Daily Ohio statesman. [volume] (Columbus, Ohio) 1855-1870, 1867-12-21
| 562536
H -a lH.'f- So2536
BID equals 23.04 plus miles. -.
A ID annals 90 tninus % "a eouals Q6 Q6 n, ile

Il
BID equals 23.04 plus miles. 4.- -..-
AID equals so minus $50 equals % .9s miles.
i think Otiose. the above is alb ut right. though
fh nO5 ns o Ss h
Otiose, your answer to NO pa sufhceth not EX-
cuse US. SAMMY"
=, WASHINGTON, De-. l6
No problem to solve this week. hence fine chance
for condensed remarks" At
forgot to say in my last that Eve discovered
taken the defni Jon of that term from Astronomy
NY answer divided ny semi major axis is the same
as Sammy's and h. b. Is. itao- 1a-. sd -Tirq..
Thank you. Brother Limestone. for that extra
dish. -,
tion, Mr. Simpson. to nv little sth heorem--No. .,3l2
Bro. Otiose gets off a little joke on theorem 29o
and he tDen ses o WSeh depends peon
this position: since M CG is Perpendisua, to the
number of lines perpendicular to a cord and not
di.meters; Ci is then assumed to bs diameter.
sni $ro o, reasoning is applies to that only
Asmento the man of straw. Guernsey's solution Of
- r. B. Is correct on the brea question. The two
portions unbakei. put together, do not make
.spheroid. but are segments of sphere. But how
near our answers came to an agreement--S0 and 81
Come. brothers send answers to my 3ls and sl4.
To 3l4. another answer is. l.ls- and II Is. In
mts. @ s'sA' nu'''' 0' answers may 0s rendered -
q ad that my friend from Virginia agrees with
me so nicely on 30l. o. Jack, can't YIN conven-
DELTA.
20 WASHINGTON o., Dec. II. 1867.
highly approve Of our teachers remarks to
"verbosity, tor frequently in this matter my
self. Hence will say but little this week. hoping
soon to see az the class in person nd have prons;
necessary arrangements for the convention. and
bring in BILL. My name has been suggested as one
of the committee, but We at t,o great distance
from the or gin Of co-ordinates' to co-operae with
others in that capacity.
said must be raised above the earth. radius ati-
tude:. to e- fourth its surface Nor did mean
Jack" is wrong on 3O4 and Otiose on 3O3, but he
rea ons well on 2so. Delta. Il. B." Limestone &c.
omnes recti STUNT. as usual.
Nv proposition 32l is stated wrong. rectify il
this week. GUERNSEY.
~ PROBLEM NO. 1926.
Delta and Glernsey buy 4s acres of land at s6t
per acre. Of which Guernsey Is to have a Iece con-
be two-ffths better than IL acres of the 36 tha
Delta is to have .in she ret of Dstss being Of th'
A. 8. SIMPSON.
PROBLEM NO. 327.
Innis and Robin set out for the same place in tn
same direction. Innis travels uniformly 10 mile
per day, and after days turns snd goes nack f.,
as Robin has Travelled in these DAYS he then turn
22k days fro the time they first set out. 1t is re
| qured to find the rate at (which Robin uniforml,
PROBLEM NO. 32S.
| -(Being SCI restated and corrected)
| Prove by pure Geometry. that the tangent of tn
sum of two ares "a and az equals sum of their tan
gents sdivided by unity minus the rectsnge of tbes
| tansents. GUERNSEY.
| PROBLEM NO. 329.
H-pothenuse of right angled triangle is IL. ar
radius of inscribed circle 2. Determine the tw
| sides. DELTA.
| PROBLEM NO. 800.
Draw lines from vertices of acute angles of righ
angled triangle to the center of inscribed circle
| What angle do they form at center? DELTA.
| go THEOREM (NO. 331.)
\
right-sngled triangle minus tho hypotenuse
equal to diameter of inscribed circle. DELTA.
PROBLEM NO. 332.
In the center of a field 25 rods square there is a
| eliStical skating park whose major axis equals sid
| Of the square. and it there Is drawn a circ
which cuts off the corners of the field for refr st
| ment saloons. Required the number of person
that could stand at time in the two crescents
witness the sport in the park, allowing each
! of three square feet. making all propsr deductio
| for eztreDsd cornuG of the figures
/ GUERNSEY.