datavorous/entrance-exam-dataset huggingface dataset:
Match List I with List II

List-I (defect)	List-II (Examples)

(A)	Frenkel defects	(1)	FeO

(B)	Schottkey defects	(2)	NaCl

(C)	Vacancy defects	(3)	AgCl

(D)	Metal deficiency defects	(4)	Crystals with vacant lattice sites.

Options:
A ABCD4321
B ABCD3241
C ABCD1234
D ABCD2341

The correct answer is:
ABCD3241

Solution:
Schottky Defect: It is basically a vacancy defect in ionic solids. In order to maintain electrical neutrality, the number of missing cations and anions are equa

Schottky defect is shown by ionic substances in which the cation and anion are of almost similar sizes. For example, NaCl, KCl, CsCl

Frenkel Defect: This defect is shown by ionic solids. The smaller ion (usually cation) is dislocated from its normal site to an interstitial site. It creates a vacancy defect at its original site and an interstitial defect at its new location.Frenkel defect is shown by ionic substance in which there is a large difference in the size of ions, for example, ZnS, AgCl.

When some of the lattice sites are vacant, the crystal is said to have vacancy defect This results in decrease in density of the substance. This defect can also develop when a substance is heated.

Metal Deficiency Defect There are many solids which are difficult to prepare in the stoichiometric composition and contain less amount of the metal as compared to the stoichiometric proportion. A typical example of this type is FeO which is mostly found with a composition of Fe0.95O

Topic: Chemistry, Solid State, AP EAMCET, AP EAMCET 2022 (04 Jul Shift 2)
Match List I with List II :

List-I
Elements

List-II Properties

(a)	Li	(i)	Poor water solubility of I-salt

(b)	Na	(ii)	Most abundant element in cell fluid

(c)	K	(iii)	Bicarbonate salt used in fire extinguisher

(d)	Cs	(iv)	Carbonate salt decomposes easily on heating

Choose the correct answer from the options given
below:

Options:
A (a)-(iv), (b)-(iii), (c)-(ii), (d)-(i)
B (a)-(i), (b)-(iii), (c)-(ii), (d)-(iv)
C (a)-(iv), (b)-(ii), (c)-(iii), (d)-(i)
D (a)-(i), (b)-(ii), (c)-(iii), (d)-(iv)

The correct answer is:
(a)-(iv), (b)-(iii), (c)-(ii), (d)-(i)

Solution:
(d) CsI salt is poor water soluble due to its low hydration energy.
(b) NaHCO3 is used in fire extinguisher.
(c) K is most abundant element in cell fluid.
(a) Li2CO3 decomposes easily due to high covalent character caused by small size Li+ cation.

Hence, option 1 is the best response.

Topic: Chemistry, s Block Elements, JEE Main, JEE Main 2021 (25 Jul Shift 2)
Match List I with List II.

List-I
Enzyme	List-II
Conversion of

A.	Invertase	I.	Starch into maltose

B.	Zymase	II.	Maltose into glucose

C.	Diastase	III.	Glucose into ethanol

D.	Maltase	IV.	Cane sugar into glucose

Choose the most appropriate answer from the options given below

Options:
A A-III,B-IV,C-II,D-I
B A-III,B-II,C-I,D-IV
C A-IV,B-III,C-I,D-II
D A-IV,B-II,C-III,D-I

The correct answer is:
A-IV,B-III,C-I,D-II

Solution:
Invertase helps in the conversion of sucrose to glucose and fructose.

Zymase catalyses the conversion of glucose or fructose to ethyl alcohol.

Diastase is a starch hydrolysing enzyme that breaks down the complex carbohydrate (polysaccharides, i.e. starch) into simple carbohydrates (monosaccharides, i.e. simple sugar like glucose).

Maltase catalyses the conversion of maltose to glucose.

Topic: Chemistry, Chemistry in Everyday Life, JEE Main, JEE Main 2022 (26 Jun Shift 2)
Match List - I with List - II.

List-I	List-II

A	Concentration of gold ore	I	Aniline

B	Leaching of alumina	II	NaOH

C	Froth stabiliser	III	SO2

D	Blister copper	IV	NaCN

Choose the correct answer from the options given below.

