divelab/Sys2Bench huggingface dataset:
Question: Envelopes can be purchased for $1.50 per pack of 100, $1.00 per pack of 50, or $0.03 each. What is the greatest number of envelopes that can be purchased for $6.30?
Options:
A)426
B)430
C)443
D)410
E)486
Rationale: I think first we should see in what group envelopes value less, so that we can buy as many as we can with a specific amount of money:
-the 100 pack costs 1.5$, meaning 0.015$ per envelope
-the 50 pack costs 1$, meaning 0.02$ per envelope
-the single envelope costs 0.03$ per envelope
Thus, we have to buy as many 100 packs as we can, then as meny of 50 packs as we can and the remaining envelopes are single ones.
Having 6.3$, we can buy as many as 4 packs of 100 (4 x 1.5$ = 6$). We then have 0.3 $ left. so we buy 10 individual envelopes. If we add up the numbers, we get 400+10=410 envelopes. Answer D
Answer: D
Question: A taxi leaves Point A 5 hours after a bus left the same spot. The bus is traveling 20 mph slower than the taxi. Find the speed of the taxi, if it overtakes the bus in three hours.
Options:
A)34
B)32
C)36
D)38
E)40
Rationale: Let the speed of bus be v - 20, speed of taxi be v
The bus travelled a total of 8 hrs and taxi a total of 3 hrs.
Hence 8 * (v-20) = 3v
8v - 160 = 3v
5v = 160
v = 32 mph
B
Answer: B
Question: The average temperature from Tuesday to Friday is 48°C and from Wednesday to Saturday is 52°C. If the temperature on Tuesday is 42°C, what was it on Saturday?
Options:
A)52°C
B)55°C
C)58°C
D)51°C
E)53°C
Rationale: Temperature on Tuesday + Wednesday + Thursday + Friday = 4 x 48°C = 192°C
Temperature on Tuesday = 42°C
Thus, Wednesday + Thursday + Friday = (192°C - 42°C) = 150°C
Temperature on Wednesday + Thursday + Friday + Saturday = 4 × 52°C = 208°C
Thus, Saturday’s temperature = 208 - 150°C = 58°C
ANSWER:C
Answer: C
Question: In a rectangular coordinate system, what is the area of a rhombus whose vertices have the coordinates (0, 5.5), (8, 0), (0, -5.5), (-8, 0)?
Options:
A)56
B)88
C)112
D)116
E)120
Rationale: Ares of rhombus= 1/2* D1 *D2
Length of 1st diagonal = 8+8= 16
Length of 2nd diagonal= 5.5+5.5= 11
Area= 1/2*16*11= 88
B is the answer
Answer: B
Question: A man engaged a servant on the condition that he would pay him Rs.600 and a uniform after one year service. He served only for 9 months and received uniform and Rs.400, find the price of the uniform?
Options:
A)s.80
B)s.85
C)s.90
D)s.100
E)s.200
Rationale: 9/12 = 3/4 * 600 = 450
400
-------------
50
1/4 -------- 50
1 --------- ? => Rs.200
ANSWER:E
Answer: E
Question: If a young child was 17 months old one year ago, how old was the child, in months, x months ago?
Options:
A)x − 29
B)x − 12
C)17 − x
D)24 − x
E)29 − x
Rationale: The child's age today is 17 months + 12 months = 29 months
x months ago, the child's age was (29 - x) months old.
The answer is E.
Answer: E
Question: When positive integer N is divided by positive integer J, the remainder is 11. If N/J = 724.04, what is value of J?
Options:
A)140
B)150
C)260
D)275
E)280
Rationale: When a number is divided by another number, we can represent it as : Dividend = Quotient * Divisor + Remainder
So, Dividend/Divisor = Quotient + Remainder/Divisor
Given that N/J = 724.04
Here 724 is the quotient.
Given that Remainder = 11
So, 724.04 = 724 + 11/J
So, J = 275
Answer: D
Question: Find the side of the largest possible square slabs which can be paved on the floor of a room 2 m 50 cm long and 1 m 50 cm broad. Also find the number of such slabs to pave the floor.
