ajayk007/querysmith-spider-bird huggingface dataset:
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
create table Student (
        StuID        INTEGER PRIMARY KEY,
        LName        VARCHAR(12),
        Fname        VARCHAR(12),
        Age      INTEGER,
        Sex      VARCHAR(1),
        Major        INTEGER,
        Advisor      INTEGER,
        city_code    VARCHAR(3)
 );

create table Faculty (
       FacID 	       INTEGER PRIMARY KEY,
       Lname		VARCHAR(15),
       Fname		VARCHAR(15),
       Rank		VARCHAR(15),
       Sex		VARCHAR(1),
       Phone		INTEGER,
       Room		VARCHAR(5),
       Building		VARCHAR(13)
);

create table Department (
       DNO   		INTEGER PRIMARY KEY,
       Division		VARCHAR(2),
       DName		VARCHAR(25),
       Room		VARCHAR(5),
       Building		VARCHAR(13),
       DPhone		INTEGER
);

create table Member_of (
       FacID 	       INTEGER,
       DNO	       INTEGER,
       Appt_Type       VARCHAR(15),
       FOREIGN KEY(FacID) REFERENCES Faculty(FacID),
       FOREIGN KEY(DNO) REFERENCES Department(DNO)
);

create table Course (
       CID   	    	VARCHAR(7) PRIMARY KEY,
       CName		VARCHAR(40),
       Credits		INTEGER,
       Instructor	INTEGER,
       Days		VARCHAR(5),
       Hours		VARCHAR(11),
       DNO		INTEGER,
       FOREIGN KEY(Instructor) REFERENCES Faculty(FacID),
       FOREIGN KEY(DNO) REFERENCES Department(DNO)
);

create table Minor_in (
       StuID 	      INTEGER,
       DNO		INTEGER,
       FOREIGN KEY(StuID) REFERENCES Student(StuID),
       FOREIGN KEY(DNO) REFERENCES Department(DNO)
);

create table Enrolled_in (
       StuID 		 INTEGER,
       CID		VARCHAR(7),
       Grade		VARCHAR(2),
       FOREIGN KEY(StuID) REFERENCES Student(StuID),
       FOREIGN KEY(CID) REFERENCES Course(CID),
       FOREIGN KEY(Grade) REFERENCES Gradeconversion(lettergrade)
);

create table Gradeconversion (
       lettergrade	     VARCHAR(2) PRIMARY KEY,
       gradepoint	     FLOAT
);

Question: What are the department name and room for the course INTRODUCTION TO COMPUTER SCIENCE?

assistant: SELECT T2.Dname , T2.Room FROM COURSE AS T1 JOIN DEPARTMENT AS T2 ON T1.DNO = T2.DNO WHERE T1.CName = "INTRODUCTION TO COMPUTER SCIENCE"
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE Ref_Document_Types (
Document_Type_Code CHAR(15) NOT NULL,
Document_Type_Name VARCHAR(255) NOT NULL,
Document_Type_Description VARCHAR(255) NOT NULL,
PRIMARY KEY (Document_Type_Code)
);
CREATE TABLE Ref_Budget_Codes (
Budget_Type_Code CHAR(15) NOT NULL,
Budget_Type_Description VARCHAR(255) NOT NULL,
PRIMARY KEY (Budget_Type_Code)
);

Question: Return the ids of documents that do not have expenses.

assistant: SELECT document_id FROM Documents EXCEPT SELECT document_id FROM Documents_with_expenses
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE Author (
  Id integer PRIMARY KEY,
  Name text,
  Affiliation text
);
CREATE TABLE Conference (
  Id integer PRIMARY KEY,
  ShortName text,
  FullName text,
  HomePage text
);
CREATE TABLE Journal (
  Id integer PRIMARY KEY,
  ShortName text,
  FullName text,
  HomePage text
);
CREATE TABLE Paper (
  Id integer PRIMARY KEY,
  Title text,
  Year integer,
  ConferenceId integer,
  JournalId integer,
  Keyword text
);
CREATE TABLE PaperAuthor (
  PaperId integer,
  AuthorId integer,
  Name text,
  Affiliation text
);
-- foreign keys: Paper.JournalId -> Journal.Id; Paper.ConferenceId -> Conference.Id; PaperAuthor.AuthorId -> Author.Id; PaperAuthor.PaperId -> Paper.Id

