datavorous/entrance-exam-dataset huggingface dataset:
A 100 V, AC source of frequency 500 Hz is connected to an LCR circuit with L=8.1 mH, C=12.5 Î¼F, R=10 Î© all connected in series as shown in figure. What is the quality factor of circuit?

Options:
A 2.02
B 2.54
C 50.54
D 200.54

The correct answer is:
2.54

Solution:
Q=1RLC
=1108.1×10-312.5×10-6=11081×1000125
=952=2.54

Topic: Physics, Alternating Current, NEET
A 100 V AC source of frequency 500 Hz is connected to a LCR circuit with L=8.1 mH, C=12.5 Î¼F and R=10 Î©, all connected in series. The potential difference across the resistance is

Options:
A 100 V
B 200 V
C 300 V
D 400 V

The correct answer is:
100 V

Solution:
Z=R2+XL-XC2
Here XL=2πfL=2×3.14×500×8.1×10-3=25.4 Ω
and XC=12πfC=12×3.14×500×12.5×10-6=25.4 Ω
∴ Z=102+25.4-25.42=10 Ω
Now irms=ErmsZ=10010=10 A
∴ VR=irms×R=10×10=100 V

Topic: Physics, Alternating Current, NEET
A 100 V, AC source of frequency 500 Hz is connected to an LCR circuit with L=8.1 mH,
C=12.5 Î¼F, R=10 Î© all connected in series as shown in the figure. What is the quality factor of the circuit?

Options:
A 2.02
B 2.54
C 50.54
D 200.54

The correct answer is:
2.54

Solution:
Q=1RLC
⇒ Q=1108.1×10-312.5×10-6
⇒ Q=11081×103125
⇒ Q=81×1025×5
⇒ Q=9×25=2.54

Topic: Physics, Alternating Current, NEET
A 100 V AC source of frequency 500 Hz is connected to an LCR circuit with L=8.1 mH, C=12.5 μF and R=10 Ω all connected in series as shown in figure. What is the quality factor of circuit?

Options:
A 2.02
B 2.54
C 50.54
D 200.54

The correct answer is:
2.54

Solution:
Quality factor of series LCR is given by
Q=1RLC
Q=1108.1×10-312.5×10-6
Q=11081×10212.5
Q=912.5=2.54

Topic: Physics, Alternating Current, NEET
A 100 V, AC source of frequency 500 Hz is connected to an LCR circuit with L=8.1 mH, C = 12.5 ÂµF, R = 10 Î© all connected in series as shown in the figure. What is the quality factor of the circuit?

Options:
A 2.02
B 2.54
C 50.54
D 200.54

The correct answer is:
2.54

Solution:
In the condition of resonance , quality factor
Q=1RLC = 110 8.1Ã10-312.5Ã10-6
=2.54

Topic: Physics, Alternating Current, NEET
A (100 W, 200 V) bulb is connected to a 160 V power supply. The power consumption would be

Options:
A 125 W

B 100 W
C 80 W

D 64 W

The correct answer is:
64 W

Solution:
Power = 100 W, Voltage = 200 V
The resistance of bulb = V2P=200×200100=400 Ω
When the bulb is connected across 160 V,
Current in bulb = 160400 A
Power consumption = VI=160×160400 = 64 W

Topic: Physics, Current Electricity, NEET
A 100 W bulb is connected to an AC source of 220 V, 50 Hz. Then, the current flowing through the bulb is

Options:
A 511 A
B 12 A
C 2 A
D 34 A

The correct answer is:
511 A

Solution:
Given, P=100 W, V=220 V
I=PV=100220=511 A

Topic: Physics, Current Electricity, NEET
A 100 W sodium lamp radiates energy uniformly in all directions. The lamp is located at the centre of a large sphere that absorbs all the sodium light which is incident on it. The wavelength of the sodium light is 589 nm. At what rate are the photons associated with the sodium light?

Options:
A 3×1020 photon s-1 are delivered
B 2×1020 photon s-1 are delivered
C 1×1020 photon s-1 are delivered
D 4×1020 photon s-1 are delivered

The correct answer is:
3×1020 photon s-1 are delivered

Solution:
Given, power of lamp, p=100 W
The wavelength of the sodium light, λ = 5 8 9 nm = 589×10-9 m
Planck constant h=6.63×10-34 J s
Let n photons are delivered per second.
∴ n = Power Energy of each photon (From P = En)
=1003.38×10-19=3×1020 photon s-1
=3×1020 photon s-1 are delivered.

