Problem: let f ( x ) = x ^ 2 + bx + c . if f ( 3 ) = 0 and f ( - 3 ) = 0 , then b + c =
Rationale: "f ( x ) = x ^ 2 + bx + c . if f ( 3 ) = 0 and f ( - 3 ) = 0 , then b + c = f ( 3 ) = 0 = 9 + 3 b + c - - - taking 9 to the other side - > 3 b + c = - 9 f ( - 3 ) = 0 = 9 - 3 b + c - - - taking - 3 b + c to the other side - > 3 b - c = 9 when we add these 2 equations , we get 6 b = 0 - - - > b = 0 and while substituting b = 0 we get c = - 9 . b + c = - 9 - - - answer e"
annotated_formula: negate(divide(subtract(power(3, 2), 3), add(3, 3)))