Problem p02679 (C++) — buggy submission, verdict: Runtime Error

#include <algorithm>
#include <bits/stdc++.h>
#include <cassert>
#include <complex>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <deque>
#include <iostream>
#include <list>
#include <map>
#include <queue>
#include <set>
#include <sstream>
#include <stack>
#include <stdio.h>
#include <string>
#include <vector>
using namespace std;
typedef long long ll;
typedef long double ld;
using edge = struct {
  ll to;
  ll cost;
};
struct point {
  ll x;
  ll y;
  bool operator<(const point &p) const {
    if (x == p.x)
      return y < p.y;
    return x < p.x;
  }
};
struct undirected_edge {
  ll from;
  ll to;
  ll cost;
  bool operator<(const undirected_edge &ue) const { return cost < ue.cost; }
};

typedef string str;
typedef std::pair<ll, ll> pl;
typedef std::pair<ll, pl> pl3;
typedef std::map<string, ll> msl;
typedef std::map<char, ll> mcl;
typedef std::map<ll, ll> mll;
typedef std::vector<ll> vl;
typedef std::vector<pl> vpl;
typedef std::vector<point> points;
typedef std::vector<pl3> vpl3;
typedef std::priority_queue<ll> pq;
typedef std::priority_queue<ll, vl, greater<ll>>
    pql; // priority queue taking from the lower value.
typedef std::vector<edge> Graph;
const ll N_DIGITS = 60;
const ll MOD = 1e9 + 7;
// const ll MOD = 998244353;
const ll INF = MOD * MOD;
const long double EPS = 1e-9;
const long double PI = 3.14159265358979323846;
vpl dirs = {
    {1, 0}, {0, 1},  {-1, 0},  {0, -1}, // four directions
    {1, 1}, {-1, 1}, {-1, -1}, {1, -1}, // diagonal
    {0, 0}                              // self
};

#define rep(i, n) for (ll(i) = 0; (i) < (n); (i)++)
#define revrep(i, n) for (ll(i) = n - 1; (i) >= 0; (i)--)
#define For(i, a, b) for (ll(i) = (a); (i) < (b); (i)++)
#define revFor(i, b, a) for (ll(i) = (b)-1; (i) >= (a); (i)--)
#define all(a) (a).begin(), (a).end()
#define rall(a) (a).rbegin(), (a).rend()
#define isUpper(c) ('a' - c > 0)
#define isNum(c) (0 <= (c) - '0' && (c) - '0' <= 9)
#define toLower(c) char((c) + 0x20)
#define toUpper(c) char((c)-0x20)
#define pb push_back
#define mp make_pair
#define pr(a) cout << (a)
#define prl(a) cout << (a) << endl
#define prl2(a, b) cout << (a) << " " << (b) << endl
#define prl3(a, b, c) cout << (a) << " " << (b) << " " << (c) << endl
#define prl4(a, b, c, d)                                                       \\
  cout << (a) << " " << (b) << " " << (c) << " " << (d) << endl
#define prs(a) cout << (a) << " "
#define yn(condition)                                                          \\
  if ((condition))                                                             \\
    prl("Yes");                                                                \\
  else                                                                         \\
    prl("No");
#define YN(condition)                                                          \\
  if ((condition))                                                             \\
    prl("YES");                                                                \\
  else                                                                         \\
    prl("NO");
#define in1(a) cin >> (a)
#define in2(a, b) cin >> (a) >> (b)
#define in3(a, b, c) cin >> (a) >> (b) >> (c)
#define in4(a, b, c, d) cin >> (a) >> (b) >> (c) >> (d)
#define e1 first
#define e2 second
#define ctol(c) ll((c)) - ll('0')
#define ltos(n) to_string((n))
#define items(kv, v) for (auto &(kv) : (v))
#define ndig(N, n) ctol(ll(ltos((N))[ll(ltos((N)).length()) - (n)]))
#define rsort(a, n) sort(a, a + n, greater<>())
#define Forchar(c, a, z) for (char(c) = (a); (c) <= (z); (c)++)
#define cntchar(s, c) count(all((s)), c)
#define substring(s, start, end) s.substr((start), (end) - (start) + 1)
#define prl_nd(num, digits)                                                    \\
  cout << fixed << setprecision(digits) << (num) << endl;
#define XOR(a, b) (a) ^ (b)
#define prl_time(s)                                                            \\
  prl3("Elapsed Time:", 1000.0 * (clock() - s) / CLOCKS_PER_SEC, "[ms]");
#define char_to_str(c) string(1, (c))
#define DEBUG(x) cerr << #x << ": " << (x) << endl
#define DEBUG_VEC(v)                                                           \\
  cerr << #v << ": ";                                                          \\
  rep(__i, (v).size()) cerr << ((v)[__i]) << ", ";                             \\
  cerr << endl

struct MaxFlow {
  struct F_edge {
    ll to, rev, capacity;
    F_edge(ll to, ll rev, ll capacity) : to(to), rev(rev), capacity(capacity) {}
  };

  typedef vector<F_edge> F_edges;
  vector<F_edges> graph;
  ll n_vertex;
  // level is the shortest path to get a given node from the source node.
  vl level, iter;

  MaxFlow(ll n_vertex) : n_vertex(n_vertex) { graph.resize(n_vertex); }

  void add_edge(ll from, ll to, ll capacity) {
    graph[from].pb({to, ll(graph[to].size()), capacity});
    graph[to].pb({from, ll(graph[from].size()) - 1, 0});
  }

  void bfs(ll source) {
    level = vl(n_vertex, -1);
    level[source] = 0;
    queue<ll> q;
    q.push(source);
    while (!q.empty()) {
      ll vertex = q.front();
      q.pop();
      rep(i, graph[vertex].size()) {
        ll target = graph[vertex][i].to;
        ll cap_target = graph[vertex][i].capacity;
        // if the flow can be into the target node, implement below.
        if (cap_target > 0 && level[target] < 0) {
          level[target] = level[vertex] + 1;
          q.push(target);
        }
      }
    }
  }

  ll dfs(ll vertex, ll sink, ll flow) {
    if (vertex == sink)
      return flow;
    for (ll &i = iter[vertex]; i < graph[vertex].size(); i++) {
      ll target = graph[vertex][i].to;
      ll cap_target = graph[vertex][i].capacity;
      ll rev_target = graph[vertex][i].rev;
      // if capasitiy is not full yet and target is farther,
      // then assign current flow
      if (cap_target > 0 && level[vertex] < level[target]) {
        ll d = dfs(target, sink, min(cap_target, flow));
        if (d > 0) { // if the flow successfully reaches the sink, reduce the
                     // flow from the capacity
          graph[vertex][i].capacity -= d;
          graph[target][rev_target].capacity += d;
          return d;
        }
      }
    }
    return 0;
  }

  ll dinic(ll source, ll sink) {
    ll flow = 0;
    while (true) {
      bfs(source);
      // if there is no path leading to the sink, the maximum flow is 0.
      if (level[sink] < 0)
        return flow;
      iter = vl(n_vertex, 0);
      ll f;
      while ((f = dfs(source, sink, INF)) > 0)
        flow += f;
    }
  }
};

class UnionFind {
  vl parents, set_size;

public:
  UnionFind() {}
  UnionFind(ll n) {
    parents = set_size = vl(n);
    rep(i, n) {
      parents[i] = i;
      set_size[i] = 1LL;
    }
  }

  ll root_find(ll x) {
    if (parents[x] == x)
      return x;
    return parents[x] = root_find(parents[x]);
  }

  void unite(ll x, ll y) {
    // priority for x is larger than that of y
    x = root_find(x);
    y = root_find(y);
    if (x == y)
      return;
    if (set_size[x] < set_size[y]) {
      parents[y] = x;
      set_size[x] += set_size[y];
    } else {
      parents[x] = y;
      set_size[y] += set_size[x];
    }
  }

  bool is_same(ll x, ll y) { // connected or not
    return root_find(x) == root_find(y);
  }

  ll size(ll x) { return set_size[root_find(x)]; }
};

struct Doubling { // ABC167D
  ll n;
  ll sz;
  vector<vl> next;
  /*
      next[k + 1][i] := next[k][next[k][i]]
      next[0][i] := edge[i]
      e.g. a0, a1, ..., an-1 / 0 <= ai <= n - 1
      a0 -> a[a0] -> a[a[a0]] -> ... -> a[a[...[a[0]]]] (m times)
      Let the function repeatedly input a[i] m times be f[m](a[i])

      - get(i, x) returns f[x](a[i])
      - lower_bound(i, j) returns minimum x which satisfies f[x](a[i]) >= j.
                                  if not possible returns n.

  */

  // edge[i]: the step size for one iteration
  Doubling(vl &edge) : n(edge.size()), sz(62) {
    next.resize(sz, vl(n, -1));
    rep(i, n) next[0][i] = edge[i];
    rep(k, sz - 1) rep(i, n) next[k + 1][i] = next[k][next[k][i]];
  }

  ll get(ll i, ll x) {
    ll ret = i;
    rep(bit, sz) {
      if (!(x >> bit & 1))
        continue;
      ret = next[bit][ret];
    }
    return ret;
  }

  ll lower_bound(ll i, ll j) {
    ll cur = i, acc = 0;
    revrep(wid, sz) {
      if (next[wid][cur] < j) {
        acc += 1LL << wid;
        cur = next[wid][cur];
      }
    }
    return min(n, acc + 1);
  }
};

/*
class LCA{
public:
    ll N, logN;
    vl depth, len;
    Graph tree[200005]; // global declaration later.
    vector<vl> parents;

    LCA(ll n){
        N = n;
        logN = 0;
        while (N > (1LL << logN)) logN++;
        depth = vl(N); len = vl(N);
        parents = vector<vl>(logN, vl(N));
        init(0, -1, 0, 0);
        build();
    }

    void init(ll source, ll parent, ll d, ll l){
        depth[source] = d;
        parents[0][source] = parent;
        len[source] = l;
        rep(i, tree[source].size()){
            ll target = tree[source][i].to;
            ll cost = tree[source][i].cost;
            if (target == parent) continue;
            init(target, source, d + 1, cost + l);
        }
    }

    void build(){
        rep(k, logN - 1) rep(n, N){
            // if there is no parent, -1.
            // otherwise, the parent of the parent is the parent.
            if (parents[k][n] < 0) parents[k + 1][n] = -1;
            else parents[k + 1][n] = parents[k][parents[k][n]];
        }
    }

    ll query(ll u, ll v){
        if (depth[u] > depth[v]) swap(u, v);
        rep(k, logN) if ((depth[v] - depth[u]) >> k & 1) v = parents[k][v];
        if (u == v) return u;

        revrep(k, logN){
            if (parents[k][u] != parents[k][v]){
                u = parents[k][u]; v = parents[k][v];
            }
        }
        return parents[0][u];
    }

    ll distance(ll u, ll v){
        ll w = query(u, v);
        return len[u] + len[v] - 2 * len[w];
    }

};
*/

struct BIT {
  ll n;
  vl tree_dat;
  BIT(ll n, ll ini = 0) : tree_dat(n + 1, ini), n(n){};

