divelab/Sys2Bench huggingface dataset:
Question: In a code language “He gives flower” is written as “nop lui na” , “Bunty gets flower” is written as “dus lap na” and “He gets nothing” is written as “nop lap ugli”. How would “Bunty gets nothing” be written in that code ?
Options:
A)dus lap ugli
B)dus lap uglJ
C)dus lap ugl2
D)Dus lFp ugli
E)dus ap uglDi
Rationale: Explanation:
He gives flower ---------> nop lui na ---------- (a)
Bunty gets flower -------> dus lap na ----------- (b)
He gets nothing ----------> nop lap ugli --------- (c)
From a and b, we get “flower ===> na”; while from b and c, we get “gets ===> lap”. Hence from b, we get “Bunty ===> dus”. Now from a and c, we get “He ===> nop”.
Hence from c, we get “nothing ===> ugli”. Hence we have “Bunty gets nothing ===> dus lap ugli”.
ANSWER: A
Answer: A
Question: Five family members are seated around their circular dinner table. If only arrangements that are considered distinct are those where family members are seated in different locations relative to each other, and Michael and Bobby insist on sitting next to one another, then how many distinct arrangements around the table are possible?
Options:
A)10
B)12
C)14
D)16
E)18
Rationale: Let's consider Michael and Bobby as one unit.
There are 4! possible arrangements of 4 units.
Around a table, there would be repetitions of each arrangement, so we divide by 4.
Then there are 3! arrangements around a circular table.
For each arrangement, Michael and Bobby can switch places, so we multiply by 2.
The number of arrangements is 3!*2 = 12.
The answer is B.
Answer: B
Question: If the selling price of 50 articles is equal to the cost price of 35 articles, then the loss or gain percent is:
Options:
A)45%
B)23%
C)30%
D)60%
E)56%
Rationale: C.P. of each article be Re. 1.
Then, C.P. of 50 articles = Rs. 50;
S.P. of 50 articles = Rs. 35.
Loss % = 15/50 * 100 = 30%
ANSWER C
Answer: C
Question: In a certain sequence, each term except for the first term is one less than twice the previous term. If the first term is 1.25, then the 3rd term is which of the following?
Options:
A)−1.5
B)−1
C)0
D)0.5
E)2
Rationale: First = 1.25
Second = 2*1.25-1 = 1.5
Second = 2*1.5-1 = 2
Answer: option E
Answer: E
Question: If x is 11 percent greater than 70, then x =
Options:
A)77.7
B)91.0
C)88.0
D)70.9
E)71.2
Rationale: 11% of 70 = (70*0.11) = 7.7
11% greater than 70 = 70 + 7.7 = 77.7
Answer is clearly A.
Answer: A
Question: A group of four girls and three boys have tickets for seven adjacent seats in one row of a theater. If the three boys will not sit in three adjacent seats, how many possible different seating arrangements are there for these 7 theatre-goers?
Options:
A) 7! – 2!3!2!
B) 7! – 4!3!
C) 7 × 2!3!2!
D) 7! – 5!3!
E) 2!3!2!
Rationale: There are 3 boys and 4 girls , we want to calculate the seating arrangements if three boys do not sit together, like MMM.
Let's calculate the # of arrangements when they SIT together and subtract from total # of arrangements of these 7 persons without restriction. Thus we'll get the # of arrangements asked in the question.
1. Total # of arrangements of 7 is 7!.
2. # of arrangements when 3 boys are seated together, like MMM;
Among themselves these 3 boys can sit in 3! # of ways,
Now consider these 3 boys as one unit like this {MMM}. We'll have total of 5 units: {MMM}{W}{W}{W}{W}. The # of arrangements of these 5 units is 5!.
Hence total # of arrangements when 3 men sit together is: 3!5!.
# of arrangements when 3 boys do not sit together would be: 7!-3!5!.
Answer: D).
Answer: D
Question: If each participant of a chess tournament plays exactly one game with each of the remaining participants, then 231 games will be played during the tournament. What is the number of participants?
