Twice as many chocolates as she ate the first day is 2*4=<<2*4=8>>8 chocolates.
And three less than twice as many chocolates as she ate the first day is 8-3=<<8-3=5>>5 chocolates.
Two less than the number she ate on the first day is 4-2=<<4-2=2>>2 chocolates.
One less than she ate the third day is 2-1=<<2-1=1>>1 chocolate.
By the end of the fourth day, 4+5+2+1=<<4+5+2+1=12>>12 chocolates had been eaten.
Thus, on the fifth day, 24-12=<<24-12=12>>12 chocolates remained uneaten.
#### 12