Problem:
 Score : 300 points    Problem Takahashi, who is a novice in competitive programming, wants to learn M algorithms.
Initially, his understanding level of each of the M algorithms is 0 .  Takahashi is visiting a bookstore, where he finds N books on algorithms.
The i -th book ( 1\leq i\leq N ) is sold for C_i yen (the currency of Japan). If he buys and reads it, his understanding level of the j -th algorithm will increase by A_{i,j} for each j ( 1\leq j\leq M ).
There is no other way to increase the understanding levels of the algorithms.  Takahashi's objective is to make his understanding levels of all the M algorithms X or higher. Determine whether this objective is achievable. If it is achievable, find the minimum amount of money needed to achieve it.      Constraints  All values in input are integers.  1\leq N, M\leq 12  1\leq X\leq 10^5  1\leq C_i \leq 10^5  0\leq A_{i, j} \leq 10^5         Input Input is given from Standard Input in the following format:  N  M  X  C_1  A_{1,1}  A_{1,2}  \cdots  A_{1,M}  C_2  A_{2,1}  A_{2,2}  \cdots  A_{2,M}  \vdots  C_N  A_{N,1}  A_{N,2}  \cdots  A_{N,M}       Output If the objective is not achievable, print -1 ; otherwise, print the minimum amount of money needed to achieve it.        Sample Input 1 3 3 10
60 2 2 4
70 8 7 9
50 2 3 9      Sample Output 1 120  Buying the second and third books makes his understanding levels of all the algorithms 10 or higher, at the minimum cost possible.       Sample Input 2 3 3 10
100 3 1 4
100 1 5 9
100 2 6 5      Sample Output 2 -1  Buying all the books is still not enough to make his understanding levels of all the algorithms 10 or higher.       Sample Input 3 8 5 22
100 3 7 5 3 1
164 4 5 2 7 8
334 7 2 7 2 9
234 4 7 2 8 2
541 5 4 3 3 6
235 4 8 6 9 7
394 3 6 1 6 2
872 8 4 3 7 2      Sample Output 3 1067

Solution (Python):
def main(sample_file = ''):

    """ convenient functions
    
    
    
    
    
    """

    """convenient decorator
    
    
        
        
        
        
        
        
        
        
        
        
    """
    
    
    import sys
    sys.setrecursionlimit(10**7)
    from itertools import accumulate, combinations, permutations, product 
    
    from math import factorial, ceil, floor, sqrt
    def factorize(n):
        """return the factors of the Arg and count of each factor
        
        Args:
            n (long): number to be resolved into factors
        
        Returns:
            list of tuples: factorize(220) returns [(2, 2), (5, 1), (11, 1)]
        """
        fct = []  
        b, e = 2, 0  
        while b * b <= n:
            while n % b == 0:
                n = n // b
                e = e + 1
            if e > 0:
                fct.append((b, e))
            b, e = b + 1, 0
        if n > 1:
            fct.append((n, 1))
        return fct
    def combinations_count(n, r):   
        """Return the number of selecting r pieces of items from n kinds of items.
        
        Args:
            n (long): number
            r (long): number
        
        Raises:
            Exception: not defined when n or r is negative
        
        Returns:
            long: number
        """
        
        if n < 0 or r < 0:
            raise Exception('combinations_count(n, r) not defined when n or r is negative')
        if n - r < r: r = n - r
        if r < 0: return 0
        if r == 0: return 1
        if r == 1: return n
        numerator = [n - r + k + 1 for k in range(r)]
        denominator = [k + 1 for k in range(r)]
        for p in range(2,r+1):
            pivot = denominator[p - 1]
            if pivot > 1:
                offset = (n - r) % p
                for k in range(p-1,r,p):
                    numerator[k - offset] /= pivot
                    denominator[k] /= pivot
        result = 1
        for k in range(r):
            if numerator[k] > 1:
                result *= int(numerator[k])
        return result
    def combinations_with_replacement_count(n, r):
        """Return the number of selecting r pieces of items from n kinds of items allowing individual elements to be repeated more than once.
        
