datavorous/entrance-exam-dataset huggingface dataset:
The correct statement about stomata is

Options:
A Guard cells are often dumb bell shaped in dicots and bean shaped in monocots
B Guards cells are epidermal cells with chloroplasts
C The inner wall of the guard cells is thin while the outer wall is thick
D The subsidiary cells are epidermal cells with chloroplasts

The correct answer is:
Guards cells are epidermal cells with chloroplasts

Solution:
Stomata are epidermal cells that help in the diffusion of gases. It has stomatal pore, guard cells and subsidiary cells. Guard cells are chloroplast containing epidermal cells which are dumbbell-shaped in monocots and bean-shaped in dicots. The inner wall of the guard cells is thick while the outer wall is thin. Subsidiary cells are epidermal cells without chloroplasts present near guard cells and are specialized in their shape and size.

Topic: Biology, Anatomy of Flowering Plants, NEET
The correct statement among the following is

Options:
A Sodium dodecylbenzenesulphonate used in toothpaste is a cationic detergent
B Sodium lauryl sulphate forms and insoluble scum with hard water
C Cetyltrimethylammonium bromide is a popular cationic detergent used in hair conditioner
D Non-ionic detergents are formed when polythene glycol reacts with adipic acid

The correct answer is:
Cetyltrimethylammonium bromide is a popular cationic detergent used in hair conditioner

Solution:
Sodium dodecylbenzene sulphonate is in anionic detergent possess excellent germicidal properties and are used in hair conditioners.
Non-ionic detergents are obtained by the reactions between polyethylene glycol and stearic acid.

Topic: Chemistry, Chemistry in Everyday Life, NEET
The correct statement is

Options:
A Glucose and mannose are C-3 epimers
B Glucose and galactose are C-4 epimers
C Glucose and fructose are anomers
D α-D- glucose and β-D- glucose are enantiomers

The correct answer is:
Glucose and galactose are C-4 epimers

Solution:
Epimers are pair of diastereomers which differ in their configuration at only single chiral carbon. Example, glucose and mannose are C-2 epimers(difference is at 2nd carbon) and glucose and galactose are C-4 epimers (differ at 4th carbon). Glucose and fructose are functional isomers and α-D- glucose and β-D- glucose are anomers.

Topic: Chemistry, Biomolecules, NEET
The correct statement of cleavage in humans is

Options:
A It is a process to convert zygote to gastrula.
B It starts while the fertilized egg is in fallopian tube.
C It is identical to normal mitosis.
D It starts when the egg reaches the uterus.

The correct answer is:
It starts while the fertilized egg is in fallopian tube.

Solution:
Fusion of the sperm with the ovum is known as fertilization and it occurs at the ampullary-isthmic junction of the fallopian tube. The division of the zygote known as cleavage begins in the isthmus of the fallopian tube and the zygote moves towards the uterus while the division continues forming 2, 4, 8, 16 daughter cells called blastomeres. The zygote with 8-16 cells is called a morula. During cleavage the number of chromosomes in the daughter cells is same but the amount of cytoplasm is reduced. Hence it is not identical to mitosis

Topic: Biology, Human Reproduction, NEET
The correct statement regarding a carbonyl compound with a hydrogen atom on its alpha carbon, is:

Options:
A A carbonyl compound with a hydrogen atom on its alpha-carbon never equilibrates with its corresponding enol.
B A carbonyl compound with a hydrogen atom on its alpha-carbon rapidly equilibrates with its corresponding enol and this process is known as aldehyde-ketone equilibration.
C A carbonyl compound with a hydrogen atom on its alpha-carbon rapidly equilibrates with its corresponding enol and this process is known as carbonylation.
D A carbonyl compound with a hydrogen atom on its alpha-carbon rapidly equilibrates with its corresponding enol and this process is known as keto-enol tautomerism.

The correct answer is:
A carbonyl compound with a hydrogen atom on its alpha-carbon rapidly equilibrates with its corresponding enol and this process is known as keto-enol tautomerism.

Solution:
The correct statement regarding a carbonyl compound with a hydrogen atom on its alpha carbon is a carbonyl compound with a hydrogen atom on its alpha-carbon rapidly equilibrates with its corresponding enol and this process is known as keto-enol tautomerism.

