datavorous/entrance-exam-dataset huggingface dataset:
When chlorine is passed over dry slaked lime at room temperature, the main reaction product is

Options:
A $\mathrm{Ca}\left(\mathrm{ClO}_2\right)_2$
B $\mathrm{CaCl}_2$
C $\mathrm{CaOCl}_2$
D $\mathrm{Ca}\left(\mathrm{OCl}_2\right)_2$

The correct answer is:
$\mathrm{CaOCl}_2$

Solution:
$\underset{\text { (slaked lime) }}{\mathrm{Ca}(\mathrm{OH})_2}+\mathrm{Cl}_2 \rightarrow \mathrm{CaOCl}_2+\mathrm{H}_2 \mathrm{O}$

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), JEE Main
When $\mathrm{Cl}_2$ gas is passed through hot and conc. solution of $\mathrm{KOH}$, following compound is formed

Options:
A $\mathrm{KCl}$
B $\mathrm{KClO}_3$
C $\mathrm{KClO}_2$
D $\mathrm{KClO}_4$

The correct answer is:
$\mathrm{KClO}_3$

Solution:
$6 \mathrm{KOH}+3 \mathrm{Cl}_2 \rightarrow 5 \mathrm{KCl}+\mathrm{KClO}_3+3 \mathrm{H}_2 \mathrm{O}$

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), JEE Main
When $\mathrm{CO}_{2(\mathrm{~g})}$ is passed over red hot coke it partially gets reduced to $\mathrm{CO}(g)$. Upon passing $0.5 \mathrm{~L}$ of $\mathrm{CO}_2(g)$ over red hot coke, the total volume of the gases increased to $700 \mathrm{~mL}$. The composition of the gaseous mixture at STP is

Options:
A
$\mathrm{CO}_2=300 \mathrm{~mL} ; \mathrm{CO}=400 \mathrm{~mL}$

B
$\mathrm{CO}_2=0.0 \mathrm{~mL} ; \mathrm{CO}=700 \mathrm{~mL}$

C
$\mathrm{CO}_2=200 \mathrm{~mL} ; \mathrm{CO}=500 \mathrm{~mL}$

D
$\mathrm{CO}_2=350 \mathrm{~mL} ; \mathrm{CO}=350 \mathrm{~mL}$

The correct answer is:
$\mathrm{CO}_2=300 \mathrm{~mL} ; \mathrm{CO}=400 \mathrm{~mL}$

Solution:
$\mathrm{CO}_2+\mathrm{C} \longrightarrow 2 \mathrm{CO}$
Stoichoimetry ratio is $1: 2$
AT STP, $P=1 \mathrm{~atm}, T=273 \mathrm{~K}, R=0.0821$
Initial moles of $\mathrm{CO}_2 ; n\left(\mathrm{CO}_2\right.$ initial $)=\frac{P V}{R T}$ $=\frac{1 \times 0.5}{0.0821 \times 273}=0.022 \mathrm{~mole}$
In final mixture no. of moles; $n\left(\mathrm{CO}_2 / \mathrm{CO}\right.$ mixture)
$$
=\frac{1 \times 0.7}{0.0821 \times 273}=0.031
$$
Increase in volume is by $=0.031-0.022$ $=0.009$ mole of gas
Final no. of moles of $\mathrm{CO}$ i.e. $n_{\text {(CO final) }}$
$$
\begin{aligned}
& n_{\text {(CO final) }}=2 n_{\left(\mathrm{CO}_2 \text { initial }\right)}-n_{\left(\mathrm{CO}_2\right. \text { final) }} \\
& \quad=2\left(0.022-\mathrm{n}_{\left(\mathrm{CO}_2 \text { final }\right)}\right. \\
& \left.n_{\text {(CO final) }}=0.044-2 n_{\text {(CO }} \text { final }\right) \\
& \therefore \text { Now, } n_{\text {(CO final) }}+n_{\text {(CO final) }}=0.031 \\
& n_{\left(\mathrm{CO}_2\right. \text { final) }}=0.031-n_{\text {(CO final) })} \ldots \text { (iii) }
\end{aligned}
$$
Substituting (ii) in eq. (i)
$$
\begin{aligned}
& n_{\text {(CO final) }}=0.044-2\left[0.031-n_{\text {(CO final) }}\right. \\
& n_{\text {(CO final) }}=0.044-0.062+2 n_{\text {(CO final })}
\end{aligned}
$$
$$
n_{(\mathrm{CO} \text { final) }}=0.018 \mathrm{~mol} .
$$
Volume of $\mathrm{CO}=V=\frac{n R T}{P}=\frac{0.018 \times 0.0821 \times 273}{1}$ $=0.40$ Litre
and volume of $\mathrm{CO}_2=0.7$ litre $-0.4$ litre $=0.3$ litre
$$
\therefore \mathrm{CO}_2=300 \mathrm{~mL}, \mathrm{CO}=400 \mathrm{~mL}
$$

