datavorous/entrance-exam-dataset huggingface dataset:
The productivity of the oceans is approximately _______ the annual net primary productivity of the whole biosphere.

Options:
A half
B one third
C one fifth
D one fourth

The correct answer is:
one third

Solution:
Primary productivity depends on the plant species inhabiting a particular area. It also depends on a variety of environmental factors, availability of nutrients and photosynthetic capacity of plants. Therefore, it varies in different types of ecosystems. The annual net primary productivity of the whole biosphere is approximately 170 billion tons (dry weight) of organic matter. Of this, despite occupying about 70 per cent of the surface, the productivity of the oceans are only 55 billion tons. Thus 55 out of 170 is 32.35% which is around one third.

Topic: Biology, Ecosystem, NEET
The products A and B are

Options:
A
B
C
D

The correct answer is:

Solution:
This reaction occurs by SN1 mechanism to give benzyl iodide and 1,4-dihydroxybenzene.

Topic: Chemistry, Alcohols Phenols and Ethers, NEET
The products $A$ and $B$ in the following reaction sequence are:

Options:
A

B

C

D

The correct answer is:

Solution:

Topic: Chemistry, Alcohols Phenols and Ethers, NEET, NEET 2022 (Phase 2)
The products A and B obtained in the following reactions, respectively, are
$\begin{aligned}
& 3 \mathrm{ROH}+\mathrm{PCl}_3 \rightarrow 3 \mathrm{RCl}+\mathrm{A} \\
& \mathrm{ROH}+\mathrm{PCl}_5 \rightarrow \mathrm{RCl}+\mathrm{HCl}+\mathrm{B}
\end{aligned}$

Options:
A $\mathrm{POCl}_3$ and $\mathrm{H}_3 \mathrm{PO}_4$
B $\mathrm{H}_3 \mathrm{PO}_4$ and $\mathrm{POCl}_3$
C $\mathrm{H}_3 \mathrm{PO}_3$ and $\mathrm{POCl}_3$
D $\mathrm{POCl}_3$ and $\mathrm{H}_3 \mathrm{PO}_3$

The correct answer is:
$\mathrm{H}_3 \mathrm{PO}_3$ and $\mathrm{POCl}_3$

Solution:
These reactions are preparation of haloalkanes from alcohols.
$3 \mathrm{ROH}+\mathrm{PCl}_3 \longrightarrow 3 \mathrm{RCl}+\mathrm{H}_3 \mathrm{PO}_3$
$\mathrm{ROH}+\mathrm{PCl}_5 \longrightarrow \mathrm{RCl}+\mathrm{HCl}+\mathrm{POCl}_3$
$A$ and $B$ are $\mathrm{H}_3 \mathrm{PO}_3$ and $\mathrm{POCl}_3$ respectively.

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), NEET, NEET 2024
The products formed in the following reaction C6H5-O-CH3+HI→heat are

Options:
A C6H5-I and CH3-OH
B C6H5-OH and CH3-I
C C6H5-CH3 and HOI
D C6H6 and CH3OI

The correct answer is:
C6H5-OH and CH3-I

Solution:

Topic: Chemistry, Alcohols Phenols and Ethers, NEET
The products obtained from the following chemical reactions are respectively

(i) NaOH ( hotââandââconc. ) + Cl 2 â

(ii) XeF 6 ( excess ) + H 2 Oâ

Options:
A NaOH and XeO 3
B HClO 3 and XeO 2 F 2
C NaClO 3 and XeOF 4
D None of these

The correct answer is:
NaClO 3 and XeOF 4

Solution:
The reactions are as follows:
(i) 6âNaOH ( hotââandââconc. ) +3 Cl 2 â5NaCl+ NaClO 3 +3 H 2 O
(ii) XeF 6 + H 2 O→ XeOF 4 +2HF

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), NEET
The products obtained when benzyl phenyl ether is heated with HI in the mole ratio 1:1 are

1. Phenol

2. Benzyl alcohol

3. Benzyl iodide

4. Iodobenzene

Options:
A 1 and 3 only
B 3 and 4 only
C 1 and 4 only
D 2 and 4 only

The correct answer is:
1 and 3 only

Solution:
Benzyl phenyl ether is an unsymmetrical ether so halide ion of HI attached to the simple alkyl group and reaction takes place by following mechanism.
1. Protonation of ether
Benzyl phenyl ether
2. Nucleophilic attack

