datavorous/entrance-exam-dataset huggingface dataset:
A micronutrient is the one which is

Options:
A More important than any major elements and are boron (B), chlorine (Cl), copper (Cu), iron (Fe), manganese (Mn), magnesium (Mg), molybdenum (Mo), and zinc (Zn).
B Less important than major elements and are boron (B), chlorine (Cl), copper (Cu), iron (Fe), manganese (Mn), molybdenum (Mo), and zinc (Zn) and phosphorous (P)
C Needed in small quantity but is as important as a major element and are boron (B), chlorine (Cl), copper (Cu), iron (Fe), manganese (Mn), molybdenum (Mo), and zinc (Zn).
D Found small quantities in the soil and are boron (B), chlorine (Cl), copper (Cu), iron (Fe), magnesium (Mg), molybdenum (Mo), and zinc (Zn) and calcium (Ca).

The correct answer is:
Needed in small quantity but is as important as a major element and are boron (B), chlorine (Cl), copper (Cu), iron (Fe), manganese (Mn), molybdenum (Mo), and zinc (Zn).

Solution:
Essential elements required in large quantities are called macro and those required in small quantities are called micronutrient. Essential elements are very much necessary for normal growth and reproduction of the plant, they participate directly in the metabolic reaction, and their deficiency results in deficiency symptoms. The important microelements are boron (B), chlorine (Cl), copper (Cu), iron (Fe), manganese (Mn), molybdenum (Mo), and zinc (Zn).

Topic: Biology, Mineral Nutrition, NEET
A microscope is focussed on a mark on a piece of paper and then a slab of glass of thickness $3 \mathrm{~cm}$ and refractive index 1.5 is placed over the mark. How should the microscope be moved to get the mark in focus again ?

Options:
A $2 \mathrm{~cm}$ upward
B $1 \mathrm{~cm}$ upward
C $4.5 \mathrm{~cm}$ downward
D $1 \mathrm{~cm}$ downward

The correct answer is:
$1 \mathrm{~cm}$ upward

Solution:
$=t\left(1-\frac{1}{4}\right)=3\left(1-\frac{1}{1 \cdot 5}\right)=1 \mathrm{~cm}$

Topic: Physics, Ray Optics, NEET, NEET 2006
A microscope is having an objective of focal length 1 cm and eyepiece of focal length 6 cm. If tube length is 30 cm and the image is formed at the least distance of distinct vision, what is the magnification produced by the microscope? (Take D=25 cm)

Options:
A 6
B 155
C 25
D 125

The correct answer is:
155

Solution:
For a compound microscope,

m=Lf01+Dfe
(Where the length of the tube L=30 cm, the focal length of the objective lens f0=1 cm, the focal length of the eye-piece fe=6 cm, D=25 cm)
⇒m=3011+256=30×6+256
⇒m=5×31
⇒m=155

Topic: Physics, Ray Optics, NEET
A microscope using suitable photons is employed to locate an electron in an atom within a distance of 0.1 Å. What is the uncertainty involved in the measurement of its velocity?

Options:
A 4.23×106m s–1
B 6.85×106m s–1
C 5.79×106m s–1
D 7.56×106m s–1

The correct answer is:
5.79×106m s–1

Solution:
Correct Option is : (C)
5.79×106m s–1

Topic: Chemistry, Structure of Atom, NEET
A millivoltmeter of $25 \mathrm{mV}$ range is to be converted into an ammeter of 25 A range. The value (in ohm) of necessary shunt will be

Options:
A 0.001
B 0.01
C 1
D 0.05

The correct answer is:
0.001

Solution:
The full scale deflection current
$i_g=\frac{25 \mathrm{mV}}{G} \text { ampere }$
where $G$ is the resistance of the meter.
The value of shunt required for converting it into ammeter of range $25 \mathrm{~A}$ is $S=\frac{i_g G}{i-i_g}$
So that, $S \approx \frac{25 \mathrm{mV}}{25}=0.001 \Omega$

Topic: Physics, Current Electricity, NEET, NEET 2012 (Screening)
A millivoltmeter of 25 mV range is to be converted into an ammeter of 25 A range. The value (in ohm) of necessary shunt will be

