datavorous/entrance-exam-dataset huggingface dataset:
Copper crystallizes into a fcc lattice with an edge length of 3.61 × 10⁻⁸ cm. Show that the calculated density is in agreement with its measured value of 8.92 g/cm³.

Options:
A The calculated density is in agreement.
B The calculated density is higher.
C The calculated density is lower.
D Not enough information to determine.

The correct answer is:
The calculated density is in agreement.

Solution:
Correct Option is : (A)
The calculated density is in agreement.

Topic: Chemistry, Solid State, NEET
Copper has face centered cubic (fcc) lattice with interatomic spacing equal to $2.54 Å$. The value of lattice constant for this lattice is:

Options:
A $2.54 Å$
B $3.59 Å$
C $1.27 Å$
D $5.08 Å$

The correct answer is:
$3.59 Å$

Solution:
Given $2 \pi=2.54 Å$
$$
\Rightarrow \quad r=\frac{2.54}{2}=1.27 Å
$$
For fcc lattice:
$$
\begin{aligned}
r & =\frac{a}{2 \sqrt{2}} \\
a & =r 2 \sqrt{2} \\
& =1.27 \times 2 \times 1.44 \\
& =3.59 \mathrm{~A}^{\circ}
\end{aligned}
$$

Topic: Chemistry, Solid State, NEET, NEET 2005
Copper is absorbed in which form ?

Options:
A Cuperrous
B Cupric
C Elemental Copper
D Copper Sulphate

The correct answer is:
Cupric

Solution:
Copper is absorbed in the form of Cupric ions.

Topic: Biology, Mineral Nutrition, NEET
Copper metal has a specific heat of 0.385 J/ g°C and has melting point of 1083°C. Calculate the amount of heat required to raise the temperature of 22.8 g of Cu from 20.0 °C to 875 °C .

Options:
A 1.97×10-5J
B 1.0×10-2J
C 329 J
D 7.50 kJ

The correct answer is:
7.50 kJ

Solution:
Q=mC.(ΔT)
So Q=22.8g×0.385Jg-1°C-1×(875°C-20°C)
=22.8×0.385×855J=7.50×103J
=7.50 kJ.

Topic: Chemistry, Thermodynamics (C), NEET
Copper of fixed volume V is drawn into wire of length l. When this wire is subjected to a constant force F, the extension produced in the wire is ∆l. Which of the following graph is a straight line?

Options:
A ∆l versus 1/l
B ∆l versus l2
C ∆l versus 1/l2
D ∆l versus l

The correct answer is:
∆l versus l2

Solution:
V=Al
Y=F/A∆ll
Y∆ll=FA
∆l=FlYA=FY.llV
∆l=FYVl2
∆l∝l2

Topic: Physics, Mechanical Properties of Solids, NEET, NEET 2014
Copper releasing IUD is

Options:
A Diaphragm
B Vault
C LNG-20
D Multiload 375

The correct answer is:
Multiload 375

Solution:
An intrauterine device (IUD) is a small, flexible plastic or stainless steel frame which is inserted in the uterine cavity. In copper IUDs, CuT, Multiload 375, the copper wire is put on the frame. Copper IUD device is also called as Paragard and is T shaped. The copper wire coiled around the frame produces an inflammatory reaction which is toxic to the sperm and eggs thereby preventing pregnancy.

Topic: Biology, Reproductive Health, NEET
Copper sulphate dissolves in excess of $\mathrm{KCN}$ to give:

Options:
A $\mathrm{Cu}(\mathrm{CN})_2$
B $\mathrm{CuCN}$
C $[\mathrm{Cu}(\mathrm{CN}) 4]^{3-}$
D $\left[\mathrm{Cu}(\mathrm{CN})_4\right]^{2-}$

The correct answer is:
$[\mathrm{Cu}(\mathrm{CN}) 4]^{3-}$

Solution:
$\mathrm{CuSO}_4+2 \mathrm{KCN} \rightarrow \mathrm{Cu}(\mathrm{CN})_2+\mathrm{K}_2 \mathrm{SO}_4$
Cupric cyanide
$$
\begin{array}{r}
2 \mathrm{Cu}(\mathrm{CN})_2 \rightarrow 2 \mathrm{Cu}(\mathrm{CN})+\mathrm{NC}-\mathrm{CN} \\
\text { Cyanogen } \\
\mathrm{Cu}(\mathrm{CN})+3 \mathrm{KCN} \rightarrow \mathrm{K}_3\left[\mathrm{Cu}(\mathrm{CN})_4\right]
\end{array}
$$
Soluble complex salt

