divelab/Sys2Bench huggingface dataset:
Question: The sum of the heights of two high-rises is x feet. If the second high rise is 37 feet taller than the first, how tall will the first high rise be after they add an antenna with a height of z feet to the top?
Options:
A)(x+z)/2 + 37
B)2x−(37+z)
C)(x−37)/2 + z
D)x/2 - 37 + z
E)(2x−37)/z
Rationale: I will note h1 the height of high-rise 1 and h2 the height of high-rise 2. SO:
h1 + h2 = x
and h2 = h1 + 37 =>
Q: h1+ z = ?
h21+ h1 + 37 = x => 2h1= x-37 =? h1 = (x-37)/2
=> h1+ z = (x-37)/2 + z, CORRECT ANSWER C
Answer: C
Question: In how many ways, a committee of 12 members can be selected from 8 men and 7 ladies, consisting of 7 men and 5 ladies?
Options:
A)150
B)167
C)200
D)168
E)178
Rationale: (7 men out 8) and (5 ladies out of 7) are to be chosen
Required number of ways = 8C7*7C5 = 168
Answer is D
Answer: D
Question: 61 small identical cubes are used to form a large cube. How many more cubes are needed to add one top layer of small cube all over the surface of the large cube ?
Options:
A)64
B)128
C)152
D)155
E)256
Rationale: 61 small cube will make a large cube with 4 cubes in each line i.e.
Adding one layer will require one cube at each end and hence new cube will have 6 cubes in each line.
Total number of small cubes in new cube = 6^3 = 216
Extra cube required = 216 - 61 = 155
Hence, D is the answer.
Answer: D
Question: A card game called “high-low” divides a deck of 52 playing cards into 2 types, “high” cards and “low” cards. There are an equal number of “high” cards and “low” cards in the deck and “high” cards are worth 2 points, while “low” cards are worth 1 point. If you draw cards one at a time, how many ways can you draw “high” and “low” cards to earn 6 points if you must draw exactly 3 “low” cards?
Options:
A)1
B)20
C)3
D)4
E)5
Rationale: Great question Ravih. This is a permutations problem (order matters) with repeating elements. Given thatlowcards are worth 1 pt andhigh cards2 pts, and you must draw 3 low cards, we know that you must also draw 1 high card. The formula for permutations problems with repeating elements isN!/A!B!...where N represents the number of elements in the group and A, B, etc. represent the number of times that repeating elements are repeated. Here there are 4 elements and thelowcard is repeated 3 times. As a result, the formula is:
5!/3! which represents (5*4*3*2*1)/(3*2*1) which simplifies to just 20, giving you answer B.
Answer: B
Question: A certain company assigns employees to offices in such a way that some of the offices can be empty and more than one employee can be assigned to an office. In how many ways can the company assign 3 employees to 3 different offices?
Options:
A)5
B)6
C)27
D)8
E)9
Rationale: Ans. Each employee can go into any of the two offices. Thus we have
=> 3 * 3 * 3= 27
Answer : C
Answer: C
Question: A person purchased a TV set for Rs. 16000 and a DVD player for Rs. 1800. He sold both the items together for Rs. 31150. What percentage of profit did he make?
Options:
A)30%
B)75%
C)40%
D)70%
E)None of these
Rationale: The total CP = Rs. 16000 + Rs. 1800 = Rs. 17800 and SP = Rs. 31150
Profit(%) = (31150 - 17800)/17800* 100 = 75%
ANSWER:B
Answer: B
Question: In a colony of 70 residents, the ratio of the number of men and women is 4:3. Among the women, the ratio of the educated to the uneducated is 1:4. If the ratio of the number of education to uneducated persons is 8:27, then find the ratio of the number of educated and uneducated men in the colony?
Options:
A)1:4
B)3:5
C)3:9
D)3:7
E)1:3
Rationale: Number of men in the colony = 4/7 (70) = 40
Number of women in the colony = 3/7 (70) = 30
Number of educated women in the colony = 1/5 (30) = 6
Number of uneducated women in the colony = 4/5 (30) = 24
Number of educated persons in the colony = 8/35 (70) = 16
As 6 females are educated, remaining 10 educated persons must be men.
