divelab/Sys2Bench huggingface dataset:
Question: In what time will Rs.4200 lent at 3% per annum on simple interest earn as much interest as Rs.5000 will earn in 5 years at 4% per annum on simple interest?
Options:
A)8 1/3
B)8 1/6
C)8
D)8 1/2
E)8 1/5
Rationale: (4200*3*R)/100 = (5000*5*4)/100
R = 8
Answer: C
Answer: C
Question: A thief steels a car at 2.30p.m. and drives it at 60kmph. The theft is discovered at 3p.m. and the owner sets off in another car at 75 kmph. When will he overtake the thief?
Options:
A)5p.m.
B)6p.m.
C)4p.m.
D)7p.m.
E)3p.m.
Rationale: Suppose the thief overtakes x hours after 2.30p.m.
Distance covered by the thief in x hrs = distance covered by the owner in (x-1/2 hours)
60x = 75(x-1/2)
15x = 75/2
x = 5/2 hrs
Thief is overtaken at 5p.m.
Answer is A
Answer: A
Question: (1/36)+(1/37)+……+(1/66)+(1/67) is including in which of the following ranges?
Options:
A)2
B)1
C)1~ 2
D)3
E)1/2~1
Rationale: Number of terms in the given series = 32.
The lowest term is 1/67 , the largest being 1/36.
Thus, the sum of the given series will be more than
1/67 + 1/67.....1/67 (32 times)
---> 32*(1/67) = 32/67
less than 1/36 + 1/36...... 1/33 (32 times)
---> 32*(1/36) = 32/36 = 1 (approx)
E
Answer: E
Question: B completes a work in 3 days. A alone can do it in 10 days. If both work together, the work can be completed in how many days?
Options:
A)2.31 days
B)4.31 days
C)5.31 days
D)6.31 days
E)7.31 days
Rationale: 1/3 + 1/10 = 13/30
30/13 = 2.31 days
ANSWER:A
Answer: A
Question: The S.I. on a certain sum of money for 3 years at 8% per annum is half the C.I. on Rs. 4000 for 2 years at 10% per annum. The sum placed on S.I. is?
Options:
A)2197
B)1267
C)1750
D)2267
E)1262
Rationale: Explanation:
C.I. = [4000 * (1 + 10/100)2 - 4000]
= (4000 * 11/10 * 11/10 - 4000) = Rs. 840.
Sum = (420 * 100)/(3 * 8) = Rs. 1750
Answer:C
Answer: C
Question: How many four digit even numbers can be formed using the digits {2, 3, 5, 1, 7, 9}
Options:
A)100
B)360
C)120
D)240
E)60
Rationale: Explanation:
The given digits are 1, 2, 3, 5, 7, 9
A number is even when its units digit is even. Of the given digits, two is the only even digit.
Units place is filled with only '2' and the remaining three places can be filled in ⁵P₃ ways.
Number of even numbers = ⁵P₃ = 60.
ANSWER IS E
Answer: E
Question: The ratio of two numbers is 3:4 and their sum is 28. The greater of the two numbers is?
Options:
A)16
B)18
C)20
D)24
E)25
Rationale: 3:4
Total parts = 7
= 7 parts --> 28 (7 × 4 = 28)
= 1 part ---->4 (1 × 4 = 4)
= The greater of the two number is = 4
= 4 parts ----> 16 (4 × 4 = 16)
A
Answer: A
Question: If the function Q is defined by the formula Q = 5e/(4x(z^2)), by what factor will Q be multiplied if e is quadrupled, x is doubled, and z is tripled?
Options:
A)1/9
B)2/9
C)4/9
D)3/9
E)2/27
Rationale: We just need to find the factor thats all,
e -> quadrupled -> 4e
x-> doubled -> 2x
z-> tripled -> 3Z
Hence, Z^2 = 9Z^2
e is in numerator, and x*z in denominator.
Hence,
Additional factor being introduced = 4/2*9
=4/18 = 2/9 = B
Answer: B
Question: The greatest common factor of two numbers is 6!. Which of the following can be the second number, if one of the numbers is 8!?
