datavorous/entrance-exam-dataset huggingface dataset:
Following are given differences between red muscle fibres and white muscle fibres. Which of them is/are incorrect?

Characteristic	Red fibres	White fibres

a	Myoglobin content	High	Low

b	Sarcoplasmic reticulum content	High	Low

c	Number of mitochondria	High	Low

d	Type of respiration	Aerobic	Anaerobic

Options:
A Only b
B b and c
C b and d
D All the characteristics are correctly matched

The correct answer is:
Only b

Solution:
Muscle contains a red coloured oxygen storing pigment called myoglobin. Myoglobin content is high in some of the muscles which gives a reddish appearance. Such muscles are called the Red fibres. These muscles also contain plenty of mitochondria which can utilise the large amount of oxygen stored in them for ATP production. These muscles, therefore, can also be called aerobic muscles. On the other hand, some of the muscles possess very less quantity of myoglobin and therefore, appear pale or whitish. These are the White fibres. Number of mitochondria are also few in them, but the amount of sarcoplasmic reticulum is high. They depend on anaerobic process for energy.

Topic: Biology, Locomotion and Movement, NEET
Following are given sequences of mRNA. Identify the one that will not undergo complete translation.

Options:
A 5′Â AUGÂ UUCÂ AGCÂ UCGÂ UGAÂ 3′Â
B 5′Â AUGÂ CCAÂ UACÂ GACÂ UAGÂ 3′
C 5′AUGÂ UUAÂ CUCÂ GCGÂ UAAÂ 3′Â
D 5′AUGÂ AACÂ UAAÂ CCAÂ CUCÂ 3′

The correct answer is:
5′AUGÂ AACÂ UAAÂ CCAÂ CUCÂ 3′

Solution:
For translation of mRNA, the unit has a sequence of start codon AUG with a terminating codon UAA/UAG/UGA . In option D, the third codon is UAA which is stop codon. So the fourth and fifth codons of this mRNA will not be completely translated

Topic: Biology, Molecular Basis of Inheritance, NEET
Following are some events of mitotic cell division, select the correct order in which these events occur.

(i) Condensation of chromosomes is completed

(ii) Chromosomes lose their identity as discrete elements

(iii) Sister chromatids separate

(iv) Initiation of the assembly of the mitotic spindle

Options:
A iÂ âÂ iiÂ âÂ iiiÂ âÂ iv
B iv â i â iii â ii
C ii â i â iv â iii
D ivÂ âÂ iiiÂ âÂ iÂ âÂ ii

The correct answer is:
ii â i â iv â iii

Solution:
Initiation of the assembly of mitotic spindle occurs during prophase. The condensation of the chromosome is completed during metaphase. Sister chromatids separate due to splitting of centromere during anaphase. Daughter reaches opposite poles and undergoes decondensation as a result hromosome lost their identity as discrete elements during telophase.

Topic: Biology, Cell Cycle and Cell Division, NEET
Following are some features of cockroach:

I. Number of ovarioles in a female cockroach (Ov)

II. The average number of oothecae produced by a female cockroach (Ot)

III. The number of times a nymph of cockroach undergoes moulting (M)

IV. The number of gastric caecae present in cockroach (G)

The correct arrangement of these in their increasing order is

Options:
A G < Ov < Ot < M
B G < Ov < M < Ot
C Ov < G < Ot < M
D G < Ot < M < Ov

The correct answer is:
G < Ot < M < Ov

Solution:
I. Number of ovarioles in a female cockroach (Ov) is 16 (8 ovarioles in one ovary and cockroach has 2 ovaries)
II. The average number of oothecae produced by a female cockroach (Ot) is 9 -10
III. The number of times a nymph of cockroach undergoes moulting (M) is 13 times
IV. The number of gastric caecae present in cockroach (G) is 6-8 which lies between the junction of foregut and hindgut

