divelab/Sys2Bench huggingface dataset:
Question: A trader has 30 kg of rice, a part of which he sells at 14% profit and rest at 6% loss. On the whole his loss is 4% . What is the quantity sold at 14% profit and that at 6% loss?
Options:
A)3 and 27 kg
B)10 and 40 kg
C)15 and 27 kg
D)20 and 30 kg
E)40 and 30 kg
Rationale: Alligation Method
I PART II PART
14 (x1) -6 (x2)
\ /
x
/ \
(x2-x) (x-x1)
2 18
1 9
Ratio of quantities sold at 14% profit and 6% loss = 1: 9
Quantity sold at 14% profit = 30/1+9 *1 = 3 kg
Quantity sold at 6% loss = 30/1+9 *9 = 27 kg
ANSWER:A
Answer: A
Question: The original price of a certain TV set is discounted by x percent, and the reduced price is then discounted by 2x percent. If P is the original price of the TV Set, which of the following represents the price of the television set after the two successive discounts?
Options:
A)P(1 - 0.03x + 0.02x^2)
B)P(1 - 0.03x + 0.0002x^2)
C)P(1 - 0.03x + 0.002x^2)
D)P(1 - 2x^2)
E)P(1 - 3x + 2x^2)
Rationale: Let us say that P = 100 $ and x = 10 %
Now if there are two successive discounts of 10 % and 20 % then the effective discount percentage will be -10 - 20 + (-10) (-20)/100 = -30 + 2 = 28 %
Hence the new price will be 100 - 28 = 72
Hence by plugging in P = 100 and x = 10 the answer should be 72
A: P(1 - 0.03x + 0.02x^2) = 100 (1 - 0.3 + 2) = 100(2.7)
B: P(1 - 0.03x + 0.0002x^2) = 100 (1 - 0.3 + 0.02) = 100 (1 - 0.28) = 72 (BINGO!) (Let's still eliminate all other answer options - what if another one gives me 72)
C: P(1 - 0.03x + 0.002x^2) = 100 (1 - 0.3 + 0.2)
D: P(1 - 2x^2) = 100 ( 1 - 200)
E: P(1 - 3x + 2x^2) = 100 ( 1 - 0.2 + 200)
Hence the answer is B
Answer: B
Question: The cost of 10 kg of mangos is equal to the cost of 24 kg of rice. The cost of 6 kg of flour equals the cost of 2 kg of rice. The cost of each kg of flour is $22. Find the total cost of 4 kg of mangos, 3 kg of rice and 5 kg of flour?
Options:
A)347.6
B)987.6
C)941.6
D)637.6
E)667.6
Rationale: Let the costs of each kg of mangos and each kg of rice be $a and $r respectively.
10a = 24r and 6 * 22 = 2r
a = 12/5 r and r = 66
a = 158.4
Required total cost = 4 * 158.4 + 3 * 66 + 5 * 22
= 633.6 + 198 + 110 = $941.60
C
Answer: C
Question: A certain store sells only black shoes and brown shoes. In a certain week, the store sold x black shoes and y brown shoes. If 2/7 of all shoes sold that week were black, which of the following expressions represents the value of y, in terms of x?
Options:
A)x/3
B)5x/2
C)2x/3
D)3x/2
E)2x
Rationale: x/(x+y) = 2/7
7x = 2x+2y
5x = 2y
y = 5x/2
Answer B
Answer: B
Question: The speed of a boat in upstream is 100 kmph and the speed of the boat downstream is 180 kmph. Find the speed of the boat in still water and the speed of the stream?
Options:
A)10
B)99
C)88
D)40
E)23
Rationale: Speed of the boat in still water = (100+180)/2 = 70 kmph. Speed of the stream = (180-100)/2 = 40 kmph. Answer:D
Answer: D
Question: At Joel’s bookstore, the current inventory is 30% historical fiction. Of the historical fiction books, 30% are new releases, while 40% of the other books are new releases. What fraction of all new releases are the historical fiction new releases?
