Problem:
   Problem Statement AtCoder currently hosts three types of contests: ABC, ARC, and AGC. As the number of users has grown, in order to meet the needs of more users, AtCoder has decided to increase the number of contests to 26 types, from AAC to AZC. For convenience, we number these 26 types as type 1 through type 26. AtCoder wants to schedule contests for D days so that user satisfaction is as high as possible. For every day, AtCoder will hold exactly one contest, and each contest will end on that day. The satisfaction is calculated as follows.   The satisfaction at the beginning of day 1 is 0. Satisfaction can be negative.  Holding contests increases satisfaction. The amount of increase will vary depending on a variety of factors. Specifically, we know in advance that holding a contest of type i on day d will increase the satisfaction by s_{d,i} .  If a particular type of contest is not held for a while, the satisfaction decreases. Each contest type i has an integer c_i , and at the end of each day d=1,2,...,D , the satisfaction decreases as follows. Let \mathrm{last}(d,i) be the last day before day d (including d ) on which a contest of type i was held. If contests of type i have never been held yet, we define \mathrm{last}(d,i)=0 . At the end of day d , the satisfaction decreases by \sum _{i=1}^{26}c_i \times (d-\mathrm{last}(d,i)) .   Please schedule contests on behalf of AtCoder.
If the satisfaction at the end of day D is S , you will get a score of \max(10^6 + S, 0) .
There are 50 test cases, and the score of a submission is the total scores for each test case.
You can make submissions multiple times, and the highest score among your submissions will be your score.      Constraints  D = 365  Each c_i is an integer satisfying 0\leq c_i \leq 100 .  Each s_{d,i} is an integer satisfying 0\leq s_{d,i} \leq 20000 .         Input Input is given from Standard Input in the following format:  D  c_1  c_2  \cdots  c_{26}  s_{1,1}  s_{1,2}  \cdots  s_{1,26}  \vdots  s_{D,1}  s_{D,2}  \cdots  s_{D,26}       Output Let t_d ( 1\leq t_d \leq 26 ) be the type of the contest that will be held at day d .
Print D integers t_d to Standard Output in the following format:  t_1  t_2  \vdots  t_D   Any output that does not follow the above format may result in 0 points WA for that test case.      Input Generation Each integer c_i and s_{d,i} is generated independently and uniformly at random from the integers in the range described in the problem statement.        Sample Input 1 5
86 90 69 51 2 96 71 47 88 34 45 46 89 34 31 38 97 84 41 80 14 4 50 83 7 82
19771 12979 18912 10432 10544 12928 13403 3047 10527 9740 8100 92 2856 14730 1396 15905 6534 4650 11469 3628 8433 2994 10899 16396 18355 11424
6674 17707 13855 16407 12232 2886 11908 1705 5000 1537 10440 10711 4917 10770 17272 15364 19277 18094 3929 3705 7169 6159 18683 15410 9092 4570
6878 4239 19925 1799 375 9563 3445 5658 19857 11401 6997 6498 19933 3848 2426 2146 19745 16880 17773 18359 3921 14172 16730 11157 5439 256
8633 15862 15303 10749 18499 7792 10317 5901 9395 11433 3514 3959 5202 19850 19469 9790 5653 784 18500 10552 17975 16615 7852 197 8471 7452
19855 17918 7990 10572 4333 438 9140 9104 12622 4985 12319 4028 19922 12132 16259 17476 2976 547 19195 19830 16285 4806 4471 9457 2864 2192      Sample Output 1 1
17
13
14
13  Note that this example is a small one for checking the problem specification. It does not satisfy the constraint D=365 and is never actually given as a test case. The final satisfaction with this output is 79325, so the score is 1079325.  Input generator, score calculator, and visualizer      Beginner's Guide If you don't know what to do, proceed to problem B or C.

