datavorous/entrance-exam-dataset huggingface dataset:
The order of leaving group ability is

The order of leaving group ability is

Options:
A I > II > III > IV
B IV > III > II > I
C I > III > IV > II
D IV > III > I > II

The correct answer is:
IV > III > I > II

Solution:
Leaving tendency of L.g. ∝ stability of L.G.
The order of leaving group ability is
IV > III > I > II.

Topic: Chemistry, General Organic Chemistry, NEET
The order of occurrence of the cytochromes in the F1 particles is

Options:
A cyt b, cyt c, cyt a-cyt a3
B cyt c, cyt b, cyt a-cyt a3
C cyt a, cyt b, cyt c-cyt a3
D cyt a3-cyt a, cyt c, cyt b

The correct answer is:
cyt b, cyt c, cyt a-cyt a3

Solution:
The order of occurrence of the cytochromes in the F1particle present in mitochondrial cristae is cyt b, cyt c, cyt a-cyt-a3. They accept the electron and pass on to the other cytochrome, cyt a3 is oxido reductive cytochrome.

Topic: Biology, Respiration in Plants, NEET
The order of rate of hydrolysis of alkyl halides 1°, 2°, 3° and CH3X by the SN2 pathway is

Options:
A 1°>2°>3°>CH3X
B CH3X>3o>2o>1o
C CH3X>1o>2o>3o
D 3o>2o>1o>CH3X

The correct answer is:
CH3X>1o>2o>3o

Solution:
For SN2 reaction reactivity â1steric hinderance
S N 2Nu+R−X → slow Nu…R…X Transitionstate → Fast Nu−R+ X −
Order of reactivity: CH3X>1o>2o>3o.

Topic: Chemistry, Haloalkanes and Haloarenes, NEET
The order of reactivities of the following alklyl halides for a SN2 reaction is

Options:
A RF > RCl > RBr > RI
B RF > RBr > RCl > RI
C RCl > RBr > RF > RI
D RI > RBr > RCl > RF

The correct answer is:
RI > RBr > RCl > RF

Solution:
The reactivity of the alkyl halide is decided by the ease with which the halide leaves the substrate. As with the decrease in size of halogen, C – X bond energy increases and so reactivity of alkyl halide decreases.
It means the leaving ability, order is I->Br->Cl->F- and the order of SN2 ​ reaction is RI > RBr > RCl > RF.

Topic: Chemistry, Haloalkanes and Haloarenes, NEET
The order of stability of the alkenes

R 2 C = CR 2 , R 2 C = CHR , R 2 C = CH 2 , RCH = CHR , RCH = CH 2 I II III IV V
( R= − CH 3 )

Options:
A I > II > III > IV > V
B I = II > III > IV > V
C II > I > IV > III > V
D V > IV > III > II > I

The correct answer is:
I > II > III > IV > V

Solution:
More substituted alkenes are more stable (more hypercnjugation) and alkyl groups on two different carbon atoms makes it more stable
I > II > III > IV > V

Topic: Chemistry, General Organic Chemistry, NEET
The order of stability of the following tatutomeric compound is

Options:
A I $>$ II $>$ III
B III $>$ II $>$ I
C II $>$ I $>$ III
D II $>$ III $>$ I

The correct answer is:
III $>$ II $>$ I

Solution:
The rolls of $\beta$-dicarbonyl compounds are more stable because of conjugation and intramolecular $\mathrm{H}$-bonding. Thus, the order of

Topic: Chemistry, General Organic Chemistry, NEET, NEET 2013 (All India)
The order of the gaseous reaction Agâ¶2Bg+Cg is found to be one at the initial pressure P 0 =90 torr . The total pressure after ten minutes is found to be 180 torr . Find the value of the rate constant ?

