datavorous/entrance-exam-dataset huggingface dataset:
The two most important property of malignant tumors are:

Options:
A metastasis and angiogenesis
B metastasis and contact inhibition
C metastasis and apoptosis
D metastasis and controlled division

The correct answer is:
metastasis and angiogenesis

Solution:
Malignant tumors are characterized by the presence of two properties:
Angiogenesis: It refers to the formation of new blood vessels, which ultimately helps in providing the nutrient to the tumors to show metastasis.
Metastasis: This refers to the ability of tumor cell to spread or move from one site to other distant sites through the blood and initiate the formation of tumor and angiogenesis.

Topic: Biology, Human Health and Diseases, NEET
The two plates of a parallel plate capacitor are 4 mm apart. A slab of dielectric constant 3 and thickness 3 mm is introduced between the plates with its faces parallel to them. The distance between the plates is so adjusted that the capacitance of the capacitor becomes 2/3rd of its original value. What is the new distance between the plates?

Options:
A

9 mm

B

21 mm

C

5 mm

D

8 mm

The correct answer is:

8 mm

Solution:
Here, distance between parallel plates d = 4 mm = 0.004 m, K = 3, thickness t = 3 mm = 0.003 m and d 1 =?

∴C= ε 0 A d and C 1 = ε 0 A d 1 −t( 1− 1 K )

since C 1 = 2 3 C (given)
∴ ε 0 A d 1 −t( 1− 1 K ) = 2 3 ε 0 A d 1 d 1 −t( 1− 1 K ) = 2 3d 1 d 1 −0.003( 1− 1 3 ) = 2 3×0.004 1 d 1 −0.003× 2 3 = 1 0.006 1 d 1 −0.002 = 1 0.006 d 1 −0.002=0.006 d 1 =0.006+0.002=0.008 m=8 mm.

Topic: Physics, Electrostatics, NEET
The two polynucleotide chains in DNA are:

Options:
A discontinuous
B antiparallel
C semiconservative
D parallel.

The correct answer is:
antiparallel

Solution:
Watson and Crick through their DNA model has shown that the two strands of DNA are antiparallel. One chain grows in $5^{\prime} \rightarrow 3^{\prime}$ direction and the other chain grows in the $3^{\prime} \rightarrow 5^{\prime}$ direction.
Caution
DNA is not semi conservative, but the replication process is.

Topic: Biology, Molecular Basis of Inheritance, NEET, NEET 2007
The two polypeptides of human insulin are linked together by:

Options:
A Hydrogen bonds
B Phosphodiester bond
C Covalent bond
D Disulphide bridges

The correct answer is:
Disulphide bridges

Solution:
The human insulin has two polypeptide chains A and B linked together by disulphide bridges.

Topic: Biology, Biotechnology and Its Applications, NEET, NEET 2016 (Phase 1)
The two polypeptides of human insulin are linked together by:

Options:
A Hydrogen bonds
B Phosphodiester bond
C Covalent bond
D Disulphide bridges

The correct answer is:
Disulphide bridges

Solution:
The human insulin has two polypeptide chains A and B linked together by disulphide bridges.

Topic: Biology, Biotechnology and Its Applications, NEET
The two surfaces of a biconvex lens has same radii of curvatures. This lens is made of glass of refractive index 1.5 and has a focal length of 10 cm in air. The lens is cut into two equal halves along a plane perpendicular to its principal axis to yield two plano-convex lenses. The two pieces are glued such that the convex surfaces touch each other. If this combination lens is immersed in water (refractive index = 43), its focal length (in cm) is

Options:
A 5 cm
B 10 cm
C 20 cm
D 40 cm

The correct answer is:
40 cm

Solution:
If a lens of focal length f is divided into two equal parts and each has a focal length f′ then
1f=1f′+1f′ , i.e, f′=2f
Now if these parts are put in contact, then resultant focal length of the combination will be
1F=12f+12f,i.e, F=f (initial value)
For this combination,
1F= aμg-11R1-1R2 …………..(i)
Now, if this combination is immersed in liquid, then
1F′= 1μg-11R1-1R2 …..(ii)
F′f=( aμg-1)( 1μg-1)=1.5-1 3243-1
or F′f=0.598-1=0.5×8
∴F'=0.5×8×10=40 cmâ´F'=0.5Ã8Ã10=40 cm