Options:
A)4/25
B)9/37
C)2/5
D)8/15
E)2/3
Rationale: let there be 100 books in all
Historic fiction books = 30% of total = 30
Other books = 70
New historic fiction = 30% of 30 = 9
Other new books = 40% of 70 = 28
total new books = 37
fraction = 9/37
Ans: B
Answer: B
Question: A person purchased a TV set for Rs. 16000 and a DVD player for Rs. 6250. He sold both the items together for Rs. 35150. What percentage of profit did he make?
Options:
A)22
B)27
C)58
D)26
E)11
Rationale: The total CP = Rs. 16000 + Rs. 6250 = Rs. 22250 and SP = Rs. 35150
Profit(%) = (35150 - 22250)/22250 * 100 = 58%.Answer:C
Answer: C
Question: A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Options:
A)288
B)2667
C)288
D)150
E)812
Rationale: Speed=(60 * 5/18) m/sec = (50/3) m/sec Length of the train = (Speed x Time)
= (50/3 * 9) m = 150 m.
Answer: D
Answer: D
Question: The average marks of a class of 30 students is 40 and that of another class of 50 students is 60. Find the average marks of all the students?
Options:
A)50
B)52.5
C)60
D)62.5
E)65
Rationale: Sum of the marks for the class of 30 students = 30 * 40 = 1200
Sum of the marks for the class of 50 students = 50 * 60 = 3000
Sum of the marks for the class of 80 students =
1200 + 3000 = 4200
Average marks of all the students = 4200/80 = 52.5
ANSWER B
Answer: B
Question: Machine W can produce x units in 3/4 of the time it takes machine N to produce x units. Machine N can produce x units in 2/3 the time it takes machine O to produce x units. If all three machines are working simultaneously, what fraction of the total output is produced by machine N?
Options:
A) 1/2
B) 1/3
C) 4/13
D) 8/29
E) 6/33
Rationale: Let the following be true:
W makes x in time t
Then the following follows:
N makes x in 4t/3
O makes x in 3/2(4t/3) = 2t
M:N:O = 1:4/3:2=3:4:6
So N=4/(3+4+6)=4/13=C
Answer: C
Question: Two trains 140 meters and 160 meters long are running in the same direction with speeds of 92 km/hr, 56km/hr. In how much time will the first train cross the second
Options:
A)37 sec
B)25 sec
C)30 sec
D)28 sec
E)32 sec
Rationale: Explanation:
Relative speed of the trains = (92 - 56) km/hr = 36 km/hr
= (36Ã— 5/18) m/sec = 10 m/sec.
Time taken by the trains to cross each other
= Time taken to cover (140 + 160) m at 10 m /sec = (300/10) sec = 30 sec.
Answer: Option C
Answer: C
Question: What is the are of an equilateral triangle of side 24 cm?
Options:
A)66âˆš3 cm2
B)74âˆš3 cm2
C)64âˆš3 cm2
D)64âˆš5 cm2
E)144âˆš3 cm2
Rationale: Area of an equilateral triangle = âˆš3/4 S2
If S = 24, Area of triangle = âˆš3/4 * 24 * 24 = 144âˆš3 cm2;
Answer:E
Answer: E
Question: If m ≠ 1 and if nm/(n - m) = 1, what is the value of n in terms of m?
Options:
A)m/(m+1)
B)(m - 1)/m
C)m/(1-m)
D)(m + 1)/m
E)(1 - m)/m
Rationale: This question comes with a particular 'quirk' (one that you probably won't see on Test Day). The GMAT won't test you on the concept of undefined numbers (re: numbers divided by 0), so any time that this concept is a possibility, the question writers have to add a restriction that removes the option that a 0 could occur in the denominator.
Here, we're told that B CANNOT = 1, which is a bit strange because that restriction doesn't seem to impact the original equation much. In fact, it impacts JUST ONE of the answer choices - so you have to ask WHY that restriction is even there. It's actually because that one answer is the correct one.
Final Answer:
C
Answer: C
Question: If the L.C.M of two numbers is 450 and their product is 22500, find the H.C.F of the numbers.
Options:
A)50
B)30
C)125
D)25
E)None of these
Rationale: H.C.F = (Product of the numbers) / (Their L.C.M) = 22500/450 = 50.
