datavorous/entrance-exam-dataset huggingface dataset:
When a fresh-water protozoan possessing a contractile vacuole, is placed in a glass containing marine water, the vacuole will:

Options:
A increase in number
B disappear
C increase in size
D decrease in size.

The correct answer is:
disappear

Solution:
Contractile vacuole is involved in osmoregulation. When a cell is placed in marine water (hypertonic solution), the water inside the cell (vacuole) rushes out, disappearing the vacuole.

Topic: Biology, Transport in Plants, NEET, NEET 2004
When a gas-filled in a closed vessel is heated through 1 Â°C, its pressure increases by 0.4%. The initial temperature of the gas was

Options:
A 250 K

B 2500 K

C 250 °C
D 25 Â°C

The correct answer is:
250 K

Solution:
p1=p and T1=T ;
p2=p+0.4100p=1.004p ;T2=(T+1)
As p2p1=T2T1 â´ 1.004pp= T+1T=1+1T
Or T=10.004=250 K

Topic: Physics, Thermodynamics, NEET
When a glass capillary tube of the radius 0.015 cm is dipped in water, the water rises to a height of 15 cm within it. Assuming the contact angle between water and glass to be 0Â°, the surface tension of water is [Ïwater =1000 kg m-3, g=9.81 m s-2]

Options:
A 0.11 N m-1
B 0.7 N m-1
C 0.072 N m-1
D None of these

The correct answer is:
0.11 N m-1

Solution:
From capillary tube experiment, we know that
2ÏrÃT cosÎ¸=Ïr2hÏg
â T=rhÏg2=0.11 N m-1

Topic: Physics, Mechanical Properties of Fluids, NEET
When a heterozygous pea plant with yellow round seeds is crossed with a homozygous pea plant with yellow round seeds, the genotype not obtained is

Options:
A YyRr
B YyRR
C YYrr
D YYRR

The correct answer is:
YYrr

Solution:
Heterozygous pea plant genotype for yellow round seed - YyRr
Homozygous pea plant genotype for yellow round seed - YYRR
On crossing these, the possible genotypes are -
YYRR, YYRr, YyRR and YyRr.
YYrr genotype will not be obtained in this cross

Topic: Biology, Principles of Inheritance and Variation, NEET
When a hydrogen atom emits a photon in going transition from n=5 to n=1, its recoil speed is almost

Options:
A 10-4 m s-1
B 2Ã10-2 m s-1
C 4 m s-1
D 8Ã102 m s-1

The correct answer is:
4 m s-1

Solution:
1Î»=R1-125=24R25
Momentum is,
â´ P=hÎ»=24Rh25=6.9Ã10-27 kg m s-1
â´ v=Pm=6.9Ã10-271.6Ã10-27â4 m s-1

Topic: Physics, Atomic Physics, NEET
When a hydrogen atom is raised from ground energy level to excited energy level, then

Options:
A Potential energy increases and kinetic energy decreases
B Kinetic energy increases and potential energy decreases
C Both KE and PE increases
D Both KE and PE decreases

The correct answer is:
Potential energy increases and kinetic energy decreases

Solution:
As I increases, the potential energy increases. Thus, it decreases kinetic energy of hydrogen atom. So, when an atom jumps from one energy level to the higher level, its potential energy increases and kinetic energy decreases.

Topic: Physics, Atomic Physics, NEET
When a ketone reacts with a Grignard reagent, what type of bond forms between the carbon atoms of the two reactants?

Options:
A Single bond
B Double bond
C Triple bond
D Ionic bond

The correct answer is:
Single bond

Solution:
A single sigma (σ) bond forms between the carbon atoms.

