divelab/Sys2Bench huggingface dataset:
Question: An choclate store received shipments of ingredients on Monday and Tuesday . Tuesday's shipment had 3 different packages, with an average (arithmetic mean) of 11 and 2/3 pounds. Wednesday's shipment included 7 packages, weighing an average of 9 and 3/7 pounds. What was the average package weight, in pounds, of the shipments received on both days?
Options:
A)0 and 1/10 pounds
B)9 and 6/7 pounds1
C)10 and 2/5 pounds
D)11 pounds
E)11 and 1/7 pounds
Rationale: Solution: Average weight = Total weight/number of packages. The total weight on Monday was 3 * (11 and 2/3 pounds), or 35 pounds. The total weight on Tuesday was 7 * (9 and 3/7 pounds), or 66 pounds. The sum of the weights for both days is 66 + 35, or 101 pounds. The average is 101 pounds/10 packages, or 10 and 1/10 pounds per package.
Answer : A
Answer: A
Question: Machine A can process 6000 envelopes in 3 hours. Machines B and C working together but independently can process the same number of envelopes in 2.5 hours. If Machines A and C working together but independently process 3000 envelopes in 1 hour, then how many hours would it take Machine B to process 9800 envelopes.
Options:
A)2
B)3
C)4
D)6
E)7
Rationale: You can either take the amount of work done as the same as Karishma has done or take the work done by each in the same time. I will do the latter
1. Work done in 1 hr by A is 2000 envelopes
2. Work done in 1 hr by A and C is 3000 envelopes
3. So work done in 1 hr by C is 1000 envelopes
4. Work done in 1 hr by B and C is 2400 envelopes
5. So work done in 1 hr by B is 1400 envelopes
6. So to process 9800 envelopes B will take 9800/1400 hrs = 7 hrs
So the answer is choice E
Answer: E
Question: John deposited $10,000 to open a new savings account that earned 10 percent annual interest, compounded quarterly. If there were no other transactions in the account, what was the amount of money in John’s account 6 months after the account was opened?
Options:
A)$10,100.75
B)$10,101.75
C)$10,506.25
D)$10,201.35
E)$10,404.25
Rationale: 10 percent annual interest compounded quarterly --> 2.5% in 3 moths.
For the first 3 moths interest was 2.5% of $10,000, so $250;
For the next 3 moths interest was 2.5% of $10,000,plus6.25 earned on previous interest of $250, so $250+$6.25=$256.25;
Total interest for 6 months was $250+$256.25=$506.25, hence balance after 6 months was $10,000+ $506.25=$10,506.25.
Answer: C.
Answer: C
Question: A committee of four people is to be chosen from five married couples. What is the number of different committees that can be chosen if two people who are married to each other cannot both serve on the committee?
Options:
A)16
B)48
C)64
D)80
E)96
Rationale: Each couple can send only one representativeto the committee. Let's see in how many ways we can choose 4 couples (as there should be 4 members) out of 4 to send only one representatives to the committee: 5c4=5.
But each of these 5 couples can send two persons (husband or wife): 2*2*2*2=2^4=16.
Total # of ways: 5C4*2^4=80
Answer: E.
Answer: D
Question: Timothy leaves home for school, riding his bicycle at a rate of 9 miles per hour. Fifteen minutes after he leaves, his mother sees Timothy’s math homework lying on his bed and immediately leaves home to bring it to him. If his mother drives at 27 miles per hour, how far (in terms of miles) must she drive before she reaches Timothy?
I think is a 700 level problem but I tag it as 600/700, let me know. Either way I hope in an explanationThanks
Options:
A)27/8
B)3
C)4
D)9
E)12
Rationale: In 15 mins, Timothy travels=9/4 miles.
Now, let his mother takes x hours to reach him, traveling at 27mph.
So, 27x=9x+9/4
x=1/8 hrs.
Thus, the distance traveled by his mother to reach= 27*1/8=27/8miles. Ans A
Answer: A
Question: Sandy invested a certain sum of money at 12% p.a. simple interest for 'n' years. At the end of 'n' years, Sandy got back 4 times the original investment. What is the value of n?
Options:
A)20
B)25
C)30
D)35
E)40
Rationale: n* 0.12 * principal + principal = 4 * principal
n * 0.12 = 3
n = 25 years
The answer is B.
Answer: B
Question: A train 550 metres long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going ?
