divelab/Sys2Bench huggingface dataset:
Question: How many odd integers S between 200 and 600 are there such that their tens digit is even?
Options:
A)20
B)25
C)100
D)150
E)200
Rationale: The hundreds digit can take 4 values: 2, 3, 4 and 5;
The tens digit can take 5 values: 0, 2, 4, 6 and 8;
The units digit can take 5 values: 1, 3, 5, 7 and 9;
Total S: 4*5*5=100.
Answer: C.
Answer: C
Question: A bus takes 2 hours to cover a distance of 180 Km. how much should the speed in Kmph be maintained to cover the same direction in 5/2th of the previous time?
Options:
A)50 Kmph
B)60 Kmph
C)36 Kmph
D)25 Kmph
E)70 Kmph
Rationale: Time = 2
Distance = 180
5/2 of 2 hours = 2 * 5/2 = 5 Hours
Required speed = 180/5 = 36 Kmph
C
Answer: C
Question: The L.C.M. of 2 numbers is 100. The numbers are in the ratio 4:1. Find their product?
Options:
A)1200
B)2000
C)2500
D)3200
E)1250
Rationale: Let the numbers be 4x and x
L.C.M. = 4x
4x = 100
x = 25
The numbers are = 100 and 25
Required product = 100*25 = 2500
Answer is C
Answer: C
Question: A 14% stock yielding 10% is quoted at :
Options:
A)83.33
B)110
C)112
D)140
E)160
Rationale: Solution
To earn Rs. 10, money invested = Rs. 100.
To earn Rs. 14, money invested = Rs.(100/10X14) = Rs. 140.
âˆ´ Market value of Rs. 100 stock =Rs. 140
Answer D
Answer: D
Question: A salesman's income consists of a commission and a base salary of $400 per week. Over the past 5 weeks, his weekly income totals have been $406, $413, $420, $436 and $395. What must his average (arithmetic mean) commission be per week over the next two weeks so that his average weekly income is $500 over the 7-week period?
Options:
A)$150
B)$245
C)$365
D)$315
E)$730
Rationale: Total weekly income over 5 weeks=$406+$413+$420+$436+$395=$2070
For avg weekly income to be $500 over 7 weeks, we need total weekly income over 7 weeks=$3500
Now, $3500-$2070=$1430
From this, we subtract base salary for 2 weeks i.e $350*2=$700
Therefore, commission=$1430-$800=$630 for 2 weeks
Avg weekly commission=$315
Answer D
Answer: D
Question: A train speeds past a pole in 15 seconds and a platform 100 m long in 25 seconds. Its length is:
Options:
A)227
B)277
C)266
D)150
E)881
Rationale: Let the length of the train be x meters and its speed be y m/sec.
They, x / y = 15 => y = x/15
x + 100 / 25 = x / 15
x = 150 m.
Answer: D
Answer: D
Question: The average (arithmetic mean) of four numbers is 4x + 3. If one of the numbers is x, what is the average of the other three numbers?
Options:
A)x + 1
B)3x + 3
C)5x + 1
D)5x + 4
E)15x + 12
Rationale: If the average of four numbers is 4x + 3, then the sum of all four numbers if 4 * (4x + 3) = 16x + 12. If one of the numbers is x, then the average of the remaining three numbers would be: (16x + 12 - x)/3 = (15x + 12)/3 = 5x + 4.
Answer is D.
Answer: D
Question: What annual payment will discharge a debt of Rs. 1025 due in 2 years at the rate of 5% compound interest?
Options:
A)Rs. 560
B)Rs. 560.75
C)Rs. 551.25
D)Rs. 550
E)Rs. 560
Rationale: Explanation:
Present worth of Rs. x due T years hence is given by
Present Worth (PW) = x/(1+R/100)T
Let x be the annual payment
Then, present worth of x due 1 year hence + present worth of x due 2 year hence = 1025
x(1 + 5/100)1 + x(1 + 5/100)2 = 1025 x/(21/20) + x/(21/20)2 = 1025
20x/21 + 400x/441 = 1025
820x/441 = 1025
x = (1025 × 441)/820
= (205 × 441)/164
= Rs. 551.25
Answer: Option C
Answer: C
Question: You are renting an apartment and you need √676 for each side, how many feet are you looking to measure?
