datavorous/entrance-exam-dataset huggingface dataset:
An acromian process is characteristically found in the:

Options:
A pelvic girdle of mammals
B pectoral girdle of mammals
C skull of frog
D sperm of mammals.

The correct answer is:
pectoral girdle of mammals

Solution:
The acromion process, is a small projection of the scapula that extends anteriorly from the spine of the scapula. serves as the point of attachment for the deltoid muscle, which is the major muscle that allows us to lift or abduct our arms.
Related Theory
The hip bone, or coxal bone, forms the pelvic girdle portion of the pelvis. The paired hip bones are the large, curved bones that form the lateral and anterior aspects of the pelvis. Each adult hip bone is formed by three separate bones that fuse together during the late teenage years. These bony components are the ilium, ischium, and pubis.

Topic: Biology, Locomotion and Movement, NEET, NEET 2005
An aeroplane in which the distance between the tips of the wings in 50 m is flying horizontally with a speed of 360 km h-1 over a place where the vertical component of Earth's magnetic field is 2Ã10-4 Wb m-2. The potential difference between the tips of the wings would be

Options:
A 0.1 V
B 1.0 V
C 0.2 V
D 0.01 V

The correct answer is:
1.0 V

Solution:
Here, l=50 m, v=360 km h-1=100 m s-1
B=2Ã10-4 Wb m-2
Potential difference e=Blv=2Ã10-4Ã50Ã100=1 V

Topic: Physics, Electromagnetic Induction, NEET
An aeroplane is flying horizontally with a velocity of 216 km h-1 and at a height of 1960 m. When it is vertically above a point A on the ground, a bomb is released from it. The bomb strikes the ground at point B. The distance AB is (ignoring air resistance) (given g=9.8 m s-2)

Options:
A 1200 m
B 0.33 km
C 3.33 km
D 33 km

The correct answer is:
1200 m

Solution:
Horizontal velocity of aeroplane, in m/s
u=216 Ã100060 Ã100=60 m s-1
Time of flight, T=2hg=2 Ã19609.8=20 s
Horizontal range, AB=uT
=60 Ã20=1200 m

Topic: Physics, Motion In Two Dimensions, NEET
An aeroplane moving horizontally at a speed of 200 m s-1 and at a height of 8x103 m is to drop a bomb on a target. The horizontal distance from the target should the bomb be released is (Take g=10 m s-2)

Options:
A 9124 m
B 8714 m
C 8000 m
D 7234 m

The correct answer is:
8000 m

Solution:
t=2hg=28×10310=1600=40 s
x=vt=20040=8000m

Topic: Physics, Motion In Two Dimensions, NEET
An aggregate fruit is one which developed from

Options:
A Multicarpellary syncarpous gynoecium
B Multicarpellary apocarpous gynoecium
C Complete inflorescence
D Multicarpellary superior ovary

The correct answer is:
Multicarpellary apocarpous gynoecium

Solution:
The aggregate fruits develop from multicarpellary apocarpous ovary. These fruits form an aggregate (also called etario) of fruitlets. Few examples are as follows -

Etario of follicles - Calotropis, Consolida.

Etario of achenes - Rose, Clematis

Etario of drupes - Raspberry,

Etario of berries - Custard apple (Anona squamosa)

Topic: Biology, Morphology of Flowering Plants, NEET, NEET 2014
An air bubble in a glass slab with refractive index 1.5 (near-normal incidence) is 5 cm deep when viewed from one surface and 3 cm deep when viewed from the opposite face. The thickness (in cm) of the slab is

Options:
A 8
B 10
C 12
D 16

The correct answer is:
12

Solution:
Apparent depth =Real depth from surfaceRefractive index
d=d1+d2μ
=1.55+3=12 cm

Topic: Physics, Ray Optics, NEET, NEET 2016 (Phase 2)
An air bubble in a glass slab with refractive index 1.5 (near-normal incidence) is 5 cm deep when viewed from one surface and 3 cm deep when viewed from the opposite face. The thickness (in cm) of the slab is

