divelab/Sys2Bench huggingface dataset:
Question: An exhibition was conducted for 4 weeks. The number of tickets sold in 2nd work week was increased by 20% and increased by 16% in the 3rd work week but decreased by 20% in the 4th work week. Find the number of tickets sold in the beginning, if 1392 tickets were sold in the last week
Options:
A)6
B)35
C)120
D)1250
E)740
Rationale: Answer: 1250
Explanation:
let initially A ticket has been sold.
So now in 2nd week 20% increases so
A × 120100120100
In 3rd week 16% increases so
A × 120100120100 × 116100116100
In 4th week 20% decrease so
A × 120100120100 × 116100116100 × 120100120100 = 1392
A = 1250
Answer:D
Answer: D
Question: Let exp(m,n) = m to the power n. If exp(10, m)= n exp(2,2) where m and n are integers then n= ___?
Options:
A)24
B)25
C)26
D)27
E)28
Rationale: 10^m=n*(2^2)
(2*5)^m=n*(2^2)
(2^m)*(5^m)=n*(2^2) now equate both side we get m=2 and (5^m)=n
(5^2)=n=>n=25
ANSWER:B
Answer: B
Question: Difference of 2 numbers is 100. If 5% of one number is 10% of the other number, find the addition of2 numbers?
Options:
A)150
B)300
C)210
D)290
E)180
Rationale: Let the numbers be x and y
5% of x = 10% of y
x = 2y
x-y = 100
2y - y =100
y = 100
x = 2y = 200
x+y = 300
Answer is B
Answer: B
Question: If y = 30p, and p is prime, what is the greatest common factor of y and 24p, in terms of p?
Options:
A)p
B)2p
C)6p
D)8p
E)p^2
Rationale: y = 30p = 2*3*5*p
24p = 2^3*3*p
The greatest common factor of 30p and 20p is the product of all the common prime factors, using the lower power of repeated factors. The greatest common factor is 2*3*p = 6p
The answer is C.
Answer: C
Question: A man has some hens and cows. If the number of heads be 48 and the number of feet equals 140, then the number of hens will be
Options:
A)22
B)24
C)26
D)20
E)28
Rationale: Explanation :
Let number of hens = h and number of cows = c
number of heads = 48
=> h + c = 48 ---(Equation 1)
number of feet = 140
=> 2h + 4c = 140
=> h + 2c = 70 ---(Equation 2)
(Equation 2) - (Equation 1) gives
2c - c = 70 - 48
=> c = 22
Substituting the value of c in Equation 1, we get
h + 22 = 48
=> h = 48 - 22 = 26
i.e., number of hens = 26
Answer : C
Answer: C
Question: It takes 8 high school students, working at identical constant individual rates, 10 hours to paint a certain house. At what time will the house be fully painted if 8 students start painting at 9:00 am and one student, working at the same rate, is added per hour starting at 2:00 pm?
Options:
A)5:10 pm
B)5:30 pm
C)5:50 pm
D)6:10 pm
E)6:30 pm
Rationale: Each student paints at a rate of 1/80 of the house per hour.
In 5 hours, the 8 students can paint 40/80 of the house.
From 2 pm to 3 pm, 9 students paint another 9/80 for a total of 49/80.
From 3 pm to 4 pm, 10 students paint another 10/80 for a total of 59/80.
From 4 pm to 5 pm, 11 students paint another 11/80 for a total of 70/80.
12 students can paint the remaining 10/80 of the house in 10/12 of an hour = 50 minutes.
The house is completed at 5:50 pm.
The answer is C.
Answer: C
Question: If books bought at prices ranging from Rs. 200 to Rs. 350 are sold at prices ranging from Rs. 300 to Rs. 425, what is the greatest possible profit that might be made in selling eight books ?
Options:
A)23267
B)2677
C)1800
D)2778
E)76611
Rationale: Explanation:
Least Cost Price = Rs. (200 * 8) = Rs. 1600.
Greatest Selling Price = Rs. (425 * 8) = Rs. 3400.
Required profit = Rs. (3400 - 1600) = Rs. 1800.
