datavorous/entrance-exam-dataset huggingface dataset:
Arrange the following compounds in increasing order of their solubilities in chloroform:
$\mathrm{NaCl}, \mathrm{CH}_3 \mathrm{OH}$, cyclohexane, $\mathrm{CH}_3 \mathrm{CN}$

Options:
A $\mathrm{NaCl} \lt \mathrm{CH}_3 \mathrm{CN} \lt \mathrm{CH}_3 \mathrm{OH} \lt $ Cyclohexane
B $\mathrm{CH}_3 \mathrm{OH} \lt \mathrm{CH}_3 \mathrm{CN} \lt \mathrm{NaCl} \lt $ Cyclohexane
C $\mathrm{NaCl} \lt \mathrm{CH}_3 \mathrm{OH} \lt \mathrm{CH}_3 \mathrm{CN} \lt $ Cyclohexane
D Cyclohexane $ \lt \mathrm{CH}_3 \mathrm{CN} \lt \mathrm{CH}_3 \mathrm{OH} \lt \mathrm{NaCl}$

The correct answer is:
$\mathrm{NaCl} \lt \mathrm{CH}_3 \mathrm{CN} \lt \mathrm{CH}_3 \mathrm{OH} \lt $ Cyclohexane

Solution:
Since $\mathrm{CHCl}_3$ is an organic solvent so, covalent (non-polar) compounds will be more soluble in it. As the dipole moment of solute increases, solubility in chloroform decreases. Hence increasing order of solubility.
$\mathrm{NaCl} \lt \mathrm{CH}_3 \mathrm{CN} \lt \mathrm{CH}_3 \mathrm{OH} \lt $ Cyclohexane

Topic: Chemistry, Chemical Bonding and Molecular Structure, NEET, NEET 2024 (Re-NEET)
Arrange the following compounds in order of increasing dipole moment
I) Toluene
II) m-dichlorobenzene
III) o-dichlorobenzene
IV) p-dichlorobenzene

Options:
A I<IV<II<III
B IV<I<II<III
C IV<I<III<II
D IV<II<I<III

The correct answer is:
IV<I<II<III

Solution:
p-dichlorobenzene<m-dichlorobenzene<Toluene<o-dichlorobenzene

Topic: Chemistry, Chemical Bonding and Molecular Structure, NEET
Arrange the following compounds in order of their reactivity towards SN2 reaction
(i) CH3(CH2)2CH2Cl
(ii) (CH3)2CHCH2CH2Cl
(iii)
(iv)

Options:
A (iv) > (ii) > (i) > (iii)
B (ii) > (iii) > (iv) > (i)
C (iii) > (i) > (ii) > (iv)
D (i) > (ii) > (iii) > (iv)

The correct answer is:
(i) > (ii) > (iii) > (iv)

Solution:
The order of reactivity of alkyl halides towards SN2 reaction is 1°>2°>3° . Here the reactivity order is given as follows

Topic: Chemistry, Haloalkanes and Haloarenes, NEET
Arrange the following compounds in order of their reactivity towards SN2 reaction
(i) CH3(CH2)3CH2Br
(ii) (CH3)2CHCH2CH2Br
CH 3                       | iii   CH 3 CH 2 −CH− CH 2 Br
CH 3                 | iv   CH 3 −C− CH 2 Br                 |                 CH 3

Options:
A (i) > (ii) > (iii) > (iv)
B (ii) > (iii) > (iv) > (i)
C (iii) > (i) > (ii) > (iv)
D (iv) > (ii) > (i) > (iii)

The correct answer is:
(i) > (ii) > (iii) > (iv)

Solution:
Order of reactivity of alkyl halides towards SN2 reaction is 1°>2°>3° . Here the reactivity order is as follows

Topic: Chemistry, Haloalkanes and Haloarenes, NEET
Arrange the following compounds in the increasing order of their boiling points: CH3CH2CH2CHO, CH3CH2CH2CH2OH, H5C2-O-C2H5,CH3CH2CH2CH3

