#include <bits/stdc++.h> // ver2.4.1
#include <complex.h>
//#include <boost/math/tools/minima.hpp>
//#include <boost/multiprecision/cpp_int.hpp>
#define fmin brent_find_minima
#define int long long
#define endl "\n"
#define ALL(v) (v).begin(),(v).end()
#define COUNT(a,k) upper_bound(ALL(a),k)-lower_bound(ALL(a),k)
#define BIGGER(a,k) a.end()-upper_bound(ALL(a),k)
#define SMALLER(a,k) lower_bound(ALL(a),k)-a.begin()
#define Vi vector<int>
#define VVi vector<Vi>
#define Vm vector<mint>
#define Vs vector<string>
#define Pii pair<int,int>
#define Pdd pair<double,double>
#define VPii vector<Pii>
#define Tiii tuple<int,int,int>
#define VTiii vector<Tiii>
#define PQi priority_queue<int>
#define PQir priority_queue<int,vector<int>,greater<int>>
#define pb push_back
#define mp make_pair
#define mt make_tuple
#define itos to_string
#define stoi stoll
#define FI first
#define SE second
#define cYES cout<<"YES"<<endl
#define cNO cout<<"NO"<<endl
#define cYes cout<<"Yes"<<endl
#define cNo cout<<"No"<<endl
#define cyes cout<<"yes"<<endl
#define cno cout<<"no"<<endl
#define sortr(v) sort(v,greater<>())
#define rep(i,a,b) for(int i=a;i<b;i++)
#define repeq(i,a,b) for(int i=a;i<=b;i++)
#define repreq(i,a,b) for(int i=a;i>=b;i--)
#define leng(n) (int)(log10(n)+1)
#define dem(a,b) ((a+b-1)/(b))
#define Vin(a) rep(iI,0,a.size())cin>>a[iI]
#define INF 3000000000000000000  //  3.0*10^18(MAXの1/3くらい)
#define MAX LLONG_MAX
#define PI 3.141592653589793238462
#define MOD 1000000007  //  10^9 + 7

using namespace std;
/* fmin(f,L,R,100) で関数の最小値を(x,min)で返す　*/
//using boost::math::tools::brent_find_minima;
/* cpp_int (任意の長さのint) */
//using boost::multiprecision::cpp_int;

/* デバッグ用 */
void Vout(auto a){if(a.size()==0) cout<<"."<<endl;
else{rep(i,0,a.size()-1)cout<<a[i]<<' ';if(a.size()>0)cout<<a.back()<<endl;}return;}
void Verr(auto a){if(a.size()==0) cerr<<"."<<endl;
else{rep(i,0,a.size()-1)cerr<<a[i]<<' ';if(a.size()>0)cerr<<a.back()<<endl;}return;}
void VVout(auto a){if(a.size()==0)cout<<"."<<endl;
else{rep(i,0,a.size())Vout(a[i]);}return;}
void VVerr(auto a){if(a.size()==0)cerr<<"."<<endl;
else{rep(i,0,a.size())Verr(a[i]);}return;}
void VPout(auto a){if(a.size()==0)cout<<"."<<endl;
else{rep(i,0,a.size())cout<<a[i].FI<<' '<<a[i].SE<<endl;}return;}
void VPerr(auto a){if(a.size()==0)cerr<<"."<<endl;
else{rep(i,0,a.size())cerr<<a[i].FI<<' '<<a[i].SE<<endl;}return;}

/* 便利関数 */
int gcd(int a,int b){return b?gcd(b,a%b):a;} // 最大公約数gcd
int lcm(int a,int b){return a/gcd(a,b)*b;} // 最小公倍数lcm
int mypow(int x, int n, int m){ // 累乗x^n(mod m) O(log(n))
if(n==0)return 1;if(n%2==0)return mypow(x*x%m,n/2,m);else return x*mypow(x,n-1,m)%m;}
int scomb(int n, int r){if((n-r)<r)r=n-r; // nCr(小さい場合)
int a=1;for(int i=n;i>n-r;--i){a=a*i;}for(int i=1;i<r+1;++i){a=a/i;}return a;}
int comb(int n, int r){if((n-r)<r)r=n-r; // nCr(%MOD)
int a=1;for(int i=n;i>n-r;--i){a=a*i%MOD;}for(int i=1;
i<r+1;++i){a=a*mypow(i,MOD-2,MOD)%MOD;}return a%MOD;}
Vi stpowV(){Vi a(100005);
a[0]=1;repeq(i,1,100004)a[i]=a[i-1]*i%MOD;return a;}
//Vi stpow = stpowV();  // 階乗配列(%MOD)
Vi Vsum(Vi &v){Vi S(v.size()+1);rep(i,1,S.size())S[i]+=v[i-1]+S[i-1];return S;}// 累積和
int digit(int k,int i){string s = itos(k);return s[s.size()-i]-'0';} // i桁目の数字
void press(auto &v){v.erase(unique(ALL(v)),v.end());} // 圧縮
Vi zip(Vi b){int Z=b.size(); // 座標圧縮
Pii p[Z+10];int a=b.size();Vi l(a);for(int i=0;i<a;i++)
p[i]=mp(b[i],i);sort(p,p+a);int w=0;for(int i=0;i<a;i++)
{if(i&&p[i].first!=p[i-1].first)w++;l[p[i].second]=w;}return l;}
Vi beki2V(){Vi a(61);int q = 1;rep(i,0,61){a[i]=q;q*=2;}return a;}
Vi beki2 = beki2V(); // 2^n配列
int modiv(int a,int b){return a*mypow(b,MOD-2,MOD)%MOD;} // a÷b(MOD環境)

