#include "bits/stdc++.h"
#define rep(i, j) for (int i = 0; i < j; i++)
#define srep(i, j, k) for (int i = j; i < k; i++)
using namespace std;
using ll = long long;
using P = pair<int, int>;
using ull = unsigned long long;

template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return true; } return false; }
template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return true; } return false; }

//エラトステネスの篩
vector<int> sosuu(100001);
vector<int> estora(vector<int> num) {
    int sel = 0;
    while (sel < num.size()) {
        int d = num[sel];
        for (int i = 0; i < num.size(); i++) {
            if (num[i] % d == 0 && num[i] != d && d != 1) {
                num.erase(num.begin() + i);
                i--;
            }
        }
        sel++;
    }
    rep(i, num.size()) {
        sosuu[num[i]] = 1;
    }
    return num;
}
/*ライブラリ最大公約数*/
//ユーグリッドの互除法
int gcd(int x, int y) {
    int num[3];
    num[0] = (x > y) ? x : y;
    num[1] = (x <= y) ? x : y;
    num[2] = num[0] % num[1];

    while (num[2]) {
        num[0] = num[1];
        num[1] = num[2];
        num[2] = num[0] % num[1];
    }

    return num[1];
}

/*素因数分解*/
//自作ライブラリ
//iを常に素数にしておかないとうまくできない&&計算量ヤバイ
//エストラネスの篩で素数を振るっておく必要性がありそう
vector<ll> fac(ll n, vector<ll> num) {
    ll kazu = n;
    for (int i = 2; i <= n; i++) {
        while (1) {
            if (kazu % i != 0) break;

            kazu /= i;
            num[i]++;
        }
    }
    if (kazu == n && n != 1)
        num[n]++;
    return num;
    int ans = 0;
    if (kazu != 1) ans++;
    for (int i = 2; i <= sqrt(n); i++) {
        for (int j = 1; j <= num[i]; j++) {
            num[i] -= j;
            ans++;
        }
    }
    return num;
}

bool IsPrime(int num)
{
    if (num < 2) return false;
    else if (num == 2) return true;
    else if (num % 2 == 0) return false; // 偶数はあらかじめ除く

    double sqrtNum = sqrt(num);
    for (int i = 3; i <= sqrtNum; i += 2)
    {
        if (num % i == 0)
        {
            // 素数ではない
            return false;
        }
    }

    // 素数である
    return true;
}
const int INF = 1001001001;

//mint用の定数 (10の9乗 + 7)
const int mod = 1000000007;

struct mint {
    ll x; // typedef long long ll;
    mint(ll x = 0) :x((x% mod + mod) % mod) {}
    mint operator-() const { return mint(-x); }
    mint& operator+=(const mint a) {
        if ((x += a.x) >= mod) x -= mod;
        return *this;
    }
    mint& operator-=(const mint a) {
        if ((x += mod - a.x) >= mod) x -= mod;
        return *this;
    }
    mint& operator*=(const mint a) { (x *= a.x) %= mod; return *this; }
    mint operator+(const mint a) const { return mint(*this) += a; }
    mint operator-(const mint a) const { return mint(*this) -= a; }
    mint operator*(const mint a) const { return mint(*this) *= a; }
    mint pow(ll t) const {
        if (!t) return 1;
        mint a = pow(t >> 1);
        a *= a;
        if (t & 1) a *= *this;
        return a;
    }

    // for prime mod
    mint inv() const { return pow(mod - 2); }
    mint& operator/=(const mint a) { return *this *= a.inv(); }
    mint operator/(const mint a) const { return mint(*this) /= a; }
};
istream& operator>>(istream& is, const mint& a) { return is >> a.x; }
ostream& operator<<(ostream& os, const mint& a) { return os << a.x; }

int main() {
    int h, w;
    cin >> h >> w;
    vector<string> s(h);
    rep(i, h) cin >> s[i];

    int b_masu = 0;
    rep(i, h)rep(j, w) {
        if (s[i][j] == '#')
            b_masu++;
    }
    queue<P> masu;
    P f = { 0, 0 };
    masu.push(f);
    vector<vector<int> > map(h, vector<int> (w, -1));
    map[0][0] = 1;
    while (!masu.empty()) {
        P current = masu.front(); masu.pop();
        vector<vector<int> > vec = {
            {0,1, 0, -1},
            {1, 0, -1, 0}
        };
        rep(i, 4) {
            if (current.first + vec[0][i] >= 0 && current.first + vec[0][i] < h && current.second + vec[1][i] >= 0 && current.second + vec[1][i] < w) {
                if (s[current.first + vec[0][i]][current.second + vec[1][i]] == '#') continue;
                if (map[current.first + vec[0][i]][current.second + vec[1][i]] != -1) continue;
                P kari = { current.first + vec[0][i], current.second + vec[1][i] };
                map[kari.first][kari.second] = map[current.first][current.second] + 1;
                masu.push(kari);
            }
        }
    }
    if (map[h - 1][w - 1] == -1) {
        cout << -1 << endl;
        return 0;
    }
    int ans = (h * w) - (b_masu + map[h - 1][w - 1]);
    cout << ans << endl;
    return 0;
}


Measured memory_bytes: 3792