datavorous/entrance-exam-dataset huggingface dataset:
A photosynthetic organism which does not release oxygen is

Options:
A brown alga.
B green bacterium.
C green alga.
D phycobiont component of lichen.

The correct answer is:
green bacterium.

Solution:
Some organisms like green sulphur bacteria do not release oxygen during the process of photosynthesis. In purple and green sulphur bacteria, the hydrogen sulphide is the hydrogen donor, instead of water (which is usually the hydrogen donor in green plants) and sulphur or sulphate is the oxidation product depending on the organism performing photosynthesis and not on the oxygen. This also proves that oxygen that evolves from the green plants comes from water and not carbon dioxide.

Topic: Biology, Photosynthesis in Higher Plants, NEET
A phylum in which the digestion is intracellular as well as extracellular and polyp body form is seen includes organisms which:

Options:
A Are triploblastic.
B Show internal fertilization and indirect development.
C Have special cells called choanocytes.
D Have a central gastro-vascular cavity with a single opening.

The correct answer is:
Have a central gastro-vascular cavity with a single opening.

Solution:
Polyp and medusa body forms with extracellular as well as intracellular digestion are seen in phylum Cnidaria. Cnidarians are diploblastic which have special stinging cells called cnidocytes. They show external fertilization with indirect development. They have a central gastro-vascular cavity with a single opening (Blind Sac body plan).

Topic: Biology, Animal Kingdom, NEET
A physical quantity of the dimensions of length that can be formed out of c, G and e24πε0, where [ c is velocity of light, G is universal constant of gravitation, e is charge & ε0 is permittivity of free space]:

Options:
A 1c2Ge24πε012
B c2Ge24ÏÎµ012
C 1c2e2G4ÏÎµ012
D 1cGe24ÏÎµ0

The correct answer is:
1c2Ge24πε012

Solution:
Let e24ÏÎµ0=A=ML3T-2
L=Cx GyAz
[ L ]=LT-1x M-1 L3 T-2y ML3 T-2z
-y+z=0 â y=z ......(i)
x+3y+3z=1 ......(ii)
-x-4z=0 ......(iii)
From (i), (ii) and (iii)
z=y=12, x= -2

Topic: Physics, Units and Dimensions, NEET, NEET 2017
A physical quantity x is calculated from the relation x=a2b3cd. If percentage error in a, b, c and d are 2%, 1%, 3% and 4% , respectively. What is the percentage error in x?

Options:
A ±11%
B ±13%
C ±12%
D ±14%

The correct answer is:
±12%

Solution:
∆XX=± 2∆aa+3∆bb+∆cc+∆d2d
=±2×2+3×1+3+12×4=±12%

Topic: Physics, Units and Dimensions, NEET
A piece of glass is heated to a high temperature and then allowed to cool. If it cracks, a probable reason for this is

Options:
A low thermal conductivity of glass
B high thermal conductivity of glass
C high specific heat of glass
D high melting point of glass

The correct answer is:
low thermal conductivity of glass

Solution:
When a piece of glass is heated, due to low thermal conductivity it does not conduct heat fast enough and as a result, unequal thermal expansion takes place. Due to this unequal thermal expansion of its layers, the glass cracks

Topic: Physics, Thermal Properties of Matter, NEET
A piece of glass is placed on a paper having letters of different colours. The letters of which colour will be raised maximum is

Options:
A red
B green
C yellow
D violet

The correct answer is:
violet

Solution:
The raise of an object =hactual1-1μ
For raise to be maximum, μ has to maximum
μ∝1λ
Therefore, wavelength has to be minimum.

Topic: Physics, Ray Optics, NEET
A piece of ice falls from a height h so that it melts completely. Only one-quarter of the heat produced is absorbed by the ice and all energy of ice gets converted into heat during its fall. The value of h is:
(Latent heat of ice is 3.4Ã105âJ kg-1 and g=10âN kg-1)

Options:
A 34  km
B 544  km
C 136  km
D 68  km

The correct answer is:
136  km

Solution:
14mgh=mL
h=4Lg=4Ã3.4Ã10510=13.6Ã104
=136Ã103 m
=136 km

Topic: Physics, Thermal Properties of Matter, NEET, NEET 2016 (Phase 1)
A piece of iron is heated in a flame. If first becomes dull red then becomes reddish yellow and finally turns to white hot. The correct explanation for the above observation is possible by using

Options:
A Stefan's law
B Wien's displacement law
C Kirchoff's law
D Newton's law of cooling

The correct answer is:
Wien's displacement law

Solution:
The equation of Wien's displacement law, i.e., $\lambda_m T=$ constant.

