divelab/Sys2Bench huggingface dataset:
Question: Find compound interest on $ 10000 at 15% per annum for 2 years 4 months, compounded annually.
Options:
A)3886.25
B)3286.25
C)3186.25
D)3386.25
E)3586.25
Rationale: Time = 2 years 4 months = 2(4/12) years = 2(1/3) years.
Amount = $ [10000 X (1+­(15/100))2 X (1+((1/3)*15)/100)]
=$ [10000 * (23/20) * (23/20) * (21/20)]
= $ 13886.25	.
:. C.I. = Rs. (13886.25 -10000) = $ 3886.25
Answer A.
Answer: A
Question: The ratio between x and y is 8/5; x is increased by 10 and y is multiplied by 10 , what is the ratio between the new values of x and y?
Options:
A)8/5
B)5/8
C)1
D)10
E)It Cannot Be Determined
Rationale: Ratio = 8k/5k = 8/5, 16/10, etc.
x and y are decreased by 5 --> (8k + 10)/(5k * 10)
New ratio can be 18/50, 26/100, etc.
Answer: E
Answer: E
Question: The lenght of a room is 5.5 m and width is 4 m. Find the cost of paving the floor by slabs at the rate of Rs. 750 per sq. metre.
Options:
A)s. 15,550
B)s. 15,600
C)s. 16,500
D)s. 17,600
E)s. 17,900
Rationale: Area of the floor = (5.5 Ã— 4) m2 = 22 m2.
Cost of paving = Rs. (750 Ã— 22) = Rs. 16500
.
Answer: Option C
Answer: C
Question: How long does a train 100 m long running at the speed of 65 km/hr takes to cross a bridge 145 m length?
Options:
A)13.6 sec
B)12.1 sec
C)17.9 sec
D)61.9 sec
E)47.98 sec
Rationale: Speed = 65 * 5/18 = 18 m/sec
Total distance covered = 100 + 145 = 245 m.
Required time = 245/18 = 13.6 sec.
Answer:A
Answer: A
Question: The slant height of a cone is 12 cm and radius of the base is 4cm, find the curved surface of the cone.
Options:
A)49 π cm2
B)40 π cm2
C)48 π cm2
D)43 π cm2
E)41 π cm2
Rationale: Explanation:
π * 12 * 4 = 48
Answer: Option C
Answer: C
Question: If P(A) = 4/5 and P (B) = 2/5, find P (A n B) if A and B are independent events.
Options:
A)7/25
B)3/25
C)8/25
D)2/13
E)3/17
Rationale: P (A n B) = P(A) . P(B)
P (A n B) = 4/5 . 2/5
P (A n B) = 8/25.
C
Answer: C
Question: Sum of three nos is 98. The ratio between 1 and 2 is 2:3. The ratio between 2 and 3 is 5:8 .
Find the second no?
Options:
A)10
B)20
C)30
D)40
E)50
Rationale: x+y+z=98
x/y=2/3
x=2y/3
and
y/z=5/8
z=8y/5 subtitute this is x and z
2y/3+y+8y/5=98
y=30
ANSWER:C
Answer: C
Question: Kaushalya can do a work in 20 days, while kaikeyi can do the same work in 25 days. They started the work jointly.Few days later Sumitra also joined them and thus all of them completed the whole work in 10 days. All of them were paid total Rs.700. What is the Share of Sumitra?
Options:
A)Rs.130
B)Rs.185
C)Rs.70
D)can't be determined
E)None of these
Rationale: Explanation:
Efficiency of kaushalya = 5%
Efficiency of kaikeyi = 4%
Thus, in 10 days working together they will complete only 90% of the work.
[(5 + 4) × 10] =90
Hence, the remaining work will surely done by sumitra, which is 10%.
Thus, sumitra will get 10% of Rs. 700, which is Rs.70
Answer: C
Answer: C
Question: Three unbiased coins are tossed. What is the probability of getting 2 Heads and 2 Tail?
