datavorous/entrance-exam-dataset huggingface dataset:
According to the following diagram, A reduces BO2 when the temperature is:

Options:
A <1400oC
B >1400oC
C >1200oC but <1400oC
D <1200oC

The correct answer is:
>1400oC

Solution:
A+BO2→B+AO2
This reaction will be spontaneous when
ΔG=−ve

Which we can see from the diagram, is possible only at temperature > 1400 °C

Topic: Chemistry, General Principles and Processes of Isolation of Metals, JEE Main, JEE Main 2020 (09 Jan Shift 1)
According to the Henderson-Hasselbalch equation, how does the pH of a buffer solution change when the ratio of weak acid to its conjugate base is increased?

Options:
A The pH decreases
B The pH increases
C The pH remains unchanged
D The pH becomes neutral

The correct answer is:
The pH remains unchanged

Solution:
According to the Henderson-Hasselbalch equation, when the ratio of weak acid to its conjugate base is increased in a buffer solution, the pH remains unchanged.

Topic: Chemistry, Ionic Equilibrium, NEET
According to the IUCN Red List, what is the status of red panda?

Options:
A Critically endangered species
B Vulnerable species
C Extinct species
D Endangered species

The correct answer is:
Endangered species

Solution:
IUCN is the International Union of Conservation of Nature and Natural resources which are now called world conservation union (WCU). It maintains a red databook or red list which is a catalogue of taxa facing a risk of extinction.
Endangered species are those facing a high risk of extinction in the wild in the near future due to a decrease in its habitat, excessive predation or poaching. The percentage of endangered species in the list of threatened ones is 19% mammals,17% birds, 21% reptiles, 22% amphibians and 19% angiosperms. In India, the number is 54 animals and 113 plants, e.g., red panda, Bentinckia nicobarica.
Critically Endangered: The taxon is facing a very high risk of extinction in the wild and can become extinct any moment in the immediate future, e.g., Sus salvinus (Pigmy Hog), Berberis nilghiriensis, Red panda.
Vulnerable: Presently the population is sufficient but is undergoing depletion due to some factors so that it is facing a risk of extinction in medium-term future, e.g., Antelope cervicarpa.
Extinct: The taxon has been completely eliminated or died out from earth, e.g., Dodo.

Topic: Biology, Biodiversity and its Conservation, NEET
According to the kinetic theory of gases, between two successive collisions, a gas molecule travels

Options:
A In a circular path
B In a wavy path
C In a straight line path
D With an accelerated velocity

The correct answer is:
In a straight line path

Solution:
According to kinetic theory, the gas molecules are in a state of constant rapid motion in all possible directions colliding in a random manner with one another and with the walls of the container and between two successive collisions, molecules travel in a straight line path but show haphazard motion due to collisions.

Topic: Chemistry, States of Matter, JEE Main
According to the kinetic theory of gases, in an ideal gas, between two successive collisions a gas molecule travels

Options:
A
in a wavy path

B
in a straight line path

C
with an accelerated velocity

D
in a circular path

The correct answer is:
in a straight line path

Solution:
According to kinetic theory the gas molecules travel in a straight line path but show haphazard motion due to collisions.

Topic: Chemistry, States of Matter, JEE Main, JEE Main 2003
According to the kinetic theory of gases the r.m.s. velocity of gas molecules is directly proportional to

Options:
A $T$
B $\sqrt{T}$
C $T^2$
D $1 / \sqrt{T}$

The correct answer is:
$\sqrt{T}$

Solution:
$V$ rms $=\sqrt{3rt/M_0}$ i.e. rms velocity of rms velocity of gas is directly proportional to $\sqrt{ T}$.

Topic: Physics, Kinetic Theory of Gases, JEE Main
According to the kinetic theory of gases, total energy of a gas is equal to

Options:
A Potential energy
B Kinetic energy
C Both (a) and (b)
D None of the above

The correct answer is:
Potential energy

Solution:
According to kinetic energy theory gases, there is no attraction force between the molecules of gases, So, potential energy $=0$

Topic: Physics, Kinetic Theory of Gases, JEE Main
According to the modern adsorption theory, what happens to the formed molecules on the catalyst's surface?

