divelab/Sys2Bench huggingface dataset:
Question: In a certain population, there are 3 times as many people aged twenty or under as there are people over twenty. The ratio of those twenty or under to the total population is
Options:
A) 1 to 2
B) 3 to 4
C) 1 to 4
D) 2 to 3
E) 3 to 5
Rationale: Consider the ratio of the under population of 20 to over the 20 as 3:1
therefore 3x:1X
Now the ratio of the under to the whole population becomes 3x/3x+1x
= 3/4
Answer is B
Answer: B
Question: A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If three marbles are drawn what is the probability that one is yellow and two are red?
Options:
A)12/429
B)12/429
C)12/455
D)12/419
E)12/492
Rationale: Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles.
When three marbles are drawn, the probability that one is yellow and two are red
= (²C₁)(⁴C₂)/¹⁵C₃
= (2 * 4 * 3 * 3 * 2)/(1 * 2 * 15 * 14 * 13)
= 12/455
Answer: C
Answer: C
Question: A manufacturer sells a pair of glasses to a wholesale dealer at a profit of 18%. The wholesaler sells the same to retailer at a profit of 20%. The retailer in turn sells them to a customer for Rs. 30.09, there by earning a profit of 25%. The cost price for the manufacturer is?
Options:
A)19
B)10
C)17
D)18
E)12
Rationale: Let the cost price for the manufacturer be Rs. x. Then, 125% of 120% of 118% of x
= 30.09.
125/100 * 120/100 * 118/100 * x
= 3009/100
177/100 x = 3009/100 => x = 17
Answer:C
Answer: C
Question: The average age of 19 boys and the class teacher is 16 years. If the ages of the class teacher and one of the boys are excluded, the average age reduces to 15 years. What is the age of the class teacher ?
Options:
A)767
B)26
C)50
D)88
E)21
Rationale: No. of Persons = 19 boys + 1 class teacher = 20
Average age of 20 people is 16 years.
Therefore, total age of 20 persons = 20 * 16 = 320 years ------ (A)
If the class teacher and one boy are excluded, then the average age is 15 years.
Therefore, total age of 18 boys = 18 * 15 = 270 years ------ (B)
Age of the class teacher and one boy = 320 – 270 = 50 years.
Data is inadequate as the relation between the ages of the boy and the teacher is not provided.
ANSWER: Data Inadequate
Explanation: C
Answer: C
Question: Ramesh can finish a piece of work in 22 days. Rohan is twice as efficient as Ramesh. If they work together how many days will they need to finish the same amount of work?
Options:
A)22/3 days
B)9/3 days
C)10/3 days
D)11/3 days
E)7/3 days
Rationale: Ramesh can finish a piece of work in 22 days. Rohan is twice as efficient as Ramesh.
So Rohan can finish a piece of work in 11 days.
days needed to finish the same amount of work = 1/(1/11+1/22)=22/3 days
ANSWER:A
Answer: A
Question: The average age of 19 students in a group is 17 years. When teacher’s age is included to it, the average increases by one. What is the teacher’s age in years?
Options:
A)36
B)37
C)38
D)cannot be determined
E)None of these
Rationale: Age of the teacher = (20 × 18 – 19 × 17) years
= 37 years.
Answer B
Answer: B
Question: The banker's gain on a bill due due 1 year hence at 12% per annum is Rs.6. The true discount is
Options:
A)Rs.72
B)Rs.36
C)Rs.54
D)Rs.50
E)none
Rationale: Solution
T.D	= [B.G x 100 / R x T]
= Rs.(6 x 100 / 12 x 1)
= Rs.50.
Answer D
Answer: D
Question: A group of 6 fishermen chartered a boat for a day to fish for flounder. The boat costs x dollars per day to rent. If the group can find 3 more fishermen on the docks who are willing to come aboard and share the rental costs, how much less will the rental cost be per person in terms of x?
