divelab/Sys2Bench huggingface dataset:
Question: Vishal invested 10% more than Trishul. Trishul invested 10% less than Raghu. If the total sum of their investments is Rs. 6069, how much amount did Raghu invest ?
Options:
A)1287
B)2887
C)2100
D)1129
E)1192
Rationale: Let money invested by Raghu = Rs. x
Money invested by Trishul = 9/10 x = 0.9x
Money invested by Vishal = 9/10x * 110/100 = 0.99x
Also, x+0.9x+0.99x = 6069
= x= 6069/2.89 = 2100
Therefore, amount invested by Raghu is Rs. 2100.
Answer: C
Answer: C
Question: If xy=4, x/y=16, for positive numbers x and y, y=?
Options:
A)1/2
B)2
C)1/3
D)3
E)1/6
Rationale: Very easy question. 2 variables and 2 easy equations.
xy=4 ---> x=4/y - (i)
x/y=16 ---> replacing (i) here ---> 4/(y^2)=16 ---> y^2=4/16=1/4 ---> y=1/2 or -1/2
The question states that x and y are positive integers. Therefore, y=1/2 is the answer.
Answer A.
Answer: A
Question: A theater box office sold an average (arithmetic mean) of 63 tickets per staff member to a particular movie. Among the daytime staff, the average number sold per member was 78, and among the evening staff, the average number sold was 60. If there are no other employees, what was the ratio of the number of daytime staff members to the number of evening staff members?
Options:
A)2:3
B)1:4
C)1:5
D)6:11
E)4:7
Rationale: Deviation from the mean for the daytime staff = 78 - 63 = 15.
Deviation from the mean for the evening staff = 63 - 60 = 3.
Thus, the ratio of the number of daytime staff members to the number of evening staff members is 3:15 = 1:5.
The answer is C.
Answer: C
Question: A boy has 9 trousers and 9 shirts. In how many different ways can he select a trouser and a shirt?
Options:
A)100
B)81
C)104
D)94
E)110
Rationale: The boy can select one trouser in nine ways.
The boy can select one shirt in 12 ways.
The number of ways in which he can select one trouser and one shirt is 9 * 9 = 81 ways.
B
Answer: B
Question: When a jogger moves at an average speed of 6 kmph, they reach their destination on time. When their average speed becomes 4 kmph, they reach their destination 15 minutes late. Find the length of journey.
Options:
A)3 km
B)5 km
C)7 km
D)6 km
E)None
Rationale: Sol.
Difference between timings = 15 min = 1/4 hr.
Let the length of journey be x km.
Then, x/4 - x/6 = 1/4
â‡” 3x - 2x = 3
â‡” x = 3 km.
Answer A
Answer: A
Question: The average of 100,200,300 and x is 250 and the average of 300,150,100,x and y is 200. What is the value of y?
Options:
A)100
B)150
C)50
D)200
E)250
Rationale: We have : (100+200+300+x) /4 = 250
600+x = 1000
x = 400
(300+150+100+x+y)/5 = 200
550+400+y = 1000
y = 50
Answer is C
Answer: C
Question: An express traveled at an average speed of 200 km/hr, stopping for 3 min after every 125 kn. How long did it take to reach its destination 800 km from the starting point?
Options:
A)5 hrs 21 min
B)4 hrs 18 min
C)6 hrs 41 min
D)6 hrs 21 min
E)4 hrs 34 min
Rationale: B
4 hrs 18 min
Time taken to cover 800 km = 800/200 = 4 hrs.
Number of stoppages = 800/125 - 1 = 6
Total time of stoppages = 3 * 6 = 18 min
Hence, total time taken = 4 hrs 18 min.
Answer: B
Question: A rower whose speed is 6 km/hr in still water rows to a certain point upstream and back to the starting point in a river which flows at 3 km/hr. What is the rower's average speed (in km/hr) for the total journey?
