# Patent

## Title
Decimal elementary functions computation

## Abstract

A method for executing a decimal elementary function (DEF) computation from multiple decimal floating-point operands, including: extracting mantissae and exponents from the operands; generating normalized mantissae by shifting the mantissae based on the number of leading zeros; calculating a plurality of approximations for a logarithm of the first normalized mantissa; calculating, using the plurality of approximations for the logarithm, a plurality of approximations for a product of the second normalized mantissa and a sum based on the logarithm of the first normalized mantissa and an exponent; generating a plurality of shifted values by shifting the plurality of approximations for the product; generating a plurality of fraction components from the plurality of shifted values; calculating an antilog based on the plurality of fraction components; and outputting a decimal floating-point result of the DEF computation comprising a resultant mantissa based on the antilog and a resultant biased exponent.

## Background
BACKGROUND
Decimal arithmetic has a growing need in many commercial applications, financial applications, green energy applications, billing applications, and database systems where binary arithmetic is not sufficient because of the inexact mapping between some decimal and binary numbers. For example, the decimal number 0.1 does not have an exact binary representation. Moreover, decimal arithmetic is the norm of the human calculations.
SUMMARY OF INVENTION
In general, in one aspect, the invention relates to a method for executing a decimal elementary function (DEF) computation from a first decimal floating-point operand (DFPO) operand and a second DFPO. The method comprises: extracting a first mantissa and a first biased exponent from the first DFPO and a second mantissa and a second biased exponent from the second DFPO; generating a first normalized mantissa by shifting the first mantissa based on a number of leading zeros in the first mantissa; generating a second normalized mantissa by shifting the second mantissa based on a number of leading zeros in the second mantissa; calculating, using a decimal logarithm hardware unit (DLHU) implementing a first digit recurrence algorithm, a plurality of approximations for a logarithm of the first normalized mantissa; calculating, using a decimal multiplier hardware unit (DMHU) and the plurality of approximations for the logarithm, a plurality of approximations for a product of the second normalized mantissa and a first sum based on the logarithm of the first normalized mantissa and the first biased exponent; generating a plurality of shifted values by shifting the plurality of approximations for the product based on the second biased exponent; generating a plurality of fraction components from the plurality of shifted values; calculating, using a decimal antilogarithm hardware unit (DAHU) implementing a second digit recurrence algorithm, an antilog based on the plurality of fraction components; and outputting a decimal floating-point result of the DEF computation comprising a resultant mantissa based on the antilog and a resultant biased exponent based on at least one integer component of at least one of the plurality of shifted values.
In general, in one aspect, the invention relates to a system for executing a decimal elementary function (DEF) computation from a first decimal floating-point operand (DFPO) operand and a second DFPO. The system comprises: an input processing hardware unit (IPHU) configured to: generate a first normalized mantissa from a first mantissa extracted from the first DFPO based on a number of leading zeros in the first mantissa; and generate a second normalized mantissa from a second mantissa extracted from the second DFPO based on a number of leading zeros in the second mantissa; a decimal logarithm hardware unit (DLHU) configured to calculate a plurality of approximations for a logarithm of the first normalized mantissa using a first digit recurrence algorithm; a decimal multiplier hardware unit (DMHU) configured to calculate a plurality of approximations for a product of the second normalized mantissa and a first sum using the plurality of approximations for the logarithm, wherein the first sum is based on the logarithm of the first normalized mantissa and a first biased exponent extracted from the first DFPO; a shifter configured to generate a plurality of shifted values by shifting the plurality of approximations for the product based on a second biased exponent extracted from the second DFPO; a decimal antilogarithm hardware unit (DAHU) configured to calculate, using a second digit recurrence algorithm, an antilog based on a plurality of fraction components generated from the plurality of shifted values; and an output formulation hardware unit configured to generate a decimal floating-point result of the DEF comprising a resultant mantissa based on the antilog and a resultant biased exponent based on at least one integer component of at least one of the plurality of shifted values.
In general, in one aspect, the invention relates to a system for calculating a logarithm of a decimal floating-point operand (DFPO) to a base (B). The system comprises: an input processing hardware unit (IPHU) configured to: extract a mantissa and a biased exponent from the DFPO; and generate a normalized mantissa by shifting the mantissa based on a number of leading zeros in the mantissa; a decimal logarithm hardware unit (DLHU) configured to calculate a plurality of approximations for a logarithm of the normalized mantissa to base 10 using a digit recurrence algorithm; a decimal multiplier hardware unit (DMHU) configured to calculate a product of a sum and an inverse of a logarithm of B to base 10 using the plurality of approximations, wherein the sum is based on the biased exponent and the logarithm of the normalized mantissa to base 10; and an output formulation hardware unit configured to generate a decimal floating-point result of the logarithm of the DFPO comprising a resultant mantissa based on the product and a resultant biased exponent based on the exponent and the number of leading zeros.
In general, in one aspect, the invention relates to a system for calculating a base (B) raised to a decimal floating-point operand (DFPO). The system comprises: an input processing hardware unit configured to: extract a mantissa and a biased exponent from the DFPO; and generate a normalized mantissa by shifting the mantissa based on a number of leading zeros in the mantissa; a decimal multiplier hardware unit (DMHU) configured to calculate a product of the normalized mantissa and a logarithm of B to base 10; a shifter configured to generated a shifted value by shifting the product based on the biased exponent and the number of leading zeros; a decimal antilogarithm hardware unit (DAHU) configured to calculate an antilog of a fraction component of the shifted value using a digit recurrence algorithm; and an output formulation hardware unit (OFHU) configured to generate a decimal floating-point result comprising a resultant mantissa based on the antilog and a resultant biased exponent based on at least an integer component of the shifted value.
Other aspects of the invention will be apparent from the following description and the appended claims.



BRIEF DESCRIPTION OF DRAWINGS
FIG. 1 shows a block diagram depicting a system in accordance in with one or more embodiments of the invention.
FIG. 2 shows a flowchart in accordance with one or more embodiments of the invention.
FIG. 3 shows a first stage of a decimal logarithm hardware unit (DLHU) in accordance with one or more embodiments of the invention.
FIG. 4 shows a second stage of the DLHU in accordance with one or more embodiments of the invention.
FIG. 5 shows a timing diagram in accordance with one or more embodiments of the invention.
FIG. 6 shows a decimal multiplier hardware unit (DMHU) in accordance with one or more embodiments of the invention.
FIG. 7 shows a first stage of a decimal antilogarithm hardware unit (DAHU) in accordance with one or more embodiments of the invention.
FIG. 8 shows a second stage of the DAHU in accordance with one or more embodiments of the invention.
FIG. 9-11 show tables in accordance with one or more embodiments of the invention.
FIG. 12 shows a computer system in accordance with one or more embodiments of the invention.



DETAILED DESCRIPTION
Specific embodiments of the invention will now be described in detail with reference to the accompanying figures. Like elements in the various figures are denoted by like reference numerals for consistency.
In the following detailed description of embodiments of the invention, numerous specific details are set forth in order to provide a more thorough understanding of the invention. However, it will be apparent to one of ordinary skill in the art that the invention may be practiced without these specific details. In other instances, well-known features have not been described in detail to avoid unnecessarily complicating the description.
In general, embodiments of the invention provide a system and method for executing a decimal elementary functions computation (e.g., a decimal power computation: XY), where both operators (X, Y) are in decimal floating-point representations. Accordingly, assume X has an absolute value of Mx·10^(EX) and Y has an absolute value of MY·10^(EY). Then XY=10^(Y·log X)=10^[MY·10^(EY)·log(MX·10^(EX))]=10^[MY·10^(EY)·(log(MX)+EX)]. Thus, to calculate the final result, three overlapped operations are done iteratively: logarithm, multiplication, and antilogarithm. One or more correction schemes are implemented between each stage.
FIG. 1 shows a system (100) in accordance with one or more embodiments of the invention. The system (100) inputs two decimal floating-point operands (X, Y) and outputs a decimal floating-point powering of the operands (i.e., Z=XY). As shown in FIG. 1, the system (100) has multiple components including an input processing hardware unit (105), a decimal logarithm hardware unit (DLHU) (110), a decimal multiplier hardware unit (120), a shifter (130), a decimal antilogarithm hardware unit (DAHU) (140), an output formulation hardware unit (145), and a master control hardware unit (150). One or more of the hardware components (105, 110, 120, 130, 140, 145, 150) may be embedded within one or more general purpose processor cores, field programmable gate arrays (FPGAs), and/or application specific integrated circuits (ASICs).
In one or more embodiments of the invention, decimal floating-point representations divide a number (e.g., X, Y, Z) into a sign, a biased exponent, and a significand (i.e., mantissa). The quantity of bits required to represent the number depends on the specific decimal floating-point format being implemented. For example, 64 bits are required for the decimal64 format, while 128 bits are required for the decimal128 format. The precision (p) of a decimal floating-point format corresponds to the size, in decimal digits, of the significand. For example, the decimal64 format includes a significand that is 16 decimal digits in size. Accordingly, the precision of the decimal64 format is 16 (i.e., p=16). Similarly, the decimal128 format includes a significand that is 34 decimal digits in size. Accordingly, the precision of the decimal128 format is 34 (i.e., p=34). Further, decimal floating-point formats may also be used to represent positive and negative infinity, and special “not a number” (NaN) values. In one or more embodiments of the invention, the decimal floating-point operands (X, Y) and result (Z) conform with the IEEE Std 754-2008 decimal format.
In one or more embodiments of the invention, the input processing hardware unit (105) is configured to: extract the mantissae (MX, MY) and the biased exponents (EX, EY) from the decimal floating-point operands (X, Y); count the number of trailing zeros and/or leading zeros (leadingZerosX, leadingZerosY) in each of the extracted mantissae; convert the mantissae and the biased exponents to binary coded decimal (BCD) format; and normalize (i.e., left shift) the mantissae (MX/, MY/) based on the number of leading zeros. The input processing hardware unit (105) may further be configured to detect if the decimal floating-point radicand is a special value (e.g., positive infinity, negative infinity, NaNs, etc.) and forward the corresponding special square-root result to the output formation hardware unit (145).
In one or more embodiments of the invention, the master control hardware unit (150) is configured to calculate a sign of the result. The master control hardware unit (150) is configured to calculate a first correction factor (K) by subtracting a bias of the X operand and the number of leading zeros in MX from a precision of the X operand (i.e., K=P−leadingZerosX−bias), and add the correction factor to the biased exponent of the X operand (EX) (i.e., EX+K). The master control hardware unit (150) is also configured to calculate a second correction factor (L) by subtracting a bias of the Y operand and the number of leading zeros in MY from a precision of the Y operand (i.e., L=P−leadingZerosY−bias), and add the correction factor (L) to the biased exponent of the operand Y (EY) (i.e., EY+L). The master control hardware unit (150) is discussed in further detail below.
In one or more embodiments of the invention, the DLHU (110) is configured to iteratively calculate log10(MX/) using a digit recurrence algorithm. In one or more embodiments of the invention, the DMHU (120) is configured to iteratively calculate MY/·(log10(MX/)+EX+K). In one or more embodiments of the invention, the shifter (130) is configured to left shift the output of the DMHU (120) by EY+L digits. The shifter (130) may also separate the integer component and the fraction component from the shifted output. The integer component may correspond to the exponent (EZ) for MZ. The fraction component may be sent to the DAHU (140). In one or more embodiments of the invention, the DAHU (140) is configured to iteratively calculate 10^[10^(EY+L)·MY/·(log10(MX/)+EX+K)] (i.e., the normalized mantissa (MZ/) of the result) using a digit recurrence algorithm. The rounder (147) is configured to generate a rounded version of MZ/ (based on user specified parameters), and the denormalizer (148) is configured to de-normalized the rounded result based on a number of trailing zeros in MX. One or more of the components (110, 120, 130, 140, 147, 148) are further discussed below.
FIG. 2 shows a flowchart in accordance with one or more embodiments of the invention. The process shown in FIG. 2 may be used, for example, with the components of system (100) (e.g., DLHU (110), DMHU (120), Shifter (130), DAHU (140), discussed above in reference to FIG. 1) to execute a decimal powering computation (DPC) from two decimal floating-point operands (X, Y). One or more steps shown in FIG. 2 may be omitted, repeated, and/or performed in a different order among different embodiments of the invention. Accordingly, embodiments of the invention should not be considered limited to the specific number and arrangement of steps shown in FIG. 2.
Initially, the signs (SX, SY), the mantissae (MX, MY), and the biased exponents (EX, EY) are extracted form the decimal floating-point operand (202). In STEP 204, the extracted mantissae (MX, MY) are normalized (MX/, MY/) based on the number of leading zeros in the extracted mantissae. In STEP 206, multiple approximations for log10(MX/) are calculated using a DLHU implementing an iterative algorithm. In STEP 208, multiple approximations for the product MY/·(log10(MX/)+EX+K) are calculated based on the multiple approximations from STEP 206. In STEP 210, the output from STEP 208 is shifted by EY+L digits resulting in 10^(EY+L)·MY/·(log10(MX/)+EX+K). In STEP 212, each output of STEP 210 is partitioned into an integer component and a fraction component. In STEP 214, an antilog is calculated based on the multiple fraction components from STEP 212. The antilog corresponds to 10^[10^(EY+L)·MY/·(log10(MX/)+EX+K)]. In STEP 216, a floating-decimal result having a resultant mantissa based on the antilog and a biased exponent based on at least one integer component from STEP 212 is output as XY. Each of the steps (202, 204, 206, 208, 210, 212, 214, 216) is discussed further below.
Decimal Logarithmic Hardware Unit
This section presents a design and implementation of a decimal logarithmic hardware unit (e.g., DLHU (110)) based on a digit recurrence algorithm in accordance with one or more embodiments of the invention.
A valid logarithmic calculation is defined as:

log10(X)=log10(Mx×10Ex)=log10(Mx)+Ex  (1.2)

Assuming a normalized MX in the form of 0·d1d2 . . . dn×10k where n is the required precision and k is the exponent, So:

log10(X)=log10(Mx)+Ex+k  (1.3)

but since normalization bounds the input to 0.1≦MX≦0.999 . . . 9, then the result is bounded to −1≦log10(MX)<0. This facilitates the summation of log10 (MX)+EX+k, as the first term is always a negative fraction (except the case of −1) and the other two terms are small integers. The sum can be calculated by concatenating the 9's complement of the negative fraction to the value of EX+k−1.

Digit Recurrence Algorithm:
Consider the following mathematical identity of logarithms:




  
    
      log
      10
    
    ⁡
    
      (
      
        M
        x
      
      )
    
  
  =
  
    
      
        log
        10
      
      ⁡
      
        (
        
          
            M
            x
          
          ⁢
          
            ∏
            
              f
              j
            
          
        
        )
      
    
    -
    
      
        ∑
        
          j
          =
          1
        
        ∞
      
      ⁢
      
        
          log
          10
        
        ⁡
        
          (
          
            f
            j
          
          )
        
      
    
  




fj is an arbitrary set of numbers, but defined as fj=1+ej10−j in which MX is transformed to 1 by successive multiplication. This form of fj allows the use of a shift-and-add implementation.

