divelab/Sys2Bench huggingface dataset:
Question: A license plate in the country Kerrania consists of four digits followed by two letters. The letters A, B, and C are used only by government vehicles while the letters D through Z are used by non-government vehicles. Kerrania's intelligence agency has recently captured a message from the country Gonzalia indicating that an electronic transmitter has been installed in a Kerrania government vehicle with a license plate starting with 79. If it takes the police 12 minutes to inspect each vehicle, what is the probability that the police will find the transmitter within three hours?
Options:
A)18/79
B)1/60
C)1/25
D)1/50
E)1/900
Rationale: If it takes 12 minutes to inspect one vehicle, the # of vehicles that can be inspected in 3 hours (180 minutes) = 180/12 = 15. Hence, for calculating the probability that the police will find the transmitter within three hours, the favorable cases = 15. Now, we need to figure out the total # of cases.
The total # of cases = Total # of such cars possible. The details given about the car is that it starts with 79, which leaves 2 more digits, both of which can be filled by all 10 numbers (0-9). In addition, we have 3 letters, each of which can be filled by any from the set {A,B,C}. Hence the total # of such cars possible = 10*10*3*3 = 900
So, the probability that the police will find the transmitter within three hours = 15/900 = 1/60. Option B
Answer: B
Question: A man swims downstream 28 km and upstream 16 km taking 4 hours each time, what is the speed of the man in still water?
Options:
A)6.5
B)8.6
C)7.5
D)9.2
E)5.5
Rationale: 28 --- 4 DS = 7
? ---- 1
16 ---- 4 US = 4
? ---- 1 M = ?
M = (7 + 4)/2 = 5.5
Answer: E
Answer: E
Question: In a river flowing at 2 km/hr, a boat travels 48 km upstream and then returns downstream to the starting point. If its speed in still water be 6 km/hr, find the total journey time.
Options:
A)10 hours
B)12 hours
C)14 hours
D)18 hours
E)None of these
Rationale: Explanation :
speed of the boat = 6 km/hr
Speed downstream = (6+2) = 8 km/hr
Speed upstream = (6-2) = 4 km/hr
Distance traveled downstream = Distance traveled upstream = 48 km
Total time taken = Time taken downstream + Time taken upstream
= (48/8) + (48/4) = 18 hr. Answer : Option D
Answer: D
Question: If x is a prime integer and y = 9x, which of the following CANNOT be a divisor of y?
Options:
A)18
B)45
C)28
D)27
E)99
Rationale: Prime integer are as follows as 2,3,5,7,11.,
y = 9x
Go with options
if it is 18 so x must be 2 which is a prime integer
if it is 45 so x must be 5 which is a prime integer
if it is 28 so x must be 4 which is not a prime integer
so ans is C
Answer: C
Question: After decreasing 20% in the price of an article costs Rs.620. Find the actual cost of an article?
Options:
A)775
B)620
C)750
D)800
E)720
Rationale: CP* (80/100) = 620
CP= 7.75 * 100 => CP = 775
ANSWER:A
Answer: A
Question: From 5 consonants and 4 vowels, how many words can be formed using 3 consonants and 2 vowels?
Options:
A)7000
B)7200
C)7800
D)7500
E)None
Rationale: From 5 consonants, 3 consonants can be selected in 5C3 ways. From 4 vowels, 2 vowels can be selected in 4C2 ways. Now with every selection, number of ways of arranging 5 letters is 5P5 Total number of words =5C3*4C2*5P5= 7200
Answer B
Answer: B
Question: A man complete a journey in 10 hours. He travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km.
Options:
A)220 km
B)224 km
C)230 km
D)234 km
E)255 km
Rationale: (1/2)x/21 + (1/2)x/24 = 10
x/21 + x/24 = 20
15x=168x20
x=[168x20/15] = 224km
Answer is B
Answer: B
Question: A coin is tossed until sequence HTH appears (H denotes the fall of heads, T denotes the fall of tails). What is the probability E that the game will end after the fourth throw?
