divelab/Sys2Bench huggingface dataset:
Question: A certain set of test scores has an average (arithmetic mean) of 70 and a standard deviation of 25. If m and n, two numbers in the set, are both within 2 standard deviations from the average, then which of the following could be the average of m and n?
Options:
A)10
B)14
C)17
D)19
E)21
Rationale: Given, mean = 70, SD = 25
Mean + 2(Standard Deviation) = 120
Mean - 2(Standard Deviation) = 20
m,n are both in this range i.e (20 to 120)
The least value that m,n take is 21 since m,n > 20
m=n=21
Average of 2 numbers is 21
Answer: E
Answer: E
Question: A money lender lends Rs.1200 for six months at 20% p.a. rate. It the interest is reckoned quarterly than find the amount given after time limit?
Options:
A)2205
B)1978
C)2834
D)1323
E)2781
Rationale: A = 1200(21/20)2
= 1323
Answer: D
Answer: D
Question: In a 60 liters of mixture of spirit and water, water is 7 %. In order to make water 19%, how much water should be added?
Options:
A)80/9 liters
B)70/9 liters
C)90/9 liters
D)60/9 liters
E)85/9 liters
Rationale: let the amount of spirit is x liters so according to the given condition
x = 60*0.93 = 55.8 and amount of water = 4.2
let the water added = y liters
so (4.2+y)/(60+y) = 19/100
on solving we will get y = 80/9 liters
ANSWER:A
Answer: A
Question: A radio station has to choose five days of the seven in a week to broadcast a certain program, and that set will repeat each week. The program can be broadcast equally on any of the seven weekdays —- weekdays vs. weekends don’t matter at all —- nor does it matter whether the days the program airs are adjacent or not. Absolutely any three of the seven weekdays can be chosen. How many different three-day combinations of the seven weekdays can be constructed?
Options:
A)9
B)15
C)21
D)35
E)56
Rationale: Behind the story, we are really being asked to evaluate 7C5. We could use the factorial formula, but above we conveniently happen to have Pascal’s Triangle written out to the seventh row. We see that 7C5, the third entry of the seventh row, is 21. Answer = C.
Answer: C
Question: 10 men and 15 women together can complete a work in 8 days. It takes 100 days for one man alone to complete the same work. How many days will be required for one woman alone to complete the same work?
Options:
A)127 days
B)667 days
C)177 days
D)187 days
E)600 days
Rationale: 1 man's 1 day work = 1/100
(10 men + 15 women)'s 1 day work = 1/8
15 women's 1 day work = (1/8 - 10/100) = 1/40
1 woman's 1 day work = 1/600
1 woman alone can complete the work in 600 days.
Answer:E
Answer: E
Question: The sum of the two numbers is 12 and their product is 35. What is the sum of the reciprocals of these numbers?
Options:
A)12/35
B)1/35
C)35/8
D)7/32
E)7/33
Rationale: Let the numbers be a and b. Then,
a + b = 12 and ab = 35.
(a + b)/ab = 12/35
= (1/b + 1/a) = 12/35
Sum of reciprocals of given numbers = 12/35.
ANSWER:A
Answer: A
Question: Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 9 hours and 16 hours respectively. The ratio of their speeds is?
Options:
A)4:6
B)4:3
C)4:1
D)4:9
E)4:2
Rationale: Let us name the trains A and B.
Then, (A's speed) : (B's speed)
= √b : √a = √16 : √9 = 4:3
Answer: B
Answer: B
Question: Two pipes A and B can fill a tank in 4 and 5 hours respectively. If they are turned up alternately for one hour each, the time taken to fill the tank is?
Options:
A)4 hrs 46 min
B)4 hrs 24 min
C)4 hrs 34 min
D)3 hrs 34 min
E)4 hrs 14 min
Rationale: 1/4 + 1/5 = 9/20
20/9 = 2 2/9
9/20 * 2 = 9/10 ---- 4 hours
WR = 1 - 9/10 = 1/10
1 h ---- 1/4
? ----- 1/10
2/5 * 60 = 24 = 4 hrs 24 min
Answer: B
Answer: B
Question: Tina’s cat weighs 2.6 kilograms. Her dog weighs 8 times as much as her cat. How much does her dog weigh in kilograms?
