datavorous/entrance-exam-dataset huggingface dataset:
If 13.6 eV energy is required to ionize the hydrogen atom, then the energy required to remove an electron from its first excited state is

Options:
A 10.2 eV
B 5.1 eV
C 3.4 eV
D 6.8 eV

The correct answer is:
3.4 eV

Solution:
The energy of an electron in hydrogen atom is

E=-13.6n2 eV

So, the energy required to remove an electron from n=2 state is

E=13.622 eV=13.64=3.4 eV

Topic: Physics, Atomic Physics, NEET
If 13.6 eV energy is required to lionize the hydrogen atom, then the energy required to remove an electron from n=2 is :

Options:
A 10.2 eV

B 0 eV

C 3.4 eV

D 6.8 eV

The correct answer is:
3.4 eV

Solution:
The energy required to remove an electron from nth orbit is n
En=-13.6n2
Here n=2
Therefore E2=-13.622
= -3.4 eV

Topic: Physics, Atomic Physics, NEET
If 0.15 g of a solute, dissolved in 15 g of solvent, is boiled at a temperature higher by 0.216℃ than that of the pure solvent. The molecular weight of the substance (molal elevation constant for the solvent is 2.16℃) is

Options:
A 100
B 80
C 10
D 1.001

The correct answer is:
100

Solution:
weight of solute (w) =0.15 g, weight of solvent (W)=15 g,
âTb =0.216â
kb = 2.16â
â´ M=kbÃwÃ1000âTbÃW
=2.16Ã0.15Ã10000.216Ã15=100

Topic: Chemistry, Solutions, NEET
If 20 J of work has to be done to move an electric charge of 4 C from a point, where potential is 10 V to another point, where potential is V, find the value of V.

Options:
A 2 V
B 70 V
C 5 V
D 15 V

The correct answer is:
15 V

Solution:
Using, Wiâf=q Vf-Vi

20=4(V-10)
V=5+10=15 V

Topic: Physics, Electrostatics, NEET
If 20J of energy is trapped at producer level, then how much energy will be available to peacock as food in the following chain?
plant → mice → snake → peacock

Options:
A 0.02 J
B 0.002Â J
C 0.2Â J
D 0.0002Â J

The correct answer is:
0.02 J

Solution:
10% rule of Lindman is applicable

plant → mice → snake → peacock
20 J 2J 0.2 J 0.02J

Topic: Biology, Ecosystem, NEET, NEET 2014
If 20kJ energy is available at the producer level, then how much energy will be transferred to the lion in the food chain: Producer → deer → lion?

Options:
A 0.2 kJ
B 0.02 kJ
C 0.002 kJ
D 2 kJ

The correct answer is:
0.2 kJ

Solution:
As per the Ten percent energy transfer law introduced by Lindeman-'During the transfer of energy from organic food from one trophic level to the next, only about ten percent of the energy from organic matter is stored as flesh.' In a typical food chain, only ten percent of the energy is passed to the next consumer in the unidirectional manner. Since, producer has 20kJ, the deer will have 2kJ. Hence, the lion will only get 0.2kJ

Topic: Biology, Ecosystem, NEET
If 21 J of heat energy is supplied to an ideal diatomic gas at constant pressure, then the change in its internal energy is

Options:
A 10 J
B 12 J
C 15 J
D 18 J

The correct answer is:
15 J

Solution:
Q=nCp∆T

⇒21=n72R∆T

⇒nR∆T=6

∆U=52nR∆T

∆U=52×6=15 J

Topic: Physics, Thermodynamics, NEET
If 50 cal of heat is supplied to the system containing 2 mol of an ideal monatomic gas as shown in the figure, then the rise in temperature is (R = 2 cal mol-1 K)

Options:
A 50 K

B 5 K

C 10 K

D 20 K

The correct answer is:
5 K

Solution:
Q=nCpdT
dT=QnCp=502×5=5K
The process is isobaric.

