Problem: a man and a boy complete a work together in 24 days . if for the last 6 days man alone does the work then it is completed in 26 days . how long the boy will take to complete the work alone ?
Rationale: explanation : ( man + boy ) ’ s 1 day ’ s work = 1 / 24 their 20 day ’ s work = 1 / 24 × 20 = 5 / 6 the remaining 1 / 6 work is done by the man in 6 days therefore , the man alone will finish the work in 6 × 6 days = 36 days man ’ s 1 day ’ s work = 1 / 36 therefore , boy ’ s 1 day ’ s work = 1 / 24 – 1 / 36 = 3 – 2 / 72 = 1 / 72 therefore , the boy alone will finish the work in 72 days . answer : option a
annotated_formula: add(subtract(26, 6), multiply(26, const_2))