datavorous/entrance-exam-dataset huggingface dataset:
The reading of the ammeter and voltmeters are (Both the instruments are AC meters and measures RMS value)

Options:
A 2 A, 110 V
B 2 A, 0 V
C 2 A, 55 V
D 1 A, 0 V

The correct answer is:
2 A, 0 V

Solution:
The circuit is RLC resonant circuit.
∴ Reading of voltmeter =VL-VC=0
Reading of ammeter =ErmsZ=ErmsR=11055=2 A

Topic: Physics, Alternating Current, NEET
The reading of the ideal ammeter in the circuit is

Options:
A 1Â A
B 2Â A
C 3Â A
D 5 A

The correct answer is:
5 A

Solution:
An ideal ammeter has zero resistance and hence the current will flow through the ammeter and not through the 3 Î© resistor.
â´ I=102=5 A

Topic: Physics, Current Electricity, NEET
The reading of the ideal ammeter will be (Resistance of ideal ammeters is zero)

Options:
A 5/6 ampere
B 6/5 ampere
C 3/2 ampere
D 2/3 ampere

The correct answer is:
5/6 ampere

Solution:
Req=36+2=2+2=4 Ω

Current from Battery, I=VReq=104=2.5 A
I1=2.5×33+6=56 A

Topic: Physics, Current Electricity, NEET
The reagent is

Options:
A sodium
B KOH in etanol
C sodamide
D zinc dust in ethanol

The correct answer is:
sodamide

Solution:
The product of first HBr elimination is a substituted vinyl bromide. The vinyl halides are less reactive and hence, a stronger base (NaNH2) is used to remove second HBr molecule.

Topic: Chemistry, Hydrocarbons, NEET
The reagent needed for converting

is :

Options:
A LiAlH4
B H2/Lindlar Catalyst
C Li/NH3
D Catalyst Hydrogenation

The correct answer is:
Li/NH3

Solution:
Li/NH3 is used for adding trans hydrogen to unsaturated compounds
In presence of Li/NH3 the reduction of alkene is through anti addition.

Topic: Chemistry, Hydrocarbons, NEET
The reagent (s) for the following conversion,

is/are

Options:
A Zn/CH3OH
B alcoholic KOH
C alcoholic KOH followed by NaNH2
D aqueous KOH followed by NaNH2

The correct answer is:
alcoholic KOH followed by NaNH2

Solution:
As CH2=CH-Br has partial C – Br double bond character, so it requires stronger base to remove HBr that is why KOH is ignored and NaNH2 is used.

Topic: Chemistry, Hydrocarbons, NEET
The reagents used in the preparation of aspirin from salicyclic acid is / are

Options:
A SOCl2
B CH3COOH,HCl
C CHCl2,AlCl3
D CH3CO2O,H+

The correct answer is:
CH3CO2O,H+

Solution:
Preparation of aspirin from salicylic acid

Topic: Chemistry, Alcohols Phenols and Ethers, NEET
The reagents with which glucose does not react to give the corresponding tests/products are
A. Tollen's reagent
B. Schiff's reagent
C. HCN
D. $\mathrm{NH}_2 \mathrm{OH}$
E. $\mathrm{NaHSO}_3$
Choose the correct options from the given below:

Options:
A A and D
B B and E
C E and D
D B and C

The correct answer is:
B and E

Solution:
Despite having the aldehyde group glucose does not give Schiff's test and it does not form the hydrogen sulphite addition product with $\mathrm{NaHSO}_3$.

Topic: Chemistry, Biomolecules, NEET, NEET 2024
The reason a moving coil galvanometer cannot be used with an alternating current is that

Options:
A The coil bends easily
B The coil heats up too much
C Sparks can be produced
D The net magnetic field produced is zero

The correct answer is:
The net magnetic field produced is zero

Solution:
The typical coil galvanometer is based on the principle that, when a current carrying coil is placed in a magnetic field, the coil experiences a torque.
Since, the current in an AC averages out to zero, the net magnetic field produced will be zero. Hence, the average torque experienced in a given time interval would be zero. Therefore, there will be no deflection.

Topic: Physics, Alternating Current, NEET
The reason for "drug induced poisoning" is

Options:
A binding reversibly at the active site of the enzyme
B bringing conformational changes in the biding site of enzyme
C binding at the allosteric sites of the enzyme
D binding irreversibly to the active site of the enzyme

The correct answer is:
binding at the allosteric sites of the enzyme

Solution:
Binding at the allosteric sties of the enzyme changes the conformation of enzyme so that affinity of the substrate for the active site is reduced.

