datavorous/entrance-exam-dataset huggingface dataset:
What words will correct fill a, b, c, and d in the following paragraph?

a develops into a pollen grain. The outer layer is b and inner layer is intine. The inner layer is made up of cellulose and c . In 60% of the angiosperms, pollen grains are shed at d celled stage.

Options:
A a - Anther, b - Exine, c - Chitin, d - 3
B a - Microspore, b - Exine, c - Chitin, d - 2
C a - Anther, b - Exine, c - Pectin, d - 2
D a - Microspore, b - Exine, c - Pectin, d - 2

The correct answer is:
a - Microspore, b - Exine, c - Pectin, d - 2

Solution:
The microspore develops into a pollen grain. The outer layer is exine. The inner layer is called intine and it is made up of cellulose and pectin. In 60% angiosperms, pollen grains shed at 2 - celled stage. In others, they are shed at 3 celled stages as the generative cell divides mitotically to form 2 male gametes.

Topic: Biology, Sexual Reproduction in Flowering Plants, NEET
What would be the blood group of a father who has a child suffering from erythroblastosis foetalis?

Options:
A Father's blood group is definitely Rh-ve
B Father's blood group is definitely Rh+ve
C Father's blood group may be Rh+ve or Rh-ve
D Father's blood group is definitely O Rh-ve

The correct answer is:
Father's blood group is definitely Rh+ve

Solution:
Rhesus factor, or Rh factor is a type of protein found on the surface membrane of RBC. This protein is genetically inherited where presence of protein is deemed as Rh+ and its absence as Rh-.
If a Rh- mother is impregnated with Rh+ father, there is a chance of Rh incompatibility as the baby will be Rh+. If the developing fetus is Rh+, the mother's blood will consider the Rh protein as foreign antigen and develop antibodies against it. Blood cells of mother will attack the baby as a defense mechanism which can be fatal. Such a condition resulting in death of baby is called erythroblastosis foetalis.

Topic: Biology, Body Fluids and Circulation, NEET
What would be the cardiac output of a person having 72 heartbeats per minute and a stroke volume of 50 ml?

Options:
A 360 mL/min
B 3600mL/min
C 7200mL/min
D 5000mL/min

The correct answer is:
3600mL/min

Solution:
Cardiac output is defined as the amount of blood pumped by the heart in one minute. So, the amount of blood pumped by the heart is the stroke volume and the number of times the heart beats in one minute is the heart rate. Therefore according to the definition of cardiac output, it is the product of stroke volume and heart rate. Cardiac output= stroke volume*heart rate (in the question, 50×72=3600mL/min ).

Topic: Biology, Body Fluids and Circulation, NEET
What would be the cardiac output of a person having 72 heartbeats per minute and a stroke volume of 50 ml?

Options:
A 360 mL
B 3600 mL
C 7200 mL
D 5000 mL

The correct answer is:
3600 mL

Solution:
The cardiac output of a person having 72 heartbeats per minute and a stroke volume of 50 ml is 3600 mL

Topic: Biology, Body Fluids and Circulation, NEET
What would be the effect of increasing the volume of each of the following system on its equilibrium.
1. 2CO(g)+O2(g)⇌2CO2(g)
2. N2O4(g)⇌2NO2(g)

Options:
A 1 in forward and 2 in backward
B both forward
C both backward
D 1 is backward and 2 in forward direction

The correct answer is:
1 is backward and 2 in forward direction

Solution:
Increasing volume will result in the decreases of concentration of all gases as per Le-Chatelier principle, the reaction should move in a direction of increases in total number of gaseous moles. Thus shift is in a direction of Δng>0 .

Topic: Chemistry, Chemical Equilibrium, NEET
What would be the effect on Kc if The temperature is increased?

