datavorous/entrance-exam-dataset huggingface dataset:
Which one of the elements with the following outer orbital configurations may exhibit the largest number of oxidation states ?

Options:
A $3 d^3, 4 \mathrm{~s}^2$
B $3 d^5, 4 \mathrm{~s}^1$
C $3 d^5, 4 s^2$
D $3 d^2, 4 s^2$

The correct answer is:
$3 d^5, 4 s^2$

Solution:
Key Idea Number of oxidation states exhibited by d-block elements is the sum of number of electrons (unpaired) in d-orbitals and number of electrons in s-orbital.
(a) $3 \mathrm{~d}^3, 4 \mathrm{~s}^2 \Rightarrow \mathrm{O} . \mathrm{S}=3+2=5$
(b) $3 \mathrm{~d}^5, 4 \mathrm{~s}^1 \Rightarrow \mathrm{O} . \mathrm{S}=5+1=6$
(c) $3 \mathrm{~d}^5, 4 \mathrm{~s}^2 \Rightarrow \mathrm{O} . \mathrm{S}=5+2=7$
(d) $3 \mathrm{~d}^2, 4 \mathrm{~s}^2 \Rightarrow \mathrm{O} . \mathrm{S}=2+2=4$
Hence, element with $3 \mathrm{~d}^5, 4 \mathrm{~s}^2$ configuration exhibits largest number of oxidation states.

Topic: Chemistry, d and f Block Elements, NEET, NEET 2009 (Screening)
Which one of the following acids is a derivative of carotenoids?

Options:
A Indole-butyric acid
B Indole-3-acetic acid
C Gibberellic acid
D Abscisic acid

The correct answer is:
Abscisic acid

Solution:
Abscisic acid is a terpenoid, $i e$, a derivative of steroid.
Indole butyric acid and indole-3-acetic acid are auxins, which are weak organic acids. Gibberellic acid (gibberellin) is a terpene.

Topic: Biology, Plant - Growth and Development, NEET, NEET 2009 (Screening)
Which one of the following acts as a physiological barrier to the entry of microorganisms in human body?

Options:
A Tears
B Monocytes
C Skin
D Epithelium of urogenital tract

The correct answer is:
Tears

Solution:
Physiological barriers to the entry of microorganisms in human body are tears in eyes, saliva in mouth and $\mathrm{HCl}$ in stomach. The enzyme lysozyme is found in tears and saliva, and inhibits the synthesis of peptidoglycan present in the cell wall of microorganisms especially eubacteria.

Topic: Biology, Human Health and Diseases, NEET, NEET 2011 (Screening)
Which one of the following acts as an inducer for lac operon?

Options:
A Glucose
B Galactose
C Sucrose
D Lactose

The correct answer is:
Lactose

Solution:
Lactose acts as inducer of lac operon. Lactose binds with repressor protein and inactivates it allowing the expression of structural genes.

Topic: Biology, Molecular Basis of Inheritance, NEET, NEET 2023 (Manipur)
Which one of the following adaptation is associated with a ‘mangrove plant’?

Options:
A Capable of absorbing water rapidly and retaining it
B Capable of minimizing water loss and facilitating aeration to underground parts
C Capable of reducing transpiration and able to store absorbed water
D Presence of well organized leaves that are adapted to absorb nitrogenous matter

The correct answer is:
Capable of minimizing water loss and facilitating aeration to underground parts

Solution:
Mangrove plants are capable to minimize water loss and facilitate aeration to underground parts.

Topic: Biology, Organisms and Populations, NEET
Which one of the following alcoholic drink has the least proportion of ethyl alcohol in it?

Options:
A Wine
B Whisky
C Rum
D Brandy

The correct answer is:
Wine

Solution:
Distillation involves the purification of a liquid to increase the concentration of the specific components in it. Wine is an undistilled product, produced due to the traditional alcoholic fermentation of fruit juices by yeast. Thus the concentratation of alcohol is less in wine. The other three drinks are formed only after distillation as follows.
Whisky: Fermentation of grain mill (barley, corn, rye and wheat) → Distillation
Rum: Direct distillation of the byproducts of sugarcane or sugarcane juice.
Brandy: Distillation of fermented wine.

Topic: Biology, Microbes in Human Welfare, NEET
Which one of the following alcoholic drinks is produced without distillation?

