Problem:
Depth First Search Depth-first search (DFS) follows the strategy to search ”deeper” in the graph whenever possible. In DFS, edges are recursively explored out of the most recently discovered vertex $v$ that still has unexplored edges leaving it. When all of $v$'s edges have been explored, the search ”backtracks” to explore edges leaving the vertex from which $v$ was discovered. This process continues until all the vertices that are reachable from the original source vertex have been discovered. If any undiscovered vertices remain, then one of them is selected as a new source and the search is repeated from that source. DFS timestamps each vertex as follows:  $d[v]$ records when $v$ is first discovered.  $f[v]$ records when the search finishes examining $v$’s adjacency list.  Write a program which reads a directed graph $G = (V, E)$ and demonstrates DFS on the graph based on the following rules:  $G$ is given in an adjacency-list. Vertices are identified by IDs $1, 2,... n$ respectively.  IDs in the adjacency list are arranged in ascending order.  The program should report the discover time and the finish time for each vertex.  When there are several candidates to visit during DFS, the algorithm should select the vertex with the smallest ID.  The timestamp starts with 1.  Input In the first line, an integer $n$ denoting the number of vertices of $G$ is given. In the next $n$ lines, adjacency lists of $u$ are given in the following format: $u$ $k$ $v_1$ $v_2$ ... $v_k$ $u$ is ID of the vertex and $k$ denotes its degree. $v_i$ are IDs of vertices adjacent to $u$. Output For each vertex, print $id$, $d$ and $f$ separated by a space character in a line. $id$ is ID of the vertex, $d$ and $f$ is the discover time and the finish time respectively. Print in order of vertex IDs. Constraints  $1 \leq n \leq 100$  Sample Input 1 4
1 1 2
2 1 4
3 0
4 1 3 Sample Output 1 1 1 8
2 2 7
3 4 5
4 3 6 Sample Input 2 6
1 2 2 3
2 2 3 4
3 1 5
4 1 6
5 1 6
6 0 Sample Output 2 1 1 12
2 2 11
3 3 8
4 9 10
5 4 7
6 5 6   This is example for Sample Input 2 (discover/finish)  Reference Introduction to Algorithms, Thomas H. Cormen, Charles E. Leiserson, Ronald L. Rivest, and Clifford Stein. The MIT Press.

Solution (Python):
n = int(input())
A = [[False for _ in range(n)] for _ in range(n)]
for _ in range(n):
    tmp = list(map(int, input().split()))
    for i in range(tmp[1]):
        A[tmp[0]-1][tmp[i+2]-1] = True

WHITE = 0
GRAY = 1
BLACK = 2
color = [WHITE for _ in range(n)]
d = [0 for _ in range(n)]
f = [0 for _ in range(n)]
time = 1

def dfs(u):
    global dfs_color, d, f, time
    color[u] = GRAY
    d[u] += time
    time += 1
    for v in range(n):
        if A[u][v]:
            if color[v] == WHITE:
                dfs(v)
        else:
            continue
    color[u] = BLACK
    f[u] = time
    time += 1 

for u in range(n):
    if color[u] == WHITE:
        dfs(u)

for i in range(n):
    print(str(i+1) + ' ' + str(d[i]) + ' ' + str(f[i]) )

Solution (Python):
from collections import defaultdict

def dfs(here, connect, visited, answer):
    global time
    answer[here][1] = time
    time += 1
    visited[here] = 1
    for c in connect[here]:
        if not visited[c]:
            dfs(c, connect, visited, answer)
    answer[here][2] = time
    time += 1

v_num = int(input())
connect = defaultdict(list)
for _ in range(v_num):
    inp = [int(n) - 1 for n in input().split(" ")]
    connect[inp[0]].extend(sorted(inp[2:]))
answer = [[n + 1 for m in range(3)] for n in range(v_num)]
time = 1
visited = [0 for n in range(v_num)]
for i in range(v_num):
    if not visited[i]:
        dfs(i, connect, visited, answer)
for v in range(v_num):
    print(*answer[v])

Solution (Python):
j = 1

def dfs(graph, start, result, visited=None):
    global j
    if visited == None:
        visited = []
    visited.append(start)
    result[start][1]  = j
    for next in graph[start][2:]:
        if next in visited:
            continue
        j += 1
        dfs(graph, next, result, visited)
    else:
        j += 1
        result[start][2] = j

n = int(input())
g = [[]]
r = [[i,0,0] for i in range(n + 1)]
v = []

for i in range(n):
    g.append(list(map(int, input().split())))


for i in range(1, n + 1):
    if i in v:
        continue
    dfs(g,i,r,v)
    j += 1

for i in range(1,n+1):
    print(*r[i])

