Problem: two numbers are less than third number by 30 % and 37 % respectively . how much percent is the second number less than by the first
Rationale: "let the third number is x . then first number = ( 100 - 30 ) % of x = 70 % of x = 7 x / 10 second number is ( 63 x / 100 ) difference = 7 x / 10 - 63 x / 100 = 7 x / 10 so required percentage is , difference is what percent of first number ( 7 x / 100 * 10 / 7 x * 100 ) % = 10 % answer : b"
annotated_formula: subtract(multiply(divide(subtract(37, 30), subtract(const_100, 30)), const_100), const_10)