datavorous/entrance-exam-dataset huggingface dataset:
Match List-I with List-II.
\(\begin{array}{|c|l|c|l|}
\hline & \text { List - I } & & \text { List - II } \\
\hline & \text { (Hydride) } & & \text { (Type of hydride) } \\
\hline(A) & \mathrm{NaH} & \text { (I) } & \text { Electron precise } \\
\hline \text { (B) } & \mathrm{PH}_3 & \text { (II) } & \text { Saline } \\
\hline \text { (C) } & \mathrm{GeH}_4 & \text { (III) } & \text { Metallic } \\
\hline \text { (D) } & \mathrm{LaH}_{2.87} & \text { (IV) } & \text { Electron rich } \\
\hline
\end{array}\)
Choose the correct answer from the options given below:

Options:
A $(\mathrm{A})-(\mathrm{I}),(\mathrm{B})-(\mathrm{III}),(\mathrm{C})-(\mathrm{II}),(\mathrm{D})-(\mathrm{IV})$
B (A)-(II), (B)-(IV), (C)-(I), (D)-(III)
C (A)-(III), (B)-(IV), (C)-(II), (D)-(I)
D $(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{III}),(\mathrm{C})-(\mathrm{IV}),(\mathrm{D})-(\mathrm{I})$

The correct answer is:
(A)-(II), (B)-(IV), (C)-(I), (D)-(III)

Solution:
$\begin{array}{ll}\text { Hydride } & \text { Type of Hydride } \\ \mathrm{NaH} & \text { Saline or lonic hydride (Generally formed by s-block elements) } \\ \mathrm{PH}_3 & \text { Electron rich hydride (Elements of group 15-17 form such hydrides) } \\ \mathrm{GeH}_4 & \text { Electron precise (Elements of group } 14 \text { form such hydrides) } \\ \mathrm{LaH}_{2.87} & \text { Metallic or Non-stoichiometric hydrides (Formed by f block element) }\end{array}$

Topic: Chemistry, Hydrogen, NEET, NEET 2023 (Manipur)
Match List-I with List-II.
\(\begin{array}{|c|l|c|l|}
\hline & \text { List-I } & & \text { List-II } \\
\hline & \text { (Mixtures/Sample) } & & \text { (Technique used for purification) } \\
\hline(A) & \text { Glycerol from spent lye } & \text { (I) } & \text { Steam distillation } \\
\hline(B) & \text { Chloroform + Aniline } & \text { (II) } & \text { Fractional distillation } \\
\hline \text { (C) } & \text { Fractions of crude oil } & \text { (III) } & \text { Distillation under reduced pressure } \\
\hline \text { (D) } & \text { Aniline + Water } & \text { (IV) } & \text { Distillation } \\
\hline
\end{array}\)
Choose the correct answer from the options given below:

Options:
A $(\mathrm{A})-(\mathrm{I}),(\mathrm{B})-(\mathrm{II}),(\mathrm{C})-(\mathrm{III}),(\mathrm{D})-(\mathrm{IV})$
B $(\mathrm{A})-(\mathrm{I}),(\mathrm{B})-(\mathrm{III}),(\mathrm{C})-(\mathrm{II}),(\mathrm{D})-(\mathrm{IV})$
C $(\mathrm{A})-(\mathrm{III}),(\mathrm{B})-(\mathrm{IV}),(\mathrm{C})-(\mathrm{II}),(\mathrm{D})-(\mathrm{I})$
D $(\mathrm{A})-(\mathrm{IV}),(\mathrm{B})-(\mathrm{II}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{III})$

The correct answer is:
$(\mathrm{A})-(\mathrm{III}),(\mathrm{B})-(\mathrm{IV}),(\mathrm{C})-(\mathrm{II}),(\mathrm{D})-(\mathrm{I})$

Solution:
- Chloroform (b.p. $334 \mathrm{~K}$ ) and aniline (b.p. 457) are easily separated by the technique of distillation as both the liquids having sufficient difference in their boiling points.
- The fractions of crude oil in petroleum industry is separated using fractional distillation due to less difference in boiling points of liquids.
- Glycerol can be separated from spent-dye using distillation under reduced pressure.
- Aniline is separated by steam distillation from aniline-water mixture.

