divelab/Sys2Bench huggingface dataset:
Question: A certain university will select 1 of 7 candidates eligible to fill a position in the mathematics department and 3 of 10 candidates eligible to fill 3 identical positions in the computer science department. If none of the candidates is eligible for a position in both departments, how many different sets of 4 candidates are there to fill the 4 positions?
Options:
A)420
B)770
C)840
D)165
E)315
Rationale: 1 of 7 will be chosen for the math
3 of 10 will be chosen for the computer
None of the 4 chosen people can be in more than one departments.
We can choose any of the 7 candidates for the math dep., which gives as 7 selections.
We can choose 3 of the 10 candidates for the computer dep., which gives us 3 selections and 7 rejections.
So, the way to find how many different selections of 2 candidates we can have for the computer dep., we do:
10! /3!*7!= 120
We are multiplying our individual selections: 7*120 = 840
In the bolded part, we don't have to multiply all of the numbers, as those in 8! are included in 10!, so we simplify instead.
Ans C
Answer: C
Question: Jo's collection contains US, Indian and British stamps. If the ratio of US to Indian stamps is 5 to 2 and the ratio of Indian to British stamps is 5 to 1, what is the ratio of US to British stamps?
Options:
A)10 : 5
B)15 : 2
C)20 : 2
D)25 : 2
E)28 : 2
Rationale: Indian stamps are common to both ratios. Multiply both ratios by factors such that the Indian stamps are represented by the same number.
US : Indian = 5 : 2, and Indian : British = 5 : 1. Multiply the first by 5, and the second by 2.
Now US : Indian = 25 : 10, and Indian : British = 10 : 2
Hence the two ratios can be combined and US : British = 25 : 2 Answer: D
Answer: D
Question: . A boy has five trousers and 11 shirts. In how many different ways can he select a trouser and a shirt?
Options:
A)45
B)55
C)65
D)75
E)80
Rationale: Explanation:
The boy can select one trouser in five ways.
The boy can select one shirt in 11 ways.
The number of ways in which he can select one trouser and one shirt is 5 * 11 = 55 ways.
Answer: Option B
Answer: B
Question: Jim is able to sell a hand-carved statue for $540 which was a 35% profit over his cost. How much did the statue originally cost him?
Options:
A)$400.00
B)$412.40
C)$455.40
D)$474.90
E)$488.20
Rationale: 540 = 1.35*X
X = 540/1.35 = 400
$400, which is (A).
Answer: A
Question: What sum of money will produce Rs.70 as simple interest in 4 years at 3 1/2 percent?
Options:
A)988
B)500
C)378
D)373
E)287
Rationale: 70 = (P*4*7/2)/100
P = 500
Answer: B
Answer: B
Question: In a car wheel, ten spokes cover 60 degrees. Then for the entire car,how many spokes are there?
Options:
A)120
B)140
C)240
D)320
E)340
Rationale: given, 10 spokes cover 60degrees,
so for 360 degrees.---->360*10/60=60..
so, for entire car, 4*60=240
ANSWER:C
Answer: C
Question: If y = x^2 + cx + d, y is minimum when x is:
Options:
A)c/d
B)-c/d
C)-c/2
D)-d/2
E)d/c
Rationale: We're given the equation Y = X^2 + cX + d.
IF.. we use a simple Classic Quadratic....
c = 2
d = 1
Y = X^2 + 2X + 1
We can then go about finding the answer that yields the MINIMUM result when X = ...
Answer A: c/d = 2/1 = 2 --> 4+4+1 = +9
Answer B: -c/d = -2/1 = -2 --> 4-4+1 = +1
Answer C: -c/2 = -2/2 = -1 --> 1-2+1 = 0
Answer D: -d/2 = -1/2 -->(1/4)-1+1 = +1/4
Answer E: d/c = 1/2 --> (1/4)+1+1 = +2 1/4
From these results, we can see the minimum result:
C
Answer: C
Question: If two sides of a triangle are 12 and 4, which of the following could be the area of triangle?
