divelab/Sys2Bench huggingface dataset:
Question: Of the 60 pizzas a being ordered, 25% are pepperoni. How many many cheese pizzas must be changed to pepperoni in order to bring the number of pepperoni pizzas up to 50 percent of the pizzas?
Options:
A)25
B)30
C)20
D)15
E)45
Rationale: Now, there are 15 smokers (15% of 60) and 60-15=45 non-smokers at a party. We need there to be 30 cheese and 30 pepperoni pizzas, in this case there will be 50% cheese and 50% pepperoni.
Therefore 45-30=15 cheese must be changed to pepperoni pizza.
Answer: D.
Answer: D
Question: Two musicians, Maria and Perry, work at independent constant rates to tune a warehouse full of instruments. If both musicians start at the same time and work at their normal rates, they will complete the job in 60 minutes. However, if Perry were to work at twice Maria’s rate, they would take only 30 minutes. How long would it take Perry, working alone at his normal rate, to tune the warehouse full of instruments?
Options:
A)1 hr 20 min
B)1 hr 45 min
C)2 hr
D)2 hr 20 min
E)3 hr
Rationale: Sol:
Lets Perry Rate be P and Rate of Maria be M
(rate)*(time)= Work or rate = work/time
first equation=> P+M = 1/60
converting it to hrs P+M= 1/(60/60) => 1
second equation => M+2M =>1/30
converting it to hrs 3M=1/(30/60) =>1/(1/2) =>2
therefore M= 2/3 and P=1/3
Rate of Perry = 1/3
time= work/rate (work = 1 job)
Time= 3 hrs
Answer : E
Answer: E
Question: When positive integer n is divided by 2, the remainder is 2. When n is divided by 7, the remainder is 5. How many values less than 100 can n take?
Options:
A) 0
B) 2
C) 3
D) 4
E) 5
Rationale: a quick approac to this Q is..
the equation we can form is.. 3x+2=7y+5..
3x-3=7y... 3(x-1)=7y...
so (x-1) has to be a multiple of 7 as y then will take values of multiple of 3..
here we can see x can be 1,8,15,22,29 so 5 values till 100 is reached
as (29-1)*3=84 and next multiple of 7 will be 84+21>100..
ans 5.. C
Answer: C
Question: A grocer has a sales of Euro 520, Euro 628, Euro 525, Euro 600 and Euro 800 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Euro 700?
Options:
A)uro 1691
B)uro 1127
C)uro 3591
D)uro 7791
E)uro 4991
Rationale: B
Euro 1127
Total sale for 5 months = Euro (520 + 628 + 525 + 600 + 800) = Euro 3073.
Required sale = Euro [ (700x 6) - 3073]
= Euro (4200- 3073)
= Euro 1127.
Answer is B
Answer: B
Question: Rajan borrowed Rs.4000 at 5% p.a compound interest. After 2 years, he repaid Rs.2210 and after 2 more year, the balance with interest. What was the total amount that he paid as interest?
Options:
A)635.5
B)635.57
C)635.87
D)635.59
E)635.28
Rationale: 4000
200 ---- I
200
10 ---- II
---------------
4410
2210
--------
2000
110 ---- III
110
5.50 ---- IV
-----------
2425.50
2210
-----------
4635.50
4000
----------
635.50
Answer:A
Answer: A
Question: If the price of petrol is increased by 20% and subsequently by 40%. If the original price was Rs25 per litre then what is then the final price per litre?
Options:
A)42
B)45
C)48
D)40
E)none
Rationale: Answer
Final Price = 25 x (1 + 20/100) x (1 + 40/100)
=Rs.25 x 1.2 x 1.4
= Rs. 42
Correct Option: A
Answer: A
Question: The tax on a commodity is diminished by 22% but its consumption is increased by 9%. Find the decrease percent in the revenue derived from it?
Options:
A)20%
B)18%
C)15%
D)12%
E)14%
Rationale: 100 * 100 = 10000
78 * 109 = 8502
10000------- 1200
100 ------- ? = 15%
ANSWER:C
Answer: C
Question: At present, the ratio between the ages of Arun and Deepak is 4:6. After 6 years, Arun's age will be 26 years. What is the age of Deepak at present?
