datavorous/entrance-exam-dataset huggingface dataset:
Colour-blindness occurs in

Options:
A Males having colour blind father and normal mother
B Females having colour blind father and normal mother
C Females having colour blind father and carrier mother
D Males have normal father and mother.

The correct answer is:
Females having colour blind father and carrier mother

Solution:
Colour blindness is a recessive sex-linked trait in which the eye fails to distinguish red-green colours. The gene for normal vision is dominant. The normal gene and its recessive alleles are carried by X-chromosome. In female, colour blindness appears only when both the sex chromosomes carry the recessive gene (XcXc). The females have normal vision but function as carrier if a single recessive gene for colour blindness is present (XXc). However, in human males the defect appears in the presence of a single recessive gene (XcY) because Y-chromosomes of males do not carry any gene for colour vision. Colour blindness, like other sex-linked trait, shows criss-cross inheritance (i.e., a male transmits his trait to his grandson through daughter, while a female transmits the traits to her grand-daughter through her son or it is transfer of trait from one sex to the offspring of the opposite sex).

Topic: Biology, Principles of Inheritance and Variation, NEET
Column - I gives certain physical terms associated with flow of current through a metallic conductor. Column - II gives some mathematical relations involving electrical quantities. Match Column - I and Column - II with appropriate relations.

Column - I	Column - II

(A) Drift Velocity	Pmne2ρ

(B) Electrical Resistivity	Qnevd

(C) Relaxation Period	ReEmτ

(D) Current Density	SEJ

Options:
A (A)-(R),(B)-(S),(C)-(P),(D)-(Q)
B (A)-(R),(B)-(S),(C)-(Q),(D)-(P)
C (A)·(R),(B)-(P),(C)-(S),(D)-(Q)
D (A)-(R),(B)-(Q),(C)-(S),(D)-(P)

The correct answer is:
(A)-(R),(B)-(S),(C)-(P),(D)-(Q)

Solution:
Drift velocity, V=eEmτ

Electrical resistivity, ρ=EJ

Relaxation period, τ=mne2ρ

Current Density, J=neVd

A-R, B-S, C-P, D-Q

Topic: Physics, Current Electricity, NEET, NEET 2021
Column I lists the components of body defence and column II lists the corresponding descriptions. Match the two column. Choose the correct option from those given.

Column-I	Column- II

(A)	Active natural immunity	(1)	Injection of gamma globulins

(B)	First line of defence	(2)	Complement proteins and interferons

(C)	Passive natural immunity	(3)	Direct contact with the pathogens that have entered inside

(D)	Second line of defence	(4)	Surface barriers

(5)	Antibodies transferred through the placenta

Options:
A A B C D 4 3 5 2
B A B C D 3 4 2 5
C A B C D 3 4 5 2
D A B C D 5 3 2 1

The correct answer is:
A B C D 3 4 5 2

Solution:
Column I	Column II

Active natural immunity	Direct contact with the pathogens that have entered inside

First line of defence	Surface barriers

Passive natural immunity	Antibodies transferred through the placenta

Second line of defence	Complement proteins and interferons

Topic: Biology, Human Health and Diseases, NEET
Comb plates for locomotion are found in:

Options:
A Porifera
B Cnidaria
C Ctenophora
D Mollusca

The correct answer is:
Ctenophora

Solution:
Ctenophores are characterized by eight rows of cilia, which are used for locomotion. The cilia in each row are arranged to form a stack of combs, also called comb plates; thus, the name ctenophore comes from the Greek word meaning 'comb bearer'.

Topic: Biology, Animal Kingdom, NEET
Comment on the following observation: Lithium is the only alkali metal to form a nitride directly.

Options:
A This is due to the smaller size and higher charge density of lithium.
B This is because lithium has the highest atomic number in the alkali metal group.
C This is a result of the higher electronegativity of lithium compared to other alkali metals.
D This is due to the higher ionization energy of lithium.

The correct answer is:
This is due to the smaller size and higher charge density of lithium.

Solution:
Correct Option is : (A)
This is due to the smaller size and higher charge density of lithium.

