divelab/Sys2Bench huggingface dataset:
Question: At an M&M factory, two types of M&Ms are produced, red and blue. The M&Ms are transported
individually on a conveyor belt. Anna is watching the conveyor belt, and has determined that
four out of every five red M&Ms are followed by a blue one, while one out of every six blue
M&Ms is followed by a red one. What proportion of the M&Ms are red?
Options:
A)1/29
B)2/29
C)3/29
D)4/29
E)5/29
Rationale: Suppose that the fraction of red M&Ms is fr and the fraction of blue M&Ms
is fb. Then the probability that Anna sees a red one emerge next is fr. This probabil-
ity can also be expressed using conditional probabilities as fr = P(blue)P(red after blue) +
P(red)P(red after red), or fr = fb(1=6) + fr(1=5). Likewise, we find fb = fr(4=5) + fb(5=6).
Solving the system of equations gives fb = 24
29 and fr =5/29
correct answer E
Answer: E
Question: If 5x + 3 = 10x – 22, what is the value of x?
Options:
A)1
B)2
C)3
D)4
E)5
Rationale: solve for x:
5x+3=10x-22
25=5x
5=x
correct answer E)5
Answer: E
Question: If each term in the sum R=a1+a2+a3+...+an either 2 or 22 and the sum equals 100, which of the following could be equal to n?
Options:
A)38
B)39
C)40
D)41
E)42
Rationale: Min value of 'n' can be 10 i.e 4*22+6*12=R => 22+22+22+22+2+2+2+2+2+2 = 100
Since we don't have 10 in the options proceed further, (10-1)+22/2 => 20 digits, which is again not in the options
(20-1) + 22/2 = 30 digits ( not in options)
(30-1) + 22/2 = 40 digits
Hence C.
Answer: C
Question: The population of locusts in a certain swarm doubles every two hours. If 4 hours ago there were 1,000 locusts in the swarm, in approximately how many hours will the swarm population exceed 32,000 locusts?
Options:
A)2
B)4
C)6
D)8
E)9
Rationale: - 4 hours: 1,000
-2 hours: 2,000
Now: 4,000
+ 2 hours: 8,000
+ 4 hours: 16,000
+ 6 hours: 32,000
Answer : C
Answer: C
Question: The price of a book is increased from $300 to $330. What is the % of increase in its price?
Options:
A)10%
B)20%
C)30%
D)35%
E)45%
Rationale: Explanation: Change in the price = Rs 330 – Rs 300
= Rs 30
Percentage of increase = Change in the price Initial Price
* 100.
Percentage increase in price =( 30 / 300
) *100 = 10%
A
Answer: A
Question: The 44 parents participating in the Smithville PTA have been assigned to at least 1 of 3 committees: festival planning, classroom aid, and teacher relations. 21 parents are assigned to the festival planning committee, 18 parents are assigned to the classroom aid committee, and 19 parents are assigned to the teacher relations committee. If 5 parents are assigned to all 3 committees, how many parents are assigned to exactly 2 committees?
Options:
A)4
B)6
C)8
D)9
E)10
Rationale: The formula is Total = A+B+C - sum of exactly two + 2*all three + neither
21+18+19-x-2*5=44
solving for x you get 4
Answer A
Answer: A
Question: A and B together can do a piece of work in 2 days. If A alone can do the same work in 22 days, then B alone can do the same work in?
Options:
A)0.35 days
B)0.45 days
C)0.55 days
D)0.25 days
E)0.15 days
Rationale: B = 1/2 – 1/22 =0.45 days
ANSWER:B
Answer: B
Question: A farmer wishes to start a 100 sq. m. rectangular vegetable garden. Since he has only 30 meter barbed wire, he fences three sides of the garden letting his house compound wall act as the fourth side fencing. Then find the dimension of the garden.
