divelab/Sys2Bench huggingface dataset:
Question: Vishal invested 10% more than Trishul. Trishul invested 10% less than Raghu. If the total sum of their investments is Rs. 7225, how much amount did Raghu invest ?
Options:
A)1287
B)2887
C)2500
D)1129
E)1192
Rationale: Let money invested by Raghu = Rs. x
Money invested by Trishul = 9/10 x = 0.9x
Money invested by Vishal = 9/10x * 110/100 = 0.99x
Also, x+0.9x+0.99x = 7225
= x= 7225/2.89 = 2500
Therefore, amount invested by Raghu is Rs. 2500.
Answer: C
Answer: C
Question: In how many ways can the letters of the word RAVED be arranged in a row so that the vowels appear in alphabetic order?
Options:
A)60
B)30
C)90
D)120
E)180
Rationale: Two letters can be arranged in 2! ways.
only one combination EIU is required.
5 letters can be arranged in 5! ways.
thus 5!/ 2! * 1 = 60.
A
Answer: A
Question: If a man lost 4% by selling oranges at the rate of 72 a rupee at how many a rupee must he sell them to gain 44%?
Options:
A)41
B)48
C)49
D)44
E)43
Rationale: 96% ---- 72
144% ---- ?
96/144 * 72 = 48
Answer: B
Answer: B
Question: In a meeting of 3 representatives from each of 5 different companies, each person shook hands with every person not from his or her own company. If the representatives did not shake hands with people from their own company, how many handshakes took place?
Options:
A)125
B)120
C)110
D)90
E)100
Rationale: In fact, all 15 people will shake hands with 12 others.
So, it SEEMS like the TOTAL number of handshakes = (15)(12)
HOWEVER, we need to keep in mind that we have counted each handshake TWICE.
To account for this DUPLICATION, we must divide (15)(12) by 2.
So, the TOTAL # of handshakes = (15)(12)/2 = 90
Answer : D
Answer: D
Question: Twelve men and six women together can complete a piece of work in four days. The work done by a women in one day is half the work done by a man in one day. If 12 men and six women started working and after two days, six men left and six women joined, then in hoe many more days will the work be completed?
Options:
A)1 (1/2) days
B)5 (1/2) days
C)3 (1/2) days
D)7 (1/2) days
E)2 (1/2) days
Rationale: E
2 (1/2) days
Work done by a women in one day = 1/2 (work done by a man/day)
One women's capacity = 1/2(one man's capacity)
One man = 2 women.
12 men = 24 women.
12 men + 6 women = 30 women
30 women can complete the work in four days. In the first 2 days they can complete 1/2 of the work. Remaining part of the work = 1/2. If 6 men leave and 6 new women join, then new work force = 30 women - 12 women + 6 women = 24 women.
Time taken by them to complete the remaining work = 1/2 (Time taken by 24 women to complete the work) = 1/2 * (30 * 4)/24 = 2 (1/2) days.
Answer: E
Question: . A car covers a distance of 1028 km in 4 hours. Find its speed?
Options:
A)104
B)255
C)266
D)257
E)276
Rationale: 1028/4= 257 kmph
Answer: D
Answer: D
Question: At the end of the day, February 14th, a florist had 90 roses left in his shop, all of which were red, white or pink in color and either long or short-stemmed. A third of the roses were short-stemmed, 15 of which were white and 10 of which were pink. The percentage of pink roses that were short-stemmed equaled the percentage of red roses that were short-stemmed. If none of the long-stemmed roses were white, what percentage of the long-stemmed roses were red?
Options:
A)20%
B)75%
C)50%
D)33.3%
E)80%
Rationale: R + W + P = 90
S + L = 90
1/3 * 90 = 30
Short-Stemmed White = 15
Short-Stemmed Pink = 10
=> Short-Stemmed Red = 5
10/P = 5/R
=> R = P/2 , P=2R
So Total Long Stemmed = 60
And Long Stemmed Red + Long Stemmed Pink = 60
So Long Stemmed Red/Long Stemmed = ?
