datavorous/entrance-exam-dataset huggingface dataset:
On the basis of crystal field theory, explain why Co(III) forms a paramagnetic octahedral complex with weak field ligands, whereas it forms a diamagnetic octahedral complex with strong field ligands.

Options:
A Weak field ligands cause a higher crystal field splitting, leading to unpaired electrons in Co(III) complexes.
B Weak field ligands result in a lower crystal field splitting, causing Co(III) complexes to be diamagnetic.
C Strong field ligands lead to a higher crystal field splitting, resulting in paired electrons in Co(III) complexes.
D Strong field ligands cause a lower crystal field splitting, making Co(III) complexes paramagnetic.

The correct answer is:
Weak field ligands cause a higher crystal field splitting, leading to unpaired electrons in Co(III) complexes.

Solution:
Correct Option is : (A)
Weak field ligands cause a higher crystal field splitting, leading to unpaired electrons in Co(III) complexes.

Topic: Chemistry, Coordination Compounds, NEET
On the basis of electrical conductivity, which one of the following material has the smallest resistivity?

Options:
A Glass
B Silicon
C Germanium
D Silver

The correct answer is:
Silver

Solution:
Silver is the only metal among the given materials, hence its resistivity will be the least.

Topic: Physics, Current Electricity, NEET, NEET 2023 (Manipur)
On the basis of information available for the reaction.
4 3 Alâ+â O 2 â 2 3 Al 2 O 3 ;ââÎGâ=ââ827âkJ/molâofâ O 2
The minimum emf required to carry out an electrolysis of Al2O3 is:
Given:âOne Faradayâ=â96500âC

Options:
A 2.14 V
B 4.28 V
C 6.42 V
D 8.56 V

The correct answer is:
2.14 V

Solution:
AlâAl3++3eâ
4 3 mol Al≡ 4 3  × 3 mol  e −
≡4 mol  e –
n=4
ÎG=ânFE
â827Ã1000=â4Ã96500ÃE
E=2.14 V

Topic: Chemistry, Electrochemistry, NEET
On the basis of information available from the reaction
$\frac{4}{3} \mathrm{Al}+\mathrm{O}_2 \rightarrow \frac{2}{3} \mathrm{Al}_2 \mathrm{O}_3, \Delta \mathrm{G}=-827 \mathrm{~kJ} \mathrm{mol}^{-1}$
of $\mathrm{O}_2$, the minimum e.m.f required to carry out an electrolysis of $\mathrm{Al}_2 \mathrm{O}_3$ is $(\mathrm{F}=$ $\left.96500 \mathrm{C} \mathrm{mol}^{-1}\right):$

Options:
A $2.14 \mathrm{~V}$
B $4.28 \mathrm{~V}$
C $6.42 \mathrm{~V}$
D $8.56 \mathrm{~V}$

The correct answer is:
$2.14 \mathrm{~V}$

Solution:
For $\mathrm{O}_2, \Delta \mathrm{G}=-n \mathrm{FE}^{\circ}$
$\mathrm{E}^{\circ}=\frac{\Delta \mathrm{G}}{-n \mathrm{~F}}=\frac{-8,27,000}{-2 \times 96,500}=4.28$
Minimum EMF required to carry out electrolysis of $\mathrm{Al}_2 \mathrm{O}_3$
$=\frac{4.28}{2}=2.14 \mathrm{~V}$

Topic: Chemistry, Electrochemistry, NEET, NEET 2003
On the basis of Lanthanoid contraction, explain the following Nature of bonding in La2O3and Lu2O3.

Options:
A La2O3has more ionic character than Lu2O3.
B Lu3O3has more ionic character than La2O3.
C Both La2O3and Lu2O3have similar ionic character.
D La2O3and Lu2O3do not follow ionic bonding.

The correct answer is:
La2O3has more ionic character than Lu2O3.

Solution:
Correct Option is : (A)
La2O3has more ionic character than Lu2O3.

Topic: Chemistry, d and f Block Elements, NEET
On the basis of Lanthanoid contraction, explain the following Radii of 4d and 5d block elements.

Options:
A Radii of 4d block elements are larger than 5d block elements.
B Radii of 5d block elements are larger than 4d block elements.
C Radii of 4d and 5d block elements are similar.
D Radii of both 4d and 5d block elements do not follow any trend.

The correct answer is:
Radii of 4d and 5d block elements are similar.

Solution:
Correct Option is : (C)
Radii of 4d and 5d block elements are similar.