Hint: about Charged particle multiplicity refers to Title which contains 'Charged particle multiplicity'; affiliated with INFN refers to Affiliation LIKE '%INFN%' ; percentage refers to DIVIDE(COUNT(Affiliation LIKE '%INFN%' ), COUNT(AuthorId)) * 100%

Question: What percentage of authors of the paper about Charged particle multiplicity are affiliated with INFN?

assistant: SELECT CAST((SUM(CASE WHEN T1.Affiliation LIKE '%INFN%' THEN 1 ELSE 0 END)) AS REAL) * 100 / COUNT(T2.Id) FROM PaperAuthor AS T1 INNER JOIN Paper AS T2 ON T1.PaperId = T2.Id WHERE T2.Title LIKE '%Charged particle multiplicity%'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE bool (
  name text PRIMARY KEY
);
CREATE TABLE person (
  name text PRIMARY KEY
);
CREATE TABLE disabled (
  name text PRIMARY KEY
);
CREATE TABLE enlist (
  name text,
  organ text
);
CREATE TABLE filed_for_bankrupcy (
  name text PRIMARY KEY
);
CREATE TABLE longest_absense_from_school (
  name text PRIMARY KEY,
  month integer
);
CREATE TABLE male (
  name text PRIMARY KEY
);
CREATE TABLE no_payment_due (
  name text PRIMARY KEY,
  bool text
);
CREATE TABLE unemployed (
  name text PRIMARY KEY
);
CREATE TABLE enrolled (
  name text PRIMARY KEY,
  school text PRIMARY KEY,
  month integer
);
-- foreign keys: disabled.name -> person.name; enlist.name -> person.name; filed_for_bankrupcy.name -> person.name; longest_absense_from_school.name -> person.name; male.name -> person.name; no_payment_due.bool -> bool.name; no_payment_due.name -> person.name; unemployed.name -> person.name; enrolled.name -> person.name

Hint: enlisted organizations refers to organ; student160 is a name of student; status of his or her payment due is mentioned in no_payment_due; bool = 'pos' means the student has payment due; bool = 'neg' means the student has no payment due;

Question: Provide the enlisted organizations of student160 and status of his/her payment due.

assistant: SELECT T1.organ, T2.bool FROM enlist AS T1 INNER JOIN no_payment_due AS T2 ON T2.name = T1.name WHERE T1.name = 'student160'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
create table Student (
        StuID        INTEGER PRIMARY KEY,
        LName        VARCHAR(12),
        Fname        VARCHAR(12),
        Age      INTEGER,
        Sex      VARCHAR(1),
        Major        INTEGER,
        Advisor      INTEGER,
        city_code    VARCHAR(3)
 );
 

create table Dorm (
       dormid		INTEGER,
       dorm_name	VARCHAR(20),
       student_capacity	INTEGER,
       gender			VARCHAR(1)
) ;

create table Dorm_amenity (
       amenid			INTEGER,
       amenity_name		VARCHAR(25)
) ;

create table Has_amenity (
       dormid			INTEGER,
       amenid				INTEGER,
	FOREIGN KEY (dormid) REFERENCES `Dorm`(dormid),
	FOREIGN KEY (amenid) REFERENCES `Dorm_amenity`(amenid)
);

create table Lives_in (
       stuid 	      INTEGER,
       dormid		INTEGER,
       room_number	INTEGER,
	FOREIGN KEY (stuid) REFERENCES `Student`(StuID),
        FOREIGN KEY (dormid) REFERENCES `Dorm`(dormid)
);

Question: What is the average age for each city and what are those cities?

