Problem:
   Problem Statement AtCoder currently hosts three types of contests: ABC, ARC, and AGC. As the number of users has grown, in order to meet the needs of more users, AtCoder has decided to increase the number of contests to 26 types, from AAC to AZC. For convenience, we number these 26 types as type 1 through type 26. AtCoder wants to schedule contests for D days so that user satisfaction is as high as possible. For every day, AtCoder will hold exactly one contest, and each contest will end on that day. The satisfaction is calculated as follows.   The satisfaction at the beginning of day 1 is 0. Satisfaction can be negative.  Holding contests increases satisfaction. The amount of increase will vary depending on a variety of factors. Specifically, we know in advance that holding a contest of type i on day d will increase the satisfaction by s_{d,i} .  If a particular type of contest is not held for a while, the satisfaction decreases. Each contest type i has an integer c_i , and at the end of each day d=1,2,...,D , the satisfaction decreases as follows. Let \mathrm{last}(d,i) be the last day before day d (including d ) on which a contest of type i was held. If contests of type i have never been held yet, we define \mathrm{last}(d,i)=0 . At the end of day d , the satisfaction decreases by \sum _{i=1}^{26}c_i \times (d-\mathrm{last}(d,i)) .   Please schedule contests on behalf of AtCoder.
If the satisfaction at the end of day D is S , you will get a score of \max(10^6 + S, 0) .
There are 50 test cases, and the score of a submission is the total scores for each test case.
You can make submissions multiple times, and the highest score among your submissions will be your score.      Constraints  D = 365  Each c_i is an integer satisfying 0\leq c_i \leq 100 .  Each s_{d,i} is an integer satisfying 0\leq s_{d,i} \leq 20000 .         Input Input is given from Standard Input in the following format:  D  c_1  c_2  \cdots  c_{26}  s_{1,1}  s_{1,2}  \cdots  s_{1,26}  \vdots  s_{D,1}  s_{D,2}  \cdots  s_{D,26}       Output Let t_d ( 1\leq t_d \leq 26 ) be the type of the contest that will be held at day d .
Print D integers t_d to Standard Output in the following format:  t_1  t_2  \vdots  t_D   Any output that does not follow the above format may result in 0 points WA for that test case.      Input Generation Each integer c_i and s_{d,i} is generated independently and uniformly at random from the integers in the range described in the problem statement.        Sample Input 1 5
86 90 69 51 2 96 71 47 88 34 45 46 89 34 31 38 97 84 41 80 14 4 50 83 7 82
19771 12979 18912 10432 10544 12928 13403 3047 10527 9740 8100 92 2856 14730 1396 15905 6534 4650 11469 3628 8433 2994 10899 16396 18355 11424
6674 17707 13855 16407 12232 2886 11908 1705 5000 1537 10440 10711 4917 10770 17272 15364 19277 18094 3929 3705 7169 6159 18683 15410 9092 4570
6878 4239 19925 1799 375 9563 3445 5658 19857 11401 6997 6498 19933 3848 2426 2146 19745 16880 17773 18359 3921 14172 16730 11157 5439 256
8633 15862 15303 10749 18499 7792 10317 5901 9395 11433 3514 3959 5202 19850 19469 9790 5653 784 18500 10552 17975 16615 7852 197 8471 7452
19855 17918 7990 10572 4333 438 9140 9104 12622 4985 12319 4028 19922 12132 16259 17476 2976 547 19195 19830 16285 4806 4471 9457 2864 2192      Sample Output 1 1
17
13
14
13  Note that this example is a small one for checking the problem specification. It does not satisfy the constraint D=365 and is never actually given as a test case. The final satisfaction with this output is 79325, so the score is 1079325.  Input generator, score calculator, and visualizer      Beginner's Guide If you don't know what to do, proceed to problem B or C.

Solution (Python):
def main(sample_file = ''):

    """ convenient functions
    
    
    
    
    
    """

    """convenient decorator
    
    
        
        
        
        
        
        
        
        
        
        
    """
    
    
    import sys
    sys.setrecursionlimit(10**7)
    from itertools import accumulate, combinations, permutations, product 
    
    from math import factorial, ceil, floor, sqrt
    def factorize(n):
        """return the factors of the Arg and count of each factor
        
        Args:
            n (long): number to be resolved into factors
        
        Returns:
            list of tuples: factorize(220) returns [(2, 2), (5, 1), (11, 1)]
        """
        fct = []  
        b, e = 2, 0  
        while b * b <= n:
            while n % b == 0:
                n = n // b
                e = e + 1
            if e > 0:
                fct.append((b, e))
            b, e = b + 1, 0
        if n > 1:
            fct.append((n, 1))
        return fct
    def combinations_count(n, r):   
        """Return the number of selecting r pieces of items from n kinds of items.
        
