datavorous/entrance-exam-dataset huggingface dataset:
In which of the following salts only cationic hydrolysis is involved?

Options:
A CH3COONH4
B CH3COONa
C NH4Cl
D Na2SO4

The correct answer is:
NH4Cl

Solution:
Cationic hydrolysis
Strong Acid + Weak Base
â´ NH4Cl
NH3+HCl
Weak Base + Strong Acid

Topic: Chemistry, Ionic Equilibrium, NEET
In which of the following sarcolemma is present?

Options:
A Collagen fibres
B Muscle fibres
C Elastin fibres
D Reticulate fibres

The correct answer is:
Muscle fibres

Solution:
Muscle fibre
- Each muscle fibre is covered by a plasma membrane, known as sarcolemma.
- Muscle fibre is a syncytium (multinucleated condition) and is having cytoplasm (sarcoplasm), endoplasmic reticulum (sarcoplasmic reticulum - store house of calcium ions) and a large number of parallely arranged filaments in the sarcoplasm - myofilaments or myofibrils.

Topic: Biology, Structural Organisation in Animals, NEET
In which of the following, Seeds do not germinate without presence of mycorrhizae?

Options:
A Cycas
B Pinus
C Genkigo
D Orchids

The correct answer is:
Pinus

Solution:
The fungus provides minerals and water to the roots, in turn the roots provide sugars and N-containing compounds to the mycorrhizae. Some plants have an obligate association with the mycorrhizae. For example, Pinus seeds cannot germinate and establish

Topic: Biology, Transport in Plants, NEET
In which of the following sexual reproduction is of oogamous type and accompanied by complex post-fertilization development?

Options:
A Ulothrix
B Spirogyra
C Polysiphonia
D Ectocarpus

The correct answer is:
Polysiphonia

Solution:
In red algae sexual reproduction is complex, gametes are non motile and complex method of gamete transfer occurs. Sexual reproduction is oogamous and complex post fertilization development occurs. Polysiphonia is red algae.

Topic: Biology, Plant Kingdom, NEET
In which of the following situations does an applied force not result in a change in kinetic energy?

Options:
A A book resting on a table
B A car accelerating on a straight road
C A charged particle moving in a uniform magnetic field
D A ball rolling down a hill

The correct answer is:
A charged particle moving in a uniform magnetic field

Solution:
Correct Option is : (C)
A charged particle moving in a uniform magnetic field

Topic: Chemistry, Work Power Energy, NEET
In which of the following situations would the decomposition of gaseous ammonia on a hot platinum surface be a zero order reaction?

Options:
A Low pressure
B High temperature
C Low concentration of ammonia
D Low surface area of platinum

The correct answer is:
Low pressure

Solution:
The decomposition of gaseous ammonia on a hot platinum surface is a zero order reaction at high pressure.

Topic: Chemistry, Chemical Kinetics, NEET
In which of the following solution the depression in freezing point is lowest?

Options:
A 0.2 M urea and 0.2 M glucose
B 0.1 M Al2(SO4)3 and 0.1 M Na2SO4
C 0.1 MKNO3 and 0.2 M Ba(NO3)2
D 0.1 M Ca(NO3)2 and 0.1 M Ba(NO3)2

The correct answer is:
0.2 M urea and 0.2 M glucose

Solution:
As ΔTf∝m×i
Urea and glucose do not dissociate in aqueous medium, hence their solution has lowest depression in freezing point as for them i is only 1. It will be maximum for 0.1 M Al2(SO4)3 and 0.1 M Na2SO4 as m×i will be maximum for them.
Δ T f ∝i×m
T f ∝ 1 i⋅m
∴ Δ T f =0= T f

Topic: Chemistry, Solutions, NEET
In which of the following species, d-orbitals having xz and yz two nodal planes involved in hybridisation of central atom?

