English: So, equation 1 is $\varepsilon(\frac{E_{y,s}^{n} - E_{y,s}^{n - 1}}{\mathrm{\Delta}t}$)=$\lbrack\ H_{z,s}^{n - 1/2}\left( i - 1/2,j + \frac{1}{2} \right) - H_{z,s}^{n - 1/2}$(i+1/2,j+1/2)]/Δx Anything changed here?
Telugu: కాబట్టి, సమీకరణం 1 అనేది $\varepsilon(\frac{E_{y,s}^{n} - E_{y,s}^{n - 1}{\mathrm{\delta}t}$)=$\lbrack\ H_{z,s}^{n - 1/2}\ఎడమ( i - 1/2,j + \frac{1}{2} \కుడి) - H_{z,s}{n - 1/2}$(i+1/2,j+1/2)]/2