Short Circuiting Techniques in Python

15 May, 2022
By short-circuiting, we mean the stoppage of execution of boolean operation if the truth value of expression has been determined already. The evaluation of expression takes place from left to right. In python, short-circuiting is supported by various boolean operators and functions. 
The chart given below gives an insight into the short-circuiting case of boolean expressions. Boolean operators are ordered by ascending priority. 
or: When the Python interpreter scans or expression, it takes the first statement and checks to see if it is true. If the first statement is true, then Python returns that object’s value without checking the second statement. The program does not bother with the second statement. If the first value is false, only then Python check the second value, and then the result is based on the second half. and: For an and expression, Python uses a short circuit technique to check if the first statement is false then the whole statement must be false, so it returns that value. Only if the first value is true, does it check the second statement and return the value. An expression containing and or stops execution when the truth value of expression has been achieved. Evaluation takes place from left to right.
Python3
# python code to demonstrate short circuiting # using and and or   # helper functiondef check():    return "geeks"   # using an expression to demonstrate# prints "geeks", and gets executed # as both are required to check truth valueprint (1 and check())          # using an expression to demonstrate# prints 1# as only if 1st value is true, or # doesnt require call check() funprint (1 or check())   # using an expression to demonstrate# prints "geeks"# the value returns true when check # is encountered. 1 is not executedprint (0 or check() or 1)   # using an expression to demonstrate# prints 1# as last value is required to evaluate# full expression because of "and"print (0 or check() and 1)
geeks
1
geeks
1

Inbuilt functions all() and any() in python also support short-circuiting. The example below would give you clear insight into how it works.
Python3
# python code to demonstrate short circuiting # using all() and any()   # helper functiondef check(i):    print ("geeks")    return i   # using all()# stops execution when false occurs# tells the compiler that even if one is # false, all cannot be true, hence stop # execution further.# prints 3 "geeks" print (all(check(i) for i in [1, 1, 0, 0, 3]))   print("\r")   # using any()# stops execution when true occurs# tells the compiler that even if one is # true, expression is true, hence stop # execution further.# prints 4 "geeks" print (any(check(i) for i in [0, 0, 0, 1, 3]))
geeks
geeks
geeks
False

geeks
geeks
geeks
geeks
True

Conditional operators also follow short-circuiting as when expression result is obtained, further execution is not required.
Python3
# python code to demonstrate short circuiting # using conditional operators   # helper functiondef check(i):    print ("geeks")    return i   # using conditional expressions# since 10 is not greater than 11# further execution is not taken place # to check for truth value.print( 10 > 11 > check(3) )   print ("\r")   # using conditional expressions# since 11 is greater than 10# further execution is taken place # to check for truth value.# return true as 11 > 3print( 10 < 11 > check(3) )      print ("\r")      # using conditional expressions# since 11 is greater than 10# further execution is taken place # to check for truth value.# return false as 11 < 12print( 10 < 11 > check(12) )
False

geeks
True

geeks
False

Short-circuiting in a ladder of if, elif, elif, ... else statements
When there is a sequence, aka a “ladder” of if and one or more elif statements, none of the conditions after the first one found to be True are evaluated.  
Python3
a = 10b = 20c = 30 def printreturn(l):   print(l)   return l if a == 11:    print("a == 11")elif b == 20 and c == 30: # This is True    print("b==20 and c==30")elif b == a+a and 0<len(printreturn("This was evaluated")):     # Though True, this is not even evaluated    print("b == a+a")
b==20 and c==30

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