Problem:
 Score : 600 points    Problem Statement We have one slime.  You can set the health of this slime to any integer value of your choice.  A slime reproduces every second by spawning another slime that has strictly less health. You can freely choose the health of each new slime. The first reproduction of our slime will happen in one second.  Determine if it is possible to set the healths of our first slime and the subsequent slimes spawn so that the multiset of the healths of the 2^N slimes that will exist in N seconds equals a multiset S .  Here S is a multiset containing 2^N (possibly duplicated) integers: S_1,~S_2,~...,~S_{2^N} .      Constraints  All values in input are integers.  1 \leq N \leq 18  1 \leq S_i \leq 10^9         Input Input is given from Standard Input in the following format:  N  S_1  S_2  ...  S_{2^N}       Output If it is possible to set the healths of the first slime and the subsequent slimes spawn so that the multiset of the healths of the 2^N slimes that will exist in N seconds equals S , print Yes ; otherwise, print No .        Sample Input 1 2
4 2 3 1      Sample Output 1 Yes  We will show one way to make the multiset of the healths of the slimes that will exist in 2 seconds equal to S .  First, set the health of the first slime to 4 .  By letting the first slime spawn a slime whose health is 3 , the healths of the slimes that exist in 1 second can be 4,~3 .  Then, by letting the first slime spawn a slime whose health is 2 , and letting the second slime spawn a slime whose health is 1 , the healths of the slimes that exist in 2 seconds can be 4,~3,~2,~1 , which is equal to S as multisets.       Sample Input 2 2
1 2 3 1      Sample Output 2 Yes  S may contain multiple instances of the same integer.       Sample Input 3 1
1 1      Sample Output 3 No       Sample Input 4 5
4 3 5 3 1 2 7 8 7 4 6 3 7 2 3 6 2 7 3 2 6 7 3 4 6 7 3 4 2 5 2 3      Sample Output 4 No

Solution (Python):
n = int(input())
s = list(map(int, input().split()))
rest = sorted(s)
parent = [rest.pop()]

for _ in range(n):
    next_parent = []
    next_rest = []
    for i in parent[::-1]:
        while rest:
            x = rest.pop()
            if x < i:
                next_parent.append(x)
                break
            else:
                next_rest.append(x)
                continue
    parent += next_parent
    parent.sort()
    rest += next_rest
    rest.sort()

if len(parent) == 2**n:
    print('Yes')
else:
    print('No')

Solution (Python):

n = int(input())
a = list(map(int, input().split()))
a.sort()
parent = [a[-1]]
rest = a[:-1]

for _ in range(n):
    next_parent = []
    next_rest = []
    for i in parent[::-1]:
        while(rest):
            x = rest.pop()
            if x < i:
                next_parent.append(x)
                break
            else:
                next_rest.append(x)
                continue
    parent += next_parent
    parent.sort()
    next_rest.reverse()
    rest += next_rest

if len(parent) == 2**n:
    print("Yes")
else:
    print("No")

Solution (Python):
n = int(input())
s = list(map(int, input().split()))
s.sort(reverse=True)

used = [s[0]]
unused = s[1:]
for i in range(n):
    nxt_used = []
    nxt_unused = []
    left = 0
    
    for j in used:
        while left < len(unused) and unused[left] >= j:
            nxt_unused.append(unused[left])
            left += 1
        if left == len(unused):
            print("No")
            exit()
        nxt_used.append(j)
        nxt_used.append(unused[left])
        left += 1
    nxt_unused += unused[left:]
    nxt_unused.sort(reverse=True)
    nxt_used.sort(reverse=True)
    used = nxt_used
    unused = nxt_unused
print("Yes")

Solution (Python):

n = int(input())
a = list(map(int, input().split()))
a.sort()
parent = [a[-1]]
rest = a[:-1]
for _ in range(n):
    next_parent = []
    next_rest = []
    for p in parent[::-1]:
        while rest:
            x = rest.pop()
            if x < p:
                next_parent.append(x)
                break
            else:
                next_rest.append(x)
                continue
    parent += next_parent
    parent.sort()
    rest = rest + next_rest[::-1]

if len(parent) == 2**n:
    ans = 'Yes'
else:
    ans = 'No'
print(ans)