Answer: C) 1800
Answer: C
Question: There are 8 stores in town that had a total of 23 visitors on a particular day. However, only 12 people went shopping that day; some people visited more than one store. If 8 people visited exactly two stores each, and everyone visited at least one store, what is the largest number of stores anyone could have visited?
Options:
A)2
B)3
C)4
D)5
E)6
Rationale: 8 people visited 2 stores each for 16 visits.
To maximize the number of stores that one person visited, let's assume that 3 people visited 1 store each. The number of remaining visits is 23 - 16 - 3 = 4, which is the maximum that one person could have visited.
The answer is C.
Answer: C
Question: A car traveling at a certain constant speed takes 4 seconds longer to travel 1 km than it would take to travel 1 km at 80 km/hour. At what speed, in km/hr, is the car traveling?
Options:
A)70
B)72
C)74
D)75
E)78
Rationale: Time to cover 1 kilometer at 80 kilometers per hour is 1/80 hours = 3,600/80 seconds = 45 seconds;
Time to cover 1 kilometer at regular speed is 45 + 4 = 49 seconds = 49/3,600 hours = 1/74 hours;
So, we get that to cover 1 kilometer 1/74 hours is needed --> regular speed 74 kilometers per hour (rate is a reciprocal of time or rate=distance/time).
Answer: C
Answer: C
Question: One night a certain hotel rented 3/5 of its rooms, including 2/3 of their air conditioned rooms. If 3/5 of its rooms were air conditioned, what percent of the rooms that were not rented were air conditioned?
Options:
A)50%
B)55%
C)60%
D)65%
E)70%
Rationale: The rooms which were not rented is 2/5
The AC rooms which were not rented is (1/3)*(3/5) = 1/5
The percentage of unrented rooms which were AC rooms is (1/5) / (2/5) = 1/2 = 50%
The answer is A.
Answer: A
Question: How many seconds will a train 150 meters long take to cross a bridge 150 meters long if the speed of the train is 36 kmph?
Options:
A)28 sec
B)23 sec
C)29 sec
D)30 sec
E)36 sec
Rationale: D
D = 150 + 150 = 300
S = 36 * 5/18 = 10 mps
T = 300/10 = 30 sec
Answer: D
Question: A train 100 m long crosses a platform 125 m long in 15 sec; find the speed of the train?
Options:
A)65 kmph
B)28 kmph
C)54 kmph
D)26 kmph
E)87 kmph
Rationale: D = 100 + 125 = 225
T = 15
S = 225/15 * 18/5
= 54 kmph
Answer:C
Answer: C
Question: In 2008, a certain factory produced 40% more widgets than it did in 2007, and its production in 2009 was 140% of its production in 2008. By approximately what percent would its production need to decrease the following year for the factory to produce the same number of widgets it did in 2007?
Options:
A)33%
B)44%
C)49%
D)60%
E)80%
Rationale: Let P be the original level of production in 2007.
Let x be the rate of production in 2010 compared to 2009.
x*1.4*1.4*P = P
x = 1/1.96 = 0.51 which is a decrease of 49%.
The answer is C.
Answer: C
Question: The number of times 99 is subtracted from 1111 so that the remainder is less than 99 is
Options:
A)10
B)11
C)12
D)13
E)14
Rationale: Sol.
Let it be n times.
Then, (1111 - 99n) < 99.
By hit and trial, we find that n = 11.
Answer B
Answer: B
Question: From a group of 3 women and 3 girls, 4 are to be randomly selected. What is the probability that equal numbers of women and girls will be selected?
Options:
A)3/5
B)1/5
C)2/5
D)4/5
E)1
Rationale: Using the first example, here is the probability of THAT EXACT sequence occurring:
wwGG = (3/6)(2/5)(3/4)(2/3) = 36/360 = 1/10
Each of the other 5 options will yield the exact SAME probability....
wGwG = (3/6)(3/5)(2/4)(2/3) = 36/360 = 1/10
So we have 6 different options that each produce a 1/10 chance of occurring.
6(1/10) = 6/10 = 3/5
Final Answer:
A
Answer: A
Question: The sale price sarees listed for Rs.150 after successive discount is 20% and 10% is?
