ajayk007/querysmith-spider-bird huggingface dataset:
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE `Accounts` (
`account_id` INTEGER PRIMARY KEY,
`customer_id` INTEGER NOT NULL,
`account_name` VARCHAR(50),
`other_account_details` VARCHAR(255)
);
CREATE TABLE `Customers` (
`customer_id` INTEGER PRIMARY KEY,
`customer_first_name` VARCHAR(20),
`customer_last_name` VARCHAR(20),
`customer_address` VARCHAR(255),
`customer_phone` VARCHAR(255),
`customer_email` VARCHAR(255),
`other_customer_details` VARCHAR(255)
);
CREATE TABLE `Customers_Cards` (
`card_id` INTEGER PRIMARY KEY,
`customer_id` INTEGER NOT NULL,
`card_type_code` VARCHAR(15) NOT NULL,
`card_number` VARCHAR(80),
`date_valid_from` DATETIME,
`date_valid_to` DATETIME,
`other_card_details` VARCHAR(255)
);
CREATE TABLE `Financial_Transactions` (
`transaction_id` INTEGER NOT NULL ,
`previous_transaction_id` INTEGER,
`account_id` INTEGER NOT NULL,
`card_id` INTEGER NOT NULL,
`transaction_type` VARCHAR(15) NOT NULL,
`transaction_date` DATETIME,
`transaction_amount` DOUBLE NULL,
`transaction_comment` VARCHAR(255),
`other_transaction_details` VARCHAR(255),
FOREIGN KEY (`card_id` ) REFERENCES `Customers_Cards`(`card_id` ),
FOREIGN KEY (`account_id` ) REFERENCES `Accounts`(`account_id` )
);

Question: What are the different card types, and how many cards are there of each?

assistant: SELECT card_type_code , count(*) FROM Customers_cards GROUP BY card_type_code
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE app_all (
  app_id integer PRIMARY KEY
);
CREATE TABLE app_events (
  event_id integer PRIMARY KEY,
  app_id integer PRIMARY KEY,
  is_installed integer,
  is_active integer
);
CREATE TABLE app_events_relevant (
  event_id integer PRIMARY KEY,
  app_id integer PRIMARY KEY,
  is_installed integer,
  is_active integer
);
CREATE TABLE app_labels (
  app_id integer,
  label_id integer
);
CREATE TABLE events (
  event_id integer PRIMARY KEY,
  device_id integer,
  timestamp datetime,
  longitude real,
  latitude real
);
CREATE TABLE events_relevant (
  event_id integer PRIMARY KEY,
  device_id integer,
  timestamp datetime,
  longitude real,
  latitude real
);
CREATE TABLE gender_age (
  device_id integer PRIMARY KEY,
  gender text,
  age integer,
  group text
);
CREATE TABLE gender_age_test (
  device_id integer PRIMARY KEY
);
CREATE TABLE gender_age_train (
  device_id integer PRIMARY KEY,
  gender text,
  age integer,
  group text
);
CREATE TABLE label_categories (
  label_id integer PRIMARY KEY,
  category text
);
CREATE TABLE phone_brand_device_model2 (
  device_id integer PRIMARY KEY,
  phone_brand text PRIMARY KEY,
  device_model text PRIMARY KEY
);
CREATE TABLE sample_submission (
  device_id integer PRIMARY KEY,
  F23- real,
  F24-26 real,
  F27-28 real,
  F29-32 real,
  F33-42 real,
  F43+ real,
  M22- real,
  M23-26 real,
  M27-28 real,
  M29-31 real,
  M32-38 real,
  M39+ real
);
-- foreign keys: app_events.event_id -> events.event_id; app_events_relevant.app_id -> app_all.app_id; app_events_relevant.event_id -> events_relevant.event_id; app_labels.app_id -> app_all.app_id; app_labels.label_id -> label_categories.label_id; events_relevant.device_id -> gender_age.device_id; gender_age.device_id -> phone_brand_device_model2.device_id

