ajayk007/querysmith-spider-bird huggingface dataset:
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE country (
  origin integer PRIMARY KEY,
  country text
);
CREATE TABLE price (
  ID integer PRIMARY KEY,
  price real
);
CREATE TABLE data (
  ID integer PRIMARY KEY,
  mpg real,
  cylinders integer,
  displacement real,
  horsepower integer,
  weight integer,
  acceleration real,
  model integer,
  car_name text
);
CREATE TABLE production (
  ID integer PRIMARY KEY,
  model_year integer PRIMARY KEY,
  country integer
);
-- foreign keys: data.ID -> price.ID; production.ID -> price.ID; production.ID -> data.ID; production.country -> country.origin

Hint: a horsepower of 130 refers to horsepower = 130; difference = subtract(count(ID where model_year = 1970), count(ID where model_year = 1976)) where horsepower = 130

Question: Calculate the difference between the number of cars that has a horsepower of 130 with the model year 1970 and model year 1976

assistant: SELECT SUM(CASE WHEN T2.model_year = 1970 THEN 1 ELSE 0 END) - SUM(CASE WHEN T2.model_year = 1976 THEN 1 ELSE 0 END) FROM data AS T1 INNER JOIN production AS T2 ON T1.ID = T2.ID WHERE T1.horsepower = 130
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE geographic (
  city text PRIMARY KEY,
  county text,
  region text
);
CREATE TABLE generalinfo (
  id_restaurant integer PRIMARY KEY,
  label text,
  food_type text,
  city text,
  review real
);
CREATE TABLE location (
  id_restaurant integer PRIMARY KEY,
  street_num integer,
  street_name text,
  city text
);
-- foreign keys: generalinfo.city -> geographic.city; location.id_restaurant -> generalinfo.id_restaurant; location.city -> geographic.city

Hint: Irving Street refers to street_name = 'irving'

Question: How many restaurants are on Irving Street?

assistant: SELECT COUNT(id_restaurant) FROM location WHERE street_name = 'irving'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE "city" (
"City_ID" int,
"Official_Name" text,
"Status" text,
"Area_km_2" real,
"Population" real,
"Census_Ranking" text,
PRIMARY KEY ("City_ID")
);

CREATE TABLE "farm" (
"Farm_ID" int,
"Year" int,
"Total_Horses" real,
"Working_Horses" real,
"Total_Cattle" real,
"Oxen" real,
"Bulls" real,
"Cows" real,
"Pigs" real,
"Sheep_and_Goats" real,
PRIMARY KEY ("Farm_ID")
);

CREATE TABLE "farm_competition" (
"Competition_ID" int,
"Year" int,
"Theme" text,
"Host_city_ID" int,
"Hosts" text,
PRIMARY KEY ("Competition_ID"),
FOREIGN KEY (`Host_city_ID`) REFERENCES `city`(`City_ID`)
);


CREATE TABLE "competition_record" (
"Competition_ID" int,
"Farm_ID" int,
"Rank" int,
PRIMARY KEY ("Competition_ID","Farm_ID"),
FOREIGN KEY (`Competition_ID`) REFERENCES `farm_competition`(`Competition_ID`),
FOREIGN KEY (`Farm_ID`) REFERENCES `farm`(`Farm_ID`)
);

Question: What are the themes of farm competitions sorted by year in ascending order?

