datavorous/entrance-exam-dataset huggingface dataset:
The cross that leads to the production of the hinny is

Options:
A Male donkey X Female horse
B Female donkey X Male horse
C Stallion X Female donkey
D Stallion X Mare

The correct answer is:
Female donkey X Male horse

Solution:
Mule is a sterile hybrid produced from mating between Male donkey and Female horse(mare) .
Hinny is another sterile hybrid produced from mating between Male horse (stallion) and female donkey.

Topic: Biology, Strategies for Enhancement in Food Production, NEET
The cross-section of a plant material showed the following features when viewed under the microscope. I. The vascular bundles were radially arranged. II. Four xylem strands with exarch condition of protoxylem. To which organ should it be assigned?

Options:
A Leaves
B Monocot Stem
C Dicot Root
D Monocot Root

The correct answer is:
Monocot Root

Solution:
In Dicot roots, vascular bundles are radially arranged along with four xylem strands with exarch condition of protoxylem.

Topic: Biology, Anatomy of Flowering Plants, NEET
The crucial requirement for the process of chemiosmosis is

Options:
A Membrane
B Proton pump
C Proton gradient
D None of these

The correct answer is:
Proton gradient

Solution:
Chemiosmosis requires a membrane, a proton pump, a proton gradient and ATPase. Energy is used to pump protons across the membrane to create a gradient or a high concentration of protons within the thylakoid lumen. However, the most essential requirement is the creation of a proton gradient across the membrane.

Topic: Biology, Respiration in Plants, NEET
The Crystal Field Stabilisation Energy (CFSE) for $\left[\mathrm{CoCl}_6\right]^{4-}$ is $18000 \mathrm{~cm}^{-1}$. The CFSE for $\left[\mathrm{CoCl}_4\right]^{2-}$ will be

Options:
A $6000 \mathrm{~cm}^{-1}$
B $16000 \mathrm{~cm}^{-1}$
C $18000 \mathrm{~cm}^{-1}$
D $8000 \mathrm{~cm}^{-1}$

The correct answer is:
$8000 \mathrm{~cm}^{-1}$

Solution:

Topic: Chemistry, Coordination Compounds, NEET, NEET 2019 (Odisha)
The crystal system having the highest and the lowest symmetrises respectively, are

Options:
A cubic and rhombohedral
B cubic and triclinic
C rhombohedral and monoclinic
D cubic and monoclinic

The correct answer is:
cubic and triclinic

Solution:
The crystal system having the highest and the lowest symmetrises respectively, are cubic and triclinic.
Cubic → Most symmetrical (a = b = c, α=β=γ=90° )
Triclinic → Least symmetrical ( a≠b≠c,α≠β≠γ≠90° )

Topic: Chemistry, Solid State, NEET
The crystal system of a compound with unit cell dimensions a = 0.387, b = 0.387 and c = 0.504 nm and α=β=90o and γ=120o is

Options:
A Hexagonal
B Cubic
C Rhombohedral
D Orthorhombic

The correct answer is:
Hexagonal

Solution:
For the given crystal,
a=b≠c,α=β=90o,γ=120o
These are the characteristic of a hexagonal system.

Topic: Chemistry, Solid State, NEET
The crystal system of a compound with unit cell dimensions a = 0.388, b = 0.388 and c = 0.506 nm and α=β=90o and γ=120o is

Options:
A Hexagonal
B Cubic
C Rhombohedral
D Orthorhombic

The correct answer is:
Hexagonal

Solution:
For the given crystal,
a=b≠c,α=β=90o,γ=120o
These are the characteristic of a hexagonal system.

Topic: Chemistry, Solid State, NEET
The crystalline compound AxBy is characterized by a body-centred cell. The compound has the formula

Options:
A AB
B A4B
C A8B
D AB4

The correct answer is:
AB

Solution:
Number of atoms of A per unit cell
=8×18=1
and number of atoms of B per unit cell = 1
So the formula of the compound = AB.

