divelab/Sys2Bench huggingface dataset:
Question: How many three-element subsets of {1,2,3,4} are there that do not contain the pair of elements 2 and 4?
Options:
A)1
B)2
C)3
D)4
E)5
Rationale: Required subsets are = {1,2,3}, {1,3,4}= 2
Answer: B
Answer: B
Question: If a(a + 6) = 27 and b(b + 6) = 27, where a ≠ b, then a + b =
Options:
A) −48
B) −6
C) 2
D) 46
E) 48
Rationale: a(a + 6) = 27 and b(b + 6) = 27
=> a, b must be integers and if a is -9 or 3, b will be 3 and -9 respectively
=> a+b = -6
Ans: B
Answer: B
Question: A train is 360 meter long is running at a speed of 45 km/hour. In what time will it pass a bridge of 140 meter length?
Options:
A)65 seconds
B)46 seconds
C)40 seconds
D)97 seconds
E)26 seconds
Rationale: Speed = 45 Km/hr = 45*(5/18) m/sec = 25/2 m/sec
Total distance = 360+140 = 500 meter
Time = Distance/speed
= 500 * (2/25)
= 40 seconds
Answer:C
Answer: C
Question: A cistern has a leak which would empty the cistern in 20 minutes. A tap is turned on which admits 1 liters a minute into the cistern, and it is emptied in 24 minutes. How many liters does the cistern hold?
Options:
A)480
B)120
C)289
D)270
E)927
Rationale: 1/x - 1/20 = -1/24
x = 120
120 * 1 = 120
Answer: B
Answer: B
Question: A palindrome is a word or a number that reads the same forward and backward. For example, 2442 and 111 are palindromes. If 5-digit palindromes are formed using one or more of the digits 1, 2, 3, 4, and 5, how many palindromes are possible?
Options:
A)25
B)75
C)125
D)225
E)625
Rationale: There are 5 choices for each of the first three digits.
The number of possible palindromes is 5^3=125.
The answer is C.
Answer: C
Question: A painting crew painted 80 houses. They painted the first y houses at a rate of x houses per week. Then more painters arrived and everyone worked together to paint the remaining houses at a rate of 2.25x houses per week. How many weeks did it take to paint all 80 houses, in terms of x and y?
Options:
A)(320 - y)/(5x)
B)(y +250)/(5x)
C)5(80 - y)/(4x)
D)(y + 400)/(4x)
E)(4y + 250)/(5x)
Rationale: Ans B
Plug some numbers
Let y = 40 houses and x = 20
then they painted 20 houses per week
as painters were added to the group , the rate of the group increased to 2.25 x => 2.25 * 20 = 45 houses per week
total time they took = (40/20) + (40/45) = 2.9 weeks
Putting the values of x and y in equation B
(y +250)/(5x) = (40+250)/5*20 = 290/100 = 2.9
Answer: B
Question: You have been given a physical balance and 7 weights of 52, 50, 48, 44, 45, 46 and 78 kgs. Keeping weights on one pan and object on the other, what is the maximum you can weigh less than 183 kgs.
Options:
A)180
B)181
C)182
D)178
E)168
Rationale: add the max weights
52+50+78=180
ANSWER:A
Answer: A
Question: The majority owner of a business received 25% of the profit, with each of 4 partners receiving 25% of the remaining profit. If the majority owner and two of the owners combined to receive $46,875, how much profit did the business make?
Options:
A)$55,000
B)$75,000
C)$95,000
D)$115,000
E)$125,000
Rationale: Let P be the total profit.
P/4 + 1/2*(3P/4) = P/4 + 3P/8 = 5P/8 = 46875
P = $75,000
The answer is B.
Answer: B
Question: When the price of an article was reduced by 40% its sale increased by 80%. What was the net effect on the sale?
Options:
A)8% increase
B)4% decrease
C)6% increase
D)66% increase
E)66% decrease
Rationale: if n items are sold for $p each, revenue is $np. If we reduce the price by 40%, the new price is 0.6p. If we increase the number sold by 80%, the new number sold is 1.8n. So the new revenue is (0.6p)(1.8n) = 1.08np, which is 1.08 times the old revenue, so is 8% greater.