Topic: Physics, Thermodynamics, NEET
If 50 glucose molecules combine to form 'A' polysaccharide. The general formula of 'A' polysaccharide will be

Options:
A C300H600O300
B C300H500O250
C C300H502O251
D C250H500O250

The correct answer is:
C300H500O250

Solution:
General formula for polysaccharide is (C6H10O5)n and substituting n=50 we get C300 H500 O250

Topic: Chemistry, Biomolecules, NEET
If 0.50 mole of BaCl2 ­is mixed with 0.20 mol of Na3PO4 , the maximum number of moles of Ba3(PO4)2 that can be formed is

Options:
A 0.10
B 0.20
C 0.30
D 0.40

The correct answer is:
0.10

Solution:
3 BaCl 2 0.5 + 2 Na 3 PO 4 0.2 → Ba 3 ( PO 4 ) 2 +6NaCl
Here Limiting reagent is Na3PO4
As 2 mole of Na3PO4 gives = 1 mol of Ba3(PO4)2 .
So (0.2 mol) of Na3PO4 gives = 0.1 mol of Ba3(PO4)2 .

Topic: Chemistry, Some Basic Concepts of Chemistry, NEET
If $60 \%$, of a first order reaction was completed in 60 minutes, $50 \%$ of the same reaction would be completed in approximately:
$$
(\log 4=0.60, \log 5=0.69)
$$

Options:
A 45 minutes
B 0 minutes
C 40 minutes
D 50 minutes

The correct answer is:
45 minutes

Solution:
For a first order reaction
$k=\frac{2.303}{t} \log \frac{a}{a-x}$
When $t=60$ and $x=60 \%$
$\begin{aligned}
k & =\frac{2.303}{60} \log \frac{100}{100-60} \\
& =\frac{2.303}{60} \log \frac{100}{40} \\
& =0.0153
\end{aligned}$
Now,
$\begin{aligned}
t^{1 / 2} & =\frac{2.303}{0.0153} \log \frac{100}{100-50} \\
& =\frac{2.303}{0.0153} \times \log 2 \\
& =\frac{2.303}{0.0153} \times 0.3010 \\
& =45.31 \mathrm{~min}
\end{aligned}$

Topic: Chemistry, Chemical Kinetics, NEET, NEET 2007
If 150 J of energy is incident on area 2 m2. If Qr= 15 J, coefficient of absorption is 0.6, then the amount of energy transmitted is

Options:
A 50 J
B 45 J
C 40 J
D 30 J

The correct answer is:
45 J

Solution:
When thermal radiations (Q) fall on a body, they are partly reflected, partly absorbed and partly transmitted.
Q = Qa+Qr+Qt
And QaQ +QrQ+QtQ= a + r+ t =1
â 15150 + 0.6 + x = 1
or 0.1 + 0.6 + x =1
or x=0.3
Transmitting power, t = QtQ
Or 0.3 = Qt150
â Qt= 45 J

Topic: Physics, Thermal Properties of Matter, NEET
If 150 J of heat is added to a system and the work done by the system is 110 J, then change in internal energy will be

Options:
A 260Â J
B 150Â J
C 110Â J
D 40 J

The correct answer is:
40 J

Solution:
ÎQ=ÎU+ÎW
âÎU=ÎQ-ÎW
âÎU=150-110
âÎU=40 J

Topic: Physics, Thermodynamics, NEET
If 200mL of He at 0.66 atm and 400mL of O2 at 0.52 atm pressure are raised in 400 mL vessel at 20Â°C then find the partial pressure of He and O2?

Options:
A 0.33 and 0.55
B 0.33 and 0.52
C 0.38 and 0.52
D 0.25 and 0.45

The correct answer is:
0.33 and 0.52

Solution:
At 293K, 200mL He is exhibiting a pressure of 0.66 atm.

It occupies 400 mL vessel. Here its partial pressure is reduced to half of its initial pressure.
â´PHe in the mixture =0.33 atm
As 400mLO2 at 293K with a
pressure of 0.52 atm occupies 400 mL volume at 293K, hence its partial pressure its not altered will exhibit 0.52 atm.

Topic: Chemistry, States of Matter, NEET
If 0.561 g of KOH is dissolved in water to give 200 mL of solution at 298 K. Calculate the concentrations of potassium, hydrogen and hydroxyl ions. What is its pH?

