akhauriyash/Code-Regression huggingface dataset:
Given an integer N, Chef wants to find the smallest positive integer M such that the bitwise XOR of M and M+1 is N. If no such M exists output -1.

-----Input-----
The first line of input contain an integer T denoting the number of test cases. Each of the following T lines contains an integer N for that test case.

-----Output-----
For each test case, output a single line containing the number M or -1 as described above.

-----Constraints-----
- 1 ≤ T ≤ 5000
- 1 ≤ N ≤ 230

-----Example-----
Input:
1
3

Output:
1

-----Explanation-----First Example :  M desired in the problem would be 1. As bitwise XOR of 1 and 2 is equal to 3.

```python

USER_FILENAME = "<user_code>"
import sys, json, builtins
import math, heapq, bisect, itertools, functools, collections, statistics, fractions, decimal, operator, array, random, re, string, os, pathlib
try:
    import resource as _res
except Exception:
    _res = None
from collections import Counter, defaultdict, deque, OrderedDict
from functools import lru_cache, reduce
from itertools import accumulate, permutations, combinations, product
from math import gcd, ceil, floor, sqrt
from decimal import Decimal
try:
    from typing import *
except Exception:
    pass
try:
    sys.setrecursionlimit(1_000_000)
except Exception:
    pass
try:
    import site as _site
    try:
        _sys_sites = _site.getsitepackages() if hasattr(_site, "getsitepackages") else []
        for _p in _sys_sites:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
    try:
        _usp = _site.getusersitepackages()
        if isinstance(_usp, str):
            _usp = [_usp]
        for _p in _usp:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
except Exception:
    pass

ns = {"__name__": "__main__"}
for _k, _v in list(globals().items()):
    if not _k.startswith("_"):
        ns[_k] = _v
_CODE = 't=int(input())\nwhile(t>0):\n n=int(input())\n if(n==1):\n  print(2)\n else:\n  q=0\n  for i in range(1,31):\n   p=1<<i\n   if(p^(p-1)==n):\n    print(p-1)\n    q=1\n    break\n  if(q==0):\n   print(-1)\n t-=1'
_co = compile(_CODE, USER_FILENAME, "exec")
exec(_co, ns, ns)

```

Measured memory_bytes: 13003
You are given a sequence D_1, D_2, ..., D_N of length N.
The values of D_i are all distinct.
Does a tree with N vertices that satisfies the following conditions exist?
 - The vertices are numbered 1,2,..., N.
 - The edges are numbered 1,2,..., N-1, and Edge i connects Vertex u_i and v_i.
 - For each vertex i, the sum of the distances from i to the other vertices is D_i, assuming that the length of each edge is 1.
If such a tree exists, construct one such tree.

-----Constraints-----
 - 2 \leq N \leq 100000
 - 1 \leq D_i \leq 10^{12}
 - D_i are all distinct.

-----Input-----
Input is given from Standard Input in the following format:
N
D_1
D_2
:
D_N

-----Output-----
If a tree with n vertices that satisfies the conditions does not exist, print -1.
If a tree with n vertices that satisfies the conditions exist, print n-1 lines.
The i-th line should contain u_i and v_i with a space in between.
If there are multiple trees that satisfy the conditions, any such tree will be accepted.

-----Sample Input-----
7
10
15
13
18
11
14
19

-----Sample Output-----
1 2
1 3
1 5
3 4
5 6
6 7

The tree shown below satisfies the conditions.

```python

USER_FILENAME = "<user_code>"
import sys, json, builtins
import math, heapq, bisect, itertools, functools, collections, statistics, fractions, decimal, operator, array, random, re, string, os, pathlib
try:
    import resource as _res
except Exception:
    _res = None
from collections import Counter, defaultdict, deque, OrderedDict
from functools import lru_cache, reduce
from itertools import accumulate, permutations, combinations, product
from math import gcd, ceil, floor, sqrt
from decimal import Decimal
try:
    from typing import *
except Exception:
    pass
try:
    sys.setrecursionlimit(1_000_000)
except Exception:
    pass
try:
    import site as _site
    try:
        _sys_sites = _site.getsitepackages() if hasattr(_site, "getsitepackages") else []
        for _p in _sys_sites:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
    try:
        _usp = _site.getusersitepackages()
        if isinstance(_usp, str):
            _usp = [_usp]
        for _p in _usp:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
except Exception:
    pass

ns = {"__name__": "__main__"}
for _k, _v in list(globals().items()):
    if not _k.startswith("_"):
        ns[_k] = _v
_CODE = 'n,*d = map(int,open(0).read().split())\nzd = {di:i for i,di in enumerate(d)}\n*sd, = sorted(d)\nparent = [-1]*n\nsize = {i:1 for i in d}\ndist = {i:0 for i in d}\nok = 1\nfor v in sd[n-1:0:-1]:\n    p = v - n + 2*size[v]\n    if p >= v:\n        ok = 0\n        break\n    if p in zd:\n        size[p] += size[v]\n        dist[p] += dist[v]+size[v]\n        parent[zd[v]] = zd[p]\n    else:\n        ok = 0\n        break\nif dist[sd[0]] != sd[0]: ok = 0\nif ok:\n    for i,pi in enumerate(parent):\n        if pi != -1: print(i+1,pi+1)\nelse:\n    print(-1)'
_co = compile(_CODE, USER_FILENAME, "exec")
exec(_co, ns, ns)

```

Measured memory_bytes: 18955
=====Function Descriptions=====
One of the built-in functions of Python is divmod, which takes two arguments a and b and returns a tuple containing the quotient of first and then the remainder.

=====Problem Statement=====
For example:
>>> print divmod(177,10)
(17, 7)

Here, the integer division is 177/10 => 17 and the modulo operator is 177%10 => 7.

