datavorous/entrance-exam-dataset huggingface dataset:
Polyethylene glycol can be used for

Options:
A biodiesel production
B seedless fruit production
C gene transfer without a vector
D energy production from sewage

The correct answer is:
gene transfer without a vector

Solution:
Biodiesel is formed from vegetable oil, animal oils etc. This is due to esterification of triglyceride. This is the process by which esters are formed due to reaction between alcohols and fatty acids. Sewage is a source of biomass energy. This energy is produced by anaerobic digestion and this produces Biogas. For this the raw material used is sewage sludge. Development of fruits without fertilization is known as parthenocarpy. These fruits have longer shelf life. Polyethylene glycol is used as a chemical method. This brings about gene transfer directly i.e. without using any vector.

Topic: Biology, Biotechnology - Principles and Processes, NEET
Polyethylene glycol method is used for

Options:
A gene transfer without a vector
B biodiesel production
C seedless fruit production
D energy production from sewage

The correct answer is:
gene transfer without a vector

Solution:
Introduction of DNA into plant cells without the involvement of a biological agent and leading to stable transformation is known as direct gene transfer. There are various methods for direct gene transfer, one of which is chemical method. Certain chemicals, eg, PEG (Polythylene Glycol), polyvinyl alcohol and calcium phosphate enhance the uptake of DNA by plant protoplast. PEG and calcium phosphate are thought to precipitate the DNA onto the outer surface of plasmalemma and the precipitate is taken up by the endocytosis.

Topic: Biology, Biotechnology - Principles and Processes, NEET, NEET 2009 (Screening)
Polyethylene glycol method is used for

Options:
A Gene transfer without a vector
B Biodiesel production
C Seedless fruit production
D Energy production from sewage

The correct answer is:
Gene transfer without a vector

Solution:
Polyethylene glycol (PEG) is a hydrocarbon solvent and a fusogen, that attaches cell membranes. PEG is widely used in the induction of cell fusion between plant protoplast and in the production of animal cell hybridoma. During fusion the genetic material gets tranferred between the cells.

Topic: Biology, Biotechnology - Principles and Processes, NEET
Polymer made up of ethylene glycol and terephthalic acid is also known as:

Options:
A Teflon
B Acrilan
C Dacron
D Caprolactam

The correct answer is:
Dacron

Solution:
Correct Option is : 3
Dacron

Topic: Chemistry, Polymers, NEET
Polymer made up of phenol and formaldehyde is also known as:

Options:
A Glyptal
B Polystyrene
C Bakelite
D Urea-formaldehyde resin

The correct answer is:
Bakelite

Solution:
Correct Option is : 3
Bakelite

Topic: Chemistry, Polymers, NEET
Polyp form in Cnidaria is -

Options:
A sessile and cylindrical in hydra
B sessile and umbrella like in Aurelia
C free living and cylindrical in Aurelia
D free living and umbrella like in Hydra

The correct answer is:
sessile and cylindrical in hydra

Solution:
Cnidarians exhibit two types of body forms:
Polyp → It is a sessile and cylindrical form like Hydra.
Medusa → It is umbrella shaped and free swimming like Aurelia.

Topic: Biology, Animal Kingdom, NEET
Polypeptide chain in eukaryotes is initiated by codons coding for amino acid

Options:
A glycine.
B leucine.
C methionine.
D lysine.

The correct answer is:
methionine.

Solution:
mRNA is the transcribed polynucleotide which is later translated by ribosomes using tRNA to join amino acids and make proteins. mRNA contains the genetic code which is a set of instructions that help cells to obtain the information in making proteins from the DNA. The work of Khorana and Nirenberg helped decipher the genetic code which is followed by all organisms in protein synthesis. The codes are always in a triplet (codon) form that sequence of three N-bases and they are universal. AUG triplet is the initiator codon whose presence is must at the start of the sequence to initiate the translation process. Without AUG, translation for that sequence will not occur. Also, AUG codes for the amino acid methionine.
UAA, UAG and UGA are called as terminator codon and they do not represent/code for any amino acid. They signal the end of the polypeptide chain during protein synthesis in translation. Stop codon is must to avoid formation of defective protein.

