divelab/Sys2Bench huggingface dataset:
Question: A person borrows Rs.5000 for 2 years at 4% p.a. simple interest. He immediately lends it to another person at 5% p.a for 2 years. Find his gain in the transaction per year.
Options:
A)50
B)150
C)225
D)112.5
E)212.5
Rationale: Explanation :
The person borrows Rs. 5000 for 2 years at 4% p.a. simple interest
Simple interest that he needs to pay = PRT/100=5000×4×2/100=400
He also lends it at 5% p.a for 2 years
Simple interest that he gets = PRT/100=5000×5×2/100=500
His overall gain in 2 years = Rs.500 - Rs.400 = Rs.100
His overall gain in 1 year = 100/2 = Rs.50
Answer : Option A
Answer: A
Question: If x is equal to the sum of the integers from 30 to 50, inclusive, and y is the number of even integers from 30 to 50, inclusive, what is the value of x + y ?
Options:
A)810
B)811
C)830
D)850
E)x + y=851
Rationale: 21 integers from 30 to 50 inclusive
so 11th integer is mean, it is 40
21*40=840
from 21 integers 11 ones is even
840+11=851
ANSWER:E
Answer: E
Question: A chair is bought for Rs.500/- and sold at a loss of 20% find its selling price
Options:
A)Rs.500/-
B)Rs.600/-
C)Rs.400/-
D)Rs.700/-
E)Rs.800/-
Rationale: Loss = 500*20/100 = 100
S.P = C.P - Loss
= 500- 100
=Rs.400/-
Answer :C
Answer: C
Question: In a group of 400 players some are outdoor players, some are indoor players and some plays both. 350 plays outdoors and 110 plays indoor. How many plays indoor as well as outdoor games.
Options:
A)70
B)60
C)90
D)100
E)110
Rationale: Consider total number of players n(O U I) = 400
Players who plays outdoors n(O) = 350
Players who plays indoors n(I) = 110
Players who plays both n(O âˆ© I) = ?
n(O U I) = n(O)+ n(I) - n(O âˆ© I)
400 = 350 + 110 - n(O âˆ© I)
n(O âˆ© I) = 460 - 400
n(O âˆ© I) = 60
SO People read both science fiction and literacy works are 60
ANSWER:B
Answer: B
Question: A man can row a boat at 26 kmph in still water. If the speed of the stream is 6 kmph, what is the time taken to row a distance of 60 km downstream?
Options:
A)30/83 hours
B)80/13 hours
C)15/13 hours
D)16/19 hours
E)15/8 hours
Rationale: Speed downstream = 26 + 6 = 32 kmph.
Time required to cover 60 km downstream
= d/s = 60/32
= 15/8 hours.
Answer:E
Answer: E
Question: Let n~ be defined for all positive integers n as the remainder when (n - 1)! is divided by n.
What is the value of 30~ ?
Options:
A)1
B)0
C)2
D)8
E)31
Rationale: n~ = (n-1)!
so 30~ = (30-1)! = 29!
when 29!/30 we have 16*2 inside 29!
hence 30 gets cancelled and we get remainder as 0
B
Answer: B
Question: If x^2 − 2x − 15 = (x + r)( x + s) for all values of x, and if r and s are constants, then which of the following is a possible value of (r − s)^2?
Options:
A)8
B)2
C)64
D)− 3
E)− 5
Rationale: We know that given ax^2 + bx + c = 0, Sum of the roots = -b/a and product of the roots = c/a.
The roots here are -r and -s.
-r - s = -(-2)/1 = r + s = -2
(-r)*(-s) = -15/1 = rs
So one of r and s is -5 and the other is 3. So
(r - s)^2 could be 64.
Answer (C)
Answer: C
Question: in base 7, a number is written only using digits 0,1,2,3,4,5,6. the number 135 in base 7 is 1*72+3*7+5=75 in base 10. what is the sum of the base 7 numbers 1234 & 6543 in base 7?
