Find the name of people whose age is greater than any engineer sorted by their age.
return engineers ;return ages of #1 ;return the  lowest of #2 ;return people ;return ages of #4 ;return #4 where #5 is higher than #3 ;return names of #6 ;return #7 sorted by #5
['select', 'project', 'aggregate', 'select', 'project', 'comparative', 'project', 'sort']