divelab/Sys2Bench huggingface dataset:
Question: A, B and C are partners in a business. Their capitals are respectively, Rs.5000, Rs.6000 and Rs.4000. A gets 30% of the total profit for managing the business. The remaining profit is divided among three in the ratio of their capitals. In the end of the year, the profit of A is Rs.200 more than the sum of the profits of B and C. Find the total profit?
Options:
A)3366
B)2777
C)3001
D)3000
E)2811
Rationale: A:B:C = 5:6:4
Let the total profit = 100 - 30 = 70
5/15 * 70 = 70/3
A share = 70/3 + 30 = 160/3
B + C share = 100 - 160/3 = 140/3
A-(B+C) = 160/3 - 140/3 = 20/3
20/3 ---- 200
100 ---- ? => 3000
Answer:D
Answer: D
Question: Out of 17 students studying in a class, 7 are from Maharashtra, 5 are from Karnataka and 3 are from Goa. Four students are to be selected at random. What are the chances that at least one is from Karnataka?
Options:
A)12â„13
B)11â„13
C)10â„15
D)1â„15
E)19/24
Rationale: Total possible ways of selecting 4 students out of 17students = 17C4 = =2380
The no. of ways of selecting 4 students in which no student belongs to Karnataka = 12C4=495
âˆ´ Hence no. of ways of selecting at least one student from Karnataka = 17C4 â€“ 12C4 = 1885
âˆ´ Probability = 1885â„2380 = 19/24
Answer E
Answer: E
Question: If any amount is distributed among A ,B and C so that the part of A is doubled that of the part of B and part of b is 7 time the part of C .Find the ratio among their parts.
Options:
A)1:2:4
B)1:4:1
C)14:7:1
D)2:4:1
E)4:3:2
Rationale: By the assumptions as mentioned we have A=2B and B=7C. So A=2(7C) and we get A=14C. We have, therefore, A:B:C = 14C:7C:C. By cancelling the ratio with C we have 14:7:1. The answer is, therefore, C.
Answer: C
Question: a circular wheel radius is 1.75m.for covering 11k.m how much time it revolve?
Options:
A)10
B)100
C)1000
D)10000
E)50
Rationale: distance traveled in 1 round=perimeter={2*22/7*175/100}m
=11 m
total no. of revolution in covering 11 km=11000/11=1000
answer C
Answer: C
Question: A 200 meter long train crosses a man standing on the platform in 9 sec. What is the speed of the train?
Options:
A)228
B)108
C)1266
D)188
E)80
Rationale: S = 200/9 * 18/5 = 80 kmph
Answer: E
Answer: E
Question: A rectangular plot measuring 90 meters by 50 meters is to be enclosed by wire fencing. If the poles of the fence are kept 5 meters apart. How many poles will be needed?
Options:
A)34
B)77
C)36
D)56
E)91
Rationale: Explanation:
perimeter of the plot = 2(90+50) = 280m
no of poles =280/5 =56m
Answer: D
Answer: D
Question: What will come in place of the x in the following Number series? X, 22, 30, 46 ,78, 142
Options:
A)35
B)56
C)18
D)87
E)98
Rationale: (C)
The pattern is +4, +8, +16, +32, +64
So the missing term is = 18
Answer: C
Question: A sum of Rs. 1550 is lent out into two parts, one at 8% and another one at 6%. If the total annual income is Rs. 106, find the money lent at each rate.
Options:
A)700
B)500
C)300
D)900
E)None of them
Rationale: Let the sum lent at 8% be Rs. x and that at 6% be Rs. (1550 - x).
=((x*8*1)/100) + ((1550-x)*6*1)/100=106
= 8x + 9300 –6x=10600  2x = 1300  x = 650.
Therefore, Money lent at 8% = Rs. 650. Money lent at 6% = Rs. (1550 - 650) = Rs. 900.
Answer is D.
Answer: D
Question: Find large number from below question The difference of two numbers is 1370. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder
Options:
A)1641
B)1376
C)1456
D)1555
E)1635
Rationale: Let the smaller number be x. Then larger number = (x + 1370).
x + 1370 = 6x + 15
5x = 1355
x = 271
Large number = 271+1370 = 1641
A
Answer: A
Question: What is 2 2/3 - 1 1/4 divided by 1/2 - 1/5 ?
