datavorous/entrance-exam-dataset huggingface dataset:
A disc has mass M and radius R. How much tangential force should be applied to the rim of the disc so as to rotate the disc with angular velocity Ï in time t?

Options:
A MRω4t
B MRω2t
C MRωt
D MRωt

The correct answer is:
MRω2t

Solution:
Ï=IÎ±
FÃR= M R 2 2 Ã Ï t
F= MR 2 Ã Ï t

Topic: Physics, Rotational Motion, NEET
A disc initially at rest, is rotated about its axis with uniform angular acceleration. In the first 2 s, it rotates an angle Î¸. In the next 2 s, the disc rotates through an angle

Options:
A θ
B 2θ
C 3θ
D 4θ

The correct answer is:
3θ

Solution:
Because of uniform angular acceleration. we can use the equation of motion in rotation
Î¸=12 Î± 22 Ï0=0

Î¸=2Î±

And
Î¸+Î¸'=12Î± 2+22 âµ Ï0=0

Î¸+Î¸'=8Î±

Hence, Î¸'=3Î¸

Topic: Physics, Laws of Motion, NEET
A disc is performing pure rolling on a smooth stationary surface with constant angular velocity as shown in the figure. At any instant, for the lowermost point of the disc.

Options:
A Velocity is v, acceleration is zero
B Velocity is zero, acceleration is zero
C Velocty is v, acceleration is v2R
D Velocity is zero, acceleration is nonzero

The correct answer is:
Velocity is zero, acceleration is nonzero

Solution:
From figure
Vnetfor lowest point=v-RÏ=v-v=0
and Acceleration=v2R+ O=v2R
(Since linear speed is constant)
Hence (D)

Topic: Physics, Rotational Motion, NEET
A disc is rolling (without slipping) on a horizontal surface. C is its centre and Q and P are two points equidistant from C . Let v P ,  v Q and v C be the magnitude of velocities of points P, Q and C respectively, then

Options:
A v Q > v C > v P
B v Q < v C < v P
C v Q = v P , v C = 1 2 v P
D v Q < v C > v P

The correct answer is:
v Q > v C > v P

Solution:
In case of pure rolling bottommost point is the instantaneous centre of zero velocity.
Velocity of any point on the disc, v=r ω, where r is the distance of point from O.
r Q > r C > r P
∴   v Q > v C > v P

Topic: Physics, Rotational Motion, NEET
A disc is rotated about its axis with a certain angular velocity and lowered gently on a rough inclined plane as shown in the figure then

Options:
A It will rotate at the position where it was placed and then will move downwards
B It will go downwards just after it is lowered
C It will go downwards first and then climb up
D It will climb upwards and then move downwards

The correct answer is:
It will rotate at the position where it was placed and then will move downwards

Solution:
Here kinetic friction force will balance the force of gravity. So it will rotate at its initial position and will not move up or down. As its angular velocity becomes zero (friction also becomes zero), it will move downwards.

Topic: Physics, Rotational Motion, NEET
A disc is rotating with angular speed $\omega$. If a child sits on it, what is conserved?

Options:
A Linear momentum
B Angular momentum
C Kinetic energy
D Potential energy

The correct answer is:
Angular momentum

Solution:
$\tau=\frac{d L}{d t}$, so $=0 \Rightarrow L=\frac{d L}{d l}$ constant
Law of conservation of angular momentum.

