divelab/Sys2Bench huggingface dataset:
Question: Three unbased coins are tossed. the probability of getting at most three T is ?
Options:
A)1/2
B)7/8
C)3/4
D)1/8
E)2/3
Rationale: S={TTT,TTH,THT,HTT,THH,HTH,HHT,HHH}
E be the event of getting at least two head is {TTT}
P(E)=n(E)/n(S)=1/8
Answer(D)
Answer: D
Question: If 130/x is an integer and 108/x is an integer, which of the following must be true?
I. 9/x is an integer
II. 12/x is an integer
III. 36/x is an integer
Options:
A)I only
B)III only
C)I and II only
D)II and III only
E)I, II and III
Rationale: I think, here we should use the greatest common factor.
The greatest common factor for 144 and 108 is 36.
So 36/x is an integer.
For the rest of the answers, if x is 36 then 9/x and 12/x leads to fractions.
Ans is A.
Answer: A
Question: A clock is started at noon. By 10 minutes past 7, the hour hand has turned through how many degrees?
Options:
A)205Â°
B)210Â°
C)215Â°
D)220Â°
E)225Â°
Rationale: The angle traced by the hour hand in 12 hrs is 360Â°
The angle traced by the hour hand in 1 hour is 30Â°
The angle traced by the hour hand in 10 minutes is 5Â°
The angle traced by the hour hand in 7 hours and 10 minutes is 7*30Â° + 5Â° = 215Â°
The answer is C.
Answer: C
Question: Find the area of circle whose radius is 14m?
Options:
A)187
B)154
C)377
D)488
E)616
Rationale: 22/7 * 14 * 14
= 616
Answer:E
Answer: E
Question: A and B invests Rs.8000 and Rs.9000 in a business. After 4 months, A withdraws half of his capital and 2 months later, B withdraws one-third of his capital. In what ratio should they share the profits at the end of the year?
Options:
A)20:23
B)34:43
C)32:45
D)37:45
E)37:35
Rationale: A : B
(8000*4)+(4000*8) : (9000*6)+(6000*6)
64000 : 90000
32 : 45
ANSWER:C
Answer: C
Question: The difference between the place value and the face value of 6 in the numeral 856973 is
Options:
A)973
B)6973
C)5994
D)6084
E)None of these
Rationale: (Place value of 6) - (Face value of 6) = (6000 - 6) = 5994
Answer: Option C
Answer: C
Question: A group of people were given 2 puzzles. 77% people solved puzzle X and 89% people solved puzzle Y. What is the maximum and minimum percentage of people who could have solved both the puzzles?
Options:
A) 11%, 0%
B) 77%, 63%
C) 68%, 57%
D) 79%, 68%
E) 89%, 79%
Rationale: To solve this question, we don't need any formulas. Just read the question carefully. If 77% of the people solved puzzle X and 89% solved puzzle Y, then maximum % that can solve both correctly can only be 77%. From the given options, only D looks good
Answer B
Answer: B
Question: There is an antique clock exhibition. So many clock are piled up with distinct numbers tagged with them. The person managing it hangs different clocks numbers periodically on the main wall. At 9:20 am, he hung the clock number 200; at 11:00 am, he hung the clock number 30; at 4:00 pm, he hung the clock number 240.
Which numbered clock will he hang on the wall when the time is 7:30pm ?
Options:
A)313
B)314
C)315
D)316
E)317
Rationale: Solution:
He will hang clock number 315 at 7:30pm. The person has been hanging the clock number which corresponds with the angle between the hour hand and the minute hand of the clock at that time.
Answer C
Answer: C
Question: In your classes you counted 124 hands. How many students were at the class?
Options:
A)62
B)61
C)85
D)86
E)88
Rationale: Total number of hands = 124
We have 2 hands.
To find how many students were at the class, divide the total number of hands by the number of hands we have.
We get, divide 124 by 2
124 ÷ 2 = 62
Therefore, there were 62 students at the class.
ANSWER IS A
Answer: A
Question: If Rs.450 amount to Rs.540 in 4 years, what will it amount to in 6 years at the same rate % per annum?
