divelab/Sys2Bench huggingface dataset:
Question: In an office, totally there are 5200 employees and 45% of the total employees are males. 50% of the males in the office are at-least 50 years old. Find the number of males aged below 50 years?
Options:
A)1040
B)1170
C)1150
D)4160
E)None of these
Rationale: Number of male employees = 5200* 45/100 = 2340
Required number of male employees who are less than 50 years old = 4160 * (100 - 50)%
= 2340* 50/100 = 1170.
ANSWER:B
Answer: B
Question: In how many different ways can 4 physics, 2 math and 3 chemistry books be arranged in a row so that all books of the same branch are together?
Options:
A)1242
B)1728
C)1484
D)1734
E)1726
Rationale: Soln:
= 3! * 4! * 2! * 3!
= 1728
Ans is B
Answer: B
Question: In the floor of a particular kitchen owned by an abstract artist, each row of tiles to the right of the first row contains two fewer tiles than the row directly to its left. If there are nine rows in all and a total of 405 tiles in the floor, how many tiles does the leftmost row contain?
Options:
A)53
B)56
C)60
D)64
E)68
Rationale: This question can be solved in a variety of ways: with algebra, by TESTing THE ANSWERS and by using a great Number Property shortcut involving consecutive integers.
We're given a few facts to work with:
1) There are 9 rows of tiles.
2) When going from 'left to right', each row contains TWO FEWER tiles than the one next to it.
3) There are a total of 405 tiles
We're asked how many tiles the left-most most row holds (meaning the one with the MOST tiles).
To start, 405 is divisible by 9, so we can figure out the AVERAGE number of tiles per row. That is 405/9 = 45. Since we're dealing with a set of 9 consecutive integers that differ by 2 each, we know that the '5th row' will have 45 tiles (the average). Then we just have to 'add 2s' until we get to the first row...
45 +2 +2 +2 +2 = 53.
Final Answer:
A
Answer: A
Question: A train runs at the speed of 72 kmph and crosses a 250 metre long platform in 26 seconds. What is the length of the train?
Options:
A)270 m
B)200 m
C)400 m
D)340 m
E)150 m
Rationale: speed = 72 * 5/18 = 20 m/s
length of the train - x m
distance covered = 250 + x
time = 26 s
250+x/26=20
250+x=26*20=520
x=520-250=270
ANSWER A
Answer: A
Question: Three numbers are in the ratio 3:5:7. The largest number value is 42. Find difference between Smallest & largest number is?
Options:
A)20
B)24
C)26
D)28
E)32
Rationale: == 3:5:7
Total parts = 15
= The largest number value is 42
= The largest number is = 7
= Then 7 parts -----> 42 ( 7 * 6 = 42 )
= smallest number = 3 & Largest number = 7
= Difference between smallest number & largest number is = 7 - 3 = 4
= Then 4 parts -----> 24 (4 * 6 = 24)
B
Answer: B
Question: Speed of a boat in standing water is 8kmph and speed of the stream is 0.5kmph. A man can rows to a place at a distance of 105km and comes back to the starting point. The total time taken by him is?
Options:
A)27.35hours
B)26.35hours
C)25.35hours
D)24.35hours
E)23.35hours
Rationale: Speed upstream = 7.5kmph
Speed downstream = 8.5kmph
Total time taken = 105/7.5 + 105/8.5 = 26.35 hours
Answer is B
Answer: B
Question: A teacher will pick a group of 4 students from a group of 8 students that includes Lisa. If one of all the possible four-student groups is picked at random, what is the probability of picking a group that includes Lisa?
Options:
A)1/7
B)3/14
C)1/2
D)1/3
E)3/7
Rationale: Probability = Favorable Outcomes / Total Outcomes
Total Outcomes= Total No. of ways of Picking Group of 4 out of 8 = 8C4 = 8! / (4! * 4!) = 70
Favorable Outcomes= Total No. of ways of Picking Group of 4 out of 8 such that L is always in the group (i.e. we only have to pick remaining 3 out of remaining 7 as L must be there in group) = 7C3 = 35
Hence,Probability=35/70=1/2
Answer: Option C
Answer: C
Question: In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. What is the duration of the flight ?
