datavorous/entrance-exam-dataset huggingface dataset:
Match column I with column II; choose the answer which gives the correct combination of the alphabets of the two columns

Column I	Column II

A	Wheat	p	Pusa Komal

B	Chilli	q	Himgiri

C	Cauliflower	r	Pusa Sadabahar

D	Cowpea	s	Pusa Shubhra

Options:
A A = s, B = q, C = r, D = p
B A = q, B = r, C = s, D = p
C A = s, B = r, C = q, D = p
D A = r, B = q, C = s, D = p

The correct answer is:
A = q, B = r, C = s, D = p

Solution:
Crop	Disease resistant variety

Wheat	Himgiri

Cauliflower	Pusa Shubhra, Pusa Snowball K-1

Chilli	Pusa Sadabahar

Cowpea	Pusa Komal

Topic: Biology, Strategies for Enhancement in Food Production, NEET
Match column I with column II:

Column I	Column II

A.	Jaundice	i.	Small blind sac, host-symbiont microbes

B.	Chylomicrons	ii.	Deposition of bile pigments

C.	Succus entericus	iii.	Protein coated fat globules

D.	Caecum	iv.	Intestinal juice

Options:
A A - IV, B - III, C - II, D - I
B A - II, B - I, C - IV, D - III
C A - II, B - III, C - IV, D - I
D A - IV, B - II, C - III, D - I

The correct answer is:
A - II, B - III, C - IV, D - I

Solution:
In Jaundice, the liver is affected, skin and eyes turn yellow due to the deposition of bile pigments. Chylomicrons are protein-coated fat globules. Succus entericus is another name of intestinal juice which contains a variety of enzymes. The caecum is a small blind sac of the large intestine which comprises of symbiotic bacteria which are beneficial for the host, i.e. humans.

Topic: Biology, Digestion and Absorption, NEET
Match Column - I with Column - II.

Column -I	Column -II

(a)	S phase	(i)	Proteins are synthesized

(b)	G2 phase	(ii)	Inactive phase

(c)	Quiescent stage	(iii)	Interval between mitosis and initiation of DNA replication

(d)	G1 phase	(iv)	DNA replication

Choose the correct answer from options given below.

Options:
A (a)-(iii); (b)-(ii); (c)-(i); (d)-(iv)
B (a)-(iv); (b)-(ii); (c)-(iii); (d)-(i)
C (a)-(iv); (b)-(i); (c)-(ii); (d)-(iii)
D (a)-(ii); (b)-(iv); (c)-(iii); (d)-(i)

The correct answer is:
(a)-(iv); (b)-(i); (c)-(ii); (d)-(iii)

Solution:
S-phase is related to DNA replication.

G2-phase is related to the synthesis of proteins.

The quiescent phase is the inactive phase.

During the G1-phase, the cell is metabolically active and continuously grows but does not replicate its DNA.

Topic: Biology, Cell Cycle and Cell Division, NEET, NEET 2021
Match Column I with Column II

Column I	Column II

Structure	Common Name

a.
p.	Caproic acid

b.
q.	Carbinol

c.
r.	Acetone

d.	CH3OH	s.	Valeric acid

e.	PhOH	t.

f.	Malonic acid	u.	Carbolic acid

Options:
A Aâr;bâs;câp;dâq;eâu;fât
B A→s;b→p;c→q;d→u;e→r;f→t
C A→p;b→q;c→u;d→s;e→r;f→t
D Aâq;bâu;cât;dâr;eâs;fâp

The correct answer is:
A→r;b→s;c→p;d→q;e→u;f→t

Solution:

Topic: Chemistry, General Organic Chemistry, NEET
Match Column - I with Column - II.

Column-I	Column-II

(a)	(i)	Brassicaceae

(b)	(ii)	Liliaceae

(c)	(iii)	Fabaceae

(d)	(iv)	Solanaceae

Choose the correct answer from the options given below.

