diff --git "a/1001.0004.txt" "b/1001.0004.txt" new file mode 100644--- /dev/null +++ "b/1001.0004.txt" @@ -0,0 +1,3227 @@ +arXiv:1001.0004v1 [quant-ph] 31 Dec 2009The Lie Algebraic Significance of +Symmetric Informationally Complete Measurements +D.M. Appleby, Steven T. Flammia and Christopher A. Fuchs +Perimeter Institute for Theoretical Physics +Waterloo, Ontario N2L 2Y5, Canada +December 30, 2009 +Abstract +Examplesofsymmetric informationallycomplete positiveoperatorva lued mea- +sures (SIC-POVMs) have been constructed in every dimension ≤67. However, +it remains an open question whether they exist in all finite dimensions. A SIC- +POVM is usually thought of as a highly symmetric structure in quantum state +space. However, its elements can equally well be regarded as a basis for the Lie +algebra gl(d,C). In this paper we examine the resulting structure constants, +which are calculated from the traces of the triple products of the S IC-POVM +elements and which, it turns out, characterize the SIC-POVM up to unitary +equivalence. We show that the structure constants have numero us remarkable +properties. In particular we show that the existence of a SIC-POV M in di- +mensiondis equivalent to the existence of a certain structure in the adjoint +representation of gl( d,C). We hope that transforming the problem in this way, +from a question about quantum state space to a question about Lie algebras, +may help to make the existence problem tractable. +Contents +1. Introduction 1 +2. The Angle Tensors 7 +3. Spectral Decompositions 14 +4. TheQ-QTProperty 18 +5. Lie Algebraic Formulation of the Existence Problem 21 +6. The Algebra sl( d,C) 31 +7. Further Identities 33 +8. Geometrical Considerations 36 +9. TheP-PTProperty 49 +10. Conclusion 52 +11. Acknowledgements 53 +References 531 +1.Introduction +Symmetric informationally complete positive operator-valued measu res (SIC- +POVMs) present us with what is, simultaneously, one of the most inte resting, and +one of the most difficult and tantalizing problems in quantum informatio n [1–46]. +SIC-POVMs are important practically, with applications to quantum t omography +and cryptography [ 4,8,12,15,20,29], and to classical signal processing [ 24,36]. +However, without in any way wishing to impugn the significance of the a pplications +which have so far been proposed, it appears to us that the interes t of SIC-POVMs +stems less from these particular proposed uses than from rather broader, more gen- +eral considerations: the sense one gets that SICs are telling us so mething deep, +and hitherto unsuspected about the structure of quantum stat e space. In spite of +its being the central object about which the rest of quantum mech anics rotates, +and notwithstanding the efforts of numerous investigators [ 47], the geometry of +quantum state space continues to be surprisingly ill-understood. T he hope which +inspires our efforts is that a solution to the SIC problem will prove to b e the key, +not just to SIC-POVMs narrowly conceived, but to the geometry o f state space in +general. Such things are, by nature, unpredictable. However, it is not unreasonable +to speculate that a better theoretical understanding of the geo metry of quantum +state space might have important practical consequences: not o nly the applica- +tions listed above, but perhaps other applications which have yet to be conceived. +On a more foundational level one may hope that it will lead to a much imp roved +understanding of the conceptual message of quantum mechanics [7,43,45,48]. +Having said why we describe the problem as interesting, let us now exp lain why +we describe it as tantalizing. The trouble is that, although there is an abundance of +reasons for suspecting that SIC-POVMs exist in every finite dimens ion (exact and +high-precision numerical examples [ 1,2,5,11,16,19,28,39,46] having now been +constructed in every dimension up to 67), and in spite of the intense efforts of many +people [1–46] extending over a period of more than ten years, a general existe nce +proof continues to elude us. In their seminal paper on the subject , published in +2004, Renes et al[5] say “A rigorous proof of existence of SIC-POVMs in all finite +dimensions seems tantalizingly close, yet remains somehow distant.” T hey could +have said the same if they were writing today. +The purposeofthis paperis totryto takeourunderstandingofSI C mathematics +(as it might be called) a little further forward. The research we repo rt began with +a chance numerical discovery made while we were working on a differen t problem. +Pursuing that initial numerical hint we uncovered a rich and interest ing set of +connections between SIC-POVMs in dimension dand the Lie Algebra gl( d,C). The +existence of these connections came as a surprise to us. However , in retrospect it +is, perhaps, not so surprising. Interest in SIC-POVMs has, to dat e, focused on the +fact that an arbitrary density matrix can be expanded in terms of a SIC-POVM. +However, a SIC-POVM in dimension ddoes in fact provide a basis, not just for the +space of density matrices, but for the space of all d×dcomplex matrices— i.e.the +Liealgebragl( d,C). Boykin et al[49] haverecentlyshownthatthere isaconnection +betweentheexistenceproblemformaximalsetsofMUBs(mutuallyu nbiasedbases) +and the theory of Lie algebras. Since SIC-POVMs share with MUBs th e property +of being highly symmetrical structures in quantum state space it mig ht have been +anticipated that there are also some interesting connections betw een SIC-POVMs +and Lie algebras.2 +Our main result (proved in Sections 3,4and5) is that the proposition, that a +SIC-POVM exists in dimension d, is equivalent to a proposition about the adjoint +representation of gl( d,C). Our hope is that transforming the problem in this way, +from a question about quantum state space to a question about Lie algebras, may +help to make the SIC-existence problem tractable. But even if this h ope fails to +materialize we feel that this result, along with the many other result s we obtain, +provides some additional insight into these structures. +Inddimensional Hilbert space Hda SIC-POVM is a set of d2operatorsE1, +...,Ed2of the form +Er=1 +dΠr (1) +where the Π rare rank-1 projectors with the property +Tr(ΠrΠs) =/braceleftigg +1r=s +1 +d+1r/ne}ationslash=s(2) +We will refer to the Π ras SIC projectors, and we will say that {Πr:r= 1,...,d2} +is a SIC set. +It follows from this definition that the Ersatisfy +d2/summationdisplay +r=1Er=I (3) +(sotheyconstitute aPOVM),andthattheyarelinearlyindependen t (sothePOVM +is informationally complete). +It is an open question whether SIC-POVMs exist for all values of d. However, +examples have been constructed analytically in dimensions 2–15 inclus ive [1,2,11, +16,19,28,39,46], and in dimensions 19, 24, 35 and 48 [ 16,46]. Moreover, high +precisionnumerical solutionshave been constructed in dimensions 2 –67inclusive [ 5, +46]. Thislendssomeplausibilitytothe speculationthat theyexistinalldime nsions. +For a comprehensive account of the current state of knowledge in this regard, and +many new results, see the recent study by Scott and Grassl [ 46]. +All known SIC-POVMs have a group covariance property. In other words, there +exists +(1) a group Ghavingd2elements +(2) a projective unitary representation of GonHd:i.e.a mapg→UgfromG +to the set of unitaries such that Ug1Ug2∼Ug1g2for allg1,g2(where the +notation “ ∼” means “equals up to a phase”) +(3) a normalized vector |ψ/an}bracketri}ht(the fiducial vector) +such that the SIC-projectors are given by +Πg=Ug|ψ/an}bracketri}ht/an}bracketle{tψ|U† +g (4) +(where we label the projector by the group element g, rather than the integer ras +above). +Most known SIC-POVMs are covariant under the action of the Weyl- Heisenberg +group (though not all—see Renes et al[5] and, for an explicit example of a non +Weyl-Heisenberg SIC-POVM, Grassl [ 19]). Here the group is Zd×Zd, and the +projective representation is p→Dp, wherep= (p1,p2)∈Zd×ZdandDpis the3 +corresponding Weyl-Heisenberg displacement operator +Dp=d−1/summationdisplay +rτ(2r+p1)p2|r+p1/an}bracketri}ht/an}bracketle{tr| (5) +In this expression τ=eiπ(d+1) +d, the vectors |0/an}bracketri}ht,...|d−1/an}bracketri}htare an orthonormal basis, +and the addition in |r+p1/an}bracketri}htis modulod. For more details see, for example, ref. [ 16]. +One should not attach too much weight to the fact that all known SI C-POVMs +have a group covariance property as this may only reflect the fact that group co- +variant SIC-POVMs are much easier to construct. So in this paper w e will try to +prove as much as we can without assuming such a property. One pot ential benefit +ofthis attitude is that, by accumulatingenough facts about SIC-P OVMsin general, +we may eventually get to the point where we can answer the question , whether all +SIC-POVMs actually do have a group covariance property. +The fact that the d2operatorsΠ rare linearly independent means that they form +a basis for the complex Lie algebra gl( d,C) (the set of all operators acting on Hd). +Since the Π rare Hermitian, then iΠrforms a basis also for the real Lie algebra +u(d) (the set of all anti-Hermitian operators acting on Hd). So for any operator +A∈gl(d,C) there is a unique set of expansion coefficients arsuch that +A=d2/summationdisplay +r=1arΠr (6) +To find the expansion coefficients we can use the fact that +d2/summationdisplay +s=1Tr(ΠrΠs)/parenleftbiggd+1 +dδst−1 +d2/parenrightbigg +=δrt (7) +from which it follows +ar=d+1 +dTr(ΠrA)−1 +dTr(A) (8) +Specializing to the case A= ΠrΠswe find +ΠrΠs=d+1 +d +d2/summationdisplay +t=1TrstΠt +−dδrs+1 +d+1I (9) +where +Trst= Tr(Π rΠsΠt) (10) +To a large extent this paper consists in an exploration of the proper ties of these +important quantities, which we will refer to as the triple products. T hey are inti- +mately related to the geometric phase, in which context they are us ually referred +to as 3-vertex Bargmann invariants (see Mukunda et al[50], and references cited +therein). We have, as an immediate consequence of the definition, +Trst=Ttrs=Tstr=T∗ +rts=T∗ +tsr=T∗ +srt (11) +It is convenient to define +Jrst=d+1 +d(Trst−T∗ +rst) (12) +Rrst=d+1 +d(Trst+T∗ +rst) (13)4 +SoJrstis imaginary and completely anti-symmetric; Rrstis real and completely +symmetric. Both these quantities play a significant role in the theory . It follows +from Eq. ( 9) that +[Πr,Πs] =d2/summationdisplay +t=1JrstΠt (14) +So theJrstare structure constants for the Lie algebra gl( d,C). As an immediate +consequence of this they satisfy the Jacobi identity: +d2/summationdisplay +b=1/parenleftbig +JrsbJtba+JstbJrba+JtrbJsba/parenrightbig += 0 (15) +for allr,s,t,a. The Jacobi identity holds for any representation of the structu re +constants. In the following sections we will derive many other identit ies which are +specific to this particular representation. +Turning to the quantities Rrst, it follows from Eq. ( 9) that they feature in the +expression for the anti-commutator +{Πr,Πs}=/summationdisplay +tRrstΠt−2(dδrs+1) +d+1I (16) +They also play an important role in the description of quantum state s pace. Let +ρbe any density matrix and let pr=1 +dTr(Πrρ) be the probability of obtaining +outcomerin the measurement described by the POVM with elements1 +dΠr. Then +it follows from Eq. ( 8) thatρcan be reconstructed from the probabilities by +ρ=d2/summationdisplay +r=1/parenleftbigg +(d+1)pr−1 +d/parenrightbigg +Πr (17) +Suppose, now, that the prareanyset ofd2real numbers. So we do not assume +that theprare even probabilities, let alone the probabilities coming from a density +matrix according to the prescription pr=1 +dTr(Πrρ). Then it is shown in ref. [ 34] +that theprare in fact the probabilities coming from a pure state if and only if they +satisfy the two conditions +d2/summationdisplay +r=1p2 +r=2 +d(d+1)(18) +d2/summationdisplay +r,s,t=1Rrstprpspt=2(d+7) +d(d+1)2(19) +Let us look at the quantities JrstandRrstin a little more detail. For each r +choose a unit vector |ψr/an}bracketri}htsuch that Π r=|ψr/an}bracketri}ht/an}bracketle{tψr|. Then the Gram matrix for these +vectors is of the form +Grs=/an}bracketle{tψr|ψs/an}bracketri}ht=Krseiθrs(20) +where the matrix θrsis anti-symmetric and +Krs=/radicalbigg +dδrs+1 +d+1(21) +Note that the SIC-POVM does not determine the angles θrsuniquely since making +the replacements |ψr/an}bracketri}ht →eiφr|ψr/an}bracketri}htleaves the SIC-POVM unaltered, but changes5 +the angles θrsaccording to the prescription θrs→θrs−φr+φs. This freedom +to rephase the vectors |ψr/an}bracketri}htis not usually important. However, it sometimes has +interesting consequences (see Section 9). It can be thought of as a kind of gauge +freedom. +The Gram matrix satisfies an important identity. Every SIC-POVM ha s the +2-design property [ 5,17] +d2/summationdisplay +r=1Πr⊗Πr=2d +d+1Psym (22) +wherePsymis the projector onto the symmetric subspace of Hd⊗Hd. Expressed +in terms of the Gram matrix this becomes +d2/summationdisplay +r=1Gs1rGs2rGrt1Grt2=d +d+1/parenleftbig +Gs1t1Gs2t2+Gs1t2Gs2t1/parenrightbig +(23) +Turning to the triple products we have +Trst=GrsGstGtr=KrsKstKtreiθrst(24) +where +θrst=θrs+θst+θtr (25) +Note that the tensor θrstis completely anti-symmetric. In particular θrst= 0 if any +two of the indices are the same. Note also that re-phasing the vect ors|ψr/an}bracketri}htleaves +the tensors Trstandθrstunchanged. They are in that sense gauge invariant. +Finally, we have the following expressions for JrstandRrst: +Jrst=2i +d√ +d+1sinθrst (26) +Rrst=2(d+1) +dKrsKstKtrcosθrst (27) +Like the triple products, JrstandRrstare gauge invariant. +For later reference let us note that the matrix Jr, with matrix elements +(Jr)st=Jrst (28) +is the adjoint representative of Π rin the SIC-projector basis: +adΠrΠs= [Πr,Πs] =d2/summationdisplay +t=1JrstΠt (29) +It can be seen that all the interesting