divelab/Sys2Bench huggingface dataset:
Question: How many integers between 324,700 and 458,600 have a 2 in the tens digit and a 1 in the units digit?
Options:
A)1339
B)2300
C)4200
D)1340
E)2414
Rationale: There is one number in hundred with 2 in th tens digit and 1 in the units digit: 21, 121, 221, 321, ...
The difference between 324,700 and 458,600 is 458,600-324,700=133,900 - one number per each hundred gives 133,900/100=1,339 numbers.
Answer: 1,339 A
Answer: A
Question: In business, A and C invested amounts in the ratio 4:2, whereas the ratio between amounts invested by A and B was 4:1, If Rs 20,000 was their profit, how much amount did A receive.
Options:
A)13333
B)26758
C)45896
D)14639
E)89576
Rationale: Explanation:
A:B = 4:1 = 4:1
=> A:C = 4:2 = 4:2
=> A:B:C = 4:1:2
A share = (4/6)*20000
= 13333
Option A
Answer: A
Question: The arithmetic mean and standard deviation of a certain normal distribution are 14.5 and 1.7, respectively. What value is exactly 2 standard deviations less than the mean?
Options:
A)10.5
B)11
C)11.1
D)12
E)12.5
Rationale: Mean = 14.5
Two standard deviations is 1.7 + 1.7 = 3.4
There could be two calues for this.
Mean + two standard deviations = 17.9
Mean - Two standard deviations = 11.1
Answer choice has 11.1 and so C is the answer.
Answer: C
Question: What number comes next?
482, 693, 754, 826, 937, ?
Options:
A)113
B)231
C)245
D)548
E)123
Rationale: D
548
The numbers 48269375 are being repeated in the same sequence.
Answer: D
Question: There is a certain relation between two given words on one side of : : and one word is given on another side of : : while another word is to be found from the given alternatives, having the same relation with this word as the given pair has.
Options:
A)Chauffeur
B)Steering
C)Mechanic
D)Brake
E)gren
Rationale: Explanation:
Horse is driven by a jockey .
Similarly,car is driven by a chauffeur
Answer: A)
Answer: A
Question: If B> 0 and B is divisible by the product of the first nine positive integers, all of the following must be factors of B except
Options:
A)35
B)40
C)63
D)315
E)704
Rationale: The question states taht B is divisible by 9!,which is 1*2*3*4*5*6*7*8*9
B=(9!) * some number
A. 35 = 5*7 so will divide B
B. 40 =5*8 so will divide B
C. 63 =9*7 so will divide B
D. 315 =5*7*9 so will divide B
E. 704 =8*8*11 This will not divide B
Ans E
Answer: E
Question: In one hour, a boat goes 11 km/hr along the stream and 5 km/hr against the stream. The speed of the boat in still water (in km/hr) is:
Options:
A)3 km/hr
B)2 km/hr
C)4 km/hr
D)6 km/hr
E)8 km/hr
Rationale: Speed in still water =	1/2	(11 + 5) kmph = 8 kmph.
ANSWER:E
Answer: E
Question: Anil spends 40% of his income on rent, 30% of the remaining on medicines and 20% of the remaining on education. If he saves Rs. 840 every month, then find his monthly salary?
Options:
A)2882
B)2672
C)2288
D)2500
E)1288
Rationale: Let's Anil's salary be Rs. 100.
Money spent on Rent = 40% of 100 = Rs. 40.
Money spent on medical grounds = 30% of (100 - 40) = 3/10 * 60 = Rs. 18.
Money spent on education = 20% of (60 - 18) = 1/5 * 42 = Rs. 8.40
Anil saves 100 - (40 + 18 + 8.40) i.e., Rs. 33.60
for 33.6 ---> 100 ; 840 ---> ?
Required salary = 840/33.6 * 100 = Rs. 2500
Answer: D
Answer: D
Question: 15 men take 21 days of 8 hrs. each to do a piece of work. How many days of 3 hrs. each would it take for 21 women if 3 women do as much work as 2 men?
