few_shots: Example 1:
Problem/activity:
Find the general solution for:
$${\mathrm{cos}\left({\pi\over2}+x\right)=\mathrm{tan}{\pi\over4}}$$


Standard options: 
A. Prove the Pythagorean identity sin^(2)(θ) + cos^(2)(θ) = 1 and use it to find sin(θ), cos(θ),or tan(θ) given sin(θ), cos(θ), or tan(θ) and the quadrant of the angle.
B. Prove the addition and subtraction formulas for sine, cosine, and tangent and use them to solve problems.


Your response:
{
  "explanation": "An initial step when solving for x in this problem requires the use of the addition formula for cosine on the left side of the equation. Solving this problem does not require use of the Pythagorean identity.",
  "answer": "B"
}

Example 2:
Problem/activity:
Task
Solve the quadratic equation
$$ x^2 = (2x - 9)^2 $$
using as many different methods as possible.


Standard options: 
A. Solve linear equations and inequalities in one variable, including equations with coefficients represented by letters.
B. Solve quadratic equations in one variable.


Your response:
{
  "explanation": "This task shows one quadratic equation with one variable, x.",
  "answer": "B"
}

Example 3:
Problem/activity:
Task
Suppose $A$ is an angle with vertex $P$, as pictured below:
[IMG]
Draw a circle with center $P$ and with  radius $r \gt 0$.  Explain why the circle
meets each ray of angle $A$ in a single point.  Label these points $Q$ and $R$ respectively.
Draw circles with centers $Q$ and $R$ respectively and radius $r$.  These circles meet at $P$ and a second point to be labelled $B$.
Show that ray $\overrightarrow{PB}$  bisects angle $P$.


Standard options: 
A. Make formal geometric constructions with a variety of tools and methods (compass and straightedge, string, reflective devices, paper folding, dynamic geometric software, etc.). Copying a segment; copying an angle; bisecting a segment; bisecting an angle; constructing perpendicular lines, including the perpendicular bisector of a line segment; and constructing a line parallel to a given line through a point not on the line.
B. Construct an equilateral triangle, a square, and a regular hexagon inscribed in a circle.


Your response:
{
  "explanation": "This task asks students to draw a ray that bisects an angle. The act of drawing circles and rays may involve compass and straightedge or dynamic geometric software.",
  "answer": "A"
}

Now, assign the following problem or activity to one or more relevant standards it aligns with.
shot_info: fl_problem_001894

HS_0

im_task_000870

HS_1

im_task_001160

HS_2
options: Create equations and inequalities in one variable and use them to solve problems. Include equations arising from linear and quadratic functions, and simple rational and exponential functions.

Create equations in two or more variables to represent relationships between quantities; graph equations on coordinate axes with labels and scales.

Represent constraints by equations or inequalities, and by systems of equations and/or inequalities, and interpret solutions as viable or nonviable options in a modeling context. For example, represent inequalities describing nutritional and cost constraints on combinations of different foods.

