Problem: a is two years older than b who is twice as old as c . if the total of the ages of a , b and c be 37 , the how old is b ?
Rationale: explanation : let c ' s age be x years . then , b ' s age = 2 x years . a ' s age = ( 2 x + 2 ) years . ( 2 x + 2 ) + 2 x + x = 37 ⇒ 5 x = 35 ⇒ x = 7 . hence , b ' s age = 2 x = 14 years . answer : d
annotated_formula: divide(multiply(subtract(37, const_2), const_2), add(const_4, const_1))