The sun. [volume] (New York [N.Y.]) 1833-1916, 1915-09-19
Q 10
J 10 b
0 Q 9 8
A-....

Clubs are trumps and T. is in the lead.
Y and Il want seven tricks against any
defence.
The solution is for u to lead the queen
of hearts, on which A plays the six, Y
discarding "A diamond. Il now leads any
one of his diamonds. A playing according
60 the size OF It. II Y leads the queen A
puts on the ace. If a small one. A plays
small and let's the trick go up to BIS jack.
Y trumps in either case.
Y's lead is an interior spade. queen or
Jack. AS there IL nothing to be gained
by holding off. Il may as well put on the
king. z ruffs the trick with the ten of
clubs. II Il holds off with the spade
king of course Y discards the losing
heart so that Y.can come along with a
small spade.
Having trumped the spade ok with
the ten u can lead the jack and then the
smaller of his two remaining trumps, so
as to exhaust A and Il at the same time,
but throw Il into the lead. As Il has
nothing left but the ten eight seven OF
spades he must &c up to Us ace jack
nine. losing the last three tricks.
The most common mistake made by
those who sent in solutions to thisp prob
lem was in leading two rounds Of hearts
at the start, VS. king of trumps winning
the second round. Some made Il discard
q small spade so as to keep a m
90 lead to A, while others made him dis
card the diamond. so that A should lie
tenace over Il In diamonds.
Now when Y leads the spade queen and
b puts on the king, u cannot afford to
ruff with the ten of clubs, or he gives Il
Q trump trick and A a diamond. II b
has kept the diamond, which defeats the
solution. Therefore n trumps with the
five and leads two rounds of trumps with
ALo ia,r and ton aNhanStinR both A
and Il.
The next lead Is the Ave of diamonds.
If A puts on the ace he loses two tricks
20 the queen and eight. If a let's the
diamond run 10 his partners Jack, b
loses two spade tricks.
This variation prompted several to
discard the diamond from BIS hand on
the second round of hearts. This forces
Il to ruff with one of his high trumps,
lead the higher OF the two remaining
and then the smaller, which brings
about the same ending as in the trunk
play, B leading spades up to Y.
But both these near solutions can be
defeated by BIS undertrumping Y on the
second round of hearts. Then, when Y
leads the spade queen n Il puts on
the king, II does not matter what u
trumps with, because he must lead two
rounds OF trumps in order TO exhaust A,
otherwise A and b Will make two tricks.
II z trumps with the five and leads
Obs two remaining trumps, B gets rid OF
the diamond and q loses two diamond
tricks. If u trunps the spade high and
leads n small trump, TO prevent the dia-
mond discard. Il leads the diamond, II
z covers with the queen A a two
diamonds. II u does not cover b cad
the spade and AS trump must maxi
then or later.
Several Thought the lead OF a small
heart originally would solve. as 1t forced
A to cover and Y TO trump. making
e queen good, but they overlooked the
importance OF the opportunity to discard
the diamond IN BIS hand, which comes
later.
When the spade queen is led for the
second trick. covered by the king and
3rsmped with the Ave, Y can win all
ths trump tricks and lead the small dia
mond. as in the u play. But In this
variation A can safely put on the ace
10 as TO prevent b from leading those
losing spades. because A can throw 2
back INTO h "a with the heart.
The point that is overlooked Is that
II 2 tries to avoid this by getting rid
IT the winning heart before he leads the
qve of diamonds, he gives Il the oppor-
tunity to discard the Jack of diamonds
70 that A can win two diamond tricks
b matter what z leads.
Correct solutions from:
c. F. Johnson, D.. Perry, D. A. w,
Roscoe c. Harris. +. II. Fairfield, George
B. Glover, o. II. Boston. Ralph Norton,
J.. 8. Hart Jr., Henry Andersen, JOIN
c.. Hume, ii. II. Fuller. J. w. Wortz,
James Steen, w. r. w, Il. S. Chicago,
Il. j. Sarle. A. I. S~trasburger, Walker
McMartin. c. +. Morse, George A.
Wolfe and S. S. Clauss.
Late solutions to No. 342 from George
b. Glover, John c. Hume and Dana
MacVicar.
hose who followed these problems IN
the past will doubtless remember tina
one OF the names which regularly APP
peared in the ist of solvers was that OF
X. W. Woolcoinbe- Boyce, who is now In
England and out of range of the honor
list, but who sends the following very
mat little exercise in endings for thu
players on this side OF the Atlantic to
puzzle ove
BRIDGE PROBLEM NO. 345.
BY X. w. Woolcombe- Roycn.