Options:
A)x/18
B)x/35
C)3x/70
D)3x/10
E)3x/7
Rationale: cost of boat per day = x
cost per person =x/6
if three more persons afre there, cost =x/9
difference = x/6-x/9
=x/18
Ans A
Answer: A
Question: A scale 6 ft. 8 inches long is divided into 5 equal parts. Find the length of each part.
Options:
A)20 inches
B)77 inches
C)16 inches
D)97 inches
E)66 inches
Rationale: Explanation:
Total length of scale in inches = (6*12) + 8 = 80 inches
Length of each of the 5 parts = 80/5 = 16 inches
ANSWER:C
Answer: C
Question: The average age of a group of 10 students was 20. The average age increased by 4 years when two new students joined the group. What is the average age of the two new students who joined the group?
Options:
A)22 years
B)30 years
C)34 years
D)44 years
E)None of these
Rationale: The total age of 10 students with average 20 = 200
The total age of 12 students with average 24 = 288
The total age of 2 new students = 88
Their average =44
Correct Option D
Answer: D
Question: A is twice as good a workman as B and together they finish a piece of work in 18 days. In how many days will A alone finish the work?
Options:
A)31 days
B)25 days
C)27 days
D)29 days
E)19 days
Rationale: If A takes x days to do a work then B takes 2x days to do the same work.
--> 1/x+1/2x = 1/18
--> 3/2x = 1/18
--> x = 27 days.
Hence, A alone can finish the work in 27 days.
Answer : C.
Answer: C
Question: One card is drawn from a pack of 52 cards. What is the probability that the card drawn is either a red card or a king?
Options:
A)2/5
B)3/13
C)4/19
D)7/13
E)6/19
Rationale: Out of 52 cards there will be 26 red cards including 2 kings and 2 more kings. Total 28
probability= 28/52 = 7/13
Answer is D
Answer: D
Question: A tradesman by means of his false balance defrauds to the extent of 20%? in buying goods as well as by selling the goods. What percent does he gain on his outlay?
Options:
A)46%
B)48%
C)44%
D)49%
E)42%
Rationale: g% = 20 + 20 + (20*20)/100
= 44%
Answer: C
Answer: C
Question: Company C sells a line of 20 products with an average retail price of $1,200. If none of these products sells for less than $400, and exactly 10 of the products sell for less than $1,000, what is the greatest possible selling price of the most expensive product?
Options:
A)12000
B)11000
C)10000
D)13000
E)15000
Rationale: The average price of 20 products is $1,200 means that the total price of 20 products is 20*1,200=$24,000.
Next, since exactly 10 of the products sell for less than $1,000, then let's make these 10 items to be at $400 each (min possible).
Now, the remaining 9 items cannot be priced less than $1,000, thus the minimum possible price of each of these 9 items is $1,000.
Thus the minimum possible value of 19 products is 10*400+9*1,000=$13,000.
Therefore, the greatest possible selling price of the most expensive product is $24,000-$13,000=$11,000.
Answer: B.
Answer: B
Question: Find the odd man out. 7, 14, 21, 28, 35, 50, 56
Options:
A)50
B)25
C)51
D)90
E)115
Rationale: Explanation :
All except 50 are multiples of 7
Answer : Option A
Answer: A
Question: A and B started a business in partnership investing Rs.20,000 and Rs.15,000 respectively. After six months, C joined them with Rs.20,000. What will be B's share in the total profit of Rs.25,000 earned at the end of 2 years from the starting of the business?
Options:
A)Rs.7500
B)Rs.9000
C)Rs.9500
D)Rs.10,000
E)None
Rationale: Solution
A : B : C	=(20000×24):(15000×24):(20000×18)
=4 :3 :3
B's share	=Rs.(25000×3/10)
= Rs.7500.
Answer A
Answer: A
Question: How much more would Rs.20000 fetch, after two years, if it is put at 20% p.a. compound interest payable half yearly than if is put at 20% p.a. compound interest payable yearly?
