divelab/Sys2Bench huggingface dataset:
Question: Joshua and Jose work at an auto repair center with 2 other workers. For a survey on health care insurance, 2 of the 6 workers will be randomly chosen to be interviewed. What is the probability that Joshua and Jose will both be chosen?
Options:
A)1/15
B)1/12
C)1/9
D)1/6
E)1/3
Rationale: Two Methods
1) Probability of chosing Josh first = 1/4
Probability of chosing Jose second = 1/3
total = 1/12
Probability of chosing Jose first = 1/4
Probability of chosing Josh second = 1/3
Total = 1/12
Final = 1/12 + 1/12 = 1/6
D
Answer: D
Question: The average of 7 numbers is 25. If each number be multiplied by 5. Find the average of new set of numbers?
Options:
A)A)110
B)B)122
C)C)120
D)D)125
E)E)145
Rationale: Explanation:
Average of new numbers = 25 * 5 = 125
Answer: Option D
Answer: D
Question: Solve 2log53 X log9x + 1 = log53
Options:
A)3/5
B)4/5
C)4
D)4/6
E)5
Rationale: Solution:
We can rewrite the above equation in the below format
=> log532 X log9x = log53 - 1
=> log59 X log9x = log53 - log55
=> log59 X log9x = log5(3/5)
By Using the change of base rule in Left side we get
=> log5x = log5(3/5)
The value of X = 3/5
ANSWER IS A
Answer: A
Question: The perimeter of a semi circle is 144 cm then the radius is?
Options:
A)22
B)28
C)98
D)37
E)13
Rationale: 36/7 r = 144
=> r
= 28
Answer: B
Answer: B
Question: If log1087.5 = 2.9421, then the number of digits in (875)10 is?
Options:
A)30
B)28
C)27
D)26
E)40
Rationale: X = (875)10 = (87.5 x 10)10
Therefore, log10X = 10(log2087.5 + 1)
= 10(2.9421 + 1)
= 10(3.9421) = 39.421
X = antilog(39.421)
Therefore, number of digits in X = 40.
ANSWER:E
Answer: E
Question: The volumes of two cubes are in the ratio 27: 125, what shall be the ratio of their surface areas?
Options:
A)9:22
B)9:20
C)9:25
D)9:26
E)9:21
Rationale: a13 : a23 = 27 : 125
a1 : a2 = 3 : 5
6 a12 : 6 a22
a12 : a22 = 9:25
Answer:C
Answer: C
Question: For every positive odd integer n, the function h(n) is defined to be the product of all the odd integers from 1 to n, inclusive. If p is the smallest prime factor of h(100) +1, then p is?
Options:
A)between 1 and 20
B)between 10 and 20
C)between 20 and 30
D)between 30 and 40
E)1
Rationale: h(100) will have 0 in its unit digit because while doing the calculation of the function we are multiplying by 10 (and 100). So h(100)+1 will have 1 in the units digit so smallest prime factor is 1.
Answer: E
Answer: E
Question: Set S consists of numbers 2, 3, 6, 48, and 164. Number K is computed by multiplying one random number from set S by one of the first 10 non-negative integers, also selected at random. If Z=6^K, what is the probability that 678,463 is not a multiple of Z?
Options:
A)10%
B)25%
C)50%
D)90%
E)100%
Rationale: Probability of any random number being picked from set S = 1
Probability of kk not being 0 = 9/10 ( as there are total of 10 ways to pick up k and 9 ways for k not being 0)
Since it's an AND event , we will multiply the probabilities of both the events.
Hence total probability = 1∗9/10=90%. Answer:D
Answer: D
Question: In a certain game, a player begins with a bag containing tiles numbered 1 through 15, each of which has an equal probability of being selected. The player draws one tile. If the tile is even, the player stops. If not, the player draws another tile without replacing the first. If this second tile is even, the player stops. If not, the player draws a third tile—without replacing either of the first two tiles—and then stops. What is the probability that at the conclusion of the game, the sum of the tiles that the player has drawn is odd?
