datavorous/entrance-exam-dataset huggingface dataset:
Predict the products of electrolysis in each of the following An aqueous solution of AgNO₃ with platinum electrodes.

Options:
A Ag⁺ ions reduced to Ag(s) at the cathode; OH⁻ ions oxidized to O₂(g) and H₂O(l) at the anode.
B Ag⁺ ions reduced to Ag(s) at the cathode; Cl⁻ ions oxidized to Cl₂(g) at the anode.
C Ag⁺ ions reduced to Ag(s) at the cathode; 2H⁺ ions reduced to H₂(g) at the anode.
D Ag⁺ ions reduced to Ag(s) at the cathode; SO₄²⁻ ions oxidized to O₂(g) and SO₄²⁻ ions at the anode.

The correct answer is:
Ag⁺ ions reduced to Ag(s) at the cathode; OH⁻ ions oxidized to O₂(g) and H₂O(l) at the anode.

Solution:
Correct Option is : (A)
Ag⁺ ions reduced to Ag(s) at the cathode; OH⁻ ions oxidized to O₂(g) and H₂O(l) at the anode.

Topic: Chemistry, Electrochemistry, NEET
Predict the products of electrolysis in each of the following An aqueous solution of AgNO₃ with silver electrodes.

Options:
A Ag⁺ ions reduced to Ag(s) at the cathode; OH⁻ ions oxidized to O₂(g) and H₂O(l) at the anode.
B Ag⁺ ions reduced to Ag(s) at the cathode; Cl⁻ ions oxidized to Cl₂(g) at the anode.
C Ag⁺ ions reduced to Ag(s) at the cathode; 2H⁺ ions reduced to H₂(g) at the anode.
D Ag⁺ ions reduced to Ag(s) at the cathode; SO₄²⁻ ions oxidized to O₂(g) and SO₄²⁻ ions at the anode.

The correct answer is:
Ag⁺ ions reduced to Ag(s) at the cathode; OH⁻ ions oxidized to O₂(g) and H₂O(l) at the anode.

Solution:
Correct Option is : (A)
Ag⁺ ions reduced to Ag(s) at the cathode; OH⁻ ions oxidized to O₂(g) and H₂O(l) at the anode.

Topic: Chemistry, Electrochemistry, NEET
Predict the products of electrolysis in each of the following An aqueous solution of CuCl₂ with platinum electrodes.

Options:
A Cu²⁺ ions reduced to Cu(s) at the cathode; Cl⁻ ions oxidized to Cl₂(g) at the anode.
B Ag⁺ ions reduced to Ag(s) at the cathode; OH⁻ ions oxidized to O₂(g) and H₂O(l) at the anode.
C 2H⁺ ions reduced to H₂(g) at the cathode; 2H⁺ ions oxidized to O₂(g) and 2H₂O(l) at the anode.
D Ag⁺ ions reduced to Ag(s) at the cathode; SO₄²⁻ ions oxidized to O₂(g) and SO₄²⁻ ions at the anode

The correct answer is:
Cu²⁺ ions reduced to Cu(s) at the cathode; Cl⁻ ions oxidized to Cl₂(g) at the anode.

Solution:
Correct Option is : (A)
Cu²⁺ ions reduced to Cu(s) at the cathode; Cl⁻ ions oxidized to Cl₂(g) at the anode.

Topic: Chemistry, Electrochemistry, NEET
Predict the products of the following reaction:

Options:
A Aniline + Bromoethane
B Phenol + Chloroethane
C Phenol + Bromoethane
D Phenyl Bromide + Bromoethane

The correct answer is:
Phenol + Bromoethane

Solution:
Correct Option is : (C)
Phenol + Bromoethane

Topic: Chemistry, Alcohols Phenols and Ethers, NEET
Predict the products of the following reaction:

Options:
A (CH3)3C-I + C2H5OH
B (CH3)3C-OH + C2H5OH
C (CH3)3C-I + C2H6
D (CH3)3C-H + C2H5OH

The correct answer is:
(CH3)3C-I + C2H5OH

Solution:
Correct Option is : (A)
(CH3)3C-I + C2H5OH

Topic: Chemistry, Alcohols Phenols and Ethers, NEET
Predict the products of the following reaction:

Options:
A No compound is formed
B 4-ethoxynitrobenzene only
C 2-ethoxynitrobenzene only
D 2-ethoxynitrobenzene + 4-ethoxynitrobenzene