Options:
A)5/8
B)1/4
C)3/8
D)7/8
E)1/8
Rationale: Let, H --> Head , T --> Tail
Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}
Let E = event of getting 3 heads
Then E = {THH,HTH,HHT,THT,TTH}
P(E) = n(E)/n(S) =5/8
Answer is A
Answer: A
Question: A tank is filled by three pipes with uniform flow. The first two pipes operating simultaneously fill the tank in the same during which the tank is filled by the third pipe alone. The second pipe fills the tank 5 hours faster than the first pipe and 4 hours slower than the third pipe. The time required by the first pipe is?
Options:
A)10
B)12
C)15
D)13
E)16
Rationale: Suppose, first pipe alone takes x hours to fill the tank. Then, second and third pipes will take (x - 5) and (x - 9) hours respectively to fill the tank.
1/x + 1/(x - 5) = 1/(x - 9)
(2x - 5)(x - 9) = x(x - 5)
x2 - 18x + 45 = 0
(x- 15)(x - 3) = 0 => x = 15
ANSWER C
Answer: C
Question: A train passes a station platform in 36 seconds and a man standing on the platform in 23 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Options:
A)877 m
B)195 m
C)167 m
D)887 m
E)265 m
Rationale: Speed = (54 * 5/18) m/sec = 15 m/sec. Length of the train
= (15 x 23)m = 345 m. Let the length of the platform be x meters. Then, (x + 345)/36 = 15
==> x + 345 = 540 ==> x
= 195 m.
Answer: B
Answer: B
Question: A man purchased a watch for Rs.400 and sold it at a gain of 20% of the selling price. The selling price of the watch is:
Options:
A)232
B)480
C)178
D)277
E)1981
Rationale: Explanation:
Cost price = 400
Gain% = 20%
Gain = 400 × 2010020100 = 80
Cost price = 400 + 80 = 480
Answer: B
Answer: B
Question: A train passes a station platform in 40 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Options:
A)180 m
B)240 m
C)260 m
D)300 m
E)380 m
Rationale: Speed = 54 x 5/18 = 15 m/s
Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
Then, (x + 300)/40 = 15
--> x + 300 = 600
x = 300m.
Answer : D.
Answer: D
Question: A family consists of two grandparents, two parents and four grandchildren. The average age of the grandparents is 70 years, that of the parents is 40 years and that of the grandchildren is 6 years. What is the average age of family?
Options:
A)8/4years
B)B)31
C)C)30
D)D)33
E)E)35
Rationale: Required average
= (70 x 2 + 40 x 2 + 6 x 4 )/(2 + 2 + 4)
= (140 + 80 + 24)/8
= 244/8
= 30 8/4years.
Answer is A
Answer: A
Question: Two goods train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one.
Options:
A)12 sec
B)24 sec
C)48 sec
D)60 sec
E)65 sec
Rationale: Explanation:
Relative speed =	= (45 + 30) km/hr
=75 x	5/18 m/sec
=125/6 m/sec
We have to find the time taken by the slower train to pass the DRIVER of the faster train and not the complete train.
So, distance covered = Length of the slower train.
Therefore, Distance covered = 500 m.
Required time =500 x	6/125 = 24 sec.
ANSWER IS B
Answer: B
Question: A chair is bought for Rs.400/- and sold at Rs.500/- find gain or loss percentage
Options:
A)15% loss
B)20% gain
C)25% gain
D)30% gain
E)35% gain
Rationale: Formula = (Selling price ~ Cost price)/Cost price * 100
= (500 - 400)/400 = 25% gain
C
Answer: C
Question: A man purchased 3 blankets @ Rs.100 each, 5 blankets @ Rs.150 each and two blankets at a certain rate which is now slipped off from his memory. But he remembers that the average price of the blankets was Rs.150. Find the unknown rate of two blankets?