Options:
A)60
B)20
C)19
D)29
E)39
Rationale: Let 1Man does 1unit/hr of work
15M in 21 days of 8hrs will do (15*21*8) units
3W = 2M
1W=(2/3)units/hr
21W with 3hrs a day will take (15*21*8)/(21*3*(2/3)) days
=> 60 Days
ANSWER:A
Answer: A
Question: Shopkeeper rise price by 31% and gives successive discount of 10% and 15%. What is overall % gain or loss?
Options:
A)0.215%
B)1.215%
C)3.215%
D)6.215%
E)7.215%
Rationale: Let d initial price be 100
31 % rise
now price = 131/100*100 = 131
10% discount
Then price = 131 * 90/100 = 117.9
15 % discount
Then price = 117.9 * 85/100 = 100.215
So Gain = 100.215 - 100 = 0.215
Gain % = Gain * 100 /CP
==> 0.215 * 100 /100 = 0.215%
ANSWER:A
Answer: A
Question: Jane covered a distance of 330 miles between city A and city B taking a total of 5 hours. If part of the distance was covered at 60 miles per hour speed and the balance at 80 miles per hour speed, how many hours did she travel at 60 miles per hour?
Options:
A)2 hours 30 minutes
B)3 hours
C)2 hours
D)1 hour 45 minutes
E)None of these
Rationale: Answer
Let Jane travel 'x' at 60 miles per hour.
As the total time taken to cover 340 miles is 5 hours, Jane would have traveled (5 - x) hours at 80 miles per hour.
Distance covered at 60 miles per hour = Speed * time = 60 * x = 60x miles.
Distance covered at 80 miles per hour = Speed * time = 80 (5 - x) = 400 - 80x miles.
Total distance covered = Distance covered at 60 miles per hour + Distance covered at 80 miles per hour.
Therefore, total distance = 60x + 400 - 80x.
Total distance travelled = 340 miles.
Therefore, 330 = 60x + 400 - 80x
20x = 50 or x = 2 hours 30 minutes.
Choice A
Answer: A
Question: 1^2 – 2^2 + 3^2 – 4^2 + 5^2 – 6^2 + 7^2 – 8^2 + 9^2 – 10^2=?
Options:
A)-21
B)-53
C)-35
D)-55
E)-58
Rationale: 1-4+9-16+25-36+49-64+81-100= -55
ANSWER:D
Answer: D
Question: Find 4 + 7 + 10 + 13 + 16 + . . . up to 20 terms
Options:
A)650
B)640
C)630
D)620
E)610
Rationale: a = 4
d = 7 – 4 = 3
Sum of first 20 terms, S20
ANSWER IS A
Answer: A
Question: A man invested Rs. 26000 in 5% stock at 104. He sold the stock when the price rose to Rs. 120 and invested the sale proceeds in 6% stock. By doing this his income increased by Rs. 2500. At what price did he purchase the second stock?
Options:
A)125
B)40
C)48
D)35
E)50
Rationale: Assuming that face value of the first stock = Rs.100 as it is not given in the question
Since it is a 5% stock, we can take the dividend per stock = Rs.5
Market Value of the first stock = Rs.104
Investment on the first stock = Rs.26000
Number of stocks purchases = 26000/104 = 250
His total income from all these stocks = Rs.250 × 5 = Rs.1250
He sells each of this stock at Rs.120
ie, amount he earns = Rs.120 × 250 = Rs.30000
He invest this Rs.30000 in 6% stock (here also face value is not given and hence take it as Rs.100)
His new income = Rs.(1250 + 2500) = Rs.3750
ie, By Rs.30000 of investment , he earns an income of Rs.3750
To get an income of Rs.6, investment needed = 30000×6/3750=Rs.48
This is the market value of the second stock
Answer is C.
Answer: C
Question: 55
a6
+ 2b
____
96
If a and b represent positive single digits in the correctly worked computation above, what is the value of a + 2b ?
