The sun., 1917-05-27

Clubs are trumps and 2 10 in the lead
and want FIVE tricks against any
defence.
As d. A. w. says. the most illogical
opening that he ever saw in q problem
is the only one that will solve. and that
Is the diamond, upon which discards a
spade. b wins. There are several lines
Of defence, but the strongest II undoubt-
| edly the lead Of q small spade. The
most interesting is probably the imme-
diate return Of the diamond.
plays a email spade and As best
play II tho ten, which 7 allows to hold,
as that simplines matters. Now A should
lead the trump 30 as to throw Y into
the lead. but 2 overtakes with the king
and leads the five. A and B have seven
| lines Of defence, all Of which must be
met in order to demonstrate that the
problem can be solved against any of
| them.
1. II A discards q small heart Y lets
go another spade and b the diamond. z
leads tbe nine OF hearts. A plays the
| ten and Y the king. The return Of the
heart puts A in and Y makes two more
! tricks.
2. II A discards the ace Of hearts in
stead Of the small one viii discard y
I heart instead OF n spade. b giving up
the diamond. 2 leads the nine Of hearts
and Y wins. putting B in with the heart
queen 30 A. to make two spade tricks
by killing AS king.
II discards the spade instead of the
diamond In this variation z will lead
the spade queen instead OF the heart
and Y will make two spade tricks
whether A covers the queen or not. and
afterward he must mako the best heart.
=. If A discards n spade on the five of
clubs, Y will discard q heart and b the
diamond. Now q leads . small spade.
Y kills the king and returns the suit.
after which the king Of hearts must
! make, As 2 leads through A.
4. To go back to the third trick. II. in
stead Of leading the trump. A leads the
| ace of hearts and another. Y wins and
leads the trump. and Alb are forced 20
discard on the second trump lead from T.
5. II b leads the spade jack for the
second trick, instead Of the small one
z covers. A plays the king. but ducks
I Now must lead the trump A. the best
defence. and the second trump lead
forces the discards. as before.
Several failed on this problem by fall
ing to mention or analyze the lead OF the
spade Jack or by assuming that the re-
suit would be the same az when small
one was led. and Y won the ten with the
ace. In that variation It does not matter
| whether wins the ten or ducks But
| IL B leads the jack Y must cover and Y
must duck. II z does not cover the jack
and Y wins with the ace or II all four
| honors fall the problem cannot be solved
6. II B returns the diamond for the
second trick. Y trumps with the king, A
| discarding a heart and Y a spade. Now
small heart from z establishes the
suit for Y. whether A wins the first
round or the second. After the second
round of hearts must get into the lead
and can play the trump.
! 7, II A discards a spade instead OF a
heart when B leads the diamond. z leads
a small spade after trumping the dia-
mond with the king. But II A under
| trumps. instead OF discarding, Y will
also undertrump, getting rid OF the
jack Of clubs, SO that 2 may go ahead
This il very important variation.
which many missed altogether.
Those who have solved every problem
since No. 400 are
Frank s. Busser, l.. A. Hawkins, e.
Converse Pierce. T. Y. Roe and d. A.
W. The only others that solved No.
4o9, giving all the important variations.
were Mary Lee and f w. white, This
gives Mary Lee OF Harrisburg. Pa. the
| Dutton prize for solving all the prob
LIENS since No. 420.
| Problems In which a large number Of
tricks are to be conceded to the op-
ponents are usually complicated, on ac-
| count Of the many variations in the
defence Here is one In which only two
tricks are TO be given UP.
sRfpoE PROBLEM NO. 43l.