If the following condition is satisfied:




  
    
      
        
          
            
              lim
              
                j
                ->
                ∞
              
            
            ⁢
            
              {
              
                
                  M
                  x
                
                ⁢
                
                  ∏
                  
                    f
                    j
                  
                
              
              }
            
          
          ->
          1
        
        ⁢
        
          

        
        ⁢
        
          Then
          ⁢
          
            
          
          ,
        
      
    
    
      
        (
        1.4
        )
      
    
  
  
    
      
        
          
            
              lim
              
                j
                ->
                ∞
              
            
            ⁢
            
              {
              
                
                  log
                  10
                
                ⁡
                
                  (
                  
                    
                      M
                      x
                    
                    ⁢
                    
                      ∏
                      
                        f
                        j
                      
                    
                  
                  )
                
              
              }
            
          
          ->
          0
        
        ⁢
        
          

        
        ⁢
        
          Finally
          ,
        
      
    
    
      
        (
        1.5
        )
      
    
  
  
    
      
        
          
            log
            10
          
          ⁡
          
            (
            
              M
              x
            
            )
          
        
        =
        
          0
          -
          
            
              ∑
              
                j
                =
                0
              
              ∞
            
            ⁢
            
              
                log
                10
              
              ⁡
              
                (
                
                  f
                  j
                
                )
              
            
          
        
      
    
    
      
        (
        1.6
        )
      
    
  




The corresponding recurrences for transforming MX and computing the logarithm, where j≧1, E[1]=MX and L[1]=0, are as follows:

E(j+1)=E[j](1+ej10−j)  (1.7)

L(j+1)=L(j)−log10(1+ej10−j)  (1.8)

The digits ej are selected so that E(j+1) converges to 1, 1 digit accuracy of the calculation result is, therefore, obtained in each iteration. After performing the last iteration of recurrence, the results are:

E(N+1)≈1  (1.9)

L(N+1)≈log10(Mx)  (1.10)

To have the selection function for ej, a scaled remainder is defined as,

W[j]=10j(1−E[j])  (1.11)

Thus,

E[j]=1−W[j]10−j  (1.12)

Substituting 1.12 in 1.7 yields,

W[j+1]=10(W[j]−ej+ejW[j]10−j)  (1.13)

A digit e1 is obtained by look-up table in the first iteration according to table 1.1. The remaining digits ej are selected by rounding the scaled remainder during the succeeding iterations. According to 1.13, the digits ej are selected according to the leading digits of W[j], and shall guarantee that W[j+1] remains bounded.
Selection by Rounding
The selected digits ej are achieved through rounding to the integer part of the residual indicated as 1.14, where ejε{−9, −8, −7 . . . , 0, . . . , 7, 8, 9}.

ej=round(W[j])  (1.14)

Then obtain 1.15:

−0.5≦W[j]−ej≦0.5  (1.15)

Since |ej+1|≦9, thus,

−9.5<W[j+1]<9.5  (1.16)

Equation 1.13 can be written as:

W[j+1]=10(W[j]−ej)+ej101-j(W[j]−ej+ej)  (1.17)

According to 1.15 and 1.17, the numerical analysis for 1.16 is expanded as follows:

−0.5×10+ej101-j(−0.5+ej)>−9.5  (1.18)

0.5×10+ej101-j(0.5+ej)<9.5  (1.19)

The numerical analysis results show that if and only if j≧3, the conditions 1.18 and 1.19 are satisfied. In doing so, the selection by rounding is only valid for iterations j≧3 and e1 and e2 can be only achieved by look-up tables. However, we can add restriction for e1 so that e2 can be achieved by selection by rounding and only one look-up table will be used. Because W[1]=10(Mx−1), W[2] can be achieved as:

W[2]=100−100×Mx−10e1×Mx  (1.20)

When the value of j is 2, the value of e2 is in the range of −7<e2<7 so that 1.18 and 1.19 are satisfied. −7<e2<7 is brought to 1.14, then 1.20 is obtained:

−6.5<W[2]<6.5  (1.21)

From 1.20 and 1.21 we can obtain a conclusion that input decimal number MX must in the range of 0.5≦MX≦1 so that e2 can be achieved by selection by rounding. The look-up table for selection for e1 is shown in table 1.1. Because MX is in the range of 0.1≦MX<1, the input number MX in the range of 0.1≦MX<0.5 needs to be adjusted by multiplying with 2, 3 or 5. Then the adjusted number MX/ is in the range of 0.5≦MX/≦1 are calculated by selection by rounding. Finally, the logarithm results log10(MX/) are adjusted by subtracting the constant (log10(2), log10(3) or log10(5)) to compensate the previous multiplication and obtain the final logarithm results of log10(MX).







TABLE 1.1







Look up table for e1 Selection










The range of Mx
e1







[0.96, 1.00)
0



[0.88, 0.95)
1



[0.81, 0.87)
2



[0.76, 0.80)
3



[0.70, 0.75)
4



[0.66, 0.69)
5



[0.62, 0.65)
6



[0.59, 0.61)
7



[0.56, 0.58)
8



[0.50, 0.55)
9










Approximation of Logarithm
Logarithm result can be achieved by accumulating the values of −log10(1+ej10−j) in each iteration. The values of −log10(1+ej10−j) may be stored in another lookup table. With the increasing number of iterations, however, the size of the table will become prohibitively large. Therefore, the series expansion of logarithm function log10(1+x) can be used to reduce the size of the look-up table:




  
    
      
        
          
            log
            10
          
          ⁡
          
            (
            
              1
              +
              x
            
            )
          
        
        =
        
          
            (
            
              x
              -
              
                
                  x
                  2
                
                2
              
              +
              ...
            
            )
          
          
            ln
            ⁡
            
              (
              10
              )
            
          
        
      
    
    
      
        (
        1.22
        )
      
    
  




Hence, after iteration j=k the values of log10(1+ej10−j) can be approximated by




  
    
      e
      j
    
    ⁢
    
      10
      
        -
        j
      
    
  
  
    ln
    ⁡
    
      (
      10
      )
    
  




where k is the number of iterations satisfying inequality 1.23. To guarantee a predetermined accuracy of n the series approximation can be used in the iterations when the constraint





  
    
      x
      2
    
    
      2
      ⁢
      
        ln
        ⁡
        
          (
          10
          )
        
      
    
  
  <
  
    10
    
      -
      n
    
  




is met where x=ej10−j





  
    
      
        
          
            
              e
              k
              2
            
            ⁢
            
              10
              
                
                  -
                  2
                
                ⁢
                
                  
                
                ⁢
                k
              
            
          
          
            2
            ⁢
            
              
            
            ⁢
            
              ln
              ⁡
              
                (
                10
                )
              
            
          
        
        <
        
          10
          
            -
            n
          
        
      
    
    
      
        (
        1.23
        )
      
    
  




Error Analysis
The error will be calculated for a predetermined generic accuracy n.
Inherent Error of Algorithm
This error due to the difference between the logarithm results obtained from finite iterations and the exact result obtained from infinite iterations. Since the decimal logarithmic result is achieved after nth iteration, εi can be defined as:




  
    
      
        
          ɛ
          i
        
        =
        
          -
          
            
              ∑
              
                j
                =
                n
              
              ∞
            
            ⁢
            
              
            
            ⁢
            
              
                log
                10
              
              ⁡
              
                (
                
                  1
                  +
                  
                    
                      e
                      j
                    
                    ⁢
                    
                      10
                      
                        -
                        j
                      
                    
                  
                
                )
              
            
          
        
      
    
    
      
        (
        1.24
        )
      
    
  




Since ej represents the error between two successive iterations and ejΣ[−9, 9], we choose the worst cases (ej=9 or −9) to analyze maximum εi




  
    
      
        
          ɛ
          i
        
        =
        
          -
          
            
              ∑
              
                j
                =
                n
              
              ∞
            
            ⁢
            
              
            
            ⁢
            
              
                log
                10
              
              ⁡
              
                (
                
                  1
                  ±
                  
                    9
                    ×
                    
                      10
                      
                        -
                        j
                      
                    
                  
                
                )
              
            
          
        
      
    
    
      
        (
        1.25
        )
      
    
  




According to 1.25, the maximum εi is in the range:

−4.34×10−n≦εi≦4.34×10−n  (1.26)

Approximation Error
The approximate value




  
    
      e
      j
    
    ⁢
    
      10
      
        -
        j
      
    
  
  
    ln
    ⁡
    
      (
      10
      )
    
  




is used to estimate log(1+ej10−j) from the kth to the nth iteration. According to the series expansion of logarithm function in 1.22, this produces an approximation error, εa:





  
    
      
        
          ɛ
          a
        
        =
        
          
            ∑
            
              j
              =
              k
            
            n
          
          ⁢
          
            
          
          ⁢
          
            
              
                -
                
                  
                    
                      (
                      
                        
                          e
                          j
                        
                        ⁢
                        
                          10
                          
                            -
                            j
                          
                        
                      
                      )
                    
                    2
                  
                  2
                
              
              +
              
                
                  
                    (
                    
                      
                        e
                        j
                      
                      ⁢
                      
                        10
                        
                          -
                          j
                        
                      
                    
                    )
                  
                  3
                
                3
              
              -
              ...
            
            
              ln
              ⁡
              
                (
                10
                )
              
            
          
        
      
    
    
      
        (
        1.27
        )
      
    
  




Since higher order terms can be neglected because they alternate in sign and reduce the magnitude of the




  
    
      
        (
        
          
            e
            j
          
          ⁢
          
            10
            
              -
              j
            
          
        
        )
      
      2
    
    2
  
  .




εa can be approximated to:





  
    
      
        
          ɛ
          a
        
        ≈
        
          
            ∑
            
              j
              =
              k
            
            n
          
          ⁢
          
            
          
          ⁢
          
            -
            
              
                
                  (
                  
                    
                      e
                      j
                    
                    ⁢
                    
                      10
                      
                        -
                        j
                      
                    
                  
                  )
                
                2
              
              
                2
                ⁢
                
                  
                
                ⁢
                
                  ln
                  ⁡
                  
                    (
                    10
                    )
                  
                
              
            
          
        
      
    
    
      
        (
        1.28
        )
      
    
  




Considering the worst cases (ej=9 or −9) we obtain the maximum εa:

ε≦1.78×10−(2k-1)  (1.29)

Quantization Error
Since only those intermediate values who have finite precisions are operated in the hardware-oriented algorithm, three quantization errors occur. First, the logarithm results are achieved by accumulating the n-digit rounding values of −log10(1+ej10−j) from the 1st to the kth iteration. In each iteration, the maximum rounding error of −log10(1+ej10−j) is 0.5×10−n therefore the maximum εq1 is:




  
    ɛ
    
      q
      ⁢
      
        
      
      ⁢
      1
    
  
  ≤
  
    
      ∑
      
        j
        =
        1
      
      k
    
    ⁢
    
      
    
    ⁢
    
      0.5
      ×
      
        10
        
          -
          n
        
      
    
  
  ≤
  
    0.5
    ⁢
    
      
    
    ⁢
    k
    ×
    
      10
      
        -
        n
      
    
  




Second, the logarithm results are achieved by accumulating the n-digit rounded values of




  
    
      -
      
        e
        j
      
    
    ⁢
    
      10
      
        -
        j
      
    
  
  
    ln
    ⁡
    
      (
      10
      )
    
  




from the kth+1 to the nth iteration. Since the values of





  
    -
    
      e
      j
    
  
  
    ln
    ⁡
    
      (
      10
      )
    
  




are precomputed and stored in a Look Up Table (LUT) for ejε[−9, 9] followed by a shifter, the maximum rounding error of





  
    
      -
      
        e
        j
      
    
    ⁢
    
      10
      
        -
        j
      
    
  
  
    ln
    ⁡
    
      (
      10
      )
    
  




is 0.5×10−n therefore the maximum εq2 is:





  
    ɛ
    
      q
      ⁢
      
        
      
      ⁢
      2
    
  
  ≤
  
    
      ∑
      
        j
        =
        
          k
          +
          1
        
      
      n
    
    ⁢
    
      
    
    ⁢
    
      0.5
      ×
      
        10
        
          -
          n
        
      
    
  
  ≤
  
    0.5
    ×
    
      (
      
        n
        -
        k
      
      )
    
    ×
    
      10
      
        -
        n
      
    
  




Third, the logarithm result log10(M′X) is adjusted by subtracting a finite n-digit rounded constant (0, log10(2), log10(3) or log10(5)) in the last iteration, so the maximum εq3 is:

εq3≦0.5×10−n 

Therefore, the maximum quantization error εq is:




  
    ɛ
    q
  
  ≤
  
    
      ɛ
      
        q
        ⁢
        
          
        
        ⁢
        1
      
    
    +
    
      ɛ
      
        q
        ⁢
        
          
        
        ⁢
        2
      
    
    +
    
      ɛ
      
        q
        ⁢
        
          
        
        ⁢
        3
      
    
  
  ≤
  
    
      0.5
      ⁢
      
        
      
      ⁢
      k
      ×
      
        10
        
          -
          n
        
      
    
    +
    
      0.5
      ×
      
        (
        
          n
          -
          k
        
        )
      
      ×
      
        10
        
          -
          n
        
      
    
    +
    
      0.5
      ×
      
        10
        
          -
          n
        
      
    
  
  ≤
  
    0.5
    ×
    
      (
      
        n
        +
        1
      
      )
    
    ×
    
      10
      
        -
        n
      
    
  




Error Estimation
Since the final logarithm result is faithfully rounded, it has a rounding error of εr=1×10−n. Hence the total error introduced is due to εi, εa, εq and εr:




  
    
      
        
          E
          total
        
        =
        
        ⁢
        
          
            ɛ
            i
          
          +
          
            ɛ
            a
          
          +
          
            ɛ
            q
          
          +
          
            ɛ
            r
          
        
      
    
  
  
    
      
        =
        
        ⁢
        
          
            4.34
            ×
            
              10
              
                -
                n
              
            
          
          +
          
            1.78
            ×
            
              10
              
                -
                
                  (
                  
                    
                      2
                      ⁢
                      
                        
                      
                      ⁢
                      k
                    
                    -
                    1
                  
                  )
                
              
            
          
          +
          
            0.5
            ×
            
              (
              
                n
                +
                1
              
              )
            
            ×
            
              10
              
                -
                n
              
            
          
          +
          
            1
            ×
            
              10
              
                -
                n
              
            
          
        
      
    
  
  
    
      
        =
        
        ⁢
        
          
            
              (
              
                5.84
                +
                
                  0.5
                  ⁢
                  
                    
                  
                  ⁢
                  n
                
              
              )
            
            ×
            
              10
              
                -
                n
              
            
          
          +
          
            1.78
            ×
            
              10
              
                -
                
                  (
                  
                    
                      2
                      ⁢
                      
                        
                      
                      ⁢
                      k
                    
                    -
                    1
                  
                  )
                
              
            
          
        
      
    
  




So,

εtotal=(5.84+0.5n)×10−n+1.78×10−(2k-1)  (1.30)

Assume for example that the needed final precision n is 16 digits. And according to 1.23, k will equal 8, substituting in 1.30:




  
    
      
        
          E
          total
        
        =
        
        ⁢
        
          
            
              (
              
                5.84
                +
                
                  0.5
                  ×
                  16
                
              
              )
            
            ×
            
              10
              
                -
                16
              
            
          
          +
          
            1.78
            ×
            
              10
              
                -
                
                  (
                  
                    
                      2
                      ×
                      8
                    
                    -
                    1
                  
                  )
                
              
            
          
        
      
    
  
  
    
      
        =
        
        ⁢
        
          
            13.84
            ×
            
              10
              
                -
                16
              
            
          
          +
          
            1.78
            ×
            
              10
              
                -
                15
              
            
          
        
      
    
  
  
    
      
        =
        
        ⁢
        
          0.3164
          ×
          
            
              10
              
                -
                14
              
            
            .
          
        
      
    
  




Therefore, according to this estimation, one can get 14-digit logarithm result with 0.3064 ulp when using a calculation precision n of 16-digits.
Architecture
In one or more embodiments of the invention, the DLHU includes two stages. Stage 1 is to obtain ej with selection by rounding. After ej is achieved, the logarithm result will be produced in stage 2.
The normalized mantissae (MX/, MY/) have the property: 0.1≦Mx/, MY/≦0.9999 . . . 9. The normalized fraction MX/ is adjusted into the range 0.5≦MX/<1. The e1 logic takes the first two most significant digits of MX/ as an input and generates the corresponding value of e1 according to table 1.1.
Stage 1 implements equation 1.13 iteratively. In the first iteration, MX/ and e1 are fed as inputs to Stage 1, to calculate W[2] according to equation 1.20. In subsequent iterations, Wj+1 and ej are selected to be the inputs. In each iteration, ej value is used by stage 2 to calculate log(MX/) using additions of −log10(1+ej10−j) values.
First Stage
The first stage (stage1) essentially implements equation 1.13,

W[j+1]=10(W[j]−ej+ejW[j]10−j)

In the first iteration (j=1) equation 1.13 reduces to

W[2]=100−100×Mx′−10e1×Mx′

where MX/ is the adjusted input fraction (multiplied by 2, 3 or 5).

Equation 1.13 can be decomposed into two parts W[j]−ej and ejW[j]10−j. Recall from equation 1.16 that W[j+1] has an upper and lower bounds of ±9.5. Hence, W[j]−ej+ejW[j]10−j will always be a fraction bounded by ±0.95.
Calculating W[j]−ej: As ej is selected by rounding W[j] according to equation 1.14, W[j]−ej is always a fraction as noted above and can be calculated according to table 1.2. Table 1.2 shows a method to calculate W[j]−ej without using a Carry Propagation Adder (CPA). The first two columns show all the possible cases for rounding and the result of W[j]−ej, respectively. In order to calculate the result without using a CPA, the operation is done depending on a round up signal. The round up signal is generated while computing ej=round(W[j]). If W[j] has a fraction part ≧5, then round_up is raised. Hence, W[j]−ej fraction can be selected to be W[j] fraction or its complement depending on W[j] sign whether it is 0 or 1, respectively. Note that −0.4 is the tens's complement of 0.6, and −0.3 in ten's complement format is 0.7. W[j]−ej sign can be calculated by XORing W[j] sign and the round_up signal.