Topic: Physics, Rotational Motion, NEET, NEET 2002
A disc of mass 4 kg and of radius 1 m rolls on a horizontal surface without slipping such that the velocity of its centre of mass is 10 cm sec-1. Its rotational kinetic energy is

Options:
A 0.005Â J
B 0.02Â J
C 0.03Â J
D 0.01 J

The correct answer is:
0.01 J

Solution:
KErotational=12IÏ2
KErotational=12124120.12
KErotational=0.01 J

Topic: Physics, Rotational Motion, NEET
A disc of mass 10 g is kept floating horizontally in the air by firing bullets, each of mass 5 g, with the same velocity at the same rate of 10 bullets per second. The bullets rebound with the same speed in positive direction. The velocity of each bullet at the time of impact is (Take g=9.8 m s-2)

Options:
A 196 cm s-1
B 98 cm s-1
C 49 cm s-1
D 392 cm s-1

The correct answer is:
98 cm s-1

Solution:
2mnv=Mg
v=Mg2mn
âu =10Ã9802Ã5Ã10cm s-1
=9800100cm s-1
=98 cm s-1

Topic: Physics, Laws of Motion, NEET
A disc of mass M and radius R has a spring of constant k attached to its centre, the other end of the spring being fixed to a vertical wall. If the disk rolls without slipping on a level floor, how far to the right does the centre of mass move, if initially the spring was unstretched and the angular speed of the disc was Ï 0

Options:
A Rω2M/3k
B RÏ3M/2k
C RωM/k
D RωM/2k

The correct answer is:
Rω3M/2k

Solution:
Due to pure rolling E t = 0 = E t = 1
I = MR 2 2
V cm = ω R
E t = 0 = 1 2 MV cm 2 + 1 2 I cm ω 2
1 2 M ω 2 R 2 + 1 2 MR 2 2 × ω 2
1 2 × 3 2 M ω 2 R 2
E t = T = 1 2 kx 2
1 2 × 3 2 M ω 2 R 2 = 1 2 kx 2
x = ω R 3 M 2 k

Topic: Physics, Rotational Motion, NEET
A disc of mass m and radius R, is placed on a smooth fixed surface. Point A is the geometrical centre of the disc while point B is the centre of mass of the disc. The moment of inertia of the disc about an axis through its centre of mass and perpendicular to the plane of the figure is I. A constant force F is applied to the top of the disc. The acceleration of the centre A of the disc at the instant B is below A (on the same vertical line) will be :

Options:
A Fm
B Fm+3FR24I
C Fm+FR24I
D Fm+3FR2I

The correct answer is:
Fm+3FR24I

Solution:
a ¯ A/g = a ¯ A/cm + a ¯ cm/g
=R2.α+a=R2F×3R2I+Fm=3FR24I+Fm

Topic: Physics, Rotational Motion, NEET
A disc of radius 2 m and mass 100 kg rolls on a horizontal floor. Its centre of mass has speed of 20 cm s-1. How much work is needed to stop it?

Options:
A 3Â J
B 30 kJ
C 2Â J
D 1Â J

The correct answer is:
3 J

Solution:
Energy of the cylinder =12mv2+12Iω2
=12mv2+12mr22v2r2
=34 mv2
=34×100×20×10-22
=3 J

Topic: Physics, Rotational Motion, NEET, NEET 2019 (All India)
A disc of radius R and mass M is pivoted at the rim and is set for small oscillations. If simple pendulum has to have the same period as that of the disc, the length of the simple pendulum should be

Options:
A 54R
B 23R
C 34R
D 32R

The correct answer is:
32R

Solution:
Ï=-mgRsinâ¡Î¸=-mgRÎ¸ âµsinâ¡Î¸âÎ¸
IÎ± =12mR2+mR2Î±=32mR2Î±
But Ï= IÎ±
32mR2Î±=-mgRÎ¸
Î±=-2g3RÎ¸=Ï2Î¸
Time period T=2Ï3R2g
For simple pendulum, T=2Ïlg
l=3R2

Topic: Physics, Oscillations, NEET
A disc of radius R and thickness R6 has a moment of inertia I about an axis passing through its centre and perpendicular to its plane. The disc is melted and recast into a solid sphere. The moment of inertia of a sphere about its diameter is

Options:
A I5
B I6
C I32
D I64

The correct answer is:
I5

Solution:
Volume of disc is A.d =Ï.R2ÃR6=R3ÃÏ6
Moment of inertia of disc is I=12MR2
When the disk is remolded in solid sphere of volume V having radius r, then
ÏR36=43ÃÏr3âR36Ã34=r3
â´r3=R38âr=R2
Moment of inertia of sphere is given by 25 M.r2=25ÃM.R24=MR210=MR22Ã15=I5

Topic: Physics, Rotational Motion, NEET
A disc of radius R is rotating with an angular speed ωoabout a horizontal axis. It is placed on a horizontal table. The coefficient of kinetic friction is µk.What was the velocity of its centre of mass before being brought in contact with the table.