Topic: Chemistry, Solid State, NEET
The crystals of ferrous sulphate on heating give

Options:
A FeO+SO2+H2O
B Fe2O3+H2SO4+H2O
C Fe2O3+SO2+SO3
D FeO+SO3+H2SO4+H2O

The correct answer is:
Fe2O3+SO2+SO3

Solution:
FeSO4.7H2O→ΔFeSO4+7H2O
2FeSO4→ΔFe2O3+SO2+SO3 .

Topic: Chemistry, d and f Block Elements, NEET
The crystals of virus obtained by Stanley were made up of

Options:
A Largely proteins
B Cholesterol
C Sterol
D Polysaccharide

The correct answer is:
Largely proteins

Solution:
W.M. Stanley showed that viruses could be crystallized and crystals consist largely of proteins. They are inert outside their specific host cell. Viruses are obligate parasites.

Topic: Biology, Biological Classification, NEET
The current flowing in 3 Î© resistance will be

Options:
A 83 A
B 38 A
C 18 A
D 58 A

The correct answer is:
83 A

Solution:
i=121+2=4 A
â´ current in 3 Î© is =63+6Ã4=83 A

Topic: Physics, Current Electricity, NEET
The current gain for a transistor used in common-emitter configuration is 98 . If the load resistance be 1 MÎ© and the internal resistance be 600Î©, What is the voltage gain?

Options:
A 90
B 95
C 100
D none

The correct answer is:
none

Solution:
A=βRLRL+Ri
A=98×106106+600
A=98

Topic: Physics, Semiconductors, NEET
The current gain α of a transistor in common base mode is 0.995. Its gain β in the common emitter mode is

Options:
A 200
B 99
C 199
D None of these

The correct answer is:
199

Solution:
The current gain α of a transistor in common base mode is 0.995β is current gain in the common emitter mode β=α1-α=0.9951-0.995=199

Topic: Physics, Semiconductors, NEET
The current graph for resonance in LC circuit is

Options:
A
B
C
D

The correct answer is:

Solution:
In LC circuit, if XL=XC then Ï=1 LC
I0=â, so Z=E0I0=0, As 1 LC is the natural frequency of Lc circuit, therefore for an LC circuit if the frequency of applied AC becomes equal to the natural frequency of an AC circuit. then the amplitude of current becomes infinite due to zero impedance.

Topic: Physics, Alternating Current, NEET
The current $i$ in a coil varies with time as shown in the figure. The variation of induced emf with time would be

Options:
A

B

C

D

The correct answer is:

Solution:
We know
$$
e=-L \frac{d i}{d t}
$$
During 0 to $\frac{T}{4}, \frac{d i}{d t}=$ constant
So, $\quad e=-$ ve
For $\quad \frac{T}{4}$ to $\frac{T}{2}, \frac{d i}{d t}=0$
$$
e=0
$$
For $\frac{T}{2}$ to $\frac{3 T}{4}, \frac{d i}{d t}=$ constant
$$
e=+ \text { ve }
$$

Topic: Physics, Electromagnetic Induction, NEET, NEET 2011 (Screening)
The current I in the given circuit is

Options:
A 1.6 A

B 2.0 A

C 0.32 A

D 3.2 A

The correct answer is:
2.0 A

Solution:
the equivalent resistance of the circuit
R = 3 × 1 2 3 + 1 2 = 3 6 1 5 = 1 2 5 Ω
∴ Current in circuit, I = V R
=4·8125=4·8×512=2 A

Topic: Physics, Current Electricity, NEET
The current $(I)$ in the inductance is varying with time according to the plot shown in figure.
Which one of the following is the correct variation of voltage with time in the coil?

Options:
A

B

C

D

The correct answer is:

Solution:
For inductor as we know induced voltage For $t=0$ to $t=T / 2$
$V=L \frac{d I}{d t}=L \frac{d}{d t}\left(\frac{2 I_0 t}{T}\right)=\text { constant, }$
For
$\begin{aligned}
t & =T / 2 \text { to } t=T \\
V & =\frac{L d I}{d t}\left(\frac{-2 I_0 t}{T}\right)=- \text { constant }
\end{aligned}$
Therefore, answer will represents by graph (d).

