Question: Is Copenhagen or the Lisbon of Instagram usernamecamara_municipal_lisboa lower relative to sea level?
Choices: Doha
Riga
Lausanne
Copenhagen
Sarajevo
Mexico City
Tallinn
Moscow
Manila
Lisbon
SPARQL: SELECT ?e WHERE { { ?e <pred:name> "Copenhagen" . } UNION { ?e <pred:name> "Lisbon" . ?e <Instagram_username> ?pv_1 . ?pv_1 <pred:value> "camara_municipal_lisboa" . } ?e <elevation_above_sea_level> ?pv . ?pv <pred:value> ?v .  } ORDER BY ?v LIMIT 1
Program:
function: Find
inputs: Copenhagen
function: Find
inputs: Lisbon
function: FilterStr
dependencies: 1
inputs: Instagram username
camara_municipal_lisboa
function: SelectBetween
dependencies: 0
2
inputs: elevation above sea level
less
Answer: Copenhagen