ANSWER:A
Answer: A
Question: If (20)² is subtracted from the square of a number, the answer so obtained is 4321. What is the number?
Options:
A)68
B)69
C)70
D)71
E)72
Rationale: x^2=4321+400=4721
4761=69*69
x=69
ANSWER:B
Answer: B
Question: If a particular player is always chosen, in how many ways can a cricket-be chosen out of 15 players?
Options:
A)1245
B)1268
C)1290
D)1345
E)1365
Rationale: A particular player is always chosen, it means that 10 players are selected out of the remaining 14 players.
=. Required number of ways = 14C10 = 14C4
= 14!/4!x19! = 1365
E
Answer: E
Question: In a certain large company, the ratio of college graduates with a graduate degree to non-college graduates is 1:8, and ratio of college graduates without a graduate degree to non-college graduates is 2:3. If one picks a random college graduate at this large company, what is the probability T this college graduate has a graduate degree?
Options:
A)1/11
B)1/12
C)1/13
D)3/19
E)3/43
Rationale: In believe the answer is D. Please see below for explanation.
0) we are told the following ratios
CGD - College Graduate with Degree
NCG - Non College Graduate
CGN - College Graduate no Degree
CGD NCG CGN
1 8
3 2
In order to make CGD and CGN comparable we need to find the least common multiple of 8 and 3 and that is 24 multiplying the first ratio by 3 and the second ratio by 8 we get
CGD NCG CGN
3 24 16
If one picks a random college graduate at this large company, what is the probability this college graduate has a graduate degree?
Nr of CGD = 3
Nr of CG = 3+ 16 = 19
Probability T of CGD / (CG) -> 3/19
Answer D
Answer: D
Question: The greatest common factor of positive integers m and n is 14. What is the greatest common factor of (2m^2, 2n^2)?
Options:
A)14
B)28
C)196
D)392
E)784
Rationale: m = 14j and n = 14k, where the greatest common factor of j and k is 1.
2m^2 = 2*14*14*j^2 and 2n^2 = 2*14*14*k^2
The greatest common factor of 2m^2 and 2n^2 is 2*14*14 = 392
The answer is D.
Answer: D
Question: A sun is divided among X, Y and Z in such a way that for each 5 rupees X gets, Y gets 3 rupees and Z gets 2 rupees. If the share of Z is RS. 200, what is the total amount of X and Y?
Options:
A)650
B)800
C)600
D)700
E)900
Rationale: x:y:z = 500:300200
5:3:2
2 --- 200
8 --- ? => 800
Answer: B
Answer: B
Question: If n is a prime number and n ≠ 3, which of the following could be the remainder when 100! + n is divided by 3?
I. 2
II. 1
III. -2
Options:
A)II only
B)III only
C)I and II only
D)II and III only
E)I, II and III
Rationale: Notice that we are told that n is a prime number and n ≠ 3. Thus, n cannot be 1.
n also cannot be 6 or any other multiple of 3, thus the remainder cannot be 0.
It can be 1 for n=2 and 2 for n=5.
Answer: C.
Answer: C
Question: If xy > 0, 1/x + 1/y = 15, and 1/xy = 5, then (x+y)/5 = ?
Options:
A)1/25
B)1/6
C)3/5
D)5
E)6
Rationale: (1/X+1/Y)=15 canbe solved as {(x+y)/xy}=5. Substituting for 1/xy=5, we get
x+y=15/5
==> (x+y)/5= 15/(5*5)=3/5.
C
Answer: C
Question: A farmer sells his strawberries through a distributor, which take a commission of 12% of the price set by the farmer. The distributor obtains the product from a farmer at the price of $35 per bushel. What is the price that the buyer observers if the distributor wants to maintain a 12% profit on the cost of a bushel?
