divelab/Sys2Bench huggingface dataset:
Question: One card is randomly drawn from a pack of 52 cards. What is the probability that the card drawn is a face card(Jack, Queen or King)
Options:
A)1/15
B)2/74
C)4/18
D)3/13
E)9/15
Rationale: Explanation :
Total number of cards, n(S) = 52
Total number of face cards, n(E) = 12
P(E)=n(E)/n(S)=12/52=3/13
D
Answer: D
Question: A boat having a length 3 m and breadth 2 m is floating on a lake. The boat sinks by 1 cm when a man gets on it. The mass of the man is:
Options:
A)12 kg
B)60 kg
C)72 kg
D)88 kg
E)96 kg
Rationale: Volume of water displaced	= (3 x 2 x 0.01) m3
= 0.06 m3.
Mass of man	= Volume of water displaced x Density of water
= (0.06 x 1000) kg
= 60 kg.
Answer: Option B
Answer: B
Question: 3 Years ago, the average age of a family of 5 members was 19 years. A baby having been born, the average age of the family is the same today. The present age of the baby is
Options:
A)1 year.
B)1.5 Years.
C)2 Years.
D)3 Years.
E)4 Years.
Rationale: We're told that 3 YEARS AGO, the average age of a family of 5 members was 19 years.
This means that the SUM of their ages was (5)(19) = 95 years.
A baby was born (meaning that there are now 6 family members). We're told that the PRESENT average age of the family members is the SAME.
This means that the sum of the ages is (6)(19) = 114 years.
We're asked for the PRESENT age of the baby.
Since each of the original 5 family members has aged 3 years since the initial average was calculated, the sum of their PRESENT ages is...
95 + (5)(3) = 110.
114-110 =4
E
Answer: E
Question: By travelling at 30 kmph, a person reaches his destination on time. He covered two-third the total distance in one-third of the total time. What speed should he maintain for the remaining distance to reach his destination on time?
Options:
A)19 kmph
B)15 kmph
C)12 kmph
D)20 kmph
E)23 kmph
Rationale: Let the time taken to reach the destination be 3x hours. Total distance = 30 * 3x = 90x km
He covered 2/3 * 90x = 60x km in 1/3 * 3x = x hours So, the remaining 30x km, he has to cover in 2x hours. Required speed = 30x/2x
=15 kmph.
Answer: B
Answer: B
Question: A grocery store has a surplus of cakes, so they price them at 10% off the wholesale price of $8.50. An employee uses their employee discount to get a further 10% discount off a cake. How much does that employee pay? Round your answer to the nearest hundredth decimal place.
Options:
A)$7.00
B)$6.80
C)$6.89
D)$7.65
E)$6.88
Rationale: Wholesale price of cake = $8.50
Cake was priced at 10% below $8.50 = $7.65
% discount given by employee discount = 10%
Employee paid = .9 * 7.65 = $6.885
Rounded to nearest hundredth = $6.89
Answer C
Answer: C
Question: The current birth rate per certain number of people is 52, whereas corresponding death rate is 16 per same number of people. If the net growth rate in terms of population increase is 1.2 percent, find number of persons.(initally)
Options:
A)4000
B)2000
C)3000
D)5000
E)1000
Rationale: Sol.
Net growth on X = (52- 16) =36.
Net growth on 100 = (36/X Ã— 100)% =1.2%. Then X = 3000
Answer:C
Answer: C
Question: The difference between two numbers is 1365. When the larger number is divided by the smaller one, the quotient is 6 and the remainder is 15. The smaller number is
Options:
A)240
B)250
C)260
D)270
E)None
Rationale: Solution
Let the numbers be x and x(x+1365).
Then, x+1365
= 6x + 15
‹=›5x = 1350.
‹=›x = 270.
Answer D
Answer: D
Question: Which of the following CANNOT be a value of 4/(x–4)?
Options:
A)-1
B)-1/2
C)0
D)2
E)6
Rationale: The question doesn't ask for the value of x here, but for the possible results of the equation.