assistant: SELECT Theme FROM farm_competition ORDER BY YEAR ASC
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE Dish (
  id integer PRIMARY KEY,
  name text,
  description text,
  menus_appeared integer,
  times_appeared integer,
  first_appeared integer,
  last_appeared integer,
  lowest_price real,
  highest_price real
);
CREATE TABLE Menu (
  id integer PRIMARY KEY,
  name text,
  sponsor text,
  event text,
  venue text,
  place text,
  physical_description text,
  occasion text,
  notes text,
  call_number text,
  keywords text,
  language text,
  date date,
  location text,
  location_type text,
  currency text,
  currency_symbol text,
  status text,
  page_count integer,
  dish_count integer
);
CREATE TABLE MenuPage (
  id integer PRIMARY KEY,
  menu_id integer,
  page_number integer,
  image_id real,
  full_height integer,
  full_width integer,
  uuid text
);
CREATE TABLE MenuItem (
  id integer PRIMARY KEY,
  menu_page_id integer,
  price real,
  high_price real,
  dish_id integer,
  created_at text,
  updated_at text,
  xpos real,
  ypos real
);
-- foreign keys: MenuPage.menu_id -> Menu.id; MenuItem.menu_page_id -> MenuPage.id; MenuItem.dish_id -> Dish.id

Hint: total dish count for uuid of '510d47e4-2958-a3d9-e040-e00a18064a99' = SUM(dish_count WHERE uuid = '510d47e4-2958-a3d9-e040-e00a18064a99'); total dish count for uuid of '510d47e4-295a-a3d9-e040-e00a18064a99 = SUM(dish_count WHERE uuid = '510d47e4-295a-a3d9-e040-e00a18064a99');

Question: Calculate the total dish count for menu with uuid of "510d47e4-2958-a3d9-e040-e00a18064a99" & "510d47e4-295a-a3d9-e040-e00a18064a99".

assistant: SELECT SUM(CASE WHEN T2.uuid = '510d47e4-2958-a3d9-e040-e00a18064a99' THEN T1.dish_count ELSE 0 END) - SUM(CASE WHEN T2.uuid = '510d47e4-295a-a3d9-e040-e00a18064a99' THEN T1.dish_count ELSE 0 END) FROM Menu AS T1 INNER JOIN MenuPage AS T2 ON T1.id = T2.menu_id
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE "people" (
"People_ID" int,
"District" text,
"Name" text,
"Party" text,
"Age" int,
PRIMARY KEY ("People_ID")
);

CREATE TABLE "debate" (
"Debate_ID" int,
"Date" text,
"Venue" text,
"Num_of_Audience" int,
PRIMARY KEY ("Debate_ID")
);

Question: Show the names of people who have been on the negative side of debates at least twice.

assistant: SELECT T2.Name FROM debate_people AS T1 JOIN people AS T2 ON T1.Negative = T2.People_ID GROUP BY T2.Name HAVING COUNT(*) >= 2
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE app_all (
  app_id integer PRIMARY KEY
);
CREATE TABLE app_events (
  event_id integer PRIMARY KEY,
  app_id integer PRIMARY KEY,
  is_installed integer,
  is_active integer
);
CREATE TABLE app_events_relevant (
  event_id integer PRIMARY KEY,
  app_id integer PRIMARY KEY,
  is_installed integer,
  is_active integer
);
CREATE TABLE app_labels (
  app_id integer,
  label_id integer
);
CREATE TABLE events (
  event_id integer PRIMARY KEY,
  device_id integer,
  timestamp datetime,
  longitude real,
  latitude real
);
CREATE TABLE events_relevant (
  event_id integer PRIMARY KEY,
  device_id integer,
  timestamp datetime,
  longitude real,
  latitude real
);
CREATE TABLE gender_age (
  device_id integer PRIMARY KEY,
  gender text,
  age integer,
  group text
);
CREATE TABLE gender_age_test (
  device_id integer PRIMARY KEY
);
CREATE TABLE gender_age_train (
  device_id integer PRIMARY KEY,
  gender text,
  age integer,
  group text
);
CREATE TABLE label_categories (
  label_id integer PRIMARY KEY,
  category text
);
CREATE TABLE phone_brand_device_model2 (
  device_id integer PRIMARY KEY,
  phone_brand text PRIMARY KEY,
  device_model text PRIMARY KEY
);
CREATE TABLE sample_submission (
  device_id integer PRIMARY KEY,
  F23- real,
  F24-26 real,
  F27-28 real,
  F29-32 real,
  F33-42 real,
  F43+ real,
  M22- real,
  M23-26 real,
  M27-28 real,
  M29-31 real,
  M32-38 real,
  M39+ real
);
-- foreign keys: app_events.event_id -> events.event_id; app_events_relevant.app_id -> app_all.app_id; app_events_relevant.event_id -> events_relevant.event_id; app_labels.app_id -> app_all.app_id; app_labels.label_id -> label_categories.label_id; events_relevant.device_id -> gender_age.device_id; gender_age.device_id -> phone_brand_device_model2.device_id