Solution (Python):
import sys
import random
import time
my_input = sys.stdin.readline

start = time.time()
D = int(input())
C = list(map(int, my_input().split()))
S = [list(map(int, my_input().split())) for _ in range(D)]


def main():
    cnt = 0
    best_ans, best_score = generate_first_ans()
    while time.time() - start < 1.8:
        cnt += 1
        ans = best_ans[:]
        si = random.randint(0, 364)
        sj = random.randint(max(0, si - 125), min(364, si + 125))
        if si == sj:
            continue
        
        ans[si], ans[sj] = ans[sj], ans[si]
        score = calc_score(ans)
        if score > best_score:
            best_score = score
            best_ans = ans

    
    for a in best_ans:
        print(a + 1)


def generate_first_ans():
    best_ans = []
    best_score = 0
    last_day = [-1] * 26
    for d in range(365):
        d_ans = -1
        d_score = -float('inf')
        d_last_day = [-1] * 26
        for t in range(26):
            d_tmp_score = 0
            d_tmp_score += S[d][t]
            d_tmp_last_day = last_day[:]
            d_tmp_last_day[t] = d
            for c, ld in zip(C, d_tmp_last_day):
                d_tmp_score -= c * (d - ld)

            if d_tmp_score > d_score:
                d_ans = t
                d_score = d_tmp_score
                d_last_day = d_tmp_last_day[:]

        best_ans.append(d_ans)
        best_score += d_score
        last_day = d_last_day[:]

    return best_ans, best_score


def calc_score(T):
    score = 0
    last_day = [-1] * 26
    for d, t in enumerate(T):
        score += S[d][t]
        last_day[t] = d
        for c, ld in zip(C, last_day):
            score -= c * (d - ld)
    return score


if __name__ == "__main__":
    main()

Solution (Python):
from collections import defaultdict
from time import time
import bisect
from random import randint
d = int(input())
T = time()
c = [0]+list(map(int,input().split()))
s = [0]
for i in range(d):
    s.append([0]+list(map(int,input().split())))
dic = defaultdict(int)
contest = [[] for _ in range(27)]
contests = [-1]*(d+1)
for i in range(1,d+1):
    maxscore = 0
    maxcontest = -1
    for k in range(1,27):
        score = 0
        score += s[i][k]
        score += c[k]*(i-dic[k])
        if score > maxscore:
            maxscore = score
            maxcontest = k
    dic[maxcontest] = i
    contests[i] = maxcontest
    contest[maxcontest].append(i)
ans = 0
for i in range(1,d+1):
    ans += s[i][contests[i]]
penalty = [0]*27
for i in range(1,27):
    p = 0
    cur = 1
    for j in contest[i]:
        blank = j-cur
        cur = j+1
        p += blank*(blank+1)//2*c[i]
    blank = d+1-cur
    p += blank*(blank+1)//2*c[i]
    ans -= p
    penalty[i] = p
def dscore(d,q):
    old = contests[d]
    ds = 0
    ds -= s[d][old]
    ds += s[d][q]
    ds += penalty[old]
    ds += penalty[q]
    p1 = 0
    p2 = 0
    cur = 1
    contest_o = contest[old][:]
    contest_o.remove(d)
    contest_q = contest[q][:]
    bisect.insort(contest_q,d)
    for j in contest_q:
        blank = j-cur
        cur = j+1
        p1 += blank*(blank+1)//2*c[q]
    blank = d+1-cur
    p1 += blank*(blank+1)//2*c[q]
    for j in contest_o:
        blank = j-cur
        cur = j+1
        p2 += blank*(blank+1)//2*c[old]
    blank = d+1-cur
    p2 += blank*(blank+1)//2*c[old]
    ds -= p1+p2
    return (ds,p1,p2)
while time()-T < 1.8:
    di = randint(1,d)
    qi = randint(1,26)
    old = contests[di]
    ds,p1,p2 = dscore(di,qi)
    if ds > 0:
        ans += ds
        penalty[old] = p2
        penalty[qi] = p1
        contest[old].remove(di)
        bisect.insort(contest[qi],di)
        contests[di] = qi
for i in range(1,d+1):
    print(contests[i])

