datavorous/entrance-exam-dataset huggingface dataset:
The correct order of increasing covalent character is

Options:
A LiCl < NaCl <  BeCl 2
B BeCl 2  < NaCl <  LiCl 2
C NaCl < LiCl <  BeCl 2
D BeCl 2  < LiCl < NaCl

The correct answer is:
NaCl < LiCl <  BeCl 2

Solution:
As per Fajan's rule:
(i) Higher the charge on cation/anion, higher will be the covalent nature.
(ii) For similar charges, a smaller cation will have more covalent nature.
Thus, correct order of covalent nature is:
BeCl 2  > LiCl > NaCl

Topic: Chemistry, Chemical Bonding and Molecular Structure, NEET
The correct order of increasing hydration energy of the following conjugate bases of oxoacids of chlorine is

Options:
A ClO4-<ClO3-<ClO2-<ClO-
B ClO-<ClO2-<ClO3-<ClO4-
C ClO3-<ClO4-<ClO2-<ClO-
D ClO4-<ClO3-<ClO-<ClO2-

The correct answer is:
ClO-<ClO2-<ClO3-<ClO4-

Solution:
As smallest cation is most hydrated here ClO4- has smallest central atom as it has +7 charge on it and on ClO3-(+5),ClO2-(+3),ClO-(+1) so the order of hydration energy is ClO â < ClO 2 â < ClO 3 â < ClO 4 â

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), NEET
The correct order of increasing reactivity of C-X bond towards nucleophile in the following compound is

Options:
A III < II < I < IV
B I < II < IV < III
C II < III < I < IV
D IV < III < I < II

The correct answer is:
I < II < IV < III

Solution:
As for alkyl halides the attack of nucleophile is favoured by the stability of carbocation formed or presence of e- withdrawing groups in aryl halides hence the order is

Topic: Chemistry, General Organic Chemistry, NEET
The correct order of increasing reactivity of $\mathrm{C} \mathrm{X}$ bond towards nucleophile in the following compounds is

Options:
A I $ < $ II $ < $ IV $ < $ III
B II $ < $ III $ < $ I $ < $ IV
C IV $ < $ III $ < $ I $ < $ II
D III $ < $ II $ < $ I $ < $ IV

The correct answer is:
I $ < $ II $ < $ IV $ < $ III

Solution:
Key Idea Alkyl halides are more reactive towards nucleophilic substitution. Reactivity depends upon the stability of carbocation intermediate formed.
Among the given halides, aryl halide $\left(\mathrm{C}_6 \mathrm{H}_5 \mathrm{X}\right)$ is least reactive towards nucleophile as in it the $\mathrm{C}-\mathrm{X}$ bond acquire some double bond character due to resonance. Presence of electron withdrawing groups like $-\mathrm{NO}_2$ at ortho and para positions facilitate the nucleophilic displacenent of $-\mathrm{X}$ of aryl halide. Among alkyl halides, $3^{\circ}$ halides are more reactive as compared to $2^{\circ}$ halides due to the formation of more stable carbocation. Hence, the order of reactivity of $\mathrm{C}-\mathrm{X}$ bond towards nucleophile is as

Topic: Chemistry, Haloalkanes and Haloarenes, NEET, NEET 2010 (Screening)
The correct order of increasing thermal stability of $\mathrm{K}_2 \mathrm{CO}_3, \mathrm{MgCO}_3, \mathrm{CaCO}_3$ and $\mathrm{BeCO}_3$ is:

Options:
A $\mathrm{BeCO}_3 < \mathrm{MgCO}_3 < \mathrm{CaCO}_3 < $ $\mathrm{K}_2 \mathrm{CO}_3$
B $\mathrm{MgCO}_3 < \mathrm{BeCO}_3 < \mathrm{CaCO}_3 < \mathrm{K}_2 \mathrm{CO}_3$
C $\mathrm{K}_2 \mathrm{CO}_3 < \mathrm{MgCO}_3 < \mathrm{CaCO}_3 < $ $\mathrm{BeCO}_3$
D $\mathrm{BeCO}_3 < \mathrm{MgCO}_3 < \mathrm{K}_2 \mathrm{CO}_3 < \mathrm{CaCO}_3$

