If there is one laptop shown front and back.
return laptop ;return front of  #1 ;return back of  #1 ;return #1 where #2 is  shown ;return #1 where #3 is  shown ;return #1 in  both  #4 and #5 ;return number of #6 ;return if  #7 is  equal to one
['select', 'project', 'project', 'comparative', 'comparative', 'intersection', 'aggregate', 'boolean']