Options:
A)20 m * 58 m
B)20 m * 7 m
C)20 m * 5 m
D)80 m * 5 m
E)20 m * 1 m
Rationale: From the question, 2b+l = 30
=> l = 30-2b
Area=100m2=>l×b=100=>b(30−2b)=100b2−15b+50=0=>(b−10)(b−5)=0
Area=100m2=>l×b=100=>b(30−2b)=100b2−15b+50=0=>(b−10)(b−5)=0
b = 10 or b = 5
when b = 10 then l = 10
when b = 5 then l = 20
Since the garden is rectangular so we will take value of breadth 5.
So its dimensions are 20 m * 5 m
Answer: C
Answer: C
Question: The length of the bridge, which a train 130 meters long and travelling at 45 km/hr can cross in 30 seconds, is?
Options:
A)27
B)82
C)245
D)288
E)232
Rationale: Speed = (45 * 5/18) m/sec = (25/2) m/sec. Time = 30 sec. Let the length of bridge be x meters. Then, (130 + X)/30 = 25/2 ==> 2(130 + X) = 750 ==> X = 245 m.
Answer:C
Answer: C
Question: A, B and C invest in a partnership in the ratio: 7/2, 4/3, 6/5. After 4 months, A increases his share 50%. If the total profit at the end of one year be Rs. 27,000, then what is B's share in the profit?
Options:
A)Rs. 2000
B)Rs. 3000
C)Rs. 4000
D)Rs. 5000
E)None of these
Rationale: Explanation :
Ratio of the initial investment = 7/2 : 4/3 : 6/5
= 105 : 40 : 36
From this ratio, we can assume that actual initial investments of A, B and C
are 105x, 40x and 36x respectively
A increases his share 50% after 4 months. Hence the ratio of their investments =
(105x * 4) + (105x * 150/100 * 8) : 40x * 12 : 36x : 12
= 105 + (105 * 3/2 * 2) : 40*3 : 36 * 3
= 105 * 4 : 40 *3 : 36 * 3
= 35 * 4 : 40 : 36
= 35 : 10 : 9
B's share = total profit * (10/54) = 27,000 * 10/54 = 5000. Answer : Option D
Answer: D
Question: A polling company surveyed a certain country, and it found that 35% of that country’s registered voters had an unfavorable impression of both of that state’s major political parties and that 20% had a favorable impression only of Party A. If one registered voter has a favorable impression of both parties for every two registered voters who have a favorable impression only of Party B, then what percentage of the country’s registered voters have a favorable impression of both parties (assuming that respondents to the poll were given a choice between favorable and unfavorable impressions only)?
Options:
A)15
B)20
C)30
D)35
E)45
Rationale: Assume the total pool of registered voters = 100, so 35 of the country’s registered voters had an unfavorable impression of both of that state’s major political parties and 20 had a favorable impression only of Party A
let x = # of voters with a favorable impression of both parties
let 2x = # of voters with a favorable impression only of Party B
so unfavorable A and favorable B # of voters = 2x-x = x
35+x = number of unfavorable A
20+ 35+x = 100
55+x=100
x=45
ANSWER:E
Answer: E
Question: In 16 minutes, the minute hand gains over the hour hand by
Options:
A)16°
B)80°
C)88°
D)96°
E)None of these
Rationale: In 1 hour, the minute hand gains 330° over the hour hand.
i.e. in 60 minute, the minute hand gains 330° over the hour hand.
∴ In 16 minutes, the minute hand gains over the hour hand by 330°⁄60 × 16° = 88°
Answer C
Answer: C
Question: A, B and C play a cricket match. The ratio of the runs scored by them in the match is A:B = 2:3 and B:C = 2:5. If the total runs scored by all of them are 75, the runs scored by B are?
Options:
A)11
B)18
C)19
D)12
E)15
Rationale: A:B = 2:3
B:C = 2:5
A:B:C = 4:6:15
6/25 * 75 = 18
Answer: B
Answer: B
Question: A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
Options:
A)10 days
B)12 days
C)15 days
D)20 days
E)25 days
Rationale: A's 2 day's work = 1	x 2 =	1	.
20	10
(A + B + C)'s 1 day's work = 1	+	1	+	1 =	6	=	1	.