Options:
A)587
B)287
C)585
D)658
E)572
Rationale: 90 = (450*4*R)/100
R = 5%
I = (450*6*5)/100 = 135
450 + 135
=585
Answer:C
Answer: C
Question: Sachin is 40 years old and Ajith is 60 years old. How many decades ago was the proportion of their ages 3 : 5?
Options:
A)10
B)69
C)37
D)21
E)20
Rationale: A
10
If the ratio was 3 : 5, ‘A’ years ago.
Then, 7A – 6A = 4
A = 4
Then, {( 40 – A)/(60 – A)}= (3/5)
5 (40 – A) = 3(60 – A)
2A = 20
A = 10
Answer: A
Question: There are 14 students in a class. On the day the test was given, Dan was absent. The other 13 students took the test and their average was 75. The next day, Dan took the test, and with this grade included, the new average was 76. What was Dan's grade on the test?
Options:
A)86
B)87
C)88
D)89
E)90
Rationale: 13*75+Dan's grade=14*76
Dan's grade is 14*76-13*75=89.
The answer is D.
Answer: D
Question: Fox jeans regularly sell for $15 a pair and Pony jeans regularly sell for $18 a pair. During a sale these regular unit prices are discounted at different rates so that a total of $8.73 is saved by purchasing 5 pairs of jeans: 3 pairs of Fox jeans and 2 pairs of Pony jeans. If the sum of the two discount rates is 22 percent, what is the discount rate on Pony jeans?
Options:
A)9%
B)10%
C)11%
D)12%
E)13%
Rationale: Let x be the discount on Pony jeans. Then 0.22-x is the discount on Fox jeans.
3(0.22-x)(15) + 2x(18) = 8.73
9.9 - 45x + 36x = 8.73
9x = 1.17
x = 0.13
The answer is E.
Answer: E
Question: The mean of 50 observations was 36. It was found later that an observation 48 was wrongly taken as 23. The corrected new mean is?
Options:
A)36.7
B)36.1
C)36.5
D)36.9
E)36.3
Rationale: Correct sum
= (36 * 50 + 48 - 23)
= 1825.
Correct mean = 1825/50
= 36.5
Answer:C
Answer: C
Question: The present ages of three persons are in the proportion of 4 : 7 : 9. Eight years ago, the sum of their ages was 96. Find their present ages.
Options:
A)24,42,54
B)8,20,28
C)16,28,36
D)16,28,46
E)None of these
Rationale: Let the present ages of three persons be 4K,7K and 9K respectively.
(4K - 8) + (7K - 8) + (9K - 8) = 96
20K = 120
K = 6
Therefore, then present ages are 24,42,54.
ANSWER:A
Answer: A
Question: An amount at compound interest sums to Rs.17640/- in 2 years and to Rs.21168/- in 3 years at the same rate of interest. Find the rate percentage?
Options:
A)5%
B)7%
C)9%
D)11%
E)20%
Rationale: Explanation:
The difference of two successive amounts must be the simple interest in 1 year on the lower amount of money.
S.I = 21168/- - 17640/- = Rs. 3528/-
Rate of interest = (3528/17640) × (100/1) => 20%
Answer: Option E
Answer: E
Question: A coin is tossed live times. What is the probability that there is at the least one tail?
Options:
A)31/32
B)31/38
C)21/32
D)31/33
E)36/32
Rationale: Let P(T) be the probability of getting least one tail when the coin is tossed five times.
= There is not even a single tail.
i.e. all the outcomes are heads.
= 1/32 ; P(T) = 1 - 1/32 = 31/32 .Answer: A
Answer: A
Question: What is the lowest possible common multiple of 2 distinct integers, each greater than 61?
Options:
A)68
B)69
C)144
D)68^2
E)68·69
Rationale: In order to get the lowest LCM, we have to take the first number as 62 and the next number as its multiple.
So, I can take 62 and 144 as two distinct numbers, such that Lowest LCM = 144.
Answer should be C.
