Abstract:
The present creation is to provide a switching circuit built in IC for earphone and loudspeaker of portable information device, and there is no any passive component outside the IC, thus making the circuit board assembly more easily, saving the area of the circuit board, decreasing the volume and the cost. It is very suitable in designing a compact portable information device. In order to avoid any possible logic error during the switching between earphone and loudspeaker, the present creation provides a special unsymmetrical design in differential MOS circuit, and provides a current mirror circuit.

Description:
FIELD OF THE INVENTION  
         [0001]    The present invention relates to a switching circuit built in IC for earphone and loudspeaker of portable information device, and more particularly to a switching circuit with the passive components thereof to be built in IC entirely.  
         BACKGROUND OF THE INVENTION  
         [0002]    Conventional switching circuit for earphone and loudspeaker of portable information device is shown in FIG. 1. When a ear phone plug is not inserted into the ear phone jack  1 , the audio output Lout is passed through the filter  2  and the switch  11  in the ear phone jack  1  to be fed into the operational amplifier  3  for operating the loudspeaker  4 . When the ear phone plug is inserted into the ear phone jack  1  to open the switch  11 , the audio output Lout is not fed to the loudspeaker  4 , but instead to an earphone.  
           [0003]    The operational amplifier  3  is designed into an integrated circuit, while the capacitor  21 , the resistor  22  in filter  2  and the input bias resistors  31 ,  32  of the operational amplifier  3  are still designed by passive components, and arranged outside the IC of the operational amplifier  3 . It is tedious to assemble the passive components in this kind of design, and the passive components occupy too much area in a circuit board, therefore increase the cost and volume, and are not suitable in designing a compact portable information device.  
         OBJECT OF THE INVENTION  
         [0004]    It is therefore an object of the present invention to provide a switching circuit built in IC for earphone and loudspeaker of portable information device, and there is no any passive component outside the IC, thus making the circuit board assembly more easily, saving the area of the circuit board, decreasing the volume and the cost. It is very suitable in designing a compact portable information device. 
       
    
    
     BRIEF DESCRIPTION OF THE DRAWINGS  
       [0005]    [0005]FIG. 1 shows a conventional switching circuit diagram for earphone and loudspeaker of portable information device.  
         [0006]    [0006]FIG. 2 shows a switching circuit diagram for earphone and loudspeaker of portable information device according to the present invention.  
         [0007]    [0007]FIG. 3 shows a schematic diagram of voltage Vp and Vn according to the present invention.  
         [0008]    [0008]FIG. 4 shows schematically an unsymmetrical circuit design of a MOS comparator in an operational amplifier according to the present invention.  
         [0009]    [0009]FIG. 5 shows schematically a current mirror circuit added beside the MOS comparator in an operational amplifier according to the present invention. 
     