TABLE 1.2







Illustration of the calculation of W[j] − ej term














W[j]

(W[j] − ej)
(W[j] − ej)


Example cases
W[j] − ej
sign
round_up
fraction
sign















−2.4 → −2
−0.4
1
0
complement
1


−2.7 → −3
0.3
1
1
complement
0


2.4 → 2
0.4
0
0
fraction
0


2.7 → 3
−0.3
0
1
fraction
1









Calculating ejW[j]10−j: This term includes a shifting and a multiplication operation. A multiplier by one digit is used in order to multiply ej(1-digit) by W[j](n-digits). The used multiplier is based on the Signed Digit (SD) format. Each value of ej is decomposed into two values according to Table 1.3. The resulting two partial products are not added, instead the three vectors (two partial products from the multiplier and W[j]−ei) are compressed using a three to two compressor.







TABLE 1.3







ej in SD format









ej


















0
1
2
3
4
5
6
7
8
9





















ej-SD
00
01
02
03
04
1 5
1 4
1 3
1 2
1 1









FIG. 3 shows the architecture of the first stage of DLHU. In the First Iteration, Mux1 (304) and Mux2 (306) select e1 and respectively. e1 is obtained according to table 1.1 to guarantee the convergence of the digit recurrence algorithm. The adjustment block (302) multiplies MX/ by a scale factor (e.g., 2, 3, or 5), if necessary, to ensure MX/ is always a fraction in the range [0.5; 1). The first part of equation 1.20 (100−100×MX/) can be thought of as the complement of MX/. The result of the multiplication of e1 with MX/ and MX/ complement are then compressed using a three to two compressor (308). Finally, W[2] and e2 are ready at the end of the 1st iteration.
In subsequent iterations, W[j]−ej is calculated as described above. Following the same architecture, W[j+1] and ej are obtained iteratively until the end of the operation after n clock cycles.
Second Stage
After ej is selected by rounding W[j+1] in every iteration, stage 2 calculates the final log result through accumulative additions of −log(1+ej10−j). FIG. 4 shows the architecture of the second stage of the DLHU in accordance with one or more embodiments of the invention.
An initial adjustment value is set in the CPA according to the adjusted input. Recall that input MX/ needs to be adjusted into the range 0.5≦MX/<1 in order to satisfy equations 1.20 and 1.21. For example, in order to calculate log(0.2), firstly MX/ needs to be adjusted into the range by multiplying it by 3. Since log(0.2×3)=log(0.2)+log(3), then an adjustment value of log(3) needs to be subtracted from the final result.
The accumulative additions of −log(1+ej10−j) values are obtained through two phases. In the first phase, the values are stored in LUT-1 (404) and an address generator (406) is used to extract the required value from the table in each iteration. In the second phase, an approximation of the logarithm value is used.
Since ejε[−9, 9], there are 18 possible values of log(1+ej10−j) that need to be stored for every iteration j. Note that log(1+ej10−j)=0 when ej=0 for any value of j, so we don't need to count for ej=0. The stored data in LUT-1 (404) is partitioned into k-sections where k is the number of iterations before approximation.
The size of LUT-1 for a calculating precision of n and a number of iterations k before approximation can be calculated according to:

Size Of LUT-1=(2+18×k)×(4×n)bits  (1.31)

LUT-1 contents as stored in the ROM:















Iteration j
Ej
Stored Value




















X
0
 9




−0
−9



2
1
18 pre-calculated rounded values




−1




. . .




9




−9



3
1
18 pre-calculated rounded values




−1




. . .




9




−9



. . .

Till iteration k










In the second phase,




  
    
      e
      j
    
    ⁢
    
      10
      
        -
        j
      
    
  
  
    ln
    ⁡
    
      (
      10
      )
    
  




is used to approximate log(1+ej10−j). The LUT-2 (408) storing 18 values of





  
    e
    j
  
  
    ln
    ⁡
    
      (
      10
      )
    
  




from ej=−9→9 is used. It is followed by a shifter (410) to implement the subsequent iterations effect 10−j. However, the shifter width can be reduced to 4×(n−k) instead of 4×n. This is because after k iterations, there will be 4×k leading zeros in the log(1+ej10−j) values due to 10−k. So a constant value of 4×k can always be concatenated to the shifter output to form the approximation of log(1+ej10−j) value. Moreover, the second look up table LUT-2 (408) is addressed simply by signed ej.

In every iteration, the address generator (406) generates the needed address based on the values of ej and internal set of counters. The stored data pattern can be accessed using a binary counter that generates multiples of nine in every iteration. This method is used in order to utilize the area of the used ROM to build LUT-1 (404) and to simplify the design of the generator. The regular binary pattern of the multiples of nine can be implemented using simpler set of counters which follow regular transitions as shown:




   
  
    
      
        
          9
          10
        
      
      
        
          000
          ⁢
          
            
          
          ⁢
          001
          ⁢
          
            
          
          ⁢
          
            001
            2
          
        
      
    
    
      
        
          18
          10
        
      
      
        
          000
          ⁢
          
            
          
          ⁢
          010
          ⁢
          
            
          
          ⁢
          
            010
            2
          
        
      
    
    
      
        
          27
          10
        
      
      
        
          000
          ⁢
          
            
          
          ⁢
          011
          ⁢
          
            
          
          ⁢
          
            011
            2
          
        
      
    
    
      
        ⋮
      
      
        ⋮
      
    
    
      
        
          63
          10
        
      
      
        
          000
          ⁢
          
            
          
          ⁢
          111
          ⁢
          
            
          
          ⁢
          
            111
            2
          
        
      
    
    
      
        
          72
          10
        
      
      
        
          001
          ⁢
          
            
          
          ⁢
          001
          ⁢
          
            
          
          ⁢
          
            000
            2
          
        
      
    
    
      
        
          81
          10
        
      
      
        
          001
          ⁢
          
            
          
          ⁢
          010
          ⁢
          
            
          
          ⁢
          
            001
            2
          
        
      
    
    
      
        ⋮
      
      
        ⋮
      
    
  




Some transitions such as 90→99 can alter the regular count of the simpler set of counters, So the higher order counters depend on the lower order ones. The least order 3-bit counter is initialized by 1 and is not altered through the whole generation. The higher order 3-bit counter skips a count every 7 clock cycles, for example the middle 3-bit counter doesn't count 0 in the first two set of counts (7 clock cycles each). The highest order counter is triggered every 7 clock cycles without any alteration.
After generating the correct multiple of nines in each iteration, the value of ej is added in binary format to the least significant portion of the generated vector using a 4-bit binary adder. The higher portion of the generated vector is incremented if required by the carry out of the 4-bit binary adder. Finally, the sign bit of ej is concatenated in the least significant bit of the address vector to access both positive and negative values of ej.
Example: Now we want to calculate log(0.5) using the proposed digit recurrence algorithm. We will choose n to be 18, in order to satisfy equation 1.23 k will be 10. The error estimation equation 1.30 shows that the total error will be Etotal=1.4018×10−17 this guarantees final precision of 17 digits with an error of 1.4018×10−17.
Firstly the input 0.5 is fit in the range and doesn't need to be adjusted. From table 1.1 m=0.5 corresponds to ej=9. And the first calculated log value is:

log1(0.5)=−log(1+ej10−j)=−log(1+9×10−1)=−0.278753600952828961

In the first iteration (j=1), substituting into

W[2]=100−100×Mx′−10e1×Mx′

So, W[2]=5 and hence, e2=5 (ej is selected by rounding W[j]).

log2(0.5)=log1(0.5)−log(1+5×10−2)

log2(0.5)=−0.299942900022767034

In subsequent iterations until j=k=10, equation 1.13 is used to calculate W[j+1]. Hence, ej is selected by rounding.

W[j+1]=10(W[j]−ej+ejW[j]10−j)

For (j=2):

W[3]=10×((5−5)+5×5×10−2)=2.5

Hence, e3=3 and,

log3(0.5)=−0.301243833043185153

Table 1.4 shows the values of W[j+1], ej, and logj values in every iteration. The correct final result obtained from a variable precision software library is:

log(0.5)=−0.301029995663981195213738894724








TABLE 1.4







Calculation of log(0.5) using the digit recurrence algorithm


Calculation of log(0.5)










Iterations (j)
W [j + 1]
ej
logj value













1
don't care
9
−0.278753600952828961


2
5
5
−0.299942900022767034


3
2.5
3
−0.301243833043185153


4
−4.925
−5
−0.301026631497320897


5
0.774625
1
−0.301030974420425350


6
−2.2536725375
−2
−0.301030105830592953


7
−2.53668030154925
−3
−0.301029975542228839


8
4.63320459454840464
5
−0.301029997256952392


9
−3.66795173791365632
−4
−0.301029995519774460


10
3.32048276758150631
3
−0.301029995650062805


11
3.20482768577651140
3
−0.301029995663091639


12
2.04827685872656230
2
−0.301029995663960228


13
0.48276858730658853
0
−0.301029995663960228


14
4.82768587306588530
5
−0.301029995663981943


15
−1.72314126933873315
−2
−0.301029995663981075


16
2.76858730661270296
3
−0.301029995663981205


17
−2.31412693387296209
−2
−0.301029995663981196


18
−3.14126933872962043
−3
−0.301029995663981195









From table 1.4 note that the values of ej is bounded by the inequality −9≦ej≦9. Recall from equation 1.4 that ej denotes the amount of error such that how much log10(MXΠfj) is away from 1. These error value can be a positive or negative quantity. Hence, the values of logj can be increased or decreased in different subsequent iterations. This results in an irregular behavior of logj values when log(MX)→0.000 . . . 000XXX or log(MX)→0.999 . . . 999XXX where the final result is alternating around 0 or 1 respectively. This behavior has an impact on the online algorithm and the operation of the subsequent blocks.
Note that the error is reduced in each iteration by more than 10−1, in most cases this leads to a new correct digit in every iteration. Hence, the algorithm converges to the correct result. Although we calculated the error due to the assumed precisions to be 1.4018×10−17 at worst case, we find that we get the complete 18 digits correctly. This is natural if the sources of error that were calculated have not been introduced in this case, however in some other cases it will be there.
Online Zeros or Nine Counting
If there is a value of log(MX/)+Ex such that there are several leading zeros in the result such as

log(0.999999999)≈−0.00000000043429448 where n=18

In this case there are 9 leading zeros, Now assume that MY=1 and EY=10, so the final result will be

10−4.34294482000000000≦0.00004539992966134

But the precise result is

0.9999999991×1010≈0.00004539992953548

As shown we have lost 5 digits of precision due to insufficient precise non-zero digits in the logarithm result. So we must have to count the number of leading zeros (or nines) online to prevent wrong calculation as in the previous example.
The main issue in counting online leading zeros (or nines) is the toggling of the positive and negative error ej around 1. FIG. 5 shows a timing diagram for MX/=0.100000000001, where

log(0.100000000001)=−0.999999999995657055

As shown in FIG. 5, in the first five iterations (501, 502, 503, 504, 505), a positive ej is always obtained and the additions of |−log(1+ej10^(−j))| is therefore increasing. Note that in the 5th iteration (505), the value of log(MX/) is actually 1.00000206 but we don't care with the integer part. In the 6th iteration (506), a negative value of ej is obtained that results in a reduction of the log(MX/) value to 0.99999989. Hence, whenever log(MX/) result is within some distance from 1, a toggling between nines and zeros in the online iterations may occur.
The online Counting leading zeros (or nines) algorithm can be decomposed into two parts:

    
    
        Fixed Zeros and Nines.
        Toggling Zeros and Nines.
    
    


In the first part, fixed zeros and nines, there is no toggling in log(K) result.
This can be noticed when log(MX) is incremented either by +Δ or −Δ away from the value of ‘0’ or ‘1’ respectively. The algorithm is as follows:













1
If 1st digit is zero → start counting


2
If next digit is not zero → stop counting, else continue


3
If 1st digit is nine → start counting


4
If next digit is not nine → stop counting, else continue









In the second part, toggling zeros and nines, the algorithm counts toggling zeros or nines. A toggling zero may occur if the first digit is 1 and flipped into 0 in subsequent iterations which can happen due to an increment with −Δ. Also the toggling nine may occur if the first digit is 8 and flipped into 9 in subsequent iterations due to an increment with +Δ. The algorithm may be described as follows:













1
If, in first iteration, 1st digit is 0 then



  → count=1 when 2nd digit ≠ 9 (will not flip) else



  → count=0 (if flipped)


2
If, in first iteration, 1st digit is 1 then



  → count=0 when 2nd digit ≠ 0 (will not flip) else



  → count=1 (if flipped)


3
If, in first iteration, 1st at digit is 8 then



  → count=0 when 2nd digit ≠ 9 (will not flip) else



  → count=1 (if flipped)


4
If, in first iteration, 1st digit is 9 then



  → count=1 when 2nd digit ≠ 0 (will not flip) else



  → count=0 (if flipped)









Whether fixed or toggling zeros are found, the count value is passed to the master control to calculate the allowable shift amount. Only non-zero precision digits are output from the log stage to the next. The following property is considered for this decision.




  
    
      
        
          log
          10
        
        (
        
          
            0.00
            ⁢
            
              
            
            ⁢
            ...
            ⁢
            
              
            
            ⁢
            00
            ⁢
            
              
            
            ⁢
            xyz
          
          =
          
          ⁢
          
            
              log
              10
            
            ⁡
            
              (
              
                0.
                ⁢
                xyz
                ×
                
                  10
                  
                    -
                    LeadingZeros
                  
                
              
              )
            
          
        
      
    
  
  
    
      
        =
        
        ⁢
        
          
            
              log
              10
            
            ⁡
            
              (
              
                0.
                ⁢
                xyz
              
              )
            
          
          -
          LeadingZeros
        
      
    
  




Only the first term is needed to continue the power calculations with sufficient precision digits. The ‘LeadingZeros’ effect is taken into consideration by the master control hardware unit (150).

Logarithm Precision Extension
As described in the previously, some leading zeros in log(MX/)+EX result with a positive value of EY may result in a loss of precision in the final result. An extension of log(MX/) precision is necessary in order to solve this problem. The maximum leading zeros for decimal-64 and decimal-128 mode is 15 and 33 respectively. It can be denoted by p−1 where p is the precision of a specific mode. Hence the data width of logarithm calculation will be n+(p−1) instead of n only.
Referring back to FIG. 4, a logLeadingZero block (450) including a shifter is placed after the logarithm stage to get rid of the unwanted leading zeros. The shifter gets its value from the master control hardware unit (150). The shift value depends on the value of EY and the online calculated leading zeros (or nines) of logarithm result. Since the value of the logarithm is always negative (because the input is a fraction), some leading nines in the result can be flipped to zeros when EX=1. So leading nines has the same effect as zeros when EX=1 and is counted as well as zeros. This is further discussed below with respect to the master control hardware unit (150).
Decimal Multiplier Hardware Unit
Multiplication is the second operation in computing XY. In one or more embodiments of the invention, the DMHU (120) is a sequential multiplier to perform the multiplication of MY/×(log(MX/)+EX+K) iteratively. Specifically, MY is the fixed multiplicand, while the multiplier is the online “correct” digit obtained from the previous ‘logarithmic’ stage, in every iteration. The multiplier is recoded into SD in every iteration as shown in table 1.6. See example for log(0.5) in table 1.5 with MX=0.5. Two correction vectors are compressed with the two partial products using two three-to-two compressors. Finally a CPA is used to calculate the final online result.







TABLE 1.5







SD recoding of log(0.5)










Iterative log(0.5)
SD multiplier







027875 . . .
0



029994 . . .
3



030124 . . .
0



030102 . . .
1



030103 . . .
0



.
.



.
.



.
.










Sources of Error
The results obtained from the logarithm stage in every iteration can maximally be varied by a value of 1. For example, when calculating log(0.5), we get:




Apparently, there is a change in the second digit from 29→30 at the end of the 3rd iteration. However, in this case, as shown in table 1.5, this change is ineffective. This can be explained by the aid of table 1.6. Note that h denotes a digit ≧5 and l denotes a digit <5.







TABLE 1.6







SD recoding - Negative sign is placed over the signed number










digits
SD













0
0l
0



0h
1


1
1l
1



1h
2


2
2l
2



2h
3


3
3l
3



3h
4


4
4l
4



4h
5


5
5l
 5



5h
 4


6
6l
 4



6h
 3


7
7l
 3



7h
 2


8
8l
 2



8h
 1


9
9l
 1



9h
 0









Therefore, every digit followed by a digit ≧5 is recoded to the same value as if the next higher digit is followed by a digit <5. And as the logarithm result is obtained with a maximum error of ‘1’ in its value, this region is our main concern. The only exception is at the boundaries 5 and 9 where

4h→5 9h→ 0

5l→ 5 0l→0

The introduced errors due to these cases can be best shown by the following examples.
Example (1)
Assume an alternating logarithm results as shown in FIG. 5. The third column of table 1.7 represents the current multiplier digit coded into SD format.







