divelab/Sys2Bench huggingface dataset:
Question: Before leaving home for the town of Madison, Pete checks a map which shows that Madison is 6 inches from his current location, Gardensquare. Pete arrives in Madison 2.5 hours later and drove at an average speed of 60 miles per hour. At what scale, in inches per mile, is the map drawn?
Options:
A)1/25
B)1/30
C)1/10
D)2
E)30
Rationale: Pete covered 2.5*60=150 miles which correspond to 6 inches on the map --> scale in inches per mile is 6/150=1/25.
Answer: A.
Answer: A
Question: An article was sold after a discount of 20% and there was a gain of 20%. If the profit made on it was Rs. 6 less than the discount offered on it, find its selling price?
Options:
A)72
B)44
C)66
D)01
E)11
Rationale: Let CP = Rs. 100x
SP = Rs. 120x
MP = 120x/80 * 100 = Rs. 150x
D = Rs. 150x - Rs. 120x = Rs. 30x
D - P = 30x - 20x = Rs. 6, 10x = Rs. 6
120x = 120/10 * 6 = Rs. 72
Answer:A
Answer: A
Question: One train is running with a speed 60 kmph and its length is 110 metres. Calculate the time by which it will pass a man running opposite with speed of 6 kmph.
Options:
A)6 sec
B)3 sec
C)2 sec
D)1 sec
E)10 sec
Rationale: ==> (60+6) = 66 km/hr
m/sec = 66*5/18
55/3 k/sec
time = 110*3/55
= 6 sec
ANSWER A
Answer: A
Question: If y is the smallest positive integer such that 3,150 multiplied by y is the square of an integer, then y must be
Options:
A)2
B)5
C)6
D)7
E)14
Rationale: 3150*y = A^2
3 * 1050 * y = A^2
3*5*210*y = A^2
3*5*7*3*2*5*y = A^2
2*3^2*5^2*7*y = A^2
Concept: The factors of squared integer should occur in pair. So, the only numbers left are 2*7
Hence 14	;
ANSWER:E
Answer: E
Question: In how many ways can five girls stand in line if Maggie and Lisa cannot stand next to each other?
Options:
A)112
B)96
C)84
D)72
E)60
Rationale: 1. the total number of permutations: 5! = 120
2. Let's consider Maggie and Lisa as one object, then the total number of permutations with Maggie and Lisa together: 4! = 24.
3. Take into account that [Maggie, Lisa] and [Lisa, Maggie] are different.
4. Maggie and Lisa cannot stand next to each other in: 120 - 2*24 = 72 ways.
ANS:D
Answer: D
Question: If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:
Options:
A)50 km
B)56 km
C)70 km
D)80 km
E)90 km
Rationale: Explanation:
Let the actual distance travelled be x km.
Then,	x/10 =x + 20/14
14x = 10x + 200
4x = 200
x = 50 km.
ANSWER IS A
Answer: A
Question: A man can row upstream at 25 kmph and downstream at 45 kmph, and then find the speed of the man in still water?
Options:
A)86
B)67
C)35
D)15
E)17
Rationale: US = 25
DS = 45
M = (45 + 25)/2
= 35
Answer: C
Answer: C
Question: Which is greater than -1?
Options:
A)-5
B)-4
C)-3
D)-2
E)0
Rationale: -1 greater than 0.
Answer: E
Answer: E
Question: In how many different ways can 6 people be seated in a room with 8 chairs?
Options:
A)20,160
B)181,440
C)403,200
D)1,814,400
E)3,628,800
Rationale: Order doesn't matter
With 8 chairs and only 6 to seat
6!- Number of ways the 6 can seat on the chair
8C2 - Number of ways the 2 empty sits can be vary with the 6 seated
6! * 8C2 = 20,160 Answer - A
Answer: A
Question: Madhav ranks seventeenth in a class of thirtyone. What is his rank from the last?
