datavorous/entrance-exam-dataset huggingface dataset:
Ratio of longest wavelengths corresponding to Lyman and Balmer series in hydrogen spectrum is

Options:
A $\frac{5}{27}$
B $\frac{3}{23}$
C $\frac{7}{29}$
D $\frac{9}{31}$

The correct answer is:
$\frac{5}{27}$

Solution:
Wavelength for Lyman series
$$
\lambda_L=\frac{1}{R\left(1-\frac{1}{4}\right)}=\frac{4}{3 R}
$$
and wavelength for Balmer series
$$
\begin{aligned}
& \lambda_B=\frac{1}{R\left(\frac{1}{4}-\frac{1}{9}\right)}=\frac{1}{R\left(\frac{5}{36}\right)}=\frac{36}{5 R} \\
& \therefore \quad \frac{\lambda_L}{\lambda_B}=\frac{4}{3 R} \times \frac{5 R}{36}=\frac{5}{27} \\
& \Rightarrow \quad \lambda_L: \lambda_B=5: 27 \\
&
\end{aligned}
$$

Topic: Physics, Atomic Physics, NEET, NEET 2013 (All India)
Ratio of minimum kinetic energies of two projectiles of same mass is 4 : 1. The ratio of the maximum height attained by them is also 4 : 1. The ratio of their ranges would be

Options:
A 16 : 1
B 4 : 1
C 8 : 1
D 2 : 1

The correct answer is:
4 : 1

Solution:
Minimum kinetic energies are at highest point
12mu12cos2â¡Î¸112mu22cos2â¡Î¸2=41
â u1cosâ¡Î¸1u2cosâ¡Î¸2=2 ......(1)
and ratio of the maximum height
u12sin2â¡Î¸1u22sin2â¡Î¸2=41
or u1sinâ¡Î¸1u2sinâ¡Î¸2=21 ...(2)
from equation no. (1) and (2)
u1sinâ¡Î¸1.u1cosâ¡Î¸1u2sinâ¡Î¸2.u2cosâ¡Î¸2=41
gR12gR22=41
â R1R2=41

Topic: Physics, Motion In Two Dimensions, NEET
Rationalize the given statements and choose the correct option: • Lead(II) chloride reacts with Cl2to give PbCl4. • Lead(IV) chloride is highly unstable towards heat. • Lead is known not to form an iodide, PbI4.

Options:
A The first statement describes a redox reaction where PbCl₂ is oxidized to PbCl₄. The second statement indicates that Lead(IV) chloride is thermally unstable, possibly decomposing upon heating. The third statement is true; Lead does not form a PbI₄ compound.
B The first statement is false as PbCl₂ reacts with Cl₂ to form PbCl₄. The second statement is true; Lead(IV) chloride is known to be highly unstable towards heat. The third statement is true; Lead does not form a PbI₄ compound.
C The first statement is true; PbCl₂ reacts with Cl₂ to form PbCl₄. The second statement is false as Lead(IV) chloride is known to be stable towards heat. The third statement is false; Lead does form a PbI₄ compound.
D The first statement is true; PbCl₂ reacts with Cl₂ to form PbCl₄. The second statement is true; Lead(IV) chloride is known to be highly unstable towards heat. The third statement is true; Lead does not form a PbI₄ compound.

The correct answer is:
The first statement is false as PbCl₂ reacts with Cl₂ to form PbCl₄. The second statement is true; Lead(IV) chloride is known to be highly unstable towards heat. The third statement is true; Lead does not form a PbI₄ compound.

Solution:
Correct Option is : (B)
The first statement is false as PbCl₂ reacts with Cl₂ to form PbCl₄. The second statement is true; Lead(IV) chloride is known to be highly unstable towards heat. The third statement is true; Lead does not form a PbI₄ compound.

