datavorous/entrance-exam-dataset huggingface dataset:
In a reaction between A and B, the initial rate of reaction (r0) was measured for different initial concentrations of A and B as given below:
What is the order of the reaction with respect to A and B?

Options:
A Order with respect to A = 2.5 and Order with respect to B = 1
B Order with respect to A = 1.5 and Order with respect to B = 1
C Order with respect to A = 2.5 and Order with respect to B = 0
D Order with respect to A = 1.5 and Order with respect to B = 0

The correct answer is:
Order with respect to A = 1.5 and Order with respect to B = 0

Solution:
Correct Option is : (D)
Order with respect to A = 1.5 and Order with respect to B = 0

Topic: Chemistry, Chemical Kinetics, NEET
In a reaction, Cr2O72- is reduced to Cr3+. What will be the concentration of 0.1âM K2Cr2O7 in equivalent per litre? Cr 2 O 7 2â +14 H + +6 e â â2 Cr 3+ +7 H 2 O

Options:
A 0.9 N
B 0.6 N
C 0.3 N
D 0.2 N

The correct answer is:
0.6 N

Solution:
N = M Ã Valence factor
âµN = 0.1 Ã 6 2â Cr 6+ +6 e â â2 Cr 3+
K2Cr2O7= 0.6 N.

Topic: Chemistry, Redox Reactions, NEET
In a reaction carried out at 400K , 0.01% of the total number of collisions is effective. The energy of activation of the reaction is

Options:
A 13.3kJ/mol
B 23.5kJ/mol
C 3.2kJ/mol
D 30.6kJ/mol

The correct answer is:
30.6kJ/mol

Solution:
K=Ae-EaRT
eEaRT=0.01100⇒EaRT=2.303logâ¡10-4
⇒Ea=2.303Ã4Ã400=30.6kJ/mol

Topic: Chemistry, Chemical Kinetics, NEET
In a reaction if the concentration of reactant A is tripled, the rate of reaction becomes twenty seven times. What is the order of the reaction?

Options:
A Two
B One
C Zero
D Three

The correct answer is:
Three

Solution:
Correct Option is : (D)
Three

Topic: Chemistry, Chemical Kinetics, NEET
In a reaction of aniline a coloured product $C$ was obtained.
$\	ext {The structure of } C \text { would be}$

Options:
A

B

C

D

The correct answer is:

Solution:
Key Idea : $1^{\circ}$ amines form diazonium salts at low temperature and diazonium salts are weak electrophiles, so react with strongly activated ring. (takes $\mathrm{H}$ from benzene nucleus).
Note : The $-\mathrm{N}=\mathrm{N}-$ linkage is called -azo linkage, and the reactions in which azo or diazo compounds are formed, are called diazo coupling reactions.

Topic: Chemistry, Aldehydes and Ketones, NEET, NEET 2008 (Screening)
In a reaction RCHO is reduced to RCH3 using amalgamated zinc and concentrated HCl and warmtextng the solution. The reaction is known as

Options:
A Meerwein-Ponndorf reaction
B Clemmensen's reduction
C Wolff-Kishner reduction
D Schiff's reaction

The correct answer is:
Clemmensen's reduction

Solution:
In Clemmensen's reduction, aldehyde (RCHO) and ketones (R-CO-Râ²) are reduced into hydrocarbons (R-R').
RCHO+6Hâ Zn amalgamated Conc.HClRCH3+2H2O

Topic: Chemistry, Aldehydes and Ketones, NEET
In a reaction, the initial conc. of the reactants increases four fold and rate becomes eight times of its initial value, order of reactions is

Options:
A 2
B 3.5
C 2.5
D 1.5

The correct answer is:
1.5

Solution:
Let the rate law be
r=k ( c ) n        ... ( i )
on increasing concentration
8r=k4cn ... (ii)
23=22n
2n=3
n=1.5

Topic: Chemistry, Chemical Kinetics, NEET
In a reaction where the stoichiometric coefficients of the reactants and products are the same, what is the relationship between the rate of disappearance of reactants and the rate of appearance of products?

Options:
A The rates are equal.
B The rates are inversely proportional.
C The rates are directly proportional.
D The rates are zero.

