divelab/Sys2Bench huggingface dataset:
Question: The decimal d is formed by writing in succession all the positive integers in descending order after the decimal point; that is d = 0.15141312111098765
What is the 19th and 20th digits of d to the right of decimal point?
Options:
A)32
B)43
C)54
D)12
E)21
Rationale: The descending order of numbers begins with 15.
0.15141312111098765
So, 15, 14, 13, 12, 11, 10, ...,(first 12 digits are 2 digit numbers).
Then, 9, 8, 7, 6, 5, ...,(next 5 digits are single digit numbers).
It follows that 4, 3, and 2 are the next digits, thus 3 and 2 are the 19th and 20th digits, respectively.
Answer: A
Answer: A
Question: Find the simple interest on Rs. 69,600 at 16 2/3% per annum for 9 months.
Options:
A)s.8500
B)s.8700
C)s.7500
D)s.7000
E)s.6500
Rationale: P = Rs.69600,R = 50/3% p.a and T = 9/12 years = 3/4years.
S.I. = (P*R*T)/100 = Rs.(69,600*(50/3)*(3/4)*(1/100))
= Rs.8700
Answer is B.
Answer: B
Question: A man positioned at the origin of the coordinate system. the man can take steps of unit measure in the direction North, East, West or South. Find the number of ways of he can reach the point (5,6), covering the shortest possible distance.
Options:
A)252
B)432
C)462
D)504
E)None
Rationale: Solution:
In order to reach (5,6) covering the shortest distance at the same time the man has to make 5 horizontal and 6 vertical steps.
The number of ways in which these steps can be taken is given by,
[11! /(5! *6!)] = 462.
Answer: Option C
Answer: C
Question: Of the final grades received by the students in a certain math course, 1/5 are A's, 1/4 are B's, 1/2 are C's, and the remaining 30 grades are D's. What is the number of students in the course?
Options:
A) 80
B) 110
C) 160
D) 600
E) 400
Rationale: We start by creating a variable for the total number of students in the math course. We can say:
T = Total number of students in the math course
Next, we can use variable T in an equation that we translate from the given information. We are given that, of the final grades received by the students in a certain math course, 1/5 are A's, 1/4 are B's, 1/2 are C's, and the remaining 30 grades are D's. Since this represents all the grades in the class, it represents all the students in the class. Thus we know:
#A’s + #B’s + #C’s + #D’s = Total number of students in the class
1/5(T) + ¼(T) + ½(T) + 30 = T
We can multiply the entire equation by 20 to cancel out the denominators of the fractions and we have:
4T + 5T + 10T + 600 = 20T
19T + 600 = 20T
600 = T
There are a total of 600 students in the math class.
Answer is D.
Answer: D
Question: How many liters of water must be evaporated from 50 liters of a 2-percent sugar solution to get a 10-percent solution?
Options:
A)25
B)30
C)35
D)40
E)45
Rationale: 2% of a 50 liter solution is 1L which is 10% of the solution at the end.
The solution at the end must be 1 L.
We need to evaporate 40 liters.
The answer is D.
Answer: D
Question: The tax on a commodity is diminished by 20% but its consumption is increased by 10%. Find the decrease percent in the revenue derived from it?
Options:
A)11%
B)82%
C)14%
D)12%
E)17%
Rationale: 100 * 100 = 10000
80 * 110 = 8800
10000------- 1200
100 ------- ? = 12%
Answer:D
Answer: D
Question: If the tens digit of positive integers j, y are 6, how many values of the tens digit of 2(j+y) can be there?
Options:
A)2
B)3
C)4
D)5
E)6
Rationale: If the tens digit of positive integers j, y are 6, how many values of the tens digit of 2(j+y) can be there?
A. 2
B. 3
C. 4
D. 5
E. 6
-> If j=y=60, 2(j+y)=240 is derived. If j=y=69, 2(j+y)=276 is derived, which makes 4,5,6,7 possible for the tens digit. Therefore, the answer is C.
