datavorous/entrance-exam-dataset huggingface dataset:
The simplest formula of the compound containing 50% X (atomic mass 10 amu) and 50% Y (atomic mass 20 amu) is

Options:
A XY2
B X2Y
C X2Y3
D XY3

The correct answer is:
X2Y

Solution:
Element
%
Atomic ratio
Simplest ratio

X
50
5010=5
52.5=2

Y
50
5020=2.5
2.52.5=1

So formula =X2Y .

Topic: Chemistry, Some Basic Concepts of Chemistry, NEET
The simplest of all nutrient cycles operating in an ecosystem is______ cycle

Options:
A Carbon
B Phosphorous
C Nitrogen
D Oxygen

The correct answer is:
Phosphorous

Solution:
Unlike many other biogeochemical cycles, the atmosphere does not play a significant role in the movement of phosphorus, because phosphorus and phosphorus-based compounds are usually solids at the typical ranges of temperature and pressure found on earth. It is absorbed by autotrophs, at each level excess phosphorus is eliminated and decomposers return them to the soil so that autotrophs can reobtain them.

Topic: Biology, Ecosystem, NEET
The site for the production of an enzyme, the deficiency of which causes SCID, in the body is

Options:
A bone marrow.
B lymphocyte.
C blood plasma.
D monocytes.

The correct answer is:
lymphocyte.

Solution:
ADA which is adenosine deaminase is an enzyme which is important of the function of the immune system. ADA is produced by the immune system cells called lymphocytes. The deficiency of ADA is caused by deletion of the gene for adenosine deaminase (Severe Combine Immuno Deficiency). The deficiency of ADA can be cured by bone marrow transplantation and in some it can be treated with the help of enzyme replacement therapy in which injections of functional ADA are given to the patient. Both these methods are not completely curative. Permanent cure can be achieved if gene isolate from marrow cells producing ADA is introduced into cells at early embryonic stages.

Topic: Biology, Biotechnology and Its Applications, NEET
The site of ADA production in the body is

Options:
A Neutrophils
B Lymphocytes
C Blood plasma
D Monocytes

The correct answer is:
Lymphocytes

Solution:
Lymphocytes are types of white blood cells present in the bone marrow. ADA (adenosine deaminase) is an enzyme that is present in lymphocytes and is very important for the immune system to function. The deficiency of this enzyme causes SCID.

Topic: Biology, Biotechnology and Its Applications, NEET
The site of glycolysis is

Options:
A nucleoplasm.
B mitochondria.
C peroxisomes.
D cytoplasm.

The correct answer is:
cytoplasm.

Solution:
The term glycolysis has originated from the Greek words, glycos for sugar and lysis for splitting. The scheme of glycolysis was given by Gustav Embden, Otto Meyerhof, and J. Parnas, and is often referred to as the EMP pathway. In anaerobic organisms, it is the only process in respiration. Glycolysis occurs in the cytoplasm of the cell and is present in all living organisms. In this process, glucose undergoes partial oxidation to form two molecules of pyruvic acid.

Topic: Biology, Respiration in Plants, NEET
The site of perception of light in plants during photoperiodism is:

Options:
A Shoot apex
B Stem
C Axillary bud
D Leaf

The correct answer is:
Leaf

Solution:
The site of perception of light/dark duration is the leaves. It has been hypothesised that there is a hypothetical hormonal substance(s) that is responsible for the flowering. This hormonal substance migrates from leaves to shoot apices for inducing flowering only when the plants are exposed to the necessary inductive photoperiod.

Topic: Biology, Plant - Growth and Development, NEET, NEET 2021
The site of perception of light/dark duration are the

Options:
A Leaves
B Shoot apical meristem
C Bud
D Roots

The correct answer is:
Leaves

Solution:
Leaves of plants consist of a pigment system known as phytochrome which perceives light and controls photoperiodic induction. Phytochrome occurs in two interconvertible forms which regulate gene activity and production of flowering hormone florigen.