1. 35
2. 48
3. 56
Options:
A)a) 1 only
B)b) 1 and 2 only
C)c) 1 and 3 only
D)d) 2 and 3 only
E)e) 1, 2 and 3 only
Rationale: when two sides of a triangle are known , the maximum area occurs when the angle between those two sides is 90.
lets say base = 12 , height =8 (angle = 90)
maximum area = (1/2)*12*8 = 48 ( this is the same maximum area even when base is 8 and height is 12).
if we fix the base and keep lowering the angle, it will result in a lower height . hence the resulting area will always be < 48.
C,D and E are ruled out.
3 and 2 are possible areas as their areas are less than 48.
Hence the answer is D.
Answer: D
Question: How many bricks each measuring 22cm x 10.25cm x 8cm, will be needed to build a wall 9m x 7m x 10.5m
Options:
A)5600
B)3066
C)3055
D)7200
E)None of these
Rationale: Explanation:
no. of bricks= volume of the wall/volume of 1 brick = (900 x 700 x 10.5) / (22 x 10.25 x 8) = 3066
Answer: B
Answer: B
Question: An association of mathematics teachers has 1,500 members. Only 525 of these members cast votes in the election for president of the association. What percent of the total membership voted for the winning candidate if the winning candidate received 36 percent of the votes cast?
Options:
A)7.5%
B)5.8%
C)4.2%
D)34.5%
E)12.6%
Rationale: Total umber of members = 1500
Number of members that cast votes = 525
Since , winning candidate received 36 percent of the votes cast
Number of votes for winning candidate = (36/100)*525 = 189
Percent of total membership that voted for winning candidate = (189/1260)*100 = 12.6%
Answer E
Answer: E
Question: Today is Sunday. After 36 days, what day of the week will it be?
Options:
A)Thursday
B)Monday
C)Tuesday
D)Saturday
E)Sunday
Rationale: Each weekday is repeated every 7 days. 36 divided by 7 is 5 with a remainder of 1. So, after 35 days it will be a Sunday. After 36 days, it will be a Monday. Answer: B
Answer: B
Question: The LCM and HCF of two numbers are 60 and 2 respectively. Find the larger of the two numbers if their sum is 22.
Options:
A)12
B)2
C)4
D)54
E)56
Rationale: There are 2 approaches in solving this.
Methode 1.
HCF * LCM = The Actual Number.
60* 2= 120
So the answer which we are looking for has to be a factor of 120.
So among the options shortlist the answers by eliminating those numbers which is not divisible by 120. and then take the highest number as the answer as the question asks abt the highest number.
answer is A
Answer: A
Question: In Cliff’s impressive rock collection, there are half as many igneous rocks as sedimentary rocks. Of the igneous rocks, 4/5 are shiny and the rest are matte, while 1/5 of the sedimentary rocks are shiny. If there are 40 shiny igneous rocks, how many total rocks does Cliff have?
Options:
A)30
B)150
C)60
D)90
E)135
Rationale: We can start with the known quantity and then go on to find the others.
Shiny igneous ricks are 40. These are (4/5) of total igneous rocks.
(4/5)*Total igneous rocks = 40
Total igneous rocks = 40 * (5/4) = 50
Total sedimentary rocks = 2*Total igneous rocks = 2*50 = 100
Total number of rocks = 50 + 100 = 150
Answer (B)
Answer: B
Question: In a bag there are coins of 50 paisa, 25 paisa and one rupee in the proportion 10:6:5. If there are in all Rs.92, the number of 25 paisa coins is?
Options:
A)26
B)46
C)48
D)42
E)28
Rationale: 10x 6x 5x
50 25 100
500x + 150x + 500x = 9200
1150x = 9200
x = 8 => 6x = 48
Answer: C
Answer: C
Question: The probability that event A occurs is 0.4, and the probability that events A and B both occur is 0.45. If the probability that either event A or event B occurs is 0.6, what is the probability that event B will occur?