Options:
A)5/18
B)13/36
C)3/8
D)5/8
E)23/36
Rationale: player begins with containing tiles 1 to 10 and have equal probability of selecting means
Proabability of selecting one number =1/10. here 5 even numbers and 5 odd numbers are there.
Next , player draws one title , if number is even player stops or otherwise title is odd without replacement
player draws second title.
If second title is even , player stops or title is odd without replacement player draws third title.
in third title , without replacement of first and second title, player draws and stops it.
the sum of tilte probability is odd. here two conditions are possible.
1st condition is
1st title is odd+ 2nd title is even stops= probability of selecting one title is 1/10*5c1.
Here are we are not selecting 1st condition as even stops because sum of tile is odd.
Here 5 odd numbers are there we can select 1out of 5 odd numbers.
without replacement of fist we select second tilte is even. is 5/10*5c1/9c1.
here we are selecting one number out of remaining 9 numbers. so probability is 5/18.
we are selecting 1 even number out of 5.
2nd condition is 1stodd without replacement,2nd odd without replacement and 3rd one also odd to get odd as sum of title.
Then probability is 5/10*4/9*3/8=1/12.
Finally sum of probability of two conditions is 5/18+1/12
=23/36.
so option E is correct.
Answer: E
Question: A 45° -45° - 90° right triangle has hypotenuse of length h. What is the area Q of the triangle in terms of h?
Options:
A)h/ √2
B)h/2
C)h/4
D)(h)^2
E)(h)^2/4
Rationale: IF...each of the two shorter sides = 3, then the hypotenuse = H = 3(root2).
The AREA Q= (1/2)(Base)(Height) = (1/2)(3)(3) = 9/2.
So we're looking for an answer that = 9/2 when H = 3(root2). There's only one answer that matches...
E
Answer: E
Question: HCF and LCM two numbers are 12 and 396 respectively. If one of the numbers is 36, then the other number is?
Options:
A)36
B)66
C)132
D)264
E)152
Rationale: 12 * 396 = 36 * x
x = 132
ANSWER:C
Answer: C
Question: 3 pumps, working 8 hours a day, can empty a tank in 2 days. How many hours a day must 8 pumps work to empty the tank in 1 day?
Options:
A)6
B)10
C)11
D)12
E)13
Rationale: 3 pumps take 16 hrs total (8 Hrs a day)
If 1 pump will be working then, it will need 16*3=48 hrs
1 pump need 48 Hrs
If I contribute 8 pumps then
48/8=6 hrs.
answer :A
Answer: A
Question: A bus leaves Los Angeles at 9:00 a.m. traveling north at 50 miles per hour. At 11:00 a.m. a plane leaves Los Angeles traveling north at 200 miles per hour. At what time will the plane overtake the bus?
Options:
A)11:40 a.m.
B)12:15 p.m.
C)10:00 a.m.
D)11:25 a.m.
E)10:40 a.m.
Rationale: At 11:00am, the bus is 100 miles ahead of plane
The plane travels at 200 mph, which gains 150 mph on bus
100/250=2/5 hours = 40 minutes
11:00 + 0:40 = 11:40
The plane will overtake bus at 11:40am
Answer:A
Answer: A
Question: What is the smallest no. that should be added to 31110 to make it exactly divisible by 9?
Options:
A)1
B)3
C)5
D)6
E)9
Rationale: If a number is divisible by 9, the sum of its digits must be a multiple of 9.
Here, 3+1+1+1+0=6, the next multiple of 9 is 9.
3 must be added to 31110 to make it divisible by 9
B
Answer: B
Question: An bus covers a certain distance at a speed of 240 kmph in 5 hours. To cover the samedistance in 1hr, it must travel at a speed of?
Options:
A)600 km/hr
B)720 km/hr
C)730 km/hr
D)750 km/hr
E)760 km/hr
Rationale: Distance = (240 x 5) = 1200 km.
Speed = Distance/Time
Speed = 1200/(5/3) km/hr. [We can write 1 hours as 5/3 hours]
Required speed = 1200 x 3 km/hr = 720 km/hr.
