divelab/Sys2Bench huggingface dataset:
Question: Find the total number of prime factors in the expression (4)^11 x (7)^5 x (11)^5
Options:
A)26
B)32
C)25
D)27
E)29
Rationale: (4)^11x (7)^5 x (11)^5
= (2 x 2)^11 x (7)^5 x (11)^5
= 2^11 x 2^11 x7^5x 11^5
= 2^22 x 7^5 x11^5
Total number of prime factors = (22 + 5 + 5) = 32.
Answer is B.
Answer: B
Question: Dawson completes a piece of work in 40 days, Rose completes the same work in 60 days. If both of them work together, then the number of days required to complete the work is?
Options:
A)18
B)20
C)21
D)22
E)24
Rationale: If A can complete a work in x days and B can complete the same work in y days, then, both
of them together can complete the work in x y/ x+ y days.
That is, the required No. of days = 40 × 60/100 = 24 days
Answer is E
Answer: E
Question: Find the principle on a certain sum of money at 5% per annum for 2 2/5 years if the amount being Rs.1232?
Options:
A)1000
B)2217
C)1100
D)2777
E)2991
Rationale: 1232 = P [1 + (5*12/5)/100]
P= 1100
Answer: C
Answer: C
Question: A mixture of 200 liters of wine and water contains 20% water. How much more water should be added so that water becomes 25% of the new mixture?
Options:
A)11 liters
B)11.2 liters
C)12.5 liters
D)13.78 liters
E)13.33 liters
Rationale: Number of liters of water in 200 liters of the mixture = 20% of 120 = 20/100 * 200 = 40 liters.
P liters of water added to the mixture to make water 25% of the new mixture.
Total amount of water becomes (40 + P) and total volume of mixture is (200 + P).
(40 + P) = 25/100 * (200 + P)
160+4P = 200+P
P = 13.33 liters.
Answer:E
Answer: E
Question: The average of 11 numbers is 10.5. If the average of first six is 10.5 and that of the last six is 11.4 the sixth number is?
Options:
A)9
B)9.2
C)10
D)15.9
E)17
Rationale: Explanation:
1 to 11 = 11 * 10.5 = 115.5
1 to 6 = 6 * 10.5 = 63
6 to 11 = 6 * 11.4 = 68.4
63 + 68.4 = 131.4 – 115.5 = 15.9
6th number = 15.9
D)
Answer: D
Question: The length of a rectangle is twice the breadth. If the area is 128 cm2, determine the length and the breadth.
Options:
A)b=2,l=9
B)b=8,l=16
C)b=9,l=9
D)b=4,l=14
E)b=3,l=9
Rationale: We are given length l=2b and l×b=128
∴2b×b=128
2b^2=128
b^2=64
b=±8
But breadth must be positive, therefore b=8 cm, and l=2b=16 cm.
Answer is B.
Answer: B
Question: A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
Options:
A)49
B)50
C)12
D)13
E)67
Rationale: Speed of the train relative to man = (125/10) m/sec = (25/2) m/sec. [(25/2) * (18/5)] km/hr = 45 km/hr. Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr. x - 5 = 45 ==> x = 50 km/hr.
Answer: Option B
Answer: B
Question: Find the odd man out
20, 40, 60, 81, 100, 120, 140, 160
Options:
A)120
B)140
C)180
D)160
E)81
Rationale: as 81 is only odd number.
ANSWER:E
Answer: E
Question: The length of the bridge, which a train 140 m long and traveling at 45 km/hr can cross in 30 sec is?
Options:
A)235
B)240
C)245
D)250
E)255
Rationale: Speed = 45 * 5/18 = 25/2 m/sec.
Time = 30 sec
Let the length of bridge be x meters.
Then, (140 + x)/30 = 25/2
x = 235 m.
Answer: Option A
Answer: A
Question: A painting at an art gallery is framed such that the area of the square frame is 1/5 the area of the painting itself. If the diagonal line connecting corners of the frame has a length of 6, what is the area of the painting inside the frame?