Options:
A)21
B)22
C)23
D)24
E)26
Rationale: Try filling the numbers into the answer y x y =
Find the closest to 676.
Answer E
Answer: E
Question: A tank contains 10,000 gallons of a solution that is 5 percent sodium chloride by volume. If 2,500 gallons of water evaporate from the tank, the remaining solution will be approximately what percent sodium chloride?
Options:
A)1.25%
B)3.75%
C)6.25%
D)6.67%
E)11.7%
Rationale: 10000 gallons solution has
500 gallons sodium chloride
9500 gallons water
=> 2500 gallons water evaporates
=> 7000 gallons water remains
hence, concentration of sodium chloride is 500/7500 = 6.67%
ANSWER:D
Answer: D
Question: If 60% of (x-y) = 20% of (x+y), then what percent of x is y?
Options:
A)50%
B)44.4%
C)22.2%
D)33.3%
E)25%
Rationale: 60% of (x-y) = 20% of (x+y)
60/100 (x-y) = 20/100 (x+y)
4x = 8y
Required percentage = y/x *100 = 4y/8y * 100 = 50%
Answer is A
Answer: A
Question: A man has $ 10,000 to invest. He invests $ 4000 at 5 % and $ 3500 at 4 %. In order to have a yearly income of $ 500, he must invest the remainder at
Options:
A) 6 %
B) 6.1 %
C) 6.2 %
D) 6.3 %
E) 6.4 %
Rationale: Income from $ 4000 at 5 % in one year = $ 4000 of 5 %.
= $ 4000 × 5/100.
= $ 4000 × 0.05.
= $ 200.
Income from $ 3500 at 4 % in one year = $ 3500 of 4 %.
= $ 3500 × 4/100.
= $ 3500 × 0.04.
= $ 140.
Total income from 4000 at 5 % and 3500 at 4 % = $ 200 + $ 140 = $ 340.
Remaining income amount in order to have a yearly income of $ 500 = $ 500 - $ 340.
= $ 160.
Total invested amount = $ 4000 + $ 3500 = $7500.
Remaining invest amount = $ 10000 - $ 7500 = $ 2500.
We know that, Interest = Principal × Rate × Time
Interest = $ 160,
Principal = $ 2500,
Rate = r [we need to find the value of r],
Time = 1 year.
160 = 2500 × r × 1.
160 = 2500r
160/2500 = 2500r/2500 [divide both sides by 2500]
0.064 = r
r = 0.064
Change it to a percent by moving the decimal to the right two places r = 6.4 %
Therefore, he invested the remaining amount $ 2500 at 6.4 % in order to get $ 500 income every year.
The answer is (E)
Answer: E
Question: The radius of a semi circle is 4.8 cm then its perimeter is?
Options:
A)32.51
B)32.4
C)32.1
D)32.92
E)24.69
Rationale: 36/7 r = 4.8 = 24.69
Answer:E
Answer: E
Question: The speed of a boat in still water is 60kmph and the speed of the current is 20kmph. Find the speed downstream and upstream?
A. 35, 25 kmph
Options:
A)76 kmph
B)40 kmph
C)29 kmph
D)26 kmph
E)12 kmph
Rationale: Speed downstream = 60 + 20
= 80 kmph
Speed upstream = 60 - 20
= 40 kmph
Answer: B
Answer: B
Question: Set C is composed of nine numbers, labeled C1 through C9. Set D is also composed of nine numbers, labeled D1 through D9. Set D is defined as follows: D1 = 1 + C1; D2 = 2 + C2; and so on, including D9 = 9 +C9. How much larger is the sum of set D's mean and range than the sum of set C's mean and range?
Options:
A)12
B)6
C)8
D)4
E)cannot be determined
Rationale: Yes, the correct answer is E
Answer: E
Question: John makes $60 a week from his job. He earns a raise andnow makes $70 a week. What is the % increase?
