TCS Placement Paper | MCQ 7

21 May, 2019
This is a TCS model placement paper for aptitude preparation. This placement paper will cover aptitude questions that are asked in TCS recruitment drives and also strictly follows the pattern of questions asked in TCS interviews. It is recommended to solve each one of the following questions to increase your chances of clearing the TCS interview.
The sticks of the same length are used to form a triangle as shown below. If 87 such sticks are used then how many triangles can be formed?a) 42b) 43c) 44d) 45Answer: b) 43Solution:As we can see the first triangle can be formed using 3 sticks. So we have 87 – 3 = 84 sticks left.So every next triangle can be formed using 2 sticks.So we have 84/2 = 42 triangles and 43 triangles in all.Find the next number in the series of 3, 12, 7, 26, 15, ?a) 54b) 55c) 64d) 74
Video Player is loading.Play VideoPlayMuteCurrent Time 0:00/Duration 0:00Loaded: 0%0:00Stream Type LIVESeek to live, currently behind liveLIVERemaining Time -0:00 1xPlayback RateChaptersChaptersDescriptionsdescriptions off, selectedCaptionscaptions settings, opens captions settings dialogcaptions off, selectedEnglishAudio TrackPicture-in-PictureFullscreenThis is a modal window.The media could not be loaded, either because the server or network failed or because the format is not supported.Beginning of dialog window. Escape will cancel and close the window.TextColorWhiteBlackRedGreenBlueYellowMagentaCyanTransparencyOpaqueSemi-TransparentBackgroundColorBlackWhiteRedGreenBlueYellowMagentaCyanTransparencyOpaqueSemi-TransparentTransparentWindowColorBlackWhiteRedGreenBlueYellowMagentaCyanTransparencyTransparentSemi-TransparentOpaqueFont Size50%75%100%125%150%175%200%300%400%Text Edge StyleNoneRaisedDepressedUniformDropshadowFont FamilyProportional Sans-SerifMonospace Sans-SerifProportional SerifMonospace SerifCasualScriptSmall CapsReset restore all settings to the default valuesDoneClose Modal DialogEnd of dialog window.Answer: a) 54Solution:3 * 2 + 1 = 712 * 2 + 2 = 267 * 2 + 1 = 1526 * 2 + 2 = 54There is a toy gun that made 10 musical sounds. It makes 2 musical sounds after being defective. What is the probability that same musical sound would be produced 5 times consecutively?a) 1/16b) 1/32c) 1/48d) 1/2Answer: b) 1/32Solution:The probability of making the same sound every time = 1/2,So, 1/2^5 = 1/32 (answer)In how many possible ways you can write 3240 as a product of 3 positive integers?a) 320b) 420c) 350d) 450Answer: d) 450 waysSolution:First let’s prime factorize the number 3240 = Let the three positive numbers be x, y and zWe have to distribute three 2’s to x, y and z ways in (3+3-1)C(3-1) = 5C2 ways = 10 waysWe have to distribute four 3’s to x, y, z in (3+4-1)C(3-1) = 6C2 waysWe have to distribute one 5 to x, y, z in 3 ways.The total number of ways = 10×15×3=450 ways.The marked price of a shirt was 40% less than the suggested retail price. Ram purchased the coat for half of the marked price at the 15th-anniversary sale. What per cent less than the suggested retail price did Ram pay?a) 70%b) 20%c) 60%d) 30%Answer: a) 70%Solution:Let the retail price of the shirt be Rs. 100So according to the question, the market price will be = 100*0.6 = 60Purchased price of Ram = 60/2 = 30which is 70% less than retail price.HCF of 2472, 1284 and a 3rd number, is 12. If their LCM is 8*9*5*103*107, then what is the number?a) 2^2*3^2*7^1b) 2^2*3^2*5^1c) 2^2*3^2*8103d) None of the above.Answer: b) 2^2×3^2×5^1Solution:2472 = 1284 = HCF = LCM = HCF of the number is the highest number which divides all the numbers. So N should be a multiple of 22×3LCM is the largest number that is divided by the given numbers. As LCM contains 32×5 these two are from N.So N = [Tex]$2^2×3^2×5^1$[Tex]An old man takes 30 minutes and a young man takes 20 minutes to walk from apartment to office. If one day the old man started at 10.00 AM and the young man at 10:05 AM from the apartment to office, when will they meet?a) 10:00b) 10:15c) 10.30d) 10:45Answer: b) 10:15Solution:Let the distance of the apartment from the office be 12 kmSo the speed of the old man = 12 / (1/2) hr = 24 km/hrThe young man speed = 12 / (1/3) hr = 36 km/hrSince the old man started 5 minutes earlier, he covers 24 × (5/60) = 2 km in 5 minutes.Now the time taken to the young man to meets him = 2/(36-24) * 60 = 10 minutesSo the time of meet = 10:05 + 10 = 10 hr 15 min or 10:15In the range of 112 to 375, how many 2’s are there?a) 312b) 156c) 159d) 160Answer: b) 156Solution:The total number of 2’s in the units place = (122, 132, 142 ... 192), (201, 212, 222, ... 292), (302, 312, ... 372) = 8 + 10 + 8 = 26 2’sThe total number of 2’s in tenth’s place = (120, 121, 122, ..., 129) + (220, 221, ..., 229) + (320, 321, ..., 329) = 30The total number of 2’s in hundred’s place = (200, 201, ... 299) = 100.So the total number of 2’s between 112 and 375 = 26 + 30 + 100 = 156Ram walks 36 km partly at a speed of 4 km/hr and partly at 3 km/hr. If he had walked at a speed of 3km/hr when he had walked at 4 and 4 km/hr when he had walked at 3 he would have walked only 34 km. The time (in hours) spent by Ram in walking wasa) 10b) 5c) 12d) 8Answer: a) 10Solution:Let Ram walk ‘x’ hrs at 4 km/hr, and ‘y’ hrs at 3 km/hr.Given,4x + 3y = 363x + 4y = 34Solving these two equations we get x + y = 10What will be the 55th word in the arrangement of the letters of the word PERFECT?a) CEPFRETb) CEPFERTc) CEPERFTd) CEPRFETAnswer: b) CEPFERTSolution:Let’s arrange the word PERFECT in dictionary order = CEEFPRTHere,CEE(4!)=24CEF(4!)=24CEPF(3!)=6So the 55th word is CEPFERT.
The sticks of the same length are used to form a triangle as shown below. If 87 such sticks are used then how many triangles can be formed?a) 42b) 43c) 44d) 45Answer: b) 43Solution:As we can see the first triangle can be formed using 3 sticks. So we have 87 – 3 = 84 sticks left.So every next triangle can be formed using 2 sticks.So we have 84/2 = 42 triangles and 43 triangles in all.
Answer: b) 43
Solution:As we can see the first triangle can be formed using 3 sticks. So we have 87 – 3 = 84 sticks left.So every next triangle can be formed using 2 sticks.So we have 84/2 = 42 triangles and 43 triangles in all.