Topic: Chemistry, General Organic Chemistry, NEET, NEET 2023 (Manipur)
Match List-I with List-II :
\(\begin{array}{|l|l|}
\hline \text { List - I } & \text { List - II } \\
\hline \text { (a) Bacteriophage } \phi \times 174 & \text { (i) } 48502 \text { base pairs } \\
\text { (b) Bacteriophage lambda } & \text { (ii) } 5386 \text { nucleotides } \\
\text { (c) Escherichia coli } & \text { (iii) } 3.3 \times 109 \text { base pairs } \\
\text { (d) Haploid content of human DNA } & \text { (iv) } 4.6 \times 106 \text { base pairs } \\
\hline
\end{array}\)
Choose the correct answer from the options given below:

Options:
A (a) - (i), (b) - (ii), (c) - (iii), (d) - (iv)
B (a) - (ii), (b) - (iv), (c) - (i), (d) - (iii)
C (a) - (ii), (b) - (i), (c) - (iv), (d) - (iii)
D (a) - (i), (b) - (ii), (c) - (iv), (d) - (iii)

The correct answer is:
(a) - (ii), (b) - (i), (c) - (iv), (d) - (iii)

Solution:

Topic: Biology, Molecular Basis of Inheritance, NEET, NEET 2022 (Phase 2)
Match List-I with List-II
\(\begin{array}{l|l}
\hline \text{ List-I } & \text{ List-II } \\
\hline \text { (a) Sodium laurylsulphate } & \text { (i) Toilet soap } \\
\text { (b) Cetyltrimethyl ammonium chloride } & \text { (ii) Non-ionic detergent } \\
\text { (c) Sodium stearate } & \text { (iii) Anionic } \\
\text { (d) Polyethyleneglycyl stearate } & \text { (iv) Cationic detergent }
\end{array}\)
Choose the correct answer from the options given below :

Options:
A (a) - (iv), (b) - (iii), (c) - (i), (d) - (ii)
B (a) - (i), (b) - (iv), (c) - (ii), (d) - (iii)
C (a) - (iii), (b) - (iv), (c) - (i), (d) - (ii)
D (a) - (iii), (b) - (i), (c) - (ii), (d) - (iv)

The correct answer is:
(a) - (iii), (b) - (iv), (c) - (i), (d) - (ii)

Solution:
Sodium lauryl sulphate :
$\frac{\mathrm{CH}_3\left(\mathrm{CH}_2\right)_{11} \mathrm{SO}_4^{-} \mathrm{Na}^{+}}{\text {anionic }}$
Cetyltrimethyl ammonium chloride :
$\frac{\mathrm{CH}_3\left(\mathrm{CH}_2\right)_{15} \mathrm{~N}^{+}\left(\mathrm{CH}_3\right)_3 \mathrm{Cl}^{-}}{\text {cationic }}$
Sodium Stearate :
$\frac{\mathrm{C}_{17} \mathrm{H}_{35} \mathrm{COO}^{-} \mathrm{Na}^{+}}{\text {anionic }}$
(Component of bath soap or toilet soap)
Polyethyleneglycyl stearate - Non ionic reagent.

Topic: Chemistry, Chemistry in Everyday Life, NEET, NEET 2022 (Phase 2)
Match List-I with List-II :
\(\begin{array}{l|l}
\text { List - I } & \text { List - II } \\
\text { (Molecules) } & \text { Shape } \\
\hline \text { (a) } \mathrm{NH}_3 & \text { (i) Square pyramidal } \\
\text { (b) } \mathrm{ClF}_3 & \text { (ii) Trigonal bipyramidal } \\
\text { (c) } \mathrm{PCl}_5 & \text { (iii) Trigonal pyramidal } \\
\text { (d) } \mathrm{BrF}_5 & \text { (iv) T-shape }
\end{array}\)
Choose the correct answer from the options given below :

Options:
A (a) - (ii), (b) - (iii), (c) - (iv), (d) - (i)
B (a) - (iii), (b) - (iv), (c) - (ii), (d) - (i)
C (a) - (iv), (b) - (iii), (c) - (i), (d) - (ii)
D (a) - (iii), (b) - (iv), (c) - (i), (d) - (ii)

The correct answer is:
(a) - (iii), (b) - (iv), (c) - (ii), (d) - (i)

Solution:

Topic: Chemistry, Chemical Bonding and Molecular Structure, NEET, NEET 2022 (Phase 2)
Match List-I with List-II :
\(\begin{array}{l|l}
\text{List-I} & \text{List-II} \\
\text{(Compounds)} & \text{(Molecular formula)} \\
\hline \text { (a) Borax } & \text { (i) } \mathrm{NaBO}_2 \\
\text { (b) Kernite } & \text { (ii) } \mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7 \cdot 4 \mathrm{H}_2 \mathrm{O} \\
\text { (c) Orthoboric acid } & \text { (iii) } \mathrm{H}_3 \mathrm{BO}_3 \\
\text { (d) Borax bead } & \text { (iv) } \mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7 \cdot 10 \mathrm{H}_2 \mathrm{O}
\end{array}\)
Choose the correct answer from the options given below :

Options:
A (a)-(iv), (b)-(ii), (c)-(iii), (d)-(i)
B (a)-(ii), (b)-(iv), (c)-(iii), (d)-(i)
C (a)-(iii), (b)-(i), (c)-(iv), (d)-(ii)
D (a)-(i), (b)-(iii), (c)-(iv), (d)-(ii)

The correct answer is:
(a)-(iv), (b)-(ii), (c)-(iii), (d)-(i)

Solution:
(a) Borax $-\mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7 \cdot 10 \mathrm{H}_2 \mathrm{O}$ or $\mathrm{Na}_2\left[\mathrm{~B}_4 \mathrm{O}_5(\mathrm{OH})_4\right] \cdot 8 \mathrm{H}_2 \mathrm{O}$
(b) Kernite $-\mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7 \cdot 4 \mathrm{H}_2 \mathrm{O}$
(c) Orthoboric acid $-\mathrm{H}_3 \mathrm{BO}_3$
(d) Borax bead $-\mathrm{NaBO}_2$
(obtained by heating of borax)
$\mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7 \cdot 10 \mathrm{H}_2 \mathrm{O} \stackrel{\Delta}{\stackrel{-10 \mathrm{H}_2 \mathrm{O}}{\longrightarrow}} \mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7 \stackrel{\Delta}{\longrightarrow} 2 \mathrm{NaBO}_2+\mathrm{B}_2 \mathrm{O}_3$
Sodium metaborate

Topic: Chemistry, p Block Elements (Group 13 & 14), NEET, NEET 2022 (Phase 2)
Match List-I with List-II:
\begin{array}{lll} List-I & {c}{ List-II } \\Organisms & {c}{ Mode of Nutrition } \\A. Euglenoid & I. Parasitic \\B.Dinoflagellate & II. Saprophytic \\C. Slime mould & III. Photosynthetic \\D. Plasmodium & IV. Switching between photosynthetic and heterotrophic mode\end{array}
Choose the correct answer from the options given below:

Options:
A A-III, B-IV, C-II, D-I
B A-IV, B-II, C-I, D-III
C A-IV, B-III, C-II, D-I
D A-IV, B-II, C-III, D-I

The correct answer is:
A-IV, B-III, C-II, D-I

Solution:
Euglenoids are photosynthetic in the presence of sunlight, when deprived of sunlight they behave like heterotrophs.
Dinoflagellates are mostly marine and photosynthetic.
Slime moulds are saprophytic protists.
Plasmodium is malarial parasite which cause malaria.

Topic: Biology, Biological Classification, NEET, NEET 2024 (Re-NEET)
Match List-I with List-II :
\begin{array}{lll} & List-I & & List-II \\A.& Abscisic acid & I.& Promotes female flowers in cucumber \\B.& Ethylene & II.& Helps seeds to withstand desiccation \\C.& Gibberellin & III.& Helps in nutrient mobilisation \\D. & Cytokinin & IV.& Promotes bolting in beet, cabbage etc\end{array}

Choose the correct answer from the options given below:

Options:
A A-II, B-III, C-IV, D-I
B A-III, B-II, C-I, D-IV
C A-II, B-I, C-IV, D-III
D A-III, B-I, C-III, D-IV

The correct answer is:
A-II, B-I, C-IV, D-III

Solution:
Abscisic acid $\rightarrow$ Helps seeds to withstand desiccation
Ethylene $\rightarrow$ Promotes female flowers in cucumber
Gibberellin $\rightarrow$ Promotes bolting in beet, cabbage etc.
Cytokinin $\rightarrow$ Helps in nutrient mobilisation
Hence, the correct answer is option (3)

