ajayk007/querysmith-spider-bird huggingface dataset:
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE Attributes (
  attribute_id integer PRIMARY KEY,
  attribute_name text
);
CREATE TABLE Categories (
  category_id integer PRIMARY KEY,
  category_name text
);
CREATE TABLE Compliments (
  compliment_id integer PRIMARY KEY,
  compliment_type text
);
CREATE TABLE Days (
  day_id integer PRIMARY KEY,
  day_of_week text
);
CREATE TABLE Years (
  year_id integer PRIMARY KEY,
  actual_year integer
);
CREATE TABLE Business_Attributes (
  attribute_id integer PRIMARY KEY,
  business_id integer PRIMARY KEY,
  attribute_value text
);
CREATE TABLE Business_Categories (
  business_id integer PRIMARY KEY,
  category_id integer PRIMARY KEY
);
CREATE TABLE Business_Hours (
  business_id integer PRIMARY KEY,
  day_id integer PRIMARY KEY,
  opening_time text,
  closing_time text
);
CREATE TABLE Checkins (
  business_id integer PRIMARY KEY,
  day_id integer PRIMARY KEY,
  label_time_0 text,
  label_time_1 text,
  label_time_2 text,
  label_time_3 text,
  label_time_4 text,
  label_time_5 text,
  label_time_6 text,
  label_time_7 text,
  label_time_8 text,
  label_time_9 text,
  label_time_10 text,
  label_time_11 text,
  label_time_12 text,
  label_time_13 text,
  label_time_14 text,
  label_time_15 text,
  label_time_16 text,
  label_time_17 text,
  label_time_18 text,
  label_time_19 text,
  label_time_20 text,
  label_time_21 text,
  label_time_22 text,
  label_time_23 text
);
CREATE TABLE Elite (
  user_id integer PRIMARY KEY,
  year_id integer PRIMARY KEY
);
CREATE TABLE Reviews (
  business_id integer PRIMARY KEY,
  user_id integer PRIMARY KEY,
  review_stars integer,
  review_votes_funny text,
  review_votes_useful text,
  review_votes_cool text,
  review_length text
);
CREATE TABLE Tips (
  business_id integer PRIMARY KEY,
  user_id integer PRIMARY KEY,
  likes integer,
  tip_length text
);
CREATE TABLE Users_Compliments (
  compliment_id integer PRIMARY KEY,
  user_id integer PRIMARY KEY,
  number_of_compliments text
);
CREATE TABLE Business (
  business_id integer PRIMARY KEY,
  active text,
  city text,
  state text,
  stars real,
  review_count text
);
CREATE TABLE Users (
  user_id integer PRIMARY KEY,
  user_yelping_since_year integer,
  user_average_stars text,
  user_votes_funny text,
  user_votes_useful text,
  user_votes_cool text,
  user_review_count text,
  user_fans text
);

Hint: "Automotive" is the category of business; star rating below 3 refers to stars < 3

Question: In businesses with a category of automotive, how many of them has an star rating below 3?

assistant: SELECT COUNT(T1.business_id) FROM Business AS T1 INNER JOIN Business_Categories ON T1.business_id = Business_Categories.business_id INNER JOIN Categories AS T3 ON Business_Categories.category_id = T3.category_id WHERE T3.category_name LIKE 'Automotive' AND T1.stars < 3
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
-- dbext:type=SQLITE:dbname=movie_rating.db

/* Delete the tables if they already exist */
drop table if exists Movie;
drop table if exists Reviewer;
drop table if exists Rating;

/* Create the schema for our tables */
create table Movie(
	mID int primary key, 
	title text, 
	year int, 
	director text
);
create table Reviewer(
	rID int primary key, 
	name text);

create table Rating(
	rID int, 
	mID int, 
	stars int, 
	ratingDate date,
	FOREIGN KEY (mID) references Movie(mID),
	FOREIGN KEY (rID) references Reviewer(rID)
);

/* Populate the tables with our data */

Question: What is the id of the reviewer named Daniel Lewis?

