ajayk007/querysmith-spider-bird huggingface dataset:
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE bool (
  name text PRIMARY KEY
);
CREATE TABLE person (
  name text PRIMARY KEY
);
CREATE TABLE disabled (
  name text PRIMARY KEY
);
CREATE TABLE enlist (
  name text,
  organ text
);
CREATE TABLE filed_for_bankrupcy (
  name text PRIMARY KEY
);
CREATE TABLE longest_absense_from_school (
  name text PRIMARY KEY,
  month integer
);
CREATE TABLE male (
  name text PRIMARY KEY
);
CREATE TABLE no_payment_due (
  name text PRIMARY KEY,
  bool text
);
CREATE TABLE unemployed (
  name text PRIMARY KEY
);
CREATE TABLE enrolled (
  name text PRIMARY KEY,
  school text PRIMARY KEY,
  month integer
);
-- foreign keys: disabled.name -> person.name; enlist.name -> person.name; filed_for_bankrupcy.name -> person.name; longest_absense_from_school.name -> person.name; male.name -> person.name; no_payment_due.bool -> bool.name; no_payment_due.name -> person.name; unemployed.name -> person.name; enrolled.name -> person.name

Hint: no payment due refers to bool = 'neg'; organization refers to organ; organ = 'fire_department';

Question: List at least 10 students who have no payment due and are enlisted in Fire Department organization.

assistant: SELECT T1.name FROM no_payment_due AS T1 INNER JOIN enlist AS T2 ON T2.name = T1.name WHERE T1.bool = 'neg' AND T2.organ = 'fire_department' LIMIT 10
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE customer (
  c_custkey integer PRIMARY KEY,
  c_mktsegment text,
  c_nationkey integer,
  c_name text,
  c_address text,
  c_phone text,
  c_acctbal real,
  c_comment text
);
CREATE TABLE lineitem (
  l_shipdate date,
  l_orderkey integer PRIMARY KEY,
  l_discount real,
  l_extendedprice real,
  l_suppkey integer,
  l_quantity integer,
  l_returnflag text,
  l_partkey integer,
  l_linestatus text,
  l_tax real,
  l_commitdate date,
  l_receiptdate date,
  l_shipmode text,
  l_linenumber integer PRIMARY KEY,
  l_shipinstruct text,
  l_comment text
);
CREATE TABLE nation (
  n_nationkey integer PRIMARY KEY,
  n_name text,
  n_regionkey integer,
  n_comment text
);
CREATE TABLE orders (
  o_orderdate date,
  o_orderkey integer PRIMARY KEY,
  o_custkey integer,
  o_orderpriority text,
  o_shippriority integer,
  o_clerk text,
  o_orderstatus text,
  o_totalprice real,
  o_comment text
);
CREATE TABLE part (
  p_partkey integer PRIMARY KEY,
  p_type text,
  p_size integer,
  p_brand text,
  p_name text,
  p_container text,
  p_mfgr text,
  p_retailprice real,
  p_comment text
);
CREATE TABLE partsupp (
  ps_partkey integer PRIMARY KEY,
  ps_suppkey integer PRIMARY KEY,
  ps_supplycost real,
  ps_availqty integer,
  ps_comment text
);
CREATE TABLE region (
  r_regionkey integer PRIMARY KEY,
  r_name text,
  r_comment text
);
CREATE TABLE supplier (
  s_suppkey integer PRIMARY KEY,
  s_nationkey integer,
  s_comment text,
  s_name text,
  s_address text,
  s_phone text,
  s_acctbal real
);
-- foreign keys: customer.c_nationkey -> nation.n_nationkey; lineitem.l_partkey -> partsupp.ps_partkey; lineitem.l_suppkey -> partsupp.ps_suppkey; lineitem.l_orderkey -> orders.o_orderkey; nation.n_regionkey -> region.r_regionkey; orders.o_custkey -> customer.c_custkey; partsupp.ps_suppkey -> supplier.s_suppkey; partsupp.ps_partkey -> part.p_partkey; supplier.s_nationkey -> nation.n_nationkey

Hint: line item refers to l_linenumber; the highest quantity refers to max(l_quantity); shipped by air refers to l_shipmode = 'AIR'

Question: Which line item with the highest quantity is shipped by air?