Options:
A)3 hours
B)2.4 hours
C)1.4 hours
D)1 hour
E)None of these
Rationale: Explanation:
Let the duration of the flight be x hours.
Then
600/x−600 /x+1/2=200
600/x−1200 /2x+1=200
x(2x+1)=3
2x2+x−3=0
=>(2x+3)(x−1)=0
Neglecting the negative value for x we get x = 1
Option D
Answer: D
Question: The average monthly income of P and Q is Rs. 2050. The average monthly income of Q and R is Rs. 5250 and the average monthly income of P and R is Rs. 6200. The monthly income ofQ is:
Options:
A)1100
B)2100
C)1200
D)3100
E)1300
Rationale: Explanation:
Let P, Q and R represent their respective monthly incomes. Then, we have:
P + Q = (2050 x 2) = 4100 .... (i)
Q + R = (5250 x 2) = 10500 .... (ii)
P + R = (6200 x 2) = 12400 .... (iii)
Adding (i), (ii) and (iii), we get: 2(P + Q + R) = 27000 or P + Q + R = 13500 .... (iv)
Subtracting (iii) from (iv), we get P = 1100.
P's monthly income = Rs. 1100.
Answer: A
Answer: A
Question: A man sitting in a train which is traveling at 50 kmph observes that a goods train, traveling in opposite direction, takes 9 seconds to pass him. If the goods train is 280 m long, find its speed
Options:
A)52 kmph
B)56 kmph
C)58 kmph
D)62 kmph
E)72 kmph
Rationale: Explanation:
Relative speed = 280/9 m / sec = ((280/9)×(18/5)) kmph = 112 kmph.
Speed of goods train = (112 - 50) kmph = 62 kmph
Answer: Option D
Answer: D
Question: If 2994 Ã· 14.5 = 177, then 29.94 Ã· 1.45 = ?
Options:
A)17.1
B)17.3
C)17.5
D)17.7
E)17.2
Rationale: 29.94/ 1.45 = 299.4/14.5
= (2994/14.5) x 1/10) [ Here, Substitute 177 in the place of 2994/14.5 ]
= 177/10
= 17.7
Answer is D.
Answer: D
Question: In a village of 2,600 people, 800 people are over 70 years old and 850 people are female. It is known that 40 percent of the females are younger than 70 years old. If no one in the village is 70 years old, what is the probability that a person chosen at random is either a male or younger than 70 years old?
Options:
A)221/250
B)199/250
C)33/50
D)8/25
E)209/260
Rationale: The number of people younger than 70 years old is 2600-800 = 1800
The number of females older than 70 years old is 0.6*850 = 510
Then the number of males older than 70 years old is 800 - 510 = 290.
The number of people who are either male or younger than 70 is 1800+290 = 2090.
P(a person is younger than 70 or male) = 2090/2600 = 209/260
The answer is E.
Answer: E
Question: A certain car can travel 40 minutes on a gallon of gasoline at 60 miles per hour. If the car had started with a full tank and had 8 gallons of gasoline left in its tank at the end, then what percent of the tank was used to travel 80 miles at 60 mph?
Options:
A)15%
B)20%
C)25%
D)30%
E)40%
Rationale: otal time for travelling 80 miles @ 60 mph = 80/60 = 4/3 hour = 80 minutes.
Given, the car uses 1 gallon for every 40 minutes of driving @ 60 mph. Thus in 80 minutes it will use = 2 gallons. Thus, full tank = 2+8 = 10 gallons ---> 2/10 = 20% of the fuel used. B is the correct answer.
Answer: B
Question: In N is a positive integer less than 200, and 14N/60 is an integer, then N has how many different positive prime factors C?
Options:
A)2
B)3
C)5
D)6
E)8
Rationale: I like to put the numbers in prime factors so it is easier and faster to visualize.
