ajayk007/querysmith-spider-bird huggingface dataset:
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE app_all (
  app_id integer PRIMARY KEY
);
CREATE TABLE app_events (
  event_id integer PRIMARY KEY,
  app_id integer PRIMARY KEY,
  is_installed integer,
  is_active integer
);
CREATE TABLE app_events_relevant (
  event_id integer PRIMARY KEY,
  app_id integer PRIMARY KEY,
  is_installed integer,
  is_active integer
);
CREATE TABLE app_labels (
  app_id integer,
  label_id integer
);
CREATE TABLE events (
  event_id integer PRIMARY KEY,
  device_id integer,
  timestamp datetime,
  longitude real,
  latitude real
);
CREATE TABLE events_relevant (
  event_id integer PRIMARY KEY,
  device_id integer,
  timestamp datetime,
  longitude real,
  latitude real
);
CREATE TABLE gender_age (
  device_id integer PRIMARY KEY,
  gender text,
  age integer,
  group text
);
CREATE TABLE gender_age_test (
  device_id integer PRIMARY KEY
);
CREATE TABLE gender_age_train (
  device_id integer PRIMARY KEY,
  gender text,
  age integer,
  group text
);
CREATE TABLE label_categories (
  label_id integer PRIMARY KEY,
  category text
);
CREATE TABLE phone_brand_device_model2 (
  device_id integer PRIMARY KEY,
  phone_brand text PRIMARY KEY,
  device_model text PRIMARY KEY
);
CREATE TABLE sample_submission (
  device_id integer PRIMARY KEY,
  F23- real,
  F24-26 real,
  F27-28 real,
  F29-32 real,
  F33-42 real,
  F43+ real,
  M22- real,
  M23-26 real,
  M27-28 real,
  M29-31 real,
  M32-38 real,
  M39+ real
);
-- foreign keys: app_events.event_id -> events.event_id; app_events_relevant.app_id -> app_all.app_id; app_events_relevant.event_id -> events_relevant.event_id; app_labels.app_id -> app_all.app_id; app_labels.label_id -> label_categories.label_id; events_relevant.device_id -> gender_age.device_id; gender_age.device_id -> phone_brand_device_model2.device_id

Hint: ratio = DIVIDE(SUM(category = 'Securities'), SUM(category = 'Finance'));

Question: What is the ratio of the number of app users that belong to the Securities category to the number of app users that belong to the Finance category?

assistant: SELECT SUM(IIF(T2.category = 'Securities', 1, 0)) / SUM(IIF(T2.category = 'Finance', 1, 0)) AS per FROM app_labels AS T1 INNER JOIN label_categories AS T2 ON T1.label_id = T2.label_id
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE `Accounts` (
`account_id` INTEGER PRIMARY KEY,
`customer_id` INTEGER NOT NULL,
`account_name` VARCHAR(50),
`other_account_details` VARCHAR(255)
);
CREATE TABLE `Customers` (
`customer_id` INTEGER PRIMARY KEY,
`customer_first_name` VARCHAR(20),
`customer_last_name` VARCHAR(20),
`customer_address` VARCHAR(255),
`customer_phone` VARCHAR(255),
`customer_email` VARCHAR(255),
`other_customer_details` VARCHAR(255)
);
CREATE TABLE `Customers_Cards` (
`card_id` INTEGER PRIMARY KEY,
`customer_id` INTEGER NOT NULL,
`card_type_code` VARCHAR(15) NOT NULL,
`card_number` VARCHAR(80),
`date_valid_from` DATETIME,
`date_valid_to` DATETIME,
`other_card_details` VARCHAR(255)
);
CREATE TABLE `Financial_Transactions` (
`transaction_id` INTEGER NOT NULL ,
`previous_transaction_id` INTEGER,
`account_id` INTEGER NOT NULL,
`card_id` INTEGER NOT NULL,
`transaction_type` VARCHAR(15) NOT NULL,
`transaction_date` DATETIME,
`transaction_amount` DOUBLE NULL,
`transaction_comment` VARCHAR(255),
`other_transaction_details` VARCHAR(255),
FOREIGN KEY (`card_id` ) REFERENCES `Customers_Cards`(`card_id` ),
FOREIGN KEY (`account_id` ) REFERENCES `Accounts`(`account_id` )
);

Question: What is the card type code with most number of cards?