Options:
A)0.05
B)0.15
C)0.45
D)0.5
E)0.55
Rationale: P(A or B) = P (A) + P(B) - p(a n b)
0.6= 0.4 + P(B) - 0.45
P(B) = 0.55
Ans : E
Answer: E
Question: 1. Mrs. Ram got a weekly raise of $145. If he gets paid every other week, write an integer describing how the raise will affect her paycheck.
Options:
A)145
B)245
C)100
D)150
E)345
Rationale: Let the 1st paycheck be x (integer).
Mrs. Ram got a weekly raise of $ 145.
So after completing the 1st week he will get $ (x+145).
Similarly after completing the 2nd week she will get $ (x + 145) + $ 145.
= $ (x + 145 + 145)
= $ (x + 290)
So in this way end of every week her salary will increase by $ 145.
Answer :A
Answer: A
Question: Rs.900 amounts to Rs.920 in 3 years at simple interest. If the interest is increased by 3%, it would amount to how much?
Options:
A)Rs.1056
B)Rs.1001
C)Rs.2056
D)Rs.1026
E)Rs.1856
Rationale: (900*3*3)/100 = 81
920 + 81 = 1001
ANSWER:B
Answer: B
Question: If x > y, x < 6, and y > -3, what is the largest prime number that could be equal to x + y?
Options:
A)10
B)11
C)12
D)14
E)16
Rationale: Primes: 2, 3, 5, 7, 11, 13, 17, etc
If X is less than 6 and y is less than X, then 6+6 = 12 would be impossible. We know 13 and all the primes > 13 are out. Let's try 11.
5.9 + 5.1 = 11
5.9 < 6
5.1 < 5.9
everything checks out
Answer 11
ANSWER:B
Answer: B
Question: In a certain game there are 8 steps, referred to as step 1, step 2, and so on with the final step being step 8. The steps are played one after the other. In each step a score of 1, 2, 3, or 4 is obtained. Angel played the game, getting at least one score of each of 1, 2, 3, and 4, and never getting the same score in consecutive steps. What is the greatest possible score that Angel could have gotten?
Options:
A)15
B)18
C)21
D)23
E)29
Rationale: There are two conditions:
1. Angel got at least one score of each of 1, 2, 3, and 4.
2. She never got the same score in consecutive steps.
Taking that into account, the greatest possible score that Angel could have gotten is 4 + 1 + 4 + 2 + 4 + 3 = 18.
Answer: B.
Answer: B
Question: The length of the room is 5.5m and width is 3.75m. Find the cost of paving the floor by slabs at the rate of Rs.800 per sq meter
Options:
A)Rs.16500
B)Rs.15500
C)Rs.17500
D)Rs.18500
E)Rs.19500
Rationale: l=5.5m w=3.75m
area of the floor = 5.5 x 3.75 = 20.625 sq m
cost of paving = 800 x 20.625 = Rs. 16500 Answer: A
Answer: A
Question: Look at this series: 83, 73, 93, 63, __, 93, 43, ... What number should fill the blank?
Options:
A)55
B)59
C)52
D)53
E)51
Rationale: D
53
This is a simple subtraction series in which a random number, 93, is interpolated as every third number. In the subtraction series, 10 is subtracted from each number to arrive at the next.
Answer: D
Question: 81,162,49,98,25,50,62
Options:
A)124
B)127
C)129
D)128
E)131
Rationale: 81*2=162
49*2=98
25*2=50
62*2=124
ANSWER:A
Answer: A
Question: The present ages of three persons are in the proportion of 4 : 7 : 9. Eight years ago, the sum of their ages was 116. Find their present ages.
Options:
A)20,35,45
B)28,49,63
C)16,28,36
D)16,28,46
E)None of these
Rationale: Let the present ages of three persons be 4K,7K and 9K respectively.