Options:
A They remain on the surface permanently
B They evaporate, leaving the surface for fresh reactant molecules
C They diffuse into the bulk of the catalyst
D They react with the inner part of the bulk

The correct answer is:
They evaporate, leaving the surface for fresh reactant molecules

Solution:
The paragraph explains that formed molecules on the catalyst's surface may evaporate, leaving the surface for fresh reactant molecules.

Topic: Chemistry, Surface Chemistry, NEET
According to the modern adsorption theory, what happens when a gas comes in contact with the surface of the catalyst?

Options:
A It diffuses into the bulk of the catalyst
B It reacts with the inner part of the bulk
C Its molecules are held up due to loose chemical combination
D It remains unchanged in mass and composition

The correct answer is:
Its molecules are held up due to loose chemical combination

Solution:
The paragraph states that when a gas comes in contact with the surface of the catalyst, its molecules are held up there due to loose chemical combination.

Topic: Chemistry, Surface Chemistry, NEET
According to the molecular orbital theory which of the following statement is incorrect?
[LUMO = lowest unoccupied molecular orbital]

Options:
A LUMO level for C2 molecule is σ2px orbital.
B In C2 molecules both the bonds π are bonds
C In C22- ion there is one σ and two π bonds
D C2 is paramagnetic but C22- is diamagnetic.

The correct answer is:
C2 is paramagnetic but C22- is diamagnetic.

Solution:
C2=Ï1s2<Ï*1s2<Ï2s2<Ï*2s2<Ï2py2 = Ï2py2HOMO<Ï2pxoLUMO , all electrons are paired so diamagnetic.

Topic: Chemistry, Chemical Bonding and Molecular Structure, JEE Main
According to the paragraph, what happens to physical adsorption with increasing temperature?

Options:
A It increases.
B It decreases.
C It remains constant.
D It becomes irreversible.

The correct answer is:
It decreases.

Solution:
The paragraph mentions that physical adsorption decreases with increasing temperature.

Topic: Chemistry, Surface Chemistry, NEET
According to the paragraph, what remains bonded to the cobalt ion during the reaction in all the compounds?

Options:
A Chloride ions only
B Ammonia molecules only
C Both chloride ions and ammonia molecules
D Neither chloride ions nor ammonia molecules

The correct answer is:
Both chloride ions and ammonia molecules

Solution:
The paragraph states that in all the compounds, either chloride ions or ammonia molecules or both remain bonded to the cobalt ion during the reaction.

Topic: Chemistry, Coordination Compounds, NEET
According to the Periodic Law of elements, the variation in properties of elements is related to their

Options:
A
nuclear masses

B
atomic numbers

C
nuclear neutron-proton number ratios

D
atomic masses

The correct answer is:
atomic numbers

Solution:
The properties of elements change with a change in atomic number.

Topic: Chemistry, Classification of Elements and Periodicity in Properties, JEE Main, JEE Main 2003
According to the sliding filament theory:

Options:
A Actin and myosin filaments slide over each other to increase the length of the sarcomere.
B Length of A-band does not change.
C I-band increases in length
D The actin filaments slide away from A-band resulting in shortening of sarcomere.

The correct answer is:
Length of A-band does not change.

Solution:
According to Sliding filament theory, thin. Filament slide over Thick filament (mainly myosin). That is why the length of $\mathrm{A}$ band does not change as A band is made up of thick filament.

Topic: Biology, Locomotion and Movement, NEET, NEET 2022 (Phase 2)
According to the three domain classification, Methanococcus and Rhizobium belong to

Options:
A same domain and different kingdom.
B same domain and same kingdom.
C different domain and different kingdom.
D different domain and same kingdom.

The correct answer is:
different domain and different kingdom.

Solution:
The three-domain system proposed by Carl Woese divides Kingdom Monera into two domains on the basis of differences in 16S rRNA genes: Archaea and Bacteria. The third domain is Eukaryota which has all eukaryotes. Also, there are 6 kingdoms- Archaebacteria in domain Archaea, Eubacteria in domain Bacteria and Protista, Fungi, Plantae and Animalia in the domain Eukaryota. Methanococcus lies in Archaebacteria in domain Archaea and Rhizobium lies in Eubacteria in domain Bacteria.

