divelab/Sys2Bench huggingface dataset:
Question: The ratio of two numbers is 3 : 4 and their H.C.F. is 4. Their L.C.M. is:
Options:
A)12
B)16
C)24
D)48
E)None
Rationale: EXPLANATION
Let the numbers be 3x and 4x. Then, their H.C.F. = x. So, x = 4.
So, the numbers 12 and 16.
L.C.M. of 12 and 16 = 48.
Answer D
Answer: D
Question: All the water in container A which was filled to its brim was poured into two containers B and C. The quantity of water in container B was 62.5% less than the capacity of container A. If 148 liters was now transferred from C to B, then both the containers would have equal quantities of water. What was the initial quantity of water in container A?
Options:
A)1726 liters
B)1362 liters
C)1280 liters
D)1184 liters
E)1173 liters
Rationale: B has 62.5% or (5/8) of the water in A. Therefore, let the quantity of water in container A(initially) be 8k.
Quantity of water in B = 8k - 5k = 3k.
Quantity of water in container C = 8k - 3k = 5k
Container: A B C
Quantity of water: 8k 3k 5k
It is given that if 148 liters was transferred from container C to container B, then both the containers would have equal quantities of water.
5k - 148 = 3k + 148 => 2k = 296 => k = 148
The initial quantity of water in A = 8k = 8 * 148 = 1184 liters.
Answer:D
Answer: D
Question: The difference of two numbers is 8 and one-fourth of their sum is 6. Find the numbers.
Options:
A)16,8
B)10,2
C)17,6
D)14,10
E)12,4
Rationale: Let numbers be x and y.
Equation (i): x - y = 8
Equation (ii): (x + y)/4 = 6
Solve system of equations: x=16, y=8
A is the correct answer.
Answer: A
Question: In the number 11,0AB, A and B represent the tens and units digits, respectively. If 11,0AB is divisible by 50, what is the greatest possible value of B × A?
Options:
A)0
B)5
C)20
D)15
E)25
Rationale: You should notice that 50*2=110 so 11,000 is divisible by 55: 55*200=11,000 (or you can notice that 11,000 is obviously divisible by both 5 and 11 so by 55) --> B*A=0*0=0. Next number divisible by 55 is 11,000+55=11,055: B*A=5*4=20 (next number won't have 110 as the first 3 digits so we have only two options 0 and 25).
Answer: C.
!
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C
Answer: C
Question: If three sides of the triangle are 8 , 15 and G respectively then the how many values can G ?
Options:
A)[A] 6
B)[B] 7
C)[C] 8
D)[D]9
E)[E] infinite number of values
Rationale: Needed: How many Values can G take
Concept: Sum of any two sides of a triangle is greater then the third side.
Case 1: 8+5 > G => G<13
Case 2: 5+G > 8 => G >3
Case 3: 8+G > 5 => G > -3 (Always true since G is one side of a Triangle)
Finally, 3 < G < 13. So, we can have infinite number of sides between 3 and 13.
Answer = E
PS: If question said G can take only integer value, the G = 9. Answer choice D.
Answer: D
Question: How long does a train 165 meters long running at the rate of 54 kmph take to cross a bridge 660 meters in length?
Options:
A)22
B)88
C)55
D)200
E)21
Rationale: T = (660 + 165)/54 * 18/5
T = 55.Answer: C
Answer: C
Question: 3x+4y=10
x^3+y^3=6
What is the minimum value of 3x+11y=?
Options:
A)32
B)34
C)35
D)36
E)38
Rationale: on subtracting 2 eqns we get y=4 and x=-2.
therefore 3x+11y=-6+44
=38.
ANSWER:E
Answer: E
Question: Dan has a membership at a local gym that also gives classes three nights a week. On any given class night, Dan has the option of taking yoga, weight training, or kickboxing classes. If Dan decides to go to either one or two classes per week, how many different combinations E of classes are available?
Options:
A)3
B)6
C)E=7
D)E=9
E)E=12
Rationale: I think it should be E only.
No where it is given that he attends different classes on each day.
Experts please provide your views.
--- EDITED my Response. It was a typo. I meant 12 is the answer.
If only Day 1 : 3 options
If Day 1 and Day 2 : 3*3 = 9 Options
So, Total = 3+9= 12.
Answer: D
Question: How many independent words can 'HEARTLESS' be divided into without changing the order of the letters and using each letter only once ?
Options:
A)1
B)2
C)5
D)3
E)4
Rationale: Explanation:
The words are HE, ART and LESS.