Answer: C
Question: The length of the bridge, which a train 120 meters long and travelling at 45 km/hr can cross in 30 seconds, is:
Options:
A)230
B)244
C)245
D)255
E)236
Rationale: Speed = (45 * 5/18) m/sec = (25/2) m/sec. Time = 30 sec. Let the length of bridge be x meters. Then, (120 + X)/30 = 25/2 ==> 2(120 + X) = 750 ==> X = 255 m.
Answer: Option D
Answer: D
Question: A trader mixes 26 kg of rice at Rs. 20 per kg with 30 kg of rice of other variety at Rs. 36 per kg and sells the mixture at Rs. 30 per kg. His profit percent is:
Options:
A)5%
B)8%
C)10%
D)12%
E)6%
Rationale: C.P. of 56 kg rice = Rs. (26 x 20 + 30 x 36)
= Rs. (520 + 1080)
= Rs. 1600.
S.P. of 56 kg rice = Rs. (56 x 30) = Rs. 1680.
Gain =(80/1600x 100)% = 5%.
Answer is A.
Answer: A
Question: How many plants will be there in a circular bed whose outer edge measure 31 cms, allowing 4 cm2 for each plant ?
Options:
A)19
B)750
C)24
D)120
E)None of these
Rationale: Circumference of circular bed = 31 cm
Area of circular bed = (31)2â„4Ï€
Space for each plant = 4 cm2
âˆ´ Required number of plants
= (31)2â„4Ï€ Ã· 4 = 19.11 = 19(approx)
Answer A
Answer: A
Question: If a,b, and c are consecutive positive integers and a>b>c, what can be the value of (a^2-b^2)(b^2-c^2)?
Options:
A)100
B)110
C)121
D)132
E)143
Rationale: (a^2-b^2)(b^2-c^2) = (a+b)*(a-b)*(b+c)*(b-c) = (a+b)*(-1)*(b+c)*(-1) = (a+b)*(b+c)
Therefore, the product should have factors with a difference of 2.
143 = 11*13, so this is a possible value for the original expression.
The answer is E.
Answer: E
Question: If B and C are digits and 8BC is a 3-digit number that is divisible by 5, which of the following is a possible product of B and C?
Options:
A)1
B)2
C)5
D)7
E)14
Rationale: Try with the options -
A. If BC = 1 , both B and C must be 1
B. If BC = 2 , either B or C must be 1 or 2 ; In that case sum of the digits will be 8 + 1 + 2 = 11 which is not divisible by 3
C. If BC = 5 , either B or C must be 1 or 5 ; In that case sum of the digits will be 8 + 1 + 5 = 14 which is not divisible by 3
D. If BC = 6 , then we can have the following possibilities
i. Either B or C must be 2 or 3 ; In that case sum of the digits will be 8 + 2 + 3 = 13 which is not divisible by 3
ii. Either B or C must be 1 or 6 ; In that case sum of the digits will be 8 + 1 + 6 = 15 which is divisible by 3
E. If BC = 14 , then either B or C must be 2 or 7 ; In that case sum of the digits will be 8 + 2 + 7 = 17 which is not divisible by 5
Thus answer is (D)
Answer: D
Question: A prize pool for a competition is divided up so that the first place winner receives 50%, the second place 30%, and third place receives 20%. If the third place competitor receives 100 000 dollars, how much is the total prize pool in dollars?
Options:
A)500 000
B)1 000 000
C)2 000 000
D)5 000 000
E)250 000
Rationale: The ratio is 5:3:2. Since third place received 100 000 dollars, a part-to-whole ratio can be set up to figure out how much the total prize pool is.
5+3+2 = 10
10/2 = X/100 000
5*100 000 = X
500 000 = X
Answer: A)
Answer: A
Question: A tap can fill a tank in 6 hours. After half the tank is filled three more similar taps are opened. What is the total time taken to fill the tank completely?
Options:
A)3 hrs 48 min
B)3 hrs 45 min
C)3 hrs 75 min
D)6 hrs 45 min
E)3 hrs 55 min
Rationale: Time taken by one tap to fill the tank = 3 hrs.
