The sun. [volume] (New York [N.Y.]) 1833-1916, 1915-09-26
"a 3
Vie.
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Clubs are trumps and z is in the
lead. Y and Y want all nine tricks
against any defence.
90 Here we have eight tricks in plain
sight five trunps. two outside aces and
y king. II the problem Is sound there
u another trick somewhere
The straightforward solution is for u
to lead the Jack of trumps. which A
covers and Y wins. II discarding n dia-
mond or a spade. When Y picks up AS
smaller trump, b discards a second
time, either diamond or spade, but not
the same suit that he discarded first. z
discards a small spade.
A third round of trumps from Y gives
n the choice OF three discards. as he Is
down to two of each red suit and three
spades. Suppose he let's go a second
spade. Then Il discards a diamond. Y
heads the diamond and Il Is in with the
king. Spade ace from Y gives Y "A
heart discard and Y trumps the next
spade.
Now Y leads the last trump, or which
z will shed his losing heart and still
have the ace of hearts to get in with
n make the established spade.
II q discards another diamond on the
third trump lead. z will also discard a
diamond, and A a heart. Y leads the
diamond Just the same; gets the same
heart discard IN the spade ace and
trumps the next spade, so as to lead his
last trump.
II h keeps the spade z discards that
suit. If b keeps the hearts n holds
the spade. Suppose Is discards the heart
nine, 1t Is A that is In trouble. because
he must either give Y two heart tricks
or let Y make a trick with the SIX or
diamonds.
The only alternative discard for II on
the third trump lead is the heart nine.
in this variation u also discards a heart,
and Y leads Il heart instead OF a dia-
mond.
Now Y leads the ace of spades and
Y shifts his discard. letting 60 the dia-
mond and keeping two hearts. The run
and the lead of the last trump follow
Just the same as before. A is now the
only one to stop Us heart, but il he
discards a diamond Y makes two tricks
IN that suit. If b keeps two diamonds
TO prevent this he must let 20 a spade,
and then rs eight is good for the last
trick.
The minor variation is when A does
not cover the first trurnp lead. Then
rotul to lead \ small spade
for Y to trump SO hat Y can pick
APP AS trump. Upon tRse three tricks
i will be forced to two discards, AMI
the play will be the same as in the
main variation. II Il discards a heart
Y will lead a heart II a diamond Y
leads the diamond.
Whichever red suit Is led, T. gets in
and leads the ace and another spade,
the second being trumped and trumps
being led by Y.
A number failed on this problem by
Ioading the ace of spades at the sec
ond trick il a did not cover the Jack
q trumps. This allows II TO discard
according u Us discard on the spade
ace. and that defeats the solution.
Suppose Y discards a diamond. This
does not affect BIS discard until
the fourth trick. but when Y leads the
ace of trumps TO catch AS king h dis
cards a second diamond and z will
have TO let go a diamond also. Then
Al the end when Y leads his last trump
4 throws away the only remaining dia-
mend.
OF course II u discards a heart on
the ace of trumps Y can lead a heart
and still get the required nine tricks.
the point of the problem being to force
b to get Town to one card in one or
other of the red suits.
Correct solutions from:
r.. C.. Mankowski. Henry Andersen,
iohn c. Hume. D.. A. w. Walker Me-
Martin. A. I. ~Strasburger and w. p. w.
None Of the others got the right dis
cards from BIS hand, either letting go
O heart on the first trick or %unguard-
ing the wrong suit at the end.
Late solutions TO hand for No. 3t3
from A. +. Morris and +. s. Chicago.
Here is a rather clever little skit
from d.. A. W., whose initials have long
been familiar TO readers of THE L
as one of the cracks at solving all sorts
of problems. This is his first appear
ance as a composer.
BRIDGE PROBLEM No. 346.
81 nv ID. A. Waffle.