Options:
A)11101
B)11110
C)10111
D)11011
E)11010
Rationale: 4+3=7 since base is 7 so it will become 0 giving 1 carry to next digits(so 4+7=0)
3+4 + 1 carry from above step= 1 and 1 carry to next digit
2+5 + 1 carry to next digit= 1 and 1 carry
1+6= 11
so ans=11110
ANSWER:B
Answer: B
Question: Notebooks are sold in packages of four or seven only. If Wilson bought 69 notebooks exactly, what could be the number of large packs Wilson bought?
Options:
A)3
B)4
C)7
D)8
E)9
Rationale: Let number of packs of four = f
let number of packs of seven = s
4f + 7s = 69
Now , we need to test for values of s .
Since sum 69 is odd and 4f will always be even , e can't be even .
Now , we can test for values e = 3 , 7 and 9
4*5 + 7*7 = 20 + 49 = 69
Answer C
Answer: C
Question: A and B start walking towards each other at 6pm at speed of 4kmph and 6kmph. They were initially 18km apart. At what time do they meet?
Options:
A)8pm
B)6pm
C)7pm
D)10pm
E)5pm
Rationale: Time of meeting = distance / relative speed = 18/6+3 = 18/9 = 2 hrs after 6pm = 8pm
Answer is A
Answer: A
Question: Which of the following number is divisible by 4 and 9?
Options:
A)2377
B)2736
C)2876
D)1988
E)1192
Rationale: Explanation:
For a number to be divisible by 4, the number formed by the last two digits of that number must be divisible by 4.
For a number to be divisible by 9, the sum of its digits must be divisible by 9.
Among the choices, choices (a) and (b) are divisible by 4 but of the first two choices, only choice (b) is divisible by 9.
Hence choice (b) is divisible by both 4 and 9.
Answer: B
Answer: B
Question: Find the perimeter and area of a square of side 13 cm.
Options:
A)121
B)144
C)169
D)196
E)225
Rationale: We know that the perimeter of square = 4 Ã— side
Side= 13 cm
Therefore, perimeter = 4 Ã— 13 cm = 52 cm
Now, area of the square = (side Ã— side) sq. units
= 13 Ã— 13 cmÂ²
= 169 cmÂ²
ANSWER : C
Answer: C
Question: Tanks A and B are each in the shape of a right circular cylinder. The interior of tank A has a height of 7 meters and a circumference of 8 meters, and the interior of tank B has a height of 8 meters and a circumference of 10 meters. The capacity of tank A is what percent of the capacity of tank B?
Options:
A)56%
B)80%
C)100%
D)120%
E)125%
Rationale: For A, r=8/2pi. Its capacity = (4pi)^2 * 7= 112pi
For B, r=10/pi. Its capacity = (5pi)^2 *8 = 200pi
A/B = 112pi/200pi = 0.56
A
Answer: A
Question: The sum of first nine prime numbers is?
Options:
A)12
B)100
C)24
D)28
E)30
Rationale: Required sum = (2 + 3 + 5 + 7 + 11 + 13 + 17 + 19 + 23) = 100.
Note: 1 is not a prime number.
Definition: A prime number (or a prime) is a natural number that has exactly two distinct natural number divisors: 1 and itself.
B
Answer: B
Question: In a certain store, the profit is 320% of the cost. If the cost increases by 25% but the selling price remains constant, approximately what percentage of the selling price is the profit?
Options:
A)30%
B)70%
C)100%
D)250%
E)150%
Rationale: Let C.P.= Rs. 100. Then, Profit = Rs. 320, S.P. = Rs. 420.
New C.P. = 125% of Rs. 100 = Rs. 125
New S.P. = Rs. 420.
Profit = Rs. (420 - 125) = Rs. 295.
Required percentage=295/420x100%=1475/21%= 70%
Answer is B.
Answer: B
Question: If 15 percent of the students at a certain school went to a camping trip and took more than $100, and 75 percent of the students who went to the camping trip did not take more than $100, what percentage of the students at the school went to the camping trip?
Options:
A)95
B)90
C)85
D)80
E)60
Rationale: Let x be the number of students in the school. 0.15x students went to the trip and took more than 100$. They compose (100-75)=25% of all students who went to the trip. Therefore the toal of 0.15x/0.25=0.6x students went to the camping which is 60%.
The answer is E
Answer: E
Question: How many words can be formed by using all letters of the word â€œBIHARâ€
Options:
A)320
B)200
C)420
D)120
E)300
Rationale: Sol. The word BIHAR contains 5 different letters.