Rearrange formulas to highlight a quantity of interest, using the same reasoning as in solving equations. For example, rearrange Ohm’s law V = IR to highlight resistance R.
problem_activity: Activity
This activity allows students to formulate a mathematical model around the framing task they saw earlier (MP4). Students are prompted to write an equation but are not expected to solve it at this point. In writing an equation and interpreting the solution in context, students practice reasoning quantitatively and abstractly (MP2).
The prompt to write an equation is left relatively open to allow for different approaches. For instance, students may think in terms of:
The length and width of the framed picture. The length is 7 inches plus the thickness of the frame,
\(x\)
, on either side, which gives
\(7 + 2x\)
. The height is 4 inches plus the same thickness,
\(x\)
, for the top and bottom, which gives
\(4 + 2x\)
. The total area is
\(7 \boldcdot 4 + 4 \boldcdot (2.5)\)
or 38 square inches, so the equation is
\((7+2x)(4+2x) = 38\)
.
The area of the picture plus the area of the frame. The area of the picture is 28 square inches. The area of the frame, in square inches, can be found by decomposing it into four squares (in the corners) that are
\(x\)
by
\(x\)
or
\(x^2\)
each, two rectangles that are
\(7x\)
each (top and bottom), and two rectangles that are
\(4x\)
each (left and right). The equation is
\(4x^2 + 2(7x) + 2(4x) + 28 = 38\)
or
\(4x^2 + 22x + 28= 38\)
.
As students work, monitor for different strategies students use. Invite students with contrasting approaches to share later.
Launch
Tell students that they are now to write an equation to represent the quantities in the framing problem. Consider arranging students in groups of 2 and asking them to think quietly about the questions before conferring with their partner.
If students have trouble getting started, suggest that they start by labeling the diagram with relevant lengths. Then, if needed, use scaffolding questions such as:
“How could we show that the frame is the same thickness all the way around?” (Use the same variable, for example
\(x\)
, to label the thickness of the strip of framing on all four sides.)
“What is the combined area of the picture and the framing material?” (38 square inches, because
\(7 \boldcdot 4 + 4 \boldcdot (2.5)=38\)
)
“How could we express the width of the framed picture?” (
\(7+2x\)
) “What about the height of the framed picture?” (
\(4+2x\)
)
“Once the framing material is cut up and arranged around the picture, how could we express its area?” (Two rectangles with area
\(x(7+2x)\)
and two rectangles with area
\(4x\)
, or
\(2x(7+2x) + 2(4x)\)
)
Reading: MLR6 Three Reads.
Use this routine to support reading comprehension, without solving, for students. Use the first read to orient students to the situation. Ask students to describe what the situation is about without using numbers (creating a frame for a rectangular picture). If students understand the situation based on their work in the prior activity, skip to the next read. After the second read, students list any quantities that can be counted or measured, without focusing on specific values (dimensions of the picture and framing materials). During the third read, the question or prompt is revealed. Invite students to brainstorm possible strategies, referencing the relevant quantities named after the second read. This helps students connect the language in the word problem and the reasoning needed to solve the problem while keeping the cognitive demand of the task.
Design Principle: Support sense-making
Representation: Internalize Comprehension.
Represent the same information through different modalities by using diagrams. Provide students with graph paper and suggest that they draw and label their diagrams with everything they know so far. Invite students to suggest types of diagrams that might be helpful to draw, such as the strips of framing material, and the picture both with and without the frame.
Supports accessibility for: Conceptual processing; Visual-spatial processing
Student Facing
Here is a diagram that shows the picture with a frame that is the same thickness all the way around. The picture is 7 inches by 4 inches. The frame is created from 10 square inches of framing material (in the form of a rectangle measuring 4 inches by 2.5 inches).
[IMG]
Write an equation to represent the relationship between the measurements of the picture and of the frame, and the area of the framed picture. Be prepared to explain what each part of your equation represents.
What would a solution to this equation mean in this situation?
Student Response
Teachers with a valid work email address can
click here to register or sign in
for free access to Student Response.
Anticipated Misconceptions
Some students may struggle to express the overall length and width of the framed picture because of trouble combining numbers and variables. Consider drawing a segment composed of 3 pieces of length 1.5 inches, 10 inches, and 1.5 inches, and prompting students to find the length of the entire segment. Then, change each 1.5 to an
\(x\)
and ask for an expression for the length of the entire segment (
\(10+2x\)
).
If students mistake the result of adding
\(x\)
and
\(x\)
as
\(x^2\)
, consider drawing a square with side length
\(x\)
and ask students to write expressions for the perimeter and area. Then, ask them to point out the difference between
multiplying
to find area and
adding
to find total length. If needed, draw a few more segments that are decomposed into parts, with each part labeled with a number or a variable expression, and ask students to write expressions for the total length.
Activity Synthesis
Select students to present their equations and reasoning. If no students bring up one of the strategies shown in the Activity Narrative, bring it up. Consider asking students whether
\((7+2x)(4+2x)=38\)
and
\(4x^2 + 22x + 28 = 38\)
(or other correct equations that come up) are equivalent and how to check if they are.
Discuss what a solution to these equations represents. Make sure students understand that a solution reveals the thickness of the frame when all of the framing material (10 square inches) is used.
Solicit some ideas on how they might go about finding the solution(s). Students may mention:
graphing the equation
\(y=(7+2x)(4+2x)\)
and finding a point on the graph with a
\(y\)
-coordinate of 38
evaluating the expression on one side of the equation at different values of
\(x\)
until it has a value of 38
using a spreadsheet to evaluate the expression at different values of
\(x\)
and see what values produce an output of 38
We can see that the equations
\((7+2x)(4+2x)=38\)
and
\(4x^2 + 22x + 28 = 38\)
are each composed of a
quadratic expression
. Tell students that these are examples of
quadratic equations
. They will learn several techniques for using algebra to solve equations like this.
Formally, a quadratic equation is defined as one that can be written in the form of
\(ax^2+bx+c=0\)
where
\(a\)
is not 0. This formal definition will be introduced in the next lesson, when students work with equations of that form and make sense of them in context.


correct_option_index: 0