datavorous/entrance-exam-dataset huggingface dataset:
The ratio of radii of gyration of a circular ring and a circular disc, of the same mass and radius about an axis passing through their centres and perpendicular to their planes are:

Options:
A $1: \sqrt{2}$
B $3: 2$
C $2: 1$
D $\sqrt{2}: 1$

The correct answer is:
$\sqrt{2}: 1$

Solution:
Let $M$ and $R$ be the mass and radius of ring and disc then
M.I. of ring about an axis passing through its centre and perpendicular to its plane is
$$
I_{\text {ring }}=M R^2
$$
And M.I. of disc about an axis passing through centre is
$\begin{aligned} & I_{\text {disc }}=\frac{M R^2}{2} \\ & \text { i.e. } \quad \begin{aligned} I & =M K^2 \\ \text { where } K=\text { radius of } & \text { gyration } \\ \therefore \quad I_{\text {ring }} & =M K_{\text {ring }}^2 \\ & =M R^2 \\ I_{\text {fring }} & =R \\ I_{\text {disc }} & =M K_{\text {disc }}^2 \\ & =\frac{M K^2}{2} \\ K_{\text {disc }} & =\frac{R}{\sqrt{2}}\end{aligned}\end{aligned}$
$\begin{aligned} \frac{\mathrm{K}_{\text {ring }}}{\mathrm{K}_{\text {desc }}} & =\frac{R}{\frac{R}{\sqrt{2}}}=\frac{\sqrt{2}}{1} \\ & =\sqrt{2}: 1\end{aligned}$

Topic: Physics, Rotational Motion, NEET, NEET 2013 (Karnataka)
The ratio of radii of nuclei Al2713 and XA52 is 3 : 5. The number of neutrons in the nuclei of X will be

Options:
A 52
B 73
C 125
D 13

The correct answer is:
73

Solution:
r∝A13
⇒35=27A13
A=125
Nn=A-Z=125-52=73

Topic: Physics, Nuclear Physics, NEET
The ratio of radius of gyration of a solid sphere of mass M and radius R about its own axis to the radius of gyration of the thin hollow sphere of same mass and radius about its axis is :

Options:
A 5:2
B 35
C 5:3
D 2:5

The correct answer is:
35

Solution:
Radius of gyration of solid sphere about its own axis is given by,

ksolid=IM=2MR25M=25R

Similarly,

khollow=IM=2MR23M=23R

Therefore, required ratio would be

ksolidkhollow=35.

Note: This option was not present in the original paper.

Topic: Physics, Rotational Motion, NEET, NEET 2023 (All India)
The ratio of resolving powers of an optical microscope for two wavelengths λ1=4000 Å and λ2=6000 Å is

Options:
A 8:27
B 9:4
C 3:2
D 16:81

The correct answer is:
3:2

Solution:
Resolving power â1Î»
R1R2=Î»2Î»1
=6000 â«4000 â«
=32

Topic: Physics, Ray Optics, NEET, NEET 2017
The ratio of solubility of AgCl in 0.1 M KCl solution to the solubility of AgCl in water is:
(Given : Solubility product of $\mathrm{AgCl}=10^{-10}$ )

Options:
A $10^{-4}$
B $10^{-6}$
C $\quad 10^{-9}$
D $10^{-5}$

The correct answer is:
$10^{-4}$

Solution:

Topic: Chemistry, Ionic Equilibrium, NEET, NEET 2024 (Re-NEET)
The ratio of spin only magnetic moments of Fe3+ and Co2+ is

Options:
A 24:15
B 7:3
C 35:15
D 5:7

The correct answer is:
35:15

Solution:
Fe3+=(Ar)3d5
Co2+=(Ar)3d7
Hence, Fe3+ has 5 unpaired electrons and Co2+ has 3 unpaired electrons
μFe3+=n(n+2)=5×7=35
μCo3+=n(n+2)=3×5=15

Topic: Chemistry, Coordination Compounds, NEET
The ratio of temperatures of sun and moon, if the wavelengths of their maximum emission radiations rates are 140 Å and 4200Å, will be

Options:
A 1:30
B 30:1
C 42:14
D 14:42

The correct answer is:
30:1

Solution:
From Wien's law
λmT=constant
Where λm is maximum wavelength and T is the absolute temperature.
Given, λ1=140 Å, λ2=4200 Å
∴ λ1λ2=T2T1=1404200
⇒ T2T1=130
⇒ T1T2=301