Required number of words = 5p5 = 5! = (5x4x3x2x1) = 120
ANSWER D
Answer: D
Question: The product of two numbers is 2028 and their H.C.F. is 13. The number of such pairs is:
Options:
A)1
B)2
C)3
D)4
E)5
Rationale: EXPLANATION
Let the numbers 13a and 13b.
Then, 13a x 13b = 2028
ab = 12.
Now, the co-primes with product 12 are (1, 12) and (3, 4).
[Note: Two integers a and b are said to be coprime or relatively prime if they have no common positive factor other than 1 or, equivalently, if their greatest common divisor is 1 ]
So, the required numbers are (13 x 1, 13 x 12) and (13 x 3, 13 x 4).
Clearly, there are 2 such pairs.
Answer B
Answer: B
Question: K is 50% faster than L. If L starts at 9 A.M. and K starts at 10 A.M. L travels at a speed of 50 km/hr. If L and K are 300 kms apart, The time when they meet when they travel in opposite direction is ?
Options:
A)12 pm
B)22 pm
C)72 pm
D)92 pm
E)23 pm
Rationale: Explanation:
let 't' be the time after which they met since L starts.
Given K is 50% faster than L
50 t + 1.5*50(t-1) = 300
50 t +75 t = 300 + 75
t = 375 / 125 = 3 hrs past the time that L starts
So they meet at (9 + 3)hrs = 12:00 noon.
Answer: A
Answer: A
Question: A farmer built a fence around his square plot. He used 27 fence poles on each side of the square. How many poles did he need altogether ?
Options:
A)100
B)104
C)108
D)106
E)None of these
Rationale: Explanation:
Since each pole at the corner of the plot is common to its two sides, so we have :
Total number of poles needed = 27 x 4 - 4 = 108 - 4 = 104.
Answer: B
Answer: B
Question: The ratio of the earnings of P and Q is 9:10. If the earnings of P increases by one-fourth and the earnings of Q decreases by one-fourth, then find the new ratio of their earnings?
Options:
A)4/7
B)3 by 2
C)3/5
D)9/4
E)3/1
Rationale: Let the earnings of P and Q be 9x and 10x respectively.
New ratio = [9x + 1/4 (9x)]/[10x - 1/4 (10x)]
=> 9*(1 + 1/4)/10*(1 - 1/4)
=> 9/10 * (5/4)/(3/4) = 3/2
Answer: B
Answer: B
Question: A man decided to cover a distance of 80km in 8 hrs. He can walk at a speed of 6 km/hr and cycle at 8 km/hr successively. How long will he walk and how long will he cycle ?
Options:
A)26.6km,53.3km
B)27.6km,53.3km
C)26.6km,54.3km
D)26.6km,55.3km
E)28.6km,53.3km
Rationale: as speed in 80km/8hrs=10 km/hr
as ques solve through mixture and alligation method
6 km/hr and 8km/hr
10km/hr
10-8 10-6
2km/hr 4km/hr
so the ratio is 1:2
ahd we have to find the distance through walk and through cycle
1/3*80=26.6km
2/3*80=53.3km
ANSWER:A
Answer: A
Question: A corporation that had $115.19 billion in profits for the year paid out $230.10 million in employee benefits. Approximately what percent of the profits were the employee benefits? (Note: 1 billion = 10^9)
Options:
A)50%
B)20%
C)5%
D)2%
E)0.2%
Rationale: required answer = [employee benefit/profit] *100
=[(230.10 million)/(115.19 billion)]*100
=[(230.10*10^6)/(115.19*10^9)]*100
=(2/1000)*100
=0.2%
So answer is (E)
Answer: E
Question: By selling 20 pens for a rupee a man loses 30%. How many for a rupee should he sell in order to gain 30%?
