divelab/Sys2Bench huggingface dataset:
Question: Rs.8000 become Rs.9724 in a certain interval of time at the rate of 5% per annum of C.I. Find the time?
Options:
A)6 YEARS
B)7
C)5
D)3
E)4
Rationale: Explanation:
9724 = 8000(21/20)N
(21/20)4 = (21/20)N => N = 4
Answer: Option E
Answer: E
Question: Robert ate 7 chocolates, Nickel ate 5 chocolates. How many more chocolates did Robert ate than nickel?
Options:
A)A)4
B)B)7
C)C)9
D)D)5
E)E)2
Rationale: 7-5=2. Answer is E
Answer: E
Question: The L.C.M of two numbers is 48. The numbers are in the ratio 2:3. The sum of numbers is?
Options:
A)22
B)67
C)40
D)88
E)11
Rationale: Let the numbers be 2x and 3x.
Then, their L.C.M = 6x. So, 6x = 48 or x = 8.
The numbers are 16 and 24.
Hence, required sum = (16 + 24) = 40.
Answer:C
Answer: C
Question: What is the Positive integer that can be Added by 595 to make it a perfect square?
Options:
A)2*3*6
B)3*2*5
C)5*3*3
D)2*3
E)3*5*4
Rationale: 596 is added to a number that gives a perfect square
Nearest perfect square is 625.
so,625-596=30
30=2*3*5
Option B is answer
Answer: B
Question: Two airplanes take off from one airfield at noon. One flies due east at 203 miles per hour while the other flies directly northeast at 283 miles per hour. Approximately how many miles apart are the airplanes at 2 p.m.?
Options:
A)166
B)332
C)406
D)483
E)566
Rationale: C
In two hours:
the plane flying East will be 406 miles away from airport.
the other plane will be 566 miles away from airport.
566/406= ~1.4 = ~sqrt(2)
This means that planes formed a right isocheles triangle => sides of such triangles relate as 1:1:sqrt(2) => the planes are 406 miles apart.C
Answer: C
Question: A train 110 m long is running with a speed of 60 km/hr. In what time will it pass a man who is running at 6 km/hr in the direction opposite to that in which the train is going?
Options:
A)5
B)6
C)7
D)9
E)5
Rationale: Speed of train relative to man = 60 + 6 = 66 km/hr.
= 66 * 5/18 = 55/3 m/sec.
Time taken to pass the men = 110 * 3/55 = 6 sec.Answer: B
Answer: B
Question: A grocer stacked oranges in a pile. The bottom layer was rectangular with 5 rows of 5 oranges each. In the second layer from the bottom, each orange rested on 4 oranges from the bottom layer, and in the third layer, each orange rested on 4 oranges from the second layer. Which of the following is the maximum number of oranges that could have been in the third layer?
Options:
A) 2
B) 4
C) 6
D) 7
E) 9
Rationale: Bottom Layer = 5 x 5 = 25
IInd Layer = (5-1) x (5-1) = 16
IIIrd Layer = (4-1) x (4-1) = 9
Answer = 9 = E
Answer: E
Question: If the numerator of a fraction is increased by 20% and its denominator is diminished by 25% value of the fraction is 2/15. Find the original fraction.
Options:
A)1/12
B)1/8
C)1/6
D)1/4
E)1/2
Rationale: X * (120/100)
---------------- = 2/15
Y * (75/100)
X/Y = 1/12
ANSWER:A
Answer: A
Question: In Township K, 1/5 of the housing units are equiped with cable Tv. If 1/12 of the housing units, including 1/3 of those that are equiped with cable tv, are equipped with videocassette recorders, what fraction of the housing units have neither cable tv nor videocassette recorders?
Options:
A)23/30
B)11/15
C)47/60
D)1/6
E)2/15
Rationale: 1/5 -- cable TV (This includes some data from video cassette recorder)
1/10 -- video cassette recorder including 1/3(equiped with cable tv) i.e. 1/3(1/5) = 1/15
therefore only video cassette recorder = 1/12 - 1/15 = 1/60
Total = 1/5+1/60+neither cable tv nor videocassette recorders
1 =13/60+ neither cable tv nor videocassette recorders
therefore neither cable tv nor videocassette recorders = 1-13/60 = 47/60
Hence C.
