divelab/Sys2Bench huggingface dataset:
Question: How many bricks, each measuring 25 cm x 11.25 cm x 6 cm, will be needed to build a wall of 8 m x 6 m x 22.5 cm?
Options:
A)5600
B)6000
C)6400
D)7200
E)None
Rationale: Solution
Number of bricks = Volume of the wall/Volume of 1 brick
=(800x600x22.5 /25x11.25x6)
= 6400.
Answer C
Answer: C
Question: Ayesha's father was 42 years of age when she was born while her mother was 30 years old when her brother four years younger to her was born. What is the difference between the ages of her parents?
Options:
A)12 years
B)14 years
C)16 years
D)17 years
E)6 years
Rationale: Explanation:
Mother's age when Ayesha's brother was born = 30 years.
Father's age when Ayesha's brother was born = (42 + 4) = 46 years.
Required difference = (46 - 30) = 16 years.
Answer: Option C
Answer: C
Question: If a trader sold two cars each at Rs. 325475 and gains 13% on the first and loses 13% on the second, then his profit or loss percent on the whole is?
Options:
A)1.69%
B)1.74%
C)1.84%
D)1.47%
E)1.24%
Rationale: SP of each car is Rs. 325475, he gains 13% on first car and losses 13% on second car.
In this case, there will be loss and percentage of loss is given by
= [(profit%)(loss%)]/100
= (13)(13)/100 % = 1.69%
Answer:A
Answer: A
Question: The average weight of 48 students in a class is 52 kg. 5 of them whose average weight is 48 kg leave the class and other 5 students whose average weight is 54 kg join the class. What is the new average weight (in kg) of the class ?
Options:
A)51 1⁄3
B)52 5/8
C)52 1⁄8
D)43.42
E)None of these
Rationale: Total weight of 48 students
= 48 × 52 = 2496 kg
Total weight of 5 students who leave
= 5 × 48 = 240 kg
Total weight of 5 students who join
= 5 × 54 = 270 kg
Therefore, new total weight of 48 students
= 2496 – 240 + 270 = 2526
⇒ New average weight = 2526⁄48 = 52 5/8 kg
Answer B
Answer: B
Question: Mike took 5 mock tests before appearing for the GMAT. In each mock test he scored 8 points more than the previous mock test. If he scored 760 on the GMAT and his average score for the mocks and the GMAT was 726.67, what was the difference in the score of his last mock and his GMAT score?
Options:
A)24
B)30
C)40
D)50
E)60
Rationale: One way to do this would be weighted average method..
1) let the average of 5 mocks be x...
so take it as a mix of5 quantitites of xand1 quantity of 760resulting in an average of 726.67...
By alligation/weighted average..
the difference in 760 and 726.67 is 5/6 of difference of 760 and x..
760-726.67 = 5/6 * (760-x)
760-x= 33.33*6/5=40...
so x = 720..
the last of mock test will be 720+8+8=736...
so ans = 760-736=24
A
Answer: A
Question: If the sides of a triangle are 26 cm, 24 cm and 10 cm, what is its area?
Options:
A)120 cm2
B)187 cm2
C)178 cm2
D)189 cm2
E)176 cm2
Rationale: The triangle with sides 26 cm, 24 cm and 10 cm is right angled, where the hypotenuse is 26 cm.
Area of the triangle
= 1/2 * 24 * 10
= 120 cm2
Answer: A
Answer: A
Question: In a function they are distributing noble prize. In how many ways can 3 prizes be distributed among 4 boys when a boy gets any no. of prizes?
Options:
A)58
B)60
C)64 ways
D)68
E)90
Rationale: Ans.(C)
Sol. In this case, repetitions are allowed, so all the three prizes can be given in 4 ways, i.e. (4 x 4 x 4) ways = 43 ways = 64 ways Or nr ways = 43 ways = 64 ways
Answer: C
Question: The average time of Izzy's past 3 100-meter sprints is 15 seconds. If the average falls 1 second after Izzy finishes another sprint, how many seconds did it take Izzy to run the most recent sprint?