Options:
A Kc will increase
B Kc will decrease
C Kc may increase or decrease depending on other factors
D Kc first increase then decrease

The correct answer is:
Kc will increase

Solution:
Correct Option is : (A)
Kc will increase

Topic: Chemistry, Ionic Equilibrium, NEET
What would be the genotype of:

(i) An individual who is carrier of sickle cell anaemia gene but apparently unaffected.

(ii) An individual affected with the disease.

Options:
A

(i)Hb A Hb S (ii)Hb A Hb S

B

(i)Hb A Hb S (ii)Hb S Hb S

C

(i)Hb S Hb S (ii)Hb A Hb S

D

(i)Hb A Hb A (ii)Hb S Hb S

The correct answer is:

(i)Hb A Hb S (ii)Hb S Hb S

Solution:
Sickle Cell Anemia is an autosomal recessive trait. And it is caused by an error in the gene for haemoglobin, a protein which transports oxygen in the bloodstream. The gene defect is a known mutation of a single nucleotide (see single-nucleotide polymorphism - SNP) (A to T) of the Î²-globin gene, which results in glutamic acid being substituted by valine at position 6. Haemoglobin S with this mutation is referred to as Hb S , as opposed to the normal adult Hb A .

Out of the three possible genotype only homozygous individuals for Hb S Hb S show the diseased phenotype.

Heterozygous Hb A Hb S individuals appear apparently unaffected but they are carrier of the disease.

Topic: Biology, Principles of Inheritance and Variation, NEET
What would be the growth rate pattern, when the resources are unlimited?

Options:
A Exponential growth
B Limited growth
C Arithmetic growth
D None of the above

The correct answer is:
Exponential growth

Solution:
In Exponential growth, resources are unlimited.

Topic: Biology, Organisms and Populations, NEET
What would be the heart rate of a person if the cardiac output is 5 L, blood volume in the ventricles at the end of diastole is 100 mL and at the end of ventricular systole is 50 mL?

Options:
A 50 beats per minute
B 75 beats per minute
C 100 beats per minute
D 125 beats per minute

The correct answer is:
100 beats per minute

Solution:
CO = HR X (EDV-ESV) (Cardiac Output = Heart rate x stroke volume; stroke volume = End Diastole volume - End Systole volume);
We have, CO = 5 Liters,5000ml
EDV = 100ml
ESV =50 ml
Hence, CO = HR x (EDV - ESV)
HR = CO / (EDV - ESV)
HR = 5000 / (100-50)
= 5000 /50
HR = 100 bpm

Topic: Biology, Body Fluids and Circulation, NEET, NEET 2019 (All India)
What would be the heart rate of a person if the cardiac output is 5 L, blood volume in the ventricles at the end of diastole is 100 mL and at the end of ventricular systole is 50 mL?

Options:
A 50 beats per minute
B 75 beats per minute
C 100 beats per minute
D 125 beats per minute

The correct answer is:
100 beats per minute

Solution:
CO = HR X (EDV-ESV) (Cardiac Output = Heart rate x stroke volume; stroke volume = End Diastole volume - End Systole volume);
We have, CO = 5 Liters,5000ml
EDV = 100ml
ESV =50 ml
Hence, CO = HR x (EDV - ESV)
HR = CO / (EDV - ESV)
HR = 5000 / (100-50)
= 5000 /50
HR = 100 bpm

Topic: Biology, Body Fluids and Circulation, NEET
What would be the IUPAC name and symbol for the element with atomic number 120?

Options:
A Copernicium (Cn)
B Unbinilium (Ubn)
C Moscovium (Mc)
D Nihonium (Nh)

The correct answer is:
Unbinilium (Ubn)

Solution:
Correct Option is : (B)
Unbinilium (Ubn)

Topic: Chemistry, Classification of Elements and Periodicity in Properties, NEET
What would be the number of chromosomes of the aleurone cells of a plant with 42 chromosomes in its root tip cells?