Answer: C
Question: Find the principle on a certain sum of money at 5% per annum for 2 2/5 years if the amount being Rs.1792?
Options:
A)1600
B)2777
C)2889
D)27670
E)2771
Rationale: 1792 = P [1 + (5*12/5)/100]
P= 1600.Answer:A
Answer: A
Question: The ratio of ducks and frogs in a pond is 31 : 39 respectively. The average number of ducks and frogs in the pond is 152. What is the number of frogs in the pond ?
Options:
A)148
B)152
C)156
D)169
E)None
Rationale: Solution:
Ratio of Ducks and Frogs in Pond,
= 31 : 39.
Average of Ducks and Frogs in Pond,
= 152.
So, total number of Ducks and Frogs in the Pond,
= 2* 152 = 304.
Therefore,
Number of Frogs, = (304 *39)/70 = 169.
Answer: Option D
Answer: D
Question: If n is an integer greater than 7, which of the following must be divisible by 3?
Options:
A)1. n (n+1) (n-4)
B)2. n (n+2) (n-1)
C)3. n (n+3) (n-5)
D)4. n (n+4) (n-2)
E)5. n (n+5) (n-6)
Rationale: We need to find out the number which is divisible by three,
In every 3 consecutive integers, there must contain 1 multiple of 3.
So n+4 and n+1 are same if we need to find out the 3's multiple. replace all the numbers which are more than or equal to three
1. n (n+1) (n-4) = > n(n+1)(n-1) = > (n-1)n(n+1)
2. n (n+2) (n-1) = > n(n+2)(n-1) = > (n-1)n(n+1)
3. n (n+3) (n-5) = > n(n+0)(n-2) = > (n-2)n(n)
4. n (n+4) (n-2) = > n(n+1)(n-2) = > (n-2)n(n+1)
5. n (n+5) (n-6) = > n(n+2)(n-0) = > (n)n(n+2)
from the above onlyoption Ais product of consecutive three numbers.
D
Answer: D
Question: A miniature roulette wheel is divided into 9 equal sectors, each bearing a distinct integer from 1 to 9, inclusive. Each time the wheel is spun, a ball randomly determines the winning sector by settling in that sector. If the wheel is spun four times, approximately what is the probability that the product of the four winning sectors’ integers will be even?
Options:
A)50%
B)67%
C)80%
D)90%
E)95%
Rationale: The only way to have an odd product is if all 4 integers are odd.
P(odd product) = 5/9*5/9*5/9*5/9 = 625/6561
P(even product) = 1 - 625/6561 = 5936/6561 which is about 90%
The answer is D.
Answer: D
Question: The sum of the first 50 positive even integers is 2550. What is the sum of even integers from 102 to 200 inclusive?
Options:
A)5100
B)7550
C)10100
D)15500
E)20100
Rationale: First 50 even integers:
2
4
6
8
<...>
Integers from 102 to 200
102
104
106
108
<...>
We notice that each integer from the second set is 100 more than the respective integer in the first set. Since we have 50 even integers from 102 to 200, then:
2550+(100*50)=7550;ANSWER:B
Answer: B
Question: The product of two numbers is 468 and the sum of their squares is 289. The sum of the number is?
Options:
A)A)23
B)B)25
C)C)27
D)D)31
E)E)35
Rationale: Let the numbers be x and y.
Then, xy = 468 and x2 + y2 = 289.
(x + y)2 = x2 + y2 + 2xy = 289 + (2 x 468) = 1225
x + y = 35.
Option E
Answer: E
Question: In what time will a train 120 meters long cross an electric pole, if its speed is 184 km/hr
Options:
A)5 seconds
B)4.5 seconds
C)3 seconds
D)2.3 seconds
E)None of these
Rationale: Explanation:
First convert speed into m/sec
Speed = 184*(5/18) = 51 m/sec
Time = Distance/speed
= 120/51 = 2.3 seconds
Option D
Answer: D
Question: A family X went for a vacation. Unfortunately it rained for 13 days when they were there. But whenever it rained in the mornings, they had clear afternoons and vice versa. In all they enjoyed 11 mornings and 12 afternoons. How many days did they stay there totally?
