divelab/Sys2Bench huggingface dataset:
Question: A and B enter into a partnership with respective capitals of Rs. 20,000 and Rs. 40,000. At the end of the year, the total profit is Rs. 33,000. If A receives Rs. 15,000 as both his salary and profit, then what is his salary?
Options:
A)Rs. 2000
B)Rs. 4000
C)Rs. 3500
D)Rs. 3000
E)None of these
Rationale: Explanation:
A's capital : B 's capital
20000 : 40000 = 1 : 2
Since, the time period is fixed, the profit is distributed in the ratio of capital 1 : 2
Profit of A = (1/3) * 33,000 = Rs. 11,000
Salary of A = Rs. (15000 – 11000) = Rs. 4000
ANSWER: B
Answer: B
Question: The owner of a furniture shop charges his customer 24% more than the cost price. If a customer paid Rs. 8339 for a computer table, then what was the cost price of the computer table?
Options:
A)3888
B)26679
C)277
D)6725
E)342
Rationale: CP = SP * (100/(100 + profit%))
= 8339(100/124) = Rs. 6725.
Answer:D
Answer: D
Question: A leak in the bottom of a tank can empty the full tank in 6 hours. An inlet pipe fills water at the rate of 6 litres a minute. When the tank is full, the inlet is opened and due to the leak, the tank is empty in 12 hours. How many litres does the cistern hold?
Options:
A)7580
B)7960
C)8290
D)4320
E)None
Rationale: Solution
Work done by the inlet in 1 hour	= (1/6 - 1/12)
= 1/12.
Work done by the inlet in 1 min.	= (1/12 × 1/60)
= 0.001389
Volume of 0.001389 part = 6 litres.
Therefore, Volume of whole= 1/0.001389 x 6
‹=› 4320 litres.
Answer D
Answer: D
Question: A mixture of certain quantity of milk with 16 liters of water is worth 90 P per liter. If pure milk be worth Rs1.08 per liter, how proportion milk is there in the mixture?
Options:
A)5/2
B)5/1
C)5/7
D)3/5
E)1/2
Rationale: The mean value is 90 P and price of water is 0 P
By the alligation rule : Quantity of milk / Quantity of water
= (90 - 0) / (108 - 90)
= 90 / 18
= 5/1
proportion milk is 5/1 there in the mixture
B
Answer: B
Question: A man can row 6 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and black. What is the total distance traveled by the man?
Options:
A)5.79
B)5.28
C)5.76
D)32.9
E)5.73
Rationale: M = 6
S = 1.2
DS = 7.2
US = 4.8
x/7.2 + x/4.8 = 1
x = 2.88
D = 2.88 * 2 = 5.76
Answer:C
Answer: C
Question: If the average of 5x and 8y is greater than 90, and x is twice y, what is the least integer value of x ?
Options:
A)4
B)5
C)20
D)21
E)23
Rationale: If y is greater than 110 percent of x, is y greater than 75?
(1)x>75x>75
(2) y−x=10y−x=10
Pls verify.
1) Sufficient.
y > 1.1 x and x > 75. Min(x) = 75
y > 1.1 * 75
y > 82.5
2) Insufficient. Substituting (x=y-10) in y > 1.1x
y > 1.1(y-10)
y < 110
Hence A.
Answer: A
Question: Sum of the squares of three numbers is 138 and the sum of their products taken two at a time is 131. Find the sum?
Options:
A)20
B)21
C)24
D)26
E)28
Rationale: (a + b + c)2 = a2 + b2 + c2 + 2(ab +bc + ca) = 138 + 2* 131
a + b + c = √400 = 20
A
Answer: A
Question: A certain bacteria colony doubles in size every day for 11 days, a which point it reaches the limit of its habitat and can no longer grow. If two bacteria colonies start growing simultaneously, how many days will it take them to reach the habitat’s limit?
Options:
A)6.33 
B)7.5 
C)10 
D)15 
E)19 
Rationale: Case 1: Consider the bacteria num to be B. As it doubles every day, number of bacteria at the end of each day would be
Day 1 – B
Day 2 – 2B
Day 3 – 4B
Day 4 – 8B
.
