Vasya is an active Internet user. One day he came across an Internet resource he liked, so he wrote its address in the notebook. We know that the address of the written resource has format: <protocol>://<domain>.ru[/<context>] 

where:  <protocol> can equal either "http" (without the quotes) or "ftp" (without the quotes),  <domain> is a non-empty string, consisting of lowercase English letters,  the /<context> part may not be present. If it is present, then <context> is a non-empty string, consisting of lowercase English letters. 

If string <context> isn't present in the address, then the additional character "/" isn't written. Thus, the address has either two characters "/" (the ones that go before the domain), or three (an extra one in front of the context).

When the boy came home, he found out that the address he wrote in his notebook had no punctuation marks. Vasya must have been in a lot of hurry and didn't write characters ":", "/", ".".

Help Vasya to restore the possible address of the recorded Internet resource.


-----Input-----

The first line contains a non-empty string that Vasya wrote out in his notebook. This line consists of lowercase English letters only. 

It is guaranteed that the given string contains at most 50 letters. It is guaranteed that the given string can be obtained from some correct Internet resource address, described above.


-----Output-----

Print a single line — the address of the Internet resource that Vasya liked. If there are several addresses that meet the problem limitations, you are allowed to print any of them.


-----Examples-----
Input
httpsunrux

Output
http://sun.ru/x

Input
ftphttprururu

Output
ftp://http.ru/ruru



-----Note-----

In the second sample there are two more possible answers: "ftp://httpruru.ru" and "ftp://httpru.ru/ru".

```python

USER_FILENAME = "<user_code>"
import sys, json, builtins
import math, heapq, bisect, itertools, functools, collections, statistics, fractions, decimal, operator, array, random, re, string, os, pathlib
try:
    import resource as _res
except Exception:
    _res = None
from collections import Counter, defaultdict, deque, OrderedDict
from functools import lru_cache, reduce
from itertools import accumulate, permutations, combinations, product
from math import gcd, ceil, floor, sqrt
from decimal import Decimal
try:
    from typing import *
except Exception:
    pass
try:
    sys.setrecursionlimit(1_000_000)
except Exception:
    pass
try:
    import site as _site
    try:
        _sys_sites = _site.getsitepackages() if hasattr(_site, "getsitepackages") else []
        for _p in _sys_sites:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
    try:
        _usp = _site.getusersitepackages()
        if isinstance(_usp, str):
            _usp = [_usp]
        for _p in _usp:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
except Exception:
    pass

ns = {"__name__": "__main__"}
for _k, _v in list(globals().items()):
    if not _k.startswith("_"):
        ns[_k] = _v
_CODE = 'n = input()\ni = 0\nz = len(n) - 1\nres = ""\nend = 0\nif n[0] == \'f\':\n    res += \'ftp://\'\n    i += 3\nelif n[0] == \'h\':\n    res += \'http://\'\n    i += 4\nwhile i < z:\n    if n[i] == \'r\' and n[i + 1] == \'u\':\n        if res[len(res) - 1:len(res)] == \'/\':\n            res += n[i]\n            i += 1\n        else:\n            res += ".ru/"\n            i += 2\n            end = i\n            break\n    else:\n        res += n[i]\n        i += 1\nresult = res + n[end:]\nif result[len(result) - 1:len(result)] == \'/\':\n    print(result[:len(result) - 1])\nelse:\n    print(result)\n'
_co = compile(_CODE, USER_FILENAME, "exec")
exec(_co, ns, ns)

```

Measured memory_bytes: 13305