Answer: C
Question: Clara is traveling from one end of a forest to the other. In order to find her way back, she is leaving morsels of bread in the following pattern: 2 morsels of wheat, 3 morsels of white, and 1 morsel of waffle. The pattern repeats after she leaves the morsel of rye. If Clara drops 2,000 morsels of bread, what are the last 3 morsels of bread that she drops?
Options:
A)waffle − wheat − wheat
B)wheat − wheat − white
C)white − waffle − wheat
D)white − white − white
E)white − white − waffle
Rationale: In a single round Clara drops 6 morsels.
Remainder (2000/6) = 2
Final action = 2 drops of Wheat --> Options B, C, D and E can be eliminated
Answer: A
Answer: A
Question: How many two digit numbers of distinct digits can be formed by using digits 1, 2, 3, 4, 5, 6 and 7 such that the numbers are divisible by 9?
Options:
A)4
B)5
C)6
D)7
E)8
Rationale: A number will be divisible by 9 if sum of all the digits of the number is divisible by 9
Here the Possible sum of the two distinct digits can be 9 only in order to satisfy the given condition
If sum of Digits = 9, No. = 27, 36, 45, 54, 63, 72 --- 6 Cases
Answer: option C
Answer: C
Question: A store sells chairs and tables. If the price of 3 chairs and 1 table is 60% of the price of 1 chair and 3 tables, and the price of 1 table and 1 chair is $80, what is the price, in dollars, of 1 table? (Assume that every chair has the same price and every table has the same price.)
Options:
A)68
B)84
C)72
D)60
E)64
Rationale: LET C= CHAIR ; T =TABLE
3C+1T = 0.6 (1C + 3T) OR C( 3-0.6) = 1.8T -1T OR 2.4C = 0.8 T THEREFORE C= 0.8/2.4 T = 1/3 T
IC +1T =80 OR 1/3T + 1T =80 THEREFORE T= 80*3/4 = 60
D
Answer: D
Question: 300 first-time customers of a fashion store were surveyed for their shopping experience right after leaving the store. 60% of the customers in the survey had purchased clothes for less than $100. 40% of the customers in the survey reported they were overall satisfied with their purchase. 35% of the customers that had purchased clothes for less than $100 reported they were overall satisfied with their purchase. What percent of the customers surveyed purchased clothes for at least $100 and reported that they were NOT overall satisfied with their purchase?
Options:
A)19
B)25
C)35
D)45
E)75
Rationale: Out of 300 - 180 purchased for less than 100$120 for more
Out of 300 - 120 responded as satisfied and 180 responded disatisfied
Out of 180 ( Purchased less than 100$) - 35% = 63 responded as satisfied, So remaining Satisfied are 120 - 63 = 57
so 57 is what percentage of 300 - 19%
So the answer should be A
Answer: A
Question: In an election between the two candidates, the candidates who gets 70% of votes polled is winned by 240 vote’s majority. What is the total number of votes polled?
Options:
A)600
B)700
C)800
D)850
E)None of these
Rationale: Explanation:
Note: majority (40 %) = difference in votes polled to win (70 %) & defeated candidates (30 %)
40 % = 70 % - 30 %
40% -----> 280 (40*6 = 240)
100% -----> 600 (100*6 = 600)
Answer: Option A
Answer: A
Question: A dress on sale in a shop is marked at $D. During the discount sale its price is reduced by 35%. Staff are allowed a further 30% reduction on the discounted price. If a staff member buys the dress what will she have to pay in terms of D ?
Options:
A)0.555D
B)0.765D
C)0.455D
D)0.785D
E)0.805D
Rationale: Effective discount = a + b + ab/100 = - 35 - 30 + (-35)(-30)/100 = -54.5
Sale price = D * ( 1 - 54.5/100)
Sale price = .455 * D
Answer (C)
Answer: C
Question: A sum of money at simple interest amounts to Rs. 800 in 3 years and to Rs. 850 in 4 years. The sum is:
Options:
A)Rs. 670
B)Rs. 690
C)Rs. 600
D)Rs. 625
E)Rs. 657
Rationale: Explanation:
S.I. for 1 year = Rs. (850 - 800) = Rs. 50.