Options:
A)3(5!)
B)4(5!)
C)5(5!)
D)6(6!)
E)7(5!)
Rationale: GCF is the product of common factors of the numbers involved.
GCF = 6!
a = 8! = 8*7*6!
b will certainly have 5! and cannot have any more common factors with a (as this will increase the GCF)
Looking at the answers only 6 (6!) and 8! will have GCF as 6!
Ans D
Answer: D
Question: if the ratio of simple interest on certain sum with same rate is 4:3.what is the ratio of time.
Options:
A)3:5
B)6:5
C)5:4
D)4:3
E)2:3
Rationale: let ratio constant be x.
4x/3x=(p*r*t1/100)/(p*r*t2/100)
t1/t2=4:3.
answer D
Answer: D
Question: The average of the first five prime numbers greater than 20 is:
Options:
A)32.2
B)32.22
C)31.22
D)32.27
E)32.28
Rationale: Explanation:
Required prime numbers are 23, 29, 31, 37, 4.
Average will be (23 + 29 + 31 + 37 + 41)/5 = 32.20
Answer: A
Answer: A
Question: 4623.186 is rounded off to the nearest thousand, hundred, ten and one. Let the results be represented with the alphabets r,s,t,u respectively. which of the statements below is accurate?
Options:
A)t<s<u<r
B)u<t<s<r
C)s<r<u<t
D)s<u<t<r
E)s<t<u<r
Rationale: 4623.186..
Nearest thousand 5000..r
Nearest hundred 4600..s
Nearest ten 4620..t
Nearest one 4623..u
s<t<u<r
The correct option is E
Answer: E
Question: Four numbers are in the ratio 2:3:4:5 add up to give a sum of 1344. Find the biggest number.
Options:
A)480
B)239
C)270
D)282
E)112
Rationale: ANSWER : A
Answer: A
Question: A gardener increased the length of a rectangle-shaped garden by 20 percent and decreased its width by 10 percent. The area of the new garden
Options:
A)has increased by 20 percent
B)has increased by 12 percent
C)has increased by 8 percent
D)is exactly the same as the old area
E)cannot be expressed in percentage terms without actual numbers
Rationale: Let L be the original length and let W be the original width.
The original area was L*W.
The new area is 0.9W*1.2L = (0.9)(1.2)L*W = 1.08*L*W
The answer is C.
Answer: C
Question: Pipe A can fill a tank in 5 hours, pipe B in 10 hours and pipe C in 30 hours. If all the pipes are open, in how many hours will the tank be filled ?
Options:
A)2
B)2.5
C)3
D)3.5
E)None
Rationale: Solution
part filled by (A+B+C) in 1 hour	= (1/5 + 1/6 + 1/30)
‹=› 1/3.
All the three pipes together will fill the tank in 3 hours.
Answer C
Answer: C
Question: On a trip, a cyclist averaged 9 miles per hour for the first 18 miles and 10 miles per hour for the remaining 12 miles. If the cyclist returned immediately via the same route and took a total of 7.2 hours for the round trip, what was the average speed (in miles per hour) for the return trip?
Options:
A)6.9
B)7.2
C)7.5
D)7.8
E)8.1
Rationale: The time to go 30 miles was 18/9+12/10=2+1.2=3.2 hours.
The average speed for the return trip was 30 miles/4 hours= 7.5 mph.
The answer is C.
Answer: C
Question: The cricket team of 11members is 28yrs old & the wicket keeper is 3 yrs older. If the ages ofthese 2are excluded, the average age of theremaining players is 1 year less than the average age of the whole team. What is the average age of the team ?
Options:
A)21
B)22
C)23
D)25
E)28
Rationale: Let the average age of the whole team be x years.
11x - (28 + 31) = 9 (x - 1)
=> 11x - 9x = 50
=> 2x = 50
=> x = 25.
So, average age of the team is 25 years.
