Rudolf is on his way to the castle. Before getting into the castle, the security staff asked him a question:

Given two binary numbers $a$ and $b$ of length $n$. How many different ways of swapping two digits in $a$ (only in $a$, not $b$) so that bitwise OR of these two numbers will be changed? In other words, let $c$ be the bitwise OR of $a$ and $b$, you need to find the number of ways of swapping two bits in $a$ so that bitwise OR will not be equal to $c$.

Note that binary numbers can contain leading zeros so that length of each number is exactly $n$.

Bitwise OR is a binary operation. A result is a binary number which contains a one in each digit if there is a one in at least one of the two numbers. For example, $01010_2$ OR $10011_2$ = $11011_2$.

Well, to your surprise, you are not Rudolf, and you don't need to help him$\ldots$ You are the security staff! Please find the number of ways of swapping two bits in $a$ so that bitwise OR will be changed.


-----Input-----

The first line contains one integer $n$ ($2\leq n\leq 10^5$) — the number of bits in each number.

The second line contains a binary number $a$ of length $n$.

The third line contains a binary number $b$ of length $n$.


-----Output-----

Print the number of ways to swap two bits in $a$ so that bitwise OR will be changed.


-----Examples-----
Input
5
01011
11001

Output
4

Input
6
011000
010011

Output
6



-----Note-----

In the first sample, you can swap bits that have indexes $(1, 4)$, $(2, 3)$, $(3, 4)$, and $(3, 5)$.

In the second example, you can swap bits that have indexes $(1, 2)$, $(1, 3)$, $(2, 4)$, $(3, 4)$, $(3, 5)$, and $(3, 6)$.

```python

USER_FILENAME = "<user_code>"
import sys, json, builtins
import math, heapq, bisect, itertools, functools, collections, statistics, fractions, decimal, operator, array, random, re, string, os, pathlib
try:
    import resource as _res
except Exception:
    _res = None
from collections import Counter, defaultdict, deque, OrderedDict
from functools import lru_cache, reduce
from itertools import accumulate, permutations, combinations, product
from math import gcd, ceil, floor, sqrt
from decimal import Decimal
try:
    from typing import *
except Exception:
    pass
try:
    sys.setrecursionlimit(1_000_000)
except Exception:
    pass
try:
    import site as _site
    try:
        _sys_sites = _site.getsitepackages() if hasattr(_site, "getsitepackages") else []
        for _p in _sys_sites:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
    try:
        _usp = _site.getusersitepackages()
        if isinstance(_usp, str):
            _usp = [_usp]
        for _p in _usp:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
except Exception:
    pass

ns = {"__name__": "__main__"}
for _k, _v in list(globals().items()):
    if not _k.startswith("_"):
        ns[_k] = _v
_CODE = "from sys import stdin\nfrom math import *\n\nline = stdin.readline().rstrip().split()\nn = int(line[0])\n\n\nnumbers = stdin.readline().rstrip().split()[0]\nnumbers2 = stdin.readline().rstrip().split()[0]\n\ncant00 = 0\ncant01 = 0\ncant11 = 0\ncant10 = 0\nfor i in range(len(numbers)):\n    if numbers[i] == '0' and numbers2[i] == '0':\n        cant00+=1\n    if numbers[i] == '1' and numbers2[i] == '0':\n        cant01+=1\n    if numbers[i] == '0' and numbers2[i] == '1':\n        cant10+=1\n    if numbers[i] == '1' and numbers2[i] == '1':\n        cant11+=1\nprint(cant00*cant01 + cant00 * cant11 + cant01 * cant10)\n\n"
_co = compile(_CODE, USER_FILENAME, "exec")
exec(_co, ns, ns)

```

Measured memory_bytes: 20085