datavorous/entrance-exam-dataset huggingface dataset:
Match List I with List II

List-I	List-II

a	Cyanide process	1	Ultrapure Ge

b	Floatation process	2	Pine oil

c	Electrolytic reduction	3	Extraction of Al

d	Zone refining	4	Extraction of Au

Options:
A a-3;b-1;c-4;d-2
B a-4;b-2;c-3;d-1
C a-3;b-2;c-4;d-1
D a-4;b-1;c-3;d-2

The correct answer is:
a-4;b-2;c-3;d-1

Solution:
Cyanide process is used for Ag & Au zone refining is to get ultrapure Ge, Electrolytic reduction is used for extraction of Al.

Topic: Chemistry, General Principles and Processes of Isolation of Metals, NEET
Match List - I with List - II.

List-I	List-II

(a)	Fe(CN)63-	(i)	5.92 BM

(b)	FeH2O63+	(ii)	0 BM

(c)	[Fe(CN)6]4-	(iii)	4.90 BM

(d)	FeH2O62+	(iv)	1.73 BM

Choose the correct answer from the options given below.

Options:
A (a)-(iv), (b)-(ii), (c)-(i), (d)-(iii)
B (a)-(ii), (b)-(iv), (c)-(iii), (d)-(i)
C (a)-(i), (b)-(iii), (c)-(iv), (d)-(ii)
D (a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)

The correct answer is:
(a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)

Solution:
Fe(CN)63- has Fe3+ central ion d5

Electronic configuration (SFL)

t2geg2,2,10,0

n=1

Magnetic moment:

μ=nn+2 BM

=1(1+2)

=3

=1.73 BM

FeH2O63+: has d5 electrons.

Electronic configuration (WFL)

t2ge1,1,1g1,1

n=5

μ=5(5+2)=35

=5.92 B.M.

Fe(CN)64- has d6 electrons.
Electronic configuration (SFL)

t2g2,2,1eg0,0

n=0

μ=0 B.M.

FeH2O62+ has d6 electron
Electronic configuration: (WFL)

t2g2,2,1eg1,1

n=4

μ=4(4+2)=4.90 B.M.

Topic: Chemistry, Coordination Compounds, NEET, NEET 2021
Match List - I with List - II.

List-I	List-II

(a)	(i)	Hell-Volhard-Zelinsky reaction

(b)	(ii)	Gattermann-Koch reaction

(c)	(iii)	Haloform reaction

(d)	(iv)	Esterification

Choose the correct answer from the options given below.

Options:
A (a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)
B (a)-(iii), (b)-(ii), (c)-(i), (d)-(iv)
C (a)-(i), (b)-(iv), (c)-(iii), (d)-(ii)
D (a)-(ii), (b)-(iii), (c)-(iv), (d)-(i)

The correct answer is:
(a)-(ii), (b)-(iii), (c)-(iv), (d)-(i)

Solution:
a

This reaction is Gattermann- Koch reaction (ii) in which benzaldehye is formed.
b

This reaction is haloform reaction (iii) which is given by methyl ketones and produce haloform as one of the product.
c

This reaction is esterification (iv) reaction which involves the formation of ester by reaction of aldehyde and ketone.
d

This reaction is HVZ reaction (i), which involves alpha halogenation of carboxylic acid.

Topic: Chemistry, Aldehydes and Ketones, NEET, NEET 2021
Match List - I with List - II.

List-I	List-II

(a)	PCl5	(i)	Square pyramidal

(b)	SF6	(ii)	Trigonal planar

(c)	BrF5	(iii)	Octahedral

(d)	BF3	(iv)	Trigonal bipyramidal

Choose the correct answer from the options given below.

