datavorous/entrance-exam-dataset huggingface dataset:
Match the columns with respect to discovery of photosynthesis

Column I	Column II

(1)	Action spectrum of photosynthesis	(A)	Julius Von Sachs

(2)	Production of glucose when plant grow	(B)	Joseph Priestley

(3)	Only the green part of the plants that release oxygen	(C)	T.W. Englemann on Cladophora

(4)	Role of air in the growth of green plant	(D)	Jan Ingenhousz

Options:
A 1-B, 2-C, 3- D, 4- A
B 1-C, 2- A, 3- D, 4-B
C 1-C, 2-A, 3-B, 4- D
D 1-C, 2-D, 3- A, 4-B

The correct answer is:
1-C, 2- A, 3- D, 4-B

Solution:
Experiments	Result / Observation / Inference

Joseph Priestley	A burning candle if placed in a bell jar, soon gets extinguished. A mouse if placed in a bell jar, soon gets suffocated. When a mint plant in the same bell jar, mouse stayed alive and also the candle continued to burn.	Conclusion : Both burning candle or animals that breathe the air damage the air while the plants restore to the air.

Jan Ingenhousz	He used a similar setup as the one used by Priestley and placed the aquatic plants once in the sunlight and then in the dark.	Inference : Sunlight is essential for photosynthesis and only the green part of the plants could evolve oxygen.

Julius von Sachs	He provided evidence for production of glucose when plants grow. Glucose is usually stored as starch. His later studies showed that the green substance in plants is located in special bodies within plant cells.	Green parts in plants is
where glucose is made, and that the glucose is usually stored as starch.

T.W. Engelmann	He used a prism to split light into its spectral components and then illuminated a green alga, Cladophora. This alga was placed in a suspension of aerobic bacteria (to detect the sites of O 2 evolution).	First action spectrum of photo- synthesis was known.

Topic: Biology, Photosynthesis in Higher Plants, NEET
Match the columns:-

Options:
A (A)-(i);Â (B)-(ii);Â (C)-(iii);Â (D)-(iv)
B (A)-(iv); (B)-(iii); (C)-(ii); (D)-(i)
C (A)-(ii);Â (B)-(iii);Â (C)-(iv);Â (D)-(i)
D (A)-(iii);Â (B)-(iv);Â (C)-(i);Â (D)-(ii)

The correct answer is:
(A)-(iv); (B)-(iii); (C)-(ii); (D)-(i)

Solution:
During prophase, the nucleolus and nuclear membrane disappear and spindle grows between the centrosomes. The chromosomes get arranged at the equator of the cell during metaphase by the formation of spindle poles oppositely. Centromere splits, sister chromatids are broken down and chromatids are separated during anaphase and daughter chromosomes start moving towards the opposite poles. Nuclear membrane, nucleolus and ER reappears during telophase, thus two nuclei are formed.

Topic: Biology, Cell Cycle and Cell Division, NEET
Match the compound with the metal for which it is used for the process of extraction.

(i) NaCN (a) Titanium

(ii) Iodine (b) Aluminium

(iii) Cryolite (c) Silver ore

Options:
A

(i)-(c),(ii)-(a),(iii)-(b)

B

(i)-(c),(ii)-(b),(iii)-(a)

C

(i)-(a),(ii)-(c),(iii)-(b)

D

(i)-(b),(ii)-(a),(iii)-(c)

The correct answer is:

(i)-(c),(ii)-(a),(iii)-(b)

Solution:
(i) Role of NaCN in the extraction of silver is to do the leaching of silver ore in the presence of air from which the silver is obtained later by replacement 4Ag(s)+8C N â (aq)+2 H 2 O(aq)+ O 2 (g)â Ag (CN) 2 â (aq)+4O H â (aq) 2 Ag (CN) 2 â (aq)+Zn(s)â2Ag(s)+ Zn (CN) 4 2â (aq)
(ii) Ti+ I 2 â Î TiI 4 â Î Ti+ I 2 (Van-Arkel method)
(iii) In the metallurgy of aluminium, cryolite lowers the melting point of the mixture and improves the electrical conductivity of the cell.

