divelab/Sys2Bench huggingface dataset:
Question: Convert the following into a fraction: 0.5%
Options:
A)1/5
B)1/2
C)5/10
D)2/5
E)None of the Above
Rationale: 0.5 =5/10 (Simplify: both are divisible by 5)= 1/2
Answer is B.
Answer: B
Question: If 5 < x < 12 and y = x + 3, what is the greatest possible integer value of x + y?
Options:
A)23
B)24
C)25
D)26
E)27
Rationale: x+y = x+x+3 = 2x+3
We need to maximize this value and it needs to be an integer.
2x is an integer when the decimal of x is .0 or .5
The largest such value is 11.5
Then x+y = 11.5 + 14.5 = 26.
The answer is D.
Answer: D
Question: The average weight of 9 person's increases by 2.5 kg when a new person comes in place of one of them weighing 65 kg. What is the weight of the new person?
Options:
A)85.5
B)86.5
C)87.5
D)88.5
E)89.5
Rationale: Total increase in weight =9 × 2.5 = 22.5
If x is the weight of the new person, total increase in weight = x−65
=> 22.5 = x - 65
=> x = 22.5 + 65 = 87.5
ANSWER:C
Answer: C
Question: Ron begins reading a book at 4: 30 p.m. and reads at a steady pace of 30 pages per hour. Michelle begins reading a copy of the same book at 6: 00 p.m. If Michelle started 5 pages behind the page that Ron started on and reads at an average pace of 50 pages per hour, at what time would Ron and Michelle be reading the same page?
Options:
A)7: 00 p.m.
B)7: 30 p.m.
C)7: 45 p.m.
D)8: 00 p.m.
E)8: 30 p.m.
Rationale: Ron's speed is 30 pages per hour =1/2 page per minute
Time at which he starts reading is 4:30 pm
now,
by the time Michelle beings reading (6:00 pm) Ron has already covered (1/2)*90=45 pages
as per the question
Michelle starts 5 pages behind the page Ron started and her speed is 5/6 pages per minute
relative speed = 5/6-1/2=1/3
pages left =45+5=50
time taken to read those pages =50/(1/3)=150 minutes
Thus time taken to reach the same page
6:00 pm + (150 minutes) =8:30 pm
ANSWER:E
Answer: E
Question: By selling an article at Rs.120, a profit of 25% is made. Find its cost price?
Options:
A)s.96
B)s.45
C)s.120
D)s.180
E)s.189
Rationale: SP = 120
CP = (SP)*[100/(100+P)]
= 120* [100/(100+25)]
= 120* [100/125]
= Rs.96
Answer: A
Answer: A
Question: Mudit's age 16 years hence will be thrice his age four years ago. Find Mudit's present age?
Options:
A)14
B)19
C)27
D)18
E)15
Rationale: Explanation:
Let Mudit's present age be 'm' years.
m + 16 = 3(m - 4)
=> 2m = 28 => m = 14 years.
Answer:A
Answer: A
Question: Anna left for city A from city B at 5.20 a.m. She travelled at the speed of 80 km/hr for 2 hrs 15 min. After that the speed was reduced to 60 km/hr. If the distance between two cities is 350 kms, at what time did Anna reach city A?
Options:
A)10.25 a.m
B)9.25 a.m
C)11.25 a.m
D)12.25 a.m
E)01.25 a.m
Rationale: A
10.25 a.m
Distance covered in 2 hrs 15 min i.e., 2 1/4 hrs = 80 * 9/4 = 180 hrs.
Time taken to cover remaining distance = (350 - 180)/60 = 17/6 hrs
= 2 5/6 = 2 hrs 50 min
Total time taken = (2 hrs 15 min + 2 hrs 50 min) = 5 hrs 5 min.
So, Anna reached city A at 10.25 a.m.
Answer: A
Question: John and Karen begin running at opposite ends of a trail until they meet somewhere in between their starting points. They each run at their respective constant rates until John gets a cramp and stops. If Karen runs 50% faster than John, who is only able to cover 25% of the distance q before he stops, what percent longer would Karen have run than she would have had John been able to maintain his constant rate until they met.