20	30	60	60	10
Work done in 3 days = 1	+	1 =	1	.
10	10	5
Now,	1	work is done in 3 days.
5
Whole work will be done in (3 x 5) = 15 days.
Option C
Answer: C
Question: What is the greatest positive integer E such that 3^E is a factor of 9^10?
Options:
A)E=5
B)E=9
C)E=10
D)E=20
E)30
Rationale: What is the greatest positive integer E such that 3^E is a factor of 9^10?
9^10 = (3^2)^10 = 3^20
D. 20
Answer: D
Question: A parking garage rents parking spaces for $10 per week or $35 per month. How much does a person save in a year by renting by the month rather than by the week?
Options:
A) $100
B) $160
C) $220
D) $240
E) $260
Rationale: 10$ per week!
An year has 52 weeks.
Annual charges per year = 52* 10 = 520$
35$ per month!
An year has 12 months.
Annual charges per year = 12 * 35 = 420$
520 - 420 = 100
Ans A
Answer: A
Question: How many arrangements of the letters of the word CONTINUES can be made, without changing the place of the vowels in the word?
Options:
A)130
B)140
C)150
D)120
E)110
Rationale: O,I,E,U fixed. Consonants can be arrangements in 5P5 = 5! = 120 ways
Option 'D'
Answer: D
Question: A train with 120 wagons crosses John who is going in the same direction, in 36 seconds. It travels for half an hour from the time it starts overtaking the John ( he is riding on the horse) before it starts overtaking the Mike(who is also riding on his horse) coming from the opposite direction in 24 seconds. In how much time (in secs) after the train has crossed the Mike do the John meets to Mike?
Options:
A)2534 s
B)5435 s
C)7645 s
D)7456 s
E)3576 s
Rationale: Let the length of the train be L metres and speeds of the train Arun and Sriram be R, A and S respectively, then
---------- (i)
and ---------(ii)
From eq.(i) and (ii)
3(R - A ) = 2 (R + K)
R = 3A + 2K
In 30 minutes (i.e 1800 seconds), the train covers 1800R (distance) but the Arun also covers 1800 A (distance) in the same time. Therefore distance between Arun and Sriram, when the train has just crossed Sriram
= 1800 ( R - A) - 24 ( A + K)
Time required =
= (3600 - 24) = 3576 s
E
Answer: E
Question: A train passes a station platform in 48 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Options:
A)476 m
B)420 m
C)440 m
D)407 m
E)402 m
Rationale: Speed = [54 * 5/18] m/sec
= 15 m/sec.
Length of the train = (15 * 20) m = 300 m.
Let the length of the platform be x meters.
Then, x + 300 / 48 = 15
x + 300 = 720
x =420 m.
Answer: B
Answer: B
Question: What was the day of the week on 17th June 1998?
Options:
A)Monday
B)Sunday
C)Wednesday
D)Friday
E)Tuesday
Rationale: Explanation:
17 Jun 1998 = (1997 years + period from 1-Jan-1998 to 17-Jun-1998)
We know that number of odd days in 400 years = 0
Hence the number of odd days in 1600 years = 0 (Since 1600 is a perfect multiple of 400)
Number of odd days in the period 1601-1900
= Number of odd days in 300 years
= 5 x 3 = 15 = 1
(As we can reduce perfect multiples of 7 from odd days without affecting anything)
Number of odd days in the period 1901-1997
= 73 normal years + 24 leap year
= 73 x 1 + 24 x 2 = 73 + 48 = 121 = (121 - 7 x 17) = 2 odd days
Number of days from 1-Jan-1998 to 17-Jun-1998
= 31 (Jan) + 28 (Feb) + 31 (Mar) + 30 (Apr) + 31(may) + 17(Jun)
= 168 = 0 odd day
Total number of odd days = (0 + 1 + 2 + 0) = 3
3 odd days = Wednesday
Hence 17th June 1998 is Wednesday.
Answer: Option C
Answer: C
Question: If p is an odd integer and q is an even integer, which of the following must be an even integer?