Topic: Biology, Molecular Basis of Inheritance, NEET
Polysome is formed by

Options:
A several ribosomes attached to a single mRNA
B many ribosomes attached to a strand of endoplasmic reticulum
C a ribosome with several subunits
D ribosomes attached to each other in a linear arrangement

The correct answer is:
several ribosomes attached to a single mRNA

Solution:
In prokaryotes, ribosomes attach to the $5^{\prime}$ end of mRNA as soon as transcription begins. A bunch of ribosome moves along a single mRNA molecule adding 15 amino acids/second to the polypeptide chain, almost the same speed at which RNA polymerase transcribes the mRNA. The group of ribosomes together with the single mRNA molecules, they are translating is called polysome. The use of polysomes is advantageous to a cell since, the overall rate of protein synthesis is increased compared to the rate that would occur if there were no polysomes.
In eukaryotic cells the ribosomes are attached to rough endoplasmic reticulum by ribophorin protein. Electron microscopy reveals that membranes of homogenised endoplasmic reticulum disrupt to form closed vesicles called microsomes. Microsomes derived from rough endoplasmic reticulum are studied with ribosomes and are called rough ribosomes.

Topic: Biology, Molecular Basis of Inheritance, NEET, NEET 2008 (Screening)
Polysome is formed by

Options:
A a ribosome with several subunits.
B several ribosomes attached to a single mRNA.
C ribosomes attached to each other in a linear arrangement.
D many ribosomes attached to a strand of endoplasmic reticulum

The correct answer is:
several ribosomes attached to a single mRNA.

Solution:
It is a cluster of numerous ribosomes that are involved in protein synthesis. These ribosomes in a polysome are connected with single mRNA and translate the genetic information coded in the mRNA. Each ribosome has two subunits i.e.one smaller and one bigger unit. Once the translation is finished these subunits get separated from each other. In the next cycle, they again reassociate for the initiation of protein synthesis.

Topic: Biology, Cell - The Unit of Life, NEET
Polysomes are aggregates of

Options:
A ribosomes and rRNA.
B only rRNA.
C peroxisomes.
D several ribosomes held together by string of mRNA.

The correct answer is:
several ribosomes held together by string of mRNA.

Solution:
Polyribosomes are aggregates of several ribosomes held together by a string of mRNA. Polyribosomes consists of 4 to 8 ribosomes which are attached to a single strand of messenger RNA or mRNA. This mechanism helps in the synthesis of several copies of the same protein.

Topic: Biology, Cell - The Unit of Life, NEET
Polyspermy is prevented by all the events, except

Options:
A Electrical changes in the egg membrane, depolarisation
B Cortical reaction
C Zona reaction
D Sodium gates in the egg membrane getting closed

The correct answer is:
Sodium gates in the egg membrane getting closed

Solution:
Although many sperm attaches to the egg, it is only one sperm enters into the egg. There are few mechanisms the animals adopt to ensure to avoid polyspermy. Among them the fast block to polyspermy is best studied.
Fast block to polyspermy occurs within a tenth of a second of fusion and involves the opening of Na+ channels in the plasma membrane of the egg. Na+ flows into the egg, by depolarizing the membrane and prevents additional sperm from fusing to the egg.
The slow block to polyspermy starts within 10 seconds of fusion of the sperm and egg. Inositol triphosphate (IP3) releases Ca++ from the endoplasmic reticulum and a wave of free Ca++ passes through the egg. This Ca++ results in the fusion of cortical vesicles with the egg plasma membrane, releasing their contents into the space surrounding the egg, called the perivitelline space. This raises the vitelline membrane and inactivates bindin receptors on the vitelline membrane. Thus, any additional sperm are released from the vitelline membrane and no more bind.

Topic: Biology, Human Reproduction, NEET
Polysulphate esters are present in the cell wall of

Options:
A Ectocarpus and Dictyota
B Gelidium and Polysiphonia.
C Ectocarpus and Laminaria
D Spirogyra and Chara

The correct answer is:
Gelidium and Polysiphonia.

Solution:
Polysulphate esters are present in the cell wall of Red algae. Cell wall of red algae is made up of two layers, inner layer of cellulose and outer layer of polysulphate esters. Gelidium and Gracilaria are red algae.

Topic: Biology, Plant Kingdom, NEET
Pomato is a

Options:
A autotetraploid.
B developed by anther culture of potato.
C somatic hybrid developed by protoplast fusion of potato and tomato.
D biofortified variety of potato.