Topic: Chemistry, d and f Block Elements, NEET
On the basis of quantum numbers, which of the following options explain that the sixth period of the periodic table should have 32 elements?

Options:
A In the 6th period, electrons can be filled in only 6s, 4f, 5d, and 6 p subshells i.e.16 orbitals and 32 electrons.
B The sixth period contains elements with atomic numbers ranging from 57 to 88.
C The quantum numbers do not predict the existence of 32 distinct elements in the sixth period.
D The sixth period is the first period to include elements with an f-block.

The correct answer is:
In the 6th period, electrons can be filled in only 6s, 4f, 5d, and 6 p subshells i.e.16 orbitals and 32 electrons.

Solution:
Correct Option is : (A)
In the 6th period, electrons can be filled in only 6s, 4f, 5d, and 6 p subshells i.e.16 orbitals and 32 electrons.

Topic: Chemistry, Classification of Elements and Periodicity in Properties, NEET
On the basis of the following \(E^{\circ}\) values, the strongest oxidizing agent is :-
\(\begin{aligned}
& {\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{4-} \rightarrow\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{3-}+e^{-1}, \mathrm{E}^{\circ}=-0.35 \mathrm{~V}} \\
& \mathrm{Fe}^{2+} \rightarrow \mathrm{Fe}^{3+}+e^{-1} ; \quad \mathrm{E}^{\circ}=-0.77 \mathrm{~V}
\end{aligned}\)

Options:
A $\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{4-}$
B $\mathrm{Fe}^{2+}$
C $\mathrm{Fe}^{3+}$
D $\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{3-}$

The correct answer is:
$\mathrm{Fe}^{3+}$

Solution:
Key Idea :
Oxidised form + ne $e^{-} \rightarrow$ Reduced form
The substances which have lower reduction substances which have higher reduction potential are stronger oxidising agent.
$\begin{array}{l}
{\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{3-}+e^{-}} \rightarrow\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{4-} ; E^{\circ}=0.35 \mathrm{~V} \\
\mathrm{Fe}^{3+}+e^{-} \rightarrow \mathrm{Fe}^{2+} ; E^{\circ}=0.77 \mathrm{~V}
\end{array}$
The reduction potential of $\mathrm{Fe}^{3+} / \mathrm{Fe}^{2+}$ is higher, hence $\mathrm{Fe}^{3+}$ is strongest oxidising agent.

Topic: Chemistry, Environmental Chemistry, NEET, NEET 2008 (Screening)
On the basis of the information available from the reaction,
4/3Al+ O 2 â2/3 Al 2 O 3 ;âÎG=â827 kJmol â1 , the minimum e.m.f. required to carry out electrolysis of Al2O3 is (F=96500 Cmol-1)

Options:
A 2.14 V
B 4.28 V
C 6.42 V
D 8.56 V

The correct answer is:
2.14 V

Solution:
ΔG=-nFE°
E°=ΔG-nF--827000-4×96500=2.14

Topic: Chemistry, Electrochemistry, NEET
On the diodes shown in the following diagrams, which one is reverse biased:

Options:
A

B

C

D

The correct answer is:

Solution:
A diode is at reverse biased if $\mathrm{P}-$ side of semiconductor of $p-n$ junction is at low potential w.r.t. n-type semiconductor of $p-n$ junction.

Topic: Physics, Semiconductors, NEET, NEET 2004
On the reaction of an alkyne with a reagent, the above given compound is formed. Which is the correct pair of an alkyne and a reagent from the following?

Options:
A
B
C
D

The correct answer is:

Solution:
The given carbonyl compound can be produced by oxymercuration-demercuration reaction of alkynes. It is basically the markovnikov addition of water to alkyne. The product enol tautomerises to give the given ketone as the final product.

Topic: Chemistry, Hydrocarbons, NEET
On translation, mRNA produces a polypeptide chain, which contains 50 amino acids. If 26th codon of mRNA UUU mutated and changed to UUC, then the polypeptide chain will be

Options:
A Completely changed
B Partially changed
C Not changed
D Only one amino acid changed

The correct answer is:
Not changed

Solution:
Codon UUU and UUC both codes for amino acid phenylalanine, hence polypeptide chain will not change.

Topic: Biology, Molecular Basis of Inheritance, NEET
On what ground can you say that scandium (Z = 21) is a transition element but zinc (Z = 30) is not?

