#include<bits/stdc++.h>
using namespace std;
typedef long long int ll;
#define mod 998244353
#include<string.h>
#define inf 1000000000000000000
#define maxn 200006
typedef pair<ll,ll> pll;
typedef pair<int,int> pint;
#define endl '\n'
#define mapint_iterator map<int,int> :: iterator
#define mapll_iterator map<ll,ll> :: iterator
#define setint_iterator set<int> :: iterator
#define setll_iterator set<ll> :: iterator
#define setpint_iterator set<pint> :: iterator
#define setpll_iterator set<pll> :: iterator
#define trace(x) cout<<#x<<": "<<x<<" "<<endl
#define trace2(x,y) cout<<#x<<": "<<x<<" | "<<#y<<": "<<y<<endl
#define trace3(x,y,z) cout<<#x<<":" <<x<<" | "<<#y<<": "<<y<<" | "<<#z<<": "<<z<<endl
#define trace4(a,b,c,d) cout<<#a<<": "<<a<<" | "<<#b<<": "<<b<<" | "<<#c<<": "<<c<<" | "<<#d<<": "<<d<<endl
#define cout1(a) cout<<a<<endl
#define cout2(a,b) cout<<a<<' '<<b<<endl
#define cout3(a,b,c) cout<<a<<" "<<b<<" "<<c<<endl
#define cout4(a,b,c,d) cout<<a<<" "<<b<<" "<<c<<" "<<d<<endl
#define vcout(v,i) cout<<v[i].fi<<" "<<v[i].se<<endl
typedef priority_queue<ll,vector<ll>,greater<ll> > pqset;
typedef priority_queue<pint,vector<pint>,greater<pint> > pqset_ll;
#define pb push_back
#define fi first
#define se second
#include<ext/pb_ds/assoc_container.hpp>
ll dxk[]={0,0,1,-1,1,1,-1,-1};
ll dyk[]={1,-1,0,0,1,-1,1,-1};
#include<ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
typedef tree<int,null_type,less<int>,rb_tree_tag,tree_order_statistics_node_update> os;
typedef tree<pll,null_type,less<pll>,rb_tree_tag,tree_order_statistics_node_update> os_pair;
#define mp make_pair
#define acc (ios::sync_with_stdio(false),cin.tie(0))
#define rep(i,n) for(ll i=0;i<n;i++)
#define per(i,n) for(ll i=n-1;i>=0;i--)
#define rep1(i,n) for(ll i=1;i<=n;i++)
#define per1(i,n) for(ll i=n;i>0;i--)
#define repeat(i,start,n) for(ll i=start;i<n;i++)
#define print(a,n) for(ll i=0;i<n;i++){ cout<<a[i]<<" ";}
ll ll_max(ll a,ll b,ll c){return max(a,max(b,c));}
int int_max(int a,int b,int c){return max(a,max(b,c));}
ll ll_min(ll a,ll b,ll c){return min(a,min(b,c));}
int int_min(int a,int b,int c){return min(a,min(b,c));}
ll max(int a,ll b){ return max((ll)a,b);}
ll min(int a,ll b){ return min((ll)a,b);} 
ll min(ll a,int b){ return min(a,(ll)b);}
ll max(ll a,int b){ return max(a,(ll)b);}
ll dx[]={0,0,1,-1};
ll dy[]={1,-1,0,0};
//ifstream cin("b_read_on.txt"); ofstream cout("output3.txt");
//Chronology: Binary Search,Greedy,dp,dfs and similar
//Use (<<) for multiplication
//Use (>>) for division
// In dp, first try top-down,then bottom-up
//ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL);cout<<fixed;cerr.tie(NULL);cout.precision(10);
// find_by_order -> value at index
// order_of_key -> index of value
ll Tree[4*maxn];
void update_max(int node,int start,int end,int i,ll val){
	if(start==end){
		Tree[node]=val;
		return;
	}
	int mid=((start+end)>>1);
	if(i<=mid)
		update_max(2*node+1,start,mid,i,val);
	else
		update_max(2*node+2,mid+1,end,i,val);
	//According to the question,change from here
	Tree[node]=max(Tree[2*node+1],Tree[2*node+2]);
}
ll query_max(int node,int start,int end,int l,int r){ 
	if(start>end||end<l||start>r)
		return 0;//0 in case of sum , high value in case of min , low value in case of max and soooo on 
	if(start>=l&&end<=r)
		return(Tree[node]);
	int mid = (start+end)/2 ; 
	ll p1 = query_max(node*2+1, start, mid, l,r);
	ll p2 = query_max(node*2+2, mid+1, end , l,r);
	return max(p1,p2);
}
ll power(ll a,ll b){
	if(a==1)
		return 1;
	if(b==0)
		return 1;
	ll c=power(a,b/2);
	ll res=1;
	if(b%2){
		res=(c*c)%mod;
		res*=a;
		res%=mod;
	}
	else
		res=((c*c)%mod);
	return res;
}
ll modInv(ll a){return power(a,mod-2)%mod;}
void solve(int countu){
	ll n;
	cin>>n;
	ll h[n],a[n];
	rep(i,n)
		cin>>h[i];
	rep(i,n)
		cin>>a[i];
	ll maxx=0;
	rep(i,n){
		ll o=h[i];
		ll p=query_max(0,0,n,0,h[i]);
		maxx=max(maxx,p+a[i]);
		update_max(0,0,n-1,h[i],p+a[i]);
	}
	cout1(maxx);
}
int main(){
    int t=1;
    //ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL);cout<<fixed;cerr.tie(NULL);
	//cin>>t;
	int countu=1;
    while(t--){
    	solve(countu);
    	countu++;
    }
}

Measured memory_bytes: 9600