divelab/Sys2Bench huggingface dataset:
Question: If x = (y)(y + 1) and y is a prime number less than 8, which of the following could not be the product of 2 consecutive integers?
Options:
A)a) 5x
B)b) 11x
C)c) 13x
D)d) 57x
E)e) 21x
Rationale: Given y is a prime number less than 11
possible values of y are 2 3 5 7
given, x=y*(y+1)
if y = 2 x=2*3=6
if y = 3 x=3*4=12
if y = 5 x=5*6=30
if y = 7 x=7*8=56
so possible values of x are 6,12,30,56
So from options
A. 5x can be (5*6)
B. 11x can be (11*12)
C. 13x can be (13*12)
D. 57x can be (56*57)
E. 21x cannot be
So answer option E
Answer: E
Question: A certain telephone company offers two plans, A and B. Under plan A, the company charges a total of $0.60 for the first 4 minutes of each call and $0.06 per minute thereafter. Under plan B, the company charges $0.08 per minute of each call. What is the duration of a call, in minutes, for which the company charges the same amount under plan A and under plan B?
Options:
A)2
B)9
C)15
D)18
E)30
Rationale: Let the duration, in minutes, for which the company charges the same under plan A and plan B be t minutes.
Then under plan A the cost would be $0.6+0.06(t-4) and under plan B the cost would be $0.08t. We want these amount to be equal: 0.6+0.06(t-4)=0.08t --> 60+6(t-4)=8t --> t=18.
Answer: D.
Answer: D
Question: There are two sections P and Q of a class, consisting of 144 and 176 students respectively. If the average weight of sections A is 160 kg and that of sections Q is 140 kg. Find the average weight of the whole class
Options:
A)147.5
B)148.0
C)148.5
D)149.0
E)None
Rationale: Solution
Total weight of(144+176)Students	= (144x160+176x140)Kg
= 47680 kg.
Average weight of the whole class	= (47680 / 320)
= 149.00.
Answer D
Answer: D
Question: A trader bought a car at 20% discount on its original price. He sold it at a 45% increase on the price he bought it. What percent of profit did he make on the original price?
Options:
A)17%
B)72%
C)12%
D)82%
E)16%
Rationale: Original price = 100
CP = 80
S = 80*(145/100) = 116
100 - 116 = 16%
Answer:E
Answer: E
Question: Pipe P can drain the liquid from a tank in 2/4 the time that it takes pipe Q to drain it and in 2/3 the time that it takes pipe R to do it. If all 3 pipes operating simultaneously but independently are used to drain liquid from the tank, then pipe Q drains what portion of the liquid from the tank?
Options:
A)3/13
B)8/23
C)3/8
D)17/29
E)3/4
Rationale: Suppose Q can drain in 1 hr. So, rQ = 1/1 = 1
So, rP = 1/[(2/4)rQ] = 4/2
Also, rP = rR/(2/3) => 2 = rR/(2/3) => rR = 4/3
Let H is the time it takes to drain by running all 3 pipes simultaneously
So combined rate = rC = 1/H = 1 + 2 + 4/3 = 13/3 = 1/(3/13)
Thus running simultaneously, Pipe Q will drain 3/13 of the liquid.
Thus answer = A.
Answer: A
Question: On a certain island, 5% of the 10000 inhabitants are one-legged and half of the others go barefooted. What is the least number of Shoes needed in the island?
Options:
A)10200
B)10000
C)9500
D)9000
E)None
Rationale: Explanation :
=> One-legged =5% of 10000=500
=> Remaining=10000-500=9500
=> Barefooted=9500/2=4750
=> Remaining people= 9500-4750=4750
=> Hence required number of shoes= 4750*2+500*1=10000
Hence (B) is the correct answer.
Answer : B
Answer: B
Question: A can do a piece of work in 13 days and B in 20 days. They began the work together but 5 days before the completion of the work, A leaves. The work was completed in?
