datavorous/entrance-exam-dataset huggingface dataset:
If the number of chromosomes in root cells is 14, what will be the number of chromosomes in synergid cells of an ovule of that parent?

Options:
A 7
B 14
C 21
D Incomplete information

The correct answer is:
7

Solution:
The number of chromosomes in root cells is 2n, while it is n in synergid cells because it develops by reductional division. Root cells are diploid in nature and thus has 2n = 14. Whereas, synergids are haploid, n = 7.

Topic: Biology, Sexual Reproduction in Flowering Plants, NEET
If the osmotic pressure of a 0.010 M aqueous solution of sucrose at 27oC is 0.25 atm, then the osmotic pressure of a 0.010 M aqueous solution of NaCl at 27oC is

Options:
A 0.062 atm
B 0.12 atm
C 0.25 atm
D 0.50 atm

The correct answer is:
0.50 atm

Solution:
Osmotic pressure =iCRT , For both the solutions, all other conditions are simtextlar except i which is 1.0 for sucrose while 2.0 for NaCl.
Therefore, osmotic pressure of NaCl
=2Ã0.25
=0.50 atm

Topic: Chemistry, Solutions, NEET
If the ovary is half inferior, then it would be called:

Options:
A Hypogynous
B Perigynous
C Epigynous
D Both (1) and (2)

The correct answer is:
Perigynous

Solution:
If the gynoecium is situated in the centre and other parts of the flower are located on the rim of the thalamus almost at the same level, it is called perigynous. The ovary here is said to be half inferior, e.g. Plum, rose, peach, etc.

Topic: Biology, Morphology of Flowering Plants, NEET
If the over-bridge is concave instead of being convex, the thrust on the road at the lowest position will be

Options:
A mg+mv2r
B mg-mv2r
C m2v2gr
D v2gr

The correct answer is:
mg+mv2r

Solution:
Thrust at the lowest point is N
N=FP+mg
N=mg+mV2R

Topic: Physics, Laws of Motion, NEET
If the $\mathrm{pH}$ in lysosomes is increased to alkaline, what will be the outcome?

Options:
A Hydrolytic enzymes will function more efficiently
B Hydrolytic enzymes will become inactive
C Lysosomal enzymes will be released into the cytoplasm
D Lysosomal enzymes will be more active

The correct answer is:
Hydrolytic enzymes will become inactive

Solution:
Lysosomal enzymes are generally Hydrolytic enzymes which are functional in Acidic $\mathrm{pH}$ only. When $\mathrm{pH}$ is turned to basic, medium these enzymes will become inactive.

Topic: Biology, Cell - The Unit of Life, NEET, NEET 2022 (Phase 2)
If the phase difference between two waves of the same frequency is 2π during superposition, then the resultant amplitude is

Options:
A maximum
B minimum
C maximum or minimum
D none of the above

The correct answer is:
maximum

Solution:
Phase difference is 2π means constrictive interference so resultant amplitude will be maximum.

Topic: Physics, Waves and Sound, NEET
If the photon of the wavelength 150 pm strikes an atom and one of its inner bound electrons is ejected out with a velocity of 1.5 × 107m s–1, calculate the energy with which it is bound to the nucleus.

Options:
A 8.9 × 103eV
B 7.6 × 103eV
C 6.1 × 103eV
D 4.6 × 103eV

The correct answer is:
7.6 × 103eV

Solution:
Correct Option is : (B)
7.6 × 103eV

Topic: Chemistry, Structure of Atom, NEET
If the pin hole in the container is very small compared to the area of the base of container and a block floats in the ideal liquid then, the speed of efflux is

Options:
A less than 2gh
B greater than 2gh
C equal to 2gh
D equal to 2gH

The correct answer is:
equal to 2gh

Solution:
Applying Bernoulli's theorem between free surface and orifice,
p0+12ÏV2+ Ïgh =p0+12Ïv2
A>>a
So, V<<v
v= 2gh

Topic: Physics, Mechanical Properties of Fluids, NEET
If the pituitary gland of an adult rat is surgically removed, which of the following endocrine glands will be the least affected?