Topic: Biology, Biological Classification, NEET
According to the wave-particle duality of matter by de-Broglie, which of the following graph plot presents most appropriate relationship between wavelength of electron λ and momentum of electron p?

Options:
A
B
C
D

The correct answer is:

Solution:
According to the de-Broglie hypothesis according to which all matters have both particle and wave nature. where h= plank's constant, p=momentum, λ= wavelength of particle. This type of graph is called a rectangular hyperbola. As λ∝1p we will have a rectangular hyperbola.

λ=hpλ∝1p

⇒λp=h (constant)

So, the plot is a rectangular hyperbola.

Topic: Chemistry, Structure of Atom, JEE Main, JEE Main 2024 (01 Feb Shift 1)
According to Thomson's experiments, what effect does a lighter particle have on its deflection in the presence of an electric or magnetic field?

Options:
A Lighter particles experience greater deflection.
B Lighter particles experience lesser deflection.
C Lighter particles remain unaffected.
D Lighter particles behave unpredictably.

The correct answer is:
Lighter particles experience greater deflection.

Solution:
In Thomson's experiments, it was observed that lighter particles experience greater deflection in the presence of an electric or magnetic field.

Topic: Chemistry, Structure of Atom, NEET
According to Transpiration pull theory, all the given factors contributes to ascent of sap, except

Options:
A Cohesive and adhesive forces of water
B Vertical water column in xylem fibres and xylem parenchyma.
C Continuity of water column
D Transpiration pull.

The correct answer is:
Vertical water column in xylem fibres and xylem parenchyma.

Solution:
According to transpiration pull theory proposed by Dixon and Jolly cohesive and adhesive forces of water and transpiration pull generated in leaves causes ascent of sap. Continuous vertical water column is maintained in xylem vessels and xylem tracheids through which upward movement of water occurs.

Topic: Biology, Transport in Plants, NEET
According to Valence Bond Theory, the number of unpaired electrons present in MnCl63-, Fe(CN)63- and CoC2O43-, respectively, are

Options:
A 0 ; 5 ; 0
B 4 ; 3 ; 2
C 4 ; 1 ; 0
D 5 ; 4 ; 3

The correct answer is:
4 ; 1 ; 0

Solution:
In MnCl63- oxidation state of manganese is +3,

Mn+3, electronic configuration is Ar3d44s0, due to the presence of weak field ligand Cl-pairing of electrons do not occur, so the number of unpaired electrons are 4.

In FeCN63- oxidation state of Fe is +3,

Fe+3 electronic configuration is Ar3d54s0

Due to the presence of strong field pairing of electrons takes place but one electron remains unpaired, t2g5 configuration is seen.

InCoC2O43-, cobalt shows +3 oxidation state and electronic configuration, Ar3d64s0.

As C2O42- behaves as a strong field ligand in complexes with cobalt, paring of electrons takes place and no unpaired electrons are left in this case.

Topic: Chemistry, Coordination Compounds, TS EAMCET, TS EAMCET 2021 (05 Aug Shift 1)
According to Werner's theory

Options:
A Primary valency can be ionized
B Secondary valency can be ionized
C Primary and secondary valencies both cannot be ionized
D Only primary valency cannot be ionized

The correct answer is:
Primary valency can be ionized

Solution:
According to Werner's theory, a coordination compound has two different types of valency, primary and secondary. The primary valency or the ionisable valency is satisfied by the negative charged ions in the solution.

Topic: Chemistry, Coordination Compounds, JEE Main
According to widely accepted "fluid mosaic model" cell membranes are semifluid, where lipids and integral proteins can diffuse randomly. In recent years, this model has been modified in several respects. In this regard, which of the following statements is incorrect?

Options:
A Proteins in cell membranes can travel within the lipid bilayer.
B Proteins can also undergo flip-flip movements in the lipid bilayer.
C Proteins can remain confined within certain domains of the membrane.
D Many proteins remain completely embedded wit him the lipid bilayer.

The correct answer is:
Proteins can also undergo flip-flip movements in the lipid bilayer.

