Problem: | x + 3 | – | 4 - x | = | 8 + x | how many s solutions will this equation have ?
Rationale: "| x | = x when x > = 0 ( x is either positive or 0 ) | x | = - x when x < 0 ( note here that you can put the equal to sign here as well x < = 0 because if x = 0 , | 0 | = 0 = - 0 ( all are the same ) so the ' = ' sign can be put with x > 0 or with x < 0 . we usually put it with ' x > 0 ' for consistency . a"
annotated_formula: divide(multiply(add(4, 3), const_2), 8)