Options:
A)13
B)14
C)15
D)16
E)17
Rationale: (Rank from top) + (Rank from bottom) - 1 = Total students
17 + x - 1 = 31
x = 15
ANSWER:C
Answer: C
Question: A certain business produced x rakes each month form November through February and shipped x/2 rakes at the beginning of each month from March through October. The business paid no storage costs for the rakes from November through February, but it paid storage costs of $0.20 per rake each month from March through October for the rakes that had not been shipped. In terms of x, what was the total storage cost, in dollars, that the business paid for the rakes for the 12 months form November through October?
Options:
A)2.80x
B)1.20x
C)1.40x
D)1.60x
E)3.20x
Rationale: because we have a total of 4X
Also from Mar- Oct the rakes will be deducted by 1/8 X
so
In Apr they pay for the storage 0.2 * 4X * 7/8
In May they pay for the storage 0.2 * 4X * 6/8
In Jun they pay for the storage 0.2 * 4X * 5/8
In Jul they pay for the storage 0.2 * 4X * 4/8
In Aug they pay for the storage 0.2 * 4X * 3/8
In Sep they pay for the storage 0.2 * 4X * 2/8
In Oct they pay for the storage 0.2 * 4X * 1/8
total = 0.2 * 4X * 1/8 * [ 1+2+3+4+5+6+7]
= 0.2 * X/2 * (28)
= 2.8X
A
Answer: A
Question: A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Options:
A)29
B)77
C)28
D)10
E)12
Rationale: lb = 150
2(l + b) = 50 => l + b = 25
l – b = 5
l = 15 b = 10
Answer:D
Answer: D
Question: Goldenrod and No Hope are in a horse race with 6 contestants. How many different R arrangements of finishes are there if No Hope always finishes before Goldenrod and if all of the horses finish the race?
Options:
A) 720
B) 360
C) 120
D) 24
E) 21
Rationale: no hope finishing before goldenrod= 1/2 of the times
therefore the different R arrangements are 1/2* 6! = 360 = B
Answer: B
Question: Ram, who is half as efficient as Krish, will take 27 days to complete a task if he worked alone. If Ram and Krish worked together, how long will they take to complete the task?
Options:
A)16 days
B)12 days
C)9 days
D)6 days
E)18 days
Rationale: Number of days taken by Ram to complete task = 27
Since Ram is half as efficient as Krish , Amount of work done by Krish in 1 day = Amount of work done by Ram in 2 days
If total work done by Ram in 27 days is 27w
Amount of work done by Ram in 1 day = w
Amount of work done by Krish in 1 day = 2w
Total amount of work done by Krish and Ram in a day = 3w
Total amount of time needed by Krish and Ram to complete task = 27w/3w = 9 days
Answer C
Answer: C
Question: Kelvin earns $60 a week from his job. His income increased and now makes $70 a week. What is the percent increase?
Options:
A)16.66%
B)16.87%
C)17.62%
D)17.85%
E)18%
Rationale: Increase = (10/60)*100 = (1/6)*100 = 16.66%.
A
Answer: A
Question: A man took loan from a bank at the rate of 13% p.a. S.I. After 3 years he had to pay Rs. 5400 interest only for the period. The principal amount borrowed by him was?
Options:
A)Rs. 1846
B)Rs. 18846
C)Rs. 13846
D)Rs. 2000
E)Rs. 14846
Rationale: Principal = (100 * 5400) / (13 * 3) = Rs. 13846
ANSWER:C
Answer: C
Question: You enter a weight loss challenge game and manage to lose 10% of your body weight. For the final weigh in you are forced to wear clothes that add 2% to your weight. What percentage of weight loss is measured at the final weigh in?
Options:
A)13%
B)8.2%
C)9%
D)14%
E)12%
Rationale: (100%-10%)*(100%+2%) = 0.90*1.02 = 8.2%
The weigh in records your weight loss at 8.2%!
