datavorous/entrance-exam-dataset huggingface dataset:
Ti plasmid is being used as cloning vectors for:

Options:
A Animals
B Plants
C Bacteria
D Both (A) and (B)

The correct answer is:
Plants

Solution:
Agrobacterium tumefaciens, a pathogen of several dicot plants is able to deliver a piece of DNA known as 'T-DNA' to transform normal plant cells into a tumour and direct these tumour cells to produce the chemicals required by the pathogen. T-DNA is the part of Ti- plasmid.

Topic: Biology, Biotechnology - Principles and Processes, NEET
Ti plasmid is found in

Options:
A Escherichia coli
B Bacillus thuringiensis
C Staphylococcus aureus
D Agrobacterium tumefaciens

The correct answer is:
Agrobacterium tumefaciens

Solution:
Ti plasmid of Agrobacterium is natural gene transfer tool used by the bacteria to induce tum or into the host plant. The Ti plasmid is used a vector to transfer the gene of interest into the plant and develop transgenic plant.

Topic: Biology, Biotechnology - Principles and Processes, NEET
Tidal Volume and Expiratory Reserve Volume of an athlete is 500 mL and 1000 mL respectively. What will be his Expiratory Capacity if the Residual Volume is 1200 mL?

Options:
A 1500 mL
B 1700 mL
C 2200 mL
D 2700 mL

The correct answer is:
1500 mL

Solution:
Given- Tidal Volume = 500 ml
Expiratory Reserve Volume = 1000 ml
Expiratory Capacity = TV + ERV = 500 + 1000
= 1500 ml
Expiratory Capacity is 1500 ml

Topic: Biology, Breathing and Exchange of Gases, NEET, NEET 2019 (All India)
Tiger is not a resident, in which one of the following national park?

Options:
A Ranthambhor
B Sunderbans
C Gir
D Jim Corbett

The correct answer is:
Gir

Solution:
Gir National Park (Gujarat) is not concerned with tiger. The animals found in Gir national park are Asiatic lion, panther, striped hyaena, sambar nilgai, chital, 4-horned antelope and chinkara.
Ranthambhor National Park Sunderbans and Jim Corbett National park (Uttarakhand) are tiger reserves.

Topic: Biology, Biodiversity and its Conservation, NEET, NEET 2009 (Screening)
Tiger is not a resident in which one of the following national park ?

Options:
A Sunderbans
B Gir
C Jim Corbett
D Ranthambhor

The correct answer is:
Gir

Solution:
Tiger is not resident in Gir national park. Gir has a large population of marsh crocodile, which is among the 40 species of reptiles and amphibians recorded in the sanctuary. According to official census, Gir has about 300 lions and 300 leopards, sambar and spotted deer (chital), blue bull (nilgai), chousingha, chinkara(Indian gazelle) and wild boar thrive in Gir.

Topic: Biology, Biodiversity and its Conservation, NEET
Time constant of the given circuit is τ. If the battery is replaced by an ac source having voltage V=V0cos⁡ωt, power factor of the circuit will be

Options:
A ωτ
B 11+ωτ2
C 1-ωτ2
D None

The correct answer is:
11+ωτ2

Solution:
For DC LR circuit, time constant is given by,
τ=L/R
For AC LR circuit, power factor is given by,
cos⁡ϕ=RR2+ω2L2=11+ω2L2R2=11+ω2τ2

Topic: Physics, Alternating Current, NEET
Time intervals measured by a clock give the following readings: 1.25 s, 1.24 s, 1.27 s, 1.21 s and 1.28 s. What is the percentage relative error of the observations?

Options:
A 2%
B 4%
C 16%
D 1.6%

The correct answer is:
1.6%

Solution:
First, calculate the mean of observations,

⇒Am=1.25+1.24+1.27+1.21+1.285=1.25 sec,
it means, ∆A1=1.25-1.25 s, ∆A2=1.24-1.25 s,∆A3=1.27-1.25 s,∆A4=1.21-1.25 s & ∆A5=1.28-1.25 s

then calculates the mean of error,

∆Am=0+0.01+0.02+0.04+0.035=0.15

% error ∆AmAm=0.1×1005×1.25=1.6%

Topic: Physics, Mathematics in Physics, NEET, NEET 2020 (Phase 2)
Time period for small oscillations in vertical x-y plane of uniform semi-circular disk of mass m and radius R, about horizontal axis through point O, is equal to