The correct answer is:
The rates are equal.

Solution:
In a reaction with stoichiometric coefficients of reactants and products being the same, the rate of disappearance of any of the reactants is the same as the rate of appearance of the products.

Topic: Chemistry, Chemical Kinetics, NEET
In a refrigerator, the low temperature coil of evaporator is at -23℃ and the compressed gas in the condenser has a temperature of 77℃. The amount of electrical energy spent in freezing 1 kg of water at 0℃ is

Options:
A 134400 J
B 1344 J
C 80000 J
D 3200 J

The correct answer is:
134400 J

Solution:
COP=T2T1-T2=273-23273+77-273-23=250100=2.5
As COP=Q2W
∴ 2.5=1000×80×4.2W
or W=1000×80×4.22.5=134400 J

Topic: Physics, Thermodynamics, NEET
In a region of constant potential

Options:
A The electric field is uniform and nonzero
B The electric field is infinity
C There can be no charge inside the region
D None of the above

The correct answer is:
There can be no charge inside the region

Solution:
Potential is constant.
Hence, E=-dVdr
E=0 â´as Vâconstant
If there is a charge, there will be an electric field associated with it.

Topic: Physics, Electrostatics, NEET
In a region of space, the electric field is given by Eâ=8i^+4j^+3k^. The electric flux through a surface of area of 100 units in x-y plane is

Options:
A 800 units
B 300 units
C 400 units
D 1500 units

The correct answer is:
300 units

Solution:
Here, E→=8i^+4j^+3k^
S→=100k^
(direction of the area is perpendicular to x-y plane)
ϕ=E→⋅ S→=8i^+4j^+3k^ ⋅100k^
= 300 units

Topic: Physics, Electrostatics, NEET
In a region of uniform electric field of intensity E, an electron of mass me is released from rest. The distance travelled by the electron in time t is

Options:
A 2met2e
B eEt22me
C megt2eE
D 2Et2eme

The correct answer is:
eEt22me

Solution:
Acceleration, a=eEm here acceleration is constant so we can use the equation of motion
S=12at2
=12eEm t2

Topic: Physics, Electrostatics, NEET
In a region the potential is represented by Vx, y, z=6x-8xy-8y+6yz, where V is in volts and x, y, z, are in meters. The electric force experienced by a charge of 2 coulombs situated at point 1, 1, 1 is:

Options:
A 65 N
B 30 N
C 24 N
D 435 N

The correct answer is:
435 N

Solution:
Potential in the space varies as Vx, y, z=6x-8xy-8y+6yz.

Electric field is given by,
Ex=-∂V∂x=-6+8y
Ey=-∂V∂y=8x+8-6z
Ez=-∂V∂z=-6y
E→=-6+8y i^+8x+8-6zj^-6y k^

Putting the value of the position we get,
E→1, 1, 1=2i^+10j^-6k^

Magnitude is given by,
E→=235 NC-1

Force on the charge is given by,
F=qE=2×235=435 N

Topic: Physics, Electrostatics, NEET, NEET 2014
In a relationship of Lichen, fungal partner is called

Options:
A Metabiont
B Phycobiont
C Mycobiont
D Probiont

The correct answer is:
Mycobiont

Solution:
Lichens are symbiotic associations, i.e., mutually useful associations between algae and fungi. The algal component is known as phycobiont and fungal component as mycobiont, which is autotrophic and heterotrophic, respectively. Algae prepare food for fungi and fungi provide shelter and absorb mineral nutrients and water for their partner.

Topic: Biology, Biological Classification, NEET
In a resonance pipe the first and second resonance are obtained at depths 22.7 cm and 70.2 cm respectively. What will be the end correction?