Options:
A)15 10/11 days
B)10 10/11 days
C)12 10/11 days
D)19 10/11 days
E)13 10/11 days
Rationale: B
(x â€“ 5)/13 + x/20 = 1
x = 10 10/11 days
Answer: B
Question: If the price of petrol increases by 25% and Kevin intends to spend only 15% more on petrol. By how much percent should he reduces the quantity of petrol that he buys?
Options:
A)8
B)9
C)7
D)2
E)6
Rationale: Explanation:
Let Petrol Price 100 per Liter and Quantity he purchases equals to 100 Liters
Then total expenditure = 100 × 100 = 10000
Petrol Price is increased by 25%. So new price = 125 per litre
And he increases the expenditure by 15%. So expenditure limit = 11500
Now his quantity = 11500/125 = 92 liters
So the quantity is reduced by 8%
Answer: A
Answer: A
Question: A train 360 m long is running at a speed of 60 km/hr. In what time will it pass a bridge 140 m long?
Options:
A)40 sec
B)30 sec
C)26 sec
D)27 sec
E)34 sec
Rationale: Speed = 60 * 5/18 = 50/3 m/sec
Total distance covered = 360 + 140 = 500 m
Required time = 500 * 3/50
= 30 sec
Answer: B
Answer: B
Question: what is average of 2000 terms of the given series
1,-3,2,-4,3,-5,4,....
Options:
A)1
B)0.5
C)-0.5
D)-1
E)-2
Rationale: 1-3=-2
2-4=-2
3-5=-2...
we get 1000 -2s for 2000 numbers.
for 2000 terms the average= -2(1000)/2000
= -1
ANSWER:D
Answer: D
Question: A money lender finds that due to a fall in the annual rate of interest from 8% to 7 3/5 % his yearly income diminishes by Rs.61.50. his capital is
Options:
A)153.75
B)37.78
C)246.0
D)27.88
E)127.71
Rationale: Explanation:
Capital = Rs.x , then
2/5x = 153.75
Answer: A) Rs.153.75
Answer: A
Question: A clock shows the time as 9 a.m. If the minute hand gains 7 minutes every hour, how many minutes will the clock gain by 6 p.m.?
Options:
A)30 min
B)35 min
C)63 min
D)50 min
E)55 min
Rationale: there are 9 hours in between 9 a.m. to 6 p.m.
9*7=63 minutes.
ANSWER:C
Answer: C
Question: Which of the following is the smallest multiple of 3!-4?
Options:
A)4!-22
B)4!-10
C)3!+1
D)4!+20
E)3!+4
Rationale: The expression 3!-4 can be expanded out to (3*2)-4
Therefore (3*2)-4=6-4=2
Looking at the options the one that gives the lowest multiple of 2 is option A)
Answer: A
Question: The average age of 16 students of a class is 16 years. Out of these, the average age of 5 students is 14 years and that of the other 9 students is 16 years, The age of the 12th student is
Options:
A)11
B)66
C)18
D)16
E)42
Rationale: Explanation:
Age of the 16th student = [16 * 16 - (14 * 5 + 16 * 9)] = (256-214) = 42 years.
Answer: E
Answer: E
Question: What quantity of water should taken out to concentrate 15 liters of 40% acidic liquid to 60% acidic liquid?
Options:
A)5liters
B)10liters
C)15liters
D)8liters
E)6liters
Rationale: Required answer is = 15(60-40)/60 = 5 liters
Answer is A
Answer: A
Question: ((-1.9)(0.6) – (2.6)(1.2))/4.0 = ?
Options:
A)-0.71
B)1.0
C)1.07
D)1.71
E)-1.065
Rationale: Dove straight into calculation
((-1.9)(0.6) – (2.6)(1.2))/4.0 = -1.065
Answer E
Answer: E
Question: the ratio of water and milk is 2:3.after adding 4litre milk ratio become 1:2? calculate amount of water?
Options:
A)6
B)8
C)5
D)10
E)12
Rationale: water is 2x and milk is 3x.
2x/3x+4=1/2,4x=3x+4,x=4
amount of water=2x=8 litre
answer B
Answer: B
Question: What day of the week will 22 Apr 2222 be?