Options:
A μkωoR
B μkRωo
C Zero
D μkRωo2

The correct answer is:
Zero

Solution:
Correct Option is : (C)
Zero

Topic: Chemistry, Rotational Motion, NEET
A disc of radius R is rotating with an angular speed ωoabout a horizontal axis. It is placed on a horizontal table. The coefficient of kinetic friction is µk.Calculate the time taken for the rolling to begin.

Options:
A $\frac{2R{{\omega }_{o}}}{{{\mu }_{k}}\left( 1+\frac{m{{R}^{2}}}{I} \right)}$
B $-\frac{R{{\omega }_{o}}}{{{\mu }_{k}}\left( 1+\frac{m{{R}^{2}}}{I} \right)}$
C $\frac{R{{\omega }_{o}}}{{{\mu }_{k}}\left( 1-\frac{m{{R}^{2}}}{I} \right)}$
D $\frac{R{{\omega }_{o}}}{{{\mu }_{k}}\left( 1+\frac{m{{R}^{2}}}{I} \right)}$

The correct answer is:
$\frac{R{{\omega }_{o}}}{{{\mu }_{k}}\left( 1+\frac{m{{R}^{2}}}{I} \right)}$

Solution:
Correct Option is : (D)
$\frac{R{{\omega }_{o}}}{{{\mu }_{k}}\left( 1+\frac{m{{R}^{2}}}{I} \right)}$

Topic: Chemistry, Rotational Motion, NEET
A disc of the moment of inertia I1 is rotating in a horizontal plane about an axis passing through a centre and perpendicular to its plane with constant angular speed Ï1 Another disc of the moment of inertia I2 having zero angular speed is placed coaxially on a rotating disc. Now both the disc are rotating with the constant angular speed Ï2. The energy lost by the initial rotating disc is

Options:
A 12I1+I2I1I2ω12
B 12I1I2I1-i2ω12
C 12I1-I2I1I2ω12
D 12I1I2I1+I2ω12

The correct answer is:
12I1I2I1+I2ω12

Solution:
I1Ï1=I1+I2Ï2
Ï2Ï1=I1I1+I2
E1-E2
=12I1Ï12-12(I1+I2)Ï22
=12Ï12I1-I1+I2Ï22Ï12
=12Ï12I1-I1+I2I12I1+I22
=12Ï12I12+I1I2-I12I1+I2=12I1I2I1+I2Ï12

Topic: Physics, Rotational Motion, NEET
A disease caused by a viroid is:

Options:
A Potato blight
B Bunchy top of papaya
C Leaf curl of papaya
D Potato spindle tuber

The correct answer is:
Potato spindle tuber

Solution:
Viroids are small, circular RNA molecules that do not encode any protein and that are infectious as naked RNA molecules. Viroids are often transmitted through vegetative propagation of plants, but can also be transmitted during agricultural or horticultural practices in which contaminated instruments are used. It is known to cause potato spindle tuber disease.

Topic: Biology, Biological Classification, NEET
A disease caused by an autosomal primary non-disjunction is

Options:
A Down's syndrome
B Klinefelter's syndrome
C Turner's syndrome
D Sickle cell anemia

The correct answer is:
Down's syndrome

Solution:
Non-disjunction is the failure of homologous chromosomes to disjoin or separate and move away to opposite poles. Non-disjunction of the 21st chromosome during oogenesis is the cause of Down's syndrome. It occurs due to the presence of an additional copy of chromosome no. 21 (trisomy of 21st chromosome) is humans.