Topic: Physics, Thermal Properties of Matter, NEET
The ratio of the acceleration due to gravity on two planets P1 and P2 is K1. The ratio of their respective radii is K2. The ratio of their respective escape velocities is

Options:
A K1K2
B 2K1K2
C K1K2
D K2K1

The correct answer is:
K1K2

Solution:
Since escape velocity from the surface of a planet can be written as v e = 2gR
ratio v e p 1 v e p 2 = 2 g p 1 R p 1 2 g p 2 R p 2 = K 1 K 2

Topic: Physics, Gravitation, NEET
The ratio of the acceleration for a solid sphere (mass ‘m' and radius R) rolling down an incline of angle ‘θ' without slipping and slipping down the incline without rolling is:

Options:
A 5:7
B 2:3
C 2:5
D 7:5

The correct answer is:
5:7

Solution:
a1=gsin⁡θ1+IMR2
a2=gsin⁡θ1+25MR2MR2=57gsin⁡θ
a1a2=57

Topic: Physics, Rotational Motion, NEET, NEET 2014
The ratio of the binding energy of a satellite at rest on earth's surface to the binding energy of a satellite of same mass revolving around the earth at a height h above the earth's surface is (R= radius of the earth).

Options:
A 2(R+h)R
B R+h2R
C R+hR
D RR+h

The correct answer is:
R+hR

Solution:
Binding energy on the surface of the earth
E1=GMm2R
Binding energy of revolving satellite
E2=GMm2(R+h)
â´ E1E2=(R+h)R

Topic: Physics, Gravitation, NEET
The ratio of the concentration of electrons to that of holes in a semiconductor is 75 and the ratio of currents is 74. Then, the ratio of their drift velocities is

Options:
A 47
B 45
C 58
D 54

The correct answer is:
54

Solution:
As
I=neAvd
â IeIh=eneAveenhAvh=nevenhvh
â vevh=IeIhÃnhne=74Ã57=54

Topic: Physics, Current Electricity, NEET
The ratio of the dimension Planck's constant and that of moment of inertia is the dimension of:

Options:
A time
B frequency
C angular momentum
D velocity

The correct answer is:
frequency

Solution:
$\frac{h}{I}=\frac{\mathrm{E} \lambda}{\mathrm{C} \times \mathrm{I}}=\frac{\left[\mathrm{ML}^2 \mathrm{~T}^{-2}\right][\mathrm{L}]}{\left[\mathrm{LT}^{-1}\right]\left[\mathrm{ML}^2\right]}$
$\frac{h}{I}=\left[\mathrm{T}^{-1}\right]=\text { Frequency }$

Topic: Physics, Units and Dimensions, NEET, NEET 2005
The ratio of the distances travelled by a freely falling body in the 1st ,2nd ,3rd and 4th second

Options:
A 1:4:9:16
B 1:3:5:7
C 1:1:1:1
D 1:2:3:4

The correct answer is:
1:3:5:7

Solution:
Galileo's law of odd numbers states that the distance covered by a falling object in successive equal time intervals is linearly proportional to the odd numbers. That is, if a body falling from rest covers one unit of distance in the first arbitrary time interval, it covers 3, 5, 7, etc. units of distance in subsequent time intervals of the same length.

Topic: Physics, Motion In One Dimension, NEET, NEET 2022 (Phase 1)
The ratio of the intensities two waves is 1 : 9. The ratio of their amplitudes is

Options:
A 3 : 1
B 1 : 3
C 1 : 9
D 9 : 1

The correct answer is:
1 : 3

Solution:
Intensity ∝ (amplitude)2
∴ I1I2=a12a22
19=a12a22
a1a2=13

Topic: Physics, Waves and Sound, NEET
The ratio of the magnetic field at the centre of a current carrying circular coil to its magnetic moment is x. If the current and radius both are doubled the new ratio will become

Options:
A 2x
B 4x
C x4
D x8

The correct answer is:
x8

Solution:
x = B M = Î¼ 0 i 2 r 1 i Ï r 2 or x â 1 r 3
i.e., x will become x 8 when radius and current both are doubled.