Options:
A IO2F2-
B CIF4-
C IF7
D All of these

The correct answer is:
IF7

Solution:
IO2F2-: Hybridisation sp 3 d, â¡s,â p x ,â p y ,â p z ,â d z 2
ClF4-: Hybridisation sp 3 d 2 ââ¡ s,â p x ,â p y ,â p z , d x 2 â y 2 â d z 2
IF7: Hybridisation sp 3 d 3 s,  p x ,  p y ,  p z ,d x 2 − y 2 d xy ,d z 2
dxy: orbital has two nodal planes xz and yz.

Topic: Chemistry, Chemical Bonding and Molecular Structure, NEET
In which of the following species the central atom has the type of hybridsation which is not the same as that present in the other three?

Options:
A PCl5
B SF4
C I3-
D SbCl52-

The correct answer is:
SbCl52-

Solution:
Here SbCl52- is having sp3d2 hybridisation while in all other the hybridization is sp3d .

Topic: Chemistry, Chemical Bonding and Molecular Structure, NEET
In which of the following steps of aerobic respiration of glucose, carbon dioxide is evolved?

I. Glycolysis
II. Link reaction
III. Krebs cycle
IV. Electron transport system

Options:
A I and II
B I, II and III
C II, III and IV
D II and III

The correct answer is:
II and III

Solution:
In the link reaction pyruvic acid is converted into acetyl coenzyme A also producing reduced coenzyme NADPH + H+ and carbon dioxide in the presence of enzyme pyruvate dehydrogenase. In the Kreb's cycle, carbon dioxide is evolved at two points:
a. During the conversion of isocitric acid to oxalosuccinic acid.
b. During the conversion of alpha-ketoglutaric acid to succinyl co-A

Topic: Biology, Respiration in Plants, NEET
In which of the following structure cartilage is absent?

Options:
A Tip of nose
B External ear pinna
C Between the cranial bones
D Between the two adjacent bones of the vertebral column

The correct answer is:
Between the cranial bones

Solution:
Cartilage - Intercellular material is solid, pliable and incompressible. Matrix is having small cavities in which chondrocytes (cells) are present.
Occurrence: During embryonic stages, most of the endoskeleton was made up of cartilage which is gradually replaced by bones.
Other sites: Tip of nose, outer ear joints, between vertebra, limbs and hands.

Topic: Biology, Structural Organisation in Animals, NEET
In which of the following systems will the radius of the first orbit be minimum?

Options:
A Hydrogen atom
B Deuterium atom
C Singly ionized Helium
D Doubly ionized Lithium

The correct answer is:
Doubly ionized Lithium

Solution:
If r0 is radius of first orbit in Hydrogen atom then radius of first orbit in Hydrogen like atoms is given by r=r0Z.
For Hydrogen, Z=1
For Deuterium, Z=1
For singly ionized Helium He+, Z=2
For doubly ionized Lithium Li2+, Z=3
∴ Radius of the first orbit, r is minimum for doubly ionized Lithium.

Topic: Physics, Atomic Physics, NEET
In which of the following systems will the radius of the first orbit $(n=1)$ be minimum?

Options:
A Doubly ionized lithium
B Singly ionized helium
C Deuterium atom
D Hydrogen atom

The correct answer is:
Doubly ionized lithium

Solution:
Radius of the first orbit of an atom \(R_1=\frac{0.529}{Z} A^{\circ}\)
\(\Rightarrow \mathrm{R}_1 \propto \frac{1}{\mathrm{Z}}\)
where \(Z\) is the atomic number of Hydrogen-like atom.
Since \(Z\) is maximum for doubly ionized lithium, thus radius of first orbit is minimum in doubly ionized lithium.

Topic: Physics, Atomic Physics, NEET, NEET 2003
In which of the following techniques, the mRNA is prevented from undergoing translation due to the presence of a complementary segment?

Options:
A Gene gun technology
B DNA interference
C RNA interference
D Gene deletion

The correct answer is:
RNA interference

Solution:
RNA interference (RNAi) is a process where a particular mRNA is not allowed to undergo translation by binding it with a complementary segment of mRNA. As a result, a dsRNA is formed which makes the original mRNA useless for making protein. This has been observed to be a cellular defence mechanism and utilised in developing a transgenic Tobacco plant that is resistant to pest Meloidegyne incognita.

