datavorous/entrance-exam-dataset huggingface dataset:
Match List-I with List-II.
Choose the correct answer from the options given below :

Options:
A $(A) -\mathrm{II},(\mathrm{B})-\mathrm{III},(\mathrm{C})-\mathrm{IV},(\mathrm{D})-\mathrm{I}$
B $(A) -\mathrm{III},(\mathrm{B})-\mathrm{IV},(\mathrm{C})-\mathrm{I},(\mathrm{D})-\mathrm{II}$
C $(A) -\mathrm{II},(\mathrm{B})-\mathrm{III},(\mathrm{C})-\mathrm{I},(\mathrm{D})-\mathrm{IV}$
D $(A) -\mathrm{III},(\mathrm{B})-\mathrm{I},(\mathrm{C})-\mathrm{IV},(\mathrm{D})-\mathrm{II}$

The correct answer is:
$(A) -\mathrm{III},(\mathrm{B})-\mathrm{IV},(\mathrm{C})-\mathrm{I},(\mathrm{D})-\mathrm{II}$

Solution:
$\begin{array}{lll}\text { Pteropsida } & - & \text { Adiantum } \\ \text { Lycopsida } & - & \text { Selaginella } \\ \text { Psilopsida } & - & \text { Psilotum } \\ \text { Sphenopsida } & - & \text { Equisetum }\end{array}$

Topic: Biology, Plant Kingdom, NEET, NEET 2023 (Manipur)
Match List-I with List-II
Choose the correct answer from the options given below :

Options:
A $(A) -\mathrm{II},(\mathrm{B})-\mathrm{III},(\mathrm{C})-\mathrm{I},(\mathrm{D})-\mathrm{IV}$
B $(A) -\mathrm{IV},(\mathrm{B})-\mathrm{III},(\mathrm{C})-\mathrm{II},(\mathrm{D})-\mathrm{I}$
C $(A) -\mathrm{III},(\mathrm{B})-\mathrm{II},(\mathrm{C})-\mathrm{IV},(\mathrm{D})-\mathrm{I}$
D $(A) -\mathrm{III},(\mathrm{B})-\mathrm{I},(\mathrm{C})-\mathrm{IV},(\mathrm{D})-\mathrm{II}$

The correct answer is:
$(A) -\mathrm{III},(\mathrm{B})-\mathrm{II},(\mathrm{C})-\mathrm{IV},(\mathrm{D})-\mathrm{I}$

Solution:
Chlorophyll a appears bright or blue green in the chromatogram
Chlorophyll b appears yellow green in the chromatogram
Xanthophyll appears yellow in the chromatogram
Carotenoid appears yellow to yellow-orange in the chromatogram

Topic: Biology, Photosynthesis in Higher Plants, NEET, NEET 2023 (Manipur)
Match List-I with List-II.
Choose the correct answer from the options given below :

Options:
A $(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{III}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{IV})$
B $(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{III}),(\mathrm{C})-(\mathrm{IV}),(\mathrm{D})-(\mathrm{I})$
C $(\mathrm{A})-(\mathrm{III}),(\mathrm{B})-(\mathrm{II}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{IV})$
D $(\mathrm{A})-(\mathrm{III}),(\mathrm{B})-(\mathrm{II}),(\mathrm{C})-(\mathrm{IV}),(\mathrm{D})-(\mathrm{I})$

The correct answer is:
$(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{III}),(\mathrm{C})-(\mathrm{IV}),(\mathrm{D})-(\mathrm{I})$

Solution:
Option (2) is correct answer because
(A) Columnar epithelium is present in inner lining of stomach and intestine
(B) Ciliated epithelium is present in inner lining of bronchioles
(C) Squamous epithelium present in inner lining of blood vessels and is called endothelium
(D) Cuboidal epithelium is present in the lining of renal tubules and ducts of glands

Topic: Biology, Structural Organisation in Animals, NEET, NEET 2023 (Manipur)
Match List-I with List-II.
Choose the correct answer from the options given below :

