Question: Hildesheim whose area is 92.29 square kilometers or Vancouver the one whose population is 603502, is at a lower altitude?
Choices: Utrecht
Dnipro
Wuppertal
Hildesheim
Vancouver
Halle (Saale)
Aachen
Stuttgart
Fort Smith
Bordeaux
SPARQL: SELECT ?e WHERE { { ?e <pred:name> "Hildesheim" . ?e <area> ?pv_1 . ?pv_1 <pred:unit> "square kilometre" . ?pv_1 <pred:value> "92.29"^^xsd:double . } UNION { ?e <pred:name> "Vancouver" . ?e <population> ?pv_2 . ?pv_2 <pred:unit> "1" . ?pv_2 <pred:value> "603502"^^xsd:double . } ?e <elevation_above_sea_level> ?pv . ?pv <pred:value> ?v .  } ORDER BY ?v LIMIT 1
Program:
function: Find
inputs: Hildesheim
function: FilterNum
dependencies: 0
inputs: area
92.29 square kilometre
=
function: Find
inputs: Vancouver
function: FilterNum
dependencies: 2
inputs: population
603502
=
function: SelectBetween
dependencies: 1
3
inputs: elevation above sea level
less
Answer: Vancouver