#pragma GCC optimize("O3")
#pragma GCC target("avx")
#include <bits/stdc++.h>
#define int long long
#define ll long long
using ull = unsigned long long;
using namespace std;
#define dump(x)                             \
    if (dbg) {                              \
        cerr << #x << " = " << (x) << endl; \
    }
#define overload4(_1, _2, _3, _4, name, ...) name
#define FOR1(n) for (ll i = 0; i < (n); ++i)
#define FOR2(i, n) for (ll i = 0; i < (n); ++i)
#define FOR3(i, a, b) for (ll i = (a); i < (b); ++i)
#define FOR4(i, a, b, c) for (ll i = (a); i < (b); i += (c))
#define FOR(...) overload4(__VA_ARGS__, FOR4, FOR3, FOR2, FOR1)(__VA_ARGS__)
#define FORR(i, a, b) for (int i = (a); i <= (b); ++i)
#define bit(n, k) ((n >> k) & 1) /*nのk bit目*/
namespace mydef {
const int INF = 1ll << 60;
const int MOD = 1e9 + 7;
template <class T>
bool chmin(T& a, const T& b) {
    if (a > b) {
        a = b;
        return 1;
    } else
        return 0;
}
template <class T>
bool chmax(T& a, const T& b) {
    if (a < b) {
        a = b;
        return 1;
    } else
        return 0;
}
void Yes(bool flag = true) {
    if (flag)
        cout << "Yes" << endl;
    else
        cout << "No" << endl;
}
void No(bool flag = true) {
    Yes(!flag);
}
void YES(bool flag = true) {
    if (flag)
        cout << "YES" << endl;
    else
        cout << "NO" << endl;
}
void NO(bool flag = true) {
    YES(!flag);
}
template <typename A, size_t N, typename T>
void Fill(A (&array)[N], const T& val) {
    std::fill((T*)array, (T*)(array + N), val);
}
bool dbg = false;
}  // namespace mydef
using namespace mydef;
#define pb push_back
#define mp make_pair
#define eb emplace_back
#define lb lower_bound
#define ub upper_bound
#define all(v) (v).begin(), (v).end()
#define SZ(x) ((int)(x).size())
#define vi vector<int>
#define vvi vector<vector<int>>
#define vp vector<pair<int, int>>
#define vvp vector<vector<pair<int, int>>>
#define pi pair<int, int>
//#define P pair<int, int>
//#define V vector<int>
//#define S set<int>
#define asn ans
template <uint MD>
struct ModInt {
    using M = ModInt;
    const static M G;
    uint v;
    ModInt(ll _v = 0) { set_v(_v % MD + MD); }
    M& set_v(uint _v) {
        v = (_v < MD) ? _v : _v - MD;
        return *this;
    }
    explicit operator bool() const { return v != 0; }
    M operator-() const { return M() - *this; }
    M operator+(const M& r) const { return M().set_v(v + r.v); }
    M operator-(const M& r) const { return M().set_v(v + MD - r.v); }
    M operator*(const M& r) const { return M().set_v(ull(v) * r.v % MD); }
    M operator/(const M& r) const { return *this * r.inv(); }
    M& operator+=(const M& r) { return *this = *this + r; }
    M& operator-=(const M& r) { return *this = *this - r; }
    M& operator*=(const M& r) { return *this = *this * r; }
    M& operator/=(const M& r) { return *this = *this / r; }
    bool operator==(const M& r) const { return v == r.v; }
    M pow(ll n) const {
        M x = *this, r = 1;
        while (n) {
            if (n & 1)
                r *= x;
            x *= x;
            n >>= 1;
        }
        return r;
    }
    M inv() const { return pow(MD - 2); }
    /*
    M inv() const {
        long long b = MD, u = 1, v = 0;
        long long a = (*this).v;
        while (b) {
            long long t = a / b;
            a -= t * b;
            swap(a, b);
            u -= t * v;
            swap(u, v);
        }
        u %= MD;
        if (u < 0)
            u += MD;
        return M{u};
    }
    */
    friend ostream& operator<<(ostream& os, const M& r) { return os << r.v; }
    friend istream& operator>>(istream& is, M& r) { return is >> r.v; }
};
using Mint = ModInt<MOD>;
//SegmentTree
//How to use
//SegmentTree(n, f, M1):= サイズ n の初期化。ここで f は2つの区間の要素をマージする二項演算, M1はモノイドの単位元である。
//set(k , x):= k 番目の要素に x を代入する。
//build():= セグメント木を構築する。
//query(a , b):= 区間 [a,b) に対して二項演算した結果を返す。
//update(k , x):= k 番目の要素を x に変更する。
//operator[k] : = k 番目の要素を返す。
template <typename Monoid>
struct SegmentTree {
    using F = function<Monoid(Monoid, Monoid)>;