Hint: ratio = DIVIDE(SUM(gender = 'M' WHERE phone_brand = 'vivo'), SUM(gender = 'F' WHERE phone_brand = 'vivo')); female refers to gender = 'F'; male refers to gender = 'M'; vivo device refers to phone_brand = 'vivo';

Question: What is the ratio of female users to male users who uses a vivo device?

assistant: SELECT SUM(IIF(T1.gender = 'M', 1, 0)) / SUM(IIF(T1.gender = 'F', 1, 0)) AS per FROM gender_age AS T1 INNER JOIN phone_brand_device_model2 AS T2 ON T1.device_id = T2.device_id WHERE T2.phone_brand = 'vivo'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE Customers (
  CustomerID integer PRIMARY KEY,
  FirstName text,
  MiddleInitial text,
  LastName text
);
CREATE TABLE Employees (
  EmployeeID integer PRIMARY KEY,
  FirstName text,
  MiddleInitial text,
  LastName text
);
CREATE TABLE Products (
  ProductID integer PRIMARY KEY,
  Name text,
  Price real
);
CREATE TABLE Sales (
  SalesID integer PRIMARY KEY,
  SalesPersonID integer,
  CustomerID integer,
  ProductID integer,
  Quantity integer
);
-- foreign keys: Sales.ProductID -> Products.ProductID; Sales.CustomerID -> Customers.CustomerID; Sales.SalesPersonID -> Employees.EmployeeID

Hint: difference = SUBTRACT((Price WHERE Name = 'HL Mountain Frame - Black, 42'), (Price WHERE Name = 'HL Mountain Frame - Black, 42'));

Question: What is the difference in price between HL Mountain Frame - Black, 42 and LL Mountain Frame - Black, 42?

assistant: SELECT ( SELECT Price FROM Products WHERE Name = 'HL Mountain Frame - Black, 42' ) - ( SELECT Price FROM Products WHERE Name = 'LL Mountain Frame - Black, 42' ) AS num
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;



CREATE TABLE "film" (
"Film_ID" int,
"Title" text,
"Studio" text,
"Director" text,
"Gross_in_dollar" int,
PRIMARY KEY ("Film_ID")
);

Question: List the studios of each film and the number of films produced by that studio.

assistant: SELECT Studio , COUNT(*) FROM film GROUP BY Studio
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
create table Student (
         StuID        INTEGER PRIMARY KEY,
         LName        VARCHAR(12),
         Fname        VARCHAR(12),
         Age      INTEGER,
         Sex      VARCHAR(1),
         Major        INTEGER,
         Advisor      INTEGER,
         city_code    VARCHAR(3)
  );


create table Club (
       ClubID           INTEGER PRIMARY KEY,
       ClubName         VARCHAR(40),
       ClubDesc         VARCHAR(1024),
       ClubLocation VARCHAR(40)
);

create table Member_of_club (
       StuID            INTEGER,
       ClubID           INTEGER,
       Position     VARCHAR(40),
       FOREIGN KEY(StuID) REFERENCES Student(StuID),
       FOREIGN KEY(ClubID) REFERENCES Club(ClubID)
);

Question: How many members of club "Bootup Baltimore" are younger than 18?

