Note : This question carries $100$ $points$
CodeLand is celebrating a festival by baking cakes! In order to avoid wastage, families follow a unique way of distributing cakes.
For $T$ families in the locality, $i$-th family (1 <= $i$ <= $T$) has $N$ members. They baked $S$ slices of cakes. The smallest member of the family gets $K$ slices of cakes. Each family has a lucky number of $R$ and they agree to distribute the slices such that the member gets $R$ times more slices than the member just smaller than them. Since the family is busy in festival preparations, find out if the number of slices would be sufficient for the family or not. Also, find how many extra slices they have or how many slices are they short of.
Also, the locality is kind and believes in sharing. So, you also need to determine if each family would have sufficient slices if families shared their cakes among each other!

-----Input :-----
- First line of input will have a single integer $T$ i.e. the number of families in the locality
- For next $T$ lines, each line will describe one family through 4 integers i.e. $S$, $N$, $K$, $R$ separated by spaces

-----Output-----
- First $T$ lines of output will show if slices are enough for the family or not, followed by extra or required slices. For example, if slices are sufficient, the output would be $POSSIBLE$ $10$ which implies 10 slices are extra. If slices are insufficient, the output would be $IMPOSSIBLE$ $15$ which implies 15 slices are required to fulfill the requirement.
- Last line of output would be $IMPOSSIBLE$ or $POSSIBLE$ depending on whether each family would get enough slices after sharing.

-----Constraints:-----
- 1 ≤ $T$ ≤ 50
- 1 ≤ $N$ ≤ 15
- 1 ≤ $S$ ≤ 10^9
- 1 ≤ $K$ ≤ 5
- 1 ≤ $R$ ≤ 5

-----Sample Input:-----
5
100 4 2 2
100 4 3 2
100 4 3 3
200 4 4 2
10 3 2 2

-----Sample Output:-----
POSSIBLE 70
POSSIBLE 55
IMPOSSIBLE 20
POSSIBLE 140
IMPOSSIBLE 4
POSSIBLE

-----Explanation-----
For the first home, the youngest member has got 2 slices, the one older than them gets 2 times more slices, and so forth. So, first home needs 2 + 4 + 8 + 16 = 30 slices. But since they made 100, they have 70 extra, hence we print 'POSSIBLE 70'.
Doing the same for other houses, we find 20 + 4 = 24 slices extra are required so that all families have enough slices. In this case we have 70 + 55 + 140 = 265 extra slices which is > 24, so we print 'POSSIBLE' in last line.

```python

USER_FILENAME = "<user_code>"
import sys, json, builtins
import math, heapq, bisect, itertools, functools, collections, statistics, fractions, decimal, operator, array, random, re, string, os, pathlib
try:
    import resource as _res
except Exception:
    _res = None
from collections import Counter, defaultdict, deque, OrderedDict
from functools import lru_cache, reduce
from itertools import accumulate, permutations, combinations, product
from math import gcd, ceil, floor, sqrt
from decimal import Decimal
try:
    from typing import *
except Exception:
    pass
try:
    sys.setrecursionlimit(1_000_000)
except Exception:
    pass
try:
    import site as _site
    try:
        _sys_sites = _site.getsitepackages() if hasattr(_site, "getsitepackages") else []
        for _p in _sys_sites:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
    try:
        _usp = _site.getusersitepackages()
        if isinstance(_usp, str):
            _usp = [_usp]
        for _p in _usp:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
except Exception:
    pass

ns = {"__name__": "__main__"}
for _k, _v in list(globals().items()):
    if not _k.startswith("_"):
        ns[_k] = _v
_CODE = 'x = int(input())\r\nli = []\r\nfor i in range(x):\r\n    temp = 0\r\n    s,n,k,r = map(int, input().split())\r\n    for j in range(n):\r\n        if j == 0:\r\n            temp += k\r\n        else:\r\n            k = k*r \r\n            temp += k\r\n    if temp > s:\r\n        print("IMPOSSIBLE {0}".format(temp-s))\r\n        li.append(s-temp)\r\n    else:\r\n        print("POSSIBLE {0}".format(s-temp))\r\n        li.append(s-temp)\r\nif sum(li) >= 0:\r\n    print("POSSIBLE")\r\nelse:\r\n    print("IMPOSSIBLE")'
_co = compile(_CODE, USER_FILENAME, "exec")
exec(_co, ns, ns)

```

Measured memory_bytes: 13283