The correct answer is:
$\mathrm{BeCO}_3 < \mathrm{MgCO}_3 < \mathrm{CaCO}_3 < $ $\mathrm{K}_2 \mathrm{CO}_3$

Solution:
The basicity of metal hydroxides increases down the group from $\mathrm{Be}$ to $\mathrm{Ba}$, so, the thermal stability of their carbonates also increases in the same order. Also, group 1 compound are more thermally stable than group 2 because their hydroxide are much basic than group 2 hydroxides.
$$
\mathrm{BeCO}_3 < \mathrm{MgCO}_3 < \mathrm{CaCO}_3 < \mathrm{K}_2 \mathrm{CO}_3
$$

Topic: Chemistry, s Block Elements, NEET, NEET 2007
The correct order of increasing thermal stability of the given compounds is

I. HF

II. HBr

III. HCl

IV. HI

Options:
A I < II < III < IV
B IV < II < III < I
C IVÂ <Â IIÂ <Â IÂ <Â III
D IIÂ <Â IVÂ <Â IÂ <Â III

The correct answer is:
IV < II < III < I

Solution:
Stability depends on bond strength Bond strength depends on bond length. Bond length depends on the size of halides. Bigger bond length easily cleavage of H-X bond and thus, the correct order is HF>HCl>HBr>HI
IV<II<III<I

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), NEET
The correct order of ionic radii of ions Na+,Mg2+,Al3+ and Si4+ is

Options:
A Na+<Mg2+<Al3+<Si4+
B Mg2+>Na+>Al3+>Si4+
C Al3+>Na+>Si4+>Mg2+
D Na+>Mg2+>Al3+>Si4+

The correct answer is:
Na+>Mg2+>Al3+>Si4+

Solution:
Na+>Mg2+>Al3+>Si4+ . All are isoelectronic but nuclear charge per electron is greatest for Si4+ . So it has smallest size and nuclear charge per electron for Na+ is smallest. So it has largest size.

Topic: Chemistry, Classification of Elements and Periodicity in Properties, NEET
The correct order of ionic radii of $\mathrm{Y}^{3+}$, $\mathrm{La}^{3+}$ and $\mathrm{Lu}^{3+}$ is:
(Atomic nos $\mathrm{Y}=39, \mathrm{La}=57, \mathrm{Eu}=63 \mathrm{Lu}$ $=71$ )

Options:
A $\mathrm{Y}^{3+} < \mathrm{La}^{3+} < \mathrm{Eu}^{3+} < \mathrm{Lu}^{3+}$
B $\mathrm{Y}^{3+} < \mathrm{Lu}^{3+} < \mathrm{Eu}^{3+} < \mathrm{La}^{3+}$
C $\mathrm{Lu}^{3+} < \mathrm{Eu}^{3+} < \mathrm{La}^{3+} < \mathrm{Y}^{3+}$
D $\mathrm{La}^{3+} < \mathrm{Eu}^{3+} < \mathrm{Lu}^{3+} < \mathrm{Y}^{3+}$

The correct answer is:
$\mathrm{Y}^{3+} < \mathrm{Lu}^{3+} < \mathrm{Eu}^{3+} < \mathrm{La}^{3+}$

Solution:
Eu and Lu are the members of lanthanide series (so they show lanthanide contraction) and $\mathrm{La}$ is the representative element of all elements of such series and $\mathrm{Y}^{3+}$ ion has lower radii as comparison to $\mathrm{La}^{3+}$ because it lies immediately above it in the periodic table.
$$
\mathrm{Y}^{3+} < \mathrm{Lu}^{3+} < \mathrm{Eu}^{3+} < \mathrm{La}^{3+}
$$

Topic: Chemistry, d and f Block Elements, NEET, NEET 2003
The correct order of ionic size in polar solvent is

Options:
A Li+>Na+>K+>Rb+
B Rb+>K+>Na+>Li+
C K+>Na+>Li+>Rb+
D Rb+>Na+>K+>Li+

The correct answer is:
Li+>Na+>K+>Rb+

Solution:
In polar solvent, solvation is maximum for Li+ , due to high charge density on small size. Hence size of solvated cation is in the order Li+>Na+>K+>Rb+

Topic: Chemistry, s Block Elements, NEET
The correct order of ionization energy in the following second-period elements is:

Options:
A B<Be<C<N<O
B B<Be<N<C<O
C Be>B>C>N>O
D B<Be<C<O<N

The correct answer is:
B<Be<C<O<N

Solution:
Ionization energy increases along the period. But Be2s2 and N2s22p3 have higher ionization energy than boron and oxygen respectively due to stable electronic configuration (half-filled and full-filled subshells are exceptionally stable).