Options:
A Adrenal cortex
B Adrenal medulla
C Thyroid
D Gonads

The correct answer is:
Adrenal medulla

Solution:
The anterior lobe of pituitary gland secretes Thyroid Stimulating Hormone (TSH), which controls the structure, and functioning of thyroid and Adrenocorticotropic Hormone (ACTH) which controls the structure and functioning of the adrenal cortex. Besides, it secretes FSH, LH, ICSH, etc, which affect the structure and functioning of gonads.
So, if the pituitary gland of an adult rat is surgically removed, out of the four options adrenal medulla will be less affected.

Topic: Biology, Chemical Coordination and Integration, NEET
If the position of the electron is measured within an accuracy of ±0.002 nm, calculate the uncertainty in the momentum of the electron.

Options:
A 3.426 × 10−23kg ms−1
B 2.638 × 10−23kg ms−1
C 4.863 × 10−23kg ms−1
D 5.123 × 10−23kg ms−1

The correct answer is:
2.638 × 10−23kg ms−1

Solution:
Correct Option is : (B)
2.638 × 10−23kg ms−1

Topic: Chemistry, Structure of Atom, NEET
If the potential of a capacitor having capacity 6 Î¼F is increased from 10 V to 20 V, then increase in its energy is

Options:
A 12×10-6 J
B 9Ã10-6 J
C 4.5×10-6 J
D 2.25×10-6 J

The correct answer is:
9Ã10-6 J

Solution:
In a capacitor, energy is stored in the electric field between the plates.
Increase in energy
âU=Uf-Ui
=12CVf2-12CVi2=12C(Vf2-Vi2)
Given, C=6 Î¼F=6Ã10-6, Vi=10 V

Vf =20 V
â´âU=12Ã6Ã10-6[202-102]
=3Ã10-6Ã300=9Ã10-4 J

Topic: Physics, Electrostatics, NEET
If the principal quantum number n=6, the correct sequence of filling of electrons will be:

Options:
A ns→n-1 d→n-2 f→np
B ns→np→n-1d→n-2f
C ns→n-2f→np→n-1d
D ns→n-2f→n-1d→np

The correct answer is:
ns→n-2f→n-1d→np

Solution:
As per n+l rule electrons fill first in that orbital which have least n+l value.
When n+l values are same, then electron fills that orbital which have lowest n value.
when n=6 as per n+l rule when n=6
ns subshell â6+0=6
nâ1 d subshell â5+2=7
nâ2 f subshell â4+3=7
np subshell â6+1=7
ns , n-2f, n-1d,np
n+l values â7, 7, 7
n value â4, 5, 6

Topic: Chemistry, Structure of Atom, NEET
If the protoplast of tomato is fused with potato protoplast and grown as new plant, it will be known as

Options:
A Explant
B Somaclones
C Callus
D Somatic hybrid

The correct answer is:
Somatic hybrid

Solution:
Somatic hybridization is the process by which two somatic cells are fused to form a hybrid cell. The isolated protoplast of these cells are fused by treating the protoplast with polyethene glycol, the hybrid cell thus produced is called somatic hybrid. The somatic hybrid of potato and tomato is named as pomato.

Topic: Biology, Strategies for Enhancement in Food Production, NEET
If the radii of A+ and B- in the crystalline solid AB are 96 pm and 200 pm respectively. Then expected structure of AB will be

Options:
A trigonal
B octahedral
C hexagonal
D cubic

The correct answer is:
octahedral

Solution:
r+r-=96200=0.48
Radius ratio lies between (0.414 to 0.732) hence the solid has octahedral structure.

Topic: Chemistry, Solid State, NEET
If the radius of 27Al nucleus is R1, then the radius of â33125Te will be

Options:
A 53R1
B 35R1
C 135312R1
D 531313R1

The correct answer is:
53R1

Solution:
Since, we know, the radius of a nucleus,
R=R0A13
Given, AAl=27 and ATe=125
∴R1R2=AAlATe13=2712513
∴R2=53R1

Topic: Physics, Nuclear Physics, NEET
If the radius of a nucleus with mass number 125 is 1.5 fm, then the radius of a nucleus with mass number 64 is

Options:
A 0.48 fm
B 0.96 fm
C 1.92 fm
D 1.2 fm

The correct answer is:
1.2 fm

Solution:
By Rutherford's experiment
R1=R0A113 .....(i)
R2=R0 A213 ......(ii)
Given,
R1=1.5 fm
A1=125
A2=64
Now, R1R2=A1A213 [from the equation (i) and (ii)]
1.5R2=1256413
â 1.5R2=54
â R2=1.5Ã45=0.3Ã4
=1.2 fm

Topic: Physics, Atomic Physics, NEET
If the radius of a sphere is measured to be (2.1Â±0.05) cm. Calculate the surface area (in cm2 ) .

