English: So, let me call this v_(n) radius r_(n) is going to be $\frac{n\hslash}{mr}$ from equation 2 above and that is going to be $\frac{n^{2}\hslash^{2}4\pi\epsilon_{0}}{e^{2}}$∝n² and therefore, the energy of the system depends on n is going to be equal to E_(n) is going to be equal to $- \frac{e^{2}}{4\pi\epsilon_{0}r_{n}}$ in the nth orbital plus $\frac{1}{2}m{v_{n}^{2}}^{}$ which is the kinetic energy and that will come out to be let’s let’s let’s substitute the numbers $- \frac{e^{2}}{4\pi\epsilon_{0}}$ , $\frac{1}{r_{n}}$ is going to be which is equal to; there should be an m here this should be m v. So, there should be m² with E_(n) here and there should be $\frac{1}{2}v_{n}^{2}$ is nothing, $\frac{e^{4}}{\left( 4\pi\epsilon_{0} \right)^{2}n^{2}\hslash^{2}}$ that is the energy and this if you collect together comes out to be E_(n) = − me⁴/(4πϵ₀)²n²ℏ².
Telugu: కాబట్టి, దీనిని v_(n) గా పిలువనివ్వండి వ్యాసార్థం r_(n) అనేది $\frac{n\hslash}{mr}$గా ఉంటుంది పైన సమీకరణం 2 నుండి మరియు అది $\frac{n^{2}\hslash^{2}4\pi\epsilon_{0}}{e^{2}}$∝n² గా ఉంటుంది మరియు అందువల్ల వ్యవస్థ యొక్క శక్తి, n మీద ఆధారపడి ఉంటుంది.