divelab/Sys2Bench huggingface dataset:
Question: In a basketball game, Tim scored 20 points more than Joe, but only half as many points as Ken. If the three players scored a combined total of 100 points, how many points did Tim score?
Options:
A)15
B)20
C)25
D)30
E)45
Rationale: Let Joe scored point = x
Then Tim Scored = x+20
Ken Scored = 2*(x+20) = 2x+40
As given, x+x+20+2x+40 = 100 points
4x+60 = 100
x = 100-60/4 = 10
So Tim Scored = x +20 i.e) 10+20 = 30
Answer : D
Answer: D
Question: If xy+z = x(y+2z), which of the following must be true?
Options:
A)1. x=0 and z=0
B)2. x=1 and y=1
C)3. y=1 and z=0
D)4. x=1 or y=0
E)5. x=1/2 or z=0
Rationale: xy+z=x(y+2z)
xy+z=xy+2xz
z=2xz
it means x=1/2 or z=0
Answer E
Answer: E
Question: When 2/9 of the votes on a certain resolution have been counted, 3/4 of those counted are in favor of the resolution. What fraction q of the remaining votes must be against the resolution so that the total count will result in a vote of 2 to 1 against the resolution?
Options:
A)11/14
B)13/18
C)4/7
D)3/7
E)3/14
Rationale: If we use variable for total votes there will be too many fractions to manipulate with, so pick some smart #: let set total # of votes is 18.
2/9 of the votes on a certain resolution have been counted--> 4 counted and 18-4=14 votes left to be counted;
3/4 of those counted are in favor of the resolution--> 3 in favor and 1 against;
Ratio of those who voted against to those who voted for to be 2 to 1 there should be total of 18*2/3=12 people who voted against, so in the remaining 14 votes there should be 12-1=11 people who voted against. Thus q=11/14 of the remaining votes must be against.
Answer: A.
Answer: A
Question: A train 550 m long is running with a speed of 60 km/hr. In what time will it pass a man who is running at 6 km/hr in the direction opposite to that in which the train is going?
Options:
A)5
B)6
C)7
D)8
E)30
Rationale: Speed of train relative to man = 60 + 6 = 66 km/hr.
= 66 * 5/18 = 55/3 m/sec.
Time taken to pass the men = 550 * 3/55 = 30 sec.
Answer: Option E
Answer: E
Question: George does 3/5th of a piece of work in 9 days.He then calls in Paul and they finish the work in 4 days.How long would Paul take to do the work by himself?
Options:
A)10
B)20
C)30
D)40
E)50
Rationale: 9day 3/5
1 day 1/15
remaing 1-3/5=2/5
both can do 2/5 work in 4 day
one day work of both=1/10
therfor paul would take 1/10-1/15=1/30 or 30 days
ANSWER:C
Answer: C
Question: If -3/(a - 3) = 3/(a + 2), then a = ?
Options:
A)1/2
B)2/3
C)3/4
D)4/5
E)5/6
Rationale: Multiply all terms of the given equation by (a - 3)(a + 2), simplify and solve
(a - 3)(a + 2)[ -3/(a - 3) ] = (a - 3)(a + 2) [ 3/(a + 2) ]
- 3 (a + 2) = 3 (a - 3)
a = 1/2
correct answer A
Answer: A
Question: Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:
Options:
A)9
B)11
C)13
D)15
E)19
Rationale: Let the three integers be x, x + 2 and x + 4.
Then, 3x = 2(x + 4) + 3 x = 11.
Third integer = x + 4 = 15.
Answer: D
Answer: D
Question: Find the 5th and 7th term of the series 1, 4, 7, 10,...? And their ratio is?
Options:
A)11/13
B)17/13
C)19/13
D)21/13
E)17/15
Rationale: common difference = d = 4 - 1 = 3 ,, n = 5, a = first term = 1-----
By using arithmetic progression , t5 = a + (n-1)*d = 1 + (5-1)*3 = 1+12 = 13
Also 7th term , t7 = a + (n-1)*d = 1 + (7-1) * 3 = 19
Ratio = t7/t5 = 19/13 = ..... Ans - C
Answer: C
Question: A sum is divided among P, Q and R in such a way that for each rupee P gets, Q gets 25 paisa and R gets 15 paisa. If the share of P is RS. 70, what is the total amount?
