divelab/Sys2Bench huggingface dataset:
Question: An exporter expects a gain of 22.5% on his cost price. If in a week, his sale was of Rs. 392, what was his profit?
Options:
A)72
B)90
C)80
D)100
E)85
Rationale: Selling price = 392
gain = 25%
cost = 100*392/122.5=>320
profit = 392-320 = 72
ANSWER A
Answer: A
Question: A statue is being carved by a sculptor. The original piece of marble weighed 190 kg. In the first week 25 percent is cut away. In the second week 15 percent of the remainder is cut away. In the third week the statue is completed when 10 percent of the remainder is cut away. What is the weight of the final statue?
Options:
A)105 kg
B)103 kg
C)109 kg
D)125 kg
E)117 kg
Rationale: C
109 kg
190 Ã— 0.75 Ã— 0.85 Ã— 0.9 = 109 kg.
Answer: C
Question: A sum of money at simple interest amounts to Rs. 815 in 3 years and to Rs. 884 in 4 years. The sum is:
Options:
A)s. 608
B)s. 690
C)s. 698
D)s. 700
E)s. 760
Rationale: S.I. for 1 year = Rs. (884 - 815) = Rs. 69.
S.I. for 3 years = Rs.(69 x 3) = Rs. 207.
Principal = Rs. (815 - 207) = Rs. 608.
Answer: Option A
Answer: A
Question: Of the following quadratic equations, which is the one whose roots are 2 and – 15 ?
Options:
A)x2 - 2x + 15 = 0
B)x2 + 15x - 2 = 0
C)x2 + 13x - 30 = 0
D)x2 - 30 = 0
E)None of these
Rationale: Sol.
(c) Sum of roots = 2 – 15 = – 13
Product of roots = 2 × (– 15) = – 30
Required equation
= x2 - x(sum of roots) + product of roots = 0
=> x2 + 13x - 30 = 0
Answer C
Answer: C
Question: Six students are equally divided into 3 groups, then, the three groups were assigned to three different topics. How many different arrangements X are possible?
Options:
A) 30
B) 60
C) 90
D) 180
E) 540
Rationale: 90 is the number of ways you can assign 3 teams formed out of 12 people to 3 different tasks.
But now you can order the 3 tasks in 3! ways. T1 T2 T3 or T2 T1 T3.... etc etc.
I was confused between 90 and 540 but since question used the wordarrangementsdecided to go with complete arrangements X including the order of tasks.
could you explain the highlighted step... i'm getting 90 = 15 * 3!
suppose the students are numbered 1,2,3,4,5,6 and tasks are X,Y and Z
one of the 15 possible ways of forming teams is 12, 34, 56. these teams can be assigned to 3 tasks in 3! = 6 ways
X--	Y--	Z
12--	34--	56
12--	56--	34
34--	12--	56
34--	56--	12
56--	12--	34
56--	34--	12
so the answer should be 15*6 = 90
But now you can fruther decide which task you want to perform first X Y or Z..C
Answer: C
Question: 1, 1, 2, 1, 2, 3, 1, 2, 3, 4, 1, 2,__ ?
Options:
A)1
B)2
C)3
D)4
E)5
Rationale: 1,1,2,1,2,3,1,2,3,4,1,2,__?
Looking at the series
1
12
123
1234
12(3)45
So the answer is 3.
ANSWER:C
Answer: C
Question: The ratio between the perimeter and the width of a rectangle is 5:1. If the area of the rectangle is 150 square centimeters, what is the length of the rectangle in centimeters?
Options:
A)15
B)16
C)17
D)18
E)19
Rationale: Perimeter = 2(W+L) = 5W
3W = 2L
W = 2L/3
WL = 150
2L^2/3 = 150
L^2 = 225
L = 15 cm
The answer is A.
Answer: A
Question: Length of a rectangular plot is 22 mtr more than its breadth. If the cost of fencin gthe plot at 26.50 per meter is Rs. 5300, what is the length of the plot in mtr?
Options:
A)51 m
B)61 m
C)71 m
D)81 m
E)91 m
Rationale: Let breadth = x metres.
Then, length = (x + 22) metres.
