Problem: if a square mirror has a 20 - inch diagonal , what is the approximate perimeter t of the mirror , in inches ?
Rationale: "if you draw the square and diagonal inside the square . u can see square becomes part of two triangles opposite to each other . and we know the property of the triangle , addition of two sides of triangle must be greater than its diagonal in order to complete the triangle . and each side must be less than 20 and perimeter t must be less than 80 , so we can eliminate answer choice c , d and e . so side 1 + side 2 > 20 , that means side 1 or side 2 must be > 10 . so we can eliminate the answer choice a . now we are left with is b"
annotated_formula: square_perimeter(divide(20, power(add(const_1, const_1), inverse(const_2))))