D
Answer: D
Question: If the sides of a triangle are 30 cm, 28 cm and 12 cm, what is its area?
Options:
A)120 cm2
B)112 cm2
C)776 cm2
D)666 cm2
E)168 cm2
Rationale: The triangle with sides 30 cm, 28 cm and 12 cm is right angled, where the hypotenuse is 30 cm.
Area of the triangle = 1/2 * 28 * 12 = 168 cm2
Answer: E
Answer: E
Question: A group of students was interviewed for that if it was asked whether or not they speak French and / or English. Among those who speak French, 30 speak English well, while 40 of them do not speak English. If 86% of students do not speak French, how many students were surveyed?
Options:
A)500
B)450
C)250
D)350
E)525
Rationale: Number of students who speak French are 30 + 40 = 70
Of total students, the percentage of students who do not speak French was 86% --> percentage of who do is 14%
70-------14%
x ------- 100%
x = 70*100/14 = 500 = number of all students
Answer is A
Answer: A
Question: The product of two numbers is 4107. If the H.C.F of these numbers is 37, then the greater number is:
Options:
A)101
B)107
C)111
D)112
E)113
Rationale: Let the numbers be 37a and 37b.
Then, 37a * 37 b = 4107 => ab = 3
Now, co-primes with product 3 are (1, 3).
So, the required numbers are (37 * 1, 37 * 3) i.e., (1, 111).
Greater number = 111.
ANSWER:C
Answer: C
Question: When positive integer x is divided by 6, the remainder is 1. Which of the following must be true?
I. x is a prime number
II. x is odd
III. x is divisible by 7
Options:
A)I only
B)II only
C)III only
D)I and II only
E)II and III only
Rationale: X=6q+1
Examine II) put q=0,1,2,3....... we have x=1,7,13,...25 so x must be odd
Examine III) 14/6 has reminder 2 & 49/7 has reminder 1 so not always true
Examine I) X= 7 true but while 2 is prime, it does not give reminder 1
Answer: B
Answer: B
Question: Rs.8000 become Rs.8988.80 in a certain interval of time at the rate of 6% per annum of C.I. Find the time?
Options:
A)6 years
B)8 years
C)9 years
D)3 years
E)2 years
Rationale: 8988.80 = 8000(53/50)N
(53/50)^2 = (53/50)^N
N = 2
At the end of two years what will be the comp.Answer: E
Answer: E
Question: If a two-digit positive integer has its digits reversed, the resulting integer differs from the original by 45. By how much do the two digits differ?
Options:
A)3
B)4
C)5
D)6
E)7
Rationale: we are given that if the integer N has its digits reversed the resulting integer differs from the original by 45. First let’s express the reversed number in a similar fashion to the way in which we expressed the original integer.
10B + A = reversed integer
Since we know the resulting integer differs from the original by 45 we can say:
10B + A – (10A + B) = 45
10B + A – 10A – B = 45
9B – 9A = 45
B – A = 5
Since B is the tens digit and A is the units digit, we can say that the digits differ by 5.
The answer is C.
Answer: C
Question: Veena ranks 73rd from the top in a class of 198. What is her rank from the bottom if 22 students have failed the examination?
Options:
A)88
B)104
C)110
D)90
E)93
Rationale: total student=198
failed=22
paasd student=198-22=176
from bottom her rank is=176-73+1=104
ANSWER:B
Answer: B
Question: The sum of the squares of three numbers is 138, while the sum of their products taken two at a time is 131. Their sum is:
Options:
A)20
B)30
C)40
D)50
E)60
Rationale: Let the numbers be a, b and c.
Then, a2 + b2 + c2 = 138 and (ab + bc + ca) = 131.
(a + b + c)2 = a2 + b2 + c2 + 2(ab + bc + ca) = 138+2x131= 400.
(a + b + c) = square root of 400 = 20
answer :A
Answer: A
Question: Which of the following has 60^80 as a factor?
Options:
A)15^60
B)30^40
C)120^80
D)60^60
E)90^80
Rationale: Here 60^80 = 30^80 * 20^80 Only Option C has both .
