Acacius is studying strings theory. Today he came with the following problem.

You are given a string $s$ of length $n$ consisting of lowercase English letters and question marks. It is possible to replace question marks with lowercase English letters in such a way that a string "abacaba" occurs as a substring in a resulting string exactly once?

Each question mark should be replaced with exactly one lowercase English letter. For example, string "a?b?c" can be transformed into strings "aabbc" and "azbzc", but can't be transformed into strings "aabc", "a?bbc" and "babbc".

Occurrence of a string $t$ of length $m$ in the string $s$ of length $n$ as a substring is a index $i$ ($1 \leq i \leq n - m + 1$) such that string $s[i..i+m-1]$ consisting of $m$ consecutive symbols of $s$ starting from $i$-th equals to string $t$. For example string "ababa" has two occurrences of a string "aba" as a substring with $i = 1$ and $i = 3$, but there are no occurrences of a string "aba" in the string "acba" as a substring.

Please help Acacius to check if it is possible to replace all question marks with lowercase English letters in such a way that a string "abacaba" occurs as a substring in a resulting string exactly once.


-----Input-----

First line of input contains an integer $T$ ($1 \leq T \leq 5000$), number of test cases. $T$ pairs of lines with test case descriptions follow.

The first line of a test case description contains a single integer $n$ ($7 \leq n \leq 50$), length of a string $s$.

The second line of a test case description contains string $s$ of length $n$ consisting of lowercase English letters and question marks.


-----Output-----

For each test case output an answer for it.

In case if there is no way to replace question marks in string $s$ with a lowercase English letters in such a way that there is exactly one occurrence of a string "abacaba" in the resulting string as a substring output "No".

Otherwise output "Yes" and in the next line output a resulting string consisting of $n$ lowercase English letters. If there are multiple possible strings, output any.

You may print every letter in "Yes" and "No" in any case you want (so, for example, the strings yEs, yes, Yes, and YES will all be recognized as positive answer).


-----Example-----
Input
6
7
abacaba
7
???????
11
aba?abacaba
11
abacaba?aba
15
asdf???f???qwer
11
abacabacaba

Output
Yes
abacaba
Yes
abacaba
Yes
abadabacaba
Yes
abacabadaba
No
No



-----Note-----

In first example there is exactly one occurrence of a string "abacaba" in the string "abacaba" as a substring.

In second example seven question marks can be replaced with any seven lowercase English letters and with "abacaba" in particular.

In sixth example there are two occurrences of a string "abacaba" as a substring.

```python

USER_FILENAME = "<user_code>"
import sys, json, builtins
import math, heapq, bisect, itertools, functools, collections, statistics, fractions, decimal, operator, array, random, re, string, os, pathlib
try:
    import resource as _res
except Exception:
    _res = None
from collections import Counter, defaultdict, deque, OrderedDict
from functools import lru_cache, reduce
from itertools import accumulate, permutations, combinations, product
from math import gcd, ceil, floor, sqrt
from decimal import Decimal
try:
    from typing import *
except Exception:
    pass
try:
    sys.setrecursionlimit(1_000_000)
except Exception:
    pass
try:
    import site as _site
    try:
        _sys_sites = _site.getsitepackages() if hasattr(_site, "getsitepackages") else []
        for _p in _sys_sites:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
    try:
        _usp = _site.getusersitepackages()
        if isinstance(_usp, str):
            _usp = [_usp]
        for _p in _usp:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
except Exception:
    pass

ns = {"__name__": "__main__"}
for _k, _v in list(globals().items()):
    if not _k.startswith("_"):
        ns[_k] = _v
_CODE = 'import sys\nINF = 10**20\nMOD = 10**9 + 7\nI = lambda:list(map(int,input().split()))\nfrom math import gcd\nfrom math import ceil\nfrom collections import defaultdict as dd, Counter\nfrom bisect import bisect_left as bl, bisect_right as br\n\n\n"""\nFacts and Data representation\nConstructive? Top bottom up down\n"""\ndef check(s):\n  t = \'abacaba\'\n  ans = 0\n  for i in range(len(s)):\n    if s[i: i + 7] == t:\n      ans += 1\n  return ans\n\ndef solve():\n  n, = I()\n  s = input()\n  t = \'abacaba\'\n  cnt = check(s)\n  if cnt > 1:\n    print(\'No\')\n    return\n  elif cnt == 1:\n    s = list(s)\n    for i in range(n):\n      if s[i] == \'?\':\n        s[i] = \'z\'\n    print(\'Yes\')\n    print(\'\'.join(s))\n  else:\n    s = list(s)\n    ok = s[::]\n    for i in range(n - 6):\n      ok = s[::]\n      for j in range(7):\n        if s[i + j] == t[j]:\n          continue\n        elif s[i + j] == \'?\':\n          ok[i + j] = t[j]\n        else:\n          break\n      else:\n        for i in range(n):\n          if ok[i] == \'?\':\n            ok[i] = \'z\'\n        ok = \'\'.join(ok)\n        if check(ok) != 1:\n          continue\n        print(\'Yes\')\n        print(ok)\n        return\n    print(\'No\')\n\nt, = I()\nwhile t:\n  t -= 1\n  solve()'
_co = compile(_CODE, USER_FILENAME, "exec")
exec(_co, ns, ns)

```

Measured memory_bytes: 14161