divelab/Sys2Bench huggingface dataset:
Question: A man swims downstream 72 km and upstream 45 km taking 10 hours each time; what is the speed of the current?
Options:
A)1.55
B)1.85
C)1.65
D)1.35
E)1.15
Rationale: 72 --- 10 DS = 7.2
? ---- 1
45 ---- 10 US = 4.5
? ---- 1 S = ?
S = (7.2 - 4.5)/2 = 1.35
Answer:D
Answer: D
Question: A father is now three times as old as his son. Eight years back, he was four times as old as his son. The age of the son (in years) is
Options:
A)12
B)24
C)18
D)27
E)25
Rationale: If father's age is F and son's age is S, then
F=3S
and
F-8 = 4*(S-8)
3S-5 =4S-32
S=24
F=72 years
ANSWER:B
Answer: B
Question: In a group of 100 people, 90 have an age of more 30 years, and the others have an age of less than 20 years. If a person is selected at random from this group, what is the probability the person's age is less than 20?
Options:
A)0.1
B)0.55
C)0.65
D)0.75
E)0.85
Rationale: Number of people whose age is less than 20 is given by
100 - 90 = 10
Probability P that a person selected at random from the group is less than 20 is given by
10 / 100 = 0.1
correct answer A
Answer: A
Question: A certain auto manufacturer sold 8% fewer vehicles in 2007 than in 2006. If the manufacturer sold 2.1 million vehicles in 2006, how many vehicles, to the nearest 10,000, did the manufacturer sell in 2007?
Options:
A)63,000
B)1,930,000
C)2,030,000
D)2,040,000
E)2,300,000
Rationale: Let's assume in 2006 the manufacturer sold X.
In 2007 he sold X-8/100(X)
If sales in 2006,X= 2.1 million find X-8/100(X)
(2.1 x 10^6)-8/100(2.1 x 10^6)
2100000-168000=1,932,000-----> 1,930,000(approx)
ANSWER:B
Answer: B
Question: Twenty percent of Country Y's yearly exports come from fruit exports. One-sixth of all fruit exports from Country Y are orange exports. If country Y generates $4.5 million from its orange exports, how much money does it generate from its yearly total of exports?
Options:
A)$21.25m
B)$25.5m
C)$106.25m
D)$127.5m
E)$135m
Rationale: 2/10*1/6*(total) = 4.5
1/30*(total) = 4.5
(total) = 4.5*30 = 135
Answer: E.
Answer: E
Question: In a 100 member association consisting of men and women, exactly 10% of men and exactly 20 % women are homeowners. What is the maximum number of members who are homeowners?
Options:
A)29
B)27
C)25
D)23
E)21
Rationale: Solution simple
Out of 100 10% are male i.e 10 and 20% are female i.e 20 , so total homeowner is 30.
Now min number homeowner is 10 and max is 30 so question ask us to find maximum and 29 has maximum value among all option.
So ans is 29.
Ans: A
Answer: A
Question: A is a working partner and B is a sleeping partner in the business. A puts in Rs.3500 and B Rs.2500, A receives 10% of the profit for managing the business the rest being divided in proportion of their capitals. Out of a total profit of Rs.9600, money received by A is?
Options:
A)1978
B)2707
C)7728
D)4200
E)6000
Rationale: 35:25 => 7:5
9600*10/100 = 960
9600 - 960 = 8640
8640*7/12 = 5040 + 960
= 6000
Answer: E
Answer: E
Question: 12 men work 8 hours per day to complete the work in 10 days. To complete the same work in 4 days, working 15 hours a day, the number of men required?
Options:
A)15days
B)12days
C)16days
D)18days
E)20days
Rationale: That is, 1 work done = 12 × 8 × 10
Then, 12 8 × 10 = ? × 15 × 6
? (i.e. No. of men required) = 12 × 8 × 10/15× 6 = 16 days
C)
Answer: C
Question: A sum fetched a total simple interest of Rs. 1000 at the rate of 10 p.c.p.a. in 4 years. What is the sum?
Options:
A)2500
B)2800
C)3500
D)1900
E)1500
Rationale: Sol.