Options:
A)25%
B)50%
C)75%
D)100%
E)200%
Rationale: John and Karen begin running at opposite ends of a trail until they meet somewhere in between their starting points. They each run at their respective constant rates until John gets a cramp and stops. If Karen runs 50% faster than John, who is only able to cover 25% of the distance q before he stops, what percent longer would Karen have run than she would have had John been able to maintain his constant rate until they met.
Lets say the distance of the trail is 100 miles. Lets also say that J rate = 10 miles/hour and K rate = 15 miles/hour.
If John stops at the 25% mark that means he travels 25 miles in 2.5 hours. It would take Karen t=d/r t=75/15 = 5 hours to reach john. If John had not stopped, their combined rate would 10+15 = 25 miles/hour meaning they would have met in 4 hours. Therefore, she ran one hour longer (25%) longer than she would have needed to if John ran for the entire time.
ANSWER: A) 25%
Answer: A
Question: A began business with Rs.45000 and was joined afterwards by B with Rs.5400. When did B join if the profits at the end of the year were divided in the ratio of 2:1?
Options:
A)5
B)6
C)7
D)9
E)3
Rationale: 45*12 : 54*x = 2: 1
x = 5
12 -5 = 7
Answer:C
Answer: C
Question: The equal amounts of money are deposited in two banks each at 15% per annum for 3.5 years and 10 years respectively. If the difference between their interests is Rs.144, find the each sum?
Options:
A)Rs.117.69
B)Rs.147.69
C)Rs.137.69
D)Rs.157.69
E)Rs.127.69
Rationale: (P*10*15)/100 - (P*3.5*15)/100 = 144
=> P = Rs.147.69
ANSWER:B
Answer: B
Question: A person's present age is two-fifth of the age of his mother. After 8years, he will be one - half of the age of his mother. How old is the mother at present ?
Options:
A)25
B)40
C)32
D)45
E)28
Rationale: Let the mother's present age be x years
Then the person's present age = 2x/5
(2x/5)+8 = 1/2(x+8)
2(2x+40) = 5 (x+8)
x = 40
Answer is B
Answer: B
Question: A group of men decided to do a work in 20days, but 2 of them became absent. If the rest of the group did the work in 22days, Find the original number of men?
Options:
A)15
B)22
C)27
D)29
E)18
Rationale: Original number of men = 2*22 / (22-20) = 22
Answer is B
Answer: B
Question: If the weight of 13 meters long rod is 23.4 kg. What is the weight of 6 meters long rod ?
Options:
A)7.2 kg.
B)10.8 kg.
C)12.4 kg.
D)18.0 kg
E)None
Rationale: Answer
∵Weight of 13 m long rod = 23.4 kg
∴ Weight of 1 m long rod = 23.4 / 13 kg
∴ Weight of 6 m long rod = 23.4 x 6 / 13
= 10.8 kg
Option: B
Answer: B
Question: The difference between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is:
Options:
A)1520 m2
B)2420 m2
C)2480 m2
D)2520 m2
E)None
Rationale: EXPLANATION
We have: (l – b) = 23 and 2(l + b) = 206 or (l + b) = 103.
Solving the two equations, we get: l = 63 and b = 40.
Area = (l x b) = (63 x 40) m2 = 2520 m2.
Answer D
Answer: D
Question: A boatman goes 2 km against the current of the stream in 1 hour and goes 1 km along the current in 10 minutes. How long will it take to go 5 km in stationary water?
Options:
A)40 minutes
B)1 hour
C)1 hr 15 min
D)1 hr 30 min
E)1 hr 40 min
Rationale: 2km in 1hr=2km/hr
1 km in 10 minutes means [1/10]*60=6km/hr
speed in still water is=1/2(6+2)=4km/hr
Required time=[5/4]hrs means 1hr 15 minutes
ANSWER:C
Answer: C
Question: John walked to the bus stop at a speed of 3 kph, but walked home at a speed of 6 kph. What was his average speed walking to and from the bus stop?
Options:
A)9 kph
B)3 kph
C)4.5 kph
D)6 kph
E)18 kph
Rationale: (3 kph + 6 kph)/2= 4.5 kph
Correct answer is C
Answer: C
Question: A word is defined as a sequence of four dots arranged in a row. Each dot is colored either yellow or blue. How many distinct words can be formed?
