divelab/Sys2Bench huggingface dataset:
Question: A jar is filled with red, white, and blue tokens that are equivalent except for their color. The chance of randomly selecting a red token, replacing it, then randomly selecting a white token is the same as the chance of randomly selecting a blue token. If the number of tokens of every color is a multiple of 4, what is the smallest possible total number of tokens in the jar?
Options:
A) 9
B) 12
C) 15
D) 18
E) 21
Rationale: (Red / Total Coins)*(White / Total Coins) = (Blue / Total Coins)
i.e. Red*White = Blue*Total Coins
Let, Red = 3a
White = 3b
Blue = 3c
Total Coins = 3(a+b+c)
i.e. 3a * 3b = 3c*3(a+b+c)
i.e. a*b = c*(a+b+c)
For smallest values of a, b and c
2*3 = 1*(1+2+3)
i.e. Minimum Total Coins = 3*(1+2+3) = 18
Answer: Option C
Answer: C
Question: Line m lies in the xy-plane. The y-intercept of line m is -2, and line m passes through the midpoint of the line segment whose endpoints are (2, 8) and (12,2). What is the slope of line m?
Options:
A)-2
B)-1
C)0
D)1
E)2
Rationale: The midpoint of (2,8) and (12,2) is (7,5).
The slope of a line through (0,-2) and (7,5) is (5-(-2))/(7-0) = 7/7 = 1
The answer is D.
Answer: D
Question: A straight pipe 7 yard in length was marked off in fourths and also in thirds. If the pipe was then cut into separate pieces at each of these markings, which of the following gives all the different lengths of the pieces, in fractions of a yard?
Options:
A) 1/6 and 1/4 only
B) 1/4 and 1/3 only
C) 1/6, 1/4, and 1/3
D) 1/12, 1/6 and 1/4
E) 1/12, 1/6, and 1/3
Rationale: Since we want to find the fractions, we can assume some other length of the pipe which will make calculation easier. Take the length of the pipe to be 12-meter long (the least common multiple of 3 and 4.
In this case the branch would be cut at3,4, 6,8, and 9meters (in black are given fourths of the length and in red thirds of the length).
Distinct lengths would be: 3=3/12=1/3, 4-3=1=1/12and 6-4=2=2/12=1/6meters long pieces.
Answer: E.
Answer: E
Question: A father said his son , " I was as old as you are at present at the time of your birth. " If the father age is 32 now, the son age 5 years back was
Options:
A)11
B)17
C)11
D)19
E)99
Rationale: Let the son's present age be x years .Then, (32 - x) = x x= 16.
Son's age 5 years back = (16 - 5) = 11 years
Answer: A
Answer: A
Question: How many integers k greater than 100 and less than 1100 are there such that if the hundreds and the unit digits of k are reversed, the resulting integer is k + 99?
Options:
A)50
B)60
C)70
D)80
E)90
Rationale: Not sure if this is the shortest.. But this is how I did this
There are 9 sets of integers with hundreds and units digits exchanged that satisfies k + 99.
1. 102 | 201 (satisfies k+99, where k = 102)
2. 203 | 302 (satisfies k+99, where k = 203)
3. ...
4. ...
5. ...
6. ...
7. 708 | 807
8. 809 | 908
9. 910 | 1001
Each set has 10 such numbers.
1. 102 | 201 (still k+99 holds good)
2. 112 | 211
3. 122 | 221
4. 132 | 231
5. ...
6. ...
7. ...
8. ...
9. 182 | 281
10. 192 | 291
Therefore, 9 sets with 10 such number in each set will give 9 x 10 = 90 integers.
E
Answer: E
Question: Compound interest of Rs.6000 at 10% per annum for 1 1/2years will be (interest compounded half yearly).