Options:
A)10
B)15
C)30
D)40
E)50
Rationale: Suppose side of the painting(which is a square) is a and side of the outer square(painting+frame) is b
Area of painting = a^2 and we know that the area of the frame is (1/5) of that of the painting so
Area of frame = (1/5) * a^2
Area of Frame + Painting = a^2 + (1/5)*a^2 = (6/5)*a^2 which is equal to b^2
Line connecting the corners of the frame is the diagonal of the outer square which is equal to b*sqrt2
so, b * sqrt2 = 6
so, b = 3 * sqrt2
b^2 = 18
we know that b^2 = (6/5)*a^2
so, a^2 = (5/6)*b^2 = (5/6)*18 = 15
And area of painting = a^2 = 40
So, answer will be B.
Answer: B
Question: 0.41 + 21.4 + 6.3 + 280=?
Options:
A)708.71
B)408.71
C)508.71
D)308.71
E)208.71
Rationale: Add 280.00+
21.40+
6.30+
0.41=
308.71
correct answer D
Answer: D
Question: How many different ways can you select a pilot and a co pilot if you have 80 people to choose from?
Options:
A) 199
B) 200
C) 398
D) 6320
E) 9900
Rationale: You are not just choosing two from 80. Each of the two people chosen fills a particular slot. The first filling the pilot slot and the second filling the copilot slot is different from the first filling the copilot slot and the second filling the pilot slot.
So the answer is in a sense (80C2) x 2 = 6320.
Ans D
Answer: D
Question: Find the number of square tiles to cover the floor of a room measuring 4 m * 9 m leaving 0.25 m space around the room. A side of square tile is given to be 25 cms?
Options:
A)422
B)476
C)429
D)428
E)413
Rationale: 3 1/2 * 8 1/2 = 1/4 * 1/4 * x => x '
= 476
Answer:B
Answer: B
Question: There are 4 copies of 5 different scales. In how many ways can they be arranged on a shelf?
Options:
A)20!/4!
B)20!/5(4!)
C)20!/(4!)^5
D)20!
E)5!
Rationale: There are 4 copies of 5 different scales.20!/((4!)^5)
Answer - C
Answer: C
Question: What profit percent is made by selling an article at a certain price, if by selling at 2/3rd of that price, there would be a loss of 30%?
Options:
A)5%
B)28%
C)27%
D)40%
E)70%
Rationale: SP2 = 2/3 SP1
CP = 100
SP2 = 70
2/3 SP1 = 70
SP1 = 105
100 --- 5 => 5%
Answer:A
Answer: A
Question: An analyst will recommend a combination of 3 industrial stocks, 2 transportation stocks, and 2 utility stocks. If the analyst can choose from 5 industrial stocks, 4 transportation stocks, and 3 utility stocks, how many different combinations of 7 stocks are possible?
Options:
A)12
B)19
C)60
D)180
E)720
Rationale: 5C3 * 4C2 * 3C2 = 10*6*3 = 180.
Answer: D
Answer: D
Question: Look at this series: 40, 44, 48, __, 52, 56, 40, 60, ... What number should fill the blank?
Options:
A)60
B)50
C)40
D)46
E)52
Rationale: C
40
In this series, 4 is added to the previous number; the number 40 is inserted as every third number.
Answer: C
Question: A shopkeeper sold an article for 360 after giving 20% discount on the labelled price and made 20% profit on the cost price. What would have been the percentage profit,had he not given the discount’?
Options:
A)25%
B)30%
C)23%
D)50%
E)None of these
Rationale: Cost price = 360×100/120= 300
S.P. at no discount = 360×100/80 = 450
∴ % profit = 150×100/300 = 50 %
Answer D
Answer: D
Question: A sum of Rs.4000 is invested at a compound interest for three years, the rate of interest being 10% p.a., 20% p.a. and 25% p.a. for the 1st, 2nd and the 3rd years respectively. Find the interest received at the end of the three years.
