If there is one black dog that has its mouth open in one of the images.
return dog ;return #1 that is black ;return mouth of #2 ;return #2 where  #3 is open ;return images ;return number of  #4 for each  #5 ;return #5 where  #6 is equal to  one ;return number of  #7 ;return if  #8 is equal to  one
['select', 'filter', 'project', 'comparative', 'select', 'group', 'comparative', 'aggregate', 'boolean']