divelab/Sys2Bench huggingface dataset:
Question: A certain bag contains 60 balls — 22 white, 10 green, 7 yellow, 15 red, and 6 purple. If a ball is to be chosen at random, what is the probability that the ball will be neither red nor purple?
Options:
A)0.09
B)0.65
C)0.54
D)0.85
E)0.91
Rationale: According to the stem the ball can be white, green or yellow, so the probability is (white + green + yellow)/(total) = (22 + 10 + 17)/60 = 39/60 = 0.65.
Answer: B.
Answer: B
Question: If Sharon's weekly salary increased by 16 percent, she would earn $348 per week. If instead, her weekly salary were to increase by 20 percent, how much would she earn per week?
Options:
A) $374
B) $382
C) $385
D) $360
E) $399
Rationale: (348/116)120 =360
In this case long division does not take much time.
(348/116)=3
3*120=360(300+60)
Answer D
Answer: D
Question: The ratio, by volume, of bleach to detergent to water in a certain solution is 2 : 40 : 100. The solution will be altered so that the ratio of bleach to detergent is tripled while the ratio of detergent to water is halved. If the altered solution will contain 200 liters of water, how many liters of detergent will it contain?
Options:
A)60
B)55
C)50
D)45
E)40
Rationale: B:D:W = 2:40:100
Bnew / Dnew = (1/3)*(2/40) = (1/60)
Dnew / Wnew = (1/2)*(40/100) = (1/5)
Wnew = 200
Dnew = Wnew/5 = 200/5 = 40
So, answer will be E
Answer: E
Question: If n is a positive integer, and n^2 has 25 factors, which of the following must be true.
1. n has 12 factors.
2. n > 50
3.√n is an integer.
Options:
A)1 and 2
B)2 only
C)3 only
D)2 and 3
E)none
Rationale: 25=1×25=5×5
So prime factorization of n^2 could be p^24 or p^4q^4 with p,q are distinct prime numbers.
Hence, n could be p^12 or p^2q^2
(1) If n=p12 then n has 12+1=13 different factors, so (1) is not true.
(2) If n=p^2q^2 , for example n=2^2×3^2=36<50n=22×32=36<50, so (2) is not true.
(3)
If n=p^12 ⟹√n=p^6 is an integer.
If n=p^2q^2 ⟹√n=pq is an integer.
So (3) is true.
Answer: C.
Answer: C
Question: Which number should replace both the asterisks in (* /21) x (*/84) = 1 ?
Options:
A)21
B)42
C)63
D)72
E)168
Rationale: Let (y/21) x (y/84) = 1
y^2 = 21 x 84 = 21 x 21 x 4
y = (21 x 2) = 42
The answer is B.
Answer: B
Question: 1600 men have provisions for 28 days in the temple. If after 4 days, 400 men leave the temple, how long will the food last now?
Options:
A)34 days
B)54 days
C)32 days
D)76 days
E)76 days
Rationale: 1600 ---- 28 days
1600 ---- 24
1200 ---- ?
1600*24 = 1200*x
x = 32 days
Answer:C
Answer: C
Question: In how many ways can six members be selected from a group of ten members?
Options:
A)10C6
B)10C8
C)10C4
D)10C3
E)10C1
Rationale: Six members can be selected from ten members in
10C6
= 10C4 ways.
Answer: B
Answer: B
Question: The value of 3.6x0.48x2.50 / 0.12x0.09x0.5 is
Options:
A)80
B)800
C)8000
D)80000
E)None of these
Rationale: Solution
Therefore	=3.6x0.48x2.50/0.12x0.09x0.5
= 36x48x250/12x9x5
= 800
Answer B
Answer: B
Question: If W is the set of all the integers between 49 and 114, inclusive, that are either multiples of 3 or multiples of 2 or multiples of both, then W contains how many numbers?