The correct answer is:
somatic hybrid developed by protoplast fusion of potato and tomato.

Solution:
Hybrids which are formed by fusion of somatic cells are called somatic hybrid and the process is called as somatic hybridization. Pomato is a hybrid formed by fusion of isolated protoplast of potato and tomato.

Topic: Biology, Strategies for Enhancement in Food Production, NEET
Population density of terrestrial organisms is measured in terms of individual per

Options:
A meter3
B meter4
C meter
D meter2

The correct answer is:
meter2

Solution:
Population density of terrestrial organisms is measured in terms of number of individuals per meter square while the population density of aquatic organisms is measured in terms of number of individuals per cubic meter.

Topic: Biology, Organisms and Populations, NEET
Population growth curve in most animals, except humans, is

Options:
A S–shaped
B J–shaped
C J–shaped with tail
D S–shaped with tail

The correct answer is:
S–shaped

Solution:
Population growth curve in most animals except human is S-shaped while in humans it is J-shaped.

Topic: Biology, Reproductive Health, NEET
Porins form Huge pores in outer membranes of?

Options:
A Plasmids
B Mitochondria
C Some bacteria
D All of the above

The correct answer is:
All of the above

Solution:
The porins are proteins that form large pores in the outer membranes of the

Topic: Biology, Transport in Plants, NEET
Position of non-polar and polar parts in micelle is:

Options:
A polar at the outer surface but nonpolar at the inner surface
B polar at the inner surface but nonpolar at the outer surface
C distributed over all the surface
D are present in the surface only

The correct answer is:
polar at the outer surface but nonpolar at the inner surface

Solution:
Micelles are the clusters formed by the association of colloids. They are formed by lyophilic and lyophobic groups. As the concentration increases, the lyophobic parts receding away from the solvent approach each (non-polar part) other and form a cluster, the lyophobic ends are in the interior, lyophilic groups (polar part) projecting outward in contact with the solvent.
In a non-polar solvent, the hydrophilic groups are sequestered in the micelle core and the hydrophobic groups extend away from the centre.

Topic: Chemistry, Surface Chemistry, NEET, NEET 2002
Positive iodoform test is given by

Options:
A 1−Pentanol
B 3−Pentanone
C 2−Pentanone
D Pentanal

The correct answer is:
2−Pentanone

Solution:
Iodoform test given by the following group:

CH 3 −CO− and CH 3 âCH OH â

Topic: Chemistry, Alcohols Phenols and Ethers, NEET
Positively charged particles are projected into a magnetic field. If the direction of the magnetic field is along the direction of motion of the charged particles, the particles get

Options:
A Accelerated
B Decelerated
C Deflected
D No change in velocity

The correct answer is:
No change in velocity

Solution:
The direction of magnetic field is along the direction of motion of the charge particles, so angle will be 0Â°.
â´Force F=qvBsinâ¡Î¸
=qvBsinâ¡Î¸
=0 (âµsinâ¡Î¸=0)
So, there will be no change in the velocity.

Topic: Physics, Magnetic Effects of Current, NEET
Potassium carbonate cannot be prepared by the Solvay process. Why?

Options:
A Potassium is not readily available in nature.
B Potassium carbonate is too unstable to be produced by this process.
C Potassium carbonate forms insoluble precipitates in the Solvay process.
D Potassium ions are too small to interact effectively with ammonia in the process.

The correct answer is:
Potassium carbonate forms insoluble precipitates in the Solvay process.

Solution:
Correct Option is : (C)
Potassium carbonate forms insoluble precipitates in the Solvay process.

Topic: Chemistry, s Block Elements, NEET
Potassium dichromate is used -

Options:
A As a reducing agent
B In electroplating
C As an insecticide
D as an oxidizing agent it oxidises ferrous ions into ferric ions in acidic media

The correct answer is:
as an oxidizing agent it oxidises ferrous ions into ferric ions in acidic media

Solution:
Potassium dichromate K2Cr2O7, is a common inorganic chemical reagent, most commonly used as an oxidizing agent in various laboratory and industrial applications.
Ferrous iron is oxidized to ferric iron by potassium dichromate in acid solution. The completion of oxidation reaction marked by the appearance of blue violet color of diphenylamine, which is used as an internal indicator.

