datavorous/entrance-exam-dataset huggingface dataset:
The following reaction
R− CH 2 CH 2 N + (CH 3 ) 3 OH − → Δ RCH =  CH 2 +N(CH 3 ) 3  +  H 2 O is called

Options:
A Hoffmann-bromamide reaction
B Cope elimination
C Hoffmann elimination
D Beckmann rearrangement

The correct answer is:
Hoffmann elimination

Solution:
Trialkyl ammonium hydroxide undergoes Hoffmann elimination to give less substituted alkene. Elimination of more acidic β -H occurs from that β -carbon, which is joined to largest number of hydrogens. Thus, elimination of H occurs opposite to that of Saytzeff rules.

Topic: Chemistry, Amines, NEET
The following results have been obtained during the kinetic studies of the reaction: 2A + B → C + D
Determine the rate law and the rate constant for the reaction.

Options:
A Rate law = k[A][B]2; Rate constant = 6.0 M–2min–1
B Rate law = k[A][B]2; Rate constant = 9.0 M–2min–1
C Rate law = k[A][B] ; Rate constant = 6.0 M–2min–1
D Rate law = k[A][B] ; Rate constant = 9.0 M–2min–1

The correct answer is:
Rate law = k[A][B]2; Rate constant = 6.0 M–2min–1

Solution:
Correct Option is : (A)
Rate law = k[A][B]2; Rate constant = 6.0 M–2min–1

Topic: Chemistry, Chemical Kinetics, NEET
The following solutions were prepared by dissolving 10 g of glucose C6H12O6 in 250 mL of water P1,10 g of urea CH4N2O in 250 mL of water P2 and 10 g of sucrose C12H22O11 in 250 mL of water P3. The right option for the decreasing order of osmotic pressure of these solutions is:

Options:
A P2>P1>P3
B P1>P2>P3
C P2>P3>P1
D P3>P1>P2

The correct answer is:
P2>P1>P3

Solution:
Osmotic pressure (π)=CRT
At same temperature, π∝C

Solution: (1)C1=10180=10180×4

C1=2501000=40180=29

C1=0.222M

Solution: (2) C2=10602501000=16×4=0.667M

Solution: (3) C3=10342×1000250=0.1169M

∵C2>C1>C3∴ Hence, order: P2>P1>P3

Topic: Chemistry, Solutions, NEET, NEET 2021
The following statements are given about different plant growth hormones:

I. Cytokinin suppresses the synthesis of chlorophyll.
II. Auxins control apical dominance.
III. Gibberellins promote shoot elongation.
IV. Abscisic acid enables seeds to withstand desiccation.

Which of the above statements are correct?

Options:
A I and II
B II and III
C I and III
D II, III and IV

The correct answer is:
II, III and IV

Solution:
'Cytokinin' delays the senescence of leaves and prevents chlorophyll degradation. It can be shown by a rapid bioassay technique. Cytokinin treated leaf tips retard the process of chlorophyll degradation as compared to untreated leaf discs.

Topic: Biology, Plant - Growth and Development, NEET
The following statements are given regarding MTP. Choose the CORRECT options given below.

(i) MTPs are generally advised during the first trimester.

(ii) MTPs are used as a contraceptive method.

(iii) MTPs are always surgical.

(iv) MTPs require the assistance of qualified medical personnel.

Options:
A ii and iii
B iii and iv
C i and iv
D i and ii

The correct answer is:
i and iv

Solution:
MTP is Medical termination of pregnancy done purposely or intentionally. It is also known as induced abortion. In India this act was not accepted earlier. But it got accepted in the year 1971. It is performed to get rid of unwanted pregnancies due to unprotected sex or rapes. There are certain laws to be followed for the same though. These are considered safe i.e. without any danger to the female if these are performed during first trimester i.e. before 12 weeks or three months of pregnancy. MTPs can be surgical or can be induced using drugs too like Prostaglandin and Mefipristone however assistance of medical personnel is needed.