Solution (Python):
n=int(input())
adj=[]
for i in range(n):
      adj.append(list(map(int, input().split())))

edge=[[0 for i2 in range(n)]for i1 in range(n)]



for i in range(n):
    for j in range(adj[i][1]):
        edge[i][adj[i][j+2]-1]=1


time=1
discover=[0 for i in range(n)]
final=[0 for i in range(n)]
stack=[]

def dfs(id,time):
    for i in range(n):
        c=0
        if edge[id][i]==1 and discover[i]==0:
            stack.append(id)
            discover[i]=time
            c+=1
            
            dfs(i,time+1)
        else:
            pass
    if c==0:
        if len(stack)>0:
            if final[id]==0:
                final[id] = time
                
                dfs(stack.pop(), time + 1)
            else:
                
                dfs(stack.pop(),time)

discover[0]=time
stack.append(0)
dfs(0,time+1)


for i in range(n):
    if discover[i]==0:
        discover[i]=final[0]+1
        stack.append(i)
        dfs(i,final[0]+2)
        break

for i in range(n):
    print(i+1,discover[i],final[i])

Solution (Python):
def dfs(u):
    global dfs_color, d, f, t
    color[u] = GRAY
    d[u] += t
    t += 1
    for v in range(n):
        if (M[u][v] == 0):
            continue
        else:
            if (color[v] == WHITE):
               dfs(v)
    color[u] = BLACK
    f[u] = t
    t += 1

n = int(input())
M = [[False for i in range(n)] for j in range(n)]
for i in range(n):
    tmp = list(map(int, input().split()))
    for j in range(tmp[1]):
        M[tmp[0]-1][tmp[j+2]-1] = True

WHITE = 0
GRAY = 1
BLACK = 2
color = [WHITE for i in range(n)]
d = [0 for i in range(n)]
f = [0 for i in range(n)]
t = 1

for u in range(n):
    if (color[u] == WHITE):
        dfs(u)
for u in range(n):
    print(str(u+1), str(d[u]), str(f[u]), sep = " ")

Solution (Python):
def dfs_visit(u):
    global dfs_color, d, f, t
    color[u] = GRAY
    d[u] += t
    t += 1
    for v in range(n):
        if M[u][v] == 0:
            continue
        if color[v] == WHITE:
            dfs_visit(v)
    color[u] = BLACK
    f[u] += t
    t += 1

n = int(input())
M = [[False for i in range(n)] for j in range(n)]
WHITE = 0
GRAY = 1
BLACK = 2
color = [WHITE for i in range(n)]
d = [0 for i in range(n)]
f = [0 for i in range(n)]
t = 1
for i in range(n):
        a = list(map(int, input().split()))
        for j in range(a[1]):
            M[a[0] - 1][a[j + 2] - 1] = True
for u in range(n):
    if color[u] == WHITE:
        dfs_visit(u)
for u in range(n):
    print(str(u + 1), str(d[u]), str(f[u]), sep = " ")

Solution (Python):
n = int(input())
a = [[0]*n for i in range(n)]
  
for i in range(n):
    v = list(map(int, input().split()))
    u = v[0]
    k = v[1]
    for j in range(k):
        a[u - 1][v[2 + j] - 1] = 1

d = [0] * n
f = [0] * n
isDiscovered = [False] * n
time_stamp = 0

def dfs(x):
    global time_stamp
    isDiscovered [x] = True
    time_stamp = time_stamp + 1
    d[x] = time_stamp
    for i in range(n):
        if a[x][i] == 1 and isDiscovered[i] == False:
            dfs(i)
    time_stamp = time_stamp + 1
    f[x] = time_stamp

for i in range(n):
    if isDiscovered[i] == False:
        dfs(i)

for i in range(n):
    print(i+1, d[i], f[i])

Solution (Python):
n = int(input())
a = [[False]*n for i in range(n)]
  
for i in range(n):
    v = list(map(int, input().split()))
    u = v[0]
    k = v[1]
    for j in range(k):
        a[u - 1][v[2 + j] - 1] = True

d = [0] * n
f = [0] * n
isDiscovered = [False] * n
time_stamp = 0

def dfs(x):
    global time_stamp
    isDiscovered [x] = True
    time_stamp = time_stamp + 1
    d[x] = time_stamp
    for i in range(n):
        if a[x][i]and not isDiscovered[i]:
            dfs(i)
    time_stamp = time_stamp + 1
    f[x] = time_stamp

for i in range(n):
    if not isDiscovered[i]:
        dfs(i)

for i in range(n):
    print(i+1, d[i], f[i])

