You are given an array $a$ of length $n$. A subsequence of this array is valid, if it satisfies these two conditions:
- There shouldn't be any two even numbers within a distance of $K$, both which have been chosen in the subsequence. i.e. there shouldn't be two indices $i, j$ such that $a_i$ and $a_j$ are even, $|i - j| \leq K$ and $a_i$ and $a_j$ are in the subsequence. 
- Similarly, there shouldn't be any two odd numbers within a distance of $K$, both which have been chosen in the subsequence
The sum of a subsequence is the sum of all the numbers in it. Your task is find the maximum sum possible in a valid subsequence of the given array. Print this maximum sum.

-----Input-----
- The first line of the input contains an integer $T$ denoting the number of test cases. The description of the test cases follows.
- The first line of each test case contains two space-separated integers $n, k$.
- The second line of each test case contains $n$ space-separated integers denoting the array $a$.

-----Output-----
For each test case, output an integer corresponding to the answer of the problem.

-----Constraints-----
- $1 \le T \le 10^5$
- $1 \le n \leq 10^5$
- $1 \le k \leq  n$
- $1 \le a_i \leq 10^9$
- Sum of $n$ over all the test cases doesn't exceed $10^6$

-----Example Input-----
3
1 1
3
2 1
2 2
5 2
1 2 3 4 6

-----Example Output-----
3
2
11

-----Explanation:-----
Testcase 2: Only one of the two 2s can be chosen. Hence the answer is 2.
Testcase 3: The subsequence containing the second, third and fifth numbers is a valid subsequence, and its sum is 2+3+6 = 11. You can check that this is the maximum possible, and hence is the answer.

```python

USER_FILENAME = "<user_code>"
import sys, json, builtins
import math, heapq, bisect, itertools, functools, collections, statistics, fractions, decimal, operator, array, random, re, string, os, pathlib
try:
    import resource as _res
except Exception:
    _res = None
from collections import Counter, defaultdict, deque, OrderedDict
from functools import lru_cache, reduce
from itertools import accumulate, permutations, combinations, product
from math import gcd, ceil, floor, sqrt
from decimal import Decimal
try:
    from typing import *
except Exception:
    pass
try:
    sys.setrecursionlimit(1_000_000)
except Exception:
    pass
try:
    import site as _site
    try:
        _sys_sites = _site.getsitepackages() if hasattr(_site, "getsitepackages") else []
        for _p in _sys_sites:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
    try:
        _usp = _site.getusersitepackages()
        if isinstance(_usp, str):
            _usp = [_usp]
        for _p in _usp:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
except Exception:
    pass

ns = {"__name__": "__main__"}
for _k, _v in list(globals().items()):
    if not _k.startswith("_"):
        ns[_k] = _v
_CODE = 'def ii():\n return int(input())\ndef mi():\n return list(map(int, input().split()))\ndef li():\n return list(mi())\nfrom collections import deque\n\nfor t in range(ii()):\n n, k = mi()\n a = [0] + li()\n\n def solve(a, k):\n  n = len(a)\n  dp = [0] * n\n  d = deque()\n  d.append((0, 0))\n  for i in range(1, n):\n   if i - d[0][0] > k:\n    d.popleft()\n   dp[i] = max(d[0][1], a[i] + (dp[i - k - 1] if i >= k + 1 else 0))\n   while d and d[-1][1] <= dp[i]:\n    d.pop()\n   d.append((i, dp[i]))\n  return d[0][1]\n\n\n odd = solve([x if x % 2 else 0 for x in a], k)\n even = solve([0 if x % 2 else x for x in a], k)\n print(odd + even)\n'
_co = compile(_CODE, USER_FILENAME, "exec")
exec(_co, ns, ns)

```

Measured memory_bytes: 14179