Options:
A 63
B 84
C 21
D 42

The correct answer is:
63

Solution:
The outermost cell layer of the endosperm (3n) of seed is called aleurone layer. Since the cells of aleurone layer are triploid, the number of chromosomes would be $\frac{42}{2} \times 3=21 \times 3=63$, root tip cells ( $2 n$ ) has 42 chromosomes.

Topic: Biology, Sexual Reproduction in Flowering Plants, NEET, NEET 2011 (Screening)
What would be the reading of the weighing scale if a person of mass 50 kg stands on it in a descending lift with a downward acceleration of 9 m s–2?

Options:
A 50 kg
B 45 kg
C 55 kg
D 5 kg

The correct answer is:
5 kg

Solution:
Correct Option is : (D)
5 kg

Topic: Chemistry, Laws of Motion, NEET
What would be the reading on the scale for a 70 kg man standing in a lift moving upwards with a uniform acceleration of 5 m/s²?

Options:
A 105 kg
B 70 kg
C 35 kg
D 140 kg

The correct answer is:
70 kg

Solution:
Correct Option is : (B)
70 kg

Topic: Chemistry, Laws of Motion, NEET
What would be the reading on the scale when a 70 kg man stands in a lift that is moving with a uniform speed of 10 m/s?

Options:
A 700 kg
B 70 kg
C 35 kg
D 350 kg

The correct answer is:
70 kg

Solution:
Correct Option is : (B)
70 kg

Topic: Chemistry, Laws of Motion, NEET
What would be the result if gas particles were at rest and occupied fixed positions?

Options:
A The gas would have a fixed shape
B The gas would have a variable shape
C The gas would condense into a liquid
D The gas would change color

The correct answer is:
The gas would have a fixed shape

Solution:
If gas particles were at rest and occupied fixed positions, the gas would have had a fixed shape.

Topic: Chemistry, States of Matter, NEET
What would be the result if iron (III) bromide is used as a catalyst in the bromination of anisole without ethanoic acid?

Options:
A No reaction
B Formation of only para isomer
C Formation of a mixture of isomers
D Formation of only ortho isomer

The correct answer is:
Formation of a mixture of isomers

Solution:
Iron (III) bromide catalyses the formation of a mixture of isomers.

Topic: Chemistry, Alcohols Phenols and Ethers, NEET
What would be the SI unit for the quantity (pV2T2) / n ?

Options:
A N m6Kmol−1
B N m4K2mol−1
C N m3K2mol−2
D N m2Kmol−3

The correct answer is:
N m4K2mol−1

Solution:
Correct Option is : (B)
N m4K2mol−1

Topic: Chemistry, States of Matter, NEET
What would bethenumber of chromosomes in the cells of the aleurone layer in a plant species with 8 chromosomes in its synergids?

Options:
A 8
B 16
C 24
D 32

The correct answer is:
24

Solution:
Synergids are haploid (n) cells, whereas the endosperm or aleurone layer is a triploid $(3 n)$ tissue. Thus, if the synergids have 8 chromosomes, the aleurone layer will contain 24 chromosomes.

Topic: Biology, Sexual Reproduction in Flowering Plants, NEET, NEET 2006
What would happen if in a gene encoding a polypeptide of 50 amino acids, $25^{\text {th }}$ codon (UAU) is mutated to UAA?

Options:
A a polypeptide of 24 amino acids will be formed
B two polypeptides of 24 and 25 amino acids will be formed
C a polypeptide or 49 amino acids will be formed
D a polypeptide of 25 amino acids will be formed

The correct answer is:
a polypeptide of 24 amino acids will be formed

Solution:
The process of translation requires transfer of genetic information from a polymer of nucleotides to a polymer of amino acids. The three letter nucleotide code of DNA and RNA is termed as codon. These are termed so since they code for amino acids by the ribosomes during the translation process. There are 64 codons in total in the genetic code of which 61 codons code for amino acids and 3 codons do not code for any amino acid and called as stop codons since protein synthesis terminated when stop codons are read. The codon is a triplet. UAA, UAG and UGA are the three stop codons. A gene is encoding a polypeptide of 50 amino acids implies that this gene has 51 codons where the 51 st codon is a stop codon. Therefore, a protein of 50 amino acids is encoded. If 25 th codon i.e., UAU coding for tyrosine is point mutated to UAA which is a stop codon, the protein formation process will stop here.