Options:
A (a)-(iv), (b)-(iii), (c)-(i), (d)-(ii)
B (a)-(ii), (b)-(iii), (c)-(iv), (d)-(i)
C (a)-(iii), (b)-(i), (c)-(iv), (d)-(ii)
D (a)-(iv), (b)-(iii), (c)-(ii), (d)-(i)

The correct answer is:
(a)-(iv), (b)-(iii), (c)-(i), (d)-(ii)

Solution:

Topic: Chemistry, Chemical Bonding and Molecular Structure, NEET, NEET 2021
Match List I with List II related to digestive system of cockroach.
$\begin{array}{|l|l|r|l|}\hline & \text{List I} & & \text{List II} \\ \hline A. & \text{The structures used for storing of food} & I. & \text{Gizzard} \\ \hline B. & \text{Ring of } 6-8 \text{ blind tubules at junction of foregut and midgut.} & II. & \text{Gastric Caeca} \\ \hline C. & \begin{array}{l} \text{Ring of } 100-150 \text{ yellow coloured thin filaments at junction} \\ \text{of midgut and hindgut.} \end{array} & III. & \text{Malpighian tubules} \\ \hline D. & \text{The structures used for grinding the food.} & IV. & \text{Crop} \\ \hline\end{array}$
Choose the correct answer from the options given below:

Options:
A A-I, B-II, C-III, D-IV
B A-IV, B-III, C-II, D-I
C A-III, B-II, C-IV, D-I
D A-IV, B-II, C-III, D-I

The correct answer is:
A-IV, B-II, C-III, D-I

Solution:
The correct answer is option no. (4) as
$\begin{array}{|l|l|l|}\hline \text{The structure used for griding the food particles} & - & \text{Gizzard} \\ \hline \text{The structure used for storing of food} & - & \text{Crop} \\ \hline \begin{array}{l} \text{Ring of } 6-8 \text{ blind tubules at junction of foregut and midgut which assists} \\ \text{in secretion of digestive juices} \end{array} & - & \text{Gastric Caeca} \\ \hline \begin{array}{l} \text{Ring of } 100-150 \text{ yellow coloured thin filaments at junction of midgut} \\ \text{and hindgut which assists in elimination of nitrogenous wastes} \end{array} & - & \text{Malpighian tubules} \\ \hline\end{array}$

Topic: Biology, Structural Organisation in Animals, NEET, NEET 2024
Match List-I with List-II with respect to methods of Contraception and their respective actions.

List-I
(Biological Molecules)	List-II
(Biological functions)

(a)	Diaphragms	(i)	Inhibit ovulation and Implantation

(b)	Contraceptive Pills	(ii)	Increase phagocytosis of sperm within Uterus

(c)	Intra Uterine Devices	(iii)	Absence of Menstrual cycle and ovulation following parturition

(d)	Lactational Amenorrhea	(iv)	They cover the cervix blocking the entry of sperms

Choose the correct answer from the options given below:

Options:
A (a) - (iv), (b) - (i), (c) - (ii), (d) - (iii)
B (a) - (ii), (b) - (iv), (c) - (i), (d) - (iii)
C (a) - (iii), (b) - (ii), (c) - (i), (d) - (iv)
D (a) - (iv), (b) - (i), (c) - (iii), (d) - (ii)

The correct answer is:
(a) - (iv), (b) - (i), (c) - (ii), (d) - (iii)

Solution:
Diaphragm are dome-shaped rubber plastic covers that have to be fitted on the cervix in the female's vagina to check the entry of sperms into the uterus.

Oral pills are the hormonal tablets are taken orally. These pills contain a combination of synthetic hormones like progesterone and estrogen. These hormones inhibit ovulation and implantation by inhibiting the secretion of FSH and LH from the pituitary gland.

IUDs (Intrauterine Devices) are made of plastic, metal, or a combination of the two and are inserted into the uterus to prevent conception.

IUDs increase phagocytosis of sperms within the uterus and the hormone releasing IUDs make the uterus unsuitable for implantation and the cervix hostile to the sperms.

Lactational amenorrhea is also a natural method of birth control where there is no menstrual cycle and therefore ovulation does not occur during intense lactation following parturition.

Topic: Biology, Reproductive Health, NEET, NEET 2022 (Phase 1)
Match List - I with List.-II.