        Args:
            n (long): number
            r (long): number
        
        Raises:
            Exception: not defined when n or r is negative
        
        Returns:
            long: number
        """
        
        if n < 0 or r < 0:
            raise Exception('combinations_count(n, r) not defined when n or r is negative')
        if n - r < r: r = n - r
        if r < 0: return 0
        if r == 0: return 1
        if r == 1: return n
        numerator = [n - r + k + 1 for k in range(r)]
        denominator = [k + 1 for k in range(r)]
        for p in range(2,r+1):
            pivot = denominator[p - 1]
            if pivot > 1:
                offset = (n - r) % p
                for k in range(p-1,r,p):
                    numerator[k - offset] /= pivot
                    denominator[k] /= pivot
        result = 1
        for k in range(r):
            if numerator[k] > 1:
                result *= int(numerator[k])
        return result
    def combinations_with_replacement_count(n, r):
        """Return the number of selecting r pieces of items from n kinds of items allowing individual elements to be repeated more than once.
        
        Args:
            n (long): number
            r (long): number
        
        Raises:
            Exception: not defined when n or r is negative
        
        Returns:
            long: number
        """
        if n < 0 or r < 0:
            raise Exception('combinations_with_replacement_count(n, r) not defined when n or r is negative')
        elif n == 0:
            return 1
        else:
            return combinations_count(n + r - 1, r)
    from bisect import bisect_left, bisect_right
    from collections import deque, Counter, defaultdict 
    from heapq import heapify, heappop, heappush, heappushpop, heapreplace,nlargest,nsmallest 
    from copy import deepcopy, copy 
    import operator
    from operator import itemgetter 
    
    
    from functools import reduce, lru_cache
    def chmin(x, y):
        """change minimum
        if x > y, x = y and return (x, True).
        convenient when solving problems of dp[i]
        
        Args:
            x (long): current minimum value
            y (long): potential minimum value
        
        Returns:
            (x, bool): (x, True) when updated, else (x, False)
        """
        if x > y:
            x = y
            return (x, True)
        else:
            return (x, False)
    def chmax(x, y):
        """change maximum
        if x < y, x = y and return (x, True).
        convenient when solving problems of dp[i]
        
        Args:
            x (long): current maximum value
            y (long): potential maximum value
        
        Returns:
            (x, bool): (x, True) when updated, else (x, False)
        """
        if x < y:
            x = y
            return (x, True)
        else:
            return (x, False)

    from fractions import gcd 
    def gcds(numbers):
        return reduce(gcd, numbers)
    def lcm(x, y):
        return (x * y) // gcd(x, y)
    def lcms(numbers):
        return reduce(lcm, numbers, 1)
    def make_divisors(n, reversed=False):
        """create list of divisors
        
        Args:
            number (int): number from which list of divisors is created
            reversed (bool, optional): ascending order if False. Defaults to False.
        
        Returns:
            list: list of divisors
        """
        divisors = set()
        for i in range(1, int(n**0.5)+1):
            if n % i == 0:
                divisors.add(i)
                divisors.add(n//i)
        return sorted(list(divisors),reverse=reversed)
    
    
    
    INF = 10 ** 18
    MOD = 10 ** 9 + 7
    AtoZ = list('abcdefghijklmnopqrsruvwxyz') 
    modpow = lambda a, n, p = MOD: pow(a, n, p) 
    def modinv(a, p = MOD):
        
        
        return modpow(a, p-2, p)
    def modinv_list(n, p = MOD):
        if n <= 1:
            return [0,1][:n+1]
        else:
            inv_t = [0,1]
            for i in range(2, n+1):
                inv_t += [inv_t[p % i] * (p - int(p / i)) % p]
            return inv_t
    def modfactorial_list(n, p = MOD):
        if n == 0:
            return [1]
        else:
            l = [0] * (n+1)
            tmp = 1
            for i in range(1, n+1):
                tmp = tmp * i % p
                l[i] = tmp
            return l
    def modcomb(n, k, fac_list = [], p = MOD):
        