Options:
A)17/36
B)36/17
C)17/6
D)17/4
E)85/18
Rationale: 2 2/3 - 1 1/4 = 8/3 - 5/4 = (32 - 15 )/12 = 17/12
1/2 - 1/5 = (5-2)/10 = 3/10
So 17/12/3/10 = 17/12 *10/ 3 = 85/18
Answer - E
Answer: E
Question: You have 6 sticks of lengths 20, 30, 40, 50, 60 and 70 centimeters. The number of non-congruent triangles that can be formed by choosing three of the sticks to make the sides is
Options:
A)3
B)6
C)7
D)13
E)12
Rationale: The length of any side of a triangle must be larger than the positive difference of the other two sides, but smaller than the sum of the other two sides.
Based on this there can be only 13 triangles formed: (20, 30, 40), (20, 40, 50), (20, 50, 60), (30, 40, 50), (30, 40, 60), (30, 50, 60), (40, 50, 60), (50, 60, 70), (40,60, 70), (30,60, 70), (20,60, 70). (30, 50, 70), (40, 50,70)
Answer; D.
Answer: D
Question: In a class there are 30 boys and 25 girls. In how many ways can a boy and a girl be selected?
Options:
A)400
B)500
C)600
D)530
E)750
Rationale: Explanation:
We can select one boy from 30 boys in 30 ways.
We select one girl from 25 girls in 25 ways
We select a boy and girl in 30 * 25 ways i.e., = 750 ways.
Answer: Option E
Answer: E
Question: Cindy paddles her kayak upstream at x kilometers per hour, and then returns downstream the same distance at n kilometers per hour. How many kilometers upstream did she travel if she spent a total of p hours for the round trip?
Options:
A)mnp
B)mn/p
C)(x + n)/p
D)xnp/(x + n)
E)px/n- pn/x
Rationale: let t1 and t2 be the time taken to row upstream and downstream respectively
now,
t1=distance/speed=d/x
similarly,
t2=d/n (as same distance has to be rowed)
also,
t1+t2=p
therefore,
p=(d/x)+(d/n)
=d(x+n)/xn
d=pxn/(x+n)=D
Answer: D
Question: If a man can cover 12 metres in one second, how many kilometres can he cover in 3 hours 30 minutes?
Options:
A)150km
B)151.2km
C)152.5km
D)153km
E)155km
Rationale: 12 m/s = 12 * 18/5 kmph
3 hours 45 minutes = 3 1/2 hours = 7/2 hours
Distance = speed * time = 12 * 18/5 * 7/2 km = 151.2 km.
Answer:B
Answer: B
Question: If x is the median the set {9/2, x,11/3, 28/9, 21/5}, x could be
Options:
A)16/5
B)17/5
C)21/7
D)4
E)31/7
Rationale: The median is the middle number once all the numbers are arranged in increasing/decreasing order.
We see that
11/3 = 3.something,
28/9 = 3.something
21/5 = 4.something
9/2 = 4.something
So x should greater than the smallest two numbers and smaller than the greatest two numbers. We can see that x = 4 is possible. (First look at the simplest option or the middle option since options are usually arranged in increasing/decreasing order)
Answer (D)
Answer: D
Question: In Kaya's teacher's desk there are 3 pink highlighters, 7 yellow highlighters, and 5 blue highlighters. How many highlighters are there in all?
Options:
A)11
B)15
C)77
D)33
E)88
Rationale: Add the numbers of highlighters.
3 + 7 + 5 =15.
Answer is B.
Answer: B
Question: A fair coin with sides marked heads and tails is to be tossed eight times. What is the probability that the coin will land tails side up more than five times?
Options:
A)A)37/256
B)B)56/256
C)C)65/256
D)D)70/256
E)E)81/256
Rationale: More than 5 times tails = 6times + 7times+8times = 8C6 + 8C7 + 8C8 = 37
- - - - - - - -
2 2 2 2 2 2 2 2
2^8 times total events and 37 events where tails side up .