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), NEET
Ratna, Himgiri and Pusa Komal are the varieties of:

Options:
A Maize, wheat and cauliflower respectively
B Rice, Maize and wheat respectively
C Rice, wheat and cowpea respectively
D Wheat, rice and cowpea respectively

The correct answer is:
Rice, wheat and cowpea respectively

Solution:
Some crop varieties are developed for disease resistance and better yield by the process of hybridization. Ratna, Himgiri and Pusa Komal are the varieties of rice, wheat and cowpea respectively.

Topic: Biology, Strategies for Enhancement in Food Production, NEET
Ray florets have

Options:
A Superior ovary
B Hypogynous ovary
C Half inferior ovary
D Inferior ovary

The correct answer is:
Inferior ovary

Solution:
Epigyne: In an epigynous flower, the margin of the thalamus grows and completely encloses the ovary. The calyx, corolla, and Androecium arise above the ovary. The ovary, in this case, is described as inferior. E.g. Sunflower, Cucumber.

In sunflower or Helianthus or sunflower, the peripheral or outer, zygomorphic flowers are called ray florets; whereas central or inner, actinomorphic flowers are known as disc florets.

Topic: Biology, Morphology of Flowering Plants, NEET, NEET 2020 (Phase 1)
Reabsorption of water from the distal part of the tubules is facilitated by hormone ___.

Options:
A oestrogen
B Testosterone
C vasopressin
D Atrial natriuretic factor

The correct answer is:
vasopressin

Solution:
Reabsorption of water from the distal part of the tubules is facilitated by hormone vasopressin

Topic: Biology, Excretory Products and their Elimination, NEET
Reaction, 2Br- (aq) + Cl2 (aq) â¶ 2Cl- (aq) + Br2 (aq) , is used for commercial preparation of bromine from its salts. Suppose we have 50 mL of a 0.60 M solution of NaBr. What volume of a 0.050 M solution of Cl2 is needed to react completely with the Br ?

Options:
A V = 500 mL
B V = 400 mL
C V = 200 mL
D V = 300 mL

The correct answer is:
V = 300 mL

Solution:
2Br- + Cl2 â¶ 2Cl- + Br2
Or 2Br- â¶ Br20 + 2e (Valence factor for Br- = 1 )
Cl20 + 2e â¶ 2Cl- (Valence factor for Cl2 = 2 )
Meq. of Cl2 = Meq. of Br-
0.05Ã2ÃV = 50Ã0.6Ã1
V = 300 mL.

Topic: Chemistry, Redox Reactions, NEET
Reaction A + B â C + D follows rate law R = K[A]1/2 [B]1/2 starting with 1 M of A and B. What is time taken for concentration of A to become 0.1 M ? [Given, K = 4.606 x 10-4 s-1]

Options:
A 1000 s
B 1500 s
C 2000 s
D 5000 s

The correct answer is:
5000 s

Solution:
R = K A 1 / 2 B 1 / 2
dx dt = K 1 - x 1 / 2 1 - x 1 / 2
dx dt = K 1 - x
Integrating on both sides
K = 2.303 t log 1 1 - x ,
( â´( 1-x )=0.1âMââatââtimeâât )
â 4.606 Ã 1 0 - 4 = 2.303 t log 1 0.1 = 2.303 t
â 2 Ã 1 0 - 4 = 1 t

or t = 1 0 4 2 = 1 0 0 0 0 2 = 5000 s

Topic: Chemistry, Chemical Kinetics, NEET
Reaction BaO2(s)⇌BaO(s)+O2(g);ΔH=+ve
In equilibrium condition, pressure of O2 depends on

Options:
A increase mass of BaO2
B increase mass of BaO
C increase temperature on equilibrium
D increase mass of BaO2 and BaO both

The correct answer is:
increase temperature on equilibrium

Solution:
Pressure of O2 does not depend on concentration terms of other reactants (because both are in solid state), since this is an endothermic reaction. If the temperature be raised dissociation of BaO2 would occur, more O2 is produced at equilibrium, pressure of O2 increases.