Options:
A 54.45 ± 2.46
B 55.44 Â± 2.64
C 52.03 ± 4.26
D 45.54 ± 2.68

The correct answer is:
55.44 Â± 2.64

Solution:
S=4Ïr2=4Ã227Ã(2.1)2

=55.44cm2

ÎSS=2Îrr

ÎS=2ÎrrS

=2Ã0.05Ã55.442.1=2.64

â´ ÎS=(55.44Â±2.64) cm2

Topic: Physics, Experimental Physics, NEET
If the radius of a star is $R$ and it acts as a black body, what would be the temperature of the star, in which the rate of energy production is $Q$ ?
( $\sigma$ stands for Stefan's constant.)

Options:
A $Q / 4 \pi R^2 \sigma$
B $\left(\mathrm{Q} / 4 \pi \mathrm{R}^2 \sigma\right)^{-1 / 2}$
C $\left(4 \pi R^2 Q / \sigma\right)^{1 / 4}$
D $\left(Q / 4 \pi R^2 \sigma\right)^{1 / 4}$

The correct answer is:
$\left(Q / 4 \pi R^2 \sigma\right)^{1 / 4}$

Solution:
From Stefan' law,
$E=\sigma T^4$
So, the rate energy production
$\begin{aligned}
& Q=E \times A \\
& Q=\sigma T^4 \times 4 \pi R^2
\end{aligned}$
Temperature of star
$T=\left(\frac{Q}{4 \pi R^2 \sigma}\right)^{1 / 4}$

Topic: Physics, Thermal Properties of Matter, NEET, NEET 2012 (Screening)
If the radius of curvature of the curved surface of a plano-convex lens is 50 cm, its focal length is Î¼=1.5

Options:
A 0.5 m
B 0.75Â m
C 0.25Â m
D 1 m

The correct answer is:
1 m

Solution:
From lens maker's formula,
1f=n-1 1R1-1R2
Given, n=1.5
R1=∞ (Plane surface)
R2= -50 cm=-0.5 m
1f=1.5-1×10.5
=0.5×10.5=1 m

Topic: Physics, Ray Optics, NEET
If the radius of first Bohr orbit is x pm, then the radius of the third orbit would be

Options:
A (3×x)pm
B (6×x)pm
C 12×xpm
D (9×x)pm

The correct answer is:
(9×x)pm

Solution:
Radius in nth orbit = Bohr radius ×n2
r3=x×n2=x×32
=(9×x)pm

Topic: Chemistry, Structure of Atom, NEET
If the radius of first Bohr's orbit of hydrogen is x, then the de-Broglie wavelength of the electron in its 3rd orbit is

Options:
A 2πx
B 6πx
C 9x
D x3

The correct answer is:
6πx

Solution:
r n ∝ n 2 z
for Hydrogen atom, (z=1), r n ∝ n 2
r 1 =x
r 3 =9x
Now, ⇒ 2πr 3 =nλ
⇒λ= 2 πr 3 3
⇒λ= 2 3 π×9x
∴ λ=6πx

Topic: Physics, Atomic Physics, NEET
If the radius of the earth is R, then the height h at which the value of g becomes one-fourth, will be

Options:
A R8
B R
C 3R4
D R2

The correct answer is:
R

Solution:
g ′ = g ( 1+ h R ) 2 = g 4
1+ h R =2
⇒h=R

Topic: Physics, Gravitation, NEET
If the radius of the first orbit of the hydrogen atom is 0.53 Aâ , then the de-Broglie wavelength of the electron in the ground state of hydrogen atom will be

Options:
A 0.53 A∘
B 3.33 Aâ
C 1.67 A∘
D 1.06 A∘

The correct answer is:
3.33 Aâ

Solution:
According to Bohr's quantization condition
mvr=nh2π
∴ h mv= 2πrn ... (i)
âµ de-Broglie wavelength
λ=hmv ... (ii)
From Eqs. (i) and (ii),
λ=2πrn
âµ Electron in the ground state
r=0.53 A∘ and n = 1
⇒λ=2π×0.53 A∘1
=3.33 A∘

Topic: Physics, Atomic Physics, NEET
If the radius of the octahedral void is ' \(r\) ' and the radius of the atoms in close packing is ' \(R\) ', derive the relation between ' \(r\) ' and ' \(R\) '.