Options:
A)16
B)11
C)15
D)14
E)10
Rationale: Total time to run 3 sprints = 3*15 = 45
Total time to run 4 sprints = 4*14 = 56
Time to run most recent sprint = 56-45 = 11 seconds
Answer is B
Answer: B
Question: From a Group of 10 People, Including George and Nina, 3 people are to be selected at random to work on a certain project. What is the probability that 3 people selected will include George but not Nina
Options:
A)5/56
B)9/56
C)28/120
D)21/56
E)25/56
Rationale: Number of ways of selecting 3 people out of 10 people = 10C3
In the three members George will always be there in the team. At this step we have vacancy for 2 more members and 9 members are available. Lina cannot be there in the team. So 2 members have to be selected and the number of available members = 9 - Nina = 8
Number of ways to form a 3 member team that includes George and excludes Nina = 8C2
Probability = 8C2/10C3 = 28/120
Answer: C
Answer: C
Question: If a coin is tossed twice, what is the probability that on the first toss the coin lands heads and on the second toss the coin lands heads?
Options:
A)1/2
B)1/8
C)3/8
D)3/4
E)1/4
Rationale: Since there are two options for how a coin can land (heads or tails), that means there is a 1/2 chance to land on heads and a 1/2 chance to land tails. To solve this problem you multiply each probability for each flip together. (1/2) chance to land heads the first time * (1/2) chance to land heads the second time = (1/4) chance to land heads both times.
Answer: E
Answer: E
Question: What would be the missing number in the series: 1, 20, 266, 675,?
Options:
A)76
B)78
C)80
D)82
E)84
Rationale: 1,20,x,266,675
> 20-1,x-20,266-x,675-266.
>again doing the same upto
>325-3x, -143+3x.
>we get 6x-486 equate it with zero.
> 6x-486 = 0
>x = 78.
ANSWER:B
Answer: B
Question: If one of the followings is the product of the two 3-digit integers 8K7 and 6L7 (K and L denote the tens digit of the respective integers), then that product must be
Options:
A) 478,823
B) 511,913
C) 531,875
D) 538,424
E) 569,119
Rationale: To know the unit digit you can multiply both digit number: 7 x 7 = 49
This eliminates A,B,C and D because the number must end with a 9
So the answer is E
Answer: E
Question: What is difference between biggest and smallest fraction among 2/3, 3/4, 4/5 and 5/7
Options:
A)2/15
B)3/5
C)1/6
D)1/7
E)None of these
Rationale: Explanation:
2/3 = .66, 3/4 = .75, 4/5 = .8 and 5/7 = .71
So biggest is 4/5 and smallest is 2/3
Their difference is 4/5 - 2/3 = 2/15
Option A
Answer: A
Question: R = {2, 3, 4, 5}
B = {4, 5, 6, 7, 8}
Two integers will be randomly selected from the sets above, one integer from set R and one integer from set B. What is the probability that the sum of the two integers will equal 9 ?
Options:
A) 0.15
B) 0.20
C) 0.25
D) 0.30
E) 0.33
Rationale: The total number of pairs R,B possible is 4*5=20. Out of these 20 pairs only 4 sum up to 9: (2, 7); (3, 6), (4, 5) and (5, 4). The probability thus is 4/20=0.2.
Answer: B.
Answer: B
Question: An article is bought for Rs.705 and sold for Rs.900, find the gain percent?
Options:
A)27.65%
B)33 1/2%
C)33 1/3%
D)33 5/3%
E)35 1/3%
Rationale: 705 ---- 195
100 ---- ? => 27.65%
Answer:A
Answer: A
Question: Car A runs at the speed of 50 km/hr and reaches its destination in 8 hours. Car B runs at the speed of 65 km/h and reaches its destination in 4 hours. What is the ratio of distances covered by Car A and Car B?