Topic: Chemistry, Alcohols Phenols and Ethers, NEET
When a large amount of KMnO4 is added to concentrated H2SO4 , an explosive compound is formed. The formula of the compound is

Options:
A Mn2O7
B Mn3O4
C MnO3
D MnO3+

The correct answer is:
Mn2O7

Solution:
When a large amount of KMnO4 is added to concentrated H2SO4 , an explosive compound is formed. The formula of the compound is Mn2O7
2KMnO4+3H2SO4→Mn2O7+2K++H3O++3HSO4-

Topic: Chemistry, d and f Block Elements, NEET
When a laser beam returns after reflection from an aeroplane, the observed change in frequency is 1%, then the speed of the aeroplane is (c is the velocity of light)

Options:
A c50
B c100
C c200
D c2

The correct answer is:
c200

Solution:
We know that for change in frequency
Δff=2vc
⇒ 1100=2vc
⇒v=c200

Topic: Physics, Waves and Sound, NEET
When a lead storage battery is discharged, then

Options:
A SO2 is evolved
B lead is formed
C lead sulphate is consumed
D sulphuric acid is consumed

The correct answer is:
sulphuric acid is consumed

Solution:
The reaction occurring during operation (i.e., discharging) of battery are
Anode: Pb(s)+HSO4-+H2OâPbSO4(s)+2e+H3O+;EOPo=+0.356&nbspV
Cathode: PbO2(s)+HSO4-+3H2O++2eâPbSO4(s)+5H2O;ERPo=+1.685&nbspV
Net Charge: Pb(s)+2HSO4-+2H3O++PbO2(s)â2PbSO4(s)+4H2O;Eo=2.041&nbspV

Topic: Chemistry, Electrochemistry, NEET
When a long spring is stretched by $2 \mathrm{~cm}$, its potential energy is $U$. If the spring is stretched by $10 \mathrm{~cm}$, the potential energy stored it will be:

Options:
A $\frac{U}{5}$
B $5 U$
C $10 U$
D $25 U$

The correct answer is:
$25 U$

Solution:
$U=\frac{1}{2} K(2)^2$
$U^{\prime}=\frac{1}{2} K(10)^2$
From above equations
$U=25 \mathrm{~U}$

Topic: Physics, Work Power Energy, NEET, NEET 2003
When a magnet is suspended at an angle 30Â° from the magnetic meridian, it makes an angle 45o with horizontal. What will be the actual angle of dip?

Options:
A tan-1⁡32
B tan-1⁡3
C 45o
D 30o

The correct answer is:
tan-1⁡32

Solution:
tan-1â¡32
Given deviation from magnetic meridian Î±=30o and apparent dip Ï′=45Â°
Then, tanâ¡Ï′=tanâ¡Ïcosâ¡Î±
tanâ¡45o=tanâ¡Ïcosâ¡30o
Ï=tan-1â¡32

Topic: Physics, Magnetic Properties of Matter, NEET
When a man moves down an inclined plane with a constant speed of 5 m s-1, he finds that the rain is falling vertically downward. When he moves up the same inclined plane with the same speed, he finds that the rain makes an angle θ=tan-1⁡78 with the horizontal. If the angle of the inclined plane with the horizontal is 37°, the speed of the rain is

Options:
A 116 m s-1
B 32 m s-1
C 5 m s-1
D 73 m s-1

The correct answer is:
32 m s-1

Solution:
VâRm=VâR-Vâm
VâRm=Vxi^-Vyj^-4i^-3j^
Rain is falling vertically. Therefore,
when the man is going up
VâRm=VâR-Vâm=4i^-Vyj^--4i^+3j^
VâRm=8i^-Vy+3j^
Given,
tanâ¡Î¸=VyVx=Vy+38=78
Vy=4,VR=vx2+vy2=32 m s-1

Topic: Physics, Motion In Two Dimensions, NEET
When a mass is rotating in a plane about a fixed point, its angular momentum is directed along

Options:
A a line perpendicular to the plane of rotation
B the line making an angle of $45^{\circ}$ to the plane of rotation
C the radius
D the tangent to the orbit

The correct answer is:
a line perpendicular to the plane of rotation

Solution:
We knows $\mathbf{L}=m(\mathbf{r} \times \mathbf{v})$
So here, angular momentum is directed along a line perpendicular to the plane of rotation.

