datavorous/entrance-exam-dataset huggingface dataset:
The common molecule between the Kreb cycle and C4 pathway is

Options:
A Phosphoenolpyruvate
B Ribulose 1, 5-diphosphate
C Oxalo-acetic acid
D Phosphoglyceric acid

The correct answer is:
Oxalo-acetic acid

Solution:
The primary acceptor of CO2 in C4 plants is phosphoenolpyruvate or PEP. PEP in mesophyll cells combine with CO2 and converted into 4 carbon compound oxaloacetic acid by PEP carboxylase. In C3 plant ribulose1,5-diphosphate is the primary acceptor of CO2.​
In the Kreb cycle, oxaloacetic acid combines with acetyl Co-A to form the first stable product called citric acid.

Topic: Biology, Photosynthesis in Higher Plants, NEET
The common name of given ester is –

Options:
A neo butyl iso butyrate
B t-butyl n-butyrate
C t-butyl iso butyrate
D iso butyl iso butyrate

The correct answer is:
t-butyl iso butyrate

Solution:
It is having tertiary butyl and isopropyl groups attached with -COO group, hence it is t-Butyl isobutyrate

Topic: Chemistry, General Organic Chemistry, NEET
The common nitrogen-fixer in paddy fields is

Options:
A Rhizobium
B Azospirillum
C Oscillatoria
D Frankia

The correct answer is:
Azospirillum

Solution:
Azospirillum is a nitrogen fixing bacterium in paddy fields. It is very useful soil and root bacterium. It is an associative symbiotic $\mathrm{N}_2$-fixing bacteria. When it is added to the soil, it multiplies in millions and can supply 20-40 $\mathrm{Kg}$ of nitrogen per hectare per season. It also produces growth promoting substances like Indole Acetic Acid (IAA), gibberellins and promotes root proliferation. These substances improve the plant growth and yield.

Topic: Biology, Mineral Nutrition, NEET, NEET 2010 (Screening)
The common pathway for both aerobic and anaerobic respiration is

Options:
A EMP pathway
B Kreb's cycle
C HMP pathway
D Oxidative phosphorylation

The correct answer is:
EMP pathway

Solution:
The term glycolysis has originated from the Greek words 'glycos' for sugar and 'lysis' for splitting. The scheme of glycolysis was given by Gustav Embden, Otto Meyerhof, and J. Parnas and is often referred to as the EMP pathway. In anaerobic organisms, it is the only process in respiration. Glycolysis occurs in the cytoplasm of the cell and is present in all living organisms. In this process, glucose undergoes partial oxidation to form two molecules of pyruvic acid.

Topic: Biology, Respiration in Plants, NEET
The competitive exclusion principle experiement involved species of _______________.

Options:
A Chlorella
B Paramoecium
C Microcystis
D Finches

The correct answer is:
Paramoecium

Solution:
The experiment performed to prove competitive exclusion principle involved the use of two Paramoecium species. It showed that the superior species tends to eliminate the inferior one. This proved two species cannot co-exist together in an environment with a limited amount of resources.

Topic: Biology, Organisms and Populations, NEET
The complex compounds formed when KCN solution is added to a solution containing both Cu2+ and Cd2+ ions are

Options:
A K2[Cu(CN)4],K2[Cd(CN)4]
B K3[Cu(CN)4],K2[Cd(CN)4]
C K3[Cu(CN)4],K3[Cd(CN)4]
D K2[Cu(CN)4],K3[Cd(CN)4]

The correct answer is:
K3[Cu(CN)4],K2[Cd(CN)4]

Solution:
The complex compounds formed when KCN solution is added to a solution containing both Cu2+ and Cd2+ ions are K3[Cu(CN)4],K2[Cd(CN)4]
1.  CuSO 4  + 2KCN→ Cu(CN) 2 Cupric cyanide  +  K 2 SO 4
2.  2Cu(CN) 2 → Cu 2 (CN) 2 Cuprous cyanide  +  (CN) 2
3.  Cu 2 (CN) 2  +  6KCN excess → 2K 3 [Cu CN) 4 stable complex

