Problem:
 Score : 300 points    Problem Statement You are given two integer sequences of length N : a_1,a_2,..,a_N and b_1,b_2,..,b_N .
Determine if we can repeat the following operation zero or more times so that the sequences a and b become equal.  Operation: Choose two integers i and j (possibly the same) between 1 and N (inclusive), then perform the following two actions simultaneously :   Add 2 to a_i .  Add 1 to b_j .       Constraints  1 ≤ N ≤ 10  000  0 ≤ a_i,b_i ≤ 10^9 ( 1 ≤ i ≤ N )  All input values are integers.         Input Input is given from Standard Input in the following format:  N  a_1  a_2  ..  a_N  b_1  b_2  ..  b_N       Output If we can repeat the operation zero or more times so that the sequences a and b become equal, print Yes ; otherwise, print No .        Sample Input 1 3
1 2 3
5 2 2      Sample Output 1 Yes  For example, we can perform three operations as follows to do our job:   First operation: i=1 and j=2 . Now we have a = \{3,2,3\} , b = \{5,3,2\} .  Second operation: i=1 and j=2 . Now we have a = \{5,2,3\} , b = \{5,4,2\} .  Third operation: i=2 and j=3 . Now we have a = \{5,4,3\} , b = \{5,4,3\} .        Sample Input 2 5
3 1 4 1 5
2 7 1 8 2      Sample Output 2 No       Sample Input 3 5
2 7 1 8 2
3 1 4 1 5      Sample Output 3 No

Solution (Python):
import sys

nN = int(input())

A = [0 for i in range(nN)]
B = [0 for i in range(nN)]

nData = []
nData  = input().rstrip().split(' ')
aT = 0
bT = 0


for i in range(nN):
    A[i] = int(nData[i])
    aT += A[i]

nData  = input().rstrip().split(' ')

for i in range(nN):
    B[i] = int(nData[i])
    bT += B[i]

N = bT - aT

nFlag = 0

if N < 0:
    print('No')
    sys.exit()

elif N == 0:
    for i in range(nN):
        if A[i] != B[i]:
            print('No')
            nFlag = 1
            break

    if nFlag == 0:
        print('Yes')

    sys.exit()

else:
    nCnt = 0
    nCntA = 0
    nCntB = 0
    nDiff = 0
    
    for i in range(nN):
        if A[i] > B[i]:
            nDiff = A[i] - B[i]
            nCntB += nDiff
            
        elif B[i] > A[i]:
            nDiff = B[i] - A[i]
            nTmp = nDiff % 2
            if nTmp == 0:
                nCntA += nDiff/2
            else:
                nCntA += nDiff//2 +1
                nCntB += 1
    
    if (N < nCntA) or (N < nCntB):
        print('No')
    
    elif nCntA == nCntB:
        print('Yes')
    
    else :
        nA = (N - nCntA) * 2
        nB = N - nCntB
        if nA == nB:
            print('Yes')
        else:
            print('No')

Solution (Python):
N = int(input())
a=list(map(int,input().split()))
b=list(map(int,input().split()))
plus=0;minus=0;co=0
for i in range(N):
    c=a[i]-b[i]
    if c < 0:
        minus-=c
        if c%2==1:
            co+=1
    elif c > 0:
        plus+=c

print("Yes" if minus >= plus*2+co else "No")

Solution (Python):
import numpy as np
N = int(input())
a = np.array([list(map(int, input().split()))])
b = np.array([list(map(int, input().split()))])

diff = b - a
limit = np.sum(diff)

minus = -sum(diff[diff < 0])
diffp = diff[0 < diff]
result = minus
for d in diffp:
    div = min(int(d / 2), minus)
    minus -= div
    result = d - div * 2
    if limit < result:
        break

if 0 < minus or limit < result:
    print("No")
else:
    print("Yes")

Solution (Python):
def main():
    N = int(input())
    A = list(map(int, input().split()))
    B = list(map(int, input().split()))

    d = sum(B) - sum(A)

    if d < 0:
        print('No')
        return

    C = [a - b for a, b in zip(A, B)]
    m = sum(((abs(x) + 1) // 2 for x in C if x < 0))

    

    if abs(m) > d:
        print('No')
        return

    
    print('Yes')


main()