    int sz;
    vector<Monoid> seg;

    const F f;
    const Monoid M1;

    SegmentTree(int n, const F f, const Monoid& M1) : f(f), M1(M1) {
        sz = 1;
        while (sz < n)
            sz <<= 1;
        seg.assign(2 * sz, M1);
    }

    void set(int k, const Monoid& x) {
        seg[k + sz] = x;
    }

    void build() {
        for (int k = sz - 1; k > 0; k--) {
            seg[k] = f(seg[2 * k + 0], seg[2 * k + 1]);
        }
    }

    void update(int k, const Monoid& x) {
        k += sz;
        seg[k] = x;
        while (k >>= 1) {
            seg[k] = f(seg[2 * k + 0], seg[2 * k + 1]);
        }
    }

    Monoid query(int a, int b) {
        Monoid L = M1, R = M1;
        for (a += sz, b += sz; a < b; a >>= 1, b >>= 1) {
            if (a & 1)
                L = f(L, seg[a++]);
            if (b & 1)
                R = f(seg[--b], R);
        }
        return f(L, R);
    }

    Monoid operator[](const int& k) const {
        return seg[k + sz];
    }
};
//example
/*
int main() {
  int N, Q;
  scanf("%d %d", &N, &Q);
  SegmentTree< int > seg(N, [](int a, int b) { return min(a, b); }, INT_MAX);
  while(Q--) {
    int T, X, Y;
    scanf("%d %d %d", &T, &X, &Y);
    if(T == 0) seg.update(X, Y);
    else printf("%d\n", seg.query(X, Y + 1));
  }
}
*/
int N, A, B, S[101010];

void solve() {
    int bef = -INF;
    S[0] = -INF;
    SegmentTree<Mint> a(N + 10, [](Mint a, Mint b) { return a + b; }, Mint{0});
    SegmentTree<Mint> b(N + 10, [](Mint a, Mint b) { return a + b; }, Mint{0});
    a.set(0, Mint{1});
    b.set(0, Mint{1});
    a.build();
    b.build();
    int a_bef = 0;
    int b_bef = 0;
    for (int i = 2; i <= N; i++) {
        auto it = upper_bound(S, S + N + 1, S[i] - A);
        b.update(i - 1, a.query(0, min(i - 1, (int)(it - S))));
        it = upper_bound(S, S + N + 1, S[i] - B);
        a.update(i - 1, b.query(0, min(i - 1, (int)(it - S))));
        if (S[i] - S[i - 1] < A) {
            while (a_bef < i - 1) {
                b.update(a_bef, Mint{0});
                a_bef++;
            }
        }
        if (S[i] - S[i - 1] < B) {
            while (b_bef < i - 1) {
                a.update(b_bef, Mint{0});
                b_bef++;
            }
        }
    }
    cout << a.query(0, N + 5) + b.query(0, N + 5) << endl;
}

signed main() {
    cin.tie(nullptr);
    ios::sync_with_stdio(false);

    cin >> N >> A >> B;
    for (int i = 1; i <= N; i++) {
        cin >> S[i];
    }

    solve();
    return 0;
}


Measured memory_bytes: 6120