ajayk007/querysmith-spider-bird huggingface dataset:
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE Attributes (
  attribute_id integer PRIMARY KEY,
  attribute_name text
);
CREATE TABLE Categories (
  category_id integer PRIMARY KEY,
  category_name text
);
CREATE TABLE Compliments (
  compliment_id integer PRIMARY KEY,
  compliment_type text
);
CREATE TABLE Days (
  day_id integer PRIMARY KEY,
  day_of_week text
);
CREATE TABLE Years (
  year_id integer PRIMARY KEY,
  actual_year integer
);
CREATE TABLE Business_Attributes (
  attribute_id integer PRIMARY KEY,
  business_id integer PRIMARY KEY,
  attribute_value text
);
CREATE TABLE Business_Categories (
  business_id integer PRIMARY KEY,
  category_id integer PRIMARY KEY
);
CREATE TABLE Business_Hours (
  business_id integer PRIMARY KEY,
  day_id integer PRIMARY KEY,
  opening_time text,
  closing_time text
);
CREATE TABLE Checkins (
  business_id integer PRIMARY KEY,
  day_id integer PRIMARY KEY,
  label_time_0 text,
  label_time_1 text,
  label_time_2 text,
  label_time_3 text,
  label_time_4 text,
  label_time_5 text,
  label_time_6 text,
  label_time_7 text,
  label_time_8 text,
  label_time_9 text,
  label_time_10 text,
  label_time_11 text,
  label_time_12 text,
  label_time_13 text,
  label_time_14 text,
  label_time_15 text,
  label_time_16 text,
  label_time_17 text,
  label_time_18 text,
  label_time_19 text,
  label_time_20 text,
  label_time_21 text,
  label_time_22 text,
  label_time_23 text
);
CREATE TABLE Elite (
  user_id integer PRIMARY KEY,
  year_id integer PRIMARY KEY
);
CREATE TABLE Reviews (
  business_id integer PRIMARY KEY,
  user_id integer PRIMARY KEY,
  review_stars integer,
  review_votes_funny text,
  review_votes_useful text,
  review_votes_cool text,
  review_length text
);
CREATE TABLE Tips (
  business_id integer PRIMARY KEY,
  user_id integer PRIMARY KEY,
  likes integer,
  tip_length text
);
CREATE TABLE Users_Compliments (
  compliment_id integer PRIMARY KEY,
  user_id integer PRIMARY KEY,
  number_of_compliments text
);
CREATE TABLE Business (
  business_id integer PRIMARY KEY,
  active text,
  city text,
  state text,
  stars real,
  review_count text
);
CREATE TABLE Users (
  user_id integer PRIMARY KEY,
  user_yelping_since_year integer,
  user_average_stars text,
  user_votes_funny text,
  user_votes_useful text,
  user_votes_cool text,
  user_review_count text,
  user_fans text
);

Hint: category of businesses refers to category_name; stars ratings are 5 refers to stars = 5

Question: List down the category of businesses whose stars ratings are 5.

assistant: SELECT DISTINCT T3.category_name FROM Business AS T1 INNER JOIN Business_Categories AS T2 ON T1.business_id = T2.business_id INNER JOIN Categories AS T3 ON T2.category_id = T3.category_id WHERE T1.stars = 5
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE "storm" (
"Storm_ID" int,
"Name" text,
"Dates_active" text,
"Max_speed" int,
"Damage_millions_USD" real,
"Number_Deaths" int,
PRIMARY KEY ("Storm_ID")
);

Question: What are the names of the storms that affected Denmark?

