ajayk007/querysmith-spider-bird huggingface dataset:
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE Categories (
  CategoryID integer PRIMARY KEY,
  CategoryName text,
  Description text
);
CREATE TABLE Customers (
  CustomerID integer PRIMARY KEY,
  CustomerName text,
  ContactName text,
  Address text,
  City text,
  PostalCode text,
  Country text
);
CREATE TABLE Employees (
  EmployeeID integer PRIMARY KEY,
  LastName text,
  FirstName text,
  BirthDate date,
  Photo text,
  Notes text
);
CREATE TABLE Shippers (
  ShipperID integer PRIMARY KEY,
  ShipperName text,
  Phone text
);
CREATE TABLE Suppliers (
  SupplierID integer PRIMARY KEY,
  SupplierName text,
  ContactName text,
  Address text,
  City text,
  PostalCode text,
  Country text,
  Phone text
);
CREATE TABLE Products (
  ProductID integer PRIMARY KEY,
  ProductName text,
  SupplierID integer,
  CategoryID integer,
  Unit text,
  Price real
);
CREATE TABLE Orders (
  OrderID integer PRIMARY KEY,
  CustomerID integer,
  EmployeeID integer,
  OrderDate datetime,
  ShipperID integer
);
CREATE TABLE OrderDetails (
  OrderDetailID integer PRIMARY KEY,
  OrderID integer,
  ProductID integer,
  Quantity integer
);
-- foreign keys: Products.SupplierID -> Suppliers.SupplierID; Products.CategoryID -> Categories.CategoryID; Orders.ShipperID -> Shippers.ShipperID; Orders.CustomerID -> Customers.CustomerID; Orders.EmployeeID -> Employees.EmployeeID; OrderDetails.ProductID -> Products.ProductID; OrderDetails.OrderID -> Orders.OrderID

Hint: female employees refers to TitleOfCourtesy = 'Mrs.' or TitleOfCourtesy = 'Ms.'; in charge of 3 or more territories refers to TerritoryID > = 3;

Question: How many female employees are in charge of 3 or more territories?

assistant: SELECT COUNT(EID) FROM ( SELECT T1.EmployeeID AS EID FROM Employees AS T1 INNER JOIN EmployeeTerritories AS T2 ON T1.EmployeeID = T2.EmployeeID WHERE T1.TitleOfCourtesy IN ('Ms.' OR 'Mrs.') GROUP BY T1.EmployeeID HAVING COUNT(T2.TerritoryID) >= 3 ) T1
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE "artist" (
    "Artist_ID" int,
    "Artist" text,
    "Age" int,
    "Famous_Title" text,
    "Famous_Release_date" text,
    PRIMARY KEY ("Artist_ID")
);



CREATE TABLE "volume" (
    "Volume_ID" int,
    "Volume_Issue" text,
    "Issue_Date" text,
    "Weeks_on_Top" real,
    "Song" text,
    "Artist_ID" int,
    PRIMARY KEY ("Volume_ID"),
    FOREIGN KEY (`Artist_ID`) REFERENCES `artist`(`Artist_ID`)
);

Question: What are the dates of ceremony at music festivals corresponding to volumes that lasted more than 2 weeks on top?

