divelab/Sys2Bench huggingface dataset:
Question: Balloons are bought at 8 for Rs.10/- and sold at 10 for Rs.8/-. Find the gain or loss percentage?
Options:
A)36% Loss
B)36% Gain
C)18% Loss
D)18% Gain
E)19% Loss
Rationale: Explanation:
8 Balloons -----> Rs.10/-
10 Balloons ----> Rs.8/-
Note: In every time same in the cost price articles and selling price articles.
10(8 10) ==> 80 100 = Cost price
8(10 8) ==> 80 64 = Selling price
Then, 36/100 × 100 = 36 % Loss
Answer: Option A
Answer: A
Question: Y and Z walk around a circular track. They start at 5 a.m from the same point in the opposite directions. Y and Z walk at a speed of 3 rounds per hour and 4 rounds per hour respectively. How many times shall they cross each other before 7 a.m
Options:
A)14
B)15
C)16
D)17
E)18
Rationale: Explanation:
Relative speed = (3+4) =9 rounds per hour
So, they cross each other 9 times in an hour hence, they cross 18 times before 7 a.m
Answer: Option E
Answer: E
Question: If p is a positive integer and 10p/96 is an integer, then the minimum number of unique prime factors p could have is Q:
Options:
A)Q=1
B)Q=2
C)Q=3
D)Q=4
E)Q=5
Rationale: 10p/96 should resolve to a integer => 5p/48 should resolve to an integer.
Hence p/48 should resolve to a integer.
48 -- > 2^4 * 3.
Hence p should have atleast 2^4*3 for p/48 to resolve to a int.
The unique prime factors in 2^4 * 3 is 2, 3 and hence the answer is B(2).
Answer: B
Question: The boat moves downside 50km and upside 10km in 2 hours each. Then find the boat speed in still water?
Options:
A)10km/hr
B)15km/hr
C)20km/hr
D)25km/hr
E)30km/hr
Rationale: Down stream = 50/2 = 25km/hr
Up stream = 10/2 = 5km/hr
speed of boat in still water = 30/2 = 15km/hr
Answer is B
Answer: B
Question: A number consists of two digits. If the digits interchange places and the new number is added to the original number, then the resulting number will be divisible by:
Options:
A)12
B)27
C)26
D)11
E)99
Rationale: Explanation:
Let the ten's digit be x and unit's digit be y.
Then, number 10x + y.
Number obtained by interchanging the digits = 10y + x.
(10x + y) + (10y + x) = 11(x + y)
which is divisible by 11.
Answer: D
Answer: D
Question: if q=0 and k = qr/2 -s, then what is r in terms of k,q,s?
Options:
A)2k+s/q
B)2sk/q
C)2(k-s)/q
D)2k+sq/q
E)2(k+s)/q
Rationale: k+s=qr/2
2(k+s)=qr
r=2(k+s)/q
ANSWER:E
Answer: E
Question: If k, (k+200), (k+350), and 15*K are all multiples of F, then F could equal which of the following ?
Options:
A)20
B)F=25
C)75
D)100
E)150
Rationale: {Multiple of F} - {Multiple of F} = {Multiple of F}.
(K+200) - k = 200 = {Multiple of F}.
(K+350) - k = 350 = {Multiple of F}.
Both 200 and 350 are multiples of only option B.
Answer: B.
Answer: B
Question: A sum of money is to be distributed among P, Q, and R in the ratio 6:19:7. If R gives Rs. 200 from his share to Q, the ratio of P, Q and R becomes 3:10:3, what is the total sum?
Options:
A)Rs. 4800
B)Rs. 12800
C)Rs. 3200
D)Rs. 7200
E)data inadequate
Rationale: Explanation:
Let the shares of P, Q and R be 6x, 19x and 7x.
By given condition, R’s new share = 7x – 200
Q’s new share = 19x + 200
New ratio = 6x :19x +200:7x-200=3:10:3
P : R = 6x :7x -200=3 :3
6x=7x-200
x=200
Total sum 6x + 19x + 7x = 32x = Rs. 4800
Answer: A
Answer: A
Question: The average weight of 25 persons sitting in a boat had some value. A new person added to them whose weight was 46 kg only. Due to his arrival, the average weight of all the persons decreased by 5 kg. Find the average weight of first 25 persons?