Options:
A)2888
B)3120
C)2877
D)2600
E)1277
Rationale: Let A be the amount received at the end of the three years.
A = 4000[1 + 10/100][1 + 20/100][1 + 25/100]
A = (4000 * 11 * 6 * 5)/(10 * 5 * 4)
A = Rs.6600
So the interest = 6600 - 4000 = Rs.2600
Answer: D
Answer: D
Question: The difference between two angles of a triangle is 24o. The average of the same two angles is 54o. Which one of the following is the value of the greatest angle of the triangle
Options:
A)45o
B)45o
C)66o
D)72o
E)None of these
Rationale: Solution:
Let a and b be the two angles in the question, with a > b. We are given that the difference between the angles is 24o.
=> a – b = 24.
Since the average of the two angles is 54o, we have (a+b)/2 =54.
Solving for b in the first equation yields b=a–24, and substituting this into the second equation yields,
[{a+(a−24)}/2] =54
2a−24 = 54*2
2a−24 = 108
2a = 108 +24
2a =132
a =66
Also,
b=a−24=66−24=42.
Now, let c be the third angle of the triangle. Since the sum of the angles in the triangle is
180o, a+b+c =180.
Putting the previous results into the equation yields 66+42+c =180.
Solving for c yields c =72
Hence, the greatest of the three angles a, b and c is c, which equ
Answer: Option D
Answer: D
Question: The area of a square is 4096 sq cm. Find the ratio of the breadth and the length of a rectangle whose length is twice the side of the square and breadth is 24 cm less than the side of the square?
Options:
A)5:18
B)5:28
C)5:29
D)5:22
E)5:16
Rationale: Let the length and the breadth of the rectangle be l cm and b cm respectively. Let the side of the square be a cm.
a2 = 4096 = 212
a = (212)1/2 = 26 = 64
L = 2a and b = a - 24
b : l = a - 24 : 2a = 40 : 128
= 5:16
Answer: E
Answer: E
Question: A certain car dealership offers its newest model in ten exterior and six interior colors. If the ten interior colors are identical to the ten exterior colors, and the dealership sells every pair of colors except those that would result in a car with an identically colored interior and exterior, how many different color combinations are possible?
Options:
A)45
B)81
C)90
D)10!/2!
E)36
Rationale: I lined up the 10 different colours for Exterion and Interior like this:
E: A B C D E F G H I J
I: A B C D E F G H I J
I calculated the number of combinations: 10*10= 100 combinations.
But, from these 100 we need to delete sth: the same colours.
There are 10 possible pairs of coulours that will be the same. So, I deleted these 10 pairs from 100, resulting in 36.
Mind here, that the 10 do not result in 20 colours, because 1 pair is one unit that is not allowed. So, 10 units are not allowed (surprised that 80 wasn't among the answer options to confuse test takers...).
E
Answer: E
Question: The ratio of red boxes to blue boxes in a certain warehouse is 20 to 25. If the number of the red boxes were doubled and the number of blue boxes were increased by 150 the ratio would be halved. How many total boxes are in the warehouse?
Options:
A)37
B)74
C)111
D)90
E)244
Rationale: Ratio = R/B = 20/25 or R = 20/25 B -----------(1)
2R/B+150 = 20/25*1/2 = 2/5 or we can say that 10R=2B+300 -------------(2)
solving (1) and (2) we get
B=50 and R = 40
so total boxes is B + R = 50+40=90
Hence D. 90 is the correct answer
Answer: D
Question: It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?
Options:
A)Sunday
B)Saturday
C)Friday
D)Wednesday
E)Monday
Rationale: On 31st December, 2005 it was Saturday.
Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.
On 31st December 2009, it was Thursday.
Thus, on 1st Jan, 2010 it is Friday.
Answeer:C
Answer: C
Question: A gym offers 11 levels of fitness classes, and in an attempt to reward those who progress toward higher levels of fitness it charges $50 less per course for each level of fitness. Jessica completed all 11 levels by taking one course at each level, and her total cost was $4675. What is the cost Q for a course at the gym's highest level?