Options:
A)66.22
B)44.55
C)44.05
D)66.02
E)75.48
Rationale: Farmer price = $35;The distributor wants to maintain a 12% profit on the cost of each strawberry bushel, thus he must get $35*1.12 = $39.20 after the distributor takes a commission of 12% of the final price --> (final price)*0.88 = $39.20 --> (final price) = $44.55Answer: B.
Answer: B
Question: A train passes a man standing on the platform. If the train is 160 meters long and its speed is 72 kmph, how much time it took in doing so?
Options:
A)5 sec
B)6 sec
C)8 sec
D)9 sec
E)7 sec
Rationale: D = 160
S = 72 * 5/18 = 20 mps
T = 160/20 = 8 sec
ANSWER:C
Answer: C
Question: Length of a rectangular plot is 12 mtr more than its breadth. If the cost of fencing the plot at 26.50 per meter is Rs. 5300, what is the length of the plot in mtr?
Options:
A)56 m
B)60 m
C)80 m
D)82 m
E)84 m
Rationale: Let breadth = x metres.
Then, length = (x + 12) metres.
Perimeter = 5300 m = 200 m.
26.50
2[(x + 12) + x] = 200
2x + 12 = 100
2x = 88
x = 44
Hence, length = x + 12 = 56 m
A
Answer: A
Question: How much time does a train 125 metres long running at 60 km/hr take to pass a pole?
Options:
A)7.9s
B)2.5s
C)7.5s
D)7.6s
E)7.4s
Rationale: Explanation:
60 km/hr = 60 * 5/18 = 16.67 m/s
Speed = distance/time; v = d/t
16.67 = 125/t
t = 7.5s
ANSWER: C
Answer: C
Question: A car travels uphill at 30 km/hr and downhill at 90 km/hr. It goes 100 km uphill and 50 km downhill. Find the average speed of the car?
Options:
A)32kmph
B)39kmph
C)34kmph
D)35kmph
E)36kmph
Rationale: avg speed=total distance/total time.
total distance traveled=100+50=150km;
time taken for uphill journey=100/30=10/3;
time taken for down hill journey=50/90=5/9;
avg speed=150/(10/3+5/9)=39kmph
ANSWER:B
Answer: B
Question: On a partly cloudy day, Derek decides to walk back from work. When it is sunny, he walks at a speed of s miles/hr (s is an integer) and when it gets cloudy, he increases his speed to (s + 1) miles/hr. If his average speed for the entire distance is 2.8 miles/hr, what fraction R of the total distance did he cover while the sun was shining on him?
Options:
A)1/4
B)4/5
C)1/5
D)1/6
E)1/7
Rationale: If s is an integer and we know that the average speed is 2.8, s must be = 2. That meanss+1= 3. This implies that the ratio of time for s=2 is 1/4 of the total time. The formula for distance/rate is D=Rt...so the distance travelled when s=2 is 2t. The distance travelled for s+1=3 is 3*4t or 12t. Therefore, total distance covered while the sun was shining over him is R=2/14 = 1/7. Answer: E
Answer: E
Question: 4,25,49,121,169,289,361,
Options:
A)149
B)169
C)189
D)529
E)219
Rationale: 23^2= 529 because follow sequence of square of the prime numbers
ANSWER:D
Answer: D
Question: The average runs scored by a batsman in 20 matches is 40. In the next 10 matches the batsman scored an average of 13 runs. Find his average in all the 30 matches?
Options:
A)31
B)66
C)55
D)77
E)81
Rationale: Total score of the batsman in 20 matches = 800.
Total score of the batsman in the next 10 matches = 130.
Total score of the batsman in the 30 matches = 930.
Average score of the batsman = 930/30 = 31.
Answer: A
Answer: A
Question: Two men and three women can repair a bridge in 10 days while three men and two women can do same work in 8 days. If two men and one woman are used to finish this work, in how many days they will complete it?