assistant: SELECT count(*) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore" AND t3.age < 18
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE geographic (
  city text PRIMARY KEY,
  county text,
  region text
);
CREATE TABLE generalinfo (
  id_restaurant integer PRIMARY KEY,
  label text,
  food_type text,
  city text,
  review real
);
CREATE TABLE location (
  id_restaurant integer PRIMARY KEY,
  street_num integer,
  street_name text,
  city text
);
-- foreign keys: generalinfo.city -> geographic.city; location.id_restaurant -> generalinfo.id_restaurant; location.city -> geographic.city

Hint: restaurant name refers to label; unidentified region refers to region = 'unknown'

Question: Please name any three restaurants that have an unidentified region.

assistant: SELECT T2.label FROM location AS T1 INNER JOIN generalinfo AS T2 ON T1.id_restaurant = T2.id_restaurant INNER JOIN geographic AS T3 ON T2.city = T3.city WHERE T3.region = 'unknown' LIMIT 3
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE film_text (
  film_id integer PRIMARY KEY,
  title text,
  description text
);
CREATE TABLE actor (
  actor_id integer PRIMARY KEY,
  first_name text,
  last_name text,
  last_update datetime
);
CREATE TABLE address (
  address_id integer PRIMARY KEY,
  address text,
  address2 text,
  district text,
  city_id integer,
  postal_code text,
  phone text,
  last_update datetime
);
CREATE TABLE category (
  category_id integer PRIMARY KEY,
  name text,
  last_update datetime
);
CREATE TABLE city (
  city_id integer PRIMARY KEY,
  city text,
  country_id integer,
  last_update datetime
);
CREATE TABLE country (
  country_id integer PRIMARY KEY,
  country text,
  last_update datetime
);
CREATE TABLE customer (
  customer_id integer PRIMARY KEY,
  store_id integer,
  first_name text,
  last_name text,
  email text,
  address_id integer,
  active integer,
  create_date datetime,
  last_update datetime
);
CREATE TABLE film (
  film_id integer PRIMARY KEY,
  title text,
  description text,
  release_year text,
  language_id integer,
  original_language_id integer,
  rental_duration integer,
  rental_rate real,
  length integer,
  replacement_cost real,
  rating text,
  special_features text,
  last_update datetime
);
CREATE TABLE film_actor (
  actor_id integer PRIMARY KEY,
  film_id integer PRIMARY KEY,
  last_update datetime
);
CREATE TABLE film_category (
  film_id integer PRIMARY KEY,
  category_id integer PRIMARY KEY,
  last_update datetime
);
CREATE TABLE inventory (
  inventory_id integer PRIMARY KEY,
  film_id integer,
  store_id integer,
  last_update datetime
);
CREATE TABLE language (
  language_id integer PRIMARY KEY,
  name text,
  last_update datetime
);
CREATE TABLE payment (
  payment_id integer PRIMARY KEY,
  customer_id integer,
  staff_id integer,
  rental_id integer,
  amount real,
  payment_date datetime,
  last_update datetime
);
CREATE TABLE rental (
  rental_id integer PRIMARY KEY,
  rental_date datetime,
  inventory_id integer,
  customer_id integer,
  return_date datetime,
  staff_id integer,
  last_update datetime
);
CREATE TABLE staff (
  staff_id integer PRIMARY KEY,
  first_name text,
  last_name text,
  address_id integer,
  picture blob,
  email text,
  store_id integer,
  active integer,
  username text,
  password text,
  last_update datetime
);
CREATE TABLE store (
  store_id integer PRIMARY KEY,
  manager_staff_id integer,
  address_id integer,
  last_update datetime
);

Hint: the total amount = sum(amount); in June 2005 refers to payment_date like '2005-06%'

Question: Calculate the total amount paid by Stephanie Mitchell for film rentals in June 2005.

