datavorous/entrance-exam-dataset huggingface dataset:
Which does not react with Fehling's solution?

Options:
A $\mathrm{CH}_{3} \mathrm{CHO}$
B $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CHO}$
C $\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}$
D $\mathrm{HCOOH}$

The correct answer is:
$\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CHO}$

Solution:
Aromatic aldehyde $i e, \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CHO}$ are not able to reduce Fehling's solution but it gives Cannizaro's reaction with alkali.

Topic: Chemistry, Alcohols Phenols and Ethers, JEE Main
Which doesn’t follow Markownikoff’s rule

Options:
A $\mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}_2$
B $\mathrm{CH}_3 \mathrm{CH}=\mathrm{CHCH}_3$
C

D $\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}=\mathrm{CH}_2$

The correct answer is:
$\mathrm{CH}_3 \mathrm{CH}=\mathrm{CHCH}_3$

Solution:
Markownikoff’s rule can not be applied for symmetrical alkene.

Topic: Chemistry, Hydrocarbons, JEE Main
Which drug given below is used as an analgesic?

Options:
A Iodex
B Tincture iodine
C Tetracyclin
D Aspirin

The correct answer is:
Aspirin

Solution:
An analgesic drugs is one which relieves or decrease the pain e.g., analgin, aspirin (belongs to non-narcotics and morphine, codein, heroin (belongs to narcotics class)

Topic: Chemistry, Chemistry in Everyday Life, JEE Main
Which element among the following cannot form an amphoteric oxide?

Options:
A Al
B Sn
C Sb
D P

The correct answer is:
P

Solution:
Phosphorus being a non-metal always forms acidic oxides like P4O6, P4O10, etc. whereas Al, Sn and Sb are amphoteric elements.
Al2O3, SnO and Sb2O3 are amphoteric oxides i.e., they can react with both acids as well as bases.

Topic: Chemistry, p Block Elements (Group 13 & 14), JEE Main
Which element is found in free state

Options:
A lodine
B Sulphur
C Phosphorus
D Magnesium

The correct answer is:
Sulphur

Solution:
Among the following options, only Sulphur is found in its free state i.e. $S_{8}$.

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), JEE Main
Which element is not present in Nessler’s reagent?

Options:
A Mercury
B Potassium
C Iodine
D Oxygen

The correct answer is:
Oxygen

Solution:
Nessler’s reagent, K2HgI4 is used to detect ammonia. It is a pale solution that gets darker yellow when some amount of ammonia is added. A brown precipitate may form at a higher concentration. Nessler's reagent can be crystallized from a concentrated solution of mercury iodide with potassium iodide.

So, the correct option is D.

Topic: Chemistry, d and f Block Elements, JEE Main, JEE Main 2023 (01 Feb Shift 2)
Which element possesses biggest atomic radii

Options:
A $P$
B Si
C Al
D $\mathrm{Mg}$

The correct answer is:
$\mathrm{Mg}$

Solution:
as we move across the period nuclear charge increases, hence, size decreases.

Topic: Chemistry, s Block Elements, JEE Main
Which elements of the periodic table does the octet rule mainly apply to?

Options:
A First period elements
B Second period elements
C Third period elements
D Noble gases

The correct answer is:
Second period elements

Solution:
The octet rule mainly applies to the second period elements of the periodic table.

Topic: Chemistry, Chemical Bonding and Molecular Structure, NEET
Which expression is correct for the work done in adiabatic reversible expansion of an ideal gas

Options:
A $W=n R T \ln \frac{V_2}{V_1}$
B $W=n_e \ln \frac{T_2}{T_1}$
C $W=P \Delta V$
D $W=-\int_1^2 P d V$

The correct answer is:
$W=P \Delta V$

Solution:
$W=P \Delta V$

Topic: Chemistry, Thermodynamics (C), JEE Main
Which extraembryonic membrane in humans prevents desiccation of the embryo inside the utrerus?

Options:
A Amnion
B Chorion
C Allantois
D Yolk sac

The correct answer is:
Amnion

Solution:
Amnion encloses amniotic fluid which prevents dessication of embryo, that's why present in all true land vertebrates.

Topic: Biology, Human Reproduction, NEET, NEET 2008 (Mains)
Which form of reproduction is correctly matched?

