Problem: a and b together can complete work in 10 days . a alone starts working and leaves it after working for 6 days completing only half of the work . in how many days it can be completed if the remaining job is undertaken by b ?
Rationale: "explanation : ( a + b ) one day work = 1 / 10 now a does half of the work in 6 days so a can complete the whole work in 12 days a ’ s one day work = 1 / 12 b ’ s one day work = 1 / 10 - 1 / 12 = 2 / 120 = 1 / 60 b alone can complete the work in 60 days so half of the work in 30 days answer : option e"
annotated_formula: multiply(10, divide(6, 10))