#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
#define F first
#define S second
#define pii pair<int, int>
#define pli pair<ll, int>
#define pil pair<int, ll>
#define pll pair<ll, ll>
#define eb emplace_back
#define all(v) v.begin(), v.end()
#define rep(i, n) for (int i = 0; i < (n); ++i)
#define rep3(i, l, n) for (int i = l; i < (n); ++i)
#define sz(v) (int)v.size()
#define endl '\n'
const int inf = 1000000007;
const ll INF = 1e18;
// int mod = 998244353;
int mod = 1000000007;
#define abs(x) (x >= 0 ? x : -(x))
#define lb(v, x) (int)(lower_bound(all(v), x) - v.begin())
#define ub(v, x) (int)(upper_bound(all(v), x) - v.begin())
template<typename T1, typename T2> inline bool chmin(T1 &a, T2 b) { if (a > b) { a = b; return 1; } return 0; }
template<typename T1, typename T2> inline bool chmax(T1 &a, T2 b) { if (a < b) { a = b; return 1; } return 0; }
ll gcd(ll a, ll b) { if (b == 0) return a; return gcd(b, a % b); }
ll lcm(ll a, ll b) { return a / gcd(a, b) * b; }
template<typename T, typename U> T pow_(T a, U b) { return b ? pow_(a * a, b / 2) * (b % 2 ? a : 1) : 1; }
ll modpow(ll a, ll b, ll _mod) { return b ? modpow(a * a % _mod, b / 2, _mod) * (b % 2 ? a : 1) % _mod : 1; }
template<class T, class U> ostream& operator << (ostream& os, const pair<T, U>& p) { os << p.F << " " << p.S; return os; }
template<class T> ostream& operator << (ostream& os, const vector<T>& vec) { rep(i, sz(vec)) { if (i) os << " "; os << vec[i]; } return os; }
template<typename T> inline istream& operator >> (istream& is, vector<T>& v) { rep(j, sz(v)) is >> v[j]; return is; }
template<class T, class T2> inline void add(T &a, T2 b) { a += b % mod; if (a >= mod) a -= mod; }
template<class T> void operator += (vector<T>& v, vector<T> v2) { rep(i, sz(v2)) v.eb(v2[i]); }

void solve();

int main() {
    ios::sync_with_stdio(false);
    cin.tie(0);
    cout.tie(0);
    cout << fixed << setprecision(12); // debuged
    int T;
    T = 1;
    while (T--) solve();
}

// https://atcoder.jp/contests/abc130/submissions/15522860
struct mint {
    ll x;
    mint (ll x = 0) : x((mod + x % mod) % mod) {}
    mint operator -() const { return mint(-x); }
    mint& operator += (const mint a) { // コンストラクタの、modで割った余りがくる
        if ((x += a.x) >= mod) x -= mod;
        return *this;
    }
    mint& operator -= (const mint a) {
        if ((x += -a.x + mod) >= mod) x -= mod;
        return *this;
    }
    mint& operator *= (const mint a) {
        (x *= a.x) %= mod;
        return *this;
    }
    mint operator + (const mint a) const {
        mint res(*this);
        return res += a; // ?
    }
    mint operator - (const mint a) const {
        mint res(*this);
        return res -= a;
    }
    mint operator * (const mint a) const {
        mint res(*this);
        return res *= a;
    }
    mint pow(ll t) const { // mint(a).pow(t) tは余りとったりしたらあかん
        if (t == 0) return 1;
        mint a = pow(t >> 1); // 再帰
        a *= a;
        if (t & 1) a *= *this;
        return a;
    }
    
    // 逆元
    mint inv() const {
        return pow(mod - 2);
    }
    mint& operator /= (const mint a) { // invを利用
        return (*this) *= a.inv();
    }
    mint operator / (const mint a) const {
        mint res(*this);
        return res /= a;
    }
    friend ostream &operator << (ostream &s, mint a) { return s << a.x; }
};

template<typename T>
struct BIT {
  vector<vector<T> > array;
  int n, m;
  BIT(int _n, int _m)
    : array(_n, vector<T>(_m)), n(_n), m(_m) {}
public:
  // [0, x), [0, y)
  T sum(int x, int y) {
    T s = 0;
    for (int i = x - 1; i >= 0; i = (i & (i + 1)) - 1) {
      for (int j = y - 1; j >= 0; j = (j & (j + 1)) - 1) {
        s += array[i][j];
      }
    }
    return s;
  }
  // [x1, x2), [y1, y2)
  T sum(int x1, int x2, int y1, int y2) {
    return sum(x2, y2) - sum(x1, y2) - sum(x2, y1) + sum(x1, y1);
  }
  void add(int x, int y, T k) {
    for (int i = x; i < n; i |= i + 1) {
      for (int j = y; j < m; j |= j + 1) {
        array[i][j] += k;
      }
    }
  }
};
// BITでmodとってたら遅い

void solve() {
    int n, m;
    cin >> n >> m;
    vector<int> a(n), b(m);
    cin >> a >> b;
    
    BIT<mint> dp(n + 1, m + 1);
    dp.add(0, 0, 1);
    
    rep3(i, 1, n + 1) rep3(j, 1, m + 1) {
        if (a[i - 1] == b[j - 1]) dp.add(i, j, dp.sum(i, j));
    }
    cout << dp.sum(n + 1, m + 1) << endl;
}


Measured memory_bytes: 34604