assistant: SELECT card_type_code FROM Customers_cards GROUP BY card_type_code ORDER BY count(*) DESC LIMIT 1
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
--data definition

create table genre(
	g_name varchar2(20) not null,
	rating varchar2(10),
	most_popular_in varchar2(50),
	primary key(g_name)
);

create table artist(
	artist_name varchar2(50) not null,
	country varchar2(20),
	gender varchar2(20),
	preferred_genre varchar2(50),
	constraint a_name primary key(artist_name),
	foreign key(preferred_genre) references genre(g_name) ON DELETE CASCADE
);

create table files(
	f_id number(10) not null,
	artist_name varchar2(50),
	file_size varchar2(20),
	duration varchar2(20),
	formats varchar2(20),
	primary key(f_id),
	foreign key(artist_name) references artist(artist_name) ON DELETE CASCADE
);


create table song(
	song_name varchar2(50),
	artist_name varchar2(50),
	country varchar2(20),
	f_id number(10),
    	genre_is varchar2(20),
	rating number(10) check(rating>0 and rating<11),
	languages varchar2(20),
	releasedate Date, 
	resolution number(10) not null,
	constraint s_name primary key(song_name),
	foreign key(artist_name) references artist(artist_name) ON DELETE CASCADE,
	foreign key(f_id) references files(f_id) ON DELETE CASCADE,
	foreign key(genre_is) references genre(g_name) ON DELETE CASCADE
);


--insertion of attributes in the table

Question: Find the names of the artists who are from Bangladesh and have never received rating higher than 7.

assistant: SELECT DISTINCT artist_name FROM artist WHERE country = "Bangladesh" EXCEPT SELECT DISTINCT artist_name FROM song WHERE rating > 7
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE customer (
  c_custkey integer PRIMARY KEY,
  c_mktsegment text,
  c_nationkey integer,
  c_name text,
  c_address text,
  c_phone text,
  c_acctbal real,
  c_comment text
);
CREATE TABLE lineitem (
  l_shipdate date,
  l_orderkey integer PRIMARY KEY,
  l_discount real,
  l_extendedprice real,
  l_suppkey integer,
  l_quantity integer,
  l_returnflag text,
  l_partkey integer,
  l_linestatus text,
  l_tax real,
  l_commitdate date,
  l_receiptdate date,
  l_shipmode text,
  l_linenumber integer PRIMARY KEY,
  l_shipinstruct text,
  l_comment text
);
CREATE TABLE nation (
  n_nationkey integer PRIMARY KEY,
  n_name text,
  n_regionkey integer,
  n_comment text
);
CREATE TABLE orders (
  o_orderdate date,
  o_orderkey integer PRIMARY KEY,
  o_custkey integer,
  o_orderpriority text,
  o_shippriority integer,
  o_clerk text,
  o_orderstatus text,
  o_totalprice real,
  o_comment text
);
CREATE TABLE part (
  p_partkey integer PRIMARY KEY,
  p_type text,
  p_size integer,
  p_brand text,
  p_name text,
  p_container text,
  p_mfgr text,
  p_retailprice real,
  p_comment text
);
CREATE TABLE partsupp (
  ps_partkey integer PRIMARY KEY,
  ps_suppkey integer PRIMARY KEY,
  ps_supplycost real,
  ps_availqty integer,
  ps_comment text
);
CREATE TABLE region (
  r_regionkey integer PRIMARY KEY,
  r_name text,
  r_comment text
);
CREATE TABLE supplier (
  s_suppkey integer PRIMARY KEY,
  s_nationkey integer,
  s_comment text,
  s_name text,
  s_address text,
  s_phone text,
  s_acctbal real
);
-- foreign keys: customer.c_nationkey -> nation.n_nationkey; lineitem.l_partkey -> partsupp.ps_partkey; lineitem.l_suppkey -> partsupp.ps_suppkey; lineitem.l_orderkey -> orders.o_orderkey; nation.n_regionkey -> region.r_regionkey; orders.o_custkey -> customer.c_custkey; partsupp.ps_suppkey -> supplier.s_suppkey; partsupp.ps_partkey -> part.p_partkey; supplier.s_nationkey -> nation.n_nationkey

Hint: orders in household segment refer to o_orderkey where c_mktsegment = 'HOUSEHOLD'; the highest total price refers to MAX(o_totalprice);

Question: Among all the orders made by a customer in the household segment, what is the highest total price?

assistant: SELECT MAX(T1.o_totalprice) FROM orders AS T1 INNER JOIN customer AS T2 ON T1.o_custkey = T2.c_custkey WHERE T2.c_mktsegment = 'HOUSEHOLD'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE "mountain" (
"Mountain_ID" int,
"Name" text,
"Height" real,
"Prominence" real,
"Range" text,
"Country" text,
PRIMARY KEY ("Mountain_ID")
);

