Context: CREATE TABLE table_name_34 (tournament VARCHAR)
Question: What is the 2011 value of the paris masters, which had A in 2008, A in 2012, A in 2009?
Answer: SELECT 2011 FROM table_name_34 WHERE 2008 = "a" AND 2012 = "a" AND 2009 = "a" AND tournament = "paris masters"