datavorous/entrance-exam-dataset huggingface dataset:
In a given above representation, the points A, B and C, respectively, are

Options:
A Hypophyseal artery, hypophyseal portal vein, Hypophyseal vein
B Hypophyseal vein, Hypophyseal portal vein, Hypophyseal artery
C Hepatic artery, Hypophyseal vein, Hepatic vein
D Hypophyseal portal vein, Hypophyseal artery, Hypophyseal vein

The correct answer is:
Hypophyseal artery, hypophyseal portal vein, Hypophyseal vein

Solution:
The hypophyseal portal system (consisting of hypophyseal artery, hypophyseal portal vein and hypophyseal vein) is a blood system of vessels in the brain that connects the hypothalamus with the anterior pituitary.

Topic: Biology, Chemical Coordination and Integration, NEET
In a given DNA segment, ATG ACC AGG ACC CCA ACA, the first base gets mutated. The effect of this on coding by this DNA segment will result in

Options:
A Complete change in the type as well as sequence of amino acid
B Change in the first amino acid only
C No change in the sequence
D One amino acid less in the protein

The correct answer is:
Change in the first amino acid only

Solution:
For the given DNA segment, if the first base gets mutated, then there will be a change in the first amino acid only because each amino acid consists of a triplet code consisting of three nucleotides bases. When for a given DNA segment the first base gets mutated then only that particular part consisting of three bases and specific for a particular amino acid will change.

Topic: Biology, Molecular Basis of Inheritance, NEET
In a given region of 10 fringes are observed in the reflected beam from a thin film. If the wavelength of the incident light is changed from 4200 Aâ to 6000 Aâ, then the number of fringes observed in the same region will be

Options:
A 4
B 7
C 11
D 3

The correct answer is:
7

Solution:
Path difference 2 μtcos⁡r=n λ
Path difference is the same for both waves
∴n1 λ1=n2 λ2
Or n2=n1λ1λ2=10×42006000=7

Topic: Physics, Wave Optics, NEET
In a gobar gas plant, methogens convert

Options:
A complex insoluble polymers into methane
B complex soluble polymers into methane
C acetic acid into methane
D simple insoluble polymers into methane

The correct answer is:
acetic acid into methane

Solution:
In a gobar gas plant, complex insoluble polymers are converted to simple soluble monomers with the help of bacterial hydrolytic enzymes like lipases, cellulases, proteases, peptidases, etc. Anaerobic microbes like Clostridium, Pseudomonas are used for this process. Then the simple soluble monomers are further converted into organic acids, chiefly acetic acid by enzymes of acidogenic bacteria.
Methanogens are bacteria such as Methanococcus or Methanobacillus convert organic acids such as acetic acid into methane.

Topic: Biology, Microbes in Human Welfare, NEET
In a gravitational field, the gravitational potential is given by, $\mathrm{V}=\frac{\mathrm{K}}{x}(\mathrm{~J} / \mathrm{kg})$. The gravitational field intensity at point $(2,0,3) \mathrm{m}$ is:

Options:
A $+\frac{K}{2}$
B $-\frac{\mathrm{K}}{2}$
C $-\frac{\mathrm{K}}{4}$
D $+\frac{K}{4}$

The correct answer is:
$-\frac{\mathrm{K}}{4}$

Solution:
Gravitational field intensity \(=\frac{-\partial V}{\partial x} \hat{i}+\frac{-\partial V}{\partial y} \hat{j}+\frac{-\partial V}{\partial x} \widehat{k}\)
where V is gravitational potential
\(\Rightarrow\) Gravitational field intensity \(=\frac{-\partial}{\partial x}\left[\frac{-K}{x}\right]=\frac{-K}{x^2} \hat{i}\)
at \((2,0,3)\)
\(\overrightarrow{E_G}=\frac{-K}{2^2}=\frac{-K}{4} \hat{i}\)

Topic: Physics, Gravitation, NEET, NEET 2022 (Phase 2)
In a group of the periodic table, how does the size of atom A affect H-A bond strength and acid strength?

Options:
A Larger size of A leads to stronger H-A bond and stronger acid.
B Larger size of A leads to weaker H-A bond and stronger acid.
C Larger size of A has no effect on H-A bond strength and acid strength.
D Larger size of A leads to stronger H-A bond and weaker acid.

