divelab/Sys2Bench huggingface dataset:
Question: Brandi received a 10% raise each month for four consecutive months. What was her salary after the four raises if her starting salary was $1,000 per month?
Options:
A)$1,248.03
B)$1,300.09
C)$1,331.12
D)$1,410.15
E)$1,464.10
Rationale: 1000 * 1.1 * 1.1 * 1.1 * 1.1 = 1000 * 1.4641 = 1464.10
Answer: E
Answer: E
Question: By selling 50 meters of cloth. I gain the selling price of 18 meters. Find the gain percent?
Options:
A)42 7/7%
B)42 5/8%
C)56 1/4%
D)42 6/8%
E)42 1/7%
Rationale: SP = CP + g
50 SP = 50 CP + 18 SP
32 SP = 50 CP
32 --- 18 CP gain
100 --- ? => 56 1/4%
Answer: C
Answer: C
Question: Indu gave Bindu Rs.3750 on compound interest for 2 years at 4% per annum. How much loss would Indu has suffered had she given it to Bindu for 2 years at 4% per annum simple interest?
Options:
A)5
B)6
C)9
D)3
E)1
Rationale: 3750
= D(100/4)2
D = 6
Answer: B
Answer: B
Question: A man took loan from a bank at the rate of 8% p.a. simple interest. After 4 years he had to pay Rs. 6200 interest only for the period. The principal amount borrowed by him was:
Options:
A)Rs.17322
B)Rs.20245
C)Rs.18230
D)Rs.18375
E)Rs.19375
Rationale: Explanation :
Principal(P) = ?
Time(T) = 4 years
Simple Interest(SI) = Rs.6200
R = 8%
P = 100×SI/RT
=100×6200/8×4
=Rs.19375
Answer : Option E
Answer: E
Question: If books bought at prices ranging from Rs. 200 to Rs. 350 are sold at prices ranging from Rs. 300 to Rs. 432, what is the greatest possible profit that might be made in selling eight books ?
Options:
A)23267
B)2677
C)1856
D)2778
E)76611
Rationale: Explanation:
Least Cost Price = Rs. (200 * 8) = Rs. 1600.
Greatest Selling Price = Rs. (432 * 8) = Rs. 3456.
Required profit = Rs. (3456 - 1600) = Rs. 1856.
Answer: C) 1856
Answer: C
Question: What is the smallest positive perfect square that is divisible by 4, 10, and 18?
Options:
A)900
B)1,600
C)2,500
D)3,600
E)4,900
Rationale: The number needs to be divisible by 2^2, 2*5, and 2*3^2.
The smallest such perfect square is 2^2*3^2*5^2 = 900
The answer is A.
Answer: A
Question: Claire has a total of 90 pets consisting of gerbils and hamsters only. One-quarter of the gerbils are male, and one-third of the hamsters are male. If there are 25 males altogether, how many gerbils does Claire have?
Options:
A)39
B)50
C)66
D)57
E)60
Rationale: G+H =90 ...1 ; G/4 +H/3 =25 ....2 OR 3G +4H =25*12 =300
G =90-H OR 3(90-H) +4H =300 H = 300-270 =30 THEN G= 96-30 =66
C
Answer: C
Question: John's favorite number is odd and has prime factors that do not repeat. Which of the following numbers is his favorite?
Options:
A)27
B)75
C)121
D)105
E)147
Rationale: Factor each option.
A 27 = 3*3*3
B 75 = 3*5*5
C 121 = 11*11
D 105 = 3*5*7
E 147 = 3*7*7
D is the only choice with no repeating prime factors
Answer: D
Question: Solution Y is 30 percent liquid X and 70 percent water. If 2 kilograms of water evaporate from 8 kilograms of solutions Y and 2 kilograms of solution Y are added to the remaining 6 kilograms of liquid, what percent of this new liquid solution is liquid X?
Options:
A)30%
B)33 1/3%
C)37 1/2%
D)40%
E)50%
Rationale: At the beginning, you have 8 KG of solution Y, i.e.
70% * 8KG = 5,6 KG of Water
30% * 8 KG = 2,4 KG of X
2 KG of water evaporate:
5,6KG - 2KG = 3,6KG of Water
2,4KG of X
2 KG of liquid are added:
3,6KG + 2*0,70 = 5 KG of Water
2,4KG + 2*0,30 = 3 KG of X
So you have 3KG of X in 8KG (3 + 5) solution.