Options:
A)17 years
B)30 years
C)18 years
D)22 years
E)19 years
Rationale: Let the present ages of Arun and Deepak be 4x and 6x years respectively.
Then, 4x + 6 = 26 => x
= 5
Deepak's age
= 6x
= 30 years.
Answer:B
Answer: B
Question: A dealer purchased an article at 3/4 of its list price and sold 50% more than the list price. Find his gain percent?
Options:
A)227
B)188
C)100
D)988
E)271
Rationale: MP = 100
CP = 75
SP = 150
------
75 ---- 75
100 ---- ? => 100%
Answer:C
Answer: C
Question: The population of a bacteria colony doubles every day. If it was started 6 days ago with 2 bacteria and each bacteria lives for 12 days, how large is the colony today?
Options:
A)512
B)768
C)102
D)204
E)128
Rationale: 6 days ago- 2
5 days ago- 4
4 days ago- 8
3 days ago- 16
2 days ago- 32
Yesterday- 64
Today- 128
Ans:E
Answer: E
Question: A, B and C rents a pasture for Rs.870. A put in 12 horses for 8 months, B 16 horses for 9 months and 18 horses for 6 months. How much should C pay?
Options:
A)270
B)288
C)1266
D)299
E)212
Rationale: 12*8 :16*9 = 18*6
8: 12: 9
9/29 * 870 = 270
Answer: A
Answer: A
Question: Out of first 40 natural numbers, one number is selected at random. The probability that it is either an even number or a prime number is ?
Options:
A)11/40
B)17/29
C)17/40
D)31/40
E)17/27
Rationale: n(S) = 40
n(Even no) = 20 = n(E)
n(Prime no) = 12 = n(P)
P(EᴜP)
= 20/40 + 12/40 - 1/40
= 31/40
Answer:D
Answer: D
Question: A, B, C together started a business. A invested Rs.6000 for 5 months B invested Rs.3600 for 6 months and C Rs.7500 for 3 months. If they get a total profit of Rs.7410. Find the share of A?
Options:
A)2277
B)3000
C)2682
D)7222
E)2682
Rationale: 60*5:36*6:75*3
100: 72: 75
100/247 * 7410 = 3000
Answer:B
Answer: B
Question: A 300 m long train crosses a platform in 27 sec while it crosses a signal pole in 18 sec. What is the length of the platform?
Options:
A)286 m
B)350 m
C)277 m
D)278 m
E)150 m
Rationale: Speed = 300/18 = 50/3 m/sec.
Let the length of the platform be x meters.
Then, (x + 300)/27 = 50/3
x = 150 m.
Answer:E
Answer: E
Question: Sakshi invests a part of Rs. 12,000 in 12% stock at Rs. 120 and the remainder in 15% stock at Rs. 125. If his total dividend per annum is Rs. 1330, how much does he invest in 12% stock at Rs. 120?
Options:
A)s. 4000
B)s. 4500
C)s. 5500
D)s. 6000
E)s. 6500
Rationale: Let investment in 12% stock be Rs. x.
Then, investment in 15% stock = Rs. (12000 - x).
12/120 * x + 15/125 * (12000- x) = 1330
x/10 + 3/25(12000-x) = 1330
5x + 72000 - 6x = 1330 x 50
x = 5500.
Answer = C
Answer: C
Question: if x:y = 1:3, then find the value of
(7x+3y):(2x+y)
Options:
A)14:5
B)15:5
C)16:5
D)17:5
E)18:5
Rationale: Explanation:
let x = 1k and y = 3k,
so
=7(k)+3(3k)/2(k)+1(3k)
=16k/5k
=16:5
ANSWER IS C
Answer: C
Question: Which of the following numbers should not be included in the set?
331, 482, 551, 263, 382, 242, 111
Options:
A)263
B)382
C)242
D)111
E)None of these
Rationale: Solution
In each number except 382,the product of first and third digits is the middle one. Answer B
Answer: B
Question: Combine terms: 15a + 26b -4b – 16a.
Options:
A)4a + 22b
B)-28a + 30b
C)-a + 22b
D)28a + 30b
E)5a + 30b
Rationale: Solution:
15a + 26b -4b – 16a.
