Rohit collects coins: he has exactly one coin for every year from 1 to n. Naturally, Rohit keeps all the coins in his collection in the order in which they were released. Once Rohit's younger brother made a change — he took all the coins whose release year dated from l to r inclusively and put them in the reverse order. That is, he took a certain segment [l, r] and reversed it. At that, the segment's endpoints did not coincide. For example, if n = 8, then initially Rohit's coins were kept in the order 1 2 3 4 5 6 7 8. If Rohit's younger brother chose the segment [2, 6], then after the reversal the coin order will change to 1 6 5 4 3 2 7 8. Rohit suspects that someone else could have spoilt the permutation after his brother. Help him to find that out. Check if the given permutation can be obtained from the permutation 1 2 … n using exactly one segment reversal. If it is possible, find the segment itself.

-----Input:-----
- The first line contains an integer N which is the number of coins in Rohit's collection. 
- The second line contains space-separated n integers which are the spoilt sequence of coins. It is guaranteed that the given sequence is a permutation, i.e. it contains only integers from 1 to n, and every number is used exactly 1 time.

-----Output:-----
If it is impossible to obtain the given permutation from the original one in exactly one action, print 0 0. Otherwise, print two numbers l, r (1 ≤ l < r ≤ n) which are the endpoints of the segment that needs to be reversed to obtain from permutation 1 2 … n the given one.

-----Constraints-----
- $1 \leq N \leq 1000$
- $1 \leq A[N] \leq 10^9$

-----Sample Input:-----
8
1 6 5 4 3 2 7 8

-----Sample Output:-----
2 6

```python

USER_FILENAME = "<user_code>"
import sys, json, builtins
import math, heapq, bisect, itertools, functools, collections, statistics, fractions, decimal, operator, array, random, re, string, os, pathlib
try:
    import resource as _res
except Exception:
    _res = None
from collections import Counter, defaultdict, deque, OrderedDict
from functools import lru_cache, reduce
from itertools import accumulate, permutations, combinations, product
from math import gcd, ceil, floor, sqrt
from decimal import Decimal
try:
    from typing import *
except Exception:
    pass
try:
    sys.setrecursionlimit(1_000_000)
except Exception:
    pass
try:
    import site as _site
    try:
        _sys_sites = _site.getsitepackages() if hasattr(_site, "getsitepackages") else []
        for _p in _sys_sites:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
    try:
        _usp = _site.getusersitepackages()
        if isinstance(_usp, str):
            _usp = [_usp]
        for _p in _usp:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
except Exception:
    pass

ns = {"__name__": "__main__"}
for _k, _v in list(globals().items()):
    if not _k.startswith("_"):
        ns[_k] = _v
_CODE = 'from sys import stdin,stdout,exit\r\nfrom heapq import *\r\ntry:\r\n    n=(int(stdin.readline()))\r\n    a=list(map(int,stdin.readline().split()))\r\n    s=0\r\n    l=0\r\n    r=n\r\n    left=right=False\r\n    for i in range(n):\r\n        if s+1==a[i]:\r\n            s=a[i]\r\n        else:\r\n            l=i\r\n            s=a[l]\r\n            break\r\n    for i in range(l+1,n):\r\n        if s-1==a[i]:\r\n            s=a[i]\r\n        else:\r\n            s=a[i]\r\n            r=i\r\n            break\r\n    arr = a[:l]+(a[l:r])[::-1]+a[r:]\r\n    s=0\r\n    ans=True\r\n    for i in arr:\r\n        if s+1==i:\r\n            s=i\r\n        else:\r\n            ans=False\r\n            break\r\n    if ans and l+1!=r:\r\n        print(l+1,r)\r\n    else:\r\n        print(0,0)\r\nexcept:\r\n    print(0,0)\r\n'
_co = compile(_CODE, USER_FILENAME, "exec")
exec(_co, ns, ns)

```

Measured memory_bytes: 13453