divelab/Sys2Bench huggingface dataset:
Question: If the dimensions of a certain rectangular box are 5 inches by 2 inches by 3 inches, then the face of greatest area is of what area?
Options:
A)225 square inches
B)45 square inches
C)25 square inches
D)15 square inches
E)10 square inches
Rationale: Definitely (D) 5*3 = 15 sq Inches
The question asks to find the greatest area of the faces of a cuboid
The Possible area of the faces are -
Length*Breadth , Breadth*Height & Height*Length
The possible areas are - 6 , 10 & 15
Thus 15 is the greatest possible area....
ANSWER:D
Answer: D
Question: If the number 24*32 is completely divided by 6. what is the smallest whole number in the place of * ?
Options:
A)4
B)3
C)1
D)2
E)5
Rationale: Solution
The number is divisible by 6 means it must be divisible by 2 and 3. Since the number has 2 as its end digit it is divisible by 2. Now, 2+4+x+3+2=11+x which must be divisible by 3. Thus x=1
Answer C
Answer: C
Question: Maxwell leaves his home and walks toward Brad's house at the same time that Brad leaves his home and runs toward Maxwell's house. If the distance between their homes is 20 kilometers, Maxwell's walking speed is 4 km/h, and Brad's running speed is 6 km/h, what is the distance traveled by Brad?
Options:
A) 12
B) 18
C) 20
D) 24
E) 30
Rationale: Time taken = Total Distance / Relative Speed
Total Distance = 20 kms
Relative Speed (Opposite side) (As they are moving towards each other speed would be added ) = 6+ 4 = 10 kms/hr
Time taken = 20 / 10 = 2 hrs
Distance traveled by Brad = Brad's speed * time taken = 6 * 2 = 12 kms... Answer - A
Answer: A
Question: An inspector rejects 0.00008% of the meters as defective. How many will be examine to project ?
Options:
A)2000
B)2300000
C)2700
D)2500000
E)250
Rationale: Let the number of meters to be examined be x.
Then, 0.00008% of x =2
[(8/100000)*(1/100)*x] = 2
x = [(2*100000*100)/8] = 2500000
Answer is D.
Answer: D
Question: Perimeter of front wheel =30, back wheel = 20. If front wheel revolves 240 times. How many revolutions will the back wheel take?
Options:
A)120
B)180
C)240
D)360
E)480
Rationale: sice the distance covered by both the wheels should be same
so
let x be the no. of revolutions by the back wheel
so 240*2*pie*30=x*2*pie*20
so x=360.
ANSWER:D
Answer: D
Question: The sum of the smallest six digit number and the greatest five digit number is
Options:
A)201110
B)199999
C)211110
D)1099999
E)None
Rationale: Solution
Requires sum	=(100000 + 99999)
=199999.
Answer B
Answer: B
Question: if a * b = 2a – 3b + ab, then 3 * 5 + 5 * 3 is equal to :
Options:
A)22
B)24
C)26
D)28
E)29
Rationale: Solution
3 × 5 + 5 ×3 = (2 ×3 - 3 × 5 + 3 × 5) + 2 (2 × 5 - 3 × 3 +5 × 3)
= (6 + 10 - 9 + 15) = 22.
Answer A
Answer: A
Question: There is a soccer tournament that is single elimination meaning that after one loss the team is out. There are 15 teams in this tournament. How many games are played?
Options:
A)15
B)7
C)8
D)14
E)10
Rationale: D
The number of games always adds up to one less than the number of teams in a single elimination tournament. You may calculate it any way. Therefore, 14 games were played.
Answer: D
Question: The sum of the present ages of a father and his son is 60 years. five years ago, father's age was four times the age of the son. so now the son's age will be:
Options:
A)5
B)10
C)15
D)20
E)25
Rationale: Explanation:
Let the present ages of son and father be x and (60 -x) years respectively.
Then, (60 - x) - 5= 4(x - 5)
55 - x = 4x - 20
5x = 75 x = 15. Answer: C
Answer: C
Question: In how many seconds will a train 100 meters long pass an oak tree, if the speed of the train is 36 km/hr?