List-I	List-II

(a)	Cells with active cell division capacity	(i)	Vascular tissues

(b)	Tissue having all cells similar in structure and function	(ii)	Meristematic tissue

(c)	Tissue having different types of cells	(iii)	Sclereids

(d)	Dead cells with highly thickened walls and narrow lumen	(iv)	Simple tissue

Select the correct answer from the options given below.

Options:
A (a)-(ii); (b)-(iv); (c)-(i); (d)-(iii)
B (a)-(iv); (b)-(iii); (c)-(ii); (d)-(i)
C (a)-(i); (b)-(ii); (c)-(iii); (d)-(iv)
D (a)-(iii); (b)-(ii); (c)-(iv); (d)-(i)

The correct answer is:
(a)-(ii); (b)-(iv); (c)-(i); (d)-(iii)

Solution:
List-I	List-II

(a)	Cells with active cell division capacity	(ii)	Meristematic tissue

(b)	Tissue having all cells similar in structure and function	(iv)	Simple tissue

(c)	Tissue having different types of cells	(i)	Vascular tissue

(d)	Dead cells with highly thickened walls and narrow lumen	(iii)	Sclereids

Topic: Biology, Anatomy of Flowering Plants, NEET, NEET 2021
Match List - I with List.-II.

List-I	List-II

(a)	Cristae	(i)	Primary constriction in chromosome

(b)	Thylakoids	(ii)	Disc-shaped sacs in Golgi apparatus

(c)	Centromere	(iii)	Infoldings in mitochondria

(d)	Cisternae	(iv)	Flattened membranous sacs in stroma of plastids

Select the correct answer from the options given below.

Options:
A

(a)	(b)	(c)	(d)

(iv)	(iii)	(ii)	(i)

B

(a)	(b)	(c)	(d)

(iii)	(iv)	(ii)	(i)

C

(a)	(b)	(c)	(d)

(iii)	(iv)	(i)	(ii)

D

(a)	(b)	(c)	(d)

(ii)	(iii)	(iv)	(i)

The correct answer is:

(a)	(b)	(c)	(d)

(iii)	(iv)	(i)	(ii)

Solution:
(a) - (iii). Cristae are the infoldings of the inner membrane of the mitochondria.

(b) - (v). Thylakoids are the flattened sac-like structures present in the stroma or matrix in the chloroplasts. They are the primary site for light-dependent reactions of photosynthesis.

(c) - (i). The centromere is also called the primary constriction of the chromosomes. They are the sites where the spindle fibres bind during metaphase.

(d) - (ii). Cisternae are the sac-like structure of Golgi bodies. There are vesicles and tubules along with cisternae in Golgi bodies.

Cristae	Infoldings in the mitochondria.

Thylakoids	Flattened membranous sacs in stroma of plastid

Centromere	Primary constriction in chromosome

Cisternae	Disc-shaped sacs in Golgi apparatus

Topic: Biology, Cell - The Unit of Life, NEET, NEET 2021
Match List -I with List-Il.

List - I	List - II

(a)	Manganese	(i)	Activates the enzyme catalase

(b)	Magnesium	(ii)	Required for pollen germination

(c)	Boron	(iii)	Activates enzymes of respiration

(d)	Iron	(iv)	Functions in splitting of water during photosynthesis

Choose the correct answer from the options given below:

Options:
A (a) — (iv), (b) — (iii), (c) — (ii), (d) — (i)
B (a) - (iv), (b) - (i), (c) - (ii), (d) - (iii)
C (a) — (iii), (b) — (i), (c) — (ii), (d) — (iv)
D (a) - (iii), (b) - (iv), (c) - (i), (d) - (ii)

The correct answer is:
(a) — (iv), (b) — (iii), (c) — (ii), (d) — (i)

Solution:
List - I	List - II

(a)	Manganese	(iv)

Functions in splitting of water during photosynthesis. During photolysis of water, mediated by PS-II, Mn, Cl, etc. help in breaking the water molecule and release of electron, proton, etc.

(b)	Magnesium	(iii)

Activates enzymes of respiration. The enzyme needed to convert glucose to glucose-6-phosphate needs the co-factor Mg+2.

