divelab/Sys2Bench huggingface dataset:
Question: If the cost of x metres of wire is d rupees, then what is the cost of y metres of wire at the same rate?
Options:
A)Rs.(yd/U)
B)Rs.(yI/x)
C)Rs.(Od/x)
D)Rs.(yd/x)
E)Rs.(yd/D)
Rationale: Cost of x metres = Rs. d.
Cost of 1 metre = Rs. d
x
Cost of y metres = Rs. d	. y = Rs. yd	.
x	x
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Answer:D
Answer: D
Question: An investor receives a total combined return of 7% on his two different investments. On his $10,000 investment he receives a return of 6%. What is the return on his $20,000 investment?
Options:
A)7.25%
B)7.5%
C)8%
D)8.5%
E)9%
Rationale: Total investment = $30000
on which he receives 7% = 2100
now,
on his $10000 he receives 6% = $600
remaining $1500
which is (1500/20000)*100 = 7.5
ANSWER:B
Answer: B
Question: A train 320 m in length crosses a telegraph post in 16 seconds. The speed of the train is?
Options:
A)22 kmph
B)77 kmph
C)54 kmph
D)72 kmph
E)88 kmph
Rationale: S = 320/16 * 18/5 = 72 kmph
Answer:D
Answer: D
Question: P is able to do a piece of work in 5 days and Q can do the same work in 10 days. If they can work together for 3 days, what is the fraction of work completed?
Options:
A)13/10
B)4/5
C)11/10
D)7/10
E)9/10
Rationale: Explanation :
Amount of work P can do in 1 day = 1/5
Amount of work Q can do in 1 day = 1/10
Amount of work P and Q can do in 1 day = 1/5 + 1/10 = 3/10
Amount of work P and Q can together do in 3 days = 3 × (3/10) = 9/10
Answer : Option E
Answer: E
Question: If 50 percent of X is 25 percent of Y, then what is the relation between X and Y?
Options:
A)X=Y
B)2X=Y
C)X=2Y
D)1
E)NONE OF ABOVE
Rationale: 50/100(X) = 25/100(Y)
2X=Y..
Option B.
Answer: B
Question: In a game of billiards, A can give B 20 points in 60 and he can give C 30 points in 60. How many points can B give C in a game of 100?
Options:
A)22
B)28
C)025
D)20
E)11
Rationale: A scores 60 while B score 40 and C scores 30.
The number of points that C scores when B scores 100 = (100 * 30)/40 = 25 * 3 = 75.
In a game of 100 points, B gives (100 - 75) = 25 points to C.
Answer: C
Answer: C
Question: A dozen bananas and 10 pounds of oranges are currently at the same price. If the price of a dozen bananas rises by 20 percent and the price of oranges rises by 4 %. How much more will it cost to buy a dozen bananas and 10 pounds of oranges.
Options:
A)24%
B)22%
C)23%
D)25%
E)29%
Rationale: Say currently both a dozen bananas and 10 pounds of oranges cost $100 (they are at the same price). So, to buy a dozen bananas and 10 pounds of oranges we need $200.
After the increase, the price of a dozen bananas will be $120 and the price of 10 pounds of oranges will be $104. So after the increase, to buy a dozen bananas and 10 pounds of oranges we'll need $224.
Increase = 24%.
Answer: A.
Answer: A
Question: What is the rate percent when the simple interest on Rs.4000 amount to Rs.640 in 2 Years?
Options:
A)8.2%
B)8%
C)8.5%
D)9%
E)9.5%
Rationale: Interest for 1 year = 640/2 = 320
Interest on Rs 4000 p/a = 320
interest rate = 320/4000*100 = 8%
Answer : B
Answer: B
Question: If x is divisible by 20, 14, and 70, which of the following must be the least multiple of x?
Options:
A)70
B)140
C)210
D)350
E)700
Rationale: We are looking for the LCM (which is not 0) of 20 = 2^2*5, 70 = 2*7*5, 14 = 2*7:
2^2 * 5 * 7 = 140
The answer is B.
