Context: CREATE TABLE table_name_21 (Id VARCHAR)
Question: What 2010 has a 2006 less than 6.9, a 2008 greater than 1.6, and 2 for 2007?
Answer: SELECT 2010 FROM table_name_21 WHERE 2006 < 6.9 AND 2008 > 1.6 AND 2007 = 2