Daily Ohio statesman. [volume] (Columbus, Ohio) 1855-1870, 1867-11-09
Co111Nsx11LE. ONO. Nov. 4. 1867.


Mr.. EDIToR:-Your paper is again before me and
also the back numbers; made blupder in No.
242. It is an easy problem and knew how to solve
idea in aas In No. oanno. divide the equation
by plus l. therefore Ioonclude that minus is not
make out little % more stone in the steps to Guern
sey's church than s. x. Let GUERNSEY tell US who
Or :, that amount Of land. and fsnce2
7sS Now afslais Broher Beta think that
little .hin BY the conditions the two men trav
zebra There wa was nothing said about difference in
their rates ard made none. In our rcommon Arith-
metics we fnd many such questions as tins II thrae
ixmencut in dsyY Nothing is said about the
rat. Each mans NG Ehss wSS SSG1
liar In regard to NO. 81 upon hch the fate Of the
that from the conditions given. there was motion
at all. But will not waste time on this point: ex-
viii Z. b. tell us his method with No; 94t2
In all these difficult problems it would be well 20
point out the method. that learners may proht
Limestone is wrong on $50 think.
No. 253 Il think Guernsey could put few more
balls in that box. 1t looks to me as if could get
1872 in by partially filling the interstices with
of balls. e.. putting the short courses in
Using the ,sitive value of equal radical X. get
equal into square root Of g equal square root of
Tbs trouble think. brother Guernsey. lies in the
first condition of the question. Ii minus equal
Wan %n's nons
will give nothing. in tea of q, one &c. as you had
In No 257 we want to fud .he tan. of 81 deg.
which is ea al to s1.cos Then to & hnd dsD esc we
easily found.
ES ass-A9sxer: Is inches tTss square - root cot
abscissas and the difference of the ordinates)
higher method of equations.
whole is his after toll 4 of this is A. 2 times this
No. a62 Answer: 2.ex. The arc is liz of 800
degrees Now tho cord Of any arc is twice the sin.
No. Ha.: aesNWidtha1sx. sse via feet.
No. 2s5-It will take 1.s4sxoz., if made no mis-
take. SAMMY.
..,....,...- PROBLEM NO. 275.. ..- .,. 20.
The area of n rectangular field is TX acres, and
the length IF the gona so rolls Requ red the cost
to cost. for making, hauling, and building 3 of q
~ '- ~ A. s. SIMPSON.
s.........- PROBLEM NO. 276. ..,--- .
SUPPOSE the internal diameter Of shell t., to be be
idityi A. s. SIMPSON.
PROBLEM NO. 277. & - /
If1gallons of MADEIRA wine cost much as 9 GAL
Ions of port, and Ions Of port much as u GAL
these taking of each s. w5ss IS each
~ PROBLEM NO. 27S. f..~
If S. H. will give me rule to solve the following
problem by, or give solution of it, he will much
suppose there be round column of equal size
throuahout, being one foot in diameter AID 90 feet
hish, and bean vine entwines itsef around it Just
IL times at equal distances, in passing from the loot
A. 5. SIMPSON.
PROBLEM NO. 279.
In Fort Rono near Washington. there are cannon
balls of two sizes Su pose box will hold lS of the
asd @ Of the second viii fiji thirteen fft.-fou tbs
ts 50 es the box. how many of each vii, it require
PROBLEM NO. $50.
Suppose Deta's garden is to-d,y a rec'ansle
whose diagonal is X, base v, and perpe ndlcniar y
plus Required these lines. the radips "f the in
scribed circle being IS yards? GUERNSEY.
PROBLEM NO. 2S1.
Being requested to measure the heighth of tree
same plain with the bottom of the tree, / took the
angle of elevation b ID equal to 81 deg. 80 nip.
line from the tree and at took the angle of elevi-
ton a equals 2s deg. 80 min kesuI5edi the
PROBLEM NO. 2S2.
If the perimeter of right snsed trisnzle be 7so
angle on the hrpothenuse be l44 feet; what are
the lengths of the side? u. s. INNS.
PROBLEM NO. ZS0.
What principal must be loaned January 1st, at s
per cent to be repaid in Z equal installments of
al50. PAYABLE on the Goth day of the succeeding
months
PROBLEM NO. 2S4.
To determine right angled triangle. having
given the side of the inscribed square, equal to
feet and the radius of the inscribed circle equal to
four feet.
Problem: To determine triangle and the radius
of the inscribed CIRCLE having given the lengths of
three lines dra from the three angles to the CEN
SAMMY"
PROBLEM NO. 2S5.
Bought stock at 20 per cent. discount and sol it
at 81 per cent premium. Invested the proceeds in
butter expenses of getting butter to market are
nineteen dollars; sold the butter at loss of per
cent. on the cost cash on hand. 81 500. Wat was
my original capital? OTIosE.
PROBLEM NO. 2S6.
What is the weight of q hollow spherical iron
shell inches in diameter. the thickness of the met
al being one inch and cubic inch Of iron weighing
129-5c0 of pound. ROBIN.
SOUTH ENDERs, ATTENTION THE peo-