datavorous/entrance-exam-dataset huggingface dataset:
The following equilibrium constant are given:
$\begin{aligned}
\mathrm{N}_2+3 \mathrm{H}_2 & \rightleftharpoons 2 \mathrm{NH}_3 ; \mathrm{K}_1 \\
\mathrm{~N}_2+\mathrm{O}_2 & \rightleftharpoons 2 \mathrm{NO} ; \mathrm{K}_2 \\
\mathrm{H}_2+1 / 2 \mathrm{O}_2 & \rightleftharpoons \mathrm{H}_2 \mathrm{O} ; \mathrm{K}_3
\end{aligned}$
The equilibrium constant for the oxidation of $\mathrm{NH}_3$ by oxygen to give $\mathrm{NO}$ is:

Options:
A $\frac{\mathrm{K}_2 \mathrm{~K}_3^2}{\mathrm{~K}_1}$
B $\frac{\mathrm{K}_2^2 \mathrm{~K}_3}{\mathrm{~K}_1}$
C $\frac{\mathrm{K}_1 \mathrm{~K}_2}{\mathrm{~K}_3}$
D $\frac{K_2 K_3^3}{K_1}$

The correct answer is:
$\frac{K_2 K_3^3}{K_1}$

Solution:
Given,
$\begin{aligned}
& \mathrm{N}_2+3 \mathrm{H}_2 \rightleftharpoons 2 \mathrm{NH}_3 ; \mathrm{K}_1 \\
& \mathrm{~N}_2+\mathrm{O}_2 \rightleftharpoons 2 \mathrm{NO} ; \mathrm{K}_2 \\
& \mathrm{H}_2+\frac{1}{2} \mathrm{O}_2 \rightleftharpoons \mathrm{H}_2 \mathrm{O} ; \mathrm{K}_3
\end{aligned}$
We have to calculate
$\begin{aligned}
& 4 \mathrm{NH}_3+5 \mathrm{O}_2 \longrightarrow 4 \mathrm{NO}+6 \mathrm{H}_2 \mathrm{O} ; \mathrm{K}=\text { ? } \\
& \text { or } 2 \mathrm{NH}_3+\frac{5}{2} \mathrm{O}_2 \longrightarrow 2 \mathrm{NO}+3 \mathrm{H}_2 \mathrm{O}
\end{aligned}$
For this equation $\mathrm{K}=\frac{[\mathrm{NO}]^2\left[\mathrm{H}_2 \mathrm{O}\right]^3}{\left[\mathrm{NH}_3\right]^2\left[\mathrm{O}_2\right]^{5 / 2}}$ but
$\begin{aligned}
\mathrm{K}_1 & =\frac{\left[\mathrm{NH}_3\right]^2}{\left[\mathrm{~N}_2\right]\left[\mathrm{H}_2\right]^3} \\
\mathrm{~K}_2 & =\frac{[\mathrm{NO}]^2}{\left[\mathrm{~N}_2\right]\left[\mathrm{O}_2\right]} \\
\mathrm{K}_3 & =\frac{\left[\mathrm{H}_2 \mathrm{O}\right]}{\left[\mathrm{H}_2\right]\left[\mathrm{O}_2\right]^{1 / 2}} \\
\mathrm{~K}_3 & =\frac{\left[\mathrm{H}_2 \mathrm{O}^3\right.}{\left[\mathrm{H}_2\right]^3\left[\mathrm{O}_2\right]^{3 / 2}}
\end{aligned}$
Now
$\begin{aligned}
& \frac{\mathrm{K}_2 \cdot \mathrm{K}_3{ }^3}{\mathrm{~K}_1} =\frac{[\mathrm{NO}]^2}{\left[\mathrm{~N}_2\right]\left[\mathrm{O}_2\right]} \times \frac{\left[\mathrm{H}_2 \mathrm{O}\right]^3}{\left[\mathrm{H}_2\right]^3\left[\mathrm{O}_2\right]^{3 / 2}} \times \frac{\left[\mathrm{N}_2\right]\left[\mathrm{H}_2\right]^3}{\left[\mathrm{NH}_3\right]^2} \\
& =\frac{[\mathrm{NO}]^2\left[\mathrm{H}_2 \mathrm{O}\right]^3}{\left[\mathrm{NH}_3\right]^2\left[\mathrm{O}_2\right]^{5 / 2}}=\mathrm{K} \\
& \therefore \mathrm{K}=\frac{\mathrm{K}_2 \cdot \mathrm{K}_3{ }^3}{\mathrm{~K}_1}
\end{aligned}$