= 15a – 16a + 26b – 4b.
= -a + 22b.
Answer: (C)
Answer: C
Question: How many multiples of 4 are there between 12 and 108, inclusive?
Options:
A)21
B)22
C)23
D)24
E)25
Rationale: The multiples of 4 are from 4*3 up to 4*27.
27-3+1 = 25.
The answer is E.
Answer: E
Question: Find out the number of ways in which 6 rings of different types can be worn in 3 fingers?
Options:
A)541
B)729
C)174
D)189
E)120
Rationale: The first ring can be worn in any of the 3 fingers (3 ways).
Similarly each of the remaining 5 rings also can be worn in 3 ways.
Hence total number of ways
=3×3×3×3×3×3=36=729
ANSWER B 729
Answer: B
Question: A retailer purchases pants from a wholesaler and then sells the pants in his store at a retail price that is 50 percent greater than the wholesale price. If the retailer decreases the retail price by 20 percent this will have the same effect as increasing the wholesale price by what percent?
Options:
A)26
B)20
C)42
D)44
E)25
Rationale: Answer: B= 20.
Assume Rs. 100 to be the price at which the retailer buys from wholesaler.
50% increase makes Retail price = 150.
Now 20% decrease -> (1-20/100) * 150 = 120.
Now compared to the wholesale price of 100, 20% increase is what will have the same effect as increasing the wholesale price.
Answer: B
Question: If c≠d and c·d≠0, which of the following may be true?
Options:
A)c.d =0
B)c-d=0
C)c+d=2
D)(c+d)(c-d)=0
E)c−d=d−c
Rationale: except D all conditions are not as per question
D
Answer: D
Question: 6 people meet for a ceremony. Each person shakes hands once with each other person present. How many handshakes take place?
Options:
A)30
B)21
C)18
D)15
E)10
Rationale: Let's look at the logic.
Every person shakes hand with other '5'. So, 6 people shake hands with 6X5= 30 people
But in this 30 we have counted two times the total handshakes (s shakes hand with t and t shakes hand with s)
So just divide 30/2= 15 total handshakes
Answer is D
Answer: D
Question: Present ages of Sameer and Anand are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively. What is Anand's present age in years?
Options:
A)12 years
B)19 years
C)26 years
D)24 years
E)30 years
Rationale: Explanation:
Let the present ages of Sameer and Anand be 5x years and 4x years respectively.
Then,5x +3/4X+3=11/9
9(5x + 3) = 11(4x + 3)
45x + 27 = 44x + 33
45x - 44x = 33 - 27
x = 6.
Anand's present age = 4x = 24 years.
Answer: D
Answer: D
Question: A sum of money at simple interest amounts to Rs. 2240 in 2 years and to Rs. 2600 in 5 years. What is
the principal amount
Options:
A)1000
B)1500
C)2000
D)2500
E)None of these
Rationale: Explanation:
SI for 3 year = 2600-2240 = 360
SI for 2 year 360/3 * 2 = 240
principal = 2240 - 240 = 2000
Answer:C
Answer: C
Question: Solve 7x – 5 = 4x + 11
Options:
A)5(1/3)
B)6(1/3)
C)7(1/3)
D)8(1/3)
E)9(1/3)
Rationale: Sol.
7x – 5 = 4x + 11
=> 7x – 4x = 11 + 5
=> 3x = 16 => x = 16/3 = 5(1/3).
Answer A
Answer: A
Question: What quantity of water should taken out to concentrate 12 liters of 40% acidic liquid to 60% acidic liquid?
Options:
A)4liters
B)10liters
C)15liters
D)8liters
E)6liters
Rationale: Required answer is = 12(60-40)/60 = 4 liters
Answer is A
Answer: A
Question: A team scored a total of 98 points. If each player on the team scored at least 14 points, then what is the greatest possible number of players on the team?
Options:
A)A)6
B)B)7
C)C)8
D)D)9
E)E)10
Rationale: 98/14=7 plus remainder.
The answer is B.
Answer: B
Question: Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is?
Options:
A)26 sec
B)28 sec
C)48 sec
D)22 sec
E)12 sec
Rationale: Relative speed = 60 + 90 = 150 km/hr.