Options:
A)16.12%
B)16.66%
C)16.56%
D)17.66%
E)18.1%
Rationale: Increase = (10/60)*100 = (1/6)*100 = 16.66%.
B
Answer: B
Question: A teacher prepares a test. She gives 7 objective type questions out of which 4 have to be answered. Find the total ways in which they can be answered if the first 2 questions have 3 choices and the last 5 have 4 choices.
Options:
A)4255
B)5280
C)1920
D)1000
E)4144
Rationale: Two cases.
First Case: 2 Questions - 3 Choices, 2 Questions - 4 Choices
2C2 * 5C2 ways to select the questions
3C1 * 3C1 * 4C1 * 4C1 ways to answer the questions
= 1 * 10 * 3 * 3 * 4 * 4
=1440
Second Case: 1 Question - 3 Choices, 3 Questions - 4 Choices
2C1 * 5C3 ways to select the questions
3C1 * 4C1 * 4C1 * 4C1 ways to answer the questions
= 2 * 10 * 3 * 4 * 4 * 4
= 3840
Total = 3840 + 1440=5280
B
Answer: B
Question: In how many ways a team of 11 must be selected a team 5 men and 11 women such that the team must comprise of not more than 3 men.
Options:
A)22399
B)2256
C)2700
D)279078
E)2911
Rationale: Maximum 3 men can be played which means there can be 0, 1, 2, 3 men in the team.
(5C0×11C11)+(5C1×11C10)+(5C2×11C9)+(5C3×11C8)=2256(5C0×11C11)+(5C1×11C10)+(5C2×11C9)+(5C3×11C8)=2256
Answer:B
Answer: B
Question: Tough and Tricky questions: Percents.
Over the course of a year, a certain microbrewery increased its beer output by 90 percent. At the same time, it decreased its total working hours by 5 percent. By what percent did this factory increase its output per hour?
Options:
A)200
B)100
C)300
D)400
E)500
Rationale: Lets assume the initial production was 100 litres of beer for 100 hr.
With the 90% increase the total amount of beer production will be 190 litres and with 5 % decrease in total hours will be reduced to 95 hr.
100hr ----> 100 lts
1hr -----> 1 lts
95hr -----> 190 lts
1hr -----> 2 lts
Total Increase in production for 1 hr = 200%
Answer A
Answer: A
Question: Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B?
Options:
A)6400
B)2388
C)3777
D)2992
E)2781
Rationale: Explanation:
Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 - x).
Then,
=> 28x - 22x = 350800 - (13900 x 22)
=> 6x = 45000
=> x = 7500.
So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.
Answer: A) Rs.6400
Answer: A
Question: In how many ways Chief Minister and Minister be elected from a team of 10 members?
Options:
A)128
B)90
C)132
D)143
E)145
Rationale: To do this, if captain is elected first, then we have 10 ways of doing this.
For election of vice-captain, we have only 9 ways left, coz 1 way is already consumed. (Situations like this is called dependent situation. One selection depends upon other selection.)
So, the ans is 10*9 = 90 ways.
Answer : B
Answer: B
Question: Elena purchased Brand X pens for $4.00 apiece and brand Y for $2.80 apiece. If Elena purchased a total of 12 of these pens for $40.00, how many brand X pens did she purchase?
Options:
A)4
B)5
C)6
D)7
E)8
Rationale: 4x+2.8y=42 --> multiply by 2.5 (to get the integers) --> 10x+7y=105 --> only one positive integers solutions x=8 and y=5 (how to solve: 7y must have the last digit of 5 in order the last digit of the sum to be 5).
Answer: E.
Answer: E
Question: Irin, Ingrid and Nell bake chocolate chip cookies in the ratio of 9.18: 5.17: 2.05. If altogether they baked a batch of 148 cookies, what percent of the cookies did Ingrid bake?
Options:
A)0.125%
B)1.25%
C)31%
D)125%
E)0.152%
Rationale: 9.18x+5.17x+2.05x = 16.4x = 148 cookies
x= 148/16.4 = 9 (approx)
So, Ingrid baked 9*5.17 cookies or 46 cookies (approx)
% share = 46/148 = 31 approx
Hence, answer is C.
