datavorous/entrance-exam-dataset huggingface dataset:
If Cowper's glands are removed, it will affect

Options:
A Erection of penis
B Sperms
C Sex recognition
D Sexual behaviour

The correct answer is:
Sperms

Solution:
Cowper's gland is located inferior to the prostate gland and lateral to the urethra. The Cowper's glands are only found in the male body and play an important role in the protection of sperm during ejaculation by secreting an alkaline mucus fluid which neutralizes the acidity of urethra.

Topic: Biology, Human Reproduction, NEET
If d represents the bond length, then select the correct relation.

Options:
A d N 2  =  d N 2 +  and  d O 2 =  d O 2 +
B d N 2 <  d N 2 +  and  d O 2 > d O 2 +
C d N 2  <  d N 2 +  and  d O 2  <  d O 2 +
D d N 2  >  d N 2 +  and  d O 2  =  d O 2 +

The correct answer is:
d N 2 <  d N 2 +  and  d O 2 > d O 2 +

Solution:
Bond order â 1/bond length.
As bond order of N2=3,N2+=2.5
As bond order of O2=2,O2+=2.5
Here the correct order of bond length is
d N 2 <  d N 2 +  and  d O 2  >  d O 2 +

Topic: Chemistry, Chemical Bonding and Molecular Structure, NEET
If decomposers are removed, what will happen to the ecosystem?

Options:
A Energy cycle is stopped
B Mineral cycle is stopped
C Consumers cannot absorb solar energy
D Rate of decomposition of mineral increases

The correct answer is:
Mineral cycle is stopped

Solution:
The ecosystem will be filled by plant and animal wastes as there will be no decompositon of waste and the minerals will not get solubilized in the soil for the mineral cycle.

Topic: Biology, Ecosystem, NEET
If degree of dissociation of 2M CH3COOH is 10% then degree of dissociation of this acetic acid in 3 Molar CH3COONa solution will be

Options:
A =10%
B <10%
C >10%
D Cannot be determine

The correct answer is:
<10%

Solution:
Due to Common ion effect it will be less than 10% as in presence of common ions degree of dissociation decreases for weak electrolyte.

Topic: Chemistry, Ionic Equilibrium, NEET
If dimensions of critical velocity, vc of a liquid flowing through a tube are expressed as ηxρyrz, where, η, ρ and r are the coefficient of viscosity of liquid, density of liquid and radius of the tube, respectively, then, the values of x, y and z are given by

Options:
A -1, -1, 1
B -1, -1, -1
C 1, 1, 1
D 1, -1, -1

The correct answer is:
1, -1, -1

Solution:
Dimensions of velocity, coefficient of viscosity and density are,

v=LT-1

η=FAdvdx=MLT-2L2T-1=ML-1T-1

ρ=ML-3

Now, v=ηxρyrz

⇒LT-1=ML-1T-1xML-3yLz

Now, by using dimensional homogeneity, we will get,

M0=Mx+y

⇒y=-x

For T,

x=1

⇒y=-x=-1

For L,

1=-x-3y+z

⇒z=-1

Topic: Physics, Units and Dimensions, NEET, NEET 2015 (Phase 2)
If DNA contained sulphur instead of phosphorus and proteins contained phosphorus instead of sulfur, what would have been the outcome of Hershey and Chase experiment?

Options:
A No radioactive sulfur in bacterial cells
B Both radioactive sulfur and phosphorus in bacterial cells
C Radioactive sulfur in bacterial cells
D Radioactive phosphorus in bacterial cells

The correct answer is:
Radioactive sulfur in bacterial cells

Solution:
If Sulphur and Phosphorus change their presence in DNA and protein respectively the result of Hershey and Chase experiment will be reversed. Bacteria with radioactive sulphur formed at the base of Test Tube.

