divelab/Sys2Bench huggingface dataset:
Question: In a certain town, the ratio of NY Yankees fans to NY Mets fans is 2:1, and the ratio of NY Mets fans to Boston Red Sox fans is 3:7. If there are 352 baseball fans in the town, each of whom is a fan of exactly one of those three teams, how many NY Mets fans are there in this town?
Options:
A)58
B)66
C)74
D)82
E)90
Rationale: The ratio of Yankees:Mets:Red Sox = 6:3:7
The Mets fans are 3/16 of the population.
(3/16)*352 = 66
The answer is B.
Answer: B
Question: Look at this series: 15, 15, 27, 27, ?, 39 What number should fill the blank?
Options:
A)51
B)39
C)23
D)15
E)None
Rationale: Explanation: In this simple addition with repetition series, each number in the series repeats itself, and then increases by 12 to arrive at the next number.
Answer: Option B
Answer: B
Question: Harriet, Isabella and Karen are business partners. Harriet invested Rs.13000. If her share of a profit of Rs.3000 is Rs.1100 and Karen's share is Rs.1000, what is Isabella's capital?
Options:
A)8676.67
B)8666.67
C)896.67
D)8566.67
E)8662.67
Rationale: 1200 + 1000 = 2200
3000 - 2200 = 800
1200 ---- 13000
800 ---- ? => 8666.67
ANSWER:B
Answer: B
Question: Given the following equation 30% of 3485 + 20% of 6218 = ?, Find the approximate value should come in place of the question mark (?).
Options:
A)2290
B)2280
C)2260
D)2240
E)2220
Rationale: ? = 30% of 3485 + 20% of 6218
? = 30/100*3485 + 20/100* 6218
? = 2289.1
≈ 2290
Answer A
Answer: A
Question: Meena bought a watch with 25% discount on the selling price. If the watch cost her Rs.1545. What is the original selling price of the watch?
Options:
A)Rs.2050
B)Rs.2040
C)Rs.2030
D)Rs.2060
E)None of these
Rationale: Explanation:
CP of Meenal is 75% of the Original SP.
:. Original SP = 1545x100/75 = Rs.2060.
Answer: Option D
Answer: D
Question: Rob also compared the Empire State Building and the Petronas
Towers. What is the height difference between the two if the Empire
State Building is 435m tall and the Petronas Towers is 458m tall?
Options:
A)9
B)17
C)23
D)45
E)12
Rationale: 458-435=23.Answer is C.
Answer: C
Question: What approximate value should come in place of the question mark (?) in the following equation ?
3⁄7 of 1596 + 3015 = ? – 2150
Options:
A)7200
B)48000
C)5830
D)58000
E)6300
Rationale: ? ≈ 3 × 230 + 3000 + 2150
= 680 + 3000 + 2150 = 5830
Answer C
Answer: C
Question: Due to reduction of 25/4% in the price of sugar , a man is able to buy 1kg more for Rs.120. Find the original and reduced rate of sugar.
Options:
A)Rs.7.50 per kg
B)Rs.2.50 per kg
C)Rs.5 per kg
D)Rs.6.25 per kg
E)Rs.10 per kg
Rationale: Let the original rate be Rs.x per kg.
Reduced rate = Rs.[(100-(25/4))*(1/100)*x}]=Rs.15x/16per kg
120/(15x/16)-(120/x)=1
(128/x)-(120/x)=1
x=8.
So, the original rate = Rs.8 per kg
Reduce rate = Rs.[(15/16)*8]per kg = Rs.7.50 per kg
Answer is A.
Answer: A
Question: Two pipes A and B can separately fill a cistern in 60 min and 75 min respectively. There is a third pipe in the bottom of the cistern to empty it. If all the three pipes are simultaneously opened, then the cistern is full in 50 min. In how much time, the third pipe alone can empty the cistern?
Options:
A)277
B)100
C)247
D)288
E)261
Rationale: Work done by the third pipe in 1 min = 1/50 - (1/60 + 1/75) = - 1/100.
[-ve sign means emptying]
The third pipe alone can empty the cistern in 100 min.
Answer: B
Answer: B
Question: After allowing a discount of 15% on the marked price, the selling price is Rs. 6800 for an article. If it was sold at marked price, there would have been a profit of 60%. The cost price of the article is?
