You are given K eggs, and you have access to a building with N floors from 1 to N. 
Each egg is identical in function, and if an egg breaks, you cannot drop it again.
You know that there exists a floor F with 0 <= F <= N such that any egg dropped at a floor higher than F will break, and any egg dropped at or below floor F will not break.
Each move, you may take an egg (if you have an unbroken one) and drop it from any floor X (with 1 <= X <= N). 
Your goal is to know with certainty what the value of F is.
What is the minimum number of moves that you need to know with certainty what F is, regardless of the initial value of F?
 



Example 1:
Input: K = 1, N = 2
Output: 2
Explanation: 
Drop the egg from floor 1.  If it breaks, we know with certainty that F = 0.
Otherwise, drop the egg from floor 2.  If it breaks, we know with certainty that F = 1.
If it didn't break, then we know with certainty F = 2.
Hence, we needed 2 moves in the worst case to know what F is with certainty.


Example 2:
Input: K = 2, N = 6
Output: 3


Example 3:
Input: K = 3, N = 14
Output: 4

 
Note:

1 <= K <= 100
1 <= N <= 10000

```python

USER_FILENAME = "<user_code>"
import sys, json, builtins
import math, heapq, bisect, itertools, functools, collections, statistics, fractions, decimal, operator, array, random, re, string, os, pathlib
try:
    import resource as _res
except Exception:
    _res = None
from collections import Counter, defaultdict, deque, OrderedDict
from functools import lru_cache, reduce
from itertools import accumulate, permutations, combinations, product
from math import gcd, ceil, floor, sqrt
from decimal import Decimal
try:
    from typing import *
except Exception:
    pass
try:
    sys.setrecursionlimit(1_000_000)
except Exception:
    pass
try:
    import site as _site
    try:
        _sys_sites = _site.getsitepackages() if hasattr(_site, "getsitepackages") else []
        for _p in _sys_sites:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
    try:
        _usp = _site.getusersitepackages()
        if isinstance(_usp, str):
            _usp = [_usp]
        for _p in _usp:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
except Exception:
    pass

def _disabled_input(*args, **kwargs):
    raise RuntimeError("input() is disabled in callable mode")
builtins.input = _disabled_input

ns = {"__name__": "__judge__"}  # prevent if __name__ == "__main__" blocks
for _k, _v in list(globals().items()):
    if not _k.startswith("_"):
        ns[_k] = _v
_CODE = "class Solution:\n    def superEggDrop(self, K: int, N: int) -> int:\n        # https://leetcode.com/problems/super-egg-drop/discuss/443089/Simplest-Python-DP-Solution-with-Detailed-Explanation-99Time-100Mem\n        # M x K --> Given M moves and K eggs, what is the maximum floor we can check ?\n        # M = 300 # big enough number\n        # dp = [[0 for j in range(K+1)] for i in range(M+1)]\n        # # Initialization 1 --> no move no floor --> dp[0][*] = 0\n        # # Initialization 2 --> no egg no floor --> dp[*][0] = 0\n        # # General case --> we want to find dp[m][k] --> we pick one egg and drop (1 move)\n        # #              --> now we have k or k-1 eggs, depending on whether the previous egg is broken\n        # #              --> so in either case, we can at least sum up 1 (first move) + dp[m-1][k] + dp[m-1][k-1] \n        # for i in range(1, M+1):\n        #     for j in range(1, K+1):\n        #         dp[i][j] = 1 + dp[i-1][j] + dp[i-1][j-1]\n        #         if dp[i][j] >= N:\n        #             return i\n        memo = dict()    \n        def dp(K, N):\n            if K == 1:\n                return N\n            if N == 0:\n                return 0\n            if (K, N) in memo:\n                return memo[(K, N)]\n            # res = float('inf')\n            low, high = 1, N + 1\n            while low < high:\n                mid = (low + high)//2\n                broken = dp(K-1, mid -1)\n                notBroken = dp(K, N-mid)\n                if broken >= notBroken:\n                    high = mid\n                    # res = min(broken + 1, res)\n                else:\n                    low = mid + 1\n                    # res = min(notBroken + 1, res)\n            memo[(K,N)] = 1 + max(dp(K-1, low -1), dp(K, N-low))\n            return memo[(K,N)]\n        return dp(K, N)\n            \n                \n            \n"
_co = compile(_CODE, USER_FILENAME, "exec")
exec(_co, ns, ns)

_target = None
_fn_name = 'superEggDrop'
if _fn_name:
    if "Solution" in ns:
        try:
            _obj = ns["Solution"]()
            if hasattr(_obj, _fn_name):
                _target = getattr(_obj, _fn_name)
        except Exception:
            _target = None
    if _target is None and _fn_name in ns and callable(ns[_fn_name]):
        _target = ns[_fn_name]
# Fallback: if there's exactly one user-defined function, use it
if _target is None:
    _cands = [v for k, v in ns.items() if callable(v) and getattr(v, "__module__", "") in ("__judge__", "__main__")]
    _user_funcs = [c for c in _cands if getattr(c, "__name__", "").startswith("_") is False]
    if len(_user_funcs) == 1:
        _target = _user_funcs[0]
if _target is None:
    raise RuntimeError(f"Could not resolve callable '{_fn_name}'")

_raw = sys.stdin.read().strip()
if _raw:
    _parsed = json.loads(_raw)
    if isinstance(_parsed, dict):
        _kwargs = _parsed.get("kwargs", {})
        _args = _parsed.get("args", [])
    else:
        _args, _kwargs = _parsed, {}
else:
    _args, _kwargs = [], {}
if not isinstance(_args, (list, tuple)):
    _args = [_args]
_res = _target(*_args, **_kwargs)
try:
    sys.stdout.write(repr(_res) + "\n")
except Exception:
    pass

```

Measured memory_bytes: 6024