Options:
A)A)10.4kg
B)B)20.8kg
C)C)22kg
D)D)48kg
E)E)20kg
Rationale: 2.6*8=20.8kg.Answer is B.
Answer: B
Question: The true discount on a bill due 9 months hence at 16% per annum is Rs. 150. The amount of the bill is
Options:
A)1200
B)1764
C)1400
D)1354
E)None of these
Rationale: Explanation:
Let P.W. be Rs.x.
Then, S.I. on Rs. x at 16% for 9 months = Rs. 150.
x Ã— 16 Ã— (9/12) Ã— (1/100) = 150 or x = 1250.
P.W. = Rs. 1250
Sum due = P.W. + T.D. = Rs.(1250
150) = Rs. 1400
Answer: C
Answer: C
Question: Find the number of triangles which can be formed by joining the angular points of a polygon of 8 sides as vertices.
Options:
A)56
B)24
C)16
D)8
E)7
Rationale: Solution: A triangle needs 3 points.
And polygon of 8 sides has 8 angular points.
Hence, number of triangle formed,
= 8C3 = (8*7*6)/(1*2*3)
= 56.
Answer: Option A
Answer: A
Question: A sun is divided among X, Y and Z in such a way that for each rupee X gets, Y gets 45 paisa and Z gets 30 paisa. If the share of Y is RS. 18, what is the total amount?
Options:
A)70
B)105
C)178
D)177
E)169
Rationale: x:y:z = 100:45:30
20:9:6
9 --- 18
35 --- ? => 70
Answer: A
Answer: A
Question: (3136 + 6160) / 28
Options:
A)380
B)350
C)332
D)310
E)None of these
Rationale: Explanation:
As per BODMAS rule, first we will solve the equation in bracket then we will go for division
= (9296)/28 = 332
Option C
Answer: C
Question: Each Machine of type A has 4 steel parts and 2 chrome parts. Each machine of type B has 2 steel parts and 1 chrome parts. If a certain group of type A and type B machines has a total of 30 steel parts and 33 chrome parts, how many machines are in the group
Options:
A)12
B)13
C)14
D)16
E)19
Rationale: Look at the below representation of the problem:
Steel Chrome total
A 4 2 30 >>no. of type A machines=30/6=5
B 2 1 33 >>no. of type B machines=33/3=11
So the answer is 16 i.e D.
Hope its clear .
Answer: D
Question: Machines P and Q are two different machines that cover jars in a factory. When Machine P works alone, it covers 5 jars in m hours. When Machines P and Q work simultaneously at their respective rates, they cover 5 jars in n hours. In terms of m and n, how many hours does it take Machine Q, working alone at its constant rate, to cover 5 jars?
Options:
A)m+n
B)5n/25-mn
C)m-n
D)m
E)n
Rationale: working rate p = 5/m ; working rate pq =( 1/p +1/q)* n =5 or mn/5 +n/q =5 0r n/q = 5-mn/5 = 25-mn/5
q = 5n/25-mn
B
Answer: B
Question: A can do a certain job in 18 days. B is 60% more efficient than A. How many days does B alone take to do the same job?
Options:
A)11 1/4 days
B)8 days
C)5 days
D)9 days
E)None of them
Rationale: Ratio of times taken by A and B = 160 : 100 = 8 : 5.
Suppose B alone takes x days to do the job.
Then, 8 : 5 :: 18 : x = 8x = 5 x 18 =x = 11 1/4 days.
Answer is A.
Answer: A
Question: If the digits 31 in the decimal 0.00031 repeat indefinitely, what is the value of (10^5-10^3)(0.00031)?
Options:
A)31
B)0.31
C)0.0031
D)0.00031
E)3.1e-05
Rationale: 99*0.31=30.69 approx. 31
Answer : A
Answer: A
Question: 1.5, 2.5, 4.5, 7.5, 11.5, (....)
