Problem: what is the length of the diagonal of a square whose area is 4 times of another square with diagonal as 5 v 2 cm ?
Rationale: solution : 10 v 2 area of square = 1 / 2 * ( length of diagonal ) 2 area of square 1 = * ( 5 v 2 ) 2 = 25 area of square 2 = 4 * 25 = 100 length of diagonal of square 2 = v 2 * area = v 2 * 100 = v 200 = 10 v 2 cm answer is c
annotated_formula: multiply(const_10, sqrt(2))