Options:
A 1.05 cm
B 115.5 cm
C 92.5 cm
D 113.5 cm

The correct answer is:
1.05 cm

Solution:
For the end correction x ,
â¹ x=l2-3l12
=70.2-3Ã22.72=1.05 cm

Topic: Physics, Waves and Sound, NEET
In a resonance tube, using a tuning fork of frequency 325 Hz, two successive resonance length are observed as 25.4 cm and 77.4 cm respectively. The velocity of sound in air is

Options:
A 338 m s-1
B 328 m s-1
C 330 m s-1
D 320 m s-1

The correct answer is:
338 m s-1

Solution:
v=2nl2-l1=2Ã32577.4-25.4 cm s-1
=650Ã52100 m s-1=338 m s-1

Topic: Physics, Waves and Sound, NEET
In a reverse-biased diode when the applied voltage changes by 1 V, the current is found to change by 0.5 μA. The reverse bias resistance of the diode is

Options:
A 2Ã105Â Î©
B 2Ã106Â Î©
C 200 Ω
D 2 Ω

The correct answer is:
2×106 Ω

Solution:
Reverse resistance = ∆V∆I=10.5×10-6=2×106 Ω

Topic: Physics, Semiconductors, NEET
In a reversible adiabatic change ΔQ is

Options:
A infinity
B zero
C equal to CV dt
D equal to nRlnV2/V1

The correct answer is:
zero

Solution:
For adiabatic change q=0

Topic: Chemistry, Thermodynamics (C), NEET
In a reversible chemical reactions equilibrium is established when

Options:
A Concentration of reactants and products are equal
B Opposing reaction ceases
C Velocity of opposing reaction is the same as that of forward reaction
D When Reaction heat becomes negative

The correct answer is:
Velocity of opposing reaction is the same as that of forward reaction

Solution:
At equillibrium, Rate of backward reaction = Rate of forward reaction

Topic: Chemistry, Chemical Kinetics, NEET
In a reversible process; Î Sâ¡ sys + Î Sâ¡ surr ; is

Options:
A > 0
B < 0
C ≥ 0
D = 0

The correct answer is:
= 0

Solution:
There exist thermodynamic equilibrium during reversible process.
Hence, △ S state =△ S system +△ S surrounding =0

Topic: Chemistry, Thermodynamics (C), NEET
In a reversible reaction, what is the condition when the reaction is at equilibrium?

Options:
A ∆rH is maximum
B ∆rS is maximum
C ∆rG is maximum
D ∆rG is minimum

The correct answer is:
∆rG is minimum

Solution:
In a reversible reaction at equilibrium, the change in Gibbs free energy (∆rG) is at a minimum. This indicates that the system has reached a stable equilibrium state.

Topic: Chemistry, Thermodynamics (C), NEET
In a ring girdled plant:

Options:
A The shoot dies first
B The root dies first
C The shoot and root die together
D Neither root nor shoot will die

The correct answer is:
The root dies first

Solution:
In a ring girdled plant the root dies first. Like all vascular plants, trees use two vascular tissues for transportation of water and nutrients: the xylem (also known as the wood), and the phloem (the innermost layer of the bark). Girdling results in the removal of the phloem, and death occurs from the inability of the leaves to transport sugars (primarily sucrose) to the roots. This is an experiment to prove the translocation of food through the phloem.

Topic: Biology, Transport in Plants, NEET, NEET 2015 (Phase 1)
In a Rutherford scattering experiment when a projectile of charge $Z_1$ and mass $M_1$ approaches a target nucleus of charge $Z_2$ and mass $\mathrm{M}_2$, the distance of closest approach is $\mathrm{r}_0$. The energy of the projectile is

Options:
A directly proportional to $\mathrm{M}_1 \times \mathrm{M}_2$
B directly proportional to $\mathrm{Z}_1 \mathrm{Z}_2$
C inversely proportional to $Z_1$
D directly proportional to mass $\mathrm{M}_1$

The correct answer is:
directly proportional to $\mathrm{Z}_1 \mathrm{Z}_2$

Solution:
A particle of mass $M_1$ and charge $z_1$ possess initial velocity $u$, when it is at a large distance from the nucleus of an atom having atomic number $\mathrm{z}_2$. At the distance of closest approach, the kinetic energy of particle is completely converted to potential energy. Mathematically,
$$
\frac{1}{2} \mathrm{M}_1 \mathrm{u}^2=\frac{1}{4 \pi \varepsilon_0} \frac{\mathrm{z}_1 \mathrm{z}_2}{\mathrm{r}_0}
$$
So the energy of the particle is directly proportional to $\mathrm{z}_1 \mathrm{z}_2$.