Options:
A 1.15Ã10-3 s-1
B 2.30×10-3 s-1
C 3.45×10-3 s-1
D 4.60×10-3s-1

The correct answer is:
1.15Ã10-3 s-1

Solution:
Given, Initial pressure of A, P 0 =90 torr

Let's assume there is a decrease in pressure of A by P 0 torr after 10 mins. Therefore, after 10 mins the reaction mixture will look like,

Agâ¶ 2Bg+C g

P 0 â p 2p p

P t = P 0 +2p=180 torr

p=45 torr

Thus, after 10 mins, the pressure of A will be, P A = P 0 âp = 90â45=45 torr

k= 1 t ln P 0 P A

k= 1 600 ln 90 45

=1.15Ã 10 â3 s â1

Topic: Chemistry, Chemical Kinetics, NEET
The order of the oxidation state of the phosphorus atom in H3PO2,H3PO4,H3PO3 and H4P2O6 is

Options:
A H3PO4>H3PO2>H3PO3>H4P2O6
B H3PO4>H4P2O6>H3PO3>H3PO2
C H3PO2>H3PO3>H4P2O6>H3PO4
D H3PO4>H3PO2>H3PO4>H4P2O6

The correct answer is:
H3PO4>H4P2O6>H3PO3>H3PO2

Solution:
Correct order is H3PO4(+5)>H4P2O6(+4)>H3PO3(+3)>H3PO2(+1)

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), NEET
The order which can explain the ease of dehydration of following is

Options:
A I < II > III
B III > II > I
C I > III > II
D III < I < II

The correct answer is:
III > II > I

Solution:
The correct order of stability of carbocation is as follows:
Rate of dehydration of alcohol is directly proportional to the stability of the carbocation.
More stable carbocation will form then easy and faster will be the dehydration.
In III, 2âcarbonation will form on dehydration of alcohol and it is resonance stabilized and there is some extended conjugation is also present.
In II 2â carbocation will form on dehydration of alcohol and it is resonance stabilized but there is no extended conjugation.
In I 2â carbocation will form on dehydration of alcohol and it is not resonance stabilized. It can be stabilized by the hyperconjugation only.
As the above discussion, the priority of resonance over the hyperconjugation is more due to this fact the stability order is the III>II>I.
Hence, The ease of dehydration of alcohol is directly proportional to the stability of the carbocation. The order of ease of dehydration is given below.

Topic: Chemistry, General Organic Chemistry, NEET
The organ which acts as a filter of blood is

Options:
A a small solid structure present in the right side within the abdomen
B a large bean-shaped organ present in the left side within the abdomen
C a lobed organ located near the heart
D also called MALT

The correct answer is:
a large bean-shaped organ present in the left side within the abdomen

Solution:
The organ which acts as a filter of blood is the spleen. It is responsible for trapping the blood-borne microorganisms. It is a large bean-shaped, purple organ. It has a large reservoir of erythrocytes.

Topic: Biology, Human Health and Diseases, NEET
The organelles that are included in the endomembrane system are:

Options:
A Endoplasmic reticulum, Mitochondria, Ribosomes and Lysosomes
B Endoplasmic reticulum, Golgi complex, Lysosomes and Vacuoles
C Golgi complex, Mitochondria, Ribosomes and Lysosomes
D Golgi complex, Endoplasmic reticulum, Mitochondria and Lysosomes

The correct answer is:
Endoplasmic reticulum, Golgi complex, Lysosomes and Vacuoles

Solution:
The endomembrane system includes the nuclear envelope, endoplasmic reticulum, Golgi apparatus, lysosomes, vacuoles, and the plasma membrane. Mitochondria and ribosomes are not a part of this system.

