ajayk007/querysmith-spider-bird huggingface dataset:
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;
CREATE TABLE Ref_Hotel_Star_Ratings (
star_rating_code CHAR(15) NOT NULL,
star_rating_description VARCHAR(80),
PRIMARY KEY (star_rating_code),
UNIQUE (star_rating_code)
);


CREATE TABLE Locations (
Location_ID INTEGER NOT NULL,
Location_Name VARCHAR(255),
Address VARCHAR(255),
Other_Details VARCHAR(255),
PRIMARY KEY (Location_ID)
);

Question: Show the tourist attractions visited by the tourist whose detail is 'Vincent'.

assistant: SELECT T1.Name FROM Tourist_Attractions AS T1 JOIN VISITS AS T2 ON T1.Tourist_Attraction_ID = T2.Tourist_Attraction_ID JOIN VISITORS AS T3 ON T2.Tourist_ID = T3.Tourist_ID WHERE T3.Tourist_Details = "Vincent"
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
--data definition

create table genre(
	g_name varchar2(20) not null,
	rating varchar2(10),
	most_popular_in varchar2(50),
	primary key(g_name)
);

create table artist(
	artist_name varchar2(50) not null,
	country varchar2(20),
	gender varchar2(20),
	preferred_genre varchar2(50),
	constraint a_name primary key(artist_name),
	foreign key(preferred_genre) references genre(g_name) ON DELETE CASCADE
);

create table files(
	f_id number(10) not null,
	artist_name varchar2(50),
	file_size varchar2(20),
	duration varchar2(20),
	formats varchar2(20),
	primary key(f_id),
	foreign key(artist_name) references artist(artist_name) ON DELETE CASCADE
);


create table song(
	song_name varchar2(50),
	artist_name varchar2(50),
	country varchar2(20),
	f_id number(10),
    	genre_is varchar2(20),
	rating number(10) check(rating>0 and rating<11),
	languages varchar2(20),
	releasedate Date, 
	resolution number(10) not null,
	constraint s_name primary key(song_name),
	foreign key(artist_name) references artist(artist_name) ON DELETE CASCADE,
	foreign key(f_id) references files(f_id) ON DELETE CASCADE,
	foreign key(genre_is) references genre(g_name) ON DELETE CASCADE
);


--insertion of attributes in the table

Question: What are the names of all singers that are from the UK and released a song in English?

assistant: SELECT artist_name FROM artist WHERE country = "UK" INTERSECT SELECT T1.artist_name FROM artist AS T1 JOIN song AS T2 ON T1.artist_name = T2.artist_name WHERE T2.languages = "english"
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE bool (
  name text PRIMARY KEY
);
CREATE TABLE person (
  name text PRIMARY KEY
);
CREATE TABLE disabled (
  name text PRIMARY KEY
);
CREATE TABLE enlist (
  name text,
  organ text
);
CREATE TABLE filed_for_bankrupcy (
  name text PRIMARY KEY
);
CREATE TABLE longest_absense_from_school (
  name text PRIMARY KEY,
  month integer
);
CREATE TABLE male (
  name text PRIMARY KEY
);
CREATE TABLE no_payment_due (
  name text PRIMARY KEY,
  bool text
);
CREATE TABLE unemployed (
  name text PRIMARY KEY
);
CREATE TABLE enrolled (
  name text PRIMARY KEY,
  school text PRIMARY KEY,
  month integer
);
-- foreign keys: disabled.name -> person.name; enlist.name -> person.name; filed_for_bankrupcy.name -> person.name; longest_absense_from_school.name -> person.name; male.name -> person.name; no_payment_due.bool -> bool.name; no_payment_due.name -> person.name; unemployed.name -> person.name; enrolled.name -> person.name

Hint: longest duration of absence refers to MAX(month); department refers to organ; organ = 'fire_department';

Question: List the longest duration of absense for a student enlisted in the fire department.

