datavorous/entrance-exam-dataset huggingface dataset:
\( \wedge_{\mathrm{m}}^{0}\left(\mathrm{NH}_{4} \mathrm{OH}\right) \) is equal to

Options:
A \( \wedge_{\mathrm{m}\left(\mathrm{NH}_{4} \mathrm{OH}\right)}^{0}+\wedge_{\mathrm{m}\left(\mathrm{NH}_{4} \mathrm{Cl}\right)}^{0}-\wedge_{(\mathrm{HCl})}^{0} \)
B \( \wedge_{\mathrm{m}}^{0}\left(\mathrm{NH}_{4} \mathrm{Cl}\right)+\wedge_{\mathrm{m}}^{0}(\mathrm{NaOH})-\wedge_{(\mathrm{NaCl})}^{0} \)
C \( \wedge_{\mathrm{m}}^{0}\left(\mathrm{NH}_{4} \mathrm{Cl}\right)+\wedge_{\mathrm{m}}^{0}(\mathrm{NaCl})-\wedge_{(\mathrm{NaOH})}^{0} \)
D \( \wedge_{\mathrm{m}(\mathrm{NaOH})}^{0}+\wedge_{\mathrm{m}(\mathrm{NaCl})}^{0}-\wedge_{\left(\mathrm{NH}_{4} \mathrm{Cl}\right)}^{0} \)

The correct answer is:
\( \wedge_{\mathrm{m}}^{0}\left(\mathrm{NH}_{4} \mathrm{Cl}\right)+\wedge_{\mathrm{m}}^{0}(\mathrm{NaOH})-\wedge_{(\mathrm{NaCl})}^{0} \)

Solution:
According to Kohlrausch's law, the molar conductivity of Ammonium hydroxide, at infinite dilution can be expressed as follows:

∧m0NH4OH =∧m0NH4++∧m0Cl-+∧m0Na++∧m0OH--∧m0Na+-∧m0Cl-

∧0mNH4OH =∧0mNH4++∧0mOH-

Hence, the molar conductivity of ammonium hydroxide is the sum of molar conductivity of NH4+ and OH- ions.

Topic: Chemistry, Electrochemistry, JEE Main
Weight of $112 \mathrm{~ml}$ of oxygen at NTP on liquefaction would be

Options:
A $0.32 \mathrm{~g}$
B $0.64 \mathrm{~g}$
C $0.16 \mathrm{~g}$
D $0.96 \mathrm{~g}$

The correct answer is:
$0.16 \mathrm{~g}$

Solution:
$22400 \mathrm{~ml}$ is the volume of $\mathrm{O}_2$ at N.T.P $=32 \mathrm{gm}$ of $\mathrm{O}_2$
$1 \mathrm{~ml}$ is the volume of $O_2$ at NTP $=\frac{32}{22400}$
$112 \mathrm{~ml}$ is the volume of $\mathrm{O}_2$ at NTP $=\frac{32}{22400} \times 112$
$=0.16 \mathrm{gm}$ of $\mathrm{O}_2$

Topic: Chemistry, States of Matter, JEE Main
Weight of a body of mass m decreases by 1% when it is raised to height h above the earth's surface. If the body is taken on depth h in a mine, change in its weight is

Options:
A 0.5%, decrease
B 2%, increase
C 0.5%, increase
D 2%, decrease

The correct answer is:
0.5%, decrease

Solution:
At an altitude h the acceleration due to gravity is
gâ²=g1-2hRe
or mgâ²=mg1-2hRe
ie, wâ²=w1-2hRe
99100w=w1-2hRe
ie, h=0.005Re
At a point below the surface of the earth at depth h. The weight of the body given by
wâ²=w1-hRe
wâ²w=0.995
%âw=1-0.995wwÃ100
%âw=0.5%, decrease

Topic: Physics, Gravitation, JEE Main
What are A,âB and C in the following

Options:
A in all case
B in all case
C
D

The correct answer is:

Solution:

Topic: Chemistry, Alcohols Phenols and Ethers, JEE Main
What are $\mathrm{A}, \mathrm{B}, \mathrm{C}$ in the following reactions?
(i) $\left(\mathrm{CH}_{3} \mathrm{CO}_{2}\right)_{2} \mathrm{Ca} \stackrel{\Delta}{\longrightarrow} \mathrm{A}$
(ii) $\mathrm{CH}_{3} \mathrm{CO}_{2} \mathrm{H} \frac{\mathrm{HI}}{\operatorname{Red} \mathrm{P}} \mathrm{B}$
(iii) $2 \mathrm{CH}_{3} \mathrm{CO}_{2} \mathrm{H} \stackrel{\mathrm{P}_{4} \mathrm{O}_{10}}{\longrightarrow} \mathrm{C}$