Topic: Biology, Cell - The Unit of Life, NEET, NEET 2021
The organism can be divided into similar halves by passing a plane at any angle along a central axis is called

Options:
A Radial symmetry
B Bilateral symmetry
C Asymmetrical
D More than one option is correct

The correct answer is:
Radial symmetry

Solution:
Asymmetric: When any plane passing through the centre does not divide the body into equal halves, the organism is said to be asymmetric, e.g., sponges. Most of the sponges are asymmetrical.
Radially symmetrical: When any plane passing through the central axis of the body divides the organism into two identical halves, it is called radial symmetry and the organisms possessing it are called radially symmetric. For e.g., some sponges, coelenterates, ctenophores, adult echinoderms.
Bilaterally symmetrical: When the body can be divided into identical left and right halves in only one plane, it is called bilateral symmetry and the animals possessing this type of symmetry are called bilaterally symmetric.

Topic: Biology, Animal Kingdom, NEET
The organism shown in the given diagram is

Options:
A Spirogyra
B Ulothrix
C Oscillatoria
D Volvox

The correct answer is:
Volvox

Solution:
The given figure is of green algae Volvox. The fusion of gametes is of oogamous type.

Topic: Biology, Plant Kingdom, NEET
The organism where the adult shows pentaradial symmetry, while the larval forms shows biradial symmetry is

Options:
A Apis.
B Pleurobrachia.
C Antedon.
D Adamsia.

The correct answer is:
Antedon.

Solution:
Phylum Echinodermata: These animals have an endoskeleton of calcareous ossicles and, hence, the name Echinodermata (Spiny bodied). All are marine with organ-system level of organisation. The adult echinoderms are radially symmetrical but larvae are bilaterally symmetrical. Examples: Asterias (Star fish), Echinus (Sea urchin), Antedon (Sea lily), Cucumaria (Sea cucumber) and Ophiura (Brittle star).

Topic: Biology, Animal Kingdom, NEET
The organisms which are restricted to a narrow range of salinity are known as

Options:
A Salinosomes
B Salinotolerants
C Euryhaline
D Stenohaline

The correct answer is:
Stenohaline

Solution:
An organism that can tolerate and survive in narrow range of salinity is called stenohaline and the organism which can tolerate a wide range of salinity are called as euryhaline.

Topic: Biology, Organisms and Populations, NEET
The organisms which cause diseases in plants and animals are called:

Options:
A Pathogens
B Vectors
C Insects
D Worms

The correct answer is:
Pathogens

Solution:
A wide range of organisms belonging to bacteria, viruses, fungi, protozoans, helminths, etc., could cause diseases in man. Such disease causing organisms are called pathogens.

Topic: Biology, Human Health and Diseases, NEET
The organization created by FOAM is related to

Options:
A Integrated wastewater treatment
B Solid waste management
C Bhopal Gas tragedy
D Terror of Bengal.

The correct answer is:
Integrated wastewater treatment

Solution:
In collaboration with Humbodlt state University, the towns people of Arcata created an integrated wastewater treatment process within a natural ecosystem. The biologist develops a series of six interconnected marshes over 60 hectares of marshland. The marshes now constitute a sanctuary which is looked after by FOAM (Friends of Arcata Marsh.)

Topic: Biology, Environmental Issues, NEET
The orientation of an atomic orbital is governed by:

Options:
A principal quantum number
B azimuthal quantum number
C spin quantum number
D magnetic quantum number

The correct answer is:
magnetic quantum number

Solution:
The orientation of an atomic orbital is governed by the magnetic quantum number.
Related Theory
Magnetic Quantum Number ( $m$ ) specifies the orientation in space of an orbital of a given energy (n) and shape (I).
1. Caution
$n, l, m_l$ specify the particular orbital of interest, and $m_s$ specifies how many electrons can occupy that orbital.

Topic: Chemistry, Structure of Atom, NEET, NEET 2006
The original Darwin's Finches on Galapagos islands was:

Options:
A Seed eater
B Fruit eater
C Cactus eater
D Insect eater

The correct answer is:
Seed eater

Solution:
Darwin in Galapagos islands observed an amazing diversity of creatures. Of particular interest, small black birds later called Darwinâs Finches amazed him. He realised that there were many varieties of finches in the same island. All the varieties, he conjectured, evolved on the island itself. From the original seed-eating features, many other forms with altered beaks arose, enabling them to become insectivorous and vegetarian finches.

