divelab/Sys2Bench huggingface dataset:
Question: Rasik walked 20 m towards north. Then he turned right and walks 30 m. Then he turns right and walks 35 m. Then he turns left and walks 15 m. Finally he turns left and walks 15 m. In which direction and how many metres is he from the starting position?
Options:
A)15 m West
B)30 m East
C)35 m East
D)45 m East
E)40 m East
Rationale: 45 m East
ANSWER:D
Answer: D
Question: There are 4 more women than there are men on a local co-ed softball team. If there are a total of 14 players on the team, what is the ratio of men to women?
Options:
A)10/16
B)6/16
C)4/16
D)6/10
E)5/9
Rationale: w = m+4
w+m = 14
m+4+m = 14
2m = 10
m = 5
w = 9
ratio:5:9
Ans: E
Answer: E
Question: The ratio of ducks and frogs in a pond is 37 : 39 respectively. The average number of ducks and frogs in the pond is 152. What is the number of frogs in the pond ?
Options:
A)148
B)152
C)156
D)144
E)None
Rationale: Solution:
Ratio of Ducks and Frogs in Pond,
= 37 : 39.
Average of Ducks and Frogs in Pond,
= 152.
So, total number of Ducks and Frogs in the Pond,
= 2* 152 = 304.
Therefore,
Number of Frogs, = (304 *39)/76 = 156.
Answer: Option C
Answer: C
Question: What comes next?
6 1 3 1 4 __
Options:
A)3
B)4
C)7
D)8
E)5
Rationale: e
5
The numbers are the alphabetical positions of the letters, spelling FACADE :
6-F; 1-A; 3-C; 1-A; 4-D; 5-E.
Answer: E
Question: What is the speed of the stream if a canoe rows upstream at 3km/hr and downstream at 12km/hr
Options:
A)1 kmph
B)4 kmph
C)3 kmph
D)2 kmph
E)4.5 kmph
Rationale: Sol.
Speed of stream = 1/2(12 -3) kmph = 4.5 kmph.
Answer E
Answer: E
Question: What least number must be added to 1078, so that the sum is completely divisible by 23 ?
Options:
A)3
B)2
C)4
D)5
E)6
Rationale: 47*23 = 1081
1081 - 1078 = 3
Answer : A
Answer: A
Question: Three pipes of same capacity can fill a tank in 8 hours. If there are only two pipes of same capacity, the tank can be filled in?
Options:
A)15 hours
B)12 hours
C)76 hours
D)16 hours
E)81 hours
Rationale: The part of the tank filled by three pipes in one hour = 1/8
=> The part of the tank filled by two pipes in 1 hour = 2/3 * 1/8 = 1/12.
The tank can be filled in 12 hours.
Answer: B
Answer: B
Question: If the average (arithmetic mean) of five consecutive negative integers is 8k – 1, what is the difference between the greatest and least of the five integers?
Options:
A)4K
B)4k^2 -4k
C)4-4k
D)4
E)4k+4
Rationale: (n-2 + n - 1 + n + n + 1 + n + 2)/5 = 8k - 1
=> n = 40k - 5
Greatest = n + 2 = 40k - 5 + 2 = 40k - 3
Least = n - 2 = 40k - 5 - 2
=> Difference = 40k - 3 - (40k - 7)
= 4
Answer - D
Answer: D
Question: Cereal A is 11% sugar by weight, whereas healthier but less delicious Cereal B is 2% sugar by weight. To make a delicious and healthy mixture that is 5% sugar, what should be the ratio of Cereal A to Cereal B, by weight?
Options:
A)1:2
B)2:3
C)1:3
D)1:4
E)3:4
Rationale: 2% is 3%-points below 5% and 11% is 6%-points above 5%.
The ratio of A:B should be 3:6 = 1:2.
The answer is A.
