datavorous/entrance-exam-dataset huggingface dataset:
$\mathrm{CaCl}_2$ and $\mathrm{Ca}(\mathrm{OCl})_2$ are components of :

Options:
A gypsum
B Portland cement
C bleaching powder
D lime water

The correct answer is:
bleaching powder

Solution:
Bleaching powder is prepared by passing $\mathrm{Cl}_2$ gas through dry slaked lime.
$2 \mathrm{Ca}(\mathrm{OH})_2+2 \mathrm{Cl}_2 \longrightarrow \underset{\text { Bleaching Powder }}{\mathrm{Ca}\left(\mathrm{OCl}\right)_2+\mathrm{CaCl}_2+2 \mathrm{H}_2 \mathrm{O}_1}$

Topic: Chemistry, s Block Elements, NEET, NEET 2022 (Phase 2)
CAD stands for

Options:
A Carotid Arterial Dysfunction
B Cerebral Artery Dysfunction
C Coronary Artery Disease
D Calcium Activated Disease

The correct answer is:
Coronary Artery Disease

Solution:
Coronary artery disease (CAD) is characterized by hardening and loss of elasticity of the arteries.

Topic: Biology, Body Fluids and Circulation, NEET
Cadmium rods are used in a nuclear reactor for

Options:
A slowing down fast neutrons
B speeding up slow neutrons
C absorbing neutrons
D provides more fuel to nuclear reactor

The correct answer is:
absorbing neutrons

Solution:
Cadmium rods are used in the form of control rods. In a nuclear reactor, it can absorb the neutrons and are used to control the nuclear chain reaction. Even Boron rods are used for this purpose.

Topic: Physics, Nuclear Physics, NEET
Caffeine, amphetamines and cocaine are:

Options:
A Nerve depressants
B Nerve initiators
C Nerve stimulants
D Nerve impulse initiators

The correct answer is:
Nerve stimulants

Solution:
These drugs stimulate the nervous system, make a person more wakeful, alert and active and cause excitement.

Topic: Biology, Human Health and Diseases, NEET
Calamine is an ore of :

Options:
A Copper
B Gold
C Iron
D Zinc

The correct answer is:
Zinc

Solution:
Correct Option is : 4
Zinc

Topic: Chemistry, General Principles and Processes of Isolation of Metals, NEET
Calcite is an example of which of the following systems?

Options:
A Cubic
B Tetragonal
C Hexagonal
D Rhombohedral

The correct answer is:
Rhombohedral

Solution:
Correct Option is : 4
Rhombohedral

Topic: Chemistry, Solid State, NEET
Calcitonin is

Options:
A protein hormone
B increases blood calcium level
C secreted from parathyroid gland
D both 'a' and 'b'

The correct answer is:
protein hormone

Solution:
Calcitonin is a protein hormone with 32 amino acids. It is secreted by the thyroid gland to decrease the blood calcium level. Thyrocalcitonin (TCT) suppresses the release of calcium ions from the bones and acts antagonist to the parathyroid homone.

Topic: Biology, Chemical Coordination and Integration, NEET
Calcitonin

Options:
A Lowers calcium level in blood
B Elevates calcium level in blood
C Has no effect on calcium levels
D Elevates potassium level in blood

The correct answer is:
Lowers calcium level in blood

Solution:
It is a long peptide hormone secreted by parafollicular cells of the thyroid gland. Its secretion is regulated by an increased plasma level of calcium by the feedback mechanism. TCT lower calcium level in the blood to normal by increasing calcium deposition in the bones so checks osteoporosis. It prevents hypercalcemia.

Topic: Biology, Chemical Coordination and Integration, NEET
Calcium carbonate reacts with aqueous HCl to give CaCl2and CO2according to the reaction, CaCO3(s) + 2HCl (aq) → CaCl2(aq) + CO2(g) + H2O(l) What mass of CaCO3is required to react completely with 25 mL of 0.75 M HCl?

