Context: CREATE TABLE table_name_84 (other VARCHAR, joe_sestak__d_ VARCHAR, margin_of_error VARCHAR, pat_toomey__r_ VARCHAR)
Question: WHAT CANDIDATE HAD A MARGIN OF ERROR OF ± 4.5%, WHEN PAT TOOMEY WAS 45% AND JOE SESTAK WAS 38%?
Answer: SELECT other FROM table_name_84 WHERE margin_of_error = "± 4.5%" AND pat_toomey__r_ = "45%" AND joe_sestak__d_ = "38%"