Smash C
Answer: C
Question: Which of the following leads to the correct mathematical solution for the number of ways that the letters of the word TIE could be arranged to create a three-letter code?
Options:
A)3!
B)3! − (3! + 2!)
C)3! − (2!)
D)3!/(3! + 2!)
E)3!/(3! × 2!)
Rationale: TIE - three letters can be arranged in 3! ways
since 'there is no repetition'
3!
Ans. A) 3!
Answer: A
Question: ----------------YES---------NO----UNSURE Subject M----500--------200-----100 Subject R----400--------100-----300 A total of 800 students were asked whether they found two subjects, M and R, interesting. Each answer was either yes or no or unsure, and the numbers of students who gave these answers are listed in the table above. If 150 students answered yes only for subject M, how many of the students did not answer yes for either subject?
Options:
A)100
B)250
C)300
D)400
E)500
Rationale: Since 150 students answered yes only for subject M, then the remaining 350 students who answered yes for subject M, also answered yes for subject R. So, 350 students answered yes for both subjects.
If 350 students answered yes for both subjects, then 400-350=50 students answered yes only for subject R.
So, we have that:
200 students answered yes only for subject M;
50 students answered yes only for subject R;
300 students answered yes for both subjects;
Therefore 800-(200+50+300)=250 students did not answer yes for either subject.
Answer: B.
Answer: B
Question: In 1982 and 1983, Company B’s operating expenses were $10.0 million and $12.0 million, respectively, and its revenues were $15.6 million and $18.8 million, respectively. What was the percent increase in Company B’s profit (revenues minus operating expenses) from 1982 to 1983 ?
Options:
A)3%
B)16 2/3%
C)25%
D)21 3/7%
E)60%
Rationale: Profit in 1982 = 15.6 - 10 = 5.6 million $
Profit in 1983 = 18.8 - 12 = 6.8 million $
Percentage increase in profit = (6.8-5.6)/5.6 * 100 %
= 21 3/7%
Answer D
Answer: D
Question: A car travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. What is the average speed for the first 320 km of the tour?
Options:
A)71.11
B)71.12
C)71.1
D)71.17
E)71.13
Rationale: Car travels first 160 km at 64 km/hr
Time taken to travel first 160 km = distancespeed=16064
Car travels next160 km at 80 km/hr
Time taken to travel next 160 km = distancespeed=16080Total distance traveled = 160+160=2×160Total time taken = 16064+16080Average speed = Total distance traveledTotal time taken=2×16016064+16080=2164+180=2×64×8080+64=2×64×80144=2×8×8018=6409=71.11 km/hr
Answer:A
Answer: A
Question: Two terms are in 3 : 4, if 10 is added to each of the terms, they will be 4 : 5. Find second term?
Options:
A)10
B)30
C)20
D)40
E)35
Rationale: Solution:
Let the two numbers be 3x and 4x. Then, (3x+10)/(4x+10) = 4/5.
=> 15x+50 = 16x+40 => x = 10.
.'. Second term = 4*10 =40.
ANSWER IS D
Answer: D
Question: How many different ways can you select a pilot and a co pilot if you have 70 people to choose from?
Options:
A)199
B)200
C)398
D)4950
E)4830
Rationale: 1) PERMUTATION:-
since it is selection, we have to find permutation..
70P2= 70!/(70-2)!=4830
ANS:E
Answer: E
Question: We have 36kg flour and 60kg sugar in stock and we would like to use the minimum number of packs that would have the same weight for both flour and sugar. How much more sugar is required if we would like to full 10 packs either of flour or sugar?
Options:
A)12
B)18
C)20
D)24
E)30
Rationale: k is the integer that represents kg of pack
ak = 36 --> k = 36/a
bk = 60 --> k = 60/b
36/a = 60/b --> 5a = 3b and then k=12 for min(a+b)
a=36/12=3 , b=60/12=5
Total number of packs = 3+5 = 8
10-8=2 packs more required
2 *12 = 24 kg more sugar required to have 10 packs.