Options:
A)5 sec
B)6 sec
C)7 sec
D)10 sec
E)30 sec
Rationale: Solution
Speed of train relative to man =(60+6) km/hr= 66km/hr
=(66x5/18) m/sec =(55/3) m/sec
∴ Time taken to pass the man = (550 x 3/55)sec = 30 sec
Answer E
Answer: E
Question: An error 2% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is:
Options:
A)2%
B)2.02%
C)4%
D)4.04%
E)5%
Rationale: Correct value is 100x100.
Measured value is 102x102.
Therefore ERROR Value is (102x102)-(100x100) = 404.
Error% = (error value/ true value)*100.
= (404/100x100)x100 = 4.04.
answer :D
Answer: D
Question: A wheel has a diameter of x inches and a second wheel has a diameter of y inches. The first wheel covers a distance of d feet in 200 revolutions. How many revolutions does the second wheel make in covering d feet?
Options:
A)200x/y
B)200y - x
C)200x - y
D)200y/x
E)200xy
Rationale: First Wheel with diameter x inches ----> So the circumference = x*pi --------- (1)
Second Wheel with diameter y inches ----> So the circumference = y*pi --------- (2)
Revolutions = distance/circumference
So, from equation (1)
200 = d/(x*pi)
d = 200 * x * pi ---------- (3)
From equation (2)
Revolutions = d/(y*pi) = (100 * x * pi) / (y*pi) = 200x/y
Answer (A)
Answer: A
Question: A certain barrel, which is a right circular cylinder, is filled to capacity with 300 gallons of oil. The first barrel is poured into a second barrel, also a right circular cylinder, which is empty. The second barrel is twice as tall as the first barrel and has twice the diameter of the first barrel. If all of the oil in the first barrel is poured into the second barrel, how much empty capacity, in gallons, is left in the second barrel?
Options:
A)There is no empty capacity
B)2100 gallons
C)2300 gallons
D)2100 gallons
E)2800 gallons
Rationale: Radius of first cylinder=r, diameter=2r, height=h
Radius of second cylinder=2r, diamter=2d and height=2h
Volume of first cylinder=pie (r^2)*h=300
Volume of second cylinder=pie(2r^2)2h
Put the value of pie (r^2)*h=300 in the second cylinder,volume= pie (r^2)*4*2=300*8=2400 gallons
Empty capacity=2100 gallons
Answer D
Answer: D
Question: Tommie spent six lucky days in Las Vegas. On his first day he won a net amount of only $20, but on each of the following days, the daily net amount he won grew by d dollars. If Tommie won a total net amount of $1620 during his stay in Las Vegas, how much did he win on the last day?
Options:
A)330
B)500
C)520
D)540
E)620
Rationale: I drew a diagram:
1 - $20
2 -
3 -
4 - $320
5 -
6 -
Total: $1,620
Between 1 and 6 are 5 days where he won $1,600. This means he averaged $320 per day (1600/5). You can put $320 by 4 because it's the middle number. Now you just find the two points betwenn $20 and $320 (320-20 = 300 / 3 = 100). So each day, he earned $100 more. This means on day 6, tommie earned$520. Answer choice C.
Answer: C
Question: If the line L passes through the point (3,n) and (n,3), where n is not equal to 3, which of the following must be true?
1. Line L must passes through the first quadrant.
2. Line L does pass the origin.
3.The slope of L is negative
Options:
A)I only
B)II only
C)III only
D)I and II
E)II and III
Rationale: Slope of the given line= 3-n/n-3
Given information is that n is not equal to 3, that means n <3 or n>3. In both these conditions the slope will be negative.
1) n<3 (n=2)
3-2/2-3= -1
2) n<3 (n= 0)
3-0/0-3= -1
3) n<3 (n=-3)
3+3/ -3-3= -2/3
4) n>3
3-4/4-3= -1
Answer C
Answer: C
Question: In an examination, 35% of total students failed in Hindi, 45% failed in English and 20% in both. The percentage of these who passed in both the subjects is :
Options:
A)23
B)37
C)28
D)40
E)81
Rationale: Explanation:
Formula n(a∪b) = n(a) + n(b) − n(a∩b)
Fail in Hindi or English = 35 + 45 – 20 = 60
Therefore students who passed = 100 – 60 = 40.
Answer: D
Answer: D
Question: A can do a piece of work n 7 days of 9 hours each and B alone can do it in 6 days of 7 hours each. How long will they take to do it working together 8 2/5 hours a day?
Options:
A)3 days
B)6 days
C)2 days
D)8 days
E)4 days
Rationale: A can complete the work in (7*9) = 63 days
B can complete the work in (6*7) = 42 days
--> A’s one hour’s work = 1/63 and B’s one hour work = 1/42.