Options:
A)Monday
B)Tuesday
C)Sunday
D)Thursday
E)None of these
Rationale: Explanation :
22 Apr 2222 = (2221 years + period from 1-Jan-2222 to 22-Apr-2222)
We know that number of odd days in 400 years = 0
Hence the number of odd days in 2000 years = 0 (Since 2000 is a perfect multiple of 400)
Number of odd days in the period 2001-2200
= Number of odd days in 200 years
= 5 x 2 = 10 = 3
(As we can reduce perfect multiples of 7 from odd days without affecting anything)
Number of odd days in the period 2201-2221
= 16 normal years + 5 leap years
= 16 x 1 + 5 x 2 = 16 + 10 = 26 = 5 odd days
Number of days from 1-Jan-2222 to 22 Apr 2222
= 31 (Jan) + 28 (Feb) + 31 (Mar) + 22(Apr) = 112
112 days = 0 odd day
Total number of odd days = (0 + 3 + 5 + 0) = 8 = 1 odd day
1 odd days = Monday
Hence 22 Apr 2222 is Monday. Answer : Option A
Answer: A
Question: Country C imposes a two-tiered tax on imported cars: the first tier imposes a tax of 12% of the car's price up to a certain price level. If the car's price is higher than the first tier's level, the tax on the portion of the price that exceeds this value is 9%. If Ron imported a $18,000 imported car and ended up paying $1950 in taxes, what is the first tier's price level?
Options:
A)$11500
B)$11000
C)$12000
D)$12100
E)$12500
Rationale: Let T be the tier price, P be total price = 18000
Per the given conditions:
0.12T + 0.09(P-T) = 1950
0.12T+0.09*18000-0.09T =1950
0.03T +1620 = 1950
0.03T = 1950-1620 = 330
T = 330/0.03 =11000
Answer B
Answer: B
Question: The value of (9x10^7)(3x10^8) is closest to which of the following?
Options:
A)10^11
B)10^12
C)10^13
D)10^17
E)10^18
Rationale: multiplying these we get,
27 x 10^7 x 10^8
= 2.7 x 10^16
which is closer to 10^17
Answer: D
Answer: D
Question: A man swims downstream 72 km and upstream 45 km taking 9 hours each time; what is the speed of the current?
Options:
A)1.6
B)1.2
C)1.9
D)1.3
E)1.5
Rationale: 72 --- 9 DS = 8
? ---- 1
45 ---- 9 US = 5
? ---- 1 S = ?
S = (8 - 5)/2 = 1.5
Answer: E
Answer: E
Question: A certain college party is attended by both male and female students. The ratio of male to female students is 4 to 5. If 6 of the male students were to leave the party, the ratio would change to 1 to 2. How many total students are at the party?
Options:
A)24
B)28
C)32
D)36
E)40
Rationale: The ratio is 4:5 = 8:10, so there are 8k males and 10k females.
If 6 males left, the ratio would be 1:2 = 5:10, so there would be 5k males and 10k females.
8k-5k = 6
k = 2
8k + 10k = 16 + 20 = 36
The answer is D.
Answer: D
Question: What will be the cost of building a fence around a square plot with area equal to 81 sq ft, if the price per foot of building the fence is Rs. 58?
Options:
A)3944
B)2287
C)2977
D)2088
E)1298
Rationale: Let the side of the square plot be a ft.
a2 = 81=> a = 9
Length of the fence = Perimeter of the plot = 4a = 36ft.
Cost of building the fence = 36 * 58 = Rs. 2088.
Answer:D
Answer: D
Question: The average age of 29 students in a group is 15 years. when teacher's age is included to it, the average increases by one.What is the teacher's age in years?
Options:
A)31
B)36
C)29
D)53
E)57
Rationale: age of the teacher=(29*16-29*15)
=29 years.
ANSWER:C
Answer: C
Question: If 0.60 : x : : 6 : 2, then x is equal to
Options:
A)0.2
B)0.5
C)2.5
D)1.8
E)None
Rationale: Sol.
(x×6) = (0.60×2) ⇒ x = 0.60/6 = 0.2.
