encode let's think about how all the rest of models can play well in this so far we said we have P of a P of B but actually no need in this entire scheme that we described at the distribution used for P of X one has to be the same decision as we use for it P of X 2 for X 3 and X 4 we can instead use conditionals that are more precise and more predictive of the next symbol and some lower entropy and a more effective encoding scheme and so this arithmetic coding scheme is perfectly compatible in all aggressive models you can just work