14*n/60
If we write the factors of 14 --> 2, 7, and the factors of 60 --> 2, 2, 3, 5, we have
(2*7*n)/(2^2*3*5)
Simplifying
7*n/(2*3*5)
The only way the equation above has an integer value is if n has AT LEAST the factors 2, 3 and 5, so we can simplify again and we have the number 7.
The number could be 2*3*5, or 2*3*5*2, or 2*3*5*.....
However to be less than 200 we can not add any prime number.
2*3*5 = 120
If we added the next prime factor 7, we would have C=2*3*5*7 = 840
Thus, answer B
Answer: B
Question: The area of a triangle will be when a = 1m, b = 4m, c = 5m, a, b, c being lengths of respective sides?
Options:
A)2
B)7
C)5
D)3
E)4
Rationale: S = (1 + 4 + 5)/2
= 5
Answer: C
Answer: C
Question: Five pieces of wood have an average length of 120cm and a median length of 140cm. What is the maximum possible length, in cm, of the shortest piece of wood?
Options:
A)a) 90
B)b) 100
C)c) 110
D)d) 130
E)e) 140
Rationale: A. 90
sum of all lengths of all 5 pieces of wood = 124 * 5 = 600
3rd piece (sorted in increasing length) length = 140 (median)
for sum of first 2 wood length to become max, last two should be least.
let 4th, 5th wood also have length 140 each.
total of last 3 = 140 * 3 = 420
sum of first 2 = 600 - 420 = 180
each of these 2 will have length 180/2 = 90
Answer A
Answer: A
Question: The distance between two cities A and B is 330 Km. A train starts from A at 8 a.m. and travel towards B at 60 km/hr. Another train starts from B at 9 a.m and travels towards A at 75 Km/hr. At what time do they meet?
Options:
A)10 am
B)11 am
C)12 pm
D)1 pm
E)2 pm
Rationale: Explanation:
Suppose they meet x hrs after 8 a.m.
then
(Distance moved by first in x hrs) + [Distance moved by second in (x-1) hrs]
= 330
So, 60x+75(x-1) = 330
x=3.
So,they meet at (8+3). i.e 11a.m.
Option B
Answer: B
Question: A trader sells 45 meters of cloth for Rs. 4500 at the profit of Rs. 14 per metre of cloth. What is the cost price of one metre of cloth?
Options:
A)Rs. 80
B)Rs. 86
C)Rs. 90
D)Rs. 95
E)None of these
Rationale: SP of 1m of cloth = 4500/45= Rs. 100
CP of 1m of cloth = SP of 1m of cloth - profit on 1m of cloth
= Rs. 105 - Rs. 14 = Rs. 86.
ANSWER:B
Answer: B
Question: A mixture of 85 kg contains milk and water in the ratio 27 : 7. How much more water is to be added to get a new mixture containing milk and water in the ratio 3:1?
Options:
A)5 kg
B)6.5 kg
C)7.5 kg
D)8 kg
E)9 kg
Rationale: Milk in 85 kg of mix = 85* (27/34) = 135/2 kg.
Water in it = 85-135/2 = 35/2 kg.
Let x kg of water be added to it.
Then, (135/2)/(35/2 + x) = 3/1; 135/(35 +2x) = 3/1;
105 + 6x = 135 ; 6x = 30; x = 5
The quantity of water to be added = 5 kg
ANSWER:A
Answer: A
Question: In a room of length 24mts, breadth 18mts, height 16 mts. what is the length of longest rod that can be placed in the room?
Options:
A)24 mtres.
B)34 mtres.
C)44 mtres.
D)54 mtres.
E)64 mtres.
Rationale: diagonal = 30m
now hypo of (floor)
diag and height will be =34 mtres.
ANSWER:B
Answer: B
Question: From a total of 3 boys and 4 girls, how many 4-person committees can be selected if the committee must have exactly 2 boys and 2 girls?
Options:
A)18
B)24
C)60
D)120
E)240
Rationale: Answer=C=18
No of 4 person committees that can be formed=3C2*4C2=18
Answer A
Answer: A
Question: A tourist purchased a total of $1,300 worth of traveler’s checks in $10 and $50 denominations, During the trip the tourist cashed 7 checks and then lost all of the rest. If the number of $10 checks cashed was one more or one less than the number of $50 checks cashed, what is the minimum possible value of the checks that were lost?