The tautomeric structures are given below:

Keto-enol tautomerism

Topic: Chemistry, General Organic Chemistry, NEET, NEET 2016 (Phase 1)
The correct statement regarding defects in crystalline solids is :

Options:
A Schottky defects have no effect on the density of crystalline solids
B Frenkel defects decrease the density of crystalline solids
C Frenkel defect is a dislocation defect
D Frenkel defect is found in halides of alkaline metals

The correct answer is:
Frenkel defect is a dislocation defect

Solution:
The Frenkel defect is a dislocation defect. When atoms or ions at the lattice point are displaced to an interstitial site creating a vacancy. The cation moves to another position between the two layers and is surrounded by a greater number of anions.

Topic: Chemistry, Solid State, NEET, NEET 2015 (Phase 2)
The correct statement regarding defects in solids is-

Options:
A Frenkel defect is favoured by a very small difference in the size of cation and anion.
B Frenkel defect is not a dislocation defect.
C Trapping of e - in lattice leads to the formation of F-center.
D Schottky defects have no effect on the physical properties of solid.

The correct answer is:
Trapping of e - in lattice leads to the formation of F-center.

Solution:
The correct statement regarding defects in solids is - Trapping of e - in lattice leads to the formation of F-center.

Topic: Chemistry, Solid State, NEET
The correct statement regarding electrophile is,

Options:
A electrophile is a negatively charged species and can form a bond by accepting a pair of electrons from a nucleophile.
B electrophile is a negatively charged species and can form a bond by accepting a pair of electrons from another electrophile.
C electrophiles are generally neutral species and can form a bond by accepting a pair of electrons from a nucleophile.
D electrophile can be either neutral or positively charged species and can form a bond by accepting a pair of electrons from a nucleophile.

The correct answer is:
electrophile can be either neutral or positively charged species and can form a bond by accepting a pair of electrons from a nucleophile.

Solution:
Electrophiles are either neutral (electron-deficient) or positively charged species.
These are electron deficient or electron loving species and can form a bond by accepting a pair of electrons from a nucleophile.
For example, \(\mathrm{NO}_2^{+}, \mathrm{Br}^{+}, \mathrm{R}_3 \mathrm{C}^{+}, \mathrm{SO}_3, \mathrm{FeCl}_3\) etc.

Topic: Chemistry, General Organic Chemistry, NEET, NEET 2017
The correct statement regarding electrophile is

Options:
A Electrophile is a negatively charged species and it can form a bond by accepting a pair of electrons
from another electrophile
B Electrophiles are generally neutral species and can form a bond by accepting a pair of electrons from a nucleophile
C Electrophile can be either neutral or positively charged species and can form a bond by accepting a
pair of electrons from a nucleophile
D Electrophile is a negatively charged species and can form a bond by accepting a pair of electrons from a nucleophile

The correct answer is:
Electrophile can be either neutral or positively charged species and can form a bond by accepting a
pair of electrons from a nucleophile

Solution:
Eletrophile is an e- deficient species which may be positively charged or neutral. It accepts electrons from e- rich species .

Topic: Chemistry, General Organic Chemistry, NEET
The correct statement regarding RNA and DNA, respectively is:

Options:
A The sugar component in RNA is arabinose and the sugar component in DNA is 2'-deoxyribose.
B The sugar component in RNA is ribose and the sugar component in DNA is 2'-deoxyribose.
C The sugar component in RNA is arabinose and the sugar component in DNA is ribose.
D The sugar component in RNA is 2'-deoxyribose and the sugar component in DNA is arabinose.

The correct answer is:
The sugar component in RNA is ribose and the sugar component in DNA is 2'-deoxyribose.

Solution:
The correct statement regarding RNA and DNA, respectively is The sugar component in RNA is ribose and the sugar component in DNA is 2'-deoxyribose.

The structure of sugar components of RNA and DNA is given below;

Topic: Chemistry, Biomolecules, NEET, NEET 2016 (Phase 1)
The correct statement regarding RNA and DNA, respectively is:

Options:
A The sugar component in RNA is arabinose and the sugar component in DNA is 2'-deoxyribose.
B The sugar component in RNA is ribose and the sugar component in DNA is 2'-deoxyribose.
C The sugar component in RNA is arabinose and the sugar component in DNA is ribose.
D The sugar component in RNA is 2'-deoxyribose and the sugar component in DNA is arabinose.

