divelab/Sys2Bench huggingface dataset:
Question: Arya starts cycling along the boundaries of the squares. She starts from a point A and after 90 minutes she reached to point C diagonally opposite to A. If she is travelling with 20km/hr, then find the area of square field.
Options:
A)125
B)225
C)325
D)425
E)None of these
Rationale: Explanation :
D = 20*3/2 = 30 km. So side of square is 15km, so area – 225km^2
Answer – B
Answer: B
Question: The length of a rectangle is increased by 25% and its breadth is decreased by 20%. What is the effect on its area?
Options:
A)10000
B)10008
C)10005
D)10004
E)10001
Rationale: 100 * 100 = 10000
125 * 80 = 10000
No change
Answer:A
Answer: A
Question: The H.C.F. and L.C.M. of two numbers are 15 and 5040 respectively If one of the numbers is 144, find the other number
Options:
A)400
B)256
C)120
D)420
E)525
Rationale: Explanation:
Solve this question by using below formula.
Product of 2 numbers = product of their HCF and LCM
144 * x = 15 * 5040
x = (15*5040)/144 = 525
Option E
Answer: E
Question: A certain junior class has 1000 students and a certain senior class has 800 students. Among these students, there are 60 siblings pairs each consisting of 1 junior and 1 senior. If 1 student is to be selected at random from each class, what is the probability that the 2 students selected will be a sibling pair?
Options:
A)3/40000
B)1/3600
C)9/2000
D)1/60
E)1/15
Rationale: There are 60 siblings in junior class and 60 their pair siblings in the senior class. We want to determine probability of choosing one sibling from junior class and its pair from senior.
What is the probability of choosing ANY sibling from junior class? 60/1000 (as there are 60 of them).
What is the probability of choosing PAIR OF CHOSEN SIBLING in senior class? As in senior class there is only one pair of chosen sibling it would be 1/800 (as there is only one sibling pair of chosen one).
So the probability of that the 2 students selected will be a sibling pair is: 60/1000∗1/800=3/40000
Answer: A.
Answer: A
Question: If r ≠ 1 and if sr/(s - r) = 1, what is the value of s in terms of r?
Options:
A)(r+1)/r
B)(r - 1)/r
C)r/(r + 1)
D)r/(1-r)
E)(1 - r)/r
Rationale: This question comes with a particular 'quirk' (one that you probably won't see on Test Day). The GMAT won't test you on the concept of undefined numbers (re: numbers divided by 0), so any time that this concept is a possibility, the question writers have to add a restriction that removes the option that a 0 could occur in the denominator.
Here, we're told that B CANNOT = 1, which is a bit strange because that restriction doesn't seem to impact the original equation much. In fact, it impacts JUST ONE of the answer choices - so you have to ask WHY that restriction is even there. It's actually because that one answer is the correct one.
Final Answer:
D
Answer: D
Question: Worker W produces n units in 5 hours. Workers V and W work independently but at the same time, produce n units in 2 hours. How long would it take V alone to produce n units?
Options:
A)8/3 hours
B)10/3 hours
C)11/3 hours
D)12/3 hours
E)18/3 hours
Rationale: w's 1 hours production=n/5
(w+v)'s 1 hours production=n/2
v's 1 hours production
n/5+V=n/2
v's 1 hours production=n/2-n/5
=3n/10
n/(10/3)
ans=10/3 hours
ANSWER:B
Answer: B
Question: A computer manufacturer produces a certain electronic component at a cost of $50 per component. Shipping costs for delivering the components are $8 per unit. Further, the manufacturer has costs of $16,000 a month related to the electronic component regardless of how many it produces. If the manufacturer produces and sells 200 components a month, what is the lowest price it can sell them for such that the costs don't exceed the revenues?
