divelab/Sys2Bench huggingface dataset:
Question: How many four letter combinations can be formed using the letters of the word HEART?
Options:
A)15
B)25
C)60
D)120
E)200
Rationale: The number of letters in the given word is five.
The number of four letter combinations that can be formed using these five letters is
= 5 * 4 * 3 * 2 = 120.
Answer: D
Answer: D
Question: Working independently, Tina can do a certain job in 12 hours. Working independently, Ann can do
the same job in 9 hours. If Tina Works independently at the job for 8 hours and then Ann works
independently, how many hours will it take Ann to complete the remainder of the jobs?
Options:
A)2/3
B)3/4
C)1
D)2
E)3
Rationale: Work done by Tina in 1 hr=1/12
Work done by Tina in 8 hr=1/12*8 which is 2/3
Now,the remaining work is 1/3 which is completed by Ann in 1/3*9 which is 3hr
ANSWER:E
Answer: E
Question: Dhoni weighs twice as much as Nameetha. Nameetha's weight is 75% of Bima's weight. Dravid weighs 20% of Leela's weight. Leela weighs 40% of Dhoni's weight. Who among these 5 persons weighs the least?
Options:
A)Bima
B)Leela
C)Dravid
D)Nameetha
E)Dhoni
Rationale: if
Bima weight = x
we get
Nameetha's weight = 0.75x
Dhoni's weight = 1.5x
Leela's weight = 0.6x
and Dravid's weight = 0.12x
Answer : C
Answer: C
Question: Number of prime numbers between 10 and 20 is
Options:
A)4
B)5
C)6
D)7
E)9
Rationale: total 4=1, 13, 17, 19
ANSWER:A
Answer: A
Question: The line Q represented by which of the following equation does not intersect with the line represented by y = 3x^2+5x+1
Options:
A)y = 2x^2+5x+1
B)y = x^2+5x+2
C)y = 3x^2+5x+2
D)y = 3x^2+7x+2
E)y = x^2+7x+1
Rationale: concept of slope for linesparabolas are different. Bunuel, please correct if I am wrong. Also please help to solve this problem if its a GMAT type question.
The general form of parabolic equ. is y^2= 4ax which implies the axis is x or x^2 = 4ay where axis is y.
We have a similar form as x^2 = 4ay.
here the vertex is origin.
So if we have same values of x and y but constant term changes then we will have parallel parabolas.
This is same as for straight line Q which are parallel for different values of constant term c
ax + by +c1 = 0 and ax +by+ c2 =0
We have quadratic equations. These equations when drawn give parabolas, not lines. The question is: which of the following parabolas does not intersect with the parabola represented by y=3x^2+5x+1.C
Answer: C
Question: What is the sum of all even integers between 99 and 301?
Options:
A)40000
B)20000
C)40400
D)20200
E)20400
Rationale: Even integers between 99 and 301 are 100,102,104,....,300
To find total even numbers n , 300=100+(n-1)2, n=101
Sum of all numbers=(101/2)[2*100+ (101-1)2]
=10100+10100 =20200
ANSWER:D
Answer: D
Question: A boatman goes 2 km against the current of the stream in 1 hour and goes 1 km along the current in 10 minutes. How long will it take to go 8 km in stationary water?
Options:
A)2 hours
B)1 hour
C)1 hour 15 min
D)1 hour 30 min
E)1 hour 10 min
Rationale: speed (upstream) =2/1 = 2 kmhr
speed (downstream)=1/(10/60)= 6 kmhr
speed in still water = 1/2 (2+6) = 4 kmhr
time taken in stationary = 8/4 = 2 hrs
ANSWER:A
Answer: A
Question: A man sells a car to his friend at 15% loss. If the friend sells it for Rs.54000 and gains 20%, the original C.P.of the car was :
Options:
A)Rs.22941.18
B)Rs.32941.18
C)Rs.52941.18
D)Rs.62941.18
E)None of these
Rationale: Explanation:
S.P = Rs.54,000. Gain earned = 20%
C.P = Rs.[100/120Ã—54000]
=Rs. 45000
This is the price the first person sold to the second at at loss of 15%.