        Args:
            n (long): number
            r (long): number
        
        Raises:
            Exception: not defined when n or r is negative
        
        Returns:
            long: number
        """
        if n < 0 or r < 0:
            raise Exception('combinations_with_replacement_count(n, r) not defined when n or r is negative')
        elif n == 0:
            return 1
        else:
            return combinations_count(n + r - 1, r)
    from bisect import bisect_left, bisect_right
    from collections import deque, Counter, defaultdict 
    from heapq import heapify, heappop, heappush, heappushpop, heapreplace,nlargest,nsmallest 
    from copy import deepcopy, copy 
    import operator
    from operator import itemgetter 
    
    
    from functools import reduce, lru_cache
    def chmin(x, y):
        """change minimum
        if x > y, x = y and return (x, True).
        convenient when solving problems of dp[i]
        
        Args:
            x (long): current minimum value
            y (long): potential minimum value
        
        Returns:
            (x, bool): (x, True) when updated, else (x, False)
        """
        if x > y:
            x = y
            return (x, True)
        else:
            return (x, False)
    def chmax(x, y):
        """change maximum
        if x < y, x = y and return (x, True).
        convenient when solving problems of dp[i]
        
        Args:
            x (long): current maximum value
            y (long): potential maximum value
        
        Returns:
            (x, bool): (x, True) when updated, else (x, False)
        """
        if x < y:
            x = y
            return (x, True)
        else:
            return (x, False)

    from fractions import gcd 
    def gcds(numbers):
        return reduce(gcd, numbers)
    def lcm(x, y):
        return (x * y) // gcd(x, y)
    def lcms(numbers):
        return reduce(lcm, numbers, 1)
    def make_divisors(n, reversed=False):
        """create list of divisors
        
        Args:
            number (int): number from which list of divisors is created
            reversed (bool, optional): ascending order if False. Defaults to False.
        
        Returns:
            list: list of divisors
        """
        divisors = set()
        for i in range(1, int(n**0.5)+1):
            if n % i == 0:
                divisors.add(i)
                divisors.add(n//i)
        return sorted(list(divisors),reverse=reversed)
    
    
    
    INF = 10 ** 18
    MOD = 10 ** 9 + 7
    AtoZ = list('abcdefghijklmnopqrsruvwxyz') 
    modpow = lambda a, n, p = MOD: pow(a, n, p) 
    def modinv(a, p = MOD):
        
        
        return modpow(a, p-2, p)
    def modinv_list(n, p = MOD):
        if n <= 1:
            return [0,1][:n+1]
        else:
            inv_t = [0,1]
            for i in range(2, n+1):
                inv_t += [inv_t[p % i] * (p - int(p / i)) % p]
            return inv_t
    def modfactorial_list(n, p = MOD):
        if n == 0:
            return [1]
        else:
            l = [0] * (n+1)
            tmp = 1
            for i in range(1, n+1):
                tmp = tmp * i % p
                l[i] = tmp
            return l
    def modcomb(n, k, fac_list = [], p = MOD):
        
        
        from math import factorial
        if n < 0 or k < 0 or n < k: return 0
        if n == 0 or k == 0: return 1
        if len(fac_list) <= n:
            a = factorial(n) % p
            b = factorial(k) % p
            c = factorial(n-k) % p
        else:
            a = fac_list[n]
            b = fac_list[k]
            c = fac_list[n-k]
        return (a * modpow(b, p-2, p) * modpow(c, p-2, p)) % p
    def modadd(a, b, p = MOD):
        return (a + b) % MOD
    def modsub(a, b, p = MOD):
        return (a - b) % p
    def modmul(a, b, p = MOD):
        return ((a % p) * (b % p)) % p
    def moddiv(a, b, p = MOD):
        return modmul(a, modpow(b, p-2, p))

