few_shots: 
Example:
Problem/activity:
Narrative
The purpose of this activity is for students to create composite shapes and compose new shapes from composite shapes. For example, students may find that a rectangular prism can be made from four triangular prisms or from eight smaller cubes. Students then discover that they can combine two of the composed rectangular prisms to make a new rectangular prism.
Required Materials
Materials to Gather
Geoblocks
Launch
Groups of 4
Give each group geoblocks.
Display a large cube.
“This cube can be built from other shapes. See how many ways you can build a cube using other shapes.”
3 minutes: partner work time
Share responses.
Activity
“Choose a different shape. Try to find smaller shapes you can use to build that shape.”
5 minutes: partner work time
Student Response
Teachers with a valid work email address can
click here to register or sign in
for free access to Student Response.
Activity Synthesis
Display a cube and a composite cube—for example, a cube composed of four small cubes and one rectangular prism.
Demonstrate putting the shapes together.
“What new shape did I make with the cube and the cube I made?”
“Put your shapes together to make a rectangular prism.”
Display a rectangular prism and two triangular prisms.
“Find these shapes. Put them together. What new shape can you make?” (a cube, a rectangular block)


Description: 
Recognize area as an attribute of plane figures and understand concepts of area measurement.

Answer: 
No. This activity does not teach students area as an attribute of plane figures. Instead, the activity focuses on solid, three-dimensional figures.

Now, assess whether the following problem or activity aligns with the provided description.

shot_info: im_lesson_009431_neg_0

1
standard_description: Multiply a vector by a scalar.
problem_activity: Problem 1
Find
$${\mathrm{sin}(u-v)}$$
given
$${\mathrm{sin}(u)={8\over17}}$$
with
$${0\leq u \leq {\pi\over2}}$$
and
$${\mathrm{cos}(v)=-{24\over25}}$$
with
$${\pi \leq v \leq {3\pi\over2}}$$
.
Problem 2
Evaluate:
$${\mathrm{sin}(-15^{\circ})}$$
$${\mathrm{cos}(15^{\circ})}$$


aligns: no