Problem: chris age after 20 years will be 5 times his age 5 years back . what is the present age of chris ?
Rationale: chris present age = x after 20 years = x + 20 5 years back = x - 5 x + 20 = 5 ( x - 5 ) x = 5 answer is e
annotated_formula: subtract(divide(add(multiply(5, 5), 20), subtract(5, const_1)), subtract(divide(add(multiply(5, 5), 20), subtract(5, const_1)), 5))