Minimum Spanning Tree using Priority Queue and Array List

05 Nov, 2021
Given a bi-directed weighted (positive) graph without self-loops, the task is to generate the minimum spanning tree of the graph.Examples:  
Input: N = 9, E = 14, edges = {{0, 1, 4}, {0, 7, 8}, {1, 2, 8}, {1, 7, 11}, {2, 3, 7}, {2, 8, 2}, {2, 5, 4}, {3, 4, 9}, {3, 5, 14}, {4, 5, 10}, {5, 6, 2}, {6, 7, 1}, {6, 8, 6}, {7, 8, 7}} Output: ((A, B), Cost) ((6, 7), 1) ((6, 5), 2) ((1, 0), 4) ((2, 3), 7) ((5, 2), 4) ((3, 4), 9) ((2, 1), 8) ((2, 8), 2)  
An undirected graph consisting of all the vertices V and (V-1) edges has been generatedInput: N = 6, E = 14, edges = {{0, 2, 103}, {0, 1, 158}, {0, 2, 2}, {0, 5, 17}, {1, 3, 42}, {2, 4, 187}, {3, 0, 14}, {3, 2, 158}, {3, 5, 106}, {3, 4, 95}, {5, 1, 144}, {5, 2, 194}, {5, 3, 118}, {5, 3, 58}} Output: ((A, B), Cost) ((0, 2), 2) ((0, 3), 14) ((0, 5), 17) ((3, 1), 42) ((3, 4), 95)  
 