Solution (Python):

def f_f():
    n, *s = map(int, open(0).read().split())
    s.sort()
    ps, next_ps, cs = [s.pop()], [], []
    for _ in range(n):
        for p in ps:
            while s:
                c = s.pop()
                if p>c:
                    next_ps.append(c)
                    break
                else:
                    cs.append(c)
        s, ps, next_ps, cs = s+cs[::-1], sorted(ps+next_ps, reverse=True), [], []

    print("No" if s else "Yes")

if __name__ == "__main__":
    f_f()

Solution (Python):
from sys import exit, stderr, stdin
input = stdin.readline
from collections import defaultdict
from sys import stderr
def debug(var, name="hoge"):
    print(name +":" + str(type(var)) + " = " + repr(var), file=stderr)
    return
def main():
    N = int(input())
    S = [int(a) for a in input().split()]
    S = sorted(S)
    exist = [S.pop()]
    debug(S)
    debug(exist)
    for i in range(N):
        next_exist = []
        next_s = []
        for p in exist[::-1]:
            while S:
                x = S.pop()
                if x < p:
                    next_exist.append(x)
                    break
                else:
                    next_s.append(x)
        exist += next_exist
        exist.sort()
        S += next_s[::-1]

    if len(exist) == 2**N:
        print("Yes")
        exit()
    else:
        print("No")
        exit()

if __name__ == "__main__":
    main()

Solution (Python):
n = int(input())
a = [int(i) for i in input().split()]
a.sort()

big =  [a[-1]]
rest = a[:-1]


for i in range(n):
    not_yet = []
    count = 0
    for b in big:
        if count==2**i:
            break
        while rest:
            r = rest.pop()
            if r < b:
                big.append(r)
                count += 1
                break
            not_yet.append(r)
    big.sort(reverse=True)
    rest += not_yet[::-1]
print("Yes" if len(rest)==0 else "No")

Solution (Python):
from collections import Counter
n = int(input())
a = [int(item) for item in input().split()]
cnt = Counter(a)

key_num = len(cnt.keys())
rank = [0] * key_num 
keys = list(cnt.keys())
keys.sort(reverse=True)
for i, key in enumerate(keys):
    rank[i] = cnt[key]
cur = [0] * key_num 
cur[0] = 1
for i in range(n):
    tmp = cur[:]
    free = 0
    for j in range(key_num):
        if rank[j] > cur[j] and free > 0:
            if cur[j] + free > rank[j]:
                free -= rank[j] - cur[j]
                cur[j] = rank[j]
            else:
                cur[j] += free
                free = 0
        free += tmp[j] 
if sum(cur) == 2**n:
    print("Yes")
else:
    print("No")

Solution (Python):
from collections import Counter
n = int(input())
a = [int(item) for item in input().split()]
cnt = Counter(a)

key_num = len(cnt.keys())
rank = [0] * key_num 
keys = list(cnt.keys())
keys.sort(reverse=True)
for i, key in enumerate(keys):
    rank[i] = cnt[key]
cur = [0] * key_num 
cur[0] = 1
for i in range(n):
    tmp = cur[:]
    free = 0
    for j in range(key_num):
        if rank[j] > cur[j] and free > 0:
            if cur[j] + free > rank[j]:
                free -= rank[j] - cur[j]
                cur[j] = rank[j]
            else:
                cur[j] += free
                free = 0
        free += tmp[j] 
if sum(cur) == 2**n:
    print("Yes")
else:
    print("No")

Solution (Python):
n = int(input())
s = list(map(int, input().strip().split()))

s.sort()

p = [s[-1]]
h = s[:-1]
for i in range(n):
    t = []
    o = []
    for j in p:

        while len(h):
            if h[-1] < j:
                o.append(h.pop())
                break
            t.append(h.pop())

    h.extend(t)
    p.extend(o)
    p.sort(reverse=True)
    h.sort()

print("Yes" if len(h) == 0 else "No")