Topic: Physics, Alternating Current, NEET, NEET 2012 (Screening)
The current in a coil of L=40 mH is to be increased uniformly from 1 A to 11 A in 4 milliseconds. The induced e.m.f. will be

Options:
A 100 V
B 0.4 V
C 440 V
D 40 V

The correct answer is:
100 V

Solution:
e=LdIdt=40×10−3(11−1)4×10−3=100 V

Topic: Physics, Electromagnetic Induction, NEET
The current in an LCR circuit is given by I=20sinâ¡100Ït+Ï3 A. The voltage across the inductance L of 0.1 H at t=0 will be

Options:
A 31.4 V
B 3.14 V
C 157 V
D 314 V

The correct answer is:
314 V

Solution:
V=20Ã100ÏÃ0.1sinâ¡100Ït+5Ï6
V=200Ïsinâ¡5Ï6
V=314 V

Topic: Physics, Alternating Current, NEET
The current needed to reduce 26.6 g of nitrobenzene to aniline in acidic medium, is

Options:
A 0.4 F
B 0.6 F
C 0.8 F
D 1.2 F

The correct answer is:
1.2 F

Solution:
No. of gram equivalent = No. of Faraday
mole x n-factor = No. of Farady
0.2×6=1.2 F

Topic: Chemistry, Electrochemistry, NEET
The current through the ideal P-N junction shown in the following circuit diagram will be

Options:
A zero
B 1 mA
C 10 mA
D 30 mA

The correct answer is:
zero

Solution:
The diode is in reverse biasing so current through it will be zero.

Topic: Physics, Semiconductors, NEET
The current through the solenoid is changing in such way that flux through it is given by ϕ = ε t . The solenoid is surrounded by a loop having resistance R 1 and R 2 as shown. Then the reading of the two voltmeters V1 and V2 differ by :

Options:
A Zero
B ε
C Îµ R 1 - R 2 R 1 + R 2
D ε R 1 R 2 R 1 + R 2

The correct answer is:
ε R 1 - R 2 R 1 + R 2

Solution:
i = 2 Îµ 1 + 2 Îµ 2 R 1 + R 2 = Îµ R 1 + R 2
Where Îµ = d Ï dt is the net emf in the circuit
â´ V 1 - V 2 = Îµ 1 - iR 1 - Îµ 1 - iR 2 = Îµ R 2 - R 1 R 1 + R 2

Topic: Physics, Electromagnetic Induction, NEET
The currents through diodes D1 and D2 are

Options:
A i1=0.1Â A,Â i2=0.1Â A
B i1=0.1 A, i2=0
C i1=0,Â i2=0.3Â A
D i1=0,Â i2=0

The correct answer is:
i1=0.1 A, i2=0

Solution:
Through D2 , i2=0 due to reverse biasing of diode.
Through D1 , i1=550=0.1 A .

Topic: Physics, Semiconductors, NEET
The curve given below shows enzymatic activity in relation to two conditions (pH and temperature). What does the two-axis (X and Y) represent?

Options:
A

X- axis	Y-axis

Temperature	Enzyme activity

B

X- axis	Y-axis

Enzymatic activity	pH

C

X- axis	Y-axis
Enzymatic activity	Temperature

D More than one option is correct

The correct answer is:

X- axis	Y-axis

Temperature	Enzyme activity

Solution:
Enzyme activity depends on three factors: Temperature, pH and substrate concentration. When graph is plotted to show the effect of these factors on enzyme activity bell curve is obtained in case of temperature and pH while sigmoid curve is obtained with respect to substrate concentration. Bell curve shows that enzyme activity is maximum at the mean value of temperature and pH and there is no activity seen at values lower and higher than the mean value. When these graphs are plotted X-axis shows temperature or pH and Y-axis shows enzyme activity.

Topic: Chemistry, Biomolecules, NEET
The curve given below shows enzymatic activity with relation to three conditions ( $\mathrm{pH}$, temperature and substrate concentration) What do the two axises ( $X$ and $Y$ ) represent?

Options:
A (a)
B (b)
C (c)
D (d)

The correct answer is:
(a)

Solution:
X-axis represent temperature and Y-axis represent enzyme activity. All enzyme act at an optimum temperature, above and below this temperature, the enzyme activity declines.