The correct answer is:
2-ethoxynitrobenzene + 4-ethoxynitrobenzene

Solution:
Correct Option is : (D)
2-ethoxynitrobenzene + 4-ethoxynitrobenzene

Topic: Chemistry, Alcohols Phenols and Ethers, NEET
Predict the products of the following reaction:

Options:
A Propanol + bromomethane
B Propanol + chloromethane
C Butanol + bromomethane
D Propanol + bromoethane

The correct answer is:
Propanol + bromomethane

Solution:
Correct Option is : (A)
Propanol + bromomethane

Topic: Chemistry, Alcohols Phenols and Ethers, NEET
Predict the reagent or the products numbered 1,3 and 5 in the following reaction sequence:

Options:
A 1 = Sn-HCl , 3 = H2O / H+and 5 = H3PO2/ H2O
B 1 = H2, 3 = H2O / H+and 5 = H3PO2/ H2O
C 1 = Sn-HCl , 3 = Br2and 5 = H3PO2/ H2O
D 1 = Sn-HCl , 3 = H2O / H+and 5 = CH3COCl

The correct answer is:
1 = Sn-HCl , 3 = H2O / H+and 5 = H3PO2/ H2O

Solution:
Correct Option is : (A)
1 = Sn-HCl , 3 = H2O / H+and 5 = H3PO2/ H2O

Topic: Chemistry, Amines, NEET
Predict which of the following reaction will have appreciable concentration of reactants and products:
a) \(\mathrm{Cl}_2(g) \rightarrow 2 \mathrm{Cl}(\mathrm{g}) \mathrm{K}_c=5 \times 10^{-39}\)
b) \(\mathrm{Cl}_2(g)+2 \mathrm{NO}(g) \rightarrow 2 \mathrm{NOCl}(g) K_c=3.7 \times 10^8\)
c) \(\mathrm{Cl}_2(g)+2 \mathrm{NO}_2(g) \rightarrow 2 \mathrm{NO}_2 \mathrm{Cl}(g) K_c=1.8\)

Options:
A a and b
B a and c
C b and c
D a, b, and c

The correct answer is:
a and b

Solution:
Correct Option is : (A)
a and b

Topic: Chemistry, Ionic Equilibrium, NEET
Pregnancy begins with implantation of

Options:
A Embryo
B Fertilised ovum
C Blastopore
D Blastocyst

The correct answer is:
Blastocyst

Solution:
The blastocyst is a structure formed in the early developmental stage of mammals. It possesses an inner cell mass, that subsequently forms the embryo. The outer layer of the blastocyst consists of cells collectively called the trophoblast.

Topic: Biology, Human Reproduction, NEET
Preparation of Bakelite proceeds via reactions

Options:
A Electrophilic addition and dehydration
B Condensation and elimination
C Electrophilic substitution and dehydration
D Nucleophilic addition and dehydration

The correct answer is:
Electrophilic substitution and dehydration

Solution:
Formation of Bakelite follows electrophillic substitution of phenol and formaldehyde followed by dehydration.

Topic: Chemistry, Polymers, NEET
_____P_____represent one of the best examples of Adaptive radiation. Another example is___Q____. A number of _____Q_____, each different from the other evolved from an ancestral stock, but all within the Australian island continent. When more than one adaptive radiation appeared to have occurred in an isolated geographical area (representing different habitats), one can call this _____R_____.

Options:
A

P	Q	R
Australian placentals	Darwin’s finches	Convergent evolution

B

P	Q	R

Darwin’s finches	Australian placentals	Convergent evolution

C

P	Q	R
Australian placentals	Darwin’s finches	Divergent evolution

D

P	Q	R

Darwin’s finches	Australian placentals	Divergent evolution

The correct answer is:

P	Q	R

Darwin’s finches	Australian placentals	Convergent evolution

Solution:
The evolution of Darwinâs finches on the Galapagos Islands is a classic example of species formation and illustrates how adaptation to local conditions produces the divergence that is the heart of species formation, i.e., such an evolutionary process, giving rise to new species adapted to new habitats and ways of life, is called adaptive radiation or divergent evolution.
Furthermore, Australia is the home to the great diversity of pouched mammals (marsupials) but relatively few placental mammals. Darwin explained that adaptive radiation gave rise to a variety of marsupials in Australia in the same process of adaptive radiation as found in the finches in the Galapagos Islands. The evolutionary process, giving rise to new species adapted to new habitats and ways of life, is called adaptive radiation.
A number of Australian marsupials and placental mammals each different from the other have evolved from an ancestral stock within the Australian island continent. This is a type of convergent evolution because more than one adaptive radiation occurred in isolated geographical area.

