divelab/Sys2Bench huggingface dataset:
Question: If w, z and r are positive integers greater than 1, and p and q are factors of r, which of the following must be the factor of r^(wz)?
I. w+z
II. z^w
III. w^2 * z^2
Options:
A)I only
B)II only
C)III only
D)I and II
E)II and III
Rationale: given that p and q are factors of r.
so we can picture it this way r=w*z*n (n-some another factor of r)
so, r^wz= (w*z*n)^wz
I. w+z .since the question is MUST BE TRUE, we eleminate this option
II. (w*z*n)^wz / z^w= integer YES!
III.(w*z*n)^wz/ w^2 * z^2 YEs, since we are said that integer w>1 and integer z>1
Answer: E
Question: Simran started a software business by investing Rs.50,000. After six months, Nanda joined her with a capital of Rs.80,000. After 3 years , they earned a profit of Rs.24,500. What was Simran's share in the profit?
Options:
A)Rs.9423
B)Rs.10,250
C)Rs.10,500
D)Rs.14,000
E)None
Rationale: Solution
Simran : Nanda	=(5000x36):(80000x30)
= 3 : 4.
Simran's share	= Rs.(24500x3/7)
= Rs.10,500.
Answer C
Answer: C
Question: Danny drove his old car 100 kilometers, from his home to a friend. To prevent the engine from overheating, he stopped his car for 9 minutes every time he completed 40 kilometers of continuous driving. When the car was moving, Danny drove it at an average speed of 60 kilometers per hour. What was Danny's average speed on that trip?
Options:
A)37.5 kilometers per hour
B)48 kilometers per hour
C)50.8 kilometers per hour
D)75 kilometers per hour
E)100 kilometers per hour
Rationale: Time taken to reach first 40 km is 40/60 = 2/3 hr
Time taken to reach next 40 km is 40/60 = 2/3 hr
Time taken to reach next 20 km is 20/60 = 1/3 hr
Danny stopped twice on his way at 40 km from starting point and at 80km from the starting point...
Each stop was of 9 min , so two 9 min break = 2*3/20 => 3/10 hr
Total time taken to reach 100 km is (2/3 + 2/3 + 1/3+3/10 ) = 59/30 hrs
So, Average speed is 100/(59/30) = 50.8km/hour
Answer will be (C)
Answer: C
Question: If 12 men and 16 boys can do a piece of work in 5 days and 13 men together will 24 boys can do it in 4 days. Compare the daily work done by a man with that of a boy.
Options:
A)2:7
B)2:1
C)2:4
D)2:2
E)2:8
Rationale: 12M + 16B ----- 5 days
13M + 24B ------- 4 days
60M + 80B = 52M + 96B
8M = 16B => 1M = 2B
M: B = 2:1
Answer:B
Answer: B
Question: The number 95 can be written as the sum of the squares of 4 different positive integers in two ways. Of the following, which can be the sum of these 4 integers
Options:
A)9
B)10
C)15
D)18
E)17
Rationale: The only possible sum for 4 different squares of an integer with total sum number is 95 are :
49 + 36 + 9 + 1 = 95 which are the square from numbers : 7, 6, 3, 1 (total sum number is 17)
or
81 + 9 + 4 + 1 = 95 which are the square from numbers : 9, 3, 2, 1 (total sum number is 15)
hence the answer is (E)
Answer: E
Question: Three business people who wish to invest in a new company. Each person is willing to pay one third of the total investment. . After careful calculation, they realize that each of them would pay $ 7500 less if they could find two more equal investors. How much is the total investment in the new business.
Options:
A)a)	$ 64,000
B)b)	$ 56,250
C)c)	$ 21,000
D)d)	$ 5,400
E)e)	$3,600
Rationale: Initially each invest in x. Hence total investment is 3x.
Total investment is also 5(x-7500).
3x = 5(x-7500)
x= 5*7500/2 = 18750
3x = 56250 and the answer is B.
Answer: B
Question: A certain sum becomes Rs. 20720 in four years and 24080 in six years at simple interest. Find sum and rate of interest?
