ajayk007/querysmith-spider-bird huggingface dataset:
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE height_info (
  height_id integer PRIMARY KEY,
  height_in_cm integer,
  height_in_inch text
);
CREATE TABLE weight_info (
  weight_id integer PRIMARY KEY,
  weight_in_kg integer,
  weight_in_lbs integer
);
CREATE TABLE PlayerInfo (
  ELITEID integer PRIMARY KEY,
  PlayerName text,
  birthdate text,
  birthyear date,
  birthmonth integer,
  birthday integer,
  birthplace text,
  nation text,
  height integer,
  weight integer,
  position_info text,
  shoots text,
  draftyear integer,
  draftround integer,
  overall integer,
  overallby text,
  CSS_rank integer,
  sum_7yr_GP integer,
  sum_7yr_TOI integer,
  GP_greater_than_0 text
);
CREATE TABLE SeasonStatus (
  ELITEID integer,
  SEASON text,
  TEAM text,
  LEAGUE text,
  GAMETYPE text,
  GP integer,
  G integer,
  A integer,
  P integer,
  PIM integer,
  PLUSMINUS integer
);
-- foreign keys: PlayerInfo.weight -> weight_info.weight_id; PlayerInfo.height -> height_info.height_id; SeasonStatus.ELITEID -> PlayerInfo.ELITEID

Hint: how much taller = SUBTRACT(SUM(height_in_cm WHERE PlayerName = 'David Bornhammar'), SUM(height_in_cm WHERE PlayerName = 'Pauli Levokari')); height in centimeters refers to height_in_cm;

Question: How much taller is David Bornhammar than Pauli Levokari in centimeters?

assistant: SELECT ( SELECT T2.height_in_cm FROM PlayerInfo AS T1 INNER JOIN height_info AS T2 ON T1.height = T2.height_id WHERE T1.PlayerName = 'David Bornhammar' ) - ( SELECT T2.height_in_cm FROM PlayerInfo AS T1 INNER JOIN height_info AS T2 ON T1.height = T2.height_id WHERE T1.PlayerName = 'Pauli Levokari' )
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE "Rooms" ( 
	"RoomId" TEXT PRIMARY KEY,
	"roomName" TEXT, 
	"beds" INTEGER, 
	"bedType" TEXT, 
	"maxOccupancy" INTEGER, 
	"basePrice" INTEGER, 
	"decor" TEXT

);

CREATE TABLE "Reservations" ( 
	"Code" INTEGER PRIMARY KEY, 
	"Room" TEXT, 
	"CheckIn" TEXT, 
	"CheckOut" TEXT, 
	"Rate" REAL, 
	"LastName" TEXT, 
	"FirstName" TEXT, 
	"Adults" INTEGER, 
	"Kids" INTEGER,
	FOREIGN KEY (Room) REFERENCES Rooms(RoomId)
);

Question: How many kids stay in the room DAMIEN TRACHSEL checked in on Sep 21, 2010?

assistant: SELECT Kids FROM Reservations WHERE CheckIn = "2010-09-21" AND FirstName = "DAMIEN" AND LastName = "TRACHSEL";
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;
CREATE TABLE Ref_Document_Types (
Document_Type_Code CHAR(15) NOT NULL,
Document_Type_Name VARCHAR(255) NOT NULL,
Document_Type_Description VARCHAR(255) NOT NULL,
PRIMARY KEY (Document_Type_Code)
);

CREATE TABLE Ref_Calendar (
Calendar_Date DATETIME NOT NULL,
Day_Number INTEGER,
PRIMARY KEY (Calendar_Date)
);
CREATE TABLE Ref_Locations (
Location_Code CHAR(15) NOT NULL,
Location_Name VARCHAR(255) NOT NULL,
Location_Description VARCHAR(255) NOT NULL,
PRIMARY KEY (Location_Code)
);

CREATE TABLE Roles (
Role_Code CHAR(15) NOT NULL,
Role_Name VARCHAR(255),
Role_Description VARCHAR(255),
PRIMARY KEY (Role_Code)
);

CREATE TABLE All_Documents (
Document_ID INTEGER NOT NULL,
Date_Stored DATETIME,
Document_Type_Code CHAR(15) NOT NULL,
Document_Name CHAR(255),
Document_Description CHAR(255),
Other_Details VARCHAR(255),
PRIMARY KEY (Document_ID),
FOREIGN KEY (Document_Type_Code) REFERENCES Ref_Document_Types (Document_Type_Code),
FOREIGN KEY (Date_Stored) REFERENCES Ref_Calendar (Calendar_Date)
);