Options:
A)48
B)84
C)74
D)47
E)64
Rationale: p:q:r = 100:25:15
20:5:3
20 --- 70
28 --- ? => 84
Answer:B
Answer: B
Question: The maximum number of student amoung them 1020 pens and 860 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is :
Options:
A)20
B)40
C)60
D)80
E)None of these
Rationale: Solution
Required number of student = H.C.F of 1020 and 860 = 20. Answer A
Answer: A
Question: Angela has 15 pairs of matched socks. If she loses 5 individual socks, which of the following is NOT a possible number of matched pairs she has left?
Options:
A)8
B)9
C)13
D)11
E)12
Rationale: I think if Angela loses 5 individual socks,then she is bound to have lost minimum of 2 pairs and 1 individual sock,in this way she is left with only 12 pairs of socks (15-(2+1)).
Hence,13 cannot be the answer as maximum is 12.
Hence, option (C)
Answer: C
Question: The sum of a number and the two numbers preceding it is equal to 30. Find the number:
Options:
A)10
B)11
C)9
D)8
E)7
Rationale: Number is 9, AS 9 +10+11=30
Answer: C
Answer: C
Question: Shop Offered 20% offer for every Shirt, Smith bought a shirt at Rs. 780. and What was the shop's original selling Price?
Options:
A)500
B)550
C)600
D)700
E)975
Rationale: SP* (80/100) = 780
SP= 9.75 * 100 => CP = 975
Answer:E
Answer: E
Question: A car traveled 281 miles in 4 hours 41 minutes. What was the average speed of the car in miles per hour?
Options:
A)60 miles / hour
B)50 miles / hour
C)80 miles / hour
D)90 miles / hour
E)40 miles / hour
Rationale: We first convert the time of 4 hours 41 minutes in minutes
4 hours 41 minutes = 4 ? 60 + 41 = 281 minutes
Average speed S is given by distance / time. Hence
S = 281 miles / 281 minutes = 1 mile / minute
= 60 miles / hour
correct answer A
Answer: A
Question: Three numbers are in the ratio 1.5:2:3.5 and their H.C.F is 18. The numbers are:
Options:
A)22,36, 63
B)27,45, 63
C)27,54, 63
D)54, 45, 36
E)27,36, 63
Rationale: Let the required numbers be 1.5x, 2x and 3.5x. Then, their H.C.F = x. So, x = 18.
The numbers are 27,36, 63.
ANSWER:E
Answer: E
Question: An inspector rejects 15% of the meters as defective. How many will he examine to reject 10?
Options:
A)A)100
B)B)66.7
C)C)250
D)D)200
E)E)160
Rationale: Then, 10% of x= 15
(15/100)x = 10
x = (10*100*)/15= 66.7
Answer is B
Answer: B
Question: If the price of a certain computer increased 30 percent from y dollars to 351 dollars, then 2y =
Options:
A)540
B)570
C)619
D)649
E)700
Rationale: Before Price increase Price = y
After 30% Price increase Price = y+(30/100)*y= 1.3y = 351 (Given)
i.e. y= 351/1.3 = $270
i.e. 2y = 2*270 = 540
Answer: option A
Answer: A
Question: Cars P and Q are approaching each other on the same highway. Car P is moving at 48 mph northbound and Car Q is moving at 52 mph southbound. At 2:00 pm, they are approaching each other and 190 miles apart. Eventually they pass each other. At what clock time are they moving away from each other and 35 miles apart?
Options:
A) 3:30 pm
B) 3:45 pm
C) 4:00 pm
D) 4:15 pm
E) 4:30 pm
Rationale: Total distance, which should be covered by both cars is 190+35=225 miles.
Let t be the time so the equation will be 48t+52t=225 thus,
t=2.25 hours
Answer: D
Answer: D
Question: Aarti can do a piece of work in 3 days. In how many days will she complete four time of work of same type?