int leaf(int n) {
  int a=1;
  while(a<n) a *= 2;
  return a;
}

struct PQ2 {
  
  vector<int> value;
  
  PQ2(int n) : value(0) {
    int ct = leaf(n)*2-1;
    rep(i,0,ct) value.pb(0); // 全部0
  }
  
  void update(int i, int x) {
    int N = (value.size()+1)/2;
    i += N - 1;
    value[i] += x;
    while (i > 0) {
      i = (i - 1) / 2;
      value[i] = value[i * 2 + 1]+value[i * 2 + 2];
    }
    return;
  }
  
  int at(int i) { //i番目の要素にアクセス
    int N = (value.size()+1)/2;
    return value[i-1+N];
  }
  
  int count(int i) { //i番目の要素にアクセス
    int N = (value.size()+1)/2;
    return value[i-1+N];
  }
  
  int RSQ2(int a, int b, int k, int l, int r) {
    // [a, b) の区間に対するクエリについて
    // ノード k （区間 [l, r) 担当）が答える
    if (r <= a || b <= l) return 0; // 区間が被らない場合は0を返す
    if (a <= l && r <= b)
      return value[k]; // ノード k の担当範囲がクエリ区間 [a, b)に完全に含まれる
    else {
      int c1 = RSQ2(a, b, 2 * k + 1, l, (l + r) / 2); // 左の子に値を聞く
      int c2 = RSQ2(a, b, 2 * k + 2, (l + r) / 2, r); // 右の子に値を聞く
      return c1+c2; // 左右の子の値の sum を取る
    }
  }
  
  int rsum(int a,int b) {
    int N = (value.size()+1)/2;
    return RSQ2(a,b+1,0,0,N);
  }
  
  void insert(int a) {
    update(a,1);
    return;
  }
  
  int rank(int i) {
    i++;
    int L=0,R=(value.size()+1)/2-1;
    int mid = (L+R)/2;
    int eq,minus,ct=0;
    while(ct<300){
      eq = rsum(0,mid);
      minus = rsum(0,mid-1);
      
      if(eq == i && minus <= i-1) {
        break;
      }
      if(eq > i) {
        R = mid;
      }
      if(eq == i && minus == i) {
        R = mid;
      }
      if(eq < i) {
        L = mid;
      }
      mid = (L+R)/2;
      ct++;
    }
    if(ct==300) mid++;
    return mid;
  }
  
  int rankr(int i) {
    return rank(value[0]-1-i);
  }
  
  void erase(int a) {
    update(a,-1);
    return;
  }
  
  int smaller(int k) {
    int L=0,R=k-1;
    if(rsum(0,k-1)==0) return -1;
    int mid = (L+R)/2;
    while(L<R) {
      if(rsum(mid,R) == 0){
        R = mid-1;
      }
      else {
        L = mid;
      }
      mid = (L+R+1)/2;
    }
    return mid;
  }
  
  int bigger(int k) {
    int L=k+1,R=(value.size()+1)/2-1;
    if(rsum(L,R)==0) return -1;
    int mid = (L+R)/2;
    while(L<R) {
      if(rsum(L,mid) == 0){
        L = mid+1;
      }
      else {
        R = mid;
      }
      mid = (L+R)/2;
    }
    return mid;
  }
  
};

signed main() {
  cin.tie(0);cout.tie(0);ios::sync_with_stdio(false);cout<<fixed<<setprecision(12);
  int n;
  cin >> n;
  Vi a(n);
  Vin(a);
  
  Vi pl(n);
  
  rep(i,0,n){
    pl[a[i]-1] = i+1;
  }
  
  //Verr(pl);
  
  PQ2 que(200020);
  
  que.insert(0);
  que.insert(n+1);
  
  int ans = 0;
  
  rep(i,0,n){
    que.insert(pl[i]);
    
    int l,r,now;
    
    now = pl[i];
    l = que.smaller(pl[i]);
    r = que.bigger(pl[i]);
    
    int ran = (now-l)*(r-now);
    
    ans += ran*(i+1);
  }
  cout << ans << endl;
  
  return 0;
}

Measured memory_bytes: 9328