ajayk007/querysmith-spider-bird huggingface dataset:
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE Community_Area (
  community_area_no integer PRIMARY KEY,
  community_area_name text,
  side text,
  population text
);
CREATE TABLE District (
  district_no integer PRIMARY KEY,
  district_name text,
  address text,
  zip_code integer,
  commander text,
  email text,
  phone text,
  fax text,
  tty text,
  twitter text
);
CREATE TABLE FBI_Code (
  fbi_code_no text PRIMARY KEY,
  title text,
  description text,
  crime_against text
);
CREATE TABLE IUCR (
  iucr_no text PRIMARY KEY,
  primary_description text,
  secondary_description text,
  index_code text
);
CREATE TABLE Neighborhood (
  neighborhood_name text PRIMARY KEY,
  community_area_no integer
);
CREATE TABLE Ward (
  ward_no integer PRIMARY KEY,
  alderman_first_name text,
  alderman_last_name text,
  alderman_name_suffix text,
  ward_office_address text,
  ward_office_zip text,
  ward_email text,
  ward_office_phone text,
  ward_office_fax text,
  city_hall_office_room integer,
  city_hall_office_phone text,
  city_hall_office_fax text,
  Population integer
);
CREATE TABLE Crime (
  report_no integer PRIMARY KEY,
  case_number text,
  date text,
  block text,
  iucr_no text,
  location_description text,
  arrest text,
  domestic text,
  beat integer,
  district_no integer,
  ward_no integer,
  community_area_no integer,
  fbi_code_no text,
  latitude text,
  longitude text
);
-- foreign keys: Neighborhood.community_area_no -> Community_Area.community_area_no; Crime.fbi_code_no -> FBI_Code.fbi_code_no; Crime.community_area_no -> Community_Area.community_area_no; Crime.district_no -> District.district_no; Crime.iucr_no -> IUCR.iucr_no; Crime.ward_no -> Ward.ward_no

Hint: "Forest Glen" is the community_area_name; neighborhoods refers to neighborhood_name

Question: How many neighborhoods can be found in the Forest Glen community area?

assistant: SELECT SUM(CASE WHEN T2.community_area_name = 'Forest Glen' THEN 1 ELSE 0 END) FROM Neighborhood AS T1 INNER JOIN Community_Area AS T2 ON T1.community_area_no = T2.community_area_no
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
-- LINK: https://en.wikibooks.org/wiki/SQL_Exercises/The_computer_store

CREATE TABLE Manufacturers (
  Code INTEGER,
  Name VARCHAR(255) NOT NULL,
  Headquarter VARCHAR(255) NOT NULL,
  Founder VARCHAR(255) NOT NULL,
  Revenue REAL,
  PRIMARY KEY (Code)   
);

CREATE TABLE Products (
  Code INTEGER,
  Name VARCHAR(255) NOT NULL ,
  Price DECIMAL NOT NULL ,
  Manufacturer INTEGER NOT NULL,
  PRIMARY KEY (Code), 
  FOREIGN KEY (Manufacturer) REFERENCES Manufacturers(Code)
);

Question: What are the names and prices of products that cost at least 180, sorted by price decreasing and name ascending?

assistant: SELECT name , price FROM products WHERE price >= 180 ORDER BY price DESC , name ASC
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
create table Student (
         StuID        INTEGER PRIMARY KEY,
         LName        VARCHAR(12),
         Fname        VARCHAR(12),
         Age      INTEGER,
         Sex      VARCHAR(1),
         Major        INTEGER,
         Advisor      INTEGER,
         city_code    VARCHAR(3)
  );


create table Club (
       ClubID           INTEGER PRIMARY KEY,
       ClubName         VARCHAR(40),
       ClubDesc         VARCHAR(1024),
       ClubLocation VARCHAR(40)
);

create table Member_of_club (
       StuID            INTEGER,
       ClubID           INTEGER,
       Position     VARCHAR(40),
       FOREIGN KEY(StuID) REFERENCES Student(StuID),
       FOREIGN KEY(ClubID) REFERENCES Club(ClubID)
);

