datavorous/entrance-exam-dataset huggingface dataset:
In the given columns match the plant with their flower based on ovary position.

Column I	Column II

i. Epigyny	a. Peach

ii. Perigyny	b. China rose

iii. Hypogyny	c. Cucumber

Options:
A i-b, ii-a, iii-c
B i-a, ii-c, iii-b
C i-a, ii-b, iii-c
D i-c, ii-a, iii-b

The correct answer is:
i-c, ii-a, iii-b

Solution:
The position of the ovary in a flower can be different for different flowers. Some flowers have a superior ovary (Hypogyny), where all the other parts of the flower are below it. Such condition is seen in China rose. Some flowers have an inferior ovary (Epigyny), where all the other parts of the flower lie above it. Such condition is seen in cucumber. Some flowers have a half-inferior ovary (Perigyny), gynoecium is situated in the centre and other parts of the flower are located on the rim of the thalamus almost at the same level. Such condition is seen in Peach.

Topic: Biology, Morphology of Flowering Plants, NEET
In the given diagram, Biome distribution is shown with respect to annual temperature and precipitation. Select the correct option.

Temperate forests	Grasslands	Arctic and Alpine tundra

(a)	C	E	A

(b)	D	B	F

(c)	E	B	F

(d)	F	A	C

Options:
A a
B b
C c
D d

The correct answer is:
b

Solution:

Topic: Biology, Organisms and Populations, NEET
In the given diagram cystic duct and common bile duct are

Options:
A 1 and 4
B 2 and 3
C 1 and 3
D 4 and 2

The correct answer is:
1 and 3

Solution:
Bile and Pancreatic juice open into the duodenum through the hepatopancreatic duct. This duct is formed by fusion of common bile duct and duct of Wirsung (functional duct of pancreas). Common bile duct contains concentrated and dilute bile from gall bladder and liver and thus it is the fusion of cystic duct (duct of gall bladder) and hepatic duct (duct of liver). Hepatic duct in turn is formed by fusion of ducts from right and left hepatic lobes.

Topic: Biology, Digestion and Absorption, NEET
In the given diagram of antibody, 'X' indicates ________.

Options:
A Constant region of heavy chain
B Antigen-binding site
C Disulphide bond
D Light chain

The correct answer is:
Antigen-binding site

Solution:
X is the antigen-binding site. Antigen combines with the antibody at this site in a lock and key manner.

Topic: Biology, Human Health and Diseases, NEET
In the given diagram of areolar connective tissue, identify parts labeled A-D.

Options:
A

A	B	C	D

Mast cell	Macrophage	Fibroblast	Collagen fibres

B

A	B	C	D

Macrophage	Mast cell	Fibroblast	Collagen fibres

C

A	B	C	D

Macrophage	Mast cell	Collagen fibres	Fibroblast

D

A	B	C	D

Mast cell	Macrophage	Collagen fibres	Fibroblast

The correct answer is:

A	B	C	D

Macrophage	Mast cell	Fibroblast	Collagen fibres

Solution:

Topic: Biology, Structural Organisation in Animals, NEET
In the given diagram of the chemical structure of DNA, identify the type of bonding shown by A, B and C.

Options:
A A: N-glycosidic bonding; B: Phosphodiester bonding; C: Hydrogen bonding
B A: N-glycosidic bonding; B: Covalent bonding; C: Phosphodiester bonding
C A: Coordinate bonding; B: Phosphodiester bonding; C: N-glycosidic bonding
D A: N-glycosidic bonding; B: Hydrogen bonding; C: Phosphodiester bonding

The correct answer is:
A: N-glycosidic bonding; B: Hydrogen bonding; C: Phosphodiester bonding

Solution:
DNA is the nucleic acid that forms the genetic material in all organisms. The structure of deoxyribose nucleic acid was elucidated by Watson and Crick. The DNA is a double helical structure having two anti-parallel strands of polynucleotide chains joined to each other by hydrogen bonding [B] formed between the N-bases. The backbone of the structure is constituted by the sugar-phosphate linked by the phosphodiester bond[C]. N-bases from double and triple H-bonds where Adenine always binds to Thymine (2 bonds) and Guanine binds to Cytosine (3 bonds). The N-bases are joined to the sugar structure by forming N-glycosidic bond[A] .

