#include <bits/stdc++.h> //library
#define rep(i, n) for(int i = 0; i < (int)(n); i++) //for-loop (from 0)
#define reps(i,n) for(int i = 1; i <= (int)(n); i++) //for-loop (from 1)
#define all(x) (x).begin(),(x).end() //start-to-end iteration, mainly in upper_bound, lower_bound
#define SZ(x) ((int)(x).size()) //unsigned to signed

using namespace std;
using ll = long long; //long long
ll M = 1000000000 + 7;

template<class T>bool chmax(T &a, const T &b) { if (a<b) { a = b; return 1; } return 0; } //compare a,b and replace by greater
template<class T>bool chmin(T &a, const T &b) { if (b<a) { a = b; return 1; } return 0; } //compare a,b and replace by smaller
ll qp(int a, ll b) { int ans = 1; do { if (b & 1)ans = 1ll * ans*a; a = 1ll * a*a; } while (b >>= 1); return ans; } //power
ll qp(int a, ll b, ll Mod = M) { int ans = 1; do { if (b & 1)ans = 1ll * ans*a%Mod; a = 1ll * a*a%Mod; } while (b >>= 1); return ans; } //power(mod)
int gcd(int a, int b) { return b ? gcd(b, a%b) : a; } //gcd
int dx[4] = { 1,0,-1,0 }; //path
int dy[4] = { 0,1,0,-1 }; //path
ll RS(ll N, ll P, ll Mod = M) { if (P == 0)return 1; else if (P % 2 == 0) { ll sq = RS(N, P / 2, Mod); return sq*sq%Mod; } else { return N*RS(N, P - 1, Mod) % Mod; } } //power(mod)(repeat-square,fast)
ll nPr(ll n, ll r, ll Mod = M) { ll ans = 1; rep(i, r) { ans = ans * (n - i) % Mod; } return ans; } //permutation
ll nCr(ll n, ll r, ll Mod = M) { ll bunbo = 1; ll bunshi = 1; rep(i, r) { bunbo = bunbo * (i + 1) % Mod; bunshi = bunshi * (n - i) % Mod; } return bunshi * RS(bunbo, Mod - 2, Mod) % Mod; } //combination

using Edge = pair<int, int>; //エッジ(本問題では使わない))
using Graph = vector<vector<int>>;	//グラフ

Graph G,B;
vector<int> ans;

struct UnionFind {
    vector<int> par; // par[i]:iの親の番号　(例) par[3] = 2 : 3の親が2
    vector<int> par_num;
  
    UnionFind(int N) : par(N) { //最初は全てが根であるとして初期化
        for(int i = 0; i < N; i++) par[i] = i;
        par_num.assign(N,1);
    }

    int root(int x) { // データxが属する木の根を再帰で得る：root(x) = {xの木の根}
        if (par[x] == x) return x;
        return par[x] = root(par[x]);
    }

    void unite(int x, int y) { // xとyの木を併合
        int rx = root(x); //xの根をrx
        int ry = root(y); //yの根をry
        if (rx == ry) return; //xとyの根が同じ(=同じ木にある)時はそのまま
        par[rx] = ry; //xとyの根が同じでない(=同じ木にない)時：xの根rxをyの根ryにつける
        par_num[root(rx)]++;
    }

    bool same(int x, int y) { // 2つのデータx, yが属する木が同じならtrueを返す
        int rx = root(x);
        int ry = root(y);
        return rx == ry;
    }
};

int vector_finder(std::vector<int> vec, int number) {
  auto itr = std::find(vec.begin(), vec.end(), number);
  size_t index = std::distance( vec.begin(), itr );
  if (index != vec.size()) { // 発見できたとき
    return 1;
  }
  else { // 発見できなかったとき
    return 0;
  }
}

int main(void) {
  int N,M,K; cin >> N >> M >> K;
  UnionFind tree(N);
  ans.assign(N,0);
  G.assign(N, vector<int>());
  for (int i = 0; i < M; i++) {
    int u, v; cin >> u >> v;
    u--, v--;
    G[u].push_back(v);
    G[v].push_back(u);
    tree.unite(u,v);
  }
  B.assign(N, vector<int>());
  for (int i = 0; i < K; i++) {
    int u, v; cin >> u >> v;
    u--, v--;
    B[u].push_back(v);
    B[v].push_back(u);
  }
  
  vector<int> root_num(N,0);
  
  rep(i,N){
    root_num[tree.root(i)]++;
  }
  
  rep(i,N){
    ans[i] += root_num[tree.root(i)];
    ans[i]-=1;//自分自身
    ans[i]-=G[i].size();//友達
    for (auto nv: B[i]){
      if (tree.same(i,nv)) ans[i] -= 1;
    }
  }
  
  rep(i,N) cout << ans[i] << " ";
  cout << endl;
  
  return 0;
}

Measured memory_bytes: 13816