Options:
A A-IV,B-III,C-II,D-I
B A-IV,B-II,C-I,D-III
C A-III,B-II,C-I,D-IV
D A-II,B-IV,C-III,D-I

The correct answer is:
A-IV,B-II,C-I,D-III

Solution:
i) Copper was smelted in an open furnace. The slightly impure copper had impurities, mostly sulphur dioxide which bubbled up through the copper as it solidified. That gave a blistered surface and the results of the smelting were called blister copper. Copper is purified by electrolytic refining of blister copper.

ii) The principle of froth floatation is that sulphide ores are preferentially wetted by pine oil, whereas the gangue particles are wetted by water. Collectors are added to enhance the non-wettability of the mineral particles. Examples of collectors are pine oil, fatty acids and xanthates.

iii) In the metallurgy of gold, the respective gold ore is leached with a dilute solution of NaCN or KCN in the presence of air (for O2) from which the gold is obtained later by replacement:

4Aus+8CN-aq+2H2Oaq+O2g→4AuCN2-aq+4OH-aq

2AuCN2-aq+Zns→ZnCN42-aq+2Aus

Topic: Chemistry, General Principles and Processes of Isolation of Metals, JEE Main, JEE Main 2022 (27 Jun Shift 1)
Match List - I with List - II.

List-I	List-II

A	I	Dishwashing powder

B	II	Toothpaste

C	C17H35COO-Na++Na2CO3+ Rosinate	III	Laundry soap

D	CH3CH216COOCH2CH2OnCH2CH2OH	IV	Hair conditioner

Choose the correct answer from the options given below

Options:
A A-IV,B-II,C-III,D-I
B A-III,B-II,C-IV,D-I
C A-IV,B-III,C-II,D-I
D A-II,B-IV,C-I,D-II

The correct answer is:
A-IV,B-II,C-III,D-I

Solution:
1. Laundry soaps contain fillers like sodium rosinate, sodium silicate, borax and sodium carbonate.

2. Cationic detergents are quaternary ammonium salts of amines with acetates, chlorides or bromides as anions. Cationic part possess a long hydrocarbon chain and a positive charge on nitrogen atom. Hence, these are called cationic detergents. Cetyltrimethylammonium bromide is a popular cationic detergent and is used in hair conditioners.

3. Non-ionic Detergents: Non-ionic detergents do not contain any ion in their constitution. One such detergent is formed when stearic acid reacts with polyethyleneglycol. Liquid dishwashing detergents are non-ionic type.

4. In anionic detergents, the anionic part of the molecule is involved in the cleansing action. Sodium salts of alkylbenzenesulphonates are an important class of anionic detergents. They are mostly used for household work.

Topic: Chemistry, Chemistry in Everyday Life, JEE Main, JEE Main 2022 (27 Jun Shift 1)
Match List - I with List II :

List-I	List-II

a	Li	i	photoelectric cell

b	Na	ii	absorbent of CO2

c	K	iii	coolant in fast breeder nuclear reactor

d	Cs	iv	treatment of cancer

v	bearings for motor engines

Choose the correct answer from the options given below:

Options:
A (a) -(v),(b)-(i),(c)-(ii),(d)-(iv)
B (a) -(v),(b)-(ii),(c)-(iv),(d)-(i)
C (a) - (iv), (b) - (iii), (c) - (i), (d) - (ii)
D (a) - (v), (b) - (iii), (c) - (ii), (d) - (i)

The correct answer is:
(a) - (v), (b) - (iii), (c) - (ii), (d) - (i)

Solution:
Li makes alloy with Lead to make white metal, bearings for motor engines. Liquid Na metal is used as coolant in fast breeder nuclear reactor. K is a very absorbent of CO2. Cs is used in making photoelectric cell.

Topic: Chemistry, s Block Elements, JEE Main, JEE Main 2021 (27 Jul Shift 2)
Match List - I with List - II.

