datavorous/entrance-exam-dataset huggingface dataset:
The given plots represent the variation of the concentration of a reactant R with time for two different reactions (i) and (ii). The respective orders of the reaction are
(i)

(ii)

Options:
A 1,1
B 0,1
C 1,0
D 0,2

The correct answer is:
1,0

Solution:
First-order R⟶P differential rate law
dRdt= -KR ;

lnR=ln⁡R0-Kt
Zero-order time.
R⟶P

Differential rate law, d[R]/dt =-K

[R]=R∘-Kt

Topic: Chemistry, Chemical Kinetics, JEE Main, JEE Main 2019 (09 Apr Shift 1)
The given plots represent the variation of the concentration of a reaction R with time for two different reaction (i) and (ii). The respective orders of the reactions are

Options:
A 1, 0
B 0, 2
C 0, 1
D 1, 1

The correct answer is:
0, 1

Solution:
Intergrated rate law for zero order reactions is Ct=Co-kt or Ct=-kt+Co or R=-kt+Co ( Ct=R given)
On comparing with y=mx+C
slope m=-k for graph between (R) and t with intercept Co
first graph is of zero order reactions.
Integrated rate law for first order reaction is
ln[R]=-kt+lnCo
On comparing with y=mx+C
Slope m=-k for graph between 1n (R) and t with intercept 1n Co
Second graph is of first order

Topic: Chemistry, Chemical Kinetics, JEE Main
The given reaction can occur in the presence of :

(a) Bromine water

(b) Br2 in CS2,273 K

(c) Br2/FeBr3

(d) Br2 in CHCl3,273 K

Choose the correct answer from the options given below:

Options:
A (b) and (d) only
B (a) and (c) only
C (b), (c) and (d) only
D (a), (b) and (d) only

The correct answer is:
(b), (c) and (d) only

Solution:
Bromine water gives tribromo products, other gives monobromo products in which para is major product.

Topic: Chemistry, Alcohols Phenols and Ethers, JEE Main, JEE Main 2021 (25 Jul Shift 1)
The given statements describe a group of organisms.

(i) Instead of a cell wall they have a protein rich pellicle making their body flexible.

(ii) They have 2 flagella, a short and a long one.

(iii) They show mixotrophic nutrition.

(iv) They are connecting links between plants and animals.

Which of the following groups is referred here?

Options:
A Dinoflagellates
B Slime moulds
C Desmids and diatoms
D Euglenoids

The correct answer is:
Euglenoids

Solution:
Euglenoids are unicellular aquatic alga that belongs to the kingdom Protista. Many of these organisms exhibit characteristics of both plants and animals. In this many of them have 2 flagella that emerges out of the cytostome through cytopharynx and are motile. Out of the two flagella, one is short and the other one is a long one. Instead of cell walls, they have a protein-rich pellicle that helps in maintaining the definite shape of the body. Nutrition in Euglena is accomplished by holophytic (able to synthesize organic compounds by photosynthesis) or saprophytic (those organisms get its nourishment from dead organisms) or both so they show the mixotrophic mode of nutrition.

Topic: Biology, Biological Classification, NEET
The given structure belongs to the organism of the phylum:

Options:
A Porifera
B Cnidaria
C Protista
D Ctenophora

The correct answer is:
Cnidaria

Solution:
The structure shown is Cnidoblast or Cnidocytes seen in Coelenterates and hence this phylum is also known as Phylum Cnidaria. These are stinging cells mainly present on the tentacles and also on the body. These cells help in anchorage, capturing the prey and for defense. These cells contain nematocysts which is filled with hypnotoxin (neurotoxin) and a thread is suspended inside the fluid. As any organism rests on the tentacles, the pressure is exerted to the fluid of cnidoblasts due to which the the thread expels out and hypnotoxin depresses the brain activity of the prey or the predator.

Topic: Biology, Animal Kingdom, NEET
The given structure of protein corresponds to:

Options:
A Primary
B Secondary
C Quaternary
D Tertiary

The correct answer is:
Tertiary

Solution:
Structure of protein has upto 4 levels :
1. Primary structure - Linear sequence of amino acids with 2 terminals :
A. N- terminal : On left side and is represented by the first amino acid (also known as N- terminal amino acid).
B. C- terminal : On right side and is represented by the last amino acid (also known as C- terminal amino acid).
- This structure appears like a thread and is non-functional.
2. Secondary structure - The above mentioned thread is folded in staircase like helix at some portions and in some other forms in remaining portions. This is also non-functional structure.
3. Tertiary structure - Long chain is also folded upon itself to form a hollow woolen ball like structure. To be functional to perform biological activity, proteins should acquire at least tertiary structure.
4. Quaternary structure - Few proteins are made up of 2 or more polypeptides because of which one more arrangement is there between them with respect to each other. This is termed as quaternary structure.
Example: Adult haemoglobin is made up of 4 globulin chains - 2α chains and 2β chains.