Topic: Physics, Ray Optics, NEET
The two types of ribosomes are

Options:
A

Nucleus	cytoplasm

Free	fixed

B

Endoplasmic reticulum	Nucleus

Fixed	Free

C

Endoplasmic reticulum	Nucleus

Free	Fixed

D

Cytoplasm	Nucleus

Fixed	Free

The correct answer is:

Endoplasmic reticulum	Nucleus

Fixed	Free

Solution:
In eukaryotic cells ribosomes are freely present in the cytoplasm are of 80S types. These ribosomes consist of a smaller subunit of the 40S and larger subunit of 60S. In the endoplasmic reticulum, it will be involved in protein synthesis and thus embedded within. In the nucleus, it is freely present dissociated in the nucleoplasm.

Topic: Biology, Cell - The Unit of Life, NEET
The two-dimensional motion of a particle, described by $\vec{r}=(\hat{i}+2 \hat{j}) A \cos \omega t$ is a/an:
A. parabolic path
B. elliptical path
C. periodic motion
D. simple harmonic motion
Choose the correct answer from the options given below:

Options:
A B, C and D only
B A, B and C only
C A, C and D only
D C and D only

The correct answer is:
C and D only

Solution:
$\vec{r}=(\hat{i}+2 \hat{j}) A \cos \omega t$
$x=A \cos \omega t$
$y=2 A \cos \omega t$
$y=2 x$
The path is straight line.
The motion is SHM and periodic as
$\frac{d r}{d t}=-(\hat{i}+2 \hat{j}) \omega A \sin \omega t$
$\frac{d^2 r}{d t^2}=-(\hat{i}+2 \hat{j}) \omega^2 A \cos \omega t$
$\vec{a}=-\omega^2 \vec{r}$

Topic: Physics, Oscillations, NEET, NEET 2024 (Re-NEET)
The type of cell junctions that helps in preventing leakage of substances is called

Options:
A Adhering junctions
B Gap junctions
C Tight junctions
D Plasmodesmata

The correct answer is:
Tight junctions

Solution:
Three types of cell junctions are found in the epithelium and other tissues. These are called tight, adhering, and gap junctions. Tight junctions help to stop substances from leaking across a tissue. Adhering junctions perform cementing to keep neighbouring cells together. Gap junctions facilitate the cells to communicate with each other by connecting the cytoplasm of adjoining cells, for rapid transfer of ions, small molecules and sometimes big molecules.

Topic: Biology, Structural Organisation in Animals, NEET
The type of chlorophyll present in Phaeophyceae is

Options:
A chlorophyll a and chlorophyll e
B chlorophyll a and chlorophyll c
C chlorophyll a and chlorophyll d
D chlorophyll a and chlorophyll b

The correct answer is:
chlorophyll a and chlorophyll c

Solution:
The major pigments present in the Phaeophyceae are chlorophyll a, c, carotenoids, and xanthophylls.

Topic: Biology, Plant Kingdom, NEET
The type of conservation in which the threatened species are taken out from their natural habitat and placed in special setting where they can be protected and given special care is called

Options:
A Biodiversity conservation
B Semi-conservative method
C Sustainable development
D in-situ conservation

The correct answer is:
Biodiversity conservation

Solution:
The type of conservation in which threatened species are taken out from their natural habitat and placed in special setting where they can be protected and given special care is called ex-situ conservation which is a type of biodiversity conservation.

Topic: Biology, Biodiversity and its Conservation, NEET, NEET 2024
The type of embryo sac discovered by Strassburger in Polygonum plant,

Options:
A Has seven celled seven nucleated structure and is bisporic.
B Has seven celled seven nucleated structure and is monosporic.
C Has seven celled eight nucleated structure and is bisporic.
D Has seven celled eight nucleated structure and is monosporic.

The correct answer is:
Has seven celled eight nucleated structure and is monosporic.

Solution:
The seven celled eight nucleated types of embryo sac are known as polygonum type because it is discovered by Strassburger in Polygonum plant. Polygonum-type embryo sac is the most common type in angiosperms. It develops from single megaspore so it is also known as the monosporic embryo sac.