assistant: SELECT SUM(T1.amount) FROM payment AS T1 INNER JOIN customer AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = 'STEPHANIE' AND T2.last_name = 'MITCHELL' AND SUBSTR(T1.payment_date, 1, 7) = '2005-06'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
-- LINK: https://en.wikibooks.org/wiki/SQL_Exercises/The_computer_store

CREATE TABLE Manufacturers (
  Code INTEGER,
  Name VARCHAR(255) NOT NULL,
  Headquarter VARCHAR(255) NOT NULL,
  Founder VARCHAR(255) NOT NULL,
  Revenue REAL,
  PRIMARY KEY (Code)   
);

CREATE TABLE Products (
  Code INTEGER,
  Name VARCHAR(255) NOT NULL ,
  Price DECIMAL NOT NULL ,
  Manufacturer INTEGER NOT NULL,
  PRIMARY KEY (Code), 
  FOREIGN KEY (Manufacturer) REFERENCES Manufacturers(Code)
);

Question: Where is the headquarter of the company founded by James?

assistant: SELECT headquarter FROM manufacturers WHERE founder = 'James'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
create table Activity (
  actid INTEGER PRIMARY KEY,
  activity_name varchar(25)
);

create table Participates_in (
  stuid INTEGER,
  actid INTEGER,
  FOREIGN KEY(stuid) REFERENCES Student(StuID),
  FOREIGN KEY(actid) REFERENCES Activity(actid)
);

create table Faculty_Participates_in (
  FacID INTEGER,
  actid INTEGER,
  FOREIGN KEY(FacID) REFERENCES Faculty(FacID),
  FOREIGN KEY(actid) REFERENCES Activity(actid)
);

create table Student (
        StuID        INTEGER PRIMARY KEY,
        LName        VARCHAR(12),
        Fname        VARCHAR(12),
        Age      INTEGER,
        Sex      VARCHAR(1),
        Major        INTEGER,
        Advisor      INTEGER,
        city_code    VARCHAR(3)
 );

create table Faculty (
       FacID 	       INTEGER PRIMARY KEY,
       Lname		VARCHAR(15),
       Fname		VARCHAR(15),
       Rank		VARCHAR(15),
       Sex		VARCHAR(1),
       Phone		INTEGER,
       Room		VARCHAR(5),
       Building		VARCHAR(13)
);

Question: How many faculty members does each building have? List the result with the name of the building.

assistant: SELECT building , count(*) FROM Faculty GROUP BY building
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;


CREATE TABLE "festival_detail" (
"Festival_ID" int,
"Festival_Name" text,
"Chair_Name" text,
"Location" text,
"Year" int,
"Num_of_Audience" int,
PRIMARY KEY ("Festival_ID")
);

Question: List the most common type of artworks.

assistant: SELECT TYPE FROM artwork GROUP BY TYPE ORDER BY COUNT(*) DESC LIMIT 1
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;
CREATE TABLE "medicine" (
"id" int,
"name" text,
"Trade_Name" text,
"FDA_approved" text,
primary key ("id")
);

CREATE TABLE "enzyme" (
"id" int,
"name" text,
"Location" text,
"Product" text,
"Chromosome" text,
"OMIM" int,
"Porphyria" text,
primary key ("id")
);


CREATE TABLE "medicine_enzyme_interaction" (
"enzyme_id" int,
"medicine_id" int,
"interaction_type" text,
primary key ("enzyme_id", "medicine_id"),
foreign key ("enzyme_id") references `enzyme`("id"),
foreign key ("medicine_id") references `medicine`("id")
);

Question: What is the maximum Online Mendelian Inheritance in Man (OMIM) value of the enzymes?

