datavorous/entrance-exam-dataset huggingface dataset:
An engine pumps water continuously through a hose. Water leaves the hose with a velocity $y$ and $m$ is the mass per unit length of the water jet. What is the rate at which kinetic energy is imparted to water ?

Options:
A $\frac{1}{2} \mathrm{mv}^3$
B $\mathrm{mv}^3$
C $\frac{1}{2} \mathrm{mv}^2$
D $\frac{1}{2} m^2 v^2$

The correct answer is:
$\frac{1}{2} \mathrm{mv}^3$

Solution:
Velocity of water is \(v\), mass flowing per unit length is \(m\).
Mass flowing per second \(=\mathrm{mv}\)
\(\therefore\) Rate of kinetic energy or K.E. per second
\(=1 / 2(m v) v^2=1 / 2 m v^3\)

Topic: Physics, Center of Mass Momentum and Collision, NEET, NEET 2009 (Screening)
An engine pumps water through a hose pipe. Water passes through the pipe and leaves it with a velocity of $2 \mathrm{~ms}^{-1}$. The mass per unit length of water in the pipe is $100 \mathrm{kgm}^{-1}$. What is the power of the engine?

Options:
A $400 \mathrm{~W}$
B $200 \mathrm{~W}$
C $100 \mathrm{~W}$
D $800 \mathrm{~W}$

The correct answer is:
$800 \mathrm{~W}$

Solution:
$$
\begin{aligned}
\text { Power } & =\mu \mathrm{v}^3=\frac{\mathrm{m}}{\mathrm{l}} \times \mathrm{v}^3 \\
& =100 \times(2)^3=800 \mathrm{~W}
\end{aligned}
$$

Topic: Physics, Center of Mass Momentum and Collision, NEET, NEET 2010 (Screening)
An engine pumps water through a hosepipe. Water passes through the pipe and leaves it with a velocity of 2 m s-1. The mass per unit length of water in the pipe is 100 kg m-1. What is the power of the engine?

Options:
A 400 W

B 200 W
C 100 W
D 800 W

The correct answer is:
800 W

Solution:
Here, Mass per unit length of water, Î¼=100 kg m-1
The velocity of water, v=2 m s-1
Power of the engine, P=Î¼v3=(100 kg m-1)(2 m s-1)3
=800ââW

Topic: Physics, Work Power Energy, NEET
An engineer claims to have made an engine delivering 10 kW power with fuel consumption of 1 g s-1. The calorific value of the fuel is 2 kcal g-1. The claim of the engineer

Options:
A is valid
B is invalid
C depends on engine design
D depends on the load

The correct answer is:
is invalid

Solution:
Input energy=1 gsec×2 kcalg=2 kcal s-1
Output energy=10 kW=10 kJ s-1=104.2 kcal s-1
η = Output energy Input energy = 10 4.2 × 2 > 1

Topic: Physics, Thermodynamics, NEET
An enzyme catalyses a reaction by _________ activation energy of the reaction.

Options:
A increasing
B decreasing
C first decreasing and then increasing.
D first increasing and then decreasing

The correct answer is:
decreasing

Solution:
Enzyme catalyses a reaction by lowering down the activation energy of the reaction so that the reaction can occur at normal cellular condition. Activation energy is lowered by using binding energy which is released when substrate binds to active site of enzyme to form ES complex. Thus ES complex formation is very much necessary for enzyme catalysed reaction to occur.

Topic: Chemistry, Biomolecules, NEET
An enzyme catalysing the removal of nucleotide from the ends of DNA is

Options:
A Endonuclease
B Exonuclease
C DNA ligase
D Hind-II

The correct answer is:
Exonuclease

Solution:
A protein that recognizes and cuts a small and specific nucleotide sequence of DNA is called a restriction enzyme. The site at which these restriction enzymes act is called restriction site or target sequence. Restriction enzymes belong to the class of nucleases. Nucleases are of two types - Endonucleases and Exonucleases. The function of endonucleases is to cut the ends of the DNA molecule where as the endonucleases cut the DNA at specific positions within it.

Topic: Biology, Biotechnology - Principles and Processes, NEET
An enzyme catalysing the removal of nucleotides from ends of DNA is

Options:
A DNA ligase
B endonuclease
C exonuclease
D protease

The correct answer is:
exonuclease

Solution:
An enzyme catalysing the removal of nucleotides from ends of DNA is exonuclease. Endonuclease made cuts at specific positions within the DNA. DNA ligase joins DNA fragments. Proteases are protein-degrading enzymes.

