You are given a string $s[1 \dots n]$ consisting of lowercase Latin letters. It is guaranteed that $n = 2^k$ for some integer $k \ge 0$.

The string $s[1 \dots n]$ is called $c$-good if at least one of the following three conditions is satisfied:  The length of $s$ is $1$, and it consists of the character $c$ (i.e. $s_1=c$); The length of $s$ is greater than $1$, the first half of the string consists of only the character $c$ (i.e. $s_1=s_2=\dots=s_{\frac{n}{2}}=c$) and the second half of the string (i.e. the string $s_{\frac{n}{2} + 1}s_{\frac{n}{2} + 2} \dots s_n$) is a $(c+1)$-good string;  The length of $s$ is greater than $1$, the second half of the string consists of only the character $c$ (i.e. $s_{\frac{n}{2} + 1}=s_{\frac{n}{2} + 2}=\dots=s_n=c$) and the first half of the string (i.e. the string $s_1s_2 \dots s_{\frac{n}{2}}$) is a $(c+1)$-good string. 

For example: "aabc" is 'a'-good, "ffgheeee" is 'e'-good.

In one move, you can choose one index $i$ from $1$ to $n$ and replace $s_i$ with any lowercase Latin letter (any character from 'a' to 'z').

Your task is to find the minimum number of moves required to obtain an 'a'-good string from $s$ (i.e. $c$-good string for $c=$ 'a'). It is guaranteed that the answer always exists.

You have to answer $t$ independent test cases.

Another example of an 'a'-good string is as follows. Consider the string $s = $"cdbbaaaa". It is an 'a'-good string, because:  the second half of the string ("aaaa") consists of only the character 'a';  the first half of the string ("cdbb") is 'b'-good string, because:   the second half of the string ("bb") consists of only the character 'b';  the first half of the string ("cd") is 'c'-good string, because:   the first half of the string ("c") consists of only the character 'c';  the second half of the string ("d") is 'd'-good string.   


-----Input-----

The first line of the input contains one integer $t$ ($1 \le t \le 2 \cdot 10^4$) — the number of test cases. Then $t$ test cases follow.

The first line of the test case contains one integer $n$ ($1 \le n \le 131~072$) — the length of $s$. It is guaranteed that $n = 2^k$ for some integer $k \ge 0$. The second line of the test case contains the string $s$ consisting of $n$ lowercase Latin letters.

It is guaranteed that the sum of $n$ does not exceed $2 \cdot 10^5$ ($\sum n \le 2 \cdot 10^5$).


-----Output-----

For each test case, print the answer — the minimum number of moves required to obtain an 'a'-good string from $s$ (i.e. $c$-good string with $c =$ 'a'). It is guaranteed that the answer exists.


-----Example-----
Input
6
8
bbdcaaaa
8
asdfghjk
8
ceaaaabb
8
bbaaddcc
1
z
2
ac

Output
0
7
4
5
1
1

```python

USER_FILENAME = "<user_code>"
import sys, json, builtins
import math, heapq, bisect, itertools, functools, collections, statistics, fractions, decimal, operator, array, random, re, string, os, pathlib
try:
    import resource as _res
except Exception:
    _res = None
from collections import Counter, defaultdict, deque, OrderedDict
from functools import lru_cache, reduce
from itertools import accumulate, permutations, combinations, product
from math import gcd, ceil, floor, sqrt
from decimal import Decimal
try:
    from typing import *
except Exception:
    pass
try:
    sys.setrecursionlimit(1_000_000)
except Exception:
    pass
try:
    import site as _site
    try:
        _sys_sites = _site.getsitepackages() if hasattr(_site, "getsitepackages") else []
        for _p in _sys_sites:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
    try:
        _usp = _site.getusersitepackages()
        if isinstance(_usp, str):
            _usp = [_usp]
        for _p in _usp:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
except Exception:
    pass

ns = {"__name__": "__main__"}
for _k, _v in list(globals().items()):
    if not _k.startswith("_"):
        ns[_k] = _v
_CODE = "def solve(n, s):\n    def _doit(l, r, c):\n        ch = chr(ord('a') + c)\n        if l+1 == r:\n            return int(s[l] != ch)\n        mid = l + (r-l)//2\n        non1 = sum(int(s[i] != ch) for i in range(l, mid))\n        non2 = sum(int(s[i] != ch) for i in range(mid, r))\n        return min(non1 + _doit(mid, r, c+1), non2 + _doit(l, mid, c+1))\n    return _doit(0, n, 0)\n\nt = int(input())\nfor _ in range(t):\n    n = int(input())\n    s = input()\n    # a = list(map(int, input().split()))\n    # x, y, z = map(int, input().split())\n    print(solve(n, s))"
_co = compile(_CODE, USER_FILENAME, "exec")
exec(_co, ns, ns)

```

Measured memory_bytes: 13055