Problem: what is the greater of the two numbers whose product is 2496 , given that the sum of the two numbers exceeds their difference by 64 ?
Rationale: "let the greater and the smaller number be g and s respectively . gs = 2496 g + s exceeds g - s by 64 i . e . , g + s - ( g - s ) = 64 i . e . , 2 s = 64 = > s = 32 . g = 2496 / s = 78 . answer : d"
annotated_formula: divide(2496, multiply(power(const_2, const_4), const_2))