Topic: Biology, Structural Organisation in Animals, NEET
Following are the stages of cell division :
A. Gap 2 phase
B. Cytokinesis
C. Synthesis phase
D. Karyokinesis
E. Gap 1 phase
Choose the correct sequence of stages from the options given below :

Options:
A E-B-D-A-C
B B-D-E-A-C
C E-C-A-D-B
D C-E-D-A-B

The correct answer is:
E-C-A-D-B

Solution:
The correct sequence of stages of cell division is
The correct sequence will be $\rightarrow \mathrm{E} \rightarrow \mathrm{C} \rightarrow \mathrm{A} \rightarrow \mathrm{D} \rightarrow \mathrm{B}$

Topic: Biology, Cell Cycle and Cell Division, NEET, NEET 2024
Following are the stages of pathway for conduction of an action potential through the heart
A. AV bundle
B. Purkinje fibres
C. AV node
D. Bundle branches
E. SA node
Choose the correct sequence of pathway from the options given below

Options:
A A-E-C-B-D
B B-D-E-C-A
C E-A-D-B-C
D E-C-A-D-B

The correct answer is:
E-C-A-D-B

Solution:
Correct answer is option (4) because the correct pathway of conduction of action potential is $\mathrm{SA} \rightarrow \mathrm{AV}$ node $\rightarrow$ AV bundle $\rightarrow$ Bundle branches $\rightarrow$ Purkinje fibres

Topic: Biology, Body Fluids and Circulation, NEET, NEET 2024
Following are the statements about prostomium of earthworm.
(a) It serves as a covering for the mouth.
(b) It helps to open cracks in the soil into which it can crawl.
(c) It is one of the sensory structures.
(d) It is the first body segment.

Options:
A (a), (b) and (c) are correct
B (a), (b) and (d) are correct
C (a), (b), (c) and (d) are correct
D (b) and (c) are correct

The correct answer is:
(a), (b) and (c) are correct

Solution:
In an earthworm, the anterior end of the body consists of the mouth and the prostomium. The prostomium is a lobe that acts as a covering for the mouth and serves as a wedge to force open cracks in the soil into which the earthworm may crawl. The prostomium is sensory in function. The first segment of the body is called the peristomium.

Topic: Biology, Structural Organisation in Animals, NEET, NEET 2021
Following are the statements with reference to 'lipids'.
(a) Lipids having only single bonds are called unsaturated fatty acids.
(b) Lecithin is a phospholipid.
(c) Trihydroxy propane is glycerol.
(d) Palmitic acid has 20 carbon atoms including carboxyl carbon.
(e) Arachidonic acid has 16 carbon atoms. Choose the correct answer from the options given below.

Options:
A (a) and (b) only
B (c) and (d) only
C (b) and (c) only
D (b) and (e) only

The correct answer is:
(b) and (c) only

Solution:
The correct statements about lipids are:

(1) Lipids having only single bonds are called saturated fatty acids, while those having single, double and triple bonds are called unsaturated fatty acids.
(2) Lecithin is a phospholipid.
(3) Trihydroxy propane or Propane-1,2 3-triol is glycerol.
(4) Palmitic acid has 16 carbon atoms including carboxyl carbon.
(5) Arachidonic acid has 20 carbon atoms including carboxyl carbon.

Topic: Biology, Biomolecules (B), NEET, NEET 2021
Following are the steps involved in action of toxin in Bt. Cotton
A. The inactive toxin converted into active form due to alkaline pH of gut of insect.
B. Bacillus thuringiensis produce crystals with toxic insecticidal proteins.
C. The alkaline pH solubilises the crystals.
D. The activated toxin binds to the surface of midgut cells, creates pores and causes death of the insect.
E. The toxin proteins exist as inactive protoxins in bacteria.
Choose the correct sequence of steps from the options given below:

Options:
A $\mathrm{E} \rightarrow \mathrm{C} \rightarrow \mathrm{B}
B $\mathrm{B} \rightarrow \mathrm{C} \rightarrow \mathrm{A} \rightarrow \mathrm{E} \rightarrow \mathrm{D}$
C $\mathrm{A} \rightarrow \mathrm{E} \rightarrow \mathrm{B} \rightarrow \mathrm{D} \rightarrow \mathrm{C}$
D $\mathrm{B} \rightarrow \mathrm{E} \rightarrow \mathrm{C} \rightarrow \mathrm{A} \rightarrow \mathrm{D}$

The correct answer is:
$\mathrm{B} \rightarrow \mathrm{E} \rightarrow \mathrm{C} \rightarrow \mathrm{A} \rightarrow \mathrm{D}$

Solution:
Option (4) is the correct answer because the correct sequence of action of toxin in Bt. cotton is
B. Bacillus thuringiensis produces crystals with toxic insecticidal proteins.
E. The toxin proteins exist as inactive protoxins in bacteria.
C. The alkaline pH solubilises the crystals.
A. The inactive toxin converted into active form due to alkaline pH of gut of insect.
D. The activated toxin binds to the surface of midgut cells, creates pores and causes death of the insect.
Hence, $\mathrm{B} \rightarrow \mathrm{E} \rightarrow \mathrm{C} \rightarrow \mathrm{A} \rightarrow \mathrm{D}$ is the correct order.

Topic: Biology, Microbes in Human Welfare, NEET, NEET 2024 (Re-NEET)
Following are the steps involved in the process of PCR.
A. Annealing
B. Amplification ( $\sim 1$ billion times)
C. Denaturation
D. Treatment with Taq polymerase and deoxynucleotides
E. Extension
Choose the correct sequence of steps of PCR from the options given below :

Options:
A $\mathrm{C} \rightarrow \mathrm{A} \rightarrow \mathrm{D} \rightarrow \mathrm{E} \rightarrow \mathrm{B}$
B $\mathrm{A} \rightarrow \mathrm{B} \rightarrow \mathrm{E} \rightarrow \mathrm{D} \rightarrow \mathrm{C}$
C $\mathrm{A} \rightarrow \mathrm{C} \rightarrow \mathrm{E} \rightarrow \mathrm{D} \rightarrow \mathrm{B}$
D $\mathrm{D} \rightarrow \mathrm{B} \rightarrow \mathrm{E} \rightarrow \mathrm{C} \rightarrow \mathrm{A}$

The correct answer is:
$\mathrm{C} \rightarrow \mathrm{A} \rightarrow \mathrm{D} \rightarrow \mathrm{E} \rightarrow \mathrm{B}$

Solution:
The correct answer is option (1) as the correct sequence of steps involved in the process of PCR are :
(C) Denaturation
(A) Annealing
(D) Treatment with Taq polymerase and deoxynucleotides
(E) Extension
(B) Amplification ( $\sim 1$ billion times).
That is $\mathrm{C} \rightarrow \mathrm{A} \rightarrow \mathrm{D} \rightarrow \mathrm{E} \rightarrow \mathrm{B}$
Option (2), (3) and (4) are incorrect as they represent incorrect sequence.

Topic: Biology, Biotechnology - Principles and Processes, NEET, NEET 2024 (Re-NEET)
Following are the two statements regarding the origin of life:

(i) The earliest organisms that appeared on the earth were non-green and presumably anaerobes.

(ii) The first autotrophic organisms were the chemoautotrophs that never released oxygen.

Of the above statements which one of the following options is correct?

Options:
A (i) is correct but (ii) is false
B (ii) is correct but (i) is false
C Both (i) and (ii) are correct
D Both (i) and (ii) are false

The correct answer is:
Both (i) and (ii) are correct

Solution:
The first originated organisms were prokaryotic chemoheterotrophs and oxygen was not available on earth at that time so it must be anaerobic too. Even the first autotrophs were dependent on chemicals as oxygen was not released.

