datavorous/entrance-exam-dataset huggingface dataset:
Match List-I with List-II

List-I	List-II

Test/Reagents/Observation(s)	Species detected

(a)	Lassaigne's Test	(i)	Carbon

(b)	Cu(II) oxide	(ii)	Sulphur

(c)	Silver nitrate	(iii)	N, S, P, and halogen

(d)	The sodium fusion extract gives black precipitate with acetic acid and lead acetate	(iv)	Halogen Specifically

The correct match is :

Options:
A (a)-(iii), (b)-(i), (c)-(ii), (d)-(iv)
B (a)-(i), (b)-(iv), (c)-(iii), (d)-(ii)
C (a)-(iii), (b)-(i), (c)-(iv), (d)-(ii)
D (a)-(i), (b)-(ii), (c)-(iv), (d)-(iii)

The correct answer is:
(a)-(iii), (b)-(i), (c)-(iv), (d)-(ii)

Solution:
Match list :-

(a)	Lassaigne's Test	(i)	N,S,P and Halogen

(b)	CuII Oxide	(ii)	Carbon

(c)	AgNO3	(iii)	Halogen specifically.

(d)	Sodium fusion extract given black precipitate with acetic acid and lead acetate CH3COOH/CH3COO2 Pb	(iv)	Sulphur

Topic: Chemistry, Practical Chemistry, JEE Main, JEE Main 2021 (16 Mar Shift 2)
Match List-I with List-II :

List-I
(Name of ore/mineral)	List-I
(Chemical formula)

a	Calamine	i	ZnS

b	Malachite	ii	FeCO3

c	Siderite	iii	ZnCO3

d	Sphalerite	iv	CuCO3·Cu(OH)2

Choose the most appropriate answer from the options given below :

Options:
A (a) - (iv), (b) - (iii), (c) - (i), (d) - (ii)
B (a) - (iii), (b) - (ii), (c) - (iv), (d) - (i)
C (a) -(iii),(b)-(iv),(c)-(i),(d)-(ii)
D (a) -(iii), (b) -(iv),(c)-(ii),(d)-(i)

The correct answer is:
(a) -(iii), (b) -(iv),(c)-(ii),(d)-(i)

Solution:
(i) Calamine
:ZnCO3

(ii) Siderite
:FeCO3

(iii) Malachite :CuCO3·Cu(OH)2

(iv) Sphalerite :ZnS

Topic: Chemistry, General Principles and Processes of Isolation of Metals, JEE Main, JEE Main 2021 (27 Aug Shift 2)
Match List-I with List-II.

List-I
Natural Amino
acid	List-II
One Letter
Code

(A)	Arginine	(I)	D

(B)	Aspartic acid	(II)	N

(C)	Asparagine	(III)	A

(D)	Alanine	(IV)	R

Choose the correct answer from the options given below:

Options:
A (A)–IV, B–I, (C)–II, (D)–III
B (A)–I, B–III, (C)–IV, (D)–II
C (A)–III, B–I, (C)–II, (D)–IV
D (A)–IV, B–I, (C)–III, (D)–II

The correct answer is:
(A)–IV, B–I, (C)–II, (D)–III

Solution:
The single letter amino acid codes is fairly easy to remember. In eleven cases out of twenty, it is just the first letter.

Natural Amino acid	One Letter Code

(A)	Arginine	(IV)	R

(B)	Aspartic acid	(I)	D

(C)	Asparagine	(II)	N

(D)	Alanine	(III)	A

Topic: Chemistry, Biomolecules, JEE Main, JEE Main 2023 (06 Apr Shift 2)
Match List-I with List-II.

List-I
(Ores)	List-II
(Composition)

(a)	Haematite	(i)	Fe3O4

(b)	Magnetite	(ii)	ZnCO3

(c)	Calamine	(iii)	Fe2O3

(d)	Kaolinite	(iv)	Al2(OH)4Si2O5

Choose the correct answer from the options given below:

Options:
A (a)-(iii), (b)-(i), (c)-(ii), (d)-(iv)
B (a)-(iii), (b)-(i), (c)-(iv), (d)-(ii)
C (a)-(i), (b)-(iii), (c)-(ii), (d)-(iv)
D (a)-(i), (b)-(ii), (c)-(iii), (d)-(iv)

The correct answer is:
(a)-(iii), (b)-(i), (c)-(ii), (d)-(iv)

Solution:
Haematite is a common iron oxide compound with the formula,Fe2O3 and is widely found in rocks and soils.