Options:
A)288
B)278
C)297
D)176
E)267
Rationale: 25x + 46 = 26(x – 5)
x = 176
Answer: D
Answer: D
Question: An army’s recruitment process included N rounds of selection tasks. For the first A rounds, the rejection percentage was 60 percent per round. For the next B rounds, the rejection percentage was 50 percent per round and for the remaining rounds, the selection percentage was 70 percent per round. If there were 100000 people who applied for the army and 1400 were finally selected, what was the value of N?
Options:
A)4
B)5
C)6
D)8
E)10
Rationale: Since 70% is accepted and figure will be 1400 therefore in last stage tested/interviewed no. candidates should be 2000
So from here i will work for those two steps of decrements of 100000 candidates.
fastly i reduce 60% till it gets closer to our required 2000 candidates
step(1) 40000 accepted.
step(2) another 40%of 40000=16000 accepted.
here it is quiet observable that if we further deduct candidate by 60% it would change our probablity of easy going 2000 candidate.
so i would get to second stage of recruitment where 50 % is accepted
step(3) 50% of 16000=8000
step(4) 50% of 8000=4000
Step(5) 50% of 4000=2000...here we are done with total 5 steps
and last step of accepting 70% of 2000=1400(our target)
total 6 steps required.
Answer: C
Answer: C
Question: If x=-3, which of the following is(are) true? I. x^2=-|x| II |x|=-x III x/-3 = -1
Options:
A)II, III only
B)II only
C)I,II only
D)I only
E)III only
Rationale: I. x^2=-|x| -3^2 = - |-3| Not true
II |x|=-x |-3| =-( -3 ) true
III x/-3 = -1 Not true
Answer : B
Answer: B
Question: A bag contains 4 black, 5 yellow and 6 green balls. Three balls are drawn at random from the bag. What is the probability that all of them are yellow?
Options:
A)2/81
B)2/91
C)1/81
D)1/91
E)1/51
Rationale: Total number of balls = 4 + 5 + 6 = 15
n(S) = tot no of ways of drawing 3 balls out of 15 =15c3
let E = event of drawing 3 balls
n(E) = no of ways of drawing 3 balls
= no of ways of drawing 3 balls from the total 5 = 5c3
=>(5*4/2*1)/(15*14*13/3*2*1)=2/91
ANSWER B
Answer: B
Question: A trucking company plans to gradually replace their older fleet of trucks with newer more energy efficient ones. Every year it plans to retire 6 trucks and buy 8 newer ones. How many years starting from 2005 will it take to reduce its fleet of 40 old trucks to less than half its fleet?
Options:
A)8
B)2
C)5
D)6
E)3
Rationale: Total fleet--40
End of year 2005 -- (retires 6 and buys 8) total fleet--42(34 old 8 new).
End of year 2006 -- (retires 6 and buys 8) total fleet--44(28 old 16 new).
End of year 2007 -- (retires 6 and buys 8) total fleet--46(22 old 24 new).
Answer is E--after 3 years the company has a total of 56 taxis (20 old 36 new), the old taxis are already less than 50% of its fleet.
Answer: E
Question: A pack of baseball cards consists of 12 outfielder cards and 8 infielder cards. What is the lowest number of outfielder cards that would have to be removed from the pack so that no more than 35 percent of the pack would be outfielder cards?
Options:
A)4
B)5
C)6
D)7
E)8
Rationale: let the number of O card to be removed=X
then remaning cards=12-X
now this 12-X cards should count less than 35% of toatal Ocards
12-X<.35*12
X>12-4.2
X>7.8
X=8
Ans E
Answer: E
Question: A can do a piece of work in 4 days. B can do it in 15 days. With the assistance of C they completed the work in 24 days. Find in how many days can C alone do it?