assistant: SELECT T1.month FROM longest_absense_from_school AS T1 INNER JOIN enlist AS T2 ON T1.name = T2.name WHERE T2.organ = 'fire_department' ORDER BY T1.month DESC LIMIT 1
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE location (
  locationID integer PRIMARY KEY,
  locationcity text,
  address text,
  state text,
  zipcode integer,
  officephone text
);
CREATE TABLE position (
  positionID integer PRIMARY KEY,
  positiontitle text,
  educationrequired text,
  minsalary text,
  maxsalary text
);
CREATE TABLE employee (
  ssn text PRIMARY KEY,
  lastname text,
  firstname text,
  hiredate text,
  salary text,
  gender text,
  performance text,
  positionID integer,
  locationID integer
);
-- foreign keys: employee.positionID -> position.positionID; employee.locationID -> location.locationID

Hint: good job performance refers to performance = 'Good'

Question: How many emplyees have a good job performance?

assistant: SELECT COUNT(*) FROM employee WHERE performance = 'Good'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys=OFF;
BEGIN TRANSACTION;
CREATE TABLE station (
    id INTEGER PRIMARY KEY,
    name TEXT,
    lat NUMERIC,
    long NUMERIC,
    dock_count INTEGER,
    city TEXT,
    installation_date TEXT);

Question: What are the ids of stations that have latitude above 37.4 and never had bike availability below 7?

assistant: SELECT id FROM station WHERE lat > 37.4 EXCEPT SELECT station_id FROM status GROUP BY station_id HAVING min(bikes_available) < 7
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;


CREATE TABLE "city" (
"City_ID" int,
"City" text,
"Hanzi" text,
"Hanyu_Pinyin" text,
"Regional_Population" int,
"GDP" real,
PRIMARY KEY ("City_ID")
);

CREATE TABLE "match" (
"Match_ID" int,
"Date" text,
"Venue" text,
"Score" text,
"Result" text,
"Competition" text,
PRIMARY KEY ("Match_ID")
);



CREATE TABLE "temperature" (
"City_ID" int,
"Jan" real,
"Feb" real,
"Mar" real,
"Apr" real,
"Jun" real,
"Jul" real,
"Aug" real,
"Sep" real,
"Oct" real,
"Nov" real,
"Dec" real,
PRIMARY KEY ("City_ID"),
FOREIGN KEY (`City_ID`) REFERENCES `city`(`City_ID`)
);

Question: What are the three largest cities in terms of regional population?

assistant: SELECT city FROM city ORDER BY regional_population DESC LIMIT 3
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;


CREATE TABLE "company" (
"Company_ID" int,
"Rank" int,
"Company" text,
"Headquarters" text,
"Main_Industry" text,
"Sales_billion" real,
"Profits_billion" real,
"Assets_billion" real,
"Market_Value" real,
PRIMARY KEY ("Company_ID")
);

CREATE TABLE "gas_station" (
"Station_ID" int,
"Open_Year" int,
"Location" text,
"Manager_Name" text,
"Vice_Manager_Name" text,
"Representative_Name" text,
PRIMARY KEY ("Station_ID")
);

Question: What is the name of the manager with the most gas stations that opened after 2000?

assistant: SELECT manager_name FROM gas_station WHERE open_year > 2000 GROUP BY manager_name ORDER BY count(*) DESC LIMIT 1
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE genre (
  id integer PRIMARY KEY,
  genre_name text
);
CREATE TABLE game (
  id integer PRIMARY KEY,
  genre_id integer,
  game_name text
);
CREATE TABLE platform (
  id integer PRIMARY KEY,
  platform_name text
);
CREATE TABLE publisher (
  id integer PRIMARY KEY,
  publisher_name text
);
CREATE TABLE game_publisher (
  id integer PRIMARY KEY,
  game_id integer,
  publisher_id integer
);
CREATE TABLE game_platform (
  id integer PRIMARY KEY,
  game_publisher_id integer,
  platform_id integer,
  release_year integer
);
CREATE TABLE region (
  id integer PRIMARY KEY,
  region_name text
);
CREATE TABLE region_sales (
  region_id integer,
  game_platform_id integer,
  num_sales real
);
-- foreign keys: game.genre_id -> genre.id; game_publisher.publisher_id -> publisher.id; game_publisher.game_id -> game.id; game_platform.platform_id -> platform.id; game_platform.game_publisher_id -> game_publisher.id; region_sales.region_id -> region.id; region_sales.game_platform_id -> game_platform.id