Therefore X concentration is 3/8 = 37,5%
ANSWER:C
Answer: C
Question: What will come in place of the x in the following Number series? 4, 8 , 16, x , 44
Options:
A)33
B)37
C)28
D)41
E)43
Rationale: (C)
The pattern is + 4, + 8, + 12, +16 â€¦â€¦â€¦..
So the missing term is = 16+ 12= 28
Answer: C
Question: (0.15)(power 3) - (0.06)(power 3)/ (0.15)(power 2) + 0.009 + (0.06)(power 2) is:
Options:
A)0.09
B)0.08
C)0.1
D)0.07
E)None of them
Rationale: Given expression
= (0.15) (power 3) - (0.06)(power 3) / (0.15)(power 2) + (0.15 x 0.06) + (0.06)(power 2)
= a (power 3) - b(power 3) / a(power 2) + ab + b(power 2)
= (a - b)
= (0.15 - 0.06)
= 0.09
Answer is A.
Answer: A
Question: A cycle is bought for Rs.900 and sold for Rs.1080, find the gain percent?
Options:
A)29%
B)20%
C)26%
D)20%
E)23%
Rationale: 900 ---- 180
100 ---- ? => 20%
Answer: B
Answer: B
Question: Find the wrong number in the series.
3, 8, 15, 24, 34, 48, 63
Options:
A)37
B)38
C)34
D)888
E)27
Rationale: Explanation:
The difference between consecutive numbers of the given series are respectively 5, 7, 9, 11, 13, and 15.
Therefore, 24+11=35 But in your problem it is given as 34.so 34 is wrong number
Answer: C) 34
Answer: C
Question: Susan can type 10 pages in 5 minutes. Mary can type 5 pages in 10 minutes. Working together, how many pages can they type in 30 minutes?
Options:
A)11
B)30
C)38
D)20
E)75
Rationale: Explanation:
Susan can type 2 pages in 1 min
Mary can type 0.5 pages in 1 min
so, both of them work together they type 2.5 pages in 1 min
so,in 30 min they type (30 × 2.5) = 75 pages
Answer: E
Answer: E
Question: The value of log343 7 is
Options:
A)1/3
B)- 3
C)- 1/3
D)3
E)0.3
Rationale: Solution
Let log3437	= n.
Then, 343n	= 7
= (73)n = 7.
‹=›3 n = 1
‹=›n = 1/3.
log343 7	= 1/3.
Answer A
Answer: A
Question: A person has to cover a distance of 6km in 45 minutes. If he covers one half of the distance in two-thirds of the total time; to cover the remaining distance in the remaining time, his speed must be?
Options:
A)12km/hr
B)10km/hr
C)15km/hr
D)20km/hr
E)18km/hr
Rationale: Remaining distance = 3km
Remaining time = 1/3 * 45 = 15min = 1/4 hour
Required speed = 3*4 = 12km/hr
Answer is A
Answer: A
Question: In 2010, Arman’s birthday was on a Thursday. What day of the week was it 64 days after his birthday?
Options:
A)Thursday
B)Friday
C)Saturday
D)Sunday
E)Monday
Rationale: Day of week after 64 days after Arman's birthday = 7*9 + 1
Saturday as the period will have 9 weeks and 1 days .
The 1 days in the end will be Friday .
Answer B
Answer: B
Question: Using all the letters of the word "NOKIA", how many words can be formed, which begin with N and end with A?
Options:
A)7
B)6
C)4
D)9
E)3
Rationale: There are five letters in the given word.
Consider 5 blanks ....
The first blank and last blank must be filled with N and A all the remaining three blanks can be filled with the remaining 3 letters in 3! ways.
The number of words = 3! = 6.
Answer:B
Answer: B
Question: A number is said to be prime saturated if the product of all the different positive prime factors of t is less than the square root of t. What is the greatest two digit prime saturated integer ?
Options:
A)99
B)98
C)97
D)96
E)95
Rationale: t=96 = 3 * 32 = 3 * 2^5
Answer is D.