assistant: SELECT rID FROM Reviewer WHERE name = "Daniel Lewis"
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE genre (
  id integer PRIMARY KEY,
  genre_name text
);
CREATE TABLE game (
  id integer PRIMARY KEY,
  genre_id integer,
  game_name text
);
CREATE TABLE platform (
  id integer PRIMARY KEY,
  platform_name text
);
CREATE TABLE publisher (
  id integer PRIMARY KEY,
  publisher_name text
);
CREATE TABLE game_publisher (
  id integer PRIMARY KEY,
  game_id integer,
  publisher_id integer
);
CREATE TABLE game_platform (
  id integer PRIMARY KEY,
  game_publisher_id integer,
  platform_id integer,
  release_year integer
);
CREATE TABLE region (
  id integer PRIMARY KEY,
  region_name text
);
CREATE TABLE region_sales (
  region_id integer,
  game_platform_id integer,
  num_sales real
);
-- foreign keys: game.genre_id -> genre.id; game_publisher.publisher_id -> publisher.id; game_publisher.game_id -> game.id; game_platform.platform_id -> platform.id; game_platform.game_publisher_id -> game_publisher.id; region_sales.region_id -> region.id; region_sales.game_platform_id -> game_platform.id

Hint: puzzle refers to genre_name = 'Puzzle'; more than 3 puzzle games refers to count(game_id where genre_name = 'Puzzle') > 3

Question: How many publishers have published more than 3 puzzle games?

assistant: SELECT COUNT(T.publisher_name) FROM ( SELECT T3.publisher_name, COUNT(DISTINCT T1.id) FROM game AS T1 INNER JOIN game_publisher AS T2 ON T1.id = T2.game_id INNER JOIN publisher AS T3 ON T2.publisher_id = T3.id INNER JOIN genre AS T4 ON T1.genre_id = T4.id WHERE T4.genre_name = 'Puzzle' GROUP BY T3.publisher_name HAVING COUNT(DISTINCT T1.id) > 3 ) t
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE Apartment_Buildings (
building_id INTEGER NOT NULL,
building_short_name CHAR(15),
building_full_name VARCHAR(80),
building_description VARCHAR(255),
building_address VARCHAR(255),
building_manager VARCHAR(50),
building_phone VARCHAR(80),
PRIMARY KEY (building_id),
UNIQUE (building_id)
);

Question: Return the apartment number with the largest number of bedrooms.

assistant: SELECT apt_number FROM Apartments ORDER BY bedroom_count DESC LIMIT 1
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
create table Student (
        StuID        INTEGER PRIMARY KEY,
        LName        VARCHAR(12),
        Fname        VARCHAR(12),
        Age      INTEGER,
        Sex      VARCHAR(1),
        Major        INTEGER,
        Advisor      INTEGER,
        city_code    VARCHAR(3)
 );
 

create table Dorm (
       dormid		INTEGER,
       dorm_name	VARCHAR(20),
       student_capacity	INTEGER,
       gender			VARCHAR(1)
) ;

create table Dorm_amenity (
       amenid			INTEGER,
       amenity_name		VARCHAR(25)
) ;

create table Has_amenity (
       dormid			INTEGER,
       amenid				INTEGER,
	FOREIGN KEY (dormid) REFERENCES `Dorm`(dormid),
	FOREIGN KEY (amenid) REFERENCES `Dorm_amenity`(amenid)
);

create table Lives_in (
       stuid 	      INTEGER,
       dormid		INTEGER,
       room_number	INTEGER,
	FOREIGN KEY (stuid) REFERENCES `Student`(StuID),
        FOREIGN KEY (dormid) REFERENCES `Dorm`(dormid)
);

Question: What are the names and types of the dorms that have a capacity greater than 300 or less than 100?

assistant: SELECT dorm_name , gender FROM dorm WHERE student_capacity > 300 OR student_capacity < 100
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE lists (
  user_id integer,
  list_id integer PRIMARY KEY,
  list_title text,
  list_movie_number integer,
  list_update_timestamp_utc text,
  list_creation_timestamp_utc text,
  list_followers integer,
  list_url text,
  list_comments integer,
  list_description text,
  list_cover_image_url text,
  list_first_image_url text,
  list_second_image_url text,
  list_third_image_url text
);
CREATE TABLE movies (
  movie_id integer PRIMARY KEY,
  movie_title text,
  movie_release_year integer,
  movie_url text,
  movie_title_language text,
  movie_popularity integer,
  movie_image_url text,
  director_id text,
  director_name text,
  director_url text
);
CREATE TABLE ratings_users (
  user_id integer,
  rating_date_utc text,
  user_trialist integer,
  user_subscriber integer,
  user_avatar_image_url text,
  user_cover_image_url text,
  user_eligible_for_trial integer,
  user_has_payment_method integer
);
CREATE TABLE lists_users (
  user_id integer PRIMARY KEY,
  list_id integer PRIMARY KEY,
  list_update_date_utc text,
  list_creation_date_utc text,
  user_trialist integer,
  user_subscriber integer,
  user_avatar_image_url text,
  user_cover_image_url text,
  user_eligible_for_trial text,
  user_has_payment_method text
);
CREATE TABLE ratings (
  movie_id integer,
  rating_id integer,
  rating_url text,
  rating_score integer,
  rating_timestamp_utc text,
  critic text,
  critic_likes integer,
  critic_comments integer,
  user_id integer,
  user_trialist integer,
  user_subscriber integer,
  user_eligible_for_trial integer,
  user_has_payment_method integer
);
-- foreign keys: lists.user_id -> lists_users.user_id; ratings_users.user_id -> lists_users.user_id; lists_users.user_id -> lists.user_id; lists_users.list_id -> lists.list_id; ratings.user_id -> ratings_users.user_id; ratings.user_id -> lists_users.user_id; ratings.movie_id -> movies.movie_id