Topic: Physics, Magnetic Effects of Current, NEET
The ratio of the magnetic field at the centre of a current-carrying circular coil to its magnetic moment is x. If the current and radius each of them are made three times, the new ratio will become

Options:
A 3x
B 9x
C x9
D x27

The correct answer is:
x27

Solution:
The magnetic field, B=μ0I2R
∴ Magnetic moment, μ=IA
Bμ=μ0I2RIπR2=μ0 2πR3 ∝1R3
if R and I are made three times, new
B'μ=127Bμ=x27

Topic: Physics, Magnetic Effects of Current, NEET
The ratio of the magnitude of the magnetic field and electric field intensity of a plane electromagnetic wave in free space of permeability $\mu_0$ and permittivity $\varepsilon_0$ is (Given that $c$ - velocity of light in free space):

Options:
A $c$
B $\frac{1}{c}$
C $\frac{c}{\sqrt{\mu_0 \varepsilon_0}}$
D $\frac{\sqrt{\mu_0 \varepsilon_0}}{c}$

The correct answer is:
$\frac{1}{c}$

Solution:
As per question,
$\frac{\mathrm{B}_0}{\mathrm{E}_0}=\frac{1}{c}=\sqrt{\mu_0 \varepsilon_0}$
(where, the symbols have their usual meanings.)

Topic: Physics, Electromagnetic Waves, NEET, NEET 2022 (Phase 2)
The ratio of the maximum wavelength of the Lyman series in hydrogen spectrum to the maximum wavelength in the Paschen series is

Options:
A 3105
B 615
C 527
D 7108

The correct answer is:
7108

Solution:
λ1λ2=19-11611-14=7108

Topic: Physics, Atomic Physics, NEET
The ratio of the radii of gyration of a circular disc about a tangential axis in the plane of the disc and of a circular ring of the same radius about a tangential axis in the plane of the ring is:

Options:
A $2: 3$
B $2: 1$
C $\sqrt{5}: \sqrt{6}$
D $1: \sqrt{2}$

The correct answer is:
$\sqrt{5}: \sqrt{6}$

Solution:
The radius of gyration of disc about a tangential axis in the plane of disc is $k_1$
$$
\therefore \quad k_1=\frac{\sqrt{5}}{2} R
$$
And radius of gyration of circular ring of same radius about tangential axis is given by:
$$
\begin{aligned}
k_2 & =\frac{\sqrt{3}}{2} \mathrm{R} \\
\therefore \quad \frac{k_1}{k_2} & =\frac{\sqrt{5}}{2} R \times \frac{\sqrt{2}}{\sqrt{3} R} \\
& =\frac{\sqrt{5}}{\sqrt{6}}
\end{aligned}
$$

Topic: Physics, Rotational Motion, NEET, NEET 2004
The ratio of the radii of gyration of a circular disc to that of a circular ring, each of same mass and radius, around their respective axes is

Options:
A $\sqrt{3}: \sqrt{2}$
B $1: \sqrt{2}$
C $\sqrt{2}: 1$
D $\sqrt{2}: \sqrt{3}$

The correct answer is:
$1: \sqrt{2}$

Solution:
Key Idea : The square root of the ratio of the moment of inertia of a rigid body and its mass is called radius of gyration.
As in key idea, radius of gyration is given by
$K=\sqrt{\frac{I}{M}}$
For given problem
$\frac{K_{\text {disc }}}{K_{\text {ring }}}=\sqrt{\frac{I_{\text {disc }}}{I_{\text {ring }}}}$
But $I_{\text {disc }}$ (about its axis) $=\frac{1}{2} M R^2$ and $I_{\text {ring }}$ (about its axis) $=M R^2$ where $R$ is the radius of both bodies. Therefore, Eq. (i) becomes
$\frac{K_{\mathrm{disc}}}{K_{\text {ring }}}=\sqrt{\frac{\frac{1}{2} M R^2}{M R^2}}=1: \sqrt{2}$

Topic: Physics, Rotational Motion, NEET, NEET 2008 (Screening)
The ratio of the radii of the planets P1 and P2 is a. The ratio of their accelerations due to gravity is b. The ratio of the escape velocities from them will be

Options:
A ab
B ab
C ab2
D a2b

The correct answer is:
ab

Solution:
vep1vep2=2g1R12g1R2=g1g2×R1R2=ab

Topic: Physics, Gravitation, NEET
The ratio of the radius of gyration of a thin uniform disc about an axis passing through its centre and normal to its plane to the radius of gyration of the disc about its diameter is

Options:
A 2:1
B 4:1
C 1:2
D 2:1

The correct answer is:
2:1

Solution:
For a thin uniform disc.

