divelab/Sys2Bench huggingface dataset:
Question: Six years ago, the ratio of ages of Kunal and Sagar was 6:5. Four years hence, the ratio of their ages will be 11:10. What is Sagar's age at present?
Options:
A)16 years
B)18 years
C)88 years
D)17 years
E)13 years
Rationale: Let the ages of Kunal and Sagar 6 years ago be 6x and 5x years respectively.
Then, [(6x + 6) + 4] / [(5x + 6) + 4] = 11/10
10(6x + 10) = 11(5x + 10) => x = 2
Sagar's present age = (5x + 6) = 16 years.
Answer: A
Answer: A
Question: In order to obtain an income of Rs. 650 from 10% stock at Rs. 96, one must make an investment of:
Options:
A)Rs. 3100
B)Rs. 6240
C)Rs. 6500
D)Rs. 9600
E)Rs. 10120
Rationale: To obtain Rs. 10, investment = Rs. 96
To obtain Rs. 650, investment = Rs. (96/10 * 650) = Rs. 6240.
Answer = B
Answer: B
Question: If 6th March, 2005 is Monday, what was the day of the week on 6th March, 2004?
Options:
A)Sunday
B)Saturday
C)Tuesday
D)Wednesday
E)Monday
Rationale: The year 2004 is a leap year. So, it has 2 odd days.
But, Feb 2004 not included because we are calculating from March 2004 to March 2005. So it has 1 odd day only.
The day on 6th March, 2005 will be 1 day beyond the day on 6th March, 2004.
Given that, 6th March, 2005 is Monday.
6th March, 2004 is Sunday (1 day before to 6th March, 2005).
Answer A
Answer: A
Question: A pump can be operated both for filling a tank and for emptying it. The capacity of the tank is 2400 m3. The emptying capacity of the pump is 10m3 per minute higher than its filling capacity. Consequently, the pump needs 8 minutes less to empty the tank than to fill it. Find the filling capacity of the pump.
Options:
A)45 m3/min
B)40 m3/min
C)50 cubic metre per minute
D)55 m3/min
E)None of these
Rationale: 2400/x - 2400/x+10=8,solving this we get x,
=50m3/min
Answer: C
Answer: C
Question: There are 624 students in a school. The ratio of boys and girls in this school is 3:5. Find the total of girls & boys are there in this school?
Options:
A)320
B)345
C)375
D)390
E)400
Rationale: In order to obtain a ratio of boys to girls equal to 3:5, the number of boys has to be written as 3 x and the number of girls as 5 x where x is a common factor to the number of girls and the number of boys. The total number of boys and girls is 624. Hence
3x + 5x = 624
Solve for x
8x = 624
x = 78
Number of boys
3x = 3 × 78 = 234
Number of girls
5x = 5 × 78 = 390
D
Answer: D
Question: Ben is driving on the highway at x miles per hour. (One mile equals 5,280 feet.) Ben's tires have a circumference of t feet. Which of the following expressions gives the number of revolutions each wheel turns in one hour?
Options:
A)5,280(x/t)
B)5,280(y/x)
C)5,280(xy)
D)5,280/(xy)
E)(xy)/5,280
Rationale: In one hour, at the rate of x miles per hour, Ben covers x miles, so 5,280x feet.
The number of revolutions = distance/circumference = 5,280x/t.
Answer: A.
Answer: A
Question: The average of seven numbers is 4. The average of first three numbers is 2 and the average of last three numbers is 6. What is the middle number?
Options:
A)3
B)4
C)6
D)7
E)8
Rationale: The total of seven numbers = 7X4 = 28
The total of first 3 and last 3 numbers is = 3 X 2+3 X 6 = 24
So, the middle number is (28 - 24 ) = 4
B
Answer: B
Question: A train running at the speed of 60 km/hr crosses a pole in 9 seconds. Find the length of the train.
Options:
A)150 meter
B)145 meter
C)140 meter
D)135 meter
E)None of these
Rationale: Explanation:
Speed = 60*(5/18) m/sec = 50/3 m/sec
Length of Train(Distance) = Speed * Time
=50/3∗9=150meter
Option A
Answer: A
Question: A researcher computed the mean, the median, and the standard deviation E for a set of performance scores. If 5 were to be added to each score, which of these three statistics would change?
Options:
A)The mean only
B)The median only
C)The standard deviation only
D)The mean and the median
E)The mean and the standard deviation
Rationale: If we add or subtract a constant to each term in a set the standard deviation E will not change..
