divelab/Sys2Bench huggingface dataset:
Question: A team of 6 cooks is chosen from 8 men and 5 women. The team must have at least 2 men and at least 3 women. How many ways can this team be created?
Options:
A)140
B)320
C)560
D)700
E)840
Rationale: Only possible combinations are a team of 2M, 4 W or 3M,3W.
Possible ways to make a team of 2M,4W = 8C2 * 5C4 =28*5 =140
Possible ways to make a team of 3M,3W = 8C3* 5C3 = 56*10 = 560
Total possible ways = 140+560 = 700
Ans D
Answer: D
Question: A tradesman by means of his false balance defrauds to the extent of 25%? in buying goods as well as by selling the goods. What percent does he gain on his outlay?
Options:
A)44%
B)48%
C)56%
D)45%
E)34%
Rationale: g% = 25 + 25+ (25*25)/100
= 56%
Answer: C
Answer: C
Question: How many different arrangements of A, B, C, D, and E are possible ?
Options:
A)96
B)48
C)32
D)30
E)120
Rationale: So you have A,B,C,D,E
five possible ways to arrange it = 5! = 120
E
Answer: E
Question: Kavin has 8 pairs of shoes; each pair is a different color. If Kavin randomly selects 2 shoes without replacement from the 16 shoes, what is the probability that she will select 2 shoes of the same color?
Options:
A)2/5
B)1/5
C)1/19
D)1/15
E)1/21
Rationale: Can be tackled in this way as well: Probability of selecting any 1 out of 16 shoes = 16/16 = 1
Probability of selecting the next shoe (out of 15 available) having the same color = 1/15 (as after selecting the 1st one, there is only 1 another shoe left with the same color).
Thus the total probability = 1*1/15=1/15.
D is the correct answer.
Answer: D
Question: (17)4.5 x (17)? = 178
Options:
A)3.5
B)2.75
C)4.25
D)4.5
E)None of these
Rationale: Solution
let (17)4.5 * (17)x = 178. then, (17)4.5 + x = (17)8.
∴ 4.5 + x = 8 ⇔ x = (8 - 4.5) ⇔ x = 3.5
Answer A
Answer: A
Question: Rice weighing 25/4 pounds was divided equally and placed in 4 containers. How many ounces of rice were in each container? (Note that 1 pound = 16 ounces)
Options:
A)22
B)25
C)28
D)31
E)34
Rationale: 25/4 ÷ 4 = 25/16 pounds in each container
25/16 pounds * 16 ounces / pound = 25 ounces in each container
The answer is B.
Answer: B
Question: The diagonals of a rhombus are 16 cm and 20 cm. Find its area?
Options:
A)176
B)186
C)150
D)179
E)160
Rationale: 1/2 * 16 * 20
= 160
Answer:E
Answer: E
Question: If a and b are positive integers and x = 4^a and y = 9^b, which of the following is a possible units digit of xy?
Options:
A)1
B)4
C)5
D)7
E)8
Rationale: unit digit of x=4^a will either be 4 or 6 (4 if a is odd and 6 if a is even)
and unit digit of y=9^b will either be 1 or 9 (9 if b is odd and 1 if b is even)
now we have total 4 possible combinations
1) a=odd, b=odd
unit digit=9*4=6
2)a=odd, b=even
unit digit=4*1=4
3) a=even,b=odd
unit digit=6*9=4
4)a=even, b=even
unit digit=6*1=6
thus, only two values are possible for the unit digits (4 or 6). out of these values only 4 is mentioned in the given choices. hence answer must be B.
Answer: B
Question: The average age of husband, wife and their child 3 years ago was 29 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is
Options:
A)22
B)46
C)38
D)21
E)11
Rationale: Explanation:
Sum of the present ages of husband, wife and child = (29 x 3 + 3 x 3) years = 96 years.
Sum of the present ages of wife and child (20 x 2 + 5 x 2) years = 50 years.
Husband's present age = (96 - 50) years = 46 years.
