datavorous/entrance-exam-dataset huggingface dataset:
Arrange the following metals in the increasing order of their densities.
K, Sc, Ti and Ca

Options:
A K < Ca < Sc < Ti
B Ti < Sc < Ca < K
C Sc < Ti < K < Ca
D Sc < Ti < Ca < K

The correct answer is:
K < Ca < Sc < Ti

Solution:
The order of densities:
alkali metals < alkaline earth metals < transition metals.
K < Ca < Sc < Ti

Topic: Chemistry, Classification of Elements and Periodicity in Properties, NEET
Arrange the following metals in the order in which they displace each other from the solution of their salts: Al, Cu, Fe, Mg, and Zn.

Options:
A Al < Mg < Zn < Fe < Cu
B Mg > Al > Zn > Fe > Cu
C Zn < Al < Mg < Fe < Cu
D Cu < Fe < Zn < Mg < Al

The correct answer is:
Cu < Fe < Zn < Mg < Al

Solution:
Correct Option is : (D)
Cu < Fe < Zn < Mg < Al

Topic: Chemistry, Redox Reactions, NEET
Arrange the following metals in the order in which they displace each other from the solution of their salts Al, Cu, Fe, Mg, and Zn.

Options:
A Al < Cu < Fe < Mg < Zn
B Mg < Al < Zn < Fe < Cu
C Zn < Fe < Cu < Al < Mg
D Cu < Fe < Zn < Mg < Al

The correct answer is:
Cu < Fe < Zn < Mg < Al

Solution:
Correct Option is : (D)
Cu < Fe < Zn < Mg < Al

Topic: Chemistry, Electrochemistry, NEET
Arrange the following options in the ascending order of their BOD value.

I. Sample of highly polluted pond water.
II. Sample from unpolluted pond water.
III. Distilled water.

Options:
A III → I → II
B II → III → I
C III â II â I
D I → III → II

The correct answer is:
III → II → I

Solution:
Biochemical oxygen demand is the oxygen in milligrams required for five days in one litre of water at 20°C for the microorganisms to metabolize organic waste. BOD increases with an increase in pollution.

Topic: Biology, Environmental Issues, NEET
Arrange the following parts in human Mammary gland, traversing the route of milk ejection.
A. Mammary duct
B. Lactiferous duct
C. Mammary alveolus
D. Ampulla
E. Mammary tubule
Choose the correct answer from the options given below:

Options:
A $\mathrm{D} \rightarrow \mathrm{C} \rightarrow \mathrm{E} \rightarrow \mathrm{A} \rightarrow \mathrm{B}$
B $\mathrm{C} \rightarrow \mathrm{E} \rightarrow \mathrm{B} \rightarrow \mathrm{A} \rightarrow \mathrm{D}$
C $\mathrm{C} \rightarrow \mathrm{E} \rightarrow \mathrm{A} \rightarrow \mathrm{D} \rightarrow \mathrm{B}$
D $\mathrm{A} \rightarrow \mathrm{C} \rightarrow \mathrm{E} \rightarrow \mathrm{D} \rightarrow \mathrm{B}$

The correct answer is:
$\mathrm{C} \rightarrow \mathrm{E} \rightarrow \mathrm{A} \rightarrow \mathrm{D} \rightarrow \mathrm{B}$

Solution:
The correct answer is Option (3) as the correct route of milk ejection via mammary glands in human is:
Mammary alveolus $\rightarrow$ Mammary tubule $\rightarrow$ Mammary duct $\rightarrow$ Mammary ampulla $\rightarrow$ Lactiferous duct
In the question, the given structures are represented as:-
$\mathrm{C} \rightarrow \mathrm{E} \rightarrow \mathrm{A} \rightarrow \mathrm{D} \rightarrow \mathrm{B}$ (given in option 3 )
The other option i.e., (1), (2) and (4) are incorrect as they represent the wrong pathway.