Magnetite is a mineral and one of the main iron ores, with the chemical formula Fe2+Fe3+2O4(Fe3O4).

Calamine is an ore of zinc. It is zinc carbonate(ZnCO3).

Kaolinite is a clay mineral, with the chemical composition Al2(OH)4Si2O5. It is an important industrial mineral.

Topic: Chemistry, General Principles and Processes of Isolation of Metals, NEET, NEET 2022 (Phase 1)
Match List-I with List-II.

List-I
(Polymer)	List-II
(Monomer)

A	Neoprene	I	Acrylonitrile

B	Teflon	II	Chloroprene

C	Acrilan	III	Tetrafluoroethene

D	Natural rubber	IV	Isoprene

Choose the correct answer from the option given
below:

Options:
A A-II,B-III,C-I,D-IV
B A-II,B-I,C-III,D-IV
C A-II,B-I,C-IV,D-III
D A-I,B-II,C-III,D-IV

The correct answer is:
A-II,B-III,C-I,D-IV

Solution:
Neoprene (CR), also called polychloroprene or chloroprene rubber, synthetic rubber produced by the polymerization (or linkage together of single molecules into giant, multiple-unit molecules) of chloroprene.

Natural rubber is polyisoprene. It is a polymer of hydrocarbon-isoprene. Polyisoprene is an addition polymer. It is cis-1, 4-polyisoprene.

Teflon is a brand name for a synthetic chemical called polytetrafluoroethylene (PTFE). Orlon is made from polymerized acrylonitrile.

Topic: Chemistry, Polymers, JEE Main, JEE Main 2022 (27 Jul Shift 2)
Match List-I with List-II.

List-I Polymer	List-II Type/Class

A.	Nylon-2-Nylon-6	I.	Thermosetting polymer

B.	Buna-N	II.	Biodegradable polymer

C.	Ureaformaldehyde resin	III.	Synthetic rubber

D.	Dacron	IV.	Polyester

Choose the correct answer from the options given below:

Options:
A A→IV; B→I; C→II; D→II
B A→II; B→III; C→I; D→IV
C A→IV; B→III; C→I; D→II
D A→II; B→I; C→IV; D→III

The correct answer is:
A→II; B→III; C→I; D→IV

Solution:
Thermoset plastics retain their form and stay solid under heat once cured. Urea-formaldehyde is an example of thermosetting polymer. Polymers which disintegrate by themselves over a period of time due to environmental degradation by bacteria etc. are called biodegradable polymers. Nylon-2-nylon-6 is an example of biodegradable polymer. Any artificial elastomer is referred to as synthetic rubber. Buna-N is an example of synthetic rubber. Polyester is a synthetic or man-made fiber material. Dacron is an example polyester.

Topic: Chemistry, Polymers, JEE Main, JEE Main 2023 (10 Apr Shift 1)
Match List-I with List-II:

List-I Species	List-II Geometry/Shape

A.	H3O+	I.	Tetrahedral

B.	Acetylide anion	II.	Linear

C.	NH4+	III.	Pyramidal

D.	ClO2-	IV.	Bent

Choose the correct answer from the options given below:

Options:
A A(III), B(IV), C(I), D(II)
B A(III), B(I), C(II), D(IV)
C A(III), B(II), C(I), D(IV)
D A(III), B(IV), C(II), D(I)

The correct answer is:
A(III), B(II), C(I), D(IV)

Solution:
The molecular geometry of H3O+ is pyramidal. It consists of three hydrogen atoms bonded to the central oxygen atom, with one lone pair of electrons on the oxygen atom.