Options:
A)4
B)8
C)12
D)16
E)20
Rationale: 2^4 = 16
The answer is D.
Answer: D
Question: The ratio between the sale price and the cost price of an article is 7:5. What is the ratio between the profit and the cost price of that article?
Options:
A)2:8
B)2:1
C)2:2
D)2:4
E)2:5
Rationale: Explanation:
Let C.P. = Rs. 5x and S.P. = Rs. 7x.
Then, Gain = Rs. 2x
Required ratio = 2x : 5x = 2:5
Answer:E
Answer: E
Question: Find the probability if a two digit number multiplied by 3 but not 5
Options:
A)2/15
B)3/15
C)4/15
D)5/15
E)6/15
Rationale: sample space of 2 digit number = (99-10)+1 = 90
probability of number multiplied by 3 but not 5 = total no. multiplied by 3 - total no. multiplied by 5
= 30 - 6=24
so, probability= 24/90 = 4/15
ANSWER:C
Answer: C
Question: In Rwanda, the chance for rain on any given day is 1/2. What is the probability that it rains on 5 out of 8 consecutive days in Rwanda?
Options:
A)4/7
B)3/7
C)7/32
D)4/28
E)28/135
Rationale: using Binomial. theorem
nCr (p)^r (q)^n-r
8C5 (1/2)^5 (1/2)^r
which is 7/32
Answer is C.
Answer: C
Question: The pilot of a small aircraft with a 40-gallon fuel tank wants to fly to Cleveland, which is 480 miles away. The pilot recognizes that the current engine, which can fly only 10 miles per gallon, will not get him there. By how many miles per gallon must the aircraft’s fuel efficiency be improved to make the flight to Cleveland possible?
Options:
A)2
B)4
C)12
D)40
E)160
Rationale: Actual miles/gallon is = 480/40 = 12 miles/gallon.
Current engine miles/gallon is 10 miles/gallon.
Additional 2 miles/gallon is required to match the actual mileage.
IMO option A.
Answer: A
Question: Average of 5 numbers is zero. At most how many numbers may be greater than zero
Options:
A)0
B)4
C)5
D)9
E)10
Rationale: Answer: Option B
Answer: B
Question: A table is bought for Rs.400/- and sold at Rs.500/- find gain or loss percentage
Options:
A)25% gain
B)20% gain
C)20% loss
D)15% gain
E)None
Rationale: Formula = (Selling price ~ Cost price)/Cost price * 100
= (500 - 400)/400 = 25% gain
A
Answer: A
Question: A train is moving at a speed of 132 km/hr. If the length of the train is 150 meters, how long will it take to cross a railway platform 235 meters long
Options:
A)6 ½ sec
B)7 ½ sec
C)8 sec
D)10 ½ sec
E)9 sec
Rationale: Explanation:
Speed of train = 132 ×(5/18) m/sec = 110/3 m/sec.
Distance covered in passing the platform = (150 + 235) m = 385 m.
Time taken =385 ×(3/110) sec =21/2 sec = 710½ sec
Answer: Option D
Answer: D
Question: If x is a sum of all even integers on the interval 13...65 and y is their number, what is the GCD (x, y)?
Options:
A)1
B)13
C)26
D)52
E)1014
Rationale: x = 14 + 16 + ... + 64 = (largest + smallest)/2 *(# of terms) = (14 + 64)/2*26 = 39*26.
GCD of 26 and 39*26 is 26.
Answer: C.
Answer: C
Question: How many pages the book have, if total 300 digits are used to form the page numbers?
Options:
A)135 pages
B)136 pages
C)137 pages
D)138 pages
E)139 pages
Rationale: First 9 pages .. 9 digits
next 90 pages .. 180 digits
next 37 pages ... 111 digits
----------------------
Total ...136 pages ...300 digits
ANSWER:B
Answer: B
Question: The sum of two numbers is 16. The difference is 4. What are the two numbers?