Topic: Chemistry, Some Basic Concepts of Chemistry, JEE Main, JEE Main 2012 (19 May Online)
When cold $\mathrm{NaOH}$ reacts with $\mathrm{Cl}_2$ which of the following is formed

Options:
A $\mathrm{NaClO}$
B $\mathrm{NaClO}_2$
C $\mathrm{NaClO}_3$
D None of these

The correct answer is:
$\mathrm{NaClO}$

Solution:
$2 \mathrm{NaOH}+\mathrm{Cl}_2 \rightarrow \mathrm{NaClO}+\mathrm{NaCl}+\mathrm{H}_2 \mathrm{O}$

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), JEE Main
When conc. sulphuric acid is added slowly to a solution of ferrous sulphate containing nitrate ion, a brown colour ring is formed. The composition of the ring is

Options:
A $\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_5 \mathrm{NO}\right] \mathrm{SO}_4$
B $\mathrm{FeSO}_4 \cdot \mathrm{NO}_2$
C $\mathrm{Fe}\left[\left(\mathrm{H}_2 \mathrm{O}\right)_5\right]\left(\mathrm{NO}_3\right)_2$
D None of these

The correct answer is:
$\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_5 \mathrm{NO}\right] \mathrm{SO}_4$

Solution:
$\mathrm{NO}_3^{-}+\mathrm{H}_2 \mathrm{SO}_4 \rightarrow \mathrm{HNO}_3+\mathrm{HSO}_4^{-}$
$2 \mathrm{HNO}_3 \rightarrow \mathrm{H}_2 \mathrm{O}+2 \mathrm{NO}+3[\mathrm{O}]$
$\mathrm{FeSO}_4+\mathrm{NO}+5 \mathrm{H}_2 \mathrm{O} \rightarrow \underset{\text{Brown ring complex}}{\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_5 \mathrm{NO}^{+}\right] \mathrm{SO}_4}$

Topic: Chemistry, d and f Block Elements, JEE Main
When concentrated HCl is added to aqueous solution of CoCl2, its colour changes from reddish pink to deep blue. Which complex ion gives blue colour in reaction?

Options:
A CoCl64-
B CoCl63-
C CoH2O62+
D CoCl42-

The correct answer is:
CoCl42-

Solution:
On addition of conc. HCl. The equilibrium between two coloured Co (II) species can be described by equation
CoH2O6aq2++4Claq-⇌CoCl4aq2-+6H2OℓPinkBlue
The equilibrium is disturbed by changing the conc. of Cl- ions by addition of conc. HCl in forward direction.

Topic: Chemistry, Coordination Compounds, JEE Main, JEE Main 2015 (11 Apr Online)
When copper sulphate solution is electrolysed in a copper voltameter for 30 sec, then m gram of copper was deposited. Time current graph for the electrolysis is

The electrochemical equivalent of copper from above plot will be

Options:
A Z = m
B Z=m2
C Z=m5
D Z=2m

The correct answer is:
Z=m2

Solution:
m = ZIt
Z=mIt
It = Total charge passed through copper voltameter
= Area under the curve
=100×10×10-3+212×10×100×10-3=2
So Z=m2

Topic: Chemistry, Electrochemistry, JEE Main
When \(\Delta \mathrm{H}_{\mathrm{vap}}=30 \mathrm{~kJ} / \mathrm{mol}\) and \(\Delta \mathrm{S}_{\mathrm{vap}}=75 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\), then the temperature of vapour, at one atmosphere is ______ \(\mathrm{K}\).