Options:
A)Rs.473
B)Rs.374
C)Rs.495
D)Rs.945
E)None of the above
Rationale: 10% interest per annum will be 5% interest half yearly for 3 terms( 1 1/2 years)
So compound interest=6000[1+(5/100)]^3 - 6000=6000[(21/20)^3 -1]
=6000(9261-8000)/8000
=6*1261/8
=945
ANSWER:D
Answer: D
Question: The speed of a boat in upstream is 50 kmph and the speed of the boat downstream is 90 kmph. Find the speed of the boat in still water and the speed of the stream?
Options:
A)10
B)40
C)88
D)66
E)23
Rationale: Speed of the boat in still water = (50+90)/2 = 70 kmph. Speed of the stream = (90-50)/2 = 20 kmph. Answer:B
Answer: B
Question: On a map the distance between two mountains is 312 inches. The actual distance between the mountains is 140 km. Ram is camped at a location that on the map is 34 inch from the base of the mountain. How many km is he from the base of the mountain?
Options:
A)14.83
B)14.81
C)14.8
D)15.25
E)14.12
Rationale: Explanation:
Since 312 inch = 140 km
So 1 inch = 140/312 km
So 34 inch = (140 Ã— 34)/ 312 = 15.25 km
Answer: D
Answer: D
Question: If the simple interest on Rs. 8010 amount to Rs $3364.20 in 6 Years, calculate the rate percent?
Options:
A)5%
B)6%
C)7%
D)3%
E)9%
Rationale: 3364.20 = (8010*6*R)/100
R = 7%
Answer: C
Answer: C
Question: During the first week of performances of a certain play, 5,400 tickets were sold, all at reduced price. During the remaining weeks of performances, 5 times as many tickets were sold at full price as were sold at reduced price. If the total number of tickets sold Q was 25,200, how many of them were sold at full price?
Options:
A)21,000
B)19,800
C)16,500
D)15,800
E)8,700
Rationale: Given:
The question tells us about the number of tickets sold in the first week at reduced price = 5,400. It also tells us that during the remaining weeks, the number of tickets sold at full price was 5 times the no. of tickets sold at reduced price. The total tickets sold was 25,200, and we are asked to find the number of tickets that where sold at full price.
Approach:
The question asks us to find the number of ticket sold at full price. We know that the number of tickets sold at full price was 5 times the no. of tickets sold at reduced price in remaining weeks. Hence, assuming tickets sold at reduced price in remaining weeks to be x would give us the no. of tickets sold at full price to be 5x.
Tickets sold in first week + Tickets sold in remaining weeks = Total no. of tickets soldi.e.
Tickets sold in first week + Tickets sold at full price in remaining weeks + Tickets sold at reduced price in remaining weeks = Total no. of tickets sold
We know the no. of tickets sold during first week and the total no. of tickets sold. We will use this relation to get to our answer.
Working Out:
Tickets sold in first week + Tickets sold at full price in remaining weeks + Tickets sold at reduced price in remaining weeks = Total no. of tickets sold
Substituting values in the equation, we get
5,400 + 5x + x = 25,200
x= 3,300
Tickets sold at full price = 5x = 16,500
Answer: Option C
Answer: C
Question: When positive integer k is divided by 5, the remainder is 2. When k is divided by 6, the remainder is 5. If k is less than 38, what is the remainder when k is divided by 7?
Options:
A)2
B)4
C)3
D)5
E)6
Rationale: Cant think of a straight approach but here is how I solved it:
K is divided by 5 and remainder is 2. This means k = 5n + 2 (n is an integer)
so the possible values of K = {2, 7, 12, 17, 22, 27, 32, 37} (less than 38)
Secondly, if K is divided by 6, the remainder is 5 => k= 6m + 5
so the possible value set for k = {5, 11, 17, 23, 29,35} (less than 38)
17 is the only common number in both the sets. Hence k = 17
Answer : C
Answer: C
Question: Two drivers began their journey with the same amount of petrol in their cars at the same time. The only difference is that the first driver�s car could drive 4 hours in that amount of petrol and the second one could drive 5 hours.