Options:
A)34
B)44
C)45
D)55
E)72
Rationale: Official Solution:
Number of multiples of 3
Step 1. Subtract the extreme multiples of 3 within the range (The greatest is 114, the smallest is 51): 114 - 51 = 63
Step 2. Divide by 3: 63 / 3 = 21
Step 3. Add 1: 21 + 1 = 22.
So there are 22 multiples of 3 within the range: examples are 51, 54, 57, 60, etc.
Number of multiples of 2
Step 1. Subtract the extreme multiples of 2 within the range (The greatest is 114, the smallest is 50): 114 - 50 = 64
Step 2. Divide by 2: 64 / 2 = 32
Step 3. Add 1: 32 + 1 = 33.
So there are 33 multiples of 2 within the range: examples are 50, 52, 54, 56, 58, 60 etc.
Add the 22 multiples of 3 and the 33 multiples of 2: 22+33=55.However, by adding the multiples of 2 and the multiples of 3, we are effectively counting several numbers twice: for example, 54 and 60 are parts of both the lists above. So we can't just take 22+33=55. Find the Number of multiples of 6 (which are the double counted, as 6 is divisible by both 2 and 3), and subtract it from 55:
Step 1. Subtract the extreme multiples of 6 within the range (The greatest is 72, the smallest is 54): 114 - 54 = 60
Step 2. Divide by 6: 60 / 6 = 10
Step 3. Add 1: 10 + 1 = 11.
So there are 11 multiples of 6 within the range: we counted 11 numbers twice.
Subtract the 11 multiples of 6 from the sum of the multiples of 2 and 3:
= 22+33 - 11
= 55 - 11
= 44
Therefore, the final number of multiples of 2, 3 or 6 is 44.
Hence, this is the correct answer. (B)
Answer: B
Question: A can do a piece of work in 6days of 9 hours each and B alone can do it in 12 days of 9 hours each.how long will they take it to do working together
4 1/2 hours a day?
Options:
A)8 days
B)9 days
C)7 days
D)6 days
E)10 days
Rationale: A's work per hour=1/54
B's work per hour=1/108
A & B's work per hour together=(1/54)+(1/108)=3/108=1/36
so A & B together complete the work in 36 hours...
if they work 4 1/2=9/2 hours a day,
it will take (36)/(9/2) days=8 days...
ANSWER: A
Answer: A
Question: In order to obtain an income of Rs. 1000 from 50% stock at Rs. 500, one must make an investment of
Options:
A)Rs.17000
B)Rs.16050
C)Rs.15400
D)Rs.10000
E)Rs.10500
Rationale: Explanation :
Market Value = Rs.500.
Required Income = Rs. 1000.
Here face value is not given. Take face value as Rs.100 if it is not given in the question
To obtain Rs.50 (ie,50% of the face value 100), investment = Rs.500
To obtain Rs.1000, investment = 500/50Ã—1000=10000
Answer : Option D
Answer: D
Question: If 6th March, 2017 is Sunday, what was the day of the week on 6th March, 2016?
Options:
A)Sunday
B)Saturday
C)Tuesday
D)Wednesday
E)None of these
Rationale: Solution
The year 2016 is a leap year. So, it has 2 odd days.
But, Feb 2016 not included because we are calculating from March 2016 to March 2017. So it has 1 odd day only.
The day on 6th March, 2017 will be 1 day beyond the day on 6th March, 2016. Given that, 6th March, 2017 is Sunday.
6th March, 2016 is Saturday (1 day before to 6th March, 2017)
Answer B
Answer: B
Question: A sum of Rs.48000 is invested at a compound interest for three years, the rate of interest being 10% p.a., 20% p.a. and 25% p.a. for the 1st, 2nd and the 3rd years respectively. Find the interest received at the end of the three years.
Options:
A)28880
B)31200
C)28770
D)29990
E)12770
Rationale: Let A be the amount received at the end of the three years.