Options:
A Zinc exhibits variable oxidation states in its compounds.
B because Scandium has an incompletely filled d-orbital in its ground state but zinc has a completely filled d-orbital(d10) in both ground and excited states
C Scandium forms colourful compounds due to d-d electronic transitions
D Zinc is paramagnetic in nature.

The correct answer is:
because Scandium has an incompletely filled d-orbital in its ground state but zinc has a completely filled d-orbital(d10) in both ground and excited states

Solution:
Correct Option is : (B)
because Scandium has an incompletely filled d-orbital in its ground state but zinc has a completely filled d-orbital(d10) in both ground and excited states

Topic: Chemistry, d and f Block Elements, NEET
On what grounds can you say that scandium(Z=21) is a transition element but zinc(Z=30) is not one?

Options:
A

Incompletely filled 3d orbitals in Sc

B

Coloured compounds

C

Variable oxidation state

D None of the above

The correct answer is:

Incompletely filled 3d orbitals in Sc

Solution:
Scandium is one of the two elements in the first transition metal period which has only one oxidation state (zinc is the other, with an oxidation state of +2).

On the basis of incompletely filled 3d orbitals, scandium (Z=21) has incompletely filled d-orbitals(3 d 1 ) in its ground state, so it is regarded as a transition element.

On the other hand, zinc(Z=30) has completely filled d-orbitals (3 d 10 ) in its ground state.

Topic: Chemistry, d and f Block Elements, NEET
On which of the following is the artificial system of classification based?

Options:
A Habit, colour, number and shape of leaves
B Androecium structure
C Cytological information such as chromosome number, structure
D Both A and B

The correct answer is:
Both A and B

Solution:
Artificial system of classification based on the gross morphological and sexual characteristics and it gave equal weightage to these for classification. They were able to separate closely related species.

Topic: Biology, Plant Kingdom, NEET
On which of the following properties affect the coagulating power of an ion?

Options:
A Both magnitude and sign of the charge on the ion
B Size of the ion alone
C The magnitude of the charge on the ion alone
D The sign of charge on the ion alone

The correct answer is:
Both magnitude and sign of the charge on the ion

Solution:
Coagulation of colloidal solution by using an electrolyte depends on the charge present (positive or negative) on colloidal particles as well as on its size.
Coagulating power of an electrolyte depends on the magnitude of charge present on effective ion of electrolyte.
Coagulation Power ∝ magnitude of charge

Topic: Chemistry, Surface Chemistry, NEET
On which of the following properties, does the coagulating power of an ion depend?

Options:
A Both the magnitude and sign of the charge on the ion.
B Size of the ion alone.
C The magnitude of the charge on the ion alone.
D The sign of charge on the ion alone.

The correct answer is:
Both the magnitude and sign of the charge on the ion.

Solution:
According to Hardy Schulze rule, the coagulating power of an ion depends on both the magnitude and sign of the charge of the ion.

Topic: Chemistry, Surface Chemistry, NEET, NEET 2018
On which principle does sonometer work?

Options:
A Hooke's law
B Elasticity
C Resonance
D Newton's law

The correct answer is:
Resonance

Solution:
Sonometer works on the principle of resonance. At resonance the wire of sonometer vibrate with maximum amplitude.

Topic: Physics, Waves and Sound, NEET
On which quantity the escape velocity for earth does not depend on

Options:
A mass of the earth
B mass of the projectile
C point of projection relative to the earth
D gravitational constant

The correct answer is:
mass of the projectile

Solution:
Potential energy = kinetic energy

+GMemR=12mve2

Where $m$ is mass of projectile, Me is mass of earth, G is gravitational constant, R is radius.

ve=2GMeRe

The above formula shows that escape velocity is independent of the mass of the projectile.

Topic: Physics, Gravitation, NEET
Once the undigested and unabsorbed substances enter the caecum, their backflow is prevented by-

Options:
A Pyloric sphincter
B Sphincter of Oddi
C Ileo-caecal valve
D Gastro-oesophageal sphincter

The correct answer is:
Ileo-caecal valve

Solution:
The Ileum opens into the large intestine, which has caecum, colon and rectum. The caecum is a small blind sac which hosts some symbiotic micro-organisms. The entry of ileum and caecum is guarded by ileo-caecal valve.

The undigested, unabsorbed substances called faeces enters into the caecum through this ileo-caecal valve. This valve prevents the back flow of the faecal matter. It is temporarily stored in the rectum till defaecation.