The Answer is B
Answer: B
Question: A welder received an order to make a 1 million liter cube-shaped tank. If he has only 5x2 meter sheets of metal that can be cut, how many metal sheets will be required for this order? (1 cubic meter = 1,000 liters)
Options:
A)92
B)60
C)82
D)78
E)75
Rationale: The question say:A welder received an order to make a 1 million liter cube-shaped tank. (1 cubic meter = 1,000 liters)
In other words, the tank is going to have a volume of 1000 cubic meters. That would equal 1 million liters.
A cube with a volume of 1000 cubic meters must be (10 meters) x (10 meters) x (10 meters).
The question doesn't specify whether this tank should have a closed top or an open top. (The real GMAT is good about specifying things like that.) Here, we are going to assume a closed top, only because if the top is open, we don't use enough metal --- we get an answer smaller than any of the answer choices. A closed-top cube, a full cube, has 6 sides, each of which is (10 meters) x (10 meters). That's a total surface area of 600 sq m.
The question tells us:he has only 5x2 meter sheets of metal that can be cut.
Each sheet has an area of 10 sq m. How many of these need to fill up 600 sq m? 600/110 = 60. He needs 60 sheets.
Answer =B
Answer: B
Question: Three numbers are in the ratio 3:4:5 and their L.C.M. is 240. Their H.C.F is?
Options:
A)2
B)3
C)4
D)5
E)6
Rationale: Let the numbers be 3x,4x and 5x
their L.C.M. = 60x
60x = 240
x = 4
The numbers are 3*4 , 4*4 , 5*4
Hence required H.C.F. = 4
Answer is C
Answer: C
Question: In how many different ways can the letters of the word ‘MODE’ be arranged?
Options:
A)60
B)24
C)36
D)12
E)16
Rationale: B
24
The word SMART has 4 distinct letters.
Number of arrangements = 4!
= 4 × 3 × 2 × 1 = 24
Answer is B
Answer: B
Question: WINK,INC recently conducted a survey and found that 180,000 of its customers live in rural areas. if the number of it customers who live in urban areas is 200 percents grater than the numbers of customers who live in rural areas, how many of WINK,INC customers live in urban areas ?
Options:
A)200,000
B)216,000
C)360,000
D)480,000
E)540.0
Rationale: Let's say that we have a starting value of X...
100% of X = X
100% MORE than X = X + X = 2X
200% MORE than X = X + 2X = 3X
300% MORE than X = X + 3X = 4X
Etc.
Here, we're told that 180,000 customers live in rural areas and the number who live in urban areas is 200% GREATER than the number who live in rural areas. That means that the number who are in urban areas is 3 times the number in rural areas...
3(180,000) = 540,000
Final Answer:E
Answer: E
Question: If the price of sugar rises from Rs. 6 per kg to Rs. 7.50 per kg, a person, to have no increase in the expenditure on sugar, will have to reduce his consumption of sugar by
Options:
A)15%
B)20%
C)25%
D)30%
E)none
Rationale: Sol.
Let the original consumption = 100 kg and new consumption = x kg.
So, 100 x 6 = x × 7.50 = x = 80 kg.
∴ Reduction in consumption = 20%.
Answer B
Answer: B
Question: The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 8 years ago was 20 years. The present age of the husband is:
Options:
A)20 years
B)30 years
C)60 years
D)34 years
E)35 years
Rationale: D
34 years
Sum of the present ages of husband, wife and child = (27 x 3 + 3 x 3) years = 90 years.
Sum of the present ages of wife and child = (20 x 2 + 8 x 2) years = 56 years.
Husband's present age = (90 - 56) years = 34 years.
Answer: D
Question: A company conducted a survey about its two brands, A and B. x percent of respondents liked product A, (x – 20) percent liked product B, 23 percent liked both products, and 23 percent liked neither product. What is the minimum number W of people surveyed by the company?
Options:
A)46
B)80
C)W.90
D)W.100
E)200
Rationale: 100 = x + x - 20 + 23 - 23
x = 60,
So, Product A = 60%, Product B = 40%, Both = 23%, Neither = 23%
23% of the total no. of people should be an integer. So, A,BC are out.
60% of D and 40% of D are both integers. So, D satisfies all conditions.
So, answer is D.