Options:
A)$175
B)$245
C)$425
D)$675
E)$725
Rationale: Let the cost of a course in level 1 = x
=> Cost of level 2 = x-(50*1)... and so on
=> cost of level 11 = x-(50*10) = x-500
=> Total cost Q of 1 course in each of the 11 levels = x+(x-50)+(x-100)+.....+(x-500)
= 11x -50 (1+2+....+10)
= 11x - (50*55)
=> 11x-2750 = 4675
11x = 7425
x= 675
x-500=175
Answer A
Answer: A
Question: One fourth of one third of two fifth of a number is 25. What will be40% of that number
Options:
A)140
B)300
C)180
D)200
E)250
Rationale: Explanation:
(1/4) * (1/3) * (2/5) * x = 25 then x = 25 * 30 = 750
40% of 250 = 300
Answer: Option B
Answer: B
Question: The banker’s gain on a certain sum due 1½ years hence is 3/25 of the banker’s discount. The rate percent is :
Options:
A)3 1/3 %
B)6 1/6 %
C)9 1/9 %
D)9 1/6 %
E)None
Rationale: Sol.
Let B.D. = Re 1. Then, B.G. = Re 3/25.
∴ T.D. = (B.D. - B.G.) = Re[1 - 3/25] = Re 22/25.
Sum = [1 * 22/25 / 1 - 22/25] = Rs. 22/3.
S.I. on Rs. 22/3 for 1 ½ years is Re 1.
∴ Rate = [100 * 1 / 22/3 * 3/2] % = 9 9/1%.
Answer C
Answer: C
Question: If f(m)=m^2 and m is a positive integer, which of the following CANNOT be the value of f(f(m))?
Options:
A)256
B)16
C)1296
D)625
E)300
Rationale: f(m)=m^2
f(f(m)) = (m^2)^2 = m^4
Therefore f(f(m)) will be numbers that are 4th power of other numbers.
Checking the options:
256 = 4^4
16 = 2^4
1296 = 6^4
625 = 5^4
300. This cannot be written as the 4th power of any number
Answer: E
Answer: E
Question: Solution Y is 30 percent liquid O and 70 percent water. If 2 kilograms of water evaporate from 8 kilograms of solutions Y and 2 kilograms of solution Y are added to the remaining 6 kilograms of liquid, what percent of this new liquid solution is liquid O?
Options:
A)30%
B)33 1/3%
C)37 1/2%
D)40%
E)50%
Rationale: Answer:C
Took time to solve this one, the statement2 kilograms of solution Y are added to the remaining 6 kilograms of liquidwas confusing to me. After thinking more deeply, it was clear to me that new 2 kg of solution Y will also be 30% liquid O and 70% water, and then I was able to get the answer. That was a bit tricky and nice question=C
Answer: C
Question: Find the compound interest on $20000 in 2years at 4% per annum, the interest being compounded half-yearly?
Options:
A)$645.56
B)$1648.64
C)$954.26
D)$745.69
E)$1020.45
Rationale: Principle = $20000
Rate = 2% half yearly = 4 half years
Amount = 20000*(1 + 2/100)^4 = 20000 * 51/50 * 51/50 * 51/50 * 51/50
= $21648.64
C.I. = 21648.64-20000 = $1648.64
Answer is B
Answer: B
Question: Riya and Priya set on a journey. Riya moves eastward at a speed of 18kmph and Priya moves westward at a speed of 24 kmph.How far will be priya from Riya after 15 minutes
Options:
A)25kms
B)11kms
C)50kms
D)30kms
E)40kms
Rationale: total eastward distance= 18kmph*1/4hr=4.5 km
total westward distance= 24kmph*1/4hr=6 km
total distn betn them= 4.5+6=10.5m
ans 11km
ANSWER:B
Answer: B
Question: John makes $60 a week from his job. He earns a raise andnow makes $70 a week. What is the % increase?