Options:

The correct answer is:
400

Solution:
At equilibrium $\Delta \mathrm{G}_{\mathrm{PT}}=0$
$\begin{aligned}
& \Delta \mathrm{H}_{\text {vap }}=\mathrm{T} \Delta \mathrm{S}_{\text {vap }} \\
& 30 \times 1000=\mathrm{T} \times 75 \\
& \mathrm{~T}=400 \mathrm{~K}
\end{aligned}$

Topic: Chemistry, Thermodynamics (C), JEE Main, JEE Main 2024 (09 Apr Shift 2)
When dilute H2SO4 and H2O2 are added to a solution of chromate ions, an intense blue colour is produced, which is stable in ether. This is due to the formation of

Options:
A Cr2O72-
B Cr2O3
C CrO5
D CrO3

The correct answer is:
CrO5

Solution:
The blue colour is due to the formation of CrO5
CrO42-+2H++2H2O2→CrO5Blue+3H2O

Topic: Chemistry, d and f Block Elements, JEE Main
When does a gas deviate the most from its ideal behavior?

Options:
A At low pressure and high temperature
B At high pressure and high temperature
C At low pressure and low temperature
D At high pressure and low temperature

The correct answer is:
At high pressure and low temperature

Solution:
At high pressure & low temperature gas almost near liquefaction range with
(i) - Intense intermolecular forces
(ii) - Volume occupied by molecules is substantial due to low intermolecular distances.

Topic: Chemistry, States of Matter, JEE Main, JEE Main 2015 (11 Apr Online)
When does an equilibrium between the liquid phase and vapor phase occur?

Options:
A When the liquid has completely evaporated.
B When the vapor pressure becomes zero.
C When the vapor pressure remains constant.
D When the liquid turns into a solid.

The correct answer is:
When the vapor pressure remains constant.

Solution:
An equilibrium is established between the liquid phase and vapor phase when the vapor pressure remains constant.

Topic: Chemistry, States of Matter, NEET
When does the surface tension of a liquid decrease?

Options:
A When the temperature decreases
B When the temperature remains constant
C When the temperature increases
D When pressure increases

The correct answer is:
When the temperature increases

Solution:
The surface tension of a liquid decreases as the temperature is raised.

Topic: Chemistry, States of Matter, NEET
When domestic sewage mixes with river water

Options:
A small animals like rats will die after drinking river water
B the increased microbial activity releases micronutrients such as iron
C the increased microbial activity uses up dissolved oxygen
D the river water is still suitable for drinking as impurities are only about $0.1 \%$

The correct answer is:
the increased microbial activity uses up dissolved oxygen

Solution:
Domestic sewage consists a lot of degradable organic matter. When this sewage is released into river water, it will result in an increase of Biochemical Oxygen Demand (BOD) and decrease in the amount of dissolved oxygen due to decomposing activity of microbes.

Topic: Biology, Microbes in Human Welfare, NEET, NEET 2010 (Mains)
When during electrolysis of a solution of $\mathrm{AgNO}_3 9650$ coulombs of charge pass through the electroplating bath, the mass of silver deposited on the cathode will be

Options:
A
$10.8 \mathrm{~g}$

B
$21.6 \mathrm{~g}$

C
$108 \mathrm{~g}$

D
$1.08 \mathrm{~g}$

The correct answer is:
$10.8 \mathrm{~g}$

Solution:
No. of moles of silver $=\frac{9650}{96500}=\frac{1}{10}$ moles
$\therefore$ Mass of silver deposited $=\frac{1}{10} \times 108=10.8 \mathrm{~g}$

Topic: Chemistry, Electrochemistry, JEE Main, JEE Main 2003
When electric current is passed through an ionic hydride in the molten state

Options:
A Hydrogen is liberated at the anode
B Hydrogen is liberated at the cathode
C No reaction takes place
D Hydride ion migrates towards cathode

The correct answer is:
Hydrogen is liberated at the anode

Solution:
Hydrogen is liberated at the anode

Topic: Chemistry, Hydrogen, JEE Main
When electric current is passed through an ionic hydride in the molten state,

Options:
A Hydrogen is liberated at the cathode
B Hydrogen is liberated at the anode
C Hydride ion migrates towards cathode
D No reaction takes place

The correct answer is:
Hydrogen is liberated at the anode

Solution:
M+H-→M++ H-
hydride ion
H-→12H2+e- at anode

Topic: Chemistry, Hydrogen, JEE Main
When electrons are trapped into the crystal in anion vacancy, the defect is known as

Options:
A Schotky defect
B Frenkel defect
C Stoichiometric defect
D F-centres

The correct answer is:
F-centres

Solution:
F-centres are the sites where anions are missing and instead electrons are present. they are responsible for colour.