Topic: Biology, Plant - Growth and Development, NEET
The site of production of ADA in the body is:

Options:
A Erythrocytes
B Lymphocytes
C Blood plasma
D Osteocytes

The correct answer is:
Lymphocytes

Solution:
The site of production of ADA in the body is Lymphocytes.

Topic: Biology, Biotechnology and Its Applications, NEET
The situation where indigenous knowledge of nature, originating with indigenous people, is used by others for profit, without taking proper permission from them and with little or no compensation or recognition to the indigenous people themselves is known as

Options:
A Biopatents
B Biopiracy
C Biological diversity
D Ethical issues

The correct answer is:
Biopiracy

Solution:
Biopiracy is the term used to refer to the use of bio-resources by multinational companies and other organizations without proper authorization from the countries and people concerned without compensatory payment.

Topic: Biology, Biotechnology and Its Applications, NEET
The size of Pleuropneumonia-like Organism (PPLO) is:

Options:
A 0.02μm
B 1-2μm
C 10-20μm
D 0.1μm

The correct answer is:
0.1μm

Solution:
The prokaryotic cells are represented by bacteria, blue-green algae, mycoplasma and PPLO (Pleuro Pneumonia Like Organisms). They are generally smaller and multiply more rapidly than the eukaryotic cells.
Size of PPLO is about \(0.1 \mu \mathrm{m}\).

Diagram showing comparison of eukaryotic cell with other organisms

Topic: Biology, Biological Classification, NEET, NEET 2020 (Phase 2)
The size of the brain of Neanderthal is about

Options:
A 1400 cc
B 900Â cc
C 600Â cc
D 1600Â cc

The correct answer is:
1400 cc

Solution:
The Neanderthal man with a brain size of 1400cc lived in the near east and central Asia between 1,00,000â40,000 years back. They used hides to protect their body and buried dead bodies.

Topic: Biology, Evolution, NEET
The size of the seed grain in pea is an example of:

Options:
A Complete Dominance
B Incomplete dominance
C Multiple alleles
D Pleiotropism

The correct answer is:
Incomplete dominance

Solution:
Starch synthesis in pea seeds is controlled by one gene. It has two alleles (B and b). Starch is synthesised effectively by BB homozygotes and therefore, large starch grains are produced. In contrast, bb homozygotes have lesser efficiency in starch synthesis and produce smaller starch grains. After maturation of the seeds, BB seeds are round and the bb seeds are wrinkled. Heterozygotes produce round seeds, and so B seems to be the dominant allele. But, the starch grains produced are of intermediate size in Bb seeds. So if starch grain size is considered as the phenotype, then from this angle, the alleles show incomplete dominance.

Topic: Biology, Principles of Inheritance and Variation, NEET
The size of VNTRs varies between

Options:
A 0.2 to 0.4 kbp
B 0.2 to 10 kbp
C 0.1 to 20 kbp
D 0.2 to 20 kbp

The correct answer is:
0.1 to 20 kbp

Solution:
The VNTR belongs to a class of satellite DNA referred to as mini satellite. A small DNA sequence is arranged tandemly in many copy numbers. The number of repeats show very high degree of polymorphism. Size of VNTRs varies from 0.1 to 20 kbp.

Topic: Biology, Molecular Basis of Inheritance, NEET
The sketch below shows cross-sections of the equipotential surface between two charged conductors that are shown in solid black. Some points on the equipotential surfaces near the conductors are marked as A, B, C.......... The arrangement lies in the air. Take Ïµ0=8.85Ã10-12 C2 N-1 m-2
The surface charge density of the plate is equal to

Options:
A 8.85×10-10 C m-2
B -8.85×10-10 C m-2
C 17.7×10-10 C m-2
D -17.7×10-10 C m-2

The correct answer is:
8.85×10-10 C m-2

Solution:
E=40-100.3=100 V m-1
(near the plate the electric field has to be uniform

∴ it is almost due to the plate).
For conducting plate
E=σε0 ⇒ σ=ε0E
Therefore σ=8.85×10-12×100
= 8.85×10-10 C m-2