Topic: Biology, Reproductive Health, NEET
The following statements describe events during the mitotic cell cycle. What is the correct order of these events in the mitotic cell cycle?

I. Chromosomes migrate to opposite poles of the spindle.
II. Chromosomes arrange themselves at the equator of the spindle.
III. Chromosomes condense and the nuclear membrane disappears.
IV. Centromeres divide.

Options:
A II → III → IV→ I
B III → II → IV → I
C III → IV → II → I
D IV → II → I → III

The correct answer is:
III → II → IV → I

Solution:
During mitosis, the chromosomes condense and nuclear membrane disappears at prophase. They are attached to spindle fibers and are brought to the equator at metaphase. Centromeres divide and one chromatid of each chromosome is pulled to opposite sides of the cell at anaphase. Chromosomes reach the poles, they decondense and form nuclear membrane at telophase.

Topic: Biology, Cell Cycle and Cell Division, NEET
The following statements describe the process of translation.

I. An amide linkage is formed between adjacent amino acids.
II. Hydrogen bonds are formed between the anticodon and the codon.
III. mRNA binds to the ribosome.
IV. tRNA enters the ribosome carrying a specific amino acid.

In which order does this process take place?

Options:
A III â IV â II â I
B IIIÂ âÂ IIÂ âÂ IÂ âÂ IV
C IVÂ âÂ IIÂ âÂ IÂ âÂ III
D IVÂ âÂ IIÂ âÂ IIIÂ âÂ I

The correct answer is:
III â IV â II â I

Solution:
Translation refers to the process of polymerization of amino acids to form a polypeptide. It occurs at ribosomes. It has three phases: initiation, elongation and termination. During initiation, mRNA combines with ribosomes. Then a tRNA carrying methionine is brought at the P site. There is a codon-anticodon pairing with the help of hydrogen bonds. Then elongation occurs, in which a new codon is exposed at A Site. A new tRNA carrying specific amino acid to that codon is brought again. There is codon-anticodon pairing and amino acid is accepted. Further, a peptide bond is formed at the P site between the first amino acid and the new amino acid brought at the A site. The ribosome moves from codon to codon along the mRNA. amino acids are added one by one, and translated into polypeptide sequences.

Topic: Biology, Molecular Basis of Inheritance, NEET
The following structure is known as

Options:
A Ampicillin
B Penicillin-K
C Penicillin-G
D Penicillin-F

The correct answer is:
Penicillin-G

Solution:
This structure is of Penicillin-G or BezylPenicillin.

Topic: Chemistry, Chemistry in Everyday Life, NEET
The following substances are the excretory products in animals. Choose the least toxic form among them?

Options:
A Urea
B Uric acid
C Ammonia
D Carbon dioxide

The correct answer is:
Uric acid

Solution:
Uric acid is the least toxic form among excretory products in animals.

Topic: Biology, Excretory Products and their Elimination, NEET
The following symptoms correspond to which of the following disorder:

1. Deaf-mutism
2. Abnormal skin
3. Mental retardation in children

Options:
A Myxoedema
B Cretinism
C Down's syndrome
D Grave's disease

The correct answer is:
Cretinism

Solution:
Hypothyroidism during pregnancy causes defective development and maturation of the growing baby leading to stunted growth (cretinism), mental retardation, low intelligence quotient, abnormal skin, deaf-mutism, etc.

Topic: Biology, Chemical Coordination and Integration, NEET
The following three kinds of leaves were exposed to light:

I. Variegated leaf
II. Green leaves partially covered with black paper
II. Green leaf

Presence of starch was seen in

Options:
A Only in the green leaves
B Both green and variegated leaves
C All the leaves in which green parts exposed to light
D Only variegated leaf

The correct answer is:
All the leaves in which green parts exposed to light

Solution:
Experiments have been carried out to look for starch formation in two leaves -a variegated leaf or a leaf that was partially covered with black paper and one that was exposed to light. On testing these leaves for starch it was clear that photosynthesis occurred only in the green parts of the leaves in the presence of light.