CREATE TABLE Employees (
Employee_ID INTEGER NOT NULL,
Role_Code CHAR(15) NOT NULL,
Employee_Name VARCHAR(255),
Gender_MFU CHAR(1) NOT NULL,
Date_of_Birth DATETIME NOT NULL,
Other_Details VARCHAR(255),
PRIMARY KEY (Employee_ID),
FOREIGN KEY (Role_Code) REFERENCES Roles (Role_Code)
);

CREATE TABLE Document_Locations (
Document_ID INTEGER NOT NULL,
Location_Code CHAR(15) NOT NULL,
Date_in_Location_From DATETIME NOT NULL,
Date_in_Locaton_To DATETIME,
PRIMARY KEY (Document_ID, Location_Code, Date_in_Location_From),
FOREIGN KEY (Location_Code) REFERENCES Ref_Locations (Location_Code),
FOREIGN KEY (Date_in_Location_From) REFERENCES Ref_Calendar (Calendar_Date),
FOREIGN KEY (Date_in_Locaton_To) REFERENCES Ref_Calendar (Calendar_Date),
FOREIGN KEY (Document_ID) REFERENCES All_Documents (Document_ID)
);

CREATE TABLE Documents_to_be_Destroyed (
Document_ID INTEGER NOT NULL,
Destruction_Authorised_by_Employee_ID INTEGER,
Destroyed_by_Employee_ID INTEGER,
Planned_Destruction_Date DATETIME,
Actual_Destruction_Date DATETIME,
Other_Details VARCHAR(255),
PRIMARY KEY (Document_ID),
FOREIGN KEY (Destroyed_by_Employee_ID) REFERENCES Employees (Employee_ID),
FOREIGN KEY (Destruction_Authorised_by_Employee_ID) REFERENCES Employees (Employee_ID),
FOREIGN KEY (Planned_Destruction_Date) REFERENCES Ref_Calendar (Calendar_Date),
FOREIGN KEY (Actual_Destruction_Date) REFERENCES Ref_Calendar (Calendar_Date),
FOREIGN KEY (Document_ID) REFERENCES All_Documents (Document_ID)
);

Question: Find the starting date and ending data in location for the document named "Robin CV".

assistant: SELECT T1.date_in_location_from , T1.date_in_locaton_to FROM Document_locations AS T1 JOIN All_documents AS T2 ON T1.document_id = T2.document_id WHERE T2.document_name = "Robin CV"
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;
CREATE TABLE `Problem_Category_Codes` (
`problem_category_code` VARCHAR(20) PRIMARY KEY,
`problem_category_description` VARCHAR(80)
);

Question: Find the ids of the problems that are reported by the staff whose last name is Bosco.

assistant: SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_last_name = "Bosco"
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE Method (
  Id integer PRIMARY KEY,
  Name text,
  FullComment text,
  Summary text,
  ApiCalls text,
  CommentIsXml integer,
  SampledAt integer,
  SolutionId integer,
  Lang text,
  NameTokenized text
);
CREATE TABLE MethodParameter (
  Id integer PRIMARY KEY,
  MethodId text,
  Type text,
  Name text
);
CREATE TABLE Repo (
  Id integer PRIMARY KEY,
  Url text,
  Stars integer,
  Forks integer,
  Watchers integer,
  ProcessedTime integer
);
CREATE TABLE Solution (
  Id integer PRIMARY KEY,
  RepoId integer,
  Path text,
  ProcessedTime integer,
  WasCompiled integer
);

Hint: linearized sequenced of API calls refers to ApiCalls;

Question: What is the linearized sequenced of API calls of the method whose solution path is "mauriciodeamorim_tdd.encontro2\Tdd.Encontro2.sln"?

assistant: SELECT T2.ApiCalls FROM Solution AS T1 INNER JOIN Method AS T2 ON T1.Id = T2.SolutionId WHERE T1.Path = 'mauriciodeamorim_tdd.encontro2Tdd.Encontro2.sln'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;


CREATE TABLE "city" (
"City_ID" int,
"City" text,
"Hanzi" text,
"Hanyu_Pinyin" text,
"Regional_Population" int,
"GDP" real,
PRIMARY KEY ("City_ID")
);

CREATE TABLE "match" (
"Match_ID" int,
"Date" text,
"Venue" text,
"Score" text,
"Result" text,
"Competition" text,
PRIMARY KEY ("Match_ID")
);