Topic: Chemistry, General Principles and Processes of Isolation of Metals, NEET
Match the compounds given in column I with the hybridization and shape given in column II and mark the correct option.

Column I	Column II

(a)	XeF6	(i)	Distorted octahedral

(b)	XeO3	(ii)	Square planar

(c)	XeOF4	(iii)	Pyramidal

(d)	XeF4	(iv)	Square pyramidal

Options:
A abciiiiiv dii
B abciiiiv diii
C abciviiii dii
D abciviii diii

The correct answer is:
abciiiiiv dii

Solution:
Molecule	Hybridization	Shape as per VSEPR Theory
1	XeF6	sp3d3	Distored octahedron
2	XeO3	sp3	Pyramidal
3	XeOF4	sp3d2	Square Pyramidal
4	XeF4	sp3d2	Square planar

Topic: Chemistry, Chemical Bonding and Molecular Structure, NEET, NEET 2016 (Phase 1)
Match the compounds of Xe in column I with the molecular structure in column II.

Column-I	Column-II

(a)	XeF2	(p)	Square planar

(b)	XeF4	(q)	Linear

(c)	XeO3	(r)	Square pyramidal

(d)	XeOF4	(s)	Pyramidal

Options:
A (a)-(q), (b)-(p), (c)-(r), (d)-(s)
B (a)-(q), (b)-(s), (c)-(r), (d)-(p)
C (a)-(q), (b)-(r), (c)-(p), (d)-(s)
D (a)-(q), (b)-(p), (c)-(s), (d)-(r)

The correct answer is:
(a)-(q), (b)-(p), (c)-(s), (d)-(r)

Solution:

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), NEET, NEET 2020 (Phase 2)
Match the contents of the following columns

Animal	Level of Organization	Phylum

A. Jelly Fish	I. Organ	w. Platyhelminthes

B. Sponges	II. Tissue	x. Annelida

C. Hirudinaria	III. Organ system	y. Cnidaria

D. Taenia	IV. Cellular	z. Porifera

Options:
A A-III-x ; B-II-y ; C-I-w ; D-IV-z
B A-II-y ; B-IV-z ; C-III-x ; D-I-w
C A-I-z ; B-III-w ; C-IV-y ; D-II-x
D A-IV-w ; B-I-x ; C-II-z ; D-III-y

The correct answer is:
A-II-y ; B-IV-z ; C-III-x ; D-I-w

Solution:
Jelly fish belong to Phylum Cnidaria and have tissue level organization. Sponges belong to Phylum Porifera and have cellular level organization. Hirudinaria (Leech) belong to Phylum Annelida and have organ system level organization. Taenia belong to Phylum Platyhelminthes and have organ level organization

Topic: Biology, Animal Kingdom, NEET
Match the coordination number and type of hybridisation with distribution of hybrid orbitals in space based on Valence bond theory.

Coordination number and type of hybridisation	Distribution of hybrid orbitals in space

(a)	4,sp3	(p)	trigonal bipyramidal

(b)	4,dsp2	(q)	octahedral

(c)	5,sp3d	(r)	tetrahedral

(d)	6,d2sp3	(s)	square planar

Select the correct option:

Options:
A (a)-(q), (b)-(r), (c)-(s), (d)-(p)
B (a)-(r), (b)-(s), (c)-(p), (d)-(q)
C (a)-(s), (b)-(p), (c)-(q), (d)-(r)
D (a)-(r), (b)-(p), (c)-(s), (d)-(q)

The correct answer is:
(a)-(r), (b)-(s), (c)-(p), (d)-(q)

Solution:
sp3- tetrahedral, dsp2- square planar
sp3d- trigonal bipyramidal, d2sp3- octahedral

Topic: Chemistry, Coordination Compounds, NEET, NEET 2020 (Phase 2)
Match the correct term and meaning.