Topic: Biology, Biotechnology - Principles and Processes, NEET, NEET 2019 (Odisha)
An enzyme is kept at -10℃ for 3 minutes and is used in a chemical reaction (P). It is then gradually brought to room temperature. It is now used in a chemical reaction (Q). Another enzyme is kept at 80 ℃ for 5 minutes and is used in chemical reaction (R). It is then gradually brought to room temperature. It is now used in a chemical reaction (S). Which of these reactions will be catalyzed by enzyme and which will not?

Options:
A Reactions in which products are formed: P and R. Reactions in which products are not formed: Q and S
B Reactions in which products are formed: Q and S. Reactions in which products are not formed: P and R
C Reactions in which products are formed: P, R and S. Reactions in which products are not formed: Q only
D Reactions in which products are formed: Only Q. Reactions in which products are not formed: P, R and S

The correct answer is:
Reactions in which products are formed: Only Q. Reactions in which products are not formed: P, R and S

Solution:
When an enzyme is kept at sub-zero temperature, it gets inactivated and it cannot catalyse the chemical reaction. Hence, P will not occur. When this enzyme is thawed (warmed) and brought back to normal temperature, the enzyme will become active and reaction Q will occur. However, when enzyme is heated beyond 60℃ , it undergoes denaturation. The tertiary structure, which is absolutely essential for the activity of enzyme, is destroyed, and hence, reaction R will not occur. When this heated enzyme is cooled down, the tertiary structure cannot be regained back, and it is still non-functional. Hence, reaction S will not occur too.

Topic: Chemistry, Biomolecules, NEET
An enzyme that can stimulate germination of barley seeds is:

Options:
A invertase
B $\alpha$-amylase
C lipase
D protease

The correct answer is:
$\alpha$-amylase

Solution:
Barley seeds are rich in carbohydrate (Starch). The starch is hydrolysed by $\alpha$ - amylase to monosaccharides at the time of germination of seeds.

Topic: Biology, Biomolecules (B), NEET, NEET 2006
An enzyme that can stimulate germination of barley seeds is

Options:
A Lipase
B Protease
C Invertase
D α-amylase

The correct answer is:
α-amylase

Solution:
Î±-amylase enzyme stimulates the germination of barley seed. Maltose is the disaccharide produced when amylase breaks down starch. It is found in germinating seeds such as barley as they break down their starch stores to use for food.

Topic: Biology, Plant - Growth and Development, NEET
An equiconvex lens is cut into two halves along i XOXâ² and ii YOYâ², as shown in the figure. Let f, fâ², fâ²â² be the focal lengths of complete lens, of each in case
(i) and of each half in case (ii), respectively

Choose the correct statement from the following.

Options:
A f′=f,Â f′′=f
B f′=2f,Â f′′=2f
C fâ²=f, fâ²â²=2f
D f′=2f,Â f′′=f

The correct answer is:
fâ²=f, fâ²â²=2f

Solution:
The focal length of an equiconvex lens is
1f=Î¼-11R1-1R2 ...(i)
For an equiconvex lens, R1=R2=R
1f=Î¼-11R-1-R=2Î¼-1R
Case I: When the lens is cut along XOX' , then each half becomes equiconvex with
R1=+R, R2=-R
â´ 1f=Î¼-11R-1-Râ1fÎ¼-11R+1R
= Î¼-12R=1fâ² âfâ²=f
Case II: When the lens is cut along YOY' , then each half becomes plano-convex with
R1=+R,R2=â
â´ 1fâ²â²=Î¼-11R1-1R2
= Î¼-1 1R-1â=Î¼-1R=12fâfâ²â²=2f

Topic: Physics, Ray Optics, NEET
An equiconvex lens is cut two halves along (i) XOX' and (ii) YOY' as shown in the figure. Let $f, f^{\prime}, f^{\prime \prime}$ be the focal length of the complete lens, of each half in case (i) and each half in case (ii), respectively.
Choose the correct statement from the following:

Options:
A $f^{\prime}=f, f^{\prime \prime}=2 f$
B $f^{\prime}=2 f, f^{\prime \prime}=f$
C $f^{\prime}=f, f^{\prime \prime}=f$
D $f=2 f, f^{\prime \prime}=2 f$