features of the tensor Grs(respectively, +the tensors Trst,JrstandRrst) are contained in the order-2 angle tensor θrs(re- +spectively, the order-3 angle tensor θrst). It is also easy to see that, for any unitary +U, the transformation +Πr→UΠrU†(30) +leaves the angle tensors invariant. This suggests that we shift our focus from indi- +vidual SIC-POVMs to families of unitarily equivalent SIC-POVMs—SIC- families, +as we will call them for short. +We begin our investigation in Section 2by giving necessary and sufficient con- +ditions for an arbitrary tensor θrs(respectively θrst) to be the rank-2 (respectively +rank-3) angle tensor corresponding to a SIC-family. We also show t hat either angle +tensor uniquely determines the corresponding SIC-family. Finally we describe a6 +method for reconstructing the SIC-family, starting from a knowle dge of either of +the two angle tensors. +In Sections 3,4and5we prove the central result of this paper: namely, that +the existence of a SIC-POVM in dimension dis equivalent to the existence of a +certain very special set of matrices in the adjoint representation of gl(d,C). In +Section3we show that, for any SIC-POVM, the adjoint matrices Jrhave the +spectral decomposition +Jr=Qr−QT +r (31) +whereQris a rankd−1 projector which has the remarkable property of being +orthogonal to its own transpose: +QrQT +r= 0 (32) +We refer to this feature of the adjoint matrices as the Q-QTproperty. In Section 3 +we also show that from a knowledge of the Jmatrices it is possible to reconstruct +the corresponding SIC-family. In Section 4we characterize the general class of +projectors which have the property of being orthogonal to their own transpose. +Then, in Section 5, we prove a converse of the result established in Section 3. The +Q-QTproperty is not completely equivalent to the property of being a SIC set. +However, it turns out that it is, in a certain sense, very nearly equiv alent. To be +more specific: let Lrbe any set of d2Hermitian operators which constitute a basis +for gl(d,C) and letCrbe the adjoint representative of Lrin this basis. Then the +necessary and sufficient condition for the Crto have the spectral decomposition +Cr=Qr−QT +r (33) +whereQris a rankd−1 projector such that QrQT +r= 0 is that there exists a +SIC set Π rsuch thatLr=ǫr(Πr+αI) for some fixed number α∈Rand signs +ǫr=±1. In particular, the existence of an Hermitian basis for gl( d,C) having the +Q-QTproperty is both necesary and sufficient for the existence of a SIC -POVM in +dimensiond. +In Section 6we digress briefly, and consider sl( d,C) (the Lie algebra consisting +of all trace-zero d×dcomplex matrices). As we have explained, this paper is +motivated by the hope that a Lie algebraic perspective will cast light o n the SIC- +existence problem, rather than by an interest in Lie algebras as suc h. We focus on +gl(d,C) because that is the casewherethe connection with SIC-POVMsse ems most +straightforward. However a SIC-POVM also gives rise to an interes ting geometrical +structure in sl( d,C), as we show in Section 6. +In Section 7we derive a number of additional identities satisfied by the Jand +Qmatrices. +The complex projectors Qr,QT +rand the real projector Qr+QT +rdefine three +families of subspaces. It turns out that there are some interestin g geometrical +relationships between these subspaces, which we study in Section 8. +Finally, in Section 9we show that, with the appropriate choice of gauge, the +Gram matrix corresponding to a Weyl-Heisenberg covariant SIC-fa mily has a fea- +ture analogous to the Q-QTproperty, which we call the P-PTproperty. It is an +open question whether this result generalizes to other SIC-families , not covariant +with respect to the Weyl-Heisenberg group.7 +2.The Angle Tensors +The purpose of this section is to establish the necessary and sufficie nt conditions +for an arbitrary tensor θrs(respectively θrst) to be the order-2 (respectively order- +3) angle tensor for a SIC-family. We will also show that either one of t he angle +tensors is enough to uniquely determine the SIC-family. Moreover, we will describe +explicit procedures for reconstructing the family, starting from a knowledge of one +of the angle tensors. +We begin by considering the general class of POVMs (not just SIC-P OVMs) +which consist of d2rank-1 elements. A POVM of this type is thus defined by a set +ofd2vectors|ξ1/an}bracketri}ht,...,|ξd2/an}bracketri}htwith the property +d2/summationdisplay +r=1|ξr/an}bracketri}ht/an}bracketle{tξr|=I (34) +Note that/summationtextd2 +r=1/vextenddouble/vextenddouble|ξr/an}bracketri}ht/vextenddouble/vextenddouble2=d, so the vectors |ξr/an}bracketri}htcannot all be normalized. In the +particular case of a SIC-POVM the vectors all have the same norm/vextenddouble/vextenddouble|ξr/an}bracketri}ht/vextenddouble/vextenddouble=1√ +d. +However in the general case they may have different norms. +Given a set of such vectors consider the Gram matrix +Prs=/an}bracketle{tξr|ξs/an}bracketri}ht (35) +Clearly the Gram matrix cannot determine the POVM uniquely since if Uis any +unitary operator then the vectors U|ξr/an}bracketri}htwill define another POVM having the same +Gram matrix. However, the theorem we now prove shows that this is the only free- +dom. In other words, the Gram matrix fixes the POVM up to unitary e quivalence. +The theorem also provides us with a criterion for deciding whether an arbitrary +d2×d2matrixPis the Gram matrix corresponding to a POVM of the specified +type. As a corollary this will give us a criterion for deciding whether an arbitrary +tensorθrsis specifically the order-2 angle tensor for a SIC-family. +Theorem 1. LetPbe anyd2×d2Hermitian matrix. Then the following conditions +are equivalent: +(1)Pis a rankdprojector. +(2)Psatisfies the trace identities +Tr(P) = Tr(P2) = Tr(P3) = Tr(P4) =d (36) +(3)Pis the Gram matrix for a set of d2vectors|ξr/an}bracketri}ht(not all normalized) such +that|ξr/an}bracketri}ht/an}bracketle{tξr|is a POVM: +/an}bracketle{tξr|ξs/an}bracketri}ht=Prs (37) +d2/summationdisplay +r=1|ξr/an}bracketri}ht/an}bracketle{tξr|=I (38) +SupposePsatisfies these conditions. To construct a POVM correspondi ng toP +let thedcolumn vectors +ξ11 +ξ12 +... +ξ1d2 +, +ξ21 +ξ22 +... +ξ2d2 +,..., +ξd1 +ξd2 +... +ξdd2 +(39)8 +be any orthonormal basis for the subspace onto which Pprojects. Define +|ξr/an}bracketri}ht=d/summationdisplay +a=1ξ∗ +ar|a/an}bracketri}ht (40) +where the vectors |a/an}bracketri}htare any orthonormal basis for Hd. ThenPis the Gram matrix +for the vectors |ξ1/an}bracketri}ht,...,|ξd2/an}bracketri}ht. Moreover, the necessary and sufficient condition for +any other set of vectors |η1/an}bracketri}ht,...,|ηd2/an}bracketri}htto have Gram matrix Pis that there exist a +unitary operator Usuch that +|ηr/an}bracketri}ht=U|ξr/an}bracketri}ht (41) +for allr. +Proof.We begin by showing that (3) = ⇒(1). Suppose |ξ1/an}bracketri}ht,...|ξd2/an}bracketri}htis any set of +d2vectors such that |ξr/an}bracketri}ht/an}bracketle{tξr|is a POVM. So +d2/summationdisplay +r=1|ξr/an}bracketri}ht/an}bracketle{tξr|=I (42) +Let +Prs=/an}bracketle{tξr|ξs/an}bracketri}ht (43) +be the Gram matrix. Then Pis Hermitian. Moreover, P2=Psince +d2/summationdisplay +t=1PrtPts=/an}bracketle{tξr| +d2/summationdisplay +t=1|ξt/an}bracketri}ht/an}bracketle{tξs| +|ξr/an}bracketri}ht +=/an}bracketle{tξr|ξs/an}bracketri}ht +=Prs (44) +Also +Tr(P) =d2/summationdisplay +r=1/an}bracketle{tξr|ξr/an}bracketri}ht=d (45) +(as can be seen by taking the trace on both sides of Eq. ( 42)). SoPis a rank-d +projector. +We next show that (1) = ⇒(3). LetPbe a rank-dprojector, and let the d +column vectors +ξ11 +ξ12 +... +ξ1d2 +, +ξ21 +ξ22 +... +ξ2d2 +,..., +ξd1 +ξd2 +... +ξdd2 +(46) +be an orthonormal basis for the subspace onto which it projects. So +d2/summationdisplay +r=1ξ∗ +arξbr=δab (47) +for alla,b, and +d2/summationdisplay +a=1ξarξ∗ +as=Prs (48)9 +for allr,s. Now let |ξ1/an}bracketri}ht,...|ξd2/an}bracketri}htbe the vectors defined by Eq. ( 40). Then it follows +from Eq. ( 47) that +d2/summationdisplay +r=1|ξr/an}bracketri}ht/an}bracketle{tξr|=d/summationdisplay +a,b=1 +d2/summationdisplay +r=1ξ∗ +arξbr +|a/an}bracketri}ht/an}bracketle{tb| +=d/summationdisplay +a=1|a/an}bracketri}ht/an}bracketle{ta| +=I (49) +implying that |ξr/an}bracketri}ht/an}bracketle{tξr|is POVM. Also, it follows from Eq. ( 48) that +/an}bracketle{tξr|ξs/an}bracketri}ht=d/summationdisplay +a=1ξarξ∗ +as=Prs (50) +implying that the |ξr/an}bracketri}hthave Gram matrix P. +We next turn to condition (2). The fact that (1) = ⇒(2) is immediate. To +prove the reverse implication observe that condition (2) implies +Tr(P4)−2Tr(P3)+Tr(P2) = 0 (51) +Letλ1,...,λ d2be the eigenvalues of P. Then Eq. ( 51) implies +d2/summationdisplay +r=1λ2 +r(λr−1)2= 0 (52) +It follows that each eigenvalue is either 0 or 1. Since Tr( P) =dwe must have d +eigenvalues = 1 and the rest all = 0. So Pis a rank-dprojector. +It remains to show that the POVM corresponding to a given rank- dprojector +is unique up to unitary equivalence. To prove this let Pbe a rank-dprojector, let +|ξr/an}bracketri}htbe the vectors defined by Eq. ( 40), and let |η1/an}bracketri}ht,...,|ηd2/an}bracketri}htbe any other set of +vectors such that +/an}bracketle{tηr|ηs/an}bracketri}ht=Prs (53) +for allr,s. Define +ηar=/an}bracketle{tηr|a/an}bracketri}ht (54) +Then +d2/summationdisplay +r=1η∗ +arηbr=/an}bracketle{ta| +d2/summationdisplay +r=1|ηr/an}bracketri}ht/an}bracketle{tηr| +|b/an}bracketri}ht=δab (55) +(because |ηr/an}bracketri}ht/an}bracketle{tηr|is a POVM) and +d/summationdisplay +a=1ηarη∗ +as=Prs (56) +(because the |ηr/an}bracketri}hthave Gram matrix P). So thedcolumn vectors + +η11 +η12 +... +η1d2 +, +η21 +η22 +... +η2d2 +,..., +ηd1 +ηd2 +... +ηdd2 +(57)10 +are an orthonormal basis for the subspace onto which Pprojects. But the column +vectors  +ξ11 +ξ12 +... +ξ1d2 +, +ξ21 +ξ22 +... +ξ2d2 +,..., +ξd1 +ξd2 +... +ξdd2 +(58) +are also an orthonormal basis for this subspace. So there must ex ist ad×dunitary +matrixUabsuch that +ηar=d/summationdisplay +b=1Uabξbr (59) +for alla,r. Define +U=d/summationdisplay +a,b=1U∗ +ab|a/an}bracketri}ht/an}bracketle{tb| (60) +Then +|ηr/an}bracketri}ht=U|ξr/an}bracketri}ht (61) +for allr. /square +In the case of a SIC-POVM we have +|ξr/an}bracketri}ht=1√ +d|ψr/an}bracketri}ht (62) +where the vectors |ψr/an}bracketri}htare normalized, and +Prs=1 +dGrs=1 +dKrseiθrs(63) +whereGis the Gram matrix of the vectors |ψr/an}bracketri}htandθrsis the order-2 angle tensor. +In the sequel we will distinguish these matrices by referring to Gas the Gram +matrix and Pas the Gram projector. +We have +Corollary 2. Letθrsbe a real anti-symmetric tensor. Then the following state- +ments are equivalent: +(1)θrsis an order- 2angle tensor corresponding to a SIC-family. +(2)θrssatisfies +d2/summationdisplay +t=1KrtKtsei(θrt+θts)=dKrseiθrs(64) +for allr,s. +(3)θrssatisfies +d2/summationdisplay +r,s,t=1KrsKstKtrei(θrs+θst+θtr)=d4(65) +and +d2/summationdisplay +r,s,t,u=1KrsKstKtuKurei(θrs+θst+θtu+θur)=d5(66)11 +LetΠr,Π′ +rbe two different SIC-sets, and let θrs,θ′ +rsbe corresponding order- 2 +angle tensors. Then there exists a unitary Usuch that +Π′ +r=UΠrU†(67) +for allrif and only if +θ′ +rs=θrs−φr+φs (68) +for some arbitrary set of phase angles φr(in other words two SIC-sets are unitarily +equivalent if and only if their order- 2angle tensors are gauge equivalent). +A SIC-family can be reconstructed from its order- 2angle tensor θrsby calculating +an orthonormal basis for the subspace onto which the Gram pro jector +Prs=1 +dKrseiθrs(69) +projects, as described in Theorem 1. +Remark. The sense in which we areusing the term “gaugeequivalence”is explain ed +in the passage immediately following Eq. ( 21). +Note that condition (2) imposes d2(d2−1)/2 independent constraints (taking +account of the anti-symmetry of θrs). Condition (3), by contrast, only imposes 2 +independent constraints. It is to be observed, however, that th e price we pay for +the reduction in the number of equations is that Eqs. ( 65) and (65) are respectively +cubic and quartic in the phases, whereas Eq. ( 64) is only quadratic. +Proof.Letθrsbe an arbitrary anti-symmetric tensor, and define +Prs=1 +dKrseiθrs(70) +The anti-symmetry of θrsmeans that Pis automatically Hermitian. So it follows +from Theorem 1that a necessary and sufficient condition for Prsto be a rank- d +projector, and for θrsto be the order-2 angle tensor of a SIC-family, is that +d2/summationdisplay +t=1KrtKtsei(θrt+θts)=dKrseiθrs(71) +for allr,s. +To prove the equivalence of conditions (1) and (3) note that the co nditions +Tr(P) = Tr(P2) =dare an automatic consequence of Phaving the specified form. +So it follows from Theorem 1thatθrsis the order-2 angle tensor of a SIC-family if +and only if Eqs. ( 65) and (66) are satisfied. +Now let Πr, Π′ +rbe two SIC-sets and let θrs,θ′ +rsbe order-2 angle tensors corre- +sponding to them. Then there exist normalized vectors |ψr/an}bracketri}ht,|ψ′ +r/an}bracketri}htsuch that +Πr=|ψr/an}bracketri}ht/an}bracketle{tψr| Π′ +r=|ψ′ +r/an}bracketri}ht/an}bracketle{tψ′ +r| (72) +for allr, and +/an}bracketle{tψr|ψs/an}bracketri}ht=Krseiθrs/an}bracketle{tψ′ +r|ψ′ +s/an}bracketri}ht=Krseiθ′ +rs (73) +for allr,s. +Suppose, first of all, that there exists a unitary Usuch that +Π′ +r=UΠrU†(74)12 +Then there exist phase angles φrsuch that +|ψ′ +r/an}bracketri}ht=eiφrU|ψr/an}bracketri}ht (75) +for allr, which is easily seen to imply that +θ′ +rs=θrs−φr+φs (76) +for allr,s. Soθrs,θ′ +rsare gauge equivalent. +Conversely, suppose there exist phase angles φrsuch that +θ′ +rs=θrs−φr+φs (77) +Define +|ψ′′ +r/an}bracketri}ht=e−iφr|ψ′ +r/an}bracketri}ht (78) +Then +/an}bracketle{tψ′′ +r|ψ′′ +s/an}bracketri}ht=Krseiθrs=/an}bracketle{tψr|ψs/an}bracketri}ht (79) +for allr,s. So it follows from Theorem 1that there exists a unitary Usuch that +|ψ′′ +r/an}bracketri}ht=U|ψr/an}bracketri}ht (80) +for allr. Consequently +Π′ +r=|ψ′′ +r/an}bracketri}ht/an}bracketle{tψ′′ +r|=UΠrU†(81) +for allr. So Πrand Π′ +rare unitarily equivalent. /square +We now turn to the order-3 angle tensors. We have +Theorem 3. Letθrstbe a real completely anti-symmetric tensor. Then the follow - +ing conditions are equivalent: +(1)θrstis the order- 3angle tensor for a SIC-family +(2)For some fixed aand allr,s,t +θars+θast+θatr=θrst (82) +and for all r,s +d2/summationdisplay +t=1KrtKtseiθrst=dKrs (83) +(3)For some fixed aand allr,s,t +θars+θast+θatr=θrst (84) +and +d2/summationdisplay +r,s,t=1KrsKstKtreiθrst=d4(85) +d2/summationdisplay +r,s,t,u=1KrsKstKtuKurei(θrst+θtur)=d5(86)13 +LetΠr,Π′ +rbe two different SIC-sets and let θrst,θ′ +rstbe the corresponding order- +3angle tensors. Then the necessary and sufficient condition fo r there to exist a +unitaryUsuch that +Π′ +r=UΠrU†(87) +for allris thatθ′ +rst=θrstfor allr,s,t(in other words two SIC-sets are unitarily +equivalent if and only if their order- 3angle tensors are identical). +Letθrstbe the order- 3angle tensor corresponding to a SIC-family. Then the +order-2angle tensor is given by (up to gauge freedom) +θrs=θars (88) +for any fixed a, from which the SIC-family can be reconstructed using the me thod +described in Theorem 1. +Remark. Unlike the order-2tensor, the order-3angletensoris gaugeinvar iant. This +means that it provides what is, in many ways, a more useful charact erization of +the SIC-family. For that reason we will be almost exclusively concern ed with the +order-3 tensor in the remainder of this paper. +Proof.The fact that (1) = ⇒(2) is an immediate consequence of the definition of +theorder-3angletensorandcondition(2)ofCorollary 2. Toprovethat(2) = ⇒(1) +letθrstbe a completely anti-symmetric tensor such that condition (2) holds . Define +θrs=θars (89) +for allr,s. Then Eq. ( 83) implies +d2/summationdisplay +t=1KrtKtsei(θrt+θts)=eiθrs +d2/summationdisplay +t=1KrtKtseiθrst +∗ +=dKrseiθrs(90) +for allr,s. It follows from Corollary 2thatθrsis the order-2 and θrstthe order-3 +angle tensor of a SIC-family. +The equivalence of conditions (1) and (3) is proved similarly. +It remains to show that two SIC-sets are unitarily equivalent if and o nly if +their order-3 angle tensors are identical. To see this let Πr=|ψr/an}bracketri}ht/an}bracketle{tψr|and Π′ +r= +|ψ′ +r/an}bracketri}ht/an}bracketle{tψ′ +r|be two different SIC-sets having the same order-3 angle tensor θrst. Let +θrs(respectively θ′ +rs) be the order-2 angle tensor corresponding to the vectors |ψr/an}bracketri}ht +(respectively |ψ′ +r/an}bracketri}ht). Choose some fixed index a. We have +θ′ +ar+θ′ +sa+θ′ +rs=θar+θsa+θrs (91) +for allr,s. Consequently +θ′ +rs=θrs+φr−φs (92) +for allr,s, where +φr=θar−θ′ +ar (93) +Soθ′ +rsandθrsare gauge equivalent. It follows from Corollary 2that Πrand Π′ +rare +unitarily equivalent. Conversely, suppose that Πrand Π′ +rare unitarily equivalent, +and letθrs,θ′ +rsbe order-2 angle tensors corresponding to them. It follows from +Corollary 2thatθrsandθ′ +rsare gauge equivalent. It is then immediate that the +order-3 angle tensors are identical. /square14 +Finally, let us note that when expressed in terms of the triple produc ts Eq. (83) +reads +d2/summationdisplay +t=1Trst=dK2 +rs (94) +while Eq. ( 85) reads +d2/summationdisplay +r,s,t=1Trst=d4(95) +For Eq. ( 86) we have to work a little harder. We have +d2/summationdisplay +r,s,t,u=11 +K2 +rtTrstTtur=d5(96) +from which it follows +d5=d2/summationdisplay +r,s,t,u=1/parenleftbig +−dδrt+d+1/parenrightbig +TrstTtur += (d+1)d2/summationdisplay +r,s,t,u=1TrstTtur−dd2/summationdisplay +r,s,u=1K2 +rsK2 +ru += (d+1)d2/summationdisplay +r,s,t,u=1TrstTtur−d5(97) +Consequently +d2/summationdisplay +s,u=1Tr/parenleftbig +TsTu/parenrightbig +=d2/summationdisplay +r,s,t,u=1TrstTtur=2d5 +d+1(98) +This equation be alternatively written +d2/summationdisplay +r,s=1Tr/parenleftbig +TrTs/parenrightbig +=2d5 +d+1(99) +whereTris the matrix with matrix elements ( Tr)uv=Truv. +When they are written like this, in terms of the triple products, the f act that +Eq. (94) implies Eqs. ( 95) and (98) becomes almost obvious. The reverse implica- +tion, by contrast, is rather less obvious. +3.Spectral Decompositions +LetTr,Jr,Rrbe thed2×d2matrices whose matrix elements are +(Tr)st=Trst (Jr)st=Jrst (Rr)st=Rrst(100) +whereJrst,RrstarethequantitiesdefinedbyEqs.( 12)and(13). SoJristheadjoint +representation matrix of Π r. In this section we derive the spectral decompositions +of these matrices. To avoid confusion we will use the notation |ψ/an}bracketri}htto denote a ket in +ddimensional Hilbert space Hd, and/bardblψ/an}bracketri}ht/an}bracketri}htto denote a ket in d2dimensional Hilbert15 +spaceHd2. In terms of this notation the spectral decompositions will turn ou t to +be: +Tr=d +d+1Qr+2d +d+1/bardbler/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{ter/bardbl (101) +Jr=Qr−QT +r (102) +Rr=Qr+QT +r+4/bardbler/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{ter/bardbl (103) +In these expressions the vector /bardbler/an}bracketri}ht/an}bracketri}htis normalized, and its components in the stan- +dard basis are all real. Qris a rankd−1 projector such that +Qr/bardbler/an}bracketri}ht/an}bracketri}ht=QT +r/bardbler/an}bracketri}ht/an}bracketri}ht= 0 (104) +and which has, in addition, the remarkable property of being orthog onal to its own +transpose (also a rank d−1 projector): +QrQT +r= 0 (105) +Explicit expressions for /bardbler/an}bracketri}ht/an}bracketri}htandQrwill be given below. +It will be convenient to define the rank 2( d−1) projector +¯Rr=Qr+QT +r (106) +We have +¯Rr=J2 +r (107) +and +Rr=¯Rr+4/bardbler/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{ter/bardbl (108) +SinceQris Hermitian we have +QT +r=Q∗ +r (109) +whereQ∗ +ris the matrix whose elements are the complex conjugates of the cor re- +sponding elements of Qr. So¯Rris twice the real part of Qrand−iJris twice the +imaginary part. +In Section 5we will show that Eq. ( 102) is essentially definitive of a SIC-POVM. +To be more specific, let Lrbe any set of d2Hermitian matrices which constitute a +basis for gl( d,C), and letCrbe the adjoint representative of Lrin that basis. Then +we will show that Crhas the spectral decomposition +Cr=Qr−QT +r (110) +whereQris a rankd−1 projector which is orthogonal to its own transpose if and +only if the Lrare a family of SIC projectors up to multiplication by a sign and +shifting by a multiple of the identity. +Having stated our results let us now turn to the task of proving the m. We begin +byderivingthespectraldecompositionof Tr. Multiplyingboth sidesoftheequation +ΠrΠs=d+1 +dd2/summationdisplay +t=1TrstΠt−K2 +rsI (111) +by Πrwe find +ΠrΠs=d+1 +dd2/summationdisplay +t=1TrstΠrΠt−K2 +rsΠr16 +=(d+1)2 +d2d2/summationdisplay +t=1(Tr)2 +stΠt−d+1 +dd2/summationdisplay +t=1TrstK2 +rtI−K2 +rsΠr(112) +We have +d2/summationdisplay +t=1TrstK2 +rt=1 +d+1d2/summationdisplay +t=1Trst(dδrt+1) +=1 +d+1 +dTrsr+d2/summationdisplay +t=1Trst + +=2d +d+1Tsrr +=2d +d+1K2 +rs (113) +Consequently +ΠrΠs=d+1 +dd2/summationdisplay +t=1/parenleftbiggd+1 +d(Tr)2 +st−K2 +rsK2 +rt/parenrightbigg +Πt−K2 +rsI (114) +Comparing with Eq. ( 111) we deduce +(Tr)2 +rs=d +d+1Trst+d +d+1K2 +rsK2 +rt (115) +Now define +/bardbler/an}bracketri}ht/an}bracketri}ht=/radicalbigg +d+1 +2dd2/summationdisplay +s=1K2 +rs/bardbls/an}bracketri}ht/an}bracketri}ht (116) +where the basis kets /bardbls/an}bracketri}ht/an}bracketri}htare given by (in column vector form) +/bardbl1/an}bracketri}ht/an}bracketri}ht= +1 +0 +... +0 +,/bardbl2/an}bracketri}ht/an}bracketri}ht= +0 +1 +... +0 +,...,/bardbld2/an}bracketri}ht/an}bracketri}ht= +0 +0 +... +1 +(117) +It is easily verified that /bardbler/an}bracketri}ht/an}bracketri}htis normalized. Eq. ( 115) then becomes +T2 +r=d +d+1Tr+2d2 +(d+1)2/bardbler/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{ter/bardbl (118) +Using Eq. ( 113) we find +/an}bracketle{t/an}bracketle{ts/bardblTr/bardbler/an}bracketri}ht/an}bracketri}ht=/radicalbigg +d+1 +2dd2/summationdisplay +t=1TrstK2 +rt +=/radicalbigg +2d +d+1K2 +rs +=2d +d+1/an}bracketle{t/an}bracketle{ts/bardbler/an}bracketri}ht/an}bracketri}ht (119) +So/bardbler/an}bracketri}ht/an}bracketri}htis an eigenvector of Trwith eigenvalue2d +d+1.17 +Also define +Qr=d+1 +dTr−2/bardbler/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{ter/bardbl (120) +So in terms of the order-3 angle tensor the matrix elements of Qrare +Qrst=d+1 +dKrsKrt/parenleftbig +Ksteiθrst−KrsKrt/parenrightbig +(121) +Qris Hermitian (because Tris Hermitian). Moreover +Q2 +r=(d+1)2 +d2T2 +r−4/bardbler/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{ter/bardbl=Qr (122) +SoQris a projection operator. Since +Tr(Tr) =/summationdisplay +uTruu=d2/summationdisplay +u=1K2 +ru=d (123) +we have +Tr(Qr) =d−1 (124) +We have thus proved that the spectral decomposition of Tris +Tr=d +d+1Qr+2d +d+1/bardbler/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{ter/bardbl (125) +whereQris a rankd−1 projector, as claimed. +We next prove that QT +r/bardbler/an}bracketri}ht/an}bracketri}ht= 0. The fact that the components of /bardbler/an}bracketri}ht/an}bracketri}htin the +standard basis are all real means +/an}bracketle{t/an}bracketle{ts/bardblTT +r/bardbler/an}bracketri}ht/an}bracketri}ht=/an}bracketle{t/an}bracketle{ter/bardblTr/bardbls/an}bracketri}ht/an}bracketri}ht=2d +d+1/an}bracketle{t/an}bracketle{ts/bardbler/an}bracketri}ht/an}bracketri}ht (126) +So/bardbler/an}bracketri}ht/an}bracketri}htis an eigenvector of TT +ras well asTr, again with the eigenvalue2d +d+1. In +view of Eq. ( 120) it follows that QT +r/bardbler/an}bracketri}ht/an}bracketri}ht= 0. +Turning to the problem of showing that Qris orthogonal to its own transpose. +We have +QrQT +r=/parenleftbiggd+1 +dTr−2/bardbler/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{ter/bardbl/parenrightbigg/parenleftbiggd+1 +dTT +r−2/bardbler/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{ter/bardbl/parenrightbigg +=(d+1)2 +d2TrTT +r−4/bardbler/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{ter/bardbl (127) +It follows from Eq. ( 24) that +/an}bracketle{t/an}bracketle{ts/bardblTrTT +r/bardblt/an}bracketri}ht/an}bracketri}ht=d2/summationdisplay +u=1TrsuTrtu +=GrsGrtd2/summationdisplay +u=1GsuGtuGurGur (128) +In view of Eq. ( 23) (i.e.the fact that every SIC-POVM is a 2-design) this implies +/an}bracketle{t/an}bracketle{ts/bardblTrTT +r/bardblt/an}bracketri}ht/an}bracketri}ht=2d +d+1|Grs|2|Grt|2 +=2d +d+1K2 +rsK2 +rt18 +=4d2 +(d+1)2/an}bracketle{t/an}bracketle{ts/bardbler/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{ter/bardblt/an}bracketri}ht/an}bracketri}ht (129) +So +TrTT +r=4d2 +(d+1)2/bardbler/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{ter/bardbl (130) +and consequently +QrQT +r= 0 (131) +Eqs. (102) and (103) are immediate consequences of the results already proved +and the definitions of Jr,Rr. +We definedthe Jmatricestobe theadjointrepresentativesofthe SIC-projecto rs, +considered as a basis for the Lie algebra gl( d,C), and that is certainly a most +important fact about them. However, the results of this section s how that, along +with the vectors /bardbler/an}bracketri}ht/an}bracketri}ht, they actually determine the whole structure. Specifically, +we have +Qr=1 +2/parenleftbig +Jr+J2 +r/parenrightbig +(132) +Rr=J2 +r+4/bardbler/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{ter/bardbl (133) +Tr=d +2(d+1)/parenleftig +Jr+J2 +r+4/bardbler/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{ter/bardbl/parenrightig +(134) +Moreover, if we know the Tmatrices then we know the order-3 angle tensor, which +in view of Theorem 3means we can reconstruct the SIC-projectors. Since the +vectors/bardbler/an}bracketri}ht/an}bracketri}htare given, once and for all, this means that the problem of proving th e +existenceofa SIC-POVMin dimension dis equivalent to the problem ofprovingthe +existence of a certain remarkable structure in the adjoint repres entation of gl( d,C) +(as we will see in more detail in Section 5). +In the Introduction webegan with the concept ofa SIC-POVM,and then defined +theJmatrices in terms of it. However, one could, if one wished, go in the op posite +direction, and take the Lie algebraic structure to be primary, with t he SIC-POVM +being the secondary, derivative entity. +4.TheQ-QTProperty +The next five sections are devoted to a study of the Jmatrices which, as we will +see, have numerous interesting properties. We begin our investiga tion by trying to +get some additional insight into what we will call the Q-QTproperty: namely, the +fact that the Jmatrices have the spectral decomposition +Jr=Qr−QT +r (135) +whereQrisarankd−1projectorwhichisorthogonaltoits owntranspose. We wish +to characterize the general class of matrices which are of this typ e. The following +theorem provides one such characterization. +Theorem 4. LetAbe a Hermitian matrix. Then the following statements are +equivalent:19 +(1)Ahas the spectral decomposition +A=P−PT(136) +wherePis a projector which is orthogonal to its own transpose. +(2)Ais pure imaginary and A2is a projector. +Proof.To show that (1) = ⇒(2) observe that the fact that Pis Hermitian means +PT=P∗(137) +whereP∗is the matrix whose elements are the complex conjugates of the cor re- +sponding elements of P. So Eq. ( 136) implies that the components of Aare pure +imaginary. Since PPT= 0 it also implies that A2is a projector. +To show that (2) = ⇒(1) observe that the fact that A2is a projector means +that the eigenvalues of A=±1 or 0. So +A=P−P′(138) +whereP,P′are orthogonal projectors. Since Ais pure imaginary we must have +PT−(P′)T=AT=A∗=−A=P′−P (139) +PTand (P′)Tare also orthogonal projectors. So if PT|ψ/an}bracketri}ht=|ψ/an}bracketri}ht, and|ψ/an}bracketri}htis nor- +malized, we must have +1 =/an}bracketle{tψ|PT|ψ/an}bracketri}ht +=/angbracketleftbig +ψ/vextendsingle/vextendsingle/parenleftbig +PT−(P′)T/parenrightbig/vextendsingle/vextendsingleψ/angbracketrightbig +=/an}bracketle{tψ|P′|ψ/an}bracketri}ht−/an}bracketle{tψ|P|ψ/an}bracketri}ht (140) +Since +0≤ /an}bracketle{tψ|P′|ψ/an}bracketri}ht ≤1 (141) +0≤ /an}bracketle{tψ|P|ψ/an}bracketri}ht ≤1 (142) +we must have /an}bracketle{tψ|P′|ψ/an}bracketri}ht= 1, implying P′|ψ/an}bracketri}ht=|ψ/an}bracketri}ht. Similarly P′|ψ/an}bracketri}ht=|ψ/an}bracketri}htimplies +PT|ψ/an}bracketri}ht=|ψ/an}bracketri}ht. So +P′=PT(143) +/square +We also have the following statement, inspired in part by Ref. [ 51], +Theorem 5. The necessary and sufficient condition for a matrix Pto be a projector +which is orthogonal to its own transpose is that +P=SDST(144) +whereSis an any real orthogonal matrix and Dhas the block-diagonal form +D= +σ ... 