Options:
A)2q-p
B)3p+q
C)2p+3q
D)4(p+q)
E)p+q^2
Rationale: p is odd; for this assume p=1
q is even; for this assume q = 2
(2*2)-1 = 3 Odd
(3*1)+2 = 5 Odd
(2*1)+(3*2) = 9 Odd
4(1+2) = 12 Even
1+(2^2) = 5 Odd
Answer:D
Answer: D
Question: Which of the following cannot be the sum of 2 different prime numbers?
Options:
A)10
B)13
C)14
D)15
E)19
Rationale: Option A: 10 = 7 + 3. Sum of 2 different prime numbers.
Option B: 13 = 11 + 2. sum of 2 different prime numbers
Option C: 4 = This is not a sum of 2 different prime numbers.
Option D: 15 = 13 + 2. Sum of 2 different prime numbers
Option E: 19 = 17 + 2. Sum of 2 different prime numbers
Correct Option: C
Answer: C
Question: A man buys $50 shares in a company which pays 10% dividend. If the man gerts 12.5% on his investment, at what price did he buy the shares?
Options:
A)37.5
B)40
C)50
D)48
E)52
Rationale: Dividend on 1 share = $(10/100*50)
=$5
$12.5 is an income on an investment of $100
$5 is an income on an investment of $(100*2/25*5)=40
Thus, cost of 1 share =$40
ANSWER B
Answer: B
Question: All of the stocks on the over-the-counter market are designated by either a 6-letter or a 7-letter code that is created by using the 26 letters of the alphabet. Which of the following gives the maximum number of different stocks that can be designated with these codes?
Options:
A)a. 2(26^5)
B)b. 26(26^4)
C)c. 27(26^4)
D)d. 26(26^5)
E)e. 27(26^6)
Rationale: no of different stocks for 6-letter code = 26^6
no of different stocks for 7-letter code = 26^7
total = 26^6 + 26^7 = 26^6(26+1) = 27(26^6)
[Reveal]Spoiler:
Option E
Answer: E
Question: There are 418 doctors and nurses in a hospital. If the ratio of the doctors to the nurses is 8 : 11, then how many nurses are there in the hospital?
Options:
A)152
B)209
C)242
D)171
E)181
Rationale: Given,
The ratio of the doctors to the nurses is 8 : 11
Number of nurses = 11/19 x 418 = 242
ANSWER:C
Answer: C
Question: Two-third of two-fifth of three-fourth of a number is 36. What is the square root of four-fifth of that number?
Options:
A)9
B)12
C)14
D)16
E)20
Rationale: Explanation:
We have, 2/3 * 2/5 * 3/4 * X = 36
X = 180
Now, 4/5 * X = 4/5 * 180 = 144
√144 = 12
ANSWER: B
Answer: B
Question: A grocer has a sale of Rs. 5921, Rs. 5468, Rs. 5568, Rs. 6088 and Rs. 6433 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 5900?
Options:
A)4902
B)4922
C)5922
D)5924
E)5928
Rationale: Total sale for 5 months = Rs. (5921 + 5468 + 5568 + 6088 + 6433) = Rs. 29478.
Required sale = Rs. [ (5900 x 6) - 29478 ]
= Rs. (35400 - 29478)
= Rs. 5922.
ANSWER:C
Answer: C
Question: Four packages have an average weight of 14.5 pounds. What is the minimum possible weight of the heaviest package in pounds if the median is 12 pounds?
Options:
A)25
B)24
C)23
D)22
E)21
Rationale: Let us denote the weights of the packages in pounds by a, b, c, d naming from the lightest one to the heaviest one. The median is 12 pounds. Therefore (b + c) / 2 = 12.
b + c = 24
The average is 14.5 pounds. Therefore (a + b + c + d) / 4 = 14.5.
a + (b + c) + d = 58
a + 24 + d = 58
a + d = 34
The weight a must be no greater than 12, since 12 is the median. Therefore the minimum possible weight of the heaviest package is 34 – 12 = 24 pounds (all the other packages would weigh 12 pounds in this case).