Answer: D
Question: Stephanie, Regine, and Brian ran a 20 mile race. Stephanie and Regine's combined times exceeded Brian's time by exactly 2 hours. If nobody ran faster than 8 miles per hour, who could have won the race?
I. Stephanie
II.Brian
III. Regine
Options:
A)I only
B)II only
C)I or III only
D)I or II only
E)I, II, or III
Rationale: Given that S+R=B+2, where S, R, and B are times in which Stephanie, Regine, and Brian completed the race.
Min time one could complete the race is 20/8=2.5 hours. Let's see if Brian could have won the race: if he ran at the fastest rate, he would complete the race in 2.5 hours, so combined time needed for Stephanie and Regine would be S+R=B+2=4.5 hours, which is not possible as sum of two must be more than or equal the twice the least time: 2*2.5=5. So Brian could not have won the race.
There is no reason to distinguish Stephanie and Regine so if one could have won the race, another also could. So both could have won the race.
Answer: C.
Answer: C
Question: The average monthly salary of 20 employees in an organisation is Rs. 1200. If the manager's salary is added, then the average salary increases by Rs. 100. What is the manager's monthly salary ?
Options:
A)3600
B)3890
C)3300
D)2789
E)2891
Rationale: Explanation:
Manager's monthly salary Rs. (1300 * 21 - 1200 * 20) = Rs. 3300.
Answer: C
Answer: C
Question: Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 sec. What is the length of the fast train?
Options:
A)27 7/6
B)27 7/5
C)27 7/4
D)27 7/9
E)27 7/3
Rationale: Relative speed = (40 - 20) = 20 km/hr.
= 20 * 5/ 18 = 50/9 m/sec.
Length of faster train = 50/9 * 5 = 250/9 = 27 7/9 m.
Answer:D
Answer: D
Question: Car A travels at three times the average speed of car B. Car A started to travel at 12:00 o'clock, car B started to travel at 16:00 o'clock. What is the speed of car B (in Km/h) if the total distance that both cars traveled until 18:00 was 2000 Km?
Options:
A)10.
B)25.
C)30.
D)38.
E)100.
Rationale: Total distance= Distance travelled by A +Distance travelled by car B
Distance= speed*time
Distance of A= 3x * 6
Distance of B= x*2
(3x * 6) + (x*2) = 2000
x= 100 KM/hr
E is the answer
Answer: E
Question: What will come in place of the x in the following Number series? 5,28,57,88,125
Options:
A)125
B)153
C)166
D)187
E)193
Rationale: 28=23+5
57=29+28
88=31+57
125=37+88
166=41+125
=166
C
Answer: C
Question: Two numbers N and 12 have LCM = 48 and GCF = 8. Find N.
Options:
A)24
B)34
C)44
D)54
E)32
Rationale: The product of two integers is equal to the product of their LCM and GCF. Hence.
12 × N = 48 × 8
N = 48 × 8 / 12 = 32
correct answer E
Answer: E
Question: 20% of a number is more than 40% of 140 by 80. Find the number?
Options:
A)680
B)620
C)652
D)520
E)458
Rationale: (20/100) * X – (40/100) * 140= 80
1/5 X = 136
X = 680
Answer:A
Answer: A
Question: A person want to give his money of $1800 to his 3 children A,B,C in the ratio 2:3:4. What is the B's share?
Options:
A)$700
B)$600
C)$900
D)$500
E)$400
Rationale: B's share = 1800*3/9 = $600
Answer is B
Answer: B
Question: A car was driving at 60 Km/h for 20 minutes, and then at 90Km/h for another 40 minutes. What was its average speed?
Options:
A)80.
B)75
C)70
D)65.
E)54.
Rationale: driving at 60 Km/h for 20 minutes ,distance covered = 60*1/3=20 km
driving at 90 km/h for 40 minutes ,distance covered = 90*2/3=60 km
average speed = total distance/total time = 80/1 = 80 km/h
ANSWER:A
Answer: A
Question: A seller has 1000 kg of rice part of which he sells at 8% profit and the rest at 18% profit. He gains 14%. The quantity sold at 18% profit is?