B
Answer: B
Question: The below sequence is a bit tricky. Can you solve it to find the next number?
8, 28, 328, 4328, ?
Options:
A)29816
B)38291
C)54325
D)38290
E)54328
Rationale: See the pattern. With every digit, the previous numbers are added after that digit
So the next number in the series is 54328
Answer : E
Answer: E
Question: The length of the bridge, which a train 130 m long and traveling at 45 km/hr can cross in 30 sec is?
Options:
A)300
B)230
C)245
D)250
E)260
Rationale: Speed = 45 * 5/18 = 25/2 m/sec.
Time = 30 sec
Let the length of bridge be x meters.
Then, (130 + x)/30 = 25/2
x = 245 m.
Answer: Option C
Answer: C
Question: The curved surface of a sphere is 64 π cm2. Find its radius?
Options:
A)9
B)8
C)4
D)5
E)6
Rationale: 4 πr2 = 64 => r = 4
Answer:C
Answer: C
Question: A card is drawn at random from a pack of 52 cards. What is the probability that it is neither a spade nor a jack?
Options:
A)9/13
B)4/13
C)2/13
D)6/13
E)5/13
Rationale: There are 13 spades including a jack and 3 more jacks of other suits.
Probability of getting spade or a jack:
= (13 + 3)/52
= 16/52
= 4/13
Therefore, the probability of getting neither a spade nor a jack:
= 1 − 4/13
= 9/13
ANSWER:A
Answer: A
Question: At a contest with 3000 participants, 1/2 of the people are aged 8 to 14. Next year, the number of people aged 8 to 14 will increase by 1/6. After this change, what percentage of the total 3000 people will the 8- to 14-year-olds represent?
Options:
A)53.33%
B)50%
C)58.33%
D)55.33%
E)68%
Rationale: I just wanted to mention a couple of things here:
* this is a pure ratio question; the number 3000 is completely irrelevant, and you can ignore it if you like. When we increase something by 1/6, we are multiplying it by 1 + 1/6 = 7/6, so the answer here must be (1/2)*(7/6) = 7/12 = 58.33 %.
Answer : C
Answer: C
Question: Strawberries are purchased for $5/lb at the Farmer's Market. 4/5 of the strawberries will be used for making jam (1/5 of strawberries are rotten and thrown out). The strawberries are crushed and 1 lb of strawberries produces 2 cups of strawberry juice which is mixed with sugar to make the jam. If 3 cups of strawberry juice can make one jar of jam, how much money is needed to buy strawberries to make x number of jars of jam, in dollars?
Options:
A)2x
B)75x/8
C)8x/15
D)2x/3
E)x/2
Rationale: Initial cost for 1 lb = $5, but ONLY 4/5 is used.
So the cost of 4/5 lb = $5, or 1 lb = $25/4,
and 1 lb of strawberries produces 2 cups of strawberry juice,so 2 cups of strawberry juice costs $25/4, but 3 cups are needed for 1 jar, so cost of 3 cups = $(25/4)(3/2) = $75/8.
If 1 jar costs $75/8, x number of jars will cost $75x/8..
Answer is B
Answer: B
Question: The parameter of a square is double the perimeter of a rectangle. The area of the rectangle is 480 sq cm. Find the area of the square?
Options:
A)398
B)379
C)237
D)480
E)111
Rationale: Let the side of the square be a cm. Let the length and the breadth of the rectangle be l cm and b cm respectively.
4a = 2(l + b)
2a = l + b
l . b = 480
We cannot find ( l + b) only with the help of l . b. Therefore a cannot be found .
Area of the square cannot be found.
Answer: D
Answer: D
Question: The tax on a commodity is diminished by 20% but its consumption is increased by 10%. Find the decrease percent in the revenue derived from it?
Options:
A)62%
B)18%
C)72%
D)12%
E)13%
Rationale: 100 * 100 = 10000
80 * 110 = 8800
10000------- 1200
100 ------- ? = 12%
Answer: D
Answer: D
Question: If N is a positive integer and 14N/60 is an integer. What is the smallest Value of N for which N has exactly four different prime factors.?