Topic: Chemistry, Chemical Equilibrium, NEET, NEET 2007
The following equilibrium constants are given
N2+3H2⇌2NH3;K1
N2+O2⇌2NO;K2
H2+12O2⇌H2O;K3
The equilibrium constant for the oxidation of 2 mol of NH3 to give NO is

Options:
A K1.K2K3
B K2.K33K1
C K2.K32K1
D K22.K3K1

The correct answer is:
K2.K33K1

Solution:
N2+3H2⇌2NH3;K1
K1=[NH3]2[N2][H2]3
N2+O2⇌2NO;K2
H2+12O2⇌H2O;K3
K2=[NO]2[N2][O2];K3=[H2O][H2][O2]1/2
Now, oxidation of NH3 takes places as below
4NH3+5O2⇌4NO+6H2O
or 2NH3+52O2⇌2NO+3H2O
K=[NO]2[H2O]3[NH3]2[O2]5/2
K=[NO]2[N2][O2].[N2][O2][NH3]2.[N2][H2]3[N2][H2]3.[H2O]3[H2]3[O2]3/2.[H2]3[O2]3/2[O2]5/2
=[NO]2[N2][O2][N2][H2]3[NH3]2.[H2O]3[H2]3[O2]3/2
=K2.1K1.K33=K33K2K1

Topic: Chemistry, Chemical Equilibrium, NEET
The following equilibrium constants are given:

N 2 + 3 H 2 ⇌ 2 NH 3 ; K⁡ 1

N 2 + O 2 ⇌ 2 NO ; K⁡ 2

H 2 + 1 / 2 O 2 ⇌ H 2 O ; K⁡ 3

The equilibrium constant for the oxidation of 2 mole NH 3 by oxygen to give NO is

Options:
A K 2 K 3 2 K 1
B K 2 2 K 3 K 1
C K 1 K 2 K 3
D K 2 K 3 3 K 1

The correct answer is:
K 2 K 3 3 K 1

Solution:
N 2 +3 H 2 ⇌ 2NH 3
K 1 = NH 3 2 N 2    H 2 3                 … i
N 2 +O 2 ⇌2NO  ;   K 2 = NO 2 N 2    O 2                 … ii
H 2 +1/2   O 2 ⇌ H 2 O  ;   K 3 = H 2 O H 2    O 2 1/2                 … iii
For the reaction, 2 NH 3 + 5 2 O 2 ⇌ 2 NO + 3 H 2 O
K⁡ = NO 2 H 2 O 3 NH 3 2 O 2 5 / 2
= NO 2 N 2 O 2 × H 2 O 3 H 2 3 O 2 3 / 2 × N 2 H 2 3 NH 3 2
= K 2 × K 3 3 K 1

Topic: Chemistry, Chemical Equilibrium, NEET
The following experiment was performed to test the effect of auxin on the plant growth. Five plant seedlings (all growing actively) were prepared as below; they were unilaterally illuminated, and growth was measured after 10 days.

Treatments :

Plant A: Tip not removed, nothing applied
Plant B: Tip removed, nothing applied
Plant C: Tip removed, gelatin block with cytokinin was placed on the cut edge
Plant D: Tip removed gelatin block with auxin placed on the cut edge.

Which of the following plants would show curvature after the above treatment?

