datavorous/entrance-exam-dataset huggingface dataset:
The resistor in which maximum heat will be produced is

Options:
A 6 Ω
B 2 Ω
C 5 Ω
D 4 Î©

The correct answer is:
4 Î©

Solution:
3 Ω, 6 Ω and 2 Ω resistances are in parallel. So, the potential drop across them will be equal. Of these, three resistances maximum heat will be generated across 2 Ω resistance
H=V2Rt or H∝1R
Similarly, 5 Ω and 4 Ω resistances are also in parallel so, more heat will be generated across 4 Ω resistor. Now the given circuit can be redrawn as :

V1V2=1209=920
∴ V1=929V
and V2=2029V
Power developed across 2 Ω resistor will be
P1=V122=9292V2
and power developed across 4 Ω resistor is
P2=V222=20292V4>P1
∴ Maximum heat is generated across 4 Ω resistance.

Topic: Physics, Current Electricity, NEET
The resonant frequency of a series AC circuit consisting of a 200 Î¼H inductor, a 0.0005 Î¼F capacitor and a 10 Î© resistance is

Options:
A 480 kHz
B 503 kHz
C 406 kHz
D 607 kHz

The correct answer is:
503 kHz

Solution:
The resonant frequency =f=12π LC
f=12π200×10-6×0.0005×10-6
f=503 kHz

Topic: Physics, Alternating Current, NEET
The respiratory organs of a whale are

Options:
A book lungs
B lungs
C gills
D skin

The correct answer is:
lungs

Solution:
Animals are classified as Non chordates or Chordates depending on absence and presence of notochord. Chordates can be Protochordates that include Cephalochordates and Urochordates as well as Vertebrates. Vertebrates are further classified as Pisces and Tetrapods depending on the locomotory organs. Tetrapods include Class Amphibia, Reptilia, Aves and Mammalia. Mammals are those animals that have mammary glands. These animals have well developed respiratory organs i.e. lungs. Whale being a mammal too has lungs.Lungs help to take in atmospheric oxygen easily.

Topic: Biology, Breathing and Exchange of Gases, NEET
The respiratory organs of flatworms, birds, frogs and cockroaches respectively are

Options:
A Body Surface, Lungs, Body surface, Tracheal tubes
B Flame cells, Lungs, Body surface, Gills
C Gills, Lungs, Body surface, Spiracles
D Nephridia, Lungs, Gills, Spiracles

The correct answer is:
Body Surface, Lungs, Body surface, Tracheal tubes

Solution:
Flatworms use body surfaces, Birds use lungs, Frogs use Lungs and Body surface and Cockroaches use tracheal tubes.

Topic: Biology, Breathing and Exchange of Gases, NEET
The respiratory quotient during cellular respiration would depend on the

Options:
A nature of enzymes involved
B nature of the substrate
C amount of carbon dioxide released
D amount of oxygen utilized

The correct answer is:
nature of the substrate

Solution:
R.Q. is the ratio of the volume of CO2 released to the volume of oxygen taken in respiration. It depends on the nature of the substrate, which is oxidized, for carbohydrates R.Q. is one, for fats and protein less than one, and is more than one for organic acids.

Topic: Biology, Respiration in Plants, NEET
The respiratory quotient during cellular respiration would depend on the

Options:
A Nature of enzymes involved
B Nature of the substrate
C Amount of carbon dioxide released
D Amount of oxygen utilized

The correct answer is:
Nature of the substrate

Solution:
RQ is the ration of the volume of carbon dioxide released to the volume of oxygen taken in respiration. It depends on the nature of the substrate, which is oxidised. For carbohydrates RQ is one, for fats and proteins less than one but more than one for organic acids, etc.

Topic: Biology, Respiration in Plants, NEET
The respiratory quotient (RQ) of a germinating castor seed is

Options:
A Equal to one
B Greater than one
C Less than one
D Equal to zero

The correct answer is:
Less than one

Solution:
Respiratory quotient (the ratio between the volume of carbon dioxide liberated to the volume of oxygen absorbed in respiration) is less than one, when fats and proteins are respired. Castor oil is rich in fatty substances.

Topic: Biology, Respiration in Plants, NEET
The restoring force of a spring with a block attached to the free end of the spring is represented by:

Options:
A

B

C

D

The correct answer is:

Solution:
Restoring force of spring,
$\mathrm{F} \propto-x$
(where, $x$ is the displacement)
Only graph (4) is representing the above equation.

