Problem: a man walking at a constant rate of 12 miles per hour is passed by a woman traveling in the same direction along the same path at a constant rate of 24 miles per hour . the woman stops to wait for the man 10 minutes after passing him , while the man continues to walk at his constant rate . how many minutes must the woman wait until the man catches up ?
Rationale: "when the woman passes the man , they are aligned ( m and w ) . they are moving in the same direction . after 5 minutes , the woman ( w ) will be ahead the man ( m ) : m - - - - - - m - - - - - - - - - - - - - - - w w in the 5 minutes , after passing the man , the woman walks the distance mw = ww , which is 10 * 24 / 60 = 4 miles and the man walks the distance mm , which is 10 * 12 / 60 = 2 mile . the difference of 4 - 2 = 2 miles ( mw ) will be covered by the man in ( 2 ) / 9 = 2 / 9 of an hour , which is ~ 13 minutes . answer a ."
annotated_formula: multiply(const_60, divide(multiply(divide(10, const_60), subtract(24, 12)), 12))