Topic: Chemistry, Chemical Equilibrium, NEET
Reaction between acetone and methylmagnesium chloride followed by hydrolysis will give:

Options:
A Sec. butyl alcohol
B Tert. butyl alcohol
C Isobutyl alcohol
D Isopropyl alcohol

The correct answer is:
Tert. butyl alcohol

Solution:
Acetone on reaction with methyl magnesium bromide gives tertiary alcohol.

In this reaction methyl carbanion attacks on carbonyl compound on the electrophilic site of carbonyl group to form tertiary alcohol.

Topic: Chemistry, Alcohols Phenols and Ethers, NEET, NEET 2020 (Phase 1)
Reaction between benzaldehyde and acetophenone in presence of dilute NaOH is known as

Options:
A Cannizzaro’s reaction
B Cross Cannizzaro’s reaction
C Cross Aldol condensation
D Aldol condensation

The correct answer is:
Cross Aldol condensation

Solution:
Cross aldol condensation reaction:

A few steps take place in this reaction

Step 1: Acid-base reaction occurs between base and alpha hydrogen of acetophenone, and carbanion is formed.

Step 2: In this step, formed carbanion behaves as a nucleophile and attacks carbonyl compound (benzaldehyde) carbon to form beta-hydroxy carbonyl compound.

Step 3: α,β-unsaturated carbonyl compound is formed as a product after heating.

Topic: Chemistry, Aldehydes and Ketones, NEET, NEET 2020 (Phase 1)
Reaction between diethyl cadmium and acetyl chloride lead to the formation of

Options:
A dimethyl ketone
B ethyl methyl ketone
C diethyl ketone
D acetaldehyde

The correct answer is:
ethyl methyl ketone

Solution:
Reaction between diethyl cadmium and acetyl chloride leads to the formation of ethyl methyl ketone.

Topic: Chemistry, Carboxylic Acid Derivatives, NEET
Reaction by which benzaldehyde cannot be prepared?

Options:
A

B

C

D

The correct answer is:

Solution:
(a) This reaction is known as Etard reaction.

(b) This reaction is called Rosenmund reaction.

(c) The above reaction is known as Gattermann-Koch aldehyde synthesis.

(d) Thus, from the reagents given in option (d) benzaldehyde is not obtained.

Topic: Chemistry, Aldehydes and Ketones, NEET, NEET 2013 (All India)
Reaction of a carbonyl compound with dilute NaOH gives 4-methylpent-3-en-2-one. The carbonyl compound is:

Options:
A Acetaldehyde
B Acetone
C Formaldehyde
D Propanal

The correct answer is:
Acetone

Solution:
The structure of the final product is

The compound is an α,β-unsaturated ketone. Such type of products is formed by the aldol condensation reaction. Among the given reagents, acetone can give the given final product on reactions with dilute NaOH.

Topic: Chemistry, Aldehydes and Ketones, NEET
Reaction of a carbonyl compound with one of the following reagents involves nucleophilic addition followed by elimination of water. The reagent is:

Options:
A A Grignard reagent
B Hydrazine in presence of feebly acidic solution
C Hydrocyanic acid
D Sodium hydrogen sulphite

The correct answer is:
Hydrazine in presence of feebly acidic solution

Solution:
Reaction of a carbonyl compound with one of the following reagents involves nucleophilic addition followed by elimination of water.
The reagent is hydrazine in presence of feebly acidic solution.
For example, the reaction between acetone and hydrazine to form hydrazone is shown below.