    class UnionFindTree:
        """union find tree class
        TODO: fix this description...
        how to use (example):
        >>  uf = UnionFindTree(N) 
        >>  if uf.find_root(a) == uf.find_root(b):
        >>      do something
        >>  else:
        >>      do something
        >>      uf.unite(a, b)
        """
        def __init__(self, N):
            self.root = [-1] * (N+1)
            self.rank   = [0]  * (N+1)
            self.connected_num = [1] * (N+1)
    
        def find_root(self,x):
            root = self.root
            while root[x] != -1:
                x = root[x]
            return x
    
        def unite(self,x,y):
            root = self.root
            rank = self.rank
            connected_num = self.connected_num
            find_root = self.find_root
    
            rx = find_root(x)
            ry = find_root(y)
            if rx != ry:
                if rank[rx] < rank[ry]:
                    root[rx] = ry
                    rx,ry = ry,rx
                else:
                    if rank[rx] == rank[ry]:
                        rank[rx] += 1
                    root[ry] = rx       
                connected_num[rx] += connected_num[ry]

    class SegTree:
        """
        ref: https://qiita.com/takayg1/items/c811bd07c21923d7ec69
        init(init_val, ide_ele): 配列init_valで初期化 O(N)
        update(k, x): k番目の値をxに更新 O(logN)
        query(l, r): 区間[l, r)をsegfuncしたものを返す O(logN)
        """
        def __init__(self, init_val, segfunc, ide_ele):
            """
            init_val: 配列の初期値
            segfunc: 区間にしたい操作
            ide_ele: 単位元
            n: 要素数
            num: n以上の最小の2のべき乗
            tree: セグメント木(1-index)
            """
            n = len(init_val)
            self.segfunc = segfunc
            self.ide_ele = ide_ele
            self.num = 1 << (n - 1).bit_length()
            self.tree = [ide_ele] * 2 * self.num
            
            for i in range(n):
                self.tree[self.num + i] = init_val[i]
            
            for i in range(self.num - 1, 0, -1):
                self.tree[i] = self.segfunc(self.tree[2 * i], self.tree[2 * i + 1])

        def update(self, k, x):
            """
            k番目の値をxに更新
            k: index(0-index)
            x: update value
            """
            k += self.num
            self.tree[k] = x
            while k > 1:
                self.tree[k >> 1] = self.segfunc(self.tree[k], self.tree[k ^ 1])
                k >>= 1

        def query(self, l, r):
            """
            [l, r)のsegfuncしたものを得る
            l: index(0-index)
            r: index(0-index)
            """
            res = self.ide_ele
            l += self.num
            r += self.num
            while l < r:
                if l & 1:
                    res = self.segfunc(res, self.tree[l])
                    l += 1
                if r & 1:
                    res = self.segfunc(res, self.tree[r - 1])
                l >>= 1
                r >>= 1
            return res

    
    
    
    
    
    
    
    

    def BellmanFord(N, M, ABC, vertex_start, vertex_end, value_if_inf = -1, find_shortest = False):
        """to calculate furthest or shortest length between vertex_start and vertex_end using BellmanFord algorithm
        
        Args:
            N (int): number of vertices
            M (int): number of edges
            ABC (list): [(ai, bi, ci) for _ in range(N)] where i-th edge is directed from vertex ai to vertex bi and the length is ci 
            vertex_start (int): start vertex. usually use 0.
            vertex_end (int): end vertex. usually use N-1.
            value_if_inf (int or string as you like, optional): value you want when the furthest (or shortest) distance is infinite (or -infinite). Defaults to -1.
            find_shortest (bool, optional): choose False to find furthest path. Defaults to False.
        