Options:
A CH3CH2CH2CH3< H5C2-O-C2H5< CH3CH2CH2CH2OH < CH3CH2CH2CHO
B CH3CH2CH2CH2OH < CH3CH2CH2CH3< H5C2-O-C2H5< CH3CH2CH2CHO
C CH3CH2CH2CHO < CH3CH2CH2CH2OH < CH3CH2CH2CH3< H5C2-O-C2H5
D CH3CH2CH2CH3< H5C2-O-C2H5< CH3CH2CH2CHO < CH3CH2CH2CH2OH

The correct answer is:
CH3CH2CH2CH3< H5C2-O-C2H5< CH3CH2CH2CHO < CH3CH2CH2CH2OH

Solution:
Correct Option is : (D)
CH3CH2CH2CH3< H5C2-O-C2H5< CH3CH2CH2CHO < CH3CH2CH2CH2OH

Topic: Chemistry, Aldehydes and Ketones, NEET
Arrange the following ecosystems in the decreasing order of their mean net primary productivity (tons/hectare/year).

I. Tropical deciduous forest
II. Temperate coniferous forest
III. Tropical rain forests
IV. Temperate deciduous forest
V. Desert scrub

Options:
A III > I > IV > II > V
B II > IV > I > III > V
C III > I > II > IV > V
D IV > II > III > I > V

The correct answer is:
III > I > IV > II > V

Solution:
Net primary productivity is the quantity of biomass produced by plants per unit area per unit time after all respiratory losses. The productivity of an ecosystem depends on temperature and annual precipitation. The tropical rain forest is the most productive terrestrial ecosystem.

Topic: Biology, Ecosystem, NEET
Arrange the following efforts to control pollution in chronological order.

A. In India, the Air (Prevention and Control of Pollution) Act was amended to include noise as an air pollutant.
B. The government of India passed the Water (Prevention and Control of Pollution) Act to safeguard our water resources.
C. Recognizing the deleterious effects of ozone depletion, the Montreal Protocol became effective.
D. The National Forest Policy of India recommended 33% forest cover for the plains and 67% for the hills.

Options:
A A - B - D - C
B B - A - D - C
C B - A - C - D
D A - B - C - D

The correct answer is:
B - A - D - C

Solution:
The government of India has passed the Water (Prevention and Control of Pollution) Act, 1974 to safeguard our water resources. In India, the Air (Prevention and Control of Pollution) Act was amended in 1987 to include noise as an air pollutant. The National Forest Policy (1988) of India has recommended 33% forest cover for the plains and 67% for the hills. Recognizing the deleterious effects of ozone depletion, an international treaty, known as the Montreal Protocol, was signed at Montreal (Canada) in 1987 (effective in 1989).

Topic: Biology, Environmental Issues, NEET
Arrange the following elements in increasing order of electronegativity:
$\mathrm{N}, \mathrm{O}, \mathrm{F}, \mathrm{C}, \mathrm{Si}$
Choose the correct answer from the options given below:

Options:
A Si $ \lt $ C $ \lt $ O $ \lt \mathrm{N} \lt \mathrm{F}$
B $\mathrm{O} \lt \mathrm{F} \lt \mathrm{N} \lt \mathrm{C} \lt \mathrm{Si}$
C $\mathrm{F} \lt \mathrm{O} \lt \mathrm{N} \lt \mathrm{C} \lt $ Si
D Si $ \lt $ C $ \lt $ N $ \lt $ O $ \lt $ F

The correct answer is:
Si $ \lt $ C $ \lt $ N $ \lt $ O $ \lt $ F

Solution:
Electronegativity increases across the period on moving left to right. It decreases on moving down the group.
The correct option is $\mathrm{Si} \lt \mathrm{C} \lt \mathrm{N} \lt \mathrm{O} \lt \mathrm{F}$

Topic: Chemistry, Classification of Elements and Periodicity in Properties, NEET, NEET 2024
Arrange the following elements in increasing order of first ionization enthalpy:
$\mathrm{Li}, \mathrm{Be}, \mathrm{B}, \mathrm{C}, \mathrm{N}$
Choose the correct answer from the options given below:

Options:
A $\mathrm{Li} \lt \mathrm{B} \lt \mathrm{Be} \lt \mathrm{C} \lt \mathrm{N}$
B $\mathrm{Li} \lt \mathrm{Be} \lt \mathrm{C} \lt \mathrm{B} \lt \mathrm{N}$
C $\mathrm{Li} \lt \mathrm{Be} \lt \mathrm{N} \lt \mathrm{B} \lt \mathrm{C}$
D $\mathrm{Li} \lt \mathrm{Be} \lt $ B $ \lt $ C $ \lt $ N

The correct answer is:
$\mathrm{Li} \lt \mathrm{B} \lt \mathrm{Be} \lt \mathrm{C} \lt \mathrm{N}$

Solution:
Increasing order of first ionization enthalpy is $\mathrm{Li} \lt \mathrm{B} \lt \mathrm{Be} \lt \mathrm{C} \lt \mathrm{N}$
$\begin{array}{|c|c|}\hline \text{Element} & \begin{array}{l} \text{First ionization enthalpy} \\ \left(\Delta_{\mathrm{i}} \mathrm{H} / \mathrm{kJ} \mathrm{mol}^{-1}\right. )\end{array} \\ \hline Li & 520 \\ \hline Be & 899 \\ \hline B & 801 \\ \hline C & 1086 \\ \hline N & 1402 \\ \hline\end{array}$

Topic: Chemistry, Classification of Elements and Periodicity in Properties, NEET, NEET 2024
Arrange the following events of meiosis in the correct sequence:
i. Crossing over
ii. Synapsis
iii. Terminalisation of chiasmata
iv. Disappearance of the nucleolus

Options:
A (ii), (i), (iii), (iv)
B (i), (ii), (iii), (iv)
C (ii), (iii), (iv), (i)
D (ii), (i), (iv), (iii)

The correct answer is:
(ii), (i), (iii), (iv)

Solution:
The sequence of event during meiosis are:
(A) Synapsis (Zygotene)- The homologous chromosomes start pairing with the help of the synaptonemal complex.
(B) Crossing over (Pachytene)- The non-sister chromatids of homologous chromosomes exchanges their parts. Enzyme recombinase takes part in this process.
(C) Terminalisation of chiasmata (Diakinesis)- The chiasmata moves towards the end of the chromosome (Telomere).
(D) The disappearance of nucleolus- The degeneration of nucleolus and nuclear membrane takes place which marks the end of prophase-I.

Topic: Biology, Cell Cycle and Cell Division, NEET, NEET 2015 (Phase 2)
Arrange the following in decreasing order of basic strength in gas phase: C2H5NH2, (C2H5)2NH, (C2H5)3N and NH3

Options:
A (C2H5)3N > C2H5NH2> NH3> (C2H5)2NH
B (C2H5)3N > (C2H5)2NH > C2H5NH2> NH3
C (C2H5)3N > NH3> C2H5NH2> (C2H5)2NH
D (C2H5)3N > C2H5NH2> (C2H5)2NH > NH3

The correct answer is:
(C2H5)3N > (C2H5)2NH > C2H5NH2> NH3

Solution:
Correct Option is : (B)
(C2H5)3N > (C2H5)2NH > C2H5NH2> NH3

Topic: Chemistry, Amines, NEET
Arrange the following in decreasing order of the pKbvalues: C2H5NH2, C6H5NHCH3, (C2H5)2NH and C6H5NH2

Options:
A C6H5NHCH3< C2H5NH2< (C2H5)2NH < C6H5NH2
B C2H5NH2< (C2H5)2NH < C6H5NH2< C6H5NHCH3
C C6H5NH2< C6H5NHCH3< (C2H5)2NH < C2H5NH2
D C6H5NH2< C6H5NHCH3< C2H5NH2< (C2H5)2NH

The correct answer is:
C6H5NH2< C6H5NHCH3< C2H5NH2< (C2H5)2NH

Solution:
Correct Option is : (D)
C6H5NH2< C6H5NHCH3< C2H5NH2< (C2H5)2NH

Topic: Chemistry, Amines, NEET
Arrange the following in decreasing order of their acidic strength : CH3CH2OH, CH3COOH, ClCH2COOH, FCH2COOH, C6H5CH2COOH.

