Problem:
Depth First Search Depth-first search (DFS) follows the strategy to search ”deeper” in the graph whenever possible. In DFS, edges are recursively explored out of the most recently discovered vertex $v$ that still has unexplored edges leaving it. When all of $v$'s edges have been explored, the search ”backtracks” to explore edges leaving the vertex from which $v$ was discovered. This process continues until all the vertices that are reachable from the original source vertex have been discovered. If any undiscovered vertices remain, then one of them is selected as a new source and the search is repeated from that source. DFS timestamps each vertex as follows:  $d[v]$ records when $v$ is first discovered.  $f[v]$ records when the search finishes examining $v$’s adjacency list.  Write a program which reads a directed graph $G = (V, E)$ and demonstrates DFS on the graph based on the following rules:  $G$ is given in an adjacency-list. Vertices are identified by IDs $1, 2,... n$ respectively.  IDs in the adjacency list are arranged in ascending order.  The program should report the discover time and the finish time for each vertex.  When there are several candidates to visit during DFS, the algorithm should select the vertex with the smallest ID.  The timestamp starts with 1.  Input In the first line, an integer $n$ denoting the number of vertices of $G$ is given. In the next $n$ lines, adjacency lists of $u$ are given in the following format: $u$ $k$ $v_1$ $v_2$ ... $v_k$ $u$ is ID of the vertex and $k$ denotes its degree. $v_i$ are IDs of vertices adjacent to $u$. Output For each vertex, print $id$, $d$ and $f$ separated by a space character in a line. $id$ is ID of the vertex, $d$ and $f$ is the discover time and the finish time respectively. Print in order of vertex IDs. Constraints  $1 \leq n \leq 100$  Sample Input 1 4
1 1 2
2 1 4
3 0
4 1 3 Sample Output 1 1 1 8
2 2 7
3 4 5
4 3 6 Sample Input 2 6
1 2 2 3
2 2 3 4
3 1 5
4 1 6
5 1 6
6 0 Sample Output 2 1 1 12
2 2 11
3 3 8
4 9 10
5 4 7
6 5 6   This is example for Sample Input 2 (discover/finish)  Reference Introduction to Algorithms, Thomas H. Cormen, Charles E. Leiserson, Ronald L. Rivest, and Clifford Stein. The MIT Press.

Solution (Python):
from collections import deque


l = int(input())
rlist = []
for i in range(l):
    li = list(map(int, input().split()))
    rlist.append(deque([ll-1 for ll in li[2:]]))


color = ['white'] * l
find_time = [0] * l
stop_time = [0] * l
stack = []
time = 0

def dfs(u):
    global time

    stack.append(u)
    color[u] = 'gray'
    time += 1
    find_time[u] = time

    while len(stack) > 0:
        
        
        

        u = stack[-1]
        
        if len(rlist[u]) > 0:
            if color[rlist[u][0]] == 'white':
                time += 1
                find_time[rlist[u][0]] = time
                color[rlist[u][0]] = 'gray'
                stack.append(rlist[u][0])
            rlist[u].popleft()
        
        else:
            time += 1
            stop_time[u] = time
            color[u] = 'black'
            stack.pop()

for i in range(l):
    if color[i] == 'white':
        dfs(i)
for i in range(len(find_time)):
    print(str(i+1) + ' ' + str(find_time[i]) + ' ' + str(stop_time[i]))

Solution (Python):
n=int(input())
G=[[j for j in range(n)] for i in range(n)]
for i in range(n):
    g_in=list(map(int,input().split()))
    u=g_in[0]
    k=g_in[1]
    v=g_in[2:]
    for j in v:
        G[u-1][j-1]=1

visited=[0 for i in range(n)]
finished=[0 for i in range(n)]
L=[]
out=[[i+1,0,0] for i in range(n)]
step=0

def dfs(cn):
    flg=0
    if visited[cn]==0:
        flg=1
        L.append(cn)
    visited[cn]=1
    for i in range(n):
        if cn!=i and G[cn][i]==1 and visited[i]==0:
            dfs(i)
    if flg==1:
        L.append(cn)

i=0
while visited.count(1)<n:
    dfs(i)
    i+=1
copied=[0 for i in range(len(L))]

for i in range(len(L)):
    if copied[L[i]]==0:
        copied[L[i]]=1
        out[L[i]][1]=i+1
    elif copied[L[i]]==1:
        copied[L[i]]=2
        out[L[i]][2]=i+1

out=[' '.join(map(str,i)) for i in out]

print('\n'.join(map(str,out)))

