datavorous/entrance-exam-dataset huggingface dataset:
In the primary structure of a protein, amino acids are linked due to the presence of

Options:
A Hydrogen bonds
B Peptide bonds
C –S–S– linkages
D Ionic bonds

The correct answer is:
Peptide bonds

Solution:
Primary structure of protein is a linear chain of amino acid in which the amino acids are joined by peptide bonds which are formed between carboxylic group of first amino acid and amino group of second amino acid.

Topic: Chemistry, Biomolecules, NEET
In the primary structure of protein

Options:
A Left end represents → 1st amino acid (C-terminal amino acid)
B Right end represents → Last amino acid (N terminal amino acid)
C Left end represents → 1st amino acid (N-terminal amino acid)
D Right end represents → 1st amino acid (C-terminal amino acid)

The correct answer is:
Left end represents → 1st amino acid (N-terminal amino acid)

Solution:
The sequence of amino acid, the positional information in protein, which is first amino acid and which is second and so on is called the primary structure. Amino acids are joined by peptide bond formed between COOH group of first amino acid and NH2 group of second amino acid. Thus the first amino acid is left end, has free NH2 group known as N Terminal amino acid and last amino acid is right end has free COOH group thus known as C Terminal amino acid.

Topic: Chemistry, Biomolecules, NEET
In the process electroplating, m g of silver is deposited when 4 ampere of current flows for 2 minutes. The amount (in g) of silver deposited by 6 ampere of current flowing for 40 sec will be

Options:
A 4 m
B m2
C 4m3
D 3 m

The correct answer is:
m2

Solution:
W1W2=Q1Q2=I1×t1I2×t2
mW2=4×2×606×40=2
W2=m2g

Topic: Chemistry, Electrochemistry, NEET
In the process of hemodialysis, when anti-heparin is being added?

Options:
A After the blood is taken out from an artery
B Before the clear blood is pumped back to the body through a vein
C Into the body before the blood is taken out for the process
D Into the body after the cleared blood in injected into the veins.

The correct answer is:
Before the clear blood is pumped back to the body through a vein

Solution:
During hemodialysis, the movement of nitrogenous wastes from the blood into the dialyzing fluid will be seen. Anti-heparin is being added to the cleared blood and the blood is then pumped back to the body through a vein.

Topic: Biology, Excretory Products and their Elimination, NEET
In the process of meiosis, there are two sequential cycles of nuclear and cell division. How many cycles of DNA replication are required in meiosis?

Options:
A One
B Four
C Two
D No replication process

The correct answer is:
One

Solution:
Meiosis is a type of cell division in which the number of chromosomes in the daughter cell is reduced by half. DNA replication occurs during S phase. This is followed by meiosis I (reduction division) and meiosis II (equational division). There is no DNA replication between the two meiotic divisions. Hence, DNA replication occurs only once.

Topic: Biology, Cell Cycle and Cell Division, NEET
In the process of producing electricity from garbage in India, what is the primary gas generated by bacterial action?

Options:
A Oxygen
B Hydrogen
C Methane
D Carbon dioxide

The correct answer is:
Methane

Solution:
The garbage that is cultured with bacterial species to produce methane, commonly known as biogas, which is used to generate electricity.

Topic: Chemistry, Environmental Chemistry, NEET
In the process of rDNA technology, the isolated foreign DNA is inserted into another DNA molecule which is known as

Options:
A Coding vector
B Lipo vector
C Protein vector
D Cloning vector

The correct answer is:
Cloning vector

Solution:
Vectors in biotechnology are the carriers of the genetic material and transfer the desired genome into the host organism. Vectors are used for making copies or clones with the recombinant DNA.
The vectors should have the following features to facilitate the cloning and transfer process.

Origin of replication to enable replication of the vector and vector supporting higher copy number is preferred.

Selectable marker to help in identifying the transformant from non-transformants.

Restriction enzyme sites for insertion of foreign DNA.

Plasmids and bacteriophages are preferred as cloning vectors from transferring genes. Even retroviruses that have been disarmed and are also preferred as vector due to their enzyme reverse transcriptase.