Options:
A FCH2COOH > ClCH2COOH > C6H5CH2COOH > CH3COOH > CH3CH2OH
B CH3COOH > CH3CH2OH > FCH2COOH > ClCH2COOH > C6H5CH2COOH
C CH3CH2OH > FCH2COOH > ClCH2COOH > C6H5CH2COOH >CH3COOH
D FCH2COOH > ClCH2COOH > CH3COOH > CH3CH2OH > C6H5CH2COOH

The correct answer is:
FCH2COOH > ClCH2COOH > C6H5CH2COOH > CH3COOH > CH3CH2OH

Solution:
Correct Option is : (A)
FCH2COOH > ClCH2COOH > C6H5CH2COOH > CH3COOH > CH3CH2OH

Topic: Chemistry, Aldehydes and Ketones, NEET
Arrange the following in decreasing order of their acidic strength. Give explanation for the arrangement. C6H5COOH, FCH2COOH, NO2CH2COOH

Options:
A NO2CH2COOH > FCH2COOH > C6H5COOH due to electron withdrawing effect of the groups present.
B FCH2COOH > NO2CH2COOH > C6H5COOH due to electron withdrawing effect of the groups present.
C FCH2COOH > C6H5COOH > NO2CH2COOH due to resonance stabilization
D NO2CH2COOH > C6H5COOH > FCH2COOH due to resonance stabilization

The correct answer is:
NO2CH2COOH > FCH2COOH > C6H5COOH due to electron withdrawing effect of the groups present.

Solution:
Correct Option is : (A)
NO2CH2COOH > FCH2COOH > C6H5COOH due to electron withdrawing effect of the groups present.

Topic: Chemistry, Aldehydes and Ketones, NEET
Arrange the following in decreasing order of their basic strength: C6H5NH2,C2H5NH2, (C2H5)2NH , NH3.

Options:
A (C2H5)2NH > C2H5NH2> NH3> C6H5NH2
B (C2H5)2NH > NH3> C6H5NH2> C2H5NH2
C C2H5NH2> NH3> C6H5NH2>(C2H5)2NH
D (C2H5)2NH > C6H5NH2> C2H5NH2> NH3

The correct answer is:
(C2H5)2NH > C2H5NH2> NH3> C6H5NH2

Solution:
Correct Option is : (A)
(C2H5)2NH > C2H5NH2> NH3> C6H5NH2

Topic: Chemistry, Amines, NEET
Arrange the following in decreasing order of their number.

(i) Number of phalanges in each hand is 14

(ii) Total number of wrist bones in a human is 16

(iii) Total number of metacarpals in human body is10

(iv) Number of bones in each upper limb is 30

Options:
A iv > i > ii > iii
B iv > ii > iii > i
C iv > ii > i > iii
D ii > i > iv > iii

The correct answer is:
iv > ii > i > iii

Solution:
Number of phalanges in each hand is 14. These are bones of digits. All digits have 3 phalanges except thumb that has only two phalanges.
Wrist bones are carpals. Total carpals in human is 8×2=16
Metacarpals are bones of palm, Total metacarpals is 5×2 = 10
Number of bones in each limb =30
Thus the answer is C.

Topic: Biology, Locomotion and Movement, NEET
Arrange the following in descending order of their percentage of the total cost of various ecosystem services

Options:
A Soil formation > nutrient cycling > climate regulation
B Soil formation > climate regulation > nutrient cycling
C Climate regulation > nutrient cycling > soil formation
D Climate regulation > soil formation > nutrient cycling

The correct answer is:
Soil formation > nutrient cycling > climate regulation

Solution:
Out of the total cost of various ecosystem services, the soil formation accounts for about 50%, nutrient cycling for less than 10% and the cost of climate regulation is about 6%.

Topic: Biology, Ecosystem, NEET
Arrange the following in descending order of their size.

