#include <bits/stdc++.h>

using namespace std;

typedef long long ll;
typedef unsigned long long ul;
typedef unsigned int ui;
typedef pair<int, int> P;
typedef pair<ll, ll> LP;
typedef long double ld;
typedef pair<ld, ld> LDP;
typedef vector<vector<ll>> mat;
typedef vector<ll> vec;
#define rep(i, n) for (int i = 0; i < n; i++)
#define per(i, n) for (int i = n - 1; i >= 0; i--)
#define Rep(i, sta, n) for (int i = sta; i < n; i++)
#define rep1(i, n) for (int i = 1; i <= n; i++)
#define per1(i, n) for (int i = n; i >= 1; i--)
#define Rep1(i, sta, n) for (int i = sta; i <= n; i++)
#define all(v) (v).begin(), (v).end()
const ll mod = 1000000007;
const ll INF = mod * mod;
const ld eps = 1e-12;
const ld pi = acos(-1.0);
//int qp(int a,ll b){int ans=1;do{if(b&1)ans=1ll*ans*a%mo;a=1ll*a*a%mo;}while(b>>=1);return ans;}
ll qp(ll a, ll b, int mo)
{
    int ans = 1;
    do
    {
        if (b & 1)
            ans = 1ll * ans * a % mo;
        a = 1ll * a * a % mo;
    } while (b >>= 1);
    return ans;
}
ll gcd(ll a, ll b) { return b ? gcd(b, a % b) : a; } // 最大公約数
ll lcm(ll a, ll b) { return a / gcd(a, b) * b; }     // 最小公倍数
int dx[4] = {0, 1, 0, -1};
int dy[4] = {1, 0, -1, 0};

template <typename T>
istream &operator>>(istream &is, vector<T> &vec)
{
    for (auto &v : vec)
        is >> v;
    return is;
}
template <typename T>
ostream &operator<<(ostream &os, const vector<T> &vec)
{
    os << "[";
    for (auto v : vec)
        os << v << ",";
    os << "]";
    return os;
}
template <typename T>
ostream &operator<<(ostream &os, const deque<T> &vec)
{
    os << "deq[";
    for (auto v : vec)
        os << v << ",";
    os << "]";
    return os;
}
template <typename T>
ostream &operator<<(ostream &os, const set<T> &vec)
{
    os << "{";
    for (auto v : vec)
        os << v << ",";
    os << "}";
    return os;
}
template <typename T>
ostream &operator<<(ostream &os, const unordered_set<T> &vec)
{
    os << "{";
    for (auto v : vec)
        os << v << ",";
    os << "}";
    return os;
}
template <typename T>
ostream &operator<<(ostream &os, const multiset<T> &vec)
{
    os << "{";
    for (auto v : vec)
        os << v << ",";
    os << "}";
    return os;
}
template <typename T>
ostream &operator<<(ostream &os, const unordered_multiset<T> &vec)
{
    os << "{";
    for (auto v : vec)
        os << v << ",";
    os << "}";
    return os;
}
template <typename T1, typename T2>
ostream &operator<<(ostream &os, const pair<T1, T2> &pa)
{
    os << "(" << pa.first << "," << pa.second << ")";
    return os;
}
template <typename TK, typename TV>
ostream &operator<<(ostream &os, const map<TK, TV> &mp)
{
    os << "{";
    for (auto v : mp)
        os << v.first << "=>" << v.second << ",";
    os << "}";
    return os;
}
template <typename TK, typename TV>
ostream &operator<<(ostream &os, const unordered_map<TK, TV> &mp)
{
    os << "{";
    for (auto v : mp)
        os << v.first << "=>" << v.second << ",";
    os << "}";
    return os;
}
template <typename T>
void ndarray(vector<T> &vec, int len) { vec.resize(len); }
template <typename T, typename... Args>
void ndarray(vector<T> &vec, int len, Args... args)
{
    vec.resize(len);
    for (auto &v : vec)
        ndarray(v, args...);
}
template <typename T>
bool chmax(T &m, const T q)
{
    if (m < q)
    {
        m = q;
        return true;
    }
    else
        return false;
}
template <typename T>
bool chmin(T &m, const T q)
{
    if (q < m)
    {
        m = q;
        return true;
    }
    else
        return false;
}
template <typename T1, typename T2>
pair<T1, T2> operator+(const pair<T1, T2> &l, const pair<T1, T2> &r) { return make_pair(l.first + r.first, l.second + r.second); }
template <typename T1, typename T2>
pair<T1, T2> operator-(const pair<T1, T2> &l, const pair<T1, T2> &r) { return make_pair(l.first - r.first, l.second - r.second); }
template <typename T1, typename T2>
pair<T1, T2> operator<(const pair<T1, T2> l, const pair<T1, T2> r) { return (l.first < r.first); }
template <typename T1, typename T2>
pair<T1, T2> operator>(const pair<T1, T2> l, const pair<T1, T2> r) { return (l.first > r.first); }


void solve(){
    ll R,G,B,N; cin >> R >> G >> B >> N;
    ll res = 0;

    rep(i,3001){
        ll sum = i*R;
        if(sum>N)break;
        rep(j,3001){
            ll tmp = sum + j*B;
            if(tmp>N)break;
            else{
                if((N-tmp)%G==0)res++;
            }
        }
    }

    cout << res << endl;

}

signed main(){
    ios::sync_with_stdio(false);
    cin.tie(0);

    std::cout << fixed << setprecision(10);
    solve();
    return 0;
}


Measured memory_bytes: 3616