Solution (Python):
n = int(input())
a = [[] for i in range(n)]

for i in range(n):
    v = list(map(int, input().split()))
    u = v[0] - 1
    for j in v[2:]:
        a[u].append(j-1)

d = [0] * n
f = [0] * n
isDiscovered = [False] * n
time_stamp = 0

def dfs(x):
    global time_stamp
    isDiscovered [x] = True
    time_stamp += 1
    d[x] = time_stamp
    for i in a[x]:
        if not isDiscovered[i]:
            dfs(i)
    time_stamp += 1
    f[x] = time_stamp

for i in range(n):
    if not isDiscovered[i]:
        dfs(i)

for i in range(n):
    print(i+1, d[i], f[i])

Solution (Python):
n=int(input())
adj=[None]
for i in range(n):
    adj_i=list(map(int,input().split()[2:]))
    adj.append(adj_i)
sndf=[None]
for i in range(1,n+1):
    sndf.append([False,i])
path=[]
time=0
def dfs(u):
    global time
    sndf[u][0]=True
    time+=1
    sndf[u].append(time)
    for v in adj[u]:
        if not sndf[v][0]:
            dfs(v)
    time+=1
    sndf[u].append(time)
for i in range(1,n+1):
    if not sndf[i][0]:
        dfs(i)
for x in sndf[1:]:
    print(*x[1:])

Solution (Python):
n=int(input())
d=[0 for _ in range(n+1)]
f=[0 for _ in range(n+1)]
G=[]
G.append([])
for i in range(n):
    u,k,*v=map(int,input().split())
    G.append(v)

checked=[False for _ in range(n+1)]
timestamp=1

def dfs(id):
    global timestamp
    d[id]=timestamp
    checked[id]=True
    timestamp+=1
    for v in G[id]:
        if not checked[v]:
            dfs(v)
    f[id]=timestamp
    timestamp+=1

for id in range(1,n+1):
    if not checked[id]:
        dfs(id)

for i in range(1,n+1):
    print("{0} {1} {2}".format(i,d[i],f[i]))

Solution (Python):

from collections import deque

n = int(input())
adj={}
visited={}
d={}
f={}
t=0
visited=set()
for i in range(n):
  raw=list(map(int,input().split()))
  u = raw.pop(0)
  k = raw.pop(0)
  raw.sort()
  q = deque(raw)
  adj[u] = q  
  d[u] = -1
  f[u] = -1

next = 1
v = next
d[next] = t + 1
stack = deque()
visited.add(v)

while True:
  t = t+1
  clear = True
  while adj[v]:
    cand = adj[v].popleft()
    if cand not in visited:
      next = cand
      d[next] = t + 1
      visited.add(next)
      clear = False
      break
  if clear:
    f[v] = t + 1
    if stack:
      next = stack.pop()
      v = next
    else:
      end = True
      for i in range(n):
        if i+1 not in visited:
          next = i+1
          end = False
          break
      if end:
        break
      else:
        t = t+1
        v = next
        d[next] = t + 1
        visited.add(v)
  else:
    stack.append(v)
    v = next


i = 0
for j in range(n):
  i += 1
  print(str(i) + " " + str(d[i]) + " " + str(f[i]))

Solution (Python):

from collections import deque
n = int(input())
arrow = {}
visited = set()
d = {}
f = {}


for i in range(n):
  raw = list(map(int,input().split()))
  
  u = raw.pop(0)
  k = raw.pop(0)
  raw.sort()
  q = deque(raw)
  arrow[u] = q
  d[u] = -1
  f[u] = -1

def dfslocal(v,t,arrow,f,d):
  t += 1
  d[v] = t
  visited.add(v)
  
  while arrow[v]:
    k = arrow[v].popleft()
    if k not in visited:
      
      t = dfslocal(k,t,arrow,f,d)
  f[v] = t+1
  return t+1

def dfsglobal(arrow,f,d):
  t = 0
  for u in range(n):
    if u+1 not in visited:
      t = dfslocal(u+1,t,arrow,f,d)
  return t

t = dfsglobal(arrow,f,d)

for i in range(n):
  print(str(i+1) + " " + str(d[i+1]) + " " + str(f[i+1]))

Solution (Python):



if __name__ == '__main__':

    n = int(input())
    M = [[0 for i in range(n)] for j in range(n)]
    for _ in range(n):
        l = list(map(int, input().split(" ")))
        u = l[0]
        k = l[1]
        if k != 0:
            for v in l[2:]:
                M[u-1][v-1] = 1
    
    color = [0]*n
    d = [0]*n
    f = [0]*n
    time = 0
    
    def dfs(u): 
        global time
        color[u] = 1
        time += 1
        d[u] = time
        for v in range(n):
            if M[u][v] == 1 and color[v] == 0:
                dfs(v)
        color[u] = 2
        time += 1
        f[u] = time
    
    for u in range(n):
        if color[u] == 0:
            dfs(u)

    for u in range(n):
        print(u+1, d[u], f[u])

