Problem:
 Score: 100 points    Problem Statement  A triple of numbers is said to be poor when two of those numbers are equal but the other number is different from those two numbers.  You will be given three integers A , B , and C . If this triple is poor, print Yes ; otherwise, print No .      Constraints   A , B , and C are all integers between 1 and 9 (inclusive).         Input  Input is given from Standard Input in the following format:  A  B  C       Output  If the given triple is poor, print Yes ; otherwise, print No .        Sample Input 1 5 7 5      Sample Output 1 Yes  A and C are equal, but B is different from those two numbers, so this triple is poor.       Sample Input 2 4 4 4      Sample Output 2 No  A , B , and C are all equal, so this triple is not poor.       Sample Input 3 4 9 6      Sample Output 3 No       Sample Input 4 3 3 4      Sample Output 4 Yes

Solution (Python):
A, B, C = map(int, input().split())
print("YNeos"[not(A==B!=C or A==C!=B or A!=B==C)::2])

Solution (Python):
import bisect
import cmath
import heapq
import itertools
import math
import operator
import os
import random
import re
import string
import sys
from collections import Counter, deque, defaultdict
from copy import deepcopy
from decimal import Decimal
from fractions import gcd
from functools import lru_cache, reduce
from operator import itemgetter, mul, add, xor

import numpy as np

if os.getenv("LOCAL"):
    sys.stdin = open("_in.txt", "r")

sys.setrecursionlimit(10 ** 9)
INF = float("inf")
IINF = 10 ** 18
MOD = 10 ** 9 + 7





A, B, C = list(map(int, sys.stdin.buffer.readline().split()))
ok = len(set([A, B, C])) == 2
if ok:
    print('Yes')
else:
    print('No')