divelab/Sys2Bench huggingface dataset:
Question: The Average of 11 results is 16, if the average of the 1st 6 results is 58 & that of the last 63. Find the 6th result.
Options:
A)60
B)59
C)62
D)66
E)58
Rationale: 6th result = (58*6+63*6-60*11)=66
Answer is D
Answer: D
Question: A certain country had a total annual expenditure of $4.8 x 10^11 last year. If the population of the country was 240 million last year, what was the per capita expenditure?
Options:
A) $ 500
B) $1,000
C) $2,000
D) $3,000
E) $5,000
Rationale: Total expenditure / Population = per capita expenditure
Hence, (4,8 x 10^11) / 240 000 000 = (4,8 x 10^11) / (2,4 x 10^8) = 2 x 10^(11-8) =
2 x 10^3 = 2000.
Answer is C.
Answer: C
Question: If Q is an odd number and the median of Q consecutive integers is 140, what is the largest of these integers?
Options:
A)Q/2 + 139
B)(Q - 1)/2 + 140
C)Q/2 + 140
D)(Q + 139)/2
E)(Q + 140)/2
Rationale: Consider the easiest case, say Q=3, then;
Set = {139, 140, 141};
The largest integer = 141.
Now, plug Q=3 into the answers to see which yields 141.
Answer: B.
Answer: B
Question: The ratio of two quantities is 1 to 4. If each of the quantities is increased by 5, what is the ratio of these two new quantities?
Options:
A)3/4
B)8/9
C)18/19
D)23/24
E)It cannot be determined from the information given
Rationale: 1/4 = 1x/4x
we need to find out (1x+5)/(4x+5) off course we cannot solve this to arrive at any rational number hence E.
Answer: E
Question: If the sum of 7 consecutive integers is x, which of the following must be true?
I. x is an even number
II. x is an odd number
III. x is a multiple of 7
Options:
A) I only
B) III only
C) II only
D) I and III
E) II and III
Rationale: I. If you start off with an even number, the sum (x) is even, and if you start off with an odd number the sum (x) is odd. Therefore this is not always true.
II. Same as above. This need not be always true.
III. Say, the first number is p. Then the sum of the five numbers = p + (p+1) + (p+2)...... + (p+4)
= 7p + 14 = 7 (p+2) => divisible by 7. There this must be true in all cases.
Therefore B is the answer.
Answer: B
Question: SCORE INTERVAL----------------NUMBER OF SCORES
50-59-------------------------- 2
60-69-------------------------- 4
70-79--------------------------10
80-89--------------------------27
90-99--------------------------18
The table above shows the distribution of test scores for a group of management trainees. Which score interval contains the median of the 61 scores?
Options:
A)30
B)32
C)31th(80-89)
D)34
E)36
Rationale: Total scores= 2+4+10+27+18 = 61, which is odd, therefore the median is the Floor(61/2)+1 = 31th score. And the 31th score is in the 80-89 range, because 50-79 only reference 28 scores.
C
Answer: C
Question: By selling 18 pencils for a rupee a man loses 20%. How many for a rupee should he sell in order to gain 20%?
Options:
A)8
B)12
C)6
D)4
E)9
Rationale: 80% --- 18
120% --- ?
80/120 * 18
= 12
Answer:B
Answer: B
Question: The age of man is three times the sum of the ages of his two sons.Five years hence,his age will be double of the sum of the ages of his sons.The father’s present age is :
Options:
A)40 years
B)45 years
C)50 years
D)55 years
E)75 years
Rationale: Solution
Let the sum of present ages of the two sons be x years.
Then,father's present age = 3x years.
∴ (3x + 5)=2 (x +10) ⇔ 3x + 5 = 2x + 20 ⇔ x =15.
Hence,father's present age = 45 years. Answer B
Answer: B
Question: How many cubes of 10 cm edge can be put in a cubical box of 1 m edge?
Options:
A)1
B)10
C)100
D)1000
E)None
Rationale: Sol.
Number of cubes = [100 * 100 * 100 / 10 * 10 * 10] = 1000.
Answer D
Answer: D
Question: Paulson spends 75% of his income. His income is increased by 20% and he increased his expenditure by 10%.Find the percentage increase in his savings
Options:
A)30%
B)35%
C)40%
D)45%
E)50%
Rationale: Let the original income=Rs.100 . Then , expenditure=Rs.75 and savings =Rs.25
New income =Rs.120 , New expenditure =
Rs.((110/100)*75)=Rs.165/2
New savings = Rs.(120-(165/2)) = Rs.75/2
Increase in savings = Rs.((75/2)-25)=Rs.25/2
Increase %= ((25/2)*(1/25)*100)% = 50%.