Now S.P = Rs.45000 and loss = 15%
C.P. Rs.[100/85Ã—45000]= Rs.52941.18
Correct Option : C
Answer: C
Question: If (4x + y)/(x + 4y) = 2/3, then find the value of (x + 4y)/(4x + y).
Options:
A)3/8
B)3/4
C)3/2
D)3/6
E)3/8
Rationale: Explanation:
Given, (4x + y)/(x + 4y) = 2/3
=> 3(4x + y) = 2(x + 4y)
=> 2x = y
.: (x + 4y)/(4x + y) = x + 4(2x)/(4x + 2x) = 9x/6x = 3/2
Answer: Option C
Answer: C
Question: A jar contains only red, yellow, and orange marbles. If there are 3 red, 3 yellow, and 4 orange marbles, and 3 marbles are chosen from the jar at random without replacing any of them, what is the probability that 2 yellow, 1 red, and no orange marbles will be chosen?
Options:
A)1/60
B)1/45
C)2/45
D)3/22
E)5/22
Rationale: I started by finding the 2 probabilities, without calculation, like this:
P(YYR)
P(YRY)
P(RYY)
I calculated the first one and ended in 1/22. I looked at the answer choices at this point and saw answer D: 3/22.
This helped me realise that for the 3 possible orderings the probabbility is the same. So, it should be (1/45)*(2), which indeed is 2/45.
C
Answer: C
Question: If the President and Vice President must sit next to each other in a row with 6 other members of the Board, how many different seating arrangements are possible?
Options:
A)12010
B)10080
C)10228
D)11080
E)72000
Rationale: We need to take President and VP as one unit. Therefore we have 7 people to arrange=7! ways
Also, we both President and VP can be arranged in 2 ! ways.
Reqd no of ways=7!*2!=10080 ways
Answer B
Answer: B
Question: 0.35 represents what percent of 0.005?
Options:
A)0.05%
B)0.5%
C)5%
D)500%
E)7000%
Rationale: One more method
0.35 represents what percent of 0.005?
Adjusting the decimal
350 represents what percent of 5?
Divide by 5
70 represents what percent of 1?
Answer = 70*100 = 7000% = E
Answer: E
Question: A train passes a station platform in 60 sec and a man standing on the platform in 20 sec. If the speed of the train is 54 km/hr. What is the length of the platform?
Options:
A)615 m
B)420 m
C)168 m
D)197 m
E)691 m
Rationale: Speed = 54 * 5/18 = 15 m/sec.
Length of the train = 15 * 20 = 300 m.
Let the length of the platform be x m . Then,
(x + 300)/36 = 15 => x
= 420 m
Answer: B
Answer: B
Question: An empty pool being filled with water at a constant rate takes 8hours to fill to 3/7 of its capacity.how much more time will it take to finish filling the pool?
Options:
A)5hr 30min
B)5hr 20min
C)4hr 48min
D)3 hr 12min
E)2hr 40 min
Rationale: As pool is filled to 3/5 of its capacity then 2/5 of its capacity is left to fill.
To fill 3/5 of the pool took 8 hours --> to fill 2/5 of the pool will take 8/(3/5)*2/5=16/3 hours = 5 hours 20 minutes (because if t is the time needed to fill the pool then t*3/5=8 --> t=8*5/3 hours --> to fill 2/5 of the pool 8*5/3*2/5=16/3 hours will be needed).
Or plug values: take the capacity of the pool to be 5 liters --> 3/5 of the pool or 3 liters is filled in 8 hours, which gives the rate of 3/8 liters per hour --> remaining 2 liters will require: time = job/rate = 2/(3/8) = 16/3 hours = 4 hours 48 minutes.
Answer: C.
Answer: C
Question: There are 12 slate rocks, 16 pumice rocks, and 8 granite rocks randomly distributed in a certain field. If 2 rocks are chosen at random and without replacement, what is the probability that both rocks will be slate rocks?
