few_shots: 
Example 1:
Problem/activity:
Find the general solution for:
$${\mathrm{cos}\left({\pi\over2}+x\right)=\mathrm{tan}{\pi\over4}}$$


Concept/skill: 
Understand that by similarity, side ratios in right triangles are properties of the angles in the triangle, leading to definitions of trigonometric ratios for acute angles.

Answer: 
No. This problem does not directly teach how side ratios in right triangles lead to definitions of trigonometric ratios. Instead, it involves solving a trigonometric function.

Example 2:
Problem/activity:
Task
Solve the quadratic equation
$$ x^2 = (2x - 9)^2 $$
using as many different methods as possible.


Concept/skill: 
Understand that the graph of an equation in two variables is the set of all its solutions plotted in the coordinate plane, often forming a curve (which could be a line).

Answer: 
No. This task does not involve an equation in two variables. There is only one variable, x.

Example 3:
Problem/activity:
Task
Suppose $A$ is an angle with vertex $P$, as pictured below:
[IMG]
Draw a circle with center $P$ and with  radius $r \gt 0$.  Explain why the circle
meets each ray of angle $A$ in a single point.  Label these points $Q$ and $R$ respectively.
Draw circles with centers $Q$ and $R$ respectively and radius $r$.  These circles meet at $P$ and a second point to be labelled $B$.
Show that ray $\overrightarrow{PB}$  bisects angle $P$.


Concept/skill: 
Construct a tangent line from a point outside a given circle to the circle.

Answer: 
No. This task does not involve drawing lines that are tangent to circles. The only line that may be drawn is the ray between points P and B.

Now, does the problem or activity shown below enable students to learn the full intent of the following concept or skill?

shot_info: fl_problem_001894_neg_0

HS_0

im_task_000870_neg_0

HS_1

im_task_001160_neg_0

HS_2
standard_description: Interpret the equation y = mx + b as defining a linear function, whose graph is a straight line; give examples of functions that are not linear. For example, the function A = s2 giving the area of a square as a function of its side length is not linear because its graph contains the points (1,1), (2,4) and (3,9), which are not on a straight line.
problem_activity: Problem 1
Determine the rate of change in each situation. Then describe the relationship using function language (for example, ____ is a function of ____ because _____.)
a.
{"table": [{"_attributes": {"class": ["table", "table-bordered"], "style": "width: 100%;"}, "tbody": [{"tr": [{"th": [{"_attributes": {"scope": "row"}, "_value": "Amt of watermelon in pounds,", "span": [{"_attributes": {"class": ["math-tex"]}, "_value": "$$x$$"}]}], "td": [{"_attributes": {"style": "text-align: center;"}, "_value": "0"}, {"_attributes": {"style": "text-align: center;"}, "_value": "0.25"}, {"_attributes": {"style": "text-align: center;"}, "_value": "0.5"}, {"_attributes": {"style": "text-align: center;"}, "_value": "1.5"}, {"_attributes": {"style": "text-align: center;"}, "_value": "2"}, {"_attributes": {"style": "text-align: center;"}, "_value": "3"}, {"_attributes": {"style": "text-align: center;"}, "_value": "5"}]}, {"th": [{"_attributes": {"scope": "row"}, "_value": "Cost of watermelon in dollars,", "span": [{"_attributes": {"class": ["math-tex"]}, "_value": "$$y$$"}]}], "td": [{"_attributes": {"style": "text-align: center;"}, "_value": "0"}, {"_attributes": {"style": "text-align: center;"}, "_value": "0.35"}, {"_attributes": {"style": "text-align: center;"}, "_value": "0.70"}, {"_attributes": {"style": "text-align: center;"}, "_value": "2.10"}, {"_attributes": {"style": "text-align: center;"}, "_value": "2.80"}, {"_attributes": {"style": "text-align: center;"}, "_value": "4.20"}, {"_attributes": {"style": "text-align: center;"}, "_value": "7.00"}]}]}]}]}
b.
$${d=25t}$$
, where
$$d$$
is distance in miles and
$$t$$
is time in hours
c.    Giovanni can decorate
$$2$$
cakes,
$$c$$
, every
$$5$$
hours,
$$h$$
.
Problem 2
Determine the starting or initial output value in each situation.
a.
{"table": [{"_attributes": {"align": "Center", "class": ["table", "table-bordered"], "style": "width:80%"}, "tbody": [{"tr": [{"td": [{"_attributes": {"style": "background-color:#eeeeee"}, "strong": [{"_value": "Distance traveled in cab in miles,", "em": [{"span": [{"_attributes": {"class": ["math-tex"]}, "_value": "$$x$$"}]}]}]}, {"_attributes": {"style": "text-align:center"}, "_value": "0"}, {"_attributes": {"style": "text-align:center"}, "_value": "1"}, {"_attributes": {"style": "text-align:center"}, "_value": "3"}, {"_attributes": {"style": "text-align:center"}, "_value": "4"}]}, {"td": [{"_attributes": {"style": "background-color:#eeeeee"}, "strong": [{"_value": "Cost of cab ride in dollars,", "em": [{"span": [{"_attributes": {"class": ["math-tex"]}, "_value": "$$y$$"}]}]}]}, {"_attributes": {"style": "text-align:center"}, "_value": "2.50"}, {"_attributes": {"style": "text-align:center"}, "_value": "4.75"}, {"_attributes": {"style": "text-align:center"}, "_value": "9.25"}, {"_attributes": {"style": "text-align:center"}, "_value": "11.50"}]}]}]}]}
b.
{"table": [{"_attributes": {"align": "Center", "class": ["table", "table-bordered"], "style": "width:80%"}, "tbody": [{"tr": [{"td": [{"_attributes": {"style": "background-color:#eeeeee"}, "strong": [{"_value": "Distance traveled in cab in miles,", "em": [{"span": [{"_attributes": {"class": ["math-tex"]}, "_value": "$$x$$"}]}]}]}, {"_attributes": {"style": "text-align:center"}, "_value": "1"}, {"_attributes": {"style": "text-align:center"}, "_value": "2"}, {"_attributes": {"style": "text-align:center"}, "_value": "4"}, {"_attributes": {"style": "text-align:center"}, "_value": "5"}]}, {"td": [{"_attributes": {"style": "background-color:#eeeeee"}, "strong": [{"_value": "Cost of cab ride in dollars,", "em": [{"span": [{"_attributes": {"class": ["math-tex"]}, "_value": "$$y$$"}]}]}]}, {"_attributes": {"style": "text-align:center"}, "_value": "4.50"}, {"_attributes": {"style": "text-align:center"}, "_value": "7.00"}, {"_attributes": {"style": "text-align:center"}, "_value": "12.00"}, {"_attributes": {"style": "text-align:center"}, "_value": "14.50"}]}]}]}]}
c.
$${p=16d+20}$$
where
$$p$$
is the total number of pages read in a book and
$$d$$
is the number of days
Problem 3
The function formula below shows the relationship between temperature in degrees Fahrenheit and degrees Celsius. °F is a function of °C.
$${F=\frac{9}{5}C+32}$$
a.   Determine what 28°C is in °F.
b.   Determine what 23°F is in °C.


aligns: no