datavorous/entrance-exam-dataset huggingface dataset:
Imaging that an electron revolves around a circle of the radius 5.3Ã10-11 m with a linear speed of 7.5 Ã104 m s-1 in a hydrogen atom. The magnetic field produced at the centre of the circle, due to the electron, is

Options:
A 43 Wb m-2
B 4300 Wb m-2
C 0.43 Wb m-2
D 43×10-4 Wb m-2

The correct answer is:
0.43 Wb m-2

Solution:
B=Î¼04Ïevr2
= 10-7Ã1.6 Ã10-19Ã7.5Ã10+45.3Ã10-112
On solving, B=0.43 Wb m-2

Topic: Physics, Magnetic Effects of Current, NEET
Immovable joints is

Options:
A composed of dense fibrous connective tissue.
B composed of cartilaginous fibres.
C composed of âsynovial fluid.
D Both A and B

The correct answer is:
composed of dense fibrous connective tissue.

Solution:
The joints which are immovable i.e. do not permit any degree of movement are known as synarthrodial joints. This type of joint is seen in the flat skull bones, which fuse end to end with each other with the help of dense fibrous connective tissue and form the cranium.
Amphiarthrodial joints are joints which permit some degree of movement. The joint between adjacent vertebrae is an example. They are also called cartilaginous joints.
Diarthrodial joints are joints which allow complete movement. Elbow joint, knee joint, etc. are some examples. They are also called synovial joints.

Topic: Biology, Locomotion and Movement, NEET
Importance of day length in flowering of plants was first shown in

Options:
A Lemna
B tobacco
C cotton
D Petunia

The correct answer is:
tobacco

Solution:
The phenomenon of photoperiodism was first discovered by Garner and Allard (1920, 1922). They observed that maryland mammoth variety of tobacco could be made to flower only by reducing the light hours with artificial darkening. On the basis of photoperiodic response to flowering, plants have been divided into short day plants (tobacco), long day plant (eg, wheat, hanbane), short-long day plants (eg, Campanula), long-short day plants (eg, Bryophyllum), intermediate plants (eg, wild kidney bean) and day neutral plants (eg, cotton).

Topic: Biology, Plant - Growth and Development, NEET, NEET 2008 (Screening)
Impulse of heart beat originates from:

Options:
A SA node
B AV node
C vagus nerve
D cardiac nerve

The correct answer is:
SA node

Solution:
An electrical stimulus is generated by the sinoatrial node, or SA node. This is a small mass of specialized tissue located in the right atrium of the heart.
Related Theory:-
The AV node gathers the electrical impulse from $S A$ node and, after a brief delay, allows it to pass through to the ventricles. This brief delay in the transmission of the electrical signal through the AV node is critical to a normal heartbeat and the efficient functioning of the heart.

Topic: Biology, Body Fluids and Circulation, NEET, NEET 2002
In 2-Bromo-2-methylpropane bromine is attached to which hybridized carbon?

Options:
A Sp2
B Sp
C Sp3
D None of the above

The correct answer is:
Sp3

Solution:
Correct Option is : 3
Sp3

Topic: Chemistry, Haloalkanes and Haloarenes, NEET
In 1811, which scientist attempted to combine the conclusions of Dalton's atomic theory and Gay Lussac's law of combining volumes to propose a new law?

Options:
A Robert Boyle
B Charles
C Amedeo Avogadro
D Joseph Gay Lussac

The correct answer is:
Amedeo Avogadro

Solution:
In 1811, the Italian scientist Amedeo Avogadro tried to combine Dalton's atomic theory and Gay Lussac's law to propose a new law, which is now known as Avogadro's law.

Topic: Chemistry, States of Matter, NEET
In 1925, what did George Uhlenbeck and Samuel Goudsmit propose regarding electrons?

Options:
A They proposed the presence of the fourth quantum number known as the electron spin quantum number (ms).
B They proposed a new model of the atom.
C They proposed the existence of isotopes.
D They proposed a new element.

The correct answer is:
They proposed the presence of the fourth quantum number known as the electron spin quantum number (ms).

Solution:
In 1925, George Uhlenbeck and Samuel Goudsmit proposed the existence of the fourth quantum number known as the electron spin quantum number (ms) to describe the intrinsic spin angular momentum of electrons.