Options:
A)187
B)120
C)108
D)178
E)175
Rationale: 150*(80/100)*(90/100)
= 108
Answer:C
Answer: C
Question: In a certain sequence, each term except for the first term is one less than twice the previous term. If the first term is 1.5, then the 3rd term is which of the following?
Options:
A)−1.5
B)−1
C)0
D)3
E)2
Rationale: First = 1.5
Second = 2*1.5-1 = 2
Second = 2*2-1 = 3
Answer: option D
Answer: D
Question: The C.P of 15 books is equal to the S.P of 18 books. Find his gain% or loss%?
Options:
A)16 2/3% loss
B)16 2/7% loss
C)16 8/3% loss
D)96 2/3% loss
E)16 4/3% loss
Rationale: 15 CP = 18 SP
18 --- 3 CP loss
100 --- ? => 16 2/3% loss
Answer:A
Answer: A
Question: The cost to park a car in a certain parking garage is $12.00 for up to 2 hours of parking and $1.75 for each hour in excess of 2 hours. What is the average (arithmetic mean) cost per hour to park a car in the parking garage for 9 hours?
Options:
A) $1.09
B) $2.69
C) $2.25
D) $2.37
E) $2.50
Rationale: Total cost of parking for 9 hours = 12$ for the first 2 hours and then 1.75 for (9-2) hours = 12+7*1.75 = 24.25
Thus the AVERAGE parking price = 24.25/9 = 2.69 $
B is the correct answer.
Answer: B
Question: A tank is filled in 10 hours by three pipes A, B and C. The pipe C is twice as fast as B and B is twice as fast as A. How much time will pipe A alone take to fill the tank?
Options:
A)30 hours
B)35 hours
C)70 hours
D)50 hours
E)58hours
Rationale: Let the pipe A can fill the tank in x hours
Then pipe B can fill the tank in x/2 hours and pipe C can fill the tank in x/4 hours
Part filled by pipe A in 1 hour = 1/x
Part filled by pipe B in 1 hour = 2/x
Part filled by pipe C in 1 hour = 4/x
Part filled by pipe A, pipe B and pipe C in 1 hour =( 1/x)+(2/x)+(4/x)=7/x
i.e., pipe A, pipe B and pipe C can fill the tank in x/7 hours
Given that pipe A, pipe B and pipe C can fill the tank in 10 hours
x/7=10
x=10×7=70 hours
Answer is C
Answer: C
Question: The rational number for recurring decimal 0.125125.... is:
Options:
A)125/990
B)125/999
C)125/900
D)12/999
E)12/990
Rationale: 0.125125...
= 0.125
= 125/999
Answer is B.
Answer: B
Question: The 19th of September 1987 was Saturday. What day was the 20th of September 1990 if 1988 was a leap-year?
Options:
A)Monday
B)Tuesday
C)Wednesday
D)Thursday
E)Friday
Rationale: There are 365 days in an ordinary year and 366 days in a leap-year.
365 divided by 7 (a week period) yields a remainder of 1, thus the same date after an ordinary year would fall on the next day of a week;
366 divided by 7 (a week period) yields a remainder of 2, thus the same date after a leap-year would fall two days after in a week;
Thus 3 years, 1988, 1989 and 1990, will accumulate 2+1+1=4 days, plus 1-day difference between 19th and 20th, which gives total of 5-day difference (5-day shift). Thus, 20th of September 1990 was Saturday+5 days=Thursday
Answer: D
Answer: D
Question: A fruit seller sells mangoes at the rate of Rs.9 per kg and thereby loses 20%. At what price per kg, he should have sold them to make a profit of 5%
Options:
A)Rs 8.81
B)Rs 9.81
C)Rs 10.81
D)Rs 11.81
E)None of these
Rationale: Explanation:
85 : 9 = 105 : x
x= (9×105/85)
= Rs 11.81
Option D
Answer: D
Question: Length of a rectangular plot is 10 mtr more than its breadth. If the cost of fencin g the plot at 26.50 per meter is Rs. 5300, what is the length of the plot in mtr?
Options:
A)46 m
B)55 m
C)58 m
D)78 m
E)80 m
Rationale: Let breadth = x metres.
