few_shots: 
Example 1:
Concept/skill: 
Prove the addition and subtraction formulas for sine, cosine, and tangent and use them to solve problems.

Problem/activity:
Find the general solution for:
$${\mathrm{cos}\left({\pi\over2}+x\right)=\mathrm{tan}{\pi\over4}}$$


Answer: 
Yes. An initial step when solving for x in this problem requires the use of the addition formula for cosine on the left side of the equation.

Example 2:
Concept/skill: 
Solve quadratic equations in one variable.

Problem/activity:
Task
Solve the quadratic equation
$$ x^2 = (2x - 9)^2 $$
using as many different methods as possible.


Answer: 
Yes. This task shows one quadratic equation with one variable, x.

Example 3:
Concept/skill: 
Make formal geometric constructions with a variety of tools and methods (compass and straightedge, string, reflective devices, paper folding, dynamic geometric software, etc.). Copying a segment; copying an angle; bisecting a segment; bisecting an angle; constructing perpendicular lines, including the perpendicular bisector of a line segment; and constructing a line parallel to a given line through a point not on the line.

Problem/activity:
Task
Suppose $A$ is an angle with vertex $P$, as pictured below:
[IMG]
Draw a circle with center $P$ and with  radius $r \gt 0$.  Explain why the circle
meets each ray of angle $A$ in a single point.  Label these points $Q$ and $R$ respectively.
Draw circles with centers $Q$ and $R$ respectively and radius $r$.  These circles meet at $P$ and a second point to be labelled $B$.
Show that ray $\overrightarrow{PB}$  bisects angle $P$.


Answer: 
Yes. This task asks students to draw a ray that bisects an angle. The act of drawing circles and rays may involve compass and straightedge or dynamic geometric software.

Now, determine whether the following problem or activity can enable students to understand the concepts or skills in the provided description.

shot_info: fl_problem_001894_pos_0

HS_0

im_task_000870_pos_0

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im_task_001160_pos_0

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standard_description: Convert among different-sized standard measurement units within a given measurement system (e.g., convert 5 cm to 0.05 m), and use these conversions in solving multi-step, real world problems.
problem_activity: Narrative
The purpose of this activity is for students to solve multi-step distance problems using centimeters, meters, and kilometers. This gives students an opportunity to think about which units are most helpful for communicating a distance (MP6). When the distance is short, like the length of a single footstep, centimeters or meters both work well. For a longer distance, like the distance a person walks in a day, it is reasonable to use meters or kilometers, but the number of centimeters is very large and more difficult to visualize.
To add movement or make this activity interactive, consider providing groups of 2 or 4 with a centimeter ruler or meter stick to measure their or a classmate’s step before working on the task. While students could use the measurements of their own steps to complete the table, the arithmetic may be more complex and, as a result, it may be harder to observe patterns.
Engagement: Provide Access by Recruiting Interest.
Optimize meaning and value. Invite students to share the places they could walk in the classroom, at home, in the community, and so on, that would be equivalent to the distances presented in the chart.
Supports accessibility for: Conceptual Processing; Visual-Spatial Processing
Required Materials
Materials to Gather
Metersticks
Launch
Groups of 2 or 4
“If someone wants to measure the length of one of their footsteps, which unit do you think they should use? Millimeters, centimeters, meters, or kilometers?”
Highlight that millimeters are too small and kilometers are too large. Both centimeters and meters make sense and the first part of this activity will use those two units of measure.
“There are 100 centimeters in a meter. About how many steps are in 1 meter?” (2 or 3)
“There are 1,000 meters in a kilometer. About how many steps are in a kilometer?” (2,000 or 3,000)
Give students access to a meter stick.
Activity
5 minutes: independent work time
5 minutes: small-group work time
Monitor for students who use the following strategies when determining how many kilometers Lin walks during the day:
multiply 50 centimeters by 8,500 steps to determine the distance in centimeters that Lin walked and divide 425,000 by 100,000
multiply 0.5 meters by 8,500 steps to determine the distance in meters that Lin walked and then divide 4,250 by 1,000
Student Facing
Lin has a watch that counts the number of steps she takes during the day and displays those steps in centimeters, meters, or kilometers.
Here is a list of activities Lin did on Monday. Next to each activity, write whether it would make sense to display the distance in cm, m, or km.
walked to her friend’s desk
walked to the front of the classroom
walked from her classroom to the bus
ran twice around the playground
The table shows the amount of steps Lin’s watch displayed for each activity. If each of her steps is 50 centimeters, how many centimeters and meters did Lin walk for each activity?
|               activity               | number of steps | distance (cm) | distance (m) |
|--------------------------------------|-----------------|---------------|--------------|
|     walked to her friend’s desk      |        5        |               |              |
| walked to the front of the classroom |       12        |               |              |
| walked from her classroom to the bus |       250       |               |              |
|   ran twice around the playground    |      1,000      |               |              |
At the end of the day, Lin’s watch displayed 8,500 steps. Would it make sense for her watch to record the distance in centimeters, meters, or kilometers? Why?
How many kilometers did Lin walk that day?
[IMG]
Student Response
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Activity Synthesis
“How did you determine how many kilometers Lin walked during the day?”
Ask previously selected students to share their solutions.
Display student work or write these equations for all to see:
\(8,\!500 \times 50= 425,\!000\)
\(8,\!500 \times 0.5 = 4,\!250\)
“How does each of these equations represent the situation?” (
\(8,\!500 \times 50= 425,\!000\)
represents 8,500 steps that are each 50 centimeters long so that would be a total of 425,000 centimeters.
\(8,\!500 \times 0.5 = 4,\!250\)
represents 8,500 steps that are each 0.5 meter long so that would be a total of 4,250 meters.)
“What is the same about these equations?” (They have the same number of steps. They are both multiplication equations.)
“What is different about these equations?” (One multiplies the number of steps by 50 centimeters and one multiplies the number of steps by 0.5 meter. The products are different. 4,250 is 100 times smaller than 425,000 because it represents meters instead of centimeters.)
Display:
\(425,\!000 \div 100,\!000= 4.25\)
\(4,\!250 \div 1,\!000 = 4.25\)
“How does each of these equations represent the situation?” (They both represent the number of kilometers that Lin walked. 425,000 is the distance she walked in centimeters so if you divide it by 100,000, you get the number of kilometers she walked. 4,250 is the distance in meters that she walked so we only have to divide by 1,000 to figure out how many kilometers she walked.)
Display: 4.25 km, 4,250 m, 425,000 cm
“Which of these do you think best communicates how far Lin walked this day?” (4.25 kilometers because I can picture how long a kilometer is.)


aligns: yes