  //       x: 1001 1010  1100 1011 1101  1111
  // x & - x: 0001 0010  0100 0001 0001  0001
  //      ->: 1010 1100 10000 1100 1100 10000

  ll update_func(ll val, ll dat) {
    // if maximum -> max(val, dat)
    // return max(val, dat);
    // if cumulative sum
    // return val + dat;
    return min(val, dat);
  }

  ll query(ll i) {
    /*
    e.g.) i = 10101
    itr1. 10101 -> 10100
    itr2. 10100 -> 10000
    itr3. 10000 -> 00000 (break)
    */
    ll ret = 0;
    for (ll j = i; j >= 0; j = (j & (j + 1)) - 1) {
      ret = update_func(ret, tree_dat[j]);
    }
    return ret;
  }

  ll lower_bound(ll key) {
    if (key <= 0)
      return 0;
    ll left = 0, right = 1;
    while (right <= n)
      right *= 2;

    for (ll i = right; i > 0; i /= 2) {
      if (left + i <= n && tree_dat[left + i - 1] < key) {
        key -= tree_dat[left + i - 1];
        left += i;
      }
    }
    return left;
  }

  void update(ll i, ll val) {
    /*
    e.g.) i = 10101, n = 11111
    itr1. i: 10101, i+1: 10110 -> 10111
    itr2. i: 10111, i+1: 11000 -> 11111 (break)
    */
    if (i < 0)
      return;
    for (ll j = i; j < n; j |= j + 1) {
      tree_dat[j] = update_func(val, tree_dat[j]);
    }
  }
};

template <class Target> class RerootingTreeDP {
public:
  using T = typename Target::type;
  struct DP_edge {
    ll to, rev; // rev is the index to trace the source node.
    T value;    // objective value
  };

private:
  ll n;
  void dfs_fwd(ll source, ll parent) {
    ll par_idx = -1;
    vector<T> values;
    rep(i, tree[source].size()) {
      const DP_edge &e = tree[source][i];
      if (e.to == parent) {
        par_idx = i;
        continue;
      }
      dfs_fwd(e.to, source);
      values.pb(e.value);
    }

    // If the parent != -1, update the value on edge from parent to source
    if (par_idx != -1) {
      ll src_idx = tree[source][par_idx].rev;
      // update values on the edge from parent to source
      tree[parent][src_idx].value = Target::merge(values);
    }
  }

  void dfs_bwd(ll source, ll parent) {
    vector<T> values;
    for (auto &&e : tree[source])
      values.pb(e.value);
    values = Target::evaluate(values);

    rep(i, tree[source].size()) {
      const DP_edge &e = tree[source][i];
      if (e.to == parent)
        continue;
      // tree[e.to][e.rev]: e.to -> source
      tree[e.to][e.rev].value = values[i];
      dfs_bwd(e.to, source);
    }
  }

public:
  UnionFind uf;
  vector<vector<DP_edge>> tree;
  RerootingTreeDP(ll n) : n(n), uf(n), tree(n) {}

  void add_edge(ll u, ll v, T val) {
    assert(!uf.is_same(u, v));
    tree[u].pb({v, ll(tree[v].size()), val});
    tree[v].pb({u, ll(tree[u].size()) - 1, val});
    uf.unite(u, v);
  }

  void dp() {
    vector<bool> visited(n, false);
    rep(i, n) {
      if (visited[uf.root_find(i)])
        continue;
      dfs_fwd(i, -1);
      visited[uf.root_find(i)] = true;
    }

    visited.assign(n, false);
    rep(i, n) {
      if (visited[uf.root_find(i)])
        continue;
      dfs_bwd(i, -1);
      visited[uf.root_find(i)] = true;
    }
  }

  ll size() const { return tree.size(); }
};

// ABC160F is one example
// Modify the functions evaluate and merge based on given problems
struct Merger {
  using type = ll;

  static vector<type> evaluate(const vector<type> &value) {
    const ll n = value.size();
    vl L(n + 1, 1), R(n + 1, 1);
    rep(i, n) L[i + 1] = (L[i] * value[i]) % MOD;
    revrep(i, n) R[i] = (R[i + 1] * value[i]) % MOD;

    vl ret(n);
    /*
    ret[i] = v[c0] * v[c1] * ... * v[ci-1] * v[ci+1] * ... * v[cn-1]
    ci: the i-th child

    Let's consider the case where the root of a given tree is 0. (0-indexed)
    Here, we try to obtain the objective values for the edges from children to
    parent. When we change the root of the tree into another, the parent node
    here also changes the family structure. Since each node has ONLY one parent
    and zero or one or multiple children, the value for edge on child i to
    source is obtained using the value from source to child j. Here j is all the
    integers which is not i.

    In this case, child i is grandparent of child j for all j and
    the computation for the value from child i to source is O(N) when we use
    cumulative sum or product.
    */
    rep(i, n) ret[i] = (L[i] * R[i + 1]) % MOD;

    return ret;
  }

  static type merge(const vector<type> &value) {
    ll ret;
    for (auto &&v : value) {
    }
    return ret;
  }
};

ll gcd(ll m, ll n) {
  ll a = max(m, n);
  ll b = min(m, n);
  while (b != 1 && b != 0) {
    a %= b;
    swap(a, b);
  }
  return b == 1 ? 1 : a;
}

ll lcm(ll m, ll n) { return m / gcd(m, n) * n; }

template <class T> inline bool chmax(T &a, T b) {
  if (a < b) {
    a = b;
    return true;
  }
  return false;
}

template <class T> inline bool chmin(T &a, T b) {
  if (a > b) {
    a = b;
    return true;
  }
  return false;
}

ll power_mod(ll a, ll power, ll mod) {
  ll value = 1;
  while (power != 0) {
    if (power & 1)
      value = (value * a) % mod;
    a = (a * a) % mod;
    power = power >> 1;
  }
  return value % mod;
}

ll modinv(ll a, ll mod) { return power_mod(a, mod - 2, mod); }

ll power_normal(ll a, ll power) {
  ll value = 1;
  while (power != 0) {
    if (power & 1)
      value = value * a;
    a = a * a;
    power = power >> 1;
  }
  return value;
}

ll comb_memo[55][55];

ll pascal_triangle(ll n) {
  comb_memo[0][0] = 1;
  For(i, 1, n + 1) rep(j, i + 1) {
    comb_memo[i][j] += comb_memo[i - 1][j];
    if (j > 0)
      comb_memo[i][j] += comb_memo[i - 1][j - 1];
  }
}

ll combination(ll n, ll r, ll mod) {
  if (n == r && n == 0)
    return 1;
  else if (n <= 0 || r < 0 || r > n)
    return 0;
  ll numerator = 1;
  ll denomenator = 1;
  for (ll i = 0; i < r; i++) {
    ll num = (n - i) % mod, den = (i + 1) % mod;
    (numerator *= num) %= mod;
    (denomenator *= modinv(den, mod)) %= mod;
  }

  return (numerator * denomenator) % mod;
}

ll combination_no_mod(ll n, ll r) {
  if (n == r && n == 0)
    return 1;
  else if (n <= 0 || r < 0 || r > n)
    return 0;
  ll numerator = 1;
  ll denomenator = 1;
  for (ll i = 0; i < r; i++) {
    numerator *= n - i;
    denomenator *= i + 1;
    ll g = gcd(numerator, denomenator);
    numerator /= g;
    denomenator /= g;
  }

  return numerator;
}

ld log_combination(ll n, ll r) {
  if (n == r && n == 0)
    return 0;
  else if (n <= 0 || r < 0 || r > n)
    return -INF;
  ld val = 0;
  for (ll i = 0; i < r; i++) {
    val += log(n - i);
    val -= log(i + 1);
  }

  return val;
}

ll bin_search(ll key, ll A[], ll left, ll right) {
  // return the index idx where A[idx] = key.
  // A[left] is start and A[right] is end..
  // In other words, A[right], not A[right - 1], must be defined.
  while (right >= left) {
    ll mid = left + (right - left) / 2;
    if (A[mid] == key)
      return mid;
    else if (A[mid] > key)
      right = mid - 1;
    else if (A[mid] < key)
      left = mid + 1;
  }
  return -1;
}

/*
ll bin_search_temp(ll left, ll right, callable judge){
    while(right > left){
        // when seeking lower bound
        ll mid = (right + left) / 2;
        if (judge(mid)) right = mid;
        else left = mid + 1;
        // when seeking upper bound
        ll mid = (right + left + 1) / 2;
        if (judge(mid)) left = mid;
        else right = mid - 1;
    }

    return right;
}

trinary_search

// Care the value EPS!!! Compare to the condition
ld left = 0; ld right = p;
while(abs(right - left) > EPS){
    ld left2 = (2 * left + right) / 3.0;
    ld right2 = (left + 2 * right) / 3.0;
    ld f1 = tak_func(left2);
    ld f2 = tak_func(right2);
    if (f1 <= f2) right = right2;
    else if (f2 <= f1) left = left2;
}

*/

str bin_expression(ll n, ll dig) {
  str s = "";
  rep(i, dig) {
    s += ltos(n % 2);
    n /= 2;
  }
  reverse(all(s));
  return s;
}

ll lower_bound_bin_search_temp(ll key, ll A[], ll left, ll right) {
  // Pay attention to the return value -1.
  // For example, sometimes you may want the value right instead of -1.
  if (A[left] >= key)
    return left;
  ll mid = left + (right - left) / 2;

  while (right >= left) {
    mid = left + (right - left) / 2;
    if (mid == left) {
      if (A[left] < key && key <= A[left + 1])
        return left + 1;
      else
        return -1;
    }
    if (A[mid - 1] < key && key <= A[mid])
      return mid;
    else if (A[mid - 1] >= key)
      right = mid - 1;
    else if (A[mid] < key)
      left = mid;
  }

  return -1; // all the elements < key
}

ll inf_bin_search_temp(ll key, ll A[], ll left, ll right) {
  // Pay attention to the return value -1.
  // For example, sometimes you may want the value right instead of -1.
  if (A[left] > key)
    return left;
  ll mid = left + (right - left) / 2;

  while (right >= left) {
    mid = left + (right - left) / 2;
    if (mid == left) {
      if (A[left] <= key && key < A[left + 1])
        return left + 1;
      else
        return -1;
    }
    if (A[mid - 1] <= key && key < A[mid])
      return mid;
    else if (A[mid - 1] > key)
      right = mid - 1;
    else if (A[mid] <= key)
      left = mid;
  }

  return -1; // all the elements <= key
}

ll upper_bound_bin_search_temp(ll key, ll A[], ll left, ll right) {
  // Pay attention to the return value -1.
  // For example, sometimes you may want the value left instead of -1.
  if (A[right] <= key)
    return right;
  ll mid = left + (right - left) / 2;

  while (right >= left) {
    mid = left + (right - left) / 2;
    if (mid == right) {
      if (A[right - 1] <= key && key < A[right])
        return right - 1;
      else
        return -1;
    }
    if (A[mid] <= key && key < A[mid + 1])
      return mid;
    else if (A[mid] > key)
      right = mid;
    else if (A[mid + 1] <= key)
      left = mid + 1;
  }

  return -1; // all the elements > key
}

ll sup_bin_search_temp(ll key, ll A[], ll left, ll right) {
  // Pay attention to the return value -1.
  // For example, sometimes you may want the value left instead of -1.
  if (A[right] < key)
    return right;
  ll mid = left + (right - left) / 2;

  while (right >= left) {
    mid = left + (right - left) / 2;
    if (mid == right) {
      if (A[right - 1] < key && key <= A[right])
        return right - 1;
      else
        return -1;
    }
    if (A[mid] < key && key <= A[mid + 1])
      return mid;
    else if (A[mid] >= key)
      right = mid;
    else if (A[mid + 1] < key)
      left = mid + 1;
  }

  return -1; // all the elements >= key
}

ll bin_search_vector(ll key, vl v, ll left, ll right) {
  // return the index idx where v[idx] = key.
  // v[left] is start and v[right] is end..
  // In other words, v[right], not v[right - 1], must be defined.
  while (right >= left) {
    ll mid = left + (right - left) / 2;
    if (v[mid] == key)
      return mid;
    else if (v[mid] > key)
      right = mid - 1;
    else if (v[mid] < key)
      left = mid + 1;
  }
  return -1;
}

ll lower_bound_bin_search_vector(ll key, vl v) {
  // the return value N satisfies
  // v[N - 1] < key <= v[N]
  // N == -1 if all the elements < key
  return lower_bound(all(v), key) - v.begin();
}

ll inf_bin_search_vector(ll key, vl v) {
  // the return value N satisfies
  // v[N - 1] <= key < v[N] <= key + 1
  // N == -1 if all the elements <= key
  return lower_bound(all(v), key + 1) - v.begin();
}

ll upper_bound_bin_search_vector(ll key, vl v) {
  // the return value N satisfies
  // v[N] <= key < v[N + 1]
  // N == -1 if all the elements > key
  return upper_bound(all(v), key) - v.begin(); // (- 1)
}

ll sup_bin_search_vector(ll key, vl v) {
  // the return value N satisfies
  // v[N] <= key - 1 < key <= v[N + 1]
  // N == -1 if all the elements >= key
  return upper_bound(all(v), key - 1) - v.begin() - 1;
}

ll fact(ll n) {
  if (n == 0)
    return 1;
  return n * fact(n - 1);
}

ll fact_mod(ll n, ll mod) {
  if (n == 0)
    return 1;
  return n * fact_mod(n - 1, mod);
}