Options:
A)16
B)18
C)20
D)22
E)24
Rationale: Let n be the number of participants.
The number of games is nC2 = n*(n-1) / 2 = 231
n*(n-1) = 462 = 22*21 (trial and error)
The answer is D.
Answer: D
Question: A club with a total membership of 30 has formed 3 committees, M, S and R, which have 8, 12 and 7 members respectively. If no members of committee M is on either of the other 2 committees, what is the greatest possible number of members in the club who are on none of the committees?
Options:
A)5
B)7
C)8
D)10
E)12
Rationale: As no member of committee M is on either of the other 2 committees then 30-M=30-8=22 people are on committee S, committee R or on none of the committee. We want to maximize the last group: members in the club who are on none of the committees
General rule for such kind of problems:
to maximize one quantity, minimize the others;
to minimize one quantity, maximize the others.
So we should minimize total # of people who are on committee S and committee R. Now if ALL 5 people who are the members of committee R are also the members of committee S (if R is subset of S) then total # members of committee S and committee R would be minimized and equal to 12. Which means that 22-12=10 is the greatest possible number of members in the club who are on none of the committees.
Answer: D.
Answer: D
Question: A train 140 m long, running with a speed of 63 km/hr will pass a tree in?
Options:
A)18 sec
B)6 sec
C)8 sec
D)15 sec
E)7 sec
Rationale: Speed = 63 * 5/18 = 35/2 m/sec
Time taken = 140 * 2/35 = 8 sec
Answer:C
Answer: C
Question: Jenny has recently moved house and is working out her optimal commute. She can take an indirect route which involves taking a bus for 1 mile and then walk 0.75 miles. Or she can take a direct route and walk for 1.5 miles and this takes her 30 minutes. What is the most amount time that the bus journey can take for Jenny to be indifferent between the two routes assuming travel time is her only concern?
Options:
A)5 minutes
B)10 minutes
C)15 minutes
D)20 minutes
E)25 minutes
Rationale: If Jenny can walk 1.5 miles in 30 minutes, then she can talk 0.75 miles in half the time i.e. 15 minutes.
For Jenny to be indifferent between the two routes, the two journeys must have the same travel time.
The direct route has a travel time of 30 minutes (walking).
The indirect route has a travel time of 15 minutes (walking) plus the bus journey.
For the two routes to be the same the bus journey must take 15 minutes (30-15).
ANSWER: C
Answer: C
Question: What are the last two digits of (301*402*503*604*646*547*448*348)^2
Options:
A) 86
B) 76
C) 56
D) 36
E) 16
Rationale: ((301*402*503*604*646)*(547*448*348))^2
If you observe above digits, last digit are: 1,2,3,4,6,7,8,8; 5 is missing; so I have rearranged them so that multiplication will be easy for me as initial 4 digits have last two digits as 01,02,03,04,46 and final three as 47*48*48.
Solving for only last two digits and multiplying them we get:( (06*04*46)(56*48))^2 = (44*88)^2=72^2=84
Hence answer is A
Answer: A
Question: Find the odd man out
2880, 480, 96, 24, 10, 4, 4
Options:
A)480
B)96
C)24
D)10
E)4
Rationale: from the right side
4*1=4,
4*2=8 but here given 10 so it's not.
8*3=24
24*4=96
96*5=480
480*6=2880
ANSWER:D
Answer: D
Question: 16 boys or 24 girls can construct the wall in 6 days. the number of days that 8 boys and 12 girls Will take to construct?
Options:
A)7 days
B)14 days
C)6 days
D)8 days
E)9 days
Rationale: Explanation:
16 boys =24 girls, 1 boy = 24/16 girls
1 boy = 6/4 girls
8 boys + 12 girls = 8 × 6/4 + 12 = 12 + 12 = 24 girls
6 days to complete the work
Answer: Option C
Answer: C
Question: If two integers x, y (x>y) are selected from -10 to 4 (inclusive), how many possible cases are there?