Options:
A Wine
B Whisky
C Rum
D Brandy

The correct answer is:
Wine

Solution:
Wine and beer are produced, without distillation. Whisky, brandy and rum are produced by distillation.

Topic: Biology, Microbes in Human Welfare, NEET
Which one of the following alcohols reacts instantaneously with Lucas reagent?

Options:
A

B

C

D

The correct answer is:

Solution:
Tertiary alcohols react instantaneously with Lucas reagent and gives immediate turbidity. In case of tertiary alcohols, they form halides easily with Lucas reagent (conc. HCl and $\mathrm{ZnCl}_2$ )

Topic: Chemistry, Alcohols Phenols and Ethers, NEET, NEET 2024
Which one of the following alkali metals gives hydrated salts?

Options:
A Li
B Na
C K
D Cs

The correct answer is:
Li

Solution:
Correct Option is : (A)
Li

Topic: Chemistry, s Block Elements, NEET
Which one of the following alkenes is the most stable?

Options:
A CH2=CH2
B CH3-CH=CH2
C CH3-CH=CH-CH3
D

The correct answer is:

Solution:
Stability of alkene ∝ extent of hyperconjugation ∝ number of α -H-atoms

Topic: Chemistry, General Organic Chemistry, NEET
Which one of the following alkenes will react faster with $\mathrm{H}_2$ under catalytic hydrogenation conditions?

Options:
A

B

C

D

The correct answer is:

Solution:
Due to steric hinderence, hyperconjugation and heat of hydrogenation, reactivity of alkenes can be shown as:
$$
\begin{aligned}
& \mathrm{H}_2 \mathrm{C}=\mathrm{CH}_2>\mathrm{R}-\mathrm{CH}=\mathrm{CH}_2> \\
& \mathrm{R}-\mathrm{CH}=\mathrm{CH}-\mathrm{R}>\mathrm{R}_2 \mathrm{C}=\mathrm{CH}_2> \\
& \mathrm{R}_2 \mathrm{C}=\mathrm{CHR}>\mathrm{R}_2 \mathrm{C}=\mathrm{CR}_2 .
\end{aligned}
$$
Related Theory
The relative rates of hydrogenation decrease with the increase of steric hindrance. In order of stability of alkene, most stable the alkene slowly it gives the product.

Topic: Chemistry, Hydrocarbons, NEET, NEET 2005
Which one of the following alkenes will react faster with H2 under catalytic hydrogenation conditions?

Options:
A
B
C
D
(R = alkyl substituent)

The correct answer is:

Solution:
The relative rates of hydrogenation decrease with the increase of steric hindrance. In order of stability of alkene, most stable the alkene slowly it gives the product.
Hence alkene which will react faster with H2 is that which is most unstable.

Topic: Chemistry, Hydrocarbons, NEET
Which one of the following alkenes will react fastest with H2 under catalytic hydrogenation condition?

Options:
A
B
C
D

The correct answer is:

Solution:
Ease of catalytic hydrogenation depends upon the size of groups present at the doubly bonded carbon. Larger the size of groups, difficult the hydrogenation. Therefore, in the given situation disubstituted reacts at faster rate than tri and tetra substituted alkenes. Among disubstituted, the stability order is:
cis < geminal < trans.

Topic: Chemistry, Hydrocarbons, NEET
Which one of the following also acts as a catalyst in a bacterial cell?

Options:
A sn RNA
B hn RNA
C 23 S rRNA
D 5 S rRNA

The correct answer is:
23 S rRNA

Solution:
23 S RNA in bacteria is the enzyme ribozyme for the formation of peptide bond. $23 \mathrm{~S} r$ RNA is found large sub-unit $(70 \mathrm{~S})$ of ribosome of bacteria.

Topic: Biology, Biotechnology - Principles and Processes, NEET, NEET 2011 (Screening)
Which one of the following also acts as a catalyst in a bacterial cell?

Options:
A 5S rRNA
B 28S rRNA
C hnRNA
D 23s rRNA

The correct answer is:
23s rRNA

Solution:
There are two sites in the large subunit, for subsequent amino acids to bind to and thus, be close enough to each other for the formation of a peptide bond. The ribosome also acts as a catalyst (23S rRNA in bacteria and 28S rRNA in an eukaryotic cell is the enzyme- ribozyme) for the formation of peptide bond.

