Daily Ohio statesman. [volume] (Columbus, Ohio) 1855-1870, 1868-01-25
raE puzzLER,s ooLUmN.

r
We commence this week on the new series. The
books are pronounced closed. and all previous ques-
tions declared answered. 7. f1 = NFsH
We present below some very excellent problems,
but they not all of them, of the order OF archl
lecture agreed upon at the convention pillars to
the door of our new temple. The agreement there
was that should begin again. presenting problems
less complex and easier of solution progressing each
month until we should again into the region of
highest" mathematics. Let us have it so.s ifss
We welcome new contributor. Will A. Our
impression is. Mr.. Will. that the same similar
problem to yours has already been answered in th.
column. However. try It again. 'st '4i ''''
Sammy. Bro her Inuis and Guernsey are Ilaying
truant. Won't they catch it. neither?
arf DUBLIN. OHIO Jan. 18th 1858.
Mr.. EDIT0R:- our most happy and entertain
ing meeting on New Years eve. when we dive ted
extended hand. it seemed like meeting with the
friends of other days: and. as we love 10 address
then knew them. so it seemed almost out of ace
to address one. by his proper name. Our cog
Se Soa
antly in the current of humor and msthema les
ssaad T dsph s es S rock
m st'ne, should not be able to rise to the sur
/ face apain. X si09IE
problem No: 14s wore cailed in sstion- | worked
it over and find he State Of California. would be
esrth's dead who Lave been consigned to the dust
whenGs they first y 5eua ,Ss
latter by, some mistake assumes the whole OF
earihs surface to be one -fou.th9
No. % SSH the Miller Academy there are study
ing Geometry. 4 Algebra ana Arithnet,c 1,,,
wAsHINaroN. o., Jan II.
Mr.. EDIroR:-Mv carelsssness caused me to send
Jack omitted to subtract the little triangle which
was not part OF the swamp in ''3ls', or my answer
I f when ny you Probem s4
solved without another part Of the triangle is given"
ter is at the middle Of the given base line and lines
drawn from center to any pon Of said circle answer
would say a few word, about Bro o sdamonstr.-
tion TO ssoi if thought lie wa' IN earnest in re.
will not allow hi in. when a demonstration ,iscalled
for to regard one. that only apple. to special case
which must be assumed. as satisfactory demon
For instance. should Brother o; offer aproposition
relative to tTsnss he would aS Soees sats to
it the assumption that he two shorter sdei were
equal. though the work might be correct if that ad-
serie. Of pr ,bemsi Essy Or hard think it xcpl.
be gvod plan to commence at least with something
moderate. DELTA.
lg,laag ~ asi JANUARY Is: 1885,,
MY FRIENDS, THE PUzzLEas :,Bepg unsbis to
ziers' Convention. l once more enter the class
through the meiium of our column s.--e-
| must CONGRATULATE our GU AZ eoue Brother OF
Dublin that with his stupidity Gas he himself call
i) on mathematics. that he is No.. on rAcrostic
iimstone's di gaise. would as K him if he knows
- JOHN SoUBRIoUET.
HEBRoS. January 90 1858. j
Mr.. EDITOR :-Sometime rast1 have been watch
ing your Puzz er's Column with some interest, But
solve any Of the problems. III hiking that of course
it was no use; but hes lug some of my friends talk
Think have the sol ion Of two in your last. The
first tried on. that 95l, about the ages of the
years had trouble with him. but took for Grant
ed that although he was SO young. he knew h. age
sSas thios can do the whole in 20 day., i" 80 daS.
in 60 days. Itl- ,.i- s-. ir 3. WILL a.
GREENvILLE O Jan. 81. 1858.