Topic: Physics, Rotational Motion, NEET, NEET 2012 (Screening)
When a material is inserted inside the inductor the current in the circuit increases, then the nature of the material is

Options:
A ferromagnetic
B paramagnetic
C diamagnetic
D all of the above

The correct answer is:
diamagnetic

Solution:
When a diamagnetic material is inserted into a coil, the value of permeability decreases, hence L decreases. Therefore Z=XL2+R2 decreases and as a result the current increases.

Topic: Physics, Magnetic Properties of Matter, NEET
When a mature mRNA was hybridized to its gene, certain loops were observed. These loops represent

Options:
A introns in DNA
B introns in rRNA
C exons in tRNA
D exons in DNA

The correct answer is:
introns in DNA

Solution:
Introns are non-coding regions of an RNA transcript, or the DNA encoding it, that are eliminated by splicing before translation. Introns are present in DNA, spliceosome complex forms during removal of introns.
The non-coding part is 98% of the total genome, functional mRNA has no introns, if it is made to hybridize with hnRNA then at certain stages the unpaired loops can be observed in the microscope.

Topic: Biology, Molecular Basis of Inheritance, NEET
When a metal of group 1 was dissolved in liquid ammonia, the following observations were obtained: (i) Blue solution was obtained initially. (ii) On concentrating the solution, blue colour changed to bronze colour. Which of the following best accounts for the blue colour of the solution?

Options:
A Formation of a metal-ammonia complex
B Formation of a metal oxide
C Formation of a metal nitride
D Formation of a metal chloride

The correct answer is:
Formation of a metal-ammonia complex

Solution:
Correct Option is : (A)
Formation of a metal-ammonia complex

Topic: Chemistry, s Block Elements, NEET
When a metallic surface is illuminated with monochromatic light of wavelength λ, stopping potential for photoelectric current is 3V0. When the same metallic surface is illuminated with a light of wavelength 2λ, the stopping potential is V0. The threshold wavelength for the surface is

Options:
A 6λ
B 4λ
C 4λ3
D 8λ

The correct answer is:
4λ

Solution:
3V0=hceÎ»-hceÎ»0 .....(1)
V0=hc2eÎ»-hceÎ»0 ......(2)
eqn1eqn2 â 3V0V0=hceÎ»-hceÎ»0hc2eÎ»-hceÎ»0
32hceÎ»-3hceÎ»0=hceÎ»-hceÎ»0
2Î»0=12Î»
Î»0=4Î»

Topic: Physics, Dual Nature of Matter, NEET
When a metallic surface is illuminated with monochromatic light of wavelength λ , the stopping potential is 5V0 . When the same surface is illuminated with light of wavelength 3λ , the stopping potential is V0 . Then the work function of the metallic surface is

Options:
A hc6λ
B hc5λ
C hc4λ
D 2hc4λ

The correct answer is:
hc6λ

Solution:
5eV0=hcλ-W ....(1)
eV0-hc3λ-W ....(2)
Solving equation (1) & (2)
hcλ-W=5hc3λ-5W
4W=2hc3λ
⇒ W=hc6λ

Topic: Physics, Dual Nature of Matter, NEET
When a metallic surface is illuminated with monochromatic light of wavelength λ, the stopping potential is 5V0. When the same surface is illuminated with light of wavelength 3λ, the stopping potential is V0. The work function of the metallic surface is

Options:
A hc6λ
B hc5λ
C hc3λ
D hc3λ

The correct answer is:
hc6λ

Solution:
e5V0=hcλ-ϕ
and, eV0=hc3λ-ϕ
⇒ϕ=hc6λ

Topic: Physics, Dual Nature of Matter, NEET
When a metallic surface is illuminated with radiation of wavelength λ, the stopping potential is V. If the same surface is illuminated with radiation of wavelength 2λ, the stopping potential is V4. The threshold wavelength for the metallic surface is:

Options:
A 4λ
B 5λ
C 52λ
D 3λ

The correct answer is:
3λ

Solution:
Given,

Stopping potential is V when the metal is illuminated with λ.

Stopping potential is V4 when the metal is illuminated with 2λ.

