ajayk007/querysmith-spider-bird huggingface dataset:
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE Community_Area (
  community_area_no integer PRIMARY KEY,
  community_area_name text,
  side text,
  population text
);
CREATE TABLE District (
  district_no integer PRIMARY KEY,
  district_name text,
  address text,
  zip_code integer,
  commander text,
  email text,
  phone text,
  fax text,
  tty text,
  twitter text
);
CREATE TABLE FBI_Code (
  fbi_code_no text PRIMARY KEY,
  title text,
  description text,
  crime_against text
);
CREATE TABLE IUCR (
  iucr_no text PRIMARY KEY,
  primary_description text,
  secondary_description text,
  index_code text
);
CREATE TABLE Neighborhood (
  neighborhood_name text PRIMARY KEY,
  community_area_no integer
);
CREATE TABLE Ward (
  ward_no integer PRIMARY KEY,
  alderman_first_name text,
  alderman_last_name text,
  alderman_name_suffix text,
  ward_office_address text,
  ward_office_zip text,
  ward_email text,
  ward_office_phone text,
  ward_office_fax text,
  city_hall_office_room integer,
  city_hall_office_phone text,
  city_hall_office_fax text,
  Population integer
);
CREATE TABLE Crime (
  report_no integer PRIMARY KEY,
  case_number text,
  date text,
  block text,
  iucr_no text,
  location_description text,
  arrest text,
  domestic text,
  beat integer,
  district_no integer,
  ward_no integer,
  community_area_no integer,
  fbi_code_no text,
  latitude text,
  longitude text
);
-- foreign keys: Neighborhood.community_area_no -> Community_Area.community_area_no; Crime.fbi_code_no -> FBI_Code.fbi_code_no; Crime.community_area_no -> Community_Area.community_area_no; Crime.district_no -> District.district_no; Crime.iucr_no -> IUCR.iucr_no; Crime.ward_no -> Ward.ward_no

Hint: more than 50000 inhabitants refers to Population > 50000; first name of alderman refers to alderman_first_name

Question: What is the first name of the aldermen of wards with more than 50,000 inhabitants?

assistant: SELECT alderman_first_name FROM Ward WHERE Population > 50000
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;
CREATE TABLE `Course_Authors_and_Tutors` (
`author_id` INTEGER PRIMARY KEY,
`author_tutor_ATB` VARCHAR(3),
`login_name` VARCHAR(40),
`password` VARCHAR(40),
`personal_name` VARCHAR(80),
`middle_name` VARCHAR(80),
`family_name` VARCHAR(80),
`gender_mf` VARCHAR(1),
`address_line_1` VARCHAR(80)
);

Question: Find the subject ID, subject name, and the corresponding number of available courses for each subject.

assistant: SELECT T1.subject_id , T2.subject_name , COUNT(*) FROM Courses AS T1 JOIN Subjects AS T2 ON T1.subject_id = T2.subject_id GROUP BY T1.subject_id
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;



CREATE TABLE "film" (
"Film_ID" int,
"Title" text,
"Studio" text,
"Director" text,
"Gross_in_dollar" int,
PRIMARY KEY ("Film_ID")
);

Question: List the title of films that do not have any market estimation.

assistant: SELECT Title FROM film WHERE Film_ID NOT IN (SELECT Film_ID FROM film_market_estimation)
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE `Attribute_Definitions` (
`attribute_id` INTEGER PRIMARY KEY,
`attribute_name` VARCHAR(30),
`attribute_data_type` VARCHAR(10)
);

Question: What is the product with the highest height? Give me the catalog entry name.