Topic: Biology, Evolution, NEET, NEET 2016 (Phase 1)
Following circuit is equivalent to

Options:
A AND gate
B OR gate
C NOT gate
D X-OR gate

The correct answer is:
OR gate

Solution:
Y=Ā.B̄¯=A+B
i.e. OR gate

Topic: Physics, Semiconductors, NEET
Following data is for a reaction between reactants A and B :
The order of the reaction with respect to $A$ and $B$, respectively, are

Options:
A 1,0
B 0,1
C 1,2
D 2,1

The correct answer is:
1,2

Solution:
Let the rate equation is
Rate $=\mathrm{k}[\mathrm{A}]^{\mathrm{x}}[\mathrm{B}]^{\mathrm{y}}$
Therefore, we can write
$2 \times 10^{-3}=k[0.1] \times\left[0.1 \rrbracket^y\right.$...(i)
$4 \times 10^{-3}=k[0.2]^x[0.1]^y$...(ii)
$1.6 \times 10^{-2}=\mathrm{k}[0.2]^{\times}[0.2]^{\mathrm{y}}$...(iii)
(ii) $\div$ (i);
$\frac{4 \times 10^{-3}}{2 \times 10^{-3}}=\frac{k[0.2]^x[0.1]^y}{k[0.1]^x[0.1]^y}$
$\Rightarrow \quad \frac{2}{1}=\frac{(0.2)^x}{(0.1)^x}=\left(\frac{2}{1}\right)^x$
$\therefore \quad x=1$
(ii) $\div$ (iii);
$\frac{4 \times 10^{-3}}{1.6 \times 10^{-2}}=\frac{k[0.2]^{\mathrm{x}}[0.1]^y}{\mathrm{k}[0.2]^{\mathrm{x}}[0.2]^{\mathrm{y}}}$
$\Rightarrow \quad \frac{1}{4}=\frac{(0.1)^y}{(0.2)^y}=\left(\frac{1}{2}\right)^y$
$\therefore \quad y=2$
$\therefore \quad$ Rate $=k[A]^1[B]^2$
First order with respect to A while second order with respect to B .

Topic: Chemistry, Chemical Kinetics, NEET, NEET 2024 (Re-NEET)
Following data is given for the reaction: CaCO3(s) → CaO (s) + CO2(g) ∆f H [CaO(s)] = – 635.1 kJ mol–1∆f H [CO2(g)] = – 393.5 kJ mol–1∆f H [CaCO3(s)] = – 1206.9 kJ mol–1Predict the effect of temperature on the equilibrium constant of the above reaction.

Options:
A 178.3 kJ mol–1
B 181.1 kJ mol-1
C 196.55 kJ mol-1
D 137.0 kJ mol-1

The correct answer is:
178.3 kJ mol–1

Solution:
Correct Option is : (A)
178.3 kJ mol–1

Topic: Chemistry, Ionic Equilibrium, NEET
Following diagram performs the logic function of:

Options:
A AND gate
B NAND gate
C OR gate
D XOR gate

The correct answer is:
AND gate

Solution:
$$
\begin{aligned}
& x=\overline{\mathrm{A} \cdot \mathrm{B}}, y=\bar{x}=\overline{\overline{\mathrm{A} \cdot \mathrm{B}}} \\
& \Rightarrow \text { AND-gate. }
\end{aligned}
$$

Topic: Physics, Semiconductors, NEET, NEET 2003
Following features belong to which syndrome?

(I) Furrowed tongue

(II) Palm is broad with characteristic palm crease.

(III) Physical and mental retardation

(IV) Short statured with small round head.