Solution (Python):

from collections import defaultdict,deque
from heapq import heappush, heappop
import sys
import math
import bisect
import random
def LI(): return [int(x) for x in sys.stdin.readline().split()]
def I(): return int(sys.stdin.readline())
def LS():return [list(x) for x in sys.stdin.readline().split()]
def S():
    res = list(sys.stdin.readline())
    if res[-1] == "\n":
        return res[:-1]
    return res
def IR(n):
    return [I() for i in range(n)]
def LIR(n):
    return [LI() for i in range(n)]
def SR(n):
    return [S() for i in range(n)]
def LSR(n):
    return [LS() for i in range(n)]

sys.setrecursionlimit(1000000)
mod = 1000000007


def A():
    n = I()
    print(n**3)
    return


def B():
    n = I()
    a = LI()
    b = LI()
    c = LI()
    ans = sum(b)
    for i in range(n-1):
        x = a[i]
        y = a[i+1]
        if y == x+1:
            ans += c[x-1]
    print(ans)
    return


def C():
    n = I()
    b = LI()
    b.append(float("inf"))
    a = [min(b[i],b[i-1]) for i in range(n)]
    print(sum(a))
    return


def D():
    n,k = LI()
    a = S()
    ans = 0
    for i in range(n-1):
        if a[i] == a[i+1]:
            ans += 1
    print(min(n-1,ans+2*k))
    return


def E():
    def add(i):
        while i <= n:
            bit[i] += 1
            i += i&-i

    def sum(i):
        res = 0
        while i > 0:
            res += bit[i]
            i -= i&-i
        return res

    n = I()
    p = LI()
    r = [0]*n
    bit = [0]*(n+1)
    for i in range(n)[::-1]:
        r[i] = (n-i-1)-sum(p[i])
        add(p[i])
    print(r)
    l = [0]*n
    bit = [0]*(n+1)
    for i in range(n):
        l[i] = i-sum(p[i])
        add(p[i])
    print(l)

    return


def F():
    n = I()
    s = LI()
    s.sort()
    s = s[::-1]
    m = 1<<n
    f = [-1]*m
    f[0] = 0
    for i in range(n):
        k = 0
        l = 0
        for j in range(1<<i):
            while f[k] != i:
                k += 1
            while f[l] >= i or s[k] <= s[l]:
                l += 1
                if l == m:
                    print("No")
                    return
            f[l] = i+1
            k += 1
        for j in range(m):
            if f[j] >= 0:
                f[j] = i+1
    print("Yes")
    return


if __name__ == "__main__":
    F()

Solution (Python):
import sys
N = int(input())
S = sorted(list(map(int, input().split())))
parent = [S[-1]]
rest = S[:-1]
for i in range(N):
    next_generation = []
    next_rest = []
    for p in parent[::-1]:
        while True:
            if len(rest) == 0:
                print('No')
                sys.exit()
            q = rest.pop()
            if p>q:
                next_generation.append(q)
                break
            else:
                next_rest.append(q)
    parent+=next_generation
    parent.sort()
    rest += next_rest
    rest.sort()
print('Yes')

Solution (Python):
def main():
    inf = 10 ** 9 + 5
    n = int(input())
    n2 = 2 ** n
    s = list(map(int, input().split()))
    s.sort(reverse=True)
    
    pp = [s[0]]
    s[0] = inf
    for _ in range(n):
        pp.sort()
        i = 1
        np = pp[:]
        while pp:
            p = pp.pop()
            while 1:
                if s[i] < p:
                    np.append(s[i])
                    s[i] = inf
                    break
                else:
                    i += 1
                if i == n2:
                    print("No")
                    exit()
        pp = np
    print("Yes")

main()

Solution (Python):
N = int(input())
N2 = 1 << N

S = sorted([int(x) for x in input().split()])

s = []
s.append(S[-1])
S[-1] = -1

flag = True
for i in range(N):
    p = sorted([x for x in s])

    Si = N2 - 1
    while len(p) > 0 and Si >= 0:
        if S[Si] == -1:
            Si -= 1
            continue

        if S[Si] < p[-1]:
            s.append(S[Si])
            del p[-1]
            S[Si] = -1
        
        Si -= 1
    
    if len(p) > 0:
        flag = False

print('Yes' if flag else 'No')