Options:
A)3/32
B)7/64
C)11/105
D)15/127
E)19/134
Rationale: 12/36*11/35 = 11/105
The answer is C.
Answer: C
Question: If a quarter kg of potato costs 60 yen, how many paise will 200 gm cost?
Options:
A)yen 49
B)yen 40
C)yen 50
D)yen 48
E)yen 41
Rationale: D
yen 48
Let the required weight be x kg.
Less weight, Less cost (Direct Proportion)
250 : 200 :: 60 : x 250 x x = (200 x 60)
x= (200 x 60)/250
x = 48
Answer: D
Question: After decreasing 24% in the price of an article costs Rs.912. Find the actual cost of an article?
Options:
A)1400
B)1300
C)1200
D)1100
E)1500
Rationale: CP* (76/100) = 912
CP= 12 * 100 => CP = 1200
ANSWER:C
Answer: C
Question: There are 50 doors marked with numbers 1 to 50. And there are 50 individuals marked 1 to 50.
An operation on a door is defined as changing the status of the door from open to closed or vice versa. All doors are closed to start with.
Now one at a time one randomly picked individual goes and operates the doors. The individual however operates only those doors which are a multiple of the number he/she is carrying. For e.g. individual marked with number 5 operates the doors marked with the following numbers: 5, 10, 15 ... 50.
If every individual in the group get one turn then how many doors are open at the end?
Options:
A)0
B)1
C)2
D)4
E)7
Rationale: Let us start with 1.
When 1 goes, all the doors are open since every number is a multiple of 1.
Also 1 will remain opened since 1 is not a multiple of any number.
Prime numbers can only be operated by people with prime numbers.
So 2,3,5,7,11,13,17,19,23,29,31,37,41,43,47 will be closed when people with respective numbers perform operations on them.
From the other numbers, only those numbers will remain opened on which even number of operations are performed including the operation performed by number 1.
This is possible only for perfect squares which are 4,9, 16,25,36 and 49.
So our numbers are 1,4,9,16,25,36 and 49.
Answer:- E
Answer: E
Question: A hiker walked for 3 days. She walked 18 miles on the first day, walking 3 miles per hour. On the second day she walked for one less hour but she walked one mile per hour, faster than on the first day. On the third day 5 miles per hour for 6 hours. How many miles in total did she walk?
Options:
A)68
B)44
C)58
D)60
E)62
Rationale: First day - 18 miles with 3 miles per hours then total - 6 hours for that day
Second day - 4 miles per hour and 5 hours - 20 miles
Third day - 5 miles per hour and 6 hours - 30 miles
Total 18+20+30 = 68
Answer: option A.
Answer: A
Question: A cat leaps 6 leaps for every 5 leaps of a dog, but 2 leaps of the dog are equal to 3 leaps of the cat. What is the ratio of the speed of the cat to that of the dog?
Options:
A)4:5
B)2:3
C)4:1
D)1:9
E)3:2
Rationale: Given;
2 dog = 3 cat;
Or, dog/cat = 3/2;
Let cat's 1 leap = 2 meter and dogs 1 leap = 3 meter.
Then, ratio of speed of cat and dog = 2*6/3*5 = 4:5''Answer: 4:5;
Answer: A
Question: If 20% of certain quantity of work is done by A and the rest 80% by B, the work is completed in 20 days. If 80% of the work is done by A and the remaining 20% by B, then the work is completed in 30 days. How many days are required to complete the work , if A and B work together.
Options:
A)11 1/9
B)10 1/9
C)12
D)15
E)Source: TIME material.
Rationale: Use algebra:
0.2/A + 0.8/B = 20
1 /A + 4/B = 100
0.8/A + 0.2/B = 30
4/A+ 1/B = 150
15/B = 250
B = 3/50 work per day
A = 3/100 work per day
Combined rate = 3/40 + 3/100 = 9/100
Time taken when working together = 100/9 = 11(1/9) days
Answer (A)
Answer: A
Question: Kate and Danny each have $10. Together, they flip a fair coin 5 times. Every time the coin lands on heads, Kate gives Danny $1. Every time the coin lands on tails, Danny gives Kate $1. After the five coin flips, what is the probability that Kate has more than $10 but less than $15?
