divelab/Sys2Bench huggingface dataset:
Question: A train 200 m long passes a man, running at 6 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is?
Options:
A)36
B)50
C)78
D)66
E)22
Rationale: Speed of the train relative to man
= (200/10) m/sec = 20 m/sec. [20 * (18/5)] km/hr
= 72 km/hr. Let the speed of the train be x km/hr. Then, relative speed = (x - 6) km/hr. x - 6
= 72 ==> x
= 78 km/hr.
Answer:C
Answer: C
Question: M and N started a business by investing Rs.4000/- and Rs.5000/- respectively. Find the M’s share out of a total profit of Rs.1800:
Options:
A)Rs.500/-
B)Rs.550/-
C)Rs.600/-
D)Rs.650/-
E)Rs.800/-
Rationale: M = Rs.4000/-
N = Rs.5000/-
M share 4 parts & N share 5 parts
Total 9 parts -----> Rs.1800/-
----> 1 part -------> Rs.200/-
M share = 4 parts -----> Rs.800/-
E
Answer: E
Question: What is the distance covered by a car if it travels with a speed of 160 kmh for 5 hours?
Options:
A)350 km
B)400 km
C)800 km
D)600 km
E)650 km
Rationale: Distance= Time x Speed
5 x 160 = 800
Answer: C
Answer: C
Question: A certain music store stocks 800 cellos and 600 violas. Of these instruments, there are 100 cello-viola pairs, such that a cello and a viola were both made with wood from the same tree (each tree can make at most one viola and one cello, so there are no pairs other than these 90). If one viola and one cello are chosen at random, what is the probability that the two instruments are made with wood from the same tree?
Options:
A)3/16,000
B)1/4,800
C)3/1,600
D)1/90
E)2/45
Rationale: Solution provided by stanford2012 is correct: 100/800 choosing one of the cellos which has a pair viola, 1/600 choosing the viola which is the pair of chosen cello --> P=100/800*1/600=1/4,800.
Answer: B.
Answer: B
Question: A boy sitting in a train which is travelling at 30 kmph observes that a goods train travelling in a opposite direction, takes 18 seconds to pass him. If the goods train is 350 m long, find its speed.
Options:
A)25
B)30
C)35
D)40
E)45
Rationale: Relative speed = (350/18)m/s = (350/18)*(18/5) = 70 kmph
speed of goods train = 70-30 = 40 kmph
Answer is D
Answer: D
Question: There are three secretaries who work for four departments. If each of the four departments have one report to be typed out, and the reports are randomly assigned to a secretary, what is the probability that all three secretary are assigned at least one report?
Options:
A)8/9
B)64/81
C)12/27
D)16/81
E)5/9
Rationale: "We havé total possibilities N =3^4"
What are these total possibilities? They are the ways in which the 4 reports can be distributed among 3 secretaries so that all reports may go to one secretary, the reports may be distributed among 2 secretaries or they may be distributed among all 3. So such cases are included (4, 0, 0), (0, 4, 0), (2, 2, 0), (1, 3, 0), (1, 1, 2), etc
In how many ways can you give 4 reports to only 1 secretary? You choose the secretary who will get the reports in 3C1 = 3 ways
In how many ways can you give 4 reports to only 2 secretaries? Choose the 2 secretaries in 3C2 ways. Each secretary must get at least one report so you can distribute them in 2 ways:
'1 and 3' - Choose one report in 4C1 ways and give it to one secretary in 2C1 ways. The other secretary gets the other 3 reports.
or
'2 and 2' - Choose 2 reports in 4C2 ways and give to the first secretary. The other secretary gets the other two reports.
Total number of ways is 3C2 * (4C1*2C1 + 4C2) = 42 ways
Note that in your method 2^4 is incorrect. It includes the ways in which all 4 reports go to one secretary.
So this means that in 3 + 42 = 45 ways, at least one secretary gets no report. In the rest of 81 - 45 = 36 ways, each secretary gets at least one report.