(4K - 8) + (7K - 8) + (9K - 8) = 116
20K = 140
K = 7
Therefore, then present ages are 28,49,63.
ANSWER:B
Answer: B
Question: Two teams are distributing information booklets. Team A distributes 60% more boxes of booklets than Team X, but each box of Team A’s has 60% fewer booklets than each box of Team X’s. Which of the following could be the total number of booklets distributed by the two groups?
Options:
A)2,000
B)3,200
C)4,100
D)4,800
E)4,900
Rationale: Let x be the no of booklets in each box that team X distributes. So, Team A has 60% fewer - 0.4x.
Let y be the no. of boxes distributed by team X. So, Team A distributes 60% more - 1.6y
Total booklets distributed by team A = xy
Total booklets distributed by team X=0.64xy
Total booklets distributed = xy+0.64xy=1.64xy
As no. of booklets can only be integer, plugging the answer choice equal to 1.64xy should give an integer.
Choice A - 1.64xy=2000; xy=2000/1.64 = doesn't provide an integer value.
Similarly all answer choices, except choice C, fail to provide an integer value.
Choice C = 4100/1.64= 2500 and is the correct answer.
Answer: C
Question: The mean of set P does not exceed mean of any subset of set P. Which of the following must be true about set P?
I. Set P contains only one element
II. All elements in set P are equal
III. The median of set P equals the mean of set P
Options:
A)of the three qualities is necessary
B)II only
C)III only
D)II and III only
E)I, II, and III
Rationale: The only necessary condition seems to be II.
If all nos are equal.... them mean of any subset is the same.
I is obviously ruled out ( e.g. P = {1,1,1} )
But III, what about 3?
It is not necessary in itself, rather, is automatically implied by II.
All sets that satsify II satisfy III=D
Answer: D
Question: If the sides of a cube are in the ratio 9:7. What is the ratio of their diagonals?
Options:
A)4:3
B)16:9
C)9:7
D)3:4
E)3:8
Rationale: Explanation:
Diagonal of a Cube=a√3 where a is side
a1:a2 = 9:7
d1:d2 = 9:7 where√3 cancelled both side
ANSWER:C
Answer: C
Question: If you roll a fair-sided die twice, what is the probability of getting a (2 ,2)?
Options:
A)1/4!
B)1/3!
C)1/2!
D)1/36
E)1/24
Rationale: total no. in two dice (1,1) ,(2,2) .....(6,)
Total number of events= 6*6
Total events of getting same pair(2, 2) = 6
Probability= 6/6*6= 1/6=1/3!
B
Answer: B
Question: What is the difference between the largest number and the least number written with the digits 7, 3, 1, 4?
Options:
A)6084
B)6184
C)5084
D)6048
E)6049
Rationale: 1347
7431
------------
6084
ANSWER:A
Answer: A
Question: The game of blackjack is played with a deck consisting of 13 cards (one of each of the numbers 2-10, one jack, one queen, one king, and one of ace) in each of four suits: clubs, diamonds, hearts, and spades.
In a game of blackjack, if your first card is a spade, what are the odds that it is a 9?
Options:
A)1/13
B)1/26
C)5/13
D)1/4
E)1/52
Rationale: The question should ask about the probability not the odds.
There are 13 spades, the probability that the spade we already have is 9 is therefore 1/13.
Answer: A.
Answer: A
Question: Each shelf of a bookcase contains 20 books. If the librarian took out 42 books and rearranged the remaining books so that all shelves but the last one contained 16 books and the last shelf contained 22 books, how many shelves does the bookcase have?
Options:
A)A)4
B)B)12
C)C)6
D)D)8
E)E)9
Rationale: Denoting x the number of the shelves,
we can build an equation: 20x=16(x−1)+22+42
Solving the equation, we get x=12
Answer: B
Answer: B
Question: A sum fetched a total simple interest of $4061.25 at the rate of 9 p.c.p.a. in 5 years. What is the sum?