The correct answer is:
Larger size of A leads to weaker H-A bond and stronger acid.

Solution:
In a group of the periodic table, as the size of atom A increases down the group, the H-A bond strength decreases, leading to stronger acids.

Topic: Chemistry, Ionic Equilibrium, NEET
In a growing population of the country,

Options:
A Reproductive and per-reproductive individuals are equal in number
B Reproductive individuals are less than the post-reproductive individuals
C Pre-reproductive individuals are more than reproductive individuals
D Pre-reproductive individuals are less than the reproductive individuals

The correct answer is:
Pre-reproductive individuals are more than reproductive individuals

Solution:
In a growing population, the younger population (or pre-reproductive individuals) size is larger than that of reproductive individuals. Such a population is represented by a triangular-shaped age pyramid whereas, the equal number of reproductive and pre-reproductive individuals represents a stable population, and the age pyramid is bell-shaped.
Less number of pre-reproductive individuals than reproductive individuals represents a declining population, and the age pyramid appears urn-shaped. A similar case is seen when reproductive individuals are less than post-reproductive individuals.âââ

Topic: Biology, Organisms and Populations, NEET, NEET 2018
In a guitar, two strings A and B made of same material are slightly out of tune and produce beats of frequency 6 Hz. When tension in B is slightly decreased, the beat frequency increases to 7 Hz. If the frequency of A is 530 Hz, the original frequency of B will be:

Options:
A 524 Hz
B 536 Hz
C 537 Hz
D 523 Hz

The correct answer is:
524 Hz

Solution:
Guitar string i.e. string is fixed from both ends

Frequency ∝ Tension
If tension in B slightly decrease then frequency of B decrease.

If B is 536 Hz, the beats produced will be 536-530 as the frequency decreases, beats with A also decreases.

If B is 524 Hz, the beats produced will be 530-524 as the frequency decreases, beats with A increases.
∴ Original frequency of B will be 524 Hz.

Topic: Physics, Waves and Sound, NEET, NEET 2020 (Phase 1)
In a half reaction, nitrate is reduced by 6e- reduction to x as follows 7H++NO3-+6e-→2H2O+x . The 'x' in the reaction is

Options:
A NO
B NH2NH2
C NH3
D NH2OH

The correct answer is:
NH2OH

Solution:
N+5O3-→N-1H2OH ,
Change in oxidation number is 6

Topic: Chemistry, Redox Reactions, NEET
In a hierarchical system of plant classification, which one of the following taxonomic ranks generally ends in 'ceae'?

Options:
A Family
B Genus
C Order
D Class

The correct answer is:
Family

Solution:
Family is a taxonomic category between the division and order. It includes one or more genera. It suffix is 'aceae'.

Topic: Biology, The Living World, NEET
In a homogeneous system, what is the key characteristic of the phase of reactants and products?

Options:
A They are in different phases
B They are in the same phase
C They are in the gaseous phase
D They are in solid phase

The correct answer is:
They are in the same phase

Solution:
In a homogeneous system, all the reactants and products are in the same phase, as mentioned in the paragraph.

Topic: Chemistry, Chemical Equilibrium, NEET
In a human female, if the duration of her menstrual cycle is of 34 days. What is the duration of the luteal phase and at what day ovulation occurs in this woman?

Options:
A 14 days; 20th day
B 20 days; 14th day
C 17 days; 17th day
D 16 days; 18th day

The correct answer is:
14 days; 20th day

Solution:
Reproductive cycle of the primate female is called menstrual cycle. Among all three phases of menstrual cycle, the luteal phase or secretary phase is most constant, fixed and is duration of 14 days.
Day of ovulation in woman = (Total no. of days in menstrual cycle - 14)= 34 - 14 =20

Topic: Biology, Human Reproduction, NEET
In a human pyramid in a circus, the entire weight of the balanced group is supported by the legs of a performer who is lying on his back (as shown in Fig.). The combined mass of all the persons performing the act, and the tables, plaques etc. involved is 280 kg. The mass of the performer lying on his back at the bottom of the pyramid is 60 kg. Each thighbone (femur) of this performer has a length of 50 cm and an effective radius of 2.0 cm. Determine the amount by which each thighbone gets compressed under the extra load.

