Question: Is Chelmsford or Beijing smaller, in terms of area?
Choices: Trieste
Kingston
Cork
Kilkenny
Santo Domingo
Bergen
Dundee
Chihuahua
Abidjan
Chelmsford
SPARQL: SELECT ?e WHERE { { ?e <pred:name> "Chelmsford" .  } UNION { ?e <pred:name> "Beijing" .  } ?e <area> ?pv . ?pv <pred:value> ?v .  } ORDER BY ?v LIMIT 1
Program:
function: Find
inputs: Chelmsford
function: Find
inputs: Beijing
function: SelectBetween
dependencies: 0
1
inputs: area
less
Answer: Chelmsford