Topic: Chemistry, Coordination Compounds, NEET, NEET 2006
Copper sulphate solution does not react with

Options:
A Zinc
B Iron
C Silver
D All of these

The correct answer is:
Silver

Solution:
CuSO4will react with elements placed above it in electrochemical series and it would not react with elements places below it in electrochemical series.
∴ CuSO4 reacts with Zn and Fe placed above it.
CuSO4 + Fe → FeSO4 + Cu
CuSO4 + Zn → ZnSO4 + Cu
∴ CuSO4 does not react with Ag, placed below it.
CuSO4 + Ag → no reaction.

Topic: Chemistry, Electrochemistry, NEET
Coralloid roots of Cycas are useful in

Options:
A N2 -fixation
B Absorption
C Transpiration
D Fixation

The correct answer is:
N2 -fixation

Solution:
Anabaena, Nostoc and other cyanobacteria are found in coralloid roots hence it helps in fixation/absorption of nitrogen. The coralloid roots containing these symbiotic cyanobacteria (blue-green algae), apart from fixing nitrogen produce beneficial amino acids asparagine and citrulline.

Topic: Biology, Mineral Nutrition, NEET
Cork cambium results in the formation of cork which becomes impermeable to water due to the accumulation of

Options:
A Resins
B Suberin
C Lignins
D Tannins

The correct answer is:
Suberin

Solution:
Cork is an impermeable buoyant material, the phellem layer of bark tissue that is harvested for commercial use primarily from Quercus suber (the cork oak). Cork is composed of suberin, a hydrophobic substance. Because of its impermeable, buoyant, elastic, and fire retardant properties, it is used in a variety of products, the most common of which is wine stoppers.

Topic: Biology, Anatomy of Flowering Plants, NEET
Corm is a modification of

Options:
A Root
B Leaf
C Stem
D Bud

The correct answer is:
Stem

Solution:
A stem is modified into various forms to perform a variety of functions like storage, vegetative propagation, etc. A corm is a type of underground modified stem which is spherical, branched, vertically growing with a diameter more than length. It bears reduced nodes and internodes.

Topic: Biology, Morphology of Flowering Plants, NEET
Corn is a crop plant. Glow-worms are organisms which give off light. Which process could use these two species to make corn plants which glow?

Options:
A breeding the organisms together
B causing mutations in the organisms
C selective breeding
D transferring genes from one species to another species

The correct answer is:
transferring genes from one species to another species

Solution:
Corn been a plant and glow-worm been of animal origin, breeding process is not applicable. Genetic engineering process can be applied where the desired gene is transferred in to the organism via different methods of biotechnology.

Topic: Biology, Biotechnology and Its Applications, NEET
Corn is immersed in the boiling water. It is then cooled, the solution becomes sweet. It is due to

Options:
A Enzymes are inactivated in boiling water
B Polysaccharides are converted to monosaccharides
C Monosaccharides are converted to disaccharides
D None of these

The correct answer is:
Polysaccharides are converted to monosaccharides

Solution:
The corn/Maize kernel comprises of endosperm that is rich in starch. Due to heating effect, the polysaccharides are broken down/dissociated into monosaccharides, which are sweet in nature.

Topic: Chemistry, Biomolecules, NEET
Cornea transplant in humans is almost never rejected. This is because

Options:
A its cells are least penetrable by bacteria
B it has no blood supply
C it is composed of enucleated cells
D it is a non-living layer

The correct answer is:
it has no blood supply

Solution:
Cornea is a transparent portion that forms the anterior one-sixth of the eyeball. The cornea admits and helps to focus light waves as they enter the eye. It is avascular, $i e$, has no blood supply therefore, cornea transplant in human is almost never rejected.

Topic: Biology, Neural Control and Coordination, NEET, NEET 2008 (Screening)
Cornea transplantation is outstandingly successful because

Options:
A Cornea is easy to preserve
B Cornea is not linked up with blood vascular and immune systems
C The technique involved is very simple
D Cornea is easily available

The correct answer is:
Cornea is not linked up with blood vascular and immune systems

Solution:
Cornea transplants are easy because there are no blood vessels involved. It is an immunocompromised area and hence, the graft rejecting molecules are absent.