Answer: B
Answer: B
Question: The average price of 10 books is Rs.12 while the average price of 8 of these books is Rs.11.75. Of the remaining two books, if the price of one book is 60% more than the price of the other, what is the price of each of these two books?
Options:
A)Rs. 5, Rs.7.50
B)Rs. 8, Rs. 12
C)Rs. 16, Rs. 10
D)Rs. 12, Rs. 14
E)NOne
Rationale: Solution:
Total cost of 10 books = Rs. 120
Total cost of 8 books = Rs. 94
=> The cost of 2 books = Rs. 26
Let the price of each book be x and y.
=> x + y = 26 ---------------- (1)
(160/100)y+y =26
On Solving for y, we get
y = 10.
Now, Substituting y = 10 in (1) we get,
x + 10 = 26
x = 16.
So the price of each book is Rs. 16 and Rs. 10 respectively.
Answer: Option C
Answer: C
Question: If the operation ∆ is defined by a ∆ b = (b - a)^2/a^2 for all numbers a and b, and a ≠ 0, then what is the result when we evaluate this expression: (-4) ∆ (4 ∆ −4) ?
Options:
A)2
B)4
C)6
D)8
E)10
Rationale: (-4) ∆ (4 ∆ −4) =
(-4) ∆ (8^2/4^2) =
(-4) ∆ (4) =
(-8^2) / (-4)^2 = 4
The answer is B.
Answer: B
Question: The probability that A speaks truth is 3/5 and that of B speaking truth is 4/7. What is the probability that they agree in stating the same fact?
Options:
A)18/35
B)18/35
C)18/39
D)18/31
E)18/32
Rationale: If both agree stating the same fact, either both of them speak truth of both speak false.
Probability = 3/5 * 4/7 + 2/5 * 3/7
= 12/35 + 6/35 = 18/35
Answer: A
Answer: A
Question: In a sample of Christ college students, 30 percent are third year students and 90 percent are not second-year students. What fraction of those students who are not third-year students are second-year students?
Options:
A) 3/4
B) 2/3
C) 4/7
D) 1/2
E) 1/7
Rationale: = 10/70. = 1/7
my answer is E too
Answer: E
Question: A monkey climbs 30 feet at the beginning of each hour and rests for a while when he slips back 20 feet before he again starts climbing in the beginning of the next hour. If he begins his ascent at 8.00 a.m., at what time will he first touch a flag at 120 feet from the ground?
Options:
A)4 p.m.
B)5 p.m.
C)6 p.m.
D)7 p.m.
E)None of these
Rationale: A monkey climbs 30 feet at the beginning of each hour and rests for a while when he slips back 20 feet before he again starts climbing in the beginning of the next hour.
It means monkey climbs effectively 10 ft in 1 hr.
so it climbs 90 ft in 9 hrs .
balance 30 ft is covered in 10th hr.
So total it will take 10 hrs.
Monkey will touch 120 ft flag at 8+10 = 1800 hrs or 6 PM.
ANSWER:C
Answer: C
Question: An article costing rs.160 is sold at 15% discount on a mark-up price. What is the selling price after
discount?
Options:
A)106
B)116
C)126
D)136
E)146
Rationale: Rs. 136
160-(160*15/100)=160*85/100=136
ANSWER:D
Answer: D
Question: For dinner at a restaurant, there are x + 1 choices of appetizers, y + 1 main courses, and z choices of dessert. How many total possible choices are there if you choose 1 appetizer, 1 main course, and 1 dessert for your meal?