Then, length = (x + 10) metres.
Perimeter = 5300/26.5 = 200 m.
2[(x + 10) + x] = 200
2x + 10 = 100
2x = 90
x = 45.
Hence, length = x + 10 = 55 m
B
Answer: B
Question: A car is purchased on hire-purchase. The cash price is $26 000 and the terms are a deposit of 10% of the price, then the balance to be paid off over 60 equal monthly installments. Interest is charged at 12% p.a. What is the monthly installment?
Options:
A)$603
B)$624
C)$625
D)$626
E)$627
Rationale: Explanation:
Cash price = $26 000
Deposit = 10% Ã— $26 000 = $2600
Loan amount = $26000 âˆ’ $2600
Number of payments = 60
= $23400
I=p*r*t/100
I=14040
Total amount = 23400 + 14040 = $37440
Regular payment = total amount /number of payments= 624
Answer: B
Answer: B
Question: Rahim and his uncle differ in their ages by 30 years. After 7 years, if the sum of their ages is 66, what will be the age of the uncle ?
Options:
A)41
B)36
C)48
D)33
E)44
Rationale: A
41
Let uncle’s present age = x
Rahim's present age = y
y– x= 30 ...(i)
After 7 year
(x + 7) + (y+ 7) = 66
x + y + 14 = 66
x + y = 52 ...(ii)
combining (i) and (ii) we get
(x + y = 52) + (x – y = 30)
2x= 82
x= 41
Uncle's age is 41
Answer: A
Question: Three number are in the ratio of 3 : 4 : 5 and their L.C.M. is 600. What is their H.C.F.?
Options:
A)10
B)20
C)30
D)40
E)50
Rationale: Let the numbers be 3x, 4x and 5x.
Then, their L.C.M. = 60x
60x = 600
x = 10
The numbers are (3 x 10), (4 x 10) and (5 x 10).
The H.C.F. is 10.
The answer is A.
Answer: A
Question: As part of a game, six people each must secretly choose an integer between 1 and 6, inclusive. What is the approximate likelihood that all six people will choose different numbers?
Options:
A)2%
B)12%
C)16%
D)20%
E)25%
Rationale: Ans:a)
1st person has option no's- (1,2,3,4,5,6) - there fore probability of getting a no = 6c1/6c1 = 1
2nd person has option no's any five ,
he has to choose a no from five no's - there fore probability of getting a no = 5c1/6c1 = 5/6
3rd person has option no's any four ,
he has to choose a no from four no's -there fore probability of getting a no = 4c1/6c1 = 4/6
4th person has only one option - there fore probability of getting a no= 3c1/6c1 =3/6
5th person has only one option - there fore probability of getting a no= 2c1/6c1 = 2/6
6th person has only one option - there fore probability of getting a no= 1c1/6c1 = 1/6
=1*5/6*4/6*3/6*2/6*1/6 = 2%
Answer: A
Question: 2. The value of x + x(xx) when x = 2 is:
Options:
A)5
B)10
C)8
D)15
E)20
Rationale: x + x(xx)
Put the value of x = 2 in the above expression we get,
2 + 2(22)
= 2 + 2(2 × 2)
= 2 + 2(4)
= 2 + 8
= 10
Answer : B
Answer: B
Question: The average age of M boys is â€˜bâ€™ years and of â€˜nâ€™ girls â€˜câ€™ years. The average age of all together is?
Options:
A)(mb + nc)/ (m + m) years
B)(mb + nn)/ (m + n) years
C)(mb + nc)/ (m + n) years
D)(nb + nc)/ (m + n) years
E)(mn + nc)/ (m + n) years
Rationale: Explanation:
(mb + nc) / (m+ n)
Answer:C
Answer: C
Question: There are 9 players in a chess group, and each player plays each of the others once. Given that each game is played by two players, how many total games will be played?
Options:
A)10
B)36
C)45
D)60
E)90
Rationale: 10 players are there.
two players play one game with one another.
so 9C2=9*8/2
=36
SO OPTION B is correct
Answer: B
Question: Find the simple interest on Rs. 5000 at 6 % per annum for the period from 5th Feb to 19th April, 2015.
