datavorous/entrance-exam-dataset huggingface dataset:
In the monocotyledon seeds, the endosperm is separated from the embryo by a distinct layer known as:

Options:
A Testa
B Aleurone
C Tegmen
D Hilum

The correct answer is:
Aleurone

Solution:
The outermost layer of endosperm monocotyledonous seeds is called aleurone layer, which is rich in protein. The endosperm is separated from the embryo by a distinct layer called aleurone.

Topic: Biology, Morphology of Flowering Plants, NEET
In the neutral or faintly alkaline medium, KMnO4 oxidises iodide into iodate. The change in oxidation state of manganese in this reaction is from

Options:
A +6 to +4
B +7 to +3
C +6 to +5
D +7 to +4

The correct answer is:
+7 to +4

Solution:
KMnO4 acts as an oxidising agent. In neutral or faintly alkaline medium When alkaline KMnO4 is treated with KI, iodide ion is oxidised to iodate IO3- andKMnO4 is reduced to MnO2. The chemical reaction can be given as,

2KMnO4+H2O+KI→2MnO2+2KOH+KIO3

The change in oxidation state of manganese in this reaction is from +7 to +4.

Topic: Chemistry, d and f Block Elements, NEET, NEET 2022 (Phase 1)
In the nitration of benzene, which reagent provides the nitro group?

Options:
A Concentrated sulfuric acid
B Concentrated hydrochloric acid
C Concentrated nitric acid
D Concentrated acetic acid

The correct answer is:
Concentrated nitric acid

Solution:
In the nitration of benzene, the nitro group (-NO2) is introduced by concentrated nitric acid.if !supportLineBreakNewLine

Topic: Chemistry, Hydrocarbons, NEET
In the nomenclature of coordination compounds, what happens to the oxidation state of the metal in the coordination entity?

Options:
A It is omitted
B It is written as a superscript
C It is indicated using Greek letters
D It is indicated using a Roman numeral in parentheses

The correct answer is:
It is indicated using a Roman numeral in parentheses

Solution:
In the nomenclature of coordination compounds, the oxidation state of the metal is indicated using a Roman numeral in parentheses.

Topic: Chemistry, Coordination Compounds, NEET
In the nuclear decay given below
$$
{ }_{\mathrm{Z}}^{\mathrm{A}} \mathrm{X} \longrightarrow{ }_{\mathrm{Z}+1}^{\mathrm{A}} \mathrm{Y} \longrightarrow{ }_{\mathrm{Z}-1}^{\mathrm{A}-4} \mathrm{~B}^* \longrightarrow{ }_{\mathrm{Z}-1}^{\mathrm{A}-4} \mathrm{~B} \text {, }
$$
the particles emitted in the sequence are

Options:
A $\beta, \alpha, \gamma$
B $\gamma, \beta, \alpha$
C $\beta, \gamma, \alpha$
D $\alpha, \beta, \gamma$

The correct answer is:
$\beta, \alpha, \gamma$

Solution:
Key Idea In a nuclear reaction conservation of charge number and mass number must hold good.
Alpha particles are positively charged particles with charge $+2 e$ and mass $4 \mathrm{~m}$. Emission of an $\alpha$-particle reduces the mass of the radionuclide by 4 and its atomic number by 2. $\beta$-particles are negatively charged particles with rest mass as well as charge same as that of electrons. $\gamma$-particles carry no charge and mass.
Radioactive transition will be as follows
$$
\begin{aligned}
& { }_{\mathrm{Z}}^{\mathrm{A}} \mathrm{X} \longrightarrow{ }_{\mathrm{Z}+1}{ }^{\mathrm{A}} \mathrm{Y}+\beta_{-1}^0 \\
& { }_{\mathrm{Z}+1}^{\mathrm{A}} \mathrm{Y} \longrightarrow{ }_{\mathrm{Z}-1}^{\mathrm{A}-4} \beta+\alpha_2^4 \\
& { }_{\mathrm{Z}+1}^{\mathrm{A}-4} \beta \longrightarrow{ }_{\mathrm{Z}-1}^{\mathrm{A}-4} \mathrm{\beta}+\gamma_0^0 \\
&
\end{aligned}
$$

Topic: Physics, Nuclear Physics, NEET, NEET 2009 (Screening)
In the nuclear emission stated above, the mass number and atomic number of the product $Q$ respectively, are