Options:
A)10-6
B)8-8
C)9-7
D)11-5
E)13-3
Rationale: Let x be the first number. Ley y be the second number
x + y = 16
x - y = 4
Solve the system of equations by elimination
Adding the left sides and the right sides gives:
x + x + y + -y = 16 + 4
2x = 20
x = 10
Since x + y = 16, 10 + y = 16
10 + y = 16
10 - 10 + y = 16 - 10
y = 6
The numbers are 10 and 6
correct answer is A)10-6
Answer: A
Question: How many four digit even numbers can be formed using the digits {2, 3, 5, 1, 7, 9}
Options:
A)76
B)88
C)77
D)67
E)60
Rationale: The given digits are 1, 2, 3, 5, 7, 9
A number is even when its units digit is even. Of the given digits, two is the only even digit.
Units place is filled with only '2' and the remaining three places can be filled in ⁵P₃ ways.
Number of even numbers = ⁵P₃ = 60.
Answer:E
Answer: E
Question: For the sequence a1, a2, a3. ..an, an is defined by an=1/2n−1−1/2n for each integer n≥1. What is the sum of the first 8 terms of the sequence?
Options:
A)63/64
B)127/128
C)255/256
D)511/512
E)513/512
Rationale: a1=1/2^0−1/2^1
a2=1/2^1−1/2^2....
a8=1/2^7−1/2^8
a1+a2+...+a8=1/2^0−1/2^8=255/256
The answer is C.
Answer: C
Question: A can do a piece of work in 15 days and B alone can do it in 10 days. B works at it for 5 days and then leaves. A alone can finish the remaining work in
Options:
A)5 days
B)6 days
C)7.5 days
D)8.5 days
E)8 days
Rationale: Explanation:
B's 5 days work = 1/10*5=1/2
Remaining work =1âˆ’1/2=1/2
A can finish work =15âˆ—1/2=7.5days
ANSWER IS C
Answer: C
Question: A trader mixes 26 kg of rice at Rs. 20 per kg with 30 kg of rice of other variety at Rs. 36 per kg and sells the mixture at Rs. 30 per kg. His profit percent is:
Options:
A)No profit, no loss
B)5%
C)8%
D)10%
E)12%
Rationale: Explanation:
C.P. of 56 kg rice = Rs. (26 x 20 + 30 x 36) = Rs. (520 + 1080) = Rs. 1600.
S.P. of 56 kg rice = Rs. (56 x 30) = Rs. 1680.
Gain =(80/1600 x 100\ )% = 5%. Answer: B
Answer: B
Question: Excluding stoppages,the speed of the bus is 54kmph and
including stoppages,it is 9kmph. For how many minutes does the bus stop per hr
Options:
A)12 min
B)11 min
C)13 min
D)20 min
E)50 min
Rationale: Due to stoppages,it covers 45km less.
time taken to cover 45 km is [45/54 *60] min = 50min
Answer is E.
Answer: E
Question: I have only 1$ and 2$ note. I want to give 95$ to John. How many maximum number of 1$ note I need?
Options:
A)53
B)35
C)47
D)95
E)62
Rationale: To give 95$ we need of 95 1$ notes
so ans is D
Answer: D
Question: Given that there are 11 cricket players per team, how many ways can you select 10 cricket players from 2 teams if no more than 3 players can be selected from each team?
Options:
A)24563
B)45784
C)14525
D)35658
E)27225
Rationale: Now from each group we have to select 5 persons only: 11C3 * 11C3= 165 * 165= 27225
Total ways=27225 ways.
Answer E
Answer: E
Question: There are 100 students in a certain geometry class. If one half of the students are boys and one fifth of the boys are under six feet tall, how many boys in the class are under six feet tall?
Options:
A)6
B)10
C)18
D)24
E)27
Rationale: Total Students = 100
One half of the students are boys = 1/2*100 = 50
One fifth of the boys are under six feet tall = 1/5*50 = 10 ...
Therefore Number of boys in the class under six feet tall = 10 ... Answer B....
Alternatively... Number of boys in the class under six feet tall = 1/5 of 1/2 of Total Students = 1/5*1/2*100 = 10...
Answer B
Answer: B
Question: A company has 600 employees, 40% of whom are employed full time. If it hires 80 new employees, 15% of whom are employed part time, what will be the percent increase in part time employees?