Topic: Chemistry, Alcohols Phenols and Ethers, NEET
The product(s) of reaction catalyzed by nitrogenase in root nodules of leguminous plants is/are:

Options:
A Nitrate alone
B Ammonia and oxygen
C Ammonia and hydrogen
D Ammonia alone

The correct answer is:
Ammonia and hydrogen

Solution:
MECHANISM OF BIOLOGICAL N2 FIXATION:

It takes place in leguminous plants (Fabaceae) by the symbiotic bacterium Rhizobium, which forms nodules in their roots. N2 is directly converted into an NH4+ ion, which is used in plant metabolism. Root nodules act as the site for N2 fixation. It contains all necessary biochemical components like enzyme nitrogenase, leghaemoglobin, that are required in N2 fixation. Enzyme nitrogenase is a Mo–Fe protein & catalyzes the conversion of atmospheric N2 to NH3.

The reaction takes place in two steps:

(i) N2 + 8e- + 8H+ +16ATP →Nitrogenase 2NH3 + H2 + 16ADP + 16Pi(ii) 2NH3 + H2 → 2NH4+ + 2e-

Topic: Biology, Mineral Nutrition, NEET, NEET 2020 (Phase 1)
The products of the following chemical reactions are

(i) C 2 â H 5 âN H 2 â+ C 6 â H 5 âS O 2 âCl â

(ii) C 2 â H 5 â NH 2 â+ HNO 2 â H 2 O

Options:
A

(i) C 6 â H 5 S O 2 NH C 2 H 5

(ii) C 2 â H 5 Cl

B

(i) C 6 â H 5 S O 2 NH 2

(ii) C 2 â H 5 OH

C

(i) C 6 â H 5 S O 2 NH C 2 H 5

(ii) C 2 â H 5 OH

D None of these

The correct answer is:

(i) C 6 â H 5 S O 2 NH C 2 H 5

(ii) C 2 â H 5 OH

Solution:
The reactions as follows :

(i) C 2 H 5 N H 2 â+ C 6 H 5 S O 2 Clâ C 6 â H 5 S O 2 NH C 2 H 5 â+HCl

(ii) C 2 â H 5 âN H 2 +HN O 2 â [ C 2 H 5 N 2 + C l â ] â H 2 O C 2 â H 5 OH+ N 2 +HCl

Topic: Chemistry, Amines, NEET
The products of the photochemical reaction are:

Options:
A O2 , ATP and NADPH
B Glucose and O2
C ATP and NADPH
D Organic compounds especially carbohydrates

The correct answer is:
O2 , ATP and NADPH

Solution:
Two reactions occur in the chloroplast of plant. First reaction takes place on the grana of chloroplast. This reaction is called light reaction (photochemical reaction) which require photosynthetic pigments, sun light and water to produce oxygen, ATP and NADPH. Second reaction takes place on the stroma of chloroplast which produces glucose by using the products of light reaction.

Topic: Biology, Photosynthesis in Higher Plants, NEET
The products of the reaction of HCHO and PhCHO in presence of concentrated base are

Options:
A HCH2OH+PhCOO-
B HCOO-+PhCH2OH
C PhCOOCH3
D HCOOCH2Ph

The correct answer is:
HCOO-+PhCH2OH

Solution:
The reaction of an aldehyde with formaldehyde and aqueous base in known as crossed-Cannizzaro reaction. It is formaldehyde rather than the other aldehyde that undergoes oxidation.
HCHO + PhCHO → HCOO-+PhCH2OH

Topic: Chemistry, Aldehydes and Ketones, NEET
The products of the reaction will be
C6H6+CH3-CH2-CH2-Br→Anhy.AlBr3

Options:
A C6H5-CH2-CH2-CH3
B
C as major product and C6H5-CH2-CH2-CH3 as minor product
D 1: 1 mixture of C6H5-CH2-CH2-CH3 and

The correct answer is:
as major product and C6H5-CH2-CH2-CH3 as minor product

Solution:
Here the major product is 2-phenylpropane and minor is 1-phenylpropane as follows
It involves rearrangement of carbocation as follows
CH3-CH2-C⊕H2p°lessstable→H-shiftCH3-C⊕H-CH3s°morestable

Topic: Chemistry, Hydrocarbons, NEET
The pro-hormone insulin is processed to become a fully mature and functional insulin hormone by removal of

Options:
A C peptide
B A peptide
C B peptide
D Both (A) and (B)

The correct answer is:
C peptide

Solution:
In humans, insulin is synthesized as a pro-hormone and is processed before it becomes a fully mature and functional hormone, by removal of an extra stretch called the C peptide. A matured insulin consist of two chains A chain (21 aa-) and B chain (30 aa-).