.
.
Day 11 – 2^19 B
It can be implied that the capacity of the habitat is 2^19 B.
Case 2: There are 2 bacteria which keep doubling every day. So, the count would be
Day 1 – 2B
Day 2 – 4B
Day 3 – 8B
.
.
.
Day 18 – 2^18 B
Day 19 – 2^19 B --> this is the point where the habitat is filled to its capacity.
Hence, 10 is the answer
C
Answer: C
Question: The average of five numbers is 27. If one number is excluded, the average becomes 24. The excluded number is?
Options:
A)36
B)37
C)38
D)39
E)40
Rationale: Excluded number = (27 * 5) - (24 * 4)
= 135 - 96
= 39.
Answer: D
Answer: D
Question: If rupee one produces rupees nine over a period of 40 years, find the rate of simple interest?
Options:
A)22 1/7%
B)22 7/2%
C)29 1/2%
D)22 1/2%
E)22 1/3%
Rationale: 9 = (1*40*R)/100
R = 22 1/2 %
Answer: D
Answer: D
Question: Jim takes a seconds to swim S meters at a constant rate from point P to point Q in a pool. Roger, who is faster than Jim, can swim the same distance in b seconds at a constant rate. If Jim leaves point P the same time that Roger leaves point Q, how many fewer meters will Jim have swum than Roger when the two swimmers pass each other?
Options:
A)c(b-a)/ a+b
B)c(a-b)/a+b
C)S(a-b)/(a+b)
D)ab(a-b)/a+b
E)ab(b-a)/a+b
Rationale: Both JimRoger are travelling at constant speedin opposite direction:
So, speed of Jim = S/a speed of Roger = S/b
Let say Jim travelled distance x from P where it met Roger, it means that Roger travelled (S-x) from point Q
[x would be less than (c-x) as Jim is travelling slow]
From above, time taken by Jim to travel x = xa/S....................... (1)
Also, time taken by Roger to travel (c-x) = (S-x)b/S.....................(2)
Time taken by both JimRoger is same, so (1) = (2)
xa/S = (S-x)b/S,
Solving further, x = bS/(a+b).................... (3)
We require to find how many fewer meters will Jim have swum i.e
additional distance travelled by Roger = (S - x) - x
= S-2x
Substituting value of x from (3)solving the equation further, we get Answer = S(a-b)/a+b
Answer = (C)
Answer: C
Question: Insert the missing number. 34, 7, 37, 14, 40, 28, 43, (...)
Options:
A)31
B)42
C)46
D)56
E)68
Rationale: Explanation :
We have two series here
34, 37, 40, 43, ... (Increase by 3)
7, 14, 28, ... (Multiply by 2)
Hence, next term is 28 × 2 = 56
Answer : Option D
Answer: D
Question: Find the average of all the numbers between 6 and 34 which is divisible by 5
Options:
A)15
B)18
C)13
D)19
E)20
Rationale: avg = (10+15+20+25+30)/5 = 100/5 => 20
ANSWER E
Answer: E
Question: Excluding stoppages, the speed of a train is 45 kmph and including stoppages it is 37 kmph. Of how many minutes does the train stop per hour?
Options:
A)73
B)83
C)12
D)83
E)11
Rationale: Explanation:
T = 8/45 * 60 = 11
Answer: Option E
Answer: E
Question: Without stoppages, a train travels certain distance with an average speed of 300 km/h, and with stoppages, it covers the same distance with an average speed of 200 km/h. How many minutes per hour the train stops ?
Options:
A)20
B)21
C)22
D)23
E)24
Rationale: Due to stoppages, it covers 100 km less .
Time taken to cover 100 km = 100â„300h = 1â„3h
= 1â„3 Ã— 60 min = 20 min
Answer A
Answer: A
Question: If a sum of Rs.17,100 is divided between, A and B in the ratio 4:5, how much amount would A get ?