TABLE 1.7







Alternating nines and zeroes











Iterations
log(0.100000000001)
current digit
next digit
tail digit





1st
09777236 . . .
1
 0
1


2nd
09989129 . . .
 0
 0
1


3rd
09997806 . . .
 0
 0
1


4th
09999977 . . .
 0
 0
1


5th
00000020 . . .
0
0
0


6th
09999998 . . .
 0
 0
1









The next column represents the SD coding of the next digit. It is necessary to know whether the next digit is negative in order to add a tail digit to the resulting partial product. Note that the negative partial products are in the Diminished Radix Complement (DRC) and a tail digit of 1 has to be added to calculate the ten's complement. The problem is that the next digit seen in iteration j is not always the same as the current digit in iteration j+1. The first is referred to as the ‘predicted’ while the second the ‘actual’.
Starting from the 1st iteration, all the next (predicted) digits in a specific iteration are the same as the current (actual) digits in the following iteration. However, in the 5th iteration, a predicted negative zero in the previous iteration is not the same as the current actual positive zero. Moreover, a negative zero in the DRC format is a train of nines. An addition of a tail digit of ‘1’ will get the actual zero. So a correction vector has to be added in order to remove the concatenated tail digit and to fix the wrong prediction of a negative zero. This correction vector is a train of nines ending at the same position of the tail digit.
The opposite scenario may happen, which is apparent from the 6th iteration. A wrong prediction of a positive zero has led to a tail digit of ‘0’. However, the next actual negative zero (train of nines in DRC format) needs a tail digit of ‘1’, So a correction vector of a value of ‘1’ is added at the same position of the missed tail digit.
Hence, whenever there is an alternating sequence of nines and zeros, a correction vector is added to the partial products. This vector can be a train of nines to eliminate the tail digit or a value of one added at the same position of the zero tail digit.
Example (2)
Assume an alternating logarithm results as shown in Table 1.8.







TABLE 1.8







mid point (55-54)










Iterations
log(0.441553671)
current digit
previous digit





1st
03524226 . . .
0
0


2nd
03552599 . . .
4
0


3rd
03549875 . . .
 5
4


4th
03550156 . . .
 5
 4


5th
03550166 . . .
0
 5


6th
03550165 . . .
2
0









In this case, the wrong prediction of a next negative digit is not a source of error. However, a toggling between 55 and 54 as in the 4th iteration does make an error. In the 3rd iteration, the current coded multiplier is 5 but unfortunately it has changed to 4 in the 4th iteration.
The calculation in the 3rd iteration is based on 5 (which can be thought of as 5) and is detected to be actually 4 (which can be thought of as 6) in the 4th iteration. Hence, to overcome this miscalculation, the multiplier has to be complemented to 5 instead of 4 in the 4th iteration. That is (assuming a multiplicand MY=1):




A comparison is held in every iteration between the previous and current multipliers in order to detect this sort of error (i.e., 0.5 boundary condition). The next partial product is complemented without the addition of any correction vectors.
FIG. 6 shows a DMHU (600) in accordance with one or more embodiments of the invention. The DMHU (600) may be an example of the DMHU (120), discussed above in reference to FIG. 1. A shifter (602) following the log(MX/)+EX+K value prepares the current and next slices in every iteration. SD coding blocks (604, 606) prepare the coded multiplier in order for the multiple selector (608) to select the right multiple of MY/. The correction vector is selected depending on a comparison, using a comparator (610), between a registered multiplier and the current multiplier. The error sources discussed above are corrected through an addition of a correction vector (either +1 or −1), or choosing the complement of the next partial product, wherein the complimenting is executed by the multiple selector (608). Finally, a three to two compressor (612) followed by a Carry Propagation Adder (CPA) (614) are used to calculate MY/·[log(MX/)+EX+K] iteratively.
Decimal Antilogarithm Hardware Unit
Antilogarithm is the third operation in calculating powering function XY. In one or more embodiments of the invention, the DAHU is based on a digit recurrence algorithm with selection by rounding. However, the algorithm is adjusted to calculate the results online with a delay of 8 at the start of the operation.
Digit Recurrence Algorithm
A valid Decimal Floating Point (DFP) anti-logarithmic calculation is defined as:

Antilog10(x)=10x 

Moreover the calculation can be decomposed to the form of:




  
    
      
        
          
            Antilog
            10
          
          ⁡
          
            (
            x
            )
          
        
        =
        
        ⁢
        
          10
          
            
              x
              int
            
            +
            
              x
              frac
            
          
        
      
    
  
  
    
      
        =
        
        ⁢
        
          
            10
            
              x
              int
            
          
          ×
          
            10
            
              x
              frac
            
          
        
      
    
  




The computation results of 10Xfrac can be achieved through the computation of em as shown in 1.34

10xfrac=εxfrac×ln(10)  (1.32)

Xfrac is in the range of (−1, 1) so m=Xfrac×ln(10) is in the range of (−ln(10), ln(10)). The digit recurrence algorithm to calculate em is summarized as follows:




  
    
      
        
          
            L
            ⁡
            
              [
              
                j
                +
                1
              
              ]
            
          
          =
          
            m
            -
            
              ∑
              
                
              
              ⁢
              
                ln
                ⁡
                
                  (
                  
                    f
                    j
                  
                  )
                
              
            
          
        
        ⁢
        
          

        
        ⁢
        
          Then
          ,
        
      
    
    
      
        (
        1.33
        )
      
    
  
  
    
      
        
          
            lim
            
              j
              →
              ∞
            
          
          ⁢
          
            {
            
              m
              -
              
                ∑
                
                  
                
                ⁢
                
                  ln
                  ⁡
                  
                    (
                    
                      f
                      j
                    
                    )
                  
                
              
            
            }
          
        
        →
        0
      
    
    
      
        (
        1.34
        )
      
    
  




If 1.34 is satisfied:




  
    
      
        
          
            
              lim
              
                j
                →
                ∞
              
            
            ⁢
            
              {
              
                ∑
                
                  
                
                ⁢
                
                  ln
                  ⁡
                  
                    (
                    
                      f
                      j
                    
                    )
                  
                
              
              }
            
          
          →
          m
        
        ⁢
        
          

        
        ⁢
        
          Thus
          ,
        
      
    
    
      
        (
        1.35
        )
      
    
  
  
    
      
        
          10
          
            x
            frac
          
        
        =
        
          
            e
            m
          
          =
          
            
              ∏
              
                j
                =
                1
              
              ∞
            
            ⁢
            
              
            
            ⁢
            
              f
              j
            
          
        
      
    
    
      
        (
        1.36
        )
      
    
  




fj is defined as fj=1+ej10−j by which m is transformed to 0 by successive subtraction of ln(fj). This form of fj allows the use of a decimal shift and add implementation. According to 1.35 and 1.38, the corresponding recurrences for transforming m and computing the antilogarithm are presented as follows:

L[j+1]=L[j]−ln(1+ej10−j)  (1.37)

E[j+1]=E[j]×(1+ej10−j)  (1.38)

In 1.37 and 1.38, j≧1, L[1]=m and E[1]=1. The digits ej are selected so that L[j+1] converges to 0. After performing the last iteration of recurrence, we obtain:

L[j+1]≦0  (1.39)

E[j+1]≈em=10xfrac  (1.40)

To obtain the selection function for ej, a scaled remainder is defined as:

W[j]=10j×L[j]  (1.41)

Thus,

L[j]=W[j]×10−j  (1.42)

Substituting 1.42 into 1.37:

W[j+1]=10W[j]−10j+1×ln(1+ej10−j)  (1.43)

According to 1.43, the digits ej are selected as a function of leading digits of scaled remainder in a way that the residual W[j] remains bounded.
Online Algorithm
The input m is introduced in the recurrence equation 1.37 as an initial condition (L[1]=m). Hence, the residual W[j+1] in equation 1.43 carries all the information about m in the first iteration. Assume that only δ digits of the input m are ready at the start of the operation, then equation 1.43 can be adjusted [9] to:

W[j+1]=10W[j]−10j+1 ln(1+ej10−j)+Xjnew10−1+δ  (1.44)

where +Xjnew is the correct new online digits and δ is the online delay of the online antilogarithm. Taking δ=2:

W[j+1]=10W[j]−10j+1 ln(1+ej10−j)+Xjnew101  (1.45)

Selection by Rounding
The selection of the digits ej is achieved through rounding to the integer part of the scaled remainder indicated as 1.46, where ej {−9, −8, −7, . . . , 7, 8, 9}.

εj=round(W[j])  (1.46)

when ej is selected by rounding in 1.46:

−0.5≦W[j]−ej≦0.5  (1.47)

Because |ej+1|≦9,

−9.5<W[j+1]<9.5  (1.48)

1.43 can be written as:

W[j+1]=10(W[j]−ej)−10j+1×ln(1+ej10−j)+10ej  (1.49)

According to 1.47, 1.48 and 1.49 the numerical analysis is processed as follows:

10j+1×ln(1+ej10−j)−10ej>−4.5  (1.50)

10j+1×ln(1+ej10−j)−10ej<4.5  (1.51)

The results in numerical analysis show that when j≧2, the conditions 1.50 and 1.51 are satisfied. So the selection by rounding is only valid for iterations j≧2 and e1 can be achieved by a look up table. Note that the numerical analysis is based on equation 1.43, but it's still valid for the online algorithm of equation 1.45. Because W[1]=10m, W[2] can be achieved as:

W[2]=100×m−102×ln(1+ej10−1)  (1.52)

When the value of j is 2, the value of e2 is obtained with selection by rounding, then (1.50) and (1.51) are satisfied. According to 1.48, W[2] satisfies:

−9.5<W[2]<9.5  (1.53)

According to (1.52) and (1.53), we obtain:

100×m−102×ln(1+ej10−j)<9.5  (1.54)

100×m−102×ln(1+ej10−j)>−9.5  (1.55)

To satisfy the conditions of (1.54) and (1.55), we conclude that when e1 is selected from −9 to 9, the input number m must be in the range of [−2.39, 0.73]. Therefore, the look-up table I is constructed to all the negative input numbers m, which are in the range [−ln(10), 0]. In order to tune the positive input numbers m, (0, ln(10)], to negative, the fraction part of positive input operand xfrac should be firstly adjusted to negative by xfrac−1 and its corresponding integer part xint is adjusted by xint+1.
The results of numerical analysis show that, a single digit e1 fails to create look-up table I for achieving a continuous ranges to cover all negative input numbers m. Therefore, e1 is extended to 4-digit so that all negative input numbers m can be achieved. 3-digits MSDs of the input operand m are necessary to address the initial look-up table I for selection of the digit e1. The look-up table is constructed by a size of 25×16 bits ROM in which the values of e1 are stored as shown in table 1.9.







TABLE 1.9







Look Up Table I for el selection










Ranges of m
el














[−0.08, 0.00]  
0.000



[−0.19, −0.09]
−1.000



[−0.20, −0.30]
−2.000



[−0.31, −0.44]
−3.000



[−0.45, −0.59]
−4.000



[−0.60, −0.77]
−5.000



[−0.78, −0.88]
−5.500



[−0.89, −1.00]
−6.000



[−1.01, −1.13]
−6.500



[−1.14, −1.28]
−7.000



[−1.29, −1.37]
−7.250



[−1.38, −1.47]
−7.500



[−1.48, −1.57]
−7.750



[−1.58, −1.69]
−8.000



[−1.70, −1.82]
−8.250



[−1.83, −1.98]
−8.500



[−1.99, −2.16]
−8.750



[−2.17, −2.26]
−8.875



[−2.27, −2.38]
−9.000










Approximation of Logarithm
The values of logarithm ln(1+ej10−j) in (1.43) can be achieved by constructing look up table II. This section will follow a similar approach to what was done in stage-1 ‘Log(Mx/)’. With the increasing number of iterations, however, the size of the table will become prohibitively larger. Thus a method for reducing the table size, to achieve a significant reduction in the overall hardware requirement is necessary. A Taylor series expansion of the logarithm function ln(1+x) is demonstrated in (1.56):




  
    
      
        
          ln
          ⁡
          
            (
            
              1
              +
              x
            
            )
          
        
        =
        
          x
          -
          
            
              x
              2
            
            2
          
          +
          ...
        
      
    
    
      
        (
        1.56
        )
      
    
  




After j=k iterations, the values of (ln(1+ej10−j)) can be approximated by ej10−j. Therefore after the kth iteration the values of ln(1+ej10−j) do not need to be stored in look up table II, the values of ej10−j, instead, will be used for approximation.
Error Analysis and Estimation
The error will be calculated for a predetermined generic calculation precision of n−1, after n iterations.
Inherent Error of Algorithm
Since the decimal antilogarithm result is achieved after n iterations, εi can be defined as:




  
    
      
        
          ɛ
          i
        
        =
        
          
            
              ∏
              
                j
                =
                1
              
              ∞
            
            ⁢
            
              
            
            ⁢
            
              (
              
                1
                +
                
                  
                    e
                    j
                  
                  ⁢
                  
                    10
                    
                      -
                      j
                    
                  
                
              
              )
            
          
          -
          
            
              ∏
              
                j
                =
                1
              
              n
            
            ⁢
            
              
            
            ⁢
            
              (
              
                1
                +
                
                  
                    e
                    j
                  
                  ⁢
                  
                    10
                    
                      -
                      j
                    
                  
                
              
              )
            
          
        
      
    
    
      
        (
        1.57
        )
      
    
  




Thus, equation (1.57) can be written as:




  
    
      
        
          ɛ
          i
        
        =
        
          
            ∏
            
              j
              =
              1
            
            ∞
          
          ⁢
          
            
          
          ⁢
          
            
              (
              
                1
                +
                
                  
                    e
                    j
                  
                  ⁢
                  
                    10
                    
                      -
                      j
                    
                  
                
              
              )
            
            ×
            
              (
              
                1
                -
                
                  1
                  
                    
                      ∏
                      
                        j
                        =
                        
                          n
                          +
                          1
                        
                      
                      ∞
                    
                    ⁢
                    
                      
                    
                    ⁢
                    
                      (
                      
                        1
                        +
                        
                          
                            e
                            j
                          
                          ⁢
                          
                            10
                            
                              -
                              j
                            
                          
                        
                      
                      )
                    
                  
                
              
              )
            
          
        
      
    
    
      
        (
        1.58
        )
      
    
  




In (1.58), since the proposed anti-logarithmic algorithm can compute the input values, which fall in the range of (−1, 0], the exact antilogarithm results, obtained after the infinite iterations are in the range of (0.1, 1]. We substitute the worst case (ej=9) and the maximum value of the exact antilogarithm results to (1.58), then the maximum εi is obtained as:




  
    
      
        
          ɛ
          i
        
        ≤
        
          1
          -
          
            1
            
              
                ∏
                
                  j
                  =
                  
                    n
                    +
                    1
                  
                
                ∞
              
              ⁢
              
                
              
              ⁢
              
                (
                
                  1
                  +
                  
                    9
                    ×
                    
                      10
                      
                        -
                        j
                      
                    
                  
                
                )
              
            
          
        
      
    
    
      
        (
        1.59
        )
      
    
  




In (1.59), it is obvious that:




  
    
      
        
          
            ∏
            
              j
              =
              
                n
                +
                1
              
            
            ∞
          
          ⁢
          
            
          
          ⁢
          
            (
            
              1
              +
              
                9
                ×
                
                  10
                  
                    -
                    j
                  
                
              
            
            )
          
        
        =
        
          e
          
            
              ∑
              
                j
                =
                
                  n
                  +
                  1
                
              
              ∞
            
            ⁢
            
              
            
            ⁢
            
              ln
              ⁡
              
                (
                
                  1
                  +
                  
                    9
                    ×
                    
                      10
                      
                        -
                        j
                      
                    
                  
                
                )
              
            
          
        
      
    
    
      
        (
        1.60
        )
      
    
  




Since the equation (1.61) is satisfied:




  
    
      
        
          
            ∑
            
              j
              =
              
                n
                +
                1
              
            
            ∞
          
          ⁢
          
            
          
          ⁢
          
            ln
            ⁡
            
              (
              
                1
                +
                
                  9
                  ×
                  
                    10
                    
                      -
                      j
                    
                  
                
              
              )
            
          
        
        <
        
          9
          ×
          
            (
            
              
                10
                
                  -
                  
                    (
                    
                      n
                      +
                      1
                    
                    )
                  
                
              
              +
              
                10
                
                  -
                  
                    (
                    
                      n
                      +
                      2
                    
                    )
                  
                
              
              +
              ...
            