Topic: Physics, Laws of Motion, NEET, NEET 2022 (Phase 2)
The restriction endonuclease of a cell does not cleave its own DNA because of

Options:
A the difference in recognition sequences.
B methylation of A or C at the recognition site.
C the property that restriction endonuclease leave the DNA out of the cells.
D of the cell's ability to identify its own restriction endonuclease

The correct answer is:
methylation of A or C at the recognition site.

Solution:
The methylation of adenine or cytosine is the recognition sequence of the DNA protect it from the restriction endonuclease.

Topic: Biology, Biotechnology - Principles and Processes, NEET
The result of the operation 2.5×1.25 should be which of the following on the basis of significant figures?

Options:
A 3.125
B 3.13
C 3.1
D 31.25

The correct answer is:
3.1

Solution:
2.5×1.25=3.125
Since 2.5 has two significant figures, the result should not have more than two significant figures. Hence, the answer will be 3.1.

Topic: Chemistry, Some Basic Concepts of Chemistry, NEET
The resultant force on the current loop PQRS due to a long current carrying conductor will be, if the current flow in the loop is clockwise,

Options:
A 10-4 N
B 3.6Ã10-4 N
C 1.8Ã10-4 N
D 5Ã10-4 N

The correct answer is:
5Ã10-4 N

Solution:
Force on SR and PQ are equal but opposite so their net will be zero.
Force between two parallel conductors carrying currents I1 and I2
F=Î¼02ÏI1I2lr
Where r= distance between two parallel conductors
F PS = 2Ã 10 â7 Ã30Ã20Ã10Ã 10 â2 10 â2
ââââââââ=6Ã 10 â4
F QR = 2Ã 10 â7 Ã30Ã20Ã10Ã 10 â2 12Ã 10 â2
ââââââââ= 10 â4 N
Fnet=FPS-FQR
ââââââââ=6Ã 10 â4
â=5Ã 10 â4 N

Topic: Physics, Magnetic Effects of Current, NEET
The resultant of two forces at right angle is 5 N. When the angle between them is 120o, the resultant is 13 N. Then the forces respectively are,

Options:
A 12 N,13 N
B 20 N,5 N
C 3 N, 4 N
D 40 N,15 N

The correct answer is:
3 N, 4 N

Solution:
Let A and B be the two forces. As per question
A2+B2=5
or A2+B2=25 ----------------------(i)
and A2+B2+2ABcos120Â°=13
or AB=25-13=12
or 2AB=24 ----------------------(ii)
Solving (i) and (ii), we get
A=3 N
and B=4 N

Topic: Physics, Mathematics in Physics, NEET
The reticulate venation is commonly found in the leaves of

Options:
A Maize, barley, sorghum, roses
B Magnolias, roses, hibiscus, Catharanthus
C Barley, china rose, grasses, bamboo
D Funaria, Cycas, magnolia, Catharanthus

The correct answer is:
Magnolias, roses, hibiscus, Catharanthus

Solution:
In reticulate venation, there is a prominent vein called the mid rid from which many small veins arise. They finally form a net-like structure in the lamina, e.g., most of the dicots. Some dicot plants like magnolias, rose, hibiscus etc., show parallel venation.

Topic: Biology, Morphology of Flowering Plants, NEET
The reverse voltage at which the current increases enormously, in a p-n junction, is called

Options:
A Knee voltage
B Breakdown voltage
C Biasing voltage
D Accelerating voltage

The correct answer is:
Breakdown voltage

Solution:
The reverse voltage at which the current increases enormously, in a p-n junction, is called Breakdown voltage.

Topic: Physics, Semiconductors, NEET
The reversible reaction
[Cu(NH3)4]2++SO32-⇌[Cu(NH3)3SO3]+NH3
is at equilibrium. What would not happen if ammonia is added –

Options:
A SO32– would increase
B CuNH33SO3 would increase
C The value of equilibrium constant would not change
D CuNH342+ would increase

The correct answer is:
CuNH33SO3 would increase

Solution:
NH3 is presenting on product side. Hence on adding NH3 , equilibrium shift to backward thus concentration of CuNH33SO3 would decrease.