Answer: D) 3
Answer: D
Question: A cylinder has a base with a circumference of 20pi meters and an equilateral triangle inscribed on the interior side of the base. A marker is dropped into the tank with an equal probability of landing on any point on the base. If the probability of the marker landing inside the triangle is (Sqrt 3)/4 , what is the length of a side of the triangle?
Options:
A)3(sqrt 2pi)
B)3(sqrt 3pi)
C)10*sqrt (pi)
D)10(sqrt 3pi)
E)20 pi
Rationale: Prob of marker landing in the triangle = area of triangle / area of base = sqrt(3)/4
Circumference of base = 20pi meters
=> Radius of base = 10 meters
=> Area of base = 100 pi sq m
Therefore area of the triangle = 100 pi * sqrt(3)/4
As the area of an equilateral triangle is sqrt(3)*(side^2)/4,
any side of the triangle = 10*sqrt(pi)
ANSWER:C
Answer: C
Question: Ten years ago, the age of Anand was one-third the age of Bala at that time. The present age of Bala is 12 years more than the present age of Anand. Find the present age of Anand?
Options:
A)22
B)16
C)82
D)27
E)15
Rationale: Explanation:
Let the present ages of Anand and Bala be 'a' and 'b' respectively.
a - 10 = 1/3 (b - 10) --- (1)
b = a + 12
Substituting b = a + 12 in first equation,
a - 10 = 1/3 (a + 2) => 3a - 30 = a + 2
=> 2a = 32 => a = 16.
Answer: B
Answer: B
Question: Solve: 387 x 387 + 114 x 114 + 2 x 387 x 114
Options:
A)251001
B)251000
C)251010
D)250101
E)None of them
Rationale: = (387)2+ (114)2+ (2 x 387x 114)
= a2 + b2 + 2ab, where a = 387,b=114
= (a+b)2 = (387 + 114 )2 = (501)2 = 251001.
Answer is A
Answer: A
Question: There are d cities. What is the number of airlines that connected 2 different cities (airline from city A to city B is different with airline from city B to city A)?
Options:
A)n(n-1)
B)n(n+1)
C)d(d-1)
D)n(n+1)/2
E)n2
Rationale: First of all, the possible number of airlines is d. Then, the possible number of airlines departing from one city to another becomes (d-1). Hence, the answer is d(d-1), C
Answer: C
Question: For any integer n greater than 1, #n denotes the product of all the integers from 1 to n, inclusive. How many prime numbers E are there between #6 +2 and #6 +6 , inclusive?
Options:
A)None
B)One
C)Two
D)Three
E)Four
Rationale: None is the answer. A.
Because for every k 6! + k :: k, because 6! :: k, since k is between 2 and 6.A
Answer: A
Question: A man cheats while buying as well as while selling. While buying he takes 10% more than what he pays for and while selling he gives 20% less than what he claims to. Find the profit percent, if he sells at 12% below the cost price of the claimed weight.
Options:
A)19.81%
B)21%
C)37.5%
D)25%
E)37.5%
Rationale: There is a one step calculation method too. It requires more thought but is faster.
The man takes 10% more than what he pays for. So if he claims to take 100 pounds, he pays $100 but he actually takes 110 pounds for which he will take from the customer $110. Hence, in effect, there is a 10% mark up.
While selling, he sells 20% less. This means, he claims to sell 100 pounds and gets $100 but actually sells only 80 pounds and should have got only $80 for it. So this is again a mark up of $20 on $80 which is 25%.
But he also sells at 12% less
(1 + m1%)(1 + m2%)(1 - d%) = (1 + p%)
11/10 * 5/4 * 22/25 = (1 + p%)
profit % = 21%
B
Answer: B
Question: Find the wrong number below mentioned series
3,20,50,60,80
Options:
A)80
B)60
C)50
D)20
E)3
Rationale: 3 is the only prime number or odd number in the series.
ANSWER:E
Answer: E
Question: For an employee to qualify for early retirement at a certain company, the sum of the employee’s age and years of service must be at least 75, If Sue was K years old when she was hired by the company, what is the minimum age at which she could possibly qualify for early retirement.
Options:
A)K+35
B)2K+35
C)(75+K)/2
D)(70-K)/2
E)2(70-K)
Rationale: Say Sue was hired when she was already 75 years old (k=75), then she could retire right away, at the age of 75. Now, plug k=75 in the answer choices and see which yields 75. Only C fits.
Answer: C.