Topic: Biology, Human Reproduction, NEET, NEET 2024 (Re-NEET)
Arrange the following places in increasing order of bird diversity.
(i) New York
(ii) India
(iii) Greenland
(iv) Columbia

Options:
A iii,iv,ii,i
B iv,iii,ii,i
C i,ii,iii,iv
D iii,i,ii,iv

The correct answer is:
iii,i,ii,iv

Solution:
In general species, diversity decreases as we move away from the equator to poles. Colombia located near the equator has nearly 1400 species of birds while India, with much of its land in Tropics, has 1200 species of birds. New York at 41o N has 105 species of birds and Greenland at 71o N has 56 species of birds.

Topic: Biology, Biodiversity and its Conservation, NEET
Arrange the following plants in the ascending order of evolution.
Cycads, monocotyledons, dicotyledons, progymnosperms, seed ferns, psilophyton.

Options:
A Psilophyton, seed ferns, progymnosperms,cycads, dicotyledons, monocotyledons
B Psilophyton, progymnosperms, seed ferns, cycads, dicotyledons, monocotyledons
C Psilophyton, progymnosperms, seed ferns,cycads, monocotyledons, dicotyledons
D Progymnosperms, psilophyton, seed ferns, cycads, dicotyledons, monocotyledons

The correct answer is:
Psilophyton, progymnosperms, seed ferns, cycads, dicotyledons, monocotyledons

Solution:
Psilophyton (genus of extinct vascular plants) â¶ progymnosperms (extinct group of plants that flourished in the mid to late Devonian (360â350 MYA) and contained the ancestors of modern gymnosperms) â¶ seed ferns (pteridospermatophyta are several distinct groups of extinct seed plants) â¶ cycads (plants typically characterized by a stout and woody trunk with a crown of large, hard and stiff, evergreen leaves) â¶ Dicotyledons (embryo with two cotyledons) â¶ monocotyledons (embryo with one cotyledon).

Topic: Biology, Evolution, NEET
Arrange the following polymers in increasing order of their intermolecular forces. Nylon 6,6, Buna-S, Polythene.

Options:
A Buna-S > Polythene > Nylon 6,6.
B Nylon 6,6 < Buna-S < Polythene.
C Buna-S < Polythene < Nylon 6,6.
D Buna-S = Polythene < Nylon 6,6.

The correct answer is:
Buna-S < Polythene < Nylon 6,6.

Solution:
Correct Option is : (C)
Buna-S < Polythene < Nylon 6,6.

Topic: Chemistry, Polymers, NEET
Arrange the following processes in the chronological order w.r.t cancer.

A. Metastasis
B. Activation of c-onc genes
C. Damage to neighboring cells
D. Loss of control of cell cycle

Options:
A B-D-C-A
B D-B-A-C
C B-D-A-C
D C-B-D-A

The correct answer is:
B-D-C-A

Solution:
Several genes called cellular oncogenes (c-onc) or proto-oncogenes have been identified in normal cells which, when activated under certain conditions, could lead to oncogenic
transformation of the cells by reducing the dependence of cells on growth like factors and thus undergo uncontrolled cell division.
Cancer cells grow very rapidly, invading, and damaging the surrounding normal tissues. As these cells actively divide and grow they also starve the normal cells by competing for vital nutrients. They secrete chemicals that promote the formation of new blood vessels for the cancer cells. This is called angiogenesis. Cells sloughed from such tumors reach distant sites through blood, and wherever they get lodged in the body, they start a new tumor there. This process is called metastasis

Topic: Biology, Human Health and Diseases, NEET
Arrange the following salts in increases order of their pH of 0.1M solution

Options:
A NaCl<NH4Cl<NaCN<HCl
B HCl<NH4Cl<NaCl<NaCN
C NaCN<NH4Cl<NaCl<HCl
D HCl<NaCl<NaCN<NH4Cl