The correct answer is:
The sugar component in RNA is ribose and the sugar component in DNA is 2'-deoxyribose.

Solution:

Topic: Chemistry, Biomolecules, NEET
The correct statement regarding the basicity of aryl amines is:

Options:
A Aryl amines are generally less basic than alkyl amines because the nitrogen lone-pair electrons are delocalized by interaction with the aromatic ring π electron system.
B Aryl amines are generally more basic than alkyl amines because the nitrogen lone-pair electrons are not delocalized by interaction with the aromatic ring π electron system.
C Aryl amines are generally more basic than alkyl amines because of aryl group.
D Aryl amines are generally more basic than alkyl amines, because the nitrogen atom in aryl amines is sp-hybridized.

The correct answer is:
Aryl amines are generally less basic than alkyl amines because the nitrogen lone-pair electrons are delocalized by interaction with the aromatic ring π electron system.

Solution:
In Aryl amines lone pair is in conjugation with double bond so basic strength decreased
While in aliphatic amine ( R−N H 2 ) no delocalisation of lone pair and +I effect of − CH 3 group so they have more basic strength.

Topic: Chemistry, General Organic Chemistry, NEET, NEET 2016 (Phase 1)
The correct statement regarding the comparison of staggered and eclipsed conformations of ethane, is:

Options:
A The staggered conformation of ethane is less stable than eclipsed conformation, because staggered conformation has torsional strain.
B The eclipsed conformation of ethane is more stable than staggered conformation, because eclipsed conformation has no torsional strain.
C The eclipsed conformation of ethane is more stable than staggered conformation even though the eclipsed conformation has torsional strain.
D The staggered conformation of ethane is more stable than eclipsed conformation, because staggered conformation has no torsional strain.

The correct answer is:
The staggered conformation of ethane is more stable than eclipsed conformation, because staggered conformation has no torsional strain.

Solution:
The correct statement regarding the comparison of staggered and eclipsed conformations of ethane is the staggered conformation of ethane is more stable than eclipsed conformation, because staggered conformation has no torsional strain.

Topic: Chemistry, General Organic Chemistry, NEET, NEET 2016 (Phase 1)
The correct statements about the compounds a, b and c is/are –

Options:
A a and b are identical
B a and b are diastereomers
C a and c are enantiomers
D a and b are enantiomers

The correct answer is:
a and b are enantiomers

Solution:
‘a’ and ‘b’ are mirror image of each other, hence they are enantiomers.

Topic: Chemistry, General Organic Chemistry, NEET
The CORRECT statements about the digestive system of cockroach are,

I. The entire foregut of the cockroach is lined by the cuticle.

II. The midgut is broader than the hindgut of the cockroach.

III. The proventriculus of the cockroach has teeth for grinding food particles.

IV. The digestive juice is secreted by 100-150 hepatic caeca present at the junction of foregut and midgut.

Options:
A I and III
B II and IV
C I and II
D III and IV

The correct answer is:
I and III

Solution:
The alimentary canal of cockroaches is divided into three regions, namely the foregut, midgut and the hindgut. The foregut has a thick layer of cuticle lying inside the outer layer of circular muscles. The midgut is not as broad as compared to the hindgut and the proventriculus (the expansion of the esophagus above the stomach) has chitinous plates (teeth) for grinding the food particles. The hindgut is broader than midgut and is differentiated into illeum, colon, rectum. The junction of the foregut and the midgut shows the presence of Malpighian tubules which help in excretion.

Topic: Biology, Structural Organisation in Animals, NEET
The correct statements about the working of oral pills are:

(i) Inhibit ovulation and implantation
(ii) Alter the quality of cervical mucus to prevent or retard the entry of sperms
(iii) Inhibit spermatogenesis

Options:
A (i), (ii) and (iii)
B (i) and (ii)
C (ii) only
D (iii) only

The correct answer is:
(i) and (ii)

Solution:
Small doses of either progestogens or progesterone-estrogen combinations are used in the form of tablets called oral pills by females. Pills inhibit ovulation and implantation as well as alter the quality of cervical mucus to prevent or retard entry of sperms inside the female genital tract.
In testis, the immature male germ cells (spermatogonia) produce sperms by spermatogenesis that begins at puberty.