If 4/(x-4) = 0, then the numerator must be 0. But since the numerator is 4, the fraction can not be equal to 0.
The answer is C.
Answer: C
Question: Sakshi can do a piece of work in 20 days. Tanya is 25% more efficient than Sakshi. The number of days taken by Tanya to do the same piece of work is
Options:
A)4 days
B)6 days
C)10 days
D)16 days
E)22 days
Rationale: Ratio of times taken by Sakshi and Tanya = 125 : 100 = 5 : 4.
Suppose Tanya takes x days to do the work.
5 : 4 :: 20 : x x = 4 x 20/5
x = 16 days.
Hence, Tanya takes 16 days to complete the work. answer :D
Answer: D
Question: One night a certain hotel rented 2/3 of its rooms, including 2/3 of their air conditioned rooms. If 3/5 of its rooms were air conditioned, what percent of the rooms that were not rented were air conditioned?
Options:
A)50%
B)60%
C)65%
D)70%
E)75%
Rationale: The rooms which were not rented is 1/3
The AC rooms which were not rented is (1/3)*(3/5) = 1/5
The percentage of unrented rooms which were AC rooms is (1/5) / (1/3) = 3/5 = 60%
The answer is B.
Answer: B
Question: Speed of a man with current measures 15 km/hr. Speed of current is 2.5 km/hr. What is the speed of man against the current?
Options:
A)12.5 kmph
B)10 kmph
C)9 kmph
D)8.5 kmph
E)None of these
Rationale: Explanation:
Let the speed of man in still water be x km/hr
Now, speed with current=15 km/hr
Speed of current: 2.5 km/hr
Speed of man with current: Speed of man in still water+Speed of current
=>15=x+2.5
=>x=12.5
Speed of man against the current: Speed of man in still water-Speed of current
=>12.5-2.5
=>10 km/hr
ANSWER B
Answer: B
Question: 2+3=8,
3+7=27,
4+5=32,
5+8=60,
6+7=72,
7+8=??
Solve it?
Options:
A)59
B)65
C)87
D)72
E)98
Rationale: 2+3=2*[3+(2-1)]=8
3+7=3*[7+(3-1)]=27
4+5=4*[5+(4-1)]=32
5+8=5*[8+(5-1)]=60
6+7=6*[7+(6-1)]=72
therefore
7+8=7*[8+(7-1)]=98
x+y=x[y+(x-1)]=x^2+xy-x
Answer: E
Question: The length of a rectangular hall is 5 m more than its breadth. The area of the hall is 7502. The length of the hall is :
Options:
A)15m
B)22.5m
C)25m
D)30m
E)None of these
Rationale: Solution
Let breadth = x metres. Then, length = (x + 5) metres.
Then, x(x + 5) = 750 ⇔ x2 + 5x - 750 = 0 ⇔ (x + 30) (x - 25) = 0 ⇔ x = 25.
∴ Length = (x + 5) = 30 m Answer D
Answer: D
Question: The speed of a boat in upstream is 60 kmph and the speed of the boat downstream is 80 kmph. Find the speed of the boat in still water and the speed of the stream?
Options:
A)10
B)99
C)77
D)62
E)12
Rationale: Speed of the boat in still water = (60+80)/2 = 70 kmph. Speed of the stream
= (80-60)/2 = 10 kmph.
Answer: A
Answer: A
Question: A man swims downstream 30 km and upstream 18 km taking 3 hours each time, what is the speed of the man in still water?
Options:
A)6
B)8
C)9
D)7
E)5
Rationale: 30 --- 3 DS = 10
? ---- 1
18 ---- 3 US = 6
? ---- 1 M = ?
M = (10 + 6)/2 = 8
Answer: B
Answer: B
Question: A is twice as good a workman as B and they took 5 days together to do the work B alone can do it in?