Topic: Biology, Molecular Basis of Inheritance, NEET
In the given diagrams, A (spine) and B (tendril) are structures which are modifications of the stem. Then, probable examples of plants in which A and B can be observed, respectively, will be:

Options:
A Opuntia, Watermelons
B Gourds, Colocasia
C Citrus, Euphorbia
D Bougainvillea, Grapevines.

The correct answer is:
Bougainvillea, Grapevines.

Solution:
Modifications of stem:
1. Underground stems may modify to store food.
Examples - potato, turmeric, ginger, Colocasia, zaminkand, etc.
2. Stem may develop into tendrils (originating from axillary buds) for support.
Examples - grapevines and gourds (cucumber, pumpkins and watermelons).
3. Stems may develop woody and pointed thorns for protection from the axillary buds.
Examples - Bougainvillea, Citrus.
4. Stems may develop chlorophyll and perform photosynthesis.
Examples - Opuntia (stem as flattened structures), Euphorbia (stem as fleshy cylindrical structures), etc.
5. Stems may help in spread and vegetative propagation.

Topic: Biology, Morphology of Flowering Plants, NEET
In the given equation below, identify the compound which is being oxidized and calculate the R.Q. of the same.

2C51H98O6+145O2→102CO2+98H2O+energy

Options:
A Palmitin, R.Q. = 0.9
B Tripalmitin, R.Q. = 0.7
C Palmitin, R.Q. = 1
D ​Tripalmitin, R.Q. = 0.2

The correct answer is:
Tripalmitin, R.Q. = 0.7

Solution:
When fats are used in respiration, the RQ is less than 1. Calculations for fatty acid, tripalmitin, if used as a substrate is shown:
Thus, R.Q. = 0.7

Topic: Biology, Respiration in Plants, NEET
In the given figure, a=15 m s-2 represents the total acceleration of a particle moving in the clockwise direction in a circle of the radius R=2.5 m at a given instant of time. The speed of the particle is

Options:
A 4.5 m s-1
B 5.0 m s-1
C 5.7 m s-1
D 6.2 m s-1

The correct answer is:
5.7 m s-1

Solution:
Centripetal acceleration is the radial component of resultant acceleration.

Referring the figure in question, radial component of the resultant acceleration,

=15cos30°=15×32

⇒v 2r=15×32

⇒v=15×32×2.5≃5.7 m s-1.

Topic: Physics, Laws of Motion, NEET, NEET 2016 (Phase 2)
In the given figure, a diode D is connected to an external resistance R = 100 Ω and an emf of 3.5 V If the barrier potential developed across the diode is 0.5 V, the current in the circuit will be

Options:
A 40 mA
B 20 mA
C 35 mA
D 30 mA

The correct answer is:
30 mA

Solution:
Current=(3.5-0.5)100A
=3100A=30 mA

Topic: Physics, Semiconductors, NEET, NEET 2015 (Phase 2)
In the given figure, a diode D is connected to an external resistance R = 100 Î© and an emf of 3.5 V If the barrier potential developed across the diode is 0.5 V, the current in the circuit will be

Options:
A 40 mA
B 20 mA
C 35 mA
D 30 mA

The correct answer is:
30 mA

Solution:
Current=(3.5-0.5)100A
=3100A=30 mA

Topic: Physics, Semiconductors, NEET
In the given figure, a smooth parabolic wire track lies in the xy-plane (vertical). The shape of track is defined by the equation y=x2 . A ring of mass m which can slide freely on the wire track, is placed at the position A(1,1). The track is rotated with constant angular speed ω such that there is no relative slipping between the ring and the track, the value of ω is

Options:
A g2
B g
C 2g
D 2g

The correct answer is:
2g

Solution:
Ncosâ¡Î¸=mg
And Nsinâ¡Î¸=mÏ2r
â´tanâ¡Î¸=Ï2rg ...(i)
Given y=x2
â´dydx=2x
Or tanâ¡Î¸=2Ã1=2 ...(ii)
From above equations, we get
Ï=2g r=1 m