Answer A
Answer: A
Question: Of the mutual funds on a “select list,” 1/2 have 5-star ratings, and 2/5 of the remaining funds have 4-star ratings. If the remaining 300 funds on the list have 3-star ratings, how many funds are on the list?
Options:
A)500
B)750
C)1,000
D)1,200
E)1,500
Rationale: C
Fraction of 5- and 4-star funds: 1/2 + (2/5)*(1/2) = 1/2 + 1/5 = 7/10
Fraction of 3-star funds = 1 - 7/10 = 3/10
(3/10)*Total = 300
Total = 1000
Answer: C
Question: What will come in place of the x in the following number series? 12, 26, 54, 110, 222, x
Options:
A)444
B)446
C)448
D)452
E)454
Rationale: 1212 × 2 + 2 = 2626 × 2 + 2 = 5454 × 2 + 2 = 110110 × 2 + 2 = 222222 × 2 + 2 = 446 B
Answer: B
Question: What approximate value should come in place of the question mark (?) in the following equation?
248.251 ÷ 12.62 × 20.52 = ?
Options:
A)400
B)450
C)600
D)350
E)375
Rationale: 248.251 ÷ 12.62 × 20.52 = ?
or,? ≈ 240 ÷ 12 × 20 = 20 × 20 = 400
Answer A
Answer: A
Question: A spike is hammered into a train rail. You are standing at the other end of the rail. You hear the sound of the hammer strike both through the air and through the rail itself. These sounds arrive at your point six seconds apart. You know that sound travels through air at 1100 feet per second and through steel at 16,500 feet per second. How far away is that spike?
Options:
A)7070.25
B)7080.25
C)6070.25
D)8070.25
E)7170.25
Rationale: d = 1100(t + 6 ), d = 16500t, so 1100(t + 6) = 16500t
1100t + 6600 = 16500t, 1100t - 1100t + 6600 = 16500t-1100t, 6600 = 15400t
6600/15400 = 15400t/15400, 0.4285 = t, 1100(.4285 + 6) = 7071.35, 16500(.4285) = 7070.25
ANSWER:A
Answer: A
Question: In a class of 100 students, there are 50 who play soccer, 45 who play
basketball, and 50 who play volleyball. Only 15 of these students play all
three sports. Everyone plays at least one of these sports. How many of
the students play exactly two of these sports?
Options:
A)15
B)20
C)25
D)30
E)35
Rationale: Let S1 be the number of students who play exactly one of the three sports; S2 - the
number of students who play exactly two of the three sports; and let S3 be the number
of students who play all three sports. We know that S3 = 15 and S1 + S2 + S3 = 100
(the total number of students). Also in the sum 50+45+50 (soccer players + basketball
players + volleyball players), each student who plays exactly one sport is counted once,
the ones who play exactly two sports are counted twice, and those who play all three
sports are counted three times. Thus, 50 + 45 + 50 = S1 + 2S2 + 3S3. Note that
S2 = (S1 + 2S2 + 3S3) − (S1 + S2 + S3) − 2S3 = 15
correct answer A
Answer: A
Question: Pipes A and B can fill a tank in 2 and 6 hours respectively. Pipe C can empty it in 12 hours. If all the three pipes are opened together, then the tank will be filled in?
Options:
A)3 9/97 hrs
B)3 9/77 hrs
C)3 9/17 hrs
D)1 5/7 hrs
E)3 9/19 hrs
Rationale: Net part filled in 1 hour = 1/2 + 1/6 - 1/12
= 7/12
The tank will be full in 12/7 hrs, i.e., 1 5/7 hrs.
Answer:D
Answer: D
Question: Tom can do a piece of work in 5 days and Ben alone can do it in 10 days. How much time will both take to finish the work ?
Options:
A)A)3.3333
B)B)4.3333
C)C)7.3333
D)D)5.3333
E)E)2.3333
Rationale: This question can be solved by different methods. We need to conserve time in exams so solving this problem using equations is the good idea.
