#include <bits/stdc++.h>
#include <boost/multiprecision/cpp_int.hpp>
using namespace std;
//#define int long long
using bll = boost::multiprecision::cpp_int;
using ll = long long;
//constexpr int INF = 1e9;//INT_MAX=(1<<31)-1=2147483647
constexpr ll INF = (ll)1e18;//(1LL<<63)-1=9223372036854775807
constexpr ll MOD = (ll)1e9 + 7;
constexpr double EPS = 1e-9;
constexpr int dx[4]={1,0,-1,0};
constexpr int dy[4]={0,1,0,-1};
#define p(var) std::cout<<var<<std::endl
#define PI (acos(-1))
#define rep(i, n)   for(ll i=0, i##_length=(n); i< i##_length; ++i)
#define repeq(i, n) for(ll i=1, i##_length=(n); i<=i##_length; ++i)
#define all(v) (v).begin(), (v).end()
#define uniq(v) (v).erase(unique((v).begin(), (v).end()), (v).end());
template<typename T> inline void pv(vector<T> v) { for(ll i=0, N=v.size(); i<N; i++) cout<< v[i] << (i==N-1 ? '\n' : ' '); }
template<typename T> inline T gcd(T a, T b) { return b ? gcd(b,a%b) : a; }
template<typename T> inline T lcm(T a, T b) { return a / gcd(a,  b) * b; }
template<typename T1, typename T2> inline T1 power(T1 x, T2 n){ return n ? power(x*x%MOD,n/2)*(n%2?x:1)%MOD : 1; }
template<typename T1, typename T2> inline bool chmax(T1 &a, T2 b) { return a < b && (a = b, true); }
template<typename T1, typename T2> inline bool chmin(T1 &a, T2 b) { return a > b && (a = b, true); }
template<typename T> class dvector : public std::vector<T> {
public:
	dvector() : std::vector<T>() {}
	explicit dvector(size_t n, const T& value = T()) : std::vector<T>(n,value) {}
	dvector(const std::vector<T>& v) : std::vector<T>(v) {}
	T& operator[](size_t n){ return this->at(n); }
};
class dbool{
public:
	dbool() : boolvalue(false) {}
	dbool(bool b) : boolvalue(b) {}
	dbool(const dbool &b) : boolvalue(b.boolvalue) {}
	operator bool&() { return boolvalue; }
	operator const bool&() const { return boolvalue; }
private:
	bool boolvalue;
};
template<typename T1, typename T2> ostream& operator<<(ostream& s, pair<T1, T2>& p) {return s << "(" << p.first << ", " << p.second << ")";}
template<typename T> ostream& operator<<(ostream& s, dvector<T>& v) {
	for (int i = 0, len = v.size(); i < len; ++i){ s << v[i]; if (i < len - 1) s << "\t"; } return s; }
template<typename T> ostream& operator<<(ostream& s, dvector< dvector<T> >& vv) {
	for (int i = 0, len = vv.size(); i < len; ++i){ s << vv[i] << endl; } return s; }
template<typename T1, typename T2> ostream& operator<<(ostream& s, map<T1, T2>& m) {
	s << "{" << endl; for (auto itr = m.begin(); itr != m.end(); ++itr){ s << "\t" << (*itr).first << " : " << (*itr).second << endl; } s << "}" << endl; return s; }
template<typename T> ostream& operator<<(ostream& s, set<T>& se) {
	s << "{ "; for (auto itr = se.begin(); itr != se.end(); ++itr){ s << (*itr) << "\t"; } s << "}" << endl; return s; }
template<typename T> ostream& operator<<(ostream& s, multiset<T>& se) {
	s << "{ "; for (auto itr = se.begin(); itr != se.end(); ++itr){ s << (*itr) << "\t"; } s << "}" << endl; return s; }
#ifdef LOCAL_DEV
	#define debug(var) std::cout<<#var" = "<<var<<std::endl
#else
	#define debug(var)
#endif
#ifdef LOCAL_TEST
	#define vector dvector
	#define bool dbool
#endif

/*-----8<-----8<-----*/

//Ax=bを解く Aは正方行列
//解がない、もしくは一意でない場合は長さ0の配列を返す
vector<double> gauss_jordan(vector<vector<double>> &A, vector<double> &b){
	ll n = A.size();
	vector<vector<double>> B(n, vector<double>(n + 1));
	for(ll i = 0; i < n; i++)
		for(ll j = 0; j < n; j++)
			B[i][j] = A[i][j];
	//行列Aの後ろにbを並べて同時に処理する
	for(ll i = 0; i < n; i++)
		B[i][n] = b[i];

	for(ll i = 0; i < n; i++){
		//注目している変数の係数の絶対値が大きい式をi番目に持ってくる
		ll pivot = i;
		for(ll j = i + 1; j < n; j++){
			if(abs(B[j][i]) > abs(B[pivot][i])) pivot = j;
		}
		if(pivot != i)swap(B[pivot], B[i]);

		//解がない、もしくは一意でない
		if(abs(B[i][i]) < EPS) return vector<double>();

		//注目している変数の係数を1にする
		for(ll j = i + 1; j <= n; j++)
			B[i][j] /= B[i][i];
		
		for(ll j = 0; j < n ; j++){
			if(i != j){
				//j番目の式からi番目の変数を消去
				for(ll k = i + 1 ; k <= n; k++)
					B[j][k] -= B[j][i] * B[i][k];
			}
		}
	}
	vector<double> x(n);
	//後ろに並べたbが解になる
	for(ll i = 0; i < n; i++)
		x[i] = B[i][n];

	return x;
}

//xが0以上の整数であるか判定
inline bool isnatural(double x) { return x > -EPS && abs(x - round(x)) < EPS; }

signed main(){
	//O(N^3)なので計算量注意！TLEしないか制約を確認してから使うこと
	//ABC085C
	double N, Y;
	cin >> N >> Y;
	rep(i, N+1){
		double t = Y - 10000.0 * i;
		if(t < 0)break;
		vector<vector<double>> a;
		vector<double> b;
		a.push_back({{    1.0,     1.0 }});	b.push_back(N - i);
		a.push_back({{ 5000.0,  1000.0 }});	b.push_back(t);
		vector<double> x = gauss_jordan(a,b);
		if(x.size()>0 && isnatural(x[0]) && isnatural(x[1])){
			cout << i << " " << (int)round(x[0]) << " " << (int)round(x[1]) << endl;
			return 0;
		}
	}
	cout << "-1 -1 -1" << endl;
	return 0;
}


signed main2(){
	//連立方程式を解く 1.0w + -2.0x + 3.0y + -4.0z = 5.0 ...の(w,x,y,z)が解ける
	vector<vector<double>> a;
	vector<double> b;
	a.push_back({{ 1.0, -2.0,  3.0, -4.0}}); b.push_back( 5.0);
	a.push_back({{-2.0,  5.0,  8.0, -3.0}}); b.push_back( 9.0);
	a.push_back({{ 5.0,  4.0,  7.0,  1.0}}); b.push_back(-1.0);
	a.push_back({{ 9.0,  7.0,  3.0,  5.0}}); b.push_back( 4.0);

	vector<double> c=gauss_jordan(a,b);

	for(int i=0, size=c.size(); i<size; i++){
		cout << c[i] << endl;
	}

	return 0;
}


Measured memory_bytes: 256