Options:
A 0.937g
B 1.054g
C 0.568g
D 0.746g

The correct answer is:
0.937g

Solution:
Correct Option is : (A)
0.937g

Topic: Chemistry, Some Basic Concepts of Chemistry, NEET
Calcium carbonate reacts with aqueous HCl to give CaCl2and CO2according to the reaction given below: CaCO3(s) + 2HCl (aq) → CaCl2(aq) + CO2(g) + H2O(l) What mass of CaCl2will be formed when 250 mL of 0.76 M HCl reacts with 1000 g of CaCO3?

Options:
A 13.45g
B 10.54g
C 12.65g
D 14.93g

The correct answer is:
10.54g

Solution:
Correct Option is : (B)
10.54g

Topic: Chemistry, Some Basic Concepts of Chemistry, NEET
Calcium chloride helps in:

Options:
A Restriction of foreign dna
B Formation of pores on cell wall
C Degradation cell membrane
D Exonuclease activity

The correct answer is:
Formation of pores on cell wall

Solution:
When Ca2+ ions are rubbed against the cell wall, it results in the enlargement of the diameter of the pores and allows the uptake of foreign DNA fragments.

Topic: Biology, Biotechnology - Principles and Processes, NEET
Calcium chloride is used as a dehydrating agent because

Options:
A it has a strong affinity for water
B it has water of crystalline attached to it
C it loses water when exposed to air
D it has a high melting point

The correct answer is:
it has a strong affinity for water

Solution:
The halides of alkaline earth metals are hygroscopic in nature. CaCl2 has a great affinity towards water.

Topic: Chemistry, s Block Elements, NEET
Calcium cyanamide on treatment with steam produces:

Options:
A CaCO3+NH3
B CaHCO3+NH3
C CaO+NH3
D Ca(OH)2+NH3

The correct answer is:
CaCO3+NH3

Solution:
Calcium cyanamide (CaCN2) on treatment with steam produce CaCO3+NH3.
CaCN2 + 3H2O ---> CaCO3 + 2NH3

Topic: Chemistry, s Block Elements, NEET
Calcium important in skeletal muscle contraction because

Options:
A Detaches the myosin head from the actin filament
B Activates the myosin ATPase by binding to it
C Binds to troponin to remove the masking of active sites on actin for myosin
D Prevents the formation of bonds between the myosin cross bridges and actin filament

The correct answer is:
Binds to troponin to remove the masking of active sites on actin for myosin

Solution:
Calcium plays a key regulatory role in muscle contraction. Ca2+ ions bind to troponin and change their shape and position. This, in turn, alters the shape and position of tropomyosin and hence, the active sites on F-actin are exposed. Due to this, myosin cross-bridges are able to bind to these active sites and muscle contraction occurs.

Topic: Biology, Locomotion and Movement, NEET, NEET 2018
Calcium is obtained by

Options:
A Electrolysis of molten CaCl2
B Electrolysis of solution of CaCl2 in water
C Reduction of CaCl2 with carbon
D Roasting of lime stone

The correct answer is:
Electrolysis of molten CaCl2

Solution:
Calcium is manufactured by the electrolysis of a molten mixture of calcium chloride containing some CaF2.
CaCl 2 → Ca + 2 + 2 Cl -
Ca + 2 + 2 e - → Ca (Cathode)
2 Cl - → Cl 2 + 2 e - (Anode)

Topic: Chemistry, s Block Elements, NEET
Calcium is tarnished in air, because it is covered with a thin film of

Options:
A oxide
B hydroxide
C carbonate
D basic carbonate

The correct answer is:
oxide

Solution:
Calcium is tarnished in air, because it is covered with a thin film of oxide.
Ca+O2→2CaO
In moist air, it is slowly tarnished, but decomposes water fairly rapidly giving hydrogen.
Ca+2H2O→CaOH2+H2

Topic: Chemistry, s Block Elements, NEET
Calcium lactate is a salt of a weak organic acid and represented as Ca (Lac)2 . A saturated solution of Ca (Lac)2 contains 0.13 mol of this salt in 0.50 litre solution. The pOH of this solution is 5.60. Assuming a complete dissociation of the salt.