Options:
A)Rs. 40
B)Rs. 50
C)Rs. 60
D)Rs. 70
E)None of these
Rationale: Explanation:
Given:
1) Principal = Rs. 5000
2) Rate of interest = 6 %
3) Time = 5th Feb to 19th April, 2015
First find the time period 5th Feb to 19th April, 2015
Feb = 28 – 5 = 23 days
March = 31 days
April = 19 days
Total days = 23 + 31 + 19 = 73 days
Convert days into years, by dividing it by 365
Time =	73/365	=	1/5
Simple Interest =	(P × R × T)/100
=	[5000 × 6 × (1/5)]/100
=Rs.60
Simple Interest = Rs. 60
ANSWER IS C
Answer: C
Question: A train running at the speed of 60 km/hr crosses a pole in 12 seconds. Find the length of the train?
Options:
A)150
B)872
C)287
D)200
E)212
Rationale: Speed = 60*(5/18) m/sec = 50/3 m/sec
Length of Train (Distance) = Speed * Time
(50/3) * 12 = 200 meter
Answer:D
Answer: D
Question: The volumes of two cones are in the ratio 1 : 12 and the radii of the cones are in the ratio of 1 : 4. What is the ratio of their heights?
Options:
A)A)2:5
B)B)2:7
C)C)2:2
D)D)2:1
E)E)4:3
Rationale: The volume of the cone = (1/3)πr2h
Only radius (r) and height (h) are varying.
Hence, (1/3)π may be ignored.
V1/V2 = r12h1/r22h2 => 1/12 = (1)2h1/(4)2h2
=> h1/h2 = 4/3
i.e. h1 : h2 = 4 : 3
Answer: E
Answer: E
Question: One pipe can fill a pool 1.25 times faster than a second pipe. When both pipes are opened, they fill the pool in 4 hours. How long would it take to fill the pool if only the slower pipe is used?
Options:
A)11.25
B)11.52
C)1.25
D)9
E)7.2
Rationale: Say the rate of the slower pipe is R pool/hour, then the rate of the faster pipe would be 1.25R=5R/4. Since when both pipes are opened, they fill the pool in four hours, then their combined rate is 1/4 pool/hour.
Thus we have that R + 5R/4 = 1/4 --> R = 1/9 pool/hour --> time is reciprocal of rate thus it's 9/1 =9 hours.
Answer: D.
Answer: D
Question: 1000 boys have provisions for 15 days. If 200 more men join them, for how many days will the provisions last now?
Options:
A)12
B)12.5
C)13
D)13.5
E)14
Rationale: Explanation:
1000*15 = 1200*x
x = 12.5
B
Answer: B
Question: When n liters of fuel was added to a tank that was already 2/3 full, the tank was filled to 7/9 of its capacity. In terms of n, what is the capacity of the tank, in liters?
Options:
A)10/9 n
B)4/3 n
C)3/2 n
D)9/4 n
E)9n
Rationale: E is the answer.
To solve this problem, draw diagram or use algebra. I'm more comfortable with algebra.
Given
- tank was already 2/3 full.
- When n ltr added, it became 7/9
So 2/3 + n = 7/9
n = 7/9 - 6/9
n = 1/9
capacity of the tank is full fraction . i.e. 1 i.e. 9/9
so the question is 9/9 is how much times n
= 9/9 = 1 = xn
so x = 9/1
and total = 9/1n=9n
Answer: E
Question: A box contains 13 apples, 12 of which are red. An apple is drawn from the box and its color is noted before it is eaten. This is done a total of n times, and the probability that a red apple is drawn each time is less than 0.5. What is the smallest possible value of n?
Options:
A)3
B)4
C)5
D)6
E)7
Rationale: P(choosing a red apple 7 times in a row) = 12/13*11/12*10/11*9/10*8/9*7/8*6/7 = 6/13 < 0.5
The answer is E.
Answer: E
Question: 96 is divided into two parts in such a way that seventh part of first and ninth part of second are equal. Find the smallest part?
