ajayk007/querysmith-spider-bird huggingface dataset:
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE location (
  LocationID integer PRIMARY KEY,
  Country text,
  State text,
  StateCode text,
  City text
);
CREATE TABLE user (
  UserID text PRIMARY KEY,
  Gender text
);
CREATE TABLE twitter (
  TweetID text PRIMARY KEY,
  Weekday text,
  Hour integer,
  Day integer,
  Lang text,
  IsReshare text,
  Reach integer,
  RetweetCount integer,
  Likes integer,
  Klout integer,
  Sentiment real,
  text text,
  LocationID integer,
  UserID text
);
-- foreign keys: twitter.UserID -> user.UserID; twitter.LocationID -> location.LocationID

Hint: "Argentina" is the Country; average number of tweets in a city = Divide (Count(TweetID where Country = 'Argentina'), Count (City))

Question: What is the average number of tweets posted by the users in a city in Argentina?

assistant: SELECT SUM(CASE WHEN T2.City = 'Buenos Aires' THEN 1.0 ELSE 0 END) / COUNT(T1.TweetID) AS avg FROM twitter AS T1 INNER JOIN location AS T2 ON T2.LocationID = T1.LocationID WHERE T2.Country = 'Argentina'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE "artist" (
"Artist_ID" int,
"Name" text,
"Country" text,
"Year_Join" int,
"Age" int,
PRIMARY KEY ("Artist_ID")
);

Question: How many exhibitions have a attendance more than 100 or have a ticket price below 10?

assistant: SELECT count(*) FROM exhibition_record AS T1 JOIN exhibition AS T2 ON T1.exhibition_id = T2.exhibition_id WHERE T1.attendance > 100 OR T2.ticket_price < 10
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE langs (
  lid integer PRIMARY KEY,
  lang text,
  locale text,
  pages integer,
  words integer
);
CREATE TABLE pages (
  pid integer PRIMARY KEY,
  lid integer,
  page integer,
  revision integer,
  title text,
  words integer
);
CREATE TABLE words (
  wid integer PRIMARY KEY,
  word text,
  occurrences integer
);
CREATE TABLE langs_words (
  lid integer PRIMARY KEY,
  wid integer PRIMARY KEY,
  occurrences integer
);
CREATE TABLE pages_words (
  pid integer PRIMARY KEY,
  wid integer PRIMARY KEY,
  occurrences integer
);
CREATE TABLE biwords (
  lid integer PRIMARY KEY,
  w1st integer PRIMARY KEY,
  w2nd integer PRIMARY KEY,
  occurrences integer
);
-- foreign keys: pages.lid -> langs.lid; langs_words.wid -> words.wid; langs_words.lid -> langs.lid; pages_words.wid -> words.wid; pages_words.pid -> pages.pid; biwords.w2nd -> words.wid; biwords.w1st -> words.wid; biwords.lid -> langs.lid

Hint: appeared 8 times refers to occurrences = 8;

Question: How many word appeared 8 times? State the language id of the page.

assistant: SELECT COUNT(T2.wid), T1.lid FROM pages AS T1 INNER JOIN pages_words AS T2 ON T1.pid = T2.pid WHERE T2.occurrences = 8
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE geographic (
  city text PRIMARY KEY,
  county text,
  region text
);
CREATE TABLE generalinfo (
  id_restaurant integer PRIMARY KEY,
  label text,
  food_type text,
  city text,
  review real
);
CREATE TABLE location (
  id_restaurant integer PRIMARY KEY,
  street_num integer,
  street_name text,
  city text
);
-- foreign keys: generalinfo.city -> geographic.city; location.id_restaurant -> generalinfo.id_restaurant; location.city -> geographic.city

Hint: kind of restaurant refers to food_type; "106 E 25th Ave" refers to street_name = 'e 25th ave'

Question: What kind of restaurants can be found at "106 E 25th Ave"?

assistant: SELECT T1.food_type FROM generalinfo AS T1 INNER JOIN location AS T2 ON T1.id_restaurant = T2.id_restaurant WHERE T2.street_num = 106 AND T2.street_name = 'e 25th ave'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;
CREATE TABLE `Customers` (
`customer_id` INTEGER PRIMARY KEY,
`customer_first_name` VARCHAR(50),
`customer_middle_initial` VARCHAR(1),
`customer_last_name` VARCHAR(50),
`gender` VARCHAR(1),
`email_address` VARCHAR(255),
`login_name` VARCHAR(80),
`login_password` VARCHAR(20),
`phone_number` VARCHAR(255),
`town_city` VARCHAR(50),
`state_county_province` VARCHAR(50),
`country` VARCHAR(50)
);