Solution (Python):
import bisect

n = int(input())
s = list(map(int, input().split(" ")))



s = sorted(s)
from collections import deque

def solve():
    global s

    parents = [s[-1]]
    s.pop()

    for i in range(n):
        newparents = list(parents)
        k = len(s)
        dropped = set()
        
        for p in parents:
            oldK = k
            k = bisect.bisect(s, p - 1, 0, k) - 1
            
            if k == -1:
                print("No")
                exit(0)

            newparents.append(s[k])
            dropped.add(k)
        s = [x for i, x in enumerate(s) if i not in dropped]
        parents = sorted(newparents, reverse=True)

    
    
    if k == len(s):
        print("Yes")
    else:
        print("No")
solve()

Solution (Python):
import sys
input = sys.stdin.readline

def main():
    N = int(input())
    s = sorted(list(map(int, input().strip().split())), reverse=True)
    check = [False] * (2**N)
    now = []
    now.append([s[0], 1])
    check[0] = True
    ok = True
    for i in range(N):
        next_ = []
        tmp = 0
        for j in range(len(now)):
            hp, start = now[j]
            start = max(start, tmp)
            ok = False
            for k in range(start, 2**N):
                if s[k] < hp and not check[k]:
                    tmp = k+1
                    now[j][1] = k+1
                    check[k] = True
                    next_.append([s[k], k+1])
                    ok = True
                    break
            if not ok:
                break
        now += next_
        now = sorted(now, reverse=True)
        if not ok:
            break
    
    if ok:
        print("Yes")
    else:
        print("No")

if __name__ == "__main__":
    main()

Solution (Python):
import sys
import copy
input = sys.stdin.readline

N = int(input())
A = sorted(map(int,input().split()),reverse=True)

USED=[0]*(1<<N)
USED[0]=1

for i in range(N):
    NOW=0
    k=0
    BUSED=copy.deepcopy(USED)
    for j in range(1<<i):
        while BUSED[k]==0:
            k+=1
        while USED[NOW]==1 or A[k]<=A[NOW]:
            NOW+=1

            if NOW==1<<N:
                print("No")
                sys.exit()

        USED[NOW]=1
        k+=1


print("Yes")

Solution (Python):
import sys
input = sys.stdin.readline

def main():
    N = int(input())
    s = sorted(list(map(int, input().strip().split())), reverse=True)
    check = [False] * (2**N)
    now = []
    now.append([s[0], 1])
    check[0] = True
    ok = True
    for i in range(N):
        next_ = []
        tmp = 0
        for j in range(len(now)):
            hp, start = now[j]
            start = max(start, tmp)
            ok = False
            for k in range(start, 2**N):
                if s[k] < hp and not check[k]:
                    tmp = k+1
                    now[j][1] = k+1
                    check[k] = True
                    next_.append([s[k], k+1])
                    ok = True
                    break
            if not ok:
                break
        now += next_
        now = sorted(now, reverse=True)
        if not ok:
            break
    
    if ok:
        print("Yes")
    else:
        print("No")

if __name__ == "__main__":
    main()

Solution (Python):
def solve(n,S):
    Used=[False]*len(S)
    Cur=[]
    Cur.append(S[0])
    Used[0]=True
    for _ in range(n):
        idx=0
        num=len(Cur)
        for i,s in enumerate(S):
            if (not Used[i]) and s<Cur[idx]:
                Cur.append(s)
                idx+=1
                Used[i]=True
                if idx==num:
                    break
        else:
            return 'No'
        Cur.sort(reverse=True)
    return 'Yes'

n=int(input())
S=list(map(int,input().split()))
S.sort(reverse=True)
print(solve(n,S))

