Simplification - Solved Examples

Q 1 - 2- [3- {6-(5-4-3)}] = ?
A - 0
B - 1
C - 2
D - 3
Answer - B
Explanation
Given exp.  =2- [3-{6-(5-4+3)}]    [ Removing viranaculam]
= 2 - [3-{6-(5-4+3)}]              [ Removing  ( )]
= 2-[ 3- {6-4}]                    [ Removing {}]
= 2-[3-2] 	                       [ Removing [ ]]
=2-1  = 1

Q 2 - (4.8 *1.8 / 3.6 +5.4  of 1/9 -1/5 ) = ?
A - 2.8
B - 3.8
C - 4.8
D - 5.8
Answer - A
Explanation
Given exp .   = 4.8 *1.8  / 3.6+ 0.6-1/5 (Removing of () )
=  4.8 * 1.8 * 1/ 3.6+ 0.6 -1/5   ( Removing /)
= 2.4 +0.6- 0.2    (Removing *)  
= 3- 0.2 = 2.8

Q 3 - ((598+ 479)2  - (598- 479)2)/(598 * 479) = ? 
A - 4
B - 5
C - 6
D - 7
Answer - A
Explanation
Given exp. (a+b)2 -(a-b)2/ab ,  where a  = 598 , b = 479
= 4ab / ab = 4

Q 4 - ((736+ 278)2 +( 736- 278)2)/(736 *736 + 278 *278) = ?
A - 1
B - 2
C - 3
D - 4
Answer - B
Explanation
Given exp.  =  (a+b)2 +(a-b)2,  Where  a= 736, b= 278
(a2 +b2)
= 2(a2+b2)/(a2+b2) = 2

Q 5 - (47*47*47+35*35*35+ 26*26*26 -47*35*78)/(47*47+35*35+26*26- 47*35- 35*26-47*26) = ?
A - 92
B - 100
C - 108
D - 116
Answer - C
Explanation
Given Exp. a3+b3+c3-3abc, where a =47 , b= 35, c= 26
a2+ b2+c2- ab-bc -ca  	
=(a+b+c) =(47+35+26)= 108

Q 6 - [(a-b)3 +(b-c)3 +(c-a)3]/[6(a-b) (b-C) (c-a)] = ?
A - 1/2
B - 1/3
C - 1/4
D - 1/5
Answer - A
Explanation
Putting (a-b) =x, (b-c) =y  and (c-a) = z ,then we find x+y+z = 0
∴ x3 +y3 + z3 = 3xyz
∴ x3 +y3+ z3 / 6xyz 
= 3xyz/6xyz  = 1/2

Q 7 - If  a+b+c =  13 ,a2 +b2+c2 = 69,) then (ab+bc+ca) = ?
A - 20
B - 30
C - 40
D - 50
Answer - D
Explanation
We have  (a+b+c)2 = (a2+b2+c2)+ 2(ab+bc+ca)
⇒ (13)2 = 69+ 2(ab+bc+ca )
⇒  2(ab+bc+ca) = (169-69) = 100 ⇒ (ab+bc+ca) = 50

Q 8 - We have a/b = 2/3,  then what would be the value the  3a+5b/ 3a-5b =?
A - 1/3
B - 2/3
C - 4/3
D - -4/3
Answer - D
Explanation
Given exp.   3a+5b/ 3a-5b  = 3(a/b)+5 /3(a/b)-5   
= (3*2/3+2)/  ( 3 *2/3-5) =   2+2/2-5 = 4/-3  = -4/3 

Q 9 - What should be the value of  a,b,c  if the we have   positive integers of a, b and c such that  the value  of a2+b2 =45 and b2+c2 = 40.
A - 1,2,3
B - 3,6,2
C - 2,6,4
D - 1,6,2
Answer - B
Explanation
a2+b2 = 45 and b2+c2 =40
On subtracting ,we get  a2-c2  =5   ⇒ (a+c) (a-c) = 5 
⇒  a+c= 5 and a-c = 1     ⇒  a = 3, c = 2 
9+ b2 = 45  ⇒ b2 = 36 ⇒ b =6 
∴ a=3, b= 6  and c = 2

Q 10 - (1-1/3) (1-1/4) (1-1/5)...(1-1/99)(1-1/100) = ?
A - 1/40 
B - 1/50 
C - 1/60 
D - 1/70 
Answer - B
Explanation
Given exp.  2/3 *3/4 *4/5 * ...* 98/99 * 99/100= 2/100 = 1/50

Q 11 - ( 1- 1/2 )( 1- 1/3 ) ( 1-1/4) ...(1-1/n-1)(1-1/n) = ?
A - 1/n 
B - 1/2n 
C - 1/3n 
D - 1/4n 
Answer - A
Explanation
Given exp.= (1-1/2 ) (1-1/3)(1- 1/2)...(n-2)/ (n-1) * (n-1)/n = 1/n

Q 12 - 1/5 + 999* 494/495 *99= ?
A - 999000
B - 99000 
C - 9000
D - 900
Answer - A
Explanation
Given exp.  = 1/5 + (999 + 494/495) * 99
=  1/5 + 999* 99 + 494/495 *99 
= 1/5 +(1000-1) * 99 + 494/5
=  999000 -99+  495/5 = 99000-99 +99 = 999000.