Topic: Physics, Thermal Properties of Matter, NEET, NEET 2013 (All India)
A piece of marble is projected from the earth's surface with a velocity of 50 m s-1. 2 s later, it just clears a wall 5 m high. What is the angle of projection?

Options:
A 45°

B 30Â°

C 60Â°

D sin-114

The correct answer is:
sin-114

Solution:
Using the equation of motion in y-dir s=ut+12at2
Height after 2 s,
h = 5 = 50 sin θ t - 1 2 g t 2
5 = 50 sin θ 2 - 1 2 · 10 · 2 2
25 100 = sin θ
sin θ = 1 4
θ = sin - 1 1 4

Topic: Physics, Motion In Two Dimensions, NEET
A piece of wire is bent in the shape of a parabola y=kx2 (y-axis vertical) with a bead of mass m on it. The bead can slide on the wire without friction. It stays at the lowest point of the parabola when the wire is at rest. The wire is now accelerated parallel to the x-axis with a constant acceleration a. The distance of the new equilibrium position of the bead, where the bead can stay at rest with respect to the wire, from the y-axis is -

Options:
A agk

B a2gk
C 2agk
D a4gk

The correct answer is:
a2gk

Solution:
slope =dydx=tan π-θ
=dydx=-tanθ
ma cos θ = mg sin θ
a=g tanθ
⇒ a=g -dydx ⇒ a=-g.2kx
⇒ x=a2gk

Topic: Physics, Laws of Motion, NEET
A piece of wire is bent in the shape of a parabola y = kx2 (y - axis vertical) with a bead of mass m on it. The bead can slide on the wire without friction. It stays at the lowest point of the parabola when the wire is at rest. The wire is now accelerated parallel to the x-axis with a constant acceleration a. The distance of the new equilibrium position of the bead, where the bead can stay at rest with respect to the wire, from the y - axis is -

Options:
A a/gk
B a/2gk
C 2a/gk
D a/4gk

The correct answer is:
a/2gk

Solution:
slope = dy dx = tan Ï - Î¸
= dy dx = - tan Î¸
ma cos Î¸ = mg sin Î¸
a = g tan Î¸
â a = g - dy dx â a = - g . 2 kx
â x = a 2 gk

Topic: Physics, Laws of Motion, NEET
A piece of wood from the ruins of an ancient building was found to have a 14C activity of 12 disintegrations per minute per gram of its carbon content. The 14C activity of the living wood is 16 disintegrations per minute per gram. How long ago did the tree, from which the wooden sample came, die? Given half-life of 14C is 5760 years.

Options:
A 3100.25 years
B 1800.50 years
C 2391.12 years
D 4520.75 years

The correct answer is:
2391.12 years

Solution:
Correct Option is : (C)
2391.12 years

Topic: Chemistry, Nuclear Physics, NEET
A pink flowered Snapdragon plant was crossed with a red flowered Snapdragon plant. What type of phenotype/s is/are expected in the progeny?

Options:
A Red flowered as well as pink flowered plants
B Only pink flowered plants
C Red, Pink as well as white flowered plants
D Only red flowered plants

The correct answer is:
Red flowered as well as pink flowered plants

Solution:
Pink colour flower in snapdragon have genotype $\mathbf{R r}$
Red flowered snapdragon have genotype RR when they both are crossed
So the progeny that we get are red and pink flowered plants only

Topic: Biology, Principles of Inheritance and Variation, NEET, NEET 2024
A pistion filled with 0.04 mol of an ideal gas expands reversibly from 50 mL to 375 mL at a constant temperature of 37Â°C . As it does so, it absorbs 208 J of heat. The values of q and w of the process will be
R = 8.314  Jmol -1 K -1 In 7.5 = 2.01

Options:
A q=+208J,w=-208J
B q=+208J,w=+208J
C q=-208J,w=+208J
D q=-208J,w=-208J

The correct answer is:
q=+208J,w=-208J

Solution:
The process is isothermal expansion, so
q=-w {âµÎu=0}
Since, q = + 208 J
w = −208 J (expansion work)