Options:
A)16.5
B)15.5
C)14.5
D)17.5
E)17
Rationale: Explanation:
1, 2, 3, 4, 5, etc.
Hence 5=16.5
Answer : A
Answer: A
Question: Source: Knewton
A cyclist's speed varies, depending on the terrain, between 6.0 miles per hour and 14.0 miles per hour, inclusive. What is the maximum distance, in miles, that the cyclist could travel in 5 hours?
Options:
A) 42
B) 56
C) 70
D) 98
E) 140
Rationale: We are told that:generallya cyclist's speed varies, depending on the terrain, between 6.0 miles per hour and 14.0 miles per hour, inclusive. Is it possible the cyclist to travel with maximum speed for some time? Why not, if there is right terrain for that. So, if there is long enough terrain for the maximum speed of 14 mph then the maximum distance, in miles, that the cyclist could travel in 5 hours would be 5*14=70 miles.
Answer: C.
Answer: C
Question: What is the probability of flipping a fair coin six times and the coin landing on heads on at least two flips?
Options:
A)11/16
B)23/32
C)29/32
D)51/64
E)57/64
Rationale: The number of possible outcomes is 2^6=64.
0 heads: There is 1 way to have all tails.
1 head: There are 6 ways to have one head.
P(0 or 1 head)=7/64
P(at least 2 heads)=1 - 7/64 = 57/64
The answer is E.
Answer: E
Question: What number should replace the question mark?
100, 93, 79, 58, ?
Options:
A)30
B)26
C)37
D)33
E)17
Rationale: A
30
The sequence progresses –7, –14, –21, –28.
Answer: A
Question: A batsman scored 120 runs whichincluded 3 boundaries and 8sixes. What % of his total score did he make by running between the wickets
Options:
A)30%
B)50%
C)40%
D)55%
E)60%
Rationale: Number of runs made by running = 110 - (3 x 4 + 8 x 6)
= 120 - (60)
= 60
Now, we need to calculate 60 is what percent of 120.
=> 60/120 * 100 = 50%
B
Answer: B
Question: With what number must 0.987 be multiplied in order to obtain the number 987?
Options:
A)100
B)1,000
C)10,000
D)100,000
E)None of these
Rationale: Explanation: The decimal must be moved three places to the right. To do this, we must multiply by a number with three zeroes. The correct answer is 1000.The decimal must be moved three places to the right. To do this, we must multiply by a number with four zeroes. The correct answer is 1000.
Answer : (B)
Answer: B
Question: I bought two books; for Rs.480. I sold one at a loss of 15% and other at a gain of 19% and then I found each book was sold at the same price. Find the cost of the book sold at a loss?
Options:
A)327
B)280
C)277
D)216
E)287
Rationale: x*(85/100) = (480 - x)119/100
x = 280
Answer: B
Answer: B
Question: Simran started a software business by investing Rs. 50,000. After six months, Nanda joined her with a capital of Rs. 80,000. After 3 years, they earned a profit of Rs. 245. What was Simran share in the profit?
Options:
A)s 950.10
B)s 10,000
C)s 125.00
D)s 105.00
E)s 140.00
Rationale: Simran : Nanda = (50000 x 36) : (80000 x 30) = 3 : 4.
Simran's share = Rs.245 x	3/7	= Rs. 105.
ANSWER :D
Answer: D
Question: Of the total amount that Jill spent on a shopping trip, excluding taxes, she spent 50 percent on clothing, 20 percent on food, and 30 percent on other items. If Jill paid a 4 percent tax on the clothing, no tax on the food, and an 10 percent tax on all other items, then the total tax that she paid was what percent of the total amount that she spent, excluding taxes?
Options:
A) 2.8%
B) 3.6%
C) 4.4%
D) 5%
E) 6.0%
Rationale: Let amount spent by Jill = 100
Clothing=50, Food=20, others=30
Tax on clothing= 2
Tax on others=3
Percentage= 5/100 =5%
Answer: D
Answer: D
Question: A number Y is chosen at random from the numbers 1, -3, -1, 0, 1, 2, 3. What is the probability that |X|<3?