Options:
A)1/16
B)3/32
C)1/8
D)3/16
E)1/4
Rationale: Another approach:
Two likely scenarios would be : HHTH or THTH
for each of the scenarios probability would be 1/16
So Probablilty E is 1/16 + 1/16 = 1/8.C
Answer: C
Question: Find the odd man out
49, 51, 53, 55, 57, 62
Options:
A)57
B)53
C)49
D)62
E)51
Rationale: 62 is the number which is not belong to the arithmetic progression where all other number are in A.P. Ans: D
Answer: D
Question: In how many ways can a group of 20 friends be seated round 2 tables if one of the tables can seat 12 and the other can seat 8 people?
Options:
A)15C5 * 9! *4!
B)15C3 * 8! *3!
C)20C4 * 11! * 7!
D)21C2 * 10! *3!
E)25C5 * 10! *4!
Rationale: 12 people can be selected from 20 people in 20C12 ways.
Remaining 8 people can be selected from 8 people in 8C8 ways.
Now, arranging 12 people on a round table = (12-1) ! = 11!
Arranging 8 people on a round table = (8-1) ! = 7!
Hence, total number of ways = 20C12 * 11! * 8C8 * 7!
= 20C4 * 11! * 7!
C
Answer: C
Question: A Man travelled a distance of 61 km in 9 hours. He travelled partly on foot at 4 km/hr and partly on bicycle at 9 km/hr. What is the distance travelled on foot?
Options:
A)33
B)38
C)16
D)87
E)127
Rationale: Let the time in which he travelled on foot = x hr
Then the time in which he travelled on bicycle = (9 - x) hr
distance = speed x time
⇒4x+9(9−x)=61⇒4x+81−9x=61⇒5x=20⇒x=4⇒ distance travelled on foot = 4x=4×4=16 km
Answer : C
Answer: C
Question: how many 6 digit no. can be formed using digits 0 to 5,without repetition such that number is divisible by digit at its unit place?
Options:
A)420
B)426
C)432
D)456
E)485
Rationale: when unit place is 1 then numbers which are divisible by 1 = 96 (4*4*3*2*1*1 ways)
when unit place is 2 then numbers which are divisible by 2 = 96 (4*4*3*2*1*1 ways)
when unit place is 3 then numbers which are divisible by 3 = 96 (4*4*3*2*1*1 ways)
when unit place is 3 then numbers which are divisible by 4 = 42 (3*3*2*1*1*1 ways when last two digits are 24 and 4*3*2*1*1*1 ways when last two digits are 04)
when unit place is 3 then numbers which are divisible by 5 = 96 (4*4*3*2*1*1 ways)
total=426
ANSWER:B
Answer: B
Question: The sum of the ages of 5 children born at the intervals of 3 years each is 70 years. What is the age of the youngest child?
Options:
A)2 years
B)4 years
C)6 years
D)8 years
E)10 years
Rationale: Let the ages of the children be x, (x + 3), (x + 6), (x + 9) and (x +12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 70
5x = 40 => x = 8.
Age of youngest child = x = 8 years.
ANSWER:D
Answer: D
Question: In how many ways can three boys and five girls sit in a row such that all boys sit together?
Options:
A)A)4320
B)B)9022
C)C)2880
D)D)1097
E)E)2781
Rationale: Treat all boys as one unit. Now there are Six students and they can be arranged in 6! ways. Again three boys can be arranged among themselves in 3! ways.
Required number of arrangements
= 6! * 3! = 720 * 6
= 4320.
Answer:A
Answer: A
Question: A and B start a business, with A investing the total capital of Rs.50000, on the condition that B pays A interest @ 10% per annum on his half of the capital. A is a working partner and receives Rs.1500 per month from the total profit and any profit remaining is equally shared by both of them. At the end of the year, it was found that the income of A is twice that of B. Find the total profit for the year?
Options:
A)53000
B)58000
C)50000
D)59000
E)69000
Rationale: Interest received by A from B = 10% of half of Rs.50000 = 10% * 25000 = 2500.