Answer: C
Question: A number when divided by 5 gives a number which is 8 more than the remainder obtained on dividing the same number by 34. Such a least possible number N is
Options:
A)74
B)N=75
C)N=175
D)N=680
E)690
Rationale: I solved this question by plugging in numbers from the answer choices.
A.) 74
Starting with answer choice A, I immediately eliminated it because 74 is not even divisible by 5.
B.) 75
I divide 75/5 and get 15 as an answer. I divide 75/34 and get a remainder of 7.
15-7 = 8 so I know the correct answer isB
Answer: B
Question: A jeep takes 9 hours to cover a distance of 480 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time?
Options:
A)48 Kmph
B)52 Kmph
C)35 Kmph
D)63 Kmph
E)65 Kmph
Rationale: Time = 9
Distance = 480
3/2 of 9 hours = 9 * 3/2 = 13.5 Hours
Required speed = 480/13.5 = 35 Kmph
C)
Answer: C
Question: The ratio of the volumes of two cubes is 1728 : 2197. What is the ratio of their total surface areas?
Options:
A)12:18
B)144:169
C)44:22
D)28:144
E)96:12
Rationale: Ratio of the sides = Â³âˆš1728 : Â³âˆš2197
= 12 : 13
Ratio of surface areas =144:169
Answer: B
Answer: B
Question: Points A, B, and, C have xy-coordinates (2,0), (8,12), and (14,0), respectively. Points X, Y, and Z have xy-coordinates (6,0), (8,4), and (10,0), respectively. What fraction S of the area of triangle ABC is the area of triangle XYZ?
Options:
A) 1/9
B) 1/8
C) 1/6
D) 1/5
E) 1/3
Rationale: If you notice, both triangles ABC and XYZ have a side on X axis. we can take these sides as bases for each triangle, therefore
Area of ABC is 1/2*12*12 (Height of ABC is the y coordinate of the third point (8,12))
similarly Area of XYZ is 1/2*4*4
dividing area of XYZ with that of ABC gives S=1/9.A
Answer: A
Question: a and b are two numbers selected randomly from 1,2,3.... 25 what is the probability of a and b are not equal.
Options:
A)1/25
B)24/25
C)13/25
D)2/25
E)3/25
Rationale: No of events=625((1,1),(1,2).......(25,25))
Probability of getting a&b are equal=(25/625)[(1,1),(2,2),(3,3).....(25,25)]
Probability of a and b or not equal=1-(25/625)
=600/625
=24/25
ANSWER:B
Answer: B
Question: A number is missing from the number series below.
Can you find it ?
84, 155, 258, 399 , 584, ?.
Options:
A)275
B)350
C)399
D)421
E)819
Rationale: E
The missing number is 819.
84 = 4^3 + 3^2 + 4
155 = 5^3 + 5^2 + 5
258 = 6^3 + 6^2 + 6
399 = 7^3 + 7^2 + 7
584 = 8^3 + 8^2 + 8
Thus,
819 = 9^3 + 9^2 + 9
Answer: E
Question: Effective annual rate of interest corresponding to nominal rate of 6% per annum compounded half
yearly will be
Options:
A)6.09%
B)6.10%
C)6.12%
D)6.14%
E)None of these
Rationale: Explanation:
Let the amount Rs 100 for 1 year when compounded half yearly, n = 2, Rate = 6/2 = 3%
Amount=100(1+3100)2=106.09
Effective rate = (106.09 - 100)% = 6.09%
Answer: A
Answer: A
Question: if log102 = 0.3010, what is the value of log101600 ?
Options:
A)3.208
B)3.202
C)3.209
D)3.204
E)3.2112
Rationale: Explanation:
log101600
= log10(16 × 100)
= log10(16) + log10(100)
= log10(24) + log10(102)
= 4 log10(2) + 2
= (4 × 0.3010) + 2
= 1.204 + 2
= 3.204
Answer: Option D
Answer: D
Question: In 165 litres of mixtures of milk and water, water is only 28%. The milkman sold 40 litres of this mixture and then he added 30 litres of pure milk and 13 litres of pure water in the remaining mixture. What is the percentage of water in the final mixture?
Options:
A)29.35%
B)28. 57%
C)24. 57%
D)27. 75%
E)26. 57%
Rationale: Initially, milk = 118.2 l, and water = 46.2 l.
40 liters is withdrawn in same ratio as it was initially, i.e., 72:28.
Remaining milk = 90 l, and water = 35 l.
Now add 30 l of milk and 13 liter of water.
Then milk = 120 l and water = 48 l.