Options:
A)2/5
B)3/5
C)3/7
D)4/9
E)4/11
Rationale: |X||X| can take 7 values.
To get |X|<2|X|<2 ( i.e., −2<x<+2−2<x
⇒ P(|X|<2)= Favourable CasesTotal CasesP(|X|<2)= Favourable CasesTotal Cases
= 3/7
C
Answer: C
Question: The average (arithmetic man) of three integers a, b, and c is exactly poland the median. If a < b < c and a = 0, what is the value of c/b?
Options:
A)2
B)3
C)8
D)5
E)Cannot be determined from the information given.
Rationale: The average of three integers a, b, and c is exactly twice the median --> (a+b+c)/3=3b --> since a=0, then (0+b+c)/3=3b --> c=8b --> c/b=8.
Answer: C.
Answer: C
Question: A car traveled 80% of the way from Town X to Town Y at an average speed of 80 mph. The car traveled at an average speed of v mph for the remaining part of the trip. The average speed for the entire trip was 50 mph. What is v in mph?
Options:
A)25
B)35
C)45
D)55
E)20
Rationale: Assume total distance = 100miles
Time taken for 80 miles = 80/80 = 1 hour
Time taken for the rest of the 20 miles = 20/v hours.
Average speed = 50
Therefore the total time needed = 2 hours.
2 = 1 + 20/v
Hence v = 20 mph
Answer : E
Answer: E
Question: A wears black shoes 25% of the time while B wears black shoes 68% of the time. 20% of the time A and B wear black shoes on the same day. Over a period of 100 days, how many days will they both not have black shoes?
Options:
A)27%
B)12%
C)45%
D)17%
E)80%
Rationale: A and B both wear black shoes 20% of the time: 0.20x100=20 days
.68x100=68-20=48 days A is wearing black shoes when B is not
.25x100=25-20=5 days B is wearing black shoes when A is not
48+5+20=73/100 either A or B is wearing black shoes
1-73/100 = 27% either A or B is NOT wearing black shoes
Answer is A
Answer: A
Question: A reduction of 25% in the price of oil enables a house wife to obtain 5kgs more for Rs.800, what is the reduced price for kg?
Options:
A)Rs.42
B)Rs.46
C)Rs.40
D)Rs.41
E)Rs.34
Rationale: 800*(25/100) = 200 ---- 5
? ---- 1 => Rs.40
Answer: C
Answer: C
Question: If X gets 25% more than Y and Y gets 20% more than Z, the share of Z out of Rs. 370 will be:
Options:
A)Rs. 300
B)Rs. 200
C)Rs. 100
D)Rs. 350
E)None of these
Rationale: Z share = Z,
Y = 1.2Z
X = 1.25Ã—1.2Z,
X+Y+Z =740
(1.25Ã— 1.2+1.2+1)Z=37
3.7Z=370, Z=100
Answer: . C
Answer: C
Question: An agent, gets a commission of 2.5% on the sales of cloth. If on a certain day, he gets Rs. 18 as commission, the cloth sold through him on that day is worth
Options:
A)333
B)500
C)887
D)720
E)132
Rationale: Explanation:
Let the total sale be Rs. x.
Then, 2.5%. of x = 18 <=> (25/10 * 1/100 * x) = 18 <=> x = 720.
Answer: D
Answer: D
Question: A circular plate with a diameter of 10 inches is kept on another plate of 12 inches diameter. What fraction of the big plate's surface is not covered by the small plate?
Options:
A)11/36
B)23/10
C)5/14
D)22/11
E)3/4
Rationale: The questions asks us to find the surface which is not covered by the plate i.e., area of the surface not covered.
Where as circumference is the length along the edge of the circle,
2*pi*r implies the length of the curve
pi*r^2 implies area enclosed by that curve..hence Area of the circle is considered for this problem
Area of the big plate=pi* r^2, where r=6
=>pi*36
Area of the small plate=pi*25
Surface not covered by the plate=pi*36-pi*25=Pi*11
fraction of big plate's surface is not covered by small plate= Pi*11/total area of the big plate
=>Pi*11/Pi*36
Answer A
Answer: A
Question: A , B and C are standing on a circular track of 4300m such that A and C are diametrically opposite and B is in between A and C .There clockwise order are ABC , B and C runs clockwise while A runs anti-clockwise .If the speed of A B and C are 5m/s , 8m/s and 10m/s respectively . They all start running at 10:00 AM. calculate the distance covered by B when A and C meet for the first time after 10:05AM .