Options:
A 8
B 10
C 12
D 16

The correct answer is:
12

Solution:
Apparent depth =Real depth from surfaceRefractive index
d=d1+d2μ
=1.55+3=12 cm

Topic: Physics, Ray Optics, NEET
An air bubble of radius 1 mm is located at a depth of 20 cm below water level. The excess pressure inside the bubble above the atmospheric pressure is [Given, the surface tension of water is 0.075 Nm-1 and density is 1000 kg m-3]

Options:
A 2110 Pa
B 2210 Pa
C 2260 Pa
D 2310 Pa

The correct answer is:
2110 Pa

Solution:
Let the atmospheric pressure be P0
Pressure just outside the bubble,

P=P0+hρg

Pressure of air inside the bubble

Pin=R+2σr; σ is surface tension

Pin=P0+hρg+2σr

∴ P'-P0=15×1000×9.8+2×0.0751×10-3

=1960+150

=2110 Pa

Topic: Physics, Mechanical Properties of Fluids, NEET
An air column, closed at one end and open at the other, resonates with a tuning fork when the smallest length of the column is 50  cm . The next larger length of the column resonating with the same tuning fork is:

Options:
A 66.7  cm
B 100  cm
C 150  cm
D 200  cm

The correct answer is:
150  cm

Solution:
First minimum resonating length for closed organ pipe =Î»4=50 cm
â´ Next larger length of air column =3Î»4=150 cm

Topic: Physics, Waves and Sound, NEET, NEET 2016 (Phase 1)
An aircraft executes a horizontal loop of the radius 1 km with a steady speed of 900 km h-1. Find the ratio of its centripetal acceleration with the acceleration due to gravity?

Options:
A 3.2
B 6.4
C 1.8
D 7.9

The correct answer is:
6.4

Solution:
a=v2r =25021000=62.5 m s-2,

ag=62.59.8=6.4

Topic: Physics, Laws of Motion, NEET
An airplane, diving at an angle of 53.0Â° with the vertical releases a projectile at an altitude of 730 m. The projectile hits the ground 5.00 s after being released. The speed of the aircraft is

Options:
A 282 m s-1
B 202 m s-1
C 182 m s-1
D 102 m s-1

The correct answer is:
202 m s-1

Solution:
Since the projectile is released its initial velocity is the same as the velocity of the plane at the time of release
Take the origin at the point of release
Let x and y(=-730 m) be the coordinates of the point on the ground where the projectile hits and let t be the time when it hits. Then
y=-v0tcosÎ¸-12gt2
where Î¸=53.0Â°
This equation gives
v0=-y+12gt2tcosÎ¸
=--730+129.8525cos53Â°=202 m s-1

Topic: Physics, Motion In Two Dimensions, NEET
An airplane flying at a velocity of 900 km h-1 loops the loop. If the maximum force pressing the pilot against the seat is five times its weight, the loop radius should be

Options:
A 1594 m
B 1402 m
C 1315 m
D 1167 m

The correct answer is:
1594 m

Solution:
v = 900 km h - 1
= 900 Ã 5 18
= 250 m s - 1
maximum force is at the bottom of vertical circle
F max = mv 2 r + mg = 5 mg
v 2 = 4gr
r = v 2 4g = 250 2 4 9.8 = 1594 m

Topic: Physics, Laws of Motion, NEET
An air-tight cage with a parrot sitting in it is suspended from the spring balance. The parrot starts flying. The reading of the spring balance will

Options:
A Increase
B Decrease
C Not change
D Be zero

The correct answer is:
Not change

Solution:
The system is closed. The weight of parrot is suppresses the base of air cage with a weight equal to weight of parrot. These are internal forces. So there will be no change in the reading of the spring balance

Topic: Physics, Mechanical Properties of Solids, NEET
An alcohol with C = 40% and H = 6.7% will have the empirical formula

Options:
A CH 2
B CH 2 O
C C 3 H 6 O 3
D C 2 H 4 O 2

The correct answer is:
CH 2 O

Solution:
Elements	No. of moles	Simple ratio

C=40%	4012	3.33	1

H=6.7%	6.71	6.7	2

O=53.3%	53.316	3.33	1

Thus, Empirical formula = CH 2 O.

