divelab/Sys2Bench huggingface dataset:
Question: A bag is filled with pennies and nickels in the ratio of 5 to 3. There are 30 nickles in the bag, how many coins are there in that bag?
Options:
A)70
B)65
C)75
D)85
E)80
Rationale: A ratio of pennies to nickels of 5 to 3 means that we can write the number of pennies and nickels in the form
number of pennies = 5x and number of nickels = 3x
But we know the number of nickels, 30. Hence
3x = 30
Solve for x
x = 10
The total number of coins is given by
5x + 3x = 8x = 8 × 10 = 80
E
Answer: E
Question: The L.C.M. of two numbers is 42. The numbers are in the ratio 2 : 3. Then sum of the number is:
Options:
A)28
B)32
C)35
D)53
E)54
Rationale: Let the numbers be 2x and 3x.
Then, their L.C.M. = 6x.
So, 6x = 42 or x = 7.
The numbers are 14 and 21.
Hence, required sum = (14 + 21) = 35.
Answer: Option C
Answer: C
Question: Kiran has $100 in her piggy bank. How much will she have in her bank 30 weeks from now if she puts $1 in the bank next week, $2 two weeks from now, $3 three weeks from now, and continues to increase the amount that she puts in by $1 each week?
Options:
A)500
B)525
C)535
D)565
E)575
Rationale: The dollar deposits are in an A.P.
1,2,3,4...30 with common difference 1
Sum of the terms is n(n+1) / 2
i.e 30 * (30+1) /2
= 30 * 31/2 = 465
Total deposit therefore with Chiu-Lihas is 100 + 465 = 565$
Answer: D
Question: Find the area of a parallelogram with base 24 cm and height 16 cm.
Options:
A)304 cm2
B)384 cm2
C)184 cm2
D)284 cm2
E)385 cm2
Rationale: Area of a parallelogram = base * height
= 24 * 16
= 384 cm2
Answer: B
Answer: B
Question: A man can row upstream at 7 kmph and downstream at 10kmph.find man’s rate in still water and the rate of current.
Options:
A)1.5 km/hr
B)2.5 km/hr
C)3.5 km/hr
D)4.5 km/hr
E)5.5 km/hr
Rationale: Rate in still water=1/2(10+7)km/hr=8.5 km/hr.
Rate of current=1/2(10-7)km/hr=1.5 km/hr.
ANSWER A 1.5 km/hr
Answer: A
Question: A cube of side 5 meter length is cut into small cubes of side 25cm each. How many such small cubes can be obtained?
Options:
A)10781
B)1276
C)1000
D)8000
E)5000
Rationale: Along one edge, the number of small cubes that can be cut
= 500/25 =20
Along each edge 20 cubes can be cut. (Along length, breadth and height). Total number of small cubes that can be cut
=20 *20 * 20 = 8000
Answer:D
Answer: D
Question: What is the ratio between perimeters of two squares one having 3 times the diagonal then the other?
Options:
A)4:8
B)1:4
C)6:2
D)3:1
E)1:2
Rationale: Explanation:
d = 3d d = d
aâˆš2 = 3d aâˆš2 = d
a = 3d/âˆš2 a = d/âˆš2 => 3: 1
ANSWER IS D
Answer: D
Question: A male student must answer 7 out of 10 questions on an examination. If at least 3 of the first 5 questions must be answered, how many possible combinations of 7 questions are available to the student?
Options:
A)120
B)140
C)110
D)150
E)160
Rationale: as there is ONLY one possiblity of choosing 7 out of 10, while choosing less than 3 in first five
choose 2 in first 5 and all 5 from later half..
ways = 5C2 = 10..
total ways = 10C3 = 120
ans = 120-10 = 110
C
Answer: C
Question: 70 is subtracted from 30% of a number, the result is 20. Find the number?
Options:
A)150
B)997
C)266
D)300
E)271
Rationale: (30/100) * X – 70 = 20
3X = 900
X = 300
Answer:D
Answer: D
Question: Five years ago the average of the ages of A and B was 40 years and now the average of the ages of B and C is 49 years. What will be the age of the B ten years hence?