Perimeter = 5300 m = 200 m.
26.50
2[(x + 22) + x] = 200
2x + 22 = 100
2x = 78
x = 39.
Hence, length = x + 22 = 61 m
B
Answer: B
Question: Given x = 20o, what is the value of log5(tan x)-log5(sin x)+log5(cos x)?
Options:
A)0
B)1 /2
C)1
D)log5 2
E)log2 5
Rationale: One approach is to use that
A + F = (A+B) + (C +D) + (E +F)􀀀(B +C)􀀀(D+E) = 1 + 3 +5􀀀2􀀀4 = 3:
The answer can also be obtained by taking A = 1 and solving for the remaining variables.
Since A + B = 1, we get B = 0. Since B + C = 2, we get C = 2. Continuing, we get
D = 1, E = 3, and F = 2. Thus, A + F = 1 + 2 = 3 is a possibility. There are other
possibilities for the variables A;B; : : : ; F (just set A equal to something else), but in any
case the sum A + F will be 3.
correct answer A
Answer: A
Question: When a positive integer A is divided by 5 and 11, the remainders obtained are 3 and 4, respectively. When the positive integer B is divided by 5 and 11, the remainders obtained are 3 and 4, respectively. Which of the following is a factor of (A - B)?
Options:
A)15
B)25
C)35
D)45
E)55
Rationale: A = 5k+3 = 11j+4
B = 5m+3 = 11n+4
A-B = 5(k-m) = 11(j-n)
A-B is a multiple of both 5 and 11, so it is a multiple of 55.
The answer is E.
Answer: E
Question: Salaries of Ranjani and Sudha are in the ratio 2:3. If the salary of each in increased by Rs.4000, the new ratio becomes 40:57. What is the Sudha's present salary?
Options:
A)34000
B)35000
C)37000
D)38000
E)36000
Rationale: let the org sal of ranjani and sudha be rs.2x and rs 3x respctvily.
then,
=2x+4000/3x+4000= 40/57
cross multiply
57(2x+4000)=40(3x+4000)
6x=68000 and 3x=34000
sudhas present sal =(3x+4000)=>(34000+4000)=>38000
ANSWER:D
Answer: D
Question: A boatman rows 96 km downstream in 8 hours with a stream speed of 4kmph. How much time will he take to cover 8km upstream?
Options:
A)2 hours
B)8 hours
C)6 hours
D)7 hours
E)9 hours
Rationale: Explanation:
Speed = distance/time
Speed downstream: 96 / 8 km/hr = 12kmph
Speed of stream = 4kmph
Effective speed of boat = (12-4) kmph
= 8kmph
Distance to be travelled upstream= 8 km
Speed upstream = boat speed-current speed
= 8-4 kmph
= 4 kmph
Time taken = distance/speed = 8/ 4 hours
=2 hours
ANSWER:A
Thus it will take 2 hours to go upstream.
Answer: A
Question: The sum of the two digits of a number is 10. If the number is subtracted from the number obtained by reversing its digits, the result is 54. Find the number?
Options:
A)15
B)12
C)28
D)36
E)96
Rationale: Explanation:
Any two digit number can be written as (10P + Q), where P is the digit in the tens place and Q is the digit in the units place.
P + Q = 10 ----- (1)
(10Q + P) - (10P + Q) = 54
9(Q - P) = 54
(Q - P) = 6 ----- (2)
Solve (1) and (2) P = 2 and Q = 8
The required number is = 28
Answer C
Answer: C
Question: The line Z represented by which of the following equation does not intersect with the line represented by y = 3x^2+5x+1
Options:
A)y = 2x^2+5x+1
B)y = x^2+5x+2
C)y = 3x^2+5x+2
D)y = 3x^2+7x+2
E)y = x^2+7x+1
Rationale: concept of slope for linesparabolas are different. Bunuel, please correct if I am wrong. Also please help to solve this problem if its a GMAT type question.
The general form of parabolic equ. is y^2= 4ax which implies the axis is x or x^2 = 4ay where axis is y.
We have a similar form as x^2 = 4ay.
here the vertex is origin.
So if we have same values of x and y but constant term changes then we will have parallel parabolas.
