance of 150 m. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 10 km and 11 km per hour respectively. What is the distance between them after 6 minutes ?
Options:
A)50 meter
B)100 meter
C)110 meter
D)120 meter
E)130 meter
Rationale: Explanation:
Relative speed of the thief and policeman = (11 – 10) km/hr = 1 km/hr
Distance covered in 6 minutes =
1/60∗6=1/10=100meters
So distance between them after 6 minutes = 150 - 100
= 50 meters
Option A
Answer: A
Question: Arun has certain number of books. It is not less than 15 and not more than 30. If he wants to give these books equally to 2 of his friends, then 1 book will remain. If he wants to give these books equally to 3 of his friends, then 2 books will remain. If he wants to give these books equally to 4 of his friends, then 3 books will remain. What is the number of books he had?
Options:
A)18
B)19
C)17
D)29
E)23
Rationale: If he wants to give these books equally to 2 of his friends, then 1 book will remain, it means possible number of books = 15,17,19,21,23,25,27,29
If he wants to give these books equally to 3 of his friends, then 2 books will remain, it means possible number of books = 17,20,23,26,29
If he wants to give these books equally to 4 of his friends, then 3 book will remain, it means possible number of books = 15,19,23,27
common number is only 23 so it will be answer
ANSWER:E
Answer: E
Question: What is the remainder when 4^381 is divided by 5 ?
Options:
A)0
B)1
C)2
D)3
E)4
Rationale: I also agree that the remainder is '4' (using the last digit of the powers of 7). Could we have the official answer please?E
Answer: E
Question: The average of 11 numbers is 10.9. If the average of first six is 10.5 and that of the last six is 11.4 the sixth number is?
Options:
A)11.9
B)11.0
C)11.3
D)11.5
E)11.1
Rationale: 1 to 11 = 11 * 10.9 = 119.9
1 to 6 = 6 * 10.5 = 63
6 to 11 = 6 * 11.4 = 68.4
63 + 68.4 = 131.4 – 119.9 = 11.5
6th number = 11.5.Answer:D
Answer: D
Question: A train running at the speed of 60 km/hr crosses a pole in 12 sec. What is the length of the train?
Options:
A)120 m
B)200 m
C)115 m
D)110 m
E)150 m
Rationale: Speed = 60 * 5/18 = 50/3 m/sec
Length of the train = speed * time = 50/3 * 12 = 200 m
Answer: B
Answer: B
Question: An investment gained an interest payment of $250 each month when the annual interest rate was 8%, how much more should we invest annually if we want to gain 12% more per month with a new annual interest rate of 7.5% ?
Options:
A)$9,360
B)$9,100
C)$8,250
D)$7,300
E)$7,150
Rationale: Answer is D : 7,300
Interest per annum with 8% interest rate is = 250* 12 = Principal * Interest Rate(8/100)
This gives Principal as 37,500$
For an revised interest of 12% more and new interest rate of 7.5% , ie. 250* 12 * 1.12 = Principal * Interest Rate (7.5/100)
This gives the new Principal as 44,800.
The question is how much more should we invest, so 44,800 - 37,500 = 7,300
ANSWER:D
Answer: D
Question: If the compound interest on a certain sum of money for 7 years at 10% per annum be Rs. 993, what would be the simple interest?
Options:
A)Rs. 880
B)Rs. 890
C)Rs. 895
D)Rs. 2100
E)None
Rationale: Let P = Principal
A - Amount
We have a = P(1 + R/100)3 and CI = A - P
ATQ 993 = P(1 + R/100)3 - P
? P = 3000/-
Now SI @ 10% on 3000/- for 7 yrs = (3000 x 10 x 7)/100
= 2100/-
Answer: D.
Answer: D
Question: What is the difference between the largest number and the least number written with the figures 3, 4, 7, 0, 3?
Options:
A)98343
B)34389
C)43983
D)43883
E)43700
Rationale: 74330 Largest
30347 Smallest
------------
43983
ANSWER C
Answer: C
Question: A certain restaurant offers 7 different salads, 5 different main courses, and 6 different desserts. If customers choose one salad, one main course, and two different desserts for their meal, how many different meals are possible?
Options:
A)125
B)275
C)525
D)600
E)1200
Rationale: The number of possible choices for desserts is 6C2 = 15
The number of possible meals is 7*5*15 = 525
The answer is C.
