divelab/Sys2Bench huggingface dataset:
Question: What is the difference between the place values of two fives in the numeral 7589452
Options:
A)499950
B)411150
C)500050
D)500000
E)50
Rationale: Required difference = 500000-50 = 499950
Answer is A
Answer: A
Question: At the wholesale store you can buy an 8-pack of hot dogs for $1.75, a 20-pack for $3.05, and a 250-pack for $22.95. What is the greatest number of hot dogs you can buy at this store with $250?
Options:
A) 1,108
B) 2,100
C) 2,108
D) 2,628
E) 2,256
Rationale: To maximize number of hot dogs with 250$
Total number of hot dogs bought in 250-pack = 22.95*10 =229.5$
Amount remaining = 250 - 229.5 = 20.5$
Total number of hot dogs bought in 20-pack = 3.05*6 =18.3$
Amount remaining = 20.5 - 18.3 = 2.2$
Total number of hot dogs bought in 8-pack = 1.55*1 =1.55$
Amount remaining = 2.2 - 1.75 = 0.45$
This amount is too less to buy any 8- pack .
Greatest number of hot dogs one can buy with 250 $ = 250*10+20*6+8*1 = 2628
Answer D
Answer: D
Question: An accurate clock shows 8 o'clock in the morning. Through how many degrees will the hour hand rotate when the clock shows 2 o'clock in the afternoon?
Options:
A)144
B)150
C)168
D)180
E)None
Rationale: Explanation :
Angle traced by hour hand in
5 hrs 10 min. = (360/12 x 6)
= 180.
Answer : D
Answer: D
Question: For the infinite sequence of numbers a1, a2, a3, ..., an, ..., for all n > 1, an = an−1an−1 + 4 if n is odd and an = an−1 if n is even. What is the value of a1a1 if a34 = 68?
Options:
A)10
B)11
C)12
D)13
E)21
Rationale: a34= 68 = a33 - 1 = a32 - 1 +4 ... and so on
So observing the trend,
a34 = a1 +(32/2) * 4 - (34/2) * (-1)
[32/2 to get all the even n (from 32 to 2) and 34/2 to get all the odd n (from 33 to 1) including 33 and 1]
a1 = 68-64+17 = 21
Hence, answer will be E.
Answer: E
Question: A and B can do a piece of work in 12 days and 16 days respectively. Both work for 3 days and then A goes away. Find how long will B take to complete the remaining work?
Options:
A)6 days
B)7 days
C)4 days
D)9 days
E)2 days
Rationale: 3/12 + (3 + x)/16 = 1
x = 9 days
Answer: D
Answer: D
Question: Patanjali walked for 3 days. She walked 18 miles on the first day, walking 3 miles per hour. On the second day she walked for one less hour but she walked one mile per hour, faster than on the first day. On the third day she walked the same number of hours as on the first day, but at the same speed as on the second day. How many miles in total did she walk?
Options:
A)24
B)44
C)58
D)60
E)62
Rationale: Patanjali walked 18 miles on the first day, walking 3 miles per hour i.e. total time of walk on Day-1 = 18/3 = 6 Hours
Second day time of walk = 6-1 = 5 hours and Speed = 3+1=4 miles per hour i.e. Distance walked on second day = 5*4 = 20 miles
Third day time of walk = 6 hours and Speed = 4 miles per hour i.e. Distance walked on second day = 6*4 = 24 miles
Total Distance travelled on three days = 18+20+24 = 62
Answer: Option E
Answer: E
Question: It takes Jack 2 more hours than Tom to type 20 pages. If working together, Jack and Tom can type 25 pages in 3 hours, how long will it take Jack to type 40 pages?