Options:
A)3.9
B)4.2
C)4.5
D)4.8
E)5.1
Rationale: time upstream = d / 3
time downstream = d / 9
total time = d/3 + d/9 = 4d/9
average speed = 2d / (4d/9) = 4.5 km/hr
The answer is C.
Answer: C
Question: How many two digit numbers of distinct digits can be formed by using digits 1, 2, 3, 4, 5 and 6 such that the numbers are divisible by 9?
Options:
A)1
B)2
C)4
D)6
E)8
Rationale: CONCEPT: A number will be divisible by 9 if sum of all the digits of the number is divisible by 9
Here the Possible sum of the two distinct digits can be 9 only in order to satisfy the given condition
If sum of Digits = 9, No. =36, 45, 54, 63 --- 4 Cases
Answer: option C
Answer: C
Question: In how much time will a train of length 100 m, moving at 36 kmph cross an electric pole?
Options:
A)17 sec
B)14 sec
C)78 sec
D)10 sec
E)12 sec
Rationale: Convert kmph to mps. 36 kmph = 36 * 5/18 = 10 mps.
The distance to be covered is equal to the length of the train.
Required time t = d/s = 100/10 = 10 sec.
Answer:D:
Answer: D
Question: A certain team consists of 4 professors and 6 teaching assistants. How many different teams of 3 can be formed in which at least one member of the group is a professor? (Two groups are considered different if at least one group member is different.)
Options:
A)48
B)100
C)120
D)288
E)600
Rationale: The groups can be formed as
PTT + PPT + PPP where P=professor and T=Teaching assistant
Number of different teams of 3 can be formed in which at least one member of the group is a professor
= 4C1* 6C2 + 4C2*6C1 + 4C3
= 4!/3! * 6*5/2 + 4*3/2 * 6 + 4
=60 +36 + 4
=100
Answer B
Answer: B
Question: What is the probability that the sum of two dice will yield a 7, and then when both are thrown again, their sum will again yield a 7? assume that each die has 6 sides with faces numbered 1 to 6.
Options:
A)1/144
B)1/36
C)1/12
D)1/6
E)1/3
Rationale: In order to get the sum of the two dices to be 7, there are six combinations that satisfy this requirement.
1+6=7
2+5=7
3+4=7
4+3=7
5+2=7
6+1=7
Each combination has 1/36 of probability of occurrence, or in total 6/36 for the six combinations, which is 1/6.
In order to get the probability of this occurring twice in a row we multiply 1/6 *1/6 and we get 1/36.
The answer is B.
Answer: B
Question: In a sample of 800 high school students in which all students are either freshmen, sophomores, juniors, or seniors, 27 percent are juniors and 75 percent are not sophomores. If there are 160 seniors, how many more freshmen than sophomores are there among the sample of students?
Options:
A)12
B)18
C)24
D)30
E)36
Rationale: 200 are sophomores.
The number of freshmen is 600 - 160 - 0.27(800) = 224
The answer is C.
Answer: C
Question: If x and y are nonnegative integers, both less than or equal to 2, then we say that (x; y) is a
friendly point. Compute the number of unordered triples of friendly points that form triangles
with positive area.
Options:
A)32
B)45
C)67
D)76
E)82
Rationale: There are
(9
3)= 84 unordered triples of friendly points. Instead of trying to count
the triples that yield triangles with positive area, we count the ones which have zero area. These
form line segments, of which there are 8 (three vertical, three horizontal, two diagonal), giving
us 76 desired unordered triples.
correct answer D
Answer: D
Question: If 15% of 30% of 50% of a number is 99, then what is the number?
Options:
A)4000
B)3050
C)4400
D)4500
E)None of these
Rationale: Let the number be a
Given, 15/100 * 30/100 * 50/100 * a = 99
=> 3/20 * 3/10 * 1/2 * a = 99
=> a = 10 * 20 * 10 * 2 = 4400.
