Language: C++

 #include <iostream>
#include <cstdio>
#include <algorithm>
#include <cmath>
#include <vector>
#include <list>
#include <set>
#include <map>
#include <queue>
#include <stack>
#include <cctype>
#include <cassert>
#include <climits>
#include <string>
#include <bitset>
#include <cfloat>
#include <unordered_set>
#include <iomanip>
using namespace std;
typedef long double ld;
typedef long long int ll;
typedef unsigned long long int ull;
typedef pair<int,int> pii;
typedef vector<int> vi;
typedef vector<char> vc;
typedef vector<bool> vb;
typedef vector<double> vd;
typedef vector<string> vs;
typedef vector<ll> vll;
typedef vector<pair<int,int> > vpii;
typedef vector<vector<int> > vvi;
typedef vector<vector<char> > vvc;
typedef vector<vector<string> > vvs;
typedef vector<vector<ll> > vvll;
#define rep(i,n) for(int i = 0; i < (n); ++i)
#define rrep(i,n) for(int i = 1; i <= (n); ++i)
#define irep(it, stl) for(auto it = stl.begin(); it != stl.end(); it++)
#define drep(i,n) for(int i = (n) - 1; i >= 0; --i)
#define fin(ans) cout << (ans) << endl
#define mp(p,q) make_pair(p, q)
#define pb(n) push_back(n)
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()
#define Sort(a) sort(a.begin(), a.end())
#define Rort(a) sort(a.rbegin(), a.rend())
#define MATHPI acos(-1)
int dx8[8] = {1, 0, -1, 0, 1, -1, -1, 1};
int dy8[8] = {0, 1, 0, -1, 1, 1, -1, -1};
int dx4[4] = {1, 0, -1, 0};
int dy4[4] = {0, 1, 0, -1};
template <class T> inline bool chmax(T& a,T b){if(a<b){a=b;return 1;} return 0;}
template <class T> inline bool chmin(T& a,T b){if(a>b){a=b;return 1;} return 0;}
template<typename A, size_t N, typename T> void Fill(A (&array)[N], const T &val){ fill((T*)array, (T*)(array+N), val); }
struct io{io(){ios::sync_with_stdio(false);cin.tie(0);}};
const int INF = INT_MAX;
const ll LLINF = 1LL<<60;
const ll MOD = 1000000007;
const double EPS = 1e-9;
template < typename T > inline string toString( const T &a ) { ostringstream oss; oss << a; return oss.str(); };

struct mint {
    ll x;
    mint(ll x=0):x((x%MOD+MOD)%MOD){}
    mint operator-() const { return mint(-x);}
    mint& operator+=(const mint a) {
        if ((x += a.x) >= MOD) x -= MOD;
        return *this;
    }
    mint& operator-=(const mint a) {
        if ((x += MOD-a.x) >= MOD) x -= MOD;
        return *this;
    }
    mint& operator*=(const mint a) { (x *= a.x) %= MOD; return *this;}
    mint operator+(const mint a) const { return mint(*this) += a;}
    mint operator-(const mint a) const { return mint(*this) -= a;}
    mint operator*(const mint a) const { return mint(*this) *= a;}
    mint pow(ll t) const {
        if (!t) return 1;
        mint a = pow(t>>1);
        a *= a;
        if (t&1) a *= *this;
            return a;
    }
    mint inv() const { return pow(MOD-2);}
    mint& operator/=(const mint a) { return *this *= a.inv();}
    mint operator/(const mint a) const { return mint(*this) /= a;}
    };
    istream& operator>>(istream& is, const mint& a) { return is >> a.x;}
    ostream& operator<<(ostream& os, const mint& a) { return os << a.x;}
string K; int D, N;
mint dp[10101][101][2];
//---------------------------------------------------------------------------------------------------
void _main() {
    cin >> K >> D;
    int N = K.length();
 
    dp[0][0][0] = 1;
    rep(dgt, 0, N) rep(d, 0, D) rep(isless, 0, 2) {
        int c = K[dgt] - '0';
        rep(nxt, 0, 10) {
            if (nxt < c) dp[dgt + 1][(d + nxt) % D][1] += dp[dgt][d][isless];
            else if(nxt == c) dp[dgt + 1][(d + nxt) % D][isless] += dp[dgt][d][isless];
            else {
                if(isless) dp[dgt + 1][(d + nxt) % D][isless] += dp[dgt][d][isless];
            }
        }
    }
 
    cout << dp[N][0][0] + dp[N][0][1] - 1 << endl;
}



Compiler output:
a.cc:98:18: error: macro "rep" passed 3 arguments, but takes just 2
   98 |     rep(dgt, 0, N) rep(d, 0, D) rep(isless, 0, 2) {
      |                  ^
a.cc:35:9: note: macro "rep" defined here
   35 | #define rep(i,n) for(int i = 0; i < (n); ++i)
      |         ^~~
a.cc:98:31: error: macro "rep" passed 3 arguments, but takes just 2
   98 |     rep(dgt, 0, N) rep(d, 0, D) rep(isless, 0, 2) {
      |                               ^
a.cc:35:9: note: macro "rep" defined here
   35 | #define rep(i,n) for(int i = 0; i < (n); ++i)
      |         ^~~
a.cc:98:49: error: macro "rep" passed 3 arguments, but takes just 2
   98 |     rep(dgt, 0, N) rep(d, 0, D) rep(isless, 0, 2) {
      |                                                 ^
a.cc:35:9: note: macro "rep" defined here
   35 | #define rep(i,n) for(int i = 0; i < (n); ++i)
      |         ^~~
a.cc:100:23: error: macro "rep" passed 3 arguments, but takes just 2
  100 |         rep(nxt, 0, 10) {
      |                       ^
a.cc:35:9: note: macro "rep" defined here
   35 | #define rep(i,n) for(int i = 0; i < (n); ++i)
      |         ^~~
a.cc: In function 'void _main()':
a.cc:98:5: error: 'rep' was not declared in this scope
   98 |     rep(dgt, 0, N) rep(d, 0, D) rep(isless, 0, 2) {
      |     ^~~