Options:
A (a)-(iii); (b)-(iv); (c)-(ii); (d)-(i)
B (a)-(i); (b)-(ii); (c)-(iii); (d)-(iv)
C (a)-(ii); (b)-(iii); (c)-(iv); (d)-(i)
D (a)-(iv); (b)-(ii); (c)-(i); (d)-(iii)

The correct answer is:
(a)-(iii); (b)-(iv); (c)-(ii); (d)-(i)

Solution:
Floral formula of Fabaceae:

Floral formula of Solanaceae:

Floral formula of Liliaceae:

Floral formula of Brassicaceae:

Topic: Biology, Morphology of Flowering Plants, NEET, NEET 2021
Match Column-I (microbes) to the Column-II (biological products) and select the option having correct matching.

Column -I	Column -II

(A)	Acetobacter aceti	(i)	Citric acid

(B)	Clostridium butylicum	(ii)	Lactic acid

(C)	Aspergillus niger	(iii)	Acetic acid

(D)	Lactobacillus	(iv)	Butyric acid

Options:
A (A)-(ii); (B)-(i); (C)-(iii); (D)-(iv)
B (A)-(iii); (B)-(ii); (C)-(i); (D)-(iv)
C (A)-(iii); (B)-(iv); (C)-(i); (D)-(ii)
D (A)-(iv); (B)-(iii); (C)-(ii); (D)-(i)

The correct answer is:
(A)-(ii); (B)-(i); (C)-(iii); (D)-(iv)

Solution:
Microbes are also used for commercial and industrial production of certain chemicals like organic acids, alcohols and enzymes. Examples of acid producers are Aspergillus niger (a fungus) of citric acid, Acetobacter aceti (a bacterium) of acetic acid; Clostridium butylicum (a bacterium) of butyric acid and Lactobacillus (a bacterium) of lactic acid.

Topic: Biology, Microbes in Human Welfare, NEET
Match Column-I with Column - II and select the CORRECT option from the codes given below.

Column â I	Column â II

(P) Autopolyploidy	(i) 2n+1

(Q) Trisomy	(ii) AAAA

(R) Allopolyploidy	(iii) AABB

(S) Nullisomy	(iv) 2n-2

Options:
A P- (ii), Q - (i), R - (iii), S - (iv)
B P- (iv), Q - (i), R - (ii), S - (iii)
C P- (ii), Q - (iv), R - (iii), S - (i)
D P- (ii), Q - (i), R - (iv), S - (iii)

The correct answer is:
P- (ii), Q - (i), R - (iii), S - (iv)

Solution:
When an individual has more than two sets of chromosomes and both of which come from the same parental species is called autopolyploidy. It will be represented by AAAA.
Trisomy is a type of aneuploidy in which abnormal sets of chromosomes are present. The somatic cell contains three copies of one chromosome in trisomy and its genomic formula is 2n+1.
When an individual has more than two sets of chromosomes and both of which come from the different parental species is called allopolyploidy. It will be represented by AABB.
Nullisomy is also a type of aneuploidy in which diploid organisms lose a pair of homologous chromosomes and its genomic formula is 2n-2.

Topic: Biology, Principles of Inheritance and Variation, NEET
Match Column-I with Column - II and select the CORRECT option from the codes given below.

Column-I	Column-II

(1)	Normal woman	(i)	14

(2)	Klinefelterâs syndrome	(ii)	45

(3)	Turnerâs syndrome	(iii)	46

(4)	Pisum sativum	(iv)	47

Options:
A 1- (iii), 2- (iv), 3- (ii), 4- (i)
B 1 - (iii), 2 - (ii), 3 - (iv), 4 - (i)
C 1- (i), 2 - (iv), 3 - (ii), 4 - (iii)
D 1- (i), 2 - (ii), 3 - (iv), 4 - (iii)

The correct answer is:
1- (iii), 2- (iv), 3- (ii), 4- (i)

Solution:
The number of chromosomes in a normal woman is 44+ XX that is 46.
Klinefelter's syndrome is a condition where individual has the chromosomal combination as 44+XXY with an extra X chromosome. Such individual is sterile. Also, individual has an overall masculine development with certain feminine characteristics.
Turner's syndrome occurs when the chromosomal count is 44+ X0, where the last pair has a missing chromosome. The individual is sterile female with webbed neck.
Pisumsativum is the pea plant that was studied by Mendel for inheritance patterns. This plant has 7 pairs of chromosomes. Thus, it has 14 chromosomes.