Options:
A)22
B)77
C)26
D)98
E)51
Rationale: Let the present ages of A, B and C be a, b and c respectively.
Given, [(a - 5) + (b - 5)] / 2 = 40 => a + b = 90 --- (1)
(b + c)/2 = 49 => b + c = 98 --- (2)
From (1) and (2), we cannot find b.
Answer: D
Answer: D
Question: A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 60 sq. feet, how many feet of fencing will be required?
Options:
A)34
B)40
C)68
D)88
E)26
Rationale: We have: l = 20 ft and lb = 60 sq. ft.
So, b = 3 ft.
Length of fencing = (l + 2b) = (20 + 6) ft = 26 ft.
ANSWER:E
Answer: E
Question: A bag contains 5 red balls, 5 green balls and 6 white balls. A ball is drawn at
random from the box. What is the probability that the ball drawn is either red or green?
Options:
A)2/5
B)3/5
C)1/5
D)7/15
E)5/8
Rationale: Total number of balls = (5 + 5 + 6) = 16.
Therefore, n(S) = 16.
Let E1 = event of drawing a red ball.
and E2 = event of drawing a green ball.
Then, E1 n E2 = f.
P (E1 n E2) = P(E1) + P(E2) = (5/16 + 5/16) = 5/8.
ANSWER:E
Answer: E
Question: A set S = {x, -8, -5, -1, 1, 6, 9, y} with elements arranged in increasing order. If the median and the mean of the set are the same, what is the value of |x|-|y|?
Options:
A)-1
B)Cannot be determined
C)1
D)0
E)2
Rationale: Median of the set = (-1+1)/2 = 0
As per statement, Mean of the set = 0
Mean of the set
|y|- |x| +16-14 = 0 (where x is negative n y is positive)
|y|- |x| = -2
So the absolute difference between two numbers is 2
Answer E
Answer: E
Question: Which of the following are roots of an equation (x^-2)-(2x^-1)-35=0
Options:
A)1/5 and -1/7
B)-1/5 and 1/7
C)1/5 and 1/7
D)-1/5 and -1/7
E)-5/2 and -1/7
Rationale: Given: (x^-2) - (2x^-1) - 35 = 0
Rewrite as: 1/(x²) - 2/x - 35 = 0
Remove fractions by multiplying both sides by x² to get: 1 - 2x - 35x² = 0
Rearrange to get: 35x² + 2x - 1 = 0
Factor to get: (5x + 1)(7x - 1) = 0
So, EITHER 5x + 1 OR 7x - 1 = 0
If 5x + 1 = 0, then x = -1/5
If 7x - 1 = 0, then x = 1/7
So, the roots (solutions) are -1/5 and 1/7
The answer is B.
Answer: B
Question: In an increasing sequence of 10 consecutive integers, the sum of the first 4 integers is 570. What is the sum of the last 6 integers in the sequence?
Options:
A)885
B)888
C)889
D)884
E)880
Rationale: Solution:
In solving this problem we must first remember that when we have 10 consecutive integers we can display them in terms of just 1 variable. Thus, we have the following:
Integer 1: x
Integer 2: x + 1
Integer 3: x + 2
Integer 4: x + 3
Integer 5: x + 4
Integer 6: x + 5
Integer 7: x + 6
Integer 8: x + 7
Integer 9: x + 8
Integer 10: x + 9
We are given that the sum of the first 4 integers is 570. This means that:
x + x+1 + x+2 + x+3 = 570
4x + 6 = 570
4x = 564
x = 141
The sum of the last 6 integers can be expressed and simplified as:
x+4 + x+5 + x+6+ x+7 +x+8 x+9 = 6x + 39
Substituting 141 for x yields:
(6)(141) + 39 = 885
Answer: A
Answer: A
Question: P and Q invested in a shop. The profits were divided in the ratio of 4 : 6 respectively. If P invested Rs. 55,000, the amount invested by Q is:
Options:
A)48000
B)40000
C)35000
D)60000
E)None
Rationale: Suppose Q invested Rs. y. Then, 50000/y = 4/6 or y = [50000 x 6/ 4] = 75000.