Topic: Physics, Laws of Motion, NEET
In the given figure, atmospheric pressure p0=1 atm and mercury column length is 9 cm. Pressure p of the gas enclosed in the tube is

Options:
A Pressure of 67  cm of Hg
B Pressure of 90  cm of Hg
C Pressure of 78  cm of Hg
D Pressure of 85  cm of Hg

The correct answer is:
Pressure of 85  cm of Hg

Solution:
Given,
Atmospheric pressure p0=1 atm=76 cm of Hg
Pressure due to mercury column pâ²=9 cm of Hg
We know that, pgas=patm+pâ²
pgas=76 cm of Hg+9 cm of Hg
pgas=85 cm of Hg

Topic: Physics, Mechanical Properties of Fluids, NEET
In the given figure capacitor of plate area A is charged upto charge q. The ratio of elongation (neglect force of gravity) in spring C and D at equilibrium position is

Options:
A k 1 k 2
B k 2 k 1
C k1k2
D None of these

The correct answer is:
k 2 k 1

Solution:
From force diagram,

F e = k 1 x 1 = k 2 x 2
∴ x 1 x 2 = k 2 k 1

Topic: Physics, Electrostatics, NEET
In the given figure, identify A, B, C, D and E respectively.

Options:
A A- Pubis; B- Acetabulum; C- Ilium; D- Ischium; E- Pubic symphysis
B A- Sacrum; B- Coccyx; C- Pubic symphysis; D- Pubis; E- Ischium
C A- Coccyx; B- Sacrum; C- Pubic symphysis; D- Pubis; E- Ischium
D A- Ilium; B- Sacrum; C- Pubic symphysis; D- Ischium; E- Pubis

The correct answer is:
A- Sacrum; B- Coccyx; C- Pubic symphysis; D- Pubis; E- Ischium

Solution:
Pelvic girdle, also called bony pelvis, is basin-shaped complex of bones that connects the trunk and the legs, supports and balances the trunk, and contains and supports the intestines, the urinary bladder, and the internal sex organs.

Topic: Biology, Locomotion and Movement, NEET
In the given figure, if the velocity of the block C at a particular instant is -20 m s-1j^, then the velocity of the rod (A) at that instant will be : (string is attached to wedge)

Options:
A 15 m s-1j^
B -15 m s-1j^
C 20 m s-1j^
D -20 m s-1j^

The correct answer is:
15 m s-1j^

Solution:
In the given figure, if the velocity
l1'+l2'=0
20-u=0
u=20 m s-1
By wedge constraint
usin37∘=v cos37∘
v=u×34=15 m s-1
v→=15j^

Topic: Physics, Laws of Motion, NEET
In the given figure of the heart, which of the marked structures (1, 2, 3, 4, and 5) carry oxygenated blood?

Options:
A 1, 2, 3 and 4
B 1 and 5
C 1 and 4
D 3 and 5

The correct answer is:
1 and 4

Solution:
The marked structures 1 and 4 are aorta and left ventricles respectively, which carry oxygenated blood.

Topic: Biology, Body Fluids and Circulation, NEET
In the given figure the area of the frictionless and movable piston is 1 m2 and it is being held in equilibrium by an external force. Now the external force is slowly removed due to that the piston displaces by L2 where L=1 m. The natural length of the ideal springs is L=1 m. Spring constant is given as K=100 N m-1. The pressure of the gas in the final situation is

Options:
A 50 N m-2
B 100 N m-2
C 200 N m-2
D 400 N m-2

The correct answer is:
100 N m-2

Solution:
In the case of equilibrium, the net force on the piston becomes zero. So,
PA-Kx=Kx⇒P=2KxA
=2×1001×12
=100 N m-2

Topic: Physics, Thermodynamics, NEET
In the given figure, what does A, B, C, D and E represent?

Options:
A repressor, inducer, beta-galactosidase, permease, transacetylase
B transacetylase, permease, beta-galactosidase, inducer, repressor
C repressor, beta-galactosidase, permease, transacetylase, inducer
D Inducer, repressor, beta-galactosidase, permease, transacetylase

The correct answer is:
repressor, inducer, beta-galactosidase, permease, transacetylase

Solution:
In the above figure, A, B, C, D and E represent repressor, inducer, beta-galactosidase, permease, transacetylase respectively

Topic: Biology, Molecular Basis of Inheritance, NEET
In the given figure, which component has thin outer walls and highly thickened inner walls?