Required Probability = 36/81 = 12/27
ANS:C
Answer: C
Question: John and Jane went out for a dinner and they ordered the same dish. Both used a 10% discount coupon. John paid a 15% tip over the original price of the dish, while Jane paid the tip over the discounted price for the coupon. If John paid $0.60 more than Jane, what was the original price of the dish?
Options:
A) 24
B) 34.8
C) 37.8
D) 40
E) 84
Rationale: The difference between the amounts John paid and Jane paid is the deference between 15% of p and 15% of 0.9p:
0.15p - 0.15*0.9p = 0.60 --> 15p - 13.5p = 60 --> p = 40.
Answer: D.
Answer: D
Question: A welder received an order to make a 1 million liter cube-shaped tank. If he has only 2x4 meter sheets of metal that can be cut, how many metal sheets will be required for this order? (1 cubic meter = 1,000 liters)
Options:
A)92
B)90
C)82
D)75
E)78
Rationale: The question say:A welder received an order to make a 1 million liter cube-shaped tank. (1 cubic meter = 1,000 liters)
In other words, the tank is going to have a volume of 1000 cubic meters. That would equal 1 million liters.
A cube with a volume of 1000 cubic meters must be (10 meters) x (10 meters) x (10 meters).
The question doesn't specify whether this tank should have a closed top or an open top. (The real GMAT is good about specifying things like that.) Here, we are going to assume a closed top, only because if the top is open, we don't use enough metal --- we get an answer smaller than any of the answer choices. A closed-top cube, a full cube, has 6 sides, each of which is (10 meters) x (10 meters). That's a total surface area of 600 sq m.
The question tells us:he has only 2x4 meter sheets of metal that can be cut.
Each sheet has an area of 8 sq m. How many of these need to fill up 600 sq m? 600/8 = 75. He needs 75 sheets.
Answer =D
Answer: D
Question: John and David can finish a job together in 6 hours. If John can do the job by himself in 8 hours, what percent of the job does David do?
Options:
A)35%
B)45%
C)25%
D)30%
E)20%
Rationale: You can also plug in numbers. For example, Bob and Alice work at a donut factory and make 24 donuts which is the job ( I picked this as a SMART number).
John on his own works 24/8 = 3 donuts per hour.
John and David work 24/6 = 4 donuts per hour so David works 1 donuts/hour
To find out the percentage, David works 1 donuts/hr x 6 hours = 6 donuts per hour.
Therefore 6 donuts/24donuts = 1/4 = 25%
Answer : C
Answer: C
Question: 8 noun, 3 verbs and 2 adjectives are written on blackboard.we can form sentence by choosing 1 from each available set without caring it makes sense or not.what is the number of ways of doing this??
Options:
A)128
B)188
C)218
D)248
E)288
Rationale: we have to choose one from each set. 1 from 8 nouns and 1 from 3 verbs and 1 from 2 adjectives.
then we have to arrange 3 different sets in 3! ways.
so,
8c1*3c1*2c1*3!=288
ANSWER:E
Answer: E
Question: In a class of 30 students, 5 students did not borrow any books from the library, 12 students each borrowed 1 book, 8 students each borrowed 2 books, and the rest of the students each borrowed at least 3 books. If the average (arithmetic mean) number of books borrowed per student was 2, what is the maximum number of books that any single student could have borrowed ?
Options:
A)5
B)8
C)15
D)18
E)20
Rationale: The average number of books per student was 2means that total of 2*30=60 books were borrowed;
5+12+8=25 students borrowed total of 5*0+12*1+8*2=28 books;
So 60-28=32 books are left to distribute among 30-25=5 students, these 5 arethe rest who borrowed at least 3 books;
Tomaximizethe number of books one student from above 5 could have borrowed we shouldminimizethe number of books other 4 students from 5 could have borrowed. Minimum these 4 students could have borrowed is 3 books per student, so total number of books they could have borrowed is 4*3=12 books. So the 5th student could have borrowed is 32-12=20 books.