Options:
A)6
B)8
C)10
D)12
E)14
Rationale: speed = 36 * 5/18 = 10 m/s
time = 100/10 = 10 seconds
The answer is C.
Answer: C
Question: What positive number, when squared, is equal to the cube of the positive square root of 15?
Options:
A)64
B)32
C)8
D)6
E)2
Rationale: Let the positive number be x
x^2 = ((15)^(1/2))^3
=>x^2 = 4^3 = 36
=> x = 6
Answer D
Answer: D
Question: Find the amount on Rs.8000 in 2 years, the rate of interest being 4% per first year and 5% for the second year?
Options:
A)5568
B)6369
C)8736
D)5635
E)6734
Rationale: 8000 * 104/100 * 105/100
=> 8736
Answer:C
Answer: C
Question: If 16 toys cost 240, then what do 40 toys cost ?
Options:
A)Rs. 600
B)Rs. 620
C)Rs. 640
D)Rs. 660
E)None of these
Rationale: Explanation:
Although we can first calculate the cost of one toy and then can multiply it with 40 to get the result.
but we will solve it with chain rule so that we can prepare ourself for other complex problems which we can solve easily by applying this rule.
Let the required cost be Rs. x
More toys means More Cost. (Direct Proportion)
15:40::240:x=>x=240∗40/15=>x=640
So 40 toys will cost Rs 640
Option C
Answer: C
Question: Of the three numbers, the sum of the first two is 45; the sum of the second and the third is 55 and the sum of the third and thrice the first is 90. The third number is
Options:
A)15
B)20
C)25
D)30
E)35
Rationale: Sol.
Let the numbers be x,y and z.
Then, x + y = 45
y+z = 55 and
3x+z = 90
⇒ y = 45 - x, z = 55 - y = 55 - (45 - x) = 10 + x.
∴ 3x + 10 + x = 90 or x = 20.
y = (45 - 20) = 25 and z = (10 + 20) = 30.
∴ Third number = 30.
Answer D
Answer: D
Question: A tank is filled in 5 hours by three pipes A, B and C. The pipe C is twice as fast as B and B is twice as fast as A. How much time will pipe A alone take to fill the tank?
Options:
A)35 hours
B)25 hours
C)20 hours
D)Cannot be determined
E)None of these
Rationale: Suppose the efficiencies of pipes C, B and A are 4K, 2K and K.
Since, the tank is filled in 5 hours by the three pipes having combined efficiency equal to 7K, the time required to fill the tank by A alone = 7K×5 /K=35hours
Answer A
Answer: A
Question: If X = 2 + 1/(1+1/(1-1/2))then the value of 4x+7/3?
Options:
A)9 2/3
B)10 1/3
C)11
D)11 2/3
E)12
Rationale: X = 2 + 1/(1+1/(1-1/2))
= 2 + 1/(1+2)
= 2 + 1/3
X = 7/3 ==> 4X + 7/3 => 4(7/3) + 7/3
==> 28/3 + 7/3
==> 35/3
==> 11 2/3.
D)
Answer: D
Question: Tammy climbed a mountain in two days. She spent a total of 14 hours climbing the mountain. On the second day, she walked at an average speed that was half a kilometer per hour faster, but 2 hours less than what she walked on the first day. If the total distance she climbed during the two days is 52 kilometers, how many Q kilometers per hour did Tammy walk on the second day?
Options:
A)3
B)3.5
C)4
D)4.5
E)6
Rationale: Ans: C
Total time = 14 hrs
Let time traveled during 1st day = x
Let time traveled during 2nd day = x-2
Total time =14
x+x-2 = 14
x=8
speed * time = distance
s*8 + (s+0.5)(8-2) = 52
solving s = 4.5
now speed for 2nd day is 0.5 less than the 1st day which is 4.5
Thus speed for 2nd day = 4
Its simple algebra for s*8 + (s+0.5)(8-2) = 52 but for some reason Im getting 3.5 and not 4.5.
