divelab/Sys2Bench huggingface dataset:
Question: How many seconds will a 500 meter long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
Options:
A)228
B)277
C)500
D)288
E)212
Rationale: Let length of tunnel is x meter
Distance = 800+x meter
Time = 1 minute = 60 seconds
Speed = 78 km/hr = 78*5/18 m/s = 65/3 m/s
Distance = Speed*Time
800+x = (65/3) * 60
800+x = 20 * 65 = 1300
x = 1300 - 800 = 500 meters.Answer:C
Answer: C
Question: Out of eight crew members three particular members can sit only on the left side. Another two particular members can sit only on the right side. Find the number of ways in which the crew can be arranged so that four men can sit on each side.
Options:
A)864
B)863
C)865
D)1728
E)890
Rationale: Explanation :
The required number of ways :-
=>3C2×4!×4!.
=>1728.
Answer : D
Answer: D
Question: The average earning of a mechanic for the first-four days of a week is Rs. 18 and for the last four days is Rs. 22. If he earns Rs . 41 on the fourth day, his average earning for the whole week is ?
Options:
A)Rs . 18.95
B)Rs 16
C)Rs. 17
D)Rs. 25.71
E)None of these
Rationale: Answer
Total earning for the week = Sum of earning of first four days + Sum of earning of last four days - Earning of 4th day
= 4 x18 + 4 x 22 -41
= Rs. 119
âˆ´ Average earning = 119 / 7
= Rs. 17
Correct Option: C
Answer: C
Question: FOG + FOG + FOG + FOG = 1444.
If F,O and G are digits in a three-digit number in the preceding equation the F + O + G = ?
Options:
A)11
B)12
C)13
D)10
E)15
Rationale: given,FOG + FOG + FOG + FOG = 1444
4(FOG)=1444
=>FOG=361
Face value of F is:3
Face value of O is:6
Face value of G is:1
so F+O+G=3+6+4=10
ANSWER:D
Answer: D
Question: A fruit wholesale dealer has been paid $329,864 in his savings account. What is the least amount of money (in whole number of dollars) that he must add to his account if if he wants to be sure that all 9 of his salesmen have paid evenly?
Options:
A)$1
B)$2
C)$3
D)$4
E)$6
Rationale: To find the least amount the fruit wholesale dealer should add to his account to ensure all 9 of his salemen have paid evenly,
he needs to make the total divisible by 9
Simply add the individual digits of the total = 3+2+9+8+6+4 = 32
If you add 4 , the number is divisible by 9 (32+ 4)
Correct Option : D
Answer: D
Question: If m,n,o,p are four consecutive even numbers, their average is
Options:
A)(m + 3)
B)5(m+4)
C)5(m+n+o+p)
D)mnop
E)None of these
Rationale: Explanation :
Clearly,n=m+2,o=m+4,p=m+6.
Average (m + (m + 2) + (m + 4) + (m + 6)) / 4
= (4m + 12) / 4
= (m + 3)
Answer : A
Answer: A
Question: A shopkeeper sold an article at $100 with 45% profit. Then find its cost price?
Options:
A)$120
B)$100
C)$91
D)$72
E)$69
Rationale: cost price = selling price *100/(100+profit)
C.P. = 100*100/145 = $69(approximately)
Answer is E
Answer: E
Question: Six lights begin to flash together at 12:00 noon and flash respectively at intervals of 3, 4, 5, 6, 7, and 8 seconds. Not including the flash at 12:00 noon, how many more times will all six lights flash together before 1:00 pm (i.e. one hour later)?
Options:
A)4
B)6
C)8
D)10
E)12
Rationale: The least common multiple is 2*2*2*3*5*7=840.
3600 seconds / 840 = 4 + remainder.
The answer is A.
Answer: A
Question: A caterer ordered 125 ice-cream bars and 125 sundaes. If the total price was $225.00 and the price of each ice-cream bar was $0.60, what was the price of each sundae?