Total White = 15 (As no Long stemmed white)
=> R + 2R + 15 = 90
=> 3R = 75 and R = 25
Long Stemmed R = 25 - 5 = 20
So Long Stemmed Red/R = 20/60 = 33.3%
Answer - D
Answer: D
Question: In a certain game, a player begins with a bag containing tiles numbered 1 through 11, each of which has an equal probability of being selected. The player draws one tile. If the tile is even, the player stops. If not, the player draws another tile without replacing the first. If this second tile is even, the player stops. If not, the player draws a third tile—without replacing either of the first two tiles—and then stops. What is the probability that at the conclusion of the game, the sum of the tiles that the player has drawn is odd?
Options:
A)5/18
B)13/36
C)3/8
D)5/8
E)23/36
Rationale: player begins with containing tiles 1 to 11 and have equal probability of selecting means
Proabability of selecting one number =1/10. here 5 even numbers and 5 odd numbers are there.
Next , player draws one title , if number is even player stops or otherwise title is odd without replacement
player draws second title.
If second title is even , player stops or title is odd without replacement player draws third title.
in third title , without replacement of first and second title, player draws and stops it.
the sum of tilte probability is odd. here two conditions are possible.
1st condition is
1st title is odd+ 2nd title is even stops= probability of selecting one title is 1/10*5c1.
Here are we are not selecting 1st condition as even stops because sum of tile is odd.
Here 5 odd numbers are there we can select 1out of 5 odd numbers.
without replacement of fist we select second tilte is even. is 5/10*5c1/9c1.
here we are selecting one number out of remaining 9 numbers. so probability is 5/18.
we are selecting 1 even number out of 5.
2nd condition is 1stodd without replacement,2nd odd without replacement and 3rd one also odd to get odd as sum of title.
Then probability is 5/10*4/9*3/8=1/12.
Finally sum of probability of two conditions is 5/18+1/12
=23/36.
so option E is correct.
Answer: E
Question: If 0 is the remainder when m is divided by 4, what is the remainder when 6m is divided by 4?
Options:
A)0
B)1
C)2
D)3
E)4
Rationale: For any m that is divisible by 4, any multiple of m (such as 6m) will also be divisible by 4.
m = 4*a
6m = 6*4*a
The answer is, therefore, (A).
Answer: A
Question: Which of the following is a pair of co–primes?
Options:
A)(16, 62)
B)(18, 25)
C)(21, 35)
D)(23, 92)
E)none
Rationale: Solution
H.C.F. of 18 and 25 is 1. So, they are co-primes.
Answer B
Answer: B
Question: Krishan and Nandan jointly started a business. Krishan invested three times as Nandan did and invested his money for double time as compared to Nandan. Nandan earned Rs. 4000. If the gain is proportional to the money invested and the time for which the money is invested then the total gain was?
Options:
A)28,009
B)28,029
C)28,019
D)28,000
E)28,0012
Rationale: 3:1
2:1
------
6:1
1 ----- 4000
7 ----- ? => Rs.28,000
Answer: D
Answer: D
Question: One type of liquid contains 10% of water and the second type of liquid contains 15% of water. A glass is filled with 5 parts of 1st liquid and 2 parts of 2nd liquid. The percentage of water in the new mixture in the glass is?
Options:
A)5.6%
B)11.4%
C)15.6%
D)21.3%
E)18.9%
Rationale: Required percentage = (10% of 5 + 15% of 2)/5+2 *100
= 0.8/7 * 100 = 11.4%
Answer is B
Answer: B
Question: Which of the following numbers is closest to 100 on the number line?
Options:
A)98
B)95
C)103
D)107
E)110
Rationale: We place each of the five answers and 100 on a number line.
Of the five answers given, the two closest numbers to 100 are 98 and 103.
Since 98 is 2 units away from 100 and 103 is 3 units away from 100, then 98 is closest to 100.
Since the smallest positive dierence is 2, then 98 is the closest to 100 on the number line
correct answer A
Answer: A
Question: Three numbers are in the ratio 3:5:7. The largest number is 35. What is the difference between smallest and largest number?
Options:
A)16
B)18
C)20
D)22
E)24
Rationale: The three numbers are 3x, 5x, and 7x.