The correct answer is:
$f^{\prime}=f, f^{\prime \prime}=2 f$

Solution:
Since the lens is equiconvex, the radius of curvature of each half is same.
Using lens maker formula
$$
\frac{1}{f}=(\mu-1)\left(\frac{1}{R_1}-\frac{1}{R_2}\right)
$$
Here $R_1=R$
$R_2=-R$ by convection
$$
\therefore \frac{1}{f}=(\mu-1) \frac{2}{\mathrm{R}}(\mu-1) \frac{1}{\mathrm{R}}=\frac{1}{2 f} \ldots(\mathrm{i})
$$
If we cut the lens along $\mathrm{XOX}^{\prime}$ then two halves of the lens will be having the same radii of curvalur and
$$
\begin{aligned}
& R_1=R, R_2=-R \\
& \therefore \frac{1}{f^{\prime}}=(\mu-1)\left(\frac{2}{R}\right) \\
& \Rightarrow \frac{1}{f^{\prime}}=\frac{2}{2 f}=\frac{1}{f}
\end{aligned}
$$
From (i) it is clear that $f^{\prime}=f$
But when we cut along $\mathrm{YOY}$ ' then
$$
\begin{aligned}
& R_1=R \text { and } R_2=\infty \\
& \therefore \infty \frac{1}{f^{\prime \prime}}=(\mu-1)\left(\frac{1}{R}-\frac{1}{\infty}\right) \\
& =(\mu-1) \frac{1}{R}=\frac{1}{2 f} \\
& \Rightarrow \quad f^{\prime \prime}=2 f
\end{aligned}
$$

Topic: Physics, Ray Optics, NEET, NEET 2003
An equilateral prism deviates a ray through 45Â° for two angles of incidence differing by 20Â°. The angles of incidence are :

Options:
A 60°and 40°
B 50° and 70°
C 62°30' and 42°30'
D 60°30' and 40°30'

The correct answer is:
62°30' and 42°30'

Solution:
Î´ = i 1 + i 2 - A
4 5 â = i 1 + i 2 - 6 0 â
i 1 + i 2 = 1 0 5 â
i 1 - i 2 = 2 0 â
or 2 i i = 1 2 5 â
i 1 = 6 2 â 3 0 â² , i 2 = 4 2 â 3 0 â²

Topic: Physics, Ray Optics, NEET
An equilateral prism has an angle of minimum deviation 30°. Find total deviation if a ray is incident normally on the surface.

Options:
A 120°
B 60°
C 90°
D none of these

The correct answer is:
60°

Solution:
A=60° and δm=30°
μ=sin⁡A+δm2sin⁡A2
μ=sin⁡60+302sin⁡602
μ=sin⁡45°sin⁡30°
μ=1212
μ=2
Therefore, θcritical=sin-1⁡1μ
θcritical=45°
Therefore after 1st incidence light goes straight. At second incidence, total internal reflection takes place, and hence deviation is δ=60°.

Topic: Physics, Ray Optics, NEET
An equilateral triangle ABC is formed by two Cu rods AB and BC and one Al rod. It is heated in such a way that temperature of each rod increases by ∆T. Find change in the angle ABC. [Coefficient of linear expansion for Cu is α1,Coeff. of linear expansion for Al is α2]

Options:
A $d\theta =\frac{\left( 2{{\alpha }_{1}}-{{\alpha }_{2}} \right)\Delta t}{\sqrt{3}}$
B $d\theta =\frac{\left( 2{{\alpha }_{1}}+{{\alpha }_{2}} \right)\Delta t}{\sqrt{3}}$
C $d\theta =\frac{2\left( {{\alpha }_{1}}-{{\alpha }_{2}} \right)\Delta t}{\sqrt{3}}$
D $d\theta =\frac{\left( {{\alpha }_{1}}+{{\alpha }_{2}} \right)\Delta t}{\sqrt{3}}$

The correct answer is:
$d\theta =\frac{2\left( {{\alpha }_{1}}-{{\alpha }_{2}} \right)\Delta t}{\sqrt{3}}$

Solution:
Correct Option is : (C)
$d\theta =\frac{2\left( {{\alpha }_{1}}-{{\alpha }_{2}} \right)\Delta t}{\sqrt{3}}$