Options:
A 824×10-4
B 8.24×10-4
C 82.4×10-4
D 8.24×104

The correct answer is:
8.24×10-4

Solution:
Molarity of salt = 0.13 0.5 =0.26 M
Ca(Lac)20.260âCa2++2Lac-02Ã0.26
pH=12pKw+12pKa+12logC
So pH=12Ã14+12pKa+12Ãlog0.52
pKa=2(8.4-7+0.142)=3.084
Ka=8.24Ã10-4

Topic: Chemistry, Ionic Equilibrium, NEET
Calculate de-Broglie wavelength of an electron having kinetic energy 2.8×10-23 J .
me=9.1×10-31kg

Options:
A 9.28×10-4 m
B 9.28×10-7 m
C 9.28×10-8 m
D 9.28×10-10 m

The correct answer is:
9.28×10-8 m

Solution:
Formula for de-Broglie wavelength is
λ=hp or λ=hmv⇒eV=12mv2 or ν=2eVm
λ=h2meV=6.62×10-342×9.1×10-31×2.8×10-23
=9.28×10-8 m

Topic: Chemistry, Structure of Atom, NEET
Calculate elevation in boiling point for 2 molal aqueous solution of glucose
(Given: Kb(H2O)=0.5 K kgmol-1 ).

Options:
A 1 oC
B 4 oC
C 3 oC
D 2 oC

The correct answer is:
1 oC

Solution:
ΔTb=iKbm=1×0.5×2=1

Topic: Chemistry, Solutions, NEET
Calculate Î f G â for (NH4Cl, s) at 310 K.

Given : Î f H â NH 4 Cl, s = - 314.5 kJ/mol ; Î r C p = 0

S N 2 g â = 192 JK -1 mol -1 ; S H 2 g â = 130.5 JK -1 mol -1 ;

S Cl 2 g â = 233 JK -1 mol -1 ; S NH 4 Cl s â = 99.5 JK -1 mol -1

All given data at 300 K.

Options:
A - 198.56 kJ/mol
B - 426.7 kJ/mol
C - 202.3 kJ/mol
D None of these

The correct answer is:
- 198.56 kJ/mol

Solution:
âfS0NH4Cl,s at 300 K
= S N H 4 Cl(S) 0 â[ 1 2 S N 2 0 +2 S H 2 0 + 1 2 S C l 2 0 ]
= -374 JK-1mol-1
â´ âfCp=0
â´ âfS3100=ârS3000
= -374 JK-1mol-1
âfH3100=âfH3000=-314.5
âfG3100=âfH0-310âfS0
= -314.5-310-3741000
-198.56 kJ/mol

Topic: Chemistry, Thermodynamics (C), NEET
Calculate (i) molality (ii) molarity and (iii) mole fraction of KI if the density of 20% (mass/mass) aqueous KI is 1.202 g mL-1.

Options:
A (i)1.5 mol kg–1(ii) 1.69 mol L–1and (iii) 0.0368
B (i)1.5 mol kg–1(ii) 1.45 mol L–1and (iii) 0.0263
C (i)2.5 mol kg–1(ii) 1.45 mol L–1and (iii) 0.0413
D (i)2.8 mol kg–1(ii) 1.86 mol L–1and (iii) 0.0263

The correct answer is:
(i)1.5 mol kg–1(ii) 1.45 mol L–1and (iii) 0.0263

Solution:
Correct Option is : (B)
(i)1.5 mol kg–1(ii) 1.45 mol L–1and (iii) 0.0263

Topic: Chemistry, Solutions, NEET
Calculate (i) wavenumber and (ii) frequency of yellow radiation having wavelength 5800 Å.

Options:
A (i) 1.724×104cm-1and (ii) 5.172×1014s-1
B (i) 2.465×104cm-1and (ii) 5.172×1014s-1
C (i) 1.724×104cm-1and (ii) 6.854×1014s-1
D (i) 2.465×104cm-1and (ii) 6.854×1014s-1

The correct answer is:
(i) 1.724×104cm-1and (ii) 5.172×1014s-1

Solution:
Correct Option is : (A)
(i) 1.724×104cm-1and (ii) 5.172×1014s-1

Topic: Chemistry, Structure of Atom, NEET
Calculate molality of 2.5 g of ethanoic acid (CH3COOH) in 75 g of benzene.