Topic: Biology, Principles of Inheritance and Variation, NEET, NEET 2017
A diseased man marries a normal woman. They get three daughter and five sons. All the daughter were diseased and sons were normal. The gene of this disease is:

Options:
A sex-linked dominant
B sex-linked recessive
C sex-limited character
D autosomal dominant

The correct answer is:
sex-linked dominant

Solution:
Father gives his X-chromosome to the daughter while Y-chromosome to the sons. In the case, only daughter and none of the sons are affected, the trait is X-linked. Since, daughters get the second copy of $\mathrm{X}$-chromosomes from the mother who is normal and hence does not carry the affected allele of the trait. The trait is expressed in daughters under heterozygous condition, hence it is a X-linked dominant trait

Topic: Biology, Principles of Inheritance and Variation, NEET, NEET 2002
A diseased man marries a normal woman. They have three daughters and five sons. All the daughters were diseased and sons were normal. The gene of this disease is

Options:
A Sex-linked dominant
B Sex-linked recessive
C Autosomal recessive
D Autosomal dominant

The correct answer is:
Sex-linked dominant

Solution:
Sex-linked disorders follow criss-cross inheritance pattern which an affected father passes it on to their daughters. The daughters receive one of their X chromosomes from their fathers.

Topic: Biology, Principles of Inheritance and Variation, NEET
A disk and a sphere of same radius but different masses roll off on two inclined planes of the same altitude and length. Which one of the two objects gets to the bottom of the plane first?

Options:
A Disk
B Sphere
C Both reach at the same time
D Depends on their masses

The correct answer is:
Sphere

Solution:
Acceleration of the object on rough inclined plane is a= gsinθ 1+ I mR 2 = gsinθ 1+ K 2 R 2
For sphere a 1 = 5gsinθ 7               ( K 2 R 2 = 2 5 )
For disc a 2 = 2gsinθ 3          ( K 2 R 2 = 1 2 )
a1>a2 , so sphere will reach bottom first.

Topic: Physics, Rotational Motion, NEET, NEET 2016 (Phase 1)
A Diwali rocket is ejecting 0.05 kg of gases per second at a velocity of 400 m s-1. The accelerating force on the rocket is

Options:
A 20 dyne
B 20Â N
C 22 dyne
D 1000Â N

The correct answer is:
20 N

Solution:
Accelerating force on rocket due to ejecting gases
F=udmdt
F=400×0.05
F=20 N

Topic: Physics, Center of Mass Momentum and Collision, NEET
A DNA fragment was cleaved by using REN and the restriction fragments (a, b, and c) produced as a result of digestion are shown below. Select the option that represents the correct gel electrophoresis separation of these fragments.

Options:
A
B
C
D

The correct answer is:

Solution:
In Gel Electrophoresis Nucleic acid molecules are separated by applying an electric field to move the negatively charged molecules through a matrix of agarose or other substances. Shorter molecules move faster and migrate farther than longer ones because shorter molecules migrate more easily through the pores of the gel. This phenomenon is called sieving.
hence c been the longest fragment travel short distance.
a and b are short fragment and nearly equal in size ove farther down.

Topic: Biology, Biotechnology - Principles and Processes, NEET
A DNA sample is 13.6 nm long. It has 10% cytosine molecules calculate the number of weak hydrogen bonds in the given sample.