Task
Read in two integers, a and b, and print three lines.
The first line is the integer division a//b (While using Python2 remember to import division from __future__).
The second line is the result of the modulo operator: a%b.
The third line prints the divmod of a and b.

=====Input Format=====
The first line contains the first integer, a, and the second line contains the second integer, b.

=====Output Format=====
Print the result as described above.

```python

USER_FILENAME = "<user_code>"
import sys, json, builtins
import math, heapq, bisect, itertools, functools, collections, statistics, fractions, decimal, operator, array, random, re, string, os, pathlib
try:
    import resource as _res
except Exception:
    _res = None
from collections import Counter, defaultdict, deque, OrderedDict
from functools import lru_cache, reduce
from itertools import accumulate, permutations, combinations, product
from math import gcd, ceil, floor, sqrt
from decimal import Decimal
try:
    from typing import *
except Exception:
    pass
try:
    sys.setrecursionlimit(1_000_000)
except Exception:
    pass
try:
    import site as _site
    try:
        _sys_sites = _site.getsitepackages() if hasattr(_site, "getsitepackages") else []
        for _p in _sys_sites:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
    try:
        _usp = _site.getusersitepackages()
        if isinstance(_usp, str):
            _usp = [_usp]
        for _p in _usp:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
except Exception:
    pass

ns = {"__name__": "__main__"}
for _k, _v in list(globals().items()):
    if not _k.startswith("_"):
        ns[_k] = _v
_CODE = 'output = divmod(int(input().strip()), int(input().strip()))\nprint(output[0])\nprint(output[1])\nprint(output)'
_co = compile(_CODE, USER_FILENAME, "exec")
exec(_co, ns, ns)

```

Measured memory_bytes: 12985
In a regular table tennis match, the player who serves changes every time after 2 points are scored, regardless of which players scored them.
Chef and Cook are playing a different match — they decided that the player who serves would change every time after $K$ points are scored instead (again regardless of which players scored them). When the game starts, it's Chef's turn to serve.
You are given the current number of points scored by Chef and Cook ($P_1$ and $P_2$ respectively). Find out whether Chef or Cook has to serve next.

-----Input-----
- The first line of the input contains a single integer $T$ denoting the number of test cases. The description of $T$ test cases follows.
- The first and only line of each test case contains three space-separated integers $P_1$, $P_2$ and $K$.

-----Output-----
For each test case, print a single line containing the string "CHEF" if it is Chef's turn or "COOK" if it is Cook's turn.

-----Constraints-----
- $1 \le T \le 10^5$
- $1 \le K \le 10^{9}$
- $0 \le P_1, P_2 \le 10^{9}$ 

-----Subtasks-----
Subtask #1 (100 points): original constraints

-----Example Input-----
3
1 3 2
0 3 2
34 55 2

-----Example Output-----
CHEF
COOK
CHEF

-----Explanation-----
Example case 1: Chef serves for the first two points, Cook serves for the next two, so Chef has to serve again now.

```python

USER_FILENAME = "<user_code>"
import sys, json, builtins
import math, heapq, bisect, itertools, functools, collections, statistics, fractions, decimal, operator, array, random, re, string, os, pathlib
try:
    import resource as _res
except Exception:
    _res = None
from collections import Counter, defaultdict, deque, OrderedDict
from functools import lru_cache, reduce
from itertools import accumulate, permutations, combinations, product
from math import gcd, ceil, floor, sqrt
from decimal import Decimal
try:
    from typing import *
except Exception:
    pass
try:
    sys.setrecursionlimit(1_000_000)
except Exception:
    pass
try:
    import site as _site
    try:
        _sys_sites = _site.getsitepackages() if hasattr(_site, "getsitepackages") else []
        for _p in _sys_sites:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
    try:
        _usp = _site.getusersitepackages()
        if isinstance(_usp, str):
            _usp = [_usp]
        for _p in _usp:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
except Exception:
    pass

ns = {"__name__": "__main__"}
for _k, _v in list(globals().items()):
    if not _k.startswith("_"):
        ns[_k] = _v
_CODE = '# cook your dish here\nfor _ in range(int(input())):\n p1,p2,k=map(int,input().split())\n x = (p1+p2)//k\n if(x%2 == 0):\n  print("CHEF")\n else:\n  print("COOK")'
_co = compile(_CODE, USER_FILENAME, "exec")
exec(_co, ns, ns)

```

Measured memory_bytes: 12949
This is probably the simplest problem ever. You just need to count the number of ordered triples of different numbers (X1, X2, X3), where Xi could be any positive integer from 1 to Ni, inclusive (i = 1, 2, 3).
No, wait. I forgot to mention that numbers N1, N2, N3 could be up to 1018. Well, in any case it is still quite simple :)
By the way, because of this the answer could be quite large. Hence you should output it modulo 109 + 7. That is you need to find the remainder of the division of the number of required triples by 109 + 7.

-----Input-----
The first line of the input contains an integer T denoting the number of test cases. The description of T test cases follows. The only line of each test case contains three space-separated integers N1, N2, N3.

-----Output-----
For each test case, output a single line containing the number of required triples modulo 109 + 7.