Options:
A)88
B)66
C)42
D)11
E)43
Rationale: x/7 = y/9 => x:y = 7:9
7/16 * 96 = 42
Answer: C
Answer: C
Question: The diagonals of a rhombus are 12 cm and 10 cm. Find its area?
Options:
A)158
B)129
C)150
D)123
E)60
Rationale: 1/2 * 12 * 10 = 60
Answer:E
Answer: E
Question: The length of the bridge, which a train 160 meters long and travelling at 45 km/hr can cross in 30 seconds, is?
Options:
A)266
B)288
C)245
D)215
E)232
Rationale: Speed = (45 * 5/18) m/sec = (25/2) m/sec. Time = 30 sec. Let the length of bridge be x meters. Then, (160 + X)/30 = 25/2 ==> 2(160 + X) = 750 ==> X
= 215 m.
Answer:D
Answer: D
Question: How many trailing zeros will be there after the rightmost non-zero digit in the value of 25! (factorial 25)?
Options:
A)25
B)8
C)6
D)5
E)2
Rationale: Explanatory Answer
25! means factorial 25 whose value = 25 * 24 * 23 * 22 *....* 1
When a number that has 5 as its factor is multiplied by an even number, it results in a trailing zero.
(Product of 5 and 2 is 10 and any number when multiplied with 10 or a power of 10 will have one or as many zeroes as the power of 10 with which it has been multiplied)
In 25!, the following numbers have 5 as their factor: 5, 10, 15, 20, and 25.
25 is the square of 5 and hence it has two 5s in it.
In toto, it is equivalent of having six 5s.
There are at least 6 even numbers in 25!
Hence, the number 25! will have 6 trailing zeroes in it.
Choice C
Answer: C
Question: A no.when divided by 142 gives a remainder 110, what remainder will be obtainedby dividingthe same no.14?
Options:
A)16
B)17
C)18
D)19
E)20
Rationale: 142 + 110 = 252/14 = 18 (Remainder)
C
Answer: C
Question: In a 100 m race between Rose and Diane, Rose lost to Diane by 0.75 m. If Diane was given a 7 m head start , how many meters more will it take before Rose overtakes Diane?
Options:
A)12.91m
B)11.91m
C)12.5m
D)10.91m
E)13.91m
Rationale: Distance Rose ran before completion of race---100 m-0.75m=99.25m
Distance gained on Diane over 99.25m---7m-0.75m=6.25
then Rose gains 99.25/6.25m = 1m on Kelly every 15.88 meters.
Therefore 15.88 divided by 0.75 of 1 meter.
ANSWER: B. 11.91m
Answer: B
Question: The blood group of 200people is distributed as follows: 50 have A group, 65have B group, 70have O blood type and 15have type AB group. If a person from this group isselected at random, what is the probability that this person has O group type?
Options:
A)0.35
B)0.5
C)1
D)1.23
E)1.25
Rationale: We construct a table of frequencies for the the blood groups as follows
group frequency
a 50
B 65
O 70
AB 15
We use the empirical formula of the probability
Frequency for O blood
P(E)= ________________________________________________
Total frequencies
= 70 / 200 = 0.35
A
Answer: A
Question: 45 persons can repair a road in 12 days, working 5 hours a day. In how many days will 30 persons, working 6 hours a day, complete the work?
Options:
A)10
B)15
C)13
D)18
E)19
Rationale: Let the required number of days be x.
Less persons, More days (Indirect Proportion)
More working hours per day, Less days (Indirect Proportion)
Persons 30 : 45 :: 12 : x
Working hours/day 6 : 5
30 x 6 x x = 45 x 5 x 12
x = (45 x 5 x 12)/(30 x 6)
x = 15
ANSWER B
Answer: B
Question: A and B invests Rs.3500 and Rs.4000 respectively in a business. If A doubles his capital after 6 months. In what ratio should A and B divide that year's profit?
Options:
A)21:5
B)21:16
C)21:2
D)9:9
E)21:11
Rationale: (3.5*6 + 7*6): (4*12)
63:48 =>
21:16
Answer:B
Answer: B
Question: P,Q and R together earn Rs.1710 in 9 days. P and R can earn Rs.600 in 5 days. Q and R in 7 days can earn Rs.910. How much amount does R can earn per day?