Options:
A)9500
B)6700
C)7600
D)7900
E)9700
Rationale: A = 17100 × 4 / 9 = Rs.7600
B = 17100 × 5 /9 = Rs.9500
Option A
Answer: A
Question: The ratio of two numbers is 3 : 4 and their H.C.F. is 4. Their L.C.M. is
Options:
A)12
B)16
C)24
D)48
E)50
Rationale: Solution
Let the numbers be 3x and 4x. Then, their H.C.F. = x. So, x = 4.
So, the numbers are 12 and 16.
L.C.M. of 12 and 16 = 48.
Answer D
Answer: D
Question: In expressing a length of 81.472 km as nearly as possible with the three significant digits, find the
percentage error
Options:
A)0.35%
B)0.34%
C)0.034%
D)0.035%
E)None of these
Rationale: Explanation:
Error = (81.5 - 81.472) = 0.028
Required percentage =
0.02881.472×100=0.034
Answer: Option C
Answer: C
Question: A person saved $50 in buying an item on sale. If he spent $500 for the item, approximately how much percent he saved in the transaction?
Options:
A)8%
B)10%
C)2%
D)5%
E)1.8%
Rationale: Actual price = 500+50 = $550
Saving = 10/550 * 100 = 100/55 = 1.8% approximately
Answer is E
Answer: E
Question: A boat having a length 8 m and breadth 2 m is floating on a lake. The boat sinks by 1cm when a man gets on it. The mass of the man is:
Options:
A)12 kg
B)60 kg
C)72 kg
D)160 kg
E)None of these
Rationale: Explanation:
Volume of water displaced = (8 x 2 x 0.01) m3
= 0.16 m3.
∴ Mass of man = Volume of Water displaced x Density of water
= (0.16 x 1000)kg
= 160 kg.
Answer: D
Answer: D
Question: The C.P of 15 books is equal to the S.P of 18 books. Find his gain% or loss%?
Options:
A)16 2/3% loss
B)11 2/3% loss
C)66 2/3% loss
D)12 2/3% loss
E)17 2/3% loss
Rationale: Explanation:
15 CP = 18 SP
18 --- 3 CP loss
100 --- ? => 16 2/3% loss
Answer: A
Answer: A
Question: A courtyard is 21 meter long and 14 meter board is to be paved with bricks of dimensions 14 cm by 8 cm. The total number of bricks required is :
Options:
A)16000
B)18000
C)20000
D)26250
E)None of these
Rationale: Explanation:
Number of bricks =Courtyard area /1 brick area
=(2100Ã—1400 /14Ã—8)=26250
Option D
Answer: D
Question: Company A imported 12,000 widgets made of either brass or aluminum. The widgets are painted blue, red or green. If 10 percent of the widgets are made of brass and of those 20 percent are painted green and 40 percent are painted red how many brass widgets painted blue were imported?
Options:
A)420
B)480
C)1050
D)1680
E)2100
Rationale: Answer A.
We are told that 10% of all imported widgets are made of brass and of those, 20% are green and 40% are red. Since we know that there are only three colors, the remaining 40% must be blue. 40% blue of 10% brass widgets leads to 4% blue brass widgets out of the total 10,550 widgets.
12,000 /100 * 4 = 480.
Answer B.
Answer: B
Question: There is a train and car. The ratio between the speed of a train & a car is 16:15 respectively. Also, a bus covered a distance of 480 km in 8 hours. The speed of the bus is 3/4th of the speed of the train. How many kilometers will the car cover in 4 hours?
Options:
A)200
B)250
C)300
D)350
E)400
Rationale: The speed of the bus is 480/8 = 60 km/hr
The speed of the train is (60*4)/3 = 80 km/hr
The speed of the car is 80/16 * 15 = 75 km/hr
The distance covered by the car in 4 hours is 75 × 4 = 300 km
The answer is C.
Answer: C
Question: The ratio of investments of two partners P and Q is 7:5 and the ratio of their profits is 7:10. If P invested the money for 20 months, find for how much time did Q invest the money?
Options:
A)11
B)40
C)18
D)16
E)12
Rationale: 7*5: 20*x = 7:10
x = 40
Answer:B
Answer: B
Question: Each of the 30 boxes in a certain shipment weighs either 10 pounds or 20 pounds, and the average (arithmetic mean) weight of the boxes in the shipment is 18 pounds. If the average weight of the boxes in the shipment is to be reduced to 15 pounds by removing some of the 20-pound boxes, how many 20-pound boxes must be removed?