Topic: Chemistry, Thermodynamics (C), NEET
A place, which used to be rocky and barren, has now turned into a lush green forest. The plant succession of the area is

Options:
A Lichen, moss, herbs, shrubs
B Moss, lichen, herbs, shrubs
C Lichen, moss, shrubs, herbs
D Shrubs, herbs, moss, lichen

The correct answer is:
Lichen, moss, herbs, shrubs

Solution:
The rocky and barren place is deficient in water and lacks any organic matter, having only minerals in disintegrated or weathered state, the pioneer to colonies this primitive substration are crustose types of lichen.
Crustose lichens→ Foliose lichens → Moss→ Herbs → Shrub → tree.

Topic: Biology, Ecosystem, NEET
A plane electromagnetic wave of frequency 40 MHz travels in free space in the x-direction. At some point and at some instant, the electric field Eâ has its maximum value of 750 N C-1 in the y-direction. The magnitude and direction of the magnetic field will be -

Options:
A 2.5 μT in x-direction
B 2.5 μT in y-direction
C 2.5 μT in z-direction
D None of these

The correct answer is:
2.5 μT in z-direction

Solution:
Crossed electric and magnetic field are constituent of electromagnetic wave
Bm=EmC=7503×108=2.5 μT in z-direction

Topic: Physics, Electromagnetic Waves, NEET
A plane electromagnetic wave of wave intensity 6 W m-2 stikes a small mirror of the area 40 cm2, held perpendicular to the approaching wave. The momentum transferred by the wave to the mirror each second will be

Options:
A 6.4×10-7 kg m s-1
B 4.8×10-8 kg m s-1
C 3.2×10-9 kg m s-1
D 1.6×10-10 kg m s-1

The correct answer is:
1.6×10-10 kg m s-1

Solution:
In the case of complete reflection, the momentum transfer by the wave to the mirror in each second will be
P=2Uc=2SavAc=2×6×40×10-43×108
=1.6×10-10 kg m s-1

Topic: Physics, Dual Nature of Matter, NEET
A plane glass plate is placed over various coloured letters (violet, green, yellow, red). The letter which appears to raise more is

Options:
A Red
B Yellow
C Green
D Violet

The correct answer is:
Violet

Solution:
âµ Î¼=Real depthapparent depth
Where, Î¼ refractive index of medium
â Apparent depth=Real depthÎ¼
But, Î¼â1Î» âµÎ»v<Î»g<Î»y<Î»r
Thus, Î¼v is greater to all of them
â´ Apparent depth is minimum for violet.
It means that the violet letter appear raised more.

Topic: Physics, Ray Optics, NEET
A plane mirror of circular shape with radius r=20 cm is fixed to the ceiling. A bulb is to be placed on the axis of the mirror. A circular area of the radius R=1 m on the floor is to be illuminated after reflection of light from the mirror. The height of the room is 3 m. What is the maximum distance from the centre of the mirror and the bulb so that the required area is illuminated?

Options:
A 75 cm

B 70 cm
C 80 cm
D 100 cm

The correct answer is:
75 cm

Solution:
tan θ = r h = R 3 + h
â 0 . 2 0 h = 1 3 + h ⇒ 0 . 6 + 0 . 2 h = h
0 . 8 h = 0 . 6 ⇒ h = 3 4 m
h = 75 cm

Topic: Physics, Ray Optics, NEET
A planet in a distant solar system is 10 times more massive than the earth and its radius is 10 times smaller. Given that the escape velocity from the earth is 11 km s-1, the escape velocity from the surface of the planet would be

Options:
A 0.11 km s-1

B 1.1 km s-1
C 11 km s-1
D 110 km s-1

The correct answer is:
110 km s-1

Solution:
vescape=2GMR for the earth
ve= 11 km s-1
Mass of the planet = 10 Me.
Radius of the planet = R10.
∴ ve=2GM×10R/10=10×11=110 km s-1

Topic: Physics, Gravitation, NEET
A planet moving along an elliptical orbit is closest to the sun at a distance $r_1$ and farthest away at a distance of $r_2$. If $y_1$ and $v_2$ are the linear velocities at these points respectively, then the ratio $\frac{y_1}{y_2}$ is

Options:
A $r_2 / r_1$
B $\left(r_2 / r_1\right)^2$
C $r_1 / r_2$
D $\left(r_1 / r_2\right)^2$