Options:
A)s.40
B)s.60
C)s.90
D)s.100
E)s.120
Rationale: Explanation :
Amount Earned by P,Q and R in 1 day = 1710/9 = 190 ---(1)
Amount Earned by P and R in 1 day = 600/5 = 120	---(2)
Amount Earned by Q and R in 1 day = 910/7 = 130	---(3)
(2)+(3)-(1) => Amount Earned by P , Q and 2R in 1 day
- Amount Earned by P,Q and R in 1 day = 120+130-190 = 60
=>Amount Earned by R in 1 day = 60
Answer : Option B
Answer: B
Question: If 45-[28-{37-(15-*)}]= 55, then * is equal to:
Options:
A)-29
B)-19
C)16
D)29
E)39
Rationale: 45-[28-{37-(15-*)}]= 55 => 45-[28-{37-15+*}]=55
45-[28-37+15-*]=55 => 45[43-37-*]=55
45-[6-*]=55 => 45-6+*=55
39+*=55 => *=55-39
= 16
ANSWER:C
Answer: C
Question: A factory has a fixed cost of $40,000 a month, and a cost of $2.5 for every item produced. If the selling price of a single item is $5, what is the number of items must be sold monthly for the factory to cover its cost exactly?
Options:
A)9,000
B)14,000
C)16,000
D)22,500
E)27,000
Rationale: selling price - Cost price = 2.5 so per unit profit =2.5
cost to recover =40000
no of items required = 40000/2.5 = 16000
Ans C
Answer: C
Question: What will be the difference in simple and compound interest on 6000 after three years at the rate of 10 percent per annum?
Options:
A)160
B)186
C)62
D)20
E)None of these
Rationale: For 3 years:
Diff.=Sum×(rate)2(300+rate)/(100)3
= 6000×10×10×310/100×100×100 = 186
Answer B
Answer: B
Question: X and Y are both integers. If X/Y = 59.40, then what is the sum of all the possible two digit remainders of X/Y?
Options:
A)450
B)616
C)672
D)900
E)1024
Rationale: Remainder = 0.40 --> 40/100 --> Can be written as (40/4) / (100/4) = 10/25
So remainders can be 10, 20, 30, 40, ..... 90.
We need the sum of only 2 digit remainders --> 10 + 20 + 30 + 40 + 50 + 60 + 70+ 80 + 90 =450
Answer: A
Answer: A
Question: A retailer buys a radio for Rs 232. His overhead expenses are Rs 15. He sellis the radio for Rs 300. The profit percent of the retailer is
Options:
A)10%
B)50%
C)21.4%
D)52%
E)None of these
Rationale: Explanation:
cost price = (232 + 15) = 247 sell price = 300
gain = (53/247)*100 = 21.4%. Answer: C
Answer: C
Question: Aman started a business investing Rs. 65,000. Rakhi joined him after six months with an amount of Rs. 1,05,000 and Sagar joined them with Rs. 1.4 lakhs after another six months. The amount of profit earned should be distributed in what ratio among Aman, Rakhi and Sagar respectively, 3 years after Aman started the business?
Options:
A)10:105:112
B)78:105:112
C)72:105:112
D)74:105:112
E)16:105:112
Rationale: Explanation:
Aman : Rakhi : Sagar = (65000 * 36) : (105000 * 30) : (140000 * 24)
= 78:105:112
Answer: B
Answer: B
Question: Find the fourth proportional to 33.6 , 41.2 and 48.9?
Options:
A)59.96
B)56.15
C)52.39
D)58.96
E)57
Rationale: Formula= Fourth proportional =(b x c)/a
a=33.6 , b=41.2 and c=48.9
(41.2 x 48.9)/33.6=59.96
A
Answer: A
Question: Calculate the share of Y , if Rs. 2690 is divided among X, Y and Z in the ratio 5 : 7 : 9?
Options:
A)890.7
B)826.7
C)895.7
D)896.7
E)816.7
Rationale: 5 + 7 + 9 =21
2690/21=128.1
Y's share =7*128.1
=896.7
ANSWER:D
Answer: D