Topic: Biology, Biotechnology and Its Applications, NEET
The prokaryote that is credited with construction of the first recombinant DNA by linking an antibiotic resistance gene with its native plasmid is

Options:
A Escherichia coli
B Pneumococcus pneumonia
C Salmonella typhimurium
D Agrobacterium tumefaciens

The correct answer is:
Salmonella typhimurium

Solution:
The construction of the first recombinant DNA by linking a gene encoding antibiotic resistance with a native plasmid of Salmonella typhimurium was accomplished in 1972 by Stanley Cohen and Herbert Boyer. This rDNA was transferred in Escherichia coli which could replicate and produce multiple copies.

Topic: Biology, Biotechnology - Principles and Processes, NEET
The promoter site and the terminator site for transcription are located at:

Options:
A 3′ (downstream) end and 5′ (upstream) end, respectively of the transcription unit
B 5′ (upstream) end and 3′ (downstream) end, respectively of the transcription unit
C the 5′ (upstream) end
D the 3′ (downstream) end

The correct answer is:
5′ (upstream) end and 3′ (downstream) end, respectively of the transcription unit

Solution:
The promoter site and the terminator site for transcription are located at5′ (upstream) end and 3′ (downstream) end, respectively of the transcription unit as promoter transcribes in the 5’to 3’ direction along the dna.

Topic: Biology, Molecular Basis of Inheritance, NEET
The properties of carbonyl group is suppressed the most in

Options:
A CH3CHO
B CH3COCH3
C CH3COOCH3
D CH3CONH2

The correct answer is:
CH3CONH2

Solution:
The resonance structures for RCOG are

or
Electron-release from G(H, CH3,OCH3 or NH2 ) to O stabilizes by diminishing the electrophilic character of carbonyl carbon. Since degree of delocalization is maximum in case of -NH2 , therefore, the properties of is suppressed most in amides (RCONH2) .

Topic: Chemistry, General Organic Chemistry, NEET
The properties of the elements are the periodic function of their atomic number. The statement is given by -

Options:
A N. Bohr
B J.W. Dobereiner
C D.I. Mendeleev
D H.G.J. Mosley

The correct answer is:
H.G.J. Mosley

Solution:
According to H.G.J. Mosley, the properties of the two elements are the periodic function of their atomic number.

Topic: Chemistry, Classification of Elements and Periodicity in Properties, NEET
The property not shown by the "amphibians of the plant kingdom" is

Options:
A The plant body is thallus like, attached to substratum by help of rhizoids
B The antherozoids are released in water for fertilization
C Zygote formed undergoes meiotic division immediately
D They have leaf like, stem like and root like structures

The correct answer is:
Zygote formed undergoes meiotic division immediately

Solution:
Bryophytes (amphibians of the plant kingdom) are plants that can live on soil but are dependent on water for fertilization. The plant body of bryophytes is thallus like and attached to the substratum by unicellular or multicellular rhizoids. The male gametes produce antherozoids which are released in the water to come in contact with archegonium and form a zygote which does not undergo reduction immediately. It undergoes mitosis to form sporophyte which is attached to the gametophyte

Topic: Biology, Plant Kingdom, NEET
The property of halogen acids, that indicated incorrect is

Options:
A HF > HCl > HBr > HI ..... acidic strength
B HI > HBr > HCl > HF ..... reducing strength
C HI > HBr > HCl > HF .... bond length
D HF > HCl > HBr > HI .... thermal stability

The correct answer is:
HF > HCl > HBr > HI ..... acidic strength

Solution:
HI is the strongest acid while HF is the weakest acid. The order of acidic strength is
HI > HBr > HCl > HF

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), NEET
The property which is not of an electromagnetic wave travelling in free space is that:

Options:
A The energy density in electric field is equal to energy density in magnetic field
B They travel with a speed equal to $\frac{1}{\sqrt{\mu_0 \varepsilon_0}}$
C They originate from charges moving with uniform speed
D They are transverse in nature

The correct answer is:
They originate from charges moving with uniform speed

Solution:
The EM waves originate from an accelerating charge. The charge moving with uniform velocity produces steady state magnetic field.