A = 48000[1 + 10/100][1 + 20/100][1 + 25/100]
A = (48000 * 11 * 6 * 5)/(10 * 5 * 4)
A = Rs.79200
So the interest = 79200 - 48000 = Rs.31200
Answer: B
Answer: B
Question: Linda spent 3/4 of her savings on furniture and the rest on a TV. If the TV cost her $150, what were her original savings?
Options:
A)$500
B)$600
C)$700
D)$800
E)$900
Rationale: If Linda spent 3/4 of her savings on furniture, the rest
4 / 4 - 3 / 4 = 1 / 4 on a TV
But the TV cost her $150. So 1 / 4 of her savings is $150. So her original savings are 4 times $150 = $600
correct answer B
Answer: B
Question: Two spherical balls lie on the ground touching. If one of the balls has a radius of 7 cm, and the point of contact is 10 cm above the ground, what is the radius of the other ball (in centimeters)?
Options:
A)30/7
B)50/3
C)70/4
D)80/5
E)90/8
Rationale: A straight line will join the two centers and the point of contact, thus making similar triangles.
3/7 = (r-10)/r
3r = 7r - 70
r = 70/4
The answer is C.
Answer: C
Question: In measuring the sides of a rectangle, one side is taken 4% in excess, and the other 3% in deficit. Find the error percent in the area calculated from these measurements.
Options:
A)0.11%
B)0.7%
C)0.4%
D)0.6%
E)0.88%
Rationale: Let x and y be the sides of the rectangle. Then, Correct area = xy.
Calculated area = (26/25) x (32/33) y = (344/341 )(xy)
Error In measurement = (344/341)xy- xy = (3/341)xy
Error percentage = [(3/341)xy (1/xy)100] % = (22/25) % = 0.88%.
Answer is E.
Answer: E
Question: In a basketball game, Dhoni scored 15 points more than Dravid, but only half as many points as Shewag. If the three players scored a combined total of 77 points, how many points did Dhoni score?
Options:
A)23
B)33
C)25
D)28
E)32
Rationale: Let Dravid scored point = x
Then Dhoni Scored = x+15
Shewag Scored = 2*(x+15) = 2x+30
As given, x+x+15+2x+30 = 77 points
4x+45 = 77
x = 77-45/4 = 8
So Dhoni Scored = x +15 i.e) 8+15 = 23
Answer : A
Answer: A
Question: A park square in shape has a 3 metre wide road inside it running along its sides. The area occupied by the road is 1764 square metres. What is the perimeter along the outer edge of the road?
Options:
A)576 metres
B)589 metres
C)600 metres
D)700 metres
E)None
Rationale: Solution
Let the length of the outer edges be x metres.
Then, length of the inner edge = ( x - 6)m.
∴ x2 - (x-6)2 = 1764
‹=› x2-(x2-12x+36)= 1764
‹=›12x = 1800
‹=›x = 150.
∴ Required perimeter = (4x)m
‹=› (4 x 150)m = 600m.
Answer C
Answer: C
Question: A man sells a horse for Rs.800 and loses something, if he had sold it for Rs.980, his gain would have been double the former loss. Find the cost price of the horse?
Options:
A)228
B)277
C)299
D)860
E)223
Rationale: CP = SP + 1CP = SP - g
800 + x = 980 - 2x
3x = 180 => x = 60
CP = 800 + 60 = 860
Answer:D
Answer: D
Question: Integer x is equal to the product of all even numbers from 2 to 60, inclusive. If V is the smallest prime number that is also a factor of x-1, then which of the following expressions must be true?
Options:
A) 0<y<4
B) 4<y<10
C) 10<y<20
D) 20<y<30
E) y>30
Rationale: V Smallest prime factor is greater than 29. So answer is E
Answer: E
Question: S is a set containing 10 different positive odd primes. T is a set containing 8 different numbers, all of which are members of S. Which of the following statements CANNOT be true?