Topic: Biology, Molecular Basis of Inheritance, NEET
Which one of the following animals has two separate circulatory pathways?

Options:
A Lizard
B Whale
C Shark
D Frog

The correct answer is:
Whale

Solution:
In the aves and mammals, double blood circulation is found. Whale is a mammal.

DOUBLE CIRCULATION:
The movement of blood follows double circulation (systemic and pulmonary circulation) and circulation through special regions.
(i) Systemic Circulation: It involves the flow of oxygenated blood from the left ventricle to all parts of the body and deoxygenated blood from various body parts to the right atrium. It is also called systemic circulation.
(ii) Pulmonary Circulation: The flow of deoxygenated blood from the right ventricle to the lungs and the return of oxygenated blood from the lungs to the left atrium is called the pulmonary circulation.

Topic: Biology, Body Fluids and Circulation, NEET, NEET 2015 (Phase 2)
Which one of the following animals is correctly matched with its one characteristic and the taxon?

Options:
A Animal-Millipede; Characteristic-Ventral nerve cord; Taxon-Arachnida
B Animal-Sea Anemone; Characteristic-Triploblastic; Taxon-Cnidaria
C Animal-Silverfish; Characteristic-Pectoral and pelvic fins; Taxon-Chordata
D Animal-Duckbilled platypus; Characteristic-Oviparous; Taxon-Mammalia

The correct answer is:
Animal-Duckbilled platypus; Characteristic-Oviparous; Taxon-Mammalia

Solution:
(D) Duckbilled platypus is a mammal, which is a oviparous. Millipede belongs to class Diplopoda. Sea anemone are diploblastic. Silverfish is an insect (non-chordata), not fish (chordate)
Caution
Mammals are usually viviparous, but Duckbilled platypus is an oviparous.

Topic: Biology, Animal Kingdom, NEET, NEET 2013 (Karnataka)
Which one of the following aqueous solutions will exhibit highest elivation in boiling point?

Options:
A 0.05 M glucose (non ionisable)
B 0.01 M KNO3 (50 % ionisable)
C 0.015 M Urea (non ionisable)
D 0.01 M Na2SO4 (75 % ionisable)

The correct answer is:
0.05 M glucose (non ionisable)

Solution:
Boiling point
=T0solvent+ÎTbelevation in b.p.
ÎTb=miKb
where, m is the molality âmolarity
If n is number of species formed after dissociation
i, the vant Hoff factor =1+n-1Î±
Kb= molal elevation constant.
Thus ÎTbâi
Assume 100% ionization
1m i Na2SO4=0.011+3-10.75=0.025
2m i KNO3=0.01Ã1+2-10.50=0.015
3m i urea=0.015
4m i glucose=0.05

Topic: Chemistry, Solutions, NEET
Which one of the following are analogous structures?

Options:
A Wings of Bat and Wings of Pigeon
B Gills of Prawn and Lungs of Man
C Thorns of Bougainvillea and Tendrils of Cucurbita
D Flippers of Dolphin and legs of Horse.

The correct answer is:
Gills of Prawn and Lungs of Man

Solution:
Analogous structures are those organs which are structurally different, but they perform the same set of functions. Of the given pairs of structures, the gills of prawns and lungs of man are analogous in nature. Both of these are respiratory structures, which are anatomically different from each others. The lungs of man are balloon-like sac organs which inflate and deflate on breathing, while gills of prawn are crescent-shaped organs which perform gas exchange for respiration.

Wings of bat and wings of pigeon have anatomically similar structures as well as they perform the same function of flying. Hence, it is difficult to strictly mark them as analogous or homologous.

The other two examples exhibit homology. That is, they are structurally the same, but they perform different functions.

Topic: Biology, Evolution, NEET, NEET 2014
Which one of the following areas in India, is a hot spot of biodiversity?

Options:
A Eastern Ghats
B Gangetic plain
C Sunderbans
D Western Ghats

The correct answer is:
Western Ghats

Solution:
Hot spots are areas that are extremely rich in species diversity, have high endemism and are under constant threat. In India, two hot spots are found extending into neighbouring countries. The Western Ghats/Sri Lanka and the Indo-Burman region (covering the Eastern Himalayas also known as cradle of speciation).