Options:
A)3 : 7
B)4 : 9
C)20 : 13
D)5 : 7
E)6 : 11
Rationale: Car A travels 50 × 8 = 400 km
Car B travels 65 × 4 = 260 km
The ratio is 400 : 260 = 40 : 26 = 20 : 13
The answer is C.
Answer: C
Question: What is the 10th digit to the right of the decimal point in the decimal equivalent of 124/22?
Options:
A)2
B)3
C)4
D)7
E)6
Rationale: 124/22 = 5.6363....
63 is non-terminating repeating decimal.
The 10th digit to the right of decimal point will be 3.
Answer B
Answer: B
Question: Find a two digit number, given that the sum of the digits is 12 and the difference of the digits is 2.?
Options:
A)66
B)87
C)75
D)88
E)90
Rationale: Using elimination method find which of the options fit the description of the number
... from the option only 75 meets this description
sum of digits---7+5 = 12
difference of digits ---7-5 = 2
Answer C.
Answer: C
Question: The probability that event M will not occur is 0.8 and the probability that event R will not occur is 0.7. If events M and R cannot both occur, which of the following is the probability that either event M or event R will occur?
Options:
A)1/2
B)2/5
C)3/5
D)4/5
E)12/25
Rationale: p(m) =0.2
p(r) =0.3
p(m intersection r) = 0 (If events M and R cannot both occur)
p(m or r) = 0.2+0.3 =0.5
Corrected !!
Answer A
Answer: A
Question: In how many different ways can the letters of the word 'LEADING' be arranged in such a way that the vowels always come together?
Options:
A)360
B)480
C)720
D)5040
E)1020
Rationale: 5!*3!=720
ANSWER:C
Answer: C
Question: In how many different ways can the letters of the word 'RETAIL' be arranged such that the vowels must occupy only the odd positions?
Options:
A)None of these
B)64
C)120
D)360
E)36
Rationale: OEOEOE
3 vowels EAI can be arranged on odd places in 3!=6 ways. Similarly 3 consonants can be arranged on even places in 3!=6 ways.
Total = 6*6 = 36.
Answer: E.
Answer: E
Question: How many digits are required to number a book containing 220 pages?
Options:
A)674
B)604
C)552
D)372
E)250
Rationale: 9 pages from 1 to 9 will require 9 digits.
90 pages from 10 to 99 will require 90*2=180 digits.
220-(90+9)=121 pages will require 121*3=363 digits.
The total number of digits is 9+180+363=552.
The answer is C.
Answer: C
Question: The total marks obtained by a student in Mathematics and Physics is 60 and his score in Chemistry is 20 marks more than that in Physics. Find the average marks scored in Mathamatics and Chemistry together.
Options:
A)40
B)30
C)25
D)Data inadequate
E)None of these.
Rationale: Let the marks obtained by the student in Mathematics, Physics and Chemistry be M, P and C respectively.
Given , M + C = 60 and C - P = 20 M + C / 2 = [(M + P) + (C - P)] / 2 = (60 + 20) / 2 = 40.
ANSWER:A
Answer: A
Question: Pipe A can fill a tank in 8 hours, pipe B in 4 hours and pipe C in 24 hours. If all the pipes are open, in how many hours will the tank be filled?
Options:
A)1.9 hour
B)2.1 hour
C)4.7 hour
D)2.4 hour
E)3.2 hour
Rationale: Part filled by pipe A in 1 hour =1/8
Part filled by pipe B in 1 hour =1/4
Part filled by pipe C in 1 hour =1/24
Part filled by pipes A,B,C together in 1 hour=1/8+1/4+1/24=10/24
i.e, pipes A,B,C together can fill the tank in = 24/10 hr =2.4 hour.
ANSWER:D
Answer: D
Question: a is the hundreds digit of the three digit integer x, b is the tens digit of x, and c is the units digit of x. a = 4b = 2c, and a > 0.
What is the difference between the two greatest possible values of x?
Tip: Dont stop till you have exhausted all answer choices to arrive at the correct one.