Topic: Physics, Dual Nature of Matter, NEET
A 100 watt bulb emits monochromatic light of wavelength 400 nm. Calculate the number of photons emitted per second by the bulb.

Options:
A 4.845×1020s-1
B 2.012×1020s-1
C 1.285×1020s-1
D 3.345×1020s-1

The correct answer is:
2.012×1020s-1

Solution:
Correct Option is : (B)
2.012×1020s-1

Topic: Chemistry, Structure of Atom, NEET
A 110 watt, 110 volt lamp is connected in series with an electrolytic cell containing CdSO4 . What mass of cadmium will be deposited by the current flowing for 10 hour? (Atomic mass of Cd = 112.4)

Options:
A 20.96 g
B 91 g
C 17 g
D 26 g

The correct answer is:
20.96 g

Solution:
P = VI
I=PV=110110=1
Equivalent mass of Cd =Atomic massValency
=112.42=56.2
W=ItE96500=1Ã(10Ã60Ã60)Ã56.296500
= 20.96 g.

Topic: Chemistry, Electrochemistry, NEET
A $200 \mathrm{~W}$ sodium street lamp emits yellow light of wavelength $0.6 \mu \mathrm{m}$. Assuming it to be $25 \%$ efficient in converting electrical energy to light, the number of photons of yellow light it emits per second is

Options:
A $1.5 \times 10^{20}$
B $6 \times 10^{18}$
C $62 \times 10^{20}$
D $3 \times 10^{19}$

The correct answer is:
$1.5 \times 10^{20}$

Solution:
Efficient power $P=\frac{N}{t} \times \frac{h c}{\lambda}=200 \times 0.25$
$\begin{aligned}
& \frac{N}{t} =50 \times \frac{\lambda}{h c} \\
& =\frac{50 \times 0.6 \times 10^{-6}}{6.6 \times 10^{-34} \times 3 \times 10^8} \\
& =1.5 \times 10^{20}
\end{aligned}$

Topic: Physics, Dual Nature of Matter, NEET, NEET 2012 (Screening)
A 200 W sodium street lamp emits yellow light of wavelength 0.6âÎ¼m. Assuming it to be 25% efficient in converting electrical energy to light, the number of photons of yellow light emitted per second is

Options:
A 1.5×1020
B 6×1018
C 62×1020
D 3×1019

The correct answer is:
1.5×1020

Solution:
Efficient power p=Nt×hcλ=200×0.25
Nt=50×λhc
=50×0.6×10-66.6×10-34×3×108
=1.5×1020

Topic: Physics, Work Power Energy, NEET
A $220 \mathrm{~V}$ input is supplied to a transformer. The output circuit draws a current of $2.0 \mathrm{~A}$ at $440 \mathrm{~V}$. If the efficiency of the transformer is $80 \%$, the current drawn by the primary windings of the transformer is

Options:
A $3.6 \mathrm{~A}$
B $2.8 \mathrm{~A}$
C $2.5 \mathrm{~A}$
D $5.0 \mathrm{~A}$

The correct answer is:
$5.0 \mathrm{~A}$

Solution:
Efficiency is defined as the ratio of output power and input power
$$
\text { ie, } \begin{aligned}
\eta \% & =\frac{\mathrm{P}_{\text {out }}}{\mathrm{P}_{\text {in }}} \times 100=\frac{\mathrm{V}_s \mathrm{i}_s}{\mathrm{~V}_{\mathrm{p}} \mathrm{i}_{\mathrm{p}}} \times 100 \\
80 & =\frac{2 \times 440}{220 \times \mathrm{i}_{\mathrm{p}}} \times 100 \\
\Rightarrow \quad \mathrm{i}_{\mathrm{p}} & =5 \mathrm{~A}
\end{aligned}
$$

Topic: Physics, Alternating Current, NEET, NEET 2010 (Screening)
A 250-Turn rectangular coil of length 2.1 cm and width 1.25 cm carries a current of 85 μA and subjected to a magnetic field of strength 0.85 T. Work done for rotating the coil by 180° against the torque is:

Options:
A 9.1 Î¼J
B 4.55Â Î¼J
C 2.3Â Î¼J
D 1.15Â Î¼J

The correct answer is:
9.1 Î¼J

Solution:
W=MB cos⁡θ1-cos⁡θ2
When it is rotated by angle 180o then θ1=0° and θ2=180°
W=2MB
W=2NIAB
=2×250×85×10-6 1.25×2.1×10-4×85×10-2
=9.1 μJ

Topic: Physics, Magnetic Effects of Current, NEET, NEET 2017
A 500 g ball is released from a height of 4 m. Each time it makes contact with the ground it loses 25% of its energy. Find the KE it possesses after 3rd hit (take g=10 m s-2)

Options:
A 15Â J
B 11.25Â J
C 8.44 J
D none of these

The correct answer is:
8.44 J

Solution:
Kinetic energy after first hit, K1=e2K
34K=e2K
â e2=34 ( here e is coefficient of restitution )
Kinetic energy after third hit =e23K=2764mgh
=276412Ã10Ã4=27516=13516=8.44 J

Topic: Physics, Center of Mass Momentum and Collision, NEET
A 500 g tooth-paste sample has 0.2 g fluoride concentration. What is the concentration of fluoride in terms of ppm level?

Options:
A 250
B 200
C 400
D 1000

The correct answer is:
400

Solution:
As 500 g of toothpaste â¡0.2 g of F-
So 106 g of toothpaste â¡ 0.2âgâÃâ 10 6 âg 500âg F â
=400 g  F −
Hence, concentration in ppm is 400.

Topic: Chemistry, Some Basic Concepts of Chemistry, NEET
A 500 kg car takes a round turn of radius 50 m with a velocity of 36 km h-1. The centripetal force is

Options:
A 250 N

B 750 N
C 1000 N
D 1200 N

The correct answer is:
1000 N

Solution:
Centripetal force in a circular motion is given as
F=mv2r=50010250=1000 N

Topic: Physics, Laws of Motion, NEET
A 600 W mercury lamp emits monochromatic radiation of wavelength 331.3 nm. How many photons are emitted from the lamp per second?
( h=6.626Ã10-34 Js; velocity of light =3Ã108 ms-1 )

Options:
A 1×1021
B 1×1023
C 1×1022
D 1×1020

The correct answer is:
1×1021

Solution:
Here, power =600 W
Î»=331.3 nm=331.3Ã10-9 m
h=6.626Ã10-34 Js
c=3Ã108 ms-1
t=1 sec
Power=EnergyTime=nhcÎ»Ãt
600=nÃ6.626Ã10-34Ã3Ã108331.3Ã10-9Ã1
n=600Ã331.3Ã10-96.626Ã10-34Ã3Ã108
=1Ã1021

Topic: Chemistry, Structure of Atom, NEET
A 800 turn coil of the effective area 0.05  m2 is kept perpendicular to the magnetic field 5×10-5  T. When the plane of the coil is rotated by 90o around any of its coplanar axis in 0.1 s, the emf induced in the coil will be:

Options:
A 2 V
B 0.2 V
C 2×10-3 V
D 0.02 V

The correct answer is:
0.02 V

Solution:
By Faraday's law, induced EMF in coil is equal to rate of change of magnetic flux linked with coil so

ε=-∆ϕ∆t=-ϕf-ϕi∆t=-0-NBA∆t
=800×5×10-5×0.050.1
=0.02 V

Topic: Physics, Electromagnetic Induction, NEET, NEET 2019 (All India)
A 900 pF capacitor is charged by 100 V battery [Fig.]. How much electrostatic energy is stored by the capacitor

Options:
A $4.5\times {{10}^{-6}}$J
B $6.0\times {{10}^{-5}}$J
C $6.0\times {{10}^{-6}}$J
D $4.5\times {{10}^{-5}}$J

The correct answer is:
$4.5\times {{10}^{-6}}$J

Solution:
Correct Option is : (A)
$4.5\times {{10}^{-6}}$J

Topic: Chemistry, Capacitance, NEET
A 900 pF capacitor is charged by 100 V battery Fig(a). The capacitor is disconnected from the battery and connected to another 900 pF capacitor [Fig.(b)]. What is the electrostatic energy stored by the system?