However, they only drove for some time and found that the amount of petrol that was left in one of the cars was four times the petrol left in the other one.
For how long had they driven at this point of time?
Options:
A)3.75 hours
B)5.45 hours
C)7.10 hours
D)4.75 hours
E)3.33 hours
Rationale: A
3.75 hours
While you can solve it as you like, a simple mathematical equation can be used to find out.
Let M be the amount of petrol initially.
Let N be the time for which they drove.
According to the question, the amount of petrol used by first car in N hours = MN / 4
The amount of petrol used by second car in N hours = MN / 5
Hence, the amount of petrol left in the first car = (M - MN / 4)
The amount of petrol left in the second car = (M - MN / 5)
AS per the details given in the question, we can form the below equation:
M - MN / 5 = 4(M - MN / 4)
N = 15 / 4 or 3.75 hours.
Hence, both the drivers have driven the car for 3.75 hours at that particular time.
Answer: A
Question: A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered.If the area of the field is 680 sq.ft, how many feet of fencing will be required?
Options:
A)44ft
B)88ft
C)22ft
D)11ft
E)66ft
Rationale: Given that length and area, so we can find the breadth.
Length x Breadth = Area
20 x Breadth = 680
Breadth = 34 feet
Area to be fenced = 2B + L = 2 (34) + 20 = 88 feet
Answer: B) 88ft
Answer: B
Question: Three bells chime at intervals of 18 min., 24 min. and 32 min. respectively. At a certain time they begin together. What length L of time will elapse before they chime together again?
Options:
A)2 hr. and 24 min.
B)4 hr. and 48 min.
C)1 hr. and 36 min.
D)5 hr.
E)2 hr.
Rationale: It should be simple. All the three bells will chime again together whenver their time intervals intersect eachother.
So the LCM of the three time intervals (18, 24,32) would be the answer.
LCM (18, 24, 32) L= 288 => 4 hours 48 mins.B
Answer: B
Question: Last year Elaine spent 20% of her annual earnings on rent. This year she earned 15% more than last year and she spent 25% of her annual earnings on rent. The amount she spent on rent this year is what percent of the amount spent on rent last year?
Options:
A) 152.5
B) 143.75
C) 155.5
D) 165.5
E) 117.5
Rationale: For this it is easiest to use simple numbers. Let's assume that Elaine's annual earnings last year were $100.
She would've spent $20 of this on rent.
This year she earned 15% more, or $115.
She would've spent 25% of this on rent, or $28.75
Do $34.5/$20
This will give you 143.75%
B is the correct answer.
Answer: B
Question: The length of the bridge, which a train 150 meters long and travelling at 45 km/hr can cross in 30 seconds, is?
Options:
A)328
B)279
C)225
D)288
E)211
Rationale: Speed = (45 * 5/18) m/sec = (25/2) m/sec. Time = 30 sec. Let the length of bridge be x meters. Then, (150 + X)/30 = 25/2 ==> 2(150 + X) = 750 ==> X = 225 m.Answer: C
Answer: C
Question: A box contains 20 balls, numbered from 1 to 20. If three balls are selected at random and with replacement from the box, what is the probability that the sum of the three numbers on the balls selected from the box will be odd?
Options:
A)1/4
B)3/8
C)1/2
D)5/8
E)3/4
Rationale: I don't think order matters in this case, because 2 + 2 + 1 = 2 + 1 + 2
My answer is: 1/4
A
Answer: A
Question: The average temperature for Monday, Tuesday, Wednesday and Thursday was 48 degrees and for Tuesday, Wednesday, Thursday and Friday was 40 degrees. If the temperature on Monday was 42 degrees. Find the temperature on Friday?
Options:
A)8
B)9
C)10
D)12
E)16
Rationale: M + Tu + W + Th = 4 * 48 = 192
Tu + W + Th + F = 4 * 40 = 160
M = 42
Tu + W + Th = 192 -42 = 150
F = 160 – 150 = 10
ANSWER:C
Answer: C
Question: On a certain date, Pat invested $10,000 at x percent annual interest, compounded annually. If the total value of the investment plus interest at the end of 12 years will be $40,000, in how many years, the total value of the investment plus interest will increase to $240,000?