Principal = Rs. [100 * 1000 / 10 * 4] = Rs. [100000 / 40] = Rs. 2500.
Answer A
Answer: A
Question: David and Rachel are getting married. The extended family wants to have its picture taken, but David's father is unwilling to stand next to Rachel's mother. How many options does the photographer have to arrange the 6 family members in a row for the picture?
Options:
A)9!
B)9×8!
C)4x5!
D)10!/2!
E)10!
Rationale: In how many ways David's father and Rachel's mother can stand together? Consider them as one unit: {F, M}. So, we'd have 9 units {F, M}, 1, 2, 3, 4, which can be arranged in 9! ways. David's father and Rachel's mother within their unit can be arranged in 2! ways. Therefore, David's father and Rachel's mother can stand together in 5!*2! ways.
Total - Restriction =
= 6! - 5!*2! =
= 5!(6- 2!) =
= 4*5!.
Answer: C.
Answer: C
Question: There are 6 gentlemen and 5 ladies to dine at a round table. In how many ways can they seat themselves so that no two ladies are seated together.
Options:
A)85400
B)36400
C)86400
D)65600
E)88600
Rationale: 6 men can be arranged around a table in (6-1)!=5! ways.
Now, if we place each woman between the men then no two women will be together. There are 6 available slots between the men, thus 6C5=6 is the number of ways we can choose 5 slots out of 6 for the women.
Next, these 5 women can be arranged in 5! ways, hence the total number of ways is 5!*6*5!=86,400.
Answer: C.
Answer: C
Question: The greatest common factor of 16 and the positive integer n is 4, and the greatest common factor of n and 45 is 3. Which of the following could be the greatest common factor of n and 420?
Options:
A)15
B)48
C)64
D)84
E)90
Rationale: n includes the factors 2^2 (but not 2^3) and 3 (but not 3^2 or 5)
420 = 4*3*5*7
The GCF could be 12 or 84.
The answer is D.
Answer: D
Question: What approximate value should come in place of the question mark (?) in the following equation?
1.542 × 2408.69 + 8134.632 = ?
Options:
A)14600
B)11800
C)12030
D)16400
E)13600
Rationale: Explanation 3700 + 8100 = 11800
Answer B
Answer: B
Question: Carol spends 1/4 of her savings on a stereo and 1/3 less than she spent on the stereo for a television. What fraction of her savings did she spend on the stereo and television?
Options:
A)1/4
B)2/7
C)5/12
D)1/2
E)7/12
Rationale: Total Savings = S
Amount spent on stereo = (1/4)S
Amount spent on television = (1-1/3)(1/4)S = (2/3)*(1/4)*S = (1/6)S
(Stereo + TV)/Total Savings = S(1/4 + 1/6)/S = 5/12
Answer: C
Answer: C
Question: If a copier makes 3 copies every 4 seconds, then continues at this rate, how many minutes will it take to make 9,000 copies?
Options:
A)60
B)100
C)120
D)200
E)3,000
Rationale: Let x = seconds to make 9000 copies.
We get: 3/4 = 9000/x
Cross multiply to get: 3x = (4)(9000)
Simplify: 3x = 36,000
Solve: x = 12,000 SECONDS
There are 60 seconds in a minute.
12,000/60 = 200
So, it takes 200 MINUTES to make 9000 copies
Answer: D
Answer: D
Question: A man can row 30 km downstream and 20 km upstream in 4 hours. He can row 45 km downstream and 40 km upstream in 7 hours. Find the speed of man in still water?
Options:
A)92.5 kmph
B)17.5 kmph
C)15.5 kmph
D)12.5 kmph
E)22.5 kmph
Rationale: Let the speed of the man in still water be a kmph and let the speed of the stream be b kmph.
Now 30/(a + b) + 20/(a - b) = 4 and 45/(a + b) + 40/(a - b) = 7
Solving the equation, the speed of man in still water is 12.5 kmph.
Answer: D
Answer: D
Question: Ten cards numbered 1 to 10 are placed in a box, mixed up thoroughly and then one card is drawn
randomly. If it is known that the number on the drawn card is more than 3, what is the probability
that it is an even number?