Topic: Chemistry, Biomolecules, NEET
The glass of optical fibre has a refractive index 1.55 and cladding with another glass of refractive index 1.51. When the surrounding medium is air, the numerical aperture will be

Options:
A 0.625
B 0.350
C 0.528
D 0.704

The correct answer is:
0.350

Solution:
For air, Î¼0=1. Here, Î¼1=1.55, Î¼2=1.51
NA=Î¼12-Î¼22Î¼0
=1.552-1.5121=0.350

Topic: Physics, Communication System, JEE Main
The glomerular area of the adrenal cortex is mainly responsible for

Options:
A maintaining glucose levels
B carbohydrate metabolism
C water and electrolyte balance
D steroid and hormone secretion

The correct answer is:
water and electrolyte balance

Solution:
Adrenals glands located on the kidneys produce a variety of hormones. Adrenal gland is divided into two parts - adrenal cortex and adrenal medulla (innermost layer). Cortex is further divided into zona glomerulosa, zona fasciculata and zona reticularis.
Zona glomerulosa is the outermost layer and responsible for production of aldosterone that is a mineralocorticoid which maintains electrolyte and water balance in the body.
Carbohydrate metabolism is regulated by glucocorticoids secreted by the zona fasciculata of adrenal cortex.
Zona reticularis is responsible for secretion steroidal hormones.

Topic: Biology, Chemical Coordination and Integration, NEET
The glycerin of density 1.25Ã103 kg m-3 is flowing through a conical tube with end radii 0.1 m and 0.04 m respectively. The pressure difference across the ends is 10 N m-2. The rate of flow of glycerine through the tube is

Options:
A 6.4Ã10-2 m2 s-1
B 6.4Ã10-4 m3 s-1
C 12.8Ã10-2 m3 s-1
D 12.8Ã103 m3 s-1

The correct answer is:
6.4Ã10-4 m3 s-1

Solution:
V=a1a22(p1-p2)Ï(a12-a22)
=Ïr12ÃÏr22 2(p1-p2)ÏÏr122-Ïr222
=Ïr12r22 2(p1-p2)Ï(r14-r24)
=227Ã0.12Ã0.042 2Ã101.25Ã103[0.14-0.044]
=6.4Ã10-4 m3 s-1

Topic: Physics, Mechanical Properties of Fluids, JEE Main
The gold numbers of a few protective colloids are

(A) Starch = 25

(B) Gelatin = 0.005 - 0.01

(C) Hemoglobin = 0.03

(D) âDextrin = 6 - 123.

Which is the best protective colloid ?

Options:
A A
B B
C C
D D

The correct answer is:
B

Solution:
Smaller the gold number, greater will be its protecting power.

Topic: Chemistry, Surface Chemistry, JEE Main
The gonadotropin-releasing hormone stimulates the release of

Options:
A LH and FSH from pituitary gland
B Testosterone from testis
C Melatonin from pineal gland
D Thyroxine from thyroid gland

The correct answer is:
LH and FSH from pituitary gland

Solution:
Gonadotropins are hormones synthesized and released by the anterior pituitary, which act on the gonads (testes and ovaries) to increase the production of sex hormones and stimulate production of either sperm or ova. Follicle stimulating hormone (FSH) and luteinizing hormones (LH) are the main gonadotropins.

Topic: Biology, Chemical Coordination and Integration, NEET
The gradient of medullary interstitium is mainly caused by

Options:
A sodium chloride and urea
B urea and HCl
C urea and uric acid
D urea and hydrogen ion

The correct answer is:
sodium chloride and urea

Solution:
One of the main functions of the kidneys is to keep the solute load of body fluids constant by regulating urine concentration and volume. The kidneys accomplish this task using countercurrent mechanisms. They depend on active transportation of solutes out of the ascending limb of the loop of Henle.