Topic: Chemistry, d and f Block Elements, NEET
The complex formed by a pair of synapsed chromosomes is called a

Options:
A kinetochore
B bivalent
C axoneme
D equatorial plate

The correct answer is:
bivalent

Solution:
Prophase 1 of Meiosis 1 shows presence of homologous chromosomes that start paring together. This forms a complex known as synaptonemal complex. This formation takes place during Zygotene stage of Prophase 1. This consists of a pair of chromosomes with four chromatids and this is known as bivalent or tetrad. The crossing over occurs between non sister chromatids of bivalent in the next stage.

Topic: Biology, Cell Cycle and Cell Division, NEET
The complex formed by a pair of synapsed homologous chromosomes is called

Options:
A equatorial plate
B kinetochore
C bivalent
D axoneme

The correct answer is:
bivalent

Solution:
Homologous chromosomes pair up. This process is called synapsis. Each pair is called bivalent. Chromosomes line up around the equator of the spindle, attached by their centromeres to the spindle fibres, which are microtubules. The microtubules forming spindles can be of two types, i.e., kinetochore microtubule and non-kinetochore microtubule.
Axoneme is the central core of a cilium or flagellum consisting of a central pair of filaments surrounded by nine other pairs. Equatorial plate is the plane located midway between the poles of a dividing cell during the metaphase stage of mitosis or meiosis. It is formed from the migration of the chromosome to the centre of the spindle.

Topic: Biology, Cell Cycle and Cell Division, NEET, NEET 2013 (All India)
The complex ion having minimum wavelength of absorption in the visible region is

Options:
A [Co(NH3)6]3+
B [CoCl(NH3)5]2+
C Cis-[CoCl2(NH3)4]+
D Trans-[CoCl2(NH3)4]+

The correct answer is:
[Co(NH3)6]3+

Solution:
Here [Co(NH3)6]3+ have minimum wavelength of absorption in the visible region as for it splitting energy is more as it has all strong ligands.
Δ0 (splitting energy) ∝1λ(Absorbed)
Basic strength of ligand C > N > O > X (halogen) donor.

Topic: Chemistry, Coordination Compounds, NEET
The complex ion which has the highest magnetic moment among the following is

Options:
A CoF63-
B CoNH363+
C NiNH342+
D FeCN64-

The correct answer is:
CoF63-

Solution:
In CoF63- complex ion Co3+ is sp3 d2 hybridized. F â is weak ligand and cannot pair up the d -electrons so, complex is high spin. Due to four unpaired electrons it is highly paramagnetic.

Topic: Chemistry, Coordination Compounds, NEET
The complex, $\left[\mathrm{Pt}(\mathrm{Py})\left(\mathrm{NH}_3\right) \mathrm{BrCl}\right]$ will have how many geometrical isomers?

Options:
A 4
B 0
C 2
D 3

The correct answer is:
3

Solution:
The complex is square planar and is of the type $[M(a b c d)]$. It has three geometrical isomers.

Topic: Chemistry, Coordination Compounds, NEET, NEET 2011 (Screening)
The complex showing a spin-only magnetic moment of 2.82 B.M. is:

Options:
A [ Ni ( CO ) 4 ]
B [ NiC l 4 ] 2−
C [ Ni ( PP h 3 ) 4 ]
D NiCN42–

The correct answer is:
[ NiC l 4 ] 2−

Solution:
CO, CN, PP h 3 are strong field ligand so forms inner hybrid complex and doesn't have unpaired electrons.
[NiCl4]2â,O.S. of Ni=+2
Ni(28)=3d84s2
No of unpaired electrons =2
Magnetic moment, Î¼=2.82 B.M.

Topic: Chemistry, Coordination Compounds, NEET
The complex tissues are made up of

Options:
A same type of cell
B more than one type of cell
C cell having different structure
D none of these

The correct answer is:
more than one type of cell

Solution:
The complex tissue is made up of more than one type of cell. These cells differ from one another in their form and structure; however, these cells work together as a unit. Hence a complex tissue can be defined as a collection of structurally dissimilar cells performing a common function or set of functions.

