divelab/Sys2Bench huggingface dataset:
Question: The value of x + x(xx) when x = 6 is:
Options:
A)8
B)10
C)12
D)14
E)222
Rationale: x + x(xx)
Put the value of x = 6 in the above expression we get,
6 + 6(6*6)
= 222
ANSWER : E
Answer: E
Question: Dan's age after 16 years will be 6 times his age 4 years ago. What is the present age of Dan?
Options:
A)8
B)10
C)12
D)14
E)16
Rationale: Let Dan's present age be x.
x+16 = 6(x-4)
5x = 40
x = 8
The answer is A.
Answer: A
Question: If e = 20! + 17, then e is divisible by which of the following?
I. 15
II. 17
III. 19
Options:
A) None
B) I only
C) II only
D) I and II
E) II and II
Rationale: Another crude way to answer this, if you did not know the properties above would be to consider that that 20! will have the number ending in 00 due to 10 and 20 being included.
So e!+17 = xxxx00 +17 = xxxx17 which is only possibly divisible by 17. Hence Option C is the answer.
Answer: C
Question: A man can row 7.8 kmph in still water and he finds that it takes him twice as long to row up as to row down the river. Find the rate of stream.
Options:
A)2.6 km/hr
B)12.5 km/hr
C)1 2.6 km/hr
D)22.5 km/hr
E)22.6 km/hr
Rationale: Given that, time taken to travel upstream = 2 × time taken to travel downstream
When distance is constant, speed is inversely proportional to the time
Hence, 2 × speed upstream = speed downstream
Let speed upstream = x
Then speed downstream = 2x
we have, 1/2(x+2x) = speed in still water
⇒1/2(3x)=7.8
3x = 15.6
x = 5.2
i.e., speed upstream = 5.2 km/hr
Rate of stream = 1/2(2x−x)=x/2=5.2/2=2.6 km/hr
Answer is A
Answer: A
Question: What is the value of (P + Q)/(P - Q) if P/Q is 5?
Options:
A)4/3
B)3/2
C)2/6
D)7/8
E)8/7
Rationale: (P + Q)/(P - Q) = [(P/Q) + 1]/[(P/Q) - 1]
= (5 + 1)/(5 - 1)
= 6/4
= 3/2
ANSWER:B
Answer: B
Question: If population of certain city increases at the rate of 5%. If population in 1981 was 324135, then population in 1978 was?
Options:
A)120000
B)228788
C)280000
D)267689
E)127791
Rationale: X * (105/100) * (105/100) * (105/100) = 324135
X = 324135/1.157625
X = 280000
Answer C
Answer: C
Question: The value of (0.137+0.098)²-(0.137 - 0.098)² / 0.137×0.098 is
Options:
A)0.039
B)0.235
C)0.25
D)4
E)5
Rationale: Solution
Given expression	= (a+b)² - (a-b)²/ab
= 4ab/ab
= 4.
Answer D
Answer: D
Question: Joe has candys on his pocket, 4 of those candies have lemon flavor, and 3 have caramel flavor. If Joe take one, what is the probability that he picks one caramel flavor?
Options:
A)1
B)2
C)none
D)3/7
E)3/4
Rationale: the total number of candies is 7
and the number of candies with lemon flavor is 3
then, in one chance the probability to pick one candie with lemon flavor is
3/7
Answer D
Answer: D
Question: ♠n denotes the number obtained when n is rounded to the nearest tenth. For example ♠4.31 = 4.3
♠0.089 - ♠1.235 =
Options:
A)1.05
B)1.04
C)-1.05
D)-1.0
E)-1.1
Rationale: ♠0.089 - ♠1.135 =
0.1 - 1.2 = -1.1
Answer : E
Answer: E
Question: Find the sum lend at C.I. at 5 p.c per annum will amount to Rs.441 in 2 years?
