The sun. [volume] (New York [N.Y.]) 1833-1916, 1915-09-05

and comes through again, so as to make
VS. nine good for the last trick, and the
spade ace dies.
III d comes back with the club in.
stead of the spade he establishes the
Jack for Y. and the ace OF diamonds
makes the required fourth trick. II b
comes back with the spade ace, so as
to make the third spade trick Y dis
cards the diamonds on both tricks. g.
as to make the club trick whenever II
leads clubs.
The composer points out that the
club ace. followed by the spade instead
OF by a diamond, will not solve. because
the spade lead comes from the wrong
hand 4 will win whichever spade
u leads. and Y does not know who will
win the next round, as 1t lies In the
power of either A or b to do so. d
underplaying the ten and queen with
the Jack IL Y leads the ten.
A mall diamond from A settles mat
tiers. III Y wins with the ace Inc leads
another spade y waits until he sees
what Y discards before deciding to win
the spade or leave 1t with A. As Y
must unguard the clubs or discard a
diamond 1t is easy for A to make three
diamond tricks or for Il to make three
clubs.
a. " unfortunate tldI HuCn n pretty
olution should be entirely covered up
by a much simpler one which the COM
poser apparently completely overlooked,
but which the cracks that solve TAIE
Sun problems promptly brought to light.
1t is this
III II leads the ace and another dia-
mond \ Is obliged to cover the second
round with the queen or ten so as to
shut out the nine. Y lets him hold
the trick. and A has to lead.
IL A leads the spade A and B can
make three spade tricks between them
at cnce. but that Is the end. because
the momen either OF them leads a club
u jumps for IL with the ace and comes
through A with another diamond, so
that Y makes we tricks with the king
nine. II A leads a diamond instead
OF the spade the two diamond tricks
mature at once.
The only persons to And both these
solutions, and TO see what the
Intended to be the line OF attack and
defence were G. +. johnson and II. r.
Markham Those who saw the authors
olution. following with the small diamond
after the original lead OF the ace of clubs.
were Henry Andersen. II. H.. Fuller
and Miss Helen c. Lucas. None OF these
mentions the ace OF diamonds opening.
'hVSt WIN Ept tHt ace anu HnOJner OlA-
mond solution were Walker McMartin,
c. +. Morse, Dana Mac Vicar. d. A. w,
Ralph Norton, +. II. Fairfield. l.. $.
Hart. Jr, j.. c. Hume. W =. w. c. ".
Statham. +. l.. Bates. II. ~. Starr, T. ].
Cline. :. s. Clauss. w. ]. Cakes, c. @.
Spotswood, Roscoe c. Harris. L. @. Chi
caeo. Edward Wheeler. S. y. King. II
c. Washburn. George W Lambton. Ed
ward Simonds and A. l. ~Strasburger.
The last named thought the ace OF dia
monds was the only opening that would
solve. 1t Is q pity that this problem
could not be changed so as to preserve
the original idea Of the spade lead from
VS. hand. Several sent In solutions that
started with the spade ten. A playing
the queen. but they forgot to give up
the Jack IN RS hand TO unlock.
In order to give this composer another
chance to show what he can do against
the cracks, THE Z takes pleasure in
putting him back on the mound with a
new ball. to see IL the cracks can solve
Its curves.
BRIDGE PROBLEM NO. 343. :.