Options:
A)289
B)278
C)211
D)450
E)476
Rationale: 10 * 150 = 1500
3 * 100 + 5 * 150 = 1050
1500 – 1050
= 450
Answer:D
Answer: D
Question: If √(3 + ³√x) = 2, then x is equal to :
Options:
A)1
B)2
C)4
D)8
E)12
Rationale: On squaring both sides, we get:
3 + ³√x = 4 or ³√x = 1.
Cubing both sides, we get x = (1 x 1 x 1) = 1
ANSWER:A
Answer: A
Question: A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed:
Options:
A)60 birds
B)72 birds
C)30 birds
D)80 birds
E)20 birds
Rationale: Let the total number of shots be x. Then,
Shots fired by A =(5/8)x
Shots fired by B =(3/8)x
Killing shots by A =(1/3)of	(5/8)x=(5/24)x
Shots missed by B =(1/2) of (3/8)x	=(3/16)x
3x/16= 27 or x =(27 x 16)/3= 144.
Birds killed by A =(5x/24)	=(5/24*144)= 30.
Answer is C.
Answer: C
Question: The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is:
Options:
A)542
B)540
C)591
D)567
E)548
Rationale: Required number = (L.C.M. of 12, 15, 20, 54) + 8
= 540 + 8
= 548.
Answer: Option E
Answer: E
Question: When y is divided by 288, the remainder is 45. What is the remainder when the same y is divided by 24?
Options:
A)20
B)21
C)23
D)25
E)26
Rationale: y = 288*a + 45 = (24*12)*a + 24 + 21
The answer is B.
Answer: B
Question: Which of the following is not a prime number ?
Options:
A)502
B)503
C)509
D)521
E)523
Rationale: Clearly, 502 is not a prime number.
Answer : A
Answer: A
Question: Best friends Sprite and Icey have are playing a game of marbles. They invite 10 of their friends to play with them. There are 36 marbles in the bag. If all 12 people are playing, how many marbles does each person get?
Options:
A)3
B)4
C)5
D)6
E)7
Rationale: Answer= A
36 / 12 = 3
Answer= A
Answer: A
Question: Of the families in City X in 1904, 50 percent owned a personal computer. The number of families in City X owning a computer in 1908 was 30 percent greater than it was in 1904, and the total number of families in City X was 5 percent greater in 1908 than it was in 1904. what percent of the families in City X owned a personal computer in 1908?
Options:
A)61.90%
B)52.20%
C)56.20%
D)70.45%
E)74.41%
Rationale: Say a 100 families existed in 1904 then the number of families owning a computer in 1904 - 50
Number of families owning computer in 1908 = 50 * 130/100 = 65
Number of families in 1908 = 105
The percentage = 65/105 * 100 = 61.90%.
Option: A
Answer: A
Question: A father was twelve times as old as his son twenty years back. Now he is twice as old as his son. What are their present ages?
Options:
A)Father 44 and Son 22
B)Father 35 and Son 23
C)Father 38 and Son 44
D)Father 55 and Son 22
E)None of these
Rationale: Let present age of the Son = X.
Present age of the father = 2X.
Now according to question,
2X -20 = 12*(X-20)
2X - 20 = 12X -240
10X = 220
X = 22
Present age son = 22 years,
Present age father = 2*22 = 44.
ANSWER : OPTION A
Answer: A
Question: The difference between a 4-digit number and the number formed by reversing its digit is not a multiple of
Options:
A)3
B)27
C)243
D)81
E)11
Rationale: Another approach is to TEST a number.
Let's say the original number is 2031
So, the REVERSED number is 1302
The DIFFERENCE = 2031-1302 =729
No check the answer choices
729 is a multiple of 3,27,81,243
11 is NOT a multiple of 729
Answer:E
Answer: E
Question: John found that the average of 15 no.'s is 40. If 10 is added to each number then the mean of number is?