Options:
A)3240 metres
B)3440 metres
C)3640 metres
D)4440 metres
E)2440 metres
Rationale: Relative speed of A & C will be.. 15 m/s.. hence for first they will meet at
2150/15= 143.33 sec (around 2min 23sec).. so time will be 10:02:23..this case will not be considered as it is before 10:05.. Again they will meet at
4300/15=286.66 sec(around 4min 46sec).. time will be 10:07:10.. this case will be considered
Hence in 7min10 sec i.e 430
In 430sec B will cover 430*8 metres=3440 metres
ANSWER:B
Answer: B
Question: Janey covered a distance of 340 miles between city A and city B taking a total of 5 hours. If part of the distance was covered at 60 miles per hour speed and the balance at 80 miles per hour speed, how many hours did she travel at 60 miles per hour?
Options:
A)1 hour 45 minutes
B)2 hours
C)2 hours 30 minutes
D)3 hours
E)None of these
Rationale: Janey covered a distance of 340 miles between city A and city B taking a total of 5 hours.time taken at 60:time taken at 80::(greater speed-average speed):(average speed-lower speed)
average speed is 340/5=68
That gives the answer 3:2=D
Answer: D
Question: A circular rim 50 inches in diameter rotates the same number of inches per second as a circular rim 15 inches in diameter. If the smaller rim makes x revolutions per second, how many revolutions per minute does the larger rim makes in terms of x ?
Options:
A)48pi/x
B)75x
C)48x
D)24x
E)200x
Rationale: Revolutions - circumference of the rim.
=> 50pi*X*60 = 15pi*Revolutions
=> 10/3 *X *60 = Revolutions => 200X - Option E
Answer: E
Question: 8^100 is divisible by 17 then find the remainder?
Options:
A)8
B)10
C)16
D)17
E)18
Rationale: This is an extremely difficult problem to solve with out Fermat's little theorem. By applying Fermat's little theorem , We know that 816 when divided by 17, the remainder is 1.
So divide 100 by 16 and find the remainder. Remainder = 4
Therefore, 100 = (16 × 6) + 4
Now this problem can be written as 810017 = 816×6+417 = (816)6×8417
Now this problem simply boils down to (1)6×8417 = 8417
84 = 82×82, we need to find the remainder when 64 × 64 is divisible by 17. Or 13 × 13 = 169. When 169 is divided by 17, remainder is 16.
C
Answer: C
Question: I chose a number and divide it by 4. Then I subtracted 175 from the result and got 10. What was the number I chose?
Options:
A)200
B)740
C)780
D)500
E)100
Rationale: Let x be the number I chose, then
x/4−175=10
x/4=185
x=740
Answer is B.
Answer: B
Question: There are 8 red, 7 blue and 6 green balls, 1 ball is picked up randomly thenwhat is the probability that neither blue nor green?
Options:
A)2/21
B)3/25
C)4/41
D)4/23
E)8/21
Rationale: Total number of balls = (8 + 7 + 6) = 21
Let E = event that the ball drawn is neither blue nor green =e vent that the ball drawn is red.
Therefore, n(E) = 8.
P(E) = 8/21.
Answer: E
Question: The total age of A and B is 17 years more than the total age of B and C. C is how many years younger than A ?
Options:
A)12
B)27
C)21
D)17
E)11
Rationale: (A+B) - (B+C) = 17
A - C = 17.
C is younger than A by 17 years.