List-I	List-II

(a)	Source of microwave frequency	(i)	Radioactive decay of nucleus

(b)	Source of infrared frequency	(ii)	Magnetron

(c)	Source of Gamma Rays	(iii)	Inner shell electrons

(d)	Source of X-rays	(iv)	Vibration of atoms and molecules

(v)	LASER

(vi)	RC circuit

Choose the correct answer from the options given below:

Options:
A (a)-(ii), (b)-(iv), (c)-(vi), (d)-(iii)
B (a)-(vi), (b)-(iv), (c)-(i), (d)-(v)
C (a)-(vi), (b)-(v), (c)-(i), (d)-(iv)
D (a)-(ii), (b)-(iv), (c)-(i), (d)-(iii)

The correct answer is:
(a)-(ii), (b)-(iv), (c)-(i), (d)-(iii)

Solution:
(a) Source of microwave frequency is magnetron.
(b) Source of infrared frequency is vibration of atoms and molecules.
(c) Source of Gamma rays is radioactive decay of nucleus
(d) Source of X-rays inner shell electron transition.

Topic: Physics, Electromagnetic Waves, JEE Main, JEE Main 2021 (24 Feb Shift 2)
Match List - I with List - II :

List-I	List-II

(A)	Sphalerite	(I)	FeCO3

(B)	Calamine	(II)	PbS

(C)	Galena	(III)	ZnCO3

(D)	Siderite	(IV)	ZnS

Choose the most appropriate answer from the options given below :

Options:
A A-IV,B-I,C-II,D-III
B A-IV,B-III,C-II,D-I
C A-II,B-II,C-I,D-IV
D A-III,B-IV,C-II,D-I

The correct answer is:
A-IV,B-III,C-II,D-I

Solution:
Calamine is the carbonate ore of zinc.It composition is ZnCO3.

Galena is also called lead glance is the natural mineral form of lead (ii) sulfide,PbS

Sphalerite is a sulfide mineral with the formula ZnS. It is the most important ore of zinc.

Siderite is a mineral composed of iron(II) carbonate (FeCO3).

Topic: Chemistry, General Principles and Processes of Isolation of Metals, JEE Main, JEE Main 2022 (24 Jun Shift 1)
Match List I with List II

List-I	List-II

A	Spring constant	I	[T–1]

B	Angular speed	II	[MT–2]

C	Angular momentum	III	[ML2]

D	Moment of Inertia	IV	[ML2T–1]

Choose the correct answer from the options given below:

Options:
A A-I, B-III, C-II, D-IV
B A-IV, B-I, C-III, D-II
C A-II, B-I, C-IV, D-III
D A-II, B-III, C-I, D-IV

The correct answer is:
A-II, B-I, C-IV, D-III

Solution:
The formula to calculate the spring constant is

F=kx ...1

The formula to calculate the angular speed is

ω=2πT ...2

The formula to calculate the angular momentum is

L=mvr ...(3)

The formula to calculate the moment of inertia is

I=MR2 ...4

Use the method of dimensional analysis to obtain the dimensions of the required quantities. From above relations, we can write

MLT-2=kL⇒k=MT-2ω=1T=T-1L=MLT-1L=ML2T-1I=ML2=ML2

Topic: Physics, Units and Dimensions, JEE Main, JEE Main 2023 (12 Apr Shift 1)
Match List I with List II.

List-I	List-II

A	Sulphate	I	Pesticide

B	Fluoride	II	Bending of bones

C	Nicotine	III	Laxative effect

D	Sodium arsinite	IV	Herbicide

Choose the correct answer from the options given below

Options:
A A-II,B-III,C-IV,D-I
B A-III,B-II,C-I,D-IV
C A-IV,B-III,C-II,D-I
D A-III,B-II,C-IV,D-I

The correct answer is:
A-III,B-II,C-I,D-IV

Solution:
A-Sulphate - III (Laxative effect)

Sulfates are a large part of the haze pollution that irritates the lungs and affects your lung health.

B-Fluoride - II (Bending of bones)

Fluoride is a neurotoxin which, in high doses, can be harmful. Excessive exposure can lead to tooth discoloration and bone problems.

C-Nictoine - I (pesticides)

Nicotine has been used as a natural insecticide and is the archetype for the large range of synthetic neonicotinoid insecticides.

D-Sodium Arsinite - IV (herbicide)

Inorganic arsenicals (arsenic trioxide, sodium arsenite and lead arsenate) have been used as rodenticides and herbicides.