Options:
A)30
B)60
C)180
D)210
E)cannot be determined
Rationale: 14N/60 tells us that N must be multiple of 30.
Or N has at least 2 *3 * 5 in it.
To find out the smallest value of N such that it has 4 different prime factors, we will multiple 30 with next smallest prime factor which is 7 here.
So, Least value of N is 30 *7 =210 .
ANSWER:D
Answer: D
Question: The decimal 0.1 is how many times greater than the decimal (0.01)^4?
Options:
A)10^5
B)10^6
C)10^7
D)10^8
E)10^9
Rationale: 0.1 = 10^-1
(0.01)^4 = (10^-2)^4 = 10^-8
10^7 * 10^-8 = 10^-1
The answer is C.
Answer: C
Question: A graph may be defined as a set of points connected by lines called edges. Every edge connects a pair of points. Thus, a triangle is a graph of 3 edges and 3 points. The degree of a point is the number of edges connected to it. For, example, a triangle is a graph with 3 points of degree 2 each. Consider a graph with 12 points. It is possible to reach any point from any through sequence of edges. The number of edges 'e' in the graph must satisfy the condition
Options:
A)11 ≤ e ≤ 66
B)10 ≤ e ≤ 66
C)11 ≤ e ≤ 65
D)0 ≤ e ≤ 11
E)None
Rationale: Explanation :
The least number of edges will be when one point is connected to each of the other 11 points, giving a total of 11 lines. One can move from any point to any other point via the common point.
The maximum edges will be when a line exists between any two points. Two points can be selected from 12 points in 12C2 i.e. 66 lines.
Answer : A
Answer: A
Question: A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Options:
A)177 m
B)176 m
C)240 m
D)187 m
E)186 m
Rationale: Speed = [54 * 5/18] m/sec = 15 m/sec.
Length of the train = (15 * 20) m = 300 m.
Let the length of the platform be x meters.
Then, x + 300 / 36 = 15
x + 300 = 540
x = 240 m.
Answer: C
Answer: C
Question: If m and n are positive integers such that m is a factor of n, how many positive multiples of m are less than or equal to 2n ?
Options:
A)2m/n + 1
B)2n/m + 1
C)2n/(m+1)
D)2m/n
E)2n/m
Rationale: Lets say N=10, M=5
2N=20. so the answer should be 4 (20/5)
lets try to plug in the answers:
A-not an integer
B-not an integer
C-not an integer
D-1 (not the answer)
E-4 - the answer. (the only one).
I would choose E.
Method 2
N=M*A (A is an integer)
So - A=N/M
therefore in 2N A will be 2N/M
Again - Answer is E.
Answer: E
Question: Jake remembers only the last three letters of his four-letter Klingon name. If he is sure that the first letter is neither "N" nor "X", and assuming that there are only 12 letters in the Klingon alphabet, what is the probability that he will give the correct name when asked for it by the space attendant?
Options:
A)A)8/100
B)B)9/100
C)C)1/8
D)D)4/5
E)E)1/10
Rationale: Total letters 12, out of which the first letter is anything of 10 but N or X...
So there are 10 possible letters for first place..
And only one of them is correct..
So 1/10.
Answer: E
Answer: E
Question: A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If three marbles are picked at random, what is the probability that they are all blue?
Options:
A)1/455
B)1/458
C)1/453
D)1/456
E)1/454
Rationale: Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles.
Probability that all the three marbles picked at random are blue
= ³C₃/¹⁵C₃ = (1 * 3 * 2 * 1)/(15 * 14 * 13)
= 1/455
Answer: A
Answer: A
Question: For any real number x, the operatoris defined as:
(x) = x(5 − x)
If p + 1 =(p + 1), then p =
Options:
A)−2
B)0
C)1
D)2
E)4
Rationale: (x) = x(5 − x)
(p + 1) = (p + 1)(5 - p - 1) = (4-p)(p+1)
We are given that p + 1 =(p + 1)
Therefore (4-p)(p+1) = (p + 1)
Or (p + 1) + (p-4)(p+1) = 0
(p + 1)(p-4) = 0
p = -1,p=4
Option E
Answer: E
Question: Last year Elaine spent 20% of her annual earnings on rent. This year she earned 20% more than last year and she spent 30% of her annual earnings on rent. The amount she spent on rent this year is what percent of the amount spent on rent last year?
