divelab/Sys2Bench huggingface dataset:
Question: A company’s four cars running 10 hrs a day consume 1200 lts of fuel in 10 days. In the next 6 days, the company will need to run 9 cars for 12 hrs each so it rents 5 more cars which consume 25% less fuel than the company’s four cars. How many lts of fuel will be consumed in the next 6 days?
Options:
A)1200 lt
B)1555 lt
C)1674 lt
D)1728 lt
E)4800 lt
Rationale: Given that
4 cars running 10 hrs a day consume 1200 lts. of fuel in 10 days.
1 car consumption per hour per day = 1200 /4 *10 *10 = 3 litre
Now question say new car consume 20% less fuel than the company’s four cars = 75/100 of 3 = 2.25 ( 25 percent less than 3)
Hence we calculate total consumption for next 6 days, the company will need to run 5 new cars for 12 hrs = 2.25 *12 *6*5 =810
similarly = old 4 car consumption for next 6 days for 12 hrs = 3*6*12*4 = 864
hence total is = 810+864 = 1674 lt
Ans is C .
Answer: C
Question: For integers x, y, and z, if (3^x) (4^y) (5^z) = 52,428,800,000 and x + y + z = 17, what is the value of xy/z?
Options:
A)0
B)2
C)4
D)6
E)8
Rationale: The number 52,428,800,000 is not divisible by 3. (We can verify this by adding the digits of the number to see that the sum is not a multiple of 3.)
Thus x = 0 and xy/z = 0.
The answer is A.
Answer: A
Question: An urn contains 10 black and 5 white balls. Two balls are drawn from the urn one after the other
without replacement. What is the probability that both drawn balls are black?
Options:
A)1/2
B)1/5
C)1/5
D)3/7
E)2/7
Rationale: Let E and F denote respectively the events that first and second ball drawn
are black. We have to find P(E n F) or P (EF).
Now P(E) = P (black ball in first draw) = 10/15
Also given that the first ball drawn is black, i.e., event E has occurred, now there are 9 black balls and five white balls left in the urn. Therefore, the probability that the second ball drawn is black, given that the ball in the first draw is black, is nothing but the conditional probability of F given that E has occurred.
That is P(F|E) = 9/14
By multiplication rule of probability, we have
P (E n F) = P(E) P(F|E)
= 10/15 × 9/14 = 3/7
D
Answer: D
Question: A single discount equivalent to the discount series of 20%, 10% and 5% is?
Options:
A)31.7
B)31.4
C)31.6
D)31.1
E)31.2
Rationale: 100*(80/100)*(90/100)*(95/100)
= 68.4
100 - 68.4
= 31.6
Answer:C
Answer: C
Question: Mary's income is 60 percent more than Tim's income, and Tim's income is 60 percent less than Juan's income. What percent of Juan's income is Mary's income?
Options:
A) 64%
B) 120%
C) 96%
D) 80%
E) 64%
Rationale: Juan's income = 100 (assume);
Tim's income = 40 (60 percent less than Juan's income);
Mary's income = 64 (60 percent more than Tim's income).
Thus, Mary's income (64) is 64% of Juan's income (100).
Answer: A.
Answer: A
Question: A work crew of 6 Men takes 8 days to complete one-half of a job. If 9 men are then added to the crew and the men continue to work at the same rate, how many days will it take the enlarged crew to do the rest of the job?
Options:
A)2
B)3
C)3 1/5
D)4
E)4 4/5
Rationale: Suppose 1 man can do work in X days..
so 4 men will do in ..
6/X=1/8*1/2 as half job is done
X=96
now 9 more are added then
15/96=1/2*1/d for remaining half job
d=3 1/5 Number of days
C
Answer: C
Question: George can do a piece of work in 8 hours. Paul can do the same work in 10 hours, Hari can do the same work in 12 hours. George, paul and hari start the same work at 9 am, while george stops at 11 am, the remaining two complete the work. What time will the work complete?