Solution (Python):
N = int(input())
DG={}  
node_ls=[]
is_visited={}  



for _ in range(N):
    tmp = input().split()
    node_id = tmp[0]
    node_ls.append(node_id)      
    is_visited[node_id] = False  
    adj_num = int(tmp[1])    
    if adj_num != 0:
        DG[node_id] = tmp[2:]  
    else:
        DG[node_id] = []


d = {} 
f = {} 
t = 1

def dfs(node):
    global t
    if is_visited[node]:  
        return
    is_visited[node] = True
    d[node] = t 
    t += 1
    
    for no in DG[node]:
        dfs(no)
        
    f[node]=t 
    t += 1
    
for node in node_ls:  
    dfs(node)
    
for node in node_ls:
    print(node, d[node], f[node])

Solution (Python):
from collections import deque


def conv_list(n):
    adj_matrix = []
    for _ in range(n):
        adj_list = input().split()
        adj_list = list(map(int, adj_list))
        adj_row = [False] * n
        if adj_list[1] > 0:
            for i in adj_list[2:]:
                adj_row[i - 1] = True
        adj_matrix.append(adj_row)
    return adj_matrix


def depth_first_search(adj_matrix, n):
    visited = [None] * n
    count = 1
    searched = [None] * n
    start = 0
    stack = deque()
    stack.append(start)
    visited[start] = 1
    while count <= 2 * n:
        has_edge = adj_matrix[start]
        i = 0
        while i < n:
            if has_edge[i] and visited[i] is None:
                stack.append(i)
                count += 1
                visited[i] = count
                break
            i += 1
        if i < n:
            start = i
        else:
            searched_node = stack.pop()
            count += 1
            searched[searched_node] = count
            if len(stack) > 0:
                start = stack[-1]
            elif count < 2 * n:
                start = visited.index(None)
                stack.append(start)
                count += 1
                visited[start] = count
            else:
                break
    return visited, searched


def main():
    n = int(input())
    adj_matrix = conv_list(n)
    visited, searched = depth_first_search(adj_matrix, n)
    for i in range(n):
        print("{} {} {}".format(i + 1, visited[i], searched[i]))


if __name__ == "__main__":
    main()

Solution (Python):

WHITE = 0
GRAY = 1
BLACK = 2

NIL = -1


def dfs(u):
    global time
    color[i] = GRAY
    time += 1
    d[u] = time
    for v in range(n):
        if m[u][v] and (color[v] == WHITE):
            dfs(v)
        color[u] = BLACK
    time += 1
    f[u] = time


def next(u):
    for v in range(nt[u], n + 1):
        nt[u] = v + 1
        if m[u][v]:
            return v
    return NIL
            


n = int(input())

m = [[0 for i in range(n + 1)] for j in range(n + 1)]
vid = [0] * n
d = [0] * n
f = [0] * n
S = []
color = [WHITE] * n
time = 0
nt = [0] * n

tmp = []
for i in range(n):
    nums=list(map(int,input().split()))
    tmp.append(nums)
    vid[i] = nums[0]

for i in range(n):
    for j in range(tmp[i][1]):
        m[i][vid.index(tmp[i][j + 2])] = 1

for i in range(n):
    if color[i] == WHITE:
        dfs(i)

for i in range(n):
    print(vid[i], d[i], f[i])

Solution (Python):
if __name__ == '__main__':
    n = int(input())
    graph = [[0 for i in range(n)] for _ in range(n)]
    frist = [0 for _ in range(n)]
    end = [0 for _ in range(n)]
    visit = [False for _ in range(n)]
    
    for i in range(n):
        datas = [int(num) for num in input().split(' ')]
        if datas[1] > 0:
            for j in datas[2:]:
                graph[datas[0] - 1][j - 1] = 1

    visit[0] = True
    frist[0] = s = 1
    stack = [0]

    while len(stack) != 0:
        point = stack.pop(-1)
        flag = False
        for i in range(n):
            if graph[point][i] == 1 and visit[i] is False:
                visit[i] = True
                flag = True
                s += 1
                frist[i] = s
                stack.append(point)
                stack.append(i)
                break
        if flag is False:
            s += 1
            end[point] = s
        
        if len(stack) == 0:
            for i in range(n):
                if visit[i] is False:
                    visit[i] = True
                    s += 1
                    frist[i] = s
                    stack.append(i)
                    break
            
    for i in range(n):
        print('%d %d %d' % (i+1, frist[i], end[i]))

Solution (Python):
N = int(input())