Options:
A) 185.5
B) 180.0
C) 167.5
D) 172.5
E) 177.5
Rationale: For this it is easiest to use simple numbers. Let's assume that Elaine's annual earnings last year were $100.
She would've spent $20 of this on rent.
This year she earned 20% more, or $120
She would've spent 30% of this on rent, or $36
Do $36/$20
This will give you 180%
B is the correct answer.
Answer: B
Question: A train crosses a platform of 150 m in 15 sec, same train crosses another platform of length 250 m in 20 sec. then find the length of the train?
Options:
A)150m
B)157m
C)750m
D)850m
E)350m
Rationale: Length of the train be ‘X’
X + 150/15 = X + 250/20
4X + 600 = 3X + 750
X = 150m
Answer:A:
Answer: A
Question: Calculate the average of all the numbers between 10 and 86 which are divisible by 9.
Options:
A)49.5
B)41.5
C)45.5
D)40.5
E)47.5
Rationale: Explanation:
numbers divisible by 9 are 18,27,36,45,54,63,72,81,
Average = (18+27+36+45+54+63+72+81,) / 8 = 396/8 = 49.5
ANSWER: A
Answer: A
Question: Two stations P and Q are 200 km apart on a straight track. One train starts from P at 7 a.m. and travels towards Q at 20 kmph. Another train starts from Q at 8 a.m. and travels towards P at a speed of 25 kmph. At what time will they meet?
Options:
A)10 am
B)12 noon
C)10.30 am
D)12.30 am
E)11 am
Rationale: Assume both trains meet after x hours after 7 am
Distance covered by train starting from P in x hours = 20x km
Distance covered by train starting from Q in (x-1) hours = 25(x-1)
Total distance = 200
=> 20x + 25(x-1) = 200
=> 45x = 225
=> x= 5
Means, they meet after 5 hours after 7 am, ie, they meet at 12 noon
Answer is B.
Answer: B
Question: A tank is 25m long 12m wide and 6m deep. The cost of plastering its walls and bottom at 55 paise per sq m is
Options:
A)Rs. 209.20
B)Rs. 309.20
C)Rs. 409.20
D)Rs. 509.20
E)None of these
Rationale: Explanation:
Area to be plastered = [2(l + b) Ã— h] + (l Ã— b)
= [2(25 + 12) Ã— 6] + (25 Ã— 12) = 744 sq m
Cost of plastering = 744 Ã— (55/100) = Rs. 409.20 Answer: C
Answer: C
Question: Working at a constant rate, P can finish a job in 3 hours. Q, also working at a constant rate, can finish the same job in 15 hours. If they work together for 2 hours, how many more minutes will it take P to finish the job, working alone at his constant rate?
Options:
A)30
B)36
C)40
D)45
E)48
Rationale: Each hour they complete 1/3 + 1/15 = 2/5 of the job.
In 2 hours, they complete 2(2/5) = 4/5 of the job.
The time for P to finish is (1/5) / (1/3) = (3/5) hour = 36 minutes
The answer is B.
Answer: B
Question: A money lender lends Rs.2000 for six months at 20% p.a. rate. It the interest is reckoned quarterly than find the amount given after time limit?
Options:
A)2205
B)2229
C)2205
D)2984
E)2223
Rationale: A = 2000(21/20)2
= 2205
Answer:A
Answer: A
Question: Find the least number of five digits which is exactly divisible by 12 and 18?
