divelab/Sys2Bench huggingface dataset:
Question: Ram and Krishna start from A and B respectively at the same time and travel towards each other at constant speeds along the same route. Ram meets Krishna at point C on the road which is 900m away from starting point A and 600m away from point B. The time taken by Ram to reach point B is 20minutes. Find the constant speed of Krishna.
Options:
A)50 m/m
B)60 m/m
C)40 m/m
D)53.5 m/m
E)none of the above
Rationale: total distance from A to B-
A - C = 900m, B - C = 600m;
therefore A-B = 1500m;
Vr=1500/20=75 m/m;
t-time taken by Ram for AB meet,
t=900/75=12 minutes = Time taken by Krishna for AB meet.
therefore,
Vk=600/12=50m/m.
option A
Answer: A
Question: A table is bought for Rs.940/- and sold at Rs.820/- find the loss percentage
Options:
A)12% Loss
B)10% Gain
C)20% Loss
D)20% Gain
E)30% Gain
Rationale: Formula = (Selling price ~ Cost price)/Cost price * 100
= (820 ~ 940)/940 = 12% Loss
A
Answer: A
Question: Rahul can finish one-fifth of hhis homework in one hour.Neha can finish three-seventh of her homework in one hout thirty minutes and riya can finish three fourth of her homework in three hours thirty minutes.If all of them start their homework at 12:00pm and can go to play as soon as they all finish their homework,when can they start to play,if they take a break at 3:30pm for thirty minutes?
Options:
A)5.00pm
B)BY 5:30 pm
C)4.40pm
D)6.30pm
E)3.30pm
Rationale: Let the work be 1
Then Rahul do 1/5 work in 60min
So Rahul do 1 work in 300 min
Then Neha do 3/7 work in 90min
So Neha do 1 work in 210min
Then Riya do 3/4 work in 210min
So Riya do 1 work in 280 min
By 300min i.e 5hr all will complete their work so
12-1,1-2,2-3,3-3:30, 4-4:30 ,4:30-5:30
By 5:30 they all go to play
ANSWER:B
Answer: B
Question: Pipe A can fill a tank in 6 hours. Due to a leak at the bottom, it takes 9 hours for the pipe A to fill the tank. In what time can the leak alone empty the full tank?
Options:
A)11
B)15
C)18
D)77
E)12
Rationale: Let the leak can empty the full tank in x hours 1/6 - 1/x = 1/9
=> 1/x = 1/6 - 1/9 = (3 - 2)/18 = 1/18
=> x = 18.
Answer: C
Answer: C
Question: An engagement team consists of a project manager, two team leaders, and four consultants. There are 2 candidates for the position of project manager, 3 candidates for the position of team leader, and 7 candidates for the 4 consultant slots. If 2 out of 7 consultants refuse to be on the same team, how many different teams are possible?
Options:
A)25
B)35
C)150
D)210
E)300
Rationale: Answer= Total number combinations - Total number of combinations with constraints
Total number of combinations = 2C1*3C2*7C4= 210
Total number of combinations with constraints = 2C1*3C2*5C2=60
Answer=210-60=150
ANSWER:C
Answer: C
Question: A distributor sells a product through an online store, which take a commission of 20% of the price set by the distributor. The distributor obtains the product from a producer at the price of $16 per item. What is the price that the buyer observers online if the distributor wants to maintain a 20% profit on the cost of the item?
Options:
A)$20
B)$21
C)$22
D)$23
E)$24
Rationale: Let x be the price that buyers see online.
The distributor wants to receive 1.2(original price) which should be 80% of x.
1.2(16) = 0.8x
x = 1.2(16) / 0.8 = 1.5(16) = $24
The answer is E.
Answer: E
Question: 112 is divided into two parts in such a way that seventh part of first and ninth part of second are equal. Find the smallest part?