Options:
A DNAâ tRNAâmRNAâ rRNA
B DNA â mRNA â rRNA â tRNA
C DNA â rRNA â mRNA â tRNA
D DNA â rRNA â tRNA â mRNA

The correct answer is:
DNA â mRNA â rRNA â tRNA

Solution:
DNA or deoxyribonucleic acid is the long chain polynucleotide which forms the hereditary material in all organisms. It is a double-stranded helical structure having the length of approx. 2.2m.
Single-stranded RNA molecule transcribed from the template strand of DNA is the mRNA or messenger RNA. This RNA formed in nucleus moves to cytoplasm where it is translated to make proteins. It is the larger in size as compared to rRNA and tRNA.
The RNA which in combination with proteins forms ribosomes is the rRNA. It forms 80% of the RNA of the cell. It is smaller than mRNA but larger than tRNA.
The RNA which carries amino acids from cytoplasm and transfer it to the growing peptide chain is called tRNA. It is the smallest RNA.

Topic: Biology, Molecular Basis of Inheritance, NEET
Arrange the following in increasing order of basic strength: Aniline, p-nitroaniline and p-toluidine

Options:
A p-nitroaniline < aniline < p-toluidine
B aniline < p-toluidine < p-nitroaniline
C p-toluidine < aniline < p-nitroaniline
D aniline < p-nitroaniline < p-toluidine

The correct answer is:
p-nitroaniline < aniline < p-toluidine

Solution:
Correct Option is : (A)
p-nitroaniline < aniline < p-toluidine

Topic: Chemistry, Amines, NEET
Arrange the following in increasing order of basic strength: C6H5NH2, C6H5N(CH3)2, (C2H5)2NH and CH3NH2

Options:
A C6H5N(CH3)2< CH3NH2< (C2H5)2NH < C6H5NH2
B C6H5NH2< C6H5N(CH3)2< CH3NH2< (C2H5)2NH
C C6H5N(CH3)2< CH3NH2< C6H5NH2< (C2H5)2NH
D CH3NH2< (C2H5)2NH < C6H5NH2< C6H5N(CH3)2

The correct answer is:
C6H5NH2< C6H5N(CH3)2< CH3NH2< (C2H5)2NH

Solution:
Correct Option is : (B)
C6H5NH2< C6H5N(CH3)2< CH3NH2< (C2H5)2NH

Topic: Chemistry, Amines, NEET
Arrange the following in increasing order of basic strength: C6H5NH2, C6H5NHCH3, C6H5CH2NH2

Options:
A C6H5NHCH3< C6H5NH2< C6H5CH2NH2
B C6H5CH2NH2< C6H5NH2< C6H5NHCH3
C C6H5CH2NH2< C6H5NHCH3< C6H5NH2
D C6H5NH2< C6H5NHCH3< C6H5CH2NH2

The correct answer is:
C6H5NH2< C6H5NHCH3< C6H5CH2NH2

Solution:
Correct Option is : (D)
C6H5NH2< C6H5NHCH3< C6H5CH2NH2

Topic: Chemistry, Amines, NEET
Arrange the following in increasing order of boiling point: C2H5OH, (CH3)2NH, C2H5NH2

Options:
A C2H5OH < (CH3)2NH < C2H5NH2
B C2H5NH2< (CH3)2NH < C2H5OH
C (CH3)2NH < C2H5NH2< C2H5OH
D (CH3)2NH < C2H5OH < C2H5NH2

The correct answer is:
(CH3)2NH < C2H5NH2< C2H5OH

Solution:
Correct Option is : (C)
(CH3)2NH < C2H5NH2< C2H5OH

Topic: Chemistry, Amines, NEET
Arrange the following in increasing order of pH. KNO3(aq), CH3COONa (aq), NH4Cl (aq), C6H5COONH4(aq)

Options:
A KNO3< NH4Cl < C6H5COONH4< CH3COONa
B NH4Cl < KNO3< C6H5COONH4< CH3COONa
C NH4Cl < C6H5COONH4< CH3COONa < KNO3
D NH4Cl < C6H5COONH4< KNO3< CH3COONa