Answer: B
Question: The longest side of a triangle is 3 times the shortest side and the third side is 2 cm shorter than the longest side. If the perimeter of the triangle is at least 61 cm,What is the minimum length of the shortest side?
Options:
A)8cm
B)9cm
C)10cm
D)11cm
E)12cm
Rationale: let the shortest measurement be x cm
then the largest side will be 3x cm
and the third side will be (3x-2)cm
now according to the problem
x+3x+3x-2 >=61
7x-2 >= 61
7x >= 63
therefore x>=9cm
ANSWER:B
Answer: B
Question: Let the function T(n) represent the product of the first n prime numbers, where n > 0. If x = T(n) + 1, which of the following must be true?
(i) x is always odd
(ii) x is always prime
(iii) x is never the square of an integer
Options:
A)ii only
B)iii only
C)i and ii only
D)i and iii only
E)ii and iii only
Rationale: T(n) is always even, because the first prime is 2 and no matter what n is, 2 always will be a divisor of T(n). Thus, T(n) + 1 = even + 1 = odd. So, (i) is always true.
Now, use logic:
If (ii) is true (so if x is always prime), then (iii) must automatically be true: no prime is the square of an integer. So, the correct answer must be i only; i, ii, and iii only; or i and iii only. since onlyi and iii onlyis among the options, then it must be true.
Or, since (i) is always true, then from options the answer must be either C or D. C cannot be correct because if (ii) is true, then so must be (iii). Thus only D remains.
Answer: D.
Answer: D
Question: A rower can row upstream at 15 kph and downstream at 35 kph. What is the speed of the rower in still water?
Options:
A)22
B)23
C)24
D)25
E)26
Rationale: Let V be the rower's speed in still water.
Let S be the speed of the current in the stream
V-S = 15
V+S = 35
When we add the two equations, we get: 2V = 50
Then V = 25 kph.
The answer is D.
Answer: D
Question: A university cafeteria offers 5 flavors of pizza - pork,pepperoni, chicken, Hawaiian and vegetarian. If a customer has an option (but not the obligation) to add extra cheese, mushrooms or both to any kind of pizza, how many different pizza varieties are available ?
Options:
A)4
B)8
C)12
D)25
E)32
Rationale: 5 flavours * 5 choices = 5C1*5C1 = 5*5=25=D
Answer: D
Question: A man goes from A to B at a speed of 20 kmph and comes back to A at a speed of 30 kmph. Find his average speed for the entire journey?
Options:
A)24 kmph
B)22 kmph
C)23 kmph
D)21 kmph
E)25 kmph
Rationale: A
24 kmph
Distance from A and B be 'd'
Average Speed = total distance/total time
Average Speed = (2d)/[(d/20) + (d/30)]
= (2d)/[5d/60) => 24 kmph.
Answer: A
Question: A certain car can travel 40 kilometers on a liter of fuel. If the fuel tank’s contents decrease by 3.9 gallons over a period of 5.7 hours as the car moves at a constant speed, how fast is the car moving, in miles per hour? (1 gallon = 3.8 liters; 1 mile = 1.6 kilometers)
Options:
A)52
B)65
C)78
D)91
E)104
Rationale: Fuel used 3.9 gallons ;convert to liters--> 3.9 x 3.8 liters
Time = 5.7 hours
1 mile = 1.6 kilometers ;convert to miles--> 1km = 1/1.6 mile
Speed (km/hour)= D/T = 40 (km*) x 3.9 x 3.8 / 5.7
replace (km*) to miles ; multiply by 1/1.6 mile
Speed (miles/hour)= 40 x 3.9 x 3.8 / 5.7 x 1.6 = 78 miles/hour
Ans :C
PS :i felt the factors were easy to cancel out ,so didn't require much rounding off
= 40 x 3.9 x 3.8 / 5.7 x 1.6
= 65
B
Answer: B
Question: An area of a circularplace is 17 hectares. Find the cost of fencing it at the rate of Rs. 3 permeter approximately.