S.I. for 3 years = Rs.(50 x 3) = Rs. 150.
Principal = Rs. (800 - 150) = Rs. 600.
Answer: Option C
Answer: C
Question: The cost of an item was reduced from its usual selling price of $23.99 to $16.99. Which of the following is closest to the percent decrease in the price of the item?
Options:
A)17%
B)21%
C)24%
D)29%
E)42%
Rationale: The price decreased by 23.99 - 16.99 = $7.
$7 is a bit more than 29% of original price of $24.
Answer: D.
Answer: D
Question: Excluding stoppages, the speed of a train is 45 kmph and including stoppages it is 36 kmph. Of how many minutes does the train stop per hour?
Options:
A)7232
B)828
C)12
D)83
E)29
Rationale: Explanation:
T = 9/45 * 60 = 12
Answer: Option C
Answer: C
Question: Three candidates contested an election and received 1136, 7636 and 11628 votes respectively. What percentage of the total votes did the winning candidate get?
Options:
A)56%
B)57%
C)60%
D)61%
E)65%
Rationale: Total number of votes polled = (1136 + 7636 + 11628) = 20400.
Required percentage = 11628	x 100	% = 57%.
20400
Option B
Answer: B
Question: Sonika deposited Rs.8000 which amounted to Rs.9200 after 3 years at simple interest. Had the interest been 2% more. She would get how much?
Options:
A)9680
B)9800
C)8000
D)7500
E)8600
Rationale: (8000*3*2)/100 = 480
9200
--------
9680
ANSWER A
Answer: A
Question: If the radius of a circle is increased by 40% then the area is increased by:
Options:
A)44%
B)120%
C)96%
D)40%
E)None of the above
Rationale: initially A=pi*r2
now R2=140/100r
then area=Pi*(140R/100)2
area=196R/100
that is area increases from 100 to 196=increase in area=96%
ANSWER:C
Answer: C
Question: What is the unit digit in {(6374)^1793 x (625)^317 x (341^491)}?
Options:
A)5
B)1
C)0
D)7
E)2
Rationale: Unit digit in (6374)^1793 = Unit digit in (4)^1793
Unit digit in [(4^2)^896 x 4]
= Unit digit in (6 x 4) = 4.
Unit digit in (625)^317 = Unit digit in (5)^317 = 5.
Unit digit in (341)^491 = Unit digit in (1)^491 = 1
Required digit = Unit digit in (4 x 5 x 1) = 0.
Answer C)0.
Answer: C
Question: A scooter costs 10,000 when it is brand new. At the end of each year, its value is only 80% of what it was at the beginning of the year. What is the value of the scooter at the end of 3 years?
Options:
A)10,000
B)12,500
C)12,800
D)12,000
E)5,120
Rationale: After first year, the value of the scooter = 8,000
After second year, the value of scooter = 6,400
After third year, the value of scooter = 5,120
Answer E
Answer: E
Question: The regular price per can of a certain brand of soda is $0.30. If the regular price per can is discounted 15 percent when the soda is purchased in 24-can cases, what is the price of 72 cans of this brand of soda purchased in 24-can cases?
Options:
A)$16.32
B)$18.36
C)$21.60
D)$24.48
E)$28.80
Rationale: The discounted price of one can of soda is (0.85)($0.30), or $0.255.
Therefore, the price of 72 cans of soda at the discounted price would be (72)($0.255) = 18.36
Answer: B.
Answer: B
Question: If a fast song has 160 beats per minute, and a slow song has 90 beats per minute, how many minutes total would you play a fast and a slow song to have a stream of music that had a total of 1,020 beats?
Options:
A)6
B)7
C)8
D)9
E)10
Rationale: We can determine quickly that total number should range between 1,020/160<= N <= 1,020/90 , so ans should be between 6 and 12.