Options:
A)8.76
B)10.76
C)8.76
D)9.76
E)5.76
Rationale: 70% --- 20130% --- ?70/130 * 20 = 10.76Answer: B
Answer: B
Question: A mixture contains alcohol and water in the ratio 4 : 3. If 5 litres of water is added to the mixture, the ratio becomes 4: 5. Find the quantity of alcohol in the given mixture
Options:
A)15 litres
B)10 litres
C)30 litres
D)22 litres
E)8 litres
Rationale: Let the quantity of alcohol and water be 4x litres and 3x litres respectively
4x/(3x+5)=4/5
20x=4(3x+5)
8x=20
x=2.5
Quantity of alcohol = (4 x 2.5) litres = 10 litres.
Answer is B.
Answer: B
Question: 3,6,9,12,15....
Options:
A)58
B)60
C)18
D)62
E)63
Rationale: 1*3=3
2*3=6
3*3=9
4*3=12
5*3=15
6*3=18
ANSWER:C
Answer: C
Question: A man spend 1/5 of his salary on food , 1/10 of his salary on house rent and 3/5 salary on clothes. he still has $18000 left with him. find salary..
Options:
A)$10800
B)$18000
C)$180000
D)$1800
E)None
Rationale: [1/(x1 / y1 + x2/y2 + x3/y3)] * Total amount= Balance amount
[1-(1/5 + 1/10 + 3/5)} * total salary= $18000, = [1-9/10] * Total salary = $18000, Total salary = $18000*10 = $180000, correct answer (C)
Answer: C
Question: For an agricultural experiment, 300 seeds were planted in one plot and 200 were planted in a second plot. If exactly 25 percent of the seeds in the first plot germinated and exactly 35 percent of the seeds in the second plot germinated, what percent of the total number of seeds germinated?
Options:
A)12%
B)26%
C)29%
D)30%
E)60%
Rationale: In the first plot 25% of 300 seeds germinated, so 0.25 x 300 = 75 seeds germinated.
In the second plot, 35% of 200 seeds germinated, so 0.35 x 200 = 70 seeds germinated.
Since 75 + 70 = 145 seeds germinated out of a total of 300 + 200 = 500 seeds, the percent of seeds that germinated is (145/500) x 100%, or 29%.
Answer: C.
Answer: C
Question: The cost C, in dollars, to remove p percent of a certain pollutant from a pond is estimated by using the formula C = 100,000p/(100 - p). According to this estimate, how much more would it cost to remove 90 percent of the pollutant from the pond than it would cost to remove 50 percent of the pollutant?
Options:
A) $400,000
B) $100,000
C) $50,000
D) $10,000
E) $5,000
Rationale: To remove 90% of pollutant
C= 100,000(90)/(100-90) = 900,000
To remove 50% of pollutant
C' = 100,000(80)/(100-80) = 500,000
Difference = C - C' = 400,000
Answer - A
Answer: A
Question: Which of the following is not a leap year?
Options:
A)700
B)800
C)1000
D)1100
E)1200
Rationale: The century divisible by 400 is a leap year.
The year 700 is not a leap year. ANSWER : A
Answer: A
Question: The average age of 8 men is increased by years when two of them whose ages are 21 years and 23 years are replaced by two new men. The average age of the two new men is
Options:
A)38
B)30
C)39
D)12
E)11
Rationale: Explanation:
Total age increased = (8 * 2) years = 16 years.
Sum of ages of two new men = (21 + 23 + 16) years = 60 years
Average age of two new men = (60/2) years = 30 years.
Answer: B
Answer: B
Question: Working, independently X takes 10 hours to finish a certain work. He works for 9 hours. The rest of the work is finished by Y whose rate is 1/10 th of X. In how much time does Y finish his work?
Options:
A)2hrs
B)4hrs
C)6hrs
D)8hrs
E)10hrs
Rationale: machine X will do 9/10 in 9 hrs, so X does 9/10 of the work ..
Therefore, Y will do the remaining 1/10 th work alone..
As the speed of Y is 1/10 rate of X, Y will do the 1/10 th work in same time that X takes to complete full job...
ans 10
E
Answer: E
Question: The probability that A speaks truth is 3/5 and that of B speaking truth is 4/7. What is the probability that they agree in stating the same fact?
Options:
A)18/35
B)18/22
C)18/29
D)18/12
E)18/33
Rationale: If both agree stating the same fact, either both of them speak truth of both speak false.