This is same as for straight line Z which are parallel for different values of constant term c
ax + by +c1 = 0 and ax +by+ c2 =0
We have quadratic equations. These equations when drawn give parabolas, not lines. The question is: which of the following parabolas does not intersect with the parabola represented by y=3x^2+5x+1.C
Answer: C
Question: Mr. Evans will states that each of his children will receive an equal share of his estate and that his grandchildren will split a portion of the estate that is equal to the share received by each of his children. If Mr. Evans has 4 children and 5 grandchildren, then approximately what percentage of Mr. Evans estate will each grandchild receive?
Options:
A)20%
B)17%
C)4.0%
D)3.3%
E)2.8%
Rationale: 20/5 = 4
Answer : C
Answer: C
Question: The average salary of all the workers in a workshop is Rs.8000. The average salary of 7 technicians is Rs.12000 and the average salary of the rest is Rs.6000. The total number of workers in the workshop is
Options:
A)20
B)21
C)22
D)23
E)24
Rationale: Solution
Let the toatl number of workers be x.
Then 8000x=(12000 x 7) + 6000 (x -7)
2000x =42000
x= 21.
Answer B
Answer: B
Question: Ross is 20 years older than his daughter Julie. In 5 years Ross will be twice as old as Julie. What is Julies current age.
Options:
A)10
B)15
C)20
D)30
E)25
Rationale: Now: Julie = x, Ross =x+20
In 5 years Julie = x+5, Ross = x+20+5 or 2(x+5)
x+20+5 = 2(x+5)
x+25=2x+10
25=x+10
15=x
Julie is 15 years old, the answer is B)
Answer: B
Question: How many kilograms of sugar costing Rs. 9 per kg must be mixed with 27 kg of sugar costing Rs. 7 per Kg so that there may be a gain of 10 % by selling the mixture at Rs. 9.24 per Kg ?
Options:
A)33
B)39
C)38
D)63
E)01
Rationale: By the rule of alligation:
C.P. of 1 kg sugar of 1st kind C.P. of 1 kg sugar of 2nd kind
{\color{Blue} \therefore } Ratio of quantities of 1st and 2nd kind = 14 : 6 = 7 : 3.
Let x kg of sugar of 1st kind be mixed with 27 kg of 2nd kind.
Then, 7 : 3 = x : 27 or x = (7 x 27 / 3) = 63 kg.
Answer: D) 63 Kg
Answer: D
Question: A tank can supply water to a village for 20 days. If a leak at the bottom of the tank drains out 10 liters per day, the supply lasts for 15 days only. For how many days will the supply last if the leak drains out 20 liters per day?
Options:
A)9
B)10
C)11
D)12
E)14
Rationale: Losing 10 liters per day results in a loss of 150 liters in 15 days. So, those 150 liters were for 5 days, making daily consumption of the village 30 liters per day. Thus the capacity of the tank is 30*20 = 600 liters.
Losing 20 liters plus 30 liters gives 50 liters per day. At this rate the supply will last 600/50 = 12 days.
The answer is D.
Answer: D
Question: The price of a certain painting increased by 30% during the first year and decreased by 15% during the second year. The price of the painting at the end of the 2-year period was what percent of the original price?
Options:
A)102%
B)105%
C)110.5%
D)112.5%
E)100%
Rationale: Easiest thing to do: Assume that price is 100
Price at the end of yr 1: 100+ 30 = 130
Price at the end of year 2 = 130 - 130*0.15 = 130*0.85 = 110.5
Hence required answer = (110.5/100)*100% = 110.5%
Answer is C.
Answer: C
Question: Divide $600 among A,B in the ratio 1:2. How many $ that A get?
Options:
A)$50
B)$500
C)$150
D)$250
E)$600
Rationale: Sum of ratio terms = 1+2 = 3
A = 600*1/3 = $200
Answer is E
Answer: E
Question: Vanya prepared 4 different letters to 4 different addresses. For each letter, she prepared one envelope with its correct address. If the 4 letters are to be put into the four envelopes at random, what is the probability that only one letter will be put into the envelope with its correct address?