Topic: Chemistry, Classification of Elements and Periodicity in Properties, NEET
The correct order of molar conductivity at infinite dilution of LiCl, NaCl and KCl is

Options:
A LiCl>KCl> NaCl
B KCl>NaCl>LiCl
C LiCl>NaCl>KCl
D NaCl>KCl>LiCl

The correct answer is:
KCl>NaCl>LiCl

Solution:
Ionic mobility depends upon the charge to size ratio of ion. The ionic size in case of hydrated cation is
K+aq<Na+aq< Li+aq
size of cation is less, will attracted by more H 2 O molecules so becomes more bulky hence, does not move easily.

Topic: Chemistry, Electrochemistry, NEET
The correct order of N-compounds in its decreasing order of oxidation states is

Options:
A HNO3, NH4Cl, NO, N2
B HNO3, NO, NH4Cl, N2
C HNO3, NO, N2,NH4Cl
D NH4Cl, N2, NO, HNO3

The correct answer is:
HNO3, NO, N2,NH4Cl

Solution:
→HNO3⇒1+x+3(−2)=0
x=5
→NO⇒x+1(−2)=0
x=2
→N2⇒2x=0
x=0
→NH4Cl=x+4(1)+1(−1)=0
x=−3

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), NEET, NEET 2018
The correct order of N-compounds in its decreasing order of oxidation states is

Options:
A HNO3,NH4Cl,NO,N2
B HNO3,NO,NH4Cl,N2
C HNO3,NO,N2,NH4Cl
D NH4Cl,N2,NO,HNO3

The correct answer is:
HNO3,NO,N2,NH4Cl

Solution:
The oxidation number of N-atoms in these molecules is as follows
HNO3+5,NO+2,N20,NH4Cl-3
Hence, the correct answer is option (C) .

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), NEET
The correct order of reactivity for the addition reaction of the following carbonyl compounds with ethyl magnesium iodide is

Options:
A III > II > I > IV
B IV > III > II > I
C I > II > IV > III
D I > III > II > IV

The correct answer is:
I > III > II > IV

Solution:
If the carbony carbonyl is stericaly crowded, then it will be reluctant to undergo addition reaction. Moreover, attachment of bulkier alkyl groups with the carbonyl carbon lessens its positive charge resulting into the minimisation of attack by R-⋅⋅ from RMgBr. So, the order is

Topic: Chemistry, Aldehydes and Ketones, NEET
The correct order of reactivity of PhMgBr with is

Options:
A I > II > III
B III > II > I
C II > III > I
D I > III > II

The correct answer is:
II > III > I

Solution:
Reactivity
â electron deficiency at carbon atom of carbonyl group
â electron withdrawing groups (-I, -R)
â1electron releasing groups(+I,+R)
â1steric hindrance
Using these concepts the correct order of reactivity is given as
II > III > I.

Topic: Chemistry, General Organic Chemistry, NEET
The correct order of reactivity towards the electrophillic substitution of the compounds aniline (I), benzene (II) and nitrobenzene (III) is:

Options:
A III $>$ II $>$ I
B II $>$ III $>$ I
C I $ < $ II $>$ III
D I $>$ II $>$ III

The correct answer is:
I $>$ II $>$ III

Solution:
Nitro group $\left(-\mathrm{NO}_2\right)$ is an electron withdrawing group. It removes electron density from aromatic nucleus. Thus, the reactivity of nitrobenzene towards electrophilic aromatic substitution reaction is less. Amine group $\left(-\mathrm{NH}_2\right)$ is an electron releasing group. They increase the electron density on benzene ring. Thus, aniline is more reactive towards electrophilic aromatic substituion reaction than benzene.
Hence, the correct order of reactivity towards the electrophilic substitution of the compounds is.
aniline $(\mathrm{I})>$ benzene (II) $>$ nitrobenzene (III).