Topic: Biology, Excretory Products and their Elimination, NEET
The graph between ψ2 and r (radical distance) is shown below. This represents:

Options:
A 3s orbital
B 2p orbital
C 2s orbital
D 1s orbital

The correct answer is:
2s orbital

Solution:
This graph shows one radial node
Formula of radial node =n-l-1 ; angular node =l ; total node =n-1
n= Principal quantum number
l= Azimuthal quantum number

Radial nodes:

for 1s =n-l-1=1-0-1=0
for 2s=2-0-1=1
for 2p=2-1-1=0
for 3s=3-0-1=2

Topic: Chemistry, Structure of Atom, JEE Main, JEE Main 2019 (10 Apr Shift 1)
The graph between angle of deviation δ and angle of incidence i for a triangular prism is represented by :

Options:
A
B
C
D

The correct answer is:

Solution:
We know that angle of deviation depend upon the angle of incidence. If we determine experimentally the angle of deviation corresponding to different angles of incidence then and then plot i (on x-axis) and δ (on y-axis), we get a curve as shown in figure.

Clearly, if angle of incidence is gradually increased from a small value, the angle of deviation first decreases, becomes minimum for a particular angle of incidence and then begins to increase.

Topic: Physics, Ray Optics, JEE Main, JEE Main 2013 (07 Apr)
The graph between angle of deviation \( (\delta) \) and angle of incidence (i) for a triangular prism is represented by:

Options:
A
B
C
D

The correct answer is:

Solution:
For a prism, as the angle of incidence of light increases the angular deviation of light decreases upto a certain value and after a particular value of angle of incidence, the angular deviation starts to increase.

The correct graph that represents the variation of angular deviation with angle of incidence is shown below.

Topic: Physics, Ray Optics, JEE Main
The graph between frequency of incident radiations and stopping potential for a given photosensitive material is as follows.

What information can be obtained from the value of the intercept on the potential axis?

Options:
A Work function
B KE of electrons
C Stopping potential
D Frequency of photon

The correct answer is:
Work function

Solution:
Graph between frequency of incident radiation and stopping potential for a given photosensitive surface is shown below:

Intercept on the potential axis =− W 0 e

∴ Work function, W 0 =e× Magnitude of intercept on the potential axis.

Topic: Physics, Dual Nature of Matter, JEE Main
The graph between logt1/2 and log a at a given temperature is

Rate of this reaction will .................. with passage of time

Options:
A increase
B decrease
C remains constant
D first increase then decrease

The correct answer is:
remains constant

Solution:
The graph represents zero order reaction, therefore, rate of reaction will be constant with the passage of time.

Topic: Chemistry, Chemical Kinetics, NEET
The graph between restoring force and time in case of S.H.M is

Options:
A A straight line
B A circle
C A parabola
D A sine curve

The correct answer is:
A sine curve

Solution:
F=Ma=Mω2x=Mω2 Asin⁡ωt
Hence, graph between F and t is a sine curve.

Topic: Physics, Oscillations, JEE Main
The graph between the displacement $x$ and time ${ }^t$ for a particle moving in a straight line is shown in figure. During the interval $O A, A B, B C$ and $C D$, the acceleration of the particle is

Options:
A

B

C

D

The correct answer is:

Solution:
In portion $O A$, slope of $x-t$ graph is decreasing
$\therefore$ Velocity is decreasing
$\Rightarrow$ Acceleration is negative.
In portion $\mathrm{AB}$, displacement is constant due to which $\mathrm{v}=0$
$\Rightarrow$ Acceleration $=0$.
In portion $B C$, slope of $x-t$ graph is increasing
$\therefore$ Velocity is increasing
$\Rightarrow$ Acceleration is positive.
In portion CD, slope is $\mathrm{O}$ due to which Velocity, $\mathrm{v}=\mathrm{O}$
$\Rightarrow$ Acceleration $=0$

Topic: Physics, Motion In One Dimension, JEE Main
The graph between the mass of liquid inside the capillary and radius of the capillary is

Options:
A
B
C
D

The correct answer is:

Solution:
Mass of liquid inside capillary =Ïr2hd
= ÏrhdÃ r
since, hr= constant for capillary,
â´ mass of liquid inside â r

Topic: Physics, Mechanical Properties of Fluids, JEE Main
The graph between the square of the time period and cube of the distance of the planet from the sun is

Options:
A
B
C
D

The correct answer is:

Solution:
According to kepler's third law T2∝r3; At r=0,T=0. It shows that the graph between T2 and r3 is a straight line passing through origin