8s+6s+3=52
14s=49
s=3.5
Answer: C
Question: 500 students took the test on English and Maths. 35% students failed in english and 45% failed in maths. 40% of those who passed in maths also passed in english, then how many students failed in both ?
Options:
A)162
B)138
C)60
D)10
E)12
Rationale: Passed in english = 65%
Passed in maths = 55%
Passed in both = 40% of 55% = 2/5 * (55%) = 22%
Passed in (English + Maths - Both + Neither) = 100%
65 + 55 - 22 + Neither = 100
Neither = 100 - 98 = 2% = 0.02 * 500 = 10
Answer: D
Answer: D
Question: How many multiples of 4 are less than 3200, and also multiples of 16?
Options:
A)104
B)200
C)625
D)832
E)833
Rationale: The LCM of 4 and 16 is 16. Divide 3200/16 = 200.xxx. So B is your answer.
Answer: B
Question: A man has a pool. This full pool can be drained using four different drainage, if he uses A it takes 10 hours to drain pool, if he uses B it takes 50 hour to drain and if he uses C it takes 5 hours to drain the pool. He first runs the water by A for 5 hours, then turning that off, he continues with B for 10 hours. Then turning that off as well he uses C for 1 hours and lastly using D for 1 hour the pool is empty. How long does it take to empty the pool only using the drainage D?
Options:
A)2 hours
B)4 hours
C)6 hours
D)8 hours
E)10 hours
Rationale: 1 - (5/10 +10/50 +2/5 + 1/x) = 0 x = 10 hours ANSWER = E
Answer: E
Question: At Children's General Hospital, 10 out of every 13 babies are crying. If 1 out of every 4 crying babies are hungry, and there are 50 hungry babies crying, how many babies total are there in the hospital?
Options:
A)140
B)240
C)50
D)130
E)150
Rationale: Proportions: Let B = babies, and Bc = babies crying, and Bch = hungry babies crying.
50Bch/xBc = 1Bch/4Bc
xBc = 100Bc
100Bc/yB = 10Bc/13B
yB = 130B
Answer: D
Answer: D
Question: 7 people average age is 30. youngest person age is 6. find average of the people when youngest was born.
Options:
A)23
B)24
C)25
D)26
E)27
Rationale: average age of people =30
so have total age =210
before 7 years we have to deduct each person age by seven years 210-42=161
so average age would be 161/7=24
ANSWER:B
Answer: B
Question: Rs.1010/- distributed among A,B and C such that on decreasing their shares by RS.25,RS.10 and RS.15 respectively, The balance money would be divided among them in the ratio 3:2:5. Then, A’s share is:?
Options:
A)Rs.255/-
B)Rs.313/-
C)Rs.365/-
D)Rs.355/-
E)Rs.345/-
Rationale: A:B:C = 3:2:5
Total parts = 10
A's share is = 3 parts
10 -----> Rs.960/-
3 -----> Rs.288/-
A's total =288 + 25 = Rs.313/-
B)
Answer: B
Question: In 50 l can, milk and water in the ratio of 3:1. if the ratio has made 1:3 then the quantity of water that has to be added further is?
Options:
A)100
B)120
C)90
D)80
E)70
Rationale: 100 litre water is to be added.
let 'x' liter water is to be added more.
Then 1/3 = 37.5 /(12.5 + x)
x= 100
ANSWER:A
Answer: A
Question: A truck owner will refuel his vehicle at a rate of 2 gallons of diesel fuel every 5 seconds. If diesel fuel costs $ 1.0 per gallon, how long will it take for the truck owner to refuel his vehicle with $ 40 worth of diesel fuel?
Options:
A)20 seconds
B)1 minute
C)1 minute 40 seconds
D)20 minutes
E)1 hour 20 minutes
Rationale: 2 gal / 5 sec
$1.25 / gal
$40/$1.25 = 40 gal
2 gal / 5 sec with 40 gal = 100 sec
C. 1 minute 40 seconds
Answer: C
Question: The avg age of class of 20 students in 20 years. If the lecturer’s age is added to the avg, increases by one. What is the age of the lecturer?