Options:
A Down's syndrome
B Turner's syndrome
C Klinefelter's syndrome
D Cri du chat syndrome

The correct answer is:
Down's syndrome

Solution:
Down's syndrome is due to an extra chromosome number 21. The patient's cells have 3 copies of 21st chromosome (Trisomy 21) instead of homologous pair. It occurs due to failure of separation of homologous chromosomes or non-disjunction during meiosis (gamete formation). Symptoms of Down's syndrome:
a Patients show Mental retardation
b Due to poor skeletal development, they have short stature and relatively small skull
c Their face is typically flat with rounded flat nose
d They have an open mouth, protruding tongue and a high arched palate.
e Most children show typical facial features with a fold of skin (epicanthal skin fold) over the inner corner of the eye. This results in downward slanting of eyelids.
f They have flat hand with characteristic crease which runs all the way across the palm (Simian crease).

Topic: Biology, Principles of Inheritance and Variation, NEET
Following figures show the arrangement of bar magnets in different configurations. Each magnet has magnetic dipole m→. Which configuration has highest net magnetic dipole moment?

Options:
A
B
C
D

The correct answer is:

Solution:
a Mnet=m2+m2+2mmcos⁡90o=2 m

b Mnet=m-m=0

c Mnet=m2+m2+2 mmcos⁡30o=m2+3
d Mnet=m2+m2+2 mmcos⁡60o=3 m
is configuration C θ is least so Mnet is maximum.

Topic: Physics, Magnetic Effects of Current, NEET, NEET 2014
Following graphs show the effect of change in concentration of substrate on enzyme activity:

Graph - A:

Graph - B:

Graph - C:

Graph - D:

In which of the above curve, the enzyme shows maximum substrate affinity?

Options:
A Graph - A
B Graph - B
C Graph - C
D Graph - D

The correct answer is:
Graph - B

Solution:
Km indicates the affinity of the enzyme towards its substrate.
Km = 12 Vmax
Km value differs from substrate to substrate because different enzymes differ in their affinity towards different substrates. A high Km indicates low affinity, whereas a low Km shows strong affinity. Out of the given graphs, Km value is lowest in this option and hence shows maximum substrate affinity.

Topic: Chemistry, Biomolecules, NEET
Following graphs show the variation in the intensity of heat radiations by the black body and frequency at a fixed temperature. Choose the correct option.

Options:
A
B
C
D

The correct answer is:

Solution:
As the temperature of body increases, the frequency corresponding to maximum energy in radiation vm increases. This is shown in the graph.

Topic: Physics, Thermal Properties of Matter, NEET
Following graphs show the variation in the intensity of heat radiations by the black body and frequency at a fixed temperature. Choose the correct option.

Options:
A
B
C
D

The correct answer is:

Solution:
As the temperature of body increases, the frequency corresponding to maximum energy in radiation νm increases. This is shown in the graph.

Topic: Physics, Thermal Properties of Matter, NEET
Following group of symptoms belong to

Options:
A An autosomal recessive disease leading to accumulation of phenylalanine and its derivatives in the body
B A disease caused by early weaning of breast milk in infants
C A disease in which the cells of the female don't show any Barr body
D A chromosomal disorder due to extra copy of chromosome 21

The correct answer is:
A chromosomal disorder due to extra copy of chromosome 21

Solution:
The above symptoms are seen in Down's syndrome. Down's syndrome is due to an extra chromosome number 21. The patient's cells have 3 copies of 21st chromosome (Trisomy 21) instead of homologous pair. It occurs due to failure of separation of homologous chromosomes or non-disjunction during meiosis (gamete formation). Symptoms of Down's syndrome:
(i) Patients show Mental retardation
(ii) Due to poor skeletal development, they have short stature and relatively small skull
(iii) Their face is typically flat with rounded flat nose
(iv) They have an open mouth, protruding tongue and a high arched palate.
(v) Most children show typical facial features with a fold of skin (epicanthal skin fold) over the inner corner of the eye. This results in downward slanting of eyelids.
(vi) They have flat hand with characteristic crease which runs all the way across the palm (Simian crease).