Options:
A)1 2/3 %
B)2 2/3 %
C)4 %
D)3.33 %
E)9 %
Rationale: Total employee = 600
Full time Empl = 600 * 40/100 =240
Part time Emp = 600 - 240 = 360
New part time empl = 80 * (15/100)
=12
Total new part time Emp = 12+360= 372
Old part time Emp = 360
% increase = (new - old)*100/old
=12*100/360
= 3.33 %
Ans-D
Answer: D
Question: Four friends are pooling their money for pizza. Emma has 8 dollars. Daya has 25% more money than Emma, Jeff has 2/5 of the money Daya has, and Brenda has 4 more dollars than Jeff. How much money does Brenda have?
Options:
A)14
B)6
C)7
D)8
E)10
Rationale: D
8
Emma has 8 dollars.
Daya has 25% more dollars than Emma.
Daya= 8 + 8 x 25%
= 8 + 8 x .25
=8 + 2
=10
Jeff has 2/5 of what Daya has.
= 10 x 2/5
= 4
Brenda has 4 more dollars than Jeff.
= 4 + 4
=8
Brenda has 8 dollars.
The correct answer is D.
Answer: D
Question: If a sample of data has mean of 20 and SD of 3, which of the following values is more than 2.7 SDs from the mean?
Options:
A)12.5
B)13
C)14
D)11.8
E)15
Rationale: 2.7 SD's mean is equal to: +/- 2.7*3 = +/- 8.1
ie. 11.9 to 28.1
Answer is: D
Answer: D
Question: In a flower shop there were 8 flowers in each bouquet. If the seller has doubled the number of flowers in each bouquet then the new average of flowers in each bouque is
Options:
A)12
B)16
C)8
D)9
E)None of these
Rationale: Answer
Now required average
= old average x Multiplicand
= 8 x 2 = 16
Correct Option: B
Answer: B
Question: If n is the greatest positive integer for which 2^n is a factor of 6!, then n =?
Options:
A)2
B)4
C)6
D)8
E)10
Rationale: 6! = 720
E. 2^10 = 512 (720/512) - this is not a factor of 6!
D. 2^8 = 256 (720/256) - this is not a factor of 6!
C. 2^6 = 64 (720/64) - this is not a factor of 6!
B. 2^4 = 16 (720/16) - this is a factor of 6!
B is answer
Answer: B
Question: For any numbers w and z, w#z = w^3z(8 - w^2). If both z and w#z are positive numbers, which of the following could be a value of w?
Options:
A)9
B)3
C)0
D)−2
E)−9
Rationale: Since w#Z and w are positive, we need to take the value of w such that w#z or w^3z(8 - w^2) is positive.
ANSWER:E
Answer: E
Question: Fresh fruit contains 55% water and dry fruit contains 10% water. How much dry fruit can be obtained from 100kg of fresh fruit?
Options:
A)A)32kg
B)B)40kg
C)C)52kg
D)D)50kg
E)E)100kg
Rationale: Quantity of pulp in 100kg of fresh fruits = (100-55)% of 100kg = 45kg
Let the quantity of dry fruit obtained be x kg
then, (100-10)% of x = 45
(90/100)*x = 45
x = 50
correct option is D
Answer: D
Question: Two trains 111 meters and 165 meters in length respectively are running in opposite directions, one at the rate of 80 km and the other at the rate of 65 kmph. In what time will they be completely clear of each other from the moment they meet?
Options:
A)4.85
B)7.85
C)6.85
D)5.85
E)6.15
Rationale: T = (111 + 165)/ (80 + 65) * 18/5
T = 6.85
ANSWER:C
Answer: C
Question: A train covers a distance of 12 km in 10 min. If it takes 6 sec to pass a telegraph post, then the length of the train is?
Options:
A)288
B)266
C)120
D)287
E)212
Rationale: Speed = (12/10 * 60) km/hr = (72 * 5/18) m/sec = 20 m/sec.
Length of the train = 20 * 6 = 120 m.
Answer: C
Answer: C
Question: Gate A runs 3000 liters of water per minute out of a check dam that has a total volume of 360000 liters. Gate B drains a third of the dam in 6 hours.
Working together how long will it take both gates to drain the dam completely ?