Options:
A)5/16
B)1/2
C)12/30
D)15/32
E)3/8
Rationale: the probability of the coin landing tails up either 3 or 4 times = P(3t) + P(4t)
Binomial distribution formula: nCk p^k (1-p)^(n-k)
P(3t) = 5C3 (1/2)^3 (1/2)^2 = 10 (1/2)^5
P(4t) = 5C4 (1/2)^4 (1/2)^1 = 5 (1/2)^5
=> P(3t) + P(4t) = 15/32
Answer:D
Answer: D
Question: How many quarters are equal to 2 dollars?
Options:
A)1
B)8
C)12
D)9
E)7
Rationale: B. 8 quarters
Answer: B
Question: I walk a certain distance and ride back taking a total time of 37 minutes. I could walk both ways in 55 minutes. How long would it take me to ride both ways?
Options:
A)20mins
B)19mins
C)5mins
D)4mins
E)12mins
Rationale: Let the distance be x km. Then,
( Time taken to walk x km) + (time taken to ride x km) =37 min.
( Time taken to walk 2x km ) + ( time taken to ride 2x km )= 74 min.
But, the time taken to walk 2x km = 55 min.
Time taken to ride 2x km = (74-55)min =19 min.
Ans: B
Answer: B
Question: A shop owner professes to sell his articles at certain cost price but he uses false weights with which he cheats by 20% while buying and by 20% while selling. What is his percentage profit?
Options:
A)10.22%
B)20.22%
C)21.22%
D)50%
E)Can't be calculated
Rationale: The owner buys 100 kg but actually gets 120kg;
The owner sells 100 kg but actually gives 80kg;
Profit: (120-80)/80*100=~50%
Answer: D.
Answer: D
Question: If a quarter kg of potato costs 60 paise, how many paise will 200 gm cost?
Options:
A)54 paise
B)48 paise
C)72 paise
D)28 paise
E)36 paise
Rationale: Let the required weight be x kg.
Less weight, Less cost (Direct Proportion)
250 : 200 :: 60 : x 250 x x = (200 x 60)
x=	(200 x 60)/250
x = 48.
Answer is B
Answer: B
Question: A rectangular plot measuring 90 metres by 60 metres is to be enclosed by wire fencing. If the poles of the fence are kept 5 metres apart, how many poles will be needed ?
Options:
A)55
B)56
C)60
D)58
E)None of these
Rationale: Solution
Perimeter of the plot = 2(90 + 60) = 300 m.
∴ Number of poles = [300/5] =60m Answer C
Answer: C
Question: A 300 metre long train crosses a platform in 39 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform?
Options:
A)320
B)600
C)700
D)350
E)500
Rationale: Speed = 300/18 m/sec = 50/3 m/sec
(x+300/39) = 50/3
x=350 m
ANSWER D
Answer: D
Question: A football field is 10800 square yards. If 1200 pounds of fertilizer are spread evenly across the entire field, how many pounds of fertilizer were spread over an area of the field totaling 3600 square yards?
Options:
A)400
B)600
C)750
D)2400
E)3200
Rationale: Answer A) 10800 yards need 1200 lbs
1 Yard will need 1200/10800 = 1/9 lbs
3600 Yards will need 1/9* 3600 Yards = 400lbs
Answer: A
Question: A man took some money for borrowed, for 3 years the total will be Rs.4500 and 5 years it will be Rs.5500/-. Then how much amount he borrowed?
Options:
A)s.2000/-
B)s.2500/-
C)s.2770/-
D)s.2800/-
E)s.3000/-
Rationale: 3 years --------> Rs.4500/-
5 years --------> Rs.5500/-
~ ~
------------------------------
2 years ---------> Rs.1000/-
1 year ----------> Rs.500/-
3years * Rs.500/- = Rs.1500/-
P = Rs.4500/- - Rs.1500/- = Rs.3000/-
P = Rs.3000/-
E
Answer: E
Question: In the following sum, “?”, stands for which digit?