Options:
A)1
B)2
C)3
D)5
E)4
Rationale: Let the total work = 120 units.
As George completes this entire work in 8 hours, his capacity is 15 units /hour
Similarly, the capacity of paul is 12 units / hour
the capacity of Hari is 10 units / hour
All 3 started at 9 am and worked upto 11 am. So total work done upto 11 am = 2 x (15 + 12 + 10) = 74
Remaining work = 120 - 74 = 46
Now this work is to be done by paul and hari. 46 / (12 + 10) = 2 hours (approx)
So work gets completed at 1 pm
Answer:E
Answer: E
Question: A 2-year certificate of deposit is purchased for K dollars. If the certificate earns interest at a n annual rate of 6 percent compound quarterly, which of the following represents the value, in dollars, of the certificate at the end of 2 years?
Options:
A)k(1.06)^2
B)k(1.06)^8
C)k(1.015)^2
D)k(1.015)^8
E)k(1.03)^4
Rationale: term (n) = 2
value of k at the end of 2 yrs, if compounded annually=k(1+r)^n=k(1+0.06)^2
quarterly int. rate (r) = 1.5%
term (n) = 2x4 = 8
value of k at the end of 2 yrs, if compounded qtrly =k(1+r)^n=k(1+0.015)^8
ANSWER:D
Answer: D
Question: An air conditioner can coo the hall in 20 minutes while another takes 25 minutes to cool under similar conditions. if both air conditioners are switched on at same instance then how long will it take to cool the room?
Options:
A)about 14 minutes
B)about 12 minutes
C)about 15 minutes
D)about 16 minutes
E)about 17 minutes
Rationale: Take LCM of 20 and 25 = 100
20*5=100/ 25*4=100.
So if both are switched on together , room cooled in 100/(5+4)=100/9=11.11 minutes
11.11 can be round to 12 minutes , so about 12 minutes
ANSWER: B
Answer: B
Question: What is 30% of 210?
Options:
A)61
B)63
C)65
D)67
E)69
Rationale: X/210 = 30/100
100X = 210X30
X =(210X30)/100
X =6300/100
= 63
ANSWER = B = 63
Answer: B
Question: The sum of 2 numbers is 2000. Their L.C.M. is 21879. Their difference is?
Options:
A)1845
B)1978
C)1945
D)1862
E)1789
Rationale: Let the numbers be x and 2000-x
L.C.M. = x(200-x) = 21879
x^2 - 2000x + 21879 = 0
(x-1989) (x-11) = 0
x = 1989 and x = 11
Difference = 1989-11 = 1978
Answer is B
Answer: B
Question: What is the present worth of Rs. 132 due in 2 years at 5% simple interest per annum?
Options:
A)277
B)278
C)120
D)276
E)298
Rationale: Let the present worth be Rs. x. Then,
S.I. = (132 - x)
(x * 5 * 2) / 100 = (132 - x)
10x = 13200 - 100x
110x = 13200 => x = 120.
Answer:C
Answer: C
Question: If the selling price is quadrupled,the profit is pentadruple, what is the percentage of profit??
Options:
A)50%
B)100%
C)150%
D)200%
E)250%
Rationale: we can make two equations from the given info..
let selling price be S and cost price be C..
so profit=P=S-C...
if S is doubled profit is tripled..
so 5P=4S-C..
or S=4P...
therefore C=P..
% of profit=P/P=100%
B
Answer: B
Question: The batting average of a particular batsman is 60 runs in 46 innings. If the difference in his highest and lowest score is 180 runs and his average excluding these two innings is 58 runs, find his highest score.
Options:
A)179
B)194
C)269
D)177
E)191
Rationale: Explanation:
Total runs scored by the batsman = 60*46 = 2760 runs
Now excluding the two innings the runs scored = 58*44 = 2552 runs
Hence the runs scored in the two innings = 2760 â€“ 2552 = 208 runs.