Topic: Biology, Human Health and Diseases, NEET
Coronavirus is highly dangerous and life-threatening for elderly. This is due to a progressive decrease in secretion of

Options:
A Adrenaline
B Vasopressin
C Thymosin
D FSH

The correct answer is:
Thymosin

Solution:
The thymus is degenerated in elderly resulting in a decreased production of thymosins. As a result, the immune responses of the elderly become weak.

Topic: Biology, Chemical Coordination and Integration, NEET
Corpus luteum secretes a hormone called

Options:
A Prolactin
B Progesterone
C Aldosterone
D Testosterone

The correct answer is:
Progesterone

Solution:
Option (b) is the answer.

Topic: Biology, Chemical Coordination and Integration, NEET
Correct increasing order for the wavelengths of absorption in the visible region the complexes of Co3+ is

Options:
A [Co(H2O)6]3+,[Co(en)3]3+,[Co(NH3)6]3+
B [Co(H2O)6]3+,[Co(NH3)6]3+,[Co(en)3]3+
C [Co(NH3)6]3+,[Co(en)3]3+,[Co(H2O)6]3+
D [Co(en)3]3+,[Co(NH3)6]3+,[Co(H2O)6]3+

The correct answer is:
[Co(en)3]3+,[Co(NH3)6]3+,[Co(H2O)6]3+

Solution:
The increasing order for the wavelengths of absorption in the visible region for the complexes of Co3+ is [Co(en)3]3+<[Co(NH3)6]3+<[Co(H2O)6]3+ .
The decreasing order of ligands strength is en>NH3>H2O . Strong ligand causes greater splitting between two energy levels.
The energy of light absorbed is more and the wavelength of light absorbed is less for the strong ligand.

Topic: Chemistry, Solid State, NEET
Correct position of floral parts over thalamus in mustard plant is:

Options:
A Gynoecium occupies the highest position, while the other parts are situated below it
B Margin of the thalamus grows upward, enclosing the ovary completely, and other parts arise below the ovary
C Gynoecium is present in the centre and other parts cover it partially
D Gynoecium is situated in the centre, and other parts of the flower are located at the rim of the thalamus, at the same level

The correct answer is:
Gynoecium occupies the highest position, while the other parts are situated below it

Solution:
Hypogyny: In a hypogynous flower, ovary occupies the topmost position on the thalamus, while the stamens, petals and sepals are separately and successively present below the ovary. The ovary in a hypogynous flower is said to be superior. E.g, Brinjal, China rose, mustard, etc.

Topic: Biology, Morphology of Flowering Plants, NEET, NEET 2020 (Phase 2)
Correct representation of 3-methylpent-3-en-2-ol is

Options:
A
B
C
D

The correct answer is:

Solution:

Topic: Chemistry, Alcohols Phenols and Ethers, NEET
Correct sequence among the following is

Options:
A Palaeozoic â Mesozoic â Cenozoic
B Mesozoic → Archaeozoic → Proterozoic
C Palaeozoic â Archaeozoic â Cenozoic
D Archaeozoic → Palaeozoic → Proterozoic

The correct answer is:
Palaeozoic → Mesozoic → Cenozoic

Solution:
The age of the earth is about 4.6 billion years. The history of earth has been divided into a number of eras. The eras are subdivided into periods. The modern periods are subdivided into epochs. The order is Proterozoic â Palaeozoic â Mesozoic â Cenozoic is the correct one.

Topic: Biology, Evolution, NEET
Correct sequence for reactivity of acid derivative is
1(RCO)2O
2RCOCl
3RCOOR
4RCONH2

Options:
A 2>1>3>4
B 1>2>3>4
C 2>1>4>3
D 1>3>2>4

The correct answer is:
2>1>3>4

Solution:
Reactivity of acid derivatives depends on nature of leaving groups. The leaving group order is -Cl>-OCOR>-OR>-NH2

Topic: Chemistry, Carboxylic Acid Derivatives, NEET
CORRECT sequence of evaluation and release of new cultivars is _________ .

(i) growing plants in natural fields in different agro-climatic zones.

(ii) growing plants in research fields under controlled conditions.

(iii) release of improved variety under a new name.

