The sun. [volume] (New York [N.Y.]) 1833-1916, 1915-03-21

Y leads the king OF clubs A and n
made a little slam. The problem WAS
to demonstrate that A and b could
have made this against any defence.
Here lie how they actually did make II.
The variations hat they could have met
follow:
3 trumps the club king with tho fou
OF hearts and leads the six OF trunps.
which A wins by a fnesse OF the ten.
A then leads tho jack of clubs through
the queen. but Y refuses to cover. as z
can trump. b shuts out z with the
queen OF trumps. This brings US 70 the
start OF the variations, as z has three
hnee OF defence-to discard q spade, to
let 60 a small diamond or to under
trump b
h actual play was tho spade dis
card. which allowed b TO lead three
rounds OF that suit az once, A trumping
rs queen. Two winning trumps fol-
lowed, stripping z down to the Jack.
Then tho ace Of clubs either forces rs
trump, leaving A with the eight, or 4
holds the trick.
z trumps the club and leads a dis-
mond 10 b. who makes two spade tricks
IND let's A ruff tho losing diamond at
the end. Had z refused to trump the
club ace. A would have put him IN with
tho losing trump and II would make
the ace OF diamonds and two spades.
Now for the variations, which make
the problem difficult. II z selects the
diamond for his discard to the third
trick. Il leads the Jack " diamonds
through him, and z has four lines Of
defence. II he wins the diamond and
returns II, y Will lead the suit twice
more. and II 2 trumps he will be over
trumped, losing all his trumps In three
tricks. Then Il gets in with a spade
TO mako the last diamond.
II Il wins the jack of diamonds ard
Soes back with the suit. but refuses 20
ruff later on, A dlscards a club and
then trumps, so as not TO have too
man. trumps at the end Three rounds
Of trurps puts z In with the Jack. and
ee must lead a spade 10 Il.
2 may win the dia and shift to
the spade euit. Then B wins three
tricks IN spades and A trumps tho
fourth round, leading a diamond. so
that B can lead a nth round OF spades
and give A a discard OF the club ace.
II z shifts 10 tho trump after win
ming the dia nond, A leads trumps twice
more, Il discarding diamonds. Now
when A leads the acc Of clubs y Is IN
trouble. II he unguards the diamonds
A will make a trick with the seven. as
ne has a ree1try trump. II z discards
a spade. r can set up the suit by let
ling A ur tho third round, and r re-
enters with the dia mond.
Should 4 refuse to cover the tack Of
dta nnnna n Ft'f1ua v-Fth xr,afI 400
II Y goes back with the suit, r also
goes on. and A overtrumps. II 2 re-
fuses TO trump, A discards tho club.
trumps the next diamond and puts y
hack again with a spade, so as 70 lie
tenaoe over " IN trumps NJ the enl.
Perhaps the most Interesting defence
10 when 2 undertrumps q on the third
trick. This forces b 20 lead a high
spade and follow with a small one. 50
that A may trump II. As n has only
two trumps left, A takes them out. u
d'scarding diamonds.
Now that ace OF clubs comes into
play and forces q 10 the d scard that
no avoided when he undertrumped the
club. b let's 20 a spade. In order 10
Keep a guard or both suits. Il lets go a
diamond, md A leads one. upon which
y plays tho ten. When Il wins the trick
ne can take his choice OF which NUT 20
A"au uP " ~ b4NAHS - Two tTl'kS IN u,
and allowing A TO run the last trick OF
all.
n - 1u-t about q year since We mad
a problem from Johnstown, y. Y. but
readers OF THE SUN have lost nothing
by tho delay. The last ono was a nullo.
This time Il Is a curious little no
trumper. which IS remarkable from the
faoe that the four honors from the four
su4ss have ell disappeared In the first
Ave tricks, Here Ia how the situation
sroSe We hand b,srs a curious resem-
plancS TO the problem 5ust solved.