Options:
A)200 kg
B)300 kg
C)400 kg
D)600 kg
E)800 kg
Rationale: By rule of alligation,
Profit% by selling 1st part	Profit% by selling 2nd part
8	18
Net % profit
14
18-14=4	14-8=6
=> Quantity of part1 : Quantity of part2 = 4 : 6 = 2 : 3
Total quantity is given as 1000 kg. So quantity of part2 (quantity sold at 18% profit)
=1000×35
= 600 kg
D
Answer: D
Question: N = 1/3 + 1/4
What is the value of N?
Options:
A)7/12
B)1/6
C)1/8
D)5/17
E)12/7
Rationale: To sum 1/3 and 1/4
Multiply both sides by 12
12 * N = 12 * 1/3 + 12 * 1/4
12 * N = 4 + 3
N = 7/12
Ans: A
Answer: A
Question: If x and y are different integers and x^2 = xy, which of the following must be true ?
I. x = 0
II. y = 0
III. x = y
Options:
A)I only
B)II only
C)III only
D)I and III only
E)I, II, and III
Rationale: Answer choice A is correct.
The question gives you x^2=xy
you can simplify that as x^2-xy=0
x(x-y)=0 the solution will be either x=0 or x=y, since x and y are different integers x cannot equal y, that leaves you x=0 to be the only answer.
Answer D
Answer: D
Question: If the number 517*324 is completely divisible by 3, then the smallest whole number in the place of * will be?
Options:
A)2
B)4
C)6
D)7
E)8
Rationale: Sum of digits = (5 + 1 + 7 + x + 3 + 2 + 4) = (22 + x), which must be divisible by 3.
x = 2.
A)
Answer: A
Question: Which of the following fractions is less than 1/3
Options:
A)22/62
B)15/46
C)15/39
D)2/3
E)1
Rationale: 1/3=0.3333333
22/62=0.35>0.3333
15/46=0.331
ANSWER:B
Answer: B
Question: A monkey tries to ascend a greased pole 14 m high. He ascends 2 m in first minute and slips 1 min next alternate minute. If he continues to ascend in this fashion, how long does he take to reach the top?
Options:
A)22
B)24
C)25
D)26
E)30
Rationale: Monkey ascends 2 m in 1 minutes and slips 1 m in next minute.
It means he ascends
2 - 1 = 1 m in every two minutes.
Take 2 minutes = 1 unit of time.
It will take 12 unit of time to climb 12 m of the pole.
In next 1 minute, he will covered 2 m and reached the top. So,
Total time = 12 unit + 1 = 24 +1 = 25 minutes.
ANSWER : OPTION C
Answer: C
Question: Seven years ago, the combined ages of Amir and Akshay was twice that of Saif. If the sum of the ages of Akshay and Amir, fifteen years hence, is 98 years, what is the present age of Saif?
Options:
A)27 yr
B)35 yrs
C)34 yrs
D)49 yr
E)29 yr
Rationale: Amir -- M
Akshay ..K
Saif .. S
M+K =2S
M+K+30= 98
M+K=68
S= 68/2=34 yrs
ANSWER:C
Answer: C
Question: If each digit in the set of A = {1,2,3,4,5,6,7,8} is exactly used once, in how many ways can the digits be arranged such that the 2 and 5 are not adjacent?
Options:
A)8! / 7!
B)8! - 7!
C)6*7!
D)8!/2!
E)7!
Rationale: The answer should be the (total arrangements) - (arrangements when 2 and 5 are adjacent).
The number of ways to arrange 8 units is 8!
If we think of 2 and 5 as one single unit, the number of arrangements is 7!
Note that 2 and 5 can have two arrangements, so we multiply by 2 to get 2*7!
The total number of valid arrangements is 8! - 2*7! = 8*7! - 2*7! = 6*7!
The answer is C.