Topic: Physics, Gravitation, JEE Main
The graph between two quantities $P$ and $Q$ is a straight line when

Options:
A $P Q=$ constant
B $\frac{P}{Q}=$ constant
C $P Q^2=$ constant
D $\frac{P}{Q^2}=$ constant

The correct answer is:
$\frac{P}{Q}=$ constant

Solution:
When the graph between two quantities $P$ and $Q$ is straight line as shown in the figure, then slope of the graph remains constant.
i.e. slope $=\tan \theta=\frac{P}{Q}=$ constant

Topic: Physics, Motion In One Dimension, AP EAMCET, AP EAMCET 2020 (22 Sep Shift 1)
The graph given below represents the \( I-V \) characteristics of a zener diode. Which part of the characteristics curve is most relevant for its operation as a voltage regulator?

Options:
A \( \mathrm{ab} \)
B bc
C \( \mathrm{cd} \)
D de

The correct answer is:
de

Solution:
Zener diode is used as a voltage regulator in breakdown region.

In the voltage regulator, the voltage should not change even after the change in current. So, in the I-V characteristic of the zener diode in reverse bias, the d-e portion will be most relevant to the voltage regulator.

Topic: Physics, Semiconductors, JEE Main
The graph is represented by which of the following function?

Options:
A $f(x)=\sqrt{|x|-2}$
B $f(x)=\sqrt{|x-1|-1}$
C $f(x)=\sqrt{|x|-1}$
D $f(x)=\sqrt{|x+1|-1}$

The correct answer is:
$f(x)=\sqrt{|x-1|-1}$

Solution:
The domain of $f(x)=\sqrt{|x-1|-1}$ is $(-\infty, 0] \cup$ $[2, \infty)$ because $|x-1| \geq 1$. Now
$x \leq 0 \Rightarrow f(x)=\sqrt{|x-1|-1}=\sqrt{-x}$
So the graph must be upper half the parabola $y^2=-x$ with vertex at origin. Again
$x \geq 2 \Rightarrow y=\sqrt{x-2} \Rightarrow y^2=x-2$
which represents parabola in the upper half of the $x$-axis with vertex at $(2,0)$.

Topic: Mathematics, Functions, JEE Main
The graph of an object's motion (along the $x-$ axis) is shown in the figure. The instantaneous velocity of the object at points $A$ and $B$ are $v_A$ and $v_B$ respectively. Then

Options:
A
$v_A=v_B=0.5 \mathrm{~m} / \mathrm{s}$

B
$v_A=0.5 \mathrm{~m} / \mathrm{s} < v_B$
C
$v_A=0.5 \mathrm{~m} / \mathrm{s}>v_B$

D
$v_A=v_B=2 \mathrm{~m} / \mathrm{s}$

The correct answer is:
$v_A=v_B=0.5 \mathrm{~m} / \mathrm{s}$

Solution:
Instantaneous velocity $v=\frac{\Delta x}{\Delta t}$ From graph, $v_A=\frac{\Delta x_A}{\Delta t_A}=\frac{4 m}{8 s}=0.5 \mathrm{~m} / \mathrm{s}$ and $v_B=\frac{\Delta x_B}{\Delta t_B}=\frac{8 m}{16 s}=0.5 \mathrm{~m} / \mathrm{s}$ i.e., $v_A=v_B=0.5 \mathrm{~m} / \mathrm{s}$

Topic: Physics, Motion In One Dimension, JEE Main, JEE Main 2012 (07 May Online)
The graph of displacement $v / s$ time is

Options:
A

B

C

D

The correct answer is:

Solution:
We know that the velocity of body is given by the slope of displacement - time graph. So it is clear that initially slope of the graph is positive and after some time it becomes zero (corresponding to the peak of graph) and then it will becomes negative.

Topic: Physics, Motion In One Dimension, JEE Main
The graph of elongation of a rod of a substance A with temperature rise is shown in the first graph. A liquid B contained in a cylindrical vessel made out of substance A (graduated in millilitres) at 0 Â°C is heated gradually. The readings of the liquid level in the vessel corresponding to different temperatures are shown in the second graph. The real coefficient of volume expansion of the liquid is

