// Problem : F - Strivore
// Contest : AtCoder - AtCoder Beginner Contest 171
// URL : https://atcoder.jp/contests/abc171/tasks/abc171_f
// Memory Limit : 1024 MB
// Time Limit : 2000 ms
// Powered by CP Editor (https://github.com/cpeditor/cpeditor)

#include<bits/stdc++.h>

#pragma GCC optimize("Ofast")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,avx2,fma")
#pragma GCC optimize("unroll-loops")  
 
#define pb push_back
#define fi first
#define se second
#define ios ios_base::sync_with_stdio(false);cin.tie(0);cout.tie(0);
#define hell1 1000000007
#define hell2 1000000009
#define ms(s, n) memset(s, n, sizeof(s))
#define prec(n) fixed<<setprecision(n)
#define eps 0.000001
#define all(v) v.begin(), v.end()
#define allr(v) v.rbegin(), v.rend()
#define ll long long
#define ld long double 
#define no_of_digits(n) floor(log10(n)) + 1
#define file() freopen("input.txt","r",stdin);freopen("output.txt","w",stdout);
#define see(x) cout << #x << "=" << x << endl;
#define see2(x, y) cout << #x << "=" << x << "\t" << #y << "=" << y << endl;
#define see3(x, y, z) cout << #x << "=" << x << "\t" << #y << "=" << y << "\t" << #z << "=" << z << endl;
#define INF 1e9+5
#define LL_MAX 1e18+5

using namespace std;

const ld PI = acos((ld)-1);
 
ll modmult(ll a,ll b, ll p=hell1){   return ((a%p)*(b%p))%p; }
ll modmultbig(ll a,ll b,ll mod=hell1){   if(a==0 or b==0) return 0;if(a==1 or b==1) return (a*b)%mod;ll cur=modmultbig(a,b/2,mod);cur=(2*cur)%mod;if(b%2) cur=(cur+a)%mod;return cur;}
ll modadd(ll a, ll b, ll p=hell1){ if(a>=p) a%=p; if(b>=p) b%=p; if(a+b>p) return (a + b)%p; else return a+b;}
ll modsub(ll a, ll b, ll p=hell1){return (a%p - b%p + p)%p;}
ll fpow(ll n, ll k, ll p = hell1) {ll r = 1; for (; k; k >>= 1) {if (k & 1) r = modmult(r,n,p); n = modmult(n,n,p);} return r;}
ll inv(ll a, ll p = hell1) {return fpow(a, p - 2, p);}
ll inv_euclid(ll a, ll m = hell1){ll m0 = m;ll y = 0, x = 1;if (m == 1)return 0;while (a > 1){ll q = a / m;ll t = m;m = a % m, a = t;t = y;y = x - q * y;x = t;}if (x < 0)x += m0;return x;}

int isPowerof2(ll x) { return (x && !(x & (x-1))); } 

ll log2(ll x) { ll res = 0; while (x >>= 1) res++; return res; } 

bool isPerfectSquare(long double x) {long double sr = sqrt(x); return ((sr - floor(sr)) == 0); }
 
bool boundary(ll i,ll j,ll n, ll m){return (i>=0 && i<n && j>=0 &&  j<m);} //matrix boundary checking

ll ceil(const ll &a, const ll &b){return (a - 1)/b + 1;}
ll lcm(ll a, ll b){return a/__gcd(a, b)*b;}

 
string alpha="abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789";

int dx[4] = {0, 0, -1, 1};
int dy[4] = {-1, 1, 0, 0};

// cout << fixed for removing e notation
 
bool comp2(const pair<int, int>&a, const pair<int, int>&b)
{
    if(a.second < b.second)
        return true;
    else if(a.second == b.second)
    {
        if(a.fi > b.fi) return true;
        else return false;
    }
    else return false;
}
 
bool prime[10000005];
void SieveOfEratosthenes(int n) 
{
    memset(prime, true, sizeof(prime)); 
    prime[0] = prime[1] = 0;
    for (int p=2; p*p<=n; p++) 
    {
        if (prime[p] == true) 
            for (int i=p*p; i<=n; i += p) 
                prime[i] = false; 
    }
}

ll fac[2000005], inverse[2000005];
  
// Returns nCr % p using Fermat's little 
// theorem. 
ll ncr(ll n, ll r, ll p) 
{ 
    // Base case 
    if (r == 0) 
        return 1;
    return (fac[n] * inverse[r] % p * inverse[n-r] % p) % p; 
} 

int main()
{
    ios
	ll k;
	cin >> k;
	string s;
	cin >> s;
	
	ll n = s.size();
	
	fac[0] = 1; 
	inverse[0] = 1;
    for (int i = 1; i <= n+k; i++)
    {
        fac[i] = modmultbig(fac[i-1], i, hell1);
        inverse[i] = inv(fac[i], hell1);
    }
	
	ll ans = 0;
	for(int i=n;i<=n+k;i++)
		ans = modadd(ans, modmultbig(ncr(k+n, i, hell1), fpow(25, k+n-i, hell1), hell1), hell1);
	
	cout << ans << "\n";
	
}
















































































































































Measured memory_bytes: 35628