            ⁢
            
              
            
            )
          
        
      
    
    
      
        (
        1.61
        )
      
    
  




We obtain:




  
    
      
        
          
            ∏
            
              j
              =
              
                n
                +
                1
              
            
            ∞
          
          ⁢
          
            
          
          ⁢
          
            (
            
              1
              +
              
                9
                ×
                
                  10
                  
                    -
                    j
                  
                
              
            
            )
          
        
        <
        
          e
          
            9
            ×
            
              (
              
                
                  10
                  
                    -
                    
                      (
                      
                        n
                        +
                        1
                      
                      )
                    
                  
                
                +
                
                  10
                  
                    -
                    
                      (
                      
                        n
                        +
                        2
                      
                      )
                    
                  
                
                +
                ...
              
              ⁢
              
                
              
              )
            
          
        
      
    
    
      
        (
        1.62
        )
      
    
  




Thus, the maximum absolute εi is:




  
    
      
        
          
          
            ɛ
            i
          
          
        
        <
        
          1
          -
          
            1
            
              e
              
                9
                ×
                
                  (
                  
                    
                      10
                      
                        -
                        
                          (
                          
                            n
                            +
                            1
                          
                          )
                        
                      
                    
                    +
                    
                      10
                      
                        -
                        
                          (
                          
                            n
                            +
                            2
                          
                          )
                        
                      
                    
                    +
                    ...
                  
                  ⁢
                  
                    
                  
                  )
                
              
            
          
        
        ≈
        
          1
          ×
          
            10
            
              -
              n
            
          
        
      
    
    
      
        (
        1.63
        )
      
    
  




Quantization Error
The antilogarithm results can be obtained by n times successive multiplication as shown in (1.64)




  
    
      
        
          10
          
            x
            frac
          
        
        =
        
          
            ∏
            
              j
              =
              1
            
            n
          
          ⁢
          
            
          
          ⁢
          
            (
            
              1
              +
              
                
                  e
                  j
                
                ⁢
                
                  10
                  
                    -
                    j
                  
                
              
            
            )
          
        
      
    
    
      
        (
        1.64
        )
      
    
  




Since only the finite precision of intermediate multiplication results are operated in the hardware implementation, the quantization error εq is produced. The intermediate precision in our design is set to ‘P+4’ digits. In the first k iteration, there are no truncation errors. To prove this, we assume the opposite, an error existed at the least significant digit at an arbitrary iteration i. Multiplying (P+4)digits×(1)digit should have resulted in (P+5)digits, and the error would have existed in the least significant part. But since only (P+4)digits are reserved from the product, the error will not exist in iteration i+1. Thus the quantization error is not taken into consideration.
However, regarding the iterations k+1 and afterwards, the truncation error τ=10−P-4, is produced in each iteration, and sums up to:




  
    
      
        
          ɛ
          q
        
        =
        
          τ
          ×
          
            [
            
              
                
                  ∑
                  
                    i
                    =
                    
                      k
                      +
                      1
                    
                  
                  n
                
                ⁢
                
                  
                
                ⁢
                
                  {
                  
                    
                      ∏
                      
                        j
                        =
                        i
                      
                      n
                    
                    ⁢
                    
                      
                    
                    ⁢
                    
                      (
                      
                        1
                        +
                        
                          
                            e
                            j
                          
                          ⁢
                          
                            10
                            
                              -
                              j
                            
                          
                        
                      
                      )
                    
                  
                  }
                
              
              +
              1
            
            ]
          
        
      
    
    
      
        (
        1.65
        )
      
    
  




and the total quantization error, εq, satisfies:

εq<τ×(eΣi=k+1nej10−j+ . . . +eΣi=nnej10−j+1)  (1.66)

Considering the worst case (ej=9) in equation 1.66, we obtain the maximum absolute εq:

|εq|<(n−k+1)×10−P-4  (1.67)

Error Estimation
It's required to sum up all error sources and find the worst case error. Having only two sources of error, inherited and quantization errors, the maximum total error εt can be expressed as:

|εt|=|εi|+|εq|≦10−n+(n−k+1)×10−P-4  (1.68)

It's quite clear that the first term dominates. Thus for correct n−1 digits, n iterations are needed.
Architecture
The online antilogarithm function is divided into two stages: in the first stage ej is achieved through rounding to the integer part of the scaled remainder. Through accumulative multiplications, using ej the final antilogarithm result is calculated. FIG. 7 shows a first stage of the DAHU in accordance with one or more embodiments of the invention. FIG. 8 shows a second stage of the DAHU in accordance with one or more embodiments of the invention.
As shown in FIG. 7, 3-digits are required in the start of the operation. An address generator (702) similar to the one discussed above in reference to the DLHU, is used to access look up table II (704). e1 is selected in the first iteration from look-up table I (706) according to table (1.9). Mux1 (708) selects the 3 MSDs of the input in the first iteration. In subsequent iteration an online input (1 digit per iteration) is selected. According to equation (1.45), the three terms 10W[j], 10^(j+1)ln(1+ej10^(−j)) and Xjnew10^(−1) are firstly compressed using a three-to-two (710) compressor. Note that in 10^(j+1)ln(1+ej10^ (−j)) a shifter is not needed as the result is internally stored in look-up table II (704). Note also that Xjnew is always multiplied by 10^ (−1), that it is always a fraction. The used correction scheme adds (or subtracts) a value of 1 to (or from) Xjnew to correct the online errors. Finally a CPA (712) followed by a rounder (714) is used to get the value of ej which is fed iteratively to the second stage.
The approximation for the values of ln(1+ej10−j) as discussed previously is ej10−j. A right shifting by 10j+1 makes the approximated value equal to ej×10. Hence, in the approximation phase, ej is shifted one digit place to the right and concatenated with zeros to achieve the approximation value.
In the second stage, equation (1.38):

E[j+1]=E[j]×(1+ej10−j)

can be implemented using a n-digit multiplier. However, this will increase the required area. Equation (1.38) can be reformulated to:

E[j+1]=E[j]+E[j]ej10−j 

This form can allow us to use a Multiplier by one digit (805) followed by a CPA (807) which can decrease the used area significantly. In the first iteration, the operand of the CPA are e1 and 1. In subsequent iterations, the previously calculated E[j] is firstly multiplied by ej followed by a shifting (i.e., Shifter (809) to the left. The result ej·E[j]·10^(−j) is added to E[j]. The result 10^(xfrac) is ready after n iterations.
Master Control Hardware Unit, De-Normalizer, Rounder, and Flags
Apart from the data path shown in the previous chapters, this section shows many internal control lines that drives the whole system. Shift amounts, iterations control and exception flags are among the outputs from the ‘Master control’. Moreover, the result shall be delivered comforting the IEEE standard; this includes rounding according to the set rounding direction, de-normalization to reach the defined preferred exponent, DPD encoding and correct exceptional flags.
Master Control
After operand X gets its leading and trailing zeros counted, it's left shifted by the amount of leading zeros, thus, normalized. Values of leading and trailing zeros, in addition to the normalized operand are input to the master control. Operand Y is normalized similarly, without counting its trailing zeros, this info is not needed.
The master control hardware unit then calculates the following values
1. EX+K:

    
    
        EX−Bias+P−LeadingZerosX—In case of negative value
        EX−Bias+P−LeadingZerosX−1—In case of positive value
    
    


This behavior is needed for correct concatenation of the negative log(MX/) fraction. In case of negative EX+K which is an integer, there is not problem concatenating the negative fraction. On the other hand, positive integers need to be decreased by a value of 1, and the negative fraction needs to be complemented.
Example: log(MX/)=−0.4. If EX+K=−2, then EX+K+log(MX/)=−2.4. But if EX+K=2, then EX+K+log(MX)=1.6.
Since all exponential values are encoded in binary, they need to be converted to binary-coded decimal ‘BCD’ before concatenating to the Log fraction.
2. EY+L: always calculated as EY−Bias+P−LeadingZerosY 
3. As discussed above, log(MX/) may introduce leading zeros in its result.
These zeros are meaningful if the concatenated EX+K has a non-zero value. If not, loss of the result precision may occur. The master control hardware unit calculates the maximum allowable shift amount to move out those zeros. The shift amount is EY+L, but validated under two conditions:

    
    
        EX+k=0 with Log having leading zeros, or ·EX+K=1 with Log having leading nines. The second case will be numerically equivalent to the first; the positive integer part, ·EX+K, will be decremented to zero, and the negative fraction will be complemented to zeros.
        The sign of EY+L is positive, left shift will occur. Thus, more precision is needed.
    
    


4. To concatenate the binary integer EX+K to the BCD fraction result from Log(MX/), the integer part needs to be converted to BCD format (discussed below).
5. The Logarithm stage has a variable number of iterations. The master control hardware unit calculates the needed iterations. In case of a required left-shift to Log(MX)+Ex, then some Log digits will be shifted to the integer part, and more precision digits are required to the fraction. Thus, more iterations are needed in this case. In the opposite situation, when a right-shift is needed to the term Log(MX/)+Ex, less precision is needed because some digits will be thrown away to the right. Our detailed implementation calculate the number of required Logarithm iterations as:

    
    
        (P+10)+(EY+L); when a left-shift is required. (1.69)
        (P+10)□(|EY+L|); when a right shifting, and |EY+L|<P+3
        0, no log precision is required if the right shift is ≧P+3.
    
    


6. The Log stage updates the master control with the actual found-and-shifted leading zeros. This number may be less or equal to the maximum allowable shift, as discussed in point 3. So the shift amount is updated accordingly to have the value: EY+L−LogLeadingZeros and forwarded to the shifter between the multiplier and the anti-log to continue the remaining shift amount, if any.
7. As discussed above, the anti-log input must be a negative fraction. The shifted-out integer part before the anti-log stage needs a correction by incrementing a value of 1 if it is positive. If the sign is negative, then no correction is needed, but the BCD value is complemented, and the flow continues normally. This corrected integer part will be used in point 9 to calculate the resultant exponent, EZ.
8. If Y is an determined to be an integer, de-normalization to the final result shall take into consideration the trailing zeros found in X. Thus, setting an upper limit for the de-normalizer.
Example: 10002=1000000, the result shall have 3×2=6 trailing zeros. Thus by multiplying the number of trailing zero (TRZ) from MX by MY, in case MY is an integer, will give the amount of leading zeros to be preserved from de-normalization. As a novel design, we optimize our implementation for this feature to use a single digit multiplication only. This is achievable knowing that trailing zeros are always bounded from 0→P−1. Thus we have several cases as follows:

    
    
        If MY is three or more digits, the product will be more than P−1. This is an invalid case.
        If MY is two digits, and TRZ(MX) is one, then this case is valid if MY≦P−1. The two digits of MY are converted from BCD to binary as the resultant product.
        The only remaining case is when MY is a single digit integer number. Thus a single digit multiplier is used.
    
    


The calculated product, MY×TRZ(MX), is then input to the de-normalizer. Moreover, a special flag is raised to the rounder to prevent any possible roundup action. Thus the trailing zeros will be delivered to the output.
9. Back to complete the calculations for EZ, it still needs adjustments; adding the standard-defined exponent bias, and add a corrective de-normalization factor. The final value is calculated as:




  
    
      
        
          
            E
            z
          
          =
          
          ⁢
          
            Shifted
            ⁢
            
              -
            
            ⁢
            left
            ⁢
            
              
            
            ⁢
            integer
            ⁢
            
              
            
            ⁢
            part
          
        
        ,
        
          
            in
            ⁢
            
              
            
            ⁢
            BCD
            ⁢
            
              
            
            ⁢
            format
          
          +
        
      
    
  
  
    
      
        
        ⁢
        
          
            1
            ⁢
            
              
            
            ⁢
            Needed
            ⁢
            
              
            
            ⁢
            correction
            ⁢
            
              
            
            ⁢
            for
            ⁢
            
              
            
            ⁢
            positive
            ⁢
            
              
            
            ⁢
            values
            ⁢
            
              
            
            ⁢
            of
            ⁢
            
              
            
            ⁢
            
              E
              z
            
          
          +
        
      
    
  
  
    
      
        
        ⁢
        
          
            Bias
            ⁢
            
              
            
            ⁢
            required
            ⁢
            
              
            
            ⁢
            by
            ⁢
            
              
            
            ⁢
            the
            ⁢
            
              
            
            ⁢
            standard
          
          -
        
      
    
  
  
    
      
        
        ⁢
        
          
            P
            ⁢
            
              
            
            ⁢
            moves
            ⁢
            
              
            
            ⁢
            the
            ⁢
            
              
            
            ⁢
            decimal
            ⁢
            
              
            
            ⁢
            point
            ⁢
            
              
            
            ⁢
            from
            ⁢
            
              
            
            ⁢
            left
            ⁢
            
              
            
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            ⁢
            
              
            
            ⁢
            right
          
          +
        
      
    
  
  
    
      
        
        ⁢
        
          De
          ⁢
          
            -
          
          ⁢
          normalized
          ⁢
          
            
          
          ⁢
          Trailing
          ⁢
          
            
          
          ⁢
          Zeros
        
      
    
  




The shifted-out integer part is in BCD-8421 format, it needs to be converted to binary. The conversion is done using the BCD-to-BID converter (below). After conversion and applying the previous adjustments, it will be output as the exponent of the final result.
The shifted exponent is compared to the maximum representable exponent, following the IEEE standard, and if the exponent will not fit, an exception occurs. Depending on the exponent sign, an overflow or underflow occurs. If the sign of the “too large” exponent is positive, then it's an overflow exception, otherwise it's an underflow. For both cases, the inexact flag is raised as well.
11. Finally, the master control hardware unit detects special standard-defined cases, and sets the special result with one of the following values:

    
    
        Quiet Not-a-Number (qNaN): Output when 0°, NaNNaN, −∞∞, −1∞ or negativefraction 
        1: Output when anything0 or 1anything.
        ∞13: Output when 0−Odd Integer or ±∞+Odd.
        +∞: output when ±0Negative, ±∞Positive,
    
    


The complete-detailed implementation follows the listed exceptions discussed below. To be able to select those exceptions, several detection circuits are needed; fraction/integer detection, odd/even detection and some special values like 0, 1, ∞ and qNaN.
Some hardware circuits are introduced to fulfill the calculation needs for the master control hardware unit.
Binary Integer to BCD Converter
This design block is used to convert binary values ranging from 0→767 as defined by the IEEE 754-2008 std, to their Binary coded decimal in 3 digits. Basically, each binary bit has a weighted value according to its position. Starting from the least significant right position bit, the values are: 1, 2, 4, 8, 16, . . . 2position, where position number 0 is the right-most.
For decimal64 format, the input binary number is 10 bits. Although bits from positions 0 to 9 may sum up to 1023, but the valid values are limited to 767, the most significant 2 bits cannot have a value of 1 at the same time. This fact is defined by the standard, and our designed circuit makes use of it for better optimization. Each input bit position may add its value to the output. For example, at bit position 6, if the bit—of weight 64—has a value of 1, then two BCD digits of value ‘6’ and ‘4’ should be added to the output. Still in the example, if bit position 7 is raised, then three digits of value ‘1’, ‘2’ and ‘8’ are added as well. Then, BCD position 0 shall add 4+8, BCD position 1 shall add 6+2 and BCD position 2 shall be 1. The complete circuit design includes all ten input bits, thus resulting in many levels of additions to reach the final BCD output.
In one or more embodiments of the invention, to optimize the design and reduce the addition levels, input bits are added on a bitlevel, not BCD digit level. On our previous example, bit-6 adds value-4 to BCD-0. But in the optimized design, it will add a value of “X1XX” to the BCD-0, where the “X” are don't care bits that may be used by another value. Still in the example, bit-7 adds value-8 to the same BCD-0, resulting in “11XX”. Thus, no addition is required in this simple example. To release any ambiguity, BCD-0 shall have its output in this format “b7-b6-X-X”. For the complete design, the addition levels are decreased significantly. Table 1.10 shows the complete design, and that 4 levels of adders are needed.