Options:
A)2
B)7
C)9
D)11
E)12
Rationale: Adding the digits in unit's place , 5+ 6 + b = 16 (Since a and b are positive single digits )
=> b = 5
Now adding the digits in ten's place , 5+a + 2 + 1= 9 (1 has been carried over from unit's place addition)
=> a= 1
a+2b = 1+2*5
=11
Answer D
Answer: D
Question: The average weight of 29 students is 28 kg. By the admission of a new student, the average weight is reduced to 27.3 kg. The weight of the new student is
Options:
A)22 kg
B)21.6 kg
C)22.4 kg
D)21 kg
E)7 Kg
Rationale: Exp . The total weight of 29 students = 29* 28
The total weight of 30 students = 30* 27.3
Weight of the new student = ( 30*27.3 – 29*28)
= 819 - 812 = 7
Answer:E
Answer: E
Question: A can do a piece of work in 4 hours; B and C together can do it in 3 hours, which A and C together can do it in 2 hours. How long will B alone take to do it?
Options:
A)11
B)77
C)12
D)99
E)02
Rationale: A's 1 hour work = 1/4;
(B + C)'s 1 hour work = 1/3;
(A + C)'s 1 hour work = 1/2
(A + B + C)'s 1 hour work = (1/4 + 1/3) = 7/12
B's 1 hour work = (7/12 + 1/2) = 1/12
B alone will take 12 hours to do the work.
Answer: C
Answer: C
Question: Company KW is being sold, and both Company A and Company B were considering the purchase. The price of Company KW is 50% more than Company A has in assets, and this same price is also 100% more than Company B has in assets. If Companies A and B were to merge and combine their assets, the price of Company KW would be approximately what percent of these combined assets?
Options:
A)66%
B)75%
C)86%
D)116%
E)150%
Rationale: Let the price of Company A's assets be 100
Price of assets of KW is 50% more than company A's assets which is 150
Price of assets of KW is 100% more than company B's assets which means price of Company B's assets is half the price of KW = 75
A+B = 175
KW = 150
KW/(A+B)*100 = 150/175*100 = 85.7% or 86%
ANSWER:C
Answer: C
Question: A certain boxer has agreed to pay his opponent a fee of 4% of his total purse for every pound over the specified weight limit he weighs in. If the boxer pays his opponent a fee of $26,250 after weighing in seven pounds over the specified limit, what was the boxer's purse?
Options:
A)$65,625
B)$105,000
C)$150,000
D)$93,750
E)$1,050,000
Rationale: .04*7 = .28
26250/.28 = $93,750
Answer: D
Answer: D
Question: In a class of 38 students 26 play football and play 20 long tennis, if 17 play above, many play neither?
Options:
A)6
B)8
C)9
D)12
E)14
Rationale: 26 + 20 - 17 = 29
38 - 29 = 9 play neither
Answer is C
Answer: C
Question: The ratio of money with Ram and Gopal is 7 : 17 and that with Gopal and Krishan is 7: 17. If Ram has Rs. 686, Krishan has ?
Options:
A)s. 2890
B)s. 4046
C)s. 1190
D)s. 1620
E)s. 2680
Rationale: Ram : Gopal = 7 : 17 = 49 : 119
Gopal : Krishan = 7 : 17 = 119 : 289
Ram : Gopal : Krishan = 49 : 119 : 289
Ram : Krishan = 49 : 289
Thus, 49 : 289 = 686 : N
&there N = 289 x 686 / 49
= Rs. 4046
Answer :B
Answer: B
Question: The list price of an article is Rs.65. A customer pays Rs.56.16 for it. He was given two successive discounts, one of them being 10%. The other discount is?
Options:
A)2%
B)4%
C)6%
D)9%
E)2%
Rationale: 65*(90/100)*((100-x)/100) = 56.16
x = 4%
Answer:B
Answer: B
Question: A salesperson received a commission of 3 percent of the sale price for each of the first 100 machines that she sold and 4 percent of the sale price for each machine that she sold after the first 100. If the sale price of each machine was $10,000 and the salesperson received a $32,000 commission, how many machines did she sell?
