#include<bits/stdc++.h>
//#include <ext/pb_ds/detail/standard_policies.hpp>

const double pi=acos(-1.0);
//memset ( a , 0 , n * sizeof(ll) ) ;
using namespace std;
//using namespace __gnu_pbds;
#define   endl    '\n'
#define   sl(n)     scanf("%lld",&n)
#define   mp      make_pair
#define   pb      push_back
#define   ppb     pop_back
#define   fi      first
#define   se      second
#define   ll      long long
#define   ull     unsigned long long
#define   ld      long double
#define   pii     pair<int, int>
#define   f(i,a,b)  for(ll i = (ll)(a); i < (ll)(b); i++)
#define   rf(i,a,b)   for(ll i = (ll)(a); i > (ll)(b); i--)
#define   ms(a,b)   memset((a),(b),sizeof(a))
#define   abs(x)    ((x<0)?(-(x)):(x))
#define   MAX     1000005
#define   inf     LLONG_MAX
#define   ninf    LLONG_MIN
#define   MIN     INT_MIN
#define   yeet    return 0;
#define fast_io ios_base::sync_with_stdio (false) ; cin.tie(0) ; cout.tie(0) ;
#define ordered_set tree<int, null_type,less<int>, rb_tree_tag,tree_order_statistics_node_update>
// Use cout.flush() for interactive problems.
// Use this for increased stack size: g++ -o a.exe -Wl,--stack=256000000 -O2 source.cpp
inline long long  MAX2(long long  a, long long  b){return (a)>(b)?(a):(b);}
inline long long  MAX3(long long  a, long long  b,long long  c){return (a)>(b)?((a)>(c)?(a):(c)):((b)>(c)?(b):(c));}
inline long long  MIN2(long long  a, long long  b){return (a)<(b)?(a):(b);}
inline long long  MIN3(long long  a, long long b,long long c){return (a)<(b)?((a)<(c)?(a):(c)):((b)<(c)?(b):(c));}

//typedef
typedef long int int32;
typedef unsigned long int uint32;
typedef long long int int64;
typedef unsigned long long int  uint64;


int mod = 1e9 +7 ;
int64_t extGcd(int64_t a, int64_t b, int64_t& x, int64_t& y) {if (!a) {x = 0;y = 1;return b;}int64_t x1, y1;int64_t d = extGcd(b % a, a, x1, y1);x = y1 - (b / a) * x1;y = x1;return d;}

inline int addMod(int a, int b, int m = mod) {return ((int64_t)a + b) % m;}
inline int mulMod(int a, int b, int m = mod) {  return ((int64_t)a * b) % m;}
inline int divMod(int a, int b, int m = mod) {int64_t x, y;int64_t g = extGcd(b, m, x, y);if (g != 1) {cerr << "Bad gcd!" << endl;for (;;);}x = (x % m + m) % m;return mulMod(a, x, m);}
int dx[]={1,1,0,-1,-1,-1, 0, 1};
int dy[]={0,1,1, 1, 0,-1,-1,-1};
inline ll exp(ll a,ll b){if(a==0)return 0ll;ll r=1LL;while(b>0){if(b&1){r=r*(a%mod);r=(r+mod)%mod;}b/=2;a=(a%mod)*(a%mod);a=(a+mod)%mod;}return (r+mod)%mod;}
ll gcd(ll a,ll b){if(b==0)return a;if(a==0)return b;return gcd(b,a%b);}
uint32 setbits(ll n){uint32 count=0;while (n){n&=(n-1);count++;}return count; }
//int clearRangeItoJ(int n,int i,int j){ int ones=(~0); int a= ones<<(j+1);int b=(1<<i)-1;int mask=a|b; int ans=n&mask;return ans}

// ll f[MAX];
// ll iv[MAX];
// ll C(ll n,ll r){
//   if(n<r)return 0;
//   ll ans=(f[n]%mod * iv[r]%mod)%mod;
//   ans=(ans%mod * iv[n-r]%mod)%mod;
//   return ans%mod;
// }
// void init(){
//   f[0]=1;
//      iv[0]=1;
//      f(i,1,MAX)f[i]=(i*f[i-1])%mod;
//      iv[MAX-1]=exp(f[MAX-1],mod-2);

//      for(int i=MAX-2;i>=0;--i)iv[i]=(iv[i+1]*(i+1))%mod;

// }

////****************************************************************************************************************************************************************************************************************////
int main(){
            int n;
            cin>>n;
            ll a[n];
            f(i,0,n)cin>>a[i];
            map<ll,ll>m1;
            for(int i=0;i<n;i++){
                   int term= a[i];
                   for(ll j=2;j*j<=term;j++){
                         int cc=0;
                        while(term%j==0){
                             cc++;
                            term=term/j;
                        }
                        m1[j]=MAX2(m1[j],cc);
                   }
                   if(term>1)m1[term]=MAX2(m1[term],1);
                   
            }
            ll lcm=1;
            for(auto x:m1){
                   lcm=(lcm%mod * (exp(x.fi,x.se))%mod)%mod;
            }
            vector<ll>g1;
            for(int i=0;i<n;i++){
                   ll term= (lcm%mod * (exp(a[i],mod-2))%mod)%mod;
                   g1.pb(term);
            }
            ll ans=0;
            f(i,0,n){ 
                 ans= (ans%mod + g1[i]%mod)%mod;
            }
            cout<<ans<<endl;
}


Measured memory_bytes: 1196