Options:
A 0.001
B 0.01
C 1
D 0.05

The correct answer is:
0.001

Solution:
Galvanometer is converted into ammeter, by connecting a shunt, in parallel with it.
GSG+S=VGI=25×10−325
GSG+S=0.001 Ω
Here S≪G so S=0.001 Ω

Topic: Physics, Current Electricity, NEET
A mineral deficiency is likely to affect older leaves more than younger leaves if

Options:
A The mineral is a micronutrient
B The mineral is very mobile within the plant
C The mineral is required for chlorophyll synthesis
D The deficiency persists for a short time

The correct answer is:
The mineral is very mobile within the plant

Solution:
Rapid remobilization of minerals creates deficiency first in the older leaves. So older leaves are first to show the deficiency of rapidly remobilized elements.

Topic: Biology, Mineral Nutrition, NEET
A mirror is inclined at an angle Î¸ with the horizontal. If a ray of light is incident on the mirror as shown in the figure, then the angle made by reflected ray with the horizontal is

Options:
A θ
B 2θ
C Î¸/2
D zero

The correct answer is:
zero

Solution:
From the figure, it is clear that reflected ray is parallel to horizontal
â´ ââââÎ¸=0Â°

Topic: Physics, Ray Optics, NEET
A missile is fired for maximum range with a initial velocity of $20 \mathrm{~m} / \mathrm{s}$. If $g=10 \mathrm{~m} / \mathrm{s}^2$, the range of the missile is

Options:
A $50 \mathrm{~m}$
B $60 \mathrm{~m}$
C $20 \mathrm{~m}$
D $40 \mathrm{~m}$

The correct answer is:
$40 \mathrm{~m}$

Solution:
For maximum range of projectile $\theta$ will be $45^{\circ}$ by the law of projectile motion
$$
\therefore \quad R_{\max }=\frac{u^2}{g}
$$
Given, $\quad u=20 \mathrm{~ms}^{-1}$ and $g=10 \mathrm{~ms}^{-2}$
$$
\begin{aligned}
& R_{\max }=\frac{(20)^2}{10}=\frac{400}{10} \\
& R_{\max }=40 \mathrm{~m}
\end{aligned}
$$

Topic: Physics, Motion In Two Dimensions, NEET, NEET 2011 (Screening)
A Mitosis produces two identical daughter cell.

B Meiosis introduces variation due to gene exchange or recombination.

C During anaphase chromosome have two chromatids.

D Telophase I may be absent.

Choose the option with the correct statements.

Options:
A All are correct
B A, B, C are correct
C A, B, D are correct
D C, D are correct

The correct answer is:
A, B, D are correct

Solution:
Mitosis is equational division in which one cell divides to produces two identical daughter cells. Variation are produced in meiosis due to gene exchange which occurs due to crossing over. During anaphase each daughter chromosome has one chromatid only.

Topic: Biology, Cell Cycle and Cell Division, NEET
A mixture consists of two radioactive materials A1 and A2 with half-lives of 20 s and 10 s, respectively. Initially, the mixture has 40 g of A1 and 160 g of A2. The amount of the two in the mixture will become equal after

Options:
A 60 s
B 80 s
C 20 s
D 40 s

The correct answer is:
40 s

Solution:
Let after time t s, A1 and A2 will become equal in the mixture.
As N⁡ = N⁡ 0 1 2 n
where n is the number of half-lives
For A⁡ 1, N⁡ 1 = N⁡ 0 1 1 2 t / 2 0
For A⁡ 2, N⁡ 2 = N⁡ 0 2 1 2 t / 1 0
According to question, N1 = N2
4 0 2 t / 2 0 = 1 6 0 2 t / 1 0
2 t / 1 0 = 4 2 t / 2 0 or 2 t / 1 0 = 2 2 2 t / 2 0
2 t / 1 0 = 2 t 2 0 + 2
t 1 0 = t 2 0 + 2 or t 1 0 - t 2 0 = 2
ort20=2ort=40 s

Topic: Physics, Nuclear Physics, NEET
A mixture contains N2O4 and NO2 in 2 : 1 ratio by volume. The vapour density of the mixture is