Options:
A 0.458 mol kg–1
B 0.365 mol kg–1
C 0.221 mol kg–1
D 0.556 mol kg–1

The correct answer is:
0.556 mol kg–1

Solution:
Correct Option is : (D)
0.556 mol kg–1

Topic: Chemistry, Solutions, NEET
Calculate molarity of the resultant solution obtained by mixing 1 M and 2.5 litre NaOH solution and 0.5 M and 3 litre NaOH solution.

Options:
A 0.50 M
B 0.73 M
C 0.80 M
D 1.0 M

The correct answer is:
0.73 M

Solution:
M1V1+M2V2=M3V3(Mixture)
(2.5Ã1+3Ã0.5)=M3Ã5.5
or 2.5+1.5=M3Ã5.5
M 3 = 0.727

Topic: Chemistry, Some Basic Concepts of Chemistry, NEET
Calculate number of sigma(σ) and pi(π) bonds in the given structure-

Options:
A σ bonds : 23, π bonds : 2
B σ bonds : 24, π bonds : 1
C σ bonds : 23, π bonds : 1
D σ bonds : 25, π bonds : 1

The correct answer is:
σ bonds : 23, π bonds : 1

Solution:
Correct Option is : (C)
σ bonds : 23, π bonds : 1

Topic: Chemistry, Hydrocarbons, NEET
Calculate number of sigma(σ) and pi(π) bonds in the given structure-

Options:
A σ bonds : 35, π bonds : 2
B σ bonds : 33, π bonds : 2
C σ bonds : 33, π bonds : 3
D σ bonds : 34, π bonds : 2

The correct answer is:
σ bonds : 33, π bonds : 2

Solution:
Correct Option is : (B)
σ bonds : 33, π bonds : 2

Topic: Chemistry, Hydrocarbons, NEET
Calculate number of sigma(σ) and pi(π) bonds in the given structure-

Options:
A σ bonds : 41, π bonds : 1
B σ bonds : 40, π bonds : 1
C σ bonds : 41, π bonds : 2
D σ bonds : 39, π bonds : 1

The correct answer is:
σ bonds : 41, π bonds : 1

Solution:
Correct Option is : (A)
σ bonds : 41, π bonds : 1

Topic: Chemistry, Hydrocarbons, NEET
Calculate number of sigma(σ) and pi(π) bonds in the given structure-

Options:
A σ bonds : 19, π bonds : 4
B σ bonds : 18, π bonds : 4
C σ bonds : 17, π bonds : 5
D σ bonds : 17, π bonds : 4

The correct answer is:
σ bonds : 17, π bonds : 4

Solution:
Correct Option is : (D)
σ bonds : 17, π bonds : 4

Topic: Chemistry, Hydrocarbons, NEET
Calculate partial pressure of B at equilibrium in the following equilibrium
A(s)⇌B(g) + 2C(g);   K p  = 32  atm 3

Options:
A 2
B 3
C 17
D 5.8

The correct answer is:
2

Solution:
A(s)⇌ B(g) P  +  2C(g) 2P
At equation Kf=P.(2P)2
32=4P3
P3=8
Pâ=â2âatm

Topic: Chemistry, Chemical Equilibrium, NEET
Calculate potential energy of a point charge –q placed along the axis due to a charge +Q uniformly distributed along a ring of radius R.

Options:
A $\frac{qQ}{4\pi {{\varepsilon }_{o}}\sqrt{1+{{z}^{2}}/{{R}^{2}}}}$
B $\frac{-qQ}{4\pi {{\varepsilon }_{o}}\sqrt{1+{{z}^{2}}/{{R}^{2}}}}$
C $\frac{-qQ}{4\pi {{\varepsilon }_{o}}\sqrt{1+2{{z}^{2}}/{{R}^{2}}}}$
D $\frac{qQ}{4\pi {{\varepsilon }_{o}}\sqrt{1+{{z}^{2}}/2{{R}^{2}}}}$

The correct answer is:
$\frac{-qQ}{4\pi {{\varepsilon }_{o}}\sqrt{1+{{z}^{2}}/{{R}^{2}}}}$

Solution:
Correct Option is : (B)
$\frac{-qQ}{4\pi {{\varepsilon }_{o}}\sqrt{1+{{z}^{2}}/{{R}^{2}}}}$

Topic: Chemistry, Capacitance, NEET
Calculate potential on the axis of a ring due to charge Q uniformly distributed along the ring of radius R.