If we add (or subtract) a constant to each term in a set the mean and the median will increase (decrease) by the value of that constant.
Answer: D.
Answer: D
Question: A basket has 5 apples and 4 oranges. Three fruits are picked at random. The probability that at least 2 apples are picked is ?
Options:
A)25/42
B)25/49
C)25/47
D)25/44
E)25/41
Rationale: Total fruits = 9
Since there must be at least two apples,
= 25/42.
Answer: A
Answer: A
Question: A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Options:
A)299
B)778
C)150
D)888
E)132
Rationale: Speed=(60 * 5/18) m/sec = (50/3) m/sec Length of the train = (Speed x Time) = (50/3 * 9) m
= 150 m.
Answer: D
Answer: D
Question: A trader wants 10% profit on the selling price of a product whereas his expenses amount to 15% on sales. What should his rate of mark up be on an article of Rs. 9?
Options:
A)20%
B)25%
C)30%
D)(100/3) %
E)none
Rationale: Let S.P. = Rs X
Therefore, expenses = 15% of X = 0.15 X
Profit = 10% of X = 0.10X
C.P. = Rs 9 (Given)
Therefore, 9 + 0.15X + 0.1X = X => X = 12
Markup % = 3/9 x 100 = 100/3 %
Therefore, the rate of mark up on the article should be 100/3 %
ANSWER:D
Answer: D
Question: The milk level in a rectangular box measuring 56 feet by 25 feet is to be lowered by 6 inches. How many gallons of milk must be removed? (1 cu ft = 7.5 gallons)
Options:
A)100
B)250
C)750
D)5250
E)5635
Rationale: 6 inches = 1/2 feet (there are 12 inches in a foot.), so 56*25*1/2=700 feet^3 of milk must be removed, which equals to 700*7.5=5250 gallons.
Answer: D.
Answer: D
Question: If the true discount on a sum due 2 years hence at 14% per annum be Rs.168,the sum due is :
Options:
A)Rs. 768
B)Rs. 968
C)Rs. 1960
D)Rs. 2400
E)None
Rationale: Solution
P.W = 100 x T.D/Rx T = 100 x168/14x2= 600.
∴ Sum = (P.W. + TD.) = Rs. 768.
Answer A
Answer: A
Question: The average of numbers 0.64205, 0.64203, 0.64202 and 0.64201 is ?
Options:
A)0.64202
B)0.64204
C)0.642022
D)0.642028
E)None
Rationale: Answer
Average = (0.64205 + 0.64203 + 0.64202 + 0.64201)/ 4
=2.56811/ 4
=0.642028
Correct Option: D
Answer: D
Question: A group of 630 children is arranged in rows for a group photograph session. Each row contains three fewer children than the row in front of it. What number of rows is not possible?
Options:
A)3
B)4
C)5
D)6
E)7
Rationale: Explanation :
Let the last row contain x seats. So, the rows in front have x + 3, x + 6 , x + 9 , …
Total no: of students are 630. So, x + (x + 3) + (x + 6) + (x + 9) + ……… = 630.
There are 2 ways of approaching the problem. You can consider it as an Arithmetic Progression, substitute the options and find the answer, else a simple “less time consuming” way explained. We know that the number of students in each row needs to be a “natural number” and not a decimal, since there cannot be 3.5 or 1.2 or any other decimal number of students/row. We exploit this condition to get the solution quickly.
1st option : 3 rows So, x, x + 3, x+ 6 are the students in 3 rows. Sum = 3x + 9 = 630. We get a natural number as value of x. So it is fine.
2nd option : 4 rows x + (x +3) + (x+6) + (x+9) = 630, x = (630 – 18)/4 = natural number.
3rd option : 5 rows x + (x +3) + (x+6) + (x+9) + (x + 12)= 630 x = (630 – 30)/5, again natural number.
4th option : 6 rows x + (x +3) + (x+6) + (x+9) + (x + 12) + (x+15) = 630
x = (630 – 45)/6 is not a natural number, and is a decimal.
Hence, we cannot have 6 rows.
Answer : D
Answer: D
Question: A is half good a work man as B and together they finish a job in 12 days. In how many days working alone B finish the job?
