-- Lean 4 proof step from Mathlib.NumberTheory.ClassNumber.AdmissibleAbsoluteValue (goal)
Goal:
R : Type u_1
inst : EuclideanDomain R
abv : AbsoluteValue R ℤ
n : ℕ
h : abv.IsAdmissible
this : DecidableEq R
zero :
  ∀ {ε : ℝ} (_hε : 0 < ε) {b : R} (_hb : b ≠ 0) (A : Fin (HPow.hPow (β := ℕ) (h.card ε) 0).succ → Fin 0 → R),
    ∃ (i₀ : Fin (HPow.hPow (β := ℕ) (h.card ε) 0).succ) (i₁ : Fin (HPow.hPow (β := ℕ) (h.card ε) 0).succ),
      i₀ ≠ i₁ ∧
        ∀ (k : Fin 0),
          (↑((abv : (a : R) → ℤ) (A i₁ k % b - A i₀ k % b)) : ℝ) < HSMul.hSMul (α := ℤ) ((abv : (a : R) → ℤ) b : ℤ) ε
⊢ ∀ {ε : ℝ} (_hε : 0 < ε) {b : R} (_hb : b ≠ 0) (A : Fin (h.card ε ^ n).succ → Fin n → R),
    ∃ (i₀ : Fin (h.card ε ^ n).succ) (i₁ : Fin (h.card ε ^ n).succ),
      i₀ ≠ i₁ ∧
        ∀ (k : Fin n),
          (↑((abv : (a : R) → ℤ) (A i₁ k % b - A i₀ k % b)) : ℝ) < HSMul.hSMul (α := ℤ) ((abv : (a : R) → ℤ) b : ℤ) ε
have succ : ∀ (n : ℕ)
  (ih :
    ∀ {ε : ℝ} (_hε : 0 < ε) {b : R} (_hb : b ≠ 0) (A : Fin (h.card ε ^ n).succ → Fin n → R),
      ∃ (i₀ : Fin (h.card ε ^ n).succ) (i₁ : Fin (h.card ε ^ n).succ),
        i₀ ≠ i₁ ∧
          ∀ (k : Fin n),
            (↑((abv : (a : R) → ℤ) (A i₁ k % b - A i₀ k % b)) : ℝ) < HSMul.hSMul (α := ℤ) ((abv : (a : R) → ℤ) b : ℤ) ε)
  {ε : ℝ} (_hε : 0 < ε) {b : R} (_hb : b ≠ 0) (A : Fin (h.card ε ^ (n + 1)).succ → Fin (n + 1) → R),
  ∃ (i₀ : Fin (h.card ε ^ (n + 1)).succ) (i₁ : Fin (h.card ε ^ (n + 1)).succ),
    i₀ ≠ i₁ ∧
      ∀ (k : Fin (n + 1)),
        (↑((abv : (a : R) → ℤ) (A i₁ k % b - A i₀ k % b)) : ℝ) < HSMul.hSMul (α := ℤ) ((abv : (a : R) → ℤ) b : ℤ) ε
Tactic: induction n with
  | zero =>
    intro ε _hε b _hb A
    refine ⟨0, 1, ?_, ?_⟩
    · simp
    rintro ⟨i, ⟨⟩⟩
  | succ n ih =>
  intro ε hε b hb A
  let M := h.card ε
  -- By the "nicer" pigeonhole principle, we can find a collection `s`
  -- of more than `M ^ n` remainders where the first components lie close together:
  obtain ⟨s, s_inj, hs⟩ :
    ∃ s : Fin (M ^ n).succ → Fin (M ^ n.succ).succ,
      Function.Injective s ∧ ∀ i₀ i₁, (abv (A (s i₁) 0 % b - A (s i₀) 0 % b) : ℝ) < abv b • ε := by
    -- We can partition the `A`s into `M` subsets where
    -- the first components lie close together:
    obtain ⟨t, ht⟩ :
      ∃ t : Fin (M ^ n.succ).succ → Fin M,
        ∀ i₀ i₁, t i₀ = t i₁ → (abv (A i₁ 0 % b - A i₀ 0 % b) : ℝ) < abv b • ε :=
      h.exists_partition hε hb fun x ↦ A x 0
    -- Since the `M` subsets contain more than `M * M^n` elements total,
    -- there must be a subset that contains more than `M^n` elements.
    obtain ⟨s, hs⟩ :=
      Fintype.exists_lt_card_fiber_of_mul_lt_card (f := t)
        (by simpa only [Fintype.card_fin, pow_succ'] using Nat.lt_succ_self (M ^ n.succ))
    have : (M ^ n).succ ≤ (Finset.toList {x | t x = s}).length := by
      rwa [Finset.length_toList]
    refine ⟨fun i ↦ (Finset.toList {x | t x = s})[i.castLE this], fun i j h ↦ ?_,
      fun i₀ i₁ ↦ ht _ _ ?_⟩
    · simpa [(Finset.nodup_toList _).getElem_inj_iff, Fin.val_inj] using h
    · have (i : Fin (M ^ n).succ) : t (Finset.toList {x | t x = s})[i.castLE this] = s :=
        (Finset.mem_filter.mp ((Finset.mem_toList (s := {x | t x = s})).mp (List.getElem_mem _))).2
      simp_rw [this]
  -- Since `s` is large enough, there are two elements of `A ∘ s`
  -- where the second components lie close together.
  obtain ⟨k₀, k₁, hk, h⟩ := ih hε hb fun x ↦ Fin.tail (A (s x))
  refine ⟨s k₀, s k₁, fun h ↦ hk (s_inj h), fun i ↦ Fin.cases ?_ (fun i ↦ ?_) i⟩
  · exact hs k₀ k₁
  · exact h i
Cleared hypotheses: n