Solution (Python):
import time
import random

def calc(D, C, S, T):
    s = 0
    l = [-1] * len(C)
    for d, t in enumerate(T):
        s += S[d][t]
        s -= C[t] * (d - l[t]) * (d - l[t] - 1) // 2
        l[t] = d
    s -= sum(c * (d - l[i]) * (d - l[i] + 1) // 2 for i, c in enumerate(C))
    return s

def main():
    start = time.time()
    D = int(input())
    C = list(map(int, input().split()))
    S = [list(map(int, input().split())) for _ in range(D)]
    
    M = [0] * 26

    P = []
    
    for d in range(D):
        for i in range(26):
            M[i] += C[i]
        T = [m + s for m, s in zip(M, S[d])]
        i = T.index(max(T))
        M[i] = 0
        P.append(i)

    Sc = calc(D, C, S, P)
    while time.time() - start <= 1.8:
        d = random.randrange(D)
        q = random.randrange(26)
        if P[d] == q:
            continue
        old = P[d]
        P[d] = q
        Sn = calc(D, C, S, P)
        pe =(Sn - Sc) / (abs(Sc) if Sc != 0 else 1)
        if pe > 0 or random.uniform(0, 1) <= -pe / 5000:
            Sc = Sn
        else:
            P[d] = old
    return P

p = main()
print('\n'.join(str(i + 1) for i in p))

Solution (Python):
def main(sample_file = ''):

    """ convenient functions
    
    
    
    
    
    """

    """convenient decorator
    
    
        
        
        
        
        
        
        
        
        
        
    """
    
    
    import sys
    sys.setrecursionlimit(10**7)
    from itertools import accumulate, combinations, permutations, product 
    
    from math import factorial, ceil, floor, sqrt
    def factorize(n):
        """return the factors of the Arg and count of each factor
        
        Args:
            n (long): number to be resolved into factors
        
        Returns:
            list of tuples: factorize(220) returns [(2, 2), (5, 1), (11, 1)]
        """
        fct = []  
        b, e = 2, 0  
        while b * b <= n:
            while n % b == 0:
                n = n // b
                e = e + 1
            if e > 0:
                fct.append((b, e))
            b, e = b + 1, 0
        if n > 1:
            fct.append((n, 1))
        return fct
    def combinations_count(n, r):   
        """Return the number of selecting r pieces of items from n kinds of items.
        
        Args:
            n (long): number
            r (long): number
        
        Raises:
            Exception: not defined when n or r is negative
        
        Returns:
            long: number
        """
        
        if n < 0 or r < 0:
            raise Exception('combinations_count(n, r) not defined when n or r is negative')
        if n - r < r: r = n - r
        if r < 0: return 0
        if r == 0: return 1
        if r == 1: return n
        numerator = [n - r + k + 1 for k in range(r)]
        denominator = [k + 1 for k in range(r)]
        for p in range(2,r+1):
            pivot = denominator[p - 1]
            if pivot > 1:
                offset = (n - r) % p
                for k in range(p-1,r,p):
                    numerator[k - offset] /= pivot
                    denominator[k] /= pivot
        result = 1
        for k in range(r):
            if numerator[k] > 1:
                result *= int(numerator[k])
        return result
    def combinations_with_replacement_count(n, r):
        """Return the number of selecting r pieces of items from n kinds of items allowing individual elements to be repeated more than once.
        