Topic: Biology, Evolution, NEET
The oscillation of a body on a smooth horizontal surface is represented by the equation, X=Acos⁡ωt, where X= displacement at time t, ω= frequency of oscillation, a= acceleration at time t and T= time period.
Which one of the following graph shows correctly the variation a with t ?

Options:
A
B
C
D

The correct answer is:

Solution:
The equation of displacement, X=Acosωt then the speed and acceleration will be in terms of amplitude of the wave and angular acceleration,

v=dxdt=Aωsinωt

a=d2xdt2=-Aω2cosωt, so the graph of acceleration and displacement.

Topic: Physics, Oscillations, NEET, NEET 2014
The osmotic expansion of a cell kept in water is chiefly regulated by:

Options:
A Mitochondria
B Vacuoles
C Plastids
D Ribosomes

The correct answer is:
Vacuoles

Solution:
The osmotic expansion of a cell kept in water is chiefly regulated by the cell organelle vacuole is surrounded by the tonoplast layer. A single large organelle constitutes about 20% of cell stores water and macromolecules including ions, sugar, amino acids, proteins and carbohydrates (cell sap) with high osmotic pressure generating turgor pressure.

Topic: Biology, Cell - The Unit of Life, NEET, NEET 2014
The osmotic pressure of 1 M solution of sucrose is 22.4 atm. What will be the osmotic potential of 0.1 M sucrose solution?

Options:
A 22.4 atm
B 2.2 atm
C -2.24 bars
D 0

The correct answer is:
-2.24 bars

Solution:
Osmotic potential is a modern term for osmotic pressure. The osmotic pressure for a solution is positive, but its value is negative for osmotic potential.
Hence, Osmotic pressure = - Osmotic potential.
The osmotic pressure of 1M solution is 22.4 atm, hence for a 0.1M solution it will be 2.24 atm.

Topic: Biology, Transport in Plants, NEET
The osmotic pressure of 0.4% urea solution is 1.66 atm and that of a solution of sugar of 3.42% is 2.46 atm. When equal volumes of both the solutions are mixed then the osmotic pressure of the resultant solution will be?

Options:
A 1.02 atm
B 2.06 atm
C 3.04 atm
D 0.02 atm

The correct answer is:
2.06 atm

Solution:
πf=c12+c22RT
As volume is doubled, concentration is halved
∴πf=c1RT+c2RT2
π1+π22=1.66+2.462

=2.06 atm.

Topic: Chemistry, Solutions, NEET
The osmotic pressure of solution containing 34.2 g of cane sugar (molar mass = 342 g mo l â1 in 1L of solution at 20o C is (Given, R=0.082 L atm K-1 mol-1)

Options:
A 2.40 atm
B 3.6 atm
C 24 atm
D 0.0024 atm

The correct answer is:
2.40 atm

Solution:
π=CRT
π=34.2342×1L×0.082×293=2.40 atm

Topic: Chemistry, Solutions, NEET
The outer and inner pleural membrane is in close contact with

Options:
A Pericardium of heart
B Thoracic lining and lung surface
C Liver hepatocytes
D All of these

The correct answer is:
Thoracic lining and lung surface

Solution:
The two lungs are covered by a double-layered pleura, with pleural fluid between them. It reduces friction on the lung surface. The outer pleural membrane is in close contact with the thoracic lining whereas the inner pleural membrane is in contact with the lung surface.