Options:
A)8
B)12
C)18
D)20
E)24
Rationale: If the average of 10-pound and 20-pound boxes is 18, the ratio of 10-pound boxes:20-pound boxes is 1:4.
So out of 30 boxes, 6 are 10-pound boxes and 24 are 20-pound boxes.
If the average of 10 and 20-pound boxes is to be 15, the ratio of 10-pound boxes:20-pound boxes should be 1:1.
The number of 10 pound boxes remain the same so we still have 6 of them.
To get a ratio of 1:1, the number of 20-pound boxes must be 6.
We need to remove 18 of the 20-pound boxes.
The answer is C.
Answer: C
Question: How many arrangements of the letters of the word BEGIN can be made, without changing the place of the vowels in the word?
Options:
A)4
B)6
C)7
D)8
E)9
Rationale: E,I fixed. Consonants can be arrangements in 3P3 = 3! = 6 ways
Option 'B'
Answer: B
Question: The average salary of the employees in a office is Rs.120/month.The avg salary of officers is Rs.460 and of non officers is Rs 110. If the no.of officers is 15,then find the No of nonofficers in the office.
Options:
A)400
B)420
C)430
D)450
E)510
Rationale: Let no. of non- officers be x
15 * 460 + x * 110 = (x + 15) 120
x = 510
E
Answer: E
Question: Find the average of all numbers between 4 and 34 which are divisible by 5
Options:
A)20
B)21
C)25
D)30
E)55
Rationale: Explanation:
Average=(5+10+15+20+25+30) / 5=105 / 5=21
Option B
Answer: B
Question: What approximate value should come in place of the question mark (?).
36.0001 ÷ 5.9998 × √? = 108.0005
Options:
A)325
B)316
C)256
D)16
E)18
Rationale: Using approximation, we get 36⁄6 × √? = 108
or, √? = 108⁄6
or, √? = 18
or, ? = 324 ≈ 325
Answer E
Answer: E
Question: A merchant sells an item at a 20% discount, but still makes a gross profit of 40 percent of the cost. What percent of the cost would the gross profit on the item have been if it had been sold without the discount?
Options:
A)20%
B)40%
C)50%
D)60%
E)75%
Rationale: original SP = X
Cost =C
current selling price = .8x ( 20% discount)
.8x = 1.4C (40% profit)
x= 1.4/.8 *C
x= 7/4 C
Original selling price is 1.75C which is 75% profit
Answer E
Answer: E
Question: Find large number from below question
The difference of two numbers is 1365. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder.
Options:
A)535
B)565
C)1234
D)1345
E)1635
Rationale: Let the smaller number be x. Then larger number = (x + 1365).
x + 1365 = 6x + 15
5x = 1350
x = 270
Large number = 270+1365 = 1635
E
Answer: E
Question: Jane and Thomas are among the 7 people from which a committee of 4 people is to be selected. How many different possible committees of 4 people can be selected from these 7 people if at least one of either Jane or Thomas is to be selected?
Options:
A)30
B)45
C)55
D)65
E)70
Rationale: The total number of ways to choose 4 people from 7 is 7C4 = 35.
The number of committees without Jane or Thomas is 5C4 = 5.
There are 35-5 = 30 possible committees which include Jane and/or Thomas.
The answer is A.
Answer: A
Question: The difference between the compound interest compounded annually and simple interest for 2 years at 20% per annum is Rs.360. Find the principal?
Options:
A)2277
B)2667
C)9000
D)2766
E)1811
Rationale: P = 360(100/5)^2 => P = 9000
Answer: C
Answer: C
Question: A man took a loan from a bank at the rate of 9% p.a. simple interest.After 3 years he had to pay Rs. 5400 interest only for the period.The principal amount borrowed by him was :
Options:
A)Rs. 2000
B)Rs. 10,000
C)Rs. 15,000
D)Rs. 20,000
E)None
Rationale: Solution
Principal = Rs.(100x5400/9x3)= Rs. 20000.