assistant: SELECT catalog_entry_name FROM catalog_contents ORDER BY height DESC LIMIT 1
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE city (
  id integer PRIMARY KEY,
  city_name text
);
CREATE TABLE games (
  id integer PRIMARY KEY,
  games_year integer,
  games_name text,
  season text
);
CREATE TABLE games_city (
  games_id integer,
  city_id integer
);
CREATE TABLE medal (
  id integer PRIMARY KEY,
  medal_name text
);
CREATE TABLE noc_region (
  id integer PRIMARY KEY,
  noc text,
  region_name text
);
CREATE TABLE person (
  id integer PRIMARY KEY,
  full_name text,
  gender text,
  height integer,
  weight integer
);
CREATE TABLE games_competitor (
  id integer PRIMARY KEY,
  games_id integer,
  person_id integer,
  age integer
);
CREATE TABLE person_region (
  person_id integer,
  region_id integer
);
CREATE TABLE sport (
  id integer PRIMARY KEY,
  sport_name text
);
CREATE TABLE event (
  id integer PRIMARY KEY,
  sport_id integer,
  event_name text
);
CREATE TABLE competitor_event (
  event_id integer,
  competitor_id integer,
  medal_id integer
);
-- foreign keys: games_city.games_id -> games.id; games_city.city_id -> city.id; games_competitor.person_id -> person.id; games_competitor.games_id -> games.id; person_region.region_id -> noc_region.id; person_region.person_id -> person.id; event.sport_id -> sport.id; competitor_event.medal_id -> medal.id; competitor_event.event_id -> event.id; competitor_event.competitor_id -> games_competitor.id

Hint: cities beginning with the letter M refer to city_name LIKE 'M%';

Question: In which cities beginning with the letter M have the Olympic Games been held?

assistant: SELECT city_name FROM city WHERE city_name LIKE 'M%'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys=OFF;
BEGIN TRANSACTION;
CREATE TABLE all_star (
    player_id TEXT,
    year INTEGER,
    game_num INTEGER,
    game_id TEXT,
    team_id TEXT,
    league_id TEXT,
    gp NUMERIC,
    starting_pos NUMERIC,
    foreign key (player_id) references player(player_id)
);

Question: What are the manager's first name, last name and id who won the most manager award?

assistant: SELECT T1.name_first , T1.name_last , T2.player_id FROM player AS T1 JOIN manager_award AS T2 ON T1.player_id = T2.player_id GROUP BY T2.player_id ORDER BY count(*) DESC LIMIT 1;
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE users (
  userid integer PRIMARY KEY,
  age text,
  u_gender text,
  occupation text
);
CREATE TABLE directors (
  directorid integer PRIMARY KEY,
  d_quality integer,
  avg_revenue integer
);
CREATE TABLE actors (
  actorid integer PRIMARY KEY,
  a_gender text,
  a_quality integer
);
CREATE TABLE movies (
  movieid integer PRIMARY KEY,
  year integer,
  isEnglish text,
  country text,
  runningtime integer
);
CREATE TABLE movies2actors (
  movieid integer PRIMARY KEY,
  actorid integer PRIMARY KEY,
  cast_num integer
);
CREATE TABLE movies2directors (
  movieid integer PRIMARY KEY,
  directorid integer PRIMARY KEY,
  genre text
);
CREATE TABLE u2base (
  userid integer PRIMARY KEY,
  movieid integer PRIMARY KEY,
  rating text
);

Question: What's different average revenue status for director who directed the movie that got the most 1 ratings?

assistant: SELECT DISTINCT T1.avg_revenue FROM directors AS T1 INNER JOIN movies2directors AS T2 ON T1.directorid = T2.directorid WHERE T1.d_quality = 5
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE "people" (
    "People_ID" int,
    "Age" int,
    "Name" text,
    "Nationality" text,
    "Graduation_College" text,
    PRIMARY KEY ("People_ID")
);