Options:
A 286,80
B 288,82
C 286,81
D 280, 81

The correct answer is:
286,81

Solution:
$\begin{aligned} & A \rightarrow 286 \\ & Z=81\end{aligned}$

Topic: Physics, Nuclear Physics, NEET, NEET 2024
In the nucleophilic substitution reactions S N 2â or S N 1 the reactivity of alkyl halides follows the sequence

Options:
A R-I > R-Br > R-Cl > R-F
B R-Cl > R-F > R-Br > R-I
C R-F > R-Cl > R-Br > R-I
D R-I > R-F > R-Cl > R-Br

The correct answer is:
R-I > R-Br > R-Cl > R-F

Solution:
Nucleophilic substitution reaction depends on learning group ability
The correct order of reactivity is
RI > RBr > RCl > RF
It is due to fact, that weaker the base, better will be the leaving group.
Leaving group ability I â > Br â >Cl> F â

Topic: Chemistry, General Organic Chemistry, NEET
In the nucleoside a base is attached at 1′ position of sugar moiety. Nucleotide is formed by linking the phosphoric acid unit to the sugar unit of nucleoside. At which position of sugar unit is the phosphoric acid linked in a nucleoside to give a nucleotide?

Options:
A Phosphoric acid is linked at 1′-position of sugar moiety of nucleoside to give a nucleotide.
B Phosphoric acid is linked at 5′-position of sugar moiety of nucleoside to give a nucleotide.
C Phosphoric acid is linked at 3′-position of sugar moiety of nucleoside to give a nucleotide.
D Phosphoric acid is not linked to nucleoside

The correct answer is:
Phosphoric acid is linked at 5′-position of sugar moiety of nucleoside to give a nucleotide.

Solution:
Correct Option is : (B)
Phosphoric acid is linked at 5′-position of sugar moiety of nucleoside to give a nucleotide.

Topic: Chemistry, Biomolecules, NEET
In the number 2.005, how many significant figures are there?

Options:
A Two
B Four
C Three
D Five

The correct answer is:
Four

Solution:
In the number 2.005, there are Four significant figures.

Topic: Chemistry, Some Basic Concepts of Chemistry, NEET
In the options given below, let E denote the rest mass energy of a nucleus and n, a neutron. The correct option is

Options:
A E(U92236)>E(I53137)+E(Y3997)+2E(n)
B E(U92236)<E(I53137)+E(Y3997)+2E(n)
C E(U92236)<E(Ba56140)+E(Kr3694)+2E(n)
D E(U92235)>E(Ba56140)+E(Kr3694)+E(n)

The correct answer is:
E(U92236)>E(I53137)+E(Y3997)+2E(n)

Solution:
Rest mass of the parent nucleus should be greater than the rest masses of daughter nuclei. Therefore, the option
E(U92236)>E(I53137)+E(Y3997)+2E(n) will be correct.

Topic: Physics, Nuclear Physics, NEET
In the options given below, let E denote the rest mass energy of a nucleus and n, a neutron. The correct option is

Options:
A E(U92236)>E(I53137)+E(Y3997)+2E(n)
B E(U92236)<E(I53137)+E(Y3997)+2E(n)
C E(U92236)<E(Ba56140)+E(Kr3694)+2E(n)
D E(U92235)>E(Ba56140)+E(Kr3694)+E(n)

The correct answer is:
E(U92236)>E(I53137)+E(Y3997)+2E(n)

Solution:
Rest mass of parent nucleus should be greater than the rest masses of daughter nuclei. Therefore, the option (E(U92236)>E(I53137)+E(Y3997)+2E(n)) will be correct.

Topic: Physics, Nuclear Physics, NEET
In the oxidation half-reaction, what is the product when Fe2+ ions are oxidized to Fe3+ ions?

Options:
A Fe2+
B Fe3+
C e- (electrons)
D Cr2O72- ions

The correct answer is:
e- (electrons)

Solution:
In the oxidation half-reaction, electrons (e_) are produced when Fe2+ ions are oxidized to Fe3+ ions.

Topic: Chemistry, Redox Reactions, NEET
In the oxidation number method for balancing redox reactions, what is the first step?