Options:
A)0.391 days
B)0.491 days
C)0.331 days
D)1.391 days
E)0.301 days
Rationale: C = 1/2 - 1/24 - 1/15 = 0.391 days
ANSWER:A
Answer: A
Question: what is the compound interest on rs:70,000 for 4 months at the rate of 5% per annum
Options:
A)1171.98
B)1172.98
C)1173.98
D)1174.98
E)1175.98
Rationale: it is monthly compound
rate=5/12% per month
70000*(1+5/1200)^4-70000=1173.98
ANSWER:C
Answer: C
Question: A bus trip of 660 miles would have taken 1 hour less if the average speed V for the trip had been greater by 5 miles per hour. What was the average speed V, in miles per hour, for the trip?
Options:
A)40
B)45
C)50
D)55
E)60
Rationale: The time is the distance/speed. The time difference is 1 hour.
660/V - 660/(V+5) = 1
660(V+5) - 660V = (V)(V+5)
3300 = (V)(V+5)
55*60 = (V)(V+5)
V = 55 mph
The answer is D.
Answer: D
Question: A worker's daily wage is increased by 50% and the new wage is $51 per day. What was the worker's daily wage before the increase?
Options:
A)$28
B)$32
C)$34
D)$35
E)$40
Rationale: Let x be the daily wage before the increase.
1.5x = $51
x = $34
The answer is C.
Answer: C
Question: A salt manufacturing company produced a total of 5000 tonnes of salt in January of a particular year. Starting from February its production increased by 100 tonnes every month over the previous months until the end of the year. Find its average monthly production for that year?
Options:
A)5578
B)5552
C)5550
D)5528
E)5598
Rationale: Total production of salt by the company in that year
= 5000 + 5100 + 5200 + .... + 6100
= 66600.
Average monthly production of salt for that year
= 66600/12 = 5550.
Answer:C
Answer: C
Question: Sides of a rectangular park are in the ratio 3: 2 and its area is 3750 sq m, the cost of fencing it at 70 ps per meter is?
Options:
A)287
B)369
C)175
D)279
E)361
Rationale: 3x * 2x = 3750 => x = 25
2(75 + 50) = 250 m
250 * 0.70
= Rs.175
Answer:C
Answer: C
Question: The average of five integers is 56, and none of these integers is greater than 100. If the average of three of the integers is 59, what is the least possible value of one of the other two integers?
Options:
A)3
B)15
C)20
D)21
E)30
Rationale: When it comes to averages, we know thataverage value = (sum of n values)/n
We can rewrite this into a useful formula:sum of n values = (average value)(n)
The average of five integers is 56
So, the sum of ALL 5 integers = (56)(5) =280
The average of three of the integers is 65
So, the sum of the 3 integers = (59)(3) =177
So, the sum of the 2 REMAINING integers =280-177=103
If the sum of the 2 REMAINING integers =103, and we want to minimize one value, we must MAXIMIZE the other value.
100 is the maximum value so let 1 integer = 100, which means the other must equal 3
Answer: A
Answer: A
Question: The average (arithmetic mean) of seven numbers is 7. If 4 is subtracted from each of three of the numbers, what is the new average?
Options:
A)4.2
B)6.3
C)5.2
D)7.9
E)8.3
Rationale: Sum of 7 numbers = 7*7=49
If4 is subtracted from each of three of the numbers , we subtract 4*3=12 from the total sum
Sum of 7 number after subtracting 4 from each of three of the numbers =49-12=37
New average = 37/7=5.2
Answer C
Answer: C
Question: If y = 30p, and p is prime, what is the greatest common factor of y and 14p, in terms of p?
Options:
A)p
B)2p
C)5p
D)7p
E)p^2
Rationale: Y=30p
other number is 14p
then GCF(30p,14P)=2P; B is the correct answer
Answer: B
Question: A train 600 m long can cross an electric pole in 20 sec and then find the speed of the train?
Options:
A)72
B)67
C)108
D)26
E)27
Rationale: Length = Speed * time
Speed = L/T
S = 600/20
S = 30 M/Sec
Speed= 30*18/5 (To convert M/Sec in to Kmph multiply by 18/5)
Speed = 108 Kmph
Answer:C
Answer: C
Question: Two trains are running in opposite directions with the same speed. If the length of each train is 60 metres and they cross each other in 12 seconds, then the speed of each train (in km/hr) is:
Options:
A)8 km/hr.