assistant: SELECT avg(age) , city_code FROM student GROUP BY city_code
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE divisions (
  division text PRIMARY KEY,
  name text,
  country text
);
CREATE TABLE matchs (
  Div text,
  Date date,
  HomeTeam text,
  AwayTeam text,
  FTHG integer,
  FTAG integer,
  FTR text,
  season integer
);
-- foreign keys: matchs.Div -> divisions.division

Hint: Bundesliga is the name of division; the most victories as the home team refers to MAX(COUNT(FTR = 'H'));

Question: Which team has the most victories as the home team in matches of the Bundesliga division?

assistant: SELECT T1.HomeTeam FROM matchs AS T1 INNER JOIN divisions AS T2 ON T1.Div = T2.division WHERE T2.name = 'Bundesliga' AND T1.FTR = 'H' GROUP BY T1.HomeTeam ORDER BY COUNT(T1.FTR) DESC LIMIT 1
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE "election" (
"Election_ID" int,
"Representative_ID" int,
"Date" text,
"Votes" real,
"Vote_Percent" real,
"Seats" real,
"Place" real,
PRIMARY KEY ("Election_ID"),
FOREIGN KEY ("Representative_ID") REFERENCES `representative`("Representative_ID")
);

CREATE TABLE "representative" (
"Representative_ID" int,
"Name" text,
"State" text,
"Party" text,
"Lifespan" text,
PRIMARY KEY ("Representative_ID")
);

Question: What is the party of the representative that has the smallest number of votes.

assistant: SELECT T2.Party FROM election AS T1 JOIN representative AS T2 ON T1.Representative_ID = T2.Representative_ID ORDER BY votes ASC LIMIT 1
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE "Songs" ( 
	"SongId" INTEGER PRIMARY KEY, 
	"Title" TEXT 
);
CREATE TABLE "Albums" ( 
	"AId" INTEGER PRIMARY KEY, 
	"Title" TEXT, 
	"Year" INTEGER, 
	"Label" TEXT, 
	"Type" TEXT );
CREATE TABLE "Band" ( 
	"Id" INTEGER PRIMARY KEY, 
	"Firstname" TEXT, 
	"Lastname" TEXT );
CREATE TABLE "Instruments" ( 
	"SongId" INTEGER, 
	"BandmateId" INTEGER, 
	"Instrument" TEXT ,
	PRIMARY KEY(SongId, BandmateId, Instrument),
	FOREIGN KEY (SongId) REFERENCES Songs(SongId),
	FOREIGN KEY (BandmateId) REFERENCES Band(Id)
);
CREATE TABLE "Performance" ( 
	"SongId" INTEGER, 
	"Bandmate" INTEGER, 
	"StagePosition" TEXT,
	PRIMARY KEY(SongId, Bandmate),
	FOREIGN KEY (SongId) REFERENCES Songs(SongId),
	FOREIGN KEY (Bandmate) REFERENCES Band(Id)
);
CREATE TABLE "Tracklists" ( 
	"AlbumId" INTEGER, 
	"Position" INTEGER, 
	"SongId" INTEGER ,
	PRIMARY KEY(AlbumId, Position),
	FOREIGN KEY (SongId) REFERENCES Songs(SongId),
	FOREIGN KEY (AlbumId) REFERENCES Albums(AId)
);
CREATE TABLE "Vocals" ( 
	"SongId" INTEGER, 
	"Bandmate" INTEGER, 
	"Type" TEXT,
	PRIMARY KEY(SongId, Bandmate),
	FOREIGN KEY (SongId) REFERENCES Songs(SongId),
	FOREIGN KEY (Bandmate) REFERENCES Band(Id)
);

Question: Find the number of vocal types used in song "Demon Kitty Rag"?

assistant: SELECT count(*) FROM vocals AS T1 JOIN songs AS T2 ON T1.songid = T2.songid WHERE title = "Demon Kitty Rag"
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE `Products` (
`product_id` INTEGER PRIMARY KEY,
`product_name` VARCHAR(20),
`product_price` DECIMAL(19,4),
`product_description` VARCHAR(255)
);