Topic: Chemistry, Chemical Equilibrium, NEET
The rhinovirus is related to the

Options:
A Respiratory tract infection
B Acute Infection to lungs
C Sexually transmitted diseases
D A member of DNA virus

The correct answer is:
Respiratory tract infection

Solution:
The rhinovirus is the most common viral infectious agent in humans and is the predominant cause of the common cold. Rhinovirus infection proliferates in temperatures of 33â35 Â°C, the temperatures found in the nose. It is an upper respiratory tract infection.

Topic: Biology, Human Health and Diseases, NEET
The ribosomes present in the cytoplasm of the causative organism of cholera and mitochondria of causative organism of malaria, respectively, are

Options:
A 70S and 70S
B 70S and 80S
C 80S and 70S
D 80S and 80S

The correct answer is:
70S and 70S

Solution:
Causative organism of cholera is a bacterium Vibrio cholerae. It is a prokaryote. The causative organism of malaria is Plasmodium which is a protozoan. It is a eukaryote. Ribosomes are the granular structures composed of RNA and proteins. They are not surrounded by any membrane and are seen as dense particles under the electron microscope. Ribosomes found in cytoplasm of eukaryotic organisms are 80S and those in cytoplasm of prokaryotic organisms are 70S, where S is the coefficient of sedimentation and is a measure of the density and size of the ribosome. Mitochondria of eukaryotes also have ribosome which resemble prokaryotes. They are 70S.

Topic: Biology, Cell - The Unit of Life, NEET
The ribs that are directly attached to the sternum are

Options:
A first seven pairs.
B first ten pairs.
C first eight pairs.
D first five pairs.

The correct answer is:
first seven pairs.

Solution:
First seven pairs of ribs are known as true ribs because these are attached to sternum by means of hyaline cartilage.

Topic: Biology, Locomotion and Movement, NEET
The richest sources of vitamin $B_{12}$ are:

Options:
A goat's liver and Spirulina
B chocolate and green gram
C rice and hen's egg
D carrot and chicken's breast.

The correct answer is:
goat's liver and Spirulina

Solution:
Vitamin $B_{12}$ is present in animal protein such as meat, liver, fish and Spirultna (single cell protein). It promotes DNA synthesis, maturation of RBCs and myelin formation.
Related Theory
Vitamin $B_{12}$ (cyanocobalamin) is only vitamin not found in vegetables.

Topic: Biology, Digestion and Absorption, NEET, NEET 2004
The right option for the mass of CO2 produced by heating 20 g of 20% pure limestone is (Atomic mass of Ca=40)

CaCO3→1200 KCaO+CO2

Options:
A 1.32 g
B 1.12 g
C 1.76 g
D 2.64 g

The correct answer is:
1.76 g

Solution:
CaCO3→1200 KCaO+CO2

According to the given equation, 100 grams of calcium carbonate gives 44 grams of carbon dioxide.

Given that 20 grams of 20% pure lime stone, it means the given lime stone contain 4 grams of CaCO3.

Hence, the maximum amount of CO2 produced

=4×44100=1.76 g

Topic: Chemistry, Some Basic Concepts of Chemistry, NEET, NEET 2023 (All India)
The right statement among the following is

Options:
A Lemur and Spotted Cuscus are result of different adaptive radiations.
B Darwin's finches show convergent evolution.
C Flying phalanger and Tasmanian wolf are results of different adaptive radiations.
D Darwin's finches have evolved from insectivorous birds.

The correct answer is:
Lemur and Spotted Cuscus are result of different adaptive radiations.

Solution:
Darwin's finches show divergent evolution. The flying phalanger and Tasmanian wolf are results of the same adaptive radiations. Darwin's finches have evolved from the original seed-eating birds.

Topic: Biology, Evolution, NEET
The ring systems having following characteristics are aromatic. (i) Planar ring containing conjugated π bonds. (ii) Complete delocalisation of the π−electrons in ring system i.e. each atom in the ring has unhybridised p-orbital, and (iii) Presence of (4n+2) π−electrons in the ring where n is an integer (n = 0, 1, 2,...........) [Huckel rule] Using this information classify the following compounds as aromatic.

Options:
A C,D,E and F are Aromatic
B A,B,E and F are Aromatic
C A,C,E and B are Aromatic
D A,C,E and F are Aromatic

The correct answer is:
A,C,E and F are Aromatic

Solution:
Correct Option is : (D)
A,C,E and F are Aromatic

Topic: Chemistry, Hydrocarbons, NEET
The rising of dough is due to

Options:
A Multiplication of yeast
B Production of CO2
C Emulsification
D Hydrolysis of wheat flour starch into sugars.