Topic: Biology, Biodiversity and its Conservation, NEET, NEET 2012 (Screening)
Which one of the following arrangement of molecules is correct on the basis of their dipole moments?

Options:
A BF3>NH3>NF3
B BF3>NF3>NH3
C NH3>BF3>NF3
D NH3>NF3>BF3

The correct answer is:
NH3>NF3>BF3

Solution:
Both NF3 and NH3 have identical shape (pyramidal) and a lone pair of electron on nitrogen. Dipole moment of NH3 is higher than NF3 molecule as the orbital moment due to lone pair of electrons and the resultant dipole moment of 3 N-F bonds point in the opposite directions to that of lone pair of electrons.
BF3 is a symmetrical molecule. It has zero dipole moment.

Topic: Chemistry, Chemical Bonding and Molecular Structure, NEET
Which one of the following arrangements does not give the correct picture of the trends indicated against it?

Options:
A $\mathrm{F}_2>\mathrm{Cl}_2>\mathrm{Br}_2>\mathrm{I}_2$ : Oxidising power
B $\mathrm{F}_2>\mathrm{Cl}_2>\mathrm{Br}_2>\mathrm{I}_2$ : Electron
gain enthalpy
C $\mathrm{F}_2>\mathrm{Cl}_2>\mathrm{Br}_2>\mathrm{I}_2$ : Bond dissociation energy
D $\mathrm{F}_2>\mathrm{Cl}_2>\mathrm{Br}_2>\mathrm{I}_2$ : Electronegativity

The correct answer is:
$\mathrm{F}_2>\mathrm{Cl}_2>\mathrm{Br}_2>\mathrm{I}_2$ : Bond dissociation energy

Solution:
Key Idea : Generally bond dissaciation energies decreases in a group. Bond dissaciation energy also decreases with repulsion.
$\begin{array}{|l|c|c|c|c|}\hline X-X \text { Bond } & \mathrm{F}-\mathrm{F} & \mathrm{Cl}-\mathrm{Cl} & \mathrm{Br}-\mathrm{Br} & \mathrm{I}-\mathrm{I} \\
\hline \text {Bond length }(Å)) & 1.42 & 1.99 & 2.28 & 2.67 \\
\hline \begin{array}{l}\text {Bond dissociation } \\
\text {energy }(\mathrm{kcal} / \mathrm{mol})\end{array} & 38 & 57 & 45.5 & 35.6 \\ \hline \end{array}$
In general the bond dissociation energy decreases as the bond length increases, but the bond dissociation energy of $\mathrm{F}_2$ is less than that of $\mathrm{Cl}_2$. It is due to greater interelectronic repulsions between the lone pair of electrons on the two bonded fluorine atoms. Hence, the order of bond dissociation energy is as :
$\mathrm{Cl}_2>\mathrm{Br}_2>\mathrm{F}_2>\mathrm{I}_2$

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), NEET, NEET 2008 (Screening)
Which one of the following arrangements represents the correct order of electron gain enthalpy (with negative sign) of the given atomic species?

Options:
A S $ < $ O $ < $ Cl $ < $ F
B $\mathrm{Cl} < $ F $ < $ S $ < $ O
C F $ < $ Cl $ < \mathrm{O} < \mathrm{S}$
D $\mathrm{O} < \mathrm{S} < \mathrm{F} < \mathrm{Cl}$

The correct answer is:
$\mathrm{O} < \mathrm{S} < \mathrm{F} < \mathrm{Cl}$

Solution:
The electron gain enthalpy of elements increases along a period towards right and decreases down the group. However, the $\mathrm{EA}$ of $\mathrm{Cl}$ is higher than that of $F$ and EA of $S$ is higher than that of $\mathrm{O}$ as $\mathrm{F}$ and $\mathrm{O}$ are very small in size. Thus, the correct order of EA is:
$$
\mathrm{O} < \mathrm{S} < \mathrm{F} < \mathrm{Cl}
$$
Caution
Oxygen molecule has a less negative electron gain enthalpy than sulphur. This is on the grounds that Oxygen, because of its compressed nature encounter more repulsion between the electrons effectively present and the approaching electron.

Topic: Chemistry, Classification of Elements and Periodicity in Properties, NEET, NEET 2005
Which one of the following arrangements represents the correct order of least negative to most negative electron gain enthalpy for $\mathrm{C}, \mathrm{Ca}, \mathrm{Al}, \mathrm{F}$ and $\mathrm{O}$ ?