Options:
A Assigning oxidation numbers to all elements
B Identifying the reactants and products
C Adding water molecules to balance hydrogen atoms
D Adding H+ ions for reactions in acidic solution

The correct answer is:
Identifying the reactants and products

Solution:
The first step in the oxidation number method is to write the correct formula for each reactant and product.

Topic: Chemistry, Redox Reactions, NEET
In the oxidation number method, what is done to ensure that the total ionic charges of reactants and products are equal in a redox reaction?

Options:
A Adjusting the temperature
B Balancing the number of carbon atoms
C Adding H+ or OH- ions
D Changing the formula of the products

The correct answer is:
Adding H+ or OH- ions

Solution:
To ensure that the total ionic charges of reactants and products are equal, you add H+ or OH- ions in the oxidation number method.

Topic: Chemistry, Redox Reactions, NEET
In the oxidation number method, what is the significance of identifying atoms that undergo a change in oxidation number?

Options:
A It helps calculate the molar mass of the atoms
B It determines the color of the reactants and products
C It is essential for assigning oxidation numbers
D It is irrelevant to balancing redox reactions

The correct answer is:
It is essential for assigning oxidation numbers

Solution:
Identifying atoms that undergo a change in oxidation number is crucial for assigning oxidation numbers and subsequently balancing redox reactions.

Topic: Chemistry, Redox Reactions, NEET
In the oxidation of sulfur dioxide into sulfur trioxide, what metal is the catalyst?

Options:
A Iron
B Platinum
C Silver
D Lead

The correct answer is:
Platinum

Solution:
The paragraph mentions platinum as the catalyst in the oxidation of sulfur dioxide into sulfur trioxide.

Topic: Chemistry, Surface Chemistry, NEET
In the oxymercuration – demercuration of the following compound
The major product is expected to be

Options:
A
B
C
D

The correct answer is:

Solution:
In this oxy mercuration de-mercuration reaction first non-classical (cyclic) mercuric acetate ion is formed which is attacked by -OH group followed by intramolecular forming cyclic ether as product.

Topic: Chemistry, Hydrocarbons, NEET
In the P-V diagram shown in figure ABC is a semicircle. The work done (in atm-litre) in the process ABC is

Options:
A zero
B π2
C π4
D 4

The correct answer is:
π2

Solution:
(Work done)
W=Ïr1r22=Ï2Ã1Ã1
W=Ï2 atm-litre

Topic: Physics, Thermodynamics, NEET
In the pathway of dark reaction, which occurs in all photosynthetic plants, the primary CO2 acceptor contains how many carbons?

Options:
A Three
B Four
C One
D Five

The correct answer is:
Five

Solution:
The primary carbon dioxide acceptor in the dark reaction is Ribulose 1,5 bisphosphate or RUBP, which is carboxylated by the enzyme Ribulose 1,5 bisphosphate carboxylase oxygenase or RuBisCo. Dark reaction is also known as the Calvin cycle and it is found in all photosynthetic plants.

Topic: Biology, Photosynthesis in Higher Plants, NEET
In the p-block, which oxidation states are favored by the heavier members?

Options:
A Higher oxidation states
B Lower oxidation states
C Intermediate oxidation states
D No specific trend

The correct answer is:
Lower oxidation states

Solution:
The paragraph contrasts the p-block with the d-block and states that in the p-block, lower oxidation states are favored by the heavier members due to the inert pair effect.

Topic: Chemistry, d and f Block Elements, NEET
In the pea seed example, what is the phenotype of the BB homozygote?

Options:
A Round seeds
B Wrinkled seeds
C Large starch grains
D Small starch grains

The correct answer is:
Large starch grains

Solution:
BB homozygotes produce large starch grains.

Topic: Biology, Principles of Inheritance and Variation, NEET
In the pea seed example, what type of dominance is exhibited based on the phenotype of starch grain size?

Options:
A Complete dominance
B Incomplete dominance
C Codominance
D Multiple alleles

The correct answer is:
Incomplete dominance

Solution:
In the pea seed example, incomplete dominance is exhibited based on the phenotype of starch grain size.

Topic: Biology, Principles of Inheritance and Variation, NEET
In the peroxide effect, what happens to the iodine free radicals in the presence of an unsymmetrical alkene like propene?

Options:
A They add to the double bond.
B They form iodine molecules.
C They combine with hydrogen atoms.
D They form stable complexes.

