Find the count and code of the job has most employees.
return jobs ;return employees of  #1 ;return number of  #2 for each  #1 ;return #1 where #3 is  highest ;return employees of  #4 ;return number of  #5 ;return code of  #4 ;return #6 ,  #7
['select', 'project', 'group', 'superlative', 'project', 'aggregate', 'project', 'union']