Problem:
 Score : 300 points    Problem Statement Does \sqrt{a} + \sqrt{b} < \sqrt{c} hold?      Constraints  1 \leq a, b, c \leq 10^9  All values in input are integers.         Input Input is given from Standard Input in the following format:  a \ b \ c       Output If \sqrt{a} + \sqrt{b} < \sqrt{c} , print Yes ; otherwise, print No .        Sample Input 1 2 3 9      Sample Output 1 No  \sqrt{2} + \sqrt{3} < \sqrt{9} does not hold.       Sample Input 2 2 3 10      Sample Output 2 Yes  \sqrt{2} + \sqrt{3} < \sqrt{10} holds.

Solution (Python):
a,b,c=map(int,input().split())
if c-a-b<=0:
    print('No')
    exit()
d= (c-a-b)**2-4*a*b
if d>0:
    print('Yes')
else:
    print('No')

Solution (Python):
a,b,c = map(int,input().split())

if a+b<c and 4*a*b<(c-(a+b))**2:
    print("Yes")
else:
    print("No")

Solution (Python):
a,b,c = map(int, input().split())

if 4*a*b < (c-a-b)**2 and c-a-b > 0:
    print("Yes")
else:
    print("No")

Solution (Python):
a, b, c = map(int, input().split())
if c-a-b <= 0:
    print("No")
else:
    print("Yes" if 4*a*b < (c-a-b)**2 else "No")

Solution (Python):
a, b, c = map(int, input().split())
if c > a + b and (c-a-b) ** 2 > 4 * a * b:
    print("Yes")
else:
    print("No")

Solution (Python):



import sys
sys.setrecursionlimit(10**6)
readline = sys.stdin.readline
read = sys.stdin.read



a,b,c = [int(i) for i in readline().split()]

ok = 0
if c-(a+b) > 0 and 4*a*b < (c-(a+b))**2: ok = 1

if ok:
    print("Yes")
else:
    print("No")