Topic: Chemistry, Aldehydes and Ketones, NEET, NEET 2015 (Phase 2)
Reaction of cyclohexanone with dimethylamine in the presence of catalytic amount of an acid forms a compound if water during the reaction is continuously removed . The compound formed is generally known as

Options:
A a Sciff's base
B an immine
C an amine
D an enamine

The correct answer is:
an enamine

Solution:

Topic: Chemistry, Amines, NEET
Reaction of $\mathrm{HBr}$ with propene in the presence of peroxide gives:

Options:
A isopropyl bromide
B 3-bromo propane
C Allyl bromide
D $n$-propyl bromide

The correct answer is:
$n$-propyl bromide

Solution:
Reaction of $\mathrm{HBr}$ with propene in the presence of peroxide gives $n$-propyl bromide. This addition reaction is an example of anti-Markownikoffs addition reaction.
Related Theory
Step 1: Peroxide undergoes fission to give free radicals.
$$
\mathrm{R}-\mathrm{O}-\mathrm{O}-\mathrm{R} \longrightarrow 2 \mathrm{R}-\dot{\mathrm{O}}
$$
Step 2: $\mathrm{HBr}$ combines with free radical to form bromine free radical.
$$
R-\dot{O}+\mathrm{HBr} \longrightarrow \mathrm{R}-\mathrm{OH}+\dot{\mathrm{B}}
$$
Step 3: $\dot{B}$ attacks the double bond of the alkene to form a more stable free radical.
Step 4: More stable free radical attacks the $\mathrm{HBr}$.
$$
\begin{aligned}
\mathrm{CH}_3 \dot{\mathrm{C}} \mathrm{CHH}_2 \mathrm{Br}+\mathrm{HBr} \longrightarrow & \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{Br}+\dot{\mathrm{B}} \\
& \text { n-propylbromide }
\end{aligned}
$$
Step 5: $\dot{B} r+\dot{B} r \longrightarrow B r_2$

Topic: Chemistry, Hydrocarbons, NEET, NEET 2004
Reaction of methyl bromide with aqueous sodium hydroxide involves

Options:
A Racemisation
B SN1 mechanism
C Retention of configuration
D SN2 mechanism

The correct answer is:
SN2 mechanism

Solution:
Since, the reaction rate depends upon the concentration of both reactant and nucleophile, it is a SN2 reaction. It involves inversion of configuration.

Topic: Chemistry, General Organic Chemistry, NEET
Reaction of phenol with dil. HNO3 gives

Options:
A p and m -nitrophenols
B o - and p -nitrophenols
C Picric acid
D o - and m -nitrophenols

The correct answer is:
o - and p -nitrophenols

Solution:

Topic: Chemistry, Alcohols Phenols and Ethers, NEET
Reaction of propanamide with ethanolic sodium hydroxide and bromine will give

Options:
A Ethylamine
B Methylamine
C Propylamine
D Aniline

The correct answer is:
Ethylamine

Solution:
Hoffmann bromamide degradation reaction.

Topic: Chemistry, Amines, NEET, NEET 2020 (Phase 2)
Reaction of with RMgX lead to the formation of

Options:
A RCH2CH2OH
B RCHOHCH3
C RCHOHR
D

The correct answer is:
RCH2CH2OH

Solution:

Topic: Chemistry, Alcohols Phenols and Ethers, NEET
Reaction, â Water gas CO + H 2 + H 2 â Cr 2 O 3 - ZnO 673 K, 300 atm. ?
may be used for manufacture of

Options:
A HCHO
B CH3COOH
C HCOOH
D CH3OH

The correct answer is:
CH3OH

Solution:
â Water gas CO + H 2 + H 2 → Cr 2 O 3 - ZnO 673 K, 300 atm CH 3 OH

Topic: Chemistry, Alcohols Phenols and Ethers, NEET
Reactivity of HCHO with the following Grignard reagent in the decreasing order is

Options:
A (4) > (3) > (2) > (1)
B (1) > (2) > (3) > (4)
C (3) > (2) > (1) > (4)
D (2) > (3) > (1) > (4)

The correct answer is:
(2) > (3) > (1) > (4)

Solution:
The reactivity order of Grignard reagent with HCHO is
Benzyl > Allyl > Ph > Vinyl
Hence the correct option is D.