Options:
A \(r=\sqrt{\frac{2}{3}} R\)
B \(r=\frac{\sqrt{2}}{2} R\)
C \(r=\frac{R}{2}\)
D \(r=\frac{\sqrt{3}}{2} R\)

The correct answer is:
\(r=\frac{\sqrt{2}}{2} R\)

Solution:
Correct Option is : (B)
\(r=\frac{\sqrt{2}}{2} R\)

Topic: Chemistry, Solid State, NEET
If the rate constant for a first order reaction is k, the time (t) required for the completion of 99% of the reaction is given by

Options:
A t=0.693/k
B t=6.909/k
C t=4.606/k
D t=2.303/k

The correct answer is:
t=4.606/k

Solution:
k=2.303tlogaa-x

a=100

a-x=100-99=1

k=2.303tlog1001

t=4.606k

Topic: Chemistry, Chemical Kinetics, NEET, NEET 2019 (All India)
If the rate of diffusion of A is 5 times that of B, what will be the density ratio of A and B?

Options:
A 1:â25
B 1: 5
C 25: 1
D 5:â1

The correct answer is:
1: 25

Solution:
rArB=dBdA
It is given that rA=5rB
â´ 5rBrB=dBdA
dA=125dB i.e., dAdB=125

Topic: Chemistry, States of Matter, NEET
If the rate of emission of energy from a star is 2.7×1036 J/sec , the rate of loss of mass in the star will be

Options:
A 3×1018kg/sec
B 3×1019kg/sec
C 3×1020kg/sec
D 3×1021kg/sec

The correct answer is:
3×1019kg/sec

Solution:
E=mc2
∴ m=Ec2=2.7×10369×1016
=27×10359×1016=3×1019kg/sec

Topic: Physics, Dual Nature of Matter, NEET
If the rate of the reaction is equal to the rate constant, the order of the reaction is:

Options:
A 0
B 1
C 2
D 3

The correct answer is:
0

Solution:
In first order reaction,
$\begin{array}{l}
-\frac{d x}{d t}=\mathrm{K}, \text { it means }-\frac{d x}{d t}=\mathrm{K}[\mathrm{A}]^{\circ} \\
=\mathrm{K}
\end{array}$

Topic: Chemistry, Chemical Kinetics, NEET, NEET 2003
If the ratio of intensities (maximum and minimum) in Young's double slit experiment is 9 : 1, then ratio of amplitude of the coherent sources is

Options:
A 9 : 1
B 3 : 1
C 2 : 1
D 1 : 1

The correct answer is:
2 : 1

Solution:
According to the question :
Imax.Imin.=91=a1+a22a1-a22 or a1+a2a1-a2=91
⇒a1=2 and a2=1
∴a1a2=21

Topic: Physics, Wave Optics, NEET
If the ratio of relative permeability and relative permittivity of a uniform medium is $1: 4$. The ratio of the magnitudes of electric field intensity $(E)$ to the magnetic field intensity $(H)$ of an EM wave propagating in that medium is
(Given that $\sqrt{\frac{\mu_0}{\varepsilon_0}}=120 \pi$ )

Options:
A $30 \pi: 1$
B $1: 120 \pi$
C $60 \pi: 1$
D $120 \pi: 1$

The correct answer is:
$60 \pi: 1$

Solution:
$\frac{\mu_r}{E_r}=\frac{1}{4}$
$\frac{E}{H}=\frac{E \mu}{B}=v \mu$
$=\frac{1}{\sqrt{\mu \varepsilon}} \mu=\sqrt{\frac{\mu}{\varepsilon}}=\sqrt{\frac{\mu_0 \mu_r}{\varepsilon_0 \varepsilon_r}}$
$=\sqrt{\frac{\mu_0}{\varepsilon_0}} \sqrt{\frac{\mu_r}{\varepsilon_r}}$
$=120 \pi\left(\frac{1}{2}\right)$
$=\frac{60 \pi}{1}$