Topic: Biology, Biotechnology - Principles and Processes, NEET
In the process of transcription in eukaryotes, the RNA polymerase I transcribes

Options:
A mRNA with additional processing, capping and tailing
B $t \mathrm{RNA}, 5 s$ srRNA and snRNAs
C rRNAs-28 S, $18 \mathrm{~S}$ and $5.8 \mathrm{~S}$
D precursor of $m \mathrm{RNA}, h n \mathrm{RNA}$

The correct answer is:
rRNAs-28 S, $18 \mathrm{~S}$ and $5.8 \mathrm{~S}$

Solution:
In the process of transcription (i.e. copying of genetic information from one strand of the DNA into RNA) in eukaryotes, the RNA polymerase I transcribes rRNA - 28S, 18S and 5.8S. On the other hand, tRNA, 5srRNA and snRNAs are transcribed by RNA polymerase III. RNA polymerase II transcribes precursor of mRNA, hnRNA.

Topic: Biology, Molecular Basis of Inheritance, NEET, NEET 2019 (Odisha)
In the process of transformation, divalent ions are used to make the host competent. The function of such ions is to

Options:
A increase the efficiency of DNA entering the bacterium
B make the DNA hydrophobic so that it enters the bacterium
C force the DNA inside the bacterium by applying heat
D break the DNA into smaller fragments for better uptake into the bacterium

The correct answer is:
increase the efficiency of DNA entering the bacterium

Solution:
In order to force bacteria to take up the plasmid, the bacterial cells must first be made âcompetentâ to take up DNA. This is done by treating them with a specific concentration of a divalent cation, such as calcium, which increases the efficiency with which DNA enters the bacterium through pores in its cell wall. Recombinant DNA can then be forced into such cells by incubating the cells with recombinant DNA on ice, followed by placing them briefly at 42Â°C (heat shock), and then putting them back on ice. This enables the bacteria to take up the recombinant DNA.

Topic: Biology, Biotechnology - Principles and Processes, NEET
In the process of treating sewage and industrial wastewaters using air and a biological floc, the sediment obtained is called:

Options:
A Activated sludge
B Biogas
C Bear
D Wine

The correct answer is:
Activated sludge

Solution:
Sewage mixed with bacteria and fungi that thrive and multiply in it and lead to its oxidation. Activation reduces the organic pollution that raw sewage otherwise will impose on the body of water to which it is discharged.
Once the BOD of sewage or waste water is reduced significantly, the effluent is passed into a setting tank where the bacterial flocs undergo sedimentation and the sediment is thus called activated sludge.

Topic: Biology, Microbes in Human Welfare, NEET
In the product >C=N-Z, what does Z represent?

Options:
A Hydrogen
B Carbon
C Nitrogen
D Oxygen

The correct answer is:
Hydrogen

Solution:
The letter Z represents a variable substituent that can vary depending on the specific derivative of ammonia used in the reaction.

Topic: Chemistry, Aldehydes, Ketones and Carboxylic Acids, NEET
In the product

F→=q(v→×B→)

=qv→×Bi^+Bj^+B0k^

For q=1 and v→=2i^+4j^+6k^ and F→=4i^-20j^+12k^

What will be the complete expression for B→?

Options:
A -8ı^-8j^-6k^
B -6ı^-6j^-8k^
C 8i^+8j^-6k^
D 6i^+6j^-8k^

The correct answer is:
-6ı^-6j^-8k^

Solution:
4ı^-20ȷ^+12k=(2ı^+4ȷ^+6k^)×Bı^+Bȷ^+Bok^

4ı^-20ȷ^+12k^=+ı^-ȷ^+k^246BBB0

=4B0-6Bı^-2B0-6Bȷ^+(2B-4B)k^

4B0-6B=4

2B0-6B=20

2B-4B=12⇒B=6

So, 2B0-6(-6)=20

2B0=20-36⇒B0=-8

∴B→=-6ı^-6ȷ^-8k^

Topic: Physics, Magnetic Effects of Current, NEET, NEET 2021
In the production of calcium carbide, what type of reaction is observed when quick lime is heated with coke?

Options:
A Combustion
B Oxidation
C Reduction
D Polymerization

The correct answer is:
Reduction

Solution:
When quick lime is heated with coke, it undergoes a reduction reaction. The carbon in coke reduces the calcium oxide in quick lime to produce calcium carbide.

Topic: Chemistry, Hydrocarbons, NEET
In the production of the test-tube baby,

Options:
A fertilization is internal and development is external.
B fertilization is external and development is internal.
C fertilization and development are external.
D fertilization and development are internal.