Options:
A)135
B)129
C)131
D)138
E)141
Rationale: $16000 is a fixed cost
Each component is $58 ($50 to produce, $8 to ship)
Manufacturer will be producing and selling 200 components
so therefore the equation to find price would be
200*p = 16000+(200*50)+(200*8)
p = (16000+10000+1600)/200
p = 138
Answer: D
Answer: D
Question: A fruit drink is made of orange, watermelon, and grape juice, where 35 percent of the drink is orange juice and 35 percent is watermelon juice. If the drink is made with 45 ounces of grape juice, how many ounces is the drink total?
Options:
A)120
B)140
C)150
D)180
E)200
Rationale: Let the total number of ounces in the drink be x.
% of orange = 35%
% of watermelon = 35%
% of grape = 100% - 70% = 30%
0.30x = 45
x = 150
Therefore there are a total of 150 ounces in the drink.
The answer is C.
Answer: C
Question: Find 44 % of 240
Options:
A)96
B)105.6
C)86
D)74
E)110
Rationale: We know that R % of m is equal to R/100 × m.
So, we have 44 % of 240
44/100 × 240
=105.6
Answer:B
Answer: B
Question: Suresh and Ramesh started a business investing Rs. 24,000 and Rs. 40,000 respectively. Out of total profit of Rs. 15,000, what is Ramesh's share?
Options:
A)Rs. 9375
B)Rs. 9379
C)Rs. 9376
D)Rs. 9372
E)Rs. 9371
Rationale: Explanation:
Ratio of Suresh and Ramesh's share = 24,000 : 40,000 = 3 : 5
Ramesh's share = Rs. (15000 x 5 / 8) = Rs. 9375
ANSWER: A
Answer: A
Question: ?% of 360 = 108.0
Options:
A)277
B)36
C)64
D)72
E)30
Rationale: ?% of 360 = 108.0
or, ? = 108.0×100/360=30
Answer E
Answer: E
Question: what is the least number by which 46,800 must be divided to get a number perfect square
Options:
A)21
B)52
C)24
D)40
E)45
Rationale: 46,800/52=900
900=(30)^2
Ans-52
ANSWER:B
Answer: B
Question: What is 15 percent of 44?
Options:
A)6.6
B)7.8
C)8.9
D)9.4
E)10.2
Rationale: (15/100) * 44 = 6.6
The answer is A.
Answer: A
Question: Rohit and Rohan can complete a work in 12 days and 6 days respectively. How much time will they take when working together?
Options:
A)4
B)3
C)5
D)2
E)1
Rationale: Time taken by Rohit and Rohan = xy/ x+y
=12*6/(12+6)
= 4 days
ANSWER:A
Answer: A
Question: If x = y^2, and x and y are positive integers, which of the following numbers could be the value of x?
Options:
A)7396
B)6847
C)4262
D)8798
E)9563
Rationale: The square of an integer can have a units digit of 0, 1, 4, 5, 6, or 9.
The answer is A.
Answer: A
Question: Two cars are traveling towards each other. If car A is traveling at a speed of 70 mph and car B is traveling 10% slower, how much time will it take the cars to meet if the initial distance between the two is 705 miles?
Options:
A)Five hours and 30 minutes.
B)Seven hours and 30 minutes.
C)Eight hours and 20 minutes.
D)Nine hours and 15 minutes.
E)Ten hours and 20 minutes.
Rationale: Speed of second train= 70*90/100= 63
Time= toral distance /total speed
705/ (70+63)= 705/133= 5.___
A is the answer
Answer: A
Question: The sum of money will be double itself in 10 years and simple interest find rate of interest?
Options:
A)A)5%
B)B)10%
C)C)15%
D)D)20%
E)E)25%
Rationale: T = 10 years
P= principle amount = x
A = total amount = 2x
SI = simple interest = A-P = 2x-x = x
R = 100SI/PT = 100x/10x =10%
Answer is B
Answer: B
Question: A person saves 10% of his income. If his income is increased by 20% and he saves 15% of the new income, by what percent his savings will increase?