Probability = 3/5 * 4/7 + 2/5 * 3/7
= 12/35 + 6/35
= 18/35
Answer:A
Answer: A
Question: The sum of two numbers is 20 and their product is 375. What will be the sum of their reciprocals?
Options:
A)1/40
B)4/75
C)75/4
D)75/8
E)75/6
Rationale: (1/a)+(1/b)=(a+b)/ab=20/375=4/75
ANSWER:B
Answer: B
Question: 31, 29, 24, 22, 17, ?
Options:
A)12
B)14
C)15
D)17
E)20
Rationale: C
15
This is a simple alternating subtraction series, with a pattern -2, -5, -2, -5 ....
Answer: C
Question: A straight fence is to be constructed from posts 5 inches wide and separated by lengths of chain 5 feet long. If a certain fence begins and ends with a post, which of the following couldnotbe the length of the fence in feet? (12 inches = 1 foot)
Options:
A)17
B)28
C)34
D)39
E)50
Rationale: The fence begins and ends with a post: {post = 0.5 feet}{chains = 5 feet}{post = 0.5 feet}...{chains = 5 feet}{post = 0.5 feet}
The minimum length is with 2 posts = 0.5 + 5 + 0.5 = 6 feet. To increase the fence, each time we should add{post = 0.5 feet}{chains = 5 feet}, so 5.5 feet. Thus, the lengths could be:
6 feet;
5 + 5.5 = 10.5 feet;
11.5 + 5.5 = 16 feet;
17 + 5.5 = 21.5 feet;
22.5 + 5.5 = 27 feet;
28 + 5.5 = 32.5 feet;
33.5 + 5.5 = 38 feet.
...
We skipped 34 feet.
Answer: C.
Answer: C
Question: How many arrangements of the letters of the word DEFEATED are there in which the three E are separated?
Options:
A)840
B)750
C)770
D)760
E)820
Rationale: Total arrangements-Three E's together-Exactly Two E's together
Total arrangement= 8!/3!2!
Three E's together= 6!/2!
Exactly Two E's together= Two E's together - Three E's together = 7!/2!−6/!2!=6∗6!/2!
8!/3!2!−6!/2!−6∗6!/2!
8!/3!2!−7!/2!=7!/2!∗13=840
Ans: "840"	A
Answer: A
Question: In the coordinate plane, points (x, 1) and (18, y) are on line k. If line k passes through the origin and has slope 1/2, then x + y =
Options:
A) 4.5
B) 7
C) 8
D) 11
E) 12
Rationale: Line k passes through the origin and has slope 1/2 means that its equation is y=1/2*x.
Thus: (x, 1)=(2, 1) and (18, y) = (18,9) --> x+y=2+9=11.
Answer: D.
Answer: D
Question: David obtained 76, 65, 82, 67 and 85 marks (out in 100) in English, Mathematics, Physics, Chemistry and Biology.What are his average marks?
Options:
A)65
B)69
C)72
D)75
E)79
Rationale: add all those marks and divide it by 5 becz they gave us 5 subjects for finding average marks we need to divide them
add them 76+65+82+67+85/5=375/5=75
ANSWER:D
Answer: D
Question: In how many ways can the letters of the word ABACUS be rearranged such that the vowels always appear together?
Options:
A)6!/2!
B)3!*3!
C)4!/2!
D)4! *3!/2!
E)3!*3!/2
Rationale: In the word ABACUS , there are 3 vowels - 2 A's and U
Number of ways the letters of word ABACUS be rearranged such that the vowels always appear together
= (4! * 3! )/2!
We can consider the the 3 vowels as a single unit and there are 3 ways to arrange them . But since 2 elements of vowel group are identical we divide by 2! .
The entire vowel group is considered as a single group .
Answer D
Answer: D
Question: The average price of 10 oranges is Rs. 12 while the average price of 8 of these oranges is Rs. 11.75. Of the remaining two oranges, if the price of one orange is 50% more than the price of the other, what is the price of each of these two oranges?
Options:
A)Rs 5, Rs 7.50
B)Rs 10.4, Rs 15.6
C)Rs 10, Rs 16
D)Rs 12, Rs 14
E)None of these
Rationale: Explanation :
Total price of the two oranges = Rs. [(12 x 10) (11.75 x 8)]
= Rs. (120 - 94) = Rs. 26.