Options:
A)15 days
B)16 days
C)17 days
D)18 days
E)19 days
Rationale: clearly 11mornings and 12 afternoons = 23 half days
since 13 days raining means 13 half days.
so 23-13 =10 halfdays ( not effecetd by rain )
so 10 halfdays =5 fulldays
total no. of days = 13+5 =18 days
ANSWER:D
Answer: D
Question: A honey bee flies for 10 seconds, from a daisy to a rose. It immediately continues to a poppy, flying for 6 additional seconds. The distance the bee passed, flying from the daisy to the rose is 18 meters longer than the distance it passed flying from the rose to the poppy. The bee flies to the poppy at 3 meters per second faster than her speed flying to the rose. The bee flies how many meters per second from the daisy to the rose?
Options:
A)1.4
B)1.5
C)1.6
D)1.8
E)1.0
Rationale: Let the speed be 's' and let the distance between rose and poppy be 'x'
The problem boils down to:
Rose to Poppy: s+3=x/6 ------- 1
Daisy to Rose: s=(x+18)/10------ 2
so from 1 we can re write x as x=6s+18
substitute the value of x in 2 gives us s=1.8 m/s
D
Answer: D
Question: A train 100m long takes 6 sec to cross a man walking at 5kmph in a direction opposite to that of the train. Find the speed of the train?
Options:
A)45kmph
B)55kmph
C)32kmph
D)61kmph
E)70kmph
Rationale: Let the speed of the train be x kmph
Speed of the train relative to man = x+5 = (x+5)*5/18 m/sec
100/[(x+5)*5/18] = 6
30(x+5) = 1800
x = 55kmph
Answer is B
Answer: B
Question: A, B, C hired a car for Rs.520 and used it for 7,8 and 11 hours respectively. Hire charges paid by B were
Options:
A)Rs.140
B)Rs.160
C)Rs.180
D)Rs.220
E)None
Rationale: Solution
A : B : C	= 7 : 8 : 11.
Hire charges paid by B	= Rs(520×8/26)
= Rs.160.
Answer B
Answer: B
Question: Johnson has a corporate proposal. The probability that vice-president Adams will approve the proposal is 0.6. If VP Adams approves the proposal, then the probability that vice-president Baker will approve the proposal is 0.7. If VP Adams doesn’t approve the proposal, then the probability that vice-president Baker will approve the proposal is 0.3. What is the probability that at least one of the two VPs, approves Johnson’s proposal?
Options:
A)0.12
B)0.24
C)0.28
D)0.66
E)0.72
Rationale: (1at approves * second rejects ) + (1st rejects * 2nd approves ) + (both approves )
=0.6*0.2+0.4*0.3+0.6*0.7
= 0.12+0.12+0.42
=0.66
D
Answer: D
Question: A painting crew painted 80 houses. They painted the first y houses at a rate of x houses per week. Then more painters arrived and everyone worked together to paint the remaining houses at a rate of 3.25x houses per week. How many weeks did it take to paint all 80 houses, in terms of x and y?
Options:
A)(320 - y)/(5x)
B)(y +220)/(5x)
C)5(80 - y)/(4x)
D)(y + 400)/(4x)
E)(4y + 320)/(5x)
Rationale: Ans B
Plug some numbers
Let y = 40 houses and x = 20
then they painted 20 houses per week
as painters were added to the group , the rate of the group increased to 3.25 x => 3.25 * 20 = 65 houses per week
total time they took = (40/20) + (40/65) = 2.6 weeks
Putting the values of x and y in equation B
(y +220)/(5x) = (40+220)/5*20 = 260/100 = 2.6
Answer: B
Question: In the xy-plane, a line has slope 3 and x-intercept 6. What is the y-intercept of the line?
Options:
A)-18
B)-3
C)0
D)3
E)9
Rationale: Let the line be represented by a general equation y=mx+b, where m = slope (3) and b=y intercept. We are also given the value of x-intercept 6.