Question: Which club has the most female students as their members? Give me the name of the club.

assistant: SELECT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.sex = "F" GROUP BY t1.clubname ORDER BY count(*) DESC LIMIT 1
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE "workshop" (
"Workshop_ID" int,
"Date" text,
"Venue" text,
"Name" text,
PRIMARY KEY ("Workshop_ID")
);

CREATE TABLE "submission" (
"Submission_ID" int,
"Scores" real,
"Author" text,
"College" text,
PRIMARY KEY ("Submission_ID")
);

Question: Which colleges have both authors with submission score above 90 and authors with submission score below 80?

assistant: SELECT College FROM submission WHERE Scores > 90 INTERSECT SELECT College FROM submission WHERE Scores < 80
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE offices (
  officeCode text PRIMARY KEY,
  city text,
  phone text,
  addressLine1 text,
  addressLine2 text,
  state text,
  country text,
  postalCode text,
  territory text
);
CREATE TABLE employees (
  employeeNumber integer PRIMARY KEY,
  lastName text,
  firstName text,
  extension text,
  email text,
  officeCode text,
  reportsTo integer,
  jobTitle text
);
CREATE TABLE customers (
  customerNumber integer PRIMARY KEY,
  customerName text,
  contactLastName text,
  contactFirstName text,
  phone text,
  addressLine1 text,
  addressLine2 text,
  city text,
  state text,
  postalCode text,
  country text,
  salesRepEmployeeNumber integer,
  creditLimit real
);
CREATE TABLE orders (
  orderNumber integer PRIMARY KEY,
  orderDate date,
  requiredDate date,
  shippedDate date,
  status text,
  comments text,
  customerNumber integer
);
CREATE TABLE payments (
  customerNumber integer PRIMARY KEY,
  checkNumber text PRIMARY KEY,
  paymentDate date,
  amount real
);
CREATE TABLE productlines (
  productLine text PRIMARY KEY,
  textDescription text,
  htmlDescription text,
  image blob
);
CREATE TABLE products (
  productCode text PRIMARY KEY,
  productName text,
  productLine text,
  productScale text,
  productVendor text,
  productDescription text,
  quantityInStock integer,
  buyPrice real,
  MSRP real
);
CREATE TABLE orderdetails (
  orderNumber integer PRIMARY KEY,
  productCode text PRIMARY KEY,
  quantityOrdered integer,
  priceEach real,
  orderLineNumber integer
);
-- foreign keys: employees.reportsTo -> employees.employeeNumber; employees.officeCode -> offices.officeCode; customers.salesRepEmployeeNumber -> employees.employeeNumber; orders.customerNumber -> customers.customerNumber; payments.customerNumber -> customers.customerNumber; products.productLine -> productlines.productLine

Question: Who is the sales agent of the distinct customer who paid the highest amount in the year 2004?

assistant: SELECT DISTINCT T3.lastName, T3.firstName FROM payments AS T1 INNER JOIN customers AS T2 ON T1.customerNumber = T2.customerNumber INNER JOIN employees AS T3 ON T2.salesRepEmployeeNumber = T3.employeeNumber WHERE STRFTIME('%Y', T1.paymentDate) = '2004' ORDER BY T1.amount DESC LIMIT 1
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;


CREATE TABLE "country" (
    "Country_id" int,
    "Country_name" text,
    "Capital" text,
    "Official_native_language" text,
    PRIMARY KEY ("Country_id")
);


CREATE TABLE `team` (
      `Team_id` int,
      `Name` text,
      PRIMARY KEY (`Team_id`)
) ;

Question: What are the names of teams that do no have match season record?

assistant: SELECT Name FROM team WHERE Team_id NOT IN (SELECT Team FROM match_season)
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;


CREATE TABLE "festival_detail" (
"Festival_ID" int,
"Festival_Name" text,
"Chair_Name" text,
"Location" text,
"Year" int,
"Num_of_Audience" int,
PRIMARY KEY ("Festival_ID")
);