Options:
A (i)-(ii)-(iii)
B (ii)-(iii)-(i)
C (ii)-(i)-(iii)
D (ii) and (iii) only

The correct answer is:
(ii)-(i)-(iii)

Solution:
Cultivars are plant variety that has been obtained by selective breeding of plants. Plant breeding is a method to develop improved variety of crops. This is done in a stepwise manner - First the cultivar is grown in research field to record their performance under normal agricultural practices. This step is followed by growing the new crop in the farming field to check for qualities in different agro-climatic conditions. At the end the new tested variety is released with a new name in the market.

Topic: Biology, Strategies for Enhancement in Food Production, NEET
Correct stability order of the following cations is

Options:
A I > II > III
B III > I > II
C III > II > I
D II > III > I

The correct answer is:
III > I > II

Solution:
CH 2 = CH - C â H 2 â C â H 2 - CH = CH 2
I Stabilised by delocalisation and two equivalent resonating structure

CH 3 - CH 2 - C â H 2
II Stabilised by only +I & hyperconjugation 2Î±-H.
III It is stabilised by maximum delocalisation by forming four equivalent resonating structure.
The order of stability is III > I > II
Order of stability is:

Topic: Chemistry, General Organic Chemistry, NEET
Correct statement about restriction endonuclease.

(I) It is the enzyme which cuts DNA at a particular point.
(II) The first restriction endonuclease was HindII.
(III) Overall, 900 restriction enzymes have been isolated from about 200 strains.
(IV) Each restriction endonuclease recognizes a specific palindromic sequence.

Options:
A I and IV are correct
B I and II are incorrect
C I and III are incorrect
D I, II, and IV are correct.

The correct answer is:
I, II, and IV are correct.

Solution:
The first restriction endonuclease HindII whose functioning ws found to be dependent on a specific DNA nucleotide sequence was isolated and characterized 5 years later. It was found that HindII always cuts DNA molecules at a particular point by recognizing a specific sequence of six base pairs. This specific base sequence is known as the recognition sequence for HindII. Besides Hind II, today we know more than 900 restriction enzymes that have been isolated from over 230 strains of bacteria, each of which recognizes different recognition sequences. Each restriction endonuclease recognizes a specific palindromic sequence.

Topic: Biology, Biotechnology - Principles and Processes, NEET
Correctly identify the energy-yielding step of glycolysis.

Options:
A 2-phosphoglycerate to 2-phosphoenolpyruvate
B Fructose 1, 6-bisphosphate to PGAL and DHAP
C Fructose to fructose-6-phosphate
D Phosphoenolpyruvic acid to pyruvic acid

The correct answer is:
Phosphoenolpyruvic acid to pyruvic acid

Solution:
ATP is synthesizes in reaction when phosphoenol pyruvic acid is converted to pyruvic acid, this direct synthesis of ATP is called transphosphorylation or substrate level phosphorylation.

Topic: Biology, Respiration in Plants, NEET
Correctly identify the stage of cell division shown in the given diagram.

Options:
A Prophase-I
B Prophase-II
C Anaphase of Mitosis.
D Metaphase -II

The correct answer is:
Prophase-I

Solution:
Prophase - I
- It is subdivided into 5 phases :
A. Leptotene (Lepto = thin or delicate)
- Chromosomes gradually become visible.
- Condensation or compaction of the chromosomes continues.
B. Zygotene (Zygo = related to pairing or joining)
- Synapsis or pairing of chromosomes occur to bring the homologous chromosomes together.
- Synapsis is followed by the formation of synaptonemal complex (or bivalent or tetrad).
C. Pachytene (Pachy = thick)
- Bivalent chromosomes clearly appear as tetrad as condensation is in progress.
- In this stage crossing over occurs.
D. Diplotene (Diplo = double)
- Starting of diplotene is characterized by the dissolution of the synaptonemal complex and the
separation of the homologous chromosomes from each other except at the X shaped sites of cross
over. These X shapes sites are termed as Chiasmata.
E. Diakinesis (= Movement or separation of both)
- It is characterized by the terminalization of chiasmata.

