#include <bits/stdc++.h>

using namespace std;

#define pb push_back
#define mp make_pair
#define mt make_tuple
#define fi first
#define se second
#define all(a) (a).begin(),(a).end()
#define endl "\n"
#define rep(i, a, b) for (auto (i) = (a); (i) < (b); (i)++)
#define rrep(i, a, b) for (auto (i) = (a); (i) > (b); (i)--)

#define aim_cpo do{ios::sync_with_stdio(false);\
cin.tie(nullptr);cout.precision(12);cout<<fixed;}while(0)

#define LOCAL_INPUT do{FILE *stream1;\
stream1=freopen("/Users/aim_cpo/CLionProjects/competitive/in.txt","r",stdin);\
if(stream1==nullptr)return 0;}while(0)
#define LOCAL_OUTPUT do{FILE *stream2;\
stream2 = freopen("out.txt", "w", stdout);\
if (stream2 == nullptr) return 0;}while(0)

#ifdef LOCAL_DEFINE
#define show(x) cerr << #x << " = " << (x) << endl
#define dump(x) cerr << #x << " = " << (x) << " (line " << __LINE__ << ")" << endl
#define showV(v, n) do{\
for(int _i_t_e_=0; _i_t_e_<(n);_i_t_e_++)\
cerr<<"("<<_i_t_e_<<" = "<<(v)[_i_t_e_]<<") ";\
cerr<<endl;}while(0)
#define showA(a, n) do{\
for(int _i_t_e_=0;_i_t_e_<(n);_i_t_e_++)\
cerr<<"("<<_i_t_e_<<" = "<<(a)[_i_t_e_]<<") ";\
cerr<<endl;}while(0)
#define showA2(a, n, m) do{\
for(int _i_t_e_=0;_i_t_e_<(n);_i_t_e_++){\
for(int _i_t_e_2=0;_i_t_e_2<(m);_i_t_e_2++){\
cerr<<"("<<_i_t_e_<<", "<<_i_t_e_2<<" = "<<(a)[_i_t_e_][_i_t_e_2]<<") ";\
}cerr<<endl;}cerr<<endl;}while(0)
#else
#define show(x)
#define dump(x)
#define showV(v, n)
#define showA(a, n)
#define showA2(a, n, m)
#endif

typedef long long ll;
typedef unsigned long long ull;

constexpr const int INT_INF=0x3f3f3f3f; //1061109567
constexpr const ll LL_INF=0x3f3f3f3f3f3f3f3f; //4557430888798830399

template <typename T> bool chmin(T &a, T b){return a>b?(a=b,true):false;}
template <typename T> bool chmax(T &a, T b){return a<b?(a=b,true):false;}
template <typename T> void ln(T i, T n){cout<<(i==n-1?"\n":" ");}
template <typename T, typename S>
ostream &operator<<(ostream &out,const pair<T, S> &pair1){
  out<<'('<<pair1.fi<<", "<<pair1.se<<')';return out;}
template <typename T>
ostream &operator<<(ostream &out,const vector<T> &vector1){
  out<<'[';for(unsigned int i=0;i<vector1.size();i++){
    out<<vector1[i];if(i==vector1.size()-1)out<<"]";else out<<", ";
  }return out;
}

// INT
#define GCD(a, b) __gcd(a, b)
template <typename T> T LCM(T a, T b) {return a / GCD(a, b) * b;}
template <typename T> T EXTGCD(T a, T b, T& x, T& y) {
  T d = a;
  if (b != 0) {d=EXTGCD(b,a%b,y,x);y-=(a/b)*x;}
  else x=1,y=0;
  return d;
}
template <typename T> bool is_prime(T a) {
  for(int i=2;i*i<=a;i++)if(a%i==0)return 1;
  return 0;
}
template <typename T, typename S> T Pow(T a, S b) {
  T res = 1, now = a;
  while(b){if(b&1)res*=now;b>>=1;now*=now;}return res;
}

