/*
    author : Aryan Agarwal, IIT KGP
    created : 22-August-2020 18:48:23 IST
*/

#include <bits/stdc++.h>
using namespace std;

typedef long long int ll;
typedef unsigned long long ull;
#define int ll

const int INF = (int)2e18;
const int MOD = 1000000007; /*more than (10)^9*/ /*7 + 1e9*/
const int PEG = 998244353; /*less than (10)^9*/  /*1 + 7*17*(2)^23*/
long double pie = acos(-1);
int timeStart = clock();

typedef vector<int> vi;
typedef vector<string> vs;
typedef vector<vi> vvi;
typedef pair<int, int> pii;
typedef vector<pii> vpii;
#define X first
#define Y second
#define pb push_back
#define sz(a) (ll)(a).size()
#define all(a) (a).begin(), (a).end()

#define F(i, a, b) for (ll i = a; i <= b; i++)
#define RF(i, a, b) for (ll i = a; i >= b; i--)
#define Fo(i, a, b, j) for (ll i = a; i <= b; i += j)
#define RFo(i, a, b, j) for (ll i = a; i >= b; i -= j)
#define in(a, n) F(i, 0, n - 1) \
                     cin >> a[i]
#define in1(a, n) F(i, 1, n) \
                      cin >> a[i]
#define out(a, n) F(i, 0, n - 1) \
                      cout << a[i] << " "
#define out1(a, n) F(i, 1, n) \
                       cout << a[i] << " "

#define fast                          \
    ios_base::sync_with_stdio(false); \
    cin.tie(NULL);                    \
    cout.tie(NULL)
#define popcount __builtin_popcountll
#define loop_check                  \
    if ((clock() - timeStart) >= 1) \
    break

#define pfy cout << "YES"
#define pfn cout << "NO"
#define pfn1 cout << "-1" // printf negative 1
#define pf1 cout << "1"
#define nl cout << "\n"

#define watch(x) cout << #x << " is " << x << "\n"
#define dbg(...) __f(#__VA_ARGS__, __VA_ARGS__)
template <typename Arg1>
void __f(const char *name, Arg1 &&arg1);
template <typename Arg1, typename... Args>
void __f(const char *names, Arg1 &&arg1, Args &&... args);

ll binpow(ll x, ll y, ll p);

signed main()
{
#ifndef ONLINE_JUDGE
// freopen("input.txt","r",stdin);
// freopen("output.txt","w",stdout);
#endif
    fast;

    int h, w, m;
    cin >> h >> w >> m;

    vpii v(m);
    set<pii> s;

    int cnth[h] = {}, cntw[w] = {}, mxh = 0, mxw = 0, hh = 0, ww = 0;

    F(i, 0, m - 1)
    {
        cin >> v[i].X >> v[i].Y;
        v[i].X--;
        v[i].Y--;
        s.insert({v[i].X, v[i].Y});

        cnth[v[i].X]++;
        if (cnth[v[i].X] > mxh)
        {
            hh = v[i].X;
            mxh = cnth[v[i].X];
        }

        cntw[v[i].Y]++;
        if (cntw[v[i].Y] > mxw)
        {
            ww = v[i].Y;
            mxw = cntw[v[i].Y];
        }
    }

    vi vh,vw;

    F(i,0,h-1)
    {
        if(cnth[i]==mxh)vh.pb(i);
    }
    F(i,0,w-1)
    {
        if(cntw[i]==mxw)vw.pb(i);
    }

    for(int i : vh)
    {
        for(int j : vw)
        {
            if(s.find({i,j})==s.end())
            {
                cout<<cnth[hh] + cntw[ww];
                return 0;
            }
        }
    }

    cout<<cnth[hh] + cntw[ww]-1;

    return 0;
}

/* ########## TIPS ##########
#
#   ceil(((1.0)*a)/b) is same as (a+b-1)/b
#   don't use ceil() function, since it returns double values,
#   it has some precision errors and doesn't work for large no.s
#
#   while using ceil() function,always type cast the parameters to double like ceil((1.0*a)/b)
#
#   mod_inverse(n,p) is binpow(n,p-2,p)
#
#   for creating a 2d vector "vec" with n rows & m columns then initialise it with it 0
#   vvi vec(n,vi(m,0))
#   vector<vector<int> > vec( n , vector<int> (m, 0))
#
#   if you want to insert an integer and a pair in a set then,
#   set <pair<int,int>,int> is wrong
#   set< pair < pii,int> > is correct                       // according to my macros
#   set < pair<pair<int,int> , int> > is correct            // pair of a pair & a integer
#
#   if you want just the sum of smallest k elements of a array
#   use nth_element(arr,arr+n) ,
#         use nth_element(arr,arr+n,greater <int> ()) if you want largest k elements
#   then take sum of first k elements ,it works in O(n) ,
#   rather than first sorting then taking sum of first k elements, which works in O(n*logn)
#
#   if you want to check that a given no. 'N' is power of 2
#   use N&(N-1)==0  ,   rather than log2(N)==ceil(log2(N))
#
#   upper_bound is > val in a non-decreasing array
#   lower_bound is >= val in a non-decreasing array
#   upper_bound is < val in a non-increasing array (use greater <int> () in 4th parameter) 
#   lower_bound is <= val in a non-increasing array (use greater <int> () in 4th parameter) 
#   
#   don't use stoi() , it doesn't works for large strings
#   use stoi() to convert string to integer, (2nd & 3rd parameter are optional)
#   1st parameter is string (address of char array)
#   2nd parameter is starting index, 0 most of the times
#   3rd parameter is base of integer, like 2 (for binary no.s), 10 (for decimel no.s) etc.
#
#   for creating a string 'S' of length 'len' , having each character 'c'
#   type    string S(len,c);    while creating the string
#
#   gcd(x-y,x)=gcd(x,y)=gcd(x+y,y)      (for all x and y)
#   gcd(a,b)=gcd(b,a)                   (for all a and b)
#
#   a+b = a|b + a&b
#   a+b = a^b + 2*(a&b)
#   x<<y = x*(2^y)
#   x>>y = x/(2^y)
#
*/

ll binpow(ll x, ll y, ll p) /* (x^y)%p in O(log y) */
{
    ll res = 1;
    x = x % p;
    while (y > 0)
    {
        if (y & 1)
            res = (res * x) % p;
        y = y >> 1;
        x = (x * x) % p;
    }
    return res;
}

template <typename Arg1>
void __f(const char *name, Arg1 &&arg1)
{
    std::cout << name << " : " << arg1 << endl;
}

template <typename Arg1, typename... Args>
void __f(const char *names, Arg1 &&arg1, Args &&... args)
{
    const char *comma = strchr(names + 1, ',');
    std::cout.write(names, comma - names) << " : " << arg1 << "\n";
    __f(comma + 1, args...);
}

Measured memory_bytes: 39740