Options:
A A and B
B A and D
C B and C
D A, B, C and D

The correct answer is:
A and D

Solution:
Auxin is the plant hormone that is synthesized in young stem apex. During day time, auxin redistribution occurs such that the plant side directly exposed to sunlight contains lower auxin concentration than the other side which is not exposed to light. This unequal distribution causes curvature. In plant A, redistribution of auxin leads to curvature, whereas removal of the tip in plant B leads to no auxin synthesis and no curvature. However, in plant D, where gelatine box with auxin is placed due to auxin redistribution, the curvature is observed.

Topic: Biology, Plant - Growth and Development, NEET
The following features belong to which syndrome?

(i) Furrowed tongue
(ii) Palm is broad with characteristic palm crease
(iii) Physical, psychomotor and mental retardation
(iv) Short statured with the small round head

Options:
A Down's syndrome
B AIDS
C Turner's syndrome
D Klinefelter's syndrome

The correct answer is:
Down's syndrome

Solution:
Down's syndrome is a chromosomal disorder. The cause of this genetic disorder is the presence of an additional copy of the chromosome number 21 (trisomy of 21). This disorder was first described by Langdon Down.

Topic: Biology, Principles of Inheritance and Variation, NEET
The following figure corresponds to:

Options:
A Meristem
B Parenchyma
C Sclerenchyma
D Collenchyma

The correct answer is:
Sclerenchyma

Solution:
The regions in plants which undergo active cell division are known as meristems. The parenchyma, sclerenchyma and collenchymas are simple tissues, where the parenchyma is majorly found within organs. The collenchyma is found in patches or homogenous layers in layers below the epidermis in dicot plants and the sclerenchyma tissue consists of narrow cells with thick walls usually spherical, oval or cylindrical with narrow cavities.

Topic: Biology, Anatomy of Flowering Plants, NEET
The following figure depicts which body system?

Options:
A Endocrine System
B Hormone System
C Neuroendocrine System
D None of the above

The correct answer is:
Endocrine System

Solution:
The figure shows endocrine glands.

Topic: Biology, Chemical Coordination and Integration, NEET
The following figure shows a conducting disc rotating about its axis in a perpendicular magnetic field B. The resistor of resistance R is connected between the centre and the rim. The current in the resistor is (The radius of the disc is 5.0 cm, angular speed Ï=10 rad s-1, B=0.40 T and R=10 Î©)

Options:
A 0.5 A
B 0.2 A
C 0.3 A
D 0.9 A

The correct answer is:
0.5 A

Solution:
Emf induced between centre and rim
ε=Βωa22, where a= radius
∴i=εR=Bωa22R=0.4×10×5×10-222×10=0.5 A

Topic: Physics, Electromagnetic Induction, NEET
The following figure shows a logic gate circuit with two inputs A and B and output C . The voltage waveforms of A , B and C are as shown in second figure below

The logic circuit gate is

Options:
A OR gate
B AND gate
C NAND gate
D NOR gate

The correct answer is:
AND gate

Solution:
Gate is AND gate.
Because

Hence this is AND gate.

Topic: Physics, Semiconductors, NEET
The following figure shows a logic gate circuit with two inputs $\mathrm{A}$ and $\mathrm{B}$ and the output $\mathrm{C}$. The voltage waveforms of $\mathrm{A}$, $\mathrm{B}$ and $\mathrm{C}$ are as shown below:
The logic circuit gate is:

Options:
A OR gate
B AND gate
C NAND gate
D NOR gate

The correct answer is:
AND gate

Solution:
Truth table
The circuit is AND- gate

Topic: Physics, Semiconductors, NEET, NEET 2006
The following figure shows the multiple reflections of a light ray along a glass corridor where the walls are either parallel or perpendicular to one another. If the angle of incidence at point P is 30°, then the angles of reflection of the light ray at points Q, R, S and T respectively are

Options:
A 30°, 30°, 30°, 30°
B 30°, 60°, 30°, 60°
C 30°, 60°, 60°, 30°
D 60°, 60°, 60°, 60°

The correct answer is:
30°, 60°, 60°, 30°

Solution:

Topic: Physics, Ray Optics, NEET
The following figure shows the variation of intensity of magnetisation I versus the applied magnetic field intensity H, for two magnetic materials A and B

Which of the material have a larger susceptibility for a given field at constant temperature?