The acetylide ion consists of two carbon atoms bonded together by a triple bond (C≡C) with a lone pair of electrons on the terminal carbon atom. So it is linear.

The NH4+ ion consists of a central nitrogen atom bonded to four hydrogen atoms. It is tetrahedral.

The ClO2- ion is bent in shape due to its molecular geometry. It consists of one central chlorine atom bonded to two oxygen atoms, with an additional lone pair of electrons on the central chlorine atom.

(A) H3O+ → (III) Pyramidal

(B) Acetylide ion → (II) Linear

(C) NH4+ ion → (I) Tetrahedral

(D) ClO2- ion → (IV) Bent

Topic: Chemistry, Chemical Bonding and Molecular Structure, JEE Main, JEE Main 2023 (11 Apr Shift 1)
Match List-I with List-II, match the gas evolved during each reaction.

List-I	List-II

A	NH42Cr2O7⟶Δ	I	H2

B	KMnO4+HCl→	II	N2

C	Al+NaOH+H2O→	III	O2

D	NaNO3⟶Δ	IV	Cl2

Choose the correct answer from the options given below

Options:
A A-II,B-III,C-I,D-IV
B A-III,B-I,C-IV,D-II
C A-II,B-IV,C-I,D-III
D A-III,B-IV,C-I,D-II

The correct answer is:
A-II,B-IV,C-I,D-III

Solution:
Thermal decomposition of ammonium dichromate (NH4)2Cr2O7 on heating gives N2, Cr2O3 and H2O as follows:

NH42Cr2O7→∆N2+Cr2O3+4H2O

2KMnO4s+16HClaq→2KClaq+2MnCl2aq+8H2Ol+5Cl2g

The reaction of Aluminium with Sodium hydroxide (Al+NaOH) gives a salt and Hydrogen gas.

2Als+2NaOHl+6H2Ol→2NaAlOH4s+3H2l

On heating sodium nitrate it undergoes decomposition reaction and liberates oxygen and convert into sodium nitrite.

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), JEE Main, JEE Main 2022 (28 Jul Shift 1)
Match List-I with List-II.

Options:
A (a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)
B (a)-(iii), (b)-(ii), (c)-(i), (d)-(iv)
C (a)-(i), (b)-(iv), (c)-(iii), (d)-(ii)
D (a)-(ii), (b)-(iii), (c)-(iv), (d)-(i)

The correct answer is:
(a)-(ii), (b)-(iii), (c)-(iv), (d)-(i)

Solution:
Ar-OH dissolve in NaOH and carbonyl group gives +ve test with 2, 4-DNP so, +ve 2, 4 DNP test.

Topic: Chemistry, Aldehydes and Ketones, JEE Main
Match List-I with Match List-II

List-I
(Metal)	List-II
(Application)

(A)	Cs	(I)	High temperature thermometer

(B)	Ga	(II)	Water repellent sprays

(C)	B	(III)	Photoelectric cells

(D)	Si	(V)	Bullet proof vest

Choose the most appropriate answer from the options given below

Options:
A A-III,B-I,C-IV,D-II
B A-II,B-III,C-IV,D-I
C A-IV,B-III,C-II,D-I
D A-I,B-IV,C-II,D-II

The correct answer is:
A-III,B-I,C-IV,D-II

Solution:
A-III,B-I,C-IV,D-II

Caesium is used in devising photoelectric cells. Boron fibres are used in making bullet-proof vest. Silicones being surrounded by non-polar alkyl groups are water repelling in nature. Gallium is less toxic and has a very high boiling point, so it is used in high temperature thermometers.