Answer: E.
Answer: E
Question: In an examination, a pupil’s average marks were 63 per paper. If he had obtained 20 more marks for his Geography paper and 2 more marks for his History paper, his average per paper would have been 65. How many papers were there in the examination?
Options:
A)8
B)9
C)10
D)11
E)12
Rationale: Let the number of papers be x. Then, 63x + 20 + 2 = 65x
or 2x = 22 or x = 11.
Answer D
Answer: D
Question: Fill in the missing number:
18 14 12 11 ? 10.25
Options:
A)10.1
B)10.4
C)10.2
D)10.5
E)10.3
Rationale: D
10.5
Divide each number by 2 and then add 5 to it.
Answer: D
Question: A diner is having lunch at a salad bar. There are four types of lettuce to choose from, as well as four types of tomatoes, and five types of olives. If the diner picks one type of lettuce, one type of tomato, and one type of olive for the salad, how many total options does the diner have for the salad?
Options:
A)20
B)40
C)60
D)80
E)100
Rationale: 4*4*5 = 80
The answer is D.
Answer: D
Question: The distance between Delhi and Mathura is 200 kms. A starts from Delhi with a speed of 20 kmph at 7 a.m. for Mathura and B starts from Mathura with a speed of 25 kmph at 8 p.m. from Delhi. When will they meet?
Options:
A)10.50 a.m.
B)12.00 a.m.
C)10.30 a.m.
D)11.40 a.m.
E)1.40 a.m.
Rationale: D = 200 â€“ 20 = 180
RS = 20 + 25 = 45
T = 180/45 = 4 hours
8 a.m. + 4 hrs 00 min = 12.00 a.m.
ANSWER:B
Answer: B
Question: In what time will a car 10 m long moving at the rate of 36 kmph pass a telegraph post on its way?
Options:
A)8 sec
B)1 sec
C)9 sec
D)6 sec
E)2 sec
Rationale: T = 10/36 * 18/5
= 1 sec
Answer:B
Answer: B
Question: If 2^(2w) = 8^(w−3), what is the value of w?
Options:
A)3
B)6
C)9
D)12
E)15
Rationale: 2^(2w) = 8^(w−3)
2^(2w) = 2^(3*(w−3))
2^(2w) = 2^(3w-9)
Let's equate the exponents as the bases are equal.
2w = 3w-9
w = 9
The answer is C.
Answer: C
Question: Pipe A can fill the tank in 30 minutes and pipe b can empty the tank in 90 minutes. How long it will take to fill the tank if both pipes are operating together?
Options:
A)30
B)35
C)40
D)45
E)50
Rationale: Pipe A fills 1/30th of the tank in a minute and pipe B empties 1/90th of the tank
(1/30)-(1/90)=(1/x)
2/90=1/x => x=45
Answer: D
Answer: D
Question: An MBA admissions committee is to be formed randomly from 6 second year MBAs for the 3 positions. If Albert and Jane are applicants, what is the probability that Albert will be selected but Jane will not?
Options:
A)10%
B)17%
C)25%
D)30%
E)44%
Rationale: Probability of selecting Albert but not Jane =
Prob(A,J',J')
= 3* 1/6 * 4/5 * 3/4 (J' is Jane is not selected and we multiply by 3 because A , J' and J' can occur in 3 distinct ways)
= 3/10
=30%
Answer D
Answer: D
Question: The average age of students in section A of 125 students is 23 years and the average age of students in section B of 162 students is 25 years. Find the average age of students in both sections taken together?
Options:
A)26 years
B)30years
C)15years
D)24years
E)20years
Rationale: The required average = (125*23+162*25)/125+162 = 24 years
Answer is D
Answer: D
Question: A ratio between two numbers is 4:5 and their L.C.M. is 200. The first number is
Options:
A)60
B)40
C)20
D)15
E)None
Rationale: Sol.
