Given two strings str1 and str2, return the shortest string that has both str1 and str2 as subsequences.  If multiple answers exist, you may return any of them.
(A string S is a subsequence of string T if deleting some number of characters from T (possibly 0, and the characters are chosen anywhere from T) results in the string S.)
 
Example 1:
Input: str1 = "abac", str2 = "cab"
Output: "cabac"
Explanation: 
str1 = "abac" is a subsequence of "cabac" because we can delete the first "c".
str2 = "cab" is a subsequence of "cabac" because we can delete the last "ac".
The answer provided is the shortest such string that satisfies these properties.

 
Note:

1 <= str1.length, str2.length <= 1000
str1 and str2 consist of lowercase English letters.

```python

USER_FILENAME = "<user_code>"
import sys, json, builtins
import math, heapq, bisect, itertools, functools, collections, statistics, fractions, decimal, operator, array, random, re, string, os, pathlib
try:
    import resource as _res
except Exception:
    _res = None
from collections import Counter, defaultdict, deque, OrderedDict
from functools import lru_cache, reduce
from itertools import accumulate, permutations, combinations, product
from math import gcd, ceil, floor, sqrt
from decimal import Decimal
try:
    from typing import *
except Exception:
    pass
try:
    sys.setrecursionlimit(1_000_000)
except Exception:
    pass
try:
    import site as _site
    try:
        _sys_sites = _site.getsitepackages() if hasattr(_site, "getsitepackages") else []
        for _p in _sys_sites:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
    try:
        _usp = _site.getusersitepackages()
        if isinstance(_usp, str):
            _usp = [_usp]
        for _p in _usp:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
except Exception:
    pass

def _disabled_input(*args, **kwargs):
    raise RuntimeError("input() is disabled in callable mode")
builtins.input = _disabled_input

ns = {"__name__": "__judge__"}  # prevent if __name__ == "__main__" blocks
for _k, _v in list(globals().items()):
    if not _k.startswith("_"):
        ns[_k] = _v
_CODE = "class Solution:\n    def shortestCommonSupersequence(self, str1: str, str2: str) -> str:\n        '''\n        @params: two strings str1 and str2\n        @return: shortest common supersequence\n        '''\n        # Use Dynamic Programming to first compute shortest common subsequence\n        m = len(str1)\n        n = len(str2)\n        dp = [[0] * (n+1) for _ in range(m+1)]\n        \n        for i in range(1, m+1):\n            for j in range(1, n+1):\n                # Case 1: delete text1[i] in common subsequence\n                deletion = dp[i-1][j]\n                # Case 2: delete text2[j] in common subsequence\n                insertion = dp[i][j-1]\n                # Case 3: match --> common subsequence extend by 1\n                match = dp[i-1][j-1] + 1\n                # Case 4: mistch --> common subsequence keeps the same\n                mismatch = dp[i-1][j-1]\n                \n                if str1[i-1] == str2[j-1]:\n                    dp[i][j] = max(deletion, insertion, match)\n                else:\n                    dp[i][j] = max(deletion, insertion, mismatch)\n                    \n        # Backtrack from dp[m][n] to construct shortest common supersequence\n        # in revered order\n        i, j = m, n\n        ans = []\n        \n        while i > 0 or j > 0:\n            # Case 1: str1 is used up\n            if i == 0:\n                ans.append(str2[j-1])\n                j -= 1\n                \n            # Case 2: str2 is used up\n            elif j == 0:\n                ans.append(str1[i-1])\n                i -= 1\n            \n            # Case 3: match\n            elif str1[i-1] == str2[j-1]:\n                ans.append(str1[i-1])\n                i -= 1\n                j -= 1\n                \n            # Case 4: insertion of str1\n            elif dp[i][j] == dp[i-1][j]:\n                ans.append(str1[i-1])\n                i -= 1\n                \n            # Case 5: deletion of str2\n            elif dp[i][j] == dp[i][j-1]:\n                ans.append(str2[j-1])\n                j -= 1\n            \n            #print('i, j: ', i, j)\n            #print(''.join(reversed(ans)))\n        \n        return ''.join(reversed(ans))\n            \n"
_co = compile(_CODE, USER_FILENAME, "exec")
exec(_co, ns, ns)

_target = None
_fn_name = 'shortestCommonSupersequence'
if _fn_name:
    if "Solution" in ns:
        try:
            _obj = ns["Solution"]()
            if hasattr(_obj, _fn_name):
                _target = getattr(_obj, _fn_name)
        except Exception:
            _target = None
    if _target is None and _fn_name in ns and callable(ns[_fn_name]):
        _target = ns[_fn_name]
# Fallback: if there's exactly one user-defined function, use it
if _target is None:
    _cands = [v for k, v in ns.items() if callable(v) and getattr(v, "__module__", "") in ("__judge__", "__main__")]
    _user_funcs = [c for c in _cands if getattr(c, "__name__", "").startswith("_") is False]
    if len(_user_funcs) == 1:
        _target = _user_funcs[0]
if _target is None:
    raise RuntimeError(f"Could not resolve callable '{_fn_name}'")

_raw = sys.stdin.read().strip()
if _raw:
    _parsed = json.loads(_raw)
    if isinstance(_parsed, dict):
        _kwargs = _parsed.get("kwargs", {})
        _args = _parsed.get("args", [])
    else:
        _args, _kwargs = _parsed, {}
else:
    _args, _kwargs = [], {}
if not isinstance(_args, (list, tuple)):
    _args = [_args]
_res = _target(*_args, **_kwargs)
try:
    sys.stdout.write(repr(_res) + "\n")
except Exception:
    pass

```

Measured memory_bytes: 7384