Let the highest score be x, hence the lowest score = x â€“ 180
x + (x - 180) = 208
2x = 388
x = 194 runs
ANSWER: B
Answer: B
Question: Find the simple interest on Rs.500 for 9 months at 6 paisa per month?
Options:
A)867
B)270
C)267
D)278
E)277
Rationale: I = (500*9*6)/100
= 270
Answer: B
Answer: B
Question: 50% of a number is added to 120, the result is the same number. Find the number?
Options:
A)300
B)277
C)240
D)99
E)121
Rationale: :
(50/100) * X + 120 = X
2X = 480
X = 240
Answer: C
Answer: C
Question: A labourer was engaged for 25 days on the condition that for every day, he works, he will be paid Rs. 2 and for every day, he is absent he will be fined 50p. If he receives only Rs. 37•50, find the no. of days he was absent is_____
Options:
A)3 days
B)4 days
C)5 days
D)6 days
E)7 days
Rationale: if a labour worked for 25 days he should get 50 Rs.
but in this he is getting 13 Rs less. if he don't go for work for 1 day he will loose 2.5 Rs then
no of days(Absent)=13/2.5=5.2. Means he was absent for 5 days
ANSWER:C
Answer: C
Question: What is the median from the below series 90, 92, 93, 88, 95, 88, 97, 87, 108and 98
Options:
A)80
B)93.5
C)92
D)98
E)100
Rationale: Ordering the data from least to greatest, we get:
87, 88, 88, 90, 92, 93, 95, 96, 98,108
The median quiz score was 93.5 (Four quiz scores were higher than 93.5 and four were lower.)
B
Answer: B
Question: How many numbers are there between 100 and 1000 in which all digits are distinct.
Options:
A)900
B)648
C)720
D)252
E)729
Rationale: We know that numbers between 100 and 1000 will be 3 digit integers.
Let the arrangement be ABC where A,B,C represent distinct digits.
We have 9 options for A (as 0 can not start a 3 digit number), 9 options again for B and 8 for C, giving a total of 9*9*8 = 648 options.
ANSWER B
Answer: B
Question: How many numbers from 10 to 43 are exactly divisible by 3?
Options:
A)13
B)11
C)16
D)17
E)18
Rationale: 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42.
11 Numbers.
10/3 = 3 and 43/3 = 14 ==> 14 - 3 = 11. Therefore 11 digits
B)
Answer: B
Question: Statements: Prime school-going children in urban India have now become avid as well as more regular viewers of TV, even in households without a TV. As a result there has been an alarming decline inthe extent of readership of newspapers.
Conclusions:
1) Method of increasing the readership of newspapers should be devised.
2) A team of experts should be sent to other countries to study the impact of TV. on the readership of newspapers.
Options:
A)Only conclusion I follows
B)Only conclusion II follows
C)Either I or II follows
D)Neither I nor II follows
E)Both I and II follow
Rationale: The statement concentrates on the increasing viewership of TV. and does not stress either on increasing the readership of newspapers or making studies regarding the same. So, neither I nor II follows.
D
Answer: D
Question: If y > 0, (6y)/20 + (3y)/10 is what percent of y?
Options:
A)40%
B)50%
C)60%
D)70%
E)80%
Rationale: can be reduced to 3y/10+3y/10 =3y/5=60%
C
Answer: C
Question: Of the three- digit integers greater than 700, how many have two digits Q that are equal to each other and the remaining digit different from the other two?
