datavorous/entrance-exam-dataset huggingface dataset:
For a zero order reaction, the plot of concentration versus time is linear with

Options:
A positive slope with zero intercept
B positive slope with non- zero intercept
C negative slope with non- zero intercept
D parallel to time axis.

The correct answer is:
negative slope with non- zero intercept

Solution:
For a zero order reaction, A→B ,
Rate=-d[A]dt=k or -d[A]=k.dt
When t=0,[A]=[A]0 and t=t,[A]=[A]
Hence -∫[A]0[A]d[A]=k∫(t=0)(t=t)dt
[A]0-[A]=kt
Or [A]=[A]0-kt
Thus the plot of [A] versus t is linear with negative slope and intercept [A]0 .

Topic: Chemistry, Chemical Kinetics, NEET
For a zero order reaction will the molecularity be equal to zero? Explain.

Options:
A Yes, the molecularity can always be zero or a fractional number.
B No, the molecularity is always equal to zero in a zero order reaction.
C Yes, the molecularity is always equal to one in a zero order reaction.
D No, the molecularity can never be zero or a fractional number.

The correct answer is:
No, the molecularity can never be zero or a fractional number.

Solution:
Correct Option is : (D)
No, the molecularity can never be zero or a fractional number.

Topic: Chemistry, Chemical Kinetics, NEET
For a zero-order reaction, what is the relationship between the half-life (t1/2) and the initial concentration of the reactants?

Options:
A They are directly proportional.
B They are inversely proportional.
C They are equal to each other.
D They are unrelated.

The correct answer is:
They are directly proportional.

Solution:
For a zero-order reaction, the half-life (t1/2) is directly proportional to the initial concentration of the reactants.

Topic: Chemistry, Chemical Kinetics, NEET
For adiabatic reversible expansion of an ideal gas the expression relating pressure and volume of the gas is-

Options:
A P1V1=P2V2
B P1V1Tl=P2V2T2
C P1V1γ=P2V2γ
D P=1v

The correct answer is:
P1V1γ=P2V2γ

Solution:
For adiabatic expansion of ideal gas the relationship between â²Pâ² & â²Vâ² is P V γ =constant
So P1V1Î³=P2 V2Î³ ,where Î³=Poissonâ²s ratioCPCV

Topic: Chemistry, Thermodynamics (C), NEET
For adsorption of gas on solid surface, the plots of logxm vs. log P is linear with a slope equal to

Options:
A K
B log K
C 1/nK
D 1/n (n being integer)

The correct answer is:
1/n (n being integer)

Solution:
logxm=logK+1nlogP
This is Freundlich isotherm. On comparing it with y = mx + C
It is clear that slope = 1n .

Topic: Chemistry, Surface Chemistry, NEET
For adsorption of gas on solid surface, the plots of log x/m vs log P is linear with a slope equal to

Options:
A K
B log K
C 1/nK
D 1/n (n being integer)

The correct answer is:
1/n (n being integer)

Solution:
logxm=logK+1nlogP
This is Freundlich isotherm
Thus, slope = 1/n.

Topic: Chemistry, Surface Chemistry, NEET
For an adiabatic process, the relation between U, P and V for an ideal gas is U=2+3 PV. The gas is

Options:
A Monoatomic
B Diatomic
C Neither monatomic nor diatomic
D Either monoatomic or diatomic

The correct answer is:
Neither monatomic nor diatomic

Solution:
For an adiabatic process
dQ=0=dU+dW
or 0=dU+PdV
From the given equation
dU=3 (PdV+VdP)
∴ 0=3 (PdV+V dP)+PdV
or 4P (dV)+3V (dP)=0
or 4 dV V = - dP P
On integrating, we get
ln (V4)+ln (P3) = constant
or PV43 = constant
i.e., γ = 4 3
i.e., gas is polyatomic.

Topic: Physics, Thermodynamics, NEET
For an electron in the second orbit of Bohr's model of hydrogen atom, the moment of linear momentum is

Options:
A nÏ
B 2Ïh
C 2hÏ
D hπ

The correct answer is:
hπ

Solution:
The moment of linear momentum is angular momentum
L = mvr = nh2π
Here, n=2
∴ L=2h2π= hπ

Topic: Physics, Atomic Physics, NEET
For an element in which impurities have chemical properties close to the properties of that element, which refining method would you suggest?