Let the required numbers be 4x and 5x. Then, their L.C.M. is 20x.
∴ 20x = 200⇔ x = 10. Hence, the first number is 40.
Answer B
Answer: B
Question: If a, b, and c are consecutive even positive integers, which of the following could be equal to a + b + c ?
Options:
A)141
B)200
C)312
D)391
E)412
Rationale: The key to answering this question quickly is to realize that a+b+c is a multiple of BOTH 2 and 3. With that information, you can quickly eliminate answer choices. If you don't recognize those two Number Properties though, then you can still get to the correct answer (but it will require a bit more work).
We're told that a, b and c are CONSECUTIVE EVEN INTEGERS, so we could write them algebraically as...
A + (A+2) + (A+4) = 3A + 6
We know that 3A + 6 COULD equal one of those five answers; we just have to find it...
Could 3A + 6 = 141
3A = 135
A = 45
This is NOT an EVEN INTEGER, so 141 is NOT the answer
Could 3A + 6 = 200
3A = 194
A = 64.6666
This is NOT an EVEN INTEGER, so 200 is NOT the answer
Could 3A + 6 = 318
3A = 312
A = 102
This IS an EVEN INTEGER! The numbers would be 102, 104 and 106. This IS the answer
Final Answer:
C
Answer: C
Question: A football field is 8400 square yards. If 1200 pounds of fertilizer are spread evenly across the entire field, how many pounds of fertilizer were spread over an area of the field totaling 3500 square yards?
Options:
A)450
B)600
C)500
D)2400
E)3200
Rationale: Answer A) 4800 yards need 1200 lbs
1 Yard will need 1200/8400 = 1/7 lbs
3600 Yards will need 1/7* 3500 Yards = 500lbs
C
Answer: C
Question: A and B starts a business with Rs.8000 each, and after 4 months, B withdraws half of his capital . How should they share the profits at the end of the 20 months?
Options:
A)18:11
B)18:15
C)20:11
D)18:121
E)18:112
Rationale: A invests Rs.8000 for 20 months, but B invests Rs.8000 for the first 4 months and then withdraws Rs.4000. So, the investment of B for remaining 14 months is Rs.4000 only.
A : B
8000*20 : (8000*4) + (4000*14)
160000 : 88000
A:B = 20:11.Answer:C
Answer: C
Question: If x is to be chosen at random from the set {1, 2, 3, 4} and y is to be chosen at random from the set {5, 6, 7}, what is the probability that xy will be odd?
Options:
A) 1/6
B) 1/3
C) 1/2
D) 2/3
E) 5/6
Rationale: Probably the best way to solve would be to use 1 - P(opposite event) = 1 - P(odd) = 1 - P(odd)*P(odd) = 1 - 2/4*2/3 = 8/12 = 1/3.
Answer: B.
Answer: B
Question: In how many different number of ways 4 boys and 1 girls can sit on a bench?
Options:
A)120
B)140
C)160
D)180
E)200
Rationale: npn = n!
5p5= 5 × 4 × 3 × 2 × 1 = 120
A
Answer: A
Question: A rectangular lawn of dimensions 90 m * 60 m has two roads each 10 m wide running in the middle of the lawn, one parallel to the length and the other parallel to the breadth. What is the cost of traveling the two roads at Rs.3 per sq m?
Options:
A)A)4200
B)B)930
C)C)9309
D)D)3900
E)E)8302
Rationale: Explanation:
Area = (l + b – d) d
(90 + 60 – 10)10 => 1400 m2
1400 * 3 = Rs.4200
Answer: Option A
Answer: A
Question: If 22 percent of the students at a certain school went to a camping trip and took more than $100, and 75 percent of the students who went to the camping trip did not take more than $100, what percentage of the students at the school went to the camping trip?