B)32 km/hr.
C)34 km/hr.
D)18 km/hr.
E)12 km/hr.
Rationale: Let the speed of each train be x m/sec.
Then, relative speed of the two trains = 2x m/sec.
So, 2x = (60 + 60)/12
2x = 10
x = 5.
Speed of each train = 5 m/sec = 5 x 18/5 km/hr = 18 km/hr.
answer :D
Answer: D
Question: Find the value for m?
21(m + n) + 21 = 21(-m + n) + 21
Options:
A)0
B)-1
C)1
D)2
E)3
Rationale: 21m + 21n - 21 = -21m + 21n + 21
42m= 42 => m = 1
C
Answer: C
Question: Excluding the stoppages, the speed of a bus is 48 km/hr and including the stoppages the speed of the bus is 12 km/hr. For how many minutes does the bus stop per hour?
Options:
A)45 min
B)10 min
C)12 min
D)20 min
E)18 min
Rationale: Speed of the bus without stoppage=48 km/hr
Speed of the bus with stoppage=12 km/hr
Difference in speed=36 km/hr
so,the time taken in the stoppages = time taken to cover 36 km=(36/48)hr = 3/4 hr =45 min
ANSWER:A
Answer: A
Question: rahul played weel in this season.his current batting averagge is 50.if he score 78 runs in today match.his batting average will become 54.how many matches had he played in this season.
Options:
A)8
B)10
C)9
D)6
E)5
Rationale: 50x+78=54(x+1)
=>4x=24
=>x=6
ANSWER:D
Answer: D
Question: If 4x - y = 32 and −x + 2y = 5, then what is the value of 3x + y?
Options:
A)37
B)3
C)15
D)52/7
E)60/7
Rationale: 4x - y = 32
−x + 2y = 5
Adding both the equations --> 3x + y = 37
Answer: A
Answer: A
Question: Evaluate 2+22+222+2.22
Options:
A)269.72
B)268.22
C)248.21
D)248.22
E)268.21
Rationale: 2+22+222+2.22=248.22
Option D
Answer: D
Question: In what time will a railway train 60 m long moving at the rate of 36 kmph pass a telegraph post on its way?
Options:
A)7 sec
B)8 sec
C)9 sec
D)6 sec
E)1 sec
Rationale: T = 60/36 * 18/5
= 6 sec
Answer: D
Answer: D
Question: S = { 1,5,3,7}
T = { 4,5,6,7 }
what is the probability that x chosen from S and y chosen from T will result x*y = even
Options:
A)1/3
B)4/5
C)2/3
D)1/2
E)1/6
Rationale: p: the probability that x*y is even, then p=1-p(x*y is odd)
p(x*y odd)=p(x odd)*p(y odd)=4/4*2/4=2/4
And p=1-2/4=1/2
Option: D
Answer: D
Question: P and Q need 8 days to complete a work. Q and R need 12 days to complete the same work. But P, Q and R together can finish it in 6 days. How many days will be needed if P and R together do it?
Options:
A)4
B)8
C)12
D)16
E)18
Rationale: Let work done by P in 1 day = p
work done by Q in 1 day =q
Work done by R in 1 day = r
p + q = 1/8 ---(1)
q + r= 1/12 ---(2)
p+ q+ r = 1/6 ---(3)
(3) – (2) => p = 1/6 - 1/12 = 1/12
(3) – (1) => r = 1/6 – 1/8 = 1/24
p + r = 1/12 + 1/24 = 3/24 = 1/8
=> P and R will finish the work in 8 days
Answer is B.
Answer: B
Question: In how many different ways can the letters of the word 'APPLE' be arranged?
Options:
A)10 ways
B)20 ways
C)30 ways
D)60 ways
E)40 ways
Rationale: Totally there are 5 letters on the word APPLE. it contains 1A,2P,1L,1E.
The no of ways is 5!/2!=120/2=60 ways.
ANSWER:D
Answer: D
Question: A Man travelled a distance of 61 km in 9 hours. He travelled partly on foot at 4 km/hr and partly on
bicycle at 9 km/hr. What is the distance travelled on foot?
