Problem: what is the area inscribed by the lines y = 4 , x = 2 , y = 6 - 2 x on an xy - coordinate plane ?
Rationale: "first , let ' s graph the lines y = 4 and x = 2 at this point , we need to find the points where the line y = 6 - 2 x intersects the other two lines . for the vertical line , we know that x = 2 , so we ' ll plug x = 2 into the equation y = 6 - 2 x to get y = 6 - 2 ( 2 ) = 2 perfect , when x = 2 , y = 2 , so one point of intersection is ( 2,2 ) for the horizontal line , we know that y = 4 , so we ' ll plug y = 4 into the equation y = 6 - 2 x to get 4 = 6 - 2 x . solve to get : x = 1 so , when y = 4 , x = 1 , so one point of intersection is ( 1,4 ) now add these points to our graph and sketch the line y = 6 - 2 x at this point , we can see that we have the following triangle . the base has length 1 and the height is 2 area = ( 1 / 2 ) ( base ) ( height ) = ( 1 / 2 ) ( 1 ) ( 2 ) = 1 answer : a"
annotated_formula: multiply(subtract(subtract(6, 4), 4), multiply(multiply(4, const_0_25), subtract(subtract(6, 4), 4)))