To determine the fluid phase we go to the saturation pressure table, Table A-5, and find the boiling temperature at 6 MPa to be 275.64C which is less than 600C, so that we have superheated vapor. We can then go to the superheat vapor table, Table A-6, and read the remaining properties for at 6 MPa and 600C. At state 2 we know the pressure, but we also that we have an isenthalpic process, so that So with the pressure and enthalpy known at State 2, it is fixed. Next, we must determine the phase. We again go to Table A-5 and find that at 10 kPa Since we must have a superheated vapor. We go to the superheat vapor table, Table A-6, and find that at 10 kPa and h of 3658, we interpolate to obtain Our changes are then given by 5.
Italicized versions read from air tables or calculated from ideal gas equation.
Bold numbers are calculated For state 1we know T and P, so the state is fixed. At state 2, we know the temperature and that the process was isobaric, then which fixes our state. Table A-17 Our changes are then given as 6. Water at 10 psia and 190F goes isentropically to 100 psia. So we have a subcooled liquid.