English: - \frac{1}{x^{2}(x + 1)} = 0 < \infty$ $\lim_{x \rightarrow - 1}\ (x + 1).p(x) = \lim_{x \rightarrow - 1} - \frac{x + 1}{x^{2}(x - 1)} = 0 < \infty$, $\lim_{x \rightarrow - 1}\ (x + 1)^{2}.
Telugu: - \frac{1}{x^{2}(x + 1)} = 0 < \infty$ $\lim_{x \rightarrow - 1}\ (x + 1.p(x) = \lim_{x \rightarrow - 1} - \frac{x + 1}{x^{2}(x - 1)} = 0 < \infty$, $\lim_ {x \rightarro - 1}\ (x + 1)^{2}