Options:
A)16%
B)16.66%
C)22%
D)24%
E)24.5%
Rationale: Increase = (10/60)*100 = (1/6)*100 = 16.66%.
B
Answer: B
Question: Given a Number 123456, from this number put any three values in numerator and remaining three are in denominator. So how many values you can make from this number less than 1/5.
Options:
A)4
B)5
C)6
D)7
E)8
Rationale: 123/645 ,123/654 ,124/635 ,124/653
,125/634 ,125/643 ,
ans is 6.
ANSWER:C
Answer: C
Question: If Jack walked 9 miles in 1 hour and 15 minutes, what was his rate of walking in miles per hour?
Options:
A) 4
B) 4.5
C) 6
D) 6.25
E) 7.2
Rationale: Distance walked in 1 hour and 15 mins = 9 miles
Speed per hour = Distance/Time = 9/(5/4) = 7.2 miles per hour
Answer E
Answer: E
Question: In 110 m race, A covers the distance in 36 seconds and B in 45 seconds. In this race A beats B by:
Options:
A)20 m
B)25 m
C)22 m
D)9 m
E)12 m
Rationale: Distance covered by B in 9 sec. =	110/45 x 9	m = 22 m.
A beats B by 20 metres.
Answer: Option C
Answer: C
Question: 4, 12, 48, 240, (...)
Options:
A)1440
B)10080
C)6200
D)10020
E)12500
Rationale: Explanation :
Go on multiplying the given numbers by 3, 4, 5, 6,
Answer : Option A
Answer: A
Question: 4000 was divided into two parts such a way that when first part was invested at 3% and the second at 5%, the whole annual interest from both the investments is Rs.144, how much was put at 3%?
Options:
A)8279
B)2890
C)2800
D)2730
E)3702
Rationale: (x*3*1)/100 + [(4000 - x)*5*1]/100 = 144
3x/100 + 200 – 5x/100 = 144
2x/100 = 56 è x = 2800
Answer: C
Answer: C
Question: What number should be added to each of the numbers 8, 21, 13 and 31 so that the resulting numbers, in this order form a proportion?
Options:
A)2
B)3
C)5
D)7
E)9
Rationale: Explanation :
(8+x)/(21+x) = (13+x)/(31+x)
Then, (8 + x)(31 + x) = (13 + x)(21 + x)
or39x + 248 = 34x + 273 or 5x=25 or x = 5.
Answer : C
Answer: C
Question: In a contest, a bowl contains 7 keys, one of which will open a treasure chest and Six of which will not. If a contestant selects the key that opens the treasure chest, she wins the contents of that chest. If Sita is allowed to draw two keys, simultaneously and at random, from the bowl as the first contestant, what is the probability that she wins the prize?
Options:
A)1/8
B)1/9
C)2/7
D)3/19
E)3/23
Rationale: The total possibilities existing while withdrawing two keys are: 7C2 = 21
For Sita to win, 6 combinations exist assuming Key 1 to unlock the treasure E.g(1,2), (1,3)....(1,6)
P = 6/21= 2/7
Option C
Answer: C
Question: By how much does the larger root of the equation 2c^2+5c = 12 exceed the smaller root?
Options:
A) 5/2
B) 10/3
C) 7/2
D) 14/3
E) 11/2
Rationale: For 2c^2+5c = 12 Roots are [-5 + sqrt(25 + 96)]/4 OR [-5 - sqrt(25 + 96)]/4
= 1.5 OR -4
Hence larger root 1.5 is 1.5 - (-4) = 5.5 = 11/2 greater than smaller root (-4).
Hence option (E).
Answer: E
Question: How many ways can six friends be arranged around a circular dinner table?
Options:
A)16
B)48
C)96
D)120
E)720
Rationale: The number of arrangements of n distinct objects in a row is given by n!n!.
The number of arrangements of n distinct objects in a circle is given by (n−1)!(n−1)!.