Topic: Chemistry, Environmental Chemistry, JEE Main, JEE Main 2022 (25 Jul Shift 2)
Match List - I with List - II

List-I	List-II

(a)	Ultravoilet rays	(i)	Study crystal structure

(b)	Microwaves	(ii)	Greenhouse effect

(c)	Infrared waves	(iii)	Sterilizing surgical instrument

(d)	X-rays	(iv)	Radar system

Options:
A a-iii, biv, c-ii, d-i
B a-iii, bi, c-ii, d-iv
C a-iv, biii, c-ii, d-i
D a-iii, biv, c-i, d-ii

The correct answer is:
a-iii, biv, c-ii, d-i

Solution:
UV → For sterilization surgical instruments

Microwaves →Communication (Radar system)

Infrared → Green house effect

X-rays → Study crystal structure

Topic: Physics, Electromagnetic Waves, JEE Main, JEE Main 2022 (27 Jun Shift 1)
Match List - I with List - II.

List-I	List-II

(a)	Valium	(i)	Antifertility drug

(b)	Morphine	(ii)	Pernicious anaemia

(c)	Norethindrone	(iii)	Analgesic

(d)	Vitamin B12	(iv)	Tranquilizer

Options:
A (a)-(iv), (b)-(iii), (c)-(ii), (d)-(i)
B (a)-(ii), (b)-(iv), (c)-(iii), (d)-(i)
C (a)-(i), (b)-(iii), (c)-(iv), (d)-(ii)
D (a)-(iv), (b)-(iii), (c)-(i), (d)-(ii)

The correct answer is:
(a)-(iv), (b)-(iii), (c)-(i), (d)-(ii)

Solution:
(a) Valium - Tranquilizer (a)-(iv)
(b) Morphine - Analgesic (b)-(iii)
(c) Norethindrone - Antifertility Drug (c)-(i)
(d) Vitamin B12- Pernicious anaemia (d)-(ii)

Topic: Chemistry, Chemistry in Everyday Life, JEE Main, JEE Main 2021 (24 Feb Shift 2)
Match List I with List II :
List-I List-II

Example of colloids Classification
(a) Cheese (i) dispersion of liquid in liquid
(b) Pumice stone (ii) dispersion of liquid in gas
(c) Hair cream (iii) dispersion of gas in solid
(d) Cloud (iv) dispersion of liquid in solid

Choose the most appropriate answer from the options given below

Options:
A (a)-(iv), (b)-(iii), (c)-(ii), (d)-(i)
B (a)-(iv), (b)-(i), (c)-(iii), (d)-(ii)
C (a)-(iii), (b)-(iv), (c)-(i), (d)-(ii)
D (a)-(iv), (b)-(iii), (c)-(i), (d)-(ii)

The correct answer is:
(a)-(iv), (b)-(iii), (c)-(i), (d)-(ii)

Solution:
Cheese → liquid in solid
Pumice stone → gas in solid Hair cream → liquid in liquid
Cloud → liquid in gas

Topic: Chemistry, Surface Chemistry, JEE Main, JEE Main 2021 (25 Jul Shift 2)
Match List - I with List - II.

List-I (Metal)	List-II (Ores)

(a)	Aluminium	(i)	Siderite

(b)	Iron	(ii)	Calamine

(c)	Copper	(iii)	Kaolinite

(d)	Zinc	(iv)	Malachite

Choose the correct answer from the options given below:

Options:
A (a)-(ii), (b)-(iv), (c)-(i), (d)-(iii)
B (a)-(iv), (b)-(iii), (c)-(ii), (d)-(i)
C (a)-(i), (b)-(ii), (c)-(iii), (d)-(iv)
D (a)-(iii), (b)-(i), (c)-(iv), (d)-(ii)

The correct answer is:
(a)-(iii), (b)-(i), (c)-(iv), (d)-(ii)

Solution:
Siderite-FeCO3

Siderite is a mineral composed of iron (II) carbonate (FeCO3). It is a widespread mineral that is an ore of iron.

Calamine-ZnCO3

Zinc ore is most commonly found as zinc carbonate (ZnCO3Ã¢â¬â¹), known as calamine or smithsonite.