Term	Meaning

I. Classification	A. Study of organisms and their diversities and the relationships between them.

II. Taxonomy	B. Process by which anything is grouped into categories based on easily observable characters.

III. Systematics	C. Unit of classification

IV. Taxon	D. Process of classification.

Options:
A I - B, II - D, III - A, IV - C
B I - D, II - B, III - A, IV - C
C I - B, II - C, III - D, IV - A
D I - B, II - D, III - C, IV - A

The correct answer is:
I - B, II - D, III - A, IV - C

Solution:
Classification is the process by which anything is grouped into categories based on easily observable characters.
Taxonomy is the process of classification.
Taxon is the unit of classification i.e. the category into which each organism is placed.
Systematics is the study of organisms and their diversities and the relationships between them.

Topic: Biology, The Living World, NEET
Match the corresponding entries of column 1 with column 2. [Where m is the magnification produced by the mirror]

Column 1	Column 2

(A)	m=-2	(a)	Convex mirror

(B)	m=-12	(b)	Concave mirror

(C)	m=+2	(c)	Real image

(D)	m=+12	(d)	Virtual image

Options:
A A → b and c; B → b and c; C → b and d; D → a and d
B A → a and c; B → a and d; C → a and b; D → c and d
C A → a and d; B → b and c; C → b and d; D → b and c
D A → c and d; B → b and d; C → b and c; D → a and d

The correct answer is:
A → b and c; B → b and c; C → b and d; D → a and d

Solution:
m=-Vu=ff-u
m=-2 then "V" and "u" same given
-2=ff-u=-2f+2u=f
=3f=2u
+3f2=u
For the concave mirror, f negative, u negative use same for all.

Topic: Physics, Ray Optics, NEET, NEET 2016 (Phase 1)
Match the disease in Column I with the appropriate items (pathogen/prevention/treatment) in Column II.

Column I	Column II

a) Amoebiasis	i) Treponema pallidum

b) Diphtheria	ii) Use only sterilized food and water

c) Cholera	iii) DPT Vaccine

d) Syphilis	iv) Use oral rehydration therapy

Options:
A a - (i), b - (ii), c - (iii), d- (iv)
B a - (ii), b - (iv), c - (i), d - (iii)
C a - (ii), b - (i), c - (iii), d - (iv)
D a - (ii), b - (iii), c - (iv), d - (i)

The correct answer is:
a - (ii), b - (iii), c - (iv), d - (i)

Solution:
Amoebiasis : Use only sterilised food and water
Diphtheria : DPT Vaccine
Cholera : Use oral rehydration therapy
Syphilis : Treponema pallidum

Topic: Biology, Human Health and Diseases, NEET
Match the disease in Column I with the appropriate items (vector/pathogen/diagnostic test/treatment) in Column II

Column â I	Column - II

a.	Ringworm	i.	Aedes

b.	Ascariasis	ii.	Widal test

c.	Dengue	iii.	Blockage of the intestinal passage

d.	Typhoid	iv.	Trichophyton

Options:
A a-(iv), b-(iii), c-(i), d-(ii)
B a-(ii), b-(iii), c-(i), d-(iv)
C a-(iv), b-(i), c-(ii), d-(iii)
D a-(i), b-(ii), c-(iii), d-(iv)

The correct answer is:
a-(iv), b-(iii), c-(i), d-(ii)

Solution:
Ascaris, an intestinal parasite causes ascariasis. Symptoms of this disease include internal bleeding, muscular pain, fever, anaemia and blockage of the intestinal passage.
Many fungi belonging to the genera Microsporum, Trichophyton and Epidermophyton are responsible for ringworms which is one of the most common infectious diseases in man.
Typhoid is caused by bacteria Salmonella typhii. It is treated by Widal test.
Aedes mosquitoes is responsible for spreading of diseases like dengue and chikungunya.