Options:
A)227
B)400
C)277
D)686
E)120
Rationale: 441 = P(21/20)2
P = 400
Answer: B
Answer: B
Question: It takes Joey the postman 1 hours to run a 3 mile long route every day. He delivers packages and then returns to the post office along the same path. If the average speed of the round trip is 6 mile/hour, what is the speed with which Joey returns?
Options:
A)11
B)12
C)13
D)14
E)18
Rationale: let his speed for one half of the journey be 3 miles an hour
let the other half be x miles an hour
now,
avg speed =6 mile an hour
2*3*x/3+x=6
6x=6x+18=>x=18
E
Answer: E
Question: My grandson is about as many days as my son in weeks, and my grandson is as many months as I am in years. My grandson, my son and I together are 140 years. Can you tell me my age in years?
Options:
A)80
B)90
C)85
D)84
E)89
Rationale: let the age of the man = x years
so according to the given condition
age of my grandson = x/12 years
and age of my son = x30/52 = 15x/26
and x + (x/12) + (15x/26) = 140
or (156x+13x+90x)/156 = 140
or 259x = 156*140
or x = 156*140/259 = 84
ANSWER:D
Answer: D
Question: A man buys an article for $100. and sells it for $110. Find the gain percent?
Options:
A)10%
B)15%
C)25%
D)20%
E)30%
Rationale: C.P. = $100
S.P. = $110
Gain = $10
Gain% = 10/100 *100 = 10%
Answer is A
Answer: A
Question: A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is :
Options:
A)45.30 km/hr
B)55.15 km/hr
C)70.15 km/hr
D)71.11 km/hr
E)None
Rationale: Sol.
Total time taken = [160/64 + 160/8] hrs = 9/2 hrs.
∴ Average speed = [320*2/9] km/hr = 71.11 km/hr.
Answer D
Answer: D
Question: Ram, who is half as efficient as Krish, will take 18 days to complete a task if he worked alone. If Ram and Krish worked together, how long will they take to complete the task?
Options:
A)16 days
B)12 days
C)8 days
D)6 days
E)18 days
Rationale: Number of days taken by Ram to complete task = 18
Since Ram is half as efficient as Krish , Amount of work done by Krish in 1 day = Amount of work done by Ram in 2 days
If total work done by Ram in 18 days is 18w
Amount of work done by Ram in 1 day = w
Amount of work done by Krish in 1 day = 2w
Total amount of work done by Krish and Ram in a day = 3w
Total amount of time needed by Krish and Ram to complete task = 18w/3w = 6 days
Answer D
Answer: D
Question: If x is a positive odd number, then each of the following is odd EXCEPT
Options:
A)(x + 3)(x + 5)
B)x^2 + 5
C)x^2 + 6x + 9
D)3x^2 + 4
E)5(x + 3)
Rationale: Since it is given tht x is even number, so any integer multiplied with x will also be even..
so, we should concentrate only on other terms..
lets see the choices..
A. (x + 3)(x + 5)
We have two terms with x and each is added with a odd number..
each bracket becomes odd and Odd*Odd=Odd
B. x^2 + 5
here we are adding an Odd number to even.. so E + O=O
C. x^2 + 6x + 9
here we are again adding an Odd number to even.. so E +E + O=O
D. 3x^2 + 4
here we are adding an Even number to even.. so E + E=E..
so tjis is our answer
E. 5(x + 3)
again O*O=O
B
Answer: B
Question: A man gave 1/8 of his property to his wife and 1/4 of the remaining to his daughter. What fraction of his property is he left with after giving to his wife and his daughter?
Options:
A)5/16
B)2/8
C)21/32
D)4/8
E)12/15
Rationale: A man gave 1/8 of his property to his wife, so remaining is 7/8
He gave 1/4 of the remaining property to his daughter, 1/4*7/8=7/32
Total property given to his wife and daughter is 1/8+7/32
To make the denominator common, we use 32=4/32
4/32+7/32=11/32 is given to his wife and daughter
Remaining property left with him is 21/32
Answer is C
Answer: C
Question: The average of 4,8,12 and x is 10. Find the value of x?