CREATE TABLE "temperature" (
"City_ID" int,
"Jan" real,
"Feb" real,
"Mar" real,
"Apr" real,
"Jun" real,
"Jul" real,
"Aug" real,
"Sep" real,
"Oct" real,
"Nov" real,
"Dec" real,
PRIMARY KEY ("City_ID"),
FOREIGN KEY (`City_ID`) REFERENCES `city`(`City_ID`)
);

Question: Which cities have served as host cities more than once? Return me their GDP and population.

assistant: SELECT t1.gdp , t1.Regional_Population FROM city AS T1 JOIN hosting_city AS T2 ON T1.city_id = T2.host_city GROUP BY t2.Host_City HAVING count(*) > 1
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE langs (
  lid integer PRIMARY KEY,
  lang text,
  locale text,
  pages integer,
  words integer
);
CREATE TABLE pages (
  pid integer PRIMARY KEY,
  lid integer,
  page integer,
  revision integer,
  title text,
  words integer
);
CREATE TABLE words (
  wid integer PRIMARY KEY,
  word text,
  occurrences integer
);
CREATE TABLE langs_words (
  lid integer PRIMARY KEY,
  wid integer PRIMARY KEY,
  occurrences integer
);
CREATE TABLE pages_words (
  pid integer PRIMARY KEY,
  wid integer PRIMARY KEY,
  occurrences integer
);
CREATE TABLE biwords (
  lid integer PRIMARY KEY,
  w1st integer PRIMARY KEY,
  w2nd integer PRIMARY KEY,
  occurrences integer
);
-- foreign keys: pages.lid -> langs.lid; langs_words.wid -> words.wid; langs_words.lid -> langs.lid; pages_words.wid -> words.wid; pages_words.pid -> pages.pid; biwords.w2nd -> words.wid; biwords.w1st -> words.wid; biwords.lid -> langs.lid

Hint: second word refers to w2nd; biwords pair with most repetitions refers to MAX(biwords.occurrences)

Question: What is the word ID for the second word for the biwords pair with most repetitions?

assistant: SELECT w2nd FROM biwords WHERE occurrences = ( SELECT MAX(occurrences) FROM biwords )
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE station (
  id integer PRIMARY KEY,
  name text,
  lat real,
  long real,
  dock_count integer,
  city text,
  installation_date text
);
CREATE TABLE status (
  station_id integer,
  bikes_available integer,
  docks_available integer,
  time text
);
CREATE TABLE trip (
  id integer PRIMARY KEY,
  duration integer,
  start_date text,
  start_station_name text,
  start_station_id integer,
  end_date text,
  end_station_name text,
  end_station_id integer,
  bike_id integer,
  subscription_type text,
  zip_code integer
);
CREATE TABLE weather (
  date text,
  max_temperature_f integer,
  mean_temperature_f integer,
  min_temperature_f integer,
  max_dew_point_f integer,
  mean_dew_point_f integer,
  min_dew_point_f integer,
  max_humidity integer,
  mean_humidity integer,
  min_humidity integer,
  max_sea_level_pressure_inches real,
  mean_sea_level_pressure_inches real,
  min_sea_level_pressure_inches real,
  max_visibility_miles integer,
  mean_visibility_miles integer,
  min_visibility_miles integer,
  max_wind_Speed_mph integer,
  mean_wind_speed_mph integer,
  max_gust_speed_mph integer,
  precipitation_inches text,
  cloud_cover integer,
  events text,
  wind_dir_degrees integer,
  zip_code text
);

Hint: starting stations refers to start_station_name; above average duration trips = DIVIDE(SUM(duration), COUNT(main_trip.id))<duration;

Question: List the name and city of starting stations which has an above-average duration trips.

assistant: SELECT DISTINCT T1.start_station_name, T2.city FROM trip AS T1 INNER JOIN station AS T2 ON T2.name = T1.start_station_name WHERE T1.duration > ( SELECT AVG(T1.duration) FROM trip AS T1 LEFT JOIN station AS T2 ON T2.name = T1.start_station_name )
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;
CREATE TABLE `Ref_Characteristic_Types` (
`characteristic_type_code` VARCHAR(15) PRIMARY KEY,
`characteristic_type_description` VARCHAR(80)
);
CREATE TABLE `Ref_Colors` (
`color_code` VARCHAR(15) PRIMARY KEY,
`color_description` VARCHAR(80)
);
CREATE TABLE `Ref_Product_Categories` (
`product_category_code` VARCHAR(15) PRIMARY KEY,
`product_category_description` VARCHAR(80),
`unit_of_measure` VARCHAR(20)
);

Question: What is the category and typical buying price  of the product with name "cumin"?