Options:
A)15 days
B)88 days
C)21 days
D)11 days
E)13 days
Rationale: WC = 2:1
2x + x = 1/5
x = 1/15 => 15 days
Answer: A
Answer: A
Question: A, B and C jointly thought of engaging themselves in a business venture. It was agreed that A would invest Rs. 6500 for 6 months, B, Rs. 8400 for 5 months and C, Rs. 10,000 for 3 months. A wants to be the working member for which, he was to receive 5% of the profits. The profit earned was Rs. 7400. What is the share of B in the profit.
Options:
A)2610
B)2650
C)2630
D)2670
E)2660
Rationale: A is a working member and for that, he receives 5% of the profit
= 5% of 7400 =5×7400/100=370
Remaining amount =7400−370=7030
Ratio of their investments
=6500×6:8400×5:10000×3
=65×6:84×5:100×3
=13×6:84:20×3
=13×2:28:20
=13:14:10
Share of B in the profit
=7030×14/37
=190×14=2660
Answer is E.
Answer: E
Question: A can complete the job in 6 hours and B can complete the same job in 3 hours. A works for 1 hour and then B joins and both complete the job. What fraction of the job did B complete
Options:
A)1/9
B)3/10
C)1/2
D)5/6
E)8/9
Rationale: A=1/9
Answer: A
Question: A pump can fill a tank with water in 3 hours. Because of a leak, it took 7 hours to fill the tank. The leak can drain all the water in ?
Options:
A)15hr 10min
B)16hr 20min
C)5hr 15min
D)15hr
E)14hr 25min
Rationale: Work done by the leak in 1 hour = 1/3 - 1/7 = 4/21
Leak will empty the tank in 21/4 hrs = 5hr 15min
Answer is C
Answer: C
Question: The compound interest on Rs. 30,000 at 7% per annum is Rs. 4347. The period(in years) is?
Options:
A)2
B)2 1/2
C)3
D)4
E)5
Rationale: Explanation:
Amount = (30000 + 4347) = Rs. 34347
Let the time be n years. Then,
30000(1 + 7/100)n = 34347
= (107/100)n = 34347/30000 = (107/100)2
n = 2 years.
ANSWER IS A
Answer: A
Question: The first term in a sequence is 1 and the second term is 9. From the third term on each term is the average (arithmetic mean) of all preceding terms. What is the 28th term in the sequence?
Options:
A)4
B)5
C)9
D)28
E)50
Rationale: The third term is 5 since this is the average of 1 and 9.
Then the next terms will all be 5 since the average stays at 5.
The answer is B.
Answer: B
Question: At Ram's party, there were five times as many females as males. There were three times as many adults as children. Which of the following could NOT be the number of people at the party?
Options:
A)384
B)258
C)216
D)120
E)72
Rationale: we have to work on the info and understand what that info takes us to...
1) there were five times as many females as males At Ram's party..
this means F=5M.. so total number=6M..
2) There were three times as many adults as children..
A=3C...
or total = 4C..
so the total is 4C or 6M..
since C and M have to be positive integers, we can say for sure that Total is a multiple of 4 and 6..
or Total is multiple of LCM of 4,6..
LCM of 4,6= 12..
lets see which number is not multiple of 12..
A. 384...12*32
B. 258... no
C. 216....12*18
D. 120....12*10
E. 72......12*6..
so B is our answer..
Answer: B
Question: If p is the sum of x consecutive positive integers. q is the sum of y consecutive positive integers. For which of the following values of x and y is it impossible that p = q?
Options:
A)x = 2 and y = 6
B)x = 3 and y = 6
C)x = 7 and y = 9
D)x = 10 and y = 7
E)x = 10 and y = 4
Rationale: I approached this in a different way, although may be longer but it's certainly more intuitive
It is impossible that p = q if one of them is necessarily even while the other is necessarily odd
for two consecutive integers the sum is necessarily odd
for six consecutive integers the sum is necessarily odd (sum of 3two consecutive integers which are all odd)
Thus A is incorrect.
The sum of 3 consecutive integers can be even or odd (an odd integer from the first 2 + an additional integer which can be even or odd). Thus B is incorrect. You can do a similar approach for C and D (it follows that the sum of a specified odd number of consecutive integers can be odd or even).