        Returns:
            int or string: normally int (but can be str if you set value_if_inf to str)
            
        Example:
                N, M, P = R()
                ABC = [R() for _ in range(M)]
                ABC = [(a-1, b-1, c-P) for a, b, c in ABC]
                print(BellmanFord(N, M, ABC, 0, N-1, value_if_inf = 'inf'))

        """

        def make_reachable_list(N, M, ABC, vertex_start, vertex_end):
            reachable_to_direct = defaultdict(list)
            reachable_from_direct = defaultdict(list)
            reachable_from_start = [False] * N
            reachable_to_end = [False] * N
            reachable_from_start[vertex_start] = True
            reachable_to_end[vertex_end] = True
            reachable_from_both_sides = [False] * N
            dfs_from_start = []
            dfs_to_end = []
            for a, b, c in ABC:
                reachable_to_direct[a].append(b)
                reachable_from_direct[b].append(a)
                if a == vertex_start:
                    dfs_from_start.append(b)
                    reachable_from_start[b] = True
                if b == vertex_end:
                    dfs_to_end.append(a)
                    reachable_to_end[a] = True
            while dfs_from_start:
                v = dfs_from_start.pop()
                for i in reachable_to_direct[v]:
                    if not reachable_from_start[i]:
                        reachable_from_start[i] = True
                        dfs_from_start.append(i)
            while dfs_to_end:
                v = dfs_to_end.pop()
                for i in reachable_from_direct[v]:
                    if not reachable_to_end[i]:
                        reachable_to_end[i] = True
                        dfs_to_end.append(i)
            for i in range(N):
                reachable_from_both_sides[i] = reachable_from_start[i] and reachable_to_end[i]
            return reachable_from_both_sides
        
        reachable_from_both_sides = make_reachable_list(N, M, ABC, vertex_start, vertex_end)
        
        if find_shortest:
            dist = [INF for i in range(N)]
        else:
            dist = [-INF for i in range(N)]
        
        dist[vertex_start] = 0
        for i in range(N):
            updated = False
            for a, b, c in ABC:
                if not reachable_from_both_sides[a]:
                    continue
                elif find_shortest:
                    update_condition = dist[a] + c < dist[b]
                else:
                    update_condition = dist[a] + c > dist[b]
                if dist[a] != INF and update_condition:
                    dist[b] = dist[a] + c
                    updated = True
                    if i == N-1:
                        return value_if_inf
            if not updated:
                break
        return dist[vertex_end]

    
    def warshall_floyd(number_vertex, XYD, shift_one_for_vertex=False):
        
        
        
        
        
        d = [[float("inf")]*number_vertex for i in range(number_vertex)]
        for x, y, dist in XYD:
            if shift_one_for_vertex:
                x = x - 1
                y = y - 1
            d[x][y] = dist
            d[y][x] = dist
        for i in range(number_vertex):
            d[i][i] = 0 
        for k in range(number_vertex):
            for i in range(number_vertex):
                for j in range(number_vertex):
                    d[i][j] = min(d[i][j],d[i][k] + d[k][j])
        return d


    """ initialize variables and set inputs
    
        
        
            
            
    
        
        
        
        
        
        
        
    
        
        
        
        
    
        
        
    """

    
    r = lambda: sys.stdin.readline().strip()
    r_int = lambda: int(r())
    r_float = lambda: float(r())
    R = lambda: list(map(int, r().split()))
    R_str = lambda: r().split()
    R_map = lambda: map(int, r().split())
    R_float = lambda: list(map(float, r().split()))
    R_tuple = lambda: tuple(map(int, r().split()))

    """ how to treat input
    
    
    
    
    
    
    
    """

    
    if sample_file:
        sys.stdin = open(sample_file)
        
    
    
    
    N, M, X = R()
    CA = [R() for _ in range(N)]
    ans = INF
    for i in range(2**N):
        bin_str = bin(i)
        cost = 0
        unde = [0] * M
        for j in range(N):
            if bin_str[-j-1] == 'b':
                break
            if bin_str[-j-1] == '1':
                for k in range(M+1):
                    if k == 0:
                        cost += CA[j][k]
                    else:
                        unde[k-1] += CA[j][k]
        for each_unde in unde:
            if each_unde < X:
                break
        else:
            ans = min(cost, ans)
    if ans == INF:
        print(-1)
    else:
        print(ans)
        

        
    
    
    

    
    
    


    
    
    