Theory : y intercept represents the point on the line where the x=0, and x intercept represents the point on the line where the y=0.
Putting these values in the equation : 0 = 3*6 + b => b = -18. Hence A.
Answer: A
Question: On a purchase of $110, a store offered a payment plan consisting of a $10 down payment and 12 monthly payments of $10 each. What percent of the purchase price, to the nearest tenth of a percent, did the customer pay in interest by using this plan?
Options:
A)9.5%
B)10.5%
C)11.5%
D)9.1%
E)12.5%
Rationale: 12*10 + 10 = 130
(10/110)* 100 = 9.1
Answer : D
Answer: D
Question: If the price of an article went up by 50%, then by what percent should it be brought down to bring it back to its original price?
Options:
A)2/3%
B)2/8%
C)2/1%
D)33.3%
E)2/7%
Rationale: Let the price of the article be Rs. 100.
50% of 100 = 50.
New price = 100 + 50 = Rs. 150
Required percentage = (150 - 100)/150 * 100
= 50/150 * 100= 33.33%.
Answer:D
Answer: D
Question: A man 24 years older than his son. In two year his age will be twice of his son. what is the present age of his son?
Options:
A)23
B)22
C)21
D)20
E)32
Rationale: Correct Answer : B
present age of son = x years
present age of man = ( x +24 )years
In two year his age will be twice of his son.
(x +24)+2=2(x+2)
x=22
Answer: B
Question: The total of the ages of Jayant, Prem and Saransh is 75 years. Ten years ago, the ratio of their ages was 2 : 3 : 4. What is the present age of Prem?
Options:
A)25 years
B)32 years
C)34 years
D)38 years
E)None
Rationale: Solution
Let the ages of Jayant, Prem and Saransh 10 years ago be 2x, 3x and 4x years respectively. Then,
(2x + 10)+(3x + 10)+(4x + 10)	= 75.
‹=›9x = 45
x = 5.
∴ Prem's present age = 3x + 10 = 25 years.
Answer A
Answer: A
Question: 6^b + 6^b + 6^b + 6^b + 6^b + 6^b =
Options:
A)7^b
B)7^(b + 1)
C)7^(7b)
D)6^(b + 1)
E)49^B
Rationale: Easy one.
6*6^b = 6^(b+1)
Ans. D
Answer: D
Question: A chemical is composed of hydrogen, oxygen and nitrogen. If 20 moles of the chemical is to be made containing twice as much hydrogen as oxygen and three times as much oxygen as nitrogen how many moles of oxygen is required?
Options:
A)5 moles
B)6 moles
C)8moles
D)2 moles
E)1.5 moles
Rationale: Amount of chemical=20 moles
hydrogen=2 oxygen
oxygen=3 nitrogen
hydrogen+oxygen+nitrogen=20
2 oxygen+oxygen+1/3 oxygen=20
10 oxygen=20
oxygen=2
Answer is D
Answer: D
Question: 3889 + 12.597 - ? = 3854.002
Options:
A)A)47.095
B)B)47.595
C)C)47.932
D)D)47.95
E)of the above
Rationale: Let 3889 + 12.597 - x = 3854.002.
Then x = (3889 + 12.597) - 3854.002
= 3901.597 - 3854.002
= 47.595.
Answer = B
Answer: B
Question: A cricketer has a certain average for 10 innings. In the eleventh inning, he scored 108 runs, there by increasing his average by 8 runs. His new average is:
Options:
A)22 runs
B)24 runs
C)26 runs
D)28 runs
E)30 runs
Rationale: Let average for 10 innings be x. Then,
(10x + 108)/11 = x + 8
= 11x + 88 = 10x + 108
= x = 20.
New average = (x + 8) = 28 runs.
Answer:D
Answer: D
Question: If 1 added to the age of the elder sister, then the ratio of the ages of two sisters becomes 0.5:1, but if 2 is subtracted from the age of the younger one, the ratio becomes 1:3, the age of the younger sister will be?
Options:
A)7 years
B)5 years
C)8 years
D)10 years
E)4 years
Rationale: Explanation :
Let, the age of the elder sister be x year, and younger sister be y year.