Hint: film released in 2007 refers to movie_release_year = 2007; film refers to movie

Question: How many films were released in 2007?

assistant: SELECT COUNT(*) FROM movies WHERE movie_release_year = 2007
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE Community_Area (
  community_area_no integer PRIMARY KEY,
  community_area_name text,
  side text,
  population text
);
CREATE TABLE District (
  district_no integer PRIMARY KEY,
  district_name text,
  address text,
  zip_code integer,
  commander text,
  email text,
  phone text,
  fax text,
  tty text,
  twitter text
);
CREATE TABLE FBI_Code (
  fbi_code_no text PRIMARY KEY,
  title text,
  description text,
  crime_against text
);
CREATE TABLE IUCR (
  iucr_no text PRIMARY KEY,
  primary_description text,
  secondary_description text,
  index_code text
);
CREATE TABLE Neighborhood (
  neighborhood_name text PRIMARY KEY,
  community_area_no integer
);
CREATE TABLE Ward (
  ward_no integer PRIMARY KEY,
  alderman_first_name text,
  alderman_last_name text,
  alderman_name_suffix text,
  ward_office_address text,
  ward_office_zip text,
  ward_email text,
  ward_office_phone text,
  ward_office_fax text,
  city_hall_office_room integer,
  city_hall_office_phone text,
  city_hall_office_fax text,
  Population integer
);
CREATE TABLE Crime (
  report_no integer PRIMARY KEY,
  case_number text,
  date text,
  block text,
  iucr_no text,
  location_description text,
  arrest text,
  domestic text,
  beat integer,
  district_no integer,
  ward_no integer,
  community_area_no integer,
  fbi_code_no text,
  latitude text,
  longitude text
);
-- foreign keys: Neighborhood.community_area_no -> Community_Area.community_area_no; Crime.fbi_code_no -> FBI_Code.fbi_code_no; Crime.community_area_no -> Community_Area.community_area_no; Crime.district_no -> District.district_no; Crime.iucr_no -> IUCR.iucr_no; Crime.ward_no -> Ward.ward_no

Hint: beat of 532 refers to beat = 532; happened in the Yard refers to location_description = 'YARD'; district commander refers to commander

Question: List down the district's commander associated with the crime that happened at the yard and has a beat of 532.

assistant: SELECT T2.address, T2.commander FROM Crime AS T1 INNER JOIN District AS T2 ON T1.district_no = T2.district_no WHERE T1.location_description = 'YARD' AND T1.beat = 532
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE divisions (
  division text PRIMARY KEY,
  name text,
  country text
);
CREATE TABLE matchs (
  Div text,
  Date date,
  HomeTeam text,
  AwayTeam text,
  FTHG integer,
  FTAG integer,
  FTR text,
  season integer
);
-- foreign keys: matchs.Div -> divisions.division

Hint: LaLiga is a name of the division; Valencia's home team refers to HomeTeam = 'Valencia'; win refers to FTR = 'H';

Question: How many times did Valencia's home team win in the LaLiga division?

assistant: SELECT COUNT(T1.HomeTeam) FROM matchs AS T1 INNER JOIN divisions AS T2 ON T1.Div = T2.division WHERE T2.name = 'LaLiga' AND T1.HomeTeam = 'Valencia' AND T1.FTR = 'H'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;
CREATE TABLE `Course_Authors_and_Tutors` (
`author_id` INTEGER PRIMARY KEY,
`author_tutor_ATB` VARCHAR(3),
`login_name` VARCHAR(40),
`password` VARCHAR(40),
`personal_name` VARCHAR(80),
`middle_name` VARCHAR(80),
`family_name` VARCHAR(80),
`gender_mf` VARCHAR(1),
`address_line_1` VARCHAR(80)
);

