ajayk007/querysmith-spider-bird huggingface dataset:
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
/* 
 * SQL scripts for CS61 Intro to SQL lectures
 * FILENAME SOCCER2.SQL
 */

DROP TABLE  IF EXISTS Player;
DROP TABLE  IF EXISTS Tryout;
DROP TABLE  IF EXISTS College;

CREATE TABLE 	College 
  ( cName   	varchar(20) NOT NULL,
    state   	varchar(2),
    enr     	numeric(5,0),
    PRIMARY KEY (cName)
  );

CREATE TABLE 	Player
  ( pID			numeric(5,0) NOT NULL,
  	pName   	varchar(20),
    yCard   	varchar(3),
    HS      	numeric(5,0),
    PRIMARY KEY (pID)
  );

CREATE TABLE 	Tryout
  ( pID			numeric(5,0),
  	cName   	varchar(20),
    pPos    	varchar(8),
    decision    varchar(3),
    PRIMARY KEY (pID, cName),
    FOREIGN KEY (pID) REFERENCES Player(pID),
    FOREIGN KEY (cName) REFERENCES College(cName)
  );

/* note that "left" and "right" are reserved words in SQL */

Question: What are the different names of the colleges involved in the tryout in alphabetical order?

assistant: SELECT DISTINCT cName FROM tryout ORDER BY cName
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE ATT_CLASSES (
  ATT_CLASS_ID integer PRIMARY KEY,
  ATT_CLASS text
);
CREATE TABLE OBJ_CLASSES (
  OBJ_CLASS_ID integer PRIMARY KEY,
  OBJ_CLASS text
);
CREATE TABLE IMG_OBJ (
  IMG_ID integer PRIMARY KEY,
  OBJ_SAMPLE_ID integer PRIMARY KEY,
  OBJ_CLASS_ID integer,
  X integer,
  Y integer,
  W integer,
  H integer
);
CREATE TABLE IMG_OBJ_ATT (
  IMG_ID integer PRIMARY KEY,
  ATT_CLASS_ID integer PRIMARY KEY,
  OBJ_SAMPLE_ID integer PRIMARY KEY
);
CREATE TABLE PRED_CLASSES (
  PRED_CLASS_ID integer PRIMARY KEY,
  PRED_CLASS text
);
CREATE TABLE IMG_REL (
  IMG_ID integer PRIMARY KEY,
  PRED_CLASS_ID integer PRIMARY KEY,
  OBJ1_SAMPLE_ID integer PRIMARY KEY,
  OBJ2_SAMPLE_ID integer PRIMARY KEY
);
-- foreign keys: IMG_OBJ.OBJ_CLASS_ID -> OBJ_CLASSES.OBJ_CLASS_ID; IMG_OBJ_ATT.IMG_ID -> IMG_OBJ.IMG_ID; IMG_OBJ_ATT.OBJ_SAMPLE_ID -> IMG_OBJ.OBJ_SAMPLE_ID; IMG_OBJ_ATT.ATT_CLASS_ID -> ATT_CLASSES.ATT_CLASS_ID; IMG_REL.IMG_ID -> IMG_OBJ.IMG_ID; IMG_REL.OBJ2_SAMPLE_ID -> IMG_OBJ.OBJ_SAMPLE_ID; IMG_REL.IMG_ID -> IMG_OBJ.IMG_ID; IMG_REL.OBJ1_SAMPLE_ID -> IMG_OBJ.OBJ_SAMPLE_ID; IMG_REL.PRED_CLASS_ID -> PRED_CLASSES.PRED_CLASS_ID

Hint: dress' object classes refer to OBJ_CLASS = 'dress'; image ID 1764 refers to IMG_ID = 1764; X and Y refer to coordinates of the bounding box;

Question: Count the number of 'dress' object classes and include their X and Y coordinates in image ID 1764.

assistant: SELECT T1.X, T1.Y FROM IMG_OBJ AS T1 INNER JOIN OBJ_CLASSES AS T2 ON T1.OBJ_CLASS_ID = T2.OBJ_CLASS_ID WHERE T1.IMG_ID = 1764 AND T2.OBJ_CLASS = 'dress'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE country (
  id integer PRIMARY KEY,
  country_name text
);
CREATE TABLE ranking_system (
  id integer PRIMARY KEY,
  system_name text
);
CREATE TABLE ranking_criteria (
  id integer PRIMARY KEY,
  ranking_system_id integer,
  criteria_name text
);
CREATE TABLE university (
  id integer PRIMARY KEY,
  country_id integer,
  university_name text
);
CREATE TABLE university_ranking_year (
  university_id integer,
  ranking_criteria_id integer,
  year integer,
  score integer
);
CREATE TABLE university_year (
  university_id integer,
  year integer,
  num_students integer,
  student_staff_ratio real,
  pct_international_students integer,
  pct_female_students integer
);
-- foreign keys: ranking_criteria.ranking_system_id -> ranking_system.id; university.country_id -> country.id; university_ranking_year.university_id -> university.id; university_ranking_year.ranking_criteria_id -> ranking_criteria.id; university_year.university_id -> university.id

Hint: total number of female students refers to SUM(DIVIDE(MULTIPLY(pct_female_students, num_students), 100)); In years 2011 to 2013 refers to year BETWEEN 2011 AND 2013

Question: In years 2011 to 2013, what is the total number of female students in university ID 40?

assistant: SELECT SUM(CAST(num_students * pct_female_students AS REAL) / 100) FROM university_year WHERE year BETWEEN 2011 AND 2013 AND university_id = 40
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;
CREATE TABLE `Course_Authors_and_Tutors` (
`author_id` INTEGER PRIMARY KEY,
`author_tutor_ATB` VARCHAR(3),
`login_name` VARCHAR(40),
`password` VARCHAR(40),
`personal_name` VARCHAR(80),
`middle_name` VARCHAR(80),
`family_name` VARCHAR(80),
`gender_mf` VARCHAR(1),
`address_line_1` VARCHAR(80)
);

Question: Which student are enrolled in at least two courses? Give me the student ID and personal name.

assistant: SELECT T1.student_id , T2.personal_name FROM Student_Course_Enrolment AS T1 JOIN Students AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id HAVING COUNT(*) >= 2
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE country (
  country_id integer PRIMARY KEY,
  country_iso_code text,
  country_name text
);
CREATE TABLE department (
  department_id integer PRIMARY KEY,
  department_name text
);
CREATE TABLE gender (
  gender_id integer PRIMARY KEY,
  gender text
);
CREATE TABLE genre (
  genre_id integer PRIMARY KEY,
  genre_name text
);
CREATE TABLE keyword (
  keyword_id integer PRIMARY KEY,
  keyword_name text
);
CREATE TABLE language (
  language_id integer PRIMARY KEY,
  language_code text,
  language_name text
);
CREATE TABLE language_role (
  role_id integer PRIMARY KEY,
  language_role text
);
CREATE TABLE movie (
  movie_id integer PRIMARY KEY,
  title text,
  budget integer,
  homepage text,
  overview text,
  popularity real,
  release_date date,
  revenue integer,
  runtime integer,
  movie_status text,
  tagline text,
  vote_average real,
  vote_count integer
);
CREATE TABLE movie_genres (
  movie_id integer,
  genre_id integer
);
CREATE TABLE movie_languages (
  movie_id integer,
  language_id integer,
  language_role_id integer
);
CREATE TABLE person (
  person_id integer PRIMARY KEY,
  person_name text
);
CREATE TABLE movie_crew (
  movie_id integer,
  person_id integer,
  department_id integer,
  job text
);
CREATE TABLE production_company (
  company_id integer PRIMARY KEY,
  company_name text
);
CREATE TABLE production_country (
  movie_id integer,
  country_id integer
);
CREATE TABLE movie_cast (
  movie_id integer,
  person_id integer,
  character_name text,
  gender_id integer,
  cast_order integer
);
CREATE TABLE movie_keywords (
  movie_id integer,
  keyword_id integer
);
CREATE TABLE movie_company (
  movie_id integer,
  company_id integer
);
-- foreign keys: movie_genres.movie_id -> movie.movie_id; movie_genres.genre_id -> genre.genre_id; movie_languages.language_role_id -> language_role.role_id; movie_languages.movie_id -> movie.movie_id; movie_languages.language_id -> language.language_id; movie_crew.person_id -> person.person_id; movie_crew.movie_id -> movie.movie_id; movie_crew.department_id -> department.department_id; production_country.movie_id -> movie.movie_id; production_country.country_id -> country.country_id; movie_cast.person_id -> person.person_id; movie_cast.movie_id -> movie.movie_id; movie_cast.gender_id -> gender.gender_id

Hint: Latin movies refers to language_name = 'Latin'; average revenue = AVG(revenue)

Question: What is the average revenue made by Latin movies?

assistant: SELECT AVG(T1.revenue) FROM movie AS T1 INNER JOIN movie_languages AS T2 ON T1.movie_id = T2.movie_id INNER JOIN language AS T3 ON T2.language_id = T3.language_id WHERE T3.language_name = 'Latin'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;


CREATE TABLE Services (
Service_ID INTEGER NOT NULL,
Service_Type_Code CHAR(15) NOT NULL,
PRIMARY KEY (Service_ID)
);

Question: What are the ids and details of events that have more than one participants?

assistant: SELECT T1.event_id , T1.event_details FROM EVENTS AS T1 JOIN Participants_in_Events AS T2 ON T1.Event_ID = T2.Event_ID GROUP BY T1.Event_ID HAVING count(*) > 1
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE "device" (
"Device_ID" int,
"Device" text,
"Carrier" text,
"Package_Version" text,
"Applications" text,
"Software_Platform" text,
PRIMARY KEY ("Device_ID")
);

CREATE TABLE "shop" (
"Shop_ID" int,
"Shop_Name" text,
"Location" text,
"Open_Date" text,
"Open_Year" int,
PRIMARY KEY ("Shop_ID")
);

Question: List the software platform shared by the greatest number of devices.

assistant: SELECT Software_Platform FROM device GROUP BY Software_Platform ORDER BY COUNT(*) DESC LIMIT 1
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE people (
  Customer ID text PRIMARY KEY,
  Customer Name text,
  Segment text,
  Country text,
  City text,
  State text,
  Postal Code integer,
  Region text PRIMARY KEY
);
CREATE TABLE product (
  Product ID text PRIMARY KEY,
  Product Name text,
  Category text,
  Sub-Category text,
  Region text PRIMARY KEY
);
CREATE TABLE central_superstore (
  Row ID integer PRIMARY KEY,
  Order ID text,
  Order Date date,
  Ship Date date,
  Ship Mode text,
  Customer ID text,
  Region text,
  Product ID text,
  Sales real,
  Quantity integer,
  Discount real,
  Profit real
);
CREATE TABLE east_superstore (
  Row ID integer PRIMARY KEY,
  Order ID text,
  Order Date date,
  Ship Date date,
  Ship Mode text,
  Customer ID text,
  Region text,
  Product ID text,
  Sales real,
  Quantity integer,
  Discount real,
  Profit real
);
CREATE TABLE south_superstore (
  Row ID integer PRIMARY KEY,
  Order ID text,
  Order Date date,
  Ship Date date,
  Ship Mode text,
  Customer ID text,
  Region text,
  Product ID text,
  Sales real,
  Quantity integer,
  Discount real,
  Profit real
);
CREATE TABLE west_superstore (
  Row ID integer PRIMARY KEY,
  Order ID text,
  Order Date date,
  Ship Date date,
  Ship Mode text,
  Customer ID text,
  Region text,
  Product ID text,
  Sales real,
  Quantity integer,
  Discount real,
  Profit real
);
-- foreign keys: central_superstore.Product ID -> product.Product ID; central_superstore.Region -> product.Region; central_superstore.Customer ID -> people.Customer ID; central_superstore.Region -> people.Region; east_superstore.Product ID -> product.Product ID; east_superstore.Region -> product.Region; east_superstore.Customer ID -> people.Customer ID; east_superstore.Region -> people.Region; south_superstore.Product ID -> product.Product ID; south_superstore.Region -> product.Region; south_superstore.Customer ID -> people.Customer ID; south_superstore.Region -> people.Region; west_superstore.Product ID -> product.Product ID; west_superstore.Region -> product.Region; west_superstore.Customer ID -> people.Customer ID; west_superstore.Region -> people.Region