Now, according to the question,
y/(x+1)=0.5/1.
=>y/(x+1)=1/2.
=>2y= x + 1
=>x−2y =−1 -------(i)
And,
=>(y−2)/x=1/3.
=>x−3y =−6 -------(ii)
On solving these equations, we get :-
x=9 and y=5
Hence, the age of the younger sister is 5 years.
Answer : B
Answer: B
Question: The current of a stream runs at the rate of 4 kmph. A boat goes 6 km and back to the starting point in 2 hours, then find the speed of the boat in still water?
Options:
A)7
B)6
C)8
D)5
E)3
Rationale: S = 4
M = x
DS = x + 4
US = x - 4
6/(x + 4) + 6/(x - 4) = 2
x = 8
Answer:C
Answer: C
Question: There are 10 children in a company's day-care center, and a pair of children is to be selected to play a game. At most, how many different pairs are possible?
Options:
A)100
B)90
C)50
D)45
E)25
Rationale: 1. first child out of 10 - 10 possibilities
2. second child out of 9 - 9 possibilities. the total number of pairs = 9*10=90
3. exclude xy yx cases: 90/2=45
Second way
N=10C2=10!/(8!2!)=10*9/2=45
ANS:D
Answer: D
Question: Ramesh can finish a work in 20 days and Sushil in 25 days. They both work together for 5 days and then Sushil goes away. In how many days will Ramesh complete the remaining work?
Options:
A)11
B)10
C)9
D)8
E)7
Rationale: (5 + x)/20 + 5/25 = 1 => x = 11 days
ANSWER A
Answer: A
Question: Of the three-digit integers greater than 900, how many have two digits that are equal to each other and the remaining digit different from the other two?
Options:
A) 94
B) 82
C) 80
D) 45
E) 36
Rationale: To satify the given condition,
required no. of cases = total numbers - numbers with all digits different - numbers when all three digits are same,
number greater than 700;
total numbers = 1*10*10 = 100
numbers with all digits different = 1*9*8 = 72
numbers when all three digits are same (777) = 1
req. = 100- 72 - 1 = 27
considering the numbers between 700999 = 27*3=95
Answer is 94 ('cause 700 can't be included)
Answer (A).
Answer: A
Question: The distance between a gym and a pharmacy is approximately 1.2 x 10^5 inches. Which of the following is closest to the distance between the gym and a pharmacy, in kilometers? (1 kilometer is approximately 3.9 x 10^4 inches.)
Options:
A)3.1
B)3.9
C)3.7
D)4.2
E)4.8
Rationale: We know that 1 kilometer = 3.9x10^4 inches. Therefore, we now have a ratio of (1 kilometer/3.9x10^4 inches).
We also know that the distance between the gym and a pharmacy is approximately 1.2 x 10^5 inches. To convert inches to kilometers, we need to multiply 1.2 x 10^5 inches by the ratio we just found out.
kilometers = 1.2 x 10^5 inches x (1 kilometer/3.9x10^4 inches) [note: "inches" cancel out, leaving us with just km]
km = 1.2 x 10^5/3.9x10^4 km
km = 3.08 = 3.1 km
Therefore, we can see that the closest answer is A.
Answer: A
Question: I. x2 + 5x + 6 = 0,
II. y2 + 9y +14 = 0 to solve both the equations to find the values of x and y?
Options:
A)If x < y
B)If x > y
C)If x ≤ y
D)If x ≥ y
E)If x = y or the relationship between x and y cannot be established.
Rationale: I. x2 + 3x + 2x + 6 = 0
=> (x + 3)(x + 2) = 0 => x = -3 or -2
II. y2 + 7y + 2y + 14 = 0
=> (y + 7)(y + 2) = 0 => y = -7 or -2
No relationship can be established between x and y.
ANSWER:E
Answer: E
Question: On a Saturday night, each of the rooms at a certain motel was rented for either $40 or $60. If 10 of the rooms that were rented for $60 had instead been rented for $40, then the total rent the motel charged for that night would have been reduced by 10 percent. What was the total rent the motel actually charged for that night ?