Hint: ratio in percentage = DIVIDE(SUM(IF(category = '80s Japanese comic',1,0)), COUNT(app_id)) as '80s'; DIVIDE(SUM(IF(category = '90s Japanese comic',1,0)), COUNT(app_id)) as '90s'; 80s Japanese comic refers to category = '80s Japanese comic'; 90s Japanese comic refers to category = '80s Japanese comic';

Question: Calculate the ratio in percentage between the average number of app users belonging to "80s Japanese comic" and "90s Japanese comic".

assistant: SELECT SUM(IIF(T1.category = '80s Japanese comic', 1, 0)) / COUNT(T1.label_id) AS J8 , SUM(IIF(T1.category = '90s Japanese comic', 1, 0)) / COUNT(T1.label_id) AS J9 FROM label_categories AS T1 INNER JOIN app_labels AS T2 ON T1.label_id = T2.label_id
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE runs (
  run_at text,
  max_rowid integer,
  reviews_added integer
);
CREATE TABLE podcasts (
  podcast_id text PRIMARY KEY,
  itunes_id integer,
  slug text,
  itunes_url text,
  title text
);
CREATE TABLE reviews (
  podcast_id text,
  title text,
  content text,
  rating integer,
  author_id text,
  created_at text
);
CREATE TABLE categories (
  podcast_id text PRIMARY KEY,
  category text PRIMARY KEY
);

Hint: "Planet Money" is the title of podcast

Question: How many reviews does "Planet Money" have?

assistant: SELECT COUNT(T2.podcast_id) FROM podcasts AS T1 INNER JOIN reviews AS T2 ON T2.podcast_id = T1.podcast_id WHERE T1.title = 'Planet Money'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE "manufacturer" (
    "Manufacturer_ID" int,
    "Open_Year" real,
    "Name" text,
    "Num_of_Factories" int,
    "Num_of_Shops" int,
    PRIMARY KEY ("Manufacturer_ID")
);

Question: Find the name of the company that produces both furnitures with less than 6 components and furnitures with more than 10 components.

assistant: SELECT t3.name FROM furniture AS t1 JOIN furniture_manufacte AS t2 ON t1.Furniture_ID = t2.Furniture_ID JOIN manufacturer AS t3 ON t2.manufacturer_id = t3.manufacturer_id WHERE t1.num_of_component < 6 INTERSECT SELECT t3.name FROM furniture AS t1 JOIN furniture_manufacte AS t2 ON t1.Furniture_ID = t2.Furniture_ID JOIN manufacturer AS t3 ON t2.manufacturer_id = t3.manufacturer_id WHERE t1.num_of_component > 10
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
--data definition

create table genre(
	g_name varchar2(20) not null,
	rating varchar2(10),
	most_popular_in varchar2(50),
	primary key(g_name)
);

create table artist(
	artist_name varchar2(50) not null,
	country varchar2(20),
	gender varchar2(20),
	preferred_genre varchar2(50),
	constraint a_name primary key(artist_name),
	foreign key(preferred_genre) references genre(g_name) ON DELETE CASCADE
);

create table files(
	f_id number(10) not null,
	artist_name varchar2(50),
	file_size varchar2(20),
	duration varchar2(20),
	formats varchar2(20),
	primary key(f_id),
	foreign key(artist_name) references artist(artist_name) ON DELETE CASCADE
);


create table song(
	song_name varchar2(50),
	artist_name varchar2(50),
	country varchar2(20),
	f_id number(10),
    	genre_is varchar2(20),
	rating number(10) check(rating>0 and rating<11),
	languages varchar2(20),
	releasedate Date, 
	resolution number(10) not null,
	constraint s_name primary key(song_name),
	foreign key(artist_name) references artist(artist_name) ON DELETE CASCADE,
	foreign key(f_id) references files(f_id) ON DELETE CASCADE,
	foreign key(genre_is) references genre(g_name) ON DELETE CASCADE
);