        Args:
            n (long): number
            r (long): number
        
        Raises:
            Exception: not defined when n or r is negative
        
        Returns:
            long: number
        """
        if n < 0 or r < 0:
            raise Exception('combinations_with_replacement_count(n, r) not defined when n or r is negative')
        elif n == 0:
            return 1
        else:
            return combinations_count(n + r - 1, r)
    from bisect import bisect_left, bisect_right
    from collections import deque, Counter, defaultdict 
    from heapq import heapify, heappop, heappush, heappushpop, heapreplace,nlargest,nsmallest 
    from copy import deepcopy, copy 
    import operator
    from operator import itemgetter 
    
    
    from functools import reduce, lru_cache
    def chmin(x, y):
        """change minimum
        if x > y, x = y and return (x, True).
        convenient when solving problems of dp[i]
        
        Args:
            x (long): current minimum value
            y (long): potential minimum value
        
        Returns:
            (x, bool): (x, True) when updated, else (x, False)
        """
        if x > y:
            x = y
            return (x, True)
        else:
            return (x, False)
    def chmax(x, y):
        """change maximum
        if x < y, x = y and return (x, True).
        convenient when solving problems of dp[i]
        
        Args:
            x (long): current maximum value
            y (long): potential maximum value
        
        Returns:
            (x, bool): (x, True) when updated, else (x, False)
        """
        if x < y:
            x = y
            return (x, True)
        else:
            return (x, False)

    from fractions import gcd 
    def gcds(numbers):
        return reduce(gcd, numbers)
    def lcm(x, y):
        return (x * y) // gcd(x, y)
    def lcms(numbers):
        return reduce(lcm, numbers, 1)
    def make_divisors(n, reversed=False):
        """create list of divisors
        
        Args:
            number (int): number from which list of divisors is created
            reversed (bool, optional): ascending order if False. Defaults to False.
        
        Returns:
            list: list of divisors
        """
        divisors = set()
        for i in range(1, int(n**0.5)+1):
            if n % i == 0:
                divisors.add(i)
                divisors.add(n//i)
        return sorted(list(divisors),reverse=reversed)
    
    
    
    INF = 10 ** 18
    MOD = 10 ** 9 + 7
    AtoZ = list('abcdefghijklmnopqrsruvwxyz') 
    modpow = lambda a, n, p = MOD: pow(a, n, p) 
    def modinv(a, p = MOD):
        
        
        return modpow(a, p-2, p)
    def modinv_list(n, p = MOD):
        if n <= 1:
            return [0,1][:n+1]
        else:
            inv_t = [0,1]
            for i in range(2, n+1):
                inv_t += [inv_t[p % i] * (p - int(p / i)) % p]
            return inv_t
    def modfactorial_list(n, p = MOD):
        if n == 0:
            return [1]
        else:
            l = [0] * (n+1)
            tmp = 1
            for i in range(1, n+1):
                tmp = tmp * i % p
                l[i] = tmp
            return l
    def modcomb(n, k, fac_list = [], p = MOD):
        
        
        from math import factorial
        if n < 0 or k < 0 or n < k: return 0
        if n == 0 or k == 0: return 1
        if len(fac_list) <= n:
            a = factorial(n) % p
            b = factorial(k) % p
            c = factorial(n-k) % p
        else:
            a = fac_list[n]
            b = fac_list[k]
            c = fac_list[n-k]
        return (a * modpow(b, p-2, p) * modpow(c, p-2, p)) % p
    def modadd(a, b, p = MOD):
        return (a + b) % MOD
    def modsub(a, b, p = MOD):
        return (a - b) % p
    def modmul(a, b, p = MOD):
        return ((a % p) * (b % p)) % p
    def moddiv(a, b, p = MOD):
        return modmul(a, modpow(b, p-2, p))

    class UnionFindTree:
        """union find tree class
        TODO: fix this description...
        how to use (example):
        >>  uf = UnionFindTree(N) 
        >>  if uf.find_root(a) == uf.find_root(b):
        >>      do something
        >>  else:
        >>      do something
        >>      uf.unite(a, b)
        """
        def __init__(self, N):
            self.root = [-1] * (N+1)
            self.rank   = [0]  * (N+1)
            self.connected_num = [1] * (N+1)
    
        def find_root(self,x):
            root = self.root
            while root[x] != -1:
                x = root[x]
            return x
    
        def unite(self,x,y):
            root = self.root
            rank = self.rank
            connected_num = self.connected_num
            find_root = self.find_root
    