Topic: Biology, Photosynthesis in Higher Plants, NEET
The following were the observations made for an infectious agent.

(i) smaller than a virus,

(ii) its nucleic acid had ribose as sugar

(iii) lacks a protein coat.

Select the disease/s it is most likely to cause.

Options:
A Potato spindle tuber disease
B Potato leaf roll
C Potato leaf curl
D Both a and b

The correct answer is:
Potato spindle tuber disease

Solution:
Potato spindle tuber disease affects the potato plant where the tubers are malformed and stunts the growth of the plant. This disease is caused by viroids which are smaller than virus and without any capsid covering of protein. It is basically a free floating single strand RNA.

Topic: Biology, Biological Classification, NEET
The food chain in which microbes split energy rich compounds of the producer community is

Options:
A parasitic food chain.
B detritus food chain.
C predators food chain.
D producer food chain.

The correct answer is:
detritus food chain.

Solution:
Detritus food chain starts from dead organic matter acted upon by decomposers which in turn are eaten by detrivores consumers which are eaten by top consumers.

Topic: Biology, Ecosystem, NEET
The forbidden energy gap in Ge is 0.72 eV, given, hc = 12400 eV-Å. The maximum wavelength of radiation that will generate electron hole pair is

Options:
A 172220 Å
B 172.2 Å
C 17222 Å
D 1722 Å

The correct answer is:
17222 Å

Solution:
The forbidden Energy gap, Eg=hcÎ»
Î» = maximum wave length of radiation
Î»=hcEg=124000.72=17222 â«

Topic: Physics, Semiconductors, NEET
The force acting per unit length on one conductor due to the other for two long parallel current-carrying wires is

Options:
A μ04πI1I2r
B μ04πI1I22r
C μ04π2I1I2r
D μ04πI1I24r

The correct answer is:
μ04π2I1I2r

Solution:
Force between two parallel current carrying wires: AB and CD are two infinitely long conductors, placed parallel to each other and separated by distance r. They carry currents I1 and I2 in the same direction.

Magnetic field produced by current I1 at any point of CD is

B1=Î¼0âI12Ïr

This field acts perpendicular to CD and into the plane of paper. It exerts a force on wire CD carrying current I2. Force exerted on unit length of CD is

F=B1âI2âl=Î¼0I12ÏrÃI2Ã1

F=Î¼0I1I22Ïrâââââ or âââÎ¼04ÏÂ·2I1âI2r

By Flemingâs left hand rule, this force acts on CD towards AB. Similarly, conductor CD also exerts an equal force AB towards itself. Hence the two wires get attracted towards each other, if currents are in same direction.

Topic: Physics, Magnetic Effects of Current, NEET
The force between two identical charges placed at a distance of r in a vacuum is F. Now a slab of dielectric constant 4 is inserted between these two charges. If the thickness of the slab is r 2, then the force between the charges will become

Options:
A 35Â F
B 49 F
C F4
D F2

The correct answer is:
49 F

Solution:
F = 1 4 Ï Îµ 0 q 1 q 2 r 2
For a dielectric of dielectric constant K between the charges, the effective separation in air reff is given by
1 4 Ï Îµ 0 q 1 q 2 r eff 2 = 1 4 Ï Îµ 0 q 1 q 2 K r 2
â r eff = K r
â´ F â² = 1 4 Ï Îµ 0 q 1 q 2 r 2 + K r 2 2
â F â² F = 1 1 2 + 4 2 2 = 4 9

Topic: Physics, Electrostatics, NEET
The force between two parallel current carrying wires is independent of

Options:
A their distance of separation
B the length of the wires
C the magnitude of currents
D the radii of the wires

The correct answer is:
the radii of the wires

Solution:
The force between two current-carrying conductors can be given by

FL=μ0I1I22πd

where,

F = force on each conductor

L = Length of the conductor

I1, I2= current in the conductors

d = distance between the conductors

Hence, we can say the force between two parallel current-carrying wires is independent of the radii of the wires.

