The Jackson standard. [volume] (Jackson C.H., Ohio) 1847-1888, 1869-11-25
EDUC4TION1L.
EDIToR STANDARD /.

EDITOR STANDARD:
noticed In the last is
sue of the Standard some problems proposed
for solution by Mr.. "Penmanite," which ]
purpose answering as follows:
1st Let &c equal the breadth Of the board
and lot 10r equal the length of the b Oard
The length, 10c multiplied by I'll c breadth, a.
will give the superficial contents, Which must
be equal to 10 81 IT. or 21GO 50, In; therefore
loo multiplied by . Or 10cs equals 2160 so. In.
Dividing both members Of The eqatiOn by the
coefIlcieht of Ea we have T2 equals PIG. En-
tracing square root of both members, we find
that equals 14.606J+ H. or IT.. 2.60G9t H.,
which Is the breadth Of the LOard, then l0r
equals 1lG 9690+ in. or II IT. 9G9Ot In. the
length the board
3D. Sl0O0, the net gain plus $500, the expenses,
is the whole gain, before deductng the cxpen-
ses which Is to be div ided among A b 9 and d
in The ratio Of 1-3 Ia Ia 1-6. AS share $500.
B's share, sl125, C's share, $112j, Dis share,
$3.50,
Sd. 70 rods multiplied by 20 rods equals $50
perehes whiCh ore equal to acres and roods.
II rods multiplied by " rods equals 1lO
perchGs, and two pieces would contain 2SO
peaches which are equal to acre and 3 luods.
The difference between A. : II. and A. 3 H. Il
l acre and rUods, OBSERVER.
swers to questions in the 81 mdUd 0t Oct. 2S:
Seer, 9th aud 9th. Observer, 3d aud 9Th Arch
or, 1st, Sd aud 4lh. Il. +. c., I'd.
Answer to Penmnnte's quCstlOnsi LIST, !.
.247+ feet long and 1,2247t feet wide, 3D. A,
$1,000, b s1125 Q 1920, and d 5000. 3D. Ia
acres.
Parse the intal alicizcd words In the following
sentence II cut down yciiOW popular tree
cut of a log ten feet toaG and hcwcd It square.
III buy IL oranges at cents each, II at
cents cach, aud at 7 cents each how many can
afford to buy cents 10 sell the lot ut cents
each, aud gain cents ou every omngo2
Solution required. TYLER.
JACKSON Nov. 20, 1860,
Sir; In your paper of las
week, noticed few questions by PenmdRite
and Archer, TO which propose TO give solutions
The answer will correspond to the number OF
the question.
1si The board must contain 10 50. IT, If Its
length bC ten times Us great as It's width, 1t will
produce ten squares, each Of which will contun
Que tenth Of 10 50. f., which is lJ ~. fl. Hence
the square root Of 10 So, feet will give the width
of the buard.--1.5z=1.22 .2247+ So. feet. Aud ten
times that Will be It's lenghth, -1.224ItxlU
s=122l1t-length.
md, The clear money, (inGudlng the pXpen-
ses, which and d Me to drtray out of lhch
own money!, Is SljOO of which receives II,
b u, G a and d 10, Sl50Os- 3==$15OO As share,
t4b0OI 4zS1l2j BIS share. $IjOO.- l=s112j CS
share md $4,000 GHz$760 DIS share But q and
D have aid The EXPENSES hom the business and
these, (Which are 5000 must be deducted from
their shares. Now Q aud d must pay the ex.
pelscs In the ratio Of ii to l-G or . ~. Hence
I will got S1l25--S9OO= 1925, And viii get
S75O-- S2OO=S55U.
.. A piece of land 2S rds by 20 rds, will equal
$50 rds. Two other pieces, each one half as
long. aud one half as broad, will equal $50 rds,--
difference (JB0 rds--9SO rds=z2SO rds.
ArchUr's question.
Ono apple ut for cents will cost 80 Of cent
One appIe ut for 4 cenls, will cost ~ of cent
Two apples, Gone OF each kind will cost 3-5+4-7
s=l1.95 ul II Ct, aud one apple will cost one huff
of ll.B5. ll.35f2=4l-70 otN cont.
He sells the apples NJ II tor7 cts which 7.l2
of Ct each Hence he must lose on each ap-
pie as much Us he pays more Than ho gets,
ll-5O- 1-l2== l-l20, Therefore he lOses 1.420 Of
II cent on each apple.
Since no loses2 cents on tho whole lot, he must
buy as many apples as l-i20 of n cent Is contan-
ed times IN 2 cents. q l-I20zsSi0 times
Therefore be bought $40 apples. .s
Yours Resp1N
LUMINARY.