The correct answer is:
fertilization is external and development is internal.

Solution:
Test tube babies are conceived outside a woman's body in a laboratory through the process called IVF. Test tube baby is a simplified terminology for baby through IVF. In this process, the woman has prescribed fertility drugs which stimulate the development of eggs, which are then removed from the ovaries once matured. These eggs are then combined with the sperm and transferred to a petri dish for fertilization into an embryo. The healthiest of the produced embryos are injected to the intended mother's uterus.

Topic: Biology, Reproductive Health, NEET
In the prothallus of a vascular cryptogam, the antherozoids and eggs mature at different times. As a result:

Options:
A there is high degree of sterility
B one can conclude that the plant is apomictic
C self fertilization is prevented
D there is no change in success rate of fertilization.

The correct answer is:
self fertilization is prevented

Solution:
In the prothallus of a vascular cryptogam, the antherozoids and eggs mature atdifferent times which result in failurity of self-fertilization.

Topic: Biology, Plant Kingdom, NEET, NEET 2007
In the ratio of diameters, lengths and Young's modulus of steel and copper wires shown in the figure are $p, q$ and $s$ respectively, then the corresponding ratio of increase in their length would be:

Options:
A $\frac{7 q}{\left(7 s p^2\right)}$
B $\frac{7 q}{\left(5 s p^2\right)}$
C $\frac{2 q}{(5 s p)}$
D $\frac{7 q}{(5 s p)}$

The correct answer is:
$\frac{7 q}{\left(5 s p^2\right)}$

Solution:
We know that
$$
\text { Young's modulus } \begin{aligned}
\gamma & =\frac{\mathrm{FL}}{\Delta 4 \mathrm{~L}} \\
& =\frac{4 \mathrm{FL}}{\pi \mathrm{D}^2 4 \mathrm{~L}} \\
\Rightarrow \quad \Delta \mathrm{L} & =\frac{4 \mathrm{FL}}{\pi \mathrm{D}^2 \mathrm{~L}}
\end{aligned}
$$
According to questions.
$$
\begin{aligned}
& \frac{\Delta \mathrm{L}_{\mathrm{S}}}{\Delta \mathrm{L}_{\mathrm{C}}}=\frac{\mathrm{F}_{\mathrm{S}}}{\mathrm{F}_{\mathrm{C}}} \cdot \frac{\mathrm{L}_{\mathrm{S}}}{\mathrm{L}_{\mathrm{C}}} \cdot \frac{\mathrm{D}_{\mathrm{C}}^2 \mathrm{~L}_{\mathrm{S}}}{\mathrm{D}_{\mathrm{S}}^2 \mathrm{~L}_{\mathrm{C}}} \\
& \text { Here } \mathrm{F}_{\mathrm{S}}=(5 \mathrm{~m}+2 \mathrm{~m}) \mathrm{g}=7 \mathrm{mg} \\
& \mathrm{F}_{\mathrm{C}}=5 \mathrm{mg},=?, \frac{\mathrm{D}_{\mathrm{S}}}{\mathrm{D}_{\mathrm{C}}}=P, \\
& \frac{\mathrm{L}_{\mathrm{S}}}{\mathrm{L}_{\mathrm{C}}}=\mathrm{S}
\end{aligned}
$$
Putting in eq. (ii)
$$
\begin{aligned}
\frac{\Delta \mathrm{L}_{\mathrm{S}}}{\Delta \mathrm{L}_{\mathrm{C}}} & =\frac{7 \mathrm{mg}}{5 \mathrm{mg}} \times q+\left(\frac{1}{\mathrm{P}}\right)^2\left(\frac{1}{\mathrm{~S}}\right) \\
& =\frac{7 q}{5 p^2 \mathrm{~S}}
\end{aligned}
$$

Topic: Physics, Mechanical Properties of Solids, NEET, NEET 2013 (Karnataka)
In the reaction ${ }_1^2 \mathrm{H}+{ }_1^3 \mathrm{H} \rightarrow{ }_2^4 \mathrm{He}+{ }_0^1 n$, if the binding energies of ${ }_1^2 \mathrm{H},{ }_1^3 \mathrm{H}$ and ${ }_2^4 \mathrm{He}$ are respectively $a, b$ and $c$ (in Me V), then the energy (in $\mathrm{MeV}$ ) released in this reaction is:

Options:
A $a+b+c$
B $a+b-c$
C $c-a-b$
D $c+a-b$

The correct answer is:
$c-a-b$

Solution:
Energy in given reaction $=B E$ of products $-B . E$. of reactants
$$
\begin{aligned}
& =C-(a+h) \\
& =C-a-b
\end{aligned}
$$

Topic: Physics, Nuclear Physics, NEET, NEET 2005
In the reaction

Options:
A
B
C
D

The correct answer is:

Solution:

Topic: Chemistry, Aldehydes and Ketones, NEET
In the reaction 2 Na(s) + H2(g) → 2 NaH(s), which element undergoes oxidation?