Options:
A)25, 20
B)30, 15
C)50, 15
D)None of these
E)75,35
Rationale: Explanation:
HCF (250, 150) = 50 cm
The number slabs = 250 *150/ 50*50
=15
Answer: C
Answer: C
Question: A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 680 sq. feet, how many feet of fencing will be required?
Options:
A)34
B)40
C)68
D)88
E)98
Rationale: Explanation:
We have: l = 20 ft and lb = 680 sq. ft.
So, b = 34 ft.
Length of fencing = (l + 2b) = (20 + 68) ft = 88 ft.
Answer: D
Answer: D
Question: A farmer brought 76 cows, the price of each cow being the same and then sold 20 cows at a profit of 15%, 40 cows at a profit of 19% and the remainder at a profit of 25% making a total profit of Rs.26,280. What is the cost price of each cow?
Options:
A)Rs.1000
B)Rs.1800
C)Rs.1500
D)Rs.1400
E)Rs.2500
Rationale: Let cost price of each Cow is x.
Total Cost of 76 Cows = 76x.
SP of 20 Cows = 20x + 15% of 20x
SP of 20 Cows = 20x + 3x = 23x
SP of 40 Cows = 40x + 19% of 40x = 47.6x
SP of remaining cows (16 cows) = 16x + 25% of 16x = 20x
Total selling price of 76 cows = 23x + 47.6x + 20x = 90.6x.
Total Profit = Rs. 26280
Total SP - Total CP = Total Profit
90.6x - 76x = 26280
14.6x = 26280
x = 1800.
CP of each Cow is Rs. 1800.
ANSWER :OPTION B
Answer: B
Question: Bus 1 and Bus 2 run between cities A and B. Bus 1 leaves city A at the same time Bus 2 leaves city B,
each at a constant rate of speed. Their first meeting is 60 miles from city A. After reaching their
respective destinations and immediately turning around, their second meeting is 30 miles from city B.
What is the distance in miles between city A and city B?
Options:
A)90
B)120
C)125
D)150
E)180
Rationale: let d=distance between cities A and B
bus 1 distance to first meeting=60 miles
bus 1 distance from first to second meeting=(d-60)+30=d-30 miles
bus 2 distance to first meeting=d-60 miles
bus 2 distance from first to second meeting=60+(d-30)=d+30 miles
because both buses take the same time for the pre-meeting leg, and
the same time for the inter-meeting leg, and their speeds remain
constant, their ratios between pre-meeting distance and inter-meeting
distance should be the same
therefore, 60/(d-30)=(d-60)/(d+30)
d^2=150d
d=150 miles
D
Answer: D
Question: If the arithmetic mean of seventy five numbers is calculated, it is 35. If each number is increased by 5, then mean of new number is?
Options:
A)87
B)40
C)37
D)28
E)26
Rationale: A.M. of 75 numbers = 35
Sum of 75 numbers = 75 * 35 = 2625
Total increase = 75 * 5 = 375
Increased sum = 2625 + 375 = 3000
Increased average = 3000/75 = 40.
Answer:B
Answer: B
Question: A shop produces sarongs. The daily average production is given by 5n + 20, where n is the number of workers aside from the owner. In the first k days, 500 units are produced, and then 5 workers are added to the team. After another k days, the cumulative total is 1300. How many workers were part of the latter production run?
Options:
A)A)6
B)B)10
C)C)9
D)D)15
E)E)23.5
Rationale: The daily average production is given by 5n + 20- given
In the first k days, 500 units are produced
= (5n+20)K =500
k = 500/5n+20...................................1
5 workers were added = 5(n+5)+20 = 5n +45
cumulative is 1300 .. thus for the current period = 1300 -500 = 800
(5n+45)K= 800
k = 800/5n+45........................................2
equate 1 and 2
500/5n+20 = 800 /5n+45
500(5n+45) = 800(5n+20)
25n + 225 = 40n + 160
-15n = -65
n = 4
thus n+5 = 9
hence C
Answer: C
Question: A car started running at a speed of 36 km/hr and the speed of the car was increased by 2 km/hr at the end of every hour. Find the total distance covered by the car in the first 10 hours of the journey.
