Daily Ohio statesman. [volume] (Columbus, Ohio) 1855-1870, 1868-04-04
ANSWERS.

| no. fo-32O Plus feet.
No. 46-3. 5, Z and o.
No. ak equals 80: equals TO- I equals 40. anl
equals 20. There are several values oan be givei
to sach letter to fill the conditions of the ques
| ton.
No. 4s-75o pounds.
either calculate n Cost of 20 ooo. 900 drinks at tw,
cents each pc day for year. is sl46 100 600, ant
the interest of 81 5000 at per cent. for
No. 5l-,osOe plus of the whole area Of circle.
No 52-Method not correct; landlord should hav'
had so bus els ins,cad of 1s.
| No. 5s-l605 8565 cubic yards.
| No 43-Needs no proof. 1t 8 self evident.
on the land and suppose It would t.ie it as Ions
70 subside as the water wOul be in f wing back
This experiment tried once and the Bible tell,
how long took but il is too long to record here
| WASHINGTON.
PIKBToN. ONO. March 26th 1868.
Mr.. EDITOR IL have placed the paper con-
tanning the lesson OF March 4th, and am compelled
theref re. to miss recitation for that week.
In reference to No. 81, Otose is certainly mi tax
en-. have not reviewed my work upon it. the pro-
cess being rather tedious bnt the size OF the
Is almost in itself a convincing argument to me that
the area OF the lane does not greatly exceed one
would be glad TO see washington's solution to
No. Al. / guessed the angles at the same figures
myself, but csnnot call thar a so,u ution-
The following answers are for the issue of March
2sth:
ANSWERS.
No. 49-The minister was incorrect in both calcu-
lstions. Twenty millions of drinks a day at two
cents per drink would amount in year 10 the snug
little sum of $l46, 900. Tue interest 81 ,S0p
100000 for one year is sios. 900 900. What picter
No. 51NOne- fourth the difference between the
area OF the circle and the area of the inscribe
No. 52-As for every three bushels taken by the
tenant, the landlord should have two bushels. if,
after tb tenant had taker IS bushels, the landlord
should consent receive instead thereof 10 bushels
he would thereby be loser to the extent of 2 bush
No. 5s-Mine. o-T
~ STE1NERNHERz.
DUBKIN. ONO. March "a. 1868
Mr.. EDITOR: Brother Otiose says you are a jok-
about your wheel problem sdy first impression was
that you were correct in claiming two revolutions
the q. the sSe
frs members Of our class. Iunis, Guernsey. Delta
and Otivse have all array ed themselves AGAINST you
preston. will, however. state few things which
seem apparent upon demonstration.
First. Mr.. Editor, my classmates attempt to dis
prove your theory by representing parallel motion
q man running upon train of cars. a circle M feet
in
their place. but do not think they apply to this
question: Some OF your correspondents are military
men, and no DOUBT, understand the relation OF in
tern Il and external lines; row the point of contact
on the fixed wheel is external line and the NOV
necessity pass over greater distance than the
circumference Of the ioner wheel. while
an internal line. Nov these conditions demand
imperatively that the outer wheel must pass over a
distance greater than the circumference OF
ner Wheel and the circumference of the two wheels
being equal it that difference an increase of
its revolutions A question suggests itself here Mr.
Editor. w hat is q revolution of wheel? / claim
that when Ioint upon the circumference hiss pass
ed around the center and returns to the place of
This soAeel proM may be illustrated in this way
Take the lids of two collar boxes of the size
tack fast to the WALL sticS pin in the center OF
th other and fasten string to the pin; then tie
bullet to the other end to make it hang plumb: place
this lid against the wall below the other and make
nm rrrAa~ Nha rny a,rya htS
around the other. making it turn by friction you
will see this mark pass completely around the
ter and take its place under the string when the
moveable lid arrives at the top of the fixed one and
will perform another complete revolution by the
81 sne erp % mars S,aps
dence. am of the opinion that the moveable wheel
Yours in revolution, LIMESTONE.
COLUMBUS, March 81, ls6s.
EDITOR OF SrATEsM AM There is little doubt.
that the Puzzers cOiu nm of your paper afforis
good deal OF amusement to many of your readers.
its publication admits of so re improvement. Ali
problems. sent in for insertion. should be accom-
panied with correct solution. for the private notice
of the editor Gas likely it is) and when answers are
ma De and published afterwards by several parties,
(some times by the dozen differing from each other
these solutions should have the additional mark of
the editor: correct or mot correct" Persons
sending soluti from different parts of the coun-
answers are right or wrong.
take this opportunity to send some answers to
Problems OF the last three columns OF your pager.
NJ. s7-The area of a Is feet wide l.ne inside the
sdss Of fan, an 0stasSn sa7 of i to
incl9sing the octsgon equals ASS sic feet and sides
Of the octagon Itself EQUALS lss .s65 feet.
No. 4l-The angles OF he triangle are, at the
tex 30 5eg.. and at the base 81 deg: and So deg.
Length of the base so feet and of the sides sc and
feet. de ecting line equals 81 plus feet, angles
deg. sz deg and 30 deg.
o 53-The levee of 1893 feet in length will require
l726 564 cubic Yards IF dirt am han
No; 54-The numbers are Il. IS. 8. 80. s5s and 4
No. $500 dollars at per cent and 200 dollars at
it tops: 80 504 plus teet-l0OU45 plus feet-12O o37
plus feet-l4O03l plus feet. ARCHI,
PROBLEM NO. So.
value of ea;h separately? ARCHI.
PROBLEM NO. SO.
agree with tinker, whose name was Doolittle,
10 make for my wife faG DO toned kettle;
Twelv1 inches exactly depth OF the same.
And twenty five gallons of beer to contain;
The number of inches across on the top,
Was twice on the bottom when new at the shop:
How many inch s across must the bottom then be.
WASHINGTON.
PROBLEM NO. 60.
Prove that if the sides of right angle triangle
in arithmetical progression the acute angles
oblised to be 81 deg min. SO sec, and SO deg. So
min. 10 SEQ. JACK.
PROBLEM NO. 81.
Prove that the three stra ght lines which bisect
the three angles Of triangle in the point.
OTIOsE.
PROBLEM NO. 81.
The moon is 100000 miles from the earth. Sup
pose traveller to start from the earth and go pa
the moon to the nearest of the fixed stars which is
twenty rlions OF miles distant from the earth what
proportion of his journey has he accomplished?
Ct. 3. INNS.