-----Constraints-----
- 1 ≤ T ≤ 1000
- 1 ≤ Ni ≤ 1018

-----Example-----
Input:
5
3 3 3
2 4 2
1 2 3
25 12 2012
1 1 2013

Output:
6
4
1
578880
0

-----Explanation-----
Example case 1. We have the following triples composed of different numbers up to 3:
(1, 2, 3)
(1, 3, 2)
(2, 1, 3)
(2, 3, 1)
(3, 1, 2)
(3, 2, 1)
Example case 2. Here the triples are:
(1, 3, 2)
(1, 4, 2)
(2, 3, 1)
(2, 4, 1)
Example case 3. Here the only triple is (1, 2, 3).
Example case 4. Merry Christmas! 
Example case 5. ... and Happy New Year! By the way here the answer is zero since the only choice for X1 and for is X2 is 1, so any such triple will have equal numbers.

```python

USER_FILENAME = "<user_code>"
import sys, json, builtins
import math, heapq, bisect, itertools, functools, collections, statistics, fractions, decimal, operator, array, random, re, string, os, pathlib
try:
    import resource as _res
except Exception:
    _res = None
from collections import Counter, defaultdict, deque, OrderedDict
from functools import lru_cache, reduce
from itertools import accumulate, permutations, combinations, product
from math import gcd, ceil, floor, sqrt
from decimal import Decimal
try:
    from typing import *
except Exception:
    pass
try:
    sys.setrecursionlimit(1_000_000)
except Exception:
    pass
try:
    import site as _site
    try:
        _sys_sites = _site.getsitepackages() if hasattr(_site, "getsitepackages") else []
        for _p in _sys_sites:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
    try:
        _usp = _site.getusersitepackages()
        if isinstance(_usp, str):
            _usp = [_usp]
        for _p in _usp:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
except Exception:
    pass

ns = {"__name__": "__main__"}
for _k, _v in list(globals().items()):
    if not _k.startswith("_"):
        ns[_k] = _v
_CODE = 'T = int(input())\nans = []\n\nm = 10**9 + 7\n\nfor _ in range(T):\n N = [int(i) for i in input().split()]\n\n N.sort()\n ans.append( ((N[0]%m)*((N[1]-1)%m)*((N[2]-2)%m))%m )\n\nfor i in ans:\n print(i)\n'
_co = compile(_CODE, USER_FILENAME, "exec")
exec(_co, ns, ns)

```

Measured memory_bytes: 13071
-----Problem description.-----
This problem deals with the I/O methods used in codechef. 
You are supposed to print the integer in its reverse form , or in simple words, print the reverse of the given integer . For instance , reverse of  120 is 21  (not 021)  .

-----Input-----
- The first line of each test case contains an integer T .

- following T lines contains distinct integers N .



-----Output-----
- Output should contain T line , each line with the distinct integer as asked in question . 

-----Constraints-----
- 1 ≤ T ≤ 105

- 1 ≤ N ≤ 1018

Subtask 1 :  N ≤ 105
Subtask 2 :  N ≤ 109
Subtask 3 :  N ≤ 1018



-----Example-----
Input:
3
1234
4567
1

Output:
4321
7654
1

-----Explanation-----
reverse of 1234 is 4321 , 4567 is 7654 & of 1 is 1 

NOTE: testcases may contain large range of data, use datatypes accordingly .

```python

USER_FILENAME = "<user_code>"
import sys, json, builtins
import math, heapq, bisect, itertools, functools, collections, statistics, fractions, decimal, operator, array, random, re, string, os, pathlib
try:
    import resource as _res
except Exception:
    _res = None
from collections import Counter, defaultdict, deque, OrderedDict
from functools import lru_cache, reduce
from itertools import accumulate, permutations, combinations, product
from math import gcd, ceil, floor, sqrt
from decimal import Decimal
try:
    from typing import *
except Exception:
    pass
try:
    sys.setrecursionlimit(1_000_000)
except Exception:
    pass
try:
    import site as _site
    try:
        _sys_sites = _site.getsitepackages() if hasattr(_site, "getsitepackages") else []
        for _p in _sys_sites:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
    try:
        _usp = _site.getusersitepackages()
        if isinstance(_usp, str):
            _usp = [_usp]
        for _p in _usp:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
except Exception:
    pass

ns = {"__name__": "__main__"}
for _k, _v in list(globals().items()):
    if not _k.startswith("_"):
        ns[_k] = _v
_CODE = "# cook your code here\nt= int(input())\nfor i in range(t):\n a = input()\n a = a.rstrip('0')\n print(a[::-1])\n"
_co = compile(_CODE, USER_FILENAME, "exec")
exec(_co, ns, ns)

```

Measured memory_bytes: 12899
Coach Moony wants the best team to represent their college in ICPC. He has $N$ students standing in a circle with certain rating $X_i$ on a competitive coding platform. It is an established fact that any coder with more rating on the platform is a better coder.      
Moony  wants to send his best $3$ coders based upon their rating. But all coders only want to have their friends in their team and every coder is friends with four other coders, adjacent two on left side in the circle, and adjacent two on right. So Moony comes up with a solution that team with maximum cumulative rating of all three members in a team shall be representing their college.
You need to give the cumulative score of the team that will be representing the college.

-----Input:-----
- First line will contain $T$, number of testcases. 
- First line of each test case contains a single integer $N$.
- Second  line of each test case takes $N$ integers, denoting rating of $ith$ coder.

-----Output:-----
For each testcase, output a single integer denoting cumulative rating  of the team.

-----Constraints-----
- $1 \leq T \leq 10$
- $7 \leq N \leq 10^5$ 
- $0 \leq X_i \leq 10^9$

-----Sample Input:-----
1

7

10 40 30 30 20 0 0  

-----Sample Output:-----
100

```python

USER_FILENAME = "<user_code>"
import sys, json, builtins
import math, heapq, bisect, itertools, functools, collections, statistics, fractions, decimal, operator, array, random, re, string, os, pathlib
try:
    import resource as _res
except Exception:
    _res = None
from collections import Counter, defaultdict, deque, OrderedDict
from functools import lru_cache, reduce
from itertools import accumulate, permutations, combinations, product
from math import gcd, ceil, floor, sqrt
from decimal import Decimal
try:
    from typing import *
except Exception:
    pass
try:
    sys.setrecursionlimit(1_000_000)
except Exception:
    pass
try:
    import site as _site
    try:
        _sys_sites = _site.getsitepackages() if hasattr(_site, "getsitepackages") else []
        for _p in _sys_sites:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
    try:
        _usp = _site.getusersitepackages()
        if isinstance(_usp, str):
            _usp = [_usp]
        for _p in _usp:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
except Exception:
    pass

ns = {"__name__": "__main__"}
for _k, _v in list(globals().items()):
    if not _k.startswith("_"):
        ns[_k] = _v
_CODE = 'for _ in range(int(input())):\n    n=int(input())\n    x=list(map(int, input().split()))\n    x.append(x[0])\n    x.append(x[1])\n    n+=2\n    s=0\n    if(n<=3):\n        print(sum(x))\n        continue\n    for i in range(n-3):\n        if(sum(x[i:i+3])>s):\n            s=sum(x[i:i+3])\n    print(s)'
_co = compile(_CODE, USER_FILENAME, "exec")
exec(_co, ns, ns)

