datavorous/entrance-exam-dataset huggingface dataset:
The correct differentiating point between trichome and root hair is

Options:
A Root hair is an epidermal structure while trichome is a hypodermal structure.
B Root hair is multicellular while trichome is unicellular
C Root hair helps in water absorption while trichome helps in prevention of water loss
D Root hair may be branched or unbranched but trichome is always branched.

The correct answer is:
Root hair helps in water absorption while trichome helps in prevention of water loss

Solution:
The root hairs are unicellular, unbranched elongations of the epidermal cells and help absorb water and minerals from the soil. The epidermal hairs on the stem are called trichomes. The trichomes are usually multicellular. They may be branched or unbranched and soft or stiff. They may even be secretory. The trichomes help in preventing water loss due to transpiration.

Topic: Biology, Anatomy of Flowering Plants, NEET
The correct explanation for the effect of catalyst on the rate of reversible reaction is

Options:
A It displaces the equilibrium state on right side
B It increases the kinetic energy of reacting molecules
C It provides a new reaction path of low activation energy
D It decreases the velocity of backward reaction

The correct answer is:
It provides a new reaction path of low activation energy

Solution:
Effect of catalyst is that it attains equilibrium quickly by providing a new reaction path of low activation energy. It does not alter the state of equilibrium.

Topic: Chemistry, Chemical Kinetics, NEET
The correct floral formula of chilli is

Options:
A

B

C

D

The correct answer is:

Solution:
Chilli (Capsicum annum) belongs to familySolanaceae. In this family, flower is actinomorphic, complete and bisexual; calyx has five sepals which are gamosepalous showing valvate aestivation; corolla has five petals which are polypetalous showing valvate aestivation; androecium has five free stamens (polyandrous) but epipetalous; gynoecium is bicarpellary, syncarpous, bilocular with superior ovary having axile placentation.

Topic: Biology, Morphology of Flowering Plants, NEET, NEET 2011 (Screening)
The correct floral formula of chilli is

Options:
A
B
C
D

The correct answer is:

Solution:
Chilli is the member of solanaceae, in which flowers are bisexual, actinomorphic ⊕, calyx-5 and gamosepalous, corolla - 5 and gamopetalous, androecium -5, free epipetalous basifixed, inferior, gynoecium - bicarpellary, syncarpous and ovary superior.
So, floral formula of chilli is

Topic: Biology, Morphology of Flowering Plants, NEET
The correct floral formula of soyabean is

Options:
A % + o â K ( 5 ) C 1 + ( 2 ) + 2 A ( 9 ) + 1 G ¯ 1
B % + o â K 5 C 1 + ( 2 ) + 2 A ( 9 ) + 1 G ¯ 1
C % + o â K ( 5 ) C 1 + 2 + ( 2 ) A ( 9 ) + 1 G ¯ 1
D % + o &nearr; K ( 5 ) C 1 + 2 + ( 2 ) A ( 9 ) + 1 G ¯ 1

The correct answer is:
% + o â K ( 5 ) C 1 + 2 + ( 2 ) A ( 9 ) + 1 G ¯ 1

Solution:
The family Fabacea is perigynous or hypogynous. They have monocarpellry gynoecium with unilocular superior ovary and have marginal placentation.

Topic: Biology, Morphology of Flowering Plants, NEET
The correct function of hormones of gastrointestinal tract is

Options:
A gastrin is inhibitory to the gastric glands but excitatory to the gall bladder.
B secretin is excitatory to pancreas but is inhibitory to the gastric glands.
C cholecystokinin is excitatory to the gall bladder but is inhibitory to the pancreas.
D pancreozymins is excitatory to the pancreas but is inhibitory to the gall bladder.

The correct answer is:
secretin is excitatory to pancreas but is inhibitory to the gastric glands.

Solution:
Gastrin is secreted by stomach and acts on the stomach. It stimulates the gastric gland to release gastric juice.
Secretin is secreted by duodenum and acts on the pancreas, liver, and stomach. It is excitatory to pancrease but is inhibitory to the gastric glands.
CCK (Cholecystokinin) is also known as pancreozymins and is secreted from small intestine and cause the release of digestive enzymes and bile from the pancreas and gallbladder, respectively.