E = [None] * (N+1)
for _ in range(N):
    u, k, *vs = list(map(int, input().split()))
    E[u] = vs

d = [0] * (N+1)
f = [0] * (N+1)
t = 0

def dfs(v):
    global t, d, f
    if d[v]:
        return
    t += 1
    d[v] = t
    for u in E[v]:
        dfs(u)
    t += 1
    f[v] = t

for v in range(1, N+1):
    dfs(v)

for v in range(1, N+1):
    print(v, d[v], f[v])

Solution (Python):

def dfs_visit(u):
    global n, M, d, f, time

    if color[u] == 'WHITE':
        color[u] = 'GRAY'
        time += 1
        d[u] = time

        for v in range(n):
            if M[u][v] == 0:
                continue
            if color[v] == 'WHITE':
                dfs_visit(v)

        color[u] = 'BLACK'
        time += 1
        f[u] = time


def dfs():
    global n, M, d, f, time

    for u in range(n):
        if color[u] == 'WHITE':  
            dfs_visit(u)

    for u in range(n):
        print('{} {} {}'.format(u+1, d[u], f[u]))


n = int(input())

M = [[0 for i in range(n)] for j in range(n)]
color = ['WHITE'] * n  
d = [None] * n  
f = [None] * n  
time = 0

for i in range(n):
    _ = list(map(int, input().split()))
    u = _[0] - 1  

    degree = _[1]
    for j in range(degree):
        v = _[j+2] - 1  
        M[u][v] = 1




dfs()

Solution (Python):
count = 0


def solve(i, a, ans):
    global count
    if ans[i][0] == 0:
        count += 1
        ans[i][0] = count

    for x in range(a[i][1]):
        if ans[a[i][2 + x] - 1][0] == 0:
            solve(a[i][2 + x] - 1, a, ans)

    if ans[i][1] == 0:
        count += 1
        ans[i][1] = count


N = int(input())
a = []
for _ in range(N):
    a.append([int(x) for x in input().split()])

ans = [[0 for i in range(2)] for j in range(N)]

for i in range(N):
    if ans[i][0] == 0:
        solve(i, a, ans)

for i, x in enumerate(ans):
    print(i + 1, *x)

Solution (Python):
n=int(input())
E=[0]*n
for _ in range(n):
    u,k,*V=map(int,input().split())
    E[u-1]=sorted(V)[::-1]
todo=[1]
seen=[0]*n
d=[0]*n
f=[0]*n
t=0
while 0 in f:
    if not todo:
        todo.append(seen.index(0)+1)    
    if seen[todo[-1]-1]==0:
        seen[todo[-1]-1]=1
        t+=1
        d[todo[-1]-1]=t
        for v in E[todo[-1]-1]:
            if d[v-1]==0:
                todo.append(v)
    elif f[todo[-1]-1]==0:
        t+=1
        f[todo.pop()-1]=t
    else:
        todo.pop()
for i in range(n):
    print(i+1,d[i],f[i])

Solution (Python):
from collections import deque


N = 100
WHITE = 0
GRAY = 1
BLACK = 2

M = [[0 for _ in range(N)] for _ in range(N)]
color = [0 for _ in range(N)]
d = [0 for _ in range(N)]
f = [0 for _ in range(N)]
nt = [0 for _ in range(N)]
tt = 0


def main():
    n = int(input())
    for _ in range(n):
        u, k, *v_s = map(int, input().split(' '))
        for j in range(k):
            M[u-1][v_s[j-1]-1] = 1

    dfs(n)

    for i in range(n):
        print('{} {} {}'.format(i+1, d[i], f[i]))


def dfs(n):
    for u in range(n):
        if color[u] == WHITE:
            dfs_visit(n, u)


def dfs_visit(n, r):
    global tt
    color[r] = GRAY
    tt += 1
    d[r] = tt
    for v in range(0, n):
        if M[r][v] == 0:
            continue
        if color[v] == WHITE:
            dfs_visit(n, v)
    color[r] = BLACK
    tt += 1
    f[r] = tt


if __name__ == '__main__':
    main()

Solution (Python):




N = int(input())
DG = {}
node_ls = []
is_visited = {}

for _ in range(N):
    tmp = input().split()
    node_id = tmp[0]
    node_ls.append(node_id)
    is_visited[node_id] = False
    adj_num = int(tmp[1])
    if adj_num != 0:
        DG[node_id] = tmp[2:]
    else:
        DG[node_id] = []

d = {}  
f = {}  
t = 1


def dfs(node):  
    
    global t
    if is_visited[node]:
        return  

    is_visited[node] = True
    
    d[node] = t
    t += 1  
    
    for no in DG[node]:
        dfs(no)
    f[node] = t
    t += 1  


for node in node_ls:  
    dfs(node)

for node in node_ls:
    print(node, d[node], f[node])