Options:
A)10
B)16
C)15
D)24
E)12
Rationale: average = (4+8+12+x)/4 = 10
x = 16
Answer is B
Answer: B
Question: If a man lost 4% by selling oranges at the rate of 12 a rupee at how many a rupee must he sell them to gain 44%?
Options:
A)2
B)8
C)6
D)4
E)2
Rationale: 96% ---- 12
144% ---- ?
96/144 * 12 = 8
Answer: B
Answer: B
Question: Two pumps are connected to an empty tank. Pump X fills the tank with water at a constant rate, while pump Y drains water out of the tank at a constant rate. The two pumps finish filling the tank in four times the duration it would take pump X alone to fill the tank. If pump Y alone can empty a whole tank in 44 minutes, then how many minutes does it take pump X alone to fill the tank?
Options:
A)27
B)30
C)33
D)36
E)39
Rationale: Let V be the volume of the tank.
Let R be the rate per minute that pump X fills the tank.
Let T be the time it takes pump X to fill the tank.
The rate at which pump Y empties the tank is V/44 per minute.
(R - V/44)*4T=V=RT.
(R-V/44)*4=R
3R=V/11.
R=V/33.
It takes pump X 33 minutes to fill the tank.
The answer is C.
Answer: C
Question: 12.1212+17.0005 - 9.1105 = ?
Options:
A)20.0015
B)20.0105
C)20.0115
D)20.1015
E)20.0112
Rationale: Solution
Given expression
=(12.1212+17.0005)-9.1105
= (29.1217 - 9.1105)
=20.0112.
Answer E
Answer: E
Question: If a and b are nonzero integers such that 4a = 10b, then each of the following must be true EXCEPT
Options:
A)0 < b/a < 1
B)ab is positive.
C)On the number line, b lies between 0 and a.
D)The ratio of a to b is equivalent to 10/4.
E)a – b is positive.
Rationale: This question can be solved by TESTing VALUES. Based on its wording, you would likely need to do 2 TESTs to get to the correct answer though.
We're told that A and B are NONZERO INTEGERS and that 4a = 10b or 2A = 5b. We're told that each of the answer is always true EXCEPT for one of them...
Before we get to the actual work, it's important to note a few details:
1) We are NOT told that A and B are positive - we're just told that they're NONZERO - that's interesting - it means that we have to consider the possibility that they're both NEGATIVE...
2) 4 of the answers will always be true, while one of them will EITHER be sometimes true OR never true. We'll have to keep working until we find 1 answer that is not true (for whatever reason) - that will be the solution to this question.
Since 2A = 5B, I'm going to run 2 pairs of TESTs at the same time...
A = 5
B = 2
AND
A = -5
B = -2
Answer A: 0 < B/A < 1
2/5 and -2/-5 both = 2/5. Answer A appears true.
Answer B: AB is positive
(2)(5) and (-2)(-5) both = +10. Answer B appears true.
Answer C: B is between 0 and A on the number line
0....2....5
-5....-2....0
Answer C appears true.
Answer D: A/B = 10/4
5/2 = -5/-2
10/4 = 5/2
Answer D appears true.
Answer E: A - B is positive
5 - 2 = 3
-5 - (-2) = -3 *****This is NOT always true.
Final Answer:
E
Answer: E
Question: Cars emerging from a motorway arrive at a junction that splits the road into two separate lanes. The number of cars per hour that continue in either lane is constant. If 7 cars per hour were diverted from the left lane to the right lane, the number of cars entering the right lane per hour would be twice as big as the number of cars entering the left lane per hour. Alternatively, if 7 cars per hour were diverted from the right lane to the left lane, the number of cars entering the left lane per hour would be four times as great as the number of cars entering the right lane per hour. How many cars enter the left lane per hour?
