datavorous/entrance-exam-dataset huggingface dataset:
The genetic instructions for forming a polypeptide chain are carried to the ribosome by the

Options:
A tRNA
B mRNA
C rRNA
D DNA

The correct answer is:
mRNA

Solution:
The genetic instructions for forming a polypeptide chain are carried to the ribosome by the mRNA molecule. The genetic information is carried in an mRNA molecule into a protein in the form of codons. During translation, the tRNA carries and transfers an amino acid to the forming polypeptide chain. The rRNA provides the place for the polypeptide chain formation.

Topic: Biology, Biotechnology - Principles and Processes, NEET
The genetic material in the following organism is

Options:
A double-stranded DNA.
B single-stranded DNA.
C double-stranded RNA.
D single-stranded RNA.

The correct answer is:
single-stranded RNA.

Solution:
Viruses are acellular organisms which contain either DNA or RNA as their genetic material. Viruses are not given any place in five kingdom classification since they lack cell. Tobacco Mosaic Virus (TMV) structurally looks like a rod. It causes mosaic disease in tobacco whose genetic material is made up of single stranded coiled RNA molecule.

Topic: Biology, Biological Classification, NEET
The genetic material of HIV virus comprises of

Options:
A One single-stranded RNA
B One double stranded RNA
C Two single-stranded RNA
D Two single-stranded DNA

The correct answer is:
Two single-stranded RNA

Solution:
AIDS is caused by the Human Immunodeficiency Virus (HIV), a
member of a group of viruses called retroviruses, which have an envelope enclosing the two single-stranded RNA genome having reverse transcriptase enzyme.

Topic: Biology, Human Health and Diseases, NEET
The genetic material of the Tobacco mosaic virus is

Options:
A Double stranded RNA
B Double stranded DNA
C Single stranded RNA
D Single stranded DNA

The correct answer is:
Single stranded RNA

Solution:
The tobacco mosaic virus has a genome of single-stranded RNA. These viruses infect a large group of plants, especially tobacco and also many other members of family Solanaceae. This disease causes patches of discoloration and a mosaic pattern on leaves as a symptom.

Topic: Biology, Biological Classification, NEET
The genetically inactive and highly condensed region with tightly packed DNA which receives dark stain is

Options:
A Euchromatin
B Heterochromatin
C Chromatin
D Chromosome

The correct answer is:
Heterochromatin

Solution:
Heterochromatin is a tightly packed form of DNA or condensed DNA, which comes in multiple varieties. These varieties lie on a continuum between the two extremes of constitutive heterochromatin and facultative heterochromatin.

Topic: Biology, Principles of Inheritance and Variation, NEET
The genetically-modified (GM) brinjal in India has been developed for

Options:
A insect-resistance
B enhancing self life
C enhancing mineral content
D drought-resistance

The correct answer is:
insect-resistance

Solution:
The genetically modified brinjal or $B t$ brinjal has the same Cry LAC gene from Bacillus thuringiensis as cotton. The gene is supposed to make the plant tolerant to the shoot and fruit borer insect, which attacks it throughout its life cycle.

Topic: Biology, Biotechnology and Its Applications, NEET, NEET 2010 (Screening)
The genome of how many of the following organisms has been sequenced during HGP.

Human, Yeast, Drosophila, Honey bee, Rice, Wheat, Arabidopsis, Caenorhabditis.

Options:
A Five
B Six
C Seven
D Eight

The correct answer is:
Six

Solution:
Many non-human model organisms, such as bacteria, yeast, Caenorhabditis elegans (a free-living nonpathogenic nematode), Drosophila (fruit fly), plants (rice and Arabidopsis) have also been sequenced. Also, the human genome has been completely sequenced.

Topic: Biology, Molecular Basis of Inheritance, NEET
The genotype of a plant showing the dominant phenotype can be determined by

Options:
A test cross
B dihybrid cross
C pedigree analysis
D back cross

The correct answer is:
test cross

Solution:
In Genetics, a test cross, first introduced by Gregor Mendel, is used to determine if an individual exhibiting a dominant trait is homozygous or heterozygous for that trait. More simply, test cross determines the genotype of an individual with a dominant phenotype. In some sources, the test cross is defined as being a type of back cross between the recessive homozygote and $\mathrm{F}_1$ generation.