Options:
A)45 km
B)76 km
C)25 km
D)15 km
E)30 km
Rationale: A
45 km
The total distance covered by the car in the first 10 hours = 36 + 38 + 40 + 42 + 44 + 46 + 48+ 50 + 52 + 54= sum of 10 terms in AP whose first term is 36 and last term is 54 = 10/2 [36 + 54] = 450 km.
Answer: A
Question: In a party there are 5 couples. Out of them 5 people are chosen at random. Find the probability that there are at the least two couples?
Options:
A)5/26
B)5/78
C)5/21
D)5/56
E)5/12
Rationale: Number of ways of (selecting at least two couples among five people selected) = (⁵C₂ * ⁶C₁)
As remaining person can be any one among three couples left.
Required probability = (⁵C₂ * ⁶C₁)/¹⁰C₅
= (10 * 6)/252
= 5/21
Answer:A
Answer: A
Question: Kristy, Amy, and Blair are going on a cross-country road trip from Washington to Maine. The total driving time is 48 hours. Each driver will drive 6 hours daily and in the remaining hours of the day the group will sight-see and explore. They will sleep in the car when they are not driving. They all have driver's licenses, but Amy is scared of driving in unfamiliar places and would prefer not to take the wheel. How much sooner would the group arrive in Maine, in hours, if Amy chose to drive, compared to just Kristy and Blair?
Options:
A)12
B)24.76
C)31.92
D)36.92
E)24
Rationale: All three girls calculation: 3 girls x 6 hours = 18 hours of driving per day, 6 nondriving hours/day
48 total trip hours divided by 18 daily driving hours = 2.67 days / driving rotations
2.67 x 24 (hours in one day) = 64.08 total hours for road trip
2 girls calculation: 2 girls x 6 hours = 12 hours of driving per day, 12 nondriving hours/day
48 total trip hours divided by 12 daily driving hours = 4 days / driving rotations
4 x 24 (hours in one day) = 96 total hours for road trip
FINAL ANSWER: 96 hours (2 girls total) minus 64.08 (3 girls total) = ANSWER C: The group would arrive in Maine 31.92 hours sooner if all three drove.
Answer: C
Question: P, Q and R can do a work in 10 , 12 and 15 days respectively. What is the share ratio of P, Q and R respectively?
Options:
A)6 : 5 : 7
B)6 : 5 : 4
C)6 : 5 : 3
D)6 : 4 : 5
E)4 : 5 : 6
Rationale: The ratio of their working rates = 1/10 : 1/12 : 1/15 = 6 : 5 : 4.
Answer: B
Answer: B
Question: A bookstore has a shelf that contains biographies which normally sell for $20 each and mysteries that normally sell for $12 each. During a sale, the biographies and mysteries are discounted at different rates so that a customer saves a total of $19 from the normal price by buying 5 discounted biographies and 3 discounted mysteries. If the sum of the discount rates for the two types of books is 30 percent, what is the discount rate on mysteries?
Options:
A)17.18%
B)12%
C)13%
D)14%
E)15%
Rationale: Let B be the discount on biographies and M be the discount on mysteries
So., B + M = 0.30 -----(1)
And
(20*5 + 12*3) - (20*5*(1-B) + 12*3*(1-M)) = 19
--> 100(1-(1-B)) + 36(1-(1-M) = 19
100B + 36M = 19 ------(2)
Solving 12., we get M = 0.1718 = 17.18
A
Answer: A
Question: Amar started a business investing Rs. 34000/-. After 3 months, Vamsi joined him with a capital of Rs. 40000/-. At the end of the year, they make a profit of Rs. 17040/-. What will be Amar’s share in the profit?
Options:
A)Rs. 9025/-
B)Rs. 9052.5/-
C)Rs. 9503.5/-
D)Rs. 9504.5/-
E)None of these
Rationale: Explanation:
Amar : Vamsi = (34000 * 12 : 40000 * 9)
= 408000 : 360000
= 408 : 300
= 51 : 45
Amar’s share = 17040 * 51/91 = 177.5 * 51 = Rs. 9052.5/-
Answer: Option B
Answer: B
Question: A bag contains ten marbles of the same size: 3 are identical green marbles, 2 are identical red marbles, and the other 5 are five distinct colors. If 5 marbles are selected at random, how many distinct combinations Q of five marbles could be drawn?
