datavorous/entrance-exam-dataset huggingface dataset:
Out of 'X' pairs of ribs in humans, only 'Y' pairs are true ribs. Select the option that correctly represents values of X and Y and provides their explanation:

Options:
A

X=12, Y=7	True ribs are attached dorsally to vertebral column and ventrally to the sternum

B

X=12,Â Y=5	True ribs are attached dorsally to vertebral column and sternum on the two ends

C

X=24,Â Y=7	True ribs are dorsally attached to vertebral column but are free on ventral side

D

X=24,Â Y=12	True ribs are dorsally attached to vertebral column but are free on ventral side

The correct answer is:

X=12, Y=7	True ribs are attached dorsally to vertebral column and ventrally to the sternum

Solution:
In human, 12 pairs of ribs are present in which 7 pairs of ribs ( 1st to 7th pairs) are attached dorsally to the vertebral column and ventrally to the sternum. That is the reason, they are called as true ribs. There are false ribs and floating ribs in human thoracic cage bones.

Topic: Biology, Locomotion and Movement, NEET, NEET 2017
Outbreeding is an important strategy of animal husbandry because it:

Options:
A Is useful in producing purelines of animals
B Is useful in overcoming inbreeding depression
C Expose harmful recessive genes that are eliminated by selection.
D Helps in accumulation of superior genes.

The correct answer is:
Is useful in overcoming inbreeding depression

Solution:
Outbreeding: It refers to the mating of unrelated animals, it may be between individuals of the same breed but not having common ancestors for 4-6 generations. It helps in overcoming inbreeding depression. It is of two types:

Cross–breeding: Mating of animals belonging to different breeds is called cross-breeding. It involves interbreeding of superior males of a breed with superior females of another breed to produce hybrid animals.

Interspecific hybridization: The crossing of male and female animals of two different but related species is called interspecific hybridization. The progeny may have desirable features of both the parents.

Topic: Biology, Strategies for Enhancement in Food Production, NEET, NEET 2015 (Phase 2)
Out-breeding is the breeding of unrelated animals. It includes

Options:
A Inbreeding only
B Inbreeding + Cross-breeding
C Out-crossing + Cross-breeding
D Out-crossing + Cross-breeding+ Interspecific hybridization

The correct answer is:
Out-crossing + Cross-breeding+ Interspecific hybridization

Solution:
Out-breeding is the breeding of unrelated animals, which may be between individuals of the same breed but having no common ancestors for 4-6 generations (out-crossing) or between different breeds (cross-breeding) or different species (interspecific hybridization).

Topic: Biology, Strategies for Enhancement in Food Production, NEET
Outer electron quantum number for Antimony is ?

Options:
A 4
B 5
C 6
D 7

The correct answer is:
5

Solution:
Correct Option is : 2
5

Topic: Chemistry, Structure of Atom, NEET
Outer electron quantum number for Fr is ?

Options:
A 4
B 5
C 6
D 7

The correct answer is:
7

Solution:
Correct Option is : 4
7

Topic: Chemistry, Structure of Atom, NEET
Ovary is half-inferior in the flowers of

Options:
A guava
B plum
C brinjal
D cucumber

The correct answer is:
plum

Solution:
If gynoecium is situated in the centre and other parts of the flower are located in the rim of the thalamus almost at the same level, it is called perigynous flower. The ovary here is said to be half inferior, eg, plum, rose, peach.

Topic: Biology, Sexual Reproduction in Flowering Plants, NEET, NEET 2010 (Screening)
Ovary is half-inferior in the flowers of

Options:
A Guava
B Plum
C Brinjal
D Cucumber.

The correct answer is:
Plum

Solution:
If gynoecium is situated in the centre and other parts of the flower are located on the rim of the thalamus almost at the same level, it is called perigynous. The ovary here is said to be half inferior, e.g., plum, rose, peach.