Options:
A)27
B)16
C)18
D)20
E)24
Rationale: if i were to choose during the test, would go for 18 or 20. probably 18 cuz it wont take too long to get the value doubled....
I found a method: Rule of 72.
Given an x% return, it takes 10,000 to quadralope 12 years.
So according to the rule: 72/x is the no of years 10,000.00 took to double 20,000.00.
Again, 20,000.00 took to double 40,000.00 same (72/x) no of years.
72/x+ 72/x = 12
x = 12% (though rate here is not very much required).
Again, 40,000.00 takes the same (72/x) no of years to double 240,000.00.
72/x = 6 years.
So altogather:
10,000 - 20,000 = 6 years
20,000 - 40,000 = 6 years
40,000 - 80,000 = 6 years
80,000 - 160,000 = 6 years
160,000 - 240,000 = 3 years
total 27 years.
Answer A
Answer: A
Question: Using all the letters of the word "NOKIA", how many words can be formed, which begin with N and end with A?
Options:
A)3
B)6
C)24
D)120
E)12
Rationale: Explanation:
There are five letters in the given word.
Consider 5 blanks ....
The first blank and last blank must be filled with N and A all the remaining three blanks can be filled with the remaining 3 letters in 3! ways.
The number of words = 3! = 6.
ANSWER IS B
Answer: B
Question: If â€˜NAGALANDâ€™ is coded as â€˜EAGACAEDâ€™, then â€˜ODISHAâ€™ is coded as
Options:
A)FDIHJA
B)FIDHAJ
C)FDIHAJ
D)FIDJHA
E)FDIJHA
Rationale: M=13,1+3=4=D
A=1=A
SIMILARLY,
O=15=F
D=4=D
I=9=I
S=19=1+9=10=J
H=8=H
A=1=A
SO ANS IS
FDIJHA
ANSWER:E
Answer: E
Question: A certain ski shop sells pairs of gloves in 11 different colors. If one pair of each color is dropped in a bag and a store clerk reaches in to draw two individual gloves simultaneously and at random, what is the probability that she draws two gloves of the same color?
Options:
A)1/144
B)1/143
C)1/21
D)1/23
E)1/12
Rationale: there are 11 different colours sothere are 11 pairs of gloves dropped..
first can be any of 22..so 22/22..
second has to be its pair, which will be just one out of remaining 21.. 1/21..
overall prob=22/22*1/21= 1/21..
C
Answer: C
Question: If 40% of a number is equal to two-third of another number, what is the ratio of first number to the second number?
Options:
A)1:2
B)2:3
C)5:3
D)3:7
E)9:13
Rationale: Let 40% of A = 2/3 B
then 40A/100 = 2B/3
2A/5 = 2B/3
A/B = 5/3
A:B = 5:3
Answer is C
Answer: C
Question: Last month, John rejected 0.7% of the products that he inspected and Jane rejected 0.8 percent of the products that she inspected. If total of 0.75 percent of the products produced last month were rejected, what fraction of the products did Jane inspect?
Options:
A)1/6
B)1/2
C)5/8
D)5/6
E)15/16
Rationale: X - fraction of products Jane inspected
(1 - X) - fraction of products John inspected
0.8(X) + 0.7(1-X) = 0.75
0.1X = 0.75 - 0.7
X = 0.05/0.1
X = 1/2
Therefore the answer is B: 1/2.
Answer: B
Question: A student chose a number, multiplied it by 2, then subtracted 138 from the result and got 112. What was the number he chose?
Options:
A)123
B)267
C)125
D)267
E)120
Rationale: Let xx be the number he chose, then
2â‹…xâˆ’138=112
x=125
Answer:C
Answer: C
Question: A trader has 1600Kg of sugar. He sells a part at 8% profit and the rest at 12% profit. If he gains 11%
on the whole , find the quantity sold at 12%.