Options:
A)9.7 days
B)12.5 days
C)10 days
D)11.3 days
E)12.7 days
Rationale: Work done by 2 men and 3 women in 1 day = 1/10
Work done by 3 men and 2 women in 1 day = 1/8
Let 1 men does m work in 1 day and 1 women does w work in 1 day. The above equations can be written as
2 m + 3 w = 1/10 ---(1)
3 m + 2 w = 1/8 ---(2)
Solving equation (1) and (2) , we get m=14/200 and w=1/100
2 men and 1 woman together can finish the work in =14/200+1/100=2/25=12.5 days
B
Answer: B
Question: A tank is filled by three pipes with uniform flow. The first two pipes operating simultaneously fill the tank in the same during which the tank is filled by the third pipe alone. The second pipe fills the tank 5 hours faster than the first pipe and 4 hours slower than the third pipe. The time required by the first pipe is?
Options:
A)16
B)13
C)15
D)18
E)12
Rationale: Suppose, first pipe alone takes x hours to fill the tank. Then, second and third pipes will take (x - 5) and (x - 9) hours respectively to fill the tank.
1/x + 1/(x - 5) = 1/(x - 9)
(2x - 5)(x - 9) = x(x - 5)
x2 - 18x + 45 = 0
(x- 15)(x - 3) = 0 => x = 15
Answer: C
Answer: C
Question: Andrew is selling fruit to be able to buy a new bike. The bike costs 400. He sells a large bag of fruit for $8. He so far has sold 32 bags, how many more need to be sold in order to buy the bike.
Options:
A)3
B)18
C)15
D)12
E)2
Rationale: 8*32=256
400-256=144
144Ã·8=18
18 more bags of fruit need to be sold in irder for the bike to be purchased.
Therefore answer B is correct.
Answer: B
Question: Pipe A fills a swimming pool in 4 hours. Pipe B empties the pool in 6 hours. If pipe A was opened at 7:00 am and Pipe B at 8:00 am, at what time will the pool be full?
Options:
A)16:00
B)18:00
C)19:00
D)20:00
E)17:00
Rationale: Pipe A fills the pool in 4 hrs.
1 hour's work : 1/4
Pipe B empties the pool in 6 hrs.
1 hour's work : 1/6
Together if they work, 1 hour's work = 1/4 -1/6 = 1/12
Given : Pipe A started at 7:00 a.m and Pipe B at 8:00 a.m
Pool filled after 1 hour by Pipe A : 1/4 or 3/12
After 8:00 a.m
Pool filled after 1 hour with both the pipes on : 1/12
Pool filled after 9 hours with both pipes on : 9/12
Pool filled in 1 hour + Pool filled in 9 hours = 3/12 +9/12 =1
Therefore, it takes 10 hrs to fill the pool
As Pipe A started at 7:00 a.m, pool is full at 17:00 hrs
Answer : E
Answer: E
Question: A number increased by 10% gives 660. The number is?
Options:
A)200
B)300
C)500
D)600
E)400
Rationale: Formula = TOTAL=100% ,INCREASE = "+" DECREASE= "-"
A number means = 100 %
That same number increased by 10 % = 110 %
110 % -------> 660 (110 Ã— 6 = 660)
100 % -------> 600 (100 Ã— 6 = 600)
Option 'D'
Answer: D
Question: A driver covers a certain distance by car driving at 60 km/hr and returns back to the starting point riding on a scooter at 10 km/hr. What was the average speed for the whole journey?
Options:
A)14.2 km/h
B)17.1 km/h
C)19.3 km/h
D)21.7 km/h
E)23.5 km/h
Rationale: time 1 = d / 60
time 2 = d / 10
total time = d/60 + d/10 = 7d/60
average speed = total distance / total time = 2d / (7d/60) = 17.1 km/h
The answer is B.
Answer: B
Question: Walking at 3/4 of her normal speed, a worker is 12 minutes later than usual in reaching her office. The usual time (in minutes) taken by her to cover the distance between her home and her office is
Options:
A)36
B)48
C)60
D)62
E)66
Rationale: Let V be her normal speed and let T be her normal time.
D = (3/4)V * (T+12)
Since the distance is the same we can equate this to a regular day which is D = V*T
V*T = (3/4)V * (T+12)
T/4 = 9
T=36
The answer is A.
Answer: A
Question: The ratio of a to b to c is 2 to 3 to 4, and a, b, c are positive integers. If the average (arithmetic mean) of the three numbers is 27, what is the value of a?
Options:
A)18
B)20
C)21
D)22
E)24
Rationale: Let a=2k, b=3k, and c=4k.
a+b+c = 2k+3k+4k = 9k
Since the average is 27:
9k/3 = 27
3k = 27
k=9
Then a=18.
The answer is A.
Answer: A
Question: A train speeds past a pole in 15 seconds and a platform 100 m long in 25 seconds. Its length is?
Options:
A)188 m
B)876 m
C)251 m
D)150 m
E)145 m
Rationale: Let the length of the train be x meters and its speed be y m/sec.
They, x / y = 15 => y = x/15
x + 100 / 25 = x / 15
x = 150 m.
Answer: D
Answer: D
Question: According to a survey, at least 55% of people like apples, at least 75% like bananas and at least 80% like cherries. What is the minimum percentage of people who like all three?
Options:
A)10%
B)20%
C)25%
D)0%
E)35%
Rationale: To minimize the percentage who like all three, let's maximize the percentage who like 2 out of 3.
80% like cherries and 20% don't like cherries.
Let's combine this with the people who like bananas.
20% don't like cherries but do like bananas.
55% like cherries and bananas.
25% like cherries but not bananas.
Now let's distribute the people who like apples.
20% like bananas and apples, but not cherries.
25% like cherries and apples, but not bananas.
10% like all three.
45% like cherries and bananas, but not apples.
The answer is A.
Answer: A
Question: If 76 is divided into four parts proportional to 7,5,3,4, then the smallest part is
Options:
A)17
B)15
C)16
D)19
E)12
Rationale: Given ratio=7:5:3:4
Sum of ratio trems =19
Smallest part=(76x3/19)=12
ANSWER E 12
Answer: E
Question: The positive integers p and q leave remainders of 2 and 3, respectively, when divided by 6. p > q. What is the remainder when p – q is divided by 6?
Options:
A)5
B)4
C)3
D)2
E)1
Rationale: Let's test out some values of p and q that satisfy the given information.
p leaves are remainder of 2 when divided by 6
So, p COULD equal 8
q leaves are remainder of 3 when divided by 6
So, q COULD equal 3
What is the remainder when p – q is divided by 6?
So, p - q = 8 - 3 = 5, and when we divide 5 by 6, we get 0 with remainder 5
Answer: A
Answer: A
Question: A student can select one of 10 different math book, one of 3 different chemistry book & one of 4 different science book.In how many different ways students can select book of math, chemistry & science.
Options:
A)22
B)72
C)99
D)37
E)120
Rationale: 10C1×3C1×4C1 = 10x3x4=120 ways
Answer:E
Answer: E
Question: Simplify: 0.2*0.4+0.6*0.8
Options:
A)0.52
B)0.42
C)0.48
D)0.64
E)0.56
Rationale: Given exp. = 0.2*0.4+(0.6*0.8) = 0.08+0.48 = 0.56
Answer is E.
Answer: E
Question: Find the number of factors W of 180 that are in the form (4*k + 2), where k is a non-negative integer?
Options:
A)1
B)2
C)3
D)4
E)W=6
Rationale: As for the question, the most straightforward way is to list out the factors (this is fine for this question as 180 is a relatively small number). Number of factors of 180 W(=2^2*3^2*5) = 18. So listing the factors gives us:
1, 180
2, 90
3, 60
4, 45
5, 36
6, 30
9, 20
10, 18
12, 15
As the question asks us about the factors of the form 4k+2 ---> eliminate all ODD factors. You are now left with
2,4,6,10,12,18,20,30,36,60,90,180
For the form 4k+2, the first few values are 2, 6, 10, 14, 18, 22, 26, 30 ... already giving you 5 factors (=2,6,10,18,30). You can stop here and mark 6 (6th one = 90) as the correct answer as 5 is not given.