Approach  
First, the edge having minimum cost/weight is found in the given graph.
The two initial vertices (vertex A, B of minimum cost edge) is added to visited/added set.
Now, all the connected edges with newly added vertex are added to priority queue.
The least cost vertex (add all the connected edges of pop vertex to priority queue) is popped from the priority queue and repeat until number of edges is equal to vertices-1.
By using priority queue time complexity will be reduced to (O(E log V)) where E is the number of edges and V is the number of vertices.
Pair class is also used to store the weights.
Below is the implementation of the above approach: 
Java
// Java implementation of the approachimport java.io.*;import java.util.*;import java.lang.Comparable;public class MST {     // Pair class with implemented comparable    static class Pair<U extends Comparable<U>,                                V extends Comparable<V> >        implements Comparable<Pair<U, V> > {         public final U a;        public final V b;         private Pair(U a, V b)        {            this.a = a;            this.b = b;        }         @Override        public boolean equals(Object o)        {            if (this == o)                return true;            if (o == null || getClass() != o.getClass())                return false;             Pair<?, ?> pair = (Pair<?, ?>)o;            if (!a.equals(pair.a))                return false;            return b.equals(pair.b);        }         // Overriding so that objects in map        // could find the object key        @Override        public int hashCode()        {            return 31 * a.hashCode() + b.hashCode();        }         @Override        public String toString()        {            return "(" + a + ", " + b + ")";        }         @Override        public int compareTo(Pair<U, V> o)        {            return getV().compareTo(o.getV());        }        private U getU()        {            return a;        }        private V getV()        {            return b;        }    }     static class Graph {         int vertices;        ArrayList[] edges;         // This variable keeps the least cost edge        static Pair<Pair<Integer, Integer>,                    Integer>            minCostEdge;         Graph(int vertices)        {            minCostEdge = new Pair<>(new Pair<>(1, 1),                                     Integer.MAX_VALUE);            this.vertices = vertices;            edges = new ArrayList[vertices + 1];            for (int i = 0; i <= vertices; i++) {                edges[i]                    = new ArrayList<Pair<Integer, Integer> >();            }        }         void addEdge(int a, int b, int weight)        {            edges[a].add(new Pair<>(b, weight));             // Since its undirected, adding the            // edges to both the vertices            edges[b].add(new Pair<>(a, weight));            if (weight < minCostEdge.b) {                minCostEdge                    = new Pair<>(new Pair<>(a, b), weight);            }        }         void MST()        {             // Priority queue for applying heap            PriorityQueue<Pair<Pair<Integer, Integer>,                               Integer> >                priorityQueue                = new PriorityQueue<>();             // Adding all the connected vertices            // of MinCostEdge vertex A to PQ            Iterator<Pair<Integer, Integer> > iterator                = edges[minCostEdge.a.a].listIterator();            while (iterator.hasNext()) {                Pair<Integer, Integer> pair                    = iterator.next();                priorityQueue.add(                    new Pair<>(                        new Pair<>(minCostEdge.a.a, pair.a),                        pair.b));            }             // Adding all the connected vertices            // of MinCostEdge vertex B to PQ            iterator = edges[minCostEdge.a.b].listIterator();            while (iterator.hasNext()) {                Pair<Integer, Integer> pair = iterator.next();                priorityQueue.add(                    new Pair<>(                        new Pair<>(minCostEdge.a.b, pair.a),                        pair.b));            }             // Set to check vertex is added or not            Set<Integer> addedVertices = new HashSet<>();             // Set contains all the added edges and cost from source            Set<Pair<Pair<Integer, Integer>, Integer> > addedEdges                = new HashSet<>();             // Using the greedy approach to find            // the least costing edge to the GRAPH            while (addedEdges.size() < vertices - 1) {                 // Polling from priority queue                Pair<Pair<Integer, Integer>, Integer> pair                    = priorityQueue.poll();                 // Checking whether the vertex A is added or not                if (!addedVertices.contains(pair.a.a)) {                    addedVertices.add(pair.a.a);                    addedEdges.add(pair);                     // Adding all the connected vertices with vertex A                    iterator = edges[pair.a.a].listIterator();                    while (iterator.hasNext()) {                        Pair<Integer, Integer> pair1                            = iterator.next();                        priorityQueue.add(                            new Pair<>(                                new Pair<>(pair.a.a, pair1.a),                                pair1.b));                    }                }                 // Checking whether the vertex B is added or not                if (!addedVertices.contains(pair.a.b)) {                    addedVertices.add(pair.a.b);                    addedEdges.add(pair);                     // Adding all the connected vertices with vertex B                    iterator = edges[pair.a.b].listIterator();                    while (iterator.hasNext()) {                        Pair<Integer, Integer> pair1                            = iterator.next();                        priorityQueue                            .add(                                new Pair<>(                                    new Pair<>(pair.a.b, pair1.a),                                    pair1.b));                    }                }            }             // Printing the MST            Iterator<Pair<Pair<Integer, Integer>, Integer> > iterator1                = addedEdges.iterator();            System.out.println("((A"                               + ", "                               + "B)"                               + ", "                               + "Cost)");            while (iterator1.hasNext()) {                System.out.println(iterator1.next());            }        }    }     // Driver code    public static void main(String[] args) throws IOException    {        // Initializing the graph        Graph g = new Graph(9);        g.addEdge(0, 1, 4);        g.addEdge(0, 7, 8);        g.addEdge(1, 2, 8);        g.addEdge(1, 7, 11);        g.addEdge(2, 3, 7);        g.addEdge(2, 8, 2);        g.addEdge(2, 5, 4);        g.addEdge(3, 4, 9);        g.addEdge(3, 5, 14);        g.addEdge(4, 5, 10);        g.addEdge(5, 6, 2);        g.addEdge(6, 7, 1);        g.addEdge(6, 8, 6);        g.addEdge(7, 8, 7);         // Applying MST        g.MST();    }}
((A, B), Cost)
((6, 7), 1)
((6, 5), 2)
((1, 0), 4)
((2, 3), 7)
((5, 2), 4)
((3, 4), 9)
((2, 1), 8)
((2, 8), 2)
 
simranarora5sos
anikakapoor
abhishek0719kadiyan
MST
Data Structures
Graph
Java
Data Structures
Java
Graph
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