Topic: Physics, Magnetic Properties of Matter, NEET, NEET 2024 (Re-NEET)
If the ratio of specific heat of a gas at constant pressure to that at the constant volume is Î³ , the change in internal energy of the mass of gas, when the volume changes from V to 2V at constant pressure p, is

Options:
A R / γ - 1
B pV
C pV / Î³ - 1
D γ pV / γ - 1

The correct answer is:
pV / γ - 1

Solution:
Î U = n C v Î T
Also, C p C v = Î³
Hence C p - C v C v = Î³ - 1
â C v = R / Î³ - 1
Î U = nR Î³ - 1 Î T = p Î V Î³ - 1 = p 2 V - V Î³ - 1 = pV Î³ - 1

Topic: Physics, Thermodynamics, NEET
If the ratio of the concentration of electrons and that of holes in a semiconductor is 7 / 5 and the ratio of their currents is 7 / 4, then the ratio of their drift velocities is

Options:
A 4 / 7
B 5 / 8
C 4 / 5
D 5 / 4

The correct answer is:
5 / 4

Solution:
Drift velocity vd=InAe
vdelectronvdhole=IeIhnhne=74×57=54.

Topic: Physics, Current Electricity, NEET
If the ratio of the concentration of electrons and that of holes in a semiconductor is 7 / 5 and the ratio of their currents is 7 / 4 , then the ratio of their drift velocities is

Options:
A 4 / 7
B 5 / 8
C 4 / 5
D 5 / 4

The correct answer is:
5 / 4

Solution:
Drift velocity vd=InAe
vdelectronvdhole=IeIhnhne=74Ã57=54.

Topic: Physics, Current Electricity, NEET
If the ratio of the radius of a nucleus with 61 neutrons to that of helium nucleus is 3, then the atomic number of this nucleus is

Options:
A 27
B 47
C 51
D 61

The correct answer is:
47

Solution:
The radius is directly proportional to 13 power of mass number, i.e., R∝A13
Or A1A2=R1R23=133=127
⇒ A2A1=27
⇒ A2=A1×27
=4×27=108
⇒ Z2=A2-61
=108-61=47

Topic: Physics, Nuclear Physics, NEET
If the reactivity factor for chlorine substitution through free radical by abstracting a primary
H-atom is 1 then the ratio of the amount of product A and B is â

Options:
A 1:1
B 1:2
C 2:1
D 3:1

The correct answer is:
2:1

Solution:
[A][B]=Reactivity factor × No. of H-atomReactivity factor × No. of H-atom=1×61×3=21

Topic: Chemistry, Haloalkanes and Haloarenes, NEET
If the refracting angle of a prism is 60°and the minimum deviation 30° , the angle of incidence will be

Options:
A 30°
B 45°
C 60°
D 90°

The correct answer is:
45°

Solution:
δm=30°
A=60°
i=A+δm2
⇒i=60+302
i=45°

Topic: Physics, Ray Optics, NEET
If the refracting angle of a prism is 60o and minimum deviation is 30o, the angle of incidence is

Options:
A 30o
B 45o
C 60o
D 90o

The correct answer is:
45o

Solution:
We know that angle of incidence is
i=δm+A2
i=30o+60o2
i=45o

Topic: Physics, Ray Optics, NEET
If the relative permittivity and permeability of a given material are Îµ r and Î¼ r , respectively then, which among the following is correct for a diamagnetic material?

Options:
A Îµ r = 1.5 , Î¼ r = 1.5
B Îµ r = 0.5 , Î¼ r = 1.5
C

Îµ r = 1.5 , Î¼ r = 0.5

D Îµ r = 0.5 , Î¼ r = 0.5

The correct answer is:

Îµ r = 1.5 , Î¼ r = 0.5

Solution:
The values of relative permeability of diamagnetic materials are slightly less than 1 and Îµ r is quite high. According to the table given, one takes Îµ r = 1.5 and Î¼ r = 0.5 . The choice ( Îµ r = 1.5 , Î¼ r = 0.5) is correct.

Topic: Physics, Magnetic Effects of Current, NEET
If the resistance of potentiometer wire is 15r then calculate the balance length l

Options:
A 320 cm
B 200Â cm
C 400Â cm
D 100Â cm

The correct answer is:
320 cm

Solution:
Potential Difference of external circuit = ϕ× balancing length
E2=EL×RpRp+r×l
⇒E2=E600×15r16r×l
∴ l=600×1630=320 cm

Topic: Physics, Current Electricity, NEET
If the resistance R1 is increased (Fig.), how will the readings of the ammeter change?