Amount received by A per annum for being a working partner = 1500 * 12 = Rs.18000.
Let 'P' be the part of the remaining profit that A receives as his share. Total income of A = (2500 + 18000 + P)
Total income of B = only his share from the remaining profit = 'P', as A and B share the remaining profit equally.
Income of A = Twice the income of B
(2500 + 18000 + P) = 2(P)
P = 20500
Total profit = 2P + 18000
= 2*20500 + 18000 = 59000
ANSWER:D
Answer: D
Question: Two trains of length 100 m and 200 m are 100 m apart. They start moving towards each other on parallel tracks, at speeds 90 kmph and 72 kmph. After how much time will the trains meet?
Options:
A)20/8 sec
B)20/9 sec
C)20/7 sec
D)22/7 sec
E)60/7 sec
Rationale: They are moving in opposite directions, relative speed is equal to the sum of their speeds.
Relative speed = (90 + 72)*5/18 = 9*5 = 45 mps.
The time required = d/s = 100/45 = 20/9 sec.Answer:B
Answer: B
Question: The sum of the numbers is 264. If the first number be twice the second and third number be one-third of the first, then the second number is:
Options:
A)48
B)54
C)72
D)84
E)27
Rationale: Let the second number be x. Then, first number = 2x and third number = 2x/3.
2x + x + 2x/3 = 264
11x/3 = 264
x = 72
ANSWER:C
Answer: C
Question: The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 43 kg, what is the weight of B?
Options:
A)28
B)30
C)32
D)34
E)31
Rationale: Let the weight of A, B and C are a,b and c respectively.
Average weight of A,B and C = 45
a + b + c = 45 × 3 = 135 --- equation(1)
Average weight of A and B = 40
a + b = 40 × 2 = 80 --- equation(2)
Average weight of B and C = 43
b + c = 43 × 2 = 86 --- equation(3)
equation(2) + equation(3) - equation(1)
=> a + b + b + c - (a + b + c) = 80 + 86 - 135
=> b = 80 + 86 -135 = 166 - 135 = 31
Weight of B = 31 Kg
Answer is E.
Answer: E
Question: Two taps can separately fill a cistern 5minutes and 15 minutes respectively and when the waste pipe is open, they can together fill it in 20 minutes. The waste pipe can empty the full cistern in?
Options:
A)A)7
B)B)4.6
C)C)8
D)D)9
E)E)5
Rationale: 1/5 + 1/15 - 1/x = 1/20
x = 4.6
Answer:B
Answer: B
Question: The speed of a boat in still water is 65kmph and the speed of the current is 20kmph. Find the speed downstream and upstream?
Options:
A)80,47 kmph
B)80,80 kmph
C)80,42 kmph
D)80,40 kmph
E)85,45 kmph
Rationale: Speed downstream = 65 + 20 = 85 kmph
Speed upstream = 65 - 20 = 45 kmph.Answer:E
Answer: E
Question: A mixture contains milk and water in the ratio 3:2. On adding 10 litters of water, the ratio of milk to water becomes 2:3. Total quantity of milk & water before adding water to it?
Options:
A)10
B)30
C)50
D)20
E)30
Rationale: Explanation:
milk:water = 3:2
after adding 10 liters of water
milk:water = 2:3
Olny water patrs increase when mixture of water
milk:wate = 3:2 = 2*(3:2) = 6:4
after adding 10 liters of water
milk:water = 2:3 = 3*(2:3) = 6:9
milk parts always same
Short cut method:
milk:water = 6 : 4
after adding 10 liters of water
milk:water = 6 : 9
milk is same but water increse 10liters then the water ratio is increse 5 parts
5 part -----> 10 liters
The quantity of milk in the original mixture is = 6 : 4 = 6 + 4 = 10
10 parts -----> 20 liters (Answer is = 20)
Short cut method - 2 : for Only milk problems
milk : water
6 : 4
6 : 9
milk ratio same but water ratio 5 parts incress per 10 liters
5 part of ratio -------> 10 liters
10 part of ratio ------> 20 liters
Answer: Option D
Answer: D
Question: How much is 55% of 40 is greater than 4/5 of 25?