Answer E
Answer: E
Question: A vessel of capacity 2 litre has 40% of alcohol and another vessel of capacity 6 litre had 60% alcohol. The total liquid of 8 litre was poured out in a vessel of capacity 10 litre and thus the rest part of the vessel was filled with the water. What is the new concentration of Mixture?
Options:
A)31%.
B)44%.
C)49%.
D)29%.
E)51%.
Rationale: 40% of 2 litres = 0.8 litres
60% of 6 litres = 3.6 litres
Therefore, total quantity of alcohol is 4.4 litres.
This mixture is in a 10 litre vessel. Hence, the concentration of alcohol in this 10 litre vessel is 44%
B
Answer: B
Question: A textile worker’s wages are increased by 10% and afterwards decreased by 10 %. Find the change percentage in his wages.
Options:
A)2 % increase
B)4% increase
C)1% decrease
D)4% decrease
E)None of these
Rationale: Explanation:
Let workers wages = X
A 10% increase would mean new wages
= (110/100) X
A 10% decrease would mean new wages
= (90/100) (110/100 X)
= 99/100 X which means a decrease of 1 %
ANSWER: C
Answer: C
Question: Two brothers Ram and Ravi appeared for an exam. The probability of selection of Ram is 3/7 and that of Ravi is 1/5. Find the probability that both of them are selected.
Options:
A)3/35
B)2/3
C)7/35
D)5/7
E)7/5
Rationale: Let A be the event that Ram is selected and B is the event that Ravi is selected.
P(A) = 3/7
P(B) = 1/5
Let C be the event that both are selected.
P(C) = P(A) x P(B) as A and B are independent events:
= 3/7 x 1/5 = 3/35
ANSWER:A
Answer: A
Question: During the months May through October, Teddy the bear doubles his weight, and during the months November through April, Teddy loses 100 pounds. If at the beginning of November 1973, Teddy's weight was m pounds, what was Teddy's weight in pounds by the end of April 1976?
Options:
A)4m - 1300
B)9m - 1200
C)4m - 1200
D)9m - 1300
E)m - 1200
Rationale: Nov ' 73 = m
April ' 74 = m - 100
Oct ' 74 = 2m - 300
April' 75 = 2m - 400
Oct' 75 = 4m - 1200
April'76 = 4m - 1300
Hence answer will be (A) 4m - 1300
Answer: A
Question: The radius of the wheel of a bus is 35 cms and the speed of the bus is 66 km/h, then the r.p.m. (revolutions per minutes)of the wheel is
Options:
A)200
B)250
C)300
D)500
E)None of these
Rationale: Radius of the wheel of bus = 35 cm. Then,
circumference of wheel = 2Ï€r = 70Ï€ = 220 cm
Distance covered by bus in 1 minute
= 66â„60 Ã— 1000 Ã— 100 cms
Distance covered by one revolution of wheel
= circumference of wheel
= 220 cm
âˆ´ Revolutions per minute = 6600000/60Ã—220 = 500
Answer D
Answer: D
Question: When the number 2y31129 is exactly divisible by 11, then what can be the smallest whole number in place of y?
Options:
A)1
B)3
C)4
D)7
E)8
Rationale: The given number =2y31129
Sum of the odd places =9+1+3+2=15
Sum of the even places = 2+1+y
(Sum of the odd places)- (Sum of even places) = Number (exactly divisible by 11)
15-(3+y) = divisible by 11
12 � y = divisible by 11.
Y must be 1, to make given number divisible by 11.
A
Answer: A
Question: A bag contains 7 white balls, 5 black balls, and 4 red balls. One by one, three balls are drawn out without replacement. What is the probability that the third ball is red?
Options:
A)1/2
B)1/4
C)3/8
D)5/12
E)2/5
Rationale: The probability for each ball to be drawn third is equal.
Then the probability a red ball is drawn third is 4/16 = 1/4.
The answer is B.
Answer: B
Question: Man1 does a work in 10 days and Man2 does the same work in 15 days. In how many days they together will do the same work ?
Options:
A)10 days
B)5 days
C)6 days
D)7 days
E)8 days
Rationale: Man1 day work = 1/10
Man2 day work = 1/15
Both work =1/10+1/15
===>3+2/30
==>1/6
ANSWER C
Answer: C
Question: A man's regular pay is $3 per hour up to 40 hours. Overtime is twice the payment for regular time. If he was paid $186, how many hours overtime did he work?