Leaving us with E to be the only not-wrong answer. To confirm, you can easily deduce that the sum of 4 consecutive integers (sum of 2 odd integers) is necessarily even while the sum of 10 consecutive integers (sum of 5 odd integers) is necessarily odd. Thus E is the right answer.
Answer: E
Question: In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is
Options:
A)3 hr.
B)5 hr.
C)2 hr.
D)7 hr.
E)1 hr.
Rationale: E
1 hr.
Let the duration of the flight be x hours.
Then, 600/x - 600/0.5x = 200
--> 600/x - 1200/(2x+1) = 200
--> x(2x + 1) = 3
--> 2x^2 + x - 3 = 0
--> (2x + 3)(x - 1) = 0
--> x = 1 hr.
Answer: E
Question: Two numbers are such that the ratio between them is 4 : 7. If each is increased by 4, the ratio becomes 3 : 5. The larger number is
Options:
A)36
B)46
C)56
D)64
E)None
Rationale: Sol.
Let the numbers be 4x and 7x.
Then, 4x+4 / 7x+4 = 3/5
⇔ 5(4x+4) = 3(7x+4)
⇔ x = 8.
∴ Larger number = 7x = 56.
Answer C
Answer: C
Question: If the charge of staying in a student youth hostel $18.00/day for the first week, and $11.00/day for each additional week, How much does it cost to stay for 23 days?
Options:
A)$160
B)$176
C)$282
D)$302
E)$286
Rationale: Total number of days of stay = 23
Charge of staying in first week = 18*7 = 126 $
Charge of staying for additional days =(23-7)*11 = 16*11 = 176 $
Total charge =126 +176 = 302$
Answer D
Answer: D
Question: Which fraction will come next, 1/2,3/4,5/8,7/16,?
Options:
A)9/30
B)11/32
C)9/28
D)9/32
E)9/28
Rationale: Numerators are getting increased by 2. i.e., numerators goes like 1,3,5,7,...
Hence, next numerator = 7+2 = 9
Denominators are getting multiplied by 2. i.e., denominators goes like 2,4,8,16,...
Hence, next denominator = 16×2 = 32
So, the next fraction is 9/32
Answer: D
Question: Cindy is thinking of a number which is 4 less than the square of a positive integer. The number
has the property that it has two 2-digit prime factors. What is the smallest possible value of
Cindy's number?
Options:
A)221
B)231
C)241
D)251
E)261
Rationale: Let x be Cindy's number. Then x = n2-4 = (n-2)(n+2) for some positive integer
n. Since n + 2 and n - 2 differ by 4, our goal is hence to find two 2-digit prime numbers which
dier by 4. By writing the first few prime numbers, we find that the pair (13,17) is the smallest
pair possible, which gives us a value of 13 * 17 = 221 .
correct answer A
Answer: A
Question: If x, y, and z are consecutive odd integers, with x < y < z, then which of the following must be true?
I. x + y + z is even
II. (x+y)/z is an integer
III. xz is even
Options:
A)I only
B)II only
C)III only
D)I and II only
E)None of the above
Rationale: consecutive odds are:
2x+1, 2x+3, 2x+5
I. 2x+1+2x+3 +2x+5 =6x+9=3(2x+3), 2x+3 is not divisible by 2 - NOT TRUE
II. 2x+1+2x+3=4x+4/2x+5=2(2x+2)/(2x+5)=Not an integer, so NOT TRUE
III. (2x+1)*(2x+5)=4x^2+10x+2x+5=4x^2+12x+5=(2x(x+6)+5)/2 is not integer, so NOT TRUE
ANSWER:E
Answer: E
Question: Find the area of circle whose radius is 28m?
Options:
A)2464
B)1543
C)7675
D)1683
E)1784
Rationale: 22/7 * 28 * 28
= 2464
Answer: A
Answer: A
Question: The difference between the ages of two persons is 30 years. Fifteen years ago, the elder one was twice as old as the younger one. The present age of the younger person is?
