divelab/Sys2Bench huggingface dataset:
Question: Find the largest 3 digit number which is exactly divisible by 88?
Options:
A)765
B)907
C)944
D)954
E)968
Rationale: Largest 3 digit number is 999
After doing 999 ÷ 88 we get remainder 31
Hence largest 3 digit number exactly divisible by 88 = 999 - 31 = 968
E
Answer: E
Question: P can complete a work in 12 days working 8 hours a day.Q can complete the same work in 8 days working 10 hours a day. If both p and Q work together,working 8 hours a day,in how many days can they complete the work?
Options:
A)60/11
B)60/12
C)60/18
D)60/16
E)65/16
Rationale: Explanation:
P can complete the work in (12 * 8) hrs = 96 hrs
Q can complete the work in (8 * 10) hrs=80 hrs
\inline {\color{Black}\therefore } P's 1 hour work=1/96 and Q's 1 hour work= 1/80
(P+Q)'s 1 hour's work =\inline {\color{Black} \left ( \frac{1}{96}+\frac{1}{80} \right )} =\inline {\color{Black} \frac{11}{480}}
so both P and Q will finish the work in \inline {\color{Black} \frac{480}{11}} hrs
\inline {\color{Black} \therefore } Number of days of 8 hours each = \inline {\color{Black} \left ( \frac{480}{11} \times \frac{1}{8}\right )=\frac{60}{11}}
Answer: A) 60/11
Answer: A
Question: The wages earned by Robin is 40% more than that earned by Erica. The wages earned by Charles is 60% more than that earned by Erica. How much % is the wages earned by Charles more than that earned by Robin?
Options:
A)23%
B)18.75%
C)28.57%
D)50%
E)100%
Rationale: Explanatory Answer
Let the wages earned by Erica be $100
Then, wages earned by Robin and Charles will be $140 and $160 respectively.
Charles earns $40 more than Robin who earns $140.
Therefore, Charles' wage is 40/140*100 = 28.57%.
The correct choice is (C)
Answer: C
Question: If the price has fallen by 11% what percent of its consumption be: increased so that the expenditure may be the same as before?
Options:
A)A)11/89%
B)B)10%
C)1/9 %
D)1/11 %
E)%
Rationale: 100 – 11 = 89
89------11
100------? => 11/89%
ANSWER:A
Answer: A
Question: Two taps can separately fill a cistern 10 minutes and 18 minutes respectively and when the waste pipe is open, they can together fill it in 18 minutes. The waste pipe can empty the full cistern in?
Options:
A)6
B)8
C)1
D)9
E)10
Rationale: 1/10 + 1/18 - 1/x = 1/18
x = 10
Answer:E
Answer: E
Question: The average of 25 results is 20. The average of first 12 of those is 14 and the average of last 12 is 17. What is the 13th result?
Options:
A)128
B)75
C)69
D)78
E)45
Rationale: Solution: Sum of 1st 12 results = 12*14
Sum of last 12 results = 12*17
13th result = x (let)
Now,
12*14+12*17+x = 25*20
Or, x = 128.
Answer: Option A
Answer: A
Question: 1 Decade ago, Karthik’s mother was quadrice older than her son. After one decade, the mother will be two times older than her son. The current age of Karthik is?
[Decade = 10 Years; quadrice= 4 times]
Options:
A)20 years
B)60 years
C)80 years
D)40 years
E)10 years
Rationale: A
20 years
Let Karthikh’s age 10 years ago be A year
His mother’s age 1 decade ago = 4A
(4A + 10) + 10 = 2 (A + 10 +10)
2A = 20 or A =10
Current age of Karthikh = (A + 10)
= 20 years
Answer: A
Question: A shopkeeper buys two articles for Rs.1000 each and then sells them, making 40% profit on the first article and 40% loss on second article. Find the net profit or loss percent?
Options:
A)200
B)278
C)282
D)400
E)270
Rationale: Profit on first article = 40% of 1000 = 400.
This is equal to the loss he makes on the second article. That, is he makes neither profit nor loss.