Solution (Python):
from sys import stdin

global time
time = 0

def dfs(graph,start,state,discover,finish):

    state[start-1] = 1
    global time
    time = time + 1
    discover[start-1] = time
    

    neighbours = sorted(graph[start])

    for neighbour in neighbours:
        if state[neighbour-1] == 0:
            dfs(graph,neighbour,state,discover,finish)

    state[start-1] = 2
    time = time + 1
    finish[start - 1] = time
    

def main():
    
    
    
    
    
    



    
    n = int(stdin.readline())

    g = {}

    d = [0]*n
    f = [0]*n

    all_vertex = []

    for i in xrange(n):
        entry = [int(s) for s in stdin.readline().split()[2:]]
        g[i+1] = entry
        all_vertex.append(i+1)



    
    
    state = [0]*n

    for node in all_vertex:
        if state[node-1] == 0:
            dfs(g,node,state,d,f)

    

    
    

    
    for i in xrange(n):
        print str(i+1) + ' ' + str(d[i]) + ' ' + str(f[i])

main()

Solution (Python):
def MAIN():
    n = int(input())
    ans = [[i, 0, 0] for i in range((n + 1))]
    G = [[] for _ in range((n + 1))]
    for _ in range(n):
        u, k, *v = map(int, input().split())
        G[u] = v
    cnt = 1
    def dfs(u):
        nonlocal ans
        if ans[u][1] != 0:
            return
        nonlocal cnt
        ans[u][1] = cnt
        cnt += 1
        for v in G[u]:
            dfs(v)
        ans[u][2] = cnt
        cnt += 1
    for i in range(1, n + 1):
        if ans[i][1] == 0:
            dfs(i)
    for i in range(1, n + 1):
        print(" ".join(map(str, ans[i])))
MAIN()

Solution (Python):
def MAIN():
    n = int(input())
    ans = [[i, 0, 0] for i in range((n + 1))]
    G = [[] for _ in range((n + 1))]
    for _ in range(n):
        u, k, *v = map(int, input().split())
        G[u] = v
    cnt = 1
    def dfs(u):
        nonlocal ans
        if ans[u][1] != 0:
            return
        nonlocal cnt
        ans[u][1] = cnt
        cnt += 1
        for v in G[u]:
            dfs(v)
        ans[u][2] = cnt
        cnt += 1
    for i in range(1, n + 1):
        if ans[i][1] == 0:
            dfs(i)
    for i in range(1, n + 1):
        print(*ans[i])
MAIN()

Solution (Python):
def MAIN():
    n = int(input())
    ans = [[i, 0, 0] for i in range((n + 1))]
    G = [[] for _ in range((n + 1))]
    for _ in range(n):
        u, k, *v = map(int, input().split())
        G[u] = v
    cnt = 1
    def dfs(u):
        nonlocal ans
        if ans[u][1] != 0:
            return
        nonlocal cnt
        ans[u][1] = cnt
        cnt += 1
        for v in G[u]:
            dfs(v)
        ans[u][2] = cnt
        cnt += 1
    for i in range(1, n + 1):
        if ans[i][1] == 0:
            dfs(i)
        print(*ans[i])
MAIN()

Solution (Python):
def d(u):
 global t
 C[u]=1;t+=1;D[u]=t
 for v in range(N):
  if M[u][v]and C[v]==0:d(v)
 C[u]=2;t+=1;F[u]=t
N=int(input())
M=[[0]*N for _ in[0]*N]
for e in[list(map(int,input().split()))for _ in[0]*N]:
 for v in e[2:]:M[e[0]-1][v-1]=1
C,D,F=[0]*N,[0]*N,[0]*N
t=0
for i in range(N):
 if C[i]==0:d(i)
for i in range(N):print(i+1,D[i],F[i])

Solution (Python):
def d(u):
 global t
 C[u]=1;t+=1;D[u]=t
 for v in range(N):
  if M[u][v]and C[v]==0:d(v)
 C[u]=2;t+=1;F[u]=t
N=int(input())
M=[[0]*N for _ in[0]*N]
for e in[list(map(int,input().split()))for _ in[0]*N]:
 for v in e[2:]:M[e[0]-1][v-1]=1
C,D,F=[0]*N,[0]*N,[0]*N
t=0
for i in range(N):
 if C[i]==0:d(i)
for i in range(N):print(i+1,D[i],F[i])