Topic: Chemistry, Chemistry in Everyday Life, NEET
The reason for greater range of oxidation states in actinoids is attributed to

Options:
A the radioactive nature of actinoids.
B actinoid contraction.
C 5f, 6d and 7s levels having comparable energies.
D 4f and 5d levels being close in energies.

The correct answer is:
5f, 6d and 7s levels having comparable energies.

Solution:
The minimum energy gap between 5f, 6d  & 7s subshell. That's why e− excitation will be easier.

Topic: Chemistry, d and f Block Elements, NEET, NEET 2017
The reason for greater range of oxidation states in actinoids is attributed to

Options:
A Actinoid contraction
B 5f, 6d and 7s levels having comparable energies
C 4f and 5d levels being close in energies
D The radioactive nature of actinoids

The correct answer is:
5f, 6d and 7s levels having comparable energies

Solution:
Actinoids show more oxidation states (+ 2, + 3, + 4, + 6 etc.) as 5f, 6d, 7s have comparable energies.

Topic: Chemistry, d and f Block Elements, NEET
The reason for the distinct difference in the properties of CO2 and SiO2 is

Options:
A Carbon is more electronegative than O and in case of SiO2 oxygen is more electronegative than silicon
B Carbon has small size and forms a π bond with good overlap whereas silicon has larger size hence has a poor π -overlap
C First ionization potential of carbon is higher than that of silicon
D Carbon has only 'p' orbitals and lacks 'd' orbitals whereas silicon has 'd' oribtals

The correct answer is:
Carbon has small size and forms a π bond with good overlap whereas silicon has larger size hence has a poor π -overlap

Solution:
CO2 is a linear discrete gaseous molecule while SiO2 is a three dimensional network solid as in CO2 π bond do not polymerised due to strong overlapping while in SiO2 π bond polymerised due to poor overlapping.

Topic: Chemistry, p Block Elements (Group 13 & 14), NEET
The reason for the exit of nerve cells from the cell cycle once after forming is:

Options:
A Absence of nucleus
B Absence of mitochondria
C Absence of centrosome
D Absence of Golgi body

The correct answer is:
Absence of centrosome

Solution:
Once being differentiated, nerve cells do not divide as they lack mitotic activity. Lack of mitotic activity indicates that they do not have centrosome.

Topic: Biology, Structural Organisation in Animals, NEET
The reason for the population explosion in the world is

Options:
A Increase in birth rate
B Decrease in death rate
C Both (A) and (B)
D None of them

The correct answer is:
Both (A) and (B)

Solution:
The factors which favours population growth is increased natality (birth rate), decreased mortality (death rate), immigration, increase in life span and better medical facilities.

Topic: Biology, Organisms and Populations, NEET
The reason why beryllium differs from rest of the members of its family (Group-IIA)

Options:
A Large size and largest ionic radius
B Small size and lower electronegativity
C Large size and lower ionisation energy
D Small size and higher electronegativity

The correct answer is:
Small size and higher electronegativity

Solution:
(i) Small atomic size.
(ii) High electronegativity
(iii) Absence of d orbitals

Topic: Chemistry, s Block Elements, NEET
The reason why saturated solution of KNO3 is used to make ‘salt-bridge’

Options:
A Velocity of K+ is greater than that of NO3-
B Velocity of NO3- is greater than that of K+
C Velocities of both K+ and NO3- are nearly the same
D KNO3 is highly soluble in water

The correct answer is:
Velocities of both K+ and NO3- are nearly the same

Solution:
Velocities of both K+ and NO3- are nearly the same in KNO3 so it is used to make salt-bridge.

Topic: Chemistry, Electrochemistry, NEET
The recessive genes located in $X$ chromosome humans are always:

Options:
A lethal
B sub-lethal
C expressed in males
D expressed in females.

The correct answer is:
expressed in males

Solution:
In human, male sex chromosome is hemizygous, $\mathrm{XY}$ while female are homozygous $\mathrm{XX}$. Thus, any recessive gene present on $\mathrm{X}$ chromosome will get expressed in male. In female, those genes can only be expressed if present in homozygous recessive condition on both X-chromosomes.