Options:
A)50
B)55
C)65
D)72
E)78
Rationale: (x+x1+...x14)/15 = 40
50
Option A
Answer: A
Question: Of the 200 students at University XYZ majoring in one or more of the engineering disciplines, 110 are majoring in electrical and 150 are majoring in mechanical. If at least 30 of the students are not majoring in either electrical or mechanical, then the number of students majoring in both electrical and mechanical could be any number from
Options:
A)30 to 70
B)70 to 100
C)110 to 130
D)130 to 150
E)150 to 170
Rationale: if there are 110 students majoring in electrical then there must be 90 person not majoring electrical at all, since both of the student not majoring electrical and mechanical is at least 30, so the number of the student who are not majoring electrical but majoring mechanical will be at least 60.
if there are 150 students majoring in mechanical there must be 50 students who are not majoring mechanical at all, since the number of the student who are not majoring electrical but majoring mechanical will be at least 60, hence the number of students both majoring mechanical and electrical will be at least 150
so there must be at least 150 students who major in both
see the answers option the only possible answer is E !
Answer: E
Question: If the selling price of 100 articles is equal to the cost price of 63 articles, then the loss or gain percent is:
Options:
A)39%
B)36%
C)35%
D)40%
E)37%
Rationale: Let C.P. of each article be Re. 1.
Then, C.P. of 100 articles = Rs. 100;
S.P. of 100 articles = Rs. 63.
Loss % = 37/100 * 100 = 37%
ANSWER:E
Answer: E
Question: Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?
Options:
A)12
B)25
C)50
D)10
E)82
Rationale: Explanation:
Due to stoppages, it covers 9 km less.
time taken to cover 9 km=(9/54*60)min=10 min
Answer D
Answer: D
Question: During the break of a football match, the coach will make 3 substitutions. If the team consists of 12 players among which there are 2 forwards, what is the probability that none of the forwards will be substituted?
Options:
A) 21/55
B) 18/44
C) 28/55
D) 28/44
E) 36/55
Rationale: Required probability = no. of favorable outcome/ total no. of outcomes
out of 12 players any 3 can be selected in 12C3 ways
after removing 2 forwards any 3 players can be selected from the remaining 9 players in 9C3 ways
thus required probability = 9C3/12C3 =21/55=A
Answer: A
Question: 529 is a perfect square. When x is added to the square root of 529, the result is also a perfect square. What is x?
Options:
A)1
B)2
C)3
D)4
E)5
Rationale: 529 is 23*23
here
A 23+1 = 24
B 23+2 = 25
C 23+3 = 26
D 23+4 = 27
E 23+5= 28
so, B is the only addition that gives a perfect square. so x=3
then the answer is B
Answer: B
Question: Braun invested a certain sum of money at 8% p.a. simple interest for 'n' years. At the end of 'n' years, Braun got back 3 times his original investment. What is the value of n?
Options:
A)50 years
B)25 years
C)12 years 6 months
D)37 years 6 months
E)40 years
Rationale: Explanatory Answer
Let us say Braun invested $100.
Then, at the end of 'n' years he would have got back $300.
Therefore, the Simple Interest earned =300 - 100 = $200.
We know that Simple Interest = (Principal * number of years * rate of interest) / 100
Substituting the values in the above equation we get 200 = (100 * n * 8) / 100
Or 8n = 200
Or n = 25 years.
correct choice is (B)
Answer: B
Question: Which of the following can be a perimeter r of a triangle inscribed in a circle of radius 1?
I. 0.001
II. 0.010
III. 0.100
Options:
A)I only
B)III only
C)II and III only
D)I, II, and III
E)Not I, II, or III
Rationale: Yes,the length of any side of a triangle must be larger than the positive difference of the other two sides, but smaller than the sum of the other two sides.
But how do you use the above property to solve the question?
The lower limit of the perimeter of an inscribed triangle in a circle of ANY radius is 0: r>0.
Answer is D.
Answer: D
Question: In what time will a train 100 m long cross an electric pole, it its speed be 144 km/hr?