assistant: SELECT product_category_code , typical_buying_price FROM products WHERE product_name = "cumin"
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE divisions (
  division text PRIMARY KEY,
  name text,
  country text
);
CREATE TABLE matchs (
  Div text,
  Date date,
  HomeTeam text,
  AwayTeam text,
  FTHG integer,
  FTAG integer,
  FTR text,
  season integer
);
-- foreign keys: matchs.Div -> divisions.division

Hint: Bundesliga is the name of division; the most final-time home-team goals refers to MAX(FTHG);

Question: Which team had the most final-time home-team goals in the 2021 season's matches of the Bundesliga division?

assistant: SELECT T1.HomeTeam FROM matchs AS T1 INNER JOIN divisions AS T2 ON T1.Div = T2.division WHERE T2.name = 'Bundesliga' AND T1.season = 2021 ORDER BY T1.FTHG DESC LIMIT 1
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE Episode (
  episode_id text PRIMARY KEY,
  season integer,
  episode integer,
  number_in_series integer,
  title text,
  summary text,
  air_date text,
  episode_image text,
  rating real,
  votes integer
);
CREATE TABLE Person (
  name text PRIMARY KEY,
  birthdate text,
  birth_name text,
  birth_place text,
  birth_region text,
  birth_country text,
  height_meters real,
  nickname text
);
CREATE TABLE Award (
  award_id integer PRIMARY KEY,
  organization text,
  year integer,
  award_category text,
  award text,
  person text,
  role text,
  episode_id text,
  season text,
  song text,
  result text
);
CREATE TABLE Character_Award (
  award_id integer,
  character text
);
CREATE TABLE Credit (
  episode_id text,
  category text,
  person text,
  role text,
  credited text
);
CREATE TABLE Keyword (
  episode_id text PRIMARY KEY,
  keyword text PRIMARY KEY
);
CREATE TABLE Vote (
  episode_id text,
  stars integer,
  votes integer,
  percent real
);
-- foreign keys: Award.episode_id -> Episode.episode_id; Award.person -> Person.name; Character_Award.award_id -> Award.award_id; Credit.person -> Person.name; Credit.episode_id -> Episode.episode_id; Keyword.episode_id -> Episode.episode_id; Vote.episode_id -> Episode.episode_id

Hint: co-executive producer refers to role = 'co-executive producer'; higher than 1.60 meters refers to height_meters > 1.60

Question: List out the birth name of crews who are co-executive producer and higher than 1.60 meters.

assistant: SELECT T1.birth_name FROM Person AS T1 INNER JOIN Award AS T2 ON T1.name = T2.person WHERE T2.role = 'co-executive producer' AND T1.height_meters > 1.60;
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE Episode (
  episode_id text PRIMARY KEY,
  season integer,
  episode integer,
  number_in_series integer,
  title text,
  summary text,
  air_date text,
  episode_image text,
  rating real,
  votes integer
);
CREATE TABLE Person (
  name text PRIMARY KEY,
  birthdate text,
  birth_name text,
  birth_place text,
  birth_region text,
  birth_country text,
  height_meters real,
  nickname text
);
CREATE TABLE Award (
  award_id integer PRIMARY KEY,
  organization text,
  year integer,
  award_category text,
  award text,
  person text,
  role text,
  episode_id text,
  season text,
  song text,
  result text
);
CREATE TABLE Character_Award (
  award_id integer,
  character text
);
CREATE TABLE Credit (
  episode_id text,
  category text,
  person text,
  role text,
  credited text
);
CREATE TABLE Keyword (
  episode_id text PRIMARY KEY,
  keyword text PRIMARY KEY
);
CREATE TABLE Vote (
  episode_id text,
  stars integer,
  votes integer,
  percent real
);
-- foreign keys: Award.episode_id -> Episode.episode_id; Award.person -> Person.name; Character_Award.award_id -> Award.award_id; Credit.person -> Person.name; Credit.episode_id -> Episode.episode_id; Keyword.episode_id -> Episode.episode_id; Vote.episode_id -> Episode.episode_id

Hint: have air date in 2008 refers to air_date LIKE '2008%'

Question: What are the keywords of the episodes which have the air date in 2008?

