#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
#define F first
#define S second
#define pii pair<int, int>
#define pli pair<ll, int>
#define pil pair<int, ll>
#define pll pair<ll, ll>
#define eb emplace_back
#define all(v) v.begin(), v.end()
#define rep(i, n) for (int i = 0; i < (n); ++i)
#define rep3(i, l, n) for (int i = l; i < (n); ++i)
#define sz(v) (int)v.size()
#define endl '\n'
const int inf = 1000000007;
const ll INF = 1e18;
// int mod = 998244353;
int mod = 1000000007;
#define abs(x) (x >= 0 ? x : -(x))
#define lb(v, x) (int)(lower_bound(all(v), x) - v.begin())
#define ub(v, x) (int)(upper_bound(all(v), x) - v.begin())
template<typename T1, typename T2> inline bool chmin(T1 &a, T2 b) { if (a > b) { a = b; return 1; } return 0; }
template<typename T1, typename T2> inline bool chmax(T1 &a, T2 b) { if (a < b) { a = b; return 1; } return 0; }
ll gcd(ll a, ll b) { if (b == 0) return a; return gcd(b, a % b); }
ll lcm(ll a, ll b) { return a / gcd(a, b) * b; }
template<typename T, typename U> T pow_(T a, U b) { return b ? pow_(a * a, b / 2) * (b % 2 ? a : 1) : 1; }
ll modpow(ll a, ll b, ll _mod) { return b ? modpow(a * a % _mod, b / 2, _mod) * (b % 2 ? a : 1) % _mod : 1; }
template<class T, class U> ostream& operator << (ostream& os, const pair<T, U>& p) { os << p.F << " " << p.S; return os; }
template<class T> ostream& operator << (ostream& os, const vector<T>& vec) { rep(i, sz(vec)) { if (i) os << " "; os << vec[i]; } return os; }
template<class T> ostream& operator << (ostream& os, const set<T>& s) { for (auto e : s) os << e; return os; }
template<typename T> inline istream& operator >> (istream& is, vector<T>& v) { rep(j, sz(v)) is >> v[j]; return is; }
template<class T, class T2> inline void add(T &a, T2 b) { (a += b % mod) %= mod; if (a < 0) a += mod; }
template<class T> void operator += (vector<T>& v, vector<T> v2) { rep(i, sz(v2)) v.eb(v2[i]); }


void solve();

int main() {
  ios::sync_with_stdio(false);
  cin.tie(0);
  cout.tie(0);
  cout << fixed << setprecision(12); // debuged
  int T;
  T = 1;
  while (T--) solve();
}

vector<pii> runlength(vector<int> v) {
  vector<pii> ret;
  int cnt = 1;
  int n = sz(v);
  rep3(i, 1, n) {
    if (v[i] == v[i - 1]) {
      cnt++;
    } else {
      ret.eb(v[i - 1], cnt);
      cnt = 1;
    }
  }
  ret.eb(v[n - 1], cnt);
  return ret;
}

// https://atcoder.jp/contests/abc143/submissions/15064042
void solve() {
  int n;
  cin >> n;
  vector<int> a(n);
  cin >> a;
  sort(all(a));

  auto v = runlength(a);
  a.clear();
  rep(i, sz(v)) a.eb(v[i].S);
  sort(all(a));

  vector<ll> b(sz(v) + 1);
  rep(i, sz(v)) b[i + 1] = b[i] + a[i];
  // cerr << a << endl << b << endl;
  vector<int> c(n + 1);
  rep(x, n + 1) c[x] = lb(a, x);

  int i = 1;
  auto binary_search = [&](int ok, int ng) {
    auto check = [&](int x) { // 最大何組とれるか
      int it = c[x]; // 前計算
      ll sum = (it >= 0 ? b[it] : 0);
      sum += (sz(v) - it) * 1LL * x;
      if (sum >= x * 1LL * i) return 1;
      return 0;
    };
    int d = 1;
    while (abs(ng - ok) > d) {
      int mid = (ng + ok) / 2;
      (check(mid) ? ok : ng) = mid;
    }
    cout << ok << endl;
  };
  for (; i <= n; ++i) { // 何枚組でとるか
    binary_search(0, n + 1);
  }
}


Measured memory_bytes: 9796