Topic: Chemistry, Structure of Atom, NEET
In 1953 S. L. Miller created primitive earth conditions in the laboratory and gave experimental evidence for the origin of the first form of life from preexisting non-living organic molecules. The primitive earth conditions created include:

Options:
A low temperature, volcanic storms, atmosphere rich in oxygen
B low temperature, volcanic storms, reducing atmosphere
C high temperature, volcanic storms, non-reducing atmosphere
D high temperature, volcanic storms, reducing atmosphere containing CH4, NH3 etc.

The correct answer is:
high temperature, volcanic storms, reducing atmosphere containing CH4, NH3 etc.

Solution:
The conditions on earth were – high temperature, volcanic storms, reducing atmosphere containing CH4, NH3, etc.

Topic: Biology, Evolution, NEET
In 1963, several varieties such as Sonalika and Kalyan Sona, which were high yielding and disease resistant variety of

Options:
A Wheat
B Bajra
C Rice
D All the above

The correct answer is:
Wheat

Solution:
In 1963, several varieties such as Sonalika and Kalyan Sona, which were high yielding and disease resistant, were introduced all over the wheat-growing belt of India.

Topic: Biology, Strategies for Enhancement in Food Production, NEET
In 1963, two enzymes responsible for restricting the growth of bacteriophage in E. coli were isolated. They were _____ and _____ respectively.

Options:
A Ligase, Restriction endonuclease
B Helicase, Restriction endonuclease
C Methylase, Restriction endonuclease
D DNA polymerase, Restriction endonuclease

The correct answer is:
Methylase, Restriction endonuclease

Solution:
The enzyme that restricted the growth of the bacteriophage is called a restriction enzyme. One of the enzymes was methylase which added methyl groups to the adenine base of the DNA thereby restricting or inhibiting the growth of bacteriophage.
Restriction endonuclease is enzymes that cut the DNA at specific sites and eliminating the foreign DNA or infecting organism.
These two groups of restriction enzymes were isolated from E. coli.

Topic: Biology, Biotechnology - Principles and Processes, NEET
In 1983, Eli lilly, an American company prepared two DNA sequences corresponding to A and B chains of human insulin and introduced them in plasmids of

A

to produce insulin chains. Chains A and B were produced separately extracted and combined by creating

B

to from human insulin.

Choose the option which correctly fills the blank marked as A and B in the given paragraph

Options:
A

a	b

E. coli	Hydrogen bond

B

a	b

E. coli	Phosphodiester bond

C

a	b

Ti plasmid	Disulphide bonds

D

a	b

E. coli	Disulphide bonds

The correct answer is:

a	b

E. coli	Disulphide bonds

Solution:
Active insulin has two polypeptide chains A and chain B, which are held together by disulphide. For insulin productions Eli Lilly an American company prepare two DNA sequence one for A chain and other for B chain. They ligate each chain with different plasmids and insert transformed plasmid in separate vectors, E.coli was used as vector system here.

Topic: Biology, Biotechnology and Its Applications, NEET
In 1984, Bhopal gas tragedy took place because methyl isocyanate

Options:
A Reacted with DDT
B Reacted with ammonia
C Reacted with CO2
D Reacted with water

The correct answer is:
Reacted with water

Solution:
In Bhopal gas tragedy methyl isocyanate (MIC) reacted with water to produce a large amount of heat, as it was an exothermic reaction. Due to this increase in pressure the safety valve of the tank bursted and the gas came out.

Topic: Biology, Environmental Issues, NEET
In 1984 , the Bhopal gas tragedy took place because methyl isocyanate:

Options:
A reacted with DDT
B reacted with ammonia
C reacted with $\mathrm{CO}_2$
D reacted with water.

The correct answer is:
reacted with water.

Solution:
The Bhopal gas tradegy happened because water entered a tank containing Methyl isocyanate This caused a chemical reaction which resulted in the build up of much Carbon dioxide, among other things. The resulting reaction increased the temperature inside the tank to reach over $200^{\circ} \mathrm{C}$.

Topic: Biology, Environmental Issues, NEET, NEET 2004
In 1997, the company that got patent rights on Basmati rice

Options:
A US Patent and Trademark Office
B Genetic engineering approval committee.
C Eli Lilly company
D None of these

The correct answer is:
US Patent and Trademark Office

Solution:
In 1997, an American company got patent rights on Basmati rice through the US Patent and Trademark Office. This allowed the company to sell a ânewâ variety of Basmati, in the US and abroad. This ânewâ variety of Basmati had actually been derived from Indian farmerâs varieties.