Topic: Biology, Molecular Basis of Inheritance, NEET, NEET 2022 (Phase 2)
If doubling the concentration of a reactant 'A' increases the rate 4 times and tripling the concentration of 'A' increases the rate 9 times, the rate is proportional to

Options:
A Concentration of ‘A’
B Square of concentration of ‘A’
C Under root of the concentration of ‘A’
D Cube of concentration of ‘A’

The correct answer is:
Square of concentration of ‘A’

Solution:
Based on rate law, rate of reaction depends on concentration of reactant with power of concentration term same as order of reactant.
Rate=AnBm
An=22=4,Bm=32=9

Topic: Chemistry, Chemical Kinetics, NEET
If due to some injury the chordae tendinae of the mitral valve of the human heart is partially non-functional, what will be the immediate effect?

Options:
A The flow of blood into the pulmonary artery will be reduced.
B The blood will tend to flow back into the right atrium.
C The flow of blood into the aorta will be reduced.
D Both (A) and (C)

The correct answer is:
The flow of blood into the aorta will be reduced.

Solution:
The chordae tendineae are a group of tough, tendinous strands in the heart. They are commonly referred to as the “heart strings” since they resemble small pieces of string. Functionally, the chordae tendineae play a vital role in holding the atrioventricular valves in place while the heart is pumping blood. The bicuspid valve is the valve in the heart between the left atrium and left ventricle. The valve opens to allow blood to flow from atrium into the ventricle. Thus if the bicuspid valve is partially non-functional, then the blood will flow back into the atrium and thus reducing flow of blood into the aorta.

Topic: Biology, Body Fluids and Circulation, NEET
If due to some injury, the chordae tendinae of the tricuspid valve of the human heart is partially non-functional, what will be the immediate effect?

Options:
A The flow of blood into the aorta will be slowed down
B The 'pace maker' will stop working
C The blood will tend to flow back into the left atrium
D The flow of blood into the pulmonary artery will be reduced

The correct answer is:
The flow of blood into the pulmonary artery will be reduced

Solution:
If cordae tendinae of the tricuspid valve become partially non-functional due to injury then flow of blood into the pulmonary artery will be reduced.

Topic: Biology, Body Fluids and Circulation, NEET
If due to some injury the chordae tendinae of the tricuspid valve of the human heart is partially non-functional, what will be the immediate effect?

Options:
A The flow of blood into the aorta will be slowed down
B The 'pacemaker' will stop working
C The blood will tend to flow back into the left atrium
D The flow of blood into the pulmonary artery will be reduced

The correct answer is:
The flow of blood into the pulmonary artery will be reduced

Solution:
Strong, thread-like tendons, called chordae tendinae, arise from papillary muscles and insert upon the flaps of tricuspid and bicuspid valves. The valves in the heart allow the flow of blood only in one direction, $i e$, from the atria to the ventricles and from the ventricles to the pulmonary artery or aorta. If chordae tendinae of the tricuspid valve became partially non-functional due to injury then the flow of blood into the pulmonary artery will be reduced.

Topic: Biology, Body Fluids and Circulation, NEET, NEET 2010 (Screening)
If due to some injury the chordae tendinae of the tricuspid valve of the human heart is partially non-functional, what will be the immediate effect?

Options:
A

The ‘pacemaker’ will stop working.

B

The flow of blood into the aorta will be slowed down.

C

The blood will tend to flow back into the left atrium.

D

The flow of blood into the pulmonary artery will be reduced.

The correct answer is:

The flow of blood into the pulmonary artery will be reduced.

Solution:
Tricuspid valve is the valve in the heart between the right atrium and right ventricle. The valve opens to allow blood to flow from atrium into the ventricle. Thus if tricuspid valve is partially non-functional, then the flow of blood into the pulmonary artery will be reduced.

Topic: Biology, Body Fluids and Circulation, NEET
If EA1 and EA2 for oxygen atom -142kJmol-1 and +844kJmol-1 . The energy released form 2O+2e-→2O- will be

Options:
A -986kJmol-1
B -702kJmol-1
C -284kJmol-1
D -1688kJmol-1

The correct answer is:
-284kJmol-1

Solution:
O+e-→O-
ΔH=-142kJmol-1
So 2O+2e-→2O-
ΔH=2×(-142)
=-284kJmol-1

Topic: Chemistry, Thermodynamics (C), NEET
If E→ and B→ represent electric and magnetic field vectors of an electromagnetic wave, the direction of propagation of the wave is along