Column I
(Element)	Column II
(Uses)

i	Cs	c	Photoelectric cell

ii	Ga	a	High temperature thermometer

iii	B	d	Bullet-proof vest

iv	Si	b	Water repellent sprays

Topic: Chemistry, p Block Elements (Group 13 & 14), JEE Main, JEE Main 2022 (29 Jun Shift 1)
Match List-I with Match List-II

List-I
(Metal)	List-II
(Emitted light wavelength nm)

(A)	Li	(I)	670.8

(B)	Na	(II)	589.2

(C)	Rb	(III)	780.0

(D)	Cs	(V)	455.5

Choose the most appropriate answer from the options given below

Options:
A A-I,B-II,C-III,D-IV
B A-III,B-II,C-I,D-IV
C A-III,B-I,C-II,D-IV
D A-IV,B-II,C-I,D-III

The correct answer is:
A-I,B-II,C-III,D-IV

Solution:
Metal	Li	Na	K	Rb	Cs

Colour	Crimson red	Yellow

Violet/Lilac

Red Violet	Blue

λnm	670.8	589.2	766.5	780.0	455.5

Topic: Chemistry, s Block Elements, JEE Main, JEE Main 2022 (29 Jun Shift 1)
Match the atomic numbers of the elements given in column I with the periods given in column II and mark the appropriate choice.

Column I (Atomic number)	Column II (Period)

(p)	31	(i)	5

(q)	50	(ii)	3

(r)	56	(iii)	4

(s)	14	(iv)	6

Options:
A (p)-(i), (q)-(ii), (r)-(iii), (s)-(iv)
B (p)-(ii), (q)-(i), (r)-(iv), (s)-(iii)
C (p)-(iii), (q)-(iv), (r)-(i), (s)-(ii)
D (p)-(iii), (q)-(i), (r)-(iv), (s)-(ii)

The correct answer is:
(p)-(iii), (q)-(i), (r)-(iv), (s)-(ii)

Solution:
Column I (Atomic number)	Column II (Period)

(p)	31	(i)	4

(q)	50	(ii)	5

(r)	56	(iii)	6

(s)	14	(iv)	3

Topic: Chemistry, Classification of Elements and Periodicity in Properties, JEE Main
Match the biological molecule listed under column I with their biological functions listed under column II and select the answer which gives the correct combination of alphabets of the two columns.

Column I
(Biological molecules)	Column II
(Functions)

A.	Glycogen	p.	Hormone

B.	Globulin	q.	Biocatalyst

C.	Steroids	r.	Antibody

D.	Thrombin	s.	Storage product

Options:
A A = r, B = q, C = s, D = p
B A = s, B = q, C = p, D = r
C A = q, B = s, C = r, D = p
D A = s, B = r, C = p, D = q

The correct answer is:
A = s, B = r, C = p, D = q

Solution:
Glycogen is the main storage polysaccharide in animals. Vertebrate animals store glycogen in the liver and muscles. All steroid hormones, are derived from cholesterol by removal of some or all of the carbons of the hydrocarbon side chain linked to a cholestrol molecule. Immunoglobulin G is an antibody that freely circulates in blood plasma. Thrombin brings about the conversion of fibrinogen to fibrin during blood clotting mechanism.

Topic: Chemistry, Biomolecules, NEET
Match the CpCv ratio for ideal gases with different type of molecules:

Molecule Type	Cp/Cv

(A) Monoatomic	(I) 7/5

(B) Diatomic rigid molecules	(II) 9/7

(C) Diatomic non-rigid molecules	(III) 4/3

(D) Triatomic rigid molecules	(IV) 5/3

Options:
A (A) – (IV), (B) – (II), (C) – (I), (D) – (III)
B (A) – (III), (B) – (IV), (C) – (II), (D) – (I)
C (A) – (IV), (B) – (I), (C) – (II), (D) – (III)
D (A) – (II), (B) – (III), (C) – (I), (D) – (IV)

The correct answer is:
(A) – (IV), (B) – (I), (C) – (II), (D) – (III)

Solution:
Relation between the ratio of specific heat and degree of freedom is given by,

γ=1+2f ...(1)

For monoatomic molecule, A, f=3

⇒γ=1+23=53

For diatomic rigid molecule B, f=5

⇒γ=1+25=75

For diatomic non-rigid molecule C, f=7 ⇒γ=1+27=97

For Triatomic rigid molecule D, f=6 ⇒γ=1+26=43

Topic: Physics, Thermodynamics, JEE Main, JEE Main 2020 (04 Sep Shift 1)
Match the catalysts (Column I) with products (Column II)