Answer: D
Answer: D
Question: Find the invalid no.from the following series 13, 18, 25, 30, 37, 40
Options:
A)23
B)35
C)40
D)45
E)67
Rationale: The differences between two successive terms from the beginning are 7, 5, 7, 5, 7, 5. So, 40 is wrong.
C
Answer: C
Question: ACME’s manufacturing costs for sets of horseshoes include a $11,450 initial outlay, and $19.75 per set. They can sell the sets $51.00. If profit is revenue from sales minus manufacturing costs, and the company producessells 987 sets of horseshoes, what was their profit?
Options:
A)$19,393.75
B)$30,943.25
C)$41,308.50
D)$51,817.50
E)$53,624.25
Rationale: its A
since options are not so close we can solve this by uniting calculation and guessing
total sales will be bit lower than 51000
from that initial outlay will get deducted 11500 so we left with 31500
variable cost say 20 X 1000 = 20000 will be deducted so finally we left with 19500
since we have considered the price greater than it actually is, the correct answer will certainly not cross the threshold of 19500.
Answer: A
Question: In a company of 180 employees, 110 are females. A total of 90 employees have advanced degrees and the rest have a college degree only. If 35 employees are males with a college degree only, how many employees are females with advanced degrees?
Options:
A)50
B)55
C)60
D)65
E)70
Rationale: The number of males is 180-110=70.
The number of males with advanced degrees is 70-35=35.
The number of females with advanced degrees is 90-35=55.
The answer is B.
Answer: B
Question: The probability that A speaks truth is 2/5 and that of B speaking truth is 3/7. What is the probability that they agree in stating the same fact?
Options:
A)18/35
B)17/35
C)18/36
D)18/16
E)18/31
Rationale: If both agree stating the same fact, either both of them speak truth of both speak false.
Probability
= 2/5 * 4/7 + 3/5 * 3/7
= 8/35 + 9/35
= 17/35
Answer: B
Answer: B
Question: When a plot is sold for Rs.18,700,the owner loses 15%.At what price must the plot be sold in order to gain 15% ?
Options:
A)Rs.21,000
B)Rs.22,500
C)Rs.25,300
D)Rs.25,800
E)None of these
Rationale: Solution
85 : 18700 = 115 : x or x =(18700x115/85) = 25300.
Hence, S.P. = Rs. 25,300.
Answer C
Answer: C
Question: A person has to cover the fixed distance through his horses. There are five horses in the cart. They ran at the full potential for the 24 hours continuously at constant speed and then two of the horses ran away to some other direction. So he reached the destination 48 hours behind the schedule. If the five horses would have run 50 miles more, then the person would have been only 24 hours late. Find the distance of the destination.
Options:
A)200/3
B)400/3
C)500/3
D)600/8
E)800/3
Rationale: Suppose his actual speed is 'v' with 5 horses,
If he travelled that 50 miles with 5 horses the time taken wud b 50/v, which equals time taken with 3/5th speed minus 24hrs
50/v = 50/(3v/5) - 24;
so, v = 25/18;
Now, suppose after 1st 24 hrs he takes 't' hrs toreach his destination, then
vt = (3v/5)(t + 48);
vt = (3v/5)(t+48)
t = 72
total time = 72+24 = 96
distance = 400/3
ANSWER:B
Answer: B
Question: The average age of a husband and a wife is 23 years when they were married five years ago but now the average age of the husband, wife and child is 23 years(the child was born during the interval). What is the present age of the child?
Options:
A)16
B)15
C)18
D)14
E)13
Rationale: 28 * 2 = 56
23 * 3 = 69
-----------
13 years.Answer: E
Answer: E
Question: What is the remainder when 14,452 × 15,652 × 16,781 is divided by 5?
Options:
A)0
B)1
C)2
D)3
E)4
Rationale: Only the unit's digit of the product will decide the remainder when divided by 5.
Hence, 2*2*1= will give units digit as 4
So, whatever be the number, if it ends in 4, the remainder after dividing with 5 will be 4.