Topic: Chemistry, Mechanical Properties of Solids, NEET
An equilateral triangular frame is made of three thin massless rods. Three point masses of mass m each are fixed at vertices of the frame as shown. The system is rotated with uniform angular speed Ï about an (fixed) axis passing through A and normal to plane of triangular frame. Neglect the effect of gravity. The tension in rod connecting mass B and C is -

Options:
A m ω2l
B mω2l2
C 3mω2l2
D zero

The correct answer is:
zero

Solution:
B moves in dotted circle of radius l with uniform speed. Massless rod 1 can exert force T1 on B only along its length. Hence T1 contributes only to centripetal acceleration of B . The tension in rod 2, that is, T2 can contribute to both tangential and centripetal acceleration of B . Since tangential acceleration of B is zero.

Hence T2=0 .

Topic: Physics, Rotational Motion, NEET
An equilateral triangular frame is made of three thin massless rods. Three point masses of mass m each are fixed at vertices of the frame as shown. The system is rotated with uniform angular speed ω about a fixed axis passing through A and normal to the plane of triangular frame. Neglect the effect of gravity. The tension in rod connecting mass B and C is

Options:
A mω2l
B mω2l2
C 32mω2l
D zero

The correct answer is:
zero

Solution:
B moves in a circle (shown by the dashed curve) of radius I with uniform speed.
Massless rod 1 can exert force T1 on B only along its length i.e. towards the centre of the circular path. Hence T1 contributes only to centripetal acceleration of B .
The tension in rod 2, that is, T2 can contribute to both tangential and centripetal acceleration of B . As the angular speed is uniform so tangential acceleration of B is zero. Hence T2=0
The tension in rod connecting mass B and C is zero.

Topic: Physics, Laws of Motion, NEET
An equilateral triangular loop ADC having some resistance is pulled with a constant velocity v out of a uniform magnetic field directed into the screen. At the time t=0, side DC of the loop is at the edge of the magnetic field. The induced current i versus time t graph will be as

Options:
A
B
C
D

The correct answer is:

Solution:
Let 2a be the side of the triangle and b the length AE.

AH AE = GH EC
â´ GH = AH AE EC
or GH=b-vtbÂ·a
=a-abvt
â´ FG=2GH=2a-abvt
Induced emf e=BvFG=2Bva-abvt
â´ Induced current i=eR=2BvRa-abvt
or i = k1- k2t
Thus, i-t graph is a straight line with a negative slope and positive intercept.

Topic: Physics, Electromagnetic Induction, NEET
An ether is more volatile than an alcohol having same molecular formula because

Options:
A Dipolar character of ether
B Alcohols having resonance structure
C Intermolecular hydrogen bonding in ethers
D Intermolecular hydrogen bonding in alcohols

The correct answer is:
Intermolecular hydrogen bonding in alcohols

Solution:
Intermolecular H-bonding leads to strong intermolecular forces in alcohols as opposed to ethers which do not have H-bonding. This leads to a higher boiling point.

Topic: Chemistry, Alcohols Phenols and Ethers, NEET
An ether is more volatile than an alcohol having the same molecular formula. This is due to

Options:
A dipolar character of ethers
B alcohols having resonance structures
C inter-molecular hydrogen bonding in ethers
D inter-molecular hydrogen bonding in alcohols

The correct answer is:
inter-molecular hydrogen bonding in alcohols

Solution:
Due to inter-molecular hydrogen bonding in alcohols boiling point of alcohols is much higher than ether.

Topic: Chemistry, Alcohols Phenols and Ethers, NEET
An ether which cannot be cleaved by HI at 373 K . The compound is

Options:
A C6H5OCH3
B C6H5OC6H5
C C6H5OC3H7
D

The correct answer is:
C6H5OC6H5

Solution:
C-O bond with benzene ring cannot undergo cleavage due to resonance, it develop partial double bond character.
(ii) C6H5-O-C6H5→X
Due to the positive charge on benzene ring CsP2 is a highly unstable.
(iii)
(iv)

Topic: Chemistry, Alcohols Phenols and Ethers, NEET
An example for opposite phyllotaxy is

Options:
A Alstonia and Calotropis
B Guava and Calotropis
C Mustard and sunflower
D China rose and guava

The correct answer is:
Guava and Calotropis

Solution:
In the alternate types of phyllotaxy, a single leaf arises at each node in an alternate manner, as in china rose, mustard, and sunflower plants. In the opposite type, a pair of leaves arise at each node and lie opposite to each other as in Calotropis and guava plants. If more than two leaves arise at a node and form a whorl, it is called whorled, as in Alstonia.