Topic: Biology, Principles of Inheritance and Variation, NEET, NEET 2003
What would happen if in a gene encoding a polypeptide of 50 amino acids, the 25th codon (UAU) is mutated to UAA?

Options:
A A polypeptide of 25 amino acids will be formed
B A polypeptide of 24 amino acids will be formed
C Two polypeptide of 24 and 25 amino acids will be formed
D A polypeptide of 49 amino acids will be formed

The correct answer is:
A polypeptide of 24 amino acids will be formed

Solution:
UAA is the stop codon, so the polypeptide synthesis will stop at the 25th amino acid. Hence, a polypeptide of 24 amino acid will be formed.

Topic: Biology, Molecular Basis of Inheritance, NEET
What would happen if oxygen availability to activated sludge flocs is reduced?

Options:
A It will slow down the rate of degradation of organic matter
B The center of flocs will become anoxic, which would cause death of bacteria and eventually breakage of flocs.
C Flocs would increase in size as anaerobic bacteria would grow around flocs.
D Protozoa would grow in large numbers.

The correct answer is:
The center of flocs will become anoxic, which would cause death of bacteria and eventually breakage of flocs.

Solution:
If oxygen availability to activated sludge flocs is reduced the center of flocs will become anoxic, which would cause death of bacteria and eventually breakage of flocs.

Topic: Biology, Microbes in Human Welfare, NEET
What would happen if syngamy does not occur in sexual reproduction?

Options:
A Parthenogenesis
B External fertilisation
C Formation of a diploid zygote
D None of the above

The correct answer is:
None of the above

Solution:
Nothing will happen if syngamy does not occur in sexual reproduction.

Topic: Biology, Reproduction in Organisms, NEET
What would happen if the meristem in plants ceases to divide?

Options:
A The plant will continue to grow
B The plant will stop growing
C The plant will decrease in size
D The plant will increase in size

The correct answer is:
The plant will stop growing

Solution:
If the meristem in plants ceases to divide, the plant will stop growing.

Topic: Biology, Plant - Growth and Development, NEET
What would happen if there is failure of receiving the atrial impulse by the ventricles, or completely independent contraction of the atria and the ventricle?

A - Ventricular escape
B - Stokes - Adams syndrome
C - Irregularity in heart rhythm
D - Arteriosclerosis

Options:
A A only
B A and B
C A, B and C
D A, B, C and D

The correct answer is:
A, B and C

Solution:
If there is failure of receiving the atrial impulse by the ventricles, or completely independent contraction of the atria and the ventricle, the heart rhythm will become irregular.

Topic: Biology, Body Fluids and Circulation, NEET
What would happen if vasa defferentia of man are cut?

Options:
A Sperms are non-nucleate
B Spermatogenesis does not occur
C Semen is without sperms
D Sperms are non-motile

The correct answer is:
Semen is without sperms

Solution:
Male reproductive organs consist of a pair of Testes, a pair of Epididymis, a pair of Vasa deferentia, Ejaculatory duct, Penis and Accesory glands. Testes are primary sex organs as they produce male sex cells i.e. sperms. These are produced inside the testes through process known as Spermatogenesis. These sperms from testes then enter the epididymis where they mature and attain motility. The sperms are then carried by vasa deferentia back into the abdomen through inguinal canal. These tubes then fuse with duct of seminal vesicles and form Ejaculatory ducts which then merges with urethra. Here seminal fluid from glands and sperms mix to form semen which is then ejaculated out. Thus if vasa deferentia are cut sperms will not be present in semen.