Options:
A)$0.60
B)$0.80
C)$1.00
D)$1.20
E)$1.60
Rationale: Let price of a sundae = S
Price of ice cream bar = .6 $
125 * .6 + 125*S = 225
=> 125*S = 150
=> S = 1.2
Answer D
Answer: D
Question: If a can do a work in 10 days and a and b can do a same piece of job in 5 days. IN how days can do a work b alone?
Options:
A)10
B)20
C)5
D)15
E)9
Rationale: a's one day work=1/10
a+b=1/5(one day work)
b=(1/5)-a=(1/5)-(1/10)
=1/10(one day work)
b can done a work in 10 days.
Answer option A
Answer: A
Question: How many terms are in the G.P. 3, 6, 12, 24, ......., 384 ,768,1536
Options:
A)8
B)9
C)67
D)5
E)10
Rationale: Explanation:
Here a = 3 and r = 6/3 = 2. Let the number of terms be n.
Then, t = 384 => a * r^(n-1) = 1536
=> 3 * 2^(n-1) = 1536 => 2^(n-1) = 512 = 2^(9)
=> n-1 = 9 => n = 10
Answer: E
Answer: E
Question: A certain factory produces buttons and buckles at a uniform weight. If the total weight of 2 buttons and 2 buckles is one third of 11 buckles and 3 buttons, then the weight of 3 buttons and 2 buckles is how many times that of 4 buckles and 6 buttons?
Options:
A)7/15.
B)4/9.
C)6/11.
D)1/2.
E)8/15.
Rationale: 2buttons + 2buckles = 1/3(11buckles + 3buttons)
6buttons + 6buckles = 11buckles + 3buttons
3buttons = 5buckles
Weight of 3buttons and 2buckles = 5buckles + 2buckles = 7buckles
Weight of 6buttons and 5buckles = 10buckles + 4buckles = 14buckles
(3buttons and 2buckles) = x * (6buttons and 5buckles)
7 = x*14
x = 7/14=1/2
Answer: D
Answer: D
Question: A 4-letter code word consists of letters L, M, AND N. If the code includes all the three letters, how many such codes are possible?
Options:
A)72
B)36
C)24
D)44
E)22
Rationale: Note that the correct answer to this question is 36, not 72.
L-LMN can be arranged in 4!/2!=12 ways;
M-LMN can be arranged in 4!/2!=12 ways;
N-LMN can be arranged in 4!/2!=12 ways;
Total: 12+12+12=36.
Answer: B
Answer: B
Question: At a certain organisation, the number of male members went up by 14% in the year 2001 from year 2000, and the number of females members went down by 6% in the same time period. If the total membership at the organisation went up by 1.2% from the year 2000 to 2001, what was the ratio of male members to female members in the year 2000?
Options:
A)1:2
B)1:3
C)2:3
D)3:2
E)4:7
Rationale: men increase by 14% ==> 1.14M = males in 2001
women decrease by 6% ==> 0.94F = women in 2001
total employees increase by 1.2% ==> 1.012*(M + F) = total number of employees in 2001
Obviously
(males in 2001) + (females in 2001) = total number of employees in 2001
1.14M + 0.94F = 1.012*(M + F)
1.14M + 0.94F = 1.012M + 1.012F
1.14M - 1.012M = 1.012F - 0.94F
0.128M = 0.072F
M/F = (0.072)/(0.128) = 72/128 = 4/7
Answer =(E)
Answer: E
Question: A candidate got 35% of the votes and lost to the rival by 1350 votes. How many votes were cast?
Options:
A)4000
B)4500
C)5000
D)5500
E)6000
Rationale: 35%-----------L
65%-----------W
------------------
30% = 1350
10% = 450
100% of the votes = 4500
Answer: B
Answer: B
Question: A and B invest in a business in the ratio 3: 2. Assume that 5% of the total profit goes to charity. If A's share is Rs. 855, what is the total profit?