Question: List the names of people that are not employed by any company

assistant: SELECT Name FROM people WHERE People_ID NOT IN (SELECT People_ID FROM employment)
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE Attributes (
  attribute_id integer PRIMARY KEY,
  attribute_name text
);
CREATE TABLE Categories (
  category_id integer PRIMARY KEY,
  category_name text
);
CREATE TABLE Compliments (
  compliment_id integer PRIMARY KEY,
  compliment_type text
);
CREATE TABLE Days (
  day_id integer PRIMARY KEY,
  day_of_week text
);
CREATE TABLE Years (
  year_id integer PRIMARY KEY,
  actual_year integer
);
CREATE TABLE Business_Attributes (
  attribute_id integer PRIMARY KEY,
  business_id integer PRIMARY KEY,
  attribute_value text
);
CREATE TABLE Business_Categories (
  business_id integer PRIMARY KEY,
  category_id integer PRIMARY KEY
);
CREATE TABLE Business_Hours (
  business_id integer PRIMARY KEY,
  day_id integer PRIMARY KEY,
  opening_time text,
  closing_time text
);
CREATE TABLE Checkins (
  business_id integer PRIMARY KEY,
  day_id integer PRIMARY KEY,
  label_time_0 text,
  label_time_1 text,
  label_time_2 text,
  label_time_3 text,
  label_time_4 text,
  label_time_5 text,
  label_time_6 text,
  label_time_7 text,
  label_time_8 text,
  label_time_9 text,
  label_time_10 text,
  label_time_11 text,
  label_time_12 text,
  label_time_13 text,
  label_time_14 text,
  label_time_15 text,
  label_time_16 text,
  label_time_17 text,
  label_time_18 text,
  label_time_19 text,
  label_time_20 text,
  label_time_21 text,
  label_time_22 text,
  label_time_23 text
);
CREATE TABLE Elite (
  user_id integer PRIMARY KEY,
  year_id integer PRIMARY KEY
);
CREATE TABLE Reviews (
  business_id integer PRIMARY KEY,
  user_id integer PRIMARY KEY,
  review_stars integer,
  review_votes_funny text,
  review_votes_useful text,
  review_votes_cool text,
  review_length text
);
CREATE TABLE Tips (
  business_id integer PRIMARY KEY,
  user_id integer PRIMARY KEY,
  likes integer,
  tip_length text
);
CREATE TABLE Users_Compliments (
  compliment_id integer PRIMARY KEY,
  user_id integer PRIMARY KEY,
  number_of_compliments text
);
CREATE TABLE Business (
  business_id integer PRIMARY KEY,
  active text,
  city text,
  state text,
  stars real,
  review_count text
);
CREATE TABLE Users (
  user_id integer PRIMARY KEY,
  user_yelping_since_year integer,
  user_average_stars text,
  user_votes_funny text,
  user_votes_useful text,
  user_votes_cool text,
  user_review_count text,
  user_fans text
);

Hint: 'Fashion' is the category_name; most review refers to Max(Count(user_id))

Question: Which business in fashion category has the most review?

assistant: SELECT T3.business_id FROM Categories AS T1 INNER JOIN Business_Categories AS T2 ON T1.category_id = T2.category_id INNER JOIN Business AS T3 ON T2.business_id = T3.business_id INNER JOIN Reviews AS T4 ON T3.business_id = T4.business_id WHERE T1.category_name LIKE 'Fashion' AND T1.category_id = 7 GROUP BY T3.business_id ORDER BY COUNT(T4.user_id) DESC LIMIT 1
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE country (
  country_id integer PRIMARY KEY,
  country_iso_code text,
  country_name text
);
CREATE TABLE department (
  department_id integer PRIMARY KEY,
  department_name text
);
CREATE TABLE gender (
  gender_id integer PRIMARY KEY,
  gender text
);
CREATE TABLE genre (
  genre_id integer PRIMARY KEY,
  genre_name text
);
CREATE TABLE keyword (
  keyword_id integer PRIMARY KEY,
  keyword_name text
);
CREATE TABLE language (
  language_id integer PRIMARY KEY,
  language_code text,
  language_name text
);
CREATE TABLE language_role (
  role_id integer PRIMARY KEY,
  language_role text
);
CREATE TABLE movie (
  movie_id integer PRIMARY KEY,
  title text,
  budget integer,
  homepage text,
  overview text,
  popularity real,
  release_date date,
  revenue integer,
  runtime integer,
  movie_status text,
  tagline text,
  vote_average real,
  vote_count integer
);
CREATE TABLE movie_genres (
  movie_id integer,
  genre_id integer
);
CREATE TABLE movie_languages (
  movie_id integer,
  language_id integer,
  language_role_id integer
);
CREATE TABLE person (
  person_id integer PRIMARY KEY,
  person_name text
);
CREATE TABLE movie_crew (
  movie_id integer,
  person_id integer,
  department_id integer,
  job text
);
CREATE TABLE production_company (
  company_id integer PRIMARY KEY,
  company_name text
);
CREATE TABLE production_country (
  movie_id integer,
  country_id integer
);
CREATE TABLE movie_cast (
  movie_id integer,
  person_id integer,
  character_name text,
  gender_id integer,
  cast_order integer
);
CREATE TABLE movie_keywords (
  movie_id integer,
  keyword_id integer
);
CREATE TABLE movie_company (
  movie_id integer,
  company_id integer
);
-- foreign keys: movie_genres.movie_id -> movie.movie_id; movie_genres.genre_id -> genre.genre_id; movie_languages.language_role_id -> language_role.role_id; movie_languages.movie_id -> movie.movie_id; movie_languages.language_id -> language.language_id; movie_crew.person_id -> person.person_id; movie_crew.movie_id -> movie.movie_id; movie_crew.department_id -> department.department_id; production_country.movie_id -> movie.movie_id; production_country.country_id -> country.country_id; movie_cast.person_id -> person.person_id; movie_cast.movie_id -> movie.movie_id; movie_cast.gender_id -> gender.gender_id