Options:
A)$8829
B)$2840
C)$6578
D)$7782
E)$8926
Rationale: E
8926
Principal
= $100 x 4016.25/9 x 5
= $406125/45
= $8926.
Answer: E
Question: A fair 2 sided coin is flipped 3 times. What is the probability that tails will be the result at least twice, but not more than 3 times?
Options:
A)5/8
B)3/4
C)3/8
D)7/4
E)5/6
Rationale: at least twice, but not more than 3 timesmeans exactly 2 times, 3 times
The probability of getting exactly k results out of n flips is nCk/2^n
3C2/2^3=3/8
Option: C
Answer: C
Question: A library has an average of 510 visitors on Sundays and 240 on other day. The average number of visitors in a month of 30 days starting with sunday is
Options:
A)280
B)285
C)290
D)295
E)275
Rationale: Explanation:
As the month begin with sunday, so there will be five sundays in the month. So result will be:
=(510×5+240×25 / 30)=(8550 / 30)=285
Option B
Answer: B
Question: Jim and Renee will play one game of Rock, Paper, Scissors. In this game, each will select and show a hand sign for one of the three items. Rock beats Scissors, Scissors beat Paper, and Paper beats Rock. Assuming that both Jim and Renee have an equal chance of choosing any one of the hand signs, what is the probability that Jim will win or draw?
Options:
A)5/6
B)2/3
C)1/2
D)5/12
E)1/3
Rationale: There are 3*3=9 combinations (cases) possible. In 3 cases there will be a tie (rock-rock, scissors/scissors, paper/paper). Now, out of 6 cases left Jim and Renee have equal chances of winning, so in 3 cases Jim will win and in other 3 Renee will win. So the probability Jim winning the game is (favorable outcomes)+Drawing the game / (total # of outcomes) = 6/9 = 2/3.
Or: no matter what sign Renee will select Jim can select 1 sign to win, 1 sign to get tie and 1 sign to loose, so the probability Jim winning the game or drawing is 2/3.
Answer: B
Answer: B
Question: If 2 cards are selected (with replacement) at random from the deck of 52 cards then what is the probability that one of the selected cards will be a heart and the other will be a club?
A deck of cards has a total of 52 cards, consisting of 4 suits: spades (black), hearts(red), diamonds (red), and clubs (black). In each suit, there are 13 cards including 1 king, 1 queen, and 1 jack.
Options:
A)1/8
B)1/16
C)1/32
D)1/64
E)1/128
Rationale: P(1 heart and 1 club) = 2(1/4*1/4) = 1/8
The answer is A.
Answer: A
Question: A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?
Options:
A)3.6 sec
B)18 sec
C)36 sec
D)72 sec
E)84 sec
Rationale: Speed of train relative to jogger = (45 - 9) km/hr = 36 km/hr.
= 36 x	5/18	m/sec
= 10 m/sec.
Distance to be covered = (240 + 120) m = 360 m. Answer: Option C
Time taken = 360/10	sec	= 36 sec.
Answer: C
Question: A policeman noticed a criminal from a distance of 180 km. The criminal starts running and the policeman chases him. The criminal and the policeman run at the rate of 8 km and 9 km per hour respectively. What is the distance between them after 3 minutes ?
Options:
A)100 m
B)120 m
C)130 m
D)150 m
E)None of these
Rationale: Explanation :
Solution: Relative speed = (9 - 8) = 1 km/hr.
Distance covered in 3 minutes = (1 * 3/60) km = 1/20 km = 50 m.
.'. Distance between the criminal and policeman = (180 - 50) m = 130 m.
Answer : C
Answer: C
Question: What percent of 500 is 125?
Options:
A)0.25%
B)4%
C)25%
D)40%
E)250%
Rationale: 500*x /100 = 125
x = 125/5
x = 25
Ans: C
Answer: C
Question: Tough and Tricky questions: Word Problems.