Options:
A 2.7Ã10-5âC-1
B 15.4Ã10-5âC-1
C 16.2Ã10-5âC-1
D 151.2Ã10-5 âC-1

The correct answer is:
16.2×10-5∘C-1

Solution:
From the graph (a),

the slope of line is
m = 1001.2 300
Î L Î T = 1001.2 - 1000.0 mm 3 0 0 - 0 â C
=4Ã10-6 m âC-1
But Î L Î T = L Î±
â´ Î±=4Ã10-61m
=4Ã10-6 âC-1
As shown in graph (b),
the slop of line is
ÎVaÎT=1003-1000mL20-0âC=320mL âC-1
But, Î V a Î T = V Î³ a
â´ Î³a=320Ã103=150Ã10-6 âC-1
Since, Î³ a = Î³ r - Î³ c
â´ Î³ r = Î³ a + Î³ c = Î³ a + 3 Î±
=150+12Ã10-6 âC-1
=16.2Ã10-5 âC-1

Topic: Physics, Thermal Properties of Matter, JEE Main
The graph of function $f(x)$ is shown below :
Then the graph of $g(x)=\frac{1}{f(|x|)}$ is :

Options:
A

B

C

D

The correct answer is:

Solution:
$\begin{aligned} & g(x)=\frac{1}{f(\mid x))} g(x) \Rightarrow \text { even functions } \Rightarrow \text { symmetric about } y \text {-axis } \\ & \Rightarrow \quad x \rightarrow \infty \quad f(x) \rightarrow 0 \\ & \text { at } x=x_1 \quad f(x)=0 \Rightarrow g\left(x_1\right) \rightarrow \infty\end{aligned}$

Topic: Mathematics, Functions, JEE Main
The graph of logxmvs log p for an adsorption process is a straight line inclined at an angle of 45° with intercept equal to 0.6020. The mass of gas adsorbed per unit mass of adsorbent at the pressure of 0.4 atm is _____×10-1 (Nearest integer)

Given : log2=0.3010

Options:

The correct answer is:
16

Solution:
The graphical representation of logarithmic form of Freundilich adsorption isotherm is as follows,

The logarithmic form of Freundilich adsorption isotherm is

logxm=logk+1nlogP

1n=tan45°=1

logk=0.6020=log4

⇒K=4

∴ xm=K·P1/n

xm=40.4=1.6

xm=1.6=16×10-1

Topic: Chemistry, Surface Chemistry, JEE Main, JEE Main 2023 (30 Jan Shift 2)
The graph of the antiderivative of fx=xex2 passes through 0,3, then the value of g2-f0 is

Options:

The correct answer is:
7

Solution:
Let gx represent the antiderivative of fx

Therefore, gx=â«xex2dxâ
=x2ex2-â«1â2ex2dxââ¦[integration by parts]
=2xex2-4ex2+c
The graph of y=g(x) passes through (0,3)
â3=0-4e0+c
âc=7
Hence, g(x)=2xex2-4ex2+7
âg(x)=2(x-2)ex2+7
âg(2)=7, f(0)=0
âg(2)-f(0)=7

Topic: Mathematics, Indefinite Integration, JEE Main
The graph of the function $\mathrm{f}(\mathrm{x})=\mathrm{x}+\frac{1}{8} \sin (2 \pi \mathrm{x}), 0 \leq \mathrm{x} \leq 1$ is shown below. Define $f_{1}(x)=f(x), f_{n+1}(x)=f\left(f_{n}(x)\right)$, for $n \geq 1$
Which of the following statements are true?
I. There are infinitely many $x \in[0,1]$ for which $\lim _{n \rightarrow \infty} f_{n}(x)=0$
II. There are infinitely many $\mathrm{x} \in[0,1]$ for which $\lim _{\mathrm{n} \rightarrow \infty} \mathrm{f}_{\mathrm{n}}(\mathrm{x})=\frac{1}{2}$
III. There are infinitely many $x \in[0,1]$ for which $\lim _{n \rightarrow \infty} f_{n}(x)=1$
IV. There are infinitely many $x \in[0,1]$ for which $\lim _{n \rightarrow \infty} f_{n}(x)$ does not exist