    """memo: how to use defaultdict of list
    
    Dic = defaultdict(list)
    
    Dic[x].append(y)
    
    for k, v in Dic.items():
    """
    
    """memo: how to solve binary problems
    
    >>> a = 5
    >>> bin_str_a = format(a, '
    >>> print(bin_str_a)
    0b0101 
    """
    
    """memo: how to solve the problem
    creating simple test/answer
    greed
    simple dp
    graph
    """

if __name__ == '__main__':
    main()

Solution (Python):
N, M, X = map(int, input().split())
CA = []
for _ in range(N):
    tmp = list(map(int, input().split()))
    CA.append(tmp)

ans = -1
for i in range(2**N):
    tmp_cost = 0
    tmp_X = [0]*(M+1)
    for j in range(N):
        if ((i >> j) & 1):
            for k in range(M+1):
                tmp_X[k] += CA[j][k]
    for j in range(1, M+1):
        if tmp_X[j] < X:
            break
    else:
        if ans == -1:
            ans = tmp_X[0]
        else:
            ans = min(ans, tmp_X[0])
print(ans)

Solution (Python):
import numpy as np

n, m, x = map(int, input().split())
ca = np.array([list(map(int, input().split())) for _ in range(n)])

pattern = []
for i in range(2 ** n):
    temp = [0] * n
    for j in range(n):
        if (i >> j) & 1:
            temp[j] = 1
    pattern.append(temp)

ans = 10 ** 10
for p in pattern:
    check = [0] * (m + 1)
    for i in range(n):
        if p[i] == 1:
            check += ca[i]
    flag = True
    for a in check[1:]:
        if a < x:
            flag = False
            break
    if flag:
        ans = min(ans, check[0])

print(ans) if ans != 10 ** 10 else print(-1)

Solution (Python):
n,m,x=map(int,input().split())
CA=[list(map(int,input().split())) for _ in range(n)]

res=10**7

for i in range(2**n):
	money=0
	under=[0]*m
	
	for j in range(n):
		if i>>j&1:
			money+=CA[j][0]
			for k in range(m):
				under[k]+=CA[j][k+1]
		
	if min(under)>=x:
		res=min(res,money)

if res==10**7:
	print("-1")
else:
	print(res)

Solution (Python):


import sys
import math
import time

import collections
from collections import deque
from collections import Counter
import queue
import copy
import bisect
import heapq
import itertools










N, M, X = map(int,input().split())
Book = [list(map(int, input().split())) for _ in range(N)]
Alg = [0]*M
money = 10**8
temp = 0
flag = True
ans = 0

for i in range(2**N):
    for j in range(N):
        if((i >> j) & 1):
            temp += Book[j][0]
            for k in range(M):
                Alg[k] += Book[j][k+1]
    for l in range(M):
        
        if(Alg[l] < X):
            flag = False
            break
    if(flag):
        money = min(money,temp)
    flag = True
    temp = 0
    for m in range(len(Alg)):
        Alg[m] = 0

if(money==10**8):
    print(-1)
else:
    print(money)

Solution (Python):
n, m, x = map(int, input().split())
a = []
max_sum = [0 for _ in range(m)]
price_sum = 0
for i in range(n):
    input_list = list(map(int, input().split()))
    a.append([input_list[0], input_list[1:]])
    price_sum += input_list[0]
    for j in range(m):
        max_sum[j] += input_list[j + 1]

flag = 0
for j in range(m):
    if max_sum[j] < x:
        flag = 1
if flag:
    print(-1)
else:
    min_price = price_sum
    for pattern in range(1, 2 ** n):
        flag = 0
        now_price = price_sum
        now_sum = max_sum.copy()
        
        for i in range(n):
            if pattern & 1 << i:
                now_price -= a[i][0]
                for j in range(m):
                    now_sum[j] -= a[i][1][j]

        
        for j in range(m):
            if now_sum[j] < x:
                flag = 1
        if not flag and now_price < min_price:
            min_price = now_price

    print(min_price)