Topic: Chemistry, s Block Elements, NEET
Comment on the following observation: The mobilities of the alkali metal ions in aqueous solution are Li+< Na+< K+< Rb+< Cs+.

Options:
A The mobility of alkali metal ions is inversely proportional to their ionic radii.
B The mobility of alkali metal ions is directly proportional to their atomic masses.
C The mobility of alkali metal ions is directly proportional to their charge densities.
D The mobility of alkali metal ions is directly proportional to their electronegativities.

The correct answer is:
The mobility of alkali metal ions is directly proportional to their charge densities.

Solution:
Correct Option is : (C)
The mobility of alkali metal ions is directly proportional to their charge densities.

Topic: Chemistry, s Block Elements, NEET
Comment on the nature of two S–O bonds formed in SO2molecule. Are the two S–O bonds in this molecule equal?

Options:
A The bonds are purely ionic.
B The bonds are purely covalent.
C The bonds are polar covalent.
D The bonds are of different lengths.

The correct answer is:
The bonds are polar covalent.

Solution:
Correct Option is : (C)
The bonds are polar covalent.

Topic: Chemistry, p Block Elements (Group 13 & 14), NEET
Comment on the thermodynamic stability of NO(g), given: 1/2 N2(g) + 1/2 O2(g) → NO(g) ; ∆rH⊖= 90 kJ mol–1NO(g) + 1/2 O2(g) → NO2(g) ; ∆rH⊖= –74 kJ mol–1

Options:
A NO(g) is unstable, but it does not get converted to NO2(g)
B NO(g) is stable, so it gets converted to NO2(g)
C NO(g) is unstable, so it gets converted to NO2(g)
D NO(g) is stable, but it does not get converted to NO2(g)

The correct answer is:
NO(g) is unstable, so it gets converted to NO2(g)

Solution:
Correct Option is : (C)
NO(g) is unstable, so it gets converted to NO2(g)

Topic: Chemistry, Thermodynamics (C), NEET
Common bile duct is form by the union of

Options:
A right and left hepatic ducts
B right and left cystic ducts
C common hepatic duct and cystic duct
D left hepatic duct and cystic duct

The correct answer is:
common hepatic duct and cystic duct

Solution:
Accessory glands in digestion are liver and pancreas. Ducts of these glands finally open into the duodenum. These ducts unite at various levels. The liver consists of right and left lobes through which righ and left hepatic ducts arise. These ducts collect bile formed by hepatic cells and unite and form a hepatic duct that further unites with the cystic duct of gall bladder. This is known as the common bile duct. This duct contains concentrated bile from gall bladder and dilute bile from liver. The common bile duct is also known as duct choledochus (chole means bile). This duct then unites with the duct of Wirsung (pancreatic duct) to form the hepatopancreatic duct that opens into the duodenum.

Topic: Biology, Digestion and Absorption, NEET
Common characters present between bryophytes and pteridophytes are

Options:
A Possess distinct gametophytic and sporophytic generations and multicellular sex organs
B Heteromorphic alternation of generation and rhizoids
C Require water for fertilization
D All of these

The correct answer is:
All of these

Solution:
The bryophytes and pteridophytes both possess distinct gametophytic and sporophytic generations, heteromorphic alternation of generation, presence of rhizoids, multicellular sex organs and require water for fertilization as their sperms are motile.

Topic: Biology, Plant Kingdom, NEET
Common cold differs from pneumonia in, that

Options:
A pneumonia is a communicable disease, whereas the common cold is a nutritional deficiency disease
B pneumonia can be prevented by a live attenuated bacterial vaccine, whereas the common cold has no effective vaccine
C pneumonia is caused by a virus, while the common cold is caused by the bacterium Haemophilus influenzae
D pneumonia pathogen infects alveoli whereas the common cold affects nose and respiratory passage but not the lungs

The correct answer is:
pneumonia is caused by a virus, while the common cold is caused by the bacterium Haemophilus influenzae

Solution:
Pneumonia is caused by the bacteria Diplococcus pneumoniae which infects the alveoli of lungs. It generally spreads through the sputum of patient. Fever, cold and difficulty in breathing are some common symptons of pneumonia.
Common cold is caused by a variety of viruses, most commonly by rhinovirus (RNA virus). It spreads through droplet infection. It affects the upper respiratory tract but not the lungs. Nasal and bronchial irritation, sneezing and coughing are some common symptoms of cold.