The correct answer is:
They form iodine molecules.

Solution:
In the peroxide effect, iodine free radicals combine to form iodine molecules in the presence of an unsymmetrical alkene like propene, instead of adding to the double bond.

Topic: Chemistry, Hydrocarbons, NEET
In the phenomenon of diffraction of light, when blue light is used in the experiment instead of red light, then

Options:
A Fringes will become narrower
B Fringes will become broader
C No change in fringe width
D Fring will disappear

The correct answer is:
Fringes will become narrower

Solution:
Width of central maximum is given by
w=2fÎ»a â¦(i)
Where f is the focal length of the lens, a is the width of slit and Î» is the wavelength of light used.
From Eq. (i), it is clear that fringe width
wâÎ»
So, when blue light is used in the experiment instead of red light, the fringes will become narrower.

Topic: Physics, Wave Optics, NEET
In the phenomenon of electric discharge through gases at low pressure, the coloured glow in the tube appears as a result of

Options:
A excitation of electrons in the atoms
B collision between the atoms of the gas
C collisions between the charged particles emitted from the cathode and the atoms of the gas
D collision between different electrons of the atoms of the gas

The correct answer is:
collisions between the charged particles emitted from the cathode and the atoms of the gas

Solution:
The discharge of electricity through rarefied gases is an interesting phenomenon which can be systematically studied with the help of a discharge tube. In discharge tube collisions between the charged particles emitted from the cathode and the atoms of the gas results to the coloured glow in the tube.

Topic: Physics, Dual Nature of Matter, NEET, NEET 2008 (Screening)
In the Phosphomolybdate method, what is the molar mass of (NH4)3PO4.12MoO3?

Options:
A 31 g
B 1877 g
C 62 g
D 222 g

The correct answer is:
1877 g

Solution:
The molar mass of (NH4)3PO4.12MoO3 is 1877 g.

Topic: Chemistry, General Organic Chemistry, NEET
In the photoelectric effect, the K.E. of electrons emitted from the metal surface depends upon

Options:
A intensity of light
B frequency of incident light
C velocity of incident light
D both intensity and velocity of light

The correct answer is:
frequency of incident light

Solution:
From Einstein's photoelectric equation the maximum kinetic energy of photoelectrons emitted from metal surface is EK and W is work function, then
EK=hv-W
If v0 is threshold frequency, then
W=hv0
∴ EK=hv-hv0=hv-v0
From the above equation, it is clear that maximum kinetic energy of electron will increase almost linearly with increase in the frequency of the incident light.

Topic: Physics, Dual Nature of Matter, NEET
In the photoelectric effect, the maximum speed of electrons is found to be 6Ã105 m s-1. The wavelength used is 4000 â«. The work function of the metal is

Options:
A 2.2 eV
B 2.076 eV
C 2.3 eV
D 2.4 eV

The correct answer is:
2.076 eV

Solution:
hcλ=KEMax+ϕ
124004000=12×9.1×10-31×36×10101.6×10-19+ϕ
3.1=102.375×10-2+ϕ
ϕ=2.076 eV

Topic: Physics, Dual Nature of Matter, NEET
In the photoelectric effect, the velocity of ejected electrons depends upon the nature of the target and

Options:
A The frequency of the incident light
B The polarisation of the incident light
C The time for which the light has been incident
D The intensity of the incident light

The correct answer is:
The frequency of the incident light

Solution:
The velocity of photoelectrons depends upon the frequency of the incident light

Topic: Physics, Dual Nature of Matter, NEET
In the photoelectric emission process from a metal of work function 1.8 eV, the kinetic energy of most energetic electrons is 0.5 eV. The corresponding stopping potential is

Options:
A 1.8 V
B 1.3 V
C 0.5 V
D 2.3 V

The correct answer is:
0.5 V

Solution:
The stopping potential Vs is related to the maximum kinetic energy of the emitted electron Kmax through the relation
Kmax = eVs
0.5 eV = eVs or Vs = 0.5 V

Topic: Physics, Dual Nature of Matter, NEET
In the photon picture of light, what determines the intensity of light for a given frequency?