Options:
A)90
B)82
C)80
D)45
E)36
Rationale: three-digit integers greater than 700: 701 to 999, inclusive.
possible values for hundreds-digit--> 7,8,9
possible values for tens-digit and ones-digit --> 0, 1,2,3,4,5,6,7,8,9
when hundreds-digit and tens-digit are the same: (3x1x10)-3=27 ---> we minus three to exclude 777, 888 and 999
when hundreds-digit and ones-digit are the same: (3x10x1)-3=27 ---> we minus three to exclude 777, 888 and 999
when tens-digit and hundreds-digit are the same:[(3x10x1)-3]-1=26 ---> we minus three to exclude 777, 888 and 999; we minus one to exclude 700
Q=27+27+26 = 80
Answer: C
Answer: C
Question: The average monthly salary of 15 employees in an organisation is Rs. 1800. If the manager's salary is added, then the average salary increases by Rs. 150. What is the manager's monthly salary?
Options:
A)Rs.3601
B)Rs.3618
C)Rs.4200
D)Rs.3619
E)Rs.3610
Rationale: Manager's monthly salary
= Rs. (1950 * 16 - 1800 * 15)
= Rs. 4200 Answer:C
Answer: C
Question: 0, 3, 8, 15, 24, ?
Options:
A)28
B)35
C)48
D)25
E)50
Rationale: The sequence is a series of squares-1
0, 3, 8, 15, 24, 35
Answer : B.
Answer: B
Question: A rectangular tiled patio is composed of 90 square tiles. The rectangular patio will be rearranged so that there will be 2 fewer columns of tiles and 4 more rows of tiles. After the change in layout, the patio will still have 90 tiles, and it will still be rectangular. How many rows are in the tile patio before the change in layout?
Options:
A)5
B)6
C)10
D)11
E)28
Rationale: r*c=90 and (11+4)(c-2)=90 --> r=11 and c=8.
Answer:D.
Answer: D
Question: John and Peter are among the seven players a basketball coach can choose from to field a five-player team. If all five players are chosen at random, what is the probability of choosing a team that includes John and Peter?
Options:
A)5/11
B)8/15
C)9/20
D)10/21
E)11/24
Rationale: The total possible ways of selecting a 5-member team is 7C5 = 21
The possible ways which include John and Peter is 5C3 = 10
The probability of choosing both John and Peter is 10/21
The answer is D.
Answer: D
Question: If money is invested at r percent interest, compounded annually, the amount of the investment will double in approximately 48/r years. If Pat's parents invested $5,000 in a long-term bond that pays 8 percent interest, compounded annually, what will be the approximate total amount of the investment 18 years later, when Pat is ready for college?
Options:
A) $20000
B) $15000
C) $12000
D) $10000
E) $9000
Rationale: Since investment doubles in 48/r years, then for r=8 it'll double in 48/8=~6 years (we are not asked about the exact amount so such an approximation will do). Thus after 18 years investment will become $5,000*3=$15,000 .
Answer: B.
Answer: B
Question: My son adores chocolates. He likes biscuits. But he hates apples. I told him that he can buy as many chocolates he wishes. But then he must have biscuits twice the number of chocolates and should have apples more than biscuits and chocolates together. Each chocolate cost Re 1. The cost of apple is twice the chocolate and four biscuits are worth one apple. Then which of the following can be the amount that I spent on that evening on my son if number of chocolates, biscuits and apples brought were all integers?
Options:
A)Rs 34
B)Rs 33
C)Rs 8
D)None of the above
E)Cannot be determined
Rationale: Explanation :
Let the person buy c chocolates, 2c buiscuits. Therefore, apples is >3c.
In any case, total cost will be
=>cost of chocolates + cost of biscuits + cost of apples.
=> (c*1) + [2c*0.5] + (2*something greater than 3c).
Thus, Total cost=>
=> 2c + (2* something greater than 3c).
Here, the total cost is an even number. Thus ans should be an even number.
Taking c=1, the total minimum cost we get is 10.
Thus the only other option that satisfies the constraints is 34.
Answer : A
Answer: A
Question: A company hired a printer to produce a total of x + 2 envelopes. The job consisted of two types of envelopes, 3¢ envelopes and 7¢ envelopes. If the company requested 2 more 3¢ envelopes than 7¢ envelopes, which of the following expressions denotes the cost, in cents, of the total x + 2 envelopes ?