Options:
A 45.4
B 49.8
C 32.6
D 38.3

The correct answer is:
38.3

Solution:
Vapour density of mixture =n1d1+n2d2n1+n2
Here molecular weight of NO2 = 46
Molecular weight of N2O4=92
Density =molecularweight2
=2×46+1×232+1=38.3

Topic: Chemistry, Some Basic Concepts of Chemistry, NEET
A mixture of 2 mol of carbon monoxide and 1 mol of oxygen in a closed vessel is ignited to get carbon dioxide, then

Options:
A ΔH>ΔE
B ΔH<ΔE
C ΔH=ΔE
D not definite

The correct answer is:
ΔH<ΔE

Solution:
2CO(g)+O2(g)→2CO2(g)
Δng=2-(2+1)=-1
ΔH=ΔE+ΔngRT
or ΔH=ΔE-1.RT
i.e., ΔH<ΔE

Topic: Chemistry, Thermodynamics (C), NEET
A mixture of 1.0 mole of Al and 3.0 mole of Cl 2 are alloved to react as: 2Al(s)+3 Cl 2 (g)→2 AlCl 3 (g). Then moles of excess reagent left unreacted is:

Options:
A 3.5
B 1.0
C 1.5
D 2.5

The correct answer is:
1.5

Solution:
2 Al + 3 Cl 2 â 2 AlCl 3 s Moles before reaction 1.0 3.0 0ââ Moles after reaction 0 1.5 1.0
Mole ratio for reactants and products are 2 : 3 : 2
Thus limiting reagent is Al .
Moles of AlCl3 formed = 1.0
Moles of excess reagent Cl2 left unreacted =1.5

Topic: Chemistry, Some Basic Concepts of Chemistry, NEET
A mixture of 100 mL of oxygen and 500 mL of hydrogen is reacted to form water. What is maximum theoretical decrease in volume at 25°C ?

Options:
A 30 mL
B 300 mL
C 100 mL
D 500 mL

The correct answer is:
300 mL

Solution:
At 25°C , the water so-obtained is in the liquid state, which is supposed to occupy negligible volume or almost zero volume.

Total volume of H2 and O2 before reaction
=100mL+500mL=600mL
and volume of H2 and O2 reacted = 200 mL + 100 mL = 300 mL
Volume of H2O(l) formed = 0.00 mL
So decrease in volume =(600-300+0.00)mL=300mL

Topic: Chemistry, Some Basic Concepts of Chemistry, NEET
A mixture of \(1.57 \mathrm{~mol}\) of \(\mathrm{N} 2,1.92 \mathrm{~mol}\) of \(\mathrm{H} 2\) and \(8.13 \mathrm{~mol}\) of \(\mathrm{NH} 3\) is introduced into a \(20 \mathrm{~L}\) reaction vessel at \(500 \mathrm{~K}\). At this temperature, the equilibrium constant, \(K_c\) for the reaction:
\(N 2(g)+3 H 2(g) \rightleftharpoons 2 N H 3(g)\)
is \(1.7 \times 10^2\). Is the reaction mixture at equilibrium? If not, what is the direction of the net reaction?

Options:
A The reaction mixture is at equilibrium.
B The reaction proceeds in the reverse direction.
C The reaction proceeds in the forward direction.
D It is not possible to determine without more information.

The correct answer is:
The reaction proceeds in the forward direction.

Solution:
Correct Option is : (C)
The reaction proceeds in the forward direction.

Topic: Chemistry, Ionic Equilibrium, NEET
A mixture of 250 g of water and 200 g of ice at 0Â°C is kept in a calorimeter of water equivalent 50g. If 200g of steam at 100Â°C is passed through the mixture then the final amount of water in the mixture will be (Latent Heat of ice = 80 cal g-1, Latent Heat of vaporisation of water = 540 cal g-1 and specific heat of water = 1 cal g-1/Â°C )

Options:
A 450Â g
B 622Â g
C 572 g
D 650Â g

The correct answer is:
572 g

Solution:
Heat required by ice to melt =200Ã80=16000 cal
Heat required by 250 g water
(ice + initial water + calorimeter) to raise up to 100Â°C
=500Ã1Ã100=50000 cal
â Total heat required =16000+50000=66000 cal
Let m g of steam condenses, then
66000=mÃ540
â mâ122g
So final amount of water =450+122=572 g