Options:
A)Rs. 4000
B)Rs. 4450
C)Rs. 4457
D)Rs. 4560
E)Rs. 5457
Rationale: Area = (17.56 x 10000) m2= 175600 m2.
ΠR2 = 175600 ⇔ (R)2 = (175600 x (7/22)) ⇔ R = 236.37 m.
Circumference = 2ΠR = (2 x (22/7) x 236.37) m =1485.78 m.
Cost of fencing = Rs. (1485.78 x 3) = Rs. 4457.
C
Answer: C
Question: A 12 month project had a total budget of $18,000. After five months, the project had spent $6,400. At this point, how much was the project under budget?
Options:
A)$1000
B)$1100
C)$1200
D)$1300
E)$1400
Rationale: Each month, the project should spend $18,000 / 12 = $1500.
In 5 months, the project should spend 5*$1500=$7500.
The project is under budget by $7500 - $6400 = $1100.
The answer is B.
Answer: B
Question: Dana borrows 6500 pounds annually for her college education. If Dana gives her parents 3% of that amount back each month, how much will she still owe her parents after four years of college?
Options:
A)16240
B)16340
C)16440
D)16540
E)16640
Rationale: dana borrows 6500 and returns 3% per month.
so returns 195 per month. and 2340 per year.
so dana owes 6500-2340=4160 per year.
after 4 years she will owe 16640.
Ans (E)
Answer: E
Question: A work could be completed in 100days by x workers. However, due to the absence of 10workers, it was completed in 110days. The original no.of workers was:
Options:
A)90
B)100
C)110
D)134
E)154
Rationale: sax Letlheo g alnumberofworkers hex
x workers can do the wor - 100 days
(x — 10) workers can do the work in 110 days
4 100x 1u1x— 10)
1100 Q x 110
C
Answer: C
Question: When m is divided by 9, the remainder is 4. When m is divided by 13, the remainder is 10. If 1 < m < 200, what is the greatest possible value of m?
Options:
A)47
B)65
C)103
D)117
E)166
Rationale: Looking at the choices, options BD can be eliminated as they are divisible by 13
Starting from the highest number 164;
166 = 162 + 4 (162 divisible by 9)
166 = 156 + 10 (156 divisible by 13)
it fits the result
Answer = E
Answer: E
Question: Tough and Tricky questions: Exponents.
If a and b are positive integers and x = 24^a and y = 9^b, which of the following is a possible units digit of xy?
Options:
A)1
B)6
C)5
D)7
E)8
Rationale: Only Units digit of X and Y contribute to the Units digit of XY.
Finding all values ofXfor positive values ofa
When,
a=1; X=24
a=2; X=576
a=3; X=13824........ Units digit repeat in a cycle of 4,6,4,6......
Similarly, Finding all values ofYfor positive values ofb
When,
b=1; Y=9
b=2; Y= 81
b=3; Y= 729....... Units digit repeat in cycle of 9,1,9,1....
So, possible value of Units digit of XY can be found by considering all possibilities of Units digit of X and Y
When X=4 and Y=9: Units digit of XY = 6
When X=4 and Y=1: Units digit of XY = 4
When X=6 and Y=9: Units digit of XY = 4
When X=6 and Y=1: Units digit of XY = 6
Only two possibilities for Units digit of XY i.e. 4 and 6.
Only 6 is given in answer choices, therefore answer is B
Answer: B
Question: Alex has $246,713 dollars in his savings account. What is the least amount of money (in whole number of dollars) that he must remove from his account if he wants to split this money evenly among his 6 children?
Options:
A)$1
B)$2
C)$3
D)$4
E)$5
Rationale: In order to divide the sum into 6 parts, the amount must be divisible by 6.
Divisibility rule of 6: A number is divisible by 6 if it is divisible by both 2 and 3
Divisibility rule of 3: A number is divisible by 3 if the sum of the digits is divisible by 3
We need to make this number even in order for it to be divisible by 2.