Options:
A 2ππR8g
B 2π3πR8g
C 2π4πRg
D 2ππRg

The correct answer is:
2π3πR8g

Solution:
T=2πImgd
I=mR22
d=4R3π

Topic: Physics, Oscillations, NEET
Time periods of vibration of two bar magnets in sum and difference positions are 4 s and 6 s respectively. The ratio of their magnetic moments M1M2 is

Options:
A 6:4
B 36:16
C 2.6:1
D 1.5:1

The correct answer is:
2.6:1

Solution:
According to sum and difference method
M1M2=T22+T12T22-T12
⇒M1M2=62+4262-42
⇒M1M2=36+1636-16
⇒M1M2=5220=2610=2.61

Topic: Physics, Magnetic Properties of Matter, NEET
Time required to decompose SO2Cl2to half of its initial amount is 60 minutes. If the decomposition is a first order reaction, calculate the rate constant of the reaction.

Options:
A 1.925 × 10–4s–1
B 3.254 × 10–4s–1
C 7.458 × 10–4s–1
D 9.642 × 10–4s–1

The correct answer is:
1.925 × 10–4s–1

Solution:
Correct Option is : (A)
1.925 × 10–4s–1

Topic: Chemistry, Chemical Kinetics, NEET
Time taken by the sunlight to pass through a slab of 4 cm and refractive index 1.5 is _____ s.

Options:
A 2×1010
B 2×10-8
C 2×108
D 2×10-10

The correct answer is:
2×10-10

Solution:
d=4 cm
μ=1.5
μ=cv ⇒v=cμ=3×1081.5=2×108 m s-1
Time t=dv=4×10-22×108=2×10-10 s

Topic: Physics, Ray Optics, NEET
Tissue culture technique can produce infinite number or new plants from a small parental tissue. The economic importance of the technique is in raising:

Options:
A genetically uniform population identical to the original parent.
B homozygous diploid plants.
C new species.
D variants through picking up somaclonal variations

The correct answer is:
genetically uniform population identical to the original parent.

Solution:
The technique to generate whole plant from an explant with in vitro condition on a suitable synthetic medium is called tissue culture. We can produce several plants. Genetic constitution of all plants is same, leading to identical population to the original parent. Disease free plants can be produced in large number.
Related Theory
In Tissue culture, culture of an excised part in an aseptic culture medium to form a callus, in which differentiation of root and shoot buds is induced by providing suitable combination of auxins and cytokinin then the plantlets are transferred to the soil to develop into mature plants. The technique is based on the property of totipotency of plant cell which means that any cell from any part of the plant can be used to generate a whole new plant.

Topic: Biology, Plant - Growth and Development, NEET, NEET 2013 (Karnataka)
To a stationary man, rain appears to be falling at his back at an angle 30o with the vertical. As he starts moving forward with a speed of 0.5 m s-1, he finds that rain falls vertically. The speed of rain with respect to stationary man is

Options:
A 0.5 m s-1
B 1 m s-1
C 32 m s-1
D 13 m s-1

The correct answer is:
1 m s-1

Solution:
For stationary person
For running person
Speed of rain with respect to a stationary man =ν
ν→=ν sin30o i^−ν cos30o j^
Velocity of rain with respect to man,
ν→RM=V→R−V→M
=(ν sin30o i^−ν cos30o j^)−(0.5 i^)
Since V→RM is vertically downward, its x-component will become zero.
∴ ν sin30o−0.5=0
⇒ν=0.5sin30o=1 m s-1

Topic: Physics, Motion In Two Dimensions, NEET
To be evolution of successful, a mutation must occur in

Options:
A Germplasm DNA
B Somatoplasm DNA
C RNA
D Cytoplasm

The correct answer is:
Germplasm DNA

Solution:
The mutations which occur in germplasm DNA are heritable and natural selection becomes active over such mutations.