Options:
A)150
B)180
C)190
D)210
E)105
Rationale: If two integers x, y (x>y) are selected from -10 to 9 (inclusive), how many possible cases are there?
A. 150
B. 180
C. 190
D. 210
E. 240
--> 15C2=15*14/2=105. Therefore, the answer is E.
Answer: E
Question: 7 girls buy hand bag cost 70 dollars. On account of Christmas there is 20% discount. They Buy hand mirrors with their savings on bag. what is actual cost of each mirror.
Options:
A)15.5
B)14
C)17.5
D)15
E)19.5
Rationale: Solution: E.70*7 = 490 without off. 490 with 20% of is 392. and total 98 savings and 14 dollars each girl. mirror cost 14 but still Christmas discount applies. so actual cost of mirror is 17.5 dollars
Answer: C
Question: In how many ways can the letters of the word MOUSES be arranged?
Options:
A)390
B)360
C)320
D)330
E)300
Rationale: MOUSES has 6 words, but S is repeated two times. Thus ways = 6! / 2! = 360 ways
B
Answer: B
Question: A and B can do a job is 16 days and 12 days respectively. 4 days before finishing the job, A joins B. B has started the work alone. Find how many days B has worked alone?
Options:
A)6 days
B)4 days
C)5 days
D)7 days
E)None of these
Rationale: A’s one day’s work = 1⁄16 th work
B’s one day’s work 1⁄12 th work
Let B has worked alone = x days. Then,
A’s amount of work + B’s amount of work = 1
⇒ 4(1⁄16) + (x + 4)(1⁄12) = 1
⇒ 1/4+x+4/12 = 1 ⇒ x = 3⁄4 × 12 - 4
⇒ x = 5 days.
Answer C
Answer: C
Question: On July 1 of last year, total employees at company E was decreased by 10 percent. Without any change in the salaries of the remaining employees, the average (arithmetic mean) employee salary was 10 percent more after the decrease in the number of employees than before the decrease. The total of the combined salaries of all the employees at Company E after July 1 last year was what percent Q of thatbeforeJuly 1 last year?
Options:
A)90%
B)99%
C)100%
D)101%
E)110%
Rationale: the total number of employees = n
the average salary = x
total salary to all emplyoees = xn
after
the total number of employees = n - 0.1n = 0.9n
the average salary = x + 10% of x = 1.1x
total salary to all emplyoees = 0.9n (1.1x)
total salary after as a % of total salary before Q= [0.9n (1.1x)]/xn= 0.99 or 99%=B
Answer: B
Question: What is the % change in the area of a rectangle when its length increases by 25% and its width decreases by 25%?
Options:
A)0%
B)20% increase
C)20% decrease
D)6% decrease
E)Insufficient data
Rationale: (125/10)*(75/10) = 9375/100 ~94 of original area
0.94 is a 6% decrease from 100/100 ->D
Answer: D
Question: A certain car averages 20 miles per gallon of gasoline when driven in the city and 40 miles per gallon when driving on the highway. According to these rates, which of the following is closest to the number of miles per gallon that the car averages when it is driven 10 miles in the city and then 50 miles on the highway?
Options:
A)28
B)30
C)34
D)36
E)38
Rationale: 10*1/20 gpm+50*1/40 gpm=1.75 total gallons
60 total miles/1.75 total gallons=34.3 average mpg
C. 34
Answer: C
Question: 3 candidates in an election and received 1136, 7636 and 11628 votes respectively. What % of the total votes did the winningcandidate got in that election?
Options:
A)45%
B)50%
C)57%
D)59%
E)62
Rationale: Total number of votes polled = (1136 + 7636 + 11628) = 20400
So, Required percentage = 11628/20400 * 100 = 57%
C
Answer: C
Question: The total number of pupils in Class A is 40 out of which 18 are girls, In Class B there are 20 are boys out of total 35 and in Class C there are 16 girls out of total 32. What is the percent of total girls in all the classes.