(A+B)’s one hour work = 1/63+1/42 = 5/126
Therefore, Both can finish the work in 126/5 hours.
Number of days of 8 2/5 hours each = (126*5/(5*42)) = 3 days
Answer : A
Answer: A
Question: What is the probability that in the rearrangements of the word AMAZED, the letter ’E’ is positioned in between the 2 ’A’s (Not necessarily flanked)?
Options:
A)1/6
B)1/4
C)1/3
D)1/5
E)1/8
Rationale: In any rearrangement of the word, consider only the positions of the letters A, A and E.
These can be as A A E, A E A or E A A.
Therefore, effectively one-third of all words will have ’E’ in between the two ’A’s.
ANSWER:C
Answer: C
Question: If b does not equal zero, and ab = b/6, what is the value of a?
Options:
A)A)1/6
B)B)1/4
C)C)1/3
D)D)1/2
E)of the above
Rationale: Explanation:
To solve for a, divide both sides of the equation by b: ab = b/6
(ab)/b = (b/6)/b
a = (b/6)*1/b
a = 1/6
Answer: (A).
Answer: A
Question: How many ways are there to split a group of 8 boys into two groups of 4 boys each? (The order of the groups does not matter)
Options:
A)35
B)40
C)42
D)44
E)46
Rationale: the combination is 8C4 /2
= 8!/4!*4! *2 = 35
A
Answer: A
Question: If A is thrice as fast as B and together can do a work in 12 days. In how many days A alone can do the work?
Options:
A)16
B)42
C)28
D)54
E)45
Rationale: A’s one day’s work= 1/X
B’s one day’s work= 1/3x
A + B’s one day’s work= 1/x + 1/3x = 1/12
= 3+1/3x = 4/3x = 1/12
x = 12*4/3 = 16
ANSWER:A
Answer: A
Question: Length of a rectangular plot is 28 mtr more than its breadth. If the cost of fencin gthe plot at 26.50 per meter is Rs. 5300, what is the length of the plot in mtr?
Options:
A)54 m
B)64 m
C)74 m
D)84 m
E)94 m
Rationale: Let breadth = x metres.
Then, length = (x + 28) metres.
Perimeter = 5300 m = 200 m.
26.50
2[(x + 28) + x] = 200
2x + 28 = 100
2x = 72
x = 36.
Hence, length = x + 28 = 64 m
B
Answer: B
Question: The sum of two number is 25 and their difference is 13. Find their product.
Options:
A)104
B)114
C)315
D)325
E)271
Rationale: Let the numbers be x and y.
Then, x + y = 25 and x - y = 13.
4xy = (x + y)2 - (x- y)2
= (25)2 - (13)2
= (625 - 169)
= 456
xy = 114.
Answer: B
Answer: B
Question: Two dice are tossed. The probability that the total score is a prime number is
Options:
A)2/13
B)5/7
C)31/7
D)6/7
E)5/12
Rationale: n(S)=36
E= {(1,1),(1,2), (1,4),….(6,5)}
n(E)=15
P(E)=15/36
=5/12
Ans: E
Answer: E
Question: A certain elevator has a safe weight limit of 2,500 pounds. What is the greatest possible number of people who can safely ride on the elevator at one time with the average (arithmetic mean) weight of half the riders being 200 pounds and the average weight of the others being 230 pounds?
Options:
A)7
B)8
C)9
D)10
E)11
Rationale: Lets assume there are 2X people.
Half of them have average weight of 200 and other half has 230.
Maximum Weight is = 2500
So 200*X + 230*X = 2500
=> 430X = 2500
=> X is approximately equal to 6.
So total people is 2*6 = 12
We are not taking 12 as answer because say 11th person has minimum of 180 weight then
200*6 + 230*6 = 2580 (Which is more than 2500)
Answer E.
Answer: E
Question: The Royals softball team played 75 games and won 55 of them. What percent of the games did they lose? (round to the nearest tenth)
Options:
A)26.7% games lost
B)27.7% games lost
C)25.7% games lost
D)20.7% games lost
E)22.7% games lost
Rationale: Total 100%=75
Won=55
Lost=20
75-55
=20
x/100=20/75
Multiply the opposites:
100 x 20 = 2000
Divide by the remaining number:
26.667/2000.000
75
26.7% games lost (rounded to tenth)
correct answer A
Answer: A
Question: Some of the people in Town B are left-handed, some are tall, some are both, and some are neither. In Town Y, three times as many people are left-handed > as are left-handed in Town B, three times as many people are tall as are tall in Town B, three times as many people are both as are both in Town B, but no one is neither. If the total number of people in Town B is four times greater than the total number of people in Town Y, which of the following could be the number of people in Town B who are neither left-handed nor tall?