--insertion of attributes in the table

Question: What is the id of every song that has a resolution higher than that of a song with a rating below 8?

assistant: SELECT f_id FROM song WHERE resolution > (SELECT max(resolution) FROM song WHERE rating < 8)
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE "driver" (
"Driver_ID" int,
"Name" text,
"Party" text,
"Home_city" text,
"Age" int,
PRIMARY KEY ("Driver_ID")
);

CREATE TABLE "school" (
"School_ID" int,
"Grade" text,
"School" text,
"Location" text,
"Type" text,
PRIMARY KEY ("School_ID")
);

Question: What is the maximum, minimum and average years spent working on a school bus?

assistant: SELECT max(years_working) , min(years_working) , avg(years_working) FROM school_bus
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE customers (
  CustomerID integer PRIMARY KEY,
  First text,
  Last text,
  StreetAddress text,
  City text,
  State text,
  ZipCode integer,
  Email text,
  PhoneNumber text,
  FirstPurchaseDate date,
  SubscribedToEmailList text,
  Gender text
);
CREATE TABLE geolocation (
  LocationID integer PRIMARY KEY,
  Latitude real,
  Longitude real
);
CREATE TABLE location (
  LocationID integer PRIMARY KEY,
  LocationName text,
  StreetAddress text,
  City text,
  State text,
  ZipCode integer
);
CREATE TABLE rootbeerbrand (
  BrandID integer PRIMARY KEY,
  BrandName text,
  FirstBrewedYear integer,
  BreweryName text,
  City text,
  State text,
  Country text,
  Description text,
  CaneSugar text,
  CornSyrup text,
  Honey text,
  ArtificialSweetener text,
  Caffeinated text,
  Alcoholic text,
  AvailableInCans text,
  AvailableInBottles text,
  AvailableInKegs text,
  Website text,
  FacebookPage text,
  Twitter text,
  WholesaleCost real,
  CurrentRetailPrice real
);
CREATE TABLE rootbeer (
  RootBeerID integer PRIMARY KEY,
  BrandID integer,
  ContainerType text,
  LocationID integer,
  PurchaseDate date
);
CREATE TABLE rootbeerreview (
  CustomerID integer PRIMARY KEY,
  BrandID integer PRIMARY KEY,
  StarRating integer,
  ReviewDate date,
  Review text
);
CREATE TABLE transaction (
  TransactionID integer PRIMARY KEY,
  CreditCardNumber integer,
  CustomerID integer,
  TransactionDate date,
  CreditCardType text,
  LocationID integer,
  RootBeerID integer,
  PurchasePrice real
);
-- foreign keys: geolocation.LocationID -> location.LocationID; location.LocationID -> geolocation.LocationID; rootbeer.BrandID -> rootbeerbrand.BrandID; rootbeer.LocationID -> location.LocationID; rootbeer.LocationID -> geolocation.LocationID; rootbeerreview.BrandID -> rootbeerbrand.BrandID; rootbeerreview.CustomerID -> customers.CustomerID; transaction.RootBeerID -> rootbeer.RootBeerID; transaction.LocationID -> location.LocationID; transaction.CustomerID -> customers.CustomerID

Hint: email addresses refers to Email; Sacramento refers to City = 'Sacramento'; star rating of more than 3 refers to StarRating > 3; in 2014 refers to ReviewDate LIKE '2014%';

Question: Tally the email addresses and phone numbers of customers from Sacramento who gave a star rating of more than 3 in 2014.

assistant: SELECT DISTINCT T1.Email, T1.PhoneNumber FROM customers AS T1 INNER JOIN rootbeerreview AS T2 ON T1.CustomerID = T2.CustomerID WHERE T2.StarRating > 3 AND T1.City = 'Sacramento' AND T2.ReviewDate BETWEEN '2014-01-01' AND '2014-12-31'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE "airport" (
"id" int,
"City" text,
"Country" text,
"IATA" text,
"ICAO" text,
"name" text,
primary key("id")
);