Topic: Chemistry, d and f Block Elements, NEET
Potassium is stored in

Options:
A Water
B Kerosene
C Alcohol
D Liquid ammonia

The correct answer is:
Kerosene

Solution:
Alkali metals are highly reactive metals. They react with
Alcohol – 2C2H5OH+2K→2C2H5OK+H2
Water – 2K+2H2O→2KOH+H2
Ammonia-K+(x+y)NH3→[K(NH3)x]+Ammoniatedcation+[e(NH3)y]-Ammoniatedelectron
But they do not react with kerosene.

Topic: Chemistry, s Block Elements, NEET
Potassium permanganate acts as an oxidant in neutral, alkaline as well as acidic media. The final products obtained from it in the three conditions are, respectively

Options:
A MnO42-,Mn3+ and Mn2+
B MnO2,MnO2 and Mn2+
C MnO2,MnO2+ and Mn2+
D MnO, MnO 2 and Mn2+

The correct answer is:
MnO2,MnO2 and Mn2+

Solution:
In neutral and alkaline medium
MnO4-+2H2O+3e-→MnO2+4OH-
In acidic medium
MnO4-+8H++5e-→Mn2++4H2O

Topic: Chemistry, d and f Block Elements, NEET
Potato and sweet potato

Options:
A have edible parts which are homologous organs.
B have edible parts which are analogous organs.
C have reproductive parts which are homologous.
D are two species of the same genus.

The correct answer is:
have edible parts which are analogous organs.

Solution:
Analogous organs are those organs, which are different in origin but similar in function. Patato and sweet potato are absolutely different in their origin as potato is modified underground stem (tuber), while sweet potato is tuberous root. It means both have edible parts, which are different organs.

Topic: Biology, Evolution, NEET
Potato spindle tuber disease is caused by:

Options:
A A nematode
B A virus
C A bacterium
D A viroid

The correct answer is:
A viroid

Solution:
Potato spindle tuber diseases is caused by viroid which are also smallest pathogens. These are small ss RNA which are not surrounded by any protein coat. They causes diseases only in plants.

Topic: Biology, Biological Classification, NEET
Potential difference between points A and B (i.e. VA-VB) is

Options:
A 2 V
B 4 V
C 6 V
D 8 V

The correct answer is:
4 V

Solution:
Apply Kirchhoff''s Voltage Law,
Along wire ACDB
VA-2-6+4=VB
VAâVB=4 V

Topic: Physics, Current Electricity, NEET
Potometer works on the principle of:

Options:
A osmotic pressure
B amount of water absorbed equals the amount transpired
C root pressure
D potential difference between the tip of the tube and that of the plant.

The correct answer is:
amount of water absorbed equals the amount transpired

Solution:
A potometer is a device, which is used to measure water uptake by shoot during transpiration. It is also known as transpirometer. The Ganong's potometer is used to measure the transpiration rate in a laboratory (Ref. to Fig. 27.5)
Related Theory
In plants, transpiration is the loss of water from leaves and stems. Potometer is a tool used for measuring the rate of transpiration. The rate of transpiration cannot be accurately determined using a potometer because all the water that is taken by the plant is not involved in transpiration.

Topic: Biology, Transport in Plants, NEET, NEET 2005
Powdered substances are more effective adsorbents than their crystalline form because

Options:
A adsorption is an exothermic process
B they become inert and do not react with the adsorbate
C the extent of adsorption increases with increases in surface area of the adsorbent
D adsorption is more if the size of adsorbent is small

The correct answer is:
the extent of adsorption increases with increases in surface area of the adsorbent

Solution:
Finely powdered substances have large, porous surface areas, hence act as better adsorbent as there are more number of active sites or free valencies.

Topic: Chemistry, Surface Chemistry, NEET
Power applied to a particle varies with time as P=(3t2-2t+1) watt, where t is in second. The change in its kinetic energy between t=2 s and t=4 s is

Options:
A 32 J

B 46 J

C 61 J

D 100 J

The correct answer is:
46 J

Solution:
P=3t2-2t+1=dEdt
â´ dE=(3t2-2t+1)dt
E=â«t=2st=4s(3t2-2t+1)dt
=3t33-2t22+tt=2st=4s
=[43-23-42-22+(4-2)]
E=56-12+2=46 J

Topic: Physics, Work Power Energy, NEET
Power applied to a particle varies with time as P=(3t2â2t+1) watts, where t is time in seconds. Then the change in kinetic energy between time t=2 s to t=4 s is

