datavorous/entrance-exam-dataset huggingface dataset:
The pollination in Pinus is

Options:
A Entomophilous
B Anemophilous
C Hydrophilous
D Malscophilous

The correct answer is:
Anemophilous

Solution:
In Pinus, the pollination is anemophilous, (wind) i.e., pollen grains are carried to the ovule through the wind.

Topic: Biology, Sexual Reproduction in Flowering Plants, NEET
The pollution due to oxides of sulphur gets enhanced due to the presence of:

(a) particulate matter
(b) ozone
(c) hydrocarbons
(d) hydrogen peroxide

Choose the most appropriate answer from the options given below:

Options:
A (a), (b), (d) only
B (b), (c), (d) only
C (a), (c), (d) only
D (a), (d) only

The correct answer is:
(a), (b), (d) only

Solution:
Sulphur dioxide causes irritation to the eyes, resulting in tears and redness. High concentration of SO2 leads to stiffness of flower buds which eventually fall off from plants. Uncatalysed oxidation of sulphur dioxide is slow. However, the presence of particulate matter in polluted air catalyses the oxidation of sulphur dioxide to sulphur trioxide. 2SO2 (g) +O2 (g) → 2SO3(g) The reaction can also be promoted by ozone and hydrogen peroxide. SO2 (g) +O3 (g) → SO3(g) + O2 (g) SO2(g) + H2O2(l) → H2SO4(aq)

Topic: Chemistry, Environmental Chemistry, NEET, NEET 2022 (Phase 1)
The polymer melmac is obtained by

Options:
A addition polymerization of melamine and formaldehyde.
B free radical polymerisation of acrylonitrile.
C condensation polymerization of melamine and formaldehyde.
D coordination polymerisation of melamine.

The correct answer is:
condensation polymerization of melamine and formaldehyde.

Solution:
Melmac is a condensation polymer of melamine and formaldehyde.

Topic: Chemistry, Polymers, NEET
The polymer that is used as a substitute for wool in making commercial fibres is

Options:
A melamine
B nylon-6, 6
C polyacrylonitrile
D buna- $\mathrm{N}$

The correct answer is:
polyacrylonitrile

Solution:
$$
\text { Polyacrylonitrile or orlon or acrilan, }
$$

Topic: Chemistry, Polymers, NEET, NEET 2019 (Odisha)
The polymerase chain reaction is a technique that

Options:
A Is used for in vivo replication of DNA
B Is used for in vivo synthesis of mRNA
C Is used for in vitro synthesis of mRNA
D Is used for in vitro replication of specific DNA sequence using thermostable DNA polymerase.

The correct answer is:
Is used for in vitro replication of specific DNA sequence using thermostable DNA polymerase.

Solution:
PCR is a technique in which a specific segment of DNA is replicated using taq DNA polymerase which is resistant to high temperature. PCR is based on principle that at high temperature double stranded DNA separates as single stranded DNA at a low temperature annealing occurs.

Topic: Biology, Biotechnology - Principles and Processes, NEET
The polymers can be classified on the basis of their mode of formation as

Options:
A As copolymers
B As condensation polymers only
C As addition polymers only
D Both as addition and condensation polymers

The correct answer is:
Both as addition and condensation polymers

Solution:
On the basis of their mode of formation polymers can be classified both as addition and condensation polymers.

Topic: Chemistry, Polymers, NEET
The population interactions in which one organism is harmed and the other is not affected and is widely used in medical science for the action of antibiotics is

Options:
A Commensalism
B Parasitism
C Mutualism
D Amensalism

The correct answer is:
Amensalism

Solution:
Amensalism is an interaction in which a chemical substance produced one organism inhibits the growth of another organism or kills other organism. Thus one organism which produces the chemical is not effected and the other is harmed. Antibiotics are chemicals produced by one organism which kills or inhibits the growth of other organism.