Topic: Biology, Principles of Inheritance and Variation, NEET, NEET 2010 (Screening)
The genotypes of a husband and wife are IAIB and IAi. Among the blood types of their children, how many different genotypes and phenotypes are possible?

Options:
A 3 genotypes; 4 phenotypes
B 4 genotypes; 3 phenotypes
C 4 genotypes; 4 phenotypes
D 3 genotypes; 3 phenotypes

The correct answer is:
4 genotypes; 3 phenotypes

Solution:
If the genotypes of husband and wife are IAIB and IAi respectively, then the probabilities of genotypes and phenotypes among their children can be worked out as: Genotype: IAIA; IAi; IAIB; IBi. Phenotype: A:AB: B :: 2:1:1. Thus, there are four possible genotypes and three possible phenotypes among the children.

Topic: Biology, Principles of Inheritance and Variation, NEET
The genotypes of a Husband and Wife are IA IB and IAi .
Among the blood types of their children, how many different genotypes and phenotypes are possible?

Options:
A 3 genotypes; 3 phenotypes
B 3 genotypes; 4 phenotypes
C 4 genotypes; 3 phenotypes
D 4 genotypes; 4 phenotypes

The correct answer is:
4 genotypes; 3 phenotypes

Solution:
Husband × Wife I A I B I A i
Number of genotypes = 4
Number of phenotypes = 3
IA IA and IAi=A
IA IB=AB
IBi=B

Topic: Biology, Principles of Inheritance and Variation, NEET, NEET 2017
The genotypes of a plant variety were TtHh, Tthh, ttHh and tthh, where T = tallness and H = hairy stem. Which one of the following crosses would produce progeny giving a phenotypic ratio approximately 1: 1: 1: 1?

Options:
A TtHh × TtHh
B TtHh × Tthh
C TtHh × ttHh
D TtHh × tthh

The correct answer is:
TtHh × tthh

Solution:
This is a dihybrid test cross which produces the ratio of 1 : 1 : 1 : 1.

Topic: Biology, Principles of Inheritance and Variation, NEET
The genus Nucleopolyhedroviruses are

Options:
A effective against disease-causing pathogens.
B effective against rodents.
C broad spectrum insecticides.
D effective against insects and other arthropods.

The correct answer is:
effective against insects and other arthropods.

Solution:
Baculovirus belongs to Nucleopolyhedroviruses and are used as effective biocontrol against some insects and other arthropods. These shows narrow spectrum specific insecticidal action.

Topic: Biology, Microbes in Human Welfare, NEET
The genus of chiton (a mollusc) is

Options:
A Chaetopleura
B Dentalium
C Aplysia
D Architeuthis

The correct answer is:
Chaetopleura

Solution:
Members of phylum Mollusca include: Ampullariidae - Apple snail, Pinctada - Pearl oyster, Loligo - Squid, Octopus - Devilfish, Dentalium - Tusk shell, Aplysia - Sea hare, Chaetopleura - Chiton, Sepia - Cuttlefish, Architeuthis - Giant squid, Helix - Land snail.

Topic: Biology, Animal Kingdom, NEET
The geometrical arrangement of electron pairs and shape of I 3 - are respectively

Options:
A Trigonal bipyramidal geometry, linear shape
B Hexagonal geometry, T-shape
C Triangular planar geometry, triangular shape
D Tetrahedral geometry, pyramidal shape

The correct answer is:
Trigonal bipyramidal geometry, linear shape

Solution:
Steric number for I 3 â â=â 1 2 7â+â2â0â+â1 â=â5
Hybridization of I in I 3 - is sp3d.
Thus I 3 - has trigonal bipyramidal geometry with linear shape.