The correct answer is:
HCl<NH4Cl<NaCl<NaCN

Solution:
NH4Cl undergoes cationic hydrolysis hence pH is <7 because the solution due to cationic hydrolysis in acids.
NaCN undergoes anionic hydrolysis hence pH is >7 .
HCl is strong acid and NaCl is neutral solution.
Hence the pH of given solutions will increases.
HCl<NH4Cl<NaCl<NaCN

Topic: Chemistry, Ionic Equilibrium, NEET
Arrange the following set of compounds in order of their decreasing relative reactivity with an electrophile, E+-

Options:
A p-H3C–C6H4–NO2> p-O2N–C6H4–NO2> Toluene
B Toluene > p-O2N–C6H4–NO2> p-H3C–C6H4–NO2
C p-O2N–C6H4–NO2> p-H3C–C6H4–NO2> Toluene
D Toluene > p-H3C–C6H4–NO2> p-O2N–C6H4–NO2

The correct answer is:
Toluene > p-H3C–C6H4–NO2> p-O2N–C6H4–NO2

Solution:
Correct Option is : (D)
Toluene > p-H3C–C6H4–NO2> p-O2N–C6H4–NO2

Topic: Chemistry, Hydrocarbons, NEET
Arrange the following set of compounds in order of their decreasing relative reactivity with an electrophile, E+-

Options:
A p-nitrochlorobenzene > chlorobenzene > 2,4-dinitrochlorobenzene
B chlorobenzene > p-nitrochlorobenzene > 2,4-dinitrochlorobenzene
C 2,4-dinitrochlorobenzene > p-nitrochlorobenzene > chlorobenzene
D chlorobenzene > 2,4-dinitrochlorobenzene > p-nitrochlorobenzene

The correct answer is:
chlorobenzene > p-nitrochlorobenzene > 2,4-dinitrochlorobenzene

Solution:
Correct Option is : (B)
chlorobenzene > p-nitrochlorobenzene > 2,4-dinitrochlorobenzene

Topic: Chemistry, Hydrocarbons, NEET
Arrange the following set of compounds in the order of their decreasing relative reactivity with an electrophile.Give reason.

Options:
A C6H5—OCH3> C6H5—Cl > C6H5–NO2
B C6H5—Cl > C6H5–NO2> C6H5—OCH3
C C6H5–NO2> C6H5—OCH3> C6H5—Cl
D C6H5—OCH3> C6H5–NO2> C6H5—Cl

The correct answer is:
C6H5—OCH3> C6H5—Cl > C6H5–NO2

Solution:
Correct Option is : (A)
C6H5—OCH3> C6H5—Cl > C6H5–NO2

Topic: Chemistry, Hydrocarbons, NEET
Arrange the following sets of compounds in order of their increasing boiling points: Pentan-1-ol, butan-1-ol, butan-2-ol, ethanol, propan-1-ol, methanol.

Options:
A Methanol < ethanol < butan-1-ol < pentan-1-ol < propan-1-ol < butan-2-ol
B Methanol < ethanol < propan-1-ol < butan-2-ol < butan-1-ol < pentan-1-ol
C Butan-1-ol < pentan-1-ol < methanol < ethanol < propan-1-ol < butan-2-ol
D Ethanol < propan-1-ol < butan-2-ol < butan-1-ol < pentan-1-ol < methanol

The correct answer is:
Methanol < ethanol < propan-1-ol < butan-2-ol < butan-1-ol < pentan-1-ol

Solution:
Correct Option is : (B)
Methanol < ethanol < propan-1-ol < butan-2-ol < butan-1-ol < pentan-1-ol

Topic: Chemistry, Alcohols Phenols and Ethers, NEET
Arrange the following sets of compounds in order of their increasing boiling points: Pentan-1-ol, n-butane, pentanal, ethoxyethane.