Options:
A Increase in ammeter readings
B Decrease in ammeter readings
C No change in ammeter readings
D Fluctuating ammeter readings

The correct answer is:
Decrease in ammeter readings

Solution:
Correct Option is : (B)
Decrease in ammeter readings

Topic: Chemistry, Semiconductors, NEET
If the salts M2X,QY2 and PZ3 have the same solubilities (but < 0.1 M) their, Ksp values are related as

Options:
A Ksp(M2X)=Ksp(QY2)>Ksp(PZ3)
B Ksp(M2X)>Ksp(QY2)=Ksp(PZ3)
C Ksp(M2X)=Ksp(QY2)<Ksp(PZ3)
D Ksp(M2X)>Ksp(QY2)>Ksp(PZ3)

The correct answer is:
Ksp(M2X)=Ksp(QY2)>Ksp(PZ3)

Solution:
Ksp of M2X=4s3
Ksp of QY2=4s3
Ksp of PZ3=27s4
(Note s < 0.1), hence
Ksp(M2X)=Ksp(QY2)>Ksp(PZ3)

Topic: Chemistry, Ionic Equilibrium, NEET
If the same weight is suspended from three springs having lengths in the ratio 1:3:5, the period of oscillations shall be in the ratio of

Options:
A 1:3:5
B 1:3:5
C 15:5:3
D 1:13:115

The correct answer is:
1:3:5

Solution:
T∝1K and K∝1l
∴T∝l
Hence the answer is 1:3:5

Topic: Physics, Oscillations, NEET
If the screen is moved away from the plane of the slits in a Young's double slit experiment, then the:

Options:
A angular separation of the fringes increases
B angular separation of the fringes decreases
C linear separation of the fringes increases
D linear separation of the fringes decreases

The correct answer is:
linear separation of the fringes increases

Solution:
As per YDSE, $x=\frac{\lambda \mathrm{D}}{d}$,
(where, symbols have their usual meanings)
If the screen is moving away from the slits then D increases, and hence the fringe width $(x)$ increases.

Topic: Physics, Wave Optics, NEET, NEET 2022 (Phase 2)
If the seedlings are grown in darkness

Options:
A They are of the same size as those grown in light
B They are much healthier than those grown in light
C They are similar to those grown in light
D They are taller than those grown in light

The correct answer is:
They are taller than those grown in light

Solution:
The seedlings grown in darkness are taller due to the activity of auxin because auxin contents in darkness are high than light.
A signal from the cell wall decides that, in the dark, seeds grow into long yellow sprouts, instead of turning green and forming leaves.

Topic: Biology, Plant - Growth and Development, NEET
If the seedlings are grown in darkness,

Options:
A they are of the same size as those grown in light
B they are much healthier than those grown in light
C they are similar to those grown in light
D they are taller than those grown in light

The correct answer is:
they are taller than those grown in light

Solution:
The seedlings grown in darkness are taller due to the activity of auxin because auxin contents in darkness are high than light.
A signal from the cell wall decides that, in the dark, seeds grow into long yellow sprouts, instead of turning green and forming leaves.

Topic: Biology, Plant - Growth and Development, NEET
If the sequence of bases in one strand of DNA is ATGACTGTC, then the sequence of bases in its complementary strand is

Options:
A TACTGACAG
B TUCTGUCUG
C GUAGTUAUG
D none of the above

The correct answer is:
TACTGACAG

Solution:
In accordance with the base pairing principle, A always faces T, T faces A and G face C in DNA molecules. Therefore, the sequence of bases is TACTGACAG.

Topic: Chemistry, Biomolecules, NEET
If the sequence of nitrogen bases of the coding strand of DNA in a transcription unit is: 5′ – A T G A A T G – 3′, the sequence of bases in its RNA transcript would be;

Options:
A 5′ – A U G A A U G – 3′
B 5′ – U A C U U A C – 3′
C 5′ – C A U U C A U – 3′
D 5′ – G U A A G U A – 3′

The correct answer is:
5′ – A U G A A U G – 3′

Solution:
The sequence of bases in its RNA transcript would be 5′ – A U G A A U G – 3’ as thymine is replaced by uracil in rna.

