Context: CREATE TABLE table_name_82 (county VARCHAR, rank VARCHAR, _percentage__1960_ VARCHAR, _percentage__2040_ VARCHAR, _percentage__2000_ VARCHAR)
Question: Which county has a % (2040) larger than 1.8, a % (2000) smaller than 4.1, a % (1960) smaller than 3.2, and is ranked 13?
Answer: SELECT county FROM table_name_82 WHERE _percentage__2040_ > 1.8 AND _percentage__2000_ < 4.1 AND _percentage__1960_ < 3.2 AND rank = "13"