Part filled by the taps in 1 hour = 4 * 1/6 = 2/3
Remaining part = 1 - 1/2 = 1/2
2/3 : 1/2 :: 1 : x
x = 1/2 * 1 * 3/2 = 3/4 hrs. i.e., 45 min
So, total time taken = 3 hrs 45 min.
Answer: B
Answer: B
Question: a contract was signed to complete a job in 30 days. after how many days can 5 men leave then so that the job can be completed in 35 days
Options:
A)30 days.
B)35 days.
C)45 days.
D)55 days.
E)65 days.
Rationale: If no of men used initially is x, then after (35-x) days 5 men can leave so that the job can be completed in 35 days.
ANSWER:B
Answer: B
Question: 3^9+3^9+3^9=?
Options:
A)a) 243^5
B)b) 243^4
C)c) 243^2
D)d) 243^6
E)e) 243^15
Rationale: The correct answer is C 243^2
Answer: C
Question: In a division sum, the remainder is 6 and the divisor is 5 times the quotient and is obtained by adding 2 to the thrice of the remainder. The dividend is:
Options:
A)86
B)88
C)92
D)94
E)96
Rationale: Divisor = (6 * 3) + 2 = 20
5 * Quotient = 20
Quotient = 4.
Dividend = (Divisor * Quotient) + Remainder
Dividend = (20 * 4) + 6 = 86.
A
Answer: A
Question: In an examination, 5% of the applicants were found ineligible and 85% of the eligible candidates belonged to the general category. If 4275 eligible candidates belonged to other categories, then how many candidates applied for the examination?
Options:
A)28000
B)30000
C)32000
D)33000
E)35000
Rationale: 85% of the eligible candidate hence remaining 15% eligible candidate
= 4275
eligible candidates = 4275*100/15=28500
5% of the applicants were ineligible
95% of applicants = 28500
no of applicants = 28500*100/95 = 30000
ANSWER B
Answer: B
Question: A container contains 40 litres of milk. From this container 4 litres of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container?
Options:
A)26 litres
B)29.16 litres
C)28 litres
D)28.2 litres
E)30 litres
Rationale: Explanation:
Suppose a container contains xx units of a liquid from which yy units are taken out and replaced by water. After nn operations, quantity of pure liquid =x(1âˆ’yx)n units
milk contained by the container now
=40(1âˆ’440)3=40(1âˆ’110)3=40Ã—9/10Ã—9/10Ã—9/10
=4Ã—9Ã—9Ã—9 / 100
=29.16
ANSWER IS B
Answer: B
Question: How many numbers from 2 to 7 are exactly divisible by 2?
Options:
A)2
B)3
C)5
D)7
E)8
Rationale: 2/2 = 1 and 7/2 = 3
3 - 1 = 2
2 + 1 = 3 Numbers.
B)
Answer: B
Question: A software has coding line 5% more than B, B software has coding line 4/12 more than C. C software has 90 lines of coding. find A lines.
Options:
A)106
B)107
C)108
D)126
E)110
Rationale: C s/w has 90 line of code
B s/w has = 90+90*4/12= 120 line of code
A s/w 5% more B' code 120+6=126
ANSWER:D
Answer: D
Question: If a 3 cm cube is cut into 1 cm cubes, then what is the percentage increase in the surface area of the resulting cubes?
Options:
A)40%
B)100%
C)150%
D)200%
E)300%
Rationale: The area A of the large cube is 3*3*6 = 54 square cm.
The area of the 27 small cubes is 27*6 = 54*3 = 3A, an increase of 200%.
The answer is D.
Answer: D
Question: Cereal A is 11% sugar by weight, whereas healthier but less delicious Cereal B is 2% sugar by weight. To make a delicious and healthy mixture that is 4% sugar, what should be the ratio of Cereal A to Cereal B, by weight?
Options:
A)2:5
B)1:3
C)2:7
D)3:4
E)1:5
Rationale: 2% is 2%-points below 4% and 11% is 7%-points above 4%.
The ratio of A:B should be 2:7.
The answer is C.
Answer: C
Question: In a certain game, you perform three tasks. You flip a quarter, and success would be heads. You roll a single die, and success would be a five. You pick a card from a full playing-card deck, and success would be picking a spades card. If any of these task are successful, then you win the game. What is the probability of winning?