Options:
A E→×B→
B B→×E→
C E→
D B→

The correct answer is:
E→×B→

Solution:
According to electromagnetic wave property, the electric field is perpendicular to the magnetic field. The direction of electromagnetic wave propagation will perpendicular to Eâ and Bâ .
i.e EâÃBâ=Câ

Topic: Physics, Electromagnetic Waves, NEET
If E and G respectively denote energy and gravitational constant, then EG has the dimensions of:

Options:
A [M]L0T0
B [M]L-1T-1
C M2L-1T0
D M2L-2T-1

The correct answer is:
M2L-1T0

Solution:
Dimensional Formulas,

Energy, [E]=M1L2T-2

Gravitational constant

[G]=Fr2M2=M1L1T-2×L2M2

[G]=M-1L3T-2

Now,

EG=ML2T-2M-1L3T-2=M2L-1T0

Correct option (3)

Topic: Physics, Units and Dimensions, NEET, NEET 2021
If Ecello for a given reaction is negative, which gives the correct relationships for the values of ΔG° and Keq ?

Options:
A ΔG°>0,Keq<1
B ΔG°>0,Keq>1
C ΔG°<0,Keq>1
D ΔG°<0,Keq<1

The correct answer is:
ΔG°>0,Keq<1

Solution:
ΔG°=-nFE°
When E° is negative, ΔG° will be positive.
ΔG°=-2.303RTlog10K
When ΔG° is positive, then the value of K will be less than 1.

Topic: Chemistry, Electrochemistry, NEET
If E denotes electric field in a uniform conductor, I corresponding current through it, vd is drift velocity of electrons and P denotes thermal power produced in the conductor, then which of the following graph is incorrect

Options:
A

B
C
D

The correct answer is:

Solution:
E=Vl=IRl=IÏlAl=neAvdÏlAl=nevdÏ
vd âE straight line
P=I2R=ElR2Ã R=E2l2ÏlÃA
â P â E2 Parabola
P â I2 (Parabola)

Topic: Physics, Current Electricity, NEET
If E denotes electric field in a uniform conductor, I corresponding current through it, vd is the drift velocity of electrons and P denotes thermal power produced in the conductor, then which of the following graph is incorrect

Options:
A

B
C
D

The correct answer is:

Solution:
E=Vl=IRl=IÏlAl=neAvdÏlAl=nevdÏ
vd âE straight line
P=I2R=ElR2Ã R=E2l2ÏlÃA
â P â E2 Parabola
P â I2 (Parabola)

Topic: Physics, Current Electricity, NEET
If EFe2+|Feo=-0.44 V, EFe3+|Fe2+o=0.77 V . The value of EFe3+|Feo is

Options:
A 0.33 V
B -0.0367V
C 0.11V
D -0.11V

The correct answer is:
-0.0367V

Solution:
Fe 2+ +2e â âFe;â ÎG 1 =â2F â0.44 A =ZaCO 3 =FeCO 3
Fe 3+ +e â â Fe 2+ ;â ÎG 2 =âF 0.77
So,
Fe 3+ +3e − →Fe; ΔG = −3F(E) =  ΔG 1 +ΔG 2
E=-0.0367 V

Topic: Chemistry, Electrochemistry, NEET
If E,m,J and G represent energy, mass, angular momentum and gravitational constant respectively, then the dimensional formula of EJ2m5G2 is

Options:
A [MLT-2]
B [M0L0T]
C [M0L2T0]
D Dimensionless

The correct answer is:
Dimensionless

Solution:
E=[ML2T-2]
J =[ML2T-1]
G=[M-1L3T-2]
EJ2M5G2ML2T-2ML2T-12M5M-1L3T-22=[M0L0T0]

Topic: Physics, Units and Dimensions, NEET
If each capacitor has capacitance C, then equivalent capacitance between A and B is

Options:
A 4C3
B 8C3
C 12C
D 5C12

The correct answer is:
8C3

Solution:
Mark equipotential points and redraw the circuit in order to identify series and parallel combinations.
Ceq.=4 × 2C×C2C+C=4× 2C3=8C3

Topic: Physics, Electrostatics, NEET
If each resistance r, is along the 12 edges of a cubical skeleton of uniform wires, then find the equivalent resistance between X and Y , where X and Y are the midpoints of two opposite edges of a face of the cube.