Topic: Biology, Human Health and Diseases, NEET
Match the disease in Column-I with the appropriate items (pathogen/ prevention/treatment) in Column-II

Options:
A (a)
B (b)
C (c)
D (d)

The correct answer is:
(d)

Solution:
Amoebiasis is caused by Entamoeba histolytica. Prevention of infection is entirely a matter of hygiene, both personal as well as municipal. Their prevention include use of only sterilized food and water.
Diphtheria is caused by corynebacterium diphtheriae. The symptoms are fever, sore throat, severe damage to heart, nerve cell and adrenal glands. The vaccine DPT is used for diphtheria, pertusis and tetanus.
Cholera is caused by Vibrio cholerae, a Gram negative bacterium. It spreads by faecal contamination. The dehydration and loss of mineral salts can cause death. It is treated by use of oral rehydration therapy.
Syphilis is caused by Treponema pallidum, a spirochaete and it spread by sexual contact.

Topic: Biology, Human Health and Diseases, NEET, NEET 2008 (Screening)
Match the disease/condition with their characteristics.

Disease	Symptom

(1)	Haemophilia	(i)	Broad palm with characteristic palm creased

(2)	Downâs syndrome	(ii)	Delayed clotting of blood

(3)	Klinefelterâs syndrome	(iii)	Gynaecomastia

(4)	Turnerâs Syndrome	(iv)	Rudimentary ovaries

Options:
A 1Â -Â i;Â 2Â -Â iii;Â 3Â -Â ii;Â 4Â -Â iv
B 1 - ii; 2 - i; 3 - iii, 4 - iv
C 1Â -Â iv,Â 2Â -Â ii,Â 3Â -Â i,Â 4Â -Â iii
D 1Â -Â i;Â 2Â -Â ii;Â 3Â -Â iii,Â 4âÂ iv

The correct answer is:
1 - ii; 2 - i; 3 - iii, 4 - iv

Solution:
Haemophilia is a disease that results in delayed clotting of blood in the individual. It is a sex-linked disorder passing from mother to son. Down's syndrome is caused due to trisomy of the 21st chromosome in the individual. It is characterized by a broad flat face with palm having creases. When an individual with XY combination has an extra X chromosome attached that condition is termed Klinefelter's syndrome. This individual will show the development of breast (gynecomastia) with overall masculine characteristics. Turner's syndrome is when the chromosome combination is 45+ XO, characterized by having rudimentary sterile ovaries.

Topic: Biology, Principles of Inheritance and Variation, NEET
Match the disorders given in column I with the conditions seen in that disorder given in column II and select the correct option from the codes given below:

No.	(Disorders)	No.	(Conditions seen)

I	Muscular dystrophy	A	Rapid muscular spasms

II	Tetany	B	Fatigue, weakness and paralysis of skeletal system

III	Myasthenia gravis	C	Decreased bone mass

IV	Osteoporosis	D	Progressive degeneration of skeletal muscle

Options:
A I-A, II-D, III-C, IV-B
B I-B, II-C, III-A, IV-D
C I-D, II-A, III-B, IV-C
D I-C, II-B, III-D, IV-A

The correct answer is:
I-D, II-A, III-B, IV-C

Solution:
I. Muscular dystrophy is characterized by progressive degeneration of skeletal muscle. II. Tetany is characterized by rapid muscular spasms. III. Myasthenia gravis is characterized by fatigue, weakness and paralysis of skeletal system. IV. Osteoporosis is characterized by decreased bone mass and increased risk of fractures.

Topic: Biology, Locomotion and Movement, NEET
Match the element in column I with that in column II.

Column-I	Column-II

(a)	Copper	(p)	Non-metal

(b)	Fluorine	(q)	Transition metal

(c)	Silicon	(r)	Lanthanoid

(d)	Cerium	(s)	Metalloid

Identify the correct match :

Options:
A (a)-(q), (b)-(s), (c)-(p), (d)-(r)
B (a)-(q), (b)-(p), (c)-(s), (d)-(r)
C (a)-(s), (b)-(r), (c)-(p), (d)-(q)
D (a)-(p), (b)-(q), (c)-(r), (d)-(s)

The correct answer is:
(a)-(q), (b)-(p), (c)-(s), (d)-(r)

Solution:
Copper - Transition metal
Fluorine - Non metal
Silicon - Metalloids
Cerium - Lanthanoid

Topic: Chemistry, Classification of Elements and Periodicity in Properties, NEET, NEET 2020 (Phase 2)
Match the elements in Column I with methods of purification in Column II.