Topic: Physics, Atomic Physics, NEET, NEET 2009 (Screening)
In a saturated solution of the sparingly soluble strong electrolyte AgIO3 ( molecular mass = 283 ) the equilibrium which sets in is
AgIO 3 s ⇌ Ag + aq + IO 3 − aq
If the solubility product constant Ksp of AgIO3 at a given temperature is 1 · 0 × 1 0 - 8 , what is the mass of AgIO3 contained in 100 ml of its saturated solution ?

Options:
A 1 · 0 × 1 0 - 4 g
B 2 8 · 3 × 1 0 - 2 g
C 1 · 0 × 1 0 - 7 g
D 2 Â· 8 3 Ã 1 0 - 3 g

The correct answer is:
2 · 8 3 × 1 0 - 3 g

Solution:
AgIO 3 â Ag + + IO 3 - [ S = Solubility ]
S S
Ksp = S2
Or, S 2 = 1 Â· 0 Ã 1 0 - 8
S = 1 Â· 0 Ã 1 0 - 4 mol / it
= 1 Â· 0 Ã 1 0 - 4 Ã 2 8 3 g / lit
= 2 8 Â· 3 Ã 1 0 - 4 gm / 100 ml
= 2 Â· 8 3 Ã 1 0 - 3 gm / 100 ml

Topic: Chemistry, Ionic Equilibrium, NEET
In a seconds pendulum, the mass of the bob is 30 g. If it is replaced by 90 g mass, then its time period will be

Options:
A 1 s
B 2 s
C 4 s
D 3 s

The correct answer is:
2 s

Solution:
The second pendulum is a special pendulum with time period of 2 s.
This time period is independent of pendulum mass.

Topic: Physics, Oscillations, NEET
In a semiconductor, separation between conduction and valence band is of the order of

Options:
A 0 eV
B 1 eV
C 10 eV
D 50 eV

The correct answer is:
1 eV

Solution:
In conductance, separation between conduction and volume bands is zero and in insulated, it is greater than 1 eV.
Hence, in semiconductor the separation between conduction and volume band is 1 eV.

Topic: Physics, Semiconductors, NEET
In a series LCR AC circuit, the current is maximum when the impedance is equal to

Options:
A The reactance
B The resistance
C Zero
D Twice the reactance

The correct answer is:
The resistance

Solution:
In L-C-R circuit, the current
l=E0R2+XL-XC2
When impedance Z= R, i.e. XL=XC the current in the L-C-R circuit will be maximum.

Topic: Physics, Alternating Current, NEET
In a series LCR circuit, resistance R=10 Î© and the impedance Z=10 Î©. The phase difference between the current and the voltage is

Options:
A 0°
B 30°
C 45°
D 60°

The correct answer is:
0°

Solution:
Impedance,
Z=R2+XL-XC2
∴ 10=(102+XL-XC2
⇒ 100=100+XL-XC2
⇒ XL-XC=0 ...(i)
Let ϕ is the phase difference between current and voltage
tan⁡ϕ=XL-XCR
∴ tan⁡ϕ=0R [From Eq.(i)]
⇒ ϕ=0°

Topic: Physics, Alternating Current, NEET
In a series LCR circuit the frequency of a 10 V AC voltage source is adjusted in such a fashion that the reactance of the inductor measures 15 Î© and that of the capacitor 11 Î©. If R=3 Î© , the potential difference across the series combination of L and C will be

Options:
A 8 V
B 10Â V
C 22Â V
D 52Â V

The correct answer is:
8 V

Solution:
Reactance, Z=R2+XL–XC2
Z=32+15-112=5
∴I=VZ=105=2 A
∴ VL=IXL=2×15=30 V
VC=IXC=2×11=22 V
but VL & VC are in opposite phase ⇒ net voltage of L & C=30-22=8 V

Topic: Physics, Alternating Current, NEET
In a series LCR circuit, the inductance L is 10 mH, capacitance C is 1 μF and resistance R is 100 Ω. The frequency at which resonance occurs is:

Options:
A 1.59 kHz
B 15.9 rad s-1
C 15.9 kHz
D 1.59 rad s-1

The correct answer is:
1.59 kHz

Solution:
Resonance occurs when the value of inductive and capacitive reactances have equal magnitude but a phase difference of 180°.