Options:
A)66
B)26
C)49
D)27
E)11
Rationale: x/7 = y/9 => x:y = 7:9
7/16 * 112 = 49
Answer: C
Answer: C
Question: An employee’s annual salary was increased 50%. If her old annual salary equals $80,000 , what was the new salary?
Options:
A)$128,000
B)$120,000
C)$110,000
D)$139,000
E)$125,000
Rationale: Old annual salary = $80,000
Salary increase = 50%.
Original salary = $80,000 *50/100
= $40,000
new salary = $80,000+$40,000
=$120,000
Hence B.
Answer: B
Question: Tom read a book containing 560 pages by reading the same number of pages each day. If he would have finished the book 5 days earlier by reading 16 pages a day more, how many days did Tom spend reading the book?
Options:
A)19
B)18
C)9.12
D)20
E)None
Rationale: Actually u can set up 2 equation
P--stands for the pages
D--stands for the days
1) P*D=560(we want to find the Days, soP=560/D)
2) (P+16)(D-5)=560 => PD-5P+16D-80=560
as the 1) stated u can put 1) into 2)
=> 560-5P+16D-80=560 => 16D-5P=80
put the bold one into it => 16D-5(560/D)=80
the we get the final equation 16D^2-2800=80D (divide 16)
=> D^2-5D-175=0
(D-15)(D+10)=0 so D=9.12days Ans: C
Answer: C
Question: If A:B = 1/2: 1/3 B:C = 1/2:1/3 then A:B:C?
Options:
A)9:6:7
B)9:6:2
C)9:6:8
D)9:6:4
E)9:6:1
Rationale: A:B = 1/2:1/3 = 3:2
B:C = 1/2:1/3 = 3:2
--------------------
A:B:C = 9:6:4
Answer: D
Answer: D
Question: At a party, there were five times as many females as males and four times as many adults as children. Which of the following could NOT be the number of people at the party?
Options:
A)380
B)250
C)210
D)120
E)72
Rationale: Five times as many females as males --> F = 5M.
Three times as many adults as children --> (F + M) = 4C.
The number of people at the party = F + M + C = 4C + C = 5C.
The number of people at the party must be a multiple of 5. The only answer choice which is NOT a multiple of 5 is E.
Answer: E
Answer: E
Question: Using all the letters of the word "THURSDAY", how many different words can be formed?
Options:
A)8!
B)1
C)7
D)6
E)5
Rationale: Total number of letters = 8
Using these letters the number of 8 letters words formed is 8P8 = 4.
Answer: A
Answer: A
Question: The ratio of the number of boys and girls in a college is 7 : 8. If the percentage increase in the number of boys and girls be 20% and 10% respectively, what will be the new ratio?
Options:
A)21:22
B)17:18
C)8:9
D)9:8
E)None of them
Rationale: Originally, let the number of boys and girls in the college be 7x and 8x respectively.
Their increased number is (120% of 7x) and (110% of 8x).
= (120/100) 7x and (110/100) 8x
= 42x/5 and 44x/5
Therefore, The required ratio = (42x/5):(44x/5)
= 21 : 22
Answer is A.
Answer: A
Question: There are three departments having students 64,58,24 .In an exam they have to be seated in rooms such that each room has equal number of students and each room has students of one type only (No mixing of departments). Find the minimum number of rooms required?
Options:
A)73
B)74
C)75
D)76
E)77
Rationale: WE NEED TO TAKE GCD WHICH IS 2
THUS ALL THE ROOMS WILL HAVE 2 STUDENTS OF THE SAME DEPT
1) 64/2 = 32
2) 58/2 = 29
3) 24/2 = 12
TOTAL NO. OF MIN ROOMS REQD = 32+12+29 = 73
ANSWER:A
Answer: A
Question: A girl sold a book at a profit of 7%. Did she sold it for Rs.7.50 more, 22% would have been gained. Find the CP?