CREATE TABLE "climber" (
"Climber_ID" int,
"Name" text,
"Country" text,
"Time" text,
"Points" real,
"Mountain_ID" int,
PRIMARY KEY ("Climber_ID"),
FOREIGN KEY ("Mountain_ID") REFERENCES "mountain"("Mountain_ID")
);

Question: Show names of climbers and the names of mountains they climb.

assistant: SELECT T1.Name , T2.Name FROM climber AS T1 JOIN mountain AS T2 ON T1.Mountain_ID = T2.Mountain_ID
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE langs (
  lid integer PRIMARY KEY,
  lang text,
  locale text,
  pages integer,
  words integer
);
CREATE TABLE pages (
  pid integer PRIMARY KEY,
  lid integer,
  page integer,
  revision integer,
  title text,
  words integer
);
CREATE TABLE words (
  wid integer PRIMARY KEY,
  word text,
  occurrences integer
);
CREATE TABLE langs_words (
  lid integer PRIMARY KEY,
  wid integer PRIMARY KEY,
  occurrences integer
);
CREATE TABLE pages_words (
  pid integer PRIMARY KEY,
  wid integer PRIMARY KEY,
  occurrences integer
);
CREATE TABLE biwords (
  lid integer PRIMARY KEY,
  w1st integer PRIMARY KEY,
  w2nd integer PRIMARY KEY,
  occurrences integer
);
-- foreign keys: pages.lid -> langs.lid; langs_words.wid -> words.wid; langs_words.lid -> langs.lid; pages_words.wid -> words.wid; pages_words.pid -> pages.pid; biwords.w2nd -> words.wid; biwords.w1st -> words.wid; biwords.lid -> langs.lid

Hint: Repetition refers to occurrences; 100 different words refers to words = 100; DIVIDE(SUM(occurrences where words = 100), COUNT(page where words = 100)) as percentage;

Question: Calculate the average of repetitions in the pages that have a total of 100 different words.

assistant: SELECT CAST(SUM(T2.occurrences) AS REAL) / COUNT(T1.page) FROM pages AS T1 INNER JOIN pages_words AS T2 ON T1.pid = T2.pid WHERE T1.words = 100
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE `Attribute_Definitions` (
`attribute_id` INTEGER PRIMARY KEY,
`attribute_name` VARCHAR(30),
`attribute_data_type` VARCHAR(10)
);

Question: Which catalog contents have length below 3 or above 5? Find the catalog entry names.

assistant: SELECT catalog_entry_name FROM catalog_contents WHERE LENGTH < 3 OR width > 5
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE "artist" (
    "Artist_ID" int,
    "Artist" text,
    "Age" int,
    "Famous_Title" text,
    "Famous_Release_date" text,
    PRIMARY KEY ("Artist_ID")
);



CREATE TABLE "volume" (
    "Volume_ID" int,
    "Volume_Issue" text,
    "Issue_Date" text,
    "Weeks_on_Top" real,
    "Song" text,
    "Artist_ID" int,
    PRIMARY KEY ("Volume_ID"),
    FOREIGN KEY (`Artist_ID`) REFERENCES `artist`(`Artist_ID`)
);

Question: Return the categories of music festivals that have the result "Awarded".

assistant: SELECT Category FROM music_festival WHERE RESULT = "Awarded"
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE Question (
  questiontext text,
  questionid integer PRIMARY KEY
);
CREATE TABLE Survey (
  SurveyID integer PRIMARY KEY,
  Description text
);
CREATE TABLE Answer (
  AnswerText text,
  SurveyID integer,
  UserID integer PRIMARY KEY,
  QuestionID integer PRIMARY KEY
);

Hint: mental health survey for 2016 refers to SurveyID = 2016

Question: Provide the number of users who took part in the "mental health survey for 2016".

assistant: SELECT COUNT(DISTINCT T1.UserID) FROM Answer AS T1 INNER JOIN Survey AS T2 ON T1.SurveyID = T2.SurveyID WHERE T2.Description = 'mental health survey for 2016'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
/* 
 * SQL scripts for CS61 Intro to SQL lectures
 * FILENAME SOCCER2.SQL
 */

DROP TABLE  IF EXISTS Player;
DROP TABLE  IF EXISTS Tryout;
DROP TABLE  IF EXISTS College;

CREATE TABLE 	College 
  ( cName   	varchar(20) NOT NULL,
    state   	varchar(2),
    enr     	numeric(5,0),
    PRIMARY KEY (cName)
  );