Solution (Python):
import sys,bisect as bs,collections as cl
sys.setrecursionlimit(100000)
mod = 10**9+7
Max = sys.maxsize
def l(): 
    return list(map(int,input().split()))
def m(): 
    return map(int,input().split())
def onem(): 
    return int(input())
def s(x): 
    a = []
    aa = x[0]
    su = 1
    for i in range(len(x)-1):
        if aa != x[i+1]:
            a.append([aa,su])
            aa = x[i+1]
            su = 1
        else:
            su += 1
    a.append([aa,su])
    return a
def jo(x): 
    return " ".join(map(str,x))
def max2(x): 
    return max(map(max,x))
def In(x,a): 
    k = bs.bisect_left(a,x)
    if k != len(a) and a[k] ==  x:
        return True
    else:
        return False

n = onem()

p = l()

p.sort(reverse = True)

ms = p[0]
s = [p[0]]

for i in range(n):
    count = 0
    local = 0
    s.sort(reverse = True)
    while count < 2**i:
        if local >= 2**n:
            print("No")
            exit()
        if s[count] > p[local]:
            s.append(p[local])
            p[local] = ms
            count += 1
        local += 1
print("Yes")

Solution (Python):
import os
import sys

if os.getenv("LOCAL"):
    sys.stdin = open("_in.txt", "r")

sys.setrecursionlimit(2147483647)
INF = float("inf")
IINF = 10 ** 18
MOD = 10 ** 9 + 7


class BinaryIndexedTree:
    
    def __init__(self, size):
        """
        :param int size:
        """
        self._bit = [0] * size
        self._size = size

    def add(self, i, w):
        """
        i 番目に w を加える
        :param int i:
        :param int w:
        :return:
        """
        x = i + 1
        while x <= self._size:
            self._bit[x - 1] += w
            x += x & -x

    def sum(self, i):
        """
        0 番目から i 番目までの合計
        :param int i:
        :return:
        """
        ret = 0
        x = i + 1
        while x > 0:
            ret += self._bit[x - 1]
            x -= x & -x
        return ret

    def __len__(self):
        return self._size


def compress(li, origin=0):
    """
    座圧
    :param li:
    :param int origin:
    :rtype: list of int
    """
    *ret, = map({v: i + origin for i, v in enumerate(sorted(set(li)))}.__getitem__, li)
    return ret


def bisect_left_callable(fn, x, lo, hi):
    """
    :param callable fn:
    :param x:
    :param int lo: 最小値
    :param int hi: 最大値 + 1
    :return: lo <= ret <= hi
    """
    while lo < hi:
        mid = (lo + hi) // 2
        if fn(mid) < x:
            lo = mid + 1
        else:
            hi = mid
    return lo


N = int(sys.stdin.readline())
S = list(map(int, sys.stdin.readline().split()))


def solve(S):
    S = compress(S, origin=1)
    S.sort(reverse=True)

    
    bit = BinaryIndexedTree(size=max(S) + 1)
    for s in S:
        bit.add(s, 1)

    slimes = [S[0]]
    bit.add(S[0], -1)

    for _ in range(N):
        cnt = len(slimes)
        for i in range(cnt):
            
            smallers = bit.sum(slimes[i] - 1)
            if smallers == 0:
                return False
            
            s = bisect_left_callable(bit.sum, smallers, lo=0, hi=slimes[i])
            slimes.append(s)
            bit.add(s, -1)
    return True


if solve(S):
    print('Yes')
else:
    print('No')

Solution (Python):
import bisect
import heapq
import itertools
import math
import operator
import os
import re
import string
import sys
from collections import Counter, deque, defaultdict
from copy import deepcopy
from decimal import Decimal
from fractions import gcd
from functools import lru_cache, reduce
from operator import itemgetter, mul, add, xor

import numpy as np

if os.getenv("LOCAL"):
    sys.stdin = open("_in.txt", "r")

sys.setrecursionlimit(2147483647)
INF = float("inf")
IINF = 10 ** 18
MOD = 10 ** 9 + 7


N = int(sys.stdin.readline())
S = list(map(int, sys.stdin.readline().split()))


def solve():
    counts = Counter(S)
    nums = list(sorted(counts.keys(), reverse=True))
    if counts[nums[0]] > 1:
        return False

    
    trees = [-i for i in range(1, N + 1)]
    heapq.heapify(trees)

    for n in nums[1:]:
        cnt = counts[n]
        if cnt > len(trees):
            return False
        uses = []
        for _ in range(cnt):
            t = -heapq.heappop(trees)
            uses.append(t)
        
        for t in uses:
            for i in range(1, t):
                heapq.heappush(trees, -i)
    return True


if solve():
    print('Yes')
else:
    print('No')