TABLE 1.10







Binary Bits are added to form BCD digits












BCD-2
BCD-1
BCD-0



















b8
b7
b6
b5
b4
b3
b2
b1
b0


c1
c0
b8
b6
b5
b7
b4
b4




c2
b7
b8

b6
b5





c1
c0

b8
b8









As the input range is biased, subtracting this bias (398 in case of decimal64) is needed for a correct BCD value. The sign is detected independently according to the carry-out from subtracting the bias. If the sign is negative, the input bits are inverted to their diminished radix complement, 1's complement. The biased range of 0:767 becomes −398:369. This range limits the meaningful binary bits from 0 to 8 only.
If all BCD-0 bit were ‘1’, an accumulated value of ‘41’ is possible. This means that three digits are needed as carry signals for BCD-1 digit. Those digits are placed within BCD-1 for correct results. To prevent BCD-0 digit from having a value in the forbidden range of [10-15], an extra 6 is added, thus proper carry signals are produced to the following BCD-1. If no carry occurs, the 6 is subtracted. Following the same manor, BCD-1 may sum to ‘24’, this is the reason only carry bits are propagated to BCD-2.
Summing all those bit columns will end up with the needed BCD result.
BCD to Binary Integer Converter
This block converts BCD digits to their binary equivalent number. This block is logically opposite to the previously mentioned ‘Binary Integer to BCD converter’. For decimal64 format 3 BCD digits are converted to 10-bits binary format. The design behind this block is simple and straight forward, each BCD digit may produce a range of binary values. According to the BCD digit, a value is selected, then all selected values (1 for each BCD digit) are added. Ranges for different BCD positions are as follow:

    
    
        BCD-0: Values 0-9 may consume up to 4 binary bits
        BCD-1: Values 00-99 may consume up to 7 binary bits
        BCD-2: Values 000-767 may consume up to 10 binary bits
    
    


For decimal64, the three selected numbers are added to get the final binary result. For example, assume the input BCD is 234, then 3 values are selected in parallel:

004→0100

030→0011110

200→0110001000

Summing those three binary number will end up with the needed binary equivalent to 234.
Rounder
The input to the Rounder is the most significant P+1 digits, while the output is P digits only. The rightmost least significant input digit is called the ‘round digit’. According to the rounding direction and the value of the round digit, the result may be delivered as the leftmost P digits or an incremented-by-one copy of it.
Table 1.11 shows all possible conditions to increment the numerical result up. This is done according to values of the least significant and rounding digits and the required rounding direction.







TABLE 1.11







Result Rounding: Conditions to round up












Rounding Direction
Sign
LSD
RD
















Nearest ties to Even
?
?
>5




?
Odd
=5



Away from zero
?
?
>0



Toward Positive (+∞)
+
?
>0



Toward Negative (−∞)
−
?
>0










Toward Zero
Never Rounds up












Half-up
?
?
≧5



Half-down
?
?
>5










If a round up action is required, a value of ‘1’ is added to the least significant digit position. In a single case when all P resultant digits are 9s, the added ‘1’ will propagate and the result will be “1000 . . . 00”. The digits are right-shifted by 1 digit place to accommodate the extra ‘1’, this shift leads to an increase of the resultant exponent by a value of 1. In more worse case, when the result is already at the maximum value, an overflow occurs, and the special result is chosen.
De-Normalizer
After the result is rounded to P digits only, a possible final right-shift is possible. This right-shift is needed if MX had trailing zeros and the rounded number has enough trailing zeros. The master control hardware unit calculates the de-normalization amount as shown in point 8. More than just a shifter, the de-normalizer counts the trailing zeros in the rounded result and if it more than the required shift (requested from the master control hardware unit) then the shift is applied.
Finally, an acknowledge signal is raised to verify that the rounded result is shifted. The master control hardware unit then applies the correction factor.
Flags
As defined by the IEEE 754-2008 standard, all functions shall signal the invalid operation exception on signaling NaN operands, and should signal the inexact exception on inexact results. Moreover, specific per-operation behavior is defined for the power function; overflow and underflow flags are allowed.
System Parameters
According to the error analysis from the DLHU and the DAHU, and emphasized by simulation results, some system design parameters are selected. The simulation was based on several chosen corner cases, rule-based generated numbers and pseudo-random generated numbers.
1. DLHU:
For the worst case of MX=0.9999.99 (all P-digits are nine), the result should have ‘P’ zeros followed by the required precision digits (discussed above). The worst case is when none of the zeros are needed 1, and more iterations are needed. Thus the internal precision for the log should be n=2×P+γ, where is the selected number of guard/extra digits. Our selection for the internal Log precision is n=2×P+6. The parameter n is, clearly, the number of required iterations as well.
As stated before, the DLHU needs to calculate ln(1+ej10−j) in the second stage. The algorithm is designed to use a LUT at the first k iterations, then start approximation for the rest of the n iterations. k is selected to be P+1 which covers the described worst case.
The output precision of the DLHU is P+6. This extra precision is needed to cover the worst case; when MY is near unity and does not add precision digits, and the required, left-shift amount is 3. Then only P+3 digits are left for the anti-log. Given P+3 correct digits, the anti-log can generate correct P+1 digits. Going forward, the rounder needs those P+1 digits to round the final result to P digits. The 3 stages are all connected and the precision allocation decision needs to consider the complete flow.
2. DMHU
The DMHU is enabled after a variable latency. This depends on the required shift amount and the detected leading zeros/nines by the DLHU (discussed above). The latency is 2 clocks+variable amount of clocks to check for the leading zeros/nines which varies between 3 ̃P. Thus, the multiplication stage stars after 5 ̃P+2.
The stage is enabled for P+6 iterations, following the Logarithm stage.
3. DAHU:

    
    
        The DAHU is enabled after P−1 clocks.
        The operation consumes: 1 initialization cycle, P+1 iterations, and a final clock for its second stage latency. Summing up to P+3 clocks, the resultant precision is P+1 digits.
        Finally the rounder may round-up or truncate the P-digit result based upon the round digit, sign and the rounding direction.
    
    


Elementary Function Support
The IEEE standard defines some elementary functions, including the power function. Embodiments of the present invention may be extended to a selected subset of the elementary functions. Table 1.12 shows the selected subset of the standardized elementary functions. The last column shows the basic modifications to support each function.
The IEEE standard defines how each function shall signal the flags. Different behaviors will be shown in details for each function. Next sections will be entitled after the function groups from table 1.12.
Pow
This is the basic group with no overrides or extra blocks to implement the needed functionality. Some notes about flags signaling are listed below.
Flags and Exceptions
For the pow function:

    
    
        pow(x, ±0) is 1 for any x (even a zero, quiet NaN, or infinity)
        pow(±0, y) is ±∞ and signals the divideByZero exception for y an odd integer <0
        pow(±0, −∞) is +∞ with no exception
        pow(±0, +∞) is +0 with no exception
        pow(±0, y) is +∞ and signals the divideByZero exception for finite y<0 and not an odd integer
        pow(±0, y) is ±0 for finite y>0 an odd integer
        pow(±0, y) is +0 for finite y>0 and not an odd integer
        pow(−1; ±∞) is 1 with no exception
        pow(+1, y) is 1 for any y (even a quiet NaN)
        pow(x, y) signals the invalid operation exception for finite x<0 and finite noninteger y.
    
    


For the pown function (integral exponents only):

    
    
        pown(x, 0) is 1 for any x (even a zero, quiet NaN, or infinity)
        pown(±0, n) is ±∞ and signals the divideByZero exception for odd integral n<0
        pown(±0, n) is +∞ and signals the divideByZero exception for even integral n<0
        pown(±0, n) is +0 for even integral n>0
        pown(±0, n) is ±0 for odd integral n>0
    
    


For the powr function:

    
    
        powr(x, ±0) is 1 for finite x>0
        powr(±0, y) is +∞ and signals the divideByZero exception for finite y<0
        powr(±0, −∞) is +∞
        powr(±0, y) is +0 for y>0
        powr(+1, y) is 1 for finite y
        powr(x, y) signals the invalid operation exception for x<0
        powr(±0, ±0) signals the invalid operation exception
        powr(+∞, ±0) signals the invalid operation exception
        powr(+1, ±∞) signals the invalid operation exception
        powr(x, qNaN) is qNaN for x≧0
        powr(qNaN, y) is qNaN.
    
    


Log
This group of functions make use of the first stage ‘Log’ of the DLHU to calculate the logarithmic values of the univariate functions. Log with bases ‘2’ or ‘e’ needs correction based on the following property:




  
    
      
        
          
            log
            b
          
          ⁡
          
            (
            x
            )
          
        
        =
        
          
            
              log
              a
            
            ⁡
            
              (
              x
              )
            
          
          
            
              log
              a
            
            ⁡
            
              (
              b
              )
            
          
        
      
    
    
      
        (
        1.70
        )
      
    
  




Thus, the DMHU is used for this correction. The multiplicand is forced to one value from table 1.13 according to the required function. The DAHU is bypassed. The rounder is used normally after the result is de-normalized.
Flags and Exceptions
For all three functions in the group log(x), common notes are listed:

    
    
        DivideByZero exception is signaled when x=0
        Invalid operation exception is signaled when x<0
        log(+∞) is +∞ with no exception
        log(±0) is −∞ and signals the divideByZero exception
        log(1) is +0
    
    


Exp
This group contains a set of exponentiation functions with different fixed bases: 10, 2, and e. Since the system can calculate XY, the needed exponentiations may be calculated by simply forcing operand ‘X’ with a value of 10, 2 or e according to the required function. A different approach is to skip the DLHU and force its output to a value of Log10(10)=1, Log10(2) or Log10(e) according to the required function.
Flags and Exceptions
For all three functions in the group Exp, common notes are listed:

    
    
        f(+∞) is +∞ and f(−∞) is +0 with no exception
        Possible overflow and underflow
    
    


Compound
This is a single function: compound(x, n). This function is usually used in calculating compound interest, where ‘x’ is the annual interest while ‘n’ is the number of years.
Flags and Exceptions
For a standard compliant implementation, some notes are listed:

    
    
        compound(x, 0) is 1 for x≧−1, +∞, or quiet NaN
        compound(−1, n) is +∞ and signals the divideByZero exception for integral n<0
        compound(1, n) is +0 for integral n>0
    
    


FIG. 9 shows table 1.12 regarding Supported Elementary Functions.







TABLE 1.13







Corrective Multiplicands for Log Functions










Function
Corrective Multiplicand







log10
1



 



log2




  
    1
    
      
        log
        10
      
      ⁡
      
        (
        2
        )
      
    
  
  ≃
  3.3219280948873623478703194294893902







 



log




  
    1
    
      
        log
        10
      
      ⁡
      
        (
        e
        )
      
    
  
  ≃
  2.3025850929940456840179914546843642














Numerical Examples
Example I
Basic XY 
This example shows a basic power operation; pow(12.34, 2.1). The result is 195.7770748667881 and it is inexact. The following steps shows the data flow:
1. DPD operands have a hexadecimal value of: X=2230000000000534, Y=2234000000000021
2. Operands are decoded to:
_X={Sign=0, Exponent=−2+bias, Significand=0000000000001234},
_Y. {Sign=0, Exponent=−1+bias, Significand=0000000000000021}
3. Leading zeros are counted, and both operands are normalized. MX/=0.1234 with an exponent correcting factor K=12, while MX/=0.21 with an exponent correcting factor L=14. The correction factors are added to EX and EY respectively as in equations 1.71 and 1.74.
4. MX/ is corrected by multiplying by 5 to fit in the required range of 0.5≦MX/<1 (discussed above).
5. According to the value of MX/, e1 is selected from table 1.1 to be 7.
6. W[j] is calculated according to equation 1.13, then rounded to get the following ej.
7. Knowing ej, L[j] is accumulated according to equation 1.8.
8. The previous two points are repeated iteratively according to the required iterations, from equation 1.69. Meanwhile, the Log(MX/) is checked for leading zeros. In our example, there are none. The Log(MX/) is fed on-line to the multiplier after a delay of 4 clocks21.
9. Since MX is normalized (i.e., MX/), EX gets a correction factor:




  
    
      
        
          
            
              
                
                  E
                  x
                
                +
                k
              
              =
              
              ⁢
              
                
                  E
                  x
                
                -
                bias
                +
                P
                -
                
                  LeadingZeros
                  x
                
              
            
          
        
        
          
            
              =
              
              ⁢
              
                
                  (
                  
                    
                      -
                      2
                    
                    +
                    bias
                  
                  )
                
                -
                bias
                +
                16
                -
                12
              
            
          
        
        
          
            
              =
              
              ⁢
              2
            
          
        
      
    
    
      
        (
        1.71
        )
      
    
  




As discussed above, it is required to add log10(MX/)+Ex+K. As an optimization technique, we can concatenate the required number only rather than building a full-width adder. Since the log of a fraction of the range 0.1≦MX/<0.5 will always be a negative fraction, and the term EX+K is always an integer, either positive or negative, then concatenation is possible with a correction. In case the integer EX+K is negative (or zero), then the negative fraction is simply concatenated. On the other hand, if the integer part is strictly positive (non-zero), and the fraction is negative as always, then the required action is subtracting the negative fraction from the positive integer. Our novelty comes to state that if the integer is decreased by a value of 1 (like a simple borrow) and the negative fraction is complemented, the same concatenation is still numerically valid. This subtraction needs much less hardware circuitry since the term EX+K is limited to 3 digits. Moreover, since the Log(MX/) is calculated on-line, it is not possible to obtain a correct 10's complement. We chose to use the 9's complement, this is faster than propagating an extra added ‘1’ to the least significant digit. The error due to this choice is neglected with respect to the logarithm total error in equation 1.30.
The integer part, after a possible decrement, is in a binary format. It needs to be converted to BCD before concatenating with the Log result. Two circuits, for Decimal64 and Decimal128, are used to convert from 10-bits (14-bits in case of Decimal128) with the standard defined EX range to 3 BCD digits (4 digits in case of Decimal128).
In our example, the negative Log(MX/) fraction is −0.9086848 . . . , the positive integer value of EX+K is decreased from 2 to 1, then concatenated to the nines complement of the log; 001:0913151 . . . . The integer part of this number is predetermined from the first iteration, while the fraction part is calculated online by the log block. This number is then passed to the DMHU.
10. The left-to-right on-line multiplier has a fixed multiplicand MY/and the on-line multiplier. At each iteration, three digits are selected—from the most significant left digits, and moving to the right least significant ones—from the multiplier to

    
    
        recode the on-line digit using the left-most 2 digits, according to table 1.6. The recoded signed-digit ‘SD’ is then used to select a multiple ranging from −5×, −4×, . . . , 5× then shifted to a position according to the iteration count. The shifted partial product is then accumulated to previous multiples.
        determine if the next (on the future iteration) partial product is negative.
    
    


This is done using the right-most 2 digits. If the next partial product is found to be negative, then its tail digit is placed in the current partial product, right to the selected shifted multiple.
In our example, the first 3 partial products are:














3-digit




Iteration
Window
Multiple
Partial Product







14
109
+1
000021000000000000000000 . . . 00


15
091
+1
000002100000000000000100 . . . 00


16
913
−1
999999789999999999999900 . . . 00









Notice at iteration 15 the tail digit to the next negative partial product. This digit compensates the value of the diminished radix complement (9's complement) for negative numbers.
11. The previous step is repeated, gaining more precision each iteration. The result is approaching to: 001.0913151 . . . ×0.21=0.22917 . . . . In our example, the value of EX+K is not high enough to fill the reserved leading zeros of the third column. In other examples, partial products may fill them.
12. The sign of the product is determined: sign(MY)⊕sign(EX+K+Log(MX/))→positive.
13. The on-line output of the multiplier is shifted by the corrected value of EY:




  
    
      
        
          
            
              
                
                  E
                  y
                
                +
                l
              
              =
              
              ⁢
              
                
                  E
                  y
                
                -
                bias
                +
                P
                -
                
                  LeadingZeros
                  y
                
              
            
          
        
        
          
            
              =
              
              ⁢
              
                
                  (
                  
                    
                      -
                      1
                    
                    +
                    bias
                  
                  )
                
                -
                bias
                +
                16
                -
                14
              
            
          
        
        
          
            
              =
              
              ⁢
              1
            
          
        
      
    
    
      
        (
        1.72
        )
      
    
  




Positive shift amounts lead to a left shift, while negative values lead to right. The shifted product is then fed to the third stage; anti-log. The shifted-out integer part ‘2’ will be used to calculate the resultant exponent.
14. Since the anti-log operand is positive, a correction is needed because the input fraction to the anti-log must be negative (discussed above). This is done by incrementing the integer part to 3, and complementing the fraction part.
15. The DAHU begins with corrective multiplication by ln(10). On the first clock, 3 ready digits are multiplied by the fixed ln(10) value. Next clocks will only have the on-line digit with the introduced correction scheme, whenever needed. In our example, the 3 most significant digits are ‘708’; the nine's complement of 0.291.
16. After the multiplicative correction, the input is approaching −0.7082381 . . . ×ln(10)=−1.630 . . . . According to table 1.9, the value of e1 is −8.0000.
17. Starting with e1, W[2] is calculated (equation 1.52) as




  
    
      
        
          W
          ⁡
          
            [
            2
            ]
          
        
        =
        
        ⁢
        
          
            100
            ×
            m
          
          -
          
            100
            ×
            
              ln
              ⁡
              
                (
                
                  1
                  +
                  
                    
                      e
                      1
                    
                    ×
                    
                      10
                      
                        -
                        1
                      
                    
                  
                
                )
              
            
          
        
      
    
  
  
    
      
        =
        
        ⁢
        
          
            100
            ×
            
              -
              1.630230
            
            ⁢
            
              
            
            ⁢
            ⋯
          
          -
          
            100
            ×
            
              ln
              ⁡
              
                (
                0.2
                )
              
            
          
        
      
    
  
  
    
      
        =
        
        ⁢
        
          
            
              -
              163.0230
            
            ⁢
            
              
            
            ⁢
            ⋯
          
          +
          
            160.94379
            ⁢
            
              
            
            ⁢
            ...
          