Answer: C
Question: Because of the economic slowdown, a multinational company curtailed some of the allowances of its employees. John, the marketing manager of the company whose monthly salary has been reduced to Rs.42,000 is unable to cut more on his expenditure. He finds that there is a deficit of Rs.2,000 between his earning and expenses in the first month. This deficit, because of inflationary pressure, will keep on increasing by Rs.500 everymonth. John has a saving of Rs 60,000 which will be used to fill the deficit. After his savings get exhausted, John would start borrowing from his friends. How soon will he start borrowing?
Options:
A)9th months
B)10th months
C)11th months
D)12th months
E)13th months
Rationale: Let the Rashid 's savings will last till 'nn' months.
⇒n2[2×2000+(n−1)500]=60,000⇒n2[2×2000+(n−1)500]=60,000
[Expenditure every month increases by 500 rupees]
⇒n2+7n−200=0⇒n2+7n−200=0
n=12.38n=12.38
⇒ Rashid after Kartik's mother asked him to get the vegetables, milk and butter from the market and gave him the money in the denominator of 1 Rupee, 2 Rupee and 5 Rupee coins.
Kartik first goes to the grocery shop to buy vegetables. At the grocery shop he gives half of his 5 Rupee coins in return receives the same number of 1 Rupee coins.
Next he goes to the dairy shop to buy milk and butter and gives all 2 Rupee coins and in return get thirty 5 Rupee coins, which increase the number of five rupee coins by 75% more than the original number.
If the number of 1 rupee coins now is 50, the number of 1 rupee and 5 rupee coins originally were will start borrowing money from his friends.
E
Answer: E
Question: The probability that a man will be alive for 10more yrs is 1/4 & the probability that his wife will alive for 10 more yrs is 1/3. The probability that none of them will be alive for 10 more yrs, is
Options:
A)1/2
B)1
C)2/3
D)3/4
E)2
Rationale: Sol. Required probability = Pg.) x P(B) = (1— D x(1 —I) =: x 1=1/2
Ans.(A)
Answer: A
Question: If w < y < -1, which of the following is true?
Options:
A)w/y > wy
B)y/w > w+y
C)y/w > wy
D)y/w < w+y
E)y/w > w/y
Rationale: Consider :
w= -3
y= -2
then put for every option. U'll get ans B.
Answer: B
Question: A rope of which a calf is tied is increased from 16 m to 23 m, how much additional grassy ground shall it graze?
Options:
A)1217
B)1219
C)1210
D)1212
E)858
Rationale: π (232 – 162) = 858
Answer:E
Answer: E
Question: How many numbers from 19 to 79 are exactly divisible by 11?
Options:
A)5
B)6
C)9
D)11
E)12
Rationale: 19/11 = 1 and 79/11 = 7 ==> 7 - 1 = 6 Numbers
Answer : B
Answer: B
Question: Miller Street begins at Baker Street and runs directly east for 4.5 kilometers until it ends when it meets Turner Street. Miller Street is intersected every 250 meters by a perpendicular street, and each of those streets other than Baker Street and Turner Street is given a number beginning at 1st Street (one block east of Baker Street) and continuing consecutively (2nd Street, 3rd Street, etc...) until the highest-numbered street one block west of Turner Street. What is the highest-numbered street that intersects Miller Street?
Options:
A)15th
B)16th
C)17th
D)18th
E)19th
Rationale: 4.5 km / 250 m = 18.
However, the street at the 4.5-km mark is not 18th Street; it is Turner Street.
Therefore, the highest numbered street is 17th Street.
The answer is C.
Answer: C
Question: Faiza has 9 purses, she gives 3 purse as gift. Now how many purse did she have?
Options:
A)2
B)6
C)11
D)9
E)4
Rationale: 9-3=6. Answer is B
Answer: B
Question: A lawyer's representation costs $150 for the first hour and $125 for each additional hour. What is the total cost, in dollars, of her representation for m hours, where m is an integer greater than 1?
Options:
A)150 + 125 m
B)150 + 125( m – 1)
C)125 + 150 m
D)125 + 150( m – 1)
E)275( m – 1)
Rationale: For the first hour the cost is 150.
As first hour is already calculated the remaining is m-1 and corresponding cost is 125.
Therefore answer is 150+125(m-1).
Answer B
Answer: B
Question: One year ago the ratio between Samir and Ashok’s age was 4:3. One year hence the ratio of their ages will be 5 :4. What is the sum of their present ages in years?