Topic: Chemistry, General Organic Chemistry, NEET
An aldehyde and a protein, respectively, of vitamin A found in the eye are

Options:
A opsin and retinal
B retinal and opsin
C carotene and opsin
D keratin and carotene

The correct answer is:
retinal and opsin

Solution:
Humans can synthesize vitamin A (retinol) with the help of plant pigment, carotene, which is available in yellow and green leafy vegetables. Vitamin A forms retinal pigments in human eyes, such as rhodopsin in rod cells and iodopsin in cone cells.

Topic: Biology, Neural Control and Coordination, NEET
An alga which can be employed as food for human beings:

Options:
A Ulothrix
B Chlorella
C Spirogyra
D Polysiphonia

The correct answer is:
Chlorella

Solution:
Chlorella is the green alga belonging to Chlorophyceae can be a nutritious food with many health benefits. It enhances the immune system, helps to improve the good cholesterol level, and acts as an antioxidant. It helps in keeping the blood pressure and blood glucose level under check. Helps in managing the respiratory diseases.

Polysiphonia is a red alga. Spirogyra and Ulothrix are also Chlorophyceae members.

Topic: Biology, Plant Kingdom, NEET, NEET 2014
An alkali is titrated against an acid with methyl orange as indicator, which of the following is a correct combination?

Options:
A Base; Strong Acid; Strong End point; Pinkish red to yellow
B Base; Weak Acid; Strong End point; Yellow to pinkish red
C Base; Strong Acid; Strong End point; Pink to colourless
D Base; Weak Strong Acid; Colourless to pink

The correct answer is:
Base; Weak Acid; Strong End point; Yellow to pinkish red

Solution:
Methyl orange is weak organic base. It is used in the titration of strong acid vs weak base.
MeOHUnionized form(Yellow)âMe++OH-Ionized form(Red)
In basic medium, equilibrium lies in backward direction so it shows yellow colour.
In acidic medium, equilibrium shifts in forward direction so colour changes from yellow to red.

Topic: Chemistry, Ionic Equilibrium, NEET
An alkane C8H18is obtained as the only product on subjecting a primary alkyl halide to Wurtz reaction. On monobromination this alkane yields a single isomer of a tertiary bromide. Write the structure of alkane and the tertiary bromide.

Options:
A The alkane is 2,5-dimethylhexane and The tertiary bromide is 2-Bromo-2,3-dimethylhexane
B The alkane is 2,5-dimethylhexane and The tertiary bromide is 2-Bromo-2,5-dimethylhexane
C The alkane is 1,5-dimethylhexane and The tertiary bromide is 2-Bromo-2,5-dimethylhexane
D The alkane is 1,5-dimethylhexane and The tertiary bromide is 2-Bromo-2,3-dimethylhexane

The correct answer is:
The alkane is 2,5-dimethylhexane and The tertiary bromide is 2-Bromo-2,5-dimethylhexane

Solution:
Correct Option is : (B)
The alkane is 2,5-dimethylhexane and The tertiary bromide is 2-Bromo-2,5-dimethylhexane

Topic: Chemistry, Hydrocarbons, NEET
An alkane with molecular mass of 72 amu when brominated gives only one monobrominated product. The alkane is

Options:
A pentane
B 2-methylbutane
C 2, 2-dimethylpropane
D all the of the above

The correct answer is:
2, 2-dimethylpropane

Solution:
The alkane has the molecular formula, C5H12 . The isomers
The isomers 3 has twelve equivalent 1° H's. It has no 2° or 3° hydrogens. Therefore, it gives only one monobrominated product.