Options:
A)28 days
B)22 days
C)20 days
D)18 days
E)19 days
Rationale: WC = 1:2
2x + x = 1/12 => x = 1/36
2x = 1/18 => 18 days
ANSWER:D
Answer: D
Question: On a ranch, a rancher can place a loop of rope, called a lasso, once in every 3 throws around a cow’s neck. What is the probability that the rancher will be able to place a lasso around a cow’s neck at least once in 4 attempts?
Options:
A)4/9
B)5/9
C)17/27
D)23/27
E)65/81
Rationale: P(missing all 3)=(2/3)^4=16/81
P(success on at least one attempt)=1-16/81=65/81
The answer is E.
Answer: E
Question: A and B can do a piece of work in 2 days and 6 days respectively. Both work for 1 days and then A goes away. Find how long will B take to complete the remaining work?
Options:
A)1 days
B)2 days
C)3 days
D)4 days
E)5 days
Rationale: 1/2 + (1 + x)/6 = 1
x = 2 days
ANSWER:B
Answer: B
Question: Integers 3n+2 and 8n+7 are divisible by an integer p. If p is not equal to 1, then p equals to?
Options:
A)2
B)3
C)5
D)7
E)11
Rationale: If p divides 3n+2, then p divides 24n+16.
If p divides 8n+7, then p divides 24n+21.
Then p must equal 5.
The answer is C.
Answer: C
Question: For the past n days, the average (arithmetic mean) daily production at a company was 50 units. If today's production of 100 units raises the average to 55 units per day, what is the value of n?
Options:
A)6
B)7
C)8
D)9
E)10
Rationale: The daily production was raised by 5 units for n days, which has a weighting of 5n.
5n = 100-55 = 45
n = 9
The answer is D.
Answer: D
Question: Pipe A, B and C are kept open and together fill a tank in t minutes. Pipe A is kept open throughout, pipe B is kept open for the first 10 minutes and then closed. Two minutes after pipe B is closed, pipe C is opened and is kept open till the tank is full. Each pipe fills an equal share of the tank. Furthermore, it is known that if pipe A and B are kept open continuously, the tank would be filled completely in t minutes. How long will C alone take to fill the tank?
Options:
A)18
B)36
C)27
D)24
E)32
Rationale: A is kept open for all t minutes and fills one-third the tank. Or, A should be able to fill the entire tank in '3t' minutes.
A and B together can fill the tank completely in t minutes. A alone can fill it in 3t minutes.
A and B together can fill 1t of the tank in a minute. A alone can fill 1/t of the tank in a minute. So, in a minute, B can fill 1/t−1/t=2/t. Or, B takes 3/2 minutes to fill an entire tank.
To fill one-third the tank, B will take t/2 minutes. B is kept open for t - 10 minutes.
t/2 = t - 10, t = 20 minutes.
A takes 60 minutes to fill the entire tank, B takes 30 minutes to fill the entire tank. A is kept open for all 20 minutes. B is kept open for 10 minutes.
C, which is kept open for 8 minutes also fills one-third the tank. Or, c alone can fill the tank in 24 minutes. Choice (D)
Answer: D
Question: The compound interest earned by Sunil on a certain amount at the end of two years at the rate of 10% p.a. was Rs.420. Find the total amount that Sunil got back at the end of two years in the form of principal plus interest earned.
Options:
A)Rs.2530
B)Rs.2430
C)Rs.2420
D)Rs.2410
E)Rs.2440
Rationale: Let the sum be Rs.P
P{ [ 1 + 10/100]2 - 1 } = 420
P(10/100)(2 + 10/100) = 420 [a2 - b2 = (a - b) ( a + b)] P = 420 / (0.1)(2.1) = 2000. Amount =2000+420=Rs.2420 Answer : C
Answer: C
Question: The product of n+1 consecutive positive integers is always divisible by
Options:
A)n^2 -1
B)(n+1)!
C)2n +1
D)n^2 + 1
E)n!
Rationale: Plug in some vlues and check -
Product of first 2 number is 2*1
Product of first 3 number is 3*2*1
Product of first 4 number is 4*3*2*1
Product of first 5 number is 5*4*3*2*1
So, The product of first n natural numbers is always divisible by n! , answer will be (B)
Answer: B
Question: x% of y is increased by x%. What is the result in terms of x and y?
Options:
A)100xy + x
B)xy + x/100
C)100xy + x/100
D)100xy + xy/100
E)xy(x + 100)/10000
Rationale: x% of y=xy/100
Increment is x% =xyx/100∗100
Total=xy/100+xyx/100∗100=xy(x+100)/10000
Answer = E
Answer: E
Question: 2 dice are tossed. What is the probability that the total score is a prime no. is?