Topic: Biology, Evolution, NEET
Presence of bundle sheath is a characteristic of

Options:
A Carbon-oxidation pathway
B C2 pathway
C C4 pathway
D C3 pathway

The correct answer is:
C4 pathway

Solution:
C4-plants have Kranz anatomy in their leaves. In this leaf, the vascular bundle is surrounded by bundle sheath and mesophyll cells. Chloroplasts in the bundle sheath cells lack grana, while mesophyll chloroplasts are normal, e.g. Sugarcane, Maize, Euphorbia, Amaranthus, Sorghum, Portulaca and Chenopodium. The HatchâSlack pathway occurs in C4 plants.

Topic: Biology, Photosynthesis in Higher Plants, NEET
Presence of gills in the tadpole of frog indicates that:

Options:
A fishes were amphibious in the past
B fishes evolved from frog-like ancestors
C frogs will have gills in future
D frogs evolved from gilled ancestors.

The correct answer is:
frogs evolved from gilled ancestors.

Solution:
Tadpoles are the larval forms of frog and toads. They respire through gills whereas the adult form respire through the skin and lungs. Since, fishes also respires through gills. Hence, presence of gills in the tadpole indicates that frogs are evolved from gilled ancestors.
Related Theory
"Ontogeny recapitulates phylogeny" mean that the development of individual organisms (ontogeny) follows (recapitulates) the same phases of the evolution of larger ancestral groups of related organisms (phylogeny).

Topic: Biology, Structural Organisation in Animals, NEET, NEET 2004
Presence of gills in the tadpole of frog indicates that

Options:
A fishes were amphibious in the past
B fishes evolved from frog-like ancestors
C frogs will have gills in future
D frogs evolved from gilled ancestors

The correct answer is:
frogs evolved from gilled ancestors

Solution:
Amphibians have moved onto terrestrial habitat, but they still need to go back to water for reproduction. The presence of gills in tadpoles indicates that fishes could be their ancestors. Fishes are completely aquatic, so the other three options are incorrect.

Topic: Biology, Evolution, NEET
Presence of mechanical barrier between stamen and carpel which prevents self pollination, is known as:

Options:
A Protoandry
B Protogyny
C Homogamy
D Herkogamy

The correct answer is:
Herkogamy

Solution:
Different timing of maturation of stamen and carpel of a bisexual flower is called dichogamy. If stamen matures first than it is called protoandry and if carpel matures first it is called protogyny. Homogamy is the same timing of maturation of stamen and carpel. Herkogamy is the presence of mechanical barrier between stamen and carpel which prevents self pollination.

Topic: Biology, Sexual Reproduction in Flowering Plants, NEET
Presence of peroxide in ethers of old stock can be tested by first treating them with FeSO4 solution and then adding an aqueous solution of....& from red colour solution

Options:
A SnCl2
B HgCl2
C KI
D KCNS

The correct answer is:
KCNS

Solution:
Presence of peroxide in ethers of old stock can be tested by first treating them with FeSO4 solution and then adding an aqueous solution of KCNS.
Ethers form peroxides, when come in contact with air and light.

Fe3++KCNS→ Red colour

Topic: Chemistry, General Organic Chemistry, NEET
Presence of plants arranged into well-defined vertical layers depending on their height can be seen best in:

Options:
A Tropical Savannah
B Tropical Rain Forest
C Grassland
D Temperate Forest

The correct answer is:
Tropical Rain Forest

Solution:
The tropical rainforest is a hot, moist biome found near Earth's equator. The tropical rain forest have five vertical strata on the basis of height of plants. i.e., ground vegetation, shrubs, short canopy trees, tall canopy trees and tall emergent trees.

Topic: Biology, Ecosystem, NEET, NEET 2017
Presence of water can be detected by

Options:
A adding a pinch of anhydrous copper sulphate which changes its colour from white to blue
B by boiling and testing for the presence of H2 and O2
C by seeing its coloured and transparency
D by checking the production of lather when mixed with soap

The correct answer is:
adding a pinch of anhydrous copper sulphate which changes its colour from white to blue

Solution:
Anhydrous CuSO4 is white which on reaction with H2O forms hydrated CuSO4 which is blue in colour.
CuSO4(anhydrous,white)+5H2O→CuSO4.5H2O(hydrated,blue)

Topic: Chemistry, s Block Elements, NEET
Presence of which of the following conditions in urine are indicative of Diabetes mellitus?