= 150 * 5/18 = 125/3 m/sec.
Distance covered = 1.10 + 0.9 = 2 km = 2000 m.
Required time = 2000 * 3/125
= 48 sec.
Answer:C
Answer: C
Question: Susan drives from city A to city B. After two hours of driving she noticed that she covered 80 km and calculated that, if she continued driving at the same speed, she would end up been 15 minutes late. So she increased her speed by 10 km/hr and she arrived at city B 36 minutes earlier than she planned.
Find the distance between cities A and B.
Options:
A)223
B)376
C)250
D)378
E)271
Rationale: Let xx be the distance between A and B. Since Susan covered 80 km in 2 hours, her speed was V=802=40V=802=40 km/hr.
If she continued at the same speed she would be 1515 minutes late, i.e. the planned time on the road is x40−1560x40−1560 hr. The rest of the distance is (x−80)(x−80) km. V=40+10=50V=40+10=50 km/hr.
So, she covered the distance between A and B in 2+x−80502+x−8050 hr, and it was 36 min less than planned. Therefore, the planned time was 2+x−8050+36602+x−8050+3660.
When we equalize the expressions for the scheduled time, we get the equation:
x40−1560=2+x−8050+3660x40−1560=2+x−8050+3660
x−1040=100+x−80+3050x−1040=100+x−80+3050
x−104=x+505x−104=x+505
5x−50=4x+2005x−50=4x+200
x=250x=250
So, the distance between cities A and B is 250 km.
Answer:C
Answer: C
Question: ? x 240 = 173 x 240
Options:
A)173
B)685
C)865
D)495
E)534
Rationale: Let y x 240 = 173 x 240
Then y = (173 x 240) / 240
=173
ANSWER :A
Answer: A
Question: Two trains running in opposite directions cross a man standing on the platform in 67 seconds and 17 seconds respectively and they cross each other in 73 seconds. The ratio of their speeds is:
Options:
A)3/2
B)3/9
C)3/6
D)3/1
E)3/5
Rationale: Let the speeds of the two trains be x m/sec and y m/sec respectively. Then, length of the first train = 27 x meters, and length of the second train = 17 y meters. (27 x + 17 y) / (x + y) = 23 ==> 27 x + 17 y = 23 x + 23 y ==> 4 x = 6 y ==> x/y = 3/2.
Answer:A
Answer: A
Question: A manâ€™s current age is (2/5) of the age of his father. After 12 years, he will be (1/2) of the age of his father. What is the age of father at now?
Options:
A)60
B)45
C)38
D)50
E)39
Rationale: Let, fatherâ€™s current age is A years.
Then, Manâ€™s current age =[ (2/5)A ]years.
Therefore, [ (2/5)A + 12 ]= (1/2)(A + 12)
2(2A + 60) = 5(A + 12)
A = 60
A
Answer: A
Question: If one positive integer is greater than another positive integer by 3, and the difference of their cubes is 63, what is their sum?
Options:
A)5
B)4
C)3
D)2
E)1
Rationale: 1^3 = 1
2^3 = 8
3^3 = 27
4^3 = 64
The two numbers are 1 and 4.
The answer is A.
Answer: A
Question: If the number 571 * 269 is completely divisible by 9, then the smallest whole number in place of * will b
Options:
A)4
B)6
C)7
D)8
E)9
Rationale: Sum of digits = (5 + 7 + 1 + x + 2 + 6 + 9) = (30 + x), which must be divisible by 9.
x = 6.
B)
Answer: B
Question: Find the roots of the quadratic equation: 2x2 + 3x - 9 = 0?
Options:
A)3, -3/2
B)3/2, -3
C)-3/2, -3
D)3/2, 3
E)2/3, -3
Rationale: Explanation:
2x2 + 6x - 3x - 9 = 0
2x(x + 3) - 3(x + 3) = 0
(x + 3)(2x - 3) = 0
=> x = -3 or x = 3/2.
ANSWER IS B
Answer: B
Question: If (A-B-C+D = 13) and (A+B-C-D = 3), what is the value of (B-D)^2?
Options:
A)4.
B)8.
C)12.
D)25.
