Output of python program | Set 13(Lists and Tuples) - GeeksforGeeks

16 Sep, 2020
Prerequisite: Lists and Tuples
1) What is the output of the following program?  
PYTHON
List = [True, 50, 10]List.insert(2, 5)   print(List, "Sum is: ", sum(List))
a) [True, 50, 10, 5] Sum is: 66 b) [True, 50, 5, 10] Sum is: 65 c) TypeError: unsupported operand type(s) for +: ‘int’ and ‘str’ d) [True, 50, 5, 10] Sum is: 66 
Ans. (d) Explanation: The List is initially has 3 elements. The insert() adds element 5 at index 2, moving element 10 at index 3 and the List becomes [True, 50, 5, 10]. Boolean has an integer value of 1, thus sum becomes 1 + 50 + 5 + 10 = 66.
2) What is the output of the following program?  
PYTHON
T = (1, 2, 3, 4, 5, 6, 7, 8)print(T[T.index(5)], end = " ")print(T[T[T[6]-3]-6])
a) 4 0 b) 5 8 c) 5 IndexError d) 4 1 
Ans. (b) Explanation: The inbuilt function index() returns the index of the element. T.index(5) = 4 and T[4] = 5. The other print statement has indexing of tuples, similar to that of Lists. T[6] = 7, T[6]-3 = 4, T[T[6]-3] = 5, T[T[6]-3]-6 = -1 and T[T[T[6]-3]-6], i.e. T[-1] = 8.
3) What is the output of the following program?  
PYTHON
L = [1, 3, 5, 7, 9]print(L.pop(-3), end = '  ')print(L.remove(L[0]), end = '  ')print(L)
a) 5 None [3, 7, 9] b) 5 1 [3, 7, 9] c) 5 1 [3, 7, 9] d) 5 None [1, 3, 7, 9] 
Ans. (a) Explanation: pop() will delete and return the element whose index was passed as parameter. L.pop(-3) will delete 5 and return 5, which is printed by print(). remove() does return any value, it’s a void function. L[0] = 1, L.remove(1) will delete 1 from the list and the list remains to be [3, 7, 9].
4) What is the output of the following program?  
PYTHON
def REVERSE(L):    L.reverse()    return(L)def YKNJS(L):    List = []    List.extend(REVERSE(L))    print(List) L = [1, 3.1, 5.31, 7.531]YKNJS(L)
a) [1, 3.1, 5.31, 7.531] b) [7.531, 5.31, 3.1, 1] c) IndexError d) AttributeError: ‘NoneType’ object has no attribute ‘REVERSE’ 
Ans. (b) Explanation: REVERSE() reverses the list and returns it. YKNJS() adds reverse of a list L to the empty list List. L = [1, 3.1, 5.31, 7.531], gets reversed and becomes [7.531, 5.31, 3.1, 1].
5) What is the output of the following program?  
PYTHON
from math import sqrtL1 = [x**2 for x in range(10)].pop()L1 + = 19print(sqrt(L1), end = " ")L1 = [x**2 for x in reversed(range(10))].pop()L1 + = 16print(int(sqrt(L1)))
a) 10.0 4.0 b) 4.3588 4 c) 10 .0 4 d) 10.0 0 
Ans. (c) Explanation: The first list compression will create list as [0, 1, 4, 9, 16, 25, 36, 49, 64, 81] and pop() will return 81. 81 + 19 = 100, whose square root is 10.0 and similarly in 2nd case pop() will return 0 due to the reversed range and integer value of square root of 16 is 4.
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RajuKumar19
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