Hint: total sales = SUM(num_sales); released in 2000 refers to release_year = 2000;

Question: Calculate the total sales made by the games released in 2000.

assistant: SELECT SUM(T1.num_sales) FROM region_sales AS T1 INNER JOIN game_platform AS T2 ON T1.game_platform_id = T2.id WHERE T2.release_year = 2000
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE authors (
  au_id text PRIMARY KEY,
  au_lname text,
  au_fname text,
  phone text,
  address text,
  city text,
  state text,
  zip text,
  contract text
);
CREATE TABLE jobs (
  job_id integer PRIMARY KEY,
  job_desc text,
  min_lvl integer,
  max_lvl integer
);
CREATE TABLE publishers (
  pub_id text PRIMARY KEY,
  pub_name text,
  city text,
  state text,
  country text
);
CREATE TABLE employee (
  emp_id text PRIMARY KEY,
  fname text,
  minit text,
  lname text,
  job_id integer,
  job_lvl integer,
  pub_id text,
  hire_date datetime
);
CREATE TABLE pub_info (
  pub_id text PRIMARY KEY,
  logo blob,
  pr_info text
);
CREATE TABLE stores (
  stor_id text PRIMARY KEY,
  stor_name text,
  stor_address text,
  city text,
  state text,
  zip text
);
CREATE TABLE discounts (
  discounttype text,
  stor_id text,
  lowqty integer,
  highqty integer,
  discount real
);
CREATE TABLE titles (
  title_id text PRIMARY KEY,
  title text,
  type text,
  pub_id text,
  price real,
  advance real,
  royalty integer,
  ytd_sales integer,
  notes text,
  pubdate datetime
);
CREATE TABLE roysched (
  title_id text,
  lorange integer,
  hirange integer,
  royalty integer
);
CREATE TABLE sales (
  stor_id text PRIMARY KEY,
  ord_num text PRIMARY KEY,
  ord_date datetime,
  qty integer,
  payterms text,
  title_id text PRIMARY KEY
);
CREATE TABLE titleauthor (
  au_id text PRIMARY KEY,
  title_id text PRIMARY KEY,
  au_ord integer,
  royaltyper integer
);
-- foreign keys: employee.pub_id -> publishers.pub_id; employee.job_id -> jobs.job_id; pub_info.pub_id -> publishers.pub_id; discounts.stor_id -> stores.stor_id; titles.pub_id -> publishers.pub_id; roysched.title_id -> titles.title_id; sales.title_id -> titles.title_id; sales.stor_id -> stores.stor_id; titleauthor.title_id -> titles.title_id; titleauthor.au_id -> authors.au_id

Hint: most expensive book refers to MAX(price)

Question: What is the publisher that has published the most expensive book?