Column I	Column II

Catalyst	Product

A.	V2O5	P.	Polyethylene

B.	TiCl4/AlMe3	Q.	Ethanal

C.	PdCl2	R.	H2SO4

D.	Iron Oxide	S.	NH3

Options:
A (A)-(S); (B)-(R); (C)-(Q); (D)-(P)
B (A)-(R); (B)-(S); (C)-(P); (D)-(Q)
C (A)-(Q); (B)-(R); (C)-(P); (D)-(S)
D (A)-(R); (B)-(P); (C)-(Q); (D)-(S)

The correct answer is:
(A)-(R); (B)-(P); (C)-(Q); (D)-(S)

Solution:
i Contact process: Industrial method to prepare H2SO4 in presence of V2O5.
ii Wacker oxidation: Conversion of ethylene to acetaldehyde by an acidic, aqueous solution of PdCl2 .
iii Ziegler-Natta catalyst is used to polymerize terminal alkenes (ethylene and alkenes with the vinyl double bond).
nCH2=CHR→[CH2-CH2R]n
iv Haber process: Haber process is used to form NH3 in presence of Iron oxide.

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), JEE Main, JEE Main 2019 (09 Apr Shift 1)
Match the catalysts to the correct process.

Catalyst	Process

A.	TiCl3	i.	Wacker process

B.	PdCl2	ii.	Ziegler – Natta polymerisation

C.	CuCl2	iii.	Contact process`

D.	V2O5	iv.	Deacon’s process

Options:
A A→iii , B→i , C→ii , D →iv
B AâiiiÂ ,Â BâiiÂ ,Â CâivÂ ,Â DÂ âi
C A→ii , B→i , C→iv , D →iii
D AâiiÂ ,Â BâiiiÂ ,Â CâivÂ ,Â DÂ âi

The correct answer is:
A→ii , B→i , C→iv , D →iii

Solution:
The Wacker process is originally referred to the oxidation of ethylene to acetaldehyde by oxygen in water, where the catalyst is tetrachloropalladate(II).

In the contact process, Platinum used to be the catalyst for this reaction, however, as it is susceptible to react with arsenic impurities in the sulphur feedstock, the preferred catalyst today is vanadium (V) oxide (V2O5).

In the Deacon's process, the reaction takes place at about 400 to 450oC in the presence of a variety of catalysts, which include copper chloride (CuCl2).

In Ziegler-Natta polymerisation, homogenous catalysts, usually based on complexes of Ti, Zr or Hf, are used. They are usually used in combination with different catalysts.

Topic: Chemistry, d and f Block Elements, JEE Main
Match the catalysts to the correct process.

Catalyst	Process

A.	TiCl3	i.	Wacker process

B.	PdCl2	ii.	Ziegler – Natta polymerisation

C.	CuCl2	iii.	Contact process`

D.	V2O5	iv.	Deacon’s process

Options:
A A→iii , B→i , C→ii , D →iv
B AâiiiÂ ,Â BâiiÂ ,Â CâivÂ ,Â DÂ âi
C A→ii , B→i , C→iv , D →iii
D AâiiÂ ,Â BâiiiÂ ,Â CâivÂ ,Â DÂ âi

The correct answer is:
A→ii , B→i , C→iv , D →iii

Solution:
The Wacker process is originally referred to the oxidation of ethylene to acetaldehyde by oxygen in water, where the catalyst is tetrachloropalladate(II).

In the contact process, Platinum used to be the catalyst for this reaction, however, as it is susceptible to react with arsenic impurities in the sulphur feedstock, the preferred catalyst today is vanadium (V) oxide (V2O5).

In the Deacon's process, the reaction takes place at about 400 to 450oC in the presence of a variety of catalysts, which include copper chloride (CuCl2).

In Ziegler-Natta polymerisation, homogenous catalysts, usually based on complexes of Ti, Zr or Hf, are used. They are usually used in combination with different catalysts.