Topic: Biology, Principles of Inheritance and Variation, NEET
Match column-I with column-II and choose the correct option.

Column-I	Column-II

A.	Phaeophyceae	I.	Funaria, Polytrichum, Sphagnum

B.	Rhodophyceae	II.	Equisetum, Psilotum, Pteris

C.	Mosses	III.	Ectocarpus, Dictyota, Laminaria

D.	Pteridophytes	IV.	Polysiphonia, Porphyra, Gracilaria

Options:
A A - III; B - IV; C - I; D - II
B A - IV; B - III; C - I; D - II
C A - IV; B - III; C - II; D - I
D A - IV; B - I; C - III; D - II

The correct answer is:
A - III; B - IV; C - I; D - II

Solution:
Ectocarpus, Dictyota, and Laminaria are the members of Phaeophyceae or brown algae, which are found primarily in marine habitats.

Polysiphonia, Porphyra, and Gracilaria are the members of Rhodophyceae or red algae, while most of them are marine with higher concentrations in the warmer areas.

Funaria, Polytrichum, and sphagnum are mosses that are found commonly growing in moist, shaded areas in the hills.

Equisetum, Psilotum, and Pteris are pteridophytes, the first terrestrial plants to possess vascular tissues â xylem and phloem.

Topic: Biology, Plant Kingdom, NEET
Match Column-I with Column-II and Choose the correct option

Column-I	Column-II

A.	Phaeophyceae	I.	Funaria, Sphagnum

B.	Rhodophyceae	II.	Equisetum, Pteris

C.	Pteridophytes	III.	Ectocarpus, Laminaria

D.	Bryophytes	IV.	Polysiphonia, Gracilaria

Options:
A

A - III; B - IV; C - I; D - II

B

A - II; B - IV; C - III; D - I

C

A - III; B - IV; C - II; D - I

D

A - IV; B - III; C - I; D - II

The correct answer is:

A - III; B - IV; C - II; D - I

Solution:
Class Phaeophyceae comprising the Brown Algae, example species are Ectocarpus, Laminaria
Class Rhodophyceae Comprising of Red Algae, example species are Polysiphonia, Gracilaria,
Division Pteridophytes Comprising of Ferns, Examples are Equisetum, Pteris
Division Bryophyta Comprising the liverworts, hornworts, and mosses. Examples are Funaria, Sphagnum,

Topic: Biology, Plant Kingdom, NEET
Match Column-I with Column-II and choose the correct option of the following:

ColumnâI	ColumnâII

(i)	Transgenic tobacco	(A)	Vitamin A

(ii)	Golden rice	(B)	Alpha-lactalbumin

(iii)	Transgenic Rosie cow	(C)	Pest resistant variety

(iv)	Transgenic animals	(D)	Alpha-1-antitrypsin

Options:
A (i) â C, (ii) â A, (iii) â B, (iv) â D
B (i) â B, (ii) â A, (iii) â C, (iv) â D
C (i) â B, (ii) â C, (iii) â A, (iv) â D
D (i) â D, (ii) â A, (iii) â B, (iv) â C

The correct answer is:
(i) â C, (ii) â A, (iii) â B, (iv) â D

Solution:
Transgenic animals that produce useful biological products can be created by the introduction of the portion of DNA (or genes) which codes for a particular product such as human protein (alpha-1 antitrypsin) used to treat emphysema. Similar attempts are being made for the treatment of phenylketonuria (PKU) and cystic fibrosis. In 1997, the first transgenic cow, Rosie, produced human protein-enriched milk (2.4 grams per litre). The milk contained the human alpha-lactalbumin and was nutritionally a more balanced product for human babies than natural cow-milk.
Several nematode parasitises are harmful to a wide variety of plants and animals, including human beings. A nematode Meloidogyne incognita infects the roots of tobacco plants and causes a great reduction in yield. A novel strategy was adopted to prevent this infestation, which was based on the process of RNA interference (RNAi). The transgenic plant, therefore, got itself protected from the parasite.
Golden rice is biofortified rice with rich vitamin A content.