assistant: SELECT T1.Date_of_ceremony FROM music_festival AS T1 JOIN volume AS T2 ON T1.Volume = T2.Volume_ID WHERE T2.Weeks_on_Top > 2
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE Attributes (
  attribute_id integer PRIMARY KEY,
  attribute_name text
);
CREATE TABLE Categories (
  category_id integer PRIMARY KEY,
  category_name text
);
CREATE TABLE Compliments (
  compliment_id integer PRIMARY KEY,
  compliment_type text
);
CREATE TABLE Days (
  day_id integer PRIMARY KEY,
  day_of_week text
);
CREATE TABLE Years (
  year_id integer PRIMARY KEY,
  actual_year integer
);
CREATE TABLE Business_Attributes (
  attribute_id integer PRIMARY KEY,
  business_id integer PRIMARY KEY,
  attribute_value text
);
CREATE TABLE Business_Categories (
  business_id integer PRIMARY KEY,
  category_id integer PRIMARY KEY
);
CREATE TABLE Business_Hours (
  business_id integer PRIMARY KEY,
  day_id integer PRIMARY KEY,
  opening_time text,
  closing_time text
);
CREATE TABLE Checkins (
  business_id integer PRIMARY KEY,
  day_id integer PRIMARY KEY,
  label_time_0 text,
  label_time_1 text,
  label_time_2 text,
  label_time_3 text,
  label_time_4 text,
  label_time_5 text,
  label_time_6 text,
  label_time_7 text,
  label_time_8 text,
  label_time_9 text,
  label_time_10 text,
  label_time_11 text,
  label_time_12 text,
  label_time_13 text,
  label_time_14 text,
  label_time_15 text,
  label_time_16 text,
  label_time_17 text,
  label_time_18 text,
  label_time_19 text,
  label_time_20 text,
  label_time_21 text,
  label_time_22 text,
  label_time_23 text
);
CREATE TABLE Elite (
  user_id integer PRIMARY KEY,
  year_id integer PRIMARY KEY
);
CREATE TABLE Reviews (
  business_id integer PRIMARY KEY,
  user_id integer PRIMARY KEY,
  review_stars integer,
  review_votes_funny text,
  review_votes_useful text,
  review_votes_cool text,
  review_length text
);
CREATE TABLE Tips (
  business_id integer PRIMARY KEY,
  user_id integer PRIMARY KEY,
  likes integer,
  tip_length text
);
CREATE TABLE Users_Compliments (
  compliment_id integer PRIMARY KEY,
  user_id integer PRIMARY KEY,
  number_of_compliments text
);
CREATE TABLE Business (
  business_id integer PRIMARY KEY,
  active text,
  city text,
  state text,
  stars real,
  review_count text
);
CREATE TABLE Users (
  user_id integer PRIMARY KEY,
  user_yelping_since_year integer,
  user_average_stars text,
  user_votes_funny text,
  user_votes_useful text,
  user_votes_cool text,
  user_review_count text,
  user_fans text
);

Hint: medium length tip refers to tip_length = 'Medium';

Question: Which city is the business that got a "medium" length tip with "3" likes located in?

assistant: SELECT T1.city FROM Business AS T1 INNER JOIN Tips AS T2 ON T1.business_id = T2.business_id WHERE T2.tip_length = 'Medium' AND T2.likes = 3
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE state (
  StateCode text PRIMARY KEY,
  State text,
  Region text
);
CREATE TABLE callcenterlogs (
  Date received date,
  Complaint ID text PRIMARY KEY,
  rand client text,
  phonefinal text,
  vru+line text,
  call_id integer,
  priority integer,
  type text,
  outcome text,
  server text,
  ser_start text,
  ser_exit text,
  ser_time text
);
CREATE TABLE client (
  client_id text PRIMARY KEY,
  sex text,
  day integer,
  month integer,
  year integer,
  age integer,
  social text,
  first text,
  middle text,
  last text,
  phone text,
  email text,
  address_1 text,
  address_2 text,
  city text,
  state text,
  zipcode integer,
  district_id integer
);
CREATE TABLE district (
  district_id integer PRIMARY KEY,
  city text,
  state_abbrev text,
  division text
);
CREATE TABLE events (
  Date received date,
  Product text,
  Sub-product text,
  Issue text,
  Sub-issue text,
  Consumer complaint narrative text,
  Tags text,
  Consumer consent provided? text,
  Submitted via text,
  Date sent to company text,
  Company response to consumer text,
  Timely response? text,
  Consumer disputed? text,
  Complaint ID text PRIMARY KEY,
  Client_ID text PRIMARY KEY
);
CREATE TABLE reviews (
  Date date PRIMARY KEY,
  Stars integer,
  Reviews text,
  Product text,
  district_id integer
);
-- foreign keys: callcenterlogs.rand client -> client.client_id; client.district_id -> district.district_id; district.state_abbrev -> state.StateCode; events.Client_ID -> client.client_id; events.Complaint ID -> callcenterlogs.Complaint ID; reviews.district_id -> district.district_id

Hint: full name refers to first, middle, last; server time of 20 minutes and above refers to ser_time > '00:20:00'

Question: State the full name of clients with server time of 20 minutes and above.