Topic: Biology, Human Health and Diseases, NEET, NEET 2012 (Screening)
Common cold differs from pneumonia in that

Options:
A the causative agent for common cold is bacteria and while for pneumonia is virus
B common cold affects upper respiratory tract while in pneumonia lower respiratory tract including lungs is infected
C a nutritional deficiency can lead to cold while pneumonia is an infectious disease
D there is no vaccine available to prevent either of the two diseases

The correct answer is:
common cold affects upper respiratory tract while in pneumonia lower respiratory tract including lungs is infected

Solution:
Common cold and Pneumonia both are infections of the respiratory tract. The common cold is a viral infection caused by Rhinoviruses while pneumonia is caused by bacteria like Streptococci and Haemophilus influenza. The common cold affects the upper respiratory tract while pneumonia affects the lower respiratory tract. Both are infectious conditions.

Topic: Biology, Human Health and Diseases, NEET
Common detritivores in our ecosystem are___.

Options:
A autotrophs
B light
C earthworms
D inverted

The correct answer is:
earthworms

Solution:
Common detritivores in our ecosystem are earthworms.

Topic: Biology, Ecosystem, NEET
Common features of striated and faintly striated cardiac muscles are

a Presence of troponin.
b Use of Ca2+ for muscle contraction.
c Vascularity
d Gap junctions.
e Control by Visceral Nervous System (ANS).

Which of these features are correct?

Options:
A b, c, d & e
B a, b & e
C a, b & c
D a, b, c & d

The correct answer is:
a, b & c

Solution:
Human muscles are classified into three types depending on location, function and structure. These three types are: 1) Skeletal or striated or voluntary 2) Smooth or involuntary or non striated 3) Cardiac muscles
Cardiac muscles are muscles related to the walls of the heart. These muscles are structurally like skeletal but functionally resemble smooth muscles. These have striations and thus contraction and relaxation results use muscle proteins like troponin , actin , myosin and tropomyosin. Gap junctions are seen in smooth and cardiac muscle.

Topic: Biology, Structural Organisation in Animals, NEET
Common indicator organism of water pollution is:

Options:
A Lemna pancicostata
B Eichhornia crassipes
C Escherichia coli
D Entamoeba histolytica.

The correct answer is:
Escherichia coli

Solution:
The most common indicators are Coliforms, E. coli, and Enterococci. The presence of bacteria commonly found in human faeces, termed coliform bacteria (e.g., E. coli), in surface water is a common indicator of faecal contamination.
Related Theory
Indicators of potential human or fecal contamination or of possible presence of pathogens include Staphylococci, Escherichia coli, fecal coliforms, Enterococci and Pseudomonas aeruginosa. Indicator organisms are used to assess overall sanitation or environmental conditions that may signal or indicate the potential presence of pathogens of food safety concern. It is important to note that indicator species are not necessarily pathogenic.

Topic: Biology, Environmental Issues, NEET, NEET 2004
Common liverwort or umbrella liverwort is a common name for

Options:
A Marchantia
B Riccia
C Funaria
D Sphagnum

The correct answer is:
Marchantia

Solution:
Asexual reproduction in some liverworts like Marchantia takes place by the formation of specialized structures called gemma cups. Gemmae are green, multicellular, asexual buds which develop in small receptacles called gemma cups located on thalli, they are also called as common liverwort or umbrella liverwort.

Topic: Biology, Plant Kingdom, NEET
Common pansy has:

Options:
A Cleistogamous flowers
B Chasmogamous flowers
C Unisexual flowers
D Both (A) and (B)

The correct answer is:
Both (A) and (B)

Solution:
Chasmogamous means the flowers that bloom. Cleistogamous means the flowers that do not open at all. This way only the pollen grains of the same flower will pollinate the flower. So is a device for self-pollination. Viola (Common pansy), Oxalis and Commelina produce chasmogamous as well cleistogamous flowers.