Options:
A)12 days
B)18 days
C)21 days
D)3 days
E)13 days
Rationale: We have the important relation, More work, More time (days)
A piece of work can be done in 3 days.
Four times of work of same type can be done in 3 x 4
= 12 days
Answer A
Answer: A
Question: A batsman in his 17th innings makes a score of 85 and their by increasing his average by 3. What is his average after the 17thinnings?
Options:
A)27
B)22
C)25
D)37
E)29
Rationale: 16x + 85 = 17(x + 3)
x = 34 + 3 = 37
Answer:D
Answer: D
Question: One day Eesha started 30 min late from home and reached her office 50 min late while driving 25% slower than her usual speed. How much time in min does eesha usually take to reach her office from home?
Options:
A)22
B)60
C)88
D)26
E)18
Rationale: We know that Speed is inversely proportional to time
While she drives 25% slower means she drove at 3434(S)
We know that D = S x T
When speed became 3434(S) then Time taken should be 4343(T)
i.e, She has taken 4343(T) - T extra to cover the distance.
Extra Time = T3T3 = 20 min (as 20 min late due to slow driving)
Actual time T = 60 Minutes
Answer:B
Answer: B
Question: 8, 27, 64, 100, 125, 216, 343
Options:
A)64
B)100
C)125
D)216
E)343
Rationale: The pattern is 2 cube, 3 cube, 4 cube, 5 cube, 6 cube, 7 cube. But, 100 is not a perfect cube.
answer : B
Answer: B
Question: Rajan borrowed Rs.4000 at 5% p.a compound interest. After 2 years, he repaid Rs.2210 and after 2 more year, the balance with interest. What was the total amount that he paid as interest?
Options:
A)635.5
B)613.5
C)975.5
D)653.5
E)670.3
Rationale: 4000
200 ---- I
200
10 ---- II
---------------
4410
2210
--------
2000
110 ---- III
110
5.50 ---- IV
-----------
2425.50
2210
-----------
4635.50
4000
----------
635.50
ANSWER A
Answer: A
Question: Bag A contains red, white and blue marbles such that the red to white marble ratio is 1:3 and the white to blue marble ratio is 2:3. Bag B contains red and white marbles in the ratio of 1:4. Together, the two bags contain 48 white marbles. How many red marbles could be in bag A?
Options:
A)1
B)3
C)4
D)10
E)12
Rationale: 6 is the answer.
Bag A-
R:W:B = 2:6:9
Let W in bag A be 6K
Bab B -
R:W = 1:4
Let W in bag B be 4P
W = 48 = 6K+4P
=> K =6, P=3
Total Red's in bag A will be 2K = 12
E
Answer: E
Question: The Shopkeeper increased the price of a product by 25% so that customer finds it difficult to purchase the required amount. But somehow the customer managed to purchase only 75% of the required amount. What is the net difference in the expenditure on that product?
Options:
A)A)12.5%
B)B)13%
C)C)13.15%
D)D)14%
E)E)93.75%
Rationale: Quantity X Rate = Price
1 x 1 = 1
0.75 x 1.25 = 0.9375
Decrease in price = ( 0.125/1) × 100 =12.5%
A)
Answer: A
Question: A developer has land that has x feet of lake frontage. The land is to be subdivided into lots, each of which is to have either 60 feet or 100 feet of lake frontage. If 1/9 of the lots are to have 60 feet of frontage each and the remaining 40 lots are to have 100 feet of frontage each, what is the value of x ?
Options:
A)400
B)4,300
C)3,700
D)4,400
E)4,760
Rationale: Total number of plots,be T
Plots with 60ft is (1/9)th of total plots.
Plots with 100ft frontage = (8/9) X total number of plots
i.e 8/9 X T = 40 T = 45
Total lake frontage = 40X100 + 5X60 = 4300
Answer : B
Answer: B
Question: What is the ratio of y to x if (x + 3y) / ( x - y) = 3/5?
Options:
A)-1/9
B)-5/3
C)-1/15
D)3/5
E)15/1
Rationale: Solving for y/x gives, -1/9 (A)
Answer: A
Question: The number 7490xy is divisible by 90. Find out (x+y).