/*
ll facts[6000], facts_inv[6000], inv[6000];

void fact_memo(ll n, ll mod){
    facts[0] = facts[1] = 1;
    facts_inv[0] = facts_inv[1] = 1;
    inv[1] = 1;

    For(i, 2, n + 1){
        facts[i] = (i * facts[i - 1]) % mod;
        inv[i] = mod - inv[mod % i] * (mod / i) % mod;
        facts_inv[i] = facts_inv[i - 1] * inv[i] % mod;
    }
}

ll nCk(ll n, ll r){
    if (n == r && n == 0) return 1;
    else if (n <= 0 || r < 0 || r > n) return 0;
    ll val = (facts[n] * facts_inv[n - r]) % MOD;
    val *= facts_inv[r];
    return val % MOD;
}
*/

bool is_prime(ll n) {
  if (n <= 1)
    return false;
  for (ll i = 2; i * i <= n; i++) {
    if (n % i == 0)
      return false;
  }
  return true;
}

ll bool_sum(ll a1, ll a2) {
  if (a1 == 1 || a2 == 1)
    return 1;
  return 0;
}

mll prime_factorization(ll n) {
  ll i = 2;
  mll table;
  while (i * i <= n) {
    while (n % i == 0) {
      table[i]++;
      n /= i;
    }
    i++;
  }
  if (n > 1)
    table[n] = 1;
  return table;
}

vl divisor_table(ll n) {
  vl table;
  ll i = 1;
  while (i * i <= n) {
    if (n % i == 0) {
      table.pb(i);
      if (i * i != n)
        table.pb(n / i);
    }
    i++;
  }

  sort(all(table));

  return table;
}

ll char_to_idx(char c) {
  ll idx = 0;
  Forchar(cc, 'a', 'z') {
    if (c == cc)
      return idx;
    else
      idx++;
  }
}

ll next_combination(ll sub) {
  /*
  ### Attention ###
  if k is 0 or 1 and n is 0, it does not work well.

  ll n, k; ll bit = (1 << k) - 1;
  for (; bit < (1 << n); bit = next_combination(bit)){
      bool ith = bit & (1 << i);
      procedures...
  }

      sub & -sub: the binary which shares the last digit whose value is 1 in sub
      sub + x   : carry up the last digit
          ~y    : the binary whose digits are 1 if y's digit is 0.
  (sub & ~y) / x: reduce the same number of 0s after first 1 in x from (sub &
  ~y).
  */
  ll x = sub & -sub, y = sub + x;
  return (((sub & ~y) / x) >> 1) | y;
}

vl z_algorithm(str s) {
  ll n = s.length();
  vl res(n);
  res[0] = n;
  ll i1 = 1, i2 = 0;

  while (i1 < n) {
    while (i1 + i2 < n && s[i2] == s[i1 + i2])
      ++i2;
    res[i1] = i2;
    if (i2 == 0) {
      ++i1;
      continue;
    }
    ll i3 = 1;
    while (i1 + i3 < n && i3 + res[i3] < i2) {
      res[i1 + i3] = res[i3];
      ++i3;
    }
    i1 += i3, i2 -= i3;
  }
  return res;
}

ll big_number_mod(str s, ll mod) {
  ll l = s.length();
  ll idx = 0;
  ll val = 0;
  ll tenth = 1;
  while (idx < l) {
    ll m = ctol(s[l - 1 - idx]);
    val += (m * tenth) % mod;
    val %= mod;
    tenth *= 10;
    tenth %= mod;
    idx++;
  }

  return val;
}

ll big_number_compare(str s1, str s2) {
  if (s1.length() > s2.length())
    return 1;
  else if (s1.length() < s2.length())
    return -1;
  else if (s1 == s2)
    return 0;

  return 2 * (s1 > s2) - 1;
}

ll string_to_ll(str s) {
  ll l = s.length();
  ll idx = 0;
  ll val = 0;
  ll tenth = 1;
  while (idx < l) {
    ll m = ctol(s[l - 1 - idx]);
    val += (m * tenth);
    tenth *= 10;
    idx++;
  }

  return val;
}

str reflected_string(str s) {
  str t, u;
  ll n = s.length();
  t = s;
  reverse(all(t));
  u = substring(t, 0, n - 2) + s + substring(t, 1, n - 1);
  return u;
}

ld distance_between_point_line(point l_begin, point l_end, point p) {
  ll xl1 = l_begin.x, yl1 = l_begin.y;
  ll xl2 = l_end.x, yl2 = l_end.y;
  ll xp = p.x, yp = p.y;
  ll a = yl2 - yl1;
  ll b = -xl2 + xl1;
  ll c = -a * xl2 - b * yl2;
  return abs(ld(a * xp + b * yp + c)) / ld(sqrt(a * a + b * b));
}

bool is_cross(point l1_begin, point l1_end, point l2_begin, point l2_end) {
  ll x1 = l1_begin.x, y1 = l1_begin.y;
  ll x2 = l1_end.x, y2 = l1_end.y;
  ll x3 = l2_begin.x, y3 = l2_begin.y;
  ll x4 = l2_end.x, y4 = l2_end.y;
  ll val1 = (x1 - x2) * (y3 - y1) + (y1 - y2) * (x1 - x3);
  ll val2 = (x1 - x2) * (y4 - y1) + (y1 - y2) * (x1 - x4);
  ll val3 = (x3 - x4) * (y1 - y3) + (y3 - y4) * (x3 - x1);
  ll val4 = (x3 - x4) * (y2 - y3) + (y3 - y4) * (x3 - x2);

  return val1 * val2 < 0 && val3 * val4 < 0;
}

ld space_of_triangle(point p1, point p2, point p3) {
  ll x1 = p1.x, y1 = p1.y;
  ll x2 = p2.x, y2 = p2.y;
  ll x3 = p3.x, y3 = p3.y;
  ll v1 = x2 - x1;
  ll u1 = y2 - y1;
  ll v2 = x3 - x1;
  ll u2 = y3 - y1;
  ld s = ld(v1 * u2 - u1 * v2) / ld(2);
  return abs(s);
}

pair<point, ll> center_2det_of_3points(point p1, point p2, point p3) {
  // the center of circle on the given three points
  // return the determinant value and the product of center points and 2 *
  // determinant value
  ll x1 = p1.x, y1 = p1.y;
  ll x2 = p2.x, y2 = p2.y;
  ll x3 = p3.x, y3 = p3.y;

  // center of 2 points
  ll c2x_2 = x2 + x1, c2y_2 = y2 + y1;
  ll c3x_2 = x3 + x1, c3y_2 = y3 + y1;

  // vertical vector of 2 lines
  ll b2y = x2 - x1, b2x = -y2 + y1;
  ll b3y = x3 - x1, b3x = -y3 + y1;

  ll x1_2 = c3x_2 * b3y - c3y_2 * b3x, y1_2 = c2x_2 * b2y - c2y_2 * b2x;
  ll det = -b3y * b2x + b3x * b2y;
  if (det == 0)
    return {{INF, INF}, det};
  ll cx_2det = -b2x * x1_2 + b3x * y1_2, cy_2det = -b2y * x1_2 + b3y * y1_2;
  return {{cx_2det, cy_2det}, det};
}

ll inversion_number(vl a, ll a_max) {
  /*
  Paramters
  ---------
  a: vector<ll>
      All the elements must be non-negative.
      Prefably the elements are compressed to reduce the computational cost.
  a_max: ll
      The maximum value of the vector a or the value bigger than the value
  stated previously.
  */

  BIT bit(a_max + 1);
  ll val = 0;
  rep(i, a.size()) {
    // i is the number of elements that have lower index than a[i].
    // call the number of elements that have lower value than a[i]
    // by subtracting these two, the residual number is the number of elements
    // that have larger value
    val += i - bit.query(a[i] - 1); // cumulative sum from 0 to a[i] - 1
    bit.update(a[i], 1);
  }
  return val;
}

template <typename T> vector<T> compress(vector<T> v) {
  // sort and remove all the duplicated values
  sort(all(v));
  v.erase(unique(all(v)), v.end());
  return v;
}

template <typename T> map<T, ll> dict(const vector<T> &v) {
  map<T, ll> d;
  rep(i, v.size()) d[v[i]] = i;
  return d;
}

void GaussJordanBitVector(vl &bs) {
  ll n = bs.size();
  ll rank = 0;
  ll j = 0;
  revrep(i, N_DIGITS) {
    for (j = rank; j < n; j++)
      if (bs[j] & (1LL << i))
        break;
    if (j == n)
      continue;
    if (j > rank)
      bs[rank] ^= bs[j];
    for (j = rank + 1; j < n; j++)
      bs[j] = min(bs[j], bs[j] ^ bs[rank]);
    rank++;
  }
}

ll kruskal(vector<undirected_edge> &es, ll n_vertex) {
  sort(all(es));
  UnionFind uf(n_vertex);

  ll min_cost = 0;

  rep(i, es.size()) {
    undirected_edge &e = es[i];
    if (!uf.is_same(e.from, e.to)) {
      min_cost += e.cost;
      uf.unite(e.from, e.to);
    }
  }
  return min_cost;
}

ll LongestIncreasedSequence(vl &v, ll n) {
  vl dp(n, INF);
  rep(i, n) * lower_bound(all(dp), v[i]) = v[i];
  return find(all(dp), INF) - dp.begin();
}

