English: So, I 1, which is the current through L 1 at 0 - was 0 and I 2 as 0 - was also 0 and just after the application the current step this will be L 2 / L 1 + L 2 × I s and I 2 of 0 + is L 1 / L 1 + L 2 × I s. So, from these and the final values, which can also be calculated quite easily for the final values in an inductor circuit, what is that we no voltage across an inductor equals 0 this is of course, assuming constant are fees wise constant in inputs this is for a constant input.
Telugu: కాబట్టి,L ₁ ద్వారా ప్రవహించే కరెంటు I₁, ఇది (0⁻) వద్ద కరెంట్ 0 గా ఉంటుంది మరియు I ₂ ( 0 ⁻) కూడా 0 మరియు ఈ కరెంట్ స్టెప్ ని వర్తించిన తర్వాత L ₂ / (L ₁ + L ₂ )× I _(s) మరియు I ₂ (0⁺ )= L ₁ /( L ₁ + L ₂ )× I _(s).