Options:
A 0.046%
B 0.0046%
C 0.091%
D 0.0091%

The correct answer is:
0.0091%

Solution:
Correct Option is : (D)
0.0091%

Topic: Chemistry, Mechanical Properties of Solids, NEET
In a hydraulic press, radii of connecting pipes, r1 and r2 are in the ratio 1:2. In order to lift a heavy mass M on the larger piston, the small piston must be pressed through a minimum force f equal to

Options:
A Mg
B Mg2
C Mg4
D Mg8

The correct answer is:
Mg4

Solution:
According to Pascal's principle,
f1f2=A1A2=r12r22=14
f1=14Mg

Topic: Physics, Mechanical Properties of Fluids, NEET
In a hydrogen atom, the energy of the first excited state is $-3.4 \mathrm{eV}$. Then, find out the K.E. of the same orbit of the hydrogen atom.

Options:
A $+3.4 \mathrm{eV}$
B $+6.8 \mathrm{eV}$
C $-13.6 \mathrm{eV}$
D $+13.6 \mathrm{eV}$

The correct answer is:
$+3.4 \mathrm{eV}$

Solution:
For hydrogen atom,
The kinetic energy is equal to the negative of the total energy. And the potential energy is equal to the twice of the total energy.
The first excited state energy of orbital $=-3.4 \mathrm{eV}$ and the kinetic energy of same orbital $=-(-3.4 \mathrm{eV})$ $=3.4 \mathrm{eV}$
Related Theory
In search of its lowest energy configuration the Hydrogen atom in the first excited state will de-excite to the ground-state, by emitting a photon of energy $\left(E_2-E_\nu\right)$.
Caution
The energy in an excited state is nothing but kinetic energy.

Topic: Chemistry, Structure of Atom, NEET, NEET 2002
In a hydrogen atom, the transition takes place from n=3 to n=2 . If Rydberg constant is 1.097×107m-1 , the wavelength of the emitted radiation is

Options:
A 365RH
B 5RH36
C 34RH
D 43RH

The correct answer is:
365RH

Solution:
1λ=RHZ21n12-1n22
1λ=RH×(1)214-19
1λ=RH536
λ=365RH

Topic: Chemistry, Structure of Atom, NEET
In a hydrogen atom, which orbital corresponds to the most stable condition and is called the ground state?

Options:
A 2s orbital
B 2p orbital
C 1s orbital
D 3d orbital

The correct answer is:
1s orbital

Solution:
In a hydrogen atom, the 1s orbital corresponds to the most stable condition and is called the ground state.

Topic: Chemistry, Structure of Atom, NEET
In a hydrogen like atom, electron makes transition from an energy level with quantum number n to another with quantum number ( n−1 ). If n>>1, the frequency of radiation emitted is (almost) proportional to

Options:
A 1 n 3
B 1 n
C 1 n 2
D 1 n 4

The correct answer is:
1 n 3

Solution:
ÎE=hv
=k[ 1 (nâ1) 2 â 1 n 2 ]
= (k)2n n 2 (nâ1) 2
≃( 2k n 3 )

Topic: Physics, Atomic Physics, NEET
In a hydrogen–oxygen fuel cell, combustion of hydrogen occurs to

Options:
A produce high purity water
B generate heat
C remove adsorbed oxygen from electrode surfaces
D create potential difference between the two electrodes

The correct answer is:
create potential difference between the two electrodes

Solution:
Any cell [like fuel cell], works when potential difference is developed.In a hydrogen–oxygen fuel cell, combustion of hydrogen occurs tocreate potential difference between the two electrodes.

Topic: Chemistry, Electrochemistry, NEET
In a large room, a person receives direct sound waves from a source 120 m away from him. He also receives waves from the same source after being reflected from the 25 m high ceiling, at a point halfway between them. The two waves interfere constructively for a wavelength of

Options:
A 20,203,205, etc
B 10,Â 5,Â 2.5,Â etc
C 10, 20, 30, etc
D 15,Â 25,Â 35,Â etc

The correct answer is:
20,203,205, etc

Solution:
Path difference between the waves
Δx=130-120=10 m
As phase between the two waves is π because reflection takes place from the rigid end, so for constructive interference.
Δx=2n+1λ2
10=2n+1λ2
∴λ=202n+1
n=0, λ1=20 m
n=1, λ2=203 m
n=2, λ3=205 m

Topic: Physics, Waves and Sound, NEET
In a longitudinal section of a root. Starting from the tip upward the four zones occur in the following order:

Options:
A rootcap, cell division, cellenlargement, cell maturation
B root cap, cell division, cell maturation, cell enlargement
C cell division, cell enlargement, cell maturation, root cap
D cell division, cell maturation, cell enlargement, root cap.