Number of uneducated men in the colony = 40 - 10 = 30
Number of educated men and uneducated men are in the ratio 10:30 => 1:3
Answer:E
Answer: E
Question: A drink vendor has 80 liters of Maaza, 144 liters of Pepsi and 368 liters of Sprite. He wants to pack them in cans, so that each can contains the same number of liters of a drink, and doesn't want to mix any two drinks in a can. What is the least number of cans required?
Options:
A)35
B)37
C)42
D)30
E)38
Rationale: The number of liters in each can = HCF of 80, 144 and 368 = 16 liters.
Number of cans of Maaza = 80/16 = 5
Number of cans of Pepsi = 144/16 = 9
Number of cans of Sprite = 368/16 = 23
The total number of cans required = 5 + 9 + 23 = 37 cans.
ANSWER:B
Answer: B
Question: If the product of two numbers is 84942 and their H.C.F. is 33, find their L.C.M.
Options:
A)2574
B)2500
C)1365
D)1574
E)None of these
Rationale: Explanation:
HCF * LCM = 84942, because we know
Product of two numbers = Product of HCF and LCM
LCM = 84942/33 = 2574
Option A
Answer: A
Question: A man traveled a total distance of 1800 km. He traveled one-third of the whole trip by plane and the distance traveled by train is three-fifth of the distance traveled by bus. If he traveled by train, plane and bus, then find the distance traveled by bus?
Options:
A)239
B)247
C)277
D)270
E)898
Rationale: Explanation:
Total distance traveled = 1800 km.
Distance traveled by plane = 600 km.
Distance traveled by bus = x
Distance traveled by train = 3x/5
=> x + 3x/5 + 600 = 1800
=> 8x/5 = 1200 => x = 750 km.
Answer: D
Answer: D
Question: Shan starts from Barabanki to Fatehpur, 1 hour after Ajay starts. Shahrukh meets Kajol 1.5 hours after Shahrukh starts. If the speed of Shan is at least 20km/hour fasterthan the speed of Kajol. What is the min speed of Shan to overtake Ajay, before he meets Kajol?
Options:
A)30
B)40
C)50
D)60
E)None of these
Rationale: Let t be the time after Kajol starts, when she meets Ajay, then
\inline t=\frac{300}{(x+y)}
This should be less than 2.5 or (x+y)>120
Since y= \inline \frac{3x}{2} \inline \Rightarrow y>72
This (y>72) is greater than 67.5 km/h and hence Shahrukh will always overtake Ajay before he meets Kajol.
E)
Answer: E
Question: A reduction of 12% in the price of oil enables a house wife to obtain 6kgs more for Rs.1200, what is the reduced price for kg?
Options:
A)24
B)27
C)40
D)28
E)20
Rationale: 1200*(12/100) = 144 ---- 6
? ---- 1 => Rs.24
Answer:A
Answer: A
Question: Laura took out a charge account at the General Store and agreed to pay 6% simple annual interest. If she charges $35 on her account in January, how much will she owe a year later, assuming she does not make any additional charges or payments?
Options:
A)$2.10
B)$37.10
C)$37.16
D)$38.10
E)$38.80
Rationale: Principal that is amount taken by Laura at year beginning = 35$
Rate of interest = 6%
Interest = (6/100)*35 = 2.10$
Total amount that Laura owes a year later = 35+2.1 = 37.1 $
Answer B
Answer: B
Question: If a person walks at 12 km/hr instead of 8 km/hr, he would have walked 20 km more. The actual distance traveled by him is?
Options:
A)50
B)40
C)45
D)60
E)25
Rationale: Let the actual distance traveled be x km. Then,
x/8 = (x + 20)/12
x - 40 =>x = 40 km.
Answer: B
Answer: B
Question: 364, 361, 19, 16, 4, 1, ?