Options:
A)(9x-5)/2
B)(7x+4)/2
C)5x+6
D)6x+5
E)4x+13
Rationale: we can take
X+2 = 10
X= 8
So 3c envelopes will be 6
and 7c envelopes will be 4
So total cost will be 46
Then that is our target
Plug x =8 in answer choices
Only c works
Correct Answer : C
Answer: C
Question: In a school of 400 boys, 44% of Muslims, 28% Hindus, 10% Sikhs and the remaining of other communities. How many belonged to the other communities?
Options:
A)41
B)63
C)72
D)63
E)50
Rationale: 44 + 28 + 10 = 82%
100 – 82 = 18%
400 * 18/100 = 72
ANSWER:C
Answer: C
Question: A man can row his boat with the stream at 14 km/h and against the stream in 4 km/h. The man's rate is?
Options:
A)1 kmph
B)3 kmph
C)8 kmph
D)7 kmph
E)5 kmph
Rationale: DS = 14
US = 4
S = ?
S = (14 - 4)/2 = 5 kmph
Answer: E
Answer: E
Question: In a certain lottery drawing, two balls are selected at random from a container with 10 balls, numbered from 1 to 10, inclusive. If the winner of the lottery is awarded a cash prize in the amount of $1,000 times the product of the numbers on the two selected balls, which of the following is a possible amount of the cash prize given to the winner?
Options:
A)$9 x 10^4
B)$9.90 x 10^6
C)$1.00 x 10^7
D)$1.05 x 10^7
E)$9.90 x 10^7
Rationale: The max product of any two balls can be 9 * 10 = 9900 = 9 * 10
If we multiply it by $1000 the max amount will be 9 * 10^4.
A
Answer: A
Question: If A : B = 4 : 3 and B : C = 5 : 9 then A : B : C is :
Options:
A)20 : 35 : 63
B)20 : 15 : 27
C)30 : 35 : 65
D)25 :34: 68
E)None of these
Rationale: Expl : A : B = 4 : 3
B : C = 5 :9 = 5*3/5 : 9 *3/5 = 3 : 27/5
A : B : C = 4 : 3 : 27/5 = 20 : 15 : 27
Answer: B
Answer: B
Question: A third of Arun’s marks in mathematics exeeds a half of his marks in english by 80.if he got 240 marks In two subjects together how many marks did he got inh english?
Options:
A)140
B)150
C)160
D)170
E)180
Rationale: M=mathematics marks
E=english marks
M+E=240-(1eqution)
M=E+E/2-(2 equation)
put 2nd equation in 1st equation
E+E/2+E=240
3E/2=240
3E=240*2
3E=180
E=180/3
E=160
ANSWER:C
Answer: C
Question: There are 3 mixtures when mixed in the ratio of 3:4:5 price was 240.When mixed with 6:4:9 price was 340.what's the price when mixed in 5:6:8 ration price is_________
Options:
A)346
B)356
C)366
D)376
E)386
Rationale: 3x+4x+5x=240
x=20
6x+4x+9x=340
x=17.89
5*20+6*20+8*20=380-4=376
ANSWER:D
Answer: D
Question: The number 81 can be written as the sum of squares of 3 integers. Which of the following could be the difference between the largest and smallest integers of the 3?
Options:
A)2
B)5
C)8
D)7
E)9
Rationale: Notice that the question asks which of the followingcouldbe the difference between the largest and smallest integers, not must be. The 3 integers could be: +/-1, +/-4 and +/-8, so the difference could be 7,9, or 12. Since only one of them is among the choices, then it must be the correct answer.
Answer: D.
Answer: D
Question: E is an even integer greater than 300,000 and smaller than 1,000,000. How many numbers can E be?
Options:
A)300,000
B)349,999
C)350,000
D)399,999
E)400,000
Rationale: E 1,000,000-300,000=700,000 integers
700,000/2= 350,000 even integers.