ANSWER E 50%
Answer: E
Question: 8 men, working 8 hours a day can complete a work in 18 days. How many hours a day must 12 men work to complete the same work in 12 days?
Options:
A)6
B)7
C)8
D)9
E)10
Rationale: The number of hours required to complete the work is 8*8*18 = 1152
12 × 12 × (x) = 1152
x = 8
The answer is C.
Answer: C
Question: There are 17 teams in the hockey league, and each team faces all the other teams 10 times each. How many games are played in the season?
Options:
A)980
B)1150
C)1360
D)1540
E)1720
Rationale: The number of ways to choose two teams is 17C2 = 17*16/2 = 136
The total number of games in the season is 10*136 = 1360.
The answer is C.
Answer: C
Question: What will come in place of the x in the following Number series? 73205, 6655, 605, 55, x
Options:
A)35678
B)73205
C)75653
D)86554
E)87565
Rationale: (B)
5 x 11 = 55, 55 x 11 = 605, 605 x 11 = 6655, 6655 x 11 = 73205
Answer: B
Question: A can do a piece of work in 40 days; B can do the same in 30 days. A started alone but left the work after 10 days, then B worked at it for 10 days. C finished the remaining work in 10 days. C alone can do the whole work in?
Options:
A)24
B)55
C)66
D)21
E)11
Rationale: 10/40 + 10/30 + 10/x = 1
x = 24 days
Answer: A
Answer: A
Question: From a pack of cards, two cards are drawn one after the other, with replacement. What is the probability that the first card is a club and the second card is a king?
Options:
A)2/13
B)1/26
C)5/26
D)1/52
E)17/52
Rationale: P(club) = 1/4
P(king) = 1/13
P(club then a king) = 1/4 * 1/13 = 1/52
The answer is D.
Answer: D
Question: The ages of Ashley and Mary are in the ratio 4:7. The sum of their ages is 22. Find the ages of Ashley .
Options:
A)7
B)8
C)9
D)10
E)11
Rationale: a:m=4:7
let the ages of a & m be x &22-x
x/22-x=4/7
x=8
a=8yrs
ANSWER:B
Answer: B
Question: The average (arithmetic mean) of y numbers is x. If 25 is added to the set of numbers, then the average will be x - 5. What is the value of y in terms of x ?
Options:
A)x/6 - 6
B)x/6 - 5
C)x/7 - 5
D)x/5 - 7
E)x/5 - 6
Rationale: (A1 + A2 + .. + Ay)/y = x
(A1 + A2 + .. + Ay + 25)/(y+1) = x - 5
=> (xy + 25)/(y+1) = x - 5
=> xy + 25 = yx -5y + x - 5
=> 30 = x - 5y
=> 5y = x - 30
=> y = x/5 - 6
E
Answer: E
Question: A certain quantity of 45% solution is replaced with 25% solution such that the new concentration is 35%. What is the fraction of the solution that was replaced?
Options:
A)1/4
B)1/3
C)1/2
D)2/3
E)3/4
Rationale: Let's say that the total original mixture A is 100 ml
The original mixture A thus has 45 ml of alcohol out of 100 ml of solution
You want to replace some of that original mixture A with another mixture B that contains 25 ml of alcohol per 100 ml. Thus, the difference between 45 ml and 25 ml is 20 ml per 100 ml of mixture. This means that every time you replace 100 ml of the original mixture A by 100 ml of mixture B, the original alcohol concentration will decrease by 20%. The question says that the new mixture, let's call it C, must be 35% alcohol, a decrease of only 10%. Therefore, 10 out of 20 is 1/2 and C is the answer.
Answer: C
Question: 4 professors and 6 students are being considered for membership on a supervisory committee which must consist of 2 people. If the committee has to include at least 2 professor, how many ways can this committee be formed?
Options:
A)36
B)60
C)72
D)80
E)64
Rationale: you count up combinations twice.
4*9*8... and let me name 6 with students A,B,C,..,F
after choosing a professor, when you choose Student A and B, you can choose A first, then B. Or B first, then A. Both combination are same.
I don't think that's the only mistake.
64 is a factor of = 2^2*4^2
64 is a factor of = 2^4*2^2.