Options:
A Zone Refining
B Liquation
C Distillation
D Fractional Crystallization

The correct answer is:
Zone Refining

Solution:
Correct Option is : (A)
Zone Refining

Topic: Chemistry, General Principles and Processes of Isolation of Metals, NEET
For an endothermic reaction:
(A) $\mathrm{qp}_{\mathrm{p}}$ is negative.
(B) $\Delta_r H$ is positive.
(C) $\Delta_r \mathrm{H}$ is negative.
(D) $\mathrm{q}_{\mathrm{p}}$ is positive.
Choose the correct answer from the options given below:

Options:
A B and D
B C and D
C A and B
D A and C

The correct answer is:
B and D

Solution:
For endothermic reactions,
$\Delta \mathrm{H}_{\mathrm{r}}=$ positive (Heat is absorbed)
$\Delta H=E_{a(f)}-E_{a(b)}$

Topic: Chemistry, Thermodynamics (C), NEET, NEET 2024 (Re-NEET)
For an endothermic reaction, energy of activation is $E_a$ and enthalpy of reaction is $\Delta H$ (both of these in $\mathrm{kJ} / \mathrm{mol}$ ). Minimum value of $E_a$ will be

Options:
A less than $\Delta \mathrm{H}$
B equal to $\Delta \mathrm{H}$
C more than $\Delta \mathrm{H}$
D equal to zero

The correct answer is:
more than $\Delta \mathrm{H}$

Solution:
Key Idea In endothermic reactions, energy of reactants is less than that of the products.
Potential energy diagram for endothermic reactions is,
where, $\mathrm{E}_{\mathrm{a}}=$ activation energy of forward reaction
$\mathrm{E}_{\mathrm{a}}^{\prime}=$ activation energy of backward reaction
$\Delta \mathrm{H}=$ enthalpy of the reaction
From the above diagram,
$$
\mathrm{E}_{\mathrm{a}}=\mathrm{E}_{\mathrm{a}}^{\prime}+\Delta \mathrm{H}
$$
Thus, $\mathrm{E}_{\mathrm{a}}>\Delta \mathrm{H}$

Topic: Chemistry, Chemical Kinetics, NEET, NEET 2010 (Screening)
For an exothermic reaction, following two steps are involved.

Step 1. A + B â I slow Step 2. I â AB fast

Which of the following graphs correctly represent this reaction ?

Options:
A
B
C
D

The correct answer is:

Solution:
In any reaction mechanism the no. of activated complexes showing maxima of potential energies is the no. of steps in that mechanism and in between these maxima is a valley where lies a more stable intermediate. There is one reaction intermediate lying at valley of two maxima representing two steps. Ea for first step should be higher than second step as first is slow step. These requirements fulfilled by choice (ii) & not choice (i) the choice (iv) is not possible because that is for endothermic reaction Δ H + ve & (ii) is single step equation so not possible.

Topic: Chemistry, Chemical Kinetics, NEET
For an ideal binary liquid solution with PAo>PBo which relation between XA (mole fraction of A in liquid phase) and YA (mole fraction of A in vapour phase) is correct, XB and YB are mole fraction of B in liquid and vapour phase respectively

Options:
A XA=YA
B XA>YA
C XAXB<YAYB
D XA,YA,XB and YB cannot be correlated

The correct answer is:
XAXB<YAYB

Solution:
PA'=PAo.XA=PM.YA
PB'=PBo.XB=PM.YB
So PAoPBo.XAXB=YAYB
Hence PAoPBo>1
So XAXB<YAYB .