Options:
A $2.25\times {{10}^{-6}}$J
B $2.25\times {{10}^{-5}}$J
C $4.5\times {{10}^{-5}}$J
D $4.5\times {{10}^{-6}}$J

The correct answer is:
$2.25\times {{10}^{-6}}$J

Solution:
Correct Option is : (A)
$2.25\times {{10}^{-6}}$J

Topic: Chemistry, Capacitance, NEET
A 2000 kg rocket in free space expels 0.5 kg of gas per second at an exhaust velocity of 400 m s-1 for 5 seconds. The increase in the speed of the rocket in this time is (Assume time interval is too small to consider variation in acceleration)

Options:
A 2000 m s-1
B 200 m s-1
C 0.5 m s-1
D zero

The correct answer is:
0.5 m s-1

Solution:
dmdtÃu=Mdvdt
0.5Ã400=2000ÃÎv5 âÎv=0.5 m s-1

Topic: Physics, Center of Mass Momentum and Collision, NEET
A 5000 kg rocket is set for vertical firing. The exhaust speed is 800 m s-1. To give an initial upward acceleration of 20 m s-2, the amount of gas ejected per second to supply the needed thrust will be (Take g=10 m s-2)

Options:
A 127.5 kg s-1
B 137.5 kg s-1
C 155.5 kg s-1
D 187.5 kg s-1

The correct answer is:
187.5 kg s-1

Solution:
Given : Mass of rocket (m)=5000 Kg
Exhaust speed (v)=800 m s-1
Acceleration of rocket (a)=20 m s-2
Gravitational acceleration (g)=10 m s-2
We know that upward force
F=m(g+a)=5000(10+20)
=5000×30=150000 N
We also know that amount of gas ejected
(dmdt)=Fv=150000800=187.5 kg s-1

Topic: Physics, Center of Mass Momentum and Collision, NEET
_____A____ (a part of alimentary canal) secretes ______B______ (an enzyme) which converts trypsinogen into trypsin.

Options:
A

A	B
Small intestine	Trypsinase

B

A	B
Small intestine	Intestinal Lipase

C

A	B
Intestinal mucosa	Enterokinse

D

A	B
Small Intestine	Steapsin

The correct answer is:

A	B
Intestinal mucosa	Enterokinse

Solution:
The secretion of the brush border cells of the mucosa, along with the secretions of the goblet cells constitute the intestinal juice or succus entericus.
Intestinal mucosa also secretes enterokinase enzyme which convert inactive trypsinogen into active trypsin.

Topic: Biology, Digestion and Absorption, NEET
...........A........... (a type of cell) in sporogenous mass undergo ...........B........... (a type of cell division) to form a tetrad that on separation gives rise to .........C........ (number) functional microspore/s.

Options:
A

A	B	C

Pollen mother cell	Meiosis	4

B

A	B	C

Pollen mother cell	Meiosis	1

C

A	B	C

Megaspore mother cell	Meiosis	4

D

A	B	C

Megaspore mother cell	Meiosis	1

The correct answer is:

A	B	C

Pollen mother cell	Meiosis	4

Solution:
Each cell of the sporogenous tissue is capable of giving rise to a microspore tetrad. Each one is potential pollen or microspore mother cell (PMC). The process of formation of microspores from a pollen mother cell through meiosis is called microsporogenesis. The microspores, as they are formed, are arranged in a cluster of four cells-the microspore tetrad. As the anthers mature and dehydrate, the microspores dissociate from each other and develop into pollen grains.

Topic: Biology, Sexual Reproduction in Flowering Plants, NEET
A and B are examples of ..............i........... organs and represent ............ii.......... evolution.

A	B

(a)	Homologous	Convergent

(b)	Analogous	Convergent

(c)	Homologous	Divergent

(d)	Analogous	Divergent

Options:
A

i	ii

Homologous	Convergent

B

i	ii

Analogous	Convergent

C

i	ii

Homologous	Divergent

D

i	ii

Analogous	Divergent

The correct answer is:

i	ii

Homologous	Divergent

Solution:
Homologous organs share a common origin (or ancestors) but have different functions.
Example 1: Pattern of bones of forelimbs in whales, bats, cheetah and humans (all mammals).
Example 2: Hearts in vertebrates.
Example 3: Brains in vertebrates.
Example 4: Thorns of Bougainvillea and tendrils of Cucurbita.

Topic: Biology, Evolution, NEET
A and B are ideal gases. The molecular weights of A and B are in the ratio of 1:4. The pressure of a gas mixture containing equal weight of A and B is p atm. What is the partial pressure (in atm) of B in the mixture?