Options:
A)12 years
B)15 years
C)16 years
D)Cannot be determined
E)none of these
Rationale: Let their ages one year ago be 4x and 3x years.
(4x + 2)/(3x + 2) = 5/4
=>4(4x + 2) = 5(3x + 2)
=> x = 2
Sum of their present ages
= (4x + 1 + 3x + 1)
=(7x + 2) = 16 years
ANSWER:C
Answer: C
Question: A certain company has 18 equally qualified applicants for 4 open positions. How many different groups of 4 applicants can be chosen by the company to fill the positions if the order of selection does not matter?
Options:
A)18
B)72
C)180
D)1,260
E)3,060
Rationale: This is a combination question since order is not important.
n!
k! (n-k!)
= 18!
4! 14!
= 18 * 17 * 16 * 15 * 14!
4 * 3 * 2 * 1 * 14!
= 3060 (Ans: E)
Answer: E
Question: What is the square root of 0.16
Options:
A)0.4
B)0.04
C)0.004
D)4
E)1
Rationale: Explanation:
as .4 * .4 = 0.16
Option A
Answer: A
Question: What is the rate percent when the simple interest on Rs.4000 amount to Rs.320 in 2 Years?
Options:
A)4%
B)4.1%
C)4.2%
D)4.3%
E)4.5%
Rationale: Interest for 1 year = 320/2 = 160
Interest on Rs 4000 p/a = 160
interest rate = 160/4000*100 = 4%
Answer : A
Answer: A
Question: When n is divided by 20, the remainder is 5. What is the remainder when n + 16 is divided by 5?
Options:
A)1
B)3
C)4
D)5
E)6
Rationale: Assume n = 15
Remainder (n/20) = 5
n+16 = 31
Remainder (31/5) = 1
Option A
Answer: A
Question: The ratio of a compound, by weight, consisting only of substances x, y, and z is 4:6:10,
respectively. Due to a dramatic increase in the surrounding temperature, the composition of the
compound is changed such that the ratio of x to y is halved and the ratio of x to z is tripled. In the
changed compound, if the total weight is 174 lbs, how much does substance x weigh?
Options:
A)48
B)36
C)24
D)12
E)10
Rationale: x:y=4:6
if the ratio is halevd then x:y=2:6
The old ratio of x to z was 4:10. If this ratio is tripled, then the new ratio of x to z is 12:10.
x:y=2:6=12:36 ( multiplied the ration with 6/6 to have a common co eff x in both the rations x:y and x:z)
so x:y:z= 12:36:10
and we know x + y + z = 174 lbs
from the ratio of x ,y and z we have x=12k y=36k z=10K
put it in the equation we have 12k+36k+10k=174
k=3
Hence x=12(3)=36
Ans B
Answer: B
Question: In how many years, Rs. 200 will produce the same interest at 6% as Rs. 800 produce in 2 years at 4½% ?
Options:
A)4 years
B)6 years
C)8 years
D)9 years
E)12 years
Rationale: Explanation :
Let Simple Interest for Rs.200 at 6% for n years = Simple Interest for Rs.800 at 4½ % for 2 years
200×6×n/100=800×9/2×2/100
200×6×n=800×9/2×2
200×6×n=800×9
n=6 years
Answer : Option B
Answer: B
Question: On one side of a coin there is the number 0 and on the other side the number 1. What is the probability that the sum of three coin tosses will be 0 ?
Options:
A)1/8
B)1/2.
C)1/5.
D)3/8.
E)1/3.
Rationale: Assume the coin is unbiased.
Possible sums from 3 tosses = 0,1,2,3
O and 3 are possible in only 1 case each. (0,0,0 or 1,1,1)
1 is possible in 3C1 = 3 cases. (1,0,0; 0,1,0 or 0,0,1) or
similarly, 2 is possible in 3C2=3 cases (1,0,1; 1,1,0; 0,1,1)
So answer will be 1/8. Option A.
Answer: A
Question: At a party, there were five ten as many females as males and four times as many adults as children. Which of the following could be the number of people at the party?
Options:
A)384
B)258
C)216
D)120
E)72
Rationale: Five times as many females as males --> F = 10M.
Three times as many adults as children --> (F + M) = 4C.
The number of people at the party = F + M + C = 4C + C = 5C.
The number of people at the party must be a multiple of 5. The only answer choice which is a multiple of 5 is D.