assistant: SELECT T1.first, T1.middle, T1.last FROM client AS T1 INNER JOIN callcenterlogs AS T2 ON T1.client_id = T2.`rand client` WHERE strftime('%M', T2.ser_time) > '20'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE ATT_CLASSES (
  ATT_CLASS_ID integer PRIMARY KEY,
  ATT_CLASS text
);
CREATE TABLE OBJ_CLASSES (
  OBJ_CLASS_ID integer PRIMARY KEY,
  OBJ_CLASS text
);
CREATE TABLE IMG_OBJ (
  IMG_ID integer PRIMARY KEY,
  OBJ_SAMPLE_ID integer PRIMARY KEY,
  OBJ_CLASS_ID integer,
  X integer,
  Y integer,
  W integer,
  H integer
);
CREATE TABLE IMG_OBJ_ATT (
  IMG_ID integer PRIMARY KEY,
  ATT_CLASS_ID integer PRIMARY KEY,
  OBJ_SAMPLE_ID integer PRIMARY KEY
);
CREATE TABLE PRED_CLASSES (
  PRED_CLASS_ID integer PRIMARY KEY,
  PRED_CLASS text
);
CREATE TABLE IMG_REL (
  IMG_ID integer PRIMARY KEY,
  PRED_CLASS_ID integer PRIMARY KEY,
  OBJ1_SAMPLE_ID integer PRIMARY KEY,
  OBJ2_SAMPLE_ID integer PRIMARY KEY
);
-- foreign keys: IMG_OBJ.OBJ_CLASS_ID -> OBJ_CLASSES.OBJ_CLASS_ID; IMG_OBJ_ATT.IMG_ID -> IMG_OBJ.IMG_ID; IMG_OBJ_ATT.OBJ_SAMPLE_ID -> IMG_OBJ.OBJ_SAMPLE_ID; IMG_OBJ_ATT.ATT_CLASS_ID -> ATT_CLASSES.ATT_CLASS_ID; IMG_REL.IMG_ID -> IMG_OBJ.IMG_ID; IMG_REL.OBJ2_SAMPLE_ID -> IMG_OBJ.OBJ_SAMPLE_ID; IMG_REL.IMG_ID -> IMG_OBJ.IMG_ID; IMG_REL.OBJ1_SAMPLE_ID -> IMG_OBJ.OBJ_SAMPLE_ID; IMG_REL.PRED_CLASS_ID -> PRED_CLASSES.PRED_CLASS_ID

Hint: images refers to IMG_ID; have at least 5 "black" classes refers to count(ATT_CLASS_ID) where ATT_CLASS = 'black' > = 5

Question: How many images have at least 5 "black" classes?

assistant: SELECT COUNT(IMGID) FROM ( SELECT T1.IMG_ID AS IMGID FROM IMG_OBJ_att AS T1 INNER JOIN ATT_CLASSES AS T2 ON T1.ATT_CLASS_ID = T2.ATT_CLASS_ID WHERE T2.ATT_CLASS = 'black' GROUP BY T1.IMG_ID HAVING COUNT(T1.ATT_CLASS_ID) >= 5 ) T3
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE `Products` (
`product_id` INTEGER PRIMARY KEY,
`product_name` VARCHAR(20),
`product_price` DECIMAL(19,4),
`product_description` VARCHAR(255)
);

Question: Find the payment method that is used most frequently.

assistant: SELECT payment_method FROM Customers GROUP BY payment_method ORDER BY count(*) DESC LIMIT 1
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
--data definition

create table genre(
	g_name varchar2(20) not null,
	rating varchar2(10),
	most_popular_in varchar2(50),
	primary key(g_name)
);

create table artist(
	artist_name varchar2(50) not null,
	country varchar2(20),
	gender varchar2(20),
	preferred_genre varchar2(50),
	constraint a_name primary key(artist_name),
	foreign key(preferred_genre) references genre(g_name) ON DELETE CASCADE
);

create table files(
	f_id number(10) not null,
	artist_name varchar2(50),
	file_size varchar2(20),
	duration varchar2(20),
	formats varchar2(20),
	primary key(f_id),
	foreign key(artist_name) references artist(artist_name) ON DELETE CASCADE
);


create table song(
	song_name varchar2(50),
	artist_name varchar2(50),
	country varchar2(20),
	f_id number(10),
    	genre_is varchar2(20),
	rating number(10) check(rating>0 and rating<11),
	languages varchar2(20),
	releasedate Date, 
	resolution number(10) not null,
	constraint s_name primary key(song_name),
	foreign key(artist_name) references artist(artist_name) ON DELETE CASCADE,
	foreign key(f_id) references files(f_id) ON DELETE CASCADE,
	foreign key(genre_is) references genre(g_name) ON DELETE CASCADE
);


--insertion of attributes in the table

Question: List the name and country of origin for all singers who have produced songs with rating above 9.

assistant: SELECT DISTINCT T1.artist_name , T1.country FROM artist AS T1 JOIN song AS T2 ON T1.artist_name = T2.artist_name WHERE T2.rating > 9
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
create table Student (
         StuID        INTEGER PRIMARY KEY,
         LName        VARCHAR(12),
         Fname        VARCHAR(12),
         Age      INTEGER,
         Sex      VARCHAR(1),
         Major        INTEGER,
         Advisor      INTEGER,
         city_code    VARCHAR(3)
  );


create table Club (
       ClubID           INTEGER PRIMARY KEY,
       ClubName         VARCHAR(40),
       ClubDesc         VARCHAR(1024),
       ClubLocation VARCHAR(40)
);

create table Member_of_club (
       StuID            INTEGER,
       ClubID           INTEGER,
       Position     VARCHAR(40),
       FOREIGN KEY(StuID) REFERENCES Student(StuID),
       FOREIGN KEY(ClubID) REFERENCES Club(ClubID)
);