Now solving the expression 160A+90B = 1,020
decreasing 1,020 by multiples of 160 and checking divisibility of that number by 9, we get
fast song plays for 3 minutes and slow somg plays for 6 minutes, 3*160 + 6*90 = 1,020
Hence total number of minutes stream of music plays is 3 + 6 = 9 minutes
Ans D
Answer: D
Question: Find the 25th term of an arithmetic progression whose first term is 5 and the common difference is 7.
Options:
A)145
B)38
C)173
D)156
E)189
Rationale: n th term of A.P = a +(n-1) *d
= 5+(25-1)*7 , = 5 + 168 = 173.
ANSWER:C
Answer: C
Question: Select the one which is different from other Four alternatives.
Options:
A)988
B)1140
C)1064
D)1197
E)1352
Rationale: E
(A) 988 ÷ 19 = 52
(B) 1352 ÷ 19 = 71.15
(C) 1064 ÷ 19 = 56
(D) 1197 ÷ 19 = 63
(E) 1140 ÷ 19 = 60
Answer: E
Question: What is the greatest prime factor of 6^8−3^8 ?
Options:
A)3
B)11
C)17
D)19
E)31
Rationale: 6⁸ − 3⁸ is a DIFFERENCE OF SQUARES. So we can factor it.
6⁸ − 3⁸ = (6⁴ + 3⁴)(6⁴ - 3⁴)
= (6⁴ + 3⁴)(6² + 3²)(6² - 3²)
= (6⁴ + 3⁴)(6² + 3²)(6 + 3)(6 - 3)
= (6⁴ + 3⁴)(45)(9)(3)
= (6⁴ + 3⁴)(3)(3)(5)(3)(3)(3)
Hmmmm, we can see that the correct answer is "hiding" in the first number (6⁴ + 3⁴)
Let's factor out the 3⁴, to get:
6⁴ + 3⁴ = 3⁴(2⁴ + 1)
= 3⁴(16 + 1)
= 3⁴(17)
= (3)(3)(3)(3)(17)
So, 6⁸ − 3⁸ = (3)(3)(3)(3)(17)(3)(3)(5)(3)(3)(3)
So the correct answer is C
Answer: C
Question: Find LCM of fraction series 4/5, 8/35, 2/15, 6/25 ?
Options:
A)36/5
B)24/5
C)16/5
D)36/7
E)25/2
Rationale: We know that the LCM for fraction can be calculated as:
LCM = (LCM of numerators) / (HCF of denominators)
= (LCM of 4, 8, 2, 6) / (HCF of 5, 35, 15, 25)
= (2 x 2 x 2 x 3) / (5)
= 24 / 5
Ans - B
Answer: B
Question: How many paying stones, each measuring 2 1/2 m * 2 m are required to pave a rectangular court yard 20 m long and 16 1/2 m board?
Options:
A)66
B)18
C)16
D)10
E)15
Rationale: 20 * 33/2 = 5/2 * 2 * x => x
= 66
Answer:A
Answer: A
Question: In how many different ways can the letters of the word RUMOUR be arranged?
Options:
A)180
B)720
C)30
D)90
E)None of these
Rationale: Reqd. number of ways
6!/2!×2!=6×5×4×3/1×2=180
Answer A
Answer: A
Question: A sum of money is to be distributed among A, B, C, D in the proportion of
5 : 2 : 1 : 4. If D gets Rs. 6000 more than C, what is B's share?
Options:
A)Rs. 500
B)Rs. 1000
C)Rs. 1500
D)Rs. 4000
E)NOne
Rationale: Sol.
Let the shares of A, B, C and D be Rs. 5x, Rs. 2x, Rs. x and Rs. 4x respectively.
Then, 4x - x = 3000 ⇔ 3x = 6000 ⇔ x = 2000.
∴ B's share = Rs. 2x= Rs. (2x2000) = Rs. 4000.