Options:
A)80%
B)90%
C)70%
D)60%
E)50%
Rationale: Ans. Let previous income = Rs. 100
Previous savings = 10% of Rs. 100 = Rs. 10
Increased income = Rs. 100 + 20% of Rs. 100 = Rs. 120
Increased savings = 15% of Rs. 120 = Rs. 18
Therefore, Increase in savings = Rs. 18 - Rs. 10 = Rs. 8
Therefore, Percent increase in savings = 8/10 x 100 = 80%
Answer A
Answer: A
Question: If 9 is a factor of 2a, then which of the following may not be an integer?
Options:
A)6a/54 + 2a/3
B)(4a-18)/9
C)(2a+27)/9
D)(81-4a^2)/81
E)(2a-3)/3
Rationale: I got the right answer A after plugging in 18 for a.
While going through Kaplan's explanation, I couldn't understand the part about choice A.
"6a/54 + 2a/3 = 3/6 * 2a/9 + 2a/3.
Since 9 is a factor of 2a, 3 is also factor of 2a. So 2a/3 is an integer, as is 2a/9. But 3/6 = 1/2, so if 2a/9 is not even, the expression 3/6 * 2a/9 will not be even."
But, isn't 2a/9 always even? 9 is a factor of 2a, which means that we could have 2(9), 2(2)(9), 2(3)(9), and so forth. The 9 in the denominator cancels out the 9 in the numerator. So we are left with 2 * something. So 2a/9 is even.A
Answer: A
Question: If a and b are both even numbers, which of the following is an even number?
Options:
A)a + b+3
B)a + b + 1
C)ab
D)ab + 1
E)NONE
Rationale: Sol.
Product of two odd numbers is always odd and adding 1 gives even.
Answer C
Answer: C
Question: The present ages of three persons in proportions 4 : 7 : 8. Eight years ago, the sum of their ages was 71. Find their present ages (in years).
Options:
A)15, 20, 28
B)24, 28, 36
C)20, 35, 40
D)33,42,43
E)of these
Rationale: Let their present ages be 4x, 7x and 8x years respectively.
Then, (4x - 8) + (7x - 8) + (8x - 8) = 71
19x = 95
x = 5.
Their present ages are 4x = 20 years, 7x = 35 years and 8x = 40 years respectively.
ANSWER:C
Answer: C
Question: If x+y=290, x-y=200, for integers of x and y, y=?
Options:
A)200
B)245
C)50
D)115
E)150
Rationale: x+y = 290
x-y = 200
2x = 90
x = 45
y = 245
Answer is B
Answer: B
Question: Worker A takes 8 hours to do a job. Worker B takes 10 hours to do the same Job. How long should it take both A and B, working together but independently, to do the same job?
Options:
A)70 hours
B)40/9 hours
C)9 hours
D)16 hours
E)20 hours
Rationale: A’s 1 hour's work = 1/8
B's 1 hour's work = 1/10
(A + B)'s 1 hour's work = (1/8) +(1/10)=9/40
Both A and B will finish the work in 40/9 days.
ANSWER B 40/9 hours
Answer: B
Question: What was the day of the week on 4th April, 2006?
Options:
A)Saturday
B)Thursday
C)Monday
D)Friday
E)Tuesday
Rationale: 28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 6 odd days
Jan. Feb. March April
(31 + 28 + 31 + 4) = 94 days
94 days = (13 weeks + 3 day) 1 odd day.
Total number of odd days = (0 + 0 + 6 + 3) = 9 0 odd day.
Given day is Tuesday.
Answer: Option E
Answer: E
Question: Each of the integers from 1 to 17 is written on the a seperate index card and placed in a box. If the cards are drawn from the box at random without replecement, how many cards must be drawn to ENSURE that the product of all the integers drawn is even?
Options:
A)19
B)12
C)11
D)10
E)3
Rationale: Out of the 17 integers: 9 are odd and 8 are even.
If we need to make sure that the product of all the integers withdrawn is even then we need to make sure that we have at least one even number. In the worst case:
1. we will end up picking odd numbers one by one, so we will pick all 9 odd numbers first
2. 10th number will be the first even number
So we need to withdraw at least 10 numbers to make sure that we get one even number and the product of all the integers picked is even.