Options:
A) 90
B) 110
C) 105
D) 115
E) 120
Rationale: First 100 machines = 3% commission = 0.03*100*10000 = 30000
Commission from sale of next machines = 34000 - 30000 = 4000
So 10 more machines..
Total = 110 machines
IMO B..
Answer: B
Question: An alloy weighing 60 ounces is 20 percent copper. How many ounces of copper must be added to create an alloy that is 60 percent copper?
Options:
A)40
B)50
C)60
D)70
E)80
Rationale: An alloy of 60oz which is 20% copper means there is 12 oz of gold. To get to an alloy that is 60% copper, let's use this expression: (12 + x)/(60 + x) = 0.60 with x representing the amount of pure copper that must be added to get to 60%. The expression we are using represents the new total weight of pure copper over the new total weight of the alloy and this fraction should represent 60% or 0.6. you will see that 60 is the correct answer, as 72/120=0.6
Choose C
Answer: C
Question: Foodmart customers regularly buy at least one of the following products: milk, chicken, or apples. 60% of shoppers buy milk, 50% buy chicken, and 45% buy apples. If 10% of the customers buy all 3 products, what percentage of Foodmart customers purchase exactly 2 of the products listed above?
Options:
A)5%
B)10%
C)15%
D)35%
E)30%
Rationale: The formula is
n(AUBUC) = n(A)+n(B)+n(C)-B+A-N
where B is both (it will sum of (AB), (BC), (CA)).
and A is All
and N is neither
so plugging in we get
100 = 60+50+45+10-B-0
B = 65.
exactly two = 65 - 3(10) = 35
subtracting 10% three times as this value is including in all the (AB), (BC), (CA).
Answer D
Answer: D
Question: A number when divided by 296 leaves 75 as remainder. When the same number is divided by 37, the remainder will be:
Options:
A)1
B)2
C)8
D)11
E)10
Rationale: Let x = 296q + 75
= (37 x 8q + 37 x 2) + 1
= 37 (8q + 2) + 1
Thus, when the number is divided by 37, the remainder is 1.
Answer :A
Answer: A
Question: Two cars start from the opposite places of a main road, 105 km apart. First car runs for 25 km and takes a right turn and then runs 15 km. It then turns left and then runs for another 25 km and then takes the direction back to reach the main road. In the mean time, due to minor break down the other car has run only 35 km along the main road. What would be the distance between two cars at this point?
Options:
A)65
B)38
C)20
D)28
E)21
Rationale: Answer: C) 20 km
Answer: C
Question: If N = 2^0.25 and N^b = 8, b must equal
Options:
A)3/80
B)3/5
C)12
D)5/3
E)80/3
Rationale: 25/100 = 1/4
N = 2 ^ 1/4
N^b = 2^3
(2^1/4)^b = 2^3
b =12
Answer: C
Answer: C
Question: If $400 is deposited into a savings account at an annual interest rate of 3% that compounds monthly, what is the value of the investment after 8 years?
Options:
A)574.65
B)514.23
C)508.35
D)536.87
E)235.87
Rationale: Using CI Formula:
A=P(1+r/n)^n*t
A=400(1+3/2)^2*8
A=508.35.
Option: C
Answer: C
Question: The wheel of a motorcycle, 70 cm in diameter makes 40 revolutions in every 10 seconds. What is the speed of the motorcycle in km/hr
Options:
A)30.68 km/hr
B)31.68 km/hr
C)32.68 km/hr
D)33.68 km/hr
E)None of these
Rationale: Explanation:
In this type of question, we will first calculate the distance covered in given time.
Distance covered will be, Number of revolutions * Circumference
So we will be having distance and time, from which we can calculate the speed. So let solve.