Options:
A $\frac{Q}{4\pi {{\varepsilon }_{o}}\sqrt{{{R}^{2}}+2{{z}^{2}}}}$
B $\frac{2Q}{4\pi {{\varepsilon }_{o}}\sqrt{{{R}^{2}}+{{z}^{2}}}}$
C $\frac{Q}{4\pi {{\varepsilon }_{o}}\sqrt{{{R}^{2}}+{{z}^{2}}}}$
D $\frac{2Q}{4\pi {{\varepsilon }_{o}}\sqrt{2{{R}^{2}}+{{z}^{2}}}}$

The correct answer is:
$\frac{Q}{4\pi {{\varepsilon }_{o}}\sqrt{{{R}^{2}}+{{z}^{2}}}}$

Solution:
Correct Option is : (C)
$\frac{Q}{4\pi {{\varepsilon }_{o}}\sqrt{{{R}^{2}}+{{z}^{2}}}}$

Topic: Chemistry, Capacitance, NEET
Calculate Q and w for the isothermal reversible expansion of one mole of an ideal gas from an initial pressure of 1.0 bar to a final pressure of 0.1 bar at a constant temperature of 273 K .

Options:
A 5.22 kJ,-5.22 kJ
B -5.22 kJ,5.22 kJ
C 27.3 kJ,-27.3 kJ
D -27.3 kJ,27.3 kJ

The correct answer is:
5.22 kJ,-5.22 kJ

Solution:
∆w=2.303×nRTlogP1P2
ΔU=0
-q=w
wrev=-2.303×1×8.314×273log10.1=-5227 J
wrev.=-5.22 kJ

Topic: Chemistry, Thermodynamics (C), NEET
Calculate ∆rG for conversion of oxygen to ozone, 3/2 O2(g) → O3(g) at 298 K, if Kpfor this conversion is 2.47 × 10–29.

Options:
A 155 kJ mol-1
B 176 kJ mol-1
C 163 kJ mol–1
D 185 kJ mol-1

The correct answer is:
163 kJ mol–1

Solution:
Correct Option is : (C)
163 kJ mol–1

Topic: Chemistry, Thermodynamics (C), NEET
Calculate the acceleration of the block and trolly system shown in the figure. The coefficient of kinetic friction between the trolly and the surface is 0.05. (g=10 m s-2, mass of the string is negligible and no other friction exists).

Options:
A 1.25 $ms^{-2}$
B 1.50 $ms^{-2}$
C 1.66 $ms^{-2}$
D 1.00 $ms^{-2}$

The correct answer is:
1.25 $ms^{-2}$

Solution:
First, make the free body diagram,

here, the equation, the relation between tension and acceleration, 20=2a+T ..1 & T=10a+5 ..2⇒20=2a+10a+5⇒12a=15⇒a=1512=1.25 m s-2

Topic: Physics, Laws of Motion, NEET, NEET 2020 (Phase 2)
Calculate the amount of 53I128(t1/2=25min) left after 75 minutes.

Options:
A 1/4
B 1/6
C 1/8
D 1/9

The correct answer is:
1/8

Solution:
N N 0 = 1 2 t t 1/2  ;  N N 0 = 1 2 75 25
N = amount at time t
t = total time
N 0  = initial amount

Topic: Chemistry, Chemical Kinetics, NEET
Calculate the amount of benzoic acid (C6H5COOH) required for preparing 250 mL of 0.15 M solution in methanol.