Options:
A)1/24
B)1/8
C)1/4
D)1/3
E)3/8
Rationale: Total Vanya# of ways - 4! = 24.
Desired:
A-Mapped to the only correct address----------x 1 way only
B-Mapped to other two incorrect addresses - x 2 ways
C-Mapped to other two incorrect addresses - x 2 ways
D-Mapped to other two incorrect addresses - x 2 ways
Therefore, 1*2*2*2/24 = 1/3.?
Answer: D
Question: At a certain high school, the senior class is twice the size of the junior class. If 1/8 of the seniors and 3/4 of the juniors study Japanese, what fraction of the students in both classes study Japanese?
Options:
A)3/8
B)3/4
C)1/3
D)4/5
E)1/2
Rationale: Start by deciding on a number of students to represent the number of students in the senior class. For this example I will choose 200 students. That would make the number of students in the junior class 100. Then we can find out how many students are taking Japanese in each grade and add them together. (1/8)*200=25 and (3/4)*100=75. 25+75=100. There are a total of 300 students in the junior class and senior class combined (100+200=300), and there are 100 total students in Japanese, so 100 students in Japanese / 300 total students equals 1/3 of the students in both classes that study Japanese.
Answer: C
Answer: C
Question: The length of a rectangular floor is more than its breadth by 200%. If Rs. 324 is required to paint the floor at the rate of Rs. 3 per sq m, then what would be the length of the floor?
Options:
A)12
B)17
C)18
D)77
E)21
Rationale: Let the length and the breadth of the floor be l m and b m respectively.
l = b + 200% of b = l + 2b = 3b
Area of the floor = 324/3 = 108 sq m
l b = 108 i.e., l * l/3 = 108
l2 = 324 => l = 18.
Answer: C
Answer: C
Question: The height of a triangle is decreased by 25% and its base increased by 40%. Its area will
Options:
A)decrease by 12.5%
B)increase by 12.5%
C)decrease by 25%
D)Increase by 25%
E)Increase by 5%
Rationale: Explanation :
Let the initial height be 100 and the base be 200 units.
âˆ´ Area = 1/2 x 100 x 200 = 1000sq units
Now, height = 75 units and base = 280 units
âˆ´ New area = 1/2 x 75 x 280 = 10500
âˆ´ Area is increased by (10500 - 10000)/10000 x 100
= 5%
Answer : Option E
Answer: E
Question: Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. If the faster train passes the slower train in 36 seconds,what is the length of each train?
Options:
A)25
B)30
C)50
D)75
E)40
Rationale: Assume the length of each train = x
Total distance covered for overtaking the slower train = x+x = 2x
Relative speed = 46-36 = 10km/hr = (10×10)/36 = 100/36 m/s
Time = 36 seconds
2x/ (100/36) = 36
=> (2x × 36 )/100 = 36
=> x = 50 meter
Answer is C.
Answer: C
Question: A fruit seller had some Mangoes. He sells 60% and still has 20 apples. Originally, he had ?
Options:
A)10 Mangoes
B)60 Mangoes
C)40 Mangoes
D)50 Mangoes
E)None
Rationale: Answer
âˆµ 40% of N = 20
âˆ´ N = (20 x 100)/40 = 50
Correct Option: D
Answer: D
Question: 5 persons A,B,C,D and E occupy seats in a row at random. What is the probability that A and B sit next to each other ?
Options:
A)3/5
B)2/5
C)1/5
D)8/5
E)None of these
Rationale: Explanation :
Without restriction, number of arrangements = 5! .
=> Number of possible outcomes = T = 5! = 120 .
With restriction, number of arrangements = 4! x 2 .
( i.e considering A and B together) = 48.
=> Number of favourable outcomes = F = 48.
Hence,
P( A and B sit together)
=> F / T
=> No. of arrangements with restriction / No. of arrangements without restriction .
=> 48 / 120.
=> 2 / 5.
Answer : B
Answer: B
Question: A train covers a distance of 12 km in 10 min. If it takes 6 sec to pass a telegraph post, then the length of the train is?
Options:
A)247
B)267
C)120
D)872
E)267
Rationale: Speed = (12/10 * 60) km/hr
= (72 * 5/18) m/sec = 20 m/sec.