Topic: Biology, Sexual Reproduction in Flowering Plants, NEET
Commonly used vectors for human genome sequencing are:

Options:
A T - DNA
B BAC and YAC
C Expression Vectors
D T/A Cloning Vectors

The correct answer is:
BAC and YAC

Solution:
A bacterial artificial chromosome (BAC) are the plasmids usually applied for the transformation and cloning in bacterial cells, generally E. coli. The usual BAC insert size is around 150-350 Kbp. A similar cloning vector named as PAC has also been developed from the bacterial P1-plasmid. BACs are mostly applied for sequencing purposes in genome projects, as they can be inserted with long size of DNA fragments.

Yeast artificial chromosomes (YACs) are genetically engineered chromosomes modified from the DNA of the yeast, that is further ligated into a bacterial plasmid. By insertion of large DNA fragments, around 100–1000 Kbp in size, the inserted sequences are usually cloned and then the physical mapping is employed by a process known as chromosome walking.

Topic: Biology, Biotechnology - Principles and Processes, NEET, NEET 2014
Companion cells are closely associated with

Options:
A Sieve elements
B Vessel elements
C Trichomes
D Guard cells

The correct answer is:
Sieve elements

Solution:
Sieve tubes are found associated with companion cells of angiosperms. Both sieve tube member and companion cell are derived from the same meristematic cell. Companion cell is nucleated. These cells provide energy for food conduction.

Topic: Biology, Anatomy of Flowering Plants, NEET
Companion cells are present in the phloem of

Options:
A Pteriophytes
B Gymnosperms
C Angiosperms
D Both 1 and 2

The correct answer is:
Angiosperms

Solution:
Companion cell is a type of cell found within the phloem of flowering plants. Each companion cell is usually closely associated with a sieve element. Its function is uncertain, though it appears to regulate the activity of the adjacent sieve element and to take part in loading and unloading sugar into the sieve element.

Topic: Biology, Anatomy of Flowering Plants, NEET
Comparable to angiosperms which of the following algae exhibits diplontic life cycle?

Options:
A Spirogyra
B Ectocarpus
C Polysiphonia
D Fucus

The correct answer is:
Fucus

Solution:
The diplontic life cycle is shown by the developed vascular plants. In plants showing this type of life-cycle, the dominant photosynthetic phase, is the diploid sporophyte. The haploid phase is represented by a short-lived and one or a few celled gametophytes eg: all gymnosperm, all angiosperm and algae-like fucus.

Topic: Biology, Reproduction in Organisms, NEET
Compare bond angles for the following molecules

Options:
A x > y
B y > x
C x = y
D None of these

The correct answer is:
x > y

Solution:
Bond angle∝ 1 electronegativity of surrounding atom
As Electronegativity of F is higher than that of H, hence x > y.

Topic: Chemistry, Chemical Bonding and Molecular Structure, NEET
Compare bond lengths (x and y) for the following molecules

Options:
A x > y
B y > x
C x = y
D None of these

The correct answer is:
y > x

Solution:
x = 153.9 pm
y = 154.5 pm
Lone pair has more s%-character than the multiple bond, hence orbital having lone pair has more s%-character and other orbital has less s%-character. s% decreases bond length increases.

Topic: Chemistry, Chemical Bonding and Molecular Structure, NEET
Compare the alkali metals and alkaline earth metals with respect to (i) ionisation enthalpy (ii) basicity of oxides and (iii) solubility of hydroxides.

Options:
A Alkali metals have higher ionization enthalpy, less basic oxides, and more soluble hydroxides compared to alkaline earth metals.
B Alkali metals have lower ionization enthalpy, less basic oxides, and less soluble hydroxides compared to alkaline earth metals.
C Alkali metals have lower ionization enthalpy, more basic oxides, and more soluble hydroxides compared to alkaline earth metals.
D Alkali metals have higher ionization enthalpy, more basic oxides, and less soluble hydroxides compared to alkaline earth metals.

The correct answer is:
Alkali metals have lower ionization enthalpy, more basic oxides, and more soluble hydroxides compared to alkaline earth metals.

