Problem: the ages of two persons differ by 16 years . if 6 years ago , the elder one be 3 times as old as the younger one , find their present ages .
Rationale: "explanation : sol . let the age of the younger person be xx years then , age of the elder person = ( x + 16 ) ( x + 16 ) years â ˆ ´ â ˆ ´ 3 ( x â ˆ ’ 6 ) = ( x + 16 â ˆ ’ 6 ) 3 ( x - 6 ) = ( x + 16 - 6 ) â ‡ ” 3 x â ˆ ’ 18 = x + 10 â ‡ ” 3 x - 18 = x + 10 â ‡ ” 2 x = 28 â ‡ ” 2 x = 28 â ‡ ” x = 14 â ‡ ” x = 14 hence , their present age are 14 years and 30 years . answer is d"
annotated_formula: subtract(add(divide(multiply(16, 6), subtract(6, const_1)), 6), 16)