Options:
A)8
B)5
C)9
D)6
E)11
Rationale: At $3 per hour up to 40 hours, regular pay = $3 x 40 = $120 If total pay = $168, overtime pay = $186 - $120 = $66 Overtime rate (twice regular) = 2 x $3 = $6 per hour => number of overtime hours = $66/$6 = 11
Ans is E
Answer: E
Question: Coins are stacked one on top of the other to form a column. The first column has 12 coins and subsequent columns have 2 more coins than the previous one. Find the number of columns if total number of coins is 432.
Options:
A)27
B)16
C)15
D)26
E)11
Rationale: Assume there are n columns. This forms an Arithmetic Progression with first term 12 and nth term (12+2*(n-1)). The average is (12+12+2n-2)/2 or (11+n) and total number of coins will be (11+n)*n = n2+11n-432=0 or (n+27)*(n-16)=0
n=16 or -27. Since n cannot be negative, n=16
Answer is B
Answer: B
Question: The cost per pound of green tea and coffee were the same in June. In July, the price of coffee shot up by 100% and that of green tea dropped by 70%. If in July, a mixture containing equal quantities of green tea and coffee costs $3.45 for 3lbs, how much did a pound of green tea cost in July?
Options:
A)$4
B)$0.3
C)$1
D)$3
E)$1.65
Rationale: Lets assume price of Coffee in June =100x
Price of green Tea in June =100x
Price of Coffee in July = 200x (because of 100% increase in price)
Price of green Tea in July = 30x (because of 70% Decrease in price)
Price of 1.5 pound of Coffee 1.5 pound of green Tea in July will be = 300x + 45x = 345x
As per question
345x= 3.45$
x = 0.01S
So the Price of Tea in July = 30x = 30 x 0.01 = 0.3$/pound
Answer B
Answer: B
Question: The average weight of 16 boys in a class is 50.25 kg and that of the remaining 8 boys is 45.15 kg. Find the average weights of all the boys in the class.
Options:
A)48
B)48.55
C)46
D)34.5
E)50.0
Rationale: Avg weight of 16 boys = 50.25
tot weight of 16 boys = 50.25 * 16
avg weight of remaining 8 boys = 45.15
tot weight of remaining 8 boys=45.15*8
tot weight of remaining 8 boys = 45.15 * 8
tot weight of all boys = 50.25 * 16 + 45.15*18
=24
avg weight=(50.25*16)+(45.15*8)/24=48.55
ANSWER B
Answer: B
Question: Two numbers are in the ratio of 1 : 2. If 5 be added to both, their ratio changes to 3 : 5. The greater number is
Options:
A)20
B)24
C)28
D)32
E)36
Rationale: Let the ratio be X : Y,
Given X/Y = 1/2 ,
(X + 5)/(Y + 5) = 3/5
=> X = 10
And Y = 20
ANSWER:A
Answer: A
Question: If R=30^65−29^65/3064+2964 then
Options:
A)0<R≤0.10<R≤0.1
B)0.1<R≤0.50.1<R≤0.5
C)0.5<R≤1.00.5<R≤1.0
D)R<1.0
E)R>1.0
Rationale: This question is based on your understanding of number properties. You don't have to do any calculations actually.
At higher powers, a difference of even 1 in the base creates creates a huge difference in the number. For example, 2^10=10242 but 3^10=59049.
So 30^65 will not be very different from 30^65-29^65
Similarly, 30^64 will not be very different from 30^64+29^64
So the question boils down to approx 30^65/30^64 This will be something less than 30 but certainly greater than 1.
Answer (E)
Answer: E
Question: If the seventh day of a month is three days earlier than Friday, What day will it be on the nineteenth day of the month?
Options:
A)Saturday
B)Monday
C)Sunday
D)Wednesday
E)None of these
Rationale: Explanation :
Given that seventh day of a month is three days earlier than Friday
=> Seventh day is Tuesday
=> 14th is Tuesday
=> 19th is Sunday, Answer : Option C
Answer: C
Question: The average of 6 observations is 14. A new observation is included and the new average is decreased by 1. The seventh observation is?