These are very different numbers and you cannot divide 64 with something to get to 64. ANS E
Answer: E
Question: A man sells a horse for Rs.1200 and loses something, if he had sold it for Rs.1500, his gain would have been trible the former loss. Find the cost price of the horse?
Options:
A)700
B)800
C)875
D)1000
E)900
Rationale: CP = SP + 1CP = SP - g
1200 + x = 1500 -3x
4x = 300 => x = 75
CP = 800 + 75 = 875
Answer: C
Answer: C
Question: Peter read Q books last year, and Nikki read N books last year. If Peter read 35 more books than Nikki last year, which of the following reflects this relationship?
Options:
A)Q > 35N
B)Q < N − 35
C)Q > N + 35
D)Q = N − 35
E)Q = N + 35
Rationale: Peter read Q books last year, and Nikki read N books last year. If Peter read 35 more books than Nikki last year, which of the following reflects this relationship?
A. Q > 35N
B. Q < N − 35
C. Q > N + 35
D. Q = N − 35
E. Q = N + 35
Since Peter read more books than Nikki we have Q>N. Moreover since Peter reads 35 more books than Nikki easily we can have Q=N+35.
So the answer is (E).
Answer: E
Question: A 4-person task force is to be formed from the 4 men and 3 women who work in Company G's human resources department. If there are to be 2 men and 2 women on this task force, how many different task forces can be formed?
Options:
A)14
B)18
C)35
D)56
E)144
Rationale: The number of ways to choose 2 men out of 4 is C24=6;
The number of ways to choose 2 women out of 3 is C23=3.
Principle of Multiplication says that if one event can occur in mm ways and a second can occur independently of the first in nn ways, then the two events can occur in mnmn ways.
Thus the number of ways to choose 2 men AND 2 women is 6*3=18.
Answer: B.
Answer: B
Question: {-10, -6, -5, -4, -2.5, -1, 0, 2.5, 4, 6, 7, 10}
A number is to be selected at random from the set above. What is the probability that the number will be a solution to the equation (x-4)(x+9)(2X+5) = 0?
Options:
A)1/12
B)1/6
C)1/4
D)1/3
E)1/2
Rationale: x = -2.5
Prob =1/12
Answer - A
Answer: A
Question: Set M contains numbers that satisfy the condition that, if integer x is in the set then x+3 will also be in the set M. If -3 is one of the value in the set, which of the following numbers must also be present in the set M.
I. 3
II. -10
III.1
Options:
A)I only
B)II only
C)I and II only
D)II and III only
E)I, II and III
Rationale: Notice that we are askedwhich of the following numbers MUST also be present in the set MnotCOULD be in the set.
Now, if -3 is in the set, then -3+3=0mustbe in the set. Since 0 is in the set then 0+3=3mustbe in the set and 6 also. Could -8 or 1 be in the set? sure no.
Answer: A.
Answer: A
Question: If a choir consists of 5 boys and 7 girls, in how many ways can the singers be arranged in a row, so that all the boys are together? Do not differentiate between arrangements that are obtained by swapping two boys or two girls.
Options:
A)120
B)30
C)24
D)11
E)8
Rationale: There are 7 possibilities:
bbbbbggggggg
gbbbbbgggggg
ggbbbbbggggg
gggbbbbbgggg
ggggbbbbbggg
gggggbbbbbgg
ggggggbbbbbg
gggggggbbbbb
Think of all 5 boys as a single unit. Together with 7 girls it makes a total of 8 units. The difference between the arrangements is the position of the boys (as a single unit). So the problem reduces to finding the number of unique patterns generated by changing the position of the boys who can occupy 1 of 8 available positions. If the number of available unique positions is 8, then the number of unique patterns equals 8 as well.
Answer: E.
Answer: E
Question: A, Band C enter into partnership. A invests 3 times as much as B and B invests two-third of what C invests. At the end of the year, the profit earned is Rs. 4400. What is the share of B ?
Options:
A)1100
B)800
C)1400
D)1200
E)None of them
Rationale: Let C's capital = Rs. x. Then, B's capital = Rs. (2/3)x
A’s capital = Rs. (3 x (2/3).x) = Rs. 2x.
Ratio of their capitals = 2x : (2/3)x :x = 6 : 2 : 3.
Hence, B's share = Rs. (4400 x (2/11))= Rs. 800.
Answer is B
Answer: B
Question: A farmer spent $35 on feed for chickens and goats. He spent 40% money on chicken feed, which he bought at a 50% discount off the full price, and spent the rest on goat feed, which he bought at full price. If the farmer had paid full price for both the chicken feed and the goat feed, what amount would he have spent on the chicken feed and goat feed combined?