Options:
A)Rs. 12000; 12% p.a.
B)Rs. 22000; 12% p.a.
C)Rs. 12000; 22% p.a.
D)Rs. 12000; 14% p.a.
E)Rs. 12000; 16% p.a.
Rationale: Let the interest for one year be x.
As amount = Principal + Interest, we have
P + 4x = 20720 --- (1) ; P + 6x = 24080 --- (2)
Solving the equations (1) and (2), we can get
P = Rs. 14000 and x = Rs. 1680
Interest for one year on Rs. 14000 is Rs. 1680
So, R = (100 * 1680)/(14000 * 1) = 12% p.a.
ANSWER:A
Answer: A
Question: Oil cans x and y are right circular cylinders and the height and radius of y are each 5 times those of x. If the oil in can x filled to capacity sells for $1, how much does the oil in y sell for if y is only 1/5th filled?
Options:
A)$25
B)$26
C)$27
D)$28
E)$30
Rationale: formula for vol of a cyl is PI*r^2*h
so Vy = 125*Vy
y when half filled will cost 25 times x so ans is A
Answer: A
Question: If a and b are integers and (2^a)(3^b) is a factor of 300^40, what is the largest possible value of ab?
Options:
A)a
B)5a
C)20a
D)40a
E)80a
Rationale: (2^a)(3^b) is a factor of 300^40
We need to find the largest possible value of ab.
We know that 300 = 2^2*5^2*3
Therefore 300^40 will have only one power of 3 in it.
Hence in (2^a)(3^b), b has to be 1
Therefore value of ab = a
Correct Option: A
Answer: A
Question: A rectangular grass field is 75 m * 55 m, it has a path of 2.5 m wide all round it on the outside. Find the area of the path and the cost of constructing it at Rs.3 per sq m?
Options:
A)675, Rs.2025
B)575, Rs.1350
C)1350, Rs.675
D)1450, Rs.775
E)1550, Rs.875
Rationale: Area = (l + b +2d) 2d
= (75 + 55 +2.5 * 2) 2*2.5 => 675
675 * 3 = Rs.2025
ANSWER:A
Answer: A
Question: The triplicate ratio of 1:2 is?
Options:
A)1:0
B)1:8
C)1:7
D)1:2
E)1:1
Rationale: 13: 23 = 1:8
Answer: B
Answer: B
Question: What two-digit number is less than the sum of the square of its digits by 11 and exceeds their doubled product by 4?
Options:
A) 95
B) 99
C) 26
D) 73
E) None of the Above
Rationale: Let the digits be x and y. The number would be 10x + y.
We are given that 2xy + 4 = 10x +y = x^2 y^2 -11
Thus 2xy +4 = x^2 + y^2 - 11
x^2 + y^2 -2xy = 16
(x-y)^2 = 16
(x-y) = 4 or -4
Substituting the values of (x-y) in the equation 2xy +5 = 10x + y
x comes out to be 1 or 9... thus the two numbers can be 26 or 98
Thus the answer is C
Answer: C
Question: Jolene entered an 16-month investment contract that guarantees to pay 2 percent interest at the end of 6 months, another 3 percent interest at the end of 12 months, and 4 percent interest at the end of the 18 month contract. If each interest payment is reinvested in the contract, and Jolene invested $10,000 initially, what will be the total amount of interest paid during the 18-month contract?
Options:
A)$506.00
B)$726.24
C)$900.00
D)$920.24
E)$926.24
Rationale: If interest were not compounded in every six months (so if interest were not earned on interest) then we would have (2+3+4)=9% simple interest earned on $10,000, which is $900. So, you can rule out A, B and C right away.
Interest earned after the first time interval: $10,000*2%=$200;
Interest earned after the second time interval: ($10,000+$200)*3%=$300+$6=$306;
Interest earned after the third time interval: ($10,000+$200+$306)*4%=$400+$8+(~$12)=~$420;
Total: 200+306+(~420)=~$920.24
Answer: D.