ANSWER:C
Answer: C
Question: The ratio of the number of red cars in a certain parking lot to the number of black cars is 3 to 8. If there are 52 black cars in the lot, how many red cars are there in the lot?
Options:
A)11
B)20
C)24
D)27
E)32
Rationale: B is correct
R/B = 3/8 and B =52
R = 52*3/8 = 20
Answer: B
Question: The original price of a suit is $200. The price increased 20%, and after this increase, the store published a 20% off coupon for a one-day sale. Given that the consumers who used the coupon on sale day were getting 20% off the increased price, how much did these consumers pay for the suit?
Options:
A)$192
B)$198
C)$200
D)$208
E)$216
Rationale: 0.8*(1.2*200) = $192
The answer is A.
Answer: A
Question: Ramu bought an old car for Rs. 42000. He spent Rs. 13000 on repairs and sold it for Rs. 64900. What is his profit percent?
Options:
A)19%
B)68%
C)18%
D)48%
E)64%
Rationale: Total CP = Rs. 42000 + Rs. 13000
= Rs. 55000 and SP = Rs. 64900
Profit(%) = (64900 - 55000)/55000 * 100
= 18%
Answer:C
Answer: C
Question: Look at this series: 52, 49, 54, 51, 56, 53, ... What number should come next?
Options:
A)58
B)60
C)52
D)50
E)62
Rationale: Explanation:
In this simple alternating subtraction and addition series; 3 is subtracted, then 5 is added, and so on.
Answer: Option A
Answer: A
Question: A shopkeeper expects a gain of 22.5% on his cost price. If in a week, his sale was of Rs. 392, what was his profit?
Options:
A)Rs. 64
B)Rs. 69
C)Rs.72
D)Rs.75
E)Rs.90
Rationale: C.P. = Rs. (100/122.5)x392
= Rs. (1000/1225)x392
= Rs. 320
Profit = Rs. (392 - 320) = Rs. 72.
Answer:C
Answer: C
Question: A clock is started at noon. By 10 minutes past 5, the hour hand has turned through
Options:
A)145 d
B)150 d
C)160 d
D)155 d
E)165 d
Rationale: Angle traced by hour hand in 12 hrs = 360Âº.
5 hrs 10min = 31/6hrs = (360/12*31/6) = 155
ANSWER D
Answer: D
Question: In a division sum, the divisor is ten times the quotient and five times the remainder. If the remainder is 56, the dividend is:
Options:
A)5324
B)6334
C)7896
D)8356
E)8400
Rationale: Divisor = (5 * 56) = 280
= 10 * Quotient = Divisor
=> Quotient = 280/10 = 28
Dividend = (Divisor * Quotient) + Remainder
Dividend = (280 * 28) + 56 = 7896.
C
Answer: C
Question: When n is divided by 5 the remainder is 3. What is the remainder when (n + 1)^2 is divided by 5?
Options:
A)0
B)1
C)2
D)3
E)4
Rationale: n = 5x+3, for some integer x
(n+1)^2=(5x+4)^2=5y+16, for some integer y
When we divide this by 5, the remainder is 1.
The answer is B.
Answer: B
Question: Coins are to be put into 8 pockets so that each pocket contains at least one coin. At most 4 of the pockets are to contain the same number of coins, and no two of the remaining pockets are to contain an equal number of coins. What is the least possible number of coins needed for the pockets?
Options:
A)7
B)18
C)17
D)22
E)28
Rationale: Since at most 3 of the pockets are to contain the same number of coins then minimize # of coins in each, so let each contain just 1 coin;
Next, we are told that no two of the remaining 4 pockets should contain an equal number of coins, so they should contain 2, 3, 4, and 5 coins each (also minimum possible);
Total: 1+1+1+1+2+3+4+5=18
Answer: B
Answer: B
Question: What is the greatest prime factor of 1+2+3+。。。+52?