Topic: Biology, Biotechnology and Its Applications, NEET
In which of the following the pollen tube enters via chalaza?

Options:
A Ottelia
B Casuarina
C Cucurbita
D Both (A) and (C)

The correct answer is:
Casuarina

Solution:
There are three possible ways for the pollen tube to enter the embryo sac:
1. In most of the cases, a pollen tube enters through Micropyle, called Porogamy (as seen in Ottelia).
2. In Casuarina, the pollen tube enters through chalaza, called Chalazogamy.
3. In Cucurbita, the pollen tube enters through integuments or funicle, called mesogamy.

Topic: Biology, Sexual Reproduction in Flowering Plants, NEET
In which of the following tissue, cells of the tissue are enclosed in small cavities within the solid and pliable matrix secreted by them?

Options:
A Dense connective tissue
B Loose connective tissue
C Bone
D Cartilage

The correct answer is:
Cartilage

Solution:
Intercellular material is solid, pliable and incompressible. Matrix is having small cavities in which chondrocytes (cells) are present. Occurrence: During embryonic stages, most of the endoskeleton was made up of cartilage which is gradually replaced by bones. Other sites: Tip of nose, outer ear joints, between vertebra, limbs and hands.

Topic: Biology, Structural Organisation in Animals, NEET
In which of the following transformations, the bond order has increased and the magnetic behaviour has changed?

Options:
A C2+→C2
B NO+→NO
C O2→O2+
D N2→N2+

The correct answer is:
C2+→C2

Solution:
On the basis of molecular orbital theory the value of bond order and magnetic nature can be given as
C2+BO=1.5Paramagnetic→C2BO=2Diamagnetic
NO+BO=3Diamagnetic→NOBO=2.5Paramagnetic
O2BO=2Paramagnetic→O2+BO=2.5Paramagnetic
N2BO=3Diamagnetic→N2+BO=2.5Paramagnetic

Topic: Chemistry, Chemical Bonding and Molecular Structure, NEET
In which of the following transitions will the wavelength be minimum?

Options:
A n=6 to n=4
B n=4 to n=2
C n=3 to n=1
D n=2 to n=1

The correct answer is:
n=3 to n=1

Solution:
ΔE=hc/λ the value of ΔE decreases as we move away from nucleous.

Topic: Chemistry, Structure of Atom, NEET
In which of the following type of pollination, flowers have pollen grains that are light and non-sticky while stigma is large and often feathery?

Options:
A Anemophilous (wind)
B Ornithophilous (birds)
C Hydrophily (water)
D Entomophilous (ants)

The correct answer is:
Anemophilous (wind)

Solution:
Pollination by wind is known as anemophilous and is the more common amongst abiotic pollinations. Wind pollination requires the pollen grains to be light and non-sticky so that they can be transported in wind currents. They often possess well-exposed stamens and large often-feathery stigma
to easily trap airborne pollen grains. Wind pollinated flowers often have a single ovule in each ovary and numerous flowers packed into an inflorescence; a familiar example is the corn cob-the tassels. In maize, pollination is going to happen through the agency of wind.

Topic: Biology, Sexual Reproduction in Flowering Plants, NEET
In which of the following types a ridge is formed along the ventral suture of the ovary?

Options:
A Marginal placentation
B Free central placentation
C Basal placentation
D Axile placentation

The correct answer is:
Marginal placentation

Solution:
In marginal placentation, the placenta forms a ridge along the ventral suture of the ovary and the ovules are borne on this ridge forming two rows, as in pea.

Topic: Biology, Morphology of Flowering Plants, NEET
In which of the following will DNA melt at the lowest temperature?

Options:
A 5′-AATAAAGC-3′3′-TTATTTCG-5′
B 5′-AATGCTGC-3′3′-TTACGACG-5′
C 5′-ATGCTGAT-3′3′-TACGACTA-5′
D 5′-GCATAGCT-3′3′-CGTATCGA-5′

The correct answer is:
5′-AATAAAGC-3′3′-TTATTTCG-5′

Solution:
In a double helix structure of DNA the bases in the two complimentary strands are paired with the help of hydrogen bonds. There are two hydrogen bonds between one adenine and thymine base pairs where as there are three hydrogen bonds between one guanine and cytosine base pairs. The energy required to break the bond between G-C will be more as compared to energy required for A-T bonds. So the DNA with maximum number of A-T pairing will melt faster at lower temperature as compared to others.