Options:
A)20%
B)30%
C)50%
D)60%
E)70%
Rationale: 50%
C
Answer: C
Question: If the probability that Green Bay wins the Super Bowl is 1/12 and the probability that Milwaukee wins the World Series is 1/20, what is the approximate probability that either Green Bay wins the Super Bowl or Milwaukee wins the World Series?
Options:
A)1/240
B)1/12
C)1/8
D)1/7
E)4/3
Rationale: P(AorB)=P(A)+P(B)−P(AandB)P(AorB)=P(A)+P(B)−P(AandB)
P(AandB)=P(A)∗P(B)P(AandB)=P(A)∗P(B)
1/12 + 1/20 - (1/12 * 1/20)
= 5/60 + 3/60 - 1/120
= 8/60 - 1/120
= 16/120 - 1/120
= 15/120
= 1/8
The correct answer is C.
Answer: C
Question: A man is 28 years older than his son. In two years, his age will be twice the age of his son. The present age of the son is
Options:
A)26 years
B)18 years
C)20 years
D)22 years
E)None
Rationale: Solution
Let the son's present age be x years .Then, man's present age	= (x+28)years.
Then	â€¹=â€º(x+28)+2= 2(x+2)
â€¹=â€ºx+30=2x+4
x= 26.
Answer A
Answer: A
Question: 10, 20, 12, 24, 16, 32, ?
Options:
A)20
B)21
C)22
D)23
E)24
Rationale: E
24
This is an alternating multiplication and subtracting series with a pattern x2, -8, x2, -8.
Answer: E
Question: Pipe A can fill a tank in 16 minutes and pipe B cam empty it in 24 minutes. If both the pipes are opened together after how many minutes should pipe B be closed, so that the tank is filled in 30 minutes?
Options:
A)21
B)55
C)66
D)77
E)81
Rationale: Let the pipe B be closed after x minutes.
30/16 - x/24 = 1 => x/24 = 30/16 - 1 = 14/16
=> x = 14/16 * 24 = 21.
Answer:A
Answer: A
Question: Puzzle !!! 🙂
if
111 = 09
444 = 12
777 = 15
then
888 = ???
Options:
A)13
B)17
C)18
D)11
E)15
Rationale: E
15
One+one+one(3+3+3)=09
Four+Four+Four(4+4+4)=12
Seven+Seven+Seven(5+5+5)=15
Therefore
Eight+Eight+Eight(5+5+5)=15
Answer: E
Question: In a consumer survey, 65% of those surveyed liked at least one of three products: 1, 2, and 3. 40% of those asked liked product 1, 35% liked product 2, and 15% liked product 3. If 7% of the people in the survey liked all three of the products, what percentage of the survey participants liked more than one of the three products?
Options:
A)12
B)14
C)16
D)18
E)20
Rationale: 40 + 35 + 15 = 90
This number includes some people counted twice and some people counted three times.
90 - 65 = 25, and this number represents people counted twice or three times.
7% of the people are counted two extra times.
The percentage of people counted one extra time is 25 - 7(2) = 11.
The percentage of people who liked more than one product is 7% + 11% = 18%.
The answer is D.
Answer: D
Question: A man can row upstream at 10 kmph and downstream at 20 kmph, and then find the speed of the man in still water?
Options:
A)11
B)77
C)25
D)88
E)34
Rationale: US = 20
DS = 30
M = (30 + 20)/2 = 25
Answer:C
Answer: C
Question: A vessel of capacity 90 litres is fully filled with pure milk. Nine litres of milk is removed from the vessel and replaced with water. Nine litres of the solution thus formed is removed and replaced with water. Find the quantity of pure milk in the final milk solution?
Options:
A)72
B)72.9
C)73
D)74
E)74.5
Rationale: Let the initial quantity of milk in vessel be T litres.
Let us say y litres of the mixture is taken out and replaced by water for n times, alternatively.
Quantity of milk finally in the vessel is then given by [(T - y)/T]n * T
For the given problem, T = 90, y = 9 and n = 2.
