Recently, you found a bot to play "Rock paper scissors" with. Unfortunately, the bot uses quite a simple algorithm to play: he has a string $s = s_1 s_2 \dots s_{n}$ of length $n$ where each letter is either R, S or P.

While initializing, the bot is choosing a starting index $pos$ ($1 \le pos \le n$), and then it can play any number of rounds. In the first round, he chooses "Rock", "Scissors" or "Paper" based on the value of $s_{pos}$:   if $s_{pos}$ is equal to R the bot chooses "Rock";  if $s_{pos}$ is equal to S the bot chooses "Scissors";  if $s_{pos}$ is equal to P the bot chooses "Paper"; 

In the second round, the bot's choice is based on the value of $s_{pos + 1}$. In the third round — on $s_{pos + 2}$ and so on. After $s_n$ the bot returns to $s_1$ and continues his game.

You plan to play $n$ rounds and you've already figured out the string $s$ but still don't know what is the starting index $pos$. But since the bot's tactic is so boring, you've decided to find $n$ choices to each round to maximize the average number of wins.

In other words, let's suggest your choices are $c_1 c_2 \dots c_n$ and if the bot starts from index $pos$ then you'll win in $win(pos)$ rounds. Find $c_1 c_2 \dots c_n$ such that $\frac{win(1) + win(2) + \dots + win(n)}{n}$ is maximum possible.


-----Input-----

The first line contains a single integer $t$ ($1 \le t \le 1000$) — the number of test cases.

Next $t$ lines contain test cases — one per line. The first and only line of each test case contains string $s = s_1 s_2 \dots s_{n}$ ($1 \le n \le 2 \cdot 10^5$; $s_i \in \{\text{R}, \text{S}, \text{P}\}$) — the string of the bot.

It's guaranteed that the total length of all strings in one test doesn't exceed $2 \cdot 10^5$.


-----Output-----

For each test case, print $n$ choices $c_1 c_2 \dots c_n$ to maximize the average number of wins. Print them in the same manner as the string $s$.

If there are multiple optimal answers, print any of them.


-----Example-----
Input
3
RRRR
RSP
S

Output
PPPP
RSP
R


-----Note-----

In the first test case, the bot (wherever it starts) will always choose "Rock", so we can always choose "Paper". So, in any case, we will win all $n = 4$ rounds, so the average is also equal to $4$.

In the second test case:   if bot will start from $pos = 1$, then $(s_1, c_1)$ is draw, $(s_2, c_2)$ is draw and $(s_3, c_3)$ is draw, so $win(1) = 0$;  if bot will start from $pos = 2$, then $(s_2, c_1)$ is win, $(s_3, c_2)$ is win and $(s_1, c_3)$ is win, so $win(2) = 3$;  if bot will start from $pos = 3$, then $(s_3, c_1)$ is lose, $(s_1, c_2)$ is lose and $(s_2, c_3)$ is lose, so $win(3) = 0$;  The average is equal to $\frac{0 + 3 + 0}{3} = 1$ and it can be proven that it's the maximum possible average.

A picture from Wikipedia explaining "Rock paper scissors" game:  $\beta$

```python

USER_FILENAME = "<user_code>"
import sys, json, builtins
import math, heapq, bisect, itertools, functools, collections, statistics, fractions, decimal, operator, array, random, re, string, os, pathlib
try:
    import resource as _res
except Exception:
    _res = None
from collections import Counter, defaultdict, deque, OrderedDict
from functools import lru_cache, reduce
from itertools import accumulate, permutations, combinations, product
from math import gcd, ceil, floor, sqrt
from decimal import Decimal
try:
    from typing import *
except Exception:
    pass
try:
    sys.setrecursionlimit(1_000_000)
except Exception:
    pass
try:
    import site as _site
    try:
        _sys_sites = _site.getsitepackages() if hasattr(_site, "getsitepackages") else []
        for _p in _sys_sites:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
    try:
        _usp = _site.getusersitepackages()
        if isinstance(_usp, str):
            _usp = [_usp]
        for _p in _usp:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
except Exception:
    pass

ns = {"__name__": "__main__"}
for _k, _v in list(globals().items()):
    if not _k.startswith("_"):
        ns[_k] = _v
_CODE = "# import sys\nfrom collections import Counter\n# input = sys.stdin.readline\n\n# T = int(input())\n\n# for t in range(T):\n#     s = input()\n#     pos = set(range(len(s)))\n\n#     answer = ['']\n\n#     for i in range(len(s)):\n#         lets = [s[k] for k in pos]\n#         if not pos:\n#             break\n#         cc = Counter(lets)\n#         fl = cc.most_common()[0][0]\n#         choice = ''\n#         if fl == 'R':\n#             choice = 'P'\n#         elif fl == 'S':\n#             choice = 'R'\n#         else:\n#             choice = 'S'\n#         answer.append(choice)\n#         next_pos = set()\n#         for p in pos:\n#             if s[p] == choice:\n#                 np = p+1\n#                 if np >= len(s):\n#                     np = 0\n#                 next_pos.add(np)\n#         pos = next_pos\n\n#     while len(answer) < len(s):\n#         answer.append('R')\n\n#     print(''.join(answer))\n\nT = int(input())\n\nfor t in range(T):\n    s = input()\n    cc = Counter(s)\n    fl = cc.most_common()[0][0]\n    if fl == 'R':\n        choice = 'P'\n    elif fl == 'S':\n        choice = 'R'\n    else:\n        choice = 'S'\n    print(choice*len(s))\n"
_co = compile(_CODE, USER_FILENAME, "exec")
exec(_co, ns, ns)

```

Measured memory_bytes: 13535