LINQ | How to find maximum value of the given sequence?

21 May, 2019
In LINQ, you can find the maximum element of the given sequence by using Max() function. This method provides the maximum element of the given set of values. It does not support query syntax in C#, but it supports in VB.NET. It is available in both Enumerable and Queryable classes in C#. It returns null if all the elements present in the collection are null. It returns any type of data type means you can also use Max with the collection of a custom type(does not contain numeric value), but for this, you have to implement the IComparable interface. It can work with nullable, non-nullable decimal, double, floats, int, etc. values.
Example 1:
// C# program to find maximum // value from the given arrayusing System;using System.Linq;  class GFG {      // Main Method    static public void Main()    {          // Data source        int[] sequence = {20, 45, 50, 79, 90,                       79, 89, 100, 567, 29};          // Display the sequence        Console.WriteLine("The sequence is:");        foreach(int s in sequence)        {            Console.WriteLine(s);        }          // Finding the maximum element        // from the given sequence        // Using Max function        int result = sequence.Max();        Console.WriteLine("Maximum Value: {0}", result);    }}
The sequence is:
20
45
50
79
90
79
89
100
567
29
Maximum Value: 567

Example 2:
// C# program to find the Maximum// salary of the employeeusing System;using System.Linq;using System.Collections.Generic;  // Employee detailspublic class Employee {      public int emp_id    {        get;        set;    }    public string emp_name    {        get;        set;    }    public string emp_gender    {        get;        set;    }    public string emp_hire_date    {        get;        set;    }    public int emp_salary    {        get;        set;    }}  class GFG {      // Main method    static public void Main()    {        List<Employee> emp = new List<Employee>() {            new Employee() { emp_id = 209, emp_name = "Anjita", emp_gender = "Female", emp_hire_date = "12/3/2017", emp_salary = 20000 },                new Employee() { emp_id = 210, emp_name = "Soniya", emp_gender = "Female", emp_hire_date = "22/4/2018", emp_salary = 30000 },                new Employee() { emp_id = 211, emp_name = "Rohit", emp_gender = "Male", emp_hire_date = "3/5/2016", emp_salary = 40000 },                new Employee() { emp_id = 212, emp_name = "Supriya", emp_gender = "Female", emp_hire_date = "4/8/2017", emp_salary = 40000 },                new Employee() { emp_id = 213, emp_name = "Anil", emp_gender = "Male", emp_hire_date = "12/1/2016", emp_salary = 40000 },                new Employee() { emp_id = 214, emp_name = "Anju", emp_gender = "Female", emp_hire_date = "17/6/2015", emp_salary = 50000 },        };          // Find the Maximum salary of the         // employee Using Max() method        var res = emp.Max(a => a.emp_salary);        Console.WriteLine("Maximum Salary of the Employee: {0}", res);    }}
Maximum Salary of the Employee: 50000

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C#
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