Find the next number in the series of 3, 12, 7, 26, 15, ?a) 54b) 55c) 64d) 74
Video Player is loading.Play VideoPlayMuteCurrent Time 0:00/Duration 0:00Loaded: 0%0:00Stream Type LIVESeek to live, currently behind liveLIVERemaining Time -0:00 1xPlayback RateChaptersChaptersDescriptionsdescriptions off, selectedCaptionscaptions settings, opens captions settings dialogcaptions off, selectedEnglishAudio TrackPicture-in-PictureFullscreenThis is a modal window.The media could not be loaded, either because the server or network failed or because the format is not supported.Beginning of dialog window. Escape will cancel and close the window.TextColorWhiteBlackRedGreenBlueYellowMagentaCyanTransparencyOpaqueSemi-TransparentBackgroundColorBlackWhiteRedGreenBlueYellowMagentaCyanTransparencyOpaqueSemi-TransparentTransparentWindowColorBlackWhiteRedGreenBlueYellowMagentaCyanTransparencyTransparentSemi-TransparentOpaqueFont Size50%75%100%125%150%175%200%300%400%Text Edge StyleNoneRaisedDepressedUniformDropshadowFont FamilyProportional Sans-SerifMonospace Sans-SerifProportional SerifMonospace SerifCasualScriptSmall CapsReset restore all settings to the default valuesDoneClose Modal DialogEnd of dialog window.Answer: a) 54Solution:3 * 2 + 1 = 712 * 2 + 2 = 267 * 2 + 1 = 1526 * 2 + 2 = 54
Chapters
descriptions off, selected
captions settings, opens captions settings dialog
captions off, selected
English
This is a modal window.
Beginning of dialog window. Escape will cancel and close the window.
End of dialog window.
Answer: a) 54
Solution:3 * 2 + 1 = 712 * 2 + 2 = 267 * 2 + 1 = 1526 * 2 + 2 = 54
There is a toy gun that made 10 musical sounds. It makes 2 musical sounds after being defective. What is the probability that same musical sound would be produced 5 times consecutively?a) 1/16b) 1/32c) 1/48d) 1/2Answer: b) 1/32Solution:The probability of making the same sound every time = 1/2,So, 1/2^5 = 1/32 (answer)
Answer: b) 1/32
Solution:The probability of making the same sound every time = 1/2,So, 1/2^5 = 1/32 (answer)
In how many possible ways you can write 3240 as a product of 3 positive integers?a) 320b) 420c) 350d) 450Answer: d) 450 waysSolution:First let’s prime factorize the number 3240 = Let the three positive numbers be x, y and zWe have to distribute three 2’s to x, y and z ways in (3+3-1)C(3-1) = 5C2 ways = 10 waysWe have to distribute four 3’s to x, y, z in (3+4-1)C(3-1) = 6C2 waysWe have to distribute one 5 to x, y, z in 3 ways.The total number of ways = 10×15×3=450 ways.
Answer: d) 450 ways
Solution:First let’s prime factorize the number 3240 = Let the three positive numbers be x, y and zWe have to distribute three 2’s to x, y and z ways in (3+3-1)C(3-1) = 5C2 ways = 10 waysWe have to distribute four 3’s to x, y, z in (3+4-1)C(3-1) = 6C2 waysWe have to distribute one 5 to x, y, z in 3 ways.The total number of ways = 10×15×3=450 ways.
The marked price of a shirt was 40% less than the suggested retail price. Ram purchased the coat for half of the marked price at the 15th-anniversary sale. What per cent less than the suggested retail price did Ram pay?a) 70%b) 20%c) 60%d) 30%Answer: a) 70%Solution:Let the retail price of the shirt be Rs. 100So according to the question, the market price will be = 100*0.6 = 60Purchased price of Ram = 60/2 = 30which is 70% less than retail price.
Answer: a) 70%
Solution:Let the retail price of the shirt be Rs. 100So according to the question, the market price will be = 100*0.6 = 60Purchased price of Ram = 60/2 = 30which is 70% less than retail price.