Options:
A)1200 Kg
B)1400 Kg
C)1600 Kg
D)800 Kg
E)None of these
Rationale: Explanation :
By the rule of alligation, we have
% Profit by selling part1 % Profit by selling part2
8 12
Net % Profit
11
12 - 11 = 1 11 - 8 = 3
=>Quantity of part1 : Quantity of part2 = 1 : 3
Given that total quantity = 1600 Kg
Hence quantity of part2 (quantity sold at 12%) = 1600×34=1200
Answer : Option A
Answer: A
Question: Tom planted vegetables in a rectangular garden that was 24 feet long and 15 feet wide. He used
1/3 of the area for corn and 1/5 of it for peas. How many square feet are left for other vegetables?
Options:
A)165 sq. ft.
B)166 sq. ft.
C)167 sq. ft.
D)168 sq. ft.
E)169 sq. ft.
Rationale: area of garden is 24 x 15 = 360 sq. ft.
1/3 x 360 = 120 sq. ft. for corn
1/5 x 360 = 72 sq. ft. for peas
120 + 72 = 192 sq. ft. used
360 - 192 = 168 sq. ft. left over
correct answer D
Answer: D
Question: Six bells commence tolling together and toll at the intervals of 2,4,6,8,10,12 seconds resp. In 60 minutes how many times they will toll together.
Options:
A)15
B)16
C)30
D)31
E)32
Rationale: Explanation:
LCM of 2-4-6-8-10-12 is 120 seconds, that is 2 minutes.
Now 60/2 = 30
Adding one bell at the starting it will 30+1 = 31
Option D
Answer: D
Question: 0.003 * ? * 0.0003 = 0.00000027
Options:
A)9
B)3
C)0.3
D)0.03
E)None of these
Rationale: Explanation:
0.003 * ? * 0.0003 = 0.00000027
3/1000 * ? * 3/10000 = 3/1000 * 3/1000 * 3/100
? = 3/10 = 0.3
ANSWER IS C
Answer: C
Question: Two sets A and B consists only of positive integers such that mean of set A is 70 . If set R consist of all the elements of both A and B such that mean of R is 80 then the mean of set B is =>
Options:
A)[A] 65
B)[B] 60
C)[C] 70
D)[D] 55
E)[E] cannot be determined
Rationale: For this question, we have zero information about the size of two sets, sets AB. These two sets may have the same size or may be wildly different. Thus, the answer is (E), the mathematical answer cannot be determined. This is a very weak math question. As someone who writes GMAT practice questions, I would give this a grade of anD-as a question.
Answer E
Answer: E
Question: A certain car traveled twice as many miles from Town A to Town B as it did from Town B to Town C. From Town A to Town B, the car averaged 8 miles per gallon, and from Town B to Town C, the car averaged 18 miles per gallon. What is the average miles per gallon that the car achieved on its trip from Town A through Town B to Town C?
Options:
A)13
B)15.5
C)14
D)14.5
E)15
Rationale: Ans is B
Given d_ab = 2*d_bc
let d_ab = d and d_bc = x so d=2x
for average miles per gallon = (d+x)/((d/8)+(x/18)) = 15.5 (formula avg speed = total distance/ total time)
Answer: B
Question: The Fisherman sale, all of the prices of the fishes sold were different. If the price of a radio sold at the fisherman sale was both the 4th highest price and the 13th lowest price among the prices of the fishes sold, how many fishes were sold at the fisherman sale?
Options:
A)13
B)14
C)15
D)41
E)16
Rationale: 3+12+1= 16
Answer: E
Answer: E
Question: Each of the following equations has at least one solution EXCEPT A. Is it true?