Options:
A 88
B 112
C 80
D 120

The correct answer is:
88

Solution:
Length of DNA sample =13.6 nm. Length of 1 turn=3.4 nm . Thus No. of turns in the sample =13.6nm3.4nm=4
No. of nucleotides in 1 turn = 20 . Thus, No. of nucleotides in the given sample = 20Ã4=80
Since cytosine is 10%, By Chargaff's rule, G = C = 10% while A = T = 40%
No. of Guanine molecules =11x 8=8 . No. of Cytosine = 8
No. of Adenine =40100Ã 80=32 . No. of Thymine = 32
Thus, no. of horizontal steps with GC linkage = 8 and No. of horizontal steps with AT linkage = 32
GC are linked by 3 weak hydrogen bonds. Thus no. of weak hydrogen bonds due to GC linkage = 8Ã 3 =24
AT are linked by 2 weak hydrogen bonds. Thus no. of weak hydrogen bonds due to AT linkage =32Ã2=64
Total no. of weak hydrogen bonds in the given sample = 24 + 64 = 88

Topic: Biology, Molecular Basis of Inheritance, NEET
A DNA sequence in a genome where replication is initiated is called ___

Options:
A Origin of replication
B Bioreactors
C Downstream processing
D None of the above

The correct answer is:
Origin of replication

Solution:
A DNA sequence in a genome where replication is initiated is called origin of replication

Topic: Biology, Biotechnology - Principles and Processes, NEET
A DNA sequence undergoes three subsequent point mutations which result in subsequent changes in the transcription of mRNA as shown below:

Original mRNA: AUG CAU CUC ACG GAU UAG

Point mutation 1: AUG CAU CUU ACG GAU UAG

Point mutation 2: AUG CAU GCU UAC GGU AUA

Point mutation 3: AUG CAU GCU UAA GGU AUA

Select the correct sequence of point mutations that occurred in DNA.

Options:
A Missense mutation- Frame shift mutation- Nonsense mutation
B Silent mutation- Nonsense mutation- Frame shift mutation
C Silent mutation- Frame shift mutation- Nonsense mutation
D Missense mutation- Frame shift mutation- Silent mutation

The correct answer is:
Silent mutation- Frame shift mutation- Nonsense mutation

Solution:
Mutation is any change in the sequence of the DNA and if such a change occurs in single nucleotide, it is called point mutation. It can be due to addition, deletion or substitution.
The given sequence of mRNA is AUG CAU CUC ACG GAU UAG .
In the first point mutation there is change in single nucleotide in third codon. In CUC, last C is replaced by U. This mutation does not have much effect due to wobble nature of codons described by Wobble hypothesis. Such mutation is referred to as silent mutation.
In the second point mutation, there is addition of G base between second and third codon. This addition caused change in the reading frame of the codons. CUU has been replaced with GCU, ACG by UAC, GAU by GGU, UAG by AUA causing change in the amino acids translation and sequence. Such mutation where the reading frame shifts or changes is called frame shift mutation.
Third point mutation, the 4th codon UAC, C is replaced by A making the triplet UAA which is a stop codon. Because of the presence of stop codon, the translation abruptly stops leading to formation of a different type of protein. Such mutation where stop codon is formed due to change in base pair is called non-sense mutation.

Topic: Biology, Molecular Basis of Inheritance, NEET
A doctor has ordered a test for serum bilirubin. The patient goes to a pathologist who collects his blood. The pathologist should collect this blood in a test tube containing

Options:
A Anti-coagulant sodium citrate
B Anti-coagulant double oxalate
C Anti-coagulant fluorides
D No anti-coagulant

The correct answer is:
No anti-coagulant

Solution:
For this test, serum is required. Serum is the fluid formed after blood clots. Hence, we have to allow the blood to clot. Thus, no anti-coagulant should be added.

Topic: Biology, Body Fluids and Circulation, NEET
A door 1.6 m wide requires a minimum force of 1 N to be applied at the free end to open or close it. The minimum force that is required at a point 0.4 m away from the hinges for opening or closing the door is

Options:
A 1.2 N
B 2.4 N
C 3.6 N
D 4 N

The correct answer is:
4 N

Solution:
It is given in the question, torque Ï=1.6Ã1=1.6 N m
So, when d=0.4 m,
F=Ïd=1.60.4=4 N.

Topic: Physics, Rotational Motion, NEET
A dorsal and hollow central nervous system is found in

Options:
A Bufo
B Loligo
C Dentalium
D Limulus

The correct answer is:
Bufo

Solution:
In chordates, four common features appear at some point during development: a notochord, a dorsal hollow nerve cord, pharyngeal slits, and a post-anal tail.