Topic: Biology, Breathing and Exchange of Gases, NEET
The outer electronic configuration of $\mathrm{Gd}$ (At. No. 64) is:

Options:
A $4 f^5 5 d^4 6 s^1$
B $4 f^{7} 5 d^1 6 s^2$
C $4 f^3 5 d^5 6 s^2$
D $4 f^4 5 d^5 6 s^1$

The correct answer is:
$4 f^{7} 5 d^1 6 s^2$

Solution:
The electronic configuration is $\left[\mathrm{X}_e\right] 4 f^{7} 5 d^1 6 s^2$

Topic: Chemistry, d and f Block Elements, NEET, NEET 2013 (Karnataka)
The outer layer of pollen is made up of:

Options:
A Pollenin
B Sporopollenin
C Pectin
D Cellulose

The correct answer is:
Sporopollenin

Solution:
Pollen grains are generally spherical, measuring about 25â50 micrometers in diameter. They have a prominent two-layered wall. The hard outer layer called the exine is made up of sporopollenin which is one of the most resistant organic material known. It can withstand high temperatures and strong acids and alkali. No enzyme that degrades sporopollenin is known to date.

Topic: Biology, Sexual Reproduction in Flowering Plants, NEET
The outer orbitals of $\mathrm{C}$ in ethene molecule can be considered to be hybridized to give three equivalent $s p^2$ orbitals. The total number of sigma $(\sigma)$ and pi $(\pi)$ bonds in ethene molecule is:

Options:
A 3 sigma ( $\sigma)$ and 2 pi ( $\pi$ ) bonds
B 4 sigma $(\sigma)$ and 1 pi $(\pi)$ bonds
C 5 sigma $(\sigma)$ and 1 pi $(\pi)$ bonds
D 1 sigma $(\sigma)$ and 2 pi ( $\pi$ bonds

The correct answer is:
5 sigma $(\sigma)$ and 1 pi $(\pi)$ bonds

Solution:

Topic: Chemistry, Chemical Bonding and Molecular Structure, NEET, NEET 2013 (Karnataka)
The outer orbitals of C in ethene molecule can be considered to be hybridized to give three equivalent sp2 orbitals. The total number of sigma (σ) and pi (π) bonds in ethene molecule is

Options:
A 3 sigma (σ) and 2 pi (π) bonds
B 4 sigma (σ) and 1 pi (π) bonds
C 5 sigma (σ) and 1 pi (π) bonds
D 1 sigma (σ) and 2 pi (π) bonds

The correct answer is:
5 sigma (σ) and 1 pi (π) bonds

Solution:

Topic: Chemistry, Chemical Bonding and Molecular Structure, NEET
The outermost layer of adrenal cortex, zona glomerulosa is associated with

Options:
A Water and electrolyte balance
B Carbohydrate metabolism
C Steroid and hormone secretion
D Blood pressure

The correct answer is:
Water and electrolyte balance

Solution:
The Adrenal gland is composed of two types of tissues the inner adrenal medulla and the outer adrenal cortex. The cortex can be divided in to Zona Reticularis, Zona Fasciculata and Zona Glomerulosa from inside out. The cortex secretes various hormones commonly known as corticoids. Zona reticularis secretes androgenic hormones also known as sex corticoids which play a role in the growth of axial hair, pubic hair and facial hair during puberty. Glucocorticoids which play a role in carbohydrate metabolism are secreted by the zona fasciculate. Aldosterone, a mineralocorticoid, plays a role in regulation of water and electrolyte balance and is secreted by Zona glomerulosa.

Topic: Biology, Chemical Coordination and Integration, NEET
The outermost layer of endosperm in monocots made up of proteins is called

Options:
A aleurone layer.
B scutellum.
C coleoptile.
D coleorrhizae.

The correct answer is:
aleurone layer.

Solution:
The outermost layer of the endosperm of monocots is called aleurone layer. It consists of enzymatic proteins which helps in the breakdown of stored food and supply it to embryo during the germination of seeds. Ploidy of cells of aleurone layer is 3n.

Topic: Biology, Morphology of Flowering Plants, NEET
The outermost limiting layer of a typical cell of mycoplasma is a

Options:
A cell wall
B cell membrane
C slime layer
D capsule

The correct answer is:
cell membrane

Solution:
Mycoplasma is a prokaryotic cell which is not surrounded by cell wall, thus its outermost limiting layer is cell membrane.