Topic: Chemistry, Hydrocarbons, NEET, NEET 2003
The correct order of response of organs for increasing blood pressure is

Options:
A Kidney - Liver - Lungs - Adrenal gland - Kidney
B Kidney - Lungs - Liver - Adrenal gland - Kidney
C Kidney - Liver - Adrenal gland - Lungs - Kidney
D Kidney - Lungs - Adrenal gland - Liver - Kidney

The correct answer is:
Kidney - Liver - Lungs - Adrenal gland - Kidney

Solution:
In response to decrease in blood pressure or GFR, the kidneys release Renin. Renin acts on the liver and converts angiotensinogen into angiotensin I. In the lungs angiotensin I is converted to angiotensin II with the help of angiotensin converting enzyme. Angiotensin II is a vasoconstrictor and also stimulates the adrenal gland which releases aldosterone. Aldosterone acts on the kidneys and helps in absorption of sodium ions. Thus this mechanism increases blood pressure

Topic: Biology, Excretory Products and their Elimination, NEET
The correct order of sedimentation of subcellular structures during differential centrifugation is

Options:
A Lysosomes → Mitochondria → Nucleus → Ribosome
B Nucleus → Mitochondria → Lysosome → Ribosome
C Mitochondria → Nucleus → Lysosome → Ribosome
D Ribosome → Mitochondria → Nucleus → Lysosome

The correct answer is:
Nucleus → Mitochondria → Lysosome → Ribosome

Solution:
Nucleus is the largest structure of cell which occupies upto 10% volume of the cell. Mitochondria is the largest cytoplasmic organelle in animal cell and ribosome is the smallest organelle of the cell.

Topic: Biology, Cell - The Unit of Life, NEET
The correct order of speed of movement of alkali metal ions in aqueous solution is

Options:
A Rb+>K+>Na+>Li+
B Li+>Na+>K+>Rb+
C Na+>K+>Rb+>Li+
D K+>Na+>Rb+>Li+

The correct answer is:
Rb+>K+>Na+>Li+

Solution:
The alkali metal ions exist as hydrated ions, MH2Ox+, in the aqueous solution. The degree of hydration, however, decreases with the increasing ionic size as we move from Li+ to Cs+. In other words, Li+ ion is the most hydrated. e.g. LiH2O6+.

Since the mobility of ion is inversely proportional to the size of their hydrated ions, therefore, amongst the alkali metal ions, lithium has the lowest ionic mobility.

Rb+aq>K+aq>Na+aq>Li+aq

Topic: Chemistry, s Block Elements, NEET
The correct order of stability for the following alkoxides is

(1) (2) (3)

Options:
A (2)>(1)>(3)
B (2)>(3)>(1)
C (3)>(1)>(2)
D (3)>(2)>(1)

The correct answer is:
(3)>(2)>(1)

Solution:

Topic: Chemistry, General Organic Chemistry, NEET
The correct order of stages in life cycle of Plasmodium is

Options:
A gametocytes - gametes - ookinete - oocyst - sporozoite
B gametocytes - gametes - ookinete - oocyst - merozoite
C gametocytes - gametes - oocyst - ookinete - sporozoite
D gametocytes - gametes - oocyst - sporozoite- ookinete

The correct answer is:
gametocytes - gametes - ookinete - oocyst - sporozoite

Solution:
Mosquitoes ingest the Plasmodium while feeding on an infected human. The malarial parasite is in the haploid Gametocyte stage. There are two types of plasmodial gametocytes: Microgametocytes and Macrogametocytes. Once ingested, One Microgametocyte undergoes a process of exflagellation to form 8 flagellated haploid male gametes (microgametes). One Macrogametocyte undergoes differentiation to form one haploid female gamete (macrogamete). This takes place within the mosquito's gut (crop). These male flagellated male gametes fertilize the female gamete to form a diploid zygote within the mosquito's gut (crop). This diploid zygote develops a motile stage is called ookinete. This ookinete penetrates the gut lining and develops a protective covering around it within the gut wall. This is called the oocyst stage. The cell within the oocyst undergo repeated divisions to form thousands of sporozoites.