The correct answer is:
rootcap, cell division, cellenlargement, cell maturation

Solution:
The root tip can be divided into three zones: a zone of cell division, a zone of elongation, and a zone of maturation. The zone of cell division is closest to the root tip and is made up of the actively-dividing cells of the root meristem, which contains the undifferentiated cells of the germinating plant. The zone of elongation is where the newlyformed cells increase in length, thereby lengthening the root. zone of cell maturation where the root cells differentiate into specialized cell types.
Related Theory
Root growth begins with seed germination. When the plant embryo emerges from the seed, the radicle of the embryo forms the root system. The tip of the root is protected by the root cap, a structure exclusive to roots and unlike any other plant structure. The root cap is continuously replaced because it is easily damaged as the root pushes through soil.

Topic: Biology, Morphology of Flowering Plants, NEET, NEET 2004
In a longitudinal section of a root, starting from the tip upward, the four zones occur in the following order :

Options:
A Root cap, cell division, cell enlargement, cell maturation
B Root cap, cell division, cell maturation, cell enlargement
C Cell division, cell enlargement, cell maturation, root cap
D Cell division, cell maturation, cell enlargement, root cap

The correct answer is:
Root cap, cell division, cell enlargement, cell maturation

Solution:
Root shows the following regions
Root cap or calyptra - cap like protective covering over tip of the root
Meristematic region is the subapical position
Zone of elongation - receives new cells from the growing point
Root hair zone - is the zone of differentiation
Zone of mature cells - have thick walled impermeable cells.

Topic: Biology, Morphology of Flowering Plants, NEET
In a maize comb, the silky hairs represent:

Options:
A Long style
B Long style with feathery stigma
C Involucre of bracts
D Hairs or pappus

The correct answer is:
Long style with feathery stigma

Solution:
Maize is a monocot plant from the Angiosperm division. Maize uses wind as agent for the pollination process. It does not need an elaborative flower with colourful petals and nector. Also, maize plant produces unisexual flowers that is male and female flowers are separate. Maize shows tassel form of inflorescence where the flowers form cluster. The female flowers give out long feathery silky hair like structures which form the style and stigma of the flower. This structure help in capturing pollen for fertilization. These are also visible on the maize comb after fertilization

Topic: Biology, Morphology of Flowering Plants, NEET
In a man, abducens nerve is injured. Which one of the following functions will be affected?

Options:
A movement of the eyeball
B movement of the tongue
C swallowing
D movement of the neck.

The correct answer is:
movement of the eyeball

Solution:
The abducens nerve is the sixth paired cranial nerve. It has a purely somatic motor function-providing innervation to the lateral rectus muscle responsible for outward gaze.
Related Theory
Six cranial nerves innervate motor, sensory, and autonomic structures in the eyes. The six cranial nerves are the optic nerve (CN II), oculomotor nerve (CN III), trochlear nerve (CN IV), trigeminal nerve (CN V), abducens nerve (CN VI), and facial nerve (CN VII).

Topic: Biology, Neural Control and Coordination, NEET, NEET 2005
In a marriage between male with blood group A and female with blood group B, the progeny had either blood group $\mathrm{AB}$ or $\mathrm{B}$. What could be the possible genotype of parents?

Options:
A \(\mathrm{I}^{\mathrm{A}} \mathbf{i}(\text {Male}): \mathrm{I}^{\mathrm{B}} \mathrm{I}^{\mathrm{B}}\) Female
B \(\mathrm{I}^{\mathrm{A}} \mathrm{I}^{\mathrm{A}} \text { (Male) }: \mathrm{I}^{\mathrm{B}} \mathrm{I}^{\mathrm{B}}\) Female
C \(\mathrm{I}^{\mathrm{A}} \mathrm{I}^{\mathrm{A}}(\text {Male}): \mathrm{I}^{\mathrm{B}} \mathrm{i}\) Female
D \(\mathrm{I}^{\mathrm{A}} \mathrm{i}(\text {Male}): \mathrm{I}^{\mathrm{B}} \mathbf{i}\) Female