The largest number is 35 = 7*5, so x = 5.
The smallest number is 3*5 = 15.
35 - 15 = 20
The answer is C.
Answer: C
Question: A bus starts from city X. The number of women in the bus is half of the number of men. In city Y, 8 men leave the bus and four women enter. Now, number of men and women is equal. In the beginning, how many passengers entered the bus ?
Options:
A)15
B)30
C)36
D)45
E)46
Rationale: Explanation:
Originally, let number of women = x. Then, number of men = 2x.
So, in city Y, we have : (2x - 8) = (x + 4) or x = 12.
Therefore Total number of passengers in the beginning = (x + 2x) = 3x = 36.
Answer: C
Answer: C
Question: Find the area of trapezium whose parallel sides are 20 cm and 18 cm long, and the distance between them is 13 cm
Options:
A)178 cm2
B)179 cm2
C)285 cm2
D)247 cm2
E)197 cm2
Rationale: Area of a trapezium = 1/2 (sum of parallel sides) * (perpendicular distance between them)
= 1/2 (20 + 18) * (13)
= 247 cm2
Answer: D
Answer: D
Question: It takes Avery 2.5 hours to build a brick wall while Tom can do it in 4 hours. If the two start working together and after an hour Avery leaves, how much time will it take Tom to complete the wall on his own?
Options:
A)1 hour and 24 minutes.
B)50 minutes.
C)1 hour and 40 minutes.
D)2 hours and 10 minutes
E)1 hour and 20 minutes
Rationale: Avery's efficiency is 100/2.5 = 40%
Tom's = 100/4= 25%
they worked together for 1 hour and finished 65% of the job
remaining = 35 %
Tom will complete 25 % in 60 minutes , and
10% in 60*10/25 minutes = 24 minutes
Time taken by Tom to finish the remaining on his own = 60+24 = 84 minutes
ANSWER:A
Answer: A
Question: The circumference of the front wheel of a cart is 30 ft long and that of the back wheel is 45 ft long. What is the distance traveled by the cart, when the front wheel has done five more revolutions than the rear wheel?
Options:
A)20 ft
B)25 ft
C)450 ft
D)900 ft
E)1000 ft
Rationale: Point to note: Both the wheels would have traveled the same distance.
Now consider, no. of revolutions made by back wheel as x, which implies that the number of revolutions made by the front wheel is (x+5).
Equating the distance traveled by front wheel to back wheel: (x+5)*30 = x * 45. (Formula for calculating the distance traveled by each wheel is: # of revolutions * circumference.)
Solving this eqn. gives x=10.
Sub x=10 either in (x+5)*30 or in x * 45 to get the distance, which is 450. So the correct choice is C.
Answer: C
Question: Gary’s Gas Station serves an average of 12 cars per hour on Saturdays, 10 cars per hour on Sundays, and 9 cars per hour on all other days of the week. If the station is open from 6 a.m. to 10 p.m. every day, how many cars does Gary’s station serve over the course of a typical week?
Options:
A)1,072
B)1,200
C)1,240
D)1,280
E)1,320
Rationale: 6 a.m. to 10 p.m. = 16 hours
Number of cars serviced on weekdays = (16 * 9 * 5)
Number of cars serviced on Saturday = (16 * 12)
Number of cars serviced on Sunday = (16 * 10)
Number of cars served in a week = 16(45 + 12 + 10) = 16 * 67 = 1072
Answer: A
Answer: A
Question: Which of the following could not be the lengths of the sides of a right angled triangle?
Options:
A)3, 4, 5
B)5, 12, 13
C)8, 15, 17
D)12, 15, 18
E)9, 12, 15
Rationale: A. 5^2 = 3^2+ 4^2
B. 13^2 = 12^2+ 5^2
C. 17^2 = 15^2 + 8^2
D. 18^2 not = 12^2 + 15^2
E. 15^2 = 12^21 + 9^2
Hence answer will be (D)
Answer: D
Question: A man can row upstream at 10kmph and downstream at 24 kmph. The speed of the stream is
Options:
A)2.5 km/hr
B)4.2 km/hr
C)7 km/hr
D)10.5 km/hr
E)None
Rationale: Sol.