Options:
A 4.575 g
B 8.123 g
C 10.352 g
D 1.234 g

The correct answer is:
4.575 g

Solution:
Correct Option is : (A)
4.575 g

Topic: Chemistry, Solutions, NEET
Calculate the amount of carbon dioxide that could be produced when 1 mole of carbon is burnt in 16 g of dioxygen

Options:
A 20 g CO2
B 26g CO2
C 24g CO2
D 22g CO2

The correct answer is:
22g CO2

Solution:
Correct Option is : (D)
22g CO2

Topic: Chemistry, Some Basic Concepts of Chemistry, NEET
Calculate the amount of carbon dioxide that could be produced when 1 mole of carbon is burnt in the air.

Options:
A 42 g CO2
B 44g CO2
C 46g CO2
D 48g CO2

The correct answer is:
44g CO2

Solution:
Correct Option is : (B)
44g CO2

Topic: Chemistry, Some Basic Concepts of Chemistry, NEET
Calculate the amount of carbon dioxide that could be produced when 2 moles of carbon are burnt in 16 g of dioxygen.

Options:
A 22 g CO2
B 28g CO2
C 25g CO2
D 24g CO2

The correct answer is:
22 g CO2

Solution:
Correct Option is : (A)
22 g CO2

Topic: Chemistry, Some Basic Concepts of Chemistry, NEET
Calculate the amount of electricity required to deposit 0.9 g of aluminium by electrolysis of a salt containing its ion, if the electrode reaction is

Al 3 + + 3 e - â Al ; ( atomic mass of Al = 2 7 , 1 F = 96500 C )

Options:
A 9.65 Ã 10 3 C
B 1.93 × 10 4 C
C 9.65 × 10 4 C
D 4.34 × 10 5 C

The correct answer is:
9.65 × 10 3 C

Solution:
Al 3 + + 3 e - â Al â
1 mole Al requires 3 mole e- (3 F charge) to dischage on electrode.
Also, 1 F = 96500 C.
Thus, 27 g of Al require = 3 Ã 9 6 5 0 0 C
0.9 g of Al requires = 3 Ã 9 6 5 0 0 C 2 7 Ã 0.9 = 9650 C .
=9.65Ã 10 3 C

Topic: Chemistry, Electrochemistry, NEET
Calculate the amount of water (in g) produced by the combustion of 16 g of methane.

Options:
A 36 g H2O
B 48 g H2O
C 24 g H2O
D 60 g H2O

The correct answer is:
36 g H2O

Solution:
Correct Option is : (A)
36 g H2O

Topic: Chemistry, Some Basic Concepts of Chemistry, NEET
Calculate the atomic mass (average) of chlorine using the following data:

Options:
A 36.2456 u
B 35.4527 u
C 35.7564 u
D 36.5784 u

The correct answer is:
35.4527 u

Solution:
Correct Option is : (B)
35.4527 u

Topic: Chemistry, Some Basic Concepts of Chemistry, NEET
Calculate the average atomic mass of hydrogen using the following data :

Options:
A 1.23000u
B 1.00057u
C 1.02350u
D 1.00015u

The correct answer is:
1.00015u

Solution:
Correct Option is : (D)
1.00015u

Topic: Chemistry, Some Basic Concepts of Chemistry, NEET
Calculate the average life (in minutes), if the half-life of a radionuclide is 69.3 minutes.

Options:
A 100
B 1/100
C 69.3×14.4
D 0.693×69.3

The correct answer is:
100

Solution:
Average life (τ)=1.44t1/2=1.44×69.3=99.7≈100 minutes.

Topic: Chemistry, Chemical Kinetics, NEET
Calculate the cell constant if the specific conductance of a solution is 0.2 ohm-1cm-1 and its conductivity is 0.04 ohm-1 .

Options:
A 1 cm-1
B 0 cm-1
C 5 cm-1
D 0.2 cm-1

The correct answer is:
5 cm-1

Solution:
K=CÃCell constant Cell constant=KC
=0.20.04=5 cm-1

Topic: Chemistry, Electrochemistry, NEET
Calculate the degree of ionization of 0.05M acetic acid if its pKa value is 4.74. How is the degree of dissociation affected when its solution also contains (a) 0.01M (b) 0.1M in HCl?