Answer: D
Question: The probability that a brand A widget is defective is x, the probability that a brand B widget is defective is 0.05, and the probability that a brand C widget is defective is 0.08. There are 40 brand A widgets, 35 brand B widgets, 25 brand C widgets, and nothing else in a container. If a widget is selected at random from the container, the probability that the widget selected is defective is 0.053. What is the value of x?
Options:
A)0.03875
B)0.04
C)0.05
D)0.6
E)0.039
Rationale: Given probability of defective items in each brand,
So, the number of items defective in brand A=x*40, in brand B=0.05*35 and brand C=0.08*25
Total number of widgets=40+35+25=100
the probability that the widget selected is defective is 0.053=(x*40+0.05*35+0.08*25)/100
=> 40x+1.75+2=5.3
=>40x=1.55
>x=1.55/40=0.03875
Ans A.
Answer: A
Question: The present worth of Rs. 242 due in 2 years at 10% per annum compound interest is:
Options:
A)Rs. 200
B)Rs. 250
C)Rs. 240
D)Rs. 220
E)Rs. 230
Rationale: Explanation:
Present worth of Rs. x due T years hence is given by
Present Worth (PW) = x/(1+R/100)T
Present Worth (PW) = 242/(1+10/100)2 = 242/(11/10)2 = Rs. 200
Answer: Option A
Answer: A
Question: A and B together can do a piece of work in 20days. A having worked for 10days, B finishes the remaining work alone in 30days. In how many days shall B finish the whole work?
Options:
A)25
B)40
C)50
D)30
E)60
Rationale: Let A's 1day work = x
B's 1day work = y
x+y = 1/20
10x+30y = 1
x = 1/40
y = 1/40
B's 1 day work = 1/40
B alone can finish the job in 40 days
Answer is B
Answer: B
Question: One out of every 500 light bulbs are defected. If 4 out of every 10 defected light bulbs have a broken glass and there are 20 broken glass light bulbs in the shipment, how many light bulbs total are there in the shipment?
Options:
A)2,000
B)5,000
C)10,000
D)25,000
E)52,000
Rationale: out of 500 only 1 bulb is defective.So for 10 defective bulbs, we must have 5000 bulbs
Now out of these 10 bulbs, 4 bulbs, have broken glass
i.e 4 broken glass out of 5000 bulbs
20 broken glass will be from 25000 bulbs
Answer is D
Answer: D
Question: A 6% stock yields 9%. The market value of the stock is:
Options:
A)Rs 66.55
B)Rs 68.55
C)Rs 69.55
D)Rs 65.55
E)Rs 66.66
Rationale: Explanation:
For an income of Rs. 9, investment = Rs. 100.
For an income of Rs 6, investment =Rs.100/9 X6 =Rs 66.66
Market value of Rs. 100 stock = Rs. 66.66
Answer is E
Answer: E
Question: A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Options:
A)277
B)266
C)288
D)150
E)332
Rationale: Speed=(60 * 5/18) m/sec = (50/3) m/sec Length of the train = (Speed x Time) = (50/3 * 9) m
= 150 m
.
Answer: D
Answer: D
Question: If the cost price of 24 articles is equal to the selling price of 16 articles, What is the percentage of profit or loss that the merchant makes?
Options:
A)20% loss
B)50% profit
C)33.33 % loss
D)30.33% loss
E)None of these
Rationale: Explanation :
Let Cost price of 1 article be Re.1.
Therefore, Cost price of 24 articles = Rs. 24.
Selling price of 16 articles = Rs. 24
Therefore, Selling price of 24 articles is :-
=>24/16Ã—24
=>36.
Therefore, Profit = Selling price - Cost price.
=>36âˆ’24=12.
Hence, the percentage of profit = profit x 100/C.P.
=>12/24Ã—100.
=>50% Profit.
Answer : B
Answer: B
Question: The sum of two whole no. is 64.from the following which can not be the ratio of these no.
