It's year 2018 and it's Christmas time! Before going for vacations, students of Hogwarts School of Witchcraft and Wizardry had their end semester exams.
$N$ students attended the semester exam. Once the exam was over, their results were displayed as either "Pass" or "Fail" behind their magic jacket which they wore. A student cannot see his/her result but can see everyone else's results. Each of $N$ students count the number of passed students they can see.
Given the number of "Pass" verdicts that each of the $N$ students counted, we have to figure out conclusively, the number of students who failed, or report that there is some inconsistency or that we cannot be sure.

-----Input:-----
- First line will contain $T$, number of testcases. Then the testcases follow. 
- The first line of each test case will contain $N$, representing the number of students who attended the exam.
- Next line contains  $N$ spaced integers representing the number of "Pass" counted by each of the $N$ students.

-----Output:-----
- For each test case, output the answer in a single line. 
- If the counts reported by the students are not consistent with each other or if it's not possible to predict the number of failed students from the given input, then print -1.

-----Constraints-----
- $1 \leq T \leq 50$
- $1 \leq N \leq 10^{5}$
- $0 \leq$ Count given by each Student $\leq 10^{5}$

-----Sample Input:-----
1
4
3 2 2 2

-----Sample Output:-----
1

-----EXPLANATION:-----
There are 4 students, and they counted the number of passed students as 3,2,2,2. The first student can see that all others have passed, and all other students can see only 2 students who have passed. Hence, the first student must have failed, and others have all passed. Hence, the answer is 1.

```python

USER_FILENAME = "<user_code>"
import sys, json, builtins
import math, heapq, bisect, itertools, functools, collections, statistics, fractions, decimal, operator, array, random, re, string, os, pathlib
try:
    import resource as _res
except Exception:
    _res = None
from collections import Counter, defaultdict, deque, OrderedDict
from functools import lru_cache, reduce
from itertools import accumulate, permutations, combinations, product
from math import gcd, ceil, floor, sqrt
from decimal import Decimal
try:
    from typing import *
except Exception:
    pass
try:
    sys.setrecursionlimit(1_000_000)
except Exception:
    pass
try:
    import site as _site
    try:
        _sys_sites = _site.getsitepackages() if hasattr(_site, "getsitepackages") else []
        for _p in _sys_sites:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
    try:
        _usp = _site.getusersitepackages()
        if isinstance(_usp, str):
            _usp = [_usp]
        for _p in _usp:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
except Exception:
    pass

ns = {"__name__": "__main__"}
for _k, _v in list(globals().items()):
    if not _k.startswith("_"):
        ns[_k] = _v
_CODE = 't=int(input())\nfor o in range(t):\n n=int(input())\n a=list(map(int,input().split()))\n b=list(set(a))\n b.sort()\n if(n==1):\n  print(-1)\n  continue\n if(len(b)>2):\n  print(-1)\n  continue\n if(len(b)==1):\n  if(b[0]==(n-1)):\n   print(0)\n  elif(b[0]==0):\n   print(n)\n  else:\n   print(-1)\n  continue\n pa=a.count(b[0])\n fa=a.count(b[1])\n if(pa!=b[1] or b[1]-b[0] != 1):\n  print(-1)\n  continue\n print(n-pa)'
_co = compile(_CODE, USER_FILENAME, "exec")
exec(_co, ns, ns)

```

Measured memory_bytes: 13495