        
        from math import factorial
        if n < 0 or k < 0 or n < k: return 0
        if n == 0 or k == 0: return 1
        if len(fac_list) <= n:
            a = factorial(n) % p
            b = factorial(k) % p
            c = factorial(n-k) % p
        else:
            a = fac_list[n]
            b = fac_list[k]
            c = fac_list[n-k]
        return (a * modpow(b, p-2, p) * modpow(c, p-2, p)) % p
    def modadd(a, b, p = MOD):
        return (a + b) % MOD
    def modsub(a, b, p = MOD):
        return (a - b) % p
    def modmul(a, b, p = MOD):
        return ((a % p) * (b % p)) % p
    def moddiv(a, b, p = MOD):
        return modmul(a, modpow(b, p-2, p))

    class UnionFindTree:
        """union find tree class
        TODO: fix this description...
        how to use (example):
        >>  uf = UnionFindTree(N) 
        >>  if uf.find_root(a) == uf.find_root(b):
        >>      do something
        >>  else:
        >>      do something
        >>      uf.unite(a, b)
        """
        def __init__(self, N):
            self.root = [-1] * (N+1)
            self.rank   = [0]  * (N+1)
            self.connected_num = [1] * (N+1)
    
        def find_root(self,x):
            root = self.root
            while root[x] != -1:
                x = root[x]
            return x
    
        def unite(self,x,y):
            root = self.root
            rank = self.rank
            connected_num = self.connected_num
            find_root = self.find_root
    
            rx = find_root(x)
            ry = find_root(y)
            if rx != ry:
                if rank[rx] < rank[ry]:
                    root[rx] = ry
                    rx,ry = ry,rx
                else:
                    if rank[rx] == rank[ry]:
                        rank[rx] += 1
                    root[ry] = rx       
                connected_num[rx] += connected_num[ry]

    class SegTree:
        """
        ref: https://qiita.com/takayg1/items/c811bd07c21923d7ec69
        init(init_val, ide_ele): 配列init_valで初期化 O(N)
        update(k, x): k番目の値をxに更新 O(logN)
        query(l, r): 区間[l, r)をsegfuncしたものを返す O(logN)
        """
        def __init__(self, init_val, segfunc, ide_ele):
            """
            init_val: 配列の初期値
            segfunc: 区間にしたい操作
            ide_ele: 単位元
            n: 要素数
            num: n以上の最小の2のべき乗
            tree: セグメント木(1-index)
            """
            n = len(init_val)
            self.segfunc = segfunc
            self.ide_ele = ide_ele
            self.num = 1 << (n - 1).bit_length()
            self.tree = [ide_ele] * 2 * self.num
            
            for i in range(n):
                self.tree[self.num + i] = init_val[i]
            
            for i in range(self.num - 1, 0, -1):
                self.tree[i] = self.segfunc(self.tree[2 * i], self.tree[2 * i + 1])

        def update(self, k, x):
            """
            k番目の値をxに更新
            k: index(0-index)
            x: update value
            """
            k += self.num
            self.tree[k] = x
            while k > 1:
                self.tree[k >> 1] = self.segfunc(self.tree[k], self.tree[k ^ 1])
                k >>= 1

        def query(self, l, r):
            """
            [l, r)のsegfuncしたものを得る
            l: index(0-index)
            r: index(0-index)
            """
            res = self.ide_ele
            l += self.num
            r += self.num
            while l < r:
                if l & 1:
                    res = self.segfunc(res, self.tree[l])
                    l += 1
                if r & 1:
                    res = self.segfunc(res, self.tree[r - 1])
                l >>= 1
                r >>= 1
            return res

    
    
    
    
    
    
    
    

    def BellmanFord(N, M, ABC, vertex_start, vertex_end, value_if_inf = -1, find_shortest = False):
        """to calculate furthest or shortest length between vertex_start and vertex_end using BellmanFord algorithm
        
        Args:
            N (int): number of vertices
            M (int): number of edges
            ABC (list): [(ai, bi, ci) for _ in range(N)] where i-th edge is directed from vertex ai to vertex bi and the length is ci 
            vertex_start (int): start vertex. usually use 0.
            vertex_end (int): end vertex. usually use N-1.
            value_if_inf (int or string as you like, optional): value you want when the furthest (or shortest) distance is infinite (or -infinite). Defaults to -1.
            find_shortest (bool, optional): choose False to find furthest path. Defaults to False.
        