Options:
A)$1,430
B)$1,310
C)$1,290
D)$1,070
E)$1,150
Rationale: since total cashed checks = 7 ans $10 check cashed = one less or more than $50 checks
Therefore either $10 checks = 3 and $50 checks = 4 OR $10 checks = 4 and $50 checks = 3
using this information 1st option gives us the maximum cashed value therefore if we negate this value from total value we will get minimum value of which checks have lost
Therfore 1300 - 230 = 1070 hence answer is D
Answer: D
Question: A man cycling along the road noticed that every 18 minutes a bus overtakes him and every 6 minutes he meets an oncoming bus. If all buses and the cyclist move at a constant speed, what is the time interval between consecutive buses?
Options:
A)5 minutes
B)6 minutes
C)8 minutes
D)9 minutes
E)10 minutes
Rationale: Let's say the distance between the buses is d. We want to determine Interval=\frac{d}{b}, where b is the speed of bus.
Let the speed of cyclist be c.
Every 18 minutes a bus overtakes cyclist: \frac{d}{b-c}=18, d=18b-18c;
Every 6 minutes cyclist meets an oncoming bus: \frac{d}{b+c}=6, d=6b+6c;
d=18b-18c=6b+6c, --> b=2c, --> d=18b-9b=9b.
Interval=\frac{d}{b}=\frac{9b}{b}=9
Answer: D (9 minutes).
Answer: D
Question: If −2≤a≤0 and n > 19, which of the following CANNOT be the value of an?
Options:
A)-48
B)-38
C)-20
D)0
E)19
Rationale: value of an not equal to -19=E....Rest all are achievable
Answer: E
Question: As a treat for her two crying children, a mother runs to the freezer in which she has four cherry ice pops, three orange ice pops, and four lemon-lime ice pops. If she chooses two at random to bring outside to the children, but realizes as she runs out the door that she cannot bring them different flavors without one invariably being jealous of the other and getting even more upset, what is the probability that she has to return to the freezer to make sure that they each receive the same flavor?
Options:
A)1/99
B)1/6
C)5/18
D)13/18
E)5/6
Rationale: Probability of not getting the same flavor ->
Fouvarable -> Cherry - orange [ 4C1 * 3C1 [or simply 4*3 ] or Cherry - lemon [ 4*4] or orange - lemon [3*4]
Prob = (4*3 + 4*4 + 3*4 ) / 9C2 = 40/3960 = 1/99
Answer -> A
Answer: A
Question: A and B walk around a circular track. A and B walk at a speed of 1 rounds per hour and 4 rounds per hour respectively. If they start at 7 a.m. from the same point in opposite directions, how many times shall they cross each other before 8.30 a.m.?
Options:
A)7
B)9
C)4
D)3
E)8
Rationale: Relative speed = Speed of A + Speed of B (âˆ´ they walk in opposite directions)
= 1 + 4 = 5 rounds per hour
=> They cross each other 5 times in 1 hour and 2 times in 1/2 hour
Time duration from 7 am to 8.30 am = 1.5 hour
Hence they cross each other 7 times before 8.30 am
Answer : A
Answer: A
Question: There are 14 songs in that 5 Rock songs, 6 western songs & 3 Hindi pop songs. How many different albums can be formed using the above repertoire if the albums should contain at least 1 Rock song & 1 western song?
Options:
A)15624
B)16478
C)17953
D)19655
E)28958
Rationale: 15624
A
Answer: A
Question: If it would take one machine 15 minutes to fill a large production order and another machine 20 minutes to fill the same order, how many minutes would it take both machines working together, at their respective rates, to fill the order?