    
     DETAILED DESCRIPTION OF THE INVENTION  
       [0010]    Referring to FIG. 2, the switching circuit built in IC for earphone and loudspeaker of portable information device according to the present invention has no any passive component to be built outside the IC, except the earphone jack  1  and the loudspeaker  4 , all other ciucuits is designed with the operational amplifier  3  to form an IC.  
         [0011]    A diode  33 , two input bias resistors  34 ,  35  are designed into the present invention, as shown in FIG. 2.  
         [0012]    When a earphone plug is not inserted into the earphone jack  1 , the audio output Lout is passed through a switch  11  in the earphone jack  1  to be fed to the positive terminal Vp of the operational amplifier  3 , the audio output Lout is also passed through the diode  33  to be fed to the negative terminal Vn of the operational amplifier  3 . Since the diode  33  has a voltage drop of 0.7 volt, the voltage of the positive terminal Vp of the operational amplifier  3  is higher than that of the negative terminal Vn, thus the output voltage Vo of the operational amplifier  3  is high to operate the loudspeaker  4 .  
         [0013]    When a earphone plug is inserted into the earphone jack  1  to open the switch  11 , the audio output Lout is fed to the earphone, and the audio output Lout is not fed to the positive terminal Vp of the operational amplifier  3 , but is passed through the diode  33  to be fed to the negative terminal Vn of the operational amplifier  3 . Since Vp does not accept any audio output, Vp is grounded as shown in FIG. 2, the voltage of the negative terminal Vn is higher than that of the positive terminal Vp. Therefore the output voltage Vo of the operational amplifier  3  is low to unoperate the loudspeaker  4 .  
         [0014]    [0014]FIG. 3 shows the schematic diagram of voltage V p  and V n  according to the present invention, in which (a) represents a status that the earphone is not inserted into the earphone jack  1  and the loudspeaker  4  is operated; while (b) represents a status that the earphone is inserted into the earphone jack  1  and the loudspeaker  4  is not operated.  
         [0015]    In (a), the voltage of Vp (=Lout) is higher than zero volt and the voltage of Vn is lower than that of Vp by 0.7 volt (due to the voltage drop in diode  33 ). When the voltage of Vp is lower than 0.7 volt, the voltage of Vn will be zero volt, as shown by the horizontal part in (a). This is because of the blockade by the diode  33 . Since the voltage of Vp is higher than that of Vn, the output voltage Vo of the operational amplifier  3  is high to operate the loudspeaker  4 . However, when the voltage of Vp is equal to zero volt, i.e. Vp=Vn, this will cause trouble that the loudspeaker  4  may be unoperated.  
         [0016]    In (b), the voltage of Vp is always a zero volt (because Lout is not fed into the positive terminal Vp of the operational amplifier  3 ), and the voltage of Vn is higher than zero volt. The voltage of Vn is lower than that of Lout by 0.7 volt (due to the voltage drop in diode  33 ). When the voltage of Lout is lower than 0.7 volt, the voltage of Vn will be a zero volt, as shown by the horizontal part in (b). This is because of the blockade by the diode  33 . Since the voltage of Vn is higher than that of Vp, the output voltage Vo of the operational amplifier  3  is low to unoperate the loudspeaker  4 , However, when the voltage of Vn is equal to zero volt, i.e. Vp=Vn, this will cause trouble that the loudspeaker  4  may be operated.  
         [0017]    In order to solve the trouble caused by Vp=Vn, the present invention provides two solutions.  
         [0018]    As to the trouble in (a), the present invention provides an unsymmetrical design in a MOS comparator  36  of the operational amplifier  3 . Referring to FIG. 4, the MOS comparator  36  of the operational amplifier  3  has PMOS transistors M 1  and M 2 . The input terminal Vno of M 1  is connected with Vn by some circuits, while the input terminal Vpo of M 2  is connected with Vp by some other circuits. In FIG. 4, there only shows a pair of M 1  and M 2 , but actually there are four PMOS transistors M 1  to be parallel connected and four PMOS transistors M 2  to be parallel connected. Since the number of M 1  is equal to the number of M 2 , the comparator  36  will present Vpo=Vno when there is no any signal to be fed into the comparator  36 . However, The present invention modifies the design by using four PMOS transistors M 1  to be parallel connected and “three” PMOS transistors M 2  to be parallel connected. Therefore even when there is no any signal to be fed into the comparator  36 , Vpo=Vno+0.15 volt. When Vp=Vn=zero volt in FIG. 3, Vpo is not equal to Vno, but higher than Vno by 0.15 volt. Consequently, the loudspeaker  4  will not be unoperated. The output of M 0  in FIG. 4 is the output Vo of the operational amplifier  3 .  
         [0019]    As to the trouble in (b), the present invention provides a current mirror circuit  37  beside the comparator  36  of the operational amplifier  3 . Referring to FIG. 5, PMOS transistors M 3  and M 4  are connected as shown. M 3  represents only one PMOS, while M 4  represents three PMOS to be parallel connected. In accordance with the property of the current mirror circuit, the current I M3  in M 3  is equal to ⅓ of the current I M4  in M 4 . Therefore, the driving current for the output Vo of the operational amplifier  3  is ⅓ of the original design. A small driving current will cause the slew rate of the comparator  36  more slow. Therefore, when Vp=Vn in (b) is encountered, the trouble that the loudspeaker  4  may be operated is solved because the operational amplifier  3  cannot change status immediately due to the slow slew rate of the comparator  36 , and the loudspeaker  4  is not operated.  
         [0020]    The spirit and scope of the present invention depends only upon the following Claims, and is not limited by the above embodiment.