Topic: Physics, Magnetic Effects of Current, NEET
The force between two parallel current-carrying wires is independent of

Options:
A their distance of separation
B the length of the wires
C the magnitude of currents
D the radii of the wires

The correct answer is:
the radii of the wires

Solution:
The force between two current-carrying conductors can be given by

FL=μ0I1I22πd

where,

F = force on each conductor

L = Length of the conductor

I1, I2= current in the conductors

d = distance between the conductors

Hence, we can say the force between two parallel current-carrying wires is independent of the radii of the wires.

Topic: Physics, Magnetic Effects of Current, NEET
The force exerted by the ideal string on the ideal pulley P shown in the figure is

Options:
A mg
B 2 mg
C √2mg
D 4 mg

The correct answer is:
mg

Solution:
As T = mg and for pulley P, we can write
Tnet =T2+T2+2.T.T.cos 120°= T = mg

Topic: Physics, Laws of Motion, NEET
The force ‘F' acting on a particle of mass ‘m' is indicated by the force-time graph shown below. The change in momentum of the particle over the time interval from zero to 8 s is:

Options:
A 24 Ns
B 20 Ns
C 12 Ns
D 6 Ns

The correct answer is:
12 Ns

Solution:
As we know that:-

Area under force-time graph gives as momentum

∆P=ar of given curve

∆P=12×b×h + l1×b1 + l2×b2

∆P=1226-32+423
=6-6+12
=12

Topic: Physics, Center of Mass Momentum and Collision, NEET, NEET 2014
The force of kinetic friction does not depend on

Options:
A the relative velocity of the two surfaces in contact.
B nature of the surfaces in contact.
C normal reaction on the moving body
D all of the above

The correct answer is:
the relative velocity of the two surfaces in contact.

Solution:
Kinetic friction is fk=μkN, where μk depends upon nature of surfaces in contact only.

Topic: Physics, Laws of Motion, NEET
The force of tension cohesion exceeds root pressure on a

Options:
A Rainy day
B Foggy morning
C Sunny day
D Full moon night

The correct answer is:
Sunny day

Solution:
It is so because the transpiration rate is very high on a sunny day.

Topic: Biology, Transport in Plants, NEET
The force on a particle of mass 10 g is 10 iâ¡^+5 jâ¡^N. If it starts from rest at the origin, what would be its position at time t=5 s?

Options:
A 12500i⁡^+6250j⁡^ m
B 6250i⁡^+12500j⁡^ m
C 12500i⁡^+12500j⁡^ m
D 6250i⁡^+6250j⁡^ m

The correct answer is:
12500i⁡^+6250j⁡^ m

Solution:
From F⁡→=10i⁡^+5j⁡^ N, we have
F⁡ x⁡ = 1 0 N ; F⁡ y⁡ = 5 N
a⁡x⁡=F⁡x⁡m⁡=100.01=1000 m s-2
As acceleration along the x-axis is constant,
∴ x⁡ = u⁡ x⁡ t⁡ + 1 2 a⁡ x⁡ t⁡ 2
= 0 + 1 2 × 1 0 0 0 × 5 2 = 1 2 5 0 0 m
Similarly, a⁡y⁡=F⁡y⁡m⁡=50.01=500 m s-2
and y⁡ = u⁡ y⁡ t⁡ + 1 2 a⁡ y⁡ t⁡ 2 = 0 + 1 2 × 5 0 0 × 5 2 = 6 2 5 0 m
Hence the position of the particle at t=5 s is
r⁡→=12500i⁡^+6250j⁡^ m

Topic: Physics, Laws of Motion, NEET
The force required just to move a body up an inclined plane is double the force required just to prevent the body sliding down. If the coefficient of friction is 0.25, then the angle of inclination of the plane is