assistant: SELECT T3.name FROM affected_region AS T1 JOIN region AS T2 ON T1.region_id = T2.region_id JOIN storm AS T3 ON T1.storm_id = T3.storm_id WHERE T2.region_name = 'Denmark'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE customers (
  CustomerID integer PRIMARY KEY,
  First text,
  Last text,
  StreetAddress text,
  City text,
  State text,
  ZipCode integer,
  Email text,
  PhoneNumber text,
  FirstPurchaseDate date,
  SubscribedToEmailList text,
  Gender text
);
CREATE TABLE geolocation (
  LocationID integer PRIMARY KEY,
  Latitude real,
  Longitude real
);
CREATE TABLE location (
  LocationID integer PRIMARY KEY,
  LocationName text,
  StreetAddress text,
  City text,
  State text,
  ZipCode integer
);
CREATE TABLE rootbeerbrand (
  BrandID integer PRIMARY KEY,
  BrandName text,
  FirstBrewedYear integer,
  BreweryName text,
  City text,
  State text,
  Country text,
  Description text,
  CaneSugar text,
  CornSyrup text,
  Honey text,
  ArtificialSweetener text,
  Caffeinated text,
  Alcoholic text,
  AvailableInCans text,
  AvailableInBottles text,
  AvailableInKegs text,
  Website text,
  FacebookPage text,
  Twitter text,
  WholesaleCost real,
  CurrentRetailPrice real
);
CREATE TABLE rootbeer (
  RootBeerID integer PRIMARY KEY,
  BrandID integer,
  ContainerType text,
  LocationID integer,
  PurchaseDate date
);
CREATE TABLE rootbeerreview (
  CustomerID integer PRIMARY KEY,
  BrandID integer PRIMARY KEY,
  StarRating integer,
  ReviewDate date,
  Review text
);
CREATE TABLE transaction (
  TransactionID integer PRIMARY KEY,
  CreditCardNumber integer,
  CustomerID integer,
  TransactionDate date,
  CreditCardType text,
  LocationID integer,
  RootBeerID integer,
  PurchasePrice real
);
-- foreign keys: geolocation.LocationID -> location.LocationID; location.LocationID -> geolocation.LocationID; rootbeer.BrandID -> rootbeerbrand.BrandID; rootbeer.LocationID -> location.LocationID; rootbeer.LocationID -> geolocation.LocationID; rootbeerreview.BrandID -> rootbeerbrand.BrandID; rootbeerreview.CustomerID -> customers.CustomerID; transaction.RootBeerID -> rootbeer.RootBeerID; transaction.LocationID -> location.LocationID; transaction.CustomerID -> customers.CustomerID

Hint: name of the location refers to LocationName; transaction no. refers to TransactionID; TransactionID = 100885;

Question: Provide the name of the location where transaction no.100885 happened.

assistant: SELECT T2.LocationName FROM `transaction` AS T1 INNER JOIN location AS T2 ON T1.LocationID = T2.LocationID WHERE T1.TransactionID = 100885
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE incidents (
  case_number text PRIMARY KEY,
  date date,
  location text,
  subject_statuses text,
  subject_weapon text,
  subjects text,
  subject_count integer,
  officers text
);
CREATE TABLE officers (
  case_number text,
  race text,
  gender text,
  last_name text,
  first_name text,
  full_name text
);
CREATE TABLE subjects (
  case_number text,
  race text,
  gender text,
  last_name text,
  first_name text,
  full_name text
);
-- foreign keys: officers.case_number -> incidents.case_number; subjects.case_number -> incidents.case_number

Question: For case number '134472-2015', list the last name of the officers involved and state the subject statuses.

assistant: SELECT T2.last_name, T1.subject_statuses FROM incidents AS T1 INNER JOIN officers AS T2 ON T1.case_number = T2.case_number WHERE T1.case_number = '134472-2015'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;
CREATE TABLE `Ref_Characteristic_Types` (
`characteristic_type_code` VARCHAR(15) PRIMARY KEY,
`characteristic_type_description` VARCHAR(80)
);
CREATE TABLE `Ref_Colors` (
`color_code` VARCHAR(15) PRIMARY KEY,
`color_description` VARCHAR(80)
);
CREATE TABLE `Ref_Product_Categories` (
`product_category_code` VARCHAR(15) PRIMARY KEY,
`product_category_description` VARCHAR(80),
`unit_of_measure` VARCHAR(20)
);

Question: List all the product names with the color description "white".

assistant: SELECT t1.product_name FROM products AS t1 JOIN ref_colors AS t2 ON t1.color_code = t2.color_code WHERE t2.color_description = "white"
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE Method (
  Id integer PRIMARY KEY,
  Name text,
  FullComment text,
  Summary text,
  ApiCalls text,
  CommentIsXml integer,
  SampledAt integer,
  SolutionId integer,
  Lang text,
  NameTokenized text
);
CREATE TABLE MethodParameter (
  Id integer PRIMARY KEY,
  MethodId text,
  Type text,
  Name text
);
CREATE TABLE Repo (
  Id integer PRIMARY KEY,
  Url text,
  Stars integer,
  Forks integer,
  Watchers integer,
  ProcessedTime integer
);
CREATE TABLE Solution (
  Id integer PRIMARY KEY,
  RepoId integer,
  Path text,
  ProcessedTime integer,
  WasCompiled integer
);

Hint: solution No. refers to Solution.Id; percentage = DIVIDE(MULTIPLY(SUBTRACT(SUM(Solution.Id = 53546), SUM(Solution.Id = 1502)), 100)), SUM(Solution.Id = 1502);

Question: How many percent more of the Forks for the repository of solution No.53546 than No.1502?

