The sun. [volume] (New York [N.Y.]) 1833-1916, 1914-06-28

Clubs are tfumps aud 2 is In the lead.
Y and Il want all eight tricks against
any defence.
Like many other great problems this
one has a simple enough theme. the difrl-
Guilty being 10 work it out successfully.
The main idea OF the problem IL to re-
verse the usual procedure in forcing dis.
cards. In every other problem OF this
sort the trick is to get the player on
he right to discard frst and to follow
him. In this one OF Whitfelds 1t Is Y
that keeps the suit which Il d'scards
A glance at the cards shows seven tricks
In plain sight Tor V and H. These are
the four trumps In VS. hand and the three
winning cards in rs. 1t Is therefore clear
that If or can make trick with
my small card In plain suit the prob
lcm Is solved.
z begins by leading small spade.
which trumps. and then leads trumps.
II y discards spade here it il evident
that can make two spade tricks By get
Ing In on either of the rcd suits and let
ting Y trump another round OF spades
80 that the King will drop the jack and the
fourth spade will be good for trick. Y
getting In TO make It by winning the lead
in the other red suit
As the spade discard will not do b must
let go one OF the red suits and u fol-
lows him. In the ordinary p:oblem z will
keep the suit that q dscards. but not in
this one. Let us suppose that y d,scards
u heart. leads that suit at once.
This puts in. but still has both
rcd suits safely stopped leads the top
spade and Y is the player who keeps the
suit which Il discarded, on the trump lead.
Another spade and Y trumps 1t. but A
stll holds the best hear; and the guarded
Jack OF diamonds When Y leads his last
trump b must either give up the winning
spade or one OF his diamonds. while his
partner must either give up one OF the
diamonds or the winning heart. Which
ever they do either wins n trick with
the six OF hearts or z gets one with the
ten OF spades
Should Il discard a diamond instead Of
a heart on the first trump lead the same
position ia brought about. although it
looks easier for A. as he has more dia-
monds than hearts. but Y will always
have one OF each red suit to lead at the
end.
When dscards a diamond z does the
same and \ has enough OF that suit TO
spare one also. y leads n diamond. put
ting z in with the queen Now when z
leads the space a can still keep two of
each red suit but will let go heart.
on the next spade lead. which Y
trumps. A wants only one diamond to stor
that suit. so he Keeps two hearts. but
when that last trump lead comes along
\ and b find themselves facing the same
problem as when II let 10 the other suit
each having the best card of n differen:
suit and two cards of the same suit Sc
that they cannot protect all three.
Several solvers thought this problem
was built on the same lines as No. 279
In which was the only player that held
any trumps. But In that problem IL was
necessary for n to get rid OF his win.
ming cards at the start, and Y never put
him in again until the end.
Correct solutions from:
w. 4. BullSley, Harris Burg. Burton D
Blair. James T.. Cox. l.. NJ Frost l.. S
Hart. Jr. j. w Wortz. Frank H. Young
ID. Shinns, X. w. Woollcombe- Boyce, w
r. w. W. II. Palmer. Jr.. Ii. q. Braine
Or, w. II. Way c. J. Schramme. Walter
Rail, c. ii. O'Connor. keystone, George Il
clover. d. A. w. Walker McMartin, ]. c
Hume. Henry Andersen. o. II. Boston anc
Il. T. Morton.
Late solutions to hand from jaime.
Steen and James T.. Cox for No. $50.
Here is another warm weather prob
lem, the solution OF which aptly illus
trates the principle OF play with which
every beginner should be familiar II h,
hopes to pick up any extra tricks a
the card table: