ajayk007/querysmith-spider-bird huggingface dataset:
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE Ref_Document_Types (
Document_Type_Code CHAR(15) NOT NULL,
Document_Type_Name VARCHAR(255) NOT NULL,
Document_Type_Description VARCHAR(255) NOT NULL,
PRIMARY KEY (Document_Type_Code)
);
CREATE TABLE Ref_Budget_Codes (
Budget_Type_Code CHAR(15) NOT NULL,
Budget_Type_Description VARCHAR(255) NOT NULL,
PRIMARY KEY (Budget_Type_Code)
);

Question: What are the dates for the documents with both 'GV' type and 'SF' type expenses?

assistant: SELECT T1.document_date FROM Documents AS T1 JOIN Documents_with_Expenses AS T2 ON T1.document_id = T2.document_id WHERE T2.budget_type_code = 'GV' INTERSECT SELECT T1.document_date FROM Documents AS T1 JOIN Documents_with_Expenses AS T2 ON T1.document_id = T2.document_id WHERE T2.budget_type_code = 'SF'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE playstore (
  App text,
  Category text,
  Rating real,
  Reviews integer,
  Size text,
  Installs text,
  Type text,
  Price text,
  Content Rating text,
  Genres text
);
CREATE TABLE user_reviews (
  App text,
  Translated_Review text,
  Sentiment text,
  Sentiment_Polarity text,
  Sentiment_Subjectivity text
);
-- foreign keys: user_reviews.App -> playstore.App

Hint: average sentiment polarity score = AVG(Sentiment_Polarity); Golf GPS Rangefinder: Golf Pad  is the App;

Question: How much is the average sentiment polarity score of Golf GPS Rangefinder: Golf Pad and what is it's rating in the Google Play Store?

assistant: SELECT AVG(T2.Sentiment_Polarity), T1.Rating FROM playstore AS T1 INNER JOIN user_reviews AS T2 ON T1.App = T2.App WHERE T1.App = 'Golf GPS Rangefinder: Golf Pad'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
-- phpMyAdmin SQL Dump
-- version 4.0.10.7
-- http://www.phpmyadmin.net
--
-- Host: localhost
-- Generation Time: Mar 20, 2015 at 01:43 AM
-- Server version: 5.5.34-cll-lve
-- PHP Version: 5.4.23



/*!40101 SET @OLD_CHARACTER_SET_CLIENT=@@CHARACTER_SET_CLIENT */;
/*!40101 SET @OLD_CHARACTER_SET_RESULTS=@@CHARACTER_SET_RESULTS */;
/*!40101 SET @OLD_COLLATION_CONNECTION=@@COLLATION_CONNECTION */;
/*!40101 SET NAMES utf8 */;
CREATE TABLE IF NOT EXISTS `regions` (
  `REGION_ID` decimal(5,0) NOT NULL,
  `REGION_NAME` varchar(25) DEFAULT NULL,
  PRIMARY KEY (`REGION_ID`)
);

--
-- Dumping data for table `regions`
--

Question: Find employee with ID and name of the country presently where (s)he is working.

assistant: SELECT T1.employee_id , T4.country_name FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id JOIN locations AS T3 ON T2.location_id = T3.location_id JOIN countries AS T4 ON T3.country_id = T4.country_id
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
-- phpMyAdmin SQL Dump
-- version 4.0.10.7
-- http://www.phpmyadmin.net
--
-- Host: localhost
-- Generation Time: Mar 20, 2015 at 01:43 AM
-- Server version: 5.5.34-cll-lve
-- PHP Version: 5.4.23



/*!40101 SET @OLD_CHARACTER_SET_CLIENT=@@CHARACTER_SET_CLIENT */;
/*!40101 SET @OLD_CHARACTER_SET_RESULTS=@@CHARACTER_SET_RESULTS */;
/*!40101 SET @OLD_COLLATION_CONNECTION=@@COLLATION_CONNECTION */;
/*!40101 SET NAMES utf8 */;
CREATE TABLE IF NOT EXISTS `regions` (
  `REGION_ID` decimal(5,0) NOT NULL,
  `REGION_NAME` varchar(25) DEFAULT NULL,
  PRIMARY KEY (`REGION_ID`)
);

--
-- Dumping data for table `regions`
--

Question: Return the full names and salaries of employees with null commissions.

assistant: SELECT first_name , last_name , salary FROM employees WHERE commission_pct = "null"
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE langs (
  lid integer PRIMARY KEY,
  lang text,
  locale text,
  pages integer,
  words integer
);
CREATE TABLE pages (
  pid integer PRIMARY KEY,
  lid integer,
  page integer,
  revision integer,
  title text,
  words integer
);
CREATE TABLE words (
  wid integer PRIMARY KEY,
  word text,
  occurrences integer
);
CREATE TABLE langs_words (
  lid integer PRIMARY KEY,
  wid integer PRIMARY KEY,
  occurrences integer
);
CREATE TABLE pages_words (
  pid integer PRIMARY KEY,
  wid integer PRIMARY KEY,
  occurrences integer
);
CREATE TABLE biwords (
  lid integer PRIMARY KEY,
  w1st integer PRIMARY KEY,
  w2nd integer PRIMARY KEY,
  occurrences integer
);
-- foreign keys: pages.lid -> langs.lid; langs_words.wid -> words.wid; langs_words.lid -> langs.lid; pages_words.wid -> words.wid; pages_words.pid -> pages.pid; biwords.w2nd -> words.wid; biwords.w1st -> words.wid; biwords.lid -> langs.lid

Hint: the biwords pair that appears "116430" times refers to occurrences = 116430; second word of the pair refers to w2nd

Question: For the biwords pair that appears "116430" times, what is the second word of the pair?

assistant: SELECT T1.word FROM words AS T1 INNER JOIN biwords AS T2 ON T1.wid = T2.w2nd WHERE T2.occurrences = 116430
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE "buildings" (
"id" int,
"name" text,
"City" text,
"Height" int,
"Stories" int,
"Status" text,
PRIMARY KEY("id")
);

Question: Which buildings do not have any company office? Give me the building names.

assistant: SELECT name FROM buildings WHERE id NOT IN (SELECT building_id FROM Office_locations)
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE lists (
  user_id integer,
  list_id integer PRIMARY KEY,
  list_title text,
  list_movie_number integer,
  list_update_timestamp_utc text,
  list_creation_timestamp_utc text,
  list_followers integer,
  list_url text,
  list_comments integer,
  list_description text,
  list_cover_image_url text,
  list_first_image_url text,
  list_second_image_url text,
  list_third_image_url text
);
CREATE TABLE movies (
  movie_id integer PRIMARY KEY,
  movie_title text,
  movie_release_year integer,
  movie_url text,
  movie_title_language text,
  movie_popularity integer,
  movie_image_url text,
  director_id text,
  director_name text,
  director_url text
);
CREATE TABLE ratings_users (
  user_id integer,
  rating_date_utc text,
  user_trialist integer,
  user_subscriber integer,
  user_avatar_image_url text,
  user_cover_image_url text,
  user_eligible_for_trial integer,
  user_has_payment_method integer
);
CREATE TABLE lists_users (
  user_id integer PRIMARY KEY,
  list_id integer PRIMARY KEY,
  list_update_date_utc text,
  list_creation_date_utc text,
  user_trialist integer,
  user_subscriber integer,
  user_avatar_image_url text,
  user_cover_image_url text,
  user_eligible_for_trial text,
  user_has_payment_method text
);
CREATE TABLE ratings (
  movie_id integer,
  rating_id integer,
  rating_url text,
  rating_score integer,
  rating_timestamp_utc text,
  critic text,
  critic_likes integer,
  critic_comments integer,
  user_id integer,
  user_trialist integer,
  user_subscriber integer,
  user_eligible_for_trial integer,
  user_has_payment_method integer
);
-- foreign keys: lists.user_id -> lists_users.user_id; ratings_users.user_id -> lists_users.user_id; lists_users.user_id -> lists.user_id; lists_users.list_id -> lists.list_id; ratings.user_id -> ratings_users.user_id; ratings.user_id -> lists_users.user_id; ratings.movie_id -> movies.movie_id

Hint: created in 2016 refers to list_creation_timestamp_utc like '2016%'; updated most recently refers to MAX(list_update_timestamp_utc)

Question: Among the lists created in 2016, which is the list that was updated most recently.