E)64.
Rationale: EQ1: A - B - C + D = 13
EQ2: A + B - C - D = 3
(1) Subtract EQ1 from EQ2
A - B - C + D = 13
- A +B - C - D = 3
------------------------
-2B + 2D = 10
(2) Simplify
-B + D = 5
B - D = -5
(B-D)^2 = (-5)^2 = 25
My answer: D
Answer: D
Question: The sum of the present ages of two persons A and B is 60. If the age of A is twice that of B, find the sum of their ages 6 years hence?
Options:
A)22
B)77
C)70
D)98
E)72
Rationale: A + B = 60, A = 2B
2B + B = 60 => B = 20 then A = 40.
6 years, their ages will be 46 and 26.
Sum of their ages = 46 + 26 = 72.
Answer: E
Answer: E
Question: Complete the series:
16, 06 , 68 , 88 , ? , 98
Options:
A)L8
B)B6
C)S5
D)E8
E)M5
Rationale: A
L8
To know why, just read the number series upside down and you will find that the numbers are 91, 90, 89, 88, __, 86
So L8 when read upside down reads as 87.
Answer: A
Question: If x + | x | = 0, which of the following must be true?
Options:
A)x > 0
B)x≥0
C)x < 0
D)x≤0
E)x = 0
Rationale: Manipulate the equations:
x + | x | = 0
|x| = -x
-x > 0 OR -x = 0
This means x could be 0 or x is less than 0.
D. x≤0
E. x=0
Answer: D
Answer: D
Question: To furnish a room in a model home an interior decorator is to select 2 chairs and 2 tables from the collection of chairs and tables in a warehouse that are all different from each other. If there are 5 chairs in the warehouse and if 150 different combinations are possible, how many tables r are there in the warehouse?
Options:
A)6
B)8
C)10
D)15
E)30
Rationale: Total number of ways to choose 2 chairs from 5 r= 5C2=10
Total number of combination=150
That means we need get 15 combinations from the selection of tables....
Screening through the answers.... 6C2=15..... 15*10=150
Answer is 6... A
Answer: A
Question: |16 - 5| - |5 - 12| = ?
Options:
A)3
B)2
C)1
D)0
E)4
Rationale: |16 - 5| - |5 - 12| = | 11 | - | -7 | =11 - 7 = 4
correct answer E
Answer: E
Question: 50% of the apartments in a certain building have windows and hardwood floors. 25% of the apartments without windows have hardwood floors. If 40% of the apartments do not have hardwood floors, what percent E of the apartments with windows have hardwood floors?
Options:
A)10
B)16 2/3
C)40
D)50
E)83 1/3
Rationale: yup you need to construct a matrix
X********| Windows'|No Windows'''| total
hardFl****'|50*****''|10*********'|60
Not hardFl*|10******|30*********'|40
Total*****|60******'|40*********'|100
so E percent of the apartments with windows have hardwood floors = 50/60 *100
= 83 1/3
so E is the answer.[/u]
Answer: E
Question: if x/4-x-3/6=1,then find the value of x.
Options:
A)2
B)4
C)6
D)8
E)5
Rationale: (x /4)-((x-3)/6)=1= (3x-2(x-3) )/12 = 1 = 3x-2x+6=12 = x=6
Answer is C.
Answer: C
Question: The probability that a man will be alive for 10more yrs is 1/4 & the probability that his wife will alive for 10 more yrs is 1/3. The probability that none of them will be alive for 10 more yrs, is
Options:
A)1/2
B)1
C)3/4
D)3/5
E)3/7
Rationale: Sol. Required probability = Pg.) x P(B) = (1— D x(1 —I) =: x 1=1/2
Ans.(A)
Answer: A
Question: 8 friends decides to eat pizza. 4 friends eat type 1 pizza which cost 100 each. Remaining friend buy pizza having off on it and saves 100 and each of them pay equal money .Total bill is 800. what is actual cost of each pizza having off on it.
Options:
A)135
B)115
C)120
D)125
E)140
Rationale: Solution: D.8 friend = 800. per friend 100. Saves 100 and each of them paid 100 and saved 100/4=25. so pizza had a 20% off so actual cost is 125 for each pizza having discount.