Solution (Python):

import sys
input = lambda: sys.stdin.readline()[:-1]
sys.setrecursionlimit(10**8)

n = int(input())
G1 = [0]*n
G2 = [[0]*n for i in range(n)]
d = [0]*n
f = [0]*n
for i in range(n):
    inp = tuple(map(int, input().split()))
    G1[inp[0]-1]=sorted(inp[2:])
time=0

def dfs(vertex):
    if d[vertex]:return
    global time
    time+=1
    d[vertex]=time
    for v in G1[vertex]:
        if not d[v-1]:
            dfs(v-1)
    time+=1
    f[vertex]=time
    return

for i in range(n):
    dfs(i)
for i in range(n):
    print(i+1,d[i],f[i])

Solution (Python):
N = int(input())

E = [None] * (N+1)
for _ in range(N):
    u, k, *vs = list(map(int, input().split()))
    E[u] = vs

d = [0] * (N+1)
f = [0] * (N+1)
t = 0

def dfs(v):
    global t, d, f
    if d[v]:
        return
    t += 1
    d[v] = t
    for u in E[v]:
        dfs(u)
    t += 1
    f[v] = t

for v in range(1, N+1):
    dfs(v)

for v in range(1, N+1):
    print(v, d[v], f[v])

Solution (Python):
from typing import List

def DFS(G: List[int]):
	global time
	time = 0
	n = len(G)
	for u in range(n):
		if color[u] == "WHITE":
			DFS_Visit(u)

def DFS_Visit(u: int):
	global time
	color[u] = "GRAY"
	time += 1
	d[u] = time
	for v in G[u]:
		if color[v] == "WHITE":
			pi[v] = u
			DFS_Visit(v)
	color[u] = "BLACK"
	time += 1
	f[u] = time


if __name__ == "__main__":
	n = int(input())
	G = []
	color = ["WHITE" for _ in range(n)]
	pi = [None for _ in range(n)]
	d = [0 for _ in range(n)]
	f = [0 for _ in range(n)]

	for _ in range(n):
		command = list(map(int, input().split()))
		G.append([x - 1 for x in command[2:]])
	DFS(G)
	for i in range(n):
		print(f"{i + 1} {d[i]} {f[i]}")

Solution (Python):
from enum import Enum

class Color(Enum):
  WHITE = 0
  GRAY = 1
  BLACK = 2

def dfs_visit(u, total_time):
  colors[u] = Color.GRAY
  total_time += 1
  d[u] = total_time
  stack.append(u)
  for v in range(N):
    if adj[u][v] == 1 and colors[v] == Color.WHITE:
      total_time = dfs_visit(v, total_time)
  colors[u] = Color.BLACK
  total_time += 1
  f[u] = total_time
  return total_time



def dfs(total_time):
  for i in range(N):
    if colors[i] != Color.WHITE:
      continue
    total_time = dfs_visit(i, total_time)

N = int(input())
L = [list(map(int, input().split())) for i in range(N)]
adj = [[0 for i in range(N)] for j in range(N)]

for i in range(N):
  for node in L[i][2:]:
    adj[i][node-1] = 1

colors = [Color.WHITE for i in range(N)]
stack = []
total_time = 0
d = [0 for i in range(N)]
f = [0 for i in range(N)]

dfs(total_time)

for i in range(N):
  print(i+1, d[i], f[i])

Solution (Python):
import sys
sys.setrecursionlimit(10**6)
input = sys.stdin.readline

global time
time = 0

def dfs(u: int, visited: list, d: list, f: list, M: list, n: int):
    global time
    visited[u] = True
    time += 1
    d[u] = time
    for j in range(n):
        if M[u][j] == 1 and not visited[j]:
            dfs(j, visited, d, f, M, n)
    time += 1
    f[u] += time

def main():
    n = int(input())
    visited = [False] * n
    M = [[0]*n for _ in range(n)]
    for _ in range(n):
        a = list(map(int, input().split()))
        for i in range(a[1]):
            M[a[0]-1][a[i+2]-1] = 1
    d = [0] * n
    f = [0] * n
    for i in range(n):
        if not visited[i]:
            dfs(i, visited, d, f, M, n)
    for i in range(n):
        print(i+1, d[i], f[i])

if __name__ == '__main__': main()