assistant: SELECT max(OMIM) FROM enzyme
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
create table Student (
        StuID        INTEGER PRIMARY KEY,
        LName        VARCHAR(12),
        Fname        VARCHAR(12),
        Age      INTEGER,
        Sex      VARCHAR(1),
        Major        INTEGER,
        Advisor      INTEGER,
        city_code    VARCHAR(3)
 );

create table Faculty (
       FacID 	       INTEGER PRIMARY KEY,
       Lname		VARCHAR(15),
       Fname		VARCHAR(15),
       Rank		VARCHAR(15),
       Sex		VARCHAR(1),
       Phone		INTEGER,
       Room		VARCHAR(5),
       Building		VARCHAR(13)
);

create table Department (
       DNO   		INTEGER PRIMARY KEY,
       Division		VARCHAR(2),
       DName		VARCHAR(25),
       Room		VARCHAR(5),
       Building		VARCHAR(13),
       DPhone		INTEGER
);

create table Member_of (
       FacID 	       INTEGER,
       DNO	       INTEGER,
       Appt_Type       VARCHAR(15),
       FOREIGN KEY(FacID) REFERENCES Faculty(FacID),
       FOREIGN KEY(DNO) REFERENCES Department(DNO)
);

create table Course (
       CID   	    	VARCHAR(7) PRIMARY KEY,
       CName		VARCHAR(40),
       Credits		INTEGER,
       Instructor	INTEGER,
       Days		VARCHAR(5),
       Hours		VARCHAR(11),
       DNO		INTEGER,
       FOREIGN KEY(Instructor) REFERENCES Faculty(FacID),
       FOREIGN KEY(DNO) REFERENCES Department(DNO)
);

create table Minor_in (
       StuID 	      INTEGER,
       DNO		INTEGER,
       FOREIGN KEY(StuID) REFERENCES Student(StuID),
       FOREIGN KEY(DNO) REFERENCES Department(DNO)
);

create table Enrolled_in (
       StuID 		 INTEGER,
       CID		VARCHAR(7),
       Grade		VARCHAR(2),
       FOREIGN KEY(StuID) REFERENCES Student(StuID),
       FOREIGN KEY(CID) REFERENCES Course(CID),
       FOREIGN KEY(Grade) REFERENCES Gradeconversion(lettergrade)
);

create table Gradeconversion (
       lettergrade	     VARCHAR(2) PRIMARY KEY,
       gradepoint	     FLOAT
);

Question: Find the rooms of faculties with rank professor who live in building NEB.

assistant: SELECT Room FROM FACULTY WHERE Rank = "Professor" AND Building = "NEB"
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE employee (
  employee_id integer PRIMARY KEY,
  first_name text,
  last_name text,
  address text,
  city text,
  state text,
  zip integer,
  phone text,
  title text,
  salary integer,
  supervisor integer
);
CREATE TABLE establishment (
  license_no integer PRIMARY KEY,
  dba_name text,
  aka_name text,
  facility_type text,
  risk_level integer,
  address text,
  city text,
  state text,
  zip integer,
  latitude real,
  longitude real,
  ward integer
);
CREATE TABLE inspection (
  inspection_id integer PRIMARY KEY,
  inspection_date date,
  inspection_type text,
  results text,
  employee_id integer,
  license_no integer,
  followup_to integer
);
CREATE TABLE inspection_point (
  point_id integer PRIMARY KEY,
  Description text,
  category text,
  code text,
  fine integer,
  point_level text
);
CREATE TABLE violation (
  inspection_id integer PRIMARY KEY,
  point_id integer PRIMARY KEY,
  fine integer,
  inspector_comment text
);
-- foreign keys: employee.supervisor -> employee.employee_id; inspection.followup_to -> inspection.inspection_id; inspection.license_no -> establishment.license_no; inspection.employee_id -> employee.employee_id; violation.point_id -> inspection_point.point_id; violation.inspection_id -> inspection.inspection_id

Hint: salary greater than 70000 refers to salary > 70000; fail the inspection refers to results = 'Fail'

Question: How many employees have salary greater than 70000 but fail the inspection?

assistant: SELECT COUNT(DISTINCT T1.employee_id) FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id WHERE T2.results = 'Fail' AND T1.salary > 70000