Options:
A)16 km
B)14 km
C)12 km
D)10 km
E)None of these
Rationale: Explanation:
Let the time in which he travelled on foot = x hour
Time for travelling on bicycle = (9 - x) hr
Distance = Speed * Time, and Total distance = 61 km
So,
4x + 9(9-x) = 61
=> 5x = 20
=> x = 4
So distance traveled on foot = 4(4) = 16 km
Answer: Option A
Answer: A
Question: 15, 31, 63, 127, 255, ?
Options:
A)543
B)447
C)972
D)532
E)511
Rationale: E
511
Each number is double of the preceding one plus 1.
Answer: E
Question: Sum of 3 consecutive even no.'s is 26 more than the 1st no. of the series. Find the middle no.?
Options:
A)9
B)12
C)15
D)17
E)19
Rationale: Let the numbers be x, x+2 and x+4 then
x + x+2 + x+4 = x+26
3x + 6 = x + 26
2x = 20
\inline \therefore x = 10
\inline \therefore Middle number = x + 2 = 10+2 = 12
B
Answer: B
Question: What is the area of a square field whose diagonal of length 24 m?
Options:
A)240 sq m
B)250 sq m
C)200 sq m
D)400 sq m
E)800 sq m
Rationale: d2/2 = (24 * 24)/2 = 240
ANSWER:A
Answer: A
Question: A man can row downstream at 18 kmph and upstream at 10 kmph. Find the speed of the man in still water and the speed of stream respectively?
Options:
A)14, 2
B)16, 4
C)14, 8
D)14, 4
E)14, 1
Rationale: Let the speed of the man in still water and speed of stream be x kmph and y kmph respectively.
Given x + y = 18 --- (1)
and x - y = 10 --- (2)
From (1) & (2) 2x = 28 => x = 14,y = 4.
Answer: D
Answer: D
Question: A metallic sphere of radius 12 cm is melted and drawn into a wire, whose radius of cross section is 16 cm. What is the length of the wire?
Options:
A)6
B)8
C)5
D)3
E)9
Rationale: Volume of the wire (in Cylindrical shape) is equal to the volume of the sphere.
π(16)2 * h = (4/3)π (12)3 => h
= 9 cm
Answer:E
Answer: E
Question: A train 140 m long passes a man,running at 6 kmph in the direction opposite to that of the train,in 6 seconds.The speed of the train is
Options:
A)54 kmph
B)60 kmph
C)66 kmph
D)72 kmph
E)78 kmph
Rationale: speed of train relative to man: 140/6 * 18/5 km/hr
= 84 km/hr
let speed of train= x
therefore x+6 = 84
x= 84-6
x=78 km/hr
ANSWER:E
Answer: E
Question: A and B began business with Rs.3000 and Rs.4000 after 8 months, A withdraws Rs.1000 and B advances Rs.1000 more. At the end of the year, their profits amounted to Rs.756 find the share of A.
Options:
A)240
B)388
C)288
D)277
E)122
Rationale: Explanation:
(3*8 + 2*4):(4*8 + 5*4)
8:13
8/21 * 756 = 288
Answer: C
Answer: C
Question: In the standard formulation of a flavored drink the ratio by volume of flavoring to corn syrup to water is 1 : 12 : 30. In the sport formulation, the ratio of flavoring to corn syrup is three times as great as in the standard formulation, and the ratio of flavoring to water is half that of the standard formulation. If a large bottle of the sport formulation contains 6 ounces of corn syrup, how many ounces of water does it contain?
Options:
A)15
B)30
C)45
D)60
E)90
Rationale: Standard:
Fl: Corn S: Water = 1:12:30
Sport:
Fl: Corn S: Water = 3:12:180
This simplifies to 1:4:60
If the large bottle has a capacity of x ounces, then
4x / 65 = 6.
So, x = 195 / 2 ounces.
Water = (60 / 65) * (195 / 2) = 60 * 3 / 4 = 90 ounces.
Ans E
Answer: E
Question: If a, b, and c are consecutive even positive integers, which of the following could be equal to a + b + c ?
