RedDreamer has an array $a$ consisting of $n$ non-negative integers, and an unlucky integer $T$.

Let's denote the misfortune of array $b$ having length $m$ as $f(b)$ — the number of pairs of integers $(i, j)$ such that $1 \le i < j \le m$ and $b_i + b_j = T$. RedDreamer has to paint each element of $a$ into one of two colors, white and black (for each element, the color is chosen independently), and then create two arrays $c$ and $d$ so that all white elements belong to $c$, and all black elements belong to $d$ (it is possible that one of these two arrays becomes empty). RedDreamer wants to paint the elements in such a way that $f(c) + f(d)$ is minimum possible.

For example:

  if $n = 6$, $T = 7$ and $a = [1, 2, 3, 4, 5, 6]$, it is possible to paint the $1$-st, the $4$-th and the $5$-th elements white, and all other elements black. So $c = [1, 4, 5]$, $d = [2, 3, 6]$, and $f(c) + f(d) = 0 + 0 = 0$;  if $n = 3$, $T = 6$ and $a = [3, 3, 3]$, it is possible to paint the $1$-st element white, and all other elements black. So $c = [3]$, $d = [3, 3]$, and $f(c) + f(d) = 0 + 1 = 1$. 

Help RedDreamer to paint the array optimally!


-----Input-----

The first line contains one integer $t$ ($1 \le t \le 1000$) — the number of test cases. Then $t$ test cases follow.

The first line of each test case contains two integers $n$ and $T$ ($1 \le n \le 10^5$, $0 \le T \le 10^9$) — the number of elements in the array and the unlucky integer, respectively. 

The second line contains $n$ integers $a_1$, $a_2$, ..., $a_n$ ($0 \le a_i \le 10^9$) — the elements of the array. 

The sum of $n$ over all test cases does not exceed $10^5$.


-----Output-----

For each test case print $n$ integers: $p_1$, $p_2$, ..., $p_n$ (each $p_i$ is either $0$ or $1$) denoting the colors. If $p_i$ is $0$, then $a_i$ is white and belongs to the array $c$, otherwise it is black and belongs to the array $d$.

If there are multiple answers that minimize the value of $f(c) + f(d)$, print any of them.


-----Example-----
Input
2
6 7
1 2 3 4 5 6
3 6
3 3 3

Output
1 0 0 1 1 0 
1 0 0

```python

USER_FILENAME = "<user_code>"
import sys, json, builtins
import math, heapq, bisect, itertools, functools, collections, statistics, fractions, decimal, operator, array, random, re, string, os, pathlib
try:
    import resource as _res
except Exception:
    _res = None
from collections import Counter, defaultdict, deque, OrderedDict
from functools import lru_cache, reduce
from itertools import accumulate, permutations, combinations, product
from math import gcd, ceil, floor, sqrt
from decimal import Decimal
try:
    from typing import *
except Exception:
    pass
try:
    sys.setrecursionlimit(1_000_000)
except Exception:
    pass
try:
    import site as _site
    try:
        _sys_sites = _site.getsitepackages() if hasattr(_site, "getsitepackages") else []
        for _p in _sys_sites:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
    try:
        _usp = _site.getusersitepackages()
        if isinstance(_usp, str):
            _usp = [_usp]
        for _p in _usp:
            if _p and _p not in sys.path:
                sys.path.append(_p)
    except Exception:
        pass
except Exception:
    pass

ns = {"__name__": "__main__"}
for _k, _v in list(globals().items()):
    if not _k.startswith("_"):
        ns[_k] = _v
_CODE = "import random\n\n\ndef gcd(a, b):\n    if a == 0:\n        return b\n    return gcd(b % a, a)\n\n\ndef lcm(a, b):\n    return (a * b) / gcd(a, b)\n\n\nfor _ in range(int(input())):\n    #n = int(input())\n    n,t= map(int, input().split())\n    a = list(map(int, input().split()))\n    d={}\n    for i in range(n):\n        if a[i] in d:\n            d[a[i]].append(i)\n        else:\n            d[a[i]]=[i]\n    ans=[-1]*n\n    for i in d.keys():\n        if ans[d[i][0]]==-1:\n            if i==t//2:\n                for j in range(len(d[i])//2):\n                    ans[d[i][j]]=0\n                for j in range(len(d[i])//2,len(d[i])):\n                    ans[d[i][j]] = 1\n            else:\n                for j in range(len(d[i])):\n                    ans[d[i][j]]=0\n                if t-i in d:\n                    for j in range(len(d[t-i])):\n                        ans[d[t-i][j]]=1\n    for i in ans:\n        print(i,end=' ')\n    print('')\n"
_co = compile(_CODE, USER_FILENAME, "exec")
exec(_co, ns, ns)

```

Measured memory_bytes: 14083