Program to check diagonal matrix and scalar matrix in C++

Given a matrix M[r][c], ‘r’ denotes number of rows and ‘c’ denotes number of columns such that r = c forming a square matrix. We have to find whether the given square matrix is diagonal and scalar matrix or not, if it is diagonal and scalar matrix then print yes in the result.
A square matrix m[][] will be diagonal matrix if and only if the elements of the except the main diagonal are zero.
Like in the given figure below −
Here, the elements in the red are main diagonal which are non-zero rest elements except the main diagonal are zero making it a Diagonal matrix.
Input: m[3][3] = { {7, 0, 0},
   {0, 8, 0},
   {0, 0, 9}}
Output: yes
Input: m[3][3] = {  {1, 2, 3},
   {0, 4, 0},
   {0, 0, 5}
}
Output: no
Start
Step 1 -> define macro of size 4
Step 2 -> declare function to check if matrix is diagonal or not
   bool ifdiagonal(int arr[size][size])
      Loop For int i = 0 and i < size and i++
         Loop for int j = 0 and j < size and j++
            IF ((i != j) & (arr[i][j] != 0))
               return false
            End
      End
   End
   return true
step 3 -> In main()
   Declare and set int arr[size][size] = { { 1, 0, 0, 0 },
      { 0, 1, 0, 0 },
      { 0, 0, 1, 0 },
      { 0, 0, 0, 1 }
   };
   IF (ifdiagonal(arr))
      Print its a diagonal matrix
   End
   Else
      Print its not a diagonal matrix
   End
Stop
#include <bits/stdc++.h>
#define size 4
using namespace std;
// check if matrix is diagonal matrix or not.
bool ifdiagonal(int arr[size][size]){
   for (int i = 0; i < size; i++)
   for (int j = 0; j < size; j++)

   if ((i != j) && (arr[i][j] != 0))
      return false;
      return true;
}
int main(){
   int arr[size][size] = { { 1, 0, 0, 0 },
      { 0, 1, 0, 0 },
      { 0, 0, 1, 0 },
      { 0, 0, 0, 1 }
   };
   if (ifdiagonal(arr))
      cout << "its a diagonal matrix" << endl;
   else
      cout << "its not a diagonal matrix" << endl;
   return 0;
}
its a diagonal matrix
 A square matrix m[][] is Scalar Matrix if the elements in the main diagonal are equal and the rest of the elements are zero.
Like in the given example below −
 
Here, the elements in the red are the diagonal elements which are same and rest elements are zero making it a Scalar Matrix. 
Input: m[3][3] = { {2, 0, 0},
   {0, 2, 0},
   {0, 0, 2} }
Output: yes
Input: m[3][3] = { {3, 0, 0},
   {0, 2, 0},
   {0, 0, 3} }
Output: no
Start
Step 1 -> Declare macro as #define size 4
Step 2 -> declare function to check matrix is scalar matrix or not.
   bool scalar(int arr[size][size])
      Loop For int i = 0 and i < size and i++
         Loop For int j = 0 and j < size and j++
            IF ((i != j) && (arr[i][j] != 0))
               return false
            End
      End
   End
   Loop for int i = 0 and i < size – 1 and i++
      If (arr[i][i] != arr[i + 1][i + 1])
         return false
      End
   End
   Return true
Step 3 -> In main()
   Declare array as int arr[size][size] = { { 2, 0, 0, 0 },
      { 0, 2, 0, 0 },
      { 0, 0, 2, 0 },
      { 0, 0, 0, 2 }
   }
   IF(scalar(arr))
      Print its a scalar matrix
   Else
      Print its not a scalar matrix
Stop
#include <bits/stdc++.h>
#define size 4
using namespace std;
// check matrix is scalar matrix or not.
bool scalar(int arr[size][size]){
   for (int i = 0; i < size; i++)
   for (int j = 0; j < size; j++)
      if ((i != j) && (arr[i][j] != 0))
         return false;
   for (int i = 0; i < size - 1; i++)
      if (arr[i][i] != arr[i + 1][i + 1])
         return false;
         return true;
}
int main(){
   int arr[size][size] = { { 2, 0, 0, 0 },
      { 0, 2, 0, 0 },
      { 0, 0, 2, 0 },
      { 0, 0, 0, 2 } };
   if (scalar(arr))
      cout << "its a scalar matrix" << endl;
   else
      cout << "its not a scalar matrix" << endl;
   return 0;
}
its a scalar matrix