Answer: D
Answer: D
Question: The operation # is defined for all nonzero x and y by x#y = x + x/y. If S>0, then 1#(1#S) =
Options:
A)S
B)S+1
C)S/(S+1)
D)(S+2)/(S+1)
E)(2S+1)/(S+1)
Rationale: x#y = x + x/y. If S>0, then 1#(1#S) =
You can see that a stands for y and 1 stands for x. I like to work with numbers so I did x=1 S=2 and S=y so y=2
1#S= 1+(1/2)=1.5 so now a is 1.5 --> 1+(1/1.5)=1 2/3 = 5/3
So now you can check by filling in S, which is 2:
A. S --> 2
B. S+1 --> 2+1=3
C. S/(S+1)-->2/(2+1)=2/3
D. (S+2)/(S+1)-->(2+2)/(2+1)=4/3
E. (2S+1)/(S+1)-->(2*2+1)/(2+1)=5/3
So E is the answer.
Answer: E
Question: A shopkeeper sells two articles at Rs.1000 each, making a profit of 20% on the first article and a loss of 20% on the second article. Find the net profit or loss that he makes?
Options:
A)6%
B)8%
C)4%
D)3%
E)5%
Rationale: C
4%
SP of first article = 1000
Profit = 20%
CP = (SP)*[100/(100+P)] = 5000/6 = 2500/3
SP of second article = 1000
Loss = 20%
CP = (SP)*[100/(100-L)] = 5000/4 = 1250
Total SP = 2000
Total CP = 2500/3 + 1250 = 6250/3
CP is more than SP, he makes a loss.
Loss = CP-SP = (6250/3)- 2000 = 250/3
Loss Percent = [(250/3)/(6250/3)]*100 =
0.04 * 100 = 4%
Answer: C
Question: The larger of two negative consecutive even integers 2t and 2(t-1) is multiplied by 4 and then added to the smaller of the two original integers. Which of the following represents this operation?
Options:
A)6t-2
B)10t-2
C)-2
D)3
E)-2-4t^2
Rationale: larger of 2t-2, 2t (when they are negative) is 2t. the smallest of 2t and 2t-2 when they are positive is 2t-2.
therefore 4* 2t + 2t-2 = 10t-2.
option B.
Answer: B
Question: Bob wants to run a mile in the same time as his sister. If Bob’s time for a mile is currently 10 minutes 20 seconds and his sister’s time is currently 9 minutes 36 seconds, by what percent does Bob need to improve his time in order run a mile in the same time as his sister?
Options:
A)3%
B)5%
C)7%
D)10%
E)12%
Rationale: Bob's time = 620 secs.
His sis' time = 576 secs.
Percent increase needed = (620-576/620) * 100 = 44/640 * 100 = 7%. Ans (C).
Answer: C
Question: If n = 2ef, where e and f are distinct prime numbers greater than 2, how many different positive even divisors does n have, including n ?
Options:
A) Two
B) Three
C) Four
D) Six
E) Eight
Rationale: Answer - 'C' - Four.
For a number 2ef with primes ef,there will be four even divisors - 2,2*e,2*f,2*e*f
Answer: C
Question: According to the directions on a can of frozen orange juice concentrate, 1 can of concentrate is to be mixed with 4 cans of water to make orange juice. How many 12 ounce cans of concentrate are required to prepare 140 six-ounce servings of orange juice?
Options:
A)12
B)14
C)16
D)18
E)20
Rationale: 1 X 12 ounce can of concentrate + 4 X 12 ounce cans of water = 60 ounces of the mixture.
60 ounces of mixture gives (60 / 6 ) = 10 servings.
Thus 1 x 12 ounce can of concentrate is used to produce 10 servings of the mixture.
To make 140 servings of the mixture, we need 140 / 10 = 14 cans of the concentrate.
The answer is B.
Answer: B
Question: A hexagon of side a cm is folded along its edges to obtain another hexagon
What is the % decrease in the area aof orignal hexagon
Options:
A)30%
B)50%
C)75%
D)80%
E)90%
Rationale: As we know, area of hexagon is = (3√3)(a^2)/2
now lets take a=2
then area = 6√3
after fold it will side become half ; a=1
new area = 1.5√3
percentage= 6√3/ 1.5√3* 100=25 %
so decrease in area =100 - 25=75%
ANSWER:C
Answer: C
Question: What is the average (arithmetic mean) of all multiples of 10 from 10 to 400 inclusive?