Options:
A)21
B)18
C)17
D)19
E)28
Rationale: as per question 7 cars diverted from left lane to right lane. Thus we get equation R+7=2(L-7)
as per question 7 cars diverted from right lane to left lane .thus we get equation L+7=4(R-7)
by solving two equation i.e R +7 =2L-14 OR. R =2L -21 AND L+7= 4R -28 OR L= 4R -35
BY SOLVING WE GET L= 4( 2L -21) -35 OR L= 8L -84-35 OR 119 =7L THUS L =17
C
Answer: C
Question: Find the unit's digit from the given 264^102+264^103?
Options:
A)0
B)1
C)2
D)3
E)4
Rationale: Required unit's digit = unit's digit in 4102+4103.4102+4103.
Now, 4242 gives unit digit 6.
⇒ 41024102 gives unit digit 6.
⇒ 41034103 gives unit digit of the product 6×46×4 i.e., 4.
Hence, unit's digit in 264102+264103264102+264103
= unit's digit in (6+4)=0
A
Answer: A
Question: On the first of the year, James invested x dollars at Proudstar bank in an account that yields 2.2% in interest every quarter year. At the end of the year, during which he made no additional deposits or withdrawals, he had y dollars in the account. If James had invested the same amount in an account which pays interest on a yearly basis, what must the interest rate be for James to have y dollars at the end of the year?
Options:
A)2.04%
B)6.12%
C)8%
D)8.25%
E)9%
Rationale: If the interest were compounded annually instead of quarterly then in one year the interest would be 2.2*4=8.8%. Now, since the interest is compounded quarterly then there would be interest earned on interest (very small amount) thus the actual interest would be a little bit more than 8.8%
Answer: E.
Answer: E
Question: Indu gave Bindu Rs.1250 on compound interest for 2 years at 4% per annum. How much loss would Indu has suffered had she given it to Bindu for 2 years at 4% per annum simple interest?
Options:
A)7
B)2
C)9
D)5
E)4
Rationale: 1250
= D(100/4)2
D = 2
Answer: B
Answer: B
Question: How long does a train 110 m long traveling at 90 kmph takes to cross a bridge of 170 m in length?
Options:
A)16.5
B)16.0
C)16.4
D)16.8
E)11.2
Rationale: D = 110 + 170 = 280 m
S = 90 * 5/18 = 25
T = 280 * 1/25 = 11.2 sec
Answer: E
Answer: E
Question: Anand and Deepak started a business investing Rs. 27,500 and Rs. 33,000 respectively. Out of a total profit of Rs. 15,000, Deepak's share is?
Options:
A)Rs. 8181.81
B)Rs. 8900
C)Rs. 8400
D)Rs. 3400
E)Rs. 8440
Rationale: Ratio of their shares = 27500 : 33000 = 5 : 6
Deepak's share = 15000 * 6/11 = Rs. 8181.81
Answer:A
Answer: A
Question: At a dinner party, 4 people are to be seated around a circular table. 2 seating arrangements are considered different only when the positions of the people are different relative to each other. what is the total number of different possible seating arrangements for the group?
Options:
A)6
B)10
C)24
D)32
E)120
Rationale: Soln: Since the arrangement is circular and 2 seating arrangements are considered different only when the positions of the people are different relative to each other, we can find the total number of possible seating arrangements, by fixing one person's position and arranging the others.
Thus if one person's position is fixed, the others can be arranged in 3! =6 ways.
Ans is A.
Answer: A
Question: A train moves fast a telegraph post and a bridge 264 m long in 8 sec and 20 sec respectively. What is the speed of the train?
Options:
A)89
B)23
C)56
D)79.2
E)67
Rationale: Let the length of the train be x m and its speed be y m/sec.
Then, x/y = 8 => x = 8y
(x + 264)/20 = y
y = 22
Speed = 22 m/sec = 22 * 18/5 = 79.2 km/hr.