Options:
A)1
B)3
C)5
D)6
E)7
Rationale: Let seventh observation = X.
Then, according to the question we have
=> (84 + X) / 7 = 13
=> X = 7.
Hence, the seventh observation is 7.
ANSWER:E
Answer: E
Question: Machine A and machine E are each used to manufacture 660 sprockets. It takes machine A 10 hours longer to produce 660 sprockets than machine E. Machine E produces 10 percent more sprockets per hour than machine A. How many sprockets per hour does machine A produces?
Options:
A)6
B)6.6
C)60
D)100
E)110
Rationale: [Reveal]Spoiler:
TimeE: 660/x
TimeA: [660/x+10]
660/x = [660/x+10] *110/100
660/x =66*11/x+10
660x+10= 66*11*x
660x +6600 = 66*11*x
x= 100
plug in back to timeA
660/100+10 => 660/110 = 6
Answer: A
Question: A person was asked to subtract 25% of a number from the original but he subtracted 25 from the number. His answer was 25 more than correct one. What was the original number?
Options:
A)100
B)919
C)102
D)200
E)234
Rationale: 25 + 25 = 50
25% ------ 50
100% ----- ? => 200
Answer:D
Answer: D
Question: A no. when divided by the sum of 555 and 445 gives 2times their difference as quotient & 40 as remainder. Find the no. is?
Options:
A)220044
B)145778
C)220400
D)220014
E)220040
Rationale: (555 + 445) * 2 * 110 + 30 = 220000 + 30 = 220040
E
Answer: E
Question: John distributes his pencil among his 4 friends Rose, Mary, Ranjan, and Rohit in the ratio 1/3 : 1/3 :1/4:1/5 . What is the minimum no. of pencils that the person should have?
Options:
A)45
B)67
C)70
D)77
E)98
Rationale: Rakesh : Rahul : Ranjan : Rohit = 1 / 3 : 1 / 3 : 1 / 4 : 1 / 5
Step 1: At First we need to do is LCM of 3,3,4 and 5 is 60.
Step 2: Then pencil are distributed in ratio among friends,
Rakesh = ( 1 / 3 x 60 ) = 20.
Rahul = ( 1 / 3 x 60 ) = 20.
Ranjan = ( 1 / 4 x 60 ) = 15.
Rohit = ( 1 / 5 x 60 ) = 12.
Step 3: Total number of pencils are ( 20 x + 20 x + 15 x + 12 x) = 67 x.
For minimum number of pencils x = 1 .
The person should have atleast 67 pencils.
B)
Answer: B
Question: A large petrol tank has two inlet tubes (a large one and a small one) and one outlet tube. It takes 3 hours to fill the tank with the large inlet tube. On the other hand, it takes 6 hours to fill the tank with the small inlet tube. The outlet tube allows the full tank to be emptied in 9 hours.
What fraction of the tank (initially empty) will be filled in 0.64 hours if all three tubes are in operation? Give your answer to two decimal places (e.g., 0.25, 0.5, or 0.75).
Options:
A)1 hour
B)2 hour
C)3 hour
D)4 hour
E)5 hour
Rationale: In one hour,
Soln 1:
the large inlet tube fills 1 / 3 of the tank;
the small inlet tube fills 1 / 6 of the tank;
the outlet tube empties 1 / 9 of the tank; and therefore
all three tubes together fill [ (1 / 3) + (1 / 6) − (1 / 9) ] of the tank.
Fraction of the tank that will be filled in 0.64 hours =
0.64 [ (1 / 3) + (1 / 6) − (1 / 9) ] = 0.25.
Soln 2:
Let V be the total volume of the tank. From equation (1),
Flow Rate (large inlet tube) = V / 3
Flow Rate (small inlet tube) = V / 6
Flow Rate (outlet tube) = V / 9.
Substituting in equation (2),
Rate of Accumulation in tank = (V / 3) + (V / 6) − (V / 9).
Using the above result in equation (1),
Time required to fill the complete tank = V / [ (V / 3) + (V / 6) − (V / 9) ].