Solution:
Correct Option is : (C)
Alkali metals have lower ionization enthalpy, more basic oxides, and more soluble hydroxides compared to alkaline earth metals.

Topic: Chemistry, s Block Elements, NEET
Compare the atomic sizes of the first series of the transition metals with those of the second and third series metals in the respective vertical columns

Options:
A The atomic sizes of the first series of transition metals are generally larger than those of the second and third series metals.
B The atomic sizes of all three series of transition metals are identical.
C The atomic sizes of the second series of transition metals are generally larger than those of the first series metals and almost equal to third series metals.
D The atomic sizes of the third series of transition metals are generally larger than those of the first and second series metals.

The correct answer is:
The atomic sizes of the second series of transition metals are generally larger than those of the first series metals and almost equal to third series metals.

Solution:
Correct Option is : (C)
The atomic sizes of the second series of transition metals are generally larger than those of the first series metals and almost equal to third series metals.

Topic: Chemistry, d and f Block Elements, NEET
Compare the behaviour of hydrides of Vanadium, Ruthenium, Nitrogen and Potassium towards water

Options:
A (V, Ru)H < NH3< KH
B NH3< KH < (V, Ru)H
C KH < (V, Ru)H < NH3
D NH3< (V, Ru)H < KH

The correct answer is:
(V, Ru)H < NH3< KH

Solution:
Correct Option is : (A)
(V, Ru)H < NH3< KH

Topic: Chemistry, Hydrogen, NEET
Compare the boiling points of
1. n-butylamine
2. n-butyl alcohol
3. pentane

Options:
A 2 > 3 > 1
B 2 > 1 > 3
C 1 > 3 > 2
D 3 > 2 > 1

The correct answer is:
2 > 1 > 3

Solution:
N is less electropositive than O, therefore, the H-bonds in the amine (1) are weaker than those in n-butyl alcohol. H-bonding is not possible in pentane (3). Here the boiling point order is as follows
(2) n-butyl alcohol > (1) n-butylamine > (3) pentane

Topic: Chemistry, Chemical Bonding and Molecular Structure, NEET
Compare the boiling points of very dilute solutions of AlCl3(t1) and CaCl2(t2) , both having the same molar concentration

Options:
A t1=t2
B t1>t2
C t2>t1
D t2≥t1

The correct answer is:
t1>t2

Solution:
Δ T b ∝i (Concentration constant)
T b ∝i
AlCl3 furnishes more ions than CaCl2 and thus shows higher boiling point i.e. t1>t2 .

Topic: Chemistry, s Block Elements, NEET
Compare the bond orders of N2, O2, O2+, and O2–

Options:
A N2has the highest bond order, followed by O2+, O2, and O2–in decreasing order.
B O2+has the highest bond order, followed by O2, N2, and O2–in decreasing order.
C O2has the highest bond order, followed by O2+, N2, and O2–in decreasing order.
D O2–has the highest bond order, followed by O2, N2, and O2+in decreasing order.

The correct answer is:
N2has the highest bond order, followed by O2+, O2, and O2–in decreasing order.

Solution:
Correct Option is : (A)
N2has the highest bond order, followed by O2+, O2, and O2–in decreasing order.

Topic: Chemistry, Chemical Bonding and Molecular Structure, NEET
Compare the chemical reactivity of actinoids with that of the lanthanoids

Options:
A Lanthanoids (electropositive and highly reactive) are more reactive than actinoids.
B Actinoids (electropositive and highly reactive) are more reactive than lanthanoids.
C Lanthanoids have similar reactivity to Actinoids
D Cannot be discussed without further information

The correct answer is:
Actinoids (electropositive and highly reactive) are more reactive than lanthanoids.

Solution:
Correct Option is : (B)
Actinoids (electropositive and highly reactive) are more reactive than lanthanoids.