Topic: Biology, Biotechnology and Its Applications, NEET
Match column-I with column-II and select the correct answer from the codes given below.

Column - I	Column - II

(A) Trichoderma	(i) Nitrification

(B) Streptomyces	(ii) Biological control

(C) Nitrosomonas	(iii) Lactic acid

(D) Lactobacillus	(iv) Source of antibiotic

Options:
A A - (ii), B - (iii), C - (iv), D - (i)
B A - (ii), B - (iv), C - (i), D - (iii)
C A - (iii), B - (i), C - (ii), D - (iv)
D A - (iv), B - (ii), C - (i), D - (iii)

The correct answer is:
A - (ii), B - (iv), C - (i), D - (iii)

Solution:
Trichoderma a fungus is used to control other soil-borne fungal pathogens, thus used as biocontrol. Streptomyces is the most important bacterial source of antibiotics. Nitrosomonas is a free-living bacteria that carry out the conversion of ammonium ion to nitrate in the soil. Lactobacillus is used to produce lactic acid.

Topic: Biology, Microbes in Human Welfare, NEET
Match Column-I with Column-II and select the CORRECT option from the codes given below.

Column-I	Column-II

(1)	River Popper hypothesis	(i)	Alexander von Humboldt

(2)	Long-term ecosystem experiments using outdoor plots	(ii)	David Tilman

(3)	Species-area relationships	(iii)	Paul Ehrlich

Options:
A (1)-(iii),Â (2)-(i),Â (3)-(ii)
B (1)-(iii), (2)-(ii), (3)-(i)
C (1)-(i),Â (2)-(iii),Â (3)-(ii)
D (1)-(ii),Â (2)-(iii),Â (3)-(i)

The correct answer is:
(1)-(iii), (2)-(ii), (3)-(i)

Solution:
Paul Elrich gave the River Popper hypothesis regarding the species impact on ecosystem.
Alexander von Humboldt gave the species-area relationship on species richness interacting with ecosystem
David Tilman conducted ecological experiments on outdoor plots.

Topic: Biology, Biodiversity and its Conservation, NEET
Match Column-I with Column-II and select the correct option using the codes given below :

Column–I	Column–II

a.	Citric acid	(i)	Trichoderma

b.	Cyclosporin A	(ii)	Clostridium

c.	Statins	(iii)	Aspergillus

d.	Butyric acid	(iv)	Monascus

Options:
A

a.	b.	c.	d.
(iii)	(i)	(ii)	(iv)

B

a.	b.	c.	d.

(iii)	(i)	(iv)	(ii)

C

a.	b.	c.	d.
(i)	(iv)	(ii)	(iii)

D

a.	b.	c.	d.
(iii)	(iv)	(i)	(ii)

The correct answer is:

a.	b.	c.	d.

(iii)	(i)	(iv)	(ii)

Solution:
Microbe	Product

Aspergillus niger	Citric acid

Trichoderma polysporum	Cyclosporin-A

Monascus purpureus	Statins

Clostridium butylicum	Butyric acid

Topic: Biology, Microbes in Human Welfare, NEET, NEET 2016 (Phase 2)
Match Column-I with Column-II and select the correct option using the codes given below:

Column–I	Column–II

a.	Mons pubis	(i)	Embryo formation

b.	Antrum	(ii)	Sperm

c.	Trophectoderm	(iii)	Female external genitalia

d.	Nebenkern	(iv)	Graafian follicle

Options:
A

a.	b.	c.	d.
(iii)	(iv)	(ii)	(i)

B

a.	b.	c.	d.

(iii)	(iv)	(i)	(ii)

C

a.	b.	c.	d.
(iii)	(i)	(iv)	(ii)

D

a.	b.	c.	d.
(i)	(iv)	(iii)	(ii)

The correct answer is:

a.	b.	c.	d.

(iii)	(iv)	(i)	(ii)

Solution:
The external genital structures of the female reproductive system are collectively called the vulva. The female external genitalia or vulva includes mons pubis, labia majora, labia minora, hymen and clitoris. Mons pubis is a cushion of fatty tissue covered by skin and pubic hair.

