ajayk007/querysmith-spider-bird huggingface dataset:
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE people (
  Customer ID text PRIMARY KEY,
  Customer Name text,
  Segment text,
  Country text,
  City text,
  State text,
  Postal Code integer,
  Region text PRIMARY KEY
);
CREATE TABLE product (
  Product ID text PRIMARY KEY,
  Product Name text,
  Category text,
  Sub-Category text,
  Region text PRIMARY KEY
);
CREATE TABLE central_superstore (
  Row ID integer PRIMARY KEY,
  Order ID text,
  Order Date date,
  Ship Date date,
  Ship Mode text,
  Customer ID text,
  Region text,
  Product ID text,
  Sales real,
  Quantity integer,
  Discount real,
  Profit real
);
CREATE TABLE east_superstore (
  Row ID integer PRIMARY KEY,
  Order ID text,
  Order Date date,
  Ship Date date,
  Ship Mode text,
  Customer ID text,
  Region text,
  Product ID text,
  Sales real,
  Quantity integer,
  Discount real,
  Profit real
);
CREATE TABLE south_superstore (
  Row ID integer PRIMARY KEY,
  Order ID text,
  Order Date date,
  Ship Date date,
  Ship Mode text,
  Customer ID text,
  Region text,
  Product ID text,
  Sales real,
  Quantity integer,
  Discount real,
  Profit real
);
CREATE TABLE west_superstore (
  Row ID integer PRIMARY KEY,
  Order ID text,
  Order Date date,
  Ship Date date,
  Ship Mode text,
  Customer ID text,
  Region text,
  Product ID text,
  Sales real,
  Quantity integer,
  Discount real,
  Profit real
);
-- foreign keys: central_superstore.Product ID -> product.Product ID; central_superstore.Region -> product.Region; central_superstore.Customer ID -> people.Customer ID; central_superstore.Region -> people.Region; east_superstore.Product ID -> product.Product ID; east_superstore.Region -> product.Region; east_superstore.Customer ID -> people.Customer ID; east_superstore.Region -> people.Region; south_superstore.Product ID -> product.Product ID; south_superstore.Region -> product.Region; south_superstore.Customer ID -> people.Customer ID; south_superstore.Region -> people.Region; west_superstore.Product ID -> product.Product ID; west_superstore.Region -> product.Region; west_superstore.Customer ID -> people.Customer ID; west_superstore.Region -> people.Region

Hint: Patrick Gardner is the "Customer Name"; Region = 'Central'

Question: Add the total profit of Patrick Gardner in the Central region.

assistant: SELECT SUM(T2.Profit) FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` WHERE T1.`Customer Name` = 'Patrick Gardner' AND T1.Region = 'Central'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE Ref_Document_Types (
Document_Type_Code CHAR(15) NOT NULL,
Document_Type_Name VARCHAR(255) NOT NULL,
Document_Type_Description VARCHAR(255) NOT NULL,
PRIMARY KEY (Document_Type_Code)
);
CREATE TABLE Ref_Budget_Codes (
Budget_Type_Code CHAR(15) NOT NULL,
Budget_Type_Description VARCHAR(255) NOT NULL,
PRIMARY KEY (Budget_Type_Code)
);

Question: Give the details of the project with the document name 'King Book'.