Options:
A)124
B)297
C)421
D)412
E)842
Rationale: Ratio of a:b:c= 4:1:2
Two possible greatest single digit values for a are 8 and 4
if a is 8, then x= 824
if a is 4, then x= 412
difference= 824-412= 412
D is the answer
Answer: D
Question: The average age of 3 girls is 18 years and their ages are in the proportion 1:2:3. The age of the youngest girl is?
Options:
A)10 years
B)9 years
C)12 years
D)14 years
E)15 years
Rationale: Total age of 3 boys = 18*3 =54
ratio of their ages = 1:2:3
Age of the youngest = 54*1/6 = 9 years
Answer is B
Answer: B
Question: How much time will a train of length 200 m moving at a speed of 72 kmph take to cross another train of length 300 m, moving at 36 kmph in the same direction?
Options:
A)50 sec
B)17 sec
C)18 sec
D)10 sec
E)14 sec
Rationale: The distance to be covered = Sum of their lengths
= 200 + 300 = 500 m.
Relative speed = 72 -36 = 36 kmph
= 36 * 5/18 = 10 mps.
Time required = d/s
= 500/10 = 50 sec.
Answer: A
Answer: A
Question: Find large number from below question The difference of two numbers is 100. On dividing the larger number by the smaller, we get 9 as quotient and the 4 as remainder
Options:
A)120
B)100
C)112
D)150
E)105
Rationale: Let the smaller number be x. Then larger number = (x +100).
x +100 =9x + 4
8x = 96
x =12
Large number = 12+100 = 112
C
Answer: C
Question: A boatman can row 96 km downstream in 8 hr. If the speed of the current is 4 km/hr, then find in what time he will be able to cover 8 km upstream ?
Options:
A)3 hrs
B)7 hrs
C)9 hrs
D)2 hrs
E)6 hrs
Rationale: Explanation:
Speed in downstream = 96/8 = 12 kmph
Speed of current = 4 km/hr
Speed of the boatman in still water = 12 â€“ 4 = 8 kmph
Speed in upstream = 8 â€“ 4 = 4 kmph
Time taken to cover 8 km upstream = 8/4 = 2 hours.
Answer: D
Answer: D
Question: A sum of money placed at CI doubles itself in 5 years. It will amount to 8 times in?
Options:
A)17 years
B)19 years
C)14 years
D)16 years
E)15 years
Rationale: Explanation:2------>5 years4------>10years8------>15 years15 yearsAnswer: Option E
Answer: E
Question: If 40% of a number is equal to two-third of another number, what is the ratio of first number to the second number?
Options:
A)5:5
B)5:8
C)5:3
D)5:2
E)5:1
Rationale: Let 40% of A = 2/3 B. Then,
40A/100 = 2B/3 => 2A/5 = 2B/3
A/B = (2/3 * 5/2) = 5/3
A:B = 5:3.
Answer: C
Answer: C
Question: In a garden, trees are planted in 4 rows. In each row there are 4 trees. If each tree bears as many fruits as the number of trees in each row and if the total number of fruits from the trees in that garden is n, then :
Options:
A)n is a perfect square
B)n is an odd number
C)n is an even number
D)n is a perfect cube
E)none
Rationale: There are 4 rows in the garden, so there are 4 trees in each row and each tree bears 4 fruits. Then, the total number of fruits in the garden would be (4*4)*4= 64, which is a cube of 4.
ANSWER:D
Answer: D
Question: A baker sold twice as much bread in the afternoon than in the morning. If he sold 360 kilograms of bread that day, how many kilograms did he sell in the morning and how many in the afternoon?
Options:
A)180kg
B)240kg
C)470kg
D)641kg
E)559kg
Rationale: Let x be the number of kilograms he sold in the morning.Then in the afternoon he sold 2x kilograms. So, the total is x+2x=3x.This must be equal to 360.
3x=360
x=3603
x=120
Therefore, the salesman sold 120 kg in the morning and 2⋅120=240 kg in the afternoon.
correct answer is B)240kg
Answer: B
Question: A goods train runs at the speed of 72 kmph and crosses a 250 m long platform in 26 seconds. What is the length of the goods train?
