/*#pragma GCC optimize("Ofast")
#pragma GCC target("avx,avx2,fna")
#pragma GCC optimization ("unroll-loops")*/
#include<bits/stdc++.h>
using namespace std;
#define fast ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
#define ordered_set tree<int, null_type,less<int>, rb_tree_tag,tree_order_statistics_node_update>
#define ll long long
#define pb push_back
#define mp make_pair
#define endl "\n"
#define int ll
#define vi vector<int>
#define vb vector<bool>
#define vvb vector<vb >
#define pii pair<int,int>
#define ss second
#define ff first
#define vpii vector<pii>
#define vvi vector<vi >
#define vs vector<string>
#define vvs vector<vs >
#define pqi priority_queue <int>
#define minpqi priority_queue <int, vector<int>, greater<int> >
#define all(x) x.begin(),x.end()
#define mii map<int,int>
#define for0(i,n) for(ll i=0;i<n;i++)
#define for1(i,n) for(ll i=1;i<=n;i++)
#define per(i,n) for(ll i=n-1;i>=0;i--)
#define per1(i,n) for(ll i=n;i>0;i--)
#define repeat(i,start,n) for(ll i=start;i<n;i++)
#define inp(arr,n) ll arr[n];rep(i,n){ cin>>arr[i];}
#define inp1(arr,n) ll arr[n+1];rep1(i,n){ cin>>arr[i];}
#define inp2d(arr,n,m) ll arr[n][m];rep(i,n)rep(j,m)cin>>arr[i][j];
#define inpg(adj,m) rep(i,m){int a,b;cin>>a>>b;adj[a].pb(b);adj[b].pb(a);}
#define print(a,n) for(ll i=0;i<n;i++){ cout<<a[i]<<" ";}
#define print1(a,n) for(ll i=1;i<=n;i++){ cout<<a[i]<<endl;}
#define mod 1000000007
#define maxx 1000000000000000000
#define PI 3.141592653589793238462643383279
#define mmax(a,b,c) max(a,max(b,c))
#define mmin(a,b,c) min(a,min(b,c))
#define init(arr,a) memset(arr,a,sizeof(arr))
#define lb lower_bound
#define ub upper_bound
#define er equal_range
#define maxe *max_element
#define mine *min_element
bool sortbysec(const pair<int,int> &a,const pair<int,int> &b){
	if(a.ss==b.ss)
		return a.ff<b.ff;
	return (a.second<b.second);
}
string convert_to_bit(int a,int bit){
	string s;
	while(a>0){
		s+=(a%2)+48;
		a/=2;
	}
	while(s.size()<bit)
		s+='0';
	reverse(s.begin(),s.end());
	return s;
}
int to_int(string s)
{
	int ans=0;
	string temp;
	int i=0;
	while(s[i]=='0')
	{
		i++;
	}
	if(i==s.size())
		return 0;
	temp.assign(s,i,s.size());
	int mul=1;
	for(i=temp.size()-1;i>=0;i--)
	{
		int a=temp[i]-'0';
		ans+=mul*a;
		mul*=10;
	}
	return ans;

}
string to_string(int n)
{
	string ans="";
	if(n==0)
		return "0";
	while(n>0)
	{
		int a=n%10;
		n/=10;
		char temp=a+'0';
		ans+=temp;
	}
	reverse(all(ans));
	return ans;
}
int bin_to_dec(int n)
{
	int num = n;
	int dec_value = 0;
	int base = 1;
	int temp = num;
	while (temp) {
		int last_digit = temp % 10;
		temp = temp / 10;
		dec_value += last_digit * base;
		base = base * 2;
	}
	return dec_value;
}
int binstr_to_dec(string s)
{
	int ans=0;
	for0(i,s.size())
		if(s[i]=='1')
			ans+=pow(2,s.size()-i-1);
	return ans;
}
int dx[]={0,1,0,-1};
int dy[]={1,0,-1,0};
void faltu()
{
	int a=2;
	while(a>0)a--;
}
int nCr(ll n, ll r)
{
	ll res = 1;
	if ( r > n - r )
		r = n-r;
	for (ll i = 0; i < r; ++i)
	{
		res *= (n - i);	//general term (n-x)/(1+x)
		res /= (i + 1);
	}
	return res;
}
//------------------------------------Code Starts here------------------------------------//

void solve()
{

}
main()
{

	/*int n,k;
	cin>>n>>k;
	int p[n],c[n];
	for0(i,n)cin>>p[i];
	for0(i,n)cin>>c[i];
	int cnt=0;vi v;
	for0(i,n)
	{
		if(c[i]>=0){v.pb(c[i]);cnt++;}
	}
	int maxi=-100000000000;
	if(cnt==0)
	{
		for0(i,n)
		maxi=max(c[i],maxi);
	}
	sort(all(v));
	int sum=0;
	if(cnt==0)cout<<maxi<<endl;
	else
	{int range=min(k,(int)v.size());
	for(int i=v.size()-1;i>=v.size()-range;i--)
		sum+=v[i];
		cout<<sum<<endl;
	}*/


	/*int x,k,d;
	cin>>x>>k>>d;
	x=abs(x);
	int turn=abs(x);
	turn=turn/d;
	int mini=min(turn,k);
	int ans=mini*d;
  if(mini==turn)
	{
		if((k-turn)%2==0)cout<<abs(x-ans);
		else cout<<abs(x-ans-d);
	}
	else cout<<abs(x-k*d);*/

    int n;
    cin>>n;
    int a[n];
    for0(i,n)
    {
    	cin>>a[i];
    }
    int cnt=0;
    for0(i,n)
    {
    	for(int j=i+1;j<n;j++)
			{
        if(a[j]!=a[i])
				{for(int k=j+1;k<n;k++)
				{
					if(a[k]!=a[j]&&a[i]!=a[k]&&a[i]!=a[j])
					{


							if(a[i]+a[j]>a[k]&&a[i]+a[k]>a[j]&&a[j]+a[k]>a[i]){cnt++;}

					}
				}
			}}
    }
    cout<<cnt<<endl;
}




Measured memory_bytes: 3672