Solution (Python):
from collections import deque

def dfs(v):
    global t
    
    d[v] = t
    visited[v] = True
    t += 1
    
    for u in graph[v]:
        if not visited[u]: dfs(u)
    f[v] = t
    t += 1
    
    
n = int(input())
graph = [deque() for i in range(n)]

visited = [False] * n
d = [0] * n
f = [0] * n
t = 1

for i in range(n):
    nums = list(map(int, input().split()))
    for j in nums[2:]:
        graph[i].append(j-1)
         
for i in range(n):
    if not visited[i]: dfs(i)

for idx, df in enumerate(zip(d, f)):
    print(idx+1, df[0], df[1])

Solution (Python):
import sys


def input():
    return sys.stdin.readline().rstrip()


def dfs(c, n, G, ans):
    count = c
    for i, flag in enumerate(G[n]):
        if flag == 1 and ans[i][0] == 0:
            count += 1
            ans[i][0] = i + 1
            ans[i][1] = count
            ans[i][2] = dfs(count, i, G, ans)
            count = ans[i][2]
    else:
        return count + 1


def main():
    n = int(input())
    G = [[0] * n for _ in range(n)]
    ans = [[0] * 3 for _ in range(n)]
    for i in range(n):
        u, k, *v = map(int, input().split())
        for j in range(k):
            G[u-1][v[j]-1] = 1

    count = 1
    for i in range(n):
        if ans[i][0] == 0:
            ans[i][0] = i + 1
            ans[i][1] = count
            ans[i][2] = dfs(count, i, G, ans)
            count = ans[i][2] + 1

    for i in range(n):
        print(*ans[i])


if __name__ == '__main__':
    main()

Solution (Python):

n = int(input())
V = [[] for _ in range(n+1)]
for _ in range(n):
    inpt = list(map(int,input().split( )))
    if len(inpt)>2:
        V[inpt[0]] = inpt[2:]


D = [0]*(n+1)
F = [0]*(n+1)

time = 1
Q = [1]
D[0] = -1
D[1] = 1
while len(Q) > 0 or 0 in D[1:]:
    v = Q[-1]
    remains = False
    for i in V[v]:
        if D[i] == 0:
            D[i] = time+1
            Q.append(i)
            remains = True
            break
    if not remains:
        F[v] = time+1
        Q.pop()
        
    time += 1
    if len(Q) == 0:
        if 0 in D:
            time += 1
            nxt = D.index(0)
            Q.append(nxt)
            D[nxt] = time
        else:
            pass
        

for i in range(1,n+1):
    print(i,D[i],F[i])

Solution (Python):
def main():
    n = int(input())
    _next, state, d, f = [], [False] * n, [0] * n, [0] * n
    for _ in range(n):
        u, k, *v = map(lambda s: int(s) - 1, input().split())
        _next.append(sorted(v, reverse=True))
    stack = []
    time = 0

    while True:
        for i in range(n):
            if not state[i]:
                stack.append(i)
                state[i] = True
                time += 1
                d[i] = time
                break
        if not stack:
            break
        while stack:
            u = stack[-1]
            if _next[u]:
                v = _next[u].pop()
                if not state[v]:
                    state[v] = True
                    time += 1
                    d[v] = time
                    stack.append(v)
            else:
                time += 1
                f[u] = time
                stack.pop()

    for i in range(n):
        print(i + 1, d[i], f[i])


if __name__ == '__main__':
    main()

Solution (Python):





from sys import stdin,setrecursionlimit

setrecursionlimit(10**6)


def dfs(v,s):
    seen[v]=True
    first[v]=s
    s+=1
    
    for i in g[v]:
        if seen[i]:
            continue
        s=dfs(i,s)
    
    last[v]=s
    return s+1

n=int(stdin.readline().rstrip())
seen=[False]*n
first=[0]*n
last=[0]*n
g=[[] for _ in range(n)]
s=1
for i in range(n):
    v=list(map(int,stdin.readline().rstrip().split()))
    for j in v[2:]:
        g[v[0]-1].append(j-1)
for i in range(n):
    if not seen[i]:
        s=dfs(i,s)
for i in range(n):
    print(i+1,first[i],last[i])

Solution (Python):
from typing import List


def dfs(adj_matrix: List[List[int]], vartex: int) -> int:
    global step
    global discover_times
    global finish_times
    if 0 != discover_times[vartex]:
        return 0
    discover_times[vartex] = step

    for col_idx in range(len(adj_matrix)):
        if (0 != adj_matrix[vartex][col_idx]) and (0 == discover_times[col_idx]):
            step += 1
            dfs(adj_matrix, col_idx)

    step += 1
    finish_times[vartex] = step

    return 1


if __name__ == "__main__":
    num_vertices = int(input())
    adj_matrix = [[0] * num_vertices for i in range(num_vertices)]

    for _ in range(num_vertices):
        vertex, _, *adjs = map(lambda x: int(x), input().split())
        for adj in adjs:
            adj_matrix[vertex - 1][adj - 1] = 1

    step = 1
    discover_times = [0] * num_vertices
    finish_times = [0] * num_vertices

    for vartex in range(num_vertices):
        if 1 == dfs(adj_matrix, vartex):
            step += 1

    for vertex, (d, f) in enumerate(zip(discover_times, finish_times)):
        print(f"{vertex + 1} {d} {f}")

