divelab/Sys2Bench huggingface dataset:
Question: If a number is 40% more than the another, how much % is the smaller number less than the first ?
Options:
A)12(1/3)%
B)16(2/3)%
C)28(4/7)%
D)16(4/3)%
E)none of these
Rationale: Take a number 100,
Then the other number is 140
% the smaller number is less than the first = [(40/(140)) x 100]% = 28(4/7)%.
ANSWER:C
Answer: C
Question: Adam borrowed some money at the rate of 6% p.a. for the first two years, at the rate of 9% p.a. for the next three years, and at the rate of 14% p.a. for the period beyond four years. If he pays a total interest of 11,800 at the end of nine years, how much money did he borrow?
Options:
A)10,421
B)12,421
C)14,000
D)16,000
E)16,421
Rationale: Let the sum borrowed be x. Then,
(x×6×21/00)+(x×9×3/100)+(x×14×4/100)= 11800
⇒ (3⁄25x + 27⁄100x + 14⁄25x) = 11400 ⇒ 95⁄100x = 11800
⇒ x = (11800×100/95)= 12421
Hence, sum borrowed = 12,421
Answer B
Answer: B
Question: A bag contains 10 black and 20 white balls. One ball is drawn at random. What is the probability that the ball drawn is white?
Options:
A)1/2
B)3/4
C)2/3
D)1/5
E)3/7
Rationale: Total number of balls = 10+20 = 30
Number of white balls = 20
probability of drawing a white ball = 20/30 = 2/3
Answer is C
Answer: C
Question: The sum of two numbers is 22. Five times one number is equal to 6 times the other. The bigger of the two numbers is
Options:
A)10
B)12
C)16
D)22
E)24
Rationale: Sol.
Let the numbers be x and (22 - x).
Then, 5x = 6(22 - x)
⇔ 11x = 132⇔ x = 12.
So, the numbers are 12 and 10.
Answer B
Answer: B
Question: The length of the bridge, which a train 130 meters long and travelling at 45 km/hr can cross in 30 seconds, is:
Options:
A)377
B)268
C)245
D)665
E)187
Rationale: Speed = (45 * 5/18) m/sec = (25/2) m/sec. Time = 30 sec. Let the length of bridge be x meters. Then, (130 + X)/30 = 25/2 ==> 2(130 + X) = 750 ==> X = 245 m.
Answer: C
Answer: C
Question: How much does a watch lose per day, if its hands coincide every 64 minutes?
Options:
A)32 8/11min
B)32 8/01min
C)32 8/31min
D)32 6/11min
E)32 7/41min
Rationale: 55 min. spaces are covered in 60 min.
60 min spaces are covered in (60/55 * 60)min = 65 5/11 min
Loss in 64 min = ( 65 5/11- 64 ) = 16/11 min
Loss in 24 hrs = ( 16/11 * 1/64 * 24 * 60 ) min
= 32 8/11 min
Answer: Option 'A'
Answer: A
Question: If each day a tree loses half its remaining leaves, what fraction of its leaves will it have lost after 6 days ?
Options:
A)X-1/8
B)X-1/16
C)X-1/64
D)X/32
E)X/96
Rationale: LET NO OF LEAVES IX X ..IST DAY X/2 ..2ND DAY X/4 ..3RD DAY X/8 , FOURTH DAY X/16 , 5TH DAY X/32 , 6TH DAY X/64 SO ON SO FOURTH.
FINALLY ON LEAVE WILL BE LEFT ..SO ON 3RD DAY LEAVE LOST IS X-1/64 ANSWER C
Answer: C
Question: 1,23,45,67 find ot next term
Options:
A)61
B)71
C)75
D)89
E)91
Rationale: 1+22=23
23+22=45
45+22=67
67+22=89
ANSWER:D
Answer: D
Question: Lary and Terry enter into a partnership by investing $700 and $300 respectively. At the end of one year, they divided their profits such that a third of the profit is divided equally for the efforts they have put into the business and the remaining amount of profit is divided in the ratio of the investments they made in the business. If Lary received $800 more than Terry did, what was the profit made by their business in that year?
Options:
A)3000
B)3546
C)35346
D)3521
E)56768
Rationale: Say the profit was $x.