Answer: B
Answer: B
Question: Reena took a loan of 1300 with simple interest for as many years as the rate of interest. If she paid 325 as interest at the end of the loan period, what was the rate of interest?
Options:
A)3.6
B)5
C)25
D)Cannot be determined
E)None
Rationale: Explanation: Let rate = R% and time = R years.
Then, (1300 x R x R)/100 = 325
13RÂ² = 325
RÂ² = 25
R = 5.
Answer: Option B
Answer: B
Question: A fisherman's day is rated as good if he catches 9 fishes, fair if he catches 7 fishes and poor if he catches 5 fishes. The fisherman catches 53 fishes in a week that includes good, fair and poor days. How many poor days the fisherman had during the week?
Options:
A)1
B)2
C)3
D)4
E)5
Rationale: Good=9 fish on a days
Fair =7 fish on b days
Poor=5 fish on c days
9a+7b+5c=53
a+b+c=7
c=1
ANSWER:A
Answer: A
Question: A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If four marbles are picked at random, what is the probability that none is blue?
Options:
A)17/91
B)33/91
C)51/91
D)65/91
E)None of these
Rationale: Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles. When four marbles are picked at random, then the probability that none is blue is = ¹²C₄/¹⁵C₄ = (12 * 11 * 10 * 9)/(15 * 14 * 13 * 12) = 33/91
ANSWER:B
Answer: B
Question: Two cars were driven by A and B. They were 580 miles apart when they started driving towards each other.A's car had traveled at a speed of 20 miles per hour, 4 hours per day for 5 days when it had met B's car. If B had driven 3 hours per day for days, what was B's speed in miles per hour?
Options:
A)8
B)9
C)105
D)11
E)10
Rationale: 1. At 20mph for 4 hours a day, then driver A was traveling 80 miles per day. When A met with B, A had already traveled 400 miles.
2. This means that driver B had traveled 580-400 = 180 miles upon meeting up with A. B traveled a total of 3 x 6 = 18 hours (3hrs/day for 6 days). 180 miles / 18 hours = 10mph
3. Answer E!
Answer: E
Question: What proximate value should come in place of the question mark (?) in the following question?
7.595 Ã— 1084 + 2568.34 â€“ 1708.34 = ?
Options:
A)6,000
B)12,000
C)10,000
D)9068
E)9,099
Rationale: ? â‰ˆ 7.6 Ã— 1080 + 2560 â€“ 1700 â‰ˆ 8208 + 860 â‰ˆ 9068
Answer D
Answer: D
Question: The charge for a single room at Hotel P is 40 percent less than the charge for a single room at Hotel R and 10 percent less than the charge for a single room at Hotel G. The charge for a single room at Hotel R is what percent greater than the charge for a single room at Hotel G ?
Options:
A)15%
B)20%
C)40%
D)50%
E)150%
Rationale: Let rate in R = 100x
then P = 60x
G = 100y
P = 90y
Thus
60 x=90y
or x = 1.50 y
Ans R = 150y
so increase = 50%
Answer: D
Answer: D
Question: The radius of a circular wheel is 1.75 m, how many revolutions will it make in traveling 1 km?
Options:
A)1000
B)3898
C)7973
D)2703
E)2881
Rationale: 2 * 22/7 * 1.75 * x = 11000
x = 1000
Answer: A
Answer: A
Question: Four brothers Adam, Bill, Charles and David together contributed certain amount of money and purchased a car. The contribution made by Adam is half that of the total contribution made by the other three brothers, contribution made by Bill is one-fourth of the total contribution made by the other three brothers and the contribution made by Charles is two-third of the total contribution made by the other three brothers. If the total price of the car is $9600, find the contribution made by David.
Options:
A)$540
B)$580
C)$600
D)$640
E)$680
Rationale: Given that A:(B+C+D)= 1:2.
Hence A contributed 1/3rd of the total price.
Given B:(A+C+D)=1:4
Hence B contributed 1/5th of the total price.