Time taken to finish the job = XY / (X + Y)
= 5 x 10 / (5 + 10)
= 50 / 15
= 3.3333 days
Answer: A
Answer: A
Question: From the starting point in a boat race, one competitor started to sail north at a speed of 1.5 Km/h, the other competitor started to sail west at a speed of 1.2 Km/h. What is the distance in Km between the two competitors after 5 hours?
Options:
A)9.6
B)12.
C)12.5.
D)14.
E)15.4.
Rationale: Both competitors are sailing making angle of 90 degrees.
After 5 hrs one competitor will cover a distance of = 1.5 *5= 7.5 KM
And, other competitor will cover a distance of = 1.2*5= 6KM
distance between them after 5 hrs = (7.5^2+ 6^2)^1/2= 9.6 KM
A is the answer
Answer: A
Question: Which of the following fractions E, if written as a decimal, would have a 2 in the thousandths place ?
Options:
A) 3/11
B) 7/9
C) 1/8
D) 4/7
E) 1/6
Rationale: (A) E=3/11 = 0.2727272727....
Answer: A
Answer: A
Question: Milk contains 5% water.What quantity of pure milk should be added to 10 litres of milk to reduce this 2%?
Options:
A)15 litres
B)16 litres
C)17 litres
D)25 litres
E)35 litres
Rationale: Present Ration of MIlK TO WATER IS 95:5
Amount of Milk is 10 litres
Hence, Pure milk content is 9.5 litre
and water content is 0.5 litres
Now, we should not disturb the water content
So, 0.5 litres of water is equivalent to 2%
So 100% mixture is :(0.5/2)*100=25litre
Thus, milk should be added=25-10=15 litres of pure milk
ANSWER:A
Answer: A
Question: A card shop contains 5 birthday cards, 5 holiday cards, and 5 graduation cards. If three cards are purchased at random from the shop, what is the probability that the three cards will be of the same type?
Options:
A)6/91
B)5/93
C)4/95
D)3/97
E)2/99
Rationale: It might require to be written as "5 different birthday cards, 5 different holiday cards, and 5 different graduation cards" rather than "5 birthday cards, 5 holiday cards, and 5 graduation cards"..
If the cards are same there will be ONLY 1 way to pick from each type and thus overall 3..
so numerator has to be 3, or 1 if 3 cancels out..
If I take all as different cards--
ways to pick 3 cards of same type = 5C3 * 3= 30
ways to pick 3 cards out of 15 = 15C3 = 455
Prob = 30/455 = 6/91
Ans: A
Answer: A
Question: The age of the two friends were in the ration of 6:5. If the sum of their ages is 55. Then after how many years their ratio will become 8:7?
Options:
A)11
B)7
C)10
D)12
E)13
Rationale: since given ratio is 6:5 of their ages.
6x+5x=55(given)
11x=55
x=5. so present ages are: 6*5=30 and 5*5=25
after few yrs ratio becomes 8:5.
so,their ages will become 8x and 7x respectively, ie. 40 and 35 respectively.
nw difference of their current ages and further ages is clear from above... ie. 10 yrs.
ANSWER:C
Answer: C
Question: A certain fraction is equivalent to 2/5. If the numerator of the fraction is increased by 4 and the denominator is doubled, the new fraction is equivalent to 1/4. What is the difference of the numerator and denominator of the original fraction?
Options:
A) 49
B) 35
C) 28
D) 24
E) 21
Rationale: x/y = 2/5 -> 1
(x+4)/2y = 1/4 -> 2
Divide 1 by 2 :
=> 2x/(x+4) = 8/5
=> 5x = 4x + 16
=> x = 16
=> y = 5/2 *16 = 40
so x - y = 24
The answer is D
Answer: D
Question: The ratio of Male to Female in last week Calvary Church attendance was 4:6. If 60% of the Male and 40% of the Female were Under 35 years, How many people under 35 years of age attended Calvary Church last Sunday.
