datavorous/entrance-exam-dataset huggingface dataset:
The Cockroach is :

Options:
A Ureotelic only
B Ureotelic and Uricotelic
C Ammonotelic only
D Uricotelic only

The correct answer is:
Uricotelic only

Solution:
Option (4) is the correct answer because in cockroach excretion is performed by Malpighian tubules. Each tubule is lined by glandular and ciliated cells. They absorb nitrogenous waste products and convert them into uric acid which is excreted out through the hindgut. Therefore, they are called uricotelic.
- Many bony fishes, aquatic amphibians and aquatic insects are ammonotelic in nature.
- Mammals, many terrestrial amphibians and marine fishes are ureotelic in nature.

Topic: Biology, Structural Organisation in Animals, NEET, NEET 2023 (Manipur)
The coconut water and the edible part of coconut are equivalent to

Options:
A endosperm
B endocarp
C mesocarp
D embryo

The correct answer is:
endosperm

Solution:
The coconut water obtained from the tender coconut is nothing but free nuclear endosperm (made up of thousands of nuclei) and the surrounding white kernel is the cellular endosperm.

Topic: Biology, Sexual Reproduction in Flowering Plants, NEET, NEET 2012 (Screening)
The coconut water from tender coconut represents:

Options:
A Endocarp
B Cellular endosperm
C Free nuclear proembryo
D Free nuclear endosperm

The correct answer is:
Free nuclear endosperm

Solution:
The coconut water from tender coconut is free-nuclear endosperm (made up of thousands of nuclei) and the surrounding white kernel is the cellular endosperm.

Topic: Biology, Morphology of Flowering Plants, NEET, NEET 2016 (Phase 1)
The coconut water from tender coconut represents:

Options:
A Endocarp
B Cellular endosperm
C Free nuclear proembryo
D Free nuclear endosperm

The correct answer is:
Free nuclear endosperm

Solution:
The coconut water from tender coconut is free-nuclear endosperm (made up of thousands of nuclei) and the surrounding white kernel is the cellular endosperm.

Topic: Biology, Sexual Reproduction in Flowering Plants, NEET
The coefficiency of apparent expansion of a liquid when determined using two different vessels A and B are Î³1 and Î³2, respectively. If the coefficient of linear expansion of the vessel A is Î±, the coefficient of linear expansion of vassel B is

Options:
A αγ1 γ2γ1+γ2
B γ1-γ22α
C γ1-γ2+α3α
D γ1-γ23+α

The correct answer is:
γ1-γ23+α

Solution:
Using γr=γa+ g, we get
γr = γ1+3α= γ2+3β
∴ β= γ1-γ23+ α

Topic: Physics, Thermal Properties of Matter, NEET
The coefficient of apparent expansion of mercury in a glass vessel is 153Ã10â6 Â°C-1 and in a steel vessel is 144Ã10â6 Â°C-1, If linear expansion coefficient ( Î± ) for steel is 12Ã10â6 Â°C-1, then that of glass is

Options:
A 9Ã10â6 Â°C-1
B 6Ã10â6 Â°C-1
C 36Ã10â6 Â°C-1
D 27Ã10â6 Â°C-1

The correct answer is:
9Ã10â6 Â°C-1

Solution:
γ real = γ app + γ vessel
⇒ 1 5 3 × 1 0 - 6 + γ vessel glass = 1 4 4 × 1 0 - 6 + γ vessel steel
Further γ vessel steel = 3 α = 3 × 1 2 × 1 0 - 6
=36×10-6 ∘C-1
∴ 1 5 3 × 1 0 - 6 + γ vessel glass = 1 4 4 × 1 0 - 6 + 3 6 × 1 0 - 6
∴ γvesselglass=27×10-6 ∘C-1
or α=γglass3=9×10-6 ∘C-1

Topic: Physics, Thermal Properties of Matter, NEET
The coefficient of friction between two surfaces is 0.2. The maximum angle of friction is