```

Measured memory_bytes: 13261
Dhote and Shweta went on a tour by plane for the first time.Dhote was surprised by the conveyor belt  at the airport.As Shweta was getting bored Dhote had an idea of playing a game with her.He asked Shweta to count the number of bags whose individual weight is greater than or equal to the half of the total number of bags on the conveyor belt.Shweta got stuck in the puzzle! Help Shweta. 

-----Input:-----
- First line will contain T$T$, number of testcases. Then the testcases follow. 
- Each testcase contains of a single line of input, one  integers N$N$.
- next line conatins N$N$ integers that represents weight of bag 

-----Output:-----
For each testcase, print required answer in new line .

-----Constraints-----
- 1≤T≤1000$1 \leq T \leq 1000$
- 1≤N≤105$1 \leq N \leq 10^5$
- 1≤weightofbag≤105$ 1\leq  weight of bag   \leq 10^5$ 

-----Sample Input:-----
1
4 
1 2 3 4

-----Sample Output:-----
3

```python

USER_FILENAME = "<user_code>"
import sys, json, builtins
import math, heapq, bisect, itertools, functools, collections, statistics, fractions, decimal, operator, array, random, re, string, os, pathlib
try:
    import resource as _res
except Exception:
    _res = None
from collections import Counter, defaultdict, deque, OrderedDict
from functools import lru_cache, reduce
from itertools import accumulate, permutations, combinations, product
from math import gcd, ceil, floor, sqrt
from decimal import Decimal
try:
    from typing import *
except Exception:
    pass
try:
    sys.setrecursionlimit(1_000_000)
except Exception:
    pass
try:
    import site as _site
    try:
        _sys_sites = _site.getsitepackages() if hasattr(_site, "getsitepackages") else []
        for _p in _sys_sites:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
    try:
        _usp = _site.getusersitepackages()
        if isinstance(_usp, str):
            _usp = [_usp]
        for _p in _usp:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
except Exception:
    pass

ns = {"__name__": "__main__"}
for _k, _v in list(globals().items()):
    if not _k.startswith("_"):
        ns[_k] = _v
_CODE = 'for _ in range(int(input())):\r\n  c = 0\r\n  n = int(input())\r\n  a = list(map(int,input().split()))\r\n  for i in range(len(a)):\r\n    if a[i] >= n//2:\r\n      c += 1\r\n  print(c)\r\n'
_co = compile(_CODE, USER_FILENAME, "exec")
exec(_co, ns, ns)

```

Measured memory_bytes: 13045
The MarkiT online virtual market startup wants to organize its grand opening in NIT Patna.
but they want maximum crowd for their inauguration. So the manager told  this  to Praveen a student in NITP who suggested them:
The first-year students come to campus  every x hour,
Second-year students come to campus every y hour,
Third-year students come to campus every z hour and 
Fourth-year is very busy so they don't come regularly.
So Praveen being very clever told him the no of times in n days he can have an audience of all year student (1st,2nd & 3rd) at max. So can you code what Praveen has done?

-----Input:-----
- First line will contain $T$, number of testcases. Then the testcases follow. 
- Each testcase contains of a 2 line of input, first line contain one  integers $N$ (No of Days). 
-Next line contain 3 space separated integer the  value of x y z

-----Output:-----
For each testcase, output in a single line answer the no of times audience consists of all year.

-----Constraints-----
- $1 \leq T \leq 1000$
- $1 \leq N \leq 10^8$
- $1 \leq x,y,z \leq 10^5$

-----Sample Input:-----
1
10
8 10 6

-----Sample Output:-----
2

-----EXPLANATION:-----
First favourable condition will come on 5th day and Second on 10th day.

```python

USER_FILENAME = "<user_code>"
import sys, json, builtins
import math, heapq, bisect, itertools, functools, collections, statistics, fractions, decimal, operator, array, random, re, string, os, pathlib
try:
    import resource as _res
except Exception:
    _res = None
from collections import Counter, defaultdict, deque, OrderedDict
from functools import lru_cache, reduce
from itertools import accumulate, permutations, combinations, product
from math import gcd, ceil, floor, sqrt
from decimal import Decimal
try:
    from typing import *
except Exception:
    pass
try:
    sys.setrecursionlimit(1_000_000)
except Exception:
    pass
try:
    import site as _site
    try:
        _sys_sites = _site.getsitepackages() if hasattr(_site, "getsitepackages") else []
        for _p in _sys_sites:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
    try:
        _usp = _site.getusersitepackages()
        if isinstance(_usp, str):
            _usp = [_usp]
        for _p in _usp:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
except Exception:
    pass

ns = {"__name__": "__main__"}
for _k, _v in list(globals().items()):
    if not _k.startswith("_"):
        ns[_k] = _v
_CODE = 't=int(input())\nn=[]\nl=[]\n\ndef gcd(a,b): \n if(b==0): \n  return a \n else: \n  return gcd(b,a%b)\n\nfor i in range(t):\n n.append(24*int(input()))\n k=input().split()\n l.append(k)\n\nfor i in range(t):\n a=l[i]\n a= [int(k) for k in a]\n a[0]=(a[0]*a[1])//gcd(a[0],a[1])\n a[0]=(a[0]*a[2])//gcd(a[0],a[2])\n\n j=a[0]\n print(n[i]//j)\n'
_co = compile(_CODE, USER_FILENAME, "exec")
exec(_co, ns, ns)

```

Measured memory_bytes: 13303
Leha is a bright mathematician. Today he is investigating whether an integer is divisible by some square number or not.
He has a positive integer X represented as a product of N integers a1, a2, .... aN. He has somehow figured out that there exists some integer P such that the number X is divisible by P2, but he is not able to find such P himself. Can you find it for him? If there are more than one possible values of P possible, you can print any one of them.