Topic: Physics, Electromagnetic Waves, NEET, NEET 2024
The proportion of assimilated energy consumed in respiration is highest in

Options:
A decomposers
B producers
C herbivores
D carnivores

The correct answer is:
carnivores

Solution:
The proportion of assimilated energy consumed in respiration in producers is 20%, in herbivores: 30% and in carnivores: 60%. As the trophic level increases, the energy spent on respiration increases.

Topic: Biology, Ecosystem, NEET
The proportion of monohybrids in the F2 generation of a monohybrid cross _________ proportion of dihybrids in the F2 generation of a dihybrid cross

Options:
A is same as
B is greater than
C is lesser than
D may be same or greater but never lesser than

The correct answer is:
is greater than

Solution:
In a monohybrid cross, there are two monohybrids out of total of four offsprings. (AA: Aa: aa =1 :2 :1). Thus their proportion is 50%. In a dihybrid cross, there are four dihybrids out of total sixteen offsprings. (AABB: AAbb: aaBB: aabb: AaBB: AABb: Aabb: aaBb : AaBb = 1 : 1 : 1 : 1 : 2 : 2: 2 : 2 : 4). Thus their proportion is 25%.

Topic: Biology, Principles of Inheritance and Variation, NEET
The proportion of the offsprings obtained from the cross AABBCC Ã AaBbCc will be completely heterozygous for all genes segregated independently will be

Options:
A 1/8
B 1/4
C 1/2
D 1/16

The correct answer is:
1/8

Solution:
As per Mendel's Law of Segregation "alleles segregate randomly into gametes: When gametes are formed, each allele of one parent segregates randomly into the gametes, such that half of the parent's gametes carry each allele."
The cross between parents with genotype produces the following progenies -
ABBCC×AaBbCc
AABBCC
AABBCc
AABbCC
AABbCc
AaBBCC
AaBbCc
AaBBCc
AaBbCC
Progeny with genotype heterozygous for all gene is 1 out of 8 types. Thus, probability is 1/8

Topic: Biology, Principles of Inheritance and Variation, NEET
The proportion of young individuals is highest in:

Options:
A stable population
B declining population
C expanding population
D both stable and declining population

The correct answer is:
expanding population

Solution:
A population with more members have more chances of making more progenies. This is due to the young individuals of the populations are in the reproductive age group. Thus, more young individuals in a group will lead to a greater number of births and increase the natality over mortality. Such population is considered to be expanding population.

Topic: Biology, Organisms and Populations, NEET
The protecting power of lyophilic colloidal sol is expressed in terms of

Options:
A coagulation value
B gold number
C critical micelle concentration
D oxidation number

The correct answer is:
gold number

Solution:
Lyophobic sols are unstable, so they are stabilised by adding some lyophilic colloids which protect them from precipitation. Thus, lyophilic colloids are called protecting colloids. Their protecting power is expressed in terms of gold number.
Note Lesser the gold number, higher is the protecting power.

Topic: Chemistry, Surface Chemistry, NEET, NEET 2012 (Screening)
The protein products of the Bt toxin genes cryIAc and cryIIAb are responsible for controlling

Options:
A Bollworm
B Roundworm
C Moth
D Fruit fly

The correct answer is:
Bollworm

Solution:
Bacillus thuringensis is a bacteria having the capacity to produce an insecticidal protein called bt toxin. This toxin is produced in the inactive form by the cry gene found in the bacterial genome. There are a number of them. cryIAc and cryIIAb control the cotton bollworm and cryIAb controls corn borer. These proteins are produced in inactive form so that the bacteria is not affected by it. When this protein comes in contact with the digestive juices of the gut of the insect, it becomes active. The activated protein bind to the surface of epithelial cells of midgut and create pores. These causes swelling and lysis of cells leading to death of the insect.

