#include <bits/stdc++.h>
#define rep(i,n) for(ll i=0;i<(n);i++)
#define rrep(i,n) for(ll i = 1; i <= (n); ++i)
#define drep(i,n) for(ll i = (n)-1; i >= 0; --i)
#define all(v) v.begin(),v.end()
#define len(x) (ll)(x).length()
#define maxs(x,y) x = max(x,y)
#define mins(x,y) x = min(x,y)
#define pb push_back
#define sz(x) (ll)(x).size()
#define v(T) vector<T>
#define vv(T) vector<vector<T>>
using namespace std;
typedef long long ll;
typedef pair<ll,ll> P;
typedef vector<int> vi;
typedef vector<vi> vvi;
typedef vector<ll> vl;
typedef vector<P> vp;
ll gcd(ll a,ll b){if(a%b==0){return b;}else{return(gcd(b,a%b));}}
ll lcm(ll a,ll b){return a/gcd(a,b)*b;}
const int INF=1e9;
const ll MX = 1e18;
const ll MOD=INF+7;
const ll mod=998244353;
const int di[] = {-1,0,1,0};
const int dj[] = {0,-1,0,1};
const double PI=acos(-1);
const string tr="abcdefghijklmnopqrstuvwxyz";
#define dame { puts("-1"); return 0;}
#define yn {puts("Yes");}else{puts("No");}
#define YN {puts("YES");}else{puts("NO");}
const ll MAX = 1000001;
long long fac[MAX], finv[MAX], inv[MAX];
void COMinit() {fac[0] = fac[1] = 1;finv[0] = finv[1] = 1;inv[1] = 1;for (ll i = 2; i < MAX; i++){fac[i] = fac[i - 1] * i % MOD;inv[i] = MOD - inv[MOD%i] * (MOD / i) % MOD;finv[i] = finv[i - 1] * inv[i] % MOD;}}
long long COM(ll n, ll k){if (n < k) return 0;if (n < 0 || k < 0) return 0;return fac[n] * (finv[k] * finv[n - k] % MOD) % MOD;}
ll llpow(ll n,ll i){ll cnt=n;  for(ll j=0;j<i-1;j++){n*=cnt;}return n;}
bool ip/*is_prime*/(long long N) {if (N == 1) return false;for (long long i = 2; i * i <= N; ++i) {if (N % i == 0) return false;}return true;}
int digit(ll N) {int ans = 0;while (N) {++ans;N /= 10;}return ans;}
vector<pair<ll,ll>> pf/*prime_factorize*/(ll n){vector<pair<ll,ll>> res;for(ll a=2;a*a<=n;a++){if(n%a!=0) continue;ll ex=0;while(n%a==0){ex++;n/=a;}res.pb({a,ex});}if(n!=1) res.pb({n,1});return res;}
vector<ll> div/*divisor*/(ll n){  vector<ll> res={1};for(ll a=2;a*a<=n;a++){if(n%a!=0) continue;ll b=n/a;res.pb(b);if(b!=a) res.pb(a);}sort(all(res));return res;}
struct mint {
  ll x; // typedef long long ll;
  mint(ll x=0):x((x%mod+mod)%mod){}
  mint operator-() const { return mint(-x);}
  mint& operator+=(const mint a) {
    if ((x += a.x) >= mod) x -= mod;
    return *this;
  }
  mint& operator-=(const mint a) {
    if ((x += mod-a.x) >= mod) x -= mod;
    return *this;
  }
  mint& operator*=(const mint a) { (x *= a.x) %= mod; return *this;}
  mint operator+(const mint a) const { return mint(*this) += a;}
  mint operator-(const mint a) const { return mint(*this) -= a;}
  mint operator*(const mint a) const { return mint(*this) *= a;}
  mint pow(ll t) const {
    if (!t) return 1;
    mint a = pow(t>>1);
    a *= a;
    if (t&1) a *= *this;
    return a;
  }
 
  // for prime mod
  mint inv() const { return pow(mod-2);}
  mint& operator/=(const mint a) { return *this *= a.inv();}
  mint operator/(const mint a) const { return mint(*this) /= a;}
};
istream& operator>>(istream& is, const mint& a) { return is >> a.x;}
ostream& operator<<(ostream& os, const mint& a) { return os << a.x;}
struct combination {
  vector<mint> fact, ifact;
  combination(int n):fact(n+1),ifact(n+1) {
    assert(n < mod);
    fact[0] = 1;
    for (int i = 1; i <= n; ++i) fact[i] = fact[i-1]*i;
    ifact[n] = fact[n].inv();
    for (int i = n; i >= 1; --i) ifact[i-1] = ifact[i]*i;
  }
  mint operator()(int n, int k) {
    if (k < 0 || k > n) return 0;
    return fact[n]*ifact[k]*ifact[n-k];
  }
} c(200005);

int main() {
  int n, m, k;
  cin >> n >> m >> k;
 
  mint ans = 0;
  mint col = m;
  for (int x = n-1; x >= 0; --x) {
    mint now = col;
    now *= c(n-1,x);
    if (x <= k) ans += now;
    col *= m-1;
  }
  cout << ans << endl;
  return 0;
}

Measured memory_bytes: 6256