Hence, quantity of milk finally in the vessel
= [(90 - 9)/90]2 (90) = 72.9 litres.
ANSWER:B
Answer: B
Question: In a forest 150 deer were caught, tagged with electronic markers, then released. A week later, 50 deer were captured in the same forest. Of these 50 deer, it was found that 20 had been tagged with the electronic markers. If the percentage of tagged deer in the second sample approximates the percentage of tagged deer in the forest, and if no deer had either left or entered the forest over the preceding week, what is the approximate number of deer in the forest?
Options:
A)150
B)6,000
C)1,250
D)1,500
E)2,500
Rationale: The percentage of tagged deer in the second sample = 20/50*100=40%.
So, 150 tagged deers comprise 10% of total # of deers --> total # of deers = 150*40 = 6,000.
Answer: B
Answer: B
Question: What is the sum of all even numbers from 1 to 801?
Options:
A)160400
B)281228
C)281199
D)122850
E)128111
Rationale: Explanation:
800/2 = 400
400 * 401 = 160400
Answer: A
Answer: A
Question: A cistern has a leak which would empty the cistern in 20 minutes. A tap is turned on which admits 4 liters a minute into the cistern, and it is emptied in 24 minutes. How many liters does the cistern hold?
Options:
A)480
B)500
C)300
D)550
E)400
Rationale: 1/x - 1/20 = -1/24
x = 120
120 * 4 = 480
ANSWER A
Answer: A
Question: Of the diplomats attending a summit conference, 25 speak French, 32 do not speak Russian, and 20% of the diplomats speak neither French nor Russian. If 10% of the diplomats speak both languages, then how many diplomats attended the conference?
Options:
A)72
B)70
C)108
D)120
E)150
Rationale: {Total} = {French} + {Russian} - {Both} + {Neither}
{Total} = 25 + ({Total} - 32) - (0.1*{Total}) + 0.2*{Total}
Solving gives {Total} = 70.
Answer: B.
Answer: B
Question: A bank pays interest to its customers on the last day of the year. The interest paid to a customer
is calculated as 10% of the average monthly balance maintained by the customer. John is a
customer at the bank. On the last day, when the interest was accumulated into his account, his
bank balance doubled to $5680. What is the average monthly balance maintained by John in his
account during the year?
Options:
A)2840
B)5680
C)6840
D)7540
E)28400
Rationale: Soln:-
Bank balance is doubled with accumulation of interest to 5680..
this means INTEREST is 5680/2=2840 for entire year..
although since interest is 10% of avg MONthly balance, it becomes 28400..
ANSWER:E
Answer: E
Question: In a hostel there were 100 students. To accommodate some more students the average budget is decreased by rupees 10. But total expenditure increased by Rs.400. If the total expenditure of the hostel now 5400, find the number of student joined?
Options:
A)30
B)20
C)35
D)32
E)40
Rationale: Let average is x
100x + 400 = 5400
x = 50
let the number of student joined is y
(100+y)*(50-10)=5400
y = 35
Answer:D
Answer: D
Question: Which one of the given numbers is completely divisible by 45?
Options:
A)202860
B)165642
C)112330
D)112332
E)None of these
Rationale: To be divisible by 45 number has to be divisible by both 9 and 5.
If number ends with zero or five then it'll be divisible by 5.
For 9, add all the digits and if addition of all the digits is divisible by 9 then number'll be divisible by 9.
So, 202860 => 2+0+2+8+6+0= 18 which is divisible of 9. Last digit is 0, means divisible by 5.
So, 202860
ANSWER:A
Answer: A
Question: lexus car agency has 243 cars.he sold some cars at 9% profit and rest at 36% profit thus he gains 17% on the sale of all his cars.the no. of cars sold at 36% profit is?