Lary share = x/6 (half of the third) + (x-x/3)*0.7
Terry share = x/6 (half of the third) + (x-x/3)*0.3
Thus (x-x/3)*0.7-(x-x/3)*0.3=800 --> x=3000.
answer is A
Answer: A
Question: If you are given $3, and the amount doubles every day, how much money will you have after 9 days?
Options:
A)$19683
B)$19898
C)$10242
D)$20481
E)$14096
Rationale: 3^9=19683
The answer is A
Answer: A
Question: Of the 50 researchers in a workgroup, 30 percent will be assigned to Team A and the remaining 80 percent to Team B. However, 70 percent of the researchers prefer Team A and 30 percent prefer Team B. What is the lowest possible number of researchers who will NOT be assigned to the team they prefer?
Options:
A) 15
B) 17
C) 20
D) 25
E) 30
Rationale: I solved it by assuming 100 people and then dividing my answer in two to save time on calculations. (percentage equals number of people) In that case
30 will be in team A
70 will be in team B
The larger diff is
70 want team A so diff is 70-30=40. At least 40 people will NOT get their wish, so for 50 researchers the same number is 20.
Answer choice C
Answer: C
Question: A man can row upstream at 25 kmph and downstream at 37 kmph, and then find the speed of the man in still water?
Options:
A)65
B)86
C)30
D)78
E)31
Rationale: US = 25
DS = 37
M = (37 + 25)/2
= 31
Answer: E
Answer: E
Question: An auction house charges a commission of 20% on the first $50,000 of the sale price of an item, plus 10% on the amount of of the sale price in excess of $50,000. What was the price of a painting for which the house charged a total commission of $24,000?
Options:
A)$115,000
B)$190,000
C)$215,000
D)$240,000
E)$365,000
Rationale: Say the price of the house was $x, then 0.2*50,000+0.1*(x-50,000)=24,000 --> x=$190,000 (20% of $50,000 plus 10% of the amount in excess of $50,000, which is x-50,000, should equal to total commission of $24,000).
Answer: B.
Answer: B
Question: What is the Mode of the following data set T- {1,2,9,1,6,9,9,10}
Options:
A)9
B)10
C)2
D)1
E)6
Rationale: Mode of a set is the data point that is repeated the most number of times. In the set given, 9 is the mode
Answer : A
Answer: A
Question: A IS TWICE AS GOOD A WORKMAN AS B AND TOGETHER THEY FINISH A PIECE OF WORK IN 14 DAYS. THE NUMBER OF DAYS TAKEN BY A ALONE TO FINISH THE WORK IS:
Options:
A)11
B)21
C)28
D)42
E)NONE OF THESE
Rationale: (A'S 1 DAY'S WORK): (B'S 1 DAY'S WORK)=2:1
(A+B)'S 1 DAY'S WORK = 1/14
DIVIDE 1/14 IN THE RATIO 2:1
A'S 1 DAY'S WORK = (1/14x2/3)=1/21
HENCE, A ALONE CAN FINISH THE WORK IN 21 DAYS.
CORRECT OPTION : B
Answer: B
Question: If you multiply all the numbers on your mobile phone , what is the answer?
Options:
A)2
B)6
C)1
D)0
E)7
Rationale: D
0
Their is a zero in your phone.
Answer: D
Question: There are two divisions A and B of a class, consisting of 36 and 44 students respectively. If the average weight of divisions A is 40 kg and that of division b is 35 kg. What is the average weight of the whole class?
Options:
A)38.25
B)37.25
C)38.5
D)37
E)37.5
Rationale: Explanation:
Total weight of students in division A = 36 × 40
Total weight of students in division B = 44 × 35
Total students = 36 + 44 = 80
Average weight of the whole class
=(36×40)+(44×35)/80
=(9×40)+(11×35)/20
=(9×8)+(11×7)/4
=72+77/4
=149/4
=37.25
Answer: Option B
Answer: B
Question: Difference of two parallel sides of atrapezium is 4cm. perpendicular distance between them is10cm. If the area of the trapezium is 250cm^2. Find the lengths of the parallel side?