Answer: C
Question: A producer of tea blends two varieties of tea from two tea gardens one costing Rs 18 per kg and another Rs 20 per kg in the ratio 5 : 3. If he sells the blended variety at Rs 21 per kg, then his gain percent is
Options:
A)12%
B)13%
C)14%
D)15%
E)16%
Rationale: Explanation:
Suppose he bought 5 kg and 3 kg of tea.
Cost Price = Rs. (5 x 18 + 3 x 20) = Rs. 150.
Selling price = Rs. (8 x 21) = Rs. 168.
Profit = 168 - 150 = 18
So, Profit % = (18/150) * 100 = 12%
Option A
Answer: A
Question: 7 teams compete in a track competition. If there are 15 events in the competition, no event ends in a tie, and no team wins more than 3 events, what is the minimum possible number of teams that won at least one event?
Options:
A)3
B)4
C)5
D)6
E)7
Rationale: 3(max wins) x 5 = 15 (5 teams win three events)
The answer is C.
Answer: C
Question: Each factor of 240 is inscribed on its own plastic ball, and all of the balls are placed in a jar. If a ball is randomly selected from the jar, what is the probability that the ball is inscribed with a multiple of 15?
Options:
A)1/16
B)5/42
C)1/8
D)3/16
E)1/4
Rationale: the # of factors 240 has is 20;
so out of 20 factors only four are multiples of 15: 15, 30, 60, 120 and 240, itself;
So, the probability is 5/20=1/4.
Answer: E.
Answer: E
Question: If Jake loses 35 pounds, he will weigh thrice as much as his sister. Together they now weigh 275 pounds. What is Jake's present weight, in pounds?
Options:
A) 131
B) 135
C) 139
D) 147
E) 188
Rationale: J = Jake’s current weight, in pounds
S = Sister’s current weight, in pounds
We are told that “If Jake loses 8 pounds, he will weigh twice as much as his sister.We put this into an equation:
J – 35 = 3S
J = 3S + 35 (Equation 1)
Next, we are told that “Together they now weigh 275 pounds.” We can also put this into an equation.
J + S = 275 (Equation 2)
To solve this equation, we can substitute 2S + 8 from Equation 1 for the variable J in Equation 2:
3S + 35 = 275-S
4S = 240
S = 60
J + 60 = 275
J = 215
Answer: E
Answer: E
Question: If the radius of a circle is diminished by 10%, then the area is diminished by:
Options:
A)200%
B)210%
C)300%
D)310%
E)None of these
Rationale: Explanation:
Let the original radius be R cm. New radius = 2R
Area=πR2
New Area =π2R2
=4πR2
Increase in area =(4πR2−πR2)=3πR2
Increase percent =3πR2 /πR2∗100=300%
Option C
Answer: C
Question: The distance from Steve's house to work is 28 Km. On the way back Steve drives twice as fast as he did on the way to work. Altogether, Steve is spending 6 hours a day on the roads. What is Steve's speed on the way back from work?
Options:
A)5.
B)10.
C)14.
D)15.
E)20.
Rationale: Time is in the ratio 2:1 :: to: fro office
Therefore, 2x+1x=6 hrs
Time take to come back - 2 hrs, distance travelled - 28km => Speed = 14kmph
C
Answer: C
Question: Which of the following numbers is divisible by 4?
Options:
A)27767
B)10224
C)26778
D)26679
E)26711
Rationale: 10224. This is the only option with last two digits divisible by 4
Answer:B
Answer: B
Question: A person's present age is two-fifth of the age of his mother. After 8 years, he will be one-half of the age of his mother. How old id the mother at present?
Options:
A)18
B)27
C)40
D)37
E)29
Rationale: Let the mother's present age be x years. Then, the person's present age = 2/5 x years.
(2/5 x + 8) = 1/2 (x + 8)
2(2x + 40) = 5(x + 8) => x = 40
Answer: C
Answer: C
Question: A no. when divided by the sum of 555 and 445 gives 2times their difference as quotient & 30 as remainder. Find the no. is?