Options:
A)1200
B)1300
C)1500
D)1400
E)1700
Rationale: Assume that the total profit is x
Since 5% goes for charity, 95% of x will be divided between A and B in the ratio 3:2
Therefore, A's profit =(95x/100)×(3/5)
Given that A's share is Rs. 855. Therefore,
(95x/100)×(3/5)=855
⇒95x/100=855×5/3=285×5=1425
⇒x=1425×100/95
=285×100/19=1500
Answer is C.
Hence the total profit = 1500
Answer: C
Question: How many positive integers less than 100 have a remainder of 2 when divided by 13?
Options:
A)5
B)7
C)8
D)9
E)6
Rationale: take the multiples of 13 and add 2
0X13+2=2 ....13X7+2=93
there are 14 numbers
answer C
Answer: C
Question: When the positive integer a is divided by 11, the quotient is b and the remainder 3. When a is divided by 19, the remainder is also 3. What is the remainder when b is divided by 19?
Options:
A)4
B)3
C)2
D)1
E)0
Rationale: Any Number which when divided by divisor d1,d2, etc. leaving same remainderrtakes the form ofK+r
where k = LCM (d1,d2)
In this case the divisors are 1119 and remainder is 3.
so LCM (11,19) = 209
So N= 209+3 = 212
Also a=d1q+3 ; which means d1q=209d1=11 therefore q=19
And ( b divided by 19)19/19 leaves remainder 0.
Answer is E
Answer: E
Question: There are 6periods in each working day of a school. In how many ways can 1 arrange 5subjects such that each subject is allowed at least 1period?
Options:
A)1200
B)1800
C)2000
D)2500
E)2600
Rationale: 5 subjects can be arranged in 6 periods in 6P5 ways.
Remaining 1 period can be arranged in 5P1 ways.
Two subjects are alike in each of the arrangement. So we need to divide by 2! to avoid overcounting.
Total number of arrangements = (6P5 x 5P1)/2! = 1800
Alternatively this can be derived using the following approach.
5 subjects can be selected in 5C5 ways.
Remaining 1 subject can be selected in 5C1 ways.
These 6 subjects can be arranged themselves in 6! ways.
Since two subjects are same, we need to divide by 2!
Total number of arrangements = (5C5 × 5C1 × 6!)/2! = 1800
B
Answer: B
Question: A pump can fill a tank with water in 2 hours. Because of a leak, it took 2 hours to fill the tank. The leak can drain all the water of the tank in:
Options:
A)14 hrs
B)15 hrs
C)10 hrs
D)20 hrs
E)25 hrs
Rationale: work done in 1 hr = 1/2-3/7 = 1/14
==>14 hrs
ANSWER A
Answer: A
Question: A train 240 m in length crosses a telegraph post in 16 seconds. The speed of the train is?
Options:
A)50
B)54
C)52
D)56
E)58
Rationale: Explanation:
speed= Distance/ Time
S = 240/16 * 18/5 = 54 kmph
Answer:B
Answer: B
Question: In a certain accounting class of 100 students, 70% of the students took the final exam on the assigned day while the rest of the students took the exam on a make-up date. If the students on the assigned day had an average score of 60%, and the students on the make-up date had an average score of 80%, what was the average score for the entire class?
Options:
A)64%
B)66%
C)68%
D)70%
E)72%
Rationale: 70% of the class scored 60% and 30% of the class scored 80%.
The difference between 60% and 80% is 20%.
The average will be 60% + 0.3(20%) = 66%.
The answer is B.
Answer: B
Question: Worker A takes 8 hours to do a job. Worker B takes 10 hours to do the same Job.How long should it take both A and B, working together but independently, to do the same job?
Options:
A)40/9 days
B)9 days
C)40 days
D)94 days
E)7 days
Rationale: A’s 1 hour's work = 1/8
B's 1 hour's work = 1/10
(A + B)'s 1 hour's work = (1/8) +(1/10)=9/40
Both A and B will finish the work in 40/9 days.