Topic: Biology, Biomolecules (B), NEET, NEET 2011 (Screening)
The curve given below shows enzymatic activity with relation to three conditions (pH, temperature and substrate concentration). What does the two axis (x and y) represent?

Options:
A X-axis: Enzymatic activity, Y-axis: pH
B X-axis: Temperature, Y-axis: Enzyme activity
C X-axis: Substrate concentration, Y-axis: Enzymatic activity
D X-axis: Enzymatic activity, Y-axis: Temperature

The correct answer is:
X-axis: Temperature, Y-axis: Enzyme activity

Solution:
In the given curve the temperature and enzyme activity relation is shown. Enzymes generally function in a narrow range of temperatures. Each enzyme shows its highest activity at a particular temperature called the optimum temperature. Activity declines both below and above the optimum value. Low temperature preserves the enzyme in a temporarily inactive state whereas high temperature destroys enzymatic activity because proteins are denatured by heat.

Topic: Chemistry, Biomolecules, NEET
The curve of binding energy per nucleon as a function of an atomic mass number has a sharp peak for the helium nucleus. This implies that helium

Options:
A Can easily be broken up
B Is very stable
C Can be used as fissionable material
D Is radioactive

The correct answer is:
Is very stable

Solution:
In order to compare the stability of the nuclei of different atoms we determine the binding energy per nucleon. Higher the binding energy per nucleon, more stable is the nucleus. A graph between energy per nucleon and the mass number of nuclei is called the binding energy curve. It gives the following information that of two or more very light nuclei (nucleus of heavy hydrogen 1H2 fuse into a relatively heavier nucleus ( 2He4), then binding energy will increase showing that helium is stable.

Topic: Physics, Nuclear Physics, NEET
The cut flowers and vegetables are kept fresh for a long period by which of the following plant hormone?

Options:
A Auxin
B Gibberellin
C Cytokinin
D Ethylene

The correct answer is:
Cytokinin

Solution:
Cytokinin is a growth promoter and delays the process of senescence by promoting nutrient mobilization. This delay in senescence by cytokinin is also called as Richmond lang effect.

Topic: Biology, Plant - Growth and Development, NEET
The cut flowers and vegetables can be kept fresh for a long period with the help of:

Options:
A Cytokinin
B Ethylene
C Auxin
D Gibberellin

The correct answer is:
Cytokinin

Solution:
Cytokinin is a growth promoter and delays the process of senescence by promoting nutrient mobilization. This delay in senescence by cytokinin is also called as Richmond Lang effect.

Topic: Biology, Plant - Growth and Development, NEET
The cutting of DNA at a specific location became possible with the discovery of:

Options:
A Probes
B Selectable markers
C Ligases
D Restriction enzymes

The correct answer is:
Restriction enzymes

Solution:
The cutting of DNA at specific locations became possible with the discovery of restriction enzymes which are also called as molecular scissors or knife.

Restriction enzymes recognize dsDNA nucleotides as target sequences called restriction sites and cut the DNA at or near those sequences. Restriction enzymes bind to double-stranded DNA and cleave it at specific sites. Different restriction sites recognize different sequences. Type II restriction enzymes recognize palindromic sequences: four, five, or six base pairs in length. To date, more than 900 other restriction enzymes have been discovered from 230 strains of bacteria.

Topic: Biology, Biotechnology - Principles and Processes, NEET, NEET 2015 (Phase 2)
The cyanobacteria are also referred to as

Options:
A protists
B golden algae
C slime moulds
D blue-green algae

The correct answer is:
blue-green algae

Solution:
Cyanobacteria, also known as blue-green algae (BGA) are most primitive prokaryotic organisms. These are considered to be the most ancient of all the chlorophyll bearing organisms on Earth.