In Graafian follicle, the antrum is cresent shaped, but with time it greatly enlarges. The fluid of antrum is liquor folliculi which is rich in hyaluronic acid.

Nebenkern is the spiral arrangement of mitochondria in the middle piece of sperm.

Trophoblast or trophoectoderm does not take part in the formation of embryo proper. It forms foetal portion of the placenta which provides food the developing embryo.

Topic: Biology, Human Reproduction, NEET, NEET 2016 (Phase 2)
Match Column-I with Column-II.
Choose the correct option

Options:
A $(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{IV}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{III})$
B $(\mathrm{A})-(\mathrm{I}),(\mathrm{B})-(\mathrm{II}),(\mathrm{C})-(\mathrm{III}),(\mathrm{D})-(\mathrm{IV})$
C $(\mathrm{A})-(\mathrm{III}),(\mathrm{B})-(\mathrm{I}),(\mathrm{C})-(\mathrm{IV}),(\mathrm{D})-(\mathrm{II})$
D $(\mathrm{A})-(\mathrm{IV}),(\mathrm{B})-(\mathrm{III}),(\mathrm{C})-(\mathrm{II}),(\mathrm{D})-(\mathrm{I})$

The correct answer is:
$(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{IV}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{III})$

Solution:
\(\begin{array}{|l|l|l|l|}
\hline \text { (A) } & \text { Nitrococcus } & - & \text { Conversion of ammonia to nitrite } \\
\hline \text { (B) } & \text { Rhizobium } & - & \text { Conversion of atmospheric nitrogen to ammonia } \\
\hline \text { (C) } & \text { Thiobacillus } & - & \text { Denitrification } \\
\hline \text { (D) } & \text { Nitrobacter } & - & \text { Conversion of nitrite to nitrate } \\
\hline
\end{array}\)

Topic: Biology, Mineral Nutrition, NEET, NEET 2023 (Manipur)
Match Column-I with Column-II for housefly classification and select the correct option using the codes given below:

Column – I	Column – II

a. Family	(i) Diptera

b. Order	(ii) Arthropoda

c. Class	(iii) Muscidae

d. Phylum	(iv) Insecta

Options:
A

a	b	c	d
(iii)	(i)	(iv)	(ii)

B

a	b	c	d
(iii)	(ii)	(iv)	(i)

C

a	b	c	d
(iv)	(iii)	(ii)	(i)

D

a	b	c	d
(iv)	(ii)	(i)	(iii)

The correct answer is:

a	b	c	d
(iii)	(i)	(iv)	(ii)

Solution:
\(\begin{array}{|l|l|l|l|l|l|l|l|}
\hline \text { Common names } & \text { Biological name } & \text { Genus } & \text { Family } & \text { Order } & \text { Class } & \text { Phylum or Division } & \text { Kingdom } \\
\hline \text { Housefly } & \text { Musca domestica } & \text { Musca } & \text { Muscidae } & \text { Diptera } & \text { Insecta } & \text { Arthropoda } & \text { Animalia } \\
\hline
\end{array}\)

Topic: Biology, The Living World, NEET, NEET 2016 (Phase 2)
Match each disease with its correct type of vaccine:

(a)	Tuberculosis	(i)	Harmless virus

(b)	Whooping cough	(ii)	Inactivated toxin

(c)	Diphtheria	(iii)	Killed bacteria

(d)	Polio	(iv)	Harmless bacteria

Options:
A

(a)	(b)	(c)	(d)
(ii)	(i)	(iii)	(iv)

B

(a)	(b)	(c)	(d)
(iii)	(ii)	(iv)	(i)

C

(a)	(b)	(c)	(d)
(iv)	(iii)	(ii)	(i)

D

(a)	(b)	(c)	(d)
(i)	(ii)	(iv)	(iii)

The correct answer is:

(a)	(b)	(c)	(d)
(iv)	(iii)	(ii)	(i)

Solution:
Tuberculosis - Harmless bacteria - Mycobacterium tuberculosis
Whooping cough - Killed bacteria - Bordetella pertussis
Diptheria - Inactivated toxin - Corynebacterium diphtheriae
Polio - harmless virus - Poliomyelitis virus

Topic: Biology, Human Health and Diseases, NEET, NEET 2015 (Phase 1)
Match from the columns given below:

Parts of Dicot Roots	Consists of

a. Epiblema	i. Unicellular root hair.

b. Casparian strips	ii. Vascular bundle and pith.

c. Pericycle	iii. Waxy material suberin.

d. Stele	iv. Thick walled parenchyomatous cells.