Radius of wheel = 70/2 = 35 cm
Distance covered in 40 revolutions will be
40 * Circumference =40 * 2*\pi*r =40∗2∗22/7∗35=8800cm
=8800/100m=88m
Distance covered in 1 sec =88/10=8.8m
Speed=8.8m/s=8.8∗18/5=31.68km/hr
Option B
Answer: B
Question: What is the absolute value of twice the difference of the roots of the equation J= 5y^2 − 20y + 15 = 0 ?
Options:
A) 0
B) 1
C) 2
D) 3
E) 4
Rationale: J=5y^2 − 20y + 15 = 0 --> y^2 − 4y + 3 = 0 --> y=1 or y=3. The difference is 2, twice the difference is 4.
Answer: E.
Answer: E
Question: Yesterday's closing prices of 2,420 different stocks listed on a certain stock exchange were all different from today's closing prices. The number of stocks that closed at a higher price today than yesterday was 20 percent greater than the number that closed at a lower price. How many of the stocks closed at a higher price today than yesterday?
Options:
A)484
B)726
C)1,100
D)1,320
E)1,694
Rationale: Lets consider the below -
The number of stocks that closed at a higher price = H
The number of stocks that closed at a lower price = L
We understand from first statement -> H+L = 2420 ----(1)
We understand from second statement -> H = (120/100)L => H = 1.2L ----(2)
Solve eq (1) & (2) to get H = 1320.
D is answer.
Answer: D
Question: 10 is 6% of a, and 6 is 10% of b. c equals b/a. What is the value of c?
Options:
A)3/10
B)6/17
C)9/25
D)10/33
E)12/35
Rationale: 6a/100 = 10
a = 500/3
b/10 = 6
b = 60
c = b/a = 60*3/ 500 = 9/25
The answer is C.
Answer: C
Question: At what time between 7 and 8 o'clock will the hands of a clock be in the same straight line but,not together?
Options:
A)(5 + 5/11 )min past 5
B)(5 + 5/11 )min past 7
C)(5 + 5/11 )min past -0
D)(5 + 7/11 )min past 7
E)(5 + 5/71 )min past 7
Rationale: Explanation:
When the hands of the clock are in the same straight line but not together, they are 30 minute spaces apart.
At 7 o'clock, they are 25 min. spaces apart.
Minute hand will have to gain only 5 min. spaces.
55 min. spaces are gained in 60 min.
5 min spaces are gained in min = min
so, Required time = min past 7
Answer: B)
Answer: B
Question: Valentine day 14 Feb. 2005 was celebrated by Anand and shilpa on Tuesday. They were very happy. What day of the week would come on 14 Feb. 2010?
Options:
A)monday
B)tuesday
C)sunday
D)wednesday
E)thursday
Rationale: feb 14 2005 - tuesday
feb 14 2006 - wednesday
feb 14 2007 - thursday
feb 14 2008 - friday
feb 14 2009 - sunday[since 2008 is leap year , 2 days ll go forward]
feb 14 2010 - monday
ANSWER:A
Answer: A
Question: A certain characteristic in a large population has a distribution that is symmetric about the mean m. 84 percent of the distribution lies within one standard deviation d of the mean. If the shelf’s average life is 9.2 years and the standard deviation is 3.5 years, what percent of the distribution has more than 12.7 years as a shelf’s average life?
Options:
A)18%
B)19%
C)20%
D)21%
E)22%
Rationale: Average = 9.2
SD = 3.5
9.2 - 3.5 < 84% of distribution < 9.2 + 3.5
5.7 < 84% of distribution < 12.7
42% is outside this range.
Given: Distribution is symmetric. So 21% of distribution is less than 5.7 and the other 21% of distribution is greater than 5.7.
Answer: D
Answer: D
Question: If 20 men can build a wall 66 meters long in 6 days, what length of a similar can be built by 86 men in 8 days?