Options:
A)29
B)776
C)2
D)12
E)99
Rationale: (55/100) * 40 – (4/5) * 25
22 - 20 = 2
Answer: C
Answer: C
Question: A car traveled the first quarter of a certain distance at six times the speed it traveled the remaining distance. What proportion of the total time traveled, was the time taken to travel the first quarter of the distance?
Options:
A)1/14
B)1/15
C)1/16
D)1/17
E)1/19
Rationale: These problems can be solved through algebra or sly number picking. Being a big fan of solving problems with numbers, let's pick a total distance divisible by 4 (say 40) so we can break it up into quarters, and a speed that can easily be one sixth, say 10. Each quarter is thus 10 kilometers (or miles or feet or angstroms for all it matters), and the runner's speed is 10 km/h for the first quarter and 1 2/3 km/h for the remaining quarters.
He'll take 1 hour to do the first quarter and then 6 hours for the second quarter, 6 hours for the third and 6 hours for the fourth. On total he will take 19 hours to complete this race, of which 1 hour was spent on the first quarter. So 1/19. Answer E.
Answer: E
Question: Alice’s take-home pay last year was the same each month, and she saved the same fraction of her take-home pay each month. The total amount of money that she had saved at the end of the year was 5 times the amount of that portion of her monthly take-home pay that she did NOT save. If all the money that she saved last year was from her take-home pay, what fraction of her take-home pay did she save each month?
Options:
A)1/7
B)1/5
C)1/4
D)5/17
E)1/3
Rationale: Alice's take-home pay was the same each month, and she saved the same fraction of her take-home pay each month. The total amount of money she had saved at the end of the year was 3 times the amount of that portion of her monthly take-home pay that she did not save. If all the money that she saved last year was from her take-home pay, what fraction of her take-home pay did she save each month?
solution:
Suppose the portion of her salary that she saved is X
and the remaining portion is Y
X+Y= total take home salary
given, 12X = 5Y
or 12/5X = Y
Total take-home salary= X+12/5X= 17/5 X
hence, she saved 5/17-th portion of her take home salary
D
Answer: D
Question: 8,27,64,125,216,???,512
Options:
A)346
B)343
C)348
D)339
E)340
Rationale: it is a series of cubes of numbers....
8=2^3
27=3^3
64=4^3
125=5^3
216=6^3
512=8^3
So, 7^3=343 is the missing number.
ANSWER:B
Answer: B
Question: Donovan took a math test and got 35 correct and 12 incorrect answers.
What was the percentage of correct answers? (Round to the nearest
hundredth)
Options:
A)57.78%
B)67.78%
C)74.47%
D)47.78%
E)97.78%
Rationale: 35 correct our of 47 total (35+12)
35/47
correct answer C
Answer: C
Question: One copy machine can make 20 copies a minute, and a second copy machine makes 10 copies a minute. If the two copiers work together, how long would it take them to make 900 copies?
Options:
A)10 minutes
B)20 minutes
C)25 minutes
D)30 minutes
E)35 minutes
Rationale: Total work done by both machines in a minute = 20 + 10 = 30 copies
Total number of copies required = 900
Time = 900/30 = 30 mins
Answer D
Answer: D
Question: In a fuel station the service costs $1.75 per car, every liter of fuel costs 0.75$. Assuming that a company owns 12 cars and that every fuel tank contains 55 liters and they are all empty, how much money total will it cost to fuel all cars?
Options:
A)320$
B)420$
C)490$
D)516$
E)680$
Rationale: 12*1.75 + 0.75*12*55 = 516 hence - D
Answer: D
Question: Find the fraction which has the same ratio to 2/13 that 5/34 has to 7/48.
Options:
A)240/1542
B)230/1521
C)240/1547
D)240/1528
E)240/1521
Rationale: P : 2/13 = 5/34 : 7/48
As the product of the means is equal to the product of the extremes.