Options:
A sin-1⁡0.2
B cos-1⁡0.2
C tan-1⁡0.1
D cot-1⁡5

The correct answer is:
cot-1⁡5

Solution:
we know that
μ=tan⁡θ where θ is angle of friction
θ=tan-1⁡(μ)
θ=tan-1⁡(0.2)

Topic: Physics, Laws of Motion, NEET
The coefficient of friction between two surfaces is μ=0.8. The tension in the string as shown in the figure is

Options:
A 0 N
B 6Â N
C 4Â N
D 8Â N

The correct answer is:
0 N

Solution:
maximum friction force
f max =μN
=μmgcos⁡30°
=0.8×1×10×32
=43
=6.92 N
And mgsin⁡30°=1×10×12 = 5 N
Also T+f=mgsin⁡30°
Since, the frictional force is more as compare to force mgsin30° i.e., 6.92 N>5 N.
Therefore, the tension in the string would be zero. No motion will take place.

Topic: Physics, Laws of Motion, NEET
The coefficient of performance of a refrigerator is 5 . If the temperature inside freezer is -20oC , the temperature of the surrounding to which it rejects heat is:

Options:
A 41 oC
B 11 oC
C 21 oC
D 31 oC

The correct answer is:
31 oC

Solution:
Coefficient of Performance = q2w=q2q1-q2=TcTH-TC=5

TC=5TH-5Tc
6Tc=5TH
TH=65 Ã253 K=303.6 K=30.6 Â°C=31 Â°C

Topic: Physics, Thermodynamics, NEET
The coefficient of performance of a refrigerator is 5. If the temperature inside the freezer is -20 Â°C, the temperature of the surrounding to which it rejects heat is:

Options:
A 41 °C
B 11 °C
C 21 °C
D 31 °C

The correct answer is:
31 °C

Solution:
Coefficient of Performance = q2w=q2q1-q2=TcTH-TC=5

TC=5TH-5Tc
6Tc=5TH
TH=65 ×253 K=303.6 K=30.6 °C=31 °C

Topic: Physics, Thermodynamics, NEET, NEET 2015 (Phase 2)
The coefficient of performance of a refrigerator is 5. If the temperature inside the freezer is -20 Â°C, the temperature of the surrounding to which it rejects heat is:

Options:
A 41 °C
B 11 °C
C 21 °C
D 31 °C

The correct answer is:
31 °C

Solution:
Coefficient of Performance = q2w=q2q1-q2=TcTH-TC=5

TC=5TH-5Tc
6Tc=5TH
TH=65 Ã253 K=303.6 K=30.6 Â°C=31 Â°C

Topic: Physics, Thermodynamics, NEET
The coefficient of performance of a refrigerator working between 10 Â°C and 20 Â°C is

Options:
A 28.3
B 29.3
C 2
D 0.5

The correct answer is:
28.3

Solution:
T1=273+20=293 K, T2=273+10=283 K
Coefficient of performance
=T2T1-T2=283293-283=28310=28.3

Topic: Physics, Thermodynamics, NEET
The coefficient of restitution for a body is e=13. At what angle the body must be incident on a perfectly hard plane so that the angle between the direction before and after the impact be at right angles?

Options:
A 37°
B 60°
C 45°
D 30°

The correct answer is:
30°

Solution:
tan⁡ϕ=1etan⁡θ
Given θ+ϕ=90°
∴ tan⁡90°-θ=113tan⁡θ
cot⁡θ13=tan⁡θ
tan2⁡θ=13
tan⁡θ=13
θ=30°

Topic: Physics, Center of Mass Momentum and Collision, NEET
The coefficient of static friction $\mu_8$, between block $A$ of mass $2 \mathrm{~kg}$ and the table as shown in the figure is 0.2 . What would be the maximum mass value of block B so that the two blocks do not move? The string and the pulley are assumed to be smooth and massless $(g$ $\left.=10 \mathrm{~m} / \mathrm{s}^2\right)$