-----Input-----
The first line of the input contains an integer T denoting the number of test cases. T test cases follow.
The first line of each test case contains one integer N denoting the number of intgers in presentation of X.
The second line contains N space-separated integers a1, a2, .... aN.

-----Output-----
For each test case, output a single integer P deoting the answer for this test case. Note that P must be in range from 2 to 1018 inclusive. It's guaranteed that at least one answer exists. If there are more than one possible answers, print any.

-----Constraints-----
- 1 ≤ T ≤ 5
- 1 ≤ N ≤ 100
- 1 ≤ ai ≤ 1018

-----Subtasks-----
- Subtask 1[19 points]: 1 ≤ a1*a2*...*aN ≤ 106
- Subtask 2[22 points]: 1 ≤ a1*a2*...*aN ≤ 1012
- Subtask 3[23 points]: 1 ≤ ai ≤ 1012
- Subtask 4[36 points]: no additional constraints

-----Example-----
Input:
1
3
21 11 6

Output:
3

-----Explanation-----
Example case 1. X = 21 * 11 * 6 = 1386. It's divisible by 9 which is a square number, as 9 = 32. So P = 3.

```python

USER_FILENAME = "<user_code>"
import sys, json, builtins
import math, heapq, bisect, itertools, functools, collections, statistics, fractions, decimal, operator, array, random, re, string, os, pathlib
try:
    import resource as _res
except Exception:
    _res = None
from collections import Counter, defaultdict, deque, OrderedDict
from functools import lru_cache, reduce
from itertools import accumulate, permutations, combinations, product
from math import gcd, ceil, floor, sqrt
from decimal import Decimal
try:
    from typing import *
except Exception:
    pass
try:
    sys.setrecursionlimit(1_000_000)
except Exception:
    pass
try:
    import site as _site
    try:
        _sys_sites = _site.getsitepackages() if hasattr(_site, "getsitepackages") else []
        for _p in _sys_sites:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
    try:
        _usp = _site.getusersitepackages()
        if isinstance(_usp, str):
            _usp = [_usp]
        for _p in _usp:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
except Exception:
    pass

ns = {"__name__": "__main__"}
for _k, _v in list(globals().items()):
    if not _k.startswith("_"):
        ns[_k] = _v
_CODE = 'import sys\nimport math\nr=int(input())\nfor v in range (0,r):\n n = int(input())\n x=1\n arr=list(map(int,input().strip().split(" ")))\n for i in range (0,n):\n  x=x*arr[i]\n  \n for i in range (2,100000000):\n  if(x%(pow(i,2))==0):\n   ans1=i\n   break\n \n \n print(ans1) \n'
_co = compile(_CODE, USER_FILENAME, "exec")
exec(_co, ns, ns)

```

Measured memory_bytes: 13155
Being a crewmate in the Among Us game, you will have to solve a task to win against the imposter. 
The task : You are given a certain number of bulbs(Say n) which are initially in OFF position. 
The bulbs are numbered from 1 to n. There will be n current fluctuations in such a way that in the 1st fluctuation all bulbs are toggled, in the 2nd fluctuation every 2nd bulb is toggled, in the 3rd fluctuation every 3rd bulb is toggled and so on.
Your job as a crewmate is to find the number of bulbs which are ON at the end of n fluctuations. But, the imposter has a special power which alerts it when a bulb with a number divisible by 3 is kept ON at the end of n fluctuations. 
So, you will have to switch off the bulbs with numbers divisible by 3 and give the final result to complete the task and win the game.

-----Input:-----
- First line will contain $T$, number of testcases. Then the testcases follow. 
- Each testcase contains of a single line of input, an integer $n$. 

-----Output:-----
- For each testcase, output a single integer - the number of bulbs that will remain ON after $n$ fluctuations.

-----Constraints :-----
- $1 \leq T \leq 1000$
- $2 \leq n \leq 10^9$

-----Sample Input:-----
2
2
20

-----Sample Output:-----
1

3

```python

USER_FILENAME = "<user_code>"
import sys, json, builtins
import math, heapq, bisect, itertools, functools, collections, statistics, fractions, decimal, operator, array, random, re, string, os, pathlib
try:
    import resource as _res
except Exception:
    _res = None
from collections import Counter, defaultdict, deque, OrderedDict
from functools import lru_cache, reduce
from itertools import accumulate, permutations, combinations, product
from math import gcd, ceil, floor, sqrt
from decimal import Decimal
try:
    from typing import *
except Exception:
    pass
try:
    sys.setrecursionlimit(1_000_000)
except Exception:
    pass
try:
    import site as _site
    try:
        _sys_sites = _site.getsitepackages() if hasattr(_site, "getsitepackages") else []
        for _p in _sys_sites:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
    try:
        _usp = _site.getusersitepackages()
        if isinstance(_usp, str):
            _usp = [_usp]
        for _p in _usp:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
except Exception:
    pass

ns = {"__name__": "__main__"}
for _k, _v in list(globals().items()):
    if not _k.startswith("_"):
        ns[_k] = _v
_CODE = 'l = []\nfor x in range(1,100000):\n    if x%3!=0:\n        l.append(x**2)\nfor _ in range(int(input())):\n    n = int(input())\n    c = 0\n    for x in l:\n        if x<=n:\n            c+=1\n        else:\n            break\n    print(c)'
_co = compile(_CODE, USER_FILENAME, "exec")
exec(_co, ns, ns)

```

Measured memory_bytes: 2708495
We have a permutation of the integers from 1 through N, p_1, p_2, .., p_N.
We also have M pairs of two integers between 1 and N (inclusive), represented as (x_1,y_1), (x_2,y_2), .., (x_M,y_M).
AtCoDeer the deer is going to perform the following operation on p as many times as desired so that the number of i (1 ≤ i ≤ N) such that p_i = i is maximized:
 - Choose j such that 1 ≤ j ≤ M, and swap p_{x_j} and p_{y_j}.
Find the maximum possible number of i such that p_i = i after operations.