Topic: Biology, Animal Kingdom, NEET
A double convex lens has focal length $25 \mathrm{~cm}$. The radius of curvature of one of the surfaces is doubled of the other. Find the radii, if the refractive index of the material of the lens is 1.5.

Options:
A $100 \mathrm{~cm}, 50 \mathrm{~cm}$
B $25 \mathrm{~cm}, 50 \mathrm{~cm}$
C $18.75 \mathrm{~cm}, 37.5 \mathrm{~cm}$
D $50 \mathrm{~cm}, 100 \mathrm{~cm}$

The correct answer is:
$18.75 \mathrm{~cm}, 37.5 \mathrm{~cm}$

Solution:
\(\begin{aligned} & \frac{1}{\mathrm{f}}=(\mu-1)\left[\frac{1}{\mathrm{R}_1}-\frac{1}{\mathrm{R}_2}\right] \\ & \frac{1}{25}=0.5\left[\frac{1}{\mathrm{R}}-\left(\frac{1}{2 R}\right)\right] \\ & \frac{1}{25}=\frac{0.5}{10}\left[\frac{3}{\mathrm{R}}\right] \\ & \mathrm{R}=\frac{75}{4}=18.75 \\ & \mathrm{R}_1=18.75 \mathrm{~cm}, \mathrm{R}_2=37.5 \mathrm{~cm}\end{aligned}\)

Topic: Physics, Ray Optics, NEET, NEET 2019 (Odisha)
A double convex thin lens made of the refractive index 1.6 has radii of curvature 15 cm each. The focal length of this lens when immersed in a fluid of refractive index 1.63, is

Options:
A 25 cm

B 125 cm

C 250 cm

D -407.5 cm

The correct answer is:
-407.5 cm

Solution:
Focal length of lens in given by
1fw= Î¼g-11R1-1R2
=1.61.63-1115+115
=-0.03Ã21.63Ã15=.061.63Ã15
so, fw= -8152
=-407.5 cm

Topic: Physics, Ray Optics, NEET
A double-slit apparatus is immersed in a liquid of refractive index 1.33. It has slit separation of 1 mm and distance between the plane of slits and screen is 1.3 m. The slits are illuminated by a parallel beam of light whose wavelength in air is 6300 Ã. Calculate the fringe width.

Options:
A 0.95 mm
B 0.36 mm
C 0.63 mm
D 0.56 mm

The correct answer is:
0.63 mm

Solution:
Given μ=1.33, d=1 mm, D=1.33 m, λ=6300 Å
The wavelength of light in the given liquid
λ′=λμ=63001.33Å =4737 Å=4737×10-10 m
Fringe width, w=λ′Dd
w=4737×10-10 m1.33 m1×10-3 m=6.3×10-4 m

Topic: Physics, Wave Optics, NEET
A double-slit experiment is immersed in a liquid of refractive index 1.33. The separation between the slits is 1 mm and the distance between the slit and screen is 1.33 m. If slits are illuminated by a parallel beam of light whose wavelength is 6300 Aâ, then fringe width will be

Options:
A 6.3 mm
B 63Â mm
C 0.63Â mm
D None of these

The correct answer is:
0.63 mm

Solution:
Given, Î»=6300 â«=6300Ã10-10 m
=6.3Ã10-7 m
When equipment is immersed in a liquid of refractive index 1.33, then wavelength Î» is changed.
â´ Î»â²=Î»Î¼=6.3Ã10-71.33
â´ Fringe width, Î²=DÎ»â²d
=1.33Ã6.3Ã10-71Ã10-3Ã1.33
=6.3Ã10-4
=0.63Ã10-3 m
=0.63 mm

Topic: Physics, Wave Optics, NEET
A drop of each of the following is placed separately on four slides. Which of them will not coagulate?