Options:
A)1/3
B)1/5
C)4/7
D)7/4
E)2/7
Rationale: Let A be the event ‘the number on the card drawn is even’ and B be the
event ‘the number on the card drawn is greater than 3’. We have to find P(A|B).
Now, the sample space of the experiment is S = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
Then A = {2, 4, 6, 8, 10}, B = {4, 5, 6, 7, 8, 9, 10}
and A n B = {4, 6, 8, 10}
Also P(A) = 5/2, P(B) = 7/10 and P(A n B) = 4/10
Then P(A|B) = P(A n B)/P(B) = (4/10)/(7/10) = 4/7
C
Answer: C
Question: How many different arrangements of letters are possible if three letters are chosen from the letters A through E and the letters E and A must be among the letters selected?
Options:
A)72
B)64
C)36
D)18
E)6
Rationale: Since A and E must be among 3 letters then the third letter must be out of B, C and D. 3C1 = 3 ways to choose which one it'll be. Now, 3 different letters (A, E and the third one) can be arranged in 3!=6 ways, so the final answer is 3*6=18.
Answer: D.
Answer: D
Question: Indu gave Bindu Rs.4375 on compound interest for 2 years at 4% per annum. How much loss would Indu has suffered had she given it to Bindu for 2 years at 4% per annum simple interest?
Options:
A)1
B)2
C)7
D)4
E)9
Rationale: 4375 = D(100/4)2
D = 7
Answer:C
Answer: C
Question: A meeting has to be conducted with 4 managers. Find the number of ways in which the managers may be selected from among 7 managers, if there are 2 managers who refuse to attend the meeting together.
Options:
A)18
B)21
C)25
D)30
E)35
Rationale: The total number of ways to choose 4 managers is 7C4 = 35
We need to subtract the number of groups which include the two managers, which is 5C2 = 10.
35 - 10 = 25
The answer is C.
Answer: C
Question: In how many different ways can the letters of the word ORGANISE be arranged in such a way that all the vowels always come together and all the consonants always come together?
Options:
A)576
B)1152
C)2880
D)1440
E)None of these
Rationale: The word ORGANISE has 4 vowels and 4 consonants.
Now, both groups (vowels and consonants) can be treated as two letters. This can be arranged in 2! ways.
Now, the 4 letters of each group can be arranged.in 4! ways.
So, total possible ways of arrangement
= 2! × 4! × 4!
= 2 × 24 × 24 = 1152.
Answer B
Answer: B
Question: In a certain school, 20% of the students are below 8 yrs of age. The number of students above 8 yrs of age is (2/3) of the number of students of 8 years age which is 96. What is the total number of students in the school?
Options:
A)237
B)200
C)267
D)176
E)161
Rationale: Explanation:
Let total students be x.
⇒ 0.2x + 2323 × 96 + 96 = x
⇒ x = 200
Answer: B
Answer: B
Question: The combined salaries of three brothers is $180,000. Mr. Big earns twice what Mr. Small earns, and Mr. Middle earns 1 1/2 times what Mr. Small earns. What is the smallest salary of the three brothers?
Options:
A) 20,000
B) 22,000
C) 25,000
D) 30,000
E) 40,000
Rationale: Mr. Small = x;
Mr. Middle = 3/2*x;
Mr. Big = 2x.
x + 3/2*x + 2x = 180 --> x=40
Answer: E
Answer: E
Question: Which of the following is closer to (22!+21!)/(22!-21!)?
Options:
A)49
B)36
C)1
D)16
E)25
Rationale: Notice that 22! = (22)(21!), so we can factor out 21! from top and bottom.
(22!+21!)/(22!-21!)=[21!(22+1)]/[21!(22-1)]
= (22+1)/(21-1)
= 23/21
≈ 1
Answer: C
Answer: C
Question: If 3 strawberry vines produce 30 fruit and 20 strawberry vines produce 200 fruit, how many fruit do 50 strawberry vines produce?
Options:
A)5
B)50
C)500
D)5000
E)3
Rationale: 3 x ? = 30
20 x ? = 200
50 x ? = ?
3 x 10 = 30
20 x 10 = 200
Therefore, each strawberry vine makes 10 fruits.