Options:
A)4
B)5
C)6
D)7
E)8
Rationale: 10×9=90 where 10 and 9 are co-prime numbers. Hence, if
7490xy is divisible by 9 and 10, it will also be divisible by 90
7490xy is divisible by 10. We know that a number is divisible by 10 if the last digit is 0.
Hence
Thus we have the number
7490x0. If this is divisible by 9,
7+4+9+0+x+0 is divisible by 9
20+x is divisible by 9 (where
x
x is a digit)
x=7
Hence,
(x+y)=(7+0)=7
Answer : D
Answer: D
Question: A man was employed on the promise that he will be paid the highest wages per day. The contract money to be paid was Rs. 1189. Finally he was paid only Rs. 1073. For how many days did he actually work?
Options:
A)39
B)40
C)37
D)35
E)45
Rationale: HCF of 1189, 1073 = 29
1073/29 = 37
ANSWER:C
Answer: C
Question: Ross has 160 shirts, 3/4 of the shirts are green and 1/10 is without buttons. Therefore Ross has between ___ and ___ shirts with buttons that are not green.
Options:
A)24 ; 40.
B)23 ; 40.
C)22 ; 40.
D)21 ; 40.
E)20 ; 40.
Rationale: Total shirts = 160
Green shirts = 3/4*160 = 120, Non green shirts = 40
Shirts without button = 1/10*160 = 16, shirts with button = 144
Required: Range of shirts with buttons that are not green.
Maximum non green shirts with buttons = number of non green shirts = 40
Minimum non green shirts with buttons (All without button shirts are non green) = Non green shirts - shirts without button = 40 - 16 = 24
Hence the range would be (24, 40)
Correct Option: A
Answer: A
Question: What is the sum of the numbers between 1 and 5, inclusive?
Options:
A)5
B)10
C)15
D)20
E)25
Rationale: Sol. add numbers between 1 and 5.
Answer = C, 15.
Answer: C
Question: Working alone at its constant rate, machine A produces x boxes in 10 minutes and working alone at its constant rate, machine B produces 3x boxes in 5 minutes. How many minutes does it take machines A and B, working simultaneously at their respective constant rates, to produce 3x boxes?
Options:
A)3 minutes
B)4 minutes
C)4.2 minutes
D)6 minutes
E)12 minutes
Rationale: Rate = Work / Time
Given Rate of Machine A = X / 10 min
Machine B Produces 3x boxes in 5 min hence , Machine B produces 4x boxes in 10 min .
Rate of Machine B = 6x / 10
we need tofind the combined time that machines A and B, working simultaneouslytakeat their respective constant rates
let's first find the combined Rate of Machine A and B
Rate of Machine A = X / 10 min + Rate of Machine B = 6x / 10 = 7X/10
Now combine Time = combine work needs to be done / Combine Rate = 3x/7x * 10 = 4.2 Min
Ans: C
Answer: C
Question: if the ratio of age of x and y is 5:7.and the sum of the ages are 48.calculate the age of X.
Options:
A)20
B)25
C)30
D)28
E)26
Rationale: 5x+7x=48
12x=48,x=4.
age of X=5x=20.
answer A
Answer: A
Question: A trader mixes 26 kg of rice at Rs. 20 per kg with 30 kg of rice of other variety at Rs. 36 per kg and sells the mixture at Rs. 30 per kg. His profit percent is:
Options:
A)2
B)5
C)6
D)7
E)1
Rationale: C.P. of 56 kg rice = Rs. (26 x 20 + 30 x 36) = Rs. (520 + 1080) = Rs. 1600.
S.P. of 56 kg rice = Rs. (56 x 30) = Rs. 1680.
Gain ={\color{Black} \left ( \frac{80}{1600} \times 100\right ) }% = 5%
Answer: B
Answer: B
Question: Someone on a skateboard is traveling 10 miles per hour. How many feet does she travel in 20 seconds? (1 mile = 5280 feet)
Options:
A)292 ft
B)293.4 ft
C)295 ft
D)296 ft
E)297 ft
Rationale: per second => 10*5280 ft/60*60 =14.67 ft
20 seconds => 14.67 * 20 = 293.4 ft
Answer : B
Answer: B
Question: The present ages of three persons in proportions 2 : 4 : 6. Eight years ago, the sum of their ages was 36. Find their present ages (in years).