Options:
A)5
B)6
C)8
D)10
E)12
Rationale: let's take answer choice D -10 h
if it took 10 h for 40 pages, then it took 5 hours for 20 pages
since it takes Jack 2 more hours than Tom to type 20 pages, Tom's time is 5-2=3 h
their combo time 5*3 /(5+3)=15/8
if it takes 3 h for 25 pages, then it will take 12/5 h ( =20*3/25) for 20 pages
as u see 15/8 <12/5 . so D is out, and we should check E, whose number is more than D's
answer choice E = 12 for 40 pages or 6 for 20 pages
then Tom's time =6-2=4 h
combo time =6*4/(6+4)=12/5
if it takes 3 h for 25 pages, then it will take 12/5 h ( =20*3/25) for 20 pages
12/5=12/5
answer choice E
Answer: E
Question: If cement, gravel and sand are to be mixed in 7:10:13 and 5 tons of cement is available how many tons of mixture can be produced assuming that sufficient gravel and sand is readily available.
Options:
A)35 7/8
B)36
C)34 2/7
D)21 3/7
E)34 6/7
Rationale: Cement:Gravel:Sand = 7:10:13 --> total of 7+10+13 = 30 parts.
If we use 8 tons of cement, then we'll get 5/7*30 =21 3/7 tons of mixture.
Answer: D.
Answer: D
Question: The avg weight of A,B & C is 84 kg. If D joins the group, the avg weight of the group becomes 80 kg.If another man E who weights is 6 kg more than D Replaces A, Then the avgof B,C,D&E becomes 79 kg. What is the weight of A?
Options:
A)45
B)65
C)75
D)78
E)90
Rationale: A + B + C = 3 *84 = 252
A + B + C + D = 4 * 80 = 320 ---- (i)
So, D = 68& E = 68 + 6 = 74
B + C + D +E = 79 * 4 = 316 --- (ii)
From Eq. (i) & (ii)
A-E = 320 – 316 = 4
A = E +4 = 74 + 4 = 78
D
Answer: D
Question: A vessel is filled with liquid, 3 parts of which are water and 5 parts syrup. How much of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup?
Options:
A)1/5
B)2/5
C)3/5
D)4/5
E)None of them
Rationale: Suppose the vessel initially contains 8 litres of liquid.
Let x litres of this liquid be replaced with water.
Quantity of water in new mixture = (3 -(3x/8)+ x)litres
Quantity of syrup in new mixture = (5 - 5x/8) litres
Therefore, (3 - (3x/8)	+ x)	= 5 -	5x/8)
= 5x + 24 = 40 - 5x
= 10x = 16
= x = 8/5
So, part of the mixture replaced = (8/5 x 1/8)= 1/5
Answer is A.
Answer: A
Question: The average of thirteen numbers is 9. The average of first six numbers is 5 and the average of last six numbers is 7. What is the middle number?
Options:
A)47
B)45
C)25
D)37
E)44
Rationale: The total of thirteen numbers = 13X9 = 117
The total of first 6 and last 6 numbers is = 6 X 5+6 X 7 = 72
So, the middle number is (117 - 72 ) = 45
B
Answer: B
Question: [(5/2 ÷ 1/2 × 5/2)]/[(5/2 × 1/2 ÷ 5/2)] = ?
Options:
A)25
B)20
C)18
D)16
E)14
Rationale: Explanation:
[(5/2 ÷ 1/2 × 5/2)]/[(5/2 × 1/2 ÷ 5/2)]
= [5/2 × 2/1 × 5/2]/[5/2 × 1/2 × 2/5]
= 25/2 / 1/2 = 25/2 x 2/1 = 25
Answer: Option A
Answer: A
Question: A man spent 1/5 of his loan amount on house construction and 1/4 of the remaining on his office renovation. How much fraction of the loan amount is he left with after spending on house and office renovation?
Options:
A)3/5
B)2/6
C)5/4
D)1/5
E)4/3
Rationale: The man spent 1/5 his loan amount on house construction, remaining amount is 4/5
He spent 1/4 of the remaining amount for office renovation, 1/4*4/5=4/20
Total loan amount spent on house and office renovation =1/5+4/20
To get a common denominator we use 20, so 1/5 is 4/20
4/20+4/20=8/20 is the total amount spent on house construction and office renovation.
remaining 12/20 is left with the man, 3/5
Answer is A
Answer: A
Question: If a and b are different values and a – b = 6(√a - √b), then in terms of b, a equals:
Options:
A)√b
B)b
C)b - 12√b + 36
D)b + 2√b + 1
E)b^2 – 2b√b + b
Rationale: (√a)^2 - (√b)^2 = 6(√a - √b) -----> ( √a + √b) ( √a - √b) = 6(√a - √b) -------> √a + √b = 6, so
√a = 6 - √b, square both sides and solve. Answer is C.