Options:
A)4 1/60
B)5
C)5 5/11
D)5 1/2
E)8 4/11
Rationale: Since , Machine 1-M1 take 15 mins to fill the order
The work done by M1 in a min = 1/15
Machine 2- M2 take 20 mins to fill the same order
and work done by M2 in a min = 1/20
Total work done by M1 and M2 in a min = 1/15 + 1/20 = 7/60
Time needed for M1 and M2 to complete the order = 60/7 = 8 4/11
Answer E
Answer: E
Question: A certain car dealership sells economy cars, luxury cars, and sport utility vehicles. The ratio of economy to luxury cars is 3:2. The ratio of economy cars to sport utility vehicles is 5:3. What is the ratio of luxury cars to sport utility vehicles?
Options:
A)9:8
B)8:9
C)3:2
D)2:3
E)10:9
Rationale: The ratio of economy to luxury cars is 3:2 --> E:L = 3:2 = 15:10.
The ratio of economy cars to sport utility vehicles is 5:3 --> E:S = 5:3 = 15:9.
Thus, L:S = 10:9.
Answer: E.
Answer: E
Question: In a kilometer race, A beats B by 40 meters or 15 seconds. What time does A take to complete the race?
Options:
A)277 sec
B)285 sec
C)267 sec
D)167 sec
E)276 sec
Rationale: Time taken by B run 1000 meters = (1000 * 15)/50 = 300 sec.
Time taken by A = 300 - 15 = 285 sec.Answer: B
Answer: B
Question: In a local school district, the high school and middle school each received r dollars toward funding for the student arts program. The high school enrolled 600 students and the middle school enrolled 300 students. Later, the middle school transferred s dollars to the high school so that they would have received the same funding per student. Which of the following is equivalent to s?
Options:
A)r/3
B)r/2
C)2r
D)3r
E)r/9
Rationale: Total per head = 2r/900
After s transfer both schools have total for head.
So at High School it will be:
r+s = (600)* (2r/900) = 12r/9=4r/3
i.e. s = 4r/3 - r/1 =4r-3r/3=r/3
Answer :A
Answer: A
Question: The Malibu Country Club needs to drain its pool for refinishing. The hose they use to drain it can remove 60 cubic feet of water per minute. If the pool is 60 feet wide by 150 feet long by 10 feet deep and is currently at 80% capacity, how long will it take to drain the pool?
Options:
A)1800
B)1000
C)1200
D)1400
E)1600
Rationale: volume of pool = 60*150*10 cu.ft , 80% full = 60*150*10*0.8 cu.ft water is available to drain.
draining capacity =60 cu.ft /min therefore time taken = 60*150*10*0.8/ 60 min= 1200 min
C
Answer: C
Question: Simplfy
3b - [b -(a+b) - {b - (b - a+b)} + 2a]
Options:
A)a
B)2b
C)4a
D)0
E)1
Rationale: Explanation:
3b-[b-(a+b)-{b-(b-a+b)}+2a]
=3b-[b-a-b-{b-(2b-a)}+2a]
=3b-[-a-{b-2b+a}+2a]
=3b-[-a-{-b+a}+2a]
=3b-[-a+b-a+2a]
=3b-[-2a+b+2a]
=3b-b
=2b
Option B
Answer: B
Question: The average age of 15 students of a class is 15 years. Out of these, the average age of 6 students is 14 years and that of the other 8 students is 16 years. The age of the 15th student is
Options:
A)9 years
B)13 years
C)14 years
D)21 years
E)25 years
Rationale: Solution
Age of the 15th student	=[15x15-(14x6+16x8)]
= (225 - 212)
= 13 years.
Answer B
Answer: B
Question: A bag contains five white and four red balls. Two balls are picked at random from the bag. What is the probability that they both are different color?
Options:
A)5/9
B)3/10
C)2/9
D)10/19
E)4/9
Rationale: 9C2 ==> 5C1, 4C1
Req = (5*4)/9C2=20/36=5/9
ANSWER A
Answer: A
Question: Two men are going along a track rail in the opposite direction. One goods train crossed the first person in 20 sec. After 10 min the train crossed the other person who is coming in opposite direction in 18 sec .After the train has passed, when the two persons will meet?