Options:
A)0
B)1
C)2
D)3
E)4
Rationale: 364-3=361
sqrt(361)=19
19-3=16
sqrt(16)=4
4-3=1
sqrt(1)=1
ANSWER:B
Answer: B
Question: What is the ratio between perimeters of two squares one having 2.5 times the diagonal then the other?
Options:
A)4: 5
B)1: 3
C)2.5: 1
D)3.5: 1
E)3: 2
Rationale: d = 2.5d d = d
a√2 = 2.5d a√2 = d
a = 2.5d/√2 a = d/√2 =>2.5: 1
Answer: C
Answer: C
Question: In 1 hour, a boat goes 8 km along the stream and 12 km against the stream. The speed of the boat in still water (in km/hr) is :
Options:
A)3 km/hr.
B)2 km/hr.
C)10 km/hr.
D)8 km/hr.
E)5 km/hr.
Rationale: Speed in still water = 1/2(8 + 12) km/hr
= 10 km/hr. ANSWER :C
Answer: C
Question: A, B and C can do a piece of work in 24 days, 30 days and 40 days respectively. They began the work together but C left 4 days before the completion of the work. In how many days was the work completed?
Options:
A)32
B)88
C)67
D)11
E)66
Rationale: One day work of A, B and C = 1/24 + 1/30 + 1/40 = 1/10 Work done by A and B together in the last 4 days = 4*(1/24 + 1/30) = 3/10
Remaining work = 7/10
The number of days required for this initial work = 7 days.
The total number of days required = 4 + 7 = 11 days.
Answer:D
Answer: D
Question: Jonathan’s grandparents lend $100,000 to Jonathan at a simple annual interest rate of 10%. He pays them back 5 years later. How much do they receive?
Options:
A)100,000∗0.1^5
B)100,000∗0.5
C)(100,000∗0.1)^5
D)100,000∗1.1^5
E)100,000∗1.5
Rationale: if you are like me and have used S.I = P x R x T formula in school, while the question is asking for Amount in 5 years. so (E) 10,000∗ 1.5
Ans : E
Answer: E
Question: The number 69 can be written as the sum of squares of 3 integers. Which of the following could be the difference between the largest and smallest integers of the 3?
Options:
A)2
B)5
C)7
D)8
E)9
Rationale: Notice that the question asks which of the followingcouldbe the difference between the largest and smallest integers, not must be. The 3 integers could be: +/-2, +/-4 and +/-7 so the difference could be 5,3 or 11. Since only one of them is among the choices, then it must be the correct answer.
Answer: B
Answer: B
Question: If four students are made to sit in a row, then 3 don't have seats. If 15 students are made to sit in a row, then two rows are empty. How many students have to sit a row such that each row has equal number of students and all students are seated?
Options:
A)0
B)1
C)4
D)5
E)9
Rationale: Let there be a rows.
Then 4a + 3= 15(a-2) [equating the number of students]
=> a= 3
and total number of students = 15
Therefore 5 students much sit in each row such that each row has an equal number of students and all students are seated.
Option (D)
Answer: D
Question: In how many different number of ways 5 men and 2 women can sit on a shopa which can accommodate persons?
Options:
A)200
B)230
C)240
D)250
E)260
Rationale: Option 'B'
7p3 = 7 × 6 × 5 = 210
Answer: B
Question: Three pipes A, B and C can fill a tank in 6 hours. After working at it together for 2 hours, C is closed and A and B can fill the remaining part in 7 hours. The number of hours taken by C alone to fill the tank is:
Options:
A)10
B)12
C)14
D)16
E)18
Rationale: Explanation:
A,B,C together fill the tank in 6 hours.
=> Part filled by pipes A,B,C together in 1 hr =1/6
All these pipes are open for only 2 hours and then C is closed.
Remaining part =1−1/3=2/3
This remaining part of 2/3 is filled by pipes A and B in 7 hours
Therefore, part filled by pipes A and B in 1 hr
=(2/3)/7=2/21
Part filled by pipe C in 1 hr
=(1/6-2/21)=7-4/42 =3/42 =1/14
i.e., C alone can fill the tank in 14 hours.