Answer: Option D
Answer: D
Question: A milk vendor has 2 cans of milk. The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the containers so as to get 12 litres of milk such that the ratio of water to milk is 3 : 5?
Options:
A)4 litres, 8 litres
B)6 litres, 6 litres
C)5 litres, 7 litres
D)7 litres, 4 litres
E)None
Rationale: Let the cost of 1 litre milk be Re. 1
Milk in 1 litre mix. in 1st can = 3/4 litre, C.P. of 1 litre mix. in 1st can Re. 3/4
Milk in 1 litre mix. in 2nd can = 1/2 litre, C.P. of 1 litre mix. in 2nd can Re. 1/2
Milk in 1 litre of final mix. = 5/8 litre, mean price = Re. 5/8.
Ratio of two mixtures = 1/8 : 1/8 = 1:1.
So, quantity of mixture taken from each can = (1/2 X 12) = 6 litres.
Answer B
Answer: B
Question: what is the units digit of the expression 17^7-2?
Options:
A)1
B)2
C)3
D)7
E)9
Rationale: 7^1=7
7^2=49
7^3=343
7^4=1(last digit)
7^5=7(last digit) and the cycle repeats after every 4 powers
Therefore, last digit of 17^7=3
3-2=1
Answer A
Answer: A
Question: Which of the following points falls outside of the region defined by 2y≤6x−17?
Options:
A)(5, 1)
B)(3, -8)
C)(2, 0)
D)(1, -2)
E)(0, -14)
Rationale: Equation given is 2y<=6x-12
Simplifying this; y<=3x-6
Plug in the values provided in the options,
A. 1<=11
B. -8<=3
C. 0<=0
D.-2<=-4
E. -14<=-12
Option D is the answer.
Answer: D
Question: The sale price sarees listed for Rs.400 after successive discount is 10% and 5% is?
Options:
A)500
B)342
C)250
D)362
E)879
Rationale: Explanation:
400*(90/100)*(95/100) = 342
Answer:B
Answer: B
Question: How many Books each of Volume 100 meter cube can be packed into a crate of volume 4000 meter cube?
Options:
A)100
B)120
C)cannot be determined
D)180
E)200
Rationale: Gud question with a simple concept.
In geo if we want to insert one shape into another we need to know the dimensions of the two shapes.
In above with volume given , we can come up with different shapes, so we cant know the answer
For ex :4000 m3 can be 400*10 or 40*100 or just 4000*1 we don't know , so we cant calculate
Answer : C
Answer: C
Question: 5years ago, the age of Anand was one-forth of the age of Bala at that time. The present age of Bala is 13 years more than the present age of Anand. Find the present age of Anand?
Options:
A)11
B)21
C)19
D)22
E)14
Rationale: Explanation:
Let the present ages of Anand and Bala be 'a' and 'b' respectively.
a - 5 = 1/3 (b - 5) --- (1)
b = a + 13
Substituting b = a + 8 in first equation,
a - 10 = 1/3 (a +8) => 3a - 30 = a + 8=> 2a = 38 => a = 19.
Answer: C
Answer: C
Question: A man can row a boat at 20 kmph in still water. If the speed of the stream is 8 kmph, what is the time taken to row a distance of 60 km downstream?
Options:
A)30/18 hours
B)15/7 hours
C)80/13 hours
D)30/13 hours
E)30/43 hours
Rationale: Speed downstream = 20 + 8 = 28 kmph.
Time required to cover 60 km downstream
= d/s = 60/28
= 15/7 hours.
Answer: B
Answer: B
Question: Simple interest on a sum at 2% per annum for 2 years is Rs.100. The C.I. on the same sum for the same period is?
Options:
A)101.8
B)101.4
C)101.2
D)100
E)110.2
Rationale: SI = 50 + 50
CI = 50 + 50 + 1.8 = 101.8
Answer: A
Answer: A
Question: Which of the following expressions CAN be equal to 0 when x^2 −16= 0 ?