Options:
A)A)Rs.6,602.50
B)B)Rs.6,601.50
C)C)Rs.6,603.50
D)D)Rs.6,604.50
E)E)Rs.6,605.50
Rationale: 20000(11/10)4 - 20000(6/5)2 = 6,602.50
ANSWER:A
Answer: A
Question: How many iron rods, each of length 7 m and diameter 2 cm can be made out of 0.88 cubic meter of iron?
Options:
A)150
B)100
C)250
D)200
E)400
Rationale: Volume of 1 rod = (( 22/7) x (1/100) x (1/100) x 7 ) cu.m = 11/5000 cu.m
Volume of iron = 0.88 cu. m.
Number of rods = (0.88 x 5000/11) = 400.
Answer is E
Answer: E
Question: Jayant opened a shop investing Rs. 30,000. Madhu joined him 2 months later, investing Rs. 45,000. They earned a profit of Rs. 56,000 after completion of one year. What will be Madhu's share of profit?
Options:
A)Rs. 28,000
B)Rs. 24,000
C)Rs. 30,000
D)Rs. 36,000
E)None of these
Rationale: 30,000 *12=45,000*8
1:1
Madhu's share=1/2*56,000
i.e. Rs. 28,000
ANSWER:A
Answer: A
Question: A computer manufacturer produces a certain electronic component at a cost of $80 per component. Shipping costs for delivering the components are $2 per unit. Further, the manufacturer has costs of $16,200 a month related to the electronic component regardless of how many it produces. If the manufacturer produces and sells 150 components a month, what is the lowest price it can sell them for such that the costs don't exceed the revenues?
Options:
A)$28
B)$82
C)$110
D)$190
E)$192
Rationale: This question can be solved easily using a equation model.
150*p = 16200(fixed cost) + 150*80+150*2.
= 16200+ 12000+300
= 28500
P= $190.
D
Answer: D
Question: Carl is facing very difficult financial times and can only pay the interest on a $10,000 loan he has taken. The bank charges him a quarterly compound rate of 8%. What is the approximate interest he pays annually?
Options:
A)1500
B)1750
C)2000
D)3500
E)2500
Rationale: An easy way too attempt this is by approximation:
For the first quarter, he pays 8% of 10,000 which is $800.
So for the four quarters in the year, he will approximately play 800*4=3200 over the entire year.
Because of compound interest it will be more than 3200. Approx. option D is correct.
Answer :D
Answer: D
Question: In Jeevans opinion, his weight is greater than 65 kg but less than 72 kg. His brother does not agree with Jeevan and he thinks that Jeevans weight is greater than 60 kg but less than 70 kg. His mothers view is that his weight cannot be greater than 68 kg. If all of them are correct in their estimation, what is the average of different probable weights of Jeevan?
Options:
A)67 kg
B)68 kg
C)69 kg
D)None of these
E)Cannot be determined
Rationale: Explanation :
Let Jeevans weight be X kg.
According to Jeevan, 65 < X < 72.
According to Jeevan's brother, 60 < X < 70.
According to Jeevan's Mother, X <= 68
The Values satisfying all the above conditions are 66, 67 and 68 .
Required average = (66 + 67+68)/3 = 201/3 = 67 kg.
Answer : A
Answer: A
Question: The interest on Rs. 750 for 2 years is the same as the true discount on Rs. 960 due 2 years hence. If the rate of interest is the same in both cases, it is:
Options:
A)12%
B)13%
C)14%
D)15%
E)18%
Rationale: S.I. on Rs. 750 = T.D. on Rs. 960.
This means P.W. of Rs. 960 due 2 years hence is Rs. 750.
T.D. = Rs. (960 - 750) = Rs. 210.
Thus, S.I. on R.s 750 for 2 years is Rs. 210.