Options:
A)36
B)37
C)72
D)39
E)40
Rationale: ratio of 36% profit cars to 9% profit cars = 8:19
so no. of cars sold at 36% profit = 243*8/27= 72 cars
ANSWER:C
Answer: C
Question: 39 persons can repair a road in 12 days, working 10 hours a day. In how many days will 30 persons, working 6 hours a day, complete the work?
Options:
A)10
B)13
C)14
D)15
E)26
Rationale: Let the required number of days be x.
Less persons, More days (Indirect Proportion)
More working hours per day, Less days (Indirect Proportion)
Persons	30	:	39	:: 12 : x
Working hours/day	6	:	10
30 x 6 x x = 39 x 10 x 12
x =	(39 x 10 x 12)/(30 x 6)
x = 26.
ANSWER:E
Answer: E
Question: How many zeros does 65! end with?
Options:
A)20
B)15
C)25
D)30
E)32
Rationale: According to above 65! has 65/5+65/25=13+2=15 trailing zeros.
Answer: B.
Answer: B
Question: What is the units digit of (3^16)(4^13)?
Options:
A)2
B)4
C)6
D)7
E)8
Rationale: -> The ones place of (~3)^n repeats after 4 times like 39713.
The ones place of (~4)^n repeats after 2 times like 464.
Then, 3^16=3^4*4=3^0=1.,
4^13=4^2*6+1=4^1=~4
which is (3^16)(4^13) (3^0)(~4)=(~1)(~4)=~4. Therefore, the answer is B.
Answer: B
Question: A sum of money becomes 7/6 of itself in 5 years at a certain rate of simple interest. The rate per annum is?
Options:
A)20/7
B)20/3
C)23/6
D)10/3
E)10/7
Rationale: Let sum = x. Then, amount = 7x/6
S.I. = 7x/6 - x = x/6; Time = 5 years.
Rate = (100 * x) / (x * 6 * 5) = 10/3 %.
Answer:D
Answer: D
Question: A train 150 m long is running at a speed of 68 kmph. How long does it take to pass a man who is running at 8 kmph in the same direction as the train?
Options:
A)2 Sec
B)6 Sec
C)8 Sec
D)9 Sec
E)5 Sec
Rationale: D
9 Sec
Speed of the train relative to man = (68 - 8) kmph
= (60* 5/18) m/sec = (50/3)m/sec
Time taken by the train to cross the man
= Time taken by It to cover 150 m at 50/3 m / sec = 150 *3/ 50 sec = 9sec
Answer: D
Question: In an election between two candidates, 70% of the voters cast their votes, out of which 4% of the votes were declared invalid. A candidate got 6552000 votes which were 75% of the total valid votes. Find the total number of votes enrolled in that election.
Options:
A)13000000
B)12500
C)14000
D)12000
E)None of these
Rationale: Explanation :
Solution: let the total number of votes enrolled be x. then, number of votes cast = 70% of x. valid votes = 96% of(70% of x). .'. 75% of(96% of (70% of of x)) = 6552000.
(75/100 * 96/100 * 70/100 * x) = 6552000.
=> x = (6552000*100*100*100)/(75*96*70) = 13000000
Answer : A
Answer: A
Question: Simplify: 0.3*0.3+0.3*0.3
Options:
A)0.52
B)0.42
C)0.18
D)0.64
E)0.46
Rationale: Given exp. = 0.3*0.3+(0.3*0.3) = 0.09+0.09 = 0.18
Answer is C.
Answer: C
Question: A starts business with Rs.3500 and after 5 months, B joins with A as his partner. After a year, the profit is divided in the ratio 2 : 3. What is B’s contribution in the Capital ?
Options:
A)24887
B)20778
C)23788
D)9000
E)2811
Rationale: Explanation:
A invested Rs.3500 for 12 months.
Let B joined with investment x. And he invested for 12 - 5 = 7 months.