// MOD
ll MOD = 1000000000L + 7L;
#define add(a, b) ((a % MOD) + (b % MOD)) % MOD
#define mul(a, b) ((a % MOD) * (b % MOD)) % MOD
#define sub(a, b) ((a % MOD) + MOD - (b % MOD)) % MOD
template <typename T, typename S> T ModPow(T a, S b) {
  T res = 1, now = a;
  while(b){if(b&1)res=mul(res,now);b>>=1;now=mul(now,now);}return res;
}
template <typename T> T mod_inverse(T a, T mod, bool prime){ // if mod is prime, "prime" is true.
  if(prime)return ModPow(a, mod - 2);
  else{T x,y;EXTGCD(a,mod,x,y);return (mod+x%mod)%mod;}
}
#define divide(a, b) ((a % MOD) * (mod_inverse(b, MOD, true))) % MOD

//LLの数値をつかう時は最後にLをつける癖をつけよう
//
//  ┏┓┏┓　┓　┏┓
//  ┏┛┃┃　┃　┗┫
//  ┗┛┗┛　┻　┗┛
//
//   謹┃賀┃新┃年┃
//   ━┛━┛━┛━┛
//WWWWWWWWWWWWWWWWWWWWWW

int n;
vector <int> two, three, six;
vector <int> ans;

int main() {
  aim_cpo; // インタラクティブのときは消すように.
#ifdef LOCAL_DEFINE
  LOCAL_INPUT; // インタラクティブのときは消すように.
//  LOCAL_OUTPUT; // ファイルに出力したいときのみ
  show(MOD);
#endif
  // テキトー考察
  //
  // 出力する数列の条件は、
  // i != j ならば ans[i] != ans[j]
  // gcd(ans[i], \sum_{j = 0} ^ {ans.size - 1} - ans[i]) != 1
  // 0 <= i < j < ans.size で gcd(ans[i], ans[j]) == 1となる i, jが存在する.
  // ans[i] <= 30000
  // 以上.
  // 2の倍数と3の倍数を使って考えてみる.(なぜ2,3の倍数なんだと聞かれたら、めっちゃ考えた結果良さそうだったからとしか...)
  // 2の倍数で6の倍数ではない数が偶数個、3の倍数で6の倍数ではない数を偶数個用意すると条件を満たすことができる
  // この条件のもとで、6の倍数はいくつ入れても良い.
  // 3000以下の該当する数の個数の合計は丁度20000なのでok
  // てかもうなんか説明すんのめんどくさい...
  cin >> n;
  if (n == 3) {
    cout << 2 << " " << 5 << " " << 63 << endl;
    return 0;
  }
  for (int i = 1; 2 * i <= 30000; i++) {
    if (2 * i % 6 == 0) continue;
    two.push_back(2 * i);
  }
  for (int i = 1; 3 * i <= 30000; i++) {
    if (3 * i % 6 == 0) continue;
    three.push_back(3 * i);
  }
  for (int i = 1; i * 6 <= 30000; i++) {
    six.push_back(6 * i);
  }
  for (int i = 0; i < (int) three.size(); i += 2) {
    if ((int) ans.size() + 4 > n) break;
    ans.push_back(two[i]);
    ans.push_back(two[i + 1]);
    ans.push_back(three[i]);
    ans.push_back(three[i + 1]);
  }
  for (int i = (int) three.size(); i < (int) two.size(); i += 2) {
    if ((int) ans.size() + 2 > n) break;
    ans.push_back(two[i]);
    ans.push_back(two[i + 1]);
  }
  rep(i, 0, (int) six.size()) {
    if ((int) ans.size() == n) break;
    ans.push_back(six[i]);
  }
  rep(i, 0, (int) ans.size()) {
    cout << ans[i];ln(i, (int) ans.size());
  }
#ifdef  LOCAL_DEFINE
  cerr << "Time elapsed: " << 1.0 * clock() / CLOCKS_PER_SEC << "s." << endl;
#endif
  return 0;
}

Measured memory_bytes: 640