assistant: SELECT l_linenumber FROM lineitem WHERE l_shipmode = 'AIR' ORDER BY l_quantity DESC LIMIT 1
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE app_all (
  app_id integer PRIMARY KEY
);
CREATE TABLE app_events (
  event_id integer PRIMARY KEY,
  app_id integer PRIMARY KEY,
  is_installed integer,
  is_active integer
);
CREATE TABLE app_events_relevant (
  event_id integer PRIMARY KEY,
  app_id integer PRIMARY KEY,
  is_installed integer,
  is_active integer
);
CREATE TABLE app_labels (
  app_id integer,
  label_id integer
);
CREATE TABLE events (
  event_id integer PRIMARY KEY,
  device_id integer,
  timestamp datetime,
  longitude real,
  latitude real
);
CREATE TABLE events_relevant (
  event_id integer PRIMARY KEY,
  device_id integer,
  timestamp datetime,
  longitude real,
  latitude real
);
CREATE TABLE gender_age (
  device_id integer PRIMARY KEY,
  gender text,
  age integer,
  group text
);
CREATE TABLE gender_age_test (
  device_id integer PRIMARY KEY
);
CREATE TABLE gender_age_train (
  device_id integer PRIMARY KEY,
  gender text,
  age integer,
  group text
);
CREATE TABLE label_categories (
  label_id integer PRIMARY KEY,
  category text
);
CREATE TABLE phone_brand_device_model2 (
  device_id integer PRIMARY KEY,
  phone_brand text PRIMARY KEY,
  device_model text PRIMARY KEY
);
CREATE TABLE sample_submission (
  device_id integer PRIMARY KEY,
  F23- real,
  F24-26 real,
  F27-28 real,
  F29-32 real,
  F33-42 real,
  F43+ real,
  M22- real,
  M23-26 real,
  M27-28 real,
  M29-31 real,
  M32-38 real,
  M39+ real
);
-- foreign keys: app_events.event_id -> events.event_id; app_events_relevant.app_id -> app_all.app_id; app_events_relevant.event_id -> events_relevant.event_id; app_labels.app_id -> app_all.app_id; app_labels.label_id -> label_categories.label_id; events_relevant.device_id -> gender_age.device_id; gender_age.device_id -> phone_brand_device_model2.device_id

Hint: age group refers to group; most OPPO users refers to MAX(COUNT(phone_brand = 'OPPO')); OPPO users refers to phone_brand = 'OPPO';

Question: What is the age group of most OPPO users?

assistant: SELECT T.`group` FROM ( SELECT T1.`group`, COUNT(T1.`group`) AS num FROM gender_age AS T1 INNER JOIN phone_brand_device_model2 AS T2 ON T1.device_id = T2.device_id WHERE T2.phone_brand = 'OPPO' GROUP BY T1.`group` ) AS T ORDER BY T.num DESC LIMIT 1
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE CBSA (
  CBSA integer PRIMARY KEY,
  CBSA_name text,
  CBSA_type text
);
CREATE TABLE state (
  abbreviation text PRIMARY KEY,
  name text
);
CREATE TABLE congress (
  cognress_rep_id text PRIMARY KEY,
  first_name text,
  last_name text,
  CID text,
  party text,
  state text,
  abbreviation text,
  House text,
  District integer,
  land_area real
);
CREATE TABLE zip_data (
  zip_code integer PRIMARY KEY,
  city text,
  state text,
  multi_county text,
  type text,
  organization text,
  time_zone text,
  daylight_savings text,
  latitude real,
  longitude real,
  elevation integer,
  state_fips integer,
  county_fips integer,
  region text,
  division text,
  population_2020 integer,
  population_2010 integer,
  households integer,
  avg_house_value integer,
  avg_income_per_household integer,
  persons_per_household real,
  white_population integer,
  black_population integer,
  hispanic_population integer,
  asian_population integer,
  american_indian_population integer,
  hawaiian_population integer,
  other_population integer,
  male_population integer,
  female_population integer,
  median_age real,
  male_median_age real,
  female_median_age real,
  residential_mailboxes integer,
  business_mailboxes integer,
  total_delivery_receptacles integer,
  businesses integer,
  1st_quarter_payroll integer,
  annual_payroll integer,
  employees integer,
  water_area real,
  land_area real,
  single_family_delivery_units integer,
  multi_family_delivery_units integer,
  total_beneficiaries integer,
  retired_workers integer,
  disabled_workers integer,
  parents_and_widowed integer,
  spouses integer,
  children integer,
  over_65 integer,
  monthly_benefits_all integer,
  monthly_benefits_retired_workers integer,
  monthly_benefits_widowed integer,
  CBSA integer
);
CREATE TABLE alias (
  zip_code integer PRIMARY KEY,
  alias text
);
CREATE TABLE area_code (
  zip_code integer PRIMARY KEY,
  area_code integer PRIMARY KEY
);
CREATE TABLE avoid (
  zip_code integer PRIMARY KEY,
  bad_alias text PRIMARY KEY
);
CREATE TABLE country (
  zip_code integer PRIMARY KEY,
  county text PRIMARY KEY,
  state text
);
CREATE TABLE zip_congress (
  zip_code integer PRIMARY KEY,
  district text PRIMARY KEY
);
-- foreign keys: congress.abbreviation -> state.abbreviation; zip_data.CBSA -> CBSA.CBSA; zip_data.state -> state.abbreviation; alias.zip_code -> zip_data.zip_code; area_code.zip_code -> zip_data.zip_code; avoid.zip_code -> zip_data.zip_code; country.state -> state.abbreviation; country.zip_code -> zip_data.zip_code; zip_congress.zip_code -> zip_data.zip_code; zip_congress.district -> congress.cognress_rep_id