Topic: Biology, Morphology of Flowering Plants, NEET
Overgrowth of algae results in:

Options:
A Increased levels of dissolved oxygen
B Decreased biological oxygen demand
C Mortality of fishes
D All of the above

The correct answer is:
Mortality of fishes

Solution:
Overgrowth of algae or algal bloom imparts a distinct colour to the water bodies, causes deterioration of the water quality and fish mortality. Few of the bloom-forming algae can be even extremely toxic to human beings and animals.

Topic: Biology, Environmental Issues, NEET
Overlapping region between two ecosystems is called

Options:
A Biome
B Ecotone
C Niche
D Photic zone

The correct answer is:
Ecotone

Solution:
The zone of transition between two different communities presenting a situation of overlapping is known as an ecotone.

Topic: Biology, Ecosystem, NEET
Ovulation in the human female normally takes place during the menstrual cycle:

Options:
A at the mid secretory phase
B just before the end of the secretory phase
C at the beginning of the proliferative phase
D at the end of the proliferative phase.

The correct answer is:
at the end of the proliferative phase.

Solution:
Follicular or Proliferative Phase follows the Menstrual phase and lasts for about 10-12 days (from 5 th to 14 th days of the menstrual cycle). Ovulatory phase involves the ovulation from the Graafian follicle of ovary. It occurs midway between two menstrual cycles (on 15 th day of onset of menstruation). Luteal/Secretory/Post ovulatory phase lasts for about 12-14 days (from $16^{\text {th }}-28^{\text {th }}$ days of menstrual cycle). Corpus luteum is formed from empty Graafian follicle which increases in size. The follicular cells are converted to Lutein cells by deposition of yellowish lipid inclusions, giving it a yellow colour. This phase is the Luteal phase.
Related Theory
Both LH and FSH attain a peak level in the middle of cycle (about 14 $14^{\text {th }}$ day). Rapid secretion of LH leading to its maximum level during the mid-cycle called LH surge induce rupture of Graafian follicle and thereby release of ovum (ovulation).

Topic: Biology, Human Reproduction, NEET, NEET 2004
Ovulation is induced by a hormone called ____.

Options:
A Thyroid hormones
B Luteinizing hormone
C Growth Hormone
D Aldosterone

The correct answer is:
Luteinizing hormone

Solution:
Ovulation is induced by a hormone called Luteinizing hormone.

Topic: Biology, Human Reproduction, NEET
Ovules in Pinus are generally

Options:
A Anatropous with four integuments
B Anatropous with one integument
C Amphitropous with three integuments
D Orthotropous with two integuments

The correct answer is:
Anatropous with one integument

Solution:
The ovule of Pinus is anatropous with one integument differentiated into 3 layers outer fleshy, middle stony, and inner fleshy.

Topic: Biology, Plant Kingdom, NEET
Oxalic acid on heating with conc. H2SO4 gives

Options:
A CO2+H2O
B CO+CO2+H2O
C CO only
D CO2 only

The correct answer is:
CO+CO2+H2O

Solution:
Here, H2SO4 is a dehydrating agent.

Topic: Chemistry, Carboxylic Acid Derivatives, NEET
Oxidation number of iodine in IO3-,IO4-,KI and I2 respectively are

Options:
A -2,-5,-1,0
B +5,+7,-1,0
C +2,+5,+1,0
D -1,+1,0,+1

The correct answer is:
+5,+7,-1,0

Solution:
IO3-→x+3(-2)=-1
x=+5
IO4-→x+4(-2)=-1
x=+7
KI→+1+x=0
x=-1
I2→0
x=0

Topic: Chemistry, Redox Reactions, NEET
Oxidation number of iodine in XO3-,XO4-,NaX and X2 respectively is

Options:
A +2,+5,+1,0
B -1,+1,0,+1
C -2,-5,-1,0
D +5,+7,-1,0

The correct answer is:
+5,+7,-1,0

Solution:
XO3-→x+3(-2)=-1
x=+5
XO4-→x+4(-2)=-1
x=+7
NaX→+1+x=0
x=-1
X2→0
x=0

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), NEET
Oxidation number of rubidium in Rb2O,Rb2O2 and RbO2 , can be given respectively, as

