There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. 

You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of wins of each team, instead he thought that absolute difference between number of wins of first and second team will be d_1 and that of between second and third team will be d_2.

You don't want any of team win the tournament, that is each team should have the same number of wins after n games. That's why you want to know: does there exist a valid tournament satisfying the friend's guess such that no team will win this tournament?

Note that outcome of a match can not be a draw, it has to be either win or loss.


-----Input-----

The first line of the input contains a single integer corresponding to number of test cases t (1 ≤ t ≤ 10^5).

Each of the next t lines will contain four space-separated integers n, k, d_1, d_2 (1 ≤ n ≤ 10^12; 0 ≤ k ≤ n; 0 ≤ d_1, d_2 ≤ k) — data for the current test case.


-----Output-----

For each test case, output a single line containing either "yes" if it is possible to have no winner of tournament, or "no" otherwise (without quotes).


-----Examples-----
Input
5
3 0 0 0
3 3 0 0
6 4 1 0
6 3 3 0
3 3 3 2

Output
yes
yes
yes
no
no



-----Note-----

Sample 1. There has not been any match up to now (k = 0, d_1 = 0, d_2 = 0). If there will be three matches (1-2, 2-3, 3-1) and each team wins once, then at the end each team will have 1 win.

Sample 2. You missed all the games (k = 3). As d_1 = 0 and d_2 = 0, and there is a way to play three games with no winner of tournament (described in the previous sample), the answer is "yes".

Sample 3. You missed 4 matches, and d_1 = 1, d_2 = 0. These four matches can be: 1-2 (win 2), 1-3 (win 3), 1-2 (win 1), 1-3 (win 1). Currently the first team has 2 wins, the second team has 1 win, the third team has 1 win. Two remaining matches can be: 1-2 (win 2), 1-3 (win 3). In the end all the teams have equal number of wins (2 wins).

```python

USER_FILENAME = "<user_code>"
import sys, json, builtins
import math, heapq, bisect, itertools, functools, collections, statistics, fractions, decimal, operator, array, random, re, string, os, pathlib
try:
    import resource as _res
except Exception:
    _res = None
from collections import Counter, defaultdict, deque, OrderedDict
from functools import lru_cache, reduce
from itertools import accumulate, permutations, combinations, product
from math import gcd, ceil, floor, sqrt
from decimal import Decimal
try:
    from typing import *
except Exception:
    pass
try:
    sys.setrecursionlimit(1_000_000)
except Exception:
    pass
try:
    import site as _site
    try:
        _sys_sites = _site.getsitepackages() if hasattr(_site, "getsitepackages") else []
        for _p in _sys_sites:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
    try:
        _usp = _site.getusersitepackages()
        if isinstance(_usp, str):
            _usp = [_usp]
        for _p in _usp:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
except Exception:
    pass

ns = {"__name__": "__main__"}
for _k, _v in list(globals().items()):
    if not _k.startswith("_"):
        ns[_k] = _v
_CODE = 'import sys\nlines = sys.stdin.readlines()\n\n\'\'\'\n(n, p) = map(int, lines[0].strip().split(" "))\nranges = []\nfor i in range(1, n+1):\n    (l, r) = map(int, lines[i].strip().split(" "))\n    ranges.append((l,r))\n\nprobs = []\nfor lr in ranges:\n    poss = lr[1]//p - (lr[0]-1)//p\n    probs.append(poss/(lr[1]-lr[0]+1))\n\nres = 0\nfor i in range(n):\n    res += probs[i] + probs[i-1] - probs[i] * probs[i-1]\nprint(res * 2000)\n\'\'\'\nN = int(lines[0].strip())\nfor i in range(1, 1+N):\n    (n, k, d1, d2) = map(int, lines[i].strip().split(" "))\n    if n % 3 != 0: print("no"); continue\n\n    def solve(da, db):\n        tmp = k - da - db\n        if tmp % 3 != 0: return True\n        b = tmp // 3\n        a = b + da\n        c = b + db\n        if min(a,b,c) < 0: return True\n        if n//3 >= max(a,b,c): return False\n        else: return True\n        \n    cannot = True\n    if cannot: cannot = solve(d1, d2)\n    if cannot: cannot = solve(d1, -d2)\n    if cannot: cannot = solve(-d1, d2)\n    if cannot: cannot = solve(-d1, -d2)\n    if cannot: print("no")\n    else: print("yes")'
_co = compile(_CODE, USER_FILENAME, "exec")
exec(_co, ns, ns)

```

Measured memory_bytes: 13885