Options:
A)3/11
B)5/12
C)7/15
D)3/13
E)2/13
Rationale: 5/12
B
Answer: B
Question: If x, y, and z are positive integers and 2x = 3y = 4z, then the least possible value of x + y + z is
Options:
A)40
B)50
C)60
D)70
E)31
Rationale: given 2x=3y=5z
x+y+z in terms of x
= x+(2x/3)+(2x/5) = 31x/15
now checking with each of the answers and see which value gives a minimum integer value.
A x = 15/31*40 , not an integer
B,C,D can be ruled out similarly.
E is minimum value as x = 15*31/31 = 15
Answer is E
Answer: E
Question: Sum of the squares of three numbers is 99 and the sum of their products taken two at a time is 131. Find the sum?
Options:
A)20
B)25
C)19
D)28
E)29
Rationale: (a + b + c)2 = a2 + b2 + c2 + 2(ab +bc + ca) = 99 + 2* 131
a + b + c = √361 = 19
C
Answer: C
Question: If Jake loses 8 pounds, he will weigh twice as much as his sister. Together they now weigh 290 pounds. What is Jake’s present weight, in pounds?
Options:
A)131
B)135
C)169
D)196
E)212
Rationale: Lets say J is the weight of Jack and S is the wt of his sister.
If he loses 8 pounds, he s twice as heavy as his sister.
J-8=2*S
Also, together they weight 290 pounds
J+S=290
solvong the 2 equation ,we get J=196 pounds !
D
Answer: D
Question: REDO’s manufacturing costs for sets of horseshoes include a $10,500 initial outlay, and $15per set. They can sell the sets $40. If profit is revenue from sales minus manufacturing costs, and the company producessells 500 sets of horseshoes, what was their profit?
Options:
A)$2100
B)$2000
C)$2050
D)$2070
E)$2500
Rationale: Total Manufacturing cost = 10500+500*15 = 18000
Total Selling cost = 500*40= 20000
Profit = 20000-18000 = 2000
Answer : B
Answer: B
Question: A rectangular block has the dimensions 5x6x7 cm it is dropped into a cylindrical vessel of radius 6cm and height 10 cm. If the level of the fluid in the cylinder rises by 4 cm, What portion of the block is immersed in the fluid ?
Options:
A)22/7 x 24/35
B)22/7 x 36 x 4
C)22/7 x 36/5
D)22/7 x 37/21
E)22/7 x 32/21
Rationale: Explanation:
Since level of water increased in cylinder by height 4.
This is because of the rectangular block .
Therefore , area of rectangular block immersed in water is = 22/7 x (6)^2 x 4
Thats why portion of block immersed in water is= (22/7 x 36 x 4) / total vol. of rectangle
= (22/7 x 36 x 4)/(7x5x6)
= 22/7 x 24/35.
ANSWER IS A
Answer: A
Question: A train 400 m long can cross an electric pole in 20 sec and then find the speed of the train?
Options:
A)72 Kmph
B)28 Kmph
C)29 Kmph
D)65 Kmph
E)25 Kmph
Rationale: Length = Speed * time
Speed = L/T
S = 400/20
S = 20 M/Sec
Speed= 20*18/5 (To convert M/Sec in to Kmph multiply by 18/5)
Speed = 72 Kmph
Answer:A
Answer: A
Question: The number 95 can be written as the sum of the squares of 4 different positive integers in two ways. Of the following, which can be the sum of these 4 integers
Options:
A)9
B)10
C)15
D)18
E)20
Rationale: The only possible sum for 4 different squares of an integer with total sum number is 95 are :
49 + 36 + 9 + 1 = 95 which are the square from numbers : 7, 6, 3, 1 (total sum number is 20)
or
81 + 9 + 4 + 1 = 95 which are the square from numbers : 9, 3, 2, 1 (total sum number is 15)
hence the answer is (E)
Answer: E
Question: In a mixture 60 liters, the ratio of milk and water 2 : 1. If the this ratio is to be 1 : 2, then the quantity of water to be further added is:
Options:
A)20 liters
B)30 liters
C)40 liters
D)60 liters
E)80 liters
Rationale: Explanation :
Quantity of milk =60 x 2/3	litres = 40 liters.Quantity of water in it = (60- 40) liters = 20 liters.New ratio = 1 : 2Let quantity of water to be added further be x liters.Then, milk : water =	40/(20 + x)Now,	40/(20+x) =1/220 + x = 80x = 60.Quantity of water to be added = 60 liters.