Topic: Biology, Human Health and Diseases, NEET
The correct order of steps in Polymerase Chain Reaction (PCR) is

Options:
A Denaturation, Extension, Annealing
B Annealing, Extension, Denaturation
C Extension, Denaturation, Annealing
D Denaturation, Annealing, Extension

The correct answer is:
Denaturation, Annealing, Extension

Solution:
The Polymerase Chain Reaction (PCR) involves three basic steps; denaturation, annealing and extension. In the denaturation step, DNA is heated at high temperature (94°C to 96°C) to separate the two strands. In the next step (annealing) the two oligonucleotide primers anneal to each single-stranded template DNA. This step is carried out at a lower temperature (40°C to 60°C). The final step is an extension, wherein Taq DNA polymerase synthesizes the DNA region between the primers, using dNTPs (deoxynucleoside triphosphates) and Mg2+ ions.

Topic: Biology, Biotechnology - Principles and Processes, NEET, NEET 2018
The correct order of strength of H-bond in the following compounds is

Options:
A H2O>H2O2>HF>H2S
B HF>H2O2>H2O>H2S
C HF>H2O>H2S>H2O2
D HF>H2O>H2O2>H2S

The correct answer is:
HF>H2O2>H2O>H2S

Solution:
The correct order of strength of H-bond is
HF>H2O2>H2O>H2S
Strength of H-bonding is higher in H2O2 than H2O , because the amount formal negative charge on oxygen atom in case of water is more than that of H2O2 .

Topic: Chemistry, Chemical Bonding and Molecular Structure, NEET
The correct order of strengths of carboxylic acids is

Options:
A I>II>III
B II>III>I
C III>II>I
D II>I>III

The correct answer is:
II>III>I

Solution:
As the order of the negative inductive effect increases, the acidity of the carboxylic acids increases.

On the basis of -I effect, the correct acidic strength would be:

Topic: Chemistry, General Organic Chemistry, NEET, NEET 2016 (Phase 2)
The correct order of the bond dissociation energies of various C-H bonds present in the compound is

Options:
A α<β<γ<θ<λ
B α<γ<θ<β<λ
C λ>α>θ>β>γ
D β<α<γ<λ<θ

The correct answer is:
α<β<γ<θ<λ

Solution:
Dissociation of C-H bond is homolytic cleavage, thus consider carbon free radical stability. Higher is the stability of free radical lesser is the amount of energy required for dissociation of bond.

Topic: Chemistry, Chemical Bonding and Molecular Structure, NEET
The correct order of the decreasing ionic radii among the following isoelectronic species is

Options:
A K+>Ca2+>Cl->S2-
B Ca2+>K+>S2->Cl-
C Cl->S2->Ca2+>K+
D S2->Cl->K+>Ca2+

The correct answer is:
S2->Cl->K+>Ca2+

Solution:
In case of isoelectronic species the value of Ionic radius follows the order M-4>M-3>M-2>M-1>M+>M+2>M+3 as the electron / proton number increase effective nuclear charge decreases hence radius increases.
Here S-2>Cl->K+>Ca+2 is the decreasing order of size.

Topic: Chemistry, Classification of Elements and Periodicity in Properties, NEET
The correct order of the mobility of the alkali metal ions in aqueous solution is:

Options:
A $\mathrm{Rb}^{+}>\mathrm{K}^{+}>\mathrm{Na}^{+}>\mathrm{Li}^{+}$
B $\mathrm{Li}^{+}>\mathrm{Na}^{+}>\mathrm{K}^{+}>\mathrm{Rb}^{+}$
C $\mathrm{Na}^{+}>\mathrm{K}^{+}>\mathrm{Rb}^{+}>\mathrm{Li}^{+}$
D $\mathrm{K}^{+}>\mathrm{Rb}^{+}>\mathrm{Na}^{+}>\mathrm{Li}^{+}$

The correct answer is:
$\mathrm{Rb}^{+}>\mathrm{K}^{+}>\mathrm{Na}^{+}>\mathrm{Li}^{+}$

Solution:
As Charge density $\propto$ hydration. Therefore hydrated size of $\mathrm{Li}^{+}$is large and having less mobility and down the group degree of hydration decreases. So, among alkali metal ions, lithium has the lowest mobility.
$$
\mathrm{Rb}^{+}>\mathrm{K}^{+}>\mathrm{Na}^{+}>\mathrm{Li}^{+}
$$
Related Theory
The magnitude of hydration enthalpy depends on the charge density of the ions. The charge density is more for smaller ions and hence the smaller ions have higher values of hydration enthalpy. The higher the charge density the higher will be the force of attraction between the ion and the water polar end.