ANSWER:A
Answer: A
Question: The diagonals of a rhombus are 11 cm and 20 cm. Find its area?
Options:
A)329
B)288
C)150
D)238
E)110
Rationale: 1/2 * 11 * 20 = 110
Answer: E
Answer: E
Question: A and B working together could mow a field in 28days and with the help of C they could have mowed it in 21 days. How long would C take by himself?
Options:
A)68days
B)84days
C)90days
D)72days
E)50days
Rationale: Required answer = 28*21 / 28-21 = 84days
Answer is B
Answer: B
Question: (2^2+4^2+6^2+.....+22^2)=?
Options:
A)5578
B)7996
C)9964
D)2024
E)1346
Rationale: =(1x2)^2+(2x2)^2,+(2x3)^3+......(2x11)^2
=2^2 x (1^2+2^2+3^2+.......+11^2)
formula is =1/6 n(n+1)(2n+1)
=(4x1/6x11x12x23)
=(4x506)=2024
Answer is D
Answer: D
Question: In how many different ways can the letters of the word 'SOFTWARE' be arranged in such a way that the vowels always come together?
Options:
A)120
B)360
C)1440
D)13440
E)4320
Rationale: The word 'SOFTWARE' contains 8 different letters.
when the vowels OAE are always together, they can be supposed to form one letter.
Thus, we have to arrange the letters SFTWR (OAE)
Now, 5 letters can be arranged in 6!=720 ways.
The vowels (OAE) can be arranged among themselves in 3!=6 ways.
Required number of ways =(720*6)=4320.
Answer is E
Answer: E
Question: Which of the following ratios is greatest?
Options:
A)7 : 15
B)15 : 23
C)17 : 25
D)21 : 29
E)None
Rationale: Sol.
7/15 = 0.466,
15/23 = 0.652,
17/25 = 0.68<,br/> 21/29 = 0.724,
Clearly, 0.724 is greatest and therefore, 21 : 29 is greatest.
Answer D
Answer: D
Question: In an examination 60% failed in Math and 40% failed in French. If 15% failed in both. What % of students passed in both.
Options:
A)25%
B)15%
C)20%
D)30%
E)10%
Rationale: Passed in Math = 100 - 60 = 40%
Passed in French = 100 - 40 = 60%
Students who passed Math or French = 100 -15 = 85%
Students passed in Math and French = (Passed in Math) + (Passed in French) - (Students who passed Math or French) = 60+40-85 =15%
ANSWER:B
Answer: B
Question: A towel, when bleached, lost 10% of its length and 20% of its breadth. What is the percentage decrease in area?
Options:
A)28%
B)30 %
C)44%
D)54%
E)64%
Rationale: percentage change in area
=(−10−20+(10×20)/100)%=−28%
i.e., area is decreased by 28%
ANSWER:A
Answer: A
Question: A snooker tournament charges $40.00 for VIP seats and $10.00 for general admission (“regular” seats). On a certain night, a total of 320 tickets were sold, for a total cost of $7,500. How many fewer tickets were sold that night for VIP seats than for general admission seats?
Options:
A)190
B)180
C)170
D)160
E)148
Rationale: let no of sits in vip enclosure is x then x*40 +10( 320-x) =7500 or 25x = 7500 -3200 , x = 4300/25 =172
vip =172 general =320-172= 148
E
Answer: E
Question: A ladder 100 feet long is leaning against a vertical wall Its lower end is 60 foot from the bottom of the wall The side of the largest cubical box that can be placed between the wall and the ladder without disturbing the ladder is (to the nearest foot).
Options:
A)26
B)34
C)21
D)40
E)30
Rationale: if we consider the 2d image then the ladder , the wall and base making a triangle ,which height =80 foot
now we have to calculate the largest square inside the triangle.
let x be the side of square.
then,there are two triange of one height=x ,base=(60-x) and the other of height=(80-x) and base=x and a squre
by condition
(60-x)*x/2+x*(80-x)/2+x^2=80*60/2
x=34.2
ANSWER:B
Answer: B
Question: On dividing a certain number by 5, 7 and 8 successively, the remainders obtained are 2, 3 and 4 respectively. When the order of division is reversed and the number is successively divided by 8, 7 and 5, the respective remainders T will be:[/b]
Options:
A)3, 3, 2
B)3, 4, 2
C)5, 4, 3
D)T=5, 5, 2
E)6, 4, 3
Rationale: Let the original number be X. Then by the successive dividing we have followings :
X=5A+2
A=7B+3
B=8C+4.
