English: So, I 1 of infinity will be R 2 / R 1 + R 2 × I s and I 2 of infinity would be R 1 / R 1 + R 2 × I s. So, from these and the time constant we can write down the functions for both I 1 and I 2.
Telugu: కాబట్టి, I ₁(∞)= R ₂ / (R ₁ + R ₂ )× I _(s) మరియు I ₂(∞)= R ₁ /( R ₁ + R ₂ ) × I _(s) గా ఉంటుంది.