Topic: Chemistry, Solid State, JEE Main
When enthalpy and entropy change for a chemical reaction are $-2.5 \times 10^3 \mathrm{cal}$ and $7.4 \mathrm{cal}^{-1} \mathrm{deg}^{-1}$ respectively. Predict the reaction at $298 K_{\text {is }}$

Options:
A Spontaneous
B Reversible
C Irreversible
D Non-spontaneous

The correct answer is:
Spontaneous

Solution:
When $\Delta H=-\mathrm{v}_G \Delta S=+\mathrm{ve}_e$ and $\Delta G=-\mathrm{ve}_e$ than reaction is spontaneous.

Topic: Chemistry, Thermodynamics (C), JEE Main
When enthanol is heated with conc. H2SO4, a gas is produced. The compound formed, when this gas is treated with cold dilute aqueous solution of Baeyer's reagent, is

Options:
A Formaldehyde
B Formic acid
C Glycol
D Ethanoic acid

The correct answer is:
Glycol

Solution:
Ethanol undergoes dehydration by heating it with concentrated H2SO4 at 443 K.

C2H5OH→443 KH2SO4CH2=CH2+H2O

Alkenes on reaction with cold, dilute, aqueous solution of potassium permanganate (Baeyer’s reagent) produce vicinal glycols. Decolorisatlon of KMnO4 solution is used as a test for unsaturation.

Topic: Chemistry, Alcohols Phenols and Ethers, JEE Main, JEE Main 2022 (29 Jul Shift 2)
When equal volume of \(1 \mathrm{M} \mathrm{HCl}\) and \(1 \mathrm{M} \mathrm{H}_2 \mathrm{SO}_4\) are separately neutralised by excess volume of \(1 \mathrm{M}\) \(\mathrm{NaOH}\) solution. \(x\) and \(y \mathrm{~kJ}\) of heat is liberated respectively. The value of \(y / x\) is _______

Options:

The correct answer is:
2

Solution:
$\begin{aligned} & \mathrm{H}^{+}+\mathrm{OH}^{-} \rightarrow \mathrm{H}_2 \mathrm{O} \Rightarrow \mathrm{x} \\ & 2 \mathrm{H}^{+}+2 \mathrm{OH}^{-} \rightarrow 2 \mathrm{H}_2 \mathrm{O} \Rightarrow 2 \mathrm{x}=\mathrm{y} \\ & \mathrm{y} / \mathrm{x}=2\end{aligned}$

Topic: Chemistry, Thermodynamics (C), JEE Main, JEE Main 2024 (09 Apr Shift 1)
When ethyl alcohol and $\mathrm{K}$ l reacted in presence of $\mathrm{Na}_2 \mathrm{CO}_3$, yellow crystals of...... are formed

Options:
A $\mathrm{CHI}_3$
B $\mathrm{CH}_3 \mathrm{I}$
C $\mathrm{CH}_2 \mathrm{I}_2$
D $\mathrm{C}_2 \mathrm{H}_5 \mathrm{I}$

The correct answer is:
$\mathrm{CHI}_3$

Solution:
$\mathrm{C}_2 \mathrm{H}_5 \mathrm{OH} \underset{\mathrm{Na}_2 \mathrm{CO}_3}{\mathrm{Kl}} \mathrm{CHI}_3$

Topic: Chemistry, Haloalkanes and Haloarenes, JEE Main
When ethyl alcohol $\left(\mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}\right)$ reacts with thionyl chloride, in the presence of pyridine, the product obtained is

Options:
A $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{Cl}+\mathrm{HCl}$
B $\mathrm{C}_2 \mathrm{H}_5 \mathrm{Cl}+\mathrm{HCl}+\mathrm{SO}_2$
C $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{Cl}+\mathrm{H}_2 \mathrm{O}+\mathrm{SO}_2$
D $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{Cl}+\mathrm{HCl}+\mathrm{SO}_2$

The correct answer is:
$\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{Cl}+\mathrm{HCl}+\mathrm{SO}_2$

Solution:
$\mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}+\mathrm{SOCl}_2 \xrightarrow{\text { Pyridine }} \mathrm{C}_2 \mathrm{H}_5 \mathrm{Cl}+\mathrm{SO}_2+\mathrm{HCl}$