Solution (Python):
import math
n = int(input())
lis1 = list(map(int,input().split()))
lis2 = list(map(int,input().split()))
k = 0
c = 0
s = 0
cou = sum(lis2)-sum(lis1)
if cou < 0:
    print("No")
else:
    for i in range(n):
        if lis1[i] < lis2[i]:
            c += math.ceil((lis2[i] - lis1[i]) / 2)
            if (lis2[i] - lis1[i])%2 == 0:
                k += 1
            else:
                s += 1
    if c > cou:
        print("No")
    elif c == cou:
        print("Yes")
    else:
        if k >= 1:
            print("Yes")
        else:
            print("No")

Solution (Python):
n=int(input())
a=input().split(" ")
a=list(map(int,a))

b=input().split(" ")
b=list(map(int,b))
counta=0
countb=0
for i in range(n):
    if a[i]<b[i]: 
        temp=b[i]-a[i] 
        if temp%2==0:
            counta+=int(temp/2)
            
        else:
            counta+=int((temp+1)/2)
            countb+=1
            
    if a[i]>b[i]:
        temp=a[i]-b[i]
        countb+=temp
       


if counta>=countb:
    print("Yes")
else:
    print("No")

Solution (Python):
N = int(input())
a = list(map(int,input().split()))
b = list(map(int,input().split()))

c = 0
for i in range(N):
   if b[i] - a[i] > 0:
      c += (b[i] - a[i])//2
   elif b[i] - a[i] < 0:
      c += b[i] - a[i]

if c >= 0:
   print("Yes")
else:
   print("No")

Solution (Python):
import math
n = int(input())
lis1 = list(map(int,input().split()))
lis2 = list(map(int,input().split()))
k = 0
c = 0
s = 0
cou = sum(lis2)-sum(lis1)
if cou < 0:
    print("No")
else:
    for i in range(n):
        if lis1[i] < lis2[i]:
            c += math.ceil((lis2[i] - lis1[i]) / 2)
            if (lis2[i] - lis1[i])%2 == 0:
                k += 1
            else:
                s += 1
    if c > cou:
        print("No")
    elif c == cou:
        print("Yes")
    else:
        if k >= 1:
            print("Yes")
        else:
            print("No")

Solution (Python):
import numpy as np


def a():
    x, y = map(int, input().split())


def b():
    n = int(input())
    a = np.asarray(list(map(int, input().split())))
    b = np.asarray(list(map(int, input().split())))
    x = b.sum() - a.sum()
    d = b - a
    a_req = 0
    b_req = 0
    for i in d:
        if i <= 0:
            b_req += i // -1
        else:
            a_req += i // 2 + i % 2
            b_req += i % 2
    
    if (a_req >= b_req and (0 < a_req + (a_req - b_req) == x)) or (a_req == 0 and b_req == 0):
        print('Yes')
    else:
        print('No')


if __name__ == '__main__':
    b()

Solution (Python):
import numpy as np
N = int(input())
a = []
b = []

a = np.array([int(num) for num in input().split(" ")])
b = np.array([int(num) for num in input().split(" ")])

flag = False
M = sum(b) - sum(a)

a_count = 0
b_count = 0
c = b - a
for i in range(N):
    if c[i] < 0:
        b_count -= c[i]
    if c[i] > 0:
        count = c[i] % 2
        a_count += count
        b_count += count
        a_count += c[i] // 2
        
if M - b_count == (M - a_count) * 2:
        flag = True
if a_count > M or b_count > M:
    flag = False
if flag:
    print("Yes")
else:
    print("No")

Solution (Python):
import math
n = input()
a = map(int, raw_input().split())
b = map(int, raw_input().split())
c = 0
for i, j in zip(a, b):
    if i < j:
        c += math.ceil(1.0*(j-i)/2)
if c > sum(b)-sum(a):
    print "No"
else:
    print "Yes"

Solution (Python):
n=int(input())

x=[int(i) for i in input().split()]
y=[int(i) for i in input().split()]
y_plus=0
xy_dif=0

for i in range(n):
    if x[i]<y[i] and (x[i]-y[i])%2==0:
        y_plus=y_plus+int(0.5*(y[i]-x[i]))
        x[i]=y[i]
    elif x[i]<y[i] and (x[i]-y[i])%2==1:
        y_plus=y_plus+int(0.5*(y[i]-x[i]+1))
        x[i]=y[i]+1
        xy_dif=xy_dif+1
    else:
        xy_dif=xy_dif+x[i]-y[i]





if xy_dif<=y_plus:
    print("Yes")
else:
    print("No")