CREATE TABLE "operate_company" (
"id" int,
"name" text,
"Type" text,
"Principal_activities" text,
"Incorporated_in" text,
"Group_Equity_Shareholding" real,
primary key ("id")
);

CREATE TABLE "flight" (
"id" int,
"Vehicle_Flight_number" text,
"Date" text,
"Pilot" text,
"Velocity" real,
"Altitude" real,
"airport_id" int,
"company_id" int,
primary key ("id"),
foreign key ("airport_id") references `airport`("id"),
foreign key ("company_id") references `operate_company`("id")
);

Question: How many companies operates airlines in each airport?

assistant: SELECT T3.id , count(*) FROM operate_company AS T1 JOIN flight AS t2 ON T1.id = T2.company_id JOIN airport AS T3 ON T2.airport_id = T3.id GROUP BY T3.id
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE "club" (
"Club_ID" int,
"name" text,
"Region" text,
"Start_year" text,
PRIMARY KEY ("Club_ID")
);

Question: What are the different years for all competitions that are not of type equal to tournament?

assistant: SELECT DISTINCT YEAR FROM competition WHERE Competition_type != "Tournament"
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE current (
  ballotpedia_id text,
  bioguide_id text PRIMARY KEY,
  birthday_bio date,
  cspan_id real PRIMARY KEY,
  fec_id text,
  first_name text,
  gender_bio text,
  google_entity_id_id text,
  govtrack_id integer,
  house_history_id real,
  icpsr_id real,
  last_name text,
  lis_id text,
  maplight_id real,
  middle_name text,
  nickname_name text,
  official_full_name text,
  opensecrets_id text,
  religion_bio text,
  suffix_name text,
  thomas_id integer,
  votesmart_id real,
  wikidata_id text,
  wikipedia_id text
);
CREATE TABLE current-terms (
  address text,
  bioguide text PRIMARY KEY,
  caucus text,
  chamber text,
  class real,
  contact_form text,
  district real,
  end text PRIMARY KEY,
  fax text,
  last text,
  name text,
  office text,
  party text,
  party_affiliations text,
  phone text,
  relation text,
  rss_url text,
  start text,
  state text,
  state_rank text,
  title text,
  type text,
  url text
);
CREATE TABLE historical (
  ballotpedia_id text,
  bioguide_id text PRIMARY KEY,
  bioguide_previous_id text,
  birthday_bio text,
  cspan_id text,
  fec_id text,
  first_name text,
  gender_bio text,
  google_entity_id_id text,
  govtrack_id integer,
  house_history_alternate_id text,
  house_history_id real,
  icpsr_id real,
  last_name text,
  lis_id text,
  maplight_id text,
  middle_name text,
  nickname_name text,
  official_full_name text,
  opensecrets_id text,
  religion_bio text,
  suffix_name text,
  thomas_id text,
  votesmart_id text,
  wikidata_id text,
  wikipedia_id text
);
CREATE TABLE historical-terms (
  address text,
  bioguide text PRIMARY KEY,
  chamber text,
  class real,
  contact_form text,
  district real,
  end text,
  fax text,
  last text,
  middle text,
  name text,
  office text,
  party text,
  party_affiliations text,
  phone text,
  relation text,
  rss_url text,
  start text,
  state text,
  state_rank text,
  title text,
  type text,
  url text
);
CREATE TABLE social-media (
  bioguide text PRIMARY KEY,
  facebook text,
  facebook_id real,
  govtrack real,
  instagram text,
  instagram_id real,
  thomas integer,
  twitter text,
  twitter_id real,
  youtube text,
  youtube_id text
);
-- foreign keys: current-terms.bioguide -> current.bioguide_id; historical-terms.bioguide -> historical.bioguide_id; social-media.bioguide -> current.bioguide_id

Hint: do not have an account on ballotpedia.org refers to ballotpedia_id IS NULL OR ballotpedia_id = ''

Question: How many current legislators do not have an account on ballotpedia.org ?

