LINQ | How to find minimum value of the given sequence?

21 May, 2019
In LINQ, you can find the minimum element of the given sequence by using Min() function. This method provides the minimum element of the given set of values. It does not support query syntax in C#, but it supports in VB.NET. It is available in both Enumerable and Queryable classes in C#. It returns null if all the elements present in the collection are null. It returns any type of data type means you can also use Min with the collection of a custom type(does not contain numeric value), but for this, you have to implement the IComparable interface. It can work with nullable, non-nullable decimal, double, floats, int, etc. values.
Example 1:
// C# program to find minimum// value from the given arrayusing System;using System.Linq;  class GFG {      // Main Method    static public void Main()    {          // Data source        int[] sequence = {20, 45, 50, 79, 90,                       79, 89, 100, 567, 29};          // Display the sequence        Console.WriteLine("The sequence is: ");          foreach(int s in sequence)        {            Console.WriteLine(s);        }          // Finding the minimum element        // from the given sequence        // Using Min function        int result = sequence.Min();        Console.WriteLine("Minimum Value: {0}", result);    }}
The sequence is: 
20
45
50
79
90
79
89
100
567
29
Minimum Value: 20

Example 2:
// C# program to find the Minimum// salary of the employeeusing System;using System.Linq;using System.Collections.Generic;  // Employee detailsclass Employee {      public int emp_id    {        get;        set;    }    public string emp_name    {        get;        set;    }    public string emp_gender    {        get;        set;    }    public string emp_hire_date    {        get;        set;    }    public int emp_salary    {        get;        set;    }}  class GFG {      // Main method    static public void Main()    {        List<Employee> emp = new List<Employee>() {            new Employee() { emp_id = 209, emp_name = "Anjita", emp_gender = "Female", emp_hire_date = "12/3/2017", emp_salary = 20000 },                new Employee() { emp_id = 210, emp_name = "Soniya", emp_gender = "Female", emp_hire_date = "22/4/2018", emp_salary = 30000 },                new Employee() { emp_id = 211, emp_name = "Rohit", emp_gender = "Male", emp_hire_date = "3/5/2016", emp_salary = 40000 },                new Employee() { emp_id = 212, emp_name = "Supriya", emp_gender = "Female", emp_hire_date = "4/8/2017", emp_salary = 40000 },                new Employee() { emp_id = 213, emp_name = "Anil", emp_gender = "Male", emp_hire_date = "12/1/2016", emp_salary = 40000 },                new Employee() { emp_id = 214, emp_name = "Anju", emp_gender = "Female", emp_hire_date = "17/6/2015", emp_salary = 50000 },        };          // Find the minimum salary         // of the employee        // Using Min () method        var res = emp.Min(a => a.emp_salary);        Console.WriteLine("Minimum salary of the employee: {0}", res);    }}
Minimum salary of the employee: 20000

CSharp LINQ
C#
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