assistant: SELECT CAST(SUM(CASE WHEN T2.Id = 53546 THEN T1.Forks ELSE 0 END) - SUM(CASE WHEN T2.Id = 1502 THEN T1.Forks ELSE 0 END) AS REAL) * 100 / SUM(CASE WHEN T2.Id = 1502 THEN T1.Forks ELSE 0 END) FROM Repo AS T1 INNER JOIN Solution AS T2 ON T1.Id = T2.RepoId
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
-- phpMyAdmin SQL Dump
-- version 4.0.10.7
-- http://www.phpmyadmin.net
--
-- Host: localhost
-- Generation Time: Mar 20, 2015 at 01:43 AM
-- Server version: 5.5.34-cll-lve
-- PHP Version: 5.4.23



/*!40101 SET @OLD_CHARACTER_SET_CLIENT=@@CHARACTER_SET_CLIENT */;
/*!40101 SET @OLD_CHARACTER_SET_RESULTS=@@CHARACTER_SET_RESULTS */;
/*!40101 SET @OLD_COLLATION_CONNECTION=@@COLLATION_CONNECTION */;
/*!40101 SET NAMES utf8 */;
CREATE TABLE IF NOT EXISTS `regions` (
  `REGION_ID` decimal(5,0) NOT NULL,
  `REGION_NAME` varchar(25) DEFAULT NULL,
  PRIMARY KEY (`REGION_ID`)
);

--
-- Dumping data for table `regions`
--

Question: display job ID for those jobs that were done by two or more for more than 300 days.

assistant: SELECT job_id FROM job_history WHERE end_date - start_date > 300 GROUP BY job_id HAVING COUNT(*) >= 2
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;
CREATE TABLE `Addresses` (
`address_id` INTEGER PRIMARY KEY,
`line_1_number_building` VARCHAR(80),
`town_city` VARCHAR(50),
`zip_postcode` VARCHAR(20),
`state_province_county` VARCHAR(50),
`country` VARCHAR(50)
);

Question: What are the different types of forms?

assistant: SELECT DISTINCT form_type_code FROM forms
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE employee (
  employee_id integer PRIMARY KEY,
  first_name text,
  last_name text,
  address text,
  city text,
  state text,
  zip integer,
  phone text,
  title text,
  salary integer,
  supervisor integer
);
CREATE TABLE establishment (
  license_no integer PRIMARY KEY,
  dba_name text,
  aka_name text,
  facility_type text,
  risk_level integer,
  address text,
  city text,
  state text,
  zip integer,
  latitude real,
  longitude real,
  ward integer
);
CREATE TABLE inspection (
  inspection_id integer PRIMARY KEY,
  inspection_date date,
  inspection_type text,
  results text,
  employee_id integer,
  license_no integer,
  followup_to integer
);
CREATE TABLE inspection_point (
  point_id integer PRIMARY KEY,
  Description text,
  category text,
  code text,
  fine integer,
  point_level text
);
CREATE TABLE violation (
  inspection_id integer PRIMARY KEY,
  point_id integer PRIMARY KEY,
  fine integer,
  inspector_comment text
);
-- foreign keys: employee.supervisor -> employee.employee_id; inspection.followup_to -> inspection.inspection_id; inspection.license_no -> establishment.license_no; inspection.employee_id -> employee.employee_id; violation.point_id -> inspection_point.point_id; violation.inspection_id -> inspection.inspection_id

Hint: under the display of inspection report summary category refers to category = 'Display of Inspection Report Summary'

Question: How many inspections were done under the display of inspection report summary category?

assistant: SELECT COUNT(T2.inspection_id) FROM inspection_point AS T1 INNER JOIN violation AS T2 ON T1.point_id = T2.point_id WHERE T1.category = 'Display of Inspection Report Summary'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;
CREATE TABLE `Ref_Characteristic_Types` (
`characteristic_type_code` VARCHAR(15) PRIMARY KEY,
`characteristic_type_description` VARCHAR(80)
);
CREATE TABLE `Ref_Colors` (
`color_code` VARCHAR(15) PRIMARY KEY,
`color_description` VARCHAR(80)
);
CREATE TABLE `Ref_Product_Categories` (
`product_category_code` VARCHAR(15) PRIMARY KEY,
`product_category_description` VARCHAR(80),
`unit_of_measure` VARCHAR(20)
);

Question: What are the names of products with category "Spices"?