Options:
A)33.9%
B)43.6%
C)32.7%
D)62.7%
E)22.8%
Rationale: Class A girls = 18
Class B girls = 35-20 = 15
Class C girls = 16
Total percentage = (18+15+16)/(40+35+32) = 35/107 = 0.327
C
Answer: C
Question: A number Y is chosen at random from the numbers 1, -3, -1, 0, 1, 2, 3. What is the probability that |X|<3?
Options:
A)1/5
B)2/7
C)2/9
D)3/7
E)3/11
Rationale: |X||X| can take 7 values.
To get |X|<2|X|<2 ( i.e., −2<x<+2−2<x
⇒ P(|X|<2)= Favourable CasesTotal CasesP(|X|<2)= Favourable CasesTotal Cases
= 3/7
D
Answer: D
Question: Consider below info to be a table:
AMOUNT OF BACTERIA
TIME - AMOUNT
1PM - 10gms
4PM - x gms
7PM - 22.5 gms
Data for a certain biology experiment are given in the table above. If the amount of bacteria present increased by the same factor during each of the two 3-hour periods shown, how many grams of bacteria were present at 4PM ?
Options:
A)15.0
B)12.1
C)12.2
D)12.3
E)12.4
Rationale: let say the factor is x, the at 7PM quantity = 10 (i.e. quantity @1PM)* x^2 =22.5 => x^2 =2.25 or x = 1.5 => @4PM quantity = 10x =10*1.5 =15.
Answer A
Answer: A
Question: A man spends 10% of his income in house rent, 20% of the rest on his children’s education, 25% of the rest miscellaneous causes. If he now posses Rs. 1944 then his income is?
Options:
A)3600
B)3607
C)3606
D)3655
E)3622
Rationale: X * (90/100) * (80/100) * (75/100) = 1944
X * 0.9 * 0.8 * 0.75
X = 1944/0.54
X = 3600
Answer: A
Answer: A
Question: Income and expenditure of a person are in the ratio 5 : 4. If the income of the person is Rs. 16000, then find his savings?
Options:
A)3600
B)3607
C)3200
D)3602
E)3603
Rationale: Let the income and the expenditure of the person be Rs. 5x and Rs. 4x respectively.
Income, 5x = 16000 => x = 3200
Savings = Income - expenditure = 5x - 4x = x
So, savings = Rs. 3200.
Answer:C
Answer: C
Question: If p is a natural number and p! ends with g trailing zeros, then the number of zeros that (5p)! ends with will be
Options:
A)a) (p+g) trailing zeros
B)b) (5p+y) trailing zeros
C)c) (5p+5y) trailing zeros
D)d) (p+5y) trailing zeros
E)e) none of them above
Rationale: Let p = 1. p! = 1! = 1, which means g= 0
(5p)! = 5! = 120, trailing zeros = 1
1 = 1 + 0 = p + g
Answer (A).
Answer: A
Question: If Rs. 782 be divided into three parts, proportional to 1/2:2/3:3/4, then the first part is:
Options:
A)Rs. 182
B)Rs. 190
C)Rs. 196
D)Rs. 204
E)Rs. 210
Rationale: Explanation:
Given ratio =1/2:2/3:3/4=6:8:9
1st part = Rs. 782*6/23=Rs. 204
Answer is D
Answer: D
Question: A team bought a total of 466 balls. If each player on the team bought at least 13 balls, then what is the greatest possible number of players on the team?
Options:
A)21
B)22
C)23
D)24
E)35
Rationale: 466/13=35 plus remainder.
The answer is E.
Answer: E
Question: A and B together can do a piece of work in 8 days. If A alone can do the same work in 12 days, then B alone can do the same work in?
Options:
A)33
B)66
C)24
D)88
E)99
Rationale: B = 1/8 – 1/2 = 1/24 => 24 days
Answer:C
Answer: C
Question: M = {-6, -5, -4, -3, -2}
T = {-2, -1, 0, 1, 2, 3, 4}
If an integer is to be randomly selected from set M above and an integer is to be randomly selected from set T above, what is the probability that the product of the two integers will be negative?