Options:
A)95 minutes
B)90 minutes
C)88 minutes
D)95 minutes
E)None of these
Rationale: Explanation :
Let us consider that speed of train , first man and second man are respectively t, f and s.
According to first given condition goods train crossed the first person moving in same direction in 20 sec.
So length of the will be 20(t-f)
Similarly train crossed the second man in 18 sec.
So length of the train will be 18(t+s) on comparing these two equations, we get 20(t-f) = 18(t+s)
=> 2t = 20f + 18s
=> t = 10f + 9s
Now it is given that After 10 min the train crossed the other person who is coming in opposite direction.
So,If we consider this way of train as L then the next equation will be
L = 600t (here 600 is used for 10 minutes)
Finally as asked in the question the time required to meet the two man after the train has passed will
be given by
Time = (L-600 f)/(f+s) {here 600f is used for the distance traveled by first man in 10 minutes}
=> = (600t-600f) / (f+s)
=> = [600(10f+9s)-600f] / (f+s)
=> = 600(10f+9s-f) / (f+s) = 600 * 9(f+s) / (f+s)
=> =600*9 seconds
=> = 600*9/60min
=> = 90 minutes
Hence (B) is the correct answer.
Answer : B
Answer: B
Question: A library branch originally contained 18360 volumes, 30% of which were fiction novels. 1/4 of the volumes were transferred to another location and 1/3 of the volumes transferred were fiction novels. What percent of the remaining collection was fiction novels?
Options:
A)2.5%
B)17.67%
C)28.8%
D)45.2%
E)73.6%
Rationale: Fiction Novels = 5,508
Transferred to another location = 4590
Transferred fiction novels = 1530
Non Transferred Fiction Novels = 3,978
Percent of the remaining collection was fiction novels = 3978/(18360 - 4590 ) * 100 => 28.888...%
Hence answer will be (C)
Answer: C
Question: If -x^2 - 2y^2 = 2xy, then (x+y)^2 =
Options:
A)x^2
B)3x^2
C)4xy
D)2y^2
E)-y^2
Rationale: Its B
-x^2 -2y^2 = 2xy
-2y^2 = 2xy + x^2
Add y^2 on both sides we get
-2y^2 +y^2 = x^2 +y^2 +2xy
-y^2 = (x+y)^2
Correct Option : E
Answer: E
Question: The compound interest accrued on an amount of Rs.44000 at the end of two years is Rs.1193.60. What would be the simple interest accrued on the same amount at the same rate in the same period?
Options:
A)34348
B)37888
C)10560
D)29877
E)27881
Rationale: Let the rate of interest be R% p.a.
4400{[1 + R/100]2 - 1} = 11193.60
[1 + R/100]2 = (44000 + 11193.60)/44000
[1 + R/100]2 = 1 + 2544/1000 = 1 + 159/625
[1 + R/100]2 = 784/625 = (28/25)2
1 + R/100 = 28/25
R/100 = 3/25
Therefore R = 12 SI on Rs.44000 at 12% p.a. for two years = 44000(2)(12)/100
=Rs.10560
Answer: C
Answer: C
Question: A = {0, 1, -3, 6, -8, 20, 4}
B = {-1, 2, -4, 7, 5}
If a is a number that is randomly selected from Set A, and b is a number that is randomly selected from Set B, what is the probability that ab > 0?
Options:
A)1/4
B)1/3
C)2/5
D)4/9
E)12/35
Rationale: For the product of 2 numbers to be positive either both of them must be positive or both of them must be negative:
P(positive, positive) = 4/7*3/5 = 12/35;
P(negative, negative) = 2/7*2/5 = 4/35.
P = 12/35 + 4/35
= 12/35
Answer: E
Answer: E
Question: 0.002 x 0.4 = ?
Options:
A)8.0
B)0.008
C)0.08
D)0.8
E)0.0008
Rationale: 2 x 4 = 8.
Sum of decimal places = 4
0.002 x 0.4 = 0.0008
Answer: Option E
Answer: E
Question: A bag contains 7 red and 3 green balls. Another bag contains 4 red and 6 green balls. If one ball is drawn from each bag. Find the probability that one ball is red and one is green.