assistant: SELECT T2.pub_name FROM titles AS T1 INNER JOIN publishers AS T2 ON T1.pub_id = T2.pub_id ORDER BY T1.price DESC LIMIT 1
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE country (
  country_id integer PRIMARY KEY,
  country_iso_code text,
  country_name text
);
CREATE TABLE department (
  department_id integer PRIMARY KEY,
  department_name text
);
CREATE TABLE gender (
  gender_id integer PRIMARY KEY,
  gender text
);
CREATE TABLE genre (
  genre_id integer PRIMARY KEY,
  genre_name text
);
CREATE TABLE keyword (
  keyword_id integer PRIMARY KEY,
  keyword_name text
);
CREATE TABLE language (
  language_id integer PRIMARY KEY,
  language_code text,
  language_name text
);
CREATE TABLE language_role (
  role_id integer PRIMARY KEY,
  language_role text
);
CREATE TABLE movie (
  movie_id integer PRIMARY KEY,
  title text,
  budget integer,
  homepage text,
  overview text,
  popularity real,
  release_date date,
  revenue integer,
  runtime integer,
  movie_status text,
  tagline text,
  vote_average real,
  vote_count integer
);
CREATE TABLE movie_genres (
  movie_id integer,
  genre_id integer
);
CREATE TABLE movie_languages (
  movie_id integer,
  language_id integer,
  language_role_id integer
);
CREATE TABLE person (
  person_id integer PRIMARY KEY,
  person_name text
);
CREATE TABLE movie_crew (
  movie_id integer,
  person_id integer,
  department_id integer,
  job text
);
CREATE TABLE production_company (
  company_id integer PRIMARY KEY,
  company_name text
);
CREATE TABLE production_country (
  movie_id integer,
  country_id integer
);
CREATE TABLE movie_cast (
  movie_id integer,
  person_id integer,
  character_name text,
  gender_id integer,
  cast_order integer
);
CREATE TABLE movie_keywords (
  movie_id integer,
  keyword_id integer
);
CREATE TABLE movie_company (
  movie_id integer,
  company_id integer
);
-- foreign keys: movie_genres.movie_id -> movie.movie_id; movie_genres.genre_id -> genre.genre_id; movie_languages.language_role_id -> language_role.role_id; movie_languages.movie_id -> movie.movie_id; movie_languages.language_id -> language.language_id; movie_crew.person_id -> person.person_id; movie_crew.movie_id -> movie.movie_id; movie_crew.department_id -> department.department_id; production_country.movie_id -> movie.movie_id; production_country.country_id -> country.country_id; movie_cast.person_id -> person.person_id; movie_cast.movie_id -> movie.movie_id; movie_cast.gender_id -> gender.gender_id

Hint: more than 150 movies refers to COUNT(company_name) > 150

Question: How many production companies made more than 150 movies?

assistant: SELECT COUNT(*) FROM ( SELECT T1.company_name AS CNAME FROM production_company AS T1 INNER JOIN movie_company AS T2 ON T1.company_id = T2.company_id GROUP BY T1.company_id HAVING COUNT(T1.company_name) > 150 )
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE film_text (
  film_id integer PRIMARY KEY,
  title text,
  description text
);
CREATE TABLE actor (
  actor_id integer PRIMARY KEY,
  first_name text,
  last_name text,
  last_update datetime
);
CREATE TABLE address (
  address_id integer PRIMARY KEY,
  address text,
  address2 text,
  district text,
  city_id integer,
  postal_code text,
  phone text,
  last_update datetime
);
CREATE TABLE category (
  category_id integer PRIMARY KEY,
  name text,
  last_update datetime
);
CREATE TABLE city (
  city_id integer PRIMARY KEY,
  city text,
  country_id integer,
  last_update datetime
);
CREATE TABLE country (
  country_id integer PRIMARY KEY,
  country text,
  last_update datetime
);
CREATE TABLE customer (
  customer_id integer PRIMARY KEY,
  store_id integer,
  first_name text,
  last_name text,
  email text,
  address_id integer,
  active integer,
  create_date datetime,
  last_update datetime
);
CREATE TABLE film (
  film_id integer PRIMARY KEY,
  title text,
  description text,
  release_year text,
  language_id integer,
  original_language_id integer,
  rental_duration integer,
  rental_rate real,
  length integer,
  replacement_cost real,
  rating text,
  special_features text,
  last_update datetime
);
CREATE TABLE film_actor (
  actor_id integer PRIMARY KEY,
  film_id integer PRIMARY KEY,
  last_update datetime
);
CREATE TABLE film_category (
  film_id integer PRIMARY KEY,
  category_id integer PRIMARY KEY,
  last_update datetime
);
CREATE TABLE inventory (
  inventory_id integer PRIMARY KEY,
  film_id integer,
  store_id integer,
  last_update datetime
);
CREATE TABLE language (
  language_id integer PRIMARY KEY,
  name text,
  last_update datetime
);
CREATE TABLE payment (
  payment_id integer PRIMARY KEY,
  customer_id integer,
  staff_id integer,
  rental_id integer,
  amount real,
  payment_date datetime,
  last_update datetime
);
CREATE TABLE rental (
  rental_id integer PRIMARY KEY,
  rental_date datetime,
  inventory_id integer,
  customer_id integer,
  return_date datetime,
  staff_id integer,
  last_update datetime
);
CREATE TABLE staff (
  staff_id integer PRIMARY KEY,
  first_name text,
  last_name text,
  address_id integer,
  picture blob,
  email text,
  store_id integer,
  active integer,
  username text,
  password text,
  last_update datetime
);
CREATE TABLE store (
  store_id integer PRIMARY KEY,
  manager_staff_id integer,
  address_id integer,
  last_update datetime
);