Options:
A)30yr
B)25yr
C)45yr
D)40yr
E)50yr
Rationale: Let their ages be x years and (x+30) years
Then, (x+30) - 15 = 2(x-15)
x +15 = 2x-30
x = 45
Answer is C
Answer: C
Question: The sum of ages of 5 children born 3 years different each is 75 yrs. What is the age of the Elder child?
Options:
A)7
B)9
C)16
D)18
E)21
Rationale: Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 75
5x = 45
x = 9.
x+12= 9+12= 21
E
Answer: E
Question: One day a car rental agency rented 2/3 of its cars, including 3/5 of its cars with CD players. If 3/5 of its cars have CD players, what percent of the cars that were not rented had CD players?
Options:
A)18/25
B)17/20
C)11/15
D)7/10
E)3/5
Rationale: The cars with CD players which were not rented is (2/5)(3/5) = 6/25 of all the cars.
The cars which were not rented is 1/3 of all the cars.
The percent of non-rented cars which had CD players is (6/25) / (1/3) = 18/25
The answer is A.
Answer: A
Question: When n is divided by 9, the remainder is 2. When n is divided by 13, the remainder is 8. If 1 < n < 200, what is the greatest possible value of n?
Options:
A)47
B)65
C)103
D)164
E)117
Rationale: Looking at the choices, options B E can be eliminated as they are divisible by 13
Starting from the highest number 164;
164 = 162 + 2 (162 divisible by 9)
164 = 156 + 8 (156 divisible by 13)
it fits the result
Answer = D
Answer: D
Question: Two cars cover the same distance at the speed of 50 and 65 kmps respectively. Find the distance traveled by them if the slower car takes 1 hour more than the faster car.
Options:
A)212 km
B)214 km
C)224 km
D)200 km
E)204 km
Rationale: 50(x + 1) = 65x
X = 3.33
60 * 3.33 = 200 km
ANSWER:D
Answer: D
Question: shopkeeper sells 20% of his stock at 10% profit ans sells the remaining at a loss of 5%. He incurred an overall loss of Rs. 400. Find the total worth of the stock?
Options:
A)Rs. 25000
B)Rs. 20000
C)Rs. 15000
D)Rs. 22000
E)None of these
Rationale: Let the total worth of the stock be Rs. x.
The SP of 20% of the stock = 1/5 * x * 1.1 = 11x/50
The SP of 80% of the stock = 4/5 * x * 0.95 = 19x/25 = 38x/50
Total SP = 11x/50 + 38x/50 = 49x/50
Overall loss = x - 49x/50 = x/50
x/50 = 400 => x = 20000
ANSWER:B
Answer: B
Question: Water is poured into a cylindrical well at the rate of 22 cubic meters per hour, the level of water in the tank rises at a rate of 0.7 meters per hour. Which of the following best approximates the diameter of the tank in meters?
Options:
A)√10/2
B)√10
C)2√10
D)5
E)10
Rationale: Here's my re-worked solution:
volume = 22 = pi (r^2)(0.7)
22 = 22/7 (7/10)(r^2)
10 = r^2
r = sqrt(10)
Diameter=2*sqrt(10)
Ans: C
Answer: C
Question: A shopping mall charges 70 cents for the first hour of parking and $5 for each additional hour until the customer reaches 4 hours, after that the parking fee is $2 per hour. If a certain customer parked his in the mall for 7 hours and 30 minutes, how much is he going to pay?
Options:
A)$36.4
B)$12.
C)$13.
D)$14.5.
E)$15.
Rationale: 0.70+5*5+2*5+0.70= $36.4
Answer: $36.4
Answer: A
Question: Tickets numbered from 1 to 20 are mixed and then a ticket is selected randomly. What is the probability that the selected ticket bearsa number which is a multiple of 3?
Options:
A)1/5
B)2/5
C)3/10
D)3/7
E)1/7
Rationale: Here, S = [1, 2, 3, 4, …., 19, 20]
Let E = event of getting a multiple of 3 = [3, 6, 9, 12, 15, 18]
P (E) = n (E) / n (S) = 6 / 20 = 3/10
C
Answer: C
Question: A bakery currently has 6 pies and 5 cakes in its inventory. The bakery’s owner has decided to display 5 of these items in the bakery’s front window. If the items are randomly selected, what is the probability that the display will have exactly 3 pies?