Solution (Python):
def d(u):
 global t
 C[u]=1;t+=1;D[u]=t
 for v in range(N):
  if M[u][v]and C[v]==0:d(v)
 C[u]=2;t+=1;F[u]=t
N=int(input())
M=[[0]*N for _ in[0]*N]
for e in[input().split()for _ in[0]*N]:
 for v in e[2:]:M[int(e[0])-1][int(v)-1]=1
C,D,F=[0]*N,[0]*N,[0]*N
t=0
for i in range(N):
 if C[i]==0:d(i)
for i in range(N):print(i+1,D[i],F[i])

Solution (Python):
def d(u):
 global t
 C[u]=0;t+=1;D[u]=t
 for v in R:
  if M[u][v]and C[v]:d(v)
 t+=1;F[u]=t
N=int(input());R=range(N)
M=[[0]*N for _ in R]
for e in[input().split()for _ in R]:
 for v in e[2:]:M[int(e[0])-1][int(v)-1]=1
C,D,F=[1]*N,[0]*N,[0]*N
t=0
for i in R:
 if C[i]:d(i)
for i in R:print(i+1,D[i],F[i])

Solution (Python):
def d(u):
 global t
 C[u]=0;t+=1;D[u]=t
 for v in R:
  if M[u][v]and C[v]:d(v)
 t+=1;F[u]=t
N=int(input());R=range(N)
M=[[0]*N for _ in R]
for e in[input().split()for _ in R]:
 for v in e[2:]:M[int(e[0])-1][int(v)-1]=1
C,D,F=[1]*N,[0]*N,[0]*N
t=0
for i in R:
 if C[i]:d(i)
for i in R:print(i+1,D[i],F[i])

Solution (Python):
def d(u):
 global t
 C[u]=0;D[u]=t;t+=1
 for v in M[u]:
  v=int(v)-1
  if C[v]:d(v)
 F[u]=t;t+=1
N=int(input());R=range(N)
M=[input().split()[2:]for _ in R]
C,D,F=[1]*N,[0]*N,[0]*N
t=1
for i in R:
 if C[i]:d(i)
for i in R:print(i+1,D[i],F[i])

Solution (Python):
def d(u):
 global t
 C[u]=0;D[u]=t;t+=1
 for v in M[u]:v=int(v)-1;C[v]and d(v)
 F[u]=t;t+=1
N=int(input());R=range(N)
M=[input().split()[2:]for _ in R]
C,D,F=[1]*N,[0]*N,[0]*N
t=1
for i in R:C[i]and d(i)
for i in R:print(i+1,D[i],F[i])

Solution (Python):
def d(u):
 global t
 C[u]=1;D[u]=t;t+=1
 for v in M[u]:v=int(v)-1;C[v]or d(v)
 F[u]=t;t+=1
N=int(input());R=range(N)
M=[input().split()[2:]for _ in R]
C,D,F=[0]*N,[0]*N,[0]*N
t=1
for i in R:C[i]or d(i)
for i in R:print(i+1,D[i],F[i])

Solution (Python):
class Vertex:
    _id = -1
    _children = []
    _visited = False
    _visited_time = 0
    _all_visited_time = 0

    def __init__(self, i, c):
        self._id = i
        self._children = c

    def getId(self):
        return self._id

    def getChildren(self):
        return self._children

    def isVisited(self):
        return self._visited

    def getVisitedTime(self):
        return self._visited_time

    def setVisitedTime(self, t):
        self._visited_time = t
        self._visited = True

    def getAllVisitedTime(self):
        return self._all_visited_time

    def setAllVisitedTime(self, t):
        self._all_visited_time = t

    def print(self):
        print("{} {} {}".format(self._id, self._visited_time, self._all_visited_time))


n = int(input())
graph = [0 for i in range(n)]
time = 0


for i in range(n):
    u = list(map(int, input().split(' ')))
    adj = []
    if u[1] > 0:
        adj = u[2:u[1]+2]
    graph[u[0]-1] = Vertex(u[0], adj)


def dfs(v):
    global time
    time += 1
    v.setVisitedTime(time)
    for child in v.getChildren():
        if not graph[child-1].isVisited():
            dfs(graph[child-1])
    time += 1
    v.setAllVisitedTime(time)


for v in graph:
    if not v.isVisited():
        dfs(v)


for v in graph:
    v.print()