Options:
A Material B
B Material B and Material A have the same susceptibility
C Material A
D None of these

The correct answer is:
Material B

Solution:
Material A is paramagnetic and Material B is ferromagnetic.
The susceptibility of material B is larger than A at given magnetic field because ferromagnetic material gets strongly magnetised and hence produces a larger intensity of magnetization in comparison to paramagnetic substance, therefore it is strongly magnetised.

Topic: Physics, Magnetic Properties of Matter, NEET
The following figure shows:

Options:
A Heterophylly in larkspur
B Heterophylly in buttercup
C Heterophylly in cotton and coriander
D Heterophylly in cotton, coriander and larkspur.

The correct answer is:
Heterophylly in larkspur

Solution:
Every plant follows different pathways as a response to the environment, to form different structures, the ability to do so is called plasticity. Heterophylly in some plants is an example of the same. These plants have leaves that have a different shape when they are juvenile and the shape changes when they mature. The given figure depicts the heterophylly seen in larkspur when its juvenile and when they turn into an adult plant.

Topic: Biology, Plant - Growth and Development, NEET
The following four wires are made of the same material. Which of these will have the largest extension when the same tension is applied?

Options:
A Length $=50 \mathrm{~cm}$, diameter $=0.5 \mathrm{~mm}$
B Length $=100 \mathrm{~cm}$, diameter $=1 \mathrm{~mm}$
C Length $=200 \mathrm{~cm}$, diameter $=2 \mathrm{~mm}$
D Length $=300 \mathrm{~cm}$, diameter $=3 \mathrm{~mm}$

The correct answer is:
Length $=50 \mathrm{~cm}$, diameter $=0.5 \mathrm{~mm}$

Solution:
$\Delta L=\frac{F L}{A Y}$
or $\Delta L \propto \frac{L}{d^2} \quad\left[\because A=\frac{\pi d^2}{4}\right]$
Therefore, $\Delta$ will be maximum for that wire which $\frac{L}{A}$ is maximum, so option (1) is correct.

Topic: Physics, Mechanical Properties of Solids, NEET, NEET 2013 (All India)
The following fusion reaction takes place 212AâB23+n+3.27 MeV. If 2 kg of A12 is subjected to the above reaction, the energy released is used to light a 100 W lamp, how long will the lamp glow?

Options:
A 7Ã103Â years
B 3Ã105 years
C 5Ã104 years
D 2Ã106Â years

The correct answer is:
5Ã104 years

Solution:
Number of atoms in 2 g of A12=6.023×1023
∴ No of atoms in 2 kg of A12=6.023×10232×2000
∵ The energy released in the fusion of two A12 nuclei =3.27  MeV
∴ The energy released in the fusion of 2 kg of A12
∴E=3272×6.023×1026×16×10-13 J
=15.76×1013  J
Power of bulb, P=100 W,=100 J s-1
∴ Time for which the bulb will glow t=EP
=15.75×1013100
=15.75×1011 s
=15.75×101160×60×24×365
=5×104 years

Topic: Physics, Nuclear Physics, NEET
The following fusion reaction takes place 212AâB23+n+3.27 MeV If 2 kg of A12 is subjected to the above reaction, the energy released is used to light a 100 W lamp, how long will the lamp glow ?

Options:
A 7Ã103Â years
B 3Ã105 years
C 5Ã104 years
D 2Ã106Â years

The correct answer is:
5Ã104 years

Solution:
Number of atoms in 2 g of A12=6.023×1023
∴ No of atoms in 2 kg of A12=6.023×10232×2000
∵ Energy released in the fusion of two A12 nuclei =3.27  MeV
∴ Energy released in the fusion of 2 kg of A12
∴E=3272×6.023×1026×16×10-13J
=15.76×1013  J
Power of bulb, P=100 W,=100 J s-1
∴ Time for which the bulb will glow t=EP
=15.75×1013100
=15.75×1011s
=15.75×101160×60×24×365
=5×104 years

Topic: Physics, Nuclear Physics, NEET
The following graph depicts changes in two populations (A and B) of herbivores in a grassy field. A possible reason for these changes is that.

