#include<algorithm>//sort,二分探索,など
#include<bitset>//固定長bit集合
#include<cmath>//pow,logなど
#include<complex>//複素数
#include<deque>//両端アクセスのキュー
#include<functional>//sortのgreater
#include<iomanip>//setprecision(浮動小数点の出力の誤差)
#include<iostream>//入出力
#include<iterator>//集合演算(積集合,和集合,差集合など)
#include<map>//map(辞書)
#include<numeric>//iota(整数列の生成),gcdとlcm(c++17)
#include<queue>//キュー
#include<set>//集合
#include<stack>//スタック
#include<string>//文字列
#include<unordered_map>//イテレータあるけど順序保持しないmap
#include<unordered_set>//イテレータあるけど順序保持しないset
#include<utility>//pair
#include<vector>//可変長配列

#define rep(i,n) for (int i = 0; i < (n); ++i)
#define erep(i,n) for (int i = 0; i <= (n); ++i)
#define brep(i,n) for (int i = n; i >= 0; i--)
#define PI 3.14159265359
using namespace std;
using P = pair<int,int>;
using ll = long long;
using Graph = vector<vector<int> > ;
const int INF = 100005;
const int MAX_K = 55;
const int MAX_W = 200005; 
const int MAX = 510000;
const int MOD = 1000000007;
long long fac[MAX], finv[MAX], inv[MAX];

// ユークリッド互除法
unsigned gcd(unsigned a, unsigned b) {
  while(1) {
    if(a < b) swap(a, b);
    if(!b) break;
    a %= b;
  }
  return a;
}

// テーブルを作る前処理
void COMinit() {
    fac[0] = fac[1] = 1;
    finv[0] = finv[1] = 1;
    inv[1] = 1;
    for (int i = 2; i < MAX; i++){
        fac[i] = fac[i - 1] * i % MOD;
        inv[i] = MOD - inv[MOD%i] * (MOD / i) % MOD;
        finv[i] = finv[i - 1] * inv[i] % MOD;
    }
}

// 二項係数計算
long long COM(int n, int k){
    if (n < k) return 0;
    if (n < 0 || k < 0) return 0;
    return fac[n] * (finv[k] * finv[n - k] % MOD) % MOD;
}

/*
int main() {
    // 前処理
    COMinit();

    // 計算例
    cout << COM(100000, 50000) << endl;
}
*/

struct mint {
  ll x; // typedef long long ll;
  mint(ll x=0):x((x%MOD+MOD)%MOD){}
  mint operator-() const { return mint(-x);}
  mint& operator+=(const mint a) {
    if ((x += a.x) >= MOD) x -= MOD;
    return *this;
  }
  mint& operator-=(const mint a) {
    if ((x += MOD-a.x) >= MOD) x -= MOD;
    return *this;
  }
  mint& operator*=(const mint a) { (x *= a.x) %= MOD; return *this;}
  mint operator+(const mint a) const { return mint(*this) += a;}
  mint operator-(const mint a) const { return mint(*this) -= a;}
  mint operator*(const mint a) const { return mint(*this) *= a;}
  mint pow(ll t) const {
    if (!t) return 1;
    mint a = pow(t>>1);
    a *= a;
    if (t&1) a *= *this;
    return a;
  }

  // for prime MOD
  mint inv() const { return pow(MOD-2);}
  mint& operator/=(const mint a) { return *this *= a.inv();}
  mint operator/(const mint a) const { return mint(*this) /= a;}
};
istream& operator>>(istream& is, const mint& a) { return is >> a.x;}
ostream& operator<<(ostream& os, const mint& a) { return os << a.x;}

const int dx[4] = {-1,0,1,0};
const int dy[4] = {0,1,0,-1};

map<ll,ll> mp;
ll n,a,b,c,d;


ll solve(ll n){
    if(n == 0) return 0;
    if(mp.count(n)) return mp[n];
    ll ans = 1e18;
    if(n <= 2e9) ans = n*d;

    for(int p=-1; p<=1;p++){
        ll x = n + p;
        if(x%2 != 0 || x<0) continue;
        ll y = x/2;
        if(y < n)
        ans = min(ans,abs(p)*d + a + solve(y));
    }
    for(int p =-2; p<=2; p++){
        ll x = n + p;
        if(x%3 !=0 || x < 0) continue;
        ll y = x/3;
        if(y < n)
        ans = min(ans,abs(p)*d + b + solve(y));
    }
    for(int p = -4; p<= 4 ; p++){
        ll x = n + p;
        if(x%5 !=0 || x < 0) continue;
        ll y = x/5;
        if(y < n)
        ans = min(ans,abs(p)*d + c+ solve(y));
    }

    return mp[n] = ans ;
}

int main(){
    int t;
    cin >> t;
    rep(i,t){
        mp.clear();
        cin >> n >> a >> b >> c >> d;
        cout << solve(n) << endl;
    }
}

Measured memory_bytes: 4400