Answer : D
Answer: D
Question: In how many no. between 10 and 30 exactly Two of the digits is 2?
Options:
A)25
B)1
C)35
D)45
E)50
Rationale: It's simple can be solved by elimination of answer choices.
Option A and C are too large, not possible. Even DE are large to have correct choice.
Ans : B
Answer: B
Question: The consumption of diesel per hour of a bus varies directly as square of its speed. When the bus is travelling at 60 kmph its consumption is 1 litre per hour. if each litre costs $30 and other expenses per hous is $ 20, then what would be the minimum expenditure required to cover a distance of 600 Km?
Options:
A)500
B)450
C)600
D)650
E)750
Rationale: 60 kmph consumption is 1 lt/hr
so 600 km will take 10 hrs and the consumption is 10 lt for entire distance.
1 lt costs $30
so 10 lt costs $300
extra expenses for 1 hr - $20
10 hrs - $200
total expense - $300 + $200= $500
Answer : A
Answer: A
Question: A man's regular pay is $3 per hour up to 40 hours. Overtime is twice the payment for regular time. If he was paid $192, how many hours overtime did he work?
Options:
A)8
B)5
C)9
D)6
E)12
Rationale: At $3 per hour up to 40 hours, regular pay = $3 x 40 = $120 If total pay = $168, overtime pay = $192 - $120 = $72 Overtime rate (twice regular) = 2 x $3 = $6 per hour => number of overtime hours = $72/$6 = 12
Ans is E
Answer: E
Question: Peter invests a sum of money and gets back an amount of $ 800 in 3 years . David invests an equal amount of money and gets an amount of $854 in 4 years. If both amounts were invested at the same rate (simple interest ) What was the sum of money invested ?
Options:
A)653
B)664
C)698
D)744
E)700
Rationale: Since both Peter and David invested the same amount of money at the same rate, they would earn same interest per year.
David invested for one year more than Peter and hence he got interest amount for one more year.
Interest earned per year = Amount received by David - Amount received by Peter = 854 - 800 = 54
Interest earned for 3 years = 54*3 = 162
Amount invested = 815 - 162= 653
Answer: A
Answer: A
Question: Ron, Harry and Blake's age is in ratio 2:5:8. Find their ages if the sum of their age is 60 years.
Options:
A)4 , 16 and 40
B)5, 20 and 35
C)8, 20 and 32
D)11, 23 and 27
E)10, 20 and 30
Rationale: Let the age of Ron, Harry and Blake be 2x, 5x and 8x.
2x + 5x + 8x = 60
15x = 60
x = 4
The ages are 8, 20 and 32.
Answer : C
Answer: C
Question: Life expectancy is defined by the formula 2SB/G, where S = shoe size, B = average monthly electric bill in dollars, and G = GMAT score. If Melvin's GMAT score is twice his monthly electric bill, and his life expectancy is 40, what is his shoe size?
Options:
A)25
B)30
C)35
D)40
E)50
Rationale: Solution -
Given that, G = 2B and Life expectancy(L) = 40
L=2SB/G -> 40 = 2SB/2B --> S=40.
ANS D
Answer: D
Question: Brent went on a hike to Leeland Lake. On his way up the trail he travelled at 2 Km/h. On his way down the trail he travelled at twice the speed and therefore his way back took three hours less. What is the distance (in Km) of the trail?
Options:
A)6 Km.
B)8 Km.
C)450.
D)500.
E)600.
Rationale: Distance is same
S1t1=s2t2
40t= 50 (t-1)
t=5
distance= speed *time
40*5= 200
B is the answer
Answer: B
Question: A and B can do a work in 12 days, B and C in 30 days and C and A in 36 days. In how many days will the work be completed, if all three of them work together?
Options:
A)124/13 days.
B)241/13 days.
C)180/13 days.
D)155/13 days.
E)150/13 days.
Rationale: C
180/13 days.
One day work of A and B = 1/12
One day work of B and C = 1/30
One day work of C and A = 1/36
2(A + B + C) = 1/12 + 1/30 + 1/36
2(A + B + C) = 13/90
(A + B + C) = 13/180
Number of days required = 180/13 days.