Topic: Biology, Biotechnology and Its Applications, NEET
The protein that is infectious to the living cells are termed as

Options:
A Plasmid
B Phages
C Prions
D Prophage

The correct answer is:
Prions

Solution:
A prion is a type of protein that can trigger normal proteins in the brain to fold abnormally. Prion diseases can affect both humans and animals and are sometimes spread to humans by infected meat products. The most common form of prion disease that affects humans is Creutzfeldt-Jakob disease (CJD). Prions are misfolded proteins with the ability to transmit their misfolded shape onto normal variants of the same protein

Topic: Biology, Biological Classification, NEET
The proteinaceous endosperm of maize is called

Options:
A Apophysis
B Scutellum
C Aleurone layer
D None of the above

The correct answer is:
Aleurone layer

Solution:
In maize, endosperm, the outermost layer of endosperm cells, becomes specialized and becomes rich in proteins. These enzymatic proteins cause breakdown of stored food in endosperm during germination and transfer it to the embryo.

Topic: Biology, Morphology of Flowering Plants, NEET
The proteinaceous layer called pellicle and two flagella one long and one short are seen in organisms which are

Options:
A unicellular, prokaryotic and are photosynthetic as well as heterotrophic
B unicellular, prokaryotic and are heterotrophic
C unicellular, eukaryotic and are photosynthetic as well as heterotrophic
D unicellular, eukaryotic and are heterotrophic

The correct answer is:
unicellular, eukaryotic and are photosynthetic as well as heterotrophic

Solution:
Euglenoids are unicellular, eukaryotic organisms that have a proteinaceous layer called pellicle instead of a cell wall. They have one pair of short and one large flagellum. They are photosynthetic in the presence of light and are heterotrophic in the absence of light. Hence, they are called connecting links between plants and animals.

Topic: Biology, Biological Classification, NEET
The proteins alter other normal proteins within the living cells are termed as

Options:
A Plasmids
B Phages
C Prions
D Viroids

The correct answer is:
Prions

Solution:
Viruses, Viroids and Prions are acellular organisms and hence did not find a place in famous Whittaker's Five - Kingdom classification. Viruses did not have organelles and hence no metabolism and also requires a host for its survival. Prions are also acellular and consist of just protein structure folded variously. These proteins can alter normal proteins in the brain and can cause various neurological infections like BSE (Bovine spongiosum encephalopathy) also known as Mad- cow disease and CJD (Cr. Jacob disease). Viroids lack protein coat.

Topic: Biology, Biological Classification, NEET
The proteolytic enzyme rennin is found in:

Options:
A Intestinal juice
B Bile juice
C Gastric juice
D Pancreatic juice

The correct answer is:
Gastric juice

Solution:
Rennin or chymosin is a proteolytic enzyme found in the gastric juice of infants which helps in the digestion of milk proteins. It is responsible for curdling of milk by transforming caseinogen into insoluble casein.

Topic: Biology, Digestion and Absorption, NEET, NEET 2020 (Phase 2)
The protons that are produced by the splitting of water accumulates

Options:
A On the outer membrane of thylakoids
B On the outer membrane of stroma lamella
C Within the lumen of thylakoids
D In the stroma

The correct answer is:
Within the lumen of thylakoids

Solution:
Since the splitting of the water molecule takes place on the inner side of the membrane, the protons or hydrogen ions that are produced by the splitting of water accumulate within the lumen of the thylakoids.

Topic: Biology, Photosynthesis in Higher Plants, NEET
The puffed-up appearance of dough in a bakery is due to:

Options:
A CO2 production during fermentation by yeast
B CO2 production during aerobic respiration by yeast
C Death of yeast
D Spoiling of the dough due to death of yeast and production of many gases

The correct answer is:
CO2 production during fermentation by yeast

Solution:
The dough which is used for making foods such as dosa, biscuit and bread etc. are fermented by bacteria or yeast (Saccharomyces cerevisiae). The puffed-up appearance of dough is due to the production of CO2 gas. Bacteria are present in the atmosphere and the yeast has to be added to the dough.

Topic: Biology, Microbes in Human Welfare, NEET
The pulley arrangements of the figure. (a) and (b) are identical. The mass of the rope is negligible. In (a) the mass m is lifted up by attaching a mass 2m to the other end of the rope. In (b), m is lifted up by pulling the other end of the rope with a constant downward force F=2 mg. The acceleration of m in both cases is?