The correct answer is:
Production of CO2

Solution:
Microbes have been used in everyday food products such as bread, curd, cheese, dosa, etc. Dough used for making breads, dosas, idlis are being treated by certain bactetria which gives them puffed up appearance. The dough used in making idli and dosas are treated by bacteria whereas dough used for making bread is fermented by yeast Saccharomyces cerevisiae. The dough appears to be puffed up due to the production of CO2 in it.

Topic: Biology, Microbes in Human Welfare, NEET
The rms speed of hydrogen molecule at a certain temperature is v. If the temperature is doubled and hydrogen gas dissociates into atomic hydrogen, the rms speed will become

Options:
A v
B v2
C 2v
D 2 v

The correct answer is:
2v

Solution:
Let the molar mass of H2 is M .
Hydrogen gas is dissociated into atomic hydrogen.
It molar mass is equal to M2 .
vrms=3RTM
v1v2=T1MO1ÃMO2T2
T2=2T1 and MO2=MO12=M2
âv1v2=T1M.M/22T1=14
v2=2v1=2v

Topic: Physics, Kinetic Theory of Gases, NEET
The rms speed of N2 molecules is u. If the temperature is doubled and the nitrogen molecules dissociate into nitrogen atoms. Then what will be the new RMS speed?

Options:
A 2u
B 4u
C 14u
D 2 u

The correct answer is:
2u

Solution:
RMS speed =3RTM, Inversely proportional to the molar mass and directly proportional to the temperature.

We can say that for the same mass of the gases rms speed is directly proportional to the number of moles of the gases.

u1u2=n1T1n2T2=nÃT2nÃ2T=14 =12
â´ u2=2u1
Therefore, in case the temperature is doubled and the nitrogen molecules dissociate into nitrogen atoms, the RMS speed becomes double.

Topic: Chemistry, States of Matter, NEET
The rms speed of oxygen at room temperature is about 500 m s-1. The rms speed of hydrogen at the same temperature is about

Options:
A 125 m s-1
B 2000 m s-1
C 8000 m s-1
D 31 m s-1

The correct answer is:
2000 m s-1

Solution:
RMS speed of gas is given by
vrms=3RTM
Where, R= gas constant
T= absolute temperature in Kelvin
M= molecular mass of the gas
∴ VrmsoxygenVrmshydrogen=MH2MO2=232
=116=14
⇒ 500(Vrms) hydrogen=14
⇒ Vrms hydrogen =2000 m s-1

Topic: Physics, Kinetic Theory of Gases, NEET
The r.m.s. velocity of hydrogen is 7 times the r.m.s. velocity of nitrogen. If T is the temperature of the gas

Options:
A T(H2)=T(N2)
B T(H2)>T(N2)
C T(H2)<T(N2)
D T(H2)=7T(N2)

The correct answer is:
T(H2)<T(N2)

Solution:
μ=3RTM
μ∝TM
So μH2/μN2=[(TH2/MH2)×(MN2/TN2)]
7=(TH2×28/TN2×2)
=TH2×14/TN2
On squaring both sides and solving we get
TN2=2TH2
so TN2>TH2

Topic: Chemistry, States of Matter, NEET
The RNA polymerase holoenzyme transcribes:

Options:
A the promoter, structural gene and the terminator region
B the promoter and the terminator region
C the structural gene and the terminator region
D the structural gene only

The correct answer is:
the structural gene only

Solution:
The promoter and terminator flank the structural gene in a transcription unit thus the RNA polymerase holoenzyme transcribes the structural gene only.

Topic: Biology, Molecular Basis of Inheritance, NEET
The RNAi process, found only in eukaryotes, is initiated by:

Options:
A ds RNA fragments
B ds DNA fragments
C ss DNA fragments
D ss RNA fragments

The correct answer is:
ds RNA fragments

Solution:
RNAi takes place in all eukaryotic organisms as a method of cellular defense. This method involves the silencing of a specific mRNA due to a complementary dsRNA molecule that binds to and prevents translation of the mRNA (silencing). The source of this complementary RNA could be from an infection by viruses having RNA genomes or mobile genetic elements (transposons) that replicate via an RNA intermediate.

