#include <bits/stdc++.h>
#include <string>
#include <iostream>
#include <stdio.h>
#include <stdlib.h>
#include <bitset>
typedef long long ll;
using namespace std;
#define rep(i,n) for(int i=0;i<(n);i++)
 
const int mod = 1000000007;
//const int mod = 998244353;
 
 
struct mint {
  ll x; // typedef long long ll;
  mint(ll x=0):x((x%mod+mod)%mod){}
  mint operator-() const { return mint(-x);}
  mint& operator+=(const mint a) {
    if ((x += a.x) >= mod) x -= mod;
    return *this;
  }
  mint& operator-=(const mint a) {
    if ((x += mod-a.x) >= mod) x -= mod;
    return *this;
  }
  mint& operator*=(const mint a) { (x *= a.x) %= mod; return *this;}
  mint operator+(const mint a) const { return mint(*this) += a;}
  mint operator-(const mint a) const { return mint(*this) -= a;}
  mint operator*(const mint a) const { return mint(*this) *= a;}
  mint pow(ll t) const {
    if (!t) return 1;
    mint a = pow(t>>1);
    a *= a;
    if (t&1) a *= *this;
    return a;
  }
 
  // for prime mod
  mint inv() const { return pow(mod-2);}
  mint& operator/=(const mint a) { return *this *= a.inv();}
  mint operator/(const mint a) const { return mint(*this) /= a;}
};
istream& operator>>(istream& is, const mint& a) { return is >> a.x;}
ostream& operator<<(ostream& os, const mint& a) { return os << a.x;}
 
 
struct combination {
  vector<mint> fact, ifact;
  combination(int n):fact(n+1),ifact(n+1) {
    assert(n < mod);
    fact[0] = 1;
    for (int i = 1; i <= n; ++i) fact[i] = fact[i-1]*i;
    ifact[n] = fact[n].inv();
    for (int i = n; i >= 1; --i) ifact[i-1] = ifact[i]*i;
  }
  mint operator()(int n, int k) {
    if (k < 0 || k > n) return 0;
    return fact[n]*ifact[k]*ifact[n-k];
  }
} c(200005);
 
vector<pair<long long, long long> > prime_factorize(long long N) {
    vector<pair<long long, long long> > res;
    for (long long a = 2; a * a <= N; ++a) {
        if (N % a != 0) continue;
        long long ex = 0; // 指数
 
        // 割れる限り割り続ける
        while (N % a == 0) {
            ++ex;
            N /= a;
        }
 
        // その結果を push
        res.push_back({a, ex});
    }
 
    // 最後に残った数について
    if (N != 1) res.push_back({N, 1});
    return res;
}
vector<long long> enum_divisors(long long N) {
    vector<long long> res;
    for (long long i = 1; i * i <= N; ++i) {
        if (N % i == 0) {
            res.push_back(i);
            // 重複しないならば i の相方である N/i も push
            if (N/i != i) res.push_back(N/i);
        }
    }
    // 小さい順に並び替える
    sort(res.begin(), res.end());
    return res;
}
 
int main(int argc, const char * argv[]) {
    
    ll sum=1,N; cin >> N;
    
    vector<ll> list26(12);
    vector<ll> list_sum(12);
    for(ll i=0;i<11;i++){
        sum *= 26;
        list26[i] = sum;
    }
    
    list_sum[0] = 1;
    for(ll i=0;i<11;i++){
        list_sum[i+1] = list_sum[i] + list26[i];
    }
    
    list_sum[11] = 1000000000000001;
        
    ll digit = 1;
    ll start_num = 1;
    for(ll i=10;i>=0;i--){
        if(N >= list_sum[i]){
            digit =  i;
            start_num = list_sum[i];
            break;
        }
    }
 
    ll x = N - start_num;
    
    
    vector<char> ans;
    
    while(digit>=1){
        ll syo = x / pow(26,digit);
        ans.push_back(syo+'a');
        x = x - syo * pow(26,digit);
        digit -= 1;
        
    }
    ans.push_back(x + 'a');
    
    for(ll i=0;i<ans.size();i++){
        cout << ans[i];
    }
    cout << endl;
    
    return 0;
}


Measured memory_bytes: 6260