Question: Show the account id and name with at least 4 transactions.

assistant: SELECT T1.account_id , T2.account_name FROM Financial_transactions AS T1 JOIN Accounts AS T2 ON T1.account_id = T2.account_id GROUP BY T1.account_id HAVING count(*) >= 4
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE `Addresses` (
`address_id` INTEGER PRIMARY KEY,
`address_content` VARCHAR(80),
`city` VARCHAR(50),
`zip_postcode` VARCHAR(20),
`state_province_county` VARCHAR(50),
`country` VARCHAR(50),
`other_address_details` VARCHAR(255)
);

Question: Find the customer name and date of the orders that have the status "Delivered".

assistant: SELECT t1.customer_name , t2.order_date FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id WHERE order_status = "Delivered"
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE Attributes (
  attribute_id integer PRIMARY KEY,
  attribute_name text
);
CREATE TABLE Categories (
  category_id integer PRIMARY KEY,
  category_name text
);
CREATE TABLE Compliments (
  compliment_id integer PRIMARY KEY,
  compliment_type text
);
CREATE TABLE Days (
  day_id integer PRIMARY KEY,
  day_of_week text
);
CREATE TABLE Years (
  year_id integer PRIMARY KEY,
  actual_year integer
);
CREATE TABLE Business_Attributes (
  attribute_id integer PRIMARY KEY,
  business_id integer PRIMARY KEY,
  attribute_value text
);
CREATE TABLE Business_Categories (
  business_id integer PRIMARY KEY,
  category_id integer PRIMARY KEY
);
CREATE TABLE Business_Hours (
  business_id integer PRIMARY KEY,
  day_id integer PRIMARY KEY,
  opening_time text,
  closing_time text
);
CREATE TABLE Checkins (
  business_id integer PRIMARY KEY,
  day_id integer PRIMARY KEY,
  label_time_0 text,
  label_time_1 text,
  label_time_2 text,
  label_time_3 text,
  label_time_4 text,
  label_time_5 text,
  label_time_6 text,
  label_time_7 text,
  label_time_8 text,
  label_time_9 text,
  label_time_10 text,
  label_time_11 text,
  label_time_12 text,
  label_time_13 text,
  label_time_14 text,
  label_time_15 text,
  label_time_16 text,
  label_time_17 text,
  label_time_18 text,
  label_time_19 text,
  label_time_20 text,
  label_time_21 text,
  label_time_22 text,
  label_time_23 text
);
CREATE TABLE Elite (
  user_id integer PRIMARY KEY,
  year_id integer PRIMARY KEY
);
CREATE TABLE Reviews (
  business_id integer PRIMARY KEY,
  user_id integer PRIMARY KEY,
  review_stars integer,
  review_votes_funny text,
  review_votes_useful text,
  review_votes_cool text,
  review_length text
);
CREATE TABLE Tips (
  business_id integer PRIMARY KEY,
  user_id integer PRIMARY KEY,
  likes integer,
  tip_length text
);
CREATE TABLE Users_Compliments (
  compliment_id integer PRIMARY KEY,
  user_id integer PRIMARY KEY,
  number_of_compliments text
);
CREATE TABLE Business (
  business_id integer PRIMARY KEY,
  active text,
  city text,
  state text,
  stars real,
  review_count text
);
CREATE TABLE Users (
  user_id integer PRIMARY KEY,
  user_yelping_since_year integer,
  user_average_stars text,
  user_votes_funny text,
  user_votes_useful text,
  user_votes_cool text,
  user_review_count text,
  user_fans text
);

Hint: average ratings of at least 4 refers to user_average_stars > = 4; no fans or followers refers to user_fans = 'None'; percentage = divide(count(user_id where user_average_stars > = 4 and user_fans = 'None'), sum(user_id where user_average_stars > = 4))*100%

Question: Among all the users with the average ratings of at least 4 and above of all reviews, calculate the percent that have no fans or followers.