Options:
A)141
B)200
C)412
D)391
E)612
Rationale: The key to answering this question quickly is to realize that a+b+c is a multiple of BOTH 2 and 3. With that information, you can quickly eliminate answer choices. If you don't recognize those two Number Properties though, then you can still get to the correct answer (but it will require a bit more work).
We're told that a, b and c are CONSECUTIVE EVEN INTEGERS, so we could write them algebraically as...
A + (A+2) + (A+4) = 3A + 6
We know that 3A + 6 COULD equal one of those five answers; we just have to find it...
Could 3A + 6 = 141
3A = 135
A = 45
This is NOT an EVEN INTEGER, so 141 is NOT the answer
Could 3A + 6 = 200
3A = 194
A = 64.6666
This is NOT an EVEN INTEGER, so 200 is NOT the answer
Could 3A + 6 = 412
3A = 406
A = 135.3333
This is NOT an EVEN INTEGER, so 412 is NOT the answer
Could 3A + 6 = 612
3A = 606
A = 202
This IS an EVEN INTEGER! The numbers would be 202, 204 and 206. This IS the answer
Final Answer:
E
Answer: E
Question: If |5x-10| = 100, then find the sum of the values of x?
Options:
A)1
B)-2
C)3
D)-3
E)4
Rationale: |5x-10| = 100
5x-10 = 100 or 5x-10 = -100
5x = 110 or 5x = -90
x = 22 or x = -18
sum = 21-18 = 3
Answer is C
Answer: C
Question: What is the are of an equilateral triangle of side 16 cm?
Options:
A)64√6
B)64√9
C)64√4
D)64√3
E)64√2
Rationale: Area of an equilateral triangle = √3/4 S2
If S = 16, Area of triangle = √3/4 * 16 * 16 = 64√3 cm2;
Answer: D
Answer: D
Question: Four packages have an average weight of 11.5 pounds. What is the minimum possible weight of the heaviest package in pounds if the median is 10 pounds?
Options:
A)11
B)11.5
C)13
D)15
E)16
Rationale: Let us denote the weights of the packages in pounds by a, b, c, d naming from the lightest one to the heaviest one. The median is 10 pounds. Therefore (b + c) / 2 = 10.
b + c = 20
The average is 11.5 pounds. Therefore (a + b + c + d) / 4 = 11.5.
a + (b + c) + d = 46
a + 20 + d = 46
a + d = 26
The weight a must be no greater than 10, since 10 is the median. Therefore the minimum possible weight of the heaviest package is 26 – 10 = 16 pounds (all the other packages would weigh 10 pounds in this case).
Answer: E
Answer: E
Question: If log(2a - 3b) = log a - log b, then a =
Options:
A)3b2/2b -1
B)3b/2b -1
C)b2/2b + 1
D)3b2/2b + 1
E)None of these
Rationale: 2a- 3b = a/b
=>2ab - 3b2 = a
=>3b2 = a(2b - 1)
Therefore, a = 3b2/2b -1.
ANSWER:A
Answer: A
Question: A and B start a business with Rs.5000 and Rs.7000 respectively. Hoe should they share their profits at the end of one year?
Options:
A)3:5
B)5:7
C)3:9
D)5:3
E)3:2
Rationale: They should share the profits in the ratio of their investments.
The ratio of the investments made by A and B =
5000 : 7000 => 5:7,Answer: B
Answer: B
Question: How many different three-digit multiples of 5 can be composed of digits 2, 3, 4, and 5 if none of the digits is repeated?
Options:
A)3
B)6
C)10
D)12
E)18
Rationale: Available: 2, 3, 4, 5
You need to make 3 digit numbers which are multiples of 5.
___ ___ ___
For the number to be a multiple of 5, it must end with either 0 or 5. We only have 5 available so the number must end with 5.
___ ___ 5
Now you select 2 numbers out of the leftover 3 numbers (2, 3 and 4) in 3C2 ways and arrange them in the 2 places in 2! ways which gives you 3C2*2! = 6
or you can say that you can select a number for the hundreds place in 3 ways and select a number for the tens place in 2 ways (since numbers cannot be repeated). So you can make the number in 3*2 = 6 ways
ANS:B
Answer: B
Question: Which of the following is the lowest positive integer that is divisible by 7, 8, 9, 10, and 11?