Question: Find the name of route that has the highest number of deliveries.

assistant: SELECT t1.route_name FROM Delivery_Routes AS t1 JOIN Delivery_Route_Locations AS t2 ON t1.route_id = t2.route_id GROUP BY t1.route_id ORDER BY count(*) DESC LIMIT 1
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;
CREATE TABLE `Ref_Characteristic_Types` (
`characteristic_type_code` VARCHAR(15) PRIMARY KEY,
`characteristic_type_description` VARCHAR(80)
);
CREATE TABLE `Ref_Colors` (
`color_code` VARCHAR(15) PRIMARY KEY,
`color_description` VARCHAR(80)
);
CREATE TABLE `Ref_Product_Categories` (
`product_category_code` VARCHAR(15) PRIMARY KEY,
`product_category_description` VARCHAR(80),
`unit_of_measure` VARCHAR(20)
);

Question: Return the name of the characteristic that is most common across all products.

assistant: SELECT t3.characteristic_name FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id = t2.product_id JOIN CHARACTERISTICS AS t3 ON t2.characteristic_id = t3.characteristic_id GROUP BY t3.characteristic_name ORDER BY count(*) DESC LIMIT 1
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE film_text (
  film_id integer PRIMARY KEY,
  title text,
  description text
);
CREATE TABLE actor (
  actor_id integer PRIMARY KEY,
  first_name text,
  last_name text,
  last_update datetime
);
CREATE TABLE address (
  address_id integer PRIMARY KEY,
  address text,
  address2 text,
  district text,
  city_id integer,
  postal_code text,
  phone text,
  last_update datetime
);
CREATE TABLE category (
  category_id integer PRIMARY KEY,
  name text,
  last_update datetime
);
CREATE TABLE city (
  city_id integer PRIMARY KEY,
  city text,
  country_id integer,
  last_update datetime
);
CREATE TABLE country (
  country_id integer PRIMARY KEY,
  country text,
  last_update datetime
);
CREATE TABLE customer (
  customer_id integer PRIMARY KEY,
  store_id integer,
  first_name text,
  last_name text,
  email text,
  address_id integer,
  active integer,
  create_date datetime,
  last_update datetime
);
CREATE TABLE film (
  film_id integer PRIMARY KEY,
  title text,
  description text,
  release_year text,
  language_id integer,
  original_language_id integer,
  rental_duration integer,
  rental_rate real,
  length integer,
  replacement_cost real,
  rating text,
  special_features text,
  last_update datetime
);
CREATE TABLE film_actor (
  actor_id integer PRIMARY KEY,
  film_id integer PRIMARY KEY,
  last_update datetime
);
CREATE TABLE film_category (
  film_id integer PRIMARY KEY,
  category_id integer PRIMARY KEY,
  last_update datetime
);
CREATE TABLE inventory (
  inventory_id integer PRIMARY KEY,
  film_id integer,
  store_id integer,
  last_update datetime
);
CREATE TABLE language (
  language_id integer PRIMARY KEY,
  name text,
  last_update datetime
);
CREATE TABLE payment (
  payment_id integer PRIMARY KEY,
  customer_id integer,
  staff_id integer,
  rental_id integer,
  amount real,
  payment_date datetime,
  last_update datetime
);
CREATE TABLE rental (
  rental_id integer PRIMARY KEY,
  rental_date datetime,
  inventory_id integer,
  customer_id integer,
  return_date datetime,
  staff_id integer,
  last_update datetime
);
CREATE TABLE staff (
  staff_id integer PRIMARY KEY,
  first_name text,
  last_name text,
  address_id integer,
  picture blob,
  email text,
  store_id integer,
  active integer,
  username text,
  password text,
  last_update datetime
);
CREATE TABLE store (
  store_id integer PRIMARY KEY,
  manager_staff_id integer,
  address_id integer,
  last_update datetime
);

Hint: "English" is the name of language

Question: How many films are in English?