(c)	Boron	(ii)

Required for pollen germination. The stigmatic surface provides complex sugar solution along with Boron which germinates the pollen on stigma.

(d)	Iron	(i)	Activates the enzyme catalase. Several enzymes like catalase and cytochrome, need cofactors like Fe, for their functioning.

Topic: Biology, Mineral Nutrition, NEET, NEET 2022 (Phase 1)
Match list - I with the list - II.

List-I	List-II

(a)	Bronchioles	(i)	Dense regular connective tissue

(b)	Goblet cell	(ii)	Loose connective tissue

(c)	Tendons	(iii)	Glandular tissue

(d)	Adipose tissue	(Iv)	Ciliated epithelium

Choose the correct answer from the options given below:

Options:
A (a) - (i), (b) - (ii), (c) - (iii), (d) - (iv
B (a) - (ii), (b) - (i), (c) - (iv), (d) - (iii)
C (a) - (iii), (b) - (iv), (c) - (ii), (d) - (i)
D (a) - (iv), (b) - (iii), (c) - (i), (d) - (ii)

The correct answer is:
(a) - (iv), (b) - (iii), (c) - (i), (d) - (ii)

Solution:
The bronchioles are lined by simple columnar to the cuboidal epithelium.

Goblet cells are simple columnar epithelial cells that secrete mucus on the surface of mucous membranes of organs and are glandular in nature.

Tendons and ligaments are made of dense regular connective tissue because they need a strong structure.

Adipose tissues are loose connective tissues that are made up of fat cells called adipose cells or adipocytes.

Topic: Biology, Structural Organisation in Animals, NEET, NEET 2022 (Phase 1)
Match List-I will List-II:
Choose the correct answer from the options given below:

Options:
A A-II, B-III, C-IV, D-I
B A-IV, B-III, C-II, D-I
C A-I, B-II, C-III, D-IV
D A-II, B-III, C-I, D-IV

The correct answer is:
A-II, B-III, C-IV, D-I

Solution:
Correct Match : A - II, B-III, C-IV, D-I

Topic: Chemistry, Practical Chemistry, NEET, NEET 2024 (Re-NEET)
Match List-I with List -II
\begin{array}{|l|l|l|l|}\hline & List-I & & List-II \\\hline A. & Schwann cells & I. & Neurotransmitter \\\hline B. & Synaptic knob & II. & Cerebral cortex \\\hline C. & Bipolar neurons & III. & Myelin sheath \\\hline D. & Multipolar neurons & IV. & Retina \\\hline\end{array}
Choose the correct answer from the options given below:

Options:
A A-III, B-I, C-IV, D-II
B A-I, B-IV, C-II, D-III
C A-IV, B-III, C-II, D-I
D A-II, B-III, C-I, D-IV

The correct answer is:
A-III, B-I, C-IV, D-II

Solution:
The correct answer is option (1) because
- The myelinated nerve fibres are enveloped with Schwann cells, which form a myelin sheath around the axon. So, (A) matches with (III)
- Synaptic knob possess synaptic vesicles containing chemicals called neurotransmitters. So, (B) matches with (I)
- Bipolar neurons have one axon and one dendrite, found in the retina of eye. So, (C) matches with (IV)
- Multipolar neurons have one axon and two or more dendrites, found in the cerebral cortex. So, (D) matches with (II)
Option (2), (3) and (4) are incorrect as they have mismatches for (A), (B), (C) and (D)

Topic: Biology, Neural Control and Coordination, NEET, NEET 2024 (Re-NEET)
Match List-I with List-II:
$\begin{array}{|l|l|r|l|}\hline & \begin{array}{l} \text{List I} \\ \text{Location of Joint} \end{array} & & \begin{array}{l} \text{List II} \\ \text{Type of Joint} \end{array} \\ \hline A. & \begin{array}{l} \text{Joint between humerus and} \\ \text{pectoral girdle} \end{array} & I. & \text{Gliding joint} \\ \hline B. & \text{Knee joint} & II. & \text{Ball and Socket joint} \\ \hline C. & \text{Joint between atlas and axis} & III. & \text{Hinge joint} \\ \hline D & \text{Joint between carpals} & IV. & \text{Pivot joint} \\ \hline \end{array}$
Chose the correct answer from the option given below:

Options:
A A-II, B-III, C-IV, D-I
B A-III, B-II, C-I, D-IV
C A-I, B-IV, C-III, D-II
D A-II, B-I, C-III, D-IV

The correct answer is:
A-II, B-III, C-IV, D-I

Solution:
$\begin{array}{|l|l|l|l|}\hline & \begin{array}{l} \text{List I} \\ \text{Location of Joint} \end{array} & & \begin{array}{l} \text{List II} \\ \text{Type of Joint} \end{array} \\ \hline A. & \begin{array}{l} \text{Joint between humerus and} \\ \text{pectoral girdle} \end{array} & II. & \text{Ball and Socket joint} \\ \hline B. & \text{Knee joint} & III. & \text{Hinge joint} \\ \hline C. & \text{Joint between atlas and axis} & IV. & \text{Pivot joint} \\ \hline D & \text{Joint between carpals} & I. & \text{Gliding joint} \\ \hline \end{array}$
Thus, A-II, B-III, C-IV, D-I is the correct match.

Topic: Biology, Locomotion and Movement, NEET, NEET 2024 (Re-NEET)
Match List-I with List-II:
$\begin{array}{|c|l|c|l|}\hline & \text{List-I} & & \text{List-II} \\ \hline A. & \text{Biodiversity hotspot} & I. & \text{Khasi and Jantia hills in Meghalaya} \\ \hline B. & \text{Sacred groves} & II. & \begin{array}{l} \text{World Summit on Sustainable} \\ \text{Development } 2002 \end{array} \\ \hline C. & \text{Johannesburg, South Africa} & III. & \text{Parthenium} \\ \hline D. & \text{Alien species invasion} & IV. & \text{Western Ghats} \\ \hline \end{array}$
Choose the correct answer from the options given below:

Options:
A A-IV, B-I, C-II, D-III
B A-II, B-III, C-IV, D-I
C A-I, B-IV, C-III, D-II
D A-III, B-I, C-II, D-IV

The correct answer is:
A-IV, B-I, C-II, D-III

Solution:
(1) Biodiversity hotspots are regions with very high levels of species richness and high degree of endemism.
Eg. Western Ghats, Sri Lanka, Indo-Burma and Himalaya
(2) In many cultures, tracts of forest were set aside, and all the trees and wildlife within were venerated and given total protection. Such sacred groves are found in Khasi and Jaintia, Hills in Meghalaya
(3) The world summit on sustainable development held in 2002 in Johannesburg, South Africa.
(4) Parthenium is an alien species

Topic: Biology, Biodiversity and its Conservation, NEET, NEET 2024 (Re-NEET)
Match List-I with List-II.
$\begin{array}{ll|rl} & \text{List-I} & & \begin{array}{l} \text{List-II} \\ \text{(Susceptibility } (\chi))\end{array} \\ \hline A. & \text{Diamagnetic} & I. & \chi=0 \\ B. & \text{Ferromagnetic} & II. & 0 \gt \chi \geq-1 \\ C. & \text{Paramagnetic} & III. & \chi \gt \gt 1 \\ D. & \text{Non-magnetic} & IV. & 0 \lt \chi \lt \varepsilon \text{(a small positive number)} \end{array}$
Choose the correct answer from the options given below

Options:
A A-II, B-I, C-III, D-IV
B A-III, B-II, C-I, D-IV
C A-IV, B-III, C-III, D-I
D A-II, B-III, C-IV, D-I

The correct answer is:
A-II, B-III, C-IV, D-I

Solution:
$\begin{array}{l|rl} \text{(Material)} & & \text{(Susceptibility } (\chi)) \\ \hline \text{Diamagnetic} & (II) & 0 \gt \chi \geq-1 \\ \text{Ferromagnetic} & (III) & \chi \gt \gt 1 \\ \text{Paramagnetic} & (IV) & 0 \lt \chi \lt \varepsilon \\ \text{Non-magnetic} & (I) & \chi=0\end{array}$

