datavorous/entrance-exam-dataset huggingface dataset:
If alien DNA is introduced using Pst I in pBR322 then transformant will grow on:

Options:
A Ampicillin
B Tetracycline
C Both A and B
D None of these

The correct answer is:
Tetracycline

Solution:
TetR gene in pBR322 can be cleaved by Bam I and Sal I, while AmpR gene in pBR322 is cleaved by Pst I and Pvu I. If foreign DNA segment is inserted in Pst I site than ampicillin-resistant gene becomes inactive due to insertional inactivation and transformant can be grown on tetracycline containing medium.

Topic: Biology, Biotechnology - Principles and Processes, NEET
If alien DNA is introduced using Sal I in pBR322 then transformant will grow on

Options:
A Ampicillin
B Tetracycline
C Both a and b
D None of these

The correct answer is:
Ampicillin

Solution:
Sal I restriction site is present in the tetracyclin resistant gene. If foreign DNA is inserted in the Sal I site then the transformant will lose tetracycline-resistant nature due to the insertional inactivation of the tetracycline gene with the insertion of the foreign DNA. The ampicillin-resistant gene will be active and hence, the transformants will grow of ampicillin containing media.

Topic: Biology, Biotechnology - Principles and Processes, NEET
If all meters are ideal and the reading of the voltmeter 3 is 6 V, then power supplied by the voltage source is

Options:
A 10 W
B 38 W
C 20 W
D 30 W

The correct answer is:
30 W

Solution:
Current through 2 0 Ω= 620
current through 1 0 Ω= 610
Total current supplied by voltage source
=610+620
= 0.9 A
Voltage of battery = 6 + 27 = 33 volt
Power supplied =910× 33
= 29.7 or 30 W ( Approx )

Topic: Physics, Current Electricity, NEET
If all nitrogenase enzymes are inactivated, then there will be no

Options:
A Fixation of nitrogen in legumes
B Fixation of atmospheric nitrogen
C Conversion from nitrate to nitrite in legumes
D Conversion from ammonium to nitrite in soil

The correct answer is:
Fixation of nitrogen in legumes

Solution:
Nitrogenase is an enzyme involved in biological nitrogen fixation. If this enzyme is inactivated then the nitrogen fixation will not be observed and this is very specific for legumes. Enzyme nitrate reductase is involved in conversion of nitrate to nitrate. Conversion of ammonia to nitrate is carried out by Nitrosomonas and Nitrobacter .

Topic: Biology, Mineral Nutrition, NEET
If all the electrolytes are removed from the colloid by persistent dialysis then

Options:
A Colloid becomes extremely stable
B Colloids get coagulated
C No effect is observed
D Colloids convert into true solution

The correct answer is:
Colloids get coagulated

Solution:
If all ions are removed the colloidal particles get neutrelized and associate with each other forming suspensions.

Topic: Chemistry, Surface Chemistry, NEET
If all the electrolytes are removed from the colloid by persistent dialysis then

Options:
A Colloid becomes extremely stable
B Colloids get coagulated
C No effect is observed
D Colloids convert into true solution

The correct answer is:
Colloids get coagulated

Solution:
If all ions are removed the colloidal particles get neutralized and associate with each other forming suspensions.

Topic: Chemistry, Surface Chemistry, NEET
If alpha, beta and gamma rays carry the same momentum, which has the longest wavelength?

Options:
A Alpha rays
B Beta rays
C Gamma rays
D None, all have the same wavelength

The correct answer is:
None, all have the same wavelength

Solution:
On the basis of dual nature of light, de-Broglie suggested that the dual nature is not only of light, but each moving material particle has the dual nature. He assumed a wave to be associated with each moving material particle which is called the matter-wave. The wavelength of this wave is determined by the momentum of the particle. If p is the momentum of the particle, the wavelength of the wave associated with it is
λ=hp, where h is Planck's constant.
Since, it is given that, alpha, beta and gamma rays carry the same momentum, so they will have the same wavelength.

Topic: Physics, Atomic Physics, NEET
If an agricultural field is liberally irrigated for a prolonged period of time, it is likely to face problem of

Options:
A metal toxicity
B alkalinity
C acidity
D salinity

The correct answer is:
salinity

Solution:
Salinity of soil is a problem faced by farmers if they liberally irrigate agricultural field for a prolonged period of time.
Irrigation salinity is the accumulation of salts in the topsoil under irrigation. It is caused by over irrigation of agricultural land, inefficient water use, poor drainage and the irrigation of unsuitable and leaky soils.

