Context: CREATE TABLE Parts (part_name VARCHAR, part_id VARCHAR); CREATE TABLE Part_Faults (part_id VARCHAR)
Question: Which parts have more than 2 faults? Show the part name and id.
Answer: SELECT T1.part_name, T1.part_id FROM Parts AS T1 JOIN Part_Faults AS T2 ON T1.part_id = T2.part_id GROUP BY T1.part_id HAVING COUNT(*) > 2