Context: CREATE TABLE furniture_manufacte (Furniture_ID VARCHAR, Price_in_Dollar INTEGER); CREATE TABLE furniture (name VARCHAR, Furniture_ID VARCHAR); CREATE TABLE furniture_manufacte (Price_in_Dollar INTEGER)
Question: Find the names of furnitures whose prices are lower than the highest price.
Answer: SELECT t1.name FROM furniture AS t1 JOIN furniture_manufacte AS t2 ON t1.Furniture_ID = t2.Furniture_ID WHERE t2.Price_in_Dollar < (SELECT MAX(Price_in_Dollar) FROM furniture_manufacte)