Options:
A +1,+4 and +2
B +2,+1 and +12
C +1,+1 and +1
D +1,+2 and +4

The correct answer is:
+1,+1 and +1

Solution:
Let oxidation number of Rb as x
Rb2O2x-2=0→x=+1
Rb2O22x-2=0(peroxide)→x=+1
In peroxide oxidation number of oxygen is taken as -1
RbO22x-2=0(superoxide)→x=+1
In superoxide oxidation number of oxygen is taken as -12

Topic: Chemistry, s Block Elements, NEET
Oxidation numbers of Mn in its compounds MnCl2 , Mn(OH)3.MnO2 and KMnO4 respectively are

Options:
A +2,+4,+7,+3
B +2,+3,+4,+7
C +7,+3,+2,+4
D +7,+4,+3,+2

The correct answer is:
+2,+3,+4,+7

Solution:
MnCl2→x+(-2)=0
x=+2
Mn(OH)3→x+(-3)=0
x=+3
MnO2→x+(-4)=0
x=+4
KMnO4→+1+x+(-8)=0
x=+7

Topic: Chemistry, Redox Reactions, NEET
Oxidation numbers of $\mathrm{P}$ in $\mathrm{PO}_4^{3-}$, of $\mathrm{S}$ in $\mathrm{SO}_4^{2-}$ and that of $\mathrm{Cr}$ in $\mathrm{Cr}_2 \mathrm{O}_7^{2-}$ are respectively,

Options:
A $+5,+6$ and +6
B $+3,+6$ and +5
C $+5,+3$ and +6
D $-3,+6$ and +6

The correct answer is:
$+5,+6$ and +6

Solution:
Key Idea (i) Sum of oxidation states of all atoms charge of ion.
(ii) Oxidation number of oxygen $=-2$.
Let the oxidation state of $\mathrm{P}$ in $\mathrm{PO}_4^{3-}$ is $x$.
$$
\therefore \quad \begin{aligned}
& \mathrm{PO}_4^{3-} \\
& \quad \therefore \quad \mathrm{x}+4(-2)=-3 \\
& \mathrm{x}-8=-3 \\
& \mathrm{x}=+5
\end{aligned}
$$
Let the oxidation state of $\mathrm{S}$ in $\mathrm{SO}_4^{2-}$ is .
$$
\begin{aligned}
& \mathrm{SO}_4^{2-} \\
& \therefore \quad \mathrm{y}+4(-2)=-2 \\
& \mathrm{y}-8=-2 \\
& \mathrm{y}=+6
\end{aligned}
$$
Let the oxidation state of $\mathrm{Cr}$ in $\mathrm{Cr}_2 \mathrm{O}_7^{2-}$ is .
$$
\therefore \quad \begin{aligned}
& \mathrm{Cr}_2 \mathrm{O}_7^{2-} \\
& 2 \times \mathrm{z}+7(-2)=-2 \\
& 2 \mathrm{z}-14=-2 \\
& \mathrm{z}=+6
\end{aligned}
$$
Hence, oxidation state of $\mathrm{P}, \mathrm{S}$ and $\mathrm{Cr}$ are +5 , +6 and +6 respectively.

Topic: Chemistry, Redox Reactions, NEET, NEET 2009 (Screening)
Oxidation of ketones involves carbon-carbon bond cleavage. What are the IUPAC names of the products formed on oxidation of 2, 5-dimethylhexan-3-one?

Options:
A 2-Methylpropanoic acid and 3-Methylbutanoic acid
B 3-Methylbutanoic acid, Ethanoic acid and Methanoic acid
C 2-Methylpropanoic acid, 1-Methylbutanoic acid, Ethanoic acid and Methanoic acid
D 2-Methylpropanoic acid, 3-Methylbutanoic acid, Ethanoic acid and Methanoic acid

The correct answer is:
2-Methylpropanoic acid, 3-Methylbutanoic acid, Ethanoic acid and Methanoic acid

Solution:
Correct Option is : (D)
2-Methylpropanoic acid, 3-Methylbutanoic acid, Ethanoic acid and Methanoic acid

Topic: Chemistry, Aldehydes and Ketones, NEET
Oxidation of one mole of tripalmitin releases

Options:
A 102 mol of carbon dioxide and 98 moles of water
B 51 mol of carbon dioxide and 49 moles of water
C 98 mol of carbon dioxide and 102 moles of water.
D 49 mol of carbon dioxide and 51 moles of water.

