Recently, Chef studied the binary numeral system and noticed that it is extremely simple to perform bitwise operations like AND, XOR or bit shift on non-negative integers, while it is much more complicated to perform arithmetic operations (e.g. addition, multiplication or division).
After playing with binary operations for a while, Chef invented an interesting algorithm for addition of two non-negative integers $A$ and $B$:
function add(A, B):
while B is greater than 0:
U = A XOR B
V = A AND B
A = U
B = V * 2
return A

Now Chef is wondering how fast this algorithm is. Given the initial values of $A$ and $B$ (in binary representation), he needs you to help him compute the number of times the while-loop of the algorithm is repeated.

-----Input-----
- The first line of the input contains a single integer $T$ denoting the number of test cases. The description of $T$ test cases follows.
- The first line of each test case contains a single string $A$.
- The second line contains a single string $B$.

-----Output-----
For each test case, print a single line containing one integer ― the number of iterations the algorithm will perform during addition of the given numbers $A$ and $B$.

-----Constraints-----
- $1 \le T \le 10^5$
- $1 \le |A|, |B| \le 10^5$
- $A$ and $B$ contain only characters '0' and '1'
- the sum of $|A| + |B|$ over all test cases does not exceed $10^6$

-----Subtasks-----
Subtask #1 (20 points): $|A|, |B| \le 30$
Subtask #2 (30 points):
- $|A|, |B| \le 500$
- the sum of $|A| + |B|$ over all test cases does not exceed $10^5$
Subtask #3 (50 points): original constraints

-----Example Input-----
3
100010
0
0
100010
11100
1010

-----Example Output-----
0
1
3

-----Explanation-----
Example case 1: The initial value of $B$ is $0$, so while-loop is not performed at all.
Example case 2: The initial values of $A$ and $B$ are $0_2 = 0$ and $100010_2 = 34$ respectively. When the while-loop is performed for the first time, we have:
- $U = 34$
- $V = 0$
- $A$ changes to $34$
- $B$ changes to $2 \cdot 0 = 0$
The while-loop terminates immediately afterwards, so it is executed only once.
Example case 3: The initial values of $A$ and $B$ are $11100_2 = 28$ and $1010_2 = 10$ respectively. After the first iteration, their values change to $22$ and $16$ respectively. After the second iteration, they change to $6$ and $32$, and finally, after the third iteration, to $38$ and $0$.

```python

USER_FILENAME = "<user_code>"
import sys, json, builtins
import math, heapq, bisect, itertools, functools, collections, statistics, fractions, decimal, operator, array, random, re, string, os, pathlib
try:
    import resource as _res
except Exception:
    _res = None
from collections import Counter, defaultdict, deque, OrderedDict
from functools import lru_cache, reduce
from itertools import accumulate, permutations, combinations, product
from math import gcd, ceil, floor, sqrt
from decimal import Decimal
try:
    from typing import *
except Exception:
    pass
try:
    sys.setrecursionlimit(1_000_000)
except Exception:
    pass
try:
    import site as _site
    try:
        _sys_sites = _site.getsitepackages() if hasattr(_site, "getsitepackages") else []
        for _p in _sys_sites:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
    try:
        _usp = _site.getusersitepackages()
        if isinstance(_usp, str):
            _usp = [_usp]
        for _p in _usp:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
except Exception:
    pass

ns = {"__name__": "__main__"}
for _k, _v in list(globals().items()):
    if not _k.startswith("_"):
        ns[_k] = _v
_CODE = 'def loji_hogya(a,b):\n count=0\n while(b>0):\n  u = a^b\n  v = a&b\n  a = u\n  b = v*2\n  count = count+1\n return count\nn=int(input())\nwhile(n!=0):\n a=input()\n b=input()\n a=int(a,2)\n b=int(b,2)\n print(loji_hogya((a),(b)))\n n = n-1\n'
_co = compile(_CODE, USER_FILENAME, "exec")
exec(_co, ns, ns)

```

Measured memory_bytes: 13087