Options:
A)$37.80
B)$49
C)$39.20
D)$39.50
E)$40.60
Rationale: A farmer spent 40% money on chicken feed, so he spent 0.4*$35=$14 on chicken feed, thus he spent the remaining 35-14=$21 on goat feed.
Now, since he bought chicken feed at a 20% discount then the original price of it was x*0.5=$14 --> x=$28.
Therefore if the farmer had paid full price for both the chicken feed and the goat feed, then he would he have spent 28+21=$49.
Answer: B.
Answer: B
Question: What is the range of all the roots of |x^2 - 5| = x ?
Options:
A)4
B)3
C)2
D)1
E)0
Rationale: we get 2 quadratic equations here ..
1) x^2-x-5=0 ....... roots 2 , -1
2) x^2+x-5=0 ........ roots -2, 1
Inserting each root in given equation , it can be seen that -1 and -2 do not satisfy the equations .
So value of x for given equation .... x=5 or x=1
I guess range is 5-1 =4
A
Answer: A
Question: What is the simple interest rate per annum on an investment that took up to 12.5 years to double its initial amount?
Options:
A)10
B)6
C)12
D)4
E)8
Rationale: P = (P*SI*12.5)/100
100P = P*SI*12.5
100 = 12.5SI
Therefore SI = 8%
E= 8
Answer: E
Question: The speed of a boat in upstream is 60 kmph and the speed of the boat downstream is 80 kmph. Find the speed of the boat in still water and the speed of the stream?
Options:
A)10 kmph
B)20 kmph
C)19 kmph
D)17 kmph
E)14 kmph
Rationale: Speed of the boat in still water = (60+80)/2 = 70 kmph. Speed of the stream
= (80-60)/2
= 10 kmph.
Answer:A
Answer: A
Question: A certain pair of used shoes can be repaired for $13.50 and will last for 1 year. A pair of the same kind of shoes can be purchased new for $32.00 and will last for 2 years. The average cost per year of the new shoes is what percent greater than the cost of repairing the used shoes?
Options:
A)17.69
B)14.85
C)21.3
D)16.5
E)18.51
Rationale: 1) Cost of repairing = 13.5 ( for one year ), Therefore for 2 years it would be$ 27.
2) Cost of new pair which will last for 2 years is$ 32.
Percentage change formula =( Final value - Initial value ) / ( Initial Value ) * 100. In this case the final value would be the price of new shoe initial value would be the cost of repairing the old shoe.
I.e ( 32 - 27 ) / ( 27 ) * 100 = 18.51 %.
Ans is E
Answer: E
Question: How many cubes of 5cm edge can be cut out of a cube of 20cm edge
Options:
A)36
B)64
C)216
D)484
E)None of these
Rationale: Explanation:
number of cubes=(20 x 20 x 20) / (5 x 5 x 5) = 64
Answer: B
Answer: B
Question: If man pays 20 for each km which he travels by taxi
and 10 for each km which he travels by bus. If in one
week he payed 800 for traveling 60 km. How many kilometers did he travel by taxi ?
Options:
A)23
B)78
C)27
D)29
E)20
Rationale: Let the distance covered by the taxi be 'x' km. Then, distance covered by bus = (60 – x) km. 20x + 10 (60 – x)⇒20x + 600 – 10x = 800 10x = 200 ⇒ x = 20 km. He traveled 20 km by taxi.
Answer:E
Answer: E
Question: A clock store sold a certain clock to a collector for 20 percent more than the store had originally paid for the clock. When the collector tried to resell the clock to the store, the store bought it back at 50 percent of what the collector had paid. The shop then sold the clock again at a profit of 80 percent on its buy-back price. If the difference between the clock's original cost to the shop and the clock's buy-back price was $100, for how much did the shop sell the clock the second time?
Options:
A)$270
B)$250
C)$240
D)$220
E)$200
Rationale: Original Price = x
Sold to collector at 1.2x
re-buy price = 1.2x * 0.5 = 0.6x
therefore, x - 0.6x = 100; x = 250
second selling price = 1.8 * 0.6 * 250 = 270
ANSWER:A
Answer: A
Question: A straight pipe 1 meter in length was marked off in fourths and also in fifths. If the pipe was then cut into separate pieces at each of these markings, which of the following gives all the different lengths of the pieces, in fractions of a meter?