Options:
A) The median of S is prime.
B) The median of T is prime
C) The median of S is equal to the median of T.
D) The sum of the terms in S is prime.
E) The sum of the terms in T is prime.
Rationale: Here is my explanation. The question states:S is a set containing 9 different positive odd primes. T is a set containing 8 different numbers, all of which are members of S. Which of the following statements CANNOT be true?
(A) The median of S is prime.
Thismust be true. If there are an odd number of members of a set, then the median is a member of the set: it's the middle number, when all the numbers are ranked from smallest to biggest. Every number in S is a positive odd prime, so the median is one of them, and is prime.
(B) The median of T is prime.
Thismay or may not be true. If a set has an even number of members, the median is average of the two numbers in the middle, when ranked from smallest to biggest. The average of two odd numberscould beeven (average of 71 and 73 is 72), and hence not prime, or itcould beodd (the average of 71 and 79 is 75). For particularly well chosen odd numbers, the average can be not only odd but also prime -- for example, the average of 89 and 113 is 101, another prime number. If the two middle numbers of T were 89 and 113, the median would be 101, a prime number.
(C) The median of S is equal to the median of T.
Under most configurations for S and T, this wouldn't happen. If you weren't trying to make it happen, it would be unlikely to happen by chance. BUT, if the number dropped going from from S to T was the median of S (say, 101), and if the two middle numbers of T happen to have an average of that number that was dropped (for example, if the two numbers were 89 and 113), then the medians would be equal. In other words, the three middle numbers of S would have to be {. . ., 89, 101, 133, . . .}, and when 101 is dropped in going to T, the median of two would be the average of 89113, which happens to be 101. It's an exceptional case, but itcouldbe true.
(D) The sum of the terms in S is prime.
Thismay or may not be true. The sum of 9 odd numbermustbe an odd number. That odd numbercould beprime. For example, the sum of the first nine odd prime numbers {3, 5, 11, 13, 17, 19, 23, 29} is 127, which is prime. If you drop 3 and include the next prime, 31, the set {5, 11, 13, 17, 19, 23, 29, 31} has a sum of 155, which is clearly not prime.
(E) The sum of the terms in T is prime.
Thismust be false. The sum of eight odd numbers must be an even number. Only 2 is prime, and all other even numbers are not. Therefore, the sum of eight odd prime numbers will be an even number bigger than two, and absolutely cannot be prime.
E
Answer: E
Question: If x > y and y > z, which of the following represents the greatest number R?
Options:
A) x − z
B) x − y
C) y − x
D) z − y
E) z − x
Rationale: Because x>y>z
thus R=x- z wil lbe greatest
Ans: A
Answer: A
Question: Twenty times a positive integer is less than its square by 96. What is the integer?
Options:
A)24
B)20
C)30
D)Cannot be determined
E)None of these
Rationale: Let the positive integer be x.
Now, x2 – 20x = 96
or, x2 – 20x – 96 = 0
or, x2 – 24x + 4x – 96 = 0
or, x(x – 24) + 4(x – 24) = 0
or, (x – 24)(x + 4) = 0
or, x = 24, – 4
x ≠ –4 because x is a positive integer
Answer A
Answer: A
Question: A merchant who marked his goods up by 50% subsequently offered a discount of 20% on the marked price. What is the percentage profit that the merchant made after offering the discount?
Options:
A)30%
B)125%
C)25%
D)20%
E)16.66%
Rationale: Explanatory Answer
The easiest way to solve these kinds of problems is to assume a value for the merchant's cost price.
To make calculations easy, it is best to assume the cost price to be $100.
The merchant marks his goods up by 50%.
Therefore, his marked price (quoted price) = cost price + mark up.
Marked price = $100 + 50% of $100 = 100 + 50 = $150.
The merchant offers a discount of 20% on his marked price.
Discount offered = 20% of 150 = $30.