Given C:(A+B+D)=2:3
Hence C contributed 2/5th of the total price.
Thus the contribution made by A,B and C= 1/3+1/5+2/5=14/15
So, the remaining 1/15th of the price is contributed by David.
Hence David's contribution= 1/15×9600=$640.
The answer is D.
Answer: D
Question: A die is thrown twice and the sum of the numbers appearing is observed to be 6.
find the conditional probability that the number 4 has appeared at least once?
Options:
A)2/5
B)3/5
C)3/11
D)3/13
E)3/17
Rationale: Let E be the event that ‘number 4 appears at least once’ and F be
the event
that ‘the sum of the numbers appearing is 6’.
Then, E = {(4,1), (4,2), (4,3), (4,4), (4,5), (4,6), (1,4), (2,4), (3,4),
(5,4), (6,4)}
and F = {(1,5), (2,4), (3,3), (4,2), (5,1)}
We have P(E) = 11/36
and P (F) = 5/36
Also EnF = {(2,4), (4,2)}
Therefore P(EnF) = 2/36
the required probability
P(E|F) = P(EnF)/P(F) = (2/36)/(5/36) = 2/5.
A)
Answer: A
Question: What is the value of (44444445*88888885*44444442+44444438)/44444444^2
Options:
A)78888883
B)98888883
C)88888886
D)88888883
E)88888888
Rationale: let consider x=44444444
(x+1)*(2x-3)*(x-2)+(x-6)/x^2
=2x^3-5x^2/x^2
=2x-5
=2*44444444-5
=88888883
ANSWER:D
Answer: D
Question: The dimensions of a room are 25 feet * 15 feet * 12 feet. What is the cost of white washing the four walls of the room at Rs. 8 per square feet if there is one door of dimensions 6 feet * 3 feet and three WINDOWS of dimensions 4 feet * 3 feet each?
Options:
A)4000
B)345
C)5673
D)7248
E)8566
Rationale: Area of the four walls = 2h(l + b)
Since there are doors and WINDOWS, area of the walls = 2 * 12 (15 + 25) - (6 * 3) - 3(4 * 3) = 906 sq.ft.
Total cost = 906 * 8 = Rs. 7248
Answer: Option D
Answer: D
Question: The denominator of a fraction is 1 less than twice the numerator. If the numerator and denominator are both increased by 1, the fraction becomes 3/5. Find the fraction?
Options:
A)5/4
B)5/5
C)5/2
D)5/9
E)5/1
Rationale: Let the numerator and denominator of the fraction be 'n' and 'd' respectively.
d = 2n - 1
(n + 1)/(d + 1) = 3/5
5n + 5 = 3d + 3
5n + 5 = 3(2n - 1) + 3 => n = 5
d = 2n - 1 => d = 9
Hence the fraction is : 5/9.
Answer:D
Answer: D
Question: One man adds 5 liters of water to 10 liters of milk and another 4 liters of water to 20 liters of milk. What is the ratio of the strengths of milk in 2 mixtures?
Options:
A)4:5
B)9:11
C)2:3
D)4:7
E)3:7
Rationale: Strength of milk in the mixture = Quantity of milk/total quantity of mixture
strength of milk in the 1st mixture = 10/15
strength of the milk 2nd mixture = 20/24
The ratio of their strengths = 10/15 : 20/24 = 4:5
Answer is B
Answer: B
Question: 7 does not occur in 1000. So we have to count the number of times it appears between 1 and 999. Any number between 1 and 999 can be expressed in the form of xyz where 0 < x, y, z < 9.
Options:
A)210
B)300
C)235
D)256
E)245
Rationale: 1. The numbers in which 7 occurs only once. e.g 7, 17, 78, 217, 743 etc
This means that 7 is one of the digits and the remaining two digits will be any of the other 9 digits (i.e 0 to 9 with the exception of 7)
You have 1*9*9 = 81 such numbers. However, 7 could appear as the first or the second or the third digit. Therefore, there will be 3*81 = 243 numbers (1-digit, 2-digits and 3- digits) in which 7 will appear only once.