Solution (Python):
import math

N = int(input())
a_list = list(map(int, input().split(' ')))
b_list = list(map(int, input().split(' ')))

cnt = sum(b_list) - sum(a_list)

cnt_tmp = 0
for i in range(N):
    if a_list[i] < b_list[i]:
        cnt_tmp += math.ceil((b_list[i] - a_list[i]) / 2)

if cnt_tmp > cnt:
    print('No')
else:
    print('Yes')

Solution (Python):

def inpl(): return tuple(map(int, input().split()))

N = int(input())
A = inpl()
B = inpl()

C = 0
D = 0

for a, b in zip(A, B):
    if b - a > 1:
        C += (b-a) - ((b-a)%2)
    else:
        D += (a-b)

if C >= 2*D:
    print("Yes")
else:
    print("No")

Solution (Python):
n = int(input())
a = [int(x) for x in input().strip().split()]
b = [int(x) for x in input().strip().split()]

p = 0
for x, y in zip(a, b):
    if x > y:
        p += x - y
    else:
        p -= (y - x) // 2

if p <= 0:
    print('Yes')
else:
    print('No')

Solution (Python):
N = int(input())
A = list(map(int, input().split()))
B = list(map(int, input().split()))

largeA = 0
largeB = 0
for i in range(N):
  d = A[i] - B[i]
  if d > 0:
    largeA += d
  elif d < 0:
    d = -d
    
    if d % 2 == 1:
      d = -1
      B[i] -= 1
    largeB += d

dsum = sum(B) - sum(A)
if dsum >= 0 and largeB//2 <= dsum and largeA <= dsum:
  print('Yes')
else:
  print('No')

Solution (Python):
n, a, b = input(), map(int, raw_input().split()), map(int, raw_input().split())
c = [a[i] - b[i] for i in xrange(n)]
print 'Yes' if sum([-x / 2 for x in c if x < 0]) >= sum([x for x in c if x > 0]) else 'No'

Solution (Python):
N = int(input())
a = list(map(int, input().split()))
b = list(map(int, input().split()))
s = sum([a[i]-b[i] if a[i]>b[i] else -((b[i]-a[i])//2) for i in range(N)])
print("Yes" if s < 1 else "No")

Solution (Python):
N = int(input())
A = list(map(int, input().split()))
B = list(map(int, input().split()))

C = [B[i]-A[i] for i in range(N)]

P = sum(filter(lambda x: x<0, C))
M = list(filter(lambda x: x>1, C))
M = list(map(lambda x: x//2, M))

M = sum(M)
if abs(M) >= abs(P):
    print("Yes")
else:
    print("No")

Solution (Python):
N = int(input())
a = list(map(int,input().split(" ")))
b = list(map(int,input().split(" ")))

dif = sum(b) - sum(a)

if dif < 0:
	print("No")
	exit(0)

count = 0
for i in range(N):
	if (a[i] % 2) != (b[i] % 2):
		b[i] += 1
		count += 1
	
	if b[i] < a[i]:
		count += (a[i] - b[i])

if count > dif:
	print("No")
	exit(0)

if ((dif - count) % 2) == 0:
	print("Yes")
else:
	print("No")

Solution (Python):
N = int(input())
st = input().split()
a = [0 for i in range(N)]
A = 0
for i in range(N):
    a[i] = int(st[i])
    A += a[i]
st = input().split()
b = [0 for i in range(N)]
B = 0
for i in range(N):
    b[i] = int(st[i])
    B += b[i]
def cost(n):
    if n == 0:
        return [0, 0]
    elif n < 0:
        return [0, -n]
    elif n > 0 and n % 2 == 0:
        return [n//2, 0]
    else:
        return [(n+1)//2, 1]

K = B - A
PC = 0
MC = 0
for i in range(N):
    c = cost(b[i] - a[i])
    PC += c[0]
    MC += c[1]
if PC <= K and MC <= K and ((K-PC)*2 == (K-MC)):
    print("Yes")
else:
    print("No")

Solution (Python):
n = int(raw_input())

a = map(int, raw_input().split())
b = map(int, raw_input().split())

ac=0
bc=0
for i in range(n):
   if (a[i]>b[i]):
      bc=bc+(a[i]-b[i])
   if (a[i]<b[i]):
      ac=ac+(b[i]-a[i]+1)/2
      bc=bc+(b[i]-a[i])%2

if ac>=bc:
   print "Yes"
else:
   print "No"