Topic: Biology, Reproductive Health, NEET
The correct structure for triphenylbromomethane is

Options:
A
B
C
D

The correct answer is:

Solution:
Triphenylbromomethane or triphenylmethyl bromide can be shown as

Topic: Chemistry, Haloalkanes and Haloarenes, NEET
The correct structure of 2, 6 - Dimethyldec-4-ene is:

Options:
A
B
C
D

The correct answer is:

Solution:
In the given IUPAC name ene is the suffix, hence, there is a double bond at the 4th position of the longest chain. Parent chain name is dec, hence, there are 10 carbon in the longest chain and methyl substituents are attached at 2 and 6th positions.

Topic: Chemistry, General Organic Chemistry, NEET, NEET 2021
The correct structure of ethylenediaminetetraacetic acid (EDTAH) is

Options:
A
B
C
D

The correct answer is:

Solution:
It is a polyprotic acid containing four carboxylic acid groups (acidic hydrogens are red) and two amine groups with lone pair electrons (green dots).

Topic: Chemistry, Coordination Compounds, NEET
The correct structure of the drug paracetamol is

Options:
A
B
C
D

The correct answer is:

Solution:
the structure formula of Paracetamol is

Topic: Chemistry, Chemistry in Everyday Life, NEET
The correct structure of the product A formed in the reaction is

Options:
A
B
C
D

The correct answer is:

Solution:
When the cyclohexene ketone reacts with hydrogen in presence of palladium charcol then double bond is reduced and cyclohexanone is formed.

The reaction is given below.

Topic: Chemistry, Aldehydes and Ketones, NEET, NEET 2016 (Phase 2)
The correct structure of tribromooctaoxide is:

Options:
A
B
C
D

The correct answer is:

Solution:
Tribromo octaoxide is

Lewis structures, also known as Lewis dot formulas, Lewis dot structures, electron dot structures, or Lewis electron dot structures, are diagrams that show the bonding between atoms of a molecule, as well as the lone pairs of electrons that may exist in the molecule.

Topic: Chemistry, Chemical Bonding and Molecular Structure, NEET, NEET 2019 (All India)
The correct thermodynamic conditions for the spontaneous reaction at all temperatures is:

Options:
A ∆H<0 and ∆S=0
B ∆H>0 and ∆S<0
C ∆H<0 and ∆S>0
D ∆H<0 and ∆S<0

The correct answer is:
∆H<0 and ∆S>0

Solution:
âG=âH-TâS
for spontaneous reaction ΔG<0
Hence for Spontaneous reaction at all temperature âH<0,âS>0

Topic: Chemistry, Thermodynamics (C), NEET, NEET 2016 (Phase 1)
The correct unit cell dimensions for tetragonal crystal system is

Options:
A a=b=c and α=β=γ=90o
B a=b≠c and α=β=γ=90o
C a≠b≠c and α=β=γ=90o
D a=b≠c and α=β=90o,γ=120o

The correct answer is:
a=b≠c and α=β=γ=90o

Solution:
Tetragonal system has the unit cell dimension a=b≠c,α=β=γ=90° .

Topic: Chemistry, Solid State, NEET
The correct value of cell potential in volt for the reaction that occurs when the following two half cells are connected, is
$\begin{aligned} & \mathrm{Fe}_{(\mathrm{aq})}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Fe}(\mathrm{s}), \mathrm{E}^{\circ}=-0.44 \mathrm{~V} \\ & \mathrm{Cr}_2 \mathrm{O}_7^{2-}(\mathrm{aq})+14 \mathrm{H}^{+}+6 \mathrm{e}^{-} \rightarrow 2 \mathrm{Cr}^{3+}+7 \mathrm{H}_2 \mathrm{O}, \mathrm{E}^0=+1.33 \mathrm{~V} \\ & \end{aligned}$

Options:
A $+0.01 \mathrm{~V}$
B $+0.89 \mathrm{~V}$
C $+1.77 \mathrm{~V}$
D $+2.65 \mathrm{~V}$

