Problem: what is the remainder when 1250 * 1040 * 1057 * 1145 is divided by 32 ?
Rationale: "oa is ' c ' . oe : take the remainder from each of 1250 / 32 , 1040 / 32 and so on . . 1250 / 32 gives remainder = 2 1040 / 32 gives remainder = 16 1057 / 32 gives remainder = 1 1145 / 32 gives remainder = 25 the net remainder is the product of above individual remainders . i . e = 2 * 16 * 1 * 25 break them into pairs 2 * 16 / 32 gives remainder 0 and 1 * 25 / 32 gives remainder 25 so 0 * 25 / 32 gives remainder 0 . answer : c"
annotated_formula: reminder(multiply(1040, 1250), 1057)