Options:
A)95
B)90
C)88
D)80
E)75
Rationale: Let x be the number of students in the school. 0.22x students went to the trip and took more than 100$. They compose (100-75)=25% of all students who went to the trip. Therefore the toal of 0.22x/0.25=0.88x students went to the camping which is 88%.
The answer is C
Answer: C
Question: Gill drives 120 miles from Los Angeles to San Diego to fetch a package. On her way there she drives at 40 miles per hour. On her way back she drives 50% faster. What is Gill's average velocity Q for the round trip?
Options:
A)24 miles per hour
B)48 miles per hour
C)50 miles per hour
D)53 1/3 miles per hour
E)68 miles per hour
Rationale: Here's an Average Speed question in which the prompt gives you almost all of the immediate numbers needed to work with.
Driving from LA to SD, we have a distance of 120 miles and a speed of 40 miles/hour.
D = (R)(T)
120 = (40)(T)
120/40 = 3 = T
3 hours to drive to SD
On the way back, she drives 50% FASTER. Gill's return speed is (1.5)(40) = 60 miles/hour.
D = (R)(T)
120 = (60)(T)
120/60 = 2 = T
2 hours to drive to SD
Total Distance = 240 miles
Total Time = 3+2 = 5 hours
Average Speed = 240/5 = 48 miles/hour
Final Answer:
B
Answer: B
Question: If the area of circle is 314 sq cm then its circumference?
Options:
A)10
B)61
C)65
D)56
E)62
Rationale: 22/7 r2 = 314 => r = 10
2 * 22/7 * 10 = 62
Answer: E
Answer: E
Question: The sector of a circle has radius of 28 cm and central angle 135o. Find its perimeter?
Options:
A)90cm
B)95cm
C)100cm
D)110cm
E)122cm
Rationale: Perimeter of the sector = length of the arc + 2(radius)
= (135/360 * 2 * 22/7 * 28) + 2(28)
= 66 + 56 = 122 cm
Answer:E
Answer: E
Question: A shopkeeper sells his goods at cost price but uses a faulty meter that weighs 960 grams. Find the profit percent.
Options:
A)4.166
B)3.1
C)2.1
D)1.256
E)3.759
Rationale: Explanation:
(100 + g) / (100 + x) = True measure / Faulty measure
x = 0
true measure = 1000
faulty measure = 960
100 + g / 100 + 0 = 1000 / 960
100+g = 100/96*100
g = 4.166
ANSWER: A
Answer: A
Question: When the positive integer A is divided by 5 and 8, the remainder is 3 and 4, respectively. When the positive integer B is divided by 5 and 8, the remainder is 3 and 4, respectively. Which of the following must be a factor of A-B?
Options:
A)32
B)35
C)36
D)40
E)50
Rationale: A = 5k+3 = 8j+4
B = 5m+3 = 8n+4
A-B = 5(k-m) = 8(j-n)
Thus A-B is a multiple of 5 and 8, so it is multiple of 40.
The answer is D.
Answer: D
Question: Narendra started a business, investing 30000. Six months later, Chandan joined him with 10000. If they make a profit of 10000 at the end of the year, what should be the share of Narendra?
Options:
A)A)Rs.7000
B)B)Rs.8000
C)C)Rs.8500
D)D)Rs.8571
E)E)Rs.8700
Rationale: The ratio of their investments = 30000 × 12 : 10000 × 6 = 6: 1.
:. Narendra’s share on profit of Rs.10000 = 10000 × 6/7 = Rs.8571.
D)
Answer: D
Question: In an engineering class that contained 50 students, the final exam consisted of 2 questions. Three fifths of the students answered the first question correctly. If four fifths of the remainder answered the second question correctly, how many students answered both questions incorrectly?