Topic: Biology, Organisms and Populations, NEET
The population of a city was 6000. In the year 2019, there were 2050 new births in the city and 650 deaths. 1325 people migrated into to the city while 175 people left the city. What was be the population of the city at the end of the year 2019?

Options:
A 7200
B 3450
C 8550
D 8900

The correct answer is:
8550

Solution:
Births and Immigration increase population while deaths and emigration decrease the population. Population at the end of 2019 = Initial population + Births + Immigration - Deaths - Emigration = 6000 + 2050 + 1325 - 650 - 175 = 8550.

Topic: Biology, Organisms and Populations, NEET
The population of an insect species shows an explosive increase in numbers during rainy season followed by its disappearance at the end of the season. What does the pattern of population show?

Options:
A S-shaped or sigmoid growth of this insect
B The food plants mature and die at the end of rainy season
C Its population growth curve is of J-type
D The population of its predators increases enormously

The correct answer is:
Its population growth curve is of J-type

Solution:
Its population growth curve is J-shaped in which density increases rapidly in exponential fashion and then stops abruptly as environmental resistance or another limiting factor becomes effective more or less suddenly. Any species growing exponentially under unlimited resource conditions can reach enormous population densities in a short time.

Topic: Biology, Organisms and Populations, NEET
The pore of gastrula is called

Options:
A blastopore
B gonopore
C zygopore
D endospore

The correct answer is:
blastopore

Solution:
Gastrulation is the process by which a blastula converts into gastrula. During gastrulation, a three-layered embryo made of ectoderm, mesoderm and endoderm enclosing a new cavity, called archenteron, is formed. The lumen of the archenteron forms the future gut, which opens outside through the blastopore. In protostomes, the blastopore becomes the mouth, and in deuterostomes, the anus.

Topic: Biology, Human Reproduction, NEET
The portion of the embryonal axis above the level of attachement of scutellum is

Options:
A Hypocotyl
B Epicotyl
C Radical
D Coleorhizae

The correct answer is:
Epicotyl

Solution:
The portion of embryonal axis above the level of the cotyledons is the epicotyls, which terminates with the plumule or stem tip. The cylindrical portion below the level of the cotyledon is the hypocotyls that terminates at the lower end in the radical or root tip.

Topic: Biology, Sexual Reproduction in Flowering Plants, NEET
The portion of the embryonal axis above the level of cotyledons is the

Options:
A Hypocotyl
B Root cap
C Root tip
D Epicotyl

The correct answer is:
Epicotyl

Solution:
The portion of the embryonal axis above the level of cotyledons is the epicotyl, which terminates with the plumule or stem tip. The cylindrical portion below the level of cotyledons is hypocotyl that terminates at its lower end in the radicle or root tip. The root tip is covered with a root cap.

Topic: Biology, Sexual Reproduction in Flowering Plants, NEET
The position and velocity of a particle executing simple harmonic motion at t=0 are given by 3 cm and 8 cm s-1 respectively. If the angular frequency of the particle is 2 rad s-1, then the amplitude of oscillation (in cm) is

Options:
A 3
B 4
C 5
D 6

The correct answer is:
5

Solution:
Given, the position and velocity of the particle executing SHM .
y=3 cm
v=8 cm s-1
Angular frequency, ω=2 rad s-1
The velocity,
v=ωa2-y2
8=2a2-32
4=a2-32
16=a2-9
a2=25
a=5 cm

Topic: Physics, Oscillations, NEET
The position coordinates of a particle moving in X-Y as a function of time t are
x=2t2+6t+25
y=t2+2t+1
The speed of the object at t=10 s is approximately

Options:
A 31 units
B 51 units
C 71 units
D 81 units

The correct answer is:
51 units

Solution:
Given, x=2t2+6t+25 and y=t2+2t+1
∴ dxdt=4t+6 and dydt=2t+2
At t=10 s
dxdt=410+6=46 and dydt=2 10+2=22
v=dxdt2+dydt2
=462+222≃51 units

Topic: Physics, Motion In One Dimension, NEET
The position of a particle is given by $r=3.0t-2.0{{t}^{2}}\hat{j}+4.0\hat{k}$ where t is in seconds and the coefficients have the proper units for r to be in meters. Find the v and a of the particle?

