Question: Astralwerks goes by what name on its Instagram account?
Choices: astralwerksrecords
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SPARQL: SELECT DISTINCT ?pv WHERE { ?e <pred:name> "Astralwerks" . ?e <Instagram_username> ?pv .  }
Program:
function: Find
inputs: Astralwerks
function: QueryAttr
dependencies: 0
inputs: Instagram username
Answer: astralwerksrecords