Sum of digits 246,713 = 23 and 21 is divisible by 3. Subtracting 2 does not yields an even number.
Sum of digits 246,713 = 23 and 18 is divisible by 3. Subtracting 5 yields an even number.
Hence, we need to subtract 5 from this number for it to be divisible by 6.
Correct Option: E
Answer: E
Question: An inspector rejects 0.008% of the meters as defective. How many will be examine to project ?
Options:
A)2000
B)230
C)2700
D)25000
E)250
Rationale: Let the number of meters to be examined be x.
Then, 0.008% of x =2
[(8/1000)*(1/100)*x] = 2
x = [(2*100*1000)/8] = 25000
Answer is D.
Answer: D
Question: In a school of 850 boys, 44% of Muslims, 32% Hindus, 10% Sikhs and the remaining of other communities. How many belonged to the other communities?
Options:
A)A)125
B)B)119
C)C)153
D)D)721
E)E)159
Rationale: 44 + 32 + 10 = 86%
100 – 84 = 14%
850 * 14/100 = 119
Answer:B
Answer: B
Question: An office supply store stocks two sizes of notebooks, each in six colors: orange, blue, green, yellow, red, or pink. The store packs the notebooks in packages that contain either 4 notebooks of the same size and the same color or 4 notebooks of the same size and of 4 different colors. If the order in which the colors are packed is not considered, how many different packages of the types described above are possible?
Options:
A)20
B)24
C)32
D)36
E)42
Rationale: First let's consider the small notebooks.
There are 6 ways to choose notebooks of the same color.
The number of ways to choose four notebooks with different colors is 6C4=15.
There are 21 different packages we can make with the small notebooks.
We can use the same process to find 21 different packages with large notebooks.
The total number of different packages is 42.
The answer is E.
Answer: E
Question: On the x-y coordinate plane there is a parabola, y=x(6-x). Which of the following points is in the region that is enclosed by this parabola and the x-axis?
I. (1, 1) II. (4, 4) III. (6, 6)
Options:
A)I only
B)II only
C)III only
D)I and II
E)I, II, and III
Rationale: Since co-efficient of x^2 is negative, the parabola will be downward facing. So the parabola and the x axis will enclose some points where the y-values of the parabola are positive.
When x = 1, y = 5 lies on the parabola, so (1, 1) will be enclosed by the parabola and x axis.
When x = 4, y = 8 lies on the parabola, so (4, 4) will be enclosed by the parabola and x axis.
When x = 6, y = 0 lies on the parabola, so (6, 6) will not be enclosed by the parabola and x axis.
The answer is D.
Answer: D
Question: Bradley owns b video game cartridges. If Bradley’s total is one-fifth the total owned by Andrew and four times the total owned by Charlie, how many video game cartridges do the three of them own altogether, in terms of b?
Options:
A)16b / 3
B)17b / 4
C)13b / 4
D)19b / 12
E)25b / 4
Rationale: b = Bradley’s total
5b = Andrew’s total
b/4 = Charlie’s total
The total number of cartridges is:
b + 5b+ b/4 = (4b + 20b + b) / 4 = 25b / 4
The answer is E.
Answer: E
Question: The length of a rectangle is halved, while its breadth is tripled. Watis the % change in area?
Options:
A)30%
B)40%
C)50%
D)60%
E)65%
Rationale: Let original length = x and original breadth = y.
Original area = xy.
New length = x .
2
New breadth = 3y.
New area = x x 3y = 3 xy.
2 2
Increase % = 1 xy x 1 x 100 % = 50%.
2 xy
C
Answer: C
Question: ♠n denotes the number obtained when n is rounded to the nearest tenth. For example ♠4.31 = 4.3
♠0.098 - ♠1.125 =
Options:
A)-1.1
B)1.04
C)-1.05
D)-1.0
E)-0.1
Rationale: ♠0.098 - ♠1.125 =
0.1 - 1.1 = -1.1
Answer : A
Answer: A
Question: A customer pays 20 dollars for a coffee maker after a discount of 20 dollars
What is the original price of the coffee maker?
