Rohit collects coins: he has exactly one coin for every year from 1 to n. Naturally, Rohit keeps all the coins in his collection in the order in which they were released. Once Rohit's younger brother made a change — he took all the coins whose release year dated from l to r inclusively and put them in the reverse order. That is, he took a certain segment [l, r] and reversed it. At that, the segment's endpoints did not coincide. For example, if n = 8, then initially Rohit's coins were kept in the order 1 2 3 4 5 6 7 8. If Rohit's younger brother chose the segment [2, 6], then after the reversal the coin order will change to 1 6 5 4 3 2 7 8. Rohit suspects that someone else could have spoilt the permutation after his brother. Help him to find that out. Check if the given permutation can be obtained from the permutation 1 2 … n using exactly one segment reversal. If it is possible, find the segment itself.

-----Input:-----
- The first line contains an integer N which is the number of coins in Rohit's collection. 
- The second line contains space-separated n integers which are the spoilt sequence of coins. It is guaranteed that the given sequence is a permutation, i.e. it contains only integers from 1 to n, and every number is used exactly 1 time.

-----Output:-----
If it is impossible to obtain the given permutation from the original one in exactly one action, print 0 0. Otherwise, print two numbers l, r (1 ≤ l < r ≤ n) which are the endpoints of the segment that needs to be reversed to obtain from permutation 1 2 … n the given one.

-----Constraints-----
- $1 \leq N \leq 1000$
- $1 \leq A[N] \leq 10^9$

-----Sample Input:-----
8
1 6 5 4 3 2 7 8

-----Sample Output:-----
2 6

```python

USER_FILENAME = "<user_code>"
import sys, json, builtins
import math, heapq, bisect, itertools, functools, collections, statistics, fractions, decimal, operator, array, random, re, string, os, pathlib
try:
    import resource as _res
except Exception:
    _res = None
from collections import Counter, defaultdict, deque, OrderedDict
from functools import lru_cache, reduce
from itertools import accumulate, permutations, combinations, product
from math import gcd, ceil, floor, sqrt
from decimal import Decimal
try:
    from typing import *
except Exception:
    pass
try:
    sys.setrecursionlimit(1_000_000)
except Exception:
    pass
try:
    import site as _site
    try:
        _sys_sites = _site.getsitepackages() if hasattr(_site, "getsitepackages") else []
        for _p in _sys_sites:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
    try:
        _usp = _site.getusersitepackages()
        if isinstance(_usp, str):
            _usp = [_usp]
        for _p in _usp:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
except Exception:
    pass

ns = {"__name__": "__main__"}
for _k, _v in list(globals().items()):
    if not _k.startswith("_"):
        ns[_k] = _v
_CODE = "n = int(input())\ncoins = list(map(int,input().split()))\nstart = -1\nend = -1\nans = [0 for x in range(n)]\nfor i in range(n):\n    if coins[i]!=i+1:\n        if start==-1:\n            start = i\n            break\n    ans[i] = coins[i]\n\nfor i in range(n-1,-1,-1):\n    if coins[i]!=i+1:\n        if end==-1:\n            end = i\n            break\n    ans[i] = coins[i]\n# print('start, end',start,end)\nmid = start + (end-start)//2\ns = start\ne = end\nwhile s<=end:\n    # print(s,e,'s,e')\n    # print('ans->',ans)\n    # print(ans[s],coins[e])\n    ans[s] = coins[e]\n    # print(ans[s],coins[e])\n    s +=1\n    e -=1\n    # print()\n\n# print(ans)\nstart +=1\nend +=1\nfor i in range(n):\n    if ans[i]!=i+1:\n        start = 0\n        end = 0\n        break\nprint(start,end)"
_co = compile(_CODE, USER_FILENAME, "exec")
exec(_co, ns, ns)

```

Measured memory_bytes: 13333