Options:
A $(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{III}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{IV})$
B $(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{IV}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{III})$
C $(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{IV}),(\mathrm{C})-(\mathrm{III}),(\mathrm{D})-(\mathrm{I})$
D $(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{I}),(\mathrm{C})-(\mathrm{IV}),(\mathrm{D})-(\mathrm{III})$

The correct answer is:
$(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{IV}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{III})$

Solution:
Option (2) is the answer because diterpenes belong to the category of terpenoides. Concanavalin A is a lectin.
- Codeine is an alkaloid
- Ricin is a toxin

Topic: Biology, Biomolecules (B), NEET, NEET 2023 (Manipur)
Match List-I with List-II
Choose the correct answer from the options given below:

Options:
A $(A) -\mathrm{I},(\mathrm{B})-\mathrm{III},(\mathrm{C})-\mathrm{I},(\mathrm{D})-\mathrm{II}$
B $(A) -\mathrm{III},(\mathrm{B})-\mathrm{II},(\mathrm{C})-\mathrm{I},(\mathrm{D})-\mathrm{IV}$
C $(A) -\mathrm{II},(\mathrm{B})-\mathrm{I},(\mathrm{C})-\mathrm{IV},(\mathrm{D})-\mathrm{III}$
D $(A) -\mathrm{IV},(\mathrm{B})-\mathrm{III},(\mathrm{C})-\mathrm{II},(\mathrm{D})-\mathrm{I}$

The correct answer is:
$(A) -\mathrm{IV},(\mathrm{B})-\mathrm{III},(\mathrm{C})-\mathrm{II},(\mathrm{D})-\mathrm{I}$

Solution:
Auxin promotes flowering in pineapple. Gibberellin increases the length of grape stalks.
Cytokinin overcome apical dominance. Ethylene promotes female flower formation in cucumber.

Topic: Biology, Plant - Growth and Development, NEET, NEET 2023 (Manipur)
Match List-I with List-II.
Choose the correct answer from the options given below :

Options:
A $(A) -\mathrm{IV},(\mathrm{B})-\mathrm{I},(\mathrm{C})-\mathrm{II},(\mathrm{D})-\mathrm{III}$
B $(A) -\mathrm{I},(\mathrm{B})-\mathrm{IV},(\mathrm{C})-\mathrm{III},(\mathrm{D})-\mathrm{II}$
C $(A) -\mathrm{II},(\mathrm{B})-\mathrm{I},(\mathrm{C})-\mathrm{IV},(\mathrm{D})-\mathrm{III}$
D $(A) -\mathrm{IV},(\mathrm{B})-\mathrm{III},(\mathrm{C})-\mathrm{I},(\mathrm{D})-\mathrm{II}$

The correct answer is:
$(A) -\mathrm{IV},(\mathrm{B})-\mathrm{I},(\mathrm{C})-\mathrm{II},(\mathrm{D})-\mathrm{III}$

Solution:
Option (1) is correct answer because
A. Proteins have Peptide bonds
B. Unsaturated fatty acid contains $\mathrm{C}=\mathrm{C}$ double bonds
C. Phosphodiester bonds present in nucleic acid
D. Glycosidic bonds present in polysaccharide

Topic: Biology, Biomolecules (B), NEET, NEET 2023 (Manipur)
Match List-I with List-II
Choose the correct answer from the options given below :

Options:
A $(\mathrm{A})-(\mathrm{IV}),(\mathrm{B})-(\mathrm{III}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{II})$
B $(\mathrm{A})-(\mathrm{III}),(\mathrm{B})-(\mathrm{I}),(\mathrm{C})-(\mathrm{IV}),(\mathrm{D})-(\mathrm{II})$
C $(\mathrm{A})-(\mathrm{IV}),(\mathrm{B})-(\mathrm{I}),(\mathrm{C})-(\mathrm{III}),(\mathrm{D})-(\mathrm{II})$
D $(\mathrm{A})-(\mathrm{I}),(\mathrm{B})-(\mathrm{IV}),(\mathrm{C})-(\mathrm{III}),(\mathrm{D})-(\mathrm{II})$

The correct answer is:
$(\mathrm{A})-(\mathrm{III}),(\mathrm{B})-(\mathrm{I}),(\mathrm{C})-(\mathrm{IV}),(\mathrm{D})-(\mathrm{II})$

Solution:
Option (2) is the answer because, the P-wave represents the electrical excitation (depolarisation) of the atria which leads to the contraction of both the atria. The QRS complex represents the depolarisation of the ventricles. The T-wave represents the return of the ventricles from excited to normal state (Repolarisation). The end of the T-wave marks the end of systole.

