Print consecutive characters together in a line

07 Jul, 2022
Given a sequence of characters, print consecutive sequence of characters in a line, otherwise print it in a new line.
Examples: 
Input  : ABCXYZACCD
Output : ABC
         XYZ
         A
         C
         CD

Input : ABCZYXACCD
Output: ABC
        ZYX
        A
        C
        CD
The idea is to traverse string from left to right. For every traversed character, print it in a line if it is consecutive to previous one, else print a new line character. 
Implementation:
C++
Java
Python3
C#
Javascript
// C++ program to print consecutive characters// together in a line.#include <iostream>using namespace std; void print(string str){    cout << str[0];    for (int i=1; str[i]!='\0'; i++)    {        if ((str[i] == str[i-1]+1) ||            (str[i] == str[i-1]-1))            cout << str[i];        else            cout << "\n" << str[i];;    }} // Driver codeint main(){    string str = "ABCXYZACCD";    print(str);    return 0;}
// Java program to print consecutive characters// together in a line.class GFG {     static void print(String str1) {        char str[] = str1.toCharArray();        System.out.print(str[0]);        for (int i = 1; i < str.length; i++) {            if ((str[i] == str[i - 1] + 1)                    || (str[i] == str[i - 1] - 1)) {                System.out.print(str[i]);            } else {                System.out.print("\n" + str[i]);            }        }    } // Driver code    public static void main(String[] args) {        String str = "ABCXYZACCD";        print(str);    }} // This code is contributed by 29AjayKumar
# Python3 program to print consecutive characters# together in a line.def _print(string):    print(string[0], end = "")     for i in range(1, len(string)):        if (ord(string[i]) == ord(string[i - 1]) + 1 or            ord(string[i]) == ord(string[i - 1]) - 1):            print(string[i], end = "")        else:            print()            print(string[i], end = "") # Driver Codeif __name__ == "__main__":     string = "ABCXYZACCD"    _print(string) # This code is contributed by# sanjeev2552
// C# program to print consecutive characters// together in a line.using System; class GFG{     static void print(String str1)    {        char []str = str1.ToCharArray();        Console.Write(str[0]);        for (int i = 1; i < str.Length; i++)        {            if ((str[i] == str[i - 1] + 1)                    || (str[i] == str[i - 1] - 1))            {                Console.Write(str[i]);            }            else            {                Console.Write("\n" + str[i]);            }        }    }     // Driver code    public static void Main()    {        String str = "ABCXYZACCD";        print(str);    }} // This code is contributed by PrinciRaj1992
<script> // Javascript program to print consecutive// characters together in a line.function print(str1){    let str = str1.split("");    document.write(str[0]);         for(let i = 1; i < str.length; i++)    {        if ((str[i].charCodeAt(0) ==         str[i - 1].charCodeAt(0) + 1) ||            (str[i].charCodeAt(0) ==         str[i - 1].charCodeAt(0) - 1))        {            document.write(str[i]);        }        else        {            document.write("<br>" + str[i]);        }    }} // Driver codelet str = "ABCXYZACCD";print(str); // This code is contributed by rag2127 </script>
ABC
XYZ
A
C
CD
Time Complexity : O(n) 
This article is contributed by Rakesh Kumar. If you like GeeksforGeeks and would like to contribute, you can also write an article using write.geeksforgeeks.org or mail your article to review-team@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks. 
29AjayKumar
princiraj1992
VishalBachchas
sanjeev2552
rag2127
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