Answer: C
Question: Following an increase in prices, the price of a candy box was 10 pounds and the price of a can of soda was 15 pounds. If the price of a candy box was raised by 25%, and the price of a can of soda was raised by 50%. What was the price of a box of candy plus a can of soda before prices were raised?
Options:
A)11.
B)12.
C)13.
D)18.
E)14.5
Rationale: Price of candy before price increase= 10/1.25= 8
Price of soda before price increase= 15/1.5= 10
Total price = 8+10= 18
D is the answer
Answer: D
Question: A cistern can be filled by a tap in 4 hours while it can be emptied by another tap in 9 hours. If both the taps are opened simultaneously, then after how much time will the cistern get filled?
Options:
A)3.9 hrs
B)2.8 hrs
C)3.7 hrs
D)7.2 hrs
E)2.5 hrs
Rationale: Net part filled in 1 hour = (1/4 - 1/9) = 5/36
The cistern will be filled in 36/5 hrs i.e., 7.2 hrs.
Answer: D
Answer: D
Question: The ratio between the length and the breadth of a rectangular park is 4 : 1. If a man cycling along the boundary of the park at the speed of 12 km/hr completes one round in 8 min, then the area of the park (in sq. m) is?
Options:
A)1024545 m
B)134561 m
C)156787 m
D)15450 m
E)102400 m
Rationale: Perimeter = Distance covered in 8 min. = 12000 x 8 m = 1600 m.
60
Let length = 4x metres and breadth = 1x metres.
Then, 2(4x + 1x) = 1600 or x = 160.
Length = 640 m and Breadth = 160 m.
Area = (640 x 160) m2 = 102400 m
E
Answer: E
Question: Look at this series: 201, 202, 204, 207, ... What number should come next?
Options:
A)234
B)134
C)351
D)211
E)413
Rationale: D
211
In this addition series, 1 is added to the first number; 2 is added to the second number; 3 is added to the third number; 4 is added to the fourth number; and go on.
Answer: D
Question: How many diagonals does a polygon with 19 sides have, if one of its vertices does not connect to any diagonal?
Options:
A)135
B)125
C)120
D)110
E)140
Rationale: If I calculate it using the formulae, #diagonals = n (n-3)/2Each vertex sends of n-3 diagonals
n= 19-1 then 18*(18-3)/2 = 135
Correct Option:	A
Answer: A
Question: A car covers a distance of 624 km in 6 ½ hours. Find its speed?
Options:
A)104
B)277
C)298
D)269
E)213
Rationale: 624/6 = 104 kmph
Answer:A
Answer: A
Question: 2^2*3^2*2^3*3^2*5^2 =
Options:
A)3^5*2^5
B)2^9*3^4
C)2^4*3^9
D)5^8
E)6^10
Rationale: 2^2*3^3*2^3*3^2 =
A) 3^5*2^5
B) 2^9*3^4
C) 2^4*3^9
D) 2^5*3^4*5^2
E) 6^10
If the base is same, powers are added so that follows D) 2^2*3^2*2^3*3^2*5^2 =.
Hence the answer is D
Answer: D
Question: Today is Thursday. The day after 53 days will be?
Options:
A)Monday
B)Tuesday
C)Saturday
D)Sunday
E)wednesday
Rationale: Explanation:
53 days = 7 weeks 4 days = 4 odd days
Hence if today is Thursday, After 53 days, it will be = (Thursday + 4 odd days)
= Monday
Answer: Option A
Answer: A
Question: The sum of ages of 5 children born at the intervals of 3 years each is 80 years. What is the age of the youngest child?
Options:
A)3 years
B)4 years
C)6 years
D)7 years
E)10 years
Rationale: Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 80
5x = 50
x = 10.
Age of the youngest child = x = 10 years.
E)
Answer: E
Question: Two persons A and B take a field on rent. A puts on it 21 horses for 3 months and 15 cows for 2 months; B puts 15 cows for 6months and 40 sheep for 7 1/2 months. If one day, 3 horses eat as much as 5 cows and 6 cows as much as 10 sheep, what part of the rent should A pay?
