datavorous/entrance-exam-dataset huggingface dataset:
Which of the following statements about aspirin is not true?

Options:
A It is effective in relieving pain
B It is a neurologically active drug
C It has antiblood clotting action
D It belongs to narcotic analgesics

The correct answer is:
It belongs to narcotic analgesics

Solution:
Aspirin is a non-narcotics analgesic . Rest are correct facts about aspirin.

Topic: Chemistry, Chemistry in Everyday Life, JEE Main
Which of the following statements about benzyl chloride is incorrect?

Options:
A It is a lachrymatory liquid and answers Beilstein's test.
B It gives a white precipitate with alcoholic silver nitrate.
C It is less reactive than alkyl halides.
D It can be oxidised to benzaldehyde by boiling with copper nitrate solution.

The correct answer is:
It is less reactive than alkyl halides.

Solution:
Benzyl chloride is more reactive than alkyl halides as benzyl carbocation is stabilised by resonance. Hence, it easily gives nucleophilic substitution reaction.

Topic: Chemistry, Haloalkanes and Haloarenes, JEE Main
Which of the following statements about colloids is false?

Options:
A When silver nitrate solution is added to potassium iodide solution a negatively charged colloidal solution is formed.
B Freezing point of colloidal solution is lower than true solution at same concentration of a solute.
C Colloidal particles can pass through ordinary filter paper.
D When excess of electrolyte is added to colloidal solution, colloidal particle will be precipitated.

The correct answer is:
Freezing point of colloidal solution is lower than true solution at same concentration of a solute.

Solution:
Freezing point of colloidal solution is same as that of true solution at same concentration of a solute. The depression in freezing point is colloidal property and depends on the number of solute particles. It is independent of size or shape of solute particles.

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Topic: Chemistry, Surface Chemistry, JEE Main, JEE Main 2018 (15 Apr)
Which of the following statements about colloids is false?

Options:
A
When silver nitrate solution is added to potassium iodide solution, a negatively charged colloidal solution is formed

B
Freezing point of colloidal solution is lower than true solution at same concentration of a solute

C
Colloidal particles can pass through ordinary filter paper

D
When excess of electrolyte is added to colloidal solution, colloidal particle will be precipitated

The correct answer is:
Freezing point of colloidal solution is lower than true solution at same concentration of a solute

Solution:
(a) Colloidal particles are so small that they can pass through ordinary filter paper. Also, they cannot be seen with ordinary microscope.
(b) Freezing point of colloidal solution is same as that of true solution at same concentration of a solute. The depression in freezing point is a colloidal property and depends on the number of solute particles and independent of size or shape of solute particles.
(c) When silver nitrate solution is added to potassium iodide solution, a negatively charged colloidal solution is formed due to selective adsorption of $\mathrm{I}^{-}$ion from the dispersion medium. However, if the order of addition is reversed, i.e, potassium iodide solution is added to silver nitrate solution, due to selective adsorption of $\mathrm{Ag}^{+}$ion from the dispersion medium, a positively charged colloidal solution is obtained.
(d) When excess of electrolyte is added to colloidal solution, colloidal particle will be precipitated. Although electrolytes in minute quantities are necessary for the stability of colloids, they cause coagulation of disperse phase if present in large quantities.

Topic: Chemistry, Surface Chemistry, JEE Main, JEE Main 2018 (15 Apr Shift 1 Online)
Which of the following statements about Cycas and Pinus is correct?

Options:
A The stem in Cycas is branched while it is unbranched in Pinus. The male and female strobili are present on the same plant in Pinus while they are present in different plants in Cycas.
B The stem in Cycas is unbranched while it is branched in Pinus. The male and female strobili are present on the same plant in Pinus while they are present in different plants in Cycas.
C The stem in Cycas is branched while it is unbranched in Pinus. The male and female strobili are present on the same plant in Cycas while they are present in different plants in Pinus.
D The stem in Cycas is unbranched while it is branched in Pinus. The male and female strobili are present on the same plant in Cycas while they are present in different plants in Pinus.

The correct answer is:
The stem in Cycas is unbranched while it is branched in Pinus. The male and female strobili are present on the same plant in Pinus while they are present in different plants in Cycas.

Solution:
The main points of difference between Cycas and Pinus:
The stem is Cycas is unbranched, while it is branched in Pinus. Cycas shows coralloid roots with the symbiotic association with cyanobacterium Anabaena, while the roots of Pinus form mycorrhiza, which is a fungal association.
The male and female strobili are present on the same plant in Pinus (monoecious), while they are present in different plants in Cycas (dioecious).