Options:
A)2.5
B)2.9
C)2.4
D)2.8
E)2.1
Rationale: Speed = 144 * 5/18 = 40 m/sec
Time taken = 100/40
= 2.5 sec.
Answer:A:
Answer: A
Question: A tradesman by means of his false balance defrauds to the extent of 60%? in buying goods as well as by selling the goods. What percent does he gain on his outlay?
Options:
A)156%
B)147%
C)134%
D)146%
E)183%
Rationale: g% = 60 + 60 + (60*60)/100
= 156%
Answer: A
Answer: A
Question: What will come in place of the x in the following Number series? 73205, 6655, 605, 55, x
Options:
A)56675
B)73205
C)86543
D)98765
E)86545
Rationale: (B)
5 x 11 = 55, 55 x 11 = 605, 605 x 11 = 6655, 6655 x 11 = 73205
Answer: B
Question: If 120/x is an integer and 108/x is an integer, which of the following must be true?
I. 9/x is an integer
II. 12/x is an integer
III. 36/x is an integer
Options:
A)I only
B)III only
C)I and II only
D)II and III only
E)I, II and III
Rationale: I think, here we should use the greatest common factor.
The greatest common factor for 144 and 108 is 36.
So 36/x is an integer.
For the rest of the answers, if x is 36 then 9/x and 12/x leads to fractions.
Ans is A.
Answer: A
Question: Let N be the greatest number that divides 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is:
Options:
A)4
B)5
C)6
D)7
E)8
Rationale: HCF of (4665-1305) , ( 6905-4665) , (6905-1305)
= HCF of 3360 ,2240,5600
= 1120
sum of digits = 4
ANSWER:A
Answer: A
Question: A contest will consist of n questions, each of which is to be answered eithertrueorfalse. anyone who answers all n questions correctly will be a winner. what is the least value of n for which the probability is less than 1/100000 that a person who randomly guesses the answer to each question will be a winner?
Options:
A)5
B)10
C)50
D)100
E)1000
Rationale: A contest will consist of n questions, each of which is to be answered eithertrueorfalse. anyone who answers all n questions correctly will be a winner. what is the least value of n for which the probability is less than 1/1000 that a person who randomly guesses the answer to each question will be a winner?
A.5
B.10
C.50
D.100
E.1000
Soln: ans is B
Probability that one question is answered right is 1/2.
Now for minimum number of questions needed to take probability less than 1/1000 is
=> (1/2)^n < 1/100000
n = 1000 satisfies this.
E
Answer: E
Question: A and B have less than 6 diamonds each.What is the probability that the sum of diamonds they have is more than 3 but less than 7?
Options:
A)3/5
B)9/25
C)4/9
D)2/3
E)3/2
Rationale: A has 0, 1, 2, 3, 4, or 5 diamonds;
B has 0, 1, 2, 3, 4, or 5 diamonds.
More than 3 but less than 7 = 4, 5, or 6.
4:
{A, B}
{4, 0}
{3, 1}
{2, 2}
{1, 3}
{0, 4}
5:
{A, B}
{5, 0}
{4, 1}
{3, 2}
{2, 3}
{1, 4}
{0, 5}
6:
{A, B}
{5, 1}
{4, 2}
{3, 3}
{2, 4}
{1, 5}
Favorable = 5 + 6 + 5 = 16.
Total = 6*6 = 36
Probability = 16/36 = 4/9.
Answer: C.
Answer: C
Question: Sally has five red cards numbered 1 through 5 and four blue cards numbered 3 through 6. She stacks the cards so that the colors alternate and so that the number on each red card divides evenly into the number on each neighboring blue card. What is the sum of the numbers on the middle three cards?
Options:
A)8
B)9
C)10
D)11
E)12
Rationale: The cards are stacked so that the colors alternate: R-B-R-B-R-B-R-B-R.
We are also told that the number on each red card divides evenly into the number on each neighboring blue card.
There are two primes in Blue cards: 3 and 5. Their divisors are 1 and 3 AND 1 and 5, respectively. Thus R1 must be between R3 and R5, R3 must be by B3 and R5 must be by B5: 3-3-1-5-5.