? + 1? + 2? + ?3 + ?1 = 21?
Options:
A)4
B)5
C)6
D)7
E)8
Rationale: let the digit be x. so the series becomes:
x + (10 + x) + (20 + x) + (10x+3) + (10x + 1)=210 + x
=> 23x + 34 = 210 + x
=> 22x = 176
=>x = 176/22 = 8
ANSWER:E
Answer: E
Question: A circle is circumscribed around a quadrilateral, and the quadrilateral is ABCD, What is the value of w when angle C is 125 degrees?
Options:
A)45
B)55
C)65
D)75
E)85
Rationale: An inscribed angle is an angle in a circle composed of two chords with a common endpoint, that is, an angle with its vertex on the circle. In this problem, all four lettered angles are inscribed angles.
An inscribed angle necessarily opens to intersect an arc (the technical word is to subtend an arc). The Inscribed Angle Theorem said that the measure of an inscribed angle is always half the measure of the arc it intersects, or subtends.
angle C = 125 degrees
Thus,
arc DAB = 250 degrees
A whole circle has 360 degrees of arc, so arc BCD should be the rest of the circle.
arc BCD = 360 - 250 = 110 degrees
The angle that intersects this arc, angle A, should have half this measure.
angle A = w = 110/2 = 55 degrees
Answer =(B)
Answer: B
Question: If (10^4 * 3.456789)^11 is written as a single term, how many digits would be to the right of the decimal place?
Options:
A)12
B)18
C)22
D)28
E)36
Rationale: 3.456789^11 has 6*11 = 66 decimal places.
10^44 moves the decimal place to the right 44 places.
(10^4 * 3.456789)^11 has 66-44 = 22 digits after the decimal point.
The answer is C.
Answer: C
Question: The average of six numbers is 3.95. The average of two of them is 3.4, while the average of the other two is 3.85. What is the average of the remaining two numbers ?
Options:
A)3.6
B)4.6
C)6.5
D)7.3
E)None of these
Rationale: Explanation:
Sum of the remaining two numbers = (3.95 * 6) - [(3.4 * 2) + (3.85 * 2)]
= 23.70 - (6.8 + 7.7) = 23.70 - 14.5 = 9.20.
Required average = (9.2 / 2) = 4.6. Answer: B
Answer: B
Question: If 6 yrs are subtracted from the present age of John & the remainder is divided by 18, then the presentage of his grandson Anup is obtained. If Anup is 2 years younger to Madan whose age is 5 yrs, then whatis John’s present age?
Options:
A)20
B)30
C)60
D)70
E)80
Rationale: Sol. Anup's age = (5 - 2) years = 3 years. Let Gagan's age be x years.
Then, (x-6)/18 = 3 => x-6 = 54 x = 60.
C
Answer: C
Question: A person saved $10 in buying an item on sale. If he spent $200 for the item, approximately how much percent he saved in the transaction?
Options:
A)8%
B)10%
C)2%
D)5%
E)6%
Rationale: Actual price = 200+10 = $210
Saving = 10/210 * 100 = 100/21 = 5% approximately
Answer is D
Answer: D
Question: The respective ages of father and his son are 42 and 16 years. In how many years will the father be twice as old as his son ?
Options:
A)19 years
B)9 years
C)10 years
D)15 years
E)12 years
Rationale: Suppose x years later the father will be twice as old as his son.
x + 42 = 2 (x + 16)
x = 42 - 32 = 10 years
answer : C
Answer: C
Question: At a certain hospital, 75% of the interns receive fewer than 6 hours of sleep and report feeling tired during their shifts. At the same time, 70% of the interns who receive 6 or more hours of sleep report no feelings of tiredness. If 80% of the interns receive fewer than 6 hours of sleep, what percent W of the interns report no feelings of tiredness during their shifts?