Radius of gyration

Case 1: K1=R2

Case 2: K2=R2

Q⇒K1K2=?

∴K1K2=R2R2 =2

Topic: Physics, Rotational Motion, NEET, NEET 2022 (Phase 1)
The ratio of the resistance of a conductor at a temperature of 15 Â°C to its resistance at a temperature of 37.5 Â°C is 4:5. The temperature coefficient of resistance of the conductor is

Options:
A 125 °C-1
B 150 °C-1
C 180 °C-1
D 175 °C-1

The correct answer is:
175 °C-1

Solution:
RT=R01+αT
R15R37.5=R01+α×15R01+α×37.5
∴45=1+α×151+α×37.5
41+α×37.5=51+α×15
4+α×150=5+α×75
By solving this we get, α=175 °C-1

Topic: Physics, Current Electricity, NEET
The ratio of the resistance of conductor at temperature 15°C to its resistance at temperature 37.5°C is 4:5 . The temperature coefficient of resistance of the conductor is -

Options:
A l25°C–1
B l50°C–1
C l80°C–1
D l75°C–1

The correct answer is:
l75°C–1

Solution:
RT=R0 1 +αT
R15R37.5=R01+α×15R01+α×37.5 ∴45=1+α×151+α×37.5

Topic: Physics, Current Electricity, NEET
The ratio of the resistance of conductor at temperature 15 oC to its resistance at temperature 37.5 oC is 4:5 . The temperature coefficient of resistance of the conductor is

Options:
A 125Â oC-1
B 150Â oC-1
C 180Â oC-1
D 175 oC-1

The correct answer is:
175 oC-1

Solution:
The resistance at temperature t is
Rt=R01+Î±t
â´ 45=1+15Î±1+37.5Î±
â 41+37.5Î±=51+15Î±
â 75Î±=1âÎ±=175 o C-1

Topic: Physics, Current Electricity, NEET
The ratio of the specific heats CPCv= γ in terms of degrees of freedom (n) is given by:

Options:
A 1+1n
B 1+n3
C 1+2n
D 1+n2

The correct answer is:
1+2n

Solution:
Mayer's formula is derived by using the difference between the specific heat of a gas at the constant pressure (Cp) and its specific heat at constant volume (Cv) which is equal to the universal gas constant (R) divided with the molecular weight (M) of the gas expressed in “J”

CV=n2R
CP=CV+R=n2R+R=n2+1R
γ=CPCV=n2+1Rn2R
=n2+12n
γ=1+2n

Topic: Physics, Kinetic Theory of Gases, NEET, NEET 2015 (Phase 1)
The ratio of the speed of electron in first Bohr orbit of H-atom to speed of light in vacuum is

Options:
A 137
B 7.30×10-3
C 100
D 10-2

The correct answer is:
7.30×10-3

Solution:
Velocity in first orbit for hydrogen atom = ue=2.188×108 cm/sec
ul=3.0×1010cm/sec
So ueul=2.188×1083.0×1010
=7.29×10-3

Topic: Chemistry, Structure of Atom, NEET
The ratio of the time taken by a solid sphere and that taken by a disc of the same mass and radius to roll down a smooth inclined plane from rest from the same height is

Options:
A 15 : 14
B 15 : 14
C 14 : 15
D 14: 15

The correct answer is:
14: 15

Solution:
t=2sgsin⁡θ 1+K2R2
t1t2=1+251+12=1415

Topic: Physics, Rotational Motion, NEET
The ratio of the value of any colligative property for K4[Fe(CN)6] to that of Fe4[Fe(CN)6]3 solution is nearly

Options:
A 0.62
B 0.71
C 1.4
D 1.2

The correct answer is:
0.71

Solution:
van't Hoff factor of K4[Fe(CN)6]=5
K4[Fe(CN)6]=4K++[Fe(CN)6]4-
van't Hoff factor of Fe4[Fe(CN)6]3=7
Fe4[Fe(CN)6]3=4Fe3++3[Fe(CN)6]4-
So ratio of colligative properties =57=0.71 .

