is mug one two three and say okay mine is three that's the most likely mode to have generated this X but of course if we know how to encode x given I we still to send I across otherwise the other person cannot decode with that scheme because I don't know of what we're coding relative to so if the semi which will cost us log of one over P of I then we have to send X which will cost as log of one over P of x given I and so the expected third length shown on the right here is well there's an expectation for possible X's we need to send when we