Question: How many distinct courses are enrolled in by students?

assistant: SELECT count(course_id) FROM Student_Course_Enrolment
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
create table Scientists (
  SSN int,
  Name Char(30) not null,
  Primary Key (SSN)
);

Create table Projects (
  Code Char(4),
  Name Char(50) not null,
  Hours int,
  Primary Key (Code)
);
	
create table AssignedTo (
  Scientist int not null,
  Project char(4) not null,
  Primary Key (Scientist, Project),
  Foreign Key (Scientist) references Scientists (SSN),
  Foreign Key (Project) references Projects (Code)
);

Question: Find the name of the scientist who worked on both a project named 'Matter of Time' and a project named 'A Puzzling Parallax'.

assistant: SELECT T3.name FROM assignedto AS T1 JOIN projects AS T2 ON T1.project = T2.code JOIN scientists AS T3 ON T1.scientist = T3.SSN WHERE T2.name = 'Matter of Time' INTERSECT SELECT T3.name FROM assignedto AS T1 JOIN projects AS T2 ON T1.project = T2.code JOIN scientists AS T3 ON T1.scientist = T3.SSN WHERE T2.name = 'A Puzzling Parallax'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE langs (
  lid integer PRIMARY KEY,
  lang text,
  locale text,
  pages integer,
  words integer
);
CREATE TABLE pages (
  pid integer PRIMARY KEY,
  lid integer,
  page integer,
  revision integer,
  title text,
  words integer
);
CREATE TABLE words (
  wid integer PRIMARY KEY,
  word text,
  occurrences integer
);
CREATE TABLE langs_words (
  lid integer PRIMARY KEY,
  wid integer PRIMARY KEY,
  occurrences integer
);
CREATE TABLE pages_words (
  pid integer PRIMARY KEY,
  wid integer PRIMARY KEY,
  occurrences integer
);
CREATE TABLE biwords (
  lid integer PRIMARY KEY,
  w1st integer PRIMARY KEY,
  w2nd integer PRIMARY KEY,
  occurrences integer
);
-- foreign keys: pages.lid -> langs.lid; langs_words.wid -> words.wid; langs_words.lid -> langs.lid; pages_words.wid -> words.wid; pages_words.pid -> pages.pid; biwords.w2nd -> words.wid; biwords.w1st -> words.wid; biwords.lid -> langs.lid

Hint: grec refers to word = 'grec'; wid where word = 'grec' AS w2nd

Question: How many biwords pairs are there whose second word is "grec"?

assistant: SELECT COUNT(T2.w1st) FROM words AS T1 INNER JOIN biwords AS T2 ON T1.wid = T2.w2nd WHERE T1.word = 'grec'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
create table Allergy_Type (
       Allergy 		  VARCHAR(20) PRIMARY KEY,
       AllergyType 	  VARCHAR(20)
);

create table Has_Allergy (
       StuID 		 INTEGER,
       Allergy 		 VARCHAR(20),
       FOREIGN KEY(StuID) REFERENCES Student(StuID),
       FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
);

create table Student (
        StuID        INTEGER PRIMARY KEY,
        LName        VARCHAR(12),
        Fname        VARCHAR(12),
        Age      INTEGER,
        Sex      VARCHAR(1),
        Major        INTEGER,
        Advisor      INTEGER,
        city_code    VARCHAR(3)
 );

Question: How many allergies are there?

assistant: SELECT count(DISTINCT allergy) FROM Allergy_type
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;
CREATE TABLE Customers (
Customer_ID INTEGER NOT NULL,
Customer_Details VARCHAR(255) NOT NULL,
PRIMARY KEY (Customer_ID)
);

Question: Find the description of the claim status "Open".

