The 13 C NMR shows a carbonyl at 208, which could be a ketone or an aldehyde but not a carboxylic acid or ester. The IR agrees with the carbonyl assignment. This eliminates the first possible formula. The absence of any signal above 5 ppm eliminates the aldehydes, and symmetry from the 13 C NMR forces us to choose 3-pentanone. 8. Describe one mechanistic role an enzyme might play in the hydrolysis of peptide bonds.
Peptide bonds are amide links.
2-methoxypropene with acid catalysis gives an acetal that has a furanose structure. Show the general mechanism for how a furanose is made from a pyranose.