Volume Calculation - Online Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to Volume Calculation. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Q 1 - A rectangular marble stone 28 cm wide and 5 cm thick weighs 112 kg. In the event that 1 cubic cm of marble measures 25 gm, then the length of given stone is:
A - 36 cm
B - 37.5 cm
C - 32 cm
D - 26.5 cm
Let the required length be x cm.
Then, its volume = (x*28*5*25/1000) kg = 7x/2 kg
∴ 7x/2= 112 ⇒x= 112*2/7= 32 cm
Required length = 32 cm
Q 2 - A rectangular water tank is open at the top. Its ability is 24m3. Its length and broadness are 4m and 3m separately. Overlooking the thickness of the material utilized for building the tank, the aggregate expense of painting the internal and external surfaces of the tank at Rs 10 for every m2, is:
A - Rs 400
B - Rs. 500
C - Rs. 600
D - Rs. 800
Let the depth of the tank be x meters. Then, 4*3*x = 24 ⇒x =2m
Area of the surface to be painted = 2* [{2*(L+b)*h} + (L*b)}]
= 2*[2*(4+3)*2+ (4*3)] m2= 80m2
Cost of painting = (80*10) = 800 Rs.
Q 3 - A swimming shower is 24 m long and 15 m wide. At the point when various men jump into the shower, the tallness of water ascends by 1 cm. On the off chance that the normal volume of water uprooted by every men be 0.1 m3, what number of men arrive in the shower?
A - 32
B - 36
C - 42
D - 46
Let there be x man in the bath .Then,
x *0.1= (24*15*1/100) ⇒x*1/10=   24*15*1/100⇒x= 36.
Q 4 - The surface territory of a (10cm *4cm*3cm) block is:
A - 84 cm2
B - 124 cm2
C - 164 cm2
D - 180 cm2
Here L =10 cm, b= 4 cm, h = 3cm
Surface area = 2(Lb+bh+Lh)
= 2(10*4+4*3+10*3) cm2 = 2*82 = 164cm2
Q 5 - The region of three contiguous appearances of a cuboid are in the proportion 2:3:4 and its volume is 9000 cm3. The littlest side has a length of:
A - 10 cm
B - 15 cm
C - 20 cm
D - 30 cm
Let the area of the three adjacent faces be 2x, 3x and 4x then,
Lb= 2x, bh= 3x and Lh= 4x
∴ (Lb*bh*Lh) = 24x3 ⇒ (Lbh) 2 =(9000) 2= 81000000
⇒x3= 81000000/24= 27000000/8 ⇒x = 300/2= 150
∴ Lb= 300, bh =450 and Lh= 600 and Lbh= 9000
∴ h = 9000/300= 30cm, L= 9000/450 = 20cm, b= 9000/600= 15cm
Smallest side = 15 cm
Q 6 - A metal 3D square of edge 12cm is liquefied and framed into three littler 3D shape. In the event that the edge of two littler 3D shapes is 6cm and 8 cm. the edge of the third littler solid shape is:
A - 10 cm
B - 14 cm
C - 12 cm
D - 16 cm
Let the edge of third smaller cube be a cm. Then,
(6) 3+ (8) 3+a3= (12) 3 ⇒ (216+512) +a3=1728
⇒a3= (1728-728) = 1000= (10) 3⇒a= 10cm
∴ Edge of third smaller cube = 10 cm
Q 7 - If the span of a barrel is diminished by half and the stature is expanded by half to frame another chamber, then the volume will be diminished by:
A - 1:4
B - 4:1
C - 2:5
D - none of these
Initial volume = πr2h
New radius = r/2, new volume = [π*(r/2)2*4] = 1/4 πr2h
Required ratio = 1/4 πr2h: πr2h = 1/4:1 = 1:4
Q 8 - The bended surface of a tube shaped column is 264 m2 and its volume is 924 m3. The proportion of its width to its stature is:
A - 7:3
B - 3:7
C - 7:6
D - 6:7
2πrh =264 and πr2h =924
∴πr2h/2πrh=   924/264= 7/2 ⇒r =7 ⇒d= 2r =14m
2*22/7*7*h =264 ⇒h = 264/44= 6
∴ d/h= 14/6=    7/3 = 7:3
Q 9 - The total of the range of base and the tallness of a barrel is 37 m. On the off chance that the aggregate surface region of the chamber is 1628m2, then its volume is:
A - 5240 m3
B - 4620 m3
C - 3180 m3
D - none of these
Given: (r+h) = 37m
Total surface area = 2πr (h+r)
∴2πr* 37= 1628 ⇒22/7* r= 22 ⇒ r = 7m
h =(37-7)= 30 m
Volume = πr2h= (22/7* 7* 7* 30) m3= 4620 m3
Q 10 - The volume of the circle is 2145(11/21) cm3. Its sweep is:
A - 7 cm
B - 8 cm
C - 9 cm
D - none of these
4/3πr3=45056/21 ⇒4/3*22/7* r3 = 45056/21
⇒r3= (45056/21 *21/88) = 512 = (8) 3 ⇒r =8
∴Radius of the sphere =8cm

    87 Lectures 
     22.5 hours 

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