Options:
A)53
B)29
C)31
D)37
E)41
Rationale: find the sum from direct formula = n(n+1)/2 = 52(52+1)/2 = 26*53...
53 is a PRIME number, so ans is 53..
A is the answer
Answer: A
Question: The ratio, by volume, of soap to alcohol to water in a certain solution is 4:20:60. The solution will be altered so that the ratio of soap to alcohol is doubled while the ratio of soap to water is halved. If the altered solution will contain 100 cubic centimeters of alcohol, how many cubic centimeters of water will it contain?
Options:
A)1200
B)1250
C)1300
D)1400
E)1450
Rationale: soap:alcohol
Initial ratio soap:alcohol: water --> 4:20:60
Initial soap:alcohol = 4/20 =4:20
after doubled soap:alcohol =2* 4/20 = 8:20
Initial soap:water = 4/60=4:60
after halved soap:water: 1/2 * 4/60 = 2/60 = 2:60
After soap: alcohol:water --> 8:20:240-->2:5:60
given alcohol 100 cubic centimeter.
ratio is 40:100:1200(2:5:60)
For 100 cubic centimeter of Alcohol --- 1200cubic cm water is required.
Answer: A
Question: The food in a camp lasts for 10 men for 50 days. If 10 more men join, how many days will the food last?
Options:
A)22 days
B)25 days
C)50 days
D)16 days
E)17 days
Rationale: one man can consume the same food in 10*50 = 500 days.
10 more men join, the total number of men = 20
The number of days the food will last = 500/20 = 25 days.
Answer:B
Answer: B
Question: if x+y+z=9 and both y and z are positive integers greater than zero, then the maximum value x can take is?
Options:
A)7
B)3
C)8
D)6
E)data insufficient
Rationale: if y=z=1, then x will be equal to 7.
ANSWER:A
Answer: A
Question: In a class there are 20 boys and 22 girls. In how many ways can a boy and a girl be selected?
Options:
A)508
B)440
C)800
D)570
E)503
Rationale: We can select one boy from 20 boys in 20 ways.
We select one girl from 22 girls in 22 ways
We select a boy and girl in 20 * 22 ways i.e., = 440 ways.
Answer:B
Answer: B
Question: In a dairy farm, 30 cows eat 30 bags of husk in 30 days. In how many days one cow will eat one bag of husk?
Options:
A)1
B)40
C)20
D)26
E)30
Rationale: Explanation :
One bag of husk = 30 cows per day
⇒ 30 × 1 × 30 = 1 × 30 × x
For one cow = 30 days
Answer : E
Answer: E
Question: The L.C.M of two numbers is 495 and their H.C.F is 5. If the sum of the numbers is 10, then their difference is
Options:
A)10
B)46
C)70
D)90
E)None
Rationale: Solution
Let the numbers be x and (100 - x) .
Then, x (100 - x) = 5 ×495
‹=›x2 - 100x + 2475 = 0.
‹=› (x -55) (x - 45) = 0.
x = 55 or x = 45.
Therefore, the numbers are 45 and 55.
Required difference = (55 - 45) = 10.
Answer A
Answer: A
Question: If -2<= x <= 2 and 3 <= y <= 10, which of the following represents the range of all possible values of y-x?
Options:
A) 5 <= y-x <= 6
B) 1 <= y-x <= 12
C) 1 <= y-x <= 6
D) 5 <= y-x <= 10
E) 1 <= y-x <= 10
Rationale: Maximum value of y-x= 10 - (-2)= 12
Minimum value of y-x= 3-2= 1
B mentions the correct range
Answer: B
Question: 5 friends visited a fruit stall, and everyone decided to contribute equally to the total bill of $100. If one of the friends had a coupon for 6% off the total bill, and if each friend still contributed equally after the coupon was applied to the bill, how much did each friend pay?