Topic: Physics, Thermal Properties of Matter, NEET
A mixture of cyclohexane and ethanol shows

Options:
A ideal solution behaviour
B negative deviation from Rault's law
C positive deviation from Rault's law
D cannot be predicted

The correct answer is:
positive deviation from Rault's law

Solution:
When cyclohexane and ethanol are mixed positive deviation is observed as hydrogen bonds are broken in ethanol.

Topic: Chemistry, Solutions, NEET
A mixture of dihydrogen and dioxygen at one bar pressure contains 20% by weight of dihydrogen. Calculate the partial pressure of dihydrogen.

Options:
A 1.6 bar
B 0.3 bar
C 0.8 bar
D 1.8 bar

The correct answer is:
0.8 bar

Solution:
Correct Option is : (C)
0.8 bar

Topic: Chemistry, States of Matter, NEET
A mixture of dihydrogen and dioxygen at one bar pressure contains 20% by weight of dihydrogen. Calculate the partial pressure of dihydrogen.

Options:
A 0.8 bar
B 0.4 bar
C 1.6 bar
D 3.2 bar

The correct answer is:
0.8 bar

Solution:
Let the weight of mixture = 100 g
PH2=PTotal.XH2
=PTotalÃnH2nH2+nO2
=1Ã202202+8032 bar=0.8 bar

Topic: Chemistry, States of Matter, NEET
A mixture of ethyl iodide and n-propyl iodide is treated with sodium metal in presence of ethoxyethane. The hydrocarbon which is not formed is

Options:
A butane
B propane
C pentane
D hexane

The correct answer is:
propane

Solution:
Here butane, pentane and hexane are formed but not propane.
2CH3CH2I+2Na→(C2H5)2OCH3CH2CH2CH3+2NaI
2CH3CH2CH2I+2Na→(C2H5)2OCH3CH2CH2CH2CH2CH3+2NaI
CH3CH2I+2Na+ICH2CH2CH3→CH3CH2CH2CH2CH3+2NaI

Topic: Chemistry, Hydrocarbons, NEET
A mixture of gases contains H2 and O2 gases in the ratio of 1 : 4 (w/w). What is the molar ratio of the two gases in the mixture?

Options:
A 1 : 4
B 4 : 1
C 16 : 1
D 2 : 1

The correct answer is:
4 : 1

Solution:
\(\begin{array}{|lcccc|}
\hline & & \mathrm{H}_2 & : & \mathrm{O}_2 \\
\hline \mathrm{W} / \mathrm{W} & \Rightarrow & 1 & : & 4 \\
\hline \text {Moles } & \Rightarrow & \frac{1}{2} & : & \frac{4}{32} \\
& \Rightarrow & 1 & : & \frac{1}{4} \\
\hline
\end{array}\)
i.e. 4 : 1

Topic: Chemistry, Some Basic Concepts of Chemistry, NEET, NEET 2015 (Phase 1)
A mixture of gases contains H2 and O2 gases in the ratio of 1 : 4 (w/w). What is the molar ratio of the two gases in the mixture?

Options:
A 4 : 1
B 16 : 1
C 2 : 1
D 1 : 4

The correct answer is:
4 : 1

Solution:
wH2wO2=14
nH2nO2=1/24/32=41

Topic: Chemistry, States of Matter, NEET
A mixture of methane and ethene in a molar ratio of x:y has an average molecular mass of 20 u. The mean molar mass when they are mixed in the molar ratio of y:x will be -

Options:
A 20 u
B 25 u
C 24 u
D 15 u

The correct answer is:
24 u

Solution:
Mol. wt. of CH4=16
Mol. wt. of C2H4=28
â´20=16x+28yx+y
or 16x+28 y=20 x+20 y
or 4x=8y
or x=2y
In the gaseous mixture when the mole ratio of CH4 and C2H4 is y : x
then avg. mol. wt=16y+28xx+y=16y+56y3y
=72y3y=24 u

