When the object reaches its peak position the velocity vanishes. As before, from eq. Of course not. Now the object starts at a distance h from the origin at a position located along the direction of increasing y. But they describe the same motion and produce the same values for the object's position and velocity at any given time.
Some patterns immediately jump out.
The other functions come in pairs in which A and B on one hand and C and D on the other differ only in the signs of various terms. Since the sign of the acceleration is unchanged, velocity and acceleration have the same sign during the trip down. Indeed, the object is speeding up. The trip down is an image reflection of the trip up. This is discussed in detail in another note .