Options:
A)4
B)6
C)10
D)12
E)24
Rationale: 1st Question : Three fifths of the students answered the first question correctly - so 3/5∗50=30
2nd Question : four fifths of the remainder answered the second question correctly so 4/5∗(50−30)=45∗20=16
total students who answered at least one Q correct =30+16=46
so students who answered BOTH incorrectly = 50−46=4
ANSWER:A
Answer: A
Question: On a certain date, Pat invested $5,000 at x percent annual interest, compounded annually. If the total value of the investment plus interest at the end of 10 years will be $20,000, in how many years total will the total value of the investment plus interest increase to $40,000?
Options:
A)15
B)16
C)18
D)20
E)24
Rationale: 5,000(1 + x)^10 = 20,000
(1+x)^10 = 4 = 2^2
(1+x)^10 = ((1+x)^5)^2 = 2^2
Therefore, (1+x)^5 = 2
5000(1 + x)^n = 40,000
(1+x)^n = 8
(1+x)^n = 2^3
(1+x)^n = ((1+x)^5)^3 = (1+x)^15
Therefore, n = 15.
The answer is A.
Answer: A
Question: Eight people are planning to share equally the cost of a rental car. If one person withdraws from the arrangement and the others share equally the entire
rest of the car, then the share of each of the remaining persons increased by ?
Options:
A)1/9
B)1/8
C)1/7
D)7/8
E)8/7
Rationale: When there are eight people, the share of each person is 1/8th the total cost
ANSWER:B
Answer: B
Question: If two dice are thrown together, the probability of getting an even number on one die and an odd number on the other is
Options:
A)2/2
B)1/2
C)7/2
D)8/2
E)6/2
Rationale: Explanation:
The number of exhaustive outcomes is 36.
Let E be the event of getting an even number on one die and an odd number on the other. Let the event of getting either both even or both odd then = 18/36 = 1/2
P(E) = 1 - 1/2 = 1/2.
Answer:B
Answer: B
Question: Departments A, B, and C have 4 employees each, and department D has 20 employees. Departments A, B, C, and D have no employees in common. A task force is to be formed by selecting 1 employee from each of departments A, B, and C and 2 employees from department D. How many different task forces are possible?
Options:
A)12,610
B)40,000
C)100,000
D)190,000
E)400,000
Rationale: 4c1 * 4c1* 4c1*20c2 = 10*10*10*190=12,610. Hence A is the correct answer.
Answer: A
Question: A father is Quadrice as old as his daughter today. After 20 years, he would be only two times as old. At the time of daughter’s birth, how much old the father be?
Options:
A)30
B)10
C)40
D)20
E)60
Rationale: A
30
If the ages of daughter and father today by ‘A’ and ‘4A’ years correspondingly.
4A + 20 = 2 (A+20)
A = 10 years => 4A = 40 years.
At the time of daughter’s birth, father’s Age
40 – 10 = 30 years old
Answer: A
Question: The unit digit in the product (784 x 618 x 917 x 463) is:
Options:
A)5
B)9
C)16
D)2
E)42
Rationale: Explanation:
Unit digit in the given product = Unit digit in (4 x 8 x 7 x 3) = (672) = 2
D
Answer: D
Question: Find the average of all the numbers between 16 and 34 which are divisible by 5?
Options:
A)10
B)20
C)28
D)30
E)15
Rationale: Average = (20+25+30) 3 = 85/3 = 28
Answer is C
Answer: C
Question: How much time will take for an amount of Rs. 100 to yield Rs. 81 as interest at 4.5% per annum of simple interest?
Options:
A)7
B)4
C)18
D)10
E)15
Rationale: Time = (100 * 81) / (100 * 4.5) = 4 years'
Answer:C
Answer: C
Question: A fill pipe can fill 1/3 of cistern in 20 minutes in how many minutes, it can fill 3/4 of the cistern?
Options:
A)15 min
B)45 min
C)25 min
D)40 min
E)50 min
Rationale: 1/3 of the cistern can fill in 20 min
3/4 of the cistern can fill in = 20*3*3/4 = 45min
Answer is B
Answer: B
Question: There are 4 copies of 5 different textbooks. In how many ways can they be arranged on a shelf?