Topic: Biology, Body Fluids and Circulation, NEET, NEET 2023 (Manipur)
Match List-I with List-II
Choose the correct answer from the options given below:

Options:
A $(\mathrm{A})-(\mathrm{III}),(\mathrm{B})-(\mathrm{I}),(\mathrm{C})-(\mathrm{IV}),(\mathrm{D})-(\mathrm{II})$
B $(\mathrm{A})-(\mathrm{III}),(\mathrm{B})-(\mathrm{IV}),(\mathrm{C})-(\mathrm{II}),(\mathrm{D})-(\mathrm{I})$
C $(\mathrm{A})-(\mathrm{IV}),(\mathrm{B})-(\mathrm{III}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{II})$
D $(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{IV}),(\mathrm{C})-(\mathrm{III}),(\mathrm{D})-(\mathrm{I})$

The correct answer is:
$(\mathrm{A})-(\mathrm{III}),(\mathrm{B})-(\mathrm{I}),(\mathrm{C})-(\mathrm{IV}),(\mathrm{D})-(\mathrm{II})$

Solution:
Option (1) is the answer because,
The IUDs are presently available as
The non-medicated IUDs e.g Lippes loop
Copper releasing IUDs e.g CuT, Cu7, Multiload 375
Hormone releasing IUDs e.g LNG- 20, Progestasert.
Vaults are barrier made of rubbers.

Topic: Biology, Reproductive Health, NEET, NEET 2023 (Manipur)
Match List-I with List-II.
Choose the correct answer from the options given below :

Options:
A $(A) -\mathrm{II},(\mathrm{B})-\mathrm{III},(\mathrm{C})-\mathrm{IV},(\mathrm{D})-\mathrm{I}$
B $(A) -\mathrm{IV},(\mathrm{B})-\mathrm{III},(\mathrm{C})-\mathrm{I},(\mathrm{D})-\mathrm{II}$
C $(A) -\mathrm{III},(\mathrm{B})-\mathrm{IV},(\mathrm{C})-\mathrm{II},(\mathrm{D})-\mathrm{I}$
D $(A) -\mathrm{II},(\mathrm{B})-\mathrm{IV},(\mathrm{C})-\mathrm{III},(\mathrm{D})-\mathrm{I}$

The correct answer is:
$(A) -\mathrm{III},(\mathrm{B})-\mathrm{IV},(\mathrm{C})-\mathrm{II},(\mathrm{D})-\mathrm{I}$

Solution:
The phenotypic ratio of monohybrid cross is $3: 1$.
The phenotypic ratio of dihybrid cross is $9: 3: 3: 1$.
The phenotypic ratio of incomplete dominance is $1: 2: 1$.
The phenotypic ratio of test cross is $1: 1$.
Thus, the option depicting the correct matches is option (3).

Topic: Biology, Principles of Inheritance and Variation, NEET, NEET 2023 (Manipur)
Match List-I with List-II.
Choose the correct answer from the options given below :

Options:
A $(\mathrm{A})-(\mathrm{III}),(\mathrm{B})-(\mathrm{I}),(\mathrm{C})-(\mathrm{II}),(\mathrm{D})-(\mathrm{IV})$
B $(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{III}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{IV})$
C $(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{III}),(\mathrm{C})-(\mathrm{IV}),(\mathrm{D})-(\mathrm{I})$
D $(\mathrm{A})-(\mathrm{III}),(\mathrm{B})-(\mathrm{I}),(\mathrm{C})-(\mathrm{IV}),(\mathrm{D})-(\mathrm{II})$

The correct answer is:
$(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{III}),(\mathrm{C})-(\mathrm{IV}),(\mathrm{D})-(\mathrm{I})$

Solution:
Option (3) is the answer as it represents the correct match of list I and list II because,
- Cytokine barriers includes interferons which are proteins secreted by virus infected cells to protect non-infected cells from further viral infection.
- Cellular barriers include certain types of W.B.Cs of our body like neutrophils and monocytes and natural killer cells in the blood as well as macrophages in tissues.
- Physiological barriers includes acid in the stomach, tears form eyes and saliva in mouth-all prevent microbial growth.
Physical barriers include skin and mucus coating of respiratory tract, GIT etc.