OptionE
Answer: E
Question: Arjun leaves home everyday at 4 p.m to pick his son from school and returns home at 6 p.m. One day, the school was over at 4 p.m and the son started walking home from school. Arjun, unaware of this, starts from home as usual and meets his son on the way and returns home with him 15 minutes early. If the speed of Arjun is 30 km\hr, find the speed of his son.
Options:
A)15km/hr
B)6 km/hr
C)4.28 km/hr
D)9 km/hr
E)4.12 km/hr
Rationale: Arjun leaves home everyday at 4 p.m to pick his son from school and returns home at 6 p.m. One day, the school was over at 4 p.m and the son started walking home from school. Arjun, unaware of this, starts from home as usual and meets his son on the way and returns home with him 15 minutes early. If the speed of Arjun is 30 km\hr, find the speed of his son.
The distance from home to school is 30 km. The round trip distance = 60 km. Because he returns home 15 minutes early, I thought it might be easier to break his trip up into 8 identical 15 minute blocks, each of which he traveled at 7.5 km/hour.
Because we are dealing with a round trip here, Arjun would have stopped 7.5 minutes short of the school. This means he traveled Distance=rate* time .5Km/hour*52.5 minutes or 26.25 KM. His son therefore traveled 3.75km/hour by the time he met his dad at 4:52.5. It took the son 52.5 minutes to travel 3.75 km. Because we are trying to find the son's rate per hour (i.e. 60 minutes) and we have his speed for 52.5 minutes it's best to convert to km/minute then multiply by 60 to get km/hour
3.75km/52.5 = .07 km/minute
.07km/minute*60 minutes = 4.28 km/hour.
Answer: C. 4.28 km/hr
Answer: C
Question: If 49(7^x) = 1 then x=
Options:
A)–2
B)–1
C)0
D)1
E)2
Rationale: 7^x = 1/49
7^x = 1/7^2
7^x= 7^-2
x = -2
A
Answer: A
Question: A store’s selling price of $2240 for a certain computer would yield a profit of 30 percent of the store’s cost for the computer. What selling price would yield a profit of 40 percent of the computer’s cost?
Options:
A)	$2400
B)	$2412
C)	$2650
D)	$2732
E)	$2800
Rationale: 1.3x = 2240
x=2240/1.3
so, 1.4X = 2240*1.4/1.3= 2412
Answer:- B
Answer: B
Question: A person purchases 90 clocks and sells 40 clocks at a gain of 10% and 50 clocks at a gain of 20%. If he sold all of them at a uniform profit of 15%, then he would have got Rs. 40 less. The cost price of each clock is:?
Options:
A)40
B)60
C)80
D)67
E)30
Rationale: Let C.P. of clock be Rs. x.
Then, C.P. of 90 clocks = Rs. 90x.
[(110% of 40x) + (120% of 50x)] - (115% of 90x) = 40
44x + 60x - 103.5x = 40
0.5x = 40 => x = 80
Answer: C
Answer: C
Question: Joe drives 180 miles at 60 miles per hour, and then he drives the next 120 miles at 40 miles per hour. What is his average speed for the entire trip in miles per hour?
Options:
A)42
B)50
C)50
D)54
E)56
Rationale: t1= 180/60=3 hours
t2=120/40=3 hours
T=t1+t2=6 hours
Avg speed = Total Distance/T
= 300/6 = 50mph=B
Answer: B
Question: The price of 10 chairs is equal to that of 4 tables. The price of 15 chairs and 2 tables together is Rs. 4000. The total price of 12 chairs and 3 tables is:
Options:
A)3500
B)3750
C)3800
D)3840
E)3900
Rationale: Let the cost of a chair and that of a table be Rs. x and Rs. y respectively.
Then, 10x = 4y or y =	5/2x.
15x + 2y = 4000
15x + 2 x	(5/2)	x = 4000
20x = 4000
x = 200.
So, y =(5/2)x 200= 500.
Hence, the cost of 12 chairs and 3 tables = 12x + 3y
= Rs. (2400 + 1500)
= Rs. 3900.