Options:
A tan-1⁡34
B tan-1⁡14
C 45°
D 30°

The correct answer is:
tan-1⁡34

Solution:
case (i)
F1=Mg sinÎ¸+fr
=Mg sinÎ¸+Î¼ cos Î¸ ... (i)
Case (ii)
F2+frâ=Mg sinÎ¸
F2=Mg cosÎ¸-Î¼ Mgcosâ¡Î¸
=Mg sinÎ¸-Î¼ cosÎ¸ ... (ii)
F1=2F2 Given
From Eqs. (i) and (ii)
Mg sinÎ¸+Î¼ cosÎ¸=2Mg sinÎ¸-Î¼ cosÎ¸
â¹sinÎ¸+14cosâ¡Î¸=2sinÎ¸-14cosÎ¸
â¹cosÎ¸14+12=sinÎ¸
â¹34 cos Î¸=sin Î¸
â¹ tan Î¸=34
â¹tanÎ¸=34
â¹Î¸=tan-1â¡34

Topic: Physics, Laws of Motion, NEET
The force required to move a body up a rough inclined plane is double the force required to prevent the body from sliding down the plane. The coefficient of friction, when the angle of inclination of the plane is 60° is

Options:
A 13
B 12
C 13
D 12

The correct answer is:
13

Solution:
For upward motion, Fup=mgsin⁡θ+μcos⁡θ ......(i)
For downward motion, Fdown=mgsin⁡θ-μcos⁡θ ......(ii)
According to the question,
Fup=2Fdown
mgsin⁡θ+μcos⁡θ=2mg sin⁡θ-μcos⁡θ
sin⁡θ+μcos⁡θ=2sin⁡θ-2μcos⁡θ
3μcos⁡θ=sin⁡θ
μ=13tan⁡θ
μ=13×tan⁡60°
⇒ μ=133=13

Topic: Physics, Laws of Motion, NEET
The force required to row a boat over the sea is proportional to the square of the speed of the boat. It is found that it takes 24 hp to row a certain boat at a speed of 8 km hr-1, the horsepower required when speed is doubled

Options:
A 12 hp
B 48 hp
C 96 hp
D 192 hp

The correct answer is:
192 hp

Solution:
Given,
Fâv2
As power is given by
P=Fv
Therefore
Pâv3
P2P1=v2v13
P224=2vv3
P224=8
P2=192 hp

Topic: Physics, Work Power Energy, NEET
The forebrain in human consists of cerebrum, diencephalon and

Options:
A Mesencephalon
B Rhinencephalon
C Pons varolii
D Medulla oblongata

The correct answer is:
Rhinencephalon

Solution:
The human brain consists of:
A. Forebrain = Cerebrum (telencephalon) + Thalamus + Hypothalamus + Olfactory lobe (Rhinencephalon)
B. Midbrain
C. Hindbrain = Medulla oblongata + Pons + Cerebellum

Topic: Biology, Neural Control and Coordination, NEET
The Î³ - form of iron has fcc structure (edge length 386 pm) and Î² - form has bcc structure (edge length 290 pm). The ratio of density in Î³ - form and Î² - form is :

Options:
A 0.848
B 1.02
C 1.57
D 0.6344

The correct answer is:
0.848

Solution:
d γ d β = d fcc d bcc
= 4 × A N a × 1 a fcc 3 2 × A N a × 1 a bcc 3 = 2 a bcc a fcc 3
= 2 × 2 9 0 3 8 6 3 = 0.848

Topic: Chemistry, Solid State, NEET
The formation of bicarbonate ion and hydrogen ion is fast near

Options:
A the alveolar site
B the tissue site
C in the pulmonary veins
D in umbilical vein

The correct answer is:
the tissue site

Solution:
At the tissue site where partial pressure of CO2 is high due to catabolism, CO2 diffuses into blood and forms bicarbonate ion and hydrogen ion.