Options:
A)10, 20, 30
B)16, 28, 36
C)20, 35, 45
D)18, 24, 32
E)None of these
Rationale: Explanation:
Let their present ages be 2x, 4x and 6x years respectively.
Then, (2x - 8) + (4x - 8) + (6x - 8) = 36
12x = 60
x = 5
Their present ages are 2x = 10 years, 4x = 20 years and 6x = 30 years respectively.
Answer: A
Answer: A
Question: From 2000 onwards, till 2003 the price of computers increased every year by 10%. After that due to government subsidy the price of computers decreases every year by 10%. The price of a computer in 2006 will be approx. how much per cent less than the price in 2000 if the same pattern of price is continued :
Options:
A)2
B)3
C)4
D)5
E)6
Rationale: Solution:
Year	Value
2000	100 (Let)
2001	110
2002	121
2003	133.1
2004	119.79
2005	107.811
2006	97.0299
Now,
[(100-97.0299)*100]/100 ≈ 3
Answer: Option B
Answer: B
Question: x, y, and z are all unique numbers. If x is chosen randomly from the set {8, 9, 10, 11} and y and z are chosen randomly from the set {20, 21, 22, 23}, what is the probability that x and y are prime and z is not?
Options:
A)1/16
B)3/11
C)13/20
D)3/10
E)1/10
Rationale: P(x is prime) = 1/4
P(y is prime) = 1/4
If y is prime, then z is not prime since y and z are unique.
Then the probability is 1/4*1/4 = 1/16
The answer is A.
Answer: A
Question: In a covering a certain distance, the speeds of A and B are in the ratio of 3:4. A takes 30 minutes more than B to reach the destination. The time taken by A to reach the destination is?
Options:
A)1 hrs
B)8 hrs
C)2 hrs
D)6 hrs
E)9 hrs
Rationale: Ratio of speeds = 3:4
Ratio of times taken = 4:3
Suppose A takes 4x hrs and B takes 3x hrs to reach the destination.
Then, 4x - 3x = 30/60 => x = 1/2
Time taken by A = 4x hrs = 4 * 1/2 = 2 hrs.
Answer:C
Answer: C
Question: The H.C.F. of two numbers is 12 and their L.C.M. is 600. If one of the number is 120, find the other?
Options:
A)100
B)60
C)120
D)200
E)150
Rationale: Other number = 12*600/120= 60
Answer is B
Answer: B
Question: Two brother X and Y appeared for an exam. The probability of selection of X is 1/3 and that of B is 2/5. Find the probability that both of them are selected.
Options:
A)2/69
B)2/15
C)2/63
D)2/29
E)2/10
Rationale: Explanation:
Let A be the event that X is selected and B is the event that Y is selected.
P(A) = 1/3, P(B) = 2/5.
Let C be the event that both are selected.
P(C) = P(A) Ã— P(B) as A and B are independent events:
= (1/3) Ã— (2/5) = 2/15
Answer: B) 2/15
Answer: B
Question: Nandesh sold half of his cloth at 10% profit, half of the remaining at 10% loss and the rest was sold at the cost price. In the transaction, his gain or loss will be :
Options:
A)2.5% gain
B)5% gain
C)2.5% loss
D)5% loss
E)None of these
Rationale: Explanation :
Solution: Let C.P. of whole be Rs. X. C.P. of 1/2 stock = Rs. x/2, C.P. of 1/4 stock = Rs. x/4.
Total S.P. = Rs.[(110% of x/2)+(90% of x/4)+x/4] = Rs. (11x/20 + 9x/40 + x/4)
= Rs. 41x/40.
Gain = Rs. (41x/40 - x) = Rs. x/40.
.'. Gain% = (x/40 * 1/x * 100)% = 2.5%
Answer : A
Answer: A
Question: A person buys an article at Rs.575. At what price should he sell the article so as to make a profit of 15%?
