If one of the dogs has its tongue visible without its teeth showing.
return dogs ;return tongue of  #1 ;return teeth of  #1 ;return #1 where #2 is  visible ;return #1 where #3 are  not showing ;return #1 in  both  #4 and #5 ;return number of #6 ;return if  #7 is  equal to one
['select', 'project', 'project', 'comparative', 'comparative', 'intersection', 'aggregate', 'boolean']