Options:
A)37
B)38
C)47
D)51
E)41
Rationale: E
41
Average x Number = Total Years
20 x 20 = 400 …(1)
21 x 21 = 441 …(2)
Lecturer’s age =Eqn (2) -Eqn (1)
= 441 – 400
= 41 years.
Answer: E
Question: Mane can make a handcrafted drum in 4 weeks. Zane can make a similar handcrafted drum in 6 weeks. If they both work together, how many weeks will it take for them to produce 15 handcrafted drums?
Options:
A)30
B)36
C)70
D)80
E)150
Rationale: Method I: the rates solution
“Mane can make a handcrafted drum in 4 weeks. Zane can make a similar handcrafted drum in 6 weeks.” Mane’s rate is (1 drum)/(4 weeks) = 1/4. Zane’s rate is (1 drum)/(6 weeks) = 1/6. The combined rate of Mane + Zane is
R = 1/4 + 1/6 = 3/12 + 2/12 = 5/12
That’s the combined rate. We need to make 15 drums — we have a rate and we have an amount, so use the “art” equation to solve for time:
T = A/R = 15/(5/12) = 15*(12/5) = (15/5)*12 = 3*12 = 36
BTW, notice in the penultimate step, the universal fraction strategy: cancelbeforeyou multiply (Tip #3:http://magoosh.com/gmat/2012/can-i-use- ... -the-gmat/. Mane and Zane need 36 weeks to make 15 drums.
Answer = B.
Answer: B
Question: A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Options:
A)328
B)279
C)240
D)288
E)231
Rationale: Speed = [54 * 5/18] m/sec = 15 m/sec.
Length of the train = (15 * 20) m = 300 m.
Let the length of the platform be x meters.
Then, x + 300 / 36 = 15
x + 300 = 540
x = 240 m. Answer:C
Answer: C
Question: A cylindrical can has a radius of 6 centimeters and a height of 12 centimeters. What is the area, in square centimeters, of a rectangular label that completely covers the curved surface of the can without over-lapping?
Options:
A)16 pi
B)64 pi
C)96 pi
D)144 pi
E)576 pi
Rationale: They are asking the lateral surface area of the cylinder.
the Lateral surface area = 2* pi * r *h
= 2*pi*6*12=144 pi
Answer is D.
Answer: D
Question: Find the product of the localvalue and absolutevalue of 4 in 20468?
Options:
A)1000
B)1100
C)1200
D)1300
E)1600
Rationale: Local value of 4 = 4 x 100 = 400
Place value of 4 = 4
There fore = 4 x 400 = 1600
E
Answer: E
Question: Set A contains three different positive odd integers and three different positive even integers. Set B contains two different positive odd integers and three different positive even integers. If one integer from set A and one integer from set B are chosen at random, what is the probability that the product of the chosen integers is even?
Options:
A)3/5
B)2/5
C)1/2
D)4/5
E)19/25
Rationale: There can be an odd product only if both integers are odd.
P(odd product) = 1/2*2/5 = 1/5
P(even product) = 1 - 1/5 = 4/5
The answer is D.
Answer: D
Question: The distance between Delhi and Mathura is 110 kms. A starts from Delhi with a speed of 20 kmph at 7 a.m. for Mathura and B starts from Mathura with a speed of 25 kmph at 9 p.m. from Delhi. When will they meet?
Options:
A)40.00 a.m.
B)10.00 a.m.
C)12.00 a.m.
D)11.00 a.m.
E)19.00 a.m.
Rationale: Explanation:
D = 110 â€“ 20 = 90
RS = 20 + 25 = 45
T = 90/45 = 2 hours
9 a.m. + 2 = 11 a.m.
Answer: Option D
Answer: D
Question: If p/q =4/5, then the value of 25/7 + {(2q - p) / (2q + p)} is ?