Options:
A D
B A
C B
D C

The correct answer is:
C

Solution:
Guard cells of stomata have thin outer wall and highly thickened inner walls.

Topic: Biology, Transport in Plants, NEET, NEET 2024
In the given figure, which part is represented by A?

Options:
A Adrenal Cortex
B Adrenal Medulla
C Adrenal Gland
D Thymus

The correct answer is:
Adrenal Gland

Solution:
X represents Adrenal Gland.

Topic: Biology, Chemical Coordination and Integration, NEET
In the given nuclear reaction

49Be+ 24Heâ 612C+X

X represents

Options:
A Neutron
B Proton
C Positron
D Electron

The correct answer is:
Neutron

Solution:
Balancing atomic number and mass number on both sides 01n (neutron)

Topic: Physics, Nuclear Physics, NEET
In the given nuclear reaction, the element X is Na1122→X+e++v

Options:
A Ne1023
B Ne1022
C Mg1222
D Na1123

The correct answer is:
Ne1022

Solution:
As positron is emitting, it is positive beta decay with equation,

XzA⟶Yz-1A+e++ν

Hence, ⇒Na1122⟶Ne1022+e++ν

Topic: Physics, Nuclear Physics, NEET, NEET 2022 (Phase 1)
In the given options, there is a property of a group and a representative example following that property. Which of these is incorrect?

Options:
A All prokaryotes classified under kingdom Monera have cell wall (Mycoplasma)
B All viroids have single stranded RNA as genetic material (Potato Tuber Spindle Viroid)
C All prions don't have nucleic acid as their genetic material (Bovine Spongiform Encephalopathy Prion)
D Unicellular plants have been placed in kingdom Protista by Whittaker (Chlorella)

The correct answer is:
All prokaryotes classified under kingdom Monera have cell wall (Mycoplasma)

Solution:
The Mycoplasma are organisms that completely lack a cell wall. They are the smallest living cells known and can survive without oxygen. Many mycoplasma are pathogenic in animals and plants. Viroids are smaller than viruses and cause potato spindle tuber disease. It was found to be a free RNA; it lacked the protein coat that is found in viruses, hence the name viroid. The RNA of the viroid was of low molecular weight. In modern medicine certain infectious neurological diseases were found to be transmitted by an agent consisting of abnormally folded protein. The agent was similar in size to viruses. These agents were called prions. The most notable diseases caused by prions are bovine spongiform encephalopathy (BSE) commonly called mad cow disease in cattle.

Topic: Biology, Biological Classification, NEET
In the given options, which one is a characteristic feature of the zygotene stage of prophase-I observed in meiosis?

Options:
A Chromomeres
B Crossing over
C Terminalisation of chiasmata
D Synaptonemal complex

The correct answer is:
Synaptonemal complex

Solution:
Zygotene stage is observed in prophase-I of meiosis-I divisional phase. In this stage, chromosomes start pairing together forming an association called synapsis. This pairing is observed between homologous chromosomes. This synapsis results in formation of a complex structure called synaptonemal complex. Crossing over is observed in pachytene stage of prophase-I, where exchange of genetic materials occurs. In diakinesis, the paired of chromosomes separate resulting in terminalisation of chiasmata. Chiasmata is formed when the chromosomes of synaptonemal complex separate from each other. Chromomeres are linearly arranged chromatin granules observed on chromosomes.

Topic: Biology, Cell Cycle and Cell Division, NEET
In the given organelle below, which part is associated with the packaging of materials to be delivered?

Options:
A cis face
B trans face
C Maturing face
D None of the above

The correct answer is:
cis face

Solution:
The Golgi cisternae are concentrically arranged near the nucleus with distinct convex cis or the forming face and concave trans or the maturing face. The Golgi apparatus principally performs the function of packaging materials, to be delivered either to the intracellular targets or secreted outside the cell. Materials to be packaged in the form of vesicles from the ER fuse with the cis face of the Golgi apparatus and move towards the maturing face.