Question: How many orders were made by Corey Roper in 2015?

assistant: SELECT COUNT(T2.`Customer ID`) FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` WHERE T1.`Customer Name` = 'Corey Roper' AND STRFTIME('%Y', T2.`Ship Date`) = '2015'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE "workshop" (
"Workshop_ID" int,
"Date" text,
"Venue" text,
"Name" text,
PRIMARY KEY ("Workshop_ID")
);

CREATE TABLE "submission" (
"Submission_ID" int,
"Scores" real,
"Author" text,
"College" text,
PRIMARY KEY ("Submission_ID")
);

Question: Which college has the most authors with submissions?

assistant: SELECT College FROM submission GROUP BY College ORDER BY COUNT(*) DESC LIMIT 1
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE country (
  id integer PRIMARY KEY,
  country_name text
);
CREATE TABLE ranking_system (
  id integer PRIMARY KEY,
  system_name text
);
CREATE TABLE ranking_criteria (
  id integer PRIMARY KEY,
  ranking_system_id integer,
  criteria_name text
);
CREATE TABLE university (
  id integer PRIMARY KEY,
  country_id integer,
  university_name text
);
CREATE TABLE university_ranking_year (
  university_id integer,
  ranking_criteria_id integer,
  year integer,
  score integer
);
CREATE TABLE university_year (
  university_id integer,
  year integer,
  num_students integer,
  student_staff_ratio real,
  pct_international_students integer,
  pct_female_students integer
);
-- foreign keys: ranking_criteria.ranking_system_id -> ranking_system.id; university.country_id -> country.id; university_ranking_year.university_id -> university.id; university_ranking_year.ranking_criteria_id -> ranking_criteria.id; university_year.university_id -> university.id

Hint: in 2011 refers to year 2011; in teaching refers to  criteria_name = 'Teaching'; score in teaching of over 90 refers to score > 90; in the United States of America refers to country_name = 'United States of America'; percentage refers to DIVIDE(COUNT(country_name = 'United States of America'), COUNT(id))

Question: Among the universities with a score in teaching of over 90 in 2011, what is the percentage of those in the United States of America?

assistant: SELECT CAST(SUM(CASE WHEN T4.country_name = 'United States of America' THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(*) AS per FROM ranking_criteria AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.ranking_criteria_id INNER JOIN university AS T3 ON T3.id = T2.university_id INNER JOIN country AS T4 ON T4.id = T3.country_id WHERE T1.criteria_name = 'Teaching' AND T2.year = 2011 AND T2.score > 90
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE "race" (
"Race_ID" int,
"Name" text,
"Class" text,
"Date" text,
"Track_ID" text,
PRIMARY KEY ("Race_ID"),
FOREIGN KEY ("Track_ID") REFERENCES "track"("Track_ID")
);

CREATE TABLE "track" (
"Track_ID" int,
"Name" text,
"Location" text,
"Seating" real,
"Year_Opened" real,
PRIMARY KEY ("Track_ID")
);

Question: Show the name and location of track with 1 race.