Topic: Biology, Evolution, NEET
To convert a galvanometer into a voltmeter one should connect a:

Options:
A high resistance in series with galvanometer
B low resistance in series with galvanometer
C high resistance in parallel with galvanometer
D low resistance in parallel with galvanometer

The correct answer is:
high resistance in series with galvanometer

Solution:
To convert a galvanometer into a voltmeter one should connect a high resistance in series with galvanometer

Topic: Physics, Current Electricity, NEET, NEET 2002
To decrease the cut-off wavelength of continuous X -ray by 25%, the potential difference across the X-ray tube

Options:
A must be increased by 1003%
B must be decreased by 20%
C must be increased by 25%
D must be decreased by 25%

The correct answer is:
must be increased by 1003%

Solution:
Î»=hceV,Î»1Î»2=V2V1,Î»2=34Î»1
V2=43V1which is equal to 1003% increase

Topic: Physics, Dual Nature of Matter, NEET
To detect light of wavelength 500 nm, the photodiode must be fabricated from a semiconductor of minimum bandwidth of

Options:
A 1.24 eV
B 0.62Â eV
C 2.48 eV
D 3.2Â eV

The correct answer is:
2.48 eV

Solution:
Minimum bandwidth ∆E
∆E=1240 eV nm500 nm=2.48 eV

Topic: Physics, Semiconductors, NEET
To determine the genotype of a tall plant of F2 generation, Mendel crossed this plant with a dwarf plant of F2 generation. This cross represents a ______.

Options:
A test cross
B back cross
C reciprocal cross
D dihybrid cross

The correct answer is:
test cross

Solution:
A test cross is a process to examine and identify whether the organism is heterozygous or not. In it, the organisms are crossed with the recessive homozygous as it will ensure the expression of the dominant character in heterozygous form for F1 generation enabling us to know the zygosity. The ratio obtained in F1 generation after crossing the heterozygous individual with a recessive homozygous individual is 1:1 .
A test cross is a type of back cross.
The Dihybrid cross is when two pairs of contrasting characters are crossed between homozygous members for those characters.
The reciprocal test is a method to determine the role of the parent in the expression of characteristics. The male and female members are interchanged for a particular set of characters to study the influence of parental gender in expression.

Topic: Biology, Principles of Inheritance and Variation, NEET
To determine the heterozygous condition of an individual, it is crossed with the homozygous recessive counterpart. Such a cross is known as

Options:
A Reciprocal cross
B Dihybrid cross
C Test cross
D Back cross

The correct answer is:
Test cross

Solution:
A test cross is a process to examine and identify whether the organism is heterozygous or not. In it, the organisms are crossed with the recessive homozygous as it will ensure the expression of the dominant character in heterozygous form for F1 generation enabling us to know the zygosity.

Topic: Biology, Principles of Inheritance and Variation, NEET
To determine the type of organic compounds found in a living organism, the living tissue is ground with the help of a mortar and a pestle in

Options:
A Trichloroacetic acid
B Trichloroamino acid
C 2,4 -D
D 2,4,5 -T

The correct answer is:
Trichloroacetic acid

Solution:
To determine the type of organic matter present living tissue is grinded in Trichloroacetic acid, the slurry thus obtained is filtered to obtain acid soluble pool which passes through the filter and acid insoluble pool which is retained . the acid soluble pool contains the micromoleules and the acid insoluble pool contains the macromolecules.
2,4 -D and 2,4,5 -T are auxin based pesticides.

Topic: Chemistry, Biomolecules, NEET
To determine the type of organic compounds found in living organisms, the living tissue is ground in

Options:
A Trichloroacetic acid
B Trichloroamino acid
C Trichlorobenzoic acid
D Trichlorobutyric acid

The correct answer is:
Trichloroacetic acid

Solution:
To determine the type of organic matter present, living tissue is grinded in trichloroacetic acid. The slurry thus obtained is filtered to obtain acid-soluble pool, which passes through the filter, and acid-insoluble pool, which is retained. The acid-soluble pool contains the micromolecules and the acid-insoluble pool contains the macromolecules.

Topic: Chemistry, Biomolecules, NEET
To determine whether F1 hybrid is homozygous or heterozygous for a particular trait________ cross is performed.

Options:
A Monohybrid
B Test
C Back
D Reciprocal

The correct answer is:
Test

Solution:
A test cross is a way to explore the genotype of an organism. Early use of the test cross was as an experimental mating test used to determine what alleles are present in the genotype. An organism's genetic makeup is called its genotype, and it reflects all of the alleles, or forms of the gene, that are carried by the organism. Consequently, a test cross can help determine whether a dominant phenotype is homozygous or heterozygous for a specific allele.

