English: So, we have 𝑠^(n)L[𝑓(𝑡)]−𝑠^(𝑛−1)𝑓(0)−𝑠^(𝑛−2)𝑓′(0)−⋯−𝑓^(𝑛−1)(0).
Telugu: కాబట్టి, మనకు s^(n)L[f(t)]−s^(n−1)f(0)−s^(n−2)f'(0)−−f^(n−1)(0) ఉన్నాయి.