Topic: Biology, Plant Kingdom, NEET
Which of the following statements about dialysis is INCORRECT?

Options:
A Blood drained from a convenient artery is pumped into a dialysing unit after adding an anticoagulant like heparin.
B The dialysing unit contains a coiled cellophane tube surrounded by a dialysing fluid.
C The cleared blood is pumped back to the body through a vein after adding anti-heparin to it.
D The dialysing fluid have the exactly the same composition as that of plasma.

The correct answer is:
The dialysing fluid have the exactly the same composition as that of plasma.

Solution:
Dialysis is used to provide an artificial replacement for lost kidney function in people with renal failure. Dialysis works on the principles of the diffusion of solutes and ultrafiltration of fluid across a semi-permeable membrane. This replicates the filtering process that takes place in the kidneys. The two main types of dialysis are Haemo-dialysis and Peritoneal dialysis. In haemo-dialysis, wastes and water are removed from the blood outside the body through an external filter called dialyzer that contains a semi-permeable membrane. Blood is drained from a convenient artery and an anti-coagulant like heparin is added to prevent clotting of blood. It is then pumped into a dialyzer containing dialyzing fluid and coiled cellophane membrane. The dialyzing fluid has the same composition as that of plasma except nitrogenous wastes. The porous cellophane membrane allows the passage of molecules along the concentration gradient. As the nitrogenous wastes are absent in the dialyzing fluid, these substances freely move out from the blood (along the concentration gradient). The cleared blood is pumped back to the body through a vein after adding anti-heparin to it. In peritoneal dialysis, wastes and water are removed from the blood inside the body using peritoneal membrane of the abdominal cavity as a natural semi-permeable membrane.

Topic: Biology, Excretory Products and their Elimination, NEET
Which of the following statements about galvanic cell is incorrect

Options:
A Anode is positive
B Oxidation occurs at the electrode with lower reduction potential
C Cathode is positive
D Reduction occurs at cathode

The correct answer is:
Anode is positive

Solution:
Anode has negative polarity

Topic: Chemistry, Electrochemistry, JEE Main
Which of the following statements about heavy water are correct?
(a) Heavy water is used as a moderator in nuclear reactors.
(b) Heavy water is more associated than ordinary water.
(c) Heavy water is a more effective solvent than ordinary water.

Options:
A (b) and (c)
B (a) and (b)
C \( (\mathrm{a}),(\mathrm{b}) \) and \( (\mathrm{c}) \)
D (a) and (c)

The correct answer is:
(a) and (b)

Solution:
Heavy water is deuterium oxide (D2O) that contains deuteriumâ, (an isotope) heavier than the hydrogen.
The difference increases the strength of water’s hydrogen-oxygen bonds. Heavy water is also a commonly used moderator (medium that reduces the speed of fast neutrons).
Hence, (a) and (b) statements are correct.

Topic: Chemistry, Hydrogen, JEE Main
Which of the following statements about low density polythene is FALSE?

Options:
A Its synthesis required dioxygen or a peroxide initiator as a catalyst
B It is used in the manufacture of buckets, dust - bins etc.
C Its synthesis requires high pressure
D It is a poor conductor of electricity

The correct answer is:
It is used in the manufacture of buckets, dust - bins etc.

Solution:
Low density polythene: It is obtained by the polymerization of ethene high pressure of 1000-2000 atm. at a temp. of 350 K to 570 K in the pressure of traces of dioxygen or a peroxide initiator (cont).
Low density polythene is chemically inert and poor conductor of electricity. It is used for manufacture squeeze bottles, toys and flexible pipes.

Topic: Chemistry, Polymers, JEE Main, JEE Main 2016 (03 Apr)
Which of the following statements about $\mathrm{Na}_2 \mathrm{O}_2$ is not correct?

Options:
A
It is diamagnetic in nature

B
It is derivative of $\mathrm{H}_2 \mathrm{O}_2$

C
$\mathrm{Na}_2 \mathrm{O}_2$ oxidises $\mathrm{Cr}^{3+}$ to $\mathrm{CrO}_4^{2-}$ in acid medium.

D
It is the super oxide of sodium

The correct answer is:
It is the super oxide of sodium

Solution:
$\mathrm{Na}_2 \mathrm{O}_2$ is peroxide of sodium not super oxide. The formula of sodium superoxide is $\mathrm{NaO}_2$.

Topic: Chemistry, s Block Elements, JEE Main, JEE Main 2014 (11 Apr Online)
Which of the following statements about physical adsorption is not correct?