Topic: Biology, Biological Classification, NEET, NEET 2012 (Screening)
The cyclotron frequency of an electron moving in a magnetic field of 1 T is approximately (assume no relativistic effect)

Options:
A 28 MHz

B 280 MHz

C 2.8 GHz

D 28 GHz

The correct answer is:
28 GHz

Solution:
Cyclotron frequency,f= eB 2Ïm âââââââââââââââââââââââââââââââââ= 1.6Ã 10 â19 Ã1 2Ã3.14Ã9.1Ã 10 â31 âââââââââââââââââââââââââââââââââ=28âGHz

Topic: Physics, Magnetic Effects of Current, NEET
The cyclotron frequency of an electron moving in a magnetic field of 1 T is approximately (assume no relativistic effect)

Options:
A 28 MHz
B 280 MHz
C 2.8 GHz
D 28 GHz

The correct answer is:
28 GHz

Solution:
Cyclotron frequency,f= eB 2Ïm âââââââââââââââââââââââââââââââââ= 1.6Ã 10 â19 Ã1 2Ã3.14Ã9.1Ã 10 â31 âââââââââââââââââââââââââââââââââ=28âGHz

Topic: Physics, Magnetic Effects of Current, NEET
The cylinder contains 100 gm of an ideal gas mol. wt.=40 gm/mol at 27Â°C and 2 atm. pressure. In transportation the cylinder fell and a dent was created. The valve present cannot keep the pressure greater than 2 atm. Hence 10 gm of a gas got leaked out. The volume of the container before and after dent is-

Options:
A 30.8 L ; 27.7 L
B 27.7 L ; 30.8 L
C 30.8 L ; 30.8 L
D 27.7 L ; 27.7 L

The correct answer is:
30.8 L ; 27.7 L

Solution:
Before dent vol. of gas=nRTP
=10040 × 0.082×3002=30.75 L
After dent vol. of gas=nRTP
=9040 × 0.082×3002=27.675 L

Topic: Chemistry, States of Matter, NEET
The cylindrical tube of a spray pump has a cross-section of 8 cm2, one end of which has 40 fine holes each of area 10-8 m2. If liquid flows inside the tube with a speed of 0.15 m min-1, the speed with which the liquid is ejected through the hole is

Options:
A 50 m s-1
B 5 m s-1
C 0.05 m s-1
D 0.5 m s-1

The correct answer is:
5 m s-1

Solution:
According to equation of continuity,
av=constant
â´ For tube, 8Ã10-4Ã0.1560=a1v1
For holes 40Ã10-8Ãv=a2v2
â´ a1v1=a2v2
â´ 40Ã10-8Ãv=8Ã10-4Ã0.1560
â¹ v=8Ã10-4Ã0.1540Ã10-8Ã60=5 m s-1

Topic: Physics, Mechanical Properties of Fluids, NEET
The cylindrical tube of a spray pump has radius R , one end of which has n fine holes, each of radius r . If the speed of the liquid in the tube is V , the speed of the ejection of the liquid through the holes is :

Options:
A VR2nr2
B VR2n3r2
C V2Rnr
D VR2n2r2

The correct answer is:
VR2nr2

Solution:
Volume inflow rate = volume an flow rate
πR2V=nπr2 ⇒ v= πR2Vnπr2= VR2nr2

Topic: Physics, Mechanical Properties of Fluids, NEET, NEET 2015 (Phase 2)
The cytoskeletal elements are involved in:

(i) Amoeboid movement
(ii) Separation of chromosomes
(iii) Ciliary movement
(iv) Formation of cell plate

Options:
A i,ii and iv
B i, ii and iii
C ii, iii and iv
D i, ii iii and iv

The correct answer is:
i, ii iii and iv

Solution:
Cell movement; is both internal, referred to as cytoplasmic streaming, and external, referred to as motility. Internal movements of organelles are governed by actin filaments and other components of the cytoskeleton. These filaments make an area in which organelles such as chloroplasts can move. Internal movement is known as cytoplasmic streaming. External movement of cells is determined by special organelles for locomotion. These could be pseudopodia, cilia and flagella.
The cytoskeletal elements are required for the delivery of vesicles to the equatorial region of the cell and provide guidance to the cell plate. Vesicles, originating from the Golgi apparatus, travel along microtubules and fuse in a unique manner at the center of the phragmoplast to give rise to the new plasma membranes of the two daughter cells. The cargo they carry contributes to the cell-plate matrix.