Options:
A Euglena \(\rightarrow\) transverse binary fission
B Paramecium \(\rightarrow\) longitudinal binary fission
C Amoeba \(\rightarrow\) multiple fission
D Plasmodium \(\rightarrow\) binary fission

The correct answer is:
Amoeba \(\rightarrow\) multiple fission

Solution:
Reproduction is an essential feature of all living organisms. It is the process by which an individual multiplies in number by producing more individuals of its own type. It maintains the continuity of race by replacing old dying members and helps in increasing the total number of individuals. Amoeba proteus does not reproduce sexually. The reproduction is essentially asexually and takes place by various methods such as binary fission, multiple fission and sporulation. Binary fission is the most common mode of reproduction. It results in the division of the parent Amoeba into two daughter amoebea. Amoeba reproduces by multiple fission during adverse environmental conditions. The animals secretes a three-layered protective, chitinous cyst around it and becomes inactive. Inside the cyst, the nucleus repeatedly divides to form several daughter nuclei, which arrange themselves near the periphery. When favourable conditions arrive, the cyst breaks off liberating the young pseudopodiospores, each with fine pseudopodia. They feed and grow rapidly to become adults and lead an independent life.
Form of reproduction present in the following animals are -
Euglena - Longitudinal binary fission
Paramecium - Transverse binary fission
Plasmodium - Multiple fission

Topic: Biology, Reproduction in Organisms, AIIMS, AIIMS 2007
Which formula does not correctly represent the bonding capacity of the central atom involved ?

Options:
A
B
C
D

The correct answer is:

Solution:
Here structure in option D is incorrect as one c-atom has 3-bonds and one has 5-bonds which is not possible.

Topic: Chemistry, Chemical Bonding and Molecular Structure, JEE Main
Which frequencies will be appropriate for communication utilizing sky waves beyond the horizon?

Options:
A $10 \mathrm{kHz}$
B $10 \mathrm{MHz}$
C $1 \mathrm{GHz}$
D $1000 \mathrm{GHz}$

The correct answer is:
$10 \mathrm{MHz}$

Solution:
Beyond the horizon, the signal waves must travel a great distance to communicate. 10 $\mathrm{kHz}$ transmissions cannot be adequately disseminated due to the antenna size. Highenergy signal waves enter the ionosphere ( $1 \mathrm{GHz}-1000 \mathrm{GHz}$ ). The ionosphere readily reflects frequencies up to $10 \mathrm{MHz}$. Therefore, the use of signal waves at such frequencies for communication beyond the horizon is allowed.

Topic: Physics, Communication System, JEE Main
Which from following alloys is used to make statues?

Options:
A Nichrome
B Stainless steel
C Bronze
D Cupra-nickel

The correct answer is:
Bronze

Solution:
Bronze, an alloy of copper and tin, is used for making statues.

Topic: Chemistry, d and f Block Elements, JEE Main
Which from following is a CORRECT decreasing order of ionisation enthalpy for different elements?

Options:
A $\mathrm{Ar}>\mathrm{Ne}>\mathrm{S}>\mathrm{Cl}$
B $\mathrm{Ne}>\mathrm{Ar}>\mathrm{Cl}>\mathrm{S}$
C $\mathrm{Ne}>\mathrm{S}>\mathrm{Cl}>\mathrm{Ar}$
D $\mathrm{Cl}>\mathrm{S}>\mathrm{Ne}>\mathrm{Ar}$

The correct answer is:
$\mathrm{Ne}>\mathrm{Ar}>\mathrm{Cl}>\mathrm{S}$

Solution:
The ionisation enthalpy decreases down the group due to increase in the atomic size.
Therefore, ionisation enthalpy of $\mathrm{Ne}$ is more than that of Ar.
Across a period ionisation enthalpy increases with increase of atomic number.
Therefore, ionisation enthalpy of $\mathrm{S}, \mathrm{Cl}$ and $\mathrm{Ar}$ is in the order: $\mathrm{S} < \mathrm{Cl} < \mathrm{Ar}$.
Hence, the correct decreasing order of ionisation enthalpy for the given elements is:
$\mathrm{Ne}>\mathrm{Ar}>\mathrm{Cl}>\mathrm{S}$

Topic: Chemistry, Classification of Elements and Periodicity in Properties, JEE Main
Which from following statements is true for group 16 elements?