Topic: Biology, Sexual Reproduction in Flowering Plants, NEET
The type of graph between length of a simple pendulum and time period is -

Options:
A elliptical
B hyperbola
C parabola
D circular

The correct answer is:
parabola

Solution:
Using the formula for time-period of a pendulum
T=2Ïlg
â lâT2
This relation suggests graph between length L and Time Period T will be a parabola.

Topic: Physics, Oscillations, NEET
The type of hybridisation of boron in diborane is

Options:
A sp
B sp2
C sp3
D dsp2

The correct answer is:
sp2

Solution:
Correct Option is : (B)
sp2

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), NEET
The type of hybridization involved in the metal ion of [Ni(H2O)6]2+ complex is

Options:
A d3sp2
B sp3d2
C sp3
D dsp2

The correct answer is:
sp3d2

Solution:

Topic: Chemistry, Coordination Compounds, NEET
The type of isomerism exhibited by pentaamminenitrochromium (III) chloride is

Options:
A Polymerization
B Geometrical
C Optical
D Linkage

The correct answer is:
Linkage

Solution:
Linkage isomerism arises in a coordination compound containing ambidentate ligand.
Cr NH35 NO2Cl2 linkage through N
and
Cr NH35 ONOCl2linkage through O

Topic: Chemistry, Coordination Compounds, NEET
The type of isomerism observed in alkanes is

Options:
A Metamerism
B Chain isomerism
C Position isomerism
D Geometrical isomerism

The correct answer is:
Chain isomerism

Solution:
Alkanes are saturated hydrocarbons without any functional group. Hence, can show chain isomerism only.

Topic: Chemistry, General Organic Chemistry, NEET
The type of isomerism shown by the complex [CoCl2(en)2] is

Options:
A Ionization isomerism
B Coordination isomerism
C Geometrical isomerism
D Linkage isomerism

The correct answer is:
Geometrical isomerism

Solution:
In [CoCl2(en)2] , Coordination number of Co is 6 and this compound has octahedral geometry.
As per given option, here the type of isomerism is geometrical isomerism.
It can not show ionization, coordination and linkage isomerisms as it does not fulfill required conditions for these isomerisms.

Topic: Chemistry, Coordination Compounds, NEET
The type of natural selection in which after the selection of traits by nature, two peak curve form is called:

Options:
A Stabilising or normalising selection
B Directional or progressive selection
C Diversifying or disruptive selection
D Balancing selection

The correct answer is:
Diversifying or disruptive selection

Solution:
The type of natural selection in which nature eliminates the mean character or intermediate value and favour both lower and upper extrimities for selection process is called diversifying or disruptive selection. The selection results in formation of two peak curve.

Topic: Biology, Evolution, NEET
The type of organisms found in the kingdom Protista are:

Options:
A Unicellular nucleated
B Multicellular, enucleated
C Eukaryotes
D Both A and C

The correct answer is:
Both A and C

Solution:
Protists are eukaryotic organisms (having a well-defined nucleus and a nuclear membrane surrounding the nucleus). The members of this kingdom are single-celled organisms who may be autotrophic, heterotrophic or parasitic. Chrysophytes, Euglenoids, Dinoflagellates, Slime moulds and Protozoans all are the members of this kingdom which are unicellular eukaryotic organisms.

Topic: Biology, Biological Classification, NEET
The type of ovule depicted in this diagram is

Options:
A Campylotropous Ovule
B Anatropous Ovule
C Amphitropous Ovule
D Circinotropous Ovule

The correct answer is:
Circinotropous Ovule

Solution:
In circinotropus ovule, the ovule is rotated by 360Â° and it is completed surrounded by funiculus. It is seen in Opuntia. In Campylotropous ovule, the body of ovule curved such that micropyle and chalaza are not present in a straight line. The embryo sac and nucellus both are present in a curved position. In, anatropous ovule the body of the ovule is completely turned at 180Âº angle, due to the unilateral growth of funiculus, (inverted ovule). The chalaza and micropyle lie in a straight line. In amphitropous ovule, embryo sac becomes horseshoe-shaped and micropyle comes close to the hilum.