Topic: Biology, Structural Organisation in Animals, NEET
The complex used as an anticancer agent is

Options:
A mer- [Co(NH3)3Cl3]
B cis- [PtCl2(NH3)2]
C cis- K2[PtCl2Br2]
D Na2CoCl4

The correct answer is:
cis- [PtCl2(NH3)2]

Solution:
Cis-platin, cis- [PtCl2(NH3)2] is used as an anticancer agent.

Topic: Chemistry, Chemistry in Everyday Life, NEET
The complexes CoNH34H2OClBr2 and CoNH34Br2Cl.H2O are examples of

Options:
A ionization isomerism
B linkage isomerism
C geometrical isomerism
D optical isomerism

The correct answer is:
ionization isomerism

Solution:
The given compounds CoHN34H2OClBr2 and Co NH 3 4 Br 2 Cl .H 2 O exhibit ionization isomerism because in ionization isomerism, compounds having same formula differ in their ionic arrangement in solution. The difference occurs because of the difference in ions that are found in the inner and outer coordination sphere of the complex.

Topic: Chemistry, Coordination Compounds, NEET
The complexes $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]\left[\mathrm{Cr}(\mathrm{CN})_6\right]$ and $\left[\mathrm{Cr}\left(\mathrm{NH}_3\right)_6\right]\left[\mathrm{Co}(\mathrm{CN})_6\right]$ are the examples of which type of isomerism?

Options:
A Ionisation isomerism
B Co-ordination isomerism
C Geometrical isomerism
D Linkage isomerism

The correct answer is:
Co-ordination isomerism

Solution:
The complexes $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]\left[\mathrm{Cr}(\mathrm{CN})_6\right]$ and $\left[\mathrm{Cr}\left(\mathrm{NH}_3\right)_6\right]\left[\mathrm{Co}(\mathrm{CN})_6\right]$ are the examples of co-ordination isomerisms. This isomerism occurs only in those complexes in which both cation and anion are complex. It occurs due to exchange of ligands between cation and anion.

Topic: Chemistry, Coordination Compounds, NEET, NEET 2011 (Screening)
The composition of antiseptic dettol contains

Options:
A Chloroxylenol
B Alcohol
C Terpineol
D All of these

The correct answer is:
All of these

Solution:
Dettol (antiseptic) is a mixture of 4.8% chloroxylenol +9.9% tepineol and absolute alcohol.

Topic: Chemistry, Chemistry in Everyday Life, NEET
The compound A, C8H10O, is found to react with NaOI (produced by reacting Y with NaOH ) and yields a yellow precipitate with a characteristic smell.
A and Y respectively, are

Options:
A
B
C
D

The correct answer is:

Solution:
Haloform reaction is shown by the compound having,

Haloform reaction mechanism starts with the disproportionation of the halogen with the presence of the hydroxide ion. This gives the halide or the hypohalite. The hydroxide abstracts the proton, producing enolate. The hypohalite also reacts with any present methyl ketones, eventually forming a haloform.

Topic: Chemistry, Aldehydes and Ketones, NEET, NEET 2018
The compound A on treatment with Na gives B, and with PCl5 gives C. B and C react together to give diethyl ether. A, B and C are in the order

Options:
A C2H5Cl,C2H6,C2H5OH
B C2H5OH,C2H5Cl,C2H5ONa
C C2H5OH,C2H6,C2H5Cl
D C2H5OH,C2H5ONa,C2H5Cl

The correct answer is:
C2H5OH,C2H5ONa,C2H5Cl

Solution:
The Williamson ether synthesis is an organic reaction, forming an ether from an organohalide and a deprotonated alcohol. This reaction was developed by Alexander Williamson in 1850. Typically it involves the reaction of an alkoxide ion with a primary alkyl halide via an SN2 reaction.