Topic: Chemistry, Solutions, NEET
For an ideal gas, consider only P – V work in going from an initial state X to the final state Z. The final state Z can be reached by either of the two paths shown in the figure. Which of the following set choice is correct? (take ΔS as change in entropy and W as work done)

(1)Wx→y→z=Wx→y
(2)ΔSx→y→z=ΔSx→y
(3)ΔSx→z=ΔSx→y+ΔSy→z
(4)Wx→z=Wx→y+Wy→z

Options:
A 1,2
B 1,3
C 2,3
D 1,2,3

The correct answer is:
1,3

Solution:
Since entropy is a state function
ΔSX→Z=ΔSX→Y+ΔSY→Z
Now WY→Z=0 (for isochoric)
WX→Y→Z=WX→Y

Topic: Chemistry, Thermodynamics (C), NEET
For an ideal gas, number of moles per litre in terms of its pressure P, gas constant R and temperature T is

Options:
A PTR
B PRT
C PRT
D RTP

The correct answer is:
PRT

Solution:
We know PV=nRT
Number of moles per litre i.e. nV=PRT

Topic: Chemistry, States of Matter, NEET
For an ideal gas, the specific heat capacity during an isentropic process is always

Options:
A zero
B infinite
C positive
D negative

The correct answer is:
zero

Solution:
A gas if fully insulated from the surroundings while undergoing adiabatic change. That is, no exchange of heat between the gas and surroundings. Hence, specific heat is zero.

Topic: Physics, Thermodynamics, NEET
For an ideal solution of two components A and B, which of the following is true?

Options:
A Δ H mixing > 0 (zero)
B A-B interaction is stronger than A-A and B-B interactions
C A-A, B-B and A-B interactions are identical
D Δ H mixing < 0 (zero)

The correct answer is:
A-A, B-B and A-B interactions are identical

Solution:
When two components A and B form an ideal solution, the interactions A – A, B – B and A – B are similar due to identical molecular sizes of species A and B.

Topic: Chemistry, Solutions, NEET
For an ideal solution, the correct option is:

Options:
A ∆mix S=0 at constant T and P
B ∆mix V≠0 at constant T and P
C ∆mix H=0 at constant T and P
D ∆mix G=0 at constant T and P

The correct answer is:
∆mix H=0 at constant T and P

Solution:
For an ideal solution,

ΔHmix=0, also ΔVmix=0

At constant temperature and pressure.

Topic: Chemistry, Solutions, NEET, NEET 2019 (All India)
For an ideal step-down transformer, the quantity which is constant for both the coils is

Options:
A Current in the coils
B Voltage across the coils
C Resistance of coils
D Power in the coils

The correct answer is:
Power in the coils

Solution:
For an ideal step-down transformer power is constant for both the coils.
i.e., Input power = Output power
∴     VpIp=VsIs or VpVs=IsIp

Topic: Physics, Alternating Current, NEET
For an interference pattern, the maximum and minimum intensity ratio is 64:1, then what will be the ratio of amplitudes?

Options:
A 8:1
B 9:7
C 1:8
D 7:9

The correct answer is:
9:7

Solution:
Since, we know,
ImaxImax=a1a2+1a1a2-12
Given, ImaxImin=641
⇒641=a1+a2a1-a22
⇒a1+a2a1-a2=8
⇒a1a2=8+18-1=97
∴ a1a2=97

Topic: Physics, Wave Optics, NEET
For an ionic compound lattice energy depends upon

Options:
A Size of the ion only
B Charge on the ion only
C Packing of ions only
D Charge on the ion and size of the ion

The correct answer is:
Charge on the ion and size of the ion

Solution:
The value of lattice energy depends on the charges present on the two ions and distance between them. It shall be high if charges are high and ionic radii are small.

Topic: Chemistry, Chemical Bonding and Molecular Structure, NEET
For an ionic crystal of the general formula A+B- and coordination number 6:6 , the radius ratio will be

Options:
A greater than 0.73
B between 0.41 and 0.73
C between 0.41 and 0.22
D less than 0.22

The correct answer is:
between 0.41 and 0.73

Solution:
For an ionic crystal of the general formula A+B- and coordination number, 6:6 the radius ratio will be between 0.41 and 0.73. For e.g. NaCl etc.

Topic: Chemistry, Solid State, NEET
For an isolated system, ∆U = 0, what will be ∆S ?