Options:
A)19/20
B)17/20
C)21/50
D)8/10
E)9/40
Rationale: Let A be the event that ball selected from the first bag is red and ball selected from second bag is green.
Let B be the event that ball selected from the first bag is green and ball selected from second bag is red.
P(A) = (7/10) x (6/10) = 21/50.
P(B) = (3/10) x (4/10) = 3/25.
Hence, the required probability is P(A) + P(B) which is nothing but 21/50.
ANSWER:C
Answer: C
Question: In My, Xiang sold 15 used cars. For these 15 used cars the range of selling prices was 15,000 and the lowest selling price was 4,500. In June, Xiang sold 10 cars. For these 10 cars the range of selling was 16,000 and the lowest selling price was 5,000. What was the range of selling prices for the 25 used car sold by xiang in May and June?
Options:
A)15,600
B)15,750
C)16,820
D)18,100
E)19,200
Rationale: for 10 cars - 16000+ 5000 = 21,000
for 15 cars - 15000+ 4500 = 19,500
max = 21,000 min 4500
answer is approx 16,500.
Option C is closest.
Answer: C
Question: The purchase price of an article is $48. In order to include 5% of cost for overhead and to provide $12 of net profit, the markup should be
Options:
A)15%
B)25%
C)30%
D)40%
E)45%
Rationale: Cost price of article = 48$
% of overhead cost = 5
Net profit = 12 $
We need to calculate % markup
Net profit as % of cost price = (12/48)*100 = 25%
Total markup should be = 25 + 5 = 30%
Answer C
Answer: C
Question: A train 100 m long crosses a platform 125 m long in 15 sec; find the speed of the train?
Options:
A)94 kmph
B)58 kmph
C)54 kmph
D)94 kmph
E)59 kmph
Rationale: D = 100 + 125 = 225
T = 15
S = 225/15 * 18/5 = 54 kmph
Answer:C
Answer: C
Question: What is the largest prime factor of 27^3−9^3−3^6?
Options:
A)2
B)3
C)5
D)7
E)11
Rationale: 27^3−9^3−3^6 = 3^9 - 3^6 - 3^6 = 3^6( 3^3-1-1) = 3^6 (27-2) = 3^6 * 5^2.
Two prime factors are 3 and 5. Therefore, max prime factor is 5.
ANSWER:C
Answer: C
Question: 5358 x 81 = ?
Options:
A)423762
B)433758
C)433298
D)433998
E)437382
Rationale: D
273258
5358 x 81 = 5358 x (80 + 1)
= 5358 x 80 + 5358 x 1
= 428640 + 5358
= 433998
Answer: D
Question: Of the land owned by a farmer, 90 percent was cleared for planting. Of the cleared land, 10 percent was planted with grapes and 80 percent of the cleared land was planted with potato. If the remaining 450 acres of cleared land was planted with tomato, how many acres did the farmer own?
Options:
A)3500
B)4500
C)5500
D)5250
E)5000
Rationale: 10% od 90% = 9%, 80% 0f 90% = 72% so the remaining 90-9-72=9%=450 acres or 10% of 90%=9% --> 450/9*100=5000 acres Answer (E)
Answer: E
Question: The average (arithmetic mean) of 16 students first quiz scores in a difficult English class is 62.5. When one student dropped the class, the average of the remaining scores increased to 62.0. What is the quiz score of the student who dropped the class?
Options:
A)a) 10
B)b) 25
C)c) 40
D)d) 55
E)e) 70
Rationale: Total Score of 16 students is 16*62.50 = 1000
Total Score of 15 students is 15*62 = 930
So, the score of the person who left is 70 ( 1000 - 930 )
Answer will be (E)
Answer: E
Question: A group of men decided to do a work in 8days, but 3 of them became absent. If the rest of the group did the work in 10days, Find the original number of men?
Options:
A)15
B)20
C)30
D)25
E)18
Rationale: Original number of men = 3*10 / (10-8) = 15
Answer is A
Answer: A