The sun. [volume] (New York [N.Y.]) 1833-1916, 1915-06-20

2AAre are no trumps and 2 y In the
nd. Y and z van only four tricks,
h0t against any defence.
Ths solution 10 for 2 to lead the nine
81 clubs. The six will not solve. Y OF
course wine the trick with the king. n
1ts inlay v to return the queen Of dia-
Mcnds. The ten will not solve. II may
b taken for granted that b will win
the diamond. and his best continuation
q to get rid Of the Jack of clubs. so as
70 avoid the lead later. which would
I'LL Ais king Of spades.
On tho club Y discards the losing
bur Of hearts. Now b can either make
MS remaining diamond while he is in. or
he . lead the spade and be thrown
back into the lead with q diamond.
No matter which spade he leads. or
ths suit II Y mag his cards prop
eSIy.
II 2 opens with the smaller of his two
clubs B will give up the Jack. and II Y
leads q diamond b will make the two
tricks in that suit and then throw Y
into the lead with the losing club. Now
he must lead a heart. n after A has
made " tricks In that suit a spade
through the ace will establish a trick
With the queen for b.
while this looks as II tho higher
9abo vi was VIC WIN VI Nv pay
81 10 really the queen of diamonds. and
q the composer points out all those who
fail to emphasize the fact that it il the
queen of diamonds and not IA" dia-
nond cannot be credited with correct
solutions.
Even IL the hand is opened correctly
With the nine Of clubs. should Y fail
10 lead the higher OF his two diamonds
\ can defeat the solution by putting
A. ll-- - tkA - al r~-.zlt.t 4 -
turning the Jack OF diamonds. holding
back the club for the last trick. A club
lead would allow Y to get rid Of the dia-
mond.
This will put Y in the lead again
end he can take his choice of giving A
two hearts and a spade or two spades
and a heart in addition to the club
trick, which is good n time. The Two
spades are obvious IL A leads a spade.
as the king is guarded and the queen
doubly guarded.
with the diamond from rs hand. but
they got the required number OF tricks
by letting Il win the trick and throw Y
In with the club. so hat Y could re-
turn the compliment by putting b In
again with the other diamond, and after
b had made his top club getting homo
three spades by proper management OF
the suit,
But this is not the correct defence
to.the diamond opening. which is for
B TO make both his diamond tricks be-
fore putting Y in with the club, which
will efectually prevent Y from putting
B back into the lead except in spades.
II q diamond Is led and b makes two
tricks inc then gives Y a club trick A
must make two hearts II y leads thai
suit and then lead a spade through the
Ace 90 that r shall make a spade and
Q club. That would be six tricks for Y
and z. II Y leads the spade instead Of
the heart the result is the same.
II Y plays the spade ace A gets In or
the next spade with the king. makes his
ace of hearts n goes through with 9
club, 30 that Il can make a trick II
each of the black suits. II Y leads thu
small spade A makes the king. takes
home the ace OF hearts and leads tn
SPADE ten. This shows the diamond
opening not only fails to solve bu
gives A and b two more tricks thar
they are entitled TO.
: Correct. solutions from the following A.:
A. I. Str~asburger, w p. w, Chas. N
Root, ]. C. Hume, keystone. Wake
McMartin. f. NJ. Frost, G. H.. O'Connor
II. X. Thaw. Lillian Bennet Weller
Henry Andersen. J. w. Wortz, d. Perry
L s.. Hart, Jr., Roscoe G. Harris, Jane!
Steen and O. H.. Boston.
Here In a curiosity in forced discardi
cent to THE SUN by a correspondent II
the West. 1t is not particularly dim
cult, but II contains a lesson that should
be, usef to the beginner and is jus
about right for the hot weather.
BRIDGE PROBLEM NO. 332.