Topic: Biology, Environmental Issues, NEET, NEET 2019 (Odisha)
If an agronomist is trying to induce flowering in a short-day plant and unknowingly it gets exposed to light for some amount of time. What will be the consequence of this plant?

Options:
A It will undergo etiolation.
B It will resume its cycle and induce flower.
C It will not flower.
D It will show extensive flowering.

The correct answer is:
It will not flower.

Solution:
Short day plants will only flower if they are exposed to a short period of daylight and long periods of darkness. If the dark period is interrupted, the plant will not flower. Hence, short-day plants are also called long night plants, e.g., rice, soyabean, etc.

Topic: Biology, Plant - Growth and Development, NEET
If an alpha particle and a proton are accelerated from rest by a potential difference of 1 MeV, then the ratio of their kinetic energies will be

Options:
A 3
B 1
C 2
D 4

The correct answer is:
2

Solution:
From conservation of mechanical energy
ΔKE=qVi-Vf
KαKp=2eVeV
KαKp=21

Topic: Physics, Electrostatics, NEET
If an angiospermic male plant is a diploid and female plant tetraploid, the ploidy level of endosperm will be

Options:
A Haploid
B Triploid
C Tetraploid
D Pentaploid

The correct answer is:
Pentaploid

Solution:
The male gamete will be haploid (n). Two polar nuclei will be diploid (2n). Endosperm formed by the fusion of male gamete with two polar nuclei will be pentaploid.
Male gamete n + 2 Polar nuclei 2 n + 2 n ⟶ Endosperm 5 n

Topic: Biology, Sexual Reproduction in Flowering Plants, NEET
If an artificial satellite is moving in a circular orbit around the earth with a speed equal to half the magnitude of the escape velocity from the earth. The height of the satellite above the surface of the earth is

Options:
A R
B 2R
C 3R
D 4R

The correct answer is:
R

Solution:
V0=Ve2=122GMR⇒Gm2R ...(i)
V0=GmR+h ...(ii)
Compare (i) & (ii) ; h=R

Topic: Physics, Gravitation, NEET
If an astronaut inside a small spaceship orbiting around the Earth cannot detect gravity, can he hope to detect gravity if the space station orbiting around the Earth has a large size?

Options:
A Yes, detecting gravity would be possible in a larger space station.
B No, the size of the space station does not affect gravity detection.
C Maybe, it depends on other factors besides the size of the space station.
D Insufficient information to determine.

The correct answer is:
Yes, detecting gravity would be possible in a larger space station.

Solution:
Correct Option is : (A)
Yes, detecting gravity would be possible in a larger space station.

Topic: Chemistry, Gravitation, NEET
If an atom is excited to principal quantum number n , how many different wavelengths may be observed in the spectrum of hydrogen sample during de-excitation?

Options:
A n nâ1 2
B n n+1 2
C n n+2 2
D n n−2 2

The correct answer is:
n n−1 2

Solution:
From the nth state, the atom may go to (n - 1)th state, ...., 2nd state of 1st state, So there are (n - 1) possible transitions starting from the nth state. The atoms reaching (n - 1)th state may make (n - 2) different transitions. Similarly for other lower sates. The total number of possible transitions is
(n - 1) + (n - 2) + (n - 3) + ... 2 + 1
= n n - 1 2

Alternative method:

Take any test value of n for e.g. case of n=3 and draw spectral lines that will be allowed for it. There will be 3 spectral lines allowed for it. Only first option satisfies this when you put value of n=3.

Topic: Physics, Atomic Physics, NEET
If an electron and a photon propagate in the form of waves having the same wavelength, it implies that they have the same magnitude of

Options:
A energy
B momentum
C velocity
D angular momentum

The correct answer is:
momentum

Solution:
λe=λph
hλe=hλph
pe=pph

Topic: Physics, Dual Nature of Matter, NEET
If an electron and a proton have the same de-Broglie wavelength, then the kinetic energy of the electron is

Options:
A Zero
B Less than that of a proton
C More than that of a proton
D Equal to that of a proton

The correct answer is:
More than that of a proton

Solution:
Given, λ=hmv=h2mKE
⇒ KE=12mλ2
As λ is same for both electron and photon
So, KE∝1m
Hence, kinetic energy will be maximum for particle with lesser mass, ie, electron.