            rx = find_root(x)
            ry = find_root(y)
            if rx != ry:
                if rank[rx] < rank[ry]:
                    root[rx] = ry
                    rx,ry = ry,rx
                else:
                    if rank[rx] == rank[ry]:
                        rank[rx] += 1
                    root[ry] = rx       
                connected_num[rx] += connected_num[ry]

    class SegTree:
        """
        ref: https://qiita.com/takayg1/items/c811bd07c21923d7ec69
        init(init_val, ide_ele): 配列init_valで初期化 O(N)
        update(k, x): k番目の値をxに更新 O(logN)
        query(l, r): 区間[l, r)をsegfuncしたものを返す O(logN)
        """
        def __init__(self, init_val, segfunc, ide_ele):
            """
            init_val: 配列の初期値
            segfunc: 区間にしたい操作
            ide_ele: 単位元
            n: 要素数
            num: n以上の最小の2のべき乗
            tree: セグメント木(1-index)
            """
            n = len(init_val)
            self.segfunc = segfunc
            self.ide_ele = ide_ele
            self.num = 1 << (n - 1).bit_length()
            self.tree = [ide_ele] * 2 * self.num
            
            for i in range(n):
                self.tree[self.num + i] = init_val[i]
            
            for i in range(self.num - 1, 0, -1):
                self.tree[i] = self.segfunc(self.tree[2 * i], self.tree[2 * i + 1])

        def update(self, k, x):
            """
            k番目の値をxに更新
            k: index(0-index)
            x: update value
            """
            k += self.num
            self.tree[k] = x
            while k > 1:
                self.tree[k >> 1] = self.segfunc(self.tree[k], self.tree[k ^ 1])
                k >>= 1

        def query(self, l, r):
            """
            [l, r)のsegfuncしたものを得る
            l: index(0-index)
            r: index(0-index)
            """
            res = self.ide_ele
            l += self.num
            r += self.num
            while l < r:
                if l & 1:
                    res = self.segfunc(res, self.tree[l])
                    l += 1
                if r & 1:
                    res = self.segfunc(res, self.tree[r - 1])
                l >>= 1
                r >>= 1
            return res

    
    
    
    
    
    
    
    

    def BellmanFord(N, M, ABC, vertex_start, vertex_end, value_if_inf = -1, find_shortest = False):
        """to calculate furthest or shortest length between vertex_start and vertex_end using BellmanFord algorithm
        
        Args:
            N (int): number of vertices
            M (int): number of edges
            ABC (list): [(ai, bi, ci) for _ in range(N)] where i-th edge is directed from vertex ai to vertex bi and the length is ci 
            vertex_start (int): start vertex. usually use 0.
            vertex_end (int): end vertex. usually use N-1.
            value_if_inf (int or string as you like, optional): value you want when the furthest (or shortest) distance is infinite (or -infinite). Defaults to -1.
            find_shortest (bool, optional): choose False to find furthest path. Defaults to False.
        
        Returns:
            int or string: normally int (but can be str if you set value_if_inf to str)
            
        Example:
                N, M, P = R()
                ABC = [R() for _ in range(M)]
                ABC = [(a-1, b-1, c-P) for a, b, c in ABC]
                print(BellmanFord(N, M, ABC, 0, N-1, value_if_inf = 'inf'))

        """

        def make_reachable_list(N, M, ABC, vertex_start, vertex_end):
            reachable_to_direct = defaultdict(list)
            reachable_from_direct = defaultdict(list)
            reachable_from_start = [False] * N
            reachable_to_end = [False] * N
            reachable_from_start[vertex_start] = True
            reachable_to_end[vertex_end] = True
            reachable_from_both_sides = [False] * N
            dfs_from_start = []
            dfs_to_end = []
            for a, b, c in ABC:
                reachable_to_direct[a].append(b)
                reachable_from_direct[b].append(a)
                if a == vertex_start:
                    dfs_from_start.append(b)
                    reachable_from_start[b] = True
                if b == vertex_end:
                    dfs_to_end.append(a)
                    reachable_to_end[a] = True
            while dfs_from_start:
                v = dfs_from_start.pop()
                for i in reachable_to_direct[v]:
                    if not reachable_from_start[i]:
                        reachable_from_start[i] = True
                        dfs_from_start.append(i)
            while dfs_to_end:
                v = dfs_to_end.pop()
                for i in reachable_from_direct[v]:
                    if not reachable_to_end[i]:
                        reachable_to_end[i] = True
                        dfs_to_end.append(i)
            for i in range(N):
                reachable_from_both_sides[i] = reachable_from_start[i] and reachable_to_end[i]
            return reachable_from_both_sides
        
