Question: How any constitutional monarchy are a member of the agent with http://www.afdb.org/ as their official website?
Choices: 0
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SPARQL: SELECT (COUNT(DISTINCT ?e) AS ?count) WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "constitutional monarchy" . ?e <member_of> ?e_1 . ?e_1 <pred:instance_of> ?c_1 . ?c_1 <pred:name> "agent" . ?e_1 <official_website> ?pv . ?pv <pred:value> "http://www.afdb.org/" .   }
Program:
function: FindAll
function: FilterStr
dependencies: 0
inputs: official website
http://www.afdb.org/
function: FilterConcept
dependencies: 1
inputs: agent
function: Relate
dependencies: 2
inputs: member of
backward
function: FilterConcept
dependencies: 3
inputs: constitutional monarchy
function: Count
dependencies: 4
Answer: 2