Topic: Biology, Morphology of Flowering Plants, NEET
An example of a disease caused by the prokaryotic pathogen is

Options:
A red rot of sugarcane.
B late blight of potato.
C black rot of crucifers.
D brown rust of wheat.

The correct answer is:
black rot of crucifers.

Solution:
Red rot of sugarcane is caused by a fungus. Late blight of potato is caused by a fungus. Brown rust of wheat is caused by a fungus. Black rot of crucifers is caused by a bacterium. Tobacco mosaic is caused by a virus.

Topic: Biology, Strategies for Enhancement in Food Production, NEET
An example of a seed with endosperm and perisperm is

Options:
A Coffee
B Lily
C Castor
D Cotton

The correct answer is:
Castor

Solution:
In castor seed, testa and tegmen are united together. The seed coat is tough and bright due to scleroproteins. Over narrower end, a brownish pad is found which is called the caruncle. The caruncle is carbohydrate in nature. This protects micropyle and develops as an integumental outgrowth after fertilization. Below the seed coat, a very thin membrane is found over the kernel and called perisperm (the persistent nucellus). Below perisperm, there is a large, white, swollen and oily mass called endosperm.

Topic: Biology, Morphology of Flowering Plants, NEET
An example of a seed with endosperm, perisperm and caruncle is

Options:
A cotton
B coffee
C lily
D castor

The correct answer is:
castor

Solution:
The seeds of castor (Ricinus communis, family-Euphorbiaceae) are endospermic dicot seeds. They possess, endosperm which acts as the food storage tissue of seed. They also possess perisperm and cruncle.

Topic: Biology, Morphology of Flowering Plants, NEET, NEET 2009 (Screening)
An example of a sigma bonded organometallic compound is

Options:
A ruthenocene.
B Grignard's reagent.
C ferrocene.
D cobaltocene.

The correct answer is:
Grignard's reagent.

Solution:
Grignard's reagent i.e., RMgX is σ-bonded organometallic compound.

Topic: Chemistry, Coordination Compounds, NEET, NEET 2017
An example of a sigma bonded organometallic compound is

Options:
A Grignard’s reagent
B Ferrocene
C Cobaltocene
D Ruthenocene

The correct answer is:
Grignard’s reagent

Solution:
Grignard reagent [Rmgx] is a Sigma bonded Organometallic Compound here.

Topic: Chemistry, Coordination Compounds, NEET
An example of a vascular cryptogam is

Options:
A Ginkgo
B Marchantia
C Cedrus
D Equisetum

The correct answer is:
Equisetum

Solution:
Equisetum is a vascular cryptogam. Equisetum is the only living genus in the Equisetaceae, a family of vascular plants that reproduce by spores rather than seeds. They are commonly known as horse tails. Equisetum is a "living fossil", as it is the only known genus of the entire class Equisetopsida.

Topic: Biology, Plant Kingdom, NEET
An example of axile placentation is

Options:
A Argemone
B Dianthus
C lemon
D marigold

The correct answer is:
lemon

Solution:
Lemon (Citrus sp.) belongs to family-Rutaceae, contains axile placentation.
Argemone belongs to family-Papaveraceae, contains parietal placentation. Dianthus belongs to family-Caryophyllaceae, contains free-central placentation. Marigold belongs to family-Asteraceae, contains basal placentation.

Topic: Biology, Morphology of Flowering Plants, NEET, NEET 2009 (Screening)
An example of axile placentation is

Options:
A Dianthus
B Lemon
C Marigold
D Argemone

The correct answer is:
Lemon

Solution:
Argemone and marigold belong to the family Asteraceae which is characterized by basal placentation. In lemon, axile placentation is found. Dianthus belongs to Caryophyllaceae.

Topic: Biology, Morphology of Flowering Plants, NEET
An example of colonial alga is

Options:
A Chlorella
B Volvox
C Ulothrix
D Spirogyra

The correct answer is:
Volvox

Solution:
Volvox is motile colonial freshwater alga with a definite number of vegetative cells.
Colonial alga is algae in which cells resembling free swimming unicells form groups. They may be large and elaborately interconnected as in Volvox or smaller and relatively simple as in Synura.

Chlorella is an unicellular, non-motile alga. Spirogyra and Ulothrix is a filamentous forms.