Topic: Biology, Cell - The Unit of Life, NEET
In the given pedigree, indicate whether the shaded symbols indicate dominant or recessive allele.

Options:
A dominant
B recessive
C codominant
D it can be both recessive or dominant.

The correct answer is:
it can be both recessive or dominant.

Solution:
The pedigree indicates inheritance of an autosomal trait in which the diseases causing allele can be dominat or recessive. For dominant condition sufferer parent is homozygous dominant and other normal parent is homozygous recessive. For recessive condition normal parent is heterozygous and the sufferer parent is homozygous recessive.

Topic: Biology, Principles of Inheritance and Variation, NEET
In the given polypeptide
Arg–Try–Ile–Asn–Gly
C-terminus amino acid is

Options:
A Gly
B Arg
C Try
D Asn

The correct answer is:
Gly

Solution:
In the given polypeptide Arg–Try–Ile–Asn–Gly C-terminus amino acid is Gly.

Topic: Chemistry, Biomolecules, NEET
In the given progressive wave y = 5 sin (100πt – 0.4πx), where y and x are in m, and t is in s, what is the frequency?

Options:
A 25 Hz
B 50 Hz
C 100 Hz
D 200 Hz

The correct answer is:
50 Hz

Solution:
Correct Option is : (B)
50 Hz

Topic: Chemistry, Waves and Sound, NEET
In the given progressive wave y = 5 sin (100πt – 0.4πx), where y and x are in meters and t is in seconds, what is the amplitude?

Options:
A 5m
B 0.4m
C 100m
D 0.2m

The correct answer is:
5m

Solution:
Correct Option is : (A)
5m

Topic: Chemistry, Waves and Sound, NEET
In the given progressive wave y = 5 sin (100πt – 0.4πx), where y and x are in meters, and t is in seconds, what is the particle velocity amplitude?

Options:
A 100π ms⁻¹
B 200π ms⁻¹
C 300π ms⁻¹
D 500π ms⁻¹

The correct answer is:
500π ms⁻¹

Solution:
Correct Option is : (D)
500π ms⁻¹

Topic: Chemistry, Waves and Sound, NEET
In the given progressive wave y = 5 sin (100πt – 0.4πx), where y and x are in meters and t is in seconds, what is the wavelength?

Options:
A 100π m
B 20 m
C 5 m
D 0.4π m

The correct answer is:
5 m

Solution:
Correct Option is : (C)
5 m

Topic: Chemistry, Waves and Sound, NEET
In the given reaction

Options:
A
B
C
D

The correct answer is:

Solution:
CH3MgBr+CuBr→CH3-Cu
Orange copper gives only conjugate addition.

Topic: Chemistry, Aldehydes and Ketones, NEET
In the given reaction

Options:
A
B
C
D

The correct answer is:

Solution:
Here X is formed as follows

Topic: Chemistry, Hydrocarbons, NEET
In the given reaction

Options:
A Cyclohexanol
B cyclohex-2-en-1-ol
C Cyclohexanone
D Benzene

The correct answer is:
cyclohex-2-en-1-ol

Solution:
It is here X is cyclohex-2-en-1-ol
It is MPV reaction.

Topic: Chemistry, Aldehydes and Ketones, NEET
In the given reaction

Options:
A
B
C
D

The correct answer is:

Solution:
Here A and B are and the reaction is as follows

Topic: Chemistry, Aldehydes and Ketones, NEET
In the given reaction

A and B will respectively be

Options:
A H3C–CH2–CHOandCH3–CH2–CHO
B H3C–CHOandCH3–CH2–CHO
C H3C–CHOandCH3–CHO
D

The correct answer is:
H3C–CHOandCH3–CH2–CHO

Solution:
Compound is β -hydroxy aldehyde hence the reaction is aldol addition. A and B can be known by retro aldol addition as follows

Topic: Chemistry, Aldehydes and Ketones, NEET
In the given reaction,
(A)+(B) → NaOH/Δ C 6 H 5 −CH=CH−CHO
A and B will be

Options:
A C6H5CHO and HCHO
B C6H5CHO and CH3CH2-CHO
C C6H5-CHO and CH3-CHO
D C6H5-CH2-CHO and CH3-CHO