Topic: Chemistry, Aldehydes and Ketones, NEET
Reactivity order of halides for dehydrohalogenation is:

Options:
A R-F $>$ R-Cl $>$ R-Br $>$ R-I
B R-I $>$ R-Br $>$ R-Cl $>$ R-F
C R-I $>$ R-Cl $>$ R-Br $>$ R-F
D R-F $>$ R-I $>$ R- $\mathrm{Br}>$ R-Cl

The correct answer is:
R-I $>$ R-Br $>$ R-Cl $>$ R-F

Solution:
The alkyl halides are very reactive due to highly polarized $\mathrm{R}-\mathrm{X}$ bonds with a large difference in electronegativities of carbon and halogen atoms. Thus, reactivity of $\mathrm{R}-\mathrm{X}$ depends on bond length.More be the bond length, easier for the $\mathrm{R}-\mathrm{X}$ to go for dehydrohalogenation.
Related Theory
Halogens increase in reactivity from the bottom to the top of their Group.

Topic: Chemistry, Haloalkanes and Haloarenes, NEET, NEET 2002
Reactivity order of haloacid HX with ethyl alcohol is?

Options:
A HF>HCl>HBr>HI
B HCl>HBr>HF>HI
C HBr>HCl>HI>HF
D HI>HBr>HCl>HF

The correct answer is:
HI>HBr>HCl>HF

Solution:
Among hydrogen halides, as the size of halide ion increases, its reactivity towards ethyl alcohol also increases.

Thus, the order of reactivity of hydrogen halide is
HI > HBr >HCl>HF

Topic: Chemistry, Alcohols Phenols and Ethers, NEET
Read statements A-D, and select the correct option.
A. Mitosis produced two identical daughter cell.
B. Meiosis introduces variation due to gene exchange.
C. After anaphase, the chromosome has two chromatids.
D. Anaphase I is responsible for the reduction in chromosome number of gametes.

Options:
A All are correct
B A,Â B,Â C are correct
C A, B, D are correct
D C,Â D are correct

The correct answer is:
A, B, D are correct

Solution:
Mitosis is an equational division in which one cell divides to form two identical daughter cells. Meiosis produces genetic variation due to crossing over which occurs during prophase I of meiosis. During anaphase centromere splits and two chromatids are separated and starts moving to opposite poles. During anaphase I, the homologous chromosome moves to opposite poles, hence reduction in the number of chromosome happens.

Topic: Biology, Cell Cycle and Cell Division, NEET
Read the below given statements with respect to three important steps of decomposition: fragmentation, leaching and catabolism. Select the correct option.
(i) Detritivores {e.g., earthworm) breakdown detritus into smaller particles.
(ii) Water soluble inorganic nutrients go down into soil horizon and get precipitated as unavailable salts.
(iii) Decomposers (e.g., bacteria and fungi) secrete digestive enzymes and degrade detritus into simpler inorganic substance.

Leaching	Fragmentation	Catabolism

(a)	(i)	(ii)	(iii)

(b)	(iii)	(ii)	(i)

(c)	(ii)	(i)	(iii)

(d)	(ii)	(iii)	(i)

Options:
A (b)
B (a)
C (c)
D (d)

The correct answer is:
(c)

Solution:
The process of decomposition can be categorised as fragmentation of detritus, leaching and catabolism. Fragmentation of detritus is the process that causes breakdown of detritus into smaller particles. It is primarily due to the action of detritus feeding invertebrates (detritivores, e.g., termites, earthworms, etc.). The detritus gets pulverised when passing through the digestive tracts of animals. Due to fragmentation, the surface area of detritus particles is greatly increased. The extracellular enzymes released by bacteria arid fungi carry out catabolism, i.e., enzymatic conversion of the decomposing detritus to simpler and inorganic substances. Leaching is the process by which dissolved nutrients are moved into lower layers of soil or groundwater to form unavailable salts.