Topic: Biology, Cell - The Unit of Life, NEET
The $d$ electron configuration of $\mathrm{Cr}^{2+}$, $\mathrm{Mn}^{2+}, \mathrm{Fe}^{2+}$ and $\mathrm{Ni}^{2+}$ are $3 \mathrm{~d}^4, 3 \mathrm{~d}^5, 3 \mathrm{~d}^6$ and $3 \mathrm{~d}^8$ respectively. Which one of the following aqua complexes will exhibit the minimum paramagnetic behaviour?
(At. No. $\mathrm{Cr}=24, \mathrm{Mn}=25, \mathrm{Fe}=26, \mathrm{Ni}=$ 28)

Options:
A $\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}$
B $\left[\mathrm{Ni}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}$
C $\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}$
D $\left[\mathrm{Mn}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}$

The correct answer is:
$\left[\mathrm{Ni}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}$

Solution:
$\begin{aligned}
& \mathrm{Cr}^{++}\left(3 \mathrm{~d}^4\right)=\begin{array}{|l|l|l|l|l|}
\hline 1 & 1 & 1 & 1 & \\
\hline
\end{array} \\
& =4 \text { unpaired } e^{-} \\
& \operatorname{Mn}^{++}\left(3 \mathrm{~d}^4\right)=\begin{array}{|l|l|l|l|l|}
\hline 1 & 1 & 1 & 1 & 1 \\
\hline
\end{array} \\
& =5 \text { unpaired } e^{-} \\
& \mathrm{Fe}^{++}\left(3 \mathrm{~d}^6\right)=\begin{array}{|l|l|l|l|l|}
\hline \text { 1L } & 1 & 1 & 1 & 1 \\
\hline
\end{array} \\
& =4 \text { unpaired } e^{-} \\
& \mathrm{Ni}^{++}\left(3 \mathrm{~d}^8\right)=\begin{array}{|l|l|l|l|l|}
\hline \text { 1h } & \text { 1L } & \text { IL } & 1 & 1 \\
\hline
\end{array} \\
& =2 \text { unpaired } e^{-} \\
&
\end{aligned}$
As $\mathrm{Ni}^{++}$ has minimum no. of unpaired $e^{-}$ thus this is least paramagnetic.

Topic: Chemistry, Coordination Compounds, NEET, NEET 2007
The α-D- glucose and β-D- glucose differ from each other at one of the carbon atom due to difference in

Options:
A Conformation
B Number of OH groups
C Size of hemiacetal ring
D Configuration

The correct answer is:
Configuration

Solution:

Topic: Chemistry, Biomolecules, NEET
The damping force on an oscillator is directly proportional to the velocity. The units of the constant of proportionality are

Options:
A $\mathrm{kg} \mathrm{ms}^{-1}$
B $\mathrm{kg} \mathrm{ms}^{-2}$
C $\mathrm{kg} \mathrm{s}^{-1}$
D $\mathrm{kg} \mathrm{s}$

The correct answer is:
$\mathrm{kg} \mathrm{s}^{-1}$

Solution:
Given, Damping force $\propto$ velocity
$\begin{aligned}
& F \propto y \\
& F=k v \\
& k=\frac{F}{v}
\end{aligned}$
$\begin{aligned}
\text {Unit of } k & =\frac{\text { unit of } F}{\text { unit of } v} \\
& =\frac{\mathrm{kg}-\mathrm{ms}^{-2}}{\mathrm{~ms}^{-1}}=\mathrm{kgs}^{-1}
\end{aligned}$

Topic: Physics, Units and Dimensions, NEET, NEET 2012 (Screening)
The de Broglie wavelength associated with an electron, accelerated by a potential difference of $81 \mathrm{~V}$ is given by:

Options:
A $1.36 \mathrm{~nm}$
B $0.136 \mathrm{~nm}$
C $13.6 \mathrm{~nm}$
D $136 \mathrm{~nm}$

The correct answer is:
$0.136 \mathrm{~nm}$

Solution:
We know, for an electron
De Broglie wavelength, $\lambda=\frac{12.27}{\sqrt{v}} Å$
$\begin{aligned} & \lambda=\frac{12.27}{\sqrt{81}}=\frac{12.27}{9} Å \\ & \lambda=1.36 Å \text { or } 0.136 \mathrm{~nm}\end{aligned}$