Options:
A pentan-1-ol < ethoxyethane < n-Butane < pentanal
B pentanal < pentan-1-ol < n-Butane < ethoxyethane
C n-Butane < pentanal < pentan-1-ol < ethoxyethane
D n-Butane < ethoxyethane < pentanal < pentan-1-ol

The correct answer is:
n-Butane < ethoxyethane < pentanal < pentan-1-ol

Solution:
Correct Option is : (D)
n-Butane < ethoxyethane < pentanal < pentan-1-ol

Topic: Chemistry, Alcohols Phenols and Ethers, NEET
Arrange the following steps for making the bacterial cell competent to take up DNA, in chronological order.

I. Incubation of cells with recombinant DNA on ice.
II. Incubation of cells with recombinant DNA at 42 degree Celsius.
III. Treating cells with a specific concentration of a divalent cation such as calcium.

Options:
A III followed by II followed by I followed by II
B III followed by I followed by II followed by I
C I followed by II followed by III followed by II
D II followed by I followed by III followed by I

The correct answer is:
III followed by I followed by II followed by I

Solution:
rDNA technology is a process to develop transformants. Transformants are bacterial cells which have successfully accepted the DNA sequence of our choice. To enable the process the cells are made competent to take in the desired DNA sequence as the DNA cannot pass through the cell membrane directly. The cells are first treated with calcium cation to increase the efficiency of DNA uptake. The cells are then kept on ice with the recombinant DNA followed by heat treatment at 42 degree Celsius for short period and again on ice. This treatment helps the bacterial cell to take in the rDNA sequence easily.

Topic: Biology, Biotechnology - Principles and Processes, NEET
Arrange the following structure according to their increasing order of acidic behaviour in polar solvent:

Options:
A i > ii < iii
B i < iii < ii
C i < ii < iii
D ii < iii < i

The correct answer is:
i < ii < iii

Solution:
This is because of the negative charge delocalizing on the vacant d-orbitals of chlorine atom present in the para position and this is not possible with fluorine atom. Thus, the conjugate base of p-chloro phenol is more stable and hence a weak base. So, p-chloro phenol is more acidic than p-fluoro phenol.

Topic: Chemistry, Hydrocarbons, NEET
Arrange the following structures according to their decreasing number.

1. Hepatic or gastric caeca
2. Malpighian tubules
3. Ommatidia

Options:
A Malpighian tubule > Ommatidia > Hepatic caeca
B Ommatidia > Malpighian tubule > Hepatic caeca
C Hepatic caeca > Ommatidia > Malpighian tubule
D Malpighian tubule > Ommatidia > Hepatic caeca

The correct answer is:
Ommatidia > Malpighian tubule > Hepatic caeca

Solution:
Hepatic caeca are 6 to 8 blind tubules present at the junction of foregut and midgut. At the junction of midgut and hindgut, 100 to 150 yellow-coloured thin filamentous malpighian tubules are present. Each compound eye of cockroach consists of about 2000 hexagonal ommatidia.

Topic: Biology, Structural Organisation in Animals, NEET
Arrange the following structures according to their decreasing number.

Hepatic or gastric caeca ; Malpighian tubules ; Ommatidia

Options:
A Malpighian tubule >Ommatidia> Hepatic caeca
B Ommatidia> Malpighian tubule >Hepatic caeca
C Hepatic caeca >Ommatidia> Malpighian tubule
D Malpighian tubule>Ommatidia>Hepatic caeca

The correct answer is:
Ommatidia> Malpighian tubule >Hepatic caeca

Solution:
Hepatic caeca are 6 to 8 blind tubules present at the junction of foregut and midgut.
At the junction of midgut and hindgut 100 to 150 yellow coloured thin filaments malpighian tubules are present.

Topic: Biology, Structural Organisation in Animals, NEET
Arrange the following terms in the correct developmental sequence: Pollen grain, sporogenous tissue, microspore tetrad, pollen mother cell, male gametes.