Topic: Chemistry, Alcohols Phenols and Ethers, NEET, NEET 2018
The compound A on treatment with Na gives B and with PCl5 gives C. B and C react together to give diethyl ether. A, B and C respectively are

Options:
A C2H5Cl,C2H6,C2H5OH
B C2H5OH,C2H5Cl,C2H5ONa
C C2H5OH,C2H6,C2H5Cl
D C2H5OH,C2H5ONa,C2H5Cl

The correct answer is:
C2H5OH,C2H5ONa,C2H5Cl

Solution:
The reaction occurs to give ethoxy ethane as the final product as follows

Topic: Chemistry, Haloalkanes and Haloarenes, NEET
The compound C6H14 has a total of ___ structural isomers.

Options:
A 4
B 5
C 6
D 3

The correct answer is:
5

Solution:
Compounds having the same molecular formula but different structures (manners in which atoms are linked) are classified as structural isomers. This includes chain isomers, position isomers, functional group isomers and metamerism.
For the given compound, C6H14, different structural isomers are possible, which are chain or position isomers of each other. The isomers are given below.
Therefore, the compound C6H14 has a total of 5 structural isomers.

Topic: Chemistry, General Organic Chemistry, NEET
The compound C7H8 undergoes the following reactions
C7H8→3Cl2/ΔA→Br2/FeB→Zn/HClC
The product ‘C’ is

Options:
A 3-bromo-2, 4, 6-trichlorotoluene
B o-bromotoluene
C m-bromotoluene
D p-bromotoluene

The correct answer is:
m-bromotoluene

Solution:
First toluene undergoes side chain halogination to give compound A. In compound A - CCl3 group is meta directing so meta product B is formed. B on reaction with Zn/HCl gives meta bromo toluene (C) .

Topic: Chemistry, Hydrocarbons, NEET
The compound C7H8 undergoes the following reactions:
The product 'C' is

Options:
A 3-bromo-2, 4, 6-trichlorotoluene
B o-bromotoluene
C m-bromotoluene
D p-bromotoluene

The correct answer is:
m-bromotoluene

Solution:
In electrophilic aromatic substitution, a substituent that favors electrophilic attack ortho or para to the substituent. Most ortho/para directors are also activators, except for the halogens, which are deactivators. A carboxylic acid is a meta director because it experiences resonance, a delocalization of electrons.

Topic: Chemistry, Haloalkanes and Haloarenes, NEET, NEET 2018
The compound C in the given sequence of reaction is , C6H5OH→NaOHA→CO2B→HClC

Options:
A Chlorobenzene
B Benzoic acid
C Salicylaldehyde
D Salicylic acid

The correct answer is:
Salicylic acid

Solution:
Treatment of sodium salt of phenol with CO2 under pressure bring about substitution of the carbonyl group -COOH, for the hydrogen of the ring. This is called as Kolbe’s reaction

Topic: Chemistry, Alcohols Phenols and Ethers, NEET
The compound finally gets converted into –

Options:
A
B
C
D

The correct answer is:

Solution:
It is haloform reaction of methyl ketonic group which produces beta keto acids, followed by decarboxylation of B- Keto acid.

Topic: Chemistry, Carboxylic Acid Derivatives, NEET
The compound formed as a result of oxidation of ethyl benzene by KMnO4 is

Options:
A Benzyl alcohol
B Acetophenone
C Benzoic acid
D Benzophenone

The correct answer is:
Benzoic acid

Solution:
When oxidises with alkaline KMnO 4 or acidic Na 2 Cr 2 O 7 , the entire side chain ( in benzene homologues ) with atleast one H at Î± - carbon , regardless of length is oxidised to −COOH.

Topic: Chemistry, Carboxylic Acid Derivatives, NEET
The compound formed in the positive test for nitrogen with the lassaigne solution of an organic compounds is

Options:
A Fe(CN)3
B Na3[Fe(CN)6]
C Fe4[Fe(CN)6]3
D Na4[Fe(CN)5NOS]

The correct answer is:
Fe4[Fe(CN)6]3

Solution:
Fe4[Fe(CN)6]3 compound formed in the positive test for nitrogen with the lassaigne solution of an organic compounds.

