datavorous/entrance-exam-dataset huggingface dataset:
The diagram shows the effect of an enzyme working in the human digestive system.

What would reduce the rate of production of amino acids?

Options:
A removing the amino acids as they are formed
B increasing the amount of protein
C raising the temperature to 37.1 °C
D raising the pH to 4.5

The correct answer is:
raising the pH to 4.5

Solution:
The given enzyme is pepsinogen which is a proteolytic enzyme in the stomach. The activity of an enzyme can be affected by a change in the conditions which can alter the tertiary structure of the protein. Enzymes generally function in a narrow range of temperature and pH. Each enzyme shows its highest activity at a particular temperature and pH called the optimum temperature and optimum pH.

Topic: Biology, Digestion and Absorption, NEET
The diagram shows the relationship between some biological molecules.

Which row is correct for this relationship?

1	2	3	4	5

A	Glucose	Carbohydrate	Sucrose	Monomer	Fructose

B	Cellulose	Polymer	Starch	Carbohydrate	Amylase

C	Fructose	Reducing sugar	Glucose	Monomer	Amino acid

D	Haemoglobin	Protein	Amylose	Polymer	Cellulose

Options:
A A
B B
C C
D D

The correct answer is:
C

Solution:
Fructose and glucose are reducing sugar turning benedict solution from blue towards red.
Amino acid with glucose act as a monomer for making polypeptide and polysaccharides respectively.

Topic: Chemistry, Biomolecules, NEET
The diagram shows the structure of a bacterial cell.

The presence of structure X in the bacterial cell is one reason why bacteria are used in genetic engineering.
In the cloning vector pBR322, which gene is responsible for the replication of structure X?

Options:
A Cla I
B BamH I
C ori
D rop

The correct answer is:
rop

Solution:
A plasmid is the extrachromosomal DNA found in bacteria which forms an important tool in easy gene manipulation and vector for carrying the gene of interest for transmission and expression. Structure X is a plasmid.
In the E. coli cloning vector, rop codes for the proteins involved in the replication of the plasmid.
BamHI and ClaI are restriction sites on the vector, while ori stands for the origin of replication site.

Topic: Biology, Biotechnology - Principles and Processes, NEET
The diagram/flow chart represents which of the sedimentary biogeochemical cycle?

Options:
A Nitrogen cycle
B Phosphorus cycle
C Oxygen cycle
D Sulphur cycle

The correct answer is:
Phosphorus cycle

Solution:
Biogeochemical cycles are of two types:
(a) Gaseous: Biogenetic materials involved in circulation are gases eg. N2,O2,CO2 etc.
(b) Sedimentary: Biogenetic materials involved in circulation are non-gaseous eg. P2, Ca, S, etc forms rocks.
The flow chart represents the phosphorus biogeochemical cycle occurring in a terrestrial ecosystem. The phosphorus cycle is a sedimentary cycle and its reservoir pool is lithosphere.

Topic: Biology, Ecosystem, NEET
The diagrams below show regions of equipotential.
A positive charge is moved from A to B in each diagram.

Options:
A Maximum work is required to move q in figure (c).
B In all the four cases the work done is the same.
C Minimum work is required to move q in figure (a).
D Maximum work is required to move q in figure (b).

The correct answer is:
In all the four cases the work done is the same.

Solution:
Work done, W=qΔV.
ΔV is same in all the cases so work is done will be same in all the cases.

Topic: Physics, Electrostatics, NEET, NEET 2017
The diagrams show the structures of two amino acids, each of which has two amine -NH2 groups.

A peptide bond is formed between the two amino acids. Which groups could form the peptide bond?

Options:
A 1 and 4
B 2 and 4
C 2 and 6
D 3 and 5

The correct answer is:
2 and 4

Solution:
Proteins are polypeptides. They are linear chains of amino acids linked by peptide bonds. Amino acids join to form polypeptides. The carboxyl group of one molecule reacts with the amino group of the other molecule, releasing a molecule of water. One of the participating amino acid loses a hydroxyl (-OH) group from its carboxylic acid group (-COOH), while the other loses a hydrogen atom from its amine group. This leaves a carbon atom of the first amino acid free to bond with the nitrogen atom of the second and resulting link formed is called a peptide bond.