Options:
A)4
B)34
C)1
D)2
E)3
Rationale: Answer
Given Exp. = 25/ 7 + {(2q - p) / (2q + p)}
Dividing numerator as well as denominator by q,
Exp = 25/7 + {2-p/q) / (2 + p/q)}
= 25/7 + {(2 - 4/5) / (2 + 4/5)}
= 25/7 + 6/14
= 25/7 + 3/7
=28/7
=4
Correct Option: A
Answer: A
Question: In what time will two trains cross each other completely, which are running on the same parallel lines in opposite directions, each 100 m in length both trains running with a speed of 80 kmph?
Options:
A)4.5 sec
B)4.8 sec
C)4.2 sec
D)5.0 sec
E)5.2 sec
Rationale: D = 100m + 100m = 200m * 1/1000 = 0.2 kms
RS = 80 + 80 = 160 kmph
T = (0.2/160) * 3600 = 4.5 sec
ANSWER:A
Answer: A
Question: 14, 35, 49, 56, 91, 126
In the sequence above, each term is related with the others. Which of the following could not be a term in the sequence?
Options:
A)560
B)259
C)562
D)686
E)847
Rationale: Simplifying the question into easier words we just need to find which of the numbers is not divisible by 7
clearly the answer is 562 because if we divide 562 by 7 we get a remainder of 80.28
Correct answer - C
Answer: C
Question: The product of all the prime numbers less than 12 is closest to which of the following powers of 10?
Options:
A)a) 10^9
B)b) 10^8
C)c) 10^7
D)d) 10^3*2.31
E)e) 10^5
Rationale: Group these numbers so as to get product close to a multiple of 10, so they can be rewritten as (2*5)(3*7)(11)= 10*21*11
Now take out power of 10 from each number and rewrite
10*10*10(1*2.1*1.1) or 10^3*(1*2.1*1.1) =2.31*10^3
D
Answer: D
Question: An urn contains 10 black and 5 white balls. Two balls are drawn from the urn one after the other
without replacement. What is the probability that both drawn balls are black?
Options:
A)1/5
B)3/7
C)2/5
D)3/5
E)2/7
Rationale: Let E and F denote respectively the events that first and second ball drawn
are black. We have to find P(E n F) or P (EF).
Now P(E) = P (black ball in first draw) = 10/15
Also given that the first ball drawn is black, i.e., event E has occurred, now there are 9 black balls and five white balls left in the urn. Therefore, the probability that the second ball drawn is black, given that the ball in the first draw is black, is nothing but the conditional probability of F given that E has occurred.
That is P(F|E) = 9/14
By multiplication rule of probability, we have
P (E n F) = P(E) P(F|E)
= 10/15 × 9/14 = 3/7
B
Answer: B
Question: A and B invests Rs.10000 each, A investing for 8 months and B investing for all the 12 months in the year. If the total profit at the end of the year is Rs.25000, find their shares?
Options:
A)Rs.15009
B)Rs.15029
C)Rs.15072
D)Rs.15000
E)Rs.15021
Rationale: The ratio of their profits A:B = 8:12 = 2:3
Share of A in the total profit = 2/5 * 25000 = Rs.10000 Share of A in the total profit
= 3/5 * 25000
= Rs.15000
Answer: D:
Answer: D
Question: Three positive integers a, b, and c are such that their average is 18 and a ≤ b ≤ c. If the median is (a + 11), what is the least possible value of c?
Options:
A)21
B)23
C)25
D)27
E)29
Rationale: Solution:
We know that the average value is 18 therefore (a+b+c)/3 = 18
so a+b+c = 54
and b = a + 11
therefore a + (a + 11) + c = 54
The least value of c is when c = b
so take c = a + 11
hence, a + (a + 11) + (a + 11) = 54
i.e., a = 32/3 a non integer therefore c is not equal to b
so take c = b+1 therefore c = a+12
a + (a + 11) + (a + 12) = 54
i.e., a= 31/3 again a non integer therefore c is not equal to b+1
next take c= b+2 therefore c = a+13
a + (a + 11) + (a + 13) = 54
i.e., a=30/3 = 10
hence, a = 10, b = 21, and c = 23
Answer: B
Answer: B
Question: At a summer camp with 1,200 participants, 1/2 of the campers are aged 8 to 12. Next year, the number of campers aged 8 to 12 will increase by 1/3. After this change, what percentage of the total 1,200 campers will the 8- to 12-year-olds represent?