Topic: Chemistry, Hydrocarbons, NEET
An alkene (A) C16H16 on ozonolysis gives only one product (B) (C8H8O) . Compound (B) on reaction with NH2OH followed by reaction with H2SO4,Δ gives N- methyl benzamide the compound ‘A’ is –

Options:
A
B
C
D

The correct answer is:

Solution:

Topic: Chemistry, Hydrocarbons, NEET
An alkene ‘A’ contains three C – C, eight C – H σ bonds and one C – C π bond. ‘A’ on ozonolysis gives two moles of an aldehyde of molar mass 44 u. Write IUPAC name of ‘A’.

Options:
A Butene
B But-1-ene
C But-2-ene
D Butyne

The correct answer is:
But-2-ene

Solution:
Correct Option is : (C)
But-2-ene

Topic: Chemistry, Hydrocarbons, NEET
An alkene ‘A’ (Mol. formula C5H10) on ozonolysis gives a mixture of two compounds ‘B’ and ‘C’. Compound ‘B’ gives positive Fehling’s test and also forms iodoform on treatment with I2and NaOH. Compound ‘C’ does not give Fehling’s test but forms an iodoform. Identify the compounds A, B and C.

Options:
A A=3-Methylbut-1-ene, B= Ethanal and C=Propan-2-one
B A=2-Methylbut-2-ene, B= Ethanal and C=Butan-2-one
C A=2-Methylbut-2-ene, B= Propanal and C=Propan-2-one
D A=2-Methylbut-2-ene, B= Ethanal and C=Propan-2-one

The correct answer is:
A=2-Methylbut-2-ene, B= Ethanal and C=Propan-2-one

Solution:
Correct Option is : (D)
A=2-Methylbut-2-ene, B= Ethanal and C=Propan-2-one

Topic: Chemistry, Aldehydes and Ketones, NEET
An alkene ‘A’ on ozonolysis gives a mixture of ethanal and pentan-3- one.Write IUPAC name of ‘A’

Options:
A 3-Ethylpent-2-ene
B Ethylpentene
C 3-Ethylpent-3-ene
D 2-Ethylpent-2-ene

The correct answer is:
3-Ethylpent-2-ene

Solution:
Correct Option is : (A)
3-Ethylpent-2-ene

Topic: Chemistry, Hydrocarbons, NEET
An alkene 'A' on reaction with O3 and Zn-H2O gives propanone and ethanal in equimolar ratio. Additional of HCl to alkene 'A' gives 'B' as the major product. The structure of product 'B' is:

Options:
A
B
C
D

The correct answer is:

Solution:

Topic: Chemistry, Hydrocarbons, NEET, NEET 2019 (All India)
An alkene on ozonolysis gives methanal as one of the product. Its structure is

Options:
A
B
C
D

The correct answer is:

Solution:
Ozone is a very reactive allotrope of oxygen. The reaction of ozone with alkenes and alkynes causes the oxidative cleaving of the alkene or alkyne. The carbon-carbon triple bonds are replaced with carbon-oxygen double bonds, giving the required carbonyl product as shown below.

Topic: Chemistry, Hydrocarbons, NEET, NEET 2020 (Phase 1)
An alkene on reductive ozonolysis gives two products A and B. When these products are treated with conc. KOH one of these products gives an alcohol and an acid salt. Here the alkene can be

Options:
A But-2-ene
B Pent-2-ene
C Isobutene
D cyclo hexene

The correct answer is:
Isobutene

Solution:
Here alkene is isobutene and the reactions are as follows

As formaldehyde on heating with conc. KOH gives CH3OH and HCOOK.
HCHO→O-HCH3OH+HCOO-

Topic: Chemistry, Aldehydes and Ketones, NEET
An alkyl halide C5H11Br (A) reacts with ethanolic KOH to give an alkene ‘B’, which reacts with Br2to give a compound ‘C’, which on dehydrobromination gives an alkyne ‘D’. On treatment with sodium metal in liquid ammonia one mole of ‘D’ gives one mole of the sodium salt of ‘D’ and half a mole of hydrogen gas. Complete hydrogenation of ‘D’ yields a straight chain alkane. Identify C and D.