Solution (Python):
def dfs(v,t):
    d[v]=t
    t+=1
    for i in edge[v]:
        if d[i]==-1:
            t=dfs(i,t)
    f[v]=t
    t+=1
    return t

n=int(input())
edge=[[] for _ in range(n)]
for _ in range(n):
    u,_,*v=map(lambda x:int(x)-1,input().split())
    edge[u]=sorted(v)
d,f=[-1]*n,[-1]*n
k=1
for i in range(n):
    if d[i]==-1:
        k=dfs(i,k)
for i in range(n):
    print(i+1,d[i],f[i])

Solution (Python):
n = int(input())
l = [[] for i in range(n)]


class V:
    def __init__(self, node):
        self.d = -1
        self.f = -1
        self.node = node


for i in range(n):
    _input = [int(j) - 1 for j in input().split(" ")]
    u = _input[0]
    k = _input[1] + 1
    node = sorted(_input[2::])
    if u in node:
        node.remove(u)
    l[u] = V(node)

time = 1


def DFS(i):
    global time
    if l[i].d == -1:
        l[i].d = time
    time += 1
    for n in l[i].node:
        if l[n].d == -1:
            DFS(n)
            time+=1
    if l[i].f == -1:
        l[i].f = time
    return


for i in range(n):
    if l[i].d == -1:
        DFS(i)
        time+=1

for i, v in enumerate(l):
    print(i + 1, v.d, v.f)

Solution (Python):
import sys
input = sys.stdin.readline
v = []
tl = []
t = 1

def rec(node):
	global t, tl, v
	if tl[node-1][0] != -1:
		
		return
	tl[node-1][0] = t
	t += 1
	
	adj = v[node-1][2:]
	
	for i in adj:
		rec(v[i-1][0])
	tl[node-1][1] = t
	t += 1

def main():
	global v, tl
	n = int(input().strip())
	tl = [[-1, -1] for _ in range(n)]
	for i in range(n):
		l = list(map(int, input().strip().split()))
		v.append(l)
	for i in range(1, n+1):
		rec(i)
	for i in range(n):
		print("{} {} {}".format(i+1, tl[i][0], tl[i][1]))

if __name__ == '__main__':
	main()

Solution (Python):
n = int(input())

A = [[0] * n for _ in range(n)]

for _ in range(n):
    u, k, *v = list(map(int, input().split()))
    for j in v:
        A[u-1][j-1] = 1




t = 0
d = [None] * n
f = [None] * n

def dfs_recursive(u):
    global t
    t += 1
    d[u] = t
    for v in range(n):
        if A[u][v] == 1 and d[v] is None:
            dfs_recursive(v)
    t += 1
    f[u] = t

def dfs_stack(root):
    global t
    stack = []
    stack.append(root)
    while stack:

        
        u = stack[-1]

        
        if d[u] is None:
            t += 1
            d[u] = t

        
        has_next_node = False
        for v in range(n):
            if A[u][v] == 1 and d[v] is None:
                stack.append(v)
                has_next_node = True
                break

        
        if not has_next_node:
            t += 1
            
            stack.pop()

            
            f[u] = t
            
for i in range(n):
    if d[i] is None:
        dfs_recursive(i)
        

for i in range(n):
    print(i+1, d[i], f[i])

Solution (Python):
WHITE = 0
GRAY = 1
BLACK = 2

n = int(input())

M = [[0] * n for i in range(n)]

d = [0] * (n)
f = [0] * (n)
color = [WHITE] * (n)


time = 0

def dfs_visit(u):
    global time
    time += 1
    color[u] = GRAY
    d[u] = time
    for v in range(n):
        if M[u][v] == 0:
            continue
        if color[v] == WHITE:
            dfs_visit(v)
    color[u] = BLACK
    time += 1
    f[u] = time

def dfs():
    for u in range(n):
        if color[u] == WHITE:
            dfs_visit(u)

    for u in range(n):
        print("{} {} {}".format(u+1, d[u], f[u]))


if __name__ == "__main__":
    for i in range(n):
        arr = list(map(int, input().split()))
        for v in (arr[2:]):
            M[arr[0]-1][v-1] = 1

    dfs()