Topic: Chemistry, Some Basic Concepts of Chemistry, NEET
A mixture of N2 and Ar gases in a cylinder contains 7 g of N2 and 8 g of Ar. If the total pressure of the mixture of the gases in the cylinder is 27 bar, the partial pressure of N2 is:
[Use atomic masses (in g mol–1): N=14,Ar=40]

Options:
A 12 bar
B 15 bar
C 18 bar
D 9 bar

The correct answer is:
15 bar

Solution:
Mass of N2 = 7 g

Moles of N2=728=14

Mass of Ar=8 g

Moles of Ar=840=15

Partial pressureN2=PT×mole fractionN2

=27×1/41/4+1/5

=27×1/49/20

=27×204×9

=3×5

=15 bar

Topic: Chemistry, States of Matter, NEET, NEET 2020 (Phase 1)
A mixture of potassium chlorate, oxalic acid and sulphuric acid is heated. During the reaction which element undergoes maximum change in the oxidation number?

Options:
A $\mathrm{S}$
B $\mathrm{H}$
C $\mathrm{Cl}$
D C

The correct answer is:
$\mathrm{Cl}$

Solution:
When a mixture of potassium chlorate, oxalic acid and sulphuric acid is heated, the following reaction occurs :
\(\stackrel{+5}{\mathrm{KClO}_3}+\mathrm{H}_2 \mathrm{C}_2 \mathrm{O}_4+\stackrel{+6}{\mathrm{H}_2 \mathrm{S} \mathrm{O}_4} \rightarrow \stackrel{+6}{\mathrm{K}_2 \mathrm{S} \mathrm{O}_4}+\stackrel{-1}{\mathrm{KCl}}+\mathrm{CO}_2+\mathrm{H}_2 \mathrm{O}\)
i.e. maximum change in oxidation number is observed in \(\mathrm{Cl}(+5\) to-1).
Thus, $\mathrm{Cl}$ is the element which undergoes maximum change in the oxidation state.

Topic: Chemistry, Redox Reactions, NEET, NEET 2012 (Screening)
A mixture of salt when heated with conc. H2SO4 and MnO2 , brown fumes are formed due to presence of which ion?

Options:
A Br-
B NO3-
C Cl-
D I-

The correct answer is:
Br-

Solution:
It is a lab method for the preparation of Br2 e.g.
2KBr+MnO2+H2SO4→ Br2Browngas+2KHSO4+MnSO4

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), NEET
A mixture of salts was treated to determine the barium content. A 0.230g sample was dissolved and treated with excess potassium chromate. The precipitate of BaCrO4 was dissolved in dil HCl to convert BaCrO4 to Cr 2 O 7 2 - anion. The solution treated with excess sodium iodide and tri Iodide produced was titrated with 21 mL of 0.095 M sodium thiosulphate. Calculate the % of BaCl 2 â2 H 2 O in the sample. [given Molar Mass of BaCl2.2H2O = 244]

Options:
A 70.5 %
B 30.25 %
C 15.12 %
D 110 %

The correct answer is:
70.5 %

Solution:
The skeletal reactions are
BaCrO 4 + HCl â¶ Cr 2 O 7 2 - + Ba 2 + Cr 2 O 7 2 - + I - â¶ Cr 3 + + I 3 - I 3 - 1 + S 2 O 3 2 - â¶ S 4 O 6 2 - + I -
Meqs of Na2S2O3 = 21 x 0.095 x 1 = 1.995 Meqs of I 3 -
≡ Meqs of Cr 2 O 7 2 -
mM of Cr 2 O 7 2 - = 1 . 9 9 5 6
mM of Cr O 4 2 - = 1 . 9 9 5 6 × 2 = 0 . 6 6 5 mM of BaCrO4
Mass % of BaCl2 . 2H2O = 0 . 6 6 5 × 1 0 - 3 × 2 4 4 0 . 2 3 0 × 1 0 0 = 7 0 . 5 %

Topic: Chemistry, Redox Reactions, NEET
A mixture of two gases is contained in a vessel. The Gas 1 is monoatomic and gas 2 is diatomic and the ratio of their molecular masses M1M2=14. The ratio of root mean square speeds of the molecules of two gases is