Topic: Biology, Digestion and Absorption, NEET
The correct geometry and hybridization for XeF4 are

Options:
A octahedral, sp3d2.
B trigonal bipyramidal, sp3d.
C planar triangle, sp3d3.
D square planar, sp3d2.

The correct answer is:
square planar, sp3d2.

Solution:
Xenon is a noble gas that has 8 valence electrons. There are 4 Fluorine atoms attached or bonded with Xe, each of a single bond.
So, the number of lone pair or non-bonding electrons surrounding of xenon atom is 8–4=4 (that means: two lone pair electrons).

Therefore, XeF4 molecule has 4 bond pairs and 2 lone pairs in the molecule.

Thus, XeF4 2lp+4bp, has a square planar geometry, where the hybridization of Xe is sp3d2.

Topic: Chemistry, Chemical Bonding and Molecular Structure, NEET, NEET 2016 (Phase 2)
The correct graph between angle of deviation δ and angle of the incident i for a triangular prism is best represented by

Options:
A
B
C
D

The correct answer is:

Solution:
We know that the angle of deviation depends upon the angle of incidence. If we determine experimentally, the angles of deviation corresponding to different angles of incidence and then plot i (on x-axis) and Î´ (on y-axis) we get a curve as shown in the figure.
Clearly, if the angle of incidence is gradually increased from a small value, the angle of deviation first decreases, becomes minimum for a particular angle of incidence and then begins to increase.

Topic: Physics, Ray Optics, NEET
The correct graph between the temperature of a hot body kept in cooler surrounding and time is (Assume newton's law of cooling)

Options:
A

B

C

D

The correct answer is:

Solution:
The hot body in cooler surrounding cools exponentially.

Topic: Physics, Thermal Properties of Matter, NEET
The correct graph representing the variation of total energy E , kinetic energy K & potential energy U of a satellite with its distance from the centre of earth is

Options:
A
B
C
D

The correct answer is:

Solution:
U⁡=-GMmr ;
K=GMm2r ;
E=–GMm2r

Topic: Physics, Gravitation, NEET
The correct IUPAC name of CH3CH(OH)CH2CH2COOH is

Options:
A 4-hydroxypentanoic acid
B 1-carboxy-3-butanoic acid
C 1-carboxy-4-butanol
D 4-carboxy-2-butanol

The correct answer is:
4-hydroxypentanoic acid

Solution:
The principle functional group is -COOH and prifix is hydroxy (OH) in a five carbon chain.

Topic: Chemistry, Carboxylic Acid Derivatives, NEET
The correct increasing order for the wavelengths of absorption in the visible region for the complexes of Co3+ is:

Options:
A Coen33+, CoNH363+, CoH2O63+
B CoH2O63+, Coen33+, CoNH363+
C CoH2O63+, CoNH363+, Coen33+
D CoNH363+, Coen33+, CoH2O63+

The correct answer is:
Coen33+, CoNH363+, CoH2O63+

Solution:
The order of the ligand in the spectrochemical series
H2O<NH3<en
Absorbed wavelength∝1Absorbed energy
Thus, the order of observed energy is:
CoH2O63+<CoNH363+<Coen33+
Hence, the wavelength absorbed will be in the opposite order i.e., Coen33+< CoNH363+< CoH2O63+.

Topic: Chemistry, Coordination Compounds, NEET, NEET 2017
The correct increasing order of basic strength for the following compounds is

Options:
A 3 < 1 < 2
B 3 < 2 < 1
C 2 < 1 < 3
D 2 < 3 < 1

The correct answer is:
2 < 1 < 3

Solution:
Basic Nature of Amines ∝+I,+R∝1-I∝1-R

Topic: Chemistry, General Organic Chemistry, NEET
The correct increasing order of pH of 0.1 M solution of the following salts/acids is:

Options:
A NaCl<NH4Cl<NaCN<HCl
B HCl<NH4Cl<NaCl< NaCN
C NaCN<NH4Cl<NaCl<HCl
D HCl<NaCl<NaCN<NH4Cl