        
      
    
  
  
    
      
        =
        
        ⁢
        
          -
          2.07921
        
      
    
  




18. According to equation 1.38, E[2]=1−0.8=0:2 and E[3]=E[2]×(1+e2*10−2)=0.2×(1−0.02)=0.196
19. Using equations 1.38 and 1.49 iteratively, E[j] and W[j] are calculated, ej is the rounded value of W[j]. The value of E[j] approaches the needed result; 0.1957770748667881365 . . . .
20. In this example, since the precise exact result needs an infinite precision, but rounded to the 16-digit decimal64, there will be no de-normalization.
21. Digits beyond position 16 will be rounded off the final result. According to the rounding direction, result sign and the round digits the result may be incremented. In our case, we assume the standard default rounding direction; round-nearest-ties-to-even. The round digits are 0.365, which will be rounded off with no increment.
22. The result sign is positive. Negative results occur under the following conditions:

    
    
        SX is negative
        MY is odd
    
    


23. The result exponent, EZ, has many corner cases for its calculations. For this particular example, it is quite simple:



  
    
      2
      ⁢
      
        
      
      ⁢
      
        (
        
          Shifted
          ⁢
          
            
          
          ⁢
          Integer
          ⁢
          
            
          
          ⁢
          Part
        
        )
      
    
    +
    
      

    
    ⁢
    
      1
      ⁢
      
        (
        
          Anti
          ⁢
          
            -
          
          ⁢
          log
          ⁢
          
            
          
          ⁢
          Adjustment
        
        )
      
    
    +
    
      

    
    ⁢
    
      -
      
        P
        ⁡
        
          (
          
            
              M
              z
            
            ⁢
            
              
            
            ⁢
            has
            ⁢
            
              
            
            ⁢
            its
            ⁢
            
              
            
            ⁢
            decimal
            ⁢
            
              
            
            ⁢
            point
            ⁢
            
              
            
            ⁢
            to
            ⁢
            
              
            
            ⁢
            the
            ⁢
            
              
            
            ⁢
            right
            ⁢
            
              
            
            ⁢
            by
            ⁢
            
              
            
            ⁢
            definition
          
          )
        
      
    
    +
    
      

    
    ⁢
    bias
  




  
    
      E
      z
    
    =
    
      
        -
        13
      
      +
      bias
    
  



The first line, the shifted integer part is in BCD format. It needs to be converted to binary format before been added to the other terms. Our novelties include two circuits; to convert 3 BCD digits to 10-bits binary integer for Decimal64 and to convert 4 BCD digits to 14-bit binary integer in case of Decimal128. Details of these circuits are shown in 1.5. If the shift amount was too high, so the shifted digits count exceed the defined limit, overflow occurs.
24. Finally the exception flags are output as:














Inexact
Invalid
Overflow
Underflow
Divide-by-zero







1
0
0
0
0









25. Accordingly, this example ends up calculating the following:




  
    
      
        
          12.34
          2.1
        
        =
        
        ⁢
        
          10
          
            
              (
              
                
                  
                    log
                    10
                  
                  ⁡
                  
                    (
                    0.1234
                    )
                  
                
                +
                2
              
              )
            
            ×
            0.21
            ×
            10
          
        
      
    
  
  
    
      
        =
        
        ⁢
        195.7770748667881
      
    
  




Example II
Basic XY, Zero Ex+k and a Final De-Normalization
In this example, the logical flow is almost the same. The main difference is that the exact result can fit within the 16 digits of the decimal64 format. The normalized precision digits of the result (0.1953125×10−2) will be de-normalized by right-shifting the final result. This shift will generate leading zeros in the result (0000000001953125×10−9). This behavior will match the standard-defined preferred exponent; lower is better as long as we do not throw any significant digits. The steps are similar to the previous example (i.e., Example I), duplicate info is omitted.
1. DPD operands have a hexadecimal value of: X=222C0000000000A5, Y=2238000000000003
2. Operands are deCoded to:

    
    
        X={Sign=0, Exponent=−3+bias, Significand=0000000000000125},
        Y={Sign=0, Exponent=0+bias, Significand=0000000000000003}
    
    


3. Leading zeros are counted, and both operands are normalized. MX/=0.125 with an exponent correcting factor K=13, while MX/=0.3 with an exponent correcting factor L=15. The correction factors are added to EX and EY respectively as before.
4. MX/ is corrected by multiplying by 5 to fit in the required range of 0.5≦MX/<1. Now, MX/=0.625.
5. According to the value of MX/, e1 is selected from table 1.1 to be 6.
6. W[j] is calculated according to equation 1.13, then rounded to get the following ej.
7. Knowing ej, L[j] is accumulated 25 according to equation 1.8.
8. The previous two points are repeated iteratively. Meanwhile, the Log(MX/) is checked for leading zeros. In our example, there are none. The Log(MX/) is fed on-line to the multiplier after a delay of 4 clocks. It seams that 0.625 is a lucky number that hits an accurate LUT entry at the first iteration. All error residuals, W[j], are of near-zero values.
9. Since Mx is normalized (i.e., MX/), EX gets a correction factor:




  
    
      
        
          
            E
            x
          
          +
          k
        
        =
        
        ⁢
        
          
            E
            x
          
          -
          bias
          +
          P
          -
          
            LeadingZeros
            x
          
        
      
    
  
  
    
      
        =
        
        ⁢
        
          
            (
            
              
                -
                3
              
              +
              bias
            
            )
          
          -
          bias
          +
          16
          -
          13
        
      
    
  
  
    
      
        =
        
        ⁢
        0
      
    
  




Accordingly, it is required to add log10(MX/)+EX+K. In our example, the negative Log(MX/) fraction is −0.90308998 . . . , the zero integer value of EX+K is not decreased. It's concatenated to the negative fraction of the log: −000:90308998 . . . . This number is then passed to the DMHU.
10. The left-to-right on-line multiplier has a fixed multiplicand MY/ and the on-line multiplier. At each iteration, three digits are selected, from the most significant left digits, and moving to the right least significant ones, to recode the on-line digit in SD format and determine if a tail digit is needed for the next negative partial product.
11. The previous step is repeated, gaining more precision each iteration. The result is approaching to: −000.90308998 . . . ×0.3=−0.270926996097583075:::.
12. The sign of the product is determined: sign(MY)⊕sign(EX+K+Log(MX/))→negative.
13. The on-line output of the multiplier is shifted by the corrected value of EY/:




  
    
      
        
          
            
              
                
                  E
                  y
                
                +
                l
              
              =
              
              ⁢
              
                
                  E
                  y
                
                -
                bias
                +
                P
                -
                
                  LeadingZeros
                  y
                
              
            
          
        
        
          
            
              =
              
              ⁢
              
                
                  (
                  
                    0
                    +
                    bias
                  
                  )
                
                -
                bias
                +
                16
                -
                15
              
            
          
        
        
          
            
              =
              
              ⁢
              1
            
          
        
      
    
    
      
        (
        1.73
        )
      
    
  




Positive shift amounts lead to a left shift, while negative values lead to right. The shifted product is then fed to the third stage; anti-log. The shifted-out integer part ‘−2’ will be used to calculate the resultant exponent.
14. Since the anti-log operand is negative, no correction is needed.
15. The DAHU begins with corrective multiplication by ln(10). On the first clock, 3 ready digits are multiplied by the fixed ln(10) value. Next clocks will only have the on-line digit with the introduced correction scheme, whenever needed. In our example, the 3 most significant digits are ‘709’.
16. After the multiplicative correction, the input is approaching −0.709269960975830 . . . ×ln(10)=−1.633 . . . . According to table 1.9, the value of e1 is −8.000.
17. Starting with e1, W[2] is calculated (equation 1.52) as




  
    
      
        
          W
          ⁡
          
            [
            2
            ]
          
        
        =
        
        ⁢
        
          
            100
            ×
            m
          
          -
          
            100
            ×
            
              ln
              ⁡
              
                (
                
                  1
                  +
                  
                    
                      e
                      1
                    
                    ×
                    
                      10
                      
                        -
                        1
                      
                    
                  
                
                )
              
            
          
        
      
    
  
  
    
      
        =
        
        ⁢
        
          
            100
            ×
            
              -
              1.63315443905
            
            ⁢
            
              
            
            ⁢
            ⋯
          
          -
          
            100
            ×
            
              ln
              ⁡
              
                (
                0.2
                )
              
            
          
        
      
    
  
  
    
      
        =
        
        ⁢
        
          
            
              -
              163.31544390
            
            ⁢
            
              
            
            ⁢
            ⋯
          
          +
          
            160.94379
            ⁢
            
              
            
            ⁢
            ...
          
        
      
    
  
  
    
      
        =
        
        ⁢
        
          
            -
            2.37165
          
          ⁢
          
            
          
          ⁢
          ...
        
      
    
  




18. According to equation 1.38, E[2]=1−0.8=0.2 and E[3]=E[2]×(1+e2*10−2)=0.2×(1−0.02)=0.196
19. Using equations 1.38 and 1.49 iteratively, E[j] and W[j] are calculated, ej is the rounded value of W[j]. The value of E[j] approaches the needed result; 0.1953125.
20. Since the precise exact result needs only 7 digits, shifting right and adjusting the exponent to reach the standard-defined preferred exponent is called ‘denormalization’. The result becomes 0000000001953125.
21. No digits are rounded-off the 16-digit.
22. The result sign is positive.
23. For this particular example, EZ, is calculated as:




  
    
      
        -
        2
      
      ⁢
      
        
      
      ⁢
      
        (
        
          Shifted
          ⁢
          
            
          
          ⁢
          Integer
          ⁢
          
            
          
          ⁢
          Part
        
        )
      
    
    +
    
      

    
    ⁢
    
      
        +
        0
      
      ⁢
      
        
      
      ⁢
      
        (
        
          Anti
          ⁢
          
            -
          
          ⁢
          log
          ⁢
          
            
          
          ⁢
          Adjustment
        
        )
      
    
    +
    
      

    
    ⁢
    
      
        +
        9
      
      ⁢
      
        
      
      ⁢
      
        (
        
          De
          ⁢
          
            -
          
          ⁢
          normalization
          ⁢
          
            
          
          ⁢
          correction
        
        )
      
    
    +
    
      

    
    ⁢
    
      -
      
        P
        ⁡
        
          (
          
            
              M
              z
            
            ⁢
            
              
            
            ⁢
            has
            ⁢
            
              
            
            ⁢
            its
            ⁢
            
              
            
            ⁢
            decimal
            ⁢
            
              
            
            ⁢
            point
            ⁢
            
              
            
            ⁢
            to
            ⁢
            
              
            
            ⁢
            the
            ⁢
            
              
            
            ⁢
            right
            ⁢
            
              
            
            ⁢
            by
            ⁢
            
              
            
            ⁢
            definition
          
          )
        
      
    
    +
    
      

    
    ⁢
    
      bias
      ⁢
      
        

      
      ⁢
      
        E
        z
      
    
  
  =
  
    
      -
      9
    
    +
    bias
  




24. Finally the exception flags are all reset:














Inexact
Invalid
Overflow
Underflow
Divide-by-zero







0
0
0
0
0









25. Accordingly, the example ends up with calculating the following:




  
    
      
        
          0.125
          3
        
        =
        
        ⁢
        
          10
          
            
              (
              
                
                  
                    log
                    10
                  
                  ⁡
                  
                    (
                    0.125
                    )
                  
                
                +
                0
              
              )
            
            ×
            0.3
            ×
            10
          
        
      
    
  
  
    
      
        =
        
        ⁢
        0.001953125
      
    
  




Example III
Basic Overflow Scenario
This example shows a basic power operation, pow(129090912,230), that results in an overflow. This is due to the result is 32062 . . . ×101866 which exceeds the standard defined maximum value of 10369 for decimal64.
1. DPD operands have a hexadecimal value of: X=223800000A90699C, Y=2238000000000130
2. Operands are decoded to:

    
    
        X={Sign=0, Exponent=0+bias, Significand=0000000129090912},
        Y={Sign=0, Exponent=0+bias, Significand=0000000000000230}
    
    


3. Leading zeros are counted, and both operands are normalized. MX/=0.129090912 with an exponent correcting factor K=7, while MY/=0.230 with an exponent correcting factor L=13. The correction factors are added to EX and EY respectively as before.
4. MX/ is corrected by multiplying by 5 to fit in the required range of 0.5≦MX/<1. Now, MX/=0.64545456.
5. According to the value of MX/, e1 is selected from table 1.1 to be 6.
6. W[j] is calculated according to equation 1.13, then rounded to get the following ej.
7. Knowing ej, L[j] is accumulated according to equation 1.8.
8. The previous two points are repeated iteratively. Meanwhile, the Log(MX/) is checked for leading zeros. In our example, there are none. The Log(MX/) is fed on-line to the multiplier after a delay of 4 clocks.
9. Since MX is normalized (i.e., MX/), EX gets a correction factor




  
    
      
        
          
            E
            x
          
          +
          k
        
        =
        
        ⁢
        
          
            E
            x
          
          -
          bias
          +
          P
          -
          
            Leading
            ⁢
            
              
            
            ⁢
            
              Zeros
              x
            
          
        
      
    
  
  
    
      
        =
        
        ⁢
        
          
            (
            
              0
              +
              bias
            
            )
          
          -
          bias
          +
          16
          -
          7
        
      
    
  
  
    
      
        =
        
        ⁢
        9
      
    
  




Accordingly, it is required to add log10(MX/)+EX/+K. In our example, the negative Log(MX/) fraction is −0.90308998 . . . , the positive integer value of EX/+K is decreased to 8. It's concatenated to the nines complement of the fraction: 008.09691001 . . . . This number is then passed to the DMHU.
10. The left-to-right on-line multiplier has a fixed multiplicand ‘MY/’ and the on-line multiplier. At each iteration, three digits are selected, from the most significant left digits, and moving to the right least significant ones, to recode the on-line digit in SD format and determine if a tail digit is needed for the next negative partial product.
11. The previous step is repeated, gaining more precision each iteration. The result is approaching to: 8.110895669011 . . . ×0.230=1.86550600387 . . . .
12. The sign of the product is determined: sign(MY)⊕sign(EX+K+Log(MX/))→positive
13. The on-line output of the multiplier is shifted by the corrected value of EY:




  
    
      
        
          
            
              
                
                  E
                  y
                
                +
                l
              
              =
              
              ⁢
              
                
                  E
                  y
                
                -
                bias
                +
                P
                -
                
                  LeadingZeros
                  y
                
              
            
          
        
        
          
            
              =
              
              ⁢
              
                
                  (
                  
                    0
                    +
                    bias
                  
                  )
                
                -
                bias
                +
                16
                -
                13
              
            
          
        
        
          
            
              =
              
              ⁢
              3
            
          
        
      
    
    
      
        (
        1.74
        )
      
    
  




Positive shift amounts lead to a left shift, while negative values lead to right. The shifted product is then fed to the third stage; anti-log. The shifted-out integer part ‘1865’ will be used to calculate the resultant exponent. But since this value is greater than the maximum standard-defined exponent, 369, then overflow occurs.
14. The special result is selected according to the rounding direction; it may be +∞ or the maximum representable number, 99 . . . 99×10369. Assuming the default rounding direction, round-nearest-ties-to-even, the result is +∞.
15. Finally the exception flags are as:














Inexact
Invalid
Overflow
Underflow
Divide-by-zero







1
0
1
0
0









Example IV
On-Line Correction for the Decimal Multiplier Hardware Unit
This example shows the correction scheme between the DLHU and the DMHU. As discussed above, the result of the Logarithm may have some flipping digits, and can cause numerical errors to the next stage (i.e., multiplication). The example is 100075. The numerical result is not shown, only the details between logarithm and multiplication is interesting in this example.
As the normal flow goes, the sequence below is applied as usual:
1. DPD operands have a hexadecimal value of: X=223c000000000080, Y=3dfe800000000000
2. Operands are decoded to:

    
    
        X={Sign=0, Exponent=1+bias, Significand=0000000000000100},
        Y={Sign=0, Exponent=−15+bias, Significand=7500000000000000}
    
    


3. EX+K is calculated to be +4, but decremented to +3 due to concatenation with the negative Log fraction.
4. Log(MX/)+EX+K=Log(0.1)+4=−1+4=3. To reach the exact value of 3, the Log iterations make some digit flip when approaching the boundary of unity; 0.999 ̃1.000. Trailing non-zero digits are beyond P+5 range of correct digits.
5. 3 digits are fed on-line to the multiplier, the first two are used to encode the multiplier signed digit (SD), while the last two are used to predict the sign of the next digit, to add a possible tail digit.
6. The current SD is compared to the previous next, if they differ, then an increment or a decrement had occurred.
7. According to increment/decrement signals, the correction factor is chosen and added to the current selected multiple:

    
    
        As shown in FIG. 10, on clock 4: The next SD was seen positive, no tail digit added. On clock 5, the current SD is negative, the missing tail digit is inserted at the correct position according to an iteration counter.
        Still referring to FIG. 10, on clock 5: The next SD was seen negative, a tail digit is added. On clock 6, the current SD is positive, a leading train of nines are added to carry-out the wrongly inserted tailing ‘1’.
        Similar errors and corrections are found on clock 7 and 11, respectively, as shown in FIG. 10.
    
