How to create half of the string in uppercase and the other half in lowercase? - GeeksforGeeks

30 Mar, 2022
The first thing that we have to keep in my mind while solving this kind of problem is that the strings are immutable i.e,
If I am taking the following string
var string1 = "geeksforgeeks";
string1[0] = "G";

console.log(string1);
As strings are immutable, so we cannot change the character of the string, so the output of the above code will be the following.
Output:
geeksforgeeks
Approach:
There are several ways to solve this problem. Some of them are as follows.
Splitting the string into 2 different parts and changing the first part to the UPPERCASE and concatenating the new strings to get the output.
Create an empty string and add each character of the string to it using FOR loop.
Using the slicing property of strings to get the output.
Method 1: This method is implemented using 2 new variables.
Add the string into the variable.
Store the length of the string into a variable using string.length function.
Create two empty strings which are used in the future to store the newly created strings.
Use of for loops to traverse in the string.
Convert the first string to the upper case using toUpperCase().
Concatenate both of the strings to get the output.
C++
Python3
Javascript
#include <iostream>using namespace std; int main() {  string str = "geeksforgeeks",ans;  int len = str.length();     for(int i = 0;i<len;i++){    if(i<=len/2){      char a = toupper(str[i]);      ans.push_back(a);    }else      ans.push_back(str[i]);       }  cout<<ans;  return 0;} // This code is co ntributed by rohitsingh07052
import math string1 = 'geeksforgeeks'string1_len = len(string1)part_a = ''part_b = '' for i in range(int(math.ceil(string1_len // 2 + 1))):    part_a += string1[i] for i in range(int(math.ceil(string1_len // 2)) + 1,               string1_len):    part_b += string1[i] new_part_a = part_a.upper() changed_string = new_part_a + part_b print(changed_string) # This code is contributed by ukasp
<script>var string1 = 'geeksforgeeks';var string1_len = string1.length;var part_a = '';var part_b = ''; for(var i=0 ; i<Math.ceil(string1_len/2) ; i++){    part_a+=string1[i];} for(var i=Math.ceil(string1_len/2) ; i<string1_len ; i++){    part_b+=string1[i];} var new_part_a = part_a.toUpperCase(); var changed_string = new_part_a + part_b; console.log(changed_string);</script>
Output:
GEEKSFOrgeeks
Time Complexity: O(N)
Auxiliary Space: O(1)
Method 2: This method is implemented using a single new variable.
Add the string into the variable.
Store the length of the string into a variable using string.length function.
Create an empty string that is used in the future to store the newly created string.
Use of for loops to traverse the string.
Log the final string to get the output.
Javascript
Python3
<script>var string1 = 'gfg';var string1_len = string1.length;var changed_string = ''; for(var i=0 ; i<Math.ceil(string1_len/2) ; i++){    changed_string+=string1[i].toUpperCase();} for(var i=Math.ceil(string1_len/2) ; i<string1_len ; i++){    changed_string+=string1[i];} console.log(changed_string);</script>
import math string1 = 'gfg';string1_len = len(string1) changed_string = '' for i in range(math.ceil(string1_len/2)):    changed_string += string1[i].upper(); for i in range(math.ceil(string1_len/2), string1_len):    changed_string += string1[i] print(changed_string) # This code is contributed by avanitrachhadiya2155
Output:
GFg
Time Complexity: O(N)
Auxiliary Space: O(1)
Method 3: This method is implemented using the JavaScript Slice property.
Add the string into the variable.
Store the length of the string into a variable using string.length function.
Store the ceil value of half of the length of the string to the new variable.
Create 2 empty strings which are used in the future to store the newly created strings.
Add string to the variables using string slicing property.
Convert the first string to the upper case using toUpperCase().
Concatenate both of the strings to get the output.
Python3
Javascript
import math string1 = 'geeks for geeks' string1_len = len(string1) half_string = math.ceil(string1_len/2) part_a = ''part_b = '' part_a = string1[:half_string]new_part_a = part_a.upper() part_b = string1[half_string:string1_len] changed_string = new_part_a+part_b print(changed_string) # This code is contributed by rag2127
<script>var string1 = 'geeks for geeks';var string1_len = string1.length;var half_string = Math.ceil(string1_len/2);var part_a;var part_b; part_a = string1.slice(0,half_string);var new_part_a = part_a.toUpperCase();part_b = string1.slice(half_string,string1_len); var changed_string = new_part_a+part_b; console.log(changed_string);</script>
Output:
GEEKS FOr geeks
Time Complexity: O(N)
Auxiliary Space: O(N)
In these ways, you can solve these kinds of problems.
ukasp
avanitrachhadiya2155
rag2127
rohitsingh07052
rohitkumarsinghcna
javascript-string
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