Options:
A)1/3
B)1/8
C)1/2
D)1/5
E)1/9
Rationale: 3h = 5c
6c = 10s
A = 21h*3 + 15c*2
= 63h + 30c
= 105c + 30c = 135c
B = 15c*6 + 40s*7 1/2
= 90c + 300s
= 90c + 180c = 270c
A:B = 135:270
27:52
A = 27/79 = 1/3
Answer:A
Answer: A
Question: A train 510 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 140 m long?
Options:
A)52
B)56
C)41
D)42
E)34
Rationale: Speed = 45 * 5/18 = 25/2 m/sec
Total distance covered = 360 + 140 = 500 m
Required time = 550 * 2/25 = 52 sec
Answer: Option A
Answer: A
Question: The reflex angle between the hands of a clock at 10.25 is
Options:
A)197 1/2
B)197 1/9
C)197 1/2
D)167 1/3
E)197 1/6
Rationale: Explanation:
Angle traced by hour hand in 125/12 hrs = (360/12 * 125/12) =
Angle traced by minute hand in 25 min = (360/60 * 25) =
Reflex angle =
Answer: A) 197 1/2
Answer: A
Question: Three cubes of metal whose edges are 9, 12 and 24 cm respectively, are melted and one new cube is made. Find the edge of the new cube?
Options:
A)28
B)77
C)66
D)18
E)25.3
Rationale: 93 + 123 + 243 = a3 => a
= 25.3
Answer: E
Answer: E
Question: If a and b are positive integers, and (2^3)(3^4)(5^7)=(a^3)∗b, how many different possible values of b are there?
Options:
A)2
B)3
C)4
D)6
E)12
Rationale: Let's assume 2^3,3^3 and 5^3 as three different entities.
The entity 5^3 is there twice.
Thus, out of these three, we can take none, 1, two or all three. This gives a total of :
3C0+3C1+3C2+3C3 = 1+3+3+1 = 8 ways. Now the other 5^3 will not make a difference when being selected in the mentioned way. It will only make a difference when it is either selected with5^3 only(1 case), or when both of them together are considered with either 2^3(1 case) or 3^3(1 case). Finally, when all the 4 are considered together, we have one final case. Thus a total of 8+3+1 = 12 cases.
ANSWER:E
Answer: E
Question: A house is to be constructed in 46 days and 117 men were set to work, each working 8 hours a day. After 33 days, 4/7 of the work is completed. How many additional men may be employed so that the work may be completed in time, each man now working 9 hours a day?
Options:
A)76
B)64
C)81
D)120
E)None of these
Rationale: Explanation :
Solution: Remaining work = (1-4/7) = 3/7. remaining period =(46-33)days = 13 days.
Let the total men working at it be x.
Less work, less men (Direct proportion)
Less days, more men (Indirect proportion)
More hrs/day, less men (Indirect proportion)
work 4/7 : 3/7
Days 13 : 33 } : : 117 : x
Hrs/Day 9 : 8
.'. 4/7*13*9*x = 3/7*33*8*117 or x = ((3*33*8*117)/4*13*9) = 198.
.'. Additional men to be employed = (198-117) = 81.
Answer : C
Answer: C
Question: The length of a rectangle is reduced by 10%. By what % would the width have to be increased to maintain the original area?
Options:
A)10%
B)11.1%
C)25%
D)30%
E)35%
Rationale: Sol. Required change = (10*100)/(100-10)=11.1%
B
Answer: B
Question: Find the amount on Rs.9000 in 2 years, the rate of interest being 4% per first year and 5% for the second year?
Options:
A)5568
B)9828
C)5460
D)5635
E)6734
Rationale: 9000 * 104/100 * 105/100
=> 9828
Answer:B
Answer: B
Question: The simple interest on a sum of money is 4/9 of the principal and the number of years is equal to the rate percent. Find the rate and the time?