Topic: Biology, Principles of Inheritance and Variation, NEET
Following is the list of STDs. Select the diseases which are not completely curable.
A. Genital warts
B. Genital herpes
C Syphilis
D Hepatitis-B
E Trichomoniasis
Choose the correct answer from the

Options:
A A and D only
B B and D only
C A and C only
D D and E only

The correct answer is:
B and D only

Solution:
The correct answer is option (2) -B and D only because except for hepatitis -B, genital herpes and HIV infections, other sexually transmitted diseases are completely curable, if detected early and treated properly.
- Genital warts, syphilis and trichomoniasis are completely curable STDs upon proper detection and treatment.
- Option (1) is incorrect as it includes genital warts
- Option (3) is incorrect as it includes genital warts and syphilis.
- Option (4) is incorrect as it includes trichomoniasis.
Genital warts, genital herpes and hepatitis -B are viral STDs, syphilis is a bacterial and trichomoniasis is a protozoan STD.

Topic: Biology, Reproductive Health, NEET, NEET 2024 (Re-NEET)
Following limiting molar conductivities are given as given as
$$
\begin{aligned}
& \lambda_{\mathrm{m}\left(\mathrm{H}_2 \mathrm{SO}_4\right)}^0=\mathrm{x} \mathrm{S} \mathrm{cm}{ }^2 \mathrm{~mol}^{-1} \\
& \lambda_{\mathrm{m}\left(\mathrm{K}_2 \mathrm{SO}_4\right)}^0=\mathrm{y} \mathrm{S} \mathrm{cm}{ }^2 \mathrm{~mol}^{-1} \\
&
\end{aligned}
$$
$\lambda_{\mathrm{m}\left(\mathrm{CH}_2 \mathrm{COOK}\right)}^0=\mathrm{Z} \mathrm{S} \mathrm{cm}{ }^2 \mathrm{~mol}^{-1}$

Options:
A $x-y+2 z$
B $x+y-z$
C $x-y+z$
D $\frac{(x-y)}{2}+z$

The correct answer is:
$\frac{(x-y)}{2}+z$

Solution:
Key Idea According to Kohlrausch's law,
$$
\lambda_m^0 \text { for } A_x B_y=x \lambda_{(A)^{0+}}^0+y \lambda_{(B)^{x-}}
$$
where, $\lambda_m^{\circ}=$ limiting molar conductivity of electrolyte and $\lambda_{(A)^{y+}}^0$ and $\lambda_{(B)^{x-}}^0$ are the limiting molar conductivities of cation $\left(A^{y+}\right)$ and anion $\left(B^{x-}\right)$, respectively.

Topic: Chemistry, Electrochemistry, NEET, NEET 2019 (Odisha)
Following pair of the organism are used for antibiotic production:

Options:
A Trichoderma and Monascus
B Aspergillus niger and Penicillium notatum
C Lactobacillus and Nucleopolyhedrovirus
D Baculovirus and Streptococcus

The correct answer is:
Aspergillus niger and Penicillium notatum

Solution:
Approximately 25% of the Penicillium strains and 40% of the Aspergillus strains yield antibiotics. Aspergillus fumigatus and Penicillium notatum are the two strains which yield antibiotics in higher concentration.

Topic: Biology, Microbes in Human Welfare, NEET
Following results are observed when sodium metal is irradiated with different wavelengths. Which of the following options is closest to the threshold wavelength?

Options:
A 530 nm
B 596 nm
C 672 nm
D 756 nm

The correct answer is:
530 nm

Solution:
Correct Option is : (A)
530 nm

Topic: Chemistry, Structure of Atom, NEET
Following solutions were prepared by mixing different volumes of NaOH and HCl of different concentrations
1. 60 mL of M10 HCl+40 mL of M10 NaOH
2. 55 mL of M10 HCl+45 mL of M10 NaOH
3. 75 mL of M5 HCl+25 mL of M5 NaOH
4. 100 mL of M10 HCl+100 mL of M10 NaOH
pH of which one of them will be equal to 1?