Topic: Chemistry, General Organic Chemistry, NEET
The compound formed when ethyl alcohol (C2H5OH) is mixed with ammonia and passed over heated alumina is

Options:
A C2H5NH2
B C2H5OC2H5
C CH3OCH3
D C2H4

The correct answer is:
C2H5NH2

Solution:
C2H5OH+NH3→Al2O3C2H5NH2+H2O

Topic: Chemistry, Amines, NEET
The compound formed when Ethyl bromide is heated with dry Silver oxide is

Options:
A dimethylether
B diethylether
C methylalcohol
D ethylalcohol

The correct answer is:
diethylether

Solution:
2 C 2 H 5 Br+ Ag 2 O Dry → C 2 H 5 −O− C 2 H 5 +2AgBr
If we take moist Ag 2 O then alcohol is formed
Ag 2 O+ H 2 O→2AgOH
C 2 H 5 Br+AgOH→ C 2 H 5 OH+AgBr

Topic: Chemistry, Alcohols Phenols and Ethers, NEET
The compound H2N-Hg-O-Hg-I is formed by the action of

Options:
A NH3 and HgO in the presence of iodine
B NI3,HgO and H2O
C NH3+K2HgI4
D KI+NH3+Hg

The correct answer is:
NH3+K2HgI4

Solution:
The compound H2N-Hg-O-Hg-I is formed by the reaction of NH3 and K2HgI4 (Nesslar's reagent).
NH 3  +  2K 2 HgI 4  + 3KOH→ H 2 N−Hg−O−Hg−I Iodide of millon's base  + 7KI +  2H 2 O

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), NEET
The compound in which carbon uses only its sp3 hybrid orbitals for bond formation is

Options:
A CH33COH
B HCOOH
C CH3CHO
D H2N2CO

The correct answer is:
CH33COH

Solution:
All bonds are Ï- bonds hence C uses only its sp3-hybrid orbitals. In all other compounds there is one C=O double bond, therefore, this carbon is sp2- hybridized

Topic: Chemistry, General Organic Chemistry, NEET
The compound is known by which of the following names

Options:
A Bicyclo-[2, 2, 2] octane
B Bicyclo-[2, 2, 1] octane
C Bicyclo-[1, 2, 1] octane
D Bicyclo-[1, 1, 1] octane

The correct answer is:
Bicyclo-[2, 2, 2] octane

Solution:
Bicyclo (2, 2, 2) octane.

Topic: Chemistry, General Organic Chemistry, NEET
The compound K2[PtCl4] would have a molar conductivity in aqueous solution most closely approaching that of

Options:
A KNO3
B CCl4
C MgSO4
D Na2SO4

The correct answer is:
Na2SO4

Solution:
The given compound K2[PtCl4] and Na2SO4 on ionization is water give the same number of ions, i.e., three.
K2[PtCl4]⇌2K++[PtCl4]2-
Na2SO4⇌2Na++SO42-
Hence both have comparable molar conductivities in aqueous solution.

Topic: Chemistry, Coordination Compounds, NEET
The compound
on reaction with $\mathrm{NaIO}_3$ in the present of $\mathrm{KMnO}_4$ gives:

Options:
A $\mathrm{CH}_3 \mathrm{COCH}_3$
B $\mathrm{CH}_3 \mathrm{COCH}_3+\mathrm{CH}_3 \mathrm{COOH}$
C $\mathrm{CH}_3 \mathrm{COCH}_3+\mathrm{CH}_3 \mathrm{CHO}$
D $\mathrm{CH}_3 \mathrm{CHO}+\mathrm{CO}_2$

The correct answer is:
$\mathrm{CH}_3 \mathrm{CHO}+\mathrm{CO}_2$

Solution:

Topic: Chemistry, Hydrocarbons, NEET, NEET 2003
The compound SiH33N is expected to be

Options:
A pyramidal and more basic than CH33N
B planar and less basic than CH33N
C pyramidal and less basic than CH33N
D planar and more basic than CH33N

The correct answer is:
planar and less basic than CH33N

Solution:
SiH33N is planar and less basic than CH33N because lone pair of N atom is used in pπ-dπ back bonding with Si atom.