Topic: Biology, Principles of Inheritance and Variation, NEET, NEET 2004
The reciprocal of resistance is:

Options:
A reactance
B mobility
C conductivity
D conductance

The correct answer is:
conductance

Solution:
Conductance $\propto \frac{1}{\text { Resistance }}$

Topic: Physics, Current Electricity, NEET, NEET 2022 (Phase 2)
The recombinant phenotypic and genotypic ratio in F2 obtained from parental cross having genotypes TTRR x ttrr will be

Options:
A

Phenotypic ratio	Genotypic ratio

9:3:3:1	1:2:2:4:1:2:1:2:1

B

Phenotypic ratio	Genotypic ratio

3:1	1:2:1

C

Phenotypic ratio	Genotypic ratio

3:3	1:2:3

D

Phenotypic ratio	Genotypic ratio

3:3	1:2:1:2

The correct answer is:

Phenotypic ratio	Genotypic ratio

3:3	1:2:1:2

Solution:
9:3:3:1 is the phenotypic ratio obtained in a dihybrid cross. Among these offsprings, 6 show recombinant phenotype in the ratio of 3:3. 9 and 1 represent the parental phenotype. The genotypic ratio for dihybrid cross will be:
TTRR:TtRR:TTRr:TtRr:TTrr:Ttrr:ttRR:ttRr:ttrr :: 1:2:2:4:1:2:1:2:1

Topic: Biology, Principles of Inheritance and Variation, NEET
The recombination frequency between the genes a and c is 5%, b and c is 15%, b and d is 9%, a and b is 20%, c and d is 24% and a and d is 29%. What will be the sequence of these genes on a linear chromosome?

Options:
A d,b,a,c
B a,b,c,d
C a,c,b,d
D a,d,b,c

The correct answer is:
a,c,b,d

Solution:
The recombination frequency is directly proportional to the distance between genes, and the recomination values are used to locate the genes on a chromosome. Here, four genes a, b, c, and d are present with their recombination frequency of a - c = 5%, b – c = 15%, b - d = 9%, a – b = 20%, c – d = 24%, a – d = 29%.

The correct sequence of genes is a-c-b-d, and this is in accordance with the recombination frequency. 29% is the highest recombination frequency present between a and d, this signifies a and d are very far apart, and they are present at the endpoint. The distance between a and c is very less of 5%, which means they are very nearby and next to each other. Likewise, the distance between b and d is very less of 9%, which means they are very nearby and next to each other.

Topic: Biology, Principles of Inheritance and Variation, NEET, NEET 2022 (Phase 1)
The red light of a wavelength 6400 â« in the air has a wavelength of 4000 â« in glass. If the wavelength of violet light in air is 4400 â«, then the wavelength in the glass is

Options:
A 2570 Å
B 2750 Å
C 1600 Å
D 2510 Å

The correct answer is:
2750 Å

Solution:
μg=λrairλrair
Now, μg= λvairλvglass=64004000
λvglass=λvairμg=44001.6=2750 Å

Topic: Physics, Ray Optics, NEET
The red light of wavelength 5400 Aâ from a distant source falls on a slit 0.80 mm wide. Calculate the distance between the first two dark bands on each side of the central bright band in the diffraction pattern observed on a screen place 1.4 m from the slit.

Options:
A 1.89 mm
B 4 mm
C 3 mm
D 5 mm

The correct answer is:
1.89 mm

Solution:
Here wavelength λ=5400 A∘=5.4×10-7m, a=0.80 mm=8×10-4m, D=1.4 m
∴ Distance between the first two dark bands on each side of central maximum is the width of central maximum
=2x=2λDd
=2×5.4×10-7×1.48×10-4
=1.89×10-3 m=1.89 mm

Topic: Physics, Wave Optics, NEET
The reddish appearance of the sun of sunrise and sunset is due to :

Options:
A the scattering of light
B the polarisation of light
C the colour of the sun
D the colour of the sky

The correct answer is:
the scattering of light

Solution:
The reddish appearance of the sun at Sunrise and sunset is due to the scattering of light.

Topic: Physics, Ray Optics, NEET, NEET 2013 (Karnataka)
The reduced leaf found at the base of the pedicel is known as

Options:
A leaflet.
B stipule.
C bract.
D calyx.

The correct answer is:
bract.

Solution:
The stalk of the flower is called as pedicel and reduced leaf which develops from the base of the pedicel is called a bract. The reduced leaf which develops from the base of petiole in the leaf is called stipule. When the incisions of the lamina reach up to the midrib breaking it into a number of leaflets, the leaf is called a compound leaf.