Topic: Physics, Electrostatics, NEET
The sliding contact $C$ is at one fourth of the length of the potential wire $(A B)$ from $A$ as shown in the circuit diagram. If the resistance of the wire $A B$ is $R_0$, then the potential drop $(V)$ across the resistor $R$ is:

Options:
A $\frac{4 \mathrm{~V}_0 R}{3 \mathrm{R}_0+16 R}$
B $\frac{4 V_0 R}{3 R_0+R}$
C $\frac{2 V_0 R}{4 R_0+R}$
D $\frac{2 V_0 R}{2 R_0+3 R}$

The correct answer is:
$\frac{4 \mathrm{~V}_0 R}{3 \mathrm{R}_0+16 R}$

Solution:
The given diagram can be redrawn as follow:

The potential across $A C$,
$\mathrm{V}_{\mathrm{AC}}=\frac{\mathrm{R}_{\mathrm{AC}}}{\mathrm{R}_{\mathrm{BC}}+\mathrm{R}_{\mathrm{AC}}} \times \mathrm{V}_0$
$\begin{aligned}
& \frac{\frac{R R_0}{4 R+R_0}}{\frac{3 R_0}{4}+\frac{R R_0}{4 R+R_0}} \times V_0 \\
& = \frac{4 R V_0}{3 R_0+16 R}
\end{aligned}$

Topic: Physics, Current Electricity, NEET, NEET 2022 (Phase 2)
The slime moulds are characterized by the presence of

Options:
A elaters
B pseudoelaters
C myxamoebae
D capitulum

The correct answer is:
myxamoebae

Solution:
The slime mould plasmodium of a slime mold is formed by the fusion of myxamoebae or swarm cells that acts as a gametes. Myxamoebae possess pseudopodia and have amoeba-like appearance and behaviour. Elaters and pseudoelaters are present in some bryophytes where as capitulum is a type of inflorescence.

Topic: Biology, Biological Classification, NEET
The slope of Arrhenius Plot lnk v/s 1 T of first order reaction is -5×103 K. The value of Ea of the reaction is. Choose the correct option for your answer.

[Given R=8.314 J K-1 mol-1]

Options:
A 41.5 kJ mol-1
B 83.0 kJ mol-1
C 166 kJ mol-1
D -83 kJ mol-1

The correct answer is:
41.5 kJ mol-1

Solution:
Arrhenius equation is k=Ae-EaRT

So, lnk=lnA-EaRT

This is a straight-line equation of form y=mx+c

where y=lnk,x=1T,m=-EaR and c=ln A

m=-EaR

-5×103K=-Ea8.314

Ea=8.314×5×103 Jmol-1=41.5 kJ mol-1

Topic: Chemistry, Chemical Kinetics, NEET, NEET 2021
The slope of the freundlich isotherm

Options:
A 1/n
B logK
C log(x/m)
D Log p

The correct answer is:
1/n

Solution:
Correct Option is : 1
1/n

Topic: Chemistry, Surface Chemistry, NEET
The slow rate of decomposition of fallen logs in nature is due to their

Options:
A low moisture content
B poor nitrogen content
C anaerobic environment around them
D low cellulose content

The correct answer is:
low moisture content

Solution:
Photosynthetically fixed carbon is eventually degraded by micro-organisms and two major forms of carbon result methane $\left(\mathrm{CH}_4\right)$ and carbon dioxide $\left(\mathrm{CO}_2\right)$. The micro-organisms breakdown the complex compounds of dead protoplasm of producers and consumers absorb some of the decomposition products and release simple substances. The slow rate of decomposition of fallen logs in nature is due to their low moisture content.
The cellulose is in high amount in fallen logs. The environment arround the fallen logs is aerobic, $i e, \mathrm{O}_2$ is present.