Question: What are the first names of all the students?

assistant: SELECT DISTINCT fname FROM student
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE actor (
  ActorID integer PRIMARY KEY,
  Name text,
  Date of Birth date,
  Birth City text,
  Birth Country text,
  Height (Inches) integer,
  Biography text,
  Gender text,
  Ethnicity text,
  NetWorth text
);
CREATE TABLE movie (
  MovieID integer PRIMARY KEY,
  Title text,
  MPAA Rating text,
  Budget integer,
  Gross integer,
  Release Date text,
  Genre text,
  Runtime integer,
  Rating real,
  Rating Count integer,
  Summary text
);
CREATE TABLE characters (
  MovieID integer PRIMARY KEY,
  ActorID integer PRIMARY KEY,
  Character Name text,
  creditOrder integer,
  pay text,
  screentime text
);
-- foreign keys: characters.MovieID -> movie.MovieID; characters.ActorID -> actor.ActorID

Hint: born in New York City refers to Birth City = 'New York City'; rating greater than 5 refers to Rating > 5

Question: Among the actors born in New York City, list the genre of their movie with a rating greater than 5.

assistant: SELECT T1.Genre FROM movie AS T1 INNER JOIN characters AS T2 ON T1.MovieID = T2.MovieID INNER JOIN actor AS T3 ON T3.ActorID = T2.ActorID WHERE T3.`Birth City` = 'New York City' AND T1.Rating > 5
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
create table Student (
        StuID        INTEGER PRIMARY KEY,
        LName        VARCHAR(12),
        Fname        VARCHAR(12),
        Age      INTEGER,
        Sex      VARCHAR(1),
        Major        INTEGER,
        Advisor      INTEGER,
        city_code    VARCHAR(3)
 );

create table Video_Games (
       GameID           INTEGER PRIMARY KEY,
       GName            VARCHAR(40),
       GType            VARCHAR(40)
);

create table Plays_Games (
       StuID                INTEGER,
       GameID            INTEGER,
       Hours_Played      INTEGER,
       FOREIGN KEY(GameID) REFERENCES Video_Games(GameID),
       FOREIGN KEY(StuID) REFERENCES Student(StuID)
);

create table SportsInfo (
  StuID INTEGER,
  SportName VARCHAR(32),
  HoursPerWeek INTEGER,
  GamesPlayed INTEGER,
  OnScholarship VARCHAR(1),
  FOREIGN KEY(StuID) REFERENCES Student(StuID)
);

Question: What are the student ids for those on scholarship in major number 600?

assistant: SELECT StuID FROM Student WHERE major = 600 INTERSECT SELECT StuID FROM Sportsinfo WHERE onscholarship = 'Y'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE "school" (
"School_ID" int,
"School" text,
"Location" text,
"Enrollment" real,
"Founded" real,
"Denomination" text,
"Boys_or_Girls" text,
"Day_or_Boarding" text,
"Year_Entered_Competition" real,
"School_Colors" text,
PRIMARY KEY ("School_Id")
);

Question: Which schools have more than 1 player? Give me the school locations.

assistant: SELECT T2.Location FROM player AS T1 JOIN school AS T2 ON T1.School_ID = T2.School_ID GROUP BY T1.School_ID HAVING COUNT(*) > 1
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE country (
  id integer PRIMARY KEY,
  country_name text
);
CREATE TABLE ranking_system (
  id integer PRIMARY KEY,
  system_name text
);
CREATE TABLE ranking_criteria (
  id integer PRIMARY KEY,
  ranking_system_id integer,
  criteria_name text
);
CREATE TABLE university (
  id integer PRIMARY KEY,
  country_id integer,
  university_name text
);
CREATE TABLE university_ranking_year (
  university_id integer,
  ranking_criteria_id integer,
  year integer,
  score integer
);
CREATE TABLE university_year (
  university_id integer,
  year integer,
  num_students integer,
  student_staff_ratio real,
  pct_international_students integer,
  pct_female_students integer
);
-- foreign keys: ranking_criteria.ranking_system_id -> ranking_system.id; university.country_id -> country.id; university_ranking_year.university_id -> university.id; university_ranking_year.ranking_criteria_id -> ranking_criteria.id; university_year.university_id -> university.id

