datavorous/entrance-exam-dataset huggingface dataset:
Which statement about aspirin is not true?

Options:
A Aspirin belongs to narcotic analgesics.
B It is effective in relieving pain.
C It has anti blood clotting action.
D It is a neurologically active drug.

The correct answer is:
Aspirin belongs to narcotic analgesics.

Solution:
Aspirin inhibits the synthesis of compounds known as prostaglandins which stimulate inflammation in the tissues and cause pain. So it is effective in relieving pain. It has anti blood clotting action, so widely used to prevent heart attacks. It does not make a person addictive, as it is non-narcotic drug.

Topic: Chemistry, Chemistry in Everyday Life, JEE Main
Which statement about aspirin is $\underline{\text { NOT }}$ ture

Options:
A It is effective in relieving pain
B Aspirin belongs to narcotic analgesics
C It reduces body temperature
D It has antiblood clotting action

The correct answer is:
Aspirin belongs to narcotic analgesics

Solution:
Aspirin, salicylates, and many over the counter pain relievers belong to a group of drugs called the nonsteroidal anti-inflammatory drugs (or NSAIDs for short). Three of the main types of NSAIDs that arthritis patient often use are acetaminophen, ibuprofen, and analgesic (pain-relieving) rubs. Aspirin does not belong to narcotic analgesics.

Topic: Chemistry, Chemistry in Everyday Life, MHT CET, MHT CET 2020 (13 Oct Shift 2)
Which statement accurately describes the behavior of acceleration due to gravity with increasing altitude?

Options:
A Acceleration due to gravity increases.
B Acceleration due to gravity decreases.
C Acceleration due to gravity remains constant.
D Acceleration due to gravity fluctuates unpredictably.

The correct answer is:
Acceleration due to gravity decreases.

Solution:
Correct Option is : (B)
Acceleration due to gravity decreases.

Topic: Chemistry, Gravitation, NEET
Which statement below best describes the ways that energy and pesticides are transferred between levels in food chains?

Options:
A Available energy increases and pesticide concentrations increase as you move up a food chain.
B Available energy decreases and pesticide concentrations increase as you move up a food chain.
C Available energy decreases and pesticide concentrations decrease as you move up a food chain.
D Available energy increases and pesticide concentrations decrease as you move up a food chain.

The correct answer is:
Available energy decreases and pesticide concentrations increase as you move up a food chain.

Solution:
The energy gain in an organism at each trophic level is utilized in all metabolic activities and also lost as heat to the surrounding. Thus, lower amount of energy is transferred to succeeding trophic level in a food chain.
Pesticides are harmful chemicals that are non-biodegradable and remain in the body tissues throughout their life. These chemicals are passed to the succeeding trophic level and accumulates and increases at each trophic level.
Concentration of pesticides increases whereas energy level decreases, from lower to higher trophic level in a food chain.

Topic: Biology, Environmental Issues, NEET
Which statement depicts incorrect characteristic of Cyanobacteria?

Options:
A They have chlorophyll a similar to green plants.
B They are unicellular, colonial or filamentous form
C Motile specialized cells "heterocysts" are present which can fix atmospheric nitrogen.
D They form water bloom in polluted water bodies.

The correct answer is:
Motile specialized cells "heterocysts" are present which can fix atmospheric nitrogen.

Solution:
Cyanobacteria have autotrophic nutrition and can perform photosynthesis with the help of chlorophyll a which is similar in green plants. They may be unicellular, colonial or filamentous forms. Nitrogen fixation in cyanobacteria mainly occurs in specialized cells called heterocysts. Heterocysts are large sized, pale coloured, non motile, mucilage free thick walled cells which are impermeable to oxygen. In polluted water bodies the algal bloom is observed due to eutrophication and the cyanobacteria/blue green algae predominates.

Topic: Biology, Biological Classification, NEET
Which statement is correct about chemisorptions?

Options:
A It is irreversible in nature
B It involves formation multi layer of adsorbent on adsorbate
C Decreases with increase of temperature
D It involves the weak attractive forces between adsorbent and adsorbate

The correct answer is:
It is irreversible in nature

Solution:
Chemical adsorption is irreversible due to formation of new strong chemical bonds. It is unilayer due formation of new chemical bonds. It first increases with increase in temperature due to supply of energy of activation then decreases due to breaking of covalent bond.