Options:
A)49
B)39
C)29
D)19
E)None of them
Rationale: Let the required length be x meters
More men, More length built (Direct Proportion)
Less days, Less length built (Direct Proportion)
Men 20: 35
Days 6: 3 : : 56 : x
Therefore (20 x 6 x x)=(35 x 3 x 56)= x=(35 x 3 x 56)/120=49
Hence, the required length is 49 m.
Answer is A.
Answer: A
Question: In a tournament, there are n teams T1 , T2 ....., Tn with n > 5. Each team consists of k players, k > 3. The following pairs of teams have one player in common: T1 & T2 , T2 & T3 ,......, Tn − 1 & Tn , and Tn & T1. No other pair of teams has any player in common. How many players are participating in the tournament, considering all the n teams together?
Options:
A)n(k-1)
B)k(n-1)
C)n(k-2)
D)k(n-2)
E)(n-1)(k-1)
Rationale: Explanation :
Let T1 - T6 be the number of teams, and let 1,2,3,4,5,6….be the players in the teams.
Total players if there are no repetition is 6*4 here. Generally, it is n * k. (n = number of teams, k = player/team). However, we see that, in each team, 1 player is repeated. i.e.
T1 & T2 have 4 in common (So 1 can be subtracted)
T2 & T3 have 7 in common (So 1 can be subtracted)
T3 & T4 have 10 in common (So 1 can be subtracted)
T4 & T5 have 13 in common (So 1 can be subtracted)
T5 & T6 have 16 in common (So 1 can be subtracted)
T6 & T1 have 1 in common (So 1 can be subtracted)
So, totally from each column 1 can be subtracted.
There are “n” columns totally, so n can be subtracted ( Here 6 needs to be subtracted)
So, here we have 6 * 4 – 6 players. Generally we have n * k – n i.e n(k-1) players.
Answer : A
Answer: A
Question: From the sale of sleeping bags, a retailer made a gross profit of 13% of the wholesale cost. If each sleeping bag was sold for $28, what was the wholesale cost per bag?
Options:
A)3.0
B)3.36
C)24.78
D)25.0
E)31.36
Rationale: Cost price * 1.13 = Selling price --> Cost price * 1.13 = $28 --> Cost price = $24.78.
Answer: C.
Answer: C
Question: A furniture store owner decided to drop the price of her recliners by 20% to spur business. By the end of the week she had sold 70% more recliners. What is the percentage increase of the gross?
Options:
A)10%
B)15%
C)20%
D)36%
E)50%
Rationale: Say a recliner is actually worth $100
If she sells 100 recliners then she earns $10000
After the discount of 20%, she will earn $80 per recliner and she sells 70% more ie.,170 recliners
Hence her sales tields 170*80=$13600
Increase in sales=13600-10000=$3600
So% increase = 3600*100/10000 =36%
D is the answer
Answer: D
Question: A sum of money is divided among A, B, C & D in the ratio 3:5:8:9 respectively. If the share of D Rs.1872 more than the share of A, then what is the total amount of money of B & C together?
Options:
A)3456
B)4056
C)4156
D)4567
E)6532
Rationale: Sol. Share of B + C = -3 x (5 + 8) = Rs. 4056
B
Answer: B
Question: Two trains, one from P to Q and the other from Q to P, start simultaneously. After they meet, the trains reach their destinations after 4 hours and 16 hours respectively. The ratio of their speeds is
Options:
A)4:1
B)4:2
C)4:5
D)4:3
E)4:6
Rationale: Ratio of their speeds = Speed of first train : Speed of second train
= √16−−√4
= 4:2
Answer is B.
Answer: B
Question: Each day a man meets his wife at the train station after work, and then she drives him home. She always arrives exactly on time to pick him up. One day he catches an earlier train and arrives at the station an hour early. He immediately begins walking home along the same route the wife drives. Eventually his wife sees him on her way to the station and drives him the rest of the way home. When they arrive home the man notices that they arrived 40 minutes earlier than usual. How much time did the man spend walking?