Topic: Chemistry, Haloalkanes and Haloarenes, JEE Main
When ethyl iodide and propyl iodide react with Na in the presence of ether, they form

Options:
A One alkane
B Two alkanes
C Four alkanes
D Three alkanes

The correct answer is:
Three alkanes

Solution:
$\mathrm{C}_2 \mathrm{H}_5 \mathrm{I}+2 \mathrm{Na}+\mathrm{C}_3 \mathrm{H}_7 \mathrm{I} \underset{\text { Ether }}{\text { Dry }} \underset{\text { Pentane }}{\mathrm{C}_2 \mathrm{H}_5-\mathrm{C}_3 \mathrm{H}_7+2 \mathrm{Nal}}$
$\mathrm{C}_2 \mathrm{H}_5 \mathrm{I}+2 \mathrm{Na}+\mathrm{C}_2 \mathrm{H}_5 \mathrm{I} \xrightarrow[\text { Ether }]{\text { Dry }} \underset{\text { Butane }}{\mathrm{C}_2 \mathrm{H}_5-\mathrm{C}_2 \mathrm{H}_5+2 \mathrm{NaI}}$
$\mathrm{C}_3 \mathrm{H}_7 \mathrm{I}+2 \mathrm{Na}+\mathrm{C}_3 \mathrm{H}_7 \mathrm{I} \underset{\text { Ether }}{\text { Dry }} \underset{\text { Hexane }}{\mathrm{C}_3 \mathrm{H}_7-\mathrm{C}_3 \mathrm{H}_7}+2 \mathrm{Nal}$

Topic: Chemistry, Hydrocarbons, JEE Main
When ethyl iodide and propyl iodide react with Na in the presence of ether, they form

Options:
A One alkane
B Two alkanes
C Four alkanes
D Three alkanes

The correct answer is:
Three alkanes

Solution:
$\mathrm{C}_2 \mathrm{H}_5 \mathrm{I}+2 \mathrm{Na}+\mathrm{C}_3 \mathrm{H}_7 \mathrm{I} \underset{\text { Ether }}{\text { Dry }} \underset{\text { Pentane }}{\mathrm{C}_2 \mathrm{H}_5-\mathrm{C}_3 \mathrm{H}_7+2 \mathrm{Nal}}$
$\mathrm{C}_2 \mathrm{H}_5 \mathrm{I}+2 \mathrm{Na}+\mathrm{C}_2 \mathrm{H}_5 \mathrm{I} \xrightarrow[\text { Ether }]{\text { Dry }} \underset{\text { Butane }}{\mathrm{C}_2 \mathrm{H}_5-} \mathrm{C}_2 \mathrm{H}_5+2 \mathrm{Nal}$
$\mathrm{C}_3 \mathrm{H}_7 \mathrm{I}+2 \mathrm{Na}+\mathrm{C}_3 \mathrm{H}_7 \mathrm{I} \xrightarrow[\text { Ether }]{\text { Dry }} \underset{\text { Hexane }}{\mathrm{C}_3 \mathrm{H}_7-\mathrm{C}_3 \mathrm{H}_7+2 \mathrm{Nal}}$

Topic: Chemistry, Hydrocarbons, JEE Main
When ethylene glycol is heated with concentrated $\mathrm{H}_2 \mathrm{SO}_4$, what is the major product?

Options:
A Ethylene oxide
B Acetaldehyde
C Ethylene
D Dioxane

The correct answer is:
Dioxane

Solution:
Dioxane
Explanation: When ethylene glycol is heated with concentrated sulfuric acid, dehydration occurs, and the major product is 1,4-dioxane, a cyclic ether.

Topic: Chemistry, Alcohols Phenols and Ethers, JEE Main
When Fe0.93O is heated in presence of oxygen, it converts to Fe2O3. The number of correct statement/s from the following is ______ .

A. The equivalent weight of Fe0.93O is Molecular weight0.79

B. The number of moles of Fe2+ and Fe3+ in 1 mole of Fe0.93O is 0.79 and 0.14 respectively.

C. Fe0.93O is metal deficient with lattice comprising of cubic closed packed arrangement of O2- ions.

D. The % composition of Fe2+ and Fe3+ in Fe0.93O is 85% and 15% respectively.

Options:

The correct answer is:
4

Solution:
A:Fe0.93O→Fe2O3

The valence factor of Fe0.93O, nf=3-20093×0.93

nf=0.79

Hence, the equivalent weight =Molecular weight0.79

B:2x+0.93-x×3=2

x=0.79

Fe2+=0.79,Fe3+=0.14

C: In Fe0.93O, O2- ions forms the lattice and iron ions occupies the voids in the lattice. As sufficient number of irons are not available, this metal oxide is said to be metal difficient.