In photo electric effects
e V 0 = hν−W
eV0=hcλ-W
eV=hcλ-W ...(i)
eV4=hc2λ-W ....(ii)
From (i) and (ii)
hcλ-W=4hc2λ-W
hcλ-W=2hcλ-4W
3W=hcλ⇒W=hc3λ
hcλmax=hc3λ⇒λmax= threshold wavelength =3λ

Topic: Physics, Dual Nature of Matter, NEET, NEET 2016 (Phase 1)
When a metallic surface of threshold wavelength 4λ is illuminated with light of wavelength λ, the stopping potential is V. When the same surface is illuminated by the light of wavelength 2λ, stopping potential is V3. Threshold wavelength for the metallic surface is

Options:
A V2
B 2V
C V3
D 3V

The correct answer is:
V3

Solution:
When a metallic surface is illuminated with light of wavelength λ,
eV=hc1λ-14λ
eV=3hc4λ ..............(1)
When a metallic surface is illuminated with light of wavelength 2λ,
eV′=hc12λ-14λ
eV′=hc4λ .............(2)
V′V=13
V′=V3

Topic: Physics, Dual Nature of Matter, NEET
When a monochromatic light ray is incident on a medium of refractive index Î¼ with an angle of incidence Î¸i, the angle of refraction is Î¸r. If Î¸i is changed slightly by ÎÎ¸i, then the corresponding change in Î¸r will be

Options:
A Δ θ i
B μ Δ θ i
C 1 μ &CenterDot; cos θ l cos θ r &CenterDot; Δ θ i
D μ &CenterDot; cos θ l cos θ r &CenterDot; Δ θ i

The correct answer is:
1 μ &CenterDot; cos θ l cos θ r &CenterDot; Δ θ i

Solution:
μ = sin θ l sin θ r
sin θ r = 1 μ sin θ i
differentiate the equation with respect to θi.
cos θ r d θ r d θ i = 1 μ cos θ i
d θ r = 1 μ cos θ i cos θ r d θ i
Δ θ r = 1 μ cos θ i cos θ r Δ θ i

Topic: Physics, Ray Optics, NEET
When a monochromatic point source of light is at a distance 0.2 m from a photoelectric cell, the saturation current and cut-off voltage are 12.0 mA and 0.5 V. If the same source is placed 0.4 m away from the photoelectric cell, then the saturation current and the stopping potential respectively are

Options:
A 4 mA and 1 V

B 3 mA and 1 V

C 12 mA and 0.5 V

D 3 mA and 0.5 V

The correct answer is:
3 mA and 0.5 V

Solution:
The cut-off voltage or stopping potential measure maximum kinetic energy of the electron. It depends on the frequency of incident light whereas the current depends on the number of photons incident. Hence, cut-off voltage will be 0.5 V. Now by inverse square law,
12â10.22 or Iâ10.42
â´ I12=0.220.42=14
or I=124=3 mA

Topic: Physics, Dual Nature of Matter, NEET
When a mutational event leads to the replacement of one codon for another calling for the same amino acid, the resulting mutation is known as

Options:
A Frameshift
B Non-sense
C Missense
D Silent

The correct answer is:
Silent

Solution:
A silent mutation is a change in the sequence of nucleotide bases which constitutes DNA, without a subsequent change in the amino acid or the function of the overall protein. A silent mutation can be caused many ways, but the key point is that it does not change the function of the amino acid or subsequent proteins. Silent mutations are mutations in DNA that do not have an observable effect on the organism's phenotype.

Topic: Biology, Principles of Inheritance and Variation, NEET
When a neuron is an resting state, $i e$, not conducting any impulse, the axonal membrane is

Options:
A equally permeable to both $\mathrm{Na}^{+}$and $\mathrm{K}^{+}$ions
B impermeable to both $\mathrm{Na}^{+}$and $\mathrm{K}^{+}$ions
C comparatively more permeable to $\mathrm{K}^{+}$ions and nearly impermeable to $\mathrm{Na}^{+}$ions
D comparatively more permeable to $\mathrm{Na}^{+}$ions and nearly impermeable to $\mathrm{K}^{+}$ions

The correct answer is:
comparatively more permeable to $\mathrm{K}^{+}$ions and nearly impermeable to $\mathrm{Na}^{+}$ions

Solution:
Neurons are excitable cells because their membrane are in a polarised state. Different types of selectively permeable channels are present on the neural membrane. When a neuron is not conducting any impulse, ie, resting, the axonal membrane is comparatively more permeable to potassium ion $\left(\mathrm{K}^{+}\right)$and nearly impermeable to sodium ion $\left(\mathrm{Na}^{+}\right)$.

