The Richmond palladium and sun-telegram. [volume] (Richmond, Ind.) 1907-1939, 1920-01-31

by observing Fig. 4, you will notice
that when the drum X is held station
airy by the band L, and the flywheel,
and, therefore, engine is revolving,
that the gears F and G. will roll about
D, and SO drive the gear E, which is
connected to the rear wheels through
the propeller shaft, etc. The gears
F and G might be regarded as a re-
volving crowbar
When, however, the band L is freed,
then the drum K will be freed, and as
there will now be more resistance to
| the revolving of the gear E than to
the gear D, the gears F and G will now
| roll on E and SO simply drive the gear
d and its drum backward. Thus there
will be no tendency to drive the car
by the running engine.
| You will note that no gears are
shifted, the connecting of the engine
| to the rear wheels being accomplished
by the Tightening of the band on the
Crum, as to hold it from revolving ;
while the disconnecting is accomplish.
ed by the freeing OF this band
| If the gears D and G. were ten inches
in diameter, and. the gear E six inches,
while F was four inches, then the
i leverage Of the pin G would be to /
but this will not be the engine lever
/ age. The diameter of the circle
| through which the crank revolves will
| be less than the diameter Of the circle
Of the pin c and so there will be re.
sulting reverse leverage. Were the
crank circle six inches, only six-tenths
| (6-1O) of the pressure of the crank
would be exerted on the pin G.. Thus
the resulting leverage would be but
| (6-10) six-tenths of five, or 3 to ].
I have assumed the crank circle as
the same diameter as the gear E, to
simplify matters. This will be found
to be fair assumption if the leverage
| is figured out in detail to the rear
wheels The cancellations will resolve
themselves to this.
| Now as to the speed ratio. BY re-
! ferring to Fig. you will observe that
If the gears D and G are of the same
diameter, or have the same number
of teeth (Which they must have if
they are of the same diameter), then
when the pin c has made complete
revolution, the gear G will have made
complete revolution about the pin
and the tooth A will again be in the
position shown. Now the gear F has
but forty teeth, while E will have
sixty and so when it makes a com
plete revolution it will have rolled
around but two-thirds of E. In other
words, the tooth B, will be in mesh
with the tooth H of gear E. Now as
the gears F. and G are one piece
when gear G has made one revolu
ton, gear F will also have made one
revolution, and the tooth B will have
to be in the position shown. In order
| therefore, for the tooth B to be mesh
ed with the tooth H., the gear E will
have have to travel SO that H comes
to B, which will be one third Of &
revolution. Thus for every revolution
of the fly wheel the gear E will make
a third of a revolution, or expressing
this differently, the engine will make
| three revolutions to one of the gear
| AS the gears F and are brought
more nearly to the same diameter, the
greater will be the engine speed. Thus
if they had forty-five and fifty-five
teeth, gear E would move for only ter
Of it's fifty-five teeth and the engine
speew would be SIS to l.
When the gears, that's is, all four
are of the same size, there will bt
no car speed, while if F is made larger
than E. thus crossing the neutra
point, the car will reverse. How this
principle is used far reversing vii
be shown next.