Java.lang.Integer class and its methods - GeeksforGeeks

21 Jun, 2021
java.lang.Integer wraps integer data type to an object containing a single field having datatype is int. Constructors :  
Integer (int arg) : Constructs integer object representing an int value.
Integer (String arg) : Constructs string object representing a string value.
Integer class methods:  
toBinaryString() : java.lang.Integer.toBinaryString() method converts the integer value of argument its Binary representation as a string. Syntax  
toBinaryString() : java.lang.Integer.toBinaryString() method converts the integer value of argument its Binary representation as a string. Syntax  
public static String toBinaryString(int arg)
Parameters
arg : integer argument whose Binary representation we want
Return
Binary representation of the argument.
 bitcount() : java.lang.Integer.bitCount() method converts the integer value of argument to Binary string and then returns the no. of 1’s present in it. Syntax  
 
bitcount() : java.lang.Integer.bitCount() method converts the integer value of argument to Binary string and then returns the no. of 1’s present in it. Syntax  
public static int bitCount(int arg)
Parameters
arg : integer argument whose no. of 1's bit we want
Return
no. of 1's bit present in the argument.
 toHexString() : java.lang.Integer.toHexString() method converts the integer value of argument its Hexadecimal representation as a string. Syntax  
 
toHexString() : java.lang.Integer.toHexString() method converts the integer value of argument its Hexadecimal representation as a string. Syntax  
public static String toHexString(int arg)
Parameters
arg : integer argument whose Hexadecimal representation we want
Return
Hexadecimal representation of the argument.
 toOctalString() : java.lang.Integer.toHexString() method converts the integer value of argument its Hexadecimal representation as a string. Syntax  
 
toOctalString() : java.lang.Integer.toHexString() method converts the integer value of argument its Hexadecimal representation as a string. Syntax  
public static String toHexString(int arg)
Parameters
arg : integer argument whose Hexadecimal representation we want
Return
Hexadecimal representation of the argument.
 parsedatatype() : java.lang.Integer.parse__() method returns primitive data type of the argumented String value. Radix (r) means numbering format used is at base ‘r’ to the string. Syntax  
 
parsedatatype() : java.lang.Integer.parse__() method returns primitive data type of the argumented String value. Radix (r) means numbering format used is at base ‘r’ to the string. Syntax  
public static int parseInt(String arg)
              or
public static int parseInt(String arg, int r)
Parameters
arg : argument passed
r : radix
Return
primitive data type of the argumented String value.
 
 
JAVA
// Java code explaining the Integer Class methods// bitcount(), toBinaryString(), toHexString(), toOctalString(), parse__()import java.lang.*;public class NewClass{    public static void main(String args[])    {        int x = 15, count1, y = 128, count2;         // Use of toBinaryString() method        System.out.println("Binary string of 16 : "                           + Integer.toBinaryString(x));        System.out.println("Binary string of 100 : "                           + Integer.toBinaryString(y));         // Use of bitCount() method        count1 = Integer.bitCount(x);        System.out.println("\n 1's bit present in 16 : "+count1);         count2 = Integer.bitCount(y);        System.out.println(" 1's bit present in 100 : "+count2);         // Use of toHexString() method        System.out.println("\nHexadecimal string of 16 : "                           + Integer.toHexString(x));        System.out.println("Hexadecimal string of 100 : "                           + Integer.toHexString(y));        System.out.println("");         // Use of toOctalString() method        System.out.println("Octal string of 16 : "                           + Integer.toOctalString(x));        System.out.println("Octal string of 100 : "                           + Integer.toOctalString(y) + "\n");         // Use of parseInt() method        int i1 =Integer.parseInt("34");        int i2 = Integer.parseInt("15",8);        double d = Double.parseDouble("54");         System.out.println(i1);        System.out.println(i2);        System.out.println(d);    }}
Output:  
Output:  
Binary string of 16   : 1111
Binary string of 100  : 10000000

 1's bit present in 16   : 4
 1's bit present in 100  : 1

Hexadecimal string of 16   : f
Hexadecimal string of 100  : 80

Octal string of 16   : 17
Octal string of 100  : 200

34
13
54.0
 hashCode() : java.lang.Integer.hashCode() method returns the hashCode value of the argument passed. Syntax:  
 
hashCode() : java.lang.Integer.hashCode() method returns the hashCode value of the argument passed. Syntax:  
public int hashCode(arg)
Parameters:
arg - the argument whose hashCode value we need
Returns:
hashCode value of arg
 lowestOneBit() : java.lang.Integer.lowestOneBit() method first convert int to Binary, then it looks for set(1) bit present at lowest position then it reset rest of the bits e.g arg = 36 It,s Binary Representation = 0010 0100 It considers lowest bit(at 3) and now reset rest of the bits i.e. 0000 0100 so result = 0100 i.e. 4 Syntax:  
 