Options:
A Uremia and Renal Calculi
B Ketonuria and Glycosuria
C Renal calculi and Hyperglycaemia
D Uremia and Ketonuria

The correct answer is:
Ketonuria and Glycosuria

Solution:
Diabetes mellitus: It is caused due to insulin deficiency or hyperfunctioning of beta cells of Islets of Langerhans of the pancreas. Urine is sweet to taste (glycosuria) due to the presence of sugar. Due to the presence of sugar, there is a failure in normal osmotic reabsorption of water by kidney tubules. Due to the breakdown of lipids, ketone bodies in the body fluids increase and as a result release out through urine (ketonuria).

Topic: Biology, Chemical Coordination and Integration, NEET, NEET 2020 (Phase 1)
Presently, total number of biodiversity hot spots in the world is _______.

Options:
A 25
B 34
C 37
D 40

The correct answer is:
34

Solution:
Biodiversity includes all the flora and fauna on Earth. All the varieties of organisms come under biodiversity.
Biodiversity hotspots are regions within a nation where more varieties of organisms are found than other places. There are nearly 34 biodiversity hotspots in the world.

Topic: Biology, Biodiversity and its Conservation, NEET
Preserving germplasm in frozen state is

Options:
A Cryopreservation
B Cold storage
C In situ preservation
D Vernalisation

The correct answer is:
Cryopreservation

Solution:
Dry, frozen storage of germplasm at –196°C is called cryopreservation. This is one of the Ex-situ conservation techniques.

Topic: Biology, Biodiversity and its Conservation, NEET
Pressure exerted by saturated water vapour is called aqueous tension. What correction term will you apply to the total pressure to obtain pressure of dry gas?

Options:
A PDry gas= PTotal+ aqueous tension
B PDry gas= PTotal– aqueous tension
C PDry gas= PTotalaqueous tension
D PDry gas= PTotal/aqueous tension

The correct answer is:
PDry gas= PTotal– aqueous tension

Solution:
Correct Option is : (B)
PDry gas= PTotal– aqueous tension

Topic: Chemistry, States of Matter, NEET
Pressure is determined as force per unit area of the surface. The SI unit of pressure, pascal is as shown below: 1Pa = 1N m–2. If the mass of air at sea level is 1034 g cm–2, what is the pressure in pascal?

Options:
A 1.01332 × 105Pa
B 1.03425 × 105Pa
C 1.05652 × 105Pa
D 1.06421 × 105Pa

The correct answer is:
1.01332 × 105Pa

Solution:
Correct Option is : (A)
1.01332 × 105Pa

Topic: Chemistry, Some Basic Concepts of Chemistry, NEET
Pressure of 1 g of an ideal gas A at 27 °C is found to be 2 bar. When 2 g of another ideal gas B is introduced in the same flask at same temperature the pressure becomes 3 bar. What is the relationship between their molecular masses?

Options:
A [Molar mass of B] = 3 × [Molar mass of A]
B [Molar mass of B] = 4 × [Molar mass of A]
C [Molar mass of B] = 5 × [Molar mass of A]
D [Molar mass of B] = 6 × [Molar mass of A]

The correct answer is:
[Molar mass of B] = 4 × [Molar mass of A]

Solution:
Correct Option is : (B)
[Molar mass of B] = 4 × [Molar mass of A]

Topic: Chemistry, States of Matter, NEET
Pressure versus temperature graph of an ideal gas is shown, The density of gas at point A is ρ0 then the density of gas at point B would be

Options:
A 34ρ0
B 32ρ0
C 43ρ0
D 2ρ0

The correct answer is:
32ρ0

Solution:
If mass of a gas is constant then there is variation in density of gas with the variation of temperature and pressure because the molar volume of the gas goes on changing because ρ=MV
We know, from Ideal gas law p=ρRTM
For point A, p=ρ0RT0M ⇒M=ρ0RT0p ...(i)
For point B, 3p=ρR(2T0)M=ρR(2T0)ρ0RT0×p [By Eq. (i)]
⇒ ρ=3ρ02

Topic: Physics, Thermodynamics, NEET
Pressure versus temperature graphs of an ideal gas are as shown in figure. Choose the wrong statement

Options:
A density of gas is increasing in graph (i)
B density of gas is decreasing in graph (ii)
C density of gas is constant in graph (iii)
D none of these

