Problem: the sum of the squares of three consecutive natural number is 2030 . what is the middle number ?
Rationale: "let the numbers be x , x + 1 and x + 2 x 2 + ( x + 1 ) 2 + ( x + 2 ) 2 = 2030 3 x 2 + 6 x - 2025 = 0 ( x + 27 ) ( x - 25 ) = 0 x = 25 the middle number is 26 answer b 26"
annotated_formula: divide(subtract(sqrt(add(multiply(subtract(2030, const_1), const_4), const_1)), const_1), const_2)