Note that V cancels out on simplifying the above expression.
Fraction of the tank that will be filled in 0.64 hours =
0.64 [ (1 / 3) + (1 / 6) − (1 / 9) ] = 0.25.
Answer: A
Question: For which of the following values of s is (20+s)/s an integer?
Options:
A)3
B)4
C)9
D)11
E)20
Rationale: This problem has to be solved by checking the options
(20 + s)/s
For this entity to be an integer, 50 + s should be divisible by s
Option A: 23/3 - Not an Integer
Option B: 24/4 - Not an Integer
Option C: 29/9 - Not an integer
Option D: 41/11 - Not an integer
Option E - 40/20 - Integer
Correct Option: E
Answer: E
Question: A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If two marbles are drawn at random, what is the probability that at least one is green?
Options:
A)23/35
B)23/32
C)23/31
D)23/30
E)63/35
Rationale: Explanation:
Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles.
Probability that at least one green marble can be picked in the random draw of two marbles = Probability that one is green + Probability that both are green
= (â¶Câ‚ * â¹Câ‚)/Â¹âµCâ‚‚ + â¶Câ‚‚/Â¹âµCâ‚‚
= (6 * 9 * 2)/(15 * 14) + (6 * 5)/(15 * 14) = 36/70 + 1/7
= 46/70 = 23/35
Answer: A
Answer: A
Question: Kamal is 60 years old and Karthi is 80 years old. How many years ago was the ratio of their ages 4 : 6?
Options:
A)20 yrs
B)30 yrs
C)25 yrs
D)40 yrs
E)15 yrs
Rationale: (60-x)/(80-x) = 4/6
6(60-x)=4(80-x)
x = 20
ANSWER A
Answer: A
Question: The average of first 9 natural numbers is?
Options:
A)1.5
B)2.5
C)3.5
D)4.5
E)5.5
Rationale: Sum of 10 natural no. = 90/2 = 45
Average = 45/10 = 4.5
ANSWER:D
Answer: D
Question: In a mixture of 60 liters, the ratio of milk and water is 2:1. What amount of water must be added to make the ratio of milk and water as 1:2?
Options:
A)60
B)277
C)299
D)66
E)221
Rationale: 2:1 --- 60
1:2
2:4
---------------
3
3 ----------- 60
3 ----------- ? => 60 liters
Answer:A
Answer: A
Question: The average age of the mother and her six children is 11 years which is reduced by 5 years if the age of the mother is excluded. How old is the mother
Options:
A)40
B)41
C)42
D)43
E)44
Rationale: Total age of mother and 6 children = avg x n = 11 x (6+1)= 77
If mother is excluded new average is (11 - 5) = 6
so for 6 children = 6 x 6 =36
so mother's age is 77 - 36 =41
Answer: Option B
Answer: B
Question: In a kilometer race, A beats B by 60 meters or 10 seconds. What time does A take to complete the race?
Options:
A)199 sec
B)156.7 sec
C)726 sec
D)127 sec
E)128 sec
Rationale: Time taken by B run 1000 meters
= (1000 * 10)/60 = 166.7 sec.
Time taken by A = 166.7 - 10
= 156.7 sec.
Answer: B
Answer: B
Question: Increasing the original price of a certain item by 30 percent and then increasing the new price by 30 percent is equivalent to increasing the original price by what percent?
Options:
A)31.25
B)37.5
C)50.0
D)52.5
E)69.0
Rationale: We're told that the original price of an item is increased by 30% and then THAT price is increased by 30%....
IF....
Starting value = $100
+ 30% = 100 + .30(100) = 130
+ 30% = 130 + .30(130) = 130 + 39 = 169
The question asks how the final price relates to the original price. This is essentially about Percentage Change, which means we should use the Percentage Change Formula:
Percentage Change = (New - Old)/Old = Difference/Original
Doing either calculation will yield the same result:
59/100 = 69%
Final Answer:
E
Answer: E
Question: Sachin borrows Rs. 5000 for 2 years at 4% p.a. simple interest. He immediately lends money to Rahul
at 25/4% p.a. for 2 years. Find the gain of one year by Sachin.