-----Constraints-----
 - 2 ≤ N ≤ 10^5
 - 1 ≤ M ≤ 10^5
 - p is a permutation of integers from 1 through N.
 - 1 ≤ x_j,y_j ≤ N
 - x_j ≠ y_j
 - If i ≠ j, \{x_i,y_i\} ≠ \{x_j,y_j\}.
 - All values in input are integers.

-----Input-----
Input is given from Standard Input in the following format:
N M
p_1 p_2 .. p_N
x_1 y_1
x_2 y_2
:
x_M y_M

-----Output-----
Print the maximum possible number of i such that p_i = i after operations.

-----Sample Input-----
5 2
5 3 1 4 2
1 3
5 4

-----Sample Output-----
2

If we perform the operation by choosing j=1, p becomes 1 3 5 4 2, which is optimal, so the answer is 2.

```python

USER_FILENAME = "<user_code>"
import sys, json, builtins
import math, heapq, bisect, itertools, functools, collections, statistics, fractions, decimal, operator, array, random, re, string, os, pathlib
try:
    import resource as _res
except Exception:
    _res = None
from collections import Counter, defaultdict, deque, OrderedDict
from functools import lru_cache, reduce
from itertools import accumulate, permutations, combinations, product
from math import gcd, ceil, floor, sqrt
from decimal import Decimal
try:
    from typing import *
except Exception:
    pass
try:
    sys.setrecursionlimit(1_000_000)
except Exception:
    pass
try:
    import site as _site
    try:
        _sys_sites = _site.getsitepackages() if hasattr(_site, "getsitepackages") else []
        for _p in _sys_sites:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
    try:
        _usp = _site.getusersitepackages()
        if isinstance(_usp, str):
            _usp = [_usp]
        for _p in _usp:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
except Exception:
    pass

ns = {"__name__": "__main__"}
for _k, _v in list(globals().items()):
    if not _k.startswith("_"):
        ns[_k] = _v
_CODE = 'n,m= map(int,input().split())\npar = [-1]*(n)\ndef find(x):\n    if par[x]<0:return x\n    else:\n        par[x]=find(par[x])\n        return par[x]\ndef unite(x,y):\n    px,py=find(x),find(y)\n    if px==py:return False\n    else:\n        if px<py:px,py=py,px\n        par[px]+=par[py]\n        par[py]=px\n        return True\np= list(map(int,input().split()))\ngl=[[] for _ in range(n)]\nfor i in range(m):\n    x,y= map(int,input().split())\n    unite(x-1,y-1)\nfor c in range(n):#par:\n    ap=find(c)\n    gl[ap].append(c)\ng=0\nfor sg in gl:\n    temp=[p[index]-1 for index in sg]\n    newset = set(sg) & set(temp)\n    g+=len(newset)\nprint(g)'
_co = compile(_CODE, USER_FILENAME, "exec")
exec(_co, ns, ns)

```

Measured memory_bytes: 13357
Soma is a fashionable girl. She absolutely loves shiny stones that she can put on as jewellery accessories. She has been collecting stones since her childhood - now she has become really good with identifying which ones are fake and which ones are not.  Her King requested for her help in mining precious stones, so she has told him which all stones are jewels and which are not. Given her description, your task is  to count the number of jewel stones. 

More formally, you're given a string J composed of latin characters where each character is a jewel. You're also given a string S composed of latin characters where each character is a mined stone. You have to find out how many characters of S are in J as well. 

-----Input-----

First line contains an integer T denoting the number of test cases. Then follow T test cases. Each test case consists of two lines, each of which contains a string composed of English lower case and upper characters. First of these is the jewel string J and the second one is stone string S. 
You can assume that  1 <= T <= 100, 1 <= |J|, |S| <= 100


-----Output-----
Output for each test case, a single integer, the number of jewels mined. 

-----Example-----
Input:
4
abc
abcdef
aA
abAZ
aaa
a
what
none

Output:
3
2
1
0

```python

USER_FILENAME = "<user_code>"
import sys, json, builtins
import math, heapq, bisect, itertools, functools, collections, statistics, fractions, decimal, operator, array, random, re, string, os, pathlib
try:
    import resource as _res
except Exception:
    _res = None
from collections import Counter, defaultdict, deque, OrderedDict
from functools import lru_cache, reduce
from itertools import accumulate, permutations, combinations, product
from math import gcd, ceil, floor, sqrt
from decimal import Decimal
try:
    from typing import *
except Exception:
    pass
try:
    sys.setrecursionlimit(1_000_000)
except Exception:
    pass
try:
    import site as _site
    try:
        _sys_sites = _site.getsitepackages() if hasattr(_site, "getsitepackages") else []
        for _p in _sys_sites:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
    try:
        _usp = _site.getusersitepackages()
        if isinstance(_usp, str):
            _usp = [_usp]
        for _p in _usp:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
except Exception:
    pass

ns = {"__name__": "__main__"}
for _k, _v in list(globals().items()):
    if not _k.startswith("_"):
        ns[_k] = _v
_CODE = 'n = int(input())\nfor i in range(n):\n count = 0\n k = input()\n x = list(k)\n kk = input()\n y = list(kk)\n for j in y:\n  for jj in x:\n   if(j==jj):\n    count = count+1\n    break\n print(count)'
_co = compile(_CODE, USER_FILENAME, "exec")
exec(_co, ns, ns)

```

Measured memory_bytes: 12937
There is an integer sequence of length 2^N: A_0, A_1, ..., A_{2^N-1}. (Note that the sequence is 0-indexed.)
For every integer K satisfying 1 \leq K \leq 2^N-1, solve the following problem:
 - Let i and j be integers. Find the maximum value of A_i + A_j where 0 \leq i < j \leq 2^N-1 and (i or j) \leq K.
Here, or denotes the bitwise OR.