So there profit ratio = (3500 × 12) : (7x) = 2 : 3
⇒ x = 9000
Answer: D
Answer: D
Question: How many multiples of 2 are there between 0 and 100, exclusive ?
Options:
A)48
B)47
C)46
D)45
E)49
Rationale: 2 * 50 = 100
Total multiples = (50 -1) + 1 = 50
Exclude 0 and 100 = 50 - 1 = 49
Answer is E.
Answer: E
Question: If 2 cards are selected (with replacement) at random from the deck of 52 cards then what is the probability that one of the selected cards will be red and the other will be black?
A deck of cards has a total of 52 cards, consisting of 4 suits: spades (black), hearts (red), diamonds (red), and clubs (black). In each suit, there are 13 cards including 1 king, 1 queen, and 1 jack.
Options:
A)1/2
B)1/4
C)1/8
D)1/16
E)1/32
Rationale: P(1 red and 1 black) = 2(1/2*1/2) = 1/2
The answer is A.
Answer: A
Question: For the past n days, the average (arithmetic mean) daily production at a company was 30 units. If today's production of 90 units raises the average to 35 units per day, what is the value of n ?
Options:
A)30
B)18
C)10
D)9
E)3
Rationale: (average production for n days) * n = (total production for n days) --> 30n=(total production for n days);
(total production for n days) + 90 = (average production for n+1 days) * (n+1) --> 30n + 90 = 35 * (n+1) --> n=3.
Answer: E.
Answer: E
Question: The G.C.D of 1.08, 0.42 and 0.9 is
Options:
A)0.19
B)0.1
C)0.06
D)0.11
E)0.12
Rationale: Explanation:
Given numbers are 1.08 , 0.42 and 0.90
H.C.F of 108, 42 and 90 is 6 [because G.C.D is nothing but H.C.F]
therefore H.C.F of given numbers = 0.06
Answer: C)
Answer: C
Question: The difference between the squares of two consecutive odd integers
is a square<1000 whose root equals the combined sum of the digits
of the two integers. What is the sum of the digits X of the larger integer?
Options:
A)X=2
B)X=5
C)X=8
D)10
E)11
Rationale: Really hard. But let's start with few concepts:
1. Square of an odd integer will be odd.
2. Difference of odd and odd will be even.
3. Any odd integer can be expressed as difference of two squares.
4. An even integer can be expressed as difference of two squares only if that even integer is a multiple of 4.
Assume two odd integers to be (2x-1) and (2x+1).
Difference of their squares = (2x+1)^2 - (2x-1)^2
= 4x^2 + 1 + 4x - (4x^2 + 1 - 4x)
= 4x^2 + 1 + 4x - 4x^2 - 1 + 4x
= 8x
Now root of 8x needs to be an integer such that it is equal to the sum of the digits of the two odd integers.
8 = 2^3, so x needs to be such that itcompletesa perfect square.
If we find x, we can find the value of 2x+1 (larger integer) and then sum of its digits.
Let's check the options, starting with c.
For sum to be 8, few possibilities are: 17, 35, 53, 71
If we take 17, the pair is 15 and 17, meaning x = 8.
8x = 64
root of 64 = 4 but 4 is not equal to 1+5+1+7.
Reject.
If we take 35, the pair is 33 and 35, meaning x = 17.
8x = 8*17
Reject since perfect square is not possible.
If we take 53, the pair is 51 and 53, meaning x = 26.
8x = 8*26
Reject since perfect square is not possible.
If we take 71, the pair is 69 and 71, meaning x = 35.
8x = 8*35
Reject since perfect square is not possible.
I tried each option and the possibilities and then got lost.
Then, it occurred to me that I was only checking 2-digit integers. What about 3-digits?
Starting with option a, only 2-digit odd integer whose sum is 2 is 101.
If we take 101, the pair is 99 and 101, meaning x = 50.
8x = 8*50 = 400
root of 400 = 20 which is indeed equal to 9+9+1+1.
Answer (A).