Options:
A The wavelength of the photons
B The speed of light in the medium
C The number of photons crossing a unit area per unit time
D The color of the photons

The correct answer is:
The number of photons crossing a unit area per unit time

Solution:
Correct Option is : (C)
The number of photons crossing a unit area per unit time

Topic: Chemistry, Wave Optics, NEET
In the plot of the species-area relationship for the co-efficient z, the axis X and Y, represents

Options:
A

x-axis	y-axis
Species richness	Area

B

x-axis	y-axis

Area	Species richness

C

x-axis	y-axis
Slope of the line	Intercept

D

x-axis	y-axis
Intercept	Slope of the line

The correct answer is:

x-axis	y-axis

Area	Species richness

Solution:
Biodiversity includes all the flora and fauna on Earth. All the varieties of organisms come under biodiversity. German naturalist Alexander von Humboldt made the observation regarding the relationship between species richness and the area of the habitat. As per his observation, species richness increased with increasing area of habitat upto a limit. When plotted in a graph with area on x-axis and species richness on y-axis, this relationship forms a rectangular hyperbola. On a log scale, the relationship is a straight line having the equation Log S=Log C+Z Log A . S=species richness, A=area of region, C=Y-intercept and Z= regression co-efficient (Slope).

Topic: Biology, Biodiversity and its Conservation, NEET
In the polymerase chain reaction, the optimum temperature for the extension step is

Options:
A 72°C.
B 50°C
C 90°C
D 45°C

The correct answer is:
72°C.

Solution:
A single PCR reaction involves three temperature-dependent steps, described as follows:
i) Denaturation: The starting solution is heated, usually to 94oC. The high temperatures break the hydrogen bonds between the two strands of the original DNA double helix, providing the necessary single-stranded templates.
ii) Annealing: After just a couple of minutes at that temperature, the reaction mixture is quickly cooled, usually to somewhere between 50oC and 60oC. It is then held for less than a minute at this lower temperature which is enough time for the primers to bind to their complementary sequences on the single-stranded templates.
iii) Primer extension (polymerization): The sample is next heated to 72oC for some time, during which time the DNA polymerase adds nucleotides to the primer, synthesizing a new DNA strand using only the template sequences that bind the primers.

Topic: Biology, Biotechnology - Principles and Processes, NEET
In the polynucleotide chain of DNA, a nitrogenous base is linked to the -OH of:

Options:
A 2'C pentose sugar
B 3'C pentose sugar
C 5'C pentose sugar
D 1'C pentose sugar

The correct answer is:
1'C pentose sugar

Solution:
N-glycosidic linkage: A nitrogenous base is linked to the pentose sugar through a N-glycosidic linkage to form a nucleoside. Purine nucleosides have 1'-9 glycosidic linkage (carbon 1'of pentose sugar and 9' nitrogen of adenine/guanine). Pyrimidine nucleosides have1'-1' linkage i.e., pentose sugar carbon 1' and 1' position of thymine/cytosine).

Topic: Biology, Molecular Basis of Inheritance, NEET, NEET 2020 (Phase 2)
In the potentiometer circuit shown in the figure the internal resistance of the 6 V battery is 1 Î© and length of the wire AB is 100 cm. When AD=60 cm, the galvanometer shows no deflection. The EMF of the cell C is (the resistance of the wire AB is 2 Î©)

Options:
A 0.7 V
B 0.8 V
C 0.9 V
D 1.0 V

The correct answer is:
0.9 V

Solution:
VAD=6Rtotal×RAD
VAD=6(5+1+2)×60100×2

VAD=0.9 V

Topic: Physics, Current Electricity, NEET
In the presence of a meta directing group, where is the electrophile most likely to attack during electrophilic aromatic substitution?

Options:
A Ortho position
B Para position
C Meta position
D None of the above

The correct answer is:
Meta position

Solution:
In the presence of a meta directing group, the electrophile is most likely to attack the comparatively electron-rich meta position during electrophilic aromatic substitution.

Topic: Chemistry, Hydrocarbons, NEET
In the presence of air, what do phenols slowly oxidise to, leading to dark-coloured mixtures?

Options:
A Carboxylic acids
B Aldehydes
C Quinones
D Aromatic hydrocarbons

The correct answer is:
Quinones

Solution:
Phenols slowly oxidise to quinones in the presence of air.

Topic: Chemistry, Alcohols Phenols and Ethers, NEET
In the presence of peroxide addition of HBr to propene takes place according to anti Markovnikov’s rule but peroxide effect is not seen in the case of HCl and HI. Explain.

