Number of words in a camelcase sequence

03 May, 2021
CamelCase is the sequence of one or more than one words having the following properties:  
It is a concatenation of one or more words consisting of English letters.All letters in the first word are lowercase.For each of the subsequent words, the first letter is uppercase and rest of the letters are lowercase.
It is a concatenation of one or more words consisting of English letters.
All letters in the first word are lowercase.
For each of the subsequent words, the first letter is uppercase and rest of the letters are lowercase.
Given a CamelCase sequence represented as a string. The task is to find the number of words in the CamelCase sequence. Examples:  
Input : str = "geeksForGeeks"
Output : 3

Input : str = "iGotAnInternInGeeksForGeeks"
Output : 8
 
Approach: As it is already known that the sequence is CamelCase, so it can be said that the number of words in the sequence will be one more than the number of uppercase letters.  
Iterate the sequence from the 2nd letter to the end of the sequence.
No. of words will be equal to uppercase letters+1 during the 1st step iteration.
Below is the implementation of the above approach:  
C++
Java
Python3
C#
Javascript
// CPP code to find the count of words// in a CamelCase sequence#include <bits/stdc++.h>using namespace std; // Function to find the count of words// in a CamelCase sequenceint countWords(string str){    int count = 1;     for (int i = 1; i < str.length() - 1; i++) {        if (isupper(str[i]))            count++;    }     return count;} // Driver codeint main(){    string str = "geeksForGeeks";     cout << countWords(str);     return 0;}
// Java code to find the count of words// in a CamelCase sequenceclass solution{ // Function to find the count of words// in a CamelCase sequencestatic int countWords(String str){    int count = 1;     for (int i = 1; i < str.length() - 1; i++) {        if (str.charAt(i)>=65&&str.charAt(i)<=90)            count++;    }     return count;} // Driver codepublic static void main(String args[]){    String str = "geeksForGeeks";     System.out.print( countWords(str)); }}//contributed by Arnab Kundu
# Python code to find the count of words# in a CamelCase sequence # Function to find the count of words# in a CamelCase sequencedef countWords(str):    count = 1    for i in range(1, len(str) - 1):        if (str[i].isupper()):            count += 1     return count # Driver codestr = "geeksForGeeks";print(countWords(str)) # This code is contributed# by sahishelangia
// C# code to find the count of words// in a CamelCase sequenceusing System;     class GFG{ // Function to find the count of words// in a CamelCase sequencestatic int countWords(String str){    int count = 1;     for (int i = 1; i < str.Length - 1; i++)    {        if (str[i] >= 65 && str[i] <= 90)            count++;    }     return count;} // Driver codepublic static void Main(String []args){    String str = "geeksForGeeks";     Console.Write(countWords(str)); }} // This code contributed by Rajput-Ji
<script> // Javascript code to find the count of words// in a CamelCase sequence // Function to find the count of words// in a CamelCase sequencefunction countWords(str){    let count = 1;     for (let i = 1; i < str.length - 1; i++) {        if (str[i]>= 'A' && str[i]<= 'Z')            count++;    }     return count;}  // driver program         let str = "geeksForGeeks";     document.write( countWords(str));    </script>
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