Options:
A)-3*a = -3-a
B)2*a = (–2)*-a
C)2* -a = (–2)*a
D)(–2)-a = –2-a
E)-2*-a = 2a
Rationale: If we put a=1 then
B. 2
C. -2
D. -3
E. 2
A. -3=-4 not true.
Answer: A
Question: A new tower has just been built at the Verbico military hospital; the number of beds available for patients at the hospital is now 7 times the number available before the new tower was built. Currently, 1/3 of the hospital's original beds, as well as 1/5 of the beds in the new tower, are occupied. For the purposes of renovating the hospital's original wing, all of the patients in the hospital's original beds must be transferred to beds in the new tower. If patients are neither admitted nor discharged during the transfer, what fraction of the beds in the new tower will be unoccupied once the transfer is complete?
Options:
A)67/90
B)29/60
C)17/30
D)19/30
E)11/15
Rationale: I think A - 67/90 is the correct answer.
Here goes:
Lets assume originally the number of beds = x
After the new tower, the total combined no of beds = 7x
So old = x, New = 6x
Now 1/3 of x are occupied and 1/5 of 6x are occupied which simplifies to (6/5)x
We are shifting 1/3 of x to the new ward so there will now be:
1/3 of x plus 6/5 of x occupied in the new ward. Add them up to get 23/15 of x
There are 6x beds in New Tower so ratio is:
(23/15)x / 6x = 23/90 of x
Subtract that from 90/90 of x and you get the number of un-occupied beds to total capacity of New Tower = 67/90.
A
Answer: A
Question: 5+3
Options:
A)8
B)13
C)28
D)6
E)2
Rationale: A
Answer: A
Question: A boy can reach a certain place in 15 hours. If he reduces his speed by 1/30th, he goes 4 km less in that time. Find his speed.
Options:
A)4 km/hr.
B)6 km/hr
C)8 km/hr
D)14 km/hr
E)None of these
Rationale: Explanation :
Solution: Let the speed be x km/hr. then,
15x - (15 * 29x/30) = 4
=> 30x-29x = 4*2
=> x = 8 km/hr.
Answer : C
Answer: C
Question: A dealer purchases 15 articles for Rs. 25 and sells 12 articles for Rs. 30. Find the profit percentage?
Options:
A)33
B)50
C)99
D)87
E)71
Rationale: L.C.M of 15 and 12 = 60
CP of 60 articles = Rs. 100 (25 * 4)
SP of 60 articles = Rs. 150 (30 * 5)
Profit percentage = (150 - 100)/100 * 100 = 50%
Answer: B
Answer: B
Question: If A=x% of y and B=y% of x, then which of the following is true?
Options:
A)A is smaller than B.
B)A is greater than B.
C)Relationship between A and B cannot be determined.
D)If x is smaller than y, then A is greater than B.
E)None of these
Rationale: Explanation :
Given,
A=x% of y=(x/100)×y.
And, B=(y/100)×x
Hence, A = B.
Answer : E
Answer: E
Question: A certain sum is invested at simple interest at 18% p.a. for two years instead of investing at 12% p.a. for the same time period. Therefore the interest received is more by Rs. 504. Find the sum?
Options:
A)7000
B)7029
C)2778
D)4200
E)2791
Rationale: Let the sum be Rs. x.
(x * 18 * 2)/100 - (x * 12 * 2)/100 = 504 => 36x/100 - 24x/100 = 504
=> 12x/100 = 840 => x = 4200.Answer:D
Answer: D
Question: Solve the given two equations and find the inequality of X and Y. (a) 3X^2+8X+4 = 0 and (b) 4Y^2-19Y+12= 0
Options:
A)If x>y
B)If x>=y
C)If x<y
D)If x<=y
E)x=y or relationship cannot be established
Rationale: Solution:-
Solving we get X= -2/3 or -2
Y= 3/4 or 4
C)
Answer: C
Question: What is the greatest possible (straight line) distance, between any two points on a hemisphere of radius 5?
Options:
A)0.1
B)10
C)π/10
D)8
E)π
Rationale: Maximum distance straight line is diameter
d = 2r = 10..
