Buchanan County bulletin. [volume] (Independence, Iowa) 1869-1891, 1876-11-10
4. Bound Indiana.
s. Bound Illinois.

4. Bound Indiana.
S. Bound Illinois.
6. Where are the highest noun
tains?
Z. In South America, on which
side of the Andes is the greatest
amount of rain and why?
8. Where arc the coal regions of
the United States?
9. How is ram produced.
10. Name five Of the largest cities
in the United States.
HISTORY.
!. What were the alien and scdi-
ton laws?
2. Why was not Adams re-elect-
ed?
3. When and under whose adj
was Louisiana purchas-
ed?
4. When and how was Hamilton
killed.
5. Name the principal battles of
1913.
6. Name the important events of
1915.
7. How did Louisiana get it's
name?
8. How did the United States OBJ
tam possession of Alaska?
8. In what Is the executive power
OF the United States vested?
10. The judicial power?
For the benefit Of those who failed
few solutions are given.
ARITlIMETIC.-FIRST CLASS,
l. The selling price must be ST..
1854 plus 10 per cent of 1864, which
is equal to $50. The asking price
is the base; call this 100 per cent; as
he abates 10 per cent of the asking
price, 90 per cent of the asking price
remains; but 10 per cent of this is
lost by bad debts; 10 per cent of 90
per cent will give per cent. He
will have left 80 per cent Of the ask
ing price less 9 per cent of the ask
ing price, or 81 per cent of the ask
ing price; he receives 81 per cent of
the asking price; also, he receives
$50; then the asking price must be
$50, divided by 81, equal to $40.
2. The base in bank discount cor
responds to the amount in interest.
The interest on any sum tor 90 days
at s per cent is equal to per cent of
the same principal for one year; then
the base of discount is lO2 per cent
of the proceeds. lO2 per cent of the
proceeds are to be discounted so as
yield 2-lo2 for 90 days or s-lo2 for
one year, which equals divided by
1917 4a-5l. In short, the solution
is divided by lO2, which equals 7
43-5l per cent.
8. 500 of stock at 6 per cent,
will yield 4 specific sum of SO; to
yield the same specific sum at per
cent, it will require 5000 of stock;
and to yield the same specific sum,
So at 9 per cent, it will require 10 OF
5000, which is s66SS, that is, the
stock must be bought at eea per cent
which is a discount of 334 per cent.
The solution is, SlOOX6, DIVIDED by
9, 100 per cent less 665 per cent.
4. 81 acres reduced to square
rods, give 600 square rods. The
area OF triangle is J of the product
of the base by the perpendicular;
then 600 must be one-halt of the pro
duct; 1900 is the product of the base
by the perpendicular; 1900 is the pro-
duct of two factors; the given side,
374 rods as one of the factors; the
other, the perpendicular, is 1900 d.
vided by 37t, which is 80 rods. The
solution is, 3aXl6OX2 divided by
374.
5. $1,000 at 8 per cent, will yield
$500 interest; this $40O at 10 per
cent for two years, compound inter
est, will amount to $4s4; the second
year, the $4,000 will yield s4OO more,
this at compound interest one year
will amount to $40; the third year
the $4,000 will yield $500. AT the
end of the three years the 5000 will
amount to $6,324. One dollar on
the same conditions will amount to
1891.
The solution is s6,324 divided by
1881, which equals $4,751.31, the
present worth; and $4,000 less s4,-
1871, which is S24S.69, the dis
count.
The sixth presents no difficulties.
I. 3.l4l6 multiplied by Sc, the
square of the radius, gives the area
of the circle, ll3.O976 square inches.
The given arc is an arc of As degrees,
| of the circumference; then the area
of the sector is ! of the area of the
circle; 1l3.o976 divided by s gives
14.137x square inches. The solution
is, 3.14l6 multiplied by 36, divided
by s.
s. Take away 10 feet, the first dis
lance through which the ball fell,
and then the question becomes:-
Find twice the sum of an infinite Sc
ries, of which the first term is 8 feet
and the ratio 90.
The sum Of the series is, 8 divided
by Ito, which is 80; then twice 80,
plus 10 is the distance through which
the ball fell, 100 feet.
The 9th and 10th questions pre-
sent no difficulties.
l. This question requires the
greatest common divisor of AGO, 3s4,
and 42O, which is IL. This subject
comes before Fractions in Rays
Arithmetic. Several persons failed
to solve the question.
2. Mainly, the second asks this:
Why do you invert the divisor? If
we teach, this question cannot be
evaded. Nearly all the applicants
solved the problem. Only two ex-
planned.
3. This requires ciphers to be an
nexed until the billionth place is
reached. The solution is 4,So6,OoO,-
900. Several failed on this.
4. In this we have the difference
and rate to find the base. The solu.
ton is 64.6 divided by .95, 6slb.
5. In this we have the amount
and rate to find the base. Divide
549sOs by LA 40, and this quo
tent by 3.lO3.
6. Had he worked the 10 hours,
he would have earned SO. For ev-