Options:
A)18
B)18.8
C)19
D)17.8
E)17.9
Rationale: At the non-discounted price, each friend would pay $20, as $100 divided by 5 friends is $20 per friend. But if the bill is 6% off, then each friend would pay 6% less. 6% of $20 is $1.2, so each friend saves $1.2 and pays the remaining 18.8
CORRECT OPTION:OPTION B
Answer: B
Question: Dan can do a job alone in 15 hours. Annie, working alone, can do the same job in just 10 hours. If Dan works alone for 12 hours and then stops, how many hours will it take Annie, working alone, to complete the job?
Options:
A)2
B)4
C)6
D)8
E)10
Rationale: Dan can complete 1/15 of the job per hour.
In 12 hours, Dan completes 12(1/15) = 4/5 of the job.
Annie can complete 1/10 of the job per hour.
To complete the job, Annie will take 1/5 / 1/10 = 2 hours.
The answer is A.
Answer: A
Question: A positive number x is multiplied by 3, and this product is then divided by 3. If the positive square root of the result of these two operations equals x, what is the value of x ?
Options:
A) 9/4
B) 3/2
C) 4/3
D) 2/3
E) 1/2
Rationale: We need to produce an equation from the information given in the problem stem. We are first given that x is multiplied by 2 and then the product is divided by 3. This gives us:
2x/3
Next we are given that the positive square root of the result (which is 2x/3) is equal to x. This gives us
√(2x/3) = x
2x/3 = x^2
2x = 3x^2
3x^2 – 2x = 0
x(3x – 2) = 0
x = 0 or
3x – 2 = 0
3x = 2
x =4/3
Because x is positive, x = 4/3. The answer is C.
Answer: C
Question: How many zeros does 10! end with?
Options:
A)10
B)4
C)4
D)3
E)2
Rationale: According to above 10! has 10/5=2=2 trailing zeros.
Answer: E
Answer: E
Question: Find the average of the series : 312, 162, 132, 142 and 122?
Options:
A)299
B)268
C)276
D)299
E)174
Rationale: Average
= (312 + 162 + 132 + 142 + 122)/5
= 870/5
= 174
Answer: E
Answer: E
Question: If the sum of 1/3 and 1/5 is converted to a decimal, what is the 3000th digit to the right of the decimal place?
Options:
A)2
B)3
C)5
D)8
E)9
Rationale: 1/3 +1/5 =0.5333333...
hence, the 3000th digit would also be 3
Ans: B
Answer: B
Question: On the xy-plane, each point on circle C has coordinates such
that x 0 and y 0. If the center of circle C is the point (3; 7),
what is the maximum possible area of C?
Options:
A) 6
B) 9
C) 24
D) 32
E) 64
Rationale: I think that theintentof this question is that the circle will have NO CO-ORDINATES that fit the following 2 forms: (0, Y) or (X, 0). In real basic terms, this circle will NEITHER touch (nor cross) the X-axis NOR will it touch (nor cross) the Y-axis.
With a center at (3,8), the longest possible radius would ALMOST touch the X-axis, so the radius would be a little less than 3.
If the radius WAS 3 exactly, then the area would be 9pi, which is approximately 28.26
Since the circle CAN'T touch the X-axis, the area has to be LESS than approximately 28.26
As it's written, none of the answers is clearly the correct one.
C
Answer: C
Question: what is the sum of all even integers between 99 and 301?
Options:
A)20200
B)20000
C)40400
D)40000
E)44000
Rationale: a=100,tn=300
a+(n-1)d=300=>n=101
Sn=n/2(a+l)=101/2(100+300)
Sn=20200
ANSWER:A
Answer: A
Question: The C.I. on a certain sum for 2 years at 10% per annum is Rs. 525. The S.I. on the same sum for double the time at half the rate percent per annum is?