Ans: A
Answer: A
Question: A basket contains 10 apples and 20 oranges out of which 3 apples and 5 oranges are defective. If we choose two fruits at random, what is the probability that either both are oranges or both are non defective?
Options:
A)316/439
B)316/438
C)316/435
D)316/299
E)316/199
Rationale: Let A be the event of getting two oranges and
B be the event of getting two non-defective fruits.
and be the event of getting two non-defective oranges
Answer: C) 316/435
Answer: C
Question: Find the least number must be subtracted from 427398 so that remaining no.is divisible by 15?
Options:
A)2
B)3
C)5
D)7
E)8
Rationale: On dividing 427398 by 15 we get the remainder 3, so 3 should be subtracted
B
Answer: B
Question: The cost of registration at a professional association meeting was $50 per person; a lunch for registrants only was available for an additional $22 per person. If the number of registrants who paid for lunch was 50 more than the number who did not, and if receipts for registration and lunch totaled $82,900, how many people paid just for registration at the meeting?
Options:
A)700
B)650
C)1,300
D)1,500
E)1,800
Rationale: Hope this might be useful to you.
Let the number of people who have opted only to register = x
Now since the registration cost is 50$ per person, the total amount sums to = 50x $
As per the information given in the question, the number of registrants who paid for lunch was 50 more than the number who did not. That means, total number of people who registered and paid for lunch = 50 + x.
For the people who registered for lunch the cost is 50 $ (for the event registration) + 22 $ (for lunch) = 72 $.
Total amount in this case sums to = 72(50 + x) = 3600 + 72x
Now, total amount received was 82900.
Thus, from the above data,
50x + 3600 + 72x = 82900
122x = 82900 - 3600
122x = 79300
x = 650
Hence the correct Ans is B
Answer: B
Question: A bullock cart has to cover a distance of 80km in 10hrs. If it covers half of the journey in 3/5th time. what should be its speed to cover the remaining distance in the time left.
Options:
A)10 kmph
B)20 kmph
C)30 kmph
D)40 kmph
E)50 kmph
Rationale: A
10 kmph
Time left = 10 - 3/5*10
= 4 hr 10 km/h
speed =40 km /4 hr
=10 kmph
Answer: A
Question: If 30 oxen can plough 1/7th of a field in 2 days, how many days 18 oxen will take to do the remaining work?
Options:
A)30 days
B)20 days
C)15 days
D)18 days
E)21 days
Rationale: Solution: We will use work equivalence method,
30/18 = (1/7)/(6/7)*x/2;
5/3 = (1/6)*x/2;
Or, x = 60/3 = 20 days.
Answer: Option B
Answer: B
Question: A shopkeeper sells 500 metres of cloth for Rs. 15000 at a loss of Rs.10 per metre. Find his cost price for one metre of cloth?
Options:
A)s.40
B)s.12
C)s.96
D)s.50
E)s.13
Rationale: SP per metre = 15000/500
= Rs. 30 Loss per metre
= Rs. 10 CP per metre = 30 + 10
= Rs.40
Answer: A
Answer: A
Question: 15 percent of new students select a science major, 10 percent select an arts major, and 35 percent select an engineering major, what fraction of students remain undecided?
Options:
A)4/5
B)3/5
C)3/10
D)2/5
E)1/10
Rationale: 100%-(15%+10%+35%)=60% remains for other allocations --> 40% = 40/100 = 2/5.
Answer: D.
Answer: D
Question: The present ages of three persons in proportions 5 : 6 : 4. Five years ago, the sum of their ages was 60. Find their present ages (in years).
Options:
A)8, 20, 28
B)16, 28, 36
C)25,30,20
D)18, 24, 32
E)None of these
Rationale: Explanation:
Let their present ages be 5x, 6x and 4x years respectively.
Then, (5x - 5) + (6x - 5) + (4x - 5) = 60
15x-15 = 60
x = 5
Their present ages are 5x = 25 years, 6x = 30 years and 4x = 20 years respectively.