Therefore, he finally sold his goods for $150 - $30 = $ 120.
We assumed his cost to be $100 and he sold it finally for $120.
Therefore, his profit = $20 on his cost of $ 100.
Hence, his % profit = profit/cost price * 100 = 20/100 * 100 = 20%.
Choice D
Answer: D
Question: The average age of students of a class is 15.8 years. The average age of boys in the class is 16.4 years and that of the girls is 15.4 years. The ration of the number of boys to the number of girls in the class is:
Options:
A)2:5
B)2:3
C)2:4
D)2:1
E)2:9
Rationale: Let the ratio be k : 1. Then,
k * 16.4 + 1 * 15.4 = (k + 1) * 15.8
= (16.4 - 15.8)k = (15.8 - 15.4)
= k = 0.4/0.6 = 2/3
Required ratio = 2/3 : 1 = 2:3.
Answer:B
Answer: B
Question: If s, t and r are positive integers greater than 1, and s and t are factors of r, which of the following must be the factor of r^(st)?
I. s+t
II. t^s
III. s^2 * t^2
Options:
A)I only
B)II only
C)III only
D)I and II
E)II and III
Rationale: given that s and t are factors of r.
so we can picture it this way r=s*t*n (n-some another factor of r)
so, r^st= (s*t*n)^st
I. s+t .since the question is MUST BE TRUE, we eleminate this option
II. (s*t*n)^st / t^s= integer YES!
III.(s*t*n)^st/ s^2 * t^2 YEs, since we are said that integer s>1 and integer t>1
Answer: E
Question: Suppose you have three identical prisms with congruent equilateral triangles as the end-polygons. Suppose you attach them by the rectangular faces so they are perfectly aligned. There will be some large faces created by two or more co-planar faces of the individual prisms: count each such large face as one. Given that, how many faces does the resultant solid have?
Options:
A)4
B)6
C)9
D)10
E)12
Rationale: The top and the bottom are each single faces formed by three equilateral triangles joining, as in the diagram on the left, to make an isosceles trapezoid. Top = 1 face, and bottom = 1 face. This is a four-sided figure, so there are four rectangles extending from the bottom of this prism to the congruent figure at the top. Notice, in particular, the larger vertical face in the “back” of the diagram to the right is formed by two faces of the original triangular prisms lying next to each other and smoothly joining. Total = 1 top + 1 bottom + 4 sides = 6 faces. Answer = B.
Answer: B
Question: 1, 9, 25, 49, 81, ?
Options:
A)100
B)121
C)144
D)169
E)171
Rationale: The series consists of squares of consecutive prime numbers.
Answer : B.
Answer: B
Question: The price of a T.V. set worth Rs. 20000 is to be paid in 20 installments of Rs. 1000 each. If the rate of interest be 6% per annum, and the first installment be paid at the time of purchase, then the value of the last installment covering the interest as well will be?
Options:
A)19002
B)19028
C)27788
D)19000
E)27711
Rationale: Money paid in cash = Rs. 1000
Balance payment = (20000 - 1000) = Rs. 19000
Answer: D
Answer: D
Question: A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If three marbles are picked at random, what is the probability that they are all blue?
Options:
A)1/455
B)1/417
C)1/418
D)1/420
E)1/428
Rationale: Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles.
Probability that all the three marbles picked at random are blue
= ³C₃/¹⁵C₃
= (1 * 3 * 2 * 1)/(15 * 14 * 13)
= 1/455
Answer: A
Answer: A
Question: A rectangular lawn of dimensions 80 m * 50 m has two roads each 10 m wide running in the middle of the lawn, one parallel to the length and the other parallel to the breadth. What is the cost of traveling the two roads at Rs.3 per sq m?
