Question: Does St. Louis or Louisville have less area?
Choices: Franklin
Oakland
St. Louis
Louisville
Compton
Lansing
Waukegan
New Haven
Greenville
Columbus
SPARQL: SELECT ?e WHERE { { ?e <pred:name> "St. Louis" .  } UNION { ?e <pred:name> "Louisville" .  } ?e <area> ?pv . ?pv <pred:value> ?v .  } ORDER BY ?v LIMIT 1
Program:
function: Find
inputs: St. Louis
function: Find
inputs: Louisville
function: SelectBetween
dependencies: 0
1
inputs: area
less
Answer: St. Louis