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//
#include <bits/stdc++.h>
#define int long long
#define rep(i,a,b) for(int i=a;i<(b);++i)
#define erep(i,a,b) for(int i=a;i<=(b);++i)
#define per(i,a,b) for(int i=(a);i>(b);--i)
#define eper(i,a,b) for(int i=(a);i>=b;--i)
#define fore(i, x, a) for(auto &&x:a) 
#define ITR(i,b,e) for(auto i=(b);i!=(e);++i)
#define IN(i,a,b) (a)<=(i) && (i)<(b)
#define pb push_back
#define mp make_pair
#define ALL(x) begin(x),end(x)
#define F first
#define S second
#define debug(x)  cout << #x << ": " << (x) << '\n';
const long long INF=1001001001001001001;
const int MOD=(int)1e9 + 7;
const double EPS=1e-9;
using namespace std;
using Pii = pair<int,int>;
using vii = vector<int>;
template<class T>using  PS_queue = priority_queue<T, vector<T>, greater<T> >;
template<class T>using vv = vector<T>;
template<class T>bool chmax(T &a, const T &b) { if (a<b) { a = b; return 1; } return 0; }
template<class T>bool chmin(T &a, const T &b) { if (b<a) { a = b; return 1; } return 0; }
template<typename A, size_t N, typename T> void Fill(A (&array)[N], const T &val){fill( (T*)array, (T*)(array+N), val );}
template<class T> ostream& operator<<(ostream &os,const vector<T> &v) {
    ITR(i,begin(v),end(v))os<<*i<<(i==end(v)-1?"":" ");return os;}
template<class T> istream& operator>>(istream &is,vector<T> &v) {
    ITR(i,begin(v),end(v)) is>>*i;return is;}
template<class T,class U> istream& operator>>(istream &is, pair<T,U> &p) {
    is>>p.first>>p.second;return is;}
template<class T>T gcd(T a, T b){ return b ? gcd(b, a % b) : a; }
template<class T>T lcm(T a, T b){ return a / gcd(a, b) * b; }
struct edge { int from, to, cost; };
int dy[]={0, 1, -1, 0}; int dx[]={1, 0, 0, -1};

int n, m, d[105][105];
signed main() {
 cin.tie(0);
 ios::sync_with_stdio(false);
  cin >> n >> m;
  vii a(m), b(m), c(m);
  rep(i, 0, n) rep(j, 0, n) 
    d[i][j] = (i == j ? 0 : INF); 
  rep(i, 0, m) {
    cin >> a[i] >> b[i] >> c[i];
    a[i]--, b[i]--;
    d[a[i]][b[i]] = min(d[a[i]][b[i]], c[i]);
    d[b[i]][a[i]] = min(d[b[i]][a[i]], c[i]);
  }
  rep(k, 0, n) rep(i, 0, n) rep(j, 0, n)
    d[i][j] = min(d[i][j], d[i][k] + d[k][j]);
  int ans = m;
  rep(i, 0, m) {
    bool flag = false;
    rep(j, 0, n) {
      if (d[j][b[i]] == d[j][a[i]] + c[i]) {
        flag = true;
      }
    }
    ans -= flag; 
  }
  cout << ans << endl;
  return 0;
}



Measured memory_bytes: 384