Options:
A Peroxide effect is only observed with HBr because hydrogen bromide is less stable than HCl and HI.
B Peroxide effect is specific to hydrogen bromide due to the nature of the peroxide used.
C Peroxide effect is not observed in addition of HCl and HI. This is due to the fact that the H—Cl bond being stronger than H—Br bond is not cleaved by the free radical whereas the H—I bond is weaker and iodine free radicals combine to form iodine molecules instead of adding to the double bond.
D Peroxide effect is not seen with HCl and HI because their addition to alkenes is inherently Markovnikov.

The correct answer is:
Peroxide effect is not seen with HCl and HI because their addition to alkenes is inherently Markovnikov.

Solution:
Correct Option is : (D)
Peroxide effect is not seen with HCl and HI because their addition to alkenes is inherently Markovnikov.

Topic: Chemistry, Hydrocarbons, NEET
In the presence of protic acids, which reaction pathway is favoured for the dehydration of primary alcohols to form ethers?

Options:
A SN1 pathway
B SN2 pathway
C E1 pathway
D E2 pathway

The correct answer is:
SN2 pathway

Solution:
Primary alcohols typically undergo SN2 reactions in the presence of protic acids to form ethers.

Topic: Chemistry, Alcohols Phenols and Ethers, NEET
In the presence of what substance is amylase catalytically very active?

Options:
A Ethyl alcohol
B Sodium chloride (Na+ ions)
C Carbon dioxide
D Manganese dioxide (Mn2+ ions)

The correct answer is:
Sodium chloride (Na+ ions)

Solution:
The paragraph mentions that amylase, in the presence of sodium chloride (Na+ ions), is catalytically very active.

Topic: Chemistry, Surface Chemistry, NEET
In the presence of what substances does enzymatic activity increase?

Options:
A Inhibitors
B Poisons
C Activators and co-enzymes
D Metal ions

The correct answer is:
Activators and co-enzymes

Solution:
The paragraph mentions that enzymatic activity is increased in the presence of certain substances, known as co-enzymes.

Topic: Chemistry, Surface Chemistry, NEET
In the presence of which catalyst is the hydrogenation of alkenes used to produce margarine and solid fats?

Options:
A Palladium
B Nickel
C Platinum
D Copper

The correct answer is:
Nickel

Solution:
Nickel is commonly used as a catalyst in the hydrogenation of alkenes to produce solid fats like margarine.

Topic: Chemistry, Hydrocarbons, NEET
In the presence of which gas is the addition of dihydrogen to alkenes typically carried out?

Options:
A Oxygen
B Nitrogen
C Hydrogen
D Carbon dioxide

The correct answer is:
Hydrogen

Solution:
The addition of dihydrogen to alkenes is typically carried out in the presence of hydrogen gas (H2), which reacts with the alkene to form alkanes.

Topic: Chemistry, Hydrocarbons, NEET
In the presence of which metal catalyst is the hydrogenation of alkenes to alkanes commonly performed in industrial processes?

Options:
A Platinum
B Silver
C Iron
D Gold

The correct answer is:
Platinum

Solution:
The hydrogenation of alkenes to alkanes in industrial processes is commonly performed in the presence of platinum catalysts. Platinum is known for its efficiency in catalyzing this reaction.

Topic: Chemistry, Hydrocarbons, NEET
In the present graph, the area of circle A and B are 25 unit and 20 unit respectively work done will be in unit?

Options:
A -5
B 5
C 10
D 45

The correct answer is:
5

Solution:
Total work done = Area of circle A (anticlockwise) – Area of circle B (clockwise)
=25-20=5 units.

Topic: Chemistry, Thermodynamics (C), NEET
In the primary circuit of a potentiometer, a cell of E.M.F. 1 V and a rheostat of 15 Î© are connected in series. If the resistance of the potentiometer wire is 10 Î©, the minimum voltage at the ends of the wire (in V) will be

Options:
A 0.1
B 0.4
C 0.06
D 1.0

The correct answer is:
0.4

Solution:
Voltage is minimum, when resistance is maximum. Therefore minimum voltage across the ends the wire is
V=ERh+RPRP
V=115+1010
V=0.4 V

Topic: Physics, Current Electricity, NEET