Options:
A Sporogenous tissue - pollen mother cell - microspore tetrad - pollen grain - male gamete
B Microspore tetrad - Sporogenous tissue - pollen mother cell - pollen grain - male gamete
C Sporogenous tissue - pollen mother cell - pollen grain - male gamete- microspore tetrad
D Sporogenous tissue - pollen grain - male gamete - pollen mother cell - microspore tetrad

The correct answer is:
Sporogenous tissue - pollen mother cell - microspore tetrad - pollen grain - male gamete

Solution:
The correct development sequence is as follows:
Sporogenous tissue - pollen mother cell - microspore tetrad - pollen grain - male gamete. During the development of microsporangium, each cell of the sporogenous tissue acts as a pollen mother cell and gives rise to a microspore tetrad, containing four haploid microspores by the process of meiosis (microsporogenesis). As the anther matures, these microspores dissociate and develop into pollen grains. The pollen grains mature and give rise to male gametes.

Topic: Biology, Sexual Reproduction in Flowering Plants, NEET
Arrange the following terms in the correct developmental sequence.

Options:
A pollen mother cell- sporogenous tissue - microspore tetrad- pollen grain - male gamete
B sporogenous tissue - pollen grain- pollen mother cell- microspore tetrad - male gamete
C sporogenous tissue - pollen mother cell - microspore tetrad - pollen grain - male gamete
D none of the above

The correct answer is:
sporogenous tissue - pollen mother cell - microspore tetrad - pollen grain - male gamete

Solution:
The correct developmental sequence is sporogenous tissue - pollen mother cell - microspore tetrad - pollen grain - male gamete

Topic: Biology, Sexual Reproduction in Flowering Plants, NEET
Arrange the following type of radiations in decreasing order of frequency: (i) radiation from microwave oven (ii) amber light from traffic signal (iii) radiation from FM radio (iv) cosmic rays from outer space and (v) X-rays.

Options:
A X-rays > Cosmic rays > amber light > microwave > FM
B Cosmic rays > FM > amber light > microwave > X-rays
C Cosmic rays > X–rays > amber light > microwave > FM
D microwave>Cosmic rays > X–rays > amber light > FM

The correct answer is:
Cosmic rays > X–rays > amber light > microwave > FM

Solution:
Correct Option is : (C)
Cosmic rays > X–rays > amber light > microwave > FM

Topic: Chemistry, Structure of Atom, NEET
Arrange the following types of soil in increasing order based on the size of the mineral particles in them.

Options:
A Silt<Clay<FineÂ sand
B Clay<Silt<Fine sand
C FineÂ sand<Clay<Silt
D Silt<FineÂ sand<Clay

The correct answer is:
Clay<Silt<Fine sand

Solution:
The particle size of clay is 0.002 mm, while that of silt is 0.002 to 0.05 mm. The particle size of fine sand is 0.05 to 0.2 mm, while that of coarse sand is 0.2 to 2 mm.

Topic: Biology, Organisms and Populations, NEET
Arrange the given acids in the decreasing order of their acidity
(I) H2SO3
(II) H3PO3 and
(III) HClO3

Options:
A I>III>II
B I>II>III
C II>III>I
D III>I>II

The correct answer is:
III>I>II

Solution:
Acidity is directly propotional to oxidation number. As the O.No. of S,P and Cl in
H2SO3,H3PO3 & HClO3 is +4, +3 & +5 respectively so decreasing order of acidity will be III>I>II .

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), NEET
Arrange the melting points of following compounds in decreasing order
1. n-butane
2. cis-2-butene
3. trans-2-butene
4. 1-butyne

Options:
A 1 > 2 > 3 > 4
B 4 > 2 > 3 > 1
C 4 > 3 > 2 > 1
D 3 > 2 > 1 > 4

The correct answer is:
4 > 3 > 2 > 1

Solution:
Melting point ∝ molecular weight, symmetry of the molecule
∝1μ of the compound. μ=dipole moment
Hence the correct order of melting point is
1-butyne > trans-2-butene > cis-2-butene > n-butane.

Topic: Chemistry, Chemical Bonding and Molecular Structure, NEET
Arrange the number of species of phylum Arthropoda (A), phylum Chordata (B), and phylum Mollusca (C) in ascending order.