Options:
A)600
B)277
C)269
D)661.25
E)281
Rationale: Cost price = Rs.575
profit = 15% of 575= Rs.86.25
Selling price = Cost price + Profit
= 575 + 86.25 = 661.25
Answer: D
Answer: D
Question: A man buys an article and sells it at a profit of 20%. If he had bought it at 20% less and sold it for Rs.75 less, he could have gained 25%. What is the cost price?
Options:
A)379
B)375
C)268
D)269
E)297
Rationale: CP1 = 100 SP1 = 120
CP2 = 80 SP2 = 80 * (125/100) = 100
20 ----- 100
75 ----- ? => 375
Answer:B
Answer: B
Question: How many halves are there in seven-fourth?
Options:
A)8
B)12
C)3.5
D)7
E)3.2
Rationale: divide 7/4 by 1/2
=7/4÷1/2
=7/4*2/1
=14/4
=3.5.
Answer is C.
Answer: C
Question: (1^2+2^2+3^2+.....+8^2)=?
Options:
A)330
B)345
C)204
D)385
E)None of them
Rationale: formula is (1^2+2^2+3^2+....+n^2=1/6 n(n+1)(2n+1)
n=8
=(1/6x8x9x17)
=204
Answer is C.
Answer: C
Question: Income and expenditure of a person are in the ratio 5 : 4. If the income of the person is Rs. 18000, then find his savings?
Options:
A)Rs.3600
B)Rs.3603
C)Rs.3639
D)Rs.3632
E)Rs.3602
Rationale: Let the income and the expenditure of the person be Rs. 5x and Rs. 4x respectively.
Income, 5x = 18000 => x = 3600
Savings = Income - expenditure = 5x - 4x = x
So, savings = Rs.3600.
Answer:A
Answer: A
Question: If w and t are integers and w^2 – t^2 is an odd integer, which of the following must be an even integer?
I. w + t + 2
II. w^2 + 2wt + t^2
III. w^2 + t^2
Options:
A)None
B)I only
C)II only
D)III only
E)I, II, and III
Rationale: w^2–t^2 is an odd integer means that either w is even and t is odd or w is odd and t is even.
Check all options:
I. w + t + 2 --> even+odd+even=odd or odd+even+even=odd. Discard;
II. w^2 + 2wt + t^2 --> even+even+odd=odd or odd+even+even=odd. Discard;
III. w^2 + t^2 --> even+odd=odd or odd+even=odd. Discard.
Answer: A.
Answer: A
Question: There are w members in a certain department, including Michael. Two representatives are to be selected to attend a company conference. If there are 55 possible combinations in which Michael is not selected, what is the value of w?
Options:
A)11
B)12
C)15
D)18
E)22
Rationale: Combinations of two persons, in which Michael was not selected = 55
number of ways two persons can be selected from m people = m*(m-1)/2
Let m be the number of people excluding Michael, then m*(m-1) = 110 => m=11
Thus, w = m + 1(Michael) = 12
option B
Answer: B
Question: In a class ratio of boys and girls is 16:25. If number of total student is 82. Find the number of girls?
Options:
A)36
B)40
C)50
D)38
E)45
Rationale: Let number of girls and boys is 25x and 16x
16x+25x = 82
41x = 82
x = 2
Number of girls = 25*2 = 50
Answer : C
Answer: C
Question: A can do a piece of work in 10 days and B alone can do it in 20 days. How much time will both take to finish the work ?
Options:
A)A)5.333
B)B)6
C)C)6.666
D)D)8.333
E)E)9
Rationale: This question can be solved by different methods. We need to conserve time in exams so solving this problem using equations is the good idea.
Time taken to finish the job = XY / (X + Y)
= 10 x 20 / (10 + 20)
= 200 / 30
= 6.666 days
Answer: C
Answer: C
Question: Seed mixture X is 40 percent ryegrass and 60 percent bluegrass by weight; seed mixture Y is 25 percent ryegrass and 75 percent fescue. If a mixture of X and Y contains 35 percent ryegrass, what percent of the weight of this mixture is X ?