Answer: D
Question: A certain company charges $6 per package to ship packages weighing less than 2 pounds each. For a package weighing 2 pounds or more, the company charges an initial fee of $6 plus $2 per pound. If the company charged $34 to ship a certain package, which of the following was the weight of the package, in pounds?
Options:
A)12
B)14
C)16
D)18
E)20
Rationale: Let the weight of the package be X.
2X + 6= 34
X = 14
The answer is B.
Answer: B
Question: Richie obtained 76, 95, 82, 67 and 85 marks (out of 100) in English, Mathematics, Physics, Chemistry and Biology. What are his average marks?
Options:
A)A)87
B)B)99
C)C)68
D)D)82
E)E)81
Rationale: Average = (76 + 95 + 82 + 67 + 85)/5
= 405/5
= 81.
Answer:E
Answer: E
Question: A tap can fill a tank in 8 hours. After half the tank is filled, two more similar taps are opened. What is the total time taken to fill the tank completely?
Options:
A)1 hr 20 min
B)4 hr
C)3 hr
D)5 hr 20 min
E)2 hr 50 min
Rationale: Explanation:
1 tap can fill the tank in 8 hours.
Therefore
1 tap can fill half tank in 4 hours.
3 taps can fill the tank in 8/3 hour.
Therefore
3 taps can fill half tank in 8/6 hour =1hour 20 minutes.
Total time taken=5 hour 20 minutes
Answer: Option D
Answer: D
Question: A thief is noticed by a policeman from a distance of 280 m. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 10 km and 11 km per hour respectively. What is the distance between them after 6 minutes?
Options:
A)100
B)277
C)180
D)278
E)271
Rationale: Relative speed of the thief and policeman = 11 - 10 = 1 km/hr.
Distance covered in 6 minutes = 1/60 * 6 = 1/10 km = 100 m.
Distance between the thief and policeman = 280 - 100 = 180 m.
Answer: C
Answer: C
Question: A tradesman by means of his false balance defrauds to the extent of 32%? in buying goods as well as by selling the goods. What percent does he gain on his outlay?
Options:
A)74%
B)78%
C)94%
D)75%
E)64%
Rationale: g% = 32 + 32 + (32*32)/100
= 74%
Answer: A
Answer: A
Question: The speed of a boat in still water is 8 kmph. If it can travel 1 km upstream in 1 hr, What time it would take to travel the same distance downstream?
Options:
A)14 minutes
B)4 minutes
C)24 minutes
D)28 minutes
E)23minutes
Rationale: Speed of the boat in still water = 8 km/hr
Speed upstream = 1⁄1 = 1 km/hr
Speed of the stream = 8-1 = 7 km/hr
Speed downstream = (8+7) = 15 km/hr
Answer is B
Time taken to travel 1 km downstream = 1/15 hr = (1×60)/15= 4 minutes
Answer: B
Question: A man is standing on a railway bridge which is 180 m long. He finds that a train crosses the bridge in 20 seconds but himself in 5 seconds. Find the length of the train and its speed.
Options:
A)5.6 m/sec
B)15 m/sec
C)18 m/sec
D)9 m/sec
E)25 m/sec
Rationale: If length of train is l and speed of train is s, then
l/s = 5
(l+180)/s = 20
(l+180)/l = 20/5 =4
l+180 =5*l
4*l=180
l=45 mtrs
s= l/5 = 45/5 = 9 m/sec
ANSWER:D
Answer: D
Question: The cost of 2 chairs and 3 tables is Rs.1300. The cost of 3 chairs and 2 tables is Rs.1200. The cost of each table is more than that of each chair by?
Options:
A)Rs.70
B)Rs.75
C)Rs.50
D)Rs.60
E)None of these
Rationale: 2C + 3T = 1300 --- (1)
3C + 3T = 1200 --- (2)
Subtracting 2nd from 1st, we get
-C + T = 100 => T - C = 100
ANSWER:E
Answer: E
Question: The ages of three friends are prime numbers. The sum of the ages is less than 51. If the ages are in Arithmetic Progression (AP) and if at least one of the ages is greater than 10, what is the difference between the maximum possible median and minimum possible median of the ages of the three friends?