Options:
A)2 hours and 36 minutes
B)1.5 hours
C)9 hours and 12 minutes
D)15 hours
E)1 hour and 28 minutes.
Rationale: Gate A has a rate of 300 liters per minute which equals a rate of 18,000 liters per hour.
Pipe B has a rate of 10,000 liters per hour.
10,000 + 18000 (A+B) = Together they have a rate of 28000 liters per hour.
36000 (The dam ) / 28000 = 36/28 = 1 Hour and 28 minutes
Answer -E
Answer: E
Question: How many real roots does the equation x^2y+16xy+60y=0 have if y < 0?
Options:
A)0
B)1
C)2
D)3
E)Infinite
Rationale: x^2y+16xy+60y=0
=> y ( x^2 + 16x + 60) = 0
=> y (x+8)^2 = 0
if y<0 , then x=-9
So although there are 2 factors , they are the same x=-9 .
The equations has 3 distinct real root .
Answer D
Answer: D
Question: A container contains a dry mixture of sand and stones. Mass of sand and stones in the container is in the ratio 1:3. If 12 kg sand is added to the container, the ratio of masses of sand and stones becomes 5:3. Originally, how much more was the mass of stones than sand in the container?
Options:
A)12
B)9
C)6
D)3
E)1
Rationale: Suppose originally the mass of sand in the container was x. So the mass of stones, originally, would be 3x because mass of sand and stones in the container is in the ratio 1:3.
If 12 kg sand is added, mass of sand becomes x + 12, and the mass of stones remains unchanged. But now the ratio of the mass of sand and stones is 5:3.
This means,
(x + 12)/3x = 5/3, which gives x = 3.
So originally, there was 3 kg sand and 9 kg stones.
So, the mass of stones was 6 kg more than the mass of sand.
Ans C
Answer: C
Question: In how many different number of ways 4 men and 2 women can sit on a shopa which can accommodate persons?
Options:
A)17
B)18
C)20
D)21
E)30
Rationale: 6p2 = 6 x 5 = 30
Answer : E
Answer: E
Question: A and B walk around a circular track. A and B walk at a speed of 2 rounds per hour and 3 rounds per hour respectively. If they start at 8 a.m. from the same point in opposite directions, how many times shall they cross each other before 10.30 a.m.?
Options:
A)5
B)6
C)7
D)8
E)12
Rationale: Relative speed = Speed of A + Speed of B (? they walk in opposite directions)
= 2 + 3 = 5 rounds per hour
=> They cross each other 5 times in 1 hour and 2 times in 1/2 hour
Time duration from 8 am to 10.30 am = 2.5 hour
Hence they cross each other 12 times before 10.30 am
Answer is E
Answer: E
Question: A person borrows Rs.5000 for 2 years at 5% p.a. simple interest. He immediately lends it to another person at 61⁄4% p.a for 2 years. Find his gain in the transaction per year.
Options:
A)62.5
B)150
C)225
D)112.5
E)212.5
Rationale: Explanation :
The person borrows Rs. 5000 for 2 years at 5% p.a. simple interest
Simple interest that he needs to pay = PRT/100=5000×5×2/100=500
He also lends it at 6 1⁄4% p.a for 2 years
Simple interest that he gets = PRT/100=5000×25/4×2/100=625
His overall gain in 2 years = Rs.625 - Rs.500 = Rs.125
His overall gain in 1 year = 125/2 = Rs.62.5
Answer : Option A
Answer: A
Question: A group of college friends plan to rent a house together for x dollars per month, which is to be shared equally among them. If four, rather than five people rent the house together, how many more dollars, in terms of x, will each person have to pay for rent per month?
Options:
A)x/4
B)x/5
C)x/9
D)x/20
E)4x/9
Rationale: If 5 people share the rent, each person would pay x/5.
If 4 people share the rent, each person will pay x/4.
The extra amount each person pays is x/4 - x/5 = 5x/20 - 4x/20 = x/20
The answer is D.
Answer: D
Question: 81,162,49,98,25,50,68
Options:
A)126
B)127
C)129
D)128
E)136
Rationale: 81*2=162
49*2=98
25*2=50
68*2=136
ANSWER:E
Answer: E
Question: The bankerâ€™s discount on Rs. 1600 at 8% per annum is the same as true discount on Rs. 1680 for the same time and at the same rate. The time is :
Options:
A)2 months
B)4.5 months
C)6.5 months
D)7.5 months
E)None
Rationale: Sol.
