The sun. [volume] (New York [N.Y.]) 1833-1916, 1914-03-22
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1here are no truInps and Y In In the
lead. and z undertake &c force a an,
II to win four tricks out OF the seven
against any defence.
The beauty OF the position IL that II
looks easy. and several fell into the error
Of making light Of II. Here In a speed.
men, from Peiig wansiey:
Frank Roy's 267 In just too easy. A,
q glance and u must take two spade
tricks, and In doing 30 z must DO In the
lead at the third lead so as to put In
with q heart and allow Y to discard q
diamond. Then A and b must take the
remaining tricks. The play is In this
manner: z leads the spade seven. Y
plays the Jack and returns the eight
taking the trick with the spade nine. .
This 10 simplicity itself. but unfor-
tunately II does not carry out the con.
ditions Of the problem, which are that
Y and 2 must win against any defence.
n z starts with the spade seven the
problem cannot be solved. no matter what
Y and Y may do after that card Is played.
II z wins the second round and puts A
in with the heart. as suggested, Y get.
ting rid OF diamond, what Is to pre-
vent Il from getting rid Of the club queen
on the heart lead? Now the Jack OF
diamonds clears As hand. and a spade
enables y to get rid OF his remaining
club What are Y and z going to do
when A leads a club?
The main reliance OF the defence 10 for
A 60 put the ten on any spade lead from
Zs hand. II starts with the seven. up
goes the ten. This forces the jack from
Y or A shoots n club and u plays queen
and nine. giving A the diamond discard
IL y wins with the spade jack and leads
the eight II Is z that leads the club and
there is no way to stop B from getting
two rounds because he can win with the
nine and lead the queen. giving A the
diamond discard. A gets rid Of the heart
on the next trick
II wins the second spade trick and
plays the Jack of clubs on the third
trick he gives up the change to overtake
VS. ten. 80 that AS discards are easy,
40 he can see whether z will win tho
second club trick or not. and adjust him
self to II.
The closest OF the near solutions was
10 open with the heart nine. and several
spoiled their chances for a credit on this
problem by giving that as an alternate
solution. AS II either we're sound. In
this opening II is clear that VS. best dis
card Ia the diamond. Two rounds OF
spades follow. the nine first so that Y
shall be In the lead for the fourth trick
by throwing A in with q diamond II
looks as II A and Ii must win the rest
no matter what b discarded on tho frst
trick" as many put IL.
But this IL not true. because BIS dis
card on the first trick is vital He lets 60
diamond. keeping both clubs for de.
fence, When A il thrown into the lead
with tho diamond at the fourth trick he
plays two winning spades. giving b two
club discards. What will and do
with the four OF clubs at the seventh
trick?
Some Of those who picked the heart
opening did not make the best discard
for Y. throwing club instead OF a dia.
mond. b still discards the diamond. But
when A il thrown into the lead with the
diamond he leads the club at once, the
tive spade leads being unnecessary be-
cause can afford to win two clubs and
then lose the diamond to Y.
The heart opening will solve II b dis
cards q club on the first trick because
will not bother about A At the fourth
trick but will lead the small club for
b to win. and II will then be Impossible
for to give A that essential diamond
discard.
There In only one correct solution TO
this ingenious problem. and that il 10
lead the spade nine and play so that Y
shall be In the lead on the second round.
regardless OF AS play on the first trick
leads the small club and d Putp on