Options:
A)A)1080
B)B)10080
C)C)10025
D)D)11080
E)E)12080
Rationale: The smallest five digit numbers are
10025,10080,11080
10025 is not divisible by 12
10080 is divisible by both 12 and 18
ANSWER:B
Answer: B
Question: A, B and C invest in a partnership in the ratio: 7/2, 4/3, 6/5. After 4 months, A increases his share 50%. If the total profit at the end of one year be Rs. 22,140, then what is B's share in the profit?
Options:
A)Rs. 2000
B)Rs. 3100
C)Rs. 4100
D)Rs. 5200
E)None of these
Rationale: Explanation :
Ratio of the initial investment = 7/2 : 4/3 : 6/5
= 105 : 40 : 36
From this ratio, we can assume that actual initial investments of A, B and C
are 105x, 40x and 36x respectively
A increases his share 50% after 4 months. Hence the ratio of their investments =
(105x * 4) + (105x * 150/100 * 8) : 40x * 12 : 36x : 12
= 105 + (105 * 3/2 * 2) : 40*3 : 36 * 3
= 105 * 4 : 40 *3 : 36 * 3
= 35 * 4 : 40 : 36
= 35 : 10 : 9
B's share = total profit * (10/54) = 22,140 * 10/54 = 4100. Answer : Option C
Answer: C
Question: Which number, when found in the denominator of any given fraction, gives a terminating decimal?
Options:
A)75
B)80
C)85
D)90
E)95
Rationale: 75 = 3 * 5 * 5; 80 = 2^4 * 5; 85 = 5 * 17; 90 = 2 * 3^2 * 5; 95 = 5 * 19.
Only Option B has 2 and 5 as factors, hence terminating.
Option B.
Answer: B
Question: an article with cost price of 180 is sold at 15% profit. what is the selling price?
Options:
A)198
B)200
C)204
D)207
E)210
Rationale: sp=1.15*180=207
ANSWER:D
Answer: D
Question: Anup start a bike at 6am. and rides it at 60kmph. Raghu started at 7pm with his car at 120kmph. When will Raghu overtake Anup?
Options:
A)8:00am
B)9:40am
C)10:00am
D)12:00pm
E)11:10am
Rationale: Suppose bike is overtaken by car xhrs after 6am
Distance covered by the bike in x hrs = distance covered by the car in x-1 hr
60x = 120(x-1)
60x = 120
x = 2 hrs
Required time = 6+2 = 8:00am
Answer is A
Answer: A
Question: The ratio of the volumes of two cubes is 729 : 1331. What is the ratio of their total surface areas?
Options:
A)81:121
B)81:131
C)81:145
D)81:167
E)81:113
Rationale: Ratio of the sides
= ³√729 : ³√1331 = 9 : 11
Ratio of surface areas
= 92 : 112 = 81:121
Answer:A
Answer: A
Question: The sum of three consecutive multiples of 3 is 99. What is the largest number?
Options:
A)36
B)33
C)30
D)27
E)24
Rationale: Let the numbers be 3x, 3x + 3 and 3x + 6.
Then,
3x + (3x + 3) + (3x + 6) = 99
9x = 90
x = 10
Largest number = 3x + 6 = 36
Answer : A
Answer: A
Question: Find the average of the series : 4555,250,355,450,150
Options:
A)129
B)1152
C)267
D)207
E)174
Rationale: Average = (4555+250+355+450+150)/5
= 5760/5
= 1152
Answer: B
Answer: B
Question: If x is a positive integer, then the least value of x for which x! is divisible by 1,000,0000 is?
Can someone please explain intuitively what the question is asking?
Options:
A)5
B)9
C)25
D)15
E)30
Rationale: In order x! to be divisible by 1,000, it should have at least 3 trailing zeros. A trailing 0 in factorial of a number is produced by 2 and 5 in it: 2*5 = 10. So, we need 10 to be in x! at least in power of 3.
5! = 120 has 1 trailing zeros.
10! will have 2 trailing zeros.
15! will have 3 trailing zeros.
20! will have 5 trailing zeros.
25! will have 7 trailing zeros. C
Answer: C
Question: population is 20000. Pop increases by 10% every year, then the pop after 3 years is?