The correct answer is:
HCl<NH4Cl<NaCl< NaCN

Solution:
Let's analyse the nature of the given compounds:

Compound	Type of compound	Nature/pH

HCl	Strong acid

Strongly Acidic

pH=-log H+pH=-log 10-1pH=1

NH4Cl	Salt of a strong acid HCl and a weak base NH4OH	Acidic pH<7

NaCl	Salt of a strong acid HCl and a strong base NaOH	Neutral pH=7

NaCN	Salt of a weak acid HCN and a strong base NaOH	Basic pH>7

Topic: Chemistry, Ionic Equilibrium, NEET
The correct increasing order of solubility among the compounds follows as

Options:
A CaCO 3  <  NaHCO 3  <  KHCO 3
B KHCO 3  <  NaHCO 3  <  CaCO 3
C CaCO 3  <  KHCO 3  <  NaHCO 3
D NaHCO 3  <  KHCO 3  <  CaCO 3

The correct answer is:
CaCO 3  <  NaHCO 3  <  KHCO 3

Solution:
Alkaline earth metals carbonates are insoluble in water because of their high lattice energies.
Among alkali metals the solubility of bicarbonates increases down the group.

Topic: Chemistry, s Block Elements, NEET
The correct increasing order of the basic strength for the following compounds is:

Options:
A II<III<I
B III<I<II
C III<II<I
D II<I<III

The correct answer is:
II<I<III

Solution:
-NO2 has a strong –M effect and -CH3 shows +I, HC effect,
Basic strength ∝ +M, +I, HC
∴ Order of basic strength is:

Topic: Chemistry, Amines, NEET, NEET 2017
The correct increasing order of trans-effect of the following species is

Options:
A NH3>CN->Br->C6H5-
B CN->C6H5->Br->NH3
C Br->CN->NH3>C6H5-
D CN->Br->C6H5->NH3

The correct answer is:
CN->C6H5->Br->NH3

Solution:
The trans effect is the increased lability of ligands that are trans to certain other ligands, which can thus be regarded as trans-directing ligands. It is attributed to electronic effects and it is most notable in square planar complexes, although it can also be observed for octahedral complexes.

CN->C6H5->Br->NH3

Topic: Chemistry, Coordination Compounds, NEET, NEET 2016 (Phase 2)
The correct inorganic content of enzyme nitrogenase is

Options:
A Mo-Fe protein
B Mo-Mn protein
C Mn-Fe protein
D Cu-Fe protein

The correct answer is:
Mo-Fe protein

Solution:
Nitrogenase is an enzyme produced by bacteria used for reducing nitrogen to ammonia. This enzyme complex contains molybdenum-iron protein chain along with a smaller iron protein.

Topic: Biology, Mineral Nutrition, NEET
The correct IUPAC name for $\left[\mathrm{CrF}_2(e n)_2\right]$ $\mathrm{Cl}$ is:

Options:
A chloro difluorido ethylene diaminechromium (III) chloride
B difluoridobis (ethylene diamine) chromium (III) chloride
C diffluorobis-(ethylene diamine) chromium (III) chloride
D chloro difluoridobis (ethylene diamine) chromium (III)

The correct answer is:
difluoridobis (ethylene diamine) chromium (III) chloride

Solution:
As per IUPAC rules the nomenclature of $\left[\mathrm{CrF}_2(e n)_2\right] \mathrm{Cl}$ is difluoridobis (ethylene diamine chromium (III) chloride

Topic: Chemistry, Coordination Compounds, NEET, NEET 2013 (Karnataka)
The correct IUPAC name of [Cr(H2O)5(NCS)][ZnBr4] is

Options:
A pentaaqua isothiocyanato chromate (II) tetra bromozincate (II)
B pentaaqua isothio cyanate zinc bromide chromate (III)
C pentaaqua isothiocyanato chromium (III) tetra bromozincate (II)
D isothio cyanatopenta aqua ammine chromium (II) zinc chloride (IV)

The correct answer is:
pentaaqua isothiocyanato chromium (III) tetra bromozincate (II)

Solution:
the correct IUPAC name of the following compound is [Cr(H2O)5(NCS)][ZnBr4]
pentaaqua isothiocyanato chromium (III) tetra bromozincate (II)