Options:
A Sodium (Na)
B Hydrogen (H)
C Both Na and H
D Neither Na nor H

The correct answer is:
Sodium (Na)

Solution:
Sodium (Na) starts with an oxidation state of 0 and ends with an oxidation state of +1 in NaH, indicating oxidation.

Topic: Chemistry, Redox Reactions, NEET
In the reaction

Options:
A A will give haloform
B B will give haloform
C Both A and B will give haloform
D Both A and B will not give haloform

The correct answer is:
Both A and B will give haloform

Solution:
As both A and B can form haloform reaction. So, they are ethanol and isopropyl alcohol respectively.

Topic: Chemistry, Carboxylic Acid Derivatives, NEET
In the reaction 2H2(g) + O2(g) → 2H2O(l), what is the oxidation state of oxygen in H2O?

Options:
A 0
B +1
C -1
D -2

The correct answer is:
-1

Solution:
The oxidation state of oxygen in H2O is -1.

Topic: Chemistry, Redox Reactions, NEET
In the reaction 2H2(g) + O2(g) → 2H2O(l), which element goes from a neutral (zero) state to a positive state?

Options:
A Hydrogen
B Oxygen
C Chlorine
D Carbon

The correct answer is:
Hydrogen

Solution:
In this reaction, hydrogen goes from a neutral (zero) state in H2 to a positive state in H2O.

Topic: Chemistry, Redox Reactions, NEET
In the reaction 2HI(g) converts to H2 (g) + I2 (g), what is the stoichiometric coefficient of H2?

Options:
A 1
B 2
C 0
D 3

The correct answer is:
1

Solution:
In the reaction 2HI(g) converts to H2 (g) + I2 (g), the stoichiometric coefficient of H2 is 1.

Topic: Chemistry, Chemical Kinetics, NEET
In the reaction 2Na(s) + Cl2(g) → 2NaCl(s), what is sodium's role?

Options:
A Oxidizing agent
B Reducing agent
C Acceptor of electrons
D Donor of electrons

The correct answer is:
Reducing agent

Solution:
Sodium is described as a reducing agent in the passage because it donates electrons to chlorine, helping in its reduction.

Topic: Chemistry, Redox Reactions, NEET
In the reaction

Options:
A p-Bromofluorobenzene
B 2, 4, 6-Tribromofluorobenzene
C p-Bromoaniline
D 1, 3, 5-Tribromobenzene

The correct answer is:
2, 4, 6-Tribromofluorobenzene

Solution:
Here X is 2, 4, 6-tribromofluorobenzene

Topic: Chemistry, Amines, NEET
In the reaction 4A+2B+3CâA4 B2 C3, what will be the number moles of product formed, starting from one mole of A,â0.6 moles of B and 0.72 moles of Câ?

Options:
A 0.25
B 0.3
C 0.24
D 2.32

The correct answer is:
0.24

Solution:
Stoichiometric mole ratio ââ ââAââââââ âBâââ ââââââC = 1 4 ââ,ââ 0.6 2 ââ,ââ 0.72 3 =â0.25,â0.30,0.24
C is Limiting Reagent
So, according to Stoichiometry of reaction
3 mol C gives = 1 mol A4B2,C3.
â´ 0.72 mol of C gives= 1 3 Ã0.72=0.24

Topic: Chemistry, Some Basic Concepts of Chemistry, NEET
In the reaction,
$A$ is

Options:
A $\mathrm{HgSO}_4 / \mathrm{H}_2 \mathrm{SO}_4$
B $\mathrm{Cu}_2 \mathrm{Cl}_2$
C $\mathrm{H}_3 \mathrm{PO}_2$ and $\mathrm{H}_2 \mathrm{O}$
D $\mathrm{H}^{+} / \mathrm{H}_2 \mathrm{O}$

The correct answer is:
$\mathrm{H}_3 \mathrm{PO}_2$ and $\mathrm{H}_2 \mathrm{O}$

Solution:
When diazonium salt is treated with $\mathrm{H}_3 \mathrm{PO}_2$ followed by hydrolysis, it diazonium group is replaced by $-\mathrm{H}$ resulting to the formation of hydrocarbon. Thus, $A$ must be $\mathrm{H}_3 \mathrm{PO}_2 / \mathrm{H}_2 \mathrm{O}$.

