Question: What is the official website of the city whose population is equal to 366151 (the determination method of this statement is census)?
Choices: http://www.federicofellini.info/
https://www.trier.de/
http://www.clairedanes.com
http://www.nba.com/nuggets/
http://chicago.whitesox.mlb.com
http://www.aepfc.com/
http://www.london.ca
https://www.orange.com
http://www.stadt-kassel.de
http://www.columbiatristar.it/
SPARQL: SELECT DISTINCT ?pv WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "city" . ?e <population> ?pv_1 . ?pv_1 <pred:unit> "1" . ?pv_1 <pred:value> "366151"^^xsd:double . [ <pred:fact_h> ?e ; <pred:fact_r> <population> ; <pred:fact_t> ?pv_1 ] <determination_method> ?qpv . ?qpv <pred:value> "census" . ?e <official_website> ?pv .  }
Program:
function: FindAll
function: FilterNum
dependencies: 0
inputs: population
366151
=
function: QFilterStr
dependencies: 1
inputs: determination method
census
function: FilterConcept
dependencies: 2
inputs: city
function: QueryAttr
dependencies: 3
inputs: official website
Answer: http://www.london.ca