Options:
A)50
B)40
C)70
D)60
E)20
Rationale: Let x be the original price.
x - 20 = 20
x - 20 + 20 = 20 + 20
x + 0 = 40
x = 40
Answer is B
Answer: B
Question: John makes $60 a week from his job. He earns a raise and now makes $90 a week. What is the % increase?
Options:
A)16%
B)50%
C)17%
D)17.61%
E)17.56%
Rationale: Increase = (30/60)*100 = (3/6)*100 = 50%.
B
Answer: B
Question: How much space, in cubic units, is left vacant when maximum number of 4x4x4 cubes are fitted in a rectangular box measuring 10x12x16 ?
Options:
A)0
B)36
C)180
D)216
E)384
Rationale: No of cubes that can be accommodated in box = (10*12*16)/(4*4*4)
12*16 in numerator can be perfectly divided by 4*4 in denominator.
side with length 10 can't be perfectly divided by 4 and hence is the limiting factor. Closet multiple of 4 less that 10 is 8. so vacant area in cube =
=12*16*(10-8)
=12*16*2
=384
ANSWER:E
Answer: E
Question: The function f is defined for all positive integers n by the following rule: f(n) is the product of the distinct prime factors of n. If f(n) < 30 and n is not prime, what is the greatest possible value of f(n)?
Options:
A)28
B)26
C)20
D)18
E)15
Rationale: Since we need the largest value of f (n), we will start with the largest option.
Option A: 28 = 2*2*7. This is not a product of distinct prime numbers. Hence incorrect
Option B: 26 = 2*13. This is a product of distinct prime numbers.
Rest all the options are smaller that 26.
Correct Option: B
Answer: B
Question: On dividing a certain number by 5, 7 and 8 successively, the remainders obtained are 2, 3 and 4 respectively. When the order of division is reversed and the number is successively divided by 8, 7 and 5, the respective remainders Q will be:[/b]
Options:
A)Q=3, 3, 2
B)Q=3, 4, 2
C)Q=5, 4, 3
D)Q=5, 5, 2
E)6, 4, 3
Rationale: Let the original number be X. Then by the successive dividing we have followings :
X=5A+2
A=7B+3
B=8C+4.
So we have A=7*(8C+4)+3=7*8C+31, and X=5*(7*8C + 31)+2 = 5*7*8C + 157.
Now by dividing X by 8, 7, 5 successively we have followings :
X=8*(5*7C+19)+5
5*7C+19=7*(5C+2) + 5
5C+2=5C+2.
The remainders are, therefore, 5, 5, 2.
The answer is (D).
Answer: D
Question: One-fourth of a tank holds 135 litres of water. What part of the tank is full if it contains 180 litres of water?
Options:
A)1/2
B)1/3
C)1/5
D)1/6
E)1/4
Rationale: 135 litres = 1/4 of tank
180 litres = 1/4 x 180/135 = 1/3
Answer B.
Answer: B
Question: ?⁄50 = 60.5⁄?
Options:
A)55
B)1512.5
C)52.5
D)57.5
E)None of these
Rationale: ?⁄50 = 60.5⁄?
or,?2 = 50 × 60.5 or, ?2 = 3025
or, ? = √3025 = 55
Answer A
Answer: A
Question: The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is?
Options:
A)87 years
B)40 years
C)19 years
D)16 years
E)18 years
Rationale: Sum of the present ages of husband, wife and child
= (27 * 3 + 3 * 3) = 90 years.
Sum of the present age of wife and child
= (20 * 2 + 5 * 2) = 50 years.
Husband's present age
= (90 - 50) = 40 years.
Answer: B
Answer: B
Question: 15 men take 21 days of 8 hours each to do a piece of work. How many days of 6 hours each would 21 women take to do the same. If 3 women do as much work as 2 men?