Options:
A Al $ < \mathrm{Ca} < \mathrm{O} < $ C $ < $ F
B $\mathrm{Al} < \mathrm{O} < \mathrm{C} < \mathrm{Ca} < \mathrm{F}$
C C $ < $ F $ < $ O $ < $ Al $ < \mathrm{Ca}$
D $\mathrm{Ca} < \mathrm{Al} < \mathrm{C} < \mathrm{O} < \mathrm{F}$

The correct answer is:
$\mathrm{Ca} < \mathrm{Al} < \mathrm{C} < \mathrm{O} < \mathrm{F}$

Solution:
Down the group the electron gain enthalpy becomes less negative, while it becomes more negative along the period.

Topic: Chemistry, Classification of Elements and Periodicity in Properties, NEET, NEET 2013 (Karnataka)
Which one of the following arrangements represents the correct order of least negative to most negative electron gain enthalpy for C, Ca, Al, F and O?

Options:
A Al < Ca < O < C < F
B Al < O < C < Ca < F
C C < F < O Al < Ca
D Ca < Al < C < O < F

The correct answer is:
Ca < Al < C < O < F

Solution:
Electron gain enthalpy becomes less negative from top to bottom in a group while it becomes more negative from left to right within a period.
Ca < Al < C < O < F

Topic: Chemistry, Classification of Elements and Periodicity in Properties, NEET
Which one of the following bacteria has found extensive use in genetic engineering work in plants?

Options:
A Clostridium septicum
B Xanthomonas citri
C Bacillus coagulens
D Agrobacterium tumefaciens

The correct answer is:
Agrobacterium tumefaciens

Solution:
For GM plants, the bacterium most frequently used is called Agrobacterium tumefaciens. The gene of interest is transferred into the bacterium and the bacterial cells then transfer the new DNA to the genome of the plant cells. The plant cells that have successfully taken up the DNA are then grown to create a new plant.
Related Theory
coli $\lambda$ bacteriophage is one of the most widely used vectors used to carry recombinant DNA into bacterial cells.

Topic: Biology, Biotechnology and Its Applications, NEET, NEET 2003
Which one of the following base in not present in DNA?

Options:
A adenine
B cytosine
C uracil
D thymine

The correct answer is:
uracil

Solution:
DNA contains four bases viz adenine (A), guanine (G), cytosine (C) and thymine (T). RNA also contains four bases, first three bases are same as in DNA but the fourth one is uracil (U).

Topic: Chemistry, Biomolecules, NEET
Which one of the following belongs to the family Muscidae?

Options:
A Fire fly
B Grasshopper
C Cockroach
D House fly

The correct answer is:
House fly

Solution:
Muscidae constitutes a family of flies found in the superfamily Muscoidea. Muscidae, some of which are commonly known as houseflies or stable flies. Both male and female flies feed on all kinds of human food, rubbish, and excreta, including sweat, and on animal dung. They are known to be a carrier of various diseases and hence they can be considered pests for humans.

Topic: Biology, The Living World, NEET, NEET 2021
Which one of the following belongs to the same class?

Options:
A Mucor, Alternaria and Yeast
B Morchella, Truffles and Saccharomyces
C Agaricus, Rhizopus and Aspergillus
D Rhizopus, Colletotrichum and Yeast

The correct answer is:
Morchella, Truffles and Saccharomyces

Solution:
Rhizopus and Mucor are members of Phycomycetes. Aspergillus, Saccharomyces (Yeast), Morchella (Morels) and Truffles are Ascomycetes fungi. Agaricus (Mushroom) is basidiomycetes fungi. Morchella commonly called as morels and also the truffles are edible ascomycetes fungi and Agaricus is edible basidiomycetes fungi. Colletotrichum and Alternaria are Deutromycetes.

Topic: Biology, Biological Classification, NEET
Which one of the following blood cells are involved in antibody production?

Options:
A B-Lymphocytes
B T-Lymphocytes
C RBC
D Neutrophils

The correct answer is:
B-Lymphocytes

Solution:
B-Lymphocytes are involved in antibody production.

Topic: Biology, Body Fluids and Circulation, NEET
Which one of the following bonds produces a solid that reflects light in the visible region and whose electrical conductivity decreases with temperature and has high melting point ?