P*7/48 = 2/13 * 5/34
P*7/48 = 10/442
P = 480/3094 => P = 240/1547
Answer: C
Answer: C
Question: Two men X and Y started working for a certain company at similar jobs on January 1, 1950. X asked for an initial salary of Rs. 300 with an annual increment of Rs. 30. Y asked for an initial salary of Rs. 200 with a rise of Rs. 15 every 6 months. Assume that the arrangements remained unaltered till December 31, 1959. Salary is paid on the last day of the month. What is the total amount paid to them as salary during the period?
Options:
A)Rs. 93,300
B)Rs. 93,200
C)Rs. 93,100
D)None of these
E)Cannot be determined
Rationale: Explanation :
Amount of money given to X
= 12 x 300 + 12 x 330 + ....... + 12 x 570.
= 12[ 300 + 330 + .........+ 540 + 570 ].
= 12 x (10/2) [ 600 + 9 x 30 ].
= 52200.
Amount of money given to Y is
= 6 x 200 + 6 x 215 + 6 x 230 + 6 x 245 + ... upto 20 terms
= 6 [ 200 + 215 + 230 + .....485 ]
= 6 x (20/2)[ 400 + 19 x 15]
= 6 x 10 [ 400 + 285 ] .
= 60 x 685 = 41110
Hence, the total amount paid is 52200 + 41110 = Rs 93,300.
Answer : A
Answer: A
Question: A is half good a work man as B and together they finish a job in 18 days. In how many days working alone B finish the job?
Options:
A)23
B)22
C)27
D)36
E)48
Rationale: C
27
WC = 1:2
2x + x = 1/18 => x = 1/54
2x = 1/27 => 27 days
Answer: C
Question: The sum of 55 consecutive integers is 5555. What is the greatest integer in the set?
Options:
A)126
B)128
C)130
D)132
E)134
Rationale: Let x be the first integer in the set, then x+54 is the largest integer.
The sum is: x+(x+1)+(x+2)+...+(x+54)
= 55x + 54*55/2
= 55(x+27)
Then x+27=101
x=74
The largest integer in the set is 74+54=128
The answer is B.
Answer: B
Question: On dividing a number by 999, the quotient is 366 and the remainder is 103. The number is:
Options:
A)364724
B)365387
C)365737
D)366757
E)None of these
Rationale: Required number= 999*366+103= (1000-1)*366+103= 366000-366+103= 365737.
Answer: C
Answer: C
Question: The ratio of three numbers is 1:2:3 and their sum is 60. The second number of the three numbers is?
Options:
A)24
B)26
C)20
D)29
E)30
Rationale: 1:2:3
Total parts = 6
6 parts --> 60
1 part ---->10
The second number of the three numbers is =2 * 10 = 20
Answer : C
Answer: C
Question: Carl can wash all the windows of his house in 6 hours. His wife Maggie can wash all the windows in 7 hours. How many hours will it take for both of them working together to wash all the windows?
Options:
A)2
B)2 1/4
C)42 3/3
D)4 1/2
E)5
Rationale: Work hrs=AB/(A+B)= 42/13 =42 3/3
Answer is C
Answer: C
Question: Gordon is twice as old as Tony was when Gordon was as old as Tony is now. The combined age of Gordon and Tony is 112 years. How old are Gordon and Tony now?
Options:
A)Gordon 64 and Tony 48
B)Gordon 74 and Tony 38
C)Gordon 84 and Tony 48
D)Gordon 64 and Tony 58
E)None of the above
Rationale: When Gordon was 48, Tony was 32(ie half the age Gordon is now).
Answer : A
Answer: A
Question: If an object travels 300 feet in 5 seconds, what is the object's approximate speed in miles per hour? (Note: 1 mile = 5280 feet)
Options:
A)39
B)38
C)40
D)41
E)34
Rationale: 1 mile = 5280 feet
=> 1 feet = 1/5280 miles
If the object travels 300 feet in 5 sec
then it travels 300/5 * 60 * 60 feet in 1 hour (1 hr = 60 min * 60 sec)
= 3600 * 60 feet in 1 hour
= 216000 feet in 1 hr
= 216000/5280 miles in 1 hour
= 21600/528 miles/hr ~ 41 miles/hr
Answer - D
Answer: D
Question: Find the amount on Rs.8000 in 9 months at 20% per annum, if the interest being compounded quarterly?