Options:
A) 41
B) 51
C) 62
D) 72
E) 82
Rationale: there will be different cases, which we will take one by one..
1)case 1 when all five colours are different-7c5=21..
2)case 2 when three different colours and 2 of same type=6c3*2=30..
3)case 3 when two different colours and 3 of same type=6c2=15..
4)case 4 when one different colours and 2 of two different colors=5c1*4!/2!2!=15...
5)case 4 when 3 of one type and 2 of other colour=1...
total Q-82 ans E
Answer: E
Question: If the greatest common divisor of (n+2)!, (n-1)!, and (n+4)! is 120, what is the value of n?
Options:
A)4
B)5
C)6
D)7
E)3
Rationale: Notice that:
1! = 1
2! = 2
3! = 6
4! = 24
5! = 120
So, the smallest factorial must be 5! for the GCD to be 120
The smallest of the three factorials is (n-1)!
So, we need (n-1)! to equal 5!
This means that n = 6
If n = 6, then (n+2)!, (n-1)!, and (n+4)! become 8!, 5! and 10!
Let's CONFIRM this conclusion
8! = (1)(2)(3)(4)(5)(6)(7)(8) = (120)(6)(7)(8)
5! = (1)(2)(3)(4)(5) = 120
10! = (1)(2)(3)(4)(5)(6)(7)(8)(9)(10) = (120)(6)(7)(8)(9)(10)
As you can see, 120 is a divisor of all three factorials.
In fact, 120 is the GREATEST COMMON divisor of all three factorials.
Answer: C
Answer: C
Question: The bus that travels from St. Louis to Chicago and back comes to St. Louis every 3 hours while the bus that travels from St. Louis to Springfield and back comes to St. Louis every 6 hours. If at 12:00 o'clock both bused arrived at St. Louis, at what time will they meet in St. Louis again?
Options:
A)16:00.
B)18:00
C)20:00
D)22:00.
E)24:00.
Rationale: Time taken by bus to travel from St. Louis to Chicago and back comes to St. Louis = 3 hours
Time taken by bus to travel from St. Louis to Springfield and back comes to St. Louis = 6 hours
Time taken by both buses to meet again in St. Louis will be LCM of 3 and 6 = 6
If the buses start at 12:00 o'clock from St. Louis , they will meet again in St. Louis at 18:00 hours
Answer B
Answer: B
Question: A man bets on no.16 on a roulette wheel 14times and losses each time. On the 15th span he does a quick calculation and finds out that the no. 12 had appeared twice in the 14 spans and istherefore, unable to decide whether to bet on 16 or 12 in the 15th span. Which will give him the best chance and what r the odds of winning on the bet that he takes?
Options:
A)35:1
B)Either ;35:1
C)Either 70;35:1
D)Either 55;45:1
E)Either 65;35:5
Rationale: Each of the span is an independent event and the outcome of the 15th span will not depend on the outcome of the earlier spans.
Either ;35:1
B)
Answer: B
Question: Let A be the event that a randomly selected two digit number is divisible by 2 and let B be the event that a randomly selected two digit number is divisible by 10. What is P(A and B)?
Options:
A)1/20
B)1/15
C)1/12
D)1/8
E)1/2
Rationale: P(A and B) = 1/2*1/10 = 1/20
The answer is A.
Answer: A
Question: A train 280 m long, running with a speed of 63 km/hr will pass a tree in?
Options:
A)65 sec
B)16 sec
C)18 sec
D)13 sec
E)76 sec
Rationale: Speed = 63 * 5/18 = 35/2 m/sec
Time taken
= 280 * 2/35
= 16 sec
Answer:B
Answer: B
Question: Shaun is starting a new diet plan that offers him the choice of fruit or yogurt for breakfast, 6 different entrees for lunch, and 9 different entrees for dinner. If Shaun chooses an Italian entree for lunch, he always chooses an Italian entree for dinner. If Shaun chooses a Chinese entree for lunch, he never chooses a Chinese entree for dinner. If there are 2 Italian entrees and 2 Chinese entrees among the lunch choices, and 3 Italian entrees and 3 Chinese entrees among the dinner choices, from how many different daily menus can Shaun choose?