Options:
A ∆S = 0
B ∆S < 0
C ∆S > 0
D ∆S cannot be calculated

The correct answer is:
∆S > 0

Solution:
Correct Option is : (C)
∆S > 0

Topic: Chemistry, Thermodynamics (C), NEET
For an object thrown at 45° to horizontal, the maximum height (H) and horizontal range (R) are related as

Options:
A R=16H
B R=8H
C R=4H
D R=2H

The correct answer is:
R=4H

Solution:
The range of particle is
R=u2sin2Î¸g at = 4 5 o ; R = u 2 g ...(1)
H = u 2 sin 2 Î¸ 2 g at = 4 5 o ; H = u 2 4 g ...(2)
Dividing Eqs. (i) by Eq. (ii),
R = 4H

Topic: Physics, Motion In Two Dimensions, NEET
For an octahedral complex, which of the following d-electron configuration will give minimum CFSE?

Options:
A High spin with d6 configuration
B Low spin with d4 configuration
C Low spin with d5 configuration
D High spin with d7 configuration

The correct answer is:
Low spin with d5 configuration

Solution:
For octachedral complex CFSE=nt2gÃâ0.4Î0+neg+ 0.6Î0
A. High spin with d6 configuration t2g4 and eg2 CFSE = - 0.4 Î0
B. Low spin with d4 configuration t2g4 and eg0 CFSE = - 1.6 Î0
C. Low spin with d5 configuration t2g5 and eg0 CFSE = - 2 Î0
D. High spin with d7 configuration t2g5 and eg2 CFSE = - 0.8 Î0

Topic: Chemistry, Coordination Compounds, NEET
For an SN2 reaction of the most effective nucleophile will be

Options:
A MeO-
B
C Me2CHOΘ
D Me2CH2O-

The correct answer is:
MeO-

Solution:
As nucleophile becomes bulkier its backside approach to the displacement site is retarded.
Negative charge on -O in all hence weak base is good lg. and less hindered anion is good nucleophile .

Topic: Chemistry, Haloalkanes and Haloarenes, NEET
For angles of projection of projectile at angle $\left(45^{\circ}-\theta\right)$ and $\left(45^{\circ}+\theta\right)$, the horizontal range described by the projectile are in the ratio of:

Options:
A $2: 1$
B $1: 1$
C 2:3
D $1: 2$

The correct answer is:
$1: 1$

Solution:
Horizontal range
$$
=R=\frac{u^2 \sin ^2 \theta}{g}
$$
When angle of projection is $\left(45^{\circ}-\theta\right)$ then
$$
\begin{aligned}
R_1 & =\frac{u^2 \sin 2\left(45^{\circ}-\theta\right)}{g} \\
& =\frac{u^2 \sin \left(90^{\circ}-\theta\right)}{g} \\
& =\frac{u^2 \cos 2 \theta}{g}
\end{aligned}
$$
Now $\quad \frac{R_1}{R_2}=\frac{u^2 \cos \frac{2 \theta}{8}}{u^2 \cos \frac{2 \theta}{g}}=1: 1$

Topic: Physics, Motion In Two Dimensions, NEET, NEET 2006
For any arbitrary motion in space, which of the following relation is true :

Options:
A ${{v}_{average}}=~\frac{1}{2}\left( v\left( {{t}_{1}} \right)-v\left( {{t}_{2}} \right) \right)$
B ${{v}_{average}}=~\frac{r\left( {{t}_{2}} \right)-r\left( {{t}_{1}} \right)}{\left( {{t}_{2}}-{{t}_{1}} \right)}$
C $v\left( t \right)={{v}_{0}}+at$
D $r\left( t \right)={{r}_{0}}+{{v}_{0}}t+\frac{1}{2}at$

The correct answer is:
${{v}_{average}}=~\frac{r\left( {{t}_{2}} \right)-r\left( {{t}_{1}} \right)}{\left( {{t}_{2}}-{{t}_{1}} \right)}$

Solution:
Correct Option is : (B)
${{v}_{average}}=~\frac{r\left( {{t}_{2}} \right)-r\left( {{t}_{1}} \right)}{\left( {{t}_{2}}-{{t}_{1}} \right)}$