assistant: SELECT T1.project_details FROM Projects AS T1 JOIN Documents AS T2 ON T1.project_id = T2.project_id WHERE T2.document_name = "King Book"
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE address_status (
  status_id integer PRIMARY KEY,
  address_status text
);
CREATE TABLE author (
  author_id integer PRIMARY KEY,
  author_name text
);
CREATE TABLE book_language (
  language_id integer PRIMARY KEY,
  language_code text,
  language_name text
);
CREATE TABLE country (
  country_id integer PRIMARY KEY,
  country_name text
);
CREATE TABLE address (
  address_id integer PRIMARY KEY,
  street_number text,
  street_name text,
  city text,
  country_id integer
);
CREATE TABLE customer (
  customer_id integer PRIMARY KEY,
  first_name text,
  last_name text,
  email text
);
CREATE TABLE customer_address (
  customer_id integer PRIMARY KEY,
  address_id integer PRIMARY KEY,
  status_id integer
);
CREATE TABLE order_status (
  status_id integer PRIMARY KEY,
  status_value text
);
CREATE TABLE publisher (
  publisher_id integer PRIMARY KEY,
  publisher_name text
);
CREATE TABLE book (
  book_id integer PRIMARY KEY,
  title text,
  isbn13 text,
  language_id integer,
  num_pages integer,
  publication_date date,
  publisher_id integer
);
CREATE TABLE book_author (
  book_id integer PRIMARY KEY,
  author_id integer PRIMARY KEY
);
CREATE TABLE shipping_method (
  method_id integer PRIMARY KEY,
  method_name text,
  cost real
);
CREATE TABLE cust_order (
  order_id integer PRIMARY KEY,
  order_date datetime,
  customer_id integer,
  shipping_method_id integer,
  dest_address_id integer
);
CREATE TABLE order_history (
  history_id integer PRIMARY KEY,
  order_id integer,
  status_id integer,
  status_date datetime
);
CREATE TABLE order_line (
  line_id integer PRIMARY KEY,
  order_id integer,
  book_id integer,
  price real
);
-- foreign keys: address.country_id -> country.country_id; customer_address.customer_id -> customer.customer_id; customer_address.address_id -> address.address_id; book.publisher_id -> publisher.publisher_id; book.language_id -> book_language.language_id; book_author.book_id -> book.book_id; book_author.author_id -> author.author_id

Hint: "Ace Book" is the publisher_name; English book refers to language_name = 'English'; percentage = Divide (Count(book_id where language_name = 'English'), Count(book_id)) * 100

Question: In books published by Ace Book, what is the percentage of English books published?

assistant: SELECT CAST(SUM(CASE WHEN T1.language_name = 'English' THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(*) FROM book_language AS T1 INNER JOIN book AS T2 ON T1.language_id = T2.language_id INNER JOIN publisher AS T3 ON T3.publisher_id = T2.publisher_id WHERE T3.publisher_name = 'Ace Book'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE characters (
  movie_title text PRIMARY KEY,
  release_date text,
  hero text,
  villian text,
  song text
);
CREATE TABLE director (
  name text PRIMARY KEY,
  director text
);
CREATE TABLE movies_total_gross (
  movie_title text PRIMARY KEY,
  release_date text PRIMARY KEY,
  genre text,
  MPAA_rating text,
  total_gross text,
  inflation_adjusted_gross text
);
CREATE TABLE revenue (
  Year integer PRIMARY KEY,
  Studio Entertainment[NI 1] real,
  Disney Consumer Products[NI 2] real,
  Disney Interactive[NI 3][Rev 1] integer,
  Walt Disney Parks and Resorts real,
  Disney Media Networks text,
  Total integer
);
CREATE TABLE voice-actors (
  character text PRIMARY KEY,
  voice-actor text,
  movie text
);
-- foreign keys: characters.hero -> voice-actors.character; director.name -> characters.movie_title; movies_total_gross.movie_title -> characters.movie_title; voice-actors.movie -> characters.movie_title

Hint: released on 2016/3/4 refers to release_date = '4-Mar-16'; adventure movie refers to genre = 'Adventure' ;

Question: Who is the hero character of the adventure movie which was released on 2016/3/4?

assistant: SELECT T1.hero FROM characters AS T1 INNER JOIN movies_total_gross AS T2 ON T2.movie_title = T1.movie_title WHERE T2.genre = 'Adventure' AND T1.release_date = '4-Mar-16'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE "election" (
"Election_ID" int,
"Representative_ID" int,
"Date" text,
"Votes" real,
"Vote_Percent" real,
"Seats" real,
"Place" real,
PRIMARY KEY ("Election_ID"),
FOREIGN KEY ("Representative_ID") REFERENCES `representative`("Representative_ID")
);

CREATE TABLE "representative" (
"Representative_ID" int,
"Name" text,
"State" text,
"Party" text,
"Lifespan" text,
PRIMARY KEY ("Representative_ID")
);