Hint: 'Lillie Kim' is the full name of a customer; full name refers to first_name, last_name

Question: Provide the email, address, city, and country of the customer Lillie Kim.

assistant: SELECT T1.email, T2.address, T3.city, T4.country FROM customer AS T1 INNER JOIN address AS T2 ON T1.address_id = T2.address_id INNER JOIN city AS T3 ON T2.city_id = T3.city_id INNER JOIN country AS T4 ON T3.country_id = T4.country_id WHERE T1.first_name = 'Lillie' AND T1.last_name = 'Kim'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE film_text (
  film_id integer PRIMARY KEY,
  title text,
  description text
);
CREATE TABLE actor (
  actor_id integer PRIMARY KEY,
  first_name text,
  last_name text,
  last_update datetime
);
CREATE TABLE address (
  address_id integer PRIMARY KEY,
  address text,
  address2 text,
  district text,
  city_id integer,
  postal_code text,
  phone text,
  last_update datetime
);
CREATE TABLE category (
  category_id integer PRIMARY KEY,
  name text,
  last_update datetime
);
CREATE TABLE city (
  city_id integer PRIMARY KEY,
  city text,
  country_id integer,
  last_update datetime
);
CREATE TABLE country (
  country_id integer PRIMARY KEY,
  country text,
  last_update datetime
);
CREATE TABLE customer (
  customer_id integer PRIMARY KEY,
  store_id integer,
  first_name text,
  last_name text,
  email text,
  address_id integer,
  active integer,
  create_date datetime,
  last_update datetime
);
CREATE TABLE film (
  film_id integer PRIMARY KEY,
  title text,
  description text,
  release_year text,
  language_id integer,
  original_language_id integer,
  rental_duration integer,
  rental_rate real,
  length integer,
  replacement_cost real,
  rating text,
  special_features text,
  last_update datetime
);
CREATE TABLE film_actor (
  actor_id integer PRIMARY KEY,
  film_id integer PRIMARY KEY,
  last_update datetime
);
CREATE TABLE film_category (
  film_id integer PRIMARY KEY,
  category_id integer PRIMARY KEY,
  last_update datetime
);
CREATE TABLE inventory (
  inventory_id integer PRIMARY KEY,
  film_id integer,
  store_id integer,
  last_update datetime
);
CREATE TABLE language (
  language_id integer PRIMARY KEY,
  name text,
  last_update datetime
);
CREATE TABLE payment (
  payment_id integer PRIMARY KEY,
  customer_id integer,
  staff_id integer,
  rental_id integer,
  amount real,
  payment_date datetime,
  last_update datetime
);
CREATE TABLE rental (
  rental_id integer PRIMARY KEY,
  rental_date datetime,
  inventory_id integer,
  customer_id integer,
  return_date datetime,
  staff_id integer,
  last_update datetime
);
CREATE TABLE staff (
  staff_id integer PRIMARY KEY,
  first_name text,
  last_name text,
  address_id integer,
  picture blob,
  email text,
  store_id integer,
  active integer,
  username text,
  password text,
  last_update datetime
);
CREATE TABLE store (
  store_id integer PRIMARY KEY,
  manager_staff_id integer,
  address_id integer,
  last_update datetime
);