D: %Fe2+=0.790.93×100=85%;Fe3+=15%

Topic: Chemistry, Solutions, JEE Main, JEE Main 2023 (24 Jan Shift 1)
When fluids are heated from the bottom, convection currents are produced because

Options:
A Molecular motion of fluid becomes aligned
B Molecular collisions take place within the fluid
C Heated fluid becomes more dense than the cold fluid above it
D Heated fluid becomes less dense than the cold fluid above it

The correct answer is:
Heated fluid becomes less dense than the cold fluid above it

Solution:
Correct option is D. Heated fluid becomes less dense than the cold fluid above it Convection is heat transfer by the movement of currents within a fluid. During convection, heated particles of fluid begin to flow. This flow transfers heat from one part of the fluid to another. Heat transfer by convection is caused by differences of temperature and density within a fluid.

Topic: Physics, Thermal Properties of Matter, JEE Main
When fluoride is heated with conc. $\mathrm{H}_2 \mathrm{SO}_4$ and $\mathrm{MnO}_2$ the gas evolved is

Options:
A $F_2$
B $\mathrm{SF}$
C $\mathrm{HF}$
D None

The correct answer is:
$\mathrm{HF}$

Solution:
$\mathrm{H}_2 \mathrm{SO}_4$ & $\mathrm{MnO}_2$ the gas evolved is $\mathrm{HF}$

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), JEE Main
When fluorine reacts with water, the compound produced is

Options:
A HF and O2
B HF and O3
C HF and OF2
D HF,O2 and O3

The correct answer is:
HF,O2 and O3

Solution:
Fluorine oxidise water into oxygen and ozone
2F 2  +  2H 2 O → 4HF +  O 2  (major)
3F 2  +  3H 2 O → 6HF +  O 3  (minor)

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), JEE Main
When food energy passes from herbivores to carnivores,

Options:
A Some energy is increased
B Some energy is decreased
C Remain unchanged
D Not relevant

The correct answer is:
Some energy is decreased

Solution:
The energy content is maximum in producers. The energy decreases at each trophic level of the food chain, as part of the energy is lost as heat and the major part of the energy is liberated during respiration for use in various activities. Only 10 % of the energy of the previous trophic level is received by the next trophic level, as proposed by 10 percent law of Lindeman (1942).

Topic: Biology, Ecosystem, NEET
When forces $F_1, F_2, F_3$ are acting on a particle of mass $m$ such that $F_2$ and $F_3$ are mutually perpendicular, then the particle remains stationary. If the force $F_1$ is now removed then the acceleration of the particle is

Options:
A
$\mathrm{F}_1 / \mathrm{m}$

B
$\mathrm{F}_2 \mathrm{~F}_3 / \mathrm{mF}_1$

C
$\left(F_2-F_3\right) / m$

D
$\mathrm{F}_2 / \mathrm{m}$

The correct answer is:
$\mathrm{F}_1 / \mathrm{m}$

Solution:
Resultant of F2 and F3 is of magnitude F1.

Topic: Physics, Laws of Motion, JEE Main, JEE Main 2002
When forces F1,F2,F3 are acting on a particle of mass m such that F2 and F3 are mutually perpendicular then the particle remains stationary. If the force F1 is now removed then the acceleration of the particle is

Options:
A F1m

B F2F3mF1

C F2-F3m

D F2m

The correct answer is:
F1m

Solution:
According to equilibrium total force acting on a particle remains zero
F1→+F2→+F3→=0
F2→+F3→=-F1→
∴a=F1m

Topic: Physics, Laws of Motion, JEE Main
When gas is given heat ΔQ, a part of heat energy is utilized into work done W by gas and the remaining part is utilized to change in internal energy. An ideal diatomic gas is heated at constant pressure, the ratio of the internal energy change to heat energy supplied, is

Options:
A 37
B 25
C 57
D 35

The correct answer is:
57

Solution:
Fraction of supplied energy which increases the internal energy is given by
f=ΔUΔQp=μCVΔTμCPΔT=1γ
[here, according to definition of sp. Heat at constant pressure ΔQp=c=nCPΔT ]
For diatomic gas γ=75
⇒ f=57