Topic: Biology, Sexual Reproduction in Flowering Plants, NEET
The type of placentation shown in the given diagram is

Options:
A Axile
B Parietal
C Free central
D Poales, floral

The correct answer is:
Free central

Solution:
When the ovules are borne on the central axis and septa are absent, as in Dianthus and Primrose the placentation is called free central.

Topic: Biology, Morphology of Flowering Plants, NEET
The type of ribosomes found in the cytoplasm of the organism responsible for causing typhoid and sleeping sickness are _____ and ____, respectively

Options:
A 70S and 70S
B 70S and 80S
C 80S and 70S
D 80S and 80S

The correct answer is:
70S and 80S

Solution:
Causative organism of typhoid is a bacterium Salmonella typhimurium. It is a prokaryote. The causative organism of sleeping sickness is Trypanosoma which is a protozoan. It is a eukaryote. Ribosomes are the granular structures composed of RNA and proteins. They are not surrounded by any membrane and are seen as dense particles under the electron microscope. Ribosomes found in cytoplasm of eukaryotic organisms are 80S and those in cytoplasm of prokaryotic organisms are 70S, where S is the coefficient of sedimentation and is a measure of the density and size of the ribosome.

Topic: Biology, Cell - The Unit of Life, NEET
The type of tissue commonly found in the fruit wall of nuts is :

Options:
A Parenchyma
B Collenchyma
C Sclerenchyma
D Sclereid

The correct answer is:
Sclereid

Solution:
In fruit wall of several nuts, various types of sclereid tissues are present. These are called stone cells. These are dead cells with obliterated lumen.

Topic: Biology, Anatomy of Flowering Plants, NEET, NEET 2022 (Phase 2)
The types of attractive forces between a polar molecule and non-polar molecule are

Options:
A dipole-dipole forces
B hydrogen bonds
C dipole-induced dipole forces
D dispersion forces

The correct answer is:
dipole-induced dipole forces

Solution:
It is the type of force between the polar molecule and a non-polar molecule. Dipole of polar molecule induces dipole on the electrically neutral molecule.

Topic: Chemistry, Chemical Bonding and Molecular Structure, NEET
The types of flowers which always produce seeds even in the absence of pollinators are called:

Options:
A Chasmogamous flowers
B Cleistogamous flowers
C Bisexual flowers
D Unisexual flowers

The correct answer is:
Cleistogamous flowers

Solution:
Cleistogamy is a type of automatic self-pollination of certain plants that can propagate by using non-opening, self-pollinating flowers. Especially well known in peanuts, peas, and pansy this behavior is most widespread in the grass family. However, the largest genus of cleistogamous plants is Viola.

Topic: Biology, Sexual Reproduction in Flowering Plants, NEET
The UN Conference of Parties on climate change in the year 2011 was held in:

Options:
A Poland
B South Africa
C Peru
D Qatar

The correct answer is:
South Africa

Solution:
UN Conference of Parties on Climate Change (2011) was held in Durban, South Africa. The Conference of Parties, known as COP, is the decision-making body responsible for monitoring and reviewing the implementation of the United Nations Framework Convention on Climate Change.

Topic: Biology, Biodiversity and its Conservation, NEET, NEET 2015 (Phase 1)
The UN Conference of Parties on climate change in the year 2019 was held in

Options:
A Spain
B Peru
C Qatar
D Poland

The correct answer is:
Spain

Solution:
These are climate change conferences held every year. This is known as COP. This is the decision making body that is responsible for monitoring and reviewing the implementation of united nations framework on climate change. This meeting brings together 197 nations and territories. This started in year 1995. In 2019 it was held in Spain.

Topic: Biology, Environmental Issues, NEET
The UN conference Parties in climate change in the year 2012 was held at:

Options:
A Doha
B Lima
C Warsaw
D Durban

The correct answer is:
Doha

Solution:
The United Nations Climate change conferences are yearly conferences and are known as the Conference of the Parties (COP). The UN Framework Convention on Climate Change (UNFCCC) was held in Doha, Qatar, from 26/11/2012 to 7/12/2012.

Topic: Biology, Biodiversity and its Conservation, NEET, NEET 2015 (Phase 2)
The underground stem of which plant is modified to store food and also acts as an organ of perennation to tide over unfavourable conditions for growth?