Solution:
According to this model, plasma membrane is formed of "protein icebergs in the sea of lipids." The phospholipid form a bilayer which is interrupted by the embedded protein molecules. The amount of proteins varies in different membranes. The phospholipid bilayer is a twodimensional fluid which allows the movement of proteins and phospholipid. The phospholipid molecules show two types of movements in this layer.
(i) Transition Movement: Change in the position of molecules within the same layer.
(ii) Flip-flop Movement : The molecules of the two layers of the bilayer can be interchanged.
Related Theory
Depending on the degree of association and the ability of separation, the membrane proteins are classified into two types, which are: internal proteins also known as intrinsic or integral proteins and the external proteins also known as extrinsic or peripheral proteins. The integral or intrinsic proteins account for $70 \%$ of the total membrane proteins and pass into the lipid bilayer to different depths. They cannot be easily separated from the membrane without disrupting it. Some of them run throughout the lipid bilayer called tunnel proteins or transmembrane proteins and form channels for the passage of water-and water-soluble substances individually or in a group.

Topic: Biology, Cell - The Unit of Life, NEET, NEET 2005
Accumulation of which of the following molecules in the muscles occurs as a result of vigorous exercise?

Options:
A Glycogen
B Pyruvic acid
C Glucose
D L-lactic acid

The correct answer is:
L-lactic acid

Solution:
As the muscles work harder during times of extreme exercises, the amount of oxygen needed to use during energy production runs short, and the muscle cells turn to another process called anaerobic metabolism. The product of this process of obtaining energy anaerobically is lactic acid. When the muscle cells continue to work anaerobically, lactic acid can build up in the muscles.

Topic: Chemistry, Biomolecules, JEE Main, JEE Main 2015 (11 Apr Online)
Acetamide changes into methylamine by

Options:
A Hofmann bromamide reaction
B Hofmann reaction
C Friedel-Craft's reaction
D Hinsberg reaction

The correct answer is:
Hofmann bromamide reaction

Solution:
Hofmann bromamide reaction: When an amide is treated with bromine in an aqueous or ethanolic solution of sodium hydroxide, degradation of amide takes place leading to the formation of primary amine.

Topic: Chemistry, Amines, JEE Main
Acetamide is treated separately with the following reagents. Which one of these would give methylamine?

Options:
A PCl5
B Br2 and NaOH
C P4O10
D LiAlH4

The correct answer is:
Br2 and NaOH

Solution:
This is a case of Hofmann reaction:
The Hofmann bromamide is the organic reaction of conversion of a primary amide to a primary amine with one fewer carbon atom.
CH 3 CONH 2  +  Br 2  + 4 NaOH→ CH 3 NH 2  +  Na 2 CO 3  + 2 NaBr + 2  H 2 O

Topic: Chemistry, Amines, JEE Main
Acetic acid and propionic acid have Ka values 1.75Ã10-5 and 1.3 ×  10 −5 respectively at a certain temperature. An equimolar solution of a mixture of the two acids is partially neutralized by NaOH. How is the ratio of the contents of acetate and propionate ions related to the Ka values and the molarity ?

Options:
A α1-α=1.751.3×β1-β, where α and β are ionized fractions of the acids
B The ratio is unrelated to the Ka values
C The ratio is unrelated to the molarity
D The ratio is unrelated to the pH of the solution

The correct answer is:
α1-α=1.751.3×β1-β, where α and β are ionized fractions of the acids

Solution:
In a given mixture, the ionization of two acids can be written as : Let Î±,Î² be degree of ionization at same concentration.
CH3COOH1-Î±âCH3COO-+Î±H+Î±+Î²
C2H5COOH1-Î²âC2H5COO-+Î²H+Î±+Î²
∴  K Acetic acid  =  α α + β ·c 1−α
K Propionic acid  =  β α + β ⋅c 1−β
∴  K Acetic acid K Propionic acid  =  α 1−α  ×  1−β β
or Î±1-Î±=1Â·751Â·3ÃÎ²1-Î²

Topic: Chemistry, Ionic Equilibrium, JEE Main
Acetic acid ( CH3COOH ) is partially dimerised to CH3COOH2 in the vapour phase. At a total pressure of 0.200 atm , acetic acid is 92.0% dimerized at 298 K . The value of equilibrium constant of dimerization under these conditions is

Options:
A 57.5â atm â1
B 9.7â atm â1
C 97â atm â1
D 194  atm −1

The correct answer is:
194  atm −1

Solution:
According to question; 0.46 a + 0.08 a = 0.2
∴ a =  0.2 0.54
K P = 0.46× 0.2 0.54 0.08× 0.2 0.54 2
=194  atm −1