Options:
A)5:3
B)7:1
C)3:4
D)3:5
E)all above
Rationale: Answer:	the addition of ratio no. should be factor of 64.so,3:4 can't be the ratio
answer C
Answer: C
Question: A credit card company has a cash back option for their customers which is based on the annual amount that they charge on their credit cards. The customer receives 1.5% cash on their first $5000 of purchase, 2.5% on the next $5000 of purchase and a 3% on cash back on portion that exceeds $10,000. If a customer receives a cash back of 2.8% on their total annual charges made on the credit card, then what was the customer's annual charge?
Options:
A)$40,000
B)$45,000
C)$50,000
D)$55,000
E)$60,000
Rationale: The customer receives $75 for the first $5000.
The customer receives $125 for the next $5000.
Let x be the total amount of the customer's annual charge.
$200 + 0.03(x-10,000)=0.028x
0.002x=100
x=50,000
The answer is C.
Answer: C
Question: ((-1.9)(0.6) – (2.6)(1.2))/3.0 = ?
Options:
A)0.71
B)1.0
C)1.07
D)-1.42
E)2.71
Rationale: Dove straight into calculation but quickly realized that the sum of two negatives is a negative so there is only one option.
-1.42
Answer D
Answer: D
Question: Two positive integers differ by 4, and sum of their reciprocals is 5 Then one of the numbers is
Options:
A)a) 3
B)b) 1
C)c) 5
D)d) 21
E)4
Rationale: Algebraic approach:
Let n be the smaller integer => 1/n + 1/(n+4) = 5
or ((n+4)+n)/n(n+4) =6 or (n^2+4n)*5 =2n+4 or n=2 as n cannot be -negative
Solve for n => n=4. Hence,
E
Answer: E
Question: Find the odd man out. 12, 24, 34, 48, 64, 84
Options:
A)48
B)34
C)24
D)12
E)64
Rationale: Explanation :
All numbers except 34 are multiples of 4
Answer : Option B
Answer: B
Question: There are two examinations rooms A and B. If 10 students are sent from A to B, then the number of students in each room is the same. If 20 candidates are sent from B to A, then the number of students in A is double the number of students in B. The number of students in room A is:
Options:
A)20
B)80
C)100
D)200
E)none
Rationale: Let the number of students in rooms A and B be x and y respectively.
Then, x - 10 = y + 10 x - y = 20 .... (i)
and x + 20 = 2(y - 20) x - 2y = -60 .... (ii)
Solving (i) and (ii) we get: x = 100 , y = 80.
The required answer A = 100.
Answer = C
Answer: C
Question: In one day, Juan sends Keith five times as many messages as he sends Laurence, and Laurence sends Missy 4.5 times as many messages as he receives from Juan. If Missy received 18 messages from Laurence, how many messages does Keith receive from Juan?
Options:
A)3
B)12
C)16
D)18
E)20
Rationale: Juan --> Laurence = x messages;
Juan --> Keith = 5x messages (Juan sends Keith five times as many messages as he sends Laurence);
Laurence --> Missy = 4.5x =18 (Laurence sends Missy 4.5 times as many messages as he receives from Juan).
4.5x =18 --> x = 4 --> 5x = 20.
Answer: E.
Answer: E
Question: A train travels from Albany to Syracuse, a distance of 120 miles, at the average rate of 30 miles per hour. The train then travels back to Albany from Syracuse. The total travelling time of the train is 6 hours . What was the average rate of speed of the train on the return trip to Albany?
Options:
A)31
B)38
C)60
D)50
E)40
Rationale: 30*T =120 THEREFORE T = 120/30 =4
ON RETURN SPEED * ( 6 -4) =120 THEREFORE T = 120/2 =60
C
Answer: C
Question: Andrew travelling to 7 cities. Gasoline prices varied from city to city. $1.75, $1.61, $1.79, $2.11, $1.96, $2.09, $1.86. What is the median gasoline price?
Options:
A)$1
B)$1.86
C)$1.92
D)$2.13
E)$2.15
Rationale: Ordering the data from least to greatest, we get:
$1.61, $1.75, $1.79, $1.86, $1.96, $2.09, $2.11
The median gasoline price is $1.86. (There were 3 states with higher gasoline prices and 3 with lower prices.)