Topic: Chemistry, Solutions, NEET
The ratio of the velocity of sound in hydrogen ( γ= 7 5 ) to that helium γ=53 at the same temperature is

Options:
A 542
B 521
C 425
D 215

The correct answer is:
425

Solution:
Velocity of sound in a gas
v=Î³pd
∴ υ H 2 υ H e = γ H 2 × d H e d H 2 × γ H e
vH2vHe=7Ã3Ã25Ã5 AsdHedH2=2
â´vH2vHe=425

Topic: Physics, Waves and Sound, NEET
The ratio of the volume occupied by an atom to the volume of the nucleus is

Options:
A 105:1
B 1020:1
C 1015:1
D 1:1015

The correct answer is:
1015:1

Solution:
The radius of an atom =IA≈10-10 m
Radius of the nucleus =IN≈10-15 m
So, the ratio of their volumes is
VAVN=43πrA343πrN3
=IAIN3=10-1010-153
⇒ VA :VN=1015 :1

Topic: Physics, Nuclear Physics, NEET
The ratio of the wavelengths for 2 â 1 transition in Li2+, He + and H is

Options:
A 1 : 2 : 3
B 19 :14 :11
C 1 : 4 : 1
D 3 : 2 : 1

The correct answer is:
19 :14 :11

Solution:
From Bohrâs formula , the wave number 1Î» is given by
1 Î» = Z2R 1n12-1n2 2
where Z is atomic number, R the Rydberg's constant and n is the quantum number.
â Î» â 1 Z 2
Atomic number of lithium is 3, of helium is 2 and of hydrogen is 1.
â´ Î» Li 2 + : Î» He + : Î» H = 1 3 2 : 1 2 2 : 1
= 1 9 : 1 4 : 1

Topic: Physics, Atomic Physics, NEET
The ratio of thermal conductivity of two rods of different material is 5:4. The two rods of same area of cross-section and same thermal resistance will have the lengths in the ratio

Options:
A 4:5
B 9:1
C 1:9
D 5:4

The correct answer is:
5:4

Solution:
Given A1=A2 and K1K2=54
R1=R2
⇒l1K1A=l2K2A
⇒l1l2=K1K2
⇒l1l2=54

Topic: Physics, Thermal Properties of Matter, NEET
The ratio of velocity of sound in hydrogen and oxygen at STP is :

Options:
A 16 : 1

B 8 : 1

C 4 : 1

D 2 : 1

The correct answer is:
4 : 1

Solution:
The velocity of sound v=γRTM, v∝1M
vHvo=MoMH
= 1 6 1
=4:1

Topic: Physics, Thermodynamics, NEET
The ratio of voltage sensitivity (VS) and current sensitivity (Is) of a moving coil galvanometer is

Options:
A 1G
B 1G2
C G
D G2

The correct answer is:
1G

Solution:
Voltage sensitivity =QV
Current sensitivity =QI
Also, potential difference
V=IG
Hence,
∴VsIs=1G

Topic: Physics, Current Electricity, NEET
The ratio of volume of CO2 evolved to the volume of oxygen consumed in respiration is called ___

Options:
A Respiration
B Respiratory quotient
C Respiratory substrates
D None of the above

The correct answer is:
Respiratory quotient

Solution:
The ratio of volume of CO2 evolved to the volume of oxygen consumed in respiration is called Respiratory quotient

Topic: Biology, Respiration in Plants, NEET
The ratio of wavelengths of the last line of the Balmer series and the last line of the Lyman series is_____.

Options:
A 2
B 1
C 4
D 0.5

The correct answer is:
4

Solution:
For last Balmer series,
1λb=R 122-1∞2
λb=4R
For last Lyman series,
1λl=R 112-1∞2
λl=1R
λbλl=4R1R
λbλl=4

Hence this is the correct answer.

Topic: Physics, Atomic Physics, NEET, NEET 2017
The ratio of work done by an ideal diatomic gas to the heat supplied by the gas in an isobaric process is

Options:
A 57
B 35
C 27
D 53

The correct answer is:
27

Solution:
ΔW(ΔQ)P=(ΔQ)P-(ΔU)P(ΔQ)P
ΔW(ΔQ)P=1-(ΔU)P(ΔQ)P
ΔW(ΔQ)P=1-CVCP
For diatomic gas
ΔW(ΔQ)P=1-52R72R
ΔW(ΔQ)P=1-57=27

Topic: Physics, Thermodynamics, NEET
The ray PQ shown in the figure, suffers minimum deviation in an equilateral prism A. Two more identical prism B and C and of the same material as A are now placed in contact as shown in the figure. If prism A produces a minimum deviation Î´m, the deviation produced by the combination of prisms A, B and C will be

Options:
A 3δm
B 2δm
C δm
D zero

The correct answer is:
δm

Solution:
The ray PQ will undergo minimum deviation in prism A if the angle of the incident on A is such that the refracted ray in A is parallel to its base. Since prisms B and C are identical to A and are made of the same materials as A, the refracted ray in A suffers no further deviation by prisms B and C. Hence the emergent ray from prism C will suffer the same deviation as that produced by prism A. Hence the correct choice is 3.