For checking any particular factor whether they conform to the form 4k+2---> do the following
4k+2 = 36 ---> 4k = 34 --> this will NOT give you an integer value for k ---> reject. Proceed with others until you find all the values asked.
E is thus the correct answer.
Answer: E
Question: To complete a work A and B takes 8 days, B and C takes 12 days, A,B and C takes 6 days. How much
time A and C will take
Options:
A)24 days
B)16 days
C)12 days
D)8 days
E)None of these
Rationale: Explanation:
A+B 1 day work = 1/8
B+C 1 day work = 1/12
A+B+C 1 day work = 1/6
We can get A work by (A+B+C)-(B+C)
And C by (A+B+C)-(A+B)
So A 1 day work =
16−112=112
Similarly C 1 day work =
16−18=4−324=124
So A and C 1 day work =
112+124=324=18
So A and C can together do this work in 8 days
Answer: D
Answer: D
Question: The current birth rate per certain number of people is 32, whereas corresponding death rate is 11 per same number of people. If the net growth rate in terms of population increase is 2.1 percent, find number of persons.(initally)
Options:
A)1000
B)10000
C)100
D)2000
E)20000
Rationale: Sol.
Net growth on X = (32- 11) =21.
Net growth on 100 = (21/X Ã— 100)% = 2.1%. Then X = 1000
Answer:A
Answer: A
Question: A and B together can do a piece of work in 10 days. B alone can finish it in 20 days. In how many days can A alone finish the work ?
Options:
A)10
B)20
C)21
D)22
E)23
Rationale: Time taken by A to finish the work = XY/(Y-X)
= 10 x 20 / (20-10)
= 200/10
= 20 days
ANSWER : OPTION B
Answer: B
Question: 5358 x 52 = ?
Options:
A)273762
B)278616
C)273298
D)273258
E)277382
Rationale: B
5358 x 52 = 5358 x (50 + 2)
= 5358 x 50 + 5358 x 2
= 267900 + 10716
= 278616.
Answer: B
Question: A can do a piece of work in 12 days which B can do in 12 days. B worked at it for 9 days. A can finish the remaining work in ?
Options:
A)3 days
B)5 days
C)6 days
D)7 days
E)11 days
Rationale: B's 9 day's work = 9 x (1/12) = 3/4
Remaining work = (1 - 3/4) = 1/4
1/4 work is done by A in = 12 x (1/4) = 3 days.
answer : A
Answer: A
Question: A reduction of 25% in the price of oil enables a house wife to obtain 5kgs more for Rs.700, what is the reduced price for kg?
Options:
A)35
B)60
C)70
D)80
E)20
Rationale: A
700*(25/100) = 175 ---- 5
? ---- 1 => Rs.35
Answer: A
Question: In the first 10 overs of a cricket game, the run rate was only 3.8. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
Options:
A)4.25
B)5
C)6.1
D)7
E)7.5
Rationale: Required run rate = 282 - (3.8 x 10) =	244
244/40= 6.1
C)
Answer: C
Question: By selling 12 toffees for a dollar, a man loses 20%. How many for a should dollar be sell to get a gain of 20%?
Options:
A)23
B)12
C)78
D)2
E)8
Rationale: E
S.P. of 12 toffees be $ x.
Then, 80:1 = 120:x or x = 120/180 = 3/2
For $ 3/2, toffees sold = 12.
For Re. 1, toffees sold = 12 * 2/3 = 8
Answer: E
Question: The average age of 20 students in a class is 15 years. If the age of teacher is also included, the average becomes 16 years, find the age of the teacher.
Options:
A)35
B)38
C)45
D)36
E)60
Rationale: Explanation:
If teacher's age is 15 years, there is no change in the average. But teacher has contributed 1 year to all the students along with maintaining his age at 16.