Options:
A)0
B)1
C)13
D)6
E)8
Rationale: Let the numbers are a-d, a , a+d
sum <51 => a-d+a+a+d < 51 => middle number a <17
prime numbers are 2,3,5,7,11,13,17,19,23,29,31,37,41,43,47
a can be 3,5,7,11,13
if a is 3 -> a-d can be 2 only; a+d not possible thus reject this.
if a is 5, a-d can be 2 and 3; only a-d = 3 satisfies
=> three numbers can be 3,5,7 ->reject this , as it is given at least one is >10
if a = 7 ; a-d can be 3 and a+d can be 11
This satisfies all the conditions hence the median is 7=> min median.
if a = 11, the three element pair is 3,11,19 or 5,11,17
median = 11; we are not sure if its the max median possible
if a = 13, 7,13,19 pair is possible
median = 13; reject 11 as the max.
thus difference = 13-7 = 6
ANSWER:D
Answer: D
Question: A coin is tossed live times. What is the probability that there is at the least one tail?
Options:
A)31/32
B)1/16
C)1/2
D)1/32
E)None of these
Rationale: Let P(T) be the probability of getting least one tail when the coin is tossed five times.
P(T)= There is not even a single tail.
i.e. all the outcomes are heads.
P(T)= 1/32 ; P(T) = 1 - 1/32 = 31/32
ANSWER:A
Answer: A
Question: How many 4 digit numbers are there, if it is known that the first digit is even, the second is odd, the third is prime, the fourth (units digit) is divisible by 3, and the digit 5 can be used only once?
Options:
A)20
B)150
C)225
D)300
E)304
Rationale: 4 options for the first digit: 2, 4, 6, 8;
5 options for the second digit: 1, 3, 5, 7, 9;
4 options for the third digit: 2, 3, 5, 7;
4 options for the fourth digit: 0, 3, 6, 9.
Four digit # possible without the restriction (about the digit 2): 4*5*4*4=320
Numbers with five 5-s, 5X5X 4*1*1*4=16.
Thus there are 320-16=304 such numbers.
Answer: E.
Answer: E
Question: Out of 9 persons working on a project, 4 are graduates. If 3 are selected, what is the probability that there is at least one graduate among them?
Options:
A)A)5/7
B)B)5/21
C)C)16/21
D)D)5/6
E)E)5/3
Rationale: P(at least one graduate) = 1 - P(no graduates)
= 1 - ⁶C₃/¹⁰C₃
= 1 - (6 * 5 * 4)/(7 * 9 * 8)
= 16/21
Answer:C
Answer: C
Question: 4 mat-weavers can weave 4 mats in 4 days. At the same rate, how many mats would be woven by 8 mat-weavers in 8 days?
Options:
A)25
B)19
C)39
D)61
E)16
Rationale: Let the required number of bottles be x.
More weavers, More mats (Direct Proportion)
More days, More mats (Direct Proportion)
Wavers	4	:	8 :: 4 : x
Days	4:8
4 * 4 * x = 8 * 8 * 4
x =	(8 * 8 * 4)/(4 x 4)
x = 16.
Answer is E.
Answer: E
Question: Ravi and Kumar are working on an assignment. Ravi takes 6 hours to type 32 pages on a computer, while Kumar takes 5 hours to type 40 pages. How much time will they take, working together on two different computers to type an assignment of 110 pages?
Options:
A)7 hours 30 minutes
B)8 hours
C)8 hours 15 minutes
D)8 hours 25 minutes
E)7 hours 35 minutes
Rationale: Number of pages typed by Ravi in 1 hour =	32/6	=	16/3	.
Number of pages typed by Kumar in 1 hour =	40/5	= 8.
Number of pages typed by both in 1 hour =	(16/3+ 8)	=	40/3	.
Therefore Time taken by both to type 110 pages =	(	110 x	3/40	)	hours
= 8	1/4 hours (or) 8 hours 15 minutes.
Option C
Answer: C
Question: If x is the sum of six consecutive integers, then x is divisible by which of the following: I. 6 II. 3 III. 7
Options:
A)I only
B)III only
C)II,III only
D)II only
E)I,III only
Rationale: We're told that X is the SUM of 6 CONSECUTIVE INTEGERS. We're asked what X is divisible by....
Let's TEST VALUES....
IF we use the 6 consecutive integers: 6, 7,8,9,10 and 11, then the sum = 51.