Topic: Biology, Biotechnology and Its Applications, NEET
The role of carotenoids in photosynthesis is to

Options:
A absorb light and transfer the energy to chlorophyll a.
B Donate electrons to the electron transport system
C protect chlorophyll a from photo-oxidation.
D More than one option is correct

The correct answer is:
More than one option is correct

Solution:
Though chlorophyll is the major pigment responsible for trapping light, other thylakoid pigments like chlorophyll b, xanthophylls and carotenoids, which are called accessory pigments, also absorb light and transfer the energy to chlorophyll a. Indeed, they not only enable a wider range of wavelength of incoming light to be utilised for photosyntesis but also protect chlorophyll a from photo-oxidation.

Topic: Biology, Photosynthesis in Higher Plants, NEET
The role of DNA ligase in the construction of a recombinant DNA molecule is:

Options:
A Formation of a phosphodiester bond between two DNA fragments
B Formation of hydrogen bonds between sticky ends of DNA fragments
C Ligation of all purine and pyrimidine bases
D None of the above

The correct answer is:
Formation of a phosphodiester bond between two DNA fragments

Solution:
When cut by the same restriction enzyme, the resultant DNA fragments have the same kind of ‘sticky-ends’ and, these can be joined together (end-to-end) using DNA ligases.

Topic: Biology, Biotechnology - Principles and Processes, NEET
The role of DNA ligase in the construction of a recombinant DNA molecule is

Options:
A Formation of phosphodiester bond between sticky ends of DNA fragments
B Formation of hydrogen bonds between sticky ends of DNA fragments
C Ligation of all purine and pyrimidine bases
D None of the above

The correct answer is:
Formation of phosphodiester bond between sticky ends of DNA fragments

Solution:
DNA ligase commonly called as genetic gum is used to join segments of DNA by forming phosphodiester bonds between 3' OH and 5' phosphate. Sticky and staggered ends facilitates the action of enzyme DNA ligase.

Topic: Biology, Biotechnology - Principles and Processes, NEET
The role of fluorspar during the electrolysis of molten alumina is
(i) To reduce the melting point
(ii) To increase conductivity
(iii) As a seeding agent

Options:
A All are correct
B Only i is correct
C i,ii are correct
D i,iii are correct

The correct answer is:
Only i is correct

Solution:
Fluorspar is used to reduce melting point of mixture and increases the fluidity of the mass.

Topic: Chemistry, General Principles and Processes of Isolation of Metals, NEET
The role of molybdenum is:

Options:
A Nitrogen metabolism
B Carbon assimilation
C Flowering induction
D Chromosome contraction

The correct answer is:
Nitrogen metabolism

Solution:
Molybdenum is essential for the functioning of enzyme nitrogenase in the leguminous plants for metabolising nitrogen and thus, it helps in biological nitrogen fixation.

Topic: Biology, Mineral Nutrition, NEET
The root mean square speed of an ideal gas in a closed container of fixed volume is increased from 5×102 m s-1 to 103 m s-1 . Which of the following statement might correctly explain how the change is accomplished?

Options:
A By heating the gas, the temperature is doubled
B By heating the gas, the pressure is quadrupled
C By heating the gas, volume is tripled
D By heating the gas, the pressure is doubled

The correct answer is:
By heating the gas, the pressure is quadrupled

Solution:
urms=3RTM=3PVM
So urmsurms'=5×102m/s103m/s=12
=3PV/M3P'V/M=PP'
14=PP'
or P'=4P.

Topic: Chemistry, States of Matter, NEET
The root mean square speed of oxygen molecules at a certain absolute temperature is v. If the temperature is doubled and the oxygen gas dissociates into atomic oxygen, the root mean square speed would be -

Options:
A v
B 2v
C 2v
D 22v

The correct answer is:
2v

Solution:
RMS speed is given by
vrms=v=3RTM
New temperature Tâ²=2T
New molar mass Mâ²= M2
â´ vrmsnew =3R (2T)M2
vrmsnew =2v

Topic: Physics, Kinetic Theory of Gases, NEET
The root mean square velocity of helium gas becomes the same as that of methane molecule at 327°C , when the temperature is

Options:
A 300 K
B 450 K
C 150 K
D 1200 K

The correct answer is:
150 K

Solution:
urms of helium =3RT4g/mol
urms of CH4=3RT16g/mol
Here T' = 600 K
So 3RT4g/mol=3R×600K16g/mol
or T4=600K16
or T=600K4=150 K

Topic: Chemistry, States of Matter, NEET
The root mean square velocity of one mole of a monoatomic gas having molar mass M is Urms. The relation between the average kinetic energy (E) of the gas and Urms is