Topic: Chemistry, Coordination Compounds, NEET
The correct IUPAC name of compound [Co(NH3)5NO2]Cl2 is:

Options:
A Pentamminenitrocobalt (III) chloride
B Pentamminenitrosocobalt (III) chloride
C Pentamminenitraetcobalt (III) chloride
D None of these

The correct answer is:
Pentamminenitrocobalt (III) chloride

Solution:
In the compounds [Co(NH3)5NO2]Cl2 , the oxidation state of cobalt is +3 and here 5 NH3 ligand, a NO2 ligand are attached to the central atom. therefore its name is pentaamminecobalt (III) chloride.

Topic: Chemistry, Coordination Compounds, NEET
The correct IUPAC name of the complex [Cr(NH3)5(NCS)][ZnCl4] is

Options:
A Pentaammine isothiocyanato chromium (III) tetrachloro zincate (II)
B Pentaammine isothiocyanato chromium (IV) tetrachloro zincate (III)
C Tetrachloro zincate (II) pentaammine isothiocyanato chromium (III)
D Pentaammine tetrachloro zincate (II) isothiocyanato chromium (III)

The correct answer is:
Pentaammine isothiocyanato chromium (III) tetrachloro zincate (II)

Solution:
The correct IUPAC name of the complex [Cr(NH3)5(NCS)][ZnCl4] is
Pentaammine isothiocyanato chromium (III) tetrachloro zincate (II).

Topic: Chemistry, Coordination Compounds, NEET
The correct IUPAC name of the compound given below is

Options:
A 3-ethyl-6-formylheptanoic acid
B 3-ethyl-6-methyl-7-oxoheptanoic acid
C 3-ethyl-6-methyl heptan-7-aloic acid
D 5-ethyl-2-methyl-1-oxoheptanoic acid

The correct answer is:
3-ethyl-6-methyl-7-oxoheptanoic acid

Solution:
3-ethyl-6-methyl-7-oxoheptanoic acid
The selected chain is the longest chain and has more number of locants than the other seven membered chains.

Topic: Chemistry, General Organic Chemistry, NEET
The correct IUPAC name of the compound
is

Options:
A 3-ethyl-4-ethenylheptane
B 3-ethyl-4-propylhex-5-ene
C 3-(1-ethyl propyl) hex-1-ene
D 4-ethyl-3-propylhex-1-ene

The correct answer is:
4-ethyl-3-propylhex-1-ene

Solution:
$$
\text { 4-Ethyl-3-propylhex-1-ene }
$$

Topic: Chemistry, General Organic Chemistry, NEET, NEET 2011 (Screening)
The correct IUPAC name of the compound

Options:
A 4-ethyl-1-fluoro-2-nitrobenzene
B 4-ethyl-1-fluoro-6-nitrobenzene
C 3-ethyl-6-fluoro-1-nitrobenzene
D 1-ethyl-4-fluoro-3-nitrobenzene

The correct answer is:
4-ethyl-1-fluoro-2-nitrobenzene

Solution:
4-ethyl-1-fluoro-2-nitrobenzene

Topic: Chemistry, General Organic Chemistry, NEET, NEET 2024 (Re-NEET)
the correct IUPAC name of the following compound [Cr(NH3)5(NCS)][ZnCl4] is

Options:
A pentaammine isothiocyanato chromium (III) tetra chlorozincate (II)
B pentammine isothio cyanatezinc chloride chromate (III)
C pentaammine isothiocyanato chromate (II)
D isothio cyanatopenta ammine chromium (II) zinc chloride (IV)

The correct answer is:
pentaammine isothiocyanato chromium (III) tetra chlorozincate (II)

Solution:
the correct IUPAC name of the following compound is [Cr(NH3)5(NCS)][ZnCl4]
pentaammine isothiocyanato chromium (III) tetra chlorozincate (II)

Topic: Chemistry, Coordination Compounds, NEET
The correct IUPAC name of the following compound is

Options:
A 1-ethyl-3-isopropyl-5-propylcyclohexane
B 1-ethyl-3-isopropyl-5-ethylcyclohexane
C 3-ethyl-5-isopropylpropylcyclohexane
D 3-ethyl-5-propyl isopropylcyclohexane

The correct answer is:
1-ethyl-3-isopropyl-5-propylcyclohexane

Solution:
1-ethyl-3-isopropyl-5-propylcyclohexane
Since all the alkyl groups are equidistant, numbering is done in alphabetical order.