assistant: SELECT CAST(SUM(CASE WHEN user_fans = 'None' THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(user_id) FROM Users WHERE user_average_stars >= 4
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE employee (
  employee_id integer PRIMARY KEY,
  first_name text,
  last_name text,
  address text,
  city text,
  state text,
  zip integer,
  phone text,
  title text,
  salary integer,
  supervisor integer
);
CREATE TABLE establishment (
  license_no integer PRIMARY KEY,
  dba_name text,
  aka_name text,
  facility_type text,
  risk_level integer,
  address text,
  city text,
  state text,
  zip integer,
  latitude real,
  longitude real,
  ward integer
);
CREATE TABLE inspection (
  inspection_id integer PRIMARY KEY,
  inspection_date date,
  inspection_type text,
  results text,
  employee_id integer,
  license_no integer,
  followup_to integer
);
CREATE TABLE inspection_point (
  point_id integer PRIMARY KEY,
  Description text,
  category text,
  code text,
  fine integer,
  point_level text
);
CREATE TABLE violation (
  inspection_id integer PRIMARY KEY,
  point_id integer PRIMARY KEY,
  fine integer,
  inspector_comment text
);
-- foreign keys: employee.supervisor -> employee.employee_id; inspection.followup_to -> inspection.inspection_id; inspection.license_no -> establishment.license_no; inspection.employee_id -> employee.employee_id; violation.point_id -> inspection_point.point_id; violation.inspection_id -> inspection.inspection_id

Hint: inspection result refers to results

Question: What is the inspection result for inspection done by Thomas Langley?

assistant: SELECT DISTINCT T2.results FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id WHERE T1.first_name = 'Thomas' AND T1.last_name = 'Langley'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;
CREATE TABLE Customers (
Customer_ID INTEGER NOT NULL,
Customer_Details VARCHAR(255) NOT NULL,
PRIMARY KEY (Customer_ID)
);

Question: What are the names of customers who do not have any policies?

assistant: SELECT customer_details FROM customers EXCEPT SELECT t2.customer_details FROM policies AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
create table Student (
        StuID        INTEGER PRIMARY KEY,
        LName        VARCHAR(12),
        Fname        VARCHAR(12),
        Age      INTEGER,
        Sex      VARCHAR(1),
        Major        INTEGER,
        Advisor      INTEGER,
        city_code    VARCHAR(3)
 );

create table Voting_record (
       StuID    	INTEGER,
       Registration_Date		VARCHAR(12),
       Election_Cycle		VARCHAR(12),
       President_Vote		INTEGER,
       Vice_President_Vote		INTEGER,
       Secretary_Vote		INTEGER,
       Treasurer_Vote		INTEGER,
       Class_President_Vote		INTEGER,
       Class_Senator_Vote		INTEGER,
       FOREIGN KEY(StuID) REFERENCES Student(StuID), 
       FOREIGN KEY(President_Vote) REFERENCES Student(StuID),
       FOREIGN KEY(Vice_President_Vote) REFERENCES Student(StuID),
       FOREIGN KEY(Secretary_Vote) REFERENCES Student(StuID),
       FOREIGN KEY(Treasurer_Vote) REFERENCES Student(StuID),
       FOREIGN KEY(Class_President_Vote) REFERENCES Student(StuID),
       FOREIGN KEY(Class_Senator_Vote) REFERENCES Student(StuID)
);

Question: Find the distinct first names of the students who have class senator votes.

assistant: SELECT DISTINCT T1.Fname FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = T2.CLASS_Senator_VOTE
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;
CREATE TABLE `Course_Authors_and_Tutors` (
`author_id` INTEGER PRIMARY KEY,
`author_tutor_ATB` VARCHAR(3),
`login_name` VARCHAR(40),
`password` VARCHAR(40),
`personal_name` VARCHAR(80),
`middle_name` VARCHAR(80),
`family_name` VARCHAR(80),
`gender_mf` VARCHAR(1),
`address_line_1` VARCHAR(80)
);

Question: What are the names of the courses taught by the tutor whose personal name is "Julio"?