51 is divisible by 3
51 is NOT divisible by 6
51 is NOT divisible by 7
There's only one answer that 'fits' with these facts. Answer : D
Answer: D
Question: The current of a stream runs at the rate of 4 kmph. A boat goes 6 km and back to the starting point in 2 hours, then find the speed of the boat in still water?
Options:
A)10 kmph
B)21 kmph
C)8 kmph
D)12 kmph
E)14 kmph
Rationale: S = 4
M = x
DS = x + 4
US = x - 4
6/(x + 4) + 6/(x - 4) = 2
x = 8
ANSWER:C
Answer: C
Question: Find the C.I. on a sum of Rs.1600 for 9 months at 20% per annum, interest being compounded quarterly?
Options:
A)Rs.7288
B)Rs.2542
C)Rs.2522
D)Rs.2625
E)Rs.6271
Rationale: A = 1600(21/20)3
= 2522
Answer: C
Answer: C
Question: Johnson completes a piece of work in 10 days, Vincent completes the same work in 40 days. If both of them work together, then the number of days required to complete the work is
Options:
A)7 days
B)8 days
C)9 days
D)10 days
E)12 days
Rationale: If A can complete a work in x days and B can complete the same work in y days, then, both
of them together can complete the work in x y/ x+ y days.
That is, the required No. of days = 10 × 40/50 = 8 days.
B)
Answer: B
Question: A restaurant meal cost $35.50 and there was no tax. If the tip was more than 10 percent but less than 15 percent of the cost of the meal, then the total amount paid must have been between
Options:
A)$40 and $42
B)$39 and $41
C)$38 and $40
D)$37 and $39
E)$36 and $37
Rationale: The total amount for the meal was between 35.5*1.1=39.05 and 35.5*1.15=~41. Only option which covers all possible values of the meal is B.
Answer: B.
Answer: B
Question: When 30 per cent of a number is added to another number the second number increases by its 20 per cent. What is the ratio between the first and the second number?
Options:
A)3 : 2
B)2 : 3
C)2 : 5
D)Data inadequate
E)None of these
Rationale: 30% of I + II = II × 120⁄100
or, 3⁄10I = 2⁄10II ⇒ I : II = 2 : 3.
Answer B
Answer: B
Question: what is the probability of getting sum of 10 on rolling three dices?
Options:
A)28/216
B)27/216
C)29/216
D)26/216
E)25/216
Rationale: The no of ways to roll three dies is 6^3=216
The possibles of getting sum as 10 is
631=3!=6
622=3!/2!=3
541=3!=6
523=3!=6
442=3!/2!=3
433=3!/2!=3
Total possibles for getting sum as 10 is 27
The probabilty is 27/216
ANSWER:B
Answer: B
Question: The last digit of the number obtained by multiplying the numbers 41 x 42 x 43 x 44 x 45 x 46 x 47 x 48 x 49 will be ?
Options:
A)0
B)1
C)4
D)5
E)7
Rationale: Solution
Last digit will be multiplication of 1x2x3x4x5x6x7x8x9.
It includes 5 & 2 so, 5x2=10, 0 will be the last digit.
Correct Option: A
Answer: A
Question: A club wants to mix 20 pounds of candy worth $8.00 per pound with candy worth $5.00 per pound to reduce the cost of the mixture to $6.00 per pound. How many pounds of the $5.00 per pound candy should be used?
Options:
A)20
B)30
C)40
D)50
E)60
Rationale: Let number of pounds of 5$ candy to be used be w
6 = (20*8 + 5*w)/(20 +w)
=>120 + 6w = 160 + 5w
=> w = 40
Answer C
Answer: C
Question: The remainder when K=1+3+3^2+3^3+..........+3^200 is divided 13.
Options:
A)12
B)7
C)0
D)5
E)3
Rationale: K=1+3+3^2+3^3+..................+3^200
Is a Geometric progression having common ratio as '3' and number of terms as '201'.
Since Sum to n terms in GP = a(r^n-1)/(r-1)
where a=First term and r =common ration
Hence,
1*(3^201 -1 )/(3-1)
Rem of (3^201-1)/2 divided by 13
3^201 -1 /26
WKT, 3^3 = 27 = 26+1
{(26+1)^67 - 1}/26
{1-1}/26
=>0.C
Answer: C
Question: In a room filled with 5 people, 3 people have exactly 2 siblings in the room and 2 people have exactly 1 sibling in the room. If two individuals are selected from the room at random, what is the probability that those two individuals are NOT siblings?