/*
const ll N_VERTEX = 310;
ll a, b, t;
ll dist[N_VERTEX][N_VERTEX];

void warshall_floyd(ll n){
    // rep(i, n) rep(j, n) dist[i][j] = INF * (i != j);
    rep(k, n) rep(i, n) rep(j, n) dist[i][j] = min(dist[i][j], dist[i][k] +
dist[k][j]);
}

int main(void){
    in2(n, m);
    rep(i, n) rep(j, n) dist[i][j] = INF * (i != j);
    rep(i, m){
        in3(a, b, t);
        a--; b--;
        dist[a][b] = t;
        dist[b][a] = t;
    }

    warshall_floyd(n);
}

ll dist[1005], vertex_pre[1005];

void dijkstra(ll start, ll n) {
    priority_queue<pl, vector<pl>, greater<pl>> edge_costs;
    fill(dist, dist + n, INF); // fill(vertex_pre, vertex_pre + n, -1);
    dist[start] = 0;
    edge_costs.push(pl(0, start));

    while (!edge_costs.empty()) {
        pl edge_cost = edge_costs.top();
        edge_costs.pop();
        ll idx = edge_cost.second;
        ll cost = edge_cost.first;
        if (dist[idx] < cost) continue;

        rep(i, graph[idx].size()){
            edge e = graph[idx][i];
            if (dist[e.to] > dist[idx] + e.cost){
                dist[e.to] = dist[idx] + e.cost;
                // vertex_pre[e.to] = idx;
                edge_costs.push(pl(dist[e.to], e.to));
            }
        }
    }
}

vl get_predecessor(ll g){
    vl path;
    for (; g != -1; g = vertex_pre[g]) path.pb(g);

    reverse(all(path));
    return path;
}

int main(void){
    in2(n, m);
    rep(i, m){
        in3(a, b, t);
        a--; b--;
        G[a].pb({b, t});
        G[b].pb({a, t});
    }

    dijkstra(0, n);
}


# ABC061D

bool find_negative_cycle(ll goal){
    rep(i, n) rep(v, n) rep(k, graph[v].size()){
        edge e = graph[v][k];
        if (dist[e.to] != INF && dist[e.to] > dist[v] + e.cost){
            dist[e.to] = -INF;
            if (goal == -1) return true;
            else if (goal == e.to) return true;
        }
    }
    return false;
}

bool bellman_ford(ll start, ll n, ll goal){
    // if there is a closed circuit, it returns false. (when goal == -1)
    // if the distance to goal cannot be obtained, it returns false (when goal
!= -1) fill(dist, dist + n, INF); dist[start] = 0; rep(i, n) rep(v, n) rep(k,
graph[v].size()){ edge e = graph[v][k]; if (dist[v] != INF && dist[e.to] >
dist[v] + e.cost) dist[e.to] = dist[v] + e.cost;
    }

    if (find_negative_cycle(goal)) return false;
    return true;
}

*/

/*
    # 1. The usage of map pair
    map<pl, ll> cnt;
    cnt[{i, j}] = 0;
    items(kv, cnt){
        prl2(kv.first, kv.second);
    }

    # 2. The usage of next_permutation and combination (factorial search)
    ll a[8];
    rep(i, 8) a[i] = i;
    sort(a, a + 8);
    do{
    }while(next_permutation(a, a+n));

    // here, combination
    ll n, r;
    ll i1, i2, ..., ir;
    For(i1, n - r, n) For(i2, n - r - 1, i1) ... For(ir, n - 2 * r + 1, irr){
   process;}

    # 3. bit search
    ll n;
    in1(n);
    const ll base = 3;
    ll upper = power_normal(base, n);

    rep(i, upper){
        ll tmp = i;
        rep(j, n){
            rep(k, base) if (tmp % base == k) prl(k);
            tmp /= base;
        }
    }

    # 4. imos method
    // used when we would like to count the number which
    // shows how many times the numbers between l and r belongs to smt.
    // This method is composed of three process.
    ll n, m, s[MAX_M], l, r;
    in2(n, m);
    rep(i, m) s[i] = 0;

    // 1st step
    rep(i, n){
        in3(l, r, c);
        l--; r--; // if l starts from 1.
        s[l] += c; s[r + 1] -= c;
    }

    // 2nd step
    rep(i, m - 1) s[i + 1] += s[i];
    // 3rd step: judgement...

    #5. shakutori method (syakutori, two pointers technique)
    // 1. strech right side while the condition is met.
    // 2. renew the answer
    // 3. increments left side
    // 4. Back to 1. (l <= r must be satisfied all the time.)

    ll l = 0; ll r = 0;
    while (l < n){
        r = max(r, l);
        if (l == r) r++;
        while(r < n && cond) r++;
        answer += r - l; l++;
    }
    prl(answer);

    #6. priority queue

    pq q;
    ll answer = 0;
    ll v;

    rep(i, n) q.push(a[i]);
    rep(i, m){
        v = q.top(); q.pop(); // get the top value and dump the value from queue
        v /= 2; q.push(v); // add the new value
    }

    while(!q.empty()){
        answer += q.top();
        q.pop();
    }

    #7. The shortest path (distance) between the k-th edge and another edge
   (Tree) Graph tree[MAX_N]; ll depth[MAX_N];

    void dfs(ll source, ll parent, ll all_cost){
        depth[source] = all_cost;
        items(e, tree[source]){
            if (e.to == parent) continue;
            dfs(e.to, source, all_cost + e.cost);
        }
    }

    ll n, k, a, b, c;

    in2(n, k);
    rep(i, n - 1){
        in3(a, b, c);
        a--; b--;
        tree[a].pb({b, c});
        tree[b].pb({a, c});
    }

    k--;
    dfs(k, -1, 0);

    #10. Visiting Subtree using recurrent function (ABC138D)

    Graph tree[MAX_N];
    ll c[MAX_N];
    bool visited[MAX_N];

    void dfs(ll source, ll parent, ll val){
        visited[source] = true;
        c[source] += val;
        rep(i, tree[source].size()){
            rep(i, m){ll res = n % match[i].e1;}
            ll vertex = tree[source][i].to;
            if (vertex == parent) continue;
            dfs(vertex, source, c[source]);
        }
    }

    #11. bfs ABC146D, ABC007C
    1. first create a tree.
    2. start searching from a node.
    3. do some processes and push nodes connected with a given target node in
   BFS.
    4. repeat a series of procedure until queue is empty.

    queue<pl> q;

    void bfs(ll source, ll parents){
        ll n_edge = graph[source].size();
        if (parents != -1) dist[source] = min(dist[source], dist[parents] + 1);
        if (visited[source]) return;
        visited[source] = true;

        rep(idx, n_edge){
            ll target = graph[source][idx].to;
            if (target == parents) continue;
            q.push(mp(target, source));
        }
    }

    q.push(mp(sg.e1, -1));
    while(!q.empty()){
        pl source = q.front(); q.pop();
        bfs(source.e1, source.e2);
    }

    #12. grid to distance matrix (dx, dy)
    ll w, h;
    ll pos_to_idx(ll x, ll y){
        return y * w + x;
    }

    pl idx_to_pos(ll idx){
        return mp(idx % w, idx / w);
    }

    rep(y, h){
        in1(s);
        rep(x, w){
            if (s[x] == '#') wall[x][y] = true;
            else wall[x][y] = false;
        }
    }

    rep(i1, h * w)rep(i2, h * w) dist[i1][i2] = INF * (i1 != i2);

    rep(x, w)rep(y, h){
        ll idx1 = pos_to_idx(x, y); ll idx2;
        if (wall[x][y]) continue;
        if (x != 0 && !wall[x - 1][y]){
            idx2 = pos_to_idx(x - 1, y);
            // if warshall floyd
            dist[idx1][idx2] = 1;
            // if dijkstra
            // graph[idx1].pb({idx2, 1});
        }
        if (x != w - 1 && !wall[x + 1][y]){
            idx2 = pos_to_idx(x + 1, y);
            dist[idx1][idx2] = 1;
            // graph[idx1].pb({idx2, 1});
        }
        if (y != 0 && !wall[x][y - 1]){
            idx2 = pos_to_idx(x, y - 1);
            dist[idx1][idx2] = 1;
            // graph[idx1].pb({idx2, 1});
        }
        if (y != h - 1 && !wall[x][y + 1]){
            idx2 = pos_to_idx(x, y + 1);
            dist[idx1][idx2] = 1;
            // graph[idx1].pb({idx2, 1});
        }
    }

    # Cumulative sum (2 dimension)

    ll func(ll x, ll y, ll dx, ll dy){
        if (x + dx > w || y + dy > h) return - INF;
        ll val = cum[x + dx][y + dy];
        val += cum[x][y];
        val -= cum[x][y + dy];
        val -= cum[x + dx][y];
        return val;
    }

    rep(x, w + 1) cum[x][0] = 0;
    rep(y, h + 1) cum[0][y] = 0;
    rep(y, h + 1) rep(x, w)
        cum[x + 1][y + 1] = cum[x][y + 1] + vs[x][y];

    rep(x, w + 1) rep(y, h)
        cum[x][y + 1] += cum[x][y];

    # DEBUG_MATRIX

    rep(i, n){
        rep(j, n) prs(a[i][j]);
        prl("");
    }

*/

/*
# the operators regarding bit
& (AND), | (OR), ^ (XOR)
- (REVERSE), >> (SMALLER SHIFT)
<< (BIGGER SHIFT)


     x1: 0000 0001 0010 0101 0110 0111 0111
     x2: xxxx 0001 0011 0100 0101 1000 0110
x1 & x2: 0000 0001 0010 0100 0100 0000 0110

      x: 1001 1010  1100 1011 1101  1111
x & - x: 0001 0010  0100 0001 0001  0001
    sum: 1010 1100 10000 1100 1100 10000

x << y is x * 2 ** y
x >> y is rep(i, y) x = x // 2

####### Attention #######
1 << i and 1LL << i is different. If programs show WA, try switch to this one.
Let S be a bit sequence and i be a non-negative integer
S & (1 << i) -> if true, i in S
S | (1 << i) -> S union {i}
S & -(1 << i) -> S - {i}
__builtin_popcount(S) -> the number of elements in S
S = 0 -> S is an empty set
__builtin_popcountl(i) -> the number of 1 in binary
S = (1 << n) - 1 -> S includes all the elements up to the n-th

#Conditional Operator
condition ? true : false;

#iterator
type declaration: auto
value reference: *itr
increment: itr++
decrement: itr--
substitution of value: *itr = smt

# inclusion-exclusion principle
|U[i = 1 to n] Ai| = sum[i = 1 to n] |Ai| - sum[i < j]|Ai ^ Aj| + ... + (-1)^(n
- 1) |^[i = 1 to n]Ai|
*/

const ll MAX_N = 200105;
bool okay = false;
ll answer = 0;
ll n, k;
// pl = (a', b') : a' and b' is coprime.
map<pl, ll> cnt;
vpl bad;
map<pl, bool> visited;
ll memo[MAX_N];

void solve() {
  rep(i, n) {
    ll a, b;
    in2(a, b);
    if (a == 0 && b != 0)
      b = 1;
    else if (a != 0 && b == 0)
      a = 1;
    else if (a != 0 && b != 0) {
      ll g = gcd(abs(a), abs(b));
      a /= g, b /= g;
    }

    if ((a > 0 && b > 0) || (a < 0 && b < 0))
      a = abs(a), b = abs(b);
    else if ((a < 0 && b > 0) || (a > 0 && b < 0))
      a = abs(a), b = -abs(b);
    cnt[{a, b}]++;
    visited[{a, b}] = false;
  }

  memo[0] = 1;
  rep(i, n + 20) {
    memo[i + 1] = 2LL * memo[i];
    memo[i + 1] %= MOD;
  }

  items(kv, cnt) {
    pl p = kv.e1;
    ll a1 = p.e1, b1 = p.e2;
    ll a2, b2;

    if (a1 == 0 && b1 == 0)
      continue;
    else if ((a1 > 0 && b1 > 0) || (a1 < 0 && b1 < 0))
      a2 = abs(b1), b2 = -abs(a1);
    else if ((a1 < 0 && b1 > 0) || (a1 > 0 && b1 < 0))
      a2 = abs(b1), b2 = abs(a1); // both positive
    else if (a1 == 0)
      a2 = 1, b2 = 0;
    else if (b1 == 0)
      a2 = 0, b2 = 1;

    if (visited[{a1, b1}] || visited[{a2, b2}])
      continue;
    bad.pb({cnt[{a1, b1}], cnt[{a2, b2}]});
    visited[{a1, b1}] = visited[{a2, b2}] = true;
  }

  answer = 1;
  rep(i, bad.size()) {
    ll c1 = bad[i].e1, c2 = bad[i].e2;
    answer *= (memo[c1] + memo[c2] - 1LL + MOD) % MOD;
    answer %= MOD;
  }

  ll c0 = cnt[{0, 0}];
  prl((answer - 1 + MOD + c0) % MOD);
}

int main(void) {
  in1(n);
  // assert(k <= 1000);
  solve();
  return 0;
}


Error: 0

Fixed submission:

#include <algorithm>
#include <bits/stdc++.h>
#include <cassert>
#include <complex>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <deque>
#include <iostream>
#include <list>
#include <map>
#include <queue>
#include <set>
#include <sstream>
#include <stack>
#include <stdio.h>
#include <string>
#include <vector>
using namespace std;
typedef long long ll;
typedef long double ld;
using edge = struct {
  ll to;
  ll cost;
};
struct point {
  ll x;
  ll y;
  bool operator<(const point &p) const {
    if (x == p.x)
      return y < p.y;
    return x < p.x;
  }
};
struct undirected_edge {
  ll from;
  ll to;
  ll cost;
  bool operator<(const undirected_edge &ue) const { return cost < ue.cost; }
};

typedef string str;
typedef std::pair<ll, ll> pl;
typedef std::pair<ll, pl> pl3;
typedef std::map<string, ll> msl;
typedef std::map<char, ll> mcl;
typedef std::map<ll, ll> mll;
typedef std::vector<ll> vl;
typedef std::vector<pl> vpl;
typedef std::vector<point> points;
typedef std::vector<pl3> vpl3;
typedef std::priority_queue<ll> pq;
typedef std::priority_queue<ll, vl, greater<ll>>
    pql; // priority queue taking from the lower value.
typedef std::vector<edge> Graph;
const ll N_DIGITS = 60;
const ll MOD = 1e9 + 7;
// const ll MOD = 998244353;
const ll INF = MOD * MOD;
const long double EPS = 1e-9;
const long double PI = 3.14159265358979323846;
vpl dirs = {
    {1, 0}, {0, 1},  {-1, 0},  {0, -1}, // four directions
    {1, 1}, {-1, 1}, {-1, -1}, {1, -1}, // diagonal
    {0, 0}                              // self
};

#define rep(i, n) for (ll(i) = 0; (i) < (n); (i)++)
#define revrep(i, n) for (ll(i) = n - 1; (i) >= 0; (i)--)
#define For(i, a, b) for (ll(i) = (a); (i) < (b); (i)++)
#define revFor(i, b, a) for (ll(i) = (b)-1; (i) >= (a); (i)--)
#define all(a) (a).begin(), (a).end()
#define rall(a) (a).rbegin(), (a).rend()
#define isUpper(c) ('a' - c > 0)
#define isNum(c) (0 <= (c) - '0' && (c) - '0' <= 9)
#define toLower(c) char((c) + 0x20)
#define toUpper(c) char((c)-0x20)
#define pb push_back
#define mp make_pair
#define pr(a) cout << (a)
#define prl(a) cout << (a) << endl
#define prl2(a, b) cout << (a) << " " << (b) << endl
#define prl3(a, b, c) cout << (a) << " " << (b) << " " << (c) << endl
#define prl4(a, b, c, d)                                                       \\
  cout << (a) << " " << (b) << " " << (c) << " " << (d) << endl
#define prs(a) cout << (a) << " "
#define yn(condition)                                                          \\
  if ((condition))                                                             \\
    prl("Yes");                                                                \\
  else                                                                         \\
    prl("No");
#define YN(condition)                                                          \\
  if ((condition))                                                             \\
    prl("YES");                                                                \\
  else                                                                         \\
    prl("NO");
#define in1(a) cin >> (a)
#define in2(a, b) cin >> (a) >> (b)
#define in3(a, b, c) cin >> (a) >> (b) >> (c)
#define in4(a, b, c, d) cin >> (a) >> (b) >> (c) >> (d)
#define e1 first
#define e2 second
#define ctol(c) ll((c)) - ll('0')
#define ltos(n) to_string((n))
#define items(kv, v) for (auto &(kv) : (v))
#define ndig(N, n) ctol(ll(ltos((N))[ll(ltos((N)).length()) - (n)]))
#define rsort(a, n) sort(a, a + n, greater<>())
#define Forchar(c, a, z) for (char(c) = (a); (c) <= (z); (c)++)
#define cntchar(s, c) count(all((s)), c)
#define substring(s, start, end) s.substr((start), (end) - (start) + 1)
#define prl_nd(num, digits)                                                    \\
  cout << fixed << setprecision(digits) << (num) << endl;
#define XOR(a, b) (a) ^ (b)
#define prl_time(s)                                                            \\
  prl3("Elapsed Time:", 1000.0 * (clock() - s) / CLOCKS_PER_SEC, "[ms]");
#define char_to_str(c) string(1, (c))
#define DEBUG(x) cerr << #x << ": " << (x) << endl
#define DEBUG_VEC(v)                                                           \\
  cerr << #v << ": ";                                                          \\
  rep(__i, (v).size()) cerr << ((v)[__i]) << ", ";                             \\
  cerr << endl

struct MaxFlow {
  struct F_edge {
    ll to, rev, capacity;
    F_edge(ll to, ll rev, ll capacity) : to(to), rev(rev), capacity(capacity) {}
  };

  typedef vector<F_edge> F_edges;
  vector<F_edges> graph;
  ll n_vertex;
  // level is the shortest path to get a given node from the source node.
  vl level, iter;

  MaxFlow(ll n_vertex) : n_vertex(n_vertex) { graph.resize(n_vertex); }

  void add_edge(ll from, ll to, ll capacity) {
    graph[from].pb({to, ll(graph[to].size()), capacity});
    graph[to].pb({from, ll(graph[from].size()) - 1, 0});
  }

  void bfs(ll source) {
    level = vl(n_vertex, -1);
    level[source] = 0;
    queue<ll> q;
    q.push(source);
    while (!q.empty()) {
      ll vertex = q.front();
      q.pop();
      rep(i, graph[vertex].size()) {
        ll target = graph[vertex][i].to;
        ll cap_target = graph[vertex][i].capacity;
        // if the flow can be into the target node, implement below.
        if (cap_target > 0 && level[target] < 0) {
          level[target] = level[vertex] + 1;
          q.push(target);
        }
      }
    }
  }

  ll dfs(ll vertex, ll sink, ll flow) {
    if (vertex == sink)
      return flow;
    for (ll &i = iter[vertex]; i < graph[vertex].size(); i++) {
      ll target = graph[vertex][i].to;
      ll cap_target = graph[vertex][i].capacity;
      ll rev_target = graph[vertex][i].rev;
      // if capasitiy is not full yet and target is farther,
      // then assign current flow
      if (cap_target > 0 && level[vertex] < level[target]) {
        ll d = dfs(target, sink, min(cap_target, flow));
        if (d > 0) { // if the flow successfully reaches the sink, reduce the
                     // flow from the capacity
          graph[vertex][i].capacity -= d;
          graph[target][rev_target].capacity += d;
          return d;
        }
      }
    }
    return 0;
  }

  ll dinic(ll source, ll sink) {
    ll flow = 0;
    while (true) {
      bfs(source);
      // if there is no path leading to the sink, the maximum flow is 0.
      if (level[sink] < 0)
        return flow;
      iter = vl(n_vertex, 0);
      ll f;
      while ((f = dfs(source, sink, INF)) > 0)
        flow += f;
    }
  }
};

class UnionFind {
  vl parents, set_size;

public:
  UnionFind() {}
  UnionFind(ll n) {
    parents = set_size = vl(n);
    rep(i, n) {
      parents[i] = i;
      set_size[i] = 1LL;
    }
  }

  ll root_find(ll x) {
    if (parents[x] == x)
      return x;
    return parents[x] = root_find(parents[x]);
  }

  void unite(ll x, ll y) {
    // priority for x is larger than that of y
    x = root_find(x);
    y = root_find(y);
    if (x == y)
      return;
    if (set_size[x] < set_size[y]) {
      parents[y] = x;
      set_size[x] += set_size[y];
    } else {
      parents[x] = y;
      set_size[y] += set_size[x];
    }
  }

  bool is_same(ll x, ll y) { // connected or not
    return root_find(x) == root_find(y);
  }

  ll size(ll x) { return set_size[root_find(x)]; }
};

struct Doubling { // ABC167D
  ll n;
  ll sz;
  vector<vl> next;
  /*
      next[k + 1][i] := next[k][next[k][i]]
      next[0][i] := edge[i]
      e.g. a0, a1, ..., an-1 / 0 <= ai <= n - 1
      a0 -> a[a0] -> a[a[a0]] -> ... -> a[a[...[a[0]]]] (m times)
      Let the function repeatedly input a[i] m times be f[m](a[i])

      - get(i, x) returns f[x](a[i])
      - lower_bound(i, j) returns minimum x which satisfies f[x](a[i]) >= j.
                                  if not possible returns n.

  */

  // edge[i]: the step size for one iteration
  Doubling(vl &edge) : n(edge.size()), sz(62) {
    next.resize(sz, vl(n, -1));
    rep(i, n) next[0][i] = edge[i];
    rep(k, sz - 1) rep(i, n) next[k + 1][i] = next[k][next[k][i]];
  }

  ll get(ll i, ll x) {
    ll ret = i;
    rep(bit, sz) {
      if (!(x >> bit & 1))
        continue;
      ret = next[bit][ret];
    }
    return ret;
  }

  ll lower_bound(ll i, ll j) {
    ll cur = i, acc = 0;
    revrep(wid, sz) {
      if (next[wid][cur] < j) {
        acc += 1LL << wid;
        cur = next[wid][cur];
      }
    }
    return min(n, acc + 1);
  }
};

/*
class LCA{
public:
    ll N, logN;
    vl depth, len;
    Graph tree[200005]; // global declaration later.
    vector<vl> parents;

    LCA(ll n){
        N = n;
        logN = 0;
        while (N > (1LL << logN)) logN++;
        depth = vl(N); len = vl(N);
        parents = vector<vl>(logN, vl(N));
        init(0, -1, 0, 0);
        build();
    }

    void init(ll source, ll parent, ll d, ll l){
        depth[source] = d;
        parents[0][source] = parent;
        len[source] = l;
        rep(i, tree[source].size()){
            ll target = tree[source][i].to;
            ll cost = tree[source][i].cost;
            if (target == parent) continue;
            init(target, source, d + 1, cost + l);
        }
    }

    void build(){
        rep(k, logN - 1) rep(n, N){
            // if there is no parent, -1.
            // otherwise, the parent of the parent is the parent.
            if (parents[k][n] < 0) parents[k + 1][n] = -1;
            else parents[k + 1][n] = parents[k][parents[k][n]];
        }
    }

    ll query(ll u, ll v){
        if (depth[u] > depth[v]) swap(u, v);
        rep(k, logN) if ((depth[v] - depth[u]) >> k & 1) v = parents[k][v];
        if (u == v) return u;

        revrep(k, logN){
            if (parents[k][u] != parents[k][v]){
                u = parents[k][u]; v = parents[k][v];
            }
        }
        return parents[0][u];
    }

    ll distance(ll u, ll v){
        ll w = query(u, v);
        return len[u] + len[v] - 2 * len[w];
    }

};
*/

struct BIT {
  ll n;
  vl tree_dat;
  BIT(ll n, ll ini = 0) : tree_dat(n + 1, ini), n(n){};