Options:
A)24
B)36
C)72
D)90
E)108
Rationale: Let the Breakfast set be {F , Y}
Lunch be {I ,I , C,C , L1,L2}
Dinner be {I,I,I , C,C,C, D1,D2,D3}
There are only 2 restrictions, Italian Lunch has to go with Italian Dinner and Chinese Lunch cannot go with Chinese dinner.
So the set of Breakfast, Lunch and Dinner will
{Any BF, Italian Lunch, Italian Dinner } = 2 * 2 * 2
{Any BF, Chinese Lunch, Not Chinese Dinner} = 2 * 2 * 6
{Any BF, Not Italian or Chinese Lunch, Any Dinner} = 2 * 2 * 9
Adding all these gives 72.
Answer is C
Answer: C
Question: If 3/p=6 & 3/q=18 then p-q=?
Options:
A)5/24
B)6/24
C)7/24
D)8/24
E)1/3
Rationale: p=3/6 , q=3/18=>q=1/6
therefore
p-q=(1/2)-(1/6)=1/3
ANSWER:E
Answer: E
Question: What is the smallest no. which must be added to 532869 so as to obtain a sum which is divisible by 9?
Options:
A)9
B)2
C)1
D)3
E)6
Rationale: For 532869 , 5+3+2+8+6+9=33
3 must be added to 532869 to make it divisible by 9.
Now ,5+3+2+8+7+2=27=> 27 is a multiple of 9 and hence 532869 is also divisible by 9
D
Answer: D
Question: In a division sum, the remainder is 8 and the divisor is 3 times the quotient and is obtained by adding 3 to the thrice of the remainder. The dividend is:
Options:
A)200
B)251
C)250
D)262
E)254
Rationale: Diver = (8*3)+3 = 27
3* Quotient = 27
Quotient = 9
Dividend = (Divisor * Quotient) + Remainder
Dividend = (27 * 9) + 8 = 251
B
Answer: B
Question: Six bells commence tolling together and toll at intervals of 2,4,6,8,10 and 12 seconds respectively. in 30 m9nutes,how many times do they toll together ?
Options:
A)4
B)10
C)15
D)16
E)17
Rationale: Solution
L.C.M. of 2,4,6,8,10,12 is 120.
So, the bells will toll together after every 120 seconds, i.e., 2 minutes
In 30 minutes, they will toll together left [ ( 30/2 )+ 1 ] = 16 times. Answer D
Answer: D
Question: The difference between compound and simple interest on a certain sum of money for 3 years at 6 2/3% p.a is Rs.184. Find the sum?
Options:
A)33772
B)26782
C)26788
D)13500
E)27761
Rationale: P = (184*106) / [6 2/3 * 6 2/3 *(300*6 2/3)]
P = 13500
Answer: D
Answer: D
Question: What annual payment will discharge a debt of Rs. 1125 due in 2 years at the rate of 5% compound interest?
Options:
A)993.2
B)551.25
C)534.33
D)605.03
E)646.33
Rationale: Explanation:
Let each installment be Rs. x. Then,
x/(1 + 5/100) + x/(1 + 5/100)2 = 1125
820x + 1125 * 441
x = 605.03
So, value of each installment = Rs. 605.03
Answer: Option D
Answer: D
Question: If the sales tax reduced from 3 1/2 % to 3 1/3%, then what difference does it make to a person who purchases an article with market price of Rs. 8400 ?
Options:
A)Rs.12
B)Rs.16
C)Rs.14
D)Rs.10
E)Rs.18
Rationale: Required difference = [3 ½ % of Rs.8400] – [3 1/3 % of Rs.8400]
= [(7/20-(10/3)]% of Rs.8400 =1/6 % of Rs.8400
= Rs. [(1/6)8(1/100)*8400] = Rs. 14.