The correct answer is:
$r_2 / r_1$

Solution:
From the law of conservation of angular momentum
$$
\begin{gathered}
m r_1 y_1=m r_2 y_2 \\
r_1 y_1=r_2 y_2 \\
\frac{y_1}{y_2}=\frac{r_2}{r_1}
\end{gathered}
$$

Topic: Physics, Gravitation, NEET, NEET 2011 (Screening)
A planet of mass 4 times that of the earth spins about itself and completes one rotation is 96 hours. The radius of a stationary satellite about this planet in comparisons to the radius of the geostationary orbit around the earth is

Options:
A 4 times
B 14 times
C 2 times
D 12 times

The correct answer is:
4 times

Solution:
T=2πr32GM
∴24= 2π r 3 2 GM    ..........( 1 ) 96= 2π r 1 3 2 G×4M ..........( 2 )  divide ( 1 ) & ( 2 )  96 24 = 1 2 ( r 1 r ) 3 2
8=r1r32⇒r1r=4
r1=4r

Topic: Physics, Gravitation, NEET
A planet of mass m is in an elliptical orbit about the sun m<<Msun with an orbital period T. If A be the area of orbit, then its angular momentum would be

Options:
A 2mAT
B mAT

C mA2T
D 2mAT

The correct answer is:
2mAT

Solution:
using Kepler's IInd law ; areal velocity = constant =L2m
⇒dAdt = L2m
⇒ L=2mdAdt
L=2mAT

Topic: Physics, Gravitation, NEET
A planet radiates heat at a rate proportional to the fourth power of its surface temperature T. If the steady temperature of the planet is due to an exactly equal amount of heat received from the sun then which of the following statements is true?

Options:
A The planet's surface temperature varies inversely as the distance of the sun
B The planet's surface temperature varies directly as the square of its distance from the sun
C The planet's surface temperature varies inversely as the square root of its distance from the sun
D The planet's surface temperature is proportional to the fourth power of distance from the sun

The correct answer is:
The planet's surface temperature varies inversely as the square root of its distance from the sun

Solution:
Rate of loss of energy by unit area of the planet = σ T 4 , where σ is the Stefan's constant. Let Q be the total energy emitted by the sun every second. If d is the distance of the planet from sun, then Q falls uniformly over the inner surface of the sphere of radius d. Rate of gain of heat by unit area of planet,
=Q4πd2
For steady temperature of planet,
σ T 4 = Q 4 π d 2
T 4 = Q 4 π σ d 2 or T = Q 4 π σ d 2 1 / 4
T ∝ 1 d

Topic: Physics, Thermal Properties of Matter, NEET
A planet revolves around the sun in an elliptical orbit. The linear speed of the planet will be maximum at

Options:
A D

B B

C A

D C

The correct answer is:
A

Solution:
From Kepler's second law of planetary motion, the linear speed of a planet is maximum, when its distance from the sun is least, i.e., at point A.

Topic: Physics, Gravitation, NEET
A planet revolves in elliptical orbit around the Sun. The linear speed of the planet will be maximum at

Options:
A A
B B
C C
D D

The correct answer is:
A

Solution:
Here, angular momentum is conserved,
i.e. L=Iω constant.
At A , the moment of inertia I is least. So angular speed and therefore the linear speed of planet at A is maximum.

Topic: Physics, Gravitation, NEET
A plank with a box on it at one end is gradually raised about the other end. As the angle of inclination with the horizontal reaches 30°, the box starts to slip and slides 4.0 m down the plank in 4.0 s. The coefficients of static and kinetic friction between the box and the plank will be, respectively:

Options:
A 0.6 and 0.5
B 0.5 and 0.6
C 0.4 and 0.3
D 0.6 and 0.6

The correct answer is:
0.6 and 0.5

Solution:
μs=tan⁡30o=13
⇒μs=0.57=0.6
S=ut+12at2
4=12a42⇒a=12=0.5
a=g sinθ-μkgcosθ
⇒μK=0.93≈0.5

Topic: Physics, Laws of Motion, NEET, NEET 2015 (Phase 2)
A plano convex lens of (f=20 cm) is silvered at plane surface. New f will be

Options:
A 20 cm
B 40 cm
C 30 cm
D 10 cm

The correct answer is:
30 cm

Solution:
As 1f=(Î¼-1)1R1-1R2
â´120=(1.5-1)1â-1R
120=-12R,R=-10 cm
Refraction from rarer to denser medium
-Î¼1u+Î¼2v=Î¼2-Î¼1R, where u=â,v=f
â´0+1.5f=1.5-110=120,f=30 cm

Topic: Physics, Ray Optics, NEET
A plano-concave lens is made up of a glass of refractive index 1.5 and the radius of the curvature of its curved face is 100 cm. What is the power of the lens?

