English: $- \frac{\hslash^{2}}{2m}\left\lbrack \psi^{'}\left( a^{+} \right) - \psi^{'}\left( a^{-} \right) \right\rbrack + V\psi(a) = 0$పొందుతాను.
Telugu: $- \frac{\hslash^{2}}{2m}\లెఫ్ట్\lbrack \psi^{'}\లెఫ్ట్(a^{+} \కుడి) - \psi^{'}\ఎడమ(a^{-} \కుడి) \కుడి\rbrack + V\psi(a) = 0$పొందుతాను.