Topic: Biology, Neural Control and Coordination, NEET, NEET 2011 (Screening)
When a neuron is in resting state i.e., not conducting any impulse, the axonal membrane is:

Options:
A Comparatively more permeable to Na+ ions and nearly impermeable to K+ ions
B Equally permeable to both Na+ and K+ ions
C Impermeable to both Na+ and K+ ions
D Comparatively more permeable to K+ ions and nearly impermeable to Na+ ions

The correct answer is:
Comparatively more permeable to K+ ions and nearly impermeable to Na+ ions

Solution:
A neuron during resting state, i.e., when not conducting any impulse, the axonal membrane is comparatively more permeable to K+ ion and nearly impermeable to Na+ ions.

Topic: Biology, Neural Control and Coordination, NEET
When a nitrite ion attacks through the nitrogen atom, what type of compound is formed in a nucleophilic substitution reaction?

Options:
A Alkyl cyanide
B Alkyl nitrite
C Alkyl isocyanide
D Alkyl nitroalkane

The correct answer is:
Alkyl nitrite

Solution:
When the nitrite ion attacks through the nitrogen atom, it forms an alkyl nitrite.

Topic: Chemistry, Amines, NEET
When a oscillator completes 100 oscillations its amplitude reduces to $\frac{1}{3}$ of the initial value. What will be its amplitude when it completes 200 oscillations?

Options:
A $\frac{1}{8}$
B $\frac{2}{3}$
C $\frac{1}{6}$
D $\frac{1}{9}$

The correct answer is:
$\frac{1}{9}$

Solution:
Let $a_0$ be the initial amplitude and $b$ be the damping constant
The used formula is $a=a_0 e^{-b t}$
In Ist case : $t=100 T$ and $a=\frac{a_0}{3}$
$\therefore \frac{a_0}{3}=a_0 e^{-b(100 T)}$
$\begin{aligned}
& \Rightarrow e^{-b \times 100 T}=\frac{1}{3} \\
& \text {In 2nd case : } t=200 T \\
& a=a_0 e^{-200 b T} \\
& \Rightarrow a=a_0\left(e^{-100 b T}\right)^2 \\
& \Rightarrow a=a_0\left(\frac{1}{3}\right)^2 \\
& \Rightarrow a=\frac{a_0}{9}
\end{aligned}$

Topic: Physics, Oscillations, NEET, NEET 2002
When a particle moves in a circle with a uniform speed

Options:
A its velocity and acceleration are both constants
B its velocity is constant but the acceleration changes
C its acceleration is constant but the velocity changes
D its velocity and acceleration both change

The correct answer is:
its velocity and acceleration both change

Solution:
Speed is constant but the direction is changing continuously hence velocity is changing.
Acceleration is acting radially inward, hence acceleration is also changing.

Topic: Physics, Motion In Two Dimensions, NEET
When a phosphate group is linked to 5' OH of deoxyadenosine by phosphodiester linkage, a corresponding nucleotide is formed, which is

Options:
A Adenosine
B Adenylic acid
C Adenine
D Deoxyadenylic acid

The correct answer is:
Deoxyadenylic acid

Solution:
Nucleotide is a combination of nucleoside and phosphate group. When deoxyribose sugar attaches to adenine nucleoside, deoxyadenosine is formed. When phosphate attaches to 5' OH of deoxyadenosine, then a corresponding nucleotide called deoxyadenylic acid is formed.