Options:
A +Â 0.5Â D
B -0.5 D
C -2Â D
D +2Â D

The correct answer is:
-0.5 D

Solution:
By using lens maker formula. Power=1focalÂ length P=1f=Î¼-11R1-1R2
=1.5-11â-11
=0.5-1
P= -0.5 D

Topic: Physics, Ray Optics, NEET
A plano-convex lens fits exactly into a plano-concave lens. Their plane surfaces are parallel to each other. If lenses are made of different materials of refractive indices $\mu_1$ and $\mu_2$ and $R$ is the radius of curvature of the curved surface of the lenses, then the focal length of the combination is

Options:
A $\frac{R}{2\left(\mu_1+\mu_2\right)}$
B $\frac{R}{2\left(\mu_1-\mu_2\right)}$
C $\frac{R}{\left(\mu_1-\mu_2\right)}$
D $\frac{2 R}{\left(\mu_2-\mu_1\right)}$

The correct answer is:
$\frac{R}{\left(\mu_1-\mu_2\right)}$

Solution:
Focal length of the combination
$$
\frac{1}{f}=\frac{1}{f_1}+\frac{1}{f_2}
$$
We have $f_1=\frac{R}{\left(\mu_1-1\right)}$ and $f_2=\frac{R}{\left(\mu_2-1\right)}$ or $\quad \frac{1}{f_1}=\frac{R}{\left(\mu_1-1\right)}$ or $\frac{1}{f_2}=-\frac{R}{\left(\mu_2-1\right)}$
Putting these values in Eq. (i), we get
$$
\begin{aligned}
\frac{1}{f} & =\frac{\left(\mu_1-1\right)}{R}-\frac{\left(\mu_2-1\right)}{R} \\
& =\frac{\left[\mu_1-1-\mu_2+1\right]}{R}=\frac{\mu_1-\mu_2}{R}
\end{aligned}
$$

Topic: Physics, Ray Optics, NEET, NEET 2013 (All India)
A plano-convex lens of refractive index 1.5 and radius of curvature 30 cm is silvered at the curved surface. Now this lens has been used to form the image of an object. The distance from this lens, an object be placed in order to have a real image of the size of the object is

Options:
A 20 cm

B 30 cm

C 60 cm

D 80 cm

The correct answer is:
20 cm

Solution:
A plano-convex lens behaves like a concave mirror when its curved surface is silvered.
∴ F of the concave mirror so formed
= R 2 μ = 30 2 × 1.5 =10 cm
To form an image of object size, the object should be placed at 2 F of the concave mirror.
∴ The distance of the object from the lens = 2 × F
= 2 × 10 = 20 cm.

Topic: Physics, Ray Optics, NEET
A plano-convex lens of unknown material and unknown focal length is given. With the help of a spherometer we can measure the

Options:
A focal length of the lens
B radius of curvature of the curved surface
C aperture of the lens
D refractive index of the material

The correct answer is:
radius of curvature of the curved surface

Solution:
A spherometer is a device that does just as the name suggests: it measures a sphere. But what exactly would you measure on a sphere? You could measure its diameter or the circumference of a great circle, the surface area, or the radius. But all of these measurements will change proportionally to the radius R of the sphere. Any surface that is curved has a radius of curvature, the radius of the sphere that approximates the surface locally. Thus, a spherometer can measure the radius of curvature of an item such as a lens and curved mirrors that are spherical.

Topic: Physics, Experimental Physics, NEET, NEET 2020 (Phase 2)
A plant breeder wants to obtain a superior quality maize crop. What are the sequence of events he must follow to pollinate the maize flowers with the chosen pollen?

Options:
A Bagging → Dusting of pollen → Rebagging
B Bagging → Emasculation → Dusting of pollen → Rebagging
C Emasculation → Bagging → Dusting of pollen → Rebagging
D Bagging → Dusting of pollen → Emasculation → Rebagging

The correct answer is:
Bagging → Dusting of pollen → Rebagging

Solution:
Emasculation is performed when a flower is bisexual and we do not want the pollen from the same flower to pollinate it (self-pollination) and contaminate the results. Maize has unisexual flowers. Its female flowers don't have anther and hence emasculation process is not needed.