assistant: SELECT T2.name , T2.location FROM race AS T1 JOIN track AS T2 ON T1.track_id = T2.track_id GROUP BY T1.track_id HAVING count(*) = 1
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE film_text (
  film_id integer PRIMARY KEY,
  title text,
  description text
);
CREATE TABLE actor (
  actor_id integer PRIMARY KEY,
  first_name text,
  last_name text,
  last_update datetime
);
CREATE TABLE address (
  address_id integer PRIMARY KEY,
  address text,
  address2 text,
  district text,
  city_id integer,
  postal_code text,
  phone text,
  last_update datetime
);
CREATE TABLE category (
  category_id integer PRIMARY KEY,
  name text,
  last_update datetime
);
CREATE TABLE city (
  city_id integer PRIMARY KEY,
  city text,
  country_id integer,
  last_update datetime
);
CREATE TABLE country (
  country_id integer PRIMARY KEY,
  country text,
  last_update datetime
);
CREATE TABLE customer (
  customer_id integer PRIMARY KEY,
  store_id integer,
  first_name text,
  last_name text,
  email text,
  address_id integer,
  active integer,
  create_date datetime,
  last_update datetime
);
CREATE TABLE film (
  film_id integer PRIMARY KEY,
  title text,
  description text,
  release_year text,
  language_id integer,
  original_language_id integer,
  rental_duration integer,
  rental_rate real,
  length integer,
  replacement_cost real,
  rating text,
  special_features text,
  last_update datetime
);
CREATE TABLE film_actor (
  actor_id integer PRIMARY KEY,
  film_id integer PRIMARY KEY,
  last_update datetime
);
CREATE TABLE film_category (
  film_id integer PRIMARY KEY,
  category_id integer PRIMARY KEY,
  last_update datetime
);
CREATE TABLE inventory (
  inventory_id integer PRIMARY KEY,
  film_id integer,
  store_id integer,
  last_update datetime
);
CREATE TABLE language (
  language_id integer PRIMARY KEY,
  name text,
  last_update datetime
);
CREATE TABLE payment (
  payment_id integer PRIMARY KEY,
  customer_id integer,
  staff_id integer,
  rental_id integer,
  amount real,
  payment_date datetime,
  last_update datetime
);
CREATE TABLE rental (
  rental_id integer PRIMARY KEY,
  rental_date datetime,
  inventory_id integer,
  customer_id integer,
  return_date datetime,
  staff_id integer,
  last_update datetime
);
CREATE TABLE staff (
  staff_id integer PRIMARY KEY,
  first_name text,
  last_name text,
  address_id integer,
  picture blob,
  email text,
  store_id integer,
  active integer,
  username text,
  password text,
  last_update datetime
);
CREATE TABLE store (
  store_id integer PRIMARY KEY,
  manager_staff_id integer,
  address_id integer,
  last_update datetime
);

Hint: "Documentary" is the name of category; number of film refers to Count(film_id)

Question: Give the number of documentary films.

assistant: SELECT COUNT(T1.film_id) FROM film_category AS T1 INNER JOIN category AS T2 ON T1.category_id = T2.category_id WHERE T2.name = 'Documentary'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE langs (
  lid integer PRIMARY KEY,
  lang text,
  locale text,
  pages integer,
  words integer
);
CREATE TABLE pages (
  pid integer PRIMARY KEY,
  lid integer,
  page integer,
  revision integer,
  title text,
  words integer
);
CREATE TABLE words (
  wid integer PRIMARY KEY,
  word text,
  occurrences integer
);
CREATE TABLE langs_words (
  lid integer PRIMARY KEY,
  wid integer PRIMARY KEY,
  occurrences integer
);
CREATE TABLE pages_words (
  pid integer PRIMARY KEY,
  wid integer PRIMARY KEY,
  occurrences integer
);
CREATE TABLE biwords (
  lid integer PRIMARY KEY,
  w1st integer PRIMARY KEY,
  w2nd integer PRIMARY KEY,
  occurrences integer
);
-- foreign keys: pages.lid -> langs.lid; langs_words.wid -> words.wid; langs_words.lid -> langs.lid; pages_words.wid -> words.wid; pages_words.pid -> pages.pid; biwords.w2nd -> words.wid; biwords.w1st -> words.wid; biwords.lid -> langs.lid