Topic: Biology, Plant - Growth and Development, NEET, NEET 2024 (Re-NEET)
Match List-I with List-II :
\begin{array}{llll} List-I & & List-II \\A. & ETS Complex I & I. & NADH Dehydrogenase \\B. & ETS Complex II & II. & Cytochrome bC { }_1 \\C. & ETS Complex III & III. & Cytochrome C oxidase \\D. & ETS Complex IV & IV. & Succinate Dehydrogenase\end{array}
Choose the correct answer from the options given below :

Options:
A A-IV, B-I, C-III, D-II
B A-I, B-IV, C-II, D-III
C A-III, B-I, C-IV, D-II
D A-I, B-II, C-IV, D-III

The correct answer is:
A-I, B-IV, C-II, D-III

Solution:
ETS complex I $\rightarrow$ NADH dehydrogenase
ETS complex II $\rightarrow$ Succinate dehydrogenase
ETS complex III $\rightarrow$ Cytochrome bC b complex $_1$
ETS complex IV $\rightarrow$ Cytochrome C oxidase complex
Hence the correct answer is option (2)

Topic: Biology, Respiration in Plants, NEET, NEET 2024 (Re-NEET)
Match List-I with List-II :
\begin{array}{llll} & List-I & & List-II \\A. & Vexillary aestivation & I.&Brinjal \\B. & Epipetalous stamens & II. & Peach \\C. & Epiphyllous stamens & III. & Pea \\D. & Perigynous flower & IV. & Lily\end{array}
Choose the correct answer from the options given below :

Options:
A A-III, B-I, C-IV, D-II
B A-III, B-IV, C-I, D-II
C A-III, B-II, C-I, D-IV
D A-II, B-I, C-IV, D-III

The correct answer is:
A-III, B-I, C-IV, D-II

Solution:
In pea, vexillary aestivation is found.
Perigynous flowers are observed in peach.
Epiphyllous stamens are found in lily.
Epipetalous stamens are found in brinjal.

Topic: Biology, Morphology of Flowering Plants, NEET, NEET 2024 (Re-NEET)
Match List-I with List-II :
\begin{array}{llll} List-I & & List-II \\A.Genetically engineered Human Insulin & I. & Gene therapy \\B. GM Cotton & II.& E. coli \\C. ADA Deficiency & III.& Antigen-antibody interaction \\D. ELISA & IV. & Bacillus thuringiensis\end{array}
Choose the correct answer from the options given below:

Options:
A A-III, B-II, C-IV, D-I
B A-II, B-I, C-IV, D-III
C A-IV, B-III, C-I, D-II
D A-II, B-IV, C-I, D-III

The correct answer is:
A-II, B-IV, C-I, D-III

Solution:
In genetically engineered human insulin, $E$. coli is used as host cell.
$\Rightarrow$ For creating GM cotton, bacteria Bacillus thuringiensis is used.
$\Rightarrow$ Gene therapy is one of the treatment for ADA deficiency.
$\Rightarrow$ ELISA test is based on antigen-antibody interaction.

Topic: Biology, Biotechnology and Its Applications, NEET, NEET 2024 (Re-NEET)
Match List-I with List-II:
\begin{array}{llll} List-I & List-II \\Type of Inheritance & Example \\A.Incomplete dominance & I. Blood groups in human \\B.Co-dominance & II. Flower colour in Antirrhinum \\C.Pleiotropy & III. Skin colour in human \\D.Polygenic inheritance & IV.Phenylketonuria\end{array}
Choose the correct answer from the options given below:

Options:
A A-III, B-IV, C-II, D-I
B A-II, B-I, C-IV, D-III
C A-II, B-III, C-I, D-IV
D A-IV, B-I, C-III, D-II

The correct answer is:
A-II, B-I, C-IV, D-III

Solution:
Flower colour in Antirrhinum is a good example of incomplete dominance.
- Blood group in humans is an example of co-dominance where $F_1$ generation resembles both the parents.
- Phenylketonuria is an example of Pleiotropy.
- Skin colour in human shows polygenic inheritance.
Hence, A-II, B-I, C-IV, D-III is correct.

