Question: Which has less elevation above sea level, Lafayette whose elevation above sea level is 11 metres or Huntsville?
Choices: Compton
Franklin
Oakland
Columbus
Huntsville
Lansing
Lafayette
Waukegan
New Haven
Greenville
SPARQL: SELECT ?e WHERE { { ?e <pred:name> "Lafayette" . ?e <elevation_above_sea_level> ?pv_1 . ?pv_1 <pred:unit> "metre" . ?pv_1 <pred:value> "11"^^xsd:double . } UNION { ?e <pred:name> "Huntsville" . } ?e <elevation_above_sea_level> ?pv . ?pv <pred:value> ?v .  } ORDER BY ?v LIMIT 1
Program:
function: Find
inputs: Lafayette
function: FilterNum
dependencies: 0
inputs: elevation above sea level
11 metre
=
function: Find
inputs: Huntsville
function: SelectBetween
dependencies: 1
2
inputs: elevation above sea level
less
Answer: Lafayette