Topic: Biology, Biotechnology and Its Applications, NEET
In 2005, for each of the 14 million people present in a country, 0.028 were born and 0.008 died during the year. Using the exponential equation, the number of people present in 2015 is predicted as:

Options:
A 25 million
B 17 million
C 20 million
D 18 million

The correct answer is:
17 million

Solution:
The number of people present in 2015 is predicted as 17 million.

Topic: Biology, Organisms and Populations, NEET
In a 5-kingdom classification system, the kingdom that includes the phototrophs, chemotrophs, and heterotrophs, is ______.

Options:
A Animalia
B Fungi
C Protista
D Monera

The correct answer is:
Monera

Solution:
The five-kingdom classification proposed by R.H.Whittaker consisted of Monera, Protista, Fungi, Plantae, and Animalia. This classification was based on differentiating features like structure, body organization, mode of nutrition, phylogenetic relationships, and reproduction. Photautotrophs like blue-green algae were included in the kingdom Plantae, but in this classification has brought together all the prokaryotic organisms under the kingdom Monera, which also includes the heterotrophic bacteria like E. coli or pathogenic bacterias, and chemotrophic bacterias like Nitrosomonas, suplur-utilizing bacteria etc.

Topic: Biology, Biological Classification, NEET
In a 10 litre box 2.5 mole hydroiodic acid is taken. After equilibrium 2HIâH2+I2 the concentration of HI is found to be 0.1âmolâ L â1. The concentration of H2 at equilibrium in mol L-1, is

Options:
A 2.4
B 0.15
C 1.5
D 7.5×10-2

The correct answer is:
7.5×10-2

Solution:
0.25-2 at equilibrium
0.25-2x=0.1
x=7.5×10-2

Topic: Chemistry, Chemical Equilibrium, NEET
In a 20 × 20 × 1.5 km³ air space, ten small planes are flying at a speed of 150 km/h in total darkness. Assuming a safety region around each plane can be approximated by a sphere of radius 10m, what is the approximate average time between near collisions with your plane?

Options:
A 112.5 h
B 225 h
C 337.5 h
D 450 h

The correct answer is:
225 h

Solution:
Correct Option is : (B)
225 h

Topic: Chemistry, Kinetic Theory of Gases, NEET
In a basic medium, what is added to the equation to balance each H+ ion?

Options:
A OH-ions
B Cl- ions
C H2O molecules
D CO2 molecules

The correct answer is:
OH-ions

Solution:
In a basic medium, OH- ions are added to balance each H+ ion in the equation.

Topic: Chemistry, Redox Reactions, NEET
In a bimolecular elementary reaction A + B → Products, what does ZAB represent?

Options:
A The rate of reaction
B The activation energy (Ea)
C The collision frequency of reactants A and B
D The fraction of molecules with energies greater than Ea

The correct answer is:
The collision frequency of reactants A and B

Solution:
ZAB represents the collision frequency of reactants A and B in the bimolecular elementary reaction.

Topic: Chemistry, Chemical Kinetics, NEET
In a binary solution with a non-volatile solute, what is the proportionality constant in Raoult's law equal to?

Options:
A The mole fraction of the solute
B The vapor pressure of the solvent in the pure state
C The temperature of the solution
D The pressure of the surroundings

The correct answer is:
The vapor pressure of the solvent in the pure state

Solution:
According to Raoult's law, the proportionality constant is equal to the vapor pressure of the pure solvent in the pure state.

Topic: Chemistry, Solutions, NEET
In a bomb calorimeter, what is the purpose of immersing the steel vessel (bomb) in a water bath?

Options:
A To keep the bomb from exploding
B To ensure no heat is lost to the surroundings
C To increase the pressure inside the bomb
D To prevent the combustion reaction

The correct answer is:
To ensure no heat is lost to the surroundings

Solution:
Immersing the steel vessel in a water bath ensures that no heat is lost to the surroundings during the calorimetric measurement.