Solution (Python):
INTERVAL = 1
WHITE = 0
GRAY = 1
BLACK = 2


def depth_first_search(u):
    global time

    time += INTERVAL
    d[u] += time
    color[u] = GRAY

    for v in range(n):
        if matrix[u][v] and color[v] == WHITE:
            depth_first_search(v)

    time += INTERVAL
    f[u] += time
    color[u] = BLACK


n = int(input())


time = 0
color = [WHITE] * n
d = [0] * n
f = [0] * n

matrix = [[0] * n for _ in range(n)]

for i in range(n):

    u, k, *V = map(int, input().split())

    for v in V:
        v -= 1
        matrix[i][v] = 1



u_search = 0
while True:

    depth_first_search(u_search)

    if WHITE not in color:
        break
    else:
        u_search = color.index(WHITE)
        


for i in range(n):
    print(i + 1, d[i], f[i])

Solution (Python):
n = int(input())
G = []
for i in range(n):
    T = [0]*n
    G.append(T)
for i in range(n):
    L = list(map(int,input().split()))
    for j in range(2,len(L)):
        G[i][L[j]-1] += 1
time = 1
D = [-1]*n
F = [-1]*n
def dfs(src):
    global time
    D[src] = time
    time += 1
    for dst in range(n):
        if G[src][dst] == 1 and D[dst] == -1:
            dfs(dst)
    F[src] = time
    time += 1
for root in range(n):
    if D[root] == -1:
        dfs(root)
for i in range(n):
    print(i+1,D[i],F[i])

Solution (Python):
n = int(input())
al = [list(map(lambda s: int(s) - 1, input().split()))[2:] for _ in range(n)]
begin = [-1] * n
end = [-1] * n
not_visited = list(range(n))
t = 1
def dfs(u):
    global begin, end, t, not_visited
    begin[u] = t
    t += 1
    not_visited.remove(u)
    for v in al[u]:
        if begin[v] == -1:
            dfs(v)
    end[u] = t
    t += 1

while len(not_visited) > 0:
    dfs(not_visited[0])

for i in range(n):
    print('{} {} {}'.format(i + 1, begin[i], end[i]))

Solution (Python):
n=int(input())
ne=[[] for _ in range(n+1)]
for _ in range(n):
    u,k,*v=map(int,input().split())
    ne[u]=v

class dfs:
    def __init__(self, n, ne):
        self.n=n
        self.ne=ne
        self.d=[0]*(n+1)
        self.f=[0]*(n+1)
        self.t=0
    def search(self, a):
        self.t+=1
        self.d[a]=self.t
        for p in ne[a]:
            if self.d[p]==0:
                self.search(p)
        self.t+=1
        self.f[a]=self.t
DFS=dfs(n,ne)
for i in range(1,n+1):
    if DFS.d[i]==0:
        DFS.search(i)
    print(i,DFS.d[i],DFS.f[i])

Solution (Python):
n=int(input())

v=[[]]*n
for i in range(n):
    tmp=list(map(int,input().split()))
    tmp=[i-1 for i in tmp[2:]]
    v[i]=tmp

time=1
D=[-1 for _ in range(n)]
F=[-1 for _ in range(n)]

def dfs(src):
    global time
    D[src]=time
    time+=1
    for dst in v[src]:
        if D[dst]==-1:
            dfs(dst)
    F[src]=time
    time+=1

for root in range(n):
    if D[root]==-1:
        dfs(root)

for i in range(n):
    print(i+1,D[i],F[i])

Solution (Python):
n = int(input())

adj = [ [] for _ in range (n) ]

for i in range(n):
    _, _, *adj[i] = list(map(int, input().split()))

d = [0] * n
f = [0] * n
flag = [0] * n
time = 0

def dfs(u):
    global time
    time += 1
    flag[u-1] = 1
    d[u-1] = time
    
    for v in adj[u-1]:
        if flag[v-1] == 0:
            dfs(v)

    time += 1
    f[u-1] = time

for i in range(n):
    if flag[i] == 0:
        dfs(i+1)

for i in range(n):
    print(i+1, d[i], f[i])