So probability = 37/2^8 = 37/256 (Answer A)
Answer: A
Question: How many numbers from 2 to 15 are exactly divisible by 2?
Options:
A)A)2
B)B)3
C)C)5
D)D)7
E)E)8
Rationale: 2/2 = 1 and 15/2 = 7
7 - 1 = 6
6 + 1 = 7 Numbers.
Answer : D
Answer: D
Question: The contents of a certain box consist of 80 apples and 30 oranges. How many oranges must be added to the box so that exactly 50% of the pieces of fruit in the box will be apples?
Options:
A)45
B)50
C)55
D)60
E)65
Rationale: apple = (apple + orange + x)*0.5
80 = (30 + 80 + x)*0.5
x = 50
Answer: B
Answer: B
Question: The tax on a commodity is diminished by 20% but its consumption is increased by 10%. Find the decrease percent in the revenue derived from it?
Options:
A)18%
B)72%
C)32%
D)12%
E)52%
Rationale: 100 * 100 = 10000
80 * 110 = 8800
10000------- 1200
100 ------- ? = 12%
Answer:D
Answer: D
Question: A man walks at a speed of 3 km/hr and runs at a speed of 7 km/hr. How much time will the man require to cover a distance of 10 1/2 km, if he completes half of the distance, i.e., (5 1/4) km on foot and the other half by running?
Options:
A)2 1/9
B)2 1/6
C)2 1/2
D)2 1/1
E)6 1/2
Rationale: Required time = (5 1/4)/3 + (5 1/4)/7 = 2 1/2 hours.Answer:E
Answer: E
Question: A trained covered x km at 50 kmph and another 2x km at 20 kmph. Find the average speed of the train in covering the entire 3x km.
Options:
A)22
B)99
C)25
D)66
E)887
Rationale: Total time taken = x/50 + 2x/20 hours
= 6x/50 = 3x/25 hours
Average speed = 3x/(3x/25) = 25kmph
Answer: C
Answer: C
Question: Ramu bought an old car for Rs. 41000. He spent Rs. 13000 on repairs and sold it for Rs. 64900. What is his profit percent?
Options:
A)A)14%
B)B)16%
C)C)19.8%
D)D)22%
E)of these
Rationale: Total CP = Rs. 41000 + Rs. 13000 = Rs. 54000 and SP = Rs. 64900
Profit(%) = (64900 - 54000)/55000 * 100 = 19.8%
ANSWER:C
Answer: C
Question: If 7^k = 2, then 7^(4k+2) =
Options:
A)729
B)754
C)784
D)783
E)108
Rationale: 7^k=2
7^4k=2^4
7^4k=16
7^(4k+2)
=7^4k*7^2
=16*49
=784
Answer: C
Answer: C
Question: In your classes you counted 128 hands. How many students were at the class?
Options:
A)64
B)61
C)85
D)86
E)88
Rationale: Total number of hands = 128
We have 2 hands.
To find how many students were at the class, divide the total number of hands by the number of hands we have.
We get, divide 128 by 2
128 ÷ 2 = 64
Therefore, there were 64 students at the class.
ANSWER IS A
Answer: A
Question: If 30 toys cost Rs, 234, what do 35 toys cost?
Options:
A)273
B)564
C)546
D)654
E)None of them
Rationale: Let the required cost be Rs. x. Then,
More toys, More cost	(Direct Proportion)
x=(35 X 234)/30 =273
Answer is A
Answer: A
Question: A sum of Rs.6800 is invested at a compound interest for three years, the rate of interest being 10% p.a., 20% p.a. and 25% p.a. for the 1st, 2nd and the 3rd years respectively. Find the interest received at the end of the three years.
Options:
A)A)282
B)B)4420
C)C)8383
D)D)8383
E)E)3284
Rationale: Let A be the amount received at the end of the three years.
A = 6800[1 + 10/100][1 + 20/100][1 + 25/100]
A = 6800 * 1.65
A = Rs.11220
So the interest = 11220-6800 = Rs.4420
Answer: B
Answer: B
Question: A man saves 10% of his monthly salary. If an account of dearness of things he is to increase his monthly expenses by 5%, he is only able to save Rs. 400 per month. What is his monthly salary?
