The dice problem

05 Aug, 2021
You are given a cubic dice with 6 faces. All the individual faces have a number printed on them. The numbers are in the range of 1 to 6, like any ordinary dice. You will be provided with a face of this cube, your task is to guess the number on the opposite face of the cube.
Examples:
Input: N = 2Output: 5Explanation:For dice facing number 5 opposite face will have the number 2.
Input: N = 6Output: 1
Naive Approach: In a normal 6 faced dice, 1 is opposite to 6, 2 is opposite to 5, and 3 is opposite to 4. Hence a normal if-else-if block can be placed 
Approach: The idea is based on the observation that the sum of two opposite sides of a cubical dice is equal to 7. So, just subtract the given N from 7 and print the answer.
Below is the implementation of the above approach:
C++
Java
Python3
C#
Javascript
// C++ program for the above approach#include<bits/stdc++.h>using namespace std; // Function to find number// written on the// opposite face of the diceint oppositeFaceOfDice(int N){    // Stores number on opposite face    // of dice    int ans = 7 - N;     // Print the answer    cout << ans;} // Driver Codeint main(){    // Given value of N    int N = 2;     // Function call to find number written on    // the opposite face of the dice    oppositeFaceOfDice(N);     return 0;}
// Java program for the above approachimport java.io.*; class GFG{       // Function to find number    // written on the    // opposite face of the dice    static void oppositeFaceOfDice(int N)    {               // Stores number on opposite face        // of dice        int ans = 7 - N;         // Print the answer        System.out.println(ans);    }     // Driver Code    public static void main(String[] args)    {               // Given value of N        int N = 2;         // Function call to find number written on        // the opposite face of the dice        oppositeFaceOfDice(N);    }} // This code is contributed by Potta Lokesh
# Python3 program for the above approach # Function to find number written on the# opposite face of the dicedef oppositeFaceOfDice(N):         # Stores number on opposite face    # of dice    ans = 7 - N         # Print the answer    print(ans) # Driver Code # Given value of NN = 2 # Function call to find number written on# the opposite face of the diceoppositeFaceOfDice(N) # This code is contributed by gfgking
// C# program for the above approachusing System;using System.Collections.Generic; class GFG{ // Function to find number// written on the// opposite face of the dicestatic void oppositeFaceOfDice(int N){       // Stores number on opposite face    // of dice    int ans = 7 - N;     // Print the answer    Console.Write(ans);} // Driver Codepublic static void Main(){    // Given value of N    int N = 2;     // Function call to find number written on    // the opposite face of the dice    oppositeFaceOfDice(N);}} // This code is contributed by SURENDRA_GANGWAR.
<script> // JavaScript program for the above approach // Function to find number// written on the// opposite face of the dicefunction oppositeFaceOfDice(N) {  // Stores number on opposite face  // of dice  let ans = 7 - N;   // Print the answer  document.write(ans);} // Driver Code // Given value of Nlet N = 2; // Function call to find number written on// the opposite face of the diceoppositeFaceOfDice(N); // This code is contributed by gfgking </script>
5
Time Complexity: O(1)Auxiliary Space: O(1)
 
lokeshpotta20
gfgking
SURENDRA_GANGWAR
Mathematical
Mathematical
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