Topic: Biology, Human Reproduction, NEET
What would happen to gases if there were a loss of kinetic energy during collisions?

Options:
A They would become more compressible
B They would expand rapidly
C The motion of molecules would stop, and gases would settle down
D They would exhibit higher pressure

The correct answer is:
The motion of molecules would stop, and gases would settle down

Solution:
If there were a loss of kinetic energy during collisions, the motion of gas molecules would stop, and gases would settle down.

Topic: Chemistry, States of Matter, NEET
What would have happened if the greenhouse gases were totally missing in the Earthâ€™s atmosphere?

Options:
A The Earth's surface temperature would be extremely high, making it uninhabitable.
B The Earth's surface temperature would be extremely low, leading to freezing conditions.
C There would be no change in the Earth's climate.
D There would be no greenhouse effect, causing drastic temperature fluctuations.

The correct answer is:
The Earth's surface temperature would be extremely low, leading to freezing conditions.

Solution:
Correct Option is : (B)
The Earth's surface temperature would be extremely low, leading to freezing conditions.

Topic: Chemistry, Environmental Chemistry, NEET
What would you observe when a compressed gas pushes a piston out and expands?

Options:
A A decrease in temperature
B An increase in temperature
C No change in temperature
D Fluctuation in temperature

The correct answer is:
A decrease in temperature

Solution:
Correct Option is : (A)
A decrease in temperature

Topic: Chemistry, Kinetic Theory of Gases, NEET
What's the increasing order of speeds of the gases

Options:
A Ump>Uavg>Urms
B Urms>Uavg>Ump
C Uavg>Ump>Urms
D Urms>Ump>Uavg

The correct answer is:
Urms>Uavg>Ump

Solution:
Correct Option is : 2
Urms>Uavg>Ump

Topic: Chemistry, States of Matter, NEET
Wheat rust is caused by?

Options:
A Claviceps
B Puccinia
C Aspergillus
D Clostridium

The correct answer is:
Puccinia

Solution:
Puccinia triticina causes Wheat leaf rust which is a fungal disease affecting wheat, barley, rye stems, etc

Topic: Biology, Biological Classification, NEET
When $1 \mathrm{~kg}$ of ice at $0^{\circ} \mathrm{C}$ melts to water at $0^{\circ} \mathrm{C}$, the resulting change in its entropy, taking latent heat of ice to be $80 \mathrm{cal} /{ }^{\circ} \mathrm{C}$, is

Options:
A $8 \times 10^4 \mathrm{cal} / \mathrm{K}$
B $80 \mathrm{cal} / \mathrm{K}$
C $293 \mathrm{cal} / \mathrm{K}$
D $273 \mathrm{cal} / \mathrm{K}$

The correct answer is:
$293 \mathrm{cal} / \mathrm{K}$

Solution:
Change in entroy
$$
\Delta S=\frac{m l}{273 \mathrm{~T}}=\frac{1000 \times 80}{273}=293 \mathrm{cal} \mathrm{K}^{-1}
$$

Topic: Physics, Thermodynamics, NEET, NEET 2011 (Screening)
When 1 L of CO2 is heated with graphite, the volume of the gases collected is 1.5 L. Calculate the number of moles of CO produced at STP

Options:
A 111.2
B 2822.4
C 122.4
D 1422.4

The correct answer is:
122.4

Solution:
CO2(g)+C(s)1-x→2CO(g)2x
Total volume =1+x=1.5
So x=0.5 L
Volume of CO=2×0.5=1 L
Moles of CO=122.4 moles

Topic: Chemistry, Some Basic Concepts of Chemistry, NEET
When 0.1 mol MnO42- is oxidized the quantity of electricity required to completely MnO42- to MnO4- is