Solution (Python):
from enum import Enum, auto

class Color(Enum):
    WHITE = auto() 
    GRAY = auto() 
    BLACK = auto() 

n = int(input())
d = [0 for i in range(n)]
f = [0 for i in range(n)]

colors = [] 
A = [[0 for j in range(n)] for i in range(n)] 



for i in range(n):
    arr = list(map(int, input().split(' ')))
    u, k, v = arr[0], arr[1], arr[2:]
    for j in range(k):
        A[u-1][v[j]-1] = 1

time = 0
def dfs_init():
    global colors
    colors = [Color.WHITE for i in range(n)]
    dfs(0)

def dfs(u):
    global time
    colors[u] = Color.GRAY
    time += 1
    d[u] = time
    for v in range(n):
        if A[u][v] == 1 and colors[v] == Color.WHITE:
            dfs(v)
    colors[u] = Color.BLACK
    time += 1
    f[u] = time

dfs_init()
for u in range(n):
    if colors[u] == Color.WHITE:
        dfs(u)


for i in range(n):
    print(i+1, d[i], f[i])

Solution (Python):
import abc


class AdjacentGraph:
    """Implementation adjacency-list Graph.
    Beware ids are between 1 and size.
    """
    def __init__(self, size):
        self.size = size
        self._nodes = [[0] * (size+1) for _ in range(size+1)]

    def set_adj_node(self, id_, adj_id):
        self._nodes[id_][adj_id] = 1

    def __iter__(self):
        self._id = 0
        return self

    def __next__(self):
        if self._id < self.size:
            self._id += 1
            return (self._id, self._nodes[self._id][1:])

        raise StopIteration()

    def dfs(self, handler=None):

        visited = []
        while len(visited) < self.size:
            for id_ in range(1, self.size+1):
                if id_ not in visited:
                    stack = [(id_, 0)]
                    break
            while len(stack) > 0:
                i, j = stack.pop()
                if j == 0:
                    if handler:
                        handler.visit(i)
                    visited.append(i)
                    yield i
                try:
                    j = self._nodes[i].index(1, j+1)
                    stack.append((i, j))
                    if j not in visited:
                        stack.append((j, 0))
                except ValueError:
                    if handler:
                        handler.leave(i)


class EventHandler(abc.ABC):
    @abc.abstractmethod
    def visit(self, i):
        pass

    @abc.abstractmethod
    def leave(self, i):
        pass


class Logger(EventHandler):
    def __init__(self, n):
        self.log = [(0, 0)] * n
        self.step = 0

    def visit(self, i):
        self.step += 1
        self.log[i-1] = (self.step, 0)

    def leave(self, i):
        self.step += 1
        (n, m) = self.log[i-1]
        self.log[i-1] = (n, self.step)

    def by_node(self):
        i = 1
        for discover, finish in self.log:
            yield (i, discover, finish)
            i += 1


def run():
    n = int(input())
    g = AdjacentGraph(n)
    log = Logger(n)

    for i in range(n):
        id_, c, *links = [int(x) for x in input().split()]
        for n in links:
            g.set_adj_node(id_, n)

    for i in g.dfs(log):
        pass

    for node in log.by_node():
        print(" ".join([str(i) for i in node]))


if __name__ == '__main__':
    run()

Solution (Python):
import sys
n = int(input())
input_line = [[int(i) for i in str.split()] for str in sys.stdin.read().splitlines()]
for i in range(n):
    input_line[i] = [] if len(input_line[i]) == 2 else input_line[i][2:]
detect_time = [0] * n
finish_time = [0] * n
is_visit = [False] * n
stack = []
time = 0

while(time < n*2):
    time += 1
    id = is_visit.index(False) + 1
    stack.append(id)
    is_visit[id-1] = True
    detect_time[id-1] = time
    while(len(stack) != 0):
        id = stack[-1]
        if len(input_line[id-1]) == 0:
            time += 1
            finish_time[stack.pop()-1] = time
        else:
            detect_id = input_line[id-1].pop(0)
            if is_visit[detect_id-1]:
                continue
            stack.append(detect_id)
            time += 1
            detect_time[detect_id-1] = time
            is_visit[detect_id-1] = True


for id in range(n):
    print('{0} {1} {2}'.format(id+1, detect_time[id], finish_time[id]))

Solution (Python):

d = None
f = None


def dfs(g, cur, time):
    global d, f
    d[cur] = time
    for next in g[cur]:
        if d[next] == 0:
            time = dfs(g, next, time+1)
    f[cur] = time + 1
    return time + 1


def main():
    global d, f
    n = int(input())
    g = [[] for _ in range(n)]
    d = [0 for _ in range(n)]
    f = [0 for _ in range(n)]
    for _ in range(n):
        inp = list(map(int, input().split()))
        m = inp[0] - 1
        k = inp[1]
        for i in range(k):
            g[m].append(inp[i+2] - 1)
    time = 1
    for i in range(n):
        if d[i] == 0:
            time = dfs(g, i, time) + 1
    for i in range(n):
        print(i+1, d[i], f[i])


if __name__ == '__main__':
    main()