HCF of 2472, 1284 and a 3rd number, is 12. If their LCM is 8*9*5*103*107, then what is the number?a) 2^2*3^2*7^1b) 2^2*3^2*5^1c) 2^2*3^2*8103d) None of the above.Answer: b) 2^2×3^2×5^1Solution:2472 = 1284 = HCF = LCM = HCF of the number is the highest number which divides all the numbers. So N should be a multiple of 22×3LCM is the largest number that is divided by the given numbers. As LCM contains 32×5 these two are from N.So N = [Tex]$2^2×3^2×5^1$[Tex]
Answer: b) 2^2×3^2×5^1
Solution:2472 = 1284 = HCF = LCM = HCF of the number is the highest number which divides all the numbers. So N should be a multiple of 22×3LCM is the largest number that is divided by the given numbers. As LCM contains 32×5 these two are from N.So N = [Tex]$2^2×3^2×5^1$[Tex]
An old man takes 30 minutes and a young man takes 20 minutes to walk from apartment to office. If one day the old man started at 10.00 AM and the young man at 10:05 AM from the apartment to office, when will they meet?a) 10:00b) 10:15c) 10.30d) 10:45Answer: b) 10:15Solution:Let the distance of the apartment from the office be 12 kmSo the speed of the old man = 12 / (1/2) hr = 24 km/hrThe young man speed = 12 / (1/3) hr = 36 km/hrSince the old man started 5 minutes earlier, he covers 24 × (5/60) = 2 km in 5 minutes.Now the time taken to the young man to meets him = 2/(36-24) * 60 = 10 minutesSo the time of meet = 10:05 + 10 = 10 hr 15 min or 10:15
Answer: b) 10:15
Solution:Let the distance of the apartment from the office be 12 kmSo the speed of the old man = 12 / (1/2) hr = 24 km/hrThe young man speed = 12 / (1/3) hr = 36 km/hrSince the old man started 5 minutes earlier, he covers 24 × (5/60) = 2 km in 5 minutes.Now the time taken to the young man to meets him = 2/(36-24) * 60 = 10 minutesSo the time of meet = 10:05 + 10 = 10 hr 15 min or 10:15
In the range of 112 to 375, how many 2’s are there?a) 312b) 156c) 159d) 160Answer: b) 156Solution:The total number of 2’s in the units place = (122, 132, 142 ... 192), (201, 212, 222, ... 292), (302, 312, ... 372) = 8 + 10 + 8 = 26 2’sThe total number of 2’s in tenth’s place = (120, 121, 122, ..., 129) + (220, 221, ..., 229) + (320, 321, ..., 329) = 30The total number of 2’s in hundred’s place = (200, 201, ... 299) = 100.So the total number of 2’s between 112 and 375 = 26 + 30 + 100 = 156
Answer: b) 156
Solution:The total number of 2’s in the units place = (122, 132, 142 ... 192), (201, 212, 222, ... 292), (302, 312, ... 372) = 8 + 10 + 8 = 26 2’sThe total number of 2’s in tenth’s place = (120, 121, 122, ..., 129) + (220, 221, ..., 229) + (320, 321, ..., 329) = 30The total number of 2’s in hundred’s place = (200, 201, ... 299) = 100.So the total number of 2’s between 112 and 375 = 26 + 30 + 100 = 156
Ram walks 36 km partly at a speed of 4 km/hr and partly at 3 km/hr. If he had walked at a speed of 3km/hr when he had walked at 4 and 4 km/hr when he had walked at 3 he would have walked only 34 km. The time (in hours) spent by Ram in walking wasa) 10b) 5c) 12d) 8Answer: a) 10Solution:Let Ram walk ‘x’ hrs at 4 km/hr, and ‘y’ hrs at 3 km/hr.Given,4x + 3y = 363x + 4y = 34Solving these two equations we get x + y = 10
Answer: a) 10
Solution:Let Ram walk ‘x’ hrs at 4 km/hr, and ‘y’ hrs at 3 km/hr.Given,4x + 3y = 363x + 4y = 34Solving these two equations we get x + y = 10
What will be the 55th word in the arrangement of the letters of the word PERFECT?a) CEPFRETb) CEPFERTc) CEPERFTd) CEPRFETAnswer: b) CEPFERTSolution:Let’s arrange the word PERFECT in dictionary order = CEEFPRTHere,CEE(4!)=24CEF(4!)=24CEPF(3!)=6So the 55th word is CEPFERT.
Answer: b) CEPFERT
Solution:Let’s arrange the word PERFECT in dictionary order = CEEFPRTHere,CEE(4!)=24CEF(4!)=24CEPF(3!)=6So the 55th word is CEPFERT.
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