Answer: C
Question: In a function they are distributing noble prize. In how many ways can 3 prizes be distributed among 4 boys when No boy gets more than one prize?
Options:
A)18
B)20
C)22
D)24
E)27
Rationale: Sol. In this case, repetitions are not allowed. So, the first prize can be given in 4 ways. The second in 3 ways and the third in 2 ways. But fundamental principle, (4 x 3 x 2) ways = 24 ways
4: Or 4p = — 4:- 4X3X2X1- 24 ways
D
Answer: D
Question: Last year Department Store X had a sales total for December that was 5 times the average (arithmetic mean) of the monthly sales totals for January through November. The sales total for December was what fraction of the sales total for the year?
Options:
A)1/4
B)4/15
C)1/3
D)5/16
E)4/5
Rationale: Let avg for 11 mos. = 10
Therefore, Dec = 50
Year total = 11*10 + 50 = 160
Answer = 50/160 = 5/16 = D
Answer: D
Question: In a bouquet of flowers, all but two are roses, all but two are tulips, and all but two are daisies. How many flowers are in the bouquet?
Options:
A)1
B)2
C)3
D)4
E)5
Rationale: C
3
There are 3 flowers (1 rose, 1 tulip, and 1 daisy).
Answer: C
Question: Anthony and Michael sit on the six-member board of directors for company w. If the board is to be split up into 2 three-person subcommittees, what percent of all the possible subcommittees that include Michael also include Anthony?
Options:
A)20%
B)30%
C)40%
D)50%
E)60%
Rationale: Soln: Let the commitees be I and II
Assuming that Anthony and Michael w go into commitee I, there is just one more place left to be filled in that commitee and it can be taken by any of the 4 remaining people. Thus 4 ways.
Since the Anthony and Michael can also go into commitee II, we get 4 ways for that commitee also.
So in total = 8 ways
Now total number of ways of choosing 3 from 6 people is
= 6C3
= 6 * 5 * 4/3!
= 20 ways
Therefore Probability is = (8 /20) * 100 = 40%
Answer: C
Question: Two employees X and Y are paid a total of Rs. 570 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?
Options:
A)s.259
B)s.289
C)s.299
D)s.300
E)s.389
Rationale: Let the amount paid to X per week = x
and the amount paid to Y per week = y
Then x + y = 570
But x = 120% of y = 120y/100 = 12y/10
∴12y/10 + y = 570
⇒ y[12/10 + 1] = 570
⇒ 22y/10 = 570
⇒ 22y = 5700
⇒ y = 5700/22 = Rs.259
A)
Answer: A
Question: a, b, c and d are four consecutive numbers. If the sum of a and dis 109, what is the product of b and c?
Options:
A)2652
B)2578
C)2970
D)3354
E)4234
Rationale: C
2970
Here d = a + 3
a + a + 3 = 109
2a = 106
a = 53
So, numbers are 53, 54, 55 and 56
∴ b × c= 54 × 55 = 2970
Answer: C
Question: 3 persons are standing at the middle of edges of a Triangle.All the 3 persons starts moving at same time with same speed in random direction
What is the probability of meeting atleast 2 persons?
Options:
A)1/4
B)2/4
C)3/4
D)5/4
E)6/4
Rationale: no of times that they dont meet is 2
so they meet in 6 ways
so required probability is=6/8=3/4
ANSWER:C
Answer: C
Question: David obtained 36, 35, 42, 57 and 55 marks (out of 100) in English, Mathematics,Physics, Chemistry and Biology What are his average marks ?
Options:
A)75
B)45
C)87
D)165
E)11
Rationale: Explanation:
Average = (36+ 35+ 42+ 57+ 55 )/ 5 = 225/5 = 45.
Answer:B
Answer: B
Question: Vasya wrote down several consecutive integers. Which of the following could not be the percentage of odd numbers among them
Options:
A) 40
B) 45
C) 48
D) 55
E) 60
Rationale: what you have to check is if the (answer given: 100-answer given) is either equal or two consecutive values..
reason for this is that there are only three possiblities of numbers of odd numbers in consecutive integers
1) equal to number of even numbers
2)one more than number of even numbers
3)one more than number of even numbers
(A) 40:60=2:3possible
(B) 45:55=9:11not possible
(C) 48:52=12:13possible
(D) 50:50=1:1possible
(E) 60:40=3:2possible
ans D
Answer: D