Options:
A α = 1.90, (a) α = 1.82 * 10-5(b) α = 1.82 * 10-4
B α = 0.020, (a) α = 0.015 (b) α = 0.025
C α = 0.014, (a) α = 0.015 (b) α = 0.025
D α = 0.020, (a) α = 0.016 (b) α = 0.030

The correct answer is:
α = 1.90, (a) α = 1.82 * 10-5(b) α = 1.82 * 10-4

Solution:
Correct Option is : (A)
α = 1.90, (a) α = 1.82 * 10-5(b) α = 1.82 * 10-4

Topic: Chemistry, Ionic Equilibrium, NEET
Calculate the density of the solid sodium, when crystallises in body centred cubic(bcc) arrangement with interfacial separation between the atoms at an edge is 53 pm .

Options:
A 1.23 g/cc
B 485 g/cc
C 4.85 g/cc
D 123 g/cc

The correct answer is:
1.23 g/cc

Solution:
Given, a â 2r =53 pm

The spheres at the corners are not touching
each other. For bcc structure,

4r=3a

2r=32a

a-32a=53

∴ a=395.6 pm

395.6Ã10-12 m

=395.6× 10 −10 cm

=3.956× 10 −8 cm

Densityd=z MNA a3

d= 2×23 6.023× 10 23 × (3.956) 3 × 10 −24 =1.23   g/cc

Topic: Chemistry, Solid State, NEET
Calculate the deposited mass of silver which is plotted against charge in electrolysis of silver nitrate.

Slope of the line gives:

Options:
A The equivalent mass of silver
B Electrochemical equivalent of silver
C The value of Faraday
D The current passed through the cell

The correct answer is:
Electrochemical equivalent of silver

Solution:
According to Faraday's 1st law of electrolysis.
W âQ
W= Z.Q
âµZ = E F
then
W= QE F or E F . Q
Compare with straight line equation
Y = mx +c [m = slope of line]
∵c=0, passing through origin
Slope of the line m = E F = Z (Electrochemical equivalent of silver)
Slope =EF

Topic: Chemistry, Electrochemistry, NEET
Calculate the depression in the freezing point of water when 10 g of CH3CH2CHClCOOH is added to 250 g of water. (Ka= 1.4×10–3, Kf=1.86 K kg mol–1)

Options:
A 3.120C
B 2.260C
C 1.340C
D 0.650C

The correct answer is:
0.650C

Solution:
Correct Option is : (D)
0.650C

Topic: Chemistry, Solutions, NEET
Calculate the dispersive power for crown glass from the given data, Î¼v=1.5230,Î¼r=1.5145.

Options:
A 2°
B 3°
C 0.0163°
D 2.5°

The correct answer is:
0.0163°

Solution:
Here
μy=μv+μr2
⇒μy=1.5230+1.51452
⇒μy=3.03752
⇒μy=1.5187
Therefore,
ω=μv-μrμy-1
⇒ω=1.5230-1.51451.5187-1
⇒ω=0.00850.5187
⇒ω=0.0163°

Topic: Physics, Ray Optics, NEET
Calculate the efficiency of packing in a body-centered cubic metal crystal. (Assuming atoms are touching each other)

Options:
A 52.4%
B 68%
C 74%
D 100%

The correct answer is:
68%

Solution:
Correct Option is : (B)
68%

Topic: Chemistry, Solid State, NEET
Calculate the efficiency of packing in a face-centered cubic metal crystal. (Assuming atoms are touching each other)

Options:
A 52.4%
B 68%
C 74%
D 100%

The correct answer is:
74%

Solution:
Correct Option is : (C)
74%

Topic: Chemistry, Solid State, NEET
Calculate the efficiency of packing in a simple cubic metal crystal. (Assuming atoms are touching each other)

Options:
A 52.4%
B 68%
C 74%
D 100%

The correct answer is:
52.4%

Solution:
Correct Option is : (A)
52.4%

Topic: Chemistry, Solid State, NEET
Calculate the elevation in boiling point, for a solution of 13.44 g of CuCl2 in 1kg of water using the following information
(Molecular weight of CuCl 2  = 134.4 and K b = 0.52  Kmolal 1 )