Topic: Chemistry, Surface Chemistry, JEE Main
Which statement is correct according to Werner's coordination theory for co-ordination compounds?

Options:
A Primary valency are ionizable in nature.
B Secondary valency are ionizable in nature.
C Primary and secondary valencies both are ionizable in nature.
D Only primary valency is not ionizable in nature.

The correct answer is:
Primary valency are ionizable in nature.

Solution:
According to Werner's coordination theory prmary valencies are ionisable while secondary valency which satisfy by ligands are non ionisable.

Topic: Chemistry, Coordination Compounds, JEE Main
Which statement is correct?

Options:
A Synthesis of Buna-S needs nascent oxygen.
B Buna-S is a synthetic and linear thermosetting polymer.
C Buna-N is a natural polymer.
D Neoprene is an addition copolymer used in plastic bucket manufacturing.

The correct answer is:
Synthesis of Buna-S needs nascent oxygen.

Solution:
Buna-S is an elastomer
Buna-N is a synthetic polymer
Buna-S is polymerised by addition polymerisation method which needs radical initiator for chain propagation step. Nascent oxygen can be used as an Radical initiator.
Neoprene is a synthetic rubber.

Topic: Chemistry, Polymers, JEE Main, JEE Main 2021 (25 Feb Shift 1)
Which statement is incorrect?

Options:
A All reversible cycles have same efficiency
B Reversible cycle has more efficiency than an irreversible one
C Carnot cycle is a reversible one
D Carnot cycle has the maximum efficiency in all cycles

The correct answer is:
All reversible cycles have same efficiency

Solution:
The efficiency of all reversible cycles is determined by the temperature of the source and sink. Therefore, all reversible cycles do not have same efficiency.

An irreversible heat engine's efficiency is always lower than that of a reversible heat engine operating between the same two reservoirs.

The Carnot heat-engine cycle is described as a totally reversible cycle and has maximum efficiency in all cycles.

Topic: Physics, Thermodynamics, JEE Main
Which statement is incorrect?

Options:
A
all reversible cycles have same efficiency

B
reversible cycle has more efficiency than an irreversible one

C
Carnot cycle is a reversible one

D
Carnot cycle has the maximum efficiency in all cycles

The correct answer is:
all reversible cycles have same efficiency

Solution:
No Solution Available

Topic: Physics, Thermodynamics, JEE Main, JEE Main 2002
Which statement is incorrect with reference to inner transition elements?

Options:
A The oxides of lanthanoids are basic
B Pm is radioactive element among actinoids
C The values of ionization enthalpy of actinoids are less than the values of ionization enthalpy of lanthanoids
D Only in the electronic configuration of lanthanoids like Ce,Gd, Lu the electrons are filled in 5d orbitals

The correct answer is:
Pm is radioactive element among actinoids

Solution:
Pm is not actinoids, its a lanthanide

Topic: Chemistry, d and f Block Elements, JEE Main
Which statement is NOT correct for p-toluenesulphonyl chloride?

Options:
A It is hinsberg's reagent
B It is used to distinguish primary and secondary amines.
C On treatment with secondary amine, it leads to a product, that is soluble in alkali.
D It does not react with tertiary amine.

The correct answer is:
On treatment with secondary amine, it leads to a product, that is soluble in alkali.

Solution:
P-toluenesulphonyl chloride, which is also known as Hinsberg's reagent, It reacts with primary and secondary amines to form sulphonamides.

Tertiary amines do not react with P-toluenesulphonyl chloride.

Topic: Chemistry, Amines, JEE Main, JEE Main 2022 (26 Jun Shift 2)
Which statement is not true with respect to nitrate ion test?

Options:
A A dark brown ring is formed at the junction of two solutions.
B Ring is formed due to nitroferrous sulphate complex.
C The brown complex is FeH2O5NOSO4
D Heating the nitrate salt with conc. H2SO4, light brown fumes are evolved.

The correct answer is:
Ring is formed due to nitroferrous sulphate complex.