The correct answer is:
C6H5-CHO and CH3-CHO

Solution:
In order to get A and B we shall revert the reaction or break the product

Topic: Chemistry, Aldehydes and Ketones, NEET
In the given reaction
C6H5-CH2-CH2-N⊕(CH3)2-CH2-CH3O⊖H→ Δ  (X) as major product will be

Options:
A C6H5-CH=CH2
B CH2=CH2
C C6H5-CH=CH-CH3
D CH3-CH=CH-CH3

The correct answer is:
CH2=CH2

Solution:
Here ethene is formed as follows

Topic: Chemistry, Amines, NEET
In the given reaction
C6H5–CH=CH–CH3+HCl→X
[X] will be

Options:
A
B
C Cl–C6H4–CH=CH–CH3
D C6H5–CH=CH–CH2Cl

The correct answer is:

Solution:
Here the reaction occurs as follows

Topic: Chemistry, Hydrocarbons, NEET
In the given reaction
C 6 H 5 − C O | | − CH 3 → (ii) H 2 O/ H + (i) C 2 H 8 MgBr (X)
X will be

Options:
A 1° -alcohol
B 2° -alcohol
C Optically inactive 3° -alcohol
D Optically active 3° -alcohol

The correct answer is:
Optically active 3° -alcohol

Solution:
Here X is an optically active 3° -alcohol and it is formed as follows

Topic: Chemistry, Aldehydes and Ketones, NEET
In the given reaction
C 6 H 5 − CH 2 −Br + AgCN→X (major product)
[X] will be

Options:
A C6H5-CH2CN
B C6H5-CH2NC
C C6H5CH2CONH2
D C6H5CONH2

The correct answer is:
C6H5-CH2NC

Solution:
In this reaction the major product is C6H5-CH2NC and minor is C6H5-CH2CN

Topic: Chemistry, Haloalkanes and Haloarenes, NEET
In the given reaction
C 6 H 5 − CH 2 − CH 3 → NBS X → Alc.KOH/Δ Y
In the given reaction X and Y respectively are

Options:
A C6H5-CHBr-CH3 and C6H5-C≡CH
B C6H5-CBr2-CH3 and C6H5-C≡CH
C C6H5-CBr2-CH3 and C6H5-CBr=CH2
D C6H5-CHBr-CH3 and C6H5-CH=CH2

The correct answer is:
C6H5-CHBr-CH3 and C6H5-CH=CH2

Solution:
Here X and Y are 2-bromo-2-phenylethane and vinyl benzene (Styrene) respectively

Topic: Chemistry, Haloalkanes and Haloarenes, NEET
In the given reaction C 6 H 5 CH 2 COOH â ii P 2 O 5 i NH 3 /Î X
X will be

Options:
A C6H5-CH2COONH4
B C6H5-CH2CONH2
C C6H5-CH2-CN
D C6H5CN

The correct answer is:
C6H5-CH2-CN

Solution:
Here X is benzyl cyanide and prepared as follows

Topic: Chemistry, Carboxylic Acid Derivatives, NEET
In the given reaction
C 6 H 5 âOH â H 2 SO 4 X as majorâproduct â Î i âNaOHâ Y . 'Y' is

Options:
A
B
C
D

The correct answer is:

Solution:
Here the final product is 1, 4-dihydroxy benzene (Quinol)

Topic: Chemistry, Alcohols Phenols and Ethers, NEET
In the given reaction
CH3–C≡CH→HOBrX
[X] will be

Options:
A
B
C
D

The correct answer is:

Solution:

Topic: Chemistry, Hydrocarbons, NEET
In the given reaction
CH3-CH2-Br→Na/dryetherProduct , product will be

Options:
A Pure n-butane
B Mixture of butane and hydrogen
C Mixture of butane, ethene and ethane
D Mixture of ethene and ethane

The correct answer is:
Mixture of butane, ethene and ethane

Solution:

Topic: Chemistry, Haloalkanes and Haloarenes, NEET
In the given reaction
CH3–CH2–C≡N→iCH3MgClX [X] will be

Options:
A
B
C
D

The correct answer is:

Solution:
Here butan-2-one is formed as follows

Topic: Chemistry, Amines, NEET
In the given reaction
CH3-CHO→3HCHO/dil.Na2CO3(X) , 'X' will be

Options:
A HOCH2-CH2-CHO
B
C
D

The correct answer is:

Solution:
The reaction is aldol addition between acetaldehyde and formaldehyde and the product is formed as follows.