So, answer will be 10. (D)
Answer: D
Question: In the last set of tests, a student scored marks in each of 5 subjects in the ratio 4:5:6:7:8 and got an overall average score of 54%. If a mark of 50% in a subject is a pass and the maximum marks of each subject is the same, how many subjects did the student pass?
Options:
A)1
B)2
C)3
D)4
E)5
Rationale: The tests scores are 4k, 5k, 6k, 7k, and 8k.
The sum of the test scores is 30k.
The average test score is 30k/5 = 54. Then k = 9.
The test scores are 36, 45, 54, 63, and 72.
The student passed 3 subjects.
The answer is C.
Answer: C
Question: The average age of seven persons sitting in a row facing east is 28 years. If the average age of the first three persons is 21 years and the average age of the last three persons is 34 years, then find the age of the person sitting in the middle of the row?
Options:
A)15 years
B)31 years
C)27 years
D)82 years
E)12 years
Rationale: Total age seven persons = (28 * 7)years
Total age of the first three persons and the last three persons are (21 * 3) years and (34 * 3) years respectively.
Age of the person sitting in the middle of the row
= 28 * 7 - 21 * 3 - 34 * 3 = 196 - 63 - 102
= 31 years.
Answer: B
Answer: B
Question: Find the simple interest on the Rs. 2000 at 25/4% per annum for the period from 4th Feb 2005 to 18th
April 2005
Options:
A)Rs 25
B)Rs 30
C)Rs 35
D)Rs 40
E)None of these
Rationale: Explanation:
One thing which is tricky in this question is to calculate the number of days.
Always remember that the day on which money is deposited is not counted while the day on which
money is withdrawn is counted.
So lets calculate the number of days now,
Time = (24+31+18) days = 73/365 years = 1/5 years
P = 2000
R = 25/4%
S.I. = =2000×254×5×100=25
Answer: A
Answer: A
Question: If 'A' means '-', 'B' means '/', 'C' means '+', and 'D' means 'X' then
Find the value of the following:
21 B 7 C 9 D 10 A 13
Options:
A)80
B)40
C)60
D)70
E)50
Rationale: A
80
Explanation:
21 B 7 C 9 D 10 A 13
= 21 / 7 + 9 X 10 - 13
= 3 + 90 - 13
= 80
Answer: A
Question: At what rate of compound interest per annum will a sum of Rs. 1200 become Rs. 1348.32 in 2 years
Options:
A)3%
B)4%
C)5%
D)6%
E)7%
Rationale: Explanation:
Let Rate will be R%
1200(1+R/100)2=134832 /100
(1+R/100)2=134832/120000
(1+R/100)2=11236/10000
(1+R/100)=106/100
=>R=6%
Option D
Answer: D
Question: Running at their respective constant rates, machine X takes 2 days longer to produce w widgets than machine Y. At these rates, if the two machines together produce 5/4 w widgets in 3 days, how many days would it take machine X alone to produce 5w widgets?
Options:
A)4
B)30
C)8
D)10
E)12
Rationale: Let Y produce w widgets in y Days
Hence, in 1 day Y will produce w/y widgets.
Also, X will produce w widgets in y+2 days (given, X takes two more days)
Hence, in 1 day X will produce w/y+2 widgets.
Hence together X and Y in 1 day will produce {w/y + w/y+2} widgets.
Together X and Y in 3 days will produce = 3 * [{w/y + w/y+2}] widgets.
It is given that in 3 days together they produce (5/4)w widgets.
Equating, 3 * [{w/y + w/y+2}] = (5/4)w
Take out w common and move 3 to denominator of RHS
w{1/y + 1/(y+2)} = (5/12)w
Canceling w from both sides
{1/y + 1/(y+2)} = 5/12
2y+2/y(y+2) = 5/12
24y+24=5y^2 + 10y
5y^2-14y-24=0
5y^2-20y+6y-24=0
5y(y-4)+6(y-4)=0
(5y+6)+(y-4)=0
y=-6/5 or y=4
Discarding y=-6/5 as no of days cannot be negative
y=4
hence it takes Y, 4 days to produce w widgets.