Answer: D.
Answer: D
Question: Every disk in a bag is either blue, yellow or green. The ratio of blue disks to yellow disks to green disks in this bag is 3 : 7 : 8. If the total number of disks in the bag is 144, how many more green disks than blue disks are in the bag?
Options:
A)25
B)28
C)30
D)35
E)40
Rationale: Let B:Y:G = 3x:7x:8x.
3x + 7x + 8x = 18x = 144 --> x= 8.
G - B = 8x - 3x = 5x = 40.
The answer is E.
Answer: E
Question: What approximate value should come in place of the question mark (?) in the following equation?
8.539 + 16.84 × 6.5 ÷ 4.2 = ?
Options:
A)25
B)42
C)44
D)35
E)None of these
Rationale: ? 8.6 + 4 × 6.5 = 35
Answer D
Answer: D
Question: In a graduating class of 233 students, 144 took geometry and 119 took biology. What is the difference between the greatest possible number and the smallest possible number of students that could have taken both geometry and biology?
Options:
A)114
B)119
C)113
D)88
E)31
Rationale: Greatest Possible Number taken both should be 144 (As it is maximum for One)
Smallest Possible Number taken both should be given by
Total - Neither = A + B - Both
Both = A+B+Neither - Total (Neither must be 0 to minimize the both)
So 144 + 119 + 0 - 233 = 30
Greatest - Smallest is 144-30 = 114
So answer must be A. 114
Answer: A
Question: A pupil’s marks were wrongly entered as 83 instead of 63. Due to that the average marks for the class got increased by half. The number of pupils in the class is:
Options:
A)10
B)20
C)40
D)73
E)50
Rationale: Let there be x pupils in the class.
Total increase in marks = (x × 1⁄2) = x⁄2.
∴ x⁄2 = (83 - 63) ⇒ x⁄2 = 20 ⇒ x = 40.
Answer C
Answer: C
Question: A group of medical interns at Bohemus Medical School want to go on dates. There are 8 girls and 8 guys. Assuming girls go on dates with guys, how many possible ways can these 16 medical interns date each other?
Options:
A)A)36320
B)B)37320
C)C)38320
D)D)39320
E)E)40320
Rationale: 1st girl can go with 8 guys
2nd girl can go with remaining 7
3rd girl can go with remaining 6 and so on
so the total ways are 8!= 40320
E should be the answer
Answer: E
Question: Find the invalid no.from the following series 2,3,12,37,86,166,288
Options:
A)123
B)145
C)166
D)173
E)187
Rationale: 3-2=1
12-3=9
37-12=25
86-37=49
166-86=80(this must be 81=167-86=81)
so wrong number in the sequence is 166
difference between two sucessive numbers sequence would be
1,9,25,49,81,121(square of 1,3,5,7,9,11)
C
Answer: C
Question: In what ratio must water be added to 10 litres of milk at Rs.20 per litre so that cost of mixture is Rs.16 per litre?
Options:
A)3:2
B)1:4
C)2:3
D)4:1
E)4:3
Rationale: C.P of 1 Lt of water =Rs.0
C.p Of 1 lt of Milk= Rs.20
So,
o(Cheaper) 20(Dearer)
16(Mixture)
4 : 16
(Dearer-Mixture) (Mixture-Cheaper)
so,
(Note: Just cross check)
4:16=1:4
ANSWER:B
Answer: B
Question: If xy ≠ 0 and x^2y^2 − 2xy = 24, which of the following could be y in terms of x?
I. 6/x
II. -4/x
III. 1/x
Options:
A)I only
B)II only
C)I and II only
D)I and III
E)II and III
Rationale: (x^2)(y^2) –2xy - 24 = 0
(xy – 6)(xy + 4) = 0
xy – 6 = 0 or xy + 4 = 0
xy = 6 or xy = -4
Since we need y in terms of x, we can isolate y in both of our equations.
y = 6/x or y = -4/x
Answer: C
Answer: C
Question: In a shop, 40% socks are white and rest are black. 60% socks are made of cotton and rest are made of wool. 25% white socks are made of cotton and 20 of the black socks are made of wool. How many black socks D are made of cotton?
Options:
A)100
B)80
C)60
D)50
E)25
Rationale: I'll prefer to solve this with plug n play method.
As we know, White Cotton socks are only 25% and Total Cotton socks is 60% - Hence Black Cotton socks D has to be [highlight]HIGH[/highlight]number. Thats why we've to pick high number... say 100 or 80.