The correct answer is:
NH4Cl < C6H5COONH4< KNO3< CH3COONa

Solution:
Correct Option is : (D)
NH4Cl < C6H5COONH4< KNO3< CH3COONa

Topic: Chemistry, Ionic Equilibrium, NEET
Arrange the following in increasing order of solubility in water: C6H5NH2, (C2H5)2NH, C2H5NH2

Options:
A (C2H5)2NH < C6H5NH2< C2H5NH2
B C6H5NH2< C2H5NH2< (C2H5)2NH
C C2H5NH2< C6H5NH2< (C2H5)2NH
D C6H5NH2< (C2H5)2NH < C2H5NH2

The correct answer is:
C6H5NH2< (C2H5)2NH < C2H5NH2

Solution:
Correct Option is : (D)
C6H5NH2< (C2H5)2NH < C2H5NH2

Topic: Chemistry, Amines, NEET
Arrange the following in increasing order of stability:
(A) \(\left(\mathrm{CH}_3\right)_2 \stackrel{\oplus}{\mathrm{C}}-\mathrm{CH}_2 \mathrm{CH}_3\)
(B) \(\left(\mathrm{CH}_3\right)_3-\stackrel{\oplus}{\mathrm{C}}\)
(C) \(\left(\mathrm{CH}_3\right)_2-\stackrel{\oplus}{\mathrm{C}} \mathrm{H}\)
(D) \(\mathrm{CH}_3-\stackrel{\oplus}{\mathrm{C}} \mathrm{H}_2\)
(E) \(\stackrel{\oplus}{\mathrm{C}} \mathrm{H}_3\)

Options:
A A < E < D < C < B
B E < D < C < B < A
C D < E < C < A < B
D E < D < C < A < B

The correct answer is:
A < E < D < C < B

Solution:
The stability of carbocations increase if the number of EDG (alkyl group) is more

Topic: Chemistry, General Organic Chemistry, NEET, NEET 2013 (Karnataka)
Arrange the following in increasing order of their basic strength: C2H5NH2, (C2H5)2NH, (C2H5)3N, C6H5NH2

Options:
A C6H5NH2< (C2H5)2NH < C2H5NH2< (C2H5)3N
B C2H5NH2< (C2H5)3N < (C2H5)2NH < C6H5NH2
C C6H5NH2< C2H5NH2< (C2H5)3N < (C2H5)2NH
D C6H5NH2< (C2H5)3N < C2H5NH2< (C2H5)2NH

The correct answer is:
C6H5NH2< C2H5NH2< (C2H5)3N < (C2H5)2NH

Solution:
Correct Option is : (C)
C6H5NH2< C2H5NH2< (C2H5)3N < (C2H5)2NH

Topic: Chemistry, Amines, NEET
Arrange the following in increasing order of their basic strength: C2H5NH2, C6H5NH2, NH3, C6H5CH2NH2and (C2H5)2NH

Options:
A C2H5NH2< C6H5NH2< NH3< C6H5CH2NH2< (C2H5)2NH
B C6H5CH2NH2< C2H5NH2< (C2H5)2NH < C6H5NH2< NH3
C C6H5NH2< C2H5NH2< (C2H5)2NH 3< C6H5CH2NH2
D C6H5NH2< NH3< C6H5CH2NH2< C2H5NH2< (C2H5)2NH

The correct answer is:
C6H5NH2< NH3< C6H5CH2NH2< C2H5NH2< (C2H5)2NH

Solution:
Correct Option is : (D)
C6H5NH2< NH3< C6H5CH2NH2< C2H5NH2< (C2H5)2NH

Topic: Chemistry, Amines, NEET
Arrange the following in increasing order of their basic strength: CH3NH2, (CH3)2NH, (CH3)3N, C6H5NH2, C6H5CH2NH2

Options:
A C6H5NH2< CH3NH2< (CH3)2NH < C6H5CH2NH2< (CH3)3N
B (CH3)3N < CH3NH2< (CH3)2NH < C6H5NH2< C6H5CH2NH2
C C6H5NH2< C6H5CH2NH2< CH3NH2< (CH3)2NH < (CH3)3N
D C6H5NH2< C6H5CH2NH2< (CH3)3N < CH3NH2< (CH3)2NH