Options:
A) 23
B) 39
C) 72
D) 143
E) 199
Rationale: Yes, correct answer is indeed D.
{B}={Left} + {Tall} - {Both} + {Neither};
{Y} = 3*{Left} + 3*{Tall} - 3*{Both};
Since the total number of people in Town B is four times greater than the total number of people in Town Y, then:
{Left} + {Tall} - {Both} + {Neither}=4*(3*{Left} + 3*{Tall} - 3*{Both});
{Neither}=11*({Left} + {Tall} - {Both}), which means that # of people in Town B who are neither left-handed nor tall must be a multiple of 11.
Only answer choice D, is a multiple of 11: 143=11*13.
Answer: D.
Answer: D
Question: January 1, 2007 was Monday. What day of the week lies on Jan. 5, 2008?
Options:
A)Monday
B)Tuesday
C)Wednesday
D)Saturday
E)Sunday
Rationale: The year 2007 is an ordinary year. So, it has 1 odd day.
day of the year 2007 was Monday
day of the year 2008 will be 5 days beyond Monday
Hence, It will be Saturday. answer : D
Answer: D
Question: Beth received 1/5 of the votes cast in a certain election. What fraction of the other votes cast would she have needed in order to have received 1/2 of the votes cast?
Options:
A)1/5
B)2/7
C)3/8
D)7/20
E)1/2
Rationale: Let the total votes be 10. Beth received 2 votes, other votes 10-2=8. In order to have received 1/2 of the votes she needed 5 votes so 3 more, which is 3/8 of the other votes.
Answer: C.
Answer: C
Question: One pipe can fill a tank four times as fast as another pipe. If together the two pipes can fill the tank in 36 minutes, then the slower pipe alone will be able to fill the tank in:
Options:
A)180 min
B)160 min
C)280 min
D)18 min
E)190 min
Rationale: Let the slower pipe alone can fill the tank in x minutes
Then the faster pipe can fill the tank in x/4 minutes
Part filled by the slower pipe in 1 minute = 1/x
Part filled by the faster pipe in 1 minute = 4/x
Part filled by both the pipes in 1 minute = (1/x)+(4/x)
Answer is A
It is given that both the pipes together can fill the tank in 36 minutes
⇒ Part filled by both the pipes in 1 minute = 1/36
(1/x)+(4/x)=1/36
5/x=1/36
x=5×36=180
i.e.,the slower pipe alone fill the tank in 180 minutes
Answer: A
Question: the present average age of a couple and their daughter is 35 years. Fifteen years from now, the age of the mother will be equal to the sum of present ages of the father and the daughter. Find the present age of mother?
Options:
A)38
B)49
C)55
D)45
E)50
Rationale: D
45
(f + m + d)/3 = 35
=> f + m + d = 105 --- (1)
m + 15 = f + d
Substituting f + d as m + 15 in (1), we get
2m + 15 = 105
2m = 90 => m = 45 years.
Answer: D
Question: A firm has 4 senior partners and 6 junior partners. How many different groups Q of 3 partners can be formed in which at least one member of the group is a senior partner. (2 groups are considered different if at least one group member is different)
Options:
A)48
B)100
C)120
D)288
E)600
Rationale: What seems to work as well, though its tougher to come up with this solution:
(10*9*8) * 2/3 + (10*9*4)*1/3 = 600. Divided by all possible permutations (=3!) yields 100.
Explanation: For the first spot you have 10 possible canditates, for the 2nd 9. For the 3rd spot you need to differentiate if a senior partner has been picked for one of the first 2 spots or not. If yes, then you can pick one of the 8 remaining guys, so 10*9*8. If no senior partner has been picked yet, you need 10*9*4.
Now you need to weight the 2 cases with the corresponding probabilities: probability of no senior partner being picked in the first 2 draws = 6/10*5/9=1/3, so you weight 10*9*4 with 1/3. For the complementary case (senior partner was picked in the first 2 draws) you just take the complementary prob (1-1/3)= 2/3 and weight 10*9*8 with it.