Options:
A Both plant populations in this habitat decreased
B Population B competed more successfully for food than population A
C Population A produced more offspring than population B
D Population A consumed the members of population B

The correct answer is:
Population B competed more successfully for food than population A

Solution:
Population B competed more successfully for food than population A and hence due to this success was able to increase the number of its offsprings.

Topic: Biology, Organisms and Populations, NEET, NEET 2015 (Phase 1)
The following graph represents the $T$ - $V$ curves of an ideal gas (where $T$ is the temperature and $V$ the volume) at three pressures $P_1, P_2$ and $P_3$ compared with those of Charles's law represented as dotted lines.
Then the correct relation is:

Options:
A $P_1\gtP_3\gtP_2$
B $P_2\gtP_1\gtP_3$
C $\quad P_1\gtP_2\gtP_3$
D $P_3\gtP_2\gtP_1$

The correct answer is:
$\quad P_1\gtP_2\gtP_3$

Solution:
At same temperature, curve with higher volume corresponds to lower pressure.
$\begin{aligned}
& V_3\gtV_2\gtV_1 \\
& \Rightarrow P_1\gtP_2\gtP_3
\end{aligned}$
(We draw a straight line parallel to volume axis to get this)

Topic: Physics, Kinetic Theory of Gases, NEET, NEET 2024
The following graph shows the range of variation among population members for a trait determined by multiple genes.

If this population is subject to stabilizing selection for several generations, which of the distribution is most likely to result?

Options:
A
B
C
D and

The correct answer is:

Solution:
Stabilizing selection is a type of natural selection that favors the average individuals in a population. This process selects against the extreme phenotypes and instead favors the majority of the population that is well adapted to the environment. Stabilizing selection is often shown on a graph as a modified bell curve that is narrower and taller than the norm.

Topic: Biology, Organisms and Populations, NEET
The following is a scheme showing the fate of carbohydrates during digestion in the human alimentary canal. Identify the enzymes acting at stages indicated as A, B, C, and D. Choose the correct option from those given.

Options:
A A-Amylase, B-Maltase, C- Lactase, D-Invertase
B A-Amylase, B- Maltase, C-Invertase, D-Latcase
C A-Amylase, B-Invertase, C-Maltase, D-Lactase
D A-Amylase, B-Lactase , C- Maltase , D- Invertase

The correct answer is:
A-Amylase, B-Lactase , C- Maltase , D- Invertase

Solution:
Starch→AmylaseMaltose+Isomaltose+limit dextrins
Lactose→Lactase Glucose+Galactose
Maltose → Maltase Glucose + Glucose Sucrose
Cane sugar→Sucrase/invertaseGlucose+Fructose

Topic: Biology, Digestion and Absorption, NEET
The following is a strip of MALA-D oral contraceptive pills. Which of these statements about it is true?

Options:
A The white tablets don't contain estrogen and progesterone
B The dark tablets don't contain estrogen and progesterone
C The white tablets should be started from the first day of menstruation
D The dark tablets should be started one week after the menstruation stops

The correct answer is:
The dark tablets don't contain estrogen and progesterone

Solution:
Oral administration of progestogen-estrogen combinations is another contraceptive method used by the females. They are used in the form of tablets and hence are popularly called the pills eg. MALA-D. These pills have to be taken daily for a period of 21 days starting preferably within the first five days of the menstrual cycle. After a gap of 7 days (during which menstruation occurs) it has to be repeated in the same pattern until the female desires to prevent conception. If you count the white tablets they are 21 while the dark tablets are 7. During the gap that needs to be taken, the lady has to consume the dark tablets which are rich in iron but they don't contain female hormones

Topic: Biology, Reproductive Health, NEET
The following is an oxygen dissociation curve. The characters depicted on the axes are