Options:
A $a\left( t \right)=-~4.0\hat{j}~,~v\left( t \right)=~3.0\hat{i}+3.0\hat{j}$
B $a\left( t \right)=~5.0\hat{j}~,~v\left( t \right)=~4.0\hat{i}+4.0\hat{j}$
C $a\left( t \right)=~-4.0\hat{j}~,~v\left( t \right)=~3.0\hat{i}-4.0\hat{j}$
D $a\left( t \right)=~-5.0\hat{j}~,~v\left( t \right)=~3.0\hat{i}+4.0\hat{j}$

The correct answer is:
$a\left( t \right)=~-4.0\hat{j}~,~v\left( t \right)=~3.0\hat{i}-4.0\hat{j}$

Solution:
Correct Option is : (C)
$a\left( t \right)=~-4.0\hat{j}~,~v\left( t \right)=~3.0\hat{i}-4.0\hat{j}$

Topic: Chemistry, Motion In Two Dimensions, NEET
The position of a particle is given by $r=3.0t\hat{i}+2.0{{t}^{2}}\hat{j}+5.0\hat{k}$ where t is in seconds and the coefficients have the proper units for r to be in meters. Find v(t) and a(t) of the particle.

Options:
A $a\left( t \right)=~4.0\hat{j}~,~v\left( t \right)=~3.0\hat{i}+3.0\hat{j}$
B $a\left( t \right)=~5.0\hat{j}~,~v\left( t \right)=~4.0\hat{i}+4.0\hat{j}$
C $a\left( t \right)=~4.0\hat{j}~,~v\left( t \right)=~3.0\hat{i}+4.0\hat{j}$
D $a\left( t \right)=~5.0\hat{j}~,~v\left( t \right)=~3.0\hat{i}+4.0\hat{j}$

The correct answer is:
$a\left( t \right)=~4.0\hat{j}~,~v\left( t \right)=~3.0\hat{i}+4.0\hat{j}$

Solution:
Correct Option is : (C)
$a\left( t \right)=~4.0\hat{j}~,~v\left( t \right)=~3.0\hat{i}+4.0\hat{j}$

Topic: Chemistry, Motion In Two Dimensions, NEET
The position of a particle is given by
$\vec{r}(t)=4 t \hat{i}+2 t^2 \hat{j}+5 \hat{k}$
where $t$ is in seconds and $r$ in metre. Find the magnitude and direction of velocity $v(t)$, at $t=1 \mathrm{~s}$, with respect to $x$-axis.

Options:
A $3 \sqrt{2} \mathrm{~ms}^{-1}, 30^{\circ}$
B $3 \sqrt{2} \mathrm{~ms}^{-1}, 45^{\circ}$
C $4 \sqrt{2} \mathrm{~ms}^{-1}, 45^{\circ}$
D $4 \sqrt{2} \mathrm{~ms}^{-1}, 60^{\circ}$

The correct answer is:
$4 \sqrt{2} \mathrm{~ms}^{-1}, 45^{\circ}$

Solution:
$\begin{aligned} & \vec{r}(t)=\left(4 t \hat{i}+2 t^2 \hat{j}+5 \hat{k}\right) \mathrm{m} \\ & \frac{d \vec{r}(t)}{d t}=4 \hat{i}+\left.4 t \hat{j}\right|_{t=1} \mathrm{~ms}^{-1} \\ & \vec{v}=4 \hat{i}+4 \hat{j} \mathrm{~ms}^{-1} \\ & |\vec{v}|=\sqrt{4^2+4^2}=4 \sqrt{2} \mathrm{~ms}^{-1} \\ & \tan \phi=\frac{v_y}{v_x}=\frac{4}{4}=1 \\ & \phi=45^{\circ}\end{aligned}$