Options:
A B < C < A
B B < A < C
C C = B < A
D C < B < A

The correct answer is:
B < C < A

Solution:
The number of species in phylum Arthropoda A is more than 1.3 billion because insects form the most species-rich taxonomic group (>70% of the total animals). Phylum Mollusca C is the second largest phylum with approximately 90000+ species. Phylum Chordata B has approximately 60,000 species, among which, half of the species are fishes.

Topic: Biology, Animal Kingdom, NEET
Arrange the sequence of different hormones for their role during gametogenesis.
(A) Gonadotropin LH stimulates synthesis and secretion of Androgen
(B) Gonadotropin releasing hormone from hypothalamus
(C) Androgen stimulates spermatogenesis
(D) Gonadotropin FSH helps in the process of spermiogenesis
(E) Gonadotropins from anterior pituitary gland
Choose the correct answer from the options given below:

Options:
A $(B),(E),(A),(C),(D)$
B $(D),(B),(A),(C),(E)$
C $(E),(A),(D),(B),(C)$
D $(C),(A),(D),(E),(B)$

The correct answer is:
$(B),(E),(A),(C),(D)$

Solution:
Option (1) is the answer because the correct sequence of different hormones for their role during gametogenesis is:
B. Gonadotropin releasing hormone from hypothalamus
E. Gonadotrophin from anterior pituitary gland
A. Gonadotropin LH stimulates synthesis and secretion of Androgen
C. Androgen stimulates spermatogenesis
D. Gonadotropin FSH helps in the process of spermiogenesis

Topic: Biology, Human Reproduction, NEET, NEET 2023 (Manipur)
Arrange the steps of PCR in decreasing order of temperature.

Options:
A Denaturation < Polymerisation < Annealing
B Polymerisation < Denaturation < Annealing
C Polymerisation < Annealing < Denaturation
D Annealing < Polymerisation < Denaturation

The correct answer is:
Annealing < Polymerisation < Denaturation

Solution:
PCR is Polymerase chain reaction. This technique is used to form numerous copies of a specific segment of DNA. Thus large quantities of DNA are obtained that are required for various experiments in medicine, molecular biology, forensic biology etc. The steps are:
1. Denaturation of the template into single strands. The temperature is 94 degree celsius.
2. Annealing of primers to each original strand for new strand synthesis. the temperature is 50-60 degree celsius
3. Polymerisation :Extension of new DNA strands from the primers. The temperature is 72 degree celsius.

Topic: Biology, Biotechnology - Principles and Processes, NEET
Arrange the various proteins involved in DNA replication in the correct sequence they are used.

(i) Single strand binding proteins

(ii) Topoisomerase

(iii) Phosphorylase

(iv) DNA ligase

(v) Helicase

Options:
A (iii) → (v) → (i) → (ii) → (iv)
B (i) → (ii) → (v) → (iii) → (iv)
C (v) → (i) → (iv) → (ii) → (iii)
D (v) → (ii) → (i) → (iii) → (iv)

The correct answer is:
(iii) → (v) → (i) → (ii) → (iv)

Solution:
The duplication of DNA is called DNA replication. Phosphorylase acts as an enzyme and helps in addition to a phosphate group to DNA. Then DNA B protein i.e. Helicase unwinds DNA and single-stranded binding protein prevents premature reannealing of double-stranded DNA. Then DNA topoisomerase I and II relieves torsional strain by cutting and joining a single strand or both strand. On the lagging strand DNA synthesized in short fragments that are known as Okazaki fragments. These fragments are joined together by DNA ligase. So the correct answer is A.

Topic: Biology, Molecular Basis of Inheritance, NEET
Arrange these compounds in decreasing order of reactivity for the nucleophilic addition reactions
(1) Acid chloride
(2) Aldehyde
(3) Ketone
(4) Anhydride
Select the correct answer from the codes given below

Options:
A 1>2>3>4
B 4>3>2>1
C 3>2>1>4
D 1>4>2>3

The correct answer is:
1>4>2>3

Solution:
(i) Stability in increasing order
(ii) Reactivity for nucleophile is in decreasing order.