Options:
A)2/3
B)2/5
C)3/5
D)3/10
E)7/10
Rationale: The 5 people consist of one set of 2 siblings and one set of 3 siblings.
The number of ways to choose 2 people is 5C2 = 10.
The number of ways to choose 2 from the first group of siblings is 2C2 = 1.
The number of ways to choose 2 from the second group of siblings is 3C2 = 3.
The number of ways to choose 2 people who are siblings is 3+1 = 4.
The number of ways to choose 2 people who are not siblings is 10-4=6.
P(the two people are not siblings) = 6/10 = 3/5
The answer is C.
Answer: C
Question: How long does a train 110 m long running at the speed of 72 km/hr takes to cross a bridge 132 m length?
Options:
A)82.1 sec
B)12.1 sec
C)16.1 sec
D)13.1 sec
E)12.15sec
Rationale: Speed = 72 * 5/18 = 20 m/sec
Total distance covered = 110 + 132 = 242 m.
Required time = 242/20 = 12.1 sec.
Answer:B
Answer: B
Question: A 180 meter long train crosses a man standing on the platform in 9 sec. What is the speed of the train?
Options:
A)72
B)108
C)1266
D)188
E)211
Rationale: S = 180/9 * 18/5 = 72 kmph
Answer: A
Answer: A
Question: If the annual interest on a principal is 8%, how many years before the amount is double?
Options:
A)11.3
B)12
C)12.5
D)10.2
E)11.2
Rationale: P = (P*8*R)/100
R = 12.5
Answer: C
Answer: C
Question: The first doughnut is priced at $1 and then if you purchase additional doughnuts as dozens then the price is $6/dozen. What is the total number of doughnuts purchased if you paid $24?
Options:
A)44
B)46
C)48
D)50
E)52
Rationale: $24 = 4 * $6
The number of doughnuts is 4*12 = 48
The answer is C.
Answer: C
Question: The toll T, in dollars, for a truck using a certain bridge is given by the formula T = 1.50 + 0.50( x − 2), where x is the number of axles on the truck. What is the toll for an 18-wheel truck that has 2 wheels on its front axle and 2 wheels on each of its other axles?
Options:
A) $ 2.50
B) $ 3.00
C) $ 3.50
D) $ 4.00
E) $ 5.00
Rationale: Number of wheels in truck = 18
Number of wheels on its front axle =2
number of wheels remaining = 16
number of axles remaining axles = 16/2 = 8
Total number of axles = 9
T = 1.50 + 0.50( 9 − 2)
= 1.50 + .5*7
= 1.5 +1.5 = 5 $
Answer E
Answer: E
Question: How many different sets of positive square integers D, each greater than 1, add up to 75?
Options:
A) 1
B) 4
C) 7
D) 11
E) 13
Rationale: E = 13 is the correct answer.
Answer: E
Question: A man swims downstream 72 km and upstream 45 km taking 9 hours each time; what is the speed of the current?
Options:
A)1.7
B)1.5
C)1.3
D)1.2
E)1.9
Rationale: 72 --- 9 DS = 8
? ---- 1
45 ---- 9 US = 5
? ---- 1 S = ?
S = (8 - 5)/2 = 1.5
Answer: B
Answer: B
Question: A envelop weight 8.2 gm,if 800 of these envelop are sent with an advertisement mail. How much wieght?
Options:
A)6.56kg
B)6.8kg
C)6.7kg
D)6.9kg
E)7.8kg
Rationale: 800*8.2
6560.0gm
6.56kg
ANSWER:A
Answer: A
Question: A table is bought for Rs.400/- and sold at Rs.550/- find gain or loss percentage
Options:
A)l10%oss
B)30%gain
C)37.5%gain
D)10%loss
E)25% loss
Rationale: Formula = (Selling price ~ Cost price)/Cost price * 100
= (550 - 400)/400 = 37.5% gain
C
Answer: C
Question: A can finish a work in 18 days and B can do the same work in 15 days. B worked for 10 days and left the job. In how many days, A alone can finish the remaining work?