Topic: Biology, Digestion and Absorption, NEET, NEET 2023 (All India)
One advantage of cleistogamy is:

Options:
A It leads to greater genetic diversity
B Seed dispersal is more efficient and widespread
C Seed set is not dependent on pollinators
D Each visit of a pollinator results in transfer of hundreds of pollen grains

The correct answer is:
Seed set is not dependent on pollinators

Solution:
Flower which never opens up are called as cleistogamous flower and the phenomenon is called as cleistogamy, such flowers are invariably self pollinated thus they do not require any pollinating agent. Thus assured seed formation is there.

Topic: Biology, Sexual Reproduction in Flowering Plants, NEET
One advantage of cleistogamy is

Options:
A It leads to greater genetic diversity
B Seed dispersal is more efficient and widespread
C Seed set is not dependent on pollinators
D Each visit of a pollinator results in transfer of hundreds of pollen grains

The correct answer is:
Seed set is not dependent on pollinators

Solution:
Cleistogamy is the phenomenon, where flowers never open and in them, only self-pollination occurs within the bud (unopened flower). It has the advantage that the seed set is not dependent on pollinators.

Topic: Biology, Sexual Reproduction in Flowering Plants, NEET
One among the following is an incorrect statement-

Options:
A Molality of a solution is dependent on the temperature
B Molarity of a solution is dependent on the temperature
C Normality of 0.5 M aqueous solution of H 2 C 2 O 4 ⋅2 H 2 O is 1 N
D Molality of a solution relates moles of solute and mass of solvent

The correct answer is:
Molality of a solution is dependent on the temperature

Solution:
Molality is moles of solute dissolve per kg of solvent (mass of solvent is temperature independent)

Topic: Chemistry, Some Basic Concepts of Chemistry, NEET
One atomic mass is equal to

Options:
A 1.66×10-27 g
B 1.66×10-24 g
C 1.66×10-23 g
D 1.66×10-25 g

The correct answer is:
1.66×10-24 g

Solution:
1 amu=1.66057×10-27 kg
=1.66057×10-24 g

Topic: Chemistry, Some Basic Concepts of Chemistry, NEET
One can distinguish a leaflet from a leaf by the absence of

Options:
A Midrib
B Petiole
C Axillary bud
D Venation

The correct answer is:
Axillary bud

Solution:
Axillary bud develops only at the axil of a simple leaf and not from the axil of leaflets in a compound leaf.

Topic: Biology, Morphology of Flowering Plants, NEET
One coolie takes 1 minute to raise a suitcase through a height of $2 \mathrm{~m}$ but the second coolie takes $30 \mathrm{~s}$ to raise the same suitcase to the same height. The power two coolies are in the ratio

Options:
A $1: 3$
B $2: 1$
C $3: 1$
D $1: 2$

The correct answer is:
$1: 2$

Solution:
We know that
$$
\text { Power }=\frac{\text { Work done }}{\text { Time }}
$$
Work done $=m g h$ is same in both the case
$$
\therefore \frac{\mathrm{P}_1}{\mathrm{P}_2}=\frac{f_2}{f_1}=\frac{30 \mathrm{sec}}{1 \mathrm{~min}}=\frac{1}{2}
$$

Topic: Physics, Work Power Energy, NEET, NEET 2013 (Karnataka)
One desires to prepare a positively charged silver iodide sol. This can be achieved by

Options:
A Adding a little AgNO3 solution to KI solution in slight excess
B Adding a little KI solution to AgNO3 solution in slight excess
C Mixing equal volumes of equimolar solutions of AgNO3 and KI
D None of these

The correct answer is:
Adding a little KI solution to AgNO3 solution in slight excess

Solution:
KI + AgNO3 â AgI + KNO3

AgNO3 â Ag+ + NO3-

AgI + Ag+ â [AgI].Ag+

Topic: Chemistry, Surface Chemistry, NEET
One E. coli bacterium contains a hybrid DNA with one heavy N15 strand and one light N14 strand. It was allowed to replicate for 3 hours in a medium containing N15. What proportion of E.coli which will neither float nor sink in the test tube on ultra-centrifugation with CsCl?