Options:
A)100/231
B)25/77
C)5/11
D)93/116
E)50/147
Rationale: The total number of ways to choose 5 from 11 is 11C5 = 462.
The number of ways that include 3 pies is 6C3*5C2 = 20*10 = 200
P(exactly 3 pies) = 200/462 = 100/231
The answer is A.
Answer: A
Question: A thief is noticed by a policeman from a distance of 300 m. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 10 km and 11 km per hour respectively. What is the distance between them after 6 minutes?
Options:
A)100
B)277
C)2987
D)278
E)200
Rationale: Relative speed of the thief and policeman = 11 - 10 = 1 km/hr.
Distance covered in 6 minutes = 1/60 * 6 = 1/10 km = 100 m.
Distance between the thief and policeman = 300 - 100 = 200 m.
Answer: E
Answer: E
Question: What is the value of 3x^2 − 1.8x + 0.3 for x = 0.9?
Options:
A)−0.3
B)0
C)0.3
D)1.11
E)2.46
Rationale: 3x^2-1.8x+0.3 for x=0.5
=3(0.9*0.9)-2*0.9*(0.9)+0.3
=0.9*0.9+0.3
=0.81+0.3
=1.11
Correct Option : D
Answer: D
Question: 21, 9, 21, 11, 21, 13, 21, ?
Options:
A)11
B)17
C)19
D)15
E)20
Rationale: D
15
In this alternating repetition series, the number 21 is interpolated. If you exclude 21, the series increases by 2, beginning with the number 9.
Answer: D
Question: At Tom's party, there were five times as many females as males. There were three times as many adults as children. Which of the following could NOT be the number of people at the party?
Options:
A)384
B)258
C)216
D)120
E)72
Rationale: we have to work on the info and understand what that info takes us to...
1) there were five times as many females as males At Tom's party..
this means F=5M.. so total number=6M..
2) There were three times as many adults as children..
A=3C...
or total = 4C..
so the total is 4C or 6M..
since C and M have to be positive integers, we can say for sure that Total is a multiple of 4 and 6..
or Total is multiple of LCM of 4,6..
LCM of 4,6= 12..
lets see which number is not multiple of 12..
A. 384...12*32
B. 258... no
C. 216....12*18
D. 120....12*10
E. 72......12*6..
so B is our answer..
Answer: B
Question: The first, second and third terms of the proportion are 56, 16, 49. Find the fourth term.
Options:
A)10
B)14
C)40
D)50
E)60
Rationale: Explanation :
Let the fourth term be x.
Thus 56, 16, 49, x are in proportion.
Product of extreme terms = 56 x
Product of mean terms = 16 X 49
Since, the numbers make up a proportion
Therefore, 56 x = 16 49
or, x = (16 49)/56
or, x = 14
Therefore, the fourth term of the proportion is 14.
Answer : B
Answer: B
Question: If each year the population of the country grows by 50%, how many years will elapse before the population of the country doubles?
Options:
A)3
B)4
C)2
D)6
E)7
Rationale: Till Year 2000, population is 100 .
Year 2001: Population becomes 150 ............. 1 Year elapsed
Year 2002: Population > 200 ............. 2 Year elapsed
Answer:C
Answer: C
Question: A two-digit number exceeds the sum of the digits of that number by 18. if the digit at the unit’s place is double that digits in the ten’s place, what is the number ?
Options:
A)24
B)42
C)48
D)data inadequate
E)None
Rationale: Solution
Let the ten's digit be x. then, unit's digit = 2 x.
Number = 10 x + 2 x = 12 x, sum of digits = x + 2 x = 3 x.
∴ 12 x - 3 x = 18 ⇔ 9 x = 18 ⇔ x = 2.