Options:
A)122456
B)145778
C)456678
D)235467
E)220030
Rationale: (555 + 445) * 2 * 110 + 30 = 220000 + 30 = 220030
E
Answer: E
Question: How many three digits no. can be formed also including the condition that the no. can have at least two same digits ?
Options:
A)458
B)249
C)251
D)252
E)254
Rationale: total 3 digit no. is-9*10*10=900
and total no. of non repeated digits are=9*9*8=648
So the total no. of repeated digits(2 & 3 repeated)=900-648=252
ANSWER:D
Answer: D
Question: Two passenger trains start at the same hour in the day from two different stations and move towards each other at the rate of 16 kmph and 21 kmph respectively. When they meet, it is found that one train has traveled 60 km more than the other one. The distance between the two stations is?
Options:
A)738 km
B)444 km
C)849 km
D)935 km
E)949 km
Rationale: 1h ----- 5
? ------ 60
12 h
RS = 16 + 21 = 37
T = 12
D = 37 * 12 = 444
Answer:B
Answer: B
Question: Calculate the fourth proportional to 6.1, 7.2 and 9.3?
Options:
A)2.98
B)11.98
C)19.98
D)10.98
E)1.98
Rationale: Explanation:
Formula = Fourth propotional = (b × c)/a
A = 6.1 , B = 7.2 and C = 9.3
(7.2 × 9.3)/6.1 = 10.98
Answer: Option D
Answer: D
Question: Find the greatest number that will divide 400, 435 and 541 leaving 9, 10 and 14 as remainders respectively
Options:
A)19
B)17
C)13
D)9
E)8
Rationale: Explanation:
Answer will be HCF of (400-9, 435-10, 541-14)
HCF of (391, 425, 527) = 17
Option B
Answer: B
Question: Find the odd man out
864, 420, 200, 86, 40, 16, 6
Options:
A)420
B)200
C)16
D)40
E)86
Rationale: 6x2+4=16
16x2+8=40
40x2+12=92
92x2+16=200.. and so on. 86
ANSWER:E
Answer: E
Question: A man can row downstream at the rate of 12 Km/hr and upstream at 6 Km/hr. Find man's rate in still water and the rate of current?
Options:
A)9,6
B)6,3
C)9,3
D)6,6
E)None of these
Rationale: Explanation:
Rate of still water = 1/2 (12 + 6) = 9 Km/hr
Rate of current = 1/2 (12-6) = 3 Km/hr
Answer: Option C
Answer: C
Question: A shopkeeper sold an book offering a discount of 5% and earned a profit of 23.5%. What would have been the percentage of profit earned if no discount was offered?
Options:
A)140
B)120
C)130
D)110
E)150
Rationale: C
130%
Let C.P. be $100.
Then, S.P. = $123.50
Let marked price be $x. Then, 95/100 x = 123.50
x = 12350/95 = $130
Now, S.P. = $130, C.P. = $100
Profit % = 30%.
Answer: C
Question: Jonathan’s grandparents lend $50,000 to Jonathan at a simple annual interest rate of 10%. He pays them back 5 years later. How much do they receive?
Options:
A)50,000∗0.1^5
B)50,000∗0.5
C)50,000∗1^.5
D)50,000∗1.5
E)(50,000∗0.1)^5
Rationale: if you are like me and have used S.I = P x R x T formula in school, while the question is asking for Amount in 5 years. so (D) 50,000∗ 1.5
Ans : D
Answer: D
Question: A girl sold her pen for Rs.39 and got a percentage of profit numerically equal to the cost price. The cost price of that pen is:
Options:
A)130
B)90
C)60
D)30
E)20
Rationale: Let Cost Price was Rs. X then % profit must be X%.
Selling Price = Rs. 39
Cost price + profit = 39
X + X% of X = 39
X + (X^2)/100 = 39
100 X + X^2 = 3900
X^2 + 100X - 3900 = 0
X^2 +130X - 30X - 3900 = 0
X = -130, 30
Cost price cannot be negative so Cost Price was Rs. 30.
ANSWER : OPTION D
Answer: D