-----Constraints-----
 - 1 \leq N \leq 18
 - 1 \leq A_i \leq 10^9
 - All values in input are integers.

-----Input-----
Input is given from Standard Input in the following format:
N
A_0 A_1 ... A_{2^N-1}

-----Output-----
Print 2^N-1 lines.
In the i-th line, print the answer of the problem above for K=i.

-----Sample Input-----
2
1 2 3 1

-----Sample Output-----
3
4
5

For K=1, the only possible pair of i and j is (i,j)=(0,1), so the answer is A_0+A_1=1+2=3.
For K=2, the possible pairs of i and j are (i,j)=(0,1),(0,2).
When (i,j)=(0,2), A_i+A_j=1+3=4. This is the maximum value, so the answer is 4.
For K=3, the possible pairs of i and j are (i,j)=(0,1),(0,2),(0,3),(1,2),(1,3),(2,3) .
When (i,j)=(1,2), A_i+A_j=2+3=5. This is the maximum value, so the answer is 5.

```python

USER_FILENAME = "<user_code>"
import sys, json, builtins
import math, heapq, bisect, itertools, functools, collections, statistics, fractions, decimal, operator, array, random, re, string, os, pathlib
try:
    import resource as _res
except Exception:
    _res = None
from collections import Counter, defaultdict, deque, OrderedDict
from functools import lru_cache, reduce
from itertools import accumulate, permutations, combinations, product
from math import gcd, ceil, floor, sqrt
from decimal import Decimal
try:
    from typing import *
except Exception:
    pass
try:
    sys.setrecursionlimit(1_000_000)
except Exception:
    pass
try:
    import site as _site
    try:
        _sys_sites = _site.getsitepackages() if hasattr(_site, "getsitepackages") else []
        for _p in _sys_sites:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
    try:
        _usp = _site.getusersitepackages()
        if isinstance(_usp, str):
            _usp = [_usp]
        for _p in _usp:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
except Exception:
    pass

ns = {"__name__": "__main__"}
for _k, _v in list(globals().items()):
    if not _k.startswith("_"):
        ns[_k] = _v
_CODE = 'N,d=1<<int(input()),[[int(s)]for s in input().split()]\nr=N\nwhile r>1:\n\tr>>=1\n\tfor i in range(N):\n\t\tif i&r:d[i]=sorted(d[i^r]+d[i])[-2:]\nfor a,b in d[1:]:r=max(r,a+b);print(r)'
_co = compile(_CODE, USER_FILENAME, "exec")
exec(_co, ns, ns)

```

Measured memory_bytes: 13085
Chef is now a corporate person. He has to attend office regularly. But chef does not want to go to office, rather he wants to stay home and discover different recipes and cook them. 
In the office where chef works, has two guards who count how many times a person enters into the office building. Though the duty of a guard is 24 hour in a day, but sometimes they fall asleep during their duty and could not track the entry of a person in the office building. But one better thing is that they never fall asleep at the same time. At least one of them remains awake and counts who enters into the office.
Now boss of Chef wants to calculate how many times Chef has entered into the building. He asked to the guard and they give him two integers A and B, count of first guard and second guard respectively.
Help the boss to count the minimum and maximum number of times Chef could have entered into the office building.

-----Input-----
The first line of the input contains an integer T denoting the number of test cases. The description of the T test cases follows. 
Each test case consists of a line containing two space separated integers A and B.

-----Output-----
For each test case, output a single line containing two space separated integers, the minimum and maximum number of times Chef could have entered into the office building.

-----Constraints-----
- 1 ≤ T ≤ 100
- 0 ≤ A, B ≤ 1000000

-----Example-----
Input:
1
19 17

Output:
19 36

```python

USER_FILENAME = "<user_code>"
import sys, json, builtins
import math, heapq, bisect, itertools, functools, collections, statistics, fractions, decimal, operator, array, random, re, string, os, pathlib
try:
    import resource as _res
except Exception:
    _res = None
from collections import Counter, defaultdict, deque, OrderedDict
from functools import lru_cache, reduce
from itertools import accumulate, permutations, combinations, product
from math import gcd, ceil, floor, sqrt
from decimal import Decimal
try:
    from typing import *
except Exception:
    pass
try:
    sys.setrecursionlimit(1_000_000)
except Exception:
    pass
try:
    import site as _site
    try:
        _sys_sites = _site.getsitepackages() if hasattr(_site, "getsitepackages") else []
        for _p in _sys_sites:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
    try:
        _usp = _site.getusersitepackages()
        if isinstance(_usp, str):
            _usp = [_usp]
        for _p in _usp:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
except Exception:
    pass

ns = {"__name__": "__main__"}
for _k, _v in list(globals().items()):
    if not _k.startswith("_"):
        ns[_k] = _v
_CODE = '# cook your dish here\nfor i in range(int(input())):\n    a,b=map(int,input().split())\n    if(a>b):\n        print(a,a+b)\n    elif(b>a):\n        print(b,a+b)'
_co = compile(_CODE, USER_FILENAME, "exec")
exec(_co, ns, ns)

```

Measured memory_bytes: 12953
The Fibonacci sequence is defined as F(n) = F(n-1) + F(n-2). You have developed two sequences of numbers. The first sequence that uses the bitwise XOR operation instead of the addition method is called the Xoronacci number. It is described as follows:
X(n) = X(n-1) XOR X(n-2)
The second sequence that uses the bitwise XNOR operation instead of the addition method is called the XNoronacci number. It is described as follows:
E(n) = E(n-1) XNOR E(n-2)
The first and second numbers of the sequence are as follows:
X(1) = E(1) = a
X(2) = E(2) = b
Your task is to determine the value of max(X(n),E(n)), where n is the n th term of the Xoronacci and XNoronacci sequence.