Options:
A)0
B)11/35
C)4/7
D)1/2
E)3/5
Rationale: Answer C.
Total # of outcomes: 5*7= 35
# of outcomes where Product is -ve : (-6,1) ,(-6,2), (-6,3)... Hence, total: 20
Probability: 4/7
Answer: C
Question: Six bells commence tolling together and toll at intervals of 2, 4, 6, 8 10 and 12 seconds respectively.
In 30 minutes, how many times do they toll together?
Options:
A)12
B)14
C)15
D)16
E)17
Rationale: Explanation :
Here's the simple solution :
Take lcm of 2,4,6,8,10,12 seconds
The outcome is 120seconds.
Convert it into minutes = 120 / 60
= 2 minutes
In 30mins it will rings 15times together
But ,In 0th second all bells rings together
Hence Total number of bell rings is = 15 + 1
= 16
Hence (D) is the correct answer.
Answer : D
Answer: D
Question: A man whose speed is 4.5 kmph in still water rows to a certain upstream point and back to the starting point in a river which flows at 1.5 kmph, find his average speed for the total journey?
Options:
A)6
B)4
C)9
D)3
E)2
Rationale: M = 45
S = 1.5
DS = 6
US = 3
AS = (2 * 6 * 3) /9
= 4
Answer:B
Answer: B
Question: A random 10-letter code is to be formed using the letters A, B, C, D, E, F, G, H, I and I (only the “I” will be used twice). What is the probability that a code that has the two I’s adjacent to one another will be formed?
Options:
A)1/10
B)1/8
C)1/5
D)1/4
E)1/2
Rationale: Total number of combinations possible = 10!/2!10!/2!
Total favorable combinations = 9!9! - We have considered the two Is as one element. Since we have two Is, they can interchange their positions, without affecting the code.
Probability = 9!/(10!/2!)=9!∗2!/10!=1/59!/(10!/2!)=9!∗2!/10!=1/5
ANS:C
Answer: C
Question: Find the number of square tiles to cover the floor of a room measuring 6 m * 14 m leaving 0.50 m space around the room. A side of square tile is given to be 50 cms?
Options:
A)271
B)260
C)277
D)200
E)212
Rationale: 5 * 13 = 1/2 *1/2* x => x = 260
Answer: B
Answer: B
Question: The average age of P, Q, R, S five years ago was 45 years. By including T, the present average age of all the five is 49 years. The present age of T is?
Options:
A)64 years
B)48 years
C)45 years
D)40 years
E)None of these
Rationale: Present age of P, Q, R, S = 45 x 4 + 20 = 200
Present age of P, Q, R, S and T = 49 x 5 = 245
Hence, the age of T = 245 - 200 = 45 years.
ANSWER:C
Answer: C
Question: The perimeter of a triangle is 40 cm and the inradius of the triangle is 2.5 cm. What is the area of the triangle?
Options:
A)87 cm2
B)28 cm2
C)98 cm2
D)26 cm2
E)50 cm2
Rationale: Area of a triangle = r * s
Where r is the inradius and s is the semi perimeter of the triangle.
Area of triangle
= 2.5 * 40/2
= 50 cm2
Answer:E
Answer: E
Question: 8k8
+ k88
--------
1,6t6
If k and t represent non-zero digits within the integers above, what is t?
Options:
A)6
B)7
C)8
D)9
E)17
Rationale: 8k8
k88
--------
16t6
Trial and error or just plug-in method might be the shortest way to solve this problem. Though you can narrow down the possible values of k to just two: 7 and 8 --> 8**+7**=16** or 8**+8**=16** (k can not be less than 7 or 9, as the result won't be 16**). After that it's easy to get that k=7 and t=6.
Answer: A.
Answer: A
Question: Sam, Suresh and Sanket run a race of 1400 meters. Sam runs twice as fast as Suresh while Suresh runs thrice as fast as Sanket. If Sanket finishes the race by clocking 15 minutes, how far was Suresh from the finish line when Sam must have finished the race?