The correct answer is:
$+1.77 \mathrm{~V}$

Solution:
$\begin{aligned} \mathrm{E}_{\text {cell }}^0 & =\mathrm{E}_{\text {cathode }}-\mathrm{E}_{\text {anode }} \\ & =1.33-(-0.44) \\ & =1.33+0.44=+1.77 \mathrm{~V}\end{aligned}$

Topic: Chemistry, Electrochemistry, NEET, NEET 2023 (Manipur)
The correct van der Waals equation for 1 mole of a real gas is

Options:
A $\left(\mathrm{p}+\frac{\mathrm{an}^2}{\mathrm{~V}^2}\right)\left(\mathrm{V}^2-\mathrm{nb}\right)=R T$
B $\left(\mathrm{p}+\frac{\mathrm{an^{2 }}}{\mathrm{V}}\right)(\mathrm{V}-\mathrm{nb})=\mathrm{nRT}$
C $\left(p+\frac{a}{V^2}\right)(V-b)=R T$
D $\left(p+\frac{V^2}{a}\right)(V-b)=R T$

The correct answer is:
$\left(p+\frac{a}{V^2}\right)(V-b)=R T$

Solution:
van der Waal equation for $\mathrm{n}$ mole gas is
$\left(p+\frac{a n^2}{V^2}\right)(V-n b)=n R T$
For $\mathrm{n}=1 \mathrm{~mol}$
$\left(\mathrm{p}+\frac{\mathrm{a}}{\mathrm{V}^2}\right)(\mathrm{V}-\mathrm{b})=\mathrm{RT}$

Topic: Chemistry, States of Matter, NEET, NEET 2023 (Manipur)
The correct variation for adsorption of a gases on a solid surface with pressure of the gas, in the following manner is

Options:
A Slow → fast → independent of the pressure
B Fast → slow → independent of the pressure
C Independent of the pressure → fast → slow
D Independent of the pressure → slow → fast

The correct answer is:
Fast → slow → independent of the pressure

Solution:
Adsorption of a gas on solid independent of the pressure start fast and after some time becomes slow.

Topic: Chemistry, Surface Chemistry, NEET
The correction factor 'a' to the ideal gas equation corresponds to which of the following?

Options:
A Electric field present between the gas molecules.
B Volume of the gas molecules.
C Density of the gas molecules.
D Force of attraction between the gas molecules.

The correct answer is:
Force of attraction between the gas molecules.

Solution:
Vanderwal constant a ∝ forces of attraction.

The constants a and b are called van der Waals constants. They have positive values and are characteristic of the individual gas. If a gas behaves ideally, both a and b are zero, and van der Waals equations approaches the ideal gas law PV=nRT. The constant a provides a correction for the intermolecular forces.

Topic: Chemistry, States of Matter, NEET, NEET 2018
The correction factor ‘a’ to the Van der waal's gas equation corresponds to

Options:
A Electric field present between the gas molecules
B Volume of the gas molecules
C Density of the gas molecules
D Forces of attraction between the gas molecules

The correct answer is:
Forces of attraction between the gas molecules

Solution:
In real gas equation, P+an2V2(V-nb)=nRT
van der Waal’s constant, ‘a’ signifies intermolecular forces of attraction. More the value of 'a' easier is liquefaction and adsorption.

Topic: Chemistry, States of Matter, NEET
The correctness of velocity of an electron moving with velocity 50 m s-1 is 0.005%. The accuracy with which its position can be measured will be

Options:
A 4634Ã10-3 m
B 4634Ã10-5 m
C 4634Ã10-6 m
D 4634Ã10-8 m

The correct answer is:
4634Ã10-5 m

Solution:
Here, Îv=0.005Ã50100=0.0025 m s-1
Îx=hmÎv
=1.034Ã10-349.1Ã10-31Ã0.0025=4634Ã10-5 m

Topic: Physics, Dual Nature of Matter, NEET
The count rate of a Geiger-Muller counter for the radiation of radioactive material of half life of 30 min decreases to 5 s-1 after 2 hr. The initial count rate was