Options:
A)A)3820
B)B)930
C)C)9309
D)D)3600
E)E)8302
Rationale: Explanation:
Area = (l + b – d) d
(80 + 50 – 10)10 => 1200 m2
1200 * 3 = Rs.3600
Answer: Option D
Answer: D
Question: Concentrated lime juice comes inside a cylinder tube with a radius of 2.5 inches and a height of 15 inches. The tubes are packed into wooden boxes, each with dimensions of 11 inches by 10 inches by 31 inches. How many tubes of concentrated lime juice, at the most, can fit into 3 wooden boxes?
Options:
A)24.
B)28.
C)36.
D)42.
E)48.
Rationale: Concentrated lime juice comes inside a cylinder tube since height of a tube is 15 inches , the tubes can fit only in one way .
now, diameter of each tube = 5 inches
therefore, 4*2 can be put in each wooden box
in 3 boxes 3*4*2 can be accommodated
= 24=A
Answer: A
Question: The telephone company wants to add an area code composed of 2 letters to every phone number. In order to do so, the company chose a special sign language containing 124 different signs. If the company used 122 of the signs fully and two remained unused, how many additional area codes can be created if the company uses all 124 signs?
Options:
A)246
B)248
C)492
D)15,128
E)30,256
Rationale: OK let's take a crack at this one.
So basically we have 144^2 - 142^2
So then (144+142)(144-142)
(246)(2) = 492
ANSWER:C
Answer: C
Question: A Bell Curve (Normal Distribution) has a mean of − 1 and a standard deviation of 1/8 . How many integer values O are within three standard deviations of the mean?
Options:
A)0
B)1
C)3
D)6
E)7
Rationale: Got the question correctly -- the second item -- [highlight] bthe list of elements in the set is required.[/highlight] is not required.
With the new information, there is only one integer value (-1) that is between (-1.375, -0.625) i.e., falls within the three 3 SD range.B
Answer: B
Question: In a recent election, Ms. Robinson received 8000 voters cast by independent voters, that is, voters not registered with a specific political party. She also received 50 percent of the votes cast by those voters registered with a political party. IF N is the total number of votes cast in the election and 40 percent of the votes cast were cast by independent voters, which of the following represents the number of votes that Mrs. Robbins received?
Options:
A) 0.06N+3200
B) 0.3N+8000
C) 0.4N+7200
D) 0.1N+8000
E) 0.06N+8000
Rationale: 40% of N are independent voters, hence 60% of N are not independent voters. From this group she received 50% votes so, 0.5*0.6*N plus 8,000 votes from independents: total=0.5*0.6*N+8,000=0.3*N+8,000.
Answer: B.
Answer: B
Question: There are 25 stations between Delhi and Chennai. How many second class tickets have to be printed, so that a passenger can travel from any station to any other station?
Options:
A)802
B)850
C)852
D)702
E)722
Rationale: The total number of stations = 27
From 27 stations we have to choose any two stations and the direction of travel (i.e., Delhi to Chennai is different from Chennai to Delhi) in 27P2 ways.
27P2= 27 * 26 = 702
ANSWER: D
Answer: D
Question: The current of a stream runs at the rate of 4 kmph. A boat goes 6 km and back to the starting point in 2 hours, then find the speed of the boat in still water?
Options:
A)7
B)9
C)8
D)65
E)2
Rationale: S = 4
M = x
DS = x + 4
US = x - 4
6/(x + 4) + 6/(x - 4) = 2
x = 8
Answer: C
Answer: C
Question: If the cost of x metres of wire is d rupees, then what is the cost of y metres of wire at the same rate?
Options:
A)Rs. (xd/y)
B)Rs. xd
C)Rs. (yd/x)
D)Rs. yd
E)none
Rationale: Explanation:
cost of x metres of wire = Rs.d
cost of 1 metre of wire = Rs.(d/x)
cost of y metre of wire = Rs.(y × d/x) = Rs. (yd/x)
Answer: Option C
Answer: C
Question: The area of a square garden is A square feet and the perimeter is p feet. If a=2p+15, what is the perimeter of the garden, in feet?