Topic: Chemistry, Thermodynamics (C), NEET
In a buffer solution consisting of a mixture of weak base and its salt, the ratio of salt to base is increases 10 times, the pOH of the solution will

Options:
A Increase by one units
B Decrease by one units
C Increase by ten untis
D Decrease by ten untis

The correct answer is:
Increase by one units

Solution:
pOH= pK a +log salt base
If the ratio [salt][base] is increased by 10 folds, then log 10 being 1, the pOH will increase by one unit.

Topic: Chemistry, Ionic Equilibrium, NEET
In a buffer solution containing equal concentration of $\mathrm{B}^{-}$and $\mathrm{HB}$, the $\mathrm{K}_{\mathrm{b}}$ for $\mathrm{B}^{-}$is $10^{-10}$. The $\mathrm{pH}$ of buffer solution is

Options:
A 10
B 7
C 6
D 4

The correct answer is:
4

Solution:
Key Idea (i) For basic buffer
$$
\mathrm{pOH}=\mathrm{pK}_{\mathrm{b}}+\log \frac{\text { [salt }]}{[\text { base }]}
$$
(ii) $\mathrm{pH}+\mathrm{pOH}=14$
Given, $\quad \mathrm{K}_{\mathrm{b}}=1 \times 10^{-10}$, [salt] = [base]
$$
\begin{aligned}
\mathrm{pOH} & =-\log \mathrm{K}_{\mathrm{b}}+\log \frac{[\text { salt }]}{[\text { base }]} \\
\therefore \quad \mathrm{pOH} & =-\log \left(1 \times 10^{-10}\right)+\log 1 \\
& =10 \\
\mathrm{pH}+\mathrm{pOH} & =14 \\
\mathrm{pH} & =14-10=4
\end{aligned}
$$

Topic: Chemistry, Ionic Equilibrium, NEET, NEET 2010 (Screening)
In a buffer solution containing equal concentrations of B- and HB the Kb for B- is 10-10 . The pH of buffer solution is

Options:
A 4
B 5
C 7
D 6

The correct answer is:
4

Solution:
For acidic buffer pH can be find out as follows
pH=pKa+log10[salt][acid]
Here Kb=10-10Ka=10-4,pKa=4
As pH=4+log10[B-][HB]
As [B-]=[HB]
pH=4+log1=4

Topic: Chemistry, Ionic Equilibrium, NEET
In a capillary tube experiment, a vertical 30 cm long capillary tube is dipped in water. The water rises up to a height of 10 cm due to capillary action. If water temperature increases, then the new height of water column in capillary becomes

Options:
A 30Â cm
B greater than 10Â cm
C equal to 10Â cm
D less than 10 cm

The correct answer is:
less than 10 cm

Solution:
As temperature increases, surface tension decreases ;
As h=2TRρg
∴h also decreases.

Topic: Physics, Mechanical Properties of Fluids, NEET
In a capillary tube having area of cross-section A, the water rises to a height h. If the cross-sectional area is reduced to A9, the rise of water in the capillary tube is

Options:
A 4h
B 3h
C 2h
D h

The correct answer is:
3h

Solution:
A 1 =Ï r 1 2
A 2 =Ï r 2 2
Ï r 1 2 9 =Ï r 2 2
r 1 2 r 2 2 =9â r 1 r 2 =3
rh= constant
r 1 h 1 = r 2 h 2
r 1 r 2 = h 2 h 1
3= h 2 h 1 = h 2 h 1
h 2 =3 h 1 =3h

Topic: Physics, Mechanical Properties of Fluids, NEET
In a capillary tube of radius R, a straight thin metal wire of radius r (R > r) is inserted symmetrically and one end of the combination is dipped vertically in water such that the lower end of the combination is at same level. The rise of water in the capillary tube is

[ T= surface tension of water, Ï = density of water, g = gravitational acceleration]

Options:
A TR+rρg
B 2TR+rρg
C 2TR-rρg
D R-rρgT

The correct answer is:
2TR-rρg

Solution:
h=2TcosθρgR-r
For cos⁡ θ=0, h=2TρgR-r

Topic: Physics, Mechanical Properties of Fluids, NEET
In a capillary tube, the water rises to a height of 4 cm. If the cross-sectional area of the tube were one-fourth, water would have risen to a height of

Options:
A 2 cm
B 4 cm
C 8 cm
D 16 cm

The correct answer is:
8 cm

Solution:
h=2Tcos⁡θrdg
⇒ r1h1=r2h2
and A=2πr2
⇒ rαA
∴ A1h1=A2h2
⇒ A×4=A4×h2
⇒ h2=8 cm

