Question: Does Shreveport or Oak Park have less area?
Choices: New Haven
Columbus
Compton
Oak Park
Franklin
Waukegan
Greenville
Oakland
Lansing
Shreveport
SPARQL: SELECT ?e WHERE { { ?e <pred:name> "Shreveport" .  } UNION { ?e <pred:name> "Oak Park" .  } ?e <area> ?pv . ?pv <pred:value> ?v .  } ORDER BY ?v LIMIT 1
Program:
function: Find
inputs: Shreveport
function: Find
inputs: Oak Park
function: SelectBetween
dependencies: 0
1
inputs: area
less
Answer: Oak Park