Topic: Physics, Motion In One Dimension, NEET, NEET 2023 (Manipur)
The position of a particle moving along x-axis is given by x=x0cos2(ωt) . Its speed when it is at mean position is

Options:
A 2x0ω
B x0ω2
C x0ω2
D x0ω

The correct answer is:
x0ω

Solution:
x=x0cos2ωt

∴x=x0cos2ωt+12

⇒x=x02+x02cos2ωt
∴dxdt=–x02sin2ωt . 2ω

⇒dxdt=–ωx0sin2ωt
So, the speed at mean position is v0=ωx0

Topic: Physics, Oscillations, NEET
The position of an object moving along x-axis is given by x = $a+b{{t}^{2}}$ where a = 8.5 m, b = 2.5 $m{{s}^{-2}}$ and t is measured in seconds. What is its velocity at t = 0 s and t = 2.0 s. What is the average velocity between t = 2.0 s and t = 4.0 s ?

Options:
A 15 m/s
B 20 m/s
C 10 m/s
D 30 m/s

The correct answer is:
15 m/s

Solution:
Correct Option is : (A)
15 m/s

Topic: Chemistry, Motion In One Dimension, NEET
The position of both, an electron and a helium atom is known within 1.0 nm. Further the momentum of the electron is known within 5.0Ã 10 â26 kgms â1 . The minimum uncertainty in the measurement of the momentum of the helium atom is

Options:
A 6.0×10-26 kgms-1
B 60 kgms-1
C 50 kgms-1
D 5.0×10-26 kgms-1

The correct answer is:
5.0×10-26 kgms-1

Solution:
According to uncertainty principle the product of uncertainty in position and uncertainty in momentum is constant for a particle.
i.e., Δx×Δp=h4π
As Δx=1.0 nm for both electron and helium atom, so Δp is also same for both the particle.
Thus, uncertainty in momentum of the helium atom is also 5.0×10-26kgms-1 .

Topic: Chemistry, Structure of Atom, NEET
The position of some metals in the electrochemical series in decreasing electropositive character is given as Mg>Al>Zn>Cu>Ag. What change will happens, if a copper spoon is used to stir a solution of aluminium nitrate?

Options:
A The solution becomes blue
B The spoon will get coated with Al
C An alloy of Cu and Al is formed
D There is no reaction

The correct answer is:
There is no reaction

Solution:
The metal placed below (less reactive) in electrochemical series does not react with that metal salt solution which metal is placed above (more reactive) in series.

Topic: Chemistry, Electrochemistry, NEET
The position of the point where the net electric field will be zero is

Options:
A 2a from 4Q
B a/2 from -Q
C 2a from -Q
D neutral point is not possible

The correct answer is:
2a from 4Q

Solution:
x=a×Q4Q-Q
⇒x=a×12-1=a

Topic: Physics, Electrostatics, NEET
The position time graph of a body of mass 2 kg is as given in Fig. What is the impulse on the body at t = 0 s

Options:
A 0
B 5 kgm/s
C 10 kgm/s
D 15 kgm/s

The correct answer is:
0

Solution:
Correct Option is : (A)
0

Topic: Chemistry, Laws of Motion, NEET
The position vector of a particle is râ=3i^+4j^ metre and its angular velocity Ïâ=j^+2k^ rad s-1 then its linear velocity is in m s-1

Options:
A -8i^-6j^+3k^
B 3i^+6j^+8k^
C -3i^+6j^+6k^
D 6i^+8j^+3k^

The correct answer is:
-8i^-6j^+3k^

Solution:
The velocity can be computed using, vâ=ÏâÃrâ
ÏâÃrâ=i^j^k^012340=-8i^+6j^-3k^

