Language: C++

#include <bits/stdc++.h>
#define rep(i, n) for(int i = 0; i < n; i++)
#define repr(i, n) for(int i = n; i >= 0; i--)
#define for(i, m, n) for(int i = m; i < n; i++)
#define inf 1e9
#define all(v) v.begin(), v.end()
using namespace std;
typedef long long ll;

const int mod = 1000000007;
struct mint {
    ll x; // typedef long long ll;
    mint(ll x=0):x((x%mod+mod)%mod){}
    mint& operator+=(const mint a) {
        if ((x += a.x) >= mod) x -= mod;
        return *this;
    }
    mint& operator-=(const mint a) {
        if ((x += mod-a.x) >= mod) x -= mod;
        return *this;
    }
    mint& operator*=(const mint a) {
        (x *= a.x) %= mod;
        return *this;
    }
    mint operator+(const mint a) const {
        mint res(*this);
        return res+=a;
    }
    mint operator-(const mint a) const {
        mint res(*this);
        return res-=a;
    }
    mint operator*(const mint a) const {
        mint res(*this);
        return res*=a;
    }
    mint pow(ll t) const {
        if (!t) return 1;
        mint a = pow(t>>1);
        a *= a;
        if (t&1) a *= *this;
        return a;
    }
    
    // for prime mod
    mint inv() const {
        return pow(mod-2);
    }
    mint& operator/=(const mint a) {
        return (*this) *= a.inv();
    }
    mint operator/(const mint a) const {
        mint res(*this);
        return res/=a;
    }
};

mint dp[61][2][2][2];

int main(){
  ll l, r;
  cin >> l >> r;
  dp[60][0][0][0] = 1;
  repr(i, 59) {
    int lb = l >> i&1;
    int rb = r >> i&1;
    rep(j, 2)rep(k, 2)rep(s, 2) {
      mint pre = dp[i+1][j][k][s];
      rep(x, 2)rep(y, 2) { 
        if (x && !y) continue;
        int nj = j, nk = k, ns = s;
        if (!s && x != y) continue;
        if (x && y) ns = 1;
        if (!j && !x && lb) continue;
        if (x && !lb) nj = 1;
        if (!k && y && rb) continue;
        if (!y && rb) nk = 1;
        dp[i][nj][nk][[ns] += pre;
      }
    }
  }
  mint ans;
  rep(j,2)rep(k,2)rep(s,2) ans += dp[0][j][k][s];
  cout << ans.x << endl;
  return 0;
}

Compiler output:
a.cc:65:13: error: macro "for" requires 3 arguments, but only 1 given
   65 |   repr(i, 59) {
      |             ^
a.cc:4:9: note: macro "for" defined here
    4 | #define for(i, m, n) for(int i = m; i < n; i++)
      |         ^~~
a.cc:68:13: error: macro "for" requires 3 arguments, but only 1 given
   68 |     rep(j, 2)rep(k, 2)rep(s, 2) {
      |             ^
a.cc:4:9: note: macro "for" defined here
    4 | #define for(i, m, n) for(int i = m; i < n; i++)
      |         ^~~
a.cc:68:22: error: macro "for" requires 3 arguments, but only 1 given
   68 |     rep(j, 2)rep(k, 2)rep(s, 2) {
      |                      ^
a.cc:4:9: note: macro "for" defined here
    4 | #define for(i, m, n) for(int i = m; i < n; i++)
      |         ^~~
a.cc:68:31: error: macro "for" requires 3 arguments, but only 1 given
   68 |     rep(j, 2)rep(k, 2)rep(s, 2) {
      |                               ^
a.cc:4:9: note: macro "for" defined here
    4 | #define for(i, m, n) for(int i = m; i < n; i++)
      |         ^~~
a.cc:70:15: error: macro "for" requires 3 arguments, but only 1 given
   70 |       rep(x, 2)rep(y, 2) {
      |               ^
a.cc:4:9: note: macro "for" defined here
    4 | #define for(i, m, n) for(int i = m; i < n; i++)
      |         ^~~
a.cc:70:24: error: macro "for" requires 3 arguments, but only 1 given
   70 |       rep(x, 2)rep(y, 2) {
      |                        ^
a.cc:4:9: note: macro "for" defined here
    4 | #define for(i, m, n) for(int i = m; i < n; i++)
      |         ^~~
a.cc:84:10: error: macro "for" requires 3 arguments, but only 1 given
   84 |   rep(j,2)rep(k,2)rep(s,2) ans += dp[0][j][k][s];
      |          ^
a.cc:4:9: note: macro "for" defined here
    4 | #define for(i, m, n) for(int i = m; i < n; i++)
      |         ^~~
a.cc:84:18: error: macro "for" requires 3 arguments, but only 1 given
   84 |   rep(j,2)rep(k,2)rep(s,2) ans += dp[0][j][k][s];
      |                  ^
a.cc:4:9: note: macro "for" defined here
    4 | #define for(i, m, n) for(int i = m; i < n; i++)
      |         ^~~
a.cc:84:26: error: macro "for" requires 3 arguments, but only 1 given
   84 |   rep(j,2)rep(k,2)rep(s,2) ans += dp[0][j][k][s];
      |                          ^
a.cc:4:9: note: macro "for" defined here
    4 | #define for(i, m, n) for(int i = m; i < n; i++)
      |         ^~~
a.cc: In function 'int main()':
a.cc:65:15: error: expected '(' before '{' token
   65 |   repr(i, 59) {
      |               ^
      |               (
a.cc:65:15: error: expected primary-expression before '{' token
a.cc:83:11: error: expected initializer before ';' token
   83 |   mint ans;
      |           ^
a.cc:83:11: error: could not convert 'ans' from 'mint' to 'bool'
   83 |   mint ans;
      |           ^
      |           |
      |           mint
a.cc:2:19: error: expected primary-expression before 'for'
    2 | #define rep(i, n) for(int i = 0; i < n; i++)
      |                   ^~~
a.cc:84:3: note: in expansion of macro 'rep'
   84 |   rep(j,2)rep(k,2)rep(s,2) ans += dp[0][j][k][s];
      |   ^~~
a.cc:83:12: error: expected ')' before 'for'
   83 |   mint ans;
      |            ^
      |            )
a.cc:65:15: note: to match this '('
   65 |   repr(i, 59) {
      |               ^
a.cc:2:19: error: expected '(' before 'for'
    2 | #define rep(i, n) for(int i = 0; i < n; i++)
      |                   ^~~
a.cc:84:11: note: in expansion of macro 'rep'
   84 |   rep(j,2)rep(k,2)rep(s,2) ans += dp[0][j][k][s];
      |           ^~~
a.cc:2:19: error: expected primary-expression before 'for'
    2 | #define rep(i, n) for(int i = 0; i < n; i++)
      |                   ^~~
a.cc:84:11: note: in expansion of macro 'rep'
   84 |   rep(j,2)rep(k,2)rep(s,2) ans += dp[0][j][k][s];
      |           ^~~
a.cc:86:3: error: expected primary-expression before 'return'
   86 |   return 0;
      |   ^~~~~~
a.cc:85:25: error: expected ')' before 'return'
   85 |   cout << ans.x << endl;
      |                         ^
      |                         )
   86 |   return 0;
      |   ~~~~~~                 
a.cc:2:19: note: to match this '('
    2 | #define rep(i, n) for(int i = 0; i < n; i++)
      |                   ^~~
a.cc:84:11: note: in expansion of macro 'rep'
   84 |   rep(j,2)rep(k,2)rep(s,2) ans += dp[0][j][k][s];
      |           ^~~