Topic: Physics, Atomic Physics, NEET
If an electron drops from 4th orbit to 2nd orbit in an H-atom , then

Options:
A it gains 2.55 eV of potential energy
B it gains 2.55 eV of total energy
C it emits a 2.55 eV photon
D it emits a 255 eV photon

The correct answer is:
it emits a 2.55 eV photon

Solution:
En=-13.6 z2n2
âE=E4-E2
= -13.6 z2116-14
=-13.6Ã1-416 =13.6Ã316
=2.55 eV

Topic: Physics, Atomic Physics, NEET
If an electron enters into a space between the plates of a parallel plate capacitor at an angle α with the plates and leaves at an angle β to the plates. The ratio of its kinetic energy while entering the capacitor to that while leaving will be

Options:
A sin⁡βsin⁡α2
B cos⁡βcos⁡α2
C cos⁡αcos⁡β2
D sin⁡αsin⁡β2

The correct answer is:
cos⁡βcos⁡α2

Solution:
In the direction parallel to plate
v1cos⁡α=v2cos⁡β
v1v2=cos⁡βcos⁡α
ratio of kinetic energy
KE1KE2=v1v22
KE1KE2=cos⁡βcos⁡α2

Topic: Physics, Electrostatics, NEET
If an electron has energy such that it's De Broglie wavelength is 5500 Aâ, then the energy value of that electron is h=6.626Ã10-34 J s, me=9.1Ã1031 kg.

Options:
A 8Ã10-20 J
B 8×10-10 J
C 8 J
D 8×10-25 J

The correct answer is:
8×10-25 J

Solution:
Î»=hp and p22m=E
p=hÎ»=2mEâ E=h22mÎ»2
Substitutions the given values
E=8Ã10-25 J

Topic: Physics, Atomic Physics, NEET
If an electron in a hydrogen atom jumps from the third orbit to the second orbit, it emits a photon of wavelength λ. When it jumps from the fourth orbit to the third orbit, the corresponding wavelength of the photon will be

Options:
A 1625λ
B 916λ
C 207λ
D 2013λ

The correct answer is:
207λ

Solution:
1λ=R1n12-1n22

⇒λ=1R122-132

⇒λ′=1R132-142

⇒λ′λ=122-132132-142⇒λ′=207λ.

Topic: Physics, Atomic Physics, NEET, NEET 2016 (Phase 2)
If an element is obtained in minute quantities, which refining method would be more suitable?

Options:
A Electrolytic Refining
B Zone Refining
C Column Chromatography
D Distillation

The correct answer is:
Column Chromatography

Solution:
Correct Option is : (C)
Column Chromatography

Topic: Chemistry, General Principles and Processes of Isolation of Metals, NEET
If an endosperm cell of an angiosperm contains 24 chromosomes, the number of chromosomes in each cell of the root will be

Options:
A 8
B 4
C 16
D 24

The correct answer is:
16

Solution:
Haploid male gamete fuses with the two polar nuclei present in the central cell in embryo sac to form triploid (3n) primary endosperm nucleus. Cells of roots are diploid (2n) in nature. Primary endosperm cell (3n) = 24, n = 8. Root cell (2n) = 16. Hence, if the endosperm cell has 24 chromosomes, the number of chromosomes in each cell of the root will be 16.

Topic: Biology, Sexual Reproduction in Flowering Plants, NEET
If an endothermic reaction is non-spontaneous at freezing of water and becomes feasible at its boiling point, then

Options:
A ΔH is –ve, ΔS is +ve
B ΔH and ΔS both are +ve
C ΔH and ΔS both are -ve
D ΔH is +ve, ΔS is -ve

The correct answer is:
ΔH and ΔS both are +ve

Solution:
ΔG=ΔH-TΔS , since ΔG=+ve at T=273 K and ΔH=+ve and at high temperature 373 K, it becomes spontaneous (ΔG=-ve) even if ΔH=+ve . This is possible only, if ΔS=+ve because at high temperature TΔS>ΔH to give ΔG=-ve .