Options:
A)2887
B)278
C)987
D)700
E)278
Rationale: Explanation:
When Sanket finishes the race in 15 minutes, Suresh & Sam would finish the same race in 5 minutes and 2.5 minutes respectively. Thus, when Sam reaches the ”finish” mark, Suresh must be “half-way” through i.e. 700 meters behind the “finish” line when “Sam” must have finished the race.
ANSWER:D
Answer: D
Question: A man whose speed is 4.5 kmph in still water rows to a certain upstream point and back to the starting point in a river which flows at 1.5 kmph, find his average speed for the total journey?
Options:
A)2 kmph
B)4 kmph
C)5 kmph
D)7 kmph
E)6 kmph
Rationale: M = 45
S = 1.5
DS = 6
US = 3
AS = (2 * 6 * 3) /9 = 4
Answer:B
Answer: B
Question: In what time a sum of money double itself at 3% per annum simple interest?
Options:
A)33 1/8%
B)33 1/3%
C)33 3/3%
D)33 1/7%
E)32 1/3%
Rationale: P = (P*3*R)/100
R = 33 1/3%
Answer: B
Answer: B
Question: The number of arrangements that can be made with the letters of the word MEADOWS so that the vowels occupy the even places?
Options:
A)788
B)144
C)298
D)177
E)191
Rationale: Explanation:
The word MEADOWS has 7 letters of which 3 are vowels.
-V-V-V-
As the vowels have to occupy even places, they can be arranged in the 3 even places in 3! i.e., 6 ways. While the consonants can be arranged among themselves in the remaining 4 places in 4! i.e., 24 ways.
Hence the total ways are 24 * 6 = 144.
Answer: B
Answer: B
Question: A certain number of workers can do a work in 35 days. If there were 10 workers more it could be finished in 10 days less. How many workers are there?
Options:
A)25
B)30
C)28
D)24
E)32
Rationale: number of workers = 10* (35-10)/10 = 25
Answer is A
Answer: A
Question: Rahul went to a shop and bought things worth Rs. 50, out of which 80 Paise went on sales tax on taxable purchases. If the tax rate was 8%, then what was the cost of the tax free items?
Options:
A)21.4
B)12.4
C)41.2
D)39.2
E)32.9
Rationale: Total cost of the items he purchased = Rs.50
Given that out of this Rs.50, 80 Paise is given as tax
=> Total tax incurred = 80 Paise = Rs.80/100
Let the cost of the tax free items = x
Given that tax rate = 8%
∴ (50−80/100−x)8/100 = 80/100
⇒ 8(50 −0.8 −x) = 80
⇒ (50 − 0.8 − x) = 10
⇒ x = 50 − 0.8−10 = 39.2
D)
Answer: D
Question: In how many ways can 4 boys and 3 girls be seated on 8 chairs so that no two girls are together?
Options:
A)5760
B)14400
C)480
D)56
E)40320
Rationale: Let us take opposite of the constraint.
2 girls sitting together:	:
1 case is GGBGBBBB.
Total number of ways=3!*5!*5 with just shifting the rightmost girl.
Then the 2 leftmost girls can shift one position , and using the above reasoning, the total number of ways = 3!*5!*4 and so on till the rightmost girl has 1 position.
So total number of ways = 3!*5!(5+4+3+2+1)=120*90=10800
Similarly another case is:
GBGGBBBB.
Using the above reasoning, the total number of cases is: 3!*5!*(15) =10800
Let us take 3 girls sitting together
GGGBBBBB
There are 3! *5! Ways. The 3 leftmost girls can shift 6 positions. So there are a total of 3!*5!*6=4320 ways
So total is 2*10800 + 4320=25920
The total number of possibilities = 8! Ways =40,320
Answer is 40320-25920=5760
Hence A.
Answer: A
Question: Two pipes can fill a tank in 20 and 24 minutes respectively and a waste pipe can empty 5 gallons per minute. All the three pipes working together can fill the tank in 15 minutes. The capacity of the tank is?