Topic: Biology, Plant - Growth and Development, NEET, NEET 2008 (Screening)
The slow ripening transgenic tomato was developed in USA by using

Options:
A antisense RNA technology
B ribozyme technology
C co-suppression silencing approach
D transgene silencing approach

The correct answer is:
antisense RNA technology

Solution:
Flavr Savr, a genetically modified tomato, was the first commercially grown genetically engineered food to be granted a license for human consumption. The Flavr Savr was made more resistant to rotting by adding an antisense gene which interferes with the production of the enzyme polygalacturonase. The enzyme normally degrades pectin in the cell walls and results in the softening of fruit which makes them more susceptible to being damaged by fungal infections. Antisense technology is a tool that inhibits gene expression. The antisense nucleic acid sequence base pairs with its complementary sense RNA strand and prevent it from being translated into a protein.

Topic: Biology, Biotechnology and Its Applications, NEET
The smallest among the following is:

Options:
A TMV
B Bacteriophage
C Neurospora
D E. coli

The correct answer is:
Bacteriophage

Solution:
Bacteriophage is a virus that attacks bacterial cell. Bacteriophages are smaller than Tobacco mosaic virus which is a plant virus.

Topic: Biology, Biological Classification, NEET
The smallest bone in the human body is

Options:
A malleus.
B vestibule.
C stapes.
D tarsal.

The correct answer is:
stapes.

Solution:
The skeletal system consists of 206 bones. It is divided into axial skeleton which consists of 80 bones and appendicular skeleton which consists of 126 bones. The axial skeleton consists of skull, vertebral column, sternum and ribs. Skull consists of face, cranium, ear ossicles and hyoid bone. There are three ear ossicles in each ear. These are malleus, incus and stapes. Stapes is the smallest bone and is stirrup in shape.

Topic: Biology, Locomotion and Movement, NEET
The smallest disease-causing agent is ________, and it is made up of ___________

Options:
A (i) mycoplasma (ii) proteins and nucleic acids
B (i) prions, (ii) proteins only
C (i) Viroids, (ii) nucleic acid only
D (i) Viroids, (ii) proteins only

The correct answer is:
(i) prions, (ii) proteins only

Solution:
Prions are discovered by Prusiner in 1982. They are the smallest infectious protein particles which lack nucleic acid. Prions are modified hydrophobic glycoproteins that are resistant to protease action compared with normal proteins; they function as infectious agents. Prions change normal proteins to an infectious form, and they are found to cause diseases in animals and not in plants.

Topic: Biology, Biological Classification, NEET
The smallest living cell is:

Options:
A Virus
B Viroid
C Mycoplasma
D Cyanobacteria

The correct answer is:
Mycoplasma

Solution:
The Mycoplasma are organisms that completely lack a cell wall. They are the smallest living cells known and can survive without oxygen. Many mycoplasma are pathogenic in animals and plants.

Topic: Biology, Biological Classification, NEET
The smut disease in maize is caused by:

Options:
A Claviceps
B Alternaria
C Phytophthora
D Ustilago

The correct answer is:
Ustilago

Solution:
The smuts are grouped under Basidiomycetes fungi. The smuts get their name from a Germanic word for dirt because of their dark, thick-walled, and dust-like teliospores.

Topic: Biology, Biological Classification, NEET
The sodium salt of a weak acid is hydrolysed to the extent of 3% in 0.1 M solution in water at 25°C . If Ka for weak acid is 1.3×10-10 . The ionic product of water is

Options:
A 1.17×10-14
B 1.17×1014
C 11.7×10-14
D 11.7×10-10

The correct answer is:
1.17×10-14

Solution:
KH=Î±2C
hydrolysis α = degree of
=(0.03)2Ã0.1=9Ã10-5
KH=KwKa
or Kw=KHÃKa
=9Ã10-5Ã1.3Ã10-10
=1.17Ã10-14.

Topic: Chemistry, Ionic Equilibrium, NEET
The sodium yellow doublet has wavelengths 5890 â« and Î» â« and resolving power of a grating to resolve these lines is 982, then value of Î» is

Options:
A 5896 Å
B 5880 Å
C 5869 Å
D 5876 Å

The correct answer is:
5896 Å

Solution:
Mean wavelength λm=5890+λ2
Wavelength difference dλ=λ-5890
Resolving power R of a grating
R=λmdλ=5890+λ2λ-5890=982
λ=5896 Å

Topic: Physics, Wave Optics, NEET
The soil which is used in polishing, filtration of oils and syrups are made of

Options:
A cellulosic plates on surfaces of dinoflagellates
B cell wall of chrysophytes
C cell body of desmids
D extremely resistant spores of slime moulds

The correct answer is:
cell wall of chrysophytes

Solution:
Chrysophytes include the diatoms and golden algae. Their cell wall deposition in the soil makes the soil gritty, known as diatomaceous earth. This soil is used polishing and filtration of oils and syrups.