The correct answer is:
51 mol of carbon dioxide and 49 moles of water

Solution:
Respiratory Quotient:

R.Q. is the ratio of the volume of carbon dioxide released to the volume of oxygen taken in respiration and it is mathematically expressed as:

R.Q. = Volume of CO2 evolvedVolume of O2 consumed
The value of R.Q. varies with the substrate. Thus the measurement of R.Q. gives some idea of the nature of the substrate being respired in a particular tissue. R.Q. is usually measured by Ganong's respirometer.

Fats/Oils: When fats or oils are used as the respiratory substrate like germinating linseed, castor, mustard, til seeds, etc. R.Q. value is generally less than one around 0.7. For example in the case of tripalmitin, the reaction can be written as follows:

2C51H98O6 + 145 O2 â 102CO2 + 196H2O + Energy

R.Q. = Volume of CO2 evolvedVolume of O2 consumed = 102145 = 0.70

Topic: Biology, Respiration in Plants, NEET
Oxidation of oxalic acid by acidified KMnO4 is an example of autocatalysis. Which of the following graph represents the variation of rate of this reaction with time?

Options:
A
B
C
D

The correct answer is:

Solution:
Rate of homogenous autocatalysis, increase with passage of time because the concentration of catalyst increases hence the correct graph is

Topic: Chemistry, Surface Chemistry, NEET
Oxidation of sulfur dioxide into sulfur trioxide in the absence of a catalyst is a slow process but this oxidation occurs easily in the atmosphere. Explain how does this happen.

Options:
A The atmosphere contains a high concentration of sulfur dioxide, which speeds up the oxidation process.
B Sulfur dioxide undergoes auto-catalysis in the atmosphere, accelerating its own oxidation.
C Atmospheric oxygen and moisture act as natural catalysts, promoting the oxidation of sulfur dioxide.
D Atmospheric pressure increases the rate of oxidation of sulfur dioxide.

The correct answer is:
Atmospheric oxygen and moisture act as natural catalysts, promoting the oxidation of sulfur dioxide.

Solution:
Correct Option is : (C)
Atmospheric oxygen and moisture act as natural catalysts, promoting the oxidation of sulfur dioxide.

Topic: Chemistry, Environmental Chemistry, NEET
Oxidation state of Cl in HClO4is

Options:
A +5
B +6
C +7
D +4

The correct answer is:
+7

Solution:
Correct Option is : 3
+7

Topic: Chemistry, Redox Reactions, NEET
Oxidation states of $\mathrm{P}$ in $\mathrm{H}_4 \mathrm{P}_2 \mathrm{O}_5, \mathrm{H}_4 \mathrm{P}_2 \mathrm{O}_6$, $\mathrm{H}_4 \mathrm{P}_2 \mathrm{O}_7$, are respectively