Kaolinite-Al2(OH)4·Si2O5

Malachite-Cu(OH)2·CuCO3

Topic: Chemistry, General Principles and Processes of Isolation of Metals, JEE Main, JEE Main 2021 (24 Feb Shift 2)
Match List I with List II :

List-I (Physical Quantity)	List-II (Dimensional Formula)

A	Pressure gradient	I	M0L2T-2

B	Energy density	II	M1L-1T-2

C	Electric Field	III	M1L-2T-2

D	Latent heat	IV	M1L1T-3A-1

Choose the correct answer from the options given below:

Options:
A A-III, B-II, C-I, D-IV
B A-II, B-III, C-IV, D-I
C A-III, B-II, C-IV, D-I
D A-II, B-III, C-I, D-IV

The correct answer is:
A-III, B-II, C-IV, D-I

Solution:
(A) Pressure gradient is stated as dPdx=FAl=MLT-2L2L=M1L-2T-2 (III)

(B) Energy density is stated as u=EnergyVolume=ML2T-2L3=M1L-1T-2 (II)

(C) Electric field is stated as E=ForceCharge=MLT-2AT=M1L1T-3A-1 (IV)

(D) Latent heat is stated as L=HeatMass=Energy Mass=ML2T-2M=M0L2T-2 (I)

Topic: Physics, Units and Dimensions, JEE Main, JEE Main 2023 (29 Jan Shift 1)
Match List I with List II

List-I
Pollutant	List-II
Disease /sickness

A	Sulphate >500ppm	I	Methemoglobinemia

B	Nitrate >50ppm	II

Brown mottling of teeth

C	Lead >50ppb	III	Laxative effect

D	Fluoride >2ppm	IV	Kidney damage

Choose the correct answer from the options given below

Options:
A A-IV,B-I,C-II,D-III
B A-III,B-I, C-IV,D-II
C A-II,B-IV,C-I,D-III
D A-II,B-IV,C-III,D-I

The correct answer is:
A-III,B-I, C-IV,D-II

Solution:
F- ion concentration above 2 ppm causes brown mottling of teeth. At the same time, excess fluoride (over 10 ppm) causes harmful effect to bones and teeth

Lead: Drinking water gets contaminated with lead when lead pipes are used for transportation of water. The prescribed upper limit concentration of lead in drinking water is about 50 ppb. Lead can damage kidney, liver, reproductive system etc.

Sulphate: Excessive sulphate >500 ppm in drinking water causes laxative effect, otherwise at moderate levels it is harmless.

Nitrate: The maximum limit of nitrate in drinking water is 50 ppm. Excess nitrate in drinking water can cause disease such as methaemoglobinaemia ('blue baby' syndrome).

Topic: Chemistry, Environmental Chemistry, JEE Main, JEE Main 2022 (27 Jul Shift 1)
Match List I with List II

List-I

Pollutant

List-II

Source

A	Microorganisms	I	Strip mining

B	Plant nutrients	II	Domestic sewage

C	Toxic heavy metals	III	Chemical fertilizer

D	Sediment	IV	Chemical factory

Choose the correct answer from the options given below

Options:
A A-II,B-III,C-IV,D-I
B A-II,B-I,C-IV,D-III
C A-I,B-IV,C-II,D-III
D A-I,B-IV,C-III,D-II

The correct answer is:
A-II,B-III,C-IV,D-I

Solution:
Pollution of water originates from human activities. Through different paths, pollution reaches surface or ground water.

water soluble inorganic chemicals that include heavy metals such as cadmium, mercury, nickel etc constitute an important class of pollutants. All these metals are dangerous to humans because our body cannot excrete them. Over the time, it crosses the tolerance limit. These metals then can damage kidneys, central nervous system, liver etc

Clean water would have BOD value of less than 5 ppm whereas highly polluted water could have a value of 17 ppm or more

List-I
Pollutant	List-II
Source

A	Microorganisms	II	Domestic sewage

B	Plant nutrients	III	Chemical fertilizer

C	Toxic heavy metals	IV	Industries and chemical factories

D	Sediment	I	Erosion of soil by agriculture and strip mining

Topic: Chemistry, Environmental Chemistry, JEE Main, JEE Main 2022 (26 Jul Shift 2)
Match List I with List II

List-I (Polymer)	List-II (Nature)

A

I	Thermosetting polymer

B

II	Fibers

C

III	Elastomer

D

IV	Thermoplastic polymer

Choose the correct answer from the options given below

Options:
A A-II,B-III,C-IV,D-I
B A-III,B-II,C-IV,D-I
C A-III,B-I,C-IV,D-II
D A-I,B-III,C-IV,D-II

The correct answer is:
A-III,B-II,C-IV,D-I

Solution:
The Thermosetting Polymers tend to have a cross-linked 3D structure.