Therefore, it will take X (4+2)=6 days to produce w widgets.
Hence it will take X 5*6=30 days to produce 2w widgets.
Answer : B
Answer: B
Question: In the quadratic equation ax2+ 1x - 6 = 0, if the sum of two roots is -1, what is the product of the two roots?
Options:
A)4
B)5
C)6
D)-6
E)8
Rationale: Explanation:
The sum of the roots of the quadratic equation ax2 + bx + c = 0 are (-b/a) and the product of the roots are (c/a).
Thus, in the equation ax2+ x - 6 = 0, where a = a, b = 1 and c = -6.
we get, sum of the roots = -1 / a = -1
a = 1
Product of the roots = -6 / 1 = -6
ANSWER: D
Answer: D
Question: If r>0.9, which of the following options can be the value of r?
Options:
A)0.9^2
B)√(0.9)
C)0.09
D)0.9
E)0.9^3
Rationale: Lets take a few examples
When .2 is squared it gives .04
when .5 is squared it gives .25
When .9 is squared it gives .81
So raising a fraction to its power of 2 or 3 only reduces the value of the fraction
This is because
.2 = 2/10
.2^2= 4/100
.2^3=8/1000
Since the denominator gets an extra 0 each time u increase the power , it is going to drag the value down
But if you just think about the opposite case :
Then we can see , if squaring a fraction diminish its value, then taking the square root of it will again increase its value
that is √(0.04) will give you back 0.2
so √(0.04) > 0.04
so obviously diminishing the power will appreciate the value
So r √(0.9) > 0.9
Hence Correct Answer is (B)
Answer: B
Question: Five friends go to see a movie at the local movie theater and sit in a row together. If there are two friends who refuse to sit next to each other, how many 5-person seating arrangements are possible?
Options:
A)72
B)90
C)120
D)140
E)180
Rationale: The number of ways to arrange 5 people in a row is 5! = 120
From this we want to subtract all the arrangements where the two friends are next to each other. If we consider them as one unit, then the number of arrangements of this 2-person unit and the 3 other friends is 4! And the number of arrangements of the two friends within this unit are 2 because the two friends can switch places. So the total number of arrangements of the 5 friends with the 2-person unit together is 4!*2
The total number of permutations where these two friends are not seated next to each other is 5! - 4!*2 = 120 - 48 = 72
The answer is A.
Answer: A
Question: 5020−(502÷100.4)=?
Options:
A)15
B)20
C)5015
D)25
E)35
Rationale: Explanation:
=5020−(502/1004×10)
=5020−5=5015
Option C
Answer: C
Question: P software has coding line 5% more than N, N software has coding line 5/2 more than M. M software has 108 lines of coding. find P lines.
Options:
A)106
B)107
C)397
D)109
E)110
Rationale: M s/w has 108 line of code
N s/w has = 108+108*5/2= 378 line of code
P s/w 5% more N' code 378+18.9=396.9
or
397 line of code
ANSWER:C
Answer: C
Question: When 5 fair coins are tossed simultaneously, in how many outcomes will the first and the last coin turn up heads?
Options:
A)1
B)3
C)8
D)31
E)30
Rationale: With 5 coins being tossed, you might expect this question to be more difficult than it actually is. The prompt asks for the number of outcomes in which the first and fifth coins are both heads. To start, we can 'lock in' those options.
H _ _ _ H
Now we just have to focus on the possible outcomes for the remaining 3 coins. Mathematically, since each coin has 2 possible outcomes, there are (2)(2)(2) = 8 options.
You could also 'map out' the possibilities:
HHH
HHT
HTH
THH
TTT
TTH
THT
HTT
8 total options.