Options:
A)20!/4!
B)20!/5(4!)
C)20!/(4!)^5
D)20!
E)5!
Rationale: There are 4 copies of 5 different textbooks.20!/((4!)^5)
Answer - C
Answer: C
Question: We define that K@J is the product of j number from k in increasing order for positive integers K, J. For example, 6@4=6*7*8*9. If A=2020and B=2120, what is the value Q of the ratio A/B?
Options:
A)1/2
B)1/3
C)2/3
D)1/4
E)1/5
Rationale: Q-> A/B=20*21*……*39/21*22*….*39*40=20/40=1/2.
Therefore, the answer is A.
Answer: A
Question: In a bag, there are 10 discs, numbered 1 to 10 (no duplicates). If we randomly choose 4 of the discs, what is the probability that the range of the numbers chosen is 7?
Options:
A)1 / 14
B)1 / 7
C)3 / 14
D)9 / 28
E)4 / 7
Rationale: Probability (A) = No of suitable outcomes where A happens/Total no of outcomes
We use combinations to get "No of suitable outcomes where A happens" and "Total no of outcomes" and then calculate the required probability. So for the time being, just forget that you have to find some probability.
Focus on two things: "No of suitable outcomes where A happens" and "Total no of outcomes"
It is easy to find total number of outcomes. 10C4. e.g. (2, 3, 4, 6), (4, 1, 9, 5) etc etc etc
In how many combinations is range 7? (This is the "No of suitable outcomes where A happens")
(3, 10, a, b), (2, 9, c, d) and (1, 8, e, f)
a and b are numbers between 3 and 10 (so that range doesn't exceed 7)
c and d are numbers between 2 and 9
e and f are numbers between 1 and 8
In how many ways can you choose a and b? 6C2 (Any 2 out of 6 numbers between 3 and 10). So how many 4 number combinations are there which look like this: (3, 10, 4, 6), (3, 10, 7, 5) etc?
I hope you agree it is 6C2.
Similarly, you get 6C2 combinations of the type (2, 9, c, d) and 6C2 of the type (1, 8, e, f).
No of suitable combinations = 6C2 + 6C2 + 6C2
Now, the required probability = No of suitable combinations where A happens/Total no of outcomes
= (3*6C2)/10C4 =3/14
Correct answer is C
Answer: C
Question: If 0.25 : x : : 2 : 6, then x is equal to
Options:
A)0.65
B)0.25
C)0.75
D)0.85
E)None
Rationale: Sol.
(x×2) = (0.25×6) ⇒ x = 1.5/2 = 0.75.
Answer C
Answer: C
Question: Ravi can do a piece of work in 26 days while Prakash can do it in 40 days. In how many days will they finish it together?
Options:
A)15 25/33 days
B)16 1/33 days
C)17 1/33 days
D)17 25/33 days
E)18 1/33 days
Rationale: 1/26 + 1/40 = 33/520
520/33
= 15 25/33 days
Answer: A
Answer: A
Question: Find the invalid no.from the following series 12, 19, 24, 31, 36, 39
Options:
A)13
B)18
C)40
D)39
E)25
Rationale: The differences between two successive terms from the beginning are 7, 5, 7, 5, 7, 5. So, 39 is wrong.
Answer : D
Answer: D
Question: For every integer n ≥ 3, the function h(n) is defined as the product of all the odd integers from 1 to n, inclusive. What is the value of h(101) + h(100)?
Options:
A)0
B)100
C)102
D)99
E)105
Rationale: h(101) = 1*3*5*7*9*...*99*101
h(100) = 1*3*5*7*9*...*99
h(101) +h(100) = 1*3*5*7*9*...*99 + 1*3*5*7*9*...*97 = 1*3*5*7*9*...*99*(101 + 1) = 1*3*5*7*9*...*99*102
hence:C
Answer: C