Topic: Biology, Biological Classification, NEET
The output A when all three inputs are first high and then low respectively, be

Options:
A 0,Â 1
B 1,Â 1
C 1, 0
D 0,Â 0

The correct answer is:
1, 0

Solution:
If X=Y=Z=1
âA=1

if X=Y=Z=0

âA=0

Topic: Physics, Semiconductors, NEET
The output from a NAND gate is divided into two in parallel and fed to another NAND gate. The resulting gate is a:

Options:
A AND gate
B NOR gate
C OR gate
D NOT gate

The correct answer is:
AND gate

Solution:
Output is $\mathrm{C}=\overline{A \cdot B}=A \cdot B \rightarrow$ This is AND-gate

Topic: Physics, Semiconductors, NEET, NEET 2013 (Karnataka)
The output of OR gate is 1 :

Options:
A if both inputs are zero
B if either of both inputs are 1
C only if both inputs are 1
D if either input is zero

The correct answer is:
if either of both inputs are 1

Solution:
$$
\text { The truth table of OR gate is: }
$$
$\therefore 1$ means if either or both inputs are 1.

Topic: Physics, Semiconductors, NEET, NEET 2004
The output of the given logic circuit is:

Options:
A AB-
B A-B
C AB+AB¯
D AB-+A-B

The correct answer is:
AB-

Solution:
y= ( A. A.B ¯ ¯ ).( A.B ¯ +B ) ¯
A.A.BÂ¯+(A.B).BÌ
=AâA-+B-
=AB-

Topic: Physics, Semiconductors, NEET
The output of the given logic circuit is

Options:
A A+B
B A+B¯
C A
D B

The correct answer is:
A

Solution:
A+B¯=Y1
A+B¯¯=Y2
Y=Y1+Y2¯=Y1·Y2
Y=A+B·A+B¯
Y=A+BB¯
Y=A

Topic: Physics, Semiconductors, NEET
The output $(X)$ of the logic circuit shown in figure will be

Options:
A $X=\overline{\bar{A}} \cdot \overline{\bar{B}}$
B $X=\overline{A \cdot B}$
C $X=A \cdot B$
D $X=\overline{A+B}$

The correct answer is:
$X=A \cdot B$

Solution:
$X=\overline{\overline{A B}}=A \cdot B$ (i.e., AND gate)
If the output $X$ of NAND gate is connected to the input of NOT gate (made from NAND gate by joining two inputs) from the given figure then we get back an AND gate.

Topic: Physics, Semiconductors, NEET, NEET 2013 (All India)
The output $Y$ for the inputs $A$ and $B$ of the given logic circuit is :

Options:
A $A \cdot B$
B $\bar{A} \cdot \bar{B}$
C $A+B$
D $\bar{A}+\bar{B}$

The correct answer is:
$A+B$

Solution:
$Y=\overline{\bar{A} \bar{B}}=A+B$

Topic: Physics, Semiconductors, NEET, NEET 2024 (Re-NEET)
The output Y of the combination of logic gates shown is equal to

Options:
A A
B A ¯
C A + B
D AB

The correct answer is:
A

Solution:
From boolean algebra we have
Y=âA . (A + B) = A

Topic: Physics, Semiconductors, NEET
The output Y of the combination of logic gates shown is equal to

Options:
A A
B A ¯
C A + B
D AB

The correct answer is:
A

Solution:
From boolean algebra we have

Y = AÂ·A+B

âY= AÂ·A+AÂ·B
âY=âA+ AÂ·B

âY=A1+B

âY=AÂ·1=A

Topic: Physics, Semiconductors, NEET
The output ( $Y$ ) of the given logic gate is similar to the output of an/a

