English: So, let us consider the state equation that is say $\left\lbrack \frac{dx_{1}(t)}{dt}\ \frac{dx_{2}(t)}{dt}\ \right\rbrack = \lbrack 0\ 1\ - 2\ - 3\ \rbrack\left\lbrack x_{1}(t)\ x_{2}(t)\ \right\rbrack + \lbrack 0\ 1\ \rbrack u(t)$ $\left\lbrack \frac{dx_{1}(t)}{dt}\ \frac{dx_{2}(t)}{dt}\ \right\rbrack = \lbrack 0\ 1\ - 2\ - 3\ \rbrack\left\lbrack x_{1}(t)\ x_{2}(t)\ \right\rbrack + \lbrack 0\ 1\ \rbrack u(t)$ So, when you compare this you get A = [0 1  − 2  − 3 ]    B = [0 1 ].
Telugu: కాబట్టి, మనం $\లెఫ్ట్\lbrack \frac{dx_{1}(t)}{dt}\ \frac{dx_{2}(t)}{dt}\ \కుడి\rbra x_{2} x_{1}ck = \lbrack = \lbrack 0\ 1\ - 2\ - 3\ \rbrack\లెఫ్ట్\lbrack x_{1}(t)\ x_{2}(t)\ \కుడి\rbrack + \lbrack 0\ 1\ \rbrack u(t)$ $\lbrack \frac{dx_{1}(t)}{dt}\ \frac{dx_{2}(t)}\కుడి\rbrack + \lbrack 0\ \rbrack 0\ rbrack + \lbrack 0\ 1\ \rbrack u(t)$ కాబట్టి, దీనిని పోల్చినప్పుడు మీకు A = [0 1 − 2 − 3 ] B = [0 1] వస్తుంది.