-----Input:-----
The first line consists of a single integer T denoting the number of test cases.
The first and the only line of each test case consists of three space separated integers a, b and n.

-----Output:-----
For each test case print a single integer max(X(n),E(n)).

-----Constraints-----
- $1 \leq T \leq 1000$
- $2 \leq a,b,n \leq 1000000000000$

-----Sample Input:-----
1
3 4 2 

-----Sample Output:-----
4

-----EXPLANATION:-----
Xoronacci Sequence : 3 4 7 …….
XNoronacci Sequence : 3 4 0 …….
Here n = 2. Hence max(X(2),E(2)) = 4

```python

USER_FILENAME = "<user_code>"
import sys, json, builtins
import math, heapq, bisect, itertools, functools, collections, statistics, fractions, decimal, operator, array, random, re, string, os, pathlib
try:
    import resource as _res
except Exception:
    _res = None
from collections import Counter, defaultdict, deque, OrderedDict
from functools import lru_cache, reduce
from itertools import accumulate, permutations, combinations, product
from math import gcd, ceil, floor, sqrt
from decimal import Decimal
try:
    from typing import *
except Exception:
    pass
try:
    sys.setrecursionlimit(1_000_000)
except Exception:
    pass
try:
    import site as _site
    try:
        _sys_sites = _site.getsitepackages() if hasattr(_site, "getsitepackages") else []
        for _p in _sys_sites:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
    try:
        _usp = _site.getusersitepackages()
        if isinstance(_usp, str):
            _usp = [_usp]
        for _p in _usp:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
except Exception:
    pass

ns = {"__name__": "__main__"}
for _k, _v in list(globals().items()):
    if not _k.startswith("_"):
        ns[_k] = _v
_CODE = 'def xnor(a, b):\n if a == 0:\n  return 1 ^ b \n p = a\n a = a|(a>>1)\n a = a|(a>>2)\n a = a|(a>>4)\n a = a|(a>>8)\n a = a|(a>>16)\n a = a|(a>>32)\n a = a|(a>>64) \n return (a ^ p) ^ b\ndef solve():\n a, b, n = list(map(int, input().split()))\n n -= 1\n index = n % 3\n if index == 0:\n  print(a)\n elif index == 1:\n  print(b)\n else:\n  x = a ^ b\n  e = xnor(max(a, b), min(a, b))\n  print(max(x, e))\n\nfor _ in range(int(input())):\n solve()\n'
_co = compile(_CODE, USER_FILENAME, "exec")
exec(_co, ns, ns)

```

Measured memory_bytes: 13121
You are given a set of n pens, each of them can be red, blue, green, orange, and violet in color. Count a minimum number of pens that should be taken out from the set so that any two neighboring pens have different colors. Pens are considered to be neighboring if there are no other pens between them.

-----Input:-----
- 
The first line contains t denoting the number of test cases.
- 
The first line of each test case will contain a single integer n.
- 
The second line of each test case will contain a string s.
(s contains only 'R', 'B', 'G', 'O', and 'V' characters denoting red, blue, green, orange, and violet respectively)

-----Output:-----
For each test case, print single line containing one integer - The minimum number of pens that need to be taken out.

-----Constraints-----
- $1 \leq T \leq 100$
- $1 \leq n \leq 1000$

-----Sample Input:-----
2
5
RBBRG
5
RBGOV

-----Sample Output:-----
1
0

-----EXPLANATION:-----
In first test case, two blue pens are neighboring each other, if we take out any one of them then the string will be RBRG in which each pen has different neighbors.
In second test case, no pen needs to be taken out as each pen has different neighbors.

```python

USER_FILENAME = "<user_code>"
import sys, json, builtins
import math, heapq, bisect, itertools, functools, collections, statistics, fractions, decimal, operator, array, random, re, string, os, pathlib
try:
    import resource as _res
except Exception:
    _res = None
from collections import Counter, defaultdict, deque, OrderedDict
from functools import lru_cache, reduce
from itertools import accumulate, permutations, combinations, product
from math import gcd, ceil, floor, sqrt
from decimal import Decimal
try:
    from typing import *
except Exception:
    pass
try:
    sys.setrecursionlimit(1_000_000)
except Exception:
    pass
try:
    import site as _site
    try:
        _sys_sites = _site.getsitepackages() if hasattr(_site, "getsitepackages") else []
        for _p in _sys_sites:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
    try:
        _usp = _site.getusersitepackages()
        if isinstance(_usp, str):
            _usp = [_usp]
        for _p in _usp:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
except Exception:
    pass

ns = {"__name__": "__main__"}
for _k, _v in list(globals().items()):
    if not _k.startswith("_"):
        ns[_k] = _v
_CODE = '# cook your dish here\ntc=int(input())\nfor t in range(tc):\n    n=int(input())\n    st=input()\n    c=0\n    for i in range(1,n):\n        if st[i]==st[i-1]:\n            i+=1\n            c+=1\n    print(c)'
_co = compile(_CODE, USER_FILENAME, "exec")
exec(_co, ns, ns)

```

Measured memory_bytes: 12965