Solution (Python):
input()
a = list(map(int, input().split()))
b = list(map(int, input().split()))

minus = 0
for v in map(lambda x: x[1] - x[0], zip(a, b)):
    if v < 0:
        minus += v
    else:
        minus += v // 2

print("Yes" if minus >= 0 else "No")

Solution (Python):
N = int(input())
A = tuple(map(int,input().split()))
B = tuple(map(int,input().split()))

x = 0
y = 0
for a,b in zip(A,B):
  if a > b:
    x += a-b
  else:
    y += (b-a)//2

print('Yes' if y >= x else 'No')

Solution (Python):
n=int(input())
line=input().split()
line2=input().split()

a=[]
asum=0
b=[]
bsum=0
extraa=0
for i in range(n):
    a.append(int(line[i]))
    b.append(int(line2[i]))
    asum+=a[-1]
    bsum+=b[-1]

for i in range(n):
    if a[i]<b[i]:
        extraa+=(b[i]-a[i])//2
    if a[i]>b[i]:
        extraa-=a[i]-b[i]
if extraa>=0 and asum<=bsum:
    print ("Yes")
else:
    print("No")

Solution (Python):
n = int(input())
a = list(map(int, input().split()))
b = list(map(int, input().split()))

ca = 0
cb = 0
for i in range(n):
    if a[i] > b[i]:
        ca += a[i] - b[i]
    elif a[i] < b[i]:
        cb += (b[i] - a[i]) // 2

if ca <= cb:
    ans = "Yes"
else:
    ans = "No"
print(ans)

Solution (Python):

import math

def main():
    N = int(input())

    a = list(map(int, input().split(' ')))
    b = list(map(int, input().split(' ')))

    man_count = 0

    for i in range(N):
        if a[i] < b[i]:
            da = math.ceil((b[i] - a[i])/2)
            a[i] += 2*da
            man_count += da

        if a[i] > b[i]:
            db = a[i] - b[i]
            b[i] += db
            man_count -= db

    if man_count >= 0:
        print('Yes')
    else:
        print('No')


main()

Solution (Python):
import random
import functools
import itertools
import math

R = lambda type_ = "int": list(map(eval(type_), input().split(' ')))

n = int(input())
a = R()
b = R()

pos, neg = 0, 0

for i in range(n):
    if a[i] > b[i]:
        neg += a[i] - b[i]
    else:
        pos += (b[i] - a[i]) // 2


print('Yes' if pos >= neg else 'No')

Solution (Python):
def LI(): return list(map(int, input().split()))
def LS(): return input().split()
def I(): return int(input())
def S(): return input()

n = I()
a = LI()
b = LI()
plus = 0
minus = 0
for i in range(n):
    c = a[i] - b[i]
    if c > 0:
        plus += c
    else:
        minus -= abs(c)//2
if minus + plus <= 0 :
    print("Yes")
else:
    print("No")

Solution (Python):
N=int(input())
a=list(map(int,input().split(' ')))
b=list(map(int,input().split(' ')))
i=0
A=0
B=0
n=0
while i < N:
    n+=(b[i]-a[i])
    if (a[i]-b[i])>=0:
        B+=(a[i]-b[i])
        i+=1
    elif (a[i]-b[i])<0 and int(abs(a[i]-b[i])%2)==0:
        A+=int(abs(a[i]-b[i])//2)
        i+=1
    else:
        A+=int(abs(a[i]-b[i])//2 + 1)
        B+=1
        i+=1
if max(n,A,B)==n:
    print('Yes')
else:
    print('No')

Solution (Python):
N=int(input())
a=[int(i) for i in input().split()]
b=[int(i) for i in input().split()]

total_do=sum(b)-sum(a)
must_do_a=0
must_do_b=0

for i in range(N):
	dist=a[i]-b[i]
	if dist<0:
		dist=-dist
		must_do_a+=int((dist+1)/2)
		if dist%2!=0:
			must_do_b+=1
	elif dist>0:
		must_do_b+=dist
left_a=total_do-must_do_a
left_b=total_do-must_do_b

if total_do>=0 and must_do_a>=must_do_b and left_a*2==left_b:
	print("Yes")
else:
	print("No")