Options:
A P5
B P2
C P2.5
D 3P4

The correct answer is:
P5

Solution:
Mol wt. ratio of A and B =1:4
â´ Mole ratio of A and B, if equal weight of A and B are taken = 4:1
â´ Partial pressure of B = 11+4ÃP
=p5

Topic: Chemistry, States of Matter, NEET
A and B are peptide hormones, known to counteract each other. Both of them are secreted by different cells of the same leaf-like organ found near the stomach. If B is used to cure a disease in which glucose is lost via urine and excess A is a potential cause of the same disease, identify A and B.

Options:
A A: insulin, B: glucagon
B A: somtatostatin, B: insulin
C A: glucagon, B: insulin
D A: insulin, B: somatostatin

The correct answer is:
A: glucagon, B: insulin

Solution:
The Î± -cells of the Islet of Langerhans are responsbile for secretion of glucagon. Glucagon is responsible for glycogenolysis. Hence, it causes hyperglycemia.The Î² -cells of the Islet of Langerans are responsible for secretion of insulin. Insulin is responsible for glycogenesis and hence caused hypoglycemia. Insulin therapy is used to treat diabetes mellitus which is associated with loss of glucose through urine and formation of harmful compounds known as ketone bodies. due to prolonged hyperglycemia.

Topic: Biology, Chemical Coordination and Integration, NEET
$\vec{A}$ and $\overline{\mathrm{B}}$ are two vectors and $\theta$ is the angle between them, if $|\overrightarrow{\mathrm{A}} \times \overline{\mathrm{B}}|=$ $\sqrt{3}(\overrightarrow{\mathrm{A}} \cdot \overline{\mathrm{B}})$, the value of $\theta$ is.

Options:
A $45^{\circ}$
B $30^{\circ}$
C $90^{\circ}$
D $60^{\circ}$

The correct answer is:
$60^{\circ}$

Solution:
Finding the angle between the vectors:
\(\begin{aligned}
& |\mathrm{A} \times \mathrm{B}|=\sqrt{3}(\mathrm{AB}) \\
& |\mathrm{A}||\mathrm{B}| \sin (\theta)=\sqrt{3}|\mathrm{~A}||\mathrm{B}| \cos (\theta)
\end{aligned}\)
Cancelling both sides we get
\(\begin{aligned}
& \sin (\theta)=\sqrt{3} \cos (\theta) \\
& \frac{\sin (\theta)}{\cos (\theta)}=\sqrt{3} \\
& \tan (\theta)=\sqrt{3}
\end{aligned}\)
Hence \(\theta=60^{\circ}\)
Hence the angle between A and B is \(60^{\circ}\)

Topic: Physics, Mathematics in Physics, NEET, NEET 2007
$\text { ' } a \text { ' and ' } b \text { ' in the following reactions are: }$

Options:
A

B

C

D

The correct answer is:

Solution:

Topic: Chemistry, Aldehydes and Ketones, NEET, NEET 2003
A and B participate in a race with acceleration a1 and a2, respectively. A reaches t times earlier than B at finish line and their velocities at finish line are v1 and v2, respectively. If difference between their velocities is v, then find the value of v

Options:
A a1+a22t
B a1a2t
C a1a2a1+a2t
D 2a1a2a1+a2t

The correct answer is:
a1a2t

Solution:
12a1t02=12a2t0+t2
v1=a1t0v2=a2t0+t
v=v1-v2=a1-a2t0-a2t
a1a2 t0=t0+t
t0=ta1a2-1
v=a1-a2ta1a2-1-a2t
=ta1a2a1-a2-a2a2a1-a2-a2
=ta1a2-a2a1a1-a2
=ta1 a2

Topic: Physics, Motion In One Dimension, NEET
A and C are vertebrate groups having a varied number of species globally. Select the correct option.

Options:
A

A	C
Fishes	Birds

B

A	C
Birds	Mammals

C

A	C
Reptiles	Birds

D

A	C
Fishes	Mammals

The correct answer is:

A	C
Fishes	Birds

Solution:
Fishes have maximum diversity, followed by birds, reptiles, amphibians and then mammals.