Percentage of water = 48*100/168 = 28.57 %
ANSWER:B
Answer: B
Question: John weighs twice as much as Susan. Susan's weight is 60% of Sam's weight. Mark weighs 50% of Lynn's weight. Lynn weighs 180% of John's weight. Which of these 5 people weighs the least?
Options:
A)John
B)Susan
C)Sam
D)Mark
E)Lynn
Rationale: John weighs twice as much as Susan --> J=2S --> John cannot weigh the least;
Susan's weight is 60% of Sam's weight --> S=0.6*Sam --> Sam cannot weigh the least;
Mark weighs 50% of Lynn's weight --> M=0.5*L --> Lynn cannot weigh the least;
Lynn weighs 180% of John's weight --> L=1.8*J --> John cannot weigh the least (we already know that);
As you can see the answer is either Susan (S) or Mark (M). To compare their weights we should express their weights in regards of the same person: M=0.5*L=0.5*(1.8*J)=0.9*J and from J=2S, S=0.5*J --> Susan weights the least: Susan's weight is 50% of that of John and Mark's weight is more than 50%of that of John.
Answer: B.
Answer: B
Question: How much pure alcohol should be added to 400ml of a 15% solution to make the strength of solution 35%?
Options:
A)100 ml
B)60 ml
C)120 ml
D)130 ml
E)175 ml
Rationale: we can also go by answer choices
Tke 100 ml for eg
400 (old)+100 (new concentr)ml
500*35/100 = 175 ml (75ml is de old concentration +100 ml (newly added)
Answer E
Answer: E
Question: At the start of an experiment, a certain population consisted of 3 animals. At the end of each month after the start of the experiment, the population size was double its size at the beginning of that month. Which of the following represents the population size at the end of 9 months?
Options:
A) 2^3
B) 3^2
C) 2(3^10)
D) 3(2^9)
E) 3(10^2)
Rationale: 3*2^n where n is the #of month --> 3*2^9 Answer (D)
Answer: D
Question: Some part of a 50% solution of acid was replaced with an equal amount of 30% solution of acid. If, as a result, 40% solution of acid was obtained, what part of the original solution was replaced?
Options:
A)1/5
B)1/4
C)1/2
D)3/4
E)2/3
Rationale: Original Removed Added Result
Concentration 0.50 0.50 0.70 0.60
Amount 1 x x 1
Multiply 0.50 0.50x 0.70x 0.60
0.50 (Original amount) - 0.50x (Removed) + 0.70x (Added) = 0.60 (End Result)
0.20x = 0.10
x = 1/2
ANSWER:C
Answer: C
Question: Machine A takes 20 hours to complete a certain job and starts that job at 6AM. After four hour of working alone, machine A is joined by machine B and together they complete the job at 1PM. How long would it have taken machine B to complete the job if it had worked alone for the entire job?
Options:
A)9.99
B)3,615
C)3.62
D)4.62
E)6.14
Rationale: Let us assume total job = 100 units
A finishes 100 units in 20 hrs(given)
Hence A (working rate)= 5 units /hr
Now Given that A works for 4 hr( so 20 units done) then A and B finish total work in 7 hours. Hence A and B finish 80 units in 3 hours. Of these 3x5=15 units were done by A. Hence B did 65 units in 3 hours.
Hence B(working rate)= 65/3 units /hr
Hence B takes 100x3/65 = 4.62 hours to complete the job.
Answer D.
Answer: D
Question: A school has received 60% of the amount it needs for a new building by receiving a donation of $600 each from people already solicited. People already solicited represent 40% of the people from whom the school will solicit donations. How much average contribution is requited from the remaining targeted people to complete the fund raising exercise?
Options:
A)$200
B)$177.78
C)$100
D)$277.78
E)$377.78
Rationale: Let the amount school needs = X
Let total people school plans to solicit = T
School has received 60 % of X => (3/5) X
People already solicited = 40% of T => (2/5) T
Now, as per the information given in the question :
(3/5)X = $400 . (2/5) . T --------------------------- 1
Remaning Amount is 40 % i.e ( 2/5 ) X ------because school has already received 60%
And the remaining people are 60 % i.e (3/5) .T -----because 40% of the people are already solicited
So, average contribution required from the remaining targeted people is
(2/5) X = (Amount required) . (3/5) . T ----------------------------------- 2
Divide eqn 1 by eqn 2
Amount required = $277.78
D
Answer: D
Question: Each of the positive integers a, b, and c is a three-digit integer. If each of the digits 1 through 9 appears in one of these three integers, what is the maximum possible value of the sum of a, b, and c?