Rate =(100 x 210)/(750 x 2)%	= 14% ANSWER : C
Answer: C
Question: How many 0's are there in the binary form of 6*1024 + 4*64 + 2
Options:
A)6
B)7
C)8
D)10
E)9
Rationale: 6*1024 + 4*64 + 2 = 6144+256 +2 = 6402
in binary code
6402 base 10 = 11001 000000 10 in base 2.
so 9 zeros are there.
ANSWER:E
Answer: E
Question: Jerome anticipated that the WebWeb.com stock price would fall and sold all his WebWeb.com stocks for $5 per stock. He paid $10,000 tax on the revenue. A week later, Jerome became convinced that the WebWeb.com stock price would rise, and he used the money that he had gotten from selling the WebWeb.com stocks to purchase them again, this time at $6 per stock. If Jerome ended up having 5000 WebWeb.com stocks fewer than the number he had before selling them, how many WebWeb.com stocks did he have originally?
Options:
A)10,000
B)11,600
C)12,000
D)15,000
E)16,400
Rationale: Let the number of shares be x.
5*x -10000(money paid in taxes) = 6(x- 5000)
Solving for x, we get the shares as 15000.
Ans :(Option D)
Answer: D
Question: A train 125 m long passes a man, running at 4 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
Options:
A)49 kmph
B)50 kmph
C)51 kmph
D)52 kmph
E)53 kmph
Rationale: Explanation:
Speed of the train relative to man
= (125/10) m/sec = (25/2) m/sec.
[(25/2) x (18/5)] km/hr = 45 km/hr.
Let the speed of the train be 'x' km/hr.
Then, relative speed = (x - 4) km/hr.
x - 4 = 45 => x = 49 km/hr.
ANSWER IS A
Answer: A
Question: If a is an integer and (a^2)/(12^3) is odd, which of the following must be an odd integer?
Options:
A)a/4
B)a/12
C)a/27
D)a/36
E)a/72
Rationale: we can rewrite: a^2 / 2^6 x 3^3
so a^2 must be at least 2^6*3^4
or a is at least 2^3 * 3^2
A. if we divide by 4, or 2^2, we still have a factor of 2 left out, which will make an even integer..so no
B. if we divide by 12 (3x2^2), we are still left with a factor of 2- so no
C. 27=3^3. it might be even a non-integer, so no. moreover, we are left with 2^3 ..which will make the number even.
D. 36 = 2^2 * 3^2. still we have at least one factor of 2, so no.
E. by poe, E is left..72=2^3 * 3^2. since we know that a is at least this number (other variations would include another odd factor)..then dividing it by this will always yield an odd integer.
ANSWER:E
Answer: E
Question: Rs.800 amounts to Rs.920 in 3 years at simple interest. If the interest is increased by 3%, it would amount to how much?
Options:
A)3387
B)277
C)223
D)992
E)213
Rationale: (800*3*3)/100 = 72
920 + 72 = 992
Answer: D
Answer: D
Question: If the diameter of circle R is 50% of the diameter of circle S, the area of circle R is what percent of the area of circle S?
Options:
A)35%
B)25%
C)20%
D)15%
E)10%
Rationale: Let diameter of circle R , dr = 50
and diameter of circle S , ds = 100
Radius of circle R , Rr = 25
Radius of circle S , Rs = 50
Area of circle R/ Area of circle S = (pi * Rr ^2 ) /( pi * Rs^2 )
= (25/50)^2 = (5/10)^2
=25%
Answer :B
Answer: B
Question: A survey of n people in the town of Eros found that 50% of them preferred Brand A. Another surveyof 100 people in the town of Angie found that 60% preferred Brand A. In total, 55% of all the people surveyed together preferred Brand A. What is the total number of people surveyed?
Options:
A)50
B)100
C)150
D)200
E)250
Rationale: 50% of n people from Eros prefer brand A.
50% of n is 50/100 x n = n/2.
60% of 100 people from Angie prefer brand A.
60% of 100 is 60/100 x 100 = 60.
