few_shots: 
Example:
Problem/activity:
Problem 1
Solve using the standard algorithm. If you get stuck, use an area model and/or the partial products algorithm to help. Then assess the reasonableness of your answer.
a.
$$5,803\times46$$
b.
$$63\times2,116$$
Problem 2
Dunkin' introduced a croissant doughnut in 2014. In the first three months of its debut, they sold 7,870 dozen of them per day. How many croissant doughnuts were sold in the first three months?


Description: 
Fluently multiply multi-digit whole numbers using the standard algorithm.

Answer: 
Yes. This set of problems involves multi-digit whole numbers because the numbers in each problem are four and two digit integers, and the mathematical calculations involved in both problems focus on multiplication. The first problem explicitly asks the student to solve its subproblems using the standard algorithm.

Now, assess whether the following problem or activity aligns with the provided description.

shot_info: fl_problem_000674_pos_0

5
standard_description: Solve problems involving velocity and other quantities that can be represented by vectors.
problem_activity: Activity
The purpose of this activity is for students to extend what they learned about square roots and
\(\frac12\)
exponents to cube roots and
\(\frac13\)
exponents.
Launch
Tell students that they will use the same reasoning as in the previous activity to make sense of numbers to the
\(\frac12\)
power or
\(\frac13\)
power. Give a few minutes of quiet work time followed by a brief, whole-class discussion.
Action and Expression: Internalize Executive Functions.
To support development of organizational skills, check in with students within the first 2–3 minutes of work time. Check that students are finding the exact values and remind them of how they could use the exponent rules to check their answers if needed. Invite students to show their thinking by rewriting the fractional exponents.
Supports accessibility for: Memory; Organization
Student Facing
Use the exponent rules and your understanding of roots to find the exact value of:
\(25^{\frac12}\)
\(15^{\frac12}\)
\(8^{\frac13}\)
\(2^{\frac13}\)
Student Response
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for free access to Student Response.
Activity Synthesis
The key takeaway is that extending exponent rules to these fractions means that
\(b^{\frac12}=\sqrt{b}\)
and
\(b^{\frac13}=\sqrt[3]{b}\)
. Select students to share their responses for
\(15^{\frac12}\)
and
\(2^{\frac13}\)
.
Conclude the discussion by reminding students that these expressions which involve the
\(\sqrt{}\)
symbol are often called
radical
expressions because the technical name for the symbol is the
radix
(which is also where the word root comes from). Expressions like
\(\sqrt{15}\)
and
\(\sqrt[3]{2}\)
are examples of radical expressions.
Speaking: MLR8 Discussion Supports.
As students share their responses for
\(15^{\frac{1}{2}}\)
and
\(2^{\frac{1}{3}}\)
, press for details by asking how they know that
\(15^{\frac{1}{2}}\)
is equal to
\(\sqrt{15}\)
and
\(2^{\frac{1}{3}}\)
is equal to
\(\sqrt[3]{2}\)
. Also ask students which properties of exponents they used to show that the exponential and radical expressions are equivalent. Some students may benefit from the opportunity to rehearse what they will say with a partner before they share with the whole class. This will help students justify why
\(b^{\frac{1}{2}} = \sqrt{b}\)
and
\(b^{\frac{1}{3}} = \sqrt[3]{b}\)
.
Design Principle(s): Support sense-making; Optimize output (for justification)


aligns: no