Topic: Chemistry, Chemical Bonding and Molecular Structure, NEET
The geometries of the ammonia complexes of Ni2+,Pt2+ and Zn2+ , respectively, are

Options:
A octahedral, square planar and tetrahedral
B square planar, octahedral and tetrahedral
C tetrahedral, square planar and octahedral
D octahedral, tetrahedral and square planar

The correct answer is:
octahedral, square planar and tetrahedral

Solution:
[Ni(NH3)6]2+= octahedral
[Pt(NH3)4]2+= square planar
[Zn(NH3)4]2+= tetrahedral

Topic: Chemistry, Coordination Compounds, NEET
The geometry and magnetic behaviour of the complex [Ni(CO)4] are

Options:
A Square planar geometry and paramagnetic
B Tetrahedral geometry and diamagnetic
C Square planar geometry and diamagnetic
D Tetrahedral geometry and paramagnetic

The correct answer is:
Tetrahedral geometry and diamagnetic

Solution:
Ni(28):[Ar]3d84s2
As CO is a strong field ligand so configuration would be

n=0(no unpaired electron)
For, four ‘CO’-ligands hybridisation would be sp3 and thus the complex would be diamagnetic and of tetrahedral geometry as follows.

Topic: Chemistry, Coordination Compounds, NEET
The geometry of some complex ions are given against them -

(1) [Ag(NH3)2]+ - Linear

(2) [MnCl4]2- - Tetrahedral

(3) [Cu(NH3)4]2+ - Square planar

(4) [Ni(CN)4]2- - square planar

The correct match is -

Options:
A 1 and 4
B 1, 2 and 3
C 1, 3 and 4
D 1, 2, 3 and 4

The correct answer is:
1, 2, 3 and 4

Solution:
[Ag(NH3)2]+-Linear ; [MnCl4]2--Tetrahedral ; [Cu(NH3)4]2+-Square plannar ; [Ni(CN)4]2--Square planar

Topic: Chemistry, Coordination Compounds, NEET
The gestation period in humans is

Options:
A 280 days from the end of the last menstrual cycle
B 280 days from the day of insemination
C 280 days from the day of fertilization of the egg
D 266 days from the day of the start of the last menstrual cycle

The correct answer is:
280 days from the end of the last menstrual cycle

Solution:
The fusion of a haploid male gamete (spermatozoan) and a haploid female gamete (ovum) to form a diploid zygote is called fertilization. In human females, fertilization is internal and it takes place in the ampulla of the fallopian tube. Fertilization occurs within 6 hours after ovulation. The condition of carrying one or more embryos in the uterus is called Pregnancy or Gestation. Human pregnancy lasts for an average of 266 days from fertilization of the egg or 280 days from the start of the last menstrual cycle.

Topic: Biology, Human Reproduction, NEET
The Gibbs free energy (ΔG) is related with cell potential (E) by ΔG=-nFE ; the cell reaction will be spontaneous if

Options:
A G is negative
B G is positive
C E is negative
D E is positive

The correct answer is:
E is positive

Solution:
If E=+ve than ΔG=-ve , the cell reaction will be spontaneous.

Topic: Chemistry, Thermodynamics (C), NEET
The give reaction
is an example of

Options:
A SE2
B SN1
C SN2
D SE1

The correct answer is:
SN2

Solution:
It is a case of SN2 reaction as inversion of configutation occurs.

Topic: Chemistry, Haloalkanes and Haloarenes, NEET
The given below diagram is the representation of

Options:
A Longitudinal binary fission in paramecium
B Longitudinal binary fission in euglena
C Transverse binary fission in chlamydomonas
D Transverse binary fission in dinoflagellates

The correct answer is:
Longitudinal binary fission in euglena

Solution:
Longitudinal Binary Fission: The plane of division passes along the longitudinal axis of the animal. It occurs in flagellates such as Euglena. The flagellum divides first followed by the body.

Topic: Biology, Reproduction in Organisms, NEET
The given below punnet squares represents

Options:
A complete dominance and incomplete dominance
B complete dominance and co-dominance
C incomplete dominance and co-dominance
D complete dominance, co-dominance and incomplete dominance

The correct answer is:
incomplete dominance and co-dominance

Solution:
The two punnet squares represent incomplete dominance and codominance. These are both types of inheritance where one allele is not completely dominant over the other allele resulting in a new phenotype.
In incomplete dominance blending of the two alleles occurs resulting in a phenotype that does not look like the parents. A cross between a white flower and a red flower produced all the offspring that are solid pink flowers due to incomplete dominance.
In codominance, in the offsprings, both alleles are expressed together. If a cross is done between red flower and white flower, the flowers of the offspring would be with red and white patches on them.