Options:
A one out of 28
B one out of 29
C one out of 210
D one out of 27

The correct answer is:
one out of 29

Solution:
E. coli divides in 20 minutes. In three hours it will divide 18020=9 times. After 9 divisions, the number of cells will be 29 . E.coli which will neither float nor sink in the test tube on ultracentrifugation with CsCl will have one heavy N15 strand and one light N14 strand. One E.coli with hybrid DNA will divide to form one E.coli with hybrid DNA and one E.coli with DNA with both N15 strands. Thus, the proportion of E.coli with hybrid DNA is 12 . When it divides for the second time, the proportion of E.coli with hybrid DNA is 14. Thus, it can be noted that in this example, the proportion of E.coli with hybrid DNA can be represented as 12n where n is the number of divisions

Topic: Biology, Molecular Basis of Inheritance, NEET
One end of a long metallic wire of length L is tied to the ceiling. The other end is tied to a massless spring of spring constant k. A mass m hangs freely from the free end of the spring. The area of cross-section and Youngâs modulus of the wire are A and Y respectively. If the mass is slightly pulled down and released, it will oscillate with a time period T equal to

Options:
A 2π mk1/2

B 2ÏmYA+kLYAk
C 2πmYAkL12

D 2πmLYA12

The correct answer is:
2πmYA+kLYAk

Solution:
Equivalent force constant for a wire is given by k=YAL. Because in case of a wire, F=YAL∆L and in case of spring, F=k∆x. Comparing these two, we find k of wire =YAL

keq=k1k2k1+k2=YALkYAL+k=YAkYA+Lk
∴T=2πmkeq=2πmYA+LkYAk

Topic: Physics, Oscillations, NEET
One end of a long metallic wire of length L is tied to the ceiling. The other end is tied to massless spring of spring constant K. A mass m hangs freely from the free end of the spring. The area of cross-section and Young's modulus of the wire are A and Y respectively. If the mass is slightly pulled down and released, it will oscillate with a time period T equal to

Options:
A 2ÏmK
B 2πYA+KLmYAK12
C 2ÏmYAKL
D 2ÏmLYA

The correct answer is:
2πYA+KLmYAK12

Solution:
The wire may be treated as a spring for which force constant
k1=ForceExtension=YAL âµ Y=FAÃLÎL
Spring constant of the spring k2=K
Hence spring constant of the combination (series)
keq=k1k2k1+k2=YALKYAL+K=YAKYA+KL
âµ Time period T=2Ïmk=2ÏYA+KLmYAK12

Topic: Physics, Oscillations, NEET
One end of a spring of force constant k is fixed to a vertical wall and the other to body of mass m resting on a smooth horizontal surface. There is another wall at a distance x0 from the body. The spring is then compressed by 2x0 and released. The time taken to strike the wall first time is

Options:
A Ï6mk
B mk
C 2π3mk
D Ï4mk

The correct answer is:
2π3mk

Solution:
In diagram B denotes the mean position.
Let, T be Time period of oscillation of the spring-mass system
Time from B to C, tBC can be given by
BC=ABsinâ¡2ÏTtBC
BCAB=x02x0=12
tBC=T12
The total time from A to C
tAC=tAB+tBC=T4+T12=T3
tAC=2Ï3mk

Topic: Physics, Oscillations, NEET
One end of a string of length l is connected to a particle of mass m and the other to a small peg on a smooth horizontal table. If the particle moves in a circle with speed v the net force on the particle (directed towards the center) is :

Options:
A $T$
B $T-\frac{m{{v}^{2}}}{l}$
C $T+\frac{m{{v}^{2}}}{l}$
D $0$

The correct answer is:
$T$

Solution:
Correct Option is : (A)
$T$

Topic: Chemistry, Laws of Motion, NEET
One end of a thermally insulated rod is kept at a temperature T1 and other at T2. The rod is composed of two sections of lengths l1 and l2 and thermal conductivities K1 and K2 respectively. The temperature at the interface of the two sections is

Options:
A (K2l2T1+K1l1T2)(K1l1+K2l2)
B (K2l1T1+K1l2T2)(K2l1+K1l2)
C (K1l2T1+K2l1T2)(K1l2+K2l1)
D (K1l1T1+K2l2T2)(K1l1+K2l2)

The correct answer is:
(K1l2T1+K2l1T2)(K1l2+K2l1)

Solution:
Let temperature at the interface is T.
For part AB,
Q1t∝T1-TK1l1
For part BC,
Q2t∝T-T2K2l2
At equilibrium, Q1t=Q2t
∴ T1-TK1l1=T-T2K2l2
⇒ T=T1K1l2+T2K2l1K1l2+K2l1

Topic: Physics, Thermal Properties of Matter, NEET
One end of a V-tube containing mercury is connected to a suction pump and the other end to atmosphere. The two arms of the tube are inclined to horizontal at an angle of 45° each. A small pressure difference is created between two columns when the suction pump is removed. Will the column of mercury in V-tube execute simple harmonic motion? Neglect capillary and viscous forces.Find the time period of oscillation.