So we have A=7*(8C+4)+3=7*8C+31, and X=5*(7*8C + 31)+2 = 5*7*8C + 157.
Now by dividing X by 8, 7, 5 successively we have followings :
X=8*(5*7C+19)+5
5*7C+19=7*(5C+2) + 5
5C+2=5C+2.
The remainders are, therefore, 5, 5, 2.
The answer is (D).
Answer: D
Question: The true discount on a bill of Rs.2160 is Rs.360.The banker's discount is
Options:
A)430
B)431
C)432
D)433
E)None of these
Rationale: Solution
P.W	= Rs.(2160 - 360)
= Rs. 1800
S.I on Rs. 2160	=Rs.(360/900 x 2160)
= Rs. 432.
Answer C
Answer: C
Question: Salesperson A's compensation for any week is $280 plus 6 percent of the portion of A's total sales above $1,000 for that week. Salesperson B's compensation for any week is 8 percent of B's total sales for that week. For what amount of total weekly sales would both salespeople earn the same compensation?
Options:
A)$5000
B)$7000
C)$9000
D)$11,000
E)$13,000
Rationale: 280+0.06(x-1000) = 0.08x
0.02x = 220
x = $11,000
The answer is D.
Answer: D
Question: In an increasing sequence of 10 consecutive integers, the sum of the first 5 integers is 550. What is the sum of the last 5 integers in the sequence?
Options:
A) 585
B) 580
C) 575
D) 570
E) 565
Rationale: All 5 integers are 5 numbers larger than in the first sum (eg. 1 becomes 6, 2 7...). 5*5=25+550=575
C
Answer: C
Question: In how many different number of ways 4 boys and 2 girls can sit on a bench?
Options:
A)700
B)720
C)740
D)750
E)760
Rationale: npn = n!
6p6 = 6 × 5 × 4 × 3 × 2 × 1 = 720
B
Answer: B
Question: Rs. 6000 is lent out in two parts. One part is lent at 7% p.a simple interest and the other is lent at 8% p.a simple interest. The total interest at the end of one year was Rs. 450. Find the ratio of the amounts lent at the lower rate and higher rate of interest?
Options:
A)5:1
B)5:5
C)5:8
D)5:4
E)5:2
Rationale: Let the amount lent at 7% be Rs. x
Amount lent at 8% is Rs. (6000 - x)
Total interest for one year on the two sums lent
= 7/100 x + 8/100 (6000 - x) = 480 - x/100
=> 480 - 1/100 x = 450 => x = 3000
Amount lent at 10% = 3000
Required ratio = 3000 : 3000 = 5:5
Answer:B
Answer: B
Question: In a race, A beats B by 15 metres and C by 29 metres. If B and C run over the course together, B wins by 15 metres. What is the length of the course?
Options:
A)225m
B)120m
C)220m
D)160m
E)180m
Rationale: Explanation:
Let X be the length of the course
according to the question,
A beats B by 15 metres and C by 29 metres
Applying this,
If A runs X metres, B runs (X-15) and C runs ( X-29) metres.
B and C together run, B runs X metres and C runs (X-15)
=> If B runs 1 metre, C runs X-15/X
=> B runs X-15 m, C runs (X-15/x) * (X-15)
APPLYING THIS,
X-29 = (X-15)(X-15) / X
Solving,
X2 -29X= X2 – 30 X + 225
X = 225
Thus, length of the course is 225 metres.
ANSWER A
Answer: A
Question: Marketing executives for a certain chewing gum company projected a 30 percent increase in revenue this year over that of last year, but revenue this year actually decreased by 25%. What percent of the projected revenue was the actual revenue ?