Topic: Biology, Principles of Inheritance and Variation, NEET
The given biomolecule is the part of the defense system which is responsible for___________response with A and B labeled as:

Options:
A Cell mediated response, I: Heavy chain, II: Light Chain
B Humoral immune response, I: Antigen binding site, II: Light chain
C Humoral immune response, I: Heavy chain, II: Light chain
D Cell mediated response, I: Light chain, II: Heavy chain

The correct answer is:
Humoral immune response, I: Antigen binding site, II: Light chain

Solution:
B cells are lymphocytes that play a large role in the humoral immune response (as opposed to the cell-mediated immune response, which is governed by T cells). B cells primarily function to make antibodies while T-Cells help B-Cells.
Each antibody has 4 peptide chains, two small which are light and two heavy which are long chains. The antibody recognizes the pathogen, called an antigen, via variable region which is antigen binding site

Topic: Biology, Human Health and Diseases, NEET
The given circuit has two ideal diodes connected as shown in the figure below. The current flowing through the resistance R1 will be

Options:
A 2.5 A
B 10.0 A
C 1.43 A
D 3.13 A

The correct answer is:
2.5 A

Solution:
D1 is in reverse bias.

D2 is in forward bias.

I=10 V2+2 Ω=2.5 A.

Topic: Physics, Semiconductors, NEET, NEET 2016 (Phase 2)
The given circuit is equivalent to

Options:
A

B

C

D

The correct answer is:

Solution:
Method 2:
$\begin{aligned} & Y=\overline{\bar{A}}+\overline{\bar{B}} \\ & Y=\overline{\bar{A}} \cdot \overline{\bar{B}}=A B\end{aligned}$
AND gate

Topic: Physics, Semiconductors, NEET, NEET 2023 (Manipur)
The given circuit shows a uniform straight wire $A B$ of 40 cm length fixed at both ends. In order to get zero reading in the galvanometer $G$, the free end of $J$ is to be placed from $B$ at:

Options:
A 32 cm
B 8 cm
C 16 cm
D 24 cm

The correct answer is:
24 cm

Solution:
$\frac{8}{x}=\frac{12}{40-x}$
$\frac{2}{x}=\frac{3}{40-x}$
$80-2 x=3 x$
$16=x$
from B
$=40-16=24 \mathrm{~cm}$

Topic: Physics, Current Electricity, NEET, NEET 2024 (Re-NEET)
The given compound

is an example of

Options:
A Vinylic halide
B Benzylic halide
C Aryl halide
D Allylic halide

The correct answer is:
Allylic halide

Solution:
Allylic halides are compounds containing halogen atoms bonded to sp3 hybridised C-atom next to carbon-carbon double bond. Vinylic halides are compounds containing halogen atom bonded to sp2 hybridised C-atom of an aliphatic compound. Benzylic halides are compounds containing halogen atoms bonded to sp3 hybridised C-atom next to benzene ring. In Aryl halides, the halogen atom directly attached to the aromatic ring.

Topic: Chemistry, General Organic Chemistry, NEET, NEET 2023 (All India)
The given data are for the reaction
2NO(g)+Cl(g)â2NOCl(g) at 298 K

[Cl2]
[NO]
Initial rate (mol L-1sec-1 )

I
0.05 M
0.05 M
1Ã10-3

II
0.15 M
0.05 M
3Ã10-3

III
0.05 M
0.15 M
9Ã10-3

The rate law of the reaction is

Options:
A rate =k[NO][Cl2]
B rate =k[Cl2][NO]2
C rate =k[Cl2]2[NO]
D rate =k[Cl2]

The correct answer is:
rate =k[Cl2][NO]2

Solution:
1×10-3=k[0.05]α[0.05]β …(i)
3×10-3=k[0.15]α[0.05]β …(ii)
9×10-3=k[0.05]α[0.15]β …(iii)
From (i) and (ii), α=1
and from (i) and (iii), β=2
So rate =k[NO]2[Cl2]1 .

Topic: Chemistry, Chemical Kinetics, NEET
The given diagram illustrates the presence of

Options:
A Amylose in aqueous solution
B Amylopectin in aqueous solution
C Iodine in aqueous solution
D Both amylose and iodine in the solution

The correct answer is:
Both amylose and iodine in the solution

Solution:
Starch can be used as an indicator for the detection of traces of iodine in aqueous solution. Amylose is responsible for the formation of deep blue colour in the test for the presence of starch. The action of amylase enzyme breaks the amylose into glucose molecules and the blue colour will not be formed.