50 x 10 = 500
answer: c
Answer: C
Question: A credit card number has 6 digits (between 1 to 9 inclusive). The first two digits are 12 in that order, the third digit is bigger than 6, the fourth digit is divisible by 3, and the fifth digit is 4 times the sixth. How many different credit card numbers are possible?
Options:
A)12
B)15
C)18
D)24
E)36
Rationale: The first two digits are fixed.
The third digit can be 7, 8, or 9 so there are 3 choices.
The fourth digit can be 3, 6, or 9 so there are 3 choices.
The fifth digit depends entirely on the sixth digit.
The sixth digit can be 1 or 2 so there are 2 choices.
The number of possibilities is 3*3*2 = 18
The answer is C.
Answer: C
Question: The breath of a rectangle is three- seventh of the radius of a circle. The radius of the circle is equal to the side of the square, whose area is 1225 sq.units. What is the area (in sq.units) of the rectangle if the rectangle if the length is 10 units?
Options:
A)310 sq.units
B)110 sq.units
C)210 sq.units
D)105 sq.units
E)205 sq.units
Rationale: Given that the area of the square = 4900 sq.units
=> Side of square = √4900 = 70units
The radius of the circle = side of the square = 49 units breath of the rectangle = 3/7 * 49 = 21units
Given that length = 10 units
Area of the rectangle = lb = 21 * 10 = 210 sq.units
Answer:C
Answer: C
Question: Each of the integers from 0 to 9, inclusive, is written on a separate slip of blank paper and the ten slips are dropped into hat. If the slips are then drawn one at a time without replacement, how many must be drawn to ensure that the numbers on two of the slips drawn will have a sum of 12?
Options:
A)8
B)4
C)5
D)6
E)7
Rationale: i'm not sure i got the question right, if it is what i think it is, then 8 should be the right answer
0,1,2,3,4,5, will not have 2 slip sum of 10, add another (either 6,7,8 or 9) and we'll have a pair with sum 12
Ans:8
Answer: A
Question: Out of the fractions 4/7, 5/13, 6/11, 3/5 and 2/3 which is the second smallest fraction ?
Options:
A)4/7
B)5/13
C)6/11
D)3/5
E)None
Rationale: Answer
4/7 = 0.57,
5/13 = 0.38,
6/11 = 0.54,
3/5 = 0.6 and
2/3 = 0.67
Clearly, the second smallest fraction is 6/11
Correct Option: C
Answer: C
Question: Rs.2500 is divided into two parts such that if one part be put out at 5% simple interest and the other at 6%, the yearly annual income may be Rs.140. How much was lent at 5%?
Options:
A)2978
B)2681
C)2689
D)1000
E)2760
Rationale: (x*5*1)/100 + [(2500 - x)*6*1]/100
= 140
X = 1000
Answer: D
Answer: D
Question: The difference between a number and its two-fifth is 510. What is 10% of that number?
Options:
A)12.75
B)85
C)204
D)224
E)95
Rationale: Let the number be x. Then,
x - 2/5 x = 510
x = (510 * 5)/3 = 850
10% of 850 = 85.
ANSWER:B
Answer: B
Question: A train of 40 carriages, each of 60 meters length, when an engine also of 60 meters length is running at a speed of 60 kmph. In what time will the train cross a bridge 1.5 km long?
Options:
A)6
B)3
C)4
D)3.9
E)3.6
Rationale: D = 40 * 60 + 1500 = 3900 m
T = 3900/60 * 18/5 = 234 sec = 3.9 mins
Answer:D
Answer: D
Question: Two mixtures A and B contain milk and water in the ratios 2:5 and 5:4 respectively. How many gallons of A must be mixed with 90 gallons of B so that the resultant mixture contains 40% milk?
Options:
A)144
B)122.5
C)105.1
D)72
E)134
Rationale: Mixture A: 2:5 ratio of Milk:Water
Mixture B: 5:4 ratio of Milk:water
90 gallons mixture B with a ratio of 5:4 = 50 gallons of milk and 40 gallons of water 90/(5+4) = 10. 10*5 = 50 and 10*4 = 40.