Question: What are the names of representatives with more than 10000 votes in election?

assistant: SELECT T2.Name FROM election AS T1 JOIN representative AS T2 ON T1.Representative_ID = T2.Representative_ID WHERE Votes > 10000
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
create table Scientists (
  SSN int,
  Name Char(30) not null,
  Primary Key (SSN)
);

Create table Projects (
  Code Char(4),
  Name Char(50) not null,
  Hours int,
  Primary Key (Code)
);
	
create table AssignedTo (
  Scientist int not null,
  Project char(4) not null,
  Primary Key (Scientist, Project),
  Foreign Key (Scientist) references Scientists (SSN),
  Foreign Key (Project) references Projects (Code)
);

Question: How many different projects are there?

assistant: SELECT count(DISTINCT name) FROM projects
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE film_text (
  film_id integer PRIMARY KEY,
  title text,
  description text
);
CREATE TABLE actor (
  actor_id integer PRIMARY KEY,
  first_name text,
  last_name text,
  last_update datetime
);
CREATE TABLE address (
  address_id integer PRIMARY KEY,
  address text,
  address2 text,
  district text,
  city_id integer,
  postal_code text,
  phone text,
  last_update datetime
);
CREATE TABLE category (
  category_id integer PRIMARY KEY,
  name text,
  last_update datetime
);
CREATE TABLE city (
  city_id integer PRIMARY KEY,
  city text,
  country_id integer,
  last_update datetime
);
CREATE TABLE country (
  country_id integer PRIMARY KEY,
  country text,
  last_update datetime
);
CREATE TABLE customer (
  customer_id integer PRIMARY KEY,
  store_id integer,
  first_name text,
  last_name text,
  email text,
  address_id integer,
  active integer,
  create_date datetime,
  last_update datetime
);
CREATE TABLE film (
  film_id integer PRIMARY KEY,
  title text,
  description text,
  release_year text,
  language_id integer,
  original_language_id integer,
  rental_duration integer,
  rental_rate real,
  length integer,
  replacement_cost real,
  rating text,
  special_features text,
  last_update datetime
);
CREATE TABLE film_actor (
  actor_id integer PRIMARY KEY,
  film_id integer PRIMARY KEY,
  last_update datetime
);
CREATE TABLE film_category (
  film_id integer PRIMARY KEY,
  category_id integer PRIMARY KEY,
  last_update datetime
);
CREATE TABLE inventory (
  inventory_id integer PRIMARY KEY,
  film_id integer,
  store_id integer,
  last_update datetime
);
CREATE TABLE language (
  language_id integer PRIMARY KEY,
  name text,
  last_update datetime
);
CREATE TABLE payment (
  payment_id integer PRIMARY KEY,
  customer_id integer,
  staff_id integer,
  rental_id integer,
  amount real,
  payment_date datetime,
  last_update datetime
);
CREATE TABLE rental (
  rental_id integer PRIMARY KEY,
  rental_date datetime,
  inventory_id integer,
  customer_id integer,
  return_date datetime,
  staff_id integer,
  last_update datetime
);
CREATE TABLE staff (
  staff_id integer PRIMARY KEY,
  first_name text,
  last_name text,
  address_id integer,
  picture blob,
  email text,
  store_id integer,
  active integer,
  username text,
  password text,
  last_update datetime
);
CREATE TABLE store (
  store_id integer PRIMARY KEY,
  manager_staff_id integer,
  address_id integer,
  last_update datetime
);

Hint: action is a name of category

Question: Please list the titles of any three action films.

assistant: SELECT T1.title FROM film AS T1 INNER JOIN film_category AS T2 ON T1.film_id = T2.film_id INNER JOIN category AS T3 ON T2.category_id = T3.category_id WHERE T3.name = 'Action' LIMIT 3
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE "captain" (
"Captain_ID" int,
"Name" text,
"Ship_ID" int,
"age" text,
"Class" text,
"Rank" text,
PRIMARY KEY ("Captain_ID"),
FOREIGN KEY ("Ship_ID") REFERENCES "Ship"("Ship_ID")
);

