Prim’s MST for Adjacency List Representation

It is similar to the previous algorithm. Here the only difference is, the Graph G(V, E) is represented by an adjacency list.
Time complexity adjacency list representation is O(E log V).
Input:
The cost matrix:

Output:
Edge: A--B And Cost: 1
Edge: B--E And Cost: 2
Edge: A--C And Cost: 3
Edge: A--D And Cost: 4
Edge: E--F And Cost: 2
Edge: F--G And Cost: 3
Total Cost: 15
prims(g: Graph, start)
Input −  The graph g and the seed vertex named ‘start’
Output − The Tree after adding edges.
Begin
   create two set B, N
   add the start node in B set.

   for all vertices u in graph g do
      add u in the set N
   done

   while B ≠ N do
      min := ∞
      for all vertices u in graph g do
         if u is in the set B then
            for all vertices v which are adjacent with u do
               if v is in (N – B) then
                  if min > cost of uv edge then
                     min := cost of uv edge
                     parent := u
                     node := v
            done
      done

      insert node in the B set
      add the edge starting from parent to node in the tree
   done

   return the tree
End
#include<iostream>
#include<list>
#include<set>
using namespace std;

typedef struct nodes {
   int dest;
   int cost;
}node;

class Graph {
   int n;
   list<node> *adjList;
   private:
      void showList(int src, list<node> lt) {
         list<node> :: iterator i;
         node tempNode;

         for(i = lt.begin(); i != lt.end(); i++) {
            tempNode = *i;
            cout << "(" << src << ")---("<<tempNode.dest << "|"<<tempNode.cost<<") ";
         }
         cout << endl;
      }

   public:
      Graph() {
         n = 0;
      }

      Graph(int nodeCount) {
         n = nodeCount;
         adjList = new list<node>[n];
      }

      void addEdge(int source, int dest, int cost) {
         node newNode;
         newNode.dest = dest;
         newNode.cost = cost;
         adjList[source].push_back(newNode);
      }

      void displayEdges() {
         for(int i = 0; i<n; i++) {
            list<node> tempList = adjList[i];
            showList(i, tempList);
         }
      }

      friend Graph primsMST(Graph g, int start);
};

set<int> difference(set<int> first, set<int> second) {
   set<int> :: iterator it;
   set<int> res;

   for(it = first.begin(); it != first.end(); it++) {
      if(second.find(*it) == second.end())
         res.insert(*it);    //add those item which are not in the second list
   }

   return res;    //the set (first-second)
}

Graph primsMST(Graph g, int start) {
   int n = g.n;
   set<int> B, N, diff;
   Graph tree(n);        //make tree with same node as graph
   B.insert(start);     //insert start node in the B set

   for(int u = 0; u<n; u++) {
      N.insert(u); //add all vertices in the N set
   }

   while(B != N) {
      int min = 9999;             //set as infinity
      int v, par;
      diff = difference(N, B);    //find the set N - B

      for(int u = 0; u < n; u++) {
         if(B.find(u) != B.end()) {
            list<node>::iterator it;
            for(it = g.adjList[u].begin(); it != g.adjList[u].end(); it++) {
               if(diff.find(it->dest) != diff.end()) {
                  if(min > it->cost) {
                     min = it->cost;    //update cost
                     par = u;
                     v = it->dest;
                  }
               }
            }
         }
      }

      B.insert(v);
      tree.addEdge(par, v, min);
      tree.addEdge(v, par, min);
   }
   return tree;
}

main() {
   Graph g(7), tree(7);
   g.addEdge(0, 1, 1);
   g.addEdge(0, 2, 3);
   g.addEdge(0, 3, 4);
   g.addEdge(0, 5, 5);
   g.addEdge(1, 0, 1);
   g.addEdge(1, 3, 7);
   g.addEdge(1, 4, 2);
   g.addEdge(2, 0, 3);
   g.addEdge(2, 4, 8);
   g.addEdge(3, 0, 4);
   g.addEdge(3, 1, 7);
   g.addEdge(4, 1, 2);
   g.addEdge(4, 2, 8);
   g.addEdge(4, 5, 2);
   g.addEdge(4, 6, 4);
   g.addEdge(5, 0, 5);
   g.addEdge(5, 4, 2);
   g.addEdge(5, 6, 3);
   g.addEdge(6, 4, 4);
   g.addEdge(6, 5, 3);

   tree = primsMST(g, 0);
   tree.displayEdges();
}
Edge: A--B And Cost: 1
Edge: B--E And Cost: 2
Edge: A--C And Cost: 3
Edge: A--D And Cost: 4
Edge: E--F And Cost: 2
Edge: F--G And Cost: 3
Total Cost: 15