Options:
A a-ii, b-iv, c-iii, d-i
B a-i, b-iii, c-iv, d-ii
C a-iii, b-iv, c-i, d-ii .
D a-iv, b-i, c-ii, d-iii .

The correct answer is:
a-i, b-iii, c-iv, d-ii

Solution:
Epiblema is the outermost layer which further becomes unicellular root hair. A water-impermeable, waxy material suberin is deposited on the tangential or radial walls of the endodermal is known as Casparian strips. Pericycle which is next to endodermal is made up of parenchymatous cells and vascular bundle and pith altogether is known as Stele.

Topic: Biology, Anatomy of Flowering Plants, NEET
Match items in Column I with those in Column II:
Select the correct answer from the following.

Options:
A (a) - (l); (b) - (j); (c) - (m); (d) - (n); (e) $-(\mathrm{k})$
B (a) - (k); (b) - (j); (c) - (l); (d) - (m); (e) - (n)
C (a) - (n); (b) - (l); (c) - (k); (d) - (n); (e) - (j)
D (a) - (j); (b) - (k); (c) - (n); (d) - (l); (e) $-(\mathrm{k})$.

The correct answer is:
(a) - (l); (b) - (j); (c) - (m); (d) - (n); (e) $-(\mathrm{k})$

Solution:
Flagellation is the arrangement of flagella over the body surface of a bacterial cell. Peritrichous bacteria has flagella all over the surface of cell e.g., E. coli.
Ginkgo biloba is called living fossil because it is the single living genus in a big fossilised order Ginkgoales.
Rhizophore is a leafless, colourless, positively geotropic elongated structure that grows down from the point of bifurcation of stem. It occurs in Selaginella.
Wolffia is a hydrophyte and the smallest angiosperm.
Macrocystis belongs to class Phaeophyceae. It is the largest perennial alga, about $40-60 \mathrm{~m}$ in size.

Topic: Biology, Plant Kingdom, NEET, NEET 2005
Match items of column-I with the items of column-II and assign the correct code:

Column I	Column II

(a)	Cyanide process	(i)	Ultrapure Ge

(b)	Froth floatation process	(ii)	Dressing of ZnS

(c)	Electrolytic reduction	(iii)	Extraction of Al

(d)	Zone refining	(iv)	Extraction of Au

(v)	Purification of Ni

Options:
A abciviiiii di
B abciiiiiiÂ Â Â Â dv
C abciiiiiiÂ Â Â Â div
D abciiiivvÂ Â Â Â di

The correct answer is:
abciviiiii di

Solution:
a. The cyanide process is used to extract Ag and Au in hydrometallurgy.
b. Froth floatation process is used for the dressing of sulfide ores.
c] The electrolytic reduction is used to extract Al.
d] The zone refining process is used for obtaining ultrapure Ge.

Topic: Chemistry, General Principles and Processes of Isolation of Metals, NEET, NEET 2016 (Phase 1)
Match List I and List II

List I	List II

A	CCK	I	Kidney

B	GIP	II	Heart

C	ANF	III	Gastric gland

D	ADH	IV	Pancreas

Choose the correct answer from the options given below:

Options:
A A-IV; B-II; C-III; D-I
B A-IV; B-III; C-II; D-I
C A-III; B-II; C-IV; D-I
D A-II; B-IV; C-I; D-III

The correct answer is:
A-IV; B-III; C-II; D-I

Solution:
CCK

Cholecystokinin or CCK acts on both pancreas and gall bladder and stimulates the secretion of pancreatic enzymes and bile juice, respectively.

GIP

GIP inhibits gastric secretion and motility by acting on the gastric glands.

ANF

The atrial wall secretes ANF. This opposes RAAS mechanism and reduces the blood pressure, as it is a vasodilator.

ADH

Secreted by neurohypophysis.