Of the total n+ 100 people surveyed, n/2 + 60 prefer brand A.
Given that this is 55%,
we have
(n/2+60)/(n+100) x100 =55
Solving the equation
(n/2+60)/(n+100) x100= 55
(n/2+60) = 55/100x(n+100)
(n/2+60) = 11/20n+55
0 = 11n /20 –n/2+55-60
Now subtracting n/2 and 60 from both sides
0=n/20-5
Adding 5 on both sides
5=n/20
n=100
Hence, the total number of people surveyed is
n+ 100 = 100 + 100
= 200.
ANSWER:D
Answer: D
Question: In a certain Parallelogram the degree measure of one angle exceeds that of the other by 20 what is the degree measure of the smaller angle?
Options:
A)75
B)80
C)85
D)90
E)95
Rationale: In a parallelogram opposite angles are equal and the angles at each side are supplementary to each other (supplementary angles are two angles that add up to 180°).
Given: x+(x+20)=180 --> x=80.
Answer: B.
Answer: B
Question: In the third grade of Windblown School there are 96 students, one third of them failed the math test and 1/6 failed that literature test. At least how many students failed both tests?
Options:
A)0.
B)6.
C)8.
D)10.
E)12.
Rationale: Total = 96
failed in math = 96/3=32
failed in literature=108/6=16
the least failed in both can be 0
while max can be 16
Answer A
Answer: A
Question: The fourth proportional to 12, 14 and 18 is?
Options:
A)21
B)66
C)55
D)88
E)61
Rationale: (14*18)/12
= 21
Answer:A
Answer: A
Question: A pupil's marks were wrongly entered as 73 instead of 63. Due to the average marks for the class got increased by half. The number of pupils in the class is?
Options:
A)18
B)82
C)20
D)27
E)29
Rationale: Let there be x pupils in the class.
Total increase in marks
= (x * 1/2) = x/2
x/2 = (73 - 63) => x/2
= 10 => x = 20.
Answer: C
Answer: C
Question: A box measuring 72 inches long by 48 inches wide by 24 inches deep is to be filled entirely with identical cubes. No space is to be left unfilled. What is the smallest number of cubes that can accomplish this objective?
Options:
A)17
B)18
C)54
D)108
E)162
Rationale: least number of cubes will be required when the cubes that could fit in are biggest.
8 is the biggest number that could divide all three, 72, 48 and 24.
Thus side of cube must be 8, and total number of cubes = 72/8 * 48/8*24/8 = 162
Ans E it is.
Answer: E
Question: Given that G and H are events such that
Q(G)= 0.30
Q(H)=0.9
Q(GnH)=0.9
find Q (G|H) and Q(G|H)
Options:
A)1/5
B)1/6
C)1/3
D)1/6
E)1/3
Rationale: Here, G and H are events
Q(G|H) = Q(GnH)/Q(H) = 0.9/0.9= 1
Q(G|H) = Q(GnH)/Q(G) = 0.9/0.30 = 1/3
Answer is C
Answer: C
Question: How many 2 digits number are there which when subtracted from the number formed by reversing its digits as well as when added to the number formed by reversing its digit, result is a perfect square.
Options:
A)63
B)64
C)65
D)66
E)67
Rationale: If xy is number, then 11(x+y) and 9*(x-y) should be perfect square.
which is possible when
x+y=11 and x-y = 1,4,9
value of x,y is valid only when x-y=1, then x=6,y=5
so number is 65.
ANSWER:C
Answer: C
Question: How many pieces can a square pizza be cut into by making 6 linear cuts?
Options:
A)20
B)21
C)22
D)23
E)24
Rationale: 1 cut makes 2 pieces
a second cut can make 4 pieces by cutting through both pieces
a third cut can make 7 pieces by cutting through 3 of the pieces
a fourth cut can make 11 pieces by cutting through 4 of the pieces
a fifth cut can make 16 pieces by cutting through 5 of the pieces
a sixth cut can make 22 pieces by cutting through 6 of the pieces
C
Answer: C
Question: What is the greatest prime factor of 4^16 - 2^28?