Answer D
Answer: D
Question: The perimeter of one face of a cube is 20 cm. Its volume will be:
Options:
A)125cm3
B)400cm3
C)250cm3
D)625cm3
E)None of these
Rationale: Explanation:
Edge of cude = 20/4 = 5 cm
Volume = a*a*a = 5*5*5 = 125 cm cube
Option A
Answer: A
Question: There are 6 physics books and 1 chemistry book on shelf P and 4 physics books on shelf Q. One book is moved from shelf P to shelf Q. A student picks up a book from shelf Q. What is the probability that the chemistry book is taken by the student?
Options:
A)1/42
B)1/35
C)1/28
D)1/21
E)1/14
Rationale: P(a chemistry book is moved to shelf Q) = 1/7
P(a chemistry book is then chosen from shelf Q) = 1/5
P(the student takes a chemistry book) = 1/7 * 1/5 = 1/35
The answer is B.
Answer: B
Question: A man purchased 3 blankets @ Rs.100 each, 5 blankets @ Rs.150 each and two blankets at a certain rate which is now slipped off from his memory. But he remembers that the average price of the blankets was Rs.154. Find the unknown rate of two blankets?
Options:
A)420
B)550
C)490
D)450
E)457
Rationale: 10 * 154 = 1540
3 * 100 + 5 * 150 = 1050
1540 – 1050 = 490
Answer:C
Answer: C
Question: Three friends Alice, Bond and Charlie divide $1245 amongs them in such a way that if $10, $20 and $15 are removed from the sums that Alice, Bond and Charlie received respectively, then the share of the sums that they got will be in the ratio of 9 : 10 : 11. How much did Charlie receive?
Options:
A)$460
B)$471
C)$455
D)$425
E)$465
Rationale: A+B+C = 1245
Given ratio 9:10:11
Let us say the shares of A,B,C deducting 10,20,15 be a,b,c
a+b+c = 1245-45= 1200 = 30K
c share = (1200X11)/30 = 440
C = charlie share = 440+15 = 455
Option C
Answer: C
Question: The average weight of 29 students is 28 kg. By the admission of a new student, the average weight is reduced to 27.2 kg. The weight of the new student is
Options:
A)4 kg
B)21.6 kg
C)22.4 kg
D)21 kg
E)None of these
Rationale: Exp . The total weight of 29 students = 29* 28
The total weight of 30 students = 30* 27.2
Weight of the new student = ( 30*27.2 – 29*28)
= 816 - 812 = 4
Answer:A
Answer: A
Question: By selling an article at Rs.600, a profit of 25% is made. Find its cost price?
Options:
A)480
B)992
C)772
D)52
E)212
Rationale: SP = 600
CP = (SP)*[100/(100+P)]
= 600 * [100/(100+25)]
= 600 * [100/125] = Rs.480
Answer: A
Answer: A
Question: 4 men and 6 women can complete a work in 8 days, while 3 men and 7 women can complete it in 10 days. In how many days will 10 women complete it?
Options:
A)21 days
B)40 days
C)27 days
D)18 days
E)17 days
Rationale: Let 1 man's 1 day work = x and 1 woman's 1 day work = y.
Then, 4x + 6y = 1/8 and 3x + 7y = 1/10
Solving these two equations, we get:
x = 11/400 and y = 1/400
1 woman's 1 day work = (1/400 * 10) = 1/40.
Hence, 10 women will complete the work in 40 days.
Answer: B
Answer: B
Question: Set A is {1, 3, 5, 7, 9}
Set B is {14, 16, 18, 20, 22}
For the sets of numbers above, which of the following is true?
I. The mean of Set B is greater than the mean of Set A.
II. The median of Set B is greater than the median of Set A.
III. The standard deviation of Set B is greater than the standard deviation of Set A.
Options:
A)I only
B)I and II only
C)I and III only
D)II and III only
E)I, II, and III
Rationale: The mean and median of Set A is 5.
The mean and median of Set B is 18.
Thus statements I and II are both true.
The standard deviation is related to the distance from the mean.
Since the elements of both sets are spaced identically around the mean (+/- 2, +/- 4), the standard deviations of both sets are equal.
The answer is B.
