Print 1 to 100 in C++ Without Loops and Recursion - GeeksforGeeks

22 Dec, 2021
We can print 1 to 100 without using loops and recursion using three approaches discussed below:
1) Template Metaprogramming: Templates in C++ allow non-datatypes also as parameters. Non-datatype means a value, not a datatype. 
Example:
CPP
// CPP Program to print 1 to 100// without loops and recursion#include <iostream>using namespace std; template <int N> class PrintOneToN {public:    static void print()    {        PrintOneToN<N - 1>::print();               // Note that this is not recursion        cout << N << endl;    }}; template <> class PrintOneToN<1> {public:    static void print() { cout << 1 << endl; }}; // Driver Codeint main(){    const int N = 100;    PrintOneToN<N>::print();    return 0;}
Output
1
2
3
..
..
98
99
100
The program prints all numbers from 1 to n without using a loop and recursion. 
Explanation: 
In the above program, N is passed as a value which is not a datatype. A new instance of a generic class is created for every parameter and these classes are created at compile time.
Here, when compiler sees the statement “PrintOneToN<>::print()” with N = 100, it creates an instance PrintOneToN<100>.
In function PrintOneToN<100>::print(), another function PrintOneToN<99>::print() is called, therefore an instance PrintOneToN<99> is created.
Similarly, all instances from PrintOneToN<100> to PrintOneToN<2> are created. PrintOneToN<1>::print() is already there and prints 1.
The function PrintOneToN<2> prints 2 and so on. Therefore we get all numbers from 1 to N printed on the screen.
2) Following is another approach using classes and static variables,  
CPP
// CPP Program to print 1 to 100 without loops and recursion#include <iostream>using namespace std; class A {public:    static int a;    A() { cout << a++ << endl; }}; int A::a = 1; // Driver Codeint main(){    int N = 100;    A obj[N];    return 0;}
Output
1
2
3
..
..
98
99
100
The output of this program is the same as the above program. 
Explanation: In the above program, class A has a static variable ‘a’, which is incremented with every instance of A. The default constructor of class A prints the value of ‘a’. When we create an array of objects of type A, the default constructor is called for all objects one by one. Therefore, we get all values from 1 to 100 printed on the screen.
3) Using goto keyword: The goto statement is a jump statement and can be used to jump from anywhere to anywhere within a function.
Example:
C++
// CPP Program to print 1 to 100// without loops and recursion#include <iostream> // Driver Codeint main(){    short sum = 0; update:    sum++;    std::cout << sum << std::endl;     if (sum == 100)        return 0;    goto update;}
Output
1
2
3
..
..
98
99
100
The output of this program is the same as the above program. 
Explanation: In the above program, goto keyword is jump again to the label named update. The value of  ‘sum’ is printed and incremented with every call. The program stops executing once the variable sum is equal to 100. In this way, we get all values from 1 to 100 printed on the console. 
mahiransh_sharma
anshikajain26
cpp-puzzle
C Language
C++
Recursion
Recursion
CPP
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