CREATE TABLE "Ship" (
"Ship_ID" int,
"Name" text,
"Type" text,
"Built_Year" real,
"Class" text,
"Flag" text,
PRIMARY KEY ("Ship_ID")
);

Question: How many captains are in each rank?

assistant: SELECT count(*) , rank FROM captain GROUP BY rank
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE authors (
  au_id text PRIMARY KEY,
  au_lname text,
  au_fname text,
  phone text,
  address text,
  city text,
  state text,
  zip text,
  contract text
);
CREATE TABLE jobs (
  job_id integer PRIMARY KEY,
  job_desc text,
  min_lvl integer,
  max_lvl integer
);
CREATE TABLE publishers (
  pub_id text PRIMARY KEY,
  pub_name text,
  city text,
  state text,
  country text
);
CREATE TABLE employee (
  emp_id text PRIMARY KEY,
  fname text,
  minit text,
  lname text,
  job_id integer,
  job_lvl integer,
  pub_id text,
  hire_date datetime
);
CREATE TABLE pub_info (
  pub_id text PRIMARY KEY,
  logo blob,
  pr_info text
);
CREATE TABLE stores (
  stor_id text PRIMARY KEY,
  stor_name text,
  stor_address text,
  city text,
  state text,
  zip text
);
CREATE TABLE discounts (
  discounttype text,
  stor_id text,
  lowqty integer,
  highqty integer,
  discount real
);
CREATE TABLE titles (
  title_id text PRIMARY KEY,
  title text,
  type text,
  pub_id text,
  price real,
  advance real,
  royalty integer,
  ytd_sales integer,
  notes text,
  pubdate datetime
);
CREATE TABLE roysched (
  title_id text,
  lorange integer,
  hirange integer,
  royalty integer
);
CREATE TABLE sales (
  stor_id text PRIMARY KEY,
  ord_num text PRIMARY KEY,
  ord_date datetime,
  qty integer,
  payterms text,
  title_id text PRIMARY KEY
);
CREATE TABLE titleauthor (
  au_id text PRIMARY KEY,
  title_id text PRIMARY KEY,
  au_ord integer,
  royaltyper integer
);
-- foreign keys: employee.pub_id -> publishers.pub_id; employee.job_id -> jobs.job_id; pub_info.pub_id -> publishers.pub_id; discounts.stor_id -> stores.stor_id; titles.pub_id -> publishers.pub_id; roysched.title_id -> titles.title_id; sales.title_id -> titles.title_id; sales.stor_id -> stores.stor_id; titleauthor.title_id -> titles.title_id; titleauthor.au_id -> authors.au_id

Hint: not located at USA refers to country! = 'USA'

Question: Who are the employees working for publisher not located in USA? State the employee's name and publisher name.

assistant: SELECT T1.fname, T1.lname, T2.pub_name FROM employee AS T1 INNER JOIN publishers AS T2 ON T1.pub_id = T2.pub_id WHERE T2.country != 'USA'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20));


CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID));


CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID));

Question: What are the names of the different banks that have provided loans?

assistant: SELECT DISTINCT T1.bname FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id = T2.branch_id
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE employee (
  employee_id integer PRIMARY KEY,
  first_name text,
  last_name text,
  address text,
  city text,
  state text,
  zip integer,
  phone text,
  title text,
  salary integer,
  supervisor integer
);
CREATE TABLE establishment (
  license_no integer PRIMARY KEY,
  dba_name text,
  aka_name text,
  facility_type text,
  risk_level integer,
  address text,
  city text,
  state text,
  zip integer,
  latitude real,
  longitude real,
  ward integer
);
CREATE TABLE inspection (
  inspection_id integer PRIMARY KEY,
  inspection_date date,
  inspection_type text,
  results text,
  employee_id integer,
  license_no integer,
  followup_to integer
);
CREATE TABLE inspection_point (
  point_id integer PRIMARY KEY,
  Description text,
  category text,
  code text,
  fine integer,
  point_level text
);
CREATE TABLE violation (
  inspection_id integer PRIMARY KEY,
  point_id integer PRIMARY KEY,
  fine integer,
  inspector_comment text
);
-- foreign keys: employee.supervisor -> employee.employee_id; inspection.followup_to -> inspection.inspection_id; inspection.license_no -> establishment.license_no; inspection.employee_id -> employee.employee_id; violation.point_id -> inspection_point.point_id; violation.inspection_id -> inspection.inspection_id