Topic: Chemistry, Thermodynamics (C), NEET
If an endothermic reaction is non-spontaneous at freezing point of water becomes feasible at its boiling point, then

Options:
A ΔH is –ve, ΔS is +ve
B ΔH and ΔS both are +ve
C ΔH and ΔS both are -ve
D ΔH is +ve, ΔS is -ve

The correct answer is:
ΔH and ΔS both are +ve

Solution:
ΔG=ΔH-TΔS, since ΔG=+ve at T = 273 K and ΔH=+ve and at high temperature 373 K, it becomes spontaneous (ΔG=-ve) even if ΔH=+ve . This is possible only, if ΔS=+ve because at high temperature. TΔS>ΔH to give ΔG=-ve.

Topic: Chemistry, Thermodynamics (C), NEET
If an ideal battery of e.m.f. 10 V is connected with external resistance 9 Î© and a wire of length 10 m and resistance 1 Î© in series as shown in figure, then calculate potential gradient for potentiometer wire

Options:
A 1 V/m
B 0.1V/m
C 0.01 V/m
D 10 V/m

The correct answer is:
0.1V/m

Solution:
Current through potentiometer wire,
i=109+1=1 A
∴ The potential drop across potentiometer wire,
V=iR=1×1=1 V
∴ Potential gradient,
ϕ=Vl=110=0.1 V/m

Topic: Physics, Current Electricity, NEET
If an individual having the genotype AaBbCc is selfed, how many squares will be required to determine the genotype of the population by Punnett's checkerboard method?

Options:
A 8×8
B 2×2
C 4×4
D 1×8

The correct answer is:
8×8

Solution:
Individual with the genotype AaBbCc will produce 8 varieties of gametes and thus when selfed will require 8X8 square table to obtain the different genotypes by Punnett's checker board method.

Topic: Biology, Principles of Inheritance and Variation, NEET
If an individual's repeated blood pressure readings are 140/90 or higher, what does it indicate?

Options:
A Normal blood pressure
B High blood pressure
C Low blood pressure
D Stable blood pressure

The correct answer is:
High blood pressure

Solution:
If an individual's repeated blood pressure readings are 140/90 or higher, it indicates hypertension, which is high blood pressure.

Topic: Biology, Body Fluids and Circulation, NEET
If Î» Î¿ and Î» be the threshold wavelength and wavelength of incident light, the velocity of photoelectron ejected from the metal surface is :

Options:
A 2 h c m λ ο - λ λ λ ο
B 2 h c m λ ο - λ
C 2 h m λ ο - λ
D 2 h m 1 λ ο - 1 λ

The correct answer is:
2 h c m λ ο - λ λ λ ο

Solution:
Einstein photo Electric Equation
hν - hν 0 = 1 2 mV max 2
h C λ - h C λ 0 = 1 2 mV max 2
2 hC m 1 λ - 1 λ 0 = V max 2
V max = 2 hC m λ 0 - λ λ λ 0

Topic: Chemistry, Structure of Atom, NEET
If at some instant of time, the displacement of a simple harmonic oscillator is 0.02 m and its acceleration is 2 m s-2, then the angular frequency of the oscillator is

Options:
A 100 rad s-1
B 10 rad s-1
C 1 rad s-1
D 0.1 rad s-1

The correct answer is:
10 rad s-1

Solution:
Acceleration Î±=Ï2xâ¡
or Ï=Î±xâ¡
=20.02
=10 rad s-1

Topic: Physics, Oscillations, NEET
If Avogadro number NA , is changed from 6.022×1023 mol-1 to 6.022×1020 mol-1 , this would change:

Options:
A The definition of mass in units of grams
B The mass of one mole of carbon
C The ratio of chemical species to each other in a balanced equation.
D The ratio of elements to each other in a compound.

The correct answer is:
The mass of one mole of carbon

Solution:
Mass of 1 mol (6.022×1023 atoms) of carbon = 12g
If Avogadro Number (NA) is changed then mass of 1 mol (6.022×1020 atom) of carbon
=12×6.022×10206.022×1023=12×10-3 g

Topic: Chemistry, Some Basic Concepts of Chemistry, NEET, NEET 2015 (Phase 2)
If BH=4Ã10â5 T and BV=2Ã10â5 T, then the Earth's total field (in T) at the place is