Topic: Biology, Principles of Inheritance and Variation, NEET, NEET 2024 (Re-NEET)
Match List-I with List-II:
\begin{array}{|l|l|l|l|}\hline & List I & & List II \\\hline A. & Parturition & I. & Several antibodies for new-born babies \\\hline B. & Placenta & II. & Collection of ovum after ovulation \\\hline C. & Colostrum & III. & Foetal ejection reflex \\\hline D. & Fimbriae & IV. & Secretion of the hormone hCG \\\hline\end{array}
Choose the correct answer from the option given below:

Options:
A A-III, B-IV, C-I, D-II
B A-I, B-IV, C-II, D-III
C A-II, B-III, C-IV, D-I
D A-III, B-IV, C-II, D-I

The correct answer is:
A-III, B-IV, C-I, D-II

Solution:
The correct answer is option (1) as
- Parturition is induced by a complex neuroendocrine mechanism. The signals for parturition originate from the fully developed foetus and the placenta that induce mild uterine contractions called foetal ejection reflex.
- Placenta acts as an endocrine tissue and produces several hormones like hCG, hPL estrogens, progestogens, etc.
- The milk produced during the initial few days of lactation is called colostrum that contains several antibodies absolutely necessary to develop resistance for the new-born babies.
Fimbriae helps in collection of the ovum after ovulation.

Topic: Biology, Human Reproduction, NEET, NEET 2024 (Re-NEET)
Match List-I with List-II:
\begin{array}{|l|l|l|l|}\hline & List I & & List II \\\hline A. & Predator & I. & Ophrys \\\hline B. & Mutualism & II. & Pisaster \\\hline C. & Parasitism & III. & Female wasp and fig \\\hline D & Sexual deceit & IV. & Plasmodium \\\hline\end{array}
Chose the correct answer from the options given below:

Options:
A A-III, B-II, C-I, D-IV
B A-IV, B-I, C-II, D-III
C A-II, B-III, C-I, D-IV
D A-II, B-III, C-IV, D-I

The correct answer is:
A-II, B-III, C-IV, D-I

Solution:
(1) In predation one species is benefitted '+' while the other is detrimental ' - '. Pisaster is an important predator in the rocky intertidal communities of the American pacific coast.
(2) In many species of fig trees, there is tight one-to-one relationship with the pollinator species of wasp. It means that a given fig species can be pollinated only by its 'partner' wasp species and no other species is an example of mutualism.
(3) Plasmodium is an endoparasite in humans that causes malaria.
(4) The Mediterranean orchid Ophrys employs 'sexual deceit' to get pollination done by a species of bee.

Topic: Biology, Organisms and Populations, NEET, NEET 2024 (Re-NEET)
Match List-I with List-II.
\begin{array}{|l|l|l|l|}\hline & List-I & & List-II \\\hline A. & Chondrichthyes & I. & Clarias \\\hline B. & Cyclostomata & II. & Carcharodon \\\hline C. & Osteichthyes & III. & Myxine \\\hline D. & Amphibia & IV. & Ichthyophis \\\hline\end{array}
Choose the correct answer from the options given below:

Options:
A A-II, B-IV, C-I, D-III
B A-I, B-III C-II, D-IV
C A-II, B-III, C-I, D-IV
D A-I, B-II, C-III, D-IV

The correct answer is:
A-II, B-III, C-I, D-IV

Solution:
The correct answer is option (3), because
- Carcharodon is a cartilaginous fish which belongs to the class Chondrichthyes.
- Myxine is a jawless vertebrate that belongs to the class Cyclostomata.
- Clarias is a bony fish which belongs to the class Osteichthyes.
- Ichthyophis is a limbless animal which belongs to the class Amphibia.
Hence the correct matches are
A. Chondrichthyes - Carcharodon
B. Cyclostomata - Myxine
C. Osteichthyes - Clarias
D. Amphibia - Ichthyophis

Topic: Biology, Animal Kingdom, NEET, NEET 2024 (Re-NEET)
Match List-I with List-II.
\begin{array}{|l|l|l|l|}\hline & List-I & & List-II \\\hline A. & F1 Particles & I. & Chromosomes \\\hline B. & Histones & II. & Cilia \\\hline C. & Axoneme & III. & Golgi apparatus \\\hline D. & Cisternae & IV. & Mitochondria \\\hline\end{array}
Choose the correct answer from the options given below:

Options:
A A-II, B-I, C-IV, D-III
B A-IV, B-I, C-II, D-III
C A-IV, B-I, C-III, D-II
D A-IV, B-III, C-I, D-II

The correct answer is:
A-IV, B-I, C-II, D-III

Solution:
$\mathrm{F}_1$ particles or oxysomes are found on the inner face of the inner membrane of mitochondria. Chromatin fibres condenses to form chromosomes.
Chromatin is essentially composed of DNA and basic histone proteins.
Core of cilia is known as axoneme.
In golgi complex cisternae are sac like structure.
A-IV, B-I, C-II, D-III

Topic: Biology, Cell - The Unit of Life, NEET, NEET 2024 (Re-NEET)
Match List-I with List-II:
\begin{array}{|l|l|l|l|}\hline & List-I & & List-II \\\hline A. & Living Fossil & I. & Elongated canine teeth \\\hline B. & Connecting Link & II. & Vermiform appendix \\\hline C. & Vestigial Organ & III. & Echidna \\\hline D. & Atavism & IV. & Latimeria \\\hline\end{array}
Choose the correct answer from the options given below:

Options:
A A-IV, B-III, C-II, D-I
B A-IV, B-II, C-III, D-I
C A-IV, B-III, C-I, D-II
D A-III, B-IV, C-I, D-II

The correct answer is:
A-IV, B-III, C-II, D-I

Solution:
The correct answer is option (1) because:
- Latimeria is a living fossil, it is a bony fish, so (A) matches with (IV).
- Echidna is the connecting link between the reptiles and the mammals, so (B) matches with (III).
- Vestigial organs are remnants of organs which were complete and functional in the ancestral forms. The vermiform appendix of man is a vestigial organ. So, (C) matches with (II).
- Atavism is a trait of distant ancestors that reappears in the modern day, e.g., elongated canine teeth in humans. So, (D) matches with (I).
Options (2), (3) and (4) are incorrect as (A), (B), (C) and (D) have incorrect matches in them.

Topic: Biology, Evolution, NEET, NEET 2024 (Re-NEET)
Match List-I with List-II
Choose the correct answer from the option given below:

Options:
A $(\mathrm{A})-(\mathrm{III}),(\mathrm{B})-(\mathrm{I}),(\mathrm{C})-(\mathrm{II}),(\mathrm{D})-(\mathrm{IV})$
B $(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{IV}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{III})$
C $(\mathrm{A})-(\mathrm{IV}),(\mathrm{B})-(\mathrm{III}),(\mathrm{C})-(\mathrm{II}),(\mathrm{D})-(\mathrm{I})$
D $(\mathrm{A})-(\mathrm{I}),(\mathrm{B})-(\mathrm{II}),(\mathrm{C})-(\mathrm{III}),(\mathrm{D})-(\mathrm{IV})$

The correct answer is:
$(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{IV}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{III})$

Solution:
Deforestation is the conversion of forested areas to non-forested ones.
Reforestation is the process of restoring a forest that once existed but was removed at some point of time in the past.
The greenhouse effect is a naturally occurring phenomenon that is responsible for heating of Earth's surface and atomosphere
Eutrophication is the natural aging of a lake by nutrient enrichment of its water.
Thus, option (2) is correct as it is mentioning all the correct matches.

Topic: Biology, Environmental Issues, NEET, NEET 2023 (Manipur)
Match List-I with List-II:
Choose the correct answer from the options given below :

Options:
A (a)-(iii), (b)-(iv), (c)-(i), (d)-(ii)
B (a)-(iv), (b)-(iii), (c)-(i), (d)-(ii)
C (a)-(iv), (b)-(iii), (c)-(ii), (d)-(i)
D (a)-(iii), (b)-(iv), (c)-(ii), (d)-(i)

The correct answer is:
(a)-(iii), (b)-(iv), (c)-(ii), (d)-(i)