Options:
A I and III only
B II only
C I, II, III only
D I, II, III and IV

The correct answer is:
II only

Solution:
$\lim _{n \rightarrow \infty} f_{n}(x)=f(f(f(\ldots \ldots \ldots \infty$ times $(x))$
Now for $\mathrm{x}_{1} \in\left(0, \frac{1}{2}\right)$
$\mathrm{f}\left(\mathrm{x}_{1}\right)>\mathrm{x}_{1}$ as $\mathrm{f}(\mathrm{x})$ is concave - downward Thus $\mathrm{f}_{\mathrm{n}} \rightarrow \frac{1}{2}$ as $\mathrm{n} \rightarrow \infty$
Similarly for $\mathrm{x}_{1} \in\left(\frac{1}{2}, 1\right)$
$\mathrm{f}\left(\mathrm{x}_{1}\right) < \mathrm{x}_{1}$ as $\mathrm{f}(\mathrm{x})$ is concave upward Thus $\mathrm{f}_{\mathrm{n}} \rightarrow \frac{1}{2}$ as $\mathrm{n} \rightarrow \infty$

Topic: Mathematics, Functions, JEE Main
The graph of the function $y=f(x)$ is symmetrical about the line $x=2$, then

Options:
A
$f(x+2)=f(x-2)$

B
$f(2+x)=f(2-x)$

C
$f(x)=f(-x)$

D
$f(x)=-f(-x)$

The correct answer is:
$f(2+x)=f(2-x)$

Solution:
If $y=f(x)$ is symmetric about the line $x=2$ then $f(2+x)=f(2-x)$

Topic: Mathematics, Functions, JEE Main, JEE Main 2004
The graph shown in the adjacent diagram represents the variation of temperature (T) of two bodies x and y having the same surface area, with time (t). Both of these bodies lose heat only due to the emission of radiation. Find the correct relation between the emissive and absorptive power of the two bodies.

Options:
A Ex>Ey and ax<ay
B Ex<Ey and ax>ay
C Ex>Ey and ax>ay
D Ex<Ey and ax<ay

The correct answer is:
Ex>Ey and ax>ay

Solution:
Rate of cooling -dTdt∝ emissivity e
From the graph,
-dTdtx>-dTdty
∴ ex>ey
Further emissivity (e)∝ absorptive power (a) (good absorbers are good emitters also)
∴ ax>ay

Topic: Physics, Thermal Properties of Matter, JEE Main
The graph shows how the magnification m produced by a thin lens varies with image distance v. The focal length of the lens used is

Options:
A bc
B ac
C b2ca
D b2ac

The correct answer is:
bc

Solution:
For a thin lens,
m=1-vf
From the above equation, slope of the line is 1f
cb=1f
f=bc

Topic: Physics, Ray Optics, JEE Main, JEE Main 2019 (10 Apr Shift 2)
The graph shows how the magnification m produced by a thin lens varies with image distance v. The focal length of the lens used is

Options:
A bc
B ac
C b2ca
D b2ac

The correct answer is:
bc

Solution:
For a thin lens,
m=1-vf
From the graph, slope of the line m=1f
cb=1f
f=bc

Topic: Physics, Ray Optics, JEE Main
The graph shows the variation of photocurrent with the applied voltage in a photoelectric effect experiment for three different beams of light falling on identical metal surfaces, then which among the following is correct?

Options:
A A and B recieve the light of the same intensity while B & C receive the light of the same frequency
B B and C recieve the light of the same intensity while A & B recieve the light of the same frequency
C A & B recieve the light of the same frequency while B & C recieve the light of the same intensity
D A and C recieve the light of the same intensity and B & C recieve the light of the same frequency

The correct answer is:
A and B recieve the light of the same intensity while B & C receive the light of the same frequency

Solution:
Saturation current for A and B Incident light will have the same intensity while stopping potential is same for B and C
eVs=Kmax=hν-ϕ
Frequency of incident light will be the same

Topic: Physics, Dual Nature of Matter, JEE Main
The graph which represents the following reaction is:

C6H53C-ClOH-PyridineC6H53C-OH

Options:
A
B
C
D

The correct answer is:

Solution:
Given reaction,

C6H53C-ClOH-PyridineC6H53C-OH

It is SN1 reaction. So rate of reaction depends on the concentration of alkyl halide only.

So, the correct graph is option (C).

Topic: Chemistry, Chemical Kinetics, JEE Main, JEE Main 2023 (01 Feb Shift 2)
The graphs of sine and cosine functions, intersect each other at a number of points and between two consecutive points of intersection, the two graphs enclose the same area A. Then A4 is equal to

Options:

The correct answer is:
64

Solution:
A=∫π/45π/4sinx-cosxdx

=-cosx-sinxπ/45π/4

=--12--12--12-12

⇒ A=22+22=22 sq. units

⇒ A4=224=16×4=64

Topic: Mathematics, Area Under Curves, JEE Main, JEE Main 2021 (25 Feb Shift 1)