Topic: Chemistry, Motion In Two Dimensions, NEET
For any material, if R, T and A represent the reflection coefficient, transparent coefficient and absorption coefficient respectively, then for a blackbody which one of the following is true

Options:
A R=1, T=0, A=0
B R=0, T=1, A=1
C R=0, T=0, A=1
D R=0, T=1, A=0

The correct answer is:
R=0, T=0, A=1

Solution:
∵ Relation between R, T and A is
A+T+R=1 ...(i)
∵ For ideal blackbody,
A=1
∴ According Equation (i),
R=0, T=0 and A=1

Topic: Physics, Thermal Properties of Matter, NEET
For c=2a and a<b<c, the magnetic field at the point P will be zero when

Options:
A a=b
B a= 3 5 b
C a= 5 3 b
D a= 1 3 b

The correct answer is:
a= 5 3 b

Solution:
Magnetic field at the centre
b = Î¼ 0 I 2 c â + Î¼ 0 I 2 b 3 4 â + Î¼ 0 I 2 a 3 4 â
As per problem :
0 = Î¼ 0 I 2 1 c - 3 4 b + 3 4 a â 3 4 1 b - 1 a = 1 c
If c=2a,
3 4 1 b - 1 a = 1 2 a â a = 5 3 b

Topic: Physics, Magnetic Effects of Current, NEET
For certain metal, incident frequency Î½ is five times threshold frequency Î½ 0 and the maximum velocity of the photoelectrons is 8 Ã 106 m s-1. If Î½ = 2 Î½ 0 , the maximum velocity of photoelectrons will be

Options:
A 4Ã106 m s-1
B 6Ã106 m s-1
C 8Ã106 m s-1
D 1Ã106 m s-1

The correct answer is:
4Ã106 m s-1

Solution:
According to Einstein's photoelectric equation
hv = hv 0 + 1 2 mv max 2
or 1 2 mv max 2 = hâ¡ vâ¡ - hâ¡ vâ¡ 0
According to the given problem
12mâ¡8Ã1062=hâ¡5vâ¡0-vâ¡0â¦i
1 2 mâ¡ v max 2 = hâ¡ 2 vâ¡ 0 - vâ¡ 0 â¦ i i
Dividing equation (i) by (ii)
8 Ã 1 0 6 2 v max 2 = 4 vâ¡ 0 vâ¡ 0
v max 2 = 8 Ã 1 0 6 2 4
vmax=8Ã1062=4Ã106 m sec-1

Topic: Physics, Dual Nature of Matter, NEET
For chemical defence against herbivores, Calotropis has

Options:
A toxic ricin
B distasteful quinine
C cardiac glycosides
D strychnine

The correct answer is:
cardiac glycosides

Solution:
For chemical defence against herbivores, Calotropis has highly poisonous cardiac glycosides.

Topic: Biology, Organisms and Populations, NEET, NEET 2023 (Manipur)
For coagulation of arsenious sulphide sol, which one of the following salt solution will be most effective

Options:
A AlCl3
B NaBr
C BaCl2
D Na3PO4

The correct answer is:
AlCl3

Solution:
Arsenious sulphide is –ve charged colloid so activated ion of electrolyte is cation. Cation having maximum positive charge will be most effective for coagulation, (Hardy Schulz rule).
Al3+>Ba2+>Na+ (coagulating power)

Topic: Chemistry, Surface Chemistry, NEET
For common emitter transistor amplifier, the audio signal voltage across the collector resistance of 2 kÎ© is 4 V. If the current amplification factor of the transistor is 100 and the base resistance is 1 kÎ© then the input signal voltage is

Options:
A 10  mV
B 20ââmV
C 30  mV
D 15  mV

The correct answer is:
20  mV

Solution:
RC=2 kΩ V0=4 V
IC=V0Rc=4 V2 kΩ=2 mA
β=ICIB=100
⇒IB=IC100=2×10-5 A
Vin=IBRi=2×10-5×1 kΩ=20 mV

Topic: Physics, Semiconductors, NEET, NEET 2016 (Phase 2)
For Daniell cell,
Zn(s)+Cu2+(aq)⇌Cu(s)+Zn2+(aq)
The reaction quotient Q is given by
Q=[Zn2+][Cu2+]