In each of these numbers, 7 is written once. Therefore, 243 times.
2. The numbers in which 7 will appear twice. e.g 772 or 377 or 747 or 77
In these numbers, one of the digits is not 7 and it can be any of the 9 digits ( 0 to 9 with the exception of 7).
There will be 9 such numbers. However, this digit which is not 7 can appear in the first or second or the third place. So there are 3 * 9 = 27 such numbers.
In each of these 27 numbers, the digit 7 is written twice. Therefore, 7 is written 54 times.
3. The number in which 7 appears thrice - 777 - 1 number. 7 is written thrice in it.
Therefore, the total number of times the digit 7 is written between 1 and 999 is 243 + 54 + 3 = 300
Ans: B
Answer: B
Question: If x and y are different prime numbers, each greater than 12, which of the following must be true? I. x+y is an even integer II. xy is an odd integer III. (x/y) is not an integer
Options:
A)I only
B)I,II and III
C)II only
D)III only
E)I,III only
Rationale: Given: x and y are different prime numbers, both greater than 12
Statement I: x+y is an even integer
Since x and y are prime numbers greater than 12, they will be odd
Therefore sum will be even.
Correct
Statement II: xy is an odd integer
Since x and y are prime numbers greater than 12, they will be odd
Therefore multiplication will be odd.
Correct
Statement III: (x/y) is not an integer
Since x and y are prime integers, therefore they will not have any common factor apart from 1
Hence (x/y) will not be an integer
Correct
Hence all three statements I, II and III are correct
Answer : B
Answer: B
Question: A certain truck uses 18 gallons of diesel fuel in traveling 270 miles. In order for the truck to travel the same distance using 10 gallons of diesel fuel, by how many miles per gallon must the truck’s fuel mileage be increased?
Options:
A)8
B)9
C)12
D)15
E)27
Rationale: There are two sets 18G1 gallons and 10G2 gallons details given.
18 gallons covering 270 miles
Then 1 G1 is used to cover 15 miles.
Now for 10 G2 covering 270 miles.
then 1 G2 is used to cover 27 miles.
There must 27 - 15 = 12 miles per gallon increment is needed for 10 gallons to improve the mileage to cover 270 miles.
Answer: C is correct answer.
Answer: C
Question: Set X consists of all two-digit primes and set Y consists of all positive odd multiples of 9 less than 100. If the two sets are combined into one, what will be the range of the new set?
Options:
A) 84
B) 89
C) 90
D) 92
E) 95
Rationale: Set X = {11, 13, 17,............., 83, 89, 97}
Set Y = {9, 27, 45,..............., 63, 81, 99}
Combining two sets, say Set Z
Set Z = {9, 11, 13, 17, 27,..................., 63, 81, 83, 89,97,99}
Range = Max Value - Min Value
Range (Z) = 99 - 9 = 90
OA C is the answer.
Answer: C
Question: What is the present worth of Rs. 165 due in 2 years at 5% simple interest per annum
Options:
A)110
B)120
C)130
D)150
E)None of these
Rationale: Explanation:
Let the present worth be Rs.x
Then,S.I.= Rs.(165 - x)
= (x*5*2/100) = 165 - x
= 10x = 16500 - 100x
= 110x = 16500
x= 150
Answer: D
Answer: D
Question: A man rows his boat 85 km downstream and 45 km upstream, taking 2 1/2 hours each time. Find the speed of the stream?
Options:
A)7
B)6
C)5
D)8
E)2
Rationale: Speed downstream = d/t = 85/(2 1/2) = 34 kmph
Speed upstream = d/t = 45/(2 1/2) = 18 kmph
The speed of the stream = (34 - 18)/2 = 8 kmph.Answer: D
Answer: D
Question: Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 9 hours and 16 hours respectively. The ratio of their speeds is?
Options:
A)4:7
B)4:3
C)4:0
D)4:2
E)4:6
Rationale: Let us name the trains A and B.