0 0...0 +............ +0... σ 0...0 +0...0 0...0 +............ +0...0 0...0 +(145)20 +with +σ=1 +2/parenleftbigg +1−i +i1/parenrightbigg +(146) +In other words Dhasncopies ofσon the diagonal, where n= rank(P), and0 +everywhere else. +Proof.Sufficiency is an immediate consequence of the fact that σis a rank 1 pro- +jector such that σσT= 0. +To prove necessity let dbe the dimension of the space and nthe rank of P. It +will be convenient to define +|1/an}bracketri}ht= +1 +0 +... +0 +,|2/an}bracketri}ht= +0 +1 +... +0 +, ... |d/an}bracketri}ht= +0 +0 +... +1 +(147) +In terms of these basis vectors we have +P=d/summationdisplay +r,s=1Prs|r/an}bracketri}ht/an}bracketle{ts| (148) +Now let |a1/an}bracketri}ht,...,|an/an}bracketri}htbe an orthonormal basis for the subspace onto which P +projects, and let |a∗ +r/an}bracketri}htbe the column vector which is obtained from |ar/an}bracketri}htby tak- +ing the complex conjugate of each of its components. Taking comple x conjugates +on each side of the equation +P|ar/an}bracketri}ht=|ar/an}bracketri}ht (149) +gives +P∗|a∗ +r/an}bracketri}ht=|a∗ +r/an}bracketri}ht (150) +So|a∗ +1/an}bracketri}ht,...,|a∗ +n/an}bracketri}htis an orthonormal basis for the subspace onto which PT=P∗ +projects. Since PTis orthogonal to Pwe conclude that +/an}bracketle{tar|a∗ +s/an}bracketri}ht= 0 (151) +for allr,s. +Next define vectors |b1/an}bracketri}ht,...,|b2n/an}bracketri}htby +|b2r−1/an}bracketri}ht=1√ +2/parenleftbig +|a∗ +r/an}bracketri}ht−|ar/an}bracketri}ht/parenrightbig +(152) +|b2r/an}bracketri}ht=i√ +2/parenleftbig +|a∗ +r/an}bracketri}ht+|ar/an}bracketri}ht/parenrightbig +(153) +By construction these vectors are orthonormal and real. So we c an extend them +to an orthonormal basis for the full space by adding a further d−2nvectors +|b2n+1/an}bracketri}ht,...,|bd/an}bracketri}ht, which can also be chosen to be real. We have +P=n/summationdisplay +r=1|ar/an}bracketri}ht/an}bracketle{tar| +=1 +2n/summationdisplay +r=1/parenleftig +|b2r−1/an}bracketri}ht/an}bracketle{tb2r−1|−i|b2r−1/an}bracketri}ht/an}bracketle{tb2r|+i|b2r/an}bracketri}ht/an}bracketle{tb2r−1|+|b2r/an}bracketri}ht/an}bracketle{tb2r|/parenrightig +(154)21 +So if we define +S=d/summationdisplay +r=1|br/an}bracketri}ht/an}bracketle{tr| (155) +thenSis a real orthogonal matrix such that +P=SDST(156) +where +D=1 +2n/summationdisplay +r=1/parenleftig +|2r−1/an}bracketri}ht/an}bracketle{t2r−1|−i|2r−1/an}bracketri}ht/an}bracketle{t2r|+i|2r/an}bracketri}ht/an}bracketle{t2r−1|+|2r/an}bracketri}ht/an}bracketle{t2r|/parenrightig +(157) +is the matrix defined by Eq. ( 145). /square +This result implies the following alternative characterization of the cla ss of ma- +trices to which the Jmatrices belong +Corollary 6. LetAbe a Hermitian matrix. Then the following statements are +equivalent: +(1)Ahas the spectral decomposition +A=P−PT(158) +wherePis a projector which is orthogonal to its own transpose. +(2)There exists a real orthogonal matrix Ssuch that +A=SDST(159) +whereDhas the block diagonal form +D= +σy...0 0...0 +............ +0... σ y0...0 +0...0 0...0 +............ +0...0 0...0 +(160) +σybeing the Pauli matrix +σy=/parenleftbigg0−i +i0/parenrightbigg +(161) +In other words Dhasncopies ofσyon the diagonal, where n=1 +2rank(A), +and0everywhere else (note that a matrix of this type must have eve n rank). +Proof.Immediate consequence of Theorem 5. /square +5.Lie Algebraic Formulation of the Existence Problem +This section is the core of the paper. We show that the problem of pr oving the +existence of a SIC-POVM in dimension dis equivalent to the problem of proving +the existence of an Hermitian basis for gl( d,C) all of whose elements have the Q-QT +property. We hope that this new way of thinking will help make the SIC -existence +problem more amenable to solution. +The result we prove is the following:22 +Theorem 7. LetLrbe a set ofd2Hermitian matrices forming a basis for gl(d,C). +LetCrstbe the structure constants relative to this basis, so that +[Lr,Ls] =d2/summationdisplay +t=1CrstLt (162) +and letCrbe the matrix with matrix elements (Cr)st=Crst. Then the following +statements are equivalent +(1)EachCrhas the spectral decomposition +Cr=Pr−PT +r (163) +wherePris a rankd−1projector which is orthogonal to its own transpose. +(2)There exists a SIC-set Πr, a set of signs ǫr=±1and a real constant +α/ne}ationslash=−1 +dsuch that +Lr=ǫr(Πr+αI) (164) +Remark. The restriction to values of α/ne}ationslash=−1 +dis needed to ensure that the matrices +Lrare linearly independent, and therefore constitute a basis for gl( d,C) (otherwise +they would all have trace = 0). The Q-QTproperty continues to hold even if α +does =−1 +d. +It will be seen that it is not only SIC-sets which have the Q-QTproperty, but +also any set of operators obtained from a SIC-set by shifting by a c onstant and +multiplying by an r-dependent sign. Sothe Q-QTpropertyis not strictly equivalent +to the property of being a SIC-set. However, it could be said that t he properties +are almost equivalent. In particular, the existence of an Hermitian b asis for gl(d,C) +having the Q-QTproperty implies the existence of a SIC-POVM in dimension d, +and conversely. +Proof that (2) =⇒(1).Taking the trace on both sides of +[Πr,Πs] =d2/summationdisplay +t=1JrstΠt (165) +we deduce that +d2/summationdisplay +t=1Jrst= 0 (166) +Then from the definition of Lrin terms of Π rwe find +Crst=ǫrǫsǫtJrst (167) +Consequently +Cr=Pr−PT +r (168) +where +Pr=ǫrSQrS (169) +Sbeing the symmetric orthogonal matrix +S= +ǫ10...0 +0ǫ2...0 +......... +0 0... ǫ d2 +(170) +The claim is now immediate.23 +Proof that (1) =⇒(2).Forthis we need to workharder. Since the proofis rather +lengthy we will break it into a number of lemmas. We first collect a few ele mentary +facts which will be needed in the sequel: +Lemma 8. LetLrbe any Hermitian basis for gl(d,C), and letCrstandCrbe +the structure constants and adjoint representatives as defi ned in the statement of +Theorem 7. Letlr= Tr(Lr). Then +(1)Thelrare not all zero. +(2)TheCrstare pure imaginary and antisymmetric in the first pair of indi ces. +(3)TheCrstare completely antisymmetric if and only if the Crare Hermitian. +(4)In every case +d2/summationdisplay +t=1Crstlt= 0 (171) +for allr,s. +(5)In the special case that the Crare Hermitian +d2/summationdisplay +r=1lrLr=κI (172) +where +κ=1 +d +d2/summationdisplay +r=1l2 +r +>0 (173) +Proof.To prove (1) observe that if the lrwere all zero it would mean that the +identity was not in the span of the Lr—contrary to the assumption that they form +a basis. +To prove(2) observethat taking Hermitian conjugates on both sid es of Eq. ( 162) +gives +−[Lr,Ls] =d2/summationdisplay +t=1C∗ +rstLt (174) +from which it follows that C∗ +rst=−Crst. The fact that Csrt=−Crstis an imme- +diate consequence of the definition. +(3) is now immediate. +(4) is proved in the same way as Eq. ( 166). +To prove (5) observe that if the Crare Hermitian it follows from (2) and (3) that +d2/summationdisplay +r=1lrCrst= 0 (175) +for alls,t. Consequently the matrix +d2/summationdisplay +r=1lrLr (176)24 +commutes with everything. But the only matrices for which that is tr ue are multi- +ples of the identity. It follows that +d2/summationdisplay +r=1lrLr=κI (177) +for some real κ. Taking the trace on both sides of this equation we deduce +d2/summationdisplay +r=1l2 +r=dκ (178) +The fact that κ>0 is a consequence of this and statement (1). /square +We next observe that if the Crhave theQ-QTproperty they must, in particular, +be Hermitian. It turns out that that is, by itself, already a very str ong constraint. +Before stating the result it may be helpful if we explain the essential idea on +which it depends. Although we have not done so before, and will not d o so again, it +will be convenient to make use of the covariant/contravariantinde x notation which +is often used to describe the structure constants. Define the me tric tensor +Mrs= Tr(LrLs) (179) +and letMrsbe its inverse. So +d2/summationdisplay +t=1MrtMts=Mr +s=/braceleftigg +1r=s +0r/ne}ationslash=s(180) +We can use these tensors to raise and lower indices (we use the Hilber t-Schmidt +inner product for this purpose because the fact that gl( d,C) is not semi-simple +means that its Killing form is degenerate [ 52–55]). In particular, the matrices +Lr=d2/summationdisplay +t=1MrsLs (181) +are the basis dual to the Lr: +Tr(LrLs) =Mr +s (182) +Suppose we now define structure constants ˜Crstby +[Lr,Ls] =d2/summationdisplay +t=1˜CrstLt(183) +(so in terms of the Crstwe have ˜Ct +rs=Crst). It follows from the relation +˜Crst= Tr/parenleftbig +[Lr,Ls]Lt/parenrightbig += Tr/parenleftbig +Lr[Ls,Lt]/parenrightbig +(184) +that the ˜Crstare completely antisymmetric for any choice of the Lr. If we now +require that the matrices Crbe Hermitian it means that, not only the ˜Crst, but +also theCrstmust be completely antisymmetric. Since the two quantities are +related by +˜Crst=d2/summationdisplay +u=1CrsuMut (185)25 +this is a very strong requirement. It means that the Lrmust, in a certain sense, +be close to orthonormal (relative to the Hilbert-Schmidt inner prod uct). More +precisely, it means we have the following lemma: +Lemma 9. LetLr,CrstandCrbe defined as in the statement of Theorem 7, and +letlr= Tr(Lr). Then the Crare Hermitian if and only if +Tr(LrLs) =βδrs+γlrls (186) +whereβ,γare real constants such that β >0andγ <1 +d. +If this condition is satisfied we also have +d2/summationdisplay +r=1lrLr=β +1−dγI (187) +d2/summationdisplay +r=1l2 +r=dβ +1−dγ(188) +Proof.To prove sufficiency observe that, in view of Eq. ( 185), the condition means +˜Crst=βCrst+γltd2/summationdisplay +u=1Crsulu (189) +In view of Lemma 8, and the fact that β/ne}ationslash= 0, this implies +Crst=1 +β˜Crst (190) +Since the ˜Crstare completely antisymmetric we conclude that the Crstmust be +also. It follows that the Crare Hermitian. +To prove necessity let ˜Cr(respectively M) be the matrix whose matrix elements +are˜Crst(respectively Mst). Then Eq. ( 185) can be written +˜Cr=CrM (191) +Taking the transpose (or, equivalently, the Hermitian conjugate) on both sides of +this equation we find +˜Cr=MCr (192) +implying +[M,Cr] = 0 (193) +for allr. Since the Lrare a basis for gl( d,C) we deduce +[M,adA] = 0 (194) +for allA∈gl(d,C). Eq. (186) is a straightforward consequence of this, the fact +that gl(d,C) has the direct sum decomposition CI⊕sl(d,C), the fact that sl( d,C) +is simple, and Schur’s lemma [ 52–55]. However, for the benefit of the reader who is +not so familiar with the theory of Lie algebras we will give the argument in a little +more detail.26 +Given arbitrary A=/summationtextd2 +r=1arLr, let/bardblA/an}bracketri}ht/an}bracketri}htdenote the column vector +/bardblA/an}bracketri}ht/an}bracketri}ht= +a1 +a2 +... +ad2 +(195) +So +/bardblLr/an}bracketri}ht/an}bracketri}ht= +1 +0 +... +0 +/bardblL2/an}bracketri}ht/an}bracketri}ht= +0 +1 +... +0 +/bardblLd2/an}bracketri}ht/an}bracketri}ht= +0 +0 +... +1 +(196) +In view of Lemma 8we then have +/bardblI/an}bracketri}ht/an}bracketri}ht=1 +κd2/summationdisplay +r=1lr/bardblLr/an}bracketri}ht/an}bracketri}ht (197) +Since +Tr(A) =d2/summationdisplay +r=1arlr=κ/an}bracketle{t/an}bracketle{tI/bardblA/an}bracketri}ht/an}bracketri}ht (198) +we have that A∈sl(d,C) if and only if /an}bracketle{t/an}bracketle{tI/bardblA/an}bracketri}ht/an}bracketri}ht= 0. +Now observe that it follows from Lemma 8and the definition of Mthat +M/bardblI/an}bracketri}ht/an}bracketri}ht=κ/bardblI/an}bracketri}ht/an}bracketri}ht (199) +IfMis a multiple of the identity we have Mrs=κδrsand the lemma is proved. +OtherwiseMhas at least one more eigenvalue, βsay. Let Ebe the corresponding +eigenspace. Since Eis orthogonal to /bardblI/an}bracketri}ht/an}bracketri}htit follows from Eq. ( 198) thatE⊆sl(d,C). +SinceMcommutes with every adjoint representation matrix we have +adAE⊆E (200) +for allA∈sl(d,C). SoEis an ideal of sl( d,C). However sl( d,C) is a simple Lie +algebra, meaning it has no proper ideals [ 52–55]. So we must have E= sl(d,C). It +follows that if we define +˜Lr=Lr−lr +dI (201) +then +M/bardblLr/an}bracketri}ht/an}bracketri}ht=lr +dM/bardblI/an}bracketri}ht/an}bracketri}ht+M/bardbl˜Lr/an}bracketri}ht/an}bracketri}ht (202) +=κlr +d/bardblI/an}bracketri}ht/an}bracketri}ht+β/bardbl˜Lr/an}bracketri}ht/an}bracketri}ht (203) +=d2/summationdisplay +s=1(βδrs+γlrls)/bardblLs/an}bracketri}ht/an}bracketri}ht (204) +whereγ=1 +d/parenleftig +1−β +κ/parenrightig +. Eqs. (186), (187) and (188) are now immediate (in view of +Lemma8).27 +It remains to establish the bounds on β,γ. LetA=/summationtextd2 +r=1arLrbe any non-zero +element of sl( d,C). Then/summationtextd2 +r=1arlr= 0, so in view of Eq. ( 186) we have +00. Also, using Lemma 8once more, we find +lr=1 +κd2/summationdisplay +s=1lsTr(LrLs) +=βlr +κ+γlr +κd2/summationdisplay +s=1l2 +s +=lr/parenleftbiggβ +κ+dγ/parenrightbigg +(206) +Since thelrcannot all be zero this implies +β +κ= 1−dγ (207) +Sinceβ +κ>0 we deduce that γ <1 +d. /square +Eq. (186) only depends on the Crbeing Hermitian. If we make the assumption +that theCrhave theQ-QTproperty we get a stronger statement: +Corollary 10. LetLr,CrstandCrbe as defined in the statement of Theorem 7. +Suppose that the Crhave the spectral decomposition +Cr=Pr−PT +r (208) +wherePris a rankd−1projector which is orthogonal to its own transpose. Then +(1)For allr +Tr(Lr) =ǫ′ +rl (209) +(2)For allr,s +Tr(LrLs) =d +d+1δrs+ǫ′ +rǫ′ +s +d/parenleftbigg +l2−1 +d+1/parenrightbigg +(210) +(3) +d2/summationdisplay +r=1ǫ′ +rLr=dlI (211) +for some real constant l>0and signsǫ′ +r=±1. +Proof.The proof relies on the fact that the Killing form for gl( d,C) is related to +the Hilbert-Schmidt inner product by [ 55] +Tr(adAadB) = 2dTr(AB)−2Tr(A)Tr(B) (212) +Specializing to the case A=B=Lrand making use of the Q-QTproperty we find +d−1 =dTr(L2 +r)−l2 +r (213) +Using Lemma 9we deduce +l2 +r=dβ−d+1 +1−dγ(214)28 +It follows that +lr=ǫ′ +rl (215) +for some real constant l≥0 and signs ǫ′ +r=±1. The fact that the Lrare a basis +for gl(d,C) means the lrcannot all be zero. So we must in fact have l>0. Using +this result in Eq. ( 188) we find +β+d2l2γ=dl2(216) +while Eq. ( 214) implies +dβ+dl2γ=d−1+l2(217) +This gives us a pair of simultaneous equations in βandγ. Solving them we obtain +β=d +d+1(218) +γ=1 +dl2/parenleftbigg +l2−1 +d+1/parenrightbigg +(219) +Substituting these expressions into Eqs. ( 186) and (187) we deduce Eqs. ( 210) +and (211). /square +The next lemma shows that each Lris a linear combination of a rank-1projector +and the identity: +Lemma 11. LetLbe any Hermitian matrix ∈gl(d,C)which is not a multiple of +the identity. Then +rank(ad L)≥2(d−1) (220) +The lower bound is achieved if and only if Lis of the form +L=ηI+ξP (221) +wherePis a rank- 1projector and η,ξare any pair of real numbers. The eigenvalues +ofadLare then ±ξ(each with multiplicity d−1) and0(with multiplicity d2−2d+2). +Proof.Letλ1≥λ2≥ ··· ≥λdbe the eigenvalues of Larranged in decreasing +order, and let |b1/an}bracketri}ht,|b2/an}bracketri}ht,...,|bd/an}bracketri}htbe the correspondingeigenvectors. We mayassume, +without loss of generality, that the |br/an}bracketri}htare orthonormal. We have +adL/parenleftbig +|br/an}bracketri}ht/an}bracketle{tbs|/parenrightbig +=/bracketleftbig +L,|br/an}bracketri}ht/an}bracketle{tbs|/bracketrightbig += (λr−λs)|br/an}bracketri}ht/an}bracketle{tbs| (222) +So the eigenvalues of ad Lareλr−λs. SinceLis not a multiple of the identity we +must haveλr/ne}ationslash=λr+1for somerin the range 1 ≤r≤d−1. We then have that +λs−λt/ne}ationslash= 0 if either s≤r2 it cannot happen that ξr= +1 for some values +ofrand−1 for others. We will do this by assuming the contrary and deducing a +contradiction. +Letmbe the number of values of rfor whichξr= +1. We are assuming that +mis in the range 1 ≤m≤d2−1. We may also assume, without loss of generality,30 +that the labelling is such that ξr= +1 for the first mvalues ofr, and−1 for the +rest. So +L′ +r=/braceleftigg +Π′ +r ifr≤m +2 +dI−Π′ +rifr>m(236) +Now define +˜Trst= Tr/parenleftbig +L′ +rL′ +sL′ +t/parenrightbig +(237) +Eqs. (230) and (231) mean that the same argument which led to Eq. ( 9) can be +used to deduce +L′ +rL′ +s=d+1 +d +d2/summationdisplay +t=1˜TrstL′ +t +−K2 +rsI (238) +SinceL′ +1is a projector it follows that +L′ +1L′ +s=/parenleftbig +L′ +1/parenrightbig2L′ +s=d+1 +d +d2/summationdisplay +t=1˜T1stL′ +1L′ +t +−K2 +1sL′ +1 (239) +By essentially the same argument which led to Eq. ( 118) we can use this to infer +/parenleftbig˜T′ +1/parenrightbig2=d +d+1˜T1+2d2 +(d+1)2/bardble1/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{te1/bardbl (240) +where˜T′ +1is the matrix with matrix elements ˜T′ +1rsand/bardble1/an}bracketri}ht/an}bracketri}htis the vector defined by +Eq.(116). Asbefore /bardble1/an}bracketri}ht/an}bracketri}htisaneigenvectorof ˜T′ +1witheigenvalue2d +d+1. Consequently +the matrix +˜Q1=d+1 +d˜T′ +1−2/bardble1/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{te1/bardbl (241) +is a projector. But that means Tr( ˜Q1) must be an integer. We now use this to +derive a contradiction. +It follows from Eq. ( 236) that +(L′ +r)2=/braceleftigg +L′ +r r≤m +2(d−2) +d2I−d−4 +dL′ +rr>m(242) +Consequently +˜T1rr=/braceleftigg +K2 +1r r≤m +2(d−2) +d2−d−4 +dK2 +1rr>m(243) +and so +Tr(˜Q1) =d+1 +dd2/summationdisplay +r=1˜T1rr−2 +=d+1−4d2+2m(d−2) +d3(244) +So if Tr( ˜Q1) is an integer/parenleftbig +4d2+2n(d−2)/parenrightbig +/d3must also be an integer. But the +fact that 1 ≤m2 means +4 +d<4d2+2m(d−2) +d3<2 (245)31 +Ifd= 3 or 4 there are no integers in this interval, which gives us a contrad iction +straight away. If, on the other hand, d≥5 there is the possibility +4d2+2m(d−2) +d3= 1 (246) +implying +m=d2(d−4) +2(d−2)(247) +This equationhasthe solution d= 6,m= 9(this is in fact the only integersolution, +ascanbe seenfrom ananalysisofthe possible primefactorizationso fthe numerator +and denominator on the right hand side). To eliminate this possibility de fine +L′′ +r=2 +dI−L′ +d2+1−r (248) +for allr. It is easily verified that +Tr(L′′ +rL′′ +s) =dδrs+1 +d+1(249) +d2/summationdisplay +r=1L′′ +r=dI (250) +and +L′′ +r=/braceleftigg +Πr r≤d2−m +2 +dI−Πrr>d2−m(251) +So we can go through the same argument as before to deduce +d2−m=d2(d−4) +2(d−2)(252) +Eqs. (247) and (252) have no joint solutions at all with d/ne}ationslash= 0, integer or otherwise. +/square +To complete the proof of Theorem 7observe that Eqs. ( 210) and (227) imply +Tr(ΠrΠs) =dδrs+1 +d+1(253) +So the Π rare a SIC-set. Moreover +Lr=ǫr(Πr+αI) (254) +whereǫr=ǫǫ′ +randα= (ǫl−1)/d. +6.The Algebra sl(d,C) +The motivation for this paper is the hope that a Lie algebraic perspec tive may +cast some light on the SIC-existence problem, and on the mathemat ics of SIC- +POVMs generally. We have focused on gl( d,C) as that is the case where the con- +nection with Lie algebras seems most straightforward. However, it may be worth +mentioning that a SIC-POVM also gives rise to an interesting geometr ical structure +in sl(d,C) (the Lie algebra consisting of all trace-zero d×dcomplex matrices).32 +Let Πrbe a SIC-set and define +Br=/radicaligg +d+1 +2(d2−1)/parenleftbigg +Πr−1 +dI/parenrightbigg +(255) +SoBr∈sl(d,C). Let +/an}bracketle{tA,A′/an}bracketri}ht= Tr(ad AadA′) = 2dTr(AA′) (256) +be the Killing form [ 55] on sl(d,C). Then +/an}bracketle{tBr,Bs/an}bracketri}ht=/braceleftigg +1 r=s +−1 +d2−1r/ne}ationslash=s(257) +So theBrform a regular simplex in sl( d,C). Since sl( d,C) isd2−1 dimensional +theBrare an overcomplete set. However, the fact that +d2/summationdisplay +r=1Br= 0 (258) +means that for each A∈sl(d,C) there is a unique set of numbers arsuch that +A=d2/summationdisplay +r=1arBr (259) +and +d2/summationdisplay +r=1ar= 0 (260) +Thearcan be calculated using +ar=d2−1 +d2/an}bracketle{tA,Br/an}bracketri}ht (261) +Similarly, given any linear transformation M: sl(d,C)→sl(d,C), there is a unique +set of numbers Mrssuch that +MBr=d2/summationdisplay +s=1MrsBs (262) +and +d2/summationdisplay +s=1Mrs=d2/summationdisplay +s=1Msr= 0 (263) +for allr. TheMrscan be calculated using +Mrs=d2−1 +d2/an}bracketle{tBs,MBr/an}bracketri}ht (264) +In short, the Brretain many analogous properties of, and can be used in much the +same way as, a basis. It could be said that they form a simplicial basis.33 +7.Further Identities +In the preceding pages we have seen that there are five different f amilies of ma- +trices naturally associated with a SIC-POVM: namely, the projecto rsQrtogether +with the matrices +Jr=Qr−QT +r (265) +¯Rr=Qr+QT +r (266) +Rr=Qr+QT +r+4/bardbler/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{ter/bardbl (267) +Tr=d +d+1Qr+2d +d+1/bardbler/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{ter/bardbl (268) +(see Section 3). As we noted previously, it is possible to define everything in terms +of the adjoint representation matrices Jrand the rank-1 projectors /bardbler/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{ter/bardbl: +Qr=1 +2Jr(Jr+I) (269) +¯Rr=J2 +r (270) +Rr=J2 +r+4/bardbler/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{ter/bardbl (271) +Tr=d +2(d+1)Jr(Jr+I)+2d +d+1/bardbler/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{ter/bardbl (272) +In that sense the structure constants of the Lie algebra, supple mented with the +vectors/bardbler/an}bracketri}ht/an}bracketri}ht, determine everything else. +In the next section we will show that there are some interesting geo metrical +relationships between the hyperplanes onto which Qr,QT +rand¯Rrproject. In this +section, as a preliminary to that investigation, we prove a number of identities +satisfied by the Q,Jand¯Rmatries. We start by computing their Hilbert-Schmidt +inner products: +Theorem 13. For allr,s +Tr/parenleftbig +QrQs/parenrightbig +=d3δrs+d2−d−1 +(d+1)2(273) +Tr/parenleftbig +QrQT +s/parenrightbig +=d2(1−δrs) +(d+1)2(274) +Tr/parenleftbig +JrJs/parenrightbig +=2(d2δrs−1) +d+1(275) +Tr/parenleftbig¯Rr¯Rs/parenrightbig +=2(d−1)(d2δrs+2d+1) +(d+1)2(276) +Tr/parenleftbig +Jr¯Rs/parenrightbig += 0 (277) +Proof.Let us first calculate some auxiliary quantities. It follows from the de finition +ofTr, andthe factthat the matrix P=1 +dGdefined byEq.( 63) isarankdprojector, +that +Tr(TrTs) =d2/summationdisplay +u,v=1TruvTsvu34 +=d2/summationdisplay +u,v=1K2 +uvGruGusGsvGvr +=d +d+1d2/summationdisplay +u=1K2 +ruK2 +su+d4 +d+1d2/summationdisplay +u,v=1PruPusPsvPvr +=d2(dδrs+d+2) +(d+1)3+d4 +d+1/vextendsingle/vextendsinglePrs/vextendsingle/vextendsingle2 +=d2(dδrs+d+2) +(d+1)3+d2 +d+1K2 +rs +=d2/parenleftbig +d(d+2)δrs+2d+3/parenrightbig +(d+1)3(278) +Also +Tr/parenleftbig +TrTT +s/parenrightbig +=d2/summationdisplay +u,v=1TruvTsuv +=d2/summationdisplay +u=1GruGsu +d2/summationdisplay +v=1GuvGuvGvrGvs + +=2d +d+1d2/summationdisplay +u=1GruGsuGurGus +=2d2 +(d+1)2/parenleftbig +1+K2 +rs/parenrightbig +=2d2(dδrs+d+2) +(d+1)3(279) +where we made two applications of Eq. ( 23) (i.e.the fact that every SIC-POVM is +a 2-design). Finally, it is a straightforward consequence of the defi nitions ofTr,TT +r +and/bardbler/an}bracketri}ht/an}bracketri}htthat +/an}bracketle{t/an}bracketle{ter/bardblTs/bardbler/an}bracketri}ht/an}bracketri}ht=/an}bracketle{t/an}bracketle{ter/bardblTT +s/bardbler/an}bracketri}ht/an}bracketri}ht +=d+1 +2dd2/summationdisplay +u,v=1TsuvK2 +ruK2 +rv +=1 +2d(d+1) +d2Tsrr+dd2/summationdisplay +v=1Tsrv+dd2/summationdisplay +u=1Tsur+d2/summationdisplay +u,v=1Tsuv + +=d +2(d+1)/parenleftbig +3K2 +rs+1/parenrightbig +=d(3dδrs+d+4) +2(d+1)2(280)35 +and +/an}bracketle{t/an}bracketle{ter/bardbles/an}bracketri}ht/an}bracketri}ht=d+1 +2dd2/summationdisplay +u=1K2 +ruK2 +su +=dδrs+d+2 +2(d+1)(281) +Using these results in the expressions +Tr/parenleftbig +QrQs/parenrightbig += Tr/parenleftigg/parenleftbiggd+1 +dTr−2/bardbler/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{ter/bardbl/parenrightbigg/parenleftbiggd+1 +dTs−2/bardbles/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tes/bardbl/parenrightbigg/parenrightigg +(282) +and +Tr/parenleftbig +QrQT +s/parenrightbig += Tr/parenleftigg/parenleftbiggd+1 +dTr−2/bardbler/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{ter/bardbl/parenrightbigg/parenleftbiggd+1 +dTT +s−2/bardbles/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tes/bardbl/parenrightbigg/parenrightigg +(283) +the first two statements follow. The remaining statements are imme diate conse- +quences of these and the fact that +Jr=Qr−QT +r (284) +¯Rr=Qr+QT +r (285) +/square +Now define +/bardblv0/an}bracketri}ht/an}bracketri}ht=1 +dd2/summationdisplay +r=1/bardblr/an}bracketri}ht/an}bracketri}ht (286) +where/bardblr/an}bracketri}ht/an}bracketri}htis the basis defined in Eq. ( 117). The following result shows (among +other things) that the subspaces onto which the Qr(respectively QT +r,Rr) project +span the orthogonal complement of /bardblv0/an}bracketri}ht/an}bracketri}ht. +Theorem 14. For allr +Qr/bardblv0/an}bracketri}ht/an}bracketri}ht=QT +r/bardblv0/an}bracketri}ht/an}bracketri}ht=Jr/bardblv0/an}bracketri}ht/an}bracketri}ht=Rr/bardblv0/an}bracketri}ht/an}bracketri}ht= 0 (287) +Moreover +d2/summationdisplay +r=1Qr=d2/summationdisplay +r=1QT +r=d2 +d+1/parenleftbig +I−/bardblv0/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tv0/bardbl/parenrightbig +(288) +d2/summationdisplay +r=1Jr= 0 (289) +d2/summationdisplay +r=1¯Rr=2d2 +d+1/parenleftbig +I−/bardblv0/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tv0/bardbl/parenrightbig +(290) +Proof.Some of this is a straightforward consequence of the fact that Jris the +adjoint representative of Π r. Since +d2/summationdisplay +s=1Πs=dI (291)36 +we must have +d2/summationdisplay +s,t=1JrstΠt=d2/summationdisplay +s=1adΠrΠs= 0 (292) +In view of the antisymmetry of the Jrstit follows that +d2/summationdisplay +r=1Jr= 0 (293) +and +Jr/bardblv0/an}bracketri}ht/an}bracketri}ht= 0 (294) +Using the relations +Qr=1 +2Jr(Jr+I) (295) +QT +r=1 +2Jr(Jr−I) (296) +¯Rr=J2 +r (297) +we deduce +Qr/bardblv0/an}bracketri}ht/an}bracketri}ht=QT +r/bardblv0/an}bracketri}ht/an}bracketri}ht=¯Rr/bardblv0/an}bracketri}ht/an}bracketri}ht= 0 (298) +It remains to prove Eqs. ( 288) and (290). It follows from Eq. ( 120) that +d2/summationdisplay +r=1Qrst=d+1 +dd2/summationdisplay +r=1Trst−2d2/summationdisplay +r=1/an}bracketle{t/an}bracketle{ts/bardbler/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{ter/bardblt/an}bracketri}ht/an}bracketri}ht += (d+1)K2 +st−d+1 +dd2/summationdisplay +r=1K2 +rsK2 +rt +=d2δst−1 +d+1(299) +from which it follows +d2/summationdisplay +r=1Qr=d2/summationdisplay +r=1QT +r=d2 +d+1/parenleftbig +I−/bardblv0/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tv0/bardbl/parenrightbig +(300) +Eq. (290) follows from this and the fact that Rr=Qr+QT +r. +/square +8.Geometrical Considerations +In this section we show that there are some interesting geometrica l relationships +between the subspaces onto which the operators Qr,QT +rand¯Rrproject. The +original motivation for this work was