Options:
A $2.0 \mathrm{~kg}$
B $4.0 \mathrm{~kg}$
C $0.2 \mathrm{~kg}$
D $0.4 \mathrm{~kg}$

The correct answer is:
$0.4 \mathrm{~kg}$

Solution:
According to the question
$$
T=m_{\mathrm{B}} q=\mu\left(m_{\mathrm{A}} q\right)
$$
$$
\begin{aligned}
\Rightarrow \quad m_{\mathrm{B}} & =\mu m_{\mathrm{A}}=0.02 \times 2 \\
& =0.4 \mathrm{~kg}
\end{aligned}
$$

Topic: Physics, Laws of Motion, NEET, NEET 2004
The coefficient of static friction, Î¼ s , between block A of mass 2 kg and the table as shown in the figure is 0.2. The maximum mass value of block B so that the two blocks do not move is (The string and the pulley are assumed to be smooth and massless g=10 m sâ2)

Options:
A 0.4 kg
B 2.0 kg
C 4.0 kg
D 0.2 kg

The correct answer is:
0.4 kg

Solution:
Condition for not moving the block is Tension in the string should be equal to static frictional force, here tention will be equal to mbg
m B  g= μ s   m A  g ⇒     m B = μ s   m A or,    m B =0.2×2=0.4 kg

Topic: Physics, Laws of Motion, NEET
The coefficient of thermal conductivity of copper is 9 times that of steel. In the composite cylindrical bar shown in the figure, what will be the temperature at the junction of copper and steel?

Options:
A 75 °C
B 67 °C
C 25 °C
D 33 °C

The correct answer is:
75 °C

Solution:
Temperature of the interface,
θ=K1θ1l2+K2θ2l1K1l2+K2l1
It is given that KCu=9Ks. So, if Ks=K1=K, then
KCu=K2=9K
⇒ θ=9K×100×6+K×0×189K×6+K×18
=5400K72K=75 °C

Topic: Physics, Thermal Properties of Matter, NEET
The coefficient of volume expansion of glycerine is 49Ã10-5 K-1. The fractional change in its density for a 30 Â°C rise in temperature will be

Options:
A 1.45×10-2
B 2×10-4
C 3.5×10-3
D 2.5×10-2

The correct answer is:
1.45×10-2

Solution:
Let V0 be the initial volume of glycerine, i.e, at 0 °C (dry). If Vt be its volume at 30 °C
Then Vt=V01+v∆t
= V01+49×10-5×30
Vt=V01+0.01470=1.0147070 V0
⇒ V0Vt=11.01470
Let ρo and ρt be the initial and final densities of glycertine then initial density, ρ0=mv0 and final density, ρt=mVt
Where, m=mass of glycertine
∆ρρ0= fractional change in the density
ρt-ρ0ρ0=m1Vt-1V0mV0=V0Vt-1
∆ρρ0=11.01470-1=-0.0145
Here, negative sign shows that density decreases with rise in temperature
∆ρρ0=0.0145=1.45×10-2
∆ρρ0=1.45×10-2

Topic: Physics, Thermal Properties of Matter, NEET
The coercivity of a small bar magnet is 4Ã103 A m-1 . It is inserted inside a solenoid of 500 turns and length 1 m to demagnetize it. The amount of current to be passed through the solenoid will be

Options:
A 2.5 A
B 5 A
C 8 A
D 10 A

The correct answer is:
8 A

Solution:
n = number of turns per unit length of solenoid ,
n=5001
H=niâi=Hn=4Ã103500=8 A

Topic: Physics, Magnetic Properties of Matter, NEET
The cofactor is a part of holoenzyme and it is

Options:
A loosely attached organic part.
B loosely attached inorganic part.
C accessory non protein substance attached firmly to protein part of holoenzyme.
D it is non protein part attached loosely to protein part of holoenzyme.

The correct answer is:
accessory non protein substance attached firmly to protein part of holoenzyme.

Solution:
The conjugate enzyme consists of protein parts called apoenzyme and non-protein part called cofactor. If the cofactor is tightly attached to apoenzyme than it is called a prosthetic group, and if the cofactor is loosely attached organic part than it is called a coenzyme.