Options:
A)110.5
B)111.5
C)112.5
D)113.5
E)None of these
Rationale: Explanation:
Two things need to give attention in this question, First we need to calculate gain for 1 year only.
Gain in 2 year = [(5000×254×2100)−(5000×4×2100)]=(625−400)=225 So gain for 1 year = 2252=112.50
Answer: C
Answer: C
Question: The average age of 36 students in a group is 14 years. When teacher's age is included to it, the average increases by one. What is the teacher's age in years?
Options:
A)31
B)41
C)51
D)61
E)71
Rationale: Solution
Age of the teacher	= (37 x 15 - 36 x 14)
= 51 years.
Answer C
Answer: C
Question: In a group of 25, 13 can speak Latin, 15 can speak French, and 6 don't speak either. How many of these speak both Latin and French?
Options:
A)9
B)10
C)11
D)12
E)8
Rationale: let no.of persons who speeks booth latin and french = x
so, no.of persons who speeks only latin = 13-x
no.of persons who speeks only french= 15-x
no.of persons who speeks dont speek any lag = 6
therefore (13-x)+(15-x)+x+6=25
34-x=25
x=9
ANSWER:A
Answer: A
Question: A train traveling at 72 kmph crosses a platform in 34 seconds and a man standing on the platform in 18 seconds. What is the length of the platform in meters?
Options:
A)240 meters
B)320 meters
C)420 meters
D)600 meters
E)Cannot be determined
Rationale: Speed of train = 72 * (5/18) = 20 m/s
Lets consider the man as a stationery point on the platform.
Crossing the point gives us the length of the train.
Lt = 20 * 18 = 360 m.
Crossing the platform gives us the length of trainlength of platform.
L(t+p) = 20 * 34 = 680 m.
So, length of platform = 680 - 360 = 320 m
IMO, Answer
B
Answer: B
Question: Siddharth wants to borrow Rs.4000 at rate of interest 6% p.a. at S.I and lend the same amount at C.I at same rate of interest for two years. What would be his income in the above transaction?
Options:
A)s.21.60
B)s.21.68
C)s.21.18
D)s.14.4
E)s.21.29
Rationale: Amount of money Siddharth borrowed at S.I at 6% p.a. for two years = Rs.4,000
He lend the same amount for C.I at 6% p.a. for two years.
=> Siddharth's income = C.I - S.I
= p[1 + r/ 100]n - p - pnr/100
= p{ [1 + r/ 100]2 - 1 - nr/100
= 4,000{ [1 + 6/100]2 - 1 - 12/100}
= 4,000 {(1.06)2- 1 - 0.12} = 4,000(1.1236 - 1 - 0.12)
= 4,000 (0.0036) = 4 * 3.6
= Rs.14.4
Answer: D
Answer: D
Question: A pump can fill a tank with water in 2 hours. Because of a leak, it took 2 1/3 hours to fill the tank. The leak can drain all the water of the tank in?
Options:
A)4 1/3 hrs
B)7 hrs
C)8 hrs
D)14 hrs
E)15 hrs
Rationale: Work done by the tank in 1 hour = (1/2 - 1/3) = 1/14 Leak will empty the tank in 14 hrs.
ANSWER:D
Answer: D
Question: Find the smallest number which should be multiplied with 13225 to make it a perfect square.
Options:
A)25
B)5
C)1
D)23
E)6
Rationale: 13225 = 5*5*23*23
Required smallest number = 1
1 is the smallest number which should be multiplied with 13225 to make it a perfect square.
ANSWER:C
Answer: C
Question: If 36 men can do a piece of work in 20 hours, in how mwny hours will15 men do it?
Options:
A)22
B)48
C)60
D)88
E)72
Rationale: Explanation:
Let the required no of hours be x. Then
Less men , More hours (Indirect Proportion)
\inline \fn_jvn \therefore 15:36 ::20:x \inline \fn_jvn \Leftrightarrow (15 x X)=(36 x 20) \inline \fn_jvn \Leftrightarrow \inline \fn_jvn x=\frac{36\times 20}{15}=48
Hence, 15 men can do it in 48hours.
Answer: B)48
Answer: B