Options:
A)26630
B)26640
C)36620
D)26620
E)26820
Rationale: population after 1st year = 20000*10/100 = 2000 ===> 20000+2000 = 22000
population after 2nd year = 22000*10/100 = 2200 ===> 22000+2200 = 24200
population after 3rd year = 24200*10/100 = 2420 ===> 24200+2420 = 26620
ANSWER:D
Answer: D
Question: The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
Options:
A)288
B)66
C)245
D)77
E)29
Rationale: Speed = [45 X 5/18] m/sec = [25/2] m/sec Time = 30 sec Let the length of bridge be x metres. Then, (130 + x)/30 = 25/2 => 2(130 + x) = 750 => x = 245 m.Answer: C
Answer: C
Question: The value of (4 3) + 2 is
Options:
A)33
B)10
C)14
D)24
E)11
Rationale: Evaluating, (4 3) + 2 = 12 + 2 = 14.
correct answer C
Answer: C
Question: A train crosses a platform of 150 m in 15 sec, same train crosses another platform of length 250 m in 20 sec. then find the length of the train?
Options:
A)150
B)878
C)277
D)992
E)187
Rationale: Length of the train be ‘X’
X + 150/15 = X + 250/20
4X + 600 = 3X + 750
X = 150m
Answer: A
Answer: A
Question: A train ,125 meters long travels at a speed of 45 km/hr crosses a bridge in 30 seconds. The length of the bridge is
Options:
A)250 m
B)245 m
C)235 m
D)220 m
E)240 m
Rationale: Explanation:
Assume the length of the bridge = x meter
Total distance covered = 125+x meter
total time taken = 30s
speed = Total distance covered /total time taken = (125+x)/30 m/s
=> 45 Ã— (10/36) = (125+x)/30
=> 45 Ã— 10 Ã— 30 /36 = 125+x
=> 45 Ã— 10 Ã— 10 / 12 = 125+x
=> 15 Ã— 10 Ã— 10 / 4 = 125+x
=> 15 Ã— 25 = 125+x = 375
=> x = 375-125 =250
Answer: Option A
Answer: A
Question: Three partners A,B and C invest Rs.18000, Rs.22500 and Rs.27000 respectively in a business. If total profit is Rs.18750 then B's share is (in Rs.)
Options:
A)10000
B)6250
C)5000
D)7500
E)8500
Rationale: 18000:22500:27000
4:5:6
B's share=18750*5/15=6250
ANSWER:B
Answer: B
Question: If the probability that the Chicago Bears win the Super Bowl is 1/20 and the probability that the Chicago Cubs win the World Series is 1/7, what is the probability that either the Bears win the Super Bowl or the Cub win the World Series (but not both)?
Options:
A)2/7
B)3/16
C)4/25
D)5/28
E)6/37
Rationale: 19/20*1/7 + 1/20*6/7 = 25/140 = 5/28
The answer is D.
Answer: D
Question: The credit card and a global payment processing companies have been suffering losses for some time now. A well known company recently announced its quarterly results. According to the results, the revenue fell to $52.0 billion from $69.0 billion, a year ago. By what percent did the revenue fall?
Options:
A)20.8
B)24.6
C)31.8
D)32.5
E)33.8
Rationale: $69-$52=17$
(17/69)*100=24.6%
ANSWER:B
Answer: B
Question: What day of the week was 1 January 1701
Options:
A)Tuesday
B)Monday
C)Friday
D)Saturday
E)Sunday
Rationale: Explanation:
1 Jan 1701 = (1700 years + 1st Jan 1701)
We know that number of odd days in 400 years = 0
Hence the number of odd days in 1600 years = 0 (Since 1600 is a perfect multiple of 400)
Number of odd days in the period 1601-1700
= Number of odd days in 100 years
= 5
(As we can reduce perfect multiples of 7 from odd days without affecting anything)
1st Jan 1701 = 1 odd day
Total number of odd days = (0 + 5 + 1) = 6
6 odd days = Saturday
Hence 1 January 1701 is Saturday.
Answer: Option D
Answer: D