Topic: Biology, Human Health and Diseases, NEET, NEET 2023 (Manipur)
Match List-I with List-II.
Choose the correct answer from the options given below:

Options:
A $(\mathrm{A})-(\mathrm{III}),(\mathrm{B})-(\mathrm{IV}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{II})$
B $(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{III}),(\mathrm{C})-(\mathrm{IV}),(\mathrm{D})-(\mathrm{I})$
C $(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{III}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{IV})$
D $(\mathrm{A})-(\mathrm{IV}),(\mathrm{B})-(\mathrm{I}),(\mathrm{C})-(\mathrm{II}),(\mathrm{D})-(\mathrm{III})$

The correct answer is:
$(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{III}),(\mathrm{C})-(\mathrm{IV}),(\mathrm{D})-(\mathrm{I})$

Solution:
Option (2) is the correct answer because, in each fore limb, metacarpals (palm bones) are 5 in number. Carpals are also known as wrist bones and they are 8 in numbers. In each limb, 14 phalanges (digits) are present. In each hind limb, tarsals (ankle bones) are 7 in number and metatarsals 5 in number.

Topic: Biology, Locomotion and Movement, NEET, NEET 2023 (Manipur)
Match List-I with List-II.
Choose the correct answer from the options given below.

Options:
A $(\mathrm{A})-(\mathrm{IV}),(\mathrm{B})-(\mathrm{III}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{II})$
B $(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{IV}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{III})$
C $(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{III}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{IV})$
D $(\mathrm{A})-(\mathrm{III}),(\mathrm{B})-(\mathrm{I}),(\mathrm{C})-(\mathrm{IV}),(\mathrm{D})-(\mathrm{II})$

The correct answer is:
$(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{III}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{IV})$

Solution:
Option (3) is the answer because, Kanamycin is an antibiotic which can be used as selectable marker for $E$. coli.
Clal is a restriction site on plasmid pBR322.
Disarmed retroviruses are used to deliver genes into animal cells, which is an indirect method of gene transfer.
Kanamycin ${ }^R$ gene exhibits resistance against kanamycin which is an antibiotic.

Topic: Biology, Biotechnology - Principles and Processes, NEET, NEET 2023 (Manipur)
Match List-I with List-II:
Choose the correct answer from the options given below:

Options:
A A-III, B-IV, C-I, D-II
B A-IV, B-I, C-III, D-II
C A-IV, B-III, C-II, D-I
D A-IV, B-III, C-I, D-II

The correct answer is:
A-IV, B-III, C-I, D-II

Solution:

Topic: Chemistry, Thermodynamics (C), NEET, NEET 2024 (Re-NEET)
Match List-I with List-II:
Choose the correct answer from the options given below:

Options:
A A-I, B-II, C-IV, D-III
B A-I, B-IV, C-III, D-II
C A-I, B-IV, C-II, D-III
D A-IV, B-I, C-II, D-III

The correct answer is:
A-I, B-IV, C-II, D-III

Solution:
\begin{array}{lll} Element & & Block/group in periodic table \\Ce (Z=58) & \rightarrow & Lanthanoid \\As (Z=33) & \rightarrow & p-block element \\Cs (Z=55) & \rightarrow & s-block element \\Mn (Z=25) & \rightarrow & d-block element\end{array}
A-I, B-IV, C-II, D-III

Topic: Chemistry, Classification of Elements and Periodicity in Properties, NEET, NEET 2024 (Re-NEET)
Match List-I with List-II:
Choose the correct answer from the options given below:

Options:
A A-II, B-IV, C-III, D-I
B A-II, B-III, C-I, D-IV
C A-I, B-II, C-III, D-IV
D A-IV, B-II, C-III, D-I

The correct answer is:
A-II, B-IV, C-III, D-I

Solution:
- Nucleus as a cell organelle was first described by Robert Brown as early as 1831.
- Later the material of the nucleus stained by the basic dyes was given the name chromatin by Flemming.
- Ribosomes are the granular structure first observed under the microscope as dense particle by George Palade.
- Camillo Golgi first observed densely stained reticular structure near the nucleus. It consist of many disc shaped sac or cisternae.
Hence, A-II, B-IV, C-III, D-I is correct.