Solution:
Brown ring test is usually carried out by adding dilute ferrous sulphate solution to an aqueous solution containing nitrate ion, and then carefully adding concentrated sulphuric acid along the sides of the test tube. A brown ring at the interface between the solution and sulphuric acid layers indicates the presence of nitrate ion in solution.

NO3−+H2SO4→HNO3+HSO4−

6FeSO4+3H2SO4+2HNO3→3Fe2SO43+2NO+4H2O

NO+FeSO4+5H2O→FeH2O5NOSO4 (Brown ring)

Brown ring complex formed is FeH2O5NOSO4

IUPAC name of the above complex is PentaaquanitrosylIron(I ) Sulphate.

Nitrate ions reacts with sulphuric acid to form nitrogen dioxide which is responsible for brown fumes.

Topic: Chemistry, Practical Chemistry, JEE Main, JEE Main 2022 (26 Jun Shift 1)
Which statement is true about bryophytes?

Options:
A They are non-photosynthetic
B Zygote produces gametophyte on germination
C Spores form gametophyte plant on germination
D They have vascular tissues

The correct answer is:
Spores form gametophyte plant on germination

Solution:
In bryophytes sporogenic meiosis takes place i.e., spore mother cells of sporophyte undergo meiosis and form haploid spores. These spores on germination form haploid gametophyte. The main plant body of Bryophytes is gametophyte which is photosynthetic. A zygote is diploid structure which develops to form diploid sporophyte. Bryophytes ar non-vascular plants.

Topic: Biology, Plant Kingdom, NEET
Which statement is true about the spontaneous cell reaction in galvanic cell:

Options:
A \( \mathrm{E}^{\circ} \) cell \( >0 ; \Delta \mathrm{G}^{\circ} < 0 ; \mathrm{Q} < \mathrm{Kc} \)
B \( \mathrm{E}^{\circ} \) cell \( >0 ; \Delta \mathrm{G}^{\circ}>0 ; \mathrm{Q} < \mathrm{Kc} \)
C \( \mathrm{E}^{\circ}{ }^{\circ} \) cell \( >0 ; \Delta \mathrm{G}^{\circ}>0 ; \mathrm{Q}>\mathrm{C} \)
D \( \mathrm{E}^{\circ} \) cell \( >0 ; \Delta \mathrm{G}^{\circ}>0 ; \mathrm{Q} < \mathrm{Kc} \)

The correct answer is:
\( \mathrm{E}^{\circ} \) cell \( >0 ; \Delta \mathrm{G}^{\circ} < 0 ; \mathrm{Q} < \mathrm{Kc} \)

Solution:
For spontaneous cell reaction in galvanic cell: ∆G°<0.

Since ∆G°=-nFE°Cell, thus E°Cell>0.

Also, in order to proceed the chemical reaction in forward direction the reaction quotient must be lesser than the equilibrium constnat, i.e. Q<Kc.

Combining all above conditions:

Eºcell>0; ∆Gº<0; Q<Kc.

Topic: Chemistry, Electrochemistry, JEE Main
Which statement is true about the transitional elements

Options:
A They are highly reactive
B They show variable oxidation states
C They have low M.P.
D They are highly electropositive

The correct answer is:
They show variable oxidation states

Solution:
They show variable oxidation states due to participation of (n -1)d-orbitals electrons with ns orbital electrons.

Topic: Chemistry, d and f Block Elements, JEE Main
Which statement is true for angiosperms?

Options:
A Microspore is the resultant of mitotic division.
B Microspore is the 1st cell of gametophytic generation.
C Microspore is the resultant of double fertilization.
D Microspore is the first cell of endosperm.

The correct answer is:
Microspore is the 1st cell of gametophytic generation.

Solution:
Microspore is the first cell of gametophytic generation. It is haploid in structure formed by reduction division or meiotic division of the microspore mother cell. The microspore mother cell is formed inside the anther which is the male reproductive structure. The main plant body is diploid (2n) and when microspore is formed, the gametophytic phase begins. The microspore gives rise to the male gametophyte.

Topic: Biology, Sexual Reproduction in Flowering Plants, NEET
Which statement is wrong for viruses?