Options:
A)1/48
B)5/16
C)11/12
D)11/16
E)22/32
Rationale: First lets get the overview
Event 1(A) = Flipping the quarter( Probability of both winning/loosing = 1/2)
Event 2(B) = Rolling a dice( Probability of winning = 1/6 ;Probability of loosing= 1 - 1\6 =5\6)
Event 3(C) = Drawing a card( SPADES) Probability of winning = 13/52=3/4 ;Probability of loosing= 1 - 3/4 =1/4)
So now as above we have three events A,BC.
1st method(This is lengthy method)
Possible cases in which it's a win( the highlighted green event is a win and red is loose.
1.ABC= 1/2*5/6*3/4
OR
2.ABC= 1/2*1/6*3/4
OR
3.ABC= 1/2*5/6*1/4
OR
4.ABC= 1/2*1/6*3/4
OR
5.ABC= 1/2*5/6*1/4
OR
6.ABC= 1/2*5/6*1/4
OR
7.ABC= 1/2*1/6*1/4
As we now OR means add
Adding up all of them we'll get the probability of winning ie 22/32
Answer : E
Answer: E
Question: The average age of seven persons sitting in a row facing east is 28 years. If the average age of the first three persons is 25 years and the average age of the last three persons is 36 years, then find the age of the person sitting in the middle of the row?
Options:
A)9 years
B)29 years
C)18 years
D)13 years
E)17 years
Rationale: Total age seven persons = (28 * 7)years
Total age of the first three persons and the last three persons are (25 * 3) years and (36 * 3) years respectively.
Age of the person sitting in the middle of the row = 28 * 7 - 25 * 3 - 36 * 3 = 196 - 75 - 108 = 13 years.
ANSWER:D
Answer: D
Question: On dividing 13787 by a certain number, we get 89 as quotient and 14 as remainder. What is the divisor?
Options:
A)743
B)155
C)852
D)741
E)785
Rationale: Divisor *quotient+remainder=dividend
divisor=(dividend)-(remainder)/quotient
(13787-14)/89=155
Answer(B)
Answer: B
Question: There are some balloons in party, 1/3rd blasted by kids . Then 2/5th of the remaining by men , then 2/3rd of the remaining by women . At last 20 were remaining . How many balloons were in total ?
Options:
A)150
B)27
C)28
D)26
E)91
Rationale: Sol:
45
If x persons were there in total , then
x × (1 – 1/3)× (1 – 2/5) ×(1 – 2/3) = 20
x×2/3 × 3/5 × 1/3 = 20
x = 150
Answer:A
Answer: A
Question: Find the compound interest on Rs. 16,000 at 20% per annum for 9 months, compounded quarterly
Options:
A)3378
B)2522
C)2778
D)2567
E)1781
Rationale: Explanation:
Principal = Rs. 16000; Time = 9 months =3 quarters;
Rate = 20% per annum = 5% per quarter.
Amount = Rs. [16000 x (1+(5/100))3] = Rs. 18522.
CJ. = Rs. (18522 - 16000) = Rs. 2522
Answer: B) 2522
Answer: B
Question: On a map, 7 centimeters represents 35 kilometers. Two cities 245 kilometers apart would be separated on the map by how many centimeters?
Options:
A)15
B)37
C)49
D)110
E)180
Rationale: 1 centimeter represents 5 kilometers ( 35/7 )
X=245/5= 49
Answer: C
Answer: C
Question: There are 60 supermarkets in the FGH chain. All of them are either in the US or Canada. If there are 14 more FGH supermarkets in the US than in Canada, how many FGH supermarkets are there in the US?
Options:
A)20
B)37
C)42
D)53
E)64
Rationale: x + (x - 14) = 60 --> x = 37.
Answer: B.
Answer: B
Question: x varies inversely as square of y. Given that y=3 for x=1. The value of x for y = 5 will be equal to:
Options:
A)3
B)6
C)1/9
D)1/3
E)9/25
Rationale: Explanation :
Solution: Given x = k/y^2, where k is constant. Now, y=3 and x =1 gives k = 9.