Speed of stream = 1/2(24 -10) kmph = 7 kmph.
Answer C
Answer: C
Question: A side of beef lost 40 percent of its weight in processing. If the side of beef weighed 240 pounds after processing, how many pounds did it weigh before processing?
Options:
A)191
B)400
C)737
D)840
E)1,560
Rationale: Let weight of side of beef before processing = x
(60/100)*x = 240
=> x = (240 * 100)/60 = 400
Answer B
Answer: B
Question: To save money, Arkadelphia Cream Cheese will reduce each dimension of its rectangular box container (which is entirely full of cream cheese) by 25%, and reduce the price it charges its consumers by 25% as well. By what percentage does this increase the price-per-cubic-inch that each consumer will pay for cream cheese?
Options:
A)1. No change
B)2. 78%
C)3. 100%
D)4. 300%
E)5. 400%
Rationale: Answer is B
Take smart numbers
Let,
L = 20: B = 10: H= 10 of initial box and Price = 100$
Therefore Price / cubic inch = 100 / (20*10*10) =0.05
Now, when dimensions are reduced by 25% and price also reduced by 25%
L = 15; B=7.5; H=7.5 and Price = 75$
Therefore price / cubic inch = 75 / (15*7.5*7.5) =0.089
Percentage change = (0.089 - 0.05) *100/ 0.025 = 78%
Answer: B
Question: A can do a piece of work in 7 days of 9 hours each and B can do it in 6 days of 7 hours each. How long will they take to do it, working together 8 hours a day?
Options:
A)2 days
B)3 days
C)4 days
D)5 days
E)6 days
Rationale: A can complete the work in (7 x 9) = 63 hours.
B can complete the work in (6 x 7) = 42 hours.
A’s 1 hour's work = (1/63) and B's 1 hour's work =(1/42)
(A + B)'s 1 hour's work =(1/63)+(1/42)=(5/126)
Both will finish the work in (126/5) hrs.
Number of days. of (42/5) hrs each =(126 x 5)/(5 x 42)=3 days
ANSWER B 3 days
Answer: B
Question: Can anyhow help me with an easy solution for this
2, 5, 25, 4, 8, 36, 6, 14, ?
Options:
A)121
B)100
C)144
D)169
E)225
Rationale: 2, 5, 25, 4, 8, 36, 6, 14, ?
5-2=3 and 3+2=5 and 5^2=25
8-4=4 and 4+2=6 and 6^2=36
14-6=8 and 8+2=10 and 10^2=100
ANSWER:B
Answer: B
Question: How much 60% of 50 is greater than 40% of 30?
Options:
A)18
B)91
C)11
D)17
E)12
Rationale: (60/100) * 50 – (40/100) * 30
30 - 12 = 18
Answer: A
Answer: A
Question: A cistern has three pipes, A, B and C. The pipes A and B can fill it in 20 and 15 hours respectively and C can empty it in 30 hours. If the pipes are opened in order at 1, 2 and 3 A.M. When will the cistern be empty?
Options:
A)7 AM
B)5 AM
C)6 AM
D)4 AM
E)11 AM
Rationale: 1 to 2 = 1/20
2 to 3 = 1/20 + 1/15 = 7/60
After 3 AM = 1/20 + 1/15 - 1/30= 5/60
1/20 + 7/60 = 1/6
1 h ---- 5/60
? ----- 1/6
2hours ==> 5 AM
Answer:B
Answer: B
Question: Two trains of length 100 m and 200 m are 100 m apart. They start moving towards each other on parallel tracks, at speeds 54 kmph and 72 kmph. In how much time will the trains cross each other?
Options:
A)80/6
B)80/7
C)80/9
D)80/2
E)80/1
Rationale: Relative speed = (54 + 72)* 5/18 = 7 * 5 = 35 mps.
The time required = d/s = (100 + 100 + 200)/35
= 400/35 = 80/7 sec.
Answer:B
Answer: B
Question: At the end of three years what will be the compound interest at the rate of 10% p.a. on an amount of Rs.25000?