  //       x: 1001 1010  1100 1011 1101  1111
  // x & - x: 0001 0010  0100 0001 0001  0001
  //      ->: 1010 1100 10000 1100 1100 10000

  ll update_func(ll val, ll dat) {
    // if maximum -> max(val, dat)
    // return max(val, dat);
    // if cumulative sum
    // return val + dat;
    return min(val, dat);
  }

  ll query(ll i) {
    /*
    e.g.) i = 10101
    itr1. 10101 -> 10100
    itr2. 10100 -> 10000
    itr3. 10000 -> 00000 (break)
    */
    ll ret = 0;
    for (ll j = i; j >= 0; j = (j & (j + 1)) - 1) {
      ret = update_func(ret, tree_dat[j]);
    }
    return ret;
  }

  ll lower_bound(ll key) {
    if (key <= 0)
      return 0;
    ll left = 0, right = 1;
    while (right <= n)
      right *= 2;

    for (ll i = right; i > 0; i /= 2) {
      if (left + i <= n && tree_dat[left + i - 1] < key) {
        key -= tree_dat[left + i - 1];
        left += i;
      }
    }
    return left;
  }

  void update(ll i, ll val) {
    /*
    e.g.) i = 10101, n = 11111
    itr1. i: 10101, i+1: 10110 -> 10111
    itr2. i: 10111, i+1: 11000 -> 11111 (break)
    */
    if (i < 0)
      return;
    for (ll j = i; j < n; j |= j + 1) {
      tree_dat[j] = update_func(val, tree_dat[j]);
    }
  }
};

template <class Target> class RerootingTreeDP {
public:
  using T = typename Target::type;
  struct DP_edge {
    ll to, rev; // rev is the index to trace the source node.
    T value;    // objective value
  };

private:
  ll n;
  void dfs_fwd(ll source, ll parent) {
    ll par_idx = -1;
    vector<T> values;
    rep(i, tree[source].size()) {
      const DP_edge &e = tree[source][i];
      if (e.to == parent) {
        par_idx = i;
        continue;
      }
      dfs_fwd(e.to, source);
      values.pb(e.value);
    }

    // If the parent != -1, update the value on edge from parent to source
    if (par_idx != -1) {
      ll src_idx = tree[source][par_idx].rev;
      // update values on the edge from parent to source
      tree[parent][src_idx].value = Target::merge(values);
    }
  }

  void dfs_bwd(ll source, ll parent) {
    vector<T> values;
    for (auto &&e : tree[source])
      values.pb(e.value);
    values = Target::evaluate(values);

    rep(i, tree[source].size()) {
      const DP_edge &e = tree[source][i];
      if (e.to == parent)
        continue;
      // tree[e.to][e.rev]: e.to -> source
      tree[e.to][e.rev].value = values[i];
      dfs_bwd(e.to, source);
    }
  }

public:
  UnionFind uf;
  vector<vector<DP_edge>> tree;
  RerootingTreeDP(ll n) : n(n), uf(n), tree(n) {}

  void add_edge(ll u, ll v, T val) {
    assert(!uf.is_same(u, v));
    tree[u].pb({v, ll(tree[v].size()), val});
    tree[v].pb({u, ll(tree[u].size()) - 1, val});
    uf.unite(u, v);
  }

  void dp() {
    vector<bool> visited(n, false);
    rep(i, n) {
      if (visited[uf.root_find(i)])
        continue;
      dfs_fwd(i, -1);
      visited[uf.root_find(i)] = true;
    }

    visited.assign(n, false);
    rep(i, n) {
      if (visited[uf.root_find(i)])
        continue;
      dfs_bwd(i, -1);
      visited[uf.root_find(i)] = true;
    }
  }

  ll size() const { return tree.size(); }
};

// ABC160F is one example
// Modify the functions evaluate and merge based on given problems
struct Merger {
  using type = ll;

  static vector<type> evaluate(const vector<type> &value) {
    const ll n = value.size();
    vl L(n + 1, 1), R(n + 1, 1);
    rep(i, n) L[i + 1] = (L[i] * value[i]) % MOD;
    revrep(i, n) R[i] = (R[i + 1] * value[i]) % MOD;

    vl ret(n);
    /*
    ret[i] = v[c0] * v[c1] * ... * v[ci-1] * v[ci+1] * ... * v[cn-1]
    ci: the i-th child

    Let's consider the case where the root of a given tree is 0. (0-indexed)
    Here, we try to obtain the objective values for the edges from children to
    parent. When we change the root of the tree into another, the parent node
    here also changes the family structure. Since each node has ONLY one parent
    and zero or one or multiple children, the value for edge on child i to
    source is obtained using the value from source to child j. Here j is all the
    integers which is not i.

    In this case, child i is grandparent of child j for all j and
    the computation for the value from child i to source is O(N) when we use
    cumulative sum or product.
    */
    rep(i, n) ret[i] = (L[i] * R[i + 1]) % MOD;

    return ret;
  }

  static type merge(const vector<type> &value) {
    ll ret;
    for (auto &&v : value) {
    }
    return ret;
  }
};

ll gcd(ll m, ll n) {
  ll a = max(m, n);
  ll b = min(m, n);
  while (b != 1 && b != 0) {
    a %= b;
    swap(a, b);
  }
  return b == 1 ? 1 : a;
}

ll lcm(ll m, ll n) { return m / gcd(m, n) * n; }

template <class T> inline bool chmax(T &a, T b) {
  if (a < b) {
    a = b;
    return true;
  }
  return false;
}

template <class T> inline bool chmin(T &a, T b) {
  if (a > b) {
    a = b;
    return true;
  }
  return false;
}

ll power_mod(ll a, ll power, ll mod) {
  ll value = 1;
  while (power != 0) {
    if (power & 1)
      value = (value * a) % mod;
    a = (a * a) % mod;
    power = power >> 1;
  }
  return value % mod;
}

ll modinv(ll a, ll mod) { return power_mod(a, mod - 2, mod); }

ll power_normal(ll a, ll power) {
  ll value = 1;
  while (power != 0) {
    if (power & 1)
      value = value * a;
    a = a * a;
    power = power >> 1;
  }
  return value;
}

ll comb_memo[55][55];

ll pascal_triangle(ll n) {
  comb_memo[0][0] = 1;
  For(i, 1, n + 1) rep(j, i + 1) {
    comb_memo[i][j] += comb_memo[i - 1][j];
    if (j > 0)
      comb_memo[i][j] += comb_memo[i - 1][j - 1];
  }
}

ll combination(ll n, ll r, ll mod) {
  if (n == r && n == 0)
    return 1;
  else if (n <= 0 || r < 0 || r > n)
    return 0;
  ll numerator = 1;
  ll denomenator = 1;
  for (ll i = 0; i < r; i++) {
    ll num = (n - i) % mod, den = (i + 1) % mod;
    (numerator *= num) %= mod;
    (denomenator *= modinv(den, mod)) %= mod;
  }

  return (numerator * denomenator) % mod;
}

ll combination_no_mod(ll n, ll r) {
  if (n == r && n == 0)
    return 1;
  else if (n <= 0 || r < 0 || r > n)
    return 0;
  ll numerator = 1;
  ll denomenator = 1;
  for (ll i = 0; i < r; i++) {
    numerator *= n - i;
    denomenator *= i + 1;
    ll g = gcd(numerator, denomenator);
    numerator /= g;
    denomenator /= g;
  }

  return numerator;
}

ld log_combination(ll n, ll r) {
  if (n == r && n == 0)
    return 0;
  else if (n <= 0 || r < 0 || r > n)
    return -INF;
  ld val = 0;
  for (ll i = 0; i < r; i++) {
    val += log(n - i);
    val -= log(i + 1);
  }

  return val;
}

ll bin_search(ll key, ll A[], ll left, ll right) {
  // return the index idx where A[idx] = key.
  // A[left] is start and A[right] is end..
  // In other words, A[right], not A[right - 1], must be defined.
  while (right >= left) {
    ll mid = left + (right - left) / 2;
    if (A[mid] == key)
      return mid;
    else if (A[mid] > key)
      right = mid - 1;
    else if (A[mid] < key)
      left = mid + 1;
  }
  return -1;
}

/*
ll bin_search_temp(ll left, ll right, callable judge){
    while(right > left){
        // when seeking lower bound
        ll mid = (right + left) / 2;
        if (judge(mid)) right = mid;
        else left = mid + 1;
        // when seeking upper bound
        ll mid = (right + left + 1) / 2;
        if (judge(mid)) left = mid;
        else right = mid - 1;
    }

    return right;
}

trinary_search

// Care the value EPS!!! Compare to the condition
ld left = 0; ld right = p;
while(abs(right - left) > EPS){
    ld left2 = (2 * left + right) / 3.0;
    ld right2 = (left + 2 * right) / 3.0;
    ld f1 = tak_func(left2);
    ld f2 = tak_func(right2);
    if (f1 <= f2) right = right2;
    else if (f2 <= f1) left = left2;
}

*/

str bin_expression(ll n, ll dig) {
  str s = "";
  rep(i, dig) {
    s += ltos(n % 2);
    n /= 2;
  }
  reverse(all(s));
  return s;
}

ll lower_bound_bin_search_temp(ll key, ll A[], ll left, ll right) {
  // Pay attention to the return value -1.
  // For example, sometimes you may want the value right instead of -1.
  if (A[left] >= key)
    return left;
  ll mid = left + (right - left) / 2;

  while (right >= left) {
    mid = left + (right - left) / 2;
    if (mid == left) {
      if (A[left] < key && key <= A[left + 1])
        return left + 1;
      else
        return -1;
    }
    if (A[mid - 1] < key && key <= A[mid])
      return mid;
    else if (A[mid - 1] >= key)
      right = mid - 1;
    else if (A[mid] < key)
      left = mid;
  }

  return -1; // all the elements < key
}

ll inf_bin_search_temp(ll key, ll A[], ll left, ll right) {
  // Pay attention to the return value -1.
  // For example, sometimes you may want the value right instead of -1.
  if (A[left] > key)
    return left;
  ll mid = left + (right - left) / 2;

  while (right >= left) {
    mid = left + (right - left) / 2;
    if (mid == left) {
      if (A[left] <= key && key < A[left + 1])
        return left + 1;
      else
        return -1;
    }
    if (A[mid - 1] <= key && key < A[mid])
      return mid;
    else if (A[mid - 1] > key)
      right = mid - 1;
    else if (A[mid] <= key)
      left = mid;
  }

  return -1; // all the elements <= key
}

ll upper_bound_bin_search_temp(ll key, ll A[], ll left, ll right) {
  // Pay attention to the return value -1.
  // For example, sometimes you may want the value left instead of -1.
  if (A[right] <= key)
    return right;
  ll mid = left + (right - left) / 2;

  while (right >= left) {
    mid = left + (right - left) / 2;
    if (mid == right) {
      if (A[right - 1] <= key && key < A[right])
        return right - 1;
      else
        return -1;
    }
    if (A[mid] <= key && key < A[mid + 1])
      return mid;
    else if (A[mid] > key)
      right = mid;
    else if (A[mid + 1] <= key)
      left = mid + 1;
  }

  return -1; // all the elements > key
}

ll sup_bin_search_temp(ll key, ll A[], ll left, ll right) {
  // Pay attention to the return value -1.
  // For example, sometimes you may want the value left instead of -1.
  if (A[right] < key)
    return right;
  ll mid = left + (right - left) / 2;

  while (right >= left) {
    mid = left + (right - left) / 2;
    if (mid == right) {
      if (A[right - 1] < key && key <= A[right])
        return right - 1;
      else
        return -1;
    }
    if (A[mid] < key && key <= A[mid + 1])
      return mid;
    else if (A[mid] >= key)
      right = mid;
    else if (A[mid + 1] < key)
      left = mid + 1;
  }

  return -1; // all the elements >= key
}

ll bin_search_vector(ll key, vl v, ll left, ll right) {
  // return the index idx where v[idx] = key.
  // v[left] is start and v[right] is end..
  // In other words, v[right], not v[right - 1], must be defined.
  while (right >= left) {
    ll mid = left + (right - left) / 2;
    if (v[mid] == key)
      return mid;
    else if (v[mid] > key)
      right = mid - 1;
    else if (v[mid] < key)
      left = mid + 1;
  }
  return -1;
}

ll lower_bound_bin_search_vector(ll key, vl v) {
  // the return value N satisfies
  // v[N - 1] < key <= v[N]
  // N == -1 if all the elements < key
  return lower_bound(all(v), key) - v.begin();
}

ll inf_bin_search_vector(ll key, vl v) {
  // the return value N satisfies
  // v[N - 1] <= key < v[N] <= key + 1
  // N == -1 if all the elements <= key
  return lower_bound(all(v), key + 1) - v.begin();
}

ll upper_bound_bin_search_vector(ll key, vl v) {
  // the return value N satisfies
  // v[N] <= key < v[N + 1]
  // N == -1 if all the elements > key
  return upper_bound(all(v), key) - v.begin(); // (- 1)
}

ll sup_bin_search_vector(ll key, vl v) {
  // the return value N satisfies
  // v[N] <= key - 1 < key <= v[N + 1]
  // N == -1 if all the elements >= key
  return upper_bound(all(v), key - 1) - v.begin() - 1;
}

ll fact(ll n) {
  if (n == 0)
    return 1;
  return n * fact(n - 1);
}

ll fact_mod(ll n, ll mod) {
  if (n == 0)
    return 1;
  return n * fact_mod(n - 1, mod);
}