Options:
A)33
B)77
C)30
D)88
E)12
Rationale: 3W = 2M
15M ------ 21 * 8 hours
21 W ------ x * 6 hours
14 M ------ x * 6
15 * 21 * 8 = 14 * x * 6
x = 30
Answer: C
Answer: C
Question: The average of 35 students in a class is 18 years. The average age of 25 students is 16. What is the average age of remaining 10 students?
Options:
A)21 years
B)23 years
C)22 years
D)20 years
E)24 years
Rationale: Sum of the ages of 14 students
= (18 * 35) - (16 * 25) = 630 - 400 = 230
Required average = (230/10) = 23 years.
Answer:B
Answer: B
Question: What is the median from the below series 93, 88, 95, 88, 97, 87, and 98
Options:
A)80
B)82
C)92.14
D)98
E)100
Rationale: Ordering the data from least to greatest, we get:
87, 88, 88, 93, 95, 96, 98
The median quiz score was 92.14 (Four quiz scores were higher than 92.14 and four were lower.)
C
Answer: C
Question: There are 380 doctors and nurses in a hospital. If the ratio of the doctors to the nurses is 8 : 11, then how many nurses are there in the hospital?
Options:
A)152
B)209
C)57
D)171
E)220
Rationale: Given,
The ratio of the doctors to the nurses is 8 : 11
Number of nurses = 11/19 x 380 = 220
ANSWER:E
Answer: E
Question: What is the greatest 6-digit number when divided by 7 ,8 , 9, and 10 leaves a remainder of 5, 6, 7, and 8 respectively?
Options:
A)456788
B)678910
C)997479
D)997919
E)997920
Rationale: When you divide a positive integer by 10, the remainder will just be the units digit. We know the remainder is 8 when we divide by 10, so A is the only possible answer.
Answer: A
Question: A train after traveling for 50km meets with an accident and then proceeds at 3/4 of its former speed and arrives at its destination 35 minutes late . Had the accident occurred 24 km farther, it would have reached the destination only 25 minutes late. What is the speed R of the train.
Options:
A)a) 45
B)b) 33
C)c) 48
D)d) 55
E)e) 61
Rationale: Let y be the balance distance to be covered and x be the former speed.
A train after traveling for 50km meets with an accident and then proceeds at 3/4 of its former speed and arrives at its destination 35 minutes late
so, y/(3x/4) - y/x = 35/60
4y/3x - y/x = 7/12
y/x(4/3-1)=7/12
y/x*1/3=7/12
y/x=7/4
4y-7x=0 ........ 1
Had the accident occurred 24 km farther, it would have reached the destination only 25 minutes late
so, (y-24)/(3x/4) - (y-24)/x = 25/60
4(y-24)/3x - (y-24)/x = 5/12
(y-24)/x (4/3-1) = 5/12
(y-24)/x *1/3 = 5/12
(y-24)*12 = 3x*5
(y-24)*4 = 5x
4y-5x = 96 ....... 2
eq2 - eq1
2x=96
x=48=R
Ans = C
Answer: C
Question: Find the average of all the numbers between 6 and 34 which are divisible by 5
Options:
A)18
B)20
C)24
D)30
E)40
Rationale: Exp. Multiples of 5 between 6 and 34 are 10,15,20,25,30
Average = (10+15+20+25+30)/5 =5(10+30)/2*5 = 40/2 =20
Answer:B
Answer: B
Question: In 1937, the ship of the great sailor SINBAD left an Egyptian port heading Ivory coast at T mile/month .
One month later another ship of the greatest pirate ever CHENG I SAO was 5000 miles due south of the same Egyptian port and heading due north at Y miles/month. Six months later after the leaving of Sinbad’s ship from Egyptian port, how far apart were the ships? [Ivory coast is in the west of Egypt]
Options:
A){ (6T)^2 + (5000-5y)^2 }^1/2
B){ (36x)^2 + (5000-7y)^2 }^1/2
C){ (16x)^2 + (5000-7y)^2 }^1/2
D){ (7x)^2 + (5200-7y)^2 }^1/2
E){ (2x)^2 + (300-7y)^2 }^1/2
Rationale: The chinese ship sailed for 5 months i.e. 5Y miles @Y miles/month, therefore distance from Egyptian port is 5000-5Y. Since A is the only option with this value ...therefore A is the answer
Answer: A
Question: After a storm deposits 120 billion gallons of water into the city reservoir, the reservoir is 80% full. If the original contents of the reservoir totaled 200 billion gallons, the reservoir was approximately what percentage full before the storm?