Topic: Biology, Breathing and Exchange of Gases, NEET
The formation of embryo directly from the cells of nucellus or integument is called:

Options:
A Apogamy
B Apospory
C Adventive embryony
D Diplospory

The correct answer is:
Adventive embryony

Solution:
When cells of nucellus divides by mitosis to form embryo directly, it is known as adventive embryony; however, when cells of nucellus divides to form embryo sac, inside which embryo is produced, then it is known as apospory.

Topic: Biology, Sexual Reproduction in Flowering Plants, NEET
"The formation of life was preceded by chemical evolution". This statement was given by,

Options:
A Urey and Miller
B Jacob and Monod
C Fischer and Huxley
D Oparin and Haldane

The correct answer is:
Oparin and Haldane

Solution:
Oparin and Sydney Fox held that large organic molecules synthesized abiotically on primitive earth later came together spontaneously and due to intermolecular attraction, formed large colloidal aggregates called coacervates.

Topic: Biology, Evolution, NEET
The formation of O3 in upper part of atmosphere is catalyzed by

Options:
A N2
B NO
C CO
D CO2

The correct answer is:
NO

Solution:
Catalyst for process is NO.

Topic: Chemistry, Environmental Chemistry, NEET
The formation of the oxide ion, O2-(g) , from oxygen atom requires first an exothermic and then an endothermic step as shown in below:
Og+e-⟶O-g ; ΔfH⊖=-141 kJ mol-1
O-g+e-⟶O2- g ; ΔfH⊖=+780 kJ mol-1
Thus process of formation of O2- in gas phase is unfavourable though O2- is isoelectronic with neon. It is due to the fact that,

Options:
A Electron repulsion outweighs the stability gained by achieving noble gas configuration.
B O- Ion has comparatively smaller size than oxygen atom.
C Oxygen is more electronegative.
D Addition of electron in oxygen results in larger size of the ion.

The correct answer is:
Electron repulsion outweighs the stability gained by achieving noble gas configuration.

Solution:
Due to the fact that electron repulsion outweighs the stability gained by achieving noble gas configuration, formation of O2- in gas phase is unfavourable though O2- is isoelectronic with neon. When an electron is added to O- anion, there is strong electrostatic repulsion between the two negative charges. Due to this, the second electron gain enthalpy of oxygen is positive.

Topic: Chemistry, Classification of Elements and Periodicity in Properties, NEET, NEET 2015 (Phase 2)
The formation of two male gametes in flowering plants occurs by

Options:
A meiosis of microspore mother cell
B mitosis of microspore
C mitosis of vegetative cell
D mitosis of generative cell

The correct answer is:
mitosis of generative cell

Solution:
In flowering plants pollen grain is the male gametophyte which undergoes unequal mitosis to form a larger vegetative cell and a smaller generative cell. The generative cell undergoes mitosis to form two spindle shaped male gametes.

Topic: Biology, Sexual Reproduction in Flowering Plants, NEET
The formula for chile saltpetre is

Options:
A NaNO3
B Na2SO4.10H2O
C KNO3
D Na2S2O3.5H2O

The correct answer is:
NaNO3

Solution:
Chile salt petre is NaNO3 While KNO3 is Indian salt petre. Na2SO4.10H2O is Glouber salt and Na2S2O3.5H2O is known as Hypo.

Topic: Chemistry, s Block Elements, NEET
The formula for Chromium(III) oxide is:

Options:
A Cr₂O₃
B CrO₃
C Cr₂O₆
D CrO₂

The correct answer is:
Cr₂O₃

Solution:
Correct Option is : (A)
Cr₂O₃

Topic: Chemistry, Redox Reactions, NEET
The formula for exponential population growth is:

Options:
A $\mathrm{dN} / \mathrm{dt}=\mathrm{rN}$
B $\mathrm{dt} / \mathrm{dN}=\mathrm{rN}$
C $\mathrm{dN} / \mathrm{rN}=\mathrm{dt}$
D $\mathrm{rN} / \mathrm{dN}=\mathrm{dt}$

The correct answer is:
$\mathrm{dN} / \mathrm{dt}=\mathrm{rN}$

Solution:
Exponential growth form can be represented mathematically by the following exponential equation:
$$
\frac{d N}{d t}=(\mathrm{B}-\mathrm{D}) \times \mathrm{N}
$$
$\mathrm{B}=$ Birth rate, $\mathrm{D}=$ Death rate
Let $(B-D)=r$ or intrinsic rate of growth.
Then, $=r \times n$
where $d$ is the rate of change, $\mathrm{N}=$ number of existing individuals.
$t=$ time and $r=$ intrinsic rate of natural increase represents the rate of change in population size.