Topic: Chemistry, General Organic Chemistry, NEET
The correct IUPAC name of the following compound is:

Options:
A 6-bromo-2-chloro-4-methylhexan-4-ol
B 1-bromo-4-methyl-5-chlorohexan-3-ol
C 6-bromo-4-methyl-2-chlorohexan-4-ol
D 1-bromo-5-chloro-4-methylhexan-3-ol

The correct answer is:
1-bromo-5-chloro-4-methylhexan-3-ol

Solution:
The root word in the given structure should be hex and alcoholic group forms the suffix and as per the least sum rule of the substituents the position of the substituents that is bromo, chloro and methyl groups should be 1,5 and 4 respectively.

The functional group with highest priority should be getting least possible number in position.

Hence,The correct IUPAC name of the given molecule is 1-bromo-5-chloro-4-methylhexan-3-ol.

Topic: Chemistry, General Organic Chemistry, NEET, NEET 2022 (Phase 1)
The correct IUPAC name of the following compound is:

Options:
A 7-Ethyl-2,4,5,6-tetramethyldeca-1,8-diene
B 4-Ethyl-5,6,7,9-tetramethyldeca-2,9-diene
C 2,4,5,6-tetramethyl-7-ethyldeca-1,7-diene
D None of these

The correct answer is:
7-Ethyl-2,4,5,6-tetramethyldeca-1,8-diene

Solution:
Longest chain of 10-C including both double bonds.
7-Ethyl-2,4,5,6-tetramethyldeca-1,8-diene

Topic: Chemistry, General Organic Chemistry, NEET
The correct match between column I and column II is

Column I	Column II

(1) Ester test	(P) Tyr

(2) Carbylamine test	(Q) Asp

(3) Phthalein dye test	(R) Ser

(S) Lys

Options:
A (1)—(Q);(2)—(S);(3)—(P)
B (1)—(R);(2)—(Q);(3)—(P)
C (1)—(Q);(2)—(S);(3)—(R)
D (1)—(R);(2)—(S);(3)—(Q)

The correct answer is:
(1)—(Q);(2)—(S);(3)—(P)

Solution:
(P) Tyrosine Tyr
Due to phenolic group gives phthalein test.
(Q) Aspartic acid ASP
As it is acidic amino acid so gives ester test.
(R) Serine Ser

(S) Lysine

As it is basic amino acid ( Pri.amine group. )so gives carbyl amine test.

Topic: Chemistry, Biomolecules, NEET
The correct match between ItemI and ItemII is

ItemI (drug)	ItemII (test)

(1) Chloroxylenol	(P) Carbylamine test

(2) Norethindrone	(Q) Sodium Hydrogen carbonate test

(3) Sulphapyridine	(R) Ferric chloride test

(4) Penicillin	(S) Bayer's test

Options:
A 1 — Q; 2 — P; 3 — S; 4 — R
B 1 — R; 2 — P; 3 — S; 4 — R
C 1 — R; 2 — S; 3 — P; 4 — Q
D 1 — Q; 2 — S; 3 — P; 4 — R

The correct answer is:
1 — R; 2 — S; 3 — P; 4 — Q

Solution:
(1) Chloroxylenol
FeCl3 test (due to phenolic group)
(2) Norethindrone
Bayer's test (due to C º C)
(3) Sulphapyridine
Carbyl amine test (due to 1° NH2 )
(4) Penicillin
Sodium hydrogen carbonate test (due to COOH group)

Topic: Chemistry, Chemistry in Everyday Life, NEET
The correct match between item 'I' and item 'II' is

Item I (Compound)	Item II (Reagent)

