List the names of 5 users followed by the largest number of other users.
return users ;return other users followed by of #1 ;return number of  #2 for each #1 ;return the  5 highest of #3 ;return #1 where #3 is equal to any of #4 ;return names of #5
['select', 'project', 'group', 'aggregate', 'comparative', 'project']