S.I. on Rs. 1600 = R.D. on Rs. 1680.
âˆ´ Rs. 1600 is the P.W. of Rs. 1680, i.e., Rs. 80 is S.I. on Rs. 1600 at 8%.
âˆ´ Time = [100 * 80 / 1600 * 8] year = 5/8 year = 7.5 months.
Answer D
Answer: D
Question: A man spends 10% of his income in house rent, 20% of the rest on his children’s education, 25% of the rest miscellaneous causes. If he now posses Rs. 1944 then his income is?
Options:
A)Rs.3600
B)Rs.3607
C)Rs.3627
D)Rs.3661
E)Rs.3628
Rationale: X * (90/100) * (80/100) * (75/100) = 1944
X * 0.9 * 0.8 * 0.75
X = 1944/0.54
X = 3600
Answer:A
Answer: A
Question: At what time between 5.30 and 6 will the hands of a clock be at right angles?
Options:
A)43*8/11 min past 5
B)42*7/11 min past 5
C)43*7/11 min past 5
D)43*7/11 min past 7
E)44*7/11 min past 5
Rationale: Explanation:
At 5 o'clock, the hands are 25 min. spaces apart.
To be at right angles and that too between 5.30 and 6, the minute hand has to gain (25 + 15) = 40 min. spaces.
55 min. spaces are gained in 60 min.
40 min. spaces are gained in 60/55 * 40 min= 43*7/11 min
Required time 43*7/11 min past 5
Answer is C
Answer: C
Question: there are 30 students in a classroom. The ratio of the # of girls to boys was 1:2, how many boys are there?
Options:
A)10
B)15
C)20
D)25
E)30
Rationale: # OF GIRLS = X
# OF BOYS =2X
X + 2X = 30
3X = 30
X = 30/3 = 10
BOYS = 2X = 2 * 10 =20
ANSWER: C
Answer: C
Question: The length of a room is 5.5 m and width is 3.75 m. What is the cost of paying the floor by slabs at the rate of Rs.800 per sq. metre.
Options:
A)Rs. 12000
B)Rs. 19500
C)Rs. 18000
D)Rs. 16500
E)Rs. 18090
Rationale: Area =5.5×3.75 sq. metre.
Cost for 1 sq. metre. = Rs.800
Hence, total cost=5.5×3.75×800=5.5×3000
= Rs.16500 Answer: Option D
Answer: D
Question: When ticket sales began, Pat was the nth customer in line for a ticket, and customers purchased their tickets at the rate of r customers per minute. Of the following, which best approximates the time, in minutes, that Pat had to wait in line from the moment ticket sales began?
Options:
A)(n - 1) r
B)(n-1)/r
C)n + r –1
D)r/(n-1)
E)n/(r-1)
Rationale: B. (n - 1) / r
Answer: B
Question: Set P is composed of nine numbers, labeled P1 through P9. Set Q is also composed of nine numbers, labeled Q1 through Q9. Set Q is defined as follows: Q1 = 1 + P1; Q2 = 2 + P2; and so on, including Q9 = 9 + P9. How much larger is the sum of set Q's mean and range than the sum of set P's mean and range?
Options:
A)3
B)6
C)9
D)cannot be determined
E)12
Rationale: Yes, the correct answer is D
Answer: D
Question: From a pack of cards, two cards are drawn one after the other, with replacement. What is the probability that the first card is a club and the second card is a red king?
Options:
A)1/13
B)1/15
C)1/26
D)1/52
E)1/104
Rationale: P(club) = 1/4
P(red king) = 1/26
P(club then a red king) = 1/4 * 1/26 = 1/104
The answer is E.
Answer: E
Question: The average age of 8 men increases by 2 years when two women are included in place of two men of ages 20 and 24 years. Find the average age of the women?
Options:
A)39
B)27
C)30
D)26
E)29
Rationale: 20 + 24 + 8 * 2 = 60/2 = 30
Answer: C
Answer: C