Problem: the average of 5 consecutive odd numbers a , b , c , d and e is 33 . what percent of a is d ?
Rationale: explanation : in such a case the middle number ( c ) is the average ∴ c = 33 and a = 31 and d = 35 required percentage = 31 / 35 x 100 = 88.6 answer : option b
annotated_formula: multiply(const_100, divide(divide(multiply(33, 5), 5), add(add(add(divide(multiply(33, 5), 5), const_2), const_2), const_2)))