Options:
A 46 J
B 52Â J
C 92Â J
D 104Â J

The correct answer is:
46 J

Solution:
P=3t2–2t+1
dKdt=P
⇒ ΔK=∫24Pdt=t3-t2+t24=46 J

Topic: Physics, Work Power Energy, NEET
Power dissipated across the $8 \Omega$ resistor in the circuit shown here is 2 watt. The power dissipated in watt units across the $3 \Omega$ resistor is:

Options:
A 3.0
B 2.0
C 1.0
D 0.5

The correct answer is:
3.0

Solution:
$1 \Omega$ and $3 \Omega$ are in series so,
$egin{aligned}
& R_s=R_1+R_2 \\
& R_s=3+1=4 \Omega
\end{aligned}$
and $R_2=8 \Omega$
net $i=$ current in the circuit
Current through $R_1$ is $i_1=\frac{i \times R_2}{R_1+R_2}$
$=\frac{i \times 8}{12}=\frac{21}{3}$
Current $R_2$ is $i_2=\frac{1 \times R_1}{R_1+R_2}=\frac{i \times 4}{12}$
$=\frac{i \times 8}{12}$
Power dissipated in $3 \Omega$ resistance is: $P_1=l_1^2 \times 3$
Power dissipated in $8 \Omega$ resistance is: $P_2=l_2^2 \times 8$
For (i) and (ii)
$\begin{aligned}
& \frac{P_1}{P_2}=\frac{i_1^2 \times 3}{i_2^2 \times 8} \\
& \Rightarrow \frac{P_1}{P_2}
\end{aligned}$
$\begin{aligned}
& =\frac{\left(\frac{2 i}{3}\right)^2 \times 3}{\left(\frac{i}{3}\right)^2 \times 8}=\frac{3}{2} \\
\therefore \quad P_1 & =\frac{3}{2} \times P_2=\frac{3}{2} \times 2 =3 \mathrm{~W}
\end{aligned}$
$\begin{aligned}
\because & P & =100 \mathrm{~W}, V=125 V \\
\therefore & P & =V I \\
\Rightarrow & I & =\frac{P}{V}=\frac{100}{125} A
\end{aligned}$

Topic: Physics, Current Electricity, NEET, NEET 2006
Power dissipated in an $L-C-R$ series circuit connected to an AC source of emf $\varepsilon$ is

Options:
A $\frac{\varepsilon^2 R}{\left[R^2+\left(L \omega-\frac{1}{C \omega}\right)^2\right]}$
B $\frac{\varepsilon^2 \sqrt{\mathrm{R}^2+\left(\mathrm{L} \omega-\frac{1}{\mathrm{C} \omega}\right)^2}}{\mathrm{R}}$
C $\frac{\varepsilon^2\left[\mathrm{R}^2+\left(\mathrm{L} \omega-\frac{1}{\mathrm{C} \omega}\right)^2\right]}{\mathrm{R}}$
D $\frac{\varepsilon^2 R}{\sqrt{R^2+\left(L \omega-\frac{1}{C \omega}\right)^2}}$

The correct answer is:
$\frac{\varepsilon^2 R}{\left[R^2+\left(L \omega-\frac{1}{C \omega}\right)^2\right]}$

Solution:
The emf of an LCR circuit is \(\varepsilon\).
The impedance of a series LCR circuit is given as,
\(Z=\sqrt{\left[R^2+\left(\omega L-\frac{1}{\omega C}\right)^2\right]}\)
The power factor in a series LCR circuit is given as,
\(\cos \phi=\frac{\mathrm{R}}{|\mathrm{Z}|}\)
The power dissipated in the circuit is given as,
\(\begin{aligned}
& \mathrm{P}=\mathrm{V}_{\mathrm{rms}} \mathrm{I}_{\mathrm{rms}} \cos \phi \\
& =\varepsilon \times \frac{\varepsilon}{|\mathrm{Z}|} \times \frac{\mathrm{R}}{|\mathrm{Z}|} \\
& =\frac{\varepsilon^2 \mathrm{R}}{\left[\mathrm{R}^2+\left(\omega \mathrm{L}-\frac{1}{\omega \mathrm{C}}\right)^2\right]}
\end{aligned}\)
Thus, the power dissipated in the series \(L C R\) circuit is \(\frac{\varepsilon^2 R}{\left[R^2+\left(\omega L-\frac{1}{\omega C}\right)^2\right]}\).