Answer D
Answer: D
Question: There is a train and car. The ratio between the speed of a train & a car is 16:15 respectively. Also, a bus covered a distance of 480 km in 8 hours. The speed of the bus is 3/4th of the speed of the train. How much distance will the car cover in 5 hours?
Options:
A)300 km
B)325 km
C)375 km
D)425 km
E)450 km
Rationale: The speed of the bus is 480/8 = 60 km/hr
The speed of the train is (60*4)/3 = 80 km/hr
The speed of the car is 80/16 * 15 = 75 km/hr
The distance covered by the car in 5 hours is 75 × 5 = 375 km
The answer is C.
Answer: C
Question: If (c - a)/(c - b) = 1, then (5b - 3a)/(c - a) =
Options:
A)0.5
B)1
C)1.5
D)2
E)2.5
Rationale: Let's say c=2, b=1, a=1 so that our 1st expression holds true. Now, ibsert those numbers in the second expression and we'll get 2
Answer D (hopefully )))
Answer: D
Question: If n is a positive integer, what is the remainder when (7^(4n+2))(6^n) is divided by 10?
Options:
A)1
B)2
C)4
D)6
E)8
Rationale: This one took me bout 3 1/2 min. Just testin numbers and what not.
First notice that n is positive. Save time by noticing thatI worked out one solution where n=0 only to find that thats not an option :p.
1-7 stands for ^1 thru 7
1: 7*1=7
2: 7*7=9
3: 7*9=3
4: 7*3=1
5: 7*1=7
6: 7*7=9
7: 7*9=3
Pattern repeats every @ 5. Notice every ^4 or multiple of 4 is always going to be 1. This is just for future notice for similar problems.
so 7^4n+3 ---> if n=1 then its ((7^7)*6))/10 which can say is going to be 3*8--> 18/10 --> R=8
Now from here if id double check just to make sure.
7^4(2)+3*6^2 ---> 7^11*36 or we can just say again 7^11*6 (b/c we are only interested in the units digit).
Since ^12 is going to be 1 that means ^11 is going to be 3 (as taken from our pattern)
so again 3*6=18/10 ---> R =4.
C or J in this problem.
Answer: C
Question: When m is divided by 9, the remainder is 2. When m is divided by 13, the remainder is 4. If 1 < m < 300, what is the greatest possible value of m?
Options:
A)210
B)230
C)250
D)270
E)290
Rationale: 13*9 = 117
Let's start with 4, and keep adding 13 until we find a number with the form 9k+2.
4, 17, 30, 43, 56 = 9*6+2
The next possible number is 56 + 117 = 173
The next possible number is 173 + 117 = 290
The next possible number would be greater than 300.
The answer is E.
Answer: E
Question: x =4 9 11
y= 64 49 9 then what is the relation between x and y
Options:
A)1*X)^1
B)1*X)^3
C)1*X)^2
D)1*X)^4
E)1*X)^5
Rationale: Y=(1*4)^3
64=(1*4)^3
64=64
ANSWER:B
Answer: B
Question: The function g(h) is defined for integers h such that if h is even, g(h) = h/2 and if h is odd, g(h) = h + 5. Given that g(g(g(g(g(h))))) = 19, how many possible values for h would satisfy this equation?
Options:
A)1
B)5
C)7
D)8
E)11
Rationale: Let me define terms:
in g(h) = R
h is argument, R is result, g() is function,
in g(g(g(g(g(h))))), g1 is inner most, g5 is outermost for identification.
From definition of function g, we can deduce that:
If Result is even then two possibilities for argument = 1 Even 1 Odd
If Result is odd then one possibility for argument = 1 Even
Since final result = 19 = Odd
Possibilities:
g1:1 Even
g2: 1*(Even,Odd ) =1 Even 1 Odd
g3: 1*(Even,Odd) + 1 Even =2 Even 1 Odd
g4: 2*(Even, Odd) + 1 Even =3 Even 2 Odd
g5: 3*(Even, Odd) + 2 Even =5 Even 3 Odd = Total 8
Ans D it is!