Answer: C
Answer: C
Question: The number of new words that can be formed by rearranging the letters of the word 'LIVE' is?
Options:
A)25
B)27
C)19
D)23
E)24
Rationale: Number of words which can be formed
= 4! - 1 = 24- 1
= 23.
Answer:D
Answer: D
Question: Number of ways in which the letters of word AMBI can be arranged with vowels in alphabetical order, is
Options:
A)360
B)240
C)12
D)480
E)None of these
Rationale: Solution
Order of vowels of fixed
âˆ´ required number of ways are 4!/2!.
Answer C
Answer: C
Question: The ratio between the speeds of two Bullet trains is 7: 8. If the second Bullet train runs 420 kms in 4 hours, then the speed of the first train is:
Options:
A)89.25 km/hr.
B)37.25 km/hr.
C)90.25 km/hr.
D)94.25 km/hr.
E)91.875 km/hr.
Rationale: Let the speed of two bullet trains be 7x and 8x km/hr.
Then, 8x = (420/4) = 105
x = (105/8) = 13.125
Hence, speed of first bullet train = (7 x 13.125) km/hr = 91.875 km/hr.
E
Answer: E
Question: It takes eight hours for a 600 km journey, if 120 km is done by train and the rest by car. It takes 20 minutes more, if 200 km is done by train and the rest by car. The ratio of the speed of the train to that of the cars is:
Options:
A)3:4
B)4:5
C)6:3
D)4:4
E)3:7
Rationale: A
3:4
Let the speed of the train be x km/hr and that of the car be y km/hr.
Then, 120/x + 480/y = 8 --> 1/x + 4/y = 1/15 ------ (i)
Also, 200/x + 400/y = 25/3 --> 1/x + 2/y = 1/24 ----(ii)
Solving (i) and (ii), we get: x = 60 and y = 80.
--> Ratio of speeds = 60 : 80 = 3 : 4.
Answer: A
Question: Rap is working on a set of Data Sufficiency problems for his December GMAT: a geometry problem, an algebra problem, and a data interpretation problem. He has determined that statement 1 of the geometry problem is insufficient on its own, that both statement 1 and 2 of the algebra problem are insufficient on their own, and that statement 2 of the data interpretation problem is insufficient on its own. If the probabilities are expressed as percents T, approximately how much greater is the probability that all three answers are “C” after Rap figures out that statement 1 of the data interpretation problem is also insufficient on its own?
Options:
A)T=2.3%
B)T=2.8%
C)T=3.3%
D)T=5.6%
E)T=8.3%
Rationale: Step 1: Figure out what we need to know.We have two probabilities T that we need to figure out: the one before Raj figures out that statement 1 of the data interpretation problem is also insufficient, and the one after. The answer is the difference between them, in the form of a percent.
Step 2: The first probability.
If statement 1 of the geometry problem is insufficient, then the only valid answer choices are B, C, and E; the probability that it is C is 1/3.
If both statements of the algebra problem are insufficient on their own, then the only remaining valid answers are C and E; the probability that it is C is 1/2
If statement 2 of the data interpretation problem is insufficient, then the remaining answers are A, C, and E, and the probability that C is correct is 1/3.
The probability of all three occurring is the product of the probability fractions: (1/3)*(1/2)*(1/3) = 1/18.
Step 3: The second probability.
Only the third problem has changed; if Raj now knows that statement 1 is also insufficient, the valid answer choices are only C and E, leaving a 1/2 probability that the answer is C.
The probability of all three occurring is still the product of those fractions, but this time they are (1/3)*(1/2)*(1/2) = 1/12.
Step 4: The answer.Note that here, as will sometimes happen on the GMAT, values that you compute “along the way” appear as wrong answer choices. This problem calls for the difference between our two numbers, (1/12)-(1/18) = 1/36, which is a 2.77777% chance, rounded to 2.8% —the correct answer is Choice B.
Answer: B
Question: If the a radio is sold for rs 490 and sold for rs 465.50.find loss value.