Topic: Biology, Cell Cycle and Cell Division, NEET
Correctly match the column I with column II

Column I	Column II

a.	Aleurone layer	i.	Without fertilization

b.	Parthenocarpic fruit	ii.	Nutrition

c.	Scutellum	iii.	The scar on the seed coat

d.	Hilum	iv.	Cotyledon in monocot seed

Options:
A a-i, b-ii, c-iii, d-iv
B a-ii, b-i, c-iv, d-iii
C a-iv, b-ii, c-i, d-iii
D a-ii, b-iv, c-i, d-iii

The correct answer is:
a-ii, b-i, c-iv, d-iii

Solution:
Parthenocarpic fruits are developed without any fertilization of the ovary. These fruits are seedless. Seedless banana is an example. In monocot seeds, the large shield shape cotyledon is known as scutellum. The endosperm is covered by a proteinous layer called aleurone layer that separates the endosperm from the embryo and nourishes it. The attachment of seeds to fruit leaves a scar on a seed coat called hilum.

Topic: Biology, Morphology of Flowering Plants, NEET
Cortex is the region found between:

Options:
A Epidermis and stele
B Pericycle and endodermis
C Endodermis and pith
D Endodermis and vascular bundle

The correct answer is:
Epidermis and stele

Solution:
Cortex is the region present between epidermis and stele. The term cortex refers to the outermost layer of cells on a plant's stem or root. The cortex has the ability to transport nutrients into the core of the root. It uses diffusion to achieve transport. It also stores nutrients in the form of starch.
The cortex acts as a protective covering on plant and is often waterproof. Depending on the type of plant, the cortex can also store carbohydrates, tannins, essential oils, and resins.

Topic: Biology, Anatomy of Flowering Plants, NEET, NEET 2016 (Phase 2)
Cortical portions projecting between the medullary pyramids in the human kidney is known as___.

Options:
A Kidney
B Henle's loop
C Columns of Bertini
D Vasa recta

The correct answer is:
Columns of Bertini

Solution:
Cortical portions projecting between the medullary pyramids in the human kidney is known as columns of Bertini

Topic: Biology, Excretory Products and their Elimination, NEET
Cortisol is secreted by

Options:
A Pancrease
B Thyroid
C Adrenal
D Thymus

The correct answer is:
Adrenal

Solution:
Option (c) is the answer.

Topic: Biology, Chemical Coordination and Integration, NEET
CoSO4Cl.5NH3exists in two isomeric forms ‘A’ and ‘B’. Isomer ‘A’ reacts with AgNO3to give a white precipitate but does not react with BaCl2. Isomer ‘B’ gives a white precipitate with BaCl2but does not react with AgNO3. Answer the following questions.Name the type of isomerism involved.

Options:
A Geometric isomerism
B Ionization isomerism
C Linkage isomerism
D Coordination isomerism

The correct answer is:
Ionization isomerism

Solution:
Correct Option is : (B)
Ionization isomerism

Topic: Chemistry, Coordination Compounds, NEET
CoSO4Cl.5NH3exists in two isomeric forms ‘A’ and ‘B’. Isomer ‘A’ reacts with AgNO3to give a white precipitate but does not react with BaCl2. Isomer ‘B’ gives a white precipitate with BaCl2but does not react with AgNO3. Answer the following questionsGive the IUPAC name of ‘A’ and ‘B’.

Options:
A IUPAC name of 'A' is Pentaamminechlorocobalt(II)sulphate and 'B' is Pentaamminesulfatocobalt(II) chloride
B IUPAC name of 'A' is Pentaamminesulfatocobalt(II) chloride and 'B' is Pentaamminesulfatochlorocobalt(II)
C IUPAC name of 'A' is Chloropentaamminesulfatocobalt(II) and 'B' is Pentaamminesulfatocobalt(II) chloride
D IUPAC name of 'A' is Pentaamminesulfatocobalt(II) chloride and 'B' is Chloropentaamminesulfatocobalt(II)

The correct answer is:
IUPAC name of 'A' is Pentaamminesulfatocobalt(II) chloride and 'B' is Pentaamminesulfatochlorocobalt(II)

Solution:
Correct Option is : (B)
IUPAC name of 'A' is Pentaamminesulfatocobalt(II) chloride and 'B' is Pentaamminesulfatochlorocobalt(II)

Topic: Chemistry, Coordination Compounds, NEET
CoSO4Cl.5NH3exists in two isomeric forms ‘A’ and ‘B’. Isomer ‘A’ reacts with AgNO3to give a white precipitate but does not react with BaCl2. Isomer ‘B’ gives a white precipitate with BaCl2but does not react with AgNO3. Answer the following questions. Identify ‘A’ and ‘B’ and write their structural formulas.