Options:
A)6
B)14
C)19
D)20
E)81
Rationale: < 6 hours sleep>= 6 hours sleepTOTAL
Tired75--
Not Tired-0.7*X?
TOTAL80X100
Interns who receive< than 6 hours sleepandNot Tired= 80 - 75 = 5;
TOTAL interns who receive >= 6 hours sleep= 100 - 80 = 20, so interns who receive>= 6 hours sleepand areNot Tired= 0.7 * 20 =14;
Interns who areNot Tired W= 5 + 14 = 19.
Answer: C.
Answer: C
Question: If $100 is invested at x percent simple annual interest for n years, which of the following represents the total amount of interest, in dollars, that will be earned by this investment in the n years?
Options:
A)10,000(x^n)
B)10,000(x/100)^n
C)100n(x/100)
D)10,000(1+x/100)^n
E)10,000n(1+x/100)
Rationale: I think answer D is for compound interest (which i assumed)
and answer C is for simple interest because it is not compounding
Answer: C
Question: A cylindrical container of radius 6 cm and height 15 cm is filled with ice-cream. The whole icecream has to be distributed to 10 children in equal cones with hemispherical tops. If the height of the conical portion is four times the radius of its base, find the radius of the ice-cream cone.
Options:
A)1
B)2
C)3
D)4
E)5
Rationale: volume of given ice cream =(pie)*6²*15=540(pie)
dividing to 10 children volume given to a child =54(pie)
let r be radius and h be the height of the cone,then
(pie)r²h/3 + 2(pie)r³/3=54(pie)
also given h=4r
4r³/3 +2r³/3=54
2r³=54
r³=27
r=3
ANSWER:C
Answer: C
Question: In Net's hair salon 48% of the customers dye their hair blond, 36% dye their eyebrows blond and 35% straighten their hair. 20% of the customers have none of these three procedures, while 12% take all of these three procedures. What percent of the customers come for exactly 2 of these 3 procedures?
Options:
A)5%
B)9%
C)12%
D)15%
E)21%
Rationale: Let a total of 100 people visit the salon.
Total = 100
Dye hair blonde (A) = 45 % = 45
Dye Eyebrows blonde (B) = 36% = 36
Straighten Hair (C) = 35% = 35
Neither = 20% = 20
All Three = 12% =12
Total = A+B+C - (Sum of Exactly Two group overlaps) - 2*(All three) + Neither
100 = 45+36+35 - (Sum of Exactly Two group overlaps) - 2*12 + 20
(Sum of Exactly Two group overlaps) = 9
%of customers coming for exactly 2 of the 3 procedures = 15%
D
Answer: D
Question: A shop owner sells 60mtr of cloth and gains SP of 10 mtrs. Find the gain %?
Options:
A)20%
B)40%
C)50%
D)60%
E)70%
Rationale: Here, selling price of 10 m cloth is obtained as profit.
Profit of 10 m cloth = (S.P. of 60 m cloth) – (C.P. of 60 m cloth)
Selling price of 50 m cloth = Selling Price of 60 m of cloth
Let cost of each metre be Rs. 100.
Therefore, cost price of 50 m cloth = Rs. 5000 and S.P. of 50 m cloth = Rs. Rs. 6000
Profit% = 10/50 × 100 = 20%
20
Profit of 20% was made by the merchant.
A
Answer: A
Question: One hour before John started walking from P to Q, a distance of 28 miles, Ann had started walking along the same road from Q to P. Ann walked at a constant speed of 3 miles per hour and John at 2 miles per hour. How many miles had Ann walked when they met?
Options:
A)6 miles
B)8,4 miles
C)9 miles
D)9,6 miles
E)18 miles
Rationale: Ann walks from Q to P at a speed of 3 miles/hr for one hour. She covers 3 miles in 1 hour and now distance between John and Ann is 28 - 3 = 25 miles.
Ann walks at 3 mph and John at 2 mph so their relative speed is 3+2 = 5 mph.
They have to cover 25 miles so it will take them 25/5 = 5 hours to meet.