Topic: Chemistry, Biomolecules, NEET
When a piece of metal is illuminated by a monochromatic light of wavelength λ, then stopping potential is 3Vs. When the same surface is illuminated by the light of wavelength 2λ, then stopping potential becomes Vs. The value of threshold wavelength for photoelectric emission will be

Options:
A 4λ
B 8λ
C 43λ
D 6λ

The correct answer is:
4λ

Solution:
According to Einstein's photoelectric equation eV=hc1Î»-1Î»0
Case I: 3eVs=hc1Î»-1Î»0 ...(i)
Case II: eVs=hc12Î»-1Î»0 ... (ii)
From the Eqs.(i) and (ii), we get
Î»0=4Î»

Topic: Physics, Dual Nature of Matter, NEET
When a positively charged particle is projected with a velocity v0 in the region between the horizontal plates of the capacitor then it leaves by making an angle Î¸ with the horizontal, as shown. If Î¸=Î¸1 is for proton and Î¸=Î¸2 for an Î±-particle then the value of tanâ¡Î¸1tanâ¡Î¸2 is

Options:
A 1
B 2
C 2
D 12

The correct answer is:
2

Solution:
tan⁡θ=VyVx
⇒tan⁡θ ∝qm
⇒tan⁡θ1tan⁡θ2=2

Topic: Physics, Electrostatics, NEET
When a proton is released from rest in a room, it starts with an initial acceleration $a_0$ towards west. When it is projected towards north with a speed $v_0$ it moves with an initial acceleration $3 a_0$ towards west. The electric and magnetic fields in the room are

Options:
A $\frac{m a_0}{e}$ west, $\frac{2 m a_0}{e v_0}$ up
B $\frac{m a_0}{e}$ west, $\frac{2 m a_0}{e v_0}$ down
C $\frac{m a_0}{e}$ east, $\frac{3 m a_0}{e v_0}$ up
D $\frac{m a_0}{e}$ east $\frac{3 m a_0}{e v_0}$ down

The correct answer is:
$\frac{m a_0}{e}$ west, $\frac{2 m a_0}{e v_0}$ down

Solution:
Initial acceleration, $a_0=\frac{\partial E}{m}$
$\begin{aligned} & \Rightarrow \quad E=\frac{a_0 m}{e} \therefore \frac{e v_0 B+e E}{m}=3 a_0 \\ & \text { or } \quad e v_0 B+e E=3 a_0 m \\ & \therefore \quad e v_0 B=3 m a_0-e E \\ & \Rightarrow \quad=3 m a_0-m a_0 \quad[\text { fromeq. (i)] } \\ & \Rightarrow \quad e v_0 B=2 m a_0 \\ & \therefore \quad B=\frac{2 m a_0}{e v_0} \\ & \end{aligned}$

Topic: Physics, Magnetic Effects of Current, NEET, NEET 2013 (All India)
When a radioactive isotope 88R228decay in series by the emission of 3Î±-particles and Î²-particle, the isotope finally formed is

Options:
A 84X228
B 86X222
C 83X216
D 83X215

The correct answer is:
83X216

Solution:
Decrease in mass number due to emission of 3α-particles
and a β-particle=3×4=12
Decrease in charge number in the process
=3×2-1=5
∴ For the resulting element,
A=228-12=216
Z=88-5=83

Topic: Physics, Nuclear Physics, NEET
When a ray is refracted from one medium into another medium, the wavelength changes from 6000 â« to 4000 â« . The critical angle for a ray from second medium will be

Options:
A cos-1⁡23
B sin-1⁡23
C tan-1⁡32
D sin-1⁡213

The correct answer is:
sin-1⁡23

Solution:
sin⁡C=μRμD=λDλR=40006000=23

Topic: Physics, Ray Optics, NEET
When a resistor of 11 Î© is connected in series with an electric cell in series, the current increases by 0.4 A. The internal resistance of the cell is

Options:
A 1.5 Ω
B 2 Ω
C 2.5 Ω
D 3.5 Ω

The correct answer is:
2.5 Ω

Solution:
i=ER+r
0.5=E11+r
E=5.5+0.5r
0.9=E5+r
E=4.5+0.9r
On solving these equation, r=2.5 Ω