Topic: Chemistry, d and f Block Elements, JEE Main, JEE Main 2015 (04 Apr)
Match the column A with column B -

Column A	Column B

A	PCT	I	Countercurrent mechanism

B	Bowmanâs capsule	II	Selective reabsorption

C	Loop of Henle	III	Ultrafiltration

D	DCT	IV	Conditional reabsorption of Na+

Options:
A A - II, B - III, C - IV, D - I
B A - III, B - II, C - I, D - IV
C A - II, B - III, C - I, D - IV
D A - III, B - II, C - IV, D - I

The correct answer is:
A - II, B - III, C - I, D - IV

Solution:
PCT absorbs about 70-80 % electrolytes and water. It is the major site for selective reabsorption. Bowman's capsule consists of cells called podocytes, that have some minute spaces in between which are termed as filtration slits or slit pores. Ultrafiltration occurs through these pores. Loop of Henle maintains the high osmolarity of medullary interstitial fluid by the counter-current mechanism.
Structures responsible for the concentration of urine:
1. Henle's loop
2. Vasa recta.
Functions of DCT - Conditional reabsorption of Na+ and water, reabsorption of HCO3 - and selective secretion of H+, and K+, for maintaining the pH and sodium-potassium balance in the blood.

Topic: Biology, Excretory Products and their Elimination, NEET
Match the column and select the correct option.

Column I	Column II

(A)	Funicle	(I)	Main part of ovule

(B)	Filiform apparatus	(II)	Protection

(C)	Integument	(III)	Outgrowth in ovule

(D)	Nucellus	(IV)	Connect placenta and main body of ovule

(V)	Synergids

Options:
A A-I, B-II, C-III, D-IV
B A-IV, B-V, C-II, D-I
C A-V, B-IV, C-I, D-II
D A-III, B-I, C-II, D-V

The correct answer is:
A-IV, B-V, C-II, D-I

Solution:
Stalk of the ovule is called as funicle and the point of attachment of funicle to the body of ovule is called as hilum. Filliform apparatus are finger like projection present on synergids towards micropylar end. Ovule is covered by covering called as integuments.

Topic: Biology, Sexual Reproduction in Flowering Plants, NEET
Match the column:

Column I	Column II

1	Copper	A	Needed for the synthesis of Auxin

2	Boron	B	Pollen germination

3	Zinc	C	Associated with an enzyme involved in Redox reaction

Options:
A 1Â -Â A,Â 2Â -Â B,Â 3Â -Â C
B 1Â -Â B,Â 2Â -Â C,Â 3Â -Â A
C 1 - C, 2 - B, 3 - A
D 1Â -Â B,Â 2Â -Â A,Â 3Â -Â C

The correct answer is:
1 - C, 2 - B, 3 - A

Solution:
Zinc is a microelement required to plants for the synthesis of Indole acetic acid (IAA) a universal natural auxin, proteins, and RNA. Copper is also a microelement involved in the electron transport, chlorophyll synthesis and maintenance of carbohydrate/nitrogen balance. Boron, a microelement is required for the formation of pollen tube, root nodule formation, cell elongation and differentiation.

Topic: Biology, Mineral Nutrition, NEET
Match the column.

Column I	Column II

a	FSH	i	Prepare endometrium for implantation

b	LH	ii	Develops female secondary sexual characters

c	Progesterone	iii	Contraction of uterine wall

d	Estrogen	iv	Development of corpus luteum

v	Maturation of Graafian follicle

Options:
A (a)â(v), (b)â(iv), (c)â(i), (d)â(ii)
B (a)â(iv),Â (b)â(v),Â (c)â(ii),Â (d)â(i)
C (a)â(iv),Â (b)â(iii),Â (c)â(ii),Â (d)â(v)
D (a)â(v),Â (b)â(i),Â (c)â(ii),Â (d)â(iv)

The correct answer is:
(a)â(v), (b)â(iv), (c)â(i), (d)â(ii)

Solution:
Pituitary hormones gonadotrophins i.e. FSH and LH control menstrual cycle in females. FSH is a follicle-stimulating hormone and its main function is to control the development and maturation of ovarian follicles. LH is luteinizing hormone that causes formation of corpus luteum after ovulation has taken place. Ovarian hormones progesterone and estrogen secreted by corpus luteum also play an important role in the menstrual cycle. Progesterone is also important as it prepares the endometrium for implantation by secreting secretory glands. Estrogen develops secondary sexual characters.

