Problem: if n is an integer and 101 n ^ 2 is less than or equal to 10000 , what is the greatest possible value of n ?
Rationale: "101 * n ^ 2 < = 10000 n ^ 2 < = 10000 / 101 which will be less than 100 since 10000 / 100 = 100 which is the square of 9 next closest value of n where n ^ 2 < = 100 is 9 ans c"
annotated_formula: floor(sqrt(divide(10000, 101)))