Options:
A)Rs.6500
B)Rs.7500
C)Rs.7200
D)Rs.7273
E)Rs.6300
Rationale: Income = Rs. 100
Expenditure = Rs. 90
Savings = Rs. 10
Present Expenditure 90+90*(5/100) = Rs.94.5
Present Savings = 100 – 94.5 =Rs. 5.50
If savings is Rs. 5.50, salary = Rs. 100
If savings is Rs.400, salary = 100/5.5*400 = 7273
Answer : D
Answer: D
Question: The average (arithmetic man) of three integers a, b, and c is exactly one third the median. If a < b < c and a = 0, what is the value of c/b?
Options:
A)1
B)3
C)4
D)5
E)Cannot be determined from the information given.
Rationale: The average of three integers a, b, and c is exactly twice the median --> (a+b+c)/3=1b/3 --> since a=0, then (0+b+c)/3=b/3 --> c=3b/3 --> c/b=1.
Answer: A.
Answer: A
Question: The calendar for the year 2005 is the same as for the year :
Options:
A)2010
B)2011
C)2012
D)2013
E)None of these
Rationale: Count the number of days from 2005 onwards to get 0 odd day.
= 7 or 0 odd day.
∴ Calender for the year 2005 is the same as that for the year 2012
Answer C
Answer: C
Question: A train with 120 wagons crosses Arun who is going in the same direction, in 36 seconds. It travels for half an hour from the time it starts overtaking the Arun ( he is riding on the horse) before it starts overtaking the Sriram( who is also riding on his horse) coming from the opposite direction in 24 seconds. In how much time (in seconds) after the train has crossed the Sriram do the Arun meets to Sriram?
Options:
A)2276 sec
B)1276 sec
C)3576 sec
D)2176 sec
E)1676 sec
Rationale: Explanation:
Let the length of the train be L metres and speeds of the train Arun and Sriram be R, A and S respectively, then
---------- (i)
and ---------(ii)
From eq.(i) and (ii)
3(R - A ) = 2 (R + K)
R = 3A + 2K
In 30 minutes (i.e 1800 seconds), the train covers 1800R (distance) but the Arun also covers 1800 A (distance) in the same time. Therefore distance between Arun and Sriram, when the train has just crossed Sriram
= 1800 ( R - A) - 24 ( A + K)
Time required =
= (3600 - 24) = 3576 s
Answer: C
Answer: C
Question: The number 61 can be written as the sum of the squares of 3 different positive integers. What is the sum of these 3 integers?
Options:
A)17
B)16
C)15
D)14
E)13
Rationale: I think brute force with some common sense should be used to solve this problem.
Write down all perfect squares less than 61: 1, 4, 9, 16, 25, 36, 49.
Now, 61 should be the sum of 3 of those 7 numbers. Also to simplify a little bit trial and error, we can notice that as 61 is an odd numbers then either all three numbers must be odd (odd+odd+odd=odd) OR two must be even and one odd (even+even+odd=odd).
We can find that 61 equals to 9+16+36=3^2+4^2+6^2=61 --> 3+4+6=13.
Answer: E.
Answer: E
Question: During 2003, a company produced an average of 2,000 products per month. How many products will the company need to produce from 2004 through 2007 in order to increase its monthly average for the period from 2003 through 2007 by 150% over its 2003 average?
Options:
A)287,000
B)290,000
C)284,000
D)285,000
E)286,000
Rationale: Company produced 12*2000 = 24,000 products in 2003. If company produces X products from 2004 to 2007, then total amount of product produced in 4 years (2003 through 2007) is X+24,000. The gives the average of (X+24,000)/4.
This average needs to be 300% higher than that in 2003. In math terms, 36,000+150%(36,000) = 80,000. So:
(X+36,000)/4 = 80,000
X+36,000 = 320,000
X = 284,000
The answer is C.
Answer: C
Question: Susan is traveling from one end of a forest to the other. In order to find her way back, she is leaving morsels of bread in the following pattern: 2 morsels of wheat, 3 morsels of white, and 1 morsel of bap. The pattern repeats after she leaves the morsel of bap. If Susan drops 2,000 morsels of bread, what are the last 3 morsels of bread that she drops?
