Question: Is evalongoria the Instagram username for Eva Longoria?
Choices: yes
no
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unknown
unknown
unknown
unknown
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SPARQL: ASK { ?e <pred:name> "Eva Longoria" . ?e <Instagram_username> ?pv . ?pv <pred:value> "evalongoria" .  }
Program:
function: Find
inputs: Eva Longoria
function: QueryAttr
dependencies: 0
inputs: Instagram username
function: VerifyStr
dependencies: 1
inputs: evalongoria
Answer: yes