Micheal , Saren and Donald decided to club together to buy a present. Each of them gave equal amount of money. Luckily Saren negotiated a 20% discount for the present so that each of them paid 4 dollars less. How much did they pay for a present?
Options:
A)20
B)36
C)48
D)60
E)72
Rationale: Answer C.
We know that Saren negotiated a discount of 20%, so each of them paid $4 less. Since there are three people, the 20% of the original price amounts to $12. 5 times 12$ is 60$, so the original price, before Saren negotiated the discount, had been $60. They paid $12 less than the base price, so they spent $48.
Answer: C
Question: The profit earned by selling an article for Rs. 832 is equal to the loss incurred when the same article is sold for Rs. 448. What should be the sale price for making 80% profit?
Options:
A)1152
B)230
C)960
D)780
E)400
Rationale: C.P. = Rs. x.
Then, 832 - x = x - 448
2x = 1280 => x = 640
Required S.P. = 180% of Rs. 640 = 180/100 * 640 = Rs. 1152.
A
Answer: A
Question: How many meters are there in 550 centimeters?
Options:
A)550 meters
B)5.5 meters
C)100 meters
D)2.5 meters
E)1 meter
Rationale: Solution:
1 meter = 100 centimeters
Just divide 550 by 100
550 Ã· 100 = 5.5, so there are 5.5 meters in 550 centimeters
Option B
Answer: B
Question: The length of a rectangle is 5 more than the width. What are the dimensions of the rectangle if the perimeter is 34?
Options:
A)11
B)12
C)13
D)14
E)None
Rationale: Pretend width = 1, then length = 6 ( 1 + 5)
2 × 1 + 2 × 7 = 2 + 14 = 16. Notice that 16 is far from a perimeter of 34
Try much bigger number.
How about if we...
Pretend width = 4, then length = 9 ( 4 + 5)
2 × 4 + 2 × 9 = 6 + 18 = 24. We are getting closer to a perimeter of 34
Pretend width = 5, then length = 10 ( 5 + 5)
2 × 5 + 2 × 10 = 10 + 30 = 30.
Pretend width = 7, then length = 12 ( 7 + 5)
2 × 7 + 2 × 12 = 14 + 24 = 38. This is higher than a perimeter of 34. So width should be higher than 5 and smaller than 7. May be a width of 6 will work.
Pretend width = 6, then length = 11 ( 6 + 5)
2 × 6 + 2 × 11 = 12 + 22 = 34.
Use of algebra:
Let width = x
Let length = x + 5
P = 2 × L + 2 × W
34 = 2 × ( x + 5) + 2 × x
34 = 2x + 10 + 2x
34 = 4x + 10
34 - 10 = 4x + 10 - 10
24 = 4x
24/4 = 4x/4
6 = x
Therefore, width = 6 and length = x + 5 = 6 + 5 = 11
Answer A
Answer: A
Question: Average families of 4 pay $3000 for their health insurance deductibles annually. There will be a 2/3 increase in the deductibles for next year. How much more will the average family pay in deductibles next year?
Options:
A) $1000
B) $2000
C) $3000
D) $4000
E) $5000
Rationale: A certain percentage of questions in the Quant section of the GMAT are just 'math questions' - you'll use a formula, do some calculations and you'll have the answer. This is one of those types of questions. You still have to write everything down and stay organized, but the work involved is relatively straight-forward.
Here, we're told that the current annual deductible is $3000 and that the deductible is to be increased by 2/3. We're asked how MUCH MORE will the deductible cost a family next year.
Original Deductible = $3000
Increase in Deductible = 2/3
The answer is calculated by the equation:
$3000 × 2/3 = $2000.
B
Answer: B
Question: Scott's average (arithmetic mean) golf score on his first four rounds was 78.What score does he need on his fifth round to drop his average score by 2 points?