Topic: Physics, Magnetic Properties of Matter, NEET, NEET 2024
Match List-I with List-II.
$\begin{array}{|l|l|r|l|}\hline & \begin{array}{l} \text{List-I} \\ \text{Event} \end{array} & & \begin{array}{l} \text{List-II} \\ \text{Stage of Prophase-I (Meiosis-I)} \end{array} \\ \hline A. & \text{Chiasmata formation} & I. & \text{Pachytene} \\ \hline B. & \text{Crossing over} & II. & \text{Diakinesis} \\ \hline C. & \text{Synaptonemal complex formation} & III. & \text{Diplotene} \\ \hline D. & \text{Terminalisation of chiasmata} & IV. & \text{Zygotene} \\ \hline \end{array}$
Choose the correct answer from the options given below :

Options:
A A-III, B-I, C-IV, D-II
B A-II, B-I, C-III, D-IV
C A-III, B-I, C-II, D-IV
D A-II, B-III, C-IV, D-I

The correct answer is:
A-III, B-I, C-IV, D-II

Solution:
Zygotene is the second stage of prophase I during this stage synaptonemal complex formation occur. In pachytene the four chromatids of each bivalent chromosomes becomes distinct and clearly appears as tetrad and in this stage crossing over occurs.
Diplotene is recognised by the dissolution of the synaptonemal complex and the tendency of the recombined homologous chromosomes of the bivalents to separate from each other except at the sites of crossovers. These X-shaped are called chiasmata. Diakinesis is marked by terminalisation of chiasmata.

Topic: Biology, Cell Cycle and Cell Division, NEET, NEET 2024 (Re-NEET)
Match List-I with List-II:
$\begin{array}{|l|l|r|l|}\hline & \text{List-I} & & \text{List-II} \\ \hline A. & \text{Histones} & I. & \text{Loosely packed chromatin} \\ \hline B. & \text{Nucleosome} & II. & \text{Densely packed Chromatin} \\ \hline C. & \text{Euchromatin} & III. & \text{Positively charged basic proteins} \\ \hline D. & \text{Heterochromatin} & IV. & \begin{array}{l} \text{DNA wrapped around histone} \\ \text{octamer} \end{array} \\ \hline\end{array}$
Choose the correct answer from the options given below:

Options:
A A-IV, B-III, C-II, D-I
B A-III, B-I, C-IV, D-II
C A-II, B-III, C-IV, D-I
D A-III, B-IV, C-I, D-I

The correct answer is:
A-III, B-IV, C-I, D-I

Solution:
$\begin{array}{lll} \text{Histones} & \rightarrow & \text{Positively charged basic proteins} \\ \text{Nucleosome} & \rightarrow & \text{DNA wrapped around histone octamer} \\ \text{Euchromatin} & \rightarrow & \text{Loosely packed chromatin} \\ \text{Heterochromatin} & \rightarrow & \text{Densely packed chromatin} \end{array}$
Hence the correct answer is option (4).

Topic: Biology, Molecular Basis of Inheritance, NEET, NEET 2024 (Re-NEET)
Match List-I with List-II:
$\begin{array}{|l|l|r|l|}\hline & \text{List-I} & & \text{List-II} \\ \hline A. & \text{Metacentric chromosome} & I. & \begin{array}{l} \text{Chromosome has a terminal} \\ centromere \end{array} \\ \hline B. & \text{Sub-metacentric chromosome} & II. & \begin{array}{l} \text{Middle centromere forming two equal} \\ \text{arms of chromosome} \end{array} \\ \hline C. & \text{Acrocentric chromosome} & III. & \begin{array}{l} \text{Centromere is slightly away from the} \\ \text{middle of chromosome resulting into} \\ \text{two unequal arms} \end{array} \\ \hline D. & \text{Telocentric chromosome} & IV. & \begin{array}{l} \text{Centromere is situated close to its} \\ \text{end forming one extremely short and} \\ \text{one very long arm} \end{array} \\ \hline \end{array}$
Choose the correct answer from the options given below:

Options:
A A-II, B-I, C-IV, D-III
B A-IV, B-I, C-II, D-III
C A-I, B-II, C-III, D-IV
D A-II, B-III, C-IV, D-I

The correct answer is:
A-II, B-III, C-IV, D-I

Solution:
$\begin{array}{lll} \text{Metacentric chromosomes} & \rightarrow & \begin{array}{l} \text{Middle centromere forming two equal arms of chromosomes} \end{array} \\ \text{Sub-metacentric chromosomes} & \rightarrow & \begin{array}{l} \text{Centromere is slightly away from the middle of chromosomes resulting into two unequal arms.} \end{array} \\ \text{Acrocentric chromosomes} & \rightarrow & \begin{array}{l} \text{Centromere is situated close to its end forming one extremely short and one very long arm.} \end{array} \\ \text{Telocentric chromosomes} & \rightarrow & \text{Chromosome has a terminal centromere} \end{array}$
Hence the correct answer is option (4).

Topic: Biology, Cell - The Unit of Life, NEET, NEET 2024 (Re-NEET)
Match List-I with List-II
$\begin{array}{|l|l|r|l|}\hline & \text{List-I} & & \text{List-II} \\ \hline A. & \text{Migratory flamingoes and resident fish in South American lakes} & I. & \text{Interference competition} \\ \hline B. & \begin{array}{l} \text{Abingdon tortoise became extinct after introduction of goats in their} \\ \text{habitat} \end{array} & II. & \text{Competitive release} \\ \hline C. & \begin{array}{l} \text{Chathamalus expands its distributional range in the absence of} \\ \text{Balanus} \end{array} & III. & \text{Resource Partitioning} \\ \hline D. & \begin{array}{l} \text{Five closely related species of Warblers feeding in different} \\ \text{locations on same tree} \end{array} & IV. & \text{Interspecific competition} \\ \hline \end{array}$
Choose the correct answer from the options given below:

Options:
A A-I, B-IV, C-III, D-II
B A-IV, B-I, C-II, D-III
C A-III, B-1, C-II, D-IV
D A-II, B-IV, C-III, D-I

The correct answer is:
A-IV, B-I, C-II, D-III

Solution:
(1) In some shallow south American lakes, visiting flamingoes and resident fishes compete for their common food i.e., their is interspecific competition.
(2) The Abingdon tortoise in Galapagos Islands become extinct within a decade after goats were introduced on the island, apparently due to the greater browsing efficiency of the goats this is an example of interference competition.
(3) The larger and competitively superior barnacle Balanus dominates the intertidal areas and excludes the smaller barnacle Chathamalus from that zone.
(4) If two species compete for the same resource, they could avoid competition by choosing for example related species of warblers living on the same tree were able to avoid competition and coexist due to behavioural difference in their foraging activities.

Topic: Biology, Organisms and Populations, NEET, NEET 2024 (Re-NEET)
Match List-I with List-II and select the correct answer using codes given below the lists â

List-I (Metal ions)	List- II Magnetic moment (B.M.)

(1)	Cr3+	(A)	35

(2)	Fe2+	(B)	30

(3)	Ni2+	(C)	24

(4)	Mn2+	(D)	15

(E)	8

Options:
A 1-(B),2-(C),3-(E),4-(D)
B 1-(B),2-(C),3-(E),4-(A)
C 1-(D),2-(C),3-(E),4-(A)
D 1-(D),2-(E),3-(C),4-(A)

The correct answer is:
1-(D),2-(C),3-(E),4-(A)

Solution:
The atomic number of Cr=24 , Fe=26 , Mn=25 , Ni=28 .
No of unpaired electrons Cr3+=3, Fe +2 =4, Ni +2 =2, Mn +2 =5.
The magnetic moment is calculated by n(n+2) , where n is number of unpaired electrons.

Topic: Chemistry, d and f Block Elements, NEET