        Returns:
            int or string: normally int (but can be str if you set value_if_inf to str)
            
        Example:
                N, M, P = R()
                ABC = [R() for _ in range(M)]
                ABC = [(a-1, b-1, c-P) for a, b, c in ABC]
                print(BellmanFord(N, M, ABC, 0, N-1, value_if_inf = 'inf'))

        """

        def make_reachable_list(N, M, ABC, vertex_start, vertex_end):
            reachable_to_direct = defaultdict(list)
            reachable_from_direct = defaultdict(list)
            reachable_from_start = [False] * N
            reachable_to_end = [False] * N
            reachable_from_start[vertex_start] = True
            reachable_to_end[vertex_end] = True
            reachable_from_both_sides = [False] * N
            dfs_from_start = []
            dfs_to_end = []
            for a, b, c in ABC:
                reachable_to_direct[a].append(b)
                reachable_from_direct[b].append(a)
                if a == vertex_start:
                    dfs_from_start.append(b)
                    reachable_from_start[b] = True
                if b == vertex_end:
                    dfs_to_end.append(a)
                    reachable_to_end[a] = True
            while dfs_from_start:
                v = dfs_from_start.pop()
                for i in reachable_to_direct[v]:
                    if not reachable_from_start[i]:
                        reachable_from_start[i] = True
                        dfs_from_start.append(i)
            while dfs_to_end:
                v = dfs_to_end.pop()
                for i in reachable_from_direct[v]:
                    if not reachable_to_end[i]:
                        reachable_to_end[i] = True
                        dfs_to_end.append(i)
            for i in range(N):
                reachable_from_both_sides[i] = reachable_from_start[i] and reachable_to_end[i]
            return reachable_from_both_sides
        
        reachable_from_both_sides = make_reachable_list(N, M, ABC, vertex_start, vertex_end)
        
        if find_shortest:
            dist = [INF for i in range(N)]
        else:
            dist = [-INF for i in range(N)]
        
        dist[vertex_start] = 0
        for i in range(N):
            updated = False
            for a, b, c in ABC:
                if not reachable_from_both_sides[a]:
                    continue
                elif find_shortest:
                    update_condition = dist[a] + c < dist[b]
                else:
                    update_condition = dist[a] + c > dist[b]
                if dist[a] != INF and update_condition:
                    dist[b] = dist[a] + c
                    updated = True
                    if i == N-1:
                        return value_if_inf
            if not updated:
                break
        return dist[vertex_end]

    
    def warshall_floyd(number_vertex, XYD, shift_one_for_vertex=False):
        
        
        
        
        
        d = [[float("inf")]*number_vertex for i in range(number_vertex)]
        for x, y, dist in XYD:
            if shift_one_for_vertex:
                x = x - 1
                y = y - 1
            d[x][y] = dist
            d[y][x] = dist
        for i in range(number_vertex):
            d[i][i] = 0 
        for k in range(number_vertex):
            for i in range(number_vertex):
                for j in range(number_vertex):
                    d[i][j] = min(d[i][j],d[i][k] + d[k][j])
        return d


    """ initialize variables and set inputs
    
        
        
            
            
    
        
        
        
        
        
        
        
    
        
        
        
        
    
        
        
    """

    
    r = lambda: sys.stdin.readline().strip()
    r_int = lambda: int(r())
    r_float = lambda: float(r())
    R = lambda: list(map(int, r().split()))
    R_str = lambda: r().split()
    R_map = lambda: map(int, r().split())
    R_float = lambda: list(map(float, r().split()))
    R_tuple = lambda: tuple(map(int, r().split()))

    """ how to treat input
    
    
    
    
    
    
    
    """

    
    if sample_file:
        sys.stdin = open(sample_file)
        
    
    
    
    D = r_int()
    C = R()
    S = [R() for _ in range(D)]
    
    
    def calc_score(D, C, S, T):
        sat = 0
        satl = [0] * D
        DI = [0] * 26 
        T_ = [t-1 for t in T]
        for i, t in enumerate(T_):
            for j in range(26):
                if j != t:
                    DI[j] += 1
                    sat -= C[j] * DI[j]
                else: 
                    DI[j] = 0
                    sat += S[i][j]
            satl[i] = sat
        return satl
    
    def donyoku(D, C, S):
        