Answer: Option C
Answer: C
Question: If the ratio of apples to bananas is 5 to 2 and the ratio of bananas to cucumbers is 1 to 2, what is the ratio of apples to cucumbers?
Options:
A)6:5
B)1:4
C)4:3
D)2:3
E)5:4
Rationale: The ratio of bananas to cucumbers is 1 to 2 which equals 2 to 4.
The ratio of apples to bananas to cucumbers is 5 to 2 to 4.
The ratio of apples to cucumbers is 5 to 4.
The answer is E.
Answer: E
Question: A sells his goods 50% cheaper than B but 50% dearer than C. The cheapest is?
Options:
A)33.3
B)33.6
C)33.0
D)33.4
E)33.1
Rationale: Let B = 100
A = 50
C * (150/100) = 50
3C = 100
C = 33.3 then 'C' Cheapest
Answer:C
Answer: C
Question: As x increases from 161 to 162, which of the following increases? I) x−1/x II) 17−1/x III) (17+x)/x
Options:
A)I only
B)II,III only
C)III only
D)II only
E)I,II only
Rationale: On Increasing the value of x from 161 to 162
I) x−1/x will increase as 1/x will be very small and x will increase by 1 unit
II) 17−1/x Will Increase as the value of 1/x will decrease thereby increasing the value of 17-(1/x)
III) (17+x)/x = (17/x)+1 will Decrease as 1/x will decrease thereby decreasing the value of (17/x)
Answer: E
Answer: E
Question: In how many ways can live men and three women sit in a row such that all men sit together?
Options:
A)1230
B)1340
C)1400
D)1500
E)2880
Rationale: Treat all boys as one unit. Now there are four students and they can be arranged in 4! ways. Again five boys can be arranged among themselves in 5! ways.
Required number of arrangements
4! * 5! = 24 * 120 = 2880
E
Answer: E
Question: A class of students consists of 6 senior and 2 junior students. If a class council is created with 3 senior and 1 junior student, in how many ways can the class council be formed?
Options:
A)12
B)20
C)40
D)57
E)432
Rationale: Choose 3 senior from 5 senior and choose 1 junior from 3 junior:
3C6 * 1C2 = 20*2 = 40
Ans: C
Answer: C
Question: The 100-milliliter solution of sugar and water is 15% sugar. How much water (in milliliters) must be added to make a solution that is 8% sugar?
Options:
A)72.5
B)77.5
C)82.5
D)87.5
E)92.5
Rationale: In the original solution the amount of sugar is 0.15*100=15 ml.
Let the volume of the new solution be V.
0.08V=15 ml.
V=187.5 ml.
The amount of water we need to add is 187.5 - 100 = 87.5 ml.
The answer is D.
Answer: D
Question: An office supply store stocks three sizes of notebooks, each in five colors: blue, green, yellow, red, or pink. The store packs the notebooks in packages that contain either 4 notebooks of the same size and the same color or 4 notebooks of the same size and of 4 different colors. If the order in which the colors are packed is not considered, how many different packages of the types described above are possible?
Options:
A)18
B)24
C)30
D)45
E)60
Rationale: First let's consider the small notebooks.
There are 5 ways to choose notebooks of the same color.
The number of ways to choose four notebooks with different colors is 5C4=5.
There are 10 different packages we can make with the small notebooks.
We can use the same process to find 10 different packages with medium and large notebooks.
The total number of different packages is 30.
The answer is C.
Answer: C
Question: If p/q = 2/7 , then 2p+q= ?
Options:
A)11
B)14
C)13
D)15
E)16
Rationale: let p=2, q=7 then 2*2+7=11
so 2p+q=11.
ANSWER:A
Answer: A
Question: A company produces computers with 7 different speeds, and the ratio of each speed to the next one is a fixed ratio. If the fastest computer is 5.4 GHz, while slowest speed is 0.2 GHz, what is the speed of the second slowest computer?