Options:
A 7r8
B r2
C 4r5
D 7r5

The correct answer is:
7r8

Solution:
Potential of point D and E and H and C are same. Hence,

Req=3r4+r2+r22=7r8

Topic: Physics, Current Electricity, NEET
If electrical force between two charges is 200 N and we increase 10% charge on one of the charges and decrease 10% charge on the other, then the electrical force between them for the same distance becomes

Options:
A 200 N
B 202 N
C 198 N
D 199 N

The correct answer is:
198 N

Solution:
Let two charges are q1 and q2 and r is the distance between them, then electrical force
F=14πε0⋅q1q2r2=200 N ..... (i)
If q1 is increased by 10%, then
q1′=110100q1
and q2 is decreased by 10%, then
q2′=90100q2
Then, the electrical force between them,
F′=14πε0×q1′q2′r2
F′=14πε0×110100q1×90100q2r2 .... (ii)
From equations (i) and (ii), we get
F′=200×99100⇒F′=198 N

Topic: Physics, Electrostatics, NEET
If elements with a principal quantum number n>4 were not allowed in nature, the number of possible elements would be

Options:
A 60
B 32
C 4
D 64

The correct answer is:
60

Solution:
The maximum number of electrons in an orbit are 2n2. If n>4, is not allowed, then the number of maximum electrons that can be in first four orbit are:
2(1)2 + 2(2)2 + 2(3)2 + 2(4)2 = 2 + 8 + 18 + 32 = 60
Therefore, possible elements can be 60.

Topic: Physics, Atomic Physics, NEET
If enough crosses are made between male flies of the genotype 'Aa' and the female flies of the genotype 'aa' to produce about 1000 offsprings. Which one of the following is the most likely distribution of genotypes in the offsprings?

Options:
A 250 Aa : 750 aa
B 750 Aa : 250 aa
C 243 AA : 517 Aa : 240 aa
D 481 Aa : 519 aa

The correct answer is:
481 Aa : 519 aa

Solution:
Crossing of Aa with aa is a test cross which produces the ratio of 1 Aa : 1 aa.

Topic: Biology, Principles of Inheritance and Variation, NEET
If enthalpy of atomisation for Br 2 l is x kJ/mol and bond enthalpy for Br2 is y kJ/mol , the relation between them

Options:
A is x<y
B is x>y
C does not exist
D is x=7y

The correct answer is:
is x>y

Solution:
Based on hess law it can be given as
As ΔHatomisation=ΔHVap.+ Bond Energy
Hence x>y

Topic: Chemistry, Thermodynamics (C), NEET
If equal volumes of BaCl2 and NaF solutions are mixed, which of these combinations will not give a precipitate?

Substance
Ksp

BaF2
1.7×10-7

Options:
A 0.004 M BaCl2 and 0.02 M NaF
B 0.010 M BaCl2 and 0.015 M NaF
C 0.015 M BaCl2 and 0.010 M NaF
D 0.020 M BaCl2 and 0.002 M NaF

The correct answer is:
0.020 M BaCl2 and 0.002 M NaF

Solution:
In the mixture of 0.02 M BaCl2 and 0.002 M NaF, the ionic product is less than solubility product, hence there will be no precipitate of BaF2 .

Topic: Chemistry, Ionic Equilibrium, NEET
If equilibrium constant for the reaction a A + b B⇋ c C + dD is Kc, then equilibrium constant for the reaction na A + nb B⇋ ncC + ndD is

Options:
A (Kc)II=(Kc)n
B c(K)II=1/(Kc)n
C (Kc)II=(Kc)n2
D (Kc)II=(Kc)1/n

The correct answer is:
(Kc)II=(Kc)n

Solution:
Correct Option is : 1
(Kc)II=(Kc)n

Topic: Chemistry, Chemical Equilibrium, NEET
If eye is kept at a depth h inside the water of refractive index and viewed outside, then the diameter of circle, through which the outer objects becomes visible, be