Hence, required number = 12 x = 24
Answer A
Answer: A
Question: A 300 m long train crosses a platform in 39 sec while it crosses a signal pole in 10 sec. What is the length of the platform?
Options:
A)187 m
B)350 m
C)267 m
D)287 m
E)870 m
Rationale: Speed = 300/10 = 30 m/sec.
Let the length of the platform be x meters.
Then, (x + 300)/39 =30
=> x = 870m.
Answer:E
Answer: E
Question: The average of 10 result is 42. Average of the first 7 of them is 30 and that of the last 7 is 80. Find the 8th result?
Options:
A)35
B)37
C)70
D)75
E)50
Rationale: Sum of all the 10 results = 10 * 42 = 420
Sum of the first 7 of them = 7 * 30 = 210
Sum of the last 7 of them = 7 * 80 = 560
So, the 8th number = 420+ 210 - 560= 70.
C
Answer: C
Question: Mother,her daughter and her grand child weighs 120 kg. daughter and her daughter(child) weighs 60 kg. child is 1/5th of her grand mother. What is the age of the daughter?
Options:
A)46
B)47
C)48
D)49
E)50
Rationale: mother + daughter + child = 120kg
daughter + child = 60kg
mother = 120 - 60 = 60kg
child = 1/5th of mother = (1/5)*60 = 12kg
So now daughter = 120 -(mother + child) = 120 - (60+12) = 48kg
ANSWER:C
Answer: C
Question: Plane leaves from Chelsea every 35 minutes from West Ham airport. Air hostess told Frank Lampard that the plane had left 25 minutes ago and the next plane for Chelsea will leave at 7:00 p.m.
At what time air hostess convey this information to Frank Lampard?
Options:
A)5:35 p.m
B)6:50 p.m
C)7:35 p.m
D)8:35 p.m
E)9:35 p.m
Rationale: Explanation:
Time of Frank Lampard last missed plane = 7:00 p.m - 35 min = 6:25 p.m
As this information has been given to Frank Lampard 25 minutes after the plane has already left, the air hostess gave the information at 6:25 p.m + 25 min = 6:50 p.m
Answer B
Answer: B
Question: Rohit spent 30 percent of his earning last month on rent and 20 percent less than what he spent on rent to purchase a new dishwasher. What percent of last month's earning did Rohit have left over?
Options:
A)29%
B)35%
C)46%
D)47%
E)52%
Rationale: SayRohit's earning last month was $100.
Rohit spent 30 percent of his earning last month on rent --> $30 on rent;
20 percent less than what he spent on rent to purchase a new dishwasher --> $30*0.8=$24 on the dishwasher.
Left over amount 100 - (30 + 24) = $46
Answer: C
Answer: C
Question: A fruit seller had some oranges. He sells 40% oranges and still has 480 oranges. How many oranges he had originally?
Options:
A)800
B)710
C)720
D)730
E)740
Rationale: 60% of oranges = 480
100% of oranges =(480×100)/6=800
total oranges = 700
ANSWER : A
Answer: A
Question: If 2^5, 3^3, and 10^2 are all factors of the product of 936 and w where w is a positive integer, what is the smallest possible value of w?
Options:
A)26
B)39
C)120
D)65
E)156
Rationale: Here 156 has three two's
two three's
and one 10
rest of them must be in w
so w= 10*3*4 = 120
Smash C
Answer: C
Question: A sum of Rs. 350 made up of 110 coins, which are of either Re.1 or Re.5 denomination. How many coins are of Re.1?
Options:
A)50
B)60
C)65
D)54
E)47
Rationale: Rs.1 coins= 50 ;50*1=50
Rs.5 coins=60 ; 60*5=300
Total=50+300=350
So total Rs.1 coins are 50
ANSWER:A
Answer: A
Question: A car takes 4.5 hours to travel from A to B, which is 360 miles apart. What is the average speed of the car?
Options:
A)40
B)50
C)60
D)80
E)85
Rationale: Average speed= 360/4.5 hours
= 360/270
=1.33 miles per min
=80 miles per hour
Answer: D
Answer: D