Hint: population of Wilcox County in 2010 refers to SUM(population_2010) where county = 'WILCOX';

Question: What was the population of Wilcox County in 2010?

assistant: SELECT SUM(T2.population_2010) FROM country AS T1 INNER JOIN zip_data AS T2 ON T1.zip_code = T2.zip_code WHERE T1.county = 'WILCOX'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE businesses (
  business_id integer PRIMARY KEY,
  name text,
  address text,
  city text,
  postal_code text,
  latitude real,
  longitude real,
  phone_number integer,
  tax_code text,
  business_certificate integer,
  application_date date,
  owner_name text,
  owner_address text,
  owner_city text,
  owner_state text,
  owner_zip text
);
CREATE TABLE inspections (
  business_id integer,
  score integer,
  date date,
  type text
);
CREATE TABLE violations (
  business_id integer,
  date date,
  violation_type_id text,
  risk_category text,
  description text
);
-- foreign keys: inspections.business_id -> businesses.business_id; violations.business_id -> businesses.business_id

Hint: Tiramisu Kitchen is the name of the business; high risks violations refer to risk_category = 'High Risk';

Question: How many high risks violations did the Tiramisu Kitchen violate?

assistant: SELECT COUNT(T1.business_id) FROM violations AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T2.name = 'Tiramisu Kitchen' AND T1.risk_category = 'High Risk'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE chapters (
  id integer PRIMARY KEY,
  Act integer,
  Scene integer,
  Description text,
  work_id integer
);
CREATE TABLE characters (
  id integer PRIMARY KEY,
  CharName text,
  Abbrev text,
  Description text
);
CREATE TABLE paragraphs (
  id integer PRIMARY KEY,
  ParagraphNum integer,
  PlainText text,
  character_id integer,
  chapter_id integer
);
CREATE TABLE works (
  id integer PRIMARY KEY,
  Title text,
  LongTitle text,
  Date integer,
  GenreType text
);

Hint: character named "Froth" refers to CharName = 'Froth'

Question: What is the title which has character named "Froth"?

assistant: SELECT DISTINCT T1.title FROM works AS T1 INNER JOIN chapters AS T2 ON T1.id = T2.work_id INNER JOIN paragraphs AS T3 ON T2.id = T3.chapter_id INNER JOIN characters AS T4 ON T3.character_id = T4.id WHERE T4.CharName = 'Froth'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE divisions (
  division text PRIMARY KEY,
  name text,
  country text
);
CREATE TABLE matchs (
  Div text,
  Date date,
  HomeTeam text,
  AwayTeam text,
  FTHG integer,
  FTAG integer,
  FTR text,
  season integer
);
-- foreign keys: matchs.Div -> divisions.division

Hint: Bundesliga is a name of division; the highest final time goals refers to MAX(FTAG);

Question: Which away team in the division of Bundesliga has the highest final time goals?

assistant: SELECT T1.AwayTeam FROM matchs AS T1 INNER JOIN divisions AS T2 ON T1.Div=T2.division WHERE T2.name = 'Bundesliga' ORDER BY T1.FTAG DESC LIMIT 1
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys=OFF;
BEGIN TRANSACTION;
CREATE TABLE all_star (
    player_id TEXT,
    year INTEGER,
    game_num INTEGER,
    game_id TEXT,
    team_id TEXT,
    league_id TEXT,
    gp NUMERIC,
    starting_pos NUMERIC,
    foreign key (player_id) references player(player_id)
);

Question: How many players were in the team Boston Red Stockings in 2000?