Then, (A's speed) : (B's speed)
= √b : √a = √16 : √9
= 4:3
Answer:B
Answer: B
Question: If x<0, y<0, and |x| > |y|, which of the following must be true?
Options:
A)x > y
B)y^2 > x^2
C)x^3 > y^2
D)x < y
E)x < –y
Rationale: Correct Answer: (E)
Let’s go through each answer choice: (A) can never be true, since no negative is greater than a positive. (B) doesn’t have to be true – consider what would happen if x = -2 and y = 1. (C) can never be true, as x^3 must be negative, and y^2 must be positive. (D) can never be true, since if x < 0, -x is the same thing as |x|, and |x| > y. (E) can be manipulated by multiplying both sides by -1, which gives us –x > y. Remember that x < 0, so –x = |x|, and y is positive, so |y| = y. Thus x < y is the same statement as |x| > |y|, and (D) must be true.
Answer: D
Question: A thief steals at a car at 2.30 p.m. and drives it at 60 km/hr. The theft is discovered at 3 p.m. and the owner sets off in another car at 75 km/hr. When will he overtake the thief?
Options:
A)1 p.m
B)3 p.m
C)4 p.m
D)5 p.m
E)6 p.m
Rationale: D
5 p.m
Suppose the thief is overtaken x hrs after 2.30 p.m.
Then, distance covered by the owner in (x - 1/2) hrs.
60x = 75(x - 1/2) => x = 5/2 hrs.
So, the thief is overtaken at 5 p.m.
Answer: D
Question: A certain street contains 100 buildings.They are numbered from 1 to 100. How many 9s are used in numbering these buildings?
Options:
A)21
B)20
C)19
D)18
E)9
Rationale: 9,19,29,39,49,59,69,79,89,90,91,92,93,94,95,96,97,98,99
so number of 9's=20
ANSWER:B
Answer: B
Question: If 1/(c – 2) = 1/(c + 2) + 1/(c – 1), which of the following is a possible value of c?
Options:
A)-2
B)2
C)-1
D)0
E)1
Rationale: Multiply by (c-2)*(c+2)*(c-1) throughout to get:
(c+2)*(c-1) = (c-2)*(c-1) + (c+2)(c-2)
Of the given options, only c=0 satisfies this.
Answer : D
Answer: D
Question: What is the number? I. The sum of the two digits is 8. The ratio of the two digits is 1 : 3. II. The product of the two digit of a number is 12. The quotient of two digits is 3.
Options:
A)I alone sufficient while II alone not sufficient to answer
B)II alone sufficient while I alone not sufficient to answer
C)Either I or II alone sufficient to answer
D)Both I and II are not sufficient to answer
E)Both I and II are necessary to answer
Rationale: Let the tens and units digit be x and y respectively. Then,
I. x + y = 8 and	x/y	=	1/3
I gives, 4y = 24 y = 6.
So, x + 6 = 8 x = 2.
II. xy = 12 and	x/y	=	3/1
II gives, x^2 = 36 x = 6.
So, 3y = 6 y = 2.
Therefore, Either I or II alone sufficient to answer.
Option C
Answer: C
Question: In a division sum, the remainder is 6 and the divisor is 5 times the quotient and is obtained by adding 2 to the thrice of the remainder. The dividend is
Options:
A)74
B)78
C)86
D)92
E)98
Rationale: Divisor = (6 * 3) + 2 = 20
5 * Quotient = 20
Quotient = 4.
Dividend = (Divisor * Quotient) + Remainder
Dividend = (20 * 4) + 6 = 86.
C)
Answer: C
Question: In an examination, a student scores 4 marks for every correct answer and loses 1mark for every wrong answer. If he attempts all 200 questions and secures 240 marks, the number of questions he attempts incorrectly, is:
Options:
A)135
B)200
C)140
D)112
E)48
Rationale: Let the number of correct answers be x.
Number of incorrect answers = (200 â€“ x).