Answer: B
Question: There is a biased dice..wen d dice is thrown. probability of occurrence of odd numbers is thrice that of even numbers. If the dice is thrown twice..find the probability of the products of the numbers appeared being odd.
Options:
A)8/16
B)9/16
C)10/16
D)11/16
E)7/16
Rationale: since, p(odd)=3p(even)
and p(odd)+p(even)=1
hence p(odd)=3/4
now only odd*odd=odd
hence two odd i s p(odd)=3/4*3/4=9/16
ANSWER:B
Answer: B
Question: In order to obtain an income of Rs. 650 from 10% stock at Rs. 96, one must make an investment of :
Options:
A)Rs. 3100
B)Rs. 6240
C)Rs. 6500
D)Rs. 9600
E)None of these
Rationale: Solution
To obtain Rs. 10, investment = Rs. 96.
To obtain Rs. 650, investment = Rs (96/10x650) =rs.6240
Answer B
Answer: B
Question: If x and y are integers and x divided by y is 15.15, then which of the following integers is a possible value for the remainder when x is divided by y? I. 15 II. 5 III. 3
Options:
A)II,III only
B)I only
C)I,III only
D)II only
E)III only
Rationale: x=15.15y from which x = 15y + 15y/100 or x = 15y + 3y/20.
Since x and y are integers, 3y/20 must also be an integer. 3 is not divisible by 20, then y must be divisible by 20, and therefore, y/20 is an integer and 3y/20 is an integer which is a multiple of 3. From the given answers, only 15 and 3 are divisible by 3.
Answer C
Answer: C
Question: A man whose bowling average is 12.4, takes 5 wickets for 26 runs and there by decreases his average by 0.4. the number of wickets taken by him before his last match is?
Options:
A)83
B)84
C)85
D)86
E)87
Rationale: 12.4*x+26=(5+x)12
solve equation x=85
so 85 wicket is ans
ANSWER:C
Answer: C
Question: Let x be a positive integer, what is the remainder when 3^(x+5)+4 is divided by 2?
Options:
A)4
B)3
C)2
D)1
E)0
Rationale: For: (3^(x+5)+4)/2
Let n = x + 5
3^n
3^1 = 3
3^2 = 9
3^3 = 27
3^4 = 81
3^5 = 243, last digit pattern repeats 3, 9, 7, 1, 3, ....
Rule: x^(m+n) = (x^m)(x^n)
(3^(x))(3^5) => Now, (3)(3) + 3 = (9) + 3 => Finally, 12/2 and remainder is 0.
Answer: E
Answer: E
Question: A sells a Cricket Bat to B at a profit of 20%. B sells it to C at a profit of 25%. If C pays $225 for it, the cost price of the Cricket Bat for A is:
Options:
A)150
B)120
C)130
D)160
E)210
Rationale: A
150
125% of 120% of A = 225
125/100 * 120/100 * A = 225
A = 225 * 2/3 = 150.
Answer: A
Question: Two varieties of wheat - A and B costing Rs. 9 per kg and Rs. 15 per kg were mixed in the ratio 3 : 7. If 5 kg of the mixture is sold at 25% profit, find the profit made?
Options:
A)16.5
B)15.5
C)20.03
D)15.65
E)17.5
Rationale: Let the quantities of A and B mixed be 3x kg and 7x kg.
Cost of 3x kg of A = 9(3x) = Rs. 27x
Cost of 7x kg of B = 15(7x) = Rs. 105x
Cost of 10x kg of the mixture = 27x + 105x = Rs. 132x
Cost of 5 kg of the mixture = 132x/10x (5) = Rs. 66
Profit made in selling 5 kg of the mixture = 25/100 (cost of 5 kg of the mixture) = 25/100 * 66 = Rs. 16.50
ANSWER A
Answer: A
Question: Using all the letters of the word "TUESDAY", how many different words can be formed?
Options:
A)A)7
B)B)8!
C)C)8
D)D)7!
E)E)3
Rationale: Explanation:
Total number of letters = 7
Using these letters the number of 7 letters words formed is 8!.
Answer: Option D
Answer: D