Options:
A)x + y + z + 1
B)xyz + xz
C)xyz+xz+yz+z
D)xyz + 1
E)xyz + 1/2
Rationale: x +1 appetizers,
y + 1 main courses,
z dessert
Required: 1 appetizer, 1 main course, and 1 dessert
Number of ways possible = (x+1)C1*(y+1)C1*zC1 {NC1 = N! / (N-1)!*1! = N}
Hence, number of ways = (x+1)(y+1)z = (yz+z)(x+1)=xyz+xz+yz+z
Correct Option: C
Answer: C
Question: In a race of length L metres, Johnson beats Lewis by X metres and Greene by Y metres, By how many metres does Lewis beat Greene in the same race ? (X<Y)
Options:
A)L(L-Y) / L-X
B)L(Y-X) / L-X
C)L-Y
D)X-Y
E)X+Y
Rationale: As the time is constant, the ratio of distances will be the same as the ratio of speeds.
If Sj,Sl,Sg are the speeds of Johnson, Lewis, and Greene respectively, then
Sj/Sl = L/(L-X)
and Sj/Sg = L/(L-Y)
=> Sg/Sl = (L-Y)/(L-X)
Therefore the speeds of Lewis and Greene are in the ratio (L-X)/(L-Y)
When Lewis finishes the race, the time run by him and Greene are same
=> The ratio of the speeds of Lewis and Greene will be the same as the ratio of distances run by them.
=> Distance run by Greene when Lewis finishes the race = (L-Y)/(L-X) * L
=> Lewis beats Greene by L - L*(L-Y)/(L-X) = L [ 1 - (L-Y)/(L-X)] = L (Y-X) / (L-X)
Option (B) is therefore correct.
Answer: B
Question: A green grocer received a boxful of tomatoes and on opening the box found that several had gone bad. He then counted them up so that he could make a formal complaint and found that 68 were mouldy, which was 16 per cent of the total contents of the box. How many tomatoes were in the box?
Options:
A)336
B)425
C)275
D)235
E)689
Rationale: B
425
(68 Ã· 16) Ã— 100
Answer: B
Question: Find the perimeter and area of the rectangle of length 15 cm and breadth 13 cm.
Options:
A)71 cm2
B)121 cm2
C)141 cm2
D)195 cm2
E)221 cm2
Rationale: length = 15 cm, breadth = 13 cm
Perimeter of rectangle = 2 (length + breadth)
= 2 (15 + 13) cm
= 2 × 28 cm
= 56 cm
We know that the area of rectangle = length × breadth
= (15 × 13) cm22
= 195 cm2
ANSWER : D
Answer: D
Question: 6 points are marked on a straight line and another 7 points are marked on a second straight line with no points in common. How many triangles can be constructed with vertices from among the above points?
Options:
A)21
B)281
C)168
D)196
E)364
Rationale: Solution: select 2 from 6 and one from 7 + select 2 from 7 and 1 from 6
6C2*7C1 + 7C2*6C1
= 281
Answer : B
Answer: B
Question: A Contractor employed a certain number of workers to finish constructing a road in a certain scheduled time. Sometime later, when a part of work had been completed, he realised that the work would get delayed by three-fourth of the scheduled time, so he at once doubled the no of workers and thus he managed to finish the road on the scheduled time. How much work he had been completed, before increasing the number of workers?
Options:
A)14 9/7 %
B)14 2/7 %
C)14 2/3 %
D)14 2/5 %
E)54 2/7 %
Rationale: Explanation:
Let he initially employed x workers which works for D days and he estimated 100 days for the whole work and then he doubled the worker for (100-D) days.
D * x +(100- D) * 2x= 175x
=> D= 25 days
Now , the work done in 25 days = 25x
Total work = 175x
therefore, workdone before increasing the no of workers = \frac{25x}{175x}\times 100=14\frac{2}{7} %
Answer: B) 14 2/7 %
Answer: B
Question: A train running at the speed of 120 km/hr crosses a pole in 18 seconds. What is the length of the train?
Options:
A)560
B)570
C)580
D)590
E)600
Rationale: Speed=(120 x(5/18)m/sec	=(100/3)m/sec.
Length of the train = (Speed x Time).