Topic: Biology, Cell - The Unit of Life, NEET, NEET 2024 (Re-NEET)
Match List-I with List-II :
Choose the correct answer from the options given below:

Options:
A A-III, B-IV, C-I, D-II
B A-IV, B-I, C-III, D-II
C A-IV, B-III, C-II, D-I
D A-IV, B-III, C-I, D-II

The correct answer is:
A-IV, B-III, C-I, D-II

Solution:

Topic: Chemistry, Practical Chemistry, NEET, NEET 2024 (Re-NEET)
Match List-I with List-II
Choose the correct answer from the options given below.

Options:
A A-I, B-II, C-III, D-IV
B A-II, B-III, C-IV, D-I
C A-III, B-IV, C-I, D-II
D A-IV, B-I, C-II, D-III

The correct answer is:
A-IV, B-I, C-II, D-III

Solution:
Correct answer is option (4)

Topic: Biology, Biomolecules (B), NEET, NEET 2024
Match List-I with List-II :
Choose the correct answer from the options given below:

Options:
A (a) - (i), (b) - (iv), (c) - (iii), (d) - (ii)
B (a) - (ii), (b) - (i), (c) - (iv), (d) - (iii)
C (a) - (iii), (b) - (ii), (c) - (i), (d) - (iv)
D (a) - (iv), (b) - (iii), (c) - (ii), (d) - (i)

The correct answer is:
(a) - (ii), (b) - (i), (c) - (iv), (d) - (iii)

Solution:
These all are methods of Asexual reproduction.

Topic: Biology, Animal Kingdom, NEET, NEET 2022 (Phase 2)
Match List-I with List-II :
Identify the correct answer from the options given below:

Options:
A A-III, B-I, C-IV, D-II
B A-I, B-IV, C-III, D-II
C A-II, B-IV, C-I, D-III
D A-III, B-IV, C-I, D-II

The correct answer is:
A-III, B-IV, C-I, D-II

Solution:
The correct match is A-III, B-IV, C-I, D-II

Topic: Chemistry, Classification of Elements and Periodicity in Properties, NEET, NEET 2024 (Re-NEET)
Match list-I with List-II :

List - I	List - II

A. Coke	I. Carbon atoms are sp3 hybridised

B. Diamond	II. Used as dry lubricants

C. Fullerene	III. Used as a reducing agent

D. Graphite	IV. Cage like molecules

Choose the correct answer from the options given below:

Options:
A A-III, B-IV, C-I, D-II
B A-II, B-IV, C-I, D-III
C A-IV, B-I, C-II, D-III
D A-III, B-I, C-IV, D-II

The correct answer is:
A-III, B-I, C-IV, D-II

Solution:
Coke when reacted with moderately reactive metal oxides at high temperature it forms CO and free metal during the metallurgical process. In this way coke play the role of removal of oxygen from metal oxide and hence act as reducing agent.

In diamond each carbon atom undergoes sp3 hybridisation and linked to four other carbon atoms by using hybridised orbitals in tetrahedral fashion.

Fullerenes are the only pure form of carbon because they have smooth structure without having ‘dangling’ bonds. Fullerenes are cage like molecules.

Graphite cleaves easily between the layers and, therefore, it is very soft and slippery. For this reason graphite is used as a dry lubricant in machines running at high temperature, where oil cannot be used as a lubricant.

