// Author : Naresh Bharasagar
// Instt. : Indian Institute of Technology Guwahati

//--------------------------------------------------------------------------------------------------------------------------------

#include<bits/stdc++.h>
using namespace std;
typedef long long int loo;
typedef long double ld;

#pragma GCC target ("sse4.2")
#define loop(i,begin,end) for(__typeof(end)i=(begin)-((begin)>(end));i!=(end)-((begin)>(end));i+=1-2*((begin)>(end)))
#define loopset(it,val,dtype) for(set<dtype>::iterator it=val.begin(); it!=val.end(); it++)
#define fast_io ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL);
#define vloo vector<loo>
#define vi vector<int>
#define pi pair<int,int>
#define mp make_pair
#define ploo pair<loo,loo>
#define fillz(a) memset(a,0,sizeof(a))
#define outa(a,n) loop(i,0,n) cout << a[i] << " ";
#define pr(a) cout << a << "\n";
#define pb(l) push_back(l)
#define ff first
#define ss second
#define input(a) for(auto &i: a) cin >> i;
#define deb0(i) cout << "[" << #i << "=" << i << "]" << endl;
#define nl cout << "\n";
#define INF 1000000000
#define M 1000000007

loo power(loo x, loo y, loo p) { 
    loo res = 1;
    x = x % p;
    while (y > 0) { 
        if (y & 1) res = (res*x) % p; 
        y = y>>1;
        x = (x*x) % p;   
    } 
    return res; 
}

loo power(loo x, loo y) { 
    loo temp; 
    if( y == 0) 
        return 1; 
    temp = power(x, y/2); 
    if (y%2 == 0) 
        return temp*temp; 
    else
        return x*temp*temp; 
}

bool sortbysec(const pair<loo,loo> &a, const pair<loo,loo> &b) { 
    return (a.second > b.second); 
}

string decToBin(loo n) {
	string s = "0";
	if(n == 0) return s;
	s = "";
    while (n > 0) { 
        s += (n % 2) + '0';
        n = n / 2;
    }
    reverse(s.begin(), s.end());
    return s;
}
 
loo binToDec(string s) {
    loo ans = 0;
    reverse(s.begin(), s.end());
    loop(i, 0, s.size()) ans += pow(2, i)*(s[i] - '0');
    return ans;
}

loo andOperator(loo a, loo b){ 
    string sa = decToBin(a);
    string sb = decToBin(b);
    loo sza=sa.size(), szb=sb.size();
    if(sza>szb) loop(i,0,sza-szb) sb = "0"+sb;
    else if(szb>sza) loop(i,0,szb-sza) sa = "0"+sa;
    string res = "";
    loop(i,0,sa.size()) {
        if(sa[i]=='1' && sb[i]=='1') res+="1";
        else res+="0";
    }
    return binToDec(res);
}

loo orOperator(loo a,loo b) {
    string sa = decToBin(a);
    string sb = decToBin(b);
    loo sza=sa.size(), szb=sb.size();
    if(sza>szb) {
        loop(i,0,sza-szb) sb = "0"+sb;
    }
    else if(szb>sza) {
        loop(i,0,szb-sza) sa = "0"+sa;
    }
    string res = "";
    loop(i,0,sa.size()) {
        if(sa[i]=='0' && sb[i]=='0') res+="0";
        else res+="1";
    }
    return binToDec(res);
}

loo nCr(loo n, loo r) {
    loo p = 1, k = 1; 
    if (n - r < r) 
        r = n - r; 
    if (r != 0) { 
        while (r) { 
            p *= n; 
            k *= r; 
            loo m = __gcd(p, k); 
            p /= m; 
            k /= m; 
            n--; 
            r--; 
        }
    } 
    else p = 1; 
    return p; 
}

// vector<int> dist;
vector<bool> vis(100001,false);
void dfs(vector<loo> adj[], loo src) {
    vis[src]=true;
    loop(i,0,adj[src].size()) {
        loo x = adj[src][i];
        if(vis[x]==false) {
            vis[x]=true;
            // dist[x] = dist[src]+1;
            dfs(adj,x);
        }
    }
}

// vector<loo> sg(100001,-1); //prev
void bfs(vector<loo> adj[], loo src) {
    list<loo> ql;
    vis[src]=true;
    ql.pb(src);
    while(!(ql.empty())) {
        src = ql.front();
        // cout << src << " ";
        ql.pop_front();

        loop(i,0,adj[src].size()) {
            if(!vis[adj[src][i]]) {
                vis[adj[src][i]]=true;
                // sg[adj[src][i]]=src;
                ql.pb(adj[src][i]);
            }
        }
    }
}

// ----------------------------------------------------------------

void printString(loo n) 
{ 
    char str[1000]; // To store result (Excel column name) 
    loo i = 0; // To store current index in str which is result 
  
    while (n > 0) { 
        // Find remainder 
        loo rem = n % 26; 
  
        // If remainder is 0, then a 'Z' must be there in output 
        if (rem == 0) { 
            str[i++] = 'z'; 
            n = (n / 26) - 1; 
        } 
        else // If remainder is non-zero 
        { 
            str[i++] = (rem - 1) + 'a'; 
            n = n / 26; 
        } 
    } 
    str[i] = '\0'; 
  
    // Reverse the string and print result 
    reverse(str, str + strlen(str)); 
    cout << str << endl; 
  
    return; 
} 

void solve() {
    loo n;
    cin >> n;
    printString(n);
}

int main() {
	fast_io

    // freopen("filename.in","r",stdin);
    // freopen("filename.out","w",stdout);

    loo q = 1;
    // cin >> q;
    while(q--) {
        solve();
    }

    return 0;
}

Measured memory_bytes: 3688