Topic: Physics, Alternating Current, NEET, NEET 2009 (Screening)
Power dissipated in an LCR series circuit connected to an A.C source of emf ε is

Options:
A ε2R2+Lω-1CωR
B ε2R2+Lω-1Cω2R
C ε2RR2+Lω-1Cω2
D ε2RR2+Lω-1Cω2

The correct answer is:
ε2RR2+Lω-1Cω2

Solution:
Average power, P=ErmsIrmscosϕ
Z=R2+XL-XC2, cosϕ=RZ
But Irms=ErmsZ ∴ P=Erms2·RZ2
∴P=Erms2RR2+XL-XC2
=ε2RR2+Lω-1Cω2

Topic: Physics, Alternating Current, NEET
Power radiated by a black body is P0 and the wavelength corresponding to maximum energy is around Î» 0 . On changing the temperature of the black body, it was observed that the power radiated becomes 25681P0. The shift in wavelength corresponding to the maximum energy will be

Options:
A + λ 0 4
B + λ 0 2
C - λ 0 4
D - λ 0 2

The correct answer is:
- λ 0 4

Solution:
According to Wien's law λ 0 T 0 = λ T
According to Stefan's law P 0 P = T 0 T 4
As P = 2 5 6 8 1 P 0 ⇒ λ = 3 4 λ 0
∴ Wavelength shift D λ = λ - λ 0 = - λ 0 4

Topic: Physics, Thermal Properties of Matter, NEET
Power supplied to a particle of mass 2 kg varies with time as P = 3 t 2 2 W . Here t is in second. velocity of particle at t = 0 is v = 0. The velocity of particle at time t = 2s will be –

Options:
A 1 m/s
B 4 m/s
C 2 m/s
D 2 2 m/s

The correct answer is:
2 m/s

Solution:
P = dK dt

dK = P dt,
1 2 mv 2 = ∫ 0 2 3 2 t 2 dt
v = 2 m/s

Topic: Physics, Work Power Energy, NEET
Power supplied to a particle of mass 2 kg varies with time as Pâ¡=3 t 2 2 watt, where t is in seconds. If the velocity of the particle at t=0 is v=0, the velocity of the particle at t=2 s will be

Options:
A 1 m s-1

B 4 m s-1

C 2 m s-1

D 22 m s-1

The correct answer is:
2 m s-1

Solution:
From work energy theorem, Δ K.E. = Wnet
Kf-Ki=∫Pdt
12mv2-0=∫0232t2dt
122v2=32t3302=4
v=2 m s-1

Topic: Physics, Work Power Energy, NEET
(p+q)2 = p2 + 2pq + q2 = 1 represents an equation used in:

Options:
A population genetics
B mendelian genetics
C biometrics
D molecular genetics

The correct answer is:
population genetics

Solution:
(p+q)2 = p2 + 2pq + q2 = 1 represents an equation used in population genetics proposed by Hardy Weinberg.

Topic: Biology, Evolution, NEET
Practical significance of taxonomy is

Options:
A To classify the organism
B To understand diversity
C To understand evolution
D Identification of organisms

The correct answer is:
Identification of organisms

Solution:
This is important to be able to distinguish different organisms from each other.

Topic: Biology, The Living World, NEET
Praying mantis is a good example of:

Options:
A camouflage
B mullerian mimicry
C warning colouration
D social insects

The correct answer is:
camouflage

Solution:
Praying mantis (Mantis religiosa) is a large social insect. Social insects are the ants, bees, wasps, and termites that have organized societies and live in colonies. They have one or a few females responsible for all the egg laying, while other members of the colony (usually sterile females) gather food and do other tasks. Camouflage or cryptic colouration is a defence mechanism that helps insects merge with their surroundings. They do it to conceal their presence or identity, either to hoodwink their predators or to deceive their prey. Müllerian mimicry is a form of biological resemblance in which two or more unrelated noxious, or dangerous, organisms and exhibit closely similar warning systems, such as the same pattern of bright colours. Warning colouration (or aposematism) is how animals let other animals know that they are poisonous or dangerous.

Topic: Biology, Organisms and Populations, NEET, NEET 2006