Find the Number which contain the digit d

25 May, 2022
Given two integer number n and d. The task is to find the number between 0 to n which contain the specific digit d.
Examples: 
Input : n = 20
        d = 5
Output : 5 15

Input : n = 50
        d = 2
Output : 2 12 20 21 22 23 24 25 26 27 28 29 32 42 
Approach 1: Take a loop from 0 to n and check each number one by one, if the number contains digit d then print it otherwise increase the number. Continue this process until loop ended.
C++
Java
Python3
C#
PHP
Javascript
// C++ program to print the number which// contain the digit d from 0 to n#include <bits/stdc++.h>using namespace std; // Returns true if d is present as digit// in number x.bool isDigitPresent(int x, int d){    // Break loop if d is present as digit    while (x > 0)    {        if (x % 10 == d)            break;         x = x / 10;    }     // If loop broke    return (x > 0);} // function to display the valuesvoid printNumbers(int n, int d){    // Check all numbers one by one    for (int i = 0; i <= n; i++)         // checking for digit        if (i == d || isDigitPresent(i, d))            cout << i << " ";} // Driver codeint main(){    int n = 47, d = 7;    printNumbers(n, d);    return 0;}
// Java program to print the number which// contain the digit d from 0 to n class GFG{    // Returns true if d is present as digit    // in number x.    static boolean isDigitPresent(int x, int d)    {        // Break loop if d is present as digit        while (x > 0)        {            if (x % 10 == d)                break;             x = x / 10;        }         // If loop broke        return (x > 0);    }     // function to display the values    static void printNumbers(int n, int d)    {        // Check all numbers one by one        for (int i = 0; i <= n; i++)             // checking for digit            if (i == d || isDigitPresent(i, d))                System.out.print(i + " ");    }      // Driver code    public static void main(String[] args)    {        int n = 47, d = 7;        printNumbers(n, d);    }}
# Python3 program to print the number which# contain the digit d from 0 to n # Returns true if d is present as digit# in number x.def isDigitPresent(x, d):     # Break loop if d is present as digit    while (x > 0):             if (x % 10 == d):            break         x = x / 10          # If loop broke    return (x > 0)  # function to display the valuesdef printNumbers(n, d):     # Check all numbers one by one    for i in range(0, n+1):         # checking for digit        if (i == d or isDigitPresent(i, d)):            print(i,end=" ") # Driver coden = 47d = 7print("The number of values are")printNumbers(n, d)#This code is contributed by#Smitha Dinesh Semwal
// C# program to print the number which// contain the digit d from 0 to nusing System; class GFG {         // Returns true if d is present as digit    // in number x.    static bool isDigitPresent(int x, int d)    {                 // Break loop if d is present as digit        while (x > 0)        {            if (x % 10 == d)                break;             x = x / 10;        }         // If loop broke        return (x > 0);    }     // function to display the values    static void printNumbers(int n, int d)    {                 // Check all numbers one by one        for (int i = 0; i <= n; i++)             // checking for digit            if (i == d || isDigitPresent(i, d))                Console.Write(i + " ");    }      // Driver code    public static void Main()    {        int n = 47, d = 7;                 printNumbers(n, d);    }} // This code contribute by parashar.
<?php// PHP program to print the number which// contain the digit d from 0 to n // Returns true if d is present as digit// in number x.function isDigitPresent($x, $d){         // Break loop if d is    // present as digit    while ($x > 0)    {        if ($x % 10 == $d)            break;         $x = $x / 10;    }     // If loop broke    return ($x > 0);} // function to display the valuesfunction printNumbers($n, $d){         // Check all numbers one by one    for ($i = 0; $i <= $n; $i++)         // checking for digit        if ($i == $d || isDigitPresent($i, $d))            echo $i , " ";}     // Driver Code    $n = 47;    $d = 7;    printNumbers($n, $d);     // This code contributed by ajit.?>
<script> // JavaScript program to print the number which// contain the digit d from 0 to n // Returns true if d is present as digit// in number x.function isDigitPresent(x, d){         // Break loop if d is present as digit    while (x > 0)    {        if (x % 10 == d)            break;         x = x / 10;    }     // If loop broke    return (x > 0);} // Function to display the valuesfunction printNumbers(n, d){         // Check all numbers one by one    for(let i = 0; i <= n; i++)             // Checking for digit        if (i == d || isDigitPresent(i, d))            document.write(i + " ");}      // Driver codelet n = 47, d = 7; printNumbers(n, d); // This code is contributed by splevel62 </script>
The number of values are
7 17 27 37 47
 
