Context: CREATE TABLE medicine (id VARCHAR, trade_name VARCHAR); CREATE TABLE medicine_enzyme_interaction (medicine_id VARCHAR)
Question: What is the id and trade name of the medicines can interact with at least 3 enzymes?
Answer: SELECT T1.id, T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id GROUP BY T1.id HAVING COUNT(*) >= 3