Solution (Python):
n = int(input())
m = [[0 for j in range(n)] for i in range(n)]
color = [0 for i in range(n)]
d = [0 for i in range(n)]
f = [0 for i in range(n)]
time = [0]


def dfs(u):
    color[u] = 1
    time[0] += 1
    d[u] = time[0]
    for i in range(n):
        if m[u][i] == 1 and color[i] == 0:
            dfs(i)

    color[u] = 2
    time[0] += 1
    f[u] = time[0]


def main():
    for i in range(n):
        data = list(map(int, input().split()))
        for j in range(2, len(data)):
            m[data[0]-1][data[j]-1] = 1

    for i in range(n):
        if color[i] == 0:
            dfs(i)

    for i in range(n):
        print(i+1, d[i], f[i])


if __name__ == '__main__':
    main()

Solution (Python):
n = int(input())
g = []
for i in range(n):
    a = list(map(int,input().split()))
    g.append(a[2:])
d = [0]*n
f = [0]*n
global t
t = 1
d[0] = 1
x = 1
def find(x):
    global t
    if len(g[x-1]) == 0:
        t += 1
        f[x-1] = t
    else:
        for i in g[x-1]:
            if d[i-1] == 0:
                t += 1
                d[i-1] = t
                find(i)
        t += 1
        f[x-1] = t

find(x)
for i in range(n):
    if d[i] == 0:
        t += 1
        d[i] = t
        find(i+1)
for i in range(n):
    print(i+1, d[i], f[i])

Solution (Python):
n = int(input())
g = []
for i in range(n):
    a = list(map(int,input().split()))
    g.append(a[2:])
d = [0]*n
f = [0]*n
global t
t = 0

def find(x):
    global t
    if len(g[x-1]) == 0:
        t += 1
        f[x-1] = t
    else:
        for i in g[x-1]:
            if d[i-1] == 0:
                t += 1
                d[i-1] = t
                find(i)
        t += 1
        f[x-1] = t

for i in range(n):
    if d[i] == 0:
        t += 1
        d[i] = t
        find(i+1)
for i in range(n):
    print(i+1, d[i], f[i])

Solution (Python):
global t
t = 0

class Node:
    def __init__(self, num, deg, neib):
        self.num = num
        self.deg = deg
        self.neib = neib

def dfs(G, d, f, now): 
    
    global t
    t += 1
    
    if d[now-1] != 0:
        t -= 1
        
    else:
        d[now-1] = t
        
        
        for i in G[now-1].neib:
            
            if i != -1:
                
                dfs(G, d, f, i)
            
        t += 1
        f[now-1] = t

        


dnum = int(input()) 
N = []
for i in range(dnum):
    data = input().split()
    
    u = int(data[0])
    k = int(data[1])
    if k > 0:
        v = list(map(int, data[2:]))
    else:
        v = [-1]

    node = Node(u,k,v)
    N.append(node)

d = [0]*dnum 
f = [0]*dnum 

while 0 in d:
    s = d.index(0)
    dfs(N, d, f, s+1)
    

for i in range(dnum):
    print(i+1, d[i], f[i])

Solution (Python):
n = int(input())
B = [[0 for i in range(n)] for j in range(n)]
chk = [0 for i in range(n)]
s = []
i_array = [0 for i in range(n)]
time = 1
node_start_time = [0 for i in range(n)]
node_finish_time = [0 for i in range(n)]

for i in range(n):
    A = list(map(int,input().split()))
    for j in range(A[1]):
        B[A[0]-1][A[j+2]-1] = 1

for i in range(n):
    if(chk[i] == 1):
        continue
    chk[i] = 1
    node_start_time[i] = time
    time += 1
    s.append(i)
    while(len(s) != 0):
        flag = 0
        v = s[len(s)-1]
        for j in range(i_array[v],n):
            if(B[v][j] == 1 and chk[j] == 0):
                chk[j] = 1
                s.append(j)
                node_start_time[j] = time
                time += 1
                i_array[v] = j+1
                flag = 1
                break
        if(flag == 0):
            s.pop()
            node_finish_time[v] = time
            time += 1

for i in range(n):
    print(i+1,node_start_time[i],node_finish_time[i])

Solution (Python):


n=int(input())
ls=[[0 for i in range(n)]for j in range(n)]
for i in range(n):
	tmp=input().split()
	for j in range(int(tmp[1])):
		ls[i][int(tmp[j+2])-1]=1