Final Answer:C
Answer: C
Question: If z is a multiple of 8902, what is the remainder when z^2 is divided by 4?
Options:
A)0
B)1
C)2
D)3
E)It depends on z.
Rationale: 2 is a factor of 8902, so 2 is a factor of z.
Then 2^2 = 4 is a factor of z^2.
Then the remainder when z^2 is divided by 4 is 0.
The answer is A.
Answer: A
Question: Sunita goes 30 km towards North from a fixed point, then after turning to her right she goes 15 km. After this she goes 30 km after turning to her right. How far and in what direction is she from her starting point?
Options:
A)45 km, East
B)15 km, East
C)45 km, West
D)45 Km, North
E)None of these
Rationale: Sunita moves 15 km right after she was moving towards north. That is she walked 15 kms towards east. Then she moves 30 kms right i.e. se comes in the same direction from which she started. Hence the displacement is only 15 km and that is towards east.
ANSWER:B
Answer: B
Question: If 4 men or 6 boys can finish a work in 20 days. How long will 6 men and 11 boys take to finish the same work?
Options:
A)10 days
B)6 days
C)4 days
D)3 days
E)8 days
Rationale: 4 men = 6 boys
Then, 1 boy = 4/6 men = 2/3 men
11 boys = 2/3 × 11 men = 22/3 men
Then, 6 men + 11 boys = 6 + 22/3 men = 40/3 men
1 work done = 4 men × 20days
That is, 4 × 20 = 40/3 × ? days
? days = 4 × 20 × 3/40 = 6 days
Answer : B
Answer: B
Question: Mr. James sold two pipes at $1.20 each. Based on the cost, his profit one was 20% and his loss on the other was 20%. On the sale of the pipes, he:
Options:
A)broke even
B)lost 4 cents
C)gained 4 cents
D)lost 10 cents
E)gained 10 cents
Rationale: A
broke even
20 % profit on $ 1.20
= $ 20/100 × 1.20
= $ 0.20 × 1.20
= $ 0.24
Similarly, 20 % loss on $ 1.20
= $ 20/100 × 1.20
= $ 0.20 × 1.20
= $ 0.24
Therefore, in one pipe his profit is $ 0.24 and in the other pipe his loss is $ 0.24.
Since both profit and loss amount is same so, it’s broke even.
Answer: A
Question: A man sitting in a train which is traveling at 40 kmph observes that a goods train, traveling in opposite direction, takes 9 seconds to pass him. If the goods train is 280 m long, find its speed.?
Options:
A)50 kmph
B)58 kmph
C)62 kmph
D)65 kmph
E)72 kmph
Rationale: Relative speed = 280/9 m / sec = ((280/9)*(18/5)) kmph = 112 kmph.
Speed of goods train = (112 - 40) kmph = 72 kmph.
Answer : E
Answer: E
Question: A train travels m miles in n hours. How many miles will it travel in x hours at the same rate?
Options:
A)mnx
B)m⁄n
C)mx⁄n
D)mx
E)mn⁄x
Rationale: Given Speed = m/n
To Find distance in x hours with same speed
Distance = speed * time
Distance = m/n*x = mx/n
Answer C
Answer: C
Question: A tradesman by means of his false balance defrauds to the extent of 20%? in buying goods as well as by selling the goods. What percent does he gain on his outlay?
Options:
A)44%
B)48%
C)94%
D)45%
E)34%
Rationale: g% = 20 + 20 + (20*20)/100
= 44%
Answer: A
Answer: A
Question: If a and b are positive integers and x = 4^a and y = 3^b, which of the following is a possible units digit of xy?
Options:
A)0
B)1
C)5
D)7
E)8
Rationale: The units digit of 4^a is either 4 or 6.
The units digit of 3^b is 3, 9, 7, or 1.
We can multiply the units digits together to see that the units digits of xy could be 2, 4, 6, or 8.
The answer is E.