Topic: Chemistry, Biomolecules, NEET
The given diagram represents which type of plant?
(The red line indicates the critical period).

Options:
A Long day plant
B Short day plant
C Day neutral plant
D None of these

The correct answer is:
Long day plant

Solution:
The given diagram is that of a long day plant, because long day plants fail to flower if the day length is shorter than the critical period.

Topic: Biology, Plant - Growth and Development, NEET
The given electrical network is equivalent to :

Options:
A OR gate
B NOR gate
C NOT gate
D AND gate

The correct answer is:
NOR gate

Solution:
Y 1 = A+B ¯
Y 2 = Y 1 + Y 1 ¯ = Y 1 ¯ =A+B
Y= Y 2 ¯ = A+B ¯ i.e., NOR gate

Topic: Physics, Semiconductors, NEET
The given electrical network is equivalent to

Options:
A AND gate
B OR gate
C NOR gate
D NOT gate

The correct answer is:
NOR gate

Solution:
Output at NOR gate Y 1 = A+B ¯
The output of first NOR gate is input to the second NOR gate, so the output of second NOR gate is Y 2 = Y 1 + Y 1 ¯ = Y 1 ¯ = A+B ¯ ¯ =A+B
The output of NOT gate is Y= Y 2 ¯ = A+B ¯
The given electrical network becomes equivalent to the NOR gate.

Topic: Physics, Semiconductors, NEET, NEET 2017
The given electrical network is equivalent to

Options:
A AND gate
B OR gate
C NOR gate
D NOT gate

The correct answer is:
NOR gate

Solution:
Y 1 = A+B ¯
Y 2 = Y 1 + Y 1 ¯ = Y 1 ¯ = A+B ¯ ¯ =A+B
Y= Y 2 ¯ = A+B ¯
The given electrical network becomes equivalent to NOR gate.

Topic: Physics, Semiconductors, NEET
The given experimental set-up demonstrate:

Options:
A Photosynthesis
B Aerobic respiration
C Anaerobic respiration
D Ascent of sap

The correct answer is:
Anaerobic respiration

Solution:
Respiration is the process of releasing energy in the form of ATP by breaking down glucose either in presence or absence of oxygen. The given setup above is to demonstrate anaerobic respiration. In it, few soaked seeds are taken and inserted in a test tube containing mercury. After inverting the tube and setting up as shown in part-A, the seeds float up above the mercury. On leaving the setup for 2-3 days as it is we observed that the level of mercury in the inverted test tube has gone down suggesting release and accumulation of CO2 . This proves anaerobic respiration has occurred as there is no oxygen in the tube. The presence of CO2 can be tested using potassium hydroxide.

Topic: Biology, Respiration in Plants, NEET
The given figure can be corresponded to:

Options:
A Packaging of DNA helix
B Reverse flow of information
C Central dogma
D Updated central dogma

The correct answer is:
Central dogma

Solution:
The central dogma of molecular biology describes the two-step process, transcription and translation, by which the information in genes flows into proteins:
DNA â RNA â Protein .
Transcription is the synthesis of an RNA copy of a segment of DNA.

Topic: Biology, Molecular Basis of Inheritance, NEET
The given figure shows L.S of the seed of maize. What do A, B, C and D represent?

Options:
A A : Endosperm B : Scutellum
C : Plumule D : Coleoptile
B A : Scutellum B : Pericarp
C : Radicle D : Coleoptile
C A : Endosperm B : Scutellum
C : Radicle D : Coleorhiza
D A : Scutellum B : Pericarp
C : Plumule D : Coleorhiza

The correct answer is:
A : Endosperm B : Scutellum
C : Radicle D : Coleorhiza

Solution:

Topic: Biology, Morphology of Flowering Plants, NEET
The given figure shows three velocity-substrate concentration curves for an enzyme reaction. What do the curves x, y, and z depict respectively ?