Answer: C
Question: Kramer can pack X boxes of cigarettes per minute. If there are Y boxes of cigarettes in one case, how many cases can Kramer pack in 6 hours?
Options:
A)60X/Y.
B)360X/Y.
C)60Y/X.
D)120Y/X.
E)(X + Y)/60.
Rationale: Kramer can pack X boxes per min.
Therefore in 6 hrs(360mins)he can pack 360X boxes.
If there are Y boxes in one case then then the total number of cases packed by Kramer = 360X/Y
(ANSWER B)
Answer: B
Question: The positive numbers w, x, y, and z are such that x is 30 percent greater than y, y is 20 percent greater than z, and w is 20 percent less than x. What percent greater than z is w ?
Options:
A)15.2%
B)16.0%
C)20.0%
D)23.2%
E)24.8%
Rationale: My strategy is same as theDobermanbut instead take z=100, which makes life a bit easy. As:
z=100
y=120 (20% greater than z)
z=144(20% greater than y)
Now calculate w 20% less than z = 144*80/100= 115.2
Now by just looking, relation between w and z:
w-z/z*100 = 20 - Answer
C
Answer: C
Question: After three successive equal percentage rise in the salary the sum of 100 rupees turned into 140 rupees and 49 paise. Find the percentage rise in the salary.
Options:
A)12%
B)22%
C)66%
D)82%
E)77%
Rationale: Solution:
We solve it through options. Choosing options for trial depends on mental thought.
100 ==12% up ==>112 ==12% up ==>125.44 ==12% Up ==> 140.49
So, answer is 12%.
Answer: Option A
Answer: A
Question: A and B put in Rs.300 and Rs.400 respectively into a business. A reinvests into the business his share of the first year's profit of Rs.210 where as B does not. In what ratio should they divide the second year's profit?
Options:
A)39:40
B)39:45
C)39:40
D)39:41
E)39:42
Rationale: 3: 4
A = 3/7*210 = 90
390: 400
39:40
Answer: A
Answer: A
Question: If x > 5 and y < -5, then which of the following must be true ?
Options:
A)x/y > 1
B)x/y < -1
C)x/y < 0
D)x + y > 0
E)xy > 0
Rationale: Pick x=3, y = -3
A) x/y > 1 - Incorrect as x/y = -1
B) x/y < -1 - Incorrect as x/y = -1
C) x/y < 0 -Correct. It will hold for all values x > 2 and y < -2 as x/y = -1 < 0
D) x + y > 0 - Incorrect. x + y = 0
E) xy > 0 - Incorrect. XY = -9 which is less than zero.
A should be the answer.
Answer: A
Question: When Greenville State University decided to move its fine arts collection to a new library, it had to package the collection in 20-inch by 20-inch by 15-inch boxes. If the university pays $0.70 for every box, and if the university needs 3.06 million cubic inches to package the collection, what is the minimum amount the university must spend on boxes?
Options:
A)$255
B)$357
C)$510
D)$1,250
E)$2,550
Rationale: Total no. Of boxes = 3060000/(20×20×15) = 510
Total cost = 510×$0.7=$357
Answer B
Answer: B
Question: In a family 13 people eat only vegetarian, 7 people eat only non veg., 8 people eat both veg and non veg.. How many people eat veg in the family?
Options:
A)20
B)11
C)9
D)31
E)21
Rationale: Total people eat veg = only veg + both veg and non veg
Total= 13+8= 21
Answer = E
Answer: E
Question: Average weight of 10 people increased by 2.5 kg when one person of 45 kg is replaced by a new
man. Then weight of the new man is
Options:
A)50
B)55
C)60
D)65
E)70
Rationale: Explanation:
Total weight increased is 2.5 * 10 = 25.
So weight of new person is 45+25 = 70
Answer: Option E
Answer: E
Question: If 10 men can reap 80 hectares in 24 days , then how many hectares can 36 men reap in 30 days?
