#include <iostream>
#include <array>
#include <vector>
#include <map>
#include <unordered_map>
#include <set>
#include <unordered_set>
#include <algorithm>
#include <math.h>
#include <string>
#include <climits>
#include <cassert>
#include <iomanip>
#include <bitset>
#include <queue>
#include <deque>
#include <stack>
#include <functional>
#include <fstream>
#include <numeric>

#define FOR(i, a, n) for(int i=(a);i<(n); ++i)
#define FOE(i, a) for(auto i : a)
#define ALL(c) (c).begin(), (c).end()
#define RALL(c) (c).rbegin(), (c).rend()
#define SUM(x) std::accumulate(ALL(x), 0LL)
#define MIN(v) *std::min_element(v.begin(), v.end())
#define MAX(v) *std::max_element(v.begin(), v.end())
#define EXIST(v, x) (std::find(v.begin(), v.end(), x) != v.end())
#define IS_BIT_ON(bit, i) (bit & (1 << i))
#define BIT_ON(bit, i) (bit |= (1 << i))
#define BIT_OFF(bit, i) (bit &= ~(1 << i))
#define BIT_COUNT(bit) (__builtin_popcount(bit))

typedef long long LL;

template<typename T>
std::vector<T> make_v(size_t a) { return std::vector<T>(a); }

template<typename T, typename... Ts>
auto make_v(size_t a, Ts... ts) { return std::vector<decltype(make_v<T>(ts...))>(a, make_v<T>(ts...)); }    // C++14
template<typename T, typename V>
typename std::enable_if<std::is_class<T>::value == 0>::type fill_v(T &t, const V &v) { t = v; }

template<typename T, typename V>
typename std::enable_if<std::is_class<T>::value != 0>::type fill_v(T &t, const V &v) { for (auto &e:t) fill_v(e, v); }

template<class T>
inline T ceil(T a, T b) { return (a + b - 1) / b; }

void print() { std::cout << std::endl; }

template<class Head, class... Tail>
void print(Head &&head, Tail &&... tail) {
    std::cout << head;
    if (sizeof...(tail) != 0) { std::cout << " "; }
    print(std::forward<Tail>(tail)...);
}

template<class T>
void print(std::vector<T> &v) {
    for (auto &a : v) {
        std::cout << a;
        if (&a != &v.back()) { std::cout << " "; }
    }
    std::cout << std::endl;
}

template<class T>
void print(std::vector<std::vector<T>> &vv) { for (auto &v : vv) { print(v); }}

void debug() { std::cerr << std::endl; }

template<class Head, class... Tail>
void debug(Head &&head, Tail &&... tail) {
    std::cerr << head;
    if (sizeof...(tail) != 0) { std::cerr << " "; }
    print(std::forward<Tail>(tail)...);
}

template<class T>
void debug(std::vector<T> &v) {
    for (auto &a : v) {
        std::cerr << a;
        if (&a != &v.back()) { std::cerr << " "; }
    }
    std::cerr << std::endl;
}

template<class T>
void debug(std::vector<std::vector<T>> &vv) { for (auto &v : vv) { print(v); }}

inline bool inside(long long y, long long x, long long H, long long W) { return 0 <= y and y < H and 0 <= x and x < W; }

template<class T>
inline double euclidean_distance(T y1, T x1, T y2, T x2) { return sqrt((x1 - x2) * (x1 - x2) + (y1 - y2) * (y1 - y2)); }

template<class T>
inline double manhattan_distance(T y1, T x1, T y2, T x2) { return abs(x1 - x2) + abs(y1 - y2); }

template<typename T>
T &chmin(T &a, const T &b) { return a = std::min(a, b); }

template<typename T>
T &chmax(T &a, const T &b) { return a = std::max(a, b); }

template<class T>
inline std::vector<T> unique(std::vector<T> v) {
    sort(v.begin(), v.end());
    v.erase(unique(v.begin(), v.end()), v.end());
    return v;
}

long long sum_of_arithmetic_progression(long long s, long long d, long long n) {
    return n * (2 * s + (n - 1) * d) / 2;
}

bool is_power_of_two(long long x) {
    return !(x & (x - 1));
}

long long gcd(long long a, long long b) {
    if (b == 0) { return a; }
    return gcd(b, a % b);
}

long long gcd(std::vector<long long> &v) {
    long long ans = v[0];
    for (int i = 1; i < (int) v.size(); ++i) {
        ans = gcd(ans, v[i]);
    }
    return ans;
}

long long lcm(long long a, long long b) {
    long long g = gcd(a, b);
    return a / g * b;
}

const int INF = 1u << 30u;
const long long LINF = 1ull << 58u;
const double EPS = 1e-9;
const long double PI = acos(-1.0);
const std::vector<int> dy2 = {0, 1}, dx2 = {1, 0};
const std::vector<int> dy4 = {0, 1, 0, -1}, dx4 = {1, 0, -1, 0};
const std::vector<int> dy8 = {0, -1, 0, 1, 1, -1, -1, 1}, dx8 = {1, 0, -1, 0, 1, 1, -1, -1};


using namespace std;

template<int mod> struct mint {
    long long x;
    mint(long long x = 0) : x(x % mod) {
    }

    mint& operator+=(const mint a) {
        if ((x += a.x) >= mod) {
            x -= mod;
        }
        return *this;
    }
    mint& operator-=(const mint a) {
        if ((x += mod-a.x) >= mod) {
            x -= mod;
        }
        return *this;
    }
    mint& operator*=(const mint a) {
        (x *= a.x) %= mod;
        return *this;
    }
    mint operator+(const mint a) const {
        mint res(*this);
        return res+=a;
    }
    mint operator-(const mint a) const {
        mint res(*this);
        return res-=a;
    }
    mint operator*(const mint a) const {
        mint res(*this);
        return res*=a;
    }
    mint pow(long long t) const {
        if (!t) {
            return 1;
        }
        mint a = pow(t>>1);
        a *= a;
        if (t&1) {
            a *= *this;
        }
        return a;
    }

    // for prime mod
    mint inv() const {
        return pow(mod-2);
    }
    mint& operator/=(const mint a) {
        return (*this) *= a.inv();
    }
    mint operator/(const mint a) const {
        mint res(*this);
        return res/=a;
    }
};

const int MOD = 1000000000 + 7;

// modがでかいときはoverflowに注意
long long powmod(long long base, long long exp, long long mod) {
    long long x = 1, y = base;
    while (exp > 0) {
        if (exp % 2 == 1) {
            x = (x * y) % mod;
        }
        y = (y * y) % mod;
        exp /= 2;
    }

    return int(x % mod);
}

int main(int argc, char *argv[]) {
    cin.tie(0);
    ios::sync_with_stdio(false);

    long long N, K;
    cin >> N >> K;

    // D2[x] = gcdがxの倍数となるような数列の場合の数
    auto D2 = make_v<mint<MOD>>(K + 1);
    FOR(x, 1, K + 1) {
        D2[x] = powmod(K / x, N, MOD);
    }

    // D[x] = gcdがxとなるような数列の場合の数
    auto D = make_v<mint<MOD>>(K + 1);
    for (int x = K; x >= 1; --x) {
        D[x] = D2[x];
        for (int i = 2; x * i <= K; ++i) {
            D[x] -= D[i * x];
        }
    }

    mint<MOD> ans = 0;
    FOR(x, 1, K + 1) {
        ans += D[x] * x;
    }
    print(ans.x);

    return 0;
}

Measured memory_bytes: 4748