Options:
A) $600
B) $800
C) $1,000
D) $1,600
E) $2,000
Rationale: Let total rent the motel charge for all rooms =x
If 10 rooms that were rented for 60 $ had instead been rented for 40 $,
then total difference in prices = 20 $ * 10 = 200 $
Total rent the motel charged would have been reduced by 10 %
.10x = 200
=> x= 2000
Answer E
Answer: E
Question: A boat running downstream covers a distance of 40 km in 2 hours while for covering the same distance upstream,it takes 4 hours.What is the speed of the boat in still water ?
Options:
A)4 km/hr
B)6 km/hr
C)8 km/hr
D)Data inadequate
E)15 kmph
Rationale: Solution
Rate downstream =(40/2) kmph = 20 kmph, Rate upstream =(40/4) = 10 kmph.
∴ Speed in still water =1/2(20+10) kmph = 15 kmph.
Answer E
Answer: E
Question: A student gets an aggregate of 60% marks in five subjects in the ratio 10 : 9 : 8 : 7 : 6. If the passing marks are 50% of the maximum marks and each subject has the same maximum marks, in how many subjects did he pass the examinaiton?
Options:
A)2
B)3
C)4
D)5
E)6
Rationale: Explanation :
Let the full marks of each subject is 100. So, total marks in 5 subject is 500.
Student gets 60% aggregate marks i.e 60% of 500 = 300.
=> 10x + 9x +8x +7x + 6x = 300
=> 40x = 300.
=> x = 300/40 = 7.5.
Hence,
The marks in first subject = 10x = 7.5 x 10 = 75.
The marks in 2ndsubject = 9x = 7.5 x 9 = 67.5.
The marks in 3rd subject = 8x = 7.5 x 8 = 60.
The marks in 4th subject = 7x = 7.5 x 7 = 52.5.
The marks in 5th subject = 6x = 7.5 x 6 = 45.
Thus , he passed in all 5 subjects.
Answer : D
Answer: D
Question: if f(f(X))=81. then. value of x=?
when f(X)=2X-1+f(X-1). is not equal to zero and f(X=0)=0
Options:
A)2
B)3
C)4
D)5
E)6
Rationale: f(X=0) = 0
f(X=1) = 2*1-1+f(1-1)
= 2-1+0
= 1
f(X=2) = 2*2-1+f(2-1)
= 4-1+1
= 4
f(X=3) = 2*3-1+f(3-1)
= 6-1+4
= 9
===>f(X=n) = n^2
f(f(X)) = 81
X = sqrt(sqrt(81)) = 3
ANSWER:B
Answer: B
Question: The ratio of male to female in a class is 6:6. the career preference of the students in the class are to be represented in a circle graph. If the area of the graph allocated to each career preference is to be proportional to the number of students who have that career preference, how many degrees of the circle should be used to represent a career that is preferred by one third of the males and two-third of the females in the class?
Options:
A)a)180 degree
B)b) 168 degree
C)c)191 degree
D)d)192 degree
E)e)204 degree
Rationale: here is my approach => males => 6x and females =6x => total =12x
now 12x=> 360
therefore 6x => 180 degree .
P.S => 6x is nothing but total number of students with the given preference
Answer A
Answer: A
Question: A shopkeeper buys mangoes at the rate of 6 a rupee and sells them at 3 a rupee. Find his net profit or loss percent?
Options:
A)200%
B)75%
C)60%
D)50%
E)100 %
Rationale: The total number of mangoes bought by the shopkeeper be 12.
If he buys 6 a rupee, his CP = 3
He selling at 3 a rupee, his SP = 6
Profit = SP - CP = 6 - 3 = 3
Profit Percent = 3/3 * 100 = 100 %
Answer:E
Answer: E
Question: A firm is comprised of partners and associates in a ratio of 2:61. If 60 more associates were hired, the ratio of partners to associates would be 4:137. How many partners are currently in the firm?
Options:
A)12
B)14
C)16
D)18
E)20
Rationale: The ratio 2:61 = 4:122 so the ratio changed from 4:122 to 4:137.
137-122 = 15 which is 1/4 of the increase in 60 associates.
The ratio changed from 16:488 to 16:548.