assistant: SELECT count(*) FROM salary AS T1 JOIN team AS T2 ON T1.team_id = T2.team_id_br WHERE T2.name = 'Boston Red Stockings' AND T1.year = 2000
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE Attributes (
  attribute_id integer PRIMARY KEY,
  attribute_name text
);
CREATE TABLE Categories (
  category_id integer PRIMARY KEY,
  category_name text
);
CREATE TABLE Compliments (
  compliment_id integer PRIMARY KEY,
  compliment_type text
);
CREATE TABLE Days (
  day_id integer PRIMARY KEY,
  day_of_week text
);
CREATE TABLE Years (
  year_id integer PRIMARY KEY,
  actual_year integer
);
CREATE TABLE Business_Attributes (
  attribute_id integer PRIMARY KEY,
  business_id integer PRIMARY KEY,
  attribute_value text
);
CREATE TABLE Business_Categories (
  business_id integer PRIMARY KEY,
  category_id integer PRIMARY KEY
);
CREATE TABLE Business_Hours (
  business_id integer PRIMARY KEY,
  day_id integer PRIMARY KEY,
  opening_time text,
  closing_time text
);
CREATE TABLE Checkins (
  business_id integer PRIMARY KEY,
  day_id integer PRIMARY KEY,
  label_time_0 text,
  label_time_1 text,
  label_time_2 text,
  label_time_3 text,
  label_time_4 text,
  label_time_5 text,
  label_time_6 text,
  label_time_7 text,
  label_time_8 text,
  label_time_9 text,
  label_time_10 text,
  label_time_11 text,
  label_time_12 text,
  label_time_13 text,
  label_time_14 text,
  label_time_15 text,
  label_time_16 text,
  label_time_17 text,
  label_time_18 text,
  label_time_19 text,
  label_time_20 text,
  label_time_21 text,
  label_time_22 text,
  label_time_23 text
);
CREATE TABLE Elite (
  user_id integer PRIMARY KEY,
  year_id integer PRIMARY KEY
);
CREATE TABLE Reviews (
  business_id integer PRIMARY KEY,
  user_id integer PRIMARY KEY,
  review_stars integer,
  review_votes_funny text,
  review_votes_useful text,
  review_votes_cool text,
  review_length text
);
CREATE TABLE Tips (
  business_id integer PRIMARY KEY,
  user_id integer PRIMARY KEY,
  likes integer,
  tip_length text
);
CREATE TABLE Users_Compliments (
  compliment_id integer PRIMARY KEY,
  user_id integer PRIMARY KEY,
  number_of_compliments text
);
CREATE TABLE Business (
  business_id integer PRIMARY KEY,
  active text,
  city text,
  state text,
  stars real,
  review_count text
);
CREATE TABLE Users (
  user_id integer PRIMARY KEY,
  user_yelping_since_year integer,
  user_average_stars text,
  user_votes_funny text,
  user_votes_useful text,
  user_votes_cool text,
  user_review_count text,
  user_fans text
);

Hint: operating hours refers to opening_time closing_time on day_id; in Black Canyon City refers to city = 'Black Canyon City'; greater than average refers to review_count > AVG(T1.review_count)

Question: Identify the operating hours of businesses in Black Canyon City with review count greater than average.

assistant: SELECT T2.opening_time, T2.closing_time FROM Business AS T1 INNER JOIN Business_Hours AS T2 ON T1.business_id = T2.business_id INNER JOIN Days AS T3 ON T2.day_id = T3.day_id WHERE T1.city = 'Black Canyon City' GROUP BY t2.business_id HAVING T1.review_count > AVG(T1.review_count)
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE Categories (
  CategoryID integer PRIMARY KEY,
  CategoryName text,
  Description text
);
CREATE TABLE Customers (
  CustomerID integer PRIMARY KEY,
  CustomerName text,
  ContactName text,
  Address text,
  City text,
  PostalCode text,
  Country text
);
CREATE TABLE Employees (
  EmployeeID integer PRIMARY KEY,
  LastName text,
  FirstName text,
  BirthDate date,
  Photo text,
  Notes text
);
CREATE TABLE Shippers (
  ShipperID integer PRIMARY KEY,
  ShipperName text,
  Phone text
);
CREATE TABLE Suppliers (
  SupplierID integer PRIMARY KEY,
  SupplierName text,
  ContactName text,
  Address text,
  City text,
  PostalCode text,
  Country text,
  Phone text
);
CREATE TABLE Products (
  ProductID integer PRIMARY KEY,
  ProductName text,
  SupplierID integer,
  CategoryID integer,
  Unit text,
  Price real
);
CREATE TABLE Orders (
  OrderID integer PRIMARY KEY,
  CustomerID integer,
  EmployeeID integer,
  OrderDate datetime,
  ShipperID integer
);
CREATE TABLE OrderDetails (
  OrderDetailID integer PRIMARY KEY,
  OrderID integer,
  ProductID integer,
  Quantity integer
);
-- foreign keys: Products.SupplierID -> Suppliers.SupplierID; Products.CategoryID -> Categories.CategoryID; Orders.ShipperID -> Shippers.ShipperID; Orders.CustomerID -> Customers.CustomerID; Orders.EmployeeID -> Employees.EmployeeID; OrderDetails.ProductID -> Products.ProductID; OrderDetails.OrderID -> Orders.OrderID