Options:
A $A - \mathrm{C}_{2} \mathrm{H}_{6} \quad B- \mathrm{CH}_{3} \mathrm{COCH}_{3}$ C - $\left(\mathrm{CH}_{3} \mathrm{CO}\right)_{2} \mathrm{O}$
B $A -\left(\mathrm{CH}_{3} \mathrm{CO}\right)_{2} \mathrm{O}\quad B - \mathrm{C}_{2} \mathrm{H}_{6}$ C - $\mathrm{CH}_{3} \mathrm{COCH}_{3}$
C $A - \mathrm{CH}_{3} \mathrm{COCH}_{3} \quad B- \mathrm{C}_{2} \mathrm{H}_{6}$ C - $\left(\mathrm{CH}_{3} \mathrm{CO}\right)_{2} \mathrm{O}$
D $A - \mathrm{CH}_{3} \mathrm{COCH}_{3}\quad B- \left(\mathrm{CH}_{3} \mathrm{CO}\right)_{2} \mathrm{O}$ C - $\mathrm{C}_{2} \mathrm{H}_{6}$

The correct answer is:
$A - \mathrm{CH}_{3} \mathrm{COCH}_{3} \quad B- \mathrm{C}_{2} \mathrm{H}_{6}$ C - $\left(\mathrm{CH}_{3} \mathrm{CO}\right)_{2} \mathrm{O}$

Solution:

Topic: Chemistry, Alcohols Phenols and Ethers, JEE Main
What are antibiotics called if they are effective mainly against either Gram-positive or Gram-negative bacteria?

Options:
A Broad spectrum antibiotics
B Narrow spectrum antibiotics
C Limited spectrum antibiotics
D Synthetic spectrum antibiotics

The correct answer is:
Narrow spectrum antibiotics

Solution:
Antibiotics effective mainly against either Gram-positive or Gram-negative bacteria are referred to as narrow spectrum antibiotics.

Topic: Chemistry, Chemistry in Everyday Life, NEET
What are azeotropes, and what are the two main types of azeotropes based on their boiling behavior? How do solutions with a large positive deviation from Raoult's law relate to the formation of azeotropes?

Options:
A Azeotropes are solutions that obey Raoult's law over the entire concentration range. There are no different types of azeotropes.
B Azeotropes are solutions that exhibit a large positive deviation from Raoult's law. They form minimum boiling azeotropes, which boil at a constant temperature.
C Azeotropes are solutions that have a constant composition in both the liquid and vapor phases and boil at a specific temperature. They can be classified into minimum boiling and maximum boiling azeotropes. Solutions with a large positive deviation from Raoult's law form minimum boiling azeotropes.
D Azeotropes are solutions that exhibit a large negative deviation from Raoult's law. They form maximum boiling azeotropes, which boil at a constant temperature.

The correct answer is:
Azeotropes are solutions that have a constant composition in both the liquid and vapor phases and boil at a specific temperature. They can be classified into minimum boiling and maximum boiling azeotropes. Solutions with a large positive deviation from Raoult's law form minimum boiling azeotropes.

Solution:
Azeotropes are solutions with a constant composition in both the liquid and vapor phases and boil at a specific temperature. They can be categorized into two main types: minimum boiling azeotropes and maximum boiling azeotropes. Solutions that exhibit a large positive deviation from Raoult's law tend to form minimum boiling azeotropes.

Topic: Chemistry, Solutions, NEET
What are benign tumors?

Options:
A Masses of cells that cause little damage
B Masses of cells that grow rapidly
C Masses of cells that invade and damage surrounding normal tissues
D Masses of cells that compete for vital nutrients

The correct answer is:
Masses of cells that cause little damage

Solution:
Benign tumors remain confined to their original location and do not spread to other parts of the body. They cause little damage and are not as dangerous as malignant tumors.

Topic: Biology, Human Health and Diseases, NEET
What are biofertilisers? Give two examples

Options:

None

Solution:
Biofertilisers are organisms that increase nutrient quality of the soil bacteria, fungi and cyanobacteria are the main source of biofertilisers. e.g.,
(i) Azospirillum, Rhizobium and Azotobacter are able to fix atmospheric nitrogen in the soil.
(ii) Blue-green algae like Anabaena, Nostoc, Ocsillatoria add organic matter to the soil and increase its fertility.

