Context: CREATE TABLE table_name_33 (official_website VARCHAR, number_of_episodes VARCHAR, english_title__chinese_title_ VARCHAR)
Question: What's the official website of Burning Flame 烈火雄心 with 22 episodes?
Answer: SELECT official_website FROM table_name_33 WHERE number_of_episodes > 22 AND english_title__chinese_title_ = "burning flame 烈火雄心"