Topic: Chemistry, Biomolecules, NEET
The dialysing unit (artificial kidney) contains a fluid which has a similar composition to plasma, except it has _____________. Such a setup is used as the cure for ___________.

Options:
A high glucose; nephritis
B high amino acids; renal failure
C no urea; uremia
D no uric acid; renal calculi

The correct answer is:
no urea; uremia

Solution:
Artificial kidney is a machine that is used for filtration of blood in the people whose kidneys fail or are damaged. This process is known as Dialysis. This machine contains Dialysing fluid. This fluid is produced by blending of treated water with electrolytes. The composition of the dialysing fluid should be the same as that of plasma except for the nitrogenous waste i.e. urea.

Topic: Biology, Excretory Products and their Elimination, NEET
The diameter of a flywheel is increased by 1%. Increase in its moment of inertia about the central axis is

Options:
A 1%
B 0.5%
C 2%
D 4%

The correct answer is:
2%

Solution:
I=MR2 â´ logâ¡I=logâ¡M+2logâ¡R
Differentiating, we get dII=0+2dRR
â´ dIIÃ100=2dRRÃ100
=2Ã1100Ã100=2%

Topic: Physics, Rotational Motion, NEET
The diameter of a spherical bob, when measured with vernier callipers yielded the following values: $3.33 \mathrm{~cm}$, $3.32 \mathrm{~cm}, 3.34 \mathrm{~cm}, 3.33 \mathrm{~cm}$ and $3.32 \mathrm{~cm}$.
The mean diameter to appropriate significant figures is:

Options:
A $3.33 \mathrm{~cm}$
B $3.32 \mathrm{~cm}$
C $3.328 \mathrm{~cm}$
D $3.3 \mathrm{~cm}$

The correct answer is:
$3.33 \mathrm{~cm}$

Solution:
$\begin{aligned} \text { Mean diameter } & =\frac{[3.33 \mathrm{~cm}+3.32 \mathrm{~cm}+3.34 \mathrm{~cm}+3.33 \mathrm{~cm}+3.32 \mathrm{~cm}]}{5} \\ & =3.328 \mathrm{~cm}\end{aligned}$
After rounding off to 2 decimal places.
Final mean diameter $=3.33 \mathrm{~cm}$

Topic: Physics, Mathematics in Physics, NEET, NEET 2023 (Manipur)
The diameter of a zinc atom is 2.6 Å.Calculate the number of atoms present in a length of 1.6 cm if the zinc atoms are arranged side by side lengthwise.

Options:
A 6.15 × 107
B 7.52 × 107
C 4.21 × 107
D 3.96 × 107

The correct answer is:
6.15 × 107

Solution:
Correct Option is : (A)
6.15 × 107

Topic: Chemistry, Structure of Atom, NEET
The diameter of the lens of a telescope is 0.61 m and the wavelength of light used is 5000 â«. The resolution power of the telescope is

Options:
A 2×106
B 106
C 2×104
D 2×102

The correct answer is:
106

Solution:
Resolving power 1dθ=D1.22λ
=0.611.22×5000×10-10
=106

Topic: Physics, Wave Optics, NEET
The diameter of zinc atom is 2.6 Å.Calculate radius of zinc atom in pm

Options:
A 150 pm
B 145 pm
C 130 pm
D 128 pm

The correct answer is:
130 pm

Solution:
Correct Option is : (C)
130 pm

Topic: Chemistry, Structure of Atom, NEET
The difference between amylose and amylopectin is

Options:
A Amylopectin have 1â4 Î± -linkage and 1â6 Î² -linkage
B Amylose have 1â4 Î± -linkage and 1â6 Î² -linkage
C Amylopectin have 1â4 Î± -linkage and 1â6 Î± -linkage
D Amylose is made up of glucose and galactose

The correct answer is:
Amylopectin have 1â4 Î± -linkage and 1â6 Î± -linkage

Solution:
Amylose and amylopectin are polymers of Î± - D- glucose, so Î² -link is not possible. Amylose is linear with 1â4 Î± -linkage whereas Amylopectin is branched and has both 1â4 (for linear chain) and 1â6 Î± -linkages (for branching).

Topic: Chemistry, Biomolecules, NEET
The difference between CPand CVcan be derived using the empirical relation H = U + pV. Calculate the difference between CPand CVfor 10 moles of an ideal gas.