Hint: What keyword refers to keyword_name; Finding Nemo refers to title = 'Finding Nemo'

Question: What keyword can the user use to search for the movie Finding Nemo?

assistant: SELECT T3.keyword_name FROM movie AS T1 INNER JOIN movie_keywords AS T2 ON T1.movie_id = T2.movie_id INNER JOIN keyword AS T3 ON T2.keyword_id = T3.keyword_id WHERE T1.title = 'Finding Nemo'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
create table Allergy_Type (
       Allergy 		  VARCHAR(20) PRIMARY KEY,
       AllergyType 	  VARCHAR(20)
);

create table Has_Allergy (
       StuID 		 INTEGER,
       Allergy 		 VARCHAR(20),
       FOREIGN KEY(StuID) REFERENCES Student(StuID),
       FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
);

create table Student (
        StuID        INTEGER PRIMARY KEY,
        LName        VARCHAR(12),
        Fname        VARCHAR(12),
        Age      INTEGER,
        Sex      VARCHAR(1),
        Major        INTEGER,
        Advisor      INTEGER,
        city_code    VARCHAR(3)
 );

Question: Show first name, last name, age for all female students. Their sex is F.

assistant: SELECT Fname , Lname , Age FROM Student WHERE Sex = 'F'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE characters (
  movie_title text PRIMARY KEY,
  release_date text,
  hero text,
  villian text,
  song text
);
CREATE TABLE director (
  name text PRIMARY KEY,
  director text
);
CREATE TABLE movies_total_gross (
  movie_title text PRIMARY KEY,
  release_date text PRIMARY KEY,
  genre text,
  MPAA_rating text,
  total_gross text,
  inflation_adjusted_gross text
);
CREATE TABLE revenue (
  Year integer PRIMARY KEY,
  Studio Entertainment[NI 1] real,
  Disney Consumer Products[NI 2] real,
  Disney Interactive[NI 3][Rev 1] integer,
  Walt Disney Parks and Resorts real,
  Disney Media Networks text,
  Total integer
);
CREATE TABLE voice-actors (
  character text PRIMARY KEY,
  voice-actor text,
  movie text
);
-- foreign keys: characters.hero -> voice-actors.character; director.name -> characters.movie_title; movies_total_gross.movie_title -> characters.movie_title; voice-actors.movie -> characters.movie_title

Hint: Comedy refers to genre = 'Comedy'; the main character of the movie refers to hero;

Question: List all the main characters of the movie that are comedy genre.

assistant: SELECT T2.hero FROM movies_total_gross AS T1 INNER JOIN characters AS T2 ON T1.movie_title = T2.movie_title WHERE T1.genre = 'Comedy'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
create table Student (
         StuID        INTEGER PRIMARY KEY,
         LName        VARCHAR(12),
         Fname        VARCHAR(12),
         Age      INTEGER,
         Sex      VARCHAR(1),
         Major        INTEGER,
         Advisor      INTEGER,
         city_code    VARCHAR(3)
  );


create table Club (
       ClubID           INTEGER PRIMARY KEY,
       ClubName         VARCHAR(40),
       ClubDesc         VARCHAR(1024),
       ClubLocation VARCHAR(40)
);

create table Member_of_club (
       StuID            INTEGER,
       ClubID           INTEGER,
       Position     VARCHAR(40),
       FOREIGN KEY(StuID) REFERENCES Student(StuID),
       FOREIGN KEY(ClubID) REFERENCES Club(ClubID)
);

Question: How many members of "Bootup Baltimore" are older than 18?