Topic: Biology, Principles of Inheritance and Variation, NEET
To enhance the chances of pollination, which of the following is provided by Amorphophallus to the pollinating agent?

Options:
A floral oils
B pollen grains
C nectar
D safe place to lay eggs

The correct answer is:
safe place to lay eggs

Solution:
Amorphophallus (amorpho - misshapen, phallus - penis) is named so because of the prominent spadix. It has the tallest flower about 6 feet tall. They provide a site for laying eggs for the insects that pollinate it

Topic: Biology, Sexual Reproduction in Flowering Plants, NEET
To ensure that only the desired pollens fall on the stigma in artifical hybridization process :
(a) the female flower buds of plant producing unisexual flower need not be bagged.
(b) there is no need to emasculate unisexual flowers of selected female parent
(c) emasculated flowers are to be bagged immediately after cross pollination
(d) emasculated flowers are to be bagged after removal of anthers
(e) bisexual flowers, showing protogyny are never selected for cross
Choose the correct answer from the options given below :

Options:
A (a), (b) and (c) only
B (b), (c) and (d) only
C (b), (c) and (e) only
D (a), (d) and (e) only

The correct answer is:
(b), (c) and (d) only

Solution:
During the process of artificial pollination in pea plant, emasculation is only needed in Bisexual plant, selected as female parent. After removing stamens from such flower and transferring selected pollens, it needs to be bagged to prevent non-desired pollen to come in contact with this flower.

Topic: Biology, Sexual Reproduction in Flowering Plants, NEET, NEET 2022 (Phase 2)
To equalize the number of electrons in both half-reactions, what is the multiplication factor applied to the oxidation half-reaction?

Options:
A 1
B 2
C 3
D 6

The correct answer is:
6

Solution:
The oxidation half-reaction is multiplied by 6 to equalize the number of electrons in both half-reactions.

Topic: Chemistry, Redox Reactions, NEET
To find out the different types of gametes produced by a pea plant having the genotype AaBb, it should be crossed to a plant with the genotype

Options:
A AABB
B AaBb
C aabb
D aaBB

The correct answer is:
aabb

Solution:
To find out the gamete or the genotype of an unknown individual, scientists perform a test cross. In test cross, the individual in question is crossed with the homozygous recessive parent. Hence, the answer is aabb.

Topic: Biology, Principles of Inheritance and Variation, NEET
To get an output 1 from the circuit shown in the figure, the input must be

Options:
A A=0,B=1,C=0
B A=1,B=0,C=0
C A=1,B=0,C=1
D A=1,B=1,C=0

The correct answer is:
A=1,B=0,C=1

Solution:
Here A+B.C=Y
Output is available if A & C are available.

Topic: Physics, Semiconductors, NEET
To get an output 1 from the circuit shown in the figure, the input must be

Options:
A A=0,Â B=1,Â C=0
B A=1,Â B=0,Â C=0
C A=1, B=0, C=1
D A=1,Â B=1,Â C=0

The correct answer is:
A=1, B=0, C=1

Solution:
The Boolean expression for the given combination is output Y=A+B.C
Hence, A=1,B=0, C=1
or other combination can be A=1,B=1,C=1

Topic: Physics, Semiconductors, NEET
To get an output $Y=1$ from the circuit shown below, the input must be

Options:
A (a)
B (b)
C (c)
D (d)

The correct answer is:
(c)

Solution:
$$
\text { Gate I is OR gate } \mathrm{Y}^{\prime}=\mathrm{A}+\mathrm{B}
$$
Gate II is AND gate $\mathrm{Y}=\mathrm{Y}^{\prime} \cdot \mathrm{C}$ $\therefore \mathrm{A}=1, \mathrm{~B}=0, \mathrm{C}=1$ will give $\mathrm{Y}=1$

Topic: Physics, Semiconductors, NEET, NEET 2010 (Screening)
To get an output y=1 in the given circuit, which of the following input is correct?

