Kefaa has developed a novel decomposition of a tree. He claims that this decomposition solves many difficult problems related to trees. However, he doesn't know how to find it quickly, so he asks you to help him.
You are given a tree with $N$ vertices numbered $1$ through $N$. Let's denote an edge between vertices $u$ and $v$ by $(u, v)$. The triple-tree decomposition is a partition of edges of the tree into unordered triples of edges $(a, b), (a, c), (a, d)$ such that $a \neq b \neq c \neq d$. Each edge must belong to exactly one triple.
Help Kefaa with this problem — find a triple-tree decomposition of the given tree or determine that no such decomposition exists.

-----Input-----
- The first line of the input contains a single integer $T$ denoting the number of test cases. The description of $T$ test cases follows.
- The first line of each test case contains a single integer $N$.
- Each of the following $N-1$ lines contains two space-separated integers $u$ and $v$ describing an edge between vertices $u$ and $v$ of the tree.

-----Output-----
- For each test case, print a line containing the string "YES" if a triple-tree decomposition of the given tree exists or "NO" otherwise.
- If it exists, print $\frac{N-1}{3}$ more lines describing a decomposition.
- Each of these lines should contain four space-separated integers $a$, $b$, $c$ and $d$ describing a triple of edges $(a, b), (a, c), (a, d)$.
If more than one triple-tree decomposition exists, you may output any one.

-----Constraints-----
- $1 \le T \le 100$
- $2 \le N \le 2 \cdot 10^5$
- $1 \le u, v \le N$
- the sum of $N$ over all test cases does not exceed $2 \cdot 10^5$

-----Subtasks-----
Subtask #1 (20 points): $2 \le N \le 10$
Subtask #2 (30 points):$2 \le N \le 5000$ and the sum of $N$ overall testcases doesn't exceed $5000$
Subtask #3 (50 points): original constraints

-----Example Input-----
2
4
1 2
1 3
1 4
7
1 2
2 3
1 4
4 5
1 6
6 7

-----Example Output-----
YES
1 2 3 4
NO

```python

USER_FILENAME = "<user_code>"
import sys, json, builtins
import math, heapq, bisect, itertools, functools, collections, statistics, fractions, decimal, operator, array, random, re, string, os, pathlib
try:
    import resource as _res
except Exception:
    _res = None
from collections import Counter, defaultdict, deque, OrderedDict
from functools import lru_cache, reduce
from itertools import accumulate, permutations, combinations, product
from math import gcd, ceil, floor, sqrt
from decimal import Decimal
try:
    from typing import *
except Exception:
    pass
try:
    sys.setrecursionlimit(1_000_000)
except Exception:
    pass
try:
    import site as _site
    try:
        _sys_sites = _site.getsitepackages() if hasattr(_site, "getsitepackages") else []
        for _p in _sys_sites:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
    try:
        _usp = _site.getusersitepackages()
        if isinstance(_usp, str):
            _usp = [_usp]
        for _p in _usp:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
except Exception:
    pass

ns = {"__name__": "__main__"}
for _k, _v in list(globals().items()):
    if not _k.startswith("_"):
        ns[_k] = _v
_CODE = '\ntest=int(input())\nfor t in range(test):\n n= int(input())\n\n adj=[[] for i in range(n+1)]\n\n for _ in range(n-1):\n  a,b=list(map(int,input().split()))\n  adj[a].append(b)\n  adj[b].append(a)\n \n\n #print(adj)\n root=1\n q,s=[root],set([root])\n\n for x in q:\n  adj[x]= [p for p in adj[x] if p not in s]\n  q.extend(adj[x])\n  s.update(adj[x])\n\n #print(adj)\n ans=True\n for i in range(n+1):\n  if(len(adj[i]) %3!=0):\n   ans=False\n if(ans):\n  print("YES")\n  for i in range(n+1):\n   while(len(adj[i])):\n    print(i,adj[i][0],adj[i][1],adj[i][2])\n    adj[i].pop(0)\n    adj[i].pop(0)\n    adj[i].pop(0)\n else:\n  print("NO")\n'
_co = compile(_CODE, USER_FILENAME, "exec")
exec(_co, ns, ns)

```

Measured memory_bytes: 13847