Topic: Biology, Morphology of Flowering Plants, NEET
The reduction reaction that happens in Daniel cell is

Options:
A Zn →Zn+2+ 2e-
B Zn→Zn+2+ 4e-
C Cu+2+ 2e-→Cu
D Cu+2+ 4e-→Cu

The correct answer is:
Cu+2+ 2e-→Cu

Solution:
Correct Option is : 3
Cu+2+ 2e-→Cu

Topic: Chemistry, Redox Reactions, NEET
The refining method used when the metal and the impurities have low and high melting temperatures, respectively, is

Options:
A vapour phase refining
B liquation
C zone refining
D distillation

The correct answer is:
liquation

Solution:
The refining method liquation is used when the metal and the impurities have low and high melting temperatures, respectively. Liquationis a metallurgical method for separating metals from an ore or alloy. The material must be heated until one of the metals starts to melt and drain away from the other and can be collected.
example: Tin

Topic: Chemistry, General Principles and Processes of Isolation of Metals, NEET
The reflectance and emittance of a perfectly black body are respectively

Options:
A 0,1
B 1,0
C 0.5,0.5
D 0,0

The correct answer is:
0,1

Solution:
According to kirchhoff's law ideal black body absorb all the heat at low temperature and emits it all at high temperature a=e=1 and r=0

Topic: Physics, Thermal Properties of Matter, NEET
The refracting angle of a prism is A , and refractive index of the material of the prism is cotA2. The angle of minimum deviation is

Options:
A 180o-3A
B 180o-2A
C 900-A
D 1800+2A

The correct answer is:
180o-2A

Solution:
μ= sin⁡δm+A2 sin⁡A2
∵ μ=cot⁡A2
∴cot⁡A2= sin⁡δm+A2sin⁡A2
cos⁡A2=sin⁡δm+A2
π2-A2= δm+A2
δm=π-2A

Topic: Physics, Ray Optics, NEET, NEET 2015 (Phase 1)
The refractive index for a prism is given as μ=cot⁡A2. Then, the angle of minimum deviation in terms of angle of the prism is

Options:
A 90°-A
B 2A
C 180°-A
D 180°-2A

The correct answer is:
180°-2A

Solution:
The refractive index of a prism is given by
μ=sin⁡A+5m2sin⁡A2
Where, A = angle of prism
δm= angle of minimum deviation
Given, μ=cot⁡A2=cos⁡A2sin⁡A2
So, from equation (i)
cos⁡A2sin⁡A2=sin⁡A+δm2sin⁡A2
⇒ sin⁡π2-A2=sin⁡A2+δm2
⇒ δm=π-2A
⇒ δm=180°-2A

Topic: Physics, Ray Optics, NEET
The refractive index of a material of a planoconcave lens is 53, the radius of curvature is 0.3 m. The focal length of the lens in air is

Options:
A -0.45 m

B -0.6 m

C -0.75 m

D -1.0 m

The correct answer is:
-0.45 m

Solution:
Lens maker's formula
1f=Î¼-1 1R1-1R2
Where , R2= â, R1=0.3 m
â´1f=53-110.3-1â
â1f=23Ã10.3
Or f=0.45 m

Topic: Physics, Ray Optics, NEET
The refractive index of the material of a concave lens is Î¼ . It is immersed in a medium of refractive index Î¼ 1 . A parallel beam of light is incident on the lens. The path of the emergent rays when Î¼ 1 > Î¼ is :

Options:
A

B

C

D

The correct answer is:

Solution:
For μ 1 > μ concave lens becomes converging while convex becomes diverging.

Topic: Physics, Ray Optics, NEET
The refractive index of the material of a prism is $\sqrt{2}$ and its refracting angle is $30^{\circ}$. One of the refracting surface of the prism is made a mirror inward. A beam of monochromatic light entering the prism from the other face will retrace its path after reflection from the mirrored surface if its angle of incidence on the prism is:

Options:
A $45^{\circ}$
B $60^{\circ}$
C 0
D $30^{\circ}$

The correct answer is:
$45^{\circ}$

Solution:
Here $\angle r=30^{\circ}$
(Using law of triangle)
$$
\begin{aligned}
& \Rightarrow \quad \mu=\frac{\sin i}{\sin r} \\
& \Rightarrow \sqrt{2} \cdot \sin 30^{\circ}=\sin i \\
& \Rightarrow \quad \sin i=\frac{1}{\sqrt{2}} \\
& \Rightarrow \quad i=45^{\circ}
\end{aligned}
$$