ANSWER: D
Answer: D
Question: You are visiting your friend. When you walk in her room, you find that there are seven girls. Each of the seven girls have seven bags which consist of 7 adult cats each. Now, each of the adult cat has seven little cats as well along with them.
We know that each cat has four legs, can you find out the total number of legs in the room?
Options:
A)26197
B)23578
C)10992
D)14728
E)11092
Rationale: C
10992
Each girl has seven bags with seven adult cats each.
Also, each adult cat has seven little cats.
Thus each girl has 49 adult cats and 343 little cats.
Hence, seven girls will have
343 adult cats and 2410 little cats.
If we calculate the number of legs now.
Girls = 7 * 2 = 14
Cats + Little cats = 2744 * 4 = 10976
Total legs = 10976 + 14 = 10990
Since I also walked in the room, there will be two more legs.
Now total legs = 10990 + 2 = 10992.
Answer: C
Question: A and B together have Sterling 1260. If 4/15 of A's amount is equal to 2/5 of B's amount, how much amount does B have?
Options:
A)Sterling 460
B)Sterling 484
C)Sterling 550
D)Sterling 504
E)None
Rationale: Explanation: 4/15A = 2/5B
A = (2/5 x 15/4)B
A = 3/2 B
A/B = 3/2
A : B = 3 : 2.
B's share = Sterling (1260 x 2/5) = Sterling 504.
Answer: Option D
Answer: D
Question: In a shop 80% of the articles are sold at a profit of 10% and the remaining at a loss of 40%.what is the overall profit/loss?
Options:
A)10% profit
B)10% loss
C)15% profit
D)no profit, no loss
E)none
Rationale: 80*1.1+20*0.6/100=1
ANSWER:D
Answer: D
Question: Some ladies can do a piece of work in 12 days. Two times the number of such ladies will do half of that work in :
Options:
A)6 days
B)4 days
C)12 days
D)3 days
E)7 days
Rationale: Let x ladies can do the work in 12 days. More ladies, less days (Indirect)
Less work, less days (direct)
Ladies 2x : x Work 1 : ½
2x : x , 1 : ½ : : 12 : y
:. 2x * 1*y = x* ½ *12 or y = 3
Hence the required number of days = 3
ANSWER:D
Answer: D
Question: A bus can hold 108 passengers. If there are 12 rows of seats on the bus, how many seats are in each row?
Options:
A)1
B)2
C)9
D)25
E)26
Rationale: Total number of passengers = 108
There are 12 rows of seats on the bus.
To find how many seats are there in each row, divide the total number of passengers by the number of rows of seats on the bus.
We get, divide 108 by 12
108 ÷ 12 = 9
Therefore, there are 9 seats in each row
ANSWER IS C
Answer: C
Question: The average age of M boys is ‘b’ years and of ‘n’ girls ‘c’ years. The average age of all together is?
Options:
A)(mb + nc)/ (m + b) years
B)(mb + bc)/ (m + n) years
C)(mb + nc)/ (m + n) years
D)(nb + nc)/ (m + n) years
E)(mb + nb)/ (m + n) years
Rationale: (mb + nc) / (m+ n).nswer: C
Answer: C
Question: An automobile financier claims to be lending money at S.I., but he includes the interest every six months for calculating the principal. If he is charging an interest of 10%, the effective rate of interest becomes?
Options:
A)10.28%
B)10.25%
C)10.85%
D)30.25%
E)10.15%
Rationale: Let the sum be Rs. 100. Then,
S.I. for first 6 months = (100 * 10 *1) / (100 * 2) = Rs. 5
S.I. for last 6 months = (105 * 10 * 1) / (100 * 2) = Rs. 5.25
So, amount at the end of 1 year = (100 + 5 + 5.25) = Rs. 110.25
Effective rate = (110.25 - 100) = 10.25%.