Option E
Answer: E
Question: On average, the bottle-nosed dolphin comes up for air once every five minutes; the beluga whale, a close relative, comes up for air on average once every eight minutes. The number of times a bottle-nosed dolphin would come up for air in a 24 hour period is approximately what percent greater than the number of times a beluga whale would come up for air in that same period?
Options:
A)50%
B)75%
C)100%
D)150%
E)200%
Rationale: Dolphin once in 5 min;
Beluga once in 8 min;
So, dolphin comes up 1.6 times frequently than beluga, which is 150% (8-5)/2*100.
Answer: D.
Answer: D
Question: What is the sum of all possible 3-digit numbers that can be constructed using the digits 1, 3, and 4 if each digit can be used only once in each number?
Options:
A)1443
B)1554
C)1665
D)1776
E)1887
Rationale: There are 6 possible arrangements of the three numbers.
Then each number will be in the hundreds, tens, and ones place two times each.
The sum is 2(111) + 2(333) + 2(444) = 1776
The answer is D.
Answer: D
Question: An amount of Rs. 100000 is invested in two types of shares. The first yields an interest of 9% p.a and the second, 11% p.a. If the total interest at the end of one year is 9 3/4 %, then the amount invested in each share was?
Options:
A)37583
B)37500
C)37507
D)37508
E)37502
Rationale: Let the sum invested at 9% be Rs. x and that invested at 11% be Rs. (100000 - x). Then,
(x * 9 * 1)/100 + [(100000 - x) * 11 * 1]/100 = (100000 * 39/4 * 1/100)
(9x + 1100000 - 11x)/100 = 39000/4 = 9750
x = 62500
Sum invested at 9% = Rs. 62500
Sum invested at 11% = Rs. (100000 - 62500) = Rs. 37500.
Answer:B
Answer: B
Question: If PINTU is coded as 79523 in a certain code language, how would you code BUNTU in the same language?
Options:
A)13426
B)23523
C)13436
D)14263
E)15263
Rationale: 1 2 3 4 5 6 7 8 9
a b c d e f g h i
j k l m n o p q r
s t u v w x y z
sooo...BUNTU is 23523...
ANSWER:B
Answer: B
Question: A and B can do a piece of work in 3 days, B and C in 4 days, C and A in 6 days. How long will C take to do it?
Options:
A)65 days
B)51 days
C)24 days
D)16 days
E)17 days
Rationale: 2c = ¼ + 1/6 – 1/3 = 1/12
c = 1/24 => 24 days
Answer: C
Answer: C
Question: A patient was given a bottle of tablets by the doctor and he was asked to take five tablets in a gap of 15 minutes.
In how much time will he be able to take all the five tablets?
Options:
A)1 Hour.
B)2 Hour.
C)3 Hour.
D)None
E)Cannot be determined
Rationale: Solution:
1 Hour.
Suppose he takes the first tablet at 12:00 pm. Then the second will be consumed by him at 12:15, third at 12:30, fourth at 12:45 and fifth at 1:00.
Answer A
Answer: A
Question: Matt gets a $1,000 commission on a big sale. This commission alone raises his average commission by $150. If Matt's new average commission is $250, how many sales has Matt made?
Options:
A)3
B)4
C)5
D)6
E)7
Rationale: Let, Average Commission = x
No. of items sold = y
Total Commission = xy
New Commission = xy+1000
New Average = (xy+1000) / (y+1) = 150+x
i.e. (xy+1000) = (y+1)* (150+x)
i.e. (xy+1000) = (xy+x+150y+150)
i.e. (850) = (x+150y)
New Commission = 250 = 150+x
i.e. x=100
i.e. y = 5
New Sales = y+1 = 6
Answer: option D
Answer: D
Question: John started a business, investing 30000. Six months later, Marry joined him with 15000. If they make a profit of 10000 at the end of the year, what should be the share of John?
Options:
A)Rs.6000
B)Rs.6500
C)Rs.7000
D)Rs.7500
E)Rs.8000
Rationale: The ratio of their investments = 30000 × 12 : 15000 × 6 = 4 : 1.