Options:
A)bap − wheat − wheat
B)wheat − wheat − white
C)white − bap − wheat
D)white − white − white
E)white − white − bap
Rationale: In a single round Susan drops 6 morsels.
Remainder (2000/6) = 2
Final action = 2 drops of Wheat --> Options B, C, D and E can be eliminated
Answer: A
Answer: A
Question: If there are 5 seats and 3 students, in how many ways can they be seated?
Options:
A)40
B)45
C)50
D)60
E)80
Rationale: The first student has 5 choices, the second student has 4 choices, and the third student has 3 choices. The number of ways to sit is 5*4*3 = 60.
The answer is D.
Answer: D
Question: If e, f, and g are distinct positive prime numbers, then (e^3)(f)(g) has how many different positive factors greater than 1?
Options:
A)a. 8
B)b. 9
C)c. 12
D)d. 11
E)e. 27
Rationale: Let Number is (e^3)(f)(g) = (1^3)(6)(10) = 60
We can write 60 as product of two numbers in following ways
1*60
2*30
3*20
4*15
5*12
6*10
6cases = 6*2 i.e. 12 factors (including 1)
Factors greater than 1 = 11
Answer: Option D
Answer: D
Question: Two trains of length 90 m and 100 m are 200 m apart. They start moving towards each other on parallel tracks, at speeds 71 kmph and 89 kmph. After how much time will the trains meet?
Options:
A)47/10
B)46/10
C)45/10
D)42/10
E)43/10
Rationale: They are moving in opposite directions, relative speed is equal to the sum of their speeds.
Relative speed = (71 + 89)*5/18 = 44.4mps.
The time required = d/s = 200/44.4= 45/10 sec.
Answer:C
Answer: C
Question: Find the fraction which has the same ratio to 2/6 that 3/4 has to 1/2
Options:
A)1/2
B)2/5
C)6/8
D)9/4
E)7/5
Rationale: P : 2/6 = 3/4 : 1/2
As the product of the means is equal to the product of the extremes.
P*1/2 = 2/6 * 3/4
P*1/2 = 6/24
P = 1/2 => P = 1/2
ANSWER:A
Answer: A
Question: If the difference between the length and breadth of a rectangle is 23 m and its perimeter is 206 m, what is its area?
Options:
A)2510
B)2535
C)2530
D)2515
E)2520
Rationale: length = breadth +23. Therefore,
4× breadth +2×23=206 m
⇒ breadth =40 m
length =40+23=63 m
Area =63×40=2520 m2
Answer is E.
Answer: E
Question: A, B and C jointly thought of engaging themselves in a business venture. It was agreed that A would invest Rs. 6500 for 6 months, B, Rs. 8400 for 5 months and C, Rs. 10,000 for 3 months. A wants to be the working member for which, he was to receive 5% of the profits. The profit earned was Rs. 7400. Calculate the share of B in the profit.
Options:
A)Rs. 1900
B)Rs. 2660
C)Rs. 2800
D)Rs. 2840
E)Rs. 2440
Rationale: For managing, A received = 5% of Rs. 7400 = Rs. 370.
Balance = Rs. (7400 - 370) = Rs. 7030.
Ratio of their investments = (6500 x 6) : (8400 x 5) : (10000 x 3)
= 39000 : 42000 : 30000
= 13 : 14 : 10
B's share = Rs.	7030 x14	= Rs. 2660
ANSWER:B
Answer: B
Question: A classroom has 3 electric lamps. From a collocation of 10 electric bulbs of which 6 are good , 3 are selected at random and put in the lamps. Find the probability that the room is lighted.
Options:
A)1/6
B)4 / 120
C)29 / 30
D)1/9
E)None of these
Rationale: Explanation :
Out of 10 electric bulbs, 3 are selected in 10C3 ways.
So, number of possible outcomes = T = 10C3 =120.
The room is lighted i.e at least one fo the 3 bulbs chosen at random is a good bulb.
Wherever 'at least one' is present, it is easier to do the problem using complement of the event(i.e room is dark and all 3 bulbs are bad ).
P(room is dark) = F / T = P(none of the bulbs is good)
=> 4C3/120. [since 4 bulbs are bad ].
