English: So, $L\{\sin\ 2t\}\ = \frac{2}{s^{2} + 4}$ where s > 0 $L\left\{ \sin\ 2t \right\} = \frac{2}{s^{2} + 4},\ s > 0$ $$L\left\{ \sin\ t\ \cos\ t \right\}\ = \frac{1}{2}L\left\{ \sin\ 2t \right\}$$ Let us take the next example, \end{matrix} \right.\ $ We need to evaluate L{F(t)}.
Telugu: కాబట్టి, $L\{\sin\ 2t\}\ = \frac{2}{s^{2} + 4}$ ఎక్కడ > 0 $L\ఎడమ\{ \sin\ 2t \కుడి\} = \frac{2}{s^{2} + 4},\s > 0$ $$L\లెఫ్ట్\{ \sin\t\ \cos\ t \కుడి\}\ = \frac{1}{2}L\లెఫ్ట్\{ \sin\ 2t \కుడి\}$$ తరువాత ఉదాహరణను తీసుకుందాం.