Options:
A hμ2+1
B hμ2-1
C 2hμ2-1
D h2μ2-1

The correct answer is:
2hμ2-1

Solution:
Let r be the radius of the circle through which other objects become visible. The ray of light must be incident at critical angle C.
sin⁡C=1μ=rr2+h2
μ2r2=r2+h2⇒ μ2-1r2=h2
⇒ r=hμ2-1
∴ Diameter=2r=2hμ2-1

Topic: Physics, Ray Optics, NEET
If $\overrightarrow{\mathrm{F}}=2 \hat{i}+\hat{j}-\hat{k}$ and $\vec{r}=3 \hat{i}+2 \hat{j}-2 \hat{k}$, then the scalar and vector products of $\vec{F}$ and $\vec{r}$ have the magnitudes respectively as:

Options:
A $5, \sqrt{3}$
B $4, \sqrt{5}$
C $10, \sqrt{2}$
D 10, 2

The correct answer is:
$10, \sqrt{2}$

Solution:
$\begin{aligned}
& \overrightarrow{\mathrm{F}}=2 \hat{i}+\hat{j}-\hat{k} \\
& \vec{r}=3 \hat{i}+2 \hat{j}-2 \hat{k} \text { (given) }
\end{aligned}$
The scalar product of $\overrightarrow{\mathrm{F}}$ and $\vec{r}$ is
$\begin{aligned}
\vec{F} . \vec{r} & =(2)(3)+(1)(2)+(-1)(-2) \\
& =6+2+2=10
\end{aligned}$
The vector product of $\vec{F}$ and $\vec{r}$ is
$\begin{aligned}
\overrightarrow{\mathrm{F}} \times \vec{r} & =\left|\begin{array}{ccc}
\hat{i} & \hat{j} & \hat{k} \\
2 & 1 & -1 \\
3 & 2 & -2
\end{array}\right| \\
& =\hat{i}[(1 \times-2)-(2 \times-1)]-\hat{j}[(2 \times-2) \\
& -(-1 \times 3)]+\hat{k}[(2 \times 2)-(3 \times 1)] \\
& =\hat{i}(0)-\hat{j}(-1)+\hat{k}(1)=\hat{j}+\hat{k}
\end{aligned}$
Magnitude $= \sqrt{(1)^2+(1)^2}=\sqrt{2}$

Topic: Physics, Mathematics in Physics, NEET, NEET 2022 (Phase 2)
If $\overrightarrow{\mathrm{F}}$ is the force acting on a particle having position vector $\vec{r}$ and $\vec{\tau}$ be the torque of this force about the origin, then

Options:
A $\overrightarrow{\mathrm{r}} \cdot \vec{\tau} \neq 0$ and $\overrightarrow{\mathrm{F}} \cdot \vec{\tau}=0$
B $\overrightarrow{\mathrm{r}} \cdot \vec{\tau}>0$ and $\overrightarrow{\mathrm{F}} \cdot \vec{\tau} < 0$
C $\overrightarrow{\mathrm{r}} \cdot \vec{\tau}=0$ and $\overrightarrow{\mathrm{F}} \cdot \vec{\tau}=0$
D $\overrightarrow{\mathrm{r}} \cdot \vec{\tau}=0$ and $\overrightarrow{\mathrm{F}} \cdot \vec{\tau} \neq 0$

The correct answer is:
$\overrightarrow{\mathrm{r}} \cdot \vec{\tau}=0$ and $\overrightarrow{\mathrm{F}} \cdot \vec{\tau}=0$

Solution:
Key Idea Torque is an axial yector ie, its direction is always perpendicular to the plane containing vectors $\overrightarrow{\mathrm{r}}$ and $\overrightarrow{\mathrm{F}}$.
$$
\vec{\tau}=\overrightarrow{\mathrm{r}} \times \overrightarrow{\mathrm{F}}
$$
Torque is perpendicular to both $\vec{r}$ and $\vec{F}$
$$
\therefore \quad \begin{aligned}
\vec{\tau} \cdot \overrightarrow{\mathrm{r}} & =0 \\
\overrightarrow{\mathrm{F}} \cdot \vec{\tau} & =0
\end{aligned}
$$