Topic: Biology, Biological Classification, NEET
The soldiers of Napoleon army while at Alps during freezing winter suffered a serious problem as regards to the tin buttons of their uniforms. White metallic tin buttons got converted to grey powder. This transformation is related to

Options:
A an interaction with nitrogen of the air at very low temperatures
B a change in the crystalline structure of tin
C an interaction with water vapour contained in the humid air
D a change in the partial pressure of oxygen in the air.

The correct answer is:
a change in the crystalline structure of tin

Solution:
As temperature decreases, white tin (Î²-form) changes to grey tin (Î±-form)
α−Sn ⇌ 13.2 o C β−Sn
Î±-Sn has a much lower density then Î²-Sn.

Topic: Chemistry, p Block Elements (Group 13 & 14), NEET
The solid linear cytoskeletal elements having a diameter of 7 nm and made up of a single type of monomer are known as:

Options:
A Microtubules
B Microfilaments
C Intermediate filaments
D Lamins

The correct answer is:
Microfilaments

Solution:
Microfilaments or actin filaments are long cytoskeletal filaments present in the cytoplasm of the eukaryotic cells. These filaments are primarily composed of polymers of actin and are 7 nm in length. The globular monomeric actin polymerizes to form the filamentous F-actin.

Topic: Biology, Cell - The Unit of Life, NEET, NEET 2014
The solids which have the negative temperature coefficient of resistance are:

Options:
A insulators only
B semiconductors only
C insulators and semiconductors
D metals

The correct answer is:
insulators and semiconductors

Solution:
The solids which have the negative temperature coefficient of resistance means the resistance of these solid will decrease when temperature increases due to more no of free electron at higher temperature. It happens in both insulators and semiconductors.

Topic: Physics, Semiconductors, NEET, NEET 2020 (Phase 1)
The solubility in terms of Ksp for A3B(aq) is

Options:
A Ksp31/4
B Ksp271/4
C (27Ksp)1/4
D (3Ksp)1/4

The correct answer is:
Ksp271/4

Solution:
A 3 B(aq)⇌ 3A + 3s + B 3− s
Ksp=27s3Ãs
=27s4
s=Ksp271/4

Topic: Chemistry, Ionic Equilibrium, NEET
The solubility of AgCls with solubility product 1.6Ã10-10 in 0.1 M NaCl solution would be

Options:
A 1.26Ã10-5Â M
B 1.6Ã10-9 M
C 1.6Ã10-11Â M
D 1.26Ã10-15 M

The correct answer is:
1.6Ã10-9 M

Solution:
The phenomenon in which the addition of an ion common to two solutes causes precipitation or reduces ionization is known as common ion effect.
∴KspAgCl=SS+0.1
∵S≪0.1
∴S+0.1 ≈0.1
∴1.6×10-10=S×0.1
∴S=1.6×10-9 M

Topic: Chemistry, Ionic Equilibrium, NEET, NEET 2016 (Phase 2)
The solubility of AgCls with solubility product 1.6Ã10-10 in 0.1 M NaCl solution would be

Options:
A 1.26Ã10-5Â M
B 1.6Ã10-9 M
C 1.6Ã10-11Â M
D 1.26Ã10-15 M

The correct answer is:
1.6Ã10-9 M

Solution:
â´KspAgCl=SS+0.1
âµSâª0.1
â´S+0.1 â0.1
â´1.6Ã10-10=SÃ0.1
â´S=1.6Ã10-9 M

Topic: Chemistry, Ionic Equilibrium, NEET
The solubility of AgI in NaI solution is less than that in pure water because

Options:
A AgI forms complex with NaI
B of common ion effect
C solubility product of AgI is less than that of NaI
D the temperature of the solution decreases

The correct answer is:
of common ion effect

Solution:
The solubility of AgI in NaI solution is less than that in pure water because of common ion effect.
AgI(s)⇌Ag+(aq)+I-(aq)
The common ion, I- , obtained from strong electrolyte NaI shifts the equilibrium from left to right and this results in the decreases of solubility of AgI.