Answer: A
Question: In a college, the ratio of the number of boys to girls is 8 : 5. If there are 350 girls, the total number of
students in the college is
Options:
A)420
B)520
C)620
D)910
E)None of these
Rationale: Explanation:
Let the boy are 8x and Girls are 5x
=> 5x = 350
=> x = 70
Total students = 8x+5x = 13x = 13(70) = 910
Answer: D
Answer: D
Question: A train speeds past a pole in 15 seconds and a platform 100 m long in 25 seconds. Its length is:
Options:
A)50 m
B)150 m
C)200 m
D)Data inadequate
E)none of these
Rationale: Let the length of the train=xm
x/15=x+100/25
by solving this we get x=150m
ANSWER:B
Answer: B
Question: The number 91 is equal to the sum of the cubes of two integers. What is the product of those integers?
Options:
A)8
B)12
C)21
D)27
E)39
Rationale: 3^3+4^3= 91 therefore number is 3*4=12
B
Answer: B
Question: What percent of the year 2017 is 219 days?
Options:
A)56%
B)72%
C)64,5%
D)51%
E)60%
Rationale: Explanation :
Total days in the year 2017 = 365
Required percentage = (219/365) Ã— 100 = 60%
Answer : Option D
Answer: D
Question: What is the population standard deviation for the numbers: 75, 83, 96, 100, 121 and 125?
Options:
A)18.2
B)20
C)25
D)26
E)28
Rationale: 1. Firstly find the mean:
Mean = (75 + 83 + 96 + 100 + 121 + 125) ÷ 6 = 600 ÷ 6 = 100
2. Next find the variance. To calculate the Variance, take each difference, square it, and then average the result:
(75 - 100)2 + (83 - 100)2 + (96 - 100)2 + (100 - 100)2 + (121 - 100)2 + (125 - 100)2
= (-25)2 + (-17)2 + (-4)2 + (0)2 + (21)2 + (25)2
= 625 + 289 + 16 + 0 + 441 + 625
= 1,996
So the Variance = 1,996 ÷ 6 = 332.66...
3. The Standard Deviation is just the square root of the Variance
= √(332.66...)
= 18.2 correct to 1 decimal places
Answer is A
Answer: A
Question: Find the odd man out. 1, 3, 9, 12, 19, 29
Options:
A)12
B)9
C)1
D)3
E)29
Rationale: 12 is an even number. All other given numbers are odd
Answer is A
Answer: A
Question: Zane and Thomas are among the 8 people from which a committee of 4 people is to be selected. How many different possible committees of 4 people can be selected from these 8 people if at least one of either Zane or Thomas is to be selected?
Options:
A)28
B)46
C)55
D)63
E)70
Rationale: Ans:C
Solution:
Z+T+6 = total 8 ,
we need to select at least one of the Z and T or both= total 4 out of 8 - 4 out of 6
8C4 - 6C4
=55
Answer: C
Question: Thabo owns exactly 200 books, and each book is either paperback fiction, paperback nonfiction, or hardcover nonfiction. If he owns 20 more paperback nonfiction books than hardcover nonfiction books, and twice as many paperback fiction books as paperback nonfiction books, how many hardcover books nonfiction books does Thabo own?
Options:
A)10
B)20
C)35
D)45
E)50
Rationale: I think we can use double-matrix method and solve using only one variable.
Our goal is to find the number of hardcover nonfiction books. Let that number be x. We are given that all 140 books are either paperback fiction, paperback nonfiction, or hardcover nonfiction. This implies that number of hardcover fiction books is 0.
Double-matrix: P = paperback; H = hardcover; F = fiction; NF = nonfiction
P H Total
F 2x+40 0
NF x+20 x
Total 3x+60 x 200
3x + 60 + x = 200
x = 35
Answer (C.)
Answer: C
Question: Exactly 30% of the reporters for a certain wire service cover local politics in Country X. If 25% of the reporters who cover politics for the wire service do not cover local politics in Country X, what percent of the reporters for the wire service do not cover politics?