Options:
A C is CH3—CH2—CH2—CH(Br)—CH2Br and D is CH3—CH2—CH2≡CH
B C is CH3—CH2—CH2—CH(Br)—CH2Br and D is CH3—CH2—CH2—CH2≡CH
C C is CH3—CH(Br)—CH2Br and D is CH3—CH2—CH2—CH2≡CH
D C is CH3—CH(Br)—CH2Br and D is CH3—CH2—CH2≡CH

The correct answer is:
C is CH3—CH2—CH2—CH(Br)—CH2Br and D is CH3—CH2—CH2—CH2≡CH

Solution:
Correct Option is : (B)
C is CH3—CH2—CH2—CH(Br)—CH2Br and D is CH3—CH2—CH2—CH2≡CH

Topic: Chemistry, Hydrocarbons, NEET
An alkyl halide C5H11Br (A) reacts with ethanolic KOH to give an alkene ‘B’, which reacts with Br2to give a compound ‘C’, which on dehydrobromination gives an alkyne ‘D’. On treatment with sodium metal in liquid ammonia one mole of ‘D’ gives one mole of the sodium salt of ‘D’ and half a mole of hydrogen gas. Complete hydrogenation of ‘D’ yields a straight chain alkane. Identify A and B.

Options:
A A is CH3—CH2—CH2—CH2—CH2Br and B is CH3—CH2—CH2—CH=CH2
B A is CH3—CH2—CH2—CH2—CH2Br and B is CH3—CH2—CH=CH2
C A is CH3—CH2—CH2Br and B is CH3—CH2—CH2—CH=CH2
D A is CH3—CH2—CH2Br and B is CH3—CH2—CH=CH2

The correct answer is:
A is CH3—CH2—CH2—CH2—CH2Br and B is CH3—CH2—CH2—CH=CH2

Solution:
Correct Option is : (A)
A is CH3—CH2—CH2—CH2—CH2Br and B is CH3—CH2—CH2—CH=CH2

Topic: Chemistry, Hydrocarbons, NEET
An allele is said to be dominant if

Options:
A It is expressed only in heterozygous combination
B It is expressed only in homozygous combination
C It is expressed in both homozygous and heterozygous conditions
D It is expressed only in second generation

The correct answer is:
It is expressed in both homozygous and heterozygous conditions

Solution:
Gene variants of the same feature/characteristic found in the same loci of the homologous chromosome are called allele. The alleles for a genetic feature present in a diploid organism interact to produce the physical characteristics. If an allele for a gene expresses itself in homozygous and heterozygous condition, such allele is called as dominant allele. The allele which expresses itself only in homozygous condition but not in heterozygous condition is called recessive.
Example, gene for stem height in pea plant has two alleles - tall and short. Tall is dominant and short is recessive as short is expressed only in homozygous condition.

Topic: Biology, Principles of Inheritance and Variation, NEET
An allele is said to be recessive, when it expresses in

Options:
A Heterozygous condition only
B F1 generation only
C Homozygous conditions only
D Both homozygous and heterozygous condition.

The correct answer is:
Homozygous conditions only

Solution:
The recessive allele can express itself only in homozygous condition when two recessive alleles are present. In a dissimilar pair of factors, one member of the pair dominates and is called dominant and the other is recessive.

