The sun. [volume] (New York [N.Y.]) 1833-1916, 1910-03-06
PROBLEMS FOR SUN READERS
q CTRIOI SITUATION WITH
THREE TRI MPS ar RRIDGE.

! THREE TRt MPS ar BRGAGF.
Mlaaakes % Wsalsl-be SEWERS &C I've
Bridge Prsbseu,s- TIE Abraham Niehas
PalnaerH 90 Nnsthsr JSS-Dver-
sigha &C q chess Master IN . Match.
Some correspondents insist that prob
lem No - can he solved by the original
lead Of the trump. although the defence
% that stack was clearly explained. 4
larger number dispute the published
! 'Olu.iOn. leading the spade king first. and
announce themselves willing to take the
Al end OF u end defeat tire attrck.
They argue that IL u starts with the
king OF spades and then leads the queen
Of clubs. A should win the queen and re-
turn the trump. not tire king % diamonds.
Their point in that instead Of forcing h
to discard ON the diamond and on the
trump. he should make one discard only
while he still has the commanding spade
and sure shoppers In hsarts.
The immediate return OF the trump puts
Y in. and he leads the three Of hearts.
which b covers with the ten. forcing zs
jack. and the still guarded king IL good.
for 70 Y returns q spade. b stin has . small
heart 10 lead. which forces Ia ace or
makes Y lead q diamond TO As king.
which haa not been given up.
The answer TO this line Of attack y for
Y to lead the nine OF hea rte. not the trey
compelling n to put on the ten or king.
won by the jack or ace In rs hand. Now
when 4 puts u in with the spade. p has
the minor tenacs in hearts and Y has the
mo ior tenAce. probably acs six over the
king ave. and a. Y's card 10 the trey. he
h not compelled 60 win his partners ak
II b leads tho five. Played in this way
the king OF diamonds dies.
| Problem No. - 10 another OI 4. P.'s
and IL caught some % the beat of them
mapping This problem has the novel
feature Of presentinG an apparently
double solution. 80 that many persons
thought IL could he solved In either %
two ways. but such 10 not the caSe. Those
who confined themselves 90 one way and
the right one saved themselves from q
failure Those who gave both ways
betray the weakness Of their analysis
and cannot IN credited with correct
Il leads the ten of apadeS, which Y wins
with the are. returning the spade AZ once
for Y tn trump. plan il now to arrange
a rsentry card for J TO get in and catch
B's trump This he accompllnhes bv
leading the Jack Of diamonds. not the small
one nor the ace. which compels 4 Co nut
ON the king or to lose IL.
4 can return either the diamond OF the
heart. II he tries the diamond Y let's
VS. eight hold the trick. 90 that can
take ont B's trump, while x gsts rid Of thu.
nine "a hearts. The rest 10 obvious.
| 10 A returns the heart Y wins the trick
and puts Y In by leading the FIVE of dis-
mond- 81 that BIS trump can be pulled.
aud 2 discards the ace OF diamonds. max
ia the last trick Nth thu hsart
Of course IL refuses to cover the Jack
Of diamonds BE trump cannot he caught.
but y makes the diamond are ~ once and
then l~sds third round OF the suit. which
B trlmps. discanding . heart what
ever leads the Last trump and the queen
of hearts are good Tor two tricks.
Although several solvers remark that
| II ia useless FOR z 10 put 4 in the lead
while 4 has q spade. and that therefore
the spade opening - ns.cca.ary 20 prevent
A from leading a SPADE when he gets in.
they clearly overlook the real object OF
the SPADE opening because will never
lead that suit.
| Those who solve the problem by start
ing with the jack OF diamonds make A
win the trick With the king and return
| . spade. This Y wins with the ace leads
the nine for 90 trump and then gets
in agnin With the eight Of diamonds aud
| catches B's trump aa before.
, ia refuses 10 win the first trick With
the king Of diamonds makes the ace
at once aud then leads the spade.
I wins this and lsad~ tr,ImTp- instead Of
forcing. letting make the established
diamond and the queen % hearts. giving
4 trick With the Jack - hearts az the
end
But this solution - unsound. although
a great many tried IL or give &c as an al
jack 4 wins IT, and al once returns the
diamond. not the spade. In spite % any
| thing y and can do A and p must make
another trick because this prompt re-
turn of the diamond takes ont 81 Va
hand the card % reentry which IL nece--
~aTy for the purpose of catching Ia
! trump after Il has ruled the spade
/ This goes 60 show that tho~e who
/ declared that the king OF diamonds was
4 the only possible trick Tor Abb no matter
how the hand was played were clearly
in the wrong because IL 10 po~sibie for
I and to make any one Of three Cards.
the king Of diamonds. the seven Of tr1Imp~
or the Jack 81 hearts.
Correct solutions from
y. Mckeage, JT.. Thomas y. Quincy.
l.. u. B.. Hatilc 4. Schon. J. u. G.. sadie
6sdssien, W r. D., !. ". Wortz. George
b. Glover. John B~At'ie, \. ". Black
gS n WALSH. 1 " co W "ro'H r y
I Balcom. u. 4. W. Mrs. Robert a. Hankin.
~ u. MACkay, Il. ". Hawkins. Igoe.
Tramp Irays, ;. {; knsey. y u. W.
George D. Morris, Mr-. R2bert eIckery.
! J l. scott. c. IL. r.. {. II. W Milton {.
lsbel ~ y. Ransom. &. =. Johnson,
/ Victor Du Point. Jr. james Hunter, y.
q. T.. 4. VI. Harrington. Robert Crothers.
William Kent. G J. Porter. Max Williams,
Roscoe G.. Harris, ". p. W. William ~
Baker. Elizabeth White. Everett A. Aborn.
u. VI. G., !. y. Barrtow. Arthur y. Ft'in-
ger, Wcehawk. EdaRr Josephson. W. ".
Dudley, Algernon fray, e. Walton Aborn.
Mary Ann. \. y. J.. Hillbrook. Richard r.
Hall. ben kard. Constance Gardner.
=. A. GuntlieY, =. Y. r.. ". X. Thaw.
-. e. Schwcclke. G. Olcott. u. n L.. W H.
DeIehanty, A. \. NJ. William J. Lipp-
mann, Frank Roy, A. \. KirkInan. James
T. Eagny. 4. Il. Huntington. Bay state.
=. ID. T.. DIR. George e. Bailey and II. G.
Jewett.
Herr h q curious arrangement 81 the
cards. in which there are no tr1Impe and
ai@o suit entirely missing. AZ that IL
does not really matter whether the missing
club suit was the trump az not y ~ IN