Topic: Biology, Microbes in Human Welfare
What are chasmogamous flowers? Can cross-pollination occur in cleistogamous flowers? Give reasons for your answer

Options:

None

Solution:
Chasmogamous flowers or open flowers in which anther and stigma are exposed for pollination.
Cross-pollination cannot occur in cleistogamous flowers. These flowers remain closed thus causing only selfpollination. In cleistogamous flowers, anthers dehisce inside the closed flowers. So the pollen grains come in contact with stigma. Thus there is no chance of crosspollination, e.g., Oxalis, Viola.

Topic: Biology, Sexual Reproduction in Flowering Plants
What are fossils?

Options:
A Remains of hard parts of plants found in rocks
B Remains of hard parts of animals found in rocks
C Remains of soft parts of animals found in rocks
D Remains of soft parts of plants found in rocks

The correct answer is:
Remains of hard parts of animals found in rocks

Solution:
Fossils are defined as remains of hard parts of life:forms found in rocks.

Topic: Biology, Evolution, NEET
What are gymnosperms?

Options:
A Plants in which the ovules are enclosed by an ovary wall
B Plants in which the ovules remain exposed before and after fertilization
C Plants in which the seeds are covered
D Plants in which the seeds are not covered

The correct answer is:
Plants in which the ovules remain exposed before and after fertilization

Solution:
Gymnosperms are plants in which the ovules are not enclosed by any ovary wall and remain exposed, both before and after fertilization. The seeds that develop post-fertilization are not covered, i.e., are naked.

Topic: Biology, Plant Kingdom, NEET
What are malpighian tubules responsible for in insects?

Options:
A Nitrogenous waste removal
B Maintaining fluid and ionic balance
C Ionic and fluid volume regulation
D Both nitrogenous waste removal and osmoregulation

The correct answer is:
Both nitrogenous waste removal and osmoregulation

Solution:
Malpighian tubules are responsible for removing nitrogenous wastes and maintaining osmoregulation in insects.

Topic: Biology, Excretory Products and their Elimination, NEET
What are nucleic acids? Mention their two important functions.

Options:
A Nucleic acids are carbohydrates that provide energy to cells. Their two important functions are regulating metabolic processes and supporting structural roles in cell membranes.
B Nucleic acids are lipids responsible for storing genetic information. Their two important functions are maintaining bone health and regulating blood sugar levels.
C Nucleic acids are long chains of nucleotides that store and transmit genetic information in cells. Their two important functions are protein synthesis [via mRNA] and carrying out enzymatic reactions [via rRNA].
D Nucleic acids are proteins that function as catalysts in biological reactions. Their two important functions are providing energy to cells and supporting immune system functions.

The correct answer is:
Nucleic acids are long chains of nucleotides that store and transmit genetic information in cells. Their two important functions are protein synthesis [via mRNA] and carrying out enzymatic reactions [via rRNA].

Solution:
Correct Option is : (C)
Nucleic acids are long chains of nucleotides that store and transmit genetic information in cells. Their two important functions are protein synthesis [via mRNA] and carrying out enzymatic reactions [via rRNA].

Topic: Chemistry, Biomolecules, NEET
What are nucleic acids? Mention their two important functions.

Options:

None

Solution:
Nucleic acids are biomolecules which are found in the nuclei of all living cell in form of nucleoproteins or chromosomes (proteins contains nucleic acids as the prosthetic group).
Nucleic acids are of two types: deoxyribonucleic acid (DNA) and ribonucleic acid (RNA). The two main functions of nucleic acids are:
(a) DNA is responsible for transmission of hereditary effects from one generation to another. This is due to its unique property of replication, during cell division and two identical DNA strands are transferred to the daughter cells.
(b) DNA and RNA are responsible for synthesis of all proteins needed for the growth and maintenance of our body. Actually the proteins are synthesized by various RNA molecules (r-RNA, m-RNA) and t-RNA) in the cell but the message for the synthesis of a particular protein is coded in DNA.

Topic: Chemistry, Biomolecules
What are plasmids? Describe their role in bacteria.