Answer: D
Question: Look at this series: 7, 10, 8, 11, 9, 12, 10, 13, 11, 14, 12, ... What number should come next?
Options:
A)12
B)13
C)14
D)15
E)16
Rationale: This is a simple alternating addition and subtraction series. In the first pattern, 3 is added; in the second, 2 is subtracted.
The answer is D.
Answer: D
Question: A train 150 m long running at 72 kmph crosses a platform in 25 sec. What is the length of the platform?
Options:
A)338
B)277
C)350
D)881
E)271
Rationale: D = 72 * 5/18 = 25 = 500 – 150 = 350
Answer: C
Answer: C
Question: The cost price of a radio is Rs.1500 and it was sold for Rs.1230, find the loss %?
Options:
A)18%
B)19%
C)28%
D)38%
E)58%
Rationale: 1500 ---- 270
100 ---- ? => 18%
Answer: A
Answer: A
Question: Excluding stoppages, the speed of a train is 45 kmph and including stoppages it is 36 kmph. Of how many minutes does the train stop per hour?
Options:
A)72
B)62
C)12
D)72
E)27
Rationale: Explanation:
T = 9/45 * 60 = 12
Answer: Option C
Answer: C
Question: A car traveling with 5/7 of its actual speed covers 42 km in 1 hr 40 min 48 sec. What is the actual speed of the car?
Options:
A)30km/hr
B)35km/hr
C)25km/hr
D)40km/hr
E)45km/hr
Rationale: Explanation:
time =1 hr 40 min 48 sec
=1 hr +4060 hr +48/3600 hr
=1+2/3+1/75=126/75hr
distance =42 km
speed=distance/time=42(126/75) =42Ã—75/126=25 km/hr=25 km/hr
â‡’57 of the actual speed =25
â‡’ Actual speed =25Ã—7/5=35 km/hr
ANSWER IS B
Answer: B
Question: A and B can do a piece of work in 18 days; Band C can do it in 24 days A and C can do it in 36 days. In how many days will A, Band C finish it together?
Options:
A)15 days
B)12 days
C)8 days
D)16 days
E)9 days
Rationale: Sol. (A + B)'s 1 day's work = (1/18) (B + C)'s 1 day's work = (1/24)
and (A + C)'s 1 day's work = (1/36)
Adding, we get: 2 (A + B + C)'s 1 day's work =¬(1/18 + 1/24 + 1/36)
=9/72 =1/8
(A +B + C)'s 1 day's work =1/16
Thus, A, Band C together can finish the work in 16 days.
Ans: D
Answer: D
Question: P and Q started a business with respective investments of Rs. 4 lakhs and Rs. 10 lakhs. As P runs the business, his salary is Rs. 5000 per month. If they earned a profit of Rs. 2 lakhs at the end of the year, then find the ratio of their earnings?
Options:
A)1:5
B)1:0
C)1:3
D)1:1
E)1:2
Rationale: Ratio of investments of P and Q is 2 : 5
Total salary claimed by P = 12 * 5000 = Rs. 60000
Total profit = Rs. 2 lakhs.
Profit is to be shared = Rs. 140000
Share of P = (2/7) * 140000 = Rs. 400000
Share of Q = Rs. 100000
Total earnings of P = (60000 + 40000) = Rs. 100000
Ratio of their earnings =1:1
Answer: D
Answer: D
Question: A cube of side one meter length is cut into small cubes of side 10 cm each. How many such small cubes can be obtained?
Options:
A)10
B)100
C)1000
D)10000
E)100000
Rationale: Along one edge, the number of small cubes that can be cut
= 100/10 = 10
Along each edge 10 cubes can be cut. (Along length, breadth and height). Total number of small cubes that can be cut = 10 * 10 * 10 = 1000
Answer: Option C
Answer: C
Question: in a tennis tournment there are 137 players .to decide the winner among them how many matches should be played among them.such that if a player losts the match he is not eligible for the next round
Options:
A)116
B)126
C)136
D)146
E)156
Rationale: 1 match = 1 player out.
2 match = 2 player out.
Like that,
136 match = 136 players out.