Options:
A)45 minutes
B)50 minutes
C)40 minutes
D)55 minutes
E)35 minutes
Rationale: As they arrived 40 minutes earlier than usual, they saved 40 minutes on round trip from home to station (home-station-home) --> 20 minutes in each direction (home-station) --> wife meets husband 20 minutes earlier the usual meeting time --> husband arrived an hour earlier the usual meeting time, so he must have spent waking the rest of the time before their meeting, which is hour-20 minutes=40minutes.
Answer: C
Answer: C
Question: Difficulty:
There are five sales agents in a certain real estate office. One month Andy sold five as many properties as Ellen, Bob sold 3 more than Ellen, Cary sold five times as many as Bob, and Dora sold as many as Bob and Ellen together. Who sold the most properties that month?
Options:
A)Andy
B)Bob
C)Cary
D)Dora
E)Ellen
Rationale: a= 5e
b =3 +e
c = 5b = 15+ 5e (highest of all)
d = b + e = 3+ e +e = 3 + 2e
Ans. C
Answer: C
Question: A man can row his boat with the stream at 18 km/h and against the stream in 8 km/h. The man's rate is?
Options:
A)5 kmph
B)2 kmph
C)7 kmph
D)8 kmph
E)3 kmph
Rationale: DS = 18
US = 8
S = ?
S = (18 - 8)/2 = 5 kmph
Answer:A
Answer: A
Question: In how many ways can be 4 boys and 4 girls sit around circular table so that no two boys sit next to each other?
Options:
A)(5!)^2
B)(6!)^2
C)3!4!
D)11!
E)(5!)^2*6!
Rationale: first fix one boy and place other 3 in alt seats so total ways is 3!
now place each girl between a pair of boys... total ways of seating arrangement of girls 4!
total is 4!*3!
ANS C
Answer: C
Question: In a bag, there are three 6-sided dice (numbered 1 to 6), three 12-sided dice (numbered 1 to 12), and two 20-sided dice (numbered 1 to 20). If four of these dice are selected at random from the bag, and then the four are rolled and we find the sum of numbers showing on the four dice, how many different possible totals are there for this sum?
Options:
A)60
B)61
C)64
D)84
E)960
Rationale: As 'complex-looking' as this question might appear, it's actually rather simple. Pay careful attention to what the specific questions asks for - the number of DIFFERENT possible SUMS from 4 dice. Since we're dealing with some 'special' dice (some 12-sided and 20-sided dice), we have to adjust out math accordingly, but the possibilities are rather limited:
1) The minimum number on any given die is 1
2) The maximum possible sum would only occur if we took the 4 biggest possible dice and rolled the highest possible number on each.
With 4 dice, we could end up with any SUM between:
4 (if we rolled 1s on all 4 dice)
to
64 (if we rolled two 20s on the 20-sided dice and two 12s on the 12-sided dice).
Thus, there are only 61 possible sums.
B
Answer: B
Question: If the population of a certain country increases at the rate of one person every 15 seconds, by how many persons does the population increase in 40 minutes?
Options:
A)80
B)100
C)160
D)240
E)300
Rationale: Since the population increases at the rate of 1 person every 15 seconds, it increases by 4 people every 60 seconds, that is, by 4 people every minute. Thus, in 40 minutes the population increases by 40 x 4 = 160 people.
Answer. C.
Answer: C
Question: In what time will Rs.4000 lent at 3% per annum on simple interest earn as much interest as Rs.5000 will earn in 5 years at 4% per annum on simple interest?
Options:
A)5 years
B)6 years
C)7 years
D)9 years
E)15 years
Rationale: (4000*T*5)/100 = (5000*5*4)/100
T = 5 years
ANSWER:A
Answer: A
Question: Replace X with the appropriate number in
1 , 2 , 3 , 4 , 7 , 10 , 11 , X
Options:
A)12
B)13
C)15
D)16
E)18
Rationale: A
list of consecutive numbers that does not contain a 'i' in the spelling
Answer: A