Problem: one pump drains one - half of a pond in 1 hours , and then a second pump starts draining the pond . the two pumps working together finish emptying the pond in one - half hour . how long would it take the second pump to drain the pond if it had to do the job alone ?
Rationale: "the tricky part here , i believed is one half hour = 1 / 2 . then everything would be easy . we have the 1 st pump working rate / hour = 1 / 2 : 1 = 1 / 2 working rate of 2 pumps : 1 / 2 : 1 / 2 = 1 . working rate of 2 nd pump : 1 - 1 / 2 = 1 / 2 - - > time taken for the 2 nd pump to finish : 1 : 1 / 2 = 2 / 1 = 2 hours . c"
annotated_formula: divide(const_1, subtract(const_1, divide(const_1, multiply(1, const_2))))