Topic: Physics, Mathematics in Physics, NEET
The position vector of a particle moving in the x-y plane at time t is râ=a 1 âcosâ¡Ït i^+ a sinâ¡Ït j^. The path of the particle is :

Options:
A a circle of radius a and centre at a, 0
B a circle of radius a and centre at 0,Â 0
C an ellipse
D neither a circle nor an ellipse

The correct answer is:
a circle of radius a and centre at a, 0

Solution:
Particle is moving in a circle of radius a and centre a, 0 with constant angular velocity Ï . At time t=0 particle is at origin and it starts rotating clockwise. At time t it has rotated an angle Î¸ given by
Î¸=Ït
y=a sinâ¡Î¸=a sinâ¡Ït
and x=a- a cosâ¡Î¸=a 1 â cosâ¡Ït
â´ râ=a 1 â cosâ¡Ït i^+ a sinâ¡Ït j^

Topic: Physics, Laws of Motion, NEET
The position vector of a particle R→ as a function of time is given by:
R→=4sin⁡2πti^+4cos⁡(2πt)j^
Where R is in meters, t is in seconds and i^ and j^ denote unit vectors along x- and y-directions, respectively. Which one of the following statements is wrong for the motion of particle?

Options:
A Magnitude of acceleration vector is v2R , where v is the velocity of particle
B Magnitude of the velocity of particle is 8 meter/second
C Patch of the particle is a circle of radius 4 meter
D Acceleration vector is along -Râ

The correct answer is:
Magnitude of the velocity of particle is 8 meter/second

Solution:
x=4 sin2πt
y=4cos⁡(2πt)

Squaring and adding

x2+y2=4sin2πt2+4cos2πt2

x2+y2=16

This means the particle is moving in a circle
V=r w=2π4=8π

Topic: Physics, Motion In One Dimension, NEET, NEET 2015 (Phase 2)
The position vectors of two identical particles with respect to the origin in the three-dimensional coordinate system are r1 and r2. The position vector of the centre of mass of the system is given by

Options:
A r1+r2
B 2r1+r2
C r1-r2
D r1 + r22

The correct answer is:
r1 + r22

Solution:
Given, position vector of first particle =r1
Position vector of second particle =r2
m1=m2=m
We know that,
Centre of mass of system
=m1r1+m2r2m1+m2
=mr1+mr2m+m
=mr1+r22m=r1+r22

Topic: Physics, Center of Mass Momentum and Collision, NEET
The position $x$ of a particle with respect to time $t$ along $x$-axis is given by $x=9 t^2$ $-t^3$ where $x$ is in metres and $t$ in second. What will be the position of this particle when it achieves maximum speed along the $+x$ direction?

Options:
A $54 \mathrm{~m}$
B $81 \mathrm{~m}$
C $24 \mathrm{~m}$
D $32 \mathrm{~m}$.

The correct answer is:
$54 \mathrm{~m}$

Solution:
It is given that
$\begin{aligned}
x & =9 t^2-t^3 \\
v & =\frac{d x}{d t}=18 t-3 t^2 \\
\frac{d v}{d t} & =a=18-6 t
\end{aligned}$
for maximum speed $\frac{d v}{d t}=0$ and $\frac{d^2 v}{d t^2}$ negative
So $18-6 t=0$
$\Rightarrow \quad t=3 s$
at $\quad t=3 s, x=9(3)^2-(3)^3$
$=81-27=54 \mathrm{~m}$

Topic: Physics, Motion In One Dimension, NEET, NEET 2007
The position-time $(x-t)$ graph for positive acceleration is:

Options:
A

B

C

D

The correct answer is:

Solution:
As $x=\frac{1}{2} a t^2$, hence the graph between $x$ and $t$ is upward parabola.

Topic: Physics, Motion In One Dimension, NEET, NEET 2022 (Phase 2)
The position-time (x-t) graphs for two children A and B returning from their school O to their homes P and Q respectively along a straight path (taken as x-axis) are shown in the figure below. Choose the incorrect option.