Topic: Chemistry, Biomolecules, NEET
The cofactor of the enzyme carboxypeptidase is:

Options:
A Niacin
B Flavin
C Haem
D Zinc

The correct answer is:
Zinc

Solution:
The correct answer is option (4) as the cofactor of the enzyme carboxypeptidase is zinc. Niacin is associated with coenzyme NAD and NADP.
Option (3) is incorrect as haem is the prosthetic group in peroxidase and catalase.

Topic: Biology, Biomolecules (B), NEET, NEET 2024
The cohesive force of water is due to

Options:
A S-bonds
B O-bonds
C H-bonds
D OH-bonds

The correct answer is:
H-bonds

Solution:
Cohesion refers to attraction between molecules of same kind. Cohesive force is found in water molecule due to ability of hydrogen bonding. It is a special type of dipole-dipole interaction between molecules. In water hydrogen bond is a dynamic attraction between neighboring water molecules which involves one hydrogen atom located between the two oxygen atoms.

Topic: Biology, Transport in Plants, NEET
The coil of a moving coil galvanometer is wound over a metal frame in order to

Options:
A reduce hysteresis
B provide electromagnetic damping
C increase the moment of inertia
D increase the sensitivity

The correct answer is:
provide electromagnetic damping

Solution:
The coil of a moving coil galvanometer is wound over a metal frame in order to provide electromagnetic damping by which the galvanometer becomes dead beat.

Topic: Physics, Experimental Physics, NEET
The Colemnite mineral is represented by

Options:
A Ca[B3O4(OH)2].2H2O
B Ca2B6O11.5H2O
C Ca(OH)2
D Na2B4O7.2H2O

The correct answer is:
Ca2B6O11.5H2O

Solution:
Colemnite is a white crystalline mineral of boron, occuring as glassy prism having composition as Ca2B6O11.5H2O .

Topic: Chemistry, General Principles and Processes of Isolation of Metals, NEET
The coleopteran insect that can be killed by proteins produced by Bacillus thuringiensis is

Options:
A beetles.
B armyworm.
C flies.
D tobacco budworm.

The correct answer is:
beetles.

Solution:
Some strains of Bacillus thuringiensis produce proteins that kill certain insects such as lepidopterans (tobacco budworm, armyworm), coleopterans (beetles) and dipterans (flies, mosquitoes). B. thuringiensis forms protein crystals during a particular phase of their growth. These crystals contain a toxic insecticidal protein.

Topic: Biology, Biotechnology and Its Applications, NEET
The collar bone is common name for

Options:
A Sternum
B Scapula
C Coracoid
D Clavicle

The correct answer is:
Clavicle

Solution:
Each clavicle is a long slender bone with two curvatures. This bone is commonly called the collar bone.

Topic: Biology, Locomotion and Movement, NEET
The collective term used for phelloderm, cork cambium and cork is

Options:
A pericycle.
B periderm.
C protoderm.
D procambium.

The correct answer is:
periderm.

Solution:
The pericycle is cylindrical tissue made up of Parenchyma or sclerenchyma cells, pericycle is present between endodermis and stele. Protoderm is the initial meristematic tissue which forms plumule and radicle. Procambium tissue forms cambium and primary vascular tissue.

Topic: Biology, Anatomy of Flowering Plants, NEET
The collector current for a transistor is 6.6 mA and its Î±=0.95, then value of Î² and base current IB are best given by

Options:
A β=19, IB=350 μA
B β=19, IB=220 μA
C β=30, IB=330 μA
D β=30, IB=220 μA

The correct answer is:
β=19, IB=350 μA

Solution:
Î²=Î±1-Î±=19
IB=IcÎ²â350 Î¼A

Topic: Physics, Semiconductors, NEET
The collector current in a common base amplifier using $n$ - $p$-n transistor is $24 \mathrm{~mA}$. If $80 \%$ of the electrons released by the emitter is accepted by the collector, then the base current is numerically:

Options:
A $6 \mathrm{~mA}$ and leaving the base
B $3 \mathrm{~mA}$ and leaving the base
C $6 \mathrm{~mA}$ and entering the base
D $3 \mathrm{~mA}$ and entering the base

The correct answer is:
$6 \mathrm{~mA}$ and entering the base

Solution:
As per question, we have, $\mathrm{I}_{\mathrm{c}}=24 \mathrm{~mA}$, and $\alpha=0.8$
Now, $\quad \mathrm{I}_{\mathrm{E}}=\frac{\mathrm{I}_{\mathrm{c}}}{\alpha}=\frac{24}{0.8}=30 \mathrm{~mA}$
As, $\quad \mathrm{I}_{\mathrm{E}}=\mathrm{I}_{\mathrm{B}}+\mathrm{I}_{\mathrm{C}}$
Hence, $\quad \mathrm{I}_{\mathrm{B}}=\mathrm{I}_{\mathrm{E}}-\mathrm{I}_{\mathrm{C}}$
$=6 \mathrm{~mA}$
(where, the symbols have their usual meanings)

Topic: Physics, Semiconductors, NEET, NEET 2022 (Phase 2)
The colonies of recombinant bacteria appear white in contrast to blue colonies of non-recombinant bacteria because of

Options:
A Non-recombinant bacteria containing $\beta$-galactosidase
B Insertional inactivation of $\alpha$-galactosidase in non-recombinant bacteria
C Insertional inactivation of $\alpha$-galactosidase in recombinant bacteria
D Inactivation of glycosidase enzyme in recombinant bacteria

The correct answer is:
Insertional inactivation of $\alpha$-galactosidase in recombinant bacteria

Solution:
The colonies of recombinant bacteria appear white in contrast to blue calories of non-recombinant bacteria because of insertional inactivation of alpha galactosidase in recombinant bacteria. Alpha galactosidase is a glycoside hydrolase enzyme that hydrolyse the terminal alpha galactosyl moieties from glycolipids and glycoprotein. It is encoded by the GLA gene. $\beta$-galactosidase is an exaglycosidase, which hydrolyzes the $\beta$-glycosidic bond formed between a galactose and its organic rhoiety.

Topic: Biology, Biotechnology - Principles and Processes, NEET, NEET 2013 (All India)
The colonies of recombinant bacteria appear white in contrast to blue colonies of non-recombinant bacteria because of

Options:
A Insertional inactivation of alpha-galactosidase in non-recombinant bacteria
B Insertional inactivation of alpha-galactosidase in recombinant bacteria
C Insertional inactivation of beta-galactosidase in recombinant bacteria.
D Insertional inactivation of beta-galactosidase in non-recombinant bacteria.

The correct answer is:
Insertional inactivation of beta-galactosidase in recombinant bacteria.

Solution:
Screenable marker, visual marker or reporter gene generates a product that can be detected. It is used in confirming transformation, determining transformation efficiency and monitoring gene expression.

The most common example is the lac Z gene of E. coli. Lac Z gene acts as a screenable marker in the presence of X-gal because its expression is readily quantitated by the intensity of the blue colour that is generated.

Lac Z (reporter gene) â Î²-galactosidase (gene product) âX-gal (substrate) â1. Blue colonies (non-transformants) 2. White colonies (transformants)

Topic: Biology, Biotechnology - Principles and Processes, NEET
The colour and magnetic nature of manganate ion MnO42- is-

Options:
A Green, paramagnetic
B Purple, diamagnetic
C Green, diamagnetic
D Purple, paramagnetic

The correct answer is:
Green, paramagnetic

Solution:
MnO42- manganate ion is green and paramagnetic

Topic: Chemistry, d and f Block Elements, NEET
The colour code of a resistance is given below
The values of resistance and tolerance, respectively, are

