datavorous/entrance-exam-dataset huggingface dataset:
In an adiabatic process, the pressure is increased by 23% and C p C v = 3 2 for the gas. Then the volume decreases by about:

Options:
A 4 9 %
B 2 3 %
C 4%
D 9 4 %

The correct answer is:
4 9 %

Solution:
For an adiabatic process, PV γ = K
Here, γ = 3 / 2 and K = constant
∴ PV 3 / 2 = K
log P + 3 2 log V = log K
Δ P P + 3 2 Δ V V = 0
∴ Δ V V = - 2 3 Δ P P
Δ V V × 1 0 0 = - 2 3 Δ P P × 1 0 0 = - 2 3 × 2 3 = - 4 9
Therefore volume decreases by about 49%.

Topic: Physics, Thermodynamics, NEET
In an adiabatic process, what distinguishes the system's interaction with its surroundings from other processes?

Options:
A Exchange of matter
B Exchange of heat
C Absence of work done
D Absence of energy transfer

The correct answer is:
Exchange of heat

Solution:
In an adiabatic process, there is no exchange of heat between the system and its surroundings, which distinguishes it from other processes.

Topic: Chemistry, Thermodynamics (C), NEET
In an adiabatic process, what is the role of the adiabatic wall?

Options:
A It prevents matter from leaving the system.
B It allows heat transfer between the system and surroundings.
C It ensures constant pressure in the system.
D It prevents heat transfer between the system and surroundings.

The correct answer is:
It prevents heat transfer between the system and surroundings.

Solution:
The adiabatic wall in an adiabatic process prevents heat transfer between the system and its surroundings.

Topic: Chemistry, Thermodynamics (C), NEET
In an angiosperm, microsporangium is

Options:
A stamen
B pollen grains
C ovule
D pollen sacs

The correct answer is:
pollen sacs

Solution:
The anther is a bilobed and four-sided tetragonal structure having four microsporangia. These microsporangia later develop into a pollen sac where the pollen grain is formed. Each microsporangium or pollen sac has four walls - epidermis, endothecium, middle layer, and tapetum. Stamen is microsporophyll while pollen grains are microspores

Topic: Biology, Sexual Reproduction in Flowering Plants, NEET
In an animal cell, cytokinesis involves

Options:
A the separation of sister chromatids
B the contraction of the contractile ring of microfilament
C depolymerization of kinetochore microtubules
D a protein kinase that phosphorylaes other enzymes

The correct answer is:
the contraction of the contractile ring of microfilament

Solution:
In animal cells, cytokinesis involves the contraction of the contractile ring of microfilaments followed by cleavage and formation of daughter cells.

Topic: Biology, Cell Cycle and Cell Division, NEET
In an aquatic ecosystem, ______________ is the major conduit for energy flow.

Options:
A Detritus food chain
B Plankton food chain
C Grazing food chain
D Food web

The correct answer is:
Grazing food chain

Solution:
In an aquatic ecosystem, GFC is the major conduit for energy flow. As against this, in a terrestrial ecosystem, a much larger fraction of energy flows through the detritus food chain than through the GFC. Detritus food chain may be connected with the grazing food chain at some levels: some of the organisms of DFC are prey to the GFC animals, and in a natural ecosystem, some animals like cockroaches, crows, etc., are omnivores. This natural interconnection of food chains makes it a food web.

Topic: Biology, Ecosystem, NEET
In an aquatic ecosystem, maximum toxicity due to biomagnification will be seen in

Options:
A Phytoplanktons
B Zooplanktons
C Large fishes
D Fish-eating birds

The correct answer is:
Fish-eating birds

Solution:
A few toxic substances, often present in industrial
waste-waters can undergo biological magnification (biomagnification) in the aquatic food chain. Biomagnification refers to an increase in the concentration of the toxicant at successive trophic levels. This happens because a toxic substance accumulated by an organism cannot be metabolized or excreted, and is thus passed on to the next higher trophic level. This phenomenon is wellknown for mercury and DDT.

Topic: Biology, Environmental Issues, NEET
In an aquatic ecosystem, the trophic level equivalent to cows in grasslands is:

Options:
A Phytoplankton
B Zooplankton
C Nekton
D Benthos

The correct answer is:
Zooplankton

Solution:
In terrestrial ecosystem cow is primary consumer and occupies the second trophic level. Similarly in aquatic ecosystem phytoplanktons are producers, which occupy first trophic level and zooplanktons are the primary consumers which occupy the second trophic level.

