Context: CREATE TABLE table_name_47 (number_of_examinees VARCHAR, number_of_passed_students VARCHAR, year VARCHAR, pass_percentage VARCHAR)
Question: What number of examines after 2005 has a pass percentage of 78.35% with less than 297 students?
Answer: SELECT COUNT(number_of_examinees) FROM table_name_47 WHERE year > 2005 AND pass_percentage = "78.35%" AND number_of_passed_students < 297