Options:
A All elements of this group form $\mathrm{EO}_2$ type oxides
B It includes all the nonmetals
C Oxides of all elements of this group are gaseous at room temperature
D Reducing properties of dioxides of this group element decreases form $\mathrm{SO}_2$ to $\mathrm{TeO}_2$

The correct answer is:
Reducing properties of dioxides of this group element decreases form $\mathrm{SO}_2$ to $\mathrm{TeO}_2$

Solution:
Besides $\mathrm{EO}_2$ type, Sulphur, Selenium, and tellurium also form $\mathrm{EO}_3$ type oxides.
Group 16 Elements: Oxygen and Sulfur are non-metals, Selenium and Tellurium are metalloids and Polonium is a metal under typical conditions.
All the elements of this group need 2 electrons to attain inert gas configuration either by gaining or sharing of electrons. Oxygen has high E.N so it gains two electrons to become inert gas configuration so all metal oxides are ionic and contains $\mathrm{O}^{2-}$ in which the oxidation state is -2 . Oxygen shows $-1,-1 / 2,+1$ and +2 oxidation state. The tendency to show -2 oxidation state decreases from sulphur to polonium.

Topic: Chemistry, Classification of Elements and Periodicity in Properties, JEE Main
Which gases are responsible for green-house effect? List some of them.

Options:

None

Solution:
\(\mathrm{CO}_2\) is the main gas responsible for green-house effect. Other green-house gases are methane, nitrous oxide, water vapors, chlorofluorocarbons (CFC's) and ozone.

Topic: Chemistry, Environmental Chemistry
Which gives violet coloured bead in borax bead test

Options:
A $\mathrm{Fe}^{2+}$
B $\mathrm{Ni}^{2+}$
C $\mathrm{Co}^{2+}$
D $\mathrm{Mn}^{2+}$

The correct answer is:
$\mathrm{Mn}^{2+}$

Solution:
As $\mathrm{Mn}^{2+}$ has all it's electrons (5) unpaired in it's $d$-orbital, so it's extra stable configuration requires high excitation energy and so it gives violet colour.

Topic: Chemistry, Practical Chemistry, JEE Main
Which graph correctly correlates Ecell as a function of concentrations for the cell (for different values of M and M' .
Zns+Cu2+M→Zn2+M'+Cus;
Ecello=1.10V
X-axis:log10Zn2+Cu2+,Y-axis:Ecell

Options:
A
B
C
D

The correct answer is:

Solution:
According to Nernst equation
Ecell=Ecello+0.05912logCu2+Zn2+
Ecell=Ecello-0.05912logZn2+Cu2+
using y=c+-mx
Thus, slope is negative.

Topic: Chemistry, Electrochemistry, JEE Main
Which graph correctly presents the variation of acceleration due to gravity with the distance from the centre of the earth (radius of the earth $=R_E$ )?

Options:
A

B

C

D

The correct answer is:

Solution:
Acceleration due to gravity, $g \propto r$ (if $r < R_E$ ) and $g \propto \frac{1}{r^2}\left(\right.$ if $\left.r>R_E\right)$

Topic: Physics, Gravitation, JEE Main, JEE Main 2012 (07 May Online)
Which graph corresponds to an object moving with a constant negative acceleration and a positive velocity?

Options:
A

B

C

D

The correct answer is:

Solution:
Let acceleration be a.
Given that a=-C
We know that, a=vdvdx=-C
vdv=-Cdx

Integrating the above equation,
v22=-Cx+k.

Thus, the velocity-distance graph is

The distance cover by the object is x= -v22C+kC.

Thus, with the increase in distance, velocity decreases.

Now, a=-C=dvdt

⇒dv=-Cdt⇒v=-Ct+u , straight line

Topic: Physics, Motion In One Dimension, JEE Main, JEE Main 2017 (08 Apr Online)
Which graph represents the difference between total energy and potential energy of a particle executing SHM vs its distance from mean position?

Options:
A

B

C

D

The correct answer is:

Solution:
In a SHM, mechanical energy is conserved. So, the sum of kinetic energy and potential energy remains constant.

For a SHM,

T.E.-U=K.E

⇒T.E.-U=12mv2=12mω2A2-x2

This is the equation of a downward parabola.

Topic: Physics, Oscillations, JEE Main, JEE Main 2023 (13 Apr Shift 1)
Which graph shows how the energy E of a photon of light is related to its wavelength λ ?

Options:
A
B
C
D

The correct answer is:

Solution:
E=hcλ
E∝1λ
Inverse relation shows that there will be rectangular hyperbola, in the plot of E against λ .