Bakelite or Novolac are examples of Thermosetting Polymer.

Polymer fibers are a subset of man-made fibers, which are based on synthetic chemicals (often from petrochemical sources) rather than arising from natural materials by a purely physical process. These fibers are made from: polyamide nylon.

Thermoplastics are a class of polymers that can be softened and melted by the application of heat, and can be processed either in the heat-softened state (e.g. by thermoforming) or in the liquid state (e.g. by extrusion and injection molding). polyvinyl chloride is an example of it.

Elastomer, any rubbery material composed of long chainlike molecules, or polymers, that are capable of recovering their original shape after being stretched to great extents - hence the name elastomer, from "elastic polymer."

Neoprene is elastomer

Nylon-6,6 is fiber

PVC is thermoplastic

Novolac is thermosetting

Topic: Chemistry, Polymers, JEE Main, JEE Main 2022 (28 Jul Shift 2)
Match List - I with List - II.

List-I
(Polymer)	List-II
(Used in)

A	Bakelite	I	Radio and television cabinets

B	Glyptal	II	Electrical switches

C	PVC	III	Paints and Lacquers

D	Polystyrene	IV	Water pipes

Choose the correct answer from the options given below

Options:
A A-II,B-III,C-I,D-IV
B A-II,B-III,C-IV,D-I
C A-I,B-II,C-III,D-IV
D A-IV,B-III,C-II,D-I

The correct answer is:
A-II,B-III,C-IV,D-I

Solution:
Polyvinyl chloride (PVC) : Manufacture of rain coats, hand bags, vinyl flooring, water pipes.

Polystyrene : As insulator, wrapping material, manufacture of toys, radio and television cabinets.

Glyptal : Manufacture of paints and lacquers.

Bakelite : For making combs, electrical switches, handles of utensils and computer discs.

Topic: Chemistry, Polymers, JEE Main, JEE Main 2022 (27 Jun Shift 1)
Match List - I with List - II.

List-I (Reactants)	List-II Products

(A)	Phenol, Zn/∆	(I)	Salicylaldehyde

(B)	Phenol, CHCl3,NaOH,HCl	(II)	Salicylic acid

(C)	Phenol, CO2,NaOH,HCl	(III)	Benzene

(D)	Phenol, Conc. HNO3	(IV)	Picric acid

Choose the correct answer from the options given below.

Options:
A (A)-(IV), (B)-(II), (C)-(I), (D)-(III)
B (A)-(IV), (B)-(I), (C)-(II), (D)-(III)
C (A)-(III), (B)-(I), (C)-(II), (D)-(IV)
D (A)-(III), (B)-(IV), (C)-(I), (D)-(II)

The correct answer is:
(A)-(III), (B)-(I), (C)-(II), (D)-(IV)

Solution:
(A) When phenol is distilled with Zn-dust, it gives benzene. it is an example of reduction. Phenol loses one O atom.

(B) When phenol is treated with CHCl3 and NaOH followed by acidification, salicyaldehyde is formed. The reaction is known as Reimer Tiemann reaction.

(C) Reaction of phenol with sodium hydroxide and carbon dioxide is Kolbe's Schmidt reaction that is a electrophilic substitution reaction resulting in the formation of salicylic acid as shown in the reaction.

The major product obtained on interaction of phenol with sodium hydroxide and carbon dioxide is salicylic acid.

(D) With concentrated nitric acid, phenol is converted to 2, 4, 6-Trinitrophenol. The product is commonly known as picric acid.

Topic: Chemistry, Alcohols Phenols and Ethers, JEE Main, JEE Main 2024 (01 Feb Shift 2)
Match List - I with List - II.

