#include <bits/stdc++.h>
#include <math.h>
#define rep(i, n) for(int i = 0; i < (n); i++)
#define rrep(i, n) for(int i = (n-1); i >= 0; i--)
using namespace std;
typedef long long ll;
const int MOD = 1000000007;
const ll INF = 1LL<<62;
const int IINF = 1000000000;
template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }
template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }
using Graph = vector<vector<int>>;

typedef pair<int, int> P;

struct mint {
    ll x;
    mint(ll x=0):x((x%MOD+MOD)%MOD){}
    mint operator-() const { return mint(-x);}
    mint& operator+=(const mint a) {
        if ((x += a.x) >= MOD) x -= MOD;
        return *this;
    }
    mint& operator-=(const mint a) {
        if ((x += MOD-a.x) >= MOD) x -= MOD;
        return *this;
    }
    mint& operator*=(const mint a) {
        (x *= a.x) %= MOD;
        return *this;
    }
    bool operator==(const mint a){
        return (x == a.x);
    }
    mint operator+(const mint a) const {
        mint res(*this);
        return res+=a;
    }
    mint operator-(const mint a) const {
        mint res(*this);
        return res-=a;
    }
    mint operator*(const mint a) const {
        mint res(*this);
        return res*=a;
    }
    mint pow(ll t) const {
        if (!t) return 1;
        mint a = pow(t>>1);
        a *= a;
        if (t&1) a *= *this;
        return a;
    }
    // for prime MOD
    mint inv() const {
        return pow(MOD-2);
    }
    mint& operator/=(const mint a) {
        return (*this) *= a.inv();
    }
    mint operator/(const mint a) const {
        mint res(*this);
        return res/=a;
    }
};
istream& operator>>(istream& is, const mint& a) { return is >> a.x;}
ostream& operator<<(ostream& os, const mint& a) { return os << a.x;}
// 2項係数を求める
struct combination {
    vector<mint> fact, ifact;
    combination(int n):fact(n+1),ifact(n+1) {
        assert(n < MOD);
        fact[0] = 1;
        for (int i = 1; i <= n; ++i) fact[i] = fact[i-1]*i;
        ifact[n] = fact[n].inv();
        for (int i = n; i >= 1; --i) ifact[i-1] = ifact[i]*i;
    }
    mint operator()(int n, int k) {
        if (k < 0 || k > n) return 0;
        return fact[n]*ifact[k]*ifact[n-k];
    }
};

//nが非常に大きく、aが小さい場合
mint choose(int n, int a){
    mint x = 1, y = 1;
    rep(i,a){
        x *= n-i;
        y *= i+1;
    }
    return x/y;
}

ll gcd(ll x, ll y){
    if (y==0) return x;
    else return gcd(y, x%y);
}


vector<pair<long long, long long> > prime_factorize(long long N) {
    vector<pair<long long, long long> > res;
    for (long long a = 2; a * a <= N; ++a) {
        if (N % a != 0) continue;
        long long ex = 0; // 指数

        // 割れる限り割り続ける
        while (N % a == 0) {
            ++ex;
            N /= a;
        }

        // その結果を push
        res.push_back({a, ex});
    }

    // 最後に残った数について
    if (N != 1) res.push_back({N, 1});
    return res;
}

int main(){
    ll N; cin >> N;
    vector<ll> A(N);
    rep(i,N){
        cin >> A[i];
    }

    vector<ll> ca;
    ca.push_back(A[0]);
    rep(i,N-1){
        ca.push_back(gcd(ca[i],A[i+1]));
    }

    //set<ll> ans;
    vector<ll> ans(10000005, 0);
    bool isOK = true;
    rep(i,N){
        ll now = ans.size();
        vector<pair<ll,ll>> pfs = prime_factorize(A[i]);
        for (auto pf : pfs) {
            /*
            if (ans.count(pf.first) > 0){
                isOK = false;
            }
            ans.insert(pf.first);
            */
            if (ans[pf.first] > 0){
                isOK = false;
                break;
            }
            ans[pf.first]++;
        }
    }

    if (isOK){
        cout << "pairwise coprime" << endl;
    }
    else{
        if (ca[N-1] == 1){
            cout << "setwise coprime" << endl;
        }
        else{
            cout << "not coprime" << endl;
        }
    }


    





}

Measured memory_bytes: 97168