Options:
A)45%
B)48%
C)50%
D)58%
E)65%
Rationale: When the storm deposited 120 billion gallons, volume of water in the reservoir = 200 + 120 = 320 billion gallons
If this is only 80% of the capacity of the reservoir, the total capacity of the reservoir = 320/0.8 = 400 billion gallons
Therefore percentage of reservoir that was full before the storm = (200/400)*100 = 50%
Option C
Answer: C
Question: A mixture of 70 litres of milk and water contains 10% water. How many litres of water should be added to the mixture so that the mixture contains 12 1/2% water?
Options:
A)2
B)8
C)6
D)3
E)4
Rationale: A
2
Quantity of milk in the mixture = 90/100 (70) = 63 litres.
After adding water, milk would form 87 1/2% of the mixture.
Hence, if quantity of mixture after adding x liters of water, (87 1/2) / 100 x = 63 => x = 72
Hence 72 - 70 = 2 litres of water must be added.
Answer: A
Question: A person's present age is two-fifth of the age of his mother. After 8 years, he will be one-half of the age of his mother. How old is the mother at present?
Options:
A)32 Yrs
B)36 Yrs
C)40 Yrs
D)48 Yrs
E)None
Rationale: Explanation:
Let the mother's present age be x years.
Then, the person's present age = (2/5)*x years.
((2/5)*x)+8 = (1/2)(x+8)
2(2x + 40) = 5(x + 8)
x = 40.
Answer: C
Answer: C
Question: By selling 15 pens for a rupee a woman loses 25%. How many for a rupee should he sell in order to gain 25%?
Options:
A)12
B)14
C)45
D)10
E)65
Rationale: D
85% --- 15
125% --- ?
85/125 * 15 = 10
Answer: D
Question: James started from his house headed North. After walking a distance of 50 m. He turned to the left and walked 60 m. He then made a right turn and walked 30 m. After this he is to turn left at 90o degrees and to cover another 40 m. How many meters did James walk in total and what direction was he headed in when he left his house?
Options:
A)158/South
B)10/East
C)South-West
D)180/North
E)180/North-West
Rationale: Answer: E
Answer: E
Question: By selling an article for 96, double profit is obtained than the profit that would have been obtained by selling it for 84. What is the cost price of the article?
Options:
A)72.0
B)75.0
C)70.00
D)68.00
E)None of these
Rationale: Let the cost price of the article be x.
Then,2(84 –x) = 96 – x
l68 – 2x= 96 – x \ x = 72
Answer A
Answer: A
Question: What is the area of square field whose side of length 13 m?
Options:
A)169
B)196
C)266
D)288
E)261
Rationale: 13 * 13 = 169 sq m
Answer: A
Answer: A
Question: If two positive numbers are in the ratio 1/8 : 1/5, then by what percent is the second number more than the first?
Options:
A)70%
B)90%
C)60%
D)50%
E)65%
Rationale: Given ratio = 1/8 : 1/5 = 5 : 8
Let first number be 5x and the second number be 8x.
The second number is more than first number by 3x.
Required percentage = 3x/5x * 100 = 60%.
Answer:C
Answer: C
Question: A circular rim A having a diameter of 24 inches is rotating at the rate of x inches/min. Another circular rim B with a diameter of 32 inches is rotating at the rate of y inches/min. What is the value of y in terms of x, if both the rims reach their starting positions at the same time after every rotation.
Options:
A)3x/4
B)4x/5
C)7x/5
D)5x/7
E)4x/3
Rationale: t = S1/V1 = S2/V2
or, 24/x = 32/y
or, y = 24x/32 = 3x/4 (Answer A)
Answer: A