#include<iostream>
#include<algorithm>
#include<vector>
#include<queue>
#include<stack>
#include<list>
#include<set>
#include<string>
using namespace std;
int gcd(int a, int b) {
	int c = a % b;
	while (c != 0) {
		a = b;
		b = c;
		c = a % b;
	}
	return b;
}
struct UnionFind {
	vector<int> par; // par[i]:iの親の番号　(例) par[3] = 2 : 3の親が2

	UnionFind(int N) : par(N) { //最初は全てが根であるとして初期化
		for (int i = 0; i < N; i++) par[i] = i;
	}

	int root(int x) { // データxが属する木の根を再帰で得る：root(x) = {xの木の根}
		if (par[x] == x) return x;
		return par[x] = root(par[x]);
	}

	void unite(int x, int y) { // xとyの木を併合
		int rx = root(x); //xの根をrx
		int ry = root(y); //yの根をry
		if (rx == ry) return; //xとyの根が同じ(=同じ木にある)時はそのまま
		par[rx] = ry; //xとyの根が同じでない(=同じ木にない)時：xの根rxをyの根ryにつける
	}

	bool same(int x, int y) { // 2つのデータx, yが属する木が同じならtrueを返す
		int rx = root(x);
		int ry = root(y);
		return rx == ry;
	}
};
typedef long long ll;

ll M = 1000000007;

vector<ll> fac(300001); //n!(mod M)
vector<ll> ifac(300001); //k!^{M-2} (mod M)

ll mpow(ll x, ll n) {
	ll ans = 1;
	while (n != 0) {
		if (n & 1) ans = ans * x % M;
		x = x * x % M;
		n = n >> 1;
	}
	return ans;
}
void setcomb() {
	fac[0] = 1;
	ifac[0] = 1;
	for (ll i = 0; i < 300000; i++) {
		fac[i + 1] = fac[i] * (i + 1) % M; // n!(mod M)
		ifac[i + 1] = ifac[i] * mpow(i + 1, M - 2) % M; // k!^{M-2} (mod M) ←累乗にmpowを採用
	}
}
ll comb(ll a, ll b) {
	if (a == 0 && b == 0)return 1;
	if (a < b || a < 0)return 0;
	ll tmp = ifac[a - b] * ifac[b] % M;
	return tmp * fac[a] % M;
}
ll perm(ll a, ll b) {
	if (a == 0 && b == 0)return 1;
	if (a < b || a < 0)return 0;
	return fac[a] * ifac[a - b] % M;
}
// mod. m での a の逆元 a^{-1} を計算する
long long modinv(long long a) {
	long long b = M, u = 1, v = 0;
	while (b) {
		long long t = a / b;
		a -= t * b; swap(a, b);
		u -= t * v; swap(u, v);
	}
	u %= M;
	if (u < 0) u += M;
	return u;
}
vector<vector<ll>> mul(vector<vector<ll>> a, vector<vector<ll>> b, int n) {
	int i, j, k, t;
	vector<vector<ll>> c(n);
	for (i = 0; i < n; i++) {
		for (j = 0; j < n; j++) {
			t = 0;
			for (k = 0; k < n; k++)
				t = (t + a[i][k] * b[k][j] % M) % M;
			c[i].push_back(t);
		}
	}
	return c;
}

template< typename Monoid >
struct SegmentTree {

	int sz;
	vector< Monoid > seg;

	const Monoid M1;

	SegmentTree(int n, const Monoid &M1) : M1(M1) {
		sz = 1;
		while (sz < n) sz <<= 1;
		seg.assign(2 * sz, M1);
	}

	void set(int k, const Monoid &x) {
		seg[k + sz] = x;
	}

	void build() {
		for (int k = sz - 1; k > 0; k--) {
			seg[k] = f(seg[2 * k + 0], seg[2 * k + 1]);
		}
	}

	void update(int k, const Monoid &x) {
		k += sz;
		seg[k] = x;
		while (k >>= 1) {
			seg[k] = f(seg[2 * k + 0], seg[2 * k + 1]);
		}
	}

	Monoid query(int a, int b) {
		Monoid L = M1, R = M1;
		for (a += sz, b += sz; a < b; a >>= 1, b >>= 1) {
			if (a & 1) L = f(L, seg[a++]);
			if (b & 1) R = f(seg[--b], R);
		}
		return f(L, R);
	}

	Monoid value(const int &k) const {
		return seg[k + sz];
	}

	Monoid f(Monoid a, Monoid b) {
		return a + b;
	}
};

int main() {
	ll n,c[111111],i,m,d[111111],p[111111],a,b;
	cin>>n>>m;
	queue<ll> q;
	vector<pair<ll,ll>> ans;
	vector<vector<ll>> l(n);
	UnionFind uf(n);
	for(i=0;i<n;i++){
		c[i]=0;
		d[i]=0;
		p[i]=0;
	}
	for(i=0;i<m;i++){
		cin>>a>>b;
		if(uf.same(a-1,b-1)){
			p[a-1]++;
			p[a-1]%=2;
			ans.push_back(make_pair(a-1,b-1));
		}
		else{
			l[a-1].push_back(b-1);
			l[b-1].push_back(a-1);
			d[a-1]++;
			d[b-1]++;
			uf.unite(a-1,b-1);
		}
	}
	for(i=0;i<n;i++)
		if(d[i]==1)
			q.push(i);
	if(m%2==1)
		cout<<"-1"<<endl;
	else{
		while(1){
			if(d[q.front()]==0)
				break;
			c[q.front()]++;
			for(auto &e:l[q.front()]){
				if(c[e]==0){
					if(p[q.front()]==1){
						ans.push_back(make_pair(q.front(),e));
					}
					else{
						ans.push_back(make_pair(e,q.front()));
						p[e]++;
						p[e]%=2;
					}
					d[e]--;
					if(d[e]==1)
						q.push(e);
				}
			}
			q.pop();
		}
		for(i=0;i<m;i++)
			cout<<ans[i].first+1<<" "<<ans[i].second+1<<endl;
	}
}

Measured memory_bytes: 17016