The sun., 1916-10-08

Clubs are trumps and Y Is in the lead.
Y and Il want four tricks against any
defence.
In the actual game z failed to get the
fourth trick by leading a spade. think
ing to make two Of his trumps or get hts
tenace In hearts led VI to, forcing BIS
high trumps. This opening allowed A to
win the spade and Il to make his smallest
trump on the hearts.
Then 1t took rs Jack Of trumps to
shut out A on the second round OF
spades. after which II was impossible 10
drop the trumps. because d won the
trump and gave A another run. making
all three of BIS trumps and two OF AS.
There Is no escape from his after the
first lead.
The solution may be briefly summed
up in the statement that Y should lead
trumps every tim he gets a chance. and
that Y should give him that chance az
often as possible. IL does moi matter
what trump z leads. nor who wins the
trick. the point being to get two for one
but the ad~versaries can put up several
defences.
One OF the clever defences IL for II TO
win the FIRST trump trick with the queen
and lead n small spade. II Y has dis
carded a spade on the irst trick he will
be forced to win this trick II A refuses
TO trump 1t. Now. II Y leads q diamond
4 trumps It. leads a heart for II to
make with his small trump and Il leads
another spade.
II z trumps this and leads the trump
r has two good spades and the lead. II
Il does not lead the trump A makes the
king of hearts. This shows that Y must
be careful to discard the diamond on the
first trump lead. Then. II A does not
trump the spade Y can leave Y in the
lead with the Jack and z can lead an
other round OF trumps.
Y annot escape by leading the ace
OF spades after winning the first spade,
because y will then be left with the two
top spades. and when A ruffs the ace and
leads a heart Il will lead the winning
spades through z. who cannot arford 10
trump and lead trumps. or Il will be In
after the trumps are gone
The only correct solution, therefore,
Ia for Y to discard the smallest diamond
on the first trick. forcing A to trump
the first spade lead II n wins the trump
trick. Now A leads the heart and u
,rumps II with the i've. Another spade
allows Il to trump with the Jack and lead
the king. while Y still holds the spade
ace over BIS suit.
II Y starts with the small trump and
A holds the trick. he must lead the
!'tdrt, "HlS9 teNeS one OF BS ncNOrs 10
win. Now, when II leads the spade. A
gets i..e run. but the next heart takes
BIS ace OF trumps and Y still has two
trumps. both higher than AS. to run
the spades. catch As trump and make
the ace Il hearts and queen Of dia-
monds.
rs starting with one Of his higher
trumps would make no difference. except
that II would force II 70 wiz the frs.
trick In order TO prevent n second round
OF trunps. Neither can II gain anything
by r4iiilng with the ace and queen. SO as
10 allow \ to win the last trump lead In
any variation. as A would Their have to
lead hearts up TO rs major tenace.
Here Is a comparatively easy problem
for the windup Of this series. after which
solvers should be IN good trim for the
next honor LIST. Beginning with prob
lem No. %oi. THE T. proposes To start
a new system OF finding out who are the
experts.
For every correct solution the solver
will be credited with n point. Those
who solve tho first ten problems in a
row without a miss will be ranked rs
experts. and all who continue TO solve
the problems. keeping their place IN line.
VIII still rank rs experts until there is
only ono left with an unbroken record.
As no one has ever succeeded In solv-
ing twenty Of the honor list problems
In a row The race may be over before
Christmas. Tho T.. A. Stokes Company
has offered 10 present the survivor with
n copy OF any standard text book on
the game OF auction, whether or not the
company publishes II. The race Is omen
"a. all, whether subscribers to THE SrN
or not