Topic: Physics, Rotational Motion, NEET, NEET 2009 (Screening)
If first ionization enthalpies of element $X$ and $Y$ are $419 \mathrm{~kJ} \mathrm{~mol}^{-1}$ and $590 \mathrm{~kJ} \mathrm{~mol}^{-1}$, respectively and second ionization enthalpies of $\mathrm{X}$ and $\mathrm{Y}$ are 3069 $\mathrm{kJ} \mathrm{mol}^{-1}$ and $1145 \mathrm{~kJ} \mathrm{~mol}^{-1}$, respectively. Then correct statement is :

Options:
A X is an alkali metal and $Y$ is an alkaline earth metal.
B X is an alkaline earth metal and $Y$ is an alkali metal.
C Both $X$ and $Y$ are alkali metals.
D Both $X$ and $Y$ are alkaline earth metals.

The correct answer is:
X is an alkali metal and $Y$ is an alkaline earth metal.

Solution:
The highest jump ion successive ionisation energy indicates a stable noble gas configuration.
The highest jump is observed in the $\mathrm{IE}_1 \& \mathrm{IE}_2$. It shows the attainment of stable noble gas configuration of $X$ after losing one electron. Hence, $\mathrm{X}$ is an alkali metal.
The $\mathrm{IE}_1$ of $Y$ is $+590 \mathrm{~kJ} \mathrm{~mol}^{-1}$ which is greater than $\mathrm{IE}_1$ of $X$ due to $n s^2$ configuration.
$\therefore \quad X=$ Alkali metal and $Y=$ Alkaline Earth metal

Topic: Chemistry, Classification of Elements and Periodicity in Properties, NEET, NEET 2022 (Phase 2)
If for a binary weak electrolyte the solubility product is 4×10-10 at 298K . Calculate its solubility in mol dm-3 at the same temperature

Options:
A 4×10-5
B 2×10-5
C 8×10-10
D 16×10-20

The correct answer is:
2×10-5

Solution:
AB⇌A++B-;Ksp=S2
S=Ksp=4×10-10=2×10-5

Topic: Chemistry, Ionic Equilibrium, NEET
If for a certain reaction ΔrH is 30 kJmol-1 at 450K, the value of ΔrS (in JK-1mol-1) for which the same reaction will be spontaneous at the same temperature is

Options:
A 70
B -33
C 33
D -70

The correct answer is:
70

Solution:
ΔG=ΔH-TΔS
For spontaneous,

ΔG<0
ΔH-TΔS<O
ΔS>ΔHT
ΔS>30×103Jmol-1450K
ΔS>66.6 Jmol-1K-1 (Check by options)

So, option (1) , i.e. \(70 \mathrm{~J} \mathrm{mol}^{-1} \mathrm{~K}^{-1}\) satisfies it.

Topic: Chemistry, Thermodynamics (C), NEET, NEET 2020 (Phase 2)
If for a radio-isotope, at the end of 4.2 days , N=0.798 N0 . What will be half-life period of its nucleus?

Options:
A 10 days
B 12.83 days
C 15 days
D 20 days

The correct answer is:
12.83 days

Solution:
t =  2.303 ×  t 1/2 0.693  log  N o N
t 1/2  =  4.2 × 0.693 2.303 × log N 0 0.796  N 0
∴ t 1/2 =12.83

Topic: Chemistry, Chemical Kinetics, NEET
If for hydrogen CP-CV=m and for the nitrogen CP-CV=n, where CP and Cv refer to specific heat per unit mass at constant pressure and specific heat per unit mass at constant volume respectively. The relation between m and n is

Options:
A m=14n
B n=7n
C m=9n
D n=16n

The correct answer is:
m=14n

Solution:
Here, for hydrogen Cp-Cv=m=R2
Or R=2m
And for nitrogen, Cp-Cv=n=R28 or R=28n
â´ 2m=28n
m=14n

Topic: Physics, Kinetic Theory of Gases, NEET
If for some reason our goblet cells are non-functional, this will adversely affect

Options:
A production of somatostatin
B secretion of sebum from the sebaceous glands
C maturation of sperms
D smooth movement of food down the intestine

The correct answer is:
smooth movement of food down the intestine

Solution:
Goblet cells are something like a wineglass that present in the columnar epithelium of the mammalian intestine and secrete mucin, a mucoprotein that forms mucus when in solution. If Goblet cells become non-functional, this will adversely affect smooth movement of food down the intestine due to absence of mucin.