Hint: average number of criterias refers to DIVIDE(SUM(id), 3); "Times Higher Education World University Ranking", "Shanghai Ranking" and "Center for World University Rankings" refers to system_name IN ('Times Higher Education World University Ranking', 'Shanghai Ranking', 'Center for World University Rankings');

Question: Calculate the average number of criterias among "Times Higher Education World University Ranking","Shanghai Ranking" and "Center for World University Rankings".

assistant: SELECT (SUM(CASE WHEN T1.system_name = 'Center for World University Rankings' THEN 1 ELSE 0 END) + SUM(CASE WHEN T1.system_name = 'Shanghai Ranking' THEN 1 ELSE 0 END) + SUM(CASE WHEN T1.system_name = 'Times Higher Education World University Ranking' THEN 1 ELSE 0 END)) / 3 FROM ranking_system AS T1 INNER JOIN ranking_criteria AS T2 ON T1.id = T2.ranking_system_id
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE city (
  city_id integer PRIMARY KEY,
  city_name text,
  state text,
  population integer,
  area real
);
CREATE TABLE customer (
  cust_id integer PRIMARY KEY,
  cust_name text,
  annual_revenue integer,
  cust_type text,
  address text,
  city text,
  state text,
  zip real,
  phone text
);
CREATE TABLE driver (
  driver_id integer PRIMARY KEY,
  first_name text,
  last_name text,
  address text,
  city text,
  state text,
  zip_code integer,
  phone text
);
CREATE TABLE truck (
  truck_id integer PRIMARY KEY,
  make text,
  model_year integer
);
CREATE TABLE shipment (
  ship_id integer PRIMARY KEY,
  cust_id integer,
  weight real,
  truck_id integer,
  driver_id integer,
  city_id integer,
  ship_date text
);
-- foreign keys: shipment.truck_id -> truck.truck_id; shipment.driver_id -> driver.driver_id; shipment.city_id -> city.city_id; shipment.cust_id -> customer.cust_id

Hint: "Sunguard Window Tinting & Truck Accessories" is the cust_name; weight exceed 10,000 pounds refers to weight > = 10000; in 2017 refers to Cast(ship_date AS DATE) = 2017; percentage = Divide (Sum(weight > = 10000), Sum(weight)) * 100

Question: Among all shipments placed by Sunguard Window Tinting & Truck Accessories in 2017, identify the percentage of shipments whose weight exceeded 10,000 pounds.

assistant: SELECT CAST(SUM(CASE WHEN T1.weight >= 10000 THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(*) FROM shipment AS T1 INNER JOIN customer AS T2 ON T1.cust_id = T2.cust_id WHERE T2.cust_name = 'Sunguard Window Tinting & Truck Accessories' AND STRFTIME('%Y', T1.ship_date) = '2017'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE city (
  id integer PRIMARY KEY,
  city_name text
);
CREATE TABLE games (
  id integer PRIMARY KEY,
  games_year integer,
  games_name text,
  season text
);
CREATE TABLE games_city (
  games_id integer,
  city_id integer
);
CREATE TABLE medal (
  id integer PRIMARY KEY,
  medal_name text
);
CREATE TABLE noc_region (
  id integer PRIMARY KEY,
  noc text,
  region_name text
);
CREATE TABLE person (
  id integer PRIMARY KEY,
  full_name text,
  gender text,
  height integer,
  weight integer
);
CREATE TABLE games_competitor (
  id integer PRIMARY KEY,
  games_id integer,
  person_id integer,
  age integer
);
CREATE TABLE person_region (
  person_id integer,
  region_id integer
);
CREATE TABLE sport (
  id integer PRIMARY KEY,
  sport_name text
);
CREATE TABLE event (
  id integer PRIMARY KEY,
  sport_id integer,
  event_name text
);
CREATE TABLE competitor_event (
  event_id integer,
  competitor_id integer,
  medal_id integer
);
-- foreign keys: games_city.games_id -> games.id; games_city.city_id -> city.id; games_competitor.person_id -> person.id; games_competitor.games_id -> games.id; person_region.region_id -> noc_region.id; person_region.person_id -> person.id; event.sport_id -> sport.id; competitor_event.medal_id -> medal.id; competitor_event.event_id -> event.id; competitor_event.competitor_id -> games_competitor.id

Hint: region refers to region_name; the majority of the athletes from refer to MAX(COUNT(region_name));

Question: Which region is the majority of the athletes from?

assistant: SELECT T2.region_name FROM person_region AS T1 INNER JOIN noc_region AS T2 ON T1.region_id = T2.id GROUP BY T2.region_name ORDER BY COUNT(T1.person_id) DESC LIMIT 1