C# | Random.Next() Method - GeeksforGeeks

30 Apr, 2019
The Next() Method of System.Random class in C# is used to get a random integer number. This method can be overloaded by passing different parameters to it as follows:
Next()
Next(Int32)
Next(Int32, Int32)
This method is used to returns a non-negative random integer.
Syntax:
public virtual int Next ();
Return Value: This method returns the 32-bit signed integer which is greater than or equal to 0 and less than MaxValue.
Example:
// C# program to illustrate the // Random.Next() Methodusing System;  class GFG {      // Driver code    public static void Main()    {        // Instantiate random number generator        Random rand = new Random();          // Print 10 random numbers        Console.WriteLine("Printing 10 random numbers");        for (int i = 1; i <= 10; i++)            Console.WriteLine("{0} -> {1}", i, rand.Next());    }}
Printing 10 random numbers
1 -> 1386420123
2 -> 2133003862
3 -> 981665925
4 -> 495382685
5 -> 1127976381
6 -> 824414652
7 -> 213006792
8 -> 1948108820
9 -> 214839986
10 -> 261560448

This method is used to get a non-negative random integer which is less than the specified maximum.
Syntax:
public virtual int Next (int maxValue);
Here, maxValue is the upper boundary of the random number to be generated. It must be greater than or equal to 0.
Return Value: The function returns a 32-bit signed integer which is greater than or equal to 0, and less than maxValue. However, if maxValue equals 0, maxValue is returned.
Exception: This method will give ArgumentOutOfRangeException if the maxValue is less than 0.
Example:
// C# program to illustrate the// Random.Next(Int32) Methodusing System;  class GFG {      // Driver code    public static void Main()    {        // Instantiate random number generator        Random rand = new Random();          // Print 10 random numbers less than 100        Console.WriteLine("Printing 10 random numbers less than 100");        for (int i = 1; i <= 10; i++)            Console.WriteLine("{0} -> {1}", i, rand.Next(100));    }}
Printing 10 random numbers less than 100
1 -> 19
2 -> 94
3 -> 14
4 -> 54
5 -> 94
6 -> 73
7 -> 39
8 -> 42
9 -> 18
10 -> 77

This method is used to get the random integer that is within a specified range.
Syntax:
public virtual int Next (int minValue, int maxValue);
Parameters:
maxValue: It is the exclusive upper boundary of the random number generated. It must be greater than or equal to minValue.
minValue: It is the inclusive lower bound of the random number returned.
Return Value: The function returns a 32-bit signed integer greater than or equal to minValue and less than maxValue; that is, the range of return values includes minValue but not maxValue. If minValue equals maxValue, minValue is returned.
Exception: This method will give the ArgumentOutOfRangeException if the minValue is greater than maxValue.
Example:
// C# program to illustrate the// Next(Int32, Int32) Methodusing System;  class GFG {      // Driver code    public static void Main()    {        // Instantiate random number generator        Random rand = new Random();          // Print 10 random numbers between 50 and 100        Console.WriteLine("Printing 10 random numbers"+                                " between 50 and 100");        for (int i = 1; i <= 10; i++)            Console.WriteLine("{0} -> {1}", i, rand.Next(50, 100));    }}
Printing 10 random numbers between 50 and 100
1 -> 91
2 -> 85
3 -> 93
4 -> 74
5 -> 88
6 -> 77
7 -> 92
8 -> 76
9 -> 77
10 -> 52

Reference:
https://docs.microsoft.com/en-us/dotnet/api/system.random.next?view=netframework-4.7.2
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