Sort the given IP addresses in ascending order

24 May, 2022
Given an array arr[] of IP Addresses where each element is a IPv4 Address, the task is to sort the given IP addresses in increasing order.Examples:  
Input: arr[] = {‘126.255.255.255’, ‘169.255.0.0’, ‘169.253.255.255’} Output: ‘126.255.255.255’, ‘169.253.255.255’, ‘169.255.0.0’ Explanation: As the second octet of the third IP Address is less than the second IP Address whereas the first octet is same. Due to which the third IP Address will be smaller than the Third IP Address. 169.255.0.0 > 169.253.255.255 Input: arr[] = {‘192.168.0.1’, ‘192.168.1.210’, ‘192.168.0.227’} Output: ‘192.168.0.1’, ‘192.168.0.227’, ‘192.168.1.210’  
 
Approach: The idea is to use a custom comparator to sort the given IP addresses. Since IPv4 has 4 octets, we will compare the addresses octet by octet.  
Check the first octet of the IP Address, If the first address has a greater first octet, then return True to swap the IP address, otherwise, return False.
If the first octet of the IP Addresses is same then compare the second octet of both IP Address. If the first address has a greater second octet, then return True to swap the IP address, otherwise, return False.
If the second octet of the IP Addresses is also the same, then compare the third octet of both IP Address. If the first address has a greater third octet, then return True to swap the IP address, otherwise, return False.
If the third octet of the IP Addresses is also the same, then compare the fourth octet of both IP Address. If the first address has a greater third octet, then return True to swap the IP address, otherwise, return False.
If the fourth octet is also the same, then both IP Address is equal. Then also return False.
Below is the implementation of the above approach: 
Python
# Python implementation to sort# the array of the IP Address from functools import cmp_to_key # Custom Comparator to sort the# Array in the increasing orderdef customComparator(a, b):         # Breaking into the octets    octetsA = a.strip().split(".")    octetsB = b.strip().split(".")         # Condition if the IP Address    # is same then return 0    if octetsA == octetsB:        return 0    elif octetsA[0] > octetsB[0]:        return 1    elif octetsA[0] < octetsB[0]:        return -1    elif octetsA[1] > octetsB[1]:        return 1    elif octetsA[1] < octetsB[1]:        return -1    elif octetsA[2] > octetsB[2]:        return 1    elif octetsA[2] < octetsB[2]:        return -1    elif octetsA[3] > octetsB[3]:        return 1    elif octetsA[3] < octetsB[3]:        return -1 # Function to sort the IP Addressesdef sortIPAddress(arr):         # Sort the Array using    # Custom Comparator    arr = sorted(arr, key = \       cmp_to_key(customComparator))            print(*arr)    return arr     # Driver Codeif __name__ == "__main__":    arr = ['192.168.0.1',           '192.168.1.210',           '192.168.0.227']         # Function Call    sortIPAddress(arr)
192.168.0.1 
192.168.0.227 
192.168.1.210
 
Time Complexity: O(N*logN) 
clintra
rkbhola5
IP Addressing
Java-Comparator
Arrays
Sorting
Arrays
Sorting
Writing code in comment?
Please use ide.geeksforgeeks.org,
generate link and share the link here.
Introduction to Data Structures
Search, insert and delete in an unsorted array
Window Sliding Technique
Chocolate Distribution Problem
Find duplicates in O(n) time and O(1) extra space | Set 1
Merge Sort
Bubble Sort Algorithm
QuickSort
Insertion Sort
Selection Sort Algorithm