Options:
A A lives closer to the school than B

B A starts from the school earlier than B
C A and B have equal average velocities from 0 to t0
D B overtakes A on the way

The correct answer is:
A and B have equal average velocities from 0 to t0

Solution:
XB > XA
So A lives closer option (i) is correct
A starts at t=0 while B at t=t0
So A starts early
option (ii) is also correct
For average velocity to be same, the slope of both line should be the same which is not the case so (iii) is wrong.
We can clearly see at the point of intersection of two graph (ii) overtakes (i) so (iv) is also correct.

Topic: Physics, Motion In One Dimension, NEET
The position-time (x-t) graphs for two children A and B returning from their school O to their homes P and Q respectively are shown in Fig. 2.9. Choose the correct option from the following

Options:
A B lives closer to the school than A
B A starts from the school earlier than B
C A walks faster than B
D A and B reach home at the different time

The correct answer is:
A starts from the school earlier than B

Solution:
Correct Option is : (B)
A starts from the school earlier than B

Topic: Chemistry, Motion In One Dimension, NEET
The possibility of a female becoming hemophilic is extremely rare because the mother of such a female has to be ____(i)____ and father should be ___(ii)_____.

Options:
A (i) haemophilic, (ii) carrier
B (i) carrier, (ii) haemophilic
C (i) haemophilic, (ii) normal
D (i) normal, (ii) haemophilic

The correct answer is:
(i) carrier, (ii) haemophilic

Solution:
Haemophilia is a X-linked recessive blood disorder. In it, the individual has delayed clotting time for blood which can be fatal. X-lined disorders are inherent disorders due to mutation in the X-chromosome which causes the phenotype to be always expressed in male and in female only in homozygous condition. For a daughter to be haemophilic, her father must be haemophilic as she receives one X-chromosome from him. And mother must be a carrier if not haemophilic to pass the X- chromosome to daughter.

Topic: Biology, Principles of Inheritance and Variation, NEET
The possible beneficial aspect of grazing animals is the

Options:
A Removal of wild animals and pests
B Eradication of weeds
C Removal of wild plants
D Addition of their excreta into the soil

The correct answer is:
Addition of their excreta into the soil

Solution:
Grazing animals are very harmful because over grazing leads to destruction of vegetation and also cause desertification. The possible beneficial aspect of grazing animals is the addition of their excreta (dung) into the soil, which increases soil fertility.

Topic: Biology, Environmental Issues, NEET
The possible number of isomers (both striuctural and stereo) for the complex [MBr2Cl2]SO4 is

Options:
A 2
B 4
C 5
D 7

The correct answer is:
5

Solution:
The complex ion [MBr2Cl2]2+ shows geometrical isomerism.
The geometrical isomers are
(i) cis- [MBr2Cl2]SO4
(ii) trans- [MBr2Cl2]SO4
The compound also shows ionization isomerism. The ionization isomers are
(i) [MBr2(SO4)]Cl2
(ii) [MCl2(SO4)]Br2
(iii) [MBrCl(SO4)]BrCl
Thus, a total of five isomers are formed.

Topic: Chemistry, Coordination Compounds, NEET
The posterior lobe of the pituitary is called

Options:
A Glandularhypophysis
B Neurohypophysis
C Adenohypophysis
D Vascularhypophysis

The correct answer is:
Neurohypophysis

Solution:
The posterior lobe of the pituitary is called neurohypophysis and is composed of non-myelinated nerve fibres and branching nerve cells. It stores and releases two hormones oxytocin and vasopressin.

Topic: Biology, Chemical Coordination and Integration, NEET
The posterior pituitary gland is not a 'true' endocrine gland because

Options:
A It is provided with a duct
B It only stores and releases hormones
C It is under the regulation of hypothalamus pressure pulling at the lung walls.
D It secretes enzymes

The correct answer is:
It only stores and releases hormones

Solution:
The posterior pituitary gland is not a true endocrine gland because it only stores and releases hormones. The posterior lobe contains the ends of nerve cells coming from the hypothalamus. The hypothalamus sends hormones directly to the posterior lobe via these nerves, and then the pituitary gland releases them.

