#include <bits/stdc++.h>
#define _GLIBCXX_DEBUG
using namespace std;
using ll = long long;
using vec = vector<ll>;
using vect = vector<double>;
using Graph = vector<vector<ll>>;
#define loop(i, n) for (ll i = 0; i < n; i++)
#define Loop(i, m, n) for (ll i = m; i < n; i++)
#define pool(i, n) for (ll i = n; i >= 0; i--)
#define Pool(i, m, n) for (ll i = n; i >= m; i--)
#define mod 1000000007ll
//#define mod 998244353ll
#define flagcount __builtin_popcount
#define flag(x) (1ll << x)
#define flagadd(bit, x) bit |= flag(x)
#define flagpop(bit, x) bit &= ~flag(x)
#define flagon(bit, i) bit &flag(i)
#define flagoff(bit, i) !(bit & (1ll << i))
#define all(v) v.begin(), v.end()
#define low2way(v, x) lower_bound(all(v), x)
#define high2way(v, x) upper_bound(all(v), x)
#define idx_lower(v, x) (distance(v.begin(), low2way(v, x)))  //配列vでx未満の要素数を返す
#define idx_upper(v, x) (distance(v.begin(), high2way(v, x))) //配列vでx以下の要素数を返す
#define idx_lower2(v, x) (v.size() - idx_lower(v, x))         //配列vでx以上の要素数を返す
#define idx_upper2(v, x) (v.size() - idx_upper(v, x))         //配列vでxより大きい要素の数を返す
#define putout(a) cout << a << endl
#define Sum(v) accumulate(all(v), 0ll)
#define gcd(x, y) __gcd(x, y)
ll ctoi(char c)
{
    if (c >= '0' && c <= '9')
    {
        return c - '0';
    }
    return -1;
}
template <typename T>
string make_string(T N)
{
    string ret;
    T now = N;
    while (now > 0)
    {
        T x = now % 10;
        ret += (char)('0' + x);
        now /= 10;
    }
    reverse(all(ret));
    return ret;
}
template <typename T>
T lcm(T x, T y)
{
    T z = gcd(x, y);
    return x * y / z;
}
template <typename T>
bool primejudge(T n)
{
    if (n < 2)
        return false;
    else if (n == 2)
        return true;
    else if (n % 2 == 0)
        return false;
    double sqrtn = sqrt(n);
    for (T i = 3; i < sqrtn + 1; i++)
    {
        if (n % i == 0)
        {
            return false;
        }
        i++;
    }
    return true;
}
template <typename T>
bool chmax(T &a, const T &b)
{
    if (a < b)
    {
        a = b; // aをbで更新
        return true;
    }
    return false;
}
template <typename T>
bool chmin(T &a, const T &b)
{
    if (a > b)
    {
        a = b; // aをbで更新
        return true;
    }
    return false;
}
//場合によって使い分ける
//const ll dx[4]={1,0,-1,0};
//const ll dy[4]={0,1,0,-1};
const ll dx[8] = {1, 1, 0, -1, -1, -1, 0, 1};
const ll dy[8] = {0, 1, 1, 1, 0, -1, -1, -1};
//2次元配列の宣言
//vector<vector<ll>> field(h, vector<ll>(w));
struct edge
{
    long long to;
    long long cost;
};
typedef pair<long long, long long> P; //P.first:最短距離,P.second:頂点の番号
//頂点V個の負閉路なし重み付きグラフGにおける始点sからの最短距離を求める
void dijkstra(const vector<vector<edge>> &G, vector<long long> &dist, long long s)
{
    //greater<P>によってfirstが小さい順に取り出される
    long long V = G.size();
    priority_queue<P, vector<P>, greater<P>> que;
    for (long long i = 0; i < V; i++)
        dist[i] = 1e18;
    dist[s] = 0;
    que.push(P(0, s));
    //queが空になるまで繰り返す
    while (!que.empty())
    {
        P p = que.top();
        que.pop();
        long long v = p.second;
        if (dist[v] < p.first)
            continue; //すでに最短距離ならスルー
        for (long long i = 0; i < G[v].size(); i++)
        {
            edge e = G[v][i];
            //更新作業
            if (dist[e.to] > dist[v] + e.cost)
            {
                dist[e.to] = dist[v] + e.cost;
                que.push(P(dist[e.to], e.to));
            }
        }
    }
}
int main()
{
    cout << fixed << setprecision(30);
    ll N, M, S, T;
    cin >> N >> M >> S >> T;
    S--;
    T--;
    vector<vector<edge>> Gyen(N), Gsnk(N);
    loop(i, M)
    {
        ll u, v, a, b;
        cin >> u >> v >> a >> b;
        u--;
        v--;
        edge e1, e2, e3, e4;
        e1.to = v;
        e2.to = u;
        e3.to = v;
        e4.to = u;
        e1.cost = a;
        e2.cost = a;
        e3.cost = b;
        e4.cost = b;
        Gyen[u].push_back(e1);
        Gyen[v].push_back(e2);
        Gsnk[u].push_back(e3);
        Gsnk[v].push_back(e4);
    }
    vector<ll> Dyen(N), Dsnk(N);
    dijkstra(Gyen, Dyen, S);
    dijkstra(Gsnk, Dsnk, T);
    vector<ll> ans(N);
    ll minn = 1e18;
    for (ll i = N - 1; i >= 0; i--)
    {
        minn = min(minn, Dyen[i] + Dsnk[i]);
        ans[i] = 1000000000000000 - minn;
    }
    loop(i, N) putout(ans[i]);
    return 0;
}


Measured memory_bytes: 21032