If Emerie has six quarters, Zain has 6+10 = <<6+10=16>>16 quarters.
At the same time, Zain has 7+10 = <<7+10=17>>17 dimes, ten more than Emerie.
The total number of quarters and dimes Zain has is 17+16 = <<17+16=33>>33 coins.
Zain also has 10 more nickels than Emerie, a total of 10+5 = <<10+5=15>>15 nickels.
In total, Zain has 33+15 = <<33+15=48>>48 coins.
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