Options:
A)127
B)237
C)360
D)450
E)281
Rationale: Explanation:
Let the required no of hectares be x. Then
Men --- Hectares---Days
10---------80---------24
36---------x---------30
More men, More hectares (Direct proportion)
More days, More hectares (Direct proportion)
x=36/10*30/24*80
x= 360
Answer: C
Answer: C
Question: 8, 27, 64, 100, 125, 216, 343
Options:
A)40
B)100
C)290
D)102
E)293
Rationale: The pattern is 23, 33, 43, 53, 63, 73. But, 100 is not a perfect cube.
Answer: B
Question: The rate of increase of the price of sugar is observed to be two percent more than the inflation rate expressed in percentage. The price of sugar, on January 1, 1994, is Rs. 24 per kg. The inflation rate for the years 1994 and 1995 are expected to be 20% each. The expected price of sugar on January 1, 1996 would be
Options:
A)23.6
B)36.45
C)35.72
D)24.6
E)None of these
Rationale: Explanation :
Increase in the price of sugar = (20+2)= 22%
Hence, price of the sugar on Jan 1, 1996
=> (24 * 122 * 122)/( 100 * 100 ) = Rs 35.72.
Answer : C
Answer: C
Question: A batsman makes a score of 87 runs in the 17th match and thus increases his average by 3. Find his average after 17th match
Options:
A)36
B)37
C)38
D)39
E)40
Rationale: Explanation:
Let the average after 17th match is x
then the average before 17th match is x-3
so 16(x-3) + 87 = 17x
=> x = 87 - 48 = 39
Answer: Option D
Answer: D
Question: f(1)=1,where f(x+y)=f(x)+f(y)+8xy-2.then f(7)=?
Options:
A)162
B)163
C)164
D)165
E)166
Rationale: f(1)=1
f(2)= f(1+1)= 1+1+8-2= 8
f(3) = f(2+1)= 8+1+ (8*2*1)-2 = 23
f(6)= f(3+3)= 23+23+ (8*3*3)-2= 116
f(7) = f(6+1)= 116+1+(8*6*1)-2= 163
thus ans is 163
ANSWER:B
Answer: B
Question: A solution contains 8 parts of water for every 7 parts of Lemonade syrup. How many parts of the solution should be removed and replaced with water so that the solution will now contain 35% lemonade syrup?
Options:
A)1.5
B)1.75
C)2.14
D)2.34
E)2.64
Rationale: Let the total solution is 150 L with 80 L water70 L syrup.
To make 35% syrup solution, the result solution must have 97.5 L syrup and 52.5 L syrup.
Therefore we are taking 17.5 L of syrup from initial solution and replacing with water.
using urinary method:
70 L syrup in 150 L solution
17.5 L syrup in 37.5 L solution
We started by multiplying 10
Now to get to the result we need to divide by 17.5 => amount of solution to be replaced with water (37.5/17.5)=2.14.
Correct option : C
Answer: C
Question: If Ajay completes a certain work in 8 days and Vijay can complete the same work in 24 days, find the time in which the work will be completed if both Ajay and Vijay work together.
Options:
A)6 days
B)9 days
C)2 days
D)7 days
E)1 days
Rationale: Explanation:
On working together Ajay and Vijay can complete the work in (8*24)/(8 + 24)
= 192/32
= 6 days
ANSWER: A
Answer: A
Question: An accurate clock shows 8 o'clock in the morning. Through how many degrees will the hour hand rotate when the clock shows 1 o'clock in the afternoon?
Options:
A)180°
B)154°
C)160°
D)170°
E)150°
Rationale: The angle traced by the hour hand in 12 hours is 360°, which is 30° per hour.
In 5 hours, the angle traced by the hour hand is 5×30° = 150°
The answer is E.
Answer: E
Question: A password of a computer used five digits where they are from 0 and 9. What is the probability that the password solely consists of prime numbers and zero?
Options:
A)1/32
B)1/16
C)1/8
D)2/5
E)1/2
Rationale: We have five digits can be used for password -0,2,3,5,7.