Options:
A)20%
B)42%
C)60%
D)80%
E)84%
Rationale: Let's assume there are 100 reporters --> 30 reporters cover local politics.
Now, as 25% of the reporters who cover all politics do not cover local politics then the rest 75% of the reporters who cover politics do cover local politics, so if there are x reporters who cover politics then 75% of them equal to 30 (# of reporters who cover local politics): 0.75x=30 --> x=40, hence 40 reporters cover politics and the rest 100-40=60 reporters do not cover politics at all.
Answer: C.
Answer: C
Question: For which of the following values of n is (900+n)/n NOT an integer?
Options:
A) 1
B) 2
C) 3
D) 4
E) 5
Rationale: Solution:
This problem is easiest solved by plugging in each answer choice.
A) (900 + 1)/1 = 901/1 = 901
Answer choice A yields an integer.
B) (900 + 2)/2 = 902/2 = 451
Answer choice B yields an integer.
C) (900 + 3)/3 = 903/3 = 301
Answer choice C yields an integer.
D) (900 + 4)/4 = 904/4 = 223, remainder 2
Answer choice D DOES NOT yield an integer.
E) (900 + 5)/5 = 905/5 = 181
Answer choice E yields an integer.
Thus, the correct answer is answer choice D.
Answer: D
Question: Angelo and Isabella are both salespersons. In any given week, Angelo makes $550 in base salary plus 8 percent of the portion of his sales above $6,000 for that week. Isabella makes 10 percent of her total sales for any given week. For what amount of weekly sales would Angelo and Isabella earn the same amount of money?
Options:
A) 3,500
B) 24,500
C) 25,500
D) 26,500
E) 27,500
Rationale: OFFICIAL SOLUTION:
The problem asks for the amount of weekly sales it takes for Angelo and Isabella to earn the same amount of money. You can write an equation that sets Angelo’s and Isabella’s weekly earnings equal to each other, with x representing weekly sales. Weekly earnings for each salesperson equal base salary plus commission. So Angelo’s earnings are 550 + (0.08)(x – 6,000), and Isabella’s are 0.10x. Set up the equation and solve:
550 + (0.08)(x – 6,000) = 0.10x
Distribute the 0.08:
550 + 0.08x – 480 = 0.10x
Combine terms and subtract 0.08x from both sides:
70 = 0.02x
Divide both sides by 0.02:
3,500 = x
Your answer is A.
Answer: A
Question: A is half good a work man as B and together they finish a job in 20 days. In how many days working alone B finish the job?
Options:
A)98 days
B)30 days
C)17 days
D)18 days
E)19 days
Rationale: WC = 1:2
2x + x = 1/20 => x = 1/60
2x = 1/60 => 30 days
Answer:B
Answer: B
Question: If a: b = 7: 5, b: c = 9: 11, find a: b: c?
Options:
A)63: 45: 59
B)63: 45: 55
C)63: 45: 56
D)63: 45: 54
E)63: 45: 51
Rationale: a: b = 7: 5
b: c = 9: 11
a: b: c = 63: 45: 55
Answer:B
Answer: B
Question: Michelle deposited a certain sum of money in a savings account on July 1st, 2007. She earns an 14% interest compounded semiannually. The sum of money in the account on December 31st, 2009 is approximately what percent of the initial deposit?
Options:
A)117%
B)120%
C)121%
D)138%
E)145%
Rationale: Since Michelle earns 14% interest compounded semiannually, then she earns 7% interest every 6 months.
Now, the simple interest earned in 5 periods (30 months = 5*6 months) would be 7%*5=35%. But, since the interest iscompoundedevery 6 months, then there would be interest earned on interest (very small amount) thus the actual interest earned would be a little bit more than 35%, only answer choice D fits.
Answer: D
Answer: D
Question: How many of the positive factors of 56 , 96 and how many common factors are there in numbers?
Options:
A)2
B)4
C)3
D)1
E)5
Rationale: factors of 56 - 1, 2, 4, 7, 8, 14, 28 and 56.
factors of 96 - 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48 and 96.
