After a long party Petya decided to return home, but he turned out to be at the opposite end of the town from his home. There are $n$ crossroads in the line in the town, and there is either the bus or the tram station at each crossroad.

The crossroads are represented as a string $s$ of length $n$, where $s_i = \texttt{A}$, if there is a bus station at $i$-th crossroad, and $s_i = \texttt{B}$, if there is a tram station at $i$-th crossroad. Currently Petya is at the first crossroad (which corresponds to $s_1$) and his goal is to get to the last crossroad (which corresponds to $s_n$).

If for two crossroads $i$ and $j$ for all crossroads $i, i+1, \ldots, j-1$ there is a bus station, one can pay $a$ roubles for the bus ticket, and go from $i$-th crossroad to the $j$-th crossroad by the bus (it is not necessary to have a bus station at the $j$-th crossroad). Formally, paying $a$ roubles Petya can go from $i$ to $j$ if $s_t = \texttt{A}$ for all $i \le t < j$. 

If for two crossroads $i$ and $j$ for all crossroads $i, i+1, \ldots, j-1$ there is a tram station, one can pay $b$ roubles for the tram ticket, and go from $i$-th crossroad to the $j$-th crossroad by the tram (it is not necessary to have a tram station at the $j$-th crossroad). Formally, paying $b$ roubles Petya can go from $i$ to $j$ if $s_t = \texttt{B}$ for all $i \le t < j$.

For example, if $s$="AABBBAB", $a=4$ and $b=3$ then Petya needs:[Image]  buy one bus ticket to get from $1$ to $3$,  buy one tram ticket to get from $3$ to $6$,  buy one bus ticket to get from $6$ to $7$. 

Thus, in total he needs to spend $4+3+4=11$ roubles. Please note that the type of the stop at the last crossroad (i.e. the character $s_n$) does not affect the final expense.

Now Petya is at the first crossroad, and he wants to get to the $n$-th crossroad. After the party he has left with $p$ roubles. He's decided to go to some station on foot, and then go to home using only public transport.

Help him to choose the closest crossroad $i$ to go on foot the first, so he has enough money to get from the $i$-th crossroad to the $n$-th, using only tram and bus tickets.


-----Input-----

Each test contains one or more test cases. The first line contains the number of test cases $t$ ($1 \le t \le 10^4$).

The first line of each test case consists of three integers $a, b, p$ ($1 \le a, b, p \le 10^5$) — the cost of bus ticket, the cost of tram ticket and the amount of money Petya has.

The second line of each test case consists of one string $s$, where $s_i = \texttt{A}$, if there is a bus station at $i$-th crossroad, and $s_i = \texttt{B}$, if there is a tram station at $i$-th crossroad ($2 \le |s| \le 10^5$).

It is guaranteed, that the sum of the length of strings $s$ by all test cases in one test doesn't exceed $10^5$.


-----Output-----

For each test case print one number — the minimal index $i$ of a crossroad Petya should go on foot. The rest of the path (i.e. from $i$ to $n$ he should use public transport).


-----Example-----
Input
5
2 2 1
BB
1 1 1
AB
3 2 8
AABBBBAABB
5 3 4
BBBBB
2 1 1
ABABAB

Output
2
1
3
1
6

```python

USER_FILENAME = "<user_code>"
import sys, json, builtins
import math, heapq, bisect, itertools, functools, collections, statistics, fractions, decimal, operator, array, random, re, string, os, pathlib
try:
    import resource as _res
except Exception:
    _res = None
from collections import Counter, defaultdict, deque, OrderedDict
from functools import lru_cache, reduce
from itertools import accumulate, permutations, combinations, product
from math import gcd, ceil, floor, sqrt
from decimal import Decimal
try:
    from typing import *
except Exception:
    pass
try:
    sys.setrecursionlimit(1_000_000)
except Exception:
    pass
try:
    import site as _site
    try:
        _sys_sites = _site.getsitepackages() if hasattr(_site, "getsitepackages") else []
        for _p in _sys_sites:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
    try:
        _usp = _site.getusersitepackages()
        if isinstance(_usp, str):
            _usp = [_usp]
        for _p in _usp:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
except Exception:
    pass

ns = {"__name__": "__main__"}
for _k, _v in list(globals().items()):
    if not _k.startswith("_"):
        ns[_k] = _v
_CODE = '\n\n"""\nNTC here\n""" \nimport sys\ninp= sys.stdin.readline\ninput = lambda : inp().strip()\n# flush= sys.stdout.flush\n# import threading\n# sys.setrecursionlimit(10**6)\n# threading.stack_size(2**26)\n\ndef iin(): return int(input())\ndef lin(): return list(map(int, input().split()))\n\n\n\ndef main():\n    T = iin()\n    while T:\n        T-=1\n        a, b, p = lin()\n        \n        s = list(input())\n        n = len(s)\n        ans = []\n        ch = \'D\'\n        for i in range( n-1):\n            if s[i]!=ch:\n                ch = s[i]\n                x = a\n                if ch==\'B\':x=b\n                ans.append([x, i])\n        l = len(ans)\n        ans = ans[::-1]\n        for i in range(1, l):\n            ans[i][0]+=ans[i-1][0]\n        ans = ans[::-1]\n        for i, j in ans:\n            if p>=i:\n                print(j+1)\n                break\n        else:\n            print(n)\n        #print(ans)\n\n\nmain()\n\n#threading.Thread(target=main).start()\n\n'
_co = compile(_CODE, USER_FILENAME, "exec")
exec(_co, ns, ns)

```

Measured memory_bytes: 14801