assistant: SELECT COUNT(T1.film_id) FROM film AS T1 INNER JOIN language AS T2 ON T1.language_id = T2.language_id WHERE T2.name = 'English'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
create table Student (
        StuID        INTEGER PRIMARY KEY,
        LName        VARCHAR(12),
        Fname        VARCHAR(12),
        Age      INTEGER,
        Sex      VARCHAR(1),
        Major        INTEGER,
        Advisor      INTEGER,
        city_code    VARCHAR(3)
 );

create table Faculty (
       FacID 	       INTEGER PRIMARY KEY,
       Lname		VARCHAR(15),
       Fname		VARCHAR(15),
       Rank		VARCHAR(15),
       Sex		VARCHAR(1),
       Phone		INTEGER,
       Room		VARCHAR(5),
       Building		VARCHAR(13)
);

create table Department (
       DNO   		INTEGER PRIMARY KEY,
       Division		VARCHAR(2),
       DName		VARCHAR(25),
       Room		VARCHAR(5),
       Building		VARCHAR(13),
       DPhone		INTEGER
);

create table Member_of (
       FacID 	       INTEGER,
       DNO	       INTEGER,
       Appt_Type       VARCHAR(15),
       FOREIGN KEY(FacID) REFERENCES Faculty(FacID),
       FOREIGN KEY(DNO) REFERENCES Department(DNO)
);

create table Course (
       CID   	    	VARCHAR(7) PRIMARY KEY,
       CName		VARCHAR(40),
       Credits		INTEGER,
       Instructor	INTEGER,
       Days		VARCHAR(5),
       Hours		VARCHAR(11),
       DNO		INTEGER,
       FOREIGN KEY(Instructor) REFERENCES Faculty(FacID),
       FOREIGN KEY(DNO) REFERENCES Department(DNO)
);

create table Minor_in (
       StuID 	      INTEGER,
       DNO		INTEGER,
       FOREIGN KEY(StuID) REFERENCES Student(StuID),
       FOREIGN KEY(DNO) REFERENCES Department(DNO)
);

create table Enrolled_in (
       StuID 		 INTEGER,
       CID		VARCHAR(7),
       Grade		VARCHAR(2),
       FOREIGN KEY(StuID) REFERENCES Student(StuID),
       FOREIGN KEY(CID) REFERENCES Course(CID),
       FOREIGN KEY(Grade) REFERENCES Gradeconversion(lettergrade)
);

create table Gradeconversion (
       lettergrade	     VARCHAR(2) PRIMARY KEY,
       gradepoint	     FLOAT
);

Question: What are the distinct first names for students with a grade point of 3.8 or above in at least one course?

assistant: SELECT DISTINCT T3.Fname FROM ENROLLED_IN AS T1 JOIN GRADECONVERSION AS T2 JOIN STUDENT AS T3 ON T1.Grade = T2.lettergrade AND T1.StuID = T3.StuID WHERE T2.gradepoint >= 3.8
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE customers (
  CustomerID integer PRIMARY KEY,
  First text,
  Last text,
  StreetAddress text,
  City text,
  State text,
  ZipCode integer,
  Email text,
  PhoneNumber text,
  FirstPurchaseDate date,
  SubscribedToEmailList text,
  Gender text
);
CREATE TABLE geolocation (
  LocationID integer PRIMARY KEY,
  Latitude real,
  Longitude real
);
CREATE TABLE location (
  LocationID integer PRIMARY KEY,
  LocationName text,
  StreetAddress text,
  City text,
  State text,
  ZipCode integer
);
CREATE TABLE rootbeerbrand (
  BrandID integer PRIMARY KEY,
  BrandName text,
  FirstBrewedYear integer,
  BreweryName text,
  City text,
  State text,
  Country text,
  Description text,
  CaneSugar text,
  CornSyrup text,
  Honey text,
  ArtificialSweetener text,
  Caffeinated text,
  Alcoholic text,
  AvailableInCans text,
  AvailableInBottles text,
  AvailableInKegs text,
  Website text,
  FacebookPage text,
  Twitter text,
  WholesaleCost real,
  CurrentRetailPrice real
);
CREATE TABLE rootbeer (
  RootBeerID integer PRIMARY KEY,
  BrandID integer,
  ContainerType text,
  LocationID integer,
  PurchaseDate date
);
CREATE TABLE rootbeerreview (
  CustomerID integer PRIMARY KEY,
  BrandID integer PRIMARY KEY,
  StarRating integer,
  ReviewDate date,
  Review text
);
CREATE TABLE transaction (
  TransactionID integer PRIMARY KEY,
  CreditCardNumber integer,
  CustomerID integer,
  TransactionDate date,
  CreditCardType text,
  LocationID integer,
  RootBeerID integer,
  PurchasePrice real
);
-- foreign keys: geolocation.LocationID -> location.LocationID; location.LocationID -> geolocation.LocationID; rootbeer.BrandID -> rootbeerbrand.BrandID; rootbeer.LocationID -> location.LocationID; rootbeer.LocationID -> geolocation.LocationID; rootbeerreview.BrandID -> rootbeerbrand.BrandID; rootbeerreview.CustomerID -> customers.CustomerID; transaction.RootBeerID -> rootbeer.RootBeerID; transaction.LocationID -> location.LocationID; transaction.CustomerID -> customers.CustomerID