Topic: Biology, Organisms and Populations, NEET, NEET 2006
The formula for Iron(III) sulfate is:

Options:
A Fe₂(SO₄)₃
B FeSO₃
C Fe₂SO₃
D Fe(SO₄)₃

The correct answer is:
Fe₂(SO₄)₃

Solution:
Correct Option is : (A)
Fe₂(SO₄)₃

Topic: Chemistry, Redox Reactions, NEET
The formula for Mercury(II) chloride is:

Options:
A HgCl
B HgCl₂
C Hg₂Cl
D Hg₂Cl₂

The correct answer is:
HgCl₂

Solution:
Correct Option is : (B)
HgCl₂

Topic: Chemistry, Redox Reactions, NEET
The formula for Nickel(II) sulfate is:

Options:
A NiSO₃
B NiSO₄
C Ni₂SO₃
D Ni₂SO₄

The correct answer is:
NiSO₄

Solution:
Correct Option is : (B)
NiSO₄

Topic: Chemistry, Redox Reactions, NEET
The formula for Thallium(I) sulfate is:

Options:
A Tl₂SO₄
B TlSO₃
C Tl₂SO₃
D Tl₂(SO₄)₃

The correct answer is:
Tl₂SO₄

Solution:
Correct Option is : (A)
Tl₂SO₄

Topic: Chemistry, Redox Reactions, NEET
The formula for Tin(IV) oxide is:

Options:
A SnO
B Sn₂O
C SnO₂
D Sn₂O₄

The correct answer is:
SnO₂

Solution:
Correct Option is : (C)
SnO₂

Topic: Chemistry, Redox Reactions, NEET
The formula of dichlorobis(urea)copper(II) is

Options:
A [Cu(O=C(NH2)2)Cl]Cl
B CuCl 2 (O=C NH 2 ) 2
C [Cu(O=C(NH2)2Cl2]
D [CuCl2(O=C(NH2)2)2]

The correct answer is:
[CuCl2(O=C(NH2)2)2]

Solution:
The formula for the complex dichlorobis(urea)copper(II) is [CuCl2(O=C(NH2)2)2] .

Topic: Chemistry, Coordination Compounds, NEET
The formula of sulphamic acid is

Options:
A H2NSO2
B NH22SO2H
C NH2SO2OH
D None of these

The correct answer is:
NH2SO2OH

Solution:
Sulphamic acid is H2N.SO2.OH

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), NEET
The formula

refers to

Options:
A BHC
B DDT
C DNA
D RNA

The correct answer is:
DDT

Solution:
DDT is form by the reaction of chloral CCl3.CHO with phenol.

Topic: Chemistry, Chemistry in Everyday Life, NEET
The formula which can be used for determination of density of cubic unit cell is

Options:
A a 3  ×  N o Z×M gcm −3
B ZÃM a 3 ÃN o gcm â3
C a 3 ×M Z×N o gcm −3
D M×N o a 3 ×Z gcm −3

The correct answer is:
Z×M a 3 ×N o gcm −3

Solution:
density= mass of unit cell volume of unit cell
Z × mol.wt. M V(=  a 3 ) × avogadro no.  (N o ) gcm −3

Topic: Chemistry, Solid State, NEET
The forward biased diode connection among the following is

Options:
A

B

C

D

The correct answer is:

Solution:
In case of forward biased circuit P-junction should be at higher potential. Therefore.

Topic: Physics, Semiconductors, NEET