Topic: Chemistry, Hydrocarbons, NEET, NEET 2013 (All India)
In the reaction

A is

Options:
A Cu2Cl2
B H3PO2 and H2O
C H+/H2O
D HgSO4/H2SO4

The correct answer is:
H3PO2 and H2O

Solution:

Topic: Chemistry, Amines, NEET
In the reaction between alcohol and sodium, what role does sodium play?

Options:
A Sodium acts as a reducing agent.
B Sodium acts as a catalyst.
C Sodium acts as an acid.
D Sodium acts as a base.

The correct answer is:
Sodium acts as a base.

Solution:
Sodium acts as a base by accepting a proton from the alcohol to form an alkoxide and release hydrogen gas.

Topic: Chemistry, Alcohols Phenols and Ethers, NEET
In the reaction between an alcohol and a carboxylic acid, what is the role of concentrated sulfuric acid?

Options:
A It acts as a catalyst.
B It acts as a base.
C It neutralises the acid.
D It removes water formed during the reaction.

The correct answer is:
It removes water formed during the reaction.

Solution:
Concentrated sulfuric acid is used to remove water formed during the reaction between an alcohol and a carboxylic acid.

Topic: Chemistry, Alcohols Phenols and Ethers, NEET
In the reaction between an alcohol and an acid chloride, what is the role of pyridine?

Options:
A Pyridine acts as a reducing agent.
B Pyridine acts as a catalyst.
C Pyridine neutralises the acid chloride.
D Pyridine removes water formed during the reaction.

The correct answer is:
Pyridine neutralises the acid chloride.

Solution:
Pyridine is used to neutralise the HCl formed during the reaction between an alcohol and an acid chloride.

Topic: Chemistry, Alcohols Phenols and Ethers, NEET
In the reaction between phenol and sodium hydroxide, which species acts as the Brönsted acid?

Options:
A Phenol
B Sodium hydroxide
C Sodium phenoxide
D Water

The correct answer is:
Phenol

Solution:
In the reaction, phenol donates a proton (H+) and acts as the Brönsted acid.

Topic: Chemistry, Alcohols Phenols and Ethers, NEET
In the reaction between water and an alkoxide, what role does water play?

Options:
A Water acts as a reducing agent.
B Water acts as a catalyst.
C Water acts as an acid.
D Water acts as a base.

The correct answer is:
Water acts as an acid.

Solution:
In the reaction, water donates a proton (H+) and acts as an acid.

Topic: Chemistry, Alcohols Phenols and Ethers, NEET
In the reaction Bromine
3  Br 2  + 6  OH − →5  Br −  +  BrO 3 −  + 3  H 2 O

Options:
A is reduced
B is oxidised
C disproportionates
D disintergrates

The correct answer is:
disproportionates

Solution:
3Br2(0)+6OH-â5Br-+BrO3-+3H2O
In this reaction, O.S. of bromine changes from (i) to 0 to -1 and (ii) 0 to +5. Hence, Br2 is reduced to Br- and also oxidized to BrO3- . Thus, Br2 is oxidised as well as reduced. In other words, Br2 undergoes disproportionation.