Topic: Biology, Human Reproduction, NEET
Match the column.

Column I	Coulmn II

(1)	SF2	(p)	sp3 and bent

(2)	XeF4	(q)	Two lone pairs on central atom

(3)	NOCl	(r)	Bond angle <109.5Â°

(4)	NF3	(s)	sp2 and bent

(t)	sp3d2 and square planar

Options:
A (1)-p, q, r; (2)-q, r, t; (3)-s; (4)-r
B (1)-p, q; (2)-q, s, t; (3)-s; (4)-r
C (1)-p, q, r; (2)-q, s, t; (3)-r; (4)-s
D (1)-p, q; (2)-q, r, t; (3)-r; (4)-s

The correct answer is:
(1)-p, q, r; (2)-q, r, t; (3)-s; (4)-r

Solution:
SF2→sp3 θ<109.208 (bent)
XeF4→sp3d (Square planar)
NOCl→sp2 (bent)
NF3→sp3 (Pyramidal)

Topic: Chemistry, Chemical Bonding and Molecular Structure, JEE Main
Match the column (I) and (II) and select the correct answer using the codes given below.

Column-I	Column-II

(I) Argentite	(1) Halide ore

(II) Cuprite	(2) Carbonate ore

(III) Siderite	(3) Oxide ore

(IV) Carnallite	(4) Sulphide ore

Options:
A i-1, ii-3, iii-4, iv-3
B i-3, ii-4, iii-1, iv-3
C i-4, ii-3, iii-2, iv-1
D i-4, iii-2, iii-3, iv-1

The correct answer is:
i-4, ii-3, iii-2, iv-1

Solution:
Argentite → Ag 2 S; Cuprite → Cu 2 O
Siderite→ FeCO 3 ; Carnallite→KCI⋅ MgCI 2 ⋅6 H 2 O

Topic: Chemistry, General Principles and Processes of Isolation of Metals, JEE Main
Match the column I with Column II and mark the appropriate choice.

Column I	Column II

(p)	State function	(i)	At constant pressure

(q)	ΔH=q	(ii)	Specific heat

(r)	ΔU=q	(iii)	Entropy

(s)	Intensive property	(iv)	At constant volume

Options:
A (p)-(iii), (q)-(i), (r)-(iv), (s)-(ii)
B (p)-(ii), (q)-(iv), (r)-(i), (s)-(iii)
C (p)-(ii), (q)-(iv), (r)-(iii), (s)-(i)
D (p)-(iii), (q)-(ii), (r)-(i), (s)-(iv)

The correct answer is:
(p)-(iii), (q)-(i), (r)-(iv), (s)-(ii)

Solution:
(p) Entropy is a state function
(q) ΔH=q at constant pressure
enthalpy ΔH is heat measured at constant pressure
(r) ΔU=q at constant volume
ΔU is heat measured at constant volume
(s) Specific heat is an intensive property.

Topic: Chemistry, Thermodynamics (C), JEE Main
Match the column I with column II and mark the appropriate choice.

Column I	Column II
(p)	3d-transition series	(i)	Z = 58 to Z = 71
(q)	Lanthanoid series	(ii)	Z = 39 to Z = 48
(r)	Actinoid series	(iii)	Z = 21 to Z = 30
(s)	4d-transition series	(iv)	Z = 90 to Z = 103

Options:
A (p)-(i), (q)-(ii), (r)-(iii), (s)-(iv)
B (p)-(ii), (q)-(iii), (r)-(iv), (s)-(i)
C (p)-(iii), (q)-(i), (r)-(iv), (s)-(ii)
D (p)-(iv), (q)-(iii), (r)-(i), (s)-(ii)

The correct answer is:
(p)-(iii), (q)-(i), (r)-(iv), (s)-(ii)

Solution:
Column I	Column II
(p)	3d-transition series	(iii)	Z = 21 to Z = 30 (Zn)
(q)	Lanthanoid series	(i)	Z = 58 to Z = 71 (Lu)
(r)	Actinoid series	(iv)	Z = 90 to Z = 103 (Lr)
(s)	4d-transition series	(ii)	Z = 39 to Z = 48 (Cd)

Topic: Chemistry, Classification of Elements and Periodicity in Properties, JEE Main
Match the column I with column II and mark the appropriate choice.