Options:
A metallic bonding
B van der Waals' bonding
C ionic bonding
D covalent bonding

The correct answer is:
metallic bonding

Solution:
Metallic bonding is formed due to attraction of valence (free) electrons with the positive ion cores. Their conductivity decreases with rise of temperature. When visible light falls on a metallic crystal, the electrons of atom absorb visible light, so they are opaque to visible light. However, some orbital electrons absorb energy and reach to excited state. They then return to their normal state, remitting light of same frequency.

Topic: Chemistry, Chemical Bonding and Molecular Structure, NEET, NEET 2010 (Screening)
Which one of the following can be explained on the basis of Mendel's Law of Dominance?
A. Out of one pair of factors one is dominant and the other is recessive.
B. Alleles do not show any expression and both the characters appear as such in $F_2$ generation.
C. Factors occur in pairs in normal diploid plants.
D. The discrete unit controlling a particular character is called factor.
E. The expression of only one of the parental characters is found in a monohybrid cross.
Choose the correct answer from the options given below:

Options:
A A, C, D and E only
B B, C and D only
C $\mathrm{A}, \mathrm{B}, \mathrm{C}, \mathrm{D}$ and E
D A, B and C only

The correct answer is:
A, C, D and E only

Solution:
According to Law of Dominance
(1) Characters are controlled by discrete units called factors
(2) Factors occur in pairs
(3) In a dissimilar pair of factors one member of the pair dominates (dominant) the other recessive
The law of dominance is used to explain the expression of only one of the parental characters in a monohybrid cross.
Law of segregation is based on the fact that the alleles do not show any expression and both the characters are recovered as such in $\mathrm{F}_2$ generation

Topic: Biology, Principles of Inheritance and Variation, NEET, NEET 2024
Which one of the following can help in the diagnosis of genetical basis of a disorder?

Options:
A ELISA
B Blood
C PCR
D Nuclear magnetic resonance

The correct answer is:
PCR

Solution:
PCR (polymerase chain reaction) is a method for amplifying a specific region of DNA molecule and thus, it can help in the diagnosis of a genetical basis of the disorder. ELISA is based on Ag–Ab interaction; hence, it can be used to diagnose diseases like AIDS.

Topic: Biology, Biotechnology and Its Applications, NEET
Which one of the following can show optical isomerism?

Options:
A FeSO4.7H2O
B K3[Cr(C2O4)3]
C K3[Fe(CN)6]
D Cr[(NH3)6]Cl3

The correct answer is:
K3[Cr(C2O4)3]

Solution:
The anion of the compound B is [Cr(C2O4)3]3- or [Cr(Ox)3]3- , where Ox≡C2O42- . Since such octahedral complexes have non-super-imposable mirror images, so they show optical isomerism.

Topic: Chemistry, Coordination Compounds, NEET
Which one of the following can utilize molecular nitrogen (N2) as a nutrient for growth?

Options:
A Rhizobium
B Spirogyra
C Mucor
D Methanococcus

The correct answer is:
Rhizobium

Solution:
N2 is unavailable for use by most organisms because there is a triple bond between the two nitrogen atoms, making the molecule almost inert. In order to use the nitrogen for growth, it must be "fixed" (combined) in the form of ammonium ions or nitrate ions. Some bacteria can fix atmospheric N2 like Rhizobium, Azotobacter, etc.

Topic: Biology, Microbes in Human Welfare, NEET
Which one of the following cannot be explained by the law of dominance?

Options:
A The discrete unit controlling a particular character is called as factor
B In a pair of factors, one unit factor is dominant, while other is recessive
C Alleles do not show any blending and both the characters recover as such in F2 generation
D Factors occur in pairs

The correct answer is:
Alleles do not show any blending and both the characters recover as such in F2 generation

Solution:
According to Mendel's law of dominance, out of two contrasting allelomorphic factors, only one expresses itself in an individual. The factor that expresses itself is called dominant while the other which has not shown its effect only in the homozygous individual is termed as recessive. The option alleles do not show any blending and both the characters recover as such in F2 generation in the given question cannot be explained on the basis of the law of dominance. It can only be explained on the basis of Mendel's law of purity of gametes.

Topic: Biology, Principles of Inheritance and Variation, NEET