Options:
A 6× 10 −5 T
B 25Ã10-5 T
C 4Ã10-5Â T
D 3Ã10-5Â T

The correct answer is:
25Ã10-5 T

Solution:
Given: BH=4×10−5 T, BV=2×10−5 T. The total earth's magnetic field B at the given place is
B=BV2+BH2=(42+22)×10−5 T
= 20 × 10 −5 T=2 5 × 10 −5 T

Topic: Physics, Magnetic Properties of Matter, NEET
If birth and death rates were equal, a zero population growth rate would result. It is known as

Options:
A Replacement level
B Rate of natural increase
C Stable population
D Doubling time

The correct answer is:
Stable population

Solution:
In the long term, zero population growth can be achieved when the birth rate of a population equals the death rate, i.e. fertility is at replacement level and birth and death rates are stable, a condition also called demographic equilibrium.

Topic: Biology, Organisms and Populations, NEET
If birth rate = B, Death rate = D, Emigration = E,Immigration = I, then choose the correct match

Column I	Column II

a.	Population is stable	(i)	B + I > D + E

b.	Population is increasing	(ii)	B + I = D + E

c.	Population is increasing	(iii)	B + I < D + E

d.	Population equation is invalid	(iv)	B + E > D + I

Options:
A a(ii), b(i), c(iii), d(iv)
B a(ii), b(iv), c(iii), d(i)
C a(iii), b(iv), c(i), d(ii)
D a(i), b(ii), c(iv), d(iii)

The correct answer is:
a(ii), b(i), c(iii), d(iv)

Solution:
Population is stable-when the sum of birth rate and immigration is equal to the sum of death rate and emigration. Population is increasing when sum of birth rate and immigration is greater than the sum of death rate and emigration. Population is decreasing when the the sum of birth rate and emigration is greater than death rate and immigration.

Topic: Biology, Organisms and Populations, NEET
If BOD of sample water is very high, the sample is

Options:
A highly polluted.
B less polluted.
C not polluted.
D potable.

The correct answer is:
highly polluted.

Solution:
BOD or Biochemical Oxygen Demand (Also known as Biological Oxygen Demand), is the amount of oxygen needed by aerobic organisms to break down the organic substances in sewage water. Polluted water will have higher BOD. For instance, if BOD of water is 1-2, the water quality is very good. BOD of poor quality of water is 6-9 and BOD of highly polluted water would be more than 17. When BOD levels are high, dissolved oxygen (DO) levels decrease because the oxygen that is available in the water is being consumed by the bacteria due to which aquatic organisms will not get oxygen for survival.

Topic: Biology, Microbes in Human Welfare, NEET
If both parents are carriers for thalassemia, which is an autosomal recessive disorder, what are the chances of pregnancy resulting in an affected child?

Options:
A No chance
B $50 \%$
C $25 \%$
D $100 \%$

The correct answer is:
$25 \%$

Solution:
Thalassemia is the disorder due to reduced synthesis of either the $\alpha$ or $\beta$-chains, likewise designated as $\alpha$ or $\beta$ - thalassemias. When this autosomal mutant gene is present in double dose. The disease is severe called as thalassemia major.

Topic: Biology, Principles of Inheritance and Variation, NEET, NEET 2013 (All India)
If by radiation all nitrogenase enzyme are inactivated, then there will be no:

Options:
A fixation of nitrogen in legumes
B fixation of atmospheric nitrogen
C conversion from nitrate to nitrite in legumes
D conversion from ammonium to nitrate in soil.

The correct answer is:
conversion from nitrate to nitrite in legumes

Solution:
If by radiation all nitrogenase enzyme is inactivated, then there will be no fixation of nitrogen in legumes. The enzyme nitrogenase is necessary for biological nitrogen fixation only. If it gets inactivated by radiation, the process of biological nitrogen fixation will get affected. Nitrogen fixation occurs through other ways also. So either phenomenon of nitrogen fixation will not stop by the absence of nitrogenase enzyme.
Neither conversion of ammonium to nitrate(nitrification) nor conversion of nitrate to nitrite require nitrogenase. Hence they will not get affected.
So, the correct answer is 'Fixation of nitrogen in legumes'.

Topic: Biology, Mineral Nutrition, NEET, NEET 2004
If by radiation all the nitrogenase enzymes are inactivated, then which of the following will not occur?

