Question: Is there less area in Pensacola or in East St. Louis?
Choices: Greenville
Franklin
East St. Louis
Waukegan
Compton
Oakland
Boulder
Columbus
New Haven
Pensacola
SPARQL: SELECT ?e WHERE { { ?e <pred:name> "Pensacola" .  } UNION { ?e <pred:name> "East St. Louis" .  } ?e <area> ?pv . ?pv <pred:value> ?v .  } ORDER BY ?v LIMIT 1
Program:
function: Find
inputs: Pensacola
function: Find
inputs: East St. Louis
function: SelectBetween
dependencies: 0
1
inputs: area
less
Answer: East St. Louis