Options:
A [K+] = 0.05 M, [H+] = 0.01 M, [OH-] = 0.01 M, pH = 12.00
B [K+] = 0.02 M, [H+] = 0.00 M, [OH-] = 0.02 M, pH = 1.70
C [K+] = 0.01 M, [H+] = 0.00 M, [OH-] = 0.02 M, pH = 2.00
D [K+] = 0.02 M, [H+] = 0.01 M, [OH-] = 0.01 M, pH = 2.00

The correct answer is:
[K+] = 0.05 M, [H+] = 0.01 M, [OH-] = 0.01 M, pH = 12.00

Solution:
Correct Option is : (A)
[K+] = 0.05 M, [H+] = 0.01 M, [OH-] = 0.01 M, pH = 12.00

Topic: Chemistry, Ionic Equilibrium, NEET
If 6.84% solution of cane sugar (mol. wt. 342) is isotonic with 1.52% solution of thio carbonate, then the mol. wt. of thio carbonate is

Options:
A 152
B 60
C 76
D 180

The correct answer is:
76

Solution:
Isotonic solutions have some osmotic pressure hence, their molarities will be equal
Molarity =10×w/v%M
10×6.84342=10×1.52x
x=10×152×34210×684=1522=76

Topic: Chemistry, Solutions, NEET
If 965 coulombs of electricity is passed through a metal cup dipped in silver(I) salt solution, in order to plate it with silver. Then the amount of silver deposited on its surface is
(Given: the molar mass of Ag=108 g mol-1, 1 F=96500 coulombs)

Options:
A 1.08 g
B 1.002 g
C 108 g
D 9.89 g

The correct answer is:
1.08 g

Solution:
The chemical equation for deposition of silver from the salt solution is

Ag+(aq)+e-→Ag(s)

Clearly, for deposition of one mole of silver one-mole electrons are required.

Charge on one mole of the electron is equal to one Faraday or 96500 Coulombs.

The mass of one mole of silver is equal to its molar mass, i.e., 108 g.

Thus, we can say that

96500 coulomb charge can deposit 108 g of silver.

Therefore, 965 coulomb will deposit 10896500×965=1.08 g of silver.

Topic: Chemistry, Electrochemistry, NEET
If 10,000 J of energy is present at the T1 level, then what is the energy available at the T2 level?

Options:
A 1000 J
B 10 J
C 100 J
D 1 J

The correct answer is:
100 J

Solution:
According to the 10 percent law, only 10% of the energy is transferred to each trophic level from its lower trophic level. If 10,000 joules of energy is available to the producer, then only 1000 joules 10000 ×10/100 = 1000 of energy will be available to the primary consumer and only 100 joules 1000×10/100= 100 of energy will be available to T2 organism.

Topic: Biology, Ecosystem, NEET
If A=1 and B=0, then in terms of Boolean algebra, A+B-=

Options:
A B
B B¯·B
C A
D A-

The correct answer is:
A

Solution:
A=1, B=0 â B-=1
â´ A+ B-=1+1=1=A

Topic: Physics, Semiconductors, NEET
If A→=4i^-3j^ and B→=6i^+8j^ then magnitude and direction of A→+B→ will be

Options:
A 5,tan-1⁡34
B 55,tan-1⁡12
C 10,tan-1⁡5
D 25,tan-1⁡34

The correct answer is:
55,tan-1⁡12

Solution:
A→+B→=4i^-3j^+6i^+8j^=10i^+5j^
A→+B→=102+52=55
tan⁡θ=510=12
⇒ θ=tan-1⁡12

Topic: Physics, Mathematics in Physics, NEET
If $A$ and $C$ make $30 \%$ and $20 \%$ of DNA, respectively, what will be the percentage composition of $\mathrm{T}$ and $\mathrm{G}$ ?

Options:
A $\mathrm{T}: 20 \%, \mathrm{G}: 30 \%$
B $\mathrm{T}: 30 \%, \mathrm{G}: 20 \%$
C $\mathrm{T}: 30 \%, \mathrm{G}: 30 \%$
D $\mathrm{T}: 20 \%, \mathrm{G}: 20 \%$

The correct answer is:
$\mathrm{T}: 30 \%, \mathrm{G}: 20 \%$

Solution:
$$
\begin{aligned}
& \mathrm{A} \rightarrow 30 \%=\mathrm{T} \rightarrow 30 \% \\
& \mathrm{C} \rightarrow 20 \%=\mathrm{G} \rightarrow 20 \%
\end{aligned}
$$
According to chargaff's rule, Adenine (A) pairs with Thymine (T) and Cytosine (C) pairs with Guanine (G). So, The ds DNA have equal percentage of $A$ and $T$ or $G$ and $C$.