Topic: Biology, Principles of Inheritance and Variation, NEET
An alloy of copper, silver and gold is found to have copper atoms at ccp lattice, silver atoms at edge centers and gold a body center of unit cell. The simplest formula of the alloy is

Options:
A CuAgAu
B Cu4Ag3Au
C Cu4Ag4Au
D Cu4Ag2Au

The correct answer is:
Cu4Ag3Au

Solution:
Number of Cu-atoms at ccp lattice (corner + face)
=8×18+6×12=4
Number of Ag-atoms
=14×12=3
Number of Au-atoms = 1
Simplest formula =Cu4Ag3Au

Topic: Chemistry, Solid State, NEET
An alpha nucleus of energy 12mv2 bombards a heavy nuclear target of charge Ze. Then the distance of closest approach for the alpha nucleus will be proportional to

Options:
A v2
B 1m

C 1/Ze
D 1 / vâ¡ 2

The correct answer is:
1m

Solution:
At distance of closest approach relative velocity of two particles is v. Here target is considered as stationary, so Î±-particle comes to rest instantaneously at distance of closest approach. Let required distance is r, then from work energy-theorem.
0-mv22=-14ÏÎµ0ZeÃZer
râ1m
â1v2
âZe2

Topic: Physics, Atomic Physics, NEET
An alpha nucleus of energy $\frac{1}{2} \mathrm{mv}^2$ bombards a heavy nuclear target of charge $Z e$. Then the distance of closest approach for the alpha nucleus will be proportional to

Options:
A $\frac{1}{\mathrm{Ze}}$
B $v^2$
C $\frac{1}{\mathrm{~m}}$
D $\frac{1}{\mathrm{v}^4}$

The correct answer is:
$\frac{1}{\mathrm{~m}}$

Solution:
An $\alpha$-particle of mass $m$ possesses initial velocity $\mathrm{v}$, when it is at a large distance from the nucleus of an atom having atomic number $Z$. At the distance of closest approach, the kinetic energy of $\alpha$-particle is completely converted into potential energy. Mathematically,
$$
\begin{aligned}
& \frac{1}{2} \mathrm{mv}^2=\frac{1}{4 \pi \varepsilon_0} \frac{(2 \mathrm{e})(\mathrm{Ze})}{\mathrm{r}_0} \\
& \mathrm{r}_0=\frac{1}{4 \pi \varepsilon_0} \frac{2 \mathrm{Ze}^2}{\frac{1}{2} \mathrm{mv}^2}
\end{aligned}
$$

Topic: Physics, Work Power Energy, NEET, NEET 2010 (Screening)
An alternating electric field of frequency $v$, is applied across the dees (radius $=R$) of a cyclotron that is being used to accelerate protons (mass $=m$ ). The operating magnetic field $(B)$ used in the cyclotron and the kinetic energy $(K)$ of the proton beam, produced by it, are given by

Options:
A $B=\frac{m v}{e}$ and $K=2 m \pi^2 v^2 R^2$
B $B=\frac{2 \pi m v}{e}$ and $K=m^2 \pi v R^2$
C $B=\frac{2 \pi m v}{e}$ and $K=2 m \pi^2 v^2 R^2$
D $B=\frac{m v}{e}$ and $K=m^2 \pi v R^2$

The correct answer is:
$B=\frac{2 \pi m v}{e}$ and $K=2 m \pi^2 v^2 R^2$

Solution:
Frequency $v=\frac{e B}{2 \pi m}$
$\mathrm{KE}=\frac{1}{2} m v^2$ and radius $R=\frac{m v}{e B}$
Here, velocity $v=\frac{\pi R}{T / 2}=\frac{2 \pi R}{T}=2 \pi R v$
$\therefore \quad$ Radius $R=\frac{m(2 \pi R v)}{e B}$
Magnetic field $B=\frac{2 \pi m v}{e}$
Kinetic energy
$K=\frac{1}{2} m(2 \pi R v)^2=2 m \pi^2 v^2 R^2$

Topic: Physics, Magnetic Effects of Current, NEET, NEET 2012 (Screening)
An ambidentate legend is one which –

Options:
A is linked to the metal atom at two points
B has two donor atoms but only one of them has the capacity to form a coordinate bond
C has two donor atoms but either of the two can form a co-ordinate bond
D forms chelate rings

The correct answer is:
has two donor atoms but either of the two can form a co-ordinate bond

Solution:
Ambident ligands more than one donor sites (donor atom), but only one can donate lone pair at a time. Given ligands have two donor atoms ex: CΘN,NΘO2

Topic: Chemistry, Coordination Compounds, NEET
An amino acid having isoelectric point below 7 (at 25 o C ), when kept in a alkaline medium present in an electric field will show migration towards -

Options:
A Cathode
B Anode
C Either Cathode/Anode
D No migration

The correct answer is:
Anode

Solution:
In alkaline medium the zwitter ion will lose a proton & migrate towards anode due to net negative charge

Topic: Chemistry, Biomolecules, NEET
An amino acid that has a single hydrogen atom as its side chain is ________ in nature.