Let the price of one orange be Rs. x.
Then, the price of other orange = Rs. (x + 50% of x) = Rs. x + 1/2x = Rs. 3x/2
So, x + 3x/2 = 26
5x = 52
x = 10.4
The prices of the two oranges are Rs. 10.4 and Rs. 15.6
Answer : B
Answer: B
Question: 4!/(4-3)!=?
Options:
A)24
B)34
C)35
D)36
E)39
Rationale: 4!/(4-3)!=4!/1!=4*3*2=24. Hence, the correct answer is A.
Answer: A
Question: A chain smoker had spent all the money he had. He had no money to buy his cigarettes. Hence, he resorted to join the stubs and to smoke them. He needed 4 stubs to make a single cigarette. If he got a pack of 10 cigarettes as a gift, then how many cigarettes could he smoke in all?
Options:
A)10
B)11
C)12
D)13
E)14
Rationale: Explanation :
10 cigarettes will produce 10 stubs.
Since, out of 10 cigarettes,
=>8 cigarettes' stubs gives 2 cigarette and, 2 stubs are still left.
=>these 2 gigarette will give 2 stubs.
Now, he will make 1 more cigarette by using 2stubs + 2 stubs.
Hence, total number of cigarettes will be 10 + 2 + 1 i.e 13.
Answer : D
Answer: D
Question: Score Interval Number of Scores
50-59 2
60-69 10
70-79 14
80-89 27
90-99 18
The table shows a distribution of test scores. Which score interval contains the median of the 71 scores?
Options:
A)a) 60-69
B)b) 70-79
C)c) 80-89
D)d) 90-99
E)e) Cannot determine.
Rationale: 36th person
80-89 C
Answer: C
Question: The sector of a circle has radius of 21 cm and central angle 135o. Find its perimeter?
Options:
A)91.5
B)92
C)93
D)94
E)95
Rationale: Perimeter of the sector = length of the arc + 2(radius)
= (135/360 * 2 * 22/7 * 21) + 2(21)
= 49.5 + 42 = 91.5 cm
Answer: Option A
Answer: A
Question: If a truck is traveling at a constant rate of 36 kilometers per hour, how many seconds will it take the truck to travel a distance of 600 meters? (1 kilometer = 1000 meters)
Options:
A)18
B)24
C)60
D)36
E)48
Rationale: Speed =36 Km/hr => 36,000 m/hr
In one minute => 36000/60 = 600 meters
In one sec => 600/60 = 10 meters
Time = Total distance need to be covered / Avg. speed
=> 600/ 10 =60 and hence the Answer : C
Answer: C
Question: A fast food company plans to build 4 new restaurants. If there are 14 sites that satisfy the company's criteria for location of new restaurant, in how many different ways can company select the 4 sites needed for the new restaurant if the order of selection doesn't matter.
Options:
A)1001
B)495
C)364
D)2002
E)756
Rationale: The number of ways of choosing 4 sites out of 14 are counted by = 14C4 ways = 1001
Answer: Option A
Answer: A
Question: Rs.1170 is divided so that 4 times the first share, thrice the 2nd share and twice the third share amount to the same. What is the value of the third share?
Options:
A)229
B)277
C)202
D)540
E)223
Rationale: A+B+C = 1170
4A = 3B = 2C = x
A:B:C = 1/4:1/3:1/2 = 3:4:6
6/13 * 1170 = Rs.540
Answer:D
Answer: D
Question: Vijay bought 160 shirts at the rate of Rs. 225 per shirt. The transport expenditure was Rs. 1400. He paid an octroi at the rate of Rs. 1.75 per shirt and labour charges were Rs. 320. What should be the selling price of one shirt, if he wants a profit of 20%?
Options:
A)338
B)2677
C)288
D)285
E)261
Rationale: Total CP per shirt = 225 + 1400/160 + 1.75 + 320/160 = Rs. 237.5
SP = CP[(100 + profit%)/100]
= 237.5 * [(100 + 20)/100] = Rs. 285.