Hint: total purchases = SUM(PurchasePrice); Visa credit card refers to CreditCardType = 'Visa'; Sac State American River Courtyard refers to LocationName = 'Sac State American River Courtyard'; between 6/3/2014 and 11/27/2015 refers to TransactionDate BETWEEN '2014-06-03' AND '2015-11-27';

Question: Calculate the total purchases made by customers using their Visa credit cards in the Sac State American River Courtyard between 6/3/2014 and 11/27/2015.

assistant: SELECT SUM(T1.PurchasePrice) FROM `transaction` AS T1 INNER JOIN location AS T2 ON T1.LocationID = T2.LocationID WHERE T2.LocationName = 'Sac State American River Courtyard' AND T1.CreditCardType = 'Visa' AND T1.TransactionDate BETWEEN '2014-06-03' AND '2015-11-27'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE station (
  id integer PRIMARY KEY,
  name text,
  lat real,
  long real,
  dock_count integer,
  city text,
  installation_date text
);
CREATE TABLE status (
  station_id integer,
  bikes_available integer,
  docks_available integer,
  time text
);
CREATE TABLE trip (
  id integer PRIMARY KEY,
  duration integer,
  start_date text,
  start_station_name text,
  start_station_id integer,
  end_date text,
  end_station_name text,
  end_station_id integer,
  bike_id integer,
  subscription_type text,
  zip_code integer
);
CREATE TABLE weather (
  date text,
  max_temperature_f integer,
  mean_temperature_f integer,
  min_temperature_f integer,
  max_dew_point_f integer,
  mean_dew_point_f integer,
  min_dew_point_f integer,
  max_humidity integer,
  mean_humidity integer,
  min_humidity integer,
  max_sea_level_pressure_inches real,
  mean_sea_level_pressure_inches real,
  min_sea_level_pressure_inches real,
  max_visibility_miles integer,
  mean_visibility_miles integer,
  min_visibility_miles integer,
  max_wind_Speed_mph integer,
  mean_wind_speed_mph integer,
  max_gust_speed_mph integer,
  precipitation_inches text,
  cloud_cover integer,
  events text,
  wind_dir_degrees integer,
  zip_code text
);

Hint: which day had the most bikes borrowed refers to MAX(start_date); the average coldest temperature can be computed as DIVIDE(SUM(min_temperature_f), COUNT(min_temperature_f));

Question: Among all the trips, which day had the most bikes borrowed? What was the average coldest temperature on that day?

assistant: SELECT T2.date, AVG(T2.min_temperature_f) FROM trip AS T1 INNER JOIN weather AS T2 ON T2.zip_code = T1.zip_code GROUP BY T2.date ORDER BY COUNT(T1.start_date) DESC LIMIT 1