Topic: Biology, Molecular Basis of Inheritance, NEET
In which of the following would you expect to find glyoxysomes?

Options:
A Endosperm of wheat
B Endosperm of castor
C Endosperm of gram
D Leaf cells

The correct answer is:
Endosperm of castor

Solution:
Glyoxysomes are present in the fat-rich seed. It carries out a break down of fats into carbohydrates by glyoxylate cycle during seed germination to provide energy to the embryo. It also occurs in other fatty seeds like ground and mustard.

Topic: Biology, Cell - The Unit of Life, NEET
In which of the following would you find retained endospermic tissue even after the formation of the seed?

Options:
A Gram
B Sunflower
C Rice
D Bean

The correct answer is:
Rice

Solution:
In some seeds, the endosperm is retained in the form of a food storing tissue. These seeds are called endospermic seeds which are found in rice, barley, coffee, and castor. The seeds in which the endosperm is completely consumed by the developing embryo. Such seeds are called non-endospermic seeds which include sunflower, bean, and gram.

Topic: Biology, Morphology of Flowering Plants, NEET
In which of the given compound Sulphur has highest oxidation state

Options:
A SO2
B H2SO4
C Na2S2O3
D Na2S4O6

The correct answer is:
H2SO4

Solution:
S*O2=+4 ; H2S*O4=+6
Na2S*2O3=+2 ; Na2S*4O6=+52..

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), NEET
In which of the organic reaction alcoholic solution of KOH is used?

Options:
A Dehalogenation
B Dehydrogenation
C Dehydrohalogenation
D Dehydration

The correct answer is:
Dehydrohalogenation

Solution:
CH3CH2Br+alc KOHâDehydrohalogenation CH2=CH2+KBr+H2O
In alcoholic KOH, hydroxide ions (OH-) are present which is a strong base. They abstract a proton from beta carbon of alkyl halide and favours elimination reaction.

Topic: Chemistry, Haloalkanes and Haloarenes, NEET
In which of the polymer the monomers used are not correctly given

Options:
A Polyme → Nylon-6,6; Monomers → adipic acid, hexamethylene diamine
B Polymer → Bakelite; Monomers → formaldehyde, phenol
C Polymer → Buna-N; Monomers → buta-1,3-diene, nitrobenzene
D Polymer → Buna-S; Monomers → buta-1,3-diene, styrene

The correct answer is:
Polymer → Buna-N; Monomers → buta-1,3-diene, nitrobenzene

Solution:
Here option C is wrong as Buna-N is a copolymer of buta-1,3-diene and vinyl cyanide.

Topic: Chemistry, Polymers, NEET
In which of the processes is both the DNA strands transcribed?

Options:
A PCR
B DNA replication
C RNAi
D Southern blotting

The correct answer is:
RNAi

Solution:
RNAi or RNA interference is the process in which a double stranded RNA is synthesized which binds to and inhibits the translation of specific mRNA. For formation of ds RNA both sense strand and anti sense strand of DNA are transcribed.

Topic: Biology, Biotechnology and Its Applications, NEET
In which of the properties listed below hydrogen does not show resemblance with halogens
I. Electropositive character
II. Electronegative character
III. Neutral nature of H2O
IV. Atomicity

Options:
A I and III
B I only
C II and III
D III and IV

The correct answer is:
I and III

Solution:
hydrogen does not show resemblance with halogens in Electropositive character and Neutral nature of H2O as halogens have electronegative character and H2O does not resemble with oxides formed by halogens.

Topic: Chemistry, s Block Elements, NEET
In which of the reaction formation of Diazonium salt takes place?

Options:
A
B
C
D

The correct answer is:

Solution:

Topic: Chemistry, Amines, NEET
In which of the sols, the colloidal particles are with negative charge?