Options:
A It is usually monolayer
B It is reversible in nature
C It involves van der Waals interactions between adsorbent and adsorbate
D It involves small value of adsorption

The correct answer is:
It is usually monolayer

Solution:
Physical adsorption is a multilayer phenomenon. Rest all are correct features of physical adsorption.

Topic: Chemistry, Surface Chemistry, JEE Main
Which of the following statements about smog is/are correct?
(i) Smog formed on sumny days contain oxidísing molecules.
(ii) Photochemical smog contains many reactive molecules.
(iii) The main polluting components of smog are oxides of carbon.
(iv) The presence of carbon monoxide in air leads to the formation of ozone in smog.

Options:
A (i), (iii)
B (i), (ii)
C (ii), (iv)
D Only (ii)

The correct answer is:
(i), (ii)

Solution:
Formation of photochemical smog over due to nitrogen oxides, hydrocarbons and sunlight.
Photochemical smog is a daytime phenomenon and it contain many reactive molecules.

Topic: Chemistry, Environmental Chemistry, TS EAMCET, TS EAMCET 2018 (07 May Shift 1)
Which of the following statements, about the advantage of roasting of sulphide ore before reduction is not true?

Options:
A the magnitude of ΔGfo of the sulphide is greater than those for CS2 and H2S
B the ΔGfo is negative for roasting of sulphide ore to oxide
C roasting of the sulphide to the oxide is thermodynamically feasible
D carbon and hydrogen are suitable reducing agents for metal sulphides

The correct answer is:
carbon and hydrogen are suitable reducing agents for metal sulphides

Solution:
The standard free energies of formation ΔGfo of most of the sulphides are greater than those of CS2 and H2S . Hence, neither carbon nor hydrogen can reduce metal sulphides to metal. The standard free energies of formation of oxides are much lower than those of SO2 . Therefore, oxidation of metal sulphides to metal oxides is thermodynamically favourable. Hence sulphide ore is roasted to the oxide before reduction.

Topic: Chemistry, General Principles and Processes of Isolation of Metals, JEE Main
Which of the following statements about the depletion of ozone layer is correct?

Options:
A
The problem of ozone depletion is less serious at poles because $\mathrm{NO}_2$ solidifies and is not available for consuming $\mathrm{CIO}^{\circ}$ radicals.

B
The problem of ozone depletion is more serious at poles because ice crystals in the clouds over poles act as catalyst for photochemical reactions involving the decomposition of ozone of $\mathrm{Cl}^{\bullet}$ and $\mathrm{CIO}^{\bullet}$ radicals.

C
Freons, chlorofluorocarbons, are inert. Chemically, they do not react with ozone in stratosphere.

D
Oxides of nitrogen also do not react with ozone in stratosphere.

The correct answer is:
Freons, chlorofluorocarbons, are inert. Chemically, they do not react with ozone in stratosphere.

Solution:
Freons and chlorofluorocarbon find their way to stratosphere through without being destroyed in the troposphere due to their low reactivity. In the stratosphere the $\mathrm{Cl}$ and $\mathrm{Br}$ atoms are liberated from the parent compounds by the action of ultraviolet light e.g.
$$
\begin{aligned}
&\mathrm{CF}_2 \mathrm{Cl}_2+h v \longrightarrow \mathrm{CF}_2 \mathrm{Cl}+\mathrm{Cl} \\
&\mathrm{CFCl}_3+h v \longrightarrow \mathrm{CFCl}_2+\mathrm{Cl}
\end{aligned}
$$
The $\mathrm{Cl}$ atoms can destroy ozone molecules through a variety of catalytic cycles.

Topic: Chemistry, Environmental Chemistry, JEE Main, JEE Main 2014 (11 Apr Online)
Which of the following statements about the disproportionation reaction of MnO4-in acidic medium is correct?

Options:
A MnO4-undergoes disproportionation in acidic medium due to the reduction of Mn(VII) to Mn(II).
B MnO4-does not undergo disproportionation in acidic medium because it remains stable.
C MnO4-undergoes disproportionation in acidic medium due to the oxidation of Mn(VII) to Mn(II).
D MnO4-does not undergo disproportionation in acidic medium because it is already in its highest oxidation state.

The correct answer is:
MnO4-does not undergo disproportionation in acidic medium because it is already in its highest oxidation state.

Solution:
Correct Option is : (D)
MnO4-does not undergo disproportionation in acidic medium because it is already in its highest oxidation state.

Topic: Chemistry, Redox Reactions, NEET
Which of the following statements about the excretory system is CORRECT?