Options:
A 10R
B 15R
C 8R
D 12R

The correct answer is:
10R

Solution:
Correct Option is : (A)
10R

Topic: Chemistry, Thermodynamics (C), NEET
The difference between C-p and C-v is
[ C-p and C-v signify molar quantities]

Options:
A larger in case of gases in comparison to solids and liquids
B larger in case of liquids in comparison to gas and solids
C larger in case of solids in comparison to gas and liquids
D equal in solids, liquids and gaes

The correct answer is:
larger in case of gases in comparison to solids and liquids

Solution:
Both for liquids and solids there is no appreciable difference between Cp and Cv because change in volume for solids and liquids is very small.

Topic: Chemistry, Thermodynamics (C), NEET
The difference between heat of reaction and change in internal energy at constant volume for the reaction given below at 25oC in kJ is

2 C 6 H 6 l +15 O 2 g →12 CO 2 g +6 H 2 O l

Options:
A -7.43
B +3.72
C -3.72
D +7.43

The correct answer is:
-7.43

Solution:
Δ H⁡ = Δ E⁡ + Δ n g RT
Δ H⁡ - Δ E⁡ = Δ n g RT = 1 2 - 1 5 × 8.3 1 4 × 2 9 8
= - 7.4 3 2 k J

Topic: Chemistry, Thermodynamics (C), NEET
The difference between heats of reaction at constant pressure and constant volume for the reaction,
2C6H6(l)+15O2(g)→12CO2(g)+6H2O(l) at 25°C in kJ is

Options:
A +7.43
B -3.72
C +3.72
D -7.43

The correct answer is:
-7.43

Solution:
În g =12â15=â3
ÎH=ÎE+ În g RT
or ÎHâÎE= În g RT
=â3Ã8.314â Jmol â1 K â1 Ã298 K
=-7.43 kJmol-1 .

Topic: Chemistry, Thermodynamics (C), NEET
The difference between heats of reaction at constant pressure and constant volume for the reaction,
2C6H6(l)+15O2(g)→12CO2(g)+6H2O(l) at 25°C in kJ is

Options:
A -7.43
B +3.72
C -3.72
D +7.43

The correct answer is:
-7.43

Solution:
ÎH-ÎE=ÎngRT
Îng=12-15=-3
So ΔH−ΔE = −3 × 8.314 J  mol −1   K −1  × 298 K
=â7.43âkJâ mol â1

Topic: Chemistry, Thermodynamics (C), NEET
The difference between kinetic energies of photoelectrons emitted from a surface by the light of wavelength 2500 Aâ and 5000 Aâ will be

Options:
A 1.61 eV

B 2.47 eV
C 3.96 eV
D 3.96Ã10-19eV

The correct answer is:
2.47 eV

Solution:
ÎE=hcÎ»1-hcÎ»2=hc(Î»2-Î»1)Î»1Î»2 (in eV)
=6.62Ã10-34Ã3Ã108Ã(5000-2500)Ã10-102500Ã5000Ã10-20Ã1.6Ã10-19
=2.47 eV

Topic: Physics, Dual Nature of Matter, NEET
The difference between spermiogenesis and spermiation is

Options:
A In spermiogenesis spermatozoa from sertoli cells are release into the cavity of seminiferous tubules, while in spermiation spermatozoa are formed
B In spermiogenesis spermatozoa are formed, while in spermiation spermatids are formed
C In spermiogenesis spermatids are formed, while spermiation spermatozoa are formed
D In spermiogenesis spermatozoa are formed, while in spermiation spermatozoa are released from sertoli cells into the cavity of seminiferous tubules

The correct answer is:
In spermiogenesis spermatozoa are formed, while in spermiation spermatozoa are released from sertoli cells into the cavity of seminiferous tubules

Solution:
Spermiogenesis is the final stage of spermatogenesis, which sees the maturation of spermatids into mature, motile spermatozoa. The spermatid is a more or less circular cell containing a nucleus, Golgi apparatus, centriole, and mitochondria. All these components take part in forming the spermatozoon.

However, in spermiation, the spermatozoa are released from the Sertoli cells into the cavity of seminiferous tubules before they are passed through the epididymis.