Solution (Python):

import sys
from functools import lru_cache

n = int(sys.stdin.readline().rstrip())
graph = [[0] * (n+1) for _ in range(n+1)]
for i in range(1, n+1):
    tmp = [int(ele) for ele in sys.stdin.readline().rstrip().split()]
    for j in tmp[2:]:
        graph[i][j] = 1

d = [-1] * (n+1)
f = [-1] * (n+1)
yet = [ele for ele in range(1, n+1)]
ct = 0


def main():
    while yet:
        stack = [min(yet)]
        dfs(stack)

    for i, detected_at, finished_at in zip(range(1, n + 1), d, f):
        print(str(i) + " " + str(detected_at) + " " + str(finished_at))


def dfs(stack):
    global yet, ct, graph, d, f
    ct += 1
    d[stack[-1]-1] = ct
    yet.remove(stack[-1])

    for i, adjacency in enumerate(graph[stack[-1]]):
        if adjacency == 1 and i in yet:  
            stack.append(i)
            dfs(stack)
    else:
        ct += 1
        f[(stack[-1]-1)] = ct
        stack.pop()


if __name__ == "__main__":
    main()

Solution (Python):
import sys

time = 0
def dfs(u):
    global time
    flag_list[u] = 1
    time += 1
    d_list[u] = time
    for v in range(n):
        if m_list[u][v] == 1 and flag_list[v] == 0:
            dfs(v)
    flag_list[u] = 2
    time += 1
    f_list[u] = time


input = sys.stdin.readline
n = int(input())
m_list = [[0]*n for _ in range(n)]
for _ in range(n):
    input_list = list(map(int, input().split()))
    index = input_list[0] - 1
    if input_list[1] > 0:
        for a in input_list[2:]:
            m_list[index][a-1] = 1
    
d_list = [0]*n
f_list = [0]*n
flag_list = [0]*n 
for i in range(n):
    if flag_list[i] == 0:
        dfs(i)

for i in range(n):
    print(i+1, d_list[i], f_list[i])

Solution (Python):
n = int(input())
a = []
for i in range(n):
    a += [list(map(int, input().split()))[2:]]
cnt = 1
pre = [0]*n
aft = [0]*n
color = [0]*n
def dfs(s):
    global cnt
    pre[s-1] = cnt
    cnt += 1
    color[s-1] = 1
    for i in a[s-1]:
        if color[i-1] == 0:dfs(i)
    aft[s-1] = cnt
    cnt += 1

for i in range(n):
    if color[i] == 0:
        dfs(i+1)

for i in range(n):
    print(i+1, pre[i], aft[i])

Solution (Python):

n = int(input())
g_list = {}
for _ in range(n):
    n1, num, *cl = map(int, input().split())
    g_list[n1] = cl



class Graph():
    def __init__(self, g_list):
        self.time = 0
        self.nodes = {}
        self.d = {}
        self.f = {}
        self.g_list = g_list

    def dfs(self, node):
        self.time += 1
        self.d[node] = self.time
        for node_ in self.g_list[node]:
            if node_ not in self.d:
                self.dfs(node_)
        self.time += 1
        self.f[node] = self.time


g = Graph(g_list)
for i in range(1, n+1):
    if i not in g.d:
        g.dfs(i)

for g, f in zip(sorted(g.d.items()), sorted(g.f.items())):
    print(g[0], g[1], f[1])

Solution (Python):

"""
Created on Sat Apr  6 11:36:14 2019

@author: Yamazaki Kenichi
"""

n = int(input())
A = [[]]
A = A + [list(map(int,input().split())) for i in range(n)]

def dfs(k):
    global counta
    for i in range(A[k][1]):
        if T[A[k][i+2]][0] == -1:
            T[A[k][i+2]][0] = 0
            T[A[k][i+2]][1] = counta
            counta += 1
            dfs(A[k][i+2])
    T[k][2] = counta
    T[k][0] = 1
    counta += 1

T = [[-1,-1,-1] for i in range(n+1)]
counta = 1
for i in range(1,n+1):
    if T[i][0] == -1:
        T[A[i][0]][0],T[A[i][0]][1] = 0, counta
        counta += 1
        dfs(i)

for i in range(1,n+1):
    print(" ".join(map(str,[i,T[i][1],T[i][2]])))

Solution (Python):
n = int(input())
g = [[0]*(n+1) for _ in range(n+1)]
for i in range(n):
    u, k, *v, = map(int, input().split())
    for vi in v:
        g[u][vi] = 1

d = [0]*(n+1)
f = [0]*(n+1)
t = 0


def dfs(u):
    global t
    if d[u] != 0:
        return
    t += 1
    d[u] = t
    for i, v in enumerate(g[u]):
        if v == 1:
            dfs(i)
    t += 1
    f[u] = t


for i in range(1, n+1):
    if d[i] == 0:
        dfs(i)
for i in range(1, n+1):
    print(f"{i} {d[i]} {f[i]}")