Options:
A All are parasites
B All of them have helical symmetry
C They have ability to synthesize nucleic acids and proteins
D Antibiotics have no effect on them

The correct answer is:
All of them have helical symmetry

Solution:
Viruses are the microorganisms which injects a living host and remain as intercellular parasite. They inject their genetic material which replicates using host cell machinery and reform their structure and attain viable structure capable enough to affect other cells. They have ability to synthesize nucleic acids by replication. Antibiotics do not acts against virus as they are made up of polymorphic protein coat. Viruses have different type of symmetry like icosahedral and helical.

Topic: Biology, Biological Classification, NEET, NEET 2012 (Screening)
Which statement (s) is/are not true for the five-kingdom classification proposed by R.H. Whittaker (1969)?

a The main criteria for classification include cell structure, thallus organization, mode of nutrition, reproductions, and phylogenetic relationship.

b All prokaryotic organisms such as bacteria, blue-green algae, and ferns are grouped together under kingdom Monera.

c Chlamydomonas, Chlorella, and Spirogyra are placed in Algae within plants due to the presence of the cell wall.

d Fungi are placed in a separate kingdom: Kingdom Fungi.

e Paramecium and Amoeba are placed in the animal kingdom due to lack of cell wall.

Options:
A Only a
B a, b and d
C a, d and e
D a, b and e

The correct answer is:
a, b and e

Solution:
The main criteria of the five kingdom classification were cell structure, body organisation, mode of nutrition and reproduction, and phylogenetic relationships. Monera includes bacteria and Ferns are included under Kingdom Plantae, Pteridophytes. Paramecium and Amoeba are placed in Kingdom Protista due to their unicellular nature. Chlamydomonas, Chlorella, and Spirogyra were placed in Algae within plants due to the presence of the cell wall and for their autotrophic nature.

Topic: Biology, Biological Classification, NEET
Which statements among the following are correct?

I. Ce+3 is an oxidizing agent & colourless.

II. Lu3+ is colourless.

III. Actinoids exhibit a higher number of oxidation states than lanthanoid

IV. All 3d elements give H2 with 1 M HCl

Options:
A II, III
B I, III
C I, II, III
D I, IV

The correct answer is:
I, II, III

Solution:
I. âCe+3 formation favoured by its noble gas configuration, but it is a strong oxidant reverting to the common +3 state and it is colourless.
II. Lu3+ is diamagnetic and colourless.
III.â Actinoids exhibit a higher number of oxidation states than lanthanoid
IV. All 3d elements do not give H2 with 1M HCl

Topic: Chemistry, d and f Block Elements, JEE Main
Which statement(s), of the following, with regard to Einstein's prediction based upon photoelectric effect is true:
1. Energy was given to electromagnetic waves in separate quanta
2. Energy was carried by these waves in separate quanta
3. Energy in light is spread out on wavefronts

Options:
A 1 and 2 both
B 3 only
C 1 only
D More than one of the above

The correct answer is:
1 and 2 both

Solution:
- Statement 1-Energy was given to electromagnetic waves in separate quanta.
This is true and predicted by Albert Einstein
- Statement 2- Energy was carried by these waves in separate quanta. This is also true predicted and proved that each quanta having fixed energy hv.
Hence both the statements are correct.
Einstein had not said about spread of wavefront in photoelectric effect. So this is not correct.

Topic: Physics, Dual Nature of Matter, JEE Main
Which structure of protein remains intact after coagulation of egg white on boiling?

Options:
A Primary
B Tertiary
C Secondary
D Quaternary

The correct answer is:
Primary

Solution:
When an egg is boiled, the soluble globular protein, albumin present in it is converted to insoluble fibrous protein.

During denaturation, its biological activity is lost. Boiling an egg causes denaturation of its protein resulting in loss of its quaternary, tertiary and secondary structures.

But the primary structure (representing the sequence of α amino acids) remains intact.

Hence option A is the answer.

Topic: Chemistry, Biomolecules, JEE Main, JEE Main 2024 (27 Jan Shift 2)
Which structure(s) of proteins remains(s) intact during denaturation process?

Options:
A Both secondary and tertiary structures
B Primary structure only
C Secondary structure only
D Tertiary structure only

The correct answer is:
Primary structure only

Solution:
The loss in biological activity of proteins due to unfolding of globules and uncoiling of helix is called denaturation of proteins. During the denaturation, primary structure remains intact but secondary and tertiary structures are destroyed. e.g. The coagulation of egg white on boiling, curding of milk caused by bacteria due to formation of lactic acid.