Options:
A)66 2/3%
B)60%
C)50%
D)45%
E)40%
Rationale: Total - 1,200 participants
campers are aged 8 to 12 = (1/2)*1200 = 600
Next year, campers are aged 8 to 12 = (4/3)*600 = 800
Percentage = (800/1200)*100 = 66 2/3%
Answer: Option A
Answer: A
Question: Niall's income is 60% less than Rex's income, and Sam's income is 25% less than Niall's income. If Rex gave 60% of his income to Sam and 40% of his income to Niall, Niall's new income would be what fraction of Sam's new income?
Options:
A)8/9
B)11/12
C)8/13
D)11/13
E)12/13
Rationale: We can take some easy numbers and make calculations simpler.
Let R ( Rex's income) = 100
Q (Niall's income) = 40%R = 40
S (Sam's income) = 75% Q = (3/4)*40 = 30
Now, if Rex gives 40% to Niall --> Q = 40 + 40 = 80
60% given to Sam --> S = 30+60 = 90
The ratio is : Q/S = 80/90 = 8/9= A
Answer: A
Question: A train 360 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 160 m long?
Options:
A)41.6 sec
B)11 sec
C)88 sec
D)19 sec
E)10 sec
Rationale: Speed = 45 * 5/18 = 25/2 m/sec
Total distance covered = 360 + 160 = 520 m
Required time = 520 * 2/25 = 41.6 sec
Answer: A
Answer: A
Question: How many kgs of flour worth 25 per kg must be blended with 30 kgs of flour worth ` 30 per kg so that by selling the blended variety at X 30 per kg there should be a gain of 10%?
Options:
A)32 kg
B)40 kg
C)36 kg
D)42 kg
E)None of these
Rationale: (x * 25) + (30 * 30) / (x + 30)
= 11/10 * 30(x + 30)
On solving the equation, x = 36.
Answer:C
Answer: C
Question: I bought two books; for Rs.480. I sold one at a loss of 15% and other at a gain of 19% and then I found each book was sold at the same price. Find the cost of the book sold at a loss?
Options:
A)288
B)280
C)268
D)256
E)876
Rationale: x*(85/100)
= (480 - x)119/100
x = 280
Answer:B
Answer: B
Question: The average salary of all the workers in a workshop is Rs.8000. The average salary of 7 technicians is Rs.12000 and the average salary of the rest is Rs.6000. How many workers are there in the workshop?
Options:
A)21
B)22
C)23
D)24
E)25
Rationale: Explanation:
Let the number of workers = x
Given that average salary of all the workers = Rs.8000
Then, total salary of all workers = 8000x
Given that average salary of 7 technicians is Rs.12000
=> Total salary of 7 technicians = 7 × 12000 = 84000
Count of the rest of the employees = (x - 7)
Average salary of the rest of the employees = Rs.6000
Total salary of the rest of the employees = (x - 7)(6000)
8000x = 84000 + (x - 7)(6000)
=> 8x = 84 + (x - 7)(6)
=> 8x = 84 + 6x - 42
=> 2x = 42
=> x = 42/2 = 21
Answer: Option A
Answer: A
Question: I had about Rs.14.40 in one rupee coins and 20 paise coins when I went out for shopping.
When I returned, I found that number of 20 paise coins and 1 rupee coins are exactly as 1
rupee and 20 paise coins respectively, that I had originally. I came back with one third of
what I had started out with. How many one rupee coins did I have initially?
Options:
A)10
B)12
C)14
D)16
E)18
Rationale: Let x be number of 1 rupee coins and y be number of 20 paise coins initially.
Initially : 1x + .2y =14.40
Finally : 1y + .2x = 4.80 (as number of coins interchange)
Solving we get, x=14 and y=2
Therefore there was 14 one rupee coins and 2 20 paise coins initially.
ANSWER:C
Answer: C
Question: If f and p are two positive integers and f/p = 1.35, then f can equal which one of the following?