ANS option B.
Answer: B
Question: Find the simple interest on Rs.850 for 10 months at 7 paisa per month?
Options:
A)s.768
B)s.329
C)s.595
D)s.600
E)s.725
Rationale: Explanation:
I = (850*10*7)/100 = 595
Answer: Option C
Answer: C
Question: What is the next number of the following sequence
1,3,4,5,6,7,8,9,1,9,16,25,36,49,64...
Options:
A)14
B)15
C)81
D)17
E)18
Rationale: (1, 3 ,4, 5, 6, 7, 8, 9) (1, 9,16, 25, 36, 49, 64, x)
square of 1st group gives 2nd group
1^2 = 1
3^2 = 9
4^2 = 16
5^2 =25
6^2 =36
7^2 = 49
8^2=64
9^2=81
ANSWER:C
Answer: C
Question: If x and y are integer, which of the following must also be an integer?
I. x/y
II. y/x
III. x
Options:
A)I alone
B)II alone
C)III alone
D)I and III
E)None of the above
Rationale: Let's take X = 4and Y = 3
Then X/Y = 4/3 Not an integer.
Y/X = 3/4 Not an integer.
X alone is 4 which is an integer.
Hence C.
Answer: C
Question: A number increased by 20% gives 480. The number is?
Options:
A)200
B)300
C)400
D)500
E)600
Rationale: Formula = TOTAL=100% ,INCREASE = "+" DECREASE= "-"
A number means = 100 %
That same number increased by 20 % = 120 %
120 % -------> 480 (120 × 4 = 480)
100 % -------> 400 (100 × 4 = 400)
Option 'C'
Answer: C
Question: Two passenger trains start at the same hour in the day from two different stations and move towards each other at the rate of 26 kmph and 21 kmph respectively. When they meet, it is found that one train has traveled 60 km more than the other one. The distance between the two stations is?
Options:
A)288
B)564
C)877
D)278
E)178
Rationale: 1h ----- 5
? ------ 60
12 h
RS = 26 + 21 = 47
T = 12
D = 47 * 12 = 564
Answer: B
Answer: B
Question: 1/2 + [(2/3 * 3/2)/4] - 9/16 =
Options:
A) 1/16
B) 3/16
C) 15/16
D) 9/13
E) 0
Rationale: We need to simplify the expression using PEMDAS.
Parentheses
Exponents
Multiplication andDivision
Addition andSubtraction
The calculation of an equation or expression must be carried out in the following order:
1) Operations within parentheses (or absolute value bars or radicals)
2) Exponents
3) Multiplication and division from left to right
4) Addition and subtraction from left to right
The answer is B.
Answer: B
Question: A Prototype fuel-efficient car (P-Car) is estimated to get 70% more miles per gallon of gasoline
than does a traditional fuel-efficient car (T-Car). However, the P-Car requires a special type
of gasoline that costs 30% more per gallon than does the gasoline used by a T-Car. If the two
cars are driven the same distance, what percent less than the money spent on gasoline for the
T-Car is the money spent on gasoline for the P-Car?
Options:
A)16 2/3%
B)23.53 %
C)50%
D)60%
E)66 2/3 %
Rationale: Assumption
Miles/Gallon
T = 100
P = 170 ( 70% more)
$/gallon
T = 100
P = 130 (30% more)
Miles
100 for both
Cost = (Miles X $/ Gallon)/ M/gallon
T = 100
P = 76.47
Hence 100 - 76.47 = 23.53%
Ans B
Answer: B
Question: Two goods trains each 500 m long are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one?
Options:
A)10
B)40
C)48
D)56
E)34
Rationale: Relative speed = 45 + 30 = 75 km/hr.
75 * 5/18 = 125/6 m/sec.
Distance covered = 500 + 500 = 1000 m.
Required time = 1000 * 6/125 = 48 sec.
Answer: Option C
Answer: C