Problem: compute all real solutions to 16 x + 4 x + 1 - 96 = 0
Rationale: if we substitute y = 4 x , we have y 2 + 4 y - 96 = 0 , so y = - 4 or y = 8 . the first does not map to a real solution , while the second maps to x = 3 / 2 correct answer a
annotated_formula: divide(subtract(4, 1), subtract(subtract(4, 1), 1))