Solution:
$\begin{array}{|c|c|c|c|}\hline \begin{array}{c}\text { Principle } \\ \text { QN }(n)\end{array} & \begin{array}{c}\text { Azimuthal } \\ \text { QN }(l)\end{array} & \begin{array}{c}\text { Possible } \\ \text { values } \\ (n-1)\end{array} & \text { Subshell } \\ \hline n=1 & 0 & & s \\ \hline n=2 & 0 & & s \\ & 1 & & p \\ \hline n=3 & 0 & & s \\ & 1 & & p \\ & 2 & & d \\ \hline n=4 & 0 & & s \\ & 1 & & p \\ & 2 & & d \\ & 3 & & f \\ \hline \end{array}$
So, for $n=2, l=1$, orbital is $2 p$ for $n=3, l=2$, orbital is $3 d$ for $n=3, l=0$, orbital is $3 \mathrm{~s}$ for $n=2, l=0$, orbital is $2 s$

Topic: Chemistry, Structure of Atom, NEET, NEET 2022 (Phase 2)
Match List-I with List-II:
Choose the correct answer from the options given below:

Options:
A (a)-(i), (b)-(iv), (c)-(ii), (d)-(iii)
B (a)-(iii), (b)-(iv), (c)-(i), (d)-(ii)
C (a)-(iii), (b)-(i), (c)-(iv), (d)-(ii)
D (a)-(iv), (b)-(iii), (c)-(ii), (d)-(i)

The correct answer is:
(a)-(iii), (b)-(i), (c)-(iv), (d)-(ii)

Solution:
(a) Biological oxygen demand (BOD) - Organic matter in water
(b) Photochemical smog-Oxidising in nature (occurs in warm, dry and sunny climate)
(c) Classical smog - Reducing in nature (occurs in cool and humid climate)
(d) Ozone layer depletion - Polar stratospheric cloud

Topic: Chemistry, Environmental Chemistry, NEET, NEET 2022 (Phase 2)
Match List-I with List-II :
Choose the correct answer from the options given below :

Options:
A (a) - (ii), (b) - (i), (c) - (iv), (d) - (iii)
B (a) - (i), (b) - (iii), (c) - (ii), (d) - (iv)
C (a) - (iv), (b) - (i), (c) - (iii), (d) - (ii)
D (a) - (ii), (b) - (iii), (c) - (iv), (d) - (i)

The correct answer is:
(a) - (ii), (b) - (i), (c) - (iv), (d) - (iii)

Solution:

Topic: Biology, Biotechnology - Principles and Processes, NEET, NEET 2022 (Phase 2)
Match List-I with List-II :
Choose the correct answer from the options given below :

Options:
A (a) - (iv), (b) - (iii), (c) - (i), (d) - (ii)
B (a) - (ii), (b) - (iv), (c) - (i), (d) - (iii)
C (a) - (iv), (b) - (i), (c) - (ii), (d) - (iii)
D (a) - (iv), (b) - (iii), (c) - (ii), (d) - (i)

The correct answer is:
(a) - (iv), (b) - (iii), (c) - (i), (d) - (ii)

Solution:

Topic: Biology, Biodiversity and its Conservation, NEET, NEET 2022 (Phase 2)
Match List-I with List-II.
Choose the correct answer from the options given below:

Options:
A $(\mathrm{A})-(\mathrm{III}),(\mathrm{B})-(\mathrm{II}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{IV})$
B $(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{I}),(\mathrm{C})-(\mathrm{III}),(\mathrm{D})-(\mathrm{IV})$
C $(\mathrm{A})-(\mathrm{IV}),(\mathrm{B})-(\mathrm{II}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{III})$
D $(\mathrm{A})-(\mathrm{I}),(\mathrm{B})-(\mathrm{III}),(\mathrm{C})-(\mathrm{II}),(\mathrm{D})-(\mathrm{IV})$

The correct answer is:
$(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{I}),(\mathrm{C})-(\mathrm{III}),(\mathrm{D})-(\mathrm{IV})$

Solution:
Option (2) is the answer as it represents the correct match.
- Contractile vacuole is present in Amoeba and helps in osmoregulation.
- Water vascular system is the most distinctive feature of echinoderms such as Asterias, Echinus etc.
- Sponges have water transport or canal system in Spongilla.
Platyhelminthes like Taenia have specialised cells called flame cells that helps in osmoregulation and excretion.

Topic: Biology, Animal Kingdom, NEET, NEET 2023 (Manipur)