Topic: Chemistry, s Block Elements, NEET, NEET 2006
The correct order of the stoichiometries of AgCl formed when AgNO3 in excess is treated with the complexs
CoCl36NH3,CoCl3.5NH3,CoCl3.4NH3 respectively is

Options:
A 3AgCl, 1AgCl, 2AgCl
B 3AgCl, 2AgCl, 1AgCl
C 2AgCl, 3AgCl, 1AgCl
D 1AgCl, 3AgCl, 2AgCl

The correct answer is:
3AgCl, 2AgCl, 1AgCl

Solution:
Using Werner theory it is clear that only primary valencies are ionisable or precipitable
[Co(NH3)6]Cl3→3AgNO3[Co(NH3)6]3++3AgCl
[Co(NH3)5Cl]Cl2→2AgNO3[Co(NH3)5Cl]2++2AgCl
[Co(NH3)4Cl2]Cl→AgNO3[Co(NH3)4Cl+]+AgCl
Hence, 3, 2, 1 AgCl are formed.

Topic: Chemistry, Coordination Compounds, NEET
The correct order of the stoichiometries of AgCl formed when AgNO3 is treated in excess with the complexes: CoCl3.6NH3, CoCl3.5NH3, CoCl3.4NH3, respectively, is:

Options:
A 1 AgCl, 3 AgCl, 2 AgCl
B 3 AgCl, 1 AgcCl, 2 AgCl
C 3 AgCl, 2 AgCl, 1 AgCl
D 2 AgCl, 3 AgCl, 1 AgCl

The correct answer is:
3 AgCl, 2 AgCl, 1 AgCl

Solution:
[Co(NH3)6]Cl3→AgNO33 moles of AgCl
[Co(NH3)5Cl]Cl2→AgNO32 moles of AgCl
[Co(NH3)4Cl2]Cl→AgNO31 mole of AgCl
The complexes are respectively CoNH36Cl3, CoNH35ClCl2 and CoNH34Cl2Cl.

Topic: Chemistry, Coordination Compounds, NEET, NEET 2017
The correct order regarding the electronegativity of hybrid orbitals of carbon is:

Options:
A $s p < s p^2 < s p^3$
B $s p>s p^2 < s p^3$
C $s p>s p^2>s p^3$
D $s p < s p^2>s p^3$

The correct answer is:
$s p>s p^2>s p^3$

Solution:
In $s p, s p^2$ and $s p^3$ hybrid orbitals, the $s$-orbital character is $50 \%, 33.3 \%$ and $25 \%$, respectively, and because of the higher $s$-orbital character, electronegativity, increases.
Related Theory
The electrons of $s p^3$ hybridized atom are farther from the nucleus than those in $s p^2$ hybridized species. Therefore, $s p^2$ hybrid species are more stable than $s p^3$ hybrid species. This is because the stability is greater when the electrons are close to the nucleus.

Topic: Chemistry, Chemical Bonding and Molecular Structure, NEET, NEET 2006
The correct pathway of milk ejection from mammary glands is

(i) Sensory impulses are transmitted through somatic nerves from the nipples to the mother's spinal cord and then to her hypothalamus.
(ii) Expulsion of milk from alveoli into the ducts.
(iii) Suckling action of baby on the breast.
(iv) Contraction of myoepithelial cells.
(v) Secretion of oxytocin.

Options:
A (iv), (iii), (v), (i) & (ii)
B (iii), (i), (v), (ii) & (iv)
C (iii), (i), (v), (iv) & (ii)
D (iv), (iii), (i), (v) & (ii)

The correct answer is:
(iii), (i), (v), (iv) & (ii)

Solution:
The mechanism by which milk is transported from the breast alveoli to the nipple is called milk ejection reflex. Suckling pf nipples by the baby Sensory impulses are transmitted through somatic nerves from the nipples to the mother's spinal cord and then to her hypothalamus (paraventricular nuclei and supraoptic nucleus). They send signals to the posterior pituitary gland to produce oxytocin. Oxytocin stimulates contraction of the myoepithelial cells surrounding the alveoli, which already hold milk. The increased pressure causes milk to flow through the duct system and be released through the nipple. This response can be conditioned e.g. to the cry of the baby.