Options:
A The vessel entering the glomerular capillaries is an arteriole while the vessel coming out of the glomerular capillaries is a venule.
B Minimum reabsorption in the nephron takes place in the distal convoluted tubule.
C The counter-current and proximity between the Henle’s loop and vasa recta maintain an increasing osmolarity towards the inner medullary interstitium.
D As the filtrate passes through the ascending limb of Henle's loop it becomes hypertonic.

The correct answer is:
The counter-current and proximity between the Henle’s loop and vasa recta maintain an increasing osmolarity towards the inner medullary interstitium.

Solution:
Mammals have the ability to produce a concentrated urine. The Henleâs loop and vasa recta play a significant role in this. The flow of filtrate in the two limbs of Henleâs loop is in opposite directions and thus forms a counter current. The flow of blood through the two limbs of vasa recta is also in a counter current pattern. The proximity between the Henleâs loop and vasa recta, as well as the counter current in them help in maintaining an increasing osmolarity towards the inner medullary interstitium, i.e., from 300 mOsmolLâ1 in the cortex to about 1200 mOsmolLâ1 in the inner medulla. This gradient is mainly caused by NaCl and urea. NaCl is transported by the ascending limb of Henleâs loop which is exchanged with the descending limb of vasa recta. NaCl is returned to the interstitium by the ascending portion of vasa recta. Similarly, small amounts of urea enter the thin segment of the ascending limb of Henleâs loop which is transported back to the interstitium by the collecting tubule. The above described transport of substances facilitated by the special arrangement of Henleâs loop and vasa recta is called the counter current mechanism.

Topic: Biology, Excretory Products and their Elimination, NEET
Which of the following statements about the given reaction are correct?
\(3 \mathrm{Fe}(\mathrm{s})+4 \mathrm{H}_2 \mathrm{O}(\mathrm{g}) \rightarrow \mathrm{Fe}_3 \mathrm{O}_4(\mathrm{~s})+4 \mathrm{H}_2 \text { (g) }\)
(i) Iron metal is getting oxidised
(ii) Water is getting reduced
(iii) Water is acting as reducing agent
(iv) Water is acting as oxidising agent

Options:
A (i), (ii) and (iii)
B (iii) and (iv)
C (i), (ii) and (iv)
D More than one of the above

The correct answer is:
More than one of the above

Solution:
Reactants:
- In the given reaction, Fe oxidation state in the reactant side is zero as it is in its elemental state.
- In water, hydrogen oxidation state is +1.
Products:
- In th product side, the oxidation state of Fe becomes \(+8 / 3\). That means it increases.
- The oxidation state of hydrogen is zero. As it is in its elemental state.
Thus, the oxidation state of Fe increases so it is getting oxidised.
- Thus, statement (i) is correct.
In water hydrogen oxidation state becomes +1 to zero. So, it can be named as reduction.
- Thus, statement (ii) is correct.
As water is getting reduced, it acts as an oxidizing agent.
- So, the statement (iv) is correct.

Topic: Chemistry, Redox Reactions, JEE Main
Which of the following statements about the gravitational constant is true?

Options:
A It is a force.
B It has same value in all systems of units.
C It depends on the value of the masses.
D It does not depend on the nature of the medium in which the bodies are kept.

The correct answer is:
It does not depend on the nature of the medium in which the bodies are kept.

Solution:
The expression of gravitational constant from Newton's law of gravitation is,

F=GMmR2⇒G=FR2Mm

Value of the universal gas constant is,

G=6.67×10-11 N m2 kg-2 or

G=6.67×10-8 dyne cm2 g-2.

That is, the value of G is not same for all system of units.

G is named as an Universal Gravitational Constant as it is constant at any location of the universe and as well as at any medium in the universe.

Hence, it does not depend on the nature of the medium in which the bodies are kept.

Topic: Physics, Gravitation, JEE Main
Which of the following statements about water is FALSE?

Options:
A There is extensive intramolecular hydrogen bonding in the condensed phase.
B Ice formed by heavy water sinks in normal water.
C Water is oxidized to oxygen during photosynthesis
D Water can act both as an acid and as a base

The correct answer is:
There is extensive intramolecular hydrogen bonding in the condensed phase.

Solution:
(i) Ice formed by heavy water sinks in normal water due to higher density of D2O than normal water.
(ii) 6 CO 2 + 6 H 2 O → chlorophyll hv C 6 H 12 O 6 +6O 2
(iii) Water can show amphiprotic nature and hence water can act both as an acid a base.
(iv) There is extensive intermolecular hydrogen bonding in the condensed phase instead of intramolecular H - bonding.

