The sun. [volume] (New York [N.Y.]) 1833-1916, 1915-09-12
y 4,
a
Haass

1ncre are no trurnps anu IA 10 III INC
lead. Y n z want five tricks against
any defence. A glance at the position
shows that II Y Fan establish one Of his
smaller diamonds and get into the lead
solved. 1t is equally obvious that about
the first thing the opponents will do
when they get Into the lead will be to
ake that reentry ace Of clubs out OF
rs hand before the diamond suit is
cleared.
There being no harm In trying II, 2
starts on the diamonds with a small
one. putting r in. Now II has two lines
OF play open to him. He can kill hat
reentry club ace at once, or he can
start out to clear his own spade suit.
Let us suppose he leads the spade.
z plays small and Y wins the trick
regardless of what A plays, so as to
lead a second round OF diamonds at
once. while z still has that winning
club. z can either let the diamond
slide or win II at once and lead a
third round. The point IL hat Y and
2 get two rounds of diamonds and es-
tablish a second trick in hat suit be-
fore z loses the ace OF clubs, the ace
Of hearts making the required fifth trick.
II B sees that this will be the result
OF leading a spade at the second trick
and turns his attention to killing h a
club reentry u will n V to abandon
| all hope of that second trick in diamonds
and turn his attention to the possibilities
Of the spade suit. which B refuses to
lead.
There are two club leads open TO q.
and the majority Of those who failed
on this problem did so through their
want of care in Analysing the different
lines of attack by which these different
leads must be met.
II II leads the club nine 2 wins with
the ace and makes his ace Of diamonds
at once. The next thing is 10 put Y
In with a heart. This enables Y to
throw A into the lead with either a
club or n heart no matter what a played
20 the first club lead. Being in the
lead, there Is no way In which A can
prevent Y and Y from making two
spade tricks, hut there are other ways
In which Y and 2 might get their
quota OF tricks when r leads the club
nine.
But II r leads the six OF clubs we
have quite a different situation 10
handle and II Is unquestionably the
better defence. 4 drops the king under
rs ace, 80 as 10 leave II with the best
club, Now. II Il leads the ace of dia-
mond he loses. and his only play is
the Immediate lead OF the heart. putting
Y In, BIS best discard is a spade.
The Immediate return OF the heart BY
Y forces another discard from Il. and he
may as well give up the nine OF clubs
as a stu holds the command with thu
seven. A diamond would be imme.
diately fatal. Y discards a diamond and
A wins the heart trick with the eight
This brings us to an ending which seems
TO be quite new in problem construc.
ton.
II A leads the spade he presents hi,
opponents with two tricks in that suit
II he leads the diamond rs ace come.
INTO play, enabling him to win the tricl
and throw Il back into the lead witt
another diamond. All right for b, blu
what Is A 10 discard? II he lets 20 IN,
club Y makes a trick with the five. Il
a spade Y makes the ace and Y tn,
queen.
To avoid all this suppose A makes hi.
club, TO which Y follows suit. All righ'
for A, but what Is r to discard? II n,
unguards the diamonds Y makes the ex
ira trick In that suit that he is schemtn,
for by dlscarding a spade. II y lets &,
another spade u discards the diamond
and either gets In with the ace of dia
monds to make the queen OF spades late,
or gets In with the spade queen to max,
the diamond.
II b tries to avoid all this by discard
ing another spade when Y returns IN,
heart, keeping his top club, z will dis
card a diamond Just the same, an,
sooner or later A or Il will have to lea
tho spade. Which. II does not matter
as Il will have only one left and W
make two tricks.
The mistake made by several who triet
this variation was to make u lead tn,
ace of diamonds and follow with a hear
or another diamond after Il had led tn
smaller club and A had given up tn
king. The defence TO this attack is 10
A to discard the club II Y leads tw,
rounds of diamonds and for j to lea,
the spade, II " follows the ace on dia
monds with a heart II discards a spad
and when Y puts him In with the clu'
leads another spade.
one tricky variation. which aevera
thought would solve, is Cor Y to let tn
diamonds alone after winning the Gin
trick and play a small heart, Y allowin
A to hold the trick. But this attack
defeated II A leads another diamond a
once.
The important points IN the probler
/, are the opening lead OF the small dia
, , mond and The play In the heart SUI
when Il 'eads the smaller club.
Correct solutions from:
Walker McMartin. F. II, Fairnelt
, 4 Henry Andersen, ID. A, W., A. I, Stras