Options:
A)51%
B)50%
C)48%
D)54%
E)46%
Rationale: let total no of last week Calvary church attendance be 100, Male 40 and Female 60, so total number of last week Calvary church attendance below 35 years for both male and female respectively 40* 60/100=24 and 60* 40/100=24
so total 48 Calvary church attendance last week out of a Total of 100 attendance is under 35 years......so required % is 48%
ANSWER:C
Answer: C
Question: A man complete a journey in 20 hours. He travels first half of the journey at the rate of 10 km/hr and second half at the rate of 15 km/hr. Find the total journey in km.
Options:
A)220 km
B)240 km
C)230 km
D)232 km
E)234 km
Rationale: 0.5x/10 + 0.5x/15 = 20
--> x/10+ x/15= 40
--> 5x = 30x40
--> x = (30x40)/5 = 240 km.
Answer : B.
Answer: B
Question: Sum of 49 odd numbers is?
Options:
A)2398
B)2399
C)2400
D)2401
E)2402
Rationale: sum of 1st n odd no.s = 1+3+5+7+... = n^2
so, Sum of 1st 49 odd numbers = 49^2 = 2401
ANSWER:D
Answer: D
Question: What is the smallest number K which when increased by 5 is completely divisible by 8, 11 and 24?
Options:
A)264
B)259
C)269
D)270
E)282
Rationale: This question includes a number of great Number Property shortcuts that you can take advantage of:
1) The question asks for the SMALLEST number that, when increased by 5 is divisible by 8, 11 and 24. Since the answers are numbers, we can TEST THE ANSWERS.
2) Any number that is divisible by 24 is ALSO divisible by 8, so we really just need to consider the 11 and the 24.
3) To be divisible by 24, the end number MUST be EVEN. Since we're adding 5 to get to that end number, the starting number MUST be ODD.
The last shortcut allows us to eliminate Answers A, D and E. Between Answers B and C, TESTING B first will prove that, when increased by 5, the end sum is divisible by both 11 and 24.
Final Answer:
B
Answer: B
Question: Ayesha's father was 38 years of age when she was born while her mother was 34 years old when her brother four years younger to her was born. What is the difference between the ages of her parents?
Options:
A)2 years
B)4 years
C)6 years
D)8 years
E)10 years
Rationale: Explanation:
Mother's age when Ayesha's brother was born = 34 years.
Father's age when Ayesha's brother was born = (38 + 4) years = 42 years.
Required difference = (42 - 34) years = 8 years.
Answer: D
Answer: D
Question: A is a working partner and B is a sleeping partner in a business. A puts in 20,000 and B 90,000. A gets 20% of the profit for managing the business, and the rest is divided in proportion to their capitals. Find the share of B in profit of 11000.
Options:
A)3500
B)7200
C)6800
D)4800
E)None of these
Rationale: The amount A gets for managing
= 20% of Rs. 11000 = 2200
Remaining profit = 11000 – 2200 = 8800
This is to be divided in the ratio 2 : 9.
Share of B = 9/11 of 8800 = 7200
Answer B
Answer: B
Question: A bullet train 150 m long is running with a speed of 30 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the bullet train is going?
Options:
A)23 sec
B)15 sec
C)12 sec
D)11 sec
E)15 sec
Rationale: E
15 sec
Speed of the bullet train relative to man = (30 + 6) kmph
= 36 *5/18 m/sec = 30/3 m/sec.
Time taken by the bullet train to cross the man = Time taken by it to cover 150 m at (30/3) m / sec
= (150 *3/30) sec = 15 sec
Answer: E
Question: 99! how many zero's?
Options:
A)20
B)21
C)22
D)23
E)24
Rationale: 99!=99/5=19
=19/5=3
so 99! has (19+3=22 zeroes)
ANSWER:C
Answer: C
Question: A can do a piece of work 30 days. B can do work in 55 days. In how many days they will complete the work together?
Options:
A)15 days
B)16 days
C)19.4 days
D)17.2 days
E)18 days
Rationale: LCM = 330, Ratio= 30:45=6:11
No of days= 330/(6+11) = 330/17 = 19.4 days
ANSWER:C
Answer: C
Question: Raman mixed 24 kg of butter at Rs. 150 per kg with 36 kg butter at the rate of Rs. 125 per kg. At what price per kg should he sell the mixture to make a profit of 40% in the transaction?