(1) Lysine	(P) 1-naphthol

(2) Furfural	(Q) ninhydrin

(3) Benzyl alcohol	(R) KMnO4

(4) Styrene	(S) Ceric ammonium Nitrate

Options:
A 1 — Q; 2 — P; 3 — S; 4 — R
B 1 — Q; 2 — R; 3 — S; 4 — P
C 1 — Q; 2 — P; 3 — R; 4 — S
D 1 — R; 2 — P; 3 — Q; 4 — S

The correct answer is:
1 — Q; 2 — P; 3 — S; 4 — R

Solution:
Lysine can be tested by ninhydrin as ninhydrin test is for testing amino acids.
Furfural can be tested by 1-naphthol.
Benzyl alcohol can be tested by Ceric ammonium nitrate which is a yellow reagent and on reaction with alcohol changes to red Styrene can be tested by KMnO4 as styrene decolourises alk. KMnO4 .

Topic: Chemistry, Biomolecules, NEET
The correct match between Item I and Item II is

Item I	Item II

(1) Norethindrone	(P) Anti-biotic

(2) Ofloxacin	(Q) Anti-fertility

(3) Equanil	(R) Hypertension

(S) Analgesics

Options:
A 1—R; 2—P; 3—S
B 1—Q; 2—P; 3—R
C 1—R; 2—P; 3—R
D 1—Q; 2—R; 3—S

The correct answer is:
1—Q; 2—P; 3—R

Solution:
(1) Norethindrone — Antifertility drug
(2) Ofloxacin — Anti – Biotic
(3) Equanil — Hypertension (tranquailizer)

Topic: Chemistry, Chemistry in Everyday Life, NEET
The correct match between Item-I and Item-II is

Item I	Item II

(p) High density polythene	(I) Peroxide catalyst

(q) Polyacrylonitrile	(II) Condensation at high temperature and pressure

(r) Novolac	(III) Ziegler-Natta catalyst

(s) Nylon 6	(IV) Acid or base catalyst

Options:
A (p)-(III), (q)-(I), (r)-(II), (s)-(IV)
B (p)-(IV), (q)-(II), (r)-(I), (s)-(III)
C (p)-(II), (q)-(IV), (r)-(I), (s)-(III)
D (p)-(III), (q)-(I), (r)-(IV), (s)-(II)

The correct answer is:
(p)-(III), (q)-(I), (r)-(IV), (s)-(II)

Solution:
Item I	Item II

(p) High density polythene	(III) Ziegler-Natta catalyst

(q) Polyacrylonitrile	(I) Peroxide catalyst

(r) Novolac	(IV) Acid or base catalyst

(s) Nylon 6	(II) Condensation at high temperature and pressure

High density polythene is obtained by using Ziegler Natta catalyst. Polyacrylo nitrile is gap obtained by acrylonitrile using peroxide as catalyst. Novolac is obtained in the presence of H+ (or) OH- as catalyst. Nylon-6 is condensation polymer of caprolactam at high temperature and pressure.

Topic: Chemistry, Polymers, NEET
The correct match between items of List-I and List-II is

List-I	List-II

1.	Coloured impurity	P.	Steam distillation

2.	Mixture of o-nitrophenol and p-nitrophenol	Q.	Fractional distillation

3.	Crude Naphtha	R.	Charcoal treatment

4.	Mixture of glycerol and sugars	S.	Distillation under reduced pressure

Options:
A 1-R,2-S,3-P,4-Q
B 1-R,2-P,3-Q,4-S
C 1-P,2-S,3-R,4-Q
D 1-R,2-P,3-S,4-Q

The correct answer is:
1-R,2-P,3-Q,4-S

Solution:
Here the correct option is as follows
1-R,2-P,3-Q,4-S

List-I	List-II

1.	Coloured impurity	R.	Charcoal treatment

2.	Mixture of o-nitrophenol and p-nitrophenol	P.	Steam distillation

3.	Crude Naphtha	Q.	Fractional distillation

4.	Mixture of glycerol and sugars	S.	Distillation under reduced pressure

Topic: Chemistry, General Organic Chemistry, NEET
The correct match between items of List-I and List-II is

