Problem: 3 friends james , david and charlie divide $ 1230 amongs them in such a way that if $ 5 , $ 10 and $ 15 are removed from the sums that james , david and charlie received respectively , then the share of the sums that they got will be in the ratio of 9 : 10 : 11 . how much did charlie receive ?
Rationale: a + b + c = 1230 given ratio 9 : 10 : 11 let us say the shares of a , b , c deducting 5 , 1015 be a , b , c a + b + c = 1230 - 30 = 1200 = 30 k c share = ( 1200 x 30 ) / 60 = 600 c = charlie share = 600 + 15 = 615 option e
annotated_formula: add(add(add(add(add(multiply(11, divide(subtract(1230, add(add(5, 10), 15)), add(add(9, 10), 11))), 15), divide(subtract(1230, add(add(5, 10), 15)), add(add(9, 10), 11))), divide(subtract(1230, add(add(5, 10), 15)), add(add(9, 10), 11))), divide(subtract(1230, add(add(5, 10), 15)), add(add(9, 10), 11))), divide(subtract(1230, add(add(5, 10), 15)), add(add(9, 10), 11)))