Python | Program to accept the strings which contains all vowels

23 Jun, 2022
Given a string, the task is to check if every vowel is present or not. We consider a vowel to be present if it is present in upper case or lower case. i.e. ‘a’, ‘e’, ‘i’.’o’, ‘u’ or ‘A’, ‘E’, ‘I’, ‘O’, ‘U’ . Examples : 
Input : geeksforgeeks
Output : Not Accepted
All vowels except 'a','i','u' are not present

Input : ABeeIghiObhkUul
Output : Accepted
All vowels are present
Approach : Firstly, create set of vowels using set() function. Check for each character of the string is vowel or not, if vowel then add into the set s. After coming out of the loop, check length of the set s, if length of set s is equal to the length of the vowels set then string is accepted otherwise not. Below is the implementation : 
Python3
# Python program to accept the strings# which contains all the vowels # Function for check if string# is accepted or notdef check(string) :     string = string.lower()     # set() function convert "aeiou"    # string into set of characters    # i.e.vowels = {'a', 'e', 'i', 'o', 'u'}    vowels = set("aeiou")     # set() function convert empty    # dictionary into empty set    s = set({})     # looping through each    # character of the string    for char in string :         # Check for the character is present inside        # the vowels set or not. If present, then        # add into the set s by using add method        if char in vowels :            s.add(char)        else:            pass                 # check the length of set s equal to length    # of vowels set or not. If equal, string is     # accepted otherwise not    if len(s) == len(vowels) :        print("Accepted")    else :        print("Not Accepted")  # Driver codeif __name__ == "__main__" :         string = "SEEquoiaL"     # calling function    check(string)
Accepted
Alternate Implementation :
Python3
def check(string):    string = string.replace(' ', '')    string = string.lower()    vowel = [string.count('a'), string.count('e'), string.count(        'i'), string.count('o'), string.count('u')]     # If 0 is present int vowel count array    if vowel.count(0) > 0:        return('not accepted')    else:        return('accepted')  # Driver codeif __name__ == "__main__":     string = "SEEquoiaL"     print(check(string))
accepted
Alternate Implementation 2.0 : 
Python3
# Python program for the above approachdef check(string):    if len(set(string.lower()).intersection("aeiou")) >= 5:        return ('accepted')    else:        return ("not accepted")  # Driver codeif __name__ == "__main__":    string = "geeksforgeeks"    print(check(string))
not accepted
Alternate Implementation 3.0 (Using Regular Expressions):
Compile a regular expression using compile() for “character is not a, e, i, o and u”.Use re.findall() to fetch the strings satisfying the above regular expression.Print output based on the result.
Python3
#import libraryimport re sampleInput = "aeioAEiuioea" # regular expression to find the strings# which have characters other than a,e,i,o and uc = re.compile('[^aeiouAEIOU]') # use findall() to get the list of strings# that have characters other than a,e,i,o and u.if(len(c.findall(sampleInput))):    print("Not Accepted")  # if length of list > 0 then it is not acceptedelse:    print("Accepted")  # if length of list = 0 then it is accepted
Accepted
Alternate Implementation 4.0 (using data structures):
Python3
# Python | Program to accept the strings which contains all vowels  def all_vowels(str_value):     new_list = [char for char in str_value.lower() if char in 'aeiou']     if new_list:         dic, lst = {}, []         for char in new_list:            dic['a'] = new_list.count('a')            dic['e'] = new_list.count('e')            dic['i'] = new_list.count('i')            dic['o'] = new_list.count('o')            dic['u'] = new_list.count('u')         for i, j in dic.items():            if j == 0:                lst.append(i)         if lst:            return f"All vowels except {','.join(lst)} are not presant"        else:            return 'All vowels are present'     else:        return "No vowels presant"  # function-callstr_value = "geeksforgeeks"print(all_vowels(str_value)) str_value = "ABeeIghiObhkUul"print(all_vowels(str_value)) # contribute by saikot
All vowels except a,i,u are not presant
All vowels are present
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