English: $\overrightarrow{\nabla} \times \overrightarrow{B} = \mu_{0}\overrightarrow{J}$ $\overrightarrow{\nabla} \times \overrightarrow{A} = \ \overrightarrow{B}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \left( \overrightarrow{B}.\overrightarrow{da} \right) = \phi$ $A_{z}(z) = \ \frac{\phi}{2}\ \frac{R^{2}}{\left( R^{2} + z^{2} \right)^{3/2}}$ So, I can write that A should be in the z direction, so the function of z on the axis and it should be there is mu 0 I, I will be replaced by now B dot d a which is the flux.
Telugu: $\overrightarrow{\nabla} \times \overrightarrow{B} = \mu_{0}\overrightrrow{J}$ $\overrightarrow{\nblla} \times \overirero{A} = \{2} {2} {2} {2} $A\  నేను ఇప్పుడు B డాట్ d a ద్వారా భర్తీ చేయబడతాను, ఇది ఫ్లక్స్.