assistant: SELECT T2.course_name FROM Course_Authors_and_Tutors AS T1 JOIN Courses AS T2 ON T1.author_id = T2.author_id WHERE T1.personal_name = "Julio"
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE Community_Area (
  community_area_no integer PRIMARY KEY,
  community_area_name text,
  side text,
  population text
);
CREATE TABLE District (
  district_no integer PRIMARY KEY,
  district_name text,
  address text,
  zip_code integer,
  commander text,
  email text,
  phone text,
  fax text,
  tty text,
  twitter text
);
CREATE TABLE FBI_Code (
  fbi_code_no text PRIMARY KEY,
  title text,
  description text,
  crime_against text
);
CREATE TABLE IUCR (
  iucr_no text PRIMARY KEY,
  primary_description text,
  secondary_description text,
  index_code text
);
CREATE TABLE Neighborhood (
  neighborhood_name text PRIMARY KEY,
  community_area_no integer
);
CREATE TABLE Ward (
  ward_no integer PRIMARY KEY,
  alderman_first_name text,
  alderman_last_name text,
  alderman_name_suffix text,
  ward_office_address text,
  ward_office_zip text,
  ward_email text,
  ward_office_phone text,
  ward_office_fax text,
  city_hall_office_room integer,
  city_hall_office_phone text,
  city_hall_office_fax text,
  Population integer
);
CREATE TABLE Crime (
  report_no integer PRIMARY KEY,
  case_number text,
  date text,
  block text,
  iucr_no text,
  location_description text,
  arrest text,
  domestic text,
  beat integer,
  district_no integer,
  ward_no integer,
  community_area_no integer,
  fbi_code_no text,
  latitude text,
  longitude text
);
-- foreign keys: Neighborhood.community_area_no -> Community_Area.community_area_no; Crime.fbi_code_no -> FBI_Code.fbi_code_no; Crime.community_area_no -> Community_Area.community_area_no; Crime.district_no -> District.district_no; Crime.iucr_no -> IUCR.iucr_no; Crime.ward_no -> Ward.ward_no

Hint: least populated refers to Min(Population); community refers to community_area_no; most common location refers to Max(Count(location_description))

Question: In the least populated community, what is the most common location of all the reported crime incidents?

assistant: SELECT T2.location_description FROM Community_Area AS T1 INNER JOIN Crime AS T2 ON T1.community_area_no = T2.community_area_no WHERE T1.population = ( SELECT MIN(population) FROM Community_Area ) AND T2.location_description IS NOT NULL GROUP BY T2.location_description
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE city (
  id integer PRIMARY KEY,
  city_name text
);
CREATE TABLE games (
  id integer PRIMARY KEY,
  games_year integer,
  games_name text,
  season text
);
CREATE TABLE games_city (
  games_id integer,
  city_id integer
);
CREATE TABLE medal (
  id integer PRIMARY KEY,
  medal_name text
);
CREATE TABLE noc_region (
  id integer PRIMARY KEY,
  noc text,
  region_name text
);
CREATE TABLE person (
  id integer PRIMARY KEY,
  full_name text,
  gender text,
  height integer,
  weight integer
);
CREATE TABLE games_competitor (
  id integer PRIMARY KEY,
  games_id integer,
  person_id integer,
  age integer
);
CREATE TABLE person_region (
  person_id integer,
  region_id integer
);
CREATE TABLE sport (
  id integer PRIMARY KEY,
  sport_name text
);
CREATE TABLE event (
  id integer PRIMARY KEY,
  sport_id integer,
  event_name text
);
CREATE TABLE competitor_event (
  event_id integer,
  competitor_id integer,
  medal_id integer
);
-- foreign keys: games_city.games_id -> games.id; games_city.city_id -> city.id; games_competitor.person_id -> person.id; games_competitor.games_id -> games.id; person_region.region_id -> noc_region.id; person_region.person_id -> person.id; event.sport_id -> sport.id; competitor_event.medal_id -> medal.id; competitor_event.event_id -> event.id; competitor_event.competitor_id -> games_competitor.id

Hint: In which Olympic Games refer to games_year;

Question: In which Olympic Games has Morten Aleksander Djupvik participated?

assistant: SELECT T1.games_name FROM games AS T1 INNER JOIN games_competitor AS T2 ON T1.id = T2.games_id INNER JOIN person AS T3 ON T2.person_id = T3.id WHERE T3.full_name = 'Morten Aleksander Djupvik'
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
-- phpMyAdmin SQL Dump
-- version 4.0.10.7
-- http://www.phpmyadmin.net
--
-- Host: localhost
-- Generation Time: Mar 20, 2015 at 01:43 AM
-- Server version: 5.5.34-cll-lve
-- PHP Version: 5.4.23