Length of the train
= 20 * 6
= 120 m.
Answer:C
Answer: C
Question: By weight, liquid X makes up 0.8 percent of solution A and 1.8 percent of solution B. If 200 grams of solution A are mixed with 700 grams of solution B, then liquid X accounts for what percent of the weight of the resulting solution?
Options:
A)1.42%
B)1.9%
C)10%
D)15%
E)19%
Rationale: I think there is a typo in question.
It should have been "By weight Liquid 'X ' makes up..... "
Weight of Liquid X = 0.8 % of Weight of A + 1.8% of Weight of B
When 200gms of A and 700gms of B is mixed :
Weight of Liquid X = (0.8 * 200)/100 + (1.8* 700)/100 = 14.2gms
% of Liquid X in resultant mixture = (14.2/1000) *100 = 1.42%
A
Answer: A
Question: The Delhi Express runs @ 144 kilometers per hours and it reaches destination 20 minute ahead of schedule. If it averages 100 km/hour, it reaches 24 minute behind schedule. What is the average speed it should maintain in order to reach the destination on schedule?
Options:
A)250
B)240
C)230
D)245
E)235
Rationale: If the destination is D kilometer and the speed in order to reach on schedule is S km/hour,
the time taken to reach on schedule is D/S hours
Thus we get two equations:
D/144 = D/S - 1/3 and
D/100 = D/S + 2/5 and
Subtracting the first equation from the second we get : 44D/14400 = 11/15
Thus D = 14400 x 11/ 44 x 15 = 240
ANSWER:B
Answer: B
Question: At what price must an Book costing $47.50 be marked in order that after deducting 20% from the list price. It may be sold at a profit of 25% on the cost price?
Options:
A)72.5
B)55.5
C)64.2
D)82.5
E)60.5
Rationale: C
$62.50
CP = 47.50
SP = 47.50*(125/100) = 59.375
MP*(80/100) = 59.375
MP = 74.2
Answer: C
Question: At an examination in which full marks were 500. A got 10% less than B, B got 25% more than C and C got 20% less than D. If A got 360marks, what percentage of full marks was obtained by D?
Options:
A)48%
B)30%
C)12%
D)80%
E)28%
Rationale: A B C D
90 100 80 100
A D
90 ----- 100
360 ------ ? = 400
500 ------ 400
100 ------- ? => 80%
Answer: C
Answer: C
Question: Calculate the value of 4.54 x 10^5 ?
Options:
A)454
B)4540000
C)454000
D)45400
E)4540
Rationale: 4.54 x 10^5 = 4.54 x 100000 = 4540000.
Answer = B
Answer: B
Question: The expression uv+u is odd when the u and v are integers. Which of the following expressions must be even?
Options:
A)u
B)v
C)u + v
D)uv - u
E)u + v^2
Rationale: uv+u is odd
u and v are integers
If u were even uv+u would be even despite any value of v.
v can't be odd, so v must be even.
Ans : B
Answer: B
Question: The time taken by a man to row his boat upstream is twice the time taken by him to row the same distance downstream. If the speed of the boat in still water is 42 kmph, find the speed of the stream?
Options:
A)12
B)15
C)14
D)18
E)19
Rationale: The ratio of the times taken is 2:1.
The ratio of the speed of the boat in still water to the speed of the stream = (2+1)/(2-1) = 3/1 = 3:1
Speed of the stream = 42/3 = 14 kmph.
Answer: C
Answer: C
Question: Two vessels contains equal number of mixtures milk and water in the ratio 8:2 and 9:1. Both the mixtures are now mixed thoroughly. Find the ratio of milk to water in the new mixture so obtained?
Options:
A)1:3
B)9:13
C)5:11
D)11:3
E)17:3
Rationale: The ratio of milk and water in the new vessel is = (8/10 + 9/10) : (2/10 + 1/10)
= 17/10 : 3/10 = 17:3
Answer is E
Answer: E
Question: A can do a work in 6 days. B can do the same work in 8 days. Both A&B together will finish the work and they got $1000 from that work. Find their shares?