Options:
A)68
B)72
C)78
D)88
E)312
Rationale: Average score for first 4 rounds = 78
Average score after 5 rounds = 76
Score Scott needs on his 5th round to drop average score by 2 points = 78 - (2*5) = 68
Answer A
Alternatively , sum of scores of first 4 rounds = 78*4 = 312
Sum of scores after 5 rounds = 76*5 = 380
Score Scott needs on his 5th round to drop average score by 2 points = 380 - 312 = 68
Answer A
Answer: A
Question: Two vertical poles 2 meter and 8 meter high stand apart on a horizontal plane. find the height in meters of the point of intersection of the lines joining the top of each pole to the bottom of the other pole.
Options:
A)1.8
B)1.9
C)1.6
D)1.7
E)56
Rationale: Let A be the point of the top of the 2m pole.
Let B be the point of the foot of the 2m pole.
Let C be the point of the top of the 8m pole.
Let D be the point of the foot of the 8m pole.
Let E be the point of intersection of the line segments AD and BC.
From E drop a perpendicular to the ground.
Let F be the point on the ground where perpendicular from E meets the ground.
Let X be the distance from E to F.
Let P be the distance from B to F.
Let Q be the distance from F to D.
Triangles BEF and BCD are similar so we get Equation 1:
X/P = 8/(P+Q)
Triangles DEF and DAB are similar so we get:
X/Q = 2/(P+Q)
Multiplying both sides by 4 we get Equation 2:
(4X)/Q = 8/(P+Q)
Combining Equations 1 and 2 we get:
X/P = (4X)/Q
Simplifying this we get:
1/P = 4/Q
And then we get:
Q = 4P
Substituting Q=4P into Equation 1 we get:
X/P = 8/(P+4P)
Simplifying this we get:
X/P = 8/(5P)
X = (8P)/(5P)
X = 8/5
X = 1.6
Therefore, the desired height is 1.6 meters.
ANSWER:C
Answer: C
Question: Find the odd man out
25, 49, 81, 121, 144, 169
Options:
A)49
B)121
C)144
D)169
E)25
Rationale: 144 is square of 12 which is even number where as all others are squares of odd numbers.
ANSWER:C
Answer: C
Question: You have a battery that is charged during the day by a solar panel. At night, 3 Iphones use that battery and deplete the charge after 4.8 hours. Your family shows up and they have brought 9 of their own Iphones. How many hours before the charge on the battery is depleted now?
Options:
A)5.3
B)1.2
C)1.8
D)2.2
E)1.5
Rationale: First set up a ratio with all the relevant values and also the unknown variable:
3*4.8 = 12*x
Now solve by multiplying 3 by 4.8 and then dividing that product by 12:
3*4.8 = 14.4
14.4/12 = x
x = 1.2
The value of x equals the number of hours the battery charge will last if 12 Iphones are connected to it.
Answer: B
Answer: B
Question: A part of certain sum of money is invested at 16% per annum and the rest at 20% per annum, if the interest earned in each case for the same period is equal, then ratio of the sums invested is?
Options:
A)4:6
B)4:9
C)4:3
D)4:1
E)5:4
Rationale: 20:16
= 5:4
Answer: E
Answer: E
Question: If 16^y = 4^16, what is y?
Options:
A)2
B)4
C)8
D)12
E)16
Rationale: 16^y = 4^2y = 4^16
2y=16
y = 8
The answer is C.
Answer: C
Question: Two trains of equal are running on parallel lines in the same direction at 48 km/hr and 36 km/hr. The faster train passes the slower train in 36 sec. The length of each train is?
Options:
A)60 m
B)72 m
C)80 m
D)82 m
E)84 m
Rationale: Let the length of each train be x m.
Then, distance covered = 2x m.
Relative speed = 48 - 36 = 12 km/hr.
= 12 * 5/18 = 10/3 m/sec.
2x/36 = 10/3=> x = 60.
ANSWER:A
Answer: A