(i) Fixation of atmospheric NO2
(ii) Conversion from nitrate to nitrite in legumes
(iii) Fixation of nitrogen in legumes
(iv) Conversion from ammonium to nitrate in soil

Options:
A (ii) and (iii)
B (i) and (iii)
C (ii) and (iv)
D (iii) only

The correct answer is:
(iii) only

Solution:
The process by which N2 is reduced to NH4+ is called nitrogen fixation. Nitrogenase enzyme catalyzes this reduction. It is only carried out by prokaryotic microorganisms. Principle N2-fixers include certain free-living cyanobacteria in symbiotic associations with fungi lichens or with ferns, mosses, and liverworts, and by bacteria or other microbes associated symbiotically with roots, especially those of legumes. About 15 percent of the nearly 20,000 species in the Fabaceae (leguminosae) family have been examined for N2 fixation, and approximately 90 percent of these have root nodules in which fixation occurs. So without active nitrogenase enzyme, there will be no N2 fixation in legumes.

Topic: Biology, Mineral Nutrition, NEET
If C be the capacitance and V be the electric potential, then the dimensional formula of CV2 is

Options:
A ML-3TA
B K0LT-2A0
C ML1T-2A-1
D ML2T-2A0

The correct answer is:
ML2T-2A0

Solution:
CV2=Energy
We know that dimensional formula of energy is ML2T-2.

Topic: Physics, Units and Dimensions, NEET
If $c$ is the velocity of light in free space, the correct statements about photon among the following are:
A. The energy of a photon is $E=h v$.
B. The velocity of a photon is $c$.
C. The momentum of a photon, $p=\frac{h \nu}{c}$.
D. In a photon-electron collision, both total energy and total momentum are conserved.
E. Photon possesses positive charge.
Choose the correct answer from the options given below:

Options:
A A, B, C and D only
B A, C and D only
C A, B, D and E only
D A and B only

The correct answer is:
A, B, C and D only

Solution:
(A) If $c$ is the velocity of light
so, $E=h \nu$ (Energy of photon)
(B) Velocity of photon is equal to velocity of light i.e. $c$.
(C) $\lambda=\frac{h}{p}$
$\begin{aligned}
& p=\frac{h}{\lambda} \\
& p=\frac{h \nu}{c}
\end{aligned}$
(D) In photon-electron collision both total energy and total momentum are conserved.

Topic: Physics, Dual Nature of Matter, NEET, NEET 2024
If CP and CV denote the specific heats of nitrogen per unit mass at constant pressure and constant volume respectively, then

Options:
A CP-CV=28R
B CP-CV=R28
C CP-CV=R14
D CP-CV=R

The correct answer is:
CP-CV=R28

Solution:
Molar heat capacity = Molar mass × specific heat capacity
So, the molar heat capacities at constant pressure and constant volume will be 28CP and 28CV respectively
∴ 28CP-28CV=R or CP-CV=R28.

Topic: Physics, Thermodynamics, NEET
If C the concentration of a weak electrolyte, α is the degree of ionization and Ka is the acid ionization constant, then the correct relationship between α,C and Ka is

Options:
A α2=KaC
B α2=CKa
C α=CKa
D α=KaC

The correct answer is:
α=KaC

Solution:
According to the Ostwaldâs dilution formula Î±2=K(1-Î±)C . But for weak electrolytes α is very small. So that (1-Î±) can be neglected. So that Î±=KaC .

Topic: Chemistry, Ionic Equilibrium, NEET
If cells are broken up and sedimented by centrifugation, the new structures formed in one of the fractions is

Options:
A lysosomes
B microsomes
C centrosomes
D peroxisomes

The correct answer is:
microsomes

Solution:
When cells are broken up under laboratory conditions, the endoplasmic reticulum breaks out to form microsomes. These are small bodies that are absent in healthy, living cells and these structures are important for many experimental purposes. Being similar to ER these structures are used to perform protein synthesis on a membrane and this helps to understand the actual process that occurs in the cell, as these microsomes mimic the activity of the endoplasmic reticulum in a test tube.

Topic: Biology, Cell - The Unit of Life, NEET
If concentration c is in mol/L or mol/dm3, and pressure p is in bar, what is the relationship between them?

Options:
A p = cRT
B p = c/V
C p = cRT/V
D p = RT/V

The correct answer is:
p = cRT

Solution:
When concentration c is in mol/L or mol/dm3 and pressure p is in bar, the relationship is given by p = cRT.

Topic: Chemistry, Chemical Equilibrium, NEET