Comparing both, we have four common factors of 56 and 96- 1,2,4,8
Answer(B)
Answer: B
Question: Working alone, machine X can manufacture 1,000 nails in 12 hours. Working together, machines X and Y can manufacture 1,000 nails in 5 hours. How many hours does it take machine Y to manufacture 1,000 nails working alone?
Options:
A)3 9/17
B)5 1/3
C)7
D)7 1/5
E)8 4/7
Rationale: Rate of machine X = 1000/12 = 250/3
Rate of machine Y = 1/Y
Rate of machine X and Y together = 1000/5 = 200
250/3 + 1/y = 200
after solving this equation we get Y= 3/350
Rate of Y = 1/y = 1/ (3/350) = 350/3
Machine Y has to manufacture 1000 nails. So work is 1000. Putting the values;
time required for machine Y = 1000/(350/3) = 1000* 3/(350) = 60/7 = 8 4/7
ANSWER:E
Answer: E
Question: A large field of 700700 hectares is divided into two parts. The difference of the areas of the two parts is one-fifth of the average of the two areas. What is the area of the smaller part in hectares?
Options:
A)400
B)365
C)385
D)315
E)355
Rationale: Explanation:
Average of the two areas =700/2=350
one-fifth of the average of the two areas=350/5=70
⇒ Difference of the two areas =70=70
Let area of the smaller part = x hectares.
Then, area of the larger part =x+70 hectares.
x+(x+70)=700
⇒2x=630
⇒x=315
Answer: Option D
Answer: D
Question: 0.1+ 0.1^2+0.1^3=
Options:
A) 0.1
B) 0.111
C) 0.1221
D) 0.2341
E) 0.3
Rationale: You have a mistake in your question. Choice B should be (.111) and not (.11).
The equation in the solution can be simplified to (.1 + .01 + .001).
Adding those together you get:
.100
.010
.001
------
.111 - Which is answer choice (B)
Answer: B
Question: P and Q are the only two applicants qualified for a short-term research project that pays 360 dollars in total. Candidate P has more experience and, if hired, would be paid 50 percent more per hour than candidate Q would be paid. Candidate Q, if hired, would require 10 hours more than candidate P to do the job. Candidate P’s hourly wage is how many dollars greater than candidate Q’s hourly wage?
Options:
A)$3
B)$6
C)$9
D)$12
E)$15
Rationale: Let Q's hourly wage be x, then P's hourly wage is 1.5x
Let T be the number of hours that Q needs, then P needs T-10 hours to do the job.
Since they both are paid an equal total amount of $360:
x*T=1.5x*(T-10)
T = 30 hours and Q's hourly wage is 360/30 = $12
P's hourly wage is 360/(T-10) = $18 which is $6 per hour more.
The answer is B.
Answer: B
Question: The price of commodity X increases by 40 paise every year, while the price of commodity Y increases by 15 paise every year. If in 2001, the price of commodity X was Rs. 4.20 and that of Y was Rs. 6.30, in which year commodity X will cost 40 paise more than the commodity Y?
Options:
A)2013
B)2015
C)2014
D)2011
E)2010
Rationale: Suppose commodity X will cost 40 paise more than Y after z years.
Then, (4.20 + 0.40z) - (6.30 + 0.15z) = 0.40
0.25z = 0.40 + 2.10
z = 2.50/0.25
= 250/25
= 10.
Therefore, X will cost 40 paise more than Y 10 years after 2001 i.e., 2011.
Answer is D.
Answer: D
Question: The contents of a certain box consist of 14 apples and 24 oranges. How many oranges must be removed from the box so that 70 percent of the pieces of fruit in the box will be apples?
Options:
A)18
B)6
C)14
D)17
E)20
Rationale: The objective here is that 70% of the fruit in the box should be apples.