Now you just need to divide the answer (600) by the number of different positions (=3!) and get Q=600/6=100.B
Answer: B
Question: A software programmer does 20% of the work in 70% of the time, and 80% of the work in the remaining 20% of the time. If the code he writes is X lines long and he was given one month (30 days) to accomplish the task, then, assuming that the programmer works at a constant rate in each of the two stages, How many lines of code were written in the last two weeks, in terms of X?
Options:
A)13x /15
B)15x/15
C)7x/15
D)2x/30
E)13x/30
Rationale: Take X=30 lines
70% of 30 = 24 lines
20% of 30 = 6 lines
W - R - T
6 lines - r1 - 24 (first 70% of the 30 days)
24 lines - r2 - 6 ( last 20% of the 20 days)
r1 = 1/4r2 = 4
Now Work in last 14 days = 6 days programmer worked at r2 + 8days programmer worked at r1
=> 6 * 4 + 8 * 1/4 = 24 + 2 = 26
Insert, X=30 in all options => B is the answer.
Answer: B
Question: If 7^(x - y) = 343 and 7^(x + y) = 16807, what is the value of x?
Options:
A)3
B)4
C)2
D)1
E)7
Rationale: 7^(x - y) = 343 = 7^3
=> x - y = 3 ---------------------------(Equation 1)
7^(x + y) = 16807 = 7^5
=> x + y = 5 ---------------------------(Equation 2)
(Equation 1)+ (Equation 2) => 2x = 3 + 5 = 8
=> x = 8/2 = 4
Answer is B
Answer: B
Question: The average marks obtained by 100 candidates in an examination is 50. Find how many candidates have passed in the examination, if the average marks of candidates who passed is 70 and that of failed candidates is 20.
Options:
A)33
B)77
C)60
D)29
E)11
Rationale: Explanation:
Let the number of students who passed the examination be X
Number of students failed = (100 - X)
Total marks of students who have passed = 70X
Total marks of 100 students = 100 * 50 = 5000
Total marks of students who have failed = 20(100 – X)
20(100 – X) + 70X = 5000
2000 – 20 X + 70X = 5000
50 X = 3000
X = 60
ANSWER: C
Answer: C
Question: David has d books, which is 2 times as many as Jeff and 1/2 as many as Paula. How many books do the three of them have altogether, in terms of d?
Options:
A) 5/6*d
B) 7/3*d
C) 10/3*d
D) 7/2*d
E) 9/2*d
Rationale: Although we could plug in a real value for d, the problem can be just as easily solved by setting up equations. However, let’s start by defining some variables. Since we are given that David has d books, we can use variable d to represent how many books David has.
number of books David has = d
number of books Jeff has = j
number of books Paula has = p
We are given that David has 3 times as many books as Jeff. We can now express this in an equation.
d = 2j
d/2 = j
We are also given that David has ½ as many books as Paula. We can also express this in an equation.
d = (1/2)p
2d = p
Notice that we immediately solved forj in terms of d and p in terms of d. Getting j and p in terms of d is useful when setting up our final expression. We need to determine, in terms of d, the sum of the number of books for David, Jeff, and Paula. Thus, we have:
=d + d/2 + 2d
=7d/2
The answer is D
Answer: D
Question: The average of 20 numbers is zero. Of them, at the most, how many may be greater than zero?
Options:
A)0
B)1
C)10
D)19
E)21
Rationale: Explanation:
Average of 20 numbers = 0.
Sum of 20 numbers (0 x 20) = 0.
It is quite possible that 19 of these numbers may be positive and if their sum is a then 20th number is (-a)
ANSWER IS D
Answer: D
Question: At a certain supplier, a machine of type A costs $20,000 and a machine of type B costs $55,000. Each machine can be purchased by making a 20 percent down payment and repaying the remainder of the cost and the finance charges over a period of time. If the finance charges are equal to 40 percent of the remainder of the cost, how much less would 2 machines of type A cost than 1 machine of type B under this arrangement?
Options:
A)$10,000
B)$11,200
C)$12,000
D)$19,800
E)$13,200
Rationale: 1 machine of type B will cost: 20% down payment of 55,000 = 11,000plusremaining sum (55,000-11,000=44,000) with 40% of finance charges 44,000*1.4=61,600 --> 11,000+61,600=72,600;
2 machine of type A will cost: 20% down payment of 2*20,000 = 8,000plusremaining sum (40,000-8,000=32,000) with 40% of finance charges 32,000*1.4=44,800 --> 8,000+44,800=52,800;
Difference = 72,600 - 52,800 = 19,800.
Answer: D.