Hint: Speedy Express is a company; Sweden is a ShipCountry; calculation = DIVIDE(SUM(ShipCountry = 'Sweden'), SEM(ShipCountry)) * 100

Question: What percentage does the shipment of products by Speedy Express to Sweden make up to the shipping company's total?

assistant: SELECT CAST(COUNT(CASE WHEN T1.ShipCountry = 'Sweden' THEN 1 ELSE NULL END) AS REAL) * 100 / COUNT(T1.OrderID) FROM Orders AS T1 INNER JOIN Shippers AS T2 ON T1.ShipVia = T2.ShipperID WHERE T2.CompanyName = 'Speedy Express'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE height_info (
  height_id integer PRIMARY KEY,
  height_in_cm integer,
  height_in_inch text
);
CREATE TABLE weight_info (
  weight_id integer PRIMARY KEY,
  weight_in_kg integer,
  weight_in_lbs integer
);
CREATE TABLE PlayerInfo (
  ELITEID integer PRIMARY KEY,
  PlayerName text,
  birthdate text,
  birthyear date,
  birthmonth integer,
  birthday integer,
  birthplace text,
  nation text,
  height integer,
  weight integer,
  position_info text,
  shoots text,
  draftyear integer,
  draftround integer,
  overall integer,
  overallby text,
  CSS_rank integer,
  sum_7yr_GP integer,
  sum_7yr_TOI integer,
  GP_greater_than_0 text
);
CREATE TABLE SeasonStatus (
  ELITEID integer,
  SEASON text,
  TEAM text,
  LEAGUE text,
  GAMETYPE text,
  GP integer,
  G integer,
  A integer,
  P integer,
  PIM integer,
  PLUSMINUS integer
);
-- foreign keys: PlayerInfo.weight -> weight_info.weight_id; PlayerInfo.height -> height_info.height_id; SeasonStatus.ELITEID -> PlayerInfo.ELITEID

Hint: most valuable player refers to MAX(P); QMJHL league refers to LEAGUE = 'QMJHL'; 2004-2005 season refers to SEASON = '2004-2005';

Question: Who is the most valuable player in QMJHL league during the 2004-2005 season?

assistant: SELECT T2.PlayerName FROM SeasonStatus AS T1 INNER JOIN PlayerInfo AS T2 ON T1.ELITEID = T2.ELITEID WHERE T1.SEASON BETWEEN '2004' AND '2005' AND T1.LEAGUE = 'QMJHL' ORDER BY T1.P DESC LIMIT 1
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE `Addresses` (
`address_id` INTEGER PRIMARY KEY,
`line_1_number_building` VARCHAR(80),
`city` VARCHAR(50),
`zip_postcode` VARCHAR(20),
`state_province_county` VARCHAR(50),
`country` VARCHAR(50)
);

Question: What are the last names that are used by customers and staff?

assistant: SELECT last_name FROM Customers INTERSECT SELECT last_name FROM Staff
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE country (
  id integer PRIMARY KEY,
  country_name text
);
CREATE TABLE ranking_system (
  id integer PRIMARY KEY,
  system_name text
);
CREATE TABLE ranking_criteria (
  id integer PRIMARY KEY,
  ranking_system_id integer,
  criteria_name text
);
CREATE TABLE university (
  id integer PRIMARY KEY,
  country_id integer,
  university_name text
);
CREATE TABLE university_ranking_year (
  university_id integer,
  ranking_criteria_id integer,
  year integer,
  score integer
);
CREATE TABLE university_year (
  university_id integer,
  year integer,
  num_students integer,
  student_staff_ratio real,
  pct_international_students integer,
  pct_female_students integer
);
-- foreign keys: ranking_criteria.ranking_system_id -> ranking_system.id; university.country_id -> country.id; university_ranking_year.university_id -> university.id; university_ranking_year.ranking_criteria_id -> ranking_criteria.id; university_year.university_id -> university.id

Hint: in 2011 refers to year 2011; female students refers to DIVIDE(MULTIPLY(pct_female_students, num_students), 100); Stanford University refers to university_name = 'Stanford University';

Question: How many female students were there at Stanford University in 2011?

assistant: SELECT CAST(T1.num_students * T1.pct_female_students AS REAL) / 100 FROM university_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T1.year = 2011 AND T2.university_name = 'Stanford University'