Topic: Physics, Thermodynamics, JEE Main
When glucose reacts with bromine water, the main product is

Options:
A acetic acid
B saccharic acid
C glyceraldehyde
D gluconic acid

The correct answer is:
gluconic acid

Solution:
When glucose react with bromine water, then it undergoes oxidation reaction to form glucoinc acid as a product. The reaction is as follows:
\(\mathrm{CH}_2 \mathrm{OH}(\mathrm{CHOH})_4 \mathrm{CHO}+[\mathrm{O}] \xrightarrow[\mathrm{CH}_2 \mathrm{OH}(\mathrm{CHOH})_4 \mathrm{COOH}]{\mathrm{Br}_2 / \mathrm{H}_2 \mathrm{O}}\)
Hence, the correct option is (d).

Topic: Chemistry, Biomolecules, JEE Main
When glucose reacts with bromine water, the main product is

Options:
A acetic acid
B saccharic acid
C glyceraldehyde
D gluconic acid

The correct answer is:
gluconic acid

Solution:
When glucose react with bromine water, then it undergoes oxidation reaction to form glucoinc acid as a product. The reaction is as follows:
\(\mathrm{CH}_2 \mathrm{OH}(\mathrm{CHOH})_4 \mathrm{CHO}+[\mathrm{O}] \xrightarrow[\mathrm{CH}_2 \mathrm{OH}(\mathrm{CHOH})_4 \mathrm{COOH}]{\mathrm{Br}_2 / \mathrm{H}_2 \mathrm{O}}\)
Hence, the correct option is (d).

Topic: Chemistry, Biomolecules, AP EAMCET, AP EAMCET 2020 (21 Sep Shift 2)
When glycerol is treated with excess of HI, it produces

Options:
A 2-iodopropane
B allyl iodide
C propene
D glycerol triiodide

The correct answer is:
2-iodopropane

Solution:

Topic: Chemistry, Alcohols Phenols and Ethers, NEET, NEET 2010 (Mains)
When glycerol is treated with excess of HI, it produces

Options:
A 2-iodopropane
B allyl iodide
C propene
D glycerol triodide

The correct answer is:
2-iodopropane

Solution:

Topic: Chemistry, Haloalkanes and Haloarenes, JEE Main
When glycol is heated with dicarboxylic acid, the products are

Options:
A Polyesters
B Polyethers
C Polyethylene
D No reaction at all

The correct answer is:
Polyesters

Solution:

Topic: Chemistry, Alcohols Phenols and Ethers, JEE Main
When graphite is subjected to an electric arc in the presence of inert atmosphere, it gives

Options:
A $\mathrm{C}_{70}$ as main product and $\mathrm{C}_{80}$ in small quantities
B $\mathrm{C}_{60}$ as main product and $\mathrm{C}_{70}$ in small quantities
C $\mathrm{C}_{50}$ as main product and $\mathrm{C}_{60}$ in small quantities
D equal amounts of $\mathrm{C}_{60}$ and $\mathrm{C}_{70}$

The correct answer is:
$\mathrm{C}_{60}$ as main product and $\mathrm{C}_{70}$ in small quantities

Solution:
Fullerenes are molecules with 60 carbon atom of which most common is $\mathrm{C}_{60}$ while others with $\mathrm{C}_{70}, \mathrm{C}_{76}, \mathrm{C}_{80}$ atoms.
Fullerenes can be made in a carbon arc, where two graphite rods are placed with a small gap between them in an inert gas below atmospheric pressure.
The carbon of the rods evaporate and convert to give fullerene, where $\mathrm{C}_{60}$ is main product and $\mathrm{C}_{70}$ is obtained in small amount.

Topic: Chemistry, p Block Elements (Group 13 & 14), AP EAMCET, AP EAMCET 2021 (23 Aug Shift 2)
When gypsum is heated to 393K, it forms:

Options:
A Anhydrous CaSO4
B CaSO4·5H2O
C CaSO4·0.5H2O
D Dead burnt plaster

The correct answer is:
CaSO4·0.5H2O

Solution:
CaS O 4 .2 H 2 O → 393 K CaS O 4 . 1 2 H 2 O

Topic: Chemistry, s Block Elements, JEE Main, JEE Main 2020 (08 Jan Shift 1)