Topic: Chemistry, Redox Reactions, NEET
In the reaction
CH3-C≡C-H→(i)NaNH2/NH3(l)(A)→CH3-CH2-CH2-Br(B)
The product B is

Options:
A CH3-C≡C-CH2-CH2-CH3
B CH3-CH=CH2
C CH3-CH2-C≡C-CH2-CH3
D CH3-CH=C=CH-CH2-CH3

The correct answer is:
CH3-C≡C-CH2-CH2-CH3

Solution:
Here propyne is converted into hex-2-yne.
CH 3 −C≡C−H → NaNH 2 / NH 3 l CH 3 −C≡ C −    Na ⊕ → CH 3 − CH 2 − CH 2 −Br CH 3 −C≡C− CH 2 − CH 2 − CH 3

Topic: Chemistry, Hydrocarbons, NEET
In the reaction CH3C*ONH2→P2O5ΔCH3C*N the hybridisation state of the C* atom changes from:

Options:
A sp2-sp
B sp3-sp
C sp3-sp2
D sp2-sp3

The correct answer is:
sp2-sp

Solution:
Here hybridisation state of the C* atom changes from sp2-sp

Topic: Chemistry, Amines, NEET
In the reaction, CH 3 â CH 2 â CBr 3 â Ag Powder/Î X ,
the product X is

Options:
A Propyne
B CH3-C≡C-Ag
C 3-Hexyne
D 3-Hexene

The correct answer is:
3-Hexyne

Solution:
Here the product X is pent-3-yne and it is formed as follows
CH3-CH2-CBr3+Br3C-CH2-CH3→6Ag/ΔCH3-CH2-C≡C-CH2-CH3+6AgBr

Topic: Chemistry, Haloalkanes and Haloarenes, NEET
In the reaction
CH 3 â CH 2 âOH â ii â LiAlH 4 i TsCl X , (X) will be

Options:
A CH2=CH2
B CH3-CH2-CH2-CH3
C CH3-CH3
D CH3-CH=CH-CH3

The correct answer is:
CH3-CH3

Solution:
Here the compound X is ethane and formed as follows
CH3-CH2-OH→TsClCH3-CH2-OTs→LiAlH4CH3-CH3.
Hint : It involves substitution followed by reduction.

Topic: Chemistry, Alcohols Phenols and Ethers, NEET
In the reaction

CH3CNâHClSnCl2XâBoiling H2OY,

The term Y is,

Options:
A Acetone
B Ethanamine
C Acetaldehyde
D Dimethyl amine

The correct answer is:
Acetaldehyde

Solution:
SnCl2+2HClgâSnCl4+2[H]
CH3CN+2H+HClâCH3CH=NH.HClâH2OboilCH3CHO+NH4Cl
(X) (Y)
(X) is acetaldimine hydrochloride and (Y) is acetaldehyde.

Topic: Chemistry, Amines, NEET
In the reaction

CH 3 COOH + HCOOH → MnO /  300 o C [X]

[X] will be

Options:
A HCHO
B CH3CHO
C CH3COCH3
D CH3-COOH

The correct answer is:
CH3CHO

Solution:
Here acetaldehyde is formed as follows

Topic: Chemistry, Carboxylic Acid Derivatives, NEET
In the reaction CH4(g) + 4Cl2(g) → CCl4(l) + 4HCl(g), which element goes from a zero state to a positive state?

Options:
A Carbon
B Chlorine
C Hydrogen
D Oxygen

The correct answer is:
Chlorine

Solution:
In this reaction, chlorine goes from a zero state to a positive state.

Topic: Chemistry, Redox Reactions, NEET
In the reaction CH4(g) + 4Cl2(g) → CCl4(l) + 4HCl(g), which element undergoes a reduction?

Options:
A Carbon
B Chlorine
C Hydrogen
D Oxygen

The correct answer is:
Carbon

Solution:
In this reaction, carbon undergoes a reduction as it gains electrons.

Topic: Chemistry, Redox Reactions, NEET
In the reaction CH4(g) + 4Cl2(g) → CCl4(l) + 4HCl(g), which element undergoes oxidation?

Options:
A Carbon
B Chlorine
C Hydrogen
D Oxygen

The correct answer is:
Chlorine

Solution:
In this reaction, chlorine undergoes oxidation as it loses electrons.

Topic: Chemistry, Redox Reactions, NEET
In the reaction
CH≡CH → Na/NH 3 / l (A) → DCl (B) → (i)  Sia 2 BH (C) , the product 'C' is

Options:
A D-C≡C-D
B CH3-C||O-H
C
D

The correct answer is:

Solution:
The reaction sequence is as follows

Topic: Chemistry, Hydrocarbons, NEET
In the reaction given below
H−C≡C−H + H−C≡C−H → NH 4 Cl Cu 2 Cl 2 (x), , 'X' will be

Options:
A CH2=CH-C≡CH
B Cu-C≡C-Cu
C CH≡C-Cu
D CH≡C-C≡CH

The correct answer is:
CH≡C-C≡CH

Solution:
CH≡CH + CH≡CH → NH 4 Cl Cu 2 Cl 2 CH≡C−C≡CH

Topic: Chemistry, Hydrocarbons, NEET
In the reaction H2(s) + Cl2(g) → 2HCl(g), what is the oxidation state of chlorine in HCl?