Options:
A)53%
B)57.7%
C)62.5%
D)64%
E)75%
Rationale: Last year revenue = 100 (assume);
This year revenue = 75;
Projected revenue = 130.
Actual/Projected*100=75/130*100 = 57.7%.
Answer: B.
Answer: B
Question: one train has crossing a bridge of length 340 m in 42 sec and same train has crossing a another bridge of 500 m in 50 sec. what is the approximate speed of the train in km/hr?
Options:
A)60
B)64.8
C)72
D)76
E)78
Rationale: length of train = l m
speed of train = v m/s then
340+l = 42v
500+l = 50v
subtract, 8v = 160
=> v = 20m/s = 72 kmph
ANSWER:C
Answer: C
Question: For every $20 that a billionaire spends, a millionaire spends the equivalent of 10 cents. For every $4 that a millionaire spends, a yuppie spends the equivalent of $1. The ratio of money spent by a yuppie, millionaire, and billionaire can be expressed as
Options:
A)1 : 4 : 400
B)1 : 4 : 100
C)20 : 4 : 1
D)1:4:800
E)400 : 4 : 1
Rationale: millionaire 10 cents = 1/10 dollar ..therefore 1 dollar M = 200 dollar of B
therefore 4 dollar M = 800 dollar of B also 1 dollar Y
Y:M:B = 1:4:800
= 1:4:800
D
Answer: D
Question: Eshan and Mary each wrote two or three poem every day over a period of time eshan wrote 43 poems while Mary wrote 61. The number of days in this period is.....
Options:
A)19
B)21
C)20
D)19
E)18
Rationale: suppose, Eshan writes 2poems in first 18days 18*2=36.
2poems in next 2 days 2*2=4, 36+4=40
and 3poems in next 1day 1*3=3, 40+3=43
So, Ultimately he takes (18+2+1) = 21days to write 43 poems.
now suppose, Marry writes 3poems in 1st 18days 18*3=54
2poems in next 2days 2*2=4, 54+4=58
3poems in next 1 day 1*3=3, 58+3=61
So ultimately marry takes (18+2+1)= 21days to write 61poems.
ANSWER:B
Answer: B
Question: If a positive odd integer N has p positive factors, how many positive factors will 3N have ?
Options:
A)p
B)2p
C)P+1
D)2p+1
E)Cannot be determined
Rationale: I have added some extra text to make this question more GMAT-like:
Let's TEST some values of N
Try N = 3
The factors of 3 are {1, 3}. Here, p =2
So, 2N = (2)(3) = 6
The factors of 6 are {1, 2, 3, 6}. So, we have a total of4
Now check the answer choices:
A) p =2No good. We want an output of4. ELIMINATE
B) 2p = (2)(2) = 4. PERFECT! KEEP B
C) P+1 =2+ 1 = 3 No good. We want an output of4. ELIMINATE
D) 2p+1 = (2)(2) + 1 = 5 No good. We want an output of4. ELIMINATE
E) Cannot be determined. POSSIBLE. KEEP E
Let's TEST another value of N
Try N = 7
The factors of 7 are {1, 7}. Here, p =2
So, 2N = (2)(7) = 14
The factors of 14 are {1, 2, 7, 14}. So, we have a total of4
Now check the REMAINING answer choices:
B) 2p = (2)(2) =4. PERFECT! KEEP B
E) Cannot be determined. POSSIBLE. KEEP E
Let's TEST one more (non-prime) value of N
Try N = 9
The factors of 9 are {1, 3, 9}. Here, p =3
So, 2N = (2)(9) = 18
The factors of 18 are {1, 2, 3, 6, 9}. So, we have a total of6
Now check the REMAINING answer choices:
B) 2p = (2)(3) =6. PERFECT! KEEP B
E) Cannot be determined. POSSIBLE. KEEP E
At this point, it SEEMS LIKELY that the correct answer is C
Answer: C
Question: Income and expenditure of a man are in the ratio 4 : 3. If the income of the person is Rs. 12000, then find his savings?
Options:
A)2600
B)2700
C)2800
D)2900
E)3000
Rationale: Let the income and the expenditure of the person be Rs. 4x and Rs. 3x respectively.