Options:
A 25Â s-1
B 80 s-1
C 625Â s-1
D 20Â s-1

The correct answer is:
80 s-1

Solution:
Given T12=30 min ,
t=2hr
R=5sec-1â¡
R0=?
n=tT12=2Ã8030=4
A.P=RR0=12n
R0=2n R=24Ã5
â´R0=16Ã5=80 s-1

Topic: Physics, Nuclear Physics, NEET
The country which hosted the first world earth summit on the conservation of environment is

Options:
A Rio de Janerio, Brazil
B Johannesburg, South Africa
C Delhi, India
D Lima, Peru

The correct answer is:
Rio de Janerio, Brazil

Solution:
The historic Convention on Biological Diversity (The Earth Summit) held in Rio de Janeiro in 1992, called upon all nations to take appropriate measures for conservation of biodiversity and sustainable utilization of its benefits.

Topic: Biology, Biodiversity and its Conservation, NEET
The Cr metal (atomic weight 52) crystallises BCC structure. The unit cell edge length is 2.88 Å . The density of Cr is 7.2 g ml-1 . The number of atom is 52 g of Cr is

Options:
A 3×1023
B 12×1023
C 6×1023
D 9×1023

The correct answer is:
6×1023

Solution:
V unitâcell = a 3
W unitâcellâ = a 3 Ãd
= 2.88Ã 10 â8 3 Ã7.2âg
no.âofâunit cell inâ S 2 gâCrâ= 52 2.88Ã 10 â8 3 Ã7.2
InâBCCâunit cellâhas zâ=â2
totalâno. of atomsâ=â 52Ã2 2.88Ã 10 â8 3 Ã7.2 =6Ã 10 23

Topic: Chemistry, Solid State, NEET
The cranial capacity of Homo erectus was

Options:
A 900 c.c
B 1350 c.c
C 1075 c.c.
D 1450 c.c.

The correct answer is:
900 c.c

Solution:
Fossils discovered in Java in 1891 revealed the next stage, i.e., Homo erectus about 1.5 mya. Homo erectus had a large brain around 900cc and probably ate meat.

Topic: Biology, Evolution, NEET
The cranial capacity of Homo habilis was about

Options:
A 560 c.c.
B 700 c.c.
C 1,300 c.c.
D 1,000 c.c.

The correct answer is:
700 c.c.

Solution:
Two mya, Australopithecines probably lived in East African grasslands. Evidence shows they hunted with stone weapons but essentially ate fruit. Some of the bones among the bones discovered were different. This creature was called the first human-like being the hominid and was called Homo habilis. The brain capacities were between 650-800cc.

Topic: Biology, Evolution, NEET
The cranial capacity of man who had first begin the burial ceremony was

Options:
A 1400 cc
B 900 cc
C 600 cc
D 1600 cc

The correct answer is:
1400 cc

Solution:
The burial ceremony was first discovered in neanderthal man.
The word neanderthalensis is based on the location where the first major specimen was discovered in 1856 - the Neander Valley in Germany.

Topic: Biology, Evolution, NEET
The critical research areas of biotechnology are

Options:
A Providing the best catalyst in the form of the improved organism usually a microbe or pure enzyme.
B Creating optimal conditions through engineering for a catalyst to act.
C Downstream processing technologies to purify the protein/organic compound.
D All of the above

The correct answer is:
All of the above

Solution:
Three critical research areas of biotechnology are:
(i) Providing the best catalyst in the form of the improved organism usually a microbe or pure enzyme.
(ii) Creating optimal conditions through engineering for a catalyst to act.
(iii) Downstream processing technologies to purify the protein/organic compound.

Topic: Biology, Biotechnology and Its Applications, NEET
The crops engineered with Bt-toxin are resistant/tolerant to:

Options:
A Fungi
B Bacteria
C Insects
D Herbicides

The correct answer is:
Insects

Solution:
Bt toxin is produced by a bacterium called Bacillus thuringiensis. Bt toxin gene has been cloned from the bacteria and been expressed in plants to provide resistance to insects without the need for insecticides (bio-pesticide). Examples are Bt cotton, Bt corn, rice, tomato, potato and soyabean etc.

Topic: Biology, Biotechnology and Its Applications, NEET, NEET 2015 (Phase 1)