Options:
A)7
B)6
C)5
D)4
E)3
Rationale: B's 10 day's work = (10*1/15) = 2/3.
Remaining work =	(1- (2/3))=1/3
Now, 1/18 work is done by A in 1 day.
A= 18* 1/3 = 6 DAYS
ANSWER:B
Answer: B
Question: The breadth of a rectangular hall is two-thirds of its length. If the area of the hall is 2400 sq metres, what is the length in metres?
Options:
A)120
B)80
C)60
D)40
E)None of these
Rationale: Let the length of the rectangular hall be ‘x’ m, then the breadth of the rectangular hall = 2x⁄3 m.
Area of hall = 2x⁄3 × x = 2x2⁄3
or, 2x2⁄3 = 2400 or x = 60 m
Answer C
Answer: C
Question: A man can row 4 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and black. What is the total distance traveled by the man?
Options:
A)5.98
B)3.98
C)3.54
D)3.87
E)3.82
Rationale: M = 4
S = 1.2
DS = 4.8
US = 2.8
x/4.8 + x/2.8 = 1
x = 1.77
D = 1.77* 2 = 3.54
Answer:C
Answer: C
Question: The standard model numbers of cell phones in a company are 1 letter followed by 6 digits. How many different model numbers are possible if letters and digits can be repeated?
Options:
A)26 × 26 × 10 × 4
B)26 x 100 000
C)26 x 10
D)26 × 25 × 24 × 10 × 9 × 8 × 7
E)26 x 1 000 000
Rationale: OFFICIAL SOLUTION:
(E) The formula for permutations of events is the product of the number of ways each event can occur. There are 26 letters and 10 digits. So there are 26 options for a letter, and 10 × 10 × 10 × 10 × 10 × 10 for the six digits. The number of different license plates is 26 × 10 × 10 × 10 × 10 × 10 × 10 = 26 × 1 000 000.
The correct answer is choice (E).
Answer: E
Question: A,B,C can complete a piece of work in 25,5,10 days. Working together, they complete the same work in how many days?
Options:
A)2
B)4/5
C)50/17
D)10
E)24/7
Rationale: A+B+C 1day work = 1/25 + 1/5 + 1/10 = 17/50
A,B,C together will complete the job in 50/17 days
Answer is C
Answer: C
Question: If 70 percent of 600 is 40 percent of x, then x=?
Options:
A)105
B)168
C)342
D)660
E)1050
Rationale: Given: 0.7*600=0.4x --> 420=4/10*x --> x=1,050.
Answer: E.
Answer: E
Question: Average of money that group of 4 friends pay for rent each month is $800.After one persons rent is increased by 20% the new mean is $860.What was original rent of friend whose rent is increased?
Options:
A)800
B)900
C)1000
D)1100
E)1200
Rationale: 0.2X = 4(860-800)
0.2X = 240
X = 1200
Answer E
Answer: E
Question: In 100 m race, A covers the distance in 36 seconds and B in 45 seconds. In this race A beats B by:
Options:
A)20 m
B)25 m
C)22.5 m
D)9 m
E)12 m
Rationale: Distance covered by B in 9 sec. =	100/45 x 9	m = 20 m.
A beats B by 20 metres.
Answer: Option A
Answer: A
Question: A fort of 4000 soldiers has provisions for 100 days. After 20 days some of them left and the food was now enough for the same period of 100 days as before. How many of them left?
Options:
A)650
B)700
C)750
D)800
E)850
Rationale: 2000 ---- 50
4000 ---- 80
x ----- 100
x*100 = 4000*80
x=3200
4000
-------
800
Answer: D
Answer: D
Question: Girl and Boy together can complete a piece of work in 35 days while Girl alone can complete the same work in 60 days. Boy alone will be able to complete the same working in:
Options:
A)72
B)75
C)84
D)88
E)90
Rationale: Subtraction of fraction
ab−cd=ad−cbbd
Girl
and Boy finish one work with company = 35
days
(Girl+Boy)′
s one day’s work = 135
Girl alone finish the same work = 60
days
Girl′
s one day’s work = 160
B′
s one day’s work = (A+B)′s one day’s work - A′
s one day’s work
135−160=184
Hence B alone can complete the work in 84 days
Answer: B