Topic: Biology, Human Reproduction, NEET, NEET 2018
The difference between systolic and diastolic pressure in human is

Options:
A 120 mm Hg
B 80 mm Hg
C 40 mm Hg
D 200 mm Hg

The correct answer is:
40 mm Hg

Solution:
Systolic blood pressure = 120 mm Hg
Diastolic blood pressure = 80 mm Hg
â´ Difference between systolic and diastolic blood pressure
= 120 - 80 = 40 mm Hg

Topic: Biology, Body Fluids and Circulation, NEET
The difference between U235 and U238 atom is that

Options:
A U238contains 3 more protons
B U238contains 3 protons and 3 more electrons
C

U238contains 3 more neutrons and 3 more electrons

D U238contains 3 more neutrons

The correct answer is:
U238contains 3 more neutrons

Solution:
As charge number is fixed (92), therefore, number of protons and electrons is the same. As atomic weight is greater by 3, therefore 92U238 contains 3 more neutrons.

Topic: Physics, Nuclear Physics, NEET
The difference between xylem of angiosperms and gymnosperms is that, in gymnosperms

Options:
A Vessels are present
B Vessels are absent
C Tracheids are absent
D Tracheids are present

The correct answer is:
Vessels are absent

Solution:
Gymnosperms are non-flowering, seed-bearing plants. Vascular bundles are present in the Gymnosperms but vessels are absent in the xylem and the phloem lacks the companion cells. Presence of vessels in xylem makes is more efficient conducting system.

Topic: Biology, Anatomy of Flowering Plants, NEET
The difference in the variation of resistance with temperature in a metal and a semiconductor arises essentially due to the difference in the

Options:
A crystal structure
B variation of the number of charge carriers with temperature
C type of bonding
D variation of scattering mechanism with temperature

The correct answer is:
variation of the number of charge carriers with temperature

Solution:
Variation of the number of charge carriers with temperature is responsible for the variation of resistance in a metal and a semiconductor.

Topic: Physics, Semiconductors, NEET
The difference shown in the morphology of leaf during the developmental stages will be in

Options:
A Cotton and brinjal
B Cotton and Larkspur
C Brinjal and tomato
D Larkspur and mango

The correct answer is:
Cotton and Larkspur

Solution:
Plasticity is an ability of the plants to modify their structural and physiological properties in response to the environmental conditions. Heterophylly is one such example, where the shape of the leaves of the plants are different in juvenile stage and different in their mature stage. The examples of such plasticity is cotton, larkspur and coriander.

Topic: Biology, Plant - Growth and Development, NEET
The different gametes produced by an individual with the genotype of aaBBCc are:

Options:
A 2
B 8
C 4
D 6

The correct answer is:
2

Solution:
Gametes are reproductive cells produced by the organism by meiosis. Each gamete cell contains half the genetic content and combination of the organism's genome. For the genotype aaBBCc, the type of gametes it will make are aBC and aBc. Thus, only two.

Topic: Biology, Principles of Inheritance and Variation, NEET
The differential rate law for the reaction,

4NH3g+5O2g→4NOg+6H2O(g)

Options:
A -dNH3dt=-dO2dt=-dNOdt=-d[H2O]dt
B dNH3dt=dO2dt=-14dNOdt=-16d[H2O]dt
C 14dNH3dt=15dO2dt=14dNOdt=16d[H2O]dt
D -14dNH3dt=-15dO2dt=14dNOdt=16d[H2O]dt

The correct answer is:
-14dNH3dt=-15dO2dt=14dNOdt=16d[H2O]dt

Solution:
The differential rate law for the reaction,
4NH3g+5O2g→4NOg+6H2O(g) is
Rate=-14dNH3dt=-15dO2dt
=+14dNOdt=+16d[H2O]dt

Topic: Chemistry, Chemical Kinetics, NEET
The dimension of $\frac{1}{2} \varepsilon_0 \mathrm{E}^2$, where $\varepsilon_0$ is permittivity of free space and $E$ is electric field, is

Options:
A $\left[\mathrm{ML}^2 \mathrm{~T}^{-2}\right]$
B $\left[\mathrm{ML}^{-1} \mathrm{~T}^{-2}\right]$
C $\left[\mathrm{ML}^2 \mathrm{~T}^{-1}\right]$
D $\left[\mathrm{MLT}^{-1}\right]$