assistant: SELECT product_name FROM products WHERE product_category_code = "Spices"
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
create table Allergy_Type (
       Allergy 		  VARCHAR(20) PRIMARY KEY,
       AllergyType 	  VARCHAR(20)
);

create table Has_Allergy (
       StuID 		 INTEGER,
       Allergy 		 VARCHAR(20),
       FOREIGN KEY(StuID) REFERENCES Student(StuID),
       FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
);

create table Student (
        StuID        INTEGER PRIMARY KEY,
        LName        VARCHAR(12),
        Fname        VARCHAR(12),
        Age      INTEGER,
        Sex      VARCHAR(1),
        Major        INTEGER,
        Advisor      INTEGER,
        city_code    VARCHAR(3)
 );

Question: What are the first name and gender of the students who have allergy to milk but can put up with cats?

assistant: SELECT fname , sex FROM Student WHERE StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy = "Milk" EXCEPT SELECT StuID FROM Has_allergy WHERE Allergy = "Cat")
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE ATT_CLASSES (
  ATT_CLASS_ID integer PRIMARY KEY,
  ATT_CLASS text
);
CREATE TABLE OBJ_CLASSES (
  OBJ_CLASS_ID integer PRIMARY KEY,
  OBJ_CLASS text
);
CREATE TABLE IMG_OBJ (
  IMG_ID integer PRIMARY KEY,
  OBJ_SAMPLE_ID integer PRIMARY KEY,
  OBJ_CLASS_ID integer,
  X integer,
  Y integer,
  W integer,
  H integer
);
CREATE TABLE IMG_OBJ_ATT (
  IMG_ID integer PRIMARY KEY,
  ATT_CLASS_ID integer PRIMARY KEY,
  OBJ_SAMPLE_ID integer PRIMARY KEY
);
CREATE TABLE PRED_CLASSES (
  PRED_CLASS_ID integer PRIMARY KEY,
  PRED_CLASS text
);
CREATE TABLE IMG_REL (
  IMG_ID integer PRIMARY KEY,
  PRED_CLASS_ID integer PRIMARY KEY,
  OBJ1_SAMPLE_ID integer PRIMARY KEY,
  OBJ2_SAMPLE_ID integer PRIMARY KEY
);
-- foreign keys: IMG_OBJ.OBJ_CLASS_ID -> OBJ_CLASSES.OBJ_CLASS_ID; IMG_OBJ_ATT.IMG_ID -> IMG_OBJ.IMG_ID; IMG_OBJ_ATT.OBJ_SAMPLE_ID -> IMG_OBJ.OBJ_SAMPLE_ID; IMG_OBJ_ATT.ATT_CLASS_ID -> ATT_CLASSES.ATT_CLASS_ID; IMG_REL.IMG_ID -> IMG_OBJ.IMG_ID; IMG_REL.OBJ2_SAMPLE_ID -> IMG_OBJ.OBJ_SAMPLE_ID; IMG_REL.IMG_ID -> IMG_OBJ.IMG_ID; IMG_REL.OBJ1_SAMPLE_ID -> IMG_OBJ.OBJ_SAMPLE_ID; IMG_REL.PRED_CLASS_ID -> PRED_CLASSES.PRED_CLASS_ID

Hint: blue' attribute classes on image ID 2355735 refer to ATT_CLASS = 'blue' where IMG_ID = 2355735;

Question: How many 'blue' attribute classes are there on image ID 2355735?

assistant: SELECT COUNT(T1.ATT_CLASS) FROM ATT_CLASSES AS T1 INNER JOIN IMG_OBJ_ATT AS T2 ON T1.ATT_CLASS_ID = T2.ATT_CLASS_ID WHERE T2.IMG_ID = 2355735 AND T1.ATT_CLASS = 'blue'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE authors (
  au_id text PRIMARY KEY,
  au_lname text,
  au_fname text,
  phone text,
  address text,
  city text,
  state text,
  zip text,
  contract text
);
CREATE TABLE jobs (
  job_id integer PRIMARY KEY,
  job_desc text,
  min_lvl integer,
  max_lvl integer
);
CREATE TABLE publishers (
  pub_id text PRIMARY KEY,
  pub_name text,
  city text,
  state text,
  country text
);
CREATE TABLE employee (
  emp_id text PRIMARY KEY,
  fname text,
  minit text,
  lname text,
  job_id integer,
  job_lvl integer,
  pub_id text,
  hire_date datetime
);
CREATE TABLE pub_info (
  pub_id text PRIMARY KEY,
  logo blob,
  pr_info text
);
CREATE TABLE stores (
  stor_id text PRIMARY KEY,
  stor_name text,
  stor_address text,
  city text,
  state text,
  zip text
);
CREATE TABLE discounts (
  discounttype text,
  stor_id text,
  lowqty integer,
  highqty integer,
  discount real
);
CREATE TABLE titles (
  title_id text PRIMARY KEY,
  title text,
  type text,
  pub_id text,
  price real,
  advance real,
  royalty integer,
  ytd_sales integer,
  notes text,
  pubdate datetime
);
CREATE TABLE roysched (
  title_id text,
  lorange integer,
  hirange integer,
  royalty integer
);
CREATE TABLE sales (
  stor_id text PRIMARY KEY,
  ord_num text PRIMARY KEY,
  ord_date datetime,
  qty integer,
  payterms text,
  title_id text PRIMARY KEY
);
CREATE TABLE titleauthor (
  au_id text PRIMARY KEY,
  title_id text PRIMARY KEY,
  au_ord integer,
  royaltyper integer
);
-- foreign keys: employee.pub_id -> publishers.pub_id; employee.job_id -> jobs.job_id; pub_info.pub_id -> publishers.pub_id; discounts.stor_id -> stores.stor_id; titles.pub_id -> publishers.pub_id; roysched.title_id -> titles.title_id; sales.title_id -> titles.title_id; sales.stor_id -> stores.stor_id; titleauthor.title_id -> titles.title_id; titleauthor.au_id -> authors.au_id