Solution (Python):

import sys
from itertools import product


def solve(N, M, X, C, A):
    L = list(product([True, False], repeat=N))
    mn = 100000000000
    for l in L:
        cst = 0
        rikai = [0 for _ in range(M)]
        for i in range(N):
            if l[i]:
                cst += C[i]
                for j in range(M):
                    rikai[j] += A[i][j]
        tf = True
        for j in range(M):
            if rikai[j] < X:
                tf = False
                break
        if tf:
            mn = min(mn, cst)
    if mn == 100000000000:
        print(-1)
    else:
        print(mn)
    return


def main():
    def iterate_tokens():
        for line in sys.stdin:
            for word in line.split():
                yield word
    tokens = iterate_tokens()
    N = int(next(tokens))  
    M = int(next(tokens))  
    X = int(next(tokens))  
    C = [0 for _ in range(N)]
    A = [[0 for _ in range(M)] for _ in range(N)]
    for i in range(N):
        C[i] = int(next(tokens))
        for j in range(M):
            A[i][j] = int(next(tokens))
    solve(N, M, X, C, A)

if __name__ == '__main__':
    main()

Solution (Python):
import numpy as np

N, M, X = map(int, input().split())

C = [0] * N
A = np.zeros((N, M), np.int64)
for i in range(N):
    Y = [int(k) for k in input().split()]
    C[i] = Y[0]
    A[i, :] = Y[1:]
ans = float('inf')
for bits in range(1 << N):
    sum = 0
    U = np.zeros(M, np.int64)
    for i in range(N):
        if (bits >> i) & 1:
            sum += C[i]
            U += A[i, :]
    if np.count_nonzero(U >= X) == M:
        ans = min(ans, sum)
print(ans if ans != float('inf') else -1)

Solution (Python):

n, m, x = map(int,input().split())
array = [[int(x) for x in input().split()] for y in range(n)]

ans = float("inf")
for i in range(2**n):
    tmp = [0 for x in range(m)]
    tmp_cost = 0
    bits = format(i, "b").zfill(n)
    for j in range(n):
        bit = bits[j]
        if bit == "1":
            tmp_cost += array[j][0]
            for k in range(m):
                tmp[k] += array[j][1+k]
    for l in tmp:
        if l < x:
            break
    else:
        ans = min(ans, tmp_cost)
print(ans if ans != float("inf") else -1)

Solution (Python):
import sys
sys.setrecursionlimit(10000000)
INF = 10 ** 10
ans = INF


def rec(A, C, X, idx, ability, sum_):
    if idx == len(A):
        for i in range(len(ability)):
            if ability[i] < X:
                break
        else:
            global ans
            ans = min(sum_, ans)
    else:
        
        rec(A, C, X, idx+1, ability, sum_)
        M = len(A[0])
        import copy 
        new_ability = copy.copy(ability)
        for i in range(M):
            new_ability[i] += A[idx][i]
        rec(A, C, X, idx+1, new_ability, sum_+C[idx])


def main():
    N, M, X = map(int, input().split())
    C = []
    A = []
    for i in range(N):
        lists = [int(c) for c in input().split()]
        ci = lists[0]
        ai = lists[1:]
        C.append(ci)
        A.append(ai)

    ability = [0] * M
    rec(A, C, X, 0, ability, 0)

    if ans == INF:
        print(-1)
    else:
        print(ans)
    

    
    



if __name__ == '__main__':
    main()

Solution (Python):
import numpy as np
import itertools

N, M, X = map(int, input().split())
CA = []
cost = 12 * (10**5) + 1

for _ in range(N):
  CA.append(list(map(int, input().split())))

for T in itertools.product([1,0], repeat = N):
  Flag = True
  ans = np.zeros(M+1)
  for i in range(N):
    if T[i] == 1:
      ans += np.array(CA[i])

  for j in range(1, M+1):
    if ans[j] < X:
      Flag = False
      break
  
  if Flag:
    cost = min(cost, ans[0])

if cost == 12 * (10**5) + 1:
  print(-1)
else:
  print(int(cost))