ADH facilitates water reabsorption from latter parts of the tubule, thereby preventing diuresis.

ADH can also affect the kidney function by its constrictory effects on blood vessels.

Topic: Biology, Chemical Coordination and Integration, NEET, NEET 2023 (All India)
Match list I (reagents for reaction of nitrobenzene) with list II (products formed) and select the correct answer using the codes given below.

List I
List II

p
Sn and HCl
1.
Hydrazobenzene

(q)
Zn and NH4Cl
2.
Azoxybenzene

(r)
Methanolic NaOMe
3.
Phenyl hydroxylamine

(s)
Zn and KOH
4.
Aniline

Options:
A (p)-4, (q)-3, (r)-1, (s)-2
B (p)-4, (q)-3, (r)-2, (s)-1
C (p)-3, (q)-4, (r)-1, (s)-2
D (p)-3, (q)-4, (r)-2, (s)-1

The correct answer is:
(p)-4, (q)-3, (r)-1, (s)-2

Solution:

Topic: Chemistry, Amines, NEET
Match List I (substances) with List II (processes) employed in the manufacture of the substances and select the correct option

List I (Substances)
List II (Processes)

1.
Sulphuric acid
(i)
Haber's process

2.
Nitric acid
(ii)
Ostwald process

3.
Sodium hydroxide
(iii)
Leblanc process

4.
Ammonia
(iv)
Contact process

Options:
A 1-(i), 2-(iv), 3-(ii), 4-(iii)
B 1-(i), 2-(ii), 3-(iii), 4-(iv)
C 1-(iv), 2-(iii), 3-(ii), 4-(i)
D 1-(iv), 2-(ii), 3-(iii), 4-(i)

The correct answer is:
1-(iv), 2-(ii), 3-(iii), 4-(i)

Solution:
1.
Sulphuric acid
(iv)
Contact process

2.
Nitric acid
(ii)
Ostwald process

3.
Sodium hydroxide
(iii)
Leblanc process

4.
Ammonia
(i)
Haber's process

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), NEET
Match List I (Sub-structures) with List II (Functions) and select the CORRECT answer using the codes given below the lists:

List-I (Sub-structures)	List-II (Functions)

(A)	Nucleosome	(1)	Cementing to keep neighbouring cells together

(B)	Tubulin	(2)	A storehouse of oils and lipids

(C)	Adhering junctions	(3)	Structural units of chromatin

(D)	Elaioplasts	(4)	Protein units of microtubules

(5)	Oxidative phosphorylation

Options:
A A-2, B-5, C-4, D-3
B A-3, B-4, C-1, D-2
C A-3, B-5, C-4, D-2
D A-2, B-4, C-1, D-3

The correct answer is:
A-3, B-4, C-1, D-2

Solution:
DNA is wrapped histone proteins to form beads like structure called nucleosomes. This structure is further condensed to fit in a coiled helical structure called solenoid that on folding forms the chromatin fibre. Nucleosome forms the structural unit of chromatin fibre.
Microtubules found in the cytoplasm of eukaryotic cells are made of polymers of protein, tubulin. Microtubules help with the structure and shape of the cell.
Tight junctions are a type of cell junctions found in epithelial tissue that help to stop substances from leaking across a tissue.
Elaioplasts are a type of leucoplast store oils and fats.

Topic: Biology, Cell - The Unit of Life, NEET
Match list I with II and choose the correct answer

List I	List II

A. Hypothalamus	1. Sperm lysins

B. Acrosome	2. Estrogen

C. Graafian follicle	3. Relaxin

D. Leydig cells	4. GnRH

E. Parturition	5. Testosterone

Options:
A A-4, B-1, C-2, D-3, E-5
B A-2, B-1, C-4, D-3, E-5
C A-2, B-1, C-5, D-4, E-3
D A-4, B-1, C-2, D-5, E-3

The correct answer is:
A-4, B-1, C-2, D-5, E-3

Solution:
Hypothalamus GnRH
Acrosome Sperm lysins
Graanfian follicle Estrogen
Leydig cells Testosterone
parturition Relaxin

Topic: Biology, Human Reproduction, NEET