Income, 4x = 12000
=> x = 3000
Savings = Income - expenditure
= 4x - 3x = x
So, savings =Rs.3000.
Answer: E
Answer: E
Question: A tour group of 25 people paid a total of $670 for entrance to a museum. If this price included a 5% sales tax, and all the tickets cost the same amount, what was the face value of each ticket price without the sales tax?
Choices
Options:
A)$22
B)$23.94
C)$24
D)$25.46
E)$30
Rationale: D.
Answer: D
Question: A man buys an item at Rs. 600 and sells it at the loss of 20 percent. Then what is the selling price of that item
Options:
A)Rs. 480
B)Rs. 760
C)Rs. 860
D)Rs. 960
E)None of these
Rationale: Explanation:
Here always remember, when ever x% loss,
it means S.P. = (100 - x)% of C.P
when ever x% profit,
it means S.P. = (100 + x)% of C.P
So here will be (100 - x)% of C.P.
= 80% of 600
= 80/100 * 600
= 480
Option A
Answer: A
Question: If Rs. 10 be allowed as true discount on a bill of Rs. 110 due at the end of a certain time, then the discount allowed on the same sum due at the end of double the time is:
Options:
A)Rs. 20
B)Rs. 21.80
C)Rs. 22
D)Rs. 22.33
E)Rs. 18.33
Rationale: S.I. on Rs. (110 - 10) for a certain time = Rs. 10.
S.I. on Rs. 100 for double the time = Rs. 20.
T.D. on Rs. 120 = Rs. (120 - 100) = Rs. 20.
T.D on Rs. 110 = Rs.(20/120)x100=Rs.18.33
answer:E
Answer: E
Question: Two cars, Car1 and Car2 move towards each other from W and Y respectively with respective speeds of 20 m/s and 15 m/s. After meeting each other Car1 reaches Y in 10 seconds. In how many seconds does Car 2 reach W starting from Y?
Options:
A)15.5 sec
B)8.4 sec
C)33.6 sec
D)31.11 sec
E)16.8 sec
Rationale: W--------------------------------------|----------------------------Y
Car A(20mps)------------------------->P<---------------Car B(15mps)
Let 2 cars meet each other at point P in t seconds.
Car1 covers distance= 20t. Car2 covers distance=15t. So, total distance WY= 35t.
From P, Car 1 reaches onto Y in 10 secs. So it covers 15t further.
so, 15t/20 = 10
So t=40/3 sec and total distance = (35*40)/3
Hence Car2 will cover total distance in (35*40)/(3*15) = 31.11 sec approx.
Answer D
Answer: D
Question: A can finish a work in 12 days and B can do same work in half the time taken by A. then working together, what part of same work they can finish in a day?
Options:
A)1/4
B)1/6
C)1/7
D)1/8
E)None of these
Rationale: Explanation:
Please note in this question, we need to answer part of work for a day rather than complete work. It was worth mentioning here because many do mistake at this point in hurry to solve the question
So lets solve now,
A's 1 day work = 1/12
B's 1 day work = 1/6 [because B take half the time than A]
(A+B)'s one day work =
(1/12+1/6)=1/4
So in one day 1/4 work will be done
Answer: A
Answer: A
Question: Find how many positive integers less than 10,000 are there such thatthe sum of the digits of the no. is divisible by 3?
Options:
A)3468
B)2378
C)2875
D)3334
E)3579
Rationale: If sum of the digits is divisible by 3, the number is divisible by 3.
Therefore, required number of non-negative integers is equal to count of numbers less than 10,000 which are divisible by 3.
Such numbers are (3, 6, 9, ... , 9999) (arithmetic progression with first term=3, last term=9999, common difference=3).
Count of such numbers =
9999
3
=
3333
99993=3333
But zero is also divisible by 3.
This makes our total count 3334
D
Answer: D
Question: There are 3 green shirts, 2 white shirts, 5 blue shirts, and 7 red shirts in the wardrobe. What is the least number of shirts that you have to take out to make sure that you will have a matching pair?
Options:
A)4
B)7
C)5
D)2
E)6
Rationale: Since there are 4 colors, if you take 4 shirts, you could still have 1 shirt per color and not have a match.