Options:
A)28
B)36
C)40
D)56
E)64
Rationale: Perimeter of square = P
Side of square = P/4
Area of Square = (P^2)/16 =A
Given that A = 2P + 15
(P^2)/16 = 2P + 15
P^2 = 32P +240
P^2 -32P -240 = 0
P^2 -40P + 6P -240 = 0
P(P-40)+6(P+40) = 0
(P-40)(P+6) = 0
P = 40 or- 6
Discarding negative value , P = 40
Answer is C
Answer: C
Question: When the positive integer A is divided by 9 and 7, the remainder is 3 and 4, respectively. When the positive integer B is divided by 9 and 7, the remainder is 3 and 4, respectively. Which of the following must be a factor of A-B?
Options:
A)35
B)48
C)54
D)63
E)72
Rationale: A = 9k+3 = 7j+4
B = 9m+3 = 7n+4
A-B = 9(k-m) = 7(j-n)
Thus A-B is a multiple of 9 and 7, so it is multiple of 63.
The answer is D.
Answer: D
Question: Shannon and Maxine work in the same building and leave work at the same time. Shannon lives due north of work and Maxine lives due south. The distance between Maxine's house and Shannon's house is 40 miles. If they both drive home at the rate 2R miles per hour, Maxine arrives home 40 minutes after Shannon. If Maxine rider her bike home at the rate of R per hour and Shannon still drives at a rate of 2R miles per hour, Shannon arrives home 2 hours before Maxine. How far does maxine live from work?
Options:
A)20
B)34
C)38
D)40
E)46
Rationale: Nice question +1
We have that X/24 - (60-X)/2R = 40
Also X/R - (60-X)/2R = 120
So we get that 2x - 60 = 80R
3x - 60 = 240R
Get rid of R
120 = 3x
x = 38
Hence answer is C
Answer: C
Question: By selling an article at Rs.800, a shopkeeper makes a profit of 25%. At what price should he sell the article so as to make a loss of 25%?
Options:
A)Rs.600
B)Rs.480
C)Rs.500
D)Rs.450
E)Rs.550
Rationale: SP = 800
Profit = 25%
CP = (SP)*[100/(100+P)]
= 800 * [100/125]
= 640
Loss = 25% = 25% of 640 = Rs.160
SP = CP - Loss = 640 - 160 = Rs.480
ANSWER:B
Answer: B
Question: Calculate the cost of u bags of fruits given that the cost of h bags of said fruit is r rupees?
Options:
A)Rs.(ur/h)
B)Rs.(r*h)
C)Rs.(ur*h)
D)Rs.(u/h)
E)Rs.(r/h)
Rationale: Cost of h bags = Rs. r.
Cost of 1 bag = Rs.	r/h
Cost of u bags = Rs.(r/h)* u= Rs.(ur/h)
Answer is A.
Answer: A
Question: In a garden, there are 10 rows and 12 columns of mango trees. The distance between the two trees is 2 metres and a distance of one metre is left from all sides of the boundary of the garden. The length of the garden is
Options:
A)20 m
B)22 m
C)24 m
D)26 m
E)28 m
Rationale: Explanation:
Each row contains 12 plants.
There are 11 gapes between the two corner trees (11 x 2) metres and 1 metre on each side is left.
Therefore Length = (22 + 2) m = 24 m.
Answer: C
Answer: C
Question: The ratio of white balls to black balls is 1:2.If 9 grey balls are added then the ratio of white:black:grey is 2:4:3.Find the number of black balls.
Options:
A)11
B)12
C)13
D)15
E)16
Rationale: If 9 grey balls added means, ratio of grey = 3 in all (i.e., 9/3 = 3)
Therefore, black balls = 3 *4 = 12
and the White balls = 3 *2 = 6
i.e., White = 6 ; Black = 12 ; Grey = 9
ANSWER:B
Answer: B