Topic: Physics, Dual Nature of Matter, NEET, NEET 2023 (Manipur)
The de Broglie wavelength of a bullet of mass 0.040 kg, travelling at a speed of 1.0 km s-1 is

Options:
A 1.66Ã10-34 m
B 1.66Ã10-35 m
C 1.66×10-32 m
D 1.66×10-33 m

The correct answer is:
1.66Ã10-35 m

Solution:
Given: mass of bullet, m=0.040 kg and speed of bullet, v=1000 m s-1
de - Broglie wavelength,
Î»=hmv=6.63Ã10-340.040Ã1Ã103 âµ m=0.040 kgv=1 km s -1=1000 m s-1
=1.66Ã10-35 m.

Topic: Physics, Dual Nature of Matter, NEET
The de Broglie wavelength of a dust particle of mass 1.0Ã10-9 kg drifting with a speed of 2.2 m s-1 is

Options:
A 3.0×10-25 m

B 1.0Ã10-25 m
C 3.0Ã1025 m
D 1.0Ã1025 m

The correct answer is:
3.0×10-25 m

Solution:
Given, Mass of a dust particle, m=1×10-9 kg and speed of the dust particle, v= 2.2 m s-1
λ = h mv = 6 . 6 3 × 1 0 - 3 4 1 × 1 0 - 9 × 2 . 2
=3.0×10-25 m.

Topic: Physics, Dual Nature of Matter, NEET
The de Broglie wavelength of an electron in the 3rd Bohr orbit is

Options:
A 2πa0
B 4πa0
C 6πa0
D 8πa0

The correct answer is:
6πa0

Solution:
We know
2πr=nλ
n=3
and r=a0n2Z
2πa0n2Z=nλ
2π32a01=3λ
λ=6πa0

Topic: Chemistry, Structure of Atom, NEET
The de-Broglie wavelength L associated with an elementary particle of linear momentum p is best represented by the graph

Options:
A
B
C
D

The correct answer is:

Solution:
Wavelength is inversely proportional to momentum.
Î»=hp or L=hp i.e., Lâ1p. The curve (d) is correct.

Topic: Physics, Dual Nature of Matter, NEET
The de-Broglie wavelength of a ball of mass 120 g moving at a speed of 20 m/s is

Options:
A 3.5 Ã 10-34 m

B 2.8Ã10-34 m

C 1.2Ã10-34 m

D 2.1Ã10-34 m

The correct answer is:
2.8Ã10-34 m

Solution:
de-Broglie wavelength, λ=hmv
=6.6×10-34120×10-3×20
=2.75×10-34 m

Topic: Physics, Dual Nature of Matter, NEET
The de-Broglie wavelength of a neutron at 927 Â°C is Î». What will be its wavelength at 27 Â°C?

Options:
A 4λ
B 2λ
C 3λ
D λ

The correct answer is:
2λ

Solution:
We know that, λ=h2mkT ;
So, λ∝1T
∴ λ27λ927=927+27327+273=2
or λ27=2λ927=2λ

Topic: Physics, Dual Nature of Matter, NEET
The de-Broglie wavelength of a neutron at 927°C is λ . What will be its wavelength at 27°C ?

Options:
A λ/2
B λ
C 2λ
D 4λ

The correct answer is:
2λ

Solution:
λ=hmv
v∝T
λ=hm×1200 …(i)
λ1=hm×300 …(ii)
eq.21
λ1λ=1200300
λ1=2λ

Topic: Chemistry, Structure of Atom, NEET
The de-Broglie wavelength of a neutron at 1327°C is λ . What will be its wavelength at 127°C ?

Options:
A λ
B 2λ
C λ/2
D 8λ

The correct answer is:
2λ

Solution:
λ= h mv ⇒λ∝ 1 v     ...  1
v∝ T    ..... 2
From   1  & 2 ⇒λ∝ 1 T
λ 1 λ 2 = T 1 T 2 ⇒ λ 1 λ 2 = 1600 400
λ 1 =2λ

Topic: Chemistry, Structure of Atom, NEET