:. John ’s share on profit of Rs.10000 = 10000 × 4/5 = Rs.8000.
E)
Answer: E
Question: What is the local value of 6 in the product of face value of 7 and local value of 8 in 7098060
Options:
A)60
B)600
C)6000
D)60000
E)6
Rationale: (Face value of 7) x (Local value of 8) = 7 x 8000 =56000
Local value of 6 in 56000 = 6000
C
Answer: C
Question: What is the probability that Jasmine and Trish will get selected for a job they both applied for in a company, given that their chances of getting selected is 3/5 and 2/7 respectively?
Options:
A)6/37
B)6/35
C)5/36
D)7/33
E)7/36
Rationale: Explanation:
P(Jasmine) = 3/5
P(Trish) = 2/7
P(E) = P(Jasmine)*P(Trish)
= 3/5 * 2/7
= 6/35
ANSWER: B
Answer: B
Question: Which of the following number is divisible by 24 ?
Options:
A)22
B)24
C)26
D)27
E)28
Rationale: 24 = 3 x8, where 3 and 8 co-prime.
Clearly, 35718 is not divisible by 8, as 718 is not divisible by 8.
Similarly, 63810 is not divisible by 8 and 537804 is not divisible by 8.
Consider option (D),
Sum of digits = (3 + 1 + 2 + 5 + 7 + 3 + 6) = 27, which is divisible by 3.
Also, 736 is divisible by 8.
3125736 is divisible by (3 x 8), i.e., 24.
B
Answer: B
Question: A man swims downstream 16 km and upstream 10 km taking 2 hours each time, what is the speed of the man in still water?
Options:
A)7.0
B)8.2
C)6.5
D)7
E)6
Rationale: 16--- 2 DS = 8
? ---- 1
10 ---- 2 US = 5
? ---- 1 M = ?
M = (8 + 5)/2 =6.5
Answer:C
Answer: C
Question: In a stack of boards at a lumber yard, the 20th board counting from the top of the stack is immediately below the 18th board counting from the bottom of the stack. How many boards are in the stack?
Options:
A)38
B)36
C)35
D)34
E)32
Rationale: Counting from the top, after the 20th board, there are 16 boards left to count.
The answer is B.
Answer: B
Question: A train is 360 meter long is running at a speed of 75 km/hour. In what time will it pass a bridge of 140 meter length?
Options:
A)87
B)69
C)40
D)72
E)24
Rationale: Speed = 75 Km/hr = 75*(5/18) m/sec = 125/6 m/sec
Total distance = 360+140 = 500 meter
Time = Distance/speed
= 500 * (6/125) = 24 seconds
Answer: E
Answer: E
Question: If X can run 48m and Y 42m, then in a race of 1km, X beats Y by:
Options:
A)125m
B)128m
C)121m
D)123m
E)127m
Rationale: Explanation:
When X runs 48m, Y runs 42m.
Hence, when X runs 1000m, Y runs (1000 * 42) / 48 = 875m
X beats Y by 125m.
ANSWER: A
Answer: A
Question: A train running at the speed of 60 km/hr crosses a pole in 3 seconds. Find the length of the train?
Options:
A)150 meter
B)170 meter
C)156 meter
D)168 meter
E)50 meter
Rationale: Speed = 60*(5/18) m/sec
= 50/3 m/sec
Length of Train (Distance)
= Speed * Time
(50/3) * 3
= 50 meter
Answer:E
Answer: E
Question: 75% of Ram's marks is equal to 20% of Rahim's marks which percent is equal to 30% of Robert's marks. If Robert's marks is 80, then find the average marks of Ram and Rahim?
Options:
A)70
B)97
C)87
D)90
E)76
Rationale: Given, 75% of Ram's marks = 20% of Rahim's marks = 30% of Robert's marks.
Given, marks of Robert = 80
30% of 80 = 30/100 * 8 = 24
Given, 75% of Ram's marks = 24.