Answer: E
Question: A, B and C are partners. A receives 2/3 of profits, B and C dividing the remainder equally. A's income is increased by Rs.300 when the rate to profit rises from 5 to 7 percent. Find the Capital of A?
Options:
A)5000
B)10000
C)15000
D)2778
E)1991
Rationale: A:B:C = 2/3:1/6:1/6 = 4:1:1
x * 2/100 * 2/3 = 300
A's capital = 22500*2/3 = 15000
Answer: C
Answer: C
Question: At what rate percent per annum will the simple interest on a sum of money be 2/5 of the amount in 10 years?
Options:
A)4 %
B)5 %
C)6 %
D)7 %
E)8 %
Rationale: Sol.
Let sum = x. Then, S.I. = 2x/5, Time = 10 years.
∴ Rate = [100 * 2x / x*5*10]% = 4%.
Answer A
Answer: A
Question: The calendar of the year 2028 can be used again in the year?
Options:
A)2041
B)1951
C)2056
D)1971
E)1973
Rationale: Explanation:
Given year 2028 when divided by 4, leaves a remainder 0.
NOTE: When remainder is 0, 28 is added to the given year to get the result.
So, 2028 + 28 = 2056
Answer: C
Answer: C
Question: If the cost price of 60 articles is equal to the selling price of 50 articles, then what is the percent profit?
Options:
A)10%
B)15%
C)20%
D)25%
E)30%
Rationale: Let x be the cost price of one article.
Let y be the selling price of one article.
50y = 60x
y = 1.2x
The answer is C.
Answer: C
Question: Tabby is training for a triathlon. She swims at a speed of 1 mile per hour. She runs at a speed of 11 miles per hour. She wants to figure out her average speed for these two events. What is the correct answer for her?
Options:
A)6 mph
B)5.25 mph
C)3.5 mph
D)4 mph
E)0.5 mph
Rationale: (1 mph +11 mph)/2 = 6 mph
Correct option is: A
Answer: A
Question: The sides of a triangle are in the ratio 5: 12: 13 and its perimeter is 300 m, its area is?
Options:
A)3000 sq m
B)1878 sq m
C)2789 sq m
D)26811 sq m
E)29762 sq m
Rationale: 5x + 12x + 13x = 300 => x = 10
a = 50, b = 120, c = 130
S = (50 + 120 + 130)/2 = 150
3000 sq m
Answer:A
Answer: A
Question: A dealer sold two of his cattle for Rs. 500 each. On one of them he lost 10% on the other, he gained 10%. His gain or loss percent in the entire transaction was:
Options:
A)2
B)1
C)7
D)9
E)0
Rationale: Explanation:
Loss%= (common gain or loss % / 10)2 = (10/10)² % = 1%.
Answer: B) 1% loss
Answer: B
Question: 47% of the students in a class of 34 students has glasses or contacts. How many students in the class have either glasses or contacts?
Options:
A)15
B)16
C)17
D)18
E)19
Rationale: a=r⋅b
a=r⋅b
47%=0.47a
47%=0.47a
=0.47⋅34
=0.47⋅34
a=15.98≈16
Option B is correct.
Answer: B
Question: A certain clock marks every hour by striking a number of times equal to the hour, and the time require for a stroke is exactly equal to the time interval between strokes. At 6:00 the time lapse between the beginning of the first stoke and the end of the last stroke is 22 seconds. At 7:00, how many seconds elapse between the beginning of the first stroke and the end of the last stroke?
Options:
A)26
B)29
C)19
D)30
E)40
Rationale: at 6'o clock, there would be 6 strikes. First strike, then a short interval, the second strike, then a short interval and so on till the 6th strike. So there would be in all 5 intervals between 6 strikes. Similarly, between 7 strikes, there would be 6 intervals.
According to the question, the time spent in the strike and the interval is same.
At 6'o clock, the 6 strikes and the 5 intervals together take 22 sec so each strike and each interval takes 2 secs.
At 7'o clock, the 7 strikes and 6 intervals will take 2*(7+6) = 26 secs
A
Answer: A