Topic: Chemistry, p Block Elements (Group 13 & 14), NEET
The compound that cannot act both as oxidising and reducing agent is

Options:
A HNO2
B H2O2
C H2SO3
D H3PO4

The correct answer is:
H3PO4

Solution:
H2O2-1 H2SO3+4 HNO2+3
As in H3PO4 phosphorous is in maximum oxidation state +5 so it can not undergo oxidation or can be reduced only so it is an oxidant only.

Topic: Chemistry, Redox Reactions, NEET
The compound that does not liberate CO2 , on treatment with aqueous sodium bicarbonate solution, is

Options:
A Benzoic acid
B Benzenesulphonic acid
C Salicylic acid
D Carbolic acid (Phenol)

The correct answer is:
Carbolic acid (Phenol)

Solution:
Compounds with -COOH group or - SO3H group can liberate CO2 with NaHCO3 solution as they are more acidic than carbonic acid. As phenol is less acidic than carbonic acid so cannot give this test.

Topic: Chemistry, Alcohols Phenols and Ethers, NEET
The compound that does not produce nitrogen gas by the thermal decomposition is

Options:
A (NH4)2SO4
B Ba(N3)2
C (NH4)2Cr2O7
D NH4NO2

The correct answer is:
(NH4)2SO4

Solution:
( NH 4 ) 2 SO 4 → Δ 2 NH 3 g +H 2 SO 4
Ba ( N 3 ) 2 s â Î Ba+3 N 2 g
( NH 4 ) 2 Cr 2 O 7 s â N 2 g + Cr 2 O 3 s +4 H 2 O
NH 4 NO 2 â Î N 2 g +2 H 2 O

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), NEET
The compound that does not undergo Friedel-Crafts alkylation reaction but gives a positive carbylamine test is :

Options:
A Aniline
B Pyridine
C N -methylaniline
D Triethylamine

The correct answer is:
Aniline

Solution:
For positive carbylamine test, there must be the presence of primary amine.

Topic: Chemistry, Amines, NEET, NEET 2024 (Re-NEET)
The compound that is most difficult to protonate is:

Options:
A
B
C
D

The correct answer is:

Solution:
The compound that is more difficult to protonate is
(i)

(ii)
(iii)
(iv)

Topic: Chemistry, General Organic Chemistry, NEET, NEET 2019 (All India)
The compound that undergoes decarboxylation most readily under mild condition is

Options:
A
B
C
D

The correct answer is:

Solution:
β -keto acid undergoes decarboxylation easily through cyclic transition state as follows

Topic: Chemistry, Aldehydes and Ketones, NEET
The compound that undergoes decarboxylation most readily under mild condition is

Options:
A
B
C
D

The correct answer is:

Solution:
Keto carboxylic acids undergo decarboxylation more easily through cyclic transition state.

Topic: Chemistry, Carboxylic Acid Derivatives, NEET
The compound that will react most readily with gaseous bromine has the formula:

Options:
A C3H6
B C2H2
C C4H10
D C2H4

The correct answer is:
C3H6

Solution:
In gaseous phase, bromine reacts with alkene by free radical allylic substitution reaction.

Here in the given molecules, C3H6 is the alkene as it has degree of unsaturation equals to one. Therefore, it will react readily with bromine in gaseous phase.

Topic: Chemistry, Hydrocarbons, NEET, NEET 2016 (Phase 2)
The compound that will undergo $S_N 1$ reaction with the fastest rate is

Options:
A

B

C

D

The correct answer is:

Solution:
Reactivity towards $\mathrm{S}_{\mathrm{N}} 1$ depends upon stability of carbocation.
Order of stability is

Topic: Chemistry, Haloalkanes and Haloarenes, NEET, NEET 2024
The compound which contains both covalent and coordinate bond is

Options:
A C2H5NC
B C2H5CN
C HCN
D KMnO4

The correct answer is:
C2H5NC

Solution:
C2H5NC contains both covalent and coordinate bond.