Options:
A)8275
B)1879
C)2779
D)2672
E)2782
Rationale: A = 25000(11/10)^3
= 33275
= 25000
----------
8275
Answer: A
Answer: A
Question: If 9 men and 2 boys working together, can do eight times as much work per hour as a man and a boy together. Find the ratio of the work done by a man and that of a boy for a given time?
Options:
A)2:5
B)1:3
C)5:8
D)6:1
E)7:2
Rationale: 9M + 2B =8(1M + 1B)
9M + 2B = 8M + 8B
1M = 6B
The required ratio of work done by a man and a boy =6:1
Answer:D
Answer: D
Question: Stephanie, Regine, and Brian ran a 20 mile race. Stephanie and Regine's combined times exceeded Brian's time by exactly 2 hours. If nobody ran faster than 8 miles per hour, who could have won the race?
I. Stephanie
II. Regine,Brian,Stephanie
III.Regine
Options:
A)I only
B)II only
C)III only
D)I or II only
E)I or III only
Rationale: Given that S+R=B+2, where S, R, and B are times in which Stephanie, Regine, and Brian completed the race.
Min time one could complete the race is 20/8=2.5 hours. Let's see if Brian could have won the race: if he ran at the fastest rate, he would complete the race in 2.5 hours, so combined time needed for Stephanie and Regine would be S+R=B+2=4.5 hours, which is not possible as sum of two must be more than or equal the twice the least time: 2*2.5=5. So Brian could not have won the race.
There is no reason to distinguish Stephanie and Regine so if one could have won the race, another also could. So both could have won the race.
Answer: E.
Answer: E
Question: The banker’s gain on a sum due 3 years hence at 12% per annum is Rs. 270. Then banker’s discount is :
Options:
A)500
B)750
C)890
D)1020
E)None
Rationale: Sol.
T.D. = [B.G. * 100 / R * T] = Rs.[270 * 100 / 12 * 3] = Rs.750.
∴ B.D. = Rs. (750 + 270) = Rs.102
Answer D
Answer: D
Question: Salad dressing P is made up of 30% vinegar and 70% oil, and salad dressing Q contains 10% vinegar and 90% oil. If the two dressings are combined to produce a salad dressing that is 12% vinegar, dressing P comprises what percentage of the new dressing?
Options:
A)50%
B)40%
C)30%
D)20%
E)10%
Rationale: Let x be the percentage of dressing P in the new dressing.
0.3x + 0.1(1-x) = 0.12
0.2x = 0.02
x = 0.1 = 10%
The answer is E.
Answer: E
Question: In an apartment building that has 490 units, 4 out of every 7 units are currently rented, including 1/4 of the one-bedroom units. If, of the rented apartments, there is a 6:1 ratio of two-bedroom units to one-bedroom units, and the building only consists of two-bedroom and one-bedroom units, how many two-bedroom units are not rented?
Options:
A)50
B)90
C)100
D)105
E)140
Rationale: Rented = 4/7*490 = 280.
Rented two-bedroom = 6/7*280 = 240;
Rented one-bedroom = 1/7*280 = 40 (or 280-240=40).
Rented one-bedroom units are 1/4 of all one-bedroom: 1/4*{All one bedroom} = 40 --> {All one-bedroom} = 160
{All two-bedroom} = 490 - 160 = 330
Two-bedroom not rented = 330 - 240 = 90
B
Answer: B
Question: After successive discounts of 20%, 10% and 5% a certain good is sold for Rs. 6840. Find the actual price of the good.
Options:
A)Rs. 6000
B)Rs. 9000
C)Rs. 10800
D)Rs. 10000
E)Rs. 9980
Rationale: Let actual price was 100.
After three successive discount this will become,
100 ==20% discount => 80 ==10% discount => 72 ==5% discount = 68.4
Now Compare,
68.4 = 6840
1 = 6840/68.4
100 = (6840 *100)/68.4 = Rs. 10,000.