Topic: Chemistry, Ionic Equilibrium, NEET
The solubility of BaSO4 in water is 2.42Ã10-3 gL-1 at 298 K. The value of its solubility product (Ksp) will be (Given molar mass of BaSO4=233 gmol-1 )

Options:
A 1.08Ã10-14 mol2L-2
B 1.08Ã10-12 mol2L-2
C 1.08Ã10-10 mol2L-2
D 1.08Ã10-8 mol2L-2

The correct answer is:
1.08Ã10-10 mol2L-2

Solution:
Solubility of BaSO 4 ,s= 2.42× 10 −3 233 molL −1
=1.04Ã10-5(molL-1)
BaSO 4 s â Ba 2+ s aq + SO 4 2â s sq
Ksp=[Ba2+][SO42-]=s2
=(1.04Ã10-5)2
=1.08Ã10-10mol2L-2

Topic: Chemistry, Ionic Equilibrium, NEET
The solubility of BaSO4 in water is 2.42×10-3 gL-1 at 298 K. The value of its solubility product Ksp will be
(Given- the molar mass of BaSO4=233 g mol-1)

Options:
A 1.08×10-14 mol2 L-2
B 1.08×10-12 mol2 L-2
C 1.08×10-10 mol2 L-2
D 1.08×10-8 mol2 L-2

The correct answer is:
1.08×10-10 mol2 L-2

Solution:
Solubility of BaSO4=2.42×10-3 gL-1
∴ s=2.42×10-3233=1.038×10-5 mol L-1
Ksp=s2=1.038×10-52
=1.08×10-10 mol2 L-2

Topic: Chemistry, Ionic Equilibrium, NEET, NEET 2018
The solubility of oxygen is

Options:
A 20-25 times higher than carbon dioxide
B 20-25 times lower than carbon dioxide
C 10-15 times higher than carbon dioxide
D 10-15 times lower than carbon dioxide

The correct answer is:
20-25 times lower than carbon dioxide

Solution:
Oxygen is 20-25 less soluble than carbon dioxide. Carbon dioxide when dissolves in water interacts with surrounding water molecules to hydrate itself and thus the interactions are very strong to dissolve more and more molecules.

Topic: Biology, Breathing and Exchange of Gases, NEET
The solubility of Pb(OH)2 in pure water is 203×10-6M . Calculate concentration of OH- ion in a buffer solution of PH=8 .

Options:
A 203×10-6M
B 103×10-6M
C 10-6M
D 2×10-6M

The correct answer is:
10-6M

Solution:
As pH = 8
So [H+]=10-8
[OH-]=Kw[H+]
[OH-]=10-1410-8=10-6

Topic: Chemistry, Ionic Equilibrium, NEET
The solubility of Sr(OH)2at 298 K is 19.23 g/L of solution. Calculate the concentrations of strontium and hydroxyl ions and the pH of the solution.

Options:
A [Sr2+] = 0.15 M, [OH-] = 0.31 M, pH = 13.50
B [Sr2+] = 0.08 M, [OH-] = 0.16 M, pH = 12.00
C [Sr2+] = 0.16 M, [OH-] = 0.08 M, pH = 12.60
D [Sr2+] = 0.04 M, [OH-] = 0.02 M, pH = 13.80

The correct answer is:
[Sr2+] = 0.15 M, [OH-] = 0.31 M, pH = 13.50

Solution:
Correct Option is : (A)
[Sr2+] = 0.15 M, [OH-] = 0.31 M, pH = 13.50

Topic: Chemistry, Ionic Equilibrium, NEET
The solubility of the alkaline earth's metal sulphates in water decreases in the sequence:

Options:
A Mg>Ca>Sr>Ba
B Ca>Sr>Ba>Mg
C Sr>Ca>Mg>Ba
D Ba>Mg>Sr>Ca

The correct answer is:
Mg>Ca>Sr>Ba

Solution:
The lattice energies of alkaline earth sulphates are almost constant, but Hydration energy∝1Size of cation
For Mg2+→Ca2+→Sr2+→Ba2+ , the cationic size increases, so the hydration energy decreases, i.e. MgSO4 is soluble and BaSO4 is a precipitate.
MgSO4>CaSO4>SrSO4>BaSO4

Topic: Chemistry, s Block Elements, NEET, NEET 2015 (Phase 1)
The solubility order for alkali metal fluoride in water is :

Options:
A LiF<RbF<KF<NaF
B RbF<KF<NaF<LiF
C LiF<NaF<KF<RbF
D LiF>NaF>KF>RbF

The correct answer is:
LiF<NaF<KF<RbF

Solution:
lattice enthalpy â1Solubility
Since the lattice enthalpy follow the order
LiF > NaF > KF > RbF
Hence, the correct order of solubility is
LiF<NaF<KF<RbF

Topic: Chemistry, s Block Elements, NEET
The solubility product constant of Ag2CrO4and AgBr are 1.1 × 10-12and 5.0 × 10-13respectively. Calculate the ratio of the molarities of their saturated solutions.

Options:
A [Ag2CrO4] / [AgBr] = 0.22
B [Ag2CrO4] / [AgBr] = 0.20
C [Ag2CrO4] / [AgBr] = 92
D [Ag2CrO4] / [AgBr] = 2.2

The correct answer is:
[Ag2CrO4] / [AgBr] = 92

Solution:
Correct Option is : (C)
[Ag2CrO4] / [AgBr] = 92

Topic: Chemistry, Ionic Equilibrium, NEET
The solubility product for a salt of the type AB is 4×10-8. What is the molarity of its saturated solution?

Options:
A 2×10-4 mol/L
B 16×10-16 mol/L
C 2×10-16 mol/L
D 4×10-4 mol/L

The correct answer is:
2×10-4 mol/L

Solution:
Ksp for AB=s2=4×10-8
∴ Molarity of solution = solubility =Ksp
=4×10-8
=2×10-4 mol/L

Topic: Chemistry, Ionic Equilibrium, NEET, NEET 2020 (Phase 2)
The solubility product of Ag2CrO4 is 32×10-12. What is the concentration of CrO4- ions in that solution?

Options:
A 2Ã10-4 M
B 16Ã10-4Â M
C 8Ã10-4Â M
D 8Ã10-8Â M

The correct answer is:
2Ã10-4 M

Solution:
Aâ¡ gâ¡ 2 Câ¡ râ¡ Oâ¡ 4 â 2 Aâ¡ gâ¡ + + Câ¡ râ¡ Oâ¡ 4 2 - sâ¡ 2 sâ¡ sâ¡
Ksp=2s2s=4s2
s=Ksp413=32Ã10-12413=2Ã10-4 M

Topic: Chemistry, Ionic Equilibrium, NEET
The solubility product of AgCl is 1.8 Ã 10â10. Precipitation of AgCl will occur only when equal volumes of which of the following solutions are mixed?

Options:
A 10â4 M Ag+ and 10â4 M Clâ
B 10â7Â MÂ Ag+ and 10â7Â MÂ Clâ
C 10â5Â MÂ Ag+ and 10â5Â MÂ Clâ
D 10â10Â MÂ Ag+ and 10â10Â MÂ Clâ

The correct answer is:
10â4 M Ag+ and 10â4 M Clâ

Solution:
After mixing,
Ag+=12 Ã 10â4=5 Ã 10â5 M
Clâ =12Ã 10â4=5 Ã 10â5 M
Q sp = Ag + Cl â = 5 Ã 10 â5 2 =2.5 Ã 10 â9
Since, Q sp > K sp â precipition takes place

Topic: Chemistry, Ionic Equilibrium, NEET