Topic: Physics, Mechanical Properties of Fluids, NEET
In a Carnot engine, the temperature of the reservoir is 927 Â°C and that of sink is 127 Â°C. If the work done by the engine when it transfers heat from the reservoir to sink is 12.6Ã106 J, the quantity of heat absorbed by the engine from the reservoir is

Options:
A 18.9×106 J
B 20.5×106 J
C 15.7×106 J
D 12.6×106 J

The correct answer is:
18.9×106 J

Solution:
Given, T1=273+927=1200 K
T2=273+127=400 K
and W=12.6×106 J
We know, the efficiency of a Carnot engine,
η=1-T2T1, where T2<T1
η=1-4001200=1-13=23
and η=Work done (W)Heat supplied(Q)
23=12.6×106Q
⇒Q=12.6×1062×3
=18.9×106 J

Topic: Physics, Thermodynamics, NEET
In a Carnot engine, when T2=0 â and T1=200 â, its efficiency is Î·1 and when T1=0 â and T2=-200 â its efficiency is Î·2, then the ratio of efficiencies is

Options:
A 0.577
B 0.733
C 0.638
D Cannot be calculated

The correct answer is:
0.577

Solution:
The efficiency η of Carnot engine is defined as the amount of work divided by the heat transferred between the system and the hot reservoir.
η=ΔWΔQH=1-Tc TH
Where, TC and TH are temperatures of cold and hot junctions respectively.
Ist case T2=0 ℃=0+273=273 K
T1=200 ℃=200+273=473 K
∴ η1=1-273473=200473=0.4228≈0.423 ...(i)
IInd case
T2=-200 ℃=-200+273=73 K
T1=0 ℃=0+273=273 K
η2=1-T2T1=1-73273=200273=0.732 ...(ii)
From Eqs. (i) and (ii), we get
η1η2=0.4230.732≈0.577

Topic: Physics, Thermodynamics, NEET
In a Carnot's cycle operating between reservoir temperatures T1= 500K and T2=300K, and producing 1 kJ of mechanical work per cycle, what is the heat transferred to the engine by the reservoirs?

Options:
A 1000 J
B 1200 J
C 1500 J
D 1800 J

The correct answer is:
1500 J

Solution:
Correct Option is : (C)
1500 J

Topic: Chemistry, Thermodynamics, NEET
In a CE transistor amplifier, the audio signal voltage across the collector resistance of $2 \mathrm{k} \Omega$ is $2 \mathrm{~V}$. If the base resistance is $1 \mathrm{k} \Omega$ and the current amplification of the transistor is 100 , the input signal voltage is

Options:
A $0.1 \mathrm{~V}$
B $1.0 \mathrm{~V}$
C $1 \mathrm{mV}$
D $10 \mathrm{mV}$

The correct answer is:
$10 \mathrm{mV}$

Solution:
Current amplification factor
$\beta=\frac{\Delta I_C}{\Delta I_B}$
Collector resistance
$\Delta I_C=\frac{2 \mathrm{~V}}{2 \times 10^3 \Omega}=1 \times 10^{-3} \mathrm{~A}$
Base current
$\Delta I_B=\frac{V_B}{R_B}=\frac{V_B}{1 \times 10^3}=V_B \times 10^{-3}$
Given, $\beta=100$
Now, $100=\frac{10^{-3}}{V_B \times 10^{-3}}$
$V_B=\frac{1}{100} \mathrm{~V}=10 \mathrm{mV}$

Topic: Physics, Semiconductors, NEET, NEET 2012 (Screening)
In a CE transistor amplifier, the audio signal voltage across the collector resistance of 2KΩ is 2V. if the base resistance is 1KΩ and the current amplification of the transistor is 100 the input signal voltage is

Options:
A 1 mV
B 10 mV
C 0.1 V
D 1 V

The correct answer is:
10 mV

Solution:
We know that Voltage amplification is given by :
V0Vin=Î²RLRi ;2Vm=1002Ã1031Ã103

Topic: Physics, Semiconductors, NEET
In a CE transistor amplifier, there is both current and voltage gain associated with the circuit, resulting in a power gain. Considering power as a measure of energy, does the circuit violate the conservation of energy?