Topic: Biology, Biodiversity and its Conservation, NEET
A astronomical telescope has objective and eyepiece of focal lengths 40 cm and 4 cm respectively. To view an object 200 cm away from the objective, the lenses must be separated by a distance:

Options:
A 37.3  cm
B 46.0  cm
C 50.0  cm
D 54.0  cm

The correct answer is:
54.0  cm

Solution:
1V-1-200=140
1V=55140-1200
=5200-1200
1V=4200=150
V=50
∴d=50+4=54 cm

Topic: Physics, Ray Optics, NEET, NEET 2016 (Phase 1)
A⋅B̄+Ā⋅B¯ is equivalent to

Options:
A A⋅B̄+Ā⋅B
B A+B̄+Ā+B
C A⋅B̄+Ā⋅B¯
D A+B⋅Ā+B

The correct answer is:
A+B̄+Ā+B

Solution:
A⋅B̄+Ā⋅B¯
A⋅B̄¯.Ā⋅B¯
A¯+B¯.A¯+B¯
A¯+B.A+B¯

Topic: Physics, Semiconductors, NEET
A⋅B̄+Ā⋅B¯ is equivalent to

Options:
A A⋅B̄+Ā⋅B
B A+B̄+Ā+B
C A⋅B̄+Ā⋅B¯
D A+B⋅Ā+B

The correct answer is:
A+B̄+Ā+B

Solution:
AâBÌ+AÌâBÂ¯
ABÌAÌBÂ¯
A-+B-A-+B-
A-+B A+B-

Topic: Physics, Semiconductors, NEET
A, B and C are three biomolecules. The results of the tests performed on them are given below

Molischâs Test	Barfoed Test	Biuret Test

1	Positive	Negative	Negative

2	Positive	Positive	Negative

3	Negative	Negative	Positive

1, 2 and 3 are respectively

Options:
A 1 = Lactose, 2 = Glucose, 3 = Alanine
B 1 = Lactose, 2 = Glucose, 3 = Albumin
C 1 = Glucose, 2 = Fructose, 3 = Albumin
D 1 = Lactose, 2 = Fructose, 3 = Alanine

The correct answer is:
1 = Lactose, 2 = Glucose, 3 = Albumin

Solution:
Lactose: Molisch’s Test
Glucose: Molisch’s Test and Barfoed Test
Albumin: Biuret Test

Topic: Chemistry, Biomolecules, NEET
$A, B$ and $C$ are three points in a uniform electric field. The electric potential is

Options:
A maximum at $A$
B maximum at $B$
C maximum at $\mathrm{C}$
D same at all the three points $A, B$ and $C$

The correct answer is:
maximum at $B$

Solution:
The electric field maximum at $B$, because electric field is directed along decreasing potential $V_B>V_C>V_A$.

Topic: Physics, Electrostatics, NEET, NEET 2013 (All India)
A , B and C are voltmeters of resistance R , 1.5 R and 3 R respectively as shown in the figure. When some potential difference is applied between X and Y , the voltmeter readings are VA, VB and VC respectively. Then:

Options:
A VA=VB=VC
B VA≠VB=VC
C VA=VB≠VC
D VA≠VB≠VC

The correct answer is:
VA=VB=VC

Solution:
Voltage in parallel is constant
\(\begin{aligned}
& i_P=i_B+i_C V_B=V_c \\
& \frac{V_p}{R_i}=\frac{V_B}{R_B}+\frac{V_C}{R_C} \\
& \frac{1}{R_p}=\frac{1}{R_B}+\frac{1}{R_C} \Rightarrow \frac{1}{R \prime}=\frac{2}{3 R}+\frac{1}{3 R} \\
\Rightarrow R^{\prime} & =R \\
& V_{X P}=V_A=i R \\
& V_{P Q}=V_B=V_C=i R \\
\Rightarrow V_A & =V_B=V_C
\end{aligned}\)

Topic: Physics, Current Electricity, NEET, NEET 2015 (Phase 1)
A, B, C and D are four different physical quantities having different dimensions. None of them is dimensionless. But we know that the equation AD=C ln( BD ) holds true. Then which of the combination is not a meaningful quantity ?

Options:
A CBD-A2D2C
B A2-B2C2
C AB-C
D A 2 −AC D

The correct answer is:
A 2 −AC D

Solution:
The dimension of A is not equal to the dimension of C
Hence it is not possible to subtract AC from A2

Topic: Physics, Units and Dimensions, NEET
A, B, C are points on a vertical line such that AB = BC. If a body is dropped from rest at A, and t1 and t2 are the time to travel for distance AB and BC, then ratio t2t1 is

Options:
A 2+1
B 2-1
C 22
D 12+1

The correct answer is:
2-1

Solution:
-h=0-12gt2
t=2hg……..1
-h2=0-12gt12
t1=hg……..2
so t2=t-t1
=2hg-hg
t2=hg2-1…….3
equation 3/1
t2t1=hg2-1hg
t2t1=2-1

Topic: Physics, Motion In One Dimension, NEET
A+B=C+D. If initially the concentration of A and B are both equal but at equilibrium, concentration of D will be twice of that of A, then what will be the equilibrium constant of reaction?