Options:
A)2445
B)2331
C)2874
D)2801
E)2256
Rationale: According to the stem we should use the digits 1 through 9 to construct 3 three-digit integers, so that their sum is as big as possible.
To maximize the sum, maximize the hundreds digits of a, b, and c, so make them 9, 8, and 7.
Next, minimize tens digits. Make them 6, 5, and 4.
Use the remaining digits (3, 2, and 1) for units digits.
So, a would be 963, b would be 852 and c would be 741.
741 + 852 + 963 =2256.
Answer: E.
Answer: E
Question: A store owner estimates that the average price of type A products will increase by 15% next year and that the price of type B products will increase by 18% next year. This year, the total amount paid for type A products was $4600 and the total price paid for type B products was $8400. According to the store owner's estimate, and assuming the number of products purchased next year remains the same as that of this year, how much will be spent for both products next year?
Options:
A)$15,202
B)$15,325
C)$16,000
D)$16,225
E)$17,155
Rationale: cost of type A products next year = 1.15 * 4600 = 5290
cost of type B products next year = 1.18 * 8400 = 9912
total 5290 +9912 = 15202
ANSWER:A
Answer: A
Question: The sale price sarees listed for Rs.400 after successive discount is 20% and 5% is?
Options:
A)338
B)277
C)342
D)882
E)304
Rationale: 400*(80/100)*(95/100) = 304
Answer: E
Answer: E
Question: The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is?
Options:
A)866 m
B)255 m
C)245 m
D)167 m
E)267 m
Rationale: Speed = [45 X 5/18] m/sec = [25/2] m/sec Time = 30 sec Let the length of bridge be x metres. Then, (130 + x)/30
= 25/2 => 2(130 + x)
= 750 => x
= 245 m.
Answer:C
Answer: C
Question: A train 125m long takes 6 sec to cross a man walking at 5kmph in a direction opposite to that of the train. Find the speed of the train?
Options:
A)65kmph
B)70kmph
C)75kmph
D)80kmph
E)85kmph
Rationale: Let the speed of the train be x kmph
Speed of the train relative to man = x+5 = (x+5)*5/18 m/sec
125/[(x+5)*5/18] = 6
30(x+5) = 2250
x = 70kmph
Answer is B
Answer: B
Question: A jar of 312 marbles is divided equally among a group of marble-players today. If 2 people joined the group in the future, each person would receive 1 marble less. How many people are there in the group today?
Options:
A)18
B)20
C)22
D)24
E)26
Rationale: 312 = 24*13 = 26*12
There are 24 people in the group today.
The answer is D.
Answer: D
Question: A person incurs a loss of 5% be selling a watch for Rs. 1140. At what price should the watch be sold to earn 5% profit.
Options:
A)2227
B)1788
C)1260
D)2889
E)7721
Rationale: Explanation:
Let the new S.P be x, then
(100 - loss%) : (1st S.P.) = (100 + gain%) : (2nd S.P.)
\inline \fn_jvn {\color{Black} \Rightarrow (\frac{95}{1140}=\frac{105}{x})}
\inline \fn_jvn {\color{Black} \Rightarrow x=1260}
Answer: C) Rs.1260
Answer: C
Question: The population of a town increased from 50,000 to 80,000 in a decade. The average percent increase of population per year is :
Options:
A)4.37%
B)5%
C)6%
D)8.75%
E)None of these
Rationale: Solution
Increase in 10 year= (80000 - 50000) = 30000.
Increase% =(30000/50000x 100 )% = 60%
âˆ´ Required average = ( 60/10 )% = 6%
Answer C
Answer: C
Question: If (x + 1)^2 = 144, which of the following could be the value of 2x?
Options:
A)–26
B)–13
C)–10
D)12
E)-21
Rationale: You can also get to the answer by backsolving using answer choices
Starting with choice B = -13
(x + 1)^2 = 144
(-13 + 1)^2 = 144 =====> (-12)^2 = 144 Bingo, Clearly, among the answer choices only -13 will result in 144 in the equation so x must be -11,
Then 2x = 2 * -13 = -26
Answer: A
Answer: A
Question: A trader sells 78 meters of cloth for Rs. 6788 at the profit of Rs. 29 per metre of cloth. What is the cost price of one metre of cloth?