Options:
A

A	B	C

1	0	0

B

A	B	C

1	0	1

C

A	B	C

1	1	0

D

A	B	C

0	1	0

The correct answer is:

A	B	C

1	0	1

Solution:
The Boolean expression for output of the given combination is Y=A+B.C
The truth table of the combination is

A	B	C	Y=A+B.C

0	0	0	0

1	0	0	0

0	1	0	0

0	0	1	0

1	1	0	0

0	1	1	1

1	0	1	1

1	1	1	1

Hence, for output, Y=1,A=1,B=0 and C=1 .

Topic: Physics, Semiconductors, NEET
To get maximum current through a resistance of 2.5 Î© , one can use m rows of cells, each row having n cells. The internal resistance of each cell is 0.5 Î© . The values of n and m, if the total number of cells is 45, are

Options:
A m= 3, n=15
B m= 5, n=9
C m= 9, n=5
D m= 15, n=3

The correct answer is:
m= 3, n=15

Solution:
R=2.5 Ω , r=0.5 Ω
no of rows=m, no of columns in each row = n
i=nER+nr/m total cells ⇒mn=45
for max. current; R=nr/m, mR=nr
m=3, n=15

Topic: Physics, Current Electricity, NEET
To get output 1 for the following circuit, the correct choice for the input is:

Options:
A A=0,Â B=1,Â C=0
B A=1,Â B=0,Â C=0
C A=1,Â B=1,Â C=0
D A=1, B=0, C=1

The correct answer is:
A=1, B=0, C=1

Solution:

Topic: Physics, Semiconductors, NEET, NEET 2016 (Phase 1)
To get three images of a single object, one should have two plane mirrors at an angle of

Options:
A 60°
B 90°
C 120°
D 30°

The correct answer is:
90°

Solution:
n=360oθo-1
∴ 3=360oθo-1⇒4θo=360o⇒θo=90o.

Topic: Physics, Ray Optics, NEET
To have practical applications why are cross links required in rubber?

Options:
A Cross links increase the solubility of rubber
B Cross links bind the planar polymer sheets thus increasing its elastomeric properties.
C Cross links reduce the strength of rubber
D Cross links decrease the elasticity of rubber

The correct answer is:
Cross links bind the planar polymer sheets thus increasing its elastomeric properties.

Solution:
Correct Option is : (B)
Cross links bind the planar polymer sheets thus increasing its elastomeric properties.

Topic: Chemistry, Polymers, NEET
To increase the length of grape stalks gibberellins are applied. The mechanism of action of gibberellins exploited in this case is its

Options:
A ability to increase length of apex.
B ability to increase in the length of the axis.
C ability to avoid apical dominance.
D all of these.

The correct answer is:
ability to increase in the length of the axis.

Solution:
Gibberellins are a group of plant growth regulators which promote stalk elongation via increasing the length of the axis. This property is used commercially for plantation purposes.

Topic: Biology, Plant - Growth and Development, NEET
To increase the sugar production in sugarcanes, they are sprayed with

Options:
A IAA.
B Cytokinin.
C Gibberellin.
D Ethylene.

The correct answer is:
Gibberellin.

Solution:
Gibberelin causes stem elongation. It increases the length of the internode. Sugarcane stores carbohydrate as sugar in their stems. Sparying sugarcane crop with gibberellins increases the length of the stem, thus increasing the yield by as much as 20 tonnes per acre.

Topic: Biology, Plant - Growth and Development, NEET
To initiate translation, the mRNA first binds to:

Options:
A The smaller ribosomal sub-unit,
B The larger ribosomal sub-unit
C The whole ribosome
D No such specificity exists.

The correct answer is:
The smaller ribosomal sub-unit,

Solution:
When the small subunit encounters an mRNA, the process of translation of the mRNA to protein begins.

Topic: Biology, Molecular Basis of Inheritance, NEET
To measure the resistance of a galvanometer by half deflection method, a shunt is connected to the galvanometer. The shunt is

Options:
A low resistance connected in parallel
B low resistance connected in series
C high resistance connected in parallel
D high resistance connected in series

The correct answer is:
low resistance connected in parallel

Solution:
Shunt is a low resistance connected in parallel to galvanometer so that most of the current passes through the shunt.

Topic: Physics, Experimental Physics, NEET
To obtain virus - free healthy plants from a diseased one by tissue culture technique, which part/parts of the diseased plant will be taken?