Topic: Biology, Ecosystem, NEET
Read the below statements about the structure of genetic material and identify the correct ones.

I. Adenine and guanine are bases that have a double ring structure; cytosine, thymine and uracil are based with a single ring structure.
II. An adenine nucleotide from DNA is the same as an adenine nucleotide from RNA; DNA adenine pairs with uracil and RNA adenine pairs with thymine.
III. The base pairing that occurs in a double DNA helix and when RNA is synthesised during transcription follows the rule that a purine pairs with a pyrimidine.
IV. The two polynucleotides on a DNA molecule run in opposite directions so that the double helix formed has two strands that are parallel to each other.

Options:
A I, II and III only
B I, II and IV only
C II, III and IV only
D I, III and IV only

The correct answer is:
I, III and IV only

Solution:
Adenine and Guanine are purines which has two-ring structure whereas Thymine, Uracil and cytosine are pyrimidines having single ring structure. The nucleotide of DNA and RNA are not same as the sugar molecule is different. Ribose in RNA and deoxyribose in DNA.

Topic: Biology, Molecular Basis of Inheritance, NEET
Read the characteristics given below of a chordate:

a) two-chambered heart
b) poikilotherms
c) exclusively marine
d) oviparous with direct development
e) separate sexes

Which of the following possess all of the above features?

Options:
A Labeo
B Rana
C Trygon
D Excoetus

The correct answer is:
Excoetus

Solution:
Class Osteichthyes:
It includes both marine and fresh water fishes with bony endoskeleton. Their body is streamlined. Mouth is mostly terminal.. They have four pairs of gills which are covered by an operculum on each side. Skin is covered with cycloid/ctenoid scales. Air bladder is present which regulates buoyancy. Heart is twochambered (one auricle and one ventricle). They are cold-blooded animals. Sexes are separate. Fertilisation is usually external. They are mostly oviparous and development is direct. Examples: Marine – Exocoetus (Flying fish), Hippocampus (Sea horse); Freshwater – Labeo (Rohu), Catla (Katla), Clarias (Magur); Aquarium – Betta (Fighting fish), Pterophyllum (Angel fish).

Topic: Biology, Animal Kingdom, NEET
Read the features given below and select the option for animals which correctly describes the features mentioned:

I. All are exclusively marine, triploblastic, coelomate organism with a water vascular system.

II.A small group of worm-like marine animals with the organ system levels of the organization.

III. The body is covered by a calcareous shell and is unsegmented with a distinct head, muscular foot, and visceral hump.

IV. Triploblastic, pesudocoelomate animals in which alimentary canal is complete with a well developed muscular pharynx.

Options:
A I-Asterias; II-Balanoglossus; III-Ascaris; IV-Ancylostoma
B I-Ascaris; II-Ophiura; III-Pila; IV-Sepia
C I-Ascaris; II-Saccoglossus; III-Sepia; IV-Ophiura
D I-Asterias; II-Balanoglossus; III-Pila; IV-Ascaris

The correct answer is:
I-Asterias; II-Balanoglossus; III-Pila; IV-Ascaris

Solution:
Echinodermata are the exclusively marine, triploblastic, coelomate organisms with a water vascular system (Asterius, ophiura). In Mollusca body is covered by calcareous shell and is unsegmented with a distinct head, muscular foot, and visceral hump (Pila, Sepia). Hemichordates are a small group of worm-like marine animals with organ system level of organization (Balanoglossus, Saccoglossus). Triploblastic, pesudocoelomate animals in which alimentary canal is complete with a well developed muscular pharynx is seen in Aschelmenthis with Ascaris as example.

Topic: Biology, Animal Kingdom, NEET
Read the following (A–D) statements:

(A) Plasma without the clotting factor is called lymph.
(B) The spleen is the graveyard of RBCs.
(C) Eosinophils resist infections and are also associated with allergic reactions.
(D) The universal donor blood group is O+ve.