Answer: D
Question: The average temperature of Tuesday Wednesday and Thursday was 37 C. The average temperature of Wednesday and Thursday and Friday was 38 C. if the temperature on Friday was 39 C.
Find the temperature on Tuesday.
Options:
A)22
B)36
C)88
D)20
E)27
Rationale: Tues + Wed + Thurs)/3=37
Tues + Wed + Thurs=111...(1)
(Wed + Thurs + Fri)/3=38
(Wed + Thurs + Fri) =114...(2)
Given friday is 39.
Then, (2) - (1) Fri - Tues = 3
So 39 - Tues = 3
Tuesday =36
Answer:B
Answer: B
Question: A 180m long train is running at 72 kmph.If it crossed the platform in 20 sec.then find the platform length?
Options:
A)220m
B)110m
C)230m
D)100m
E)90m
Rationale: Length=speed*time
Length=72km/hr*time
Length=[72*(5/18)]*20 {(ie)(x)km/hr)}
=x*(5/18)
=20*20
Length=400m
Length of platform=Length-Length of the train
Length of platform=400-180
Length of platform=220m
Option A
Answer: A
Question: A sum of money at simple interest amounts to Rs. 835 in 3 years and to Rs. 854 in 4 years. The sum is:
Options:
A)647
B)698
C)778
D)847
E)976
Rationale: S.I. for 1 year = Rs. (854 - 835) = Rs. 19.
S.I. for 3 years = Rs.(19 x 3) = Rs. 57.
Principal = Rs. (835 - 57) = Rs. 778.
Answer:C
Answer: C
Question: If w is an even integer and q is an odd integer, which of the following must be an odd integer?
Options:
A)w/q
B)wq
C)2w+q
D)2(w+q)
E)3w/q
Rationale: this is a must question:
A. w/q
can be a non-integer
B. wq
always even
C. 2w+q
2w = even -> even+odd = odd
D. 2(w+q)
always even - w+q = odd *2 -> even
E. 3w/q
might be a non integer.
C
Answer: C
Question: In how many ways a committee of 4 members can be selected from 7men and 6ladies, consisting of 2 men and 2 ladies?
Options:
A)250
B)315
C)412
D)256
E)362
Rationale: (2 men out 7) and (2 ladies out of 6) are to be chosen
Required number of ways = 7C2 * 6C2 = (7*6*6*5)/(2*1*2*1) = 315
Answer is B
Answer: B
Question: A salt manufacturing company produced a total of 5000 tonnes of salt in January of a particular year. Starting from February its production increased by 170 tonnes every month over the previous months until the end of the year. Find its average monthly production for that year?
Options:
A)2989
B)2765
C)5950
D)2989
E)9772
Rationale: Total production of salt by the company in that year
= 5000 + 5170 + 5340 + .... + 6870 = 71390.
Average monthly production of salt for that year
= 71390/12
= 5950.
Answer:C
Answer: C
Question: A brick measures 20 cm * 10 cm * 7.5 cm how many bricks will be required for a wall 23 m * 2 m * 0.75 m?
Options:
A)22377
B)27782
C)27891
D)25000
E)23000
Rationale: 23 * 2 * 0.75 = 20/100 * 10/100 * 7.5/100 * x
23 = 1/100 * x => x = 23000
Answer: E
Answer: E
Question: What is the smallest positive integer K such that the product of 3675 x K is a perfect square?
Options:
A)3
B)9
C)15
D)25
E)63
Rationale: A perfect square, is just an integer that can be written as the square of some other integer. For example 16=4^2, is a perfect square.
Now, 3675= 5^2 * 7^2 * 3, so if k=3 then 3675 k = (5 * 7 * 3)^2, which is a perfect square (basically the least positive value of k must complete only the power of 7 to even power as powers of other primes are already even).
Answer: A.
Answer: A
Question: The sale price of a trolley bag including the sale tax is Rs. 1120. The rate of sale tax is 12% . If the shopkeeper has made a profit of 25%, the cost price of the trolley bag is:
Options:
A)Rs 1000
B)Rs 1515
C)Rs 800
D)Rs 900
E)None of these
Rationale: Explanation :
112% of S.P. = 1120
S.P. = Rs.(1120x 100/112) = Rs.1000.