The correct answer is:
C6H5NH2< C6H5CH2NH2< (CH3)3N < CH3NH2< (CH3)2NH

Solution:
Correct Option is : (D)
C6H5NH2< C6H5CH2NH2< (CH3)3N < CH3NH2< (CH3)2NH

Topic: Chemistry, Amines, NEET
Arrange the following in increasing order of their intermolecular forces:
Nylon -6,6 (I), Buna –S (II), Polythene (III)

Options:
A I, II, III
B II, III, I
C II, I, III
D III, II, I

The correct answer is:
II, III, I

Solution:
Nylon- 6, 6 are fibres and these are polymers which have strong intermolecular forces such as hydrogen bonding. Buna- S is an elastomer and has weak intermolecular forces. Polyethylene are thermoplastics in which intermolecular forces of attraction are neither very strong nor very weak. Based on it the correct order is I > III > II.

Topic: Chemistry, Polymers, NEET
Arrange the following in order of decreasing number of unpaired electrons:
I: FeH2O62+
II: FeCN63–
III: FeCN64–
IV: FeH2O63+

Options:
A IV,I,II,III
B I,II,III,IV
C III,II,I,IV
D II,III,I,IV

The correct answer is:
IV,I,II,III

Solution:
FeH2O62+âno of unpaired eââ4,FeH2O63+-no of unpaired eââ5FeCN63ââno of unpaired eââ1FeCN64ââno of unpaired eââ0

Topic: Chemistry, Coordination Compounds, NEET
Arrange the following in order of increasing reactivity towards nucleophilic substitution reaction-

Options:
A 1<2<3
B 3<1<2
C 1<3<2
D 2<1<3

The correct answer is:
3<1<2

Solution:
Reactivity order of acid derivatives is directly proportional to leaving group ability of group. It is in the order -Cl>-OR>-NHR

Topic: Chemistry, Carboxylic Acid Derivatives, NEET
Arrange the following in the chronological order of their appearance i.e. from oldest to latest:

Options:
A Ramapithecus â Homo habilis â Java ape man â Australopithecus â Neanderthal man
B Ramapithecus â Australopithecus â Homo habilis â Java ape man â Neanderthal man
C Ramapithecus â Java ape man â Australopithecus â Neanderthal man â Homo habilis
D Ramapithecus â Java ape man â Australopithecus â Homo habilis â Neanderthal man

The correct answer is:
Ramapithecus â Australopithecus â Homo habilis â Java ape man â Neanderthal man

Solution:
About 15 mya , primates called Dryopithecus and Ramapithecus were existing. They were hairy and walked like gorillas and chimpanzees. Australopithecines probably lived in East African grasslands about 2 mya . Evidence shows they hunted with stone weapons but essentially ate fruit. The first human-like being the hominid was called Homo habilis. The brain capacities were between 650-800cc . They probably did not eat meat. Fossils discovered in Java in 1891 revealed the next stage, i.e., Homo erectus (Java Man) who lived about 1.5 mya . The Neanderthal man with a brain size of 1400cc lived in near east and central Asia between 1,00,000-40,000 years back.

Topic: Biology, Evolution, NEET
Arrange the following in the correct order of Lewis acidity: BF3, BCl3, BBr3.

Options:
A BF3 > BBr3 > BCl3
B BF3 > BCl3 > BBr3
C BF3 < BCl3 < BBr3
D BBr3 < BF3 < BCl3

The correct answer is:
BF3 < BCl3 < BBr3

Solution:
In BF3, BCl3 and BBr3 each will shown p Ï - p Ï back bonding as follows.
Extant of overlapping as the 2pâ2p>2pâ3p>2pâ4p difference between the size of p orbital increases the extent of overlapping decreases the availability of vacant orbital increases and the acidic character increases.
Hence correct order of Lewis acidity represented by option (BF3 < BCl3 < BBr3) .

