/*
ID: Aman Raj
LANG: C++
TASK: nocows
*/
//#include<iostream>
#include <stdio.h>
//#include<iostream>
#include<vector>
#include<algorithm>
using namespace std;
#include<math.h>
typedef  long long  ll;
#include <bits/stdc++.h>
#include <vector>
#include <set>
#include <map>
#include <string>
#include <cstdio>
#include <cstdlib>
#include <climits>
#include <utility>
#include <algorithm>
#include <cmath>
#include <queue>
#include <stack>
#include <iomanip>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
//setbase - cout << setbase (16); cout << 100 << endl; Prints 64
//setfill -   cout << setfill ('x') << setw (5); cout << 77 << endl; prints xxx77
//setprecision - cout << setprecision (14) << f << endl; Prints x.xxxx
//cout.precision(x)  cout<<fixed<<val;  // prints x digits after decimal in val

using namespace std;
using namespace __gnu_pbds;

#define f(i,a,b) for(i=a;i<b;i++)
#define rep(i,n) f(i,0,n)
#define fd(i,a,b) for(i=a;i>=b;i--)
#define pb push_back
#define mp make_pair
#define vi vector< int >
#define vl vector< ll >
#define ss second
#define ff first
#define fast  ios_base::sync_with_stdio(false); cin.tie(0);  cout.tie(0);
//#define ll long long
#define pii pair< int,int >
#define pll pair< ll,ll >
#define sz(a) a.size()
#define inf (1000*1000*1000+5)
#define all(a) a.begin(),a.end()
#define tri pair<int,pii>
#define vii vector<pii>
#define vll vector<pll>
#define viii vector<tri>
#define mod (1000*1000*1000+7)
//#define mod 3
#define pqueue priority_queue< int >
#define pdqueue priority_queue< int,vi ,greater< int > >
//#define flush fflush(stdout)
#define primeDEN 727999983
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
#include <fstream>
// find_by_order()  // order_of_key
typedef tree<
	int,
	null_type,
	less<int>,
	rb_tree_tag,
	tree_order_statistics_node_update>
	ordered_set;


   /*bool comp(pair<ll,ll> p1, pair<ll,ll> p2)
   {
    if(p1.first!=p2.first)return p1.first < p2.first;
     else return p1.second < p2.second;
   }*/



   ll power1(ll a, ll b)//a raised to power b
   {  if(b<=0) return 1; if(b==1) return a;
       ll c=power1(a,b/2);
        c*=c;c%=mod;if(b%2==1) c*=a;c%=mod;
        return c;
   }
   ll mi(ll a,ll m)
   { ll c= power1(a,m-2);

     return c;
   }

   ll findpower(ll a,ll b)
   {
       ll i=0;
       ll c=1;
        while(1)
        {
            c*=2;

            if(c>a)return i;
            i++;
        }
   }


vector<ll> dpfact;
   ll fact(ll a)
   { return dpfact[a];

   }
   /*
   ll gcd(ll a,ll b)
   {
       if(b==0)return a;
       return gcd(b,a%b);
   }
   #define MAXN 1000001

// stores smallest prime factor for every number
int spf[MAXN];
void sieve()
{
	spf[1] = 1;
	for (int i=2; i<MAXN; i++)

		// marking smallest prime factor for every
		// number to be itself.
		spf[i] = i;

	// separately marking spf for every even
	// number as 2
	for (int i=4; i<MAXN; i+=2)
		spf[i] = 2;

	for (int i=3; i*i<MAXN; i++)
	{
		// checking if i is prime
		if (spf[i] == i)
		{
			// marking SPF for all numbers divisible by i
			for (int j=i*i; j<MAXN; j+=i)

				// marking spf[j] if it is not
				// previously marked
				if (spf[j]==j)
					spf[j] = i;
		}
	}
}*/

 ll n,m;
  vector<ll> vpar;
   vector<ll> vtotal;
  ll findpar(ll i)
  {
       if(vpar[i]!=-1)return vpar[i]=findpar(vpar[i]);
       return i;
  }
 int main()
 {     cin>>n>>m;
        vector<pair<ll,ll> > vcon(m);
         for(auto &x:vcon){cin>>x.first>>x.second;}
         vpar.resize(n+1,-1);
         vtotal.resize(n+1,1);
         vector<ll> vans(m+1);
           ll ans=((n-1)*n)/2;
            vans[m]=ans;

          for(ll i=m;i>1;i--)// ith ko jod ke i-1 ka ans          {
          {
                ll a=vcon[i-1].first,b=vcon[i-1].second;
                ll p1=findpar(a),p2=findpar(b);
                 if(p1!=p2){


                ans-=vtotal[p1]*vtotal[p2];
                 if(vtotal[a]>vtotal[b]){swap(a,b);swap(p1,p2);}
                  vpar[p2]=p1;
                  vtotal[p1]+=vtotal[p2];

                 }




               vans[i-1]=ans;
          }
          for(ll i=1;i<=m;i++)cout<<vans[i]<<endl;




     return 0 ;
 }


Measured memory_bytes: 5248