100 fits perfectly after relevant calculations. Hence answer A.
Answer: A
Question: In a function they are distributing noble prize. In how many ways can 3 prizes be distributed among 4 boys when No boy gets more than one prize?
Options:
A)14
B)19
C)20
D)24
E)26
Rationale: Sol. In this case, repetitions are not allowed. So, the first prize can be given in 4 ways. The second in 3 ways and the third in 2 ways. But fundamental principle, (4 x 3 x 2) ways = 24 ways
4: Or 4p = — 4:- 4X3X2X1- 24 ways
D
Answer: D
Question: Points M(13,22) and N(5,8) lie on the xy - plane. What is the midpoint of line segment MN?
Options:
A)(5,0)
B)(0,5)
C)(0, (136^(1/2))/2)
D)(3/2,0)
E)(9,15)
Rationale: The midpoint of a segment is exactly halfway between its endpoints and it's location can be found using the Midpoint Theorem, which states:-
The x-coordinate of the midpoint is the average of the x-coordinates of the two endpoints.• Likewise, the y-coordinate is the average of the y-coordinates of the endpoints.
So, x=(13+5)/2=9 and y=(22+8)/2=15 --> coordinates of the midpoint are (9, 15).
Answer: E.
Answer: E
Question: In a certain district, the ratio of the number of registered Republicans to the number of registered Democrats was 3/5. After 600 additional Republicans and 500 additional Democrats registered, the ratio was 4/5. After these registrations, there were how many more voters in the district registered as Democrats than as Republicans?
Options:
A) 100
B) 300
C) 400
D) 1,000
E) 2,500
Rationale: 3/5 republican voters = 0.6*x
Another 600 register as republican, with the total amount being 80% republican (4/5)
Total new voters is 1,100 (500+600)
So, 0.6x + 600 = 0.8(x+1,100)
0.6x + 600 = 0.8x + 880
answer is B
Answer: B
Question: The length of a rectangular plot is thrice its breadth. If the area of the rectangular plot is 867 sq m, then what is the breadth of the rectangular plot?
Options:
A)11
B)17
C)88
D)66
E)12
Rationale: Let the breadth of the plot be b m.
Length of the plot = 3 b m
(3b)(b) = 867
3b2 = 867
b2 = 289 = 172 (b > 0)
b = 17 m.Answer: B
Answer: B
Question: A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Options:
A)816 m
B)577 m
C)240 m
D)176 m
E)126 m
Rationale: Speed = [54 * 5/18] m/sec = 15 m/sec.
Length of the train = (15 * 20) m = 300 m.
Let the length of the platform be x meters.
Then, x + 300 / 36 = 15
x + 300 = 540
x = 240 m.
Answer:C
Answer: C
Question: what is the next term of this series6,10,9,15,12,20,15...?
Options:
A)9
B)25
C)11
D)12
E)15
Rationale: 3&2=6;
5*2=10;
3*3=9;
3*5=15
3*4=12
5*4=20
3*5=15
5*5=25
ANSWER:B
Answer: B
Question: Light glows for every 20 seconds . How many max. times did it glow between 1:57:58 and 3:20:47 am.
Options:
A)380 times
B)381 times
C)382 times
D)248 times
E)482 times
Rationale: Time difference is 1hr,22min,49sec=4969sec. So, light glows floor(4969/20)=248 times.
ANSWER:D
Answer: D
Question: Andrew started saving at the beginning of the year and had saved $160 by the end of the year. He continued to save and by the end of 2 years had saved a total of $540. Which of the following is closest to the percent increase in the amount Andrew saved during the second year compared to the amount he saved during the first year?
Options:
A)11%
B)25%
C)44%
D)56%
E)137.5%
Rationale: Percent increase in the amount Andrew saved during the second year compared to the amount he saved during the first year.
Percentage Change = ( Change in value / Original value ) * 100
Percentage Change = [ (Saving in 2nd year - Saving in 1st year ) / Saving in 1st year ] * 100
Saving in 2nd year + Saving in 1st year = 540
Saving in 2nd year + 160 = 540
Saving in 2nd year = 540 - 160 = 380
Change in Value = 380 - 160 = 220
Original Value = 160
Percentage Increase = (220 / 160 ) * 100 = 137.5 % ..... Answer E.....
Answer: E