Problem: 4 liters of a 25 percent solution of alcohol in water are mixed with 3 liters of a 11 percent alcohol in water solution . what is the percentage of alcohol in the new solution ?
Rationale: "the total amount of alcohol is 0.25 ( 4 ) + 0.11 ( 3 ) = 1.33 liters . the percentage is 1.33 / 7 = 133 / 700 = 19 / 100 which is 19 % the answer is c ."
annotated_formula: multiply(divide(add(multiply(4, divide(25, const_100)), multiply(divide(11, const_100), multiply(4, divide(25, const_100)))), add(4, 3)), const_100)