Therefore, resonance frequency =12πLC=12π10×10-3×1×10-6=1.591×103≈1.59 kHz

Topic: Physics, Alternating Current, NEET, NEET 2023 (All India)
In a series LCR circuit, the voltage across resistance, capacitance and inductance is 10 V each. If the capacitor is removed, the voltage across the inductance will be

Options:
A 10 V
B 102 V
C 102V
D 20 V

The correct answer is:
102V

Solution:
Given, VR=VL=VC=10 V

This means the LCR circuit is in resonance and the reactance of inductor and capacitor is equal to the resistance of the resistor.
⇒Vsupply=VR=10 V
After removing capacitor
Vsupply=VR2+VL2
Since, VR=VL

⇒ 10=VL2+VL2

⇒ 2VL2=100
VL=102 V

Topic: Physics, Alternating Current, NEET
In a series L-R circuit, under which condition the power loss will be least for an a.c voltage source?

Options:
A high resistance and high inductance
B high resistance and low inductance
C low resistance and high inductance
D low resistance and low inductance

The correct answer is:
low resistance and high inductance

Solution:
The power loss in an a.c circuit will be minimum when resistance is low so that inductor is dominating the circuit.

Topic: Physics, Alternating Current, NEET
In a series LCR circuit, an alternating emf (V) and current (I) are given by the equation V=V0sin⁡ωt,I=I0sin⁡ωt+π3. The average power dissipated in the circuit over a cycle of AC is

Options:
A V0I02
B V0I04
C 32V0I0
D Zero

The correct answer is:
V0I04

Solution:
V=V0sinâ¡Ït
I=I0sinâ¡Ït+Ï3
The average dissipated power to AC circuit.
P=Vrms Irmscosâ¡Ï
Here, Vrms=V02
Irms=I02;Ï=Ï3
P=V02ÃI02Ãcosâ¡Ï3=V0I02Ãcosâ¡60o
=V0I02Ã12=V0I04

Topic: Physics, Alternating Current, NEET
In a series LCR circuit, the potential drop across L, C and R respectively are 40 V, 120 V and 60 V. Then, the source voltage is

Options:
A 220 V

B 160 V

C 180 V

D 100 V

The correct answer is:
100 V

Solution:
In series LCR circuit, the source voltage
V=VR2+VL-VC2
Here, VR=60 V â VL=40 V
VC=120 V
V=602+40-1202
=602+-802=3600+6400
=10000=100 V

Topic: Physics, Alternating Current, NEET
In a series LCR circuit the rms voltages across the inductance, capacitance and resistance are respectively 4 V, 8 V and 5 V. The RMS voltage of the AC source in the circuit is

Options:
A 17 V

B 13 V
C 5 V
D 6.4 V

The correct answer is:
6.4 V

Solution:
Given V L =4âV,â V C =8âV,â V R =5âV
Using V=VR2+VC~VL2
=52+8-42=41
=6.4âV

Topic: Physics, Alternating Current, NEET
In a series LCR circuit, the voltage across the resistor, capacitor and inductor is 10 V each. If the capacitor is short-circuited, the voltage across the inductor will be

Options:
A 10 V
B 102 V
C 103 V
D 20 V

The correct answer is:
102 V

Solution:
Here, R=XL=XC, because voltage across them is the same.
When the capacitor is short circuited,
I=10R2+XL212=102R
Hence, potential drop across inductor =IXL=IR=102 V

Topic: Physics, Alternating Current, NEET
In a series LCR circuit, the voltage drop across the resistance is 8 V, across the inductor is 6 V and across the capacitor is 12 V. Then,

Options:
A the voltage of the source will be leading the current in the circuit
B the voltage drop across each element will be less than the applied voltage
C the power factor of the circuit will be 43
D none of these

The correct answer is:
none of these

Solution:
Since, cosâ¡Ï=RZ=IRIZ=810=45
(Also cosâ¡Ï can never be greater than 1)
Hence, (c) is wrong
Also IXC>IXL â XC>XL
â´ Current will be leading.
In an LCR circuit,
V= VL-VC2+VR2=6-122+82
V=10 V, which is less than the voltage drop across the capacitor.