Options:
A 47 kΩ, 10%
B 4.7 kΩ, 5%
C 470 kΩ, 5%
D 470 Ω, 5%

The correct answer is:
470 Ω, 5%

Solution:
The colours brown, red, green, blue, and violet are used to give value of resistance while golden strip is for tolerance.

yellow - 4

violet - 7

brown - 1

gold - 5%

R=47×101±5%

R=470 Ω,5%

Topic: Physics, Current Electricity, NEET, NEET 2020 (Phase 1)
The colour of light absorbed by an aqueous solution of CuSO4 is

Options:
A Blue green
B Yellow
C Violet
D Orange – red

The correct answer is:
Orange – red

Solution:
RO stands for Red orange light
Emission: blue colour light is emitted
Absorption: orange – Red light is absorbed (these are complementary colours)

Topic: Chemistry, Coordination Compounds, NEET
The colour of potassium dichromate is due to

Options:
A d-d transition
B transition in K+ ion
C ligand-to-metal charge transfer
D metal to ligand charge transfer

The correct answer is:
ligand-to-metal charge transfer

Solution:
Theorange color of dichromate is due to charge (electron) transfer from O2- ligands to the empty d-orbitals of the central metal Cr6+ , i.e. LMCT. This electronic transfer absorbs greenish blue light and leaves the complimentary orange light behind as the observed colour.

Topic: Chemistry, Coordination Compounds, NEET
The colour of the colloidal particles of gold obtained by different methods differ because of

Options:
A variable valency of gold
B different concentration of gold particles
C different type of impurities
D different diameters of colloidal particles

The correct answer is:
different diameters of colloidal particles

Solution:
The colour of the colloidal particles of gold obtained by different methods differ because of different diameters of colloidal particles.

Topic: Chemistry, Surface Chemistry, NEET
The columnar epithelium is found in

Options:
A Lining of intestine
B Lining of blood vessel
C Seminiferous tubule
D Uriniferous tubules

The correct answer is:
Lining of intestine

Solution:
SIMPLE COLUMNAR EPITHELIUM:
Structure: The cells of the simple columnar epithelium are tall pillar-like and are placed side by side. The free surface of columnar epithelial cells is smooth. The oval nucleus lies close to the base of the cell.
Location: Simple columnar epithelium forms a lining of the stomach, small intestine, colon, gall bladder, gastric glands, intestinal gland, and pancreatic lobules. Since here it performs the secretory functions, it is called the glandular epithelium. Certain cells of the columnar epithelium of stomach and intestine produce mucus which forms a fine mucus coating over epithelium. These mucus-producing cells are called goblet cells. The epithelium having mucus-secreting cells along with underlying connective-tissue is called mucous membrane or mucosa. The other columnar cells lining the intestine are specialized for the absorption of water and digested food. In order to surface area for absorption, they bear microvilli at the free ends. The columnar epithelium of this called brush-bordered columnar epithelium.
Function: Protection, secretion, and absorption.

Topic: Biology, Structural Organisation in Animals, NEET
The combination of gates shown below produces

Options:
A AND gate
B XOR gate
C NOR gate
D NAND gate

The correct answer is:
NAND gate

Solution:
y=A¯+B¯¯
y=A¯+B¯
y=A.B¯

Topic: Physics, Semiconductors, NEET
The combination of gates shown below yields

Options:
A OR gate
B NOT gate
C XOR gate
D NAND gate

The correct answer is:
OR gate

Solution:
The final boolean expression is,
X=(A¯.B¯)¯=A-+B-=A+B⇒ OR gate

Topic: Physics, Semiconductors, NEET
The combination of gates shown in the figure below produces

Options:
A NOR gate
B OR gate
C AND gate
D XOR gate

The correct answer is:
OR gate

Solution:
Here, the output of these gate
Y= A ¯ . B ¯ ¯
But according to Boolean algebra,
A ¯ . B ¯ = A+B ¯
∴Y= A ¯ + B ¯ ¯ =A+B
or Y=A+B
It means the whole circuit of gates behaves as OR gate

Topic: Physics, Semiconductors, NEET
The combination of gates shown in the figure below produces.