In 5 hrs, Ann would have covered 5 hrs * 3 miles per hour = 15 miles.
Adding this to the 3 miles she covered before John, Ann covered a total of 3 + 15 = 18 miles.
Answer (E)
Answer: E
Question: If a fair die is rolled two times, what is the probability that a 3 occurs on at least one roll?
Options:
A)25/36
B)125/216
C)91/216
D)11/36
E)36/216
Rationale: Questions such as these that talk aboutat leastormaximumorminimumin probability questions should make sure realize that probability of any event (N) to occur = 1- P(Not N)
Thus, the probability of at least 1 roll = 1- Probability of NO 3s = 1- (5/6)(5/6) = 1-25/36 = 11/36.
5/6 is the probability of NOT getting a 3 in any 1 roll with 5 allowed numbers (=1,2,4,5,6) out of a total of 6 possibilities.
D is thus the correct answer.
Answer: D
Question: In 1937, the ship of the great sailor SINBAD left an Egyptian port heading Ivory coast at R mile/month .
One month later another ship of the greatest pirate ever CHENG I SAO was 5000 miles due south of the same Egyptian port and heading due north at Y miles/month. Six months later after the leaving of Sinbad’s ship from Egyptian port, how far apart were the ships? [Ivory coast is in the west of Egypt]
Options:
A){ (6R)^2 + (5000-5y)^2 }^1/2
B){ (36x)^2 + (5000-7y)^2 }^1/2
C){ (16x)^2 + (5000-7y)^2 }^1/2
D){ (7x)^2 + (5200-7y)^2 }^1/2
E){ (2x)^2 + (300-7y)^2 }^1/2
Rationale: The chinese ship sailed for 5 months i.e. 5Y miles @Y miles/month, therefore distance from Egyptian port is 5000-5Y. Since A is the only option with this value ...therefore A is the answer
Answer: A
Question: The compound interest on Rs. 30,000 at 7% per annum is Rs. 4347. What is the period (in years)?
Options:
A)1
B)2
C)3
D)3.5
E)5
Rationale: Explanation:
Let the period be n years
Then, amount after n years = Rs.(30000 + 4347) = Rs. 34347
P(1+R/100)T=34347
30000(1+7/100)n=34347
30000(107100)n=34347
(107/100)n=34347/30000=11449/10000=(107/100)2
n=2 years
Answer: Option B
Answer: B
Question: A sum of money becomes 7/6 of itself in 7 years at a certain rate of simple interest. The rate per annum is?
Options:
A)50/13
B)50/17
C)50/19
D)50/21
E)50/23
Rationale: Let sum = x. Then, amount = 7x/6
S.I. = 7x/6 - x = x/6; Time = 7 years.
Rate = (100 * x) / (x * 6 * 7) = 50/21 %.
Answer:D
Answer: D
Question: Ashok secured average of 77 marks in 6 subjects. If the average of marks in 5 subjects is 74, how many marks did he secure in the 6th subject?
Options:
A)38
B)27
C)92
D)17
E)80
Rationale: Explanation:
Number of subjects = 6
Average of marks in 6 subjects = 77
Therefore total marks in 6 subjects = 77 * 6 = 462
Now, No. of subjects = 5
Total marks in 5 subjects = 74 * 5 = 370
Therefore marks in 6th subject = 462 – 370 = 92
ANSWER: C
Answer: C
Question: In the x-y plane, the area of the region bounded by the graph of |x+y| + |x-y| = 10 is
Options:
A)8
B)625
C)16
D)20
E)24
Rationale: I've never seen such kind of question in GMAT before.
OK there can be 4 cases:
|x+y| + |x-y| = 10
A. x+y+x-y = 10 --> x=5
B. x+y-x+y = 10 --> y=5
C. -x-y +x-y= 10 --> y=-5
D. -x-y-x+y=10 --> x=-5
The area bounded by 4 graphs x=5, x=-5, y=5, y=-5 will be square with the side of 4 so the area will be25*25=625
Answer: B
Answer: B