Topic: Physics, Alternating Current, NEET
In a series LCR circuit, the voltages across an inductor, a capacitor, and a resistor are 30 V, 30 V and 60 V respectively. The phase difference between the applied voltage and the current in the circuit is

Options:
A

60°

B

30°

C

90°

D

0Â°

The correct answer is:

0Â°

Solution:
tanϕ=VL−VCVR=30−3060=0

or ϕ=0°

Topic: Physics, Alternating Current, NEET
In a series LCR circuit with an AC source R=300 Î©, C=20 Î¼F, L=1 H, Erms=50 V and f=50Ï Hz. The potential difference across the capacitor is -

Options:
A 50 V
B 502V
C 40Â V
D 402V

The correct answer is:
50 V

Solution:
XC=1Cω=120×10-6×2π×50π=500 Ω
XL=Lω=L×2π×50π=100 Ω
Irms=ErmsZ=50R2+XC-XL2
=503002+500-1002
=50500=110A
VC=Irms × XC
=110×500 V
=50 V

Topic: Physics, Alternating Current, NEET
In a series resonant LCR circuit, the voltage across R is 100 Vand R=1 kÎ© with C = 2 Î¼ F. The resonant frequency Ï is 200 rad s-1. At resonance the voltage across L is

Options:
A 4 × 10 - 3 V
B 2.5 × 10 - 2 V
C 40 V
D 250 V

The correct answer is:
250 V

Solution:
Current I = E Z
where E = V R 2 + V L - V C 2
Z = R 2 + X L - X C 2
At resonance, X L = X C
∴ Z = R
Again at resonance, V L = V C
∴ E = V R
∴ I = V R R = 100 1 × 10 3 = 0.1 A
∴ V L = I L ω = I C ω = 0.1 2 × 10 - 6 × 200
∴ VL=250 V.

Topic: Physics, Alternating Current, NEET
In a set of reaction acetic acid yielded a product 'd'.

Options:
A

B

C

D

The correct answer is:

Solution:

Topic: Chemistry, Carboxylic Acid Derivatives, NEET, NEET 2005
In a set of reactions, ethyl benzene yielded a product $D$.
' $D$ ' would be

Options:
A

B

C

D

The correct answer is:

Solution:
Key Idea Alkaline $\mathrm{KMnO}_4$ converts complete carbon chain that is directly attached to benzene nucleus, to $-\mathrm{COOH}$ group. $\mathrm{Br}_2$ in the presence of halogon carrier causes bromination and ethyl alcohol in acidic medium results in esterification.

Topic: Chemistry, Carboxylic Acid Derivatives, NEET, NEET 2010 (Screening)
In a set of reactions, ethyl benzene yielded a product D

Options:
A
B
C
D

The correct answer is:

Solution:

Topic: Chemistry, Hydrocarbons, NEET
In a set of reactions, $m$-bromobenzoic acid gave a product $D$. Identify the product $D$.

Options:
A

B

C

D

The correct answer is:

Solution:

Topic: Chemistry, Carboxylic Acid Derivatives, NEET, NEET 2011 (Screening)
In a set of reactions propionic acid yielded a compound 'd'.
\(\mathrm{CH}_2 \mathrm{CH}_2 \mathrm{COOH}\xrightarrow{\mathrm{SOCl}_2}{ }^{\prime} b^{\prime} \xrightarrow{\mathrm{NH}_3}{ }^{\prime} c^{\prime} \xrightarrow[\mathrm{Br}_2]{\mathrm{KOH}}{ }^{\prime} \mathrm{d}^{\prime}\)
The structure of 'd' would be:

Options:
A $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{NH}_2$
B $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{NH}_2$
C $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CONH}_2$
D $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{NHCH}_3$

The correct answer is:
$\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{NH}_2$

Solution:
Related Theory
When an amide is treated with bromine in an aqueous or ethanolic solution of sodium hydroxide, degradation of amide takes place leading to the formation of primary amine. This reaction is known as Hoffmann bromamide degradation reaction.