"""
for i in range(n):
    for j in range(n):
        if(j!=n-1):
            print(int(ls[i][j]), end=' ')
        else:
            print(int(ls[i][j]))
"""
stuck=[0]
count=1
d=[0 for i in range(n)]
f=[0 for i in range(n)]
d[0]=count
for i in range(n):
	ls[i][0]=0

while True:
	count+=1
	p=0
	
	for i in range(n):
		if ls[stuck[len(stuck)-1]][i] is not 0:
			ls[stuck[len(stuck)-1]][i]=0
			p=1
			
			stuck.append(i)
			d[stuck[len(stuck)-1]]=count
			break
	
	if p is 1:
		for i in range(n):
			ls[i][stuck[len(stuck)-1]]=0

	if p is 0:
		
		a=stuck.pop()
		f[a]=count
		for i in range(n):
			ls[a][i]=0
	
	if len(stuck) is 0:
		t=0
		for i in range(n):
			for j in range(n):
				if ls[i][j] is not 0 and t is 0:
					count+=1
					stuck.append(i)
					d[stuck[len(stuck)-1]]=count
					
					t=1
					
		if t is 0:
			break
		
	

for i in range(n):
	print(i+1,d[i],f[i])

Solution (Python):
def dfs(adj, s, d, f, now):
    now += 1
    d[s] = now
    for t in adj[s]:
        if t != s and f[t] < 0 and d[t] < 0:
            d, f, now = dfs(adj, t, d, f, now)
    now += 1
    f[s] = now
    return d, f, now


n = int(input())
adj = [[] for _ in range(n)]
for _ in range(n):
    s = [int(x) for x in input().split()]
    u = s[0]
    for v in s[2:]:
        adj[u - 1].append(v - 1)
    adj[u - 1].sort()

d = [-1 for _ in range(n)]
f = [-1 for _ in range(n)]
now = 0
for s in range(n):
    if f[s] < 0:
        d, f, now = dfs(adj, s, d, f, now)

for i in range(n):
    print(str(i + 1) + " " + str(d[i]) + " " + str(f[i]))

Solution (Python):
n=int(input())

next=[[] for i in range(n)]
for i in range(n):
	l=list(map(int,input().split()))
	u=l[0]
	k=l[1]
	for j in range(2,k+2):
		next[u-1].append(l[j]-1)

stk=[]
stk.append(0)
time=1
d=[0 for i in range(n)]
f=[0 for i in range(n)]
know=[0 for i in range(n)]

def dfs(x):
	global time
	know[x]=1
	d[x]=time
	time+=1
	for n in next[x]:
		if know[n]==0:
			dfs(n)
	f[x]=time
	time+=1
	
for i in range(n):
	if know[i]==0:
		dfs(i)

for i in range(n):
	out=[]
	out.append(i+1)
	out.append(d[i])
	out.append(f[i])
	print(*out)

Solution (Python):
n=0
t=1
def adjacent_matrix():
    global n
    n=int(input())
    v=[]
    array=[]
    for i in range(n):
        zero=[0 for i in range(n)]
        a=list(map(int,input().split()))
        a=a[2:]
        for j in a:
            zero[j-1]=1
        array.append(zero)
    return array
def dfs(array,i,d,f):
    global t
    if i == n:
        return
    else:
        if(d[i] == 0):
            d[i] = t
            t += 1
            for (j,x) in enumerate(array[i]):
                if x == 1:
                    dfs(array,j,d,f)
            f[i] = t
            t += 1
    return 


def main():
    array=adjacent_matrix()
    d=[0 for i in range(n)]
    f=[0 for i in range(n)]
    for i in range(n):
        dfs(array,i,d,f)
    for i in range(n):
        print("{} {} {}".format(i+1,d[i],f[i]))

if __name__ == "__main__":
    main()

Solution (Python):

n=int(input())

l=[[0 for i in range(n)] for j in range(n)]
d=[0 for i in range(n)]
f=[0 for i in range(n)]
stack=[]
check=[]

for i in range(n):
    p=[int(x) for x in input().split()]
    
    for j in range(n):
        if j+1 in p[2:]:
            l[i][j]=1



time=1


while len(check)<n:
    for i in range(n):
        if i+1 not in check:
            stack+=[i+1]
            d[i]=time
            break
        else: pass

    while len(stack)!=0:
        
        for i in range(n):
            if l[stack[-1]-1][i]==1 and not i+1 in check and i+1 not in stack and stack[-1]-1!=i:
                time+=1
                d[i]=time
                stack+=[i+1]

               
               
               
                break
            elif i==n-1:

                check+=[stack[-1]]
                time+=1
                f[stack.pop()-1]=time

               
               
    time+=1


for i in range(n):
    print(i+1,d[i],f[i])