Topic: Biology, Ecosystem, NEET
In an aqueous solution the correct order of mobility of alkali metal ions is ?

Options:
A Rb â > K â > Na â > Li â
B Li ⊕ > Na ⊕ > K ⊕ > Rb ⊕
C Na ⊕ > K ⊕ > Rb ⊕ > Li ⊕
D K ⊕ > Na ⊕ > Rb ⊕ > Li ⊕

The correct answer is:
Rb ⊕ > K ⊕ > Na ⊕ > Li ⊕

Solution:
Ionic mobility depends upon the size of the hydration sphere means greater the size cation lesser the hydration sphere and higher ionic mobility. that is
Ionic mobility â 1 Hydration sphere of alkali cation
Size of hydration sphere: Li + > Na + > K + > Rb + > Cs + â
Ionic Mobility: Li + < Na + < K + < Rb + < Cs +

Topic: Chemistry, s Block Elements, NEET
In an area, a population with large size individuals having a long life span, more parental care, and slow development was present. The type of population growth curve will be

Options:
A S-shaped
B J-shaped
C Initially J-shaped then S-shaped
D Initially S-shaped then J-shaped

The correct answer is:
S-shaped

Solution:
The population growth curve will be S-shaped or sigmoid or logistics.
The growth curve has five phases - lag phase, positive acceleration phase, and stationary phase. Most of the organisms including human population show S-shaped curve.

Topic: Biology, Organisms and Populations, NEET
In an area where DDT had been used extensively, the population of birds declined significantly because

Options:
A birds stopped laying eggs
B earthworms in the area got eradicated
C cobras were feeding exclusively on birds
D many of the birds eggs laid, did not hatch

The correct answer is:
many of the birds eggs laid, did not hatch

Solution:
DDT, its breakdown products and other chlorinated hydrocarbon pesticides posed an insidious threat to birds. These persistant poisons enter the food chain and they accumulate in the fatty tissues of organisms at lower trophic level and then tend to concentrate as they move through the food chain. This is called biomagnification or bioconcentration. The insidious aspect of this phenomenon is that large concentrations of chlorinated hydrocarbons do not usually kill the bird out right. Rather, DDT and its relatives alter the bird's calcium metabolism in a way that results in thin egg shells which are unable to support the weight of incubating bird. So, many of the birds eggs laid are not hatched. this causes a significant decline in the population of birds.

Topic: Biology, Environmental Issues, NEET, NEET 2012 (Screening)
In an astronomical telescope in normal adjustment a straight black line of the length L is drawn on inside part of objective lens. The eye-piece forms a real image of this line. The length of this image is l . The magnification of the telescope is:

Options:
A Ll-1
B L+lL-l
C Ll
D Ll+1

The correct answer is:
Ll

Solution:
Magnification by eyepiece
m=ff+u
-lL= fefe+(-(f0+fe)
â lL=fef0
m.p. =f0fe=Ll

Topic: Physics, Ray Optics, NEET, NEET 2015 (Phase 2)
In an atom, an electron is moving with a speed of 600 m/s with a certainty of 0.005% with which the position of the electron can be located is (h=6.6Ã10-34 kgm2s-1 , mass of electron =9.1Ã10-31 kg ):

Options:
A 5.10Ã10-3 m
B 1.92Ã10-3 m
C 3.84Ã10-3 m
D 1.52Ã10-3 m

The correct answer is:
1.92Ã10-3 m

Solution:
Îx.mÎv=h4Ï
Îx=h4ÏmÎv
Îv=600Ã0.005100
Îx=6.625Ã10-344Ã3.14Ã9.1Ã10-31Ã0.03
=1.92Ã10-3 m

Topic: Chemistry, Structure of Atom, NEET
In an E. coli strain, i gene gets mutated, and its product cannot bind the inducer molecule. If the growth medium is provided with lactose, what will be the outcome?

Options:
A z, y, a genes will be transcribed
B z, y, a genes will not be translated
C RNA polymerase will bind the promoter region
D Only z gene will get transcribed

The correct answer is:
z, y, a genes will not be translated

Solution:
Given above is the functioning of the normal lac operon in E. coli.

The question says that due to mutation, the product of i gene which is the repressor, cannot bind to the inducer molecule which is lactose.

The repressor gene binds to the operator region and does not allow the binding of RNA polymerase to the promoter region in the mRNA molecule.