Options:
A) 1/20 and 1/10 only
B)1/5, 1/20 ,3/20 and 1/10
C) 1/6, 1/4, and 1/3
D) 1/12, 1/6 and 1/4
E) 1/12, 1/6, and 1/3
Rationale: Generally fast way to solve such problem is writing the different marks in ascending/descending order with same denominator:
Here 4th : 0/4, 1/4, 2/4, 3/4, 4/4
and 5th : 0/5, 1/5, 2/5, 3/5 , 4/5, 5/5
Now with understood common denominator 20 write the numbers : for 4th : 0,5,10,15,20 and for 5th : 0,4,8,12,16,20
Now comine : 0,4,5,8,10,12,15,16,20
Now find the cut with denominator 20 (Substracrt adjacent terms : 1/5, 1/20, 3/20, 1/10,1/10,3/20,1/20,1/5 i.e. 1/5, 1/20 ,3/20 and 1/10 after removing duplicates.
Answer : B
Answer: B
Question: How many multiples of 4 are there between 1 and 99 ?
Options:
A)20
B)24
C)26
D)25
E)22
Rationale: 4 multiples are 4,8,12,---------,92,96
It should be mentioned whether 1 and 99 are inclusive.
the answer is (96-4)/4+1=24
Answer is B
Answer: B
Question: A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 32, the how old is B?
Options:
A)10 years
B)12 years
C)14 years
D)15 years
E)16 years
Rationale: Let C's age be x years. Then, B's age = 2x years. A's age = (2x + 2) years.
(2x + 2) + 2x + x = 32
5x = 30
x = 6.
Hence, B's age = 2x = 12years.
B)
Answer: B
Question: Two trains 121 meters and 165 meters in length respectively are running in opposite directions, one at the rate of 80 km and the other at the rate of 65 kmph. In what time will they be completely clear of each other from the moment they meet?
Options:
A)7.75 sec
B)9.15 sec
C)7.15 sec
D)7.19 sec
E)7.25 sec
Rationale: Explanation:
T = (121 + 165)/ (80 + 65) * 18/5
T = 7.15
Answer: Option D
Answer: D
Question: A thief steals at a car at 2.30 p.m. and drives it at 60 km/hr. The theft is discovered at 3 p.m. and the owner sets off in another car at 75 km/hr. When will he overtake the thief?
Options:
A)5 pm
B)4 pm
C)3 pm
D)2 pm
E)1 pm
Rationale: the thief is overtaken x hrs after 2.30 p.m.
Then, distance covered by the owner in (x - 1/2) hrs.
60x = 75(x - 1/2) => x = 5/2 hrs.
So, the thief is overtaken at 5 p.m.
ANSWER A
Answer: A
Question: A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Options:
A)267
B)240
C)166
D)111
E)121
Rationale: Speed = (54 * 5/18) m/sec = 15 m/sec. Length of the train
= (15 x 20)m = 300 m. Let the length of the platform be x meters. Then, (x + 300)/36 = 15 ==> x + 300
= 540 ==> x
= 240 m.
Answer: B
Answer: B
Question: In a 100m race, Sam beats John by 6 seconds. On the contrary, if Sam allowed John to start 36m ahead of Sam, then Sam and John reach the finishing point at the same time. How long does Sam take to run the 100m race?
Options:
A)10.66 seconds
B)25 seconds
C)29 seconds
D)21 seconds
E)6.25 seconds
Rationale: Their difference is 6 second but this difference is 0 if john allows Sam to start the race from 36m ahead . that means Jhon was 36m away from finishing line when they started together . so He will cover 36 m in 6 seconds . so his speed =36/6=6 metre / second . so time taken =100/6=16.66 seconds . so Sam took = 10.66 seconds .
correct answer = A
Answer: A
Question: The speed at which a man can row a boat in still water is 15 kmph. If he rows downstream, where the speed of current is 3 kmph, what time will he take to cover 60 metres?
Options:
A)10
B)15
C)20
D)12
E)15
Rationale: Speed of the boat downstream = 15 + 3 = 18 kmph
= 18 * 5/18 = 5 m/s
Hence time taken to cover 60 m = 60/5 = 12 seconds.
ANSWER:D
Answer: D
Question: A man shows his friend a woman sitting in a park and says that she the daughter of my grandmother's only son.What is the relation between the two
Options:
A)brother sister relation
B)sister sister-in-law relation
C)daughter father relation
D)daughter mother relation
E)grand daughter father relation
Rationale: man(ram)--says-->friend(somu)
Let the Daughter (ramya)
(ram's)grandmother---->(ram's father)only son----->(ram's sister)Daughter.