Options:
A 96500Â C
B 2Ã96500Â C
C 9650 C
D 96.50Â C

The correct answer is:
9650 C

Solution:
MnO42-âMnO4-
0.1 mole
v.f.=1
So, 0.1 mole=96500Ã0.1
=9650 C charge is required

Topic: Chemistry, Electrochemistry, NEET, NEET 2014
When 0.1 mol MnO42- is oxidised the quantity of electricity required to completely oxidise MnO42- to MnO4- is

(1 F=96500)

Options:
A 96.50 C
B 96500 C
C 9650 C
D 2×96500 C

The correct answer is:
9650 C

Solution:
Mn+6O4-20.1mole→Mn+7O4-+e-0.1mole
charge required =0.1F=0.1×96500=9650 C

Topic: Chemistry, Electrochemistry, NEET
When 0.1 mol of CH3NH2 (ionisation constant, Kb = 5 Ã 10-4) is mixed with 0.08 mol HCl and the volume is made up to 1 litre. Find the [H+] ofthe resulting solution.
Given log2 = 0.3

Options:
A 8 × 10-2
B 2 × 10-11
C 1.23 × 10-4
D 8 Ã 10-11

The correct answer is:
8 × 10-11

Solution:
CH 3 NH 2 + HCl â CH 3 NH 3 + Cl -
Initial moles 0.1 0.08 0
Resulting solution contains [salt] = 0.08
[base] = 0.1 - 0.08 = 0.02
Applying pOH = pK b + log salt base
pKb = -log Kb = -log 5 Ã 10-4 = 4 - log 5 = 3.30
pOH = 3.30 + log 0.08 0.02 = 3.30 + 0.60 = 3.90
pH + pOH = 14, pH = 14 - 3.902 = 10.1
Applying pH = -log [H+]
10.1=âlog[ H + ]
So H + =8Ã 10 â11
[H+] â« 8 Ã 10-11

Topic: Chemistry, Chemical Equilibrium, NEET
When 0.01 moles of NaOH are added to a buffer solution, its pH changes from 4.745 to 4.832. The buffer capacity is

Options:
A 0.0115
B 11.5
C 0.115
D None

The correct answer is:
0.115

Solution:
Change in pH =4.832-4.745=0.115
Buffer capacity = Number of moles of base added perl itre change in pH
=0.010.087=0.115 .

Topic: Chemistry, Ionic Equilibrium, NEET
When 1/n is equal to 1 in Freundlich's equation, how does x/m vary with pressure?

Options:
A x/m becomes constant
B x/m varies directly with pressure
C x/m varies inversely with pressure
D x/m becomes zero

The correct answer is:
x/m varies directly with pressure

Solution:
When 1/n is equal to 1 in Freundlich's equation, x/m varies directly with pressure, indicating a linear relationship.

Topic: Chemistry, Surface Chemistry, NEET
When 2 moles of O2 and 1 mole of He are mixed together, then the ratio of Cp/Cv for the mixture is

Options:
A 1913
B 1319
C 136
D 613

The correct answer is:
1913

Solution:
Cv=2×52R+1×32R3
=135R+3R2
=132R13=136R
Cp=196R
CpCv=1913

Topic: Physics, Thermodynamics, NEET
When 3, 3-dimethyl-2-butanol is heated with H2SO4, the major product obtained is

Options:
A 2,3-dimethyl-2-butene
B cis and trans isomers of 2,3-dimethyl-2-butene
C 2,3-dimethyl-1-butene
D 3,3-dimethyl-1-butene

The correct answer is:
2,3-dimethyl-2-butene

Solution:

Topic: Chemistry, Alcohols Phenols and Ethers, NEET
When 3Li7 nuclei are bombarded by protons, and the resultant nuclei are 4Be8, the emitted particles will be

Options:
A alpha particles
B beta particles
C gamma photons
D neutrons

The correct answer is:
gamma photons

Solution:
The nuclear reaction can be represented as
3Li7 + 1H1 → 4Be8 + zXA
Applying conservation of atomic number (charge)
3+1=4+Z ⇒ Z=0
Applying conservation of atomic mass
7+1=8+A ⇒A=0
Thus, the emitted particles are γ-photons ( 0X0).