Topic: Chemistry, Structure of Atom, JEE Main
Which group of the periodic table contains only metals

Options:
A IIA
B IB
C IA
D None of these

The correct answer is:
IB

Solution:
Group 2A elements: These are also known as Alkali Earth Metals. The metals contain this group are beryllium (Be), magnesium (Mg), calcium (Ca), strontium (Se), barium (Ba) and radium (Ra).

Topic: Chemistry, Classification of Elements and Periodicity in Properties, JEE Main
Which group of three of the following five statements (a-e) contain all three correct statements regarding beri-beri?

(a) a crippling disease prevalent among the native population of sub-Saharan Africa.

(b) a deficiency disease caused by lack of thiamine (vitamin B1).

(c) a nutritional disorder in infants and young children when the diet is persistently deficient in essential protein.

(d) occurs in those countries where the staple diet is polished rice.

(e) the symptoms are pain from neuritis, paralysis, muscle wasting, progressive oedema, mental deterioration and finally heart failure.

Options:
A b, d and e
B a, b and d
C a, c and e
D b, c and e

The correct answer is:
b, d and e

Solution:
Deficiency of vitamin B1 causes Beri Beri disease. Beri Beri disease was discovered by Eijkman in 1897. Eijkman observed that the disease beri beri occured mainly in people subsisting on a polished rice diet. This disease is rare in the western word because of food habits and food enrichment. Beri beri disease is characterized by loss of apetite and weight and vigour, retarted growth, degeneration of nerves, muscle atrophy, even paralysis, weakened heart beat and failure.

Topic: Biology, Digestion and Absorption, NEET
Which halide will be least reactive in respect to hydrolysis

Options:
A Vinyl chloride
B Allyl chloride
C Ethyl chloride
D $t$-Butyl chloride

The correct answer is:
Vinyl chloride

Solution:
The reason for the non-reactivity of the halogen atom is that the \(\mathrm{C}-\mathrm{Cl}\) bond in vinyl chloride is stronger than one in alkyl chloride, and is therefore less readily broken. This is so because a p orbital on chlorine interacts with the \(p\) orbital on the adjacent carbon atom. The new delocalized orbital permits the movement of the unshared electrons of the \(\mathrm{p}\) orbital of the halogen atom and those of the \(\pi\) orbital of the double bond such that, the \(\mathrm{C}-\mathrm{Cl}\) bond becomes slightly stronger than in alkyl chloride. Also, the delocalization of electrons makes the chlorine atom slightly less negative and the adjacent carbon slightly more negative. This makes the carbon holding the chlorine less prone to nucleophilic attack.
Hence, the halide less reactive towards hydrolysis is vinyl chloride.

Topic: Chemistry, Haloalkanes and Haloarenes, JEE Main
Which halogen has the highest value of negative electron gain enthalpy?

Options:
A Fluorine
B Chlorine
C Bromine
D Iodine

The correct answer is:
Chlorine

Solution:
The added electron goes to the bigger n=3 is i.e., occupies larger region to space and the electron-electron repulsion is much less.
So, Chlorine has the highest value of negative electron gain enthalpy

Topic: Chemistry, Classification of Elements and Periodicity in Properties, JEE Main
Which halogen is known to cause the reaction given below?

Options:
A All halogens
B Only Bromine
C Only Iodine
D Only Chlorine

The correct answer is:
Only Iodine

Solution:
All Cu2+ halides are known except the iodide. In this case, Cu2+ oxidises I– to I2.

2Cu2++4I-→Cu2I2+I2

However, many copper (I) compounds are unstable in aqueous solution and undergo disproportionation.

2Cu+ → Cu2+ + Cu

Topic: Chemistry, d and f Block Elements, JEE Main, JEE Main 2023 (08 Apr Shift 1)
Which halogen shows the maximum oxidation state in forming interhalogen compound?

Options:
A \( \mathrm{F} \)
B \( \mathrm{Br} \)
C \( \mathrm{Cl} \)
D I

The correct answer is:
I

Solution:
When two different halogens react with each other, interhalogen compounds are formed. Generally, they are indicated as AX, AX3, AX5 and AX7.Where A is halogen of larger size and X of smaller size.

All halogens exhibit -1 oxidation state. However, Chlorine, bromine and iodine exhibit exhibit +1, +3, +5 and +7 oxidation states. Fluorine being the most electronegative element, it exhibits -1 oxidation state. The fluorine atom has no d-orbitals in its valence shell and therefore cannot expand its octet.