The difference between placement in a row and that in a circle is following: if we shift all object by one position, we will get different arrangement in a row but the same relative arrangement in a circle. So, for the number of circular arrangements of n objects we have:
n!n=(n−1)!n!n=(n−1)!.
So, the answer is (6 - 1)! = 5! = 120.
Answer: D.
Answer: D
Question: On planet Jupiter the people use a certain number system to the base ‘n’ (n > 2), Jerk, a resident of the planet, one day received twice his daily wage because the digits of this wage, which was a 2 digit number, were reversed. If the value of ‘n’ is the least possible value there the decimal representation of the difference between Jerk’s correct wage for the day is
Options:
A)8
B)9
C)10
D)11
E)12
Rationale: Sol:
Let the base of the number system be n and the two digit number be ab
given 2(ab)n = (ba)n
⇒⇒ nb + a = 2na + 2b
⇒⇒ a(2n - 1) = b(n - 2)
⇒a/b= n−2 /2n−1
Now the maximum possible value of a or b is (n - 1) (base n) for n = 3 we get
a/b=1/5 which is not possible as in base 3, 5 won't exist.
Similarly, for n = 4
but for n = 5
We get a/b=3/9 i.e.1/3
a = 1, b = 3 is the only number possible when n is the least possible.
The correct wage = (13)5=(8)10
The actual wage paid = (31)5=(16)10
So difference = 8
Answer A
Answer: A
Question: A man bought 40 shares of Rs. 60 at 6 discount, the rate of dividend being 12 1/2%The rate of interest obtained is
Options:
A)13.89%
B)15.5%
C)14%
D)14.25%
E)14.95%
Rationale: Explanation :
Face Value of a share = Rs.60
He bought each share at Rs.60 - Rs.6 = Rs.54
Number of shares = 40
Dividend = 12 1/2%=25/2%
Dividend per share = 60×25/2×100=Rs.7.5
Total dividend = (40 × 7.5)
ie, He got a dividend of (40 × 7.5) for an investment of Rs.(40 × 54)
Interest obtained = 40×7.5×100/40×54=13.89%
Answer : Option A
Answer: A
Question: The average age 12 monkeys in a tree is 16 years. Out of these, the average age of 6 monkeys is 18 years and that of the other 6 monkeys is 13 years. The age of the 12th monkey is?
Options:
A)10
B)9
C)4
D)6
E)7
Rationale: Age of the 12th monkey= 12*16 - (6*18+6*13) = 192-186= 6 years
Answer is D
Answer: D
Question: In the following number sequence how many such even numbers are there which are exactly divisible by its immediate preceding number but not exactly divisible by its immediate following number?
3 8 4 1 5 7 2 8 3 4 8 9 3 9 4 2 1 5 8 2
Options:
A)Two
B)Three
C)Four
D)More than four
E)One
Rationale: correct answer is a
283,489
ANSWER:B
Answer: B
Question: If (68-a)(68-b)(68-c)(68-d)(68-e)=725
then a+b+c+d=?
Options:
A)231
B)231
C)233
D)234
E)235
Rationale: we will first break 725 in prime factor=(5*5*29*1*1) a/c to whatever factors is here
then we we will compare like
(68-63)(68-63)(68-39)(68-67)(68-67)i.e.5*5*29*1*1
a=63
b=63
c=39
d=67
and now sum is =a+ b+ c+ d=232
ANSWER:B
Answer: B
Question: What should come in place of question mark(?) in the following equation?
8597 – ? = 7429 – 4358
Options:
A)5706
B)5526
C)5426
D)5626
E)None of these
Rationale: 8597 – ? = 7429 – 4358
∴ ? = 5526
Answer B
Answer: B
Question: For 6-digit integer 46x,y12, when x and y are drawn at random from {3,5,8}, what is the probability E that the integer drawn is divisible by 8?
* A solution will be posted in two days.
Options:
A)1/6
B)1/3
C)1/2
D)2/3
E)5/6
Rationale: In general, the remainder divided by integer n is the same as the remainder that up to tens of n is divided by 8.