Options:
A)600,800
B)500,500
C)300,700
D)800,200
E)550,450
Rationale: Ratio of their works A:B = 6:8
Ratio of their wages A:B = 3:4
A's share = (3/5)1000 = 600
B's share = (4/5)1000 = 800
correct option is A
Answer: A
Question: Randy'sbar serves customers every weeknight from 5 pm to 1 am. In Randy's bar,Silvermoonbeer is sold at a constant rate except during happy hour, from 6:30 to 9:30 pm, when the rate triples.
If a keg of Silvermoon beer is half empty at 5pm on Monday, and two-thirds empty at the beginning of the happy hour, when will it be completely empty?
Options:
A)Monday, 7:30 pm
B)Monday, 9 pm
C)Monday, 7 pm
D)Monday, 6:45 pm
E)Monday, 9:30 pm
Rationale: Let the keg be a 150 Litre keg
At 5 pm.. There are 75 litres
At 6:30 pm there are 50 litres.
So, consumption rate is 25 litres per 1.5 hours.
So it will take 3 hours to finish 50 litres at this rate.
During happy hour it sells 3 times faster. So, rate = 1 hour per 50 litres.
So, keg becomes empty at 6:30 + 1 hour = 9:30 pm
Answer is E.
Answer: E
Question: 196, 144, 100, 64, 36, ?
Options:
A)16
B)8
C)18
D)12
E)6
Rationale: Explanation :
The pattern is 14^2, 12^2, 10^2, 8^2, 6^2, ...
So next number is 4^2 = 16
Answer : Option A
Answer: A
Question: A person covered one-fourth of the total distance at 20 kmph and remaining distance at 24 kmph. What is the average speed for the total distance?
Options:
A)21 (1/8)
B)21 (1/7)
C)22 (6/7)
D)29 (1/7)
E)21 (4/3)
Rationale: Let the total distance be x km
total time taken = (x/4)/20 + (3x/4)/24 = 7x/160
Average speed = x/(7x/160) = 22 (6/7)kmph.
Answer: C
Answer: C
Question: The sides of a rectangular field are in the ratio 3 : 4. If the area of the field is 10800 sq. m, the cost of fencing the field @ 25 paise per metre is
Options:
A)Rs. 55.50
B)Rs. 67.50
C)Rs. 86.50
D)Rs. 105.00
E)None of these
Rationale: Solution
Let length = (3x) metres and breadth = (4x) metres.
Then, 3x × 4x = 10800 ⇔ 12x2 = 10800 ⇔ x2 =900 ⇔ x = 30.
So, length = 90 m and breadth = 120 m.
Perimeter = [2(90 + 120)] m = 420 m.
∴ Cost of fencing = Rs. (0.25 × 420) = Rs. 105.00. Answer D
Answer: D
Question: Find the fourth proportion to 12,3,6
Options:
A)1.8
B)1.2
C)2.5
D)1.5
E)4
Rationale: Explanation:
12:3 :: 6:x
=> 12/3 = 6/x
=> x = 18/12
=> x = 3/2=1.5
Option D
Answer: D
Question: In one year, the population, of a village increased by 10% and in the next year, it decreased by 10%. If at the end of 2nd year, the population was 7920, what was it in the beginning?
Options:
A)8008
B)8000
C)8022
D)8021
E)8022
Rationale: x*110/100 * 90/100 = 7920
X*0.99=7920
X=7920/0.99
=> 8000
Answer:B
Answer: B
Question: In Town X, 64 percent of the population are employed, and 49 percent of the population are employed males. What percent of the employed people in Town X are females?
Options:
A)16%
B)20%
C)32%
D)40%
E)52%
Rationale: answer b
male-employed - 64%
female-employed-15%
Total employed 64%
means total unemployed = 36%
therefore d and e are not correct because female unemployed has to be less than 36%
female-unemployed = 32% male unemployed = 4%
48% + 4% = 52%
16% + 32% = 48%
plug in a and b in place of 32% and the sum is not 100%
15/64 =20 B
Answer: B
Question: How many numbers can be formed with the digits 1, 6, 7, 8, 6, 1 so that the odd digits always occupy the odd places
Options:
A)15
B)12
C)18
D)20
E)22
Rationale: Solution
The digits are 1, 6, 7, 8, 7, 6, 1. In this seven-digit no.there are four odd places and three even places OEOEOEO. The four odd digits 1, 7, 7, 1 can be arranged in four odd places in [4!/2!×2] = 6 ways [as 1 and 7 are both occurring twice].