Answer: B
Answer: B
Question: Two numbers are less than third number by 32% and 37% respectively. How much percent is the second number less than by the first
Options:
A)8%
B)10%
C)9%
D)11%
E)14%
Rationale: Let the third number is x.
then first number = (100-32)% of x
= 68% of x
Second number is (63x/100)
Difference = 68x/100 - 63x/100 = x/20
So required percentage is, difference is what percent of first number
(x/20 * 100/68x * 100 )% = 14% ANSWER :E
Answer: E
Question: A train 3000 m long can cross an electric pole in 120 sec and then find the speed of the train?
Options:
A)90
B)95
C)100
D)105
E)110
Rationale: Length = Speed * time
Speed = L/T
S = 3000/120
S = 25 M/Sec
Speed= 25*18/5 (To convert M/Sec in to Kmph multiply by 18/5)
Speed = 90 Kmph
Answer:A
Answer: A
Question: The area of a square is equal to five times the area of a rectangle of dimensions 125 cm * 64 cm. What is the perimeter of the square?
Options:
A)876 cm
B)800 cm
C)167 cm
D)765 cm
E)167 cm
Rationale: Area of the square = s * s = 5(125 * 64)
=> s = 25 * 8 = 200 cm
Perimeter of the square = 4 * 200
= 800 cm.
Answer:B
Answer: B
Question: x and y are positive integers. If xy + 4x is odd, then which of the following must be even?
Options:
A)x
B)y
C)x + y
D)xy − x
E)y+4
Rationale: Given that xy + 4x is odd, which means x(y+4) is odd.
Product of two nos. will be odd only if both the nos. are odd.
Hence x is odd, y+4 is also odd.
y+4 is odd means y is even. Answer will be E.
Answer: E
Question: By selling 200 apples, a fruit-seller gains the selling price of 50 apples. Find the gain percent?
Options:
A)33.33%
B)35%
C)27.75%
D)35.75%
E)32.25%
Rationale: SP = CP + g
200 SP = 200 CP + 50 SP
150 SP = 200 CP
150 --- 50 CP
100 --- ? => 33.33%
Answer: A
Answer: A
Question: If C is the temperature in degrees Celsins and F is the temperature in degrees Fahrenheit, then the relationship between temperatures on the two scales is expressed by the equation 9C=5(F-32). In a weekly range of temperature recorded at a certain weather station differed by 25 degrees on the Fahrenheit scale, by how many degrees did the temperature extremes differ on the Celsius scale?
Options:
A)a) 65/9
B)b) 13
C)c) 25
D)d) 45
E)e) 81
Rationale: The relationship is 9/5 - 32, so approximately half of difference in Celsius (the -32 part won't be used in this case). Just looking at the answer choices you can pick B which is the only number near half of 25. The other answer choices are too far apart so no need to calculate.
Answer: B
Question: Pipe A can fill a tank in 10 hours, pipe B in 20 hours, and pipe C in 60 hours. If all the pipes are open, in how many hours will the tank be filled?
Options:
A)6
B)7
C)8
D)9
E)10
Rationale: The part filled by A + B + C in 1 hour is 1/10 + 1/20 + 1/60 = 1/6
All the three pipes together will fill the tank in 6 hours.
The answer is A.
Answer: A
Question: A dishonest grocer professes to sell pure butter at cost price, but he mixes it with adulterated fat and thereby gains 35%. Find the percentage of adulterated fat in the mixture assuming that adulterated fat is freely available?
Options:
A)20%
B)25%
C)33.33%
D)40%
E)30%
Rationale: Say 100g pure butter costs $100
But; $100 is his 35% profit because he just used 80gram pure butter.
80g would have costed him $80 and he sold it for $100 by adding 20g of freely available fat. $100 is 1.35(70)
so;
total weight=100g
fat=30g
30%
E
Answer: E
Question: Dacid obtained 76, 65, 82, 67 and 85 marks (out of 100) in English, Mathematics, Physics, Chemistry and Biology. What are his average marks?