Options:
A)24.5
B)12.5
C)17.25
D)6.5
E)13.62
Rationale: cp=rs490,sp= 465.50.
loss=rs(490-465.50)=rs 24.50.
Ans: A
Answer: A
Question: If rupee one produces rupees nine over a period of 40 years, find the rate of simple interest?
Options:
A)22 1/9 %
B)22 2/2 %
C)23 1/2 %
D)22 1/2 %
E)62 1/2 %
Rationale: 9 = (1*40*R)/100
R = 22 1/2 %
Answer:D
Answer: D
Question: David and Lewis leave Chennai for Tirupati simultaneously at 7 A.M in the morning driving in two cars at speeds of 60 mph and 80 mph respectively. As soon as Lewis reaches Tirupati he returns back to Chennai along the same route and meets David on the way back. If the distance between the two cities is 160 miles, how far from Chennai did David and Lewis meet?
Options:
A)100 mlies
B)120 miles
C)90 miles
D)95 miles
E)110 miles
Rationale: Time taken by Lewis to reach Tirupati = 160/80 = 2 hours
In 2 hours, David travels 60*2 = 120 miles
So distance at which they meet should be greater than 120 miles.
Only B satisfies.
Answer is B.
Answer: B
Question: In an exam, X scored 30 percent, Y scored 50 percent and Z 40 percent. The maximum score awarded in the exam is 800. Find the average mark scored by all the three candidates?
Options:
A)270
B)280
C)290
D)300
E)320
Rationale: Average mark scored by all the three boys
= [30/100 (800) + 50/100 (800) + 40/100 (800)] / 3
= 320
Answer: E
Answer: E
Question: In how many ways can 4 boys and 2girls be arranged ata table if 2 girls are never together?
Options:
A)76
B)74
C)72
D)73
E)79
Rationale: Total ways of arranging 6 person in a circle = 5! = 120 ways
If we consider two women as one, then we have 4+1=5 persons. Arranging these five persons in circle will take = 4! = 24 ways
And two women can arrange themselves in 2! ways
Total ways in which two women sit together in circle = 4!*2! = 48 ways
Total ways in which two women doesn’t sit together in circle = 5! - 4!*2! =120 - 48 = 72 ways
C
Answer: C
Question: If 0 < c< 1 < d, which of the following must be true?
Options:
A)1 < 1/c< 1/d
B)1/c< 1 < 1/d
C)1/c< 1/d< 1
D)1/d< 1 < 1/c
E)1/d< 1/c< 1
Rationale: 0<c<1<d. Let c=1/2 and d=2
Substituting values:
A. 1<2<1/2 ---Wrong
B. 2<1< 1/2 ---Wrong
C. 2<1/2<1 ---Wrong
D. 1/2<1<2 ---Correct
E. 1/2<2<1 ---Wrong
Hence answer is D
Answer: D
Question: a farmer have 10%cow,15%buffalo,25%goat,50% chicken.he has 30 goat.then calculate the no. of cow,buffalo and chicken.
Options:
A)12,15,45
B)12,18,60
C)10,18,45
D)10,16,60
E)14,16,30
Rationale: total no. of livestock is x.
x*25/100=30
x=3000/25=120
no.of cow=120*10/100=12
no. of buffalo=120*15/100=18
no. of chicken=120*50/100=60
answer B
Answer: B
Question: The total of a company's assets in 1994 was 200% greater than the total in 1993, which in turn was 300% greater than the total in 1992. If the total of the company's assets in 1992 was N dollars, what were the company's assets in 1994?
Options:
A)5N
B)6N
C)9N
D)12N
E)15N
Rationale: In 1992, the company's assets were N.
In 1993, the company's assets were N + 3N =4N.
In 1994, the company's assets were 4N + 8N = 12N.
The answer is D.
Answer: D
Question: A fill pipe can fill 1/6 of cistern in 90 minutes in how many minutes, it can fill 5/6 of the cistern?