        reachable_from_both_sides = make_reachable_list(N, M, ABC, vertex_start, vertex_end)
        
        if find_shortest:
            dist = [INF for i in range(N)]
        else:
            dist = [-INF for i in range(N)]
        
        dist[vertex_start] = 0
        for i in range(N):
            updated = False
            for a, b, c in ABC:
                if not reachable_from_both_sides[a]:
                    continue
                elif find_shortest:
                    update_condition = dist[a] + c < dist[b]
                else:
                    update_condition = dist[a] + c > dist[b]
                if dist[a] != INF and update_condition:
                    dist[b] = dist[a] + c
                    updated = True
                    if i == N-1:
                        return value_if_inf
            if not updated:
                break
        return dist[vertex_end]

    
    def warshall_floyd(number_vertex, XYD, shift_one_for_vertex=False):
        
        
        
        
        
        d = [[float("inf")]*number_vertex for i in range(number_vertex)]
        for x, y, dist in XYD:
            if shift_one_for_vertex:
                x = x - 1
                y = y - 1
            d[x][y] = dist
            d[y][x] = dist
        for i in range(number_vertex):
            d[i][i] = 0 
        for k in range(number_vertex):
            for i in range(number_vertex):
                for j in range(number_vertex):
                    d[i][j] = min(d[i][j],d[i][k] + d[k][j])
        return d


    """ initialize variables and set inputs
    
        
        
            
            
    
        
        
        
        
        
        
        
    
        
        
        
        
    
        
        
    """

    
    r = lambda: sys.stdin.readline().strip()
    r_int = lambda: int(r())
    r_float = lambda: float(r())
    R = lambda: list(map(int, r().split()))
    R_str = lambda: r().split()
    R_map = lambda: map(int, r().split())
    R_float = lambda: list(map(float, r().split()))
    R_tuple = lambda: tuple(map(int, r().split()))

    """ how to treat input
    
    
    
    
    
    
    
    """

    
    if sample_file:
        sys.stdin = open(sample_file)
        
    
    
    
    D = r_int()
    C = R()
    S = [R() for _ in range(D)]
    
    
    def calc_score(D, C, S, T):
        sat = 0
        satl = [0] * D
        DI = [0] * 26 
        T_ = [t-1 for t in T]
        for i, t in enumerate(T_):
            for j in range(26):
                if j != t:
                    DI[j] += 1
                    sat -= C[j] * DI[j]
                else: 
                    DI[j] = 0
                    sat += S[i][j]
            satl[i] = sat
        
        return sat
    
    def donyoku(D, C, S):
        
        DI = [0] * 26
        T = [0] * D
        for i in range(D):
            candidate = -1
            candidate_value = -INF
            for j in range(26):
                tmp_j = (DI[j] + 1) * C[j] + S[i][j] 
                if candidate_value < tmp_j:
                    candidate_value = tmp_j
                    candidate = j
            T[i] = candidate
        return [t+1 for t in T]

    def emphasize_c(D, C, S, emp = 0.9):
        
        DI = [0] * 26
        T = [0] * D
        for i in range(D):
            candidate = -1
            candidate_value = -INF
            for j in range(26):
                tmp_j = (DI[j] + 1) * C[j] + S[i][j] * emp 
                if candidate_value < tmp_j:
                    candidate_value = tmp_j
                    candidate = j
            T[i] = candidate
        return [t+1 for t in T]

    import time
    start = time.perf_counter()
    