Options:
A U rms = 3E/2M
B U rms = 2E/3M
C U rms = 2E/M
D U rms = E/3M

The correct answer is:
U rms = 2E/M

Solution:
RMS of one mole of monoatomic gas is U rms = 3RT/M
Average K.E. is E=32 RT or 2E = 3RT
U rms = 2E/M

Topic: Chemistry, States of Matter, NEET
The rope shown in the figure is wound around a uniform cylinder of mass 4 kg, about the axis of the cylinder. If the cylinder rolls without slipping, then the linear acceleration of its centre of mass is

Options:
A 6.7 m s-2
B 10.0 m s-2
C 9.0 m s-2
D none of these

The correct answer is:
6.7 m s-2

Solution:
For rotational motion

Ï=IÎ±
âF2R=32MR2aR
âa=4F3M=42034=6.7 m s-2

Topic: Physics, Rotational Motion, NEET
The rotation period of an earth satellite close to the surface of the earth is 83 min then that of the satellite in an orbit at a distance of three times earth radii from its surface will be

Options:
A 83  min
B 838 min
C 664  min
D 249  min

The correct answer is:
664  min

Solution:
From Kepler's 3 rd law
T 2 ∝ R 3
( 83 ) 2 ∝ R 3
T 2 ∝ ( 4R ) 3
( 83 T ) 2 = ( 1 4 ) 3
T= 4 3/2 ×83
=8×83=664  min

Topic: Physics, Gravitation, NEET
The R.Q. for anaerobic respiration is

Options:
A 1
B 0
C 0.9
D Infinity

The correct answer is:
Infinity

Solution:
Respiratory Quotient = Volume of CO2 evolvedVolume of O2 consumed

For anaerobic respiration, oxygen is not consumed.

Respiratory Quotient = Volume of CO2 evolved0 = Infinity

Topic: Biology, Respiration in Plants, NEET
The rupture of the Graafian follicle and the release of ovum occurs under the influence of

Options:
A LH
B FSH
C MSH
D GH

The correct answer is:
LH

Solution:
Ovulation occurs under the influence of LH from pituitary gland.

Topic: Biology, Human Reproduction, NEET
The rusting of iron is catalysed by which of the following?

Options:
A Fe
B O2
C Zn
D H+

The correct answer is:
H+

Solution:
The rusting of iron is catalysed by H+ (acidic medium)
O2+4H++4e-→2H2O
The more the concentration of H+ , the faster is the rusting of iron.

Topic: Chemistry, d and f Block Elements, NEET
The rusting of iron takes place as
2H++2e+12O2âH2O(l);EÂ°=+1.23 V
Fe2++2eâFe(s);EÂ°=-0.44 V
Thus, ÎGÂ° for the net process is

Options:
A -322 kJ/mol
B -161 kJ/mol
C -1522 kJ/mol
D -76 kJ/mol

The correct answer is:
-322 kJ/mol

Solution:
EÂ°=EOPFeo+ERPH2Oo
=0.44+1.23=1.67 V
So ÎGÂ°=-nFEÂ°
=-2Ã1.67Ã96500
=- 322.31 kJ/mole.

Topic: Chemistry, Electrochemistry, NEET
The saccule and utricle contain a projecting ridge which is known as

Options:
A Macula
B Ampulla
C Cristae
D Both B & C

The correct answer is:
Macula

Solution:
Vestibular apparatus is located above the cochlea. Vestibular apparatus = Saccule + Utricle + 3 Semicircular canals. In saccule and utricle, macula (a projecting ridge) is the sensory part. It possess otoliths.

Topic: Biology, Neural Control and Coordination, NEET
The salient features of genetic code are :
(A) The code is palindromic
(B) UGA act as initiator codon
(C) The code is unambiguous and specific
(D) The code is nearly universal
Choose the most appropriate answer from the options given below :

Options:
A $(A)$ and $(B)$ only
B $(C)$ and $(D)$ only
C $(A)$ and $(D)$ only
D $(B)$ and $(C)$ only

The correct answer is:
$(C)$ and $(D)$ only

Solution:
The genetic code are unambiguous and specific
The genetic code is universal.
Genetic codon are non-palindromic
UGA is terminator codon.
Therefore option (2) is correct.

Topic: Biology, Molecular Basis of Inheritance, NEET, NEET 2023 (Manipur)