Since you have a gaseous reactant reacting to make a solid product, you would expect D S for this reaction to be negative. Since there are 4 moles of gaseous reactants reacting to make 2 moles of gaseous products you would expect D S to be negative. Since a highly ordered solid is being broken up into a disordered aqueous phase you would expect D S to be positive. Since a solid phase is melting into a liquid phase you would expect D S to be positive. 2 O at 0 K because of the higher temperature.
Liquids are more disordered than solids.
You would predict that D S is negative because a gaseous reactant is producing products in the aqueous phase. Since the equilibrium constant is a smaller number at the higher temperature, there is no thermodynamic reason for the high temperature.