Options:
A)60 gallons
B)200 gallons
C)120 gallons
D)180 gallons
E)130 gallons
Rationale: Work done by the waste pipe in 1 minute = 1/15 - (1/20 + 1/24) = - 1/40
Volume of 1/40 part = 5 gallons\
Volume of whole = 5 * 40 = 200 gallons.
ANSWER:B
Answer: B
Question: One fourth of one third of two fifth of a number is 15. What will be40% of that number
Options:
A)140
B)150
C)180
D)200
E)220
Rationale: Explanation:
(1/4) * (1/3) * (2/5) * x = 15
then x = 15 * 30 = 450
40% of 450 = 180
Answer: Option C
Answer: C
Question: There are three places P, Q and R such that 3 roads connects P and Q and 4 roads connects Q and R. In how many ways can one travel from P to R?
Options:
A)8
B)10
C)12
D)14
E)15
Rationale: Number of ways in which one can travel from P to R
=3×4=12
Answer: Option C
Answer: C
Question: 1000 men have provisions for 17 days. If 500 more men join them, for how many days will the provisions last now?
Options:
A)12.9
B)12.5
C)11.3
D)12.2
E)12.1
Rationale: 1000*17 = 1500*x
x = 11.3
Answer: C
Answer: C
Question: The ratio between the sale price and the cost price of an article is 7:5. What is the ratio between the profit and the cost price of that article?
Options:
A)2:8
B)2:0
C)2:2
D)2:1
E)2:5
Rationale: Let C.P. = Rs. 5x and S.P. = Rs. 7x.
Then, Gain = Rs. 2x
Required ratio = 2x : 5x = 2:5
Answer:E
Answer: E
Question: A train moves fast a telegraph post and a bridge 250 m long in 8 sec and 20 sec respectively. What is the speed of the train?
Options:
A)70
B)39
C)79
D)75
E)71
Rationale: Let the length of the train be x m and its speed be y m/sec.
Then, x/y = 8 => x = 8y
(x + 250)/20 = y
y = 20.83
Speed = 20.83 m/sec = 20.83 * 18/5 = 75 km/hr.
Answer:D
Answer: D
Question: A clock shows the time as 3:30 P.m. If the minute hand gains 2 minutes every hour, how many minutes will the clock gain by 6 a.m.?
Options:
A)23 Minutes
B)24 Minutes
C)29 Minutes
D)26 Minutes
E)None of these
Rationale: if the minute hand gains 2 minutes in 1 hour the from 3:30 p.m-4:00 p.m it gains 1 min
then from 4:00p.m-6:00 a.m =14*2=28 total=29
ANSWER:C
Answer: C
Question: The ratio of two quantities is 2 to 5. If each of the quantities is increased by 5, what is the ratio of these two new quantities?
Options:
A)2/5
B)5/8
C)7/13
D)22/25
E)It cannot be determined from the information given.
Rationale: Correct Answer: E
Let x and y be the two quantities such that x/y = 2/5. There is no algebraic operation that can be used to increase x and y each by 3 and determine what happens to the ratio 2/5.
For example, if x = 2 and y = 5, then (x+5)/(y+5) = (2+5)/(5+5) = 7/10. However, if x = 4 and y = 10 (which would still set x/y = 2/5), then (x+5)/(y+5) = (4+5)/(10+5) = 9/15. The ratio of the two new quantities cannot be uniquely determined from the information given, and the correct answer is (E).
Answer: E
Question: In a covering a distance of 30 km, Abhay takes 2 hours more than Sameer. If Abhay double his speed, then he would take 1 hour less than Sammer. Abhay's speed is?
Options:
A)5 km/hr
B)1 km/hr
C)6 km/hr
D)3 km/hr
E)7 km/hr
Rationale: A
5 km/hr
Let Abhay's speed be x km//hr.
Then, 30/x - 30/2x = 3
x = 5 km/hr.
Answer: A