Solution (Python):
import numpy as np


def main():
    n, m, x = map(int, input().split())
    cas = np.array([list(map(int, input().split())) for _ in range(n)])

    ans = -1
    for i in range(2 ** n):
        if i == 0:
            continue
        books = []
        for j in range(n):
            if ((i >> j) & 1):
                books.append(cas[j])

        books = np.array(books)
        if np.all(np.sum(books[:, 1:], axis=0) >= x):
            ans_temp = np.sum(books[:, 0])
            if ans == -1:
                ans = ans_temp
            else:
                ans = min(ans, ans_temp)
    print(ans)


if __name__ == "__main__":
    main()

Solution (Python):
import itertools
from collections import defaultdict
import collections
import sys
sys.setrecursionlimit(200000)
mod = 1000000007

n, m, x = map(int, input().split())
ca = [list(map(int, input().split())) for i in range(n)]

ans = mod
for i in range(2 ** n):
    alg = [0] * (m+1)
    switch = [0] * n
    for j in range(n):
        if((i >> j) & 1):
            switch[j] = 1
    for k in range(n):
        for l in range(m + 1):
            if switch[k] == 1:
                alg[l] += ca[k][l]
    for y in range(m+1):
        if y != 0:
            if x > alg[y]:
                break
        if y == m:
            ans = min(ans, alg[0])

if ans == mod:
    print("-1")
else:
    print(ans)

Solution (Python):
from itertools import groupby, accumulate, product, permutations, combinations
def solve():
    N, M, X = map(int, input().split())
    A = [list(map(int, input().split())) for _ in range(N)]
    ans = 10**9
    for p in product([0,1],repeat=N):
        cost = 0
        for i in range(N):
            if p[i]==1:
                cost += A[i][0]
        for j in range(1,M+1):
            und = 0
            for i in range(N):
                if p[i]==1:
                    und += A[i][j]
            if und<X:
                break
        else:
            ans = min(ans,cost)
    if ans == 10**9:
        return -1
    return ans
print(solve())

Solution (Python):
import copy
n, m, x = map(int, input().split())
c, a = [], []

for i in range(n):
    temp = list(map(int, input().split()))
    c.append(temp[0])
    a.append(temp[1:])


ans = 10**10

def isClear(arr):
    return all(val >= x for val in arr)

def solve(idx, price, arr):
    global ans
    if idx == n:
        if isClear(arr):
            
            ans = min(ans, price)
        return

    
    temp = copy.deepcopy(arr)
    for i in range(m):
        temp[i] += a[idx][i]

    solve(idx + 1, price + c[idx], temp)

    
    solve(idx + 1, price, arr)

score = [0]*m
solve(0, 0, score)

if ans == 10**10:
    print(-1)
else:
    print(ans)

Solution (Python):




import sys
input = sys.stdin.readline



def main():
    N,M,X = map(int,input().split())
    CA = [list(map(int,input().split())) for i in range(N)]

    res = 10 ** 9
    isFound = False

    for i in range(2**N):
        now = [0 for _ in range(M+1)]
        for j in range(N):
            if (i & (1<<j)):
                for k in range(M+1):
                    now[k] += CA[j][k]
        isOK = True
        for k in range(M):
            if now[k+1] < X:
                isOK = False
                break
        if isOK:
            res = min(res,now[0])
            isFound = True

    if not isFound:
        res = -1

    print(res)



main()

Solution (Python):
n,m,x=map(int,input().split())
lis=[list(map(int,input().split())) for _ in range(n)]
ans=10**18
for i in range(2**n):
    l=[]
    rikai=[0]*m
    ok=True
    for j in range(n):
        if (i>>j)&1:
            l.append(j)
    cost=0
    for k in l:
        cost+=lis[k][0]
        for s in range(1,m+1):
            rikai[s-1]+=lis[k][s]
    for j in range(m):
        if rikai[j]<x:
            ok=False
    
    if ok:
        ans=min(ans,cost)
if ans==10**18:
    ans=-1
print(ans)