The higher oxidation states of chlorine, bromine and iodine are possible when they combine with small and more electronegative elements such as fluorine and oxygen. For e.g, in interhalogens, oxides and oxoacids.

As the ratio between radii of A and X increases, the number of atoms per molecule also increases. Thus, iodine fluoride should have maximum number of atoms and formula is IF7. Oxidation number of iodine in IF7 is +7. So, iodine exhibit maximum oxidation state of +7 in forming interhalogen compound.

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), JEE Main
Which has highest $\mathrm{pH}$ ?

Options:
A $\mathrm{CH}_3 \mathrm{COOK}$
B $\mathrm{Na}_2 \mathrm{CO}_3$
C $\mathrm{NH}_4 \mathrm{Cl}$
D $\mathrm{NaNO}_3$

The correct answer is:
$\mathrm{Na}_2 \mathrm{CO}_3$

Solution:
$\mathrm{NaNO}_3$ is salt formed by the combination of a strong acid $\mathrm{HNO}_3$ and a strong base $\mathrm{NaOH}$ and hence it is neutral with a $\mathrm{pH}$.
$\mathrm{CH}_3 \mathrm{COOK}$ is formed by the combination of weak acid $\mathrm{CH}_3 \mathrm{COOH}$ and strong base $\mathrm{KOH}$ and hence $\mathrm{pH}$ will be above 7 .
$\mathrm{NH}_4 \mathrm{Cl}$ is formed by the formation of strong and $\mathrm{HCl}$ and a weak base $\mathrm{NH}_4 \mathrm{OH}$ and hence $\mathrm{pH}$ will be lesser than 7.
$\mathrm{Na}_2 \mathrm{CO}_3$ is a salt formed by the strong base $\mathrm{NaOH}$ and weak acid $\mathrm{H}_2 \mathrm{CO}_3$. Hence, $\mathrm{pH}$ of the salt will be highest.
The pH scale was invented in 1909 by a Danish biochemist Soren Sorensen. It describes how many hydrogen ions (protons) are present in a solution: the higher the pH, the lower the hydrogen ion concentration, and vice versa. But the scale does not have fixed limits, so it is indeed possible to have a pH above 14 or below zero. For example, concentrated hydrochloric acid can have a pH of around -1 , while sodium hydroxide solution can have a pH as high as 15 .

Topic: Chemistry, Ionic Equilibrium, JEE Main
Which has maximum vapour pressure

Options:
A $\mathrm{HI}$
B $\mathrm{HBr}$
C $\mathrm{HCl}$
D $H F$

The correct answer is:
$\mathrm{HCl}$

Solution:
The lower is boiling point more is vapour pressure; boiling point order, $\mathrm{HCl} \lt \mathrm{HBr} \lt \mathrm{HI} \lt \mathrm{HF}$

Topic: Chemistry, Solutions, JEE Main
Which has the maximum number of molecules among the following?

Options:
A $44 \mathrm{gCO}_2$
B $48 \mathrm{gO}_3$
C $8 \mathrm{~g} \mathrm{H}_2$
D $64 \mathrm{gSO}_2$

The correct answer is:
$8 \mathrm{~g} \mathrm{H}_2$

Solution:
$44 \mathrm{gCO}_2=1 \mathrm{~mol} \mathrm{CO} \mathrm{CO}_2=N_A$ molecules of $\mathrm{CO}_2$
$48 \mathrm{~g} \mathrm{O}_3=1 \mathrm{molO}_3=N_A$ molecules of $\mathrm{O}_3$
$8 \mathrm{~g} \mathrm{H}_2=4 \mathrm{~mol} \mathrm{H}_2=4 \times N_A$ molecules of $\mathrm{H}_2$
$64 \mathrm{gSO}_2=1 \mathrm{molSO}_2=N_A$ molecules of SO 2

Topic: Chemistry, Some Basic Concepts of Chemistry, NEET, NEET 2011 (Mains)
Which has the strong bond

Options:
A $F-F$
B $\mathrm{F}-\mathrm{Cl}$
C $\mathrm{F}-\mathrm{Br}$
D $\mathrm{Cl}-\mathrm{B}$

The correct answer is:
$F-F$

Solution:
F-F more strong bond compare to $\mathrm{F}-\mathrm{Cl}, \mathrm{F}-\mathrm{Br}$ and $\mathrm{Cl}-\mathrm{Br}$ bond.

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), JEE Main
Which has trigonal bipyramidal shape ?