        DI = [0] * 26
        T = [0] * D
        for i in range(D):
            candidate = -1
            candidate_value = -INF
            for j in range(26):
                tmp_j = (DI[j] + 1) * C[j] + S[i][j] 
                if candidate_value < tmp_j:
                    candidate_value = tmp_j
                    candidate = j
            T[i] = candidate
        return [t+1 for t in T]
    
    
    print(*donyoku(D, C, S), sep='\n')
        


    
    
    
    
    
    
    
    
    
    

    
    
    
    


    
    
    

    """memo: how to use defaultdict of list
    
    Dic = defaultdict(list)
    
    Dic[x].append(y)
    
    for k, v in Dic.items():
    """
    
    """memo: how to solve binary problems
    
    >>> a = 5
    >>> bin_str_a = format(a, '
    >>> print(bin_str_a)
    0b0101 
    """
    
    """memo: how to solve the problem
    creating simple test/answer
    greed
    simple dp
    graph
    """

if __name__ == '__main__':
    main()

Solution (Python):
import sys
import random
import time

readline = sys.stdin.readline
readall = sys.stdin.read
ns = lambda: readline().rstrip()
ni = lambda: int(readline().rstrip())
nm = lambda: map(int, readline().split())
nl = lambda: list(map(int, readline().split()))
prn = lambda x: print(*x, sep='\n')




def solve():
    D = ni()
    c = nl()
    s = [nl() for _ in range(D)]
    m = 26
    start = time.time()

    def calc(sche, m=26):
        last = [-1] * m
        ans = 0
        for i in range(D):
            t = sche[i]
            ans += s[i][t]
            last[t] = i
            for j in range(m):
                ans -= c[j] * (i - last[j])
        return ans

    def change(d, q, sc):
        b = sche[d]
        fq, bq = -1, D
        fb, bb = -1, D
        for i in range(d):
            if sche[i] == q:
                fq = i
            if sche[i] == b:
                fb = i
        for i in range(D-1, d, -1):
            if sche[i] == q:
                bq = i
            if sche[i] == b:
                bb = i
        sc += ((bb - d) * (bb - d - 1) // 2 + (d - fb) * (d - fb - 1) // 2) * c[b]
        sc += ((bq - fq) * (bq - fq - 1) // 2) * c[q]
        sc -= s[d][b]
        sc -= ((bq - d) * (bq - d - 1) // 2 + (d - fq) * (d - fq - 1) // 2) * c[q]
        sc -= ((bb - fb) * (bb - fb - 1) // 2) * c[b]
        sc += s[d][q]
        return sc

    sche = [random.randint(0, m-1) for _ in range(D)]
    sc = calc(sche)
    for _ in range(15):
        a = [random.randint(0, m-1) for _ in range(D)]
        nsc = calc(a)
        if sc < nsc:
            sche = a
            sc = nsc

    while time.time() - start < 1.8:
        for _ in range(500):
            d = random.randint(0, D-1)
            q = random.randint(0, m-1)
            nsc = change(d, q, sc)
            if nsc > sc:
                sche[d] = q
                sc = nsc
    prn([1 + x for x in sche])

    return

solve()

Solution (Python):
D = int(input())
C = list(map(int, input().split()))
S = [list(map(int, input().split())) for _ in range(D)]
INF = 10**18

N = 26
L = [0] * N
now = 0
for d in range(D):
    nx = 0
    mx = -INF

    for i in range(N):
        res = now
        prevL = L[i]
        L[i] = d

        res += S[d][i]
        for l, c in zip(L, C):
            res -= c * (d - l)

        L[i] = prevL
        if mx < res:
            mx = res
            nx = i
    now = res
    print(nx + 1)

Solution (Python):
d=int(input())
c=list(map(int,input().split()))
s=[]
for _ in range(d):
    s_i=list(map(int,input().split()))
    s.append(s_i)

dp=[0]*26

from random import randint

def score_ans(s,c,now):
    tmp=0
    for i in range(26):
        tmp+=c[i]*(now - dp[i])
    
    return s-tmp

for i in range(d):

    score=0
    ans=randint(1,26)

    for j in range(26):

        s_i=s[i][j]

        if score<score_ans(s_i,c,i):

            ans=j+1

            score+=score_ans(s_i,c,i)

    dp[ans-1]=i    
    

    print(ans)

