#include <iostream>
#include <sstream>
#include <cstdio>
#include <cstdlib>
#include <cmath>
#include <ctime>
#include <cstring>
#include <string>
#include <vector>
#include <stack>
#include <queue>
#include <deque>
#include <map>
#include <set>
#include <bitset>
#include <numeric>
#include <utility>
#include <iomanip>
#include <algorithm>
#include <functional>
#include <unordered_map>
using namespace std;

template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }
template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }

#define COUT(x) cout << #x << " = " << (x) << " (L" << __LINE__ << ")" << endl
template<class T1, class T2> ostream& operator << (ostream &s, pair<T1,T2> P)
{ return s << '<' << P.first << ", " << P.second << '>'; }
template<class T> ostream& operator << (ostream &s, vector<T> P)
{ for (int i = 0; i < P.size(); ++i) { if (i > 0) { s << " "; } s << P[i]; } return s; }
template<class T> ostream& operator << (ostream &s, vector<vector<T> > P)
{ for (int i = 0; i < P.size(); ++i) { s << endl << P[i]; } return s << endl; }

#define EACH(i, s) for (__typeof__((s).begin()) i = (s).begin(); i != (s).end(); ++i)
template<class T> ostream& operator << (ostream &s, set<T> P)
{ EACH(it, P) { s << "<" << *it << "> "; } return s << endl; }
template<class T1, class T2> ostream& operator << (ostream &s, map<T1,T2> P)
{ EACH(it, P) { s << "<" << it->first << "->" << it->second << "> "; } return s << endl; }

template<class T> vector<T> make_vec(size_t a) { return vector<T>(a); }
template<class T, class... Ts> auto make_vec(size_t a, Ts... ts) {
  return vector<decltype(make_vec<T>(ts...))>(a, make_vec<T>(ts...));
}
template<class T, class V>
typename enable_if<is_class<T>::value == 0>::type fill(T &t, const V &v) {
    t = v;
}
template<class T, class V>
typename enable_if<is_class<T>::value != 0>::type fill(T &t, const V &v){
    for (auto &e : t) fill(e, v);
}



struct RollingHash {
    static const int base1 = 1007, base2 = 2009;
    static const int mod1 = 1000000007, mod2 = 1000000009;
    vector<long long> hash1, hash2, power1, power2;

    // construct
    RollingHash(const vector<long long> &S) {
        int n = (int)S.size();
        hash1.assign(n+1, 0);
        hash2.assign(n+1, 0);
        power1.assign(n+1, 1);
        power2.assign(n+1, 1);
        for (int i = 0; i < n; ++i) {
            hash1[i+1] = (hash1[i] * base1 + S[i]) % mod1;
            hash2[i+1] = (hash2[i] * base2 + S[i]) % mod2;
            power1[i+1] = (power1[i] * base1) % mod1;
            power2[i+1] = (power2[i] * base2) % mod2;
        }
    }
    
    // get hash of S[left:right]
    inline pair<long long, long long> get(int l, int r) const {
        long long res1 = hash1[r] - hash1[l] * power1[r-l] % mod1;
        if (res1 < 0) res1 += mod1;
        long long res2 = hash2[r] - hash2[l] * power2[r-l] % mod2;
        if (res2 < 0) res2 += mod2;
        return {res1, res2};
    }

    // get lcp of S[a:] and S[b:]
    inline int getLCP(int a, int b) const {
        int len = min((int)hash1.size()-a, (int)hash1.size()-b);
        int low = 0, high = len;
        while (high - low > 1) {
            int mid = (low + high) >> 1;
            if (get(a, a+mid) != get(b, b+mid)) high = mid;
            else low = mid;
        }
        return low;
    }

    // get lcp of S[a:] and T[b:]
    inline int getLCP(const RollingHash &T, int a, int b) const {
        int len = min((int)hash1.size()-a, (int)hash1.size()-b);
        int low = 0, high = len;
        while (high - low > 1) {
            int mid = (low + high) >> 1;
            if (get(a, a+mid) != T.get(b, b+mid)) high = mid;
            else low = mid;
        }
        return low;
    }
};


int N;
vector<long long> a, b;

void solve() {
    vector<long long> da(N*2), db(N*2);
    for (int i = 0; i < N*2; ++i) {
        int j = i % N;
        int k = (i + 1) % N;
        da[i] = a[j] ^ a[k];
        db[i] = b[j] ^ b[k];
    }

    RollingHash A(da), B(db);
    for (int k = 0; k < N; ++k) {
        int len = A.getLCP(B, k, 0);
        if (len >= N) {
            cout << k << " " << (a[k] ^ b[0]) << endl;
        }
    }
}

int main() {
    ios::sync_with_stdio(false);
    cin.tie(0);
    
    while (cin >> N) {
        a.resize(N); b.resize(N);
        for (int i = 0; i < N; ++i) cin >> a[i];
        for (int i = 0; i < N; ++i) cin >> b[i];
        solve();
    }
}


















Measured memory_bytes: 37888