Topic: Biology, Molecular Basis of Inheritance, NEET
If the sequence of the coding strand of DNA is written as follows. 5' - ATGCATGCA - 3' What is the sequence of complementary strands in the 5'-3' direction?

Options:
A 5'- GCATGCATG - 3'
B 5'- ATCTCGATG - 3'
C 5' - CGTAACTGA-3'
D 5'- ATATATCGTA-3'

The correct answer is:
5'- GCATGCATG - 3'

Solution:
The correct sequence is 5'- GCATGCATG - 3'.

Topic: Biology, Molecular Basis of Inheritance, NEET
If the solubility of $\mathrm{MX}_2$ type electrolyte is $0.5 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1}$, then, find out $\mathrm{K}_{s p}$ of the electrolyte.

Options:
A $5 \times 10^{-12}$
B $25 \times 10^{-10}$
C $1 \times 10^{-13}$
D $5 \times 10^{-13}$

The correct answer is:
$5 \times 10^{-13}$

Solution:
An electrolyte \(\mathrm{MX}_2\) undergoes dissociation as follows :-
\(\mathrm{MX}_2 \rightleftharpoons \mathrm{M}^{+2}+2 \mathrm{X}^{-}\)
\(\begin{array}{|c|c|c|c|}
\hline \text {Concentration } & \mathrm{MX}_2 & \mathrm{M}^{+2} & \mathrm{X}^{-} \\
\hline \text {Initial concentration } & 1 & 0 & 0 \\
\hline \text {Concentration at Equilibrium } & 1-\mathrm{s} & \mathrm{s} & 2 \mathrm{~s} \\
\hline
\end{array}\)
Thus from the above condition we can say that,
\(\mathrm{K}_{\mathrm{sp}}=\mathrm{s} \times(2 \mathrm{~s})^2=4 \times(\mathrm{s})^3\)
Here, s (the solubility) is \(0.5 \times 10^{-4} \mathrm{~mole} / \mathrm{lit}\).
\(\begin{aligned}
& \therefore \mathrm{K}_{\mathrm{sp}}=4 \times\left(0.5 \times 10^{-4}\right)^3 \\
& \therefore \mathrm{K}_{\mathrm{sp}}=5 \times 10^{-13}
\end{aligned}\)

Topic: Chemistry, Ionic Equilibrium, NEET, NEET 2002
If the solubility of three nitrogenous wastes is arranged in the ascending order S1< S2< S3 and their toxicity levels also arranged in ascending order T1< T2< T3, identify the correct option.

Ammonia	Urea	Uric acid

i	S3 T1	S2 T3	S1 T2

ii	S2 T2	S1 T1	S3 T3

iii	S1 T3	S2 T2	S3 T3

iv	S3 T3	S2 T2	S1 T1

Options:
A i
B ii
C iii
D iv

The correct answer is:
iv

Solution:
Ammonia is formed in the liver by the process of oxidative de-amination of amino acids. Among all the modes of excretion, formation of ammonia requires least expenditure of energy. Ammonia is highly toxic to the surrounding tissues and hence it cannot stored be stored in the body for a long time. It is eliminated as soon as it is formed. Ammonia is highly soluble in water and requires a large quantity of water for its removal. 1 gram of ammonia requires 300-500 ml of water for its elimination.
Urea is formed in the liver by the addition of carbon dioxide to ammonia. This process is called ornithine cycle or urea cycle. Among all the modes of excretion, formation of urea requires moderate expenditure of energy. Urea is less toxic than ammonia. Hence it can be stored in the body for some time and can be excreted at a lower rate. Urea is soluble in water and requires a moderate quantity of water for its removal. 1 gram of urea requires 30 ml of water for its elimination.
Uric acid is formed in the liver from ammonia by inosinic acid pathway. In man and other mammals, small quantity of uric acid is formed in the body by breakdown of purine and pyrimidine nitrogen bases of nucleic acid. Among all the modes of excretion, formation of uric acid requires maximum expenditure of energy. Uric acid is least toxic. Hence it can be stored in the body for a long time. Uric acid is insoluble in water and requires very little water for its removal. 1 gram of uric acid requires 10 ml of water for its elimination.

Topic: Biology, Excretory Products and their Elimination, NEET