Options:
A) 21
B) 28
C) 20
D) 27
E) 23
Rationale: f/p = 1.35 = 135/100 = 27/20
So, p COULD equal 27
Answer: D
Answer: D
Question: During the first two weeks of March, the total rainfall in Springdale was 25 inches. If the rainfall during the second week was 1.5 times the rainfall during the first week, what was the rainfall in inches during the second week of March?
Options:
A)10
B)12
C)15
D)16
E)18
Rationale: Let x be the rainfall in the first week. Then 1.5x was the rainfall in the second week.
2.5x = 25
x = 10
The rainfall during the second week was 1.5 * 10 = 15 inches
The answer is C.
Answer: C
Question: subash can copy 50 pages in 10 hrs.subash and prakash together can copy 300 pages in 40 hours.in how much time prakash can copy 30 pages.
Options:
A)8
B)10
C)12
D)14
E)16
Rationale: subhas 's 1 hr copy page=50/10=5 page
(subhas+prakash)'s 1 hr copy page=300/40=7.5 page
from above prakash's 1 hr copy page= 2.5 page
so time taken in 30 page's copy =(30/2.5)=12 hrs
ANSWER:C
Answer: C
Question: One fourth of a solution that was 12% salt by weight was replaced by a second solution resulting in a solution that was 16 percent sugar by weight. The second solution was what percent salt by weight?
Options:
A)28%
B)34%
C)22%
D)18%
E)8.5%
Rationale: consider total solution to be 100 liters and in this case you'll have: 75*0.12+25*x=100*0.16 --> x=0.28.
Answer: A.
Answer: A
Question: Daniel went to a shop and bought things worth Rs. 25, out of which 60 Paise went on sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax free items?
Options:
A)A)14.4
B)B)20
C)C)21.3
D)D)21.5
E)E)22
Rationale: Total cost of the items he purchased = Rs.25
Given that out of this Rs.25, 30 Paise is given as tax
=> Total tax incurred = 60 Paise = Rs.60/100
Let the cost of the tax free items = x
Given that tax rate = 6%
∴ (25−60/100−x)6/100 = 60/100
⇒ 6(25 −0.6 −x) = 60
⇒ (25 − 0.6 − x) = 10
⇒ x = 25 − 0.6 − 10 = 14.4
A
Answer: A
Question: how many such letters pairs are in word MONKEY having same no. of letters left between them in the word as they have in the series
Options:
A)1
B)2
C)3
D)4
E)5
Rationale: one pair is observed that is (ON) as there is no alphabet in between them and in series also threre is no letter in between them.
ANSWER:A
Answer: A
Question: A train is 360 meter long is running at a speed of 45 km/hour. In what time will it pass a bridge of 140 meter length?
Options:
A)42 seconds
B)47 seconds
C)40 seconds
D)49 seconds
E)45 seconds
Rationale: Speed = 45 Km/hr = 45*(5/18) m/sec = 25/2 m/sec
Total distance = 360+140 = 500 meter
Time = Distance/speed
= 500 * (2/25) = 40 seconds
Answer:C
Answer: C
Question: How many multiples of 8 are less than 4500, and also multiples of 12?
Options:
A)104.6
B)187.5
C)625.6
D)450.5
E)467.4
Rationale: LCM of 8 & 12 = 24
Tried dividing 4500 by 24
Got quotient 187.5 'So B is answer
Answer: B
Question: Country C imposes a two-tiered tax on imported cars: the first tier imposes a tax of 20% of the car's price up to a certain price level. If the car's price is higher than the first tier's level, the tax on the portion of the price that exceeds this value is 10%. If Ron imported a $20,000 imported car and ended up paying $2500 in taxes, what is the first tier's price level?
Options:
A)$6000
B)$5500
C)$5000
D)$5700
E)$5800
Rationale: Let T be the tier price, P be total price = 20000
Per the given conditions:
0.20T + 0.10(P-T) = 2500
0.20T+0.10*20000-0.10T =2500
0.10T +2000 =2500
0.10T = 2500-2000 = 500
T = 500/0.10 =5000
Answer C
Answer: C