Options:

None

Solution:
A plasmid is usually a circular (sometimes linear), double stranted DNA that can autonomously replicate. These are found in the cytoplam of the bacterial cell. Plasmids normally remain separated from the chromosome, but sometimes may temporarily integrate into it and replicate with it incidentally.
Role and Plasmids in Bacteria
Plasmids are the extra chromosomal circular, independently replicating unit besides nucleoid in the bacterial cell. Plasmids are used to transfer information from one cell to another, i.e., transfer of important genes, enabling to metabolise a nutrient, which normally a bacteria is unable to. It also helps in conjugation of bacteria. These days plasmids are used in a variety of recombination experiments, as cloning vectors.

Topic: Biology, Cell - The Unit of Life
What are product of the reaction shown ?

Options:
A (CH3)2 CHCl and m-bromophenol
B (CH3)2 CHCl and m-bromo chlorobenzene
C (CH3)2 CHOH and m-bromophenol
D (CH3)2 CHOH and m-bromo chlorobenzene

The correct answer is:
(CH3)2 CHCl and m-bromophenol

Solution:

Topic: Chemistry, Alcohols Phenols and Ethers, JEE Main
What are protonephridia primarily concerned with?

Options:
A Nitrogenous waste removal
B Maintaining fluid and ionic balance
C Ionic and fluid volume regulation
D Improving osmoregulation

The correct answer is:
Ionic and fluid volume regulation

Solution:
Protonephridia are primarily concerned with ionic and fluid volume regulation, also known as osmoregulation.

Topic: Biology, Excretory Products and their Elimination, NEET
What are side reactions?

Options:
A Reactions that occur on the side of a reaction vessel.
B Reactions that produce unexpected products alongside the main reaction.
C Reactions that are unrelated to the main reaction.
D Reactions that involve secondary reactants.

The correct answer is:
Reactions that produce unexpected products alongside the main reaction.

Solution:
Side reactions are reactions that produce unexpected products alongside the main reaction.

Topic: Chemistry, Chemical Kinetics, NEET
What are some of the functions of the cytoskeleton in a cell?

Options:
A Mechanical support
B Motility
C Maintenance of cell shape
D All of the above

The correct answer is:
All of the above

Solution:
The cytoskeleton is involved in various functions such as mechanical support, motility, and maintenance of cell shape.

Topic: Biology, Cell - The Unit of Life, NEET
What are structures of $X, Y$ and $Z$ in the above given reaction sequence?

Options:
A

B

C

D

The correct answer is:

Solution:

Topic: Chemistry, Hydrocarbons, JEE Main
What are taxonomical aids? Give the importance of herbaria and museums. How are Botanical gardens and Zoological parks useful in conserving biodiversity?

Options:

None

Solution:
The aids which help in identification, classification and naming of a newly discovered organisms (plant or animal) the taxonomic aids.
It could be in the form of a preserved document like herbaria or specimen kept at museums or scientific institutions. Other aids include written document like monography, taxonomic keys, couplets, etc.
A new organism found can be studied while comparing it with living plants and animals living in protected areas like Botanical gardens, Zoological parks, etc.
Botanical gardens helps in conservation of plants by
(i) Plant species growing important local and keeping record of them.
(ii) Growing and maintaining species that rare are and endangered.
(iii) Supplying seeds for different aspects of botanical research.
Zoological parks contribute in conserving biodiversity by
(i) Providing natural environment and open space to animals.
(ii) Providing home to different native and exotic wild animals.
(iii) Rescue of endangered species.
(iv) Facilitating breeding animal and releasing them free.
Thus, both botanical gardens and zoological parks play an important role in conservation of biodiversity.

Topic: Biology, The Living World
What are the advantages of the null-point method in a Wheatstone bridge? What additional measurements would be required to calculate $\mathrm{R}_{\text {unknown }}$ by any other methmd?

Options:

None

Solution:
As we know that the necessary and sufficient condition for balanced Wheatstone bridge is
$$
\frac{\mathrm{P}}{\mathrm{Q}}=\frac{\mathrm{R}}{\mathrm{S}}
$$
where $\mathrm{P}$ and $\mathrm{Q}$ are ratio arms and $\mathrm{R}$ is known resistance and $\mathrm{S}$ is unknown resistance.
The main advantage of null point method in a Wheatstone bridge is that the resistance of galvanometer does not affect the balance point, there is no need to determine current in resistances and the internal resistance of a galvanometer.
We can calculate the $\mathrm{R}_{\text {unknown }}$ by ohm's law in which we need to calculate the least counts and readings of ammeter and voltmeter.
The $\mathrm{R}_{\text {unknown }}$ can be calculated applying Kirchhoff's rules to the circuit. We would need additional accurate measurement of all the currents in resistances and galvanometer and internal resistance of the galvanometer.

