Show the member names which are in both the party with id 3 and the party with id 1.
return members ;return parties of  #1 ;return id of  #2 ;return #1 where #3 is  3 ;return #1 where #3 is  1 ;return #1 of  both #4 and  #5 ;return names of  #6
['select', 'project', 'project', 'comparative', 'comparative', 'intersection', 'project']