Column I	Column II
(p)	CH3COONa	(i)	Almost neutral, pH > 7 or < 7
(q)	NH4Cl	(ii)	Acidic, pH < 7
(r)	NaNO3	(iii)	Alkaline, pH > 7
(s)	CH3COONH4	(iv)	Neutral, pH = 7

Options:
A (p)-(i), (q)-(ii), (r)-(iii), (s)-(iv)
B (p)-(ii), (q)-(iii), (r)-(iv), (s)-(i)
C (p)-(iii), (q)-(ii), (r)-(iv), (s)-(i)
D (p)-(iv), (q)-(i), (r)-(iii), (s)-(ii)

The correct answer is:
(p)-(iii), (q)-(ii), (r)-(iv), (s)-(i)

Solution:
(p) CH3COONa⇌CH3COO-Weak acid+Na+Strong base (Basic)
(q) NH4Cl⇌NH4+Weak acid+Cl-Strong acid (Acidic)
(r) NaNO3⇌Na+Strong base+NO3-Strong acid (Neutral)
(s) CH3COONH4⇌CH3COO-Weak acid+NH4+Weak base (Almost neutral)
May be slightly acidic or basic depending upon pKa and pKb values of acid and base.

Topic: Chemistry, Ionic Equilibrium, JEE Main
Match the column I with column II and mark the appropriate choice.

Column I	Column II

(p)	Clark's method	(i)	Na6P6O18

(q)	Calgon's method	(ii)	NaAlSiO4

(r)	Ion-exchange method	(iii)	RSO3H

(s)	Synthetic resins method	(iv)	CaOH2

Options:
A (p)-(i), (q)-(iii), (r)-(iv), (s)-(ii)
B (p)-(ii), (q)-(iii), (r)-(iv), (s)-(i)
C (p)-(iii), (q)-(ii), (r)-(i), (s)-(iv)
D (p)-(iv), (q)-(i), (r)-(ii), (s)-(iii)

The correct answer is:
(p)-(iv), (q)-(i), (r)-(ii), (s)-(iii)

Solution:
Column I	Column II

(p)	Clark's method	(iv)	CaOH2

(q)	Calgon's method	(i)	Na6P6O18

(r)	Ion-exchange method	(ii)	NaAlSiO4

(s)	Synthetic resins method	(iii)	RSO3H

Topic: Chemistry, Chemistry in Everyday Life, JEE Main
Match the column I with column II and mark the appropriate choice.

Column I	Column II

(p)	H2g+Br2gâ2HBrg	(i)	ÎH=ÎU-2RT

(q)	PCl5gâPCl3g+Cl2g	(ii)	ÎH=ÎU+3RT

(r)	N2g+3H2gâ2NH3g	(iii)	ÎH=ÎU

(s)	2N2O5gâ4NO2g+O2g	(iv)	ÎH=ÎU+RT

Options:
A (p)-(iii), (q)-(i), (r)-(ii), (s)-(iv)
B (p)-(iii), (q)-(iv), (r)-(i), (s)-(ii)
C (p)-(ii), (q)-(i), (r)-(iv), (s)-(iii)
D (p)-(iv), (q)-(ii), (r)-(i), (s)-(iii)

The correct answer is:
(p)-(iii), (q)-(iv), (r)-(i), (s)-(ii)

Solution:
(p) Δng=2-2=0; hence ΔH=ΔU
(q) Δng=2-1=1; hence ΔH=ΔU+RT
(r) Δng=2-4=-2; hence ΔH=ΔU-2RT
(s) Δng=5-2=3; hence ΔH=ΔU+3RT

Topic: Chemistry, Thermodynamics (C), JEE Main