Options:
A)50299
B)50289
C)5000
D)17728
E)50189
Rationale: Given SP = Rs. 6800
Marked price = [SP(100)]/(100 - d%) = (6800 * 100)/(100 - 15) = Rs. 8000
If SP = Rs. 8000, profit = 60%
CP = [SP(100)]/(100 + 60) = (8000 * 100)/160 = Rs. 5000
Answer: C
Answer: C
Question: Solve x2 – 3x – 4 = 0.
Options:
A)1,4
B)-1,4
C)2,3
D)2,-3
E)3,4
Rationale: This one factors easily:
x2 – 3x – 4 = 0
(x + 1)(x – 4) = 0
x + 1 = 0 or x – 4 = 0
x = –1 or x = 4
The solution is x = –1, 4
ANSWER B -1,4
Answer: B
Question: There are two positive numbers in the ratio 5:8. If the larger number exceeds the smaller by 36, then find the smaller number?
Options:
A)25
B)66
C)77
D)60
E)44
Rationale: Let the two positive numbers be 5x and 8x respectively.
8x - 5x = 36
3x = 36 => x = 12
=> Smaller number = 5x = 60.
Answer: D
Answer: D
Question: The larger of two negative consecutive odd integers 5t and 5(t-1) is multiplied by 3 and then added to the smaller of the two original integers. Which of the following represents this operation?
Options:
A)6t-2
B)8t-2
C)-2
D)20t-5
E)-2-4t^2
Rationale: larger of 5t-5, 5t (when they are negative) is 5t. the smallest of 5t and 5t-5 when they are positive is 5t-5.
therefore 3* 5t + 5t-5 = 20t-5.
option D.
Answer: D
Question: There are 1000 students in a school and among them 25 % of them attends chess class. 50% of the students who are in the chess class are also enrolled for swimming. No other students are interested in swimming so how many will attend the swimming class if all enrolled attends?
Options:
A)1
B)10
C)125
D)50
E)20
Rationale: 25% of 1000 gives 250. so 250 attends chess and 50% of 250 gives 125
so 125 enrolled for swimming
Answer: C
Answer: C
Question: Out of 10 persons working on a project, 4 are graduates. If 3 are selected, what is the probability that there is at least one graduate among them?
Options:
A)5/8
B)5/4
C)5/2
D)5/6
E)5/1
Rationale: P(at least one graduate) = 1 - P(no graduates)
1 = 1 - (6 * 5 * 4)/(10 * 9 * 8) = 5/6.Answer: D
Answer: D
Question: In how many different number of ways 3 boys and 4 girls can sit on a bench?
Options:
A)5700
B)5710
C)5040
D)8000
E)5820
Rationale: npn = n!
7p7 = 7 X 6 × 5 × 4 × 3 × 2 × 1 = 5040
C)
Answer: C
Question: The mean of 50 observations was 40. It was found later that an observation 45 was wrongly taken as15 The corrected new mean is
Options:
A)40
B)36.5
C)46.5
D)20.5
E)40.6
Rationale: Explanation:
Correct Sum = (40 * 50 + 45 - 15) = 2030
Correct mean = = 2030/50 = 40.6
Answer: E
Answer: E
Question: A and B joined a partnership business. In which A invested rs. 10,000 for 6 months and B invested Rs. 6000 for 8 months. If they earn a profit of Rs. 3000. find A's share in the profit.
Options:
A)rs 2500
B)rs 1500
C)rs 1000
D)rs 1667
E)rs 1567
Rationale: 10,000*6==60000
6000*8== 48000
60000:48000=15:12
a=15, b==12
sp A share= 15*3000/15+12==1667
ANSWER:D
Answer: D
Question: If the reciprocals of two consecutive positive integers are added together, what is the sum in terms of the greater integer b?
Options:
A)b^2- b
B)2b-1
C)(2b-1)/(b^2- b)
D)2b-3
E)2b-5
Rationale: Let two consecutive positive integers be b and b-1 (Greater integer is b)
So,
(1/b) + [1/(b-1)]
= (2b-1)/b(b-1)
=(2b-1)/(b^2- b)
Answer : C
Answer: C
Question: (10+0.0001)/(0.04+1)
The value of the expression above is closet to which of the following?
Options:
A)0.0001
B)0.001
C)0.1
D)1
E)10
Rationale: Notice that we need approximate value of the fraction.
Now, the nominator is very close to 10 and the denominator is very close to 1, hence the value of the fraction is very close to 10/1=10
Answer: E.
Answer: E
Question: The squared value of the diagonal of a rectangle is (64 + B2) sq cm, where B is less than 8 cm. What is the breadth of that rectangle?