If the repressor is absent, then it will not bind to the operator, the binding of RNA polymerase to the promoter region will be open always and there will be the transcription of lac z, y, and a genes.

Topic: Biology, Molecular Basis of Inheritance, NEET, NEET 2022 (Phase 1)
In an ECG, the depolarization of atria is indicated by

Options:
A P-wave
B Q-wave
C R-wave
D S-wave

The correct answer is:
P-wave

Solution:
ECG is the graphical recording of electrical changes that accompany the cardiac cycle. It is represented by five waves - P, Q, R, S and T. P-wave indicates depolarization of atria, QRS complex indicates ventricular depolarization, while T-wave indicates ventricular repolarization.

Topic: Biology, Body Fluids and Circulation, NEET
In an ecosystem,

1 cycling of energy and nutrients is a coupled process.
2 cycling of energy is an independent process.
3 movement of energy is unidirectional.
4 both macro and micro consumers are necessary.

Choose the correct option for statement/s which complete/s the above statement.

Options:
A only 1
B only 3
C 1 and 3 both
D only 4

The correct answer is:
1 and 3 both

Solution:
In an ecosystem cycling of energy and nutrient is a coupled process, which occurs simultaneously. Movement of energy is always unidirectional and occurs from producers to consumers. An ecosystem may function without macroconsumer but producer and microconsumer or decomposers are necessary for its functioning.

Topic: Biology, Ecosystem, NEET
In an ecosystem dominated by trees, the pyramid (of numbers) is ___ type.

Options:
A autotrophs
B inverted
C light
D earthworms

The correct answer is:
inverted

Solution:
In an ecosystem dominated by trees, the pyramid (of numbers) is inverted.

Topic: Biology, Ecosystem, NEET
In an ecosystem if the Net Primary Productivity (NPP) of first trophic level is $100 x\left(\mathrm{kcal} \mathrm{m}^{-2}\right) \mathrm{yr}^{-1}$, what would be the GPP (Gross Primary Productivity) of the third trophic level of the same ecosystem?

Options:
A $x\left(\mathrm{kcal} \mathrm{m}^{-2}\right) \mathrm{yr}^{-1}$
B $10 x\left(\mathrm{kcal} \mathrm{m}^{-2}\right) \mathrm{yr}^{-1}$
C $\frac{100 x}{3 x}\left(\mathrm{kcal} \mathrm{m}^{-2}\right) \mathrm{yr}^{-1}$
D $\frac{x}{10}\left(\mathrm{kcal} \mathrm{m}^{-2}\right) \mathrm{yr}^{-1}$

The correct answer is:
$10 x\left(\mathrm{kcal} \mathrm{m}^{-2}\right) \mathrm{yr}^{-1}$

Solution:
NPP at first trophic level would be the GPP for second trophic level. NPP at second trophic level would be GPP for third trophic level. Therefore, $100 x\left(\mathrm{kcal} / \mathrm{m}^2 / \mathrm{yr}\right.$ ) would be GPP at second trophic level and $100 x \times 10 \%\left(\mathrm{kcal} / \mathrm{m}^2 / \mathrm{yr}\right)$ i.e., $10 x\left(\mathrm{kcal} / \mathrm{m}^2 / \mathrm{yr}\right)$ energy would be GPP at third trophic level.

Topic: Biology, Ecosystem, NEET, NEET 2024
In an elastic collision of two billiard balls:

Options:
A total kinetic energy conserved during the short time of collision of the balls
B total potential energy conserved during the short time of collision of the balls
C total energy conserved during the short time of collision of the balls
D None of the above

The correct answer is:
total kinetic energy conserved during the short time of collision of the balls

Solution:
Correct Option is : (A)
total kinetic energy conserved during the short time of collision of the balls

Topic: Chemistry, Work Power Energy, NEET
In an electrical circuit $R, L, C$ and an $\mathrm{AC}$ voltage source are all connected in series. When $L$ is removed from the circuit, the phase difference between the voltage and the current in the circuit is $\pi / 3$. If instead, $C$ is removed from the circuit, the phase difference is again $\pi / 3$. The power factor of the circuit is