Options:
A)238
B)500
C)287
D)197
E)172
Rationale: Explanation:
Let the sum be Rs. P. Then,
[P(1 + 10/100)2 - p] = 525
P[(11/10)2 - 1] = 525
P = (525 * 100) / 21 = 2500
Sum = Rs. 2500
So, S.I. = (2500 * 5 * 4)/100 = Rs. 500
Answer:B
Answer: B
Question: Find the total number of prime factors in the expression (4)^11 x (7)^5 x (11)^3
Options:
A)26
B)22
C)25
D)30
E)29
Rationale: (4)^11x (7)^5 x (11)^3
= (2 x 2)^11 x (7)^5 x (11)^3
= 2^11 x 2^11 x7^5x 11^3
= 2^22 x 7^5 x11^3
Total number of prime factors = (22 + 5 + 3) = 30.
Answer is D.
Answer: D
Question: How many odd numbers are possible between 1 to 100000? find out the number of odd number of digits?
Options:
A)2999
B)3500
C)4000
D)4599
E)49999
Rationale: There are always one odd and one even no. And the question is odd no. Between 1 to 100000
So we have to find no. Between 1 to 100000 so we should not includes 1
100000/2 -1=49999
ANSWER:E
Answer: E
Question: On a scale of map, 0.4 cm represents 5.3 km. If the distance between the points on the map is 64 cm, the actual distance between these points is:
Options:
A)9 km
B)72.5 km
C)190.75 km
D)848 km
E)None of these
Rationale: Explanation :
Let the actual distance be x km. Then,
More distance on the map, More is the actual distance (Direct Proportion)
=> 0.4 : 64 :: 5.3 : x
=> 0.4x = 64 x 5.3
=> x = 64 x 5.3 /0.4
=> x = 848
Answer : D
Answer: D
Question: If three sides of the triangle are 8 , 15 and S respectively then the how many values can S ?
Options:
A)[A] 6
B)[B] 7
C)[C] 8
D)[D]9
E)[E] infinite number of values
Rationale: Needed: How many Values can S take
Concept: Sum of any two sides of a triangle is greater then the third side.
Case 1: 8+5 > S => S<13
Case 2: 5+S > 8 => S >3
Case 3: 8+S > 5 =>S > -3 (Always true since S is one side of a Triangle)
Finally, 3 < S < 13. So, we can have infinite number of sides between 3 and 13.
Answer = E
PS: If question said S can take only integer value, the S = 9. Answer choice D.
Answer: D
Question: A three-digit code for certain locks uses the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 according to the following constraints. The first digit cannot be 0 , 1 or 3, the second digit must be 0 or 1, and the second and third digits cannot both be 0 in the same code. How many different codes are possible?
Options:
A)144
B)142
C)160
D)168
E)176
Rationale: The first digit can be filled in 8 ways
For second digit , it can either be 0 or 1 or 3
Case 1 -
If second digit is 1 ,Third digit can take 10 values
number of codes = 7 * 1 * 10 = 70
Case 2 -
If second digit is 0,Third digit can take 9 values ( Third digit can't be zero)
number of codes = 8 * 1 * 9= 72
Total number of codes = 142
Answer B
Answer: B
Question: A paper is in a square form whose one side is 20 cm. Two semi circles are drawn on its opposites as diameters. If these semi circles are cut down what is the area of the remaining paper?
Options:
A)8.76
B)8.79
C)8.75
D)8.78
E)8.71
Rationale: (5 * 3.5)/2
= 8.75
Answer:C
Answer: C
Question: Donald has five different kinds of fruit to choose from at the grocery store. How many ways can he buy one or more types of fruit?
Options:
A)125
B)54
C)43
D)31
E)29
Rationale: Donald needs to buy one or more types of fruit out of five types
=> 2^5 - 1 = 31
Answer: D
Question: What is the unit digit in (4137)^754?
Options:
A)9
B)11
C)12
D)13
E)15
Rationale: Unit digit in (4137)754 = Unit digit in {[(4137)4]188 x (4137)2}
=Unit digit in { 292915317923361 x 17114769 }
= (1 x 9) = 9
A)
Answer: A
Question: The average of five numbers is 27. If one number is excluded, the average becomes 25. The excluded number is?