Options:
A Yes, the additional power is generated within the circuit.
B No, the extra power required for the amplified output is obtained from the DC source.
C Yes, the circuit converts energy into matter, violating conservation laws.
D No, the power gain is a result of the efficient use of input energy.

The correct answer is:
No, the extra power required for the amplified output is obtained from the DC source.

Solution:
Correct Option is : (B)
No, the extra power required for the amplified output is obtained from the DC source.

Topic: Chemistry, Semiconductors, NEET
In a cereal grain, the single cotyledon of an embryo is represented by the

Options:
A coleoptile
B coleorhiza
C prophyll
D scutellum

The correct answer is:
scutellum

Solution:
The cotyledons are known as seed leaves, they are attached to the embryonic axis. Dicotyledons typically have two cotyledons & monocotyledons have only one cotyledon. The single shield shaped cotyledon in grains is known as scutellum.
The scutellum does not contain food & its function is to absorb food from the endosperm & transfer it to the growing parts of the embryo. The plumule consists of growing tip of the shoot along with few young leaf primordia.
It is covered by a sheath called coleoptile. The radicle which lies at the base of the grain is also covered with a sheath called coleorhiza. The hypocotyl is very short & is represented by a short axis in between radicle And plumule.

Topic: Biology, Sexual Reproduction in Flowering Plants, NEET
In a cereal grain the single cotyledon of embryo is represented by:

Options:
A coleoptile
B coleorhiza
C scutellum
D prophyll

The correct answer is:
scutellum

Solution:
In a cereal grain (e.g., wheat), the single cotyledon of embryo is represented by the scutellum. Scutellum is specialized for nutrient absorption from the endosperm. Coleoptile is a modified ensheathing leaf that covers and protects the young primary leaves of a grass seedling. Coleorhiza is a sheath like structure found on the radicle which covers and protects it during the growth into the soil.
Related Theory
The scutellum is a modified cotyledon, or seed leaf in grasses which never develops into a green structure but serves only to digest endosperm and transfer nutrients to the rest of the embryo. Scutellum is diploid while endosperm is triploid.

Topic: Biology, Sexual Reproduction in Flowering Plants, NEET, NEET 2006
In a certain plant, yellow fruit colour (Y) is dominant to green fruit colour (y) and round shape (R) is dominant to oval shape (r). The two genes involved are located on different chromosomes. Identify the outcome of this particular cross when a plant with genotype YyRr is back-crossed with the double recessive parent?

Options:
A 9:3:3:1 ratio of phenotypes only
B 9:3:3:1 ratio of genotypes only
C 1:1:1:1 ratio of phenotypes only
D 1:1:1:1 ratio of phenotypes and genotypes

The correct answer is:
1:1:1:1 ratio of phenotypes and genotypes

Solution:
When YyRr is crossed with a double recessive parent then genotypic and phenotypic ratio will be 1:1:1:1 .
Phenotypic ratio =1 yellow round: 1 yellow oval: 1 green round: 1 green and oval. This represents a test cross.

Topic: Biology, Principles of Inheritance and Variation, NEET
In a certain region of space with volume 0.2 m3, the electric potential is found to be 5 V throughout. The magnitude of electric field in this region is:

Options:
A 0.5 N C-1
B 1 N C-1
C 5 N C-1
D zero

The correct answer is:
zero

Solution:
We know that electric field and potential are related as

E=-dVdx

Potential is constant throughout the volume
∴ Electric field is zero.

Topic: Physics, Electrostatics, NEET, NEET 2020 (Phase 1)
In a certain region, uniform electric field E and magnetic field B are present in the opposite direction. A particle of mass m and of charge q enters in this region with a velocity v at an angle θ from the magnetic field. The time after which the speed of the particle would be minimum is equal to

Options:
A 2πmBq
B mvsin⁡θqE
C mvcos⁡θqE
D mvqE

The correct answer is:
mvcos⁡θqE

Solution:
The charges experiences a retarding force F=qE along x-axis
Retardation =qEm.
It is clear that the speed of the particle will be minimum when its component of velocity is along the direction of electric field.
Then, using the equation of motion,
v=u+at
â 0=vcosâ¡Î¸-qEmt
â t=mvcosâ¡Î¸qE

Topic: Physics, Magnetic Effects of Current, NEET