//AUTHOR: RAVAN_2070
//PUNE INSTITUTE OF COMPUTER TECHNOLOGY
/*                                                    
      I ♥ CLARICE STARLING...                                                               
        EXPLAINATION BELOW->
*/
#include<bits/stdc++.h>
using namespace std;
typedef unsigned long long int ull;
typedef long long int ll;
typedef long double ld;
typedef vector<ll> vi;
typedef vector<pair<ll,ll>> vii;
typedef pair<ll,ll> pii;
typedef map<ll,ll> mii;
#define MOD7 1000000007
#define MOD9 1000000009
#define pi 3.1415926535
#define Test_cases ll TC;cin>>TC;while(TC--)
#define fastio ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
#define pb push_back
#define mp make_pair
#define F first
#define S second
#define all(x) x.begin(),x.end()
#define rall(x) x.rbegin(), x.rend()
#define sp(x) fixed<<setprecision(x)
#define sz(x) (ll)(x.size())
#define fo(i,a,b) for(i=a;i<b;i++)
#define foe(i,a,b) for(i=a;i<=b;i++)
const ll INF = (ll)2e18 + 77;
const int N=(int)4e5+5;
/*ll tree[N],A[N];
void build(int node, int start, int end)
{
    if(start == end)
    {
        // Leaf node will have a single element
        tree[node] = A[start];
    }
    else
    {
        int mid = (start + end) / 2;
        // Recurse on the left child
        build(2*node, start, mid);
        // Recurse on the right child
        build(2*node+1, mid+1, end);
        // Internal node will have the sum of both of its children
        tree[node] = tree[2*node] + tree[2*node+1];
    }
}
void update(int node, int start, int end, int idx, int val)
{
    if(start == end)
    {
        // Leaf node
        A[idx] += val;
        tree[node] += val;
    }
    else
    {
        int mid = (start + end) / 2;
        if(start <= idx and idx <= mid)
        {
            // If idx is in the left child, recurse on the left child
            update(2*node, start, mid, idx, val);
        }
        else
        {
            // if idx is in the right child, recurse on the right child
            update(2*node+1, mid+1, end, idx, val);
        }
        // Internal node will have the sum of both of its children
        tree[node] = tree[2*node] + tree[2*node+1];
    }
}
void solve()
{
    int n,i,q,b,c;cin>>n;
    map<int,int>idx;
    fo(i,0,n){cin>>A[i];idx[A[i]]=i;}
    build(1,1,n);
    foe(i,1,7)cout<<tree[i]<<" ";
    cout<<"\n";
    cin>>q;
    while(q--)
    {
        cin>>b>>c;
       cout<<idx[b]<<"\n";
       i=idx[b];
        update(1,1,n,i,c);
        cout<<tree[1]<<"\n";
    }
}*/
void solve()
{
    int n,i;cin>>n;
    int A[n];
    map<int,int>M;
    ll sum=0;
    fo(i,0,n)cin>>A[i],sum+=A[i],M[A[i]]++;
    
    int q,b,c;cin>>q;
    ll cnt;
    while(q--)
    {
        cin>>b>>c;
        cnt=M[b];
        sum=sum+(c-b)*cnt;
        M[c]+=cnt;
        M[b]=0;
        cout<<sum<<"\n";
    }
}
int main()
{
   fastio
   //Test_cases
   solve();
  return 0;
}
//map<ll,ll,greater<int>> to sort in descending order ,in iterator declaration no greater<int>
//if you want to apply lowerbound on set use s.lower_bound(key),not the one used for vector
// Syntax to create a min heap for priority queue priority_queue <int, vector<int>, greater<int>>; 
//for modinverse use modularexponention(x,M-2,M);
//for "each" subtraction from ans(ans-k) if(ans<0) do ans+=MOD,ans%=MOD
//vector<vector<int>>dp(201,vector<int>(n+1)); A way to initialize vector of vector
//If wrong on pretest 2 means logically wrong


/* TIPS FOR DEBUGGING
 * Check if values are not overflowing (use long long where required)
 * Check if ranges are inclusive or not.
 * Check properly if greedy will work or not before using it.
 * Check EDGE CASES!! Seriously, even in 2B, saving 8 points by being
 * 2 minutes faster will bite you in the ass if you don't make sure
 * it works on edge cases.
 * Keep adding to this list.
*/


Measured memory_bytes: 8364