Among Johnny's numerous hobbies, there are two seemingly harmless ones: applying bitwise operations and sneaking into his dad's office. As it is usually the case with small children, Johnny is unaware that combining these two activities can get him in a lot of trouble.

There is a set $S$ containing very important numbers on his dad's desk. The minute Johnny heard about it, he decided that it's a good idea to choose a positive integer $k$ and replace each element $s$ of the set $S$ with $s \oplus k$ ($\oplus$ denotes the exclusive or operation). 

Help him choose such $k$ that Johnny's dad will not see any difference after his son is done playing (i.e. Johnny will get the same set as before playing). It is possible that no such number exists. It is also possible that there are many of them. In such a case, output the smallest one. Note that the order of elements in a set doesn't matter, i.e. set $\{1, 2, 3\}$ equals to set $\{2, 1, 3\}$.

Formally, find the smallest positive integer $k$ such that $\{s \oplus k | s \in S\} = S$ or report that there is no such number.

For example, if $S = \{1, 3, 4\}$ and $k = 2$, new set will be equal to $\{3, 1, 6\}$. If $S = \{0, 1, 2, 3\}$ and $k = 1$, after playing set will stay the same.


-----Input-----

In the first line of input, there is a single integer $t$ ($1 \leq t \leq 1024$), the number of test cases. In the next lines, $t$ test cases follow. Each of them consists of two lines. 

In the first line there is a single integer $n$ ($1 \leq n \leq 1024$) denoting the number of elements in set $S$. Second line consists of $n$ distinct integers $s_i$ ($0 \leq s_i < 1024$), elements of $S$.

It is guaranteed that the sum of $n$ over all test cases will not exceed $1024$.


-----Output-----

Print $t$ lines; $i$-th line should contain the answer to the $i$-th test case, the minimal positive integer $k$ satisfying the conditions or $-1$ if no such $k$ exists.


-----Example-----
Input
6
4
1 0 2 3
6
10 7 14 8 3 12
2
0 2
3
1 2 3
6
1 4 6 10 11 12
2
0 1023

Output
1
4
2
-1
-1
1023



-----Note-----

In the first test case, the answer is $1$ because it is a minimum positive integer and it satisfies all the conditions.

```python

USER_FILENAME = "<user_code>"
import sys, json, builtins
import math, heapq, bisect, itertools, functools, collections, statistics, fractions, decimal, operator, array, random, re, string, os, pathlib
try:
    import resource as _res
except Exception:
    _res = None
from collections import Counter, defaultdict, deque, OrderedDict
from functools import lru_cache, reduce
from itertools import accumulate, permutations, combinations, product
from math import gcd, ceil, floor, sqrt
from decimal import Decimal
try:
    from typing import *
except Exception:
    pass
try:
    sys.setrecursionlimit(1_000_000)
except Exception:
    pass
try:
    import site as _site
    try:
        _sys_sites = _site.getsitepackages() if hasattr(_site, "getsitepackages") else []
        for _p in _sys_sites:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
    try:
        _usp = _site.getusersitepackages()
        if isinstance(_usp, str):
            _usp = [_usp]
        for _p in _usp:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
except Exception:
    pass

ns = {"__name__": "__main__"}
for _k, _v in list(globals().items()):
    if not _k.startswith("_"):
        ns[_k] = _v
_CODE = 'import sys\nints = (int(x) for x in sys.stdin.read().split())\nsys.setrecursionlimit(3000)\n\ndef main():\n    ntc = next(ints)\n    for tc in range(1,ntc+1):\n        n = next(ints)\n        s = [next(ints) for i in range(n)]\n        P = None\n        for x in s:\n            p = set(x^y for y in s)\n            if P==None: P = p\n            else: P &= p\n        ans = next(iter(sorted(P)[1:]), -1)\n        print(ans)\n    return\n\nmain()\n'
_co = compile(_CODE, USER_FILENAME, "exec")
exec(_co, ns, ns)

```

Measured memory_bytes: 12827