You are given two strings of equal length $s$ and $t$ consisting of lowercase Latin letters. You may perform any number (possibly, zero) operations on these strings.

During each operation you choose two adjacent characters in any string and assign the value of the first character to the value of the second or vice versa.

For example, if $s$ is "acbc" you can get the following strings in one operation:   "aabc" (if you perform $s_2 = s_1$);  "ccbc" (if you perform $s_1 = s_2$);  "accc" (if you perform $s_3 = s_2$ or $s_3 = s_4$);  "abbc" (if you perform $s_2 = s_3$);  "acbb" (if you perform $s_4 = s_3$); 

Note that you can also apply this operation to the string $t$.

Please determine whether it is possible to transform $s$ into $t$, applying the operation above any number of times.

Note that you have to answer $q$ independent queries.


-----Input-----

The first line contains one integer $q$ ($1 \le q \le 100$) — the number of queries. Each query is represented by two consecutive lines.

The first line of each query contains the string $s$ ($1 \le |s| \le 100$) consisting of lowercase Latin letters.

The second line of each query contains the string $t$ ($1 \le |t| \leq 100$, $|t| = |s|$) consisting of lowercase Latin letters.


-----Output-----

For each query, print "YES" if it is possible to make $s$ equal to $t$, and "NO" otherwise.

You may print every letter in any case you want (so, for example, the strings "yEs", "yes", "Yes", and "YES" will all be recognized as positive answer).


-----Example-----
Input
3
xabb
aabx
technocup
technocup
a
z

Output
YES
YES
NO



-----Note-----

In the first query, you can perform two operations $s_1 = s_2$ (after it $s$ turns into "aabb") and $t_4 = t_3$ (after it $t$ turns into "aabb"). 

In the second query, the strings are equal initially, so the answer is "YES".

In the third query, you can not make strings $s$ and $t$ equal. Therefore, the answer is "NO".

```python

USER_FILENAME = "<user_code>"
import sys, json, builtins
import math, heapq, bisect, itertools, functools, collections, statistics, fractions, decimal, operator, array, random, re, string, os, pathlib
try:
    import resource as _res
except Exception:
    _res = None
from collections import Counter, defaultdict, deque, OrderedDict
from functools import lru_cache, reduce
from itertools import accumulate, permutations, combinations, product
from math import gcd, ceil, floor, sqrt
from decimal import Decimal
try:
    from typing import *
except Exception:
    pass
try:
    sys.setrecursionlimit(1_000_000)
except Exception:
    pass
try:
    import site as _site
    try:
        _sys_sites = _site.getsitepackages() if hasattr(_site, "getsitepackages") else []
        for _p in _sys_sites:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
    try:
        _usp = _site.getusersitepackages()
        if isinstance(_usp, str):
            _usp = [_usp]
        for _p in _usp:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
except Exception:
    pass

ns = {"__name__": "__main__"}
for _k, _v in list(globals().items()):
    if not _k.startswith("_"):
        ns[_k] = _v
_CODE = "n=int(input())\nfor i in range(n):\n    s=input()\n    t=input()\n    s1 = set()\n    s2=set()\n    for q in s:\n        s1.add(q)\n    for q in t:\n        s2.add(q)\n    if len(s1.intersection(s2)):\n        print('YES')\n    else:\n        print('NO')"
_co = compile(_CODE, USER_FILENAME, "exec")
exec(_co, ns, ns)

```

Measured memory_bytes: 13079