Options:
A)2977
B)9261
C)2890
D)2890
E)3243
Rationale: A = 8000(21/20)3
= 9261
Answer: B
Answer: B
Question: In a company 10% of male staff are same in number as 1/4th of the female staff. What is the ratio of male staff to female staff
Options:
A)3 : 2
B)5 : 2
C)2 : 1
D)4 : 3
E)1 : 2
Rationale: 10% of MS = 1/4th of FS
-> 10MS/100 = 1/4FS
-> MS = 5/2 FS
:. MS/FS = 5/2 = MS : FS = 5 : 2
ANSWER:B
Answer: B
Question: A train moves fast a telegraph post and a bridge 264 m long in 4 sec and 20 sec respectively. What is the speed of the train?
Options:
A)89
B)23
C)59.4
D)79.2
E)67
Rationale: Let the length of the train be x m and its speed be y m/sec.
Then, x/y = 4 => x = 4y
(x + 264)/20 = y
y = 16.5
Speed = 16.5m/sec = 16.5 * 18/5 = 59.4 km/hr.
Answer: Option C
Answer: C
Question: There are 600 students in a school. The ratio of boys and girls in this school is 3:5. Find the total of girls & boys are there in this school?
Options:
A)243
B)265
C)375
D)390
E)400
Rationale: In order to obtain a ratio of boys to girls equal to 3:5, the number of boys has to be written as 3 x and the number of girls as 5 x where x is a common factor to the number of girls and the number of boys. The total number of boys and girls is 600. Hence
3x + 5x = 600
Solve for x
8x = 600
x = 75
Number of boys
3x = 3 × 75 = 225
Number of girls
5x = 5 × 75 = 375
C
Answer: C
Question: A circular rim 30 inches in diameter rotates the same number of inches per second as a circular rim 15 inches in diameter. If the smaller rim makes x revolutions per second, how many revolutions per minute does the larger rim makes in terms of x ?
Options:
A)48pi/x
B)75x
C)48x
D)24x
E)120x
Rationale: Revolutions - circumference of the rim.
=> 30pi*X*60 = 15pi*Revolutions
=> 2/1 *X *60 = Revolutions => 120X - Option E
Answer: E
Question: A 160 meter long train crosses a man standing on the platform in 9 sec. What is the speed of the train?
Options:
A)96 kmph
B)64 kmph
C)52 kmph
D)86 kmph
E)76 kmph
Rationale: S = 160/9 * 18/5 = 64 kmph
ANSWER:B
Answer: B
Question: If circles x and y have the same area and circle x has a circumference of 10π, half of the radius of circle y is:
Options:
A)16
B)8
C)4
D)2.5
E)1
Rationale: x be radius of circle x
y be radius of circle y
given:
pi*x^2 = pi*y^2
also,
2*pi*x = 10*pi
x =5
thus y = 5
y/2 = 2.5
Ans: D
Answer: D
Question: If $5,000 is invested in an account at a simple annual rate of r percent, the interest is $250. When $20,000 is invested at the same interest rate, what is the interest from the investment?
Options:
A)$700
B)$750
C)$800
D)$1000
E)$900
Rationale: -> 250/5,000=5% and 20,000*5%=1000.
Thus, D is the answer.
Answer: D
Question: If the perimeter of a rectangular garden is 900 m, its length when its breadth is 190 m is?
Options:
A)338 m
B)778 m
C)200 m
D)260 m
E)971 m
Rationale: 2(l + 190)
= 900 => l
= 260 m
Answer:D
Answer: D
Question: A completes a piece of work in 3/4 of the time in B does, B takes 4/5 of the time in C does. They got a profit of Rs. 40000 how much B gets?