Options:
A 4
B 1
C 2
D 3

The correct answer is:
3

Solution:
Meq of HCl =75×15×1=15
Meq of NaOH =25×15×1=5
Meq of HCl in resulting solution = 10
Normality of [H+] in resulting mixture =10100=110
pH=-log[H+]=-log110=1.0

Topic: Chemistry, Some Basic Concepts of Chemistry, NEET
Following solutions were prepared by mixing different volumes of NaOH and HCl of different concentrations.
(i) 60 mLM10 HCl+40mLM10NaOH
(ii) 55 mLM10HCl+45mLM10NaOH
(iii) 75 mLM5HCl+25mLM5NaOH
(iv) 100 mLM10HCl+100 mLM10NaOH
The pH of which one of them will be equal to 1?

Options:
A (iv)
B (i)
C (ii)
D (iii)

The correct answer is:
(iii)

Solution:
Equivalent of acid =N1V1
Equivalent of base =N2V2
As N1V1>N2V2,
acid is left at the end of the reaction.
The 'n' factor of NaOH and HCl are 1,1. So, N=M for both.
Nfinal solution=H+=N1V1-N2V2V1+V2
=15×75-15×2575+25
=110= 10 −1

Topic: Chemistry, Ionic Equilibrium, NEET, NEET 2018
Following statements describe the characteristics of restriction endonucleases. Identify the incorrect statement.

Options:
A The enzyme cuts DNA molecules at identified position within the DNA.
B The enzyme binds DNA at specific sites and cuts only one of the two strands.
C The enzyme cuts the sugar-phosphate backbone at specific site on each strand.
D The enzyme recognizes a specific palindromic nucleotide sequence in the DNA.

The correct answer is:
The enzyme binds DNA at specific sites and cuts only one of the two strands.

Solution:
DNA consists of two complementary strands of nucleotides that spiral around each other in a double helix. Restriction enzymes cut through both nucleotide strands, breaking the DNA into fragments. These are the endonucleases that are used in RDT or genetic engineering techniques.

Topic: Biology, Biotechnology - Principles and Processes, NEET, NEET 2019 (All India)
Following statements describe the characteristics of restriction endonucleases. Identify the incorrect statement.

Options:
A The enzyme cuts DNA molecules at identified position within the DNA.
B The enzyme binds DNA at specific sites and cuts only one of the two strands.
C The enzyme cuts the sugar-phosphate backbone at specific site on each strand.
D The enzyme recognizes a specific palindromic nucleotide sequence in the DNA.

The correct answer is:
The enzyme binds DNA at specific sites and cuts only one of the two strands.

Solution:
DNA consists of two complementary strands of nucleotides that spiral around each other in a double helix. Restriction enzymes cut through both nucleotide strands, breaking the DNA into fragments

Topic: Biology, Biotechnology - Principles and Processes, NEET
Food chain in which micro-organisms breakdown the food formed by primary producers:

Options:
A Parasitic food chain
B Detritus food chain
C Consumer food chain
D Predator food chain

The correct answer is:
Detritus food chain

Solution:
Detritus food chain being with dead organic matter with dead plant parts, animals and their excretory product which is being acted upon by decomposers such as saprophytes to obtain energy needed for their survival.

Topic: Biology, Ecosystem, NEET
Food preservatives prevent spoilage of food due to microbial growth. The most commonly used preservatives are

Options:
A vegetable oils and sodium benzoate
B C6H5COONa
C table salt, sugar
D all of the above

The correct answer is:
all of the above

Solution:
Table salt (NaCl), sugar, sodium nitrite, spices, vinegar and alcohol have been used to preserve foods for centuries. Sodium benzoate, calcium propionate, and potassium sorbate are used to prevent microbial growth that causes spoil age and to slow changes in color, texture, and flavor.

Topic: Chemistry, Chemistry in Everyday Life, NEET