Options:
A)6 2/3%
B)6 2/7%
C)6 2/2%
D)6 3/3%
E)6 5/3%
Rationale: 4/9 P = (P*R*R)/100
R = 20/3 = 6 2/3%
Answer: A
Answer: A
Question: There are three foam generators in the factory, each of the first two can generate 12 liters of foam in one hour and the third can generate 18 liters in an hour. The three generators start working together at the same time and after one hour and a half one of the first generators stops working and two hours after that the third generator stops working and only one generator is left. If 5 hours after they all started to work the last generator stops working, how many liters of foam were generated?
Options:
A)120.
B)132.
C)141
D)154.
E)166.
Rationale: Let the foam generators capacity be -
A = 12 lit/hr
B = 12 lit/hr
C = 18 lit/hr
Total foam generation in 1 hour will be 42 lit ( 12 + 12 + 18 ) ; since in 1 and 1/2 hr they will generate 42 + 21 => 63 litres...
Now one of the first generators stops working ( Say A stops working ) , so we have -
B = 12 lit/hr
C = 18 lit/hr
Total foam generation in 2 hour will be 60 litres {2 (12+18)}
The third generator stops working and now only B works for the remaining time 1 and 1/2 ( 5 - 1 and 1/2 - 2 )...
Foam generated by B will be 3/2 * 12 => 18 litres
So, total foam generated will be 141 Litres ( 63 + 60 + 18 ) ; hence answer will be (C)
Answer: C
Question: A man spend 1/5 of his salary on food , 1/10 of his salary on house rent and 3/5 salary on clothes. he still has $17000 left with him. find salary..
Options:
A)$10700
B)$17000
C)$180000
D)$1700
E)$170000
Rationale: [1/(x1 / y1 + x2/y2 + x3/y3)] * Total amount= Balance amount
[1-(1/5 + 1/10 + 3/5)} * total salary= $17000, = [1-9/10] * Total salary = $17000, Total salary = $17000*10 = $180000, correct answer (E)
Answer: E
Question: Oranges are bought at 7 for Rs.5. At what rate per hundred must they be sold to gain 33%?
Options:
A)57
B)58
C)69
D)84
E)95
Rationale: 7 oranges bought for rs 5
1 orange cost =5/7
therefore for 100 oranges =100*(5/7)
gain =33%
500/7+(33/100)*500/7=rate per hundred he want to sell
ans :95
ANSWER:E
Answer: E
Question: A trader sells 85 meters of cloth for Rs. 8925 at the profit of Rs. 15 per metre of cloth. What is the cost price of one metre of cloth?
Options:
A)22
B)75
C)90
D)78
E)11
Rationale: SP of 1m of cloth = 8925/85 = Rs. 105
CP of 1m of cloth = SP of 1m of cloth - profit on 1m of cloth
= Rs. 105 - Rs. 15 = Rs. 90.
Answer: C
Answer: C
Question: If the ratio of apples to bananas is 3 to 2 and the ratio of bananas to cucumbers is 1 to 3, what is the ratio of apples to cucumbers?
Options:
A)2:3
B)1:2
C)3:5
D)2:5
E)5:6
Rationale: The ratio of bananas to cucumbers is 1 to 3 which equals 2 to 6.
The ratio of apples to bananas to cucumbers is 3 to 2 to 6.
The ratio of apples to cucumbers is 3 to 6 which equals 1:2.
The answer is B.
Answer: B
Question: A rectangular table seats 4 people on each of two sides, with every person directly facing another person across the table. If eight people choose their seats at random, what is probability that any two of them directly face other?
Options:
A)1/56
B)1/8
C)1/7
D)15/56
E)4/7
Rationale: A B C D
------------
| TABLE |
------------
E F G H
A to H are 8 people.
Prob to select any 1 person = 1
Prob to select the person opposite to the chosen person = 1/7
For ex. If we select A as the person than prob of choosing E is 1/7.
Hence, answer will be C.
Answer: C
Question: Two pipes A and B can fill a tank in 36 min. and 45 min. respectively. A water pipe C can empty the tank in 30 min. First A and B are opened. After 7 minutes, C is also opened. In how much time, the tank is full?
