Context: CREATE TABLE dorm_amenity (amenity_name VARCHAR, amenid VARCHAR); CREATE TABLE has_amenity (amenid VARCHAR)
Question: Find the name of amenity that is most common in all dorms.
Answer: SELECT T1.amenity_name FROM dorm_amenity AS T1 JOIN has_amenity AS T2 ON T1.amenid = T2.amenid GROUP BY T2.amenid ORDER BY COUNT(*) DESC LIMIT 1