This kata is an extension of "Combinations in a Set Using Boxes":https://www.codewars.com/kata/5b5f7f7607a266914200007c

The goal for this kata is to get all the possible combinations (or distributions) (with no empty boxes) of a certain number of balls, but now, **with different amount of boxes.** In the previous kata, the number of boxes was always the same

Just to figure the goal for this kata, we can see in the picture below the combinations for four balls using the diagram of Hasse:



Points that are isolated represent balls that are unique in a box.
k points that are bonded in an area respresent a subset that is content in a box.

The unique square at the bottom of the diagram, means that there is only one possible combination for four balls in four boxes.

The above next line with 6 squares, means that we have 6 possible distributions of the four balls in 3 boxes. These six distributions have something in common, all of them have one box with 2 balls.

Going up one line more, we find the 7 possible distributions of the four balls in 2 boxes. As it is shown, we will have 7 distributions with: three balls in a box and only one ball in the another box, or two balls in each box.

Finally, we find again at the top, an unique square, that represents, the only possible distribution, having one box, the four balls together in the only available box.

So, for a set of 4 labeled balls, we have a total of 15 possible distributions (as always with no empty boxes) and with a maximum of 7 possible distributions for the case of two boxes.

Prepare a code that for a given number of balls (an integer), may output an array with required data in the following order:
```
[total_amount_distributions, maximum_amount_distributions_case_k_boxes, k_boxes]
```
Just see how it would be for the example given above:
```
combs_non_empty_boxesII(4) == [15, 7, 2] # A total of 15 combinations            
                                         #The case with maximum distributions is 7 using 2 boxes.

```
Features of the random tests:
```
1 < n <= 1800 (python)
1 < n <= 1200 (ruby)
```
You may see the example tests for more cases.
Enjoy it!
Ruby version will be published soon.

```python

USER_FILENAME = "<user_code>"
import sys, json, builtins
import math, heapq, bisect, itertools, functools, collections, statistics, fractions, decimal, operator, array, random, re, string, os, pathlib
try:
    import resource as _res
except Exception:
    _res = None
from collections import Counter, defaultdict, deque, OrderedDict
from functools import lru_cache, reduce
from itertools import accumulate, permutations, combinations, product
from math import gcd, ceil, floor, sqrt
from decimal import Decimal
try:
    from typing import *
except Exception:
    pass
try:
    sys.setrecursionlimit(1_000_000)
except Exception:
    pass
try:
    import site as _site
    try:
        _sys_sites = _site.getsitepackages() if hasattr(_site, "getsitepackages") else []
        for _p in _sys_sites:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
    try:
        _usp = _site.getusersitepackages()
        if isinstance(_usp, str):
            _usp = [_usp]
        for _p in _usp:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
except Exception:
    pass

def _disabled_input(*args, **kwargs):
    raise RuntimeError("input() is disabled in callable mode")
builtins.input = _disabled_input

ns = {"__name__": "__judge__"}  # prevent if __name__ == "__main__" blocks
for _k, _v in list(globals().items()):
    if not _k.startswith("_"):
        ns[_k] = _v
_CODE = '# this is [A000110, A002870, A024417]\n\n# Stirling numbers of second kind\n# http://mathworld.wolfram.com/StirlingNumberoftheSecondKind.html\n# S(n,k) = S(n-1,k-1)+k*S(n-1,k)\nS = {}\nfor n in range(1,1800):\n    S[(n,1)] = S[(n,n)] = 1\n    for k in range(2,n): S[(n,k)]=S[(n-1,k-1)]+k*S[(n-1,k)]\n\ndef combs_non_empty_boxesII(n):\n    ss = [(S[(n,k)],k) for k in range(1,n+1)]\n    return [sum(p[0] for p in ss), *max(ss)]'
_co = compile(_CODE, USER_FILENAME, "exec")
exec(_co, ns, ns)

_target = None
_fn_name = 'combs_non_empty_boxesII'
if _fn_name:
    if "Solution" in ns:
        try:
            _obj = ns["Solution"]()
            if hasattr(_obj, _fn_name):
                _target = getattr(_obj, _fn_name)
        except Exception:
            _target = None
    if _target is None and _fn_name in ns and callable(ns[_fn_name]):
        _target = ns[_fn_name]
# Fallback: if there's exactly one user-defined function, use it
if _target is None:
    _cands = [v for k, v in ns.items() if callable(v) and getattr(v, "__module__", "") in ("__judge__", "__main__")]
    _user_funcs = [c for c in _cands if getattr(c, "__name__", "").startswith("_") is False]
    if len(_user_funcs) == 1:
        _target = _user_funcs[0]
if _target is None:
    raise RuntimeError(f"Could not resolve callable '{_fn_name}'")

_raw = sys.stdin.read().strip()
if _raw:
    _parsed = json.loads(_raw)
    if isinstance(_parsed, dict):
        _kwargs = _parsed.get("kwargs", {})
        _args = _parsed.get("args", [])
    else:
        _args, _kwargs = _parsed, {}
else:
    _args, _kwargs = [], {}
if not isinstance(_args, (list, tuple)):
    _args = [_args]
_res = _target(*_args, **_kwargs)
try:
    sys.stdout.write(repr(_res) + "\n")
except Exception:
    pass

```

Measured memory_bytes: 5784