Question: Show the names of artworks in ascending order of the year they are nominated in.

assistant: SELECT T2.Name FROM nomination AS T1 JOIN artwork AS T2 ON T1.Artwork_ID = T2.Artwork_ID JOIN festival_detail AS T3 ON T1.Festival_ID = T3.Festival_ID ORDER BY T3.Year
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE genre (
  id integer PRIMARY KEY,
  genre_name text
);
CREATE TABLE game (
  id integer PRIMARY KEY,
  genre_id integer,
  game_name text
);
CREATE TABLE platform (
  id integer PRIMARY KEY,
  platform_name text
);
CREATE TABLE publisher (
  id integer PRIMARY KEY,
  publisher_name text
);
CREATE TABLE game_publisher (
  id integer PRIMARY KEY,
  game_id integer,
  publisher_id integer
);
CREATE TABLE game_platform (
  id integer PRIMARY KEY,
  game_publisher_id integer,
  platform_id integer,
  release_year integer
);
CREATE TABLE region (
  id integer PRIMARY KEY,
  region_name text
);
CREATE TABLE region_sales (
  region_id integer,
  game_platform_id integer,
  num_sales real
);
-- foreign keys: game.genre_id -> genre.id; game_publisher.publisher_id -> publisher.id; game_publisher.game_id -> game.id; game_platform.platform_id -> platform.id; game_platform.game_publisher_id -> game_publisher.id; region_sales.region_id -> region.id; region_sales.game_platform_id -> game_platform.id

Hint: name of games refers to game_name; adventure games refers to game_name WHERE genre_name = 'Adventure';

Question: Indicate the name of all adventure games.

assistant: SELECT T2.game_name FROM genre AS T1 INNER JOIN game AS T2 ON T1.id = T2.genre_id WHERE T1.genre_name = 'Adventure'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE customers (
  CustomerID integer PRIMARY KEY,
  First text,
  Last text,
  StreetAddress text,
  City text,
  State text,
  ZipCode integer,
  Email text,
  PhoneNumber text,
  FirstPurchaseDate date,
  SubscribedToEmailList text,
  Gender text
);
CREATE TABLE geolocation (
  LocationID integer PRIMARY KEY,
  Latitude real,
  Longitude real
);
CREATE TABLE location (
  LocationID integer PRIMARY KEY,
  LocationName text,
  StreetAddress text,
  City text,
  State text,
  ZipCode integer
);
CREATE TABLE rootbeerbrand (
  BrandID integer PRIMARY KEY,
  BrandName text,
  FirstBrewedYear integer,
  BreweryName text,
  City text,
  State text,
  Country text,
  Description text,
  CaneSugar text,
  CornSyrup text,
  Honey text,
  ArtificialSweetener text,
  Caffeinated text,
  Alcoholic text,
  AvailableInCans text,
  AvailableInBottles text,
  AvailableInKegs text,
  Website text,
  FacebookPage text,
  Twitter text,
  WholesaleCost real,
  CurrentRetailPrice real
);
CREATE TABLE rootbeer (
  RootBeerID integer PRIMARY KEY,
  BrandID integer,
  ContainerType text,
  LocationID integer,
  PurchaseDate date
);
CREATE TABLE rootbeerreview (
  CustomerID integer PRIMARY KEY,
  BrandID integer PRIMARY KEY,
  StarRating integer,
  ReviewDate date,
  Review text
);
CREATE TABLE transaction (
  TransactionID integer PRIMARY KEY,
  CreditCardNumber integer,
  CustomerID integer,
  TransactionDate date,
  CreditCardType text,
  LocationID integer,
  RootBeerID integer,
  PurchasePrice real
);
-- foreign keys: geolocation.LocationID -> location.LocationID; location.LocationID -> geolocation.LocationID; rootbeer.BrandID -> rootbeerbrand.BrandID; rootbeer.LocationID -> location.LocationID; rootbeer.LocationID -> geolocation.LocationID; rootbeerreview.BrandID -> rootbeerbrand.BrandID; rootbeerreview.CustomerID -> customers.CustomerID; transaction.RootBeerID -> rootbeer.RootBeerID; transaction.LocationID -> location.LocationID; transaction.CustomerID -> customers.CustomerID