Options:
A)67
B)55
C)77
D)83
E)75
Rationale: Average
= (76 + 65 + 82 + 67 + 85)/5
= 375/5 = 75.
Answer:E
Answer: E
Question: If two of the four expressions x+y, x+5y, x-y, and 5x-y are chosen at random, what is the probability Q that their product will be of the form of x^2-(by)^2, where b is an integer?
Options:
A)Q=1/2
B)Q=1/3
C)Q=1/4
D)Q=1/5
E)Q=1/6
Rationale: Only (X+y)(x-y) pair will give the form x^2-(by)^2
The probability of selecting these two pairs are 1/4 * 1/3 = 1/12, assuming x+y is picked first, then x-y, but x-y can be picked first followed by x+y. So the probability Q= 1/12 * 2 = 1/6
Ans E
Answer: E
Question: The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is
Options:
A)33
B)40
C)38
D)27
E)211
Rationale: Explanation:
Sum of the present ages of husband, wife and child = (27 x 3 + 3 x 3) years = 90 years.
Sum of the present ages of wife and child (20 x 2 + 5 x 2) years = 50 years.
Husband's present age = (90 - 50) years = 40 years.
Answer: B) 40
Answer: B
Question: A boat running downstream covers a distance of 20 km in 2 hours while for covering the same distance upstream, it takes 5 hours. What is the speed of the boat in still water?
Options:
A)6
B)7
C)8
D)9
E)1
Rationale: Explanation:
Rate downstream = (20/2) kmph = 10 kmph;
Rate upstream = (20/5) kmph = 4 kmph
Speed in still water = 1/2 (10 + 4) kmph = 7 kmph
ANSWER: B
Answer: B
Question: A man sells a car to his friend at 12% loss. If the friend sells it for Rs.54000 and gains 20%, the original C.P.of the car was :
Options:
A)Rs.21136.36
B)Rs.31136.36
C)Rs.51136.36
D)Rs.61136.36
E)None of these
Rationale: Explanation:
S.P = Rs.54,000. Gain earned = 20%
C.P = Rs.[100/120Ã—54000]
=Rs. 45000
This is the price the first person sold to the second at at loss of 12%.
Now S.P = Rs.45000 and loss = 12%
C.P. Rs.[100/88Ã—45000]= Rs.51136.36
Correct Option : C
Answer: C
Question: In an election between two candidates, one got 55% of the total valid votes, 20% of the votes were invalid. If the total number of votes was 5500, the number of valid votes that the other candidate got, was:
Options:
A)2800
B)1980
C)2900
D)2200
E)2300
Rationale: B
Number of valid votes = 80% of 5500 = 4400.
Valid votes polled by other candidate = 45% of 4400
= (45/100 x 4400) = 1980.
Answer: B
Question: How many meters are there in 330 centimeters?
Options:
A)550 meters
B)3.3 meters
C)100 meters
D)3.5 meters
E)3 meter
Rationale: Solution:
1 meter = 100 centimeters
Just divide 330 by 100
330 Ã· 100 = 3.3, so there are 3.3 meters in 330 centimeters
Option B
Answer: B
Question: In a can, there is a mixture of milk and water in the ratio 4 : 5. If it is filled with an additional 8 litres of milk the can would be full and ratio of milk and water would become 6 : 5. Find the capacity of the can?
Options:
A)40
B)44
C)47
D)83
E)84
Rationale: Explanation:
Let the capacity of the can be T litres.
Quantity of milk in the mixture before adding milk = 4/9 (T - 8)
After adding milk, quantity of milk in the mixture = 6/11 T.
6T/11 - 8 = 4/9(T - 8)
10T = 792 - 352 => T = 44.
Answer: Option B
Answer: B
Question: The sum of the mean, the median, and the range of the set {1,2,3} equals which one of the following values?
Options:
A)3
B)4
C)5
D)6
E)7
Rationale: Here Mean => 1+2+3/3 => 2
median => 2
and range => 3-1 => 2
hence sum => 2+2+2 => 6
Answer: D
Answer: D