Options:
A)(3^1/2) (0.2)
B)(27^1/7) (0.2)
C)(5.2/7) + 0.2
D)(0.2)^2
E)0.8
Rationale: 1st speed=0.2
Let x be ratio,then 1st/2nd=x
0.2/2nd =x------>2nd=0.2/x------(a)
.
.
.
7th=0.2/x^6=5.4
x^6=0.2/5.4=1/27----->1/3^3
x=1 / 3^(3*1/6)------->1/3^1/2
therefore 2nd speed(from (a)) =0.2/(1/3^1/2)-------->3^1/2*0.2
Ans A
Answer: A
Question: A is a working partner and B is a sleeping partner in the business. A puts in Rs.15000 and B Rs.25000, A receives 10% of the profit for managing the business the rest being divided in proportion of their capitals. Out of a total profit of Rs.9600, money received by A is?
Options:
A)Rs.3240
B)Rs.3600
C)Rs.3800
D)Rs.4200
E)Rs.4250
Rationale: 15:25 => 3:5
9600*10/100 = 960
9600 - 960 = 8640
8640*3/8 = 3240 + 960
= 4200
ANSWER:D
Answer: D
Question: The product of two numbers is 266 and their difference is 5. What is the bigger number ?
Options:
A)13
B)15
C)19
D)24
E)None of these
Rationale: Explanation:
Let the two numbers be A and B, here A > B
AB = 266
B = 266/A -----------------(I)
Given,
A – B = 5 ----------- (II)
Substitute from (I) in (II), we get
A – 266/A = 5
A2 – 5A + 266 = 0
(A – 19)(A – 14) = 0
Therefore , A = 19 or A = 14
Hence, bigger number = A = 19
ANSWER: C
Answer: C
Question: The probability of rain showers in Barcelona on any given day is 0.3. What is the probability that it will rain on exactly one out of three straight days in Barcelona?
Options:
A)0.441
B)0.072
C)0.432
D)0.72
E)0.288
Rationale: IMO This is just for first day! It can rain on 2nd day or 3 rd day (and not rain on other days) in 3 consecutive days!
Hence,
0.3*0.7*0.7 + 0.7*0.3*0.7 + 0.7*0.7*0.3 = 0.441
Option - A
Answer: A
Question: How many odd, positive divisors does 640 have?
Options:
A)6
B)8
C)12
D)15
E)24
Rationale: Make a prime factorization of a number: 540=2^2*3^3*5 --> get rid of powers of 2 as they give even factors --> you'll have 3^3*5 which has (3+1)(1+1)=12 factors.
Another example: 60=2^2*3*5 it has (2+1)(1+1)(1+1)=12 factors out of which (1+1)(1+1)=4 are odd: 1, 3, 5 and 15 the same # of odd factors as 60/2^2=15 has.
Answer: C.
Answer: C
Question: A certain animal shelter has 28 cats and 46 dogs. How many dogs must be adopted and taken away from the animal shelter so that 70 percent of the animals in the shelter will be cats?
Options:
A)6
B)12
C)28
D)34
E)40
Rationale: (28 + 46 - x)*0.7 = 28
x = 34.
Answer: D.
Answer: D
Question: Three grades of milk are 1 percent, 2 percent and 5 percent fat by volume. If x gallons of the 1 percent grade, y gallons of the 2 percent grade, and z gallons of the 5 percent grade are mixed to give x+y+z gallons of a 3 percent grade, what is x in terms of y and z?
Options:
A)y + 3z
B)(y +z) / 4
C)2y + 3z
D)z - 0.5 y
E)3y + 4.5z
Rationale: Based on the given information, the following equation could be dervied: 1% * x + 2% * y + 5% * z = 3% * (x+y+z) Then use algebra to figure out 2%*x = -1%*y + 2%*z. Thus, x = z - 0.5 y
D
Answer: D
Question: 36 men can complete a piece of work in 18 days. In how many days will 27 men complete the same work?
Options:
A)56
B)28
C)45
D)24
E)45
Rationale: D
24
Let the required number of days be x.