Options:
A)22
B)75
C)60
D)58
E)11
Rationale: SP of 1m of cloth = 6788/78 = Rs. 87
CP of 1m of cloth = SP of 1m of cloth - profit on 1m of cloth
= Rs. 87 - Rs. 29 = Rs. 58.
Answer: D
Answer: D
Question: Special codes are designated by either a 6-letter or a 7-letter code that is created by using the 26 letters of the alphabet. Which of the following gives the maximum number of different codes that can be designated with this system?
Options:
A)2 (26)^7
B)26(26)^6
C)27(26)^6
D)26(26)^7
E)27(26)^7
Rationale: 26^6+26^7 = 26^6(1+26)=27*26^6
The answer is C.
Answer: C
Question: In a certain alphabet, 11 letters contain a dot and a straight line. 24 letters contain a straight line but do not contain a dot. If that alphabet has 40 letters, all of which contain either a dot or a straight line or both, how many letters contain a dot but do not contain a straight line?
Options:
A)5
B)8
C)14
D)20
E)28
Rationale: We are told that all of the letters contain either a dot or a straight line or both, which implies that there are no letters without a dot and a line (no line/no dot box = 0).
First we find the total # of letters with lines: 11 +24 = 35;
Next, we find the total # of letters without line: 40 - 35 = 5;
Finally, we find the # of letters that contain a dot but do not contain a straight line: 5 - 0 = 5.
A
Answer: A
Question: 5 x 1.6 - 2 x 1.4/1.3 = ?
Options:
A)0.2
B)0.9
C)1.4
D)4
E)None of them
Rationale: Given Expression
= (8 - 2.8)/1.3
= 5.2/1.3
= 52/1.3
= 4.
Answer is D.
Answer: D
Question: A company, Chauncy Co., has an annual travel budget of $54,000. The accounting department estimates that transportation expenses will increase 5 percent in the coming year, and nontransportation travel expenses will increase by 15 percent in the coming year. Last year, Chauncy Co. spent $19,500 on transportation-related expenses, and $35,000 on nontransportation travel expenses. If the annual travel budget does not increase this year, and if the accounting department’s estimates are correct, how far over the annual travel budget will expenses be this year?
Options:
A)Expenses will not go over the budget.
B)$500
C)$4,225
D)$6,725
E)$60,725
Rationale: annual travel budget of $54,000
Let, Transportation expenses = T = 19500
and Non-Transportation expenses = N=35000
i.e. Increased Transportation expenses = 1.05T = 20475
and Increased Non-Transportation expenses = 1.15N = 40250
Total Expense = 20475+40250 = 60725
Expense over Budget = Budget - expense = 54000-60725 = 6725
Answer: Option D
Answer: D
Question: By selling 100 pencil, a trader gains the cost of 10 Pencil. Find his gain percentage?
Options:
A)26 1/3%
B)51 1/3%
C)10%
D)53 1/3%
E)34 1/3%
Rationale: C
10%
Let the CP of each pencil be Rs. 1.
CP of 100 pens = Rs. 100
Profit = Cost of 10 pencil = Rs. 10
Profit% = 10/100 * 100 = 10%
Answer: C
Question: What is the length of a running train?
I. The train crosses a man in 9 seconds.
II.The train crosses a 240 metre long platform in 24 seconds.
Options:
A)I alone sufficient while II alone not sufficient to answer
B)II alone sufficient while I alone not sufficient to answer
C)Either I or II alone sufficient to answer
D)Both I and II are not sufficient to answer
E)Both I and II are necessary to answer
Rationale: Explanation:
Time taken by train to cross a man = Length of train / Speed of train => Speed = L/9 …..(1)
Time taken by train to cross a platform = (Length of train + Length of platform) / speed of train speed = L+240/24 ……(2)
from (1) and (2), we get L/9 = (L+240)/24
Thus, l can be obtained. So both 1 and 2 are necessary to get the answer….
Answer E
Answer: E
Question: A pet store regularly sells pet food at a discount of 10 percent to 30 percent from the manufacturer’s suggested retail price. If during a sale, the store discounts an additional 20 percent from the discount price, what would be the lowest possible price of a container of pet food that had a manufacturer’s suggested retail price o f $ 35.00?
Options:
A)$ 10.00
B)$ 11.20
C)$ 14.40
D)$ 16.00
E)$ 19.60
Rationale: For retail price = $35
First maximum discounted price = 35 - 30% of 35 = 35-10.5 = 24.5
Price after additional discount of 20% = 24.5 - 20% of 24.5 = 24.5- 4.9 = 19.6
Answer: Option E
Answer: E