Assuming that the numbers can be repeated any number of times in the password, probability of selecting any one of them is 5/10 (out of 10 digits from 0-9)
So, 5/10 * 5/10 * 5/10 * 5/10 * 5/10 =1/32 (A)
Answer: A
Question: A pupil's marks were wrongly entered as 83 instead of 63. Due to that the average marks for the class got increased by half. The number of pupils in the class is
Options:
A)38
B)40
C)28
D)12
E)19
Rationale: Explanation:
Let there be x pupils in the class.
Total increase in marks = (x * 1/2) = x/2.
x/2 = (83 - 63) => x/2 = 20 => x = 40.
Answer: B
Answer: B
Question: A shopkeeper buys mangoes at the rate of 4 a rupee and sells them at 3 a rupee. Find his net profit or loss percent?
Options:
A)33 1/4 %
B)33 9/3 %
C)33 1/3 %
D)33 1/5 %
E)33 1/3 %
Rationale: The total number of mangoes bought by the shopkeeper be 12.
If he buys 4 a rupee, his CP = 3
He selling at 3 a rupee, his SP = 4
Profit = SP - CP = 4 - 3 = 1
Profit Percent = 1/3 * 100 = 33 1/3 %
Answer:C
Answer: C
Question: A, B and C invested Rs.6300, Rs.4200 and Rs.10500 respectively, in a partnership business. Find the share of A in profit of Rs.12100 after a year?
Options:
A)3630
B)3617
C)3187
D)7288
E)2661
Rationale: 6300:4200:10500
3:2:5
3/10 * 12100 = 3630
Answer: A
Answer: A
Question: On my sister's birthday, she was 154 cm in height, having grown 10% since the year before. How tall was she the previous year?
Options:
A)150 cm
B)140 cm
C)142 cm
D)148 cm
E)146 cm
Rationale: Let the previous year's height be x.
1.1x = 154
x = 140
The answer is B.
Answer: B
Question: Triangle STV has sides ST = TV = 10, and SV = 12. What is the area?
Options:
A)36
B)40
C)44
D)48
E)52
Rationale: Let the base B of the triangle be SV = 12. Then we need to find the height H.
H^2 = 100^2 - 6^2 = 64 and then H = 8.
The area is (1/2)*B*H = 6*8 = 48
The answer is D.
Answer: D
Question: A 240 m long train running at the speed of 120 km/hr crosses another train running in opposite direction at the speed of 80 km/hr in 9 sec. What is the length of the other train?
Options:
A)260
B)250
C)240
D)230
E)220
Rationale: Relative speed = 120 + 80 = 200 km/hr.
= 200 * 5/18 = 500/9 m/sec.
Let the length of the other train be x m.
Then, (x + 240)/9 = 500/9 => x = 260.
Answer: Option A
Answer: A
Question: I. a3 - 212 = 131,
II. b2 - 72 = -23 to solve both the equations to find the values of a and b?
Options:
A)a > b
B)a ≥ b
C)a < b
D)a ≤ b
E)a = b or the relationship between a and b cannot be established.
Rationale: a3 = 343 => a = 7
b2 = 49 => b = ± 7
a ≥ b
ANSWER:B
Answer: B
Question: Jennifer had $60 to spend on herself. She spent 1/5 of the money on a sandwich, 1/6 for a ticket
to a museum, and 1/2 of it on a book. How much money does Jennifer have left over?
Options:
A)$8
B)$14
C)$5
D)$15
E)$0
Rationale: 1/5 x $60 = $12 for sandwich
1/6 x $60 = $10 for museum
1/2 x $60 = $30 for book
$12 + $10 + $30 = $52 spent
$60 - $52 = $8 left over
correct answer A
Answer: A
Question: Two varieties of wheat - A and B costing Rs. 9 per kg and Rs. 15 per kg were mixed in the ratio 3 : 7. If 5 kg of the mixture is sold at 25% profit, find the profit made?
Options:
A)16.9
B)16.59
C)16.53
D)16.5
E)16.55
Rationale: Explanation:
Let the quantities of A and B mixed be 3x kg and 7x kg.