350,000+1 inclusive. But since 1,000,000 and 300,000 are not included.
350,001-2=349,999
B
Answer: B
Question: Some of the workers at a hedge fund are analysts; the others are not analysts. There are a total of 2x/3 analysts at the hedge fund. A total of x hedge fund workers have an MBA. Furthermore, x/3 analysts have an MBA, y/4 of the hedge fund workers are neither analysts nor have an MBA, and 80 workers are not analysts. If there are y total workers at the hedge fund, x is equal to which of the following?
Options:
A)45
B)50
C)60
D)72
E)80
Rationale: AnalystsNot AnalystsTotal
MBAx/32x/3x
No MBAy/4
Total2x/350y
We are asked for the value of x.
From the table: 2x/3 = y - 80
y - 80 + (y/4) = 80
5y/4 =160
y = 128
2x/3 = 128 - 80 = 48
x = 144/2 = 72
Answer: D
Answer: D
Question: From the set of numbers x, y, t, z, p, q and w, how many different combinations can we have without the t and w in them? Ex:. (x,y), (x), (p,q,z,y,x), etc and (x,y)=(y,x)
Options:
A)10
B)14
C)15
D)16
E)30
Rationale: Another way: Any letter (x, y, z, p, q) can be included or not. So, we have 2^5 combinations - 2 empty combinations = 30 combinations
E
Answer: E
Question: An urn contains g green marbles and b blue marbles. If 2 green marbles and 5 blue marbles are added, and then one marble is selected at random from the urn, what is the probability that a blue marble will be drawn?
Options:
A)b/(b+g)
B)(b+5)/(g+3)
C)(b+5)/(b+g+7)
D)(b+5)/(b+g+3)
E)b/(b+g+5)
Rationale: no of fav outcomes i.e. blue MArbles = b+5
Total no of outcomes i.e. total Marbles = (b+5)+(g+2)= b+g+7
probability = (b+5) /(b+g+7)
Answer C
Answer: C
Question: P and Q are both positive integers. When P is divided by Q, the remainder is some positive integer D, and when P is divided by (Q + 7), the remainder is also D. If P/Q = 1020.75 and P/(Q + 7) = 816.6, then which of the following gives the correct set of {D, Q}?
Options:
A){6, 12}
B){6, 15}
C){21,28}
D){9, 15}
E){15, 24}
Rationale: p/q= d=p/q+7
d= .75 q
d= .6(q+7)
we get d = 21 and q = 28. Answer = C.
Answer: C
Question: Of the 50 electronics components that a factory must
manufacture, 70 percent would be most e¢ ciently manufactured
by Machine A and the remaining 30 percent would be most
e¢ ciently manufactured by Machine B, though either machine
could manufacture any of the 50 components. If 36 percent of
the components were manufactured by Machine A and the
remainder were manufactured by Machine B, what is the
highest possible number of components that were
manufactured by the machine that would manufacture them
the most efficiently?
Options:
A)30
B)31
C)32
D)33
E)34
Rationale: # components A and B could manufacture efficiently:
A: 50*70% = 35
B: 50*30% = 15
# components A and B effectively manufacture:
A: 50*36% = 18
B: 50*64% = 32
Max. # components efficiently manufactured:
18 (from A) and 15 (from B) = 33
ANSWER:D
Answer: D
Question: It is known that no more than 5 children will be attending a party. What is the smallest number of cookies that must be brought to the party so that each child receives the same number of cookies?
Options:
A)35
B)105
C)60
D)210
E)420
Rationale: The question states that there are no more than 5 children in the party. Thus, the possibility is that there could be 1, 2, 3, 4 or 5 children.
If you assume answer as 35 and there are 3 children, you may not distribute be able to distribute cookies equally.
similarly if there were 105 cookies, and 2 children, cookies cannot be distributed equally.
or if there were 210 cookies, and 4 children, cookies cannot be distributed equally.