B
Answer: B
Question: Julie wants to play chess with her friends. She have 6 friends. What are the possible ways to select friends to play with her?
Options:
A)10
B)3
C)6
D)2
E)11
Rationale: Julie want to play chess. So she need only one friend but there 6 friends.
That is she have to select 1 out of 6
6C1=6
6 possible ways to select her friends to play with julie(herself)
Answer is option C
Answer: C
Question: Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the game remainder in each case. Then sum of the digits in N is :
Options:
A)4
B)5
C)6
D)8
E)9
Rationale: Solution
N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305)
= H.C.F. of 3360, 2240 and 5600 = 1120.
Sum of digits in N = (1 + 1 + 2 + 0) = 4. Answer A
Answer: A
Question: How many seconds will a 600 m long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
Options:
A)22
B)36
C)99
D)77
E)12
Rationale: Speed of train relative to man = 63 - 3 = 60 km/hr.
= 60 * 5/18 = 50/3 m/sec.
Time taken to pass the man = 600 * 3/50 = 36 sec.
Answer: B
Answer: B
Question: If Jake loses 33 pounds, he will weigh twice as much as his sister. Together they now weigh 153 pounds. What is Jake's present weight, in pounds?
Options:
A) 131
B) 135
C) 113
D) 147
E) 188
Rationale: J = Jake’s current weight, in pounds
S = Sister’s current weight, in pounds
We are told that “If Jake loses 8 pounds, he will weigh twice as much as his sister.We put this into an equation:
J – 33 = 2S
J = 2S + 33 (Equation 1)
Next, we are told that “Together they now weigh 153 pounds.” We can also put this into an equation.
J + S = 153 (Equation 2)
To solve this equation, we can substitute 2S + 8 from Equation 1 for the variable J in Equation 2:
2S + 33 = 153-S
3S = 120
S = 40
J + 40 = 153
J = 113
Answer: C
Answer: C
Question: If A : B : C = 2 : 3 : 4, then A⁄B : B⁄C : C⁄A is equal to :
Options:
A)4 : 9 : 16
B)8 : 9 : 12
C)8 : 9 : 16
D)8 : 9 : 24
E)None
Rationale: Let A = 2x, B = 3x and C = 4x. Then,
A⁄B = 2x⁄3x = 2⁄3, B⁄C = 3x⁄4x = 3⁄4 and C⁄A = 4x⁄2x = 2⁄1
⇒ A⁄B : B⁄C : C⁄A = 2⁄3 : 3⁄4 : 2⁄1 = 8 : 9 : 24
Answer D
Answer: D
Question: In a division sum, the divisor is 5 times the quotient and two times the remainder. If the remainder is 40, then the dividend is
Options:
A)1320
B)1380
C)1395
D)1367
E)None of these
Rationale: Explanation:
Dividend = (Divisor x Quotient) + Remainder
Remainder = 40
Divisor = 5Q = 2R = 2 x 40 = 80
=> Q = (80/5) = 16
Now, Dividend = (80 x 16) + 40 = 1320
Answer: Option A
Answer: A
Question: If 200!/10^n is an integer, what is the largest possible value of n?
Options:
A)40
B)42
C)44
D)48
E)49
Rationale: We have to basically count the number of 5s withing 200
200/5 =40
200/5^2=8
200/5^3=1
We know for sure that there will be at least 49 even numbers(multiples of 2)within 200
So there are 49 10s in 200!
ANSWER:E
Answer: E
Question: Sandy bought 65 books for $1480 from one shop and 55 books for $920 from another shop. What is the average price that Sandy paid per book?
Options:
A)$38
B)$18
C)$99
D)$27
E)$20
Rationale: average price per book = (1480 + 920) / (65 + 55) = 2400 / 120 = $20
The answer is E.
Answer: E
Question: If x^2+(1/x^2)=5, x^4+(1/x^4)=?
Options:
A)10
B)11
C)23
D)14
E)15
Rationale: -> x^4+(1/x^4)=(x^2)^2+(1/x^2)^2=(x^2+1/x^2)^2-2x^2(1/x^2)=5^2-2=23.