Options:
A NOR gate
B OR gate
C AND gate
D XOR gate

The correct answer is:
OR gate

Solution:
Outputs of different gates are shown below
â´ output of the combinations
Y= A ¯ . B ¯ ¯ =A+B
This is the expression of OR gate.

Topic: Physics, Semiconductors, NEET
The combination of NAND gates shown here in the figure give output C and C'. C and C' are equivalent to

Options:
A OR gate and AND gate respectively
B AND gate and NOT gate respectively
C AND gate and OR gate respectively
D OR gate and NOT gate respectively

The correct answer is:
OR gate and AND gate respectively

Solution:
C=A¯⋅B¯¯
=A+B
Thus its OR gate
C'=A⋅B¯¯=A⋅B
Thus its AND gate

Topic: Physics, Semiconductors, NEET
The common ancestor for cycads and angiosperms is

Options:
A Seed ferns
B Progymnosperms
C Zosterophyllum
D Bryophytes

The correct answer is:
Seed ferns

Solution:
In the evolution of plants, chlorophyte ancestors gave rise to tracheophyte ancestors which gave rise to Rhynia type plants. They further evolved into Psilophyton. Psilophyton further branched and gave rise to Sphenopsids, Ferns, Ginkgos, Conifers, Gnetales and Progymnosperms. Progymnosperms evolved to seed ferns which gave rise to cycads and angiosperms

Topic: Biology, Evolution, NEET
The common basic structural unit in silicates and silica is

Options:
A Si2O64-
B SiO32-
C SiO44-
D Si2O76-

The correct answer is:
SiO44-

Solution:
Silica (SiO2) and silicates contain a common structural unit SiO44- in which each Si is surrounded tetrahedrally by four oxygen atoms.

Topic: Chemistry, p Block Elements (Group 13 & 14), NEET
The common characteristics between tomato and potato will be maximum at the level of their:

Options:
A family
B order
C division
D genus.

The correct answer is:
family

Solution:
Potato (Solanum tuberosum) and tomato (Lycopersicum esculentum) both belong to family Solanaceae.
Related Theory
Taxonomy is a branch of study that deals with principles and procedures of identification, nomenclature and classification of organisms. Taxonomic hierarchy is the framework by which taxonomic groups are arranged in definite order from higher to lower (descending order) or lower to higher (ascending) categories. The hierarchical order of classifying organisms is:
Kingdom $\rightarrow$ Phylum $\rightarrow$ Class $\rightarrow$ Order $\rightarrow$ Family $\rightarrow$ Genus $\rightarrow$ Species.

Topic: Biology, The Living World, NEET, NEET 2013 (Karnataka)
The common characteristics between tomato and potato will be maximum at the level of their

Options:
A Family
B Order
C Division
D Genus

The correct answer is:
Family

Solution:
Tomato is Lycopersicum esculentum and potato is Solanum tuberosum, both belong to different genus but are members of the same family, thus maximum common characters are observed at the level of the family.

Topic: Biology, The Living World, NEET
The common features among the species CN– , CO and NO+ are

Options:
A Bond order three and isoelectronic
B Bond order three and weak field ligand
C Bond order two and π - e- acceptors
D Isoelectronic and weak field ligands

The correct answer is:
Bond order three and isoelectronic

Solution:
CN- (Total Electron 14) B.O = 1 0 - 4 2 = 3
CO (Total Electron 14) B.O = 1 0 - 4 2 = 3
NO+ (Total electrons 14) B.O = 1 0 - 4 2 = 3

Topic: Chemistry, Chemical Bonding and Molecular Structure, NEET
The common impurities in bauxite are
(i) Fe2O3
(ii) SiO2
(iii) CuO
(iv) ZnO

Options:
A 1,3
B 2,3
C 1,2
D 2,4

The correct answer is:
1,2

Solution:
Bauxite is ore of aluminum, it has impurities of Fe2O3 and SiO2

Topic: Chemistry, General Principles and Processes of Isolation of Metals, NEET