Options:
A)6 cm
B)10 cm
C)8 cm
D)Data inadequate
E)None of these
Rationale: Diagonal2 = 64 + B2 or, 10(2) = 64 + 6(2)
Answer A
Answer: A
Question: What is the least common multiple of 5,40,36,50
Options:
A)3698
B)874
C)3692
D)1800
E)3214
Rationale: The given numbers are 5,40,36,50
thus the l.c.m is 5*2*2*1*2*9*5=1800
the answer is D
Answer: D
Question: The average weight of 20 persons sitting in a boat had some value. A new person added to them whose weight was 50 kg only. Due to his arrival, the average weight of all the persons decreased by 5 kg. Find the average weight of first 20 persons?
Options:
A)55
B)56
C)57
D)58
E)59
Rationale: 20x + 50 = 21(x – 5)
X=55
ANSWER:A
Answer: A
Question: A person walking at 4 Kmph reaches his office 6 minutes late. If he walks at 6 Kmph, he reaches there 8 minutes earlier. How far is the office from his house?
Options:
A)4 1/5 Km
B)4 1/7 Km
C)3 1/5 Km
D)3 1/7 Km
E)2 4/5 Km
Rationale: Formula = S1*S2/S2-S1 * T1+T2/60
= 4*6/2 * 14/6
= 24/2 * 14/60
= 7 * 2/5
= 14/5 = 2 4/5 Km
E)
Answer: E
Question: Jessica can text 95 words per minute, while Maurice can text 10 words per minute. An abridged English translation of Tolstoy’s War and Peace contains 410,400 words. Working together, how many days will it take Jessica and Maurice to text the entire abridged translation of War and Peace?
Options:
A)2.7
B)1.3
C)3
D)9
E)11.3
Rationale: Since the answer choices are reasonably spaced out, we can approximate and save time
Combined words per day = 105*60*24 which should be something close to 151200
410400/151200 will be closest to only 2.7,
So, Answer should be A
Answer: A
Question: What is the least number to be added to 661 to make it a perfect square?
Options:
A)13
B)15
C)20
D)16
E)45
Rationale: The numbers greater than 661 and are square of number is 676.
The least number that should be added 661 to make it perfect square = 676 - 661 = 15.
ANSWER:B
Answer: B
Question: A person travels from P to Q at a speed of 40 km/hr and returns by increasing his speed by 50%. What is his average speed for both the trips ?
Options:
A)43
B)25
C)48
D)50
E)62
Rationale: Speed = 40 km/hr
Return= 150% of 40 = 60 km/hr
avg = 2xy/x+y
=2*40*60/40+60 = 4800/100
== 48 km/hr
ANSWER C
Answer: C
Question: If a farmer sells 10 of his chickens, his stock of feed will last for 4 more days than planned, but if he buys 15 more chickens, he will run out of feed 3 days earlier than planned. If no chickens are sold or bought, the farmer will be exactly on schedule. How many chickens does the farmer have?
Options:
A)12
B)24
C)48
D)35
E)60
Rationale: Say farmer has n chicken and he is good for d days.:-
We have 3 equations given in question:-
(n-10) * d+4 =(n+15) *(d-3) = n * d
Solving these: (You can solve 1st and 3rd and 2nd and 3rd together)
We get:
15d-3n=45
4n-10d =40
=> n=35
Ans D it is!
Answer: D
Question: A certain collage has total of 400 seniors each majoring in exactly one of six subjects. A minimum of 25 seniors major in each six subjects. If three quarter of the seniors major in one of four subjects, what is the greatest possible number of seniors majoring in one of the other two subjects?
Options:
A)100
B)80
C)75
D)60
E)50
Rationale: Answer is B.
Six majors are as follows: a + b + c + d + e + f
Each has at least 20 seniors: 25 + 25 + 25 + 25 + 25 + 25
4 of the majors have 300 seniors: a + b + c +d = 300
There are a total of 400 seniors.
So e + f = 100. One of the subjects has to be 25 for the other to be maximized. If e = 25, then f = 75
C.
Answer: C
Question: Jack, Jill, and Sandy each have one try to make a basket from half court. If their individual probabilities of making the basket are 1/6, 1/7, and 1/8 respectively, what is the probability that Jack and Sandy will make a basket but Jill will miss?
Options:
A)1/8
B)3/8
C)3/28
D)5/28
E)1/56
Rationale: The probability that Jack and Sandy will make a basket but Jill will miss is 1/6*6/7*1/8=1/56.
The answer is E.
