// https://atcoder.jp/contests/abc177/tasks/abc177_c
#include <bits/stdc++.h>
using namespace std;
#define int long long
#define REP(i, n) FOR(i, 0, n)
#define FOR(i, s, n) for (int i = (s), i##_len = (n); i < i##_len; ++i)
#define ALL(obj) (obj).begin(), (obj).end()
#define ALLR(obj) (obj).rbegin(), (obj).rend()
#define CEIL(a, b) ((a - 1) / b + 1)
const int MOD = 1e9 + 7;

// 参考
// https://atcoder.jp/contests/s8pc-1/submissions/15772604
template <int mod> struct ModInt {
    int x;

    ModInt() : x(0) {}

    ModInt(int64_t y) : x(y >= 0 ? y % mod : (mod - (-y) % mod) % mod) {}

    ModInt &operator+=(const ModInt &p) {
        if ((x += p.x) >= mod)
            x -= mod;
        return *this;
    }

    ModInt &operator-=(const ModInt &p) {
        if ((x += mod - p.x) >= mod)
            x -= mod;
        return *this;
    }

    ModInt &operator*=(const ModInt &p) {
        x = (int)(1LL * x * p.x % mod);
        return *this;
    }

    ModInt &operator/=(const ModInt &p) {
        *this *= p.inverse();
        return *this;
    }

    ModInt operator-() const { return ModInt(-x); }

    ModInt operator+(const ModInt &p) const { return ModInt(*this) += p; }

    ModInt operator-(const ModInt &p) const { return ModInt(*this) -= p; }

    ModInt operator*(const ModInt &p) const { return ModInt(*this) *= p; }

    ModInt operator/(const ModInt &p) const { return ModInt(*this) /= p; }

    bool operator==(const ModInt &p) const { return x == p.x; }

    bool operator!=(const ModInt &p) const { return x != p.x; }

    ModInt inverse() const {
        int a = x, b = mod, u = 1, v = 0, t;
        while (b > 0) {
            t = a / b;
            swap(a -= t * b, b);
            swap(u -= t * v, v);
        }
        return ModInt(u);
    }

    ModInt pow(int64_t n) const {
        ModInt ret(1), mul(x);
        while (n > 0) {
            if (n & 1)
                ret *= mul;
            mul *= mul;
            n >>= 1;
        }
        return ret;
    }

    friend ostream &operator<<(ostream &os, const ModInt &p) {
        return os << p.x;
    }

    friend istream &operator>>(istream &is, ModInt &a) {
        int64_t t;
        is >> t;
        a = ModInt<mod>(t);
        return (is);
    }

    static int get_mod() { return mod; }
};

using modint = ModInt<MOD>;

// https://ei1333.github.io/algorithm/segment-tree.html
template <typename Monoid> struct SegmentTree {
    using F = function<Monoid(Monoid, Monoid)>;

    int sz;
    vector<Monoid> seg;

    const F f;
    const Monoid M1;

    // サイズnのセグ木の初期化。fは2つの要素をマージする二項演算, M1は単位元
    SegmentTree(int n, const F f, const Monoid &M1) : f(f), M1(M1) {
        sz = 1;
        while (sz < n)
            sz <<= 1;
        seg.assign(2 * sz, M1);
    }

    // k番目の要素にxをセットする。後でbuildが必要
    void set(int k, const Monoid &x) { seg[k + sz] = x; }

    // setした結果で構築する
    void build() {
        for (int k = sz - 1; k > 0; k--) {
            seg[k] = f(seg[2 * k + 0], seg[2 * k + 1]);
        }
    }

    // k番目の要素をxに変更する
    void update(int k, const Monoid &x) {
        k += sz;
        seg[k] = x;
        while (k >>= 1) {
            seg[k] = f(seg[2 * k + 0], seg[2 * k + 1]);
        }
    }

    // 区間 [l,r) に対して二項演算をした結果を返す
    Monoid query(int a, int b) {
        Monoid L = M1, R = M1;
        for (a += sz, b += sz; a < b; a >>= 1, b >>= 1) {
            if (a & 1)
                L = f(L, seg[a++]);
            if (b & 1)
                R = f(seg[--b], R);
        }
        return f(L, R);
    }

    Monoid operator[](const int &k) const { return seg[k + sz]; }
};

void solve() {
    int N;
    cin >> N;
    vector<int> A(N);
    // 区間sum
    SegmentTree<modint> seg(
        N, [](modint a, modint b) { return a + b; }, 0);

    REP(i, N) {
        cin >> A[i];
        seg.set(i, A[i]);
    }
    seg.build();
    modint a = 0;
    for (int i = N - 1; i > 0; i--) {
        modint u = seg.query(0, i);
        a += u * A[i];
    }
    cout << a << endl;
}

signed main() {
    cin.tie(nullptr)->sync_with_stdio(false);
    solve();
}


Measured memory_bytes: 9004