Hint: brand of root beer refers to BrandName; produced by Dr Pepper Snapple Group refers to BreweryName = 'Dr Pepper Snapple Group'; percentage of purchases = MULTIPLY(DIVIDE(SUM(BrandID WHERE PurchaseDate > = '2014-01-01' AND PurchaseDate < = '2016-12-31'), COUNT(BrandID) WHERE BreweryName = 'Dr Pepper Snapple Group'), 1.0); between 2014 to 2016 refers to PurchaseDate > = '2014-01-01' AND PurchaseDate < = '2016-12-31;

Question: List the brands of root beer produced by Dr Pepper Snapple Group and calculate their percentage of purchases between 2014 to 2016.

assistant: SELECT T1.BrandName , CAST(SUM(CASE WHEN T2.PurchaseDate >= '2014-01-01' AND T2.PurchaseDate <= '2016-12-31' THEN 1 ELSE 0 END) AS REAL) / COUNT(T2.BrandID) AS purchase FROM rootbeerbrand AS T1 INNER JOIN rootbeer AS T2 ON T1.BrandID = T2.BrandID WHERE T1.BreweryName = 'Dr Pepper Snapple Group' GROUP BY T2.BrandID
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
-- LINK: https://en.wikibooks.org/wiki/SQL_Exercises/The_computer_store

CREATE TABLE Manufacturers (
  Code INTEGER,
  Name VARCHAR(255) NOT NULL,
  Headquarter VARCHAR(255) NOT NULL,
  Founder VARCHAR(255) NOT NULL,
  Revenue REAL,
  PRIMARY KEY (Code)   
);

CREATE TABLE Products (
  Code INTEGER,
  Name VARCHAR(255) NOT NULL ,
  Price DECIMAL NOT NULL ,
  Manufacturer INTEGER NOT NULL,
  PRIMARY KEY (Code), 
  FOREIGN KEY (Manufacturer) REFERENCES Manufacturers(Code)
);

Question: Select the names of manufacturer whose products have an average price higher than or equal to $150.

assistant: SELECT avg(T1.Price) , T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name HAVING avg(T1.price) >= 150
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE employee (
  employee_id integer PRIMARY KEY,
  first_name text,
  last_name text,
  address text,
  city text,
  state text,
  zip integer,
  phone text,
  title text,
  salary integer,
  supervisor integer
);
CREATE TABLE establishment (
  license_no integer PRIMARY KEY,
  dba_name text,
  aka_name text,
  facility_type text,
  risk_level integer,
  address text,
  city text,
  state text,
  zip integer,
  latitude real,
  longitude real,
  ward integer
);
CREATE TABLE inspection (
  inspection_id integer PRIMARY KEY,
  inspection_date date,
  inspection_type text,
  results text,
  employee_id integer,
  license_no integer,
  followup_to integer
);
CREATE TABLE inspection_point (
  point_id integer PRIMARY KEY,
  Description text,
  category text,
  code text,
  fine integer,
  point_level text
);
CREATE TABLE violation (
  inspection_id integer PRIMARY KEY,
  point_id integer PRIMARY KEY,
  fine integer,
  inspector_comment text
);
-- foreign keys: employee.supervisor -> employee.employee_id; inspection.followup_to -> inspection.inspection_id; inspection.license_no -> establishment.license_no; inspection.employee_id -> employee.employee_id; violation.point_id -> inspection_point.point_id; violation.inspection_id -> inspection.inspection_id

Hint: phone number refers to phone; sanitarian refers to title = 'Sanitarian'; inspection no.634597 refers to inspection_id = '634597'