Answer is C.
Answer: C
Question: If 0.5% of A =80 paise, then the value of A is ?
Options:
A)Rs. 170
B)Rs. 160
C)Rs. 1.70
D)Rs. 4.25
E)None
Rationale: Answer
∵ 0.5/100 of A = 80/100
∴ A = Rs. (80 / 0.5) = Rs. 160
Correct Option: B
Answer: B
Question: In the Biotechnology class of 2000, there were X graduates. 32 of the graduates found a job, 45 continued on to their second degree and 13 did both. If only 9 people didn't do both, What is X equal to?
Options:
A)69.
B)71
C)73
D)75
E)76
Rationale: Graduates got job = 32
Graduates continued to second degree = 45
Graduates got job and continued to second degree = 13
Graduates didn't get job and didn't continue to second degree = 9
Job	No Job	Total
Second Degree 13	32	45
No Second Degree	19	9	28
Total	32	41	X
Therefore X = 73
Answer C
Answer: C
Question: The original price of a car was $30,000. Because the car owner thought he could get more money for the car, he set a new price by increasing the original price of the car by 5%. After a week, the car had not sold, so the owner discounted the new price by 5%, and the car was finally sold. What price was the car sold for?
Options:
A)$29,915
B)$29,925
C)$29,935
D)$29,945
E)$29,955
Rationale: The car was sold for (0.95)(1.05)($30,000)=$29,925.
The answer is B.
Answer: B
Question: Due to construction, the speed limit along an 9-mile section of highway is reduced from 55 miles per hour to 30 miles per hour. Approximately how many minutes more will it take to travel along this section of highway at the new speed limit than it would have taken at the old speed limit ?
Options:
A)A) 5.61
B)B) 8
C)C) 10
D)D) 15
E)E) 8.19
Rationale: Old time in minutes to cross 9 miles stretch = 9*60/55 = 9*12/11 = 9.81
New time in minutes to cross 9 miles stretch = 9*60/30 = 9*2/1 = 18
Time difference = 8.19
Ans:E
Answer: E
Question: Points M(7,2) and N(5,14) lie on the xy - plane. What is the midpoint of line segment MN?
Options:
A)(5,0)
B)(6,8)
C)(0, (136^(1/2))/2)
D)(3/2,0)
E)(1,5)
Rationale: The midpoint of a segment is exactly halfway between its endpoints and it's location can be found using the Midpoint Theorem, which states:
• The x-coordinate of the midpoint is the average of the x-coordinates of the two endpoints.
• Likewise, the y-coordinate is the average of the y-coordinates of the endpoints.
So, x=(7+5)/2=6 and y=(2+14)/2=8 --> coordinates of the midpoint are (6, 8).
Answer: B.
Answer: B
Question: When x is multiplied by 3, the result is 26 more than the result of subtracting x from 62. What is the value of x?
Options:
A)-4
B)-2
C)11
D)13
E)22
Rationale: The equation that can be formed is:
3x-26=62-x
or, 4x=88
or, x=22.
Answer : E
Answer: E
Question: What is remainder of the division (1425*1427*1429)/12?
Options:
A)5
B)0
C)1
D)2
E)3
Rationale: remainder will be number/ 100 here as the divisor is two digit number = 12.
hence checking for the last two digits = 5*7*9 = 15
Thus remainder = 3.
Answer : E
Answer: E
Question: Missing number in the series
4 9 20 43 90 185 376?
Options:
A)175
B)185
C)759
D)195
E)180
Rationale: 4*2+1=9
9*2+2=20
20*2+3=43
43*2+4=90
90*2+5=185
185*2+6=376
376*2+7=759
ANSWER:C
Answer: C
Question: The roof of an apartment building is rectangular and its length is 4 times longer than its width. If the area of the roof is 1024 feet squared, what is the difference between the length and the width of the roof?
Options:
A)38.
B)40.
C)42.
D)48.
E)46.