Options:
A)339
B)278
C)189
D)287
E)211
Rationale: CP per kg of mixture = [24(150) + 36(125)]/(24 + 36) = Rs. 135
SP = CP[(100 + profit%)/100]
= 135 * [(100 + 40)/100] = Rs. 189.
Answer: C
Answer: C
Question: Nitin ranks 18th in a class of 49 students. What is rank from the last ?
Options:
A)33
B)38
C)32
D)28
E)19
Rationale: Explanation:
Number students behind the nitin in rank = (49 - 18) = 31
Nitin is 32nd from the last
Answer: C) 32
Answer: C
Question: Linda and Angela contract to paint a neighbor's house. Even though Linda
spends 30% more time painting the house than Angela, each receives a payment
of m dollars when the work is completed. If Angela decides to pay Linda n
dollars so that they would have received the same compensation per hour
worked, what is n in terms of m?
Options:
A)A)(3/23)m
B)B)(1/3)m
C)C)(1/4)m
D)D)(1/5)m
E)E)(1/6)m
Rationale: let angela work for 10hrs and get 1150 rs. (m =1150)
According to question, linda works 30% more time and gets the same amount. so let linda work 13 hrs and get 1150 rs.
so they do a total of 13 +10=23 hrs of work and get 2300 rs together . The question basically asks to equalise their payment. so a total of 2300 rs is received by them and they do 23 hrs work together. average rate will be 2300/23 = 100 rs per hr. so linda should get 13*100 =1300 rs. But she got only 1150. so angela should give 150 rs to linda. answer = 150/1150 =3/23
answer A
Answer: A
Question: Three partners A, B, C in a business invested money such that 2(Aâ€™s capital) = 5(Bâ€™s capital) = 10(Câ€™s capital) then, The ratio of their capitals is
Options:
A)63 : 45 : 34
B)63 : 54 : 34
C)5 : 2 : 1
D)63 : 45 : 35
E)None of these
Rationale: Explanation:
Let 2(Aâ€™s capital) = 5(Bâ€™s capital) = 10(Câ€™s capital) = Rs.x
Then, Aâ€™s capital = Rs x/2, Bâ€™s capital = Rs. x/5 and Câ€™s capital = Rs. x/10
A : B : C = x/2 : x/5 : x/10
5 : 2 : 1
Answer: Option C
Answer: C
Question: the walker walking at a constant rate of 4 miles per hour is passed by a cyclist traveling in the same direction along the same path at 20 miles per hour. the cyclist stops to wait for the hiker 5 minutes after passing her, while the walker continues to walk at her constant rate, how many minutes must the cyclist wait until the walker catches up?
Options:
A)16
B)18
C)20
D)22
E)24
Rationale: After passing the hiker the cyclist travels for 5 minutes at a rate of 20 miles/hour.
In those 5 mins the cyclist travels a distance of 5/3 miles.
In those 5 mins the hiker travels a distance of 1/3 miles.
So the hiker still has to cover 4/3 miles to meet the waiting cyclist.
The hiker will need 1/3 hours or 20 mins to cover the remaining 4/3 miles.
So the answer is C.
Answer: C
Question: Doughnut delivery delivers about 75 orders using 15 fleet bikes in any given day of 15 hours. They need to increase their delivery for Christmas and so they bought 10 more bikes and now work for 4 extra hours. How many more orders will be delivered in the next eight days?
Options:
A)200
B)225
C)37.5
D)16,875
E)95
Rationale: old bikes deliver 75/15= 5 orders per hour, which is 5* (15+4) hours= 95 orders in new day time frame.
Total bikes is 25* 95 orders is 225 orders.
Answer is B.
Answer: B
Question: If the sides of a triangle are 30 cm, 26 cm and 10 cm, what is its area?
Options:
A)120
B)110
C)130
D)140
E)150
Rationale: The triangle with sides 30 cm, 26 cm and 10 cm is right angled, where the hypotenuse is 30 cm.
Area of the triangle = 1/2 * 26 * 10 = 130 cm2
Answer: Option C
Answer: C