Answer: E
Question: Tammy climbed a mountain in two days. She spent a total of 14 hours climbing the mountain. On the second day, she walked at an average speed that was half a kilometer per hour faster, but 2 hours less than what she walked on the first day. If the total distance she climbed during the two days is 52 kilometers, how many E kilometers per hour did Tammy walk on the second day?
Options:
A)3
B)3.5
C)4
D)4.5
E)6
Rationale: Ans: C
Total time = 14 hrs
Let time traveled during 1st day = x
Let time traveled during 2nd day = x-2
Total time =14
x+x-2 = 14
x=8
speed * time = distance
s*8 + (s+0.5)(8-2) = 52
solving s = 4.5
now speed for 2nd day is 0.5 less than the 1st day which is 4.5
Thus speed for 2nd day = 4
Its simple algebra for s*8 + (s+0.5)(8-2) = 52 but for some reason Im getting 3.5 and not 4.5.
8s+6s+3=52
14s=49
s=3.5
Answer: C
Question: Running at the same constant rate, 16 identical machines can produce a total of 32 shirt per minute. At this rate, how many shirt could 8 such machines produce in 10 minutes?
Options:
A) 911
B) 100
C) 101
D) 160
E) 785
Rationale: Let's take the approach that uses the answer choices to eliminate wasted time.
32/16 = 2 shirt per minute per machine. 8 machines = 16 per minute. 10 minutes worth = 160 shirt.
Looking at the answers it is clear...we can only choose (D)
THE CORRECT ANSWER IS D.
Answer: D
Question: A began business with 10000 and is joined afterwards by B with 20000. When did B join, if the profits at the end of the year are divided equally?
Options:
A)8 months
B)9 months
C)6 months
D)7 months
E)None of these
Rationale: Let B join after x months of the start of the business so that B’s money is invested for (12 – x) months.
∴ Profit ratio is 12 × 10000 : (12 – x) × 20000
or 12 : 2(12 – x)
Since profit is equally divided so
12 = 2(12 – x) or x = 6. Thus B joined after 8 months.
Answer C
Answer: C
Question: There are 40 doors marked with numbers 1 to 40. There are 40 individuals marked 1 to 40.
An operation on a door is defined as changing the status of the door from open to closed or vice versa. All the doors are closed to start with. One at a time, one randomly chosen individual goes and operates the doors. The individual however operates only those doors which are a multiple of the number he/she is carrying. For example, the individual marked with number 5 operates the doors marked with 5, 10, 15, 20, 25, 30, 35, and 40. If every individual in the group gets one turn, then how many doors are open at the end?
Options:
A)3
B)4
C)5
D)6
E)7
Rationale: If a door is closed at the start, it requires an odd number of people to operate to be open at the end. Only the perfect squares have an odd number of factors.
The doors which are open at the end are: 1, 4, 9, 16, 25, 36 for a total of 6 doors.
The answer is D.
Answer: D
Question: A box contains nine bulbs out of which 4 are defective. If four bulbs are chosen at random, find the probability that exactly three bulbs are good?
Options:
A)20/65
B)20/63
C)20/45
D)20/29
E)20/20
Rationale: Required probability = (5C3 . 4C1)/9C4
= (10 * 4)/126
= 20/63
Answer:B
Answer: B
Question: If q is a positive integer and q^2 is divisible by 12, then the largest positive integer that must divide q ^3 is
Options:
A) 2^3
B) 2^6
C) 3^3
D) 6^3
E) 12^2
Rationale: Since q is an integer so q cannot have a 2 and sqrt 3 (because squaring this will give us a 2^2 and 3 (making the product as 12, and making q^2 as a multiple of 12))
q^2 is divisible by 12 (12 = 2*2*3), So, q should have at least one 2 and one 3 so that q^2 has a 2^2 and two 3
So, q will have a 2 and a 3. Or q will be a multiple of 6
So, largest possible integer than should divide q^3 is 6^3
So, Answer will be D
Answer: D
Question: A farmer spent $34 on feed for chickens and goats. He spent 40% money on chicken feed, which he bought at a 20% discount off the full price, and spent the rest on goat feed, which he bought at full price. If the farmer had paid full price for both the chicken feed and the goat feed, what amount would he have spent on the chicken feed and goat feed combined?
Options:
A)$37.40
B)$38.50
C)$39.20
D)$39.50
E)$40.60
Rationale: A farmer spent 40% money on chicken feed, so he spent 0.4*$34=$13.6 on chicken feed, thus he spent the remaining 34-13.6=$20.4 on goat feed.