Thus, the question asks for a number of cookies which can be distributed to any number of children (from 1 to 5).
And therefore the smallest number of cookies would be lcm of (1, 2, 3, 4, 5), i.e., 60.
Answer (C)
Answer: C
Question: Company A has 13 employees, 6 of whom belong to the union. If 5 people work any one shift, and the union contract specifies that at least 4 union members work each shift, then how many different combinations of employees might work any given shift?
Options:
A)81
B)231
C)336
D)350
E)406
Rationale: Looks easy: -- 6C4*5C1 + 6C5 -- 81 (A).
Answer: A
Question: A is 30% more efficient than B. How much time will they working together take to complete a job which A alone could have done in 23 days?
Options:
A)11
B)13
C)20 3/17
D)14
E)None of these
Rationale: Explanation:
Ratio of times taken by A and B= 100:130 =10:13
suppose B takes x days to work the 10:13::23:x =>x=23 x 13/10 = 299/10
A’s one day work = 1/23 and B’s is 10/299
Then A+B ‘s work = 1/23 + 10/299 = 23/299 =1/13 => 13 days
Answer: Option B
Answer: B
Question: How many bricks each measuring 21cm x 10cm x 8cm, will be needed to build a wall 9m x 5m x 18.5m
Options:
A)4955
B)4899
C)4650
D)7200
E)None of these
Rationale: Explanation:
no. of bricks= volume of the wall/volume of 1 brick = (900 x 500 x 18.5) / (21 x 10 x 8) = 4955
Answer: A
Answer: A
Question: John has taken four (4) tests that have an average of 82. In order to bring his course grade up to a ‘B’, he will need to have a final average of 88. What will he need to average on his final two tests to achieve this grade?
Options:
A)100
B)90
C)92
D)94
E)97
Rationale: 88-82=6*4=24 points
2*88=176
176+24=200 points to be scored in the 2 tests.
Avg of 2 tests = 200/2=100
Answer: A
Traditional Method:
Total scored till now 82*4=328
Total score to avg 88 in 6 tests = 88*6=528
Total to be scored on 2 tests = 528-328=200
Avg on 2 tests = 200/2 = 100
Answer A
Answer: A
Question: If shares of two persons in profits are Rs.300 and Rs.500 then ratio of their capitals is
Options:
A)3:4
B)3:5
C)4:3
D)1:3
E)1:5
Rationale: total profit =1000
ratio=300/500
=3:5
ANSWER:B
Answer: B
Question: A tailor had a number of shirt pieces to cut from a roll of fabric. He cut each roll of equal length into 10 pieces. He cut at the rate of 45 cuts a minute. How many rolls would be cut in 24 minutes ?
Options:
A)32 rolls
B)54 rolls
C)108 rolls
D)120 rolls
E)140 rolls
Rationale: Explanation:
Number of cuts made to cut a roll into 10 pieces = 9.
Therefore Required number of rolls = (45 x 24)/9 = 120.
Answer: D
Answer: D
Question: Rama bought goods at a discount of 20% of list price.He marks them at a price as search he can give discount of 20% on a marked price and still makes the profit of 20% on selling price.What percent of list price is the marked price
Options:
A)100%
B)175%
C)125%
D)180%
E)160%
Rationale: If marked price is Rs 100/-
Selling price = Rs 80/-
Profit = 80*0.2= Rs 16
CP= Rs 64
List price = 64*100/80 = Rs 80
so marked price is 100*100/80 = 125%
ANSWER:C
Answer: C
Question: if 3rd december 1999 is sunday what day is 3rd january 2000
Options:
A)wednesday
B)thursday
C)friday
D)saturday
E)sunday
Rationale: There is difference of 31 days from 3rd Dec 1999 to 3rd Jan 2000..
31/7 left with 3 odd days..
that is wednesday
ANSWER:A
Answer: A