Topic: Biology, Sexual Reproduction in Flowering Plants, NEET
A plant cell that has the potential to develop into a full plant is called

Options:
A Totipotency
B Unipotency
C Multipotency
D Regeneration

The correct answer is:
Totipotency

Solution:
Any cell which has an ability to develop into a complete organism is totipotent.

Topic: Biology, Strategies for Enhancement in Food Production, NEET
A plant exhibits the appearance of brown spots surrounded by chlorotic veins. When inspected in more detail, it is observed that its calcium translocation to the shoot is also disrupted. The plant is showing toxicity of

Options:
A Mn
B Mg
C Fe
D Ca

The correct answer is:
Mn

Solution:
Toxicity levels for any element also vary for different plants. Many a times, excess of an element may inhibit the uptake of another element. For example, the prominent symptom of manganese toxicity is the appearance of brown spots surrounded by chlorotic veins. It is important to know that manganese competes with iron and magnesium for uptake and with magnesium for binding with enzymes. Manganese also inhibit calcium translocation in shoot apex. Therefore, excess of manganese may, in fact, induce deficiencies of iron, magnesium and calcium.

Topic: Biology, Mineral Nutrition, NEET
A plant is of $F_1$ generation with genotype "AABbCC". On selfing of this plant what is the phenotypic ratio in $\mathrm{F}_2$ generation?

Options:
A $3: 1$
B $1: 1$
C $9: 3: 3: 1$
D $27: 9: 9: 9: 3: 3: 3: 1$

The correct answer is:
$3: 1$

Solution:
The genotype of $F_1$ generation is AABbCC
Number of gametes that are obtained by crossing can be obtained by formula $=2^n$
(where $n$ represents the number of heterozygous gametes)
Thus, the number of heterozygous gametes $=2^1=2$
2 gametes formed are: $\mathrm{ABC}$ and $\mathrm{AbC}$.
On self crossing $F_1$ generation, the phenotypes that are formed in $\mathrm{F}_2$ generation are in the ratio of $3: 1$

Topic: Biology, Principles of Inheritance and Variation, NEET, NEET 2002
A plant leaf is found to have bundle sheath cells having large-sized chloroplasts full of starch granules. Which of the following characteristics can be observed in this plant?

I. Stomata open at night.
II. Presence of PEP carboxylase in mesophylls.
III. Presence of RubisCo in bundle sheath cells.
IV. High photorespiration rate in hot summer days.
V. Light reaction and carbon fixation as carbohydrates occur in different cell types.
VI. The carbon assimilation rate is saturated in the early morning on summer days.

Options:
A Only I, III
B Only II, IV
C Only II, IV, V
D Only II, III, V

The correct answer is:
Only II, III, V

Solution:
C4 plant has bundle sheet cell with large chloroplast. In C4 plants carbon fixation occur twice i.e., first in mesophyll cell with the help of enzyme PEP carboxylase and second in bundle sheet with help of enzyme RUBISCO. Bundle sheath cell has all the enzymes for the Calvin cycle.

Topic: Biology, Photosynthesis in Higher Plants, NEET
A plant placed near a window bends outward because

Options:
A Its tip is able to get more oxygen
B Its tip is able to obtain more light
C Its tip is able to receive necessary warmth
D Its tip has auxin which is responsible for phototropic movement.

The correct answer is:
Its tip has auxin which is responsible for phototropic movement.

Solution:
Plant bends outwards when it placed near the window because of auxin responsible for the phototropism movement.
The auxin contents on the shadow side is higher than that on the lighter side and as a result, the shaded side elongate more than the cells on the illuminated side and the tip bends outwards

Topic: Biology, Plant - Growth and Development, NEET
A plant requires magnesium for

Options:
A Protein synthesis
B Chlorophyll synthesis
C Cell wall development
D Holding cells together

The correct answer is:
Chlorophyll synthesis

Solution:
Plants require magnesium for chlorophyll synthesis. All four tetrapyrrole rings bind with magnesium (Mg++) ion at the center of chlorophyll molecule.

Topic: Biology, Mineral Nutrition, NEET