The relation between Ram & Ramya is brother sister relation
ANSWER:A
Answer: A
Question: The cost price of a particular amount of articles is same as the number of articles. Selling price of the articles comes out to be 20. Over the whole transaction 25% is gained. What is X?
Options:
A)15
B)18
C)16
D)20
E)None of these
Rationale: Explanation:
According to the question let n be the number of articles.
=> Cost price of n articles = n
=> Selling price of n articles = 20
=> Profit % = 25%
=> Profit % = (SP - CP)/CP X 100
Putting the values in the formula
(20-n)/n x 100 = 25
=> 5n/4 = 20
=> n = 16
ANSWER C
Answer: C
Question: How many different positive integers are factors of 256 ?
Options:
A) 4
B) 6
C) 8
D) 16
E) 18
Rationale: 16×16=4^2 × 4^2
So total factors = (3+1)(3+1) = 16
Answer: D
Answer: D
Question: The sum of three prime numbers is 100. If one of them exceeds another by 36, then one of the numbers is:
Options:
A)7
B)29
C)41
D)67
E)89
Rationale: x+(x+36)+y=100 => 2x+y=64
Therefore y must be even prime, which is 2.
Therefore 2x+2=64 => x=31
Third prime number= (x+36)= (31+36)= 67.
Answer: D
Answer: D
Question: In what time will a train 100 meters long cross an electric pole, if its speed is 90 km/hr
Options:
A)8.5 seconds
B)2.8 seconds
C)3.5 seconds
D)2.5 seconds
E)4 seconds
Rationale: First convert speed into m/sec
Speed = 90*(5/18) = 25 m/sec
Time = Distance/speed
= 100/25 = 4 seconds
Answer: E
Answer: E
Question: What should come in the place of the question mark(?) in the following equation?
69012 – 20167 + (51246 ÷ 6) = ?
Options:
A)57385
B)57286
C)57476
D)57368
E)None of these
Rationale: ? = 48845 + 51246⁄6 = 48845 + 8541 = 57386
Answer E
Answer: E
Question: Tensile strength of a material A is a multiple of amount of materials a, b, c, d used. If the amount of material of a, b, c, d are changed by +30%, -30%, -25%, +25% respectively, what will be the overall change in tensile strength of A?
Options:
A)No Change
B)+14.68%
C)–14.68%
D)Depends on the initial amount of a, b, c, d
E)None of these
Rationale: DETAILED SOLUTION
Since, tensile strength of A = a x b x c x d, If we assume initial tensile strength to be 100, we can apply successive % changes to arrive at the final figure
100 -30% ---> 70 (Any of the change can be carried out first, the result would be same)
70 + 30% ---> 91
91 + 25% ---> 113.75
113.75 – 25% --> ~85.31
Therefore, percent change in tensile strength = -14.68%
Note – This question could have been solved by just looking at the options. As the individual percentage increase and percentage decrease are same, it will effectively result in an overall percentage decrease for sure because any increase by any % will result in a greater subsequent decrease if same % decrease is applied. Similarly, aby % decrease by any % will result in a smaller subsequent increase if same % increase is applied.
Correct Answer: C
Answer: C
Question: When T is divided by 9, the remainder is 4. All of the following are possible values of T, except for which of the following?
Options:
A)13
B)31
C)49
D)57
E)67
Rationale: The number can be expressed in the form of 9x+4 where x can 0,1,2,3,4....
by evaluating the answer choices carefully we can clearly observe that 57 is the only number which can't be expressed T in the form of 9x+4
In other words we can also say that the (answer - 4) will not be divisible by 9.57 is the number which doesn't follow this condition
Correct Answer - D
Answer: D
Question: Two trains 140 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time (in seconds) which they take to cross each other, is:
Options:
A)10.8 sec
B)9.5 sec
C)7.4 sec
D)8.9 sec
E)8.8 sec
Rationale: Relative speed = (60 + 40) km/hr = 100x5/18 = 250/9 m/ sec.
Distance covered in crossing each other = (140 + 160) m = 300 m.
Required time = 300x9/250 = 54/5 = 10.8 sec.
Answer : A.
Answer: A
Question: Ram professes to sell his goods at the cost price but he made use of 900 grms instead of a kg, what is the gain percent?
Options:
A)21 1/9%
B)61 1/9%
C)11 1/9%
D)31 1/9%
E)81 1/9%
Rationale: Explanation:
900 --- 100
100 --- ? => 11 1/9%
Answer: C
Answer: C