Less men, More days (Indirect Proportion)
27 : 36 :: 18 : x <-> 27 x x = 36 x 18
x = (36 x 18)/27
x = 24
Answer: D
Question: A person decided to build a house in 100days. He employed 100men in the beginning and 100 more after 50 days and completed the construction in stipulated time. If he had not employed the additional men , how many days behind schedule would it have been finished?
Options:
A)40
B)80
C)50
D)60
E)50
Rationale: 200 men do the rest of the work in 100-50 = 50days
100 men can do the rest of the work in 50*200/100 = 100days
Required number of days = 100-50 = 50 days
Answer is C
Answer: C
Question: The number 243 has been divided into three parts in such a way that one third of the first part, fourth of the second part and half of the third part are equal. Determine the largest part.
Options:
A)108
B)276
C)297
D)266
E)911
Rationale: Explanation:
It is given that 243 has been divided into 3 numbers x y and z for instance.
Second condition mentioned in the question is:
=> x/3 = y/4 =z/2
Clearly the biggest number is y. So let us solve w.r.t. y.
=> x = 3y/4
=> x =3z/2
=> z = y/2
=> x+y+z = 243
=> y/2 + 3y/4 + y = 243
9y/4 = 243
=> 243*4/9
=> 108
ANSWER: A
Answer: A
Question: A wire in the form of a circle of radius 3.5 m is bent in the form of a rectangule, whose length and breadth are in the ratio of 6 : 5. What is the area of the rectangle?
Options:
A)60 cm2
B)30 cm2
C)45 cm2
D)15 cm2
E)None of these.
Rationale: The circumference of the circle is equal to the permeter of the rectangle.
Let l = 6x and b = 5x 2(6x + 5x) = 2 * 22/7 * 3.5
=> x = 1
Therefore l = 6 cm and b = 5 cm Area of the rectangle = 6 * 5 = 30 cm2
14. The area of a square is 40
ANSWER:B
Answer: B
Question: A wire in the form of a circle of radius 3.5 m is bent in the form of a rectangule, whose length and breadth are in the ratio of 6 : 5. What is the area of the rectangle?
Options:
A)87 cm2
B)30 cm2
C)76 cm2
D)26 cm2
E)98 cm2
Rationale: The circumference of the circle is equal to the permeter of the rectangle.
Let l = 6x and b = 5x 2(6x + 5x) = 2 * 22/7 * 3.5
=> x = 1
Therefore l = 6 cm and b = 5 cm Area of the rectangle
= 6 * 5
= 30 cm2
Answer: B
Answer: B
Question: How many obtuse triangle can be made when one of the side of the triangle is taken between the 1st natural number and 8.
Options:
A)1
B)2
C)3
D)4
E)5
Rationale: 3 triangles can be formed....because we have to take the property that sum of two sides of a triangle should be greater than the third side
ANSWER:C
Answer: C
Question: John deposited $10,000 to open a new savings account that earned 4 percent annual interest, compounded quarterly. If there were no other transactions in the account, what was the amount of money in John's account 6 months after the account was opened?
Options:
A)$10,100
B)$10,101
C)$10,200
D)$10,201
E)$10,400
Rationale: john amount is compounded quarterly so the formula is A=P*(1+R/100)^N her p=principle R=rate of interest N=no of terms
rate of interest is 4% for a yr
so for quarter R=4/4=1%
john receive amt after 6 months so there are two quarter
so N=2
Amount A=P(1+R/100)^2
=10000(1+1/100)^2
=10000(1+0.01)^2
=1020
ANSWER:C
Answer: C
Question: . 729ml of mixture contains milk and water in the ratio 7:2 how much more wate is to be added to get a new mixture containing milk and water in the ratio 7:3?
Options:
A)22
B)77
C)36
D)28
E)81
Rationale: Difficulty Level : Easy Moderately easy Difficult Basic Formula: Facts and ratios a: b = a/b
Answer with Explanation: Ratio of milk and water in 729 ml = 7:2 Step (i) Milk in 729 ml of mixture = (7/9 x 729 ) ml = 567 ml  water in 729 ml of mixture = 729 – 567 = 162 ml Step (ii) Let x be the quantity of water added to new mixture, with the ratio 7:3  Quantity of water in the new mixture = (162 + x ) ml
Then 7/3 =
x162 567  7 (162 + x) = 3 x 567  1134 + 7x = 1701 7x = 1701 – 1134 X = 567/7 = 81 ml  Quantity of water added to new mixture = 81 ml.
