hex() function in Python - GeeksforGeeks

27 Oct, 2021
hex() function is one of the built-in functions in Python3, which is used to convert an integer number into it’s corresponding hexadecimal form.
Syntax : 
hex(x) 
Parameters : 
x - an integer number (int object)
Returns :  Returns hexadecimal string.
Errors and Exceptions : 
TypeError :  Returns TypeError when anything other than
             integer type constants are passed as parameters.
  Code #1 : Illustrates use of hex() function. 
Python3
# Python3 program to illustrate# hex() function print("The hexadecimal form of 23 is "                            + hex(23))                             print("The hexadecimal form of the "      "ascii value is 'a' is " + hex(ord('a')))       print("The hexadecimal form of 3.9 is "                        + float.hex(3.9))
Output : 
The hexadecimal form of 23 is 0x17
The hexadecimal form of the ascii value os 'a' is 0x61
The hexadecimal form of 3.9 is 0x1.f333333333333p+1
Code #2: Demonstrate TypeError when floating point values are passed as parameter. 
Python3
# hex() accepts only integer values as parametersprint("The hexadecimal form of 11.1 is "                            + hex(11.1)) '''# The hexadecimal conversion of floating # point integers can be done using the# function float.hex()print("The hexadecimal form of 11.1 is "                    + float.hex(11.1))# Output :# The hexadecimal form of 11.1 is 0x1.6333333333333p+3 # Similarly, float.hex() throws a TypeError# when integer values are passed in it.'''
Output : 
Traceback (most recent call last):
  File "/home/7e1ac7e34362fd690cdb72cf294502e1.py", line 2, in 
    print("The hexadecimal form of 11.1 is "+hex(11.1))
TypeError: 'float' object cannot be interpreted as an integer
  Applications : hex() is used in all the standard conversions. For example conversion of hexadecimal to decimal, hexadecimal to octal, hexadecimal to binary. 
Code #3 : 
Python3
# TypeConversion from decimal with base 10# to hexadecimal form with base 16  # Taking input from user# an integer with base 10number = int(input("Enter a number with base 10\n")) # The choices present to the userprint("a. Decimal to Hexadecimal ")print("b. Decimal to Octal")print("c. Decimal to Binary") # taking user inputprint("Enter your choice :- ")choice = input() # Running a variable choice# Hexadecimal form if choice# is set to 'a'if choice is 'a':     # lstrip helps remove "0x" from the left    # rstrip helps remove "L" from the right,    # L represents a long number    print("Hexadecimal form of " + str(number) +        " is " + hex(number).lstrip("0x").rstrip("L"))         if choice is 'b':         # Octal representation is done    # by adding a prefix "0o"    print("Octal form of " + str(number) +        " is " + oct(number).lstrip("0o").rstrip("L"))         if choice is 'c':         # Binary representation is done by    # the addition of prefix "0b"    print("Binary form of " + str(number) +        " is "+bin(number).lstrip("0b").rstrip("L"))
Output : 
input variant a)
Enter a number with base 10
123
a. Decimal to Hexadecimal 
b. Decimal to Octal
c. Decimal to Binary
Enter your choice:- 
a
Hexadecimal form of 123 is 7b
input variant b)
Enter a number with base 10
123456789
a. Decimal to Hexadecimal 
b. Decimal to Octal
c. Decimal to Binary
Enter your choice:- 
a
Hexadecimal form of 123456789 is 75bcd15
nidhi_biet
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