Topic: Chemistry, Chemical Bonding and Molecular Structure, NEET
Arrange the following in the order of property indicated for each set (i) F2, Cl2, Br2, I2- increasing bond dissociation enthalpy. (ii) HF, HCl, HBr, HI - increasing acid strength. (iii) NH3, PH3, AsH3, SbH3, BiH3– increasing base strength.

Options:
A i) F2< Cl2< Br2< I2ii) HF < HCl < HBr < HI iii) NH3< PH3< AsH3< SbH3< BiH3
B i) I2< Br2< Cl2< F2ii) HI < HBr < HCl < HF iii) NH3< PH3< AsH3< SbH3< BiH3
C i) F2< Cl2< Br2< I2ii) HF < HCl < HBr < HI iii) BiH3< SbH3< AsH3< PH3< NH3
D i) I2< Br2< Cl2< F2ii) HI < HBr < HCl < HF iii) BiH3< SbH3< AsH3< PH3< NH3

The correct answer is:
i) F2< Cl2< Br2< I2ii) HF < HCl < HBr < HI iii) NH3< PH3< AsH3< SbH3< BiH3

Solution:
Correct Option is : (A)
i) F2< Cl2< Br2< I2ii) HF < HCl < HBr < HI iii) NH3< PH3< AsH3< SbH3< BiH3

Topic: Chemistry, p Block Elements (Group 13 & 14), NEET
Arrange the following in the order of their location from the periphery to center in the dicotyledons body

I. Endodermis
II. Metaxylem
III. Trichoblasts
IV. Phloem

Options:
A IV, I, II, III
B IV, II, III,I
C I, II, III, IV
D III, I, IV, II

The correct answer is:
III, I, IV, II

Solution:
The correct sequence of these cells is trichoblast-endodermis-phloem-metaxylem.

A trichoblast is a cell on the exterior surface of a plant's root that is responsible for forming root hairs. The endodermis is the rod-shaped cells having the deposition of water-impermeable, waxy material suberin in the form of Casparian strips. Phloem and xylem are the vascular bundles present at the center.

Topic: Biology, Anatomy of Flowering Plants, NEET
Arrange the following ions in increasing order of their ionic radii, Ce+3,La+3,Pm+3 and Yb+3.

Options:
A Ce+3<Yb+3<Pm+3<La+3
B Yb+3<Pm+3<Ce+3<La+3
C Yb+3<Pm+3<La+3<Ce+3
D Pm+3<La+3<Ce+3<Yb+3

The correct answer is:
Yb+3<Pm+3<Ce+3<La+3

Solution:
Due to Lanthanoid contraction their is greater decrease in ionic radii of elements in lanthanide series because of poor shielding of nuclear charge by 4f electrons, hence the order will be Yb+3<Pm3+<Ce+3<La3+

Topic: Chemistry, d and f Block Elements, NEET
Arrange the following layers of microsporangium according to their presence from inside to outside.

A Endothecium
B Middle layer
C Tapetum
D Epidermis

Options:
A D, A, B, C
B B,Â A,Â C,Â D
C D,Â C,Â B,Â A
D C,Â B,Â A,Â D

The correct answer is:
D, A, B, C

Solution:
The microsporangia is circular in outline and is surrounded by a four-layered wall, outermost epidermis which is protective in function. Next to it is endothecium which helps in dehiscence of sporangia. Than middle layer and the innermost tapetum which is nutritive layer and provides nutrition to developing microspore.

Topic: Biology, Sexual Reproduction in Flowering Plants, NEET
Arrange the following ligands in order of increasing field strength, from weakest to strongest.

Options:
A Cl– < CO < NCS– < F– < OH– < edta4– < S2– < I–
B I– < S2– < edta4– < OH– < F– < NCS– < CO < Cl–
C Cl– < S2– < edta4– < F– < NCS– < OH– < CO < I–
D I– < edta4– < CO < S2– < OH– < NCS– < F– < Cl–

The correct answer is:
I– < S2– < edta4– < OH– < F– < NCS– < CO < Cl–

Solution:
The correct order of increasing field strength is I– < S2– < edta4– < OH– < F– < NCS– < CO < Cl–

Topic: Chemistry, Coordination Compounds, NEET