The correct answer is:
$\left[\mathrm{ML}^{-1} \mathrm{~T}^{-2}\right]$

Solution:
$$
\begin{aligned}
& \text { Dimensions of } \varepsilon_0=\left[\mathrm{M}^{-1} \mathrm{~L}^{-3} \mathrm{~T}^4 \mathrm{~A}^2\right] \\
& \text { Dimensions of } \mathrm{E}=\left[\mathrm{MLT}^{-3} \mathrm{~A}^{-1}\right] \\
& \therefore \text { Dimensions of } \frac{1}{2} \varepsilon_0 \mathrm{E}^2=\left[\mathrm{M}^{-1} \mathrm{~L}^{-3} \mathrm{~T}^4 \mathrm{~A}^2\right] \\
& \quad=\left[\mathrm{ML}^{-1} \mathrm{~T}^{-3}\right] \quad \times\left[\mathrm{M}^2 \mathrm{~L}^2 \mathrm{~T}^{-6} \mathrm{~A}^{-2}\right]
\end{aligned}
$$

Topic: Physics, Units and Dimensions, NEET, NEET 2010 (Screening)
The dimensional formula for entropy is

Options:
A [MLT-2K-1]
B [ML2T-2]
C [ML2T-2K-1]
D [ML-2T-2K-1]

The correct answer is:
[ML2T-2K-1]

Solution:
Entropy=heattemperature ( ΔQ=TΔS )
[Entropy]=QT=[ML2T-2][K]=[ML2T-2K-1]

Topic: Physics, Units and Dimensions, NEET
The dimensional formula for permittivity of free space ε0 in the equation F=14πε0q1q2r2 , where symbols have their usual meaning, is

Options:
A M1 L3 A-2 T-4
B M-1 L-3 T4 A2
C M-1 L-3 A-2 T-4
D M1 L3 T2 A-4

The correct answer is:
M-1 L-3 T4 A2

Solution:
As, F= 1 4π ε 0 q 1 q 2 r 2
⇒ ε 0 = q 1 q 2 4πF r 2
=TA2L2MLT-2
=M-1L-3 T4A2

Topic: Physics, Units and Dimensions, NEET
The dimensional formula for the magnetic field is

Options:
A MT-2A-1
B ML2T-1A-2
C MT-2A-2
D MT-1A-2

The correct answer is:
MT-2A-1

Solution:
Magnetic field =ForceCharge × velocity
=MLT-2ATLT-1=MA-1T-2

Topic: Physics, Units and Dimensions, NEET
The dimensional formula of Î¼ 0 Îµ 0 is

Options:
A M0L-2T2
B M0L2T-2
C M0L1T-1
D M0L-1T1

The correct answer is:
M0L-2T2

Solution:
C= 1 μ 0 ε 0 ⇒ μ 0   ε 0 = 1 C 2
C→M0L1T-1
⇒ 1C2→M0L-2T2

Topic: Physics, Units and Dimensions, NEET
The dimensional formula of 1μ0∈0 is .............

Options:
A M0L2T-2
B M0L1T-1
C M0L-2T-2
D M0L1T-2

The correct answer is:
M0L2T-2

Solution:
c=1Î¼0â0

or c2=1Î¼0â0

The dimensional formula is, 1Î¼0â0=M0L2T-2

Topic: Physics, Units and Dimensions, NEET
The dimensional formula of magnetic flux is

Options:
A M L 2 T - 2 A -1
B L M 2 T - 2 A -1
C M L 2 T - 1 A -2
D M L -1 T - 2 A -1

The correct answer is:
M L 2 T - 2 A -1

Solution:
The magnetic flux linked with a surface,
ϕ=BAcosθ
Since B=F/q⁡v⁡,
ϕ=F⁡q⁡v⁡Acosθ=FI×tv⁡Acosθ
⇒ MLT-2L2ATLT-1=ML2T-2A-1

Topic: Physics, Electromagnetic Induction, NEET
The dimensional formula of magnetic flux is

Options:
A [ML0T−2A−1]
B [ML2T−2A−1]
C [ML2T−1A3]
D [ML−2T−2A−2]

The correct answer is:
[ML2T−2A−1]