Options:
A)230 m
B)240 m
C)260 m
D)270 m
E)None of these
Rationale: Explanation:
Speed =[ 72 x (5/18) ]m/sec= 20 m/sec.
Time = 26 sec.
Let the length of the train be x metres.
Then,[ (x+250)/26 ]= 20
=> x + 250 = 520
=> x = 270. Answer: D
Answer: D
Question: What sum of money will produce Rs.70 as simple interest in 4 years at 3 1/2 percent?
Options:
A)500
B)550
C)600
D)650
E)700
Rationale: 70 = (P*4*7/2)/100
P = 500
ANSWER A
Answer: A
Question: If you are provided that
(78)^9 = 6
And (69)^4 = 11
What will be the result of (89)^2 = ?
Options:
A)15
B)16
C)17
D)18
E)19
Rationale: Solution:
7 + 8 = 15 and 15 - 9 = 6
6 + 9 = 15 and 15 - 4 = 11
Therefore, (89)^2 will be:
8 + 9 = 17 and 17 - 2 = 15
Answer A
Answer: A
Question: Raghu went to a shop and bought things worth Rs. 22, out of which 30 Paise went on sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax free items?
Options:
A)16.7
B)20
C)22
D)21.4
E)21.5
Rationale: Total cost of the items he purchased = Rs.22
Given that out of this Rs.22, 30 Paise is given as tax
=> Total tax incurred = 30 Paise = Rs.30/100
Let the cost of the tax free items = x
Given that tax rate = 6%
∴ (22−30/100−x)6/100 = 30/100
⇒ 6(22 −0.3 −x) = 30
⇒ (22 − 0.3 − x) = 5
⇒ x = 22 − 0.3 − 5 = 16.7
A
Answer: A
Question: Look at this series: 22, 21, 23, 22, 24, 23, ... What number should come next?
Options:
A)36
B)27
C)41
D)19
E)25
Rationale: E
25
In this simple alternating subtraction and addition series; 1 is subtracted, then 2 is added, and so on.
Answer: E
Question: If a man walks at the rate of 5 kmph, he misses a train by 7 minutes. However, if he walks at the rate of 6 kmph, he reaches the station 5 minutes before the arrival of the train. Find the distance covered by him to reach the station.
Options:
A)10 km
B)8 km
C)6 km
D)4 km
E)9 km
Rationale: Let the required distance be x km
Difference in the time taken at two speeds=1 min =1/2 hr
Hence x/5-x/6=1/5<=>6x-5x=6
x=6
Hence, the required distance is 6 km
answer:Option C
Answer: C
Question: The difference between the place value and the face value of 8 in the numeral 856973 is
Options:
A)973
B)6973
C)5994
D)6084
E)None of these
Rationale: (Place value of 8) - (Face value of 8) = (800000 - 8) = 799992
Answer: Option E
Answer: E
Question: Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 9 hours and 16 hours respectively. The ratio of their speeds is?
Options:
A)4:5
B)4:3
C)4:4
D)4:9
E)4:2
Rationale: Let us name the trains A and B.
Then, (A's speed) : (B's speed)
= √b : √a = √16 : √9 = 4:3
Answer:B
Answer: B
Question: A boat takes 90 minutes less to travel 36 miles downstream than to travel the same distance upstream. If the speed of the boat in still water is 10 mph, the speed of the stream is:
Options:
A)4 mph
B)2.5 mph
C)3 mph
D)2 mph
E)None of these
Rationale: Explanation :
Speed of the boat in still water = 10 mph
Let speed of the stream be x mph
Then, speed downstream = (10+x) mph
speed upstream = (10-x) mph
Time taken to travel 36 miles upstream - Time taken to travel 36 miles downstream = 90/60 hours
=>36/(10−x) − 36/(10+x) = 3/2
=>12/(10−x) − 12/(10+x) = 1/2
=>24(10 + x) − 24(10 − x) = (10 + x)(10 − x)
=>240 + 24x − 240 + 24x = (100−x2)
=>48x = 100 − x2
=>x2 + 48x − 100 =0
=>(x+50)(x−2)=0
=> x = -50 or 2. Answer : Option D
Answer: D
Question: The present ages of three persons are in proportions 4:7:9. Seven years ago, the sum of their ages was 79. Find their present ages.