Hint: qty is abbreviation for quantity; sold more than average refers to qty > AVG(qty); california refers to state = 'CA"

Question: Name the top five titles that sold more than average and list them in descending order of the number of sales in California stores?

assistant: SELECT T1.title FROM titles AS T1 INNER JOIN sales AS T2 ON T1.title_id = T2.title_id INNER JOIN publishers AS T3 ON T1.pub_id = T3.pub_id WHERE T2.qty > ( SELECT CAST(SUM(qty) AS REAL) / COUNT(title_id) FROM sales ) AND T3.state = 'CA' ORDER BY T2.qty DESC LIMIT 5
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE Customers (
Customer_ID INTEGER NOT NULL,
Customer_name VARCHAR(40),
PRIMARY KEY (Customer_ID)
);

Question: Which policy type has the most records in the database?

assistant: SELECT policy_type_code FROM available_policies GROUP BY policy_type_code ORDER BY count(*) DESC LIMIT 1
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE Author (
  Id integer PRIMARY KEY,
  Name text,
  Affiliation text
);
CREATE TABLE Conference (
  Id integer PRIMARY KEY,
  ShortName text,
  FullName text,
  HomePage text
);
CREATE TABLE Journal (
  Id integer PRIMARY KEY,
  ShortName text,
  FullName text,
  HomePage text
);
CREATE TABLE Paper (
  Id integer PRIMARY KEY,
  Title text,
  Year integer,
  ConferenceId integer,
  JournalId integer,
  Keyword text
);
CREATE TABLE PaperAuthor (
  PaperId integer,
  AuthorId integer,
  Name text,
  Affiliation text
);
-- foreign keys: Paper.JournalId -> Journal.Id; Paper.ConferenceId -> Conference.Id; PaperAuthor.AuthorId -> Author.Id; PaperAuthor.PaperId -> Paper.Id

Hint: word computing refers to FullName LIKE '%computing%'

Question: How many journals have a word "computing" in its full name?

assistant: SELECT COUNT(Id) FROM Journal WHERE FullName LIKE '%computing%'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
create table Student (
         StuID        INTEGER PRIMARY KEY,
         LName        VARCHAR(12),
         Fname        VARCHAR(12),
         Age      INTEGER,
         Sex      VARCHAR(1),
         Major        INTEGER,
         Advisor      INTEGER,
         city_code    VARCHAR(3)
  );


create table Club (
       ClubID           INTEGER PRIMARY KEY,
       ClubName         VARCHAR(40),
       ClubDesc         VARCHAR(1024),
       ClubLocation VARCHAR(40)
);

create table Member_of_club (
       StuID            INTEGER,
       ClubID           INTEGER,
       Position     VARCHAR(40),
       FOREIGN KEY(StuID) REFERENCES Student(StuID),
       FOREIGN KEY(ClubID) REFERENCES Club(ClubID)
);

Question: Count the number of members in club "Bootup Baltimore" whose age is below 18.

assistant: SELECT count(*) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore" AND t3.age < 18
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;
CREATE TABLE `Addresses` (
`address_id` INTEGER PRIMARY KEY,
`address_details` VARCHAR(255)
);

Question: What is the code of the product type with an average price higher than the average price of all products?

assistant: SELECT product_type_code FROM products GROUP BY product_type_code HAVING avg(product_price) > (SELECT avg(product_price) FROM products)