Approach 2: This approach uses every number as a String and checks digit is present or not. This approach use of String.indexOf() function to check if the character is present in the string or not.String.indexOf() >= 0 means character is present and String.indexOf() = -1 means character is not present 
C++
Java
Python3
C#
Javascript
// CPP program to print the number which// contain the digit d from 0 to n#include<bits/stdc++.h>using namespace std; // function to display the valuesvoid printNumbers(int n, int d){             // Converting d to character    string st = "";    st += to_string(d);    char ch = st[0];             string p = "";    p += ch;             // Loop to check each digit one by one.    for (int i = 0; i <= n; i++)    {                     // initialize the string        st = "";        st = st + to_string(i);        int idx = st.find(p);                     // checking for digit        if (i == d || idx!=-1)                    cout << (i) << " ";    }} // Driver codeint main(){    int n = 100, d = 5;    printNumbers(n, d);}     // This code is contributed by// Surendra_Gangwar
// Java program to print the number which// contain the digit d from 0 to n public class GFG {     // function to display the values    static void printNumbers(int n, int d)    {                 // Converting d to character        String st = "" + d;        char ch = st.charAt(0);                 // Loop to check each digit one by one.        for (int i = 0; i <= n; i++) {                         // initialize the string            st = "";            st = st + i;             // checking for digit            if (i == d || st.indexOf(ch) >= 0)                               System.out.print(i + " ");        }    }     // Driver code    public static void main(String[] args)    {        int n = 100, d = 5;        printNumbers(n, d);    }}
# Python 3 program to print the number# which contain the digit d from 0 to n def index(st, ch):    for i in range(len(st)):        if(st[i] == ch):            return i;    return -1     # function to display the valuesdef printNumbers(n, d):     # Converting d to character    st = "" + str(d)    ch = st[0]     # Loop to check each digit one by one.    for i in range(0, n + 1, 1):                 # initialize the string        st = ""        st = st + str(i)                 # checking for digit        if (i == d or index(st, ch) >= 0):            print(i, end = " ") # Driver codeif __name__ == '__main__':    n = 100    d = 5    printNumbers(n, d) # This code is contributed by# Shashank_Sharma
// C# program to print the number which// contain the digit d from 0 to nusing System; class GFG{     // function to display the values    static void printNumbers(int n, int d)    {                 // Converting d to character        String st = "" + d;        char ch = st[0];                 // Loop to check each digit one by one.        for (int i = 0; i < n; i++)        {                         // initialize the string            st = "";            st = st + i;             // checking for digit            if (i == d || st.IndexOf(ch) >= 0)                            Console.Write(i + " ");        }    }     // Driver code    public static void Main()    {        int n = 100, d = 5;        printNumbers(n, d);    }} /* This code contributed by PrinciRaj1992 */
<script> // Javascript program to print the number which// contain the digit d from 0 to n // Function to display the valuesfunction printNumbers(n, d){         // Converting d to character    let st = "" + d;    let ch = st[0];          // Loop to check each digit one by one.    for(let i = 0; i < n; i++)    {                 // Initialize the string        st = "";        st = st + i;         // Checking for digit        if (i == d || st.indexOf(ch) >= 0)                       document.write(i + " ");    }} // Driver codelet n = 100, d = 5; printNumbers(n, d); // This code is contributed by decode2207 </script>
5 15 25 35 45 50 51 52 53 54 55 56 57 58 59 65 75 85 95
 
Smitha Dinesh Semwal
parashar
jit_t
Shashank_Sharma
princiraj1992
SURENDRA_GANGWAR
splevel62
decode2207
simmytarika5
surinderdawra388
Java-Strings
number-digits
Numbers
Mathematical
Strings
Java-Strings
Strings
Mathematical
Numbers
Writing code in comment?
Please use ide.geeksforgeeks.org,
generate link and share the link here.