    T = [1] * D
    score = -INF
    Cand = [donyoku(D, C, S), emphasize_c(D, C, S), emphasize_c(D, C, S, 0.5), emphasize_c(D, C, S, 0)]
    for c in Cand:
        tmp = calc_score(D, C, S, c)
        if tmp > score:
            T = c
            score = tmp
    
    score_ = score
    import random
    while time.perf_counter() - start < 1.8:
        target_t = random.randint(0, D-1)
        after_abc = random.randint(1, 24)
        before_abc = T[target_t]
        T[target_t] = after_abc
        tmp = calc_score(D, C, S, T)
        if score < tmp:
            score = tmp
        
        elif score * random.uniform(0.95, 1) < tmp:
            T_ = T.copy()
            T_[target_t] = before_abc
            score_ = score
            score = tmp
        else:
            T[target_t] = before_abc
    
    if score_ < score:
    
        print(*T, sep='\n')
    else:
        print(*T_, sep='\n')


    
    
    
    
    
    
    
    
    
    

    
    
    
    


    
    
    

    """memo: how to use defaultdict of list
    
    Dic = defaultdict(list)
    
    Dic[x].append(y)
    
    for k, v in Dic.items():
    """
    
    """memo: how to solve binary problems
    
    >>> a = 5
    >>> bin_str_a = format(a, '
    >>> print(bin_str_a)
    0b0101 
    """
    
    """memo: how to solve the problem
    creating simple test/answer
    greed
    simple dp
    graph
    """

if __name__ == '__main__':
    main()

Solution (Python):
d=int(input())
*c,=map(int, input().split())
s=[]
for _ in range(d):
    *si,=map(int, input().split())
    s.append(si)
last=[-1]*26

ss=0
for i in range(d):
    ind=-1
    smx=-10**10
    for j in range(26):
        ssj=ss+s[i][j]
        for k in range(26):
            if k!=j:
                ssj-= c[k]*(i-last[k])
        if smx<ssj:
            smx=ssj
            ind=j
    last[ind]=i
    ss=smx        
    print(ind+1)

Solution (Python):
import sys
from random import randint
input = sys.stdin.readline
sys.setrecursionlimit(2 * 10**6)


def inpl():
    return list(map(int, input().split()))


def count_v(last_d, C, S, t, d):
    ret = S[t - 1]
    last_d[t - 1] = d
    for i in range(len(last_d)):
        ret -= C[i] * (d - last_d[i])
    return ret


def count_v_virtual(last_d, C, S, t, d):
    ret = S[t]
    tmp = last_d[t]
    last_d[t] = d
    for i in range(len(last_d)):
        ret -= C[i] * (d - last_d[i])
    last_d[t] = tmp
    return ret


def get_diff_score(T, d, q, C, D, Ss):
    diff = 0
    original_t = T[d - 1]
    last_d_q = 0
    last_d_ori = 0
    for i in range(d):
        if T[i] == q:
            last_d_q = i + 1
        if T[i] == original_t and i < d - 1:
            last_d_ori = i + 1
    
    for i in range(d - 1, D):
        if T[i] == q:
            break
        diff += C[q - 1] * (d - last_d_q)
    
    T[d - 1] = q
    for i in range(d - 1, D):
        if T[i] == original_t:
            break
        diff -= C[original_t - 1] * (d - last_d_ori)
    
    diff += Ss[d - 1][q - 1] - Ss[d - 1][original_t - 1]
    return diff


def main():
    D = int(input())
    C = inpl()
    Ss = [inpl() for _ in range(D)]
    T = []
    last_d = [-1] * len(C)
    Contest = 26

    for d in range(D):
        tmp_t, tmp_v = -1, -float('inf')
        for i in range(Contest):
            tmp_score = count_v_virtual(last_d, C, Ss[d], i, d)
            if tmp_score > tmp_v:
                tmp_v = tmp_score
                tmp_t = i
        last_d[tmp_t] = d
        T.append(tmp_t + 1)