Options:
A $+3,+5,+4$
B $+5,+3,+4$
C $+5,+4,+3$
D $+3,+4,+5$

The correct answer is:
$+3,+4,+5$

Solution:
Key Idea Oxidation state of $\mathrm{H}$ is +1 and that of $\mathrm{O}$ is -2.
Let the oxidation state of $\mathrm{P}$ in the given compounds is $\mathrm{x}$.
In $\mathrm{H}_4 \mathrm{P}_2 \mathrm{O}_5$,
$\begin{aligned}
(+1) \times 4+2 \times x+(-2) \times 5 & =0 \\
4+2 x-10 & =0 \\
2 x & =6 \\
\therefore x & =+3
\end{aligned}$
$\begin{array}{l}
\text {In } \mathrm{H}_4 \mathrm{P}_2 \mathrm{O}_6, \\
(+1) \times 4+2 \times \mathrm{x}+(-2) \times 6 =0 \\
4+2 \mathrm{x}-12 =0 \\
2 \mathrm{x} =8 \\
\therefore \mathrm{x} =+4
\end{array}$
In $\mathrm{H}_4 \mathrm{P}_2 \mathrm{O}_7$
$\begin{aligned}
(+1) \times 4+2 \times x+(-2) \times 7 & =0 \\
4+2 x-14 & =0 \\
2 x & =10 \\
\mathrm{x} & =+5
\end{aligned}$
Thus, the oxidation states of $\mathrm{P}$ in $\mathrm{H}_4 \mathrm{P}_2 \mathrm{O}_5$, $\mathrm{H}_4 \mathrm{P}_2 \mathrm{O}_6$ and $\mathrm{H}_4 \mathrm{P}_2 \mathrm{O}_7$ are $+3,+4$ and +5 respectively.

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), NEET, NEET 2010 (Screening)
Oxidation states of P in H4P2O5,H4P2O6,H4P2O7, are respectively

Options:
A +3, +4, +5
B +3, +5, +4
C +5, +3, +4
D +5, +4, +3

The correct answer is:
+3, +4, +5

Solution:
The value of O.No. of P- atoms in these acids are as follows
H4P2O5→4+2x-10=0
2x=+6
x=+3
H4P2O7→4+2x-12=0
x=+4
H4P2O7→4+2x-14=0
x=+5

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), NEET
Oxidation states of the metal in the minerals haematite and magnetite respectively are

Options:
A II, III in haematite and II in magnetite
B II, III in haematite and III in magnetite
C III in haematite and II, III in magnetite
D II in haematite and II, III in magnetite

The correct answer is:
III in haematite and II, III in magnetite

Solution:
Iron is in +3 oxidation state in Haematite and +2 and +3 states in Magnetite.
Haematite: Fe2O3:2x+3×(-2)=0
x=3
Magnetite: Fe2O4 [an equimolar mixture of FeO and Fe2O3 ]
FeO : x-2=0
x=2
Fe2O3 : x=3

Topic: Chemistry, General Principles and Processes of Isolation of Metals, NEET
Oxidative phosphorylation in eukaryotes occurs during ________.

Options:
A Light reaction in chloroplast
B Dark reaction in chloroplast
C Anaerobic respiration in mitochondria
D Aerobic respiration in mitochondria

The correct answer is:
Aerobic respiration in mitochondria

Solution:
The process of ATP synthesis during oxidation of reduced coenzymes in ETC is called oxidative phosphorylation or terminal oxidation. It takes place in mitochondria.

Topic: Biology, Respiration in Plants, NEET
Oxidative phosphorylation involves simultaneous oxidation and phosphorylation to form

Options:
A	Pyruvate
B NADP
C DPN
D ATP

The correct answer is:
ATP

Solution:
In oxidative phosphorylation, ATP is formed, as the electrons are transferred from NADH or FADH2 to O2 by electron transport chain. Oxidative phosphorylation is the synthesis of energy-rich ATP from ADP and inorganic phosphate, which is connected to oxidation of reduced coenzymes produced in cellular respiration.

Topic: Biology, Respiration in Plants, NEET
Oxidative phosphorylation is

Options:
A Formation of ATP by transfer of phosphate group from a substrate to ADP
B Oxidation of phosphate group in ATP
C Addition of phosphate group to ATP
D Formation of ATP by energy released from electrons removed during substrate oxidation

The correct answer is:
Formation of ATP by energy released from electrons removed during substrate oxidation

Solution:
Oxidative phosphorylation uses the energy of oxidation-reduction of a substrate to generate ATP. Oxidative phosphorylation is made up of two closely connected components: the electron transport chain and chemiosmosis. In the electron transport chain, electrons are passed from one molecule to another, and energy released in these electron transfers is used to form an electrochemical gradient. In chemiosmosis, the energy stored in the gradient is used to make ATP.