Options:
A)2
B)3
C)5
D)7
E)11
Rationale: I'm happy to help with this.
We know 4 = 2^2, so 4^17 = (2^2)^17 = 2^(2*16) = 2^32
That takes advantage of a law of exponents that says (a^n)^m = a^(n*m)
So, 4^16 - 2^28 = 2^32 - 2^28 = 2^(28 + 4) - 2^28 = (2^28)*(2*4) - 2^28 = (2^4 - 1) *(2^28)
= (16 - 1)*(2^28) = 15*(2^28)
The prime factors of 63 are 3*5, so the largest prime factor is 7, answer choice D.
Here's a blog you may find helpful.
http://magoosh.com/gmat/2012/gmat-math-factors/
Does all that make sense? Please let me know if you have any further questions.
Mike
Wow. I am floored by how great of an explanation you provided. Posts like that make me really think that doing thousands of practice problems with good explanations beats out reading books on math every day of the week.
C
Answer: C
Question: A bat is bought for Rs.400 and sold at a gain of 30% find its selling price?
Options:
A)s.460/-
B)s.480/-
C)s.500/-
D)s.520/-
E)s.540/-
Rationale: 100 % ------> 400 (100 * 4 = 400)
130 % ------> 520 (130 * 4 = 520)
Selling price = Rs.520/-
Option 'D'
Answer: D
Question: In a division, a student took 87 as divisor instead of 36. his answer was 24 . The correct answer is-
Options:
A)42
B)32
C)48
D)28
E)58
Rationale: X/87 = 24.
X = 24 *87.
So correct answer would be,
(24 *87) /36 = 58.
ANSWER : E
Answer: E
Question: The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is:
Options:
A)40
B)25
C)30
D)35
E)48
Rationale: Sum of the present ages of husband, wife and child = (27 * 3 + 3 * 3) = 90 years.
Sum of the present age of wife and child = (20 * 2 + 5 * 2) = 50 years.
Husband's present age = (90 - 50) = 40 years.
ANSWER A
Answer: A
Question: Matt gets a $1,000 commission on a big sale. This commission alone raises his average commission by $150. If Matt's new average commission is $550, how many sales has Matt made?
Options:
A)3
B)4
C)5
D)6
E)7
Rationale: Let, Average Commission = x
No. of items sold = y
Total Commission = xy
New Commission = xy+1000
New Average = (xy+1000) / (y+1) = 150+x
i.e. (xy+1000) = (y+1)* (150+x)
i.e. (xy+1000) = (xy+x+150y+150)
i.e. (850) = (x+150y)
New Commission = 550 = 150+x
i.e. x=400
i.e. y = 3
New Sales = y+1 = 4
Answer: option B
Answer: B
Question: The Cottage Grove Loop Line travels the distance between the north side and the south side of the city in two hours, at a rate of speed of 100 km/h. How long is a round trip, measured in kilometers?
Options:
A)100 km
B)150 km
C)200 km
D)300 km
E)400 km
Rationale: Distance covered in 2 hours: 100 x 2 = 200 km
Duration of a return trip: 2 x 2 = 4 hours
Distance covered in 4 hours: 100 x 4 = 400 km
IMO, correct answer is "E."
Answer: E
Question: A vending machine randomly dispenses four different types of fruit candy. There are twice as many apple candies as orange candies, twice as many strawberry candies as grape candies, and twice as many apple candies as strawberry candies. If each candy cost $0.1, and there are exactly 90 candies, what is the minimum amount of money required to guarantee that you would buy at least three of each type of candy?
Options:
A)$8.30
B)$20.75
C)$22.50
D)$42.75
E)$45.00
Rationale: Let number of Apple , Orange , strawberry and grape candies be A, O ,S and G respectively .