Topic: Physics, Nuclear Physics, NEET
When 3 Li 7 nuclei are bombarded by protons, and the resultant nuclei are 4 Be 8, the emitted particles will be

Options:
A Neutrons
B Alpha particles
C Beta particles
D Gamma photons

The correct answer is:
Gamma photons

Solution:
3 Li 7 + 1 H 1 → 4 Be 8 + Z X A
Z for the unknown X nucleus = (3+1)-4=0
A for the unknown X nucleus = (7+1)-8=0
Hence particle emitted has zero Z and zero A
It is a gamma photon.

Topic: Physics, Atomic Physics, NEET
When 5 litres of a gas mixture of methane and propane is perfectly combusted at $0^{\circ} \mathrm{C}$ and 1 atmosphere, 16 litres of oxygen at the same temperature and pressure is consumed. The amount of heat released from the combustion in kJ $\left(\triangle \mathrm{H}_{\text {eomb }}\left(\mathrm{CH}_4\right)\right.$ $=890 \mathrm{~kJ} \mathrm{~mol}^{-1}, \Delta \mathrm{H}_{\text {comb }}\left(\mathrm{C}_3 \mathrm{H}_8\right)=2220 \mathrm{~kJ}$ $\left.\mathrm{mol}^{-1}\right)$

Options:
A 38
B 317
C 477
D 32 benzyl

The correct answer is:
317

Solution:
The chemical and their mole reaction can be expressed as follows
$$
\begin{aligned}
\mathrm{CH}_4+2 \mathrm{O}_2 & \rightarrow \mathrm{CO}_2+\mathrm{H}_2 \mathrm{O} \\
\mathrm{C}_3 \mathrm{H}_8+5 \mathrm{O}_2 & \rightarrow 3 \mathrm{CO}_2+4 \mathrm{H}_2 \mathrm{O} \\
\mathrm{CH}_4+\mathrm{C}_3 \mathrm{H}_8 & =\frac{5}{22.4}=0.22 \text { moles } \\
\mathrm{O}_2 & =\frac{16}{224}=0.71 \text { moles } \\
2 x+(0.22-x) 5 & =0.71 \\
\mathrm{x} & =0.13 \\
\text { Heat liberated } & =0.13 \times 890+0.09 \\
& =316 \mathrm{~kJ}
\end{aligned}
$$

Topic: Chemistry, Thermodynamics (C), NEET, NEET 2013 (Karnataka)
When 10 g of ice at â20 Â°C is mixed with 10 g of water at 50 Â°C , the amount of ice melted is -

Options:
A 2 g
B 3 g
C 4 g
D 5 g

The correct answer is:
5 g

Solution:
Let x gram converts into watar & final temperature is 0Â°C
Q=q1+q2
10Ã1Ã50=10Ã0.5Ã20+80x
x=5 g

Topic: Physics, Thermal Properties of Matter, NEET
When 12H+ pass through F0-F1 particle, how many ATPs are produced?

Options:
A 6 ATP
B 4 ATP
C 8 ATP
D 10 ATP

The correct answer is:
6 ATP

Solution:
ATP synthase is an enzyme that helps in generating ATP which is used for all cell activities. It is a globular protein having two subunits -a headpiece - F1 and integral base- F0 . The head part is the peripheral protein and the site for ATP synthesis. The integral base protein forms the channel for movement of proton across the inner membrane. The proton movement is coupled to the catalytic site of ATP synthesis. For every ATP produced, 2H+ passes through the F0 and into the matrix down the electrochemical gradient. For 12H+ , 6ATP will be synthesized.

Topic: Biology, Respiration in Plants, NEET