CREATE TABLE 	Player
  ( pID			numeric(5,0) NOT NULL,
  	pName   	varchar(20),
    yCard   	varchar(3),
    HS      	numeric(5,0),
    PRIMARY KEY (pID)
  );

CREATE TABLE 	Tryout
  ( pID			numeric(5,0),
  	cName   	varchar(20),
    pPos    	varchar(8),
    decision    varchar(3),
    PRIMARY KEY (pID, cName),
    FOREIGN KEY (pID) REFERENCES Player(pID),
    FOREIGN KEY (cName) REFERENCES College(cName)
  );

/* note that "left" and "right" are reserved words in SQL */

Question: For each position, what is the maximum number of  hours for students who spent more than 1000 hours training?

assistant: SELECT max(T1.HS) , pPos FROM player AS T1 JOIN tryout AS T2 ON T1.pID = T2.pID WHERE T1.HS > 1000 GROUP BY T2.pPos
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE actor (
  ActorID integer PRIMARY KEY,
  Name text,
  Date of Birth date,
  Birth City text,
  Birth Country text,
  Height (Inches) integer,
  Biography text,
  Gender text,
  Ethnicity text,
  NetWorth text
);
CREATE TABLE movie (
  MovieID integer PRIMARY KEY,
  Title text,
  MPAA Rating text,
  Budget integer,
  Gross integer,
  Release Date text,
  Genre text,
  Runtime integer,
  Rating real,
  Rating Count integer,
  Summary text
);
CREATE TABLE characters (
  MovieID integer PRIMARY KEY,
  ActorID integer PRIMARY KEY,
  Character Name text,
  creditOrder integer,
  pay text,
  screentime text
);
-- foreign keys: characters.MovieID -> movie.MovieID; characters.ActorID -> actor.ActorID

Hint: No.2 character refers to creditOrder = '2'; movie "American Hustle" refers to Title = 'American Hustle'

Question: Who played the No.2 character in the credit list of the movie "American Hustle"?

assistant: SELECT T3.Name FROM movie AS T1 INNER JOIN characters AS T2 ON T1.MovieID = T2.MovieID INNER JOIN actor AS T3 ON T3.ActorID = T2.ActorID WHERE T1.Title = 'American Hustle' AND T2.creditOrder = '2'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE film_text (
  film_id integer PRIMARY KEY,
  title text,
  description text
);
CREATE TABLE actor (
  actor_id integer PRIMARY KEY,
  first_name text,
  last_name text,
  last_update datetime
);
CREATE TABLE address (
  address_id integer PRIMARY KEY,
  address text,
  address2 text,
  district text,
  city_id integer,
  postal_code text,
  phone text,
  last_update datetime
);
CREATE TABLE category (
  category_id integer PRIMARY KEY,
  name text,
  last_update datetime
);
CREATE TABLE city (
  city_id integer PRIMARY KEY,
  city text,
  country_id integer,
  last_update datetime
);
CREATE TABLE country (
  country_id integer PRIMARY KEY,
  country text,
  last_update datetime
);
CREATE TABLE customer (
  customer_id integer PRIMARY KEY,
  store_id integer,
  first_name text,
  last_name text,
  email text,
  address_id integer,
  active integer,
  create_date datetime,
  last_update datetime
);
CREATE TABLE film (
  film_id integer PRIMARY KEY,
  title text,
  description text,
  release_year text,
  language_id integer,
  original_language_id integer,
  rental_duration integer,
  rental_rate real,
  length integer,
  replacement_cost real,
  rating text,
  special_features text,
  last_update datetime
);
CREATE TABLE film_actor (
  actor_id integer PRIMARY KEY,
  film_id integer PRIMARY KEY,
  last_update datetime
);
CREATE TABLE film_category (
  film_id integer PRIMARY KEY,
  category_id integer PRIMARY KEY,
  last_update datetime
);
CREATE TABLE inventory (
  inventory_id integer PRIMARY KEY,
  film_id integer,
  store_id integer,
  last_update datetime
);
CREATE TABLE language (
  language_id integer PRIMARY KEY,
  name text,
  last_update datetime
);
CREATE TABLE payment (
  payment_id integer PRIMARY KEY,
  customer_id integer,
  staff_id integer,
  rental_id integer,
  amount real,
  payment_date datetime,
  last_update datetime
);
CREATE TABLE rental (
  rental_id integer PRIMARY KEY,
  rental_date datetime,
  inventory_id integer,
  customer_id integer,
  return_date datetime,
  staff_id integer,
  last_update datetime
);
CREATE TABLE staff (
  staff_id integer PRIMARY KEY,
  first_name text,
  last_name text,
  address_id integer,
  picture blob,
  email text,
  store_id integer,
  active integer,
  username text,
  password text,
  last_update datetime
);
CREATE TABLE store (
  store_id integer PRIMARY KEY,
  manager_staff_id integer,
  address_id integer,
  last_update datetime
);