Solution:
According to Faraday’s law of electro-magnetic induction, E.M.F = (dϕ/dt)
So [ϕ]=[EMF][T]=[W/q][T]
i.e., [ϕ]=[ML2T−2/AT][T]=[ML2T−2A−1]
and its unit will be volt ×  s, known as weber Wb

Topic: Physics, Units and Dimensions, NEET
The dimensional formula of magnetic induction B is

Options:
A [M0ALT0]
B [M0AL-1T0]
C [M0AL2T0]
D [ML0T-2A-1]

The correct answer is:
[ML0T-2A-1]

Solution:
Fm=Bqv
or B=Fmqv=FmItv
=MLT-2AT[LT-1]=[ML0T-2A-1]

Topic: Physics, Units and Dimensions, NEET
The dimensional formula of magnetic permeability is

Options:
A [M0L-1T]
B [M0L2T-1]
C [M0L2T-1A2]
D [MLT-2A-2]

The correct answer is:
[MLT-2A-2]

Solution:
Fl=μ0I1I22πr
Or μ0=[F][I1I2]=[MLT-2][A2]=[MLT-2A-2].

Topic: Physics, Units and Dimensions, NEET
The dimensional formula of Planckâs constant is

Options:
A [M L â3 T â1 ]
B [M L −2 T −1 ]
C [ M 0 L −1 T −3 ]
D [M L 2 T −1 ]

The correct answer is:
[M L 2 T −1 ]

Solution:
According to Planck:
E=hv
h= E v
Substituting the dimensions of known physical quantities:
ââââââ[ h ]= [ M L 2 T â2 ] [ T â1 ] orââ[ h ]=M L 2 T â1
So, SI unit or Planckâs constant is kg m2sâ1 which can also be written as
( kgââ m 2 â s â2 )Ãs . But as kgââ m 2 â s â2 is joule, so unit of h is jouleââÃââsec , i.e., Js.

Topic: Physics, Units and Dimensions, NEET
The dimensions MLTA-2-2 belong to the

Options:
A self inductance
B magnetic permeability
C electric permittivity
D magnetic flux

The correct answer is:
magnetic permeability

Solution:
Force, F=q1q24πε0r2 or ε0=q1q24πr2F

Charge = current × time

Force = mass × acceleration

Thus, dimensional formula of electric permittivity,

ε0=ITITL2MLT-2=M-1L-3T4I2

Since speed of light, c=1ε0μ0

Therefore, dimensional formula of magnetic permeability, μ0=1c2ε0=1L2T-2M-1L-3T4I2

⇒μ0=MLT-2I-2

Topic: Physics, Units and Dimensions, NEET, NEET 2022 (Phase 1)
The dimensions of $\left(\mu_0 \varepsilon_0\right)^{-1 / 2}$ are

Options:
A $\left[\mathrm{L}^{-1} \mathrm{~T}\right]$
B $\left[\mathrm{LT}^{-1}\right]$
C $\left[\mathrm{L}^{-1 / 2} \mathrm{~T}^{1 / 2}\right]$
D $\left[\mathrm{L}^{1 / 2} \mathrm{~T}^{-1 / 2}\right]$

The correct answer is:
$\left[\mathrm{LT}^{-1}\right]$

Solution:
This expression for speed of light and the dimensions of speed of light are $\left[\mathrm{LT}^{-1}\right]$.

Topic: Physics, Units and Dimensions, NEET, NEET 2011 (Screening)
The dimensions of e⁡ 2 / 4 π ε 0 hc⁡, where e,⁡ ε 0,h⁡ and c⁡ are electronic charge, electric permittivity, Planck's constant and velocity of light in vacuum respectively, are

Options:
A M0L0T0
B ML0T0
C M0LT0
D M0L0T1

The correct answer is:
M0L0T0

Solution:
The dimension of y=e24πε0hc
Putting the dimensions of
e=Q=AT
ε0=M-1L-3T4A2, h=ML2T-1, c=LT-1
y=A2T2M-1L-3T4A2ML2T-1LT-1
y=M0L0T0

Topic: Physics, Units and Dimensions, NEET
The dimensions of the coefficient of self-inductance are

Options:
A ML2T-2A-2
B ML2T-2A-1
C MLT-2A-2
D MLT-2A-1

The correct answer is:
ML2T-2A-2

Solution:
Energy U=12LI2
⇒ L=2UI2
∴L=UI2=ML2T-2A2=ML2T-2A-2

Topic: Physics, Units and Dimensions, NEET
The dimensions of the ratio of magnetic flux ϕ and permeability μ are