Topic: Biology, Molecular Basis of Inheritance, NEET, NEET 2022 (Phase 2)
If $|\vec{A} \times \vec{B}|=\sqrt{3} \vec{A} \cdot \vec{B}$ then the value of $|\vec{A} + \vec{B}|$ is:

Options:
A $\left(A^2+B^2+A B\right)^{1 / 2}$
B $\left(A^2+B^2+\frac{A B}{\sqrt{3}}\right)^{1 / 2}$
C $A+B$
D $\left(A^2+B^2+\sqrt{3} A B\right)^{1 / 2}$

The correct answer is:
$\left(A^2+B^2+A B\right)^{1 / 2}$

Solution:
According to the question
$\begin{aligned}
& \vec{A} \times \vec{B}=\sqrt{3} \vec{A} \cdot \vec{B} \\
& A B \sin =\sqrt{3} A B \cos \theta \\
& \Rightarrow \tan \theta=\sqrt{3} \\
& \Rightarrow \theta=60^{\circ} \\
& \Rightarrow|\vec{A}+\vec{B}|=\sqrt{|\vec{A}|^2+|\vec{B}|^2+2|A|} \overline{B \mid \cos \theta}
\end{aligned}$

Topic: Physics, Mathematics in Physics, NEET, NEET 2004
If a, b, c, d are inputs to a gate and x is its output, then, as per the following time graph, the gate is:

Options:
A OR
B NAND
C NOT
D AND

The correct answer is:
OR

Solution:
a	b	c	d	X
0	0	0	0	0
0	0	0	1	1

When any input is one output is one hence the gate is 'OR' gate.

Topic: Physics, Semiconductors, NEET
If A & B is given in figure, then output will be

Options:
A
B
C
D

The correct answer is:

Solution:
For AND gate

Topic: Physics, Semiconductors, NEET
If a ball is thrown vertically upwards with a speed u, the distance covered by it during the last t seconds of its ascent is

Options:
A ut
B 1 2 g t 2
C ut− 1 2 g t 2
D (u+gt)t

The correct answer is:
1 2 g t 2

Solution:
Let total height =H
Total Time of ascent =T
So, H=uTâ12gT2
Distance covered by ball in time (Tât)âsec is
y=u(Tât)â 1 2 g (Tât) 2
So, distance covered by ball in last t sec
h=Hây= uTâ 1 2 g T 2 â u(Tât)â 1 2 g (Tât) 2
By solving and putting T= u g
we will get,
h= 1 2 g t 2

Topic: Physics, Motion In One Dimension, NEET
If a ball is thrown vertically upwards with a velocity of 40  m s , then velocity of the ball after two seconds will be (g = 10 m s 2 )

Options:
A

15  m s

B

20  m s

C

25  m s

D

28  m s

The correct answer is:

20  m s

Solution:
Initial velocity, u = 40  m s

Acceleration, a = −g  m s 2  = −10  m s 2

Time = 2 seconds (given)

By 1st equation of motion, we get–

v = u+at

⇒    v = 40−10 (2) = 20  m s

Topic: Physics, Motion In One Dimension, NEET
If a ball is thrown vertically with speed $u$, the distance covered during the last $t$ seconds of its ascent is:

Options:
A $u t$
B $\frac{1}{2} g t^2$
C $u t-\frac{1}{2} g t^2$
D $(u+g t) t$

The correct answer is:
$\frac{1}{2} g t^2$

Solution:
Let time of flight be $T$, then $T=\frac{u}{g}$
Again Let $h$ be the distance covered during last ' $t$ ' second of its ascent.
$\therefore$ Velocity at point $\mathrm{B}=V_B=u-g$ $(T-t)$
$=u-g\left(\frac{u}{g}-t\right)=g t$

$\Rightarrow h=V_B t-\frac{1}{2} g t^2$

Topic: Physics, Motion In One Dimension, NEET, NEET 2003
If a bamboo plant is growing in a far forest then what will be the trophic level of it?

