//#i#include "pch.h"
#include <iostream>
#include <algorithm>
#include <map>
#include <set>
#include <queue>
#include <bitset>
#include <limits.h>
#include <string>
#include <stack>
#include <deque>
#include <cmath>
#include <bitset>
#include <complex>
#include <functional>
#include <time.h>
#include <stdio.h>

typedef long long ll;
typedef std::pair<int, int> Pii;
typedef std::pair<long long, long long> Pll;
typedef std::pair<double, double> Pdd;

#define rip(i, n, s) for (int i = (s);i < (int)( n ); i++)
#define mapa make_pair
#define all(a) a.begin(), a.end()
#define MM << " " <<

template<typename T>
using MaxHeap = std::priority_queue<T>;
template<typename T>
using MinHeap = std::priority_queue<T, std::vector<T>, std::greater<T>>;

template<typename T>
inline bool chmax(T &a, T b) {
	if (a < b) {
		a = b;
		return true;
	}
	return false;
}
template<typename T>
inline bool chmin(T &a, T b) {
	if (a > b) {
		a = b;
		return true;
	}
	return false;
}
template<typename T>
std::vector<T> vec(int len, T elem) { return std::vector<T>(len, elem); }
template<typename T>
void vdeb(std::vector<T> &da) {
	for (int i = 0;i < da.size();i++) {
		if (i == da.size() - 1) std::cout << da[i];
		else std::cout << da[i] << ' ';
	}
	std::cout << std::endl;
}
template<typename T>
void vdeb(std::vector<std::vector<T>> &da) {
	for (int i = 0;i < da.size();i++) vdeb(da[i]);
	std::cout << std::endl;
}
long long pow(long long n, long long p, long long k) {//n^k(mod p)
	if (!k) return 1;
	long long a = pow(n,p, k>>1);
	a = a * a%p;
	if (k & 1) a = a * n%p;
	return a;
}
void euclid(long long &a, long long &b, long long p) { // a>=b A*b+B*(a-a/b*b)=1
	if (a == 1) {
		a = 1;
	}
	else {
		long long A = b, B = a % b;
		euclid(A, B, p);
		b = (A - (p + a / b) % p * B % p + p) % p;
		a = B;
	}
}
long long rev(long long n, long long p) {//nの逆元 n*x-p*y=1
	//long long q = p;
	//euclid(p, n, p);
	//return n % q;
    return pow(n,p,p-2);
}
long long bino(long long n, long long m, long long p) {//nCm(mod p)
	long long ans = 1, div = 1;
	for(int i = 0;i < m; i++){
		ans = (n - i) * ans % p;
		div = div * (i +1) % p;
	}
	return ans * rev(div, p) % p;
}
struct modint {
	long long num;
	long long p;
	modint() {
		num = 0;
		p = 1000000007;
	}
	modint(int x) {
		p = 1000000007;
		num = (long long)x%p;
	}
	modint(long long x) {
		p = 1000000007;
		num = x % p;
	}
	modint operator+(const modint &other) {
		modint ret;
		ret.p = p;
		ret.num = (num + other.num) % p;
		return ret;
	}
	modint operator+(const long long &other) {
		modint ret;
		ret.p = p;
		ret.num = (num + (other%p)) % p;
		return ret;
	}
	modint operator-(const modint &other) {
		modint ret;
		ret.p = p;
		ret.num = (num - other.num + p) % p;
		return ret;
	}
	modint operator-(const long long &other) {
		modint ret;
		ret.p = p;
		ret.num = (num - (other%p) + p) % p;
		return ret;
	}
	modint operator*(const modint &other) {
		modint ret;
		ret.p = p;
		ret.num = (num*other.num) % p;
		return ret;
	}
	modint operator*(const long long &other) {
		modint ret;
		ret.p = p;
		ret.num = (num*(other%p)) % p;
		return ret;
	}
	modint operator/(const modint &other) {
		modint ret;
		ret.p = p;
		ret.num = (num*rev(other.num, p)) % p;
		return ret;
	}
	modint operator/(const long long &other) {
		modint ret;
		ret.p = p;
		ret.num = (num*rev(other%p, p)) % p;
		return ret;
	}
	void operator+=(const long long &other) {
		num = (num + other) % p;
	}
	void operator+=(const modint &other) {
		num = (num + other.num) % p;
	}
	void operator-=(const long long &other) {
		num = (num - other + p) % p;
	}
	void operator-=(const modint &other) {
		num = (num - other.num + p) % p;
	}
	void operator*=(const long long &other) {
		num = (num*other) % p;
	}
	void operator*=(const modint &other) {
		num = (num*other.num) % p;
	}
};
std::ostream& operator<<(std::ostream &os, const modint &x){
	std::cout << x.num;
	return os;
}

using namespace std;

int k,q;
const int S = 5000; 

vector<ll> daa(S), eq(S), su(S); 

int query(vector<ll> &da){
	ll n,x,m;cin >> n >> x >> m;
	int ret = n-1;
	rip(i,k,0) daa[i] = da[i]%m;
	eq[0] = 0;su[0] = 0;
	rip(i,k,0){
		su[i+1] = su[i]+daa[i];
		eq[i+1] = eq[i]+max((ll)0, 1-daa[i]);
	}
	//vdeb(eq);
	n--;
	x %= m;
	ll alsu = su[k]*(n/k) + su[n%k];
	ret -= eq[k]*(n/k) + eq[n%k];
	ret -= (x+alsu)/m;
	return ret;
}

int main() {;cin >> k >> q;
	vector<ll> da(k);
	rip(i,k,0) cin >> da[i];
	vector<ll> ans(q);
	rip(i,q,0){
		ans[i] = query(da);
	}
	rip(i,q,0) printf("%lld\n",ans[i]);
}

Measured memory_bytes: 512