Options:
A)450 min
B)360 min
C)240 min
D)306 min
E)500 min
Rationale: 1/6 of the cistern can fill in 90 min
5/6 of the cistern can fill in = 90*6*5/6 = 450 min
Answer is A
Answer: A
Question: If $100,000 is invested at x percent simple annual interest for n years, which of the following represents the total amount of interest, in dollars, that will be earned by this investment in the n years?
Options:
A)10,000(x^n)
B)10,000(x/100)^n
C)10,000n(x/100)
D)10,000(1+x/100)^n
E)100,000n(x/100)
Rationale: I think answer D is for compound interest (which i assumed)
and answer E is for simple interest because it is not compounding.
Answer: E
Question: A farmer grows Broccoli in his farm that is in the shape of a square. Each Broccoli takes 1 square foot of area in his garden. This year, he has increased his output by 101 Broccoli when compared to last year. The shape of the area used for growing the Broccoli has remained a square in both these years. How many Broccoli did he produce this year?
Options:
A)2400
B)2601
C)1987
D)2000
E)Cannot be determined
Rationale: Explanatory Answer
The shape of the area used for growing Broccoli has remained a square in both the years.
Let the side of the square area used for growing Broccoli this year be X ft.
Therefore, the area of the ground used for cultivation this year = X2 sq.ft.
Let the side of the square area used for growing Broccoli last year be Y ft.
Therefore, the area of the ground used for cultivation last year = Y2 sq.ft.
As the number of Broccoli grown has increased by 101, the area would have increased by 101 sq ft because each Broccoli takes 1 sq ft space.
Hence, X2 - Y2 = 101
(X + Y)(X - Y) = 101.
101 is a prime number and hence it will have only two factors. i.e., 101and 1.
Therefore, 101 can be expressed as product of 2 numbers in only way = 101 * 1
i.e., (X + Y)(X - Y) = 101* 1
So, (X + Y) should be 101 and (X - Y) should be 1.
Solving the two equations we get X = 51 and Y = 50.
Therefore, number of Broccoli produced this year = X2 = 512 = 2601.
Alternative Approach : Use answer choices
The area in both the years are squares of two numbers.
That rules out choice A,C and D. as 2400,1987 and 2000 are not the square of any number.
Check Choice B: If this year's produce is 2601, last year's produce would have been 2601 - 101 = 2500
2500 is the square of 50.
So, 2601 is the answer.
Choice B
Answer: B
Question: 2, 3, 5, 7, 11, ?, 17
Options:
A)15
B)14
C)13
D)12
E)11
Rationale: The series consists of prime numbers starting from 2.
Answer : C.
Answer: C
Question: Out of 18 students studying in a class, 7 are from Maharashtra, 5 are from Karnataka and 3 are from Goa. Four students are to be selected at random. What are the chances that at least one is from Karnataka?
Options:
A)12â„13
B)11â„13
C)10â„15
D)59/77
E)None of these
Rationale: Total possible ways of selecting 4 students out of 18 students = 18C4 =3060
The no. of ways of selecting 4 students in which no student belongs to Karnataka = 13C4=715
âˆ´ Hence no. of ways of selecting at least one student from Karnataka = 18C4 â€“ 13C4 = 2345
âˆ´ Probability = 2345â„3060= 59/77
Answer D
Answer: D
Question: John makes $60 a week from his job. He earns a raise and now makes $100 a week. What is the % increase?
Options:
A)16%
B)66.67%
C)17%
D)17.61%
E)17.56%
Rationale: Increase = (40/60)*100 = (4/6)*100 = 66.67%.
B
Answer: B
Question: If the sides of a triangle are 30 cm, 28 cm and 10 cm, what is its area?
Options:
A)120
B)110
C)130
D)140
E)150
Rationale: The triangle with sides 30 cm, 28 cm and 10 cm is right angled, where the hypotenuse is 30 cm.
Area of the triangle = 1/2 * 28 * 10 = 140 cm2
Answer: Option D
Answer: D