Age of teacher = Average age of all + Total increase in age
= 16 + (1 x 20 ) = 36 years
Answer:D
Answer: D
Question: A, B and C run around a circular track starting from the same point simultaneously and in the same direction at speeds of 4 kmph, 6 kmph and 8 kmph respectively. If the length of the track is 400 meters, when will A, B and C meet at the starting point for the first time after they started the race?
Options:
A)1 minute
B)5 minutes
C)12 minutes
D)20 minutes
E)24 minutes
Rationale: 4 kmph, 6 kmph and 8 kmph is equal to 4000/60 mtrs/min, 6000/60 mtrs/min and 8000/60 mtrs/min or 200/3, 100, 400/3 mtrs/min respectively.
Seeing this we can infer that the answer should be at least divisible by 3. (minutes in options are integers. So if the answer is not divisible by 3, we will have 200/3*answer = distance traveled by A in fractions whereas 100*answer = distance traveled by A as integer)
So, A,B and D are out.
At 12 min A,B and C will travel 800, 1200 and 1600 mtrs respectively. Length of the circle is given as 400 mtrs.
As 800, 1200 and 1600 are divisible by 400, we can say that A,B and C will be at starting point after 12 min.
Hence, C will be the answer.
Answer: C
Question: There is a unique number which when multiplied by any number from 1 to 6, we will get the new number that contains same digits only.Can you find that number ?
Options:
A)142857
B)135957
C)123354
D)114457
E)133257
Rationale: 142857 * 1 = 142857
142857 * 2 = 285714
142857 * 3 = 428571
142857 * 4 = 571428
142857 * 5 = 714285
142857 * 6 = 857142
These number are considered as cyclic numbers.
correct answer is A)142857
Answer: A
Question: The area of a sector of a circle of radius 5 cm formed by an arc of length 3.5 cm is?
Options:
A)8.78
B)8.67
C)8.75
D)8.98
E)8.28
Rationale: (5 * 3.5)/2
= 8.75
Answer:C
Answer: C
Question: A man traveled a total distance of 1800 km. He traveled one-third of the whole trip by plane and the distance traveled by train is three-fifth of the distance traveled by bus. If he traveled by train, plane and bus, then find the distance traveled by bus?
Options:
A)450 km
B)850 km
C)1200 km
D)750 km
E)None of these
Rationale: Total distance traveled = 1800 km.
Distance traveled by plane = 600 km.
Distance traveled by bus = x
Distance traveled by train = 3x/5
=> x + 3x/5 + 600 = 1800
=> 8x/5 = 1200 => x = 750 km.
ANSWER:D
Answer: D
Question: Of the 3,600 employees of Company X, 1/3 are clerical. If the clerical staff were to be reduced by 1/6, what percent of the total number of the remaining employees would then be clerical?
Options:
A) 25%
B) 22.2%
C) 20%
D) 29.4%
E) 11.1%
Rationale: Welcome, just post the question and the choices
Let's see, the way I did it was
1/3 are clerical out of 3600 so 1200 are clerical
1200 reduced by 1/6 is 1200*1/6
so it reduced 200 people , so there is 1000 clerical people left
but since 200 people left, it also reduced from the total of 3600 so there are 3400 people total
since 1000clerical left / 3400 people total
you get (A) 29.4%
Answer : D
Answer: D
Question: 3 buffaloes eat as much as 4 cows or 2 oxen. At a farm there are 15 buffaloes, 8 oxen and 24 cows. The fodder for these cattle is available for 24days. If 8 more cows & 9 more buffaloes are brought in, how long will the fodder last?
Options:
A)11
B)12
C)14
D)18
E)21
Rationale: Sol. 2 oxen = 3 buffaloes = 4 cows 8 oxen = 16 cows and 15 buffaloes = 20 cows 16 cows + 20 cows + 24 cows = 60 cows Since fodder is available for 60 cows for 24 days
So fodder will be available for (60 + 8 + 12) = 80 cows c 24x60 .0 .
for-^—=18 days.
D
Answer: D