Column-I	Column-II

(a)	Boron	(p)	Van Arkel method

(b)	Tin	(q)	Mond's process

(c)	Zirconium	(r)	Liquation

(d)	Nickel	(s)	Zone refining

Options:
A (a)-(s), (b)-(r), (c)-(p), (d)-(q)
B (a)-(s), (b)-(r), (c)-(q), (d)-(p)
C (a)-(q), (b)-(p), (c)-(s), (d)-(r)
D (a)-(r), (b)-(s), (c)-(p), (d)-(q)

The correct answer is:
(a)-(s), (b)-(r), (c)-(p), (d)-(q)

Solution:
B - Purified by Zone Refining

Sn - Liquation

Zr - Van arkel method

Ni - Mond's process

Topic: Chemistry, General Principles and Processes of Isolation of Metals, NEET, NEET 2020 (Phase 2)
Match the endocrine glands given in column I with their respective hormones in column II and the functions performed by those hormones in column III and select the correct option from the codes given below.

No.	Endocrine gland	No.	Hormone	No.	Column III (Functions)

I	Neuorohypophysis	A	Cortisol	a	Hypocalcemic hormone

II	Adrenal cortex	B	PTH	b	Prevents excessive urination

III	Thyroid gland	C	Vasopressin	c	Hypercalcemic hormone

IV	Parathyroid gland	D	TCT	d	Anti-inflammatory reaction and suppression of immune response

Options:
A I-C-b, II-A-d, III-B-c, IV-D-a
B I-C-b, II-A-d, III-D-a, IV-B-c
C I-C-b, II-A-d, III-D-c, IV-B-a
D I-B-d, II-B-a, III-C-d, IV-A-b

The correct answer is:
I-C-b, II-A-d, III-D-a, IV-B-c

Solution:
I. Neurohypophysis (posterior pituitary) secretes the hormone vasopressin, also known as anti-diuretic hormone (ADH). This hormone is responsible for reabsorption of water from the renal tubules and hence prevents excessive urination.
II. Adrenal cortex is responsible for secretion of hormone 'cortisol' which is a major glucocorticoid. It is responsible for anti-inflammatory reaction and suppression of immune response.
III. Thyroid gland secretes the hormone thyrocalcitonin (TCT). It is prevents resorption of calcium from the bones. It is a 'hypocalcemic hormone'.
IV. Parathyroid gland secretes parathyroid hormone (PTH). It is rresponsible for resorption if calcium from the bones and also prevents urinary excretion of calcium. Hence, it is a 'hypercalcemic hormone'.

Topic: Biology, Chemical Coordination and Integration, NEET
Match the entries in Column - I with those of Column- II and choose the correct answer

Column - I	Column - I I

(A)	Cleistogamy	(i)	Insect pollination

(B)	Anemophily	(ii)	Bud pollination

(C)	Entomophily	(iii)	Wind pollination

(D)	Xenogamy	(iv)	Bat pollination

(v)	Cross-pollination

Options:
A A - iii; B - i; C - iv; D - ii
B A - ii; B - v; C - i; D - iii
C A - ii; B - iii; C - i; D - v
D A - v; B - iv; C - iii; D - ii

The correct answer is:
A - ii; B - iii; C - i; D - v

Solution:
Cleistogamous flowers do not open at all. In such flowers, the anthers and stigma lie close to each other. When anthers dehisce in the flower buds, pollen grains come in contact with the stigma to effect pollination. Thus, cleistogamous flowers are invariably autogamous as there is no chance of cross-pollen landing on the stigma.
Xenogamy: Transfer of pollen grains from anther to the stigma of a different plant i.e. cross-pollination. This is the only type of pollination which during pollination brings genetically different types of pollen grains to the stigma.
Plants use two abiotic i.e. wind (anemophily) and water(hydrophily) and one biotic (animals) agents to achieve pollination. Pollination by insects is called entomophily.