Length of the train =	((100/3)x 18)m = 600 m
E
Answer: E
Question: In an examination, 25% of total students failed in Hindi, 40% failed in English and 35% in both. The percentage of these who passed in both the subjects is :
Options:
A)10%
B)20%
C)30%
D)40%
E)50%
Rationale: pass percentage = 100 - (25+40-35) = 100-70 = 30
ANSWER:C
Answer: C
Question: A set of 11 positive integers has an average of 20. Which of the following is the greatest possible value for the median of this set?
Options:
A)25
B)30
C)35
D)45
E)46
Rationale: for the median to bé max , we should take all the values below meadian to be the lowest and the remaining values to be the same..
here 1 is the lowest value(positive int) số thẻ lowest 5 int will equal 5..
remaining 6= 20*11-5=215..
therefore each valueof these 6 int =215/6=35
ans C
Answer: C
Question: here are 6 periods in each working day of a school. In how many ways can one organize 5 subjects such that each subject is allowed at least one period?
Options:
A)1234
B)4512
C)1800
D)1203
E)4512
Rationale: 5 subjects can be arranged in 6 periods in 6P5 ways.
Any of the 5 subjects can be organized in the remaining period (5C1 ways).
Two subjects are alike in each of the arrangement. So we need to divide by 2! to avoid overcounting.
Total number of arrangements
= 6P5× 5C1 /2!=1800
Ans: C
Answer: C
Question: How many E ways can Jason sit with his five friends in a row of six seats with an aisle on either side of the row, if Jason insists on sitting next to one of the aisles?
Options:
A)120
B)240
C)360
D)540
E)720
Rationale: Jason can select his seat in 2 Ways (two aisles)
His 1st of 4 friends have 5 seats to select =>
His 2nd of remaining 3 friends will have 4 seat to chose from...and so on
Total ways E=> 2*5*4*3*2*1 = 240.B
Answer: B
Question: At the end of three years what will be the compound interest at the rate of 10% p.a. on an amount of Rs.20000?
Options:
A)Rs.6620
B)3378
C)2768
D)2999
E)2771
Rationale: A = 20000(11/10) 3
= 26620
= 20000
----------
6620
Answer: A
Answer: A
Question: The speed of a boat in still water is 60kmph and the speed of the current is 20kmph. Find the speed downstream and upstream?
Options:
A)87 kmph
B)40 kmph
C)16 kmph
D)15 kmph
E)18 kmph kmph
Rationale: Speed downstream = 60 + 20
= 80 kmph
Speed upstream = 60 - 20
= 40 kmph
Answer:B
Answer: B
Question: Anita, Indu and Geeta can do a piece of work in 18 days, 27 days and 36 days respectively. They start working together. After working for 4 days. Anita goes away and Indu leaves 7 days before the work is finished. Only Geeta remains at work from beginning to end. In how many days was the whole work done?
Options:
A)16 days
B)14 days
C)18 days
D)19 days
E)12 days
Rationale: 4/18 + (x -7)/27 + x/36 = 1
x = 16 days
Answer: A
Answer: A
Question: In a certain shop , 70 percent of customers buy mobiles made by company (A) and the rest buy mobiles made by company (B) . A new mobile is made by company (A) . If 90 percent of customers who prefer company (A) and 50 percent of customers who prefer company (B) are expected to buy the new mobile , whats percent of customers are expected to buy the new mobile ?
Options:
A)70
B)78
C)80
D)82
E)86
Rationale: Say there are total of 100 customers in the shop . Thus 70 customers prefer company (A) and 30 customers prefer company(B).
70*0.9=63 customers who prefer company (A) are expected to buy for the new mobile ;
30*0.5=15 customers who prefer company (B) are expected to buy for the new mobile .
Thus total of 63+15=78 members are expected to buy the new mobile, which is 78% of the total number of customers .
Answer: B.
Answer: B
Question: A customer pays 30 dollars for a coffee maker after a discount of 20 dollars
What is the original price of the coffee maker?
Options:
A)90
B)40
C)70
D)60
E)50
Rationale: Let x be the original price.
x - 20 = 30
x - 20 + 20 = 30 + 20
x + 0 = 50
x = 50
Answer is E
Answer: E