Options:
A $1 / 2$
B $1 / \sqrt{2}$
C 1
D $\sqrt{3} / 2$

The correct answer is:
1

Solution:
Here, phase difference
$\begin{aligned}
\tan \phi & =\frac{X_L-X_C}{R} \\
\tan \frac{\pi}{3} & =\frac{X_L-X_C}{R}
\end{aligned}$
When, $L$ is removed
$\begin{aligned}
& \sqrt{3}=\frac{X_C}{R} \\
& X_C=\sqrt{3} R
\end{aligned}$
When $C$ is removed
$\begin{gathered}
\tan \frac{\pi}{3}=\sqrt{3}=\frac{X_L}{R} \\
X_L=R \sqrt{3}
\end{gathered}$
Hence, in resonant circuit
$\begin{aligned}
\tan \phi & =\frac{\sqrt{3} R-\sqrt{3} R}{R}=0 \\
\phi & =0
\end{aligned}$
$\therefore$ Power factor $\cos \phi=1$
It is the condition of resonance therefore phase difference between voltage and current is zero and power factor is $\cos \phi=1$.

Topic: Physics, Alternating Current, NEET, NEET 2012 (Screening)
In an electrical circuit, the voltage is measured as $V=(200 \pm 4)$ volt and the current is measured as $I=(20 \pm 0.2) \mathrm{A}$. The value of the resistance is:

Options:
A $(10 \pm 4.2) \Omega$
B $(10 \pm 0.3) \Omega$
C $(10 \pm 0.1) \Omega$
D $(10 \pm 0.8) \Omega$

The correct answer is:
$(10 \pm 0.3) \Omega$

Solution:
$R=\frac{V}{l}=\frac{200}{20}=10 \Omega$
$\frac{\Delta R}{R}=\frac{\Delta V}{V}+\frac{\Delta l}{l}=\frac{4}{200}+\frac{0.2}{20}=\frac{4+2}{200}=\frac{6}{200}$
$\Rightarrow \Delta R=\frac{6}{200} \times R=\frac{6}{20}=\frac{3}{10}=0.3 \Omega$
$\therefore$ Resistance $=R \pm \Delta R=(10 \pm 0.3) \Omega$

Topic: Physics, Current Electricity, NEET, NEET 2024 (Re-NEET)
In an electromagnetic wave in free space the root mean square value of the electric field is Erms=6 V m-1. The peak value of the magnetic field is

Options:
A 1.41Ã10-8 T
B 2.83Ã10-8 T
C 0.70Ã10-8Â T
D 4.23Ã10-8Â T

The correct answer is:
2.83Ã10-8 T

Solution:
Speed of electromagnetic wave c is given by, ErmsBrms=c
Brms=Ermsc
=63×108
Brms=2×10-8
Brms=B02
B0= 2×Brms
= 2×2×10-8
=2.83×10-8 T

Topic: Physics, Electromagnetic Waves, NEET, NEET 2017
In an electron gun, the electrons are accelerated by a potential V. If e is the charge and m is the mass of an electron, then the maximum velocity of these electrons will be

Options:
A 2eVm
B 2eVm
C 2meV
D V22em

The correct answer is:
2eVm

Solution:
eV=12mv2⇒v2=2eVm⇒v=2eVm

Topic: Physics, Atomic Physics, NEET
In an electron transport chain, the cytochrome which donates electrons to O2 is

Options:
A Cytochrome b
B Cytochrome c
C Cytochrome a3
D Cytochrome a

The correct answer is:
Cytochrome a3

Solution:
Cytochrome a3 is the terminal cytochrome of ETC. It has Fe+3 and Cu+2 both. With Fe+3, it picks up electrons and through Cu+2, it passes electrons to oxygen.

Topic: Biology, Respiration in Plants, NEET
In an elementary reaction, what is the molecularity when only one reacting species is involved?

Options:
A Unimolecular
B Bimolecular
C Trimolecular
D Multimolecular

The correct answer is:
Unimolecular

Solution:
In an elementary reaction where only one reacting species is involved, the molecularity is referred to as "unimolecular".

Topic: Chemistry, Chemical Kinetics, NEET
In an enzyme-mediated reaction, Km value is:

Options:
A The substrate concentration at which the velocity of the chemical reaction is maximum
B The substrate concentration at which the velocity of the chemical reaction is half its maximum value
C The velocity of the chemical reaction at which the substrate concentration is maximum
D The velocity of the chemical reaction at which the substrate concentration is half its maximum value

The correct answer is:
The substrate concentration at which the velocity of the chemical reaction is half its maximum value

Solution:
Km (Michaelis Menten Constant) is the substrate concentration at which the chemical reaction attains half of its maximum velocity. With the increase in concentration of substrate, the enzymatic velocity also increases. At a certain value all the active site of the enzyme molecules are saturated. Increase in substrate concentration does not increase the velocity of the enzymatic reaction. Higher is the affinity of an enzyme for a substrate, lower is the Km value. Km value lies in between 10-1 to 10-6M . Km value is independent of enzyme and substrate concentration.