lowestOneBit() : java.lang.Integer.lowestOneBit() method first convert int to Binary, then it looks for set(1) bit present at lowest position then it reset rest of the bits e.g arg = 36 It,s Binary Representation = 0010 0100 It considers lowest bit(at 3) and now reset rest of the bits i.e. 0000 0100 so result = 0100 i.e. 4 Syntax:  
public static int lowestOneBit(int arg)
Parameters:
arg - argument passed
Returns:
integer value by only considering lowest 1 bit in the argument.
 highestOneBit() : java.lang.Integer.highestOneBit() method first convert int to Binary, then it looks for set(1) bit present at lowest position then it reset rest of the bits e.g arg = 36 It,s Binary Representation = 0010 0100 It considers highest bit(at 6) and now reset rest of the bits i.e. 0001 0000 so result = 10000 i.e. 32 Syntax:  
 
highestOneBit() : java.lang.Integer.highestOneBit() method first convert int to Binary, then it looks for set(1) bit present at lowest position then it reset rest of the bits e.g arg = 36 It,s Binary Representation = 0010 0100 It considers highest bit(at 6) and now reset rest of the bits i.e. 0001 0000 so result = 10000 i.e. 32 Syntax:  
public static int highestOneBit(int arg)
Parameters:
arg - argument passed
Returns:
integer value by only considering highest 1 bit in the argument.
 
 
JAVA
// Java program explaining Integer class methods// hashcode(), lowestOneBit(), highestOneBit()import java.lang.*;public class NewClass{    public static void main(String[] args)    {        // Use of incrementExact() method        int f1 = 30, f2 = -56;        f1 = Integer.hashCode(f1);        System.out.println("HashCode value of f1 : "+f1);         f2 = Integer.hashCode(f2);        System.out.println("HashCode value of f2 : "+f2);         System.out.println("\nBinary representation of 30 : "                           + Integer.toBinaryString(f1));         // Use of lowestOneBit() method        // Here it considers 00010 i.e. 2        System.out.println("lowestOneBit of 30 : "                           + Integer.lowestOneBit(f1));          // Use of highestOneBit() method        // Here it considers 10000 i.e. 16        System.out.println("highestOneBit of 30 : "                           + Integer.highestOneBit(f1));     }}
Output:  
Output:  
HashCode value of f1 : 30
HashCode value of f2 : -56

Binary representation of 30 : 11110
lowestOneBit of 30 : 2
highestOneBit of 30 : 16
 numberOfTrailingZeros() : java.lang.Integer.numberOfTrailingZeros() method converts int value to Binary then considers the lowest one bit and return no. of zero bits following it. e.g arg = 36 It,s Binary Representation = 0010 0100 It considers highest bit(at 6) i.e. 0001 0000 so result = 4 Syntax:  
 
numberOfTrailingZeros() : java.lang.Integer.numberOfTrailingZeros() method converts int value to Binary then considers the lowest one bit and return no. of zero bits following it. e.g arg = 36 It,s Binary Representation = 0010 0100 It considers highest bit(at 6) i.e. 0001 0000 so result = 4 Syntax:  
public static int numberOfTrailingZeros(int arg)
Parameters:
arg - the argument
Returns:
Number of zero bits following the 1 bit at lowest position
 numberOfLeadingZeros() : java.lang.Integer.numberOfLeadingZeros() method converts int value to Binary then considers the highest one bit and return no. of zero bits preceding it. e.g arg = 36 It,s Binary Representation = 0010 0100 It considers highest bit(at 6) i.e. 0010 0000 so result = 32 – 6 i.e. 26 Syntax:  
 
numberOfLeadingZeros() : java.lang.Integer.numberOfLeadingZeros() method converts int value to Binary then considers the highest one bit and return no. of zero bits preceding it. e.g arg = 36 It,s Binary Representation = 0010 0100 It considers highest bit(at 6) i.e. 0010 0000 so result = 32 – 6 i.e. 26 Syntax:  
public static int numberOfLeadingZeros(int arg)
Parameters:
arg - the argument
Returns:
Number of zero bits preceding the 1 bit at highest position
 reverse() : java.lang.Integer.reverse() method first find 2’s compliment of the argument passed and reverses the order of bits in the 2’s compliment. Syntax:  
 
reverse() : java.lang.Integer.reverse() method first find 2’s compliment of the argument passed and reverses the order of bits in the 2’s compliment. Syntax:  
public static int reverse(int arg)
Parameters:
arg - the argument 
Returns:
int with reverse order of bits in 2's compliment of the passed argument
 
 
JAVA
// Java program explaining Integer class methods// numberOfTrailingZeros(), numberOfLeadingZeros(), reverse()import java.lang.*;public class NewClass{    public static void main(String[] args)    {        int f1 = 30;         // Binary representation of int arg for your understanding        System.out.println("Binary representation of 30 : "                           + Integer.toBinaryString(f1));         // Use of numberOfTrailingZeros() method        // No. of zeros following 1 in 00010 = 1        System.out.println("\nNo. Of Trailing Zeros : "                           + Integer.numberOfTrailingZeros(f1));         // Use of highestOneBit() method        // No. of zeros following 1 in 10000 i.e. 32 - 5 = 27        System.out.println("\nNo. Of Leading Zeros : "                           + Integer.numberOfLeadingZeros(f1));         // Use of Reverse() method        System.out.println("\nReverse : " + Integer.reverse(f1));    }}
Output:  
Output:  
Binary representation of 30 : 11110

No. Of Trailing Zeros : 1

No. Of Leading Zeros  : 27

Reverse : 2013265920
 
 
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