Topic: Biology, Plant Kingdom, NEET, NEET 2017
An example of competitive inhibition is:

Options:
A Succinic dehydrogenase and malonate
B Sulpha drugs and /P- amino benzoic acid.
C Cytochrome oxidase/Cyanide
D More than one option is correct

The correct answer is:
More than one option is correct

Solution:
Competitive inhibition: The action of an enzyme may be reduced or inhibited in the presence of a substance that closely resembles the substrate in molecular structure. Such an inhibitor is called a Competitive Inhibitor of that enzyme. Due to its close structural similarity with the substrate, the inhibitor competes with the latter for the substrate-binding site of the enzyme. Consequently, the enzyme cannot participate in catalysing the change of the substrate. As a result the enzyme action declines, e.g, the inhibition of succinic dehydrogenase by malonate, which closely resembles succinate in structure. This may be compared to a lock jammed by a key similar to the original key. Such competitive inhibitors are often used in the control of bacterial pathogens. For instance, sulpha drugs are competitive inhibitors of folic acid synthesis in bacteria as they substitute for p-amino benzoic acid, thus preventing the next step in the synthesis.

Topic: Chemistry, Biomolecules, NEET
An example of drupe is

Options:
A mango.
B wheat.
C pea.
D tomato.

The correct answer is:
mango.

Solution:
Drupe is a fleshy fruit that develops from either one or several fused carpels and contains one or many seeds. The seeds are enclosed by the hard protective endocarp (pericarp) of the fruit, e.g.,mango. In mango the pericarp is well differentiated into an outer thin epicarp, a middle fleshy edible mesocarp and an inner stony hard endocarp.

Topic: Biology, Morphology of Flowering Plants, NEET
An example of edible underground stem is:

Options:
A Carrot
B Groundnut
C Sweet potato
D Potato

The correct answer is:
Potato

Solution:
In potato the edible part is underground tuber that is modification of underground stem. In carrot and sweet potato the edible parts are conical root and tuberous root respectively while in groundnut edible part is cotyledons.

Topic: Biology, Morphology of Flowering Plants, NEET, NEET 2014
An example of ex situ conservation is :

Options:
A National Park
B Seed Bank
C Wildlife sanctuary
D Sacred Grove

The correct answer is:
Seed Bank

Solution:
Ex-situ conservation is the approach where threatened animal and plant species are taken out of their natural habitats and conserved in a special setting, where they can be given special care. Seed bank is an example of ex-situ conservation, where seeds of different genetic traits of several commercial plants can be preserved for a long period of time. National parks, wildlife sanctuaries and sacred groves are examples of in-situ conservation.

Topic: Biology, Biodiversity and its Conservation, NEET, NEET 2014
An example of gene therapy is:

Options:
A Production of injectable hepatitis B vaccine
B Production of vaccines in food crops like potatoes which can be eaten
C Introduction of gene for adenosine deaminase in persons suffering from Severe Combined Immuno-deficiency (SCID)
D Production of test tube babies by artificial insemination and implantation of fertilized eggs.

The correct answer is:
Introduction of gene for adenosine deaminase in persons suffering from Severe Combined Immuno-deficiency (SCID)

Solution:
On September 14, 1990 researchers at the U.S. National Institutes of Health performed the first (approved) gene therapy procedure on four-year old Ashanti DeSilva. Born with a rare genetic disease called severe combined immune deficiency (SCID), she lacked a healthy immune system, and was vulnerable to every passing germ. Children with this illness usually develop overwhelming infections and rarely survive to adulthood.

Topic: Biology, Biotechnology and Its Applications, NEET
An example of gene therapy is:

Options:
A Production of injectable hepatitis B vaccine
B Production of vaccines in food crops like potatoes which can be eaten
C Introduction of the gene for adenosine deaminase in persons suffering from Severe Combined Immuno Deficiency (SCID)
D Production of test - tube babies by artificial insemination and implantation of fertilized eggs

The correct answer is:
Introduction of the gene for adenosine deaminase in persons suffering from Severe Combined Immuno Deficiency (SCID)

Solution:
The treatment of inherited diseases by introducing wild type copies of the defective gene is called gene therapy. For example, the introduction of gene for adenosine deaminase in a person suffering from Severe Combined Immunodeficiency (SCID).

Topic: Biology, Biotechnology and Its Applications, NEET