#include <bits/stdc++.h>

using namespace std;

#define int long long
#define double long double
#define FOR(i, a, b) for(ll i = (a); i < (b); ++i)
#define FORR(i, a, b) for(ll i = (a); i > (b); --i)
#define REP(i, n) for(ll i = 0; i < (n); ++i)
#define REPR(i, n) for(ll i = n; i >= 0; i--)
#define FOREACH(x, a) for(auto &(x) : (a))
#define VECCIN(x)                                                              \
    for(auto &youso_ : (x)) cin >> youso_
#define bitcnt(x) __builtin_popcount(x)
#define lbit(x) __builtin_ffsll(x)
#define rbit(x) __builtin_clzll(x)
#define SZ(x) ((ll)(x).size())
#define fi first
#define se second
#define All(a) (a).begin(), (a).end()
#define rAll(a) (a).rbegin(), (a).rend()

template <typename T = long long> inline T IN() {
    T x;
    cin >> x;
    return (x);
}
inline void CIN() {}
template <class Head, class... Tail>
inline void CIN(Head &&head, Tail &&... tail) {
    cin >> head;
    CIN(move(tail)...);
}
#define CCIN(...)                                                              \
    char __VA_ARGS__;                                                          \
    CIN(__VA_ARGS__)
#define DCIN(...)                                                              \
    double __VA_ARGS__;                                                        \
    CIN(__VA_ARGS__)
#define LCIN(...)                                                              \
    ll __VA_ARGS__;                                                            \
    CIN(__VA_ARGS__)
#define SCIN(...)                                                              \
    string __VA_ARGS__;                                                        \
    CIN(__VA_ARGS__)
#define Yes(a) cout << (a ? "Yes" : "No") << "\n"
#define YES(a) cout << (a ? "YES" : "NO") << "\n"
#define Printv(v)                                                              \
    {                                                                          \
        FOREACH(x, v) { cout << x << " "; }                                    \
        cout << "\n";                                                          \
    }
template <typename T = string> inline void eputs(T s) {
    cout << s << "\n";
    exit(0);
}
template <typename A, size_t N, typename T>
void Fill(A (&array)[N], const T &val) {
    std::fill((T *)array, (T *)(array + N), val);
}

template <typename T> using PQG = priority_queue<T, vector<T>, greater<T>>;
template <typename T> using PQ = priority_queue<T>;

typedef long long ll;
typedef vector<ll> VL;
typedef vector<VL> VVL;
typedef pair<ll, ll> PL;
typedef vector<PL> VPL;
typedef vector<bool> VB;
typedef vector<double> VD;
typedef vector<string> VS;

const int INF = 1e9;
// const int MOD = 1e9 + 7;
// const int MOD = 998244353;
const ll LINF = 1e18;
// const double PI = atan(1.0) * 4.0;
const ll dh[] = {0, 1, 1, 1, 0, -1, -1, -1};
const ll dw[] = {1, 1, 0, -1, -1, -1, 0, 1};
#define PI 3.141592653589793238

ll N;
VL x, y;
static int MOD = 1e9 + 7;

using vec = vector<ll>;
using mat = vector<vec>;

mat matmul(const mat &A, const mat &B) {
    mat ret(A.size(), vec(B[0].size()));
    REP(i, A.size()) REP(j, B[0].size()) {
        REP(k, B.size()) { ret[i][j] += (A[i][k] % MOD) * (B[k][j] % MOD); }
        ret[i][j] %= MOD;
    }
    return ret;
}

mat matpow(mat A, ll n) {
    mat ret(A.size(), vec(A.size()));
    REP(i, A.size()) ret[i][i] = 1;
    while(n) {
        if(n & 1) ret = matmul(ret, A);
        A = matmul(A, A);
        n >>= 1;
    }
    return ret;
}

ll mypow(ll x, ll n) {
    ll res = 1;
    while(n > 0) {
        if(n & 1) res = res * x;
        x *= x;
        n >>= 1;
    }
    return res;
}

signed main() {
    LCIN(L, A, B);
    cin >> MOD;
    ll cnt = 0;
    auto f = [&](ll idx) {
        ll val = A + B * idx;
        return to_string(val).length();
    };
    mat now(3, vec(1));
    now[0][0] = 0;
    now[1][0] = A;
    now[2][0] = 1;
    FOR(d, 1, 19) {
        if(mypow(10, d) - 1 - A < 0) continue;
        ll ub = min((mypow(10, d) - 1 - A) / B + 1, L);
        ll k = ub - cnt;
        mat A(3, vec(3));
        A[0][0] = mypow(10, d);
        A[0][1] = 1;
        A[1][1] = 1;
        A[1][2] = B;
        A[2][2] = 1;
        now = matmul(matpow(A, k), now);
        if(ub == L) break;
        cnt = ub;
    }
    cout << now[0][0] << "\n";
}


Measured memory_bytes: 256