Solution (Python):
import sys

def main():
    N,*S = map(int, open(0).read().split())
    S = sorted(S)

    g = [S.pop(-1)]

    for gen in range(N):
        tmp = []
        for p in g[:2**gen]:
            while S:
                s = S.pop(-1)
                if p > s:
                    g.append(s)
                    break
                else:
                    tmp.append(s)
            else:
                print('No')
                sys.exit()
        S.extend(tmp[::-1])
        g.sort(reverse=True)
    print('Yes')

if __name__=='__main__':
    main()

Solution (Python):
import sys

def main():
    N,*S = map(int, open(0).read().split())
    S = sorted(S)

    g = [S.pop(-1)]

    for _ in range(N):
        tmp = []
        lg = len(g)
        for p in g[:lg]:
            while S:
                s = S.pop(-1)
                if p > s:
                    g.append(s)
                    break
                else:
                    tmp.append(s)
            else:
                print('No')
                sys.exit()
        S.extend(tmp[::-1])
        g.sort(reverse=True)
    print('Yes')

if __name__=='__main__':
    main()

Solution (Python):
def solve_f(n, s_list):
    res = 'Yes'
    stage = 0
    s_list_s = sorted(s_list)
    length = len(s_list_s)
    resolved = [0] * length
    resolved[-1] = 1

    for i in range(n):
        parents = [s_list_s[k] for k in range(length) if resolved[k]]
        for j in range(length - 1, -1, -1):
            if parents[-1] > s_list_s[j] and resolved[j] == 0:
                resolved[j] = 1
                _ = parents.pop()
            if len(parents) == 0:
                break
        if len(parents) > 0:
            res = "No"
            break

    return res


def main():
    n = int(input())
    s_list = list(map(int, input().split()))
    print(solve_f(n, s_list))


if __name__ == "__main__":
    main()

Solution (Python):
N = int(input())
S = list(map(int, input().split()))

S.sort()

parent = [S.pop()]
rest = S
for _ in range(N):
	n_parent = []
	n_rest = []

	for p in parent[::-1]:
		while rest:
			x = rest.pop()
			if x < p:
				n_parent.append(x)
				break
			else:
				n_rest.append(x)
	parent += n_parent
	parent.sort()
	rest = rest + n_rest[::-1]

if len(parent) == (2**N):
	print("Yes")
else:
	print('No')

Solution (Python):
import sys

def main():
    N,*S = map(int, open(0).read().split())
    S = sorted(S)

    g = [S.pop(-1)]

    for _ in range(N):
        c = []
        tmp = []
        for p in g:
            while S:
                s = S.pop(-1)
                if p > s:
                    c.append(s)
                    break
                else:
                    tmp.append(s)
            else:
                print('No')
                sys.exit()
        S.extend(tmp[::-1])
        g.extend(c)
        g.sort(reverse=True)
    print('Yes')

if __name__=='__main__':
    main()

Solution (Python):

N = int(input())
a = list(map(int,input().split(' ')))
a.sort()
    

fathers = [a.pop()]
for _ in range(N):
    sons = list()
    b = list()
    
    for father in fathers:
        while a:
            x = a.pop()
            if father > x:
                sons.append(x)
                break
            else:
                b.append(x)
                
    a = a + b[::-1]
    fathers.extend(sons)
    fathers.sort(reverse = True)
    
    
    
if len(fathers) == 2**N:
    print('Yes')
else:
    print('No')

Solution (Python):

N = int(input())
S = list(map(int,input().split()))
S.sort(reverse=True)
visit = [0]*(2**N)
visit[0] = 1
used = [S[0]]

flag = 0
for i in range(N):
    add = used[::-1]
    k = 0
    for u in used:
        while k < 2**N:
            if visit[k] == 0 and S[k] < u:
                visit[k] = 1
                add.append(S[k])
                break
            k+=1
        if k >= 2**N:
            print("No")
            flag = 1
            break
    if flag == 1:
        break
    
    used = add[::-1]
    used.sort(reverse=True)
    
if flag == 0:
    print("Yes")