C.P. = Rs (100/125x 1000) = Rs 800.
Answer : C
Answer: C
Question: The ages of two person , differ by 20 years. If 5 years ag , the elder one be 5 times as old as the younger one their present ages (in years) are respectively
Options:
A)30, 10
B)20,10
C)35,15
D)51,17
E)20,17
Rationale: Let their ages be x and (x + 20) years
(x - 5) * 5 = (x +20 - 5)
after solving this we get
x= 10 years
The age of elder one = 10 + 20 = 30 years
So the present ages are 30 and 10 years
ANSWER : A
Answer: A
Question: A van takes 5 hours to cover a distance of 495 km. What speed in kph should the van maintain to cover the same distance in 3/2 of the previous time?
Options:
A)60
B)63
C)66
D)69
E)72
Rationale: (3/2)*5 = 7.5 hours
495 / 7.5 = 66 kph
The answer is C.
Answer: C
Question: SP of a book is Rs. 450 he gets a loss of 10%, find CP of the book?
Options:
A)Rs.300
B)Rs.450
C)Rs.500
D)Rs.600
E)Rs.640
Rationale: Find cost price
Let C.P. of book = x and S.P. = Rs. 450
S.P. of book = C.P. – (10% of C.P.)
S.P. = x – (0.10x)
450 = 0.9 x
x i.e cost price = Rs.500
C
Answer: C
Question: Complete the sequence:
E G K Q ?
Options:
A)M
B)D
C)Y
D)F
E)Z
Rationale: E+2=G
G+4=K
K+6=Q
Q+8=Y
C
Answer: C
Question: What is the smallest of six consecutive odd integers whose average (arithmetic mean) is y + 2?
Options:
A)y - 3
B)y-57
C)y - 1
D)y
E)x + 1
Rationale: Since the numbers are consecutive odd integers, mean = median = 3rd integer + 4th integer /2
And 1st integer= 3rd integer- 4
let's say 3rd integer = n and 4th integer = n+2
2n+2/2= y+2
n= y+1
1st integer= y+1-4= y-3
A is the answer
Answer: A
Question: Right triangle PQR is the base of the prism in the figure above. If PQ=PR=âˆš14 and the height of the prism is 8, what is the volume of the prism?
Options:
A)12
B)45
C)87
D)56
E)23
Rationale: Volume of prism = Area of base * height = 1/2* (square root of 14) * (square root of 14)*8 =56
Answer: D
Answer: D
Question: Two pipes P and Q can fill a cistern in 12 and 16 minutes respectively. Both are opened together, but at the end of 3 minutes the first is turned off. How much longer will the cistern take to fill?
Options:
A)11 1/2 min
B)11 1/4 min
C)11 2/4 min
D)12 min
E)11 7/4 min
Rationale: 3/12 + x/16 = 1
x= 12
Answer: D
Answer: D
Question: The total of the ages of Amar, Akbar and Anthony is 30 years. What was the total of their ages three years ago ?
Options:
A)20 years
B)28 years
C)71 years
D)21 years
E)31 years
Rationale: Explanation:
Required sum = (30 - 3 x 3) years = (30 - 9) years = 21 years.
Answer: Option D
Answer: D
Question: At a certain college, 80 percent of the total number of students are freshmen. If 60 percent of the fresh-men are enrolled in the school of liberal arts and, of these, 50 percent are psychology majors, what percent of the students at the college are freshmen psychology majors enrolled in the school of liberal arts?
Options:
A)25%
B)20%
C)22%
D)21%
E)24%
Rationale: Let's say there is a TOTAL of100students at this college.
80 percent of the total number of students are freshmen.
# of freshmen = 80% of 100 =80
60 percent of the fresh-men are enrolled in the school of liberal arts...
Number of liberal arts freshmen = 60% of 80 = 48
...and, of these, 50 percent are psychology majors...
Number of liberal arts freshmen who are psychology majors = 50% of 48=24
What percent of the students at the college are freshmen psychology majors enrolled in the school of liberal arts?
24/100= 24%
Answer:E
Answer: E