English: Now $\left\lbrack {c^{'}}_{1}\ {c^{'}}_{2}\ \right\rbrack = \left\lbrack - \frac{y_{2}(x)f(x)}{W(y_{1},y_{2})(x)}\ \frac{y_{1}(x)f(x)}{W(y_{1},y_{2})(x)}\ \right\rbrack$ $\left\lbrack {c^{'}}_{1}\ {c^{'}}_{2}\ \right\rbrack = \left\lbrack - \frac{y_{2}(x)f(x)}{W(y_{1},y_{2})(x)}\ \frac{y_{1}(x)f(x)}{W(y_{1},y_{2})(x)}\ \right\rbrack$ This is my c^(′)₁ and c^(′)₂, having known this vector we can write integrating this will give me integrating this will provide $c_{2} = \frac{y_{1}(x)f(x)}{W(y_{1},y_{2})(x)}dx$.
Telugu: ఇప్పుడు $\left\lbrack {c^{'}}_{1}\ {c^{'}}_{2}\ \కుడి\rbrack = \left\lbrack - \frac{y_{2}(x)f(x)}{W(y_{1},y_{2})(x)}\ \frac{y_{1}(x)f(x)}{W(y_{1},y_{2})(x)}\కుడి\rbrack$ $\left\lbrack {c^{'}}_{1}\ {c^{'}}_{2}\ \right\rbrack = \left\lbrack - \frac{y_{2}(x)f(x)}{W(y_{1}, y_{2})(x)}\ \frac{y_{1}(x)f(x)}{W(y_{1},y_{2})(x)}\right\rbrack$ ఇది నా c^(')₁ మరియు c^(')₂, ఈ వెక్టార్ గురించి తెలిసిన తరువాత, దీనిని ఇంటిగ్రేట్ చేయడం ద్వారా $c_{2} = \frac{y_{1}(x)f(x)}{W(y_{1},y_{2})(x)}dx$.