Options:
A First trophic level $\left(\mathrm{T}_1\right)$
B Second trophic level $\left(\mathrm{T}_2\right)$
C Third trophic level $\left(\mathrm{T}_3\right)$
D Fourth trophic level $\left(\mathrm{T}_4\right)$

The correct answer is:
First trophic level $\left(\mathrm{T}_1\right)$

Solution:
The bamboo is found in the first trophic level or the producer level that can obtain its food by the process of photosynthesis.

Topic: Biology, Ecosystem, NEET, NEET 2002
If a bar magnet of pole strength m and magnetic moment M is cut equally 4 times parallel to its axis and 3 times perpendicular to its axis then the pole strength and magnetic moment of each piece are respectively

Options:
A m20,M20
B m4,M20
C m5,M20
D m5,M4

The correct answer is:
m5,M20

Solution:
Pole strength m is directly proportional to cross-sectional area.
m′=m5 M′=M5×4

Topic: Physics, Magnetic Properties of Matter, NEET
If A be the absolute charge of a neutron and B be the absolute mass of a neutron . Find A+B.

Options:
A 0
B 1
C 2
D none of the above

The correct answer is:
1

Solution:
Correct Option is : 2
1

Topic: Chemistry, Structure of Atom, NEET
If a bimetallic strip is heated, it will

Options:
A bend towards the metal with lower thermal expansion coefficient
B bend towards the metal with higher thermal expansion coefficient
C not bend at all
D twist itself into a helix

The correct answer is:
bend towards the metal with lower thermal expansion coefficient

Solution:
Metal with higher thermal expansion coefficient expands more than metal with lower thermal expansion coefficient therefore if a bimetallic strip is heated it bend towards the metal with lower thermal expansion coefficient.

Topic: Physics, Thermal Properties of Matter, NEET
If a black man marries a white skin female, the mulattoes are born. If such mulattoes intermarry, the progeny will show a gradual gradation of skin colour in the ratio of

Options:
A 9 : 3 : 3 : 1
B 1 : 4 : 6 : 4 : 1
C 1 : 4 : 6 : 15 : 20 : 15 : 6 : 4 : 1
D 1 : 6 : 15 : 20 : 15 : 6 : 1

The correct answer is:
1 : 6 : 15 : 20 : 15 : 6 : 1

Solution:
Polygenic inheritance is defined as characters which are determined by two or more gene pairs, and they have additive or cumulative effect. Classic example is the human skin colour which is controlled by three pairs of genes. When a dark skinned individual male and a white skin female have children, they will get alleles of both characters and are generally referred to as mulatto. All shades of colours can be expressed in the population like very dark, dark, fairly dark intermediate, fairly light, light and very light respectively in the ratio 1 : 6 : 15 : 20 : 15 : 6 : 1

Topic: Biology, Principles of Inheritance and Variation, NEET
If A block is dragged on a smooth horizontal plane with the help of a light rope which moves with a velocity v as given in the figure. Then find The horizontal velocity of the block .

Options:
A v
B vsin⁡θ
C vsinâ¡Î¸
D vcos⁡θ⁡

The correct answer is:
vsin⁡θ

Solution:
From geometry l2=x2+y2 but y is constant, hence differentiating, we have, 2ldldt=2xdxdt
But dldt=v. Hence horizontal velocity of block,
vx=dxdt
â lv=x.vx or vx=l.vx=vsinâ¡Î¸

Topic: Physics, Laws of Motion, NEET
If a body coated black at 600 K surrounded by atmosphere at 300 K has cooling rate r0. If the same body is again coated black at 900 K and surrounded by the same atmospheric temprature then its cooling rate equals to

Options:
A 163r0
B 816r0
C 16 r0
D 4 r0

The correct answer is:
163r0

Solution:
Cooling rate ∝T4-T04
⇒r=9004-30046004-3004r0
⇒r=163r0

Topic: Physics, Thermal Properties of Matter, NEET
If a body has kinetic energy T, moving on a rough horizontal surface stops at distance y. The frictional force exerted on the body is