Topic: Chemistry, Chemical Equilibrium, JEE Main
Acetic acid exists as a dimer in benzene solution. This is due to

Options:
A Condensation
B Presence of $-\mathrm{COOH}$ group
C Presence of $\alpha$-hydrogen
D Hydrogen bonding

The correct answer is:
Hydrogen bonding

Solution:
Due to $\mathrm{H}$-bonding

Topic: Chemistry, Carboxylic Acid Derivatives, JEE Main
Acetic acid is obtained when

Options:
A Methyl alcohol is oxidised with potassium permanganate
B Calcium acetate is distilled in the presence of calcium formate
C Acetaldehyde is oxidised with potassium dichromate and sulphuric acid
D Glycerol is heated with sulphuric acid

The correct answer is:
Acetaldehyde is oxidised with potassium dichromate and sulphuric acid

Solution:
$\mathrm{CH}_3 \mathrm{CHO} \xrightarrow[\mathrm{H}_2 \mathrm{SO}_4]{\mathrm{K}_2 \mathrm{Cr}_7} \mathrm{CH}_3 \mathrm{COOH}$

Topic: Chemistry, Carboxylic Acid Derivatives, JEE Main
Acetic acid is reacted with metallic sodium to form hydrogen and $X$. When $X$ is heated with sodalime, $Y$ and sodium carbonate are formed. $Y$ is

Options:
A $\mathrm{C}_2 \mathrm{H}_6$
B $\mathrm{CH}_4$
C $\mathrm{CH}_3 \mathrm{COONa}$
D $\mathrm{CH}_3 \mathrm{CONH}_2$

The correct answer is:
$\mathrm{CH}_4$

Solution:

Topic: Chemistry, Carboxylic Acid Derivatives, JEE Main
Acetic acid on heating with \(\mathrm{NH}_3\) forms \(A\). When \(A\) reacts with \(\mathrm{LiAlH}_4\) followed by hydrolysis gives \(B\). When \(B\) is heated with chloroform in \(\mathrm{KOH}\) medium gives \(C\). What are \(B\) and \(C\) respectively?

Options:
A \(\mathrm{CH}_3 \mathrm{CONH}_2, \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{NC}\)
B \(\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{NH}_2, \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{NC}\)
C \(\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{NH}_2, \mathrm{CH}_3 \mathrm{COOH}\)
D \(mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{NH}_2, \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{NC}\)

The correct answer is:
\(\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{NH}_2, \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{NC}\)

Solution:

Topic: Chemistry, Carboxylic Acid Derivatives, JEE Main
Acetic acid reacts with $\mathrm{PCl}_s$ to form

Options:
A $\mathrm{CH}_3 \mathrm{COCl}$
B $\mathrm{CHCl}_2 \mathrm{COOH}$
C $\mathrm{CH}_2 \mathrm{ClCOOH}$
D $\mathrm{CH}_3 \mathrm{COOCl}$

The correct answer is:
$\mathrm{CH}_3 \mathrm{COCl}$

Solution:
When acetic acid is reacted with $\mathrm{PCl}_5$, the product formed are acetyl chloride, phosphoryl chloride and hydrochloric acid

Topic: Chemistry, Carboxylic Acid Derivatives, JEE Main
Acetic acid will be obtained on oxidation of

Options:
A Ethanol
B Propanal
C Methanal
D Glyoxal

The correct answer is:
Ethanol

Solution:
Since acetic acid has two carbon atom so it will be produced by reduction of the two carbon conataing alcohol.

Acetic acid is obtained by the oxidation of ethanol with alkaline KMnO4.
C2H5OH+O→Alkaline KMnO4 CH3COOH
Ethanol acetic acid

Topic: Chemistry, Alcohols Phenols and Ethers, JEE Main
Acetoacetic ester behaves as

Options:
A An unsaturated hydroxy compound
B A keto compound
C Both of these ways
D None of these

The correct answer is:
Both of these ways

Solution:

Topic: Chemistry, Carboxylic Acid Derivatives, JEE Main
Acetone and acetaldehyde are

Options:
A Position isomers
B Functional isomers
C Not isomers
D Chain isomers

The correct answer is:
Position isomers

Solution:
Acetone has ketone functional group and propanal has aldehyde functional group therefore, these are functional isomers.