Options:
A x-Normal enzyme reaction, y-Competitive inhibition, z-Non-competitive inhibition
B x-Enzyme with an allosteric modulator added, y-Normal enzyme activity, z-Competitive nhibition
C x-Enzyme with an allosteric stimulator, y-Competitive inhibition added, z-Normal enzyme reaction
D x-Normal enzyme reaction, y-Non-competitive inhibitor added, z-Allosteric inhibitor added

The correct answer is:
x-Normal enzyme reaction, y-Competitive inhibition, z-Non-competitive inhibition

Solution:
Enzymes or biocatalysts are proteinaceous substance that are capable of catalysing chemical reactions of biological systems without themselves undergoing any change. The graph x shows normal enzyme reaction, graph y shows competitve inhibition and graph z shows non competitive inhibition. In competitive inhibition the inhibitor, which is a substrate analogue, combines reversibly to the free enzyme at the active site. In non competitive inhibition, the inhibitor binds to enzyme at a place other than substrate binding site. It results in destruction of enzyme activity.

Topic: Chemistry, Biomolecules, NEET
The given floral formula can be seen in

Options:
A Soyabean
B Sunhemp
C Tobacco
D Colchicine

The correct answer is:
Tobacco

Solution:
Tobacco belongs to the family Solanaceae. The flower is actinomorphic, bisexual, gamosepalous with 5 sepals, gamopetalous corolla with 5 petals, 5 epipetalous stamens, and bicarpellary syncarpous superior ovary.

Topic: Biology, Morphology of Flowering Plants, NEET
The given floral formula corresponds to:

Options:
A Sunhemp
B Belladonna
C Tulip
D Soyabean

The correct answer is:
Belladonna

Solution:
Sun hemp, Tulip, Indigofera, Soyabean, Pea and Bean belong to Fabaceae family.
The floral formula of Fabaceae family is i.e. Fabaceae family has monocarpellary, unilocular ovary with many ovules.
Common example of Solanaceae family are Atropa belladonna, Solanum tuberosum (Potato), Tomato and Solanum melangena (Brinjal). Floral formula of this family is

Topic: Biology, Morphology of Flowering Plants, NEET
The given graph is a representation of kinetics of a reaction.

The y and x axes for zero and first order reactions, respectively are

Options:
A zero order (y= concentration and x= time), first order (y= rate constant and x= concentration)
B zero order (y= rate and x= concentration), first order (y=t12 and x= concentration)
C zero order (y= rate and x= concentration), first order (y= rate and x=t12
D zero order (y= concentration and x=time),
first order (y=t12 and x= concentration)

The correct answer is:
zero order (y= rate and x= concentration), first order (y=t12 and x= concentration)

Solution:
In zero order, rate is independent of Concentration of reactants

Rate =K

In first order, half life t12 is dependent only on K

t12=0.693K

So no change with respect to concentration.

Topic: Chemistry, Chemical Kinetics, NEET, NEET 2022 (Phase 1)
The given graph represents V - I characteristic for a semiconductor device.
Which of the following statement is correct?

Options:
A It is V - I characteristic for solar cell where, point A represents open circuit voltage and point B short circuit current
B It is for a solar cell and points A and B represent open circuit voltage and current, respectively
C It is for a photodiode and points A and B represent open circuit voltage and current respectively
D It is for a LED and points A and B represent open circuit voltage and short circuit current, respectively

The correct answer is:
It is V - I characteristic for solar cell where, point A represents open circuit voltage and point B short circuit current

Solution:
The given graph is V - I characteristic curve for a solar cell, where A i.e point where V=0 represents open circuit voltage of solar cell and B i.e. the point where i=0 represents short circuit current.

Topic: Physics, Semiconductors, NEET, NEET 2014
The given group of animals belong to Gnathostomata and bear limbs are:

Options:
A Myxine, Clarius, Exocoetus
B Ichthyophis, Hippocampus, Bufo
C Hyla, Chelone, Corvus
D Chelone, Betta, Psittacula

The correct answer is:
Hyla, Chelone, Corvus

Solution:
On the basis of absence and presence of jaw, vertebrates are divided into:
A. Agnatha (Jawless vertebrates) including Cyclostomata.
B. Gnathostomata with jaw and which bears fins are Pisces (true fishes) and which bears limbs include class Amphibia, Reptilia, Aves and Mammalia.
Hyla is frog and belongs to class Amphibia, Chelone is a turtle and belongs to Reptilia, Corvus is crow and belongs to Aves.

Topic: Biology, Animal Kingdom, NEET