    Cs = [i + 1 for i, c in enumerate(C)]
    Cs.sort(key=lambda x: C[x - 1])

    for _ in range(30000):
        d, q = randint(1, D), randint(1, Contest)
        ori_q = T[d - 1]
        diff = get_diff_score(T, d, q, C, D, Ss)
        if diff < 0:
            T[d - 1] = ori_q

    for t in T:
        print(t)

    return


if __name__ == '__main__':
    main()

Solution (Python):
import numpy
d = int(input())
c = list(map(int,input().split()))
s = [[2 for j in range(26)] for i in range(d)]
k = [1]*26
for i in range(d):
    if i%36 == 0:
        k = [1]*26
    x = sum(k)
    if x >= 30 - i%30:
        q = 0
        for i in range(26):
            if k[i] == 1:
                q = i
                break
    else:
        q = numpy.argmax(s[i])
    print(q+1)
    k[q] = 0

Solution (Python):
def getLast(d, i):
    if last_d[i] == 0:
        return 0
    return d - last_d[i]

def calcC(d):
    res = 0
    for i in range(26):
        res = res + C[i] * getLast(d, i)
    return res

def getBestd(d):
    preLast_d = last_d[25]
    last_d[25] = d
    res = S[d][25] - calcC(d)
    last_d[25] = preLast_d
    res_i = 25
    now = 0
    for i in range(25):
        preLast_d = last_d[i]
        now = S[d][i] - calcC(d)
        last_d[i] = preLast_d
        if res > now:
            res = now
            res_i = i
    return res, res_i

D = int(input())
C = list(map(int, input().split()))
S = []
for i in range(D):
    s = list(map(int, input().split()))
    S.append(s)

score = 0

last_d = [0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]

T = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26]

resT = []

for d in range(D):
    now, i = getBestd(d)
    score = score + now
    last_d[i] = d
    resT.append(T[i])

for i in range(D):
    print(resT[i])

Solution (Python):





import random
import sys
input = sys.stdin.readline

import math

import bisect
import heapq
from collections import defaultdict
from collections import deque
from collections import Counter
from functools import lru_cache

D = int(input().strip())
C = list(map(int,input().split()))
S = [list(map(int, input().split())) for _ in range(D)]

ans = 0
score = 0
last = [[-1] for i in range(26)]
schedule = []

for d in range(D):
  t = random.choice(range(26))
  last[t].append(d)
  score += S[d][t]
  schedule.append(t)

for i in range(26):
  last[i].append(D)
  for k in range(len(last[i])-1):
    g = last[i][k+1]-last[i][k]-1
    score -= C[i]*g*(g+1)//2

count = 2000000

while count:
  count -= 1
  prev = score
  d,q = random.choice(range(D)),random.choice(range(26))
  p = schedule[d]
  schedule[d] = q
  score -= S[d][p]
  score += S[d][q]
  
  pos = last[p].index(d)
  score -= C[p]*(last[p][pos]-last[p][pos-1])*(last[p][pos+1]-last[p][pos])
  last[p].remove(d)
  
  pos = bisect.bisect(last[q],d)
  score += C[q]*(d-last[q][pos-1])*(last[q][pos]-d)
  bisect.insort(last[q],d)
  if score<prev:
    score = prev
    bisect.insort(last[p],d)
    last[q].remove(d)
    schedule[d] = p
    
for i in schedule:
  print(i+1)

Solution (Python):
dur=int(input())
c=list(map(int,input().split()))
d=[0]*26
r=5
for i in range(dur):
  t=0
  s=list(map(int,input().split()))
  m=-1<<64
  for j in range(26):
    alt=s[j]+r*c[j]*(i+1-d[j])+sum([-r*c[k]*(i+1-d[k]) for k in range(26)])
    if alt>m:
      m=alt
      t=j
  print(t+1)
  d[t]=i+1