Solution (Python):
import sys

def I(): return(int(sys.stdin.readline()))
def LI(): return([int(x) for x in sys.stdin.readline().split()])

def main():
    N = I()
    S = sorted(LI(),reverse=True)

    flag = [True]*len(S)
    cur = []
    cur.append(S[0])
    flag[0] = False

    for i in range(N):
        j = 0
        jM = len(cur)
        for k in range(len(S)):
            if flag[k] and S[k]<cur[j]:
                cur.append(S[k])
                j+=1
                flag[k] = False
                if j==jM:
                  break
        else:
            return("No")
        cur.sort(reverse=True)
    return("Yes")

if __name__ == "__main__":
    print(main())

Solution (Python):
import sys

def I(): return(int(sys.stdin.readline()))
def LI(): return([int(x) for x in sys.stdin.readline().split()])


def main():
    N = I()
    S = sorted(LI(),reverse=True)

    flag = [True]*len(S)

    cur = []
    nxt = []
    cur.append(S[0])
    nxt.append(S[0])
    
    flag[0] = False

    for i in range(N):
        j = 0
        for k in range(len(S)):
            if flag[k] and S[k]<cur[j]:
                nxt.append(S[k])
                j+=1
                flag[k] = False
                if j==len(cur):
                  break
        else:
            return("No")
        nxt.sort(reverse=True)
        cur = [x for x in nxt]
    return("Yes")

if __name__ == "__main__":
    print(main())

Solution (Python):
import sys

def I(): return(int(sys.stdin.readline()))
def LI(): return([int(x) for x in sys.stdin.readline().split()])


def main():
    N = I()
    S = sorted(LI(),reverse=True)

    flag = [True]*len(S)

    cur = []
    nxt = []
    cur.append(S[0])
    nxt.append(S[0])
    
    flag[0] = False

    for i in range(N):
        j = 0
        for k in range(len(S)):
            if j >= len(cur):
                break
            elif flag[k] and S[k]<cur[j]:
                nxt.append(S[k])
                j+=1
                flag[k] = False
        if len(cur) != j:
            return("No")
        nxt.sort(reverse=True)
        cur = [x for x in nxt]
    return("Yes")

if __name__ == "__main__":
    print(main())

Solution (Python):

import sys
def input():
	return sys.stdin.readline().strip()

N = int(input())
S = list(map(int, input().split()))

S.sort(reverse=True)

max_S = S[0]
S2 = [S[0]]
for bit in range(N):
	i = 0
	loc = 0
	S2.sort(reverse=True)
	while i < 2**bit:
		if loc >= 2**N:
			print("No")
			exit()
		if S2[i] > S[loc]:
			S2.append(S[loc])
			S[loc] = max_S 
			i += 1
		loc += 1
print("Yes")

Solution (Python):
N = int(input())
S = sorted([int(a) for a in input().split()])
X = [1] + [0] * N

def popX(i0):
    for i in range(i0, N+1):
        if X[i]:
            X[i] -= 1
            return i
    return N+1
def addX():
    for l in L:
        for i in range(l+1, N+1):
            X[i] += 1

while S:
    a = S.pop()
    L = [popX(0)]
    while S and S[-1] == a:
        S.pop()
        L.append(popX(L[-1]))
    if L[-1] > N:
        print("No")
        break
    addX()
else:
    print("Yes")

Solution (Python):
N = int(input())
S = sorted([int(a) for a in input().split()])
X = [1] + [0] * N

def popX(i0):
    for i in range(i0, N+1):
        if X[i]:
            X[i] -= 1
            return i
    return N+1
def addX():
    for l in L:
        for i in range(l+1, N+1):
            X[i] += 1

while S:
    a = S.pop()
    c = 1
    L = [popX(0)]
    while S and S[-1] == a:
        S.pop()
        c += 1
        L.append(popX(L[-1]))
    if L[-1] > N:
        print("No")
        break
    addX()
else:
    print("Yes")