=> Ram's marks = (24 * 100)/75 = 32
Also, 20% of Rahim's marks = 24
=> Rahim's marks = (24 * 100)/20 = 120
Average marks of Ram and Rahim = (32 + 120)/2 = 76.
Answer:E
Answer: E
Question: The ratio between the length and the breadth of a rectangular park is 3 : 2. If a man cycling along the boundary of the park at the speed of 12 km/hr completes one round in 5 minutes, then the area of the park (in sq. m) is:
Options:
A)153601
B)153600
C)153602
D)60000
E)153604
Rationale: Perimeter = Distance covered in 5 min. =(12000/60) x 5m = 1000 m.
Let length = 3x metres and breadth = 2x metres.
Then, 2(3x + 2x) = 1000 or x = 100.
Length = 300 m and Breadth = 200 m.
Area = (300 x 200) m2 = 60000 m2.
Answer: D
Answer: D
Question: A train 800 m long can cross an electric pole in 20 sec and then find the speed of the train?
Options:
A)72
B)67
C)28
D)26
E)144
Rationale: Length = Speed * time
Speed = L/T
S = 800/20
S = 40 M/Sec
Speed= 40*18/5 (To convert M/Sec in to Kmph multiply by 18/5)
Speed = 144 Kmph
Answer:E
Answer: E
Question: Suhas sold an item for Rs.7500 and incurred a loss of 25%. At what price, should he have sold the item to have gained a profit of 25%?
Options:
A)Rs.13800
B)Rs.12500
C)Rs.11200
D)Cannot be determined
E)None of these
Rationale: Explanation:
255 loss means that Rs.7500 is 75% of CP.
Therefore, CP = 7500x100/75 = Rs.10000.
25% of Rs.10000 = Rs.2500.
To get a gain of 25%, the SP should be = Rs.10000+2500 = Rs.12500
Answer: Option B
Answer: B
Question: A sum of money lent out at S.I. amounts to Rs. 820 after 2 years and to Rs. 1020 after a further period of 4 years. The sum is?
Options:
A)s.440
B)s. 500
C)s. 720
D)s. 740
E)s. 840
Rationale: S.I for 5 years = (1020 - 820) = Rs. 200.
S.I. for 2 years = 200/4 * 2 = Rs. 100.
Principal = (820 - 100) = Rs. 720.
ANSWER:C
Answer: C
Question: If n is a positive integer and 10!=25×7×81×2n10!=25×7×81×2n, what is the value of n?
Options:
A)2
B)4
C)5
D)8
E)10
Rationale: The question simply asks to find the highest power of 2 which divides 10!
So, we need to find the maximum power of 2 as below -
10/2 =5
5/2 = 2
2/1 = 1
Total Powers of 2 is 5+2+1 =8
Answer is definitely (D)
ANSWER:D
Answer: D
Question: A store owner is packing small radios into larger boxes that measure 25 in. by 42 in. by 60 in. If the measurement of each radio is 7 in. by 6 in. by 5 in., then how many radios can be placed in the box?
Options:
A)300
B)325
C)400
D)420
E)480
Rationale: No of radios that can be placed in the box = (25*42*60)/(7*6*5)=300
ANSWER:A
Answer: A
Question: The water from one outlet, flowing at a constant rate, can fill a swimming pool in 6 hours. The water from a second outlet, flowing at a constant rate, can fill the same pool in 2 hours. If both outlets are used at the same time, approximately what is the number of hours required to fill the pool?
Options:
A) 1.5
B) 1.9
C) 2.50
D) 3.21
E) 4.56
Rationale: Always remember RT=W i.e Rate*Time = Work
Also remember that rate can be added or subtracted. For e.g if A do a work in 2 day and B do a work in 2 day.
They both of them together will do a work in 1 day.
So now your question first determine both outlets rate.
1st outlet rate = 1/6 (R=W/T here W=1 work, T = 6hrs)
2nd outlet rate = 1/2 (R=W/T here W=1 work, T = 2hrs)
Both of them working together rate = 1st outlet rate + 2nd outlet rate = 1/6+1/2 = 4/6=2/3
again apply the formula RT=W
T = W/R = 1/2/3 = 3/2 =1.5
Answer is A.
