You are given a binary string $s$ consisting of $n$ zeros and ones.

Your task is to divide the given string into the minimum number of subsequences in such a way that each character of the string belongs to exactly one subsequence and each subsequence looks like "010101 ..." or "101010 ..." (i.e. the subsequence should not contain two adjacent zeros or ones).

Recall that a subsequence is a sequence that can be derived from the given sequence by deleting zero or more elements without changing the order of the remaining elements. For example, subsequences of "1011101" are "0", "1", "11111", "0111", "101", "1001", but not "000", "101010" and "11100".

You have to answer $t$ independent test cases.


-----Input-----

The first line of the input contains one integer $t$ ($1 \le t \le 2 \cdot 10^4$) — the number of test cases. Then $t$ test cases follow.

The first line of the test case contains one integer $n$ ($1 \le n \le 2 \cdot 10^5$) — the length of $s$. The second line of the test case contains $n$ characters '0' and '1' — the string $s$.

It is guaranteed that the sum of $n$ does not exceed $2 \cdot 10^5$ ($\sum n \le 2 \cdot 10^5$).


-----Output-----

For each test case, print the answer: in the first line print one integer $k$ ($1 \le k \le n$) — the minimum number of subsequences you can divide the string $s$ to. In the second line print $n$ integers $a_1, a_2, \dots, a_n$ ($1 \le a_i \le k$), where $a_i$ is the number of subsequence the $i$-th character of $s$ belongs to.

If there are several answers, you can print any.


-----Example-----
Input
4
4
0011
6
111111
5
10101
8
01010000

Output
2
1 2 2 1 
6
1 2 3 4 5 6 
1
1 1 1 1 1 
4
1 1 1 1 1 2 3 4

```python

USER_FILENAME = "<user_code>"
import sys, json, builtins
import math, heapq, bisect, itertools, functools, collections, statistics, fractions, decimal, operator, array, random, re, string, os, pathlib
try:
    import resource as _res
except Exception:
    _res = None
from collections import Counter, defaultdict, deque, OrderedDict
from functools import lru_cache, reduce
from itertools import accumulate, permutations, combinations, product
from math import gcd, ceil, floor, sqrt
from decimal import Decimal
try:
    from typing import *
except Exception:
    pass
try:
    sys.setrecursionlimit(1_000_000)
except Exception:
    pass
try:
    import site as _site
    try:
        _sys_sites = _site.getsitepackages() if hasattr(_site, "getsitepackages") else []
        for _p in _sys_sites:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
    try:
        _usp = _site.getusersitepackages()
        if isinstance(_usp, str):
            _usp = [_usp]
        for _p in _usp:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
except Exception:
    pass

ns = {"__name__": "__main__"}
for _k, _v in list(globals().items()):
    if not _k.startswith("_"):
        ns[_k] = _v
_CODE = "from bisect import bisect_left as bl\nfrom bisect import bisect_right as br\nfrom heapq import heappush,heappop,heapify\nimport math\nfrom collections import *\nfrom functools import reduce,cmp_to_key\nimport sys\ninput = sys.stdin.readline\n\nfrom itertools import accumulate\n\nM = mod = 998244353\ndef factors(n):return sorted(set(reduce(list.__add__, ([i, n//i] for i in range(1, int(n**0.5) + 1) if n % i == 0))))\ndef inv_mod(n):return pow(n, mod - 2, mod)\n \ndef li():return [int(i) for i in input().rstrip('\\n').split()]\ndef st():return input().rstrip('\\n')\ndef val():return int(input().rstrip('\\n'))\ndef li2():return [i for i in input().rstrip('\\n')]\ndef li3():return [int(i) for i in input().rstrip('\\n')]\n\n\nfor _ in range(val()):\n    n = val()\n    l = li3()\n\n    d = defaultdict(list)\n    ans = {}\n    curr = 1\n    for i in range(n):\n        if len(d[1 - l[i]]):\n            d[l[i]].append(d[1 - l[i]].pop())\n            ans[i] = d[l[i]][-1]\n        else:\n            d[l[i]].append(curr)\n            ans[i] = curr\n            curr += 1\n    print(curr - 1)\n    for i in range(n):\n        print(ans[i], end = ' ')\n    print()"
_co = compile(_CODE, USER_FILENAME, "exec")
exec(_co, ns, ns)

```

Measured memory_bytes: 15427