Topic: Chemistry, Carboxylic Acid Derivatives, NEET
Arrange these hominids in ascending order of their cranial capacities.

Options:
A Java man → Homo habilis → Neanderthal man
B Homo habilis → Java man → Neanderthal man
C Neanderthal man → Homo habilis → Java man
D Homo habilis → Neanderthal man → Java man

The correct answer is:
Homo habilis → Java man → Neanderthal man

Solution:
The first hominid was called Homo habilis and his cranial capacity was between 650 and 800cc. Homo erectus, whose fossils were discovered in Java, had a large brain with a cranial capacity of around 900cc. The Neanderthal man had a cranial capacity of 1400cc and lived near east and central Asia.

Topic: Biology, Evolution, NEET
Arrange these metals in their increasing order of reducing power.

Options:
A

B

C

D

The correct answer is:

Solution:
Correct Option is : (C)

Topic: Chemistry, Electrochemistry, NEET
Arrange these respiratory substrates used in aerobic respiration in increasing order of their respiratory quotients.

Options:
A Protein - Tripalmitin - Oxalic acid - Glucose
B Protein - Tripalmitin - Glucose - Oxalic acid
C Tripalmitin - Protein - Oxalic acid - Glucose
D Tripalmitin - Protein - Glucose - Oxalic acid

The correct answer is:
Tripalmitin - Protein - Glucose - Oxalic acid

Solution:
The respiratory quotient is the ratio of the volume of carbon dioxide evolved to the volume of oxygen consumed in respiration. The respiratory quotient of tripalmitin (fatty acid) is 0.7, and that if protein is 0.9, glucose is 1 and oxalic acid is 4 during their aerobic respiration.

Topic: Biology, Respiration in Plants, NEET
Arrange water, ethanol and phenol in increasing order of acidity.

Options:
A Ethanol < Water < Phenol
B Ethanol < Phenol < Water
C Phenol < Ethanol < Water
D Phenol < Water < Ethanol

The correct answer is:
Ethanol < Water < Phenol

Solution:
Correct Option is : (A)
Ethanol < Water < Phenol

Topic: Chemistry, Alcohols Phenols and Ethers, NEET
Arrangement of different zones present in the root in a vertical section and choose the correct option.

A Root hair zone
B Zone of meristem
C Rootcap zone
D Zone of maturation
E Zone of elongation

Options:
A C, B, E, A, D
B A, B, C, D, E
C D, E, A, C, B
D E, D, C, B, A

The correct answer is:
C, B, E, A, D

Solution:
The root is covered at the apex by thimble like structure called as root cap, a few millimeter above root cap is zone of meristem in which cell repeatedly divides. Proximal to this zone is zone of elongation which undergo rapid elongation and enlargement. The region of elongation gradually differentiates and mature. Unicellular root hair develops and proximal to this is region of maturation.

Topic: Biology, Morphology of Flowering Plants, NEET
Arrangement of sepals and petals with respect to each other in the floral bud is called

Options:
A Vernation
B Venation
C Aestivation
D Phyllotaxy

The correct answer is:
Aestivation

Solution:
Number of sepals and petals are more in a flower thus they show a specific pattern of arrangement called aestivation which is clearly visible in bud condition.

Topic: Biology, Morphology of Flowering Plants, NEET
Arrangements of charges are shown in the figure. Flux linked with the closed surface P and Q respectively are _____ and _____.

Options:
A Zero, zero
B q∈0,-q∈0
C -q∈0,q∈0
D q∈0, zero

The correct answer is:
-q∈0,q∈0

Solution:
Flux= Total enclosed charge∈0
ϕ1=-q∈0, ϕ2=q∈0

Topic: Physics, Electrostatics, NEET