Options:
A Gourds
B Bougainvillea
C Colocasia
D Opuntia

The correct answer is:
Colocasia

Solution:
Underground stem of plants like potato, ginger, turmeric, zamikand and Colocasia stores food and helps the plant to survive during unfavourable condition.

Topic: Biology, Morphology of Flowering Plants, NEET
The undigested, unabsorbed substance which enters into the caecum of the large intestine through the ileocecal valve is

Options:
A micelle
B chyle
C feces
D chyme

The correct answer is:
chyme

Solution:
From the small intestine, chyme passes through the ileocecal valve into the cecum of the large intestine. The peristaltic waves move the chyme into the ascending and transverse colons, and together with dehydration, compaction of the chyme occurs by forming faeces.

Topic: Biology, Digestion and Absorption, NEET
The unique characteristic of phylum Annelida is

Options:
A coelom.
B nephridia.
C hermaphrodite.
D alimentary canal is complete.

The correct answer is:
nephridia.

Solution:
The unique characteristic of phylum Annelida is the presence of nephridia. Nephridia are organs which osmoregulation and excretion. Hermaphrodites are animals in which the male, as well as female reproductive organ, is present in the same organism. This feature is seen in members of Phylum Annelida like an earthworm, but it is also seen in members of other phyla, like that of Phylum Echinodermata. Thus, it is not a feature which is unique to Phylum Annelida.

Topic: Biology, Animal Kingdom, NEET
The unique feature of Haldane's hot dilute soup was

Options:
A its molecules did not show any degradation as there was no free oxygen and enzymes.
B it had C, H, and O in gaseous form.
C its temperature was suited to provide environment for formation of first cell.
D it contained enzymes to accelerate reactions.

The correct answer is:
its molecules did not show any degradation as there was no free oxygen and enzymes.

Solution:
According to Haldane, there was a time during the evolution of life when simple organic molecules (monomers) were just formed and they accumulated at the bottom of the sea. He called it hot dilute soup or primitive broth. They were no oxygen available at that time. Also, proteins were not formed yet and there were no enzymes. Hence there was no degradation of molecules.

Topic: Biology, Evolution, NEET
The unique mammalian characteristics are:

Options:
A pinna, monocondylic skull and mammary glands
B hairs, tympanic membrane and mammary glands
C hairs, pinna and mammary glands
D hairs, pinna and indirect development

The correct answer is:
hairs, pinna and mammary glands

Solution:
Class: Mammalia:

They are homoiothermous.

The skin has hairs and glands.

External ears or pinnae are present.

Respiration is by lungs.

Heart is four chambered.

They have mammary glands by which the young ones are nourished.

Sexes are separate and fertilisation is internal. They show direct development.

Topic: Biology, Animal Kingdom, NEET, NEET 2023 (All India)
The unit cell cube length for LiCl ( NaCl type structure) is 5.14Å . Assuming anion cation contact, calculate the ionic radius for chloride ion.

Options:
A 1.815
B 3.63
C 2.75
D 5.14

The correct answer is:
1.815

Solution:
In NaCl type of arrangement anion occupies corner of unit cell and and cation in octahedral void at edge center.
Length of unit cell a=2r-+2r+
Surface diagonal is,
4r-=2a (given α=5.14Å )
r-=2a/4=1.414×5.144=1.815Å

Topic: Chemistry, Solid State, NEET
The unit cell of aluminium is cube with edge length 405 pm. The density of aluminium is 2.70 g cm-3 . The unit cell type of aluminium crystal is

Options:
A fcc
B simple cubic
C bcc
D none of these

The correct answer is:
fcc

Solution:
Z=density×a3×NAM
=(2.70gcm-3)(4.05×10-8cm)36.023×1023mol-126.98mol-1
=4
The unit cell of Al is fcc as Z is 4.

Topic: Chemistry, Solid State, NEET
The unit cell with crystallographic dimensions , a=b≠c is α=β=γ=900

Options:
A Cubic
B Tetragonal
C Monoclinic
D Hexagonal

The correct answer is:
Tetragonal

Solution:
The dimensions of tetragonal geometry are a=b≠c
α=β=γ=900

Topic: Chemistry, Solid State, NEET
The unit of classification containing concrete biological entities is

Options:
A taxon
B species
C category
D order

The correct answer is:
species

Solution:
Species are defined as a group of organisms that can sexually produce fertile offspring. There are other parameters that facilitate the classification of the species based on their DNA sequence, morphology, behavior, etc. These organisms share common characteristics with a common gene pool. They have grouped into species based on their morphological or external similarities and more importantly their ability to interbreed.

