Daily Ohio statesman. [volume] (Columbus, Ohio) 1855-1870, 1867-07-08
ITO the garden or green ward.
Close to the door. repair to build again
Within its wonted tree?"

| Thy ctume of praise" ..,-4
In sdditiSn to my Cuban Problem. sent last week.
1se q anotner on marbles GUERNSEY.
| Mr.. kDIToR:-I am well pleased that you have
given us the tine and opportunity to review and
square up the books. Sammy and / have been
have not answered each others problems. All the
rest We hays.4 believe sent for except two
answered this week have ree that Het reyaS aas
unanswered-Nos. "a 81 and So. Viii some of the
them up oncef have been wrong ' time or tWo
Mr.. Editor. in my ans wers. which do regret as
my posi in regard to the courtesy due each 9TH
er, by the eontrib busors to this column. When any
wrong. am obliged to him for it, but cannot saw
TINS tor mere assertions, unaccompanied by any
proof whahteveri .h No one can ever pique me BY
wrong calculation in solving any problem; only
want them to explain how | am wrong. Now. as to
dant enough to seek controversy with you thr ugh
your own paper Therefore you occupy somewhat
no one wishes to molest them nor to be ANNOYED by
them; Only give " ur proof. Mr.. Editor and show
obligations to reu Unees VOW Mii see ee 81 to
take the trsu6e to do this, wou drather you would
conditions O the problem make the above saIe Iae
me9ts m not tina. have any grievances to complain
and kindness from i, and certainly from none more
than YOURSELF Mr. Editor. but to set self right
BY of the contributors to the Puzzer Column.
do not claim that am al right, but, on the
contrary, H. know % l am often mistaken; But when
srwise receive nc benefit Rest assured. Mr.. Edi
instruction or benefit Others shalt very soon quit
being contributor to the Puzzler's Column. We
ought to carry this column on. and feel still more
ana more kindly towards each other. Nothing /
would give pleasure than to meet ali the con-
and discuss with them the merits and de-
merits OF our solutions to the different problems
GEO. 5. INNS.
COLUMBUS, o.. June 20. 1857.
MIR. EDIToR:. am glad you have given a
have lost one or two of the papers, cann"t tell ex-
actly what problems have not been solved But if
Robins; except two, which think can solve this
ems unanswered. But, according to agreement. we
were not to solve each others problems till others
sr / have quite an array of unanswered psoSIems
They are as follows: Nos. and =. No. i6 has had
'C%s attention lis simply case in Di2phanten
ance from hanging point to perpendieular then
xe-y2@ 1872. Let x=a2xb and y=2ab. then sue
o2.l5 Now the only values which will ratiopaiize
his equation are a=4 and b=l. whence x.l7 and
ls Innis has correctly stated.
No. %, my age question" has rot been solved.
Use, solve it? want to know how old am.
No. "a. my "bulley question" has not been solved
No. 6s was solved BY Guernsey. think. correctly.
have forgotten his answer mine is SOC. 8 x yds
he longest perpendicular bey ond the meridian Is
5 distant on meridian between perpendiculars
9S.7IS to lind hypOtenuse drawn to the short per-
endlcuiar Is yds beyor ds meridian. which is equal
No. s7.-I want the answers correct to places
In the number Of June 9th sent the following,
Find three numbers in arithmetical progression
uch that the sum of every two of them may be a
N %. llS and Ils remain for solution,
wish TO say to the contributors of this interest
eler demonstration; and when J am wrong own
Up. l do not claim infal.ibity. / do not say, 81
m SIR oTaeiei Sh,n L oPe my mouth let NO dog
ARK. wish these gentlemen would give my pi OBJ
have examined Delta's solution of 11s carefully.
nd think can show him that he is wrong. His
emi. phere, but it is cone inches in depth This
low if he will diminish the diameter his ball
title, he can depress it more than the hemisphere,
ear the center will displacs more water than two
r hree inces near the surface. Do you see, Delta?
hen make the Diameter of your ball little less.
dOq't see now Delta and Guernsey get SO feet
ha s s fOG NO. o. S can az On only get Ss feet
ne sides Of triangle formed Call ss the base If
perpendicu ar be drawn from the vertical angle of
quares Of the sides is equal to the difference of the
qrsres of the segments of base Let x=one seq
Then we We the hypoteouse and base of one right
'ugisd trisng,e m s and the hypotenuse and base Of
perpendicular.
ng else except 50 will make the perpendicular the
How does Delta get os feet for answer to No ,o4?
r work Hronea Delta also @ differs % from s. K. and
myself on No. liz. Are we both wrong? Will
Delta or Guernsey give the rule for solving lis?
It No. 72. Let x2 25x2 and 4sx2 represent the num-
,ers respectiyels Then from the conditions Xxx
qnaEs lG!as, 81. Let xz-7xaa2Sa. then x=l
di1id.d in 81 bv and 90. 5 haye to
-,2=a square -. and 4s divided by I--2a2 plus al
! : divided by l--aSa square (5) or performing
he subtraction and rejecting the square denomins-
md Tax ga square C. These two expressions are
quares when q Is equal to plus or minus l. Put
b2-l4b 40 square 10. making 5b2-iOO x25=l
KS, whence b=l10-I0m di-
,ided BY 6-ma qo,, substituting this value Of in
l0--1Om divided by 5--m2l n4s= square Qo). Per-
orm the subtraction and multiply by square de-
66m snd we oTs muss ma Take ss ,bo
35)2=45L4-- i4om3 ,<39Om2 -7oOm < l2s5
l3. whence 7Om2=l4OOm aud M 7O.s7 Now in Of
lso positive. m greater than X and less than or
,s ss, t,ki shssa .ss4sson div dsdi5S
'ided by s5s75s766 and n r7e-37=235ss565673 di-
,ided by 32s47ll2452. this yaue of m being greater
renee b=lO-10m divided by y5-m2=3Ol0s36sOO794
3szloso divided BY 4s3Slse373530ss73s591 81
divided by
divided by aoi77S4a7i5i9
25x2=25 times tAis
Robin can you send Ok to me? Worked two days.
NoTE.-In the above x signifies plus.
A HUNKY FOURTH OF July PROCESSION.
There was procession on the Fourth noti