Topic: Physics, Ray Optics, NEET, NEET 2004
The refractive index of the materiel of a prism is 2 and the angle of the prism is 30o. One of the two refracting surface of the prism is made a mirror inwards, by silver coating. A beam of monochromatic light entering the prism from the other face will retrace its path (after reflection from the silvered surface) if its angle of incidence on the prism is

Options:
A 30o
B 45o
C 60o
D Zero

The correct answer is:
45o

Solution:
by principle of reversibility, the beam will return its path when it strikes the mirror perpendicularly

r2=0, r1=A=30o
∴ r 1 + r 2 =A in a prism
Applying Snell's law at P sin⁡i=2sin⁡30o=2×12=12
∠i=45o

Topic: Physics, Ray Optics, NEET, NEET 2018
The refractive index of water is 1.33. What will be the speed of light in water?

Options:
A 3 × 1 0 8 ms - 1
B 4 × 1 0 8 ms - 1
C 1.33 × 1 0 8 ms - 1
D 2.26 Ã 1 0 8 ms - 1

The correct answer is:
2.26 Ã 1 0 8 ms - 1

Solution:
We know that refractive index of a medium is given by :
Î¼ = c vâ¡
â´ vâ¡ = c Î¼ = 3 Ã 1 0 8 1 Â· 3 3 = 2.26 Ã 1 0 8 ms - 1

Topic: Physics, Ray Optics, NEET
The regent who can’t be used to detect the presence of both CO32- and HCO3- in a mixture is –

Options:
A CaCl2
B SrCl2
C AgNO3
D MgCl2

The correct answer is:
MgCl2

Solution:
During the formation of ppt by MgCl2 with CO32- , it will be produced HCO3- ion in the solution. Hence, we can’t be used to detect the presence of both CO32- and HCO3- in a mixture

Topic: Chemistry, s Block Elements, NEET
The region of Biosphere Reserve which is legally protected and where no human activity is allowed is known as :

Options:
A Core zone
B Buffer zone
C Transition zone
D Restoration zone

The correct answer is:
Core zone

Solution:
Biosphere reserve is protected area with multipurpose activities.
It has three zones
(i) Core zone - without any human interference
(ii) Buffer zone - with limited human activity
(iii) Transition zone - human settlement, grazing cultivation etc. are allowed.

Topic: Biology, Biodiversity and its Conservation, NEET, NEET 2017
The region of the biosphere reserve, where human activity is restricted is:

Options:
A Restoration zone
B Core zone
C Buffer zone
D Transition zone

The correct answer is:
Core zone

Solution:
Biosphere reserves are large area which are legally protected in which central core area is very dense forest in which all sort of human activity is prohibited. In buffer zone some human activities like tourism is permitted. But in all zones cutting down of trees and hunting of animals is banned.

Topic: Biology, Biodiversity and its Conservation, NEET
The region outside the seminiferous tubule

Options:
A is called interstitial space
B has leydig cells
C has blood vessels
D all of the above

The correct answer is:
all of the above

Solution:
In males the interstitial cells of Leydig, located in the connective tissue surrounding the sperm-producing tubules of the testes, are responsible for the production and secretion of testosterone.

Topic: Biology, Human Reproduction, NEET
The region where probability density function reduce to zero is called

Options:
A probability density region
B nodal surface
C orientation surfaces
D wave function

The correct answer is:
nodal surface

Solution:
Probability density region defines the electron density around the nucleus.
Nodal surfaces are defined as the region of absence of electron i.e. the region where probability density function reduces to zero.

Topic: Chemistry, Structure of Atom, NEET
The regions with high level of species richness, high degree of endemism and a loss of $70 \%$ of the species and habitat are identified as:

Options:
A Natural Reserves
B Sacred Groves
C Biodiversity Hotspots
D Biogeographical Regions

The correct answer is:
Biodiversity Hotspots

Solution:
The regions with high level of species richness, high degree of endemism and a loss of most of the species and habitat are identified as Biodiversity hotspots.

Topic: Biology, Biodiversity and its Conservation, NEET, NEET 2024 (Re-NEET)
The regulation of gene expression in eukaryotes occurs at / or include

Options:
A Translation level
B Transport of mRNA from nucleus to the cytoplasm
C Formation of primary transcript
D All of these

The correct answer is:
All of these

Solution:
Regulation of gene expression refers to a very broad term that may occur at various levels. Considering that gene expression results in the formation of a polypeptide, it can be regulated at several levels. In eukaryotes, the regulation could be exerted at (i) transcriptional level (formation of primary transcript), (ii) processing level (regulation of splicing), (iii) transport of mRNA from nucleus to the cytoplasm, (iv) translational level.