Solution (Python):
N = int(input())
S = sorted([int(a) for a in input().split()])
X = [1] + [0] * N

def popX(i0):
    for i in range(i0, N+1):
        if X[i]:
            X[i] -= 1
            return i
    return N+1
def addX():
    for l in L:
        for i in range(l+1, N+1):
            X[i] += 1

while S:
    a = S.pop()
    c = 1
    L = [popX(0)]
    while S and S[-1] == a:
        S.pop()
        c += 1
        L.append(popX(L[-1]))
    if L[-1] > N:
        print("No")
        break
    addX()
else:
    print("Yes")

Solution (Python):
import sys

def I(): return(int(sys.stdin.readline()))
def LI(): return([int(x) for x in sys.stdin.readline().split()])


def main():
    N = I()
    S = sorted(LI(),reverse=True)

    flag = [True]*len(S)

    cur = []
    cur.append(S[0])
    flag[0] = False

    for i in range(N):
        nxt = [x for x in cur]
        j = 0

        for k in range(len(S)):
            if j >= len(cur):
                break
            elif flag[k] and S[k]<cur[j]:
                nxt.append(S[k])
                j+=1
                flag[k] = False
        if len(cur) != j:
            return("No")
        cur = sorted(nxt,reverse=True)
    return("Yes")

if __name__ == "__main__":
    print(main())

Solution (Python):
N = int(input())
S = list(map(int, input().split()))
S.sort(reverse = True)
ans = 'Yes'
used = set([0])
L = [S[0]]
for k in range(1, N+1):
    cnt = 0
    for i in range(2**N):
        if i in used:
            continue
        if L[cnt] > S[i]:
            used.add(i)
            cnt += 1
            L.append(S[i])
        if cnt == (2**(k-1)):
            break
    else:
        ans = 'No'
        break
    L.sort(reverse = True)
    continue
print(ans)

Solution (Python):

N = int(input())
a = list(map(int,input().split(' ')))
a.sort()
 
 
fathers = [a.pop()]
for _ in range(N):
    sons = list()
    b = list()

    for father in fathers:
        while a:
            x = a.pop()
            if father > x:
                sons.append(x)
                break
            else:
                b.append(x)
                
    a = a + b[::-1]
    fathers.extend(sons)
    fathers.sort(reverse = True)
    


if len(fathers) == 2**N:
    print('Yes')
else:
    print('No')

Solution (Python):
N=int(input())
S=list(map(int,input().split()))
S.sort()
p=S[-1:]
r=S[:-1]
for i in range(N):
    nr=[]
    for p_ in p[::-1]:
        while r:
            r_=r.pop()
            if r_<p_:
                p.append(r_)
                break
            nr.append(r_)
    p.sort()
    r+=nr[::-1]
print("Yes" if len(r)==0 else "No")

Solution (Python):
N=int(input())
S=list(map(int,input().split()))
S.sort()
p=[S[-1]]
r=S[:-1]

for i in range(N):
    nr = []
    for p_ in p[::-1]:
        while r:
            nr.append(r.pop())
            if nr[-1]<p_:
                p.append(nr.pop(-1))
                break
    p.sort()
    r+=nr[::-1]

print("Yes" if len(r)==0 else "No")

Solution (Python):
N=int(input())
S=list(map(int,input().split()))
S.sort()
p = [S.pop(-1)]
r = S

for i in range(N):
    nr = []
    for p_ in p[::-1]:
        while r:
            r_ = r.pop()
            if r_ < p_:
                p.append(r_)
                break
            nr.append(r_)
    p.sort()
    r+=nr[::-1]

print("Yes" if len(r)==0 else "No")

Solution (Python):
N = int(input())
A = sorted((int(x) for x in input().split()))
 
parent = [A[-1]]
rest = A[:-1]
bl = True
for _ in range(N):
    next_parent = []
    next_rest = []
    for p in parent[::-1]:
        while rest:
            x = rest.pop()
            if x < p:
                next_parent.append(x)
                break
            else:
                next_rest.append(x)
                continue
    parent += next_parent
    parent.sort()
    rest = rest + next_rest[::-1]
 
bl = len(parent) == (2**N)
answer = 'Yes' if bl else 'No'
print(answer)