Answer: D
Answer: D
Question: A man purchases 2 watches for $ 900. He sells one at 10% loss and the other at a profit of 20%. He neither gains nor loses on the whole. Thus, the cost price of two watches are :
Options:
A)$ 900 and $ 300
B)$600 and $ 900
C)$900 and $450
D)$600 and $300
E)$550 and $ 350
Rationale: x + y = 900 --- (1)
0.90x + 0.80y = 900--- (2)
(2) - (1) --> -.10x +.20y = 0
10x = 20y
x/y = 2/1 = (2*300)/(1*300) = 600/300
Answer: D
Answer: D
Question: If a man reduces the selling price of a fan from 400 to 380 his loss increases by 20% .What is the cost price of fan
Options:
A)300
B)400
C)500
D)600
E)700
Rationale: increase in loss=20%
consider loss is x initially, so final loss will increase by .2x which is equal to 20.
.2x=20
x=100,
so total cost =selling price +loss=400+100=500.
so ans is 500.
ANSWER:C
Answer: C
Question: John and Steve are speed walkers in a race. John is 10 meters behind Steve when he begins his final push. John blazes to the finish at a pace of 4.2 m/s, while Steve maintains a blistering 3.7 m/s speed. If John finishes the race 2 meters ahead of Steve, how long was John’s final push?
Options:
A)13 seconds
B)17 seconds
C)24 seconds
D)34 seconds
E)51 seconds
Rationale: Let t be the time that John spent for his final push.
Thus, per the question,
4.2t = 3.7t+10+2 ---> 0.5t = 12 ---> t = 24 seconds.
C is the correct answer.
Answer: C
Question: The length of rectangle is thrice its breadth and its perimeter is 56 m, find the area of the rectangle?
Options:
A)432
B)252
C)299
D)276
E)111
Rationale: 2(3x + x) = 96
l = 36 b = 7
lb = 36 * 7
= 252
B
Answer: B
Question: There are different 5 circles. What is the number of the greatest possible points with which the circles intersect?
Options:
A)20
B)10
C)15
D)22
E)21
Rationale: Maximum points of intersection between n different circles = n*(n - 1) = 5*4 = 20
Answer: A
Answer: A
Question: The speed of a boat in still water is 10 km/hr. If it can travel 78 km downstream and 42 km upstream in the same time, the speed of the stream is
Options:
A)3 km/hr
B)12 km/hr
C)1.5 km/hr
D)4.4 km/hr
E)None of these
Rationale: Explanation :
Let the speed of the stream be x km/hr. Then
Speed upstream = (10-x) km/hr
Speed downstream = (10+x) km/hr
Time taken to travel 78 km downstream = Time taken to travel 42 km upstream
=> 78/(10+x) = 42/(10−x)
=> 26/(10+x) = 14/(10−x)
=>13/(10+x) = 7/(10−x)
=>130 − 13x = 70 + 7x
=>20x = 60
=> x = 3 km/hr
Answer : Option A
Answer: A
Question: Two cylindrical candles of the same height but different diameters are lit at the same time. The
first is consumed in 4 hours and the second in 3 hours. Assuming that they burn at a constant
rate, how long after being lit was the first candle twice the height of the second candle?
Options:
A)1 hr
B)1 hr 12 min
C)2 hr
D)2 hr 12 min
E)2 hr 24 min
Rationale: Assume each candle is 1 unit high. Since the burn rates are 1/3 and 1/4 units
per hour, after t hours they have been consumed by an amount of t/3 and t/4. We want
1- t=4 = 2(1 - t=3). This occurs when t = 2.4 = 2*24/60 hrs.
correct answer E
Answer: E
Question: If m and n are positive integers and m^2 + n^2 = 20, what is the value of m^3 + n^3?
Options:
A)72
B)224
C)320
D)512
E)1,600
Rationale: You need to integers which squared are equal 20.
Which could it be ? Let's start with the first integer:
1^2 = 1
2^2 = 4
3^2 = 9
4^2 = 16
Stop. The integers can't be greater than 4 or we will score above 20.
The second integer need to be picked up the same way.
1^2 = 1
2^2 = 4
3^2 = 9
4^2 = 16
The only pair that matches is 4^2 + 2^2 = 20.
So 4^3 + 2^3 = 72.
Answer A.)
Answer: A