Options:
A)x^2 − 6x + 9
B)x^2 − 4x + 3
C)x^2 − x − 2
D)x^2 − 7x + 6
E)x^2 − 5x + 4
Rationale: x^2 − 16 = 0
x=-4 or x=4
Onle one choice results in a possibility of 0 when you plug in -4 or 4 for x except rest of all
x^2 − 5x + 4
Answer is E
Answer: E
Question: If 100% of j is equal to 25% of k, 150% of k is equal to 50% of l, and 125% of l is equal to 75% of m, then 20% of m is equal to what percent of 200% of j ?
Options:
A)0.35
B)3.5
C)350
D)35
E)3500
Rationale: IMO answer should be 350...
consider j=10, then k=50, l=150 and m=350....
20% of 350, comes out to be 70....
200% of 10 is 20....
(70*100)/20=350....
Ans : C
Answer: C
Question: W and B are integers. The expression (W+1)(B+1) is even. What can be said about W and B?
Options:
A)They are both even numbers.
B)At least one of them is even.
C)At least one of them is odd.
D)They are both odd.
E)Nothing can be said surly on W and B
Rationale: Odd x Odd = Odd
Odd x Even = Even
Even x Even = Even
To fulfill condition Either (W+1) or (B+1) needs to be Even
So either W or B needs to be odd
Or At least one of them is odd.
At least one of them is odd=C
Answer: C
Question: Two friends want to buy a snack. They combine their money and find they have $4.15, consisting of quarters, dimes, and nickels. If they have 37 coins and the number of quarters is half the number of nickels, how many quarters do they have?
Options:
A)9
B)10
C)11
D)12
E)13
Rationale: Let x be the number of quarters. Then 2x is the number of nickels.
(1) 25x + 10x + 10D = 415. Then 7x + 2D = 83
(2) 3x + D = 37. Then 6x + 2D = 74
Let's subtract equation (2) from equation (1).
x = 9
The answer is A.
Answer: A
Question: Bobby bought 2 shares, and which he sold for $96 each. If he had a profit of 25% on the sale of one of the shares but a loss of 28% on the sale of the other share, then on the sale of both shares Bobby had...
Options:
A)a profit of 10
B)a profit of 8
C)a loss of 8
D)a loss of 18
E)neither a profit nor a loss
Rationale: Cost of the first stock: 96/1.25=76.8, so profit from it 96-76.8=19.2
Cost of the second stock: 96/0.72=133.33, so loss from it 96-133.33=-37.33
Overall loss 19.2 - 37.33=-18.13
Answer: D.
Answer: D
Question: Average monthly income of a family of 4 earning members was Rs. 735. One of the earning members died and therefore, the average income came down to Rs 590. The income of the deceased was?
Options:
A)Rs. 692.80
B)Rs. 820
C)Rs. 1170
D)Rs. 1385
E)None
Rationale: Answer
Income of the deceased = Total income of 4 members - total income of remaining 3 members.
= 735 x 4 - 590 x 3 Rs.
= 1170 Rs.
Correct Option: C
Answer: C
Question: There are 14 cans in the refrigerator. 7 of them are red and 7 of them are blue. In how many ways we can remove 8 cans so that at least one red and at least one blue cans to remain the refrigerator.
Options:
A)460
B)490
C)493
D)455
E)445
Rationale: Answer: C.
Answer: C
Question: At a restaurant, glasses are stored in two different-sized boxes. One box contains 12 glasses, and the other contains 16 glasses. If the average number of glasses per box is 15, and there are 16 more of the larger boxes, what is the total number of glasses W at the restaurant? (Assume that all boxes are filled to capacity.)
Options:
A)96
B)240
C)W=256
D)W=384
E)W=480
Rationale: Most Test Takers would recognize thesystemof equations in this prompt and just do algebra to get to the solution (and that's fine). The wording of the prompt and the 'spread' of the answer choices actually provide an interesting 'brute force' shortcut that you can take advantage of to eliminate the 4 wrong answers....