Answer: Option D
Answer: D
Question: 7212 + 15.231 - ? = 6879
Options:
A)359.022
B)362.02
C)328.221
D)348.231
E)None of these
Rationale: Explanation :
Required Value = 7212 + 15.231 - 6879 = 348.231. Answer : Option D
Answer: D
Question: ?% of 360 = 151.2
Options:
A)42
B)36
C)64
D)72
E)None of these
Rationale: ?% of 360 = 151.2
or, ? = 151.2×100/360=42
Answer A
Answer: A
Question: Ravi and Kavi start a business by investing â‚¹ 3000 and â‚¹ 72000, respectively. Find the ratio of their profits at the end of year.
Options:
A)2 : 24
B)5 : 24
C)7 : 24
D)1 : 24
E)3 : 24
Rationale: Ratio of profit = Ratio of investments
= 3000 : 72000 = 1 : 24
Answer : D
Answer: D
Question: The average of first five prime numbers greater than 20 is?
Options:
A)32.6
B)32.9
C)32.3
D)32.2
E)32.7
Rationale: 23 + 29 + 31 + 37 + 41 = 161/5 = 32.2
Answer: D
Answer: D
Question: 80 370 860 1550 ? 3530
Options:
A)900
B)2440
C)750
D)244
E)960
Rationale: 10^2 - 20 = 80
20^2 - 30 = 370
30^2 - 40 = 860
40^2 - 50 = 1550
50^2 - 60 = 2440
60^2 - 70 = 3530.
ANSWER:B
Answer: B
Question: Which one of the following is divisible by 9?
Options:
A)23, 50, 821
B)28, 70, 052
C)42, 13, 533
D)64, 000, 80
E)65, 000, 90
Rationale: Explanation:
(a) 2350821 = 2+3+5+0+8+2+1 = 21, not divisible by 9
(b) 2870052 = 2+8+7+5+2 = 24, not divisible by 9.
(c) 4213533 = 4+2+1+3+5+3+3 = 19, not divisible by 9.
(d) 6400080 = 6+4+8 = 18, divisible by 9.
Answer: D
Answer: D
Question: A train is moving at 4/5 of its usual speed. The train is 30 minutes too late. What is the usual time (in hours) for the train to complete the journey?
Options:
A)1
B)1.5
C)2
D)2.5
E)3
Rationale: new time = d / (4v/5) = 5/4 * usual time
30 minutes represents 1/4 of the usual time.
The usual time is 2 hours.
The answer is C.
Answer: C
Question: Three persons invested Rs.9000 in a joint business. The second person invested Rs.1000 more than the first and the third Rs.1000 more than second. After two years, they gained Rs.3600. How much third person will get?
Options:
A)1600
B)2878
C)2699
D)2662
E)1821
Rationale: First persons investment = x
Second persons investment = x + 1000
Third persons investments = x + 2000
x + x + 1000 + x + 2000 = 9000
3x = 6000
x = 2000
Ratio = 2000 : 3000 : 4000
2:3:4
4/9 * 3600 = 1600
Answer: A
Answer: A
Question: Evaluate
6202.5 + 620.25 + 62.025 + 6.2025 + .62025
Options:
A)6791.59775
B)6891.59775
C)6891.59675
D)5891.59775
E)None of these
Rationale: Explanation:
Just we need to take care to put decimal under decimal, rest add in a simple way
Option B
Answer: B
Question: Find the area of a rhombus whose side is 25 cm and one of the diagonals is 33 cm?
Options:
A)276 sq.cm
B)268 sq.cm
C)618 sq.cm
D)660 sq.cm
E)600 sq.cm
Rationale: Consider the rhombus ABCD. Let the diagonals intersect at E. Since diagonals bisect at right angles in a rhombus.
BE2 + AE2 = AB2
252 = 152 + AE2 AE = √(625 - 225)
= √400 = 20,
AC = 20 + 20 = 40 cm.
Area of a rhombus
= 1/2 * d1d2
= 1/2 * 40 * 33
= 660 sq.cm.
Answer:D
Answer: D
Question: The average weight of three boys P, Q and R is 54 kg, while the average weight of three boys Q, S and T is 60 kg. What is the average weight of P, Q, R, S and T?