Question: Show the phone number of the sanitarian who was responsible for inspection no.634597.

assistant: SELECT T2.phone FROM inspection AS T1 INNER JOIN employee AS T2 ON T1.employee_id = T2.employee_id WHERE T1.inspection_id = 634597 AND T2.title = 'Sanitarian'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE height_info (
  height_id integer PRIMARY KEY,
  height_in_cm integer,
  height_in_inch text
);
CREATE TABLE weight_info (
  weight_id integer PRIMARY KEY,
  weight_in_kg integer,
  weight_in_lbs integer
);
CREATE TABLE PlayerInfo (
  ELITEID integer PRIMARY KEY,
  PlayerName text,
  birthdate text,
  birthyear date,
  birthmonth integer,
  birthday integer,
  birthplace text,
  nation text,
  height integer,
  weight integer,
  position_info text,
  shoots text,
  draftyear integer,
  draftround integer,
  overall integer,
  overallby text,
  CSS_rank integer,
  sum_7yr_GP integer,
  sum_7yr_TOI integer,
  GP_greater_than_0 text
);
CREATE TABLE SeasonStatus (
  ELITEID integer,
  SEASON text,
  TEAM text,
  LEAGUE text,
  GAMETYPE text,
  GP integer,
  G integer,
  A integer,
  P integer,
  PIM integer,
  PLUSMINUS integer
);
-- foreign keys: PlayerInfo.weight -> weight_info.weight_id; PlayerInfo.height -> height_info.height_id; SeasonStatus.ELITEID -> PlayerInfo.ELITEID

Hint: average height in centimeter = AVG(height_in_cm); height in centimeter refers to height_in_cm; players refers to PlayerName; Acadie-Bathurst Titan refers to TEAM = 'Acadie-Bathurst Titan'; regular season refers to GAMETYPE = 'Regular Season';

Question: Calculate the average height in centimeter of all players who played in Acadie-Bathurst Titan during regular season.

assistant: SELECT CAST(SUM(T1.height_in_cm) AS REAL) / COUNT(T2.ELITEID) FROM height_info AS T1 INNER JOIN PlayerInfo AS T2 ON T1.height_id = T2.height INNER JOIN SeasonStatus AS T3 ON T2.ELITEID = T3.ELITEID WHERE T3.TEAM = 'Acadie-Bathurst Titan' AND T3.GAMETYPE = 'Regular Season'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE "artist" (
"Artist_ID" int,
"Name" text,
"Country" text,
"Year_Join" int,
"Age" int,
PRIMARY KEY ("Artist_ID")
);

Question: Show theme and year for all exhibitions in an descending order of ticket price.

assistant: SELECT theme , YEAR FROM exhibition ORDER BY ticket_price DESC
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE businesses (
  business_id integer PRIMARY KEY,
  name text,
  address text,
  city text,
  postal_code text,
  latitude real,
  longitude real,
  phone_number integer,
  tax_code text,
  business_certificate integer,
  application_date date,
  owner_name text,
  owner_address text,
  owner_city text,
  owner_state text,
  owner_zip text
);
CREATE TABLE inspections (
  business_id integer,
  score integer,
  date date,
  type text
);
CREATE TABLE violations (
  business_id integer,
  date date,
  violation_type_id text,
  risk_category text,
  description text
);
-- foreign keys: inspections.business_id -> businesses.business_id; violations.business_id -> businesses.business_id

Hint: inspection in 2014 refers to year(date) = 2014; low risk violations refer to risk_category = 'Low Risk';

Question: Please list the names of the restaurants that had a low risk violation in inspections in 2014.

assistant: SELECT DISTINCT T2.name FROM violations AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE STRFTIME('%Y', T1.`date`) = '2014' AND T1.risk_category = 'Low Risk'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;
CREATE TABLE "medicine" (
"id" int,
"name" text,
"Trade_Name" text,
"FDA_approved" text,
primary key ("id")
);

