Question: How was it determined that the US state whose percent of water area is equal to 41.54 percentage have a population of 3668412?
Choices: United Kingdom Census 2001
middle
census
Canada 2016 Census
national estimation
resident registration
United Kingdom Census 1991
tradition
United Kingdom Census 2011
1860 United States Census
SPARQL: SELECT DISTINCT ?qpv WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "state of the United States" . ?e <water_as_percent_of_area> ?pv_1 . ?pv_1 <pred:unit> "percentage" . ?pv_1 <pred:value> "41.54"^^xsd:double . ?e <population> ?pv . ?pv <pred:unit> "1" . ?pv <pred:value> "3668412"^^xsd:double . [ <pred:fact_h> ?e ; <pred:fact_r> <population> ; <pred:fact_t> ?pv ] <determination_method> ?qpv .  }
Program:
function: FindAll
function: FilterNum
dependencies: 0
inputs: water as percent of area
41.54 percentage
=
function: FilterConcept
dependencies: 1
inputs: state of the United States
function: QueryAttrQualifier
dependencies: 2
inputs: population
3668412
determination method
Answer: census