Options:
A NOR gate
B OR gate
C AND gate
D NAND gate

The correct answer is:
AND gate

Solution:
$\begin{aligned} Y_1 & =\overline{A \cdot A} \\ & =\bar{A} \\ Y_2 & =\overline{B+B} \\ & =\bar{B}\end{aligned}$
$\begin{aligned}
Y & =\overline{Y_1+Y_2} \\
& =\overline{\bar{A}+\bar{B}} \\
& =\overline{\bar{A}} \cdot \overline{\bar{B}}
\end{aligned}$
$=A \cdot B$ is similar to output of AND Gate

Topic: Physics, Semiconductors, NEET, NEET 2024
The ovary is half inferior in flowers of

Options:
A cucumber
B cotton
C guava
D peach

The correct answer is:
peach

Solution:
If gynoecium is situated in the center and other parts of the flowers are located on the rim of the thalamus almost at the same level, it is called perigynous. The ovary here is said to be half inferior, i.e., plum rose, peach, etc.

Topic: Biology, Morphology of Flowering Plants, NEET, NEET 2011 (Screening)
The ovary is half inferior in flowers of

Options:
A Peach
B Cucumber
C Cotton
D Guava

The correct answer is:
Peach

Solution:
A half-inferior ovary (also known as âhalf-superiorâ, âsub-inferior,â or âpartially inferior,â) is embedded or surrounded by the receptacle. A flower in which the other floral parts arise from around the ovary is called perigynous. Here ovary is half inferior or half superior. E.g. peach, plum etc.

Topic: Biology, Morphology of Flowering Plants, NEET
The ovary is half inferior in the flowers of

Options:
A Peach
B Cucumber
C Cotton
D Guava

The correct answer is:
Peach

Solution:
In perigynous flower, all the floral whorls are occured at the same level of height on the thalamus so they are called half superior or half inferior. E.g.: Rose, peach & Prunus.
The ovary is half - inferior in flowers of peach.

Topic: Biology, Morphology of Flowering Plants, NEET
The ovary is half inferior in:

Options:
A Mustard
B Sunflower
C Plum
D Brinjal

The correct answer is:
Plum

Solution:
Perigyny: In perigynous flowers, the margin of the thalamus grows upward to forma cup like structure, enclosing the ovary. On the rim of the cup are present all the other floral parts. Such an ovary is said to half inferior (half-superior). E.g. Plum, Rose.

Topic: Biology, Morphology of Flowering Plants, NEET, NEET 2020 (Phase 1)
The ovary is said to be hypogynous in the flowers of

Options:
A Brinjal
B Cucumber
C Peach
D Guava

The correct answer is:
Brinjal

Solution:
The flower of the angiosperm plant can be categorized depending on the arrangement of the whorls around the gynoecium.
Epigynous flowers have the ovary is in the inferior position as the thalamus surrounds the ovary and may even fuse with it. The other whorls develop over the thalamus. This arrangement is shown by guava, cucumber and ray florets of sunflower.
If the ovary position is above the thalamus, that is superior to other whorls, the arrangement is called hypogynous. Mustard, brinjal develop such flowers.
When the gynoecium and other whorls are arranged almost at same level, the flower is called perigynous and ovary position is considered half inferior. Peach plant has such type of flower arrangement.

Topic: Biology, Morphology of Flowering Plants, NEET
The overall rate d[P]dt, for the reaction 2A ⇌ K B; B + C → k f P is given by

Options:
A Kkf[A]2[C]
B K[A][B]
C kf[B][C]
D Kkf[A]2[B][C]

The correct answer is:
Kkf[A]2[C]

Solution:
2A ⇌ K B
B+CâkfP
K=[B][A]2 â¦(i)
d[P]dt=kf[B][C] â¦(ii)
From (i) and (ii),
d[P]dt=Kkf[A]2[C]

Topic: Chemistry, Chemical Kinetics, NEET
The oxidation number of C in sucrose (C12H22O11) is

Options:
A +4
B +3
C +2
D 0

The correct answer is:
0

Solution:
C12xH22+1O11-2
So, 12x+22(+1)+11(−2)=0
or x=0

Topic: Chemistry, Redox Reactions, NEET