OA = 1.10 volt
Where Ecell=1.1591 volt, then

Options:
A Q = 0.01
B Q = 100
C Q = 0.1
D Q = 1

The correct answer is:
Q = 0.01

Solution:
E=E°-0.059nlog10Q
For Daniell cell, E°=1.10 V (equal to OA)
E=1.10-0.0592log0.01
=+1.159 V

Topic: Chemistry, Electrochemistry, NEET
For dry cleaning, in the place of tetrachloroethane, liquefied carbon dioxide with suitable detergent is an alternative solvent. What type of harm to the environment will be prevented by stopping use of tetrachloroethane?

Options:
A Replacement of halogenated solvent by liquid CO2will result in less harm to air.
B Replacement of halogenated solvent by liquid CO2will result in less harm to groundwater.
C Replacement of halogenated solvent by liquid CO2will result in less harm to birds and insects
D Replacement of halogenated solvent by liquid CO2does not change anything

The correct answer is:
Replacement of halogenated solvent by liquid CO2will result in less harm to groundwater.

Solution:
Correct Option is : (B)
Replacement of halogenated solvent by liquid CO2will result in less harm to groundwater.

Topic: Chemistry, Environmental Chemistry, NEET
For each molecule of glucose formed in plants, the number of molecules of ATP and NADPH2 required, respectively, are

Options:
A 12 and 18
B 18 and 12
C 15 and 10
D 3 and 22

The correct answer is:
18 and 12

Solution:
Six turns of Calvin cycles are required to form one glucose molecule. Thus to fix 6 CO2 molecules 18 ATP and 12 NADPH2 are required.

Topic: Biology, Photosynthesis in Higher Plants, NEET
For effective functioning of PS II, the ions required are

Options:
A Mn+, Cl-
B Mg+ and NO-3
C Fe+ and Cl-
D K+ and Na+

The correct answer is:
Mn+, Cl-

Solution:
The photosystem is the reaction center that is surrounded by a light-harvesting complex. Photosystem II takes place in the inner membrane of the thylakoid membrane. The reaction center in PSII is P680. They pass high energy electrons to the electron transport chain. For effective functioning of PSII, Manganese ion and chloride ion are required for the proper function of an enzyme.

Topic: Biology, Photosynthesis in Higher Plants, NEET
For effective treatment of the disease, early diagnosis and understanding its pathophysiology is very important. Which of the following molecular diagnostic techniques is very useful for early detection?

Options:
A Western Blotting Technique
B Southern Blotting Technique
C ELISA Technique
D Hybridization Technique

The correct answer is:
ELISA Technique

Solution:
For effective treatment of a disease, early diagnosis and understanding its pathophysiology is very important. Using conventional methods of diagnosis (serum and urine analysis, etc.) early detection is not possible. Recombinant DNA technology, Polymerase Chain Reaction (PCR) and Enzyme-Linked Immunosorbent Assay (ELISA) are some of the techniques that serve the purpose of early diagnosis.

Topic: Biology, Biotechnology and Its Applications, NEET, NEET 2021
If 0.1 M solution of glucose and 0.1 M solution of urea are placed on two sides of the semipermeable membrane to equal heights, then it will be correct to say that

Options:
A there will be no net movement across the membrane
B glucose will flow towards urea solution
C urea will flow towards glucose solution
D water will flow from urea solution to glucose

The correct answer is:
there will be no net movement across the membrane

Solution:
There is no net movement of the solvent through the semipermeable membrane between two solutions of equal concentration.

Topic: Chemistry, Solutions, NEET
If 0.1 mol of salt is added to 1 L water, which of these salts expected to produce the most acidic solution?

Options:
A NaC2H3O2
B NH4NO3
C CuSO4
D AlCl3

The correct answer is:
NH4NO3

Solution:
NH4NO3 is salt of very weak base and very strong acid hence it will produce most acidic solution on hydrolysis. Aqueous solutions of CuSO4 and AlCl3 are also acidic.