4x â€“ (200 â€“ x) = 240 or 5x = 440 or x = 88.
Number of incorrect answers=200-88=112
ANSWER:D
Answer: D
Question: Paper charge is Rs. 60 per kg. How much expenditure would be there to cover a cube of edge 10m with a paper, if one kg of paper covers 20 sq.m. area?
Options:
A)Rs. 2250
B)Rs. 3600
C)Rs. 2700
D)Rs. 1800
E)None of these
Rationale: Explanation:
Total surface area of the cube =6x(10)2=600sq.m
1kg covers 20sq.m area,for 600 we need=600/20=30kg paper.
Expenditure=rate x quantity=Rs.60x30kg=Rs.1800
ANSWER IS D
Answer: D
Question: Last year, the taxes for small enterprises, was a minimum of 28 dollars for every 5000 dollars of revenue. Tax rates were revised this year to a minimum tax of 2.5 dollars for every 1500 dollars of revenue. By approximately what percent did the ratio of tax to revenue decrease from the previous charge?
Options:
A)70
B)69
C)71
D)66
E)72
Rationale: Initial tax/revenue ratio = 28/5000 = 84/15000
Revised charge/transaction ratio = 2.5/1500 = 25/15000
Answer: A
Answer: A
Question: A person crosses a 800m long street in 10 minnutes. What is his speed in km per hour?
Options:
A)5.8km/hr
B)4.68km/hr
C)9km/hr
D)2.5km/hr
E)3km/hr
Rationale: Speed = 800/10*60 = 1.3m/sec
=1.3*18/5
=4.68km/hr
Answer is B
Answer: B
Question: what is the smallest integer that is multiple of 7, 12 and 20
Options:
A)141
B)180
C)130
D)122
E)420
Rationale: Correct Answer :E
It is the lcm of 7, 12 and 20 which is 420
Answer: E
Question: If A speaks the truth 40% of the times, B speaks the truth 20% of the times. What is the probability that at least one will tell the truth
Options:
A)1.8
B)2.0
C)1.52
D)0.52
E)1.3
Rationale: probability of A speaks truth p(A)=4/10;false=6/10
probability of B speaks truth p(B)=2/10;false=8/10.For given qtn
Ans=1-(neither of them tell truth).Because A & B are independent events
=1-[(6/10)*(8/10)]=1-48/100=1-0.48=0.52
ANSWER:D
Answer: D
Question: This is a famous paradox probability riddle which has caused a great deal of argument and disbelief from many who cannot accept the correct answer.
Four balls are placed in a bowl. One is Green, one is Black and the other two are Yellow. The bowl is shaken and someone draws two balls from the bowl. He looks at the two balls and announces that atleast one of them is Yellow. What are the chanches that the other ball he has drawn out is also Yellow?
Options:
A)1/4
B)1/5
C)1/6
D)1/7
E)1/8
Rationale: B
1/5
There are six possible pairings of the two balls withdrawn,
Yellow+Yellow
Yellow+Green
Green+Yellow
Yellow+Black
Black+Yellow
Green+Black.
We know the Green + Black combination has not been drawn.
This leaves five possible combinations remaining. Therefore the chances tbowl the Yellow + Yellow pairing has been drawn are 1 in 5.
Many people cannot accept tbowl the solution is not 1 in 3, and of course it would be, if the balls had been drawn out separately and the color of the first ball announced as Yellow before the second had been drawn out. However, as both balls had been drawn together, and then the color of one of the balls announced, then the above solution, 1 in 5, must be the correct one.
Answer: B
Question: Find the compound interest on $ 36,000 at 20% per annum for 9 months, compounded quarterly
Options:
A)2532.6
B)2552.2
C)2524.1
D)5674.5
E)2512.9
Rationale: Principal = $ 36000; Time = 9 months =3 quarters;
Rate = 20% per annum = 5% per quarter.
Amount = $ [36000 x (1+(5/100))^3] = $ 41674.5
CI. = $ (41674.5 - 36000) = $ 5674.5
Answer D.