Topic: Biology, Human Reproduction, NEET
The correct relation between the angle of diffraction ϕ and the glancing angle θ in Davisson - Germer experiment will be

Options:
A θ=90o-ϕ2
B ϕ=θ2-90o
C θ=90o-ϕ
D ϕ=90o-θ

The correct answer is:
θ=90o-ϕ2

Solution:
From the diagram, Î¸=90o-Ï2

Topic: Physics, Atomic Physics, NEET
The correct relation between the angle of diffraction ϕ and the glancing angle θ in the Davisson-Germer experiment will be

Options:
A θ=90°-ϕ2
B ϕ=θ2-90°
C θ=90°-ϕ
D ϕ=90°-θ

The correct answer is:
θ=90°-ϕ2

Solution:

Topic: Physics, Atomic Physics, NEET
The correct relation between the elevation in boiling point and the molar mass of a solute is: ( W 1 and W 2 are respectively weight of solvent & solute)

Options:
A M 2 = K b × W 2 ×1000 ΔT b × W 1
B M 2 = K b × W 1 ×1000 ΔT b × W 2
C M 2 = ΔT b × K b ×1000 W 1 × W 2
D M 2 = ΔT b × W 1 ×1000 K b × W 2

The correct answer is:
M 2 = K b × W 2 ×1000 ΔT b × W 1

Solution:
Î T b = K b Ã W 2 Ã 1 0 0 0 W 1 Ã M 2
M 2 = K b × W 2 ×1000 ΔT b × W 1

Topic: Chemistry, Solutions, NEET
The correct relation for freundlich isotherm is

Options:
A log(x/m)=logk + nlog(p)
B log(x/m)=logk + (1/n)log(p)
C log(x/m)=logk + n2(log p)
D log(x/m)=logk - (1/n)log(p)

The correct answer is:
log(x/m)=logk + (1/n)log(p)

Solution:
Correct Option is : 2
log(x/m)=logk + (1/n)log(p)

Topic: Chemistry, Surface Chemistry, NEET
The correct relationship between pH of isomolar solution of sodium oxide (pH1) , sodium sulphide (pH2) , sodium selenoid (pH3) and sodium selenide (pH4) is

Options:
A pH1>pH2>pH3>pH4
B pH1<pH2<pH3≤pH4
C pH1<pH2<pH3<pH4
D pH1>pH2=pH3>pH4

The correct answer is:
pH1>pH2>pH3>pH4

Solution:
The correct relationship between pH of isomolar solution of sodium oxide (pH1) , sodium sulphide (pH2) , sodium selenide (pH3) and sodium telluride (pH4) is given as
pH1>pH2>pH3>pH4
As there equimolar solution are used and on their dissolution NaOH, NaOH + H2S , NaOH + H2Se and NaOH + H2Te are formed respectively so pH will decrease.
H 2 S <  H 2 Se <  H 2 Te (Acidity order)

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), NEET
The correct relationship between the free energy change in a reaction and the corresponding equilibrium constant K is

Options:
A − ΔG o =RTlnK
B ÎG=RTlnK
C -ÎG=RTlnK
D ΔG o  = RTlnK

The correct answer is:
− ΔG o =RTlnK

Solution:
ÎGâ=â ÎG o â+âRTlnk
At equilibrium
ÎG=0
So − ΔG o  = RTlnK

Topic: Chemistry, Electrochemistry, NEET
The correct representation of binomial nomenclature is

Options:
A Brassica indica
B Mangifera Indica
C SOLANUM TUBEROSUM
D MIMOSA pudica

The correct answer is:
Brassica indica

Solution:
As per the binomial system of nomenclature,â the botanical name consists of generic epithet. The names are written in italic, generic name begins with a capital letter and the specific name begins with a small letter, e.g., Brassica indica.

Topic: Biology, The Living World, NEET