Options:
A)20 cm and 21 cm
B)25 cm and 23 cm
C)27 cm and 23 cm
D)30 cm and 34 cm
E)28 cm and 36 cm
Rationale: Let the two parallel sides of the trapezium be a cm and b cm.
Then, a-b = 4 ------ (1)
And, (1/2) x (a+b) x 10 = 475 =>(a+b) =((250 x 2)/10) => a + b = 50------- (2)
Solving 1 and 2, we get: a=27,b=23
So, the two parallel sides are 27 cm and 23 cm.
C
Answer: C
Question: A, B, C and D enter into partnership. A subscribes 1/3 of the capital B 1/4, C 1/5 and D the rest. How much share did A get in a profit of Rs.2490 ?
Options:
A)Rs. 820
B)Rs. 830
C)Rs. 840
D)Rs. 850
E)NONE OF THESE
Rationale: Explanation:
Let the total amount in the partnership be 'x'.
Then A's share = x/3
B's share = x/4
C's share = x/5
D's share = x - (x/3 + x/4 +x/5) = 13x/60
A : B : C : D = x/3 : x/4 : x/5 : 13x/60 = 20 : 15 : 12 : 13
A's share in the profit of Rs. 2490 = 20 (2490/60) = Rs. 830.
ANSWER IS B
Answer: B
Question: A $89.95 lawn chair was sold for $59.95 at a special sale. By approximately what percent was the price decreased?
Options:
A)15%
B)20%
C)25%
D)60%
E)33%
Rationale: Listed selling price of chair = 89.95 $
Discounted selling price of chair = 59.95 $
Discount = 89.95 - 59.95 = 30 $
% decrease in price of chair = (30/89.95) * 100% = 33 % approx
Answer E
Answer: E
Question: Solve for x: 2x â€“ y = (3/4)x + 4.
Options:
A)(y + 6)/5
B)4(y + 4)/5
C)(y + 6)
D)4(y - 6)/5
E)5/4(y-6)
Rationale: Solution:
2x â€“ y = (3/4)x + 4.
or, 2x - (3/4)x = y + 4.
or, (8x -3x)/4 = y + 4.
or, 5x/4 = y + 4.
or, 5x = 4(y + 4).
or, 5x = 4y + 16.
or, x = (4y + 16)/5.
Therefore, x = 4(y + 4)/5.
correct answer B
Answer: B
Question: A water supply company charges $3 for the first 500 liters of water plus $0.06 for each additional litter of water in a month. What would this company charge for a water consumption of 750 liters in a month ?
Options:
A)$15.60
B)$16.00
C)$18
D)$18.70
E)$19.10
Rationale: first 500 litres chages = $3
rest of the litres = 750 - (500) = 250
charge for the rest of the units = 250 *06 = 15
total charge = 3 + 15 = 18
Answer is C
Answer: C
Question: A woman is budgeting her 500 dollars over the next 50 days. After 10 days she paid off enough bills so that the remaining money will now be enough for the same period of 50 days as before. How much money did she spend?
Options:
A)100
B)200
C)150
D)50
E)250
Rationale: 500 ---- 50
500 ---- 40
x ---- 50
x*50 = 500*40
x = 400
500
-----
100
Answer = A
Answer: A
Question: 18 men shake hands with each other. Maximum no of handshakes without cyclic handshakes.
Options:
A)190
B)153
C)210
D)220
E)230
Rationale: 1st person will shake hand with 17 people
2nd person will shake hand with 16 people
3rd person will shake hand with 15 people
......
total no. of handshakes = 17+...+3+2+1 = 17*(17+1)/2 = 153
or, if there are n persons then no. of shakehands = nC2 = 18C2 = 153
ANSWER:B
Answer: B
Question: √(21)^2
Options:
A)7
B)14
C)49
D)21
E)None of these
Rationale: explanation
√(21)^2 =?
or, ? = 21
Answer D
Answer: D
Question: The difference between the squares of two consecutive odd integers is always divisible by:
Options:
A)3
B)6
C)7
D)8
E)9
Rationale: Let the two consecutive odd integers be (2x + 1) and (2x + 3)
Then, (2x + 3)2 - (2x + 1)2 = (2x + 3 + 2x + 1) (2x + 3 - 2x - 1) = (4x + 4)(2)
= 8 (x + 1), which is always divisible by 8
ANSWER:D
Answer: D
Question: A car crosses a 600 m long bridge in 5 minutes. Whatis the speed of car in km per hour?