Therefore, upon taking the 5th shirt, you will definitely have a match since the 5th shirt will form at least a pair with the 1st 4
So 4+1 = 5
Answer is C
Answer: C
Question: If 4a = 16b and 8b = 13c, Find a:b:c?
Options:
A)52:13:8
B)13:7:52
C)7:13:52
D)7:13:54
E)None of these
Rationale: Explanation:
(4a = 16b ==> a/b = 16/4)
and (8b = 13c ==> b/c = 13/8)
==> a:b = 16:4 and b:c = 13:8
a:b:c = 52:13:8
Answer: Option A
Answer: A
Question: A rectangular floor is covered by a rug except for a strip 4 meters wide along each of the four edge. If the floor is 25 meters by 20 meters, what is the area of the rug in square meters?
Options:
A)256
B)266
C)204
D)224
E)324
Rationale: A strip of 4 meters is covering the inner rectangular rug for all 4 sides.
Length of inner rug = 25-(2*4)
breadth of inner rug= 20-(2*4)
Area of Rug= 17 * 12 = 204 sq. mt
Ânswer: C
Answer: C
Question: Ten telegenic contestants with a variety of personality disorders are to be divided into two “tribes” of four members each, tribe A and tribe B, for a competition. How many distinct groupings of two tribes are possible?
Options:
A)120
B)126
C)210
D)1200
E)1260
Rationale: My ans is 10C4 = 210
C
Answer: C
Question: Find the value of
(10)150÷(10)146
Options:
A)10
B)100
C)1000
D)10000
E)None of these
Rationale: Explanation:
=(10)150/(10)146=10(4)=10000
Option D
Answer: D
Question: The average salary per head of the entire staff of an office including the officers and clerks is Rs.90. The average salary of officers is Rs.600 and that of the clerks is Rs.84. If the number of officers is 2, find the number of officers in the office?
Options:
A)3
B)1
C)8
D)9
E)5
Rationale: 6 * 22 = 132
7 * 19 = 133
--------------
1
Answer:B
Answer: B
Question: The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is:
Options:
A)123
B)127
C)235
D)305
E)315
Rationale: HCF of 1651 ( 1657-6) and 2032 (2037-5) is 127.
ANSWER:B
Answer: B
Question: In each of the following questions a number series is given with one term missing. Choose the correct alternative that will continue the same pattern and fill in the blank spaces.
2, 7, 14, ?, 34, 47
Options:
A)31
B)23
C)36
D)31
E)33
Rationale: B
23
The given sequence is +5, +7, +9, ——
ie. 2+ 5 = 7, 7 + 7 = 14, 14 + 9 = 23
Answer: B
Question: What is the probability of getting exactly 1 head in a single throw of five fair coins?
Options:
A)1/4
B)3/8
C)3/16
D)5/32
E)7/32
Rationale: One possible case is HTTTT.
P(HTTTT) = 1/2*1/2*1/2*1/2*1/2 = 1/32
There are 5C1 = 5 possible cases.
P(1 head) = 5*1/32 = 5/32
The answer is D.
Answer: D
Question: If a store adds 60 chairs to its current inventory, the total number of chairs will be the same as three-halves the current inventory of chairs. If the manager wants to increase the current inventory by 50%, what will the new inventory of chairs be?
Options:
A)40
B)60
C)100
D)180
E)160
Rationale: Explanation:
Letâ€™s say t = total current inventory of chairs. The first sentence states that 60 + t = (3/2)t. First solve for the current inventory:
60 + t = (3/2)t
60 = (3/2)t âˆ’ t
60 = (1/2)t
120 = t
The manager wants to increase this by 50%.
50% of 120 is 60, so the new inventory will be 180.
Answer: (D).
Answer: D
Question: Find the value of x in the sequence of numbers 5,1,6,0,4,8,x,2 if the sum of the first 7 numbers is 30 and the average is 4.
Options:
A)4
B)9
C)8
D)6
E)7
Rationale: Given 5+1+6+0+4+8+x =30 (36+6)/7 =6 Answer : D
Answer: D