Now, since he bought chicken feed at a 20% discount then the original price of it was x*0.8=$13.6 --> x=$17.
Therefore if the farmer had paid full price for both the chicken feed and the goat feed, then he would he have spent 17+20.4=$37.4.
Answer:A.
Answer: A
Question: If 2^z is a factor of 23!, which of the following could be the value of z?
I. 22
II. 23
III. 24
Options:
A)I ​only
B)II only
C)I​ and II
D)I, II, and III
E)None
Rationale: 23! contains all numbers from 1 to 23. To find the factor with the highest power of 2, we count the number of multiples of 2, 4, 8 and 16.
Multiples of 2 = 11
Multiples of 4 = 5
Multiples of 8 = 2
Multiples of 16 = 1
Total count = 19
The answer is E.
Answer: E
Question: A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Options:
A)150 m
B)200 m
C)240 m
D)400 m
E)150 m
Rationale: Answer: Option C
Speed = [54 * 5/18] m/sec = 15 m/sec.
Length of the train = (15 * 20) m = 300 m.
Let the length of the platform be x meters.
Then, x + 300 / 36 = 15
x + 300 = 540
x = 240 m.
Answer: C
Question: A man can row his boat with the stream at 6 km/h and against the stream in 4 km/h. The man's rate is?
Options:
A)1 kmph.
B)2 kmph.
C)3 kmph.
D)4 kmph.
E)5 kmph.
Rationale: DS = 6
US = 4
S = ?
S = (6 - 4)/2 = 1 kmph
Answer: A
Answer: A
Question: The sale price at which a store sells an article is 25% more than its cost price. If the sale price is an integer, which of the following cannot be the cost price?
Options:
A)$23
B)$28
C)$36
D)$44
E)$72
Rationale: Sale Price = (5/4)*(Cost Price)
If the sale price is an integer, then the cost price must be divisible by 4.
The answer is A.
Answer: A
Question: From a vessel on the first day, 1/3rd of the liquid evaporates. On the second day 3/4th of the remaining liquid evaporates. what fraction of the volume is present at the end of the 2 day
Options:
A)1/3
B)1/4
C)1/5
D)1/6
E)1/7
Rationale: let x be the volume...
after 1st day volume remaining=(x-x/3)=2x/3
after 2st day volume remaining=(2x/3)-((2x/3)*(3/4))
=(2x/3)(1-3/4)=(2x/3)*(1/4)=x/6
ANSWER:D
Answer: D
Question: Four barrels of water have an average capacity of 8 gallons. What is the maximum possible capacity of the smallest barrel W if the median is 10 gallons?
Options:
A)1
B)2
C)3
D)4
E)5
Rationale: Suppose 4 barrels are B1, B2, B3, B4 in ascending capacity.
(B1+B2+B3+B4)/4 = 8
B1+B2+B3+B4=32
median is 10 ....... as the no. of terms are even i.e 4, median = (B2+B3)/2
==> B2+B3 = 20
now we have B1+B4 = 32-20 =12
Only the following possible cases can be there :
1,9,11,11
1,10,10,11
2,10,10,10
Max value of smallest barrel W= 2
Answer: B
Question: A sum of money at simple interest amounts to Rs. 800 in 3 years and to Rs. 854 in 4 years. The sum is:
Options:
A)Rs. 438.
B)Rs. 488.
C)Rs. 518.
D)Rs. 638.
E)Rs. 664.
Rationale: S.I. for 1 year = Rs. (854 - 800) = Rs. 54
S.I. for 3 years = Rs.(54 x 3) = Rs. 162.
Principal = Rs. (800 - 162) = Rs. 638.
ANSWER : D
Answer: D
Question: Of the 14 temporary employees in a certain company, 4 will be hired as permanent employees. If 5 of the 12 temporary employees are women, how many of the possible groups of 4 employees consist of 3 women and one man?
Options:
A)22
B)35
C)56
D)70
E)90
Rationale: another approach :
one scenario : [WWWM]
now we have 5 ways for the first women , 4 ways for the 2nd women and , 3 ways for the third women.
and 9 ways to select one man
so 5*4*3*9 = 540
now the three women are same so combinations with win them are irrelevant the 3 women can we arranged in 3! ways
hence 540/3!= 540/6= 90
E
Answer: E
Question: A person purchased a TV set for Rs. 16000 and a DVD player for Rs. 6250. He sold both the items together for Rs. 37150. What percentage of profit did he make?