Options:
A M0L1T0A1
B M0L-3T0A1
C M0L1T1A-1
D M0L2T0A1

The correct answer is:
M0L1T0A1

Solution:
Dimensions of magnetic flux,
ϕ=ML2T-2A-1
Dimensions of permeability, μ=ML T-2A-2
∴ ϕμ=ML2T-2A-1MLT-2A-2
=M0L1T0A1

Topic: Physics, Units and Dimensions, NEET
The dimensions of universal gravitational constant are:

Options:
A $\left[\mathrm{M}^{-1} \mathrm{~L}^3 \mathrm{~T}^{-2}\right]$
B $\left[\mathrm{ML}^2 \mathrm{~T}^{-1}\right]$
C $\left[\mathrm{ML}^{-2} \mathrm{~L}^3 \mathrm{~T}^{-2}\right]$
D $\left[\mathrm{ML}^{-2} \mathrm{~L}^2 \mathrm{~T}^{-1}\right]$

The correct answer is:
$\left[\mathrm{M}^{-1} \mathrm{~L}^3 \mathrm{~T}^{-2}\right]$

Solution:
$\begin{aligned}
F & =\frac{\mathrm{GMm}}{R^2} \\
\Rightarrow \mathrm{G}=\frac{F R^2}{M m} & =\frac{\left[\mathrm{MLT}^{-2}\right]\left[\mathrm{L}^2\right]}{\left[\mathrm{M}^2\right]} \\
& =\left[\mathrm{M}^{-1} \mathrm{~L}^3 \mathrm{~T}^{-2}\right]
\end{aligned}$

Topic: Physics, Units and Dimensions, NEET, NEET 2004
The diode used in the circuit, shown in the figure, has a constant voltage drop of 0.5 V at all currents and a maximum power rating of 100 milliwatts. The value of the resistor R, connected in series with the diode, for obtaining maximum current is

Options:
A 1 . 5 Ω
B 5 Î©
C 6 . 6 7 5 Ω
D 2 0 0 Ω

The correct answer is:
5 Ω

Solution:
Pmax=VImax â Imax=PV=1000.5Ã10-3
Imax = 1 5 A
Imax = V net R net = 1 . 5 - 0 . 5 R = 1 R
â R = 5

Topic: Physics, Semiconductors, NEET
The dipole moment of H2O2 is more than that of H2O but H2O2 is not a good solvent because

Options:
A It has a very high dielectric constant so that ionic compounds cannot be dissolved in it
B It does not act as an oxidising agent
C It acts as a reducing agent
D It dissociates easily and acts as an oxidising agent in chemical reactions

The correct answer is:
It dissociates easily and acts as an oxidising agent in chemical reactions

Solution:
The dipole moment of H2O2 is more than that of H2O but H2O2 is not a good solvent because H2O2 is thermally unstable and it decomposes easily.
H2O2lâH2O l+12O2g
Its decomposition is catalysed by alkali metals present in traces in the glass the vessel.

Topic: Chemistry, s Block Elements, NEET
The dipole moment of H2O2 is more than that of H2O but H2O2 is not a good solvent because :

Options:
A It has a very high dielectric constant so that ionic compounds cannot be dissolved in it
B It does not act as an oxidising agent
C It acts as a reducing agent
D It dissociates easily and acts as an oxidising agent in chemical reactions.

The correct answer is:
It dissociates easily and acts as an oxidising agent in chemical reactions.

Solution:
H2O2 is thermally unstable and it decomposes easily.
H 2 O 2 l⁡ ⟶ H 2 O l⁡ + 1 2 O 2 g
Its decomposition is catalysed by alkali metals present in traces in the glass of the vessel .

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), NEET
The dipole moment of is 1.5 D . The dipole moment of is

Options:
A 1 D
B 1.5 D
C 2.25 D
D 3 D

The correct answer is:
1.5 D

Solution:
the dipole moment of 1,3,5- trihalobenzene is zero due to symmetry, thus its net dipole moment is same as halo benzene.

Topic: Chemistry, Chemical Bonding and Molecular Structure, NEET