Options:
A) 10%
B) 33.33 %
C) 40%
D) 50%
E) 66.66 %
Rationale: ---------------->Ryegrass
X-------------->	40%
Y-------------->	25%
M(mixture)---->35%
0.4X + (M-X)0.25 = 0.35M
0.15X = 0.10M
X = 0.6666M
X = 66.66% of M
E
Answer: E
Question: The Italian size of a suit jacket is N centimeters, where N is the linear distance between the armpits when the jacket is laid on a flat surface. The American size of a suit jacket is P inches, where P is twice the linear distance between the armpits when the jacket is laid on a flat surface. If, for a particular jacket, N = P + 20, which of the following is closest to the value of N? (One inch is approximately 2.54 centimeters.)
Options:
A)36
B)47
C)58
D)65
E)91
Rationale: Since one inch is approximately 2.54 centimeters, then N centimeters is N/2.54 inches.
Next, since the American size (P inches) is twice the Italian size (N/2.54 inches), then P=2*N/2.54.
As given that N = P + 10, then N=2*N/2.54+20 --> N=~91.
Answer: E.
Answer: E
Question: ----------------YES---------NO----UNSURE
Subject M----500--------200-----100
Subject R----400--------100-----300
A total of 800 students were asked whether they found two subjects, M and R, interesting. Each answer was either yes or no or unsure, and the numbers of students who gave these answers are listed in the table above. If 180 students answered yes only for subject M, how many of the students did not answer yes for either subject?
Options:
A)100
B)220
C)300
D)400
E)500
Rationale: Since 180 students answered yes only for subject M, then the remaining 320 students who answered yes for subject M, also answered yes for subject R. So, 320 students answered yes for both subjects.
If 320 students answered yes for both subjects, then 400-320=80 students answered yes only for subject R.
So, we have that:
200 students answered yes only for subject M;
80 students answered yes only for subject R;
300 students answered yes for both subjects;
Therefore 800-(200+80+300)=220 students did not answer yes for either subject.
Answer: B.
Answer: B
Question: when i was married 10 years ago,my wife was the 6th member in the family.today,my father died,and a baby was born to me.the average age in my family today is what it was when i was married.how old was my father when he died?
Options:
A)50yrs
B)60yrs
C)70yrs
D)80yrs
E)indeterminate
Rationale: 10 years ago the family members there were 6 members with age= I+Father+Wife+3 others
Now 6 members with age= (I+10)+(Wife +10)+ (3 others+3*10) + (baby=0).
I+Father+Wife+3 others=(I+10)+(Wife +10)+ (3 others+3*10) + (baby=0)
Father =50+0 = 50 = Father's age 10 year ago
So now father's age=50 +10=60.
ANSWER:B
Answer: B
Question: A can do a piece of work in 7 days and B can do it in 6 days how long will they both work together to complete the work?
Options:
A)6/11
B)8/13
C)3/13
D)9/11
E)10/13
Rationale: Explanation:
A’s one day work = 1/5
B’s one day work = 1/6
(A+B)’s one day work = 1/7 + 1/6 = 13/42 => time = 42/13 = 3 3/13 days
Answer: Option C
Answer: C
Question: At a certain university, 65% of the professors are women, and 70% of the professors are tenured. If 90% of the professors are women, tenured, or both, then what percent of the men are tenured?
Options:
A)25
B)37.5
C)50
D)62.5
E)75
Rationale: total women = 65%
total men = 40%
total tenured = 70% (both men and women)
therefore, women tenured + women professors + men tenured = 90%
men tenured = 25%
but question wants to know the percent of men that are tenured
25%/40% = 62.5%
D
Answer: D
Question: The marks obtained by Vijay and Amith are in the ratio 4:5 and those obtained by Amith and Abhishek in the ratio of 3:2. The marks obtained by Vijay and Abhishek are in the ratio of?
Options:
A)6:8
B)6:2
C)6:5
D)6:4
E)6:2
Rationale: 4:5
3:2
-------
12:15:10
12:10
6:5
Answer: C
Answer: C