Problem: 50 men shake hands with each other . maximum no of handshakes without cyclic handshakes .
Rationale: total no . of handshakes = 49 + 48 + 47 + . . . + 3 + 2 + 1 = 19 * ( 19 + 1 ) / 2 = 1225 or , if there are n persons then no . of shakehands = nc 2 = 50 c 2 = 1225 answer : c
annotated_formula: multiply(subtract(50, const_1), divide(50, const_2))