Topic: Chemistry, Biomolecules, NEET, NEET 2019 (Odisha)
Which substance does not speed up decomposition of $\mathrm{H}_2 \mathrm{O}_2$

Options:
A Glycerol
B $P t$
C Gold
D $\mathrm{MnO}_2$

The correct answer is:
Glycerol

Solution:
Glycerol, phosphoric acid or acetanilide is added to $\mathrm{H}_2 \mathrm{O}_2$ to check its decomposition

Topic: Chemistry, Hydrogen, JEE Main
Which substance is obtained in the solution on electrolysis of aq. CuSO4 solution using graphite electrodes?

Options:
A CuOH2
B Na2SO4
C H2SO4
D H2O

The correct answer is:
H2SO4

Solution:
AtâcathodeâC u +2 âwillâgetâreducedâdueâtoâgreaterâreductionâpotentialâ C u +2 +2 e â âCu( s ) Atâanode,â H 2 Oâwillâgetâpreferentiallyâdischarged. ââ H 2 Oâ 1 2 O 2 +2 H + +2 e â Henceâtheâfinalâsolutionâwillâcontainâ H + â&âS O 4 â2 or H 2 S O 4

Topic: Chemistry, Electrochemistry, JEE Main
Which sulphide is soluble in $\left(\mathrm{NH}_4\right)_2 \mathrm{CO}_3$

Options:
A $\mathrm{Sn} \mathrm{S}$
B $A s_2 S_3$
C $\mathrm{Sb}_2 \mathrm{~S}_3$
D $\operatorname{CaS}$

The correct answer is:
$A s_2 S_3$

Solution:
$\mathrm{As}_2 \mathrm{~S}_3$ forms complex with $\left(\mathrm{NH}_4\right)_2 \mathrm{CO}_3$

Topic: Chemistry, Practical Chemistry, JEE Main
Which technique among the following, is most appropriate in separation of a mixture of 100mg of p-nitrophenol and picric acid?

Options:
A Steam distillation
B 2-5 ft long column of silica gel
C Sublimation
D Preparative TLC (Thin Layer Chromatography)

The correct answer is:
Preparative TLC (Thin Layer Chromatography)

Solution:
Solvent polarity has been related to Rf value of nitrocompounds.

100mg p-nitrophenol and picric acid have different Rf value on silica gel plate

∴ Preparative TLC is best to separate 100mg of para nitrophenol and picric acid

Topic: Chemistry, General Organic Chemistry, JEE Main, JEE Main 2022 (26 Jul Shift 1)
Which tissue is not correctly related to its fate during the secondary growth?

Options:
A

Tissue	Fate during secondary growth
Secondary xylem	Produced in high amount

B

Tissue	Fate during secondary growth
Primary phloem	Produced in low amount

C

Tissue	Fate during secondary growth
Cambial ring	Cut off secondary permanent tissue on both side

D

Tissue	Fate during secondary growth
Secondary phloem	Synthesized on outer side

The correct answer is:

Tissue	Fate during secondary growth
Primary phloem	Produced in low amount

Solution:
Mechanism in secondary growth in vascular region of dicot stem
1. Vascular cambium (intrafscicular cambium) alongwith interfascicular cambium forms a continuous ring of cambium.
2. Cambial ring becomes active and cut off secondary phloem towards outer side and secondary xylem towards inner side.
3. Secondary xylem is produced more in quantity as cambium is more active in its inner part.
4. When secondary growth repeats few more times, high amount of secondary xylem is accumulates which results in crushing of the primary phloem and most of the secondary phloem (although primary xylem may remain intact).
5. Cambium forms narrow bands of secondary phloem at some places which are termed as medullary rays.
6. Girth of plant increases.