assistant: SELECT COUNT(*) FROM current WHERE ballotpedia_id = '' OR ballotpedia_id IS NULL
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE current (
  ballotpedia_id text,
  bioguide_id text PRIMARY KEY,
  birthday_bio date,
  cspan_id real PRIMARY KEY,
  fec_id text,
  first_name text,
  gender_bio text,
  google_entity_id_id text,
  govtrack_id integer,
  house_history_id real,
  icpsr_id real,
  last_name text,
  lis_id text,
  maplight_id real,
  middle_name text,
  nickname_name text,
  official_full_name text,
  opensecrets_id text,
  religion_bio text,
  suffix_name text,
  thomas_id integer,
  votesmart_id real,
  wikidata_id text,
  wikipedia_id text
);
CREATE TABLE current-terms (
  address text,
  bioguide text PRIMARY KEY,
  caucus text,
  chamber text,
  class real,
  contact_form text,
  district real,
  end text PRIMARY KEY,
  fax text,
  last text,
  name text,
  office text,
  party text,
  party_affiliations text,
  phone text,
  relation text,
  rss_url text,
  start text,
  state text,
  state_rank text,
  title text,
  type text,
  url text
);
CREATE TABLE historical (
  ballotpedia_id text,
  bioguide_id text PRIMARY KEY,
  bioguide_previous_id text,
  birthday_bio text,
  cspan_id text,
  fec_id text,
  first_name text,
  gender_bio text,
  google_entity_id_id text,
  govtrack_id integer,
  house_history_alternate_id text,
  house_history_id real,
  icpsr_id real,
  last_name text,
  lis_id text,
  maplight_id text,
  middle_name text,
  nickname_name text,
  official_full_name text,
  opensecrets_id text,
  religion_bio text,
  suffix_name text,
  thomas_id text,
  votesmart_id text,
  wikidata_id text,
  wikipedia_id text
);
CREATE TABLE historical-terms (
  address text,
  bioguide text PRIMARY KEY,
  chamber text,
  class real,
  contact_form text,
  district real,
  end text,
  fax text,
  last text,
  middle text,
  name text,
  office text,
  party text,
  party_affiliations text,
  phone text,
  relation text,
  rss_url text,
  start text,
  state text,
  state_rank text,
  title text,
  type text,
  url text
);
CREATE TABLE social-media (
  bioguide text PRIMARY KEY,
  facebook text,
  facebook_id real,
  govtrack real,
  instagram text,
  instagram_id real,
  thomas integer,
  twitter text,
  twitter_id real,
  youtube text,
  youtube_id text
);
-- foreign keys: current-terms.bioguide -> current.bioguide_id; historical-terms.bioguide -> historical.bioguide_id; social-media.bioguide -> current.bioguide_id

Hint: started the term in 1875 refers to start LIKE '1875%'; started the term in 2005 refers to start LIKE '2005%'

Question: Compare the number of legislators who started the term in 1875 and 2005.