Thus, in order for 46,x,y12 to be divided by 8, y12 should be divided by 8.
Amongst 3,5,8, 3 and 5 can be divided by 8.
Therefore,E= two out of three can be divided and the answer is D.
Answer: D
Question: Hector runs a one-product widget shop. Each month, his fixed costs, whether he produces anything or not, amount to x dollars. The marginal cost of producing and selling one widget is a constant y dollars, regardless of the number he produces. He generally can sell widgets for s dollars each. What is the minimum number of widgets he must produce, assuming he sells every widget he produces, to break even (neither make a profit nor incur a loss) in a given month?
Options:
A)x/(y - s)
B)x/(s - y)
C)x
D)x/s
E)x/y
Rationale: Two ways...
1) let t be the total number, so cost = t*y+x and selling price=t*s..
No profit no loss....t*y+x=t*s.....T=x/(s-y)...
B
Answer: B
Question: 123 school girls are to be transported in small vans. Each van can carry 8 girls only. What is the smallest possible number of vans that are needed to transport all 123 school girls?
Options:
A)16 vans
B)26 vans
C)12 vans
D)17 vans
E)10 vans
Rationale: To find the number of vans, we divide 123 by 8.
123 / 8 = 15 and remainder = 3
So 15 vans are needed to transport 15 x 8 = 120 girls, and 1 van is needed to transport the 3 remaining girls. A total of 16 vans are needed.
correct answer A
Answer: A
Question: A, B and C invested Rs.6300, Rs.4200 and Rs.10500 respectively, in a partnership business. Find the share of A in profit of Rs.12500 after a year?
Options:
A)3630
B)2881
C)2887
D)3750
E)2212
Rationale: 6300:4200:10500
3:2:5
3/10 * 12100 = 3750.Answer: D
Answer: D
Question: If x is equal to the sum of the integers from 30 to 50, inclusive, and y is the number of even integers from 30 to 50, inclusive, what is the value of x + y ?
Options:
A)810
B)811
C)830
D)850
E)851
Rationale: 21 integers from 30 to 50 inclusive
so 11th integer is mean, it is 40
21*40=840
from 21 integers 11 ones is even
840+11=851
ANSWER:E
Answer: E
Question: A certain sum of money at simple interest amounted Rs.840 in 10 years at 3% per annum, find the sum?
Options:
A)971
B)973
C)268
D)646
E)365
Rationale: 840 = P [1 + (10*3)/100]
P = 646
Answer: D
Answer: D
Question: The owner of a wood furniture shop charges his customer 24% more than the cost price. If a customer paid Rs. 8339 for a computer table, then what was the cost price of the computer table?
Options:
A)6535
B)6532
C)6725
D)6874
E)6972
Rationale: C
6725
CP = SP * (100/(100 + profit%))
= 8339(100/124) = Rs. 6725
Answer: C
Question: A discount of 10 percent on an order of goods followed by a discount of 40 percent amounts to
Options:
A)the same as one 46 percent discount
B)the same as one 40 percent discount
C)the same as one 36 percent discount
D)the same as one 30 percent discount
E)the same as one 25 percent discount
Rationale: 0.9*0.6*x=0.54x from initial value, meaning 0.46 or 46% discount
A
Answer: A
Question: A foreign language club at Washington Middle School consists of n students, 3/5 of whom are boys. All of the students in the club study exactly one foreign language. 1/3 of the girls in the club study Spanish and 4/5 of the remaining girls study French. If the rest of the girls in the club study German, how many girls in the club, in terms of n, study German?
Options:
A)2n/5
B)n/3
C)4n/75
D)2n/15
E)n/15
Rationale: 3/5 of the students are boys, thus 2/5 of the students are girls.
1/3 of the girls in the club study Spanish and 4/5 of the remaining girls study French.
Thus 1/5 of 2/3 = 2/15 of the girls study German.
Since girls comprise 2/5 of the students, then 2/5*2/15=4/75 are girls who study German.
The answer is C.
Answer: C