Topic: Physics, Current Electricity
What are the commonly used names for the two main reactants in organic reactions?

Options:
A Nucleophiles and electrophiles
B Substrates and products
C Reagents and intermediates
D Isomers and catalysts

The correct answer is:
Substrates and products

Solution:
The paragraph mentions that it is convenient to name one reagent as substrate and the other as reagent in organic reactions.

Topic: Chemistry, General Organic Chemistry, NEET
What are the constituent amines formed when the mixture of a and b undergoes Hofmann bromamide degradation?

Options:
A
B
C
D

The correct answer is:

Solution:

Topic: Chemistry, Carboxylic Acid Derivatives, JEE Main
What are the coordination number (C.N.) of Ca2+ and F- ion in calcium fluoride CaF2 crystal structure?

Options:
A C.N. of Ca2+=4 and F-=8
B C.N. of Ca2+=6 and F-=6
C C.N. of Ca2+=8 and F-=8
D C.N. of Ca2+=8 and F-=4

The correct answer is:
C.N. of Ca2+=8 and F-=4

Solution:
Each Ca2+ ion is surrounded by 8 F- ions and each F- ion by 4 Ca2+ ions. Thus, coordination number of Ca2+ is 8 and F- is 4.

Topic: Chemistry, Solid State, JEE Main
What are the criteria of the five Kingdom classification?

Options:
A Cell structure, body organization, mode of nutrition and reproduction, and phylogenetic relationships.
B Simple morphological characters
C Distribution
D Metabolic diversity

The correct answer is:
Cell structure, body organization, mode of nutrition and reproduction, and phylogenetic relationships.

Solution:
The main criteria of the five Kingdom classification were cell structure, body organization, mode of nutrition and reproduction, and phylogenetic relationships.

Topic: Biology, Biological Classification, NEET
What are the effects of malignant tumors on normal tissues?

Options:
A They cause little damage
B They remain confined to their original location
C They invade and damage surrounding normal tissues
D They compete for vital nutrients

The correct answer is:
They invade and damage surrounding normal tissues

Solution:
Malignant tumors are a mass of proliferating cells that grow rapidly, invading and damaging the surrounding normal tissues. They also compete for vital nutrients, leading to damage and starvation of normal cells.

Topic: Biology, Human Health and Diseases, NEET
What are the excretory functions performed by the antennal glands in crustaceans?

Options:
A Nitrogenous waste removal
B Maintaining fluid and ionic balance
C Ionic and fluid volume regulation
D Both nitrogenous waste removal and osmoregulation

The correct answer is:
Nitrogenous waste removal

Solution:
Antennal glands, also known as green glands, perform the excretory function of removing nitrogenous waste in crustaceans.

Topic: Biology, Excretory Products and their Elimination, NEET
What are the final concentrations of all the ions when following are mixed? 50 mL of 0.12 M FeNO33, 100 mL of 0.10M FeCl3 and 100 mL of 0.26 M MgNO32 .

Options:
A Fe3+=0.064M;Â NO3-=0.28Â M ; Â Fe3+=0.12Â M;Mg2+=0.04Â M
B Fe3+=0.064M; NO3-=0.28 M ; Fe3+=0.12 M;Mg2+=0.104 M
C Fe3+=0.04M;Â NO3-=0.28Â M ; Â Fe3+=0.12Â M;Mg2+=0.104Â M
D Fe3+=0.064M;Â NO3-=0.8Â M ; Â Fe3+=0.12Â M;Mg2+=0.104Â M

The correct answer is:
Fe3+=0.064M; NO3-=0.28 M ; Fe3+=0.12 M;Mg2+=0.104 M

Solution:
Milli-mole of FeNO33 = 50 Ã 0.12 = 6 (mm=MÃVmL)
â´ Milli-mole of Fe3+ = 6 ;
Milli-mole of NO3-=3 Ã6= 18
Milli-mole of FeCl3= 100 Ã 0.1 = 10
Milli-mole of Fe3+= 10 ;
Milli-mole of Cl- =3 Ã 10 = 30
Milli-mole of MgNO32 = 100 Ã 0.26 = 26
Milli-mole of Mg2+ = 26 ;
Milli-mole of NO3-= 2 Ã 26 = 52
On mixing these three, total volume he comes 250 mL
Thus Fe3+=6+10250=0.064M
NO3-=18+52250=0.28 M
Cl-=30250=0.12 M
Mg2+=26250=0.104 M

