Document: NRC Regulatory Guide
Document ID: 2704425a-c58a-45c4-93ab-8761721c3e7a
Document Type: regulatory_guide
Title: Evaluation of Reactor Pressure Vessels with Charpy Upper-Shelf Energy Less Than 50 Ft-Lb
Source: NRC Regulatory Guide Division 1
Source URL: https://www.nrc.gov/docs/ML0037/ML003740038.pdf
Revision Date: 2023-06
Chapter: 
Section ID: RG-1.161
CFR Part: 
CFR Title: 

Content:
(constant, for each analysis) Inner wall temperature, Tk .(R - = 550'F; TsJR = R) = 150F Base Metal Thermo-Elastic Properties: Modulus of elasticity, E = 27E3 ksi; Poisson's ratio, v = 0.3 Fluid-film heat transfer coefficient,= 1000 BTUihr-f -PF Thermal diffusivity = 0.98 in!/minute; (Ea)/(I - v) = 0.305 Cladding Thermo-Elastic Properties: Thermal expansion coefficient, a = 9.1E-61F; Poisson's ratio, v = 0.3 Modulus of elasticity, E = 27E3 ksi; Thermal conductivity- 10 BTU/hr-ft-OF Sftr -free temperature of cladding = 550-F; Initial operating temp. = 550WF The VISA-i1 code was used to determine temperature and thermal stress history for constant CR transients of 1 00F/hr, 15( 0F/hr, 20(0Fir, 30(0F/hr, 400-F/hr, 500rFihr, and 600¶bhr. The corresponding peak thermal stress intensity factors, Y41, as a function ofcrack depth to vessel thickness ratio, aWt,, for 6-to. i aspect ratio semi-elliptical flaws, were computed using the VISA-11 code. These are shown in Figure A-6 and are presented here in polynomial expressions using least-square fits as: For CR - 100"Fhr with 0.05 <(aft') < 0.5: Ka - [27.284 - 5.838 (aft') - 0.3548 (aft')2 - 8.3858 (aht'Y] ksifin. For CR - 150°F/hr, with 0.05 g (aft') s 0.5: K,4 = [32.003 + 40.012 (aft') - 138.2 (a/t'r - 113.98 (aht')r] ksif"in For CR = 200F/hr with 0.05 < (aft') g 0.5: KI = [36.362 + 82.011 (aft') - 265.01 (aft')r + 226.9 (aft')2] ksi/rin. For CR - 300F7hr with 0.05 : (aft') 10.5: K,4 = [43.667 + 150.77 (aft') - 474.9 (aft')2 + 415.01 (a/t')2] ksijrin. For CR - 400°F/hr with 0.05 r. (aft') < 0.5: Kft = [49.254 + 201.12 (aft') - 632.1 (a/t'r + 557.87 (a/t')3] ksii"in. For CR - 500OF/hr with 0.05 < (aft') < 0.5: 4 = [53.552 + 237.64 (aft') - 749.6 (aA')2 + 666.62 (aft') 3] ksarin For CR - 600F•hr with 0.05 g (at') < 0.5: K,, = [56.927 + 264.21 (a/t') - 838.6 (aft')2 + 750.88 (aft')2] ksiv"in. A-3 These results were also used in developing the unified Equation 13 for K, where the constant CR and the nomalizhd crack depth,