Topic: Chemistry, Amines, NEET, NEET 2006
In a set of the given reactions, acetic acid yielded a product ' $c$ '.
Product ' $c$ ' would be:

Options:
A $\mathrm{CH}_3 \mathrm{CH}(\mathrm{OH}) \mathrm{C}_2 \mathrm{H}_5$
B $\mathrm{CH}_3 \mathrm{COC}_6 \mathrm{H}_5$
C $\mathrm{CH}_3 \mathrm{CH}(\mathrm{OH}) \mathrm{C}_6 \mathrm{H}_5$
D

The correct answer is:

Solution:

Topic: Chemistry, Alcohols Phenols and Ethers, NEET, NEET 2003
In a setup where a conducting wire XY of mass m and negligible resistance slides smoothly on two parallel conducting wires as shown in Fig, a closed circuit with a resistance R due to AC is formed. AB and CD are perfect conductors. The magnetic field is Bk and is independent of time. If the initial velocity is v(0) = u0, determine the velocity v(t) of the wire XY as a function of time. Which of the following options represents the correct expression for v(t)?

Options:
A u0exp (–l2B2t/mR)
B u0exp (–2l2B2t/mR)
C u0exp (–lBt/mR)
D u0exp (–lB2t/mR)

The correct answer is:
u0exp (–l2B2t/mR)

Solution:
Correct Option is : (A)
u0exp (–l2B2t/mR)

Topic: Chemistry, Electromagnetic Induction, NEET
In a silicon crystal doped with 5 × 10²⁸ atoms/m³ of arsenic to form an 'n' type wafer, and 1 ppm concentration of boron is added on the surface to create a 'P' region, given that the intrinsic carrier concentration (ni) is 1.5 × 10¹⁶ m⁻³, what is the density of holes in the 'nh' region?

Options:
A 0.45 × 10¹⁶/m³
B 0.45 × 10²⁸/m³
C 0.45 × 1010/m³
D 0.45 × 10²¹/m³

The correct answer is:
0.45 × 1010/m³

Solution:
Correct Option is : (C)
0.45 × 1010/m³

Topic: Chemistry, Semiconductors, NEET
In a simple cubic unit cell, how many spheres are contained within the unit cell?

Options:
A 1
B 2
C 4
D 8

The correct answer is:
1

Solution:
In a simple cubic unit cell, there is only one sphere contained within the unit cell.

Topic: Chemistry, Solid State, NEET
In a simple pendulum, the breaking strength of the string is double the weight of the bob. The bob is released from rest when the string is horizontal. The string breaks when it makes an angle θ with the vertical

Options:
A θ=sin-1⁡13
B θ=60°
C Î¸=cos-1â¡23
D θ=0°

The correct answer is:
θ=cos-1⁡23

Solution:
Tâ Mg cosâ¡Î¸=Mv2r
Where T=2Mg and 12Mv2= Mg r cosâ¡Î¸
2 Mg-Mgcosâ¡Î¸=2 Mg rcosâ¡Î¸r
cosâ¡Î¸=23
Î¸=cos-1â¡23

Topic: Physics, Oscillations, NEET
In a single process of the Krebs Cycle, decarboxylation takes place in ________ steps.

Options:
A Five
B Four
C Three
D Two

The correct answer is:
Two

Solution:
Oxalosuccinate in Step 4 of the Krebs cycle undergoes decarboxylation. In the presence of oxalosuccinate decarboxylase enzyme, oxalosuccinate is changed into Î±-ketoglutarate.

In step 5 of Kreb's cycle -carbon compound, Î± â Ketoglutarate undergoes simultaneous dehydrogenation and decarboxylation in the presence of enzyme Î± â ketoglutarate dehydrogenase complex. This enzyme complex contains TPP, Lipoic Acid, Mg2+, and trans â succinylase. NAD+ and CoA are required. The products formed are 4 â carbon compound succinyl CoA, NADH2 and CO2.

Topic: Biology, Respiration in Plants, NEET