assistant: SELECT list_title FROM lists WHERE strftime('%Y', list_update_timestamp_utc) = '2016' ORDER BY list_update_timestamp_utc DESC LIMIT 1
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE course (
  course_id integer PRIMARY KEY,
  name text,
  credit integer,
  diff integer
);
CREATE TABLE prof (
  prof_id integer PRIMARY KEY,
  gender text,
  first_name text,
  last_name text,
  email text,
  popularity integer,
  teachingability integer,
  graduate_from text
);
CREATE TABLE RA (
  student_id integer PRIMARY KEY,
  capability integer,
  prof_id integer PRIMARY KEY,
  salary text
);
CREATE TABLE registration (
  course_id integer PRIMARY KEY,
  student_id integer PRIMARY KEY,
  grade text,
  sat integer
);
CREATE TABLE student (
  student_id integer PRIMARY KEY,
  f_name text,
  l_name text,
  phone_number text,
  email text,
  intelligence integer,
  gpa real,
  type text
);
-- foreign keys: RA.student_id -> student.student_id; RA.prof_id -> prof.prof_id; registration.student_id -> student.student_id; registration.course_id -> course.course_id

Hint: teachability < = 3; percentage = MULTIPLY(DIVIDE(COUNT(salary = 'low'), COUNT(salary)), 1.0);

Question: Among the professors with a teachability of 3 and below, what is the percentage of their student advisees with a low salary?

assistant: SELECT CAST(SUM(CASE WHEN T1.salary = 'low' THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(T1.salary) FROM RA AS T1 INNER JOIN prof AS T2 ON T1.prof_id = T2.prof_id WHERE T2.teachingability < 3
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE Author (
  Id integer PRIMARY KEY,
  Name text,
  Affiliation text
);
CREATE TABLE Conference (
  Id integer PRIMARY KEY,
  ShortName text,
  FullName text,
  HomePage text
);
CREATE TABLE Journal (
  Id integer PRIMARY KEY,
  ShortName text,
  FullName text,
  HomePage text
);
CREATE TABLE Paper (
  Id integer PRIMARY KEY,
  Title text,
  Year integer,
  ConferenceId integer,
  JournalId integer,
  Keyword text
);
CREATE TABLE PaperAuthor (
  PaperId integer,
  AuthorId integer,
  Name text,
  Affiliation text
);
-- foreign keys: Paper.JournalId -> Journal.Id; Paper.ConferenceId -> Conference.Id; PaperAuthor.AuthorId -> Author.Id; PaperAuthor.PaperId -> Paper.Id

Hint: "Stitching videos streamed by mobile phones in real-time" is the Title of paper; what the paper is about refers to Keywords

Question: What is the paper "Stitching videos streamed by mobile phones in real-time" about?

assistant: SELECT Keyword FROM Paper WHERE Title = 'Stitching videos streamed by mobile phones in real-time'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;
CREATE TABLE `Addresses` (
`address_id` INTEGER PRIMARY KEY,
`address_details` VARCHAR(255)
);

Question: Give the ids and names of products with price lower than 600 or higher than 900.

assistant: SELECT product_id , product_name FROM products WHERE product_price < 600 OR product_price > 900
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE Demog (
  GEOID integer PRIMARY KEY,
  INHABITANTS_K real,
  INCOME_K real,
  A_VAR1 real,
  A_VAR2 real,
  A_VAR3 real,
  A_VAR4 real,
  A_VAR5 real,
  A_VAR6 real,
  A_VAR7 real,
  A_VAR8 real,
  A_VAR9 real,
  A_VAR10 real,
  A_VAR11 real,
  A_VAR12 real,
  A_VAR13 real,
  A_VAR14 real,
  A_VAR15 real,
  A_VAR16 real,
  A_VAR17 real,
  A_VAR18 real
);
CREATE TABLE mailings3 (
  REFID integer PRIMARY KEY,
  REF_DATE datetime,
  RESPONSE text
);
CREATE TABLE Customers (
  ID integer PRIMARY KEY,
  SEX text,
  MARITAL_STATUS text,
  GEOID integer,
  EDUCATIONNUM integer,
  OCCUPATION text,
  age integer
);
CREATE TABLE Mailings1_2 (
  REFID integer PRIMARY KEY,
  REF_DATE datetime,
  RESPONSE text
);
CREATE TABLE Sales (
  EVENTID integer PRIMARY KEY,
  REFID integer,
  EVENT_DATE datetime,
  AMOUNT real
);

Hint: geographic identifier refers to GEOID; OCCUPATION = 'Handlers-cleaners';

Question: List down the customer's geographic identifier who are handlers or cleaners.

assistant: SELECT GEOID FROM Customers WHERE OCCUPATION = 'Handlers-cleaners'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
/* 
 * SQL scripts for CS61 Intro to SQL lectures
 * FILENAME SOCCER2.SQL
 */

DROP TABLE  IF EXISTS Player;
DROP TABLE  IF EXISTS Tryout;
DROP TABLE  IF EXISTS College;

CREATE TABLE 	College 
  ( cName   	varchar(20) NOT NULL,
    state   	varchar(2),
    enr     	numeric(5,0),
    PRIMARY KEY (cName)
  );

CREATE TABLE 	Player
  ( pID			numeric(5,0) NOT NULL,
  	pName   	varchar(20),
    yCard   	varchar(3),
    HS      	numeric(5,0),
    PRIMARY KEY (pID)
  );

CREATE TABLE 	Tryout
  ( pID			numeric(5,0),
  	cName   	varchar(20),
    pPos    	varchar(8),
    decision    varchar(3),
    PRIMARY KEY (pID, cName),
    FOREIGN KEY (pID) REFERENCES Player(pID),
    FOREIGN KEY (cName) REFERENCES College(cName)
  );

/* note that "left" and "right" are reserved words in SQL */

Question: Find the name of all students who were in the tryout sorted in alphabetic order.

assistant: SELECT T1.pName FROM player AS T1 JOIN tryout AS T2 ON T1.pID = T2.pID ORDER BY T1.pName
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE Episode (
  episode_id text PRIMARY KEY,
  season integer,
  episode integer,
  number_in_series integer,
  title text,
  summary text,
  air_date text,
  episode_image text,
  rating real,
  votes integer
);
CREATE TABLE Person (
  name text PRIMARY KEY,
  birthdate text,
  birth_name text,
  birth_place text,
  birth_region text,
  birth_country text,
  height_meters real,
  nickname text
);
CREATE TABLE Award (
  award_id integer PRIMARY KEY,
  organization text,
  year integer,
  award_category text,
  award text,
  person text,
  role text,
  episode_id text,
  season text,
  song text,
  result text
);
CREATE TABLE Character_Award (
  award_id integer,
  character text
);
CREATE TABLE Credit (
  episode_id text,
  category text,
  person text,
  role text,
  credited text
);
CREATE TABLE Keyword (
  episode_id text PRIMARY KEY,
  keyword text PRIMARY KEY
);
CREATE TABLE Vote (
  episode_id text,
  stars integer,
  votes integer,
  percent real
);
-- foreign keys: Award.episode_id -> Episode.episode_id; Award.person -> Person.name; Character_Award.award_id -> Award.award_id; Credit.person -> Person.name; Credit.episode_id -> Episode.episode_id; Keyword.episode_id -> Episode.episode_id; Vote.episode_id -> Episode.episode_id

Hint: scores 5 to 10 refers to TOTAL(percent) where 1 < = stars < 5

Question: Out of the rating of 6.8 scored by title "No Loan Again, Naturally", how many percent of it consists of scores 5 to 10?

assistant: SELECT SUM(T2.percent) FROM Episode AS T1 INNER JOIN Vote AS T2 ON T2.episode_id = T1.episode_id WHERE T1.title = 'No Loan Again, Naturally' AND T1.rating = 6.8 AND T2.stars BETWEEN 5 AND 10;
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE Episode (
  episode_id text PRIMARY KEY,
  series text,
  season integer,
  episode integer,
  number_in_series integer,
  title text,
  summary text,
  air_date date,
  episode_image text,
  rating real,
  votes integer
);
CREATE TABLE Keyword (
  episode_id text PRIMARY KEY,
  keyword text PRIMARY KEY
);
CREATE TABLE Person (
  person_id text PRIMARY KEY,
  name text,
  birthdate date,
  birth_name text,
  birth_place text,
  birth_region text,
  birth_country text,
  height_meters real,
  nickname text
);
CREATE TABLE Award (
  award_id integer PRIMARY KEY,
  organization text,
  year integer,
  award_category text,
  award text,
  series text,
  episode_id text,
  person_id text,
  role text,
  result text
);
CREATE TABLE Credit (
  episode_id text PRIMARY KEY,
  person_id text PRIMARY KEY,
  category text,
  role text,
  credited text
);
CREATE TABLE Vote (
  episode_id text,
  stars integer,
  votes integer,
  percent real
);
-- foreign keys: Keyword.episode_id -> Episode.episode_id; Award.person_id -> Person.person_id; Award.episode_id -> Episode.episode_id; Credit.person_id -> Person.person_id; Credit.episode_id -> Episode.episode_id; Vote.episode_id -> Episode.episode_id

Hint: average rating = divide(sum(rating), count(episode_id))

Question: What is the average rating for each episode in season 9?