/*!40101 SET @OLD_CHARACTER_SET_CLIENT=@@CHARACTER_SET_CLIENT */;
/*!40101 SET @OLD_CHARACTER_SET_RESULTS=@@CHARACTER_SET_RESULTS */;
/*!40101 SET @OLD_COLLATION_CONNECTION=@@COLLATION_CONNECTION */;
/*!40101 SET NAMES utf8 */;
CREATE TABLE IF NOT EXISTS `regions` (
  `REGION_ID` decimal(5,0) NOT NULL,
  `REGION_NAME` varchar(25) DEFAULT NULL,
  PRIMARY KEY (`REGION_ID`)
);

--
-- Dumping data for table `regions`
--

Question: display the employee number, name( first name and last name ), and salary for all employees who earn more than the average salary and who work in a department with any employee with a 'J' in their first name.

assistant: SELECT employee_id , first_name , last_name , salary FROM employees WHERE salary > ( SELECT AVG (salary) FROM employees ) AND department_id IN ( SELECT department_id FROM employees WHERE first_name LIKE '%J%')
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
CREATE TABLE country (
  country_id integer PRIMARY KEY,
  country_iso_code text,
  country_name text
);
CREATE TABLE department (
  department_id integer PRIMARY KEY,
  department_name text
);
CREATE TABLE gender (
  gender_id integer PRIMARY KEY,
  gender text
);
CREATE TABLE genre (
  genre_id integer PRIMARY KEY,
  genre_name text
);
CREATE TABLE keyword (
  keyword_id integer PRIMARY KEY,
  keyword_name text
);
CREATE TABLE language (
  language_id integer PRIMARY KEY,
  language_code text,
  language_name text
);
CREATE TABLE language_role (
  role_id integer PRIMARY KEY,
  language_role text
);
CREATE TABLE movie (
  movie_id integer PRIMARY KEY,
  title text,
  budget integer,
  homepage text,
  overview text,
  popularity real,
  release_date date,
  revenue integer,
  runtime integer,
  movie_status text,
  tagline text,
  vote_average real,
  vote_count integer
);
CREATE TABLE movie_genres (
  movie_id integer,
  genre_id integer
);
CREATE TABLE movie_languages (
  movie_id integer,
  language_id integer,
  language_role_id integer
);
CREATE TABLE person (
  person_id integer PRIMARY KEY,
  person_name text
);
CREATE TABLE movie_crew (
  movie_id integer,
  person_id integer,
  department_id integer,
  job text
);
CREATE TABLE production_company (
  company_id integer PRIMARY KEY,
  company_name text
);
CREATE TABLE production_country (
  movie_id integer,
  country_id integer
);
CREATE TABLE movie_cast (
  movie_id integer,
  person_id integer,
  character_name text,
  gender_id integer,
  cast_order integer
);
CREATE TABLE movie_keywords (
  movie_id integer,
  keyword_id integer
);
CREATE TABLE movie_company (
  movie_id integer,
  company_id integer
);
-- foreign keys: movie_genres.movie_id -> movie.movie_id; movie_genres.genre_id -> genre.genre_id; movie_languages.language_role_id -> language_role.role_id; movie_languages.movie_id -> movie.movie_id; movie_languages.language_id -> language.language_id; movie_crew.person_id -> person.person_id; movie_crew.movie_id -> movie.movie_id; movie_crew.department_id -> department.department_id; production_country.movie_id -> movie.movie_id; production_country.country_id -> country.country_id; movie_cast.person_id -> person.person_id; movie_cast.movie_id -> movie.movie_id; movie_cast.gender_id -> gender.gender_id

Hint: average number of crews = divide(count(person_id), COUNT(movie_id))

Question: What is the average number of crews for a movie?

assistant: SELECT CAST(SUM(CD) AS REAL) / COUNT(movie_id) FROM ( SELECT movie_id, COUNT(person_id) AS CD FROM movie_crew GROUP BY movie_id )
system: You are a text-to-SQL generator. Given a database schema and a question, reply with a single valid SQLite query that answers it. Output only the SQL on one line, with no explanation and no markdown.

user: Schema:
PRAGMA foreign_keys = ON;

CREATE TABLE "party" (
"Party_ID" int,
"Party_Theme" text,
"Location" text,
"First_year" text,
"Last_year" text,
"Number_of_hosts" int,
PRIMARY KEY ("Party_ID")
);

CREATE TABLE "host" (
"Host_ID" int,
"Name" text,
"Nationality" text,
"Age" text,
PRIMARY KEY ("Host_ID")
);

Question: Compute the average number of hosts for parties.

assistant: SELECT avg(Number_of_hosts) FROM party