Topic: Biology, Sexual Reproduction in Flowering Plants, NEET
Match the enzyme in column I with its function in column II and choose the correct option.

Column – I	Column – II

A. β -galactosidase	1. Joining of DNA fragments

B. Permease	2. Peptide bond formation

C. Ligase	3. Hydrolysis of lactose

D. Ribozyme	4. Increases permeability to β -galactosidase

Options:
A ABC214D3
B ABC321D4
C ABC244D3
D ABC124D3

The correct answer is:
ABC321D4

Solution:
β- gal, coded by Z structural gene is primarily responsible for the hydrolysis of the disaccharide lactose into its monomeric units, galactose and glucose.
Ligase is also called the molecular glue. It joins DNA fragments.
Permease is a membrane transport protein which allows increases the permeability of beta galactosidase across the membrane.
Ribozymes are RNA molecules which act as enzymes which is involved in peptide bond formation.

Topic: Chemistry, Biomolecules, NEET
Match the enzymes given in column I with the substrates they act upon in column II and the product obtained from the reaction given in column III and select the correct option from the codes given below.

No.	Enzyme	No.	Substrate	No.	Product

I	Trypsin	i	Polysaccharides	a	Diglycerides

II	Amylase	ii	Nucleic acids	b	Dipeptides

III	Lipase	iii	Proteins	c	Nucleosides

IV	Nuclease	iv	Fats	d	Disaccharides

Options:
A I-iii-b, II-i-d, III-iv-a, IV-ii-c
B I-iii-b, II-iv-a, III-i-d, IV-ii-c
C I-i-b, II-ii-c, III-iii-d, IV-iv-a
D I-ii-a, II-iii-b, III-i-b, IV-iv-d

The correct answer is:
I-iii-b, II-i-d, III-iv-a, IV-ii-c

Solution:
I. Trypsin acts on proteins to form dipeptides.
II. Amylase acts on polysaccharides to form disaccharides.
III. Lipase acts on fats to form diglycerides.
IV. Nuclease acts on nucleic acids to form nucleosides.

Topic: Biology, Digestion and Absorption, NEET
Match the features of given algae with their respective examples:

Features	Organism

1. Filamentous form with flagellated gamete.	a. Ulothrix

2. Colonial oogamous form.	b. Spirogyra

3. Forming Massive plant bodies.	c . Volvox

4. Filamentous form with non motile gamete.	d. Kelps

e. Fucus

Options:
A 1-e, 2-b, 3-d, 4- a
B 1-b, 2-e, 3-d, 4- c
C 1-a, 2-c, 3-d, 4- b
D 1-c, 2-a, 3-e, 4- d

The correct answer is:
1-a, 2-c, 3-d, 4- b

Solution:
The form and size of algae is highly variable in size, ranging from colonial forms like Volvox, the filamentous forms like Ulothrix and Spirogyra and the marine forms like kelps which form massive plant bodies. Sexual reproduction takes place through fusion of two gametes. These gametes can be flagellated and similar in size as in Ulothrix or non-flagellated (non motile) but similar in size as in Spirogyra. Fusion between one large, non motile female gamete and a smaller motile male gamete is termed as oogamous eg; Volvox, Fucus

Topic: Biology, Plant Kingdom, NEET
Match the following:

(a)	Aquaporin	(i)	Amide

(b)	Asparagine	(ii)	Polysaccharide

(c)	Abscisic acid	(iii)	Polypeptide

(d)	Chitin	(iv)	Carotenoids

Select the correct option:

Options:
A (a)-(iii),(b)-(i),(c)-(iv),(d)-(ii)
B (a)-(ii), (b)-(iii), (c)-(iv), (d)-(i)
C (a)-(ii), (b)-(i), (c)-(iv), (d)-(iii)
D (a)-(iii), (b)-(i), (c) -(ii), (d)-(iv)

The correct answer is:
(a)-(iii),(b)-(i),(c)-(iv),(d)-(ii)

Solution:
Aquaporins are protein ion channels that facilitate the transport of water. Thus, chemically they are polypeptide in nature.