Hint: most occurrences refers to max(occurrences)

Question: Which word has the most occurrences within the same page of wikipedia about Catalan language?

assistant: SELECT T1.word FROM words AS T1 INNER JOIN pages_words AS T2 ON T1.wid = T2.wid WHERE T2.occurrences = ( SELECT MAX(occurrences) FROM pages_words )
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE country (
  id integer PRIMARY KEY,
  country_name text
);
CREATE TABLE ranking_system (
  id integer PRIMARY KEY,
  system_name text
);
CREATE TABLE ranking_criteria (
  id integer PRIMARY KEY,
  ranking_system_id integer,
  criteria_name text
);
CREATE TABLE university (
  id integer PRIMARY KEY,
  country_id integer,
  university_name text
);
CREATE TABLE university_ranking_year (
  university_id integer,
  ranking_criteria_id integer,
  year integer,
  score integer
);
CREATE TABLE university_year (
  university_id integer,
  year integer,
  num_students integer,
  student_staff_ratio real,
  pct_international_students integer,
  pct_female_students integer
);
-- foreign keys: ranking_criteria.ranking_system_id -> ranking_system.id; university.country_id -> country.id; university_ranking_year.university_id -> university.id; university_ranking_year.ranking_criteria_id -> ranking_criteria.id; university_year.university_id -> university.id

Hint: highest number of female students refers to MAX(SUBTRACT(num_students, DIVIDE(MULTIPLY(num_students, pct_female_students), 100))); name of university refers to university_name

Question: Provide the name of the university with the highest number of male students.

assistant: SELECT T2.university_name FROM university_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id ORDER BY T1.num_students * T1.pct_female_students / 100 - T1.num_students DESC LIMIT 1
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;



CREATE TABLE "film" (
"Film_ID" int,
"Title" text,
"Studio" text,
"Director" text,
"Gross_in_dollar" int,
PRIMARY KEY ("Film_ID")
);

Question: List the names of studios that have at least two films.

assistant: SELECT Studio FROM film GROUP BY Studio HAVING COUNT(*) >= 2
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE Episode (
  episode_id text PRIMARY KEY,
  season integer,
  episode integer,
  number_in_series integer,
  title text,
  summary text,
  air_date text,
  episode_image text,
  rating real,
  votes integer
);
CREATE TABLE Person (
  name text PRIMARY KEY,
  birthdate text,
  birth_name text,
  birth_place text,
  birth_region text,
  birth_country text,
  height_meters real,
  nickname text
);
CREATE TABLE Award (
  award_id integer PRIMARY KEY,
  organization text,
  year integer,
  award_category text,
  award text,
  person text,
  role text,
  episode_id text,
  season text,
  song text,
  result text
);
CREATE TABLE Character_Award (
  award_id integer,
  character text
);
CREATE TABLE Credit (
  episode_id text,
  category text,
  person text,
  role text,
  credited text
);
CREATE TABLE Keyword (
  episode_id text PRIMARY KEY,
  keyword text PRIMARY KEY
);
CREATE TABLE Vote (
  episode_id text,
  stars integer,
  votes integer,
  percent real
);
-- foreign keys: Award.episode_id -> Episode.episode_id; Award.person -> Person.name; Character_Award.award_id -> Award.award_id; Credit.person -> Person.name; Credit.episode_id -> Episode.episode_id; Keyword.episode_id -> Episode.episode_id; Vote.episode_id -> Episode.episode_id

Hint: star score of 10 refers to stars = 10

Question: Which episode id did award Outstanding Animated Program (For Programming Less Than One Hour) with an episode star score of 10?

assistant: SELECT DISTINCT T1.episode_id FROM Award AS T1 INNER JOIN Vote AS T2 ON T2.episode_id = T1.episode_id WHERE T1.award = 'Outstanding Animated Program (For Programming Less Than One Hour)' AND T2.stars = 10;