P (room is lighted )
= 1 - ( 4C3 / 120 ). [ room is lighted if at least one bulb is good ].
or P (at least one)
= 1 - (4 / 120).
= 29 / 30.
Answer : C
Answer: C
Question: It takes 30 days to fill a laboratory dish with bacteria. If the size of the bacteria doubles each day, how long did it take for the bacteria to fill one eighth of the dish?
Options:
A)10 days
B)15 days
C)27 days
D)28 days
E)29 days
Rationale: The bacteria doubles each day, so after 29 days, the dish was half full.
After 28 days, the dish was one quarter full.
After 27 days, the dish was one eighth full.
The answer is C.
Answer: C
Question: Which of the following is closest in value to (9^13)-(9^2)?
Options:
A)9^9
B)9^8
C)9^13
D)9^6
E)9^5
Rationale: 9^13 is much larger number than 9^2 and as we need approximate value then it's pretty much negligible in this case, so: (9^13)-(9^2) = ~9^9.
Answer: C.
Similar questions to practice:
Hope it helps.
Answer: C
Question: 325325 is a six digit number. It is divisible by
Options:
A)7 only
B)11 only
C)13 only
D)all 7,11 and 13
E)None
Rationale: Sol.
Clearly, 325325 is divisible by all 7, 11 and 13.
Answer D
Answer: D
Question: The length and breadth of a rectangle is increased by 10% and 25% respectively. What is the increase in the area?
Options:
A)37.7%
B)37.5%
C)87.5%
D)37.54%
E)32.5%
Rationale: 100 * 100 = 10000
110 * 125 = 13750
-----------
3750
10000 ------ 3750
100 ------- ? => 37.5%
Answer:B
Answer: B
Question: Tom opened a shop investing Rs.500. Jose joined him 2 months later, investing Rs.350. They earned a profit of Rs.1720 after completion of one year. What will be Jose's share of profit?
Options:
A)80
B)20
C)30
D)41
E)15
Rationale: SoL = ~s- So Anju’s share = [5/9] x 1720 = 80
A
Answer: A
Question: Which of the following cannot be the sum of 3 different odd numbers?
Options:
A)10
B)13
C)17
D)15
E)19
Rationale: Option A: 10 as odd + odd + odd = odd
Correct Option: A
Answer: A
Question: A sum of money invested at C.I. amounts to Rs. 800 in 3 years to Rs. 880 in 4 years. The rate of interest per annum is?
Options:
A)2 1/2 %
B)4%
C)10%
D)6 2/3 %
E)6%
Rationale: S.I. on Rs. 800 for 1 year = (880 - 800) = Rs. 80 Rate = (100 * 80)/(800 * 1) = 10%
ANSWER:C
Answer: C
Question: The average age 40 teachers of a school is 35 years. Out of these, the average age of 25 teachers is 30 years and that of the other 15 teachers is 39 years. The age of the 40th teacher is?
Options:
A)65
B)69
C)61
D)62
E)72
Rationale: Age of the 40th teacher= 40*35 - (25*30+15*39) = 1400-1335= 65 years
Answer is A
Answer: A
Question: When a 186 meters long rod is cut down into small pieces of length 2.0 meters each. Then how many pieces are available ?
Options:
A)52
B)68
C)62
D)67
E)69
Rationale: Answer
No. of pieces = Total length / Length of each piece
= 186/3.0
= 62
Option: C
Answer: C
Question: Abhijit started a business investing 70000. Anuja joined him after six months with an amount of 105000 and Sunil joined them with 1.4 lakhs after another six months. The amount of profit earned should be distributed in what ratio among Abhijit, Anuja and Sunil respectively, three years after Abhijit started the business?
Options:
A)42 : 45 : 56
B)7 : 6 : 10
C)12 : 15 : 16
D)Cannot be determined
E)None of these
Rationale: Ratio of their investments
= 70 × 36 : 105 × 30 : 140 × 24 = 12 : 15 : 16
Answer C
Answer: C
Question: The arithmetic mean of the scores of a group of students in a test was 52. The brightest 20% of them secured a mean score of 80 and the dullest 25% of a mean score of 31. The mean score of remaining 55% is
Options:
A)40.8 approx
B)45.3 approx
C)51.4 approx
D)53.8 approx
E)None
Rationale: Sol.