Options:
A Apical meristem only
B Palisade parenchyma
C Both apical and axillary meristems
D Epidermis only

The correct answer is:
Both apical and axillary meristems

Solution:
The meristems are the actively dividing cells that are undifferentiated and lacks the virus. Hence, to obtain virus free plants meristematic region is selected.

Topic: Biology, Strategies for Enhancement in Food Production, NEET, NEET 2014
To produce an instantaneous displacement current of $2 \mathrm{~mA}$ in the space between the parallel plates of a capacitor of capacitance $4 \mu \mathrm{F}$, the rate of change of applied variable potential difference $\left(\frac{d V}{d t}\right)$ must be

Options:
A $200 \mathrm{~V} / \mathrm{s}$
B $400 \mathrm{~V} / \mathrm{s}$
C $800 \mathrm{~V} / \mathrm{s}$
D $500 \mathrm{~V} / \mathrm{s}$

The correct answer is:
$500 \mathrm{~V} / \mathrm{s}$

Solution:
$\begin{aligned} & \text { Displacement current } i_d=c \frac{d V}{d t} \\ & \Rightarrow 2 \times 10^{-3}=4 \times 10^{-6} \times \frac{d V}{d t} \\ & \Rightarrow \frac{2 \times 10^{-3}}{4 \times 10^{-6}}=\frac{d V}{d t} \\ & \Rightarrow \frac{d V}{d t}=500 \mathrm{~V} / \mathrm{s}\end{aligned}$

Topic: Physics, Electromagnetic Waves, NEET, NEET 2023 (Manipur)
To produce insulin via a non-human cell, which of the following would be required to be inserted in the vector's plasmid?

Options:
A a segment of DNA from a human
B a segment of DNA from another bacterium
C a molecule of insulin
D an enzyme

The correct answer is:
a segment of DNA from a human

Solution:
To induce human insulin production in a bacterial cell, the human insulin gene (DNA) must be ligated to the bacterial (example E. coli) plasmid successfully. On successful ligation in the plasmid will enable the expression of the insulin gene and produce human insulin without any demerits.

Topic: Biology, Biotechnology and Its Applications, NEET
To remove colouring matter from pure substances the activated charcoal is used. It works by

Options:
A Bleaching
B Reduction
C Oxidation
D Adsorption

The correct answer is:
Adsorption

Solution:
It has been observed that the surface of a solid has the tendency to attract and retain the molecules of other immiscible phase with which it is brought into contact. These molecules remian only at the surface and do not go deeper into the bulk. This tendency of accumulation of molecular species at the surfacec of a solid it termed adsorption.

Topic: Chemistry, Surface Chemistry, NEET
To see the effect of sex on inheritance, Mendel performed:

Options:
A Test cross
B Outcross
C Reciprocal cross
D Back cross

The correct answer is:
Reciprocal cross

Solution:
The cross designed to determine the role of parental sex in the inheritance pattern is called reciprocal cross.
In it, one cross will be conducted where the male expressing the trait will be crossed with female not expressing the trait. Another cross will be conducted where female will be expressing the trait but male will not. Such crosses were conducted by Mendel to eliminate the effect of sex on inheritance pattern.

Topic: Biology, Principles of Inheritance and Variation, NEET
To stop bleeding, FeCl3 is applied locally because

Options:
A FeCl3 seals the blood vessels
B FeCl3 changes the direction of blood flow
C FeCl3 reacts with blood to form a solid substance which seals the blood vessel
D FeCl3 causes denaturation of proteins present in blood

The correct answer is:
FeCl3 causes denaturation of proteins present in blood

Solution:
To stop bleeding, FeCl3 is applied locally because FeCl3 causes denaturation of proteins present in blood. It is a case of coagulation.

Topic: Chemistry, Biomolecules, NEET
To stop bleeding from cut we use ferric chloride, it is because

Options:
A Fe3+ ion coagulates blood, which is a negatively charged sol
B Fe3+ ion coagulates blood, which is a positively charged sol
C Cl- coagulates blood, which is a positively charged sol
D Cl- ion coagulates blood, which is a negatively charged sol

The correct answer is:
Fe3+ ion coagulates blood, which is a negatively charged sol

Solution:
FeCl3 is a electrolyte give Fe3+ and blood contain negatively colloid so stop bleeding due to coagulation.

Topic: Chemistry, Surface Chemistry, NEET