Options:
A 0
B +1
C -1
D -2

The correct answer is:
-1

Solution:
The oxidation state of chlorine in HCl is -1.

Topic: Chemistry, Redox Reactions, NEET
In the reaction, H3PO4+Ca(OH)2→CaHPO4+2H2O, the equivalent mass of H3PO4 is

Options:
A 49 g
B 32.7 g
C 196 g
D 98 g

The correct answer is:
49 g

Solution:
In the reaction
H3PO4+Ca(OH)2âCaHPO4+2H2O,
Basicity of phosphoric acid is 2.
Thus, equivalent mass of H3PO4=Molecular massBasicity
=982=49 g .

Topic: Chemistry, Some Basic Concepts of Chemistry, NEET
In the reaction, \(\mathrm{BrO}_3^{-}\)(aq.) \(+5 \mathrm{Br}^{-}\)(aq.) \(+6 \mathrm{H}^{+}\)(aq.) \(\rightarrow 3 \mathrm{Br}_2(\mathrm{l})+3 \mathrm{H}_2 \mathrm{O}\) (l) .The rate of appearance of bromine $\left(\mathrm{Br}_2\right)$ is related to rate of disappearance of bromide ions as following

Options:
A $\frac{\mathrm{d}\left[\mathrm{Br}_2\right]}{\mathrm{dt}}=-\frac{3}{5} \frac{\mathrm{d}\left[\mathrm{Br}^{-}\right]}{\mathrm{dt}}$
B $\frac{\mathrm{d}\left[\mathrm{Br}_2\right]}{\mathrm{dt}}=-\frac{5}{3} \frac{\mathrm{d}\left[\mathrm{Br}^{-}\right]}{\mathrm{dt}}$
C $\frac{\mathrm{d}\left[\mathrm{Br}_2\right]}{\mathrm{dt}}=\frac{5}{3} \frac{\mathrm{d}\left[\mathrm{Br}^{-}\right]}{\mathrm{dt}}$
D $\frac{\mathrm{d}\left[\mathrm{Br}_2\right]}{\mathrm{dt}}=\frac{3}{5} \frac{\mathrm{d}\left[\mathrm{Br}^{-}\right]}{\mathrm{dt}}$

The correct answer is:
$\frac{\mathrm{d}\left[\mathrm{Br}_2\right]}{\mathrm{dt}}=-\frac{3}{5} \frac{\mathrm{d}\left[\mathrm{Br}^{-}\right]}{\mathrm{dt}}$

Solution:
Key Idea Rate of appearance/disappearance
$$
= \pm \frac{1}{\begin{array}{l}
\text { stoichiometric } \\
\text { coefficient }
\end{array}} \times \frac{\text { [reactant or product] }}{\text { time taken }}
$$
For reaction,
$$
\begin{aligned}
\mathrm{BrO}_3^{-}(\mathrm{aq})+5 \mathrm{Br}^{-}(\mathrm{aq})+6 \mathrm{H}^{+} \longrightarrow & 3 \mathrm{Br}_2(1) \\
& +3 \mathrm{H}_2 \mathrm{O}(\mathrm{l})
\end{aligned}
$$
Rate of appearance of bromine $\left(\mathrm{Br}_2\right)$
$$
=+\frac{1}{3} \frac{\mathrm{d}\left[\mathrm{Br}_2\right]}{\mathrm{dt}}
$$
Rate of disappearance of bromide ion $\left(\mathrm{Br}^{-}\right)$
$$
=-\frac{1}{5} \frac{\mathrm{d}\left[\mathrm{Br}^{-}\right]}{\mathrm{dt}}
$$
or $\quad \frac{\mathrm{d}\left[\mathrm{Br}_2\right]}{\mathrm{dt}}=-\frac{3}{5} \frac{\mathrm{d}\left[\mathrm{Br}^{-}\right]}{\mathrm{dt}}$

Topic: Chemistry, Chemical Kinetics, NEET, NEET 2009 (Screening)