an observation concerning the subspaces onto +which the ¯Rrproject. ¯Rris a real matrix, and so it defines a 2( d−2) subspace +inRd2, which we will denote Rr. We noticed that for each pair of distinct indices +randsthe intersection Rr∩Rsis a 1-dimensional line. This led us to speculate +that a set of hyperplanes parallel to the Rrmight be the edges of an interesting +polytope. We continue to think that this could be the case. Unfortu nately we have +not been able to prove it. However, it appears to us that the result s we obtained37 +while trying to prove it have an interest which is independent of the tr uth of the +motivating speculation. +We will begin with some terminology. Let Pbe any projector (on either RN +orCN), letPbe the subspace onto which Pprojects, and let |ψ/an}bracketri}htbe any non-zero +vector. Then we define the angle between |ψ/an}bracketri}htandPin the usual way, to be +θ= cos−1/parenleftigg/vextenddouble/vextenddoubleP|ψ/an}bracketri}ht/vextenddouble/vextenddouble +/vextenddouble/vextenddouble|ψ/an}bracketri}ht/vextenddouble/vextenddouble/parenrightigg +(301) +(soθis the smallest angle between |ψ/an}bracketri}htand any of the vectors in P). +Suppose, now, that P′is another projector, and let P′be the subspace onto +whichP′projects. We will say that P′is uniformly inclined to Pif every vector in +P′makes the same angle θwithP. Ifθ= 0 this means that P′⊆P, while ifθ=π +2 +it means P′⊥P. Suppose, on the other hand, that 0 < θ <π +2. Let|u′ +1/an}bracketri}ht,...,|u′ +n/an}bracketri}ht +be any orthonormal basis for P′, and define |ur/an}bracketri}ht= secθP|u′ +r/an}bracketri}ht. Then/an}bracketle{tur|ur/an}bracketri}ht= 1 +for allr. Moreover, if P,P′are complex projectors, +/an}bracketle{tu′ +r+eiφu′ +s|P|u′ +r+eiφu′ +s/an}bracketri}ht= 2cos2θ/parenleftig +1+Re/parenleftbig +eiφ/an}bracketle{tur|us/an}bracketri}ht/parenrightbig/parenrightig +(302) +for allφandr/ne}ationslash=s. On the other hand it follows from the assumption that P′is +uniformly inclined to Pthat +/an}bracketle{tu′ +r+eiφu′ +s|P|u′ +r+eiφu′ +s/an}bracketri}ht= 2cos2θ (303) +for allφandr/ne}ationslash=s. Consequently +/an}bracketle{tur|us/an}bracketri}ht=δrs (304) +for allr,s. It is easily seen that the same is true if P,P′are real projectors. +Suppose we now make the further assumption that dim( P′) = dim( P) =n. Then +|u1/an}bracketri}ht,...,|un/an}bracketri}htis an orthonormal basis for P, and we can write +P=n/summationdisplay +r=1|ur/an}bracketri}ht/an}bracketle{tur| (305) +P′=n/summationdisplay +r=1|u′ +r/an}bracketri}ht/an}bracketle{tu′ +r| (306) +Observe that +/an}bracketle{tu′ +r|us/an}bracketri}ht=/an}bracketle{tu′ +r|P|us/an}bracketri}ht= cosθ/an}bracketle{tur|us/an}bracketri}ht= cosθδrs (307) +for allr,s. Consequently +P′|ur/an}bracketri}ht= cosθ|ur/an}bracketri}ht (308) +for allr. It follows that +/vextenddouble/vextenddoubleP′|ψ/an}bracketri}ht/vextenddouble/vextenddouble=/vextenddouble/vextenddouble/vextenddouble/vextenddouble/vextenddoublen/summationdisplay +r=1cosθ/an}bracketle{tur|ψ/an}bracketri}ht|u′ +r/an}bracketri}ht/vextenddouble/vextenddouble/vextenddouble/vextenddouble/vextenddouble= cosθ/vextenddouble/vextenddouble|ψ/an}bracketri}ht/vextenddouble/vextenddouble (309) +for all|ψ/an}bracketri}ht ∈P. SoPis uniformly inclined to P′at the same angle θ. +It follows from Eqs. ( 305) and (306) that +PP′P= cos2θP (310) +P′PP′= cos2θP′(311) +Eq. (310), or equivalently Eq. ( 311), is not only necessary but also sufficient for +the subspaces to be uniformly inclined. In fact, let P,P′be any two subspaces38 +which have the same dimension n, but which are not assumed at the outset to be +uniformly inclined, and let P,P′be the corresponding projectors. Suppose +PP′P= cos2θP (312) +for someθin the range 0 ≤θ≤π +2. It is immediate that P=P′ifθ= 0, and +P⊥P′ifθ=π +2. Either way, the subspaces are uniformly inclined. Suppose, on +the other hand, that 0 <θ<π +2. Let|u′ +1/an}bracketri}ht,...,|u′ +n/an}bracketri}htbe any orthonormal basis for P′, +and define |ur/an}bracketri}ht= secθP|u′ +r/an}bracketri}ht. Eq. (305) then implies +P= sec2θn/summationdisplay +r=1P|u′ +r/an}bracketri}ht/an}bracketle{tu′ +r|P=n/summationdisplay +r=1|ur/an}bracketri}ht/an}bracketle{tur| (313) +Given any |ψ/an}bracketri}ht ∈Pwe have +|ψ/an}bracketri}ht=P|ψ/an}bracketri}ht=n/summationdisplay +r=1/an}bracketle{tur|ψ/an}bracketri}ht|ur/an}bracketri}ht (314) +Since dim( P) =nit follows that the |ur/an}bracketri}htare linearly independent. In particular +|ur/an}bracketri}ht=P|ur/an}bracketri}ht=n/summationdisplay +s=1/an}bracketle{tus|ur/an}bracketri}ht|us/an}bracketri}ht (315) +Since the |ur/an}bracketri}htare linearly independent this means +/an}bracketle{tus|ur/an}bracketri}ht=δrs (316) +So the|ur/an}bracketri}htare an orthonormal basis for P. It follows, that if |ψ′/an}bracketri}htis any vector in +P′, then +/vextenddouble/vextenddoubleP|ψ′/an}bracketri}ht/vextenddouble/vextenddouble=/vextenddouble/vextenddouble/vextenddouble/vextenddouble/vextenddoublen/summationdisplay +r=1/an}bracketle{tu′ +r|ψ′/an}bracketri}htP|u′ +r/an}bracketri}ht/vextenddouble/vextenddouble/vextenddouble/vextenddouble/vextenddouble= cosθ/vextenddouble/vextenddouble/vextenddouble/vextenddouble/vextenddoublen/summationdisplay +r=1/an}bracketle{tu′ +r|ψ′/an}bracketri}ht|ur/an}bracketri}ht/vextenddouble/vextenddouble/vextenddouble/vextenddouble/vextenddouble= cosθ/vextenddouble/vextenddouble|ψ′/an}bracketri}ht/vextenddouble/vextenddouble(317) +implying that P′is uniformly inclined to Pat angleθ. +It will be convenient to summarise all this in the form of a lemma: +Lemma 15. LetP,P′be any two subspaces, real or complex, having the same +dimensionn. LetP,P′be the corresponding projectors. Then the following state- +ments are equivalent: +(a)P′is uniformly inclined to Pat angleθ. +(b)Pis uniformly inclined to P′at angleθ. +(c) +PP′P= cos2θP (318) +(d) +P′PP′= cos2θP′(319) +Suppose these conditions are satisfied for some θin the range 0< θ <π +2, and +let|u1/an}bracketri}ht,...|un/an}bracketri}htbe any orthonormal basis for P. Then there exists an orthonormal +basis|u′ +1/an}bracketri}ht,...,|u′ +n/an}bracketri}htforP′such that +P′|ur/an}bracketri}ht= cosθ|u′ +r/an}bracketri}ht (320) +P|u′ +r/an}bracketri}ht= cosθ|ur/an}bracketri}ht (321) +We are now in a position to state the main results of this section. Let Qr +(respectively ¯Qr) be the subspace onto which Qr(respectively QT +r) projects. We +then have39 +Theorem 16. For each pair of distinct indices r,sthe subspaces Qr,¯Qrhave the +orthogonal decomposition +Qr=Q0 +rs⊕Qrs (322) +¯Qr=¯Q0 +rs⊕¯Qrs (323) +where +Q0 +rs⊥Qrs dim(Q0 +rs) = 1 dim( Qrs) =d−2 +¯Q0 +rs⊥¯Qrs dim(¯Q0 +rs) = 1 dim( ¯Qrs) =d−2 +We have +(a)Relation of the subspaces QrandQs: +(1)Q0 +rs⊥QsrandQrs⊥Q0 +sr. +(2)Q0 +rsandQ0 +srare inclined at angle cos−1/parenleftbig1 +d+1/parenrightbig +. +(3)QrsandQsrare uniformly inclined at angle cos−1/parenleftig +1√d+1/parenrightig +. +(b)Relation of the subspaces ¯Qrand¯Qs: +(1)¯Q0 +rs⊥¯Qsrand¯Qrs⊥¯Q0 +sr. +(2)¯Q0 +rsand¯Q0 +srare inclined at angle cos−1/parenleftbig1 +d+1/parenrightbig +. +(3)¯Qrsand¯Qsrare uniformly inclined at angle cos−1/parenleftig +1√d+1/parenrightig +. +(c)Relation of the subspaces Qrand¯Qs: +(1)Q0 +rs⊥¯Qsr,Qrs⊥¯Q0 +srandQrs⊥¯Qsr. +(2)Q0 +rsand¯Q0 +srare inclined at angle cos−1/parenleftbigd +d+1/parenrightbig +. +The relations between these subspaces are, perhaps, easier to a ssimilate if pre- +sented pictorially. In the following diagrams the line joining each pair of subspaces +is labelled with the cosine of the angle between them. In particular a 0 o n the line +joining two subspaces indicates that they are orthogonal. +Q0 +rs Qrs +Q0 +sr Qsr0 +01 +d+11√d+1 + +0❅ +❅ +❅ +❅ +❅ +❅❅0¯Q0 +rs¯Qrs +¯Q0 +sr¯Qsr0 +01 +d+11√d+1 + +0❅ +❅ +❅ +❅ +❅ +❅❅0 +Q0 +rs Qrs +¯Q0 +sr¯Qsr0 +0d +d+10 + +0❅ +❅ +❅ +❅ +❅ +❅❅040 +Wewillprovethistheorembelow. Beforedoingso,however,letusst atetheother +mainresult ofthis section. Let Rrbe the subspace ontowhichthe ¯Rrproject. Since +¯Rris a real matrix we regard Rras a subspace of Rd2. We have +Theorem 17. For each pair of distinct indices r,sthe subspace Rrhas the decom- +position +Rr=R0 +rs⊕R1 +rs⊕Rrs (324) +whereR0 +rs,R1 +rs,Rrsare pairwise orthogonal and +dim(R0 +rs) = 1 dim( R1 +rs) = 1 dim( Rrs) = 2d−4 (325) +We have +(1)R0 +rs=R0 +sr. +(2)R1 +rs⊥RsrandRrs⊥R1 +sr. +(3)R1 +rsandR1 +srare inclined at angle cos−1/parenleftbigd−1 +d+1/parenrightbig +. +(4)RrsandRsrare uniformly inclined at angle cos−1/parenleftig/radicalig +1 +d+1/parenrightig +In particular, the subspaces ¯Rrand¯Rsintersect in a line. +In diagrammatic form the relations between these subspaces are +R0 +rs=R0 +srR1 +rs Rrs +R1 +sr Rsr0 +0d−1 +d+1/radicalig +1 +d+1 + +0❅ +❅ +❅ +❅ +❅ +❅❅0✟✟✟✟✟0 +❍❍❍❍❍00 +0 +where, as before, each line is labelled with the cosine of the angle betw een the two +subspaces it connects. +Proof of Theorem 16.Let/bardbl1/an}bracketri}ht/an}bracketri}ht,...,/bardbld2/an}bracketri}ht/an}bracketri}htbethestandardbasisfor Hd2, asdefined +by Eq. (117). For each pair of distinct indices r,sdefine +/bardblfrs/an}bracketri}ht/an}bracketri}ht=i√ +d+1Qr/bardbls/an}bracketri}ht/an}bracketri}ht (326) +/bardblf∗ +rs/an}bracketri}ht/an}bracketri}ht=−i√ +d+1QT +r/bardbls/an}bracketri}ht/an}bracketri}ht (327) +The significance of these vectors is that /bardblfrs/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tfrs/bardbl(respectively /bardblf∗ +rs/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tf∗ +rs/bardbl) will +turn out to be the projectoronto the 1-dimensionalsubspace Q0 +rs(respectively ¯Q0 +rs).41 +Note that the fact that Qris Hermitian means +QT +r=Q∗ +r (328) +(whereQ∗ +ris the matrix whose elements are the complex conjugates of the cor re- +sponding elements of Qr). Consequently +/an}bracketle{t/an}bracketle{tt/bardblf∗ +rs/an}bracketri}ht/an}bracketri}ht=/parenleftig +/an}bracketle{t/an}bracketle{tt/bardblfrs/an}bracketri}ht/an}bracketri}ht/parenrightig∗ +(329) +for allr,s,t. +It is easily seen that /bardblfrs/an}bracketri}ht/an}bracketri}ht,/bardblf∗ +rs/an}bracketri}ht/an}bracketri}htare normalized. In fact, it follows from +Eqs. (116) and (120) that +/an}bracketle{t/an}bracketle{tfrs/bardblfrs/an}bracketri}ht/an}bracketri}ht= (d+1)/an}bracketle{t/an}bracketle{ts/bardblQr/bardbls/an}bracketri}ht/an}bracketri}ht +=(d+1)2 +dTrss−2(d+1)/an}bracketle{t/an}bracketle{ts/bardbler/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{ter/bardbls/an}bracketri}ht/an}bracketri}ht +=(d+1)2 +d/parenleftbig +K2 +rs−K4 +rs/parenrightbig += 1 (330) +for allr/ne}ationslash=s. In view of Eq. ( 329) we then have +/an}bracketle{t/an}bracketle{tf∗ +rs/bardblf∗ +rs/an}bracketri}ht/an}bracketri}ht=/parenleftig +/an}bracketle{t/an}bracketle{tfrs/bardblfrs/an}bracketri}ht/an}bracketri}ht/parenrightig∗ += 1 (331) +for allr/ne}ationslash=s. The fact that QrQT +r= 0 means we also have +/an}bracketle{t/an}bracketle{tfrs/bardblf∗ +rs/an}bracketri}ht/an}bracketri}ht= 0 (332) +for allr/ne}ationslash=s. +Note that, although we required that r/ne}ationslash=sin the definitions of /bardblfrs/an}bracketri}ht/an}bracketri}ht,/bardblf∗ +rs/an}bracketri}ht/an}bracketri}ht, +the definitions continue to make sense when r=s. However, the vectors are then +zero (as can be seen by setting r=sin Eq. (121)). +The vectors /bardblfrs/an}bracketri}ht/an}bracketri}ht,/bardblf∗ +rs/an}bracketri}ht/an}bracketri}htsatisfy a number of identities, which it will be conve- +nient to collect in a lemma: +Lemma 18. For allr/ne}ationslash=s +/bardblfrs/an}bracketri}ht/an}bracketri}ht=−/bardblf∗ +sr/an}bracketri}ht/an}bracketri}ht+i/radicalbigg +2 +d/parenleftig +/bardbles/an}bracketri}ht/an}bracketri}ht−/bardbler/an}bracketri}ht/an}bracketri}ht/parenrightig +(333) +/bardblf∗ +rs/an}bracketri}ht/an}bracketri}ht=−/bardblfsr/an}bracketri}ht/an}bracketri}ht−i/radicalbigg +2 +d/parenleftig +/bardbles/an}bracketri}ht/an}bracketri}ht−/bardbler/an}bracketri}ht/an}bracketri}ht/parenrightig +(334) +(where/bardbler/an}bracketri}ht/an}bracketri}htis the vector defined by Eq. ( 116)) +Qr/bardblfrs/an}bracketri}ht/an}bracketri}ht=/bardblfrs/an}bracketri}ht/an}bracketri}ht QT +r/bardblf∗ +rs/an}bracketri}ht/an}bracketri}ht=/bardblf∗ +rs/an}bracketri}ht/an}bracketri}ht (335) +QT +r/bardblfrs/an}bracketri}ht/an}bracketri}ht= 0 Qr/bardblf∗ +rs/an}bracketri}ht/an}bracketri}ht= 0 (336) +Qs/bardblfrs/an}bracketri}ht/an}bracketri}ht=−1 +d+1/bardblfsr/an}bracketri}ht/an}bracketri}ht QT +s/bardblf∗ +rs/an}bracketri}ht/an}bracketri}ht=−1 +d+1/bardblf∗ +sr/an}bracketri}ht/an}bracketri}ht(337) +QT +s/bardblfrs/an}bracketri}ht/an}bracketri}ht=−d +d+1/bardblf∗ +sr/an}bracketri}ht/an}bracketri}ht Qs/bardblf∗ +rs/an}bracketri}ht/an}bracketri}ht=−d +d+1/bardblfsr/an}bracketri}ht/an}bracketri}ht(338) +/an}bracketle{t/an}bracketle{tfrs/bardblfsr/an}bracketri}ht/an}bracketri}ht=/an}bracketle{t/an}bracketle{tf∗ +rs/bardblf∗ +sr/an}bracketri}ht/an}bracketri}ht=−1 +d+1(339)42 +/an}bracketle{t/an}bracketle{tfrs/bardblf∗ +sr/an}bracketri}ht/an}bracketri}ht=/an}bracketle{t/an}bracketle{tf∗ +rs/bardblfsr/an}bracketri}ht/an}bracketri}ht=−d +d+1(340) +Proof.It follows from Eqs. ( 116) and (120) that +/an}bracketle{t/an}bracketle{tt/bardblfrs/an}bracketri}ht/an}bracketri}ht+/an}bracketle{t/an}bracketle{tt/bardblf∗ +sr/an}bracketri}ht/an}bracketri}ht=i√ +d+1/parenleftbig +Qrts−Qsrt/parenrightbig +=i√ +d+1/parenleftbiggd+1 +d/parenleftbig +Trts−Tsrt/parenrightbig +−2/parenleftbig +/an}bracketle{t/an}bracketle{tt/bardbler/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{ter/bardbls/an}bracketri}ht/an}bracketri}ht−/an}bracketle{t/an}bracketle{tr/bardbles/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tes/bardblt/an}bracketri}ht/an}bracketri}ht/parenrightbigg +=i/radicalbigg +2 +d/parenleftbig +/an}bracketle{t/an}bracketle{tt/bardbles/an}bracketri}ht/an}bracketri}ht−/an}bracketle{t/an}bracketle{tt/bardbler/an}bracketri}ht/an}bracketri}ht/parenrightbig +(341) +where we used the fact that Trts=Tsrtin the third step, and the fact that /an}bracketle{t/an}bracketle{tt/bardbles/an}bracketri}ht/an}bracketri}htis +real in the last. This establishes Eq. ( 333). Eq. (334) is obtained by taking complex +conjugates on both sides, and using the fact that the vectors /bardbles/an}bracketri}ht/an}bracketri}htare real. +Eqs. (335) and (336) are immediate consequences of the definitions, and the fact +thatQrQT +r= 0. Turning to the proof of Eqs. ( 337) and (338), it follows from +Eqs. (119) and (120) that +Qs/bardbles/an}bracketri}ht/an}bracketri}ht= 0 (342) +Using this and the fact that Qs/bardblf∗ +sr/an}bracketri}ht/an}bracketri}ht= 0 in Eq. ( 333) we find +Qs/bardblfrs/an}bracketri}ht/an}bracketri}ht=−i/radicalbigg +2 +dQs/bardbler/an}bracketri}ht/an}bracketri}ht (343) +Since +/bardbler/an}bracketri}ht/an}bracketri}ht=/radicaligg +d +2(d+1)/parenleftig +/bardblr/an}bracketri}ht/an}bracketri}ht+/bardblv0/an}bracketri}ht/an}bracketri}ht/parenrightig +(344) +and taking account of the fact that Qs/bardblv0/an}bracketri}ht/an}bracketri}ht= 0 (see Eq. ( 287)) we deduce +Qs/bardblfrs/an}bracketri}ht/an}bracketri}ht=−i/radicalbigg +1 +d+1Qs/bardblr/an}bracketri}ht/an}bracketri}ht=−1 +d+1/bardblfsr/an}bracketri}ht/an}bracketri}ht (345) +Taking complex conjugates on both sides of this equation we deduce the second +identity in Eq. ( 337). +In the same way, acting on both sides of Eq. ( 333) withQT +swe find +QT +s/bardblfrs/an}bracketri}ht/an}bracketri}ht=−/bardblf∗ +sr/an}bracketri}ht/an}bracketri}ht−i/radicalbigg +2 +dQT +s/bardbler/an}bracketri}ht/an}bracketri}ht +=−/bardblf∗ +sr/an}bracketri}ht/an}bracketri}ht−i/radicalbigg +1 +d+1QT +s/bardblr/an}bracketri}ht/an}bracketri}ht +=−d +d+1/bardblf∗ +sr/an}bracketri}ht/an}bracketri}ht (346) +Taking complex conjugates on both sides of this equation we deduce the second +identity in Eq. ( 338). +Turning to the last group of identities we have +/an}bracketle{t/an}bracketle{tfrs/bardblfsr/an}bracketri}ht/an}bracketri}ht=/an}bracketle{t/an}bracketle{tfrs/bardblQr/bardblfsr/an}bracketri}ht/an}bracketri}ht=−1 +d+1/an}bracketle{t/an}bracketle{tfrs/bardblfrs/an}bracketri}ht/an}bracketri}ht=−1 +d+1(347) +and +/an}bracketle{t/an}bracketle{tfrs/bardblf∗ +sr/an}bracketri}ht/an}bracketri}ht=/an}bracketle{t/an}bracketle{tfrs/bardblQr/bardblf∗ +sr/an}bracketri}ht/an}bracketri}ht=−d +d+1/an}bracketle{t/an}bracketle{tfrs/bardblfrs/an}bracketri}ht/an}bracketri}ht=−d +d+1(348)43 +The other two identities are obtained by taking complex conjugates on both sides +of the two just derived. /square +This lemma provides a substantial part of what we need to prove the theorem. +The remaining part is provided by +Lemma 19. For allr/ne}ationslash=s +QrQsQr=1 +d+1Qr−d +(d+1)2/bardblfrs/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tfrs/bardbl (349) +QrQT +sQr=d2 +(d+1)2/bardblfrs/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tfrs/bardbl (350) +Proof.It follows from Eq. ( 120) that +QrQsQr=d+1 +dQrTsQr−2Qr/bardbles/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tes/bardblQr (351) +QrQT +sQr=d+1 +dQrTT +sQr−2Qr/bardbles/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tes/bardblQr (352) +In view of Eqs. ( 344), (287) and the definition of /bardblfrs/an}bracketri}ht/an}bracketri}htwe have +Qr/bardbles/an}bracketri}ht/an}bracketri}ht=/radicaligg +d +2(d+1)Qr/bardbls/an}bracketri}ht/an}bracketri}ht=−i√ +d√ +2(d+1)/bardblfrs/an}bracketri}ht/an}bracketri}ht (353) +Substituting this expression into Eqs. ( 351) and (352) we obtain +QrQsQr=d+1 +dQrTsQr−d +(d+1)2/bardblfrs/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tfrs/bardbl (354) +QrQT +sQr=d+1 +dQrTT +sQr−d +(d+1)2/bardblfrs/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tfrs/bardbl (355) +The problem therefore reduces to showing +QrTsQr=d +(d+1)2Qr (356) +QrTT +sQr=d2 +(d+1)2/bardblfrs/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tfrs/bardbl (357) +Using Eq. ( 120) we find +/an}bracketle{t/an}bracketle{ta/bardblQrTsQr/bardblb/an}bracketri}ht/an}bracketri}ht=(d+1)2 +d2/an}bracketle{t/an}bracketle{ta/bardblTrTsTr/bardblb/an}bracketri}ht/an}bracketri}ht +−1 +2/parenleftbigg2(d+1) +d/parenrightbigg3 +2/parenleftig +K2 +ra/an}bracketle{t/an}bracketle{ter/bardblTsTr/bardblb/an}bracketri}ht/an}bracketri}ht+K2 +rb/an}bracketle{t/an}bracketle{ta/bardblTrTs/bardbler/an}bracketri}ht/an}bracketri}ht/parenrightig ++2(d+1) +dK2 +raK2 +rb/an}bracketle{t/an}bracketle{ter/bardblTs/bardbler/an}bracketri}ht/an}bracketri}ht (358) +/an}bracketle{t/an}bracketle{ta/bardblQrTT +sQr/bardblb/an}bracketri}ht/an}bracketri}ht=(d+1)2 +d2/an}bracketle{t/an}bracketle{ta/bardblTrTT +sTr/bardblb/an}bracketri}ht/an}bracketri}ht +−1 +2/parenleftbigg2(d+1) +d/parenrightbigg3 +2/parenleftig +K2 +ra/an}bracketle{t/an}bracketle{ter/bardblTT +sTr/bardblb/an}bracketri}ht/an}bracketri}ht+K2 +rb/an}bracketle{t/an}bracketle{ta/bardblTrTT +s/bardbler/an}bracketri}ht/an}bracketri}ht/parenrightig ++2(d+1) +dK2 +raK2 +rb/an}bracketle{t/an}bracketle{ter/bardblTT +s/bardbler/an}bracketri}ht/an}bracketri}ht (359)44 +Using the definitions of Tr,/bardbler/an}bracketri}ht/an}bracketri}htand Eq. ( 23) (the 2-design property) we find, after +some algebra, +/an}bracketle{t/an}bracketle{ta/bardblTrTsTr/bardblb/an}bracketri}ht/an}bracketri}ht=d2 +(d+1)2/parenleftig +K2 +raTrsb+K2 +rbTras+K2 +rsTrab+K2 +raK2 +rb/parenrightig +(360) +/an}bracketle{t/an}bracketle{ter/bardblTsTr/bardblb/an}bracketri}ht/an}bracketri}ht= 2/parenleftbiggd +2(d+1)/parenrightbigg3 +2/parenleftig +2K2 +rsK2 +rb+K2 +rb+Trsb/parenrightig +(361) +/an}bracketle{t/an}bracketle{ta/bardblTrTs/bardbler/an}bracketri}ht/an}bracketri}ht= 2/parenleftbiggd +2(d+1)/parenrightbigg3 +2/parenleftig +2K2 +rsK2 +ra+K2 +ra+Tras/parenrightig +(362) +/an}bracketle{t/an}bracketle{ter/bardblTs/bardbler/an}bracketri}ht/an}bracketri}ht=d +2(d+1)/parenleftbig +3K2 +rs+1/parenrightbig +(363) +and +/an}bracketle{t/an}bracketle{ta/bardblTrTT +sTr/bardblb/an}bracketri}ht/an}bracketri}ht=d2 +(d+1)2/parenleftig +GraGasGsbGbr ++K2 +raTrsb+K2 +rbTras+K2 +raK2 +rb/parenrightig +=d2 +(d+1)2/parenleftig +(d+1)TrasTrsb ++K2 +raTrsb+K2 +rbTras+K2 +raK2 +rb/parenrightig +(364) +/an}bracketle{t/an}bracketle{ter/bardblTT +sTr/bardblb/an}bracketri}ht/an}bracketri}ht= 2/parenleftbiggd +2(d+1)/parenrightbigg3 +2/parenleftig +K2 +rsK2 +rb+K2 +rb+2Trsb/parenrightig +(365) +/an}bracketle{t/an}bracketle{ta/bardblTrTT +s/bardbler/an}bracketri}ht/an}bracketri}ht= 2/parenleftbiggd +2(d+1)/parenrightbigg3 +2/parenleftig +K2 +rsK2 +ra+K2 +ra+2Tras/parenrightig +(366) +/an}bracketle{t/an}bracketle{ter/bardblTT +s/bardbler/an}bracketri}ht/an}bracketri}ht=d +2(d+1)/parenleftbig +3K2 +rs+1/parenrightbig +(367) +where in deriving Eq. ( 364) we used the fact that GraGasGsbGbr= (d+1)TrasTrsb +(in view of the fact that r/ne}ationslash=s). Substituting these expressions into Eqs. ( 358) +and (359) we deduce Eqs. ( 356) and (357). /square +Now define the rank d−1 projectors +Qrs=Qr−/bardblfrs/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tfrs/bardbl (368) +QT +rs=QT +r−/bardblf∗ +rs/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tf∗ +rs/bardbl (369) +andletQ0 +rs,Qrs,¯Q0 +rsand¯Qrsbe, respectively, the subspacesontowhich /bardblfrs/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tfrs/bardbl, +Qrs,/bardblf∗ +rs/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tf∗ +rs/bardblandQ∗ +rsproject. It is immediate that we have the orthogonal +decompositions +Qr=Q0 +rs⊕Qrs (370) +¯Qr=¯Q0 +rs⊕¯Qrs (371) +Using Lemma 18we find +Qsr/bardblfrs/an}bracketri}ht/an}bracketri}ht=Qrs/bardblfsr/an}bracketri}ht/an}bracketri}ht= 0 (372)45 +implying that Q0 +rs⊥QsrandQrs⊥Q0 +sr, and +/vextendsingle/vextendsingle/an}bracketle{t/an}bracketle{tfrs/bardblfsr/an}bracketri}ht/an}bracketri}ht/vextendsingle/vextendsingle=1 +d+1(373) +implying that Q0 +rsandQ0 +srare inclined at angle cos−1/parenleftbig1 +d+1/parenrightbig +. Using Lemma 18 +together with Lemma 19we find +QrsQsrQrs=QrsQsQrs +=QrQsQr−/bardblfrs/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tfrs/bardblQsQr−QrQs/bardblfrs/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tfrs/bardbl ++/an}bracketle{t/an}bracketle{tfrs/bardblQs/bardblfrs/an}bracketri}ht/an}bracketri}ht/bardblfrs/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tfrs/bardbl +=1 +d+1Qr−1 +d+1/bardblfrs/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tfrs/bardbl +=1 +d+1Qrs (374) +which in view of Lemma 15implies that QrsandQsrare uniformly inclined at angle +cos−1/parenleftbig1√d+1/parenrightbig +. This proves part (a) of the theorem. Parts (b) and (c) are prov ed +similarly. +Proof of Theorem 17.Define +/bardblgrs/an}bracketri}ht/an}bracketri}ht=1√ +2/parenleftbig +/bardblf∗ +rs/an}bracketri}ht/an}bracketri}ht+/bardblfrs/an}bracketri}ht/an}bracketri}ht/parenrightbig +(375) +/bardbl¯grs/an}bracketri}ht/an}bracketri}ht=i√ +2/parenleftbig +/bardblf∗ +rs/an}bracketri}ht/an}bracketri}ht−/bardblfrs/an}bracketri}ht/an}bracketri}ht/parenrightbig +(376) +By construction the components of /bardblgrs/an}bracketri}ht/an}bracketri}ht,/bardbl¯grs/an}bracketri}ht/an}bracketri}htin the standard basis are real, so +we can regard them as ∈Rd2. They are orthonormal: +/an}bracketle{t/an}bracketle{tgrs/bardblgrs/an}bracketri}ht/an}bracketri}ht=/an}bracketle{t/an}bracketle{t¯grs/bardbl¯grs/an}bracketri}ht/an}bracketri}ht= 1 and /an}bracketle{t/an}bracketle{tgrs/bardbl¯grs/an}bracketri}ht/an}bracketri}ht= 0 (377) +It is also readily verified, using Lemma 18, that +¯Rr/bardblgrs/an}bracketri}ht/an}bracketri}ht=/bardblgrs/an}bracketri}ht/an}bracketri}ht (378) +¯Rr/bardbl¯grs/an}bracketri}ht/an}bracketri}ht=/bardbl¯grs/an}bracketri}ht/an}bracketri}ht (379) +So +Rrs=¯Rr−/bardblgrs/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tgrs/bardbl−/bardbl¯grs/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{t¯grs/bardbl (380) +is a rank 2 d−4 projector. If we define R0 +rs,R1 +rsandRrsto be, respectively, +the subspaces onto which /bardblgrs/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tgrs/bardbl,/bardbl¯grs/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{t¯grs/bardblandRrsproject we have the +orthogonal decomposition +Rr=R0 +rs⊕R1 +rs⊕Rrs (381) +It follows from Eqs. ( 333) and (334) that +/bardblgrs/an}bracketri}ht/an}bracketri}ht=−/bardblgsr/an}bracketri}ht/an}bracketri}ht (382) +implying that R0 +rs=R0 +srfor allr/ne}ationslash=s. It is also easily verified, using Lemma 18, +that/vextendsingle/vextendsingle/an}bracketle{t/an}bracketle{t¯grs/bardbl¯gsr/an}bracketri}ht/an}bracketri}ht/vextendsingle/vextendsingle=d−1 +d+1(383) +from which it follows that R1 +rsandR1 +srare inclined at angle cos−1/parenleftbigd−1 +d+1/parenrightbig +. We next +observe that +Rrs=Qrs+QT +rs (384)46 +Using Lemma 18once again we deduce +Rrs/bardbl¯gsr/an}bracketri}ht/an}bracketri}ht=Rsr/bardbl¯grs/an}bracketri}ht/an}bracketri}ht= 0 (385) +from which it follows that R1 +rs⊥RsrandRrs⊥R1 +sr. Finally, we know from +Theorem 16thatQT +rsQsr=QrsQT +sr= 0. Consequently +RrsRsrRrs=QrsQsrQrs+QT +rsQT +srQT +rs +=d +d+1Qrs+d +d+1QT +rs +=1 +d+1Rrs (386) +In view of Lemma 15it follows that RrsandRsrare uniformly inclined at angle +cos−1/parenleftbig1√d+1/parenrightbig +. +Further Identities. We conclude this section with another set of identities in- +volving the vectors /bardblfrs/an}bracketri}ht/an}bracketri}ht,/bardblf∗ +rs/an}bracketri}ht/an}bracketri}ht,/bardblgrs/an}bracketri}ht/an}bracketri}htand/bardbl¯grs/an}bracketri}ht/an}bracketri}ht. +Define +/bardbl¯er/an}bracketri}ht/an}bracketri}ht=/radicalbigg +2d +d−1/bardbler/an}bracketri}ht/an}bracketri}ht−/radicalbigg +d+1 +d−1/bardblv0/an}bracketri}ht/an}bracketri}ht (387) +where/bardblv0/an}bracketri}ht/an}bracketri}htis the vector defined by Eq. ( 286). It is readily verified that +/an}bracketle{t/an}bracketle{t¯er/bardbl¯er/an}bracketri}ht/an}bracketri}ht= 0 and /an}bracketle{t/an}bracketle{t¯er/bardblv0/an}bracketri}ht/an}bracketri}ht= 0 (388) +So/bardbl¯er/an}bracketri}ht/an}bracketri}ht,/bardblv0/an}bracketri}ht/an}bracketri}htis an orthonormal basis for the 2-dimensional subspace spanned b y +/bardbler/an}bracketri}ht/an}bracketri}ht,/bardblv0/an}bracketri}ht/an}bracketri}ht. Note that +Qr/bardbl¯er/an}bracketri}ht/an}bracketri}ht=QT +r/bardbl¯er/an}bracketri}ht/an}bracketri}ht=¯Rr/bardbl¯er/an}bracketri}ht/an}bracketri}ht= 0 (389) +We then have +Theorem 20. For allr +1 +d+1d2/summationdisplay +s=1 +(s/negationslash=r)/bardblfrs/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tfrs/bardbl=Qr (390) +1 +d+1d2/summationdisplay +s=1 +(s/negationslash=r)/bardblf∗ +rs/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tf∗ +rs/bardbl=QT +r (391) +2 +d+1d2/summationdisplay +s=1 +(s/negationslash=r)/bardblgrs/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tgrs/bardbl=¯Rr (392) +2 +d+1d2/summationdisplay +s=1 +(s/negationslash=r)/bardbl¯grs/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{t¯grs/bardbl=¯Rr (393) +and +1 +d−1d2/summationdisplay +s=1 +(s/negationslash=r)/bardblfsr/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tfsr/bardbl=QT +r+/bardbl¯er/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{t¯er/bardbl+1 +d2−1/parenleftig +I−/bardblv0/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tv0/bardbl/parenrightig +(394)47 +1 +d−1d2/summationdisplay +s=1 +(s/negationslash=r)/bardblf∗ +sr/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tf∗ +sr/bardbl=Qr+/bardbl¯er/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{t¯er/bardbl+1 +d2−1/parenleftig +I−/bardblv0/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tv0/bardbl/parenrightig +(395) +2 +d+1d2/summationdisplay +s=1 +(s/negationslash=r)/bardblgsr/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tgsr/bardbl=¯Rr (396) +2 +d−3d2/summationdisplay +s=1 +(s/negationslash=r)/bardbl¯gsr/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{t¯gsr/bardbl=¯Rr+4(d−1) +d−3/bardbl¯er/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{t¯er/bardbl+4 +(d+1)(d−3)/parenleftig +I−/bardblv0/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tv0/bardbl/parenrightig +(397) +Proof.It follows from the definition of /bardblfrs/an}bracketri}ht/an}bracketri}htthat +1 +d+1d2/summationdisplay +s=1 +(s/negationslash=r)/bardblfrs/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tfrs/bardbl=d2/summationdisplay +s=1 +(s/negationslash=r)Qr/bardbls/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{ts/bardblQr +=Qr +d2/summationdisplay +s=1/bardbls/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{ts/bardbl +Qr +=Qr (398) +where in the second step we used the fact that Qr/bardblr/an}bracketri}ht/an}bracketri}ht= 0 (as can be seen by setting +r=sin Eq. (121)). Eq. (391) is obtained by taking the complex conjugate on both +sides. +We also have +1 +d+1d2/summationdisplay +s=1 +(s/negationslash=r)/bardblfrs/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tf∗ +rs/bardbl=−d2/summationdisplay +s=1 +(s/negationslash=r)Qr/bardbls/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{ts/bardblQT +r +=−Qr +d2/summationdisplay +s=1/bardbls/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{ts/bardbl +QT +r +=−QrQT +r += 0 (399) +Taking the complex conjugate on both sides we find +1 +d+1d2/summationdisplay +s=1 +(s/negationslash=r)/bardblf∗ +rs/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tfrs/bardbl= 0 (400) +Consequently +2 +d+1d2/summationdisplay +s=1 +(s/negationslash=r)/bardblgrs/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tgrs/bardbl=1 +d+1d2/summationdisplay +s=1 +(s/negationslash=r)/parenleftig +/bardblfrs/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tfrs/bardbl+/bardblf∗ +rs/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tf∗ +rs/bardbl ++/bardblfrs/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tf∗ +rs/bardbl+/bardblf∗ +rs/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tfrs/bardbl/parenrightig +=¯Rr (401)48 +Eq. (393) is proved similarly. +To prove the second group of identities we have to work a little harde r. Using +Eqs. (116) and (120) we find +1 +d−1d2/summationdisplay +s=1 +(s/negationslash=r)/an}bracketle{t/an}bracketle{ta/bardblfsr/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tfsr/bardblb/an}bracketri}ht/an}bracketri}ht=d+1 +d−1d2/summationdisplay +s=1/an}bracketle{t/an}bracketle{ta/bardblQs/bardblr/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tr/bardblQs/bardblb/an}bracketri}ht/an}bracketri}ht +=(d+1)3 +d2(d−1)d2/summationdisplay +s=1/parenleftig +TsarTsrb−K2 +saK2 +srTsrb +−K2 +srK2 +sbTsar+K2 +saK4 +srK2 +sb/parenrightig +(402) +(where we used the fact that Qs/bardbls/an}bracketri}ht/an}bracketri}ht= 0 in the first step). After some algebra we +find +d2/summationdisplay +s=1TsarTsrb=d +d+1/parenleftigg/parenleftigg/radicalbigg +d−1 +d+1/an}bracketle{t/an}bracketle{ta/bardbl¯er/an}bracketri}ht/an}bracketri}ht+1 +d/parenrightigg/parenleftigg/radicalbigg +d−1 +d+1/an}bracketle{t/an}bracketle{t¯er/bardblb/an}bracketri}ht/an}bracketri}ht+1 +d/parenrightigg ++Trba/parenrightigg +(403) +d2/summationdisplay +s=1K2 +saK2 +srTsrb=d +d+1/parenleftigg/parenleftigg/radicalbigg +d−1 +d+1/an}bracketle{t/an}bracketle{ta/bardbl¯er/an}bracketri}ht/an}bracketri}ht+2d+1 +d(d+1)/parenrightigg/parenleftigg/radicalbigg +d−1 +d+1/an}bracketle{t/an}bracketle{t¯er/bardblb/an}bracketri}ht/an}bracketri}ht+1 +d/parenrightigg ++1 +d+1Trba/parenrightigg +(404) +d2/summationdisplay +s=1K2 +srK2 +sbTsar=d +d+1/parenleftigg/parenleftigg/radicalbigg +d−1 +d+1/an}bracketle{t/an}bracketle{ta/bardbl¯er/an}bracketri}ht/an}bracketri}ht+1 +d/parenrightigg/parenleftigg/radicalbigg +d−1 +d+1/an}bracketle{t/an}bracketle{t¯er/bardblb/an}bracketri}ht/an}bracketri}ht+2d+1 +d(d+1)/parenrightigg ++1 +d+1Trba/parenrightigg +(405) +d2/summationdisplay +s=1K2 +saK4 +srK2 +sb=d +(d+1)/parenleftigg +d+2 +d+1/parenleftigg/radicalbigg +d−1 +d+1/an}bracketle{t/an}bracketle{ta/bardbl¯er/an}bracketri}ht/an}bracketri}ht+1 +d/parenrightigg/parenleftigg/radicalbigg +d−1 +d+1/an}bracketle{t/an}bracketle{t¯er/bardblb/an}bracketri}ht/an}bracketri}ht+1 +d/parenrightigg ++d +(d+1)3δab+d+2 +(d+1)3/parenrightigg +(406) +wherewe usedEq. ( 23) to derivethe firstexpression. Substituting these expressions +into Eq. ( 402) and using +/an}bracketle{t/an}bracketle{ta/bardblQT +r/bardblb/an}bracketri}ht/an}bracketri}ht=d+1 +d/parenleftigg +Trba−/parenleftigg/radicalbigg +d−1 +d+1/an}bracketle{t/an}bracketle{ta/bardbl¯er/an}bracketri}ht/an}bracketri}ht+1 +d/parenrightigg/parenleftigg/radicalbigg +d−1 +d+1/an}bracketle{t/an}bracketle{t¯er/bardblb/an}bracketri}ht/an}bracketri}ht+1 +d/parenrightigg/parenrightigg +(407) +we deduce Eq. ( 394). Taking complex conjugates on both sides we obtain Eq. ( 395). +Eq. (396) is an immediate consequence of Eq. ( 392) and the fact that /bardblgsr/an}bracketri}ht/an}bracketri}ht= +−/bardblgrs/an}bracketri}ht/an}bracketri}htfor allr,s.49 +To prove Eq. ( 397) observe that it follows from Eqs. ( 394)–(396) that +d2/summationdisplay +s=1 +(s/negationslash=r)/parenleftig +/bardblfsr/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tf∗ +sr/bardbl+/bardblf∗ +sr/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tfsr/bardbl/parenrightig +=d2/summationdisplay +s=1 +(s/negationslash=r)/parenleftig +2/bardblgsr/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tgsr/bardbl−/bardblfsr/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tfsr/bardbl−/bardblf∗ +sr/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tf∗ +sr/bardbl/parenrightig += 2/parenleftig +¯Rr−(d−1)/bardbl¯er/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{t¯er/bardbl +−1 +d+1/parenleftig +I−/bardblv0/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tv0/bardbl/parenrightig/parenrightbigg +(408) +Hence +2 +d−3d2/summationdisplay +s=1 +(s/negationslash=r)/bardbl¯gsr/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{t¯gsr/bardbl=1 +d−3d2/summationdisplay +s=1 +(s/negationslash=r)/parenleftig +/bardblfsr/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tfsr/bardbl+/bardblf∗ +sr/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tf∗ +sr/bardbl +−/bardblfsr/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tf∗ +sr/bardbl−/bardblf∗ +sr/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tf∗ +sr/bardbl/parenrightig +=¯Rr+4(d−1) +d−3/bardbl¯er/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{t¯er/bardbl+4 +(d+1)(d−3)/parenleftig +I−/bardblv0/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tv0/bardbl/parenrightig +(409) +/square +9.TheP-PTProperty +In the preceding sections the Q-QTproperty has played a prominent role. In +this section we show that in the particular case ofa Weyl-Heisenberg covariantSIC- +POVM, and with the appropriate choice of gauge, the Gram project or (defined in +Eq. (63)) has an analogous property, which we call the P-PTproperty. Specifically +one has +PPT=PTP=/bardblh/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{th/bardbl (410) +where/bardblh/an}bracketri}ht/an}bracketri}htis a normalized vector whose components in the standard basis are a ll +real. In odd dimensions the components of /bardblh/an}bracketri}ht/an}bracketri}htin the standard basis can be simply +expressed in terms of the Wigner function of the fiducial vector. I t could be said +thattheprojectors PandPTarealmostorthogonal(bycontrastwiththeprojectors +QrandQT +rwhich are completely orthogonal). More precisely Phas the spectral +decomposition +P=¯P+/bardblh/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{th/bardbl (411) +where¯Pis a rank (d−1) projector with the property +¯P¯PT= 0 (412) +This means that the matrix +JP=P−PT(413) +is a pure imaginary Hermitian matrix with the property that J2 +Pis a real rank +2d−2 projector ( c.f.the discussion in Section 4). +Although we are mainly interested in the P-PTproperty as it applies to SIC- +POVMs, itshould benoted that itactuallyholdsforanyWeyl-Heisenbe rgcovariant +POVM (with the appropriate choice of gauge). So we will prove the ab ove propo- +sitions for this more general case.50 +Let us begin by fixing notation. Let |0/an}bracketri}ht,...,|d−1/an}bracketri}htbe an orthonormal basis for +d-dimensional Hilbert space and let XandZbe the operators whose action on the +|r/an}bracketri}htis +X|a/an}bracketri}ht=|a+1/an}bracketri}ht (414) +Z|a/an}bracketri}ht=ωa|a/an}bracketri}ht (415) +whereω=e2πi +dand the addition of indices in the first equation is modd. We then +define the Weyl-Heisenberg displacement operators by (adopting t he convention +used in, for example, ref. [ 16]) +Dp=τp1p2Xp1Zp2(416) +wherepis the vector ( p1,p2) (p1,p2being integers) and τ=e(d+1)πi +d. Generally +speaking the decision to insert the phase τp1p2is a matter of convention, and many +authors define it differently, or else omit altogether. However, for the purposes of +this section it is essential, as a different choice of phase at this stage would lead to a +different gauge in the class of POVMs to be defined below, and the Gra m projector +would then typically not have the P-PTproperty. +Note thatτ2=τd2=ωin every dimension. If the dimension is odd we can write +τ=ωd+1 +2. Soτis adthroot of unity. However, if the dimension is even τd=−1. +This has the consequence that +Dp+du= (−1)u1p2+u2p1Dp (417) +Soin even dimension p=q(modd) does notnecessarilyimply Dp=Dq(although +the operators are, of course, equal if p=q(mod 2d)) +In every dimension (even or odd) we have +D† +p=D−p (418) +for allp +(Dp)n=Dnp (419) +for allp,nand +DpDq=τ/angbracketleftp,q/angbracketrightDp+q (420) +for allp,q. In the last expression /an}bracketle{tp,q/an}bracketri}htis the symplectic form +/an}bracketle{tp,q/an}bracketri}ht=p2q1−p1q2 (421) +Now let|ψ/an}bracketri}htbe any normalized vector (not necessarily a SIC-fiducial vector), and +define +|ψp/an}bracketri}ht=Dp|ψ/an}bracketri}ht (422) +Let +L=/summationdisplay +p∈Z2 +d|ψp/an}bracketri}ht/an}bracketle{tψp| (423) +It is easily seen that/bracketleftbig +Dp,L/bracketrightbig += 0 (424) +for allp.51 +We now appeal to the fact that there is no non-trivial subspace of Hdwhich +the displacement operators leave invariant. To see this assume the contrary. Then +there would exist non-zero vectors |φ/an}bracketri}ht,|χ/an}bracketri}htsuch that +/an}bracketle{tφ|Dp|χ/an}bracketri}ht= 0 (425) +for allp. Writing the left-hand side out in full this gives +d−1/summationdisplay +a=0ωp2a/an}bracketle{tφ|a+p1/an}bracketri}ht/an}bracketle{ta|χ/an}bracketri}ht= 0 (426) +for allp1,p2. Taking the discrete Fourier transform with respect to p2, we have +/an}bracketle{tφ|a+p1/an}bracketri}ht/an}bracketle{ta|χ/an}bracketri}ht= 0 (427) +for alla,p1, implying that either |φ/an}bracketri}ht= 0 or|χ/an}bracketri}ht= 0—contrary to assumption. We +can therefore use Schur’s lemma [ 55] to deduce that +L=kI (428) +for some constant k. Taking the trace on both sides of this equation we infer +thatk=d. We conclude that1 +d|ψp/an}bracketri}ht/an}bracketle{tψp|is a POVM. We refer to POVMs of this +general class as Weyl-Heisenberg covariant POVMs. We refer to th e vector |ψ/an}bracketri}ht +which generates the POVM as the fiducial vector (with no implication t hat it is +necessarily a SIC-fiducial). +Now consider the Gram projector +P=/summationdisplay +p,q∈Z2 +dPp,q/bardblp/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tq/bardbl (429) +where +Pp,q=1 +d/an}bracketle{tψp|ψq/an}bracketri}ht (430) +and where we label the matrix elements of Pand the standard basis kets with the +vectorsp,qrather than with the single integer indices r,sas in the rest of this +paper. We know from Theorem 1thatPis a rankdprojector. +In view of Eqs. ( 418) and (420) we have +/an}bracketle{t/an}bracketle{tp/bardblP/bardblq/an}bracketri}ht/an}bracketri}ht=Pp,q +=1 +dτ−/angbracketleftp,q/angbracketright/an}bracketle{tψ|Dq−p|ψ/an}bracketri}ht +=1 +dd−1/summationdisplay +a=0τp1p2+q1q2ωaq2−(q1+a)p2/an}bracketle{tψ|a+q1−p1/an}bracketri}ht/an}bracketle{ta|ψ/an}bracketri}ht(431) +Hence +/an}bracketle{t/an}bracketle{tp/bardblPPT/bardblq/an}bracketri}ht/an}bracketri}ht=/summationdisplay +u∈Zd/an}bracketle{t/an}bracketle{tp/bardblP/bardblu/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{tq/bardblP/bardblu/an}bracketri}ht/an}bracketri}ht +=1 +d2d−1/summationdisplay +a,b,u1,u2=0τp1p2+q1q2ωu2(u1+a+b)−(u1+a)p2−(u1+b)q2 +×/an}bracketle{tψ|a+u1−p1/an}bracketri}ht/an}bracketle{tψ|b+u1−q1/an}bracketri}ht/an}bracketle{ta|ψ/an}bracketri}ht/an}bracketle{tb|ψ/an}bracketri}ht52 +=1 +dd−1/summationdisplay +a,b=0τp1p2+q1q2ωp2b+q2a/an}bracketle{tψ|−b−p1/an}bracketri}ht/an}bracketle{tb|ψ/an}bracketri}ht/an}bracketle{tψ|−a−q1/an}bracketri}ht/an}bracketle{ta|ψ/an}bracketri}ht +=/an}bracketle{t/an}bracketle{tp/bardblh/an}bracketri}ht/an}bracketri}ht/an}bracketle{t/an}bracketle{th/bardblq/an}bracketri}ht/an}bracketri}ht (432) +where/bardblh/an}bracketri}ht/an}bracketri}htis the vector with components +/an}bracketle{t/an}bracketle{tp/bardblh/an}bracketri}ht/an}bracketri}ht=1√ +dd−1/summationdisplay +a=0τp1p2ωp2a/an}bracketle{tψ|−a−p1/an}bracketri}ht/an}bracketle{ta|ψ/an}bracketri}ht (433) +It is easily verified that /bardblh/an}bracketri}ht/an}bracketri}htis normalized, and that /an}bracketle{t/an}bracketle{tp/bardblh/an}bracketri}ht/an}bracketri}htis real. +Finally, suppose that the dimension is odd. Then the Wigner function o f the +state|ψ/an}bracketri}htis [56,57] +W(p) =1 +d/an}bracketle{tψ|DpUPD† +p|ψ/an}bracketri}ht=1 +d/an}bracketle{tψ|D2pUP|ψ/an}bracketri}ht (434) +whereUPistheparityoperator,whoseactiononthestandardbasisis UP|a/an}bracketri}ht=|−a/an}bracketri}ht. +It is straightforward to show +/an}bracketle{t/an}bracketle{tp/bardblh/an}bracketri}ht/an}bracketri}ht=√ +dW(−2−1p) (435) +where 2−1= (d+1)/2 is the multiplicative inverse of 2 considered as an element of +Zd:i.e.the unique integer 0 ≤m