Options:
A)66.4 kg
B)63.2 kg
C)58.8 kg
D)Data Inadequate
E)None of these
Rationale: Explanation:
Total weight of (P + Q + R) = {54*3} kg = 162 kg
Total weight of(Q + S + T) = (60 *3) kg = 180 kg
Adding both, we get : P + 2Q + S + R + T = (162 + 180) kg = 342 kg
So, to find the average weight of P, Q, R, S & T, we ought to know Q's weight, which is not given.
The data is inadequate
ANSWER: D
Answer: D
Question: In a lottery, there are 10 prizes and 25 blanks. A lottery is drawn at random. What is the probability of getting a prize?
Options:
A)1/10
B)2/5
C)2/7
D)5/7
E)NONE OF THESE
Rationale: P (getting a prize) =	10/(10 + 25)	=	10/35	=	2/7	.
Answer :C
Answer: C
Question: A tree increases annually by 1⁄5 th of its height. If its height today is 50 cm, what will be the height after 2 years?
Options:
A)64 cm
B)84 cm
C)72 cm
D)64 cm
E)74 cm
Rationale: Explanation:
This problem is similar to the problems we saw in compound interest.
We can use the formulas of compound interest here as well.
Rate of increase = 1/5 × 100 = 20%
Height after 2 years = P(1+R/100)T
= 50(1 + 20/100)2 = 50(1 + 1/5)2
= 50(6/5)2 = (50 × 6 × 6)/(5 × 5) = 2 × 6 × 6 = 72 cm
Answer: Option C
Answer: C
Question: When 0.232323..... is converted into a fraction, then the result is
Options:
A)23/99
B)2/9
C)1/5
D)23/100
E)23/98
Rationale: 0.232323... = 0.23
=	23/99
Answer is A.
Answer: A
Question: If the perimeter of a rectangular garden is 1800 m, its length when its breadth is 400 m is?
Options:
A)500
B)600
C)700
D)800
E)900
Rationale: 2(l + 400) = 1800 => l = 500 m Answer: A
Answer: A
Question: If n is the product of integers from 1 to 20 inclusive what is the greatest integer k for which 2^k is a factor of n?
Options:
A)10
B)12
C)15
D)18
E)20
Rationale: Given: n=20!n=20!. The highest power k for which 2^k is a factor of n can be found with the above formula:
k=20/2+20/4+20/8+20/16=10+5+2+1=18
Answer: D.
Answer: D
Question: Tina’s cat weighs 2.6 kilograms. Her dog weighs 5 times as much as her cat. How much does her dog weigh in kilograms?
Options:
A)A)10.4kg
B)B)13kg
C)C)22kg
D)D)48kg
E)E)20kg
Rationale: 2.6*5=13 kg.Answer is B.
Answer: B
Question: For a certain art exhibit, a museum sold admission tickets to a group of 50 people every 5 minutes from 9:00 in the morning to 5:55 in the afternoon, inclusive. The price of a regular admission ticket was $10 and the price of a student ticket was $6. If on one day 3 times as many regular admission tickets were sold as student tickets, what was the total revenue from ticket sales that day?
Options:
A)$24960
B)$25920
C)$28080
D)$38500
E)$48600
Rationale: From 9:00 in the morning to 5:55 in the afternoon, inclusive there are 9*12=108 five-minute intervals, thus total of 108*50 tickets were sold.
Say x student and 3x regular tickets were sold, then x+3x=108*50 --> x=27*50 and 3x=3*(27*50)=27*150.
Therefore, the total revenue from ticket sales that day was 27*50*6+27*150*10=$48,600.
Answer: E.
Answer: E
Question: Evaluate combination
100C100
Options:
A)10000
B)1000
C)10
D)1
E)0
Rationale: Explanation:
nCn=1
100C100=1
Option D
Answer: D
Question: Jerry’s average (arithmetic mean) score on the first 3 of 4 tests is 85. If Jerry wants to raise his average by 2 points, what score must he earn on the fourth test?
Options:
A)87
B)89
C)90
D)93
E)95
Rationale: Total score on 3 tests = 85*3 = 255
Jerry wants the average to be = 87
Hence total score on 4 tests should be = 87*4 = 348
Score required on the fourth test = 348 - 255 = 93
Option D
Answer: D