#include<bits/stdc++.h>
#define pb push_back

#define f(i,a,b) for(int i=a;i<b;i++)
#define f1(i,a,b) for(int i=a;i<=b;i++)
#define int long long
using namespace std;
#define mod 1000000007
#define MAX 1e6
void SieveOfEratosthenes(int n, bool prime[], 
                         bool primesquare[], int a[]) 
{ 
    // Create a boolean array "prime[0..n]" and 
    // initialize all entries it as true. A value 
    // in prime[i] will finally be false if i is 
    // Not a prime, else true. 
    for (int i = 2; i <= n; i++) 
        prime[i] = true; 
  
    // Create a boolean array "primesquare[0..n*n+1]" 
    // and initialize all entries it as false. A value 
    // in squareprime[i] will finally be true if i is 
    // square of prime, else false. 
    for (int i = 0; i <= (n * n + 1); i++) 
        primesquare[i] = false; 
  
    // 1 is not a prime number 
    prime[1] = false; 
  
    for (int p = 2; p * p <= n; p++) { 
        // If prime[p] is not changed, then 
        // it is a prime 
        if (prime[p] == true) { 
            // Update all multiples of p 
            for (int i = p * 2; i <= n; i += p) 
                prime[i] = false; 
        } 
    } 
  
    int j = 0; 
    for (int p = 2; p <= n; p++) { 
        if (prime[p]) { 
            // Storing primes in an array 
            a[j] = p; 
  
            // Update value in primesquare[p*p], 
            // if p is prime. 
            primesquare[p * p] = true; 
            j++; 
        } 
    } 
} 
int countDivisors(int n) 
{ 
    // If number is 1, then it will have only 1 
    // as a factor. So, total factors will be 1. 
    if (n == 1) 
        return 1; 
  
    bool prime[n + 1], primesquare[n * n + 1]; 
  
    int a[n]; // for storing primes upto n 
  
    // Calling SieveOfEratosthenes to store prime 
    // factors of n and to store square of prime 
    // factors of n 
    SieveOfEratosthenes(n, prime, primesquare, a); 
  
    // ans will contain total number of distinct 
    // divisors 
    int ans = 1; 
  
    // Loop for counting factors of n 
    for (int i = 0;; i++) { 
        // a[i] is not less than cube root n 
        if (a[i] * a[i] * a[i] > n) 
            break; 
  
        // Calculating power of a[i] in n. 
        int cnt = 1; // cnt is power of prime a[i] in n. 
        while (n % a[i] == 0) // if a[i] is a factor of n 
        { 
            n = n / a[i]; 
            cnt = cnt + 1; // incrementing power 
        } 
  
        // Calculating the number of divisors 
        // If n = a^p * b^q then total divisors of n 
        // are (p+1)*(q+1) 
        ans = ans * cnt; 
    } 
  
    // if a[i] is greater than cube root of n 
  
    // First case 
    if (prime[n]) 
        ans = ans * 2; 
  
    // Second case 
    else if (primesquare[n]) 
        ans = ans * 3; 
  
    // Third case 
    else if (n != 1) 
        ans = ans * 4; 
  
    return ans; // Total divisors 
} 
int findDivisors(int n) 
{ 
  
    // Array to store the count 
    // of divisors 
    int div[n + 1]; 
    int sum=0;
    memset(div, 0, sizeof div); 
  
    // For every number from 1 to n 
    for (int i = 1; i <= n; i++) { 
  
        // Increase divisors count for 
        // every number divisible by i 
        for (int j = 1; j * i <= n; j++) 
            div[i * j]++; 
    } 
  
    // Print the divisors 
    for (int i = 1; i <= n; i++) 
        sum+=div[i];
    return sum;
} 
signed main()
{

    ios_base::sync_with_stdio(false);
    cin.tie(NULL);
    cout.tie(NULL);

    int n, sum = 0;
    cin >> n;

    cout<<findDivisors(n-1)<<endl;
    return 0;
}


Measured memory_bytes: 11408