List - I	List - II

(A)	Coloured impurity	(P)	Steam distillation

(B)	Mixture of o â nitrophenol and p ânitrophenol	(Q)	Fractional distillation

(C)	Crude Naphtha	(R)	Charcoal treatment

(D)	Mixture of glycerol and sugars	(S)	Distillation under reduced pressure

Options:
A (A)-(R),(B)-(S),(C)-(P),(D)-(Q)
B (A)-(P),(B)-(S),(C)-(R),(D)-(Q)
C (A)-(R),(B)-(P),(C)-(Q),(D)-(S)
D (A)-(R),(B)-(P),(C)-(S),(D)-(Q)

The correct answer is:
(A)-(R),(B)-(P),(C)-(Q),(D)-(S)

Solution:
(A)-(R),(B)-(P),(C)-(Q),(D)-(S)
1.Coloured impurity → Charcoal treatment
2.mixture of o – nitrophenol and p –nitrophenol → Steam distillation(Both form intermolecular H-Bond)
3.Crude Naphtha → Fractional distillation
4.mixture of glycerol and sugars → Distillation under reduced pressure

Topic: Chemistry, General Organic Chemistry, NEET
The correct match of the group of protozoans with the correct example.

Protozoan	Example

P	Amoeboid protozoan	i	Plasmodium

Q	Sporozoan	ii	Trypanosoma

R	Ciliated protozoan	iii	Paramoecium

S	Flagellated protozoan	iv	Entamoeba

Options:
A P-iv, Q-iii, R-ii, S-i
B P-i, Q-ii, R-iii, S-iv
C P-ii, Q-iii, R-iv, S-i
D P-iv, Q-i, R-iii, S-ii

The correct answer is:
P-iv, Q-i, R-iii, S-ii

Solution:
The species mentioned in Column II represent one of the group/class given in Column I basis their characteristics. Therefore, Entamoebais a genus of Amoebozoa. Plasmodium is one of the parasitic & pathogenic species of sporozoans. Paramoecium is a genus of ciliated protozoa and lastly, Trypanosomabelongs to the group of protozoans with the flagellum.

Topic: Biology, Biological Classification, NEET
The correct meaning of the expression 'gynoecium is apocarpous' is

Options:
A gynoecium comprises only one pistil which is fused with stamens
B gynoecium comprises more than one carpel, all of which are free.
C gynoecium comprises more than one carpel, which are fused.
D gynoecium comprises only one carpel, which is free.

The correct answer is:
gynoecium comprises more than one carpel, all of which are free.

Solution:
The gynoecium is the female reproductive part of flower and its unit is carpel or pistil. If gynoecium carpel may be single (monocarpellary) or several (multicarpellary). In multicarpellary condition, carpels may be free (apocarpous) or fused (syncarpous). Apocarpous gynoecium can be seen in lotus, rose, etc., while syncarpous gynoecium can be seen in mustard, tomato, etc.

Topic: Biology, Morphology of Flowering Plants, NEET
The correct measure of magnetic hardness of a material is

Options:
A remanant magnetism
B hysterses loss
C coercivity
D curie temperature

The correct answer is:
coercivity

Solution:
The correct measure of the hardness of a material is its coercivity, i.e., the field strength required to be applied in the opposite direction to reduce the residual magnetism of the specimen to zero.

Topic: Physics, Magnetic Properties of Matter, NEET
The CORRECT names at 'X', 'Y' & 'Z' respectively are

Options:
A X-Endosperm, Y-Pericarp, Z-Scutellum
B X-Pericarp, Y-Mesocarp, Z-Scutellum
C X-Scutellum, Y-Endosperm, Z-Pericarp
D X-Endosperm, Y-Scutellum, Z-Pericarp

The correct answer is:
X-Endosperm, Y-Pericarp, Z-Scutellum

Solution:
In the seeds of cereals such as maize the seed coat is membranous and generally fused with the fruit wall. The endosperm is bulky and stores food. The outer covering of endosperm separates the embryo by a proteinous layer called aleurone layer. The embryo is small and situated in a groove at one end of the endosperm. It consists of one large and shield shaped cotyledon known as scutellum and a short axis with a plumule and a radicle. The plumule and radicle are enclosed in sheaths which are called coleoptile and coleorhiza respectively.

Topic: Biology, Morphology of Flowering Plants, NEET