Answer: A
Question: In a class of 120 students numbered 1 to 120, all even numbered students opt for Physics, whose numbers are divisible by 5 opt for Chemistry and those whose numbers are divisible by 7 opt for Math. How many opt for none of the three subjects?
Options:
A)19
B)41
C)21
D)26
E)25
Rationale: Number of students who took at least one of the three subjects can be found by finding out A U B U C, where A is the set of those who took Physics, B the set of those who took Chemistry and C the set of those who opted for Math.
Now, AUBUC = A + B + C - (A n B + B n C + C n A) + (A n B n C)
A is the set of those who opted for Physics = 120/2 = 60 students
B is the set of those who opted for Chemistry = 120/5 = 24
C is the set of those who opted for Math = 120/7 = 17.
The 10th, 20th, 30th…… numbered students would have opted for both Physics and Chemistry.
Therefore, A n B = 120/10 = 12
The 14th, 28th, 42nd…. Numbered students would have opted for Physics and Math.
Therefore, C n A = 120/14 = 8
The 35th, 70th …. Numbered students would have opted for Chemistry and Math.
Therefore, A n B = 120/35 = 3
And the 70th numbered student would have opted for all three subjects.
Therefore, AUBUC = 60 + 24 + 17 - (12 + 8 + 3) + 1 = 79.
Number of students who opted for none of the three subjects = 120 - 79 = 41.
ANSWER:B
Answer: B
Question: The probability that a convenience store has no iced tea is 60%. If Karl is stopping by 2 convenience stores on his way to work, what is the probability that at least one of the stores will not have a can of iced tea?
Options:
A)1/8
B)1/4
C)1/2
D)3/4
E)16/25
Rationale: p=1-3/5^32(all stores have iced tea)=16/25
E
Answer: E
Question: At Scratch and Dents Rent-a-Car, it costs $34.95 a day plus $0.23 per mile to rent a car. At Rent-a-Lemon, the charge is $25.00 a day plus $1.31 per mile. If you need to rent a car for three days, how many miles (to nearest tenth) must you drive for a car from both agencies to cost the same amount?
Options:
A)25.7 Miles
B)26.2 Miles
C)27.6 Miles
D)27.9 Miles
E)29.9 Miles
Rationale: For SaD:
SaDDaily = $34.95/Day
SaDMile = $0.23/Mile
For RaL:
RaLDaily = $25.00/Day
RaLMile = $1.31/Mile
We want the RaLTotal = SaDTotal, so we get
(RaLDaily * Days) + (RalMile * Miles) = (SaDDaily * Days) + (SaDMile * Miles)
=> Miles = ( (SaDDaily * Days) - (RaLDaily * Days) ) / (RalMiles - SaDMiles) = ((SaDDaily - RaLDaily )* Days) / (RalMiles - SaDMiles)
Miles = (( $34.95 * 3 ) - ( $25.00 * 3 ))/($1.31 - $0.23) = 27.6 Miles
C. 27.6 Miles
Answer: C
Question: What is the largest 4 digit number exactly divisible by 88?
Options:
A)9944
B)9999
C)9988
D)9900
E)None of these
Rationale: Explanation :
Largest 4 digit number = 9999
9999 ÷ 88 = 113, remainder = 55
Hence largest 4 digit number exactly divisible by 88 = 9999 - 55 = 9944. Answer : Option A
Answer: A
Question: A worker's take-home pay last year was the same each month, and she saved the same fraction of her take-home pay each month. The total amount of money that she had saved at the end of the year was 2 times the amount of that portion of her monthly take-home pay that she did NOT save. If all the money that she saved last year was from her take-home pay, what fraction of her take-home pay did she save each month?
Options:
A)1/7
B)1/6
C)1/5
D)1/4
E)1/3
Rationale: Let x be the fraction of her take-home pay that the worker saved.
Let P be the monthly pay.
12xP = 2(1-x)P
12xP = 2P - 2xP
14xP = 2P
x = 1/7
The answer is A.
Answer: A