Options:
A TiO2
B Haemoglobin
C Starch
D Hydrated Aℓ2O3

The correct answer is:
Starch

Solution:
In general natural colloids are negative sol. Starch is example of negative sol.

Topic: Chemistry, Surface Chemistry, NEET, NEET 2020 (Phase 2)
In which of these cyclic compounds you find the minimum angle strain?

Options:
A C3H6
B C4H8
C C5H10
D C6H12

The correct answer is:
C6H12

Solution:
According to Baeyer's strain theory:-

Stability of cycloalkane is inversely proportional to the angle of strain Î¸ means a greater angle of strain lesser stability of cycloalkane (till cyclohexane).

Stability order of cycloalkane:

C 3 H 6 < C 4 H 8 < C 5 H 10 < C 6 H 12 Minimum Î¸ â

Topic: Chemistry, General Organic Chemistry, NEET
In which of these disease's does the patient doesn't have the same number of chromosomes as the rest?

Options:
A Down's syndrome
B Edward's syndrome
C Turner's syndrome
D Klinefelter's syndrome

The correct answer is:
Turner's syndrome

Solution:
The presence of an extra chromosome in diploid chromosome number is called trisomy. It is represented by 2n+1 . Here the patient has 47 chromosomes instead of 46. Trisomy of the 21st pair of chromosome- Down's syndrome. Trisomy of the 18th pair of chromosome- Edward's syndrome. Trisomy of the 13th pair of chromosome- Patau syndrome. Klinefelter's syndrome is due to presence of an extra X chromosome in males. The patient's cells contain one additional X chromosome along with XY. Thus their genotype is represented by 44+XXY and they have 47 chromosomes. The absence of a chromosome in diploid chromosome number is called monosomy. It is represented by ` 2n-1 .Thus they have 45 chromosomes. Turner's syndrome is due to absence of one X chromosome in females. The patient's cells contain only one X chromosome instead of two. Thus their genotype is represented by 44+XO

Topic: Biology, Principles of Inheritance and Variation, NEET
In which of these options, the plants are correctly matched with the modification seen in them?

Phylloclade	Phyllode	Cladode

(i)	Opuntia	Asparagus	Acacia

(ii)	Casuarina	Opuntia	Asparagus

(iii)	Euphorbia	Asparagus	Casuarina

(iv)	Euphorbia	Opuntia	Acacia

Options:
A (i)
B (ii)
C (iii)
D (iv)

The correct answer is:
(i)

Solution:
Phylloclade is green photosynthetic flattened or rounded succulent stem with reduced leavesmodified into spines. Phylloclade is seen in Opuntia, Casuarina, Euphorbia, Cactus. Cladode is a also a modification of stem which usually is one or two internodes long and is succulent. Cladode is seen in Asparagus and Ruscus.Phyllode is a modification of leaf in which its petiole becomes flat and functions as normal leaf. It is seen in Australian acacia.

Topic: Biology, Morphology of Flowering Plants, NEET
In which of these plants, the diploid stage of their life is dependent on the haploid stage of their life?

Options:
A Riccia, Marchantia
B Pinus, Cycas
C Nephrolepis, Adiantum.
D Hibiscus, Cycas

The correct answer is:
Riccia, Marchantia

Solution:
Bryophytes have a haplo-diplontic life cycle in which haploid gametophyte is a dominant, independent, photosynthetic, thalloid, or erect and it alternates with the short-lived multicellular sporophyte totally or partially dependent on the gametophyte for its anchorage and nutrition. Riccia and Marchantia are liverworts a type of bryophyte. In gymnosperms (Cycas and Pinus) and in angiosperms (Hibiscus) diplontic life cycle is seen in which sporophyte is independent. In pteridophytes (Nephrolepis and Adiantum), the sporophyte and gametophyte both are photosynthetic and independent.

Topic: Biology, Plant Kingdom, NEET
In which of these points did Darwin believe?