Solution (Python):
days = int(input())
clast = list(map(int,input().split()))

allpref = [] 
for i in range(days):
    allpref.append(list(map(int,input().split())))
donelist = [0]*26
contestlist = []
for i in range(days):
    max = 0
    result = 0
    contest = False
    for held in range(26):
        tempdonelist = donelist[:]
        tempdonelist[held] = i+1
        zanen = sum([clast[j]*((i+1)-donelist[j]) for j in range(26)])
        result += allpref[i][held] - zanen
        if result >= max:
            max = result;contest = held


    donelist[contest] = i+1
    contestlist.append(contest+1)

for num in contestlist:
    print(num)

Solution (Python):


d=int(input())
c= list(map(int, input().split()))
D= [list(map(int, input().split())) for i in range(d)]


for i in range(d):
    print(1)

Solution (Python):
from time import time
from random import randrange

def calc():
    s = 0
    last = [-1] * 26
    for i, t in enumerate(A):
        s += S[i][t]
        last[t] = i
        for j, c in enumerate(C):
            s -= c * (i - last[j])
    return s

sTime = time()
D = int(input())
C = [int(a) for a in input().split()]
S = [[int(a) for a in input().split()] for _ in range(D)]
A = [randrange(26) for _ in range(D)]
ans = calc()
while time() - sTime < 1.8:
    d = randrange(D)
    i = A[d]
    for k in range(d)[::-1]:
        if A[k] == i:
            prev = k
            break
    else:
        prev = -1
    for k in range(d + 1, D):
        if A[k] == i:
            prev_ne = k
            break
    else:
        prev_ne = D
    for j in range(26):
        t = S[d][j] - S[d][i]
        for k in range(d)[::-1]:
            if A[k] == j:
                new = k
                break
        else:
            new = -1
        for k in range(d + 1, D):
            if A[k] == j:
                new_ne = k
                break
        else:
            new_ne = D
        t += C[j] * (d - new) * (new_ne - d) - C[i] * (d - prev) * (prev_ne - d)
        if t > 0:
            A[d] = j
            ans += t
            prev, prev_ne = new, new_ne

print(*[a + 1 for a in A], sep = "\n")

Solution (Python):
d=int(input())
c=list(map(int,input().split()))
s=[list(map(int,input().split())) for _ in range(d)]
score=0
prev=0
se=set()
for i in range(d):
    lis=[]
    if i//26>prev:
        se=set()
        prev=i//26
    for j in range(26):
        lis.append((s[i][j],j))
    lis.sort(reverse=True)
    for j in range(26):
        if lis[j][1] not in se:
            se.add(lis[j][1])
            print(lis[j][1]+1)
            break

Solution (Python):
def main():
    D = int(input())
    fuman = list(map(int, input().split()))
    manzoku = [[0]*26 for _ in range(D)]
    for i in range(D): manzoku[i] = list(map(int, input().split()))
    
    
    
    
    timepass = [0]*26
    
    x,t = 0,0
    for j in range(26):
        tmp = manzoku[i][j]
        if tmp>x:
            x = tmp
            t = j
    print(t+1)
    for i in range(1,D):
        x1 = 0
        t1 = 0
        for j in range(26):
            tmp = manzoku[i][j]
            for k in range(26):
                if not j==k: tmp -= fuman[k]*timepass[k]
            if tmp>x1:
                x1 = tmp
                t1 = j

        
        for j in range(26):
            if not j==t1: timepass[j] += 1
            else: timepass[j] = 0
        print(t1+1)



main()

Solution (Python):
D = int(input())
C = list(map(int, input().split()))
S = []
for _ in range(D):
    ver = list(map(int,input().split()))
    S.append(ver)
d = 0
last = [0 for _ in range(26)]

t = []
for d in range(1, D+1):
    dc = [C[i]*(d-last[i]) for i in range(26)]
    best = []
    for i in range(26):
        if_i = S[d-1][i] + dc[i]
        best.append(if_i)
    t.append(best.index(max(best))+1)
    
    last_i = best.index(max(best))
    last[last_i] += d
for t_i in t:
    print(t_i)

Solution (Python):
d=int(input())
c=list(map(int,input().split()))
s=[list(map(int,input().split())) for i in range(d)]
for i in range(d):
    cand=0
    for j in range(26):
        if s[i][cand]<s[i][j]:
            cand=j
    print(1)