Answer: D
Question: A discount electronics store normally sells all merchandise at a discount of 2 percent to 50 percent off the suggested retail price. If, during a special sale, an additional 20 percent were to be deducted from the discount price, what would be the lowest possible price of an item costing $100 before any discount?
Options:
A)$100.00
B)$40.00
C)$50.00
D)$30.00
E)$10.00
Rationale: Original price : 100 $
Max first discount = -50%
Thus : 100âˆ—(1âˆ’50/100)=50
Second discount on the discounted price = -20%
Thus : 50âˆ—(1âˆ’20/100)=40
Answer B.
Answer: B
Question: The letters of the word 'SURITE' are written in all possible orders and these words are written in alphabetical order. Then what is the rank of the word 'SURITI'
Options:
A)- 236
B)- 245
C)- 307
D)- 315
E)- 475
Rationale: Total Number of Words = 6! = 720 [(number of characters)/(repeating group )!]
After S, we have T and U.
Number of words starting with T = 5! = 120
Number of words starting with U = 5! = 120
So any word starting with S will have rank < 720 - 120(for Us) - 120(for Ts) = 480
Only option A < 480, so Answer is E
Answer: E
Question: Which of the following numbers should not be included in the set?
331, 482, 551, 263, 385, 242, 111
Options:
A)263
B)385
C)242
D)111
E)None of these
Rationale: Solution
In each number except 385,the product of first and third digits is the middle one. Answer B
Answer: B
Question: What should come in place of the question mark (?) in the following equation?
90000 + 5010 = 87050 + ?
Options:
A)7960
B)7554
C)8465
D)4578
E)4689
Rationale: 90000 + 5010 = 87050 + ?
90000 + 5010 – 87050 = 7960
Answer A
Answer: A
Question: A rectangular grass field is 75 m * 55 m, it has a path of 2.5 m wide all round it on the outside. Find the area of the path and the cost of constructing it at Rs.2 per sq m?
Options:
A)1350
B)2997
C)2087
D)2697
E)9824
Rationale: Area = (l + b +2d) 2d
= (75 + 55 +2.5 * 2) 2*2.5
=> 675
675 * 2
= Rs.1350
Answer:A
Answer: A
Question: Each person who attended a company meeting was either a stockholder in the company, an employee of the company, or both. If 60 percent of those who attended the meeting were stockholders and 47 percent were employees, what percent were stockholders who were not employees?
Options:
A) 34%
B) 38%
C) 45%
D) 53%
E) 62%
Rationale: Let M represent the number of meeting attendees. Then, since 60% of M or 0.60M
were stockholders and 47% of M or 0.47M were employees, it follows that 0.60M +
0.47M = 1.07M were either stockholders, employees, or both. Since 1.07M exceeds
M, the excess 1.07M − M = 0.07M must be the number of attendees who were both
stockholders and employees, leaving the rest 0.60M − 0.07M = 0.53M, or 53%, of
the meeting attendees to be stockholders but not employees.
The correct answer is D.
Answer: D
Question: The average weight of 5 persons increases by 1.5 kg. If a person weighing 65 kg is replaced by a new person, what could be the weight of the new person?
Options:
A)76 kg
B)77 kg
C)72.5 kg
D)Data inadequate
E)None of these
Rationale: total weight increases = 5 × 1.5 = 7.5 kg
so the weight of new person = 65 + 7.5 = 72.5 kg
Answer C
Answer: C
Question: A certain NYC taxi driver has decided to start charging a rate of r cents per person per mile. How much, in dollars, would it cost 5 people to travel x miles if he decides to give them a 50% discount?
Options:
A)xr/40
B)3x/200r
C)3r/200x
D)3xr/200
E)xr/600
Rationale: 1 person for x miles = xr cents
5 person for x miles = 5xr
After discount 50% = 5xr/2 cents
In dollars = 5xr/200= xr/40
Answer : A
Answer: A