The correct answer is:
none of these

Solution:
(i) At constant temperature P∝ρ
(ii) At constant pressure T∝1ρ
(iii) V→ constant
∴ρ→ constant

Topic: Physics, Thermodynamics, NEET
Primary acceptor in TCA cycle is

Options:
A Oxaloacetate
B Acetyl CoA
C Citric acid
D Pyruric acid

The correct answer is:
Oxaloacetate

Solution:
In the TCA cycle, a four-carbon compound (oxaloacetate) condenses with a two-carbon acetyl unit to yield a six-carbon tricarboxylic acid (citrate). It is the gateway to the aerobic metabolism of any molecule that can be transformed into an acetyl group or dicarboxylic acid. The cycle is also an important source of precursors, not only for the storage forms of fuels, but also for the building blocks of many other molecules such as amino acids, nucleotide bases, cholesterol and porphyrin.

Topic: Biology, Respiration in Plants, NEET
Primary alkyl halide C4H9Br (a) reacted with alcoholic KOH to give compound (b). Compound (b) is reacted with HBr to give (c) which is an isomer of (a). When (a) is reacted with sodium metal it gives compound (d), C8H18which is different from the compound formed when n-butyl bromide is reacted with sodium. Give the IUPAC name of (a)

Options:
A 1−bromo−1−methylpropane
B 2−bromo−1−methylpropane
C 1−bromo−3−methylpropane
D 2−bromo−2−methylpropane

The correct answer is:
2−bromo−2−methylpropane

Solution:
Correct Option is : (D)
2−bromo−2−methylpropane

Topic: Chemistry, Haloalkanes and Haloarenes, NEET
Primary lymphoid organs of the human body are

Options:
A bone marrow and thymus
B thymus and lymph nodes
C bursa of Fabricius and thymus
D both a and c

The correct answer is:
bone marrow and thymus

Solution:
Primary lymphoid organs includes → Bone marrow and thymus, where production, maturation and proliferation of lymphocytes occurs.

Topic: Biology, Human Health and Diseases, NEET
Primary productivity does not depend upon

Options:
A plant species
B environmental factors
C herbivore species
D availability of nutrients.

The correct answer is:
herbivore species

Solution:
Primary production
- It is the amount of biomass or organic matter produced per unit area over a time period by the
plants during photosynthesis.
- It is expressed in terms of weight or energy.
- Primary productivity:The rate of biomass production.

Topic: Biology, Ecosystem, NEET
Primary proteins are also called as polypeptides because :

Options:
A They are linear chains
B They are polymers of peptide monomers
C Successive amino acids are joined by peptide bonds
D They can assume many conformations

The correct answer is:
Successive amino acids are joined by peptide bonds

Solution:
Primary structure in proteins are continuous, in which successive amino acids are added with the help of peptide bond formation.
It is simplest yet generally non-Functional structure of proteins.

Topic: Biology, Biomolecules (B), NEET, NEET 2022 (Phase 2)
Primates called Dryopithecus and Ramapithecus existed nearly:

Options:
A 5 mya
B 15 mya
C 1 mya
D 2 mya

The correct answer is:
15 mya

Solution:
The human evolution is the gradual process leading to the emergence of the modern humans. It is characterized by number of changes in the morphology, physiology, behaviour which has occurred since the split between the last common ancestor of human and chimpanzees. Dryopithecus and Ramapithecus were early primates in the evolution of man and present about 15mya. Dryopithecus was inhabited in the European region having forelimbs longer than hindlimbs. They resembled more like apes.
Ramapithecus inhabited the Siwalik hills from India had forelimbs smaller than hindlimbs. They resembled more like man.

Topic: Biology, Evolution, NEET
Primates called Dryopithecus and Ramapithecus were existing about

Options:
A 1 mya
B 15 mya
C 5mya
D 2.5 mya

The correct answer is:
15 mya

Solution:
About 15 mya, primates called Dryopithecus and Ramapithecus were existing. They were hairy and walked like gorillas and chimpanzees. Ramapithecus was more man-like while Dryopithecus was more ape-like. Two mya, Australopithecines probably lived in East African grasslands. Homo erectus about 1.5 mya.

Topic: Biology, Evolution, NEET
Primers used in PCR must be:

Options:
A 3'-end specific
B 5'-end specific
C It can be 3'-end specific or 5'-end specific.
D Primers are not needed in PCR.