Options:
A 2
B 4
C 8
D 16

The correct answer is:
2

Solution:
From kinetic theory of gases
P=13MV×Vrms2
Since, P and V are constant (same)
∴ M1Vrms12=M2Vrms22
⇒Vrms12Vrms22=M2M1
⇒Vrms1Vrms2=M2M1=4/1=2 given,M1M2=14

Topic: Physics, Kinetic Theory of Gases, NEET
A modified form of adenine, a purine

Options:
A was discovered from autoclaved herring sperm DNA
B is naturally found in plants and helps in preventing apical dominance
C was isolated from corn kernels and coconut milk
D is a synthetic compound which promotes cell division in plants

The correct answer is:
was discovered from autoclaved herring sperm DNA

Solution:
N6-furfurylamino purine is a modified form of adenine called kinetin. It was discovered from autoclaved herring sperm DNA. It is not naturally found in plants. It has cytokinin activity and used in plant tissue culture along with low auxin to promote the formation of the stem in callus. Zeatin was isolated from corn kernels and coconut milk.

Topic: Biology, Plant - Growth and Development, NEET
A molecule of lactose is formed by a glycosidic bond between

Options:
A Galactose and fructose
B Glucose and galactose
C Galactose and glucose
D Fructose and galactose

The correct answer is:
Galactose and glucose

Solution:
Lactose or milk sugar is a disaccharide formed by a glycosidic bond between the first carbon of beta-D-galactopyranose and the fourth carbon of alpha-D-glucopyranose. It is the least sweet naturally occurring sugar.

Topic: Chemistry, Biomolecules, NEET
A molecule of mass m moving at a velocity v elastically impinges on the wall at an angle Î± with the wall. Then

Options:
A the impulsive reaction of the wall is 2mvcos⁡α
B the impulsive reaction of the wall is 2mvsin⁡α
C the impulsive reaction of the wall is nonzero
D given data is insufficient to calculate impulsive reaction of the wall

The correct answer is:
the impulsive reaction of the wall is 2mvsin⁡α

Solution:
Impulse, Δp→=pf→-pi→
Δp→=mv-sin⁡αi^+cos⁡αj^-mvsin⁡αi^+cos⁡αj^
Δp→=-2mvsin⁡αi^

Topic: Physics, Center of Mass Momentum and Collision, NEET
A molecule of oxygen diffuses from the alveolar air space into an erythrocyte to form oxyhaemoglobin. How many times does it need to diffuse through the cell membranes to reach the haemoglobin?

Options:
A 3
B 5
C 6
D 9

The correct answer is:
5

Solution:
For oxygen to enter the RBC, it has to pass through squamous epithelium of alveoli, squamous epithelium of capillaries and finally it will reach the RBC. It will enter the squamous epithelium of alveolus through one end and will leave it through the other. Thus, for passing through the squamous epithelium of alveolus, it has to pass through plasma lemma or cell membrane twice. Similarly, to pass through the squamous epithelium of capillary it has to pass through cell membrane twice. Then it passes through the cell membrane of RBC to reach haemoglobin. Thus, it crosses the cell membrane 5 times.

Topic: Biology, Breathing and Exchange of Gases, NEET
A molecule that acts as a genetic material must fulfill the following criteria, except

Options:
A It should be structurally and chemically unstable
B It should have the ability to generate its replica
C It should facilitate slow changes necessary for evolution.
D It should be able to express itself in the form of Mendelian characters.

The correct answer is:
It should be structurally and chemically unstable

Solution:
The substance which can function as genetic material must be structurally and chemically be stable. It should be stable enough, not to change with different stages of life cycle, age or with change in physiology of the organism.

