VK gave a problem to Chef, but Chef is too lazy, so he asked you to solve the problem for him. The statement of the problem follows.
Consider an integer with $N$ digits (in decimal notation, without leading zeroes) $D_1, D_2, D_3, \dots, D_N$. Here, $D_1$ is the most significant digit and $D_N$ the least significant. The weight of this integer is defined as ∑i=2N(Di−Di−1).∑i=2N(Di−Di−1).\sum_{i=2}^N (D_i - D_{i-1})\,.
You are given integers $N$ and $W$. Find the number of positive integers with $N$ digits (without leading zeroes) and weight equal to $W$. Compute this number modulo $10^9+7$.

-----Input-----
- The first line of the input contains a single integer $T$ denoting the number of test cases. The description of $T$ test cases follows.
- The first and only line of each test case contains two space-separated integers $N$ and $W$ denoting the number of digits and the required weight.

-----Output-----
For each test case, print a single line containing one integer — the number of $N$-digit positive integers with weight $W$, modulo $10^9+7$.

-----Constraints-----
- $1 \le T \le 10^5$
- $2 \le N \le 10^{18}$
- $|W| \le 300$

-----Subtasks-----
Subtask #1 (20 points):
- $1 \le T \le 10^3$
- $2 \le N \le 10^3$
Subtask #2 (80 points): original constraints

-----Example Input-----

1
2 3

-----Example Output-----

6

-----Explanation-----
Example case 1: Remember that the digits are arranged from most significant to least significant as $D_1, D_2$. The two-digit integers with weight $3$ are $14, 25, 36, 47, 58, 69$. For example, the weight of $14$ is $D_2-D_1 = 4-1 = 3$. We can see that there are no other possible numbers.

```python

USER_FILENAME = "<user_code>"
import sys, json, builtins
import math, heapq, bisect, itertools, functools, collections, statistics, fractions, decimal, operator, array, random, re, string, os, pathlib
try:
    import resource as _res
except Exception:
    _res = None
from collections import Counter, defaultdict, deque, OrderedDict
from functools import lru_cache, reduce
from itertools import accumulate, permutations, combinations, product
from math import gcd, ceil, floor, sqrt
from decimal import Decimal
try:
    from typing import *
except Exception:
    pass
try:
    sys.setrecursionlimit(1_000_000)
except Exception:
    pass
try:
    import site as _site
    try:
        _sys_sites = _site.getsitepackages() if hasattr(_site, "getsitepackages") else []
        for _p in _sys_sites:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
    try:
        _usp = _site.getusersitepackages()
        if isinstance(_usp, str):
            _usp = [_usp]
        for _p in _usp:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
except Exception:
    pass

ns = {"__name__": "__main__"}
for _k, _v in list(globals().items()):
    if not _k.startswith("_"):
        ns[_k] = _v
_CODE = '# Python3 program to find total possible \n# numbers with n digits and weight w \n\n# Function to find total possible \n# numbers with n digits and weight w \ndef findNumbers(n, w): \n\n x = 0; \n s = 0; \n\n # When Weight of an integer \n # is Positive \n if (w >= 0 and w <= 8): \n  # Subtract the weight from 9 \n  x = 9 - w; \n \n # When weight of an integer \n # is negative \n elif (w >= -9 and w <= -1): \n  \n  # add the weight to 10 to \n  # make it positive \n  x = 10 + w; \n \n s = pow(10, n - 2); \n s = (x * s); \n \n return s; \n\n# Driver code \n\n# number of digits in an \n# integer and w as weight \n\n\n# This code is contributed \n# by mits\nm = 10**9 + 7\nfor _ in range(int(input())):\n n,w = list(map(int,input().split()))\n print(findNumbers(n,w)%m)\n'
_co = compile(_CODE, USER_FILENAME, "exec")
exec(_co, ns, ns)

```

Measured memory_bytes: 13111