Answer: D
Question: A watch was sold at a loss of 10%. If it was sold for Rs.182 more, there would have been a gain of 4%. What is the cost price?
Options:
A)s:1000
B)s:1067
C)s:1278
D)s:1300
E)s:1027
Rationale: 90%
104%
--------
14% ---- 182
100% ---- ? =>
Rs:1300
Answer: D
Answer: D
Question: If the complement of a certain angle is three times the measure of that certain angle, then what is the measure of that certain angle?
Options:
A)45
B)30
C)22.5
D)18
E)15
Rationale: The original angle is x, so the complement is 3x, and together, these add up to 90 degrees.
x + 3x = 90
4x = 90
x = 22.5
Answer = (C)
Answer: C
Question: The length of a rectangular garden is three times its width. If the area of the rectangular garden is 432 square meters, then what is the width of the rectangular garden?
Options:
A)8
B)9
C)10
D)11
E)12
Rationale: Let x be the width of the garden.
3x^2 = 432
x^2 = 144
x = 12
The answer is E.
Answer: E
Question: If the number 517*324 is completely divisible by 7, then the smallest whole number in the place of * will be:
Options:
A)3
B)1
C)2
D)4
E)6
Rationale: Sum of digits = (5 + 1 + 7 + x + 3 + 2 + 4) = (22 + x), which must be divisible by 7.
x = 6.
E
Answer: E
Question: Vijay went to a shop and bought things worth Rs. 25, out of which 30 Paise went on sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax free items?
Options:
A)19
B)19.7
C)21
D)21.1
E)23
Rationale: Total cost of the items he purchased = Rs.25
Given that out of this Rs.25, 30 Paise is given as tax
=> Total tax incurred = 30 Paise = Rs.30/100
Let the cost of the tax free items = x
Given that tax rate = 6%
∴ (25−30/100−x)6/100 = 30/100
⇒ 6(25 −0.3 −x) = 30
⇒ (25 − 0.3 − x) = 5
⇒ x = 25 − 0.3 − 5 = 19.7
B)
Answer: B
Question: In a certain population, there are 4 times as many people aged twenty-one or under as there are people over twenty-one. The ratio of those twenty-one or under to the total population is
Options:
A) 4 to 5
B) 1 to 3
C) 1 to 4
D) 2 to 3
E) 3 to 4
Rationale: Consider the ratio of the under population of 21 to over the 21 as 4:1
therefore 4x:1X
Now the ratio of the under to the whole population becomes 4x/4x+1x
= 4/5
Answer is A
Answer: A
Question: In how many ways can 8 Indians , 4 Americans and 4 Englishmen be selected in a row so that all persons of the same nationality sit together?
Options:
A)3!8!4!4!
B)2!4!4!
C)8!
D)4!4!4!
E)4!4!
Rationale: Treat each nationality as one. So there are 3 persons can be arranged in 3! ways
8 Indians can be arranged in 8! ways
4Englishman can be arranged in 4!ways
4American can be arranged in 4! ways
Required number of ways = 3!8!4!4!
Answer is A
Answer: A
Question: Sonika bought a V.C.R. at the list price of 18,400. If the rate of sales tax was 8%, find the amount she had to pay for purchasing the V.C.R.
Options:
A)19,872
B)19,780
C)19,680
D)19,380
E)None of these
Rationale: Sol. List price of V.C.R. =18,400
Rate of sales tax = 8%
∴ Sales tax = 8% of 18,400
= 8⁄100 × 18400 = 1472
So, total amount which Sonika had to pay for purchasing the V.C.R. = 18,400 + 1472
= 19,872. Answer A
Answer: A
Question: A word is defined as a sequence of four dots arranged in a row. Each dot is colored either red, yellow, or blue. How many distinct words can be formed?
Options:
A)36
B)48
C)64
D)81
E)120
Rationale: 3^4 = 81
The answer is D.
Answer: D
Question: The area of a triangle is with base 4m and height 6m?
Options:
A)11 m2
B)10 m2
C)18 m2
D)19 m2
E)12 m2
Rationale: 1/2 * 4 * 6
= 12 m2
Answer: E
Answer: E
Question: A can do a piece of work in 21 days and B in 28 days. Together they started the work and B left after 4 days. In how many days can A alone do the remaining work?
Options:
A)33
B)276
C)27
D)14
E)66
Rationale: Let A worked for x days.
x/21 + 4/28 = 1 => x/21 = 6/7 => x = 18
A worked for 18 days. So, A can complete the remaining work in 18 - 4 = 14 days.
Answer: D
Answer: D