Rationale: Let the width= x
x*4x=1024
x^2= 256
x= 16
Length= 4*16=64
difference= 64-16= 48
D is the answer
Answer: D
Question: At present the age of the father is 3 times that of the age of the son. Three years hence the father's age would be 2 times that of his son. Find the present age of the father?
Options:
A)18years
B)12years
C)20years
D)16years
E)25years
Rationale: Age of the son = (3-1)*3 / (3-2) = 6 years
Age of the father = 6*3 = 18 years
Answer is A
Answer: A
Question: Pat and Cara begin running at the same time and they start at the same place on a straight path. Pat runs at 9 miles per hour, and Cara runs at 5 miles per hour. After 10 minutes, Pat stops to stretch. If it takes Pat 20 minutes to stretch and Cara continues to run during this time, how many minutes will it take Pat to catch up to Cara?
Options:
A)12
B)15
C)18
D)21
E)24
Rationale: In 10 minutes, Pat runs 1.5 miles.
In 30 minutes, Cara runs 2.5 miles.
Pat can catch Cara at a rate of 4 miles per hour.
Since Cara is ahead by 1 mile, it will take Pat 1 / 4 = 0.25 hours = 15 minutes to catch Cara.
the answer is B.
Answer: B
Question: Tomy's age 16 years hence will be thrice his age four years ago. Find Tomy's present age?
Options:
A)12 years
B)13 years
C)15 years
D)14 years
E)18 years
Rationale: Let MTomy's present age be 'x' years.
x+ 16 = 3(x- 4)
=> 2x = 28 => x = 14 years.
D
Answer: D
Question: Suppose son name is 120,his brother name is 150 and his mother name is 190.find out his father's name???
Options:
A)220
B)210
C)230
D)240
E)250
Rationale: since difference between all name is =30
so father's name will be 190+30=220.
ANSWER:A
Answer: A
Question: A man goes from A to B at a speed of 20 kmph and comes back to A at a speed of 30 kmph. Find his average speed for the entire journey?
Options:
A)19 kmph
B)24 kmph
C)17 kmph
D)12 kmph
E)16 kmph
Rationale: Distance from A and B be 'd'
Average Speed = total distance/total time
Average Speed = (2d)/[(d/20) + (d/30)]
= (2d)/[5d/60) => 24 kmph.
Answer:B
Answer: B
Question: 5301 x 13 =?
Options:
A)89136
B)31986
C)68910
D)53113
E)68913
Rationale: Append 0 before and after: 053010
Calculation:
1 x 3 + 0 = 3 (take 3 as ones digit of the product)
0 x 3 + 1 = 1 (take 1 tens digit of the product)
3 x 3 + 0 = 9 (take 9 hundreds digit of the product)
5 x 3 + 3 = 18 (take 8 as thousands digit of the product, carry over 1)
0 x 3 + 5 = 5; 5 + 1 = 6 (take 6 as ten thousands digits of the product)
So, 5301 x 13 = 68913
Answer is E.
Answer: E
Question: Tommy has a lot of Lego blocks, but only green and red blocks. There are four times as many green blocks as there are red blocks. If Tommy has Y Lego blocks, how many red blocks are there, in terms of Y.
Options:
A)3*Y
B)Y/3
C)Y/5
D)Y/4
E)Y/6
Rationale: Since Y equals the number of blocks, then Y = Green + Red
Since there are four times green blocks as red blocks, then Green = 4*Red
Thus Y = 4*Red + Red, which simplifies to Y=5*Red
Therefore the Red = Y/5
Answer: C
Answer: C
Question: Milk contains 5% water.What quantity of pure milk should be added to 10 litres of milk to reduce this to 2% ?
Options:
A)5 litres
B)7 litres
C)15 litres
D)Cannot be determined
E)None of these
Rationale: Here required quantity of pure milk = 10×(5−2)/2
= 10×3/2 = 15 litres.
Answer C
Answer: C
Question: How many three letter words are formed using the letters of the word BREAK?
Options:
A)A)240
B)B)360
C)C)720
D)D)120
E)E)480
Rationale: The number of letters in the given word is five.
The number of three letter words that can be formed using these four letters is 5P4
= 5 * 4 * 3*2 = 120.
Answer:D
Answer: D