Options:
A)7 km/hr
B)7.2 km/hr
C)7.5 km/hr
D)7.678 km/hr
E)8 km/hr
Rationale: Speed = 600 m/sec.
5 x 60
= 2 m/sec.
Converting m/sec to km/hr (see important formulas section)
= 2 x 18 km/hr
5
= 7.2 km/hr
B
Answer: B
Question: By selling 32 orange in a dollar, a man loses 40%. How many orange must he sell in a dollar to gain 20% profit?
Options:
A)16
B)18
C)20
D)25
E)28
Rationale: x - expenses
0.6x after selling 32 oranges per 1$
want to get 1.2x
1.2x/0.6x=2, so should be 32/2=16 oranges
ANSWER:A
Answer: A
Question: X can finish a work in 24 days. Y can finish the same work in 16 days. Yworked for 10 days and left the job. how many days does X alone need to finish the remaining work?
Options:
A)3
B)5
C)6
D)8
E)9
Rationale: Work done by X in 1 day = 1/24
Work done by Y in 1 day = 1/16
Work done by Y in 10 days = 10/16 = 5/8
Remaining work = 1 – 5/8 = 3/8
Number of days in which X can finish the remaining work = (3/8) / (1/24) = 9
E
Answer: E
Question: From the set of numbers x, y, t, z, p, q and w, how many different combinations can we have without the t in them? Ex:. (x,y), (x), (w,z,y,x,p,q), etc and (x,y)=(y,x)
Options:
A)10
B)14
C)45
D)63
E)80
Rationale: Another way: Any letter (x, y, z, w, p, q) can be included or not. So, we have 2^6 combinations - 1 empty combination = 63 combinations
D
Answer: D
Question: The ratio of red, yellow, and green jelly beans in a jar is 1:3:4. If the number of jelly beans is increased by 60%, 20%, and 40% respectively, what will be the new ratio?
Options:
A)3:7:12
B)4:9:14
C)5:11:15
D)6:14:17
E)8:17:24
Rationale: The new ratio will be 1.6:3.6:5.6=16:36:56=4:9:14.
The answer is B.
Answer: B
Question: In the formula V = 1/(2r)^4, if r is halved, then V is multiplied by?
Options:
A)16
B)8
C)1
D)1/8
E)1/64
Rationale: Say r=2 => V1 = 1/256
when r=1; V2 = 1/16
V2 = 16*V1.
Answer : A
Answer: A
Question: From a pack of cards two cards are drawn one after the other, with replacement. The probability that the first is a red card and the second is a king is?
Options:
A)1/26
B)1/25
C)1/19
D)1/11
E)1/87
Rationale: Let E1 be the event of drawing a red card.
Let E2 be the event of drawing a king .
P(E1 ∩ E2) = P(E1) . P(E2)
(As E1 and E2 are independent)
= 1/2 * 1/13 = 1/26
Answer:A
Answer: A
Question: While extinguishing a fire that has caught a mansion, the firefighter is standing on the middlemost rung of the ladder. In order to reach at a better position, he climbs 6 rungs but due to the devious flames, he has to climb down 10 rungs back. When the fire calms down a little, he climbs 18 rungs to reach the top rung.
How many rungs did the ladder have?
Options:
A)29
B)33
C)21
D)45
E)41
Rationale: A
29 rungs.
Since he is standing on the middle rung in the beginning,
Let the middle rung be x
He climbs 6 rungs first and then climbs down rungs and again climbs 18 rungs to reach the top.
Thus the position is now,
X+6-10+18 = x + 14.
This position is on the top rung.
Thus the ladder has 14 rungs above the middle rung and also it must be having 14 rungs down the middle point as well.
14+14+1 = 29.
Thus there are total 29 rungs in the ladder.
Answer: A
Question: The average weight of 8 person's increases by 6 kg when a new person comes in place of one of them weighing 45 kg. What is the weight of the new person?