assistant: SELECT count(*) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore" AND t3.age > 18
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE "gymnast" (
"Gymnast_ID" int,
"Floor_Exercise_Points" real,
"Pommel_Horse_Points" real,
"Rings_Points" real,
"Vault_Points" real,
"Parallel_Bars_Points" real,
"Horizontal_Bar_Points" real,
"Total_Points" real,
PRIMARY KEY ("Gymnast_ID"),
FOREIGN KEY ("Gymnast_ID") REFERENCES "people"("People_ID")
);

CREATE TABLE "people" (
"People_ID" int,
"Name" text,
"Age" real,
"Height" real,
"Hometown" text,
PRIMARY KEY ("People_ID")
);

Question: What is the most common hometown of gymnasts?

assistant: SELECT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID GROUP BY T2.Hometown ORDER BY COUNT(*) DESC LIMIT 1
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;
CREATE TABLE `Addresses` (
`address_id` INTEGER PRIMARY KEY,
`address_details` VARCHAR(255)
);

Question: What are the distinct names of customers who have purchased a keyboard?

assistant: SELECT DISTINCT T1.customer_name FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id = T2.customer_id JOIN order_items AS T3 ON T2.order_id = T3.order_id JOIN products AS T4 ON T3.product_id = T4.product_id WHERE T4.product_name = "keyboard"
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE course (
  course_id integer PRIMARY KEY,
  courseLevel text
);
CREATE TABLE person (
  p_id integer PRIMARY KEY,
  professor integer,
  student integer,
  hasPosition text,
  inPhase text,
  yearsInProgram text
);
CREATE TABLE advisedBy (
  p_id integer PRIMARY KEY,
  p_id_dummy integer PRIMARY KEY
);
CREATE TABLE taughtBy (
  course_id integer PRIMARY KEY,
  p_id integer PRIMARY KEY
);
-- foreign keys: advisedBy.p_id -> person.p_id; advisedBy.p_id_dummy -> person.p_id; taughtBy.course_id -> course.course_id; taughtBy.p_id -> person.p_id

Hint: non-faculty members refers to hasPosition = 0; are not undergoing the phase of qualifications refers to inPhase = 0

Question: How many non-faculty members are not undergoing the phase of qualifications?

assistant: SELECT COUNT(*) FROM person WHERE hasPosition = 0 AND inPhase = 0
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE playstore (
  App text,
  Category text,
  Rating real,
  Reviews integer,
  Size text,
  Installs text,
  Type text,
  Price text,
  Content Rating text,
  Genres text
);
CREATE TABLE user_reviews (
  App text,
  Translated_Review text,
  Sentiment text,
  Sentiment_Polarity text,
  Sentiment_Subjectivity text
);
-- foreign keys: user_reviews.App -> playstore.App

Hint: percentage = DIVIDE(SUBTRACT(SUM(Sentiment = 'Positive')), (SUM(Sentiment = 'Negative')), SUM(Sentiment = 'Negative')) as percentage; having more positive sentiment than negative sentiment refers to Sentiment = 'Positive'>Sentiment = 'Negative';

Question: What is the percentage of application with 4.7 rating having more positives sentiment than negative sentiment?

assistant: SELECT CAST(COUNT(CASE WHEN ( SELECT COUNT(CASE WHEN Sentiment = 'Positive' THEN 1 ELSE NULL END) - COUNT(CASE WHEN Sentiment = 'Negative' THEN 1 ELSE NULL END) FROM user_reviews GROUP BY App ) > 0 THEN 1 ELSE NULL END) AS REAL) * 100 / COUNT(T2.Sentiment) FROM playstore AS T1 INNER JOIN user_reviews AS T2 ON T1.App = T2.App WHERE T1.Rating = 4.7
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
create table Scientists (
  SSN int,
  Name Char(30) not null,
  Primary Key (SSN)
);

Create table Projects (
  Code Char(4),
  Name Char(50) not null,
  Hours int,
  Primary Key (Code)
);
	
create table AssignedTo (
  Scientist int not null,
  Project char(4) not null,
  Primary Key (Scientist, Project),
  Foreign Key (Scientist) references Scientists (SSN),
  Foreign Key (Project) references Projects (Code)
);

Question: What is the name of the project that has a scientist assigned to it whose name contains 'Smith'?

assistant: SELECT T2.name FROM assignedto AS T1 JOIN projects AS T2 ON T1.project = T2.code JOIN scientists AS T3 ON T1.scientist = T3.SSN WHERE T3.name LIKE '%Smith%'