.'. x = 9/y^2
=> x =9 /5^2 = 9/25
Answer : E
Answer: E
Question: If k is a positive integer, which of the following must be divisible by 25?
Options:
A) (k – 4)(k)(k + 3)(k + 7)
B) (k – 4)(k – 2)(k + 3)(k + 5)
C) (k – 2)(k + 3)(k + 5)(k + 6)
D) (k + 1)(k + 3)(k + 5)(k + 7)
E) (k – 3)(k + 1)(k + 4)(k + 6)
Rationale: 24=8*3.
Note that the product of two consecutive even integers is always divisible by 8 (since one of them is divisible by 4 and another by 2). Only option B offers two consecutive even numbers for any integer value of k: k-4 and k-2, if k=even or k+3 and k+5 if k=odd.
Also from the following 3 consecutive integers:(k-4), (k-3),(k-2)one must be divisible by 3, if it's not k-4 or k-2 then it must be k-3 (if it's k-4 or k-2 option B is divisible by 3 right away). But if it's k-3 then (k-3)+6=k+3must also be divisible by 3.
So, option B: (k – 4)(k – 2)(k + 3)(k + 5) is divisible by 8 and 3 in any case.
Answer: C.
Answer: C
Question: If PINTU is coded as 79523 in a certain code language, how would you code MUMBO in the same language?
Options:
A)43426
B)14236
C)13436
D)14263
E)15263
Rationale: 1 2 3 4 5 6 7 8 9
a b c d e f g h i
j k l m n o p q r
s t u v w x y z
sooo...MUMBO is 43426...
ANSWER:A
Answer: A
Question: Amy has two decks of 52 cards each: Deck 1 and Deck 2. She takes 7 black cards from Deck 2 and adds them to Deck 1 and shuffles it thoroughly. She now picks a card from the newly formed pack of cards. If the probability of either picking a red ace or a king from the newly formed pack is greater than 1/8, what is the probability that Amy picks a black king or a red Jack from the new pack?
Options:
A)1/6
B)1/8
C)1/9
D)1/10
E)1/12
Rationale: Your solution is correct answer should be 1/8.
B
Answer: B
Question: A, B and C can do a work in 5 days, 8 days and 12 days respectively. In how many days can all three of them working together, complete the work?
Options:
A)2 22/49
B)2 2/49
C)2 2/0
D)2 2/2
E)2 2/19
Rationale: Work done by all three of them in one day = 1/5 + 1/8 + 1/12 = 49/120.
The number of days required = 120/49 = 2 22/49 days.
Answer:A
Answer: A
Question: Exactly 36% of the numbers in set W are even multiples of 3. If 40% of the even integers in set W are not multiples of 3, what percent of the numbers in set W are not even integers?
Options:
A) 76%
B) 60%
C) 50%
D) 40%
E) 24%
Rationale: Everything is correct except the red part with a typo: it should be N=0.6W --> even numbers are 60% of W --> 40% of W are not even integers.
Answer: D.
Answer: D
Question: When a train travels at a speed of 110kmph,it reaches the destination on time.when the same train travels at a speed of 50kmph,it reaches its destination 15min late.what is the length of journey?
Options:
A)12.5km
B)50km
C)60km
D)8.5km
E)9.5km
Rationale: Let x be the time reached with the speed 110km/h
50km/h ----> x+15
Distance is equal so
110(km/h)× xhr = 50(km/h) × (x+15) hr
So
110 x = 50x + 750
So the would be in km
And x = 12.5
ANSWER:A
Answer: A
Question: Paul sells encyclopedias door-to-door. He earns $170 on every paycheck, regardless of how many sets he sells. In addition, he earns commission as follows:
Commission Sales
10% $0.00 - $10,000.00
5% $10,000.01 --->
He does not earndouble commission.That is, if his sales are $12,000, he earns 10% on the first $10,000 and 5% on the remaining $2,000.
His largest paycheck of the year was $1,320. What were his sales for that pay period?