The correct answer is:
3'-end specific

Solution:
Since the replication of DNA occurs in a 5' to 3' direction, the primers used should be complementary to 3' end of template DNA. The primers used in PCR are the small primers of DNA.

Topic: Biology, Biotechnology and Its Applications, NEET
Primitive bacteria living in salty areas are called:

Options:
A Methanogens
B Thermoacidophiles
C Heliophytes
D Halophiles

The correct answer is:
Halophiles

Solution:
It is a group of archaebacteria, whose plasma membrane is single lipid bilayer, halophiles are heterotrophic bacteria which can tolerate high salty condition. Thermoacidophiles can tolerate acidic and high temperature.

Topic: Biology, Biological Classification, NEET
Probe used in molecular diagnosis of diseases can be

Options:
A a single stranded or double stranded DNA molecule tagged with a radioactive molecule
B a single stranded or double stranded RNA molecule tagged with a radioactive molecule
C a single stranded DNA or RNA molecule tagged with a radioactive molecule
D a double stranded DNA or RNA molecule tagged with a radioactive molecule

The correct answer is:
a single stranded DNA or RNA molecule tagged with a radioactive molecule

Solution:
The probe is a single-stranded DNA or RNA tagged with a radioactive molecule. When a probe is allowed to hybridize its complementary DNA, the cells which will have mutated DNA will not accept the probe. When autoradiography is done, the cells with probes will appear in the photographic film, whereas those without the probes will not appear.

Topic: Biology, Biotechnology and Its Applications, NEET
Probes, used in DNA fingerprinting, are initially

Options:
A Single stranded RNA
B Mini satellite
C 19 base long oligonucleotide
D All of the above

The correct answer is:
Mini satellite

Solution:
The probes used for DNA fingerprinting are usually prepared from minisatellite or microsatellite DNA.

Topic: Biology, Biotechnology and Its Applications, NEET
Probiotics are:

Options:
A cancer inducing microbes
B new kind of food allergens
C live microbial food supplement
D safe antibiotics.

The correct answer is:
live microbial food supplement

Solution:
Probiotics are defined as live microorganisms, including Lactobacillus species, Bifidobacterium species and yeasts, that may beneficially affect the host upon ingestion by improving the balance of the intestinal microflora. The dietary use of live microorganisms has a long history

Topic: Biology, Microbes in Human Welfare, NEET, NEET 2007
Product formed by addition of HCN to ethyne in presence of Ba(CN)2 as catalyst is

Options:
A Ethyl cyanide
B 1, 1-dicyano ethane
C Divinyl cyanide
D Vinyl cyanide

The correct answer is:
Vinyl cyanide

Solution:
CHâ¡CH+HCNâBa(CN)2CH2=CH-Câ¡Vinyl cyanideN

Topic: Chemistry, Hydrocarbons, NEET
Product formed in the following reaction is CH3CH2CHOHCH3→H2SO4

Options:
A CH3CH=CHCH3 predominates
B CH2=CHCH2CH3 predominates
C Both are formed in equal amounts
D The amount of production depends on the nature of catalyst

The correct answer is:
CH3CH=CHCH3 predominates

Solution:
CH3CH2CHOHCH3âH2SO4CH3-CH=CH-CH3More symmetricla(major product)+CH2=CH-CH2-CH3Lesss ymmetrical o run symetrical(min or product)

It is based on Saytzeffâs rule. According to this more symmetrical or more alkylated alkene predominates.

Topic: Chemistry, Hydrocarbons, NEET
product is

Options:
A
B
C
D

The correct answer is:

Solution:
In the presence of base, cyclohexanone show aldol condensation

Topic: Chemistry, Aldehydes and Ketones, NEET
Product is?

Options:
A
B
C
D CH 3 - CH 2 - COOH

The correct answer is:

Solution:
Jones reagent oxidises 1° alcohols to aldehydes and 2° alcohols to ketones without affecting C=C doubled bond.

Topic: Chemistry, Aldehydes and Ketones, NEET
Product obtain in reaction of t-butyl bromide with sodium methoxide is

Options:
A t- butyl methyl ether
B Isobutylene
C Sodium t- butoxide
D Isobutane

The correct answer is:
Isobutylene

Solution:
CH3ONa→CH3O-+Na+
methoxide ion (CH3O-) is a strong base, therefore it abstract proton from 3o alkyl halide and favours elimination reaction.

Topic: Chemistry, Hydrocarbons, NEET