How many of the above statements are correct?

Options:
A Four
B Three
C Two
D One

The correct answer is:
Two

Solution:
Lymph is blood without RBCs. Plasma without the clotting factors is serum. The universal donor is O negative because it does not have Rh antigen which is present in an O positive individual. This Rh antigen can induce an immune response. Hence, O negative (not O positive) is a universal donor.

Topic: Biology, Body Fluids and Circulation, NEET
Read the following and select the correct option :

A. Carnivora is a/an (i) that involves (ii) and Canidae.
B. Petunia and (iii) belongs to Family (iv).

Options:
A

(i)	(ii)	(iii)	(iv)

order	Panthera	Solanum	Cucurbitaceae

B

(i)	(ii)	(iii)	(iv)

order	Felidae	Datura	Solanaceae

C

(i)	(ii)	(iii)	(iv)

Family	Felidae	Datura	Cucurbitaceae

D

(i)	(ii)	(iii)	(iv)

Family	Panthera	Solanum	Solanaceae

The correct answer is:

(i)	(ii)	(iii)	(iv)

order	Felidae	Datura	Solanaceae

Solution:
Order	Group of closely related families.	Carnivora (involves Felidae and Canidae), Polymoniales (include Convolvulaceae and Solanaceae).

Family	Group of closely related genera.	Felidae (involve Felis and Panthera i.e. all cats), Canidae (involve Canis, Ursus, etc), Solanaceae (involve Solanum, Petunia and Datura).

Topic: Biology, The Living World, NEET
Read the following and select the only true statements about cockroach:

A. Each Malpighian tubule is lined by glandular and ciliated cells.
B. A characteristic mushroom gland is present in the female cockroach in the 6th-7th abdominal segments.
C. Both compound eye consists of about 2000 hexagonal ommatidia.
D. The development of P. americana is paurometabolous through the nymphal stage.

Options:
A A & B
B C & D
C B & C
D A & D

The correct answer is:
A & D

Solution:
A characteristic mushroom gland is present in male cockroach only in the 6th-7th abdominal segments. It functions as an accessory reproductive gland. Both compound eye consists of about 4000 hexagonal ommatidia.

Topic: Biology, Structural Organisation in Animals, NEET
Read the following cell processes. In how many of them are mesosomes involves?

(Respiration, Secretion, DNA replication, Cell wall formation, Resistance to antibiotics, Protection)

Options:
A Five
B Three
C Four
D Six

The correct answer is:
Four

Solution:
In Prokaryotes, the plasma membrane extends into the cytoplasm to form special structure known as mesosomes. These extend into the cell and hence are known as inclusions of the cell. These perform various functions like Cell wall formation, DNA replication, Distribution of DNA to daughter cells, Respiration, Secretion of substances in and out of cells and Increase in surface area of plasma membrane. These organelles are absent in Eukaryotes.

Topic: Biology, Biological Classification, NEET
Read the following characteristics (I-V) and identify the structure to which these features correspond.

I. Cortex is made up of several layers of thin-walled parenchyma cells with intercellular spaces.
II. Endoderm is made up of a single layer of barrel-shaped cells without any intercellular spaces.
III. Few layers of thick-walled parenchymatous cell forms pericycle.
IV. Pith is small or inconspicuous.
V. Conjunctive tissue present, and 2 to 4 xylem and phloem patches.

Options:
A Dicot root
B Dicot stem
C Monocot root
D Monocot stem

The correct answer is:
Dicot root

Solution:
Dicot root differs from monocot root in few features like, in dicot root 2 to 4 xylem and phloem patches are present and pith is small and inconspicuous, whereas in monocot root there are more than six xylem bundle and pith is large. Vascular bundles are radial and the xylem is exarch in both monocot and dicot root.

Topic: Biology, Anatomy of Flowering Plants, NEET