Problem: how many three - digit numbers are divisible by 6 in all ?
Rationale: "solution required numbers are 102 , 018,114 , . . . . 996 . this is an a . p with a = 102 , d = 6 . let the number of its terms be n . then a + ( n - 1 ) d ‹ = › 102 + ( n - 1 ) × 6 = 996 ‹ = › n = 150 . answer b"
annotated_formula: add(multiply(const_100, 6), const_100)