Topic: Chemistry, d and f Block Elements, NEET
Compare the electronic configuration of actinoids with that of the lanthanoids

Options:
A Lanthanoids have general electronic configuration [Xe]4f1−145d0−16s2but Actinoids have general electronic configuration [Rn]5f1−146d0−17s2
B Lanthanoids have general electronic configuration [Xe]4f1−105d0−106s2but Actinoids have general electronic configuration [Rn]5f1−146d07s1
C Lanthanoids have general electronic configuration [Xe]4f1−125d0−56s1but Actinoids have general electronic configuration [Rn]5f1−106d0−57s0
D Lanthanoids have general electronic configuration [Xe]4f1−135d1-36s2but Actinoids have general electronic configuration [Rn]5f1−96d0−77s1

The correct answer is:
Lanthanoids have general electronic configuration [Xe]4f1−145d0−16s2but Actinoids have general electronic configuration [Rn]5f1−146d0−17s2

Solution:
Correct Option is : (A)
Lanthanoids have general electronic configuration [Xe]4f1−145d0−16s2but Actinoids have general electronic configuration [Rn]5f1−146d0−17s2

Topic: Chemistry, d and f Block Elements, NEET
Compare the electronic configurations of the first series of the transition metals with those of the second and third series metals

Options:
A The electronic configurations of the first series metals are characterized by the filling of 3d orbitals, while the second and third series metals fill 4d and 5d orbitals, respectively.
B The electronic configurations of all three series of transition metals are identical.
C The electronic configurations of the first series metals involve the filling of 4d orbitals, while the second and third series metals fill 5d and 6d orbitals, respectively.
D The electronic configurations of the first series metals involve the filling of 5d orbitals, while the second and third series metals fill 6d and 7d orbitals, respectively.

The correct answer is:
The electronic configurations of the first series metals are characterized by the filling of 3d orbitals, while the second and third series metals fill 4d and 5d orbitals, respectively.

Solution:
Correct Option is : (A)
The electronic configurations of the first series metals are characterized by the filling of 3d orbitals, while the second and third series metals fill 4d and 5d orbitals, respectively.

Topic: Chemistry, d and f Block Elements, NEET
Compare the following on the basis of acidity

Options:
A p-Nitrophenol>m-Nitrophenol>o-Nitrophenol
B p-Nitrophenol
C p-Nitrophenol>o-Nitrophenol>m-Nitrophenol
D p-Nitrophenol

The correct answer is:
p-Nitrophenol>o-Nitrophenol>m-Nitrophenol

Solution:
Correct Option is : 3
p-Nitrophenol>o-Nitrophenol>m-Nitrophenol

Topic: Chemistry, Alcohols Phenols and Ethers, NEET
Compare the following on the basis of bond enthalpies

Options:
A CH3F > CH3Cl > CH3Br > CH3I
B CH3F < CH3Cl < CH3Br < CH3I
C CH3F < CH3Cl > CH3Br > CH3I
D CH3F > CH3Cl < CH3Br > CH3I

The correct answer is:
CH3F > CH3Cl > CH3Br > CH3I

Solution:
Correct Option is : 1
CH3F > CH3Cl > CH3Br > CH3I

Topic: Chemistry, Haloalkanes and Haloarenes, NEET
Compare the following on the basis of bond length

Options:
A CH3F > CH3Cl > CH3Br > CH3I
B CH3F < CH3Cl < CH3Br < CH3I
C CH3F < CH3Cl > CH3Br > CH3I
D D)CH3F > CH3Cl < CH3Br > CH3I

The correct answer is:
CH3F < CH3Cl < CH3Br < CH3I

Solution:
Correct Option is : 2
CH3F < CH3Cl < CH3Br < CH3I

Topic: Chemistry, Haloalkanes and Haloarenes, NEET
Compare the following on the basis of dipole moment

Options:
A CH3F > CH3Cl > CH3Br > CH3I
B CH3F < CH3Cl < CH3Br < CH3I
C CH3F < CH3Cl > CH3Br < CH3I
D CH3F > CH3Cl < CH3Br > CH3I

The correct answer is:
CH3F < CH3Cl > CH3Br < CH3I

Solution:
Correct Option is : 3
CH3F < CH3Cl > CH3Br < CH3I

Topic: Chemistry, Haloalkanes and Haloarenes, NEET