Options:
A Ty
B Ty
C yT
D Ty

The correct answer is:
Ty

Solution:
A body of mass m moving initially with velocity u on a rough surface and due to friction, it comes to rest after covering a distance s, then the retarding force is given by
ma=μ mg or a=μg .... (i)
Using, v2=u2-2as, we have
0=u2-2μg s .... (ii)
T=12 mu2or u2=2Tm
We have from equation (ii),
0=2Tm-μg s
2Tm=2μgy ∵ s=y .... (iii)
Frictional force, f=μmg .... (iv)
From equation (iii) and (iv), we get f=Ty

Topic: Physics, Work Power Energy, NEET
If a body is lying in yz -plane, then according to the theorem of perpendicular axes the correct expression will be -

Options:
A Iz=Ix+Iy
B Iy=Ix+Iz
C Ix=Iy+Iz
D Iy=Iz+Mh2

The correct answer is:
Ix=Iy+Iz

Solution:
∵ body is lying in y-z planeIx=Iy+Iz

Topic: Physics, Rotational Motion, NEET
If a body is projected with an angle θ to the horizontal, then

Options:
A its velocity is always perpendicular to its acceleration
B its velocity becomes zero at its maximum height
C its velocity makes zero angle with the horizontal at its maximum height
D just before hitting the ground, the direction of velocity coincides with the acceleration

The correct answer is:
its velocity makes zero angle with the horizontal at its maximum height

Solution:
The direction of velocity is always tangential to the path. Hence, at the top of the trajectory, velocity is in the horizontal direction.

Topic: Physics, Motion In Two Dimensions, NEET
If a body of mass m is moving on a rough horizontal surface of coefficient of kinetic friction μ, the net electromagnetic force exerted by the surface on the body is

Options:
A mg1+μ2
B μmg
C mg
D mg1-μ2

The correct answer is:
mg1+μ2

Solution:
As, normal force and friction force are the two electromagnetic forces acting on the body
The net electromagnetic force =N2+f2
But N=mg,f=μmg
Force = mg1+μ2

Topic: Physics, Laws of Motion, NEET
If a body of moment of inertia 2 kg m2 revolves about its own axis making 2 rotations per second, then its angular momentum (in J s) is

Options:
A 2π
B 4π
C 6π
D 8π

The correct answer is:
8π

Solution:
Given,
Moment of inertia of body I=2 kg m2
Rotation of the body in one second f=2
We know that,
Angular momentum L=Iω
L=2×2πf
L=2×2π2
L=8π J s

Topic: Physics, Rotational Motion, NEET
If a bullet of mass 5 g moving with velocity 100 m s-1 , penetrates the wooden block up to 6 cm . Then the average force imposed by the bullet on the block is

Options:
A 8300 N
B 417 N
C 830Â N
D zero

The correct answer is:
417 N

Solution:
u=100 m s-1, v=0, s=0.06 m
Retardation =a=u22s=10022Ã0.06=1Ã10612
â´ Force =ma=5Ã10-3Ã1Ã10612=500012=417 N

Topic: Physics, Laws of Motion, NEET
If a capillary tube of radius r is immersed in a liquid, then the liquid rises to a height h. The corresponding mass of liquid column is m. The mass of water that would rise in another capillary tube of twice the radius is

Options:
A 2m
B 5m
C 3m
D 4m

The correct answer is:
2m

Solution:
Force due to surface tension =2πrT
This force supports the weight
⇒2πrT=mg
⇒m∝r
As radius r doubles, weight supported will also doubles

Topic: Physics, Mechanical Properties of Fluids, NEET
If a cell A with OP 10 bars and TP 4 bars are connected to cells B, C and D having OP and TP 4 and 4, 10 and 5 and 7 and 3 bars respectively, the flow of water will be

Options:
A C to A, B and D
B B to A, C and D
C A to D, B and C
D A to B, C and D

The correct answer is:
B to A, C and D

Solution:
Diffusion pressure deficit (DPD) represents the absorbing capacity of the cell. It is also called as suction pressure. It is represented by DPD = OP - TP.
The net movement of water will be nil when DPD is zero and water moves from lower DPD to higher DPD. Accordingly, DPD of cell
A is OP - TP = 10 - 4 = 6
B is 4 - 4 = 0
C is 10 - 5 = 5
D is 7 - 3 = 4
Hence, the water flows from B to A, C and D as B is having the lowest DPD, which is zero.