Topic: Chemistry, Some Basic Concepts of Chemistry, JEE Main
What are the following and where do you find them in animal body.
(a) Chondrocytes
(b) Axons
(c) Ciliated epithelium

Options:

None

Solution:
(a) Chondrocytes:
These are the cells found in cartilage connective tissue. The number of chondrocytes found in cartilage determine how bendy the cartilage is chondrocytes produce and maintain the cartilage matrix. It is present in the tip of the nose, pinna of ear, joints between vertebral column, etc.
(b) Axon:
It is the longest processes of a neuron, that conducts the impulse away from the cell body. They are present in all nerve fibres.
(c) Ciliated epithelium :
When cuboidal or columnar epithelial cells bear cilia, they are called as ciliated epithelium.
Ciliated epithelium is found in the living of respirator tract, bronchioles and fallopian tube. It contains goblet cells, which secretes mucus.

Topic: Biology, Structural Organisation in Animals
What are the formal charges on the carbon and oxygen atoms and the formal charge difference, \( \Delta \mathrm{FC} \), in the Lewis (electron dot) structure of carbon dioxide shown in the figure? \[\ddot{0}=c=\ddot{0}\]

Options:
A \( +4,-2 \) and \( +6 \)
B \( +4,+4 \) and \( 0 \)
C \( +4,+2 \) and \( +2 \)
D \( 0,0 \) and \( 0 \)

The correct answer is:
\( 0,0 \) and \( 0 \)

Solution:
The calculation of formal charge (FC) can be considered as a process involving electronic book-keeping, it is a hypothetical charge worked out as follows:

FC=(number of valence electrons)-12(number of bonding electrons)-(number of non-bonding electrons)

∴FC (C)=(4)-12(8)-0=0
FC (O)=(6)-12(4)-4=0

Hence, ∆FC=0-0=0.

Topic: Chemistry, Chemical Bonding and Molecular Structure, JEE Main
What are the four main colligative properties discussed in the paragraph?

Options:
A Boiling point, freezing point, solute nature, vapor pressure
B Boiling point, freezing point, density, viscosity
C Lowering of vapor pressure, depression of freezing point, elevation of boiling point, osmotic pressure
D Solubility, molarity, molality, density

The correct answer is:
Lowering of vapor pressure, depression of freezing point, elevation of boiling point, osmotic pressure

Solution:
The paragraph mentions that the four colligative properties are the lowering of vapor pressure, depression of freezing point, elevation of boiling point, and osmotic pressure.

Topic: Chemistry, Solutions, NEET
What are the four major parts of the stomach?

Options:
A Cardiac, fundic, body, pyloric
B Cardiac, fundic, body, duodenum
C Cardiac, fundic, jejunum, ileum
D Cardiac, fundic, pyloric, ileum

The correct answer is:
Cardiac, fundic, body, pyloric

Solution:
The stomach has four major parts – a cardiac portion into which the oesophagus opens, a fundic region, body (main central region) and a pyloric portion which opens into the first part of small intestine.

Topic: Biology, Digestion and Absorption, NEET
What are the functional groups present in the structure of maltose?

Options:
A One ketal and one hemiketal
B Two acetals
C One acetal and one hemiacetal
D One acetal and one ketal

The correct answer is:
One acetal and one hemiacetal

Solution:
Cyclic hemiacetal are formed when an alcohol oxygen atom adds to the carbonyl carbon of an aldehyde or a ketone. Molecules (aldehyde or ketone), which contain both an alcohol and a carbonyl group, can instead undergo an intramolecular reaction to form a cyclic hemiacetal/ hemiketal.

Topic: Chemistry, Biomolecules, JEE Main, JEE Main 2020 (04 Sep Shift 1)
What are the functions of liver?

Options:

None

Solution:
Functions of Liver :
1. The liver performs several roles in carbohydrate, lipid and protein metabolism.
2. The liver is responsible for the mainstay of protein metabolism, synthesis as well as degradation.
3. The liver produces and excretes bile (a greenish liquid) required for emulsifying fats.
4. The breakdown of insulin and other hormones
5. The liver breaks down haemoglobin, creating metabolites that are added to bile as pigment (bilirubin and biliverdin).
6. The liver converts ammonia to urea.

Topic: Biology, Digestion and Absorption