(50+(2/7x))/(90+x) = .40
50+(2/7x)=.4(90+x)
50+(2/7x)=(2/5x)+36
50+(10/35x)=(14/35x) +36
4/35x=14
4x=14*35
4x=490
x=122.5 gallons
ANSWER:B
Answer: B
Question: 0.1 decates ago, Vijaya was quadrice as old as her daughter Simran. 0.6 decades hence, Vijaya’s age will beat her daughter’s age by 0.9 decades. The proportion of the current ages of Vijaya and Simran is : [ 0.1 Decates =1 Year; quadrice = 4 times]
Options:
A)8:1
B)10:2
C)11:4
D)13:4
E)None of these
Rationale: Explanation:
Let, Ages of Vijaya and Simran – 1 year ago was 4A and A years correspondingly.
Then, [(4A + 1) + 6] – [(A + 1) + 6] = 9
3A = 9 A = 3
Needed Ratio = (4A + 1) : (A + 1) = 13 : 4.. Answer: D
Answer: D
Question: The total car population in a Mumbai is 2,94,00 out of which 1,50,00 are made by Honda. Out of every 100 Honda cars, 98 are red in color, but only 53% of the total car population is red. Find the % of non-Honda cars that are red
Options:
A)5.456%
B)6.124%
C)6.125%
D)7.256%
E)8.234%
Rationale: Total Car.29.10 i.e., Honda +non Honda = 29400 Given: Whim. tractor .150W
Now,5346 of 2..00 = Honda +Red Non-Honda 29400 .:4 =15582 Thus...El Mall... 1.0 Now Honda 15582 flow, Non-. Honda =15582 - 15.582-14700=8B2 96 non-Honda =1=1.100 = 6.125%
C
Answer: C
Question: 46 x 46 = ?
Options:
A)2500
B)2516
C)1600
D)36
E)2116
Rationale: 46 x 46	= (46)2
= (50 - 4)2
= (50)2 + (4)2 - (2 x 50 x 4)
= 2500 + 16- 400
= 2516 - 400
= 2116
E)
Answer: E
Question: Points M(9,4) and N(5,8) lie on the xy - plane. What is the midpoint of line segment MN?
Options:
A)(7,6)
B)(0,5)
C)(0, (136^(1/2))/2)
D)(3/2,0)
E)(1,5)
Rationale: The midpoint of a segment is exactly halfway between its endpoints and it's location can be found using the Midpoint Theorem, which states:
• The x-coordinate of the midpoint is the average of the x-coordinates of the two endpoints.
• Likewise, the y-coordinate is the average of the y-coordinates of the endpoints.
So, x=(9+5)/2=7 and y=(4+8)/2=6 --> coordinates of the midpoint are (7, 6).
Answer: A.
Answer: A
Question: A certain amount earns simple interest of Rs. 1750 after 7 years. Had the interest been 2% more, how much more interest would it have earned?
Options:
A)2:6
B)2:6
C)2:3
D)2:4
E)2:9
Rationale: Let the principal be P and rate of interest be R%.
Required ratio = [(P * R * 6)/100] / [(P * R * 9)/100]
= 6PR/9PR = 6/9
= 2:3
Answer: C
Answer: C
Question: The ratio between a two-digit number and the sum of the digits of that
number is 4 : 1.If the digit in the unit's place is 3 more than the digit in the ten’s place, what is the number?
Options:
A)47
B)36
C)58
D)25
E)14
Rationale: Let the ten's digit be x. Then, unit's digit = (x + 3).
Sum of the digits = x + (x + 3) = 2x + 3. Number = l0x + (x + 3) = llx + 3.
11x+3 / 2x + 3 = 4 / 1 => 11x + 3 = 4 (2x + 3) => 3x = 9 => x = 3.
Hence, required number = 11x + 3 = 36.
Answer is B.
Answer: B
Question: The ratio of number of ladies to gents at a party was 1 : 2, but when 2 ladies and 2 gents left, the ratio became 1 : 3. How many people were originally present at the party?
Options:
A)6
B)9
C)12
D)10
E)11
Rationale: Let number of ladies = x
then, number of gents = 2x
Now, x−2/2x−2=1/3⇒ 3x - 6 = 2x - 2
⇒ x = 4
∴ Total number of people originally present = 4 + 8 = 12
Answer C
Answer: C
Question: 15 men take 21 days of 8 hours each to do a piece of work. How many days of 6 hours each would 21 women take to do the same. If 3 women do as much work as 2 men?