Options:
A)22
B)27
C)40
D)26
E)67
Rationale: The total CP = Rs. 16000 + Rs. 6250 = Rs. 22250 and SP = Rs. 37150
Profit(%) = (37150 - 22250)/22250 * 100 = 67%.Answer:E
Answer: E
Question: If 1/a + 2/a + 3/a is an integer, which of the following must also be an integer?
Options:
A)12/a
B)3/a
C)6/a
D)9/a
E)15/a
Rationale: 1/a + 2/a + 3/a
=6/a
Answer C
Answer: C
Question: A group of medical interns at Bohemus Medical School want to go on dates. There are 5 girls and 5 guys. Assuming girls go on dates with guys, how many possible ways can these 10 medical interns date each other?
Options:
A)10
B)25
C)60
D)90
E)120
Rationale: 1st girl can go with 5 guys
2nd girl can go with remaining 4
3rd girl can go with remaining 3 and so on
so the total ways are 5!= 120
E should be the answer
Answer: E
Question: Average of five numbers is 16. If one number is excluded the average becomes 15. The excluded number is
Options:
A)20
B)40
C)55
D)65
E)67
Rationale: Explanation:
Number is (5*16) - (4*15) = 80-60= 20
Answer: Option A
Answer: A
Question: A straight one-mile stretch of highway is 40 feet wide. You ride your bike on a
path composed of semicircles as shown. If you ride at 5 miles per hour, how many hours will
it take you to cover the one-mile stretch?
Note: 1 mile = 5280 feet
Options:
A)π/11 hours
B)π/10 hours
C)π/5 hours
D)2π/5 hours
E)2π/3 hours
Rationale: We wish to solve for t in the equation s = v t, where s is the distance covered in
feet, and v = 5 5280 feet an hour.
Note that each semicircle has a radius of 20 feet (half the width of the road). This means
that you must complete 5280=40 semicircles to cover the one-mile stretch. Each of thosesemicircles measures 20 feet. You ride then a grand total of
5280/40*20π=5280/2π
feet. We have then :
5280/2π=5*5280*t which gives t =π/10 hours
correct answer B
Answer: B
Question: Five medical experts, working together at the same constant rate, can write an anatomy textbook in 32 days. How many additional experts, working together at this same constant rate, are needed to write the textbook in 10 days?
Options:
A)7
B)9
C)11
D)13
E)15
Rationale: Each expert can write 1/160 of the book per day.
To complete the book in 10 days, we need 160/10 = 16 experts, thus 13 more experts are needed.
The answer is D.
Answer: D
Question: Govind, Bipul and Shaik has won Rs. 6000, Rs. 4000 and Rs. 8000 respectively in a Jockpat. The next time, Bipul has won Rs. 3000. The difference between the additional winnings of Govind and Shaik is?
Options:
A)400
B)1500
C)986
D)600
E)670
Rationale: Ratio of the Jockpat won by Govind, Bipul and Shaik is 6000 : 4000 : 8000 = 3 : 2 : 4
And also given that, additional winning of Bipul is Rs. 3000
=> 2 parts out of 9 parts is Rs. 3000
Now, required difference is 4 - 3 = 1 part
Required difference = 1/2 (3000) = Rs. 1500.Answer: B
Answer: B
Question: In 2003 there are 28 days in February and 365 days in a year in 2004 there are 29 days in February and 366 days in the year. If the date march 11 2003 is Tuesday, then which one of the following would the date march 11 2004 would be?
Options:
A)27
B)35
C)56
D)2
E)11
Rationale: If 11-3-2003 is Tuesday, Then 11-3 - 2004 is Thursday
The number of odd days between the two dates are [3667]Rem[3667]Rem= 2.
Answer:D
Answer: D
Question: The average (arithmetic mean) of 4 different integers is 74. If the largest integer is 90, what is the least possible value of the smallest integer?
Options:
A)1
B)19
C)29
D)30
E)33
Rationale: Total of Integers=74*4=296
Lowest of the least possible integer is when the middle 2 intergers are at the maximum or equal to the highest possible integer.
But all integers are distinct. So if the largest integer is 90, then the middle 2 will be 88 and 89
Lowest of least possible integer = 296-(90+89+88)=296-267=29
Answer: C
Answer: C
Question: Solve the equation for x : 2(x + 2y + 3) = -x + y
Options:
A)1
B)2
C)3
D)-1
E)-2
Rationale: E
-2
2(x + 2y + 3) = -x + 4y
2x + 4y + 6 = -x + 4y
3x + 6 = 0
3x = -6
=> x = -2
Answer: E