Problem: x does a work in 40 days . y does the same work in 60 days . in how many days they together will do the same work ?
Rationale: "x ' s 1 day ' s work = 1 / 40 y ' s 1 day ' s work = 1 / 60 ( x + y ) ' s 1 day ' s work = ( 1 / 40 + 1 / 60 ) = 1 / 24 both together will finish the work in 24 days . correct option is c"
annotated_formula: inverse(add(divide(const_1, 40), divide(const_1, 60)))