A= 2O
S= 2G
A= 2S
A= 4G
A+O+S+G = 90
=>A + A/2 + A/2 +A/4 = 90
=> 9A/4 = 90
=> A = 40
O = 20
S = 20
G = 10
Cost of each candy = .1 $
Mininum amount of money required to guarantee that you would buy at least three of each type of candy
We can buy 40 Apple candies , 20 orange candies , 20 strawberry candies and 3 grape candies to ensure atleast 3 of each type of candies .
Total = 83 candies
Amount required = 83 * .1 = 8.30 $
Answer A
Answer: A
Question: A completes a work in 12 days and B complete the same work in 24 days. If both of them work together, then the number of days required to complete the work will be?
Options:
A)8 days
B)11 days
C)21 days
D)22 days
E)24 days
Rationale: If A can complete a work in x days and B can complete the same work in y days, then, both
of them together can complete the work in x y/ x+ y days
Therefore, here, the required number of days = 12 × 24/ 36 = 8 days.
Option 'A'
Answer: A
Question: If x is less than y by 20% then y exceed x by:
Options:
A)33.33%
B)25%
C)75%
D)66.66%
E)None of these
Rationale: Using formula (x/(100-x)*100) where x is Percentage decrease (here it is 20%)
=> 20/(100-20)*100
=25%
ANSWER:B
Answer: B
Question: A can do a piece of work in 4 days. B can do it in 8 days. With the assistance of C they completed the work in 2 days. Find in how many days can C alone do it?
Options:
A)22 days
B)8 days
C)67 days
D)1 days
E)18 days
Rationale: C = 1/2 - 1/4 - 1/8 = 1/8
=> 8 days
Answer:B
Answer: B
Question: What is the least common multiple of 15, 22 and 24?
Options:
A)60
B)120
C)240
D)1320
E)1720
Rationale: Let us first write the numbers in the form of prime factors:
15 = 3*5
22 = 2*11
24 = 2 * 17^1
The LCM would be the largest powers of the prime numbers from all these three numbers.
Hence LCM = 1320
Option D
Answer: D
Question: It takes printer A 4 more minutes more than printer B to print 40 pages. Working together, the two printers can print 50 pages in 6 minutes. How long will it take Printer A to print 160 pages?
Options:
A)12
B)18
C)48
D)20
E)30
Rationale: If it takes 4 more minutes for A to print 40 pages than it takes B,
it takes 5 more minutes for A to print 50 pages than it takes B.
Thus if b is the number of minutes than B takes to print 50 pages,
we can write:
1/b+1/(b+5)=1/6 (since in 1 minute, they print 1/6th of the 50 page job)
6(2b+5)=b(b+5)
b^2-7b-30=0
(b-10)(b+3)=0
b=10
Thus it takes A 15 minutes to print 50 pages and 15*160/50=48 minutes to print 160 pages (ANSWER C)
Answer: C
Question: Last year Sandy saved 6% of her annual salary. This year, she made 10% more money than last year, and she saved 9% of her salary. The amount saved this year was what percent of the amount she saved last year?
Options:
A)140%
B)152%
C)165%
D)176%
E)190%
Rationale: Let last year's salary be x.
Last year, Sandy save 0.06x
This year, Sandy saved 0.09*1.1x = 0.099x
0.099x / 0.06x = 99/60 = 1.65 = 165%
The answer is C.
Answer: C
Question: A boy is travelling from his home to school at 4 km/hr and reached 7 min late. Next day he traveled at 8 km/hr and reached 8 min early. Distance between home and school?
Options:
A)2km
B)3km
C)4km
D)5km
E)6km
Rationale: Let the distance be x
T1 = x/4 hr
T2 = x/8hr
Difference in time = 7+8 = 15 =1/4hr
x/4-x/8= 1/4
x/8=1/4
x =2 km
Answer is A
Answer: A