Context: CREATE TABLE table_name_62 (tournament VARCHAR)
Question: Which tournament has 1r in 2011, 1r in 2012, A in 2005, and 1r in 2010?
Answer: SELECT tournament FROM table_name_62 WHERE 2011 = "1r" AND 2012 = "1r" AND 2005 = "a" AND 2010 = "1r"