Thus, the answer is C.
Answer: C
Question: The area of a circular field is 13.86 hectares. Find the cost of fencing it at the rate of Rs. 4.90 per metre.
Options:
A)2399
B)3888
C)2999
D)5808
E)6468
Rationale: Explanation:
Area = (13.86 x 10000) sq.m = 138600 sq.m
Circumference =
Cost of fencing = Rs. (1320 x 4.90) = Rs. 6468.
Answer: E) 6468
Answer: E
Question: In a drawer of shirts 8 are blue, 6 are green and 4 are magenta. If Mason draws 2 shirts at random, what is the probability T at least one of the shirts he draws will be blue?
Options:
A)25/153
B)28/153
C)5/17
D)4/9
E)T=12/17
Rationale: P(at least one blue) = 1- P(0 blue) = 1 - 10/18*9/17 =T= 12/17.
Answer: E.
Answer: E
Question: At 12:00 a.m., Tom begins traveling on a certain bike path from Riverdale at a constant rate of 10 mph. If, at 4:00 p.m., Jim begins traveling from Riverdale on the same path at a constant rate of 20 mph, at what time will he catch up to Peter?
Options:
A)5:00 p.m.
B)6:00 p.m.
C)7:00 p.m.
D)8:00 p.m.
E)9:00 p.m.
Rationale: By the time Jim starts, Tom has already covered = 4 hr * 10 mph = 40 miles
Relative speed = 20- 10 = 10mph
To catch up, Jim needs to cover 40 miles which can be covered in = 40/10= 4 hours
If Jim leaves at 4 pm, he will catch Tom at 8 pm
Answer: D
Answer: D
Question: The perimeter of a triangle is 48 cm and the inradius of the triangle is 2.5 cm. What is the area of the triangle?
Options:
A)87 cm2
B)28 cm2
C)98 cm2
D)26 cm2
E)60 cm2
Rationale: Area of a triangle = r * s
Where r is the inradius and s is the semi perimeter of the triangle.
Area of triangle
= 2.5 * 48/2
= 60 cm2
Answer:E
Answer: E
Question: When 8% of a number is added to the number itself the result is 810. What is the number?
Options:
A)750
B)758
C)288
D)270
E)712
Rationale: Explanation:
No explanation is available for this question!
ANSWER: A
Answer: A
Question: John bought 2 shares and sold them for $95 each. If he had a profit of 20% on the sale of one of the shares but a loss of 20% on the sale of the other share, then on the sale of both shares John had
Options:
A) a profit of $10
B) a profit of $8
C) a loss of $8
D) a loss of $10
E) neither a profit nor a loss
Rationale: $ Profit of the share sold at 20% profit =
120-95
20-?
$15 profit on the sale of 1 share.
$ Loss of the share sold at 20% loss=
80-95
20-?
$25 loss on the sale of 1 share.
15-25=Loss of $10
Answer: D
Answer: D
Question: The salary of Mr. X is 30% more than that of Mr. Y . Find what percent of Mr. Y’s salary is less than Mr. X’s?
Options:
A)23 1/6%
B)23 9/3%
C)23 1/3%
D)28 1/3%
E)21 1/3%
Rationale: y=100	x=130
130---------30
100---------? => 23 1/3%
Answer: C
Answer: C
Question: The 7th grade French and Spanish classes each have 26 students in them, and there are nine students in the 7th grade taking both languages. If everyone in the 7th grade is in at least one of the two language classes, how many students are taking just one of the two classes?
Options:
A)26
B)28
C)30
D)32
E)34
Rationale: French class + Spanish class = 52 students.
Nine students are in both classes so they were counted twice.
The number of students taking just one class is 52 - 2(9) = 34.
The answer is E.
Answer: E
Question: A fair coin is to be tossed twice and an integer is to be selected at random from one of the integers 3, 8, and 10. What is the probability that at least one head is tossed and an even integer is selected?