assistant: SELECT SUM(rating) / COUNT(episode_id) FROM Episode WHERE season = 9
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE `Roles` (
`role_code` VARCHAR(15) PRIMARY KEY,
`role_description` VARCHAR(80)
);

CREATE TABLE `Users` (
`user_id` INTEGER PRIMARY KEY,
`role_code` VARCHAR(15) NOT NULL,
`user_name` VARCHAR(40),
`user_login` VARCHAR(40),
`password` VARCHAR(40),
FOREIGN KEY (`role_code` ) REFERENCES `Roles`(`role_code` )
);

Question: Give the section titles of the document with the name "David CV".

assistant: SELECT t2.section_title FROM documents AS t1 JOIN document_sections AS t2 ON t1.document_code = t2.document_code WHERE t1.document_name = "David CV"
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE "race" (
"Race_ID" int,
"Name" text,
"Class" text,
"Date" text,
"Track_ID" text,
PRIMARY KEY ("Race_ID"),
FOREIGN KEY ("Track_ID") REFERENCES "track"("Track_ID")
);

CREATE TABLE "track" (
"Track_ID" int,
"Name" text,
"Location" text,
"Seating" real,
"Year_Opened" real,
PRIMARY KEY ("Track_ID")
);

Question: What are the different classes of races, and how many races correspond to each?

assistant: SELECT CLASS , count(*) FROM race GROUP BY CLASS
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;


CREATE TABLE Services (
Service_ID INTEGER NOT NULL,
Service_Type_Code CHAR(15) NOT NULL,
PRIMARY KEY (Service_ID)
);

Question: Which services type had both successful and failure event details?

assistant: SELECT T1.service_type_code FROM services AS T1 JOIN EVENTS AS T2 ON T1.service_id = T2.service_id WHERE T2.event_details = 'Success' INTERSECT SELECT T1.service_type_code FROM services AS T1 JOIN EVENTS AS T2 ON T1.service_id = T2.service_id WHERE T2.event_details = 'Fail'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE "perpetrator" (
"Perpetrator_ID" int,
"People_ID" int,
"Date" text,
"Year" real,
"Location" text,
"Country" text,
"Killed" int,
"Injured" int,
PRIMARY KEY ("Perpetrator_ID"),
FOREIGN KEY ("People_ID") REFERENCES "people"("People_ID")
);

CREATE TABLE "people" (
"People_ID" int,
"Name" text,
"Height" real,
"Weight" real,
"Home Town" text,
PRIMARY KEY ("People_ID")
);

Question: What is the average number of people injured by all perpetrators?

assistant: SELECT avg(Injured) FROM perpetrator
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE "county_public_safety" (
"County_ID" int,
"Name" text,
"Population" int,
"Police_officers" int,
"Residents_per_officer" int,
"Case_burden" int,
"Crime_rate" real,
"Police_force" text,
"Location" text,
PRIMARY KEY ("County_ID")
);

CREATE TABLE "city" (
"City_ID" int,
"County_ID" int,
"Name" text,
"White" real,
"Black" real,
"Amerindian" real,
"Asian" real,
"Multiracial" real,
"Hispanic" real,
PRIMARY KEY ("City_ID"),
FOREIGN KEY ("County_ID") REFERENCES "county_public_safety"("County_ID")
);

Question: Which police forces operate in both counties that are located in the East and in the West?

assistant: SELECT Police_force FROM county_public_safety WHERE LOCATION = "East" INTERSECT SELECT Police_force FROM county_public_safety WHERE LOCATION = "West"
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE torrents (
  groupName text,
  totalSnatched integer,
  artist text,
  groupYear integer,
  releaseType text,
  groupId integer,
  id integer PRIMARY KEY
);
CREATE TABLE tags (
  index integer PRIMARY KEY,
  id integer,
  tag text
);

Hint: From 1979 to 1982 refers to groupYear between 1979 and 1982; United States refer to tag; albums refer to releaseType; DIVIDE(COUNT(releaseType = 'album' where tag = 'united.states' and groupYear between 1979 and 1982), COUNT(releaseType = 'album' where groupYear between 1979 and 1982)) as percentage;

Question: From 1979 to 1982, what was the percentage of united.states albums out of total albums were released?

assistant: SELECT CAST(SUM(CASE WHEN T2.tag LIKE 'united.states' THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(T1.releaseType) FROM torrents AS T1 INNER JOIN tags AS T2 ON T1.id = T2.id WHERE T1.groupYear BETWEEN 1979 AND 1982 AND T1.releaseType LIKE 'album'