Options:
A 49
B 94
C 19
D 4

The correct answer is:
4

Solution:
Let the initial concentration be 'a'
A + B → C + D Initial a a 0 0 at equilibrium a - x a - x x x
given x=2 a−x =2a−2x 3x= 2a x= 2 3 a
at eq. ⇒ a 3 a 3 2 a 3 2 a 3
K eq = C D A B = 2 a 3 2a 3 a 3 a 3 = 4

Topic: Chemistry, Chemical Equilibrium, NEET
$A B$ crystallizes in a body centred cubic lattice with edge length ' $a$ ' equal to $387 \mathrm{pm}$. The distance between two oppositively charged ions in the lattice is

Options:
A $335 \mathrm{pm}$
B $250 \mathrm{pm}$
C $200 \mathrm{pm}$
D $300 \mathrm{pm}$

The correct answer is:
$335 \mathrm{pm}$

Solution:
For body centred cubic (bcc) lattice, distance between two oppositely charged ions,
$$
\begin{aligned}
\mathrm{d} & =\frac{\sqrt{3} \mathrm{a}}{2}=\frac{\sqrt{3} \times 387}{2} \mathrm{pm} \\
& =335.15 \mathrm{pm}
\end{aligned}
$$

Topic: Chemistry, Solid State, NEET, NEET 2010 (Screening)
A baby boy aged two years is admitted to playing school and passes through a dental check-up. The dentist observed that the boy had twenty teeth. Which teeth were absent?

Options:
A Incisors
B Canines
C Pre-molars
D Molars

The correct answer is:
Pre-molars

Solution:
A total number of teeth in human child = 20. Premolars are absent in primary dentition. Jaw size in children is very less compared to adults so it only contains 20 teeth altogether. By seeing their primary functions there is no need of premolars in deciduous teeth as their function is the same as molars. Later when jaw size grows gradually deciduous molars are replaced by permanent premolars and molars take their own path in eruption. Which leads to 28 to 32 teeth in adult jaws, where all the teeth are used effectively for mastication.

Topic: Biology, Digestion and Absorption, NEET, NEET 2017
A bacterial cell was transformed with a recombinant DNA that was generated using a human gene. However, the transformed cells didn't produce the desired protein. The reason for this could be:

Options:
A Human gene might have intron which bacteria cannot process
B Amino acid codons for humans and bacteria are different
C Human protein is formed but degraded by bacteria
D All of the above

The correct answer is:
Human gene might have intron which bacteria cannot process

Solution:
Intron sequences are removed in eukaryotes, while bacteria don't have the mechanism for that and hence can't produce a desired protein.

Topic: Biology, Biotechnology - Principles and Processes, NEET
A bacteriophage ϕ×174 has

Options:
A 3826 bp
B 5386 bp
C 5386 nucleotides
D 3826 nucleotides

The correct answer is:
5386 nucleotides

Solution:
DNA is the genetic material and is double stranded molecule made up of long chain of deoxyribonucleotides. The length of DNA is defined as number of base pairs present in it. This length of DNA is different in different organisms. In a bacteriophage known as φ 174 there are 5386 nucleotides, while Bacteriophage lambda has 48502 base pairs (bp). Bacteria like E. coli has 4.6×106 bp. The haploid content of human DNA is 3.3×109 bp.

Topic: Biology, Molecular Basis of Inheritance, NEET
A bacterium commonly used in plant genetic engineering is:

Options:
A E.coli
B Agrobacterium
C Mycobacterium
D Rhizobium

The correct answer is:
Agrobacterium

Solution:
Agrobacterium tumefaciens is the most commonly studied species in this genus. Agrobacterium is well known for its ability to transfer DNA between itself and plants, and for this reason it has become an important tool for genetic engineering. The genus Agrobacterium is quite heterogeneous.

Topic: Biology, Biotechnology - Principles and Processes, NEET