#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <algorithm>
#include <iostream>
#include <set>
#include <map>
#include <vector>
#include <string>

#include <cmath>
#include <queue>
#include <stack>

using namespace std;

#define LL long long

const int dx[4] = {1, -1, 0, 0};
const int dy[4] = {0, 0, 1, -1};

LL mod(LL x, LL md) {
	return ((x % md) + md) % md;
}

class Mint {
public:
	static LL md;
	LL x;
	Mint(LL _x = 0) {
		x = mod(_x, md);
	}
	Mint(const Mint &y) {
		x = mod(y.x, md);
	}
};

void MintMyExgcd(LL a, LL b, LL &x, LL &y) {
	// solve equation ax + by = 1 (mod m)
	LL md = Mint::md;
	if (b == 0) {
		y = 0;
		x = 1;
		return ;
	}
	MintMyExgcd(b, a % b, x, y);
	LL t = y;
	y = mod(x - (a / b) * y, md);
	x = t;
}

LL MintNY(LL x) {
	if (x == 0) {
		return 1;
	}
	LL md = Mint::md;
	LL a, b;
	MintMyExgcd(x, md, a, b);
	while (a < 0) {
		a += md;
	}
	return a;
}

/* LL gcd(LL a, LL b) {
	if (b == 0) {
		return a;
	}
	return gcd(b, a % b);
} */

Mint operator+(Mint a, Mint b) {
	return Mint(mod(a.x + b.x, Mint::md));
}
Mint operator-(Mint a, Mint b) {
	return Mint(mod(a.x - b.x, Mint::md));
}
Mint operator*(Mint a, Mint b) {
	return Mint(mod(a.x * b.x, Mint::md));
}
Mint operator/(Mint a, Mint b) {
	Mint c = Mint(MintNY(b.x));
	return Mint(mod(a.x * c.x, Mint::md));
}

Mint operator-(Mint a) {
	return Mint(-a.x);
}
bool operator==(Mint a, Mint b) {
	return a.x == b.x;
}
bool operator!=(Mint a, Mint b) {
	return a.x != b.x;
}
bool operator>(Mint a, Mint b) {
	return a.x > b.x;
}
bool operator<(Mint a, Mint b) {
	return a.x < b.x;
}
bool operator>=(Mint a, Mint b) {
	return a.x >= b.x;
}
bool operator<=(Mint a, Mint b) {
	return a.x <= b.x;
}

void operator+=(Mint &a, Mint b) {
	a = a + b;
}
void operator-=(Mint &a, Mint b) {
	a = a - b;
}
void operator*=(Mint &a, Mint b) {
	a = a * b;
}
void operator/=(Mint &a, Mint b) {
	a = a / b;
}

ostream& operator<<(ostream &out, Mint a) {
	out << a.x;
	return out;
}

istream& operator>>(istream &in, Mint &a) {
	in >> a.x;
	return in;
}

Mint factorial(LL n) {
	if (n == 0) {
		return Mint(1);
	}
	Mint res = 1;
	for (LL i = 1; i <= n; ++i) {
		res *= i;
	}
	return res;
}
Mint multiRange(LL s, LL t) {
	Mint res = 1;
	for (LL i = s; i <= t; ++i) {
		res *= i;
	}
	return res;
}

Mint getC(LL n, LL k) {
	if (n - k < k) {
		return getC(n, n - k);
	}
	return multiRange(n - k + 1, n) / factorial(k);
}

Mint getA(LL n, LL k) {
	return multiRange(n - k + 1, n);
}

Mint countNonNegativeDivision(LL n, LL k) {
	return getC(n + k - 1, k - 1);
}
Mint countPositiveDivision(LL n, LL k) {
	if (n < k) {
		return 0;
	}
	if (k <= 0) {
		return 0;
	}
	return getC(n - 1, k - 1);
}
Mint quickMod(Mint a, LL b) {
	Mint res = 1;
	while (b > 0) {
		if (b % 2) {
			res *= a;
		}
		a *= a;
		b /= 2;
	}
	return res;
}
template<class TypeName>
vector<TypeName> getVector1D(int n, TypeName val) {
    return vector<TypeName>(n, val);
}
template<class TypeName>
vector<vector<TypeName> > getVector2D(int n1, int n2, TypeName val) {
    vector<vector<TypeName> > res(n1);
    for (int i = 0; i < n1; ++i) {
        res[i] = vector<TypeName>(n2, val);
    }
    return res;
}
template<class TypeName>
vector<vector<vector<TypeName> > > getVector3D(int n1, int n2, int n3, TypeName val) {
    vector<vector<vector<TypeName> > > res(n1);
    for (int i = 0; i < n1; ++i) {
        res[i] = vector<vector<TypeName> >(n2);
        for (int j = 0; j < n2; ++j) {
            res[i][j] = vector<TypeName>(n3, val);
        }
    }
    return res;
}
template<class TypeName>
vector<vector<vector<vector<TypeName> > > > getVector4D(int n1, int n2, int n3, int n4, TypeName val) {
    vector<vector<vector<vector<TypeName> > > > res(n1);
    for (int i = 0; i < n1; ++i) {
        res[i] = vector<vector<vector<TypeName> > >(n2);
        for (int j = 0; j < n2; ++j) {
            res[i][j] = vector<vector<TypeName> >(n3);
            for (int k = 0; k < n3; ++k) {
                res[i][j][k] = vector<TypeName>(n4, val);
            }
        }
    }
    return res;
}

LL Mint::md = 1000000007;

int n, k;
vector<int> p;
int main() {
	cin >> n >> k;
	p = vector<int>(n);
	for (int i = 0; i < n; ++i) {
		cin >> p[i];
	}
	sort(p.begin(), p.end());
	int res = 0;
	for (int i = 0; i < k; ++i) {
		res += p[i];
	}
	cout << res << endl;
	return 0;
}

Measured memory_bytes: 3680