Context: CREATE TABLE table_name_19 (swimsuit VARCHAR, interview VARCHAR, average VARCHAR, evening_gown VARCHAR)
Question: What is the total number of swimsuit scores that have average scores less than 8.823, evening gown scores less than 8.69, and interview scores equal to 8.27?
Answer: SELECT COUNT(swimsuit) FROM table_name_19 WHERE average < 8.823 AND evening_gown < 8.69 AND interview = 8.27