Topic: Chemistry, Biomolecules, NEET
In an equilateral triangle ABC, three equal masses of m kg each are fixed at its vertices. If the mass at vertex A is doubled, what will be the effect on the gravitational force between the masses?(Take AG = BG = CG = 1 m )

Options:
A $4G{{m}^{2}}\hat{j}$
B $4G{{m}^{2}}\hat{i}$
C $2G{{m}^{2}}\hat{j}$
D $2G{{m}^{2}}\hat{i}$

The correct answer is:
$2G{{m}^{2}}\hat{j}$

Solution:
Correct Option is : (C)
$2G{{m}^{2}}\hat{j}$

Topic: Chemistry, Gravitation, NEET
In an example (oxidation of ethane to CO2 and H2O), what type of reactions are the formation of alcohol, aldehyde, and acid?

Options:
A Consecutive reactions
B Reverse reactions
C Side reactions
D Simultaneous reactions

The correct answer is:
Consecutive reactions

Solution:
In the given example, the formation of alcohol, aldehyde, and acid represents consecutive reactions because they are intermediate steps in the overall oxidation of ethane.

Topic: Chemistry, Chemical Kinetics, NEET
In an experiment, 0.04 F was passed through 400 mL of a 1 M solution of NaCl. What would be the pH of the solution after the electrolysis?

Options:
A 8
B 10
C 13
D 6

The correct answer is:
13

Solution:
Electrolysis of NaCl (aq) gives hydrogen gas at cathode and oxygen gas at anode, the electrolyte solution contains NaOH after electrolysis.
Number of equivalents (W/E) of NaOH formed = 0.04
Normality =WE×V×1000
Normality, N=0.04×1000400=0.1
[OH-]=0.1 M
pOH =1
So pH = 13.

Topic: Chemistry, Some Basic Concepts of Chemistry, NEET
In an experiment, AaBb obtained in the F1 generation was test crossed. In the progeny, genotype Aabb and aaBb were more frequent than AaBb and aabb. Then the genotype of the parents should be

Options:
A AABB and aabb
B AAbb and aaBB
C AAbb and AABB
D AABB and aaBB

The correct answer is:
AAbb and aaBB

Solution:
Since Aabb and aaBb are more frequent, it means in parental condition, dominant and recessive alleles are present together. In parental condition, AAbb and aaBB are present representing trans-condition of linkage.

Topic: Biology, Principles of Inheritance and Variation, NEET
In an experiment, addition of 5.0 mL, of 0.006 M BaCl2 to 10.0 mL of arsenic sulphite sol just causes the complete coagulation in 34 h. The flocculating value of the effective ion is :

Options:
A 2
B 3
C 4
D 5

The correct answer is:
2

Solution:
As2S3 sol is negatively charged owing to preferential adsorption of S2- ions. Cation would be effective ion in coagulation.
Flocculating value = millimole of the effective ion per litre of sol = 5 × 0.006 × 1 0 3 5 + 1 0 = 2

Topic: Chemistry, Surface Chemistry, NEET
In an experiment during the analysis of carbon compound 145 cm3 of H2 was collected at 760 mm Hg pressure and 27° C temperature. The weight of H2 is nearly

Options:
A 10 mg
B 12 mg
C 24 mg
D 6 mg

The correct answer is:
12 mg

Solution:
n=PV/RT
P = 760 mm, Hg = 1 atm
V = 145  cm 3  = 0.145 L
T=27+273K=300K
R=0.0821 L atm mol-1K-1
So nâ=â 1âatmâÃâ0.145âL 0.082âLâatmâ mol â1 â K â1 â300âK
=5.9Ã10-3 mol
So weight of H 2 â=â5.9âÃâ 10 â3 âmolâÃâ 2âg 1âmol
= 11.8 mg≈12 mg.