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), NEET, NEET 2023 (All India)
Match List-I with List-II :
$\begin{array}{|l|l|}
\hline \begin{array}{c}
\text{List-I} \\
\text{(Complexes)}
\end{array} & \begin{array}{c}
\text{List-II} \\
\text{(Types)}
\end{array} \\
\hline (a) \left[\mathrm{CO}\left(\mathrm{NH}_3\right)_5 \mathrm{NO}_2\right] \mathrm{Cl}_2 & \text{(i) } \text{ionisation} \\
\text{and} \left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{ONO}\right] & \text{isomerism} \\
\mathrm{Cl}_2 & \\
\hline (b) \left[\mathrm{Cr}\left(\mathrm{NH}_3\right)_6\right]\left[\mathrm{CO}(\mathrm{CN})_6\right] & \text{(ii) } \text{coordination} \\
\text{and } \left[\mathrm{Cr}(\mathrm{CN})_6\right] & \text{isomerism} \\
{\left[\mathrm{CO}\left(\mathrm{NH}_3\right)_6\right]} & \\
\hline (c) \left[\mathrm{CO}\left(\mathrm{NH}_3\right)_5\left(\mathrm{SO}_4\right)\right] \mathrm{Br} \text{ and} & \text{(iii) } \text{linkage} \\
{\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{Br}^2\right] \mathrm{SO}_4} & \text{isomerism} \\
\hline (d) \left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right] \mathrm{Cl}_3 \text{ and} & \text{(iv) } \text{solvate} \\
{\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_5 \mathrm{Cl}\right] \mathrm{Cl}_2 \cdot \mathrm{H}_2 \mathrm{O}} & \text{isomerism} \\
\hline
\end{array}$
Choose the correct answer from the options given below :

Options:
A (a)-(iii), (b)-(i), (c)-(ii), (d)-(iv)
B (a)-(ii), (b)-(iii), (c)-(iv), (d)-(i)
C (a)-(iii), (b)-(ii), (c)-(i), (d)-(iv)
D (a)-(iv), (b)-(iii), (c)-(ii), (d)-(i)

The correct answer is:
(a)-(iii), (b)-(ii), (c)-(i), (d)-(iv)

Solution:
(a) $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{NO}_2\right] \mathrm{Cl}_2$ and $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{ONO}\right] \mathrm{Cl}_2$ - linkage Isomerism due to difference in binding site.
(b) $\left[\mathrm{Cr}\left(\mathrm{NH}_3\right)_6\right]\left[\mathrm{Co}(\mathrm{CN})_6\right]$ and $\left[\mathrm{Cr}(\mathrm{CN})_6\right]\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]$
- It is an example of coordination Isomerism due to exchange of ligands between the two coordination spheres.
(c) $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5\left(\mathrm{SO}_4\right)\right] \mathrm{Br}$ and $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{Br} \mathrm{SO}_4\right.$
- It is an example of Ionisation Iosmerism arising due to formation of different ions due to ionisation. The case arises due to exchange of ions between the coordination sphere and ionisation sphere.
(d) $\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right] \mathrm{Cl}_3$ and $\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_5 \mathrm{Cl}\right] \mathrm{Cl}_2 \cdot \mathrm{H}_2 \mathrm{O}$
- It is an example of solvate isomerism arising due to difference in $\mathrm{H}_2 \mathrm{O}$ molecules acting as potential ligand and as water of crystallisation.

Topic: Chemistry, Coordination Compounds, NEET, NEET 2022 (Phase 2)
Match List-I with List-II

List-I(Oxo acids of Sulphur)	List-II(Bonds)

A	Peroxodisulphuric acid	I	Two S-OH, Four S=O, One S-O-S

B	Sulphuric acid	II	Two S-OH, One S=O

C	Pyrosulphuric acid	III	Two S-OH, Four S=O, One S-O-O-S

D	Sulphurous acid	IV	Two S-OH, Two S=O

Options:
A A-III, B-IV, C-I, D-II
B A-I, B-III, C-IV, D-II
C A-III, B-IV, C-II, D-I
D A-I, B-III, C-II, D-IV

The correct answer is:
A-III, B-IV, C-I, D-II

Solution:
The formula for peroxodisulphuric acid is H2S2O8. It has Two S-OH, Four S=O, One S-O-O-S bonds. Sulphuric acid formula is H2SO4. It has Two S-OH, Two S=O bonds. Pyrosulphuric acid has formula H2S2O7 it has two S-OH, four S=O, One S-O-S. Sulphurous acid has formula H2S2O3 and it has two S-OH, one S=O bonds. The structures of the given compounds are given below.