Options:
A Isomer 'A' is [Co(NH3)5Cl]SO4and Isomer 'B' is [Co(NH3)5SO4]Cl
B Isomer 'A' is [Co(NH3)5SO4]Cl and Isomer 'B' is [Co(NH3)5Cl]SO4
C Isomer 'A' is [Co(NH3)5Cl]SO4and Isomer 'B' is [CoSO4(NH3)5]Cl
D Isomer 'A' is [CoSO4(NH3)5]Cl and Isomer 'B' is [Co(NH3)5Cl]SO4

The correct answer is:
Isomer 'A' is [Co(NH3)5Cl]SO4and Isomer 'B' is [Co(NH3)5SO4]Cl

Solution:
Correct Option is : (A)
Isomer 'A' is [Co(NH3)5Cl]SO4and Isomer 'B' is [Co(NH3)5SO4]Cl

Topic: Chemistry, Coordination Compounds, NEET
Cotton bollworms are controlled by certain proteins that are coded by

Options:
A cryIAc.
B cryIAb and cryIIAb.
C cryIAb and cryIAc.
D cryIAc and cryIIAb.

The correct answer is:
cryIAc and cryIIAb.

Solution:
cry gene : These are the various types of genes that code for the Bt toxins.
Example 1. cryIAc and cryIIAb code for proteins that control the cotton bollworms.
2. cryIAb code for proteins that control the corn borers.

Topic: Biology, Biotechnology and Its Applications, NEET
Cotyledon of maize grain is called:

Options:
A Plumule
B Coleorhiza
C Coleoptile
D Scutellum

The correct answer is:
Scutellum

Solution:
In maize grains, the single large shield-shaped cotyledon is called scutellum. The scutellum is believed to contain an as yet unidentified protein transporter that facilitates starch movement from the endosperm to the embryo.

Coleoptile is a sheath-like structure that protects the young shoot tip in monocots.

Coleorhiza is another sheath-like structure that protects the young root tip in monocots.

Plumule is the rudimentary shoot or stem of an embryo plant.

Topic: Biology, Morphology of Flowering Plants, NEET, NEET 2016 (Phase 1)
Cotyledons and testa are edible parts of

Options:
A groundnut and pomegranate
B walnut and tamarind
C french bean and coconut
D cashew nut and litchi

The correct answer is:
groundnut and pomegranate

Solution:
Cotyledons and testa are edible parts of groundnut and pomegranate respectively.
The edible part of walnut is cotyledon; tamarind-mesocarp; french bean-seeds, coconut-endosperm, testa, cotyledons and embryo, cashewnut-cotyledons and fleshy pedicels and of litchi is fleshy aril.

Topic: Biology, Morphology of Flowering Plants, NEET, NEET 2009 (Screening)
Could the number of eggs or young ones produced by an Oviparous and viviparous mother be equal?

Options:
A Yes
B No
C Not given
D Maybe Yes

The correct answer is:
No

Solution:
No, the number of eggs or young ones produced by an oviparous and viviparous mother are not equal.

Topic: Biology, Animal Kingdom, NEET
Coulomb's law is valid for

Options:
A charged particles separated by atomic distances (10 â11 m) .
B charged particles separated by nuclear distances (10 â15 m) .
C charged as well as uncharged particles separated by any distances.
D charged particles separated by any distances.

The correct answer is:
charged particles separated by any distances.

Solution:
Coulomb's law is true for all distances small and large. Hence, it is called a long-range force.

Topic: Physics, Electrostatics, NEET
Cow milk, an example of natural emulsion is stabilised by

Options:
A Fat
B Water
C Casein
D Mg2+ions

The correct answer is:
Casein

Solution:
Cow milk is stabilized by casein.

Topic: Chemistry, Biomolecules, NEET
C-peptide of human insulin is:

Options:
A A part of mature insulin molecule
B Responsible for formation of disulphide bridges
C Removed during maturation of pro-insulin to insulin
D Responsible for its biological activity

The correct answer is:
Removed during maturation of pro-insulin to insulin

Solution:
C-peptide of human insulin is removed during maturation of pro-insulin to insulin.

Topic: Biology, Biotechnology and Its Applications, NEET