Daily Ohio statesman. [volume] (Columbus, Ohio) 1855-1870, 1867-11-16
Tb, ourfe- solIs-the knell Of n.rtinr ;,.y.

So viii proceed to problems.
Problem No 1ea.Sammy is kind enough to, find
i out way TO work this problem of mine Tor Innis,
but demand the solution. LA
No. as4-Sammy says "otiose tell us the answer
| and it spfficth us"-the answer is l7964 y ~
No. 2s7-The crust must be baked 1898 inches
thick. ,fg! ~. r aif D
1 No. 27o-This question is a matter of dispute.
Some say cne-fourth of the area is meant. L con-
tend that i bsesne b;% 0a the circle Gust
the higher mathematics to say circle when he
means ares My answer is 81 IS feet. j. d,
| No. 27l-The required angles are As degrees and
No 279.13ss. .e6 miles. is7d- Tfin.
No. e73-lt has sailed e. Al degrees 4s minutes 81
seconds. T..- -.ir-.
| No. 27-I think understand the principle of
this question but haven't time now to work it,
~ 'r4 ~ % "a 0TIosE.
| GENOA. Pickaway county. O.. Nov H. 1867.
Mr.. EDITOR: Once more our Puzzler's Column
| is fping a fine business. Come dear Robin. follow
brother Limsstone's advice and fall into rank.
Brothers, rs... t 10 tr.l .-ls... - -. I-.4
q Say not ev.r on the hight .s. .f 1li
Mid intellectual sncw; 20 ~ i'l0Ei
Come down sometimes to tread the grass
| And roam where waters flow -tl +
Send not so hard problems altogether. but let US
haye few common ones on the list. -
No. 26l-A receives 26 3l-56 pounds of coffee,
would like if one of the brothe would please
explain No 27o. when answered, as it is different
from anything Lever saw. lave time for n more
.tE esr-.-. a en- SoUBRIQUET.
PROBLEM NO. 2S7.
Two boys. wishing to amuse themselves by PLAYING
at snatch-apple took a string feet long. and
tied it to hook in the ceiling of room TX feet
string Nov desire 20 know the distance they
must stand from each other in order that the apnle
when put in motion. may touch each of their mouths
- : : = :" A. s. SIMPSON.
PROBLEM NO. 2S3. '.''"
At 81 20 per bushel what would te the cost OF the
potatoes in box Is feet long y feet in,hes high
top. potatoes being measured rounding. S. K.
PROBLEM (oR THEoREM RATHER) NO. 2S9.
From one of the equal angles Al of an isos ,eles
triangle A c., ca d being the side included be-
twee the equal angles. and A being produced be-
making A n equal one Of the equal sides A or y
B, Prove that the angle A NJ is three times b.
one of the equal angles. SAMMY.
z THEoREM NO. 300. - .lss
n ABC is a right angled triangle, AC is the hypot-
enuse and ALB is the base. the right angle -
Draw BID perpendicular to the hypothenuse and AID
perpendicular to the base: pass circle -tnrous
in f f. Prove 'as ssss 'n aD AB BG Ind AE are IN
condition proportion. ], e, that ALB is mean pro-
portional between AID and BE. and BIC. between
- 80 s.L f.e SAMMY.
i-2 i' PROBLEM NO. POI.
s Molie Matte. Maria and Corl,sta bought bail
of butter inches in diameter for % Sc Mollie
az Goriista 81 cents IL IS agreed that each shall
take her share separately from the surface of
the ball. MOlie taklng her share hrSt. Matte sec
ond. Maria third and CorIista the central part How
ias rJ -ai A. 3. SIMPSON.
PROBLEM NO. 292. a..4u-aA
I want the full solution of this Problem. Com
ing from sea, at the point ID observed two head
distarce between the two headIands was II -os
miles; and found with sextant that the angle ID
distance of headand A added to the distance of
headand B is so miles IT is required from these
data to compute the distance of each head and.
OTI0sE.
--r+s PROBLEM NO. 293. -
To find rom numbers in geometrical progression
whose sum is Is. and the sum of their squares IS
demand the solution OF TINS question. as some
may manage TO guess the answers without any sci
ence. OTIosE.
PROBLEM NO. 294.r ...-,. ...,
Having had occasion to examine some old '.Field
Notes. lately. found the data Of an irregular poly
the data obliterated. Two bearings were wanting,
and one side, The known side, 5s3.s rods. l fcunl
1928. The angle included by the unknown side
and the di9gonal was 50 degrees 40 minutes and ss
ona was the same as the side from which it was
drawI. thai is. was itproduced.
West by South it is required to find the bearings of
the two sides, the length of the unknown side and
what the included area is worth in 7-3o bonds at
per cent premium. gold being l42h at sS4 per acre
-"-'.-. . ~ JEWHILLIKENS.
PROBLEM NO. 295.
Anequation of the 4th degree has minus the radi-
cal 3 and plus the radical minus 3, for ts of its
roots. Who can construct it GUERNSEY.
PROBLEM NO. 296. -
If Limestone eat at our supper the square root of
So plus times the radical dc ysters. aud Del
the so of $50 minues times the radical
n dozen. now many will both eat, and which the
most? - as - GUERNSEY.
= PROBLEM NO. 297.
There is boarded fence Is feet high and stand
10 from it, now how high must a rocket be
thrown that may see it.supposing am feet high?
L he rocket thrown one mile awav.
Yours, mathenatically, ,sss.t
SoUBRIQUET.