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), NEET, NEET 2023 (All India)
Match List-I with List-II regarding the organs of Cockroach:
Choose the correct answer from the options given below:

Options:
A (a) - (iv), (b) - (i), (c) - (ii), (d) - (iii)
B (a) - (iii), (b) - (ii), (c) - (i), (d) - (iv)
C (a) - (ii), (b) - (iv), (c) - (i), (d) - (iii)
D (a) - (i), (b) - (iv), (c) - (iii), (d) - (ii)

The correct answer is:
(a) - (iv), (b) - (i), (c) - (ii), (d) - (iii)

Solution:

Topic: Biology, Digestion and Absorption, NEET, NEET 2022 (Phase 2)
Match List-I with List-II relating to examples of various kind of IUDs and barrier:
\begin{array}{|l|l|l|l|}\hline & List-I & & List-II \\\hline A. & Copper releasing IUD & I. & Vaults \\\hline B. & Non-medicated IUD & II. & Multiload 375 \\\hline C. & Contraceptive barrier & III. & LNG-20 \\\hline D. & Hormone releasing IUD & IV. & Lippes loop \\\hline\end{array}
Choose the correct answer from the options given below:

Options:
A A-II, B-IV, C-III, D-I
B A-IV, B-III, C-I, D-II
C A-II, B-I, C-III, D-IV
D A-II, B-IV, C-I, D-III

The correct answer is:
A-II, B-IV, C-I, D-III

Solution:
The correct answer is option (4) because
- Multiload 375 is a copper releasing IUD which suppresses sperm motility and fertilizing capacity of sperms.
- Lippes loop is a non-medicated intra uterine device.
- Vaults are barrier type of contraceptives which prevent physical meeting of ovum and sperms.
- LNG-20 is a hormone releasing IUD that makes the uterus unsuitable for implantation and the cervix hostile to the sperms.
Hence the correct matches are
A. Copper releasing IUD - Multiload 375
B. Non-medicated IUD - Lippes loop
C. Contraceptive barrier - Vaults
D. Hormone releasing IUD - LNG-20

Topic: Biology, Reproductive Health, NEET, NEET 2024 (Re-NEET)
Match List-I with List-II relating to human female external genitalia.
$\begin{array}{|l|l|r|l|}\hline & \begin{array}{l} \text{List I} \\ \text{(Structures)} \end{array} & & \begin{array}{l} \text{List II} \\ \text{(Features)} \end{array} \\ \hline A. & \text{Mons pubis} & I. & \text{A fleshy fold of tissue surrounding the vaginal opening} \\ \hline B. & \text{Clitoris} & II. & \text{Fatty cushion of cells covered by skin and hair} \\ \hline C. & \text{Hymen} & III. & \text{Tiny finger-like structure above labia minora} \\ \hline D. & \text{Labina majora} & IV. & \text{A thin membrane-like structure covering vaginal opening }\\ \hline \end{array}$
Choose the correct answer from the option given below :

Options:
A A-II, B-III, C-IV, D-I
B A-IV, B-III, C-II, D-I
C A-I, B-IV, C-III, D-II
D A-II, B-III, C-I, D-IV

The correct answer is:
A-II, B-III, C-IV, D-I

Solution:
The correct answer is option (1) because
- Mons pubis is a cushion of fatty tissue covered by skin and pubic hair. So (A) matches with (II).
- Clitoris is a tiny finger like structure which lies at the upper junction of the two labia minora above the urethral opening. So, (B) matches with (III)
- Hymen is a membrane which partially covers the opening of vagina., So (C) matches with (IV)
- Labia majora are fleshy folds of tissue which extends down from the mons pubis and surround the vaginal opening. So, (D) matches with (I)
Other options (2), (3) and (4) are incorrect as they represent mismatches for (A), (B), (C) and (D)

Topic: Biology, Human Reproduction, NEET, NEET 2024 (Re-NEET)