Solution (Python):
import numpy as np

N,M,X = list(map(int, input().split()))
books = np.array([list(map(int, input().split())) for i in range(N)])

borders = np.ones(M+1) * X
borders[0] = 0
maxi = 2 ** N

init_cost = 10**8
cost = init_cost
for i in range(1,maxi):
    bits = [j for j in range(N) if (i >> j &1)]
    res = sum(books[bits])

    if np.all(np.where(res[1:] >= X, True, False)):
        cost = min(res[0],cost)

if cost == init_cost:
    print(-1)
else:
    print(cost)

Solution (Python):
from itertools import product

N,M,X=map(int,input().split())
C=[0]*N
A=[[0] for _ in range(N)]
for i in range(N):
  C[i],*A[i] = map(int,input().split())
  
s= product([1,0],repeat=N)
ans=float("inf")

for kumi in s:
  gou=True
  cost=0
  R=[0 for _ in range(M)]
  for i,n in enumerate(kumi):
    for j in range(M):  
      R[j] +=n*A[i][j]
    cost +=n*C[i]
  
  for pt in R:
    if pt<X:
      gou=False
  if gou:
    ans=min(ans,cost)
else:
  if ans!=float("inf"):
    print(ans)
  else:
    print(-1)

Solution (Python):
N, M, X = map(int, input().split())
CA = [list(map(int, input().split())) for _ in range(N)]
ans = -1
cost = 10 ** 7
for i in range(2 ** N):
    bit = format(i, '0' + str(N) + 'b')
    A = [0] * M
    work_cost = 0
    counter = 0
    for b in bit:
        if b == "0":
            counter += 1
        else:
            work_cost += CA[counter][0]
            for i, ca in enumerate(CA[counter][1:]):
                A[i] += ca
            counter += 1
        
    x = sum([1 for i in A if i >= X])
    if M == x:
        cost = min(cost, work_cost)
    

if cost == 10 ** 7:
    cost = -1
print(cost)

Solution (Python):



import numpy as np
from itertools import *






N, M, X = [int(x) for x in input().split()]

r = [0] * M
b = []

for n in range(N):
    b += [[int(x) for x in input().split()]]
C = []

for n in range(N):
    C += list(combinations(b, n+1))

minm = -1

for c in C:
    c = np.array(c)
    if min(np.sum(c[:, 1:M+1], axis=0)) >= X:
        if minm == -1 or np.sum(c[:, 0]) < minm:
            minm = np.sum(c[:, 0])

print(minm)

Solution (Python):
import itertools

N, M, X = map(int, input().split())
CA = [list(map(int, input().split())) for _ in range(N)]

mn = 10**10
for pat in itertools.product([0,1], repeat=N):
    cost = 0
    skills = [0]*M
    for i in range(N):
        cost += pat[i] * CA[i][0]
        for j in range(M):
            skills[j] += pat[i] * CA[i][j+1]
    ok = True
    for j in range(M):
        if skills[j] < X:
            ok = False
    if ok:
        mn = min(mn, cost)

if mn == 10**10:
    print(-1)
else:
    print(mn)

Solution (Python):

N, M, X = map(int,input().split())
C = []
A = []
for i in range(N):
    c,*a = map(int,input().split())
    C.append(c)
    A.append(a)

def calc_price(C,s):
    ans = 0
    for i,v in enumerate(s):
        if v==1:
            ans+=C[i]
    return ans


import itertools
status = [(0, 1) for _ in range(N)]
state = list(itertools.product(*status))

ans = 10**9+7
flg = -1
for s in state:
    price = 0
    gakuryoku = [0]*M
    for j,v in enumerate(s):
        if v == 1:
            price+=C[j]
            for k in range(M):
                gakuryoku[k] += A[j][k]
        if min(gakuryoku)>=X and ans > price:
            ans = price
            flg=0
if flg==-1:
    print(-1)
else:
    print(ans)