Topic: Biology, Digestion and Absorption, NEET, NEET 2010 (Screening)
If for some reason our goblet cells become non-functional, it will adversely affect

Options:
A production of somatostatin
B secretion of sebum from the sebaceous glands
C maturation of sperms
D smooth movement of food down the intestine

The correct answer is:
smooth movement of food down the intestine

Solution:
Goblet cells, found in the intestinal mucosal epithelium, secrete mucus. the mucus lubricates the food for an easy passage. So, if for some reason, goblet cells become non-functional, it will adversely affect the smooth movement of food down the intestine.

Topic: Biology, Digestion and Absorption, NEET
If for some reason, the vasa efferentia in the human reproductive system get blocked, the gametes will not be transported from

Options:
A epididymis to vas deferens
B ovary to uterus
C vagina to uterus
D testes to epididymis

The correct answer is:
testes to epididymis

Solution:
Vasa efferentia (Ductuli efferences) are $10-20$ fine tubules which connect rete testis with an epididymis (Ductus epididymis). The latter is a pair of ducts from each testis which is formed by union of its vasa efferendia. If the vasa efferentia get blocked, the sperms will not be transported from testis to epididymis.

Topic: Biology, Excretory Products and their Elimination, NEET, NEET 2011 (Screening)
If for some reason, the vasa efferentia in the human reproductive system gets blocked, the gametes will not be transported from

Options:
A Epididymis to vas deferens
B Ovary to uterus
C Vagina to uterus
D Testes to epididymis

The correct answer is:
Testes to epididymis

Solution:
Vasa efferentia (Ductuli efferences) are 10-20 fine tubules which connect rete testis with an epididymis (Ductus epididymis). The latter is a pair of ducts from each testis which is formed by union of its vasa efferentia. If the vasa efferentia get blocked, the sperms will not be transported from testis to epididymis.

Topic: Biology, Human Reproduction, NEET
If Î G = Î H - T Î S and Î G = Î H + T d Î G dT , then variation of EMF of a cell E, with temperature T, is given by

Options:
A Δ H nF
B Δ G nF
C Δ S nF
D - Δ S nF

The correct answer is:
Δ S nF

Solution:
By comparision we get
Δ S = - d Δ G dT
by substituting Δ G = - nFE and rearranging we get
dE dT = Δ S nF

Topic: Chemistry, Thermodynamics (C), NEET
If g is the acceleration due to gravity at the Earth's surface, the gain of the potential energy of an object of mass m raised from the surface of the Earth to the height equal to the radius R of the Earth is

Options:
A mgR4
B mgR2
C mgR
D 2 mgR

The correct answer is:
mgR2

Solution:
Potential energy of an object at the surface of the Earth is
U1=-GMmR ..... (i)
Potential energy of the object at a height, h=R from the surface of the Earth.
U2=-GMmR+h=-GMmR+R
Gain in potential energy
âU=U2-U1= ( − GMm 2R )−( − GMm R )=12GMmR
Also, GM=gR2
âU=12gR2mR=mgR2

Topic: Physics, Gravitation, NEET
If g is the acceleration due to gravity on earth's surface, the gain of the potential energy of an object of mass m raised from the surface of the earth to a height equal to the radius R of the earth is

Options:
A 2mgR
B mgR
C 12mgR
D 14mgR

The correct answer is:
12mgR

Solution:
The potential energy of an object at the surface of the earth
U1=-GMmR â¦.i
The potential energy of the subject at a height h=R from the surface of the earth
U2=-GMmR+h=-GMmR+R â¦ii
Hence, the gain in potential energy of the object
âU=U2-U1
âU=-GMmR+R+GMmR
âU=-GMm2R+GMmR
âU=12GMmR
But we know that GM=gR2
Hence, âU=12gR2mR
or âU=12mgR

Topic: Physics, Gravitation, NEET