Now, there are 14 apples at start and there is no talk of removing any apples, so number of apples should remain 14 and they should constitute 70% of total fruit, so total fruit = 14/0.7 = 20
So we should have 20-14 = 6 oranges.
Right now, there are 24 oranges, so to get to 6 oranges, we should remove 24 - 6 = 18 oranges.
Answer A
Answer: A
Question: A shopkeeper buys two articles for Rs.1000 each and then sells them, making 15% profit on the first article and 15% loss on second article. Find the net profit or loss percent?
Options:
A)200
B)150
C)282
D)202
E)270
Rationale: Profit on first article = 15% of 1000 = 150.
This is equal to the loss he makes on the second article. That, is he makes neither profit nor loss.
Answer: B
Answer: B
Question: A grocer buys apples for 72¢ per pound. If 10% of the apples goes bad and he still wants to make a 20% profit over his purchase price, what should be the sales price?
Options:
A)96¢
B)70¢
C)80¢
D)85¢
E)98¢
Rationale: for making calculation simple let us consider he buys 10pounds @ 72/pound=720¢ in total .
10% apples lost...means 9 pounds left.
further he wants 20% profit on 720 ¢
means he wants to earn 864¢
sales price should be 864/9=¢ 96
Ans A
Answer: A
Question: The difference between a number and its three-fourth is 100. what is 25% of that number?
Options:
A)120
B)100
C)125
D)150
E)None of these
Rationale: Explanation :
Solution: Let the number be x. then, x - 3/4x = 100
=> x/4 = 100
=> x =400.
25% of x = 25% of 400 = 25/100 *400 = 100.
Answer : B
Answer: B
Question: If each digit in the set of A = (1,2,3,4,5) is exactly used once, in how many ways can the digits be arranged such that the 2 and 5 are not adjacent?
Options:
A)6
B)24
C)72
D)96
E)112
Rationale: The answer should be = total arrangements - arrangements when 2 and 5 are together.
= 5! - 4! * 2! = 120 -48 = 72
ANS:C
Answer: C
Question: A car covers a distance of 624 km in 6 Â½ hours. Find its speed?
Options:
A)104 kmph
B)106 kmph
C)108 kmph
D)110 kmph
E)120 kmph
Rationale: 624/6 = 104 kmph
ANSWER A
Answer: A
Question: Of the 12,210 employees of the anvil factory, 2/7 are journeymen. If half of the journeymen were laid off, what percentage of the total remaining employees would be journeymen?
Options:
A) 14.3%
B) 13.67%
C) 33%
D) 28.6%
E) 49.67%
Rationale: The exam gives us a number that is easily divisible by 7 to pique our curiosity and tempt us into calculating actual numbers (also because otherwise the ratio would be incorrect). Since the question is about percentages, the actual numbers will be meaningless, as only the ratio of that number versus others will be meaningful. Nonetheless, for those who are curious, each 1/7 portion represents (14210/7) 2,030 employees. This in turn means that 4,060 employees are journeymen and the remaining 10,150 are full time workers.
If half the journeymen were laid off, that would mean 1/7 of the total current workforce would be removed. This statistic is what leads many students to think that since half the journeymen are left, the remaining journeymen would represent half of what they used to be, which means 1/7 of the total workforce. If 1/7 of the workforce is journeymen, and 1/7 is roughly 14.3%, then answer choice A should be the right answer. In this case, though, it is merely the tempting trap answer choice.
What changed between the initial statement and the final tally? Well, you let go of 1/7 of the workforce, so the total number of workers went down. The remaining workers are still 1/7 of the initial workers, but the group has changed. The new workforce is smaller than the original group, specifically 6/7 of it because 1/7 was eliminated. The remaining workers now account for 1/7 out of 6/7 of the force, which if we multiply by 7 gives us 1 out of 6. This number as a percentage is answer choice B, 13.67%.
