Context: CREATE TABLE table_name_92 (best_fit__wmap VARCHAR, _extra_parameter_ VARCHAR, best_fit__all_data_ VARCHAR)
Question: What is the best fit (WMAP, extra parameter)when the best fit (all data) is .0224 ± .0009?
Answer: SELECT best_fit__wmap, _extra_parameter_ FROM table_name_92 WHERE best_fit__all_data_ = ".0224 ± .0009"