Topic: Physics, Ray Optics, NEET
The rays of the sun are focused on a piece of ice through a lens of diameter 5 cm, as a result of which 10 g ice melts in 10 minutes. The amount of heat received from the sun per unit area per minute is

Options:
A 4 cal cm-2 min-1
B 40Â calÂ cm-2Â min-1Â
C 4 J cm-2 min-1
D 400Â calÂ cm-2Â min-1

The correct answer is:
4 cal cm-2 min-1

Solution:
Mass of ice melted/ min =1010=1 g
Quantity of heat used = 1Ã80 cal
Area of lens = Ïr2=3.142.52=19.625 cm2
â´ Amount of heat received per minute per cm2 from sun
= 8019.625=4 cal cm-2 min-1

Topic: Physics, Thermal Properties of Matter, NEET
The RBC deficiency is deficiency disease of:

Options:
A Vitamin B12.
B Vitamin B6
C Vitamin B1
D Vitamin B2

The correct answer is:
Vitamin B12.

Solution:
RBC deficiency is because of deficiency of vitamin B12.

Topic: Chemistry, Biomolecules, NEET, NEET 2021
The reactant 'P' in the following reaction is

Options:
A CH3CHOHCH3
B CH3COCH3
C CH3CH2OH
D CH3COOH

The correct answer is:
CH3CHOHCH3

Solution:

Topic: Chemistry, Alcohols Phenols and Ethers, NEET
The reactant X in the reaction,

X â CH3COONa CH3CO2O Cinnamic acid is

Options:
A
B
C
D

The correct answer is:

Solution:
Perkin reaction is the condensation reaction in which aromatic aldehyde is heated with an anhydride of an aliphatic acid in the presence of sodium salt of the same acid to form α,β-unsaturated acid.

Topic: Chemistry, Aldehydes and Ketones, NEET
The reaction, 2RCHO→Al-ethoxideRCOOCH2R is called-

Options:
A Tishchenko reaction
B Knoevangel reaction
C Cannizzaro reaction
D HVZ reaction

The correct answer is:
Tishchenko reaction

Solution:
It is Tishchenko reaction, any aldehyde with or without alpha hydrogen undergoes disproportionation in the presence of aluminium ethoxide to give ester.

Topic: Chemistry, Aldehydes and Ketones, NEET
The reaction 2K(s) + F₂(g) → 2K⁺F⁻(s) involves a redox reaction because:

Options:
A Potassium gains electrons, and Fluorine loses electrons.
B Potassium loses electrons, and Fluorine gains electrons.
C Potassium gains electrons, and Fluorine gains electrons.
D Potassium loses electrons, and Fluorine loses electrons.

The correct answer is:
Potassium loses electrons, and Fluorine gains electrons.

Solution:
Correct Option is : (B)
Potassium loses electrons, and Fluorine gains electrons.

Topic: Chemistry, Redox Reactions, NEET
The reaction 2SO 2 g +O 2 g â 2SO 3 g is carried out in a 1 dm3 vessel and 2 dm3 vessel separately. The ratio of the reaction velocities will be

Options:
A 1:8
B 1:4
C 4:1
D 8:1

The correct answer is:
8:1

Solution:
2SO2g+O2(g)⇌2SO3(g)
For this reaction, rate
r 1 =k [S O 2 ] 2 [ O 2 ]
On doubling the volume of vessel, concentration would be half. Hence,
Rater2=kSO222O22=r18
r1r2=8:1

Topic: Chemistry, Chemical Kinetics, NEET
The reaction 3ClO-(aq)→ClO3-(aq)+2Cl-(aq) is an example of

Options:
A oxidation reaction
B reduction reaction
C disproportionation reaction
D decomposition reaction

The correct answer is:
disproportionation reaction

Solution:
As in a disproportionation reaction both oxidation & reduction takes place simultaneously .
Here ClO- is reduced into Cl- and simultaneously oxidised into ClO3- .
3ClO-(aq)→ClO3-(aq)+2Cl-(aq)

Topic: Chemistry, Redox Reactions, NEET
The reaction 4BCl₃(g) + 3LiAlH₄(s) → 2B₂H₆(g) + 3LiCl(s) + 3 AlCl₃(s) involves a redox reaction because:

Options:
A Boron gains electrons, and Lithium loses electrons.
B Boron loses electrons, and Aluminum gains electrons.
C Boron loses electrons, and Hydrogen gains electrons.
D Boron gains electrons, and Chlorine loses electrons.

