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Given an array, a positive integer, sort the array in ascending order such that the element at index K in the unsorted array stays unmoved and all other elements are sorted. 
Examples: 
Input : arr[] = {10, 4, 11, 7, 6, 20}
            k = 2;
Output : arr[] = {4, 6, 11, 7, 10, 20}

Input : arr[] = {30, 20, 10}
         k = 0
Output : arr[] = {30, 10, 20} 
A simple solution is to copy all elements except k-th of a given array to another array. Then sort the other array using a sorting algorithm. Finally, again copy the sorted array to the original array. While copying, skip k-th element. 
Below is an efficient solution.  
Swap k-th element with the last element.Sort all elements except the last.For every element from (k+1)-th to last, move them one position ahead.1Copy k-th element back to position k. 
Swap k-th element with the last element.
Sort all elements except the last.
For every element from (k+1)-th to last, move them one position ahead.1
Copy k-th element back to position k. 
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// CPP program to sort all elements except// element at index k.#include <bits/stdc++.h>using namespace std; int sortExceptK(int arr[], int k, int n){    // Move k-th element to end    swap(arr[k], arr[n-1]);     // Sort all elements except last    sort(arr, arr + n - 1);     // Store last element (originally k-th)    int last = arr[n-1];     // Move all elements from k-th to one    // position ahead.    for (int i=n-1; i>k; i--)       arr[i] = arr[i-1];     // Restore k-th element    arr[k] = last;} // Driver codeint main(){    int a[] = {10, 4, 11, 7, 6, 20 };    int k = 2;    int n = sizeof(a) / sizeof(a[0]);    sortExceptK(a, k, n);    for (int i = 0; i < n; i++)        cout << a[i] << " ";}
// Java program to sort all elements except// element at index k.import java.util.Arrays; class GFG {         static int sortExceptK(int arr[], int k, int n)    {                 // Move k-th element to end        int temp = arr[k];        arr[k] = arr[n-1];        arr[n-1] = temp;             // Sort all elements except last        Arrays.sort(arr, 0, n-1);             // Store last element (originally k-th)        int last = arr[n-1];             // Move all elements from k-th to one        // position ahead.        for (int i = n-1; i > k; i--)        arr[i] = arr[i-1];             // Restore k-th element        arr[k] = last;        return 0;    }         //Driver code    public static void main (String[] args)    {        int a[] = {10, 4, 11, 7, 6, 20 };        int k = 2;        int n = a.length;                 sortExceptK(a, k, n);                 for (int i = 0; i < n; i++)            System.out.print(a[i] + " ");    }} //This code is contributed by Anant Agarwal.
# Python3 program to sort all elements except# element at index k.def sortExcept(arr, k, n):     # Move k-th element to end    arr[k], arr[-1] = arr[-1], arr[k]     # Sort all elements except last    arr = sorted(arr, key = lambda i: (i is arr[-1], i))         # Store last element (originally k-th)    last = arr[-1]     # Move all elements from k-th to one    # position ahead.    i = n - 1    while i > k:        arr[i] = arr[i - 1]        i -= 1     # Restore k-th element    arr[k] = last    return arr # Driver codeif __name__ == '__main__':    a = [10, 4, 11, 7, 6, 20]    k = 2    n = len(a)    a = sortExcept(a, k, n)    print(" ".join(list(map(str, a))))     # This code is contributed by Shivam Singh.
// C# program to sort all elements except// element at index k.using System; public class GFG {         static int sortExceptK(int[] arr, int k, int n)    {        // Move k-th element to end        int temp = arr[k];        arr[k] = arr[n - 1];        arr[n - 1] = temp;         // Sort all elements except last        Array.Sort(arr, 0, n - 1);         // Store last element (originally k-th)        int last = arr[n - 1];         // Move all elements from k-th to one        // position ahead.        for (int i = n - 1; i > k; i--)            arr[i] = arr[i - 1];         // Restore k-th element        arr[k] = last;                 return 0;    }         // Driver code    public static void Main()    {        int[] a = { 10, 4, 11, 7, 6, 20 };        int k = 2;        int n = a.Length;         sortExceptK(a, k, n);         for (int i = 0; i < n; i++)        Console.Write(a[i] + " ");    }} // This article is contributed by shiv_bhakt
<?php// PHP program to sort all// elements except element// at index k.function sortExceptK(&$arr, $k, $n){    // Move k-th element to end    $t = $arr[$k];    $arr[$k] = $arr[$n - 1];    $arr[$n - 1] = $t;     // Sort all elements    // except last    $t = $arr[count($arr) - 1];    $arr = array_slice($arr, 0, -1);    sort($arr);    array_push($arr, $t);     // Store last element    // (originally k-th)    $last = $arr[$n - 1];     // Move all elements from    // k-th to one position ahead.    for ($i = $n - 1; $i > $k; $i--)    $arr[$i] = $arr[$i - 1];     // Restore k-th element    $arr[$k] = $last;} // Driver code$a = array(10, 4, 11,            7, 6, 20 );$k = 2;$n = count($a);sortExceptK($a, $k, $n); for ($i = 0; $i < $n; $i++)    echo ($a[$i]." ");     // This code is contributed by// Manish Shaw(manishshaw1)?>
<script>    // Javascript program to sort all elements except    // element at index k.         function sortExceptK(arr, k, n)    {                   // Move k-th element to end        let temp = arr[k];        arr[k] = arr[n-1];        arr[n-1] = temp;               // Sort all elements except last        arr.sort(function(a, b){            return a - b});               // Store last element (originally k-th)        let last = arr[n-1];               // Move all elements from k-th to one        // position ahead.        for (let i = n-1; i > k; i--)            arr[i] = arr[i-1];               // Restore k-th element        arr[k] = last;                 // Move k-th element to end        temp = arr[k];        arr[k] = arr[n-1];        arr[n-1] = temp;                 return 0;    }         let a = [10, 4, 11, 7, 6, 20 ];    let k = 2;    let n = a.length;     sortExceptK(a, k, n);     for(let i = 0; i < n; i++)      document.write(a[i] + " "); </script>
4 6 11 7 10 20 
 
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