math.Pow() Function in Golang With Examples - GeeksforGeeks

13 Apr, 2020
Go language provides inbuilt support for basic constants and mathematical functions to perform operations on the numbers with the help of the math package. You can find the base-a exponential of b(a**b)with the help of Pow() function provided by the math package. So, you need to add a math package in your program with the help of the import keyword to access Pow() function.
Syntax:
func Pow(a, b float64) float64
If Pow(a, ±0), then this method will return 1 for any a.
If Pow(1, b), then this method will return 1 for any b.
If Pow(a, 1), then this method will return a for any a.
If Pow(NaN, b), then this method will return NaN.
If Pow(a, NaN), then this method will return NaN.
If Pow(±0, b), then this method will return ± Inf for b an odd integer < 0.
If Pow(±0, -Inf), then this method will return +Inf.
If Pow(±0, +Inf), then this method will return +0.
If Pow(±0, b), then this method will return +Inf for finite b < 0 and not an odd integer.
If Pow(±0, b), then this method will return ± 0 for b an odd integer > 0.
If Pow(±0, b), then this method will return +0 for finite b > 0 and not an odd integer.
If Pow(+1, ±Inf), then this method will return 1.
If Pow(a, +Inf), then this method will return +Inf for |a| > 1.
If Pow(a, -Inf), then this method will return +0 for |a| > 1.
If Pow(a, +Inf), then this method will return +0 for |a| < 1.
If Pow(a, -Inf), then this method will return +Inf for |a| < 1.
If Pow(+Inf, b), then this method will return +Inf for b > 0.
If Pow(+Inf, b), then this method will return +0 for b < 0.
If Pow(-Inf, b), then this method will return Pow(-0, -b).
If Pow(a, b), then this method will return NaN for finite a < 0 and finite non-integer b.
Example 1:
// Golang program to illustrate// the use of math.Pow() function  package main  import (    "fmt"    "math")  // Main functionfunc main() {      // Finding the base-a exponential of b    // Using Pow() function    res_1 := math.Pow(3, 5)    res_2 := math.Pow(math.Inf(1), 3)    res_3 := math.Pow(2, 0)    res_4 := math.Pow(1, math.NaN())    res_5 := math.Pow(-0, math.Inf(-1))      // Displaying the result    fmt.Printf("Result 1: %.1f", res_1)    fmt.Printf("\nResult 2: %.1f", res_2)    fmt.Printf("\nResult 3: %.1f", res_3)    fmt.Printf("\nResult 4: %.1f", res_4)    fmt.Printf("\nResult 5: %.1f", res_5)}
Output:
Result 1: 243.0
Result 2: +Inf
Result 3: 1.0
Result 4: 1.0
Result 5: +Inf

Example 2:
// Golang program to illustrate// the use of math.Pow() function  package main  import (    "fmt"    "math")  // Main functionfunc main() {       // Finding the base-a exponential of b    // Using Pow() function    nvalue_1 := math.Pow(3, 4)    nvalue_2 := math.Pow(5, 6)      // Sum of the given numbers    res := nvalue_1 + nvalue_2    fmt.Printf("%.3f + %.3f = %.3f",            nvalue_1, nvalue_2, res)  }
Output:
81.000 + 15625.000 = 15706.000
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