Options:
A $2\pi \sqrt{\frac{l}{g}}$
B $2\pi \sqrt{\frac{2l}{g}}$
C $2\pi \sqrt{\frac{l}{2g}}$
D $2\pi \sqrt{\frac{l}{3g}}$

The correct answer is:
$2\pi \sqrt{\frac{l}{g}}$

Solution:
Correct Option is : (A)
$2\pi \sqrt{\frac{l}{g}}$

Topic: Chemistry, Oscillations, NEET
One end of copper rod of length 1.0 m and area of cross - section 10-3 m2 is immersed in boiling water and the other end in ice. If the coefficient of thermal conductivity of copper is 92 cal/m-sec-Co and latent heat of ice is 8 x 104 cal/kg, then the amount of ice with will melt in one minute is

Options:
A 9.2Ã10-3 kg
B 8Ã10-3 kg
C 6.9Ã10-3 kg
D 5.4Ã10-3 kg

The correct answer is:
6.9Ã10-3 kg

Solution:
KA Ã Î Î¸ Î x = dm dt L f
â â« dm = â« KA Ã 1 0 0 lâ¡ Ã 1 L f dt

Topic: Physics, Thermal Properties of Matter, NEET
One end of string of length l is connected to a particle of mass m and the other end is connected to a small peg on a smooth horizontal table. If the particle moves in circle with speed v, the net force on the particle (directed towards center) will be (T represents the tension in the string)

Options:
A T
B T+mv2l
C T-mv2l
D Zero

The correct answer is:
T

Solution:
Centripetal force mv2l is provided by tension so the net force will be equal to tension i.e., T.

Topic: Physics, Work Power Energy, NEET, NEET 2017
One example of animals having a single opening to the outside that serves both as mouth as well as anus is

Options:
A Octopus
B Asterias
C Ascidia
D Fasciola

The correct answer is:
Fasciola

Solution:
Fasciola hepatica (sheep liver fluke) belongs to phylum-Platyhelminthes. These worms have incomplete alimentary canal, there is a single opening for both ingestion and egestion. This is also called as blind sac body plan.

Topic: Biology, Animal Kingdom, NEET, NEET 2010 (Screening)
One Faraday of electricity is passed through molten Al2O3 , aqueous solution of CuSO4 and molten NaCl taken in three different electrolytic cells connected in series. The mole ratio of Al, Cu and Na deposited at the respective cathode is

Options:
A 2: 3: 6
B 6: 3: 2
C 1: 2: 3
D 3: 6: 2

The correct answer is:
2: 3: 6

Solution:
Al3++3e-âAl
3F = 1 mol
1F= 1/3 mol
Cu2++2e-âCu
2F =1 mol
1F =1/2 mol
Na++e-âNa
1F =1 mol
The mole ratio of Al, Cu and Na deposited at the respective cathode is 13:12:1 or 2: 3: 6

Topic: Chemistry, General Principles and Processes of Isolation of Metals, NEET
One function of the telomeres in a chromosome is to:

Options:
A Identify the correct number of the homologous pair of chromosomes
B Help two chromatids to move towards poles
C Seal the ends of chromosomes
D Start RNA synthesis

The correct answer is:
Seal the ends of chromosomes

Solution:
The telomere is a 'ribonucleoprotein complex' composed of a protein component and an RAN primer sequence which acts to protect the terminal ends of the chromosome. This prevents the ends of the chromosome from being processed as a doubled strand DNA break, which could lead to chromosome-to -chromosome telomere fusions.

Topic: Biology, Molecular Basis of Inheritance, NEET
One gas bleaches the colour of flowers by reduction, while the other by oxidation, the two gases respectively are

Options:
A CO and Cl2
B H2S and Br2
C NH3 and SO3
D SO2 and Cl2

The correct answer is:
SO2 and Cl2

Solution:
Here two gases are SO2 and Cl2 and they are bleaching agents
Aqueous solution of SO2 acts as a reducing agent
SO 2  +  2H 2 O→ H 2 SO 4  +  2H Nascent  hydrogen
Thus, SO2 in presence of moisture is used as bleaching agent. This is due to the reducing nature of SO2 . For delicate articles
Coloured matter +Hâ Colourless matter.

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), NEET