Q 13 - If x + 1/  {1+  1/ (3+ 1/4) = 2 , then x = ?  
A - 1/17
B - 21/17 
C - 20/17 
D - 19/17 
Answer - B
Explanation
x + 1/{ 1+ 1/(3+1/4 )} = 2 ⇒  x+ 1/ { 1+ 1/ (13/4) }=2 ⇒ x+ 1/ (1+ 4/13) = 2
= x + 1/( 17/13) = 2 ⇒  x+ 17/13 = 2 ⇒ x= (2-13/17) 
= x =  34-13/ 17 = 21/17

Q 14 - 1 / (1 + (2/3)/(1+ 2/3 + (8/9)/(1- 2/3)))
A - 13/15
B - 12/15
C - 11/15
D - 7/15
Answer - A
Explanation
1 / (1 + (2/3)/(1+ 2/3 + (8/9)/(1- 2/3)))
= 1 / (1 + (2/3)/(1+ 2/3 + (8/9)/(1/3)))
= 1 / (1 + (2/3)/(1+ 2/3 + (8/9)/3/1))
= 1 / (1 + (2/3)/(1+ 2/3 + 8/3))
= 1 / (1 + (2/3)/(13/3))
= 1 / (1 + 2/3 * 3/13)
= 1 / (1 + 2/13)
= 1 / (15/13) 
= 13/15

Q 15 - Find the value  of 3/7  of the estate if the value of 4/5 of this estate is 16800.
A - Rs. 9000 
B - Rs. 10000
C - Rs. 8000
D - Rs. 7000
Answer - A
Explanation
If  we assume x  Rs. is the  estate  value.  Then, 
4/5 *x = 16800  ⇒  x= (16800* 5/4)  = 21000
∴ 3/7 of the estate = Rs. (3/7 *21000) = Rs. 9000.

Q 16 - What is the number if 3/7 of 2/5 of a number is  198.
A - 1255 
B - 1155
C - 1055
D - 955
Answer - B
Explanation
If the number  be x then, 
3/7 of 2/5 of x =  198 
⇒ 6x/35 = 198  
⇒ x = (198* 35/6 )  = (33*35) = 1155. 

Q 17 - Divide the amount 312 in such a way that 100 boys gets Rs. 3.60 each and each girl gets Rs. 2.40. How many girls are there?
A - 40 
B - 30 
C - 25 
D - 20 
Answer - A
Explanation
If x is the quantity of girls  then,  the quantity of boys = (100-x)
∴ 2.40 *x + 3.60 *(100-x) = 312 
⇒  240/100 *x +  {360*(100-x)/100} = 312
⇒  240x + 36000 - 360 x = 31200
⇒ 120x = (36000- 31200 ) = 4800  ⇒ x = 4800/120 = 40
⇒  quantity of girls = 40.

Q 18 - A boy wants to multiply a number by 25  but by mistake  he multiplied it by 52 and he got the result which was 324 more in the comparisons of correct answer. Find the number?
A - 12  
B - 13 
C - 14 
D - 15 
Answer - A
Explanation
Let the number be x. then ,
52x-25x = 324 ⇒ 27x = 324 ⇒ x = 12 
∴  Required number = 12

Q 19 - A cab start from his center with full  capacity. Cab stops on stoppage  A where 1/3  of the passanger shift down the cab and new 30  passenger entered in cab, in the next attempt  cab stop on C Stoppage  where 1/4 of the passengers shift down the cab and 12 new passenger entered in the cab and  last stoppage which was C all the 84 passengers shifted down. Find  how much passengers can board at a time?
A - 98 
B - 99 
C - 100 
D - 101  
Answer - B
Explanation
If  x passenger can board / sit  in a cab  at  the same time.
Number of passanger  between  the  stations from A to B = (x-x/3 +30) = (2x/3+ 30)
Number of passanger  between  the  stations from B to C = (2x/3+30)- 1/4 (2x/3+30)+12
=  3/4 (2x/30)+12 =  x/2 +45/2+12 
∴ x/2+ 45/2+12= 84 ⇒ x+ 45+24 = 168 ⇒  x = (168-69)= 99
So,  we  can say 99 passengers can board at a time.

Q 20 - Total cost of a TV and VCR  is Rs. 35000 . If the cost of tv is 3/2 times more in the comparisons of VCR. In that case what should be the value of VCR?
A - 14000 Rs  
B - 15000 Rs
C - 16000 Rs 
D - 17000 Rs 
Answer - A
Explanation
If x is the value of  VCR then,  the cost  of the  TV is  = 3x/2 
x+ 3x/2 = 35000 ⇒  5x = 70000 ⇒ x = 14000


    87 Lectures 
     22.5 hours 

 Programming Line
 Print
 Add Notes
 Bookmark this page