The sun., 1913-12-07
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There are no trumps and n Is in the
lead. and want five tricks against
any defence.
The solution evidently depends on fore
Ing discards fro'a b in such a manner that
z shall discard after him. and adapt him.
self to the situation. The solution Is
for z to Trad a small diamond which
may win With the ace or pass The au-
thors solution Is for to play one or
his higher diamonds in either case. so
as to lubbock. II a plays the ace
gives up the queen. Now IL leads a
small spade Y wins and returns 1t, b
letting go a heart a heart and CLUB.
This puts A in with the spade ten. IL
he leads a diamond wins with the King
and teads the queen of clubs. forcing the
discard from Il. which enables u to keep
two winning diamonds: or two hearts
and q diamond for reentry. II leads
a club instead of a diamond. the discard
Is forced from j. at once. because y wins
the club. and after he leads the king
Of diar,onds, II Is left with two hearts
and one diamond, or two diamonds and
one heait.
II A leads high club after winning
the first trick with the ace OF diamonds,
Y lets hiru hold the trick. Another club
and the spade queen forces b to give up
a heart or make three diamonds good
In rs hand. II Il blanks the ace of
hearts Y puts him in. forcing him TO lead
diamonds up 10 Us king. and the return
Of the four enables Il to make the ten OF
hearts.
6rSt n
playing the Jack. the authors idea is for
Y to win with tAe queen and lead the
queen of spades and then the king of
diamonds. a can make his spade trick
at once, or he can lead a high club II
the club passes II. and lets him lead
again. and these two tricks force the
discards from Il.
While the unlocking play in the d!a-
mond suit was intended to be one Of the
KEYS to the solution, and u can win the
required number OF tricks without il.
Suppose takes tho first trick with the
ace and plays small Whatever leads.
Y wins and proceeds TO make three more
tricks at once. with the two top diamonds
and the two black queens.
BY that time both and will be down
tn three hearts apiece. or two hearts and
a. diamond. Whichever it is, all that r
can make is two hearts as he must leave
himself with a losing card in one or other
OF the red suits. II y passes the first
diamond trick, y can win with the queen
and return small diamond, instead OF
the spade queen or the high diamond.
Now the same plays come about as be-
fore. winning whatever \ leads. so as
always to give Il the discards after b.
The following solved the problem ac-
cording to the composers idea:
Frank L. Haycock, James Hunter
Walker McMartin, T.. NJ. Frost Frank
II. Young w. =. W, II. l.. Munsen l.
s. Hart Jr,, *. w. Woollcombe- Boyce
S. q. r., James r.. Cox and u. A. W.
Those who got the solution without un.
blocking the diamonds were .. ii. Boston
j. G. Hume. j. W. Wortz c. f. John.
son. Milt. Ferd Samuels, Henry Andersen
NJ. +. NJ. John H. Whiting, 6. L. Hempel
D. G. Braine, Charles NJ. Root. Roscoe C
Harris &. ~. O'Connor. Il. Bccbe, Man
Williams. &. +. Darling and James Steen.
Those who tried to get 1t by starting
with club overlooked AS immediate leat
OF a club, II left with the trick. which h'
must be. or he makes three clubs. Now
y must lead diamond some time 0l
other. and a is in with the clubs
The first OF Mr.. Strasburger's problems
appeared in THE Sun on January 30, 1910
Since then ne has given us nearly dozen
several OF which have been selected fol
the honor list. and THE Sun takes pleas.
ure In presenting his portrait.