Solution (Python):

def solve(A, B):
    t = 0
    s = 0
    for a, b in zip(A, B):
        if a > b:
            s += a - b
        if b > a:
            x = b - a
            t += x // 2
    if s <= t:
        return True
    else:
        return False

N = [int(x) for x in input().split()]
A = [int(x) for x in input().split()]
B = [int(x) for x in input().split()]

if solve(A, B):
    print("Yes")
else:
    print("No")

Solution (Python):
N = int(input())

astr = input().split()
bstr = input().split()

dp = []
dm = []
for (ai, bj)  in zip(astr, bstr):
    d = int(bj)-int(ai)
    if d < 0:
        dm.append(d)
    else:
        dp.append(d)
    
plus = 0
for d in dp:
    plus += d//2

if plus<abs(sum(dm)):
    print('No')
else:
    print('Yes')

Solution (Python):
n=int(input())
a=list(map(int,input().split()))
b=list(map(int,input().split()))
m=sum(b)-sum(a)
if m<0:
    print("No")
elif m==0:
    ok=True
    for i in range(n):
        if a[i]!=b[i]:
            ok=False
            break
    print("Yes" if ok else "No")
else:
    upb=0
    for i in range(n):
        if a[i]>b[i]:
            upb+=a[i]-b[i]
            b[i]=a[i]
    for i in range(n):
        if a[i]<b[i]:
            use=(b[i]-a[i])//2
            upb-=use
    print("Yes" if upb<=0 else "No")

Solution (Python):
N = int(input())
*A, = map(int, input().split())
*B, = map(int, input().split())

K = sum(B) - sum(A)
C = 0; D = 0
for i in range(N):
    p = B[i] - A[i]
    if p > 0:
        C += (p+1)//2
        D += (p%2)
    else:
        D += -p
if C < K:
    D += 2*(K - C)
    C = K
if K >= 0 and C == D == K:
    print("Yes")
else:
    print("No")

Solution (Python):

N = int(input())
a_list = list(map(int, input().split()))
b_list = list(map(int, input().split()))

cnt_plus_a_2 = 0
cnt_plus_a_1 = 0
cnt_plus_b = 0

for i in range(N):
    if a_list[i] < b_list[i]:
        cnt_plus_a_2 += (b_list[i] - a_list[i]) // 2
        cnt_plus_a_1 += (b_list[i] - a_list[i]) % 2
    elif a_list[i] > b_list[i]:
        cnt_plus_b += -(b_list[i] - a_list[i])
        
if cnt_plus_a_2 >= cnt_plus_b:
    print("Yes")
else:
    print("No")

Solution (Python):
n = int(raw_input())
a = map(int, raw_input().split())
b = map(int, raw_input().split())
c = [a[i] - b[i] for i in xrange(n)]
f = -sum(c)
if f < 0:
    print 'No'
    quit()
t = f
for i in xrange(n):
    if c[i] < 0:
        k = (-c[i] + 1) / 2
        t -= k
        c[i] += k * 2
if t < 0:
    print 'No'
    quit()
s = f
for i in xrange(n):
    s -= c[i]
if s < 0:
    print 'No'
    quit()
if t * 2 == s:
    print 'Yes'
else:
    print 'No'

Solution (Python):
def solve(sa, sb):
    d = 0
    for a, b in zip(sa, sb):
        if a >= b:
            d += a - b
        else:
            d -= (b - a) // 2
    return d <= 0


n = input()
sa = map(int, input().split())
sb = map(int, input().split())

print('Yes' if solve(sa, sb) else 'No')

Solution (Python):
n = int(input())
a = [int(x) for x in input().split()]
b = [int(x) for x in input().split()]

c = 0
for i in range(n):
    ai = a[i]
    bi = b[i]
    if ai < bi:
        c += (bi-ai)//2
    else:
        c -= (ai-bi)
print('Yes' if c >= 0 else 'No')

Solution (Python):
def main():
    n = int(input())
    a = list(map(int,input().split()))
    b = list(map(int,input().split()))
    move = sum(b)-sum(a)
    if move<0:
        print("No")
        return 0
    amove = 0
    bmove = 0
    for i in range(n):
        if a[i] < b[i]:
            amove += (b[i]-a[i]+1)//2
            bmove += (b[i]-a[i])%2
        elif a[i] > b[i]:
            bmove += a[i]-b[i]
    if max(amove,bmove) <= move:
        print("Yes")
    else:
        print("No")

main()