Question: How many films did actor Daryl Wahlberg appear in?

assistant: SELECT COUNT(T1.film_id) FROM film_actor AS T1 INNER JOIN actor AS T2 ON T1.actor_id = T2.actor_id WHERE T2.first_name = 'DARYL' AND T2.last_name = 'WAHLBERG'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE `Addresses` (
`address_id` INTEGER PRIMARY KEY,
`address_content` VARCHAR(80),
`city` VARCHAR(50),
`zip_postcode` VARCHAR(20),
`state_province_county` VARCHAR(50),
`country` VARCHAR(50),
`other_address_details` VARCHAR(255)
);

Question: Find the city where the most customers live.

assistant: SELECT t3.city FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id GROUP BY t3.city ORDER BY count(*) DESC LIMIT 1
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE Customers (
Customer_ID INTEGER NOT NULL,
Customer_name VARCHAR(40),
PRIMARY KEY (Customer_ID)
);

Question: What are the maximum and minimum settlement amount on record?

assistant: SELECT max(settlement_amount) , min(settlement_amount) FROM settlements
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE chapters (
  id integer PRIMARY KEY,
  Act integer,
  Scene integer,
  Description text,
  work_id integer
);
CREATE TABLE characters (
  id integer PRIMARY KEY,
  CharName text,
  Abbrev text,
  Description text
);
CREATE TABLE paragraphs (
  id integer PRIMARY KEY,
  ParagraphNum integer,
  PlainText text,
  character_id integer,
  chapter_id integer
);
CREATE TABLE works (
  id integer PRIMARY KEY,
  Title text,
  LongTitle text,
  Date integer,
  GenreType text
);

Hint: scene numbers refers to Scene; character named Sir Toby Belch refers to CharName = 'Sir Toby Belch'; in the Twelfth Night refers to Title = 'Twelfth Night'

Question: List the scene numbers involving the character named Sir Toby Belch in the Twelfth Night.

assistant: SELECT DISTINCT T2.Scene FROM works AS T1 INNER JOIN chapters AS T2 ON T1.id = T2.work_id INNER JOIN paragraphs AS T3 ON T2.id = T3.chapter_id INNER JOIN characters AS T4 ON T3.character_id = T4.id WHERE T1.Title = 'Twelfth Night' AND T4.CharName = 'Sir Toby Belch'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE Episode (
  episode_id text PRIMARY KEY,
  series text,
  season integer,
  episode integer,
  number_in_series integer,
  title text,
  summary text,
  air_date date,
  episode_image text,
  rating real,
  votes integer
);
CREATE TABLE Keyword (
  episode_id text PRIMARY KEY,
  keyword text PRIMARY KEY
);
CREATE TABLE Person (
  person_id text PRIMARY KEY,
  name text,
  birthdate date,
  birth_name text,
  birth_place text,
  birth_region text,
  birth_country text,
  height_meters real,
  nickname text
);
CREATE TABLE Award (
  award_id integer PRIMARY KEY,
  organization text,
  year integer,
  award_category text,
  award text,
  series text,
  episode_id text,
  person_id text,
  role text,
  result text
);
CREATE TABLE Credit (
  episode_id text PRIMARY KEY,
  person_id text PRIMARY KEY,
  category text,
  role text,
  credited text
);
CREATE TABLE Vote (
  episode_id text,
  stars integer,
  votes integer,
  percent real
);
-- foreign keys: Keyword.episode_id -> Episode.episode_id; Award.person_id -> Person.person_id; Award.episode_id -> Episode.episode_id; Credit.person_id -> Person.person_id; Credit.episode_id -> Episode.episode_id; Vote.episode_id -> Episode.episode_id

Hint: the first episode refers to episode = 1; the last episode refers to episode = 24; 10 stars vote refers to stars = 10; the difference = subtract(votes where episode = 1, votes where episode = 24) where stars = 10

Question: What is the difference of 10 stars votes between the first episode and the last episode?

assistant: SELECT SUM(CASE WHEN T2.episode = 24 THEN T1.votes ELSE 0 END) - SUM(CASE WHEN T2.episode = 1 THEN T1.votes ELSE 0 END) FROM Vote AS T1 INNER JOIN Episode AS T2 ON T2.episode_id = T1.episode_id WHERE T1.stars = 10