Options:
A)16
B)30
C)86
D)27
E)82
Rationale: 3W = 2M
15M ------ 21 * 8 hours
21 W ------ x * 6 hours
14 M ------ x * 6
15 * 21 * 8 = 14 * x * 6
x = 30
Answer: C
Answer: C
Question: A student traveled 30 percent of the distance of the trip alone, continued another 20 miles with a friend, and then finished the last half of the trip alone. How many miles long was the trip?
Options:
A)240
B)200
C)160
D)100
E)50
Rationale: Let x be the total length of the trip.
0.3x + 20 miles + 0.5x = x
20 miles = 0.2x
x = 100 miles
The answer is D.
Answer: D
Question: A and B enter into a partnership with respective capitals of Rs. 20,000 and Rs. 40,000. At the end of the year, the total profit is Rs. 27,000. If A receives Rs. 15,000 as both his salary and profit, then what is his salary?
Options:
A)Rs. 2000
B)Rs. 4000
C)Rs. 6000
D)Rs. 3000
E)None of these
Rationale: Explanation:
A's capital : B 's capital
20000 : 40000 = 1 : 2
Since, the time period is fixed, the profit is distributed in the ratio of capital 1 : 2
Profit of A = (1/3) * 27,000 = Rs. 9,000
Salary of A = Rs. (15000 – 9000) = Rs. 6000
ANSWER: C
Answer: C
Question: On dividing $200 between A and B such that twice of A's share is less than 2 times the total share of A and B by 100. Find B's share.
Options:
A)100
B)120
C)70
D)90
E)50
Rationale: Let A's share be X and B's share be Y.
=>2*X=2*(X+Y)-100
=>2Y=100
=>Y=50
Option E
Answer: E
Question: If the ratio of the sum of the first 6 terms of a G.P. to the sum of the first 3 terms of the G.P. is 217, what is the common ratio of the G.P?
Options:
A)3
B)1/3
C)2
D)6
E)1/6
Rationale: 217=(a1+a2+a3+a4+a5+a6)/(a1+a2+a3)
Factorize the same terms
217=1+(a4+a5+a6)/(a1+a2+a3)
Write every term with respect to r
a1=a1
a2=a1*r^1
a3=a1*r^2
.........
217=1+(a1(r^3+r^4+r^5))/(a1(1+r^1+r^2))
216=(r^3 (1+r^1+r^2))/((1+r^1+r^2))
216=r^3
r=6
D
Answer: D
Question: Find the sum of all 3 digit natural numbers, which are divisible by 8
Options:
A)61376
B)54411
C)612314
D)64170
E)64171
Rationale: The three digit natural numbers divisible by 8 are
104, 112, 120, …. 992.
Let Sndenote their sum. That is, Sn = 104 112 120 128 , 992 g + + + + + .
Now, the sequence 104, 112, 120, g, 992 forms an A.P.
a=104, d=8, l=992
n=l-a/d
n=112
S112=n/2(a+l)=61376
ANSWER A 61376
Answer: A
Question: If x=3y=4z, what is z+y, in terms of x?
Options:
A)3x/5
B)4x/9
C)11x/13
D)7x/12
E)5x/11
Rationale: x=3y=4z
x/4 = z
and y = x/3
z+y = x/4 + x/3 = 7x/12
Answer is D
Answer: D
Question: What amount does Kiran get if he invests Rs.6450 at 15% p.a. compound interest for two years, compounding done annually?
Options:
A)8400
B)8900
C)4560
D)8530
E)9890
Rationale: A= P{1 + R/100}n
=> 6450{1 + 15/100}2
= Rs.8530
Answer: D
Answer: D
Question: On Thursday Mabel handled 90 transactions. Anthony handled 10% more transactions than Mabel, Cal handled 2/3rds of the transactions that Anthony handled, and Jade handled 18 more transactions than Cal. How much transactions did Jade handled?