Cost of 3x kg of A = 9(3x) = Rs. 27x
Cost of 7x kg of B = 15(7x) = Rs. 105x
Cost of 10x kg of the mixture = 27x + 105x = Rs. 132x
Cost of 5 kg of the mixture = 132x/10x (5) = Rs. 66
Profit made in selling 5 kg of the mixture = 25/100 (cost of 5 kg of the mixture) = 25/100 * 66 = Rs. 16.50
Answer: Option D
Answer: D
Question: How many five-digit numbers can be formed from the digits 0, 1, 2, 3, 4, and 5, if no digits can repeat and the number must be divisible by 4?
Options:
A)36
B)48
C)72
D)96
E)144
Rationale: Thus the last two digit must be 04, 12, 20, 24, 32, 40, or 52.
If the last two digits are 04, 20, or 40, the first three digits can take 4*3*2= 24 values.
Total for this case: 24*3 = 72.
If the last two digits are 12, 24, 32, or 52, the first three digits can take 3*3*2= 18 values (that's because the first digit in this case cannot be 0, thus we are left only with 3 options for it not 4, as in previous case).
Total for this case: 18*4 = 72.
Grand total 72 +72 =144.
Answer: E.
Answer: E
Question: By the how much is two-fifth of 100 greater than three -fifths of 25?
Options:
A)25
B)3
C)5
D)30
E)None of these
Rationale: Reqd no. = 2â„5 Ã— 200 - 3â„5 Ã— 25
= 40 - 15 = 25
Answer A
Answer: A
Question: If |x|/|4| > 1, which of the following must be true?
Options:
A)x>4
B)x<4
C)x=4
D)x!=4
E)x<-4
Rationale: Notice that if x = 4, then |x| / |4| = |4| / |4| = 1, so |x| / |4| is NOT more than 1, it's equal to 1. Thus if x = 4, the given inequality does NOT hold true.
As for the other options.
D. x ≠ 4 --> we know that x < -4 or x >4. Thus x cannot be 4. Thus this option is true.
ANSWER: D x!=4
Answer: D
Question: A company that ships boxes to a total of 12 distribution centers uses color coding to identify each center. If either a single color or a pair of two different colors is chosen to represent each center and if each center is uniquely represented by that choice of one or two colors, what is the minimum number of colors needed for the coding? (assume that the order of colors in a pair does not matter)
Options:
A)4
B)5
C)6
D)12
E)24
Rationale: Let # of colors needed be nn, then it must be true that n+C2n≥12n+Cn2 - # of ways to choose the pair of different colors from nn colors when order doesn't matter) --> n+n(n−1)/2≥12 --> 2n+n(n−1)≥24 --> n is an integer (it represents # of colors) n≥5--> nmin=5
Answer: B.
Answer: B
Question: Which greatest possible length can be used to measure exactly 12 meter 15 cm, 10 meter 15 cm and 10 meter 65 cm
Options:
A)45cm
B)25cm
C)4cm
D)5cm
E)50cm
Rationale: Explanation:
Convert first all terms into cm.
i.e. 1215 cm, 1015cm, 1065cm.
Now whenever we need to calculate this type of question, we need to find the HCF. HCF of above terms is 5.
Option D
Answer: D
Question: Kramer can pack X boxes of cigarettes per minute. If there are Y boxes of cigarettes in one case, how many cases can Kramer pack in 3 hours?
Options:
A)60X/Y.
B)180X/Y.
C)60Y/X.
D)120Y/X.
E)(X + Y)/60.
Rationale: Kramer can pack X boxes per min.
Therefore in 3 hrs(180mins)he can pack 180X boxes.
If there are Y boxes in one case then then the total number of cases packed by Kramer = 180X/Y
(ANSWER B).
Answer: B
Question: Divide Rs. 2379 into 3 parts so that their amounts after 2, 3 and 4 years respectively may be equal, the rate of interest being 5% per annum at simple interest. The first part is?
Options:
A)Rs. 759
B)Rs. 792
C)Rs. 818
D)Rs. 828
E)Rs. 838
Rationale: Let the parts be x, y and [2379 - (x + y)]
x + (x * 2 * 5/100) = y + (y * 3 * 5/100) = z + (z * 4 * 5/100)
11x/10 = 23y/20 = 6z/5 = k
x = 10k/11, y = 20k/23, z = 5k/6
But x + y + z = 2379
10k/11 + 20k/23 + 5k/6 = 2379
k = (2379 * 11 * 23 * 6)/3965 = (3 * 11 * 23 * 6)/5
x = [10/11 * (3 * 11 * 23 * 6)/5] = 828
Hence, the first part is Rs. 828.