Topic: Biology, Molecular Basis of Inheritance, NEET
The regulatory protein of skeletal muscles whose filaments run close to the F-actin throughout its length is

Options:
A Troponin T
B Troponin C
C Troponin I
D Tropomyosin

The correct answer is:
Tropomyosin

Solution:
Actin filaments are made of two F actins wound helically. F actin which is a polymer is made of monomers of G actins. Two filaments of tropomyosin run close to these F actins throughout its length. Troponin which is a complex protein is distributed on tropomyosin at regular intervals. Subunit of troponin masks the active binding sites for myosin on the actin filament in the resting state.

Topic: Biology, Locomotion and Movement, NEET
The rejection of organ transplanting in human is prevented by using

Options:
A Aspirin
B Cyclosporin
C Calcitonin
D Thrombin

The correct answer is:
Cyclosporin

Solution:
Cyclosporine is used as an immunosuppressant, this drug is derived from a fungus called Trichoderma polysporum and inhibit the activity of helper-T cells, thus help to prevent rejection of organ transplant.

Topic: Biology, Human Health and Diseases, NEET
The relation between α and β parameters of a transistor is given by

Options:
A α=1+ββ
B α=1-ββ
C α=β1+β
D α=β1-β

The correct answer is:
α=β1+β

Solution:
α and β both are amplification factors
IE=IC+IB
IEIC=1+IBIC
1α=1+1β
α=β1+β

Topic: Physics, Semiconductors, NEET
The relation between efficiency Î· of a heat engine and the co-efficient of performance Î± of a refrigerator is

Options:
A η=11-α
B η=11+α
C η=1+α
D η=1-α

The correct answer is:
η=11+α

Solution:
η=dwdQ but α=dQ2dw=Q2Q1-Q2⇒ 1α=Q1Q2-1 ⇒1α+1=Q1Q2⇒ α+1α=Q1Q2⇒Q2Q1=αα+1
η=Q1-Q2Q1=1-Q2Q1=1-α1+α=1+α-α1+α
η=11+α

Topic: Physics, Thermodynamics, NEET
The relation between given pair is

and

Options:
A enatiomers
B Identical
C constitutional isomers
D diastereomers

The correct answer is:
enatiomers

Solution:

Topic: Chemistry, General Organic Chemistry, NEET
The relation between glucose and mannose is

Options:
A Anomers
B Disaccharides
C Epimers
D Ketohexoses

The correct answer is:
Epimers

Solution:
Glucose and mannose are epimers because they both differ in configuration at C-2 and the Pair of diastereomer which differ at in configuration at only one chiral atom is known as epimers of each other.

Topic: Chemistry, Biomolecules, NEET
The relation between internal energy U, pressure P and volume V of gas in an adiabatic process is U=a+bPV, where a and b are constants. What is the effective value of adiabatic constant Î³ ?

Options:
A ab
B b+1b
C a+1a
D ba

The correct answer is:
b+1b

Solution:
For an adiabatic process,
0=dU+PdV
or d(a + bPV) + PdV = 0
or bP dV + bV dP + p dV = 0
or (b + 1) PdV + bV dP = 0
or b + 1 dV V + b dP P = 0
(b+1) logV+b logP = constant
V b + 1 p b = constant
or PV b + 1 b = constant
∴ γ = b + 1 b

Topic: Physics, Thermodynamics, NEET
The relation between KP and KC for the reaction A g +B g ⇌ C g +2D g is-

Options:
A KP=KCRT–1
B KP.KC–1=RT
C KCKP–1=RT
D KP=KCRT3

The correct answer is:
KP.KC–1=RT

Solution:
Δn g = (No. Moles of products- No. of moles of reactant) =1
Δn g  = 1
Kp =  K c Δn g RT

Topic: Chemistry, Chemical Equilibrium, NEET
The relation between length L and radius R of the cylinder, if its moment of inertia about its axis is equal to that about the equatorial axis, will be

Options:
A L=R
B L=2R
C L=3R
D L=3R

The correct answer is:
L=3R

Solution:
mR22=ML212+R24
or R22=L212+R24
or L=3R

Topic: Physics, Rotational Motion, NEET