Options:
A)80
B)81
C)82
D)83
E)84
Rationale: Solution:
Mabel handled 90 transactions
Anthony handled 10% more transactions than Mabel
Anthony = 90 + 90 × 10%
= 90 + 90 × 0.10
= 90 + 9
= 99
Cal handled 2/3rds of the transactions than Anthony handled
Cal = 2/3 × 99
= 66
Jade handled 18 more transactions than Cal.
Jade = 66 + 18
= 84
Jade handled = 84 transactions.
Answer: E
Answer: E
Question: Find the number of square tiles to cover the floor of a room measuring 4 m * 9 m leaving 0.25 m space around the room. A side of square tile is given to be 25 cms?
Options:
A)125
B)879
C)476
D)255
E)789
Rationale: Explanation:
3 1/2 * 8 1/2 = 1/4 * 1/4 * x => x = 476
Answer : C
Answer: C
Question: Find large number from below question The difference of two numbers is 1375. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder
Options:
A)1245
B)1345
C)1455
D)1577
E)1647
Rationale: Let the smaller number be x. Then larger number = (x + 1375).
x + 1375 = 6x + 15
5x = 1360
x = 272
Large number = 272+1375 = 1647
E
Answer: E
Question: The average weight of 10 persons increases by 3.2 kg when a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person?
Options:
A)76 kg
B)80 kg
C)85 kg
D)97 kg
E)None
Rationale: Solution
Total weight increased	= (10 x 3.2)kg
= 32 kg.
Weight of new person	= (65 + 32)kg
= 97 kg.
Answer D
Answer: D
Question: What no. should be subtracted from x^3+4x^2−7x+12x^3+4x^2−7x+12, if it is to be perfectly divisible by x+3x+3?
Options:
A)40
B)42
C)44
D)48
E)52
Rationale: According to remainder theorem when dfracf(x)x+adfracf(x)x+a, then the remainder is f(−a)f(−a).
In this case, as x+3x+3 divides x3+4x2−7x+12–kx3+4x2−7x+12–k perfectly (kk being the number to be subtracted), the remainder is 0 when the value of xx is substituted by -3.
i.e., (−3)3+4(−3)2−7(−3)+12−k=0(−3)3+4(−3)2−7(−3)+12−k=0
or −27+36+21+12=k−27+36+21+12=k
or k=k= 42
B
Answer: B
Question: A rectangular paper, when folded into two congruent parts had a perimeter of 34 cm for each part folded along one set of sides and the same is 38 cm when folded along the other set of sides. What is the area of the paper?
Options:
A)140 cm2
B)240 cm2
C)560 cm2
D)160 cm2
E)None of these
Rationale: When folded along breadth, we have :
2(l⁄2 + b) = 34 or l + 2b = 34 ....(i)
When folded along length, we have :
2(l + b⁄2) = 38 or 2l + b = 38 ....(ii)
Solving (i) and (ii), we get :
l = 14 and b = 10.
∴ Area of the paper = (14 × 10) cm2 = 140 cm2
Answer A
Answer: A
Question: If tomorrow will be a Sunday, what day was the day before yesterday?
Options:
A)Monday
B)Tuesday
C)Wednesday
D)Thursday
E)Friday
Rationale: Explanation:
Tomorrow will be a Sunday
=>Today is a Saturday
=> Yesterday was a Friday
=> The day before yesterday was Thursday
Answer: Option D
Answer: D
Question: There are b cities. What is the number of airlines that connected 2 different cities (airline from city A to city B is different with airline from city B to city A)?
Options:
A)n(n-1)
B)n(n+1)
C)n(n-1)/2
D)n(n+1)/2
E)b(b-1)
Rationale: First of all, the possible number of airlines is b. Then, the possible number of airlines departing from one city to another becomes (b-1). Hence, the answer is b(b-1), which makes E
Answer: E
Question: What approximate value should come in place of the question mark (?) in each of the following equations ?
52.861 + 0.2563 + 8.1 + 57.35 + 0.0087 = ?
Options:
A)119
B)116
C)121
D)115
E)120
Rationale: Explanation :
52.8 + 3 + 8 + 57.4 + 0087 = 118.5 + 0.0087 = 119
Answer : Option A
Answer: A