Options:
A)13,000
B)14,800
C)16,400
D)15,800
E)19,600
Rationale: His pay check was $1320.
Out of this, $170 was his fixed salary so the total commission he earned was $1320 - $170 = $1150
He earns 10% on the sales of first $10,000 which gives a commission of $1000.
He earns 5% on every subsequent dollar. Since he earns another $150, he must have had sales of another 150*(100/5) = 3000
So his total sales must have been $10,000 + $3000 = $13,000
A
Answer: A
Question: John purchased 8kg of apples at the rate of 70 per kg and 9 kg of banana at the rate of 55 per kg. How much amount did he pay to the shopkeeper?
Options:
A)950
B)1000
C)1055
D)1060
E)1080
Rationale: Cost of 8 kg apples= 70 × 8 = 560.
Cost of 9 kg of bananas= 55 × 9 = 490.
Total cost he has to pay = 560 + 490 = 1055.
C)
Answer: C
Question: Find the average of all the numbers between 6 and 38 which are divisible by 4.
Options:
A)18
B)22
C)20
D)30
E)28
Rationale: Solution
Average	= ((8+12+16+20+24+28+32+36)/8)
= 186 / 7
= 22
Answer B
Answer: B
Question: If x and y are integers, and 4y+3x=23, which of the following could be the value of y ?
Options:
A)0
B)1
C)4
D)3
E)2
Rationale: Use answer options to solve this problem -
Put y = 2
So, 4y+3x=23
Or, 4(2)+3x=23
Or, 3x=23-8;3x=15
Or, x = 5
Answer will be (E)
Answer: E
Question: A man can do a job in 15 days. His father takes 20 days and his son finishes it in 25 days. How long will they take to complete the job if they all work together?
Options:
A)6.3
B)6.9
C)6.4
D)6.1
E)6.2
Rationale: 1 day work of the three persons = (1/15 + 1/20 + 1/25) = 47/300
So, all three together will complete the work in 300/47 = 6.4 days.
Answer:C
Answer: C
Question: There are 2 scales of temp A & B. It was given A 14 to 133, B 36 to 87. Find the temp when temp of A is equal to temp of B
Options:
A)52.5
B)53.5
C)51.5
D)54.5
E)55.5
Rationale: Actually, when corresponding ranges of two scales of temperatures are given, then, the formula to relate the two scales are given by, (A-l1)/(u1-l1) = (B-l2)/(u2-l2), where l1 and u1 are lower and upper limits of scale A; and l2 and u2 are lower and upper limits of scale B; and when it is l1 in scale A, it is l2 in scale B; and when it is u1 in scale A, it is u2 in scale B. Here, l1=14, u1=133, l2=36, u2=87. Substituting, we get (A-14)/(133-14)=(B-36)/(87-36). Or, 3(A-14)=7(B-36). When temperature readings are equal, i.e., A=B=x, 3(x-14)=7(x-36), 4x=210, x=52.5
ANSWER:A
Answer: A
Question: A class of students ate a total of 457 mints. If each student in the class ate at least 12 mints, then what is the greatest possible number of students in the class?
Options:
A)36
B)38
C)40
D)42
E)44
Rationale: 457/12=38 plus remainder.
The answer is B.
Answer: B
Question: Jacob brought a scooter for a certain sum of money. He spent 10% of the cost on repairs and sold the scooter for a profit of Rs. 1100. How much did he spend on repairs if he made a profit of 20%?
Options:
A)309
B)508
C)389
D)378
E)500
Rationale: Explanation:
Let the C.P. be Rs. x. Then, 20% of x = 1100
20/100 * x = 1100 => x = 5500
C.P. = Rs. 5500, expenditure on repairs = 10%
Actual price = Rs. (100 * 5500)/110 = Rs. 5000
Expenditures on repairs = (5500 - 5000) = Rs. 500.
Answer:E
Answer: E
Question: In a colony of 70 residents, the ratio of the number of men and women is 4:3. Among the women, the ratio of the educated to the uneducated is 1:4. If the ratio of the number of education to uneducated persons is 8:27, then find the ratio of the number of educated and uneducated men in the colony?