List-I (Salt)	List-II (Flame colour wavelength)

(a)	(i)	Br2/NaOH

(b)	(ii)	H2/Pd-BaSO4

(c)	(iii)	ZnHg/Conc.HCl

(d)	(iv)	Cl2/Red P, H2O

Choose the correct answer from the options given below:

Options:
A (a)-(ii), (b)-(iv), (c)-(i), (d)-(iii)
B (a)-(iii), (b)-(i), (c)-(iv), (d)-(ii)
C (a)-(ii), (b)-(i), (c)-(iv), (d)-(iii)
D (a)-(iii), (b)-(iv), (c)-(i), (d)-(ii)

The correct answer is:
(a)-(ii), (b)-(iv), (c)-(i), (d)-(iii)

Solution:
Rosenmund Reduction: The Rosenmund reduction is a reaction where acid chlorides are converted into aldehydes by employing hydrogen gas over palladium poisoned by barium sulfate.

Hoffmann Bromamide reaction

Clemmenson reduction

Topic: Chemistry, Amines, JEE Main, JEE Main 2021 (24 Feb Shift 2)
Match List - I with List - II.

List-I
(Si-Compounds)	List-II
(Si-Polymeric/Other Products)

A	CH34Si	I	Chain Silicone

B	CH3SiOH3	II	Dimeric Silicone

C	CH32SiOH2	III	Silane

D	CH33SiOH	IV	2 D- Silicone

Choose the correct answer from the options given below

Options:
A A-III,B-II,C-I,D-IV
B A-IV,B-I,C-II,D-III
C A-II,B-I,C-IV,D-III
D A-III,B-IV,C-I,D-II

The correct answer is:
A-III,B-IV,C-I,D-II

Solution:
CH34Si is a silane CH3SiOH3polymerise to form 2D silicone CH32SiOH2 polymerise to form chain silicone CH33SiOH form dimer CH33Si-O-SiCH33

Topic: Chemistry, p Block Elements (Group 13 & 14), JEE Main, JEE Main 2022 (27 Jun Shift 1)
Match List I with List II

List-I

Species

List-2

Maximum allowed concentration in ppm in drinking water

A	F-	I	< 50 ppm

B	SO42-	II	< 5 ppm

C	NO3-	III	<2 ppm

D	Zn	IV	<500 ppm

Choose the correct answer from the options given below.

Options:
A A-I, B-II, C-III, D-IV
B A-II, B-I, C-III, D-IV
C A-IV, B-III, C-II, D-I
D A-III, B-II, C-I, D-IV

The correct answer is:
A-III, B-II, C-I, D-IV

Solution:
Species	Maximum allowed concentration in ppm in drinking water

A.	F-	2

B.	SO42-	500

C.	NO3-	50

D.	Zn	5

F– ion concentration above 2 ppm causes brown mottling of teeth. At the same time, excess fluoride (over 10 ppm) causes harmful effect to bones and teeth.

Excessive sulphate (>500 ppm) in drinking water causes laxative effect, otherwise at moderate levels it is harmless.

The maximum limit of nitrate in drinking water is 50 ppm. Excess nitrate in drinking water can cause disease such as methemoglobinemia (‘blue baby’ syndrome).

Topic: Chemistry, Environmental Chemistry, JEE Main, JEE Main 2023 (08 Apr Shift 1)
Match List - I with List - II:

List-I (Species)	List-II (Number of lone pairs of electrons on the central atom)

(a)	XeF2	(i)	0

(b)	XeO2F2	(ii)	1

(c)	XeO3F2	(iii)	2

(d)	XeF4	(iv)	3

Choose the most appropriate answer from the options given below:

Options:
A (a)-(iii), (b)-(iv), (c)-(ii), (d)-(i)
B (a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)
C (a)-(iii), (b)-(ii), (c)-(iv), (d)-(i)
D (a)-(iv), (b)-(ii), (c)-(i), (d)-(iii)

The correct answer is:
(a)-(iv), (b)-(ii), (c)-(i), (d)-(iii)

Solution:
No of lone pairs of electrons on the central atom

(a)	XeF2	3

(b)	XeO2F2	1

(c)	XeO3F2	0

(d)	XeF4	2

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), JEE Main, JEE Main 2021 (27 Aug Shift 1)