assistant: SELECT claim_status_description FROM claims_processing_stages WHERE claim_status_name = "Open"
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE authors (
  au_id text PRIMARY KEY,
  au_lname text,
  au_fname text,
  phone text,
  address text,
  city text,
  state text,
  zip text,
  contract text
);
CREATE TABLE jobs (
  job_id integer PRIMARY KEY,
  job_desc text,
  min_lvl integer,
  max_lvl integer
);
CREATE TABLE publishers (
  pub_id text PRIMARY KEY,
  pub_name text,
  city text,
  state text,
  country text
);
CREATE TABLE employee (
  emp_id text PRIMARY KEY,
  fname text,
  minit text,
  lname text,
  job_id integer,
  job_lvl integer,
  pub_id text,
  hire_date datetime
);
CREATE TABLE pub_info (
  pub_id text PRIMARY KEY,
  logo blob,
  pr_info text
);
CREATE TABLE stores (
  stor_id text PRIMARY KEY,
  stor_name text,
  stor_address text,
  city text,
  state text,
  zip text
);
CREATE TABLE discounts (
  discounttype text,
  stor_id text,
  lowqty integer,
  highqty integer,
  discount real
);
CREATE TABLE titles (
  title_id text PRIMARY KEY,
  title text,
  type text,
  pub_id text,
  price real,
  advance real,
  royalty integer,
  ytd_sales integer,
  notes text,
  pubdate datetime
);
CREATE TABLE roysched (
  title_id text,
  lorange integer,
  hirange integer,
  royalty integer
);
CREATE TABLE sales (
  stor_id text PRIMARY KEY,
  ord_num text PRIMARY KEY,
  ord_date datetime,
  qty integer,
  payterms text,
  title_id text PRIMARY KEY
);
CREATE TABLE titleauthor (
  au_id text PRIMARY KEY,
  title_id text PRIMARY KEY,
  au_ord integer,
  royaltyper integer
);
-- foreign keys: employee.pub_id -> publishers.pub_id; employee.job_id -> jobs.job_id; pub_info.pub_id -> publishers.pub_id; discounts.stor_id -> stores.stor_id; titles.pub_id -> publishers.pub_id; roysched.title_id -> titles.title_id; sales.title_id -> titles.title_id; sales.stor_id -> stores.stor_id; titleauthor.title_id -> titles.title_id; titleauthor.au_id -> authors.au_id

Hint: year to date sales refers to ytd_sales; average order = AVG(ytd_sales)

Question: List all titles which have year to date sales higher than the average order by pubisher name.

assistant: SELECT T1.title FROM titles AS T1 INNER JOIN publishers AS T2 ON T1.pub_id = T2.pub_id WHERE T1.ytd_sales > ( SELECT AVG(ytd_sales) FROM titles )
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE genre (
  id integer PRIMARY KEY,
  genre_name text
);
CREATE TABLE game (
  id integer PRIMARY KEY,
  genre_id integer,
  game_name text
);
CREATE TABLE platform (
  id integer PRIMARY KEY,
  platform_name text
);
CREATE TABLE publisher (
  id integer PRIMARY KEY,
  publisher_name text
);
CREATE TABLE game_publisher (
  id integer PRIMARY KEY,
  game_id integer,
  publisher_id integer
);
CREATE TABLE game_platform (
  id integer PRIMARY KEY,
  game_publisher_id integer,
  platform_id integer,
  release_year integer
);
CREATE TABLE region (
  id integer PRIMARY KEY,
  region_name text
);
CREATE TABLE region_sales (
  region_id integer,
  game_platform_id integer,
  num_sales real
);
-- foreign keys: game.genre_id -> genre.id; game_publisher.publisher_id -> publisher.id; game_publisher.game_id -> game.id; game_platform.platform_id -> platform.id; game_platform.game_publisher_id -> game_publisher.id; region_sales.region_id -> region.id; region_sales.game_platform_id -> game_platform.id

Hint: name of game refers to game_name; published by 505 Games refers to publisher_name = '505 Games'

Question: What are the names of the games that were published by 505 Games?

assistant: SELECT T3.game_name FROM publisher AS T1 INNER JOIN game_publisher AS T2 ON T1.id = T2.publisher_id INNER JOIN game AS T3 ON T2.game_id = T3.id WHERE T1.publisher_name = '505 Games'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE "race" (
"Race_ID" int,
"Name" text,
"Class" text,
"Date" text,
"Track_ID" text,
PRIMARY KEY ("Race_ID"),
FOREIGN KEY ("Track_ID") REFERENCES "track"("Track_ID")
);

CREATE TABLE "track" (
"Track_ID" int,
"Name" text,
"Location" text,
"Seating" real,
"Year_Opened" real,
PRIMARY KEY ("Track_ID")
);

Question: How many races are there?

assistant: SELECT count(*) FROM race