Options:
A)43 min
B)44 min
C)45 min
D)46 min
E)47 min
Rationale: part filled in 7 min= 7*(1/36+1/45) =7/20
remaining part= 1-7/20 =13/20
net part filled by pipes A,B,C=(1/36+1/45-1/30) =1/60 (in 1 min.)
13/20 part is filled in = 60*13/20 =39 min
total time taken to fill the tank = 39+7 =46 min
ans = 46 min.
ANSWER:D
Answer: D
Question: Ronald and Elan are working on an assignment. Ronald takes 6 hrs to type 32 pages on a computer, while Elan takes 5 hrs to type 40 pages. How much time will they take, working together on two different computers to type an assignment of 110 pages?
Options:
A)8 hrs 85 min
B)8 hrs 18 min
C)8 hrs 15 min
D)6 hrs 15 min
E)3 hrs 15 min
Rationale: Number of pages typed by Ronald in 1 hour = 32/6 = 16/3
Number of pages typed by Elan in 1 hour = 40/5 = 8
Number of pages typed by both in 1 hour = (16/3 + 8) = 40/3
Time taken by both to type 110 pages = (110 * 3/40) = 8 1/4 = 8 hrs 15 min
Answer:C
Answer: C
Question: Question:	By selling an mobile for Rs. 3000, a shop keeper gains 20%. During a clearance sale, the shopkeeper allows a discount of 10% on the marked price. His gain percent during the sale is?
Options:
A	7%.
B	9%.
C	8%.
D	2%.
E	3%.
Options:
A)9%
B)2%
C)3%
D)7%
E)8%
Rationale: Explanation:
Marked price = Rs. 3000
C.P. = 100/120 * 3000 = Rs. 2500
Sale price = 90% of Rs. 3000 = Rs. 2700
Required gain % = 20/2500 * 100 = 8%.
Answer: E
Answer: E
Question: Alex deposited x dollars into a new account that earned 6 percent annual interest, compounded annually. One year later Alex deposited an additional x dollars into the account. If there were no other transactions and if the account contained w dollars at the end of two years, which of the following expresses x in terms of w ?
Options:
A)w/(1+1.08)
B)w/(1.08+1.16)
C)w/(1.16+1.24)
D)w/(1.08^2+1.08^2)
E)w/(1.06+1.06^2)
Rationale: Account at the end of the first year would be 1.06x dollars. At this time x dollars was deposited, hence the account at the beginning of the second year would be (1.06x+x) dollars. Account at the end of the second year would be (1.06x+x)*1.06=w --> x(1.06^2+1.06)=w --> x=w/(1.06+1.06^2).
Answer: E.
Answer: E
Question: Cubes with each side one inch long are glued together to form a larger cube. The larger cube's face is painted with red color and the entire assembly is taken apart. 25 small cubes are found with no paints on them . How many of unit cubes have at least one face that is painted red?
Options:
A)64
B)72
C)86
D)98
E)100
Rationale: Use the options.
The options which after getting added to 25 shows a cube of a number could be right.
Here
64+25 = 89
72+25 = 97
86+25 = 111
98+25 = 123
100+25=125 ---(5*5*5)
So we have 100 as the answer!
E
Answer: E
Question: The sum of all possible two digit numbers formed from
three different one digit natural numbers when divided by
the sum of the original three numbers is equal to?
Options:
A)14
B)16
C)18
D)20
E)22
Rationale: Let the one digit numbers x,y,z
Sum of all possible two digit numbers
=(10x+y)+(10x+z)+(10y+x)+(10y+z)+(10z+x)+(10z+y) = 22(x+y+z)
Therefore sum of all possible two digit numbers when
divided by sum of one digit numbers gives 22.
ANSWER E
Answer: E
Question: Which of the following MUST yield a fractional integer when divided by 4?
Options:
A)The sum of four consecutive positive integers.
B)The square of a prime number.
C)The sum of two odd integers.
D)The product of three consecutive odd numbers.
E)The difference between a multiple of 8 and a multiple of 3.
Rationale: Hence A is true. No need to check other answers since there can only be one correct answer.
So, Ans(A).
Answer: A