/*
ll facts[6000], facts_inv[6000], inv[6000];

void fact_memo(ll n, ll mod){
    facts[0] = facts[1] = 1;
    facts_inv[0] = facts_inv[1] = 1;
    inv[1] = 1;

    For(i, 2, n + 1){
        facts[i] = (i * facts[i - 1]) % mod;
        inv[i] = mod - inv[mod % i] * (mod / i) % mod;
        facts_inv[i] = facts_inv[i - 1] * inv[i] % mod;
    }
}

ll nCk(ll n, ll r){
    if (n == r && n == 0) return 1;
    else if (n <= 0 || r < 0 || r > n) return 0;
    ll val = (facts[n] * facts_inv[n - r]) % MOD;
    val *= facts_inv[r];
    return val % MOD;
}
*/

bool is_prime(ll n) {
  if (n <= 1)
    return false;
  for (ll i = 2; i * i <= n; i++) {
    if (n % i == 0)
      return false;
  }
  return true;
}

ll bool_sum(ll a1, ll a2) {
  if (a1 == 1 || a2 == 1)
    return 1;
  return 0;
}

mll prime_factorization(ll n) {
  ll i = 2;
  mll table;
  while (i * i <= n) {
    while (n % i == 0) {
      table[i]++;
      n /= i;
    }
    i++;
  }
  if (n > 1)
    table[n] = 1;
  return table;
}

vl divisor_table(ll n) {
  vl table;
  ll i = 1;
  while (i * i <= n) {
    if (n % i == 0) {
      table.pb(i);
      if (i * i != n)
        table.pb(n / i);
    }
    i++;
  }

  sort(all(table));

  return table;
}

ll char_to_idx(char c) {
  ll idx = 0;
  Forchar(cc, 'a', 'z') {
    if (c == cc)
      return idx;
    else
      idx++;
  }
}

ll next_combination(ll sub) {
  /*
  ### Attention ###
  if k is 0 or 1 and n is 0, it does not work well.

  ll n, k; ll bit = (1 << k) - 1;
  for (; bit < (1 << n); bit = next_combination(bit)){
      bool ith = bit & (1 << i);
      procedures...
  }

      sub & -sub: the binary which shares the last digit whose value is 1 in sub
      sub + x   : carry up the last digit
          ~y    : the binary whose digits are 1 if y's digit is 0.
  (sub & ~y) / x: reduce the same number of 0s after first 1 in x from (sub &
  ~y).
  */
  ll x = sub & -sub, y = sub + x;
  return (((sub & ~y) / x) >> 1) | y;
}

vl z_algorithm(str s) {
  ll n = s.length();
  vl res(n);
  res[0] = n;
  ll i1 = 1, i2 = 0;

  while (i1 < n) {
    while (i1 + i2 < n && s[i2] == s[i1 + i2])
      ++i2;
    res[i1] = i2;
    if (i2 == 0) {
      ++i1;
      continue;
    }
    ll i3 = 1;
    while (i1 + i3 < n && i3 + res[i3] < i2) {
      res[i1 + i3] = res[i3];
      ++i3;
    }
    i1 += i3, i2 -= i3;
  }
  return res;
}

ll big_number_mod(str s, ll mod) {
  ll l = s.length();
  ll idx = 0;
  ll val = 0;
  ll tenth = 1;
  while (idx < l) {
    ll m = ctol(s[l - 1 - idx]);
    val += (m * tenth) % mod;
    val %= mod;
    tenth *= 10;
    tenth %= mod;
    idx++;
  }

  return val;
}

ll big_number_compare(str s1, str s2) {
  if (s1.length() > s2.length())
    return 1;
  else if (s1.length() < s2.length())
    return -1;
  else if (s1 == s2)
    return 0;

  return 2 * (s1 > s2) - 1;
}

ll string_to_ll(str s) {
  ll l = s.length();
  ll idx = 0;
  ll val = 0;
  ll tenth = 1;
  while (idx < l) {
    ll m = ctol(s[l - 1 - idx]);
    val += (m * tenth);
    tenth *= 10;
    idx++;
  }

  return val;
}

str reflected_string(str s) {
  str t, u;
  ll n = s.length();
  t = s;
  reverse(all(t));
  u = substring(t, 0, n - 2) + s + substring(t, 1, n - 1);
  return u;
}

ld distance_between_point_line(point l_begin, point l_end, point p) {
  ll xl1 = l_begin.x, yl1 = l_begin.y;
  ll xl2 = l_end.x, yl2 = l_end.y;
  ll xp = p.x, yp = p.y;
  ll a = yl2 - yl1;
  ll b = -xl2 + xl1;
  ll c = -a * xl2 - b * yl2;
  return abs(ld(a * xp + b * yp + c)) / ld(sqrt(a * a + b * b));
}

bool is_cross(point l1_begin, point l1_end, point l2_begin, point l2_end) {
  ll x1 = l1_begin.x, y1 = l1_begin.y;
  ll x2 = l1_end.x, y2 = l1_end.y;
  ll x3 = l2_begin.x, y3 = l2_begin.y;
  ll x4 = l2_end.x, y4 = l2_end.y;
  ll val1 = (x1 - x2) * (y3 - y1) + (y1 - y2) * (x1 - x3);
  ll val2 = (x1 - x2) * (y4 - y1) + (y1 - y2) * (x1 - x4);
  ll val3 = (x3 - x4) * (y1 - y3) + (y3 - y4) * (x3 - x1);
  ll val4 = (x3 - x4) * (y2 - y3) + (y3 - y4) * (x3 - x2);

  return val1 * val2 < 0 && val3 * val4 < 0;
}

ld space_of_triangle(point p1, point p2, point p3) {
  ll x1 = p1.x, y1 = p1.y;
  ll x2 = p2.x, y2 = p2.y;
  ll x3 = p3.x, y3 = p3.y;
  ll v1 = x2 - x1;
  ll u1 = y2 - y1;
  ll v2 = x3 - x1;
  ll u2 = y3 - y1;
  ld s = ld(v1 * u2 - u1 * v2) / ld(2);
  return abs(s);
}

pair<point, ll> center_2det_of_3points(point p1, point p2, point p3) {
  // the center of circle on the given three points
  // return the determinant value and the product of center points and 2 *
  // determinant value
  ll x1 = p1.x, y1 = p1.y;
  ll x2 = p2.x, y2 = p2.y;
  ll x3 = p3.x, y3 = p3.y;

  // center of 2 points
  ll c2x_2 = x2 + x1, c2y_2 = y2 + y1;
  ll c3x_2 = x3 + x1, c3y_2 = y3 + y1;

  // vertical vector of 2 lines
  ll b2y = x2 - x1, b2x = -y2 + y1;
  ll b3y = x3 - x1, b3x = -y3 + y1;

  ll x1_2 = c3x_2 * b3y - c3y_2 * b3x, y1_2 = c2x_2 * b2y - c2y_2 * b2x;
  ll det = -b3y * b2x + b3x * b2y;
  if (det == 0)
    return {{INF, INF}, det};
  ll cx_2det = -b2x * x1_2 + b3x * y1_2, cy_2det = -b2y * x1_2 + b3y * y1_2;
  return {{cx_2det, cy_2det}, det};
}

ll inversion_number(vl a, ll a_max) {
  /*
  Paramters
  ---------
  a: vector<ll>
      All the elements must be non-negative.
      Prefably the elements are compressed to reduce the computational cost.
  a_max: ll
      The maximum value of the vector a or the value bigger than the value
  stated previously.
  */

  BIT bit(a_max + 1);
  ll val = 0;
  rep(i, a.size()) {
    // i is the number of elements that have lower index than a[i].
    // call the number of elements that have lower value than a[i]
    // by subtracting these two, the residual number is the number of elements
    // that have larger value
    val += i - bit.query(a[i] - 1); // cumulative sum from 0 to a[i] - 1
    bit.update(a[i], 1);
  }
  return val;
}

template <typename T> vector<T> compress(vector<T> v) {
  // sort and remove all the duplicated values
  sort(all(v));
  v.erase(unique(all(v)), v.end());
  return v;
}

template <typename T> map<T, ll> dict(const vector<T> &v) {
  map<T, ll> d;
  rep(i, v.size()) d[v[i]] = i;
  return d;
}

void GaussJordanBitVector(vl &bs) {
  ll n = bs.size();
  ll rank = 0;
  ll j = 0;
  revrep(i, N_DIGITS) {
    for (j = rank; j < n; j++)
      if (bs[j] & (1LL << i))
        break;
    if (j == n)
      continue;
    if (j > rank)
      bs[rank] ^= bs[j];
    for (j = rank + 1; j < n; j++)
      bs[j] = min(bs[j], bs[j] ^ bs[rank]);
    rank++;
  }
}

ll kruskal(vector<undirected_edge> &es, ll n_vertex) {
  sort(all(es));
  UnionFind uf(n_vertex);

  ll min_cost = 0;

  rep(i, es.size()) {
    undirected_edge &e = es[i];
    if (!uf.is_same(e.from, e.to)) {
      min_cost += e.cost;
      uf.unite(e.from, e.to);
    }
  }
  return min_cost;
}

ll LongestIncreasedSequence(vl &v, ll n) {
  vl dp(n, INF);
  rep(i, n) * lower_bound(all(dp), v[i]) = v[i];
  return find(all(dp), INF) - dp.begin();
}