Topic: Chemistry, Aldehydes and Ketones, JEE Main
Acetone on addition to methyl magnesium bromide forms a complex, which on decomposition with acid gives Xand Mg(OH)Br. Which one of the following is X?

Options:
A CH3OH
B CH33COH
C CH32CHOH
D CH3CH2OH

The correct answer is:
CH33COH

Solution:
Complex

Topic: Chemistry, Aldehydes and Ketones, JEE Main
Acetone on treatment with CH 3 −Mg−I and on further hydrolysis gives

Options:
A Isopropyl alcohol
B Primary alcohol
C Acetic acid
D 2-methyl 2-propanol

The correct answer is:
2-methyl 2-propanol

Solution:
Acetone reacts with Grignard's reagent to give tertiary alcohol.
(CH 3 ) 2 C = O +  CH 3 MgBr → H 2 O (CH 3 ) 3 C−OH tert-butyl alcohol

Topic: Chemistry, Alcohols Phenols and Ethers, JEE Main
Acetophenone is prepared by the reaction of which of the following in the presence of $\mathrm{AlCl}_3$ catalyst

Options:
A Phenol and acetic acid
B Benzene and acetone
C Benzene and acetyl chloride
D Phenol and acetone

The correct answer is:
Benzene and acetyl chloride

Solution:

Topic: Chemistry, Aldehydes and Ketones, JEE Main
Acetophenone is prepared from

Options:
A Rosenmund reaction
B Sandmayer reaction
C Wurtz reaction
D Friedel craft reaction

The correct answer is:
Friedel craft reaction

Solution:
Explanation:The Friedel-Crafts acylation reaction is a common method for preparing ketones like acetophenone. In this reaction, benzene reacts with an acyl chloride (such as acetyl chloride) in the presence of a Lewis acid catalyst (like $\mathrm{A} 1 \mathrm{Cl}$ ) to form acetophenone.
The reaction is as follows:
\(\mathrm{C}_6 \mathrm{H}_6+\mathrm{CH}_3 \mathrm{COCl} \xrightarrow{\text { anhydrous aluminium chloride }} \mathrm{C}_6 \mathrm{H}_5 \mathrm{COCH}_3+\mathrm{HCl}\)
This reaction introduces the acetyl group $\left(\mathrm{COCH} 3 \mathrm{COCH}_3\right)$ to the benzene ring, forming acetophenone.

Topic: Chemistry, Aldehydes and Ketones, JEE Main
Acetophenone is prepared from

Options:
A Rosenmund reaction
B Sandmayer reaction
C Wurtz reaction
D Friedel craft reaction

The correct answer is:
Friedel craft reaction

Solution:
acetophenone can be prepared by Friedel Craft's acylation. Acetyl chloride reacts with benzene in the presence of anhydrous aluminum chloride to form acetophenone.
Acetophenone

Topic: Chemistry, Aldehydes and Ketones, JEE Main
Acetophenone when reacted with a base, $\mathrm{C}_2 \mathrm{H}_5 \mathrm{ONa}$, yields a stable compound which has the structure?

Options:
A

B

C

D

The correct answer is:

Solution:
It show condensation reaction

Topic: Chemistry, Aldehydes and Ketones, NEET, NEET 2008 (Mains)
Acetophenone when reacted with a base, $\mathrm{C}_2 \mathrm{H}_5 \mathrm{ONa}$, yields a stable compound which has the structure?

Options:
A

B

C

D

The correct answer is:

Solution:
It show condensation reaction

Topic: Chemistry, Aldehydes and Ketones, JEE Main
Acetyl bromide reacts with excess of $\mathrm{CH}_3 \mathrm{Mgl}$ followed by treatment with a saturated solution of $\mathrm{NH}_4 \mathrm{Cl}$ given

Options:
A
acetone

B
acetyl iodide

C
2- methyl -2-propanol

D
acetamide

The correct answer is:
2- methyl -2-propanol

Solution:
No Solution Available

Topic: Chemistry, Alcohols Phenols and Ethers, JEE Main, JEE Main 2004