Options:
A g3, g3
B g3, g
C g4, g3
D g4, g

The correct answer is:
g3, g

Solution:
Case A
For mass m
T−mg=ma (i)
For mass 2m
2 mg−T=2 ma (ii)
From (i) and (ii), we get –
a= g 3 …(iii)
Case B
T – mg = ma'
⇒    2mg−mg=ma' [ ∵  T=2mg ]
∴     a' =g …(iv)

Topic: Physics, Laws of Motion, NEET
The purest form of commercial iron is

Options:
A Cast iron
B Scarp iron and pig iron
C Pig iron
D Wrought iron

The correct answer is:
Wrought iron

Solution:
Wrought iron is the purest form of commercial iron. It contains only 0.12 to 0.25% of carbon.

Topic: Chemistry, General Principles and Processes of Isolation of Metals, NEET
The purest form of iron is prepared by oxidizing impurities from cast iron in a reverberatory furnace. Which iron ore is used to line the furnace?

Options:
A Limonite
B Magnetite
C Haematite
D Siderite

The correct answer is:
Haematite

Solution:
Correct Option is : (C)
Haematite

Topic: Chemistry, General Principles and Processes of Isolation of Metals, NEET
The purplish red pigment rhodopsin contained in the rods type of photoreceptor cells of the human eyes is a derivative of

Options:
A vitamin-C
B vitamin-D
C vitamin-A
D vitamin-B

The correct answer is:
vitamin-A

Solution:
There are two types of photoreceptor cells of retina, namely rods and cones. The rods contain a purplish red protein called the rhodopsin or visual purple, which contains a derivative of vitamin-A.

Topic: Biology, Neural Control and Coordination, NEET, NEET 2011 (Screening)
The purpose served by keeping beehives in crop fields is an increase in

Options:
A crop yield.
B honey yield.
C weeds yield.
D both (A) and (B)

The correct answer is:
both (A) and (B)

Solution:
Handling and collection of honey and beeswax. Bees are the pollinators of many crop species such as sunflower, Brassica, apple and pear. Keeping beehives in crop fields during the flowering period increases pollination efficiency and improves the yield–beneficial both from the point of view of crop yield and honey yield.

Topic: Biology, Strategies for Enhancement in Food Production, NEET
The pyknometric density of sodium chloride crystal is $2.165 \times 10^3 \mathrm{~kg} \mathrm{~m}^{-3}$ while its X-ray density is $2.178 \times 10^3 \mathrm{~kg}$ $\mathrm{m}^{-3}$. The fraction of unoccupied sites in sodium chloride crystal is:

Options:
A 5.96
B $5.96 \times 10^{-2}$
C $5.96 \times 10^{-1}$
D $5.96 \times 10^{-3}$

The correct answer is:
$5.96 \times 10^{-3}$

Solution:
Molar volume from pyknometric density
$=\frac{\mathrm{M}}{2.165 \times 10^3} \mathrm{~m}^3$
Molar volume of X-ray density
$=\frac{\mathrm{M}}{2.178 \times 10^3} \mathrm{~m}^3$
Volume unoccupied
$=\frac{M}{10^3}\left(\frac{1}{2.165}-\frac{1}{2.178}\right) \mathrm{m}^3$
Fraction occupied
$\begin{aligned} & =\frac{0.013 \times 10^{-3}}{2.165 \times 2.178} \times \frac{2.165}{\mathrm{M} \times 10^{-3}} \\ & =5.96 \times 10^{-3}\end{aligned}$
Related Theory
Pyknometric density is the closest approximation to true density calculated from the molecular weight and crystalline lattice of a substance.

Topic: Chemistry, Solid State, NEET, NEET 2003
The pyramid given below can be observed in a:

Options:
A Pyramid of number without any exception
B Pyramid of energy without any exception
C Pyramid of biomass without any exception
D Both a and c .

The correct answer is:
Pyramid of energy without any exception

Solution:
Types of Ecological Pyramid	General Appearance	Exceptions

1. Pyramid of Number	Usually upright	1. Single tree ecosystem (Single Tree â Many insects, less number of smaller birds â Very few large birds)

2. Pyramid of Biomass	Usually upright	1. Pyramid of biomass in sea (Biomass of fishes is more than phytoplanktons)

3. Pyramid of Energy	Always upright	No exception

Topic: Biology, Ecosystem, NEET