Context: CREATE TABLE table_name_48 (Id VARCHAR)
Question: What is the 2007 value with a 4r in 2006, a 1r in 2004, and a 4r in 2009?
Answer: SELECT 2007 FROM table_name_48 WHERE 2006 = "4r" AND 2004 = "1r" AND 2009 = "4r"