Options:
A)190
B)195
C)200
D)205
E)210
Rationale: We're asked for the average of all of the multiples of 10 from 10 to 400, inclusive.
To start, we can figure out the total number of terms rather easily:
1(10) = 10
2(10) = 20
...
40(10) = 400
So we know that there are 40 total numbers.
We can now figure out the SUM of those numbers with 'bunching':
10 + 400 = 410
20 + 390 = 410
30 + 380 = 410
Etc.
Since there are 40 total terms, this pattern will create 20 'pairs' of 410.
Thus, since the average = (Sum of terms)/(Number of terms), we have...
(20)(410)/(40) =
410/2 =
205
Final Answer:D
Answer: D
Question: A firm is comprised of partners and associates in a ratio of 2:63. If 45 more associates were hired, the ratio of partners to associates would be 1:34. How many partners are currently in the firm?
Options:
A)12
B)14
C)16
D)18
E)20
Rationale: The ratio 1:34 = 2:68 so the ratio changed from 2:63 to 2:68.
68-63 = 5 which is 1/9 of the increase in 45 associates.
The ratio changed from 18:567 to 18:612.
Thus the number of partners is 18.
The answer is D.
Answer: D
Question: If 35% of a number is 24 less than 50% of that number, then the number is ?
Options:
A)180
B)450
C)160
D)170
E)185
Rationale: Explanation:
Let the number be n. Then,
50% of n - 35% of n = 24
50/100 n - 35/100 n = 24
n = (24 x 100)/15 = 160.
Answer C
Answer: C
Question: A single discount equivalent to the discount series of 16%, 10% and 5% is?
Options:
A)28.18
B)38.9
C)41.6
D)31.4
E)31.1
Rationale: 100*(84/100)*(90/100)*(95/100) = 71.82
100 - 71.82 = 28.18
Answer: A
Answer: A
Question: In how many ways Chief Minister and Minister be elected from a team of 12 members?
Options:
A)128
B)134
C)132
D)145
E)150
Rationale: To do this, if captain is elected first, then we have 12 ways of doing this.
For election of vice-captain, we have only 11 ways left, coz 1 way is already consumed. (Situations like this is called dependent situation. One selection depends upon other selection.)
So, the ans is 12*11 = 132 ways.
C
Answer: C
Question: A grocer has a sale of Rs. 435, Rs. 927, Rs. 855, Rs. 230 and Rs. 562 for 5 consecutive days. How much sale must he have in the sixth day so that he gets an average sale of Rs. 625?
Options:
A)Rs 741
B)Rs 5991
C)Rs 6001
D)Rs 6991
E)None of these
Rationale: Explanation :
Total sale for 5 days = Rs. (435 + 927 + 855 + 230 + 562)
= Rs. 3009.
Required sale = Rs. [ (625 x 6) - 3009 ]
= Rs. (3750 - 3009)
= Rs. 741.
Answer : A
Answer: A
Question: When n liters of fuel was added to a tank that was already 1/3 full, the tank was filled to 4/9 of its capacity. In terms of n, what is the capacity of the tank, in liters?
Options:
A)10/9 n
B)4/3 n
C)3/2 n
D)9/4 n
E)7/3n
Rationale: E is the answer.
To solve this problem, draw diagram or use algebra. I'm more comfortable with algebra.
Given
- tank was already 1/3 full.
- When n ltr added, it became 4/9
So 1/3 + n = 4/9
n = 4/9 - 3/9
n = 1/9
capacity of the tank is full fraction . i.e. 1 i.e. 9/9
so the question is 9/9 is how much times n
= 9/9 = 1 = xn
so x = 9/1
and total = 9/1n=9n
Answer: E
Question: Four people each roll a die once. Find the probability that at least two people will roll the same number?
Options:
A)13/18
B)14/18
C)15/18
D)16/18
E)17/18
Rationale: atleast 2 means
1-p(no one has same number)
p(no person has same number)=6*5*4*3/6^4=10/36
reqd probability=1-10/36
=26/36=13/18
ANSWER:A
Answer: A