Options:
A 0.05
B 0.16
C 0.1
D 0.2

The correct answer is:
0.16

Solution:
ΔTb=i.Kb.m
CuCl2→Cu2++2Cl100(1-α)α2α
i=1+2α
Assuming 100% ionization, α=1
So, i = 3
ΔTb=3×0.52×0.1=0.156≅0.16

Topic: Chemistry, Solutions, NEET
Calculate the emf of the cell in which the following reaction takes place Ni(s) + 2Ag⁺ (0.002 M) → Ni²⁺ (0.160 M) + 2Ag(s) Given that E(cell) = 1.05 V

Options:
A 1.05 V
B 0.85 V
C 0.65 V
D 1.25 V

The correct answer is:
0.85 V

Solution:
Correct Option is : (B)
0.85 V

Topic: Chemistry, Electrochemistry, NEET
Calculate the empirical formula of an organic compound, which contains C=74.0%, H=8.65% and N=17.3% .

Options:
A C5H8N
B C10H12N
C C5H7N
D C10H14N

The correct answer is:
C5H7N

Solution:
ElementNo.ofMolesSimpleRatioC=7474/12=6.16.1/1.2=5.08&nbspor&nbsp5H=8.658.65/1=8.658.6/1.2=7.16&nbspor&nbsp7N=17.317.3/14=1.21.2/1.2=1&nbspor&nbsp1
Empirical formula =C5H7N .

Topic: Chemistry, General Organic Chemistry, NEET
Calculate the energy and frequency of the radiation emitted when an electron jumps from n = 3 to n = 2 in a hydrogen atom.

Options:
A Energy = 1.51 × 10-19Joules, Frequency = 2.56 × 1015Hz
B Energy = 1.51 × 10-19Joules, Frequency = 4.86 × 1015Hz
C Energy = 4.86 × 10-19Joules, Frequency = 1.51 × 1015Hz
D Energy = 3.02 × 10-19Joules, Frequency = 0.45 × 1015Hz

The correct answer is:
Energy = 3.02 × 10-19Joules, Frequency = 0.45 × 1015Hz

Solution:
Correct Option is : (D)
Energy = 3.02 × 10-19Joules, Frequency = 0.45 × 1015Hz

Topic: Chemistry, Structure of Atom, NEET
Calculate the energy associated with the first orbit of He+.What is the radius of this orbit?

Options:
A Energy associated is −5.46×10-18J and Radius of this orbit is 0.06322 nm
B Energy associated is −8.72×10-18J and Radius of this orbit is 0.03645 nm
C Energy associated is −8.72×10-18J and Radius of this orbit is 0.02645 nm
D Energy associated is −7.53×10-18J and Radius of this orbit is 0.03345 nm

The correct answer is:
Energy associated is −8.72×10-18J and Radius of this orbit is 0.02645 nm

Solution:
Correct Option is : (C)
Energy associated is −8.72×10-18J and Radius of this orbit is 0.02645 nm

Topic: Chemistry, Structure of Atom, NEET
Calculate the energy in corresponding to light of wavelength 45 nm: (Planck’s constant h=6.63×10-34Js:speed of light c=3×108 ms-1)

Options:
A 6.67×1015
B 6.67×1011
C 4.42×10-15
D 4.42×10-18

The correct answer is:
4.42×10-18

Solution:
E=hcλ=6.63×10-34×3×10845×10-9=4.4×10-18

Topic: Chemistry, Structure of Atom, NEET, NEET 2014
Calculate the energy in joule corresponding to light of wavelength 45 nm.
(Planck's constant h =6.63×10-34 Js; speed of light c=3×108ms-1 )

Options:
A 6.67×1011
B 4.42×10-15
C 6.67×1015
D 4.42×10-18

The correct answer is:
4.42×10-18

Solution:
E=hcλ=6.63×10-34×3×10845×10-9
E=4.42×20-18J

Topic: Chemistry, Structure of Atom, NEET