Options:
A
$\mathrm{XeOF}_4$

B
$\mathrm{XeO}_3$

C
$\mathrm{XeO}_3 \mathrm{~F}_2$

D
$\mathrm{XeOF}_2$

The correct answer is:
$\mathrm{XeO}_3 \mathrm{~F}_2$

Solution:
$$
\text { The shape of } \mathrm{XeO}_3 \mathrm{~F}_2 \text { is Trigonal bipyramidal. }
$$
(Trigonal bipyramidal Structure)

Topic: Chemistry, p Block Elements (Group 15, 16, 17 & 18), JEE Main, JEE Main 2013 (23 Apr Online)
Which hormone is a potent hyperglycemic hormone?

Options:
A Insulin
B Glucagon
C Parathormone
D Calcitonin

The correct answer is:
Glucagon

Solution:
Glucagon is a peptide hormone, and plays an important role in maintaining the normal blood glucose levels. Glucagon acts mainly on the liver cells (hepatocytes) and stimulates glycogenolysis resulting in an increased blood sugar (hyperglycemia). In addition, this hormone stimulates the process of gluconeogenesis which also contributes to hyperglycemia. Glucagon reduces the cellular glucose uptake and utilisation. Thus, glucagon is a hyperglycemic hormone.

Topic: Biology, Chemical Coordination and Integration, NEET
Which hormone is secreted in a woman if pregnancy has occurred?

Options:
A Estrogen
B Progesterone
C Luteinizing hormone
D Human chorionic gonadotropin

The correct answer is:
Human chorionic gonadotropin

Solution:
If fertilization occurs and the foetus is implanted in the endometrium, the trophoblast cells of the developing placenta secrete a hormone called Human Crionic Gonadtrophic hormone (HCG). This hormone like LH maintains the corpus luteum and secretion of progesterone and estradiol by it. These two hormone check the breakdown of the endometrium of the uterus. The absence of menstrual bleeding is the earliest sign of pregnancy.

Topic: Biology, Human Reproduction, JIPMER, JIPMER 2012
Which hormone maintains progesterone and estrogen secretion by the corpus luteum through the first trimester of pregnancy?

Options:
A LH
B FSH
C hCG
D GnRH

The correct answer is:
hCG

Solution:
After fertilization, the zygote undergoes a series of development and thus forms embryo. This embryo then gets implanted in the uterus at around the eighth day after fertilization and this marks the beginning of pregnancy. It is the blastula that gets implanted. The pregnancy can also be confirmed through blood or urine tests as hormone hCG (Human chorionic gonadotropin) begins to increase in blood and urine. This hormone begins to increase from the 8th day and remains in the blood till the parturition. Human chorionic gonadotrophin is the embryonic hormone that ensures the corpus luteum continues to produce progesterone throughout the first trimester of pregnancy. This hormone initially is released by trophoblast and then by placenta.

Topic: Biology, Human Reproduction, NEET
Which hormone possesses an anti-insulin effect?

Options:
A Cortisol
B Calcitonin
C Oxytocin
D Aldosterone

The correct answer is:
Cortisol

Solution:
Insulin is a hormone produced by beta cells of pancreas. Its main function is to transport glucose to the cells. Thus it decreases the blood glucose levels.. Glucagon is a hormone secreted by alpha cells of pancreas. Its function is opposite to that of insulin. Glucagon converts the glycogen into glucose and thus increases the blood glucose levels. Growth hormone and cortisol also have functions similar to glucagon i.e. opposite to that of insulin. Under stressful conditions, cortisol hormone secreted from the Adrenal cortex breaks down glucose from non carbohydrate sources. This is known as gluconeogenesis. This is important as body has increased demands to use glucose.

Topic: Biology, Chemical Coordination and Integration, NEET
Which hormone promotes internode / petiole elongation in deep water rice?

Options:
A 2,4-D
B GA3
C Kinetin
D Ethylene

The correct answer is:
Ethylene

Solution:
Ethylene (C2H4) is a gaseous hormone which is mainly involved in the fruit ripening process. The major physiological effects of ethylene are:

Ethylene promotes rapid internode/petiole elongation in deep water rice plants.

Ethylene also promotes root growth and root hair formation, thus helping the plants to increase their absorption surface.

Ethylene breaks seed and bud dormancy, initiates germination in peanut seeds, sprouting of potato tubers.

Topic: Biology, Plant - Growth and Development, NEET, NEET 2023 (All India)