Topic: Chemistry, Hydrogen, JEE Main, JEE Main 2016 (03 Apr)
Which of the following statements accurately describes the thermal stability of oxosalts for alkali and alkaline earth metals?

Options:
A Carbonates and sulphates of Li decompose on heating, while the stability of carbonates and sulphates of other metals increases down the group.
B All alkali and alkaline earth metal oxosalts exhibit increasing thermal stability down the group.
C Carbonates of all alkali and alkaline earth metals decompose on heating, while sulphates increase in stability down the group.
D The thermal stability of carbonates and sulphates of alkali and alkaline earth metals remains constant across the periodic table.

The correct answer is:
Carbonates and sulphates of Li decompose on heating, while the stability of carbonates and sulphates of other metals increases down the group.

Solution:
Correct Option is : (A)
Carbonates and sulphates of Li decompose on heating, while the stability of carbonates and sulphates of other metals increases down the group.

Topic: Chemistry, s Block Elements, NEET
Which of the following statements are correct?
1. A σ bond is stronger than a Ï bond
2. A covalent bond is stronger than a hydrrogen bond
3. HF is more polar than HCl
4. There is one electrovalent bond and three covalent bonds in methylene chloride
Select the correct answer using the codes given below

Options:
A 2, 3 and 4
B 1 and 3
C 1, 2 and 4
D 1, 2 and 3

The correct answer is:
1, 2 and 3

Solution:
Here statement 1, 2 and 3 are correct while 4 is incorrect as in methylene chloride CH2Cl2 , all four bonds are covalent.
A σ and covalent bond are stronger than a π bond due to stronger overlapping.
HF is more polar than HCl due to more electronegativity difference.

Topic: Chemistry, Chemical Bonding and Molecular Structure, JEE Main
Which of the following statements are correct?

1. The hormone responsible for maintaining the diurnal rhythm of the body is secreted by a gland situated on the dorsal side of the forebrain.
2. Exophthalmic goitre is characterized by protrusion of eyeballs, weight loss, enlargement of the thyroid gland and decreased basal metabolic rate.
3. Addison's disease occurs due to decreased production of hormones from the outer part of the adrenal gland.
4. Hypersecretion of parathormone causes an increase in the deposition of calcium in bones.

Options:
A 1, 2 and 3
B 2, 3 and 4
C 1 and 3
D 2 and 4

The correct answer is:
1 and 3

Solution:
The hormone responsible for maintaining the diurnal rhythm of the body is melatonin. It is secreted by the pineal gland, which is situated on the dorsal side of the forebrain.
Exopthalmic goitre is characterized by protrusion of eyeballs, weight loss, enlargement of thyroid gland and an increased basal metabolic rate. This increased basal metabolic rate is the cause for excessive weight loss.
Addison's disease is a condition occurring due to decreased secretion of hormones from the adrenal cortex i.e. the outer part of adrenal gland. It is characterized by a lot of weakness and fatigue.
Hypersecretion of parathormone causes decrease in the deposition of calcium in bones.

Topic: Biology, Chemical Coordination and Integration, NEET
Which of the following statements are correct ?

(A) Both LiCl and MgCl2 are soluble in ethanol.

(B) The oxides Li2O and MgO combine with excess of oxygen to give superoxide.

(C) LiF is less soluble in water than other alkali metal fluorides.

(D) Li2O is more soluble in water than other alkali metal oxides.

Choose the most appropriate answer from the options given below

Options:
A A and C only
B A,C and D only
C B and C only
D A and D only

The correct answer is:
A and C only

Solution:
(A) Both LiCl & MgCl2 have covalent character so soluble in ethanol.

(C) LiF have low solubility due to high lattice energy.

So these two statements are correct. And other two statements are wrong.

Since,

(B) Li and Mg do not form superoxide

(D) Li2O is least soluble in water than other alkali metal oxides

Topic: Chemistry, s Block Elements, JEE Main, JEE Main 2022 (24 Jun Shift 1)
Which of the following statements are correct?
A. Glycerol is purified by vacuum distillation because it decomposes at its normal boiling point.
B. Aniline can be purified by steam distillation as aniline is miscible in water.
C. Ethanol can be separated from ethanol water mixture by azeotropic distillation because it forms azeotrope.
D. An organic compound is pure, if mixed M.P. is remained same.
Choose the most appropriate answer from the options given below :

Options:
A A, B, C only
B A, C, D only
C A, B, D only
D B, C, D only

The correct answer is:
A, C, D only

Solution:
Option (B) is incorrect because aniline is immisible in water.

Topic: Chemistry, General Organic Chemistry, JEE Main, JEE Main 2024 (06 Apr Shift 1)