Using the absolute numbers we calculated before, there were 4,060 journeymen employees out of 14,210 total. If 2,030 of them are laid off, then there are 2,030 journeyman employees left, but now out of a total of (14,210-2,030) 12,180 employees. 2,030/12,180 is exactly 1/6, or 16.67%. The answer will work with either percentages or absolute numbers, but the percentage calculation will be significantly faster and applicable to any similar situation.
The underlying principle of percentages (and, on a related note, ratios) can be summed up in the brainteaser I like to ask my students: If you’re running a race and you overtake the 2nd place runner just before the end, what position do you end up in?
The correct answer is 2nd place.
Percentages, like ratios and other concepts of relative math, depend entirely on the context. Whether 100% more of something is better than 50% more of something else depends on the context much more than the percentages quoted. When it comes to percentages on the GMAT, the goal is to understand them enough to instinctively not fall into the traps laid out for you.
B
Answer: B
Question: A confectioner decides to sell all of his pastry due to the coming holiday. His pastry goods are equally divided among a group of 25 regular customers. If only 49 customers come to the bakery, each one will receive 6 less pastry goods. How much pastry does the confectioner needs to sell?
Options:
A)300.
B)412.
C)432.
D)502.
E)522.
Rationale: Pastry is divided in 25 customers equally. So,total number of pastry must be a multiple of 25
Only option A satisfies the condition, and hence is the answer
Answer: A
Question: A company has 50 employees, of which 22 studied accounting, 15 studied finance and 14 studied marketing. Eight employees have done just two courses and only one made ​​the three courses. How many employees have no training?
Options:
A)A)0
B)B)9
C)C)10
D)D)11
E)E)26
Rationale: Total employees=50
studied accounting=22
studied finance=15
studied marketing=14
8 employees have been double counted and one employee has been counted thrice.
Therefore employees who have received training=22+15+14-8-(2*1)
=51-10
=41
Employees with no training
=50-41
=9
Ans=B
Answer: B
Question: A trader marks his articles 20% more than the cost price. If he allows 20% discount, then find his gain or loss percent?
Options:
A)7
B)6
C)8
D)5
E)4
Rationale: Let CP of an article = RS. 100
MP= Rs. 120
Discount = 20%
SP = M[(100 - d%)/100] = 120(80/100) = Rs. 96
Clearly, the trader gets 4% loss.
Answer: E
Answer: E
Question: 529 is a perfect square. When x is added to the prime factor of 529, the result will give a perfect cube.then what is x?
Options:
A)1
B)2
C)3
D)4
E)5
Rationale: 529 is 23*23
here
A 23+1 = 24
B 23+2 = 25
C 23+3 = 26
D 23+4 = 27
E 23+5= 28
so, D is the only addition that gives a perfect cube. so x=4
then the answer is D
Answer: D
Question: In a three digit number, the hundred digit is 2 more than the tens digit and the units digit is 2 less than the tens digit. If the sum of the digits is 18, find the number?
Options:
A)867
B)864
C)385
D)946
E)549
Rationale: B
864
Let the three digit numbers be 100a + 10b + c
a = b + 2
c = b - 2
a + b + c = 3b = 18 => b = 6
So a = 8 and b = 4
Hence the three digit number is: 864
Answer: B
Question: Two numbers are in the ratio of 7:6. If 18 be subtracted from each, they are in the ratio of 6:5. Find the numbers?
Options:
A)5,9
B)7,9
C)4,7
D)7,6
E)6,9
Rationale: (7x-18):(6x-18) = 6:5
x = 1 => 7,6
Answer: D
Answer: D
Question: A person bought apples at 10 for $1 and sold them at 4 for $1. Find his gain or loss percent?
Options:
A)150%
B)-100%
C)100%
D)-50%
E)50%
Rationale: Number of bananas bought = L.C.M of 10 and 4 = 20
C.P. = 1/10 * 20 = $2
S.P. = 1/4 * 20 = $5
Gain% = 3/2 * 100 = 150%
Answer is A
Answer: A
Question: If n ≠ 0, which of the following must be greater than n?