Topic: Biology, Anatomy of Flowering Plants, NEET
Which transition in the hydrogen spectrum would have the same wavelength as the Balmer type transition from n=4 to n=2 of He+spectrum

Options:
A n=2 to n=1
B n=1 to n=3
C n=1 to n=2
D n=3 to n=4

The correct answer is:
n=2 to n=1

Solution:
For He+ ion, the wave number associated with the Balmer transition, n = 4 to n = 2 is given by:

1λ = RZ2 1n12 - 1n22

Where, n1 = 2

n2 = 4

Z = atomic number of helium

1λ=R(2)2122-142

⇒1λ=4R4-116

⇒1λ= 3R4

⇒λ = 43R

According to the question, the desired transition for hydrogen will have the same wavelength as that of He+.

λ(H)=λHe+

R(1)21n12-1n22 = 3R4

By hit and trial method,

1n12-1n22=112-122

On comparing n1=1 & n2=2

So, the correct answer is n = 2 to n = 1.

Topic: Chemistry, Structure of Atom, JEE Main, JEE Main 2023 (31 Jan Shift 1)
Which transitions in a hydrogen atom emit photons of highest frequency?

Options:
A $n=2$ to $n=1$
B $n=1$ to $n=\infty$
C $n=\infty$ to $n=1$
D $n=3$ to $n=1$

The correct answer is:
$n=2$ to $n=1$

Solution:
Lower the value of the lower quantum number to which electron is jumping, higher will be the frequency. Therefore $n=2$ to $n=1$ transition produces highest frequency.

Topic: Physics, Atomic Physics, JEE Main
Which trend is observed in the boiling point of alkynes with an increase in molar mass?

Options:
A It decreases with an increase in molar mass.
B It remains constant.
C It increases with an increase in molar mass.
D It is not affected by molar mass.

The correct answer is:
It increases with an increase in molar mass.

Solution:
The boiling point of alkynes generally increases with an increase in molar mass.

Topic: Chemistry, Hydrocarbons, NEET
Which two of the following five physical parameters have the same dimensions?
(a) energy density
(b) refractive index
(c) dielectric constant
(d) Young's modulus
(e) magnetic field

Options:
A (a) and (e)
B (b) and (d)
C (c) and (e)
D (a) and (d)

The correct answer is:
(a) and (d)

Solution:
Energy density and Young's modulus have same dimensional formula.

Topic: Physics, Units and Dimensions, NEET, NEET 2008 (Mains)
Which two of the following five physical parameters have the same dimensions?
(A) Energy density
(B) Refractive index
(C) Dielectric constant
(D) Young’s modulus
(E) Magnetic field

Options:
A (B) and (D)
B (C) and (E)
C (A) and (D)
D (A) and (E)

The correct answer is:
(A) and (D)

Solution:
[Energy density] =ââ [Workâdone] [Volume]
=â[ML2âTâ2][L3]â=â[MLâ1âTâ2]
[Youngâs modulus] =â[ F A âÃâ l Îl ]
=â[MLââTâ2][L2]â[L][L]â=â[MLâ1âTâ2]

Topic: Physics, Units and Dimensions, JEE Main
Which two sets of reactants best represent the amphoteric character of Zn(OH)2 ?

Set 1 : Zn(OH)2 (s) and OHâ (aq)

Set 2 : Zn(OH)2(s) and H2O(l)

Set 3 : Zn(OH)2(s) and H+(aq)

Set 4 : Zn(OH)2(s) and NH3 (aq)

Options:
A 1 and 2
B 1 and 3
C 2 and 4
D 2 and 3

The correct answer is:
1 and 3

Solution:
Zn OH 2 Acid + 2 OH - Base ⟶ ZnO 2 2 - Salt + 2 H 2 O Water
Zn OH 2 Base + 2 H + Acid ⟶ Zn 2 + Salt + 2 H 2 O Water

Topic: Chemistry, d and f Block Elements, JEE Main
Which two statements are correct for racemose inflorescence?

(i) The main axis continues to grow.

(ii) The main axis terminates in a flower.

(iii) Flowers are borne laterally in acropetal succession.

(iv) Flowers are borne in a basipetal order.

Options:
A i, iii
B i, iv
C ii, iii
D ii, iv

The correct answer is:
i, iii

Solution:
In racemose type of inflorescences the main axis continues to grow, the flowers are borne laterally in an acropetal succession. In cymose type of inflorescence the main axis terminates in a flower, hence is limited in growth. The flowers are borne in a basipetal order

Topic: Biology, Morphology of Flowering Plants, NEET