We're told that there are 2 types of boxes: those that hold 12 glasses and those that hold 16 glasses. Since the AVERAGE number of boxes is 15, we know that there MUST be at least some of each. We're also told that that there are 16 MORE of the larger boxes.
This means, at the minimum, we have...
1 small box and 17 large boxes = 1(12) + 17(16) = 12 + 272 = 284 glasses at the MINIMUM
Since the question asks for the total number of glasses, we can now eliminate Answers A, B and C....
The difference in the number of boxes MUST be 16 though, so we could have....
2 small boxes and 18 large boxes
3 small boxes and 19 large boxes
etc.
With every additional small box + large box that we add, we add 12+16= 28 MORE glasses. Thus, we can justadd 28suntil we hit the correct answer....
284+28 = 312
312+28 = 340
340+28 = 368
368+28 = 396
At this point, we've 'gone past' Answer D, so the correct answer MUST be Answer E.....But here's the proof....
396+28 = 424
424+28 = 452
452+28 = 480
Final Answer:
E
Answer: E
Question: The pilot of a small aircraft with a 40-gallon fuel tank wants to fly to Cleveland, which is 480 miles away. The pilot recognizes that the current engine, which can fly only 7 miles per gallon, will not get him there. By how many miles per gallon must the aircraft’s fuel efficiency be improved to make the flight to Cleveland possible?
Options:
A)2
B)4
C)5
D)40
E)160
Rationale: Actual miles/gallon is = 480/40 = 12 miles/gallon.
Current engine miles/gallon is 7 miles/gallon.
Additional 5 miles/gallon is required to match the actual mileage.
IMO option C.
Answer: C
Question: John has taken four (4) tests that have an average of 85. In order to bring his course grade up to a ‘B’, he will need to have a final average of 89. What will he need to average on his final two tests to achieve this grade?
Options:
A)87
B)90
C)92
D)97
E)98
Rationale: Traditional Method:
Total scored till now 85*4=340
Total score to avg 89 in 6 tests = 89*6=534
Total to be scored on 2 tests = 534-340=194
Avg on 2 tests = 194/2 = 97
Answer: D
Answer: D
Question: If the price of an article went up by 25%, then by what percent should it be brought down to bring it back to its original price?
Options:
A)20%
B)16 4/3%
C)16 7/3%
D)16 6/3%
E)16 2/3%
Rationale: Let the price of the article be Rs. 100.
25% of 100 = 25.
New price
= 100 + 25 = Rs. 125
Required percentage
= (125 - 100)/125 * 100
= 25/125 * 100
= 20%
Answer:A
Answer: A
Question: A paint crew gets a rush order to paint 80 houses in a new development. They paint the first y houses at a rate of x houses per week. Realizing that they'll be late at this rate, they bring in some more painters and paint the rest of the houses at the rate of 1.25x houses per week. The total time Q it takes them to paint all the houses under this scenario is what fraction of the time it would have taken if they had painted all the houses at their original rate of x houses per week?
Options:
A) 0.8(80 – y)
B) 0.8 + 0.0025y
C) 80/y – 1.25
D) 80/1.25y
E) 80 – 0.25y
Rationale: This may be a case of bad numberpicking but it worked for me.
80 houses. Let's say that y=40 houses are painted at the rate x=10 houses per week <=> 1/10 week per house. 40*1/10 = 4 houses per week will be painted at this rate.
80-y = 80-40 = 40 houses are to be painted at the faster rate. X*1,25=12,5 houses per week <=> 1/12,5 weeks per house * 40 houses = 40/12,5 = 80/25 = 320/100 = 3,2 weeks.
Which means finishing all houses at normal rate Q=> 2*4 = 8 weeks. Faster rate = 4+3,2 = 7,2 weeks.
7,2/8 = 9/10 = 0,9. Insert y=40 in equations and it is clear that only (B) gives us 0,9.
Answer: B