Antidiuretic hormone (ADH) or Vasopressin: This hormone prompts the kidneys to increase water absorption in the blood.

Oxytocin is involved in a variety of processes, such as contracting the uterus during childbirth and stimulating breast milk production.

Topic: Biology, Chemical Coordination and Integration, NEET, NEET 2016 (Phase 2)
The postulate on which the photoelectric equation is derived is

Options:
A Light is emitted only when electrons jump between orbits
B Light is absorbed in quanta of energy E=hν
C Electrons are restricted to orbits of angular momentum nh2π where n is an integer
D Electrons are associated with wave of wavelength λ=hp where p is the momentum

The correct answer is:
Light is absorbed in quanta of energy E=hν

Solution:
When light of sufficiently low wavelength fall on a metal surface, electrons are ejected. This phenomenon is called the photoelectric effect and can be understood in terms of the particle nature of light. i.e. if ν is the frequency light that falls on metallic surface, which eject an electron, then we can say that E=hÎ½ quanta of energy is absorbed during photoelectric emission.

Topic: Physics, Dual Nature of Matter, NEET
The potential at a point x (measured in Î¼m) due to some charges situated on the x-axis is given by Vx=20x2 - 4 volt. The electric field E at x=4 Î¼m is given by

Options:
A 53Vμm and in positive x -direction
B 109Vμm and in negative x -direction
C 109Vμm and in positive x -direction
D 53Vμm and in negative x -direction

The correct answer is:
109Vμm and in positive x -direction

Solution:
Here, Vx=20x2-4 V
As, E=-dVdx
=-ddx20x2-4
=+201x2-42â2x
E=40xx2-42
at x=4 m,
E=40Ã442-42
=160144
=109 V/Î¼m in positive x -direction

Topic: Physics, Electrostatics, NEET
The potential difference across the resting membrane is negative. This is due to the differential distribution of the following ions

Options:
A Na⁺ and K⁺
B CO₃⁺ and CI
C Ca⁺⁺ and Mg⁺⁺
D Ca⁺⁺ and CI

The correct answer is:
Na⁺ and K⁺

Solution:
The potential difference across the resting membrane is negative due to the differential distribution of Na⁺ and K⁺

Topic: Biology, Neural Control and Coordination, NEET
The potential difference across the terminals of a cell varies with the current drawn from the cell, according to the graph

Options:
A
B
C
D

The correct answer is:

Solution:
When current is drawn from cell, its cell potential decreases linearly and it becomes zero, when the cell is discharged.

Topic: Chemistry, Electrochemistry, NEET
The potential difference between A and B in the following circuit is

Options:
A 4 V
B 5.6 V
C 2.8 V
D 6 V

The correct answer is:
4 V

Solution:
Applying Kirchhoff's voltage law,
I2+8=6+4
I.10=10
I=1 A
VA-IÃ2+6=VB
VA-VB=1Ã2-6
And VBA=4 V

Topic: Physics, Current Electricity, NEET
The potential difference between A and B in the following figure is

Options:
A 32Â V
B 48 V
C 24Â V
D 14Â V

The correct answer is:
48 V

Solution:
According to Kirchhoff voltage law
VA â2 Ã 6- 12- 2 Ã 9+4- 2 Ã 5=VB
â´ VA- VB=48 V

Topic: Physics, Current Electricity, NEET
The potential difference between the fixed charged layer and the diffused layer having opposite charge is called:

Options:
A Water potential
B Zeta potential
C Electrode potential
D None of these

The correct answer is:
Zeta potential

Solution:
The potential difference between the fixed charged layer and the diffused layer having opposite charge is called Zeta potential.

Topic: Chemistry, Surface Chemistry, NEET