Topic: Chemistry, Ionic Equilibrium, NEET
If 2n=12, the number of chromosomes in nucellus, integument and egg cell would be:

Options:
A 12, 12, 6
B 12,Â 18,Â 24
C 12,Â 12,Â 12
D 12,Â 12,Â 24

The correct answer is:
12, 12, 6

Solution:
Sporophytic phase or diploid phase: Root, Stem, Leaf, Flower, stamen, ovary, ovule's cell such as nucellus cell, integument, funiculus etc. are all diploid.
Gametophytic generation or haploid phase: This phase includes microspore, generative cell, tube cell, megaspore, antipodal cell, egg cell etc.

Topic: Biology, Sexual Reproduction in Flowering Plants, NEET
If 0.3 mole Zn are added to HCl containing 0.52 mole of HCl, how many moles of H2 are produced, according to the reaction
Zn(s)+2HCl(a)→ZnCl2(a)+H2(g)

Options:
A 1 mole
B 2 mole
C 0.8 mole
D 0.26 mole

The correct answer is:
0.26 mole

Solution:
Zn(s)+2HCl(a)→ZnCl2(a)+H2(g)
As we have 0.30 mole of Zn, therefore, HCl will react completely, i.e., HCl is the limiting reactant.
2 moles of HCl produce H2=1 mole
So 0.52 mole of HCl will produce
H2=12×0.52 mole
=0.26 mole

Topic: Chemistry, Some Basic Concepts of Chemistry, NEET
If 0.5 mole of BaCl2 is mixed with 0.2 mole of Na3PO4, the maximum number of moles of Ba3PO42 that can be formed is

Options:
A 0.7
B 0.5
C 0.03
D 0.10

The correct answer is:
0.10

Solution:
3â BaCl 2 3 mol + 2â Na 3 PO 4 2 mol â Ba 3 PO 4 2 1 mol +â6âNaCl
Here, Na 3 PO 4 is the limiting reactant.
2 moles of Na 3 PO 4 gives 1 mole of Ba 3 PO 4 2
So, 0.2 mole of Na 3 PO 4 will give 0.1 mole of Ba 3 PO 4 2

Topic: Chemistry, Some Basic Concepts of Chemistry, NEET
If '8' Drosophila in a laboratory population of '80' died during a week, the death rate in the population is ____ individuals per Drosophila per week.

Options:
A 10
B 1.0
C zero
D 0.1

The correct answer is:
0.1

Solution:
Mortality rate, or death rate, is a measure of the number of deaths in a particular population, scaled to the size of that population, per unit of time.
Death rate in the population is \(=\frac{8}{80}=0.1\)

Topic: Biology, Organisms and Populations, NEET, NEET 2022 (Phase 1)
If 8 g of a non-electrolyte solute is dissolved in 114 g of n-octane to reduce its vapour pressure to 80%, the molar mass (in g mol-1) of the solute is [Given that molar mass of n-octane is 114 g mol-1]

Options:
A 40
B 60
C 80
D 20

The correct answer is:
40

Solution:
Assuming dilute solution,
P0-PsPs≈P0-PsP0=nsolute nsolvent
Let P0=100, V.P reduced to 80%,∴Ps=80
100-80100=8/m114/114
m=40 g/mol.

Topic: Chemistry, Solutions, NEET, NEET 2020 (Phase 2)
If 10% of a radioactive substance decays in 5 years, then the percentage of the substance that will have decayed in 20 years, will be

Options:
A 40%
B 50%
C 65.6%
D 34.4%

The correct answer is:
34.4%

Solution:
N N 0 = e −λt
10100=e-λ5
N N 0 = e −λ20
ln 10 100 ln N N 0 = 5 20
N N 0 =0.656
∴ The fraction of material decayed is
=1-0.656=0.344
=34.4%

Topic: Physics, Nuclear Physics, NEET
If 10 volumes of dihydrogen gas react with five volumes of dioxygen gas, how many volumes of water vapour would be produced?

Options:
A 8 volumes of water vapour
B 4 volumes of water vapour
C 10 volumes of water vapour
D 12 volumes of water vapour

The correct answer is:
10 volumes of water vapour

Solution:
Correct Option is : (C)
10 volumes of water vapour

Topic: Chemistry, Some Basic Concepts of Chemistry, NEET