The correct answer is:
Boron loses electrons, and Aluminum gains electrons.

Solution:
Correct Option is : (B)
Boron loses electrons, and Aluminum gains electrons.

Topic: Chemistry, Redox Reactions, NEET
The reaction 4NH₃(g) + 5O₂(g) → 4NO(g) + 6H₂O(g) involves a redox reaction because:

Options:
A Nitrogen gains electrons, and Oxygen loses electrons.
B Nitrogen loses electrons, and Oxygen gains electrons.
C Nitrogen gains electrons, and Hydrogen loses electrons.
D Nitrogen loses electrons, and Hydrogen gains electrons.

The correct answer is:
Nitrogen gains electrons, and Oxygen loses electrons.

Solution:
Correct Option is : (A)
Nitrogen gains electrons, and Oxygen loses electrons.

Topic: Chemistry, Redox Reactions, NEET
The reaction A g â B g + 2 C g is a first-order reaction with a rate constant of 2.303 x 10-3 s-1. Starting with 0.1 moles of 'A' in a 2 litre vessel, find the concentration of A after 301 sec when the reaction is allowed to take place at constant pressure at 300 K.

Options:
A 0.0125 M
B 0.025 M
C 0.05 M
D None of these

The correct answer is:
0.025 M

Solution:
t 1 / 2 = 0 . 6 9 3 2 . 3 0 3 Ã 1 0 - 3 = 6 9 3 2 . 3 0 3 = 3 0 1 sec
initial concentration = moles of A/volume = 0.1/2 = 0.05 mole/L
i.e., after t1/2, no. of moles of 'A' reacted is half the initial moles.
Final conc. of [A] = 0.05/2 = 0.025 M

Topic: Chemistry, Chemical Kinetics, NEET
The reaction between A and B is first order with respect to A and zero order with respect to B. Fill in the blanks in the following table:

Options:
A (i) 0.1 molL−1, (ii) 0.2 mol L−1and (iii) 8.0×10−2mol L−1min−1
B (i) 0.2 molL−1, (ii) 0.1 mol L−1and (iii) 8.0×10−2mol L−1min−1
C (i) 0.2 molL−1, (ii) 0.1 mol L−1and (iii) 4.6×10−2mol L−1min−1
D (i) 0.1 molL−1, (ii) 0.2 mol L−1and (iii) 4.6×10−2mol L−1min−1

The correct answer is:
(i) 0.2 molL−1, (ii) 0.1 mol L−1and (iii) 8.0×10−2mol L−1min−1

Solution:
Correct Option is : (B)
(i) 0.2 molL−1, (ii) 0.1 mol L−1and (iii) 8.0×10−2mol L−1min−1

Topic: Chemistry, Chemical Kinetics, NEET
The reaction between an alcohol and an acid with the elimination of water molecule is called

Options:
A Esterification
B Saponification
C Etherification
D Elimination

The correct answer is:
Esterification

Solution:
CH 3 COOH+CH 3 OH⇌ CH 3 COOCH 3 +H 2 O                                                                          Esterification
When a carboxylic acid is treated with an alcohol and an acid catalyst, an ester is formed (along with water). This reaction is called the Fischer esterification.

Topic: Chemistry, Carboxylic Acid Derivatives, NEET
The reaction between H2(g) and O2(g) is highly feasible yet allowing the gases to stand at room temperature in the same vessel does not lead to the formation of water. Explain.

Options:
A This is because activation energy for the reaction is very high at room temperature.
B This is because activation energy for the reaction is very low at room temperature.
C This is because activation energy for the reaction is zero at room temperature.
D This is because activation energy for the reaction is infinite at room temperature.

The correct answer is:
This is because activation energy for the reaction is very high at room temperature.

Solution:
Correct Option is : (A)
This is because activation energy for the reaction is very high at room temperature.

Topic: Chemistry, Chemical Kinetics, NEET