Topic: Physics, Current Electricity, NEET
When a silicon p-n junction is in forward biased condition with a series resistance, it has a knee voltage of 0.6 V. If 5 mA of current flows in it when the p-n junction is connected with a 2.6 V battery, the value of the series resistance is

Options:
A 100Â Î©
B 200Â Î©
C 400 Î©
D 500Â Î©

The correct answer is:
400 Î©

Solution:
R=2.6-0.65Ã10-3=400 Î©

Topic: Physics, Semiconductors, NEET
When a single gene expresses more than one effect, the phenomenon is called

Options:
A multiple allelism.
B two gene inheritance.
C pleiotropy.
D polygenes.

The correct answer is:
pleiotropy.

Solution:
Single gene affecting the different characters which may be physiologically unrelated. Pleiotropic gene has a multiple phenotypic effect because it can control expression of a number of characters. Example, Sickle cell anaemia, cystic fibrosis, Morphan syndrome.

Topic: Biology, Principles of Inheritance and Variation, NEET
When a small amount of HCl is added to an aqueous solution of BiCl3 , a white precipitate is formed. This is due to formation of

Options:
A Bi(OH)3
B Bi2O3
C BiOCl
D None of the above

The correct answer is:
BiOCl

Solution:
BiCl3 , being the salt of a strong acid and weak base, undergoes partial hydrolysis under weakly acidic conditions to give a white precipitate of BiOCl, which dissolves in the excess of the acid.
BiCl3+3HOH→BiOCl(ppt.)+2HCl
BiOCl+2HCl→BiCl3+H2O

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), NEET
When a sound wave of frequency 300 Hz passes through a medium the maximum displacement of a particle of the medium is 0.1 cm. The maximum velocity of the particle is equal to

Options:
A 60Ï cm s-1
B 30Ï cm s-1
C 30 cm s-1
D 60 cm s-1

The correct answer is:
60Ï cm s-1

Solution:
vmax=aÏ
vmax=aÃ2Ïf
vmax=0.12ÏÃ300
vmax=60Ï cm s-1

Topic: Physics, Waves and Sound, NEET
When a source of frequency f0 moves away from a stationary observer with a certain velocity, an apparent frequency f' is observed. When it moves with the same speed towards the observer, the observed frequency is 1.2f'. If the velocity of sound is v, then the actual frequency f0 is

Options:
A 1211f′
B 1112f′
C 76f′
D 67f′

The correct answer is:
1211f′

Solution:
When source moves away from a stationary observer f′=f0vv+u
When source moves with the same speed towards the observer 1.2f′=f0vv-u
â´Â Â u=v11
â´Â Â Â f0=f′1+uv=1211f′

Topic: Physics, Waves and Sound, NEET
When a sulphur sol is evaporated sulphur is obtained. On mixing with water sulphur sol is not formed. The sol is

Options:
A Lyophilic
B Reversible
C Hydrophobic
D Hydrophilic

The correct answer is:
Hydrophobic

Solution:
Hydrophobic sol are irreversible in nature. They have no affinity between the dispersed phase and the dispersion medium (H2O). Further once precipitated, they do not form the colloidal sol by simple addition of water.

Topic: Chemistry, Surface Chemistry, NEET
When a tall pea plant with round seeds was selfed, it produced the progeny of :
(a) Tall plants with round seeds and
(b) Tall plants with wrinkled seeds.
Identify the genotype of the parent plant.

Options:
A TtRr
B TtRR
C TTRR
D TTRr

The correct answer is:
TTRr

Solution:
As per the type of given progeny the genotype of the parent will be TTRr.
Selfing $=\stackrel{\text { 우 }}{\mathrm{T}} \mathrm{Rr} \times \stackrel{\text { ₪ }}{\mathrm{T}} \mathrm{Rr}$
According to the above cross progeny will be Tall round and Tall wrinkle.

Topic: Biology, Principles of Inheritance and Variation, NEET, NEET 2024 (Re-NEET)