Daily Ohio statesman. [volume] (Columbus, Ohio) 1855-1870, 1867-05-18
Answers to No. 2e from John F. Esrhart. Robin
Tommy, Sammy and Matte.

COLUMBUS OHIO, May 18th, 1867.
Mr.. EDITOR: Your correspondent from Pataska-
Ia gives tumbler full the answer to Problem No.
., W ,ich is Inconsistent for in that case much
Of the operation the overflow Of wine is much less
than of water and only equals it at the end. hence
and his answer is wrong. will wait tor another |
Guernsey's answer to Problem l6 is wrong. for ac-
cording to his answer we would have the kypothe-
of right sng ed triangle. just equal to of
1 will inform Guernsey if you publish this how
solved Robins digit problems.
In No. Is the equation is Of the fourth degree.
There great many artifces by which such equa-
tions can be solved. This is the method for this
one: Transpose all the terms to the first number.
take the square root to- two TERMS then factor the
| remaining terms containing K. and add ! to each
equation Of the second degree. which We suppose
No. II is cubic equation. Take the cube root
there is remainder which will divide the equation.
furnishing one root and giving quadratic.
eraI method for finding the commensurable roots in
higher equations. The equation has only one COM
m mensurable root, and that is 4.
No. %, after substituting, is solved in the same
way. Answer-x equals 2. and y equals3.
ANSWER TO PROBLEM NO. %.
ls by rds. -.s ri ar-r-
- ANSWER TO PROBLEM NO. q.
COLUMBUS, o., May 18th.
Mr. EDIToR:-I will inform Mr.. Guernsey" that |
the 18th and 18th problems can be solved by the
The answer to problem number 26 is SO; to 29-15
apples.
MIR. Guernsey" is 4, which can be worked by the |
rule have given above. That rule will also solve
| all equations of the 4th degree. /
ANSWER TO PROBLEM NO. 90. lHs
Tommy" sends answer to this problem as fol-
lows: i.s.. oaa ..a aca .s-t Iisr.7 NY i
He left apples at the first gate, at the second
at the third. Hs had Is apples. /
Matte sends correct answer, also. -..,s
| A. J. Courtwright wants to kno if we have re-
ceived answer to his problem concerning fencing
field that it shall contain acre for every rail
in the fence. We have received an answer from
Limestone" of D lblin. but have mislaid it. and
unable to lay our lily white hands it after
tedious search. Some must help US to another
answer. -zre --s,s.--
ANSWER TO PROBLEM NO. %.
~ shoemakers paid 2s. Sd. 21d. each 16 tailors
paid Is 3D.. I'D each 90 tin paid Is. Sd. or
I'd. each "a pedlars paid los. 3D., or I'd. each.
We hope to greet many new friends next week
and hope our old ones will continue to furnish as
good ones we give below:
i4-aa PROBLEM NO. 80.
If two:sevenths equal nine, what will nine and
two!ninths equal. A. j. J.CoURrwBIeHT.
| ~,,v.s PROBLEM NO. 81. ,s.7-
g Find the length Of minute,hand whose extreme
point moves 4inches in minutes and % seconds
go PROBLEM NO. 80. sI - ....
Thereare 1gpoints in plane, no three of which
in the same straight line, with the exception Of
nes bs b.
ing the points? ln ROBIN.
.s'ii7 PROBLEM NO. 80.
Twodrovers were driving each flock of sheep Said
ss M e OF ;ysd s Sbs s1d will have
yours and will have as many again as you. Re-
auirsd the number in each E0s. fESys; = Du,,,vor
PROBLEM NO. 81.
Given three pulleys on the axle &C. leo feet,
sslOo feet 2-lo0 feet in circumference. The dia
axle. is 2H feet. Required. the diameters Of the
belt will fit on each set of corresponding pulleys?
-Grf- SAMMY.
ais PROBLEM NO. 35.
CHERRY GROVE, May IL. 1867,
EDITORS STATEsMAN:-I send the follow ng
! " chain" problem. # -
II If twelve barrels of -four worth sixty bushels
Of wheat. and five bushels of wheat worth thirty
i've bushels Of rye and fou bushels of rye are worth
three bushels OF barley, and two bushels of barley
worth sixteen pounds Of butter and nine pounds
OF butter are worth seven pounds of Coffee and three
pounds 6sres Of OS
/ cost? v. q. SEEDS.
PROBLEM NO. Sc.
There is pyramid 90 feet square at the base and
tions parallel with the base, SO that each sect IN
may contain an eq1al number of solid feet. Re-
quired. the height of each section. v. U. SEEDS.
| ,f PROBLEM NO. 81. ..E-r
Find two nup pbers whose Product is equal to the
difference of their squares. and the sum Of their
squares equal to the difference of their cubes.
Il PROBLEM NO. 3S.
Il What number is that which divided BY % leaves
remainder Of la and divided by 10 leaves remain
der of l5 and divided by Is leaves remainder of IL?
PROBLEM NO 3S.
The dimensions Of bushel measure are IsH
incnes N dla meter an inches deep. What shou I'd
be the dimens ions of two measures that will hold
= GEORGE S. INNS.
I PROBLEM NO. 80.
Divide the No. "a into two such parts so that the
larger minus 10 aud IS minus the smaller may have
, ! the same ratio as to3. E. W. SEEDS.
f PROBLEM NO. 40.
AMSTERDAM, May l1th, 1867
| MIR. EDIT0R-A merchant bou ght twenty pieces
cloth % each; sold nine pieces at $40 each and
seven pieces at Sl2 each; at how much piece must
wholef ~ " ' R. A. WI WATSON fi-'
, | .. ,.-.-- PROBLEM NO. Al.
: boy had bcx of marbles which he thought con-
81 but did If he had times I-i3 of the
would have 81 marbles. How many had he?
JNo +. EARHARr, Columbus, U.
PROBLEM NO. AZ.
In the center of square garden there is circular
LIE of the whole garden. How maay rods of fence
t will inclose the garden? MATTE.
: TRANSFERS YEsTERDAY.-The following
, transfers of real estate were left at the Re-
corder's office yesterday:
Erssy Parry to John Walsh, assignment
. of lease for so years and renewable for
ever. This is a lease of lot SO of William
Neil's addition to the city of Columbus.
John S. Gard and wife to Elizabeth Ba-
ker, April 18th, inlot No. 241 in the city OF
. Columbus, for $10,50O.
:. William A. Neil and wife to Lewis Rocco,
|, March 18th, lot 80 of William Neil's second