ANSWER:C
Answer: C
Question: Because of weight limits, a lorry can carry a maximum of 20 crates of apples. The weight of a crate of oranges is 3434 the weight of a crate of apples. If 10 crates of apples were loaded into the lorry, what is the maximum number of crates of oranges that the lorry can still accommodate?
Options:
A)8
B)9
C)12
D)13
E)14
Rationale: There's still room for 10 crates of apples. The weight of 10 crates of apples is the same as the weight of 10∗(4/3)=13 1/3 crates of oranges. Because the number of crates has to be an integer, the lorry can accommodate a maximum of 13 crates of oranges.
Answer: D
Answer: D
Question: A certain restaurant offers 8 different salads, 5 different main courses, 6 different desserts. If customers choose one salad, one main course and two different desserts for their meal, how many different meals are possible?
Options:
A)120
B)240
C)480
D)600
E)1200
Rationale: In order to select x things from group of n things can be written as nCx
8C1*5C1*6C2= 8*5*15=600 answer is D
Answer: D
Question: A and B together can do a piece of work in 6 days and A alone can do it in 9 days. In how many days can B alone can do it?
Options:
A)12 days
B)15 days
C)18 days
D)21 days
E)22 days
Rationale: Explanation:
A and B can do work 1/6 in 1 day
A alone can do 1/9 work in 1 day
B alone can do (1/6 -1/9) =1/18 work in 1 day
=> complete work can be done in 18 days by B
Answer: Option C
Answer: C
Question: The distance between two cities A and B is 330 km. A train starts from A at 8 a.m. and travel towards B at 60 km/hr. Another train starts from B at 9 a.m. and travels towards A at 75 Km/hr. At what time will they meet?
Options:
A)10
B)07
C)08
D)11
E)04
Rationale: Explanation :
Assume that they meet x hours after 8 a.m.
Then, train1,starting from A , travelling towards B, travels x hours till the trains meet
⇒Distance travelled by train1 in x hours = Speed ×Time = 60x
Then, train2, starting from B , travelling towards A, travels (x-1) hours till the trains meet
⇒Distance travelled by train2 in (x-1) hours = Speed ×Time = 75(x-1)
Total distance travelled = Distance travelled by train1 + Distance travelled by train2
=> 330 = 60x + 75(x-1)
=> 12x + 15(x-1) = 66
=> 12x + 15x - 15 = 66
=> 27x = 66 + 15 = 81
=> 3x = 9
=> x = 3
Hence the trains meet 3 hours after 8 a.m., i.e. at 11 a.m.
Answer : D
Answer: D
Question: What was the day of the week on 17th June 1998?
Options:
A)Monday
B)Sunday
C)Wednesday
D)Friday
E)None of these
Rationale: Explanation :
17 Jun 1998 = (1997 years + period from 1-Jan-1998 to 17-Jun-1998)
We know that number of odd days in 400 years = 0
Hence the number of odd days in 1600 years = 0 (Since 1600 is a perfect multiple of 400)
Number of odd days in the period 1601-1900
= Number of odd days in 300 years
= 5 x 3 = 15 = 1
(As we can reduce perfect multiples of 7 from odd days without affecting anything)
Number of odd days in the period 1901-1997
= 73 normal years + 24 leap year
= 73 x 1 + 24 x 2 = 73 + 48 = 121 = (121 - 7 x 17) = 2 odd days
Number of days from 1-Jan-1998 to 17-Jun-1998
= 31 (Jan) + 28 (Feb) + 31 (Mar) + 30 (Apr) + 31(may) + 17(Jun)
= 168 = 0 odd day
Total number of odd days = (0 + 1 + 2 + 0) = 3
3 odd days = Wednesday
Hence 17th June 1998 is Wednesday. Answer : Option C
Answer: C
Question: From a pack of cards two cards are drawn one after the other, with replacement. The probability that the first is a red card and the second is a king is?
Options:
A)1/26
B)1/23
C)1/22
D)1/97
E)1/27
Rationale: Let E1 be the event of drawing a red card.
Let E2 be the event of drawing a king .
P(E1 ∩ E2) = P(E1) . P(E2)
(As E1 and E2 are independent)
= 1/2 * 1/13
= 1/26
Answer:A
Answer: A