know if i do this for enough rounds you know at the worst case i need n rounds to sort my or log n rounds if i do it smartly but you know in you know the single step here is uh the single step is just o of n so i have now an o of n sorting algorithm i you know i have my sort of a bit of wary to express things like that and um yeah but you know it is from an empirical standpoint i absolutely believe that this uh this is enough now my second quarrel right here is that if you look at the proof first of all what it