Remove a given word from a String

18 Nov, 2019
Given a String and a Word, the task is remove that Word from the String.
Examples:
Input: String = "Geeks For Geeks", Word = "For"
Output: "Geeks Geeks"

Input: String = "A computer Science Portal", Word = "Geeks"
Output: "A computer Science Portal"

Approach : In Java, this can be done using String replaceAll method by replacing given word with a blank space.
Below is the solution to the above problem:
C++
Java
C#
// C++ program to remove// a given word from a string  #include <bits/stdc++.h>using namespace std;  string removeWord(string str, string word) {    // Check if the word is present in string    // If found, remove it using removeAll()    if (str.find(word) != string::npos)    {        size_t p = -1;          // To cover the case        // if the word is at the        // beginning of the string        // or anywhere in the middle        string tempWord = word + " ";        while ((p = str.find(word)) != string::npos)            str.replace(p, tempWord.length(), "");          // To cover the edge case        // if the word is at the        // end of the string        tempWord = " " + word;        while ((p = str.find(word)) != string::npos)            str.replace(p, tempWord.length(), "");    }      // Return the resultant string    return str;}  // Driver Codeint main(int argc, char const *argv[]) {    // Test Case 1:    // If the word is in the middle    string string1 = "Geeks for Geeks.";    string word1 = "for";      // Test Case 2:    // If the word is at the beginning    string string2 = "for Geeks Geeks.";    string word2 = "for";      // Test Case 3:    // If the word is at the end    string string3 = "Geeks Geeks for.";    string word3 = "for";      // Test Case 4:    // If the word is not present    string string4 = "A computer Science Portal.";    string word4 = "Geeks";      // Test case 1    cout << "String: " << string1 << "\nWord: "          << word1 << "\nResult String: "          << removeWord(string1, word1) << endl;      // Test case 2    cout << "\nString: " << string2 << "\nWord: "          << word2 << "\nResult String: "          << removeWord(string2, word2) << endl;      // Test case 3    cout << "\nString: " << string3 << "\nWord: "         << word3 << "\nResult String: "          << removeWord(string3, word3) << endl;      // Test case 4    cout << "\nString: " << string4 << "\nWord: "          << word4 << "\nResult String: "          << removeWord(string4, word4) << endl;    return 0;}  // This code is contributed by// sanjeev2552
// Java program to remove// a given word from a stringpublic class GFG {    public static String removeWord(String string, String word)    {          // Check if the word is present in string        // If found, remove it using removeAll()        if (string.contains(word)) {              // To cover the case            // if the word is at the            // beginning of the string            // or anywhere in the middle            String tempWord = word + " ";            string = string.replaceAll(tempWord, "");              // To cover the edge case            // if the word is at the            // end of the string            tempWord = " " + word;            string = string.replaceAll(tempWord, "");        }          // Return the resultant string        return string;    }      public static void main(String args[])    {          // Test Case 1:        // If the word is in the middle        String string1 = "Geeks for Geeks.";        String word1 = "for";          // Test Case 2:        // If the word is at the beginning        String string2 = "for Geeks Geeks.";        String word2 = "for";          // Test Case 3:        // If the word is at the end        String string3 = "Geeks Geeks for.";        String word3 = "for";          // Test Case 4:        // If the word is not present        String string4 = "A computer Science Portal.";        String word4 = "Geeks";          // Test case 1        System.out.println("String: " + string1                           + "\nWord: " + word1                           + "\nResult String: "                           + removeWord(string1, word1));          // Test case 2        System.out.println("\nString: " + string2                           + "\nWord: " + word2                           + "\nResult String: "                           + removeWord(string2, word2));          // Test case 3        System.out.println("\nString: " + string3                           + "\nWord: " + word3                           + "\nResult String: "                           + removeWord(string3, word3));          // Test case 4        System.out.println("\nString: " + string4                           + "\nWord: " + word4                           + "\nResult String: "                           + removeWord(string4, word4));    }}
// C# program to remove// a given word from a stringusing System;  class GFG {    public static String removeWord(String str, String word)    {          // Check if the word is present in string        // If found, remove it using removeAll()        if (str.Contains(word))        {              // To cover the case            // if the word is at the            // beginning of the string            // or anywhere in the middle            String tempWord = word + " ";            str = str.Replace(tempWord, "");              // To cover the edge case            // if the word is at the            // end of the string            tempWord = " " + word;            str = str.Replace(tempWord, "");        }          // Return the resultant string        return str;    }      // Driver code    public static void Main(String []args)    {          // Test Case 1:        // If the word is in the middle        String string1 = "Geeks for Geeks.";        String word1 = "for";          // Test Case 2:        // If the word is at the beginning        String string2 = "for Geeks Geeks.";        String word2 = "for";          // Test Case 3:        // If the word is at the end        String string3 = "Geeks Geeks for.";        String word3 = "for";          // Test Case 4:        // If the word is not present        String string4 = "A computer Science Portal.";        String word4 = "Geeks";          // Test case 1        Console.WriteLine("String: " + string1                        + "\nWord: " + word1                        + "\nResult String: "                        + removeWord(string1, word1));          // Test case 2        Console.WriteLine("\nString: " + string2                        + "\nWord: " + word2                        + "\nResult String: "                        + removeWord(string2, word2));          // Test case 3        Console.WriteLine("\nString: " + string3                        + "\nWord: " + word3                        + "\nResult String: "                        + removeWord(string3, word3));          // Test case 4        Console.WriteLine("\nString: " + string4                        + "\nWord: " + word4                        + "\nResult String: "                        + removeWord(string4, word4));    }}  // This code contributed by Rajput-Ji
String: Geeks for Geeks.
Word: for
Result String: Geeks Geeks.

String: for Geeks Geeks.
Word: for
Result String: Geeks Geeks.

String: Geeks Geeks for.
Word: for
Result String: Geeks Geeks.

String: A computer Science Portal.
Word: Geeks
Result String: A computer Science Portal.

Rajput-Ji
sanjeev2552
Java-String-Programs
Java-Strings
Java
Java Programs
Java-Strings
Java
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