Answer:E
Answer: E
Question: What least value must be assigned to * so that the number 63576*2 is divisible by 8?
Options:
A)1
B)2
C)3
D)4
E)5
Rationale: Sol.
The given number is divisible by 8, if the number 6x2 is divisible by 8.
Clearly, the least value of x is 3.
Answer C
Answer: C
Question: The total cost of a vacation was divided among 3 people. If the total cost of the vacation had been divided equally among 4 people, the cost per person would have been $40 less. What was the total cost cost of the vacation?
Options:
A)$200
B)$300
C)$480
D)$500
E)$600
Rationale: C for cost.
P price per person.
C= 3*P
C=4*P-160
Substituting the value of P from the first equation onto the second we get P = 160.
Plugging in the value of P in the first equation, we get C= 480. Which leads us to answer choice C
Answer: C
Question: A boat goes 100 km downstream in 10 hours, and 75 m upstream in 15 hours. The speed of the stream is?
Options:
A)27 1/2 kmph
B)22 1/2 kmph
C)32 1/2 kmph
D)22 1/1 kmph
E)22 5/2 kmph
Rationale: 100 --- 10 DS = 10
? ---- 1
75 ---- 15 US = 5
? ----- 1 S = (10 - 5)/2
= 22 1/2 kmph
Answer: B
Answer: B
Question: Winners will be announced the following day at 11 AM Pacific/1 PM Eastern Time.
If A, X, Y, and Z are unique nonzero digits in the equation:
XY
*YX
____
AYZ
And Y > X, the 2-digit number XY = ?
Options:
A)13
B)21
C)22
D)24
E)25
Rationale: The reasoning is as follows:-
B) can't be answer because Y<X
D) can't be answer because it XY x YX will give 4 digit number. Thus wrong
E) can't be answer because it XY x YX will give 4 digit number. Thus wrong
A) can't be answer because it XY x YX will give 3 digit number but the middle digit will not be equal to Y. Thus wrong
C) is the correct answer because Y>xwill give 2 digit numbermiddle digit is Y
C
Answer: C
Question: If x and y are positive odd integers, then which of the following must also be an odd integer?
I. x^(y+1)
II. x(y+1)
III. (y+1)^(x-1) + 1
Options:
A)I only
B)II only
C)III only
D)I and III
E)None of the above
Rationale: I. x^(y+1)>> (odd)^even=odd
II. x(y+1)>>(odd)*even=even
III. (y+1)^(x-1) + 1>>(even)^even+1>>even+1>> odd if x is not equal to 1 and if x=1 then its (even)^0+1=1+!=2 even.
answer A
Answer: A
Question: Sonika deposited Rs.8000 which amounted to Rs.9200 after 3 years at simple interest. Had the interest been 0.5% more. She would get how much?
Options:
A)9320
B)96288
C)26667
D)1662
E)2882
Rationale: (8000*3*0.5)/100 = 120
9200
--------
9320
Answer:A
Answer: A
Question: Car A runs at the speed of 100km/hr & reaches its destination in 5hr. Car B runs at the speed of 80 km/h & reaches its destination in 6h. What is the respective ratio of distances covered by Car A & Car B?
Options:
A)11 : 5
B)11 : 8
C)13 : 7
D)25 : 24
E)16 : 9
Rationale: Sol. Distance travelled by Car A = 100 × 5 = 500 km
Distance travelled by Car B = 80 × 6 = 480 km
Ratio = 500/480 = 25 : 24
Answer : D
Answer: D
Question: The average of first 14 even numbers is?
Options:
A)10
B)11
C)12
D)13
E)15
Rationale: Sum of 14 even numbers = 14 * 15 = 210
Average =210/14= 15
ANSWER:E
Answer: E