Options:
A)1:7
B)1:1
C)1:2
D)1:9
E)1:3
Rationale: Number of men in the colony = 4/7 (70) = 40
Number of women in the colony = 3/7 (70) = 30
Number of educated women in the colony = 1/5 (30) = 6
Number of uneducated women in the colony = 4/5 (30) = 24
Number of educated persons in the colony = 8/35 (70) = 16
As 6 females are educated, remaining 10 educated persons must be men.
Number of uneducated men in the colony = 40 - 10 = 30
Number of educated men and uneducated men are in the ratio 10:30 => 1:3
Answer:E
Answer: E
Question: Evaluate: 60 - 12÷4×2 =
Options:
A)A)45
B)B)54
C)C)63
D)D)72
E)E)81
Rationale: According to order of operations, 12÷4×2 (division and multiplication) is done first from left to right
12÷4×2 = 3 × 2 = 6
Hence
60 - 12÷4×2 = 60 - 6 = 54
correct answer is B) 54
Answer: B
Question: Bradley owns b video game cartridges. If Bradley’s total is one-fourth the total owned by James and six times the total owned by Charlie, how many video game cartridges do the three of them own altogether, in terms of b?
Options:
A)(16/3)b
B)(31/6)b
C)(13/6)b
D)(19/12)b
E)(7/12)b
Rationale: b = Bradley’s total
4b = James’s total
(1/6)b = Charlie’s total
Add each total
b + 4b+ (1/6)b = 5b + (1/6)b = = (31/6)b
Answer : B
Answer: B
Question: Jerry covers a distance of 8km in 50 minutes. If he covers 3km distance in 2/5th of time then, What speed should he maintain to cover the remaining distance in the remaining time?
Options:
A)29 Kmph
B)15 Kmph
C)23 Kmph
D)22 Kmph
E)19 Kmph
Rationale: Total distance = 8 Km
Total time = 50 Km
Time taken to cover the distance of 3 Km = 50*2/5 = 20 min = 1/3 hours
Remaining distance = 8 - 3 = 5 Km
Required speed = 5/1/3 = 15 Kmph
B
Answer: B
Question: What number comes next in this sequence?
1, 3, 11, 47, ?
Options:
A)153
B)364
C)239
D)266
E)484
Rationale: C
239
1 Ã— 2 + 1 = 3;
3 Ã— 3 + 2= 11;
11 Ã— 4 + 3 = 47;
47 Ã— 5 + 4 = 239;
Answer: C
Question: There are two decks of 10 cards each. The cards in each deck are labeled with integers from 11 to 20 inclusive. If we pick a card from each deck at random, what is the probability that the product of the numbers on the picked cards is a multiple of 5?
Options:
A)0.23
B)0.36
C)0.4
D)0.42
E)0.46
Rationale: If 6 is a multiple, we need 2 and 3 as a factor of the number. If we factor the numbers 11 through 20 we have:
11 = 11
12 = 2*2*3
13 = 13
14 = 7*2
15 = 5*3
16 = 2*2*2
17 = 17
18 = 3*2*3
19 = 19
20 = 5*2*2
Combos that have a 2 and a 3 as factors (first + second card):
12 + anything - 19 of these possibilities (we count 12 + 12 only once)
14 + 15 - 2 of these possibilities
15 + 16 - 2 of these possibilities
15 + 20 - 2 of these possibilities
18 + anything (except 12, since that is counted in our first option) - 17 of these possibilities
Total possibilities that will be a multiple of 6: 42
Total possibilites: 10*10=100
Probability = 42/100 = 0.36
Answer:B
Answer: B
Question: The length of the bridge, which a train 130 meters long and travelling at 45 km/hr can cross in 30 seconds, is?
Options:
A)156
B)245
C)288
D)265
E)271
Rationale: Speed = (45 * 5/18) m/sec = (25/2) m/sec. Time
= 30 sec. Let the length of bridge be x meters. Then, (130 + X)/30 = 25/2 ==> 2(130 + X)
= 750 ==> X
= 245 m.
Answer: C
Answer: C