Next, add multiple of 3 to the left of 3: 6-3-3-1-5-5.
Add factor of 6 to the left of 6: 2-6-3-3-1-5-5.
Add multiple of 2 to the left of 2: 4-2-6-3-3-1-5-5.
And finally add factor of 4 to the left of 4: 4-4-2-6-3-3-1-5-5.
The sum of the numbers on the middle three cards is 6+3+3=12.
Answer: E.
Answer: E
Question: Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 1.9 km respectively. The time taken by the slower train to cross the faster train in seconds is?
Options:
A)99
B)72
C)48
D)96
E)22
Rationale: Relative speed = 60 + 90 = 150 km/hr.
= 150 * 5/18 = 125/3 m/sec.
Distance covered = 1.10 + 1.9 = 3 km = 3000 m.
Required time = 3000 * 3/125 = 72 sec.
Answer:B
Answer: B
Question: What amount does Kiran get if he invests Rs.8000 at 10% p.a. compound interest for two years, compounding done annually?
Options:
A)Rs.19828.89
B)Rs.19828.80
C)Rs.19878.80
D)Rs.19825.80
E)Rs.19828.90
Rationale: Let the sum be Rs.P
P{ [ 1 + 8/100]2 - 1 } = 2828.80
P(8/100)(2 + 8/100) = 2828.80 [a2 - b2 = (a - b) ( a + b)] P
= 2828.80 / (0.08)(2.08) = 1360/0.08 = 17000 Principal + Interest
= Rs.19828.80
Answer:B
Answer: B
Question: What will be the cost of building a fence around a square plot with area equal to 289 sq ft, if the price per foot of building the fence is Rs. 55?
Options:
A)3944
B)3740
C)7290
D)6928
E)3729
Rationale: Explanation:
Let the side of the square plot be a ft.
a2 = 289 => a = 17
Length of the fence = Perimeter of the plot = 4a = 68 ft.
Cost of building the fence = 68 * 55 = Rs. 3740.
Answer: Option B
Answer: B
Question: if length of a rectangle is equal to side of a square and breadth of rectangle is half of length.if area of square is 36 sq.m.calculate the area of rectangle?
Options:
A)18
B)20
C)27
D)32
E)25
Rationale: side of square=√36=6 m.
length=6 m and breadth=3 m
area of rectangle=6*3=18 sq.m
answer A
Answer: A
Question: Bottle R contains 250 capsules and costs $5.25. Bottle T contains 130 capsules and costs $2.99. What is the difference between the cost per capsule for bottle R and the cost per capsule for bottle T?
Options:
A) $0.25
B) $0.12
C) $0.05
D) $0.03
E) $0.002
Rationale: Cost per capsule in R is 5.25/250=0.525/25=0.021
Cost per capsule in T is 2.99/130=0.023
The difference is 0.002
The answer is E
Answer: E
Question: A tea expert claims that he can easily find out whether milk or tea leaves were added first to water just by tasting the cup of tea. In order to check this claims 16 cups of tea are prepared, 8 in one way and 8 in other. Find the different possible ways of presenting these 16 cups to the expert.
Options:
A)12520
B)12870
C)13000
D)13400
E)None
Rationale: Solution:
Since, there are 8 cups of each kind, prepared with milk or tea leaves added first, are identical hence, total number of different people ways of presenting the cups to the expert is,
[16!/(8!x8!)]= 12870
Answer: Option B
Answer: B
Question: Statement: Unemployment allowance should be given to all unemployed Indian youth above 18 yrs of age. Assumptions: 1) There are unemployed youth in India who needs monetary support. 2) The government has sufficient funds to provide allowance to all unemployed youth.
Options:
A)Only assumption I is implicit
B)Only assumption II is implicit
C)Either I or II is implicit
D)Neither I nor II is implicit
E)Both I and II are implicit
Rationale: I directly follows from the statement and so is implicit. Also, the statement is a suggestion and does not tell about a government policy or its position of funds. So, II is not implicit.