Options:
A Every organism has an internal vital force that tends to increase its size up to a certain limit.
B Variations appear due to change in genetic make up
C The organs put to more use will develop more while organs not used begin to degenerate.
D All living cells produce minute particles which pass into germ cells for transmission to the offspring.

The correct answer is:
All living cells produce minute particles which pass into germ cells for transmission to the offspring.

Solution:
Lamarck believed that every organism has an internal vital force that tends to increase its size up to a certain limit. He also believed that the organs put to more use will develop more while organs not used begin to degenerate. Genetics were never a part of Darwin's theory. Darwin proposed the theory of pangenesis which states that all living cells produce minute particles called pangenes which pass into germ cells for transmission to the offspring.

Topic: Biology, Evolution, NEET
In which one of the following arrangements the given sequence is not strictly according to the properties indicated against it?

Options:
A HF<HCl<HBr<HI: Increasing acidic strength
B H2O<H2 S<H2Se<H2Te: Increasing pKa values
C NH3<PH3<AsH3<SbH3: Increasing acidic character
D CO2<SiO2<SnO2<PbO2: Increasing oxidizing power

The correct answer is:
H2O<H2 S<H2Se<H2Te: Increasing pKa values

Solution:
1) HF<HCl<HBr<HI bond strength decreases therefore, acidic strength increases.
2) H2O<H2 S<H2Se<H2Te from going down the group bond length increase so bond strength decreases therefore, acidic nature of these will increase but pKa will decrease.
So, this given order is wrong.
3) NH3<PH3<AsH3<SbH3 from going down the group bond length increases, so bond strength decreases therefore, acidic nature of these will increase
4) CO2<SiO2<SnO2<PbO2 From going down the group stability of higher oxidation state decreases due to inert pair effect therefore, their tendency to reduce will increase, so their oxidizing power will increase.

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), NEET, NEET 2021
In which one of the following, do both the names refer to the same thing?

Options:
A Tricarboxylic acid cycle and urea cycle
B Krebs cycle and Calvin cycle
C Tricarboxylic acid cycle and citric acid cycle
D	Citric acid cycle and Calvin cycle

The correct answer is:
Tricarboxylic acid cycle and citric acid cycle

Solution:
The TCA cycle is also called the citric acid cycle because the first stable product formed is a tricarboxylic acid molecule that is citric acid. Hence the name citric acid cycle. It is also called the Kreb's cycle.

Topic: Biology, Respiration in Plants, NEET
In which one of the following do the two names refer to one and the same thing ?

Options:
A Krebs' cycle and Calvin cycle
B tricarboxylic acid cycle and citric acid cycle
C citric acid cycle and Calvin cycle
D tricarboxylic acid cycle and urea cycle

The correct answer is:
tricarboxylic acid cycle and citric acid cycle

Solution:
Tricarboxylic acid cycle is the same as citric acid cycle. It is also known as Krebs cycle. It is called so as the first compound formed is citric acid which is a tricarboxylic acid with carboxyl groups.

Topic: Biology, Respiration in Plants, NEET, NEET 2003
In which one of the following habitats does the diurnal temperature of soil surface vary most?

Options:
A shrub land
B forest
C desert
D grassland.

The correct answer is:
desert

Solution:
Deserts have a very hot days and very cold nights. Due to bare plant cover, the soil of desert is much more exposed to these fluctuations as compared to that of other areas. During day time, the soil becomes hot and in night it frequently, becomes cool. This is one of the reasons for poor vegetation and faunal population in deserts.

Topic: Biology, Ecosystem, NEET, NEET 2004
In which one of the following is nitrogen not a constituent?

Options:
A idioblast
B bacteriochlorophyll
C invertase
D pepsin

The correct answer is:
idioblast

Solution:
Idioblasts are parenchyma cells which store tannins, resins etc. it is an isolated cell found in cells of plant tissue, in the middle of homogenous group of cells. Idioblastic parenchyma have various functions such as storage of reserves, excretory materials, pigments, and minerals.
Related Theory
Idioblasts can contain biforine cells that form crystals.

Topic: Biology, Anatomy of Flowering Plants, NEET, NEET 2003