Options:
A)27,720
B)29,940
C)31,960
D)33,970
E)35,890
Rationale: The number needs to be divisible by 7, 2^3, 3^2, 2*5, and 11.
The lowest positive integer is 7 * 2^3 * 3^2 * 5 * 11 = 27,720
The answer is A.
Answer: A
Question: A sum of money lent out at S.I. amounts to a total of $420 after 2 years and to $595 after a further period of 5 years. What was the initial sum of money that was invested?
Options:
A)$310
B)$320
C)$330
D)$340
E)$350
Rationale: S.I for 5 years = $595 - $420 = $175
The S.I. is $35/year
S.I. for 2 years = $70
Principal = $420 - $70 = $350
The answer is E.
Answer: E
Question: 5/9 of the part of the population in a villagae are males.if 30 % of the males are married.the percentage of unmarried females in the total population is..
Options:
A)250/9%
B)150/9%
C)350/9%
D)450/9%
E)550/9%
Rationale: Let total population = p
no. of males =5p/9
no. of females =(p-5p/9)=4p/9
married males = 30% of 5p/9=30*5p/100*9 =p/6
married females = p/6
unmarried females =(4p/9-p/6)=5p/18
%age of unmarried females in the total population = {(5p/18)/p}*100= 250/9%
ANSWER:A
Answer: A
Question: Find the value of (50+ 20/90) × 90
Options:
A)2520
B)3520
C)4520
D)1520
E)1750
Rationale: (4500+20)/90*90 = 4520
Answer : C
Answer: C
Question: A train leaves Mumabai at 9 am at a speed of 40 kmph. After one hour, another train leaves Mumbai in the same direction as that of the first train at a speed of 50 kmph. When and at what distance from Mumbai do the two trains meet?
Options:
A)338
B)378
C)200
D)298
E)122
Rationale: When the second train leaves Mumbai the first train covers 40 * 1 = 40 km
So, the distance between first train and second train is 40 km at 10.00am
Time taken by the trains to meet
= Distance / relative speed = 40 / (50 -40) = 4 hours
So, the two trains meet at 2 p.m. The two trains meet 4 * 50 = 200 km away from Mumbai.
Answer: C
Answer: C
Question: A can complete a project in 30 days while B can complete same project in 30 days. If A and B start working together and A leaves the work 10 days before completion of project, then in how many days the project will be completed?
Options:
A)18
B)19
C)20
D)21
E)22
Rationale: A's 1day work=1/30;
B's 1day work=1/30;
(A+B) 1day work=(1/30+1/30)=1/15;
It is given that A leaves the work 10 days before completion of the project..
Thus,B alone does the remaining job in 10 days.
So,In 10 days ,B can do 1/3 w ..
Thus,(A+B) have worked (1-1/3)=2/3 w..
(A+B)can do 1/15 work in 1 day...
They did 2/3 w in 10 days.
Total days=(10+10) = 20
ANSWER:C
Answer: C
Question: If a sum of money doubles itself in 5 years at simple interest, the ratepercent per annum is
Options:
A)12
B)12.5
C)20
D)13.5
E)14
Rationale: Explanation:
Let sum = x then Simple Interest = x
Rate = (100 * x) / (x * 5) = 20
Option C
Answer: C
Question: Mr. Smitherly leaves Cedar Rapids at 8:00 a.m. and drives north on the highway at an average speed of 50 km per hour. Mr. Dinkle leaves Cedar Rapids at 8:30 a.m. and drives north on the same highway at an average speed of 55 km per hour. Mr. Dinkle will
Options:
A)overtake Mr. Smitherly at 10:30 a.m.
B)overtake Mr. Smitherly at 11:30 a.m.
C)overtake Mr. Smitherly at 1:30 p.m.
D)be 30 miles behind at 9:35 a.m.
E)never overtake Mr. Smitherly
Rationale: After thirty minutes, Mr. Smitherly is ahead by 25 km.
Mr. Dinkle gains on Mr. Smitherly 5 km each hour.
5 hours after 8:30 a.m., Mr. Dinkle will catch Mr. Smitherly.
The answer is C.
Answer: C