You are given two strings $s$ and $t$ both of length $n$ and both consisting of lowercase Latin letters.

In one move, you can choose any length $len$ from $1$ to $n$ and perform the following operation:   Choose any contiguous substring of the string $s$ of length $len$ and reverse it;  at the same time choose any contiguous substring of the string $t$ of length $len$ and reverse it as well. 

Note that during one move you reverse exactly one substring of the string $s$ and exactly one substring of the string $t$.

Also note that borders of substrings you reverse in $s$ and in $t$ can be different, the only restriction is that you reverse the substrings of equal length. For example, if $len=3$ and $n=5$, you can reverse $s[1 \dots 3]$ and $t[3 \dots 5]$, $s[2 \dots 4]$ and $t[2 \dots 4]$, but not $s[1 \dots 3]$ and $t[1 \dots 2]$.

Your task is to say if it is possible to make strings $s$ and $t$ equal after some (possibly, empty) sequence of moves.

You have to answer $q$ independent test cases.


-----Input-----

The first line of the input contains one integer $q$ ($1 \le q \le 10^4$) — the number of test cases. Then $q$ test cases follow.

The first line of the test case contains one integer $n$ ($1 \le n \le 2 \cdot 10^5$) — the length of $s$ and $t$.

The second line of the test case contains one string $s$ consisting of $n$ lowercase Latin letters.

The third line of the test case contains one string $t$ consisting of $n$ lowercase Latin letters.

It is guaranteed that the sum of $n$ over all test cases does not exceed $2 \cdot 10^5$ ($\sum n \le 2 \cdot 10^5$).


-----Output-----

For each test case, print the answer on it — "YES" (without quotes) if it is possible to make strings $s$ and $t$ equal after some (possibly, empty) sequence of moves and "NO" otherwise.


-----Example-----
Input
4
4
abcd
abdc
5
ababa
baaba
4
asdf
asdg
4
abcd
badc

Output
NO
YES
NO
YES

```python

USER_FILENAME = "<user_code>"
import sys, json, builtins
import math, heapq, bisect, itertools, functools, collections, statistics, fractions, decimal, operator, array, random, re, string, os, pathlib
try:
    import resource as _res
except Exception:
    _res = None
from collections import Counter, defaultdict, deque, OrderedDict
from functools import lru_cache, reduce
from itertools import accumulate, permutations, combinations, product
from math import gcd, ceil, floor, sqrt
from decimal import Decimal
try:
    from typing import *
except Exception:
    pass
try:
    sys.setrecursionlimit(1_000_000)
except Exception:
    pass
try:
    import site as _site
    try:
        _sys_sites = _site.getsitepackages() if hasattr(_site, "getsitepackages") else []
        for _p in _sys_sites:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
    try:
        _usp = _site.getusersitepackages()
        if isinstance(_usp, str):
            _usp = [_usp]
        for _p in _usp:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
except Exception:
    pass

ns = {"__name__": "__main__"}
for _k, _v in list(globals().items()):
    if not _k.startswith("_"):
        ns[_k] = _v
_CODE = 'import random\n\n\ndef count_lens(t):\n t=list(t)\n n=len(t)\n res=0\n for _ in range(n):\n  for k in range (n-1):\n   if t[k]>t[k+1]:\n    t[k],t[k+1]=t[k+1],t[k]\n    res+=1\n    \n return (res) % 2\n\n\ndef prog():\n    input()\n    a, b = input(), input()\n    if sorted(a) != sorted(b):\n        print("NO")\n        return\n\n    if len(set(a)) < len(a):\n        print("YES")\n        return\n\n    print("YES" if count_lens(a) == count_lens(b) else "NO")\n\n\nt = int(input())\nfor _ in range(t):\n    prog()'
_co = compile(_CODE, USER_FILENAME, "exec")
exec(_co, ns, ns)

```

Measured memory_bytes: 13117