Solution (Python):
import random
d = int(input())
c = list(map(int, input().split()))
s = [list(map(int, input().split())) for _ in range(d)]
ans = 0
last = [0]*26
for i in range(1,d+1):
    res = -float("inf")
    maindex = 0
    ma = 0
    for k in range(26):
        if (s[i-1][k]>ma):
            ma = s[i-1][k]
            maindex = k+1
    print(maindex)

Solution (Python):
import sys
input = sys.stdin.buffer.readline
import numpy as np

D = int(input())
c = np.array(input().split(), dtype=np.int32)
s = np.array([input().split() for _ in range(D)], dtype=np.int32)
last = np.zeros(26, dtype=np.int32)



ans = []
point = 0
for i in range(D):
    down = (i+1-last)*c
    loss = down * 3 + s[i,:]
    idx = np.argmax(loss)
    ans.append(idx+1)
    point += s[i, idx] - down.sum()
    last[idx] = i+1
    

for i in range(D):
    print(ans[i])

Solution (Python):
from random import randint

D = int(input())
cl = list(map(int, input().split()))
sl = [list(map(int, input().split())) for _ in range(D)]

def score(d, ti, last):
    s = sl[d-1][ti]
    for i in range(len(cl)):
        c = cl[i]
        s -= c*(d-last[i])
    return s

def scores(tl):
    s = 0
    last = [0]*26
    for d in range(D):
        t = tl[d] - 1
        last[t] = d+1
        s += score(d+1,t,last)
    return s


tl = [randint(1,26) for _ in range(D)]
s = scores(tl)
for _ in range(10000):
    d = randint(1,D)
    q = randint(1,26)
    x = tl[d-1]
    tl[d-1] = q
    s2 = scores(tl)
    if s2>s:
        s = s2
    else:
        tl[d-1] = x


for t in tl:
    print(t)

Solution (Python):
import copy

D = int(input())
c = list(map(int, input().split()))
s = []
for i in range(D):
    s.append(list(map(int, input().split())))

score = 0
last = [0] * 26
for d in range(D):
    score_max = -999999999
    t_max = -1
    for t in range(26):
        
        tmp_score = 0
        tmp_last = copy.deepcopy(last)

        
        tmp_score += s[d][t]
        tmp_last[t] = d + 1
        for _type in range(26):
            tmp_score -= (d + 1 - tmp_last[_type]) * c[_type]
        
        if score_max < tmp_score:
            score_max = tmp_score
            t_max = t
    
    score += score_max
    last[t_max] = d + 1
    print(t_max + 1)

Solution (Python):
import random
d = int(input())
for i in range(d):
  print(random.randint(1, 26))

Solution (Python):
D = int(input())
C = list(map(int, input().split()))
S = []
for _ in range(D):
    s_row = list(map(int, input().split()))
    S.append(s_row)

results = []














last = [0 for i in range(26)]
next_costs = [0 for i in range(26)]

for d in range(D):

    for i in range(26):
        next_costs[i] = C[i] * (d-last[i])

    result = -100000
    next_costs_sum = sum(next_costs)
    result_idx = -1
    for i in range(26):
        tmp_result = - (next_costs_sum - C[i] * (d-last[i]))
        if tmp_result > result:
            result = tmp_result
            result_idx = i
    last[result_idx] = d
    results.append(result_idx + 1)

for result in results:
    print(result)

Solution (Python):

from copy import deepcopy
D = int(input())
C = list(map(int, input().split()))
S = [list(map(int, input().split())) for i in range(D)]

last = {}
for i in range(26):
    last[i] = -1

s = 0
for d in range(D):
    ret = 0
    sr = {}
    ll = {}
    for c in range(26):
        last_cp = deepcopy(last)
        s_cp = deepcopy(s)
        last_cp[c] = d
        s_cp += S[d][c]
        for i in range(26):
            s_cp -= C[i] * (d-last[i])
        sr[c] = s_cp
        ll[c] = last_cp
    sr = sorted(sr.items(), key=lambda x:x[1])
    ret = sr[-1][0]
    s += sr[-1][1]
    last = deepcopy(ll[ret])
    print(ret+1)

Solution (Python):
d=int(input())
c=list(map(int,input().split()))
s=[]
for i in range(d):
    t=list(map(int,input().split()))
    s.append(t)

for i in range(d):
    p=sorted(s[i])
    print(s[i].index(p[-3])+1)