CREATE TABLE "enzyme" (
"id" int,
"name" text,
"Location" text,
"Product" text,
"Chromosome" text,
"OMIM" int,
"Porphyria" text,
primary key ("id")
);


CREATE TABLE "medicine_enzyme_interaction" (
"enzyme_id" int,
"medicine_id" int,
"interaction_type" text,
primary key ("enzyme_id", "medicine_id"),
foreign key ("enzyme_id") references `enzyme`("id"),
foreign key ("medicine_id") references `medicine`("id")
);

Question: What is the id and trade name of the medicines can interact with at least 3 enzymes?

assistant: SELECT T1.id , T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id GROUP BY T1.id HAVING COUNT(*) >= 3
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE Attributes (
  attribute_id integer PRIMARY KEY,
  attribute_name text
);
CREATE TABLE Categories (
  category_id integer PRIMARY KEY,
  category_name text
);
CREATE TABLE Compliments (
  compliment_id integer PRIMARY KEY,
  compliment_type text
);
CREATE TABLE Days (
  day_id integer PRIMARY KEY,
  day_of_week text
);
CREATE TABLE Years (
  year_id integer PRIMARY KEY,
  actual_year integer
);
CREATE TABLE Business_Attributes (
  attribute_id integer PRIMARY KEY,
  business_id integer PRIMARY KEY,
  attribute_value text
);
CREATE TABLE Business_Categories (
  business_id integer PRIMARY KEY,
  category_id integer PRIMARY KEY
);
CREATE TABLE Business_Hours (
  business_id integer PRIMARY KEY,
  day_id integer PRIMARY KEY,
  opening_time text,
  closing_time text
);
CREATE TABLE Checkins (
  business_id integer PRIMARY KEY,
  day_id integer PRIMARY KEY,
  label_time_0 text,
  label_time_1 text,
  label_time_2 text,
  label_time_3 text,
  label_time_4 text,
  label_time_5 text,
  label_time_6 text,
  label_time_7 text,
  label_time_8 text,
  label_time_9 text,
  label_time_10 text,
  label_time_11 text,
  label_time_12 text,
  label_time_13 text,
  label_time_14 text,
  label_time_15 text,
  label_time_16 text,
  label_time_17 text,
  label_time_18 text,
  label_time_19 text,
  label_time_20 text,
  label_time_21 text,
  label_time_22 text,
  label_time_23 text
);
CREATE TABLE Elite (
  user_id integer PRIMARY KEY,
  year_id integer PRIMARY KEY
);
CREATE TABLE Reviews (
  business_id integer PRIMARY KEY,
  user_id integer PRIMARY KEY,
  review_stars integer,
  review_votes_funny text,
  review_votes_useful text,
  review_votes_cool text,
  review_length text
);
CREATE TABLE Tips (
  business_id integer PRIMARY KEY,
  user_id integer PRIMARY KEY,
  likes integer,
  tip_length text
);
CREATE TABLE Users_Compliments (
  compliment_id integer PRIMARY KEY,
  user_id integer PRIMARY KEY,
  number_of_compliments text
);
CREATE TABLE Business (
  business_id integer PRIMARY KEY,
  active text,
  city text,
  state text,
  stars real,
  review_count text
);
CREATE TABLE Users (
  user_id integer PRIMARY KEY,
  user_yelping_since_year integer,
  user_average_stars text,
  user_votes_funny text,
  user_votes_useful text,
  user_votes_cool text,
  user_review_count text,
  user_fans text
);

Hint: highest quality user refers to number_of_compliments = 'Uber'; user of under ID 100 refers to user_id < 100 ;

Question: Among highest quality user of under ID 100, mention compliment type which got highest compliment number and user's followers.

assistant: SELECT T1.compliment_type, T3.user_fans FROM Compliments AS T1 INNER JOIN Users_Compliments AS T2 ON T1.compliment_id = T2.compliment_id INNER JOIN Users AS T3 ON T2.user_id = T3.user_id WHERE T2.number_of_compliments = 'Uber' AND T2.user_id < 100