The even digits 6, 8, 6 can be arranged in three even places in 3!/2! = 3 ways.
Total no. of ways = 6 × 3 = 18
Answer C
Answer: C
Question: A, B, C together started a business. A invested Rs.6000 for 5 months B invested Rs.3600 for 6 months and C Rs.7500 for 3 months. If they get a total profit of Rs.7410. Find the share of C?
Options:
A)2250
B)3000
C)3018
D)3019
E)3012
Rationale: 60*5:36*6:75*3
100: 72: 75
75/247 * 7410 = 2250
Answer: A
Answer: A
Question: A farmer used 1,034 acres of land for beans, wheat, and corn in the ratio of 5 : 2 : 4, respectively. How many R acres were used for corn?
Options:
A) 188
B) 258
C) 376
D) 470
E) 517
Rationale: consider 5x acres of land used for bean
consider 2x acres of land used for wheat
consider 4x acres of land used for corn
Total given is 1034 acres
11x =1034
x = 94
land used for corn R= 4 * 94 = 376
correct option - C
Answer: C
Question: 2, 4, 6, 8, 10, ?
Options:
A)10
B)14
C)16
D)12
E)24
Rationale: The sequence is a series of even numbers, 2, 4, 6, 8, 10, 12....
Answer : D.
Answer: D
Question: The C.P of 15 books is equal to the S.P of 18 books. Find his gain% or loss%?
Options:
A)16 2/3% loss
B)100/3% loss
C)50/3% profit
D)100/3% loss
E)200/3% loss
Rationale: Explanation:
15 CP = 18 SP
18 --- 3 CP loss
100 --- ? => 16 2/3% loss
ANSWER IS A
Answer: A
Question: If it is 5:27 in the evening on a certain day, what time in the morning was it exactly 2,880,717 minutes earlier? (Assume standard time in one location.)
Options:
A)5:22
B)5:24
C)5:27
D)5:30
E)5:32
Rationale: 5:27minus 2,880,717in any way must end with 0, the only answer choice which ends with 0 is D.
Answer: D.
Answer: D
Question: If (1 – 1.25)N = 4, then N =
Options:
A) −400
B) −16
C) −4
D) 4
E) 400
Rationale: (1 – 1.25)N = 4
Simplify to get: -0.25N = 4
Rewrite as (-1/4)N = 4
Multiply both sides by -4 to get: N = -16
Answer: B
Answer: B
Question: Three pieces of timber 24 m, 28 m and 36 m long have to be divided into planks of the same length, What is the greatest possible length of each plank ?
Options:
A)7 m
B)4 m
C)42 m
D)63 m
E)None of these
Rationale: Answer
Greatest possible length of each plank = H.C.F of 24, 28, 36 = 4 m
Correct Option: B
Answer: B
Question: Line Q has the equation 5y – 3x = 15. If Line S is perpendicular to Q, has an integer for its y-intercept, and intersects Q in the second quadrant, then how many possible Line S’s exist? (Note: Intersections on one of the axes do not count.)
Options:
A)9
B)11
C)13
D)15
E)17
Rationale: 5y - 3x = 15 and so y = 3x/5 + 3
When x = 0, then y = 3.
When y = 0, then x = -5
The slope is 3/5, so the slope of line S is -5/3.
Through the point (-5, 0), 0 = -5(-5)/3 + c
The y-intercept is c = -25/3 < -8.
Thus the perpendicular line S can have y-intercepts from -8 up to 2.
The number of possible lines is 8 + 2 + 1 = 11
The answer is B.
Answer: B
Question: Today is Saturday. After 72 days, it will be:
Options:
A)Sunday
B)Saturday
C)Monday
D)Thursday
E)Wednesday
Rationale: Each day of the week is repeated after 7 days.
So, after 70 days, it will be Saturday.
After 72 days, it will be Monday.
Answer :C
Answer: C