Problem: x varies inversely as square of y . given that y = 3 for x = 1 . the value of x for y = 5 will be equal to :
Rationale: "explanation : solution : given x = k / y ^ 2 , where k is constant . now , y = 3 and x = 1 gives k = 9 . . ' . x = 9 / y ^ 2 = > x = 9 / 5 ^ 2 = 9 / 25 answer : e"
annotated_formula: divide(multiply(1, power(3, const_2)), power(5, const_2))