Options:
A X axis: partial pressure gradient of oxygen in mm Hg and
Y axis: saturation of haemoglobin with oxygen
B X axis: saturation of haemoglobin with oxygen and
Y axis: partial pressure gradient of oxygen in mm Hg
C X axis: percentage saturation of haemoglobin with oxygen and
Y axis: partial pressure of oxygen in mm Hg
D X axis: partial pressure of oxygen in mm Hg
Y axis: percentage saturation of haemoglobin with oxygen

The correct answer is:
X axis: partial pressure of oxygen in mm Hg
Y axis: percentage saturation of haemoglobin with oxygen

Solution:
Oxygen dissociation curve is a sigmoid shaped curve. This graph has a partial pressure of oxygen on X-axis and percentage saturation of hemoglobin on the Y-axis. This explains oxygen transport through blood. Right, and left deviations are seen in case of oxygen dissociation near tissues and its association near alveoli with hemoglobin respectively.

Topic: Biology, Breathing and Exchange of Gases, NEET
The following is not an appropriate reaction for the preparation of t-butyl ethyl ether.
What would be the major product of this reaction?

Options:
A 1-methylprop-2-ene
B 1-methylprop-1-ene
C 2-methylprop-2-ene
D 2-methylprop-1-ene

The correct answer is:
2-methylprop-1-ene

Solution:
Correct Option is : (D)
2-methylprop-1-ene

Topic: Chemistry, Alcohols Phenols and Ethers, NEET
The following is the labelled representation of a typical plant cell. Among the labelled parts, which of these will also be observed in a typical animal cell?

Options:
A 1, 3 and 4 only
B 1,4 and 5 only
C 2, 3 and 4 only
D 1, 3, 4 and 5 only

The correct answer is:
2, 3 and 4 only

Solution:
1 – cell wall - found only in plant cell.
2 - mitochondrion - found in both plant cell and animal cell
3 – nucleus - present in both plant cell and animal cell.
4 – vacuole - present in both plant(large) and animal cell(small)
5 – chloroplast - found in plant cell only.
We can say that labels 2, 3 and 5 will be observed in animal cell as well.

Topic: Biology, Cell - The Unit of Life, NEET
The following list contains some connective tissues. Which of these is/are present beneath our integument?

a. Areolar tissue
b. Adipose tissue
c. Dense irregular connective tissue

Options:
A Only b
B Both a & c
C Both a and b
D a, b, and c

The correct answer is:
a, b, and c

Solution:
Skin/ Integument is the largest organ in the body acting as the protective covering. Skin is made up of multiple layers of connective tissue including areolar tissue, adipose tissue (fat layer ), and dense irregular connective tissue. The outermost layer of skin is made of tightly packed epithelial tissue. Skin is vascularized with vessels and ducts of glands.

Topic: Biology, Structural Organisation in Animals, NEET
The following options have a property of a fungus paired with its example. Which of these is an incorrect pair?

Options:
A Sporangiospores - Mucor
B Conidia - Penicillium
C Asexual reproduction is absent - Agaricus
D Only by asexual reproduction - Alternaria

The correct answer is:
Asexual reproduction is absent - Agaricus

Solution:
In phycomycetes, these asexual spores are endogenously produced in sporangium. Example is Mucor
In ascomycetes, conidia are the asexual spores conidia produced exogenously on the special mycelium called conidiophores. Example is Penicillium. In deuteromycetes or imperfect fungi only the asexual or vegetative phases of these fungi are known. Example is Alternaria. In basidiomycetes, asexual spores are not found but asexual reproduction is seen in the form of fragmentation. Example is Agaricus. In Agaricus (mushroom), asexual spores called chlamydospore on dikaryotic mycelium, which on germination during favourable condition produce dikaryotic mycelium.