Topic: Biology, Respiration in Plants, NEET, NEET 2016 (Phase 2)
Oxidative phosphorylation refers to:

Options:
A Anaerobic production of ATP
B The citric acid cycle production of ATP
C Production of ATP by chemiosmosis
D Alcoholic fermentation

The correct answer is:
Production of ATP by chemiosmosis

Solution:
In respiration during ETS, the movement of electrons from reduced NADH2 and FADH2 to terminal electron acceptor causes accumulation of H+ in perimitochondrialspace, this generates a proton gradient and breakdown of this gradient results in generation of ATP, through chemiosmosis. And this mechanism of ATP generation is known as oxidative phosphorylation.

Topic: Biology, Photosynthesis in Higher Plants, NEET
Oxidising power of chlorine in aqueous solution can be determined by the parameters indicated below

The energy involved in the conversion of 12Cl2(g) to Cl-(aq) (Using the data)

ΔH diss Cl 2 =240 kJ  mol −1

ΔH eg Cl= -349 kJ  mol −1

ΔH hyd Cl= -381 kJ  mol −1

Options:
A +152Â kJÂ mol-1
B -610 kJ mol-1
C -850Â kJÂ mol-1
D +120Â kJÂ mol-1

The correct answer is:
-610 kJ mol-1

Solution:
12Cl2(g)â¶Cl-(aq)
ΔH= 1 2 Δ H diss ( Cl 2 )+Δ H eg Cl+Δ H hyd ( Cl − )
=2402-349-381
=-610 kJ mol-1

Topic: Chemistry, Chemical Bonding and Molecular Structure, NEET
Oxyacid of phosphorus that can reduce AgNO3 to silver is

Options:
A H3PO4
B H4P2O7
C H3PO3
D HPO3

The correct answer is:
H3PO3

Solution:
H3PO3 can reduce AgNO3 to silver.
H3PO3+2AgNO3+H2O→H3PO4+2HNO3+2Ag
Rest other are only oxidants as in them oxidation number of phosphorus is +5.

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), NEET
Oxygen atom forms FCC unit cell with 'A' atoms occupying all tetrahedral voids and 'B' atoms occupying all octahedral voids. If atoms are removed from two of the body diagonals then determine the formula of resultant compound formed.

Options:
A A4 B4 O7
B A8 B6 O7
C A8 B8 O7
D A6 B8 O6

The correct answer is:
A8 B6 O7

Solution:
This problem is based on determination of molecular formula of solid which can be determined by using following steps.
Since O-atom form FCC unit cell, the number of
O-atoms per unit cell = 6 × 1 2 + 8 Face atom × 1 8 = 4 Corner atoms
Number of B atoms at octahedral voids = Number of O-atoms = 4
Number of A atoms at tetrahedral voids
= 2 x Number of O-atoms
= 2 x 4 = 8
Initial formula of compound is A8 B4 O4
After removal about two body diagonal
A atom ⇒ 8 - 4 = 4 (Removed from 2 body diagonals)
B atoms ⇒ 4 - 1 = 3 (Removed from body centre)
O atom ⇒ 4 - 4 × 1 8 = 3.5 (Removed 4 corners)
Formula will be A4B3O3.5 i.e. A8B6O7

Topic: Chemistry, Solid State, NEET
Oxygen boils at -183 Â°C. This temperature, on the Fahrenheit scale is

Options:
A -297.4 Â°F
B -253.6 °F
C -342.6 °F
D -225.3 °F

The correct answer is:
-297.4 Â°F

Solution:
Using C5= F-329
-1835=F-329
F-32= -183Ã95=-329.4
F=-329.4+32=-297.4

Topic: Physics, Thermal Properties of Matter, NEET
Oxygen dissolved in water is an example of which type of solution?

Options:
A Gas in Liquid
B Liquid in Liquid
C Solid in Liquid
D Liquid in Gas

The correct answer is:
Gas in Liquid

Solution:
Correct Option is : 1
Gas in Liquid

Topic: Chemistry, Solutions, NEET
Oxygen is available in plenty in air yet fuels do not burn by themselves at room temperature. Explain.