Options:
A)12765
B)121227
C)26887
D)19977
E)26992
Rationale: Assume C takes 20 Days. Now B takes 4/5 (20) = 16 days. A takes 3/4(16) = 12
Now their efficiencies ratio = 1/20 : 1/16 : 1/12 = 12 : 15 : 20
B's share in the profit of Rs.40000 = 15/47 (40000) = Rs.12765
Answer:A
Answer: A
Question: A tank is filled by 3 pipes A,B,C in 8 hours. Pipe C is twice as fast as B and B is twice as fast as A. How much will pipe A alone take to fill the tank ?
Options:
A)25hr
B)35hr
C)56hr
D)20hr
E)50hr
Rationale: Suppose pipe A alone take x hours to fill the tank
Then pipe B and C will take x/2 and x/4 hours respectively to fill the tank.
1/x + 2/x + 4/x = 1/8
7/x = 1/8
x = 56 hours
Answer is C
Answer: C
Question: Apple costs L rupees per kilogram for first 30kgs and Q rupees per kilogram for each additional kilogram. If the price of 33 kilograms is 360 and for 36kgs of Apples is 420 then the cost of first 25kgs of Apples is
Options:
A)100
B)250
C)125
D)110
E)115
Rationale: Ans: By framing equations we get
30L+3Q=360
30L+6Q=420
Eliminate Q by multiplying the first equation by 2 and subtracting second equation from the first
Then we get L = 10
Cost of 10 kgs of apples =25x 10 = 250
Answer:B
Answer: B
Question: Approximately how many cubic feet of water are needed to fill a circular swimming pool that is 60 feet across and 6 feet deep?
Options:
A)900
B)4000
C)10000
D)17000
E)25000
Rationale: Answer Should be D.
V= \pir^2h= \pi*30^2*6= approximately 17000
Answer: D
Question: At what time between 8 and 9 o’clock will the hands of a watch be in straight line but not together?
Options:
A)10 11⁄10 min. past 8
B)10 10⁄11 min. past 8
C)11 10⁄11 min. past 8
D)12 10⁄11 min. past 8
E)None of these
Rationale: At 8 o’clock, the hands of the watch are 20 min. spaces apart.
To be in straight line but not together they will be 30 min. space apart.
∴ Minute hand will have to gain 10 min. spaces 55 min.spaces are gained in 60 min.
10 min. spaces will be gained in (60⁄55 × 50) min or 10 10⁄11 min
∴ Required time = 10 10⁄11 min. past 8
Answer B
Answer: B
Question: The cost price of an article is 55% of the marked price. Calculate the gain percent after allowing a discount of 15%.
Options:
A)40.5 %
B)48.7 %
C)54.5%
D)55.6% %
E)none
Rationale: Sol.
Let marked price = Rs. 100. Then, C.P. = Rs. 55. S.P = Rs. 85.
âˆ´ Gain % = [30/55 * 100]% = 54.5%.
Answer C
Answer: C
Question: A sum of Rs. 25000 becomes Rs. 27250 at the end of 3 years when calculated at simple interest. Find the rate of interest.
Options:
A)1%
B)2%
C)3%
D)4%
E)5%
Rationale: Simple interest = 27250 – 25000 = 2250
Time = 3 years.
SI = PTR / 100 → R = SI * 100 / PT
R = 2250 * 100 / 25000 * 3 → R = 3%. ANSWER : C
Answer: C
Question: The age of father 7 years ago was five times the age of his son. Five years hence, father's age will be thrice that of his son. The ratio of their present ages is:
Options:
A)67 : 19
B)65 : 17
C)61 : 19
D)63 : 15
E)67 : 17
Rationale: Let the ages of father and son 7 years ago be 5x and x years respectively.
Then, (5x + 7) + 5 = 3[(x + 7) + 5]
5x + 12 = 3x + 36
x = 12.
Required ratio = (5x + 7) : (x + 7) = 67 : 19.
Answer: Option A
Answer: A