assistant: SELECT T2.keyword FROM Episode AS T1 INNER JOIN Keyword AS T2 ON T1.episode_id = T2.episode_id WHERE SUBSTR(T1.air_date, 1, 4) = '2008';
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
--data definition

create table genre(
	g_name varchar2(20) not null,
	rating varchar2(10),
	most_popular_in varchar2(50),
	primary key(g_name)
);

create table artist(
	artist_name varchar2(50) not null,
	country varchar2(20),
	gender varchar2(20),
	preferred_genre varchar2(50),
	constraint a_name primary key(artist_name),
	foreign key(preferred_genre) references genre(g_name) ON DELETE CASCADE
);

create table files(
	f_id number(10) not null,
	artist_name varchar2(50),
	file_size varchar2(20),
	duration varchar2(20),
	formats varchar2(20),
	primary key(f_id),
	foreign key(artist_name) references artist(artist_name) ON DELETE CASCADE
);


create table song(
	song_name varchar2(50),
	artist_name varchar2(50),
	country varchar2(20),
	f_id number(10),
    	genre_is varchar2(20),
	rating number(10) check(rating>0 and rating<11),
	languages varchar2(20),
	releasedate Date, 
	resolution number(10) not null,
	constraint s_name primary key(song_name),
	foreign key(artist_name) references artist(artist_name) ON DELETE CASCADE,
	foreign key(f_id) references files(f_id) ON DELETE CASCADE,
	foreign key(genre_is) references genre(g_name) ON DELETE CASCADE
);


--insertion of attributes in the table

Question: What is the average song rating for each language?

assistant: SELECT avg(rating) , languages FROM song GROUP BY languages
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE Customers (
  CustomerID integer PRIMARY KEY,
  Customer Names text
);
CREATE TABLE Products (
  ProductID integer PRIMARY KEY,
  Product Name text
);
CREATE TABLE Regions (
  StateCode text PRIMARY KEY,
  State text,
  Region text
);
CREATE TABLE Sales Team (
  SalesTeamID integer PRIMARY KEY,
  Sales Team text,
  Region text
);
CREATE TABLE Store Locations (
  StoreID integer PRIMARY KEY,
  City Name text,
  County text,
  StateCode text,
  State text,
  Type text,
  Latitude real,
  Longitude real,
  AreaCode integer,
  Population integer,
  Household Income integer,
  Median Income integer,
  Land Area integer,
  Water Area integer,
  Time Zone text
);
CREATE TABLE Sales Orders (
  OrderNumber text PRIMARY KEY,
  Sales Channel text,
  WarehouseCode text,
  ProcuredDate text,
  OrderDate text,
  ShipDate text,
  DeliveryDate text,
  CurrencyCode text,
  _SalesTeamID integer,
  _CustomerID integer,
  _StoreID integer,
  _ProductID integer,
  Order Quantity integer,
  Discount Applied real,
  Unit Price text,
  Unit Cost text
);
-- foreign keys: Store Locations.StateCode -> Regions.StateCode; Sales Orders._ProductID -> Products.ProductID; Sales Orders._StoreID -> Store Locations.StoreID; Sales Orders._CustomerID -> Customers.CustomerID; Sales Orders._SalesTeamID -> Sales Team.SalesTeamID

Hint: AVG(Median Income) where Type = 'City';

Question: What is the average median income for all City type of stores?

assistant: SELECT AVG(`Median Income`) FROM `Store Locations` WHERE Type = 'City'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE `Attribute_Definitions` (
`attribute_id` INTEGER PRIMARY KEY,
`attribute_name` VARCHAR(30),
`attribute_data_type` VARCHAR(10)
);

Question: On which days more than one revisions were made on catalogs.

assistant: SELECT date_of_latest_revision FROM Catalogs GROUP BY date_of_latest_revision HAVING count(*) > 1
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE "school" (
"School_ID" int,
"School" text,
"Location" text,
"Enrollment" real,
"Founded" real,
"Denomination" text,
"Boys_or_Girls" text,
"Day_or_Boarding" text,
"Year_Entered_Competition" real,
"School_Colors" text,
PRIMARY KEY ("School_Id")
);

Question: Find the team of each player and sort them in ascending alphabetical order.

assistant: SELECT Team FROM player ORDER BY Team ASC
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE Question (
  questiontext text,
  questionid integer PRIMARY KEY
);
CREATE TABLE Survey (
  SurveyID integer PRIMARY KEY,
  Description text
);
CREATE TABLE Answer (
  AnswerText text,
  SurveyID integer,
  UserID integer PRIMARY KEY,
  QuestionID integer PRIMARY KEY
);

Hint: what is your age? refer to QuestionText; 2014 refer to SurveyID; oldest age refers to MAX(AnswerText)

Question: What is the oldest age of the users in 2014's survey?

assistant: SELECT T2.AnswerText FROM Question AS T1 INNER JOIN Answer AS T2 ON T1.questionid = T2.QuestionID WHERE T1.questiontext = 'What is your age?' AND T2.SurveyID = 2014 ORDER BY T2.AnswerText DESC LIMIT 1