Answer: A
Question: John and Karen begin running at opposite ends of a trail until they meet somewhere in between their starting points. They each run at their respective constant rates until John gets a cramp and stops. If Karen runs 50% faster than John, who is only able to cover 25% of the distance w before he stops, what percent longer would Karen have run than she would have had John been able to maintain his constant rate until they met.
Options:
A)25%
B)50%
C)75%
D)100%
E)200%
Rationale: John and Karen begin running at opposite ends of a trail until they meet somewhere in between their starting points. They each run at their respective constant rates until John gets a cramp and stops. If Karen runs 50% faster than John, who is only able to cover 25% of the distance w before he stops, what percent longer would Karen have run than she would have had John been able to maintain his constant rate until they met.
Lets say the distance of the trail is 100 miles. Lets also say that J rate = 10 miles/hour and K rate = 15 miles/hour.
If John stops at the 25% mark that means he travels 25 miles in 2.5 hours. It would take Karen t=d/r t=75/15 = 5 hours to reach john. If John had not stopped, their combined rate would 10+15 = 25 miles/hour meaning they would have met in 4 hours. Therefore, she ran one hour longer (25%) longer than she would have needed to if John ran for the entire time.
ANSWER: A) 25%
Answer: A
Question: If 1+2+3+...+n=n (n+1), then 3 (1+3+5+....+79)=?
Options:
A)4500
B)4250
C)4350
D)4800
E)4150
Rationale: Explanation :
To solve this use the formula of AP,
Sn= (n/2)(a+l) ................(1)
To find n, use
=> Tn= a+(n-1)d
=> 79=1+(n-1)2
=> n=40
Use value of n in (1)
then,
Sn = (40/2)(1+79) = 1600
Ans:- 3(Sn) = 4800
Answer : D
Answer: D
Question: Look at this series: 72, 76, 73, 77, 74, __, 75, ... What number should fill the blank?
Options:
A)70
B)71
C)75
D)78
E)79
Rationale: Explanation: This series alternates the addition of 4 with the subtraction of 3.
Answer: Option D
Answer: D
Question: Find large number from question the difference of two numbers is 1365.On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder?
Options:
A)1235
B)1455
C)1535
D)1615
E)1635
Rationale: Let the smaller number be x. Then larger number = (x + 1365).
x + 1365 = 6x + 15
5x = 1350
x = 270
Large number = 270+1365 = 1635
E
Answer: E
Question: In a friendship gang Raja has 9 gang, in how many ways can he invite one or more of the gang to his house?
Options:
A)124
B)587
C)987
D)511
E)263
Rationale: Raja can select one or more than one of his 8 gang.
=> Required number of ways = 2^9 – 1= 511.
D
Answer: D
Question: The average height of 20 girls out of a class of 50 is 142 cm. and that of the remaining girls is 149 cm. The average height of the whole class is :
Options:
A)146.2 cms
B)146.5 cms
C)146.9 cms
D)142.2 cms
E)136.2 cms
Rationale: Explanation:
Average height of the whole class =(20×142+30×149/50)=146.2 cms
Answer A
Answer: A
Question: A certain bag contains 60 balls — 22 white, 18 green, 5 yellow, 6 red, and 9 purple. If a ball is to be chosen at random, what is the probability that the ball will be neither red nor purple?
Options:
A)0.09
B)0.15
C)0.54
D)0.75
E)0.91
Rationale: According to the stem the ball can be white, green or yellow, so the probability is (white + green + yellow)/(total) = (22 + 18 + 5)/60 = 45/60 = 0.75.
Answer: D.
Answer: D
Question: A boy runs 200 metres in 60 seconds. What is his speed ?
Options:
A)12 km/hr
B)24 km/hr
C)13 km/hr
D)14 km/hr
E)16 km/hr
Rationale: 200/60 * 18/5 = 12 km/hr
ANSWER:A
Answer: A