assistant: SELECT SUM(CASE WHEN `current-terms`.start LIKE '2005%' THEN 1 ELSE 0 END) - ( SELECT SUM(CASE WHEN start LIKE '1875%' THEN 1 ELSE 0 END) FROM `historical-terms` ) FROM `current-terms`
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE Attributes (
  attribute_id integer PRIMARY KEY,
  attribute_name text
);
CREATE TABLE Categories (
  category_id integer PRIMARY KEY,
  category_name text
);
CREATE TABLE Compliments (
  compliment_id integer PRIMARY KEY,
  compliment_type text
);
CREATE TABLE Days (
  day_id integer PRIMARY KEY,
  day_of_week text
);
CREATE TABLE Years (
  year_id integer PRIMARY KEY,
  actual_year integer
);
CREATE TABLE Business_Attributes (
  attribute_id integer PRIMARY KEY,
  business_id integer PRIMARY KEY,
  attribute_value text
);
CREATE TABLE Business_Categories (
  business_id integer PRIMARY KEY,
  category_id integer PRIMARY KEY
);
CREATE TABLE Business_Hours (
  business_id integer PRIMARY KEY,
  day_id integer PRIMARY KEY,
  opening_time text,
  closing_time text
);
CREATE TABLE Checkins (
  business_id integer PRIMARY KEY,
  day_id integer PRIMARY KEY,
  label_time_0 text,
  label_time_1 text,
  label_time_2 text,
  label_time_3 text,
  label_time_4 text,
  label_time_5 text,
  label_time_6 text,
  label_time_7 text,
  label_time_8 text,
  label_time_9 text,
  label_time_10 text,
  label_time_11 text,
  label_time_12 text,
  label_time_13 text,
  label_time_14 text,
  label_time_15 text,
  label_time_16 text,
  label_time_17 text,
  label_time_18 text,
  label_time_19 text,
  label_time_20 text,
  label_time_21 text,
  label_time_22 text,
  label_time_23 text
);
CREATE TABLE Elite (
  user_id integer PRIMARY KEY,
  year_id integer PRIMARY KEY
);
CREATE TABLE Reviews (
  business_id integer PRIMARY KEY,
  user_id integer PRIMARY KEY,
  review_stars integer,
  review_votes_funny text,
  review_votes_useful text,
  review_votes_cool text,
  review_length text
);
CREATE TABLE Tips (
  business_id integer PRIMARY KEY,
  user_id integer PRIMARY KEY,
  likes integer,
  tip_length text
);
CREATE TABLE Users_Compliments (
  compliment_id integer PRIMARY KEY,
  user_id integer PRIMARY KEY,
  number_of_compliments text
);
CREATE TABLE Business (
  business_id integer PRIMARY KEY,
  active text,
  city text,
  state text,
  stars real,
  review_count text
);
CREATE TABLE Users (
  user_id integer PRIMARY KEY,
  user_yelping_since_year integer,
  user_average_stars text,
  user_votes_funny text,
  user_votes_useful text,
  user_votes_cool text,
  user_review_count text,
  user_fans text
);

Hint: do not open on Thursday refers to day_of_week = 'Thursday' AND label_time_4 = 'None';

Question: How many businesses in AZ state do not open on Thursday?

assistant: SELECT COUNT(T1.business_id) FROM Business AS T1 INNER JOIN Checkins AS T2 ON T1.business_id = T2.business_id INNER JOIN Days AS T3 ON T2.day_id = T3.day_id WHERE T2.label_time_4 LIKE 'None' AND T1.state LIKE 'AZ' AND T3.day_of_week LIKE 'Thursday'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
/* 
 * SQL scripts for CS61 Intro to SQL lectures
 * FILENAME SOCCER2.SQL
 */

DROP TABLE  IF EXISTS Player;
DROP TABLE  IF EXISTS Tryout;
DROP TABLE  IF EXISTS College;

CREATE TABLE 	College 
  ( cName   	varchar(20) NOT NULL,
    state   	varchar(2),
    enr     	numeric(5,0),
    PRIMARY KEY (cName)
  );

CREATE TABLE 	Player
  ( pID			numeric(5,0) NOT NULL,
  	pName   	varchar(20),
    yCard   	varchar(3),
    HS      	numeric(5,0),
    PRIMARY KEY (pID)
  );

CREATE TABLE 	Tryout
  ( pID			numeric(5,0),
  	cName   	varchar(20),
    pPos    	varchar(8),
    decision    varchar(3),
    PRIMARY KEY (pID, cName),
    FOREIGN KEY (pID) REFERENCES Player(pID),
    FOREIGN KEY (cName) REFERENCES College(cName)
  );

/* note that "left" and "right" are reserved words in SQL */

Question: What is the average number of hours spent practicing for students who got rejected?

assistant: SELECT avg(T1.HS) FROM player AS T1 JOIN tryout AS T2 ON T1.pID = T2.pID WHERE T2.decision = 'no'