Options:
A Fuels require a catalyst to initiate combustion.
B Oxygen in air is not pure enough to support combustion.
C The presence of nitrogen in air suppresses combustion.
D The activation energy for combustion reactions of fuels is very high at room temperature therefore they do not burn by themselves.

The correct answer is:
The activation energy for combustion reactions of fuels is very high at room temperature therefore they do not burn by themselves.

Solution:
Correct Option is : (D)
The activation energy for combustion reactions of fuels is very high at room temperature therefore they do not burn by themselves.

Topic: Chemistry, Chemical Kinetics, NEET
Oxygen is very important for aerobic respiration, but oxygen never participates as a reactant in any reaction. What is the role of oxygen in cellular respiration?

Options:
A It is terminal electron acceptor for aerobic respiration.
B It is a nucleotide source for ATP synthesis
C It functions as an electron carrier
D It is the final electron acceptor for anaerobic respiration

The correct answer is:
It is terminal electron acceptor for aerobic respiration.

Solution:
In aerobic respiration oxidation of glucose releases hydrogen which is carried by NAD+ or FAD+, this hydrogen is ultimately accepted by oxygen forming water. Oxygen functions as terminal electron acceptor in aerobic respiration.

Topic: Biology, Respiration in Plants, NEET
Oxygenic photosynthesis occurs in

Options:
A Chromatium
B Oscillatoria
C Rhodospiritlum
D Chlorobium

The correct answer is:
Oscillatoria

Solution:
Oscillatoria is a photosynthetic cyanobacterium. In this, during photosynthesis water is electron donor and oxygen is a by-product, ie, oxygenic photosynthesis occurs. Rhodospirillum and Chlorobium are non-oxygenic photosynthetic, purple non-sulphur and green- sulphur bacteria. Chromatium is purple sulphur bacterium, also a non-oxygenic photosynthetic.

Topic: Biology, Biological Classification, NEET, NEET 2009 (Screening)
Oxygenic photosynthesis occurs in

Options:
A Oscillatoria
B Rhodospirillum
C Chlorobium
D Chromatium

The correct answer is:
Oscillatoria

Solution:
Oscillatoria is a filamentous Gram-ve cyanobacteria which performs oxygenic photosynthesis because of the presence of chlorophyll-a like eukaryotic algae and higher plants.

Topic: Biology, Biological Classification, NEET
Oxytocin acts on which of the following layers of the uterine wall?

Options:
A Endometrium
B Perimetrium
C Mesometrium
D Myometrium

The correct answer is:
Myometrium

Solution:
Perimetrium: outermost thin membranous layer of uterus.
Myometrium: Middle thick layer of smooth muscle which exhibits strong contraction during parturition.
Endometrium: Innermost glandular and vascular layer that lines the uterine cavity, undergo cyclic changes during menstrual cycle.

Topic: Biology, Chemical Coordination and Integration, NEET
Ozone day is

Options:
A January, 30
B September, 16
C April, 21
D December 25

The correct answer is:
September, 16

Solution:
In 1994, the United Nations General Assembly designated September 16 as Ozone day. This International Day is recognized for the preservation of the Ozone Layer, commemorating the date of the signing, in 1987, of the Montreal Protocol on substances that deplete the ozone layer.

Topic: Biology, Environmental Issues, NEET
Ozone depletion takes place as
2O3(g)→3O2(g)
Step-1 O 3 (g)  ↔ K   O 2 (g) + [O]
Step-2 O 3 (g) + [O] → k 2O 2 (g) (slow)
Order of the reaction will be

Options:
A 1
B 2
C 3
D Unpredictable

The correct answer is:
1

Solution:
Rate =k[O3][O] ...(i) (for RDS)
K=[O2][O][O3] …(i)
[O]=K[O3][O2] (from step 1)
From equation (i) and (ii)
Rate =kK[O3]2[O2]-1
Order =2-1=1

Topic: Chemistry, Chemical Kinetics, NEET