Let the required mean score be x. Then,
20 × 80 + 25 × 31 + 55 × x = 52 × 100
⇔ 1600 + 775 + 55x = 5200
⇔ 55x = 2825
⇔ x = 565 / 11 = 51.4.
Answer C
Answer: C
Question: The sum of a number and its square is 1406. What is the number?
Options:
A)1409
B)1402
C)1221
D)1406
E)8828
Rationale: Explanation:
By option Verification 37 + 37 × 37 = 1406
Answer: D
Answer: D
Question: How many seconds does a train 125 meters long, traveling at 54 km/h, take to completely cross a bridge of 205 meters in length?
Options:
A)18
B)20
C)22
D)24
E)26
Rationale: 54 km/h = 54000/3600 = 15 m/s
Time = 330 / 15 = 22 seconds
The answer is C.
Answer: C
Question: A bag making machine can make 20 bags per hour. If the company adjusts the machine to produce twice the amount per hour to satisfy expected rise in demand. How many bags can the machine make in the next 5 days if it works 10 hours a day?
Options:
A)2,000
B)1,000
C)400
D)50
E)1,500
Rationale: 20*2= 40 bags per hour.
5 days* 10 hours* 40 bags per hour= 2,000 bags.
Answer is option A.
Answer: A
Question: The length of the bridge, which a train 170 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
Options:
A)205
B)210
C)215
D)250
E)260
Rationale: Speed = [45 X 5/18] m/sec = [25/2] m/sec Time = 30 sec Let the length of bridge be x metres. Then, (170 + x)/30 = 25/2 => 2(170 + x) = 750 => x = 205 m.
Answer: Option A
Answer: A
Question: A can do a work in 25 days and B can do it in 10 days. In how many days A and B can do the work?
Options:
A)20 days
B)10 days
C)6 8/7days
D)8 days
E)7 days
Rationale: Explanation:
A's 1day's work = 1/25
B's 1day's work = 1/10
They work together = 1/25 + 1/10 = 7/50 = 50/7 = 6 8/7days
Answer: Option C
Answer: C
Question: A train 200m long passes a standing man in 10 seconds. What is the speed of the train?
Options:
A)30km/hr
B)36km/hr
C)42km/hr
D)50km/hr
E)72km/hr
Rationale: Speed of the train = 200/10* 18/5 = 72km/hr
Answer is E
Answer: E
Question: If books bought at prices ranging from Rs.200 to Rs.350 are sold at prices ranging from Rs.300 to Rs.425,what is the greatest possible profit that might be made in selling eight books ?
Options:
A)Rs.400
B)Rs.600
C)Cannot be determined
D)None of these
E)Rs.800
Rationale: Solution
Least C.P. = Rs.(200 8) = Rs.1600. Greatest S.P. = Rs.(425 8) = Rs.3400.
Required profit = Rs.(3400 - 1600) = Rs.1800. Answer D
Answer: D
Question: Amar takes as much time in running 18 meters as a car takes in covering 48 meters. What will be the distance covered by Amar during the time the car covers 1.6 km?
Options:
A)339
B)278
C)289
D)600
E)821
Rationale: Distance covered by Amar = 18/4.8 (1.6km)
= 3/8(1600) = 600 m
Answer:D
Answer: D
Question: Find the value of x from the below equation: x^2−7x+10=0
Options:
A)5 or 2
B)3 or 5
C)3 or 7
D)4 or 6
E)None
Rationale: Here we need to find out a and b such that a + b = -7 and ab = +10
a = -5 and b = -2 satisfies the above condition.
Hence
x^2−7x+10=(x−5)(x−2)
x2−7x+10=(x−5)(x−2)
x^2−7x+10
=0
⇒(x−5)(x−2)
=0
x2−7x+10=0⇒(x−5)(x−2)=0
Step 3: Equate each factor to 0 and solve the equations
(x−5)(x−2)
=0
⇒(x−5)
=0or (x−2)=0
⇒x= 5 or 2
A
Answer: A