I. 6n
II. n^2
III. 2 - n
Options:
A)I only
B)None
C)I and II only
D)II and III only
E)II only
Rationale: n ≠ 0 => n = negative or n = positive
if n = negative:
2n < n (n = -1 then 2n = -2 => -2 < -1)
n^2 > n (n =-1 then n^2 = 1 => n^2 > n)
2 - n > n (n = -1 then 2--1 = 2+1=3 => 2-n > n)
but if n = positive:
n^2 > n (n = 2 then n^2 = 4 => n^2 > n) => II
2 - n < n(n =2 then 2-2 = 0)
=> only II
=>answer is E
Answer: E
Question: Line Q has the equation 5y – 3x = 75. If Line S is perpendicular to Q, has an integer for its y-intercept, and intersects Q in the second quadrant, then how many possible Line S’s exist? (Note: Intersections on one of the axes do not count.)
Options:
A)48
B)52
C)56
D)60
E)64
Rationale: 5y - 3x = 75 and so y = 3x/5 + 15
When x = 0, then y = 15.
When y = 0, then x = -25
The slope is 3/5, so the slope of line S is -5/3.
Through the point (-25, 0), 0 = -5(-25)/3 + c
The y-intercept is c = -125/3 < -41.
Thus the perpendicular line S can have y-intercepts from -41 up to 14.
The number of possible lines is 41 + 14 + 1 = 56
The answer is C.
Answer: C
Question: In a certain match all the teams were to play with each other. If there are 12 teams, how many matches will have to be played?
Options:
A)40
B)45
C)66
D)90
E)None of the above
Rationale: 12c2
=66
ANSWER:C
Answer: C
Question: A question paper has 2parts, A & B, each containing 10 questions. If a student has to choose 5 from part A &10 from part B, in how many ways can he choose the questions?
Options:
A)100
B)120
C)125
D)350
E)252
Rationale: There 5 questions in part A out of which 10 question can be chosen as = 10C5
Similarly, 10 questions can be chosen from 10 questions of Part B as = 10C10.
Hence, total number of ways,
=10C5*10C10
=[10!/(5!5!)]*[10!/(0!*10)]
= {10*9*8*7*6/(5*4*3*2*1)}* 10!/1*10!
= 252
E
Answer: E
Question: A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Options:
A)100
B)120
C)130
D)150
E)160`
Rationale: Speed=(60 * 5/18) m/sec = (50/3) m/sec Length of the train = (Speed x Time) = (50/3 * 9) m = 150 m.
Answer: Option D
Answer: D
Question: If the roots of the equation 2x2 - 5x + b = 0 are in the ratio of 2:3, then find the value of b?
Options:
A)2
B)3
C)4
D)5
E)7
Rationale: Let the roots of the equation 2a and 3a respectively.
2a + 3a = 5a = -(- 5/2) = 5/2 => a = 1/2
Product of the roots: 6a2 = b/2 => b = 12a2
a = 1/2, b = 3.
B
Answer: B
Question: Find the missing figures :
?% of 30 = 2.125
Options:
A)8.5
B)6.5
C)8.07
D)7.08
E)4.05
Rationale: (i)	Let x% of 30 = 2.125. Then , (x/100)*30 = 2.125
X = (2.125 * 100/30) = 7.08
Answer is D.
Answer: D
Question: A can run 3 Kms in 3 min 18 sec and B can run same distance in 3 min 40 sec, then by how much distance A can beat B?
Options:
A)300 m
B)220 m
C)280 m
D)195 m
E)295 m
Rationale: Distance travelled=3000m
Time taken by A=3 m 18 s
Time taken by B=3 m 40 sec=220 sec
speed of B=3000m/220 s=150/11 m/s
Difference between time of A and B=22 sec
when time will be 3 m 18 s A will have travelled 3000m but B need 22 sec more to finish.
Distance travelled by B in 22 sec=(150/11)*22=300 m
Hence, A beat B by 300 m
ANSWER:A
Answer: A