Topic: Chemistry, States of Matter, NEET
In an experiment four quantities $a, b, c$ and $d$ are measured with percentage error $1 \%, 2 \%, 3 \%$ and $4 \%$ respectively. Quantity $P$ is calculated as follows
$P=\frac{a^3 b^2}{c d} \%$, Error in $P$ is

Options:
A $14 \%$
B $10 \%$
C $7 \%$
D $4 \%$

The correct answer is:
$14 \%$

Solution:
Here, $P=\frac{a^3 b^2}{c d}$
$\begin{aligned}
\therefore \frac{\Delta P}{P} & \times 100 = \left(\frac{3 \Delta a}{a}+\frac{2 \Delta b}{b}+\frac{\Delta c}{c}+\frac{\Delta d^{\prime}}{d}\right) \times 100 \\
= & 3 \frac{\Delta a}{a} \times 100+2 \frac{\Delta b}{b} \times 100+\frac{\Delta c}{c} \times 100+\frac{\Delta d^{\prime}}{d} \times 100 \\
= & 3 \times 1+2 \times 2+3+4 \\
= & 3+4+3+4=14 \%
\end{aligned}$

Topic: Physics, Mathematics in Physics, NEET, NEET 2013 (All India)
In an experiment, in pBR322 an alien DNA is introduced using Sal I. The transformant will grow on

Options:
A Tetracycline
B Ampicillin
C Both (A) and (B)
D None of these

The correct answer is:
Ampicillin

Solution:
Sal I restriction site is present in Tetracyclin resistant gene. If foreign DNA is inserted in Sal I site than the transformant will loss tetracycline-resistant nature due to insertional inactivation of foreign DNA.

Topic: Biology, Biotechnology - Principles and Processes, NEET
In an experiment it is shown that $10 \mathrm{ml}$ of $0.05 \mathrm{M}$ solution of chloride required 10 $\mathrm{ml}$ of $0.1 \mathrm{M}$ solution of $\mathrm{AgNO}_3$, which of the following will be the formula of the chloride ( $\mathrm{X}$ stands for the symbol of the element other than chlorine)

Options:
A $\mathrm{X}_2 \mathrm{Cl}_2$
B $\mathrm{XCl}_2$
C $\mathrm{XCl}_4$
D $\mathrm{X}_2 \mathrm{Cl}$

The correct answer is:
$\mathrm{XCl}_2$

Solution:
Millimoles solution of chloride $=$ $0.05 \times 10=0.5$
Millimoles of $\mathrm{AgNO}_3=10 \times 0.1=$ 0.1.
$\mathrm{XCl}_2+2 \mathrm{AgNO}_3 \rightarrow 2 \mathrm{AgCl}+\mathrm{X}\left(\mathrm{NO}_3\right)_2$

Topic: Chemistry, Some Basic Concepts of Chemistry, NEET, NEET 2013 (Karnataka)
In an experiment on the photoelectric effect, a student plots a graph of stopping potential (Vstop) against the frequency (ν) for two materials, A and B, as shown in Fig. 11.2. Which of the two materials, A or B, has a higher work function?

Options:
A Material A
B Material B
C Both have the same work function
D Insufficient data to determine

The correct answer is:
Material B

Solution:
Correct Option is : (B)
Material B

Topic: Chemistry, Dual Nature of Matter, NEET
In an experiment on the photoelectric effect, the slope of the cut-off voltage versus frequency of incident light is found to be 4.12 x 10-15 V s. The value of Planck's constant is

Options:
A 6.592 x 10-34 J s
B

6.592 x 10-31 J s

C 9.592 x 10-34 J s
D 6.592 x 10-30 J s

The correct answer is:
6.592 x 10-34 J s

Solution:
Given, slope of graph tan Î¸ = 4.12 x 10-15 V - s and charge on electron e = 1.6 x 10-19 C

For slope of graph tan Î¸ = V v
We know that
hv = eV
V v = h e
â´ h e = 4 . 1 2 Ã 1 0 - 1 5
h = 1.6 x 10-19 x 4.12 x 10-15
= 6.592 x 10-34 J - s.

Topic: Physics, Dual Nature of Matter, NEET
In an experiment, one set of plants were exposed to 12 hr day and 12 hr night and the plants flowered. The other set with similar exposure to the day-night period but with a dark period interrupted by the flash of light did not produce the flower. Such a plant is referred to as

Options:
A long day plants
B day-neutral plants
C indeterminate plants
D short day plants

The correct answer is:
short day plants

Solution:
Every plant requires a certain amount of light and darkness to grow and this aspect is known as photoperiodism. The plants which require only a short period of darkness to flower are known as long-day plants whereas the plants which require a short day length and the long period of darkness without any interruption by light are known as short-day plants. Day-neutral plants are those which flower in which spectrum of the amount of light it receives. The intermediate type of plants is one which does not require long periods of darkness or light to flower.

Topic: Biology, Plant - Growth and Development, NEET