// base. https://atcoder.jp/contests/abc146/submissions/8612775

#include <algorithm>
#include <bitset>
#include <cassert>
#include <cmath>
#include <functional>
#include <iomanip>
#include <iostream>
#include <map>
#include <queue>
#include <unordered_map>
#include <vector>
#include <string.h>
#include <set>

using namespace std;

#define COUT(x) cout << #x << " = " << (x) << " (L" << __LINE__ << ")" << endl

template<class T> void printvec(const vector<T>& v) {
  for (auto x : v) { cout << x << " "; }
  cout << endl;
}
template<class T> void printtree(const vector< vector<T> >& tree) {
  for (long long i = 0; i < tree.size(); ++i) {
    cout << i + 1 << ": "; printvec(tree[i]);
  }
}
template<class T, class U> void printmap(const map<T, U>& mp) {
  for (auto x : mp) { cout << x.first << "=>" << x.second << endl; }
}

template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return true; } return false; }
template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return true; } return false; }

#define rep(i, n) for(ll i = 0; i < n; ++i)
#define all(s) s.begin(), s.end()
#define fr first
#define sc second
#define mp make_pair
#define pb push_back

typedef long long ll;
typedef unsigned long long ull;
typedef pair<ll, ll> P;
typedef tuple<ll, ll, ll> triple;
typedef double D;

const ll INF = 1e9;
const ll MOD = 1000000007;  // 1e9 + 7

// Segment Tree
template <typename T>
class SegTree {
public:
  SegTree(int _n) {
    n = 1;
    while (n < _n) { n *= 2; }
    dat = vector<T>(2 * n - 1, INF);
  }

  void update(int k, T a) {
    k += n - 1;
    dat[k] = a;
    while (k > 0) {
      k = (k - 1) / 2;
      dat[k] = min(dat[k * 2 + 1], dat[k * 2 + 2]);
    }
  }

  // Calculate the min of [a, b)
  T query(int a, int b) {
    return _query(a, b, 0, 0, n);
  }

  // Calculate the min of [a, b)
  // k is the index (dat[k]). This is matched to [l, r)
  T _query(int a, int b, int k, int l, int r) {
    // The intersection of [a, b) and [r, l) is blank.
    if (r <= a || b <= l) { return INF; }

    if (a <= l && r <= b) {  // [r, l) is completely included in [a, b)
      return dat[k];
    } else {
      int vl = _query(a, b, k * 2 + 1, l, (l + r) / 2);
      int vr = _query(a, b, k * 2 + 2, (l + r) / 2, r);
      return min(vl, vr);
    }
  }

private:
  int n; // The size of source data. The power of 2.
  vector<T> dat; // The data. The size if 2*n-1. The last n elements(dat[n..2*n-2]) are leaves(source data). The first n-1 elements are nodes.
};

// int main(int argc, char** argv) {
//   int arr[] = { 1, 3, 2, 7, 9, 11 };
//   int n = 6;
//
//   SegTree<int> st(n);
//   rep(i, n) {
//     st.update(i, arr[i]);
//   }
//
//   cout << st.query(1, 5) << endl;
//   cout << st.query(0, 4) << endl;
//   cout << st.query(3, 5) << endl;
// }

const int MAXN = 1e5 + 5;

int main(int argc, char** argv) {
  cin.tie(NULL);
  cout.tie(NULL);
  ios_base::sync_with_stdio(false);
  //cout << setprecision(10) << fixed;

  int n, m;
  cin >> n >> m;
  string s;
  cin >> s;

  vector<int> acc(n+2);
  rep(i, n+1) {
    acc[i+1] = acc[i] + (s[i] == '0');
  }
  vector<int> te;

  int now = n;
  while (now > 0) {
    int l = max(now - m, 0), r = now;
    if (acc[l] == acc[now]) { // can not reach to l from now.
      cout << -1 << endl;
      return 0;
    }
    // We want to find the minimum l in which acc[l] != acc[l+1].
    while (r-l > 1) {
      int c = (l + r) / 2;
      if (acc[c] == acc[l]) {
        l = c;
      } else {
        r = c;
      }
    }
    te.push_back(now-l);
    now = l;
  }
  reverse(all(te));
  rep(i, te.size()) {
    cout << te[i] << (i == te.size()-1 ? '\n' : ' ');
  }
}


Measured memory_bytes: 1480