Topic: Biology, Molecular Basis of Inheritance, NEET
A molecule that can act as a genetic material must fulfill the traits given below, except

Options:
A It should be unstable structurally and chemically
B It should provide the scope for slow changes that are required for evolution
C It should be able to express itself in the form of 'Mendelian characters'
D It should be able to generate its replica

The correct answer is:
It should be unstable structurally and chemically

Solution:
A molecule that can act as genetic material must fulfill the following criteria:
i) It should chemically and structurally be stable.
ii) It should be able to generate its replica (replication).
iii) It should provide the scope for slow mutation that are required for evolution.
iv) It should be able to express itself in the form of Mendelian characters.
The genetic material should be stable enough not to change with different stages of life cycle, ago or with change in physiology of the organism. DNA being more stable is preferred as genetic material, as
a) Free 2'OH of RNA makes it more labile and easily degradable. Therefore DNA in comparison is more stable.
b) Presence of thymine (5 - Methyl uracil) at the place of uracil also confers additional stability to DNA.
c) RNA being unstable mutates at a faster rate.

Topic: Biology, Molecular Basis of Inheritance, NEET, NEET 2016 (Phase 2)
A molecule that can act as a genetic material must fulfill the traits given below, except

Options:
A It should be able to express itself in the form of 'Mendelian characters'
B It should be able to generate its replica
C It should be stable structurally but not chemically
D It should provide the scope for slow changes that are required for evolution

The correct answer is:
It should be stable structurally but not chemically

Solution:
A molecule that can act as genetic material must fulfill the following criteria:
i) It should chemically and structurally be stable.
ii) It should be able to generate its replica (replication).
iii) It should provide the scope for slow mutation that are required for evolution.
iv) It should be able to express itself in the form of Mendelian characters.
The genetic material should be stable enough not to change with different stages of life cycle, ago or with change in physiology of the organism. DNA being more stable is preferred as genetic material, as
a) Free 2âOH of RNA makes it more labile and easily degradable. Therefore DNA in comparison is more stable.
b) Presence of thymine (5 â Methyl uracil) at the place of uracil also confers additional stability to DNA.
c) RNA being unstable mutates at a faster rate.

Topic: Biology, Molecular Basis of Inheritance, NEET
A monatomic gas initially at 17 Â°C has suddenly compressed adiabatically to one-eighth of its original volume. The temperature after compression is

Options:
A 887 K

B 36.25 K

C 2320 K

D 1160 K

The correct answer is:
1160 K

Solution:
Sudden compression is adiabatic for which
T 1 V 1 Î³ - 1 = T 2 V 2 Î³ - 1
â T 2 = T 1 V 1 V 2 Î³ - 1 = 2 9 0 Ã 8 2 / 3 = 2 9 0 Ã 4 = 1160 K

Topic: Physics, Thermodynamics, NEET
A monkey climbs up a slippery pole for 3 seconds and subsequently slips for 3 seconds. Its velocity at time (t) is given by v(t) = 2t (3-t); 0< t < 3 and v (t)=–(t–3)(6–t) for 3 < t < 6 s It repeats this cycle until it reaches the height of 20 m.At what time is its velocity maximum?

Options:
A 1.5 s
B 2.0 s
C 2.5 s
D 3.0 s

The correct answer is:
1.5 s

Solution:
Correct Option is : (A)
1.5 s

Topic: Chemistry, Motion In One Dimension, NEET
A monkey climbs up a slippery pole for 3 seconds and subsequently slips for 3 seconds. Its velocity at time (t) is given by v(t) = 2t (3-t); 0< t < 3 and v (t)=–(t–3)(6–t) for 3 < t < 6 s It repeats this cycle until it reaches the height of 20 m.At what time is its acceleration maximum in magnitude?

Options:
A 1.5 s
B 2.0 s
C 2.5 s
D 3.0 s

The correct answer is:
3.0 s

Solution:
Correct Option is : (D)
3.0 s

Topic: Chemistry, Motion In One Dimension, NEET
A monkey climbs up a slippery pole for 3 seconds and subsequently slips for 3 seconds. Its velocity at time (t) is given by v(t) = 2t (3-t); 0< t < 3 and v (t)=–(t–3)(6–t) for 3 < t < 6 s It repeats this cycle until it reaches the height of 20 m.At what time is its average velocity maximum?

Options:
A 1.5 s
B 1.750 s
C 2.25 s
D 3.25 s

The correct answer is:
2.25 s

Solution:
Correct Option is : (C)
2.25 s

Topic: Chemistry, Motion In One Dimension, NEET