There is a country with $n$ citizens. The $i$-th of them initially has $a_{i}$ money. The government strictly controls the wealth of its citizens. Whenever a citizen makes a purchase or earns some money, they must send a receipt to the social services mentioning the amount of money they currently have.

Sometimes the government makes payouts to the poor: all citizens who have strictly less money than $x$ are paid accordingly so that after the payout they have exactly $x$ money. In this case the citizens don't send a receipt.

You know the initial wealth of every citizen and the log of all events: receipts and payouts. Restore the amount of money each citizen has after all events.


-----Input-----

The first line contains a single integer $n$ ($1 \le n \le 2 \cdot 10^{5}$) — the numer of citizens.

The next line contains $n$ integers $a_1$, $a_2$, ..., $a_n$ ($0 \le a_{i} \le 10^{9}$) — the initial balances of citizens.

The next line contains a single integer $q$ ($1 \le q \le 2 \cdot 10^{5}$) — the number of events.

Each of the next $q$ lines contains a single event. The events are given in chronological order.

Each event is described as either 1 p x ($1 \le p \le n$, $0 \le x \le 10^{9}$), or 2 x ($0 \le x \le 10^{9}$). In the first case we have a receipt that the balance of the $p$-th person becomes equal to $x$. In the second case we have a payoff with parameter $x$.


-----Output-----

Print $n$ integers — the balances of all citizens after all events.


-----Examples-----
Input
4
1 2 3 4
3
2 3
1 2 2
2 1

Output
3 2 3 4 

Input
5
3 50 2 1 10
3
1 2 0
2 8
1 3 20

Output
8 8 20 8 10 



-----Note-----

In the first example the balances change as follows: 1 2 3 4 $\rightarrow$ 3 3 3 4 $\rightarrow$ 3 2 3 4 $\rightarrow$ 3 2 3 4

In the second example the balances change as follows: 3 50 2 1 10 $\rightarrow$ 3 0 2 1 10 $\rightarrow$ 8 8 8 8 10 $\rightarrow$ 8 8 20 8 10

```python

USER_FILENAME = "<user_code>"
import sys, json, builtins
import math, heapq, bisect, itertools, functools, collections, statistics, fractions, decimal, operator, array, random, re, string, os, pathlib
try:
    import resource as _res
except Exception:
    _res = None
from collections import Counter, defaultdict, deque, OrderedDict
from functools import lru_cache, reduce
from itertools import accumulate, permutations, combinations, product
from math import gcd, ceil, floor, sqrt
from decimal import Decimal
try:
    from typing import *
except Exception:
    pass
try:
    sys.setrecursionlimit(1_000_000)
except Exception:
    pass
try:
    import site as _site
    try:
        _sys_sites = _site.getsitepackages() if hasattr(_site, "getsitepackages") else []
        for _p in _sys_sites:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
    try:
        _usp = _site.getusersitepackages()
        if isinstance(_usp, str):
            _usp = [_usp]
        for _p in _usp:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
except Exception:
    pass

ns = {"__name__": "__main__"}
for _k, _v in list(globals().items()):
    if not _k.startswith("_"):
        ns[_k] = _v
_CODE = 'n = int(input().strip())\na = list(map(int, input().split()))\nq = int(input().strip())\nqueries = []\nlast_balance = [-1]*n\nlast_balance_id = [-1]*n\n\nfor i in range(q):\n    query = list(map(int, input().split()))\n    queries.append(query)\n    if query[0]==1:\n        p = query[1]-1\n        last_balance[p] = query[2]\n        last_balance_id[p] = i\n\n\n#print(last_balance)\n#print(last_balance_id)\n\nmax_pay = [0]*(q+1)\nfor i in range(q-1,-1,-1):\n    query = queries[i]\n    if query[0]==2:\n        max_pay[i]=max(query[1], max_pay[i+1])\n    else:\n        max_pay[i]=max_pay[i+1]\n\n#print(max_pay)\n\nfor p in range(n):\n    #print("person: ",p)\n    if last_balance_id[p]>=0:\n        id = last_balance_id[p]\n        pay = max_pay[id]\n        #print(id, pay)\n        a[p] = max(pay, last_balance[p])\n    else:\n        a[p] = max(a[p], max_pay[0])\n\nprint(" ".join([str(x) for x in a]))'
_co = compile(_CODE, USER_FILENAME, "exec")
exec(_co, ns, ns)

```

Measured memory_bytes: 13699