A
Answer: A
Question: A fruit seller sells mangoes at the rate of Rs.6 per kg and thereby loses 15%. At what price per kg, he should have sold them to make a profit of 5%
Options:
A)Rs 7.41
B)Rs 9.81
C)Rs 10.41
D)Rs 11.81
E)None of these
Rationale: Explanation:
85 : 6 = 105 : x
x= (6×105/85)
= Rs 7.41
Option A
Answer: A
Question: Sandy gets 3 marks for each correct sum and loses 2 marks for each incorrect sum. Sandy attempts 30 sums and obtains 45 marks. How many sums did Sandy get correct?
Options:
A)18
B)21
C)24
D)27
E)28
Rationale: Let x be the correct sums and (30-x) be the incorrect sums.
3x - 2(30-x) = 45
5x = 105
x = 21
The answer is B.
Answer: B
Question: What ratio must a shopkeepermix Peas and Soybean of Rs.16 and Rs. 25/kg, As to obtain a mixture of Rs.22?
Options:
A)10 : 7
B)9 : 8
C)1 : 2
D)13 : 11
E)14 : 8
Rationale: Correct option: (C)
Use rule of alligation, to determine the ratio
The required ratio of Soybean and Peas = 3 : 6 = 1 :2
Answer: C
Question: Jolene entered an 18-month investment contract that guarantees to pay 2 percent interest at the end of 4 months, another 3 percent interest at the end of 12 months, and 4 percent interest at the end of the 18 month contract. If each interest payment is reinvested in the contract, and Jolene invested $10,000 initially, what will be the total amount of interest paid during the 18-month contract?
Options:
A)$506.00
B)$726.24
C)$900.00
D)$920.24
E)$926.24
Rationale: If interest were not compounded in every six months (so if interest were not earned on interest) then we would have (2+3+4)=9% simple interest earned on $10,000, which is $900. So, you can rule out A, B and C right away.
Interest earned after the first time interval: $10,000*2%=$200;
Interest earned after the second time interval: ($10,000+$200)*3%=$300+$6=$306;
Interest earned after the third time interval: ($10,000+$200+$306)*4%=$400+$8+(~$12)=~$420;
Total: 200+306+(~420)=~$920.24
Answer: D.
Answer: D
Question: (3+√3+√5)^2-(√3+√5)^2=?
Options:
A)9+6√3+6√5
B)1+2√3+3√5
C)1-√3+√5
D)1+√3-√5
E)√3+√5
Rationale: (3+√3+√5)^2-(√3+√5)^2
(3+√3)^2 + 5 +2 (3+√3) (√5) - ( 3 +5 + 2√3√5)
9+ 3+ 6√3 +5 +6 √5 + 2 √15 - 3-5 -2√15
9+6√3+6√5
A is the answer
Answer: A
Question: Mohan went to a shop and bought things worth Rs. 100, out of which 90 Paise went on sales tax on taxable purchases. If the tax rate was 9%, then what was the cost of the tax free items?
Options:
A)89.1
B)88.1
C)79.1
D)80.1
E)85.1
Rationale: Total cost of the items he purchased = Rs.100
Given that out of this Rs.100, 90 Paise is given as tax
=> Total tax incurred = 90 Paise = Rs.90/100
Let the cost of the tax free items = x
Given that tax rate = 6%
∴ (100−90/100−x)9/100 = 90/100
⇒ 9(100−0.9−x) = 90
⇒ (100 − 0.9 − x) = 10
⇒ x = 100 − 0.9 − 10 = 89.1
A)
Answer: A
Question: Reeya obtained 65, 67, 76, 82 and 85 out of 100 in different subjects, What will be the average
Options:
A)70
B)75
C)80
D)85
E)60
Rationale: Explanation:
(65+67+76+82+855)=75
Answer: Option B
Answer: B