Hint: restaurant refers to facility_type = 'Restaurant'; the highest risk level refers to max(risk_level); pass the inspection refers to results = 'Pass'

Question: How many restaurants with the highest risk level still passed the inspection?

assistant: SELECT COUNT(DISTINCT T1.license_no) FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T1.risk_level = 3 AND T2.results = 'Pass' AND T1.facility_type = 'Restaurant'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE cars (
  id integer PRIMARY KEY,
  train_id integer,
  position integer,
  shape text,
  len text,
  sides text,
  roof text,
  wheels integer,
  load_shape text,
  load_num integer
);
CREATE TABLE trains (
  id integer PRIMARY KEY,
  direction text
);
-- foreign keys: cars.train_id -> trains.id

Hint: short refers to len = 'short'; 4 cars run refers to position = 4

Question: Please list the directions in which the trains with 4 short cars run.

assistant: SELECT T2.direction FROM cars AS T1 INNER JOIN trains AS T2 ON T1.train_id = T2.id WHERE T1.len = 'short' AND T1.position = 4
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE bool (
  name text PRIMARY KEY
);
CREATE TABLE person (
  name text PRIMARY KEY
);
CREATE TABLE disabled (
  name text PRIMARY KEY
);
CREATE TABLE enlist (
  name text,
  organ text
);
CREATE TABLE filed_for_bankrupcy (
  name text PRIMARY KEY
);
CREATE TABLE longest_absense_from_school (
  name text PRIMARY KEY,
  month integer
);
CREATE TABLE male (
  name text PRIMARY KEY
);
CREATE TABLE no_payment_due (
  name text PRIMARY KEY,
  bool text
);
CREATE TABLE unemployed (
  name text PRIMARY KEY
);
CREATE TABLE enrolled (
  name text PRIMARY KEY,
  school text PRIMARY KEY,
  month integer
);
-- foreign keys: disabled.name -> person.name; enlist.name -> person.name; filed_for_bankrupcy.name -> person.name; longest_absense_from_school.name -> person.name; male.name -> person.name; no_payment_due.bool -> bool.name; no_payment_due.name -> person.name; unemployed.name -> person.name; enrolled.name -> person.name

Hint: have no payment due refers to bool = 'neg'; female students refers to name NOT in male table

Question: How many female students have no payment due?

assistant: SELECT COUNT(name) FROM no_payment_due WHERE name NOT IN ( SELECT name FROM male )
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE "manufacturer" (
    "Manufacturer_ID" int,
    "Open_Year" real,
    "Name" text,
    "Num_of_Factories" int,
    "Num_of_Shops" int,
    PRIMARY KEY ("Manufacturer_ID")
);

Question: Find the name and component amount of the least popular furniture.

assistant: SELECT name , Num_of_Component FROM furniture ORDER BY market_rate LIMIT 1
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE "election" (
"Election_ID" int,
"Representative_ID" int,
"Date" text,
"Votes" real,
"Vote_Percent" real,
"Seats" real,
"Place" real,
PRIMARY KEY ("Election_ID"),
FOREIGN KEY ("Representative_ID") REFERENCES `representative`("Representative_ID")
);

CREATE TABLE "representative" (
"Representative_ID" int,
"Name" text,
"State" text,
"Party" text,
"Lifespan" text,
PRIMARY KEY ("Representative_ID")
);

Question: What are the names of representatives whose party is not "Republican"?

assistant: SELECT Name FROM Representative WHERE Party != "Republican"
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE `Addresses` (
`address_id` INTEGER PRIMARY KEY,
`line_1_number_building` VARCHAR(80),
`city` VARCHAR(50),
`zip_postcode` VARCHAR(20),
`state_province_county` VARCHAR(50),
`country` VARCHAR(50)
);

Question: How many employees are there?

assistant: SELECT count(*) FROM Staff;