Topic: Chemistry, Aldehydes and Ketones, NEET
In the given reaction
CH3-CN+CH3CHO→NaNH2/NH3(l)(X) , (X) will be

Options:
A
B
C
D

The correct answer is:

Solution:

Topic: Chemistry, Aldehydes and Ketones, NEET
In the given reaction

CH3MgBr+D2O→(X),

(X) will be

Options:
A CH4
B CH3D
C CH2D2
D CH3OH

The correct answer is:
CH3D

Solution:
Here X is CH3D

Topic: Chemistry, General Organic Chemistry, NEET
In the given reaction
CH 2 Br | −CH= CH 2 → NaNH 2 /Δ (X)
X will be

Options:
A CH3-C≡CH
B CH2=C=CH2
C CH 3 −C≡ C − N ⊕ a
D CH2=C=CHNa!⊕

The correct answer is:
CH 3 −C≡ C − N ⊕ a

Solution:
Here X is CH 3 âCâ¡ C â N â a which is formed as follows
Br− CH 2 −CH= CH 2 → N − H 2 CH 2 =C= CH 2 → Rearrangement CH 3 −C≡CH → NaNH 2 CH 3 −C≡ C − N ⊕ a

Topic: Chemistry, Hydrocarbons, NEET
In the given reaction
CH 3 –C≡N → H 2 O/Δ A → Δ H 2 O/ H + (B) (A) and (B) respectively are

Options:
A and CH3COOH
B CH3COONH4 and CH3COOH
C CH3CONH2 and CH3COONH4
D CH3–CH=NH and CH3COOH

The correct answer is:
and CH3COOH

Solution:
Here A is acetamide and B is acetic acid as follows

Topic: Chemistry, Amines, NEET
In the given reaction

CH 3 −C≡N → (i)  CH 3 MgBr (excess) (X)

(X) will be

Options:
A
B
C
D

The correct answer is:

Solution:
Here X is acetone

Topic: Chemistry, Amines, NEET
In the given reaction
CH 3 − CH 2 −Br → Moist  Ag 2 O [X]
[X] will be

Options:
A Ethanol
B Diethyl ether
C Propane
D Propyne

The correct answer is:
Ethanol

Solution:
When ethyl bromide reacts with moist Ag2O to give ethanol
CH3-CH2-Br→MoistCH3-CH2-OH+AgBr

Topic: Chemistry, Haloalkanes and Haloarenes, NEET
In the given reaction
CH3−CH2−CBr|H−CH=CH2→Alc.KOH/ΔX
X will be

Options:
A CH3-CH2-CH=C=CH2
B CH2=CH-CH2-CH=CH2
C CH3-CH=CH-CH=CH2
D CH3-CH2-CH2-C≡CH

The correct answer is:
CH3-CH=CH-CH=CH2

Solution:
Here X is penta-1,3-di-ene
CH3-CH2Î²-CH|BrÎ±-CH=CH2âAlc.KOH/ÎCH3-CH=CH-CH=CH2Conjugate diene

Topic: Chemistry, Hydrocarbons, NEET
In the given reaction
CH 3 − CH 2 − CH 2 −O− CH 2 − CH 3 → Conc. HI X + Y
X and Y will respectively be

Options:
A CH3-CH2-CH2OH and CH3-CH2-I
B CH3-CH2-CH2-I and CH2-CH2-OH
C CH3-CH2-CH2-I and CH2=CH2
D CH3-CH=CH2 and CH2=CH2

The correct answer is:
CH3-CH2-CH2OH and CH3-CH2-I

Solution:
Here X is propanol and Y is ethyl chloride
Reaction will occur by S N 2 mechanism hence Nu − will attack at less crowded α -carbon

Topic: Chemistry, Alcohols Phenols and Ethers, NEET