Options:
A Blood serum
B Blood sample from the thoracic duct of lymphatic system
C Whole blood from pulmonary vein
D Blood plasma

The correct answer is:
Blood serum

Solution:
Blood serum is liquid minus clotting elements. It is of pale yellow colour. It does not have fibrinogen and other clotting materials. Thus, it does not take part in blood clotting.

Topic: Biology, Body Fluids and Circulation, NEET
A drop of mercury of radius 2 mm is split into 8 identical droplets. Find the increase in surface energy. (Surface tension of mercury is 0.465 J m-2 )

Options:
A 23.4 μJ
B 18.5 μJ
C 26.8 μJ
D 16.8 μJ

The correct answer is:
23.4 μJ

Solution:
Increase in surface energy or work done in splitting a big drop =4π R 2 T( n 1/3 −1) ⇒W=4π×(2×10−3)2×0.465(81/3−1)=23.4 μJ

Topic: Physics, Mechanical Properties of Fluids, NEET
A droplet infection is

Options:
A Tetanus
B Pneumonia
C Syphilis
D Typhoid

The correct answer is:
Pneumonia

Solution:
Pneumonia is a condition that affects respiratory passages. It is an inflammation of air sacs of lungs. This condition produces dry cough, fever, chest pain and difficulty in breathing. Infections that can easily spread by sneeze or cough are regarded as droplet infections. Pneumonia is one such example.

Topic: Biology, Human Health and Diseases, NEET
A drum of radius $R$ and mass $M$ rolls down without slipping along an inclined plane of angle $\theta$. The frictional force:

Options:
A dissipates energy as heat
B decreases the rotational motion'
C decreases the rotational and translational motion
D converts translational energy to rotational energy

The correct answer is:
converts translational energy to rotational energy

Solution:
Required frictional force converts translational energy into rotational energy.

Topic: Physics, Rotational Motion, NEET, NEET 2005
A drum of radius R and mass M rolls down without slipping along an inclined plane of angle Î¸. The frictional force

Options:
A Converts translational energy to rotational energy
B Dissipates energy as heat
C Decreases the rotational motion
D Decreases the rotational and translational motion

The correct answer is:
Converts translational energy to rotational energy

Solution:
When a body rolls down without slipping along an inclined plane of inclination θ, it rotates about a horizontal axis through its centre of mass and also its centre of mass moves. Therefore, rolling motion may be regarded as a rotational motion about an axis through its centre of mass plus a translational motion of the centre of mass. As it rolls down, it suffers loss in gravitational potential energy provided translational energy due to frictional force is converted into rotational energy.

Topic: Physics, Rotational Motion, NEET
A drunkard walking in a narrow lane takes 5 steps forward and 3 steps backward, followed again by 5 steps forward and 3 steps backward, and so on. Each step is 1 m long and requires 1 s.If there is a pit 13m away from the start, find how much time will it take for the drunkard to fall in it.

Options:
A 48s
B 49s
C 37s
D 38s

The correct answer is:
49s

Solution:
Correct Option is : (B)
49s

Topic: Chemistry, Motion In One Dimension, NEET
A drupe develope in

Options:
A wheat
B pea
C tomato
D mango

The correct answer is:
mango

Solution:
In mango, coconut, plum, etc, the fruit is known as drupe (stony fruit). They develop from monocarpellary, superior ovaries and are one seeded. In mango, the pericarp is well differentiated into an outer thin epicarp, a middle fleshy edible mesocarp and an inner stony hard endocarp.

Topic: Biology, Sexual Reproduction in Flowering Plants, NEET, NEET 2011 (Screening)
A drupe develops in:

Options:
A Mangifera
B Wheat plant
C Pisum sativum
D Tomato plant

The correct answer is:
Mangifera

Solution:
Some fleshy fruits such as mango (Mangifera), plum usually have a single hard stone, called drupe, that encloses a seed.

Topic: Biology, Sexual Reproduction in Flowering Plants, NEET