#include <bits/stdc++.h>
using namespace std;

using i64 = int64_t;

#define rep(i, x, y) for (i64 i = i64(x), i##_max_for_repmacro = i64(y); i < i##_max_for_repmacro; ++i)
#define debug(x) #x << "=" << (x)

#ifdef DEBUG
#define _GLIBCXX_DEBUG
#define print(x) std::cerr << debug(x) << " (L:" << __LINE__ << ")" << std::endl
#else
#define print(x)
#endif

template <i64 p>
class fp {
    public:
    i64 x;
    fp() : x(0) {}
    fp(i64 x_) : x((x_ % p + p) % p) {}
    fp operator+() const { return fp(x); }
    fp operator-() const { return fp(-x); }
    fp& operator+=(const fp& y) {
        x += y.x;
        if (x >= p) x -= p;
        return *this;
    }
    fp& operator-=(const fp& y) { return *this += -y; }
    fp& operator*=(const fp& y) {
        x = x * y.x % p;
        return *this;
    }
    fp& operator/=(const fp& y) { return *this *= fp(inverse(y.x)); }
    fp operator+(const fp& y) const { return fp(x) += y; }
    fp operator-(const fp& y) const { return fp(x) -= y; }
    fp operator*(const fp& y) const { return fp(x) *= y; }
    fp operator/(const fp& y) const { return fp(x) /= y; }
    bool operator==(const fp& y) const { return x == y.x; }
    bool operator!=(const fp& y) const { return !(*this == y); }
    i64 extgcd(i64 a, i64 b, i64& x, i64& y) {
        i64 d = a;
        if (b != 0) {
            d = extgcd(b, a % b, y, x);
            y -= (a / b) * x;
        } else {
            x = 1;
            y = 0;
        }
        return d;
    }
    i64 inverse(i64 a) {
        i64 x, y;
        extgcd(a, p, x, y);
        return (x % p + p) % p;
    }
};

template <i64 p>
i64 abs(const fp<p>& x) { return x.x; }

template <i64 p>
istream& operator>>(istream& is, fp<p>& x) {
    is >> x.x;
    return is;
}

template <i64 p>
ostream& operator<<(ostream& os, const fp<p>& x) {
    os << x.x;
    return os;
}

template <typename T, typename U>
ostream& operator<<(ostream& os, const pair<T, U>& p) {
    os << "(" << p.first << ", " << p.second << ")";
    return os;
}

template <typename T>
ostream& operator<<(ostream& os, const vector<T>& vec) {
    os << "[";
    for (const auto& v : vec) {
        os << v << ",";
    }
    os << "]";
    return os;
}

template <typename T>
bool chmin(T& a, const T& b) {
    if (a > b) {
        a = b;
        return true;
    }
    return false;
}

template <typename T>
bool chmax(T& a, const T& b) {
    if (a < b) {
        a = b;
        return true;
    }
    return false;
}

template <typename A, typename T, size_t size>
void fill(A (&ary)[size], const T& val) {
    fill((T*)ary, (T*)(ary + size), val);
}

constexpr int inf = 1.01e9;
constexpr i64 inf64 = 4.01e18;
constexpr long double eps = 1e-9;

// double(64bit浮動小数)のn分探索のループ回数の上限(2分探索なら50でも十分かもしれない). long double(80ビットの x87 浮動小数点型?)だと, 2分探索であってもこれだと足りないケースがある気がするので, もうちょっと余裕を持たせた方が良さそう.
constexpr i64 max_loop = 100;

void solve() {
    //constexpr i64 mod = 1'000'000'007;

    i64 N;
    cin >> N;
    vector<i64> c(N);
    rep(i,0,N){
        cin >> c[i];
        --c[i];
    }

    vector<vector<i64>> tree(N);
    rep(i,0,N-1){
        i64 a,b;
        cin >> a >> b;
        --a;
        --b;
        tree[a].emplace_back(b);
        tree[b].emplace_back(a);
    }

    vector<i64> size(N);
    function<i64(i64,i64)> calc_size=[&](i64 u,i64 p){
        size[u]=1;
        for(auto v:tree[u]){
            if(v==p) continue;
            size[u]+=calc_size(v,u);
        }
        return size[u];
    };
    calc_size(0,-1);

    vector<i64> ans(N,N*(N-1)/2+N);

    function<void(i64,i64,unordered_map<i64,i64>&)> dfs=[&](i64 u,i64 p,unordered_map<i64,i64>& minus){
        i64 pre=minus[c[u]];

        for(auto v:tree[u]){
            if(v==p) continue;

            minus[c[u]]=0;
            dfs(v,u,minus);

            i64 k=size[v]-minus[c[u]];
            ans[c[u]]-=k*(k+1)/2;
        }

        minus[c[u]]=pre+size[u];

        if(p==-1){
            rep(i,0,N){
                if(i==c[u]) continue;
                i64 k=size[u]-minus[i];
                ans[i]-=k*(k+1)/2;
            }
        }
    };

    unordered_map<i64,i64> minus;
    dfs(0,-1,minus);

    rep(i,0,N){
        cout << ans[i] << endl;
    }
}

int main() {
    std::cin.tie(0);
    std::ios::sync_with_stdio(false);
    cout.setf(ios::fixed);
    cout.precision(16);
    solve();
    return 0;
}


Measured memory_bytes: 51884