Sort 3 Integers without using if condition or using only max() function

23 Jun, 2022
Given three inte­gers, print them in sorted order with­out using if condition.Examples :  
Input  : a = 3, b = 2, c = 9
Output : 2 3 9

Input  : a = 4, b = 1, c = 9
Output : 1 4 9
 
Approach : 1. Find the max­i­mum of a, b, c using max() function. 3. Mul­ti­ply all inte­gers by –1. Again find Min­i­mum of –a, –b, –c using max() function. 4. Add the Max and Min from above steps and sub­tract the sum from (a+b+c). It gives us mid­dle element.It works for negative numbers also. 
C++
Java
Python3
C#
PHP
Javascript
// C++ program to print three numbers// in sorted order using max function#include<bits/stdc++.h>using namespace std; void printSorted(int a, int b, int c){    // Find maximum element    int get_max = max(a, max(b, c));     // Find minimum element    int get_min = -max(-a, max(-b, -c));     int get_mid = (a + b + c)                 - (get_max + get_min);     cout << get_min << " " << get_mid        << " " << get_max;} // Driver codeint main(){    int a = 4, b = 1, c = 9;    printSorted(a, b, c);    return 0;}
// Java program to print three numbers// in sorted order using max functionclass GFG{         static void printSorted(int a, int b, int c)    {        // Find maximum element        int get_max = Math.max(a, Math.max(b, c));             // Find minimum element        int get_min = -Math.max(-a, Math.max(-b, -c));             int get_mid = (a + b + c)                      - (get_max + get_min);             System.out.print(get_min + " " + get_mid                                + " " + get_max);    }         // Driver code    public static void main(String[] args)    {                 int a = 4, b = 1, c = 9;                 printSorted(a, b, c);    }} // This code is contributed by Anant Agarwal.
# Python3 program to print three numbers# in sorted order using max function def printSorted(a, b, c):         # Find maximum element    get_max = max(a, max(b, c))     # Find minimum element    get_min = -max(-a, max(-b, -c))     get_mid = (a + b + c) - (get_max + get_min)     print(get_min, " " , get_mid, " " , get_max) # Driver Codea, b, c = 4, 1, 9printSorted(a, b, c) # This code is contributed by Anant Agarwal.
// C# program to print three numbers// in sorted order using max functionusing System; class GFG {         static void printSorted(int a, int b, int c)    {        // Find maximum element        int get_max = Math.Max(a, Math.Max(b, c));             // Find minimum element        int get_min = -Math.Max(-a, Math.Max(-b, -c));             int get_mid = (a + b + c) -                      (get_max + get_min);         Console.Write(get_min + " " + get_mid                          + " " + get_max);    }         // Driver code    public static void Main()    {        int a = 4, b = 1, c = 9;                 printSorted(a, b, c);    }} // This code is contributed by nitin mittal.
<?php// PHP program to print three numbers// in sorted order using max function function printSorted($a, $b, $c){         // Find maximum element    $get_max = max($a, max($b, $c));     // Find minimum element    $get_min = -max(-$a, max(-$b, -$c));     $get_mid = ($a + $b + $c) -               ($get_max + $get_min);     echo $get_min , " " , $get_mid, " " , $get_max;}     // Driver Code    $a = 4;    $b = 1;    $c = 9;    printSorted($a, $b,$c); // This code is contributed by nitin mittal.?>
<script> // JavaScript program for the above approachfunction printSorted(a, b, c)    {             // Find maximum element        let get_max = Math.max(a, Math.max(b, c));               // Find minimum element        let get_min = -Math.max(-a, Math.max(-b, -c));               let get_mid = (a + b + c)                       - (get_max + get_min);               document.write(get_min + " " + get_mid                                + " " + get_max);    } // Driver Code          let a = 4, b = 1, c = 9;             printSorted(a, b, c); // This code is contributed by splevel62.</script>
Output:  
 1 4 9
Time Complexity: O(1)Auxiliary Space: O(1)
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