Asparagine is an amino acid with -CONH2 group in the side chain. Thus, it is chemically an amide.

Chitin is a mucopolysaccharide of the monomer N-acetylglucosamine. It is found in the cell wall of fungi and in the exoskeleton of arthropods.

Abscisic acid (ABA), synthesised in response to water stress, is an apocarotenoid.

Topic: Biology, Biomolecules (B), NEET, NEET 2020 (Phase 2)
Match the following.

âAâ	âBâ

(A)	Auxin	(I)	Ripening and maturity of fruits

(B)	Gibberellin	(II)	Differentiation of xylem elements

(C)	Cytokinin	(III)	Prevention of genetic and physiological dwarfism

(D)	Ethylene	(IV)	Found from tumour tissue of tobacco

Options:
A (A)-(IV);(B)-(III);(C)-(II);(D)-(I)
B (A)-(IV);(B)-(II);(C)-(III);(D)-(I)
C (A)-(II);(B)-(III);(C)-(IV);(D)-(I)
D (A)-(III);(B)-(IV);(C)-(II);(D)-(I)

The correct answer is:
(A)-(II);(B)-(III);(C)-(IV);(D)-(I)

Solution:
Auxins are used for the differentiation of xylem elements, gibberellin is used for the removal of dwarfism and used for inter-nodal elongation. Cytokinin is a modified form of adenine and found in tumour cell of tobacco and used for overcoming apical dominance. Ethylene is a ripening hormone.

Topic: Biology, Plant - Growth and Development, NEET
Match the following:

a	Pure nitrogen	i	Chlorine

b	Haber process	ii	Sulphuric acid

c	Contact process	iii	Ammonia

d	Deacon’s process	iv	Sodium azide or Barium azide

Which of the following is the correct option?

Options:
A a-i; b-ii; c-iii; d-iv
B a-ii; b-iv; c-i; d-iii
C a-iii; b-iv; c-ii; d-i
D a-iv; b-iii; c-ii; d-i

The correct answer is:
a-iv; b-iii; c-ii; d-i

Solution:
Haber's process is the industrial process for production of ammonia.
Contact process is the industrial process for production of sulphuric acid.
Pure nitrogen is prepared from sodium azide.
Deacon's process is the commercial preparation of chlorine.

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), NEET, NEET 2019 (All India)
Match the following and choose the correct combination from given options.

Column-I	Column- II

(A) Sulphur	(1) Chlorophyll

(B) Zinc	(2) Nitrogenase

(C) Magnesium	(3) Methionine

(D) Molybdenum	(4) Auxin

Options:
A A B C D 1 2 3 4
B A B C D 3 4 1 2
C A B C D 3 1 2 4
D A B C D 2 4 1 3

The correct answer is:
A B C D 3 4 1 2

Solution:
Column I	Column II

Sulphur	Methionine

Zinc	Auxin

Magnesium	Chlorophyll

Molybdenum	Nitrogenase

Topic: Biology, Mineral Nutrition, NEET
Match the following and choose the correct combination from the options given.

Column I	Column II

A.	Mustard	1.	Polyadelphy

B.	Brinjal	2.	Diadelphy

C.	Citrus	3.	Variations in the length of filaments

D.	Pea	4.	Epipetalous stamens

Options:
A A-4,Â B-3,Â C-2,Â D-1
B A-1,Â B-2,Â C-3,Â D-4
C A-2,Â B-3,Â C-4,Â D-1
D A-3, B-4, C-1, D-2

The correct answer is:
A-3, B-4, C-1, D-2

Solution:
Pisum sativum, beans, gram etc. belong to family Fabaceae and root of all members of Fabaceae contains root nodules that have nitrogen fixing bacteria and they shows the presence of diadelphous stamen whereas potato, tomato, brinjal are included in family Solanaceae which shows bicarpellary, syncarpous and superior ovary and their Stamens are five in number, epipetalous (stamens attached to petals)

Topic: Biology, Morphology of Flowering Plants, NEET