Snuke's town has a subway system, consisting of N stations and M railway lines. The stations are numbered 1 through N. Each line is operated by a company. Each company has an identification number.
The i-th ( 1 \leq i \leq M ) line connects station p_i and q_i bidirectionally. There is no intermediate station. This line is operated by company c_i.
You can change trains at a station where multiple lines are available.
The fare system used in this subway system is a bit strange. When a passenger only uses lines that are operated by the same company, the fare is 1 yen (the currency of Japan). Whenever a passenger changes to a line that is operated by a different company from the current line, the passenger is charged an additional fare of 1 yen. In a case where a passenger who changed from some company A's line to another company's line changes to company A's line again, the additional fare is incurred again.
Snuke is now at station 1 and wants to travel to station N by subway. Find the minimum required fare.

-----Constraints-----
 - 2 \leq N \leq 10^5
 - 0 \leq M \leq 2×10^5
 - 1 \leq p_i \leq N (1 \leq i \leq M)
 - 1 \leq q_i \leq N (1 \leq i \leq M)
 - 1 \leq c_i \leq 10^6 (1 \leq i \leq M)
 - p_i \neq q_i (1 \leq i \leq M)

-----Input-----
The input is given from Standard Input in the following format:
N M
p_1 q_1 c_1
:
p_M q_M c_M

-----Output-----
Print the minimum required fare. If it is impossible to get to station N by subway, print -1 instead.

-----Sample Input-----
3 3
1 2 1
2 3 1
3 1 2

-----Sample Output-----
1

Use company 1's lines: 1 → 2 → 3. The fare is 1 yen.

```python

USER_FILENAME = "<user_code>"
import sys, json, builtins
import math, heapq, bisect, itertools, functools, collections, statistics, fractions, decimal, operator, array, random, re, string, os, pathlib
try:
    import resource as _res
except Exception:
    _res = None
from collections import Counter, defaultdict, deque, OrderedDict
from functools import lru_cache, reduce
from itertools import accumulate, permutations, combinations, product
from math import gcd, ceil, floor, sqrt
from decimal import Decimal
try:
    from typing import *
except Exception:
    pass
try:
    sys.setrecursionlimit(1_000_000)
except Exception:
    pass
try:
    import site as _site
    try:
        _sys_sites = _site.getsitepackages() if hasattr(_site, "getsitepackages") else []
        for _p in _sys_sites:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
    try:
        _usp = _site.getusersitepackages()
        if isinstance(_usp, str):
            _usp = [_usp]
        for _p in _usp:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
except Exception:
    pass

ns = {"__name__": "__main__"}
for _k, _v in list(globals().items()):
    if not _k.startswith("_"):
        ns[_k] = _v
_CODE = 'import sys\nstdin = sys.stdin\n \nsys.setrecursionlimit(10**7) \n \ndef li(): return list(map(int, stdin.readline().split()))\ndef li_(): return [int(x)-1 for x in stdin.readline().split()]\ndef lf(): return list(map(float, stdin.readline().split()))\ndef ls(): return stdin.readline().split()\ndef ns(): return stdin.readline().rstrip()\ndef lc(): return list(ns())\ndef ni(): return int(stdin.readline())\ndef nf(): return float(stdin.readline())\n\nfrom collections import deque, defaultdict\n\nn,m = li()\nmod = 10**7\n\ntable = defaultdict(set)\nvisit = defaultdict(int)\n\nfor i in range(m):\n    a,b,c = li()\n    \n    table[a].add(a + c*mod)\n    table[b].add(b + c*mod)\n    table[a + c*mod].add(a)\n    table[b + c*mod].add(b)\n    table[a + c*mod].add(b + c*mod)\n    table[b + c*mod].add(a + c*mod)\n    \n    visit[a] = 0\n    visit[b] = 0\n    visit[b + c*mod] = 0\n    visit[a + c*mod] = 0\n    \nque = deque()\nque.append((1,0))\n\nvisit[1] = 1\nans = mod\n\nwhile que:\n    x, cost = que.popleft()\n    visit[x] = 1\n    \n    if x == n:\n        ans = min(ans, cost)\n        break\n    \n    for y in table[x]:\n        if visit[y] == 1:\n            continue\n        \n        if x <= 10**5 and mod <= y:\n            que.append((y, cost+1))\n            \n        else:\n            que.appendleft((y, cost))\n        \nprint((-1 if ans == mod else ans))\n'
_co = compile(_CODE, USER_FILENAME, "exec")
exec(_co, ns, ns)

```

Measured memory_bytes: 16013