Topic: Chemistry, Chemical Bonding and Molecular Structure, NEET
The compound which does not react with sodium is

Options:
A C2H5OH
B CH3-O-CH3
C CH3COOH
D CH3-CHOH-CH3

The correct answer is:
CH3-O-CH3

Solution:
CH3-OCH3 does not have replaceable H- atom.
Therfore the compound does not react with sodium.

Topic: Chemistry, Alcohols Phenols and Ethers, NEET
The compound which gives off oxygen on moderate heating is

Options:
A Cupric oxide
B Mercuric oxide
C Zinc oxide
D Aluminium oxide

The correct answer is:
Mercuric oxide

Solution:
Mercuric oxide gives off oxygen on moderate heating
2 HgO â¶ Î 2 Hg + O 2 â

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), NEET
The compound which is NOT formed when a mixture of n-butyl bromide and ethyl bromide treated with sodium metal in presence of dry ether is

Options:
A Butane
B Octane
C Hexane
D Ethane

The correct answer is:
Ethane

Solution:
Mixture of n-butyl bromide and ethyl bromide gives the following compounds- butane, octane and hexane. It does not give ethane.

Topic: Chemistry, Hydrocarbons, NEET
The compound, which on reductive ozonolysis gives one mole of O=CH−C H 2 −C H 2 −C H 2 −CH=O , is

Options:
A 1-methylbut-1-ene
B 3-methylbut-1-ene
C cyclopentane
D 1, 2-dimethylpropene

The correct answer is:
cyclopentane

Solution:
The presence of two C=O groups in the same product indicates a cycloalkene, i.e., cylclopentene.

Topic: Chemistry, Aldehydes and Ketones, NEET
The compound which reacts with both HCl and NaOH is

Options:
A CaO
B CO 2
C ZnO
D N 2 O 5

The correct answer is:
ZnO

Solution:
ZnCl 2 ← HCl ZnO → NaOH Na 2 ZnO 2

Topic: Chemistry, s Block Elements, NEET
The compound which shows metamerism is:

Options:
A C5H12
B C3H8O
C C3H6O
D C4H10O

The correct answer is:
C4H10O

Solution:
Metamerism is shown by polyvalent functional groups like ester ether and ketone.
Unequal distribution of alkyl groups around polyvalent functional group give rise to metamerism. C4H10O: ether

I and II are metamers

Topic: Chemistry, General Organic Chemistry, NEET, NEET 2021
The compound with molecular formula C8H10 which will give only two isomers on electrophilic substitution with Cl2/FeCl3 or with HNO3/H2SO4 is

Options:
A none of these
B 1, 4- dimethyl benzene
C 1, 2-dimethyl benzene
D ethylbenzene

The correct answer is:
1, 2-dimethyl benzene

Solution:
Here the reaction mechanism is electrophilic substitution which occurs as follows

Topic: Chemistry, Hydrocarbons, NEET
The compounds A and B in the following reaction are, respectively

Options:
A A = Benzyl alcohol, B = Benzyl isocyanide
B A = Benzyl alcohol, B = Benzyl cyanide
C A = Benzyl chloride, B = Benzyl cyanide
D A = Benzyl chloride, B = Benzyl isocyanide

The correct answer is:
A = Benzyl chloride, B = Benzyl isocyanide

Solution:
Here the reaction is as follows

Topic: Chemistry, Haloalkanes and Haloarenes, NEET
The compounds formed by the reaction of ammonia with chlorine and iodine are respectively

Options:
A NCl3 and NI3
B NCl3 and NH4I
C NH4Cl and NH4I
D NCl3 and (NI3.NH3)

The correct answer is:
NCl3 and (NI3.NH3)

Solution:
Ammonia on reaction with chlorine and iodine gives NCl3 and (NI3.NH3) respectively as follows
NH3+3Cl2excess→NCl3+3HCl
2NH3+3I2→NI3.NH3+3HI

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), NEET