Options:
A)90
B)93
C)56
D)80.5
E)78
Rationale: Total increase in weight =8 ×6= 48
If x is the weight of the new person, total increase in weight = x−45
=> 48 = x - 45
=> x =48+45 = 93
ANSWER:B
Answer: B
Question: There are 5 magazines and 4 fiction books. In how many ways can 4 magazines and 2 fiction can be arranged on a shelf?
Options:
A)21400
B)21500
C)21600
D)21700
E)None
Rationale: 4 magazines can be selected out of 5 in 5C4 ways. 2 fiction can be selected out of4 in 4C2 ways. Number of ways of arranging magazines and fiction: = 5C4*4C2 =30 After selecting any 6 books (4 magazines and 2 fiction) in one of the 30 ways, they can be arranged on the shelf in 6!=720 ways. By the Counting Principle, the total number of arrangements =30*720= 21600
Answer C
Answer: C
Question: The sum of four consecutive odd numbers is equal to the sum of 3 consecutive even numbers. Given that the middle term of the even numbers is greater than 101 and lesser than 216, how many such sequences can be formed?
Options:
A)28
B)17
C)25
D)33
E)50
Rationale: Four consecutive odd numbers: k-2, k, k+2, k+4
Three consecutive even numbers: n-2, n, n+2
k-2+k+k+2+k+4=n-2+n+n+2
4k+4=3n
4(k+1)=3n
k+1=(3/4)n
k=(3/4)n-1
All n's that's divisible by 4 will have an integral k. So, we need to find out how many such n's are available within given range:
We know,
101<n<216
104<=n<=212
Count=(212-104)/4+1=108/4+1=27+1=28
Ans: 28.
Answer: A
Question: hree 6 faced dice are thrown together. The probability that all the three show the same number on them is ?
Options:
A)1/39
B)1/36
C)1/32
D)1/287
E)1/29
Rationale: It all 3 numbers have to be same basically we want triplets. 111, 222, 333, 444, 555 and 666. Those are six in number. Further the three dice can fall in 6 * 6 * 6 = 216 ways.
Hence the probability is 6/216 = 1/36
Answer: B
Answer: B
Question: Tanya prepared 4 different letters to be sent to 4 different addresses. For each letter, she prepared an envelope with its correct address. If the 4 letters are to be put into the 4 envelopes at random, what is the probability that only 1 letter will be put into the envelope with its correct address?
Options:
A)1/24
B)1/8
C)1/4
D)1/3
E)3/8
Rationale: Total # of ways of choosing envelopes=4!=24.
Only one letter in the right envelope: 4(# of envelopes)*2(# of ways possible to arrange 3 letters incorrectly in the envelopes, when one is correct)
ABCD(envelopes)
ACDB(letters)
ADBC(letters)
(When A is in the right envelope other three have only 2 possible incorrect arrangements)
As we have 4 letters, total # of ways 4*2=8
P(C=1)=8/24=1/3
Answer:D
Answer: D
Question: A Fruit store sells four varieties of Mangoes. A,B,C & D. IF A Costs 20% less than B, and C costs 25% less than A,and D costs 40% less than C what percent of B's cost is D?
Options:
A)40%
B)38%
C)44%
D)36%
E)42%
Rationale: Soln:-
B=100
A 20% less than B = 80
C 25% less than A = 60
D 40% less than C = 36
D is what percent of B = D/B * 100
= 36/100 * 100 = 36%
ANSWER:D
Answer: D
Question: In what time will a bus 200 m long cross in the road, if its speed be 72 km/hr?
Options:
A)15
B)20
C)14
D)10
E)12
Rationale: Speed = 72 * 5/18 = 20 m/sec
Time taken = 200/20 = 10 sec.
Answer:D
Answer: D
Question: If c is a positive integer, which of the following could NOT be the square of c?
Options:
A)5532
B)9426
C)4966
D)6415
E)3155
Rationale: A number ending in 2 cannot be a perfect square.
5532 ends in a number 2, making that the correct answer
(A) 5532
Answer: A
Question: The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ Rs. 26.50 per metre is Rs. 5300, what is the length of the plot in metres?
Options:
A)238
B)200
C)287
D)117
E)198
Rationale: Let length of plot = L meters, then breadth = L - 20 meters
and perimeter = 2[L + L - 20] = [4L - 40] meters
[4L - 40] * 26.50 = 5300
[4L - 40] = 5300 / 26.50 = 200
4L = 240
L = 240/4= 60 meters.
