English: So, ∆𝛿₂ will be 𝛿₂⁽¹⁾+∆𝛿₂⁽¹⁾, −0.86 −01.3 so, − 2.16 degree,𝛿₃⁽²⁾to will be 𝛿₃⁽¹⁾+∆𝛿₃⁽¹⁾ that is − 3.2−0.15 so, −3.35 degree and 𝑉₂⁽²⁾ will be 𝑉₂⁽¹⁾ + ∆𝑉₂⁽¹⁾.
Telugu: కాబట్టి, ∆δ δ₂⁽⁽⁾+∆δ₂⁽⁽⁾⁾ అవుతుంది. −0.86 −01.3 సో, − 2.16 డిగ్రీ, δ⁽⁾⁾⁽⁾⁾∆δ⁾⁽⁽⁾⁾⁾⁾⁽⁾⁽⁽⁾⁽⁽⁾⁾ + δ ∆V₂⁽⁽¹⁾⁾⁽ ⁾ ⁾ ⁽ ⁾⁾⁽⁽⁾⁽⁾⁾⁽⁽⁾⁾⁽⁾⁽⁽⁾⁽⁾⁾ ⁾ ⁽ ⁽ ⁾ ⁽ ⁽ ⁾ ⁽ ⁾ ⁾ ⁽ ⁾ ⁽ ⁽䞍⁽⁽⁾⁽⁾⁽⁽⁾⁽