few_shots: 
Example:
Concept/skill: 
Prove the addition and subtraction formulas for sine, cosine, and tangent and use them to solve problems.

Problem/activity:
Find the general solution for:
$${\mathrm{cos}\left({\pi\over2}+x\right)=\mathrm{tan}{\pi\over4}}$$


Answer: 
Yes. An initial step when solving for x in this problem requires the use of the addition formula for cosine on the left side of the equation.

Now, determine whether the following problem or activity can enable students to understand the concepts or skills in the provided description.

shot_info: fl_problem_001894_pos_0

HS_0
standard_description: Solve linear equations and inequalities in one variable, including equations with coefficients represented by letters.
problem_activity: Narrative
The purpose of this activity is for students to find the missing value in addition and subtraction equations. This activity is optional because determining the missing value of an equation is not required by the standards. Students may “just know” some of the answers or they may use counting forward or backward (MP7) or they may draw a picture.
MLR8 Discussion Supports.
Invite students to read their completed equations aloud.
Advances: Listening, Speaking
Required Materials
Materials to Gather
Connecting cubes or two-color counters
Launch
Groups of 2
Give students access to connecting cubes or two-color counters.
Display the student book.
“What do you notice? What do you wonder?” (The equations have a number missing. Why are there numbers missing?)
30 seconds: quiet think time
1 minute: partner discussion
Share responses.
“FIll in the missing part of each equation.”
Activity
10 minutes: partner work time
Monitor for students who use two-color counters or connecting cubes.
Monitor for students who draw pictures.
Student Facing
Fill in the missing part of each equation.
\(3 - \underline{\hspace{1.1 cm}} = 2\)
\(2 + \underline{\hspace{1.1 cm}} = 2\)
\(5 - \underline{\hspace{1.1 cm}} = 2\)
\(1 + \underline{\hspace{1.1 cm}} = 2\)
\(5 - \underline{\hspace{1.1 cm}} = 3\)
\(2 + \underline{\hspace{1.1 cm}} = 3\)
\(4 - \underline{\hspace{1.1 cm}} = 3\)
\(0 + \underline{\hspace{1.1 cm}} = 3\)
\(5 - \underline{\hspace{1.1 cm}} = 4\)
\(3 + \underline{\hspace{1.1 cm}} = 4\)
\(4 - \underline{\hspace{1.1 cm}} = 4\)
\(2 + \underline{\hspace{1.1 cm}} = 4\)
\(1 + \underline{\hspace{1.1 cm}} = 5\)
\(4 + \underline{\hspace{1.1 cm}} = 5\)
\(5 - \underline{\hspace{1.1 cm}} = 5\)
\(3 + \underline{\hspace{1.1 cm}} = 5\)
Student Response
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Activity Synthesis
Invite previously identified students to share.


aligns: no