Options:
A)1/6
B)1/4
C)1/3
D)1/2
E)7/12
Rationale: 1) Let us simply state the possibilities. This method works for this problem due to the limited number of possibilities
Ways of getting at least a head and an even number =6
HT8
TH8
HT10
TH10
HH8
HH10
Ways of not getting at least one head and an even number=6
TT8
TT10
HT3
TH3
HH3
TT3
Total probability=6/12=1/2
Answer:D
Answer: D
Question: Elizabeth bought a dress with a 35% off coupon. If the dress cost her $87.61, what is the original selling price of the dress?
Options:
A)$134.78
B)$250.31
C)$118.27
D)$87.61
E)None of these.
Rationale: Explanation:CP of Elizabeth is 35% of the Original SP.:. Original SP = $87.61x100/65 = $134.78.Answer: Option A.
Answer: A
Question: In a set of numbers from 100 to 400 inclusive, how many integers are odd and do not contain the digit 5?
Options:
A)180
B)196
C)286
D)288
E)324
Rationale: We have to find the total number of 3-digit odd numbers not having 5 as a digit.
Units digits will be among 1,3,5,7,9
Tenth digits will be among 0,1,2,3,4,6,7,8,9
Hundredth digits will be among 1,2,3,4
So total numbers = 5*9*4 =180
Answer : A
Answer: A
Question: How many seconds will a train 100 meters long take to cross a bridge 150 meters long if the speed of the train is 36 kmph?
Options:
A)22 sec
B)77 sec
C)25 sec
D)18 sec
E)17 sec
Rationale: D = 100 + 150 = 250
S = 36 * 5/18 = 10 mps
T = 250/10 = 25 sec
Answer:C
Answer: C
Question: A discount of 20 percent on an order of goods followed by a discount of 30 percent amounts to
Options:
A)the same as one 44 percent discount
B)the same as one 40 percent discount
C)the same as one 36 percent discount
D)the same as one 30 percent discount
E)the same as one 25 percent discount
Rationale: 0.8*0.7*x=0.56x from initial value, meaning 0.44 or 44% discount
A
Answer: A
Question: Car A runs at the speed of 60 km/hr and reaches its destination in 8 hours. Car B runs at the speed of 70 km/h and reaches its destination in 4 hours. What is the ratio of distances covered by Car A and Car B?
Options:
A)3 : 7
B)4 : 9
C)12 : 7
D)5 : 7
E)6 : 11
Rationale: Car A travels 60 × 8 = 480 km
Car B travels 70 × 4 = 280 km
The ratio is 480 : 280 = 48 : 28 = 12 : 7
The answer is C.
Answer: C
Question: A person distributed 20% of his income to his 3 children each. He deposited 30% of his income to his wife's account. He donated 5% of remaining amount to an orphan house.Finally he has $40000. Find his total income?
Options:
A)452000
B)562000
C)800000
D)500000
E)652000
Rationale: 3 children got = 3*20% = 60%
wife got = 30%
orphan house = 5%
total = 60+30+5 = 95%
remaining = 100-95 = 5%
5% = 40000
100% = 40000*100/5 = $800000
Answer is C
Answer: C
Question: A man rows his boat 95 km downstream and 45 km upstream, taking 2 1/2 hours each time. Find the speed of the stream?
Options:
A)6
B)7
C)10
D)8
E)9
Rationale: Speed downstream = d/t = 95/(2 1/2) = 38 kmph
Speed upstream = d/t = 45/(2 1/2) = 18 kmph
The speed of the stream = (38 - 18)/2
= 10 kmph
Answer: C
Answer: C
Question: How many 3 digit numbers can be formed from the digits 2,3,5,6,7 and 9 which are divisible by 5 and none of the digits is repeated?
Options:
A)30
B)20
C)10
D)45
E)50
Rationale: Since each desired number is divisible by 5,
so we much have 5 at the unit place.
The hundreds place
can now be filled by any of the remaining 4 digits .
so, there4 ways of filling it.
Required number of numbers = (1 * 5 * 4)
= 20
Ans: B
Answer: B