Topic: Biology, Transport in Plants, NEET
If a certain amount of current liberated 0.504 g of hydrogen in 2 hours. Calculate the mass of copper liberated by the same current flowing for the same time in a copper sulphate solution

Options:
A 12.7 g
B 15.9 g
C 31.8 g
D 63.5 g

The correct answer is:
15.9 g

Solution:
Weight of Cu Weight of  H 2  =  Eq. weight of Cu Eq. weight of H
Weight of Cu 0.50 = 63.6/2 1
Weight of Cu = 15.9 g

Topic: Chemistry, Electrochemistry, NEET
If a certain group of cells utilise the amino acid glycine exclusively for protein synthesis, and if a growing culture of these cells is fed radioactive glycine, radioactivity will be found first in the

Options:
A Ribosomes
B tRNA
C mRNA
D Mitochondria

The correct answer is:
tRNA

Solution:
All amino acids are firstly attached with tRNA.

Topic: Biology, Molecular Basis of Inheritance, NEET
If a charged spherical conductor of the radius 10 cm has potential V at a point distant 5 cm from its centre, then the potential at a point distant 15 cm from the centre will be

Options:
A 13V
B 23V
C 32V
D 3 V

The correct answer is:
23V

Solution:
For charged spherical conductor, potential inside the sphere is same as that on its surface.
â´ Potential inside the surface, Vin=Vsurface
1 4Ï Îµ 0 q 10 =V
and potential outside the surface, 1 4Ï Îµ 0 q 15
â´ The ratio V15V=q15Ã10q=23
â V 15 = 2 3 V
â Vout=23V

Topic: Physics, Electrostatics, NEET
If a child is born with sickle-cell anaemia, then his/her parents must be:

Options:
A Homozygous
B Heterozygous
C Co-dominant
D Nullizygous

The correct answer is:
Heterozygous

Solution:
Sickle-cell anaemia is an autosome linked recessive trait that can be transmitted from parents to the offspring when both the partners are carriers for the gene (or heterozygous).

Topic: Biology, Principles of Inheritance and Variation, NEET
If a child is having blood group O, he/she cannot have parents of blood groups:

Options:
A AB and AB
B A and B
C B and B
D O and O

The correct answer is:
AB and AB

Solution:
The inheritance of blood group is determined by some allelic genes which are IA, IB & IO. In one individual two allelic genes are present. IA & IB are dominant while IO is recessive in heterozygous condition. So if a child has a blood group O he/she must have IOIO & he/she cannot have the parents of blood group AB and AB.

Topic: Biology, Principles of Inheritance and Variation, NEET
If a colour blind female marries a man whose mother was also colour blind, what are the chances of her progeny having colour blindness?

Options:
A 50%
B 75%
C 100%
D 25%

The correct answer is:
100%

Solution:
Colour blindness is an X-linked disorder. For colour blindness to be effective, all X chromosomes within an individual must be affected, and since men only have one X chromosome and women have two, the chances of men being impacted are exponentially higher.

However, in this case, the mother is colour-blind and hence she carries XCXC genotype. Father’s mother is also colour-blind and hence even she will be having the genotype as XCXC, and she will be transferring her XC chromosome to her son and hence, even the son will be colour-blind (XCY). So, by this, we can tell all the X chromosomes are coding for colour-blind gene, and they inherit this gene to all their children, and hence, the chances of their child being colour-blind would be 100%.

Topic: Biology, Principles of Inheritance and Variation, NEET, NEET 2022 (Phase 1)
If a colour blind person marries a normal woman whose father was colour blind, then what percentage of the male progeny will be affected?

Options:
A 0%
B 25%
C 50%
D 75%

The correct answer is:
50%

Solution:
Overall, 50% of males are affected. Colourblindness is an X-linked recessive trait.

Topic: Biology, Principles of Inheritance and Variation, NEET