Options:
A acidic
B basic
C neutral
D none of these

The correct answer is:
neutral

Solution:
Amino acids are substituted methanes as these consist of four bonds. These are carboxyl group, amino group, hydrogen and variable R group. Since the carbon in amino acids have four different bonds, it is considered as chiral carbon and such amino acids are optically active. Optically active compounds can rotate the plane-polarized light. Glycine amino acid is optically inactive as it does not show chiral carbon because in glycine variable R is H. Glycine is also termed as neutral amino acid as it has one acidic and one amino group. This amino acid is commonly found in proteins and hence is termed as proteinogenic.

Topic: Chemistry, Biomolecules, NEET
An amino acid under certain conditions has both positive and negative charges simultaneously in the same molecule. Such a form of amino acid is called

Options:
A Acidic form
B Basic form
C Aromatic form
D Zwitterionic form

The correct answer is:
Zwitterionic form

Solution:
Zwitterionic form has both positive and negative charges simultaneously in the same molecule.

Topic: Biology, Biomolecules (B), NEET
An ammeter and a voltmeter of resistance R are connected in series to an electric cell of negligible internal resistance. Their readings are A and V respectively. If another resistance R is connected in parallel with the voltmeter, then

Options:
A Both A and V will increase
B Both A and V will decrease
C A will decrease and V will increase
D A will increase and V will decrease

The correct answer is:
A will increase and V will decrease

Solution:
When resistance R is connected in parallel with the voltmeter, the effective resistance will decrease.
According to Ohm's law,
V=IR
R=VI
Here, R decreases and hence I increases. As I increases, Potentential across (A) increases and hence potential across (V) decreases.

Topic: Physics, Current Electricity, NEET
An amount of heat 500 J of heat energy is removed from 4 moles of a monoatomic ideal gas at constant volume. The temperature drops by

Options:
A 40â
B 30℃
C 10â
D 0â

The correct answer is:
10℃

Solution:
For monoatomic gas,
Cv=32R=32Ã8.31 Jmol-1Â°C-1
Q=500 J, n=4, Î¸=?
Î¸=QnCv=5004Ã32Ã8.31=10â

Topic: Physics, Thermal Properties of Matter, NEET
An analysis of chromosomal DNA using the Southern hybrization technique does not use:

Options:
A Electrophoresis
B Blotting
C Autoradiography
D PCR

The correct answer is:
PCR

Solution:
The method is named after its inventor, the British biologist Edwin Southern. Southern blotting is a hybridization technique that enables researchers to determine the presence of certain nucleotide sequences in a sample of DNA. This technique involves the following steps:

1. DNA is digested with one or more restriction enzymes, and the resulting fragments are separated according to size by electrophoresis through agarose or polyacrylamide gel.

2. The DNA is denatured and transferred from the gel to a solid support, i.e. nitrocellulose membrane by a technique called blotting.

3. The reason for transferring the DNA fragments to a solid support (usually a nitrocellulose plate) is that the DNA is inaccessible to DNA probes while embedded in the gel.

4. The relative positions of the DNA fragments are preserved during their transfer to the filter. The DNA fragments attached to the filter are then exposed to a strand of radioactively labelled DNA that is complementary to the DNA strand on the plate that is of interest.

5. Autoradiography is then used to locate the positions of bands complementary to the probe.

Topic: Biology, Biotechnology and Its Applications, NEET, NEET 2014