Options:
A)20, 28
B)28, 36
C)35, 45
D)35, 55
E)of these
Rationale: Let their present ages be 4x, 7x and 9x years respectively.
Then, (4x - 7) + (7x - 7) + (9x - 7) = 79
20x = 100 => x = 5
Their present ages are 20, 35 and 45 years respectively.
ANSWER:C
Answer: C
Question: A bag of blue and green colored marbles has 25% green marbles, with a total of 40 marbles. how many green marbles need to be added to bring their percentage in the bag up to 40%?
Options:
A)4
B)8
C)12
D)10
E)15
Rationale: A bag of 40 marbles which is 25% green marbles means we have 10 green marbles. To get a bag that is 40% green marbles, let's use this expression: (10 + x)/(40 + x) = 0.4 with x representing the amount of green marbles that must be added to get to 40%. The expression thus represents the new number of green marbles over the total new number of marbles in the bag and this fraction should equal 40%. only ten marbles need to be added, as 20/50=0.4 or 40%
choose D
Answer: D
Question: John can complete a given task in 20 days. Jane will take only 10 days to complete the same task. John and Jane set out to complete the task by beginning to work together. However, Jane was indisposed 5 days before the work got over. In how many days did the work get over from the time John and Jane started to work on it together?
Options:
A)8
B)10
C)12
D)16
E)20
Rationale: In such questions, you need to start from the end. Last 5 days John works alone and completes 5 * (1/20) = 1/4 of the work.
So 3/4 of the work should have been completed by the two of them together before Jane left.
Their combined rate of work is 1/20 + 1/10 = 3/20
Time taken to complete 3/4 of the work = (3/4)/(3/20) = 5 days.
So total number of days taken to complete the work = 5 + 5 = 10 days.
B
Answer: B
Question: By selling 90 pens, a trader gains the cost of 30 pens. Find his gain percentage?
Options:
A)33.3%
B)32.3%
C)31.3%
D)30.3%
E)29.3%
Rationale: Let the CP of each pen be Rs. 1.
CP of 90 pens = Rs. 90
Profit = Cost of 30 pens = Rs. 30
Profit% = 30/90 * 100 = 33.3%
Answer:A
Answer: A
Question: In how many ways can 5 arts and 3 science students be arranged in a row so that the arts and the science students are placed alternately?
Options:
A)2880
B)1850
C)326
D)720
E)360*120
Rationale: The five art students can be arranged in those 5 A-slots in 5! = 120 ways.
The three science students can be arranged in those 3 S-slots in 3! = 6 ways.
Total arrangements = 120*6 = 720
Answer =(D)
Answer: D
Question: What is the year next to 1990 which will have the same calendar as that of the year 1990?
Options:
A)1992
B)2001
C)1995
D)1996
E)None of these
Rationale: Explanation :
For a year to have the same calendar with 1990 ,total odd days from 1990 should be 0.
Take the year 1992 from the given choices.
Total odd days in the period 1990-1991= 2 normal years
≡ 2 x 1 = 2 odd days
Take the year 1995 from the given choices.
Number of odd days in the period 1990-1994 = 4 normal years + 1 leap year
≡ 4 x 1 + 1 x 2 = 6 odd days
Take the year 1996 from the given choices.
Number of odd days in the period 1990-1995= 5 normal years + 1 leap year
≡ 5 x 1 + 1 x 2 = 7 odd days ≡ 0 odd days
(As we can reduce multiples of 7 from odd days which will not change anything)
Though number of odd days in the period 1990-1995 is 0, there is a catch here.
1990 is not a leap year whereas 1996 is a leap year.