ANSWER:D
Answer: D
Question: The ratio of two natural numbers is 5:6. If a certain number is added to both the numbers, the ratio becomes 7:8. If the larger number exceeds the smaller number by 10, find the number added?
Options:
A)17
B)12
C)20
D)27
E)18
Rationale: Let the two numbers be 5x and 6x.
Let the number added to both so that their ratio becomes 7:8 be k.
(5x + k)/(6x + k) = 7/8
42x = 7k => k = 2x.
6x - 5x = 10 => x = 10
k = 2x = 20.
Answer:C
Answer: C
Question: David's Bank's saving amount is decreased 10% due to loan payment and current balance is Rs.90000. Find the actual balance before deduction?
Options:
A)8000
B)8500
C)9000
D)9500
E)100000
Rationale: 10% decreased
90% Balance = 90000
100% = 90000/90*100 = 100000
Answer : E
Answer: E
Question: Find the odd man out. 2, 3, 7, 11, 19, 32
Options:
A)32
B)9
C)1
D)3
E)19
Rationale: 32 is an not prime number. All other given numbers are prime
Answer : Option A
Answer: A
Question: A train leaves Mumabai at 9 am at a speed of 40 kmph. After one hour, another train leaves Mumbai in the same direction as that of the first train at a speed of 50 kmph. When and at what distance from Mumbai do the two trains meet?
Options:
A)276
B)271
C)200
D)278
E)268
Rationale: When the second train leaves Mumbai the first train covers 40 * 1 = 40 km
So, the distance between first train and second train is 40 km at 10.00am
Time taken by the trains to meet
= Distance / relative speed = 40 / (50 -40) = 4 hours
So, the two trains meet at 2 p.m. The two trains meet 4 * 50
= 200 km away from Mumbai.
Answer: C
Answer: C
Question: Find value of X: (422+404)^2−(4×422×404)=X.
Options:
A)234
B)267
C)324
D)356
E)577
Rationale: Given Equation is in the form (a+b)2−4ab where a=422 and b=404
Hence answer
=(a+b)2−4ab=(a−b)2=(422−404)2=182=324
C
Answer: C
Question: What is 30 % of 80?
Options:
A)24
B)66
C)367
D)28
E)267
Rationale: 30 % of 80
= 30/100 × 80
= (30 × 80)/100
= 2400/100
= 24
Answer:A
Answer: A
Question: A train approaches a tunnel AB. Inside the tunnel is a cat located at a point that is 3/8 of the distance AB measured from the entrance A. When the train whistles the cat runs. If the cat moves to the entrance of the tunnel A, the train catches the cat exactly at the entrance. If the cat moves to the exit B, the train catches the cat at exactly the exit. The speed of the train is greater than the speed of the cat by what order?
Options:
A)3 : 1
B)4:1
C)5:1
D)None of these
E)Cannot be determined
Rationale: Explanation :
Let tunnel = 8 km and speed of the cat is 1 km/hr.
Time taken to reach entrance of tunnel by cat = 3 hr
Time taken to reach exit of tunnel by cat = 5 hr
Train will cover the sum ( length of tunnel) = 2 hr.
Therefore, ratios of speeds of train and cat = 4 : 1
=> Speed of the train is greater by 3 : 1 than that of the cat.
Answer : A
Answer: A
Question: The first flight out of Phoenix airport had a late departure. If the next three flights departed on-time, how many subsequent flights need to depart from Phoenix on-time, for the airport's on-time departure rate to be higher than 50%?
Options:
A)3
B)5
C)7
D)8
E)6
Rationale: We need on-time departure rate to be higher than 5/10, so it should be at least 6/11, which means that 6 out of 11 flights must depart on time. Since for now 3 out of 4 flights departed on time then 6-3=3 subsequent flights need to depart on-time.
Answer: A
Answer: A