Options:
A)12
B)72
C)23
D)35
E)28
Rationale: Excluded number = (27 * 5) - (25 * 4)
= 135 - 100
= 35.
Answer: D
Answer: D
Question: A rectangular football field is fenced on all four sides. The length of the football field is 3 times the length of its breadth. The cost of fencing the field was $360. The football management has decided to change the dimensions of field by increasing the breadth by 50% of its original value and reducing the length by 25% of its original value and fence the field again.. What will be the cost of the new fencing?
Options:
A)$360
B)$180
C)$425
D)$337.5
E)$415
Rationale: Let's take x to be the breadth. Then the length of the football field is 3x.
The perimeter of the old football field is x + 3x + x + 3x = 8x.
Now, for the new football field:
The new breadth = 1.5 times old breadth = 1.5x
The new length is 0.75 times old length = (.75)3x = 2.25x
So the new perimeter is 1.5x + 2.25x + 1.5x + 2.25x = 7.5 x.
for old perimeter rate is $360
For new perimeter = (360 * 7.5)/8
= 337.5
Ans - D
Answer: D
Question: Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:
Options:
A)3 : 1
B)3 : 2
C)3 : 4
D)3 : 5
E)3 : 28
Rationale: Let the speeds of the two trains be x m/sec and y m/sec respectively. Then, length of the first train = 27 x meters, and length of the second train = 17 y meters. (27 x + 17 y) / (x + y) = 23 ==> 27 x + 17 y = 23 x + 23 y ==> 4 x = 6 y ==> x/y = 3/2.
Answer: B
Answer: B
Question: REDO’s manufacturing costs for sets of horseshoes include a $10,000 initial outlay, and $20 per set. They can sell the sets $50. If profit is revenue from sales minus manufacturing costs, and the company producessells 500 sets of horseshoes, what was their profit?
Options:
A)$4500
B)$3500
C)$5500
D)$5000
E)$6300
Rationale: Total Manufacturing cost = 10000+500*20 = 20000
Total Selling cost = 500*50= 25000
Profit = 25000-20000 = 5000
Answer : D
Answer: D
Question: A trader sells 80 meters of cloth for Rs. 6900 at the profit of Rs. 20 per metre of cloth. What is the cost price of one metre of cloth?
Options:
A)22
B)75
C)90
D)78
E)66
Rationale: SP of 1m of cloth = 6900/80 = Rs. 86
CP of 1m of cloth = SP of 1m of cloth - profit on 1m of cloth
= Rs. 86 - Rs. 20 = Rs. 66.
Answer: E
Answer: E
Question: Which smallest prime number is:
Options:
A)22
B)28
C)32
D)42
E)19
Rationale: E
19
Answer: E
Question: The average age of 8 men increases by 2 years when two women are included in place of two men of ages 20 and 24 years. Find the average age of the women?
Options:
A)30
B)35
C)32
D)40
E)46
Rationale: 20 + 24 + 8 * 2 = 60/2 = 30
ANSWER A
Answer: A
Question: A dealer offers a cash discount of 10% and still makes a profit of 20% when he further allows 45 articles to be sold at the cost price of 40 articles to a particular sticky bargainer. How much percent above the cost price were his articles listed?
Options:
A)40%
B)50%
C)55%
D)80%
E)90%
Rationale: Given
Cash Discount - 10%
Profit - 20%
Items Sold - 45
Price Sold at = List Price of 40
Assume List price = $10
Total Invoice = $400
-10% Cash Discount = $360
Let cost price of 45 items be x
So total cost = 45*x
Given the shopkeeper had a profit of 20%
45 * x * 120/100 = 360
or x = $20/3=$6+(2/3)
Which means his products were listed at $10 which is a 50% markup over $6+(2/3)
Answer B
Answer: B