    


8. This novel correction scheme fixes many cases other than Log(0.1).
Whenever the numerical result is near the unity boundary (0.xyz00000000abc) or the tie boundary (0.xzy50000000abc), this correction scheme is a must.
9. The on-line accumulation of all partial products and the correction factors, will converge to the correct numerical product 2.25000 . . . 00.
Example V
On-Line Correction for the Decimal Antilogarithm Hardware Unit
This example shows the correction scheme between the DMHU and the DAHU. As discussed above, the result of the on-line multiplication may have some flipping digits, and can cause numerical errors to the next stage: anti-log. The example is 200003. The numerical result is not of interest, only the details between multiplication and the antilogarithm is interesting in this example.
As the normal flow goes, the sequence below is applied as usual:
1. Operands are decoded to:

    
    
        X={Sign=0, Exponent=1+bias, Significand=00000000000200000},
        Y={Sign=0, Exponent=−6+bias, Significand=00000000003000000}
    
    


2. The term EX+K=5.301029995663 . . . is multiplied by the normalized MY/=0.3. The product is approaching: 1:590308998699 . . . .
3. The product is then shifted with the value EY+L=−6+16−9=1. The positive value is a left-shift. The integer part, 15, is shifted out, while the fraction is fed to the DAHU.
4. Due to the positive value of the product, the fraction fed to the antilog must be corrected to be negative. The integer part is incremented to 16, and the fraction is complemented. Thus the input to the antilog is −0:096910013 . . . .
5. Due to initial conditions constraints on e1, the 3 most significant digits are needed to address e1. The 3 digit data path is used only on the first iteration, and a single digit is fed afterwards in the next iterations. The correction scheme makes use of those unused digit places to insert correction digits.
6. After the initial iteration where all 3 digits are used, the 3 input digit to the DAHU are selected as follows:

    
    
        00D: No correction needed. Here, ‘D’ is the on-line digit.
        01D: The previous on-line digit has flipped to the higher value, incremental correction is applied by adding an extra ‘1’ to the tens place.
        00 D: The previous on-line digit has flipped to the lower value, decremental correction is applied by replacing ‘1’ with its ten's complement. This is numerically equivalent to subtracting 1 from the previous multiple.
    
    


7. FIG. 11 shows a real example: At the fourth clock the input is flipped to a higher value. A correction is applied by adding ‘1’ to the tens place, thus incrementing the current multiple to compensate the previous one.
8. As seen from the table, the resultant antilog is sticking to 8. A final de-normalization is done, since both operands are integers. The final result is 0008000000000000×103.
The system(s) and processes described in this detailed description may be used in any application requiring decimal calculations, including (but not limited to) applications of: finance, taxation, investments, transportation, commerce, energy consumption, energy pricing/purchasing, etc.
Embodiments of the invention may be implemented on virtually any type of computer regardless of the platform being used. For example, as shown in FIG. 12, a computer system (1200) includes one or more hardware processor(s) (1202) (such as a central processing unit (CPU), integrated circuit, etc.), associated memory (1204) (e.g., random access memory (RAM), cache memory, flash memory, etc.), a storage device (1206) (e.g., a hard disk, an optical drive such as a compact disk drive or digital video disk (DVD) drive, a flash memory stick, etc.), and numerous other elements and functionalities typical of today's computers (not shown). The computer system (1200) may also include input means, such as a keyboard (1208), a mouse (1210), or a microphone (not shown). Further, the computer system (1200) may include output means, such as a monitor (1212) (e.g., a liquid crystal display (LCD), a plasma display, or cathode ray tube (CRT) monitor). The computer system (1200) may be connected to a network (1214) (e.g., a local area network (LAN), a wide area network (WAN), the Internet, or any other type of network) via a network interface connection (not shown). Those skilled in the art will appreciate that many different types of computer systems exist, and the aforementioned input and output means may take other forms. Generally speaking, the computer system (1200) includes at least the minimal processing, input, and/or output means necessary to practice embodiments of the invention.
Further, in one or more embodiments of the invention, one or more elements of the aforementioned computer system (1200) may be located at a remote location and connected to the other elements over a network. Further, embodiments of the invention may be implemented on a distributed system having a plurality of nodes, where each portion of the invention may be located on a different node within the distributed system. In one embodiment of the invention, the node corresponds to a computer system. Alternatively, the node may correspond to a processor with associated physical memory. The node may alternatively correspond to a processor or micro-core of a processor with shared memory and/or resources. Further, software instructions in the form of computer readable program code to perform embodiments of the invention may be stored, temporarily or permanently, on a non-transitory computer readable storage medium, such as a compact disc (CD), a diskette, a tape, a hard drive, punch cards, memory, or any other tangible computer readable storage device.
While the invention has been described with respect to a limited number of embodiments, those skilled in the art, having benefit of this disclosure, will appreciate that other embodiments can be devised which do not depart from the scope of the invention as disclosed herein. Accordingly, the scope of the invention should be limited only by the attached claims.

## Claims

1. A method for executing a decimal elementary function (DEF) computation from a first decimal floating-point operand (DFPO) operand and a second DFPO, comprising:
extracting a first mantissa and a first biased exponent from the first DFPO and a second mantissa and a second biased exponent from the second DFPO;
generating a first normalized mantissa by shifting the first mantissa based on a number of leading zeros in the first mantissa;
generating a second normalized mantissa by shifting the second mantissa based on a number of leading zeros in the second mantissa;
calculating, using a decimal logarithm hardware unit (DLHU) implementing a first digit recurrence algorithm, a plurality of approximations for a logarithm of the first normalized mantissa;
calculating, using a decimal multiplier hardware unit (DMHU) and the plurality of approximations for the logarithm, a plurality of approximations for a product of the second normalized mantissa and a first sum based on the logarithm of the first normalized mantissa and the first biased exponent;
generating a plurality of shifted values by shifting the plurality of approximations for the product based on the second biased exponent;
generating a plurality of fraction components from the plurality of shifted values;
calculating, using a decimal antilogarithm hardware unit (DAHU) implementing a second digit recurrence algorithm, an antilog based on the plurality of fraction components; and
outputting a decimal floating-point result of the DEF computation comprising a resultant mantissa based on the antilog and a resultant biased exponent based on at least one integer component of at least one of the plurality of shifted values.

2. The method of claim 1, further comprising:
scaling the first normalized mantissa by a scale factor in response to the first normalized mantissa being less than 0.5; and
subtracting a logarithm of the scale factor from an output of the first digit recurrence algorithm.

3. The method of claim 1, further comprising:
calculating a first correction factor by subtracting a bias of the first biased exponent and the number of leading zeros in the first mantissa from a precision of the first DFPO;
generating a second sum by adding the first correction factor and the first biased exponent; and
adding, before calculating the plurality of approximations for the product, the second sum to an approximation of the logarithm.

4. The method of claim 3, further comprising:
calculating a second correction factor by subtracting the bias and the number of leading zeros in the second mantissa from the precision of the first DFPO;
generating a third sum by adding the second correction factor and the second biased exponent; and
shifting, in response to the second sum equaling zero and the third sum being positive, an approximation for the logarithm by a number of leading zeros in the approximation for the logarithm,
wherein shifting at least one of the plurality of approximations for the product is further based on the second correction factor and the number of leading zeros in the approximation for the logarithm.

5. The method of claim 1, wherein calculating the plurality of approximations for the product comprises:
identifying a current slice and a next slice of a first approximation for the logarithm;
coding the current slice of the first approximation for the logarithm to a first signed-digit (SD);
coding the next slice of the first approximation for the logarithm to a second SD;
selecting a first multiple of the second normalized mantissa corresponding to the first SD;
shifting the first multiple based on an iteration being executed by the DMHU; and
adding, in response to the second SD being negative, a tail digit of one to the first multiple after shifting.

6. The method of claim 5, further comprising:
identifying a current slice and a next slice of a second approximation for the logarithm;
coding the current slice of the second approximation for the logarithm to a third SD;
selecting a second multiple of the second normalized mantissa corresponding to the third SD;
shifting the second multiple based on an iteration being executed by the DMHU; and
removing, in response to the third SD being positive, the tail digit by adding a correction vector to the second multiple after shifting.

7. The method of claim 1, wherein calculating the plurality of approximations for the product comprises:
identifying a current slice of a first approximation for the logarithm;
identifying a current slice of a second approximation for the logarithm;
coding the current slice of the second approximation for the logarithm to a signed-digit (SD);
selecting a multiple of the second normalized mantissa corresponding to the SD; and
complimenting the multiple in response to a 0.5 boundary condition between the current slice of the first approximation for the logarithm and the current slice of the second approximation for the logarithm.

8. The method of claim 1, further comprising:
identifying a fraction component and an integer component of a shifted value;
subtracting, before calculating the antilog, one from the fraction component in response to the fraction component being positive; and
adding, in response to subtracting one from the fraction component, one to the integer component.

9. The method of claim 1, further comprising:
identifying a number of trailing zeros in the first mantissa;
generating a rounded version of the antilog; and
de-normalizing the rounded version based on the number of trailing zeros.

10. The method of claim 1, further comprising:
incrementing, in response to the DEF being a compound operation, the first DFPO by one.

11. A system for executing a decimal elementary function (DEF) computation from a first decimal floating-point operand (DFPO) operand and a second DFPO, comprising:
an input processing hardware unit (IPHU) configured to:
generate a first normalized mantissa from a first mantissa extracted from the first DFPO based on a number of leading zeros in the first mantissa; and
generate a second normalized mantissa from a second mantissa extracted from the second DFPO based on a number of leading zeros in the second mantissa;

a decimal logarithm hardware unit (DLHU) configured to calculate a plurality of approximations for a logarithm of the first normalized mantissa using a first digit recurrence algorithm;
a decimal multiplier hardware unit (DMHU) configured to calculate a plurality of approximations for a product of the second normalized mantissa and a first sum using the plurality of approximations for the logarithm,
wherein the first sum is based on the logarithm of the first normalized mantissa and a first biased exponent extracted from the first DFPO;
a shifter configured to generate a plurality of shifted values by shifting the plurality of approximations for the product based on a second biased exponent extracted from the second DFPO;
a decimal antilogarithm hardware unit (DAHU) configured to calculate, using a second digit recurrence algorithm, an antilog based on a plurality of fraction components generated from the plurality of shifted values; and
an output formulation hardware unit configured to generate a decimal floating-point result of the DEF comprising a resultant mantissa based on the antilog and a resultant biased exponent based on at least one integer component of at least one of the plurality of shifted values.

12. The system of claim 11, wherein the DLHU comprises:
an adjustment block configured to scale the first normalized mantissa by a scale factor in response to the first normalized mantissa being less than 0.5; and
an adder to subtract a logarithm of the scale factor from an output of the first digit recurrence algorithm.

13. The system of claim 11, wherein the IPHU is further configured to:
calculate a correction factor by subtracting a bias of the first biased exponent and the number of leading zeros in the first mantissa from a precision of the first DFPO; and
generate a second sum by adding the correction factor and the first biased exponent,
wherein the second sum is added to an approximation of the logarithm using a wire concatenation.

14. The system of claim 13, wherein the DLHU comprises:
a logLeadingZero block configured to shift, in response to at least the second sum being zero, an approximation of the logarithm by a number of leading zeros in the approximation of the logarithm,
wherein shifting at least one of the plurality of approximations for the product is further based on the number of leading zeros in the approximation of the logarithm.

15. The system of claim 11, wherein the DMHU comprises:
a first signed-digit (SD) coding block configured to code a current slice of a first approximation for the logarithm to a first signed-digit (SD) and a current slice of a second approximation for the logarithm to a second SD;
a multiple selector configured to select a first multiple of the second mantissa based on the first SD and a second multiple of the second mantissa based on the second SD; and
a second SD coding block configured to code a next slice of the first approximation for the logarithm to a third SD and concatenate a tail digit of one to the first multiple in response the third SD being negative.

16. The system of claim 15, wherein the DMHU further comprises:
a compressor configured to add, in response to the second SD being positive, a correction vector to the second multiple to remove the tail digit.

17. The system of claim 11, wherein the DMHU comprises:
a first signed-digit (SD) coding block configured to code a current slice of a first approximation for the logarithm to a first SD and a current slice of a second approximation for the logarithm to a second SD;
a comparator configured to identify a 0.5 boundary condition between the current slice of the first approximation for the logarithm and the current slice of the second approximation for the logarithm; and
a multiple selector configured to select a multiple of the second mantissa based on the second SD and compliment the multiple based on an output of the comparator.

18. The system of claim 11, further comprising:
a master control hardware unit configured to calculate a sign of the decimal floating-point result and to calculate a correction factor by subtracting a bias of the second biased exponent and the number of leading zeros in the second mantissa from a precision of the second DFPO.

19. The system of claim 11, wherein the shifter further comprises functionality to:
subtract one from a fraction component in response to the fraction component being positive; and
add, in response to subtracting one from the fraction component, one to an integer component corresponding to the fraction component.

20. The system of claim 11, wherein the DAHU comprises:
a first stage configured to select only one digit from an approximation of the product during an iteration; and
a second stage configured to calculate the antilog based on an output from the first stage.

21. The system of claim 11, further comprising:
a rounder configured to generate a rounded version of the antilog; and
a de-normalizer configured to denormalize the rounded version based on a number of trailing zeros in the first mantissa.

22. A system for calculating a logarithm of a decimal floating-point operand (DFPO) to a base (B), comprising:
an input processing hardware unit (IPHU) configured to:
extract a mantissa and a biased exponent from the DFPO; and
generate a normalized mantissa by shifting the mantissa based on a number of leading zeros in the mantissa;

a decimal logarithm hardware unit (DLHU) configured to calculate a plurality of approximations for a logarithm of the normalized mantissa to base 10 using a digit recurrence algorithm;
a decimal multiplier hardware unit (DMHU) configured to calculate a product of a sum and an inverse of a logarithm of B to base 10 using the plurality of approximations, wherein the sum is based on the biased exponent and the logarithm of the normalized mantissa to base 10; and
an output formulation hardware unit configured to generate a decimal floating-point result of the logarithm of the DFPO comprising a resultant mantissa based on the product and a resultant biased exponent based on the exponent and the number of leading zeros.

23. The system of claim 22, wherein the IPHU is further configured to increment the DFPO operand by one before generating the normalized mantissa.

24. A system for calculating a base (B) raised to a decimal floating-point operand (DFPO), comprising:
an input processing hardware unit configured to:
extract a mantissa and a biased exponent from the DFPO; and
generate a normalized mantissa by shifting the mantissa based on a number of leading zeros in the mantissa;

a decimal multiplier hardware unit (DMHU) configured to calculate a product of the normalized mantissa and a logarithm of B to base 10;
a shifter configured to generated a shifted value by shifting the product based on the biased exponent and the number of leading zeros;
a decimal antilogarithm hardware unit (DAHU) configured to calculate an antilog of a fraction component of the shifted value using a digit recurrence algorithm; and
an output formulation hardware unit (OFHU) configured to generate a decimal floating-point result comprising a resultant mantissa based on the antilog and a resultant biased exponent based on at least an integer component of the shifted value.

25. The system of claim 24, wherein the OFHU is further configured to subtract one from the decimal floating-point result.