Topic: Biology, Biological Classification, NEET
The following particles are moving with the same velocity. Then the maximum de-Broglie wavelength will be for

Options:
A α- particle
B β- particle
C Proton
D Neutron

The correct answer is:
β- particle

Solution:
De-Broglie wavelength is given by
λ=hP=hmv
As velocity is same, then the particle having higher mass will have minimum wavelength and vice versa. Since β- particle has least mass.

Topic: Physics, Atomic Physics, NEET
The following pedigree depicts the inheritance of an X-linked recessive trait.

The phenotype of the progeny 1A, 1B and 1C is unknown. What could be the possibility for the progeny?

Options:
A Only offspring 1A would be affected.
B Offspring 1B and 1C would be affected
C Offspring 1A, 1B and 1C would be normal.
D Offspring 1A, IB and 1C would all be affected

The correct answer is:
Only offspring 1A would be affected.

Solution:
Pedigree analysis provides information regarding inheritance of particular traits or diseases and using it we can predict the possibility of appearance of any traits in the new generation.
Sex-linked recessive disorders are inherent disorders due to mutation in the sex chromosomes, generally the X chromosome. As per the diagram, the female is homozygous for the recessive trait and shows it phenotypically. Since the son (1A) receives X chromosome from mother and Y chromosome from father, the X-linked trait will get expressed in the son. But it will not be expressed in the daughter as she is receiving only one X-from mother and other X chromosome from father resulting in heterozygous condition.
X-linked recessive traits show phenotypically in females only in homozygous condition.

Topic: Biology, Principles of Inheritance and Variation, NEET
The following ratio is generally constant for a given species:

Options:
A $\mathrm{A}+\mathrm{G} / \mathrm{C}+\mathrm{T}$
B $\mathrm{T}+\mathrm{C} / \mathrm{G}+\mathrm{A}$
C $\mathrm{G}+\mathrm{C} / \mathrm{A}+\mathrm{T}$
D $\mathrm{A}+\mathrm{C} / \mathrm{T}+\mathrm{G}$.

The correct answer is:
$\mathrm{G}+\mathrm{C} / \mathrm{A}+\mathrm{T}$

Solution:
The $\mathrm{C}+\mathrm{G} / \mathrm{A}+\mathrm{T}$ ratio varies from organism to organism among the prokaryotes), but within (particularly the limits of experimental error, $\mathrm{A}=\mathrm{T}$ and $\mathrm{C}=\mathrm{G}$.
Related Theory
Erwin Chargaff discovered that the number of nitrogenous bases in the DNA was present in equal quantities. The amount of $A$ is equal to $T$, whereas the amount of $C$ is equal to $G$, i.e., $A=T ; C=G$

Topic: Biology, Evolution, NEET, NEET 2004
The following reaction method
is not suitable for the preparation of the corresponding haloarene products, due to high reactivity of halogen, when X is :

Options:
A F
B I
C Cl
D Br

The correct answer is:
F

Solution:
- Aryl chlorides and bromides can easily be prepared by electrophilic substitution of arenes (toluene) with $\mathrm{Cl}_2$ and $\mathrm{Br}_2$ respectively in the presence of Lewis acid catalyst ( Fe in dark).
- Reaction with $\mathrm{I}_2$ is reversible and requires the presence of oxidising agent.
- Corresponding fluoroarene is not prepared by this method due to high reactivity of fluorine. Hence, ' X ' is $F$.

Topic: Chemistry, Haloalkanes and Haloarenes, NEET, NEET 2024 (Re-NEET)
The following reaction occurs in the Blast Furnace where iron ore is reduced to iron metal:

Fe2O3s+3COg â2Fe l+3CO2g

Using the Le Chatelier's principle, predict which one of the following will not disturb the equilibrium?

Options:
A Addition of CO2
B Removal of CO2
C Addition of Fe2O3
D Removal of CO

The correct answer is:
Addition of Fe2O3

Solution:
It is heterogeneous equilibrium Fe is liquid Fe2O3 is solid whose active mass is taken to be unity so, it will not be considered in kp, kc,& kx expresssion.
So, it will not disturb the equilibrium

Topic: Chemistry, Chemical Equilibrium, NEET