Thus the number of partners is 16.
The answer is C.
Answer: C
Question: x, y, a, and b are positive integers of E. When x is divided by y, the remainder is 6. When a is divided by b, the remainder is 9. Which of the following is NOT a possible value for y + b?
Options:
A)24
B)21
C)20
D)17
E)15
Rationale: x, y, a, and b are positive integers of E. When x is divided by y, the remainder is 6. When a is divided by b, the remainder is 9. Answer: E.
Answer: E
Question: Difference of 2 numbers is 1660. If 7.5% of one number is 12.5% of the other number, find the 2 numbers?
Options:
A)125,150
B)5124,4515
C)4150,2490
D)3250,4510
E)1254,3210
Rationale: Let the numbers be x and y
7.5% of x = 12.5% of y
x = 125y/75 = 5y/3
x-y = 1660
5y/3 - y = 1660
y = 2490
x = 5y/3 = 4150
Answer is C
Answer: C
Question: Rahul is younger than Karthi by 7 years. If the ratio of their ages is 7:9, find the age of Rahul
Options:
A)20
B)24
C)24.5
D)23
E)23.5
Rationale: karthi age is x and rahul x-7
=> (x-7)/x = 7/9
=> 9x-63 = 7x
=> 2x = 63
=> x = 31.5
then Rahul age is 31.5- 7 = 24.5
ANSWER C
Answer: C
Question: A cistern can be filled by a tap in 5 hours while it can be emptied by another tap in 8 hours. If both the taps are opened simultaneously, then after how much time will the cistern get filled?
Options:
A)5.2 hrs
B)13.3 hrs
C)1.9 hrs
D)7.2 hrs
E)1.4 hrs
Rationale: Net part filled in 1 hour = (1/5 - 1/8) = 3/40
The cistern will be filled in 40/3 hrs i.e., 13.3 hrs.
Answer:B
Answer: B
Question: Compound interest earned on a sum for the second and the third years are Rs.1200 and Rs.1440 respectively. Find the rate of interest?
Options:
A)18% p.a.
B)22% p.a.
C)20% p.a.
D)24% p.a.
E)None of these.
Rationale: Rs.1440 - 1200 = Rs.240 is the interest on Rs.1200 for one year.
Rate of interest = (100 * 240) / (100 * 1) = 20% p.a
ANSWER:C
Answer: C
Question: There are 13 cans in the refrigerator. 7 of them are red and 6 of them are blue. In how many ways we can remove 8 cans so that at least one red and at least one blue cans to remain the refrigerator.
Options:
A)460
B)490
C)493
D)455
E)445
Rationale: Answer: A.
Answer: A
Question: The average (arithmetic mean) of eight numbers is 8. If 4 is added from each of five of the numbers, what is the new average?
Options:
A)4.5
B)8.9
C)10.5
D)4.5
E)5.6
Rationale: Sum of 8 numbers = 8*8=64
If 4 is added from each of five of the numbers , we added 4*5=20 from the total sum
Sum of 8 number after adding 4 from each of five of the numbers =64+20=84
New average = 84/8=10.5
Answer C
Answer: C
Question: If a committee of 3 people is to be selected from among 6 married couples so that the committee does not include two people who are married to each other, how many such committees are possible?
Options:
A)20
B)40
C)50
D)80
E)480
Rationale: Each couple can send only onerepresentativeto the committee. Let's see in how many ways we can choose 3 couples (as there should be 3 members) each to send onerepresentativeto the committee: 6C3=60.
But these 3 chosen couples can send two persons (either husband or wife): 2*2*2=2^3=8.
Total # of ways: 6C3*2^3=480.
Answer: E.
Answer: E
Question: In a 500 m race, the ratio of the speeds of two contestants A and B is 3 : 4. A has a start of 140 m. Then, A wins by:
Options:
A)10 m
B)20 m
C)30 m
D)40 m
E)45 m
Rationale: A - distance of (500 - 140)m =>360 m
A cover 3 m , B covers 4 m => 480 m
when A reaches the winning post B covers 480 m and remains 20 m behind
= > A wins by 20 m
ANSWER B
Answer: B