Answer: B
Answer: B
Question: A shopkeeper has 280 kg of apples. He sells 40% of these at 20% profit and remaining 60% at 30% profit. Find his % profit on total.
Options:
A)24%
B)25%
C)26%
D)28%
E)35%
Rationale: Total number of apples = 280
Let the cost price be x
Selling price at 20% profit = 1.2x
Selling price at 30% profit = 1.3x
Profit % = ((SP - CP)/CP)*100
Profit % = ((2/5)*280*1.2x + (3/5)*280*1.3x - 280x)/280x * 100 = (1/5*(2.4 + 3.9) - 1)*100
= (6.3 - 5)*20 = 26%
Answer: C
Answer: C
Question: There are 35 students in a hostel. If the no. of students increases by 7, the expenses of the mess increase by Rs.42/day while the average expenditure per head diminishes by Rs1. Find the original expenditure of the mess?
Options:
A)Rs. 30
B)Rs. 35
C)Rs. 42
D)Rs. 48
E)Rs. 52
Rationale: Suppose the average join the mess , total expenditure = 35x + 42
Now, the average expenditure = (35x + 42)/ (35 + 7) = x – 1
or, 35x + 42 = 42x – 42
or, x = 12
Thus the original expenditure of the mess = 35 x 12 = Rs. 42
C
Answer: C
Question: A big container is 50% full with water. If 20 liters of water is added, the container becomes 3/4 full. What is the capacity of the big container in liters?
Options:
A)80
B)90
C)100
D)110
E)120
Rationale: 20 liters is 25% of the capacity C.
20 = 0.25C
C = 80 liters.
The answer is A.
Answer: A
Question: If (a – b) is 15 more than (c + d) and (a + b) is 3 less than (c – d), then (a – c) is:
Options:
A)6
B)2
C)3
D)4
E)5
Rationale: (a – b) – (c + d) = 15 and (c – d) – (a + b) = 3
=> (a – c) – (b + d) = 15 and (c – a) – (b + d) = 3
=> (b + d) = (a – c) – 15 and (b + d) = (c – a) – 3
=> (a – c) – 15 = (c – a) – 3 => 2(a – c) = 12 => (a – c) = 6
ANSWER:A
Answer: A
Question: The simple interest accrued on an amount of Rs.49500 at he end of three is Rs.17820. What would be the compound interest accured on the same amount at teh same rate in the same period? (Round off your answer to two decimal places)
Options:
A)20043.94
B)20043.948
C)20043.93
D)20043.92
E)20043.91
Rationale: Let the rate of interest be R% p.a.
(49500)(3)(R)/100 = 17820
495R = 5940
R = 12
CI on Rs.49500 at 12% p.a. for three years
= 49500{[1 + 12/100]3 - 1} = 69543.936 - 49500 = Rs.20043.94
when rounded off to two decimal places.
Answer:A
Answer: A
Question: In Arun's opinion, his weight is greater than 65 kg but leas than 72 kg. His brother does not agree with Arun and he thinks that Arun's weight is greater than 60 kg but less than 70 kg. His mother's view is that his weight cannot be greater than 68 kg. If all of them are correct in their estimation, what is the average of diferent probable weights of Arun ?
Options:
A)66.9 kg
B)66.5 kg
C)66.6 kg
D)86.5 kg
E)66.7 kg
Rationale: Let Arun's weight be X kg.
According to Arun, 65 < X < 72.
According to Arun's brother, 60 < X < 70.
According to Arun's mother, X < 68.
The values satisfying all the above conditions are 66 and 67.
Required average = (66 + 67) / 2 = 66.5 kg
Answer:B
Answer: B
Question: In 1998 the profits of company N were 10 percent of revenues. In 1999, the revenues of company N fell by 30 percent, but profits were 15 percent of revenues. The profits in 1999 were what percent of the profits in 1998?
Options:
A)80%
B)105%
C)120%
D)124.2%
E)138%
Rationale: 0,105R = x/100*0.1R
Answer B
Answer: B
Question: The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 23 years. The present age of the husband is
Options:
A)40
B)34
C)45
D)55
E)65
Rationale: Explanation:
Sum of the present ages of husband, wife and child = (27 * 3 + 3 * 3) years = 90 years.