Hint: release in 2006 refers to release_year = 2006;

Question: Among the films starring PENELOPE GUINESS, how many of them are released in 2006?

assistant: SELECT COUNT(T2.film_id) FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T3.release_year = 2006 AND T1.first_name = 'PENELOPE' AND T1.last_name = 'GUINESS'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE customers (
  CustomerID integer PRIMARY KEY,
  First text,
  Last text,
  StreetAddress text,
  City text,
  State text,
  ZipCode integer,
  Email text,
  PhoneNumber text,
  FirstPurchaseDate date,
  SubscribedToEmailList text,
  Gender text
);
CREATE TABLE geolocation (
  LocationID integer PRIMARY KEY,
  Latitude real,
  Longitude real
);
CREATE TABLE location (
  LocationID integer PRIMARY KEY,
  LocationName text,
  StreetAddress text,
  City text,
  State text,
  ZipCode integer
);
CREATE TABLE rootbeerbrand (
  BrandID integer PRIMARY KEY,
  BrandName text,
  FirstBrewedYear integer,
  BreweryName text,
  City text,
  State text,
  Country text,
  Description text,
  CaneSugar text,
  CornSyrup text,
  Honey text,
  ArtificialSweetener text,
  Caffeinated text,
  Alcoholic text,
  AvailableInCans text,
  AvailableInBottles text,
  AvailableInKegs text,
  Website text,
  FacebookPage text,
  Twitter text,
  WholesaleCost real,
  CurrentRetailPrice real
);
CREATE TABLE rootbeer (
  RootBeerID integer PRIMARY KEY,
  BrandID integer,
  ContainerType text,
  LocationID integer,
  PurchaseDate date
);
CREATE TABLE rootbeerreview (
  CustomerID integer PRIMARY KEY,
  BrandID integer PRIMARY KEY,
  StarRating integer,
  ReviewDate date,
  Review text
);
CREATE TABLE transaction (
  TransactionID integer PRIMARY KEY,
  CreditCardNumber integer,
  CustomerID integer,
  TransactionDate date,
  CreditCardType text,
  LocationID integer,
  RootBeerID integer,
  PurchasePrice real
);
-- foreign keys: geolocation.LocationID -> location.LocationID; location.LocationID -> geolocation.LocationID; rootbeer.BrandID -> rootbeerbrand.BrandID; rootbeer.LocationID -> location.LocationID; rootbeer.LocationID -> geolocation.LocationID; rootbeerreview.BrandID -> rootbeerbrand.BrandID; rootbeerreview.CustomerID -> customers.CustomerID; transaction.RootBeerID -> rootbeer.RootBeerID; transaction.LocationID -> location.LocationID; transaction.CustomerID -> customers.CustomerID

Hint: difference = SUBTRACT(SUM(CaneSugar = 'TRUE'), SUM(CornSyrup = 'TRUE')); use cane sugar refers to CaneSugar = 'TRUE'; corn syrup refers to CornSyrup = 'TRUE';

Question: Calculate the difference between the number of root beers sold that use cane sugar and corn syrup.

assistant: SELECT COUNT(CASE WHEN T3.CaneSugar = 'TRUE' THEN T1.BrandID ELSE NULL END) - COUNT(CASE WHEN T3.CornSyrup = 'TRUE' THEN T1.BrandID ELSE NULL END) AS DIFFERENCE FROM rootbeer AS T1 INNER JOIN `transaction` AS T2 ON T1.RootBeerID = T2.RootBeerID INNER JOIN rootbeerbrand AS T3 ON T1.BrandID = T3.BrandID