/*
const ll N_VERTEX = 310;
ll a, b, t;
ll dist[N_VERTEX][N_VERTEX];

void warshall_floyd(ll n){
    // rep(i, n) rep(j, n) dist[i][j] = INF * (i != j);
    rep(k, n) rep(i, n) rep(j, n) dist[i][j] = min(dist[i][j], dist[i][k] +
dist[k][j]);
}

int main(void){
    in2(n, m);
    rep(i, n) rep(j, n) dist[i][j] = INF * (i != j);
    rep(i, m){
        in3(a, b, t);
        a--; b--;
        dist[a][b] = t;
        dist[b][a] = t;
    }

    warshall_floyd(n);
}

ll dist[1005], vertex_pre[1005];

void dijkstra(ll start, ll n) {
    priority_queue<pl, vector<pl>, greater<pl>> edge_costs;
    fill(dist, dist + n, INF); // fill(vertex_pre, vertex_pre + n, -1);
    dist[start] = 0;
    edge_costs.push(pl(0, start));

    while (!edge_costs.empty()) {
        pl edge_cost = edge_costs.top();
        edge_costs.pop();
        ll idx = edge_cost.second;
        ll cost = edge_cost.first;
        if (dist[idx] < cost) continue;

        rep(i, graph[idx].size()){
            edge e = graph[idx][i];
            if (dist[e.to] > dist[idx] + e.cost){
                dist[e.to] = dist[idx] + e.cost;
                // vertex_pre[e.to] = idx;
                edge_costs.push(pl(dist[e.to], e.to));
            }
        }
    }
}

vl get_predecessor(ll g){
    vl path;
    for (; g != -1; g = vertex_pre[g]) path.pb(g);

    reverse(all(path));
    return path;
}

int main(void){
    in2(n, m);
    rep(i, m){
        in3(a, b, t);
        a--; b--;
        G[a].pb({b, t});
        G[b].pb({a, t});
    }

    dijkstra(0, n);
}


# ABC061D

bool find_negative_cycle(ll goal){
    rep(i, n) rep(v, n) rep(k, graph[v].size()){
        edge e = graph[v][k];
        if (dist[e.to] != INF && dist[e.to] > dist[v] + e.cost){
            dist[e.to] = -INF;
            if (goal == -1) return true;
            else if (goal == e.to) return true;
        }
    }
    return false;
}

bool bellman_ford(ll start, ll n, ll goal){
    // if there is a closed circuit, it returns false. (when goal == -1)
    // if the distance to goal cannot be obtained, it returns false (when goal
!= -1) fill(dist, dist + n, INF); dist[start] = 0; rep(i, n) rep(v, n) rep(k,
graph[v].size()){ edge e = graph[v][k]; if (dist[v] != INF && dist[e.to] >
dist[v] + e.cost) dist[e.to] = dist[v] + e.cost;
    }

    if (find_negative_cycle(goal)) return false;
    return true;
}

*/

/*
    # 1. The usage of map pair
    map<pl, ll> cnt;
    cnt[{i, j}] = 0;
    items(kv, cnt){
        prl2(kv.first, kv.second);
    }

    # 2. The usage of next_permutation and combination (factorial search)
    ll a[8];
    rep(i, 8) a[i] = i;
    sort(a, a + 8);
    do{
    }while(next_permutation(a, a+n));

    // here, combination
    ll n, r;
    ll i1, i2, ..., ir;
    For(i1, n - r, n) For(i2, n - r - 1, i1) ... For(ir, n - 2 * r + 1, irr){
   process;}

    # 3. bit search
    ll n;
    in1(n);
    const ll base = 3;
    ll upper = power_normal(base, n);

    rep(i, upper){
        ll tmp = i;
        rep(j, n){
            rep(k, base) if (tmp % base == k) prl(k);
            tmp /= base;
        }
    }

    # 4. imos method
    // used when we would like to count the number which
    // shows how many times the numbers between l and r belongs to smt.
    // This method is composed of three process.
    ll n, m, s[MAX_M], l, r;
    in2(n, m);
    rep(i, m) s[i] = 0;

    // 1st step
    rep(i, n){
        in3(l, r, c);
        l--; r--; // if l starts from 1.
        s[l] += c; s[r + 1] -= c;
    }

    // 2nd step
    rep(i, m - 1) s[i + 1] += s[i];
    // 3rd step: judgement...

    #5. shakutori method (syakutori, two pointers technique)
    // 1. strech right side while the condition is met.
    // 2. renew the answer
    // 3. increments left side
    // 4. Back to 1. (l <= r must be satisfied all the time.)

    ll l = 0; ll r = 0;
    while (l < n){
        r = max(r, l);
        if (l == r) r++;
        while(r < n && cond) r++;
        answer += r - l; l++;
    }
    prl(answer);

    #6. priority queue

    pq q;
    ll answer = 0;
    ll v;

    rep(i, n) q.push(a[i]);
    rep(i, m){
        v = q.top(); q.pop(); // get the top value and dump the value from queue
        v /= 2; q.push(v); // add the new value
    }

    while(!q.empty()){
        answer += q.top();
        q.pop();
    }

    #7. The shortest path (distance) between the k-th edge and another edge
   (Tree) Graph tree[MAX_N]; ll depth[MAX_N];

    void dfs(ll source, ll parent, ll all_cost){
        depth[source] = all_cost;
        items(e, tree[source]){
            if (e.to == parent) continue;
            dfs(e.to, source, all_cost + e.cost);
        }
    }

    ll n, k, a, b, c;

    in2(n, k);
    rep(i, n - 1){
        in3(a, b, c);
        a--; b--;
        tree[a].pb({b, c});
        tree[b].pb({a, c});
    }

    k--;
    dfs(k, -1, 0);

    #10. Visiting Subtree using recurrent function (ABC138D)

    Graph tree[MAX_N];
    ll c[MAX_N];
    bool visited[MAX_N];

    void dfs(ll source, ll parent, ll val){
        visited[source] = true;
        c[source] += val;
        rep(i, tree[source].size()){
            rep(i, m){ll res = n % match[i].e1;}
            ll vertex = tree[source][i].to;
            if (vertex == parent) continue;
            dfs(vertex, source, c[source]);
        }
    }

    #11. bfs ABC146D, ABC007C
    1. first create a tree.
    2. start searching from a node.
    3. do some processes and push nodes connected with a given target node in
   BFS.
    4. repeat a series of procedure until queue is empty.

    queue<pl> q;

    void bfs(ll source, ll parents){
        ll n_edge = graph[source].size();
        if (parents != -1) dist[source] = min(dist[source], dist[parents] + 1);
        if (visited[source]) return;
        visited[source] = true;

        rep(idx, n_edge){
            ll target = graph[source][idx].to;
            if (target == parents) continue;
            q.push(mp(target, source));
        }
    }

    q.push(mp(sg.e1, -1));
    while(!q.empty()){
        pl source = q.front(); q.pop();
        bfs(source.e1, source.e2);
    }

    #12. grid to distance matrix (dx, dy)
    ll w, h;
    ll pos_to_idx(ll x, ll y){
        return y * w + x;
    }

    pl idx_to_pos(ll idx){
        return mp(idx % w, idx / w);
    }

    rep(y, h){
        in1(s);
        rep(x, w){
            if (s[x] == '#') wall[x][y] = true;
            else wall[x][y] = false;
        }
    }

    rep(i1, h * w)rep(i2, h * w) dist[i1][i2] = INF * (i1 != i2);

    rep(x, w)rep(y, h){
        ll idx1 = pos_to_idx(x, y); ll idx2;
        if (wall[x][y]) continue;
        if (x != 0 && !wall[x - 1][y]){
            idx2 = pos_to_idx(x - 1, y);
            // if warshall floyd
            dist[idx1][idx2] = 1;
            // if dijkstra
            // graph[idx1].pb({idx2, 1});
        }
        if (x != w - 1 && !wall[x + 1][y]){
            idx2 = pos_to_idx(x + 1, y);
            dist[idx1][idx2] = 1;
            // graph[idx1].pb({idx2, 1});
        }
        if (y != 0 && !wall[x][y - 1]){
            idx2 = pos_to_idx(x, y - 1);
            dist[idx1][idx2] = 1;
            // graph[idx1].pb({idx2, 1});
        }
        if (y != h - 1 && !wall[x][y + 1]){
            idx2 = pos_to_idx(x, y + 1);
            dist[idx1][idx2] = 1;
            // graph[idx1].pb({idx2, 1});
        }
    }

    # Cumulative sum (2 dimension)

    ll func(ll x, ll y, ll dx, ll dy){
        if (x + dx > w || y + dy > h) return - INF;
        ll val = cum[x + dx][y + dy];
        val += cum[x][y];
        val -= cum[x][y + dy];
        val -= cum[x + dx][y];
        return val;
    }

    rep(x, w + 1) cum[x][0] = 0;
    rep(y, h + 1) cum[0][y] = 0;
    rep(y, h + 1) rep(x, w)
        cum[x + 1][y + 1] = cum[x][y + 1] + vs[x][y];

    rep(x, w + 1) rep(y, h)
        cum[x][y + 1] += cum[x][y];

    # DEBUG_MATRIX

    rep(i, n){
        rep(j, n) prs(a[i][j]);
        prl("");
    }

*/

/*
# the operators regarding bit
& (AND), | (OR), ^ (XOR)
- (REVERSE), >> (SMALLER SHIFT)
<< (BIGGER SHIFT)


     x1: 0000 0001 0010 0101 0110 0111 0111
     x2: xxxx 0001 0011 0100 0101 1000 0110
x1 & x2: 0000 0001 0010 0100 0100 0000 0110

      x: 1001 1010  1100 1011 1101  1111
x & - x: 0001 0010  0100 0001 0001  0001
    sum: 1010 1100 10000 1100 1100 10000

x << y is x * 2 ** y
x >> y is rep(i, y) x = x // 2

####### Attention #######
1 << i and 1LL << i is different. If programs show WA, try switch to this one.
Let S be a bit sequence and i be a non-negative integer
S & (1 << i) -> if true, i in S
S | (1 << i) -> S union {i}
S & -(1 << i) -> S - {i}
__builtin_popcount(S) -> the number of elements in S
S = 0 -> S is an empty set
__builtin_popcountl(i) -> the number of 1 in binary
S = (1 << n) - 1 -> S includes all the elements up to the n-th

#Conditional Operator
condition ? true : false;

#iterator
type declaration: auto
value reference: *itr
increment: itr++
decrement: itr--
substitution of value: *itr = smt

# inclusion-exclusion principle
|U[i = 1 to n] Ai| = sum[i = 1 to n] |Ai| - sum[i < j]|Ai ^ Aj| + ... + (-1)^(n
- 1) |^[i = 1 to n]Ai|
*/

const ll MAX_N = 200005;
bool okay = false;
ll answer = 0;
ll n, k;
vl as, bs;
// pl = (a', b') : a' and b' is coprime.
map<pl, ll> cnt;
vpl bad;
map<pl, bool> visited;
ll memo[65];

void solve() {
  as = bs = vl(n);
  rep(i, n) {
    ll a, b;
    in2(a, b);
    if (a == 0 && b != 0)
      b = 1;
    else if (a != 0 && b == 0)
      a = 1;
    else if (a != 0 && b != 0) {
      ll g = gcd(a, b);
      a /= g, b /= g;
    }

    if (a * b >= 0)
      a = abs(a), bs[i] = abs(b);
    else
      a = abs(a), b = -abs(b);
    as[i] = a, bs[i] = b;
    cnt[{a, b}]++;
    visited[{a, b}] = false;
  }

  memo[0] = 1;
  rep(i, 60) {
    memo[i + 1] = 2 * memo[i];
    memo[i + 1] %= MOD;
  }

  items(kv, cnt) {
    pl p = kv.e1;
    ll a1 = p.e1, b1 = p.e2;
    ll a2 = p.e2, b2 = -p.e1;

    if (b1 < 0)
      a2 = -b1, b2 = a1; // both positive
    if (visited[{a1, b1}] || visited[{a2, b2}])
      continue;
    bad.pb({cnt[{a1, b1}], cnt[{a2, b2}]});
    visited[{a1, b1}] = visited[{a2, b2}] = true;
  }

  answer = 1;
  rep(i, bad.size()) {
    ll c1 = bad[i].e1, c2 = bad[i].e2;
    answer *= (memo[c1] + memo[c2] - 1) % MOD;
    answer %= MOD;
  }
  prl(answer - 1);
}

int main(void) {
  in1(n);
  // assert(k <= 1000);
  solve();
  return 0;
}