Sum of the present ages of wife and child = (23 * 2 + 5 * 2) years = 56 years.
Husband's present age = (90 - 56) years = 34 years
Option B
Answer: B
Question: If the price has fallen by 13% what percent of its consumption be: increased so that the expenditure may be the same as before?
Options:
A)11 1/8%
B)11 1/5%
C)14 82/87%
D)14 7/9%
E)21 1/9%
Rationale: 100 â€“ 13 = 87
87------13
100------? => 14 82/87%
Answer: C
Answer: C
Question: Find the probability that the number drawn is a multiple of 6 and 8.
Options:
A)3/50
B)2/25
C)1/50
D)1/25
E)4/25
Rationale: From 1 to 100 there are 4 numbers which are multiples of 6 and 8. (i.e, multiples of 24)
Therefore, required probability = 4 /100
= 1/25
ANSWER:D
Answer: D
Question: The average of first eight prime numbers:
Options:
A)5.6
B)11.2
C)9.625
D)6.3
E)7.4
Rationale: Explanation:
The first eight prime numbers is 2, 3, 5, 7, 11, 13, 17, 19
Average = 77/8 = 9.625
Answer: Option C
Answer: C
Question: In how many ways Chief Minister and Minister be elected from a team of 15 members?
Options:
A)128
B)131
C)132
D)143
E)210
Rationale: To do this, if captain is elected first, then we have 15 ways of doing this.
For election of vice-captain, we have only 14 ways left, coz 1 way is already consumed. (Situations like this is called dependent situation. One selection depends upon other selection.)
So, the ans is 15*14 = 210 ways.
Answer : E
Answer: E
Question: A right triangle has sides of a, b, and 12, respectively, where a and b are both integers. What is the value of (a + b)?
Options:
A)144
B)146
C)148
D)150
E)152
Rationale: LET a= hypotenuse , b =base ,12 = perpendicular . therefore a^2 -b^2 =12^2 or (a+b)(a-b) = 144
a+b =144/a-b ' a-b cannot be zero ..therefore a+ b =144 where a-b is equal to 1
A
Answer: A
Question: Carol spends 1/4 of her savings on a stereo and 2/3 less than she spent on the stereo for a television. What fraction of her savings did she spend on the stereo and television?
Options:
A)1/4
B)2/7
C)5/12
D)1/2
E)7/12
Rationale: Total Savings = S
Amount spent on stereo = (1/4)S
Amount spent on television = (1-2/3)(1/4)S = (1/3)*(1/4)*S = (1/12)S
(Stereo + TV)/Total Savings = S(1/4 + 1/12)/S = 1/4
Answer: A
Answer: A
Question: A milkman sells his milk at CP but he mixes it with water and thereby gains 25%. What is the % of water in the mixture?
Options:
A)10%
B)15%
C)20%
D)30%
E)45%
Rationale: Here Gain= 25%
error = quantity of water he mixes in the milk =x
true value = true quantity of milk = T
So the formula becomes, 25=x(T−x)×100
⇒1=x(T−x)×4⇒T−x=4x⇒T=5x
Percentage of water in the mixture
=xT×100=x5x×100=15×100=20%
C
Answer: C
Question: A person want to give his money of $5400 to his 3 children A,B,C in the ratio 2:3:4. What is the B's share?
Options:
A)$2000
B)$1800
C)$2500
D)$1500
E)$1600
Rationale: B's share = 5400*3/9 = $1800
Answer is B
Answer: B
Question: Find the middle one when The sum of five consecutive even numbers is 75?
Options:
A)16
B)11
C)17
D)16
E)13
Rationale: Let the first number be n
Let the second number be n + 2
Let the third number be n + 4
Let the third number be n + 6
Let the third number be n + 8
n + n + 2 + n + 4 + n + 6 + n + 8= 75
Combine like terms:
5n + 20 = 75
5n = 75 - 20
5n = 55
5n = 55
n = 11
n + 2 = 13
n + 4 = 16
n + 6 = 17
n + 8 = 19
The middle number is 16
Answer: A
Answer: A