Mr. EDITOR :-Wishing to obey my MASTER will
try to recite this week. l have been receiving the
STATEsMA An Tegplarlg. for which an indebted !"
a Here are SF fs% OF the a'1
No. sos Solution: The equations are Xa plus
2XY plus avg. equals 60 %; ~ plus 7XZ. plus 3Z2.
sSn s. @ @G.Sas sHS s pd' Mx a
NX, in these equations. then finding the ,,ue If
Xa in each eqaatins them then clearing s% Sf f5sc
sas minus PLUS o. minus sSa nina; sMN.@ &c saasis aSa
posing and dividing BY sM. minus 8. we hav:. N
EQUALS 2 plus /. minus 2M2: divided By sY minus
ing, we have 4Ml. minus 6M2, eausis m nm nus T j, in
which NJ eq lals i44I By substituting, we fad n
s'i pus l. eaasis @ 10 l5ss7ss.' and equals is7s1:
Y equals MX. equals 8 364ss-; Zequais NIX. eqaals
No. s4o.-The yertex Of tho cup will be 1 5th
INCHES from ON the crntsr OF the sphere
ca g the
Brother . iose please give your solution for No.
224. your answer differs considerably from SAM
No s52-a47 81 plus. .t .,la. 4-,4 = E.B.
.NArcHEz. o.. Jan. 81. 1858.
DEAR PUzzL EEs:.The column Of this week j.,
suppose. the peludipg chapter of The Puzzler's
w en- we see "fnss" upon anything. we are con-
strained by the irresistible influence Of some coles
tial divinity to be serious aad thoughtful; but
written upon a dear friend like this column.s
friend which has been source of long continued
to a o Us and s
minds TO q brighter theme-to the "Puzzlers' Col
it moro worthy of attention than volume
No answer has beeu given to the second part of
Problem Nc, 306.. Fhe answer is .0U3407-The clip
ITCHY is quail to the difference of the axes. divided
No. saa- e. b. does not answer 1856 .7e5s7 plus
miles is the answer. 4 81 i1Fts
No 3as, (tae second 3!s) was no: answered correct
In column of Dec. 2s. Soubrquet gives q very
s sqd md, asks = tbs + the yas Of
3x plus As equals TX. Answer is. equals minus
to see our co.umn twice full this week.
i PROBLEM NO. L.. t ~ lt l-s
A cone is cut obliquely BY plane. which enters
four inches from the vertex slant side.
comes out fonr inches from the base on the opposite
slant SIDE are tne oi tae sec.ien
tude sixteen inches JACK.
PROBLEM No.2.
The diameter of an inscribed circle is to the per-
pen .icu.ar le fall on hypothenuse from the vertex
&Lrz rula Exrn, - IN
dus Of The circam,cribsd circle IS seventy I've
What are the sides of the triai gle JACK. &.
- .iEss PROBLEM NO. 8. 's7t..e.
There is triangle whose perimeter is one hun
''' JACK.
PROBLEM NO. 4.
What arc the 81 les Of. an eq ii!ateral 1 trangle
JACK.
PROBLEM NO. 5.
A man left 500 acres to sons and 8 daughters.
The Ian being in tue form Of an equ,atcr,l trisn
gle a circle wa. described rithn it. and the three
cut off by the circle were given to the slns
ts equay WHAT
ter. JACK.
IL PROBLEM NO. 6. =
The following problem has caused me considerable
Of bother ipraetiea y thsfefofe please give either
I wo lights shining on an object throw shadows at
an angle of 80 deg. 80 min, and tho straight line
passing fr)m the object to the center of straigh
Ii jpnng the lights is sixty four CD feet long.
Required the distance of the lights apart.
t-gs y,,lf+ p . X ,,a Humby yours.
j. SoUBkIoUET,
f PROBLEM NO. z. -l -Il1
tree 100 feet high breaks SO that in faliny. the
top strikes the gound 1s feet from the root of the
tree. Required the length of each piece:
a5ss PROBLEM NO. s. "
Three lights A, b and G., are placed respectively
at the vertces of the three anS es of an equaeral
triangle, whose side is l4o feet; The intensity o
the light is TO times, and that of the light q
Z times the intensity of the light A.. body