Topic: Biology, The Living World, NEET
The unit of permittivity of free space $\varepsilon_0$, is:

Options:
A coulomb/newton-metre
B newton-metre ${ }^2 /$ coulomb $^2$
C coulomb ${ }^2 /$ newton-metre $^2$
D coulomb $^2 /$ (newton-metre) ${ }^2$

The correct answer is:
coulomb ${ }^2 /$ newton-metre $^2$

Solution:
We know that
$$
\begin{aligned}
& F=\frac{1}{4 \pi \varepsilon_0} \frac{q^2}{r^2} \\
& \Rightarrow \quad \varepsilon_0=\frac{1}{4 \pi} \frac{a^2}{\mathrm{Fr} r^2}=\frac{\mathrm{C}^2}{\mathrm{~N}-\mathrm{m}^2} \\
&
\end{aligned}
$$

Topic: Physics, Units and Dimensions, NEET, NEET 2004
The unit of Stefan's constant σ is

Options:
A W m−2 K−1
B W m2 K−4
C W m−2 K−4
D W m−2 K4

The correct answer is:
W m−2 K−4

Solution:
Stefan's law is E=σ( T 4 ) ⇒ σ= E T 4

where, E= Energy Area×Time =Wattm2

σ=Watt-m−2K4=W m−2 K−4

Topic: Physics, Units and Dimensions, NEET
The unit of the rate of a second order reaction

Options:
A time-1
B molÂ L-1time-1
C L mol-1time-1
D L2Â mol-2Â time-1

The correct answer is:
L mol-1time-1

Solution:
dA dt =k [ A ] 2
k= Reaction rate constant
Then unit of second order reaction rate constant
k=− d[ A ] dt × 1 [ A ] 2
Therefore unit of second order reaction is L mol-1time-1.

Topic: Chemistry, Chemical Kinetics, NEET
The unit of thermal conductivity is

Options:
A J m K-1
B J m-1 K-1
C W m K-1
D W m-1 K-1

The correct answer is:
W m-1 K-1

Solution:
∆Q∆t=KA∆T∆l
K=∆Q∆t ∆l∆T1A
∴ Unit of K is W m-1 K-1

Topic: Physics, Units and Dimensions, NEET, NEET 2019 (All India)
The unit to measure productivity is

Options:
A gm-2m-2yr-1
B kcal m-2yr-1
C gm-2yr-2
D kcal m-2 yr-2

The correct answer is:
kcal m-2yr-1

Solution:
The annual rate of biomass production is called productivity. It is measured in terms of kcal m-2yr-1 or gm-2yr-1

Topic: Biology, Ecosystem, NEET
The unpaired electrons in Al and Si are present in 3p orbital. Which electrons will experience more effective nuclear charge from the nucleus?

Options:
A Both experience the same charge
B Al
C Si
D None of them experience any charge

The correct answer is:
Si

Solution:
Correct Option is : (C)
Si

Topic: Chemistry, Structure of Atom, NEET
The upper half of an inclined plane of inclination $\theta$ is perfectly smooth while lower half is rough. A block starting from rest at the top of the plane will again come to rest at the bottom, if the coefficient of friction between the block and lower half of the plane is given by

Options:
A $\mu=\frac{1}{\tan \theta}$
B $\mu=\frac{2}{\tan \theta}$
C $\mu=2 \tan \theta$
D $\mu=\tan \theta$

The correct answer is:
$\mu=2 \tan \theta$

Solution:
The block may be stationary, when
$m g \sin \theta \cdot L=\alpha m g \cos \theta \frac{L}{2}$
$\begin{aligned}
\alpha & =\frac{m g \sin \theta \cdot L}{m g \cos \theta \frac{L}{2}} \\
& =2 \frac{\sin \theta}{\cos \theta}=2 \tan \theta \\
\text {or } \alpha & =2 \tan \theta
\end{aligned}$

Topic: Physics, Laws of Motion, NEET, NEET 2013 (All India)