Hence calendar for 1990 and 1996 will never be the same.
Take the year 2001 from the given choices.
Number of odd days in the period 1990-2000= 8 normal years + 3 leap years
≡ 8 x 1 + 3 x 2 = 14 odd days ≡ 0 odd days
Also, both 1990 and 2001 are normal years.
Hence 1990 will have the same calendar as that of 2001
Answer : Option B
Answer: B
Question: The average of 5 consecutive integers starting with m as the first integer is n. What is the average of 11 consecutive integers that start with (m + 2)?
Options:
A)m + 4
B)n + 6
C)n + 3
D)n + 5
E)n + 4
Rationale: The average of consecutive numbers is the middle number.
Then n = m+2.
The average of 11 consecutive numbers starting from n is n+5.
The answer is D.
Answer: D
Question: Arun and Tarun can do a work in 10 days.After 4 days tarun went to his village.How many days are required to complete the remaining work by Arun alone.Arun can do the work alone in 40 days.
Options:
A)16 days.
B)17 days.
C)18 days.
D)19 days.
E)24 days.
Rationale: They together completed 4/10 work in 4 days.
balance 6/10 work will be completed by Arun alone in 40*6/10 = 24 days.
ANSWER:E
Answer: E
Question: A train 110 m long is running with a speed of 40 km/hr. In what time will it pass a man who is running at 5 km/hr in the direction opposite to that in which the train is going?
Options:
A)5
B)6
C)7.5
D)8.8
E)9
Rationale: Speed of train relative to man = 40 + 5 = 45 km/hr.
= 45 * 5/18 = 25/2 m/sec.
Time taken to pass the men = 110 * 2/25= 8.8 sec.
Answer: Option D
Answer: D
Question: If a man lost 10% by selling oranges at the rate of 12 a rupee at how many a rupee must he sell them to gain 44%?
Options:
A)6.5
B)7.5
C)7
D)8
E)2
Rationale: 90% ---- 12
144% ---- ?
90/144 * 12 = 7.50
Answer: B
Answer: B
Question: What is the probability that Abel and Bob will get selected for a job they both applied for in a company, given that their chances of getting selected is 1/5 and 2/3 respectively?
Options:
A)2/15
B)2/11
C)2/17
D)2/13
E)2/19
Rationale: Explanation:
P(Abel) = 1/5
P(Bob) = 2/3
E = {Jamie and Tom both get selected}
P(E) = P(Abel)*P(Bob)
= 1/5 * 2/3
= 2/15
ANSWER: A
Answer: A
Question: If the average of 10x and 8y is greater than 70, and x is twice y, what is the least integer value of x ?
Options:
A)12
B)14
C)16
D)10
E)20
Rationale: Substitution can be used in the following way:
Always start with the equation: x = 2y. It is more straight forward to manage as compared to the inequality.
Substitute y = x/2, not the other way because you need to find the minimum value of x. So you can get rid of y.
Now go on to the inequality. So 8y = 8x/2 = 4x
Now average of 10x and 4x is greater than 70. Average of 10x and 4x is 7x. So,
7x > 70
x > 10
Answer : D
Answer: D
Question: Gary had an average score of 70 on his first four quizzes. He had an
average score of 75 on his first five quizzes. What score did he receive on
his fifth quiz?
Options:
A)90
B)95
C)65
D)42
E)43
Rationale: The sum of Gary's first 4 scores is 4 Â· 70 and the sum of his first 5 scores is 5 Â· 75, so he received
5 Â· 75 âˆ’ 4 Â· 70 on his 5th quiz. You can do the arithmetic or note that the answer ends in a 5 and eliminate answer C because it is lower than the average. The correct answer is B.
Answer: B
Question: A is half good a work man as B and together they finish a job in 10 days. In how many days working alone B finish the job?
Options:
A)23
B)22
C)15
D)36
E)48
Rationale: C
15
WC = 1:2
2x + x = 1/10 => x = 1/30
2x = 1/15 => 15 days
Answer: C