The correct answer is:
\(\mathrm{I}^{\mathrm{A}} \mathbf{i}(\text {Male}): \mathrm{I}^{\mathrm{B}} \mathrm{I}^{\mathrm{B}}\) Female

Solution:
The possible genotype of parents having progeny with either blood group $\mathrm{AB}$ or $\mathrm{B}$ is $\mathrm{I}^{\mathrm{A}} \mathrm{i}$ (male): $\mathrm{I}^{\mathrm{B}} \mathrm{I}^{\mathrm{B}}$ (female)

Topic: Biology, Principles of Inheritance and Variation, NEET, NEET 2019 (Odisha)
In a mass spectrometer for measuring the masses of ions, the ions are initially accelerated by an electric potential V and then made to describe semicircular paths of radius $R$ using a magnetic field $B$. If $V$ and $B$ are kept constant, the ratio $\left(\frac{\text { charge on the ion }}{\text { mass of the ion }}\right)$ will be proportional to:

Options:
A $\frac{1}{R^2}$
B $R^2$
C $R$
D $\frac{1}{R}$

The correct answer is:
$\frac{1}{R^2}$

Solution:
Radius of semicircular path
$R=\frac{m v}{q B}=\frac{\sqrt{2 m q V}}{q B}$
As $V$ and $B$ are constant so
$\begin{aligned}
& R \propto \frac{\sqrt{m q}}{q} \\
& \Rightarrow \frac{q}{m} \propto \frac{1}{R^2}
\end{aligned}$

Topic: Physics, Magnetic Effects of Current, NEET, NEET 2007
In a medicolegal case of accidental interchange between two babies in a hospital, the baby of the blood group-A could not be rightly given to a couple with

Options:
A Husband of O group and wife of AB group
B Husband of A group and wife of O group
C Husband of B group and wife of O group
D Husband of AB group and wife of A group

The correct answer is:
Husband of B group and wife of O group

Solution:
Father's blood group-B and mother's blood group-O will not be able to produce a offspring of blood group-A. Hence, the baby of the blood group-A could not be rightly given to a couple with husband of B group and wife of O group.

Topic: Biology, Principles of Inheritance and Variation, NEET
In a Mendelian dihybrid cross, the probability of getting seeds with genotype Rryy, RrYy, rrYy and RrYY in F2 generation is respectively

Options:
A 216 :416 :18 :18
B 216Â :216Â :216Â :216
C 416Â :416Â :216Â :216
D 18Â :14Â :28Â :116

The correct answer is:
216 :416 :18 :18

Solution:
In a Mendelian dihybrid cross, the genotypic ratio is RRYY:RrYY:RRYy:RrYy:rrYY:rrYy:RRyy:Rryy:rryy is 1:2:2:4:1:2:1:2:1.

Topic: Biology, Principles of Inheritance and Variation, NEET
In a Mendelian dihybrid cross, when heterozygous round yellow seeded plants were self crossed, round green seeded offsprings are represented by the genotype

Options:
A RrYy, RrYY, RRYy
B Rryy, RRyy, rryy
C rrYy, rrYY
D Rryy, RRyy

The correct answer is:
Rryy, RRyy

Solution:
In Mendelian dihybrid cross when heterozygous round yellow seeded plants are self-crossed, round green seeded offsprings are represented by RRyy, Rryy genotypes. This is illustrated as given below.

RY	Ry	rY	ry

RY	RRYY	RRYy	RrYY	RrYy

Ry	RRYy	RRyy	RrYy	Rryy

rY	RrYY	RrYy	rrYY	rrYy

ry	RrYy	Rryy	rrYy	rryy

Round green genotypes = RRyy, Rryy.

Topic: Biology, Principles of Inheritance and Variation, NEET
In a meter bridge circuit as shown in the figure, the bridge is balanced when AJ=20 cm. On interchanging P and Q the balance length shifts by

Options:
A zero
B 80Â cm
C 40Â cm
D 60 cm

The correct answer is:
60 cm

Solution:
Initially balancing point is J,
Hence AJBJ=PQ=2080
Now if P & Q are interchanged,
Let balancing point be J1
AJ1BJ1=QP=8020
The balanced point shifts by AJ1-AJ=80-20=60 cm.

Topic: Physics, Current Electricity, NEET
In a mitotic cycle, the correct sequence of phases is:

Options:
A S,G1,G2,M
B G1,S,G2,M
C M,G1,G2,S
D G1,G2,S,M

The correct answer is:
G1,S,G2,M

Solution:
The cell cycle is divided into two basic phases:
a. Interphase: The phase between subsequent cell divisions is called the interphase. The interphase lasts for more than 95% of the cell cycle. The interphase is further divided into three stages, i.e. G1, S and G2.
b. M Phase (Mitotic phase): The actual cell division takes place in the M-phase. The M-phase lasts for less than 5% of the cell cycle.

Topic: Biology, Cell Cycle and Cell Division, NEET, NEET 2020 (Phase 2)
In a mixture, DNA fragments are separated by:

Options:
A Bioprocess engineering
B Restriction digestion
C Electrophoresis
D Polymerase chain reaction

The correct answer is:
Electrophoresis

Solution:
The cutting of DNA by restriction endonucleases results in the fragments of DNA. These fragments can be separated by a technique known as gel electrophoresis. Since, DNA fragments are negatively charged molecules they can be separated by forcing them to move towards the positive electrode anode under an electric field through a medium/matrix. The DNA fragments separate (resolve) according to their size through sieving effect provided by the agarose gel. Hence, the smaller the fragment size, the farther it moves.

Topic: Biology, Biotechnology - Principles and Processes, NEET, NEET 2020 (Phase 2)
In a mixture of A and B , components show negative deviation when -

Options:
A A-B interaction is stronger than A-A and B-B interaction
B A-B interaction is weaker than A-A and B-B interaction
C ΔVmix>0, ΔSmix>0
D ΔVmix=0, ΔSmix>0

The correct answer is:
A-B interaction is stronger than A-A and B-B interaction

Solution:
Negative deviation is when A-B (solute-solvent) interaction is stronger than A-A (solute-solute) and B-B (solvent-solvent) interaction. Hence ΔVmix<0, ΔHmix<0

Topic: Chemistry, Solutions, NEET
In a mixture of gases, the average number of degrees of freedom per molecule is 6. The root mean square speed of the molecules of the gas is c. The velocity of sound in the gas is

Options:
A c2
B 3c4
C 2c3
D c3

The correct answer is:
2c3

Solution:
γ=1+2f=1+26=43
Root mean square speed, c=3Pρ
and speed of sound, v=γPρ
∴ vc=γ3
vc=433
v=2c3

Topic: Physics, Waves and Sound, NEET
In a monoecious plant:

Options:
A Male and female sex organs are on different individuals
B Male and female gametes are of two morphologically distinct types
C Male and female sex organs are on the same individual
D All the stamens are fused to form one unit

The correct answer is:
Male and female sex organs are on the same individual

Solution:
When a single plant produces both male and female flower than the plant is called as monoecious. When two different plant body occurs one producing male flower and the other producing different flower than the plant is called as dioecious.

Topic: Biology, Reproduction in Organisms, NEET
In a monohybrid cross, 120 plants are obtained. The ratio of homozygous and heterozygous will be

Options:
A 40 : 80
B 60 : 60
C 20 : 100
D 10 : 110

The correct answer is:
60 : 60

Solution:
Monohybrid ratio of homozygous and heterozygous individuals is 1:1.
Phenotypic Ratio = 3:1
Genotypic Ration = 1:2:1
1 = Homizygous Dominant
2 = Heterozygous
1 = Homozygous Recessive

Topic: Biology, Principles of Inheritance and Variation, NEET
In a monohybrid cross between two heterozygous individuals, percentage of pure homozygous individuals obtained in F1 generation is _____.

Options:
A 25%
B 50%
C 75%
D 100%